RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. Calculate the share of B in the profit.
A.Rs. 1900
B.Rs. 2660
C.Rs. 2800
D.Rs. 2840
Answer: B.Rs. 2660
Explanation: Explanation:
For managing, A received = 5% of Rs. 7400 = Rs. 370.
Balance = Rs. (7400 - 370) = Rs. 7030.
Ratio of their investments = (6500 x 6) : (8400 x 5) : (10000 x 3)
= 39000 : 42000 : 30000
= 13 : 14 : 10
B's share = Rs.(7030 X 14/37)=Rs. 2660.
ANSWER IS B
Question: Three numbers are in the ratio 1 : 2 : 3 and their H.C.F is 4. The numbers are
A.12, 24, 30
B.12, 24, 38
C.12, 24, 362
D.4, 8, 12
Answer: D.4, 8, 12
Explanation: Explanation:
Let the required numbers be x, 2x, 3x. Then, their H.C.F =x. so, x= 4
\inline \fn_jvn \therefore The numbers are 4, 8, 12
Answer: D) 4, 8, 12
Question: In the line xy plane line m has the equation y = 4x - 8, then the line m passes through which of the following points?
A.(3, 1)
B.(3, 4)
C.(4, 2)
D.(4, 8)
Answer: D.(4, 8)
Explanation: Yes it is y=3x-8....extremely sorry for mistake....
IF that's the case then answer is D
y=3x-8
8=3X4-8
8=16-8
8=8 (satisfied)
Question: n is an integer chosen at random from the set
{5, 7, 9, 11 }
p is chosen at random from the set
{2, 6, 10, 14, 18}
What is the probability that n + p = 25 ?
A.0.1
B.0.2
C.0.05
D.0.3
Answer: C.0.05
Explanation: Set N: there is 4 ways to chose a number
Set P: there is 5 ways to chose a number
so total outcome is 4*5 = 20 which is represent 20 pairs of number
now we have 1 pairs can give us 25 which are (11,14) .
1/20 = 0.05
Answer C
Question: Following an increase in prices, the price of a candy box was 10 pounds and the price of a can of soda was 12 pounds. If the price of a candy box was raised by 25%, and the price of a can of soda was raised by 50%. What was the price of a box of candy plus a can of soda before prices were raised?
A.11.
B.12.
C.16.
D.14.
Answer: C.16.
Explanation: Price of candy before price increase= 10/1.25= 8
Price of soda before price increase= 12/1.5= 8
Total price = 8+8= 16
C is the answer
Question: The length of the bridge, which a train 120 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
A.230
B.240
C.245
D.255
Answer: D.255
Explanation: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (120 + x)/30 = 25/2 => 2(120 + x) = 750 => x = 255 m.
Answer: Option D
Question: In the quadrilateral PQRS d=8 cm, h1=6.2 cm and
h2=3.1 cm. Find the area
A.37.2
B.22
C.23
D.24
Answer: A.37.2
Explanation: area of quad.=1/2*any diagonal*(sum of 2 perpendiculars which is drawn on that diagona)
so 1/2*8*(6.2+3.1)=37.2
ANSWER:A
Question: If small rectangular boxes, each measuring 4 inches by 7 inches by 8 inches are arranged in a rectangular box measuring 20 inches by 42 inches by 24 inches, how many smaller boxes fit into the larger box?
A.45
B.90
C.64
D.12
Answer: B.90
Explanation: The 4 inch side should be aligned to the 20 inch side ( 5 layer)
7 inch side should be aligned to the 42 inch side. (6 layer)
and 8 inch side should be aligned to the 24 inch side.(3 layer)
Maximum number of rectangles =5*6*3=90 Answer is B
Question: If a≠b and a·b≠0, which of the following may be true?
A.a/b=−b/a
B.a^2=−b^2
C.(a−b)^2<0
D.a−b=b−a
Answer: B.a^2=−b^2
Explanation: A and B are the same, but how are they wrong? Those equations still makes sense because we're not told whether a and b are integers only.
Consider a = \sqrt{-5} and b= \sqrt{5}
So, a^2 = -5
and b^2 = 5
Therefore, a^2 = - b^2 ;
ANSWER:B
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
A.22
B.77
C.36
D.71
Answer: C.36
Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.
Answer:C
Question: 9log9(2) = ?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: Exponential and log functions are inverse of each other. Hence
aloga(x) = x , for all x real and positive.
and therefore
9log9(2) = 2
correct answer B
Question: Find the average marks of all the students in classes A and B, if :
classes A = 55 students (average marks of students is 85)
classes B = 48 students (average marks of students is 78)
A.88.5
B.46.3
C.81.7
D.78.3
Answer: C.81.7
Explanation: Sum of the marks for the class of 55 students = 55 * 85 = 4675
Sum of the marks for the class of 48 students = 48 * 78 = 3744
Sum of the marks for the class of 103 students =
4675 + 3744 = 8419
Average marks of all the students =8419/103
= 81.7
Answer:C
Question: The compound ratio of 7:6, 3:2 and 4:5?
A.7:5
B.1:87
C.1:6
D.1:9
Answer: A.7:5
Explanation: 7/6 * 3/2 * 4/5 = 7/5
7:5
Answer: A
Question: There is 60% increase in an amount in 6 years at S.I. What will be the C.I. of Rs. 12,000 after 3 years at the same rate?
A.Rs. 2160
B.Rs. 3120
C.Rs. 3972
D.Rs. 6240
Answer: C.Rs. 3972
Explanation: Explanation:
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R = (100 * 60)/(100 * 6) = 10% p.a.
Now, P = Rs. 12000, T = 3 years and R = 10% p.a.
C.I. = [12000 * {(1 + 10/100)3 - 1}]
= 12000 * 331/1000 = Rs. 3972
ANSWER IS C
Question: A baker charges P dollars for a birthday cake. Next week, she intends to earn 320 dollars selling cakes. If she were to reduce the price of the cake by 20 percent, she would have to sell two more cakes to earn the same amount of revenue. How many cakes does she intend to sell next week?
A.2
B.4
C.6
D.8
Answer: D.8
Explanation: We're told that by selling cakes at P dollars/cake, a baker will make $320.
Reducing the price by 20% and selling 2 MORE cakes will also make her $320.
We're asked for the original number of cakes that the baker intends to sell.
$320 is a rather interesting number. Based on the answer choices, we're almost certainly dealing with integer values for the number of cakes AND the price per cake. As such, 6 is probably NOT going to be part of the solution (either as 4 and 6 cakes or as 6 and 8 cakes). As such, we can avoid Answers B and C....
Let's TEST ANSWER D: 8 cakes
IF....
Original cakes = 8
8(P) = $320, so P = $40/cake
20% off = $8 off = 40-8 = $32/cake
+2 more cakes = 8+2 = 10 cakes
10(32) = $320
This is an exact MATCH for what we were told, so this MUST be the answer.
Final Answer:
D
Question: present ages of A and B are in the ratio of 7:5 respectively. 5 years hence, the ratio of their ages will become 15:12 respectively . what A's present age in years?
A.20
B.7/3
C.15/4
D.21/5
Answer: D.21/5
Explanation: A and B be 7x years and 5x years respectively
(7x+5)/(5x+5)=15/12
4(7x+5)= 5(5x+5)
x = 3/5
therefore A's present age : 7x=21/5 years
correct answer(D)
Question: the reciprocal of the hcf and lcm of two are 1/12 and 1/312 .if one of the number is 24 then other no. is
A.126
B.136
C.146
D.156
Answer: D.156
Explanation: reciprocal of the hcf and lcm of two are 1/12 and 1/312
so, HCF = 12 , LCM = 312
LCM * HCF = product of two numbers = a*b => b = LCM * HCF / a
so, other = 12*312 / 24 = 156
ANSWER:D
Question: A polling company found that, of 300 households surveyed, 120 spent at least $100 per month on both gasoline and electricity, 60 spent at least $100 per month on gasoline but not on electricity, and for every household that did not spend at least $100 per month on gasoline or electricity, 4 spent at least $100 per month on electricity but not on gasoline. How many of the 300 households did not spend at least $100 per month on either gasoline or electricity?
A.24
B.30
C.36
D.90
Answer: A.24
Explanation: 120 spend $100 on gas & electricity
60 spend $100 on gas but not on electricity
For every one that spent <$100 on both there are 4 that spent $100 on electricity not gas
Let the ones that spent on neither be x
The ones that spent on just electricity will be 4x
Total households = Those who spend >$100 on both + Those who spend >$100 on just one + Those who spend <$100 on both = 120 + 60 + 4x + x
300 = 180 + 5x implies x=24
Answer is (A)
Question: How many tow-digit integers exist such that all their digits are even?
A.20
B.100
C.120
D.125
Answer: A.20
Explanation: 0 is also an even integer
so last digit can be filled in 5 ways- 0,2,4,6,8
for both second and third digit there are 5 possibilities-
5 X 5 = 25
_______________
The first digit can be any of the four: 2, 4, 6, or 8. For both seconddigits, there are 5 possibilities. The answer is 4∗5=20.
The correct answer is A
Question: In Orange County, one ninth of the people are gathering mushrooms and one seventh of the people are collecting apples. What can be the number of people in Orange County?
A.212
B.235
C.240
D.252
Answer: D.252
Explanation: The number must be a multiple of both 9 and 7 so the answer is 252.
The answer is D.
Question: Sandy purchased 20 dozen toys at the rate of $360 per dozen. Sandy sold each toy at the rate of $30.60. What was the percentage profit?
A.1%
B.2%
C.3%
D.4%
Answer: B.2%
Explanation: A dozen toys cost $360, so each toy cost $30.
selling price / cost price = 30.60 / 30 = 1.02
The percentage profit is 2%.
The answer is B.
Question: The greatest possible length which can be used to measure exactly the length 5m, 4m 45m, 10 m 45 cm is
A.15 cm
B.25 cm
C.5 cm
D.42 cm
Answer: C.5 cm
Explanation: Explanation:
Required Length = H.C.F of 500 cm, 445 cm and 1045 c
= 5 cm. Answer: C
Question: Smithtown High School is holding a lottery to raise money. The tickets are assigned numbers from 1 to 200. Tickets with numbers divisible by 2 win t-shirts, tickets with numbers divisible by 3 win gift certificates, and tickets with numbers divisible by 7 win movie passes. How many tickets win none of the prizes?
A.6
B.52
C.58
D.142
Answer: C.58
Explanation: Total numbers divisible by:
3->200/3=66.66; Ignore the decimal part=66
2->200/2=100;
7->200/7=28.Something; Ignore decimal part=28
3*2->200/6=33
3*7->200/21=9
2*7->200/14=14
3*2*7->200/42=4
Thus, total numbers that can win prize= 66+100+28-33-9-14+4=142 [:Note Used the same formula as we do for overlapping sets A∪B∪C=n(A)+n(B)+n(C)−n(A∩B)−n(A∩C)−n(B∩C)+n(A∩B∩C)
Non-winnable numbers=200-142=58
Ans: "C"
Question: Machine M, N, O working simultaneously Machine M can produce x units in 3/4 of the time it takes machine N to produce the same amount of units. Machine N can produce x units in 2/7 the time it takes machine O to produce that amount of units. If all three machines are working simultaneously, what fraction of the total output is produced by machine N?
A.1/2
B.7/13
C.4/13
D.8/29
Answer: B.7/13
Explanation: Now ultimately the speed of every machine is given with respect to Mach O.
So lets assume the speed of O, say 12 hrs to make x units (assuming 6 because we can see we will need to divide by 3 and 4
Mach O makes x units in 12 hrs
So, Mach N = 2/7 of O = 2/7*12 = 24/7 hrs to make x units
and Mach M = 3/4 of N = 3/4*24/7 = 1/6hrs to make x units
No they are running simultaneously. Lets see how much each mach makes in 1 hr
Mach O = x/12 units
Mach N = 7/24 units
Mach M = x/6 units
In 1 hr, together they make - x/12+7/24+x/6 = 13/24
So what ratio of this has Mach N made?
(7/24) / (13/24) = 7/13
Ans:B=7/13
Question: Three rugs have a combined area of 204 square meters. By overlapping the rugs to cover floor area of 140 square meters, the area that is covered by exactly two layers of rug is 24 square meters. What is the area that is covered with three layers of rug ?
A.18 square meters
B.20 square meters
C.24 square meters
D.28 square meters
Answer: B.20 square meters
Explanation: Total = Rug1 + Rug2 + Rug3 - {overlap of exactly 2 rugs} - 2*{overlap of exactly 3 rugs}
140 = 204 - 24 - 2*{overlap of exactly 2 rugs} --> {overlap of exactly 3 rugs} = 20.
Answer: B.
Question: 38 68 22 70 31 47 13 82
Which of the following numbers is greater than three fourths of the numbers but less than one fourth of the numbers in the list above?
A.56
B.68
C.69
D.71
Answer: C.69
Explanation: Arrange the numbers in ascending order:
13, 22, 31, 38, 47, 68, 70, 82 (Just cross check the count to ensure that you didn't miss anything)
How many numbers do we see?
8, alright.
What's (1/4)8?
2.
What's (3/4)8?
6.
We're asked to find a number that are greater than 6 numbers in the list AND smaller than the remaining two.
13, 22, 31, 38, 47, 68,70, 82
13, 22, 31, 38, 47, 68: Find a number greater than any of these numbers.
70, 82: Find a number smaller than any of these numbers.
Only 69 fits the description.
Ans:C
Question: A man saves Rs. 200 at the end of each year and lends the money at 5% compound interest. How much will it become at the end of 3 years?
A.Rs.662.22
B.Rs.662.20
C.Rs.662.02
D.Rs.662.12
Answer: C.Rs.662.02
Explanation: Amount = [200(1 + 5/100)3 + 200(1 + 5/100)2 + 200(1 + 5/100)]
= [200 * 21/20(21/20 * 21/20 + 21/20 + 1)]
= Rs.662.02
Answer: C
Question: Teacher took exam for English, average for the entire class was 80 marks. If we say that 10% of the students scored 95 marks and 20% scored 90 marks then calcualte average marks of the remaining students of the class.
A.60
B.70
C.65
D.75
Answer: D.75
Explanation: Lets assume that total number of students in class is 100 and required average be x.
Then from the given statement we can calculate :
(10 * 95) + (20 * 90) + (70 * x) = (100 * 80)
70x = 8000 - (950 + 1800) = 5250 ANSWER : D
x = 75.
Question: Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
A.10
B.12
C.14
D.15
Answer: B.12
Explanation: Speed of the first train =(120/10) m/sec = 12 m/sec
Speed of the second train =(120/15) m/sec = 8 m/sec
Relative speed = (12 + 8) = 20 m/sec.
Required time = (120+120)/20 sec = 12 sec
answer :B
Question: The sum of the digits of a two-digit number is 9 less than the number. Which of the following digits is at unit’s place of the number?
A.1
B.2
C.4
D.Data inadequate
Answer: D.Data inadequate
Explanation: Solution
Let the ten's digit be x and unit's digit be y. Then, (10x + y) - (x + y) = 9 or x = 1.
From this data, we cannot find y, the unit's digit. So the data is inadequate.
Answer D
Question: A dealer purchased an article at 3/4 of its list price and sold 50% more than the list price. Find his gain percent?
A.10%
B.12%
C.100%
D.18%
Answer: C.100%
Explanation: MP = 100
CP = 75
SP = 150
------
75 ---- 75
100 ---- ? => 100%
Answer:C
Question: what is next no. 11 23 47 83 131 191 263 347???
A.171
B.181
C.443
D.201
Answer: C.443
Explanation: 11+12*1=23
23+12*2=47
47+12*3=83
83+12*4=131
131+12*5=191
191+ 12*6=263
263+12*7=347
347+12*8=443
ANSWER:C
Question: The average of runs of a cricket player of 10 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 4 ?
A.76
B.79
C.85
D.87
Answer: A.76
Explanation: Explanation:
Average = total runs / no.of innings = 32
So, total = Average x no.of innings = 32 x 10 = 320.
Now increase in avg = 4runs. So, new avg = 32+4 = 36runs
Total runs = new avg x new no. of innings = 36 x 11 = 396
Runs made in the 11th inning = 396 - 320 = 76 Answer: A
Question: if A and B can do a piece of work in 10 days and A alone can do it in 15 days, how long will B take to do it?
A.20
B.30
C.35
D.40
Answer: B.30
Explanation: 1/10-1/15=1/30
30 days
ANSWER:B
Question: A and B start a business, with A investing the total capital of Rs.50000, on the condition that B pays A interest @ 10% per annum on his half of the capital. A is a working partner and receives Rs.1500 per month from the total profit and any profit remaining is equally shared by both of them. At the end of the year, it was found that the income of A is twice that of B. Find the total profit for the year?
A.59002
B.59028
C.59128
D.59000
Answer: D.59000
Explanation: Explanation:
Interest received by A from B = 10% of half of Rs.50000 = 10% * 25000 = 2500.
Amount received by A per annum for being a working partner = 1500 * 12 = Rs.18000.
Let 'P' be the part of the remaining profit that A receives as his share. Total income of A = (2500 + 18000 + P)
Total income of B = only his share from the remaining profit = 'P', as A and B share the remaining profit equally.
Income of A = Twice the income of B
(2500 + 18000 + P) = 2(P)
P = 20500
Total profit = 2P + 18000
= 2*20500 + 18000 = 59000
Answer:D
Question: Arun went for a movie nine days ago. He goes to watch movies only on Thursdays. What day of the week is today?
A.Wednesday
B.Saturday
C.Friday
D.Sunday
Answer: B.Saturday
Explanation: Explanation :
Clearly it can be understood from the question that 9 days ago was a Thursday
Number of odd days in 9 days = 2 (As 9-7 = 2, reduced perfect multiple of 7 from total days)
Hence today = (Thursday + 2 odd days) = Saturday. Answer : Option B
Question: After offering a discount of 37.5%, Pankaj sold the rice at a profit of 25%. Had he offered a discount of 41.67%, his profit or loss percent would have been:-
A.16.66% profit
B.12% loss
C.29.17% loss
D.8.33% profit
Answer: A.16.66% profit
Explanation: Explanation :
Let the Marked Price of the rice = 8p,
And the discount is 37.5% i.e 37.5%=(3/8)MP.
Thus, the Selling Price is:-
=>8p-(3/8)8p=5p.
=>5p=CP(25/100)x25.
=>CP=4p.
If he had offered a discount of 41.67%=5/12.
S.P=8p-(5/12)X8p.
=>14p/3.
The profit is:-
=>(14p/3)-4p.
=>2p/3.
Hence, the required profit percentage is :-
=>(2p/3)x100/4p.
=>(100/6)%.
=>16.66%.
Answer : A
Question: A building contractor employs 20 male, 15 female and 5 child workers. To a male worker he pays Rs.25 per day, to a female worker Rs.20 per day and a child worker Rs.8 per day. The average wage per day paid by the contractor is?
A.19
B.21
C.23
D.25
Answer: B.21
Explanation: Explanation:
20 15 5
25 20 8
500 + 300 + 40 = 840/40 = 21
B
Question: The L.C.M of two numbers is 495 and their H.C.F is 5. If the sum of the numbers is 100, then their difference is
A.19
B.10
C.28
D.27
Answer: B.10
Explanation: Let the numbers be x and (100-x).
Then,
\inline \fn_jvn \Rightarrow \inline \fn_jvn x^{2}-100x+2475=0
\inline \fn_jvn \Rightarrow (x-55) (x-45) = 0
\inline \fn_jvn \Rightarrow x = 55 or x = 45
\inline \fn_jvn \therefore The numbers are 45 and 55
Required difference = (55-45) = 10
Answer:B
Question: Alex takes a loan of $9,000 to buy a used truck at the rate of 9 % simple Interest.Calculate the annual interest to be paid for the loan amount.
A.680
B.810
C.800
D.730
Answer: B.810
Explanation: From the details given in the problem Principle = P = $9,000 and R = 9% or 0.09 expressed as a decimal.
As the annual Interest is to be calculated, the time period T =1.
Plugging these values in the simple Interest formula,
I = P x T x R
= 9,000 x 1 x 0.09
= 810.00
Annual Interest to be paid = $810
answer :B
Question: According to the directions on the can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12 ounces cans of the concentrate are required to prepare 272 6 ounces servings of orange juice?
A.a) 25
B.b) 34
C.c) 50
D.d) 67
Answer: B.b) 34
Explanation: Its B.
Total juice rquired = 272*6 = 1632 ounce
12 ounce concentate makes = 12 * 4 = 48 ounce juice
Total cans required = 1632/48 = 34.
Answer B
Question: The value of (256)5/4 is:
A.11 hrs 562 min
B.3 hrs 860 min
C.7 hrs 1020 min
D.7 hrs 1024 min
Answer: D.7 hrs 1024 min
Explanation: Sol.
(256)5/4 = (44)5/4 = 4(4*5/4) = 45 = 1024.
Answer D
Question: The cross-section of a cannel is a trapezium in shape. If the cannel is 12 m wide at the top and 2 m wide at the bottom and the area of cross-section is 4200 sq m, the depth of cannel is?
A.500
B.600
C.700
D.800
Answer: B.600
Explanation: 1/2 * d (12 + 2)
= 4200
d = 600
Answer: B
Question: If the LCM of 7, 10, 3, and x is 210, which of the following could be x?
A.13
B.6
C.21
D.2
Answer: C.21
Explanation: Using elimination method, eliminate the option to arrive at 21
if x is replaced by 21 and the LCM is calculated you arrive at 210
C
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 51
kmph, find the speed of the stream?
A.16 kmph
B.19 kmph
C.14 kmph
D.17 kmph
Answer: D.17 kmph
Explanation: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream
= (2+1)/(2-1) = 3/1
= 3:1
Speed of the stream
= 51/3 = 17 kmph.
Answer: D
Question: (w^2+x^2)x(y^2+z^2) is always divisible by which of the max no. Where w;x;y;z are odd integers?
A.20
B.8
C.4
D.2
Answer: C.4
Explanation: ((odd)^2+(odd)^2)*((odd)^2+(odd)^2)
(even)*(even)
2*2
4
ANSWER:C
Question: A pipe can fill a cistern in 20 minutes whereas the cistern when fill can be emptied by a leak in 40 minutes. When both pipes are opened, find when the cistern will be full?
A.17 minutes
B.87 minutes
C.40 minutes
D.27 minutes
Answer: C.40 minutes
Explanation: 1/20 - 1/40 = 1/40
40 minutes
Answer:C
Question: A 150 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
A.220 meter
B.225 meter
C.230 meter
D.350 meter
Answer: D.350 meter
Explanation: Explanation:
As trains are running in opposite directions so their relative speed will get added
So, Relative speed = 120 +80 = 200 kmph
= 200*(5/18) = 500/9 m/sec
Let the length of other train is x meter then
x+150 /9=500 /9
=>x+150=500
=>x=350
So the length of the train is 350 meters
Option D
Question: Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in scheme B?
A.Rs.6400
B.2878
C.2899
D.2660
Answer: A.Rs.6400
Explanation: Let the sum invested in scheme A be Rs. x and that in scheme B be Rs. (13900 - x). Then,
(x * 14 * 2)/100 + [(13900 - x) * 11 * 2]/100 = 3508
28x - 22x = 350800 - (13900 * 22)
6x = 45000 => x = 7500
So, sum invested in scheme B = (13900 - 7500) = Rs. 6400.Answer:A
Question: In how many ways Chief Minister and Minister be elected from a team of 6 members?
A.124
B.29
C.30
D.154
Answer: C.30
Explanation: To do this, if captain is elected first, then we have 6 ways of doing this.
For election of vice-captain, we have only 5 ways left, coz 1 way is already consumed. (Situations like this is called dependent situation. One selection depends upon other selection.)
So, the ans is 6*5 = 30 ways.
C
Question: In shop contains some articles each of a cost of $5. He sold them at a price of $10. If the shop keeper has a order of 150 articles, how much profit he will get?
A.200
B.250
C.750
D.1000
Answer: C.750
Explanation: Total money after selling articles = 150*10 = 1500
cost price = 150*5 = 750
profit = 750
correct option is C
Question: With # andeach representing different digits in the problem below, the difference between #and ## is 623. What is the value of?
#
-##
___
623
A.7
B.8
C.9
D.10
Answer: A.7
Explanation: 100x
-(10x +x)
-----------
89 x= 667
x = 7
A
Question: A Certain item costs to Harris $50. At what price must the merchant sell this item in order to make a profit of 10% ?
A.$50
B.$55
C.$65
D.$60
Answer: B.$55
Explanation: Cost Price = $50
Profit % = 10
Selling Price = ?
Selling Price = (100 + profit %) * Cost Price /100
= (100 + 10) * 50 / 100
= 55
Answer is B
Question: How many words can be formed from the letters of the word ‘EXTRA’ so that the vowels are never together?
A.72
B.24
C.48
D.120
Answer: A.72
Explanation: The given word contains 5 different letters.
Taking the vowels EA together, we treat them as one letter.
Then, the letters to be arranged are XTR (EA).
These letters can be arranged in 4! = 24 ways.
The vowels EA may be arranged amongst themselves in 2! = 2 ways.
Number of words, each having vowels together = (24x2) = 48 ways.
Total number of words formed by using all the letters of the given words
= 5! = (5x4x3x2x1) = 120.
Number of words, each having vowels never together = (120-48) = 72
ANSWER A 72