RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: John and Ingrid pay 30% and 40% tax annually, respectively. If John makes $58000 and Ingrid makes $72000, what is their combined tax rate?
A.32%
B.34.4%
C.35%
D.35.6%
Answer: D.35.6%
Explanation: (1) When 30 and 40 has equal weight or weight = 1/2, the answer would be 35.
(2) When 40 has larger weight than 30, the answer would be in between 35 and 40. Unfortunately, we have 2 answer choices D and E that fit that condition so we need to narrow down our range.
(3) Get 72000/130000 = 36/65. 36/65 is a little above 36/72 = 1/2. Thus, our answer is just a little above 35.
Answer: D
Question: If x is divisible by 6 and 5, which of the following must divide evenly into x? I. 64 II. 32 III. 15
A.I only
B.II only
C.III only
D.II,III only
Answer: C.III only
Explanation: If x is divisible by 6,5 means it will be = or > 30, 60,90 etc...
That are not divisible by 32, 64.
So, the answer is C
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
A.65 km/hr
B.50 km/hr
C.21 km/hr
D.25 km/hr
Answer: B.50 km/hr
Explanation: Speed of the train relative to man
= (125/10) m/sec
= (25/2) m/sec. [(25/2) * (18/5)] km/hr
= 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed
= (x - 5) km/hr. x - 5 = 45 ==> x
= 50 km/hr.
Answer: B
Question: How many numbers between 400 and 1000 can be made with the digits 2,3,4,5,6 and 0?
A.30
B.60
C.90
D.120
Answer: B.60
Explanation: Required number = 3 * 5P2 = 3*20 = 60
Answer is B
Question: The length of a train and that of a platform are equal. If with a speed of 144 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
A.757
B.758
C.718
D.1200
Answer: D.1200
Explanation: Speed = [144 * 5/18] m/sec = 40 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 40 è x = 40 * 60 / 2
=1200
Answer:D
Question: A train running at the speed of 60 km/hr crosses a pole in 15 sec. What is the length of the train?
A.118
B.150
C.277
D.250
Answer: D.250
Explanation: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 15 = 250 m
Answer: D
Question: The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.6270.What was his original salary?
A.6000
B.2999
C.1000
D.2651
Answer: A.6000
Explanation: X * (110/100) * (95/100) = 6270
X * (11/10) * (1/100) = 66
X = 6000
Answer: A
Question: The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
A.1%
B.2%
C.3%
D.5%
Answer: D.5%
Explanation: D
5%
Increase in 10 years = (262500 - 175000) = 87500.
Increase% = (87500/175000 x 100)% = 50%.
Required average = (50/10)% = 5%.
Question: Find the cost of fencing around a circular field of diameter 42 m at the rate of Rs.3 a meter?
A.138
B.390
C.393
D.279
Answer: C.393
Explanation: 2 * 22/7 * 21 = 131
131 * 3
= Rs.393
Answer: C
Question: The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
A.4 years
B.6 years
C.8 years
D.10 years
Answer: A.4 years
Explanation: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Answer: Option A
Question: A, B and C rents a pasture for Rs.841. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should C pay?
A.270
B.279
C.276
D.261
Answer: D.261
Explanation: 12*8 :16*9 = 18*6
8: 12: 9
9/29 * 841 = 261
Answer: D
Question: Find the numbers which are in the ratio 3 : 2 : 4 such that the sum of the first and the second added to the difference of the third and the second is 21 ?
A.9, 6, 11
B.9, 6, 17
C.9, 6, 19
D.9, 6, 12
Answer: D.9, 6, 12
Explanation: Let the numbers be a, b and c.
Given that a, b and c are in the ratio 3 : 2 : 4.
let, a = 3x, b = 2x and c = 4x
Given, (a+b) + (c - b) = 21
= > a + b + c - b = 21 = > a + c = 21
= > 3x + 4x = 21 = >7x = 21 = > x = 3
a , b , c are 3x, 2x, 4x.
a, b, c are 9 , 6 , 12.
Answer: D
Question: The owner of a furniture shop charges his customer 100% more than the cost price. If a customer paid Rs. 1000 for a computer table, then what was the cost price of the computer table?
A.800
B.650
C.500
D.600
Answer: C.500
Explanation: CP = SP * (100/(100 + profit%))
= 1000(100/200) = Rs. 500.
Answer: C
Question: Find the unit's digit in 264^102+264^103
A.0
B.2
C.3
D.5
Answer: A.0
Explanation: Required unit's digit = unit's digit in 4102+4103.4102+4103.
Now, 4242 gives unit digit 6.
⇒ 41024102 gives unit digit 6.
⇒ 41034103 gives unit digit of the product 6×46×4 i.e., 4.
Hence, unit's digit in 264102+264103264102+264103
= unit's digit in (6+4)=0
A
Question: A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 5:3 and B:C = 5:2. If the total runs scored by all of them are 60, the runs scored by B are?
A.20.23
B.20.13
C.30.93
D.19.56
Answer: D.19.56
Explanation: A:B = 5:3
B:C = 5:2
A:B:C = 25:15:6
15/46 * 60 = 19.56
ANSWER:D
Question: A boy incurs 5% loss by selling a book for Rs. 1000. At what price should the book be sold to earn 5 % profit?
A.Rs. 1105.26
B.Rs. 1251.50
C.Rs. 1085.13
D.Rs. 1885.13
Answer: A.Rs. 1105.26
Explanation: Explanation:
Let the new selling price be Rs. x
(100 – loss %) /1000 = (100 + gain %) / x
(100 – 5) / 1000 = (100 + 5) / x
x = (105 × 1000) / 95 = 105000 / 95
x = 1105.26.
ANSWER A
Question: In a store, the profit is 320% of the cost. If the cost increases by 25% but the SP remains constant, approximately what % of the sellingprice is the profit?
A.50%
B.70%
C.90%
D.100%
Answer: B.70%
Explanation: Let C.P. = Rs. 100. Then, profit = Rs. 320, S.P. = Rs. 420
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 420
Profit = 420 - 125 = Rs. 295
Required percentage = 295/420 * 100 = 1475/21 = 70%
B
Question: The average of ten numbers is 0. In those 10, at the least, how many may be greater than or equal to zero?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: Explanation :
Average of 10 numbers = 0
Sum of 10 numbers =(0 x 10) =0.
It is quite possible that 9 of these numbers may be negative and if there sum is -a, then 10th number is (a).
Answer : B
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 57 kmph, find the speed of the stream?
A.16 kmph
B.19 kmph
C.14 kmph
D.11 kmph
Answer: B.19 kmph
Explanation: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream
= (2+1)/(2-1) = 3/1
= 3:1
Speed of the stream
= 57/3 = 19 kmph.
Answer: B
Question: In the county of Veenapaniville, there are a total of 50 high schools, of three kinds: 25 public schools, 16 parochial schools, and 9 private independent schools. These 50 schools are divided between three districts: A, B, and C. District A has 18 high schools total. District B has 17 high schools total, and only one of those are private independent schools. If District C has an equal number of each of the three kinds of schools, how many private independent schools are there in District A?
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: Total Private Schools = 9
Dist A: High Schools = 18 ==> Private Schools = ?
Dist B: High Schools = 17 ==> Private Schools = 1
Dist C: High Schools = 15 ==> Private Schools = 5
Therefore, 9 - 1 - 5 ==> 3
Answer B)
Question: An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases.
A.8 : 6
B.8 : 7
C.8 : 8
D.8 : 9
Answer: B.8 : 7
Explanation: Let the length and breadth of the carpet in the first case be 3x units and 2x units respectively.
Let the dimensions of the carpet in the second case be 7y, 3y units respectively.
From the data,.
2(3x + 2x) = 2(7y + 3y)
=> 5x = 10y
=> x = 2y
Required ratio of the areas of the carpet in both the cases
= 3x * 2x : 7y : 3y
= 6x2 : 21y2
= 6 * (2y)2 : 21y2
= 6 * 4y2 : 21y2
= 8 : 7
Answer: Option B
Question: In one hour a boat goes 18 km long the stream and 6 km against the stream.The speed of the boat in still water is?
A.12
B.14
C.16
D.17
Answer: A.12
Explanation: Speed in still water A = ½ ( 18+6) km/hr A= 12 kmph
Answer: A
Question: A bag contains a certain number of 50 paise coins, 20 paise coins and 10 paise coins inthe ratio 3:4:5. If the total value of all the coins in the bag is Rs.400, find the number of 50 paise coins ?
A.498
B.488
C.428
D.528
Answer: C.428
Explanation: 50*3k + 20*4k + 10*5k = 40000
280k = 40000 => k = 142.85
50p coins = 3k = 3*142.85 = 428
20p coins = 4k = 4*142.85 = 571
10p coins = 5k = 5*142.85 = 714
ANSWER:C
Question: A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 1200. How many workers were part of the latter production run?
A.A)6
B.B)14
C.C)11
D.D)15
Answer: B.B)14
Explanation: The daily average production is given by 5n + 20- given
In the first k days, 500 units are produced
= (5n+20)K =500
k = 500/5n+20...................................1
5 workers were added = 5(n+5)+20 = 5n +45
cumulative is 1200 .. thus for the current period = 1200 -500 = 700
(5n+45)K= 700
k = 700/5n+45........................................2
equate 1 and 2
500/5n+20 = 700 /5n+45
500(5n+45) = 700(5n+20)
25n + 225 = 35n + 140
-10n = -85
n = 8.5
thus n+5 = 14
hence B
Question: a series of natural number 1+2+3+4+5+6+7+8+9+10 is divisibel by 11 so we has to find how many such series is possible upto n where n is less than 1000.
A.90
B.99
C.180
D.96
Answer: C.180
Explanation: the total multiple of 11 less then 1000 are 90 .
and for every multiple there are two such series which are divisible by 11.
. .
. sum of series = n(n+1)/2
for multiple 11 we can take n=10 and 11
for 22 '' '' ''' n=21 and 22
and so on and for 990 multiple of 11 we can take n=989 and 990
so total series formed are 90*2= 180
ANSWER:C
Question: A company conducted a survey about its two brands, A and B. x percent of respondents liked product A, (x – 20) percent liked product B, 23 percent liked both products, and 23 percent liked neither product. What is the minimum number G of people surveyed by the company?
A.46
B.G=80
C.G=90
D.G=100
Answer: D.G=100
Explanation: 100 = x + x - 20 + 23 - 23
x = 60,
So, Product A = 60%, Product B = 40%, Both = 23%, Neither = 23%
23% of the total no. of people should be an integer. So, A,BC are out.
60% of D and 40% of D are both integers. So, D satisfies all conditions.
So, answer is D.
Question: A firm is divided into four departments, each of which contains four people. If a project is to be assigned to a team of three people, none of which can be from the same department,what is the greatest number of distinct teams to which the project could be assigned?
A.4^3
B.4^4
C.4^5
D.6(4^4)
Answer: B.4^4
Explanation: First member: 4*4=16 choices;
Second member: 4*3=12 choices (as one department already provided with a member);
Third member: 4*2=8 choices (as two departments already provided with members);
So, we have: 16*12*8.
Since the order of the members in a team does not matter (we don't actually have 1st, 2nd and 3rd members) then we should divide above by 3! to get rid of duplication: 16*12*8/3!=4^4.
ANSWER:B
Question: Working at their respective constant rates, Paul, Abdul and Adam alone can finish a certain work in 3, 4, and 5 hours respectively. If all three work together to finish the work, what fraction M of the work will be done by Adam?
A. 1/4
B. 12/47
C. 1/3
D. 5/12
Answer: B. 12/47
Explanation: Let the total work be 60 units. Pual does 60/3 =20 units of work per hr. abdul does 15 units per hr and adam does 12 units per hr. If all work together they do (20 + 15 + 12) units per hr = 47 units per hr. So the time taken to finish the work = 60/47 hrs.
adam will do 60/47 * 12 units of work in 60/47 hr . fraction of work adam does =work done by adam / total work
M>( 60/47 *12)/60 =12/47
Answer B
Question: A car during its journey travels 30 minutes at a speed of 60 kmph, another 45 minutes at a speed of 60 kmph, and 2 hours at a speed of 80 kmph.The average speed of the car is
A.63.07 kmph
B.64 kmph
C.72.30 kmph
D.64.02 kmph
Answer: C.72.30 kmph
Explanation: First car travels 30 min at speed of 60 kmph
distance = 60 x 1/2 = 30 m
Then car travels 45 min at a speed of 60 kmph
distance = 45 min at speed of 60 kmph
distance = 60 x 3/4 = 45 m
at last it travels 2 hours at speed of 70 kmph
distance = 80 x 2 = 160 m
Total distance = 30 + 45 + 160 = 235
Total time= 1/2 + 3/4 + 2 = 3.25
Average speed of the car = 235/3.25 = 72.30
ANSWER:C
Question: What is the greatest of 3 consecutive integers whose sum is 21 ?
A.6
B.7
C.8
D.9
Answer: C.8
Explanation: The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3
If the sum is 24, we need to solve the equation 3n + 3 = 21;
=> 3n = 18;
=> n = 6
The greatest of the three numbers is therefore 6 + 2 = 8 Answer: C
Question: Which of the following fraction is the smallest?
A.12/14
B.13/19
C.17/21
D.7/8
Answer: B.13/19
Explanation: Explanation:
12/14 = 0.857, 13/19 = 0.684, 17/21 = 0.8095 and 7/8 = 0.875
Since 0.684 is the smallest, so 13/19 is the smallest fraction.
ANSWER: B
Question: At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.20000?
A.6620
B.3277
C.2688
D.2998
Answer: A.6620
Explanation: A = 20000(11/10)3
= 26620
= 20000
----------
6620
Answer:A
Question: A man covers a certain distance by car driving at 30 km/hr and he returns back to the starting point riding on a scooter at 10 km/hr. Find his average speed for the whole journey.
A.8 Km/hr
B.17 Km/hr
C.15 Km/hr
D.12 km/hr
Answer: C.15 Km/hr
Explanation: Explanation:
= (2 x a x b)/(a + b)
= (2 x 30 x 10)/(30 + 10)
= (2 x 30 x 10)/40
= 15 km/hr
Answer: Option C
Question: Four car rental agencies A, B, C and D rented a plot for parking their cars during the night. A parked 15 cars for 12 days, B parked 12 cars for 20 days, C parked 18 cars for 18 days and D parked 16 cars for 15 days. If A paid Rs. 1125 as rent for parking his cars, what is the total rent paid by all the four agencies?
A.2388
B.2778
C.1279
D.6150
Answer: D.6150
Explanation: The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15
= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60
Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.
The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k
It is given that A paid Rs. 1125
45k = 1125 => k = 25
246k = 246(25) = Rs. 6150
Thus the total rent paid by all the four agencies is Rs. 6150.
Answer: D
Question: A sum of money at simple interest amounts to Rs. 830 in 3 years and to Rs. 854 in 4 years. The sum is:
A.647
B.698
C.758
D.847
Answer: C.758
Explanation: S.I. for 1 year = Rs. (854 - 830) = Rs. 24.
S.I. for 3 years = Rs.(24 x 3) = Rs. 72.
Principal = Rs. (830 - 72) = Rs. 758.
Answer:C
Question: Thirty percent of the members of a swim club have passed the lifesaving test. Among the members who havenotpassed the test, 5 have taken the preparatory course and 30 have not taken the course. How many members are there in the swim club?
A. 60
B. 80
C. 50
D. 120
Answer: C. 50
Explanation: 30% of the members have passed the test, thus 70% have not passed the test.
We also know that 30+5=42 members have not passed the test, thus 0.7*Total=35 --> Total=50.
Answer: C.
Question: A company pays project contractors a rate of a dollars for the first hour and b dollars for each additional hour after the first, where a > b.
In a given month, a contractor worked on two different projects that lasted 6 and 8 hours, respectively. The company has the option to pay for each project individually or for all the projects at the end of the month. Which arrangement would be cheaper for the company and how much would the company save?
A.Per month, with savings of $(5a + 5b)
B.Per month, with savings of $(5a - 5b)
C.The two options would cost an equal amount.
D.Per project, with savings of $(5a + 5b)
Answer: B.Per month, with savings of $(5a - 5b)
Explanation: Per Project, company will pay as follows:
For 6 hours work = a+5b
For 8 hours work = a+7b
Total = 2a+12b
Per Month, company will pay for 14 hours work = a+13b
Total per contract - total per month
6a+8b - (a+13b)
5a-5b
Since a>b Amount 6a+8b(per contract amount) > a+13b (per project amount) by 5a-5b.
Hence per month payment will be cheaper by 5a-5b .
OA B
Question: A rectangular field is to be fenced on three sides leaving a side of 30 feet uncovered. If the area of the field is 720 sq. feet, how many feet of fencing will be required?
A.78
B.40
C.68
D.88
Answer: A.78
Explanation: EXPLANATION
We have: l = 30 ft and lb = 720 sq. ft.
So, b = 24 ft.
Length of fencing = (l + 2b) = (30 + 48) ft = 78 ft.
Answer A
Question: Car Z travels 45 miles per gallon of gasoline when driven at a constant rate of 45 miles per hour, but travels 20 percent fewer miles per gallon of gasoline when driven at a constant rate of 60 miles per hour. How many miles does car Z travel on 10 gallons of gasoline when driven at a constant rate of 60 miles per hour?
A.320
B.360
C.400
D.408.3
Answer: B.360
Explanation: The question stem asks us for the distance possible with 10 gallons of fuel at a constant speed of 60 miles per hour. We therefore first calculate the fuel efficiency at that speed.
The stem tells us that at 45 miles/hour, the car will run 45 miles/gallon and at 60 miles/hour, that distance decreases by 20%. We can therefore conclude that the car will travel 36 miles/gallon at a constant speed of 60 miles/gallon. With 10 gallons of fuel, the car can therefore travel 36 miles/gallon * 10 gallons = 360 miles.
Answer B.
Question: Two cyclist start on a circular track from a given point but in opposite direction with speeds of 7m/s and 8m/s. If the circumference of the circle is 180meters, after what time will they meet at the starting point?
A.20sec
B.12sec
C.30sec
D.50sec
Answer: B.12sec
Explanation: They meet every 180/7+8 = 12sec
Answer is B
Question: 5 skilled workers can build a wall in 20days; 8
semi-skilled workers can build a wall in 25 days; 10
unskilled workers can build a wall in 30days. If a te
am has 2 skilled, 6 semi-skilled and 5 unskilled
workers, how long will it take to build the wall?
A.15days
B.16days
C.14days
D.18days
Answer: A.15days
Explanation: For Skilled
5 workers --------20 days
5 workers 1 day work= 1/20
1 worker's 1 day work= 1/(5*20)
Similarly,
For Semi-Skilled------
1 worker's 1 day work= 1/(8*25)
For Unskilled------
1 worker's 1 day work= 1/(10*30)
For 2 skilled,6 semi-skilled and 5 unskilled
workers
One day work= 2*[1/(5*20)] +6*[1/(8*25)] + 5*[ 1/(10*30)] = 1/15
Therefore no. of days taken= 15
ANSWER:A
Question: Twenty coins are tossed simultaneously. In how many of the outcomes will the third coin turn up a head?
A.2^19
B.2^10
C.3 * 2^8
D.3 * 2^9
Answer: A.2^19
Explanation: Fix the third coin as H. The remaining 19 coins have 2^19 outcomes.
A
Question: The manufacturing cost of a shoe is Rs.180 and the transportation lost is Rs.500 for 100 shoes. What will be the selling price if it is sold at 20% gains
A.Rs 222
B.Rs 216
C.Rs 220
D.Rs 210
Answer: A.Rs 222
Explanation: Explanation :
Total cost of a watch = 180 + (500/100) = 185.
Gain = 20% => SP = 1.2CP = 1.2 X 185 = 222
Answer : A
Question: Shopkeeper rise price by 33% and gives successive discount of 10% and 15%. What is overall % gain or loss?
A.1.745%
B.4.745%
C.3.745%
D.6.745%
Answer: A.1.745%
Explanation: Let d initial price be 100
33 % rise
now price = 133/100*100 = 133
10% discount
Then price = 133 * 90/100 = 119.7
15 % discount
Then price = 119.7 * 85/100 = 101.745
So Gain = 101.745 - 100 = 1.745
Gain % = Gain * 100 /CP
==> 1.745 * 100 /100 = 1.745%
ANSWER:A
Question: A relay race covers 1 1/2 miles,and each runner on a team will run 1/4 of a mile. How many runners are needed for a team?
A.9
B.6
C.3
D.10
Answer: B.6
Explanation: Number of runners=total distance/distance each runner runs
=1 1/2 ÷ 1/4
=3/2 ÷ 1/4 = 3/2*4/1
=12/2
= 6.
Answer is B.
Question: Today Jennifer, who is 30 years old, and her daughter, who is 6 years old, celebrate their birthdays. How many years will pass before Jennifer’s age is twice her daughter’s age?
A.18
B.20
C.22
D.24
Answer: A.18
Explanation: Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.
After x years passes Jennifer’s age will be (30+x) years old, and her daughter’s age will be (6+x) years old. Since the Jennifer’s age is twice her daughter’s age (30+x)= 2 * (6+x) ---> 30+x=12+2x ---> x= 18.
The answer is (A).
Question: A 3-digit positive integer consists of non zero digits. If exactly two of the digits are the same, how many such integers are possible?
A.72
B.144
C.216
D.283
Answer: C.216
Explanation: here is the answer in pure probability terms.
let the 3 digit number be XYZ
now none of them contain zero --> they can vary from 1 - 9
so lets take the value of X, X can be from 1 - 9, hence X can be selected in 9 ways
since Y =X, after selecting X you can select Y in 1 way only
Z can be an selected from 1 -9 (minus 1 because it cannot be the same as X) in exactly 8 ways
hence total number of ways of selecting the number is 9 * 8 = 72.
BUT we are asked for all possible numbers that can be formed.
So XYZ ( or XXZ in this case) can be moved around in 3 ways
XXZ
XZX
ZXX
hence the total number of numbers is 72 *3 = 216
ANSWER:C
Question: There were 35 students in a hostel. Due to the admission of 7 new students, ;he expenses of the mess were increased by Rs. 42 per day while the average expenditure per head diminished by Rs 1. Wbat was the original expenditure of the mess?
A.320
B.120
C.400
D.420
Answer: D.420
Explanation: Sol. Let the original average expenditure be Rs. x. Then,
42 (x - 1) - 35x=42	ïƒ³	7x= 84	ïƒ³	x =12.
Original expenditure = Rs. (35 x 12) =Rs. 420. .
ANSWER D
Question: A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 3.5t seconds, then what is the length of the platform?
A.0.5L
B.1.5L
C.2.5L
D.3.5L
Answer: C.2.5L
Explanation: The train passes a pole in t seconds, so velocity v = L/t
(L+P)/v = 3.5t
(L+P) / (L/t) = 3.5t
P = 2.5L
The answer is C.
Question: In how many days does B alone complete the work
1. B and C together can complete the work in 8 days
2. A and B together can complete the work in 12 days
A.Statement 1 alone is sufficient
B.Statement 2 alone is sufficient
C.Statement 1 and 2are sufficient
D.Statement 1 and 2are not sufficient
Answer: D.Statement 1 and 2are not sufficient
Explanation: Explanation:
We cannot find the work done by B.
If C+A work is given we can find it by
B’s work = (A+B+C) work - (A+C) work
Answer: Option D
Question: A project scheduled to be carried out over a single fiscal year has a budget of $12,600, divided into12 equal monthly allocations. At the end of the fourth month of that fiscal year, the total amount actually spent on the project was $5,580. By how much was the project over its budget?
A. $380
B. $540
C. $1,050
D. $1,380
Answer: D. $1,380
Explanation: Difficulty level: 600
Each month's budget = 12600/12 = 1050
Budget for 4 months = 4*1050 = 4200
Actual amount spent = 5580
Amount spent over the budget = 5580 - 4200 = 1380
Answer (D),
Regards,
Question: A student's mark was wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by 1/2. What is the number of students in the class?
A.20
B.30
C.10
D.40
Answer: D.40
Explanation: Let the total number of students = x
The average marks increased by 1/2 due to an increase of 83 - 63 = 20 marks.
But total increase in the marks = (1/2)x=x/2
Hence we can write as
x/2=20
⇒x=20×2=40
Answer is D.