RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A normal six-sided die bearing the numbers 1, 2, 3, 4, 5, and 6 is thrown until the running
total surpasses 6. What is the most likely total that will be obtained?
A.7
B.8
C.9
D.10
Answer: A.7
Explanation: The total before the last throw could be any number between one and six. The last
throw will also be a number between one and six but with equal probability. Seven is the only
final total that can come from each of these possibilities. Therefore seven is the most likely
final total.
correct answer A
Question: Mike earns $12per hour and Phil earns $6 per hour. Approximately how much less, as a percentage, does Phil earn than Mike per hour?
A.50%
B.32.5%
C.37%
D.37.5%
Answer: A.50%
Explanation: What % less of 12 is 6
let it be x % less ,then
=12(1-x/100)=6
1-x/100=6/12
x=100/2
x=50%
Ans A
Question: A man can row 4.2 km/hr in still water. It takes him twice as long to row upstream as to row downstream. What is the rate of the current ?
A.1.9
B.1.7
C.1.4
D.1.5
Answer: C.1.4
Explanation: Speed of boat in still water (b) = 4.2 km/hr. Speed of boat with stream (Down Stream), D = b + u Speed of boat against stream (Up stream), U = b – u It is given upstream time is twice to that of down stream. ⇒ Downstream speed is twice to that of upstream. So b + u = 2(b – u) ⇒ u =b/3 = 1.4 km/hr.
Answer: C
Question: A candidate scoring 25% in an examination fails by 30 marks , while another candidate scores 50 % mark, gets 20 marks more than the minimum pass marks . Find the minimum pass marks. Find the minimum pass percentage.
A.40
B.50
C.60
D.25
Answer: A.40
Explanation: x/4+30 = x/2-20
maximum marks = 200
min pass marks = 200/4+30 = 80
=>80/200*100=40%
ANSWER A
Question: If a man buys 20 lollipops for $90 and sold them for $2 dollars determine his loss.
A.$35
B.$43
C.$50
D.$65
Answer: C.$50
Explanation: Cost of 20 lollipops = $90
Sold each lollipop for $2
So he sold 20 lollipops for $(20 × 2) = $40
Loss = $(90 – 40) = $50
Therefore, loss = $ 50.
Question: Michelle has $80 to buy a new outfit. She found a skirt for $20, a blouse
for $25, and a belt for $8. How much does she have left to buy shoes?
A.$27 left.
B.$37 left.
C.$47 left.
D.$57 left.
Answer: A.$27 left.
Explanation: 80 – 20 – 25 – 8 = 27
She has $27 left.
correct answer A
Question: A container holding 12 ounces of a solution that is 1 part alcohol to 2 parts water is added to a container holding 8 ounces of a solution that is 1 part alcohol to 3 parts water. What is the ratio of alcohol to water in the resulting solution?
A.2:5
B.3:7
C.3: 5
D.4:7
Answer: B.3:7
Explanation: Container 1 has 12 ounces in the ratio 1:2
or,
x+2x=12 gives x(alcohol)=4 and remaining water =8
container 2 has 8 ounces in the ratio 1:3
or,
x+3x=8 gives x(alcohol)=2 and remaining water =6
mixing both we have alcohol=4+2 and water =8+6
ratio thus alcohol/water =6/14=3/7
ANSWER:B
Question: The ratio of men to women in a class is 4 to 3. If 2 men and 7 woman drop out of the class and the ratio of men to women after the drop out is 2 to 1, then how many men are currently in the class?
A.22
B.20
C.18
D.19
Answer: A.22
Explanation: Equation on the basis of question
4x-2/3x-7=2/1
x=6
Original number of men = 4*6=24
Original Number of Women = 3*6=18
Current number of men = 24-2=22 (Answer)
Current number of women = 18-7=11
Ratio = 22/11= 2/1 ( Just to verify)
Ans A
Question: In a certain store, the profit is 320% of the cost. If the cost increases by 35% but the selling price
remains constant, approximately what percentage of the selling price is the profit
A.68%
B.80%
C.90%
D.100%
Answer: A.68%
Explanation: Explanation:
Let C.P.= Rs. 100.
Then, Profit = Rs. 320,
S.P. = Rs. 420.
New C.P. = 135% of Rs. 100 = Rs. 135
New S.P. = Rs. 420.
Profit = Rs. (420 - 135) = Rs. 285
Required percentage = (285/420) * 100
= 68%(approx)
Answer: A
Question: A, B and C are partners. A receives 2/3 of profits, B and C dividing the remainder equally. A's income is increased by Rs.200 when the rate to profit rises from 5 to 7 percent. Find the Capital of B?
A.3989
B.2772
C.2500
D.2888
Answer: C.2500
Explanation: A:B:C = 2/3:1/6:1/6 = 4:1:1
x * 2/100 * 2/3 = 200
B capital = 15000*1/6 = 2500
Answer: C
Question: A factory produced 2300 TV sets in its first year of production. 4500 sets were produced in its second year and 500 more sets were produced in its third year than in its second year. How many TV sets were produced in three years?
A.11,800
B.15,900
C.13,250
D.17,900
Answer: A.11,800
Explanation: 500 TV sets were produced in the third year than in the second year. The number of sets produced in the third year is equal to
4,500 + 500 = 5,000
The number of TV sets produced in three years is equal to sum of the number of TV sets produced in each year
2,300 + 4,500 + 5,000 = 11,800
correct answer A
Question: How many terms are in the G.P. 3, 6, 12, 24, ......., 384 ?
A.8
B.9
C.67
D.5
Answer: A.8
Explanation: Explanation:
Here a = 3 and r = 6/3 = 2. Let the number of terms be n.
Then, t = 384 => a * r^(n-1) = 384
=> 3 * 2^(n-1) = 384 => 2^(n-1) = 128 = 2^(7)
=> n-1 = 7 => n = 8.
Answer: A) 8
Question: A Baker decides to make a cake of 5 layers, one of strawberry, chocolate, butterscoch, vanila and pista. Baker decides not to put the layers of butterscoch and vanila next to each other as they both are white in colour. How many different type of such cakes can he make?
A.5! - (4!×2!)
B.4! - (6!×2!)
C.3! - (2!×4!)
D.4! - (4!×2!)
Answer: A.5! - (4!×2!)
Explanation: We can find the answer by substracting the number of arrangements in which V and B comes together from the total number of arrangements of 5 layers. Arrangements in which V and B comes next to each other: We can consider V and B as a single object having 2! Variations(VB and BV). VB, S, C, P can be arranged in 4! Ways. In total there are 4!×2! Ways of arranging 5 layers with B and V layers coming next to each other. Required answer = A. 5! - (4!×2!)
Question: Two trains start from a certain place on two parallel tracks in the same directions. The speed of the trains are 45km/hr. and 40km/hr. respectively. The distance between the two trains after 45 minutes will be
A.2 km 500 m
B.2 km 750 m
C.3 km 750 m
D.3 km 250 m
Answer: D.3 km 250 m
Explanation: Explanation:
In one hour the distance between the trains is 5 km.
In 45 mins = ¾ hour the distance would be equal to ¾ X 50
= 3.75 Km = 3 Km 750 m.
Answer D
Question: 550, 620, 589, 100, 560, 50, 100
Which of the following numbers is lower than the median but greater than the mean of the set of the numbers in the list?
A.200
B.310
C.480
D.550
Answer: C.480
Explanation: Yes, it can be solved with observation even without approximation in 30 sec.
Just observe given numbers: 50,100 ,100,550, 560, 580,620,
Median is very easy to tell - its 550. Now we want a number lower than 550 and greater than mean. How many numbers are lower than 550? DE are already out.
Now, we have 200, 310 and 480 and we want a number among these which is greater than mean. logically whatever be the mean, if one value out of these 5 has to be greater than mean it has to be 480. (Notice, if 200 is more than mean then 480 is also. If 31 is more than mean, 480 is also. )
Hence C it is!
Question: A rectangle having length 89 cm and width 34 cm. If the length of the rectangle is increased by eighty percent then how much percent the breadth should be decreased so as to maintain the same area.
A.25%
B.33.33%
C.47.33%
D.75%
Answer: C.47.33%
Explanation: Explanation :
Solution: (80/(89+80) * 100)% = 47.33%
Answer : C
Question: In a game of 80 points. A can give B 5 points and C 15 points. Then how many points B can give C in a game of 60?
A.9 points
B.6 points
C.8 points
D.10 points
Answer: C.8 points
Explanation: A can give B 5 points :- A / B = 80 / 75
A can give C 15 points :- A / C = 80/ 65
B can give C a points of ( B / A ) * ( A / C)
(75 / 80) * ( 80 / 65)
(75 / 65) = 15/13
As we have to find in a game of 60 , so multiply numerator and denominator with 4 such that the ratio becomes 60/52
therefore B can give C of (60-52) = 8 points
ANSWER:C
Question: In a jar there are 20 white balls, 24 green balls and 30 blue balls. How many balls must be taken out in order to make sure we have 21 balls of the same color?
A.a)	23
B.b)	46
C.c)	57
D.d)	60
Answer: D.d)	60
Explanation: Here, we need to find minimum number of marbles to be taken out to get 21 marbles of same color.
For a instance, if we take 19 white marbles 1st and followed by 20 Green and then 20 Blue.
Total will be 19 + 20+ 20= 59 draws.
If we choose either Green or Blue next time. This will bring the total of either of these colored marble to 21.
So Minimum we need to take 59+1 = 60 Times to get 21 marbles of same color(either Green or Blue).
Answer : D.
Question: A bowl of nuts is prepared for a party. Brand P mixed nuts are 20% almonds and Brand Q's Deluxe nuts are 25% almonds. If a bowl contains a total of 65 ounces of nuts, representing a mixture of both brands, and 15 ounces of the mixture are almonds, how many ounces of Brand Q's Deluxe mixed nuts are used?
A. 16
B. 20
C. 32
D. 40
Answer: D. 40
Explanation: lets say x ounces of P is mixed with Q.
=> 65-x ounces of Q is present in the mixture (as the total = 65 ounces)
given total almond weight = 15 ounces
(20x/100)+(25/100)(65-x) = 15
=> x = 25
=> 65-25 = 40 ounces of Q is present in the mixture.
Answer is D.
Question: Product of two natural numbers is 17. Then, the sum of reciprocals of their squares is
A.290/289
B.1/289
C.290/90
D.290/19
Answer: A.290/289
Explanation: Explanation:
If the numbers are a, b, then ab = 17,
as 17 is a prime number, so a = 1, b = 17.
1/a2+1/b2=1/1(2)+1/17(2)
=290/289
Option A
Question: Based on this year's costs, an orcharde grower budgets P dollars for planing N new trees next year. If the average cost of planting each tree were to increase 10% from this year's cost, then the greatest number of trees that the orchard grower could plant next year using P dollars would be
A.9% less than N
B.25% less than N
C.equal to N
D.20% greater than N
Answer: A.9% less than N
Explanation: Correct answer is (A).
This year, the price of a tree is price1=P/N.
If this price increases by 10% it becomes price2=P/N*1.10
Then with P dollars, you can grow P/price2 tress i.e. P/(P/N*1.10) i.e. N/1.1 i.e. .91%
Question: If 4x=6y=z, what is x+y, in terms of z?
A.z/2
B.5z/12
C.z/3
D.3z/5
Answer: B.5z/12
Explanation: 4x=6y=z
x = z/4
and y = z/6
x+y = z/4 + z/6 = 5z/12
Answer is B
Question: By walking at 3/4th of his usual speed, a man reaches office 15 minutes later than usual. What is his usual time?
A.45min
B.50min
C.65min
D.60min
Answer: A.45min
Explanation: let T be the usual time.
time spent=4T/3
therefore, 4T/3=T+15
4T=3T+45..therefor T=45min
ANSWER:A
Question: the sides of a triangle are in the ratio 37.if the perimeter is 60 cms, the longest side is
A.7
B.30
C.28
D.14
Answer: C.28
Explanation: Triangle property: sum of any two sides is always greater than the third one.
and Here we have been asked for longest side...
now we can have longest side as 29 or 28 but not 30
because 31>29 and 32>28 is true but 30>30 is not true
hence Answer is 28
ANSWER:C
Question: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?
A.4:3:2
B.4:2:3
C.3:2:4
D.2:3:4
Answer: D.2:3:4
Explanation: Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).
= (140/100 x 5x), (150/100 x 7x) and (175/100 x 8x)
= 7x, 21x/2 and 14x.
Therefore, The required ratio = 7x : 21x/2 : 14x
= 14x : 21x : 28x
= 2 : 3 : 4.
Answer is D.
Question: When a number is divided by 6 &then multiply by 12 the answer is 9 what is the no.?
A.4.5
B.5
C.5.6
D.5.7
Answer: A.4.5
Explanation: if $x$ is the number, x/6 * 12 = 9
=> 2x = 9
=> x = 4.5
A
Question: In a is a positive integer smaller than 200 and (14a)/60 is an integer, then a has how many different positive prime factors?
A.2
B.3
C.5
D.6
Answer: B.3
Explanation: 7a/30 tells us that a is a factor of 30, which has 2, 3, and 5 as its prime factors. Each of them is distinct. Moreover, all multiples of 30 less than 200 can be derived by multiplying these prime factors alone. Thus, number of different prime factors is 3.
Answer: B
Question: A thief goes away with a MARUTHI car at a speed of 40 kmph. The theft has been discovered after half an hour and the owner sets off in a bike at 50 kmph when will the owner over take the thief from the start ?
A.8 hrs
B.2 hrs
C.5 hrs
D.4 hrs
Answer: B.2 hrs
Explanation: Explanation:
|-----------20--------------------|
50 40
Difference = 20kms
Relative Speed = 50 â€“ 40 = 10 kmph
Time = 20/10 = 2 hours.
Answer: B
Question: A room is 7 meters 68 centimeters in length and 4 meters 32 centimeters in Width. Find the least number of square tiles of equal size required to cover the entire floor of the room.
A.107
B.144
C.175
D.165
Answer: B.144
Explanation: Let us calculate both the length and width of the room in centimeters.
Length = 7 meters and 68 centimeters = 768 cm
width = 4 meters and 32 centimeters = 432 cm
As we want the least number of square tiles required, it means the length of each square tile should be as large as possible.Further,the length of each square tile should be a factor of both the length and width of the room.
Hence, the length of each square tile will be equal to the HCF of the length and width of the room = HCF of 768 and 432 = 48
Thus, the number of square tiles required = (768 x 432 ) / (48 x 48) = 16 x 9 = 144
Answer: B
Question: In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is 2/3 of the number of students of 8 years of age which is 48. What is the total number of students in the school?
A.100
B.102
C.110
D.90
Answer: A.100
Explanation: Explanation :
Let the total number of students = x
Given that 20% of students are below 8 years of age
then The number of students above or equal to 8 years of age = 80% of x -----(Equation 1)
Given that number of students of 8 years of age = 48 -----(Equation 2)
Given that number of students above 8 years of age = 2/3 of number of students of 8 years of age
=> number of students above 8 years of age = (2/3) × 48 = 32-----(Equation 3)
From Equation 1,Equation 2 and Equation 3,
80% of x = 48 + 32 = 80
⇒ 80x/100 = 80
⇒ x/100 = 1
⇒ x = 100
Answer : Option A
Question: If a number p is prime, and 2p+5 = q, where q is also prime, then the decimal expansion of 1/q will produce a decimal with q-1 digits. If this method produces a decimal with 166 digits, what is the units digit of the product of p and q?
A.1
B.3
C.5
D.7
Answer: A.1
Explanation: 1/7 = 014285... (a repeating pattern one digit long)
A
Question: Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000?
A.81000
B.81028
C.81287
D.29766
Answer: A.81000
Explanation: 64000* 9/8 * 9/8
= 81000
Answer: A
Question: In a certain population, there are 4 times as many people aged thirtty-one or under as there are people over thirtty-one. The ratio of those thirty-one or under to the total population is
A. 1 to 2
B. 1 to 3
C. 4 to 5
D. 2 to 3
Answer: C. 4 to 5
Explanation: Consider the ratio of the under population of 21 to over the 21 as 4:1
therefore 4x:1X
Now the ratio of the under to the whole population becomes 4x/4x+1x
= 4/5
Answer is C
Question: 18 men can complete a piece of work in 20 days. In how many days can 15 men complete that piece of work?
A.23
B.27
C.20
D.24
Answer: D.24
Explanation: 18 * 20 = 15 * x => x = 24 days
Answer:D
Question: A train covers the first 16 km at a speed of 20 km per hour another 20 km at 40 km per hour and the last 10 km at 15 km per hour. Find the average speed for the entire journey.
A.24 km
B.26 km
C.21 km
D.23(23/59) km
Answer: D.23(23/59) km
Explanation: Solution: Average speed = total distance covered/ total time
Total distance = (16+40+10) = 46 km
Time taken = (16/20)+ (20/40)+ (10/15) = 59/30
Average speed = 46*30/59 = 23(23/59) km/hr.
Answer: Option D
Question: A large tanker can be filled by two pipes A and B in 60 and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?
A.67 min
B.45 min
C.97 min
D.30 min
Answer: D.30 min
Explanation: Part filled by (A + B) in 1 minute
= (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40)
= 1
x/2 * 1/15 = 1 => x
= 30 min.
Answer: D
Question: If a no. when divided by 44, gives 432 as quotient and 0 as remainder. What will be the remainder when dividing thesame no. by 31
A.1
B.3
C.5
D.7
Answer: C.5
Explanation: P ÷ 44 = 432
=> P = 432 * 44 = 19008
P / 31 = 19008 / 31 = 613, remainder = 5
C
Question: 4 dice are thrown simultaneously on the board. Find the probability show the same face.
A.1/209
B.1/211
C.1/216
D.1/117
Answer: C.1/216
Explanation: The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:
=6×6×6×6=64=6×6×6×6=64
n(S)=64n(S)=64
Let XX be the event that all dice show the same face.
X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}
n(X)=6n(X)=6
Hence required probability,
=n(X)n(S)=664=n(X)n(S)=664
=1/216
C
Question: 3 candidates in an election and received 1136, 8236 and 11628 votes respectively. What % of the total votes did the winning candidate gotin that election?
A.40%
B.55.4%
C.57%
D.60%
Answer: B.55.4%
Explanation: Total number of votes polled = (1136 + 8236 + 11628) = 21000
So, Required percentage = 11628/21000 * 100 = 55.4%
B
Question: There were 35 students in a hostel. Due to the admission of 7 new students, ;he expenses of the mess were increased by Rs. 42 per day while the average expenditure per head diminished by Rs 1. What was the original expenditure of the mess?
A.320
B.120
C.400
D.420
Answer: D.420
Explanation: Sol. Let the original average expenditure be Rs. x. Then,
42 (x - 1) - 35x=42		7x= 84		x =12.
Original expenditure = Rs. (35 x 12) =Rs. 420. .
ANSWER D
Question: What is the sum of natural numbers between 20 and 100
A.4800
B.4860
C.5000
D.5500
Answer: B.4860
Explanation: a = first number
l = last number
Sn = n/2[a + l]
between 20 and 100 numbers = 81 => 100 - 20 = 80 + 1 = 81
Sn = 81/2 × 120 = 81 × 60 = 4860
B)
Question: Three partners A,B,C starts a business. Twice A's capital is equal to thrice B's capital and B's capital is four times C's capital. Out of a total profit of Rs.12000 at the end of the year, B's share is
A.Rs.4000
B.Rs.4320
C.Rs.7500
D.Rs.6600
Answer: B.Rs.4320
Explanation: Solution
Let C = x.
Then, B = 4x and 2A = 3x4x = 12x or A = 6x.
âˆ´ A : B : C = 6x : 4x : x	= 6 : 4 : 1.
So B's capital	= Rs(12000 x 4 / 11)
= Rs.4320.
Answer B
Question: An plane covers a distance at a speed of 180 kmph in 5 hours. To cover the same distance in 3/2 hours, it must travel at a speed of ?
A.100
B.200
C.720
D.600
Answer: D.600
Explanation: We know
Distance = speed * time
= 180 * 5
= 900 km
Now to cover 900 km in 3/2 hrs ,
speed = distance / time
= 900 / (3/2)
= 600 KMPH
Ans- D
Question: A Water Heater is available for $39000 cash or $17000 as down payment followed by five equal monthly instalments of $4800 each. The simple rate of interest per annum under the instalment plan would be
A.18%
B.19%
C.21.2%
D.21.81%
Answer: D.21.81%
Explanation: Simple interest SI = (P*R*T)/100
where P is the principal amount
R is the rate of interest
and T is time in years
the way I see it: Water Heater on down payment of 17,000, customer is not paying any interest. it is the remaining sum which will be paid for 5 months that will bear an interest. Therefore, the principal amount for which interest is being charged is 39,000 - 17,000 = 22,000
For this 22,000 a total sum of 5*4800 = 24,000 was pain. (Time is five months, so T = 5/12, as T is in years.)
thus, SI = 2000 or
2000 = (P*R*T)/100
2000 = (22,000*R*5)/(100*12)
R = (2,000*12*100)/22,000*5
R = 21.81%
Therefore answer is D
Question: In a business there are three partners sum of A and B investments to total investment is in the ratio 4 : 5, and sum of B and C investments to total investment is in the ratio 4 : 5, then which of the following is correct with regard to investments, if investments of two of the partners are equal ?
A.A = B
B.B = C
C.A = B = C
D.B > (A + C)
Answer: D.B > (A + C)
Explanation: If ( A + B ) : ( A + B + C ) = 4 : 5, then C = 5 – 4 = 1 unit
If ( B + C ) : ( A + B + C ) = 4 : 5, then A = 5 – 4 = 1 unit
Therefore B = ( A + B + C ) – ( A + C ) = 5 – 2 = 3
Clearly B > ( A + C )
Option D
Question: One millisecond is 0.001 of a second. The costs for a single run of a computer program are $1.36 for operating-system overhead, $0.023 per millisecond of computer time, and $4.35 for the mounting of a data tape. What is the total of these three costs for 1 run of a program that requires 1.5 seconds of computer time ?
A. $7.15
B. $8.87
C. $35.96
D. $40.21
Answer: D. $40.21
Explanation: Operating system overhead for 1 run = 1.36 $
Mounting of data tape = 4.35$
Cost per 1 millisecond of computer time = .023 $
Total cost of 1 run of a program that requires 1.5 seconds of computer time
= 1.36 + (.023*1500) + 4.35
=1.36 + 34.5 + 4.35
= 40.21$
Answer D
Question: 15 times a positive integer is more than its square by 56, then the positive integer is
A.13
B.8
C.11
D.12
Answer: B.8
Explanation: Explanation:
Let the number be x. Then,
15x = x2 + 56
=> x2 - 15x + 56 = 0
=>(x - 7)(x - 8) = 0
=> x = 7 or 8
Answer: Option B
Question: if a@b = a * b^(1/2) then 2@9 = ?
A.2
B.6
C.3
D.8
Answer: B.6
Explanation: a@b = a * b^(1/2)
2@9 = 2*9^(1/2) = 2*3 = 6
Correct Option: B
Question: Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 2 litres from vessel P is mixed with 8 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is?
A.33:1
B.33:7
C.33:8
D.33:5
Answer: B.33:7
Explanation: Quantity of alcohol in vessel P = 62.5/100 * 2 = 5/4 litres
Quantity of alcohol in vessel Q = 87.5/100 * 4 = 7/1 litres
Quantity of alcohol in the mixture formed = 5/4 + 7/1 = 33/4 = 8.25 litres
As 10 litres of mixture is formed, ratio of alcohol and water in the mixture formed
= 8.25 : 1.75 = 33:7.
Answer: B
Question: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
A.127.8 m
B.127.5 m
C.127.5 m
D.227.5 m
Answer: B.127.5 m
Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.
In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000
= 127.5 m.
Answer: B
Question: The sum of money will be double itself in 40 years and simple interest find rate of interest?
A.A)1.5%
B.B)2.5%
C.C)3.5%
D.D)4.5%
Answer: B.B)2.5%
Explanation: T = 40 years
P= principle amount = x
A = total amount = 2x
SI = simple interest = A-P = 2x-x = x
R = 100SI/PT = 100x/40x =2.5%
Answer is B
Question: In the biology lab of "Jefferson" High School there are 0.036*10^5 germs, equally divided among 18000*10^(-3) Petri dishes. How many germs live happily in a single dish?
A.100
B.200
C.300
D.400
Answer: B.200
Explanation: 0.036*10^5 can be written as 3600
18000*10^(-3) can be written as 18
Required= 3600/18= 200
ANSWER:B
Question: 1/0.05 is equal to
A.25.5
B.2.5
C.25
D.20
Answer: D.20
Explanation: Explanation:
1/0.05 = (1 * 100)/5 = 100/5 = 20
Option D
Question: A man buys an article and sells it at a profit of 5%. If he had bought it at 5% less and sold it for Rs.25 less, he could have gained 5%. What is the cost price?
A.197
B.476
C.279
D.278
Answer: B.476
Explanation: CP1 = 100 SP1 = 105
CP2 = 95 SP2 = 95 * (105/100) = 99.75
5.25 ----- 100
25 ----- ? => 476
Answer:B
Question: The length of a bridge in meters, which a train 110-meters long and traveling at 45 km/hr can cross in 30 seconds is?
A.245
B.265
C.295
D.325
Answer: B.265
Explanation: 45 km/h = 45000 m/3600 s = 12.5 m/s
In 30 seconds, the train can go 30(12.5) = 375 meters
Let x be the length of the bridge.
x+110 = 375 meters
x = 265 meters
The answer is B.