RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A class contains five juniors and five seniors. If one member of the class is assigned at random to present a paper on a certain subject, and another member of the class is randomly assigned to assist him, what is the probability R that both will be juniors?
A.1/10
B.1/5
C.2/9
D.2/5
Answer: C.2/9
Explanation: I think you're right. The other way to do it (but the long way) is to figure out the probability that it is not two Juniors.
2 seniors = P(Senior) * P(Senior) = 2/9
1 Senior and 1 Junior = (1/2) *(5/9)*2 = 5/9
Probability that it is not two Juniors is 5/9+2/9 = 7/9 so the probability R that it is two juniors is 1- (7/9) = 2/9.C
Question: The average of 5 quantities is 9. The average of 3 of them is 4. What is the average of remaining 2 numbers?
A.16.5
B.10
C.8
D.9.5
Answer: A.16.5
Explanation: ANSWER: A
(5x9-3x4)/2=16.5
Question: Sreenivas sells a table to Shiva at 10% profit and Shiva sells it to Mahesh at 10% loss. At what price did Sreenivas purchase the table if Mahesh paid Rs. 2178?
A.2228
B.2771
C.2200
D.2877
Answer: C.2200
Explanation: Explanation:
Let the cost price of table for Sreenivas be Rs. x and given that, cost price of table for Mahesh = Rs. 2178.
=> (90%) of (110%) of x = Rs. 2178.
=> (90/100)(110/100)x = 2178
=> x = (2178 * 100)/(9 * 11)
=> x = Rs. 2200
Answer:C
Question: The number 0.8 is how much greater than 1/8 ?
A.½
B.27/40
C.1/50
D.1/500
Answer: B.27/40
Explanation: let x be the difference
then
.8-1/8=x
8/10-1/8=x
x=27/40
ans B
Question: How many ways can 10 letters be posted in 5 post boxes, if each of the post boxes can take more than 10 letters ?
A.5^10
B.5^11
C.5^18
D.5^12
Answer: A.5^10
Explanation: Each of the 10 letters can be posted in any of the 5 boxes.
So, the first letter has 5 options, so does the second letter and so on and so forth for all of the 10 letters.
i.e. 5*5*5*….*5 (upto 10 times)
= 5 ^ 10.
Answer: A
Question: The difference between C.I. and S.I. on an amount of $15,000 for 2 years is $54. What is the rate of interest per annum?
A.5%
B.6%
C.7%
D.8%
Answer: B.6%
Explanation: $54 is the interest on the first year of interest.
Let x be the interest rate.
The interest after the first year is 15000*x.
The interest on the first year's interest is 15000*x*x
15000*x^2 = 54
x = 0.06
The answer is B.
Question: The difference in compound interest earned on a deposit (compounded annually) in year 1 and year 2 is $ 40. Had the interest rate been three times its present value, the difference z would have been how much?
A.40/3
B.40
C.120
D.360
Answer: D.360
Explanation: CASE 1:
Deposit = $x;
Rate of increase = r.
Interest yearned in 1 year = xr. Deposit in 1 year = x + xr.
Interest yearned in 2 year = (x + xr)r.
The difference z= (x + xr)r - xr = xr^2 = 40.
CASE 2:
Deposit = $x;
Rate of increase = 3r.
Interest yearned in 1 year = x(3r). Deposit in 1 year = x + 3xr.
Interest yearned in 2 year = (x + 3xr)3r.
The difference = (x + 3xr)3r - 3xr = 9xr^2. Since from CASE 1 we know that xr^2 = 40, then 9xr^2 = 9*40 = 360.
Answer: D.
Question: Lagaan is levied on the 60 percent of the cultivated land. The revenue department collected total Rs. 3,84,000 through the lagaan from the village of Mettur. Mettur, a very rich farmer, paid only Rs.480 as lagaan. The percentage of total land of Mettur over the total taxable land of the village is:
A.0.20833
B.0.34667
C.0.45788
D.0.78452
Answer: A.0.20833
Explanation: Total land of Sukhiya = \inline \frac{480x}{0.6} = 800x
\therefore Cultivated land of village = 384000x
\therefore Required percentage = \inline \frac{800x}{384000}\times 100 = 0.20833
A
Question: Each light bulb at a hotel is either incandescent or fluorescent. At a certain moment, forty percent of the incandescent bulbs are switched on, and eighty percent of the fluorescent bulbs are switched on. If 75 percent of all the bulbs are switched on at this moment, what percent of the bulbs that are switched on are incandescent?
A.6.7%
B.10.3%
C.14.5%
D.18.2%
Answer: A.6.7%
Explanation: Let I be the number of incandescent bulbs.
Let F be the number of fluorescent bulbs.
0.4I + 0.8F = 0.75(I+F)
0.05F = 0.35I
F = 7I
This means that for every 1 incandescent bulb, there are 7 fluorescent bulbs.
The percent of bulbs that are switched on which are incandescent is:
0.4I / (0.4I + 0.8F) = 0.4I / (0.4I + 0.8*7I) = 0.4I / 6I = 1/15 which is about 6.7%.
The answer is A.
Question: A man is standing on a railway bridge which is 165 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the length of the train and its speed.
A.10 m/sec
B.13.75 m/sec
C.18 m/sec
D.19 m/sec
Answer: B.13.75 m/sec
Explanation: If length of train is l and speed of train is s, then
l/s = 8
(l+165)/s = 20
(l+165)/l = 20/8 =5/2
2l+330 =5*l
3*l= 330
l=110 mtrs
s= l/8 = 110/8 = 13.75 m/sec
ANSWER:B
Question: A Book was sold at a loss of 10%. If it was sold for $140 more, there would have been a gain of 4%. What is the cost price?
A.$1200
B.$1300
C.$1000
D.$1700
Answer: C.$1000
Explanation: C
$1000
90%
104%
--------
14% ---- 140
100% ---- ? => $1000
Question: John sells encyclopedias door-to-door. He earns $160 on every paycheck, regardless of how many sets he sells. In addition, he earns commission as follows:
Commission Sales
10% $0.00 - $10,000.00
5% $10,000.01 --->
He does not earn double commission.That is, if his sales are $12,000, he earns 10% on the first $10,000 and 5% on the remaining $2,000.
His largest paycheck of the year was $1,320. What were his sales for that pay period?
A.A)13,000
B.B)13,200
C.C)16,400
D.D)15,800
Answer: B.B)13,200
Explanation: His pay check was $1320.
Out of this, $160 was his fixed salary so the total commission he earned was $1320 - $160 = $1160
He earns 10% on the sales of first $10,000 which gives a commission of $1000.
He earns 5% on every subsequent dollar. Since he earns another $160, he must have had sales of another 160*(100/5) = 3200
So his total sales must have been $10,000 + $3200 = $13,200
B
Question: The C.P of 16 books is equal to the S.P of 18 books. Find his gain% or loss%?
A.16 2/3% loss
B.11 1/9% loss
C.16 3/3% loss
D.36 2/3% loss
Answer: B.11 1/9% loss
Explanation: 16 CP = 18 SP
18 --- 2 CP loss
100 --- ? => 11 1/9% loss
Answer:B
Question: On multiplying a number A by 153, the result obtained was 102325. However, it is found that both the 2's are wrong. Find the correct result.
A.104345
B.107375
C.108385
D.109395
Answer: D.109395
Explanation: The only thing you actually know about the correct number A is that it is divisible by 153 and has 5 as a factor.
You should immediately try to find the factors of 153 and look for them in the options.
153 = 9*17
Divisibility by 9 is easy to check. Only (D) satisfies.
Question: From a group of 3 boys and 3 girls, 2 children are to be randomly selected. What is the probability that 1 boy and 1 girl will be selected?
A.1/10
B.4/9
C.1/2
D.9/15
Answer: D.9/15
Explanation: The total number of ways to choose 2 children from 6 is 6C2 = 15
The number of ways to choose 1 boy and 1 girl is 3*3 = 9
P(1 boy and 1 girl) = 9/15
The answer is D.
Question: In what time will a train 110 m long cross an electric pole, it its speed be 128 km/hr?
A.2.5 sec
B.2.9 sec
C.3.1 sec
D.8.7 sec
Answer: C.3.1 sec
Explanation: Speed = 128 * 5/18 = 36 m/sec
Time taken = 110/36 = 3.1 sec.
Answer: C
Question: In the following list of numerals, how many 3s are followed by 3, but NOT preceded by 3?
2463315 7833346233339723
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: total 3 are there
ANSWER:C
Question: Two circular signs are to be painted. If the diameter of the larger sign is seven times that of the smaller sign, how many times more paint is needed to paint the larger sign? (We can assume that a given amount of paint covers the same area on both signs.)
A.7
B.14
C.42
D.49
Answer: D.49
Explanation: Let R be the radius of the smaller sign.
Then the diameter of the smaller sign is 2R, the diameter of the larger sign is 14R, and the radius of the larger sign is 7R.
The area A of the smaller sign is A = piR^2.
The area of the larger sign is pi(7R)^2=49piR^2=49A.
Since the area is 49 times larger, we need 49 times more paint for the larger sign.
The answer is D.
Question: A side of beef lost 20 percent of its weight in processing. If the side of beef weighed 640 pounds after processing, how many pounds did it weigh before processing?
A.191
B.355
C.800
D.840
Answer: C.800
Explanation: Let weight of side of beef before processing = x
(80/100)*x = 640
=> x = (640 * 100)/80 = 800
Answer C
Question: Murugan, Prasanna and Arun invested Rs.8000, Rs.4000 and Rs.8000 respectively in a business. Arun left after six months .If after eight months, there was a gain of Rs.4005, then what will be the share of Prasanna?
A.Rs.890
B.Rs.1335
C.Rs.1602
D.Rs. 1780
Answer: A.Rs.890
Explanation: Solution
Murugan : Prasanna : Arun	=(8000×6):(4000×8):(8000×8)
= 48 : 32 : 64
= 3 : 2 : 4.
Kamal's share	= Rs.4005×2/9)
= Rs.890.
Answer A
Question: The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages.
A.16, 28, 38
B.16, 28, 36
C.16, 28, 32
D.16, 28, 30
Answer: B.16, 28, 36
Explanation: Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
20x = 80 => x = 4
Their present ages are 16, 28 and 36 years respectively.
Answer: B
Question: If the price of a TV is first decreased by 20% and then increased by 50%, then the net change in the price will be :
A.20% increase
B.10% increase
C.10% decrease
D.6% increase
Answer: A.20% increase
Explanation: Explanation :
Solution: let the original price be Rs. 100.
New final price = 150% of(80% of 100) =Rs. 150/100 * 80/100 * 100 = Rs. 120.
.'. Increase = 20%
Answer : A
Question: Weights of two friends Ram and Shyam are in the ratio of 4 : 5. Ram’s weight increases by 10% and the total weight of Ram and Shyam together becomes 82.8 kg, with an increase of 15%. By what per cent did the weight of Shyam increase?
A.12.5%
B.17.5%
C.19%
D.21%
Answer: C.19%
Explanation: Let the weights of Ram and Shyam be 4x and 5x. Now,according to question,
4x×110/100+Shyam?snewwt4x×110100+Shyam?s new wt = 82.8........ (i)
and 4x + 5x = 9x+115/100= 82.8........ (ii)
From (ii), x = 8
Putting in (i),
we get Shyam’s new wt = (82.8 – 35.2) = 47.6
% increase in Shyam’s wt = (47.6−40/40×100) = 19
Answer C
Question: nine baseball players each stand at different corners of a baseball diamond. The sides of the diamond are all of equal length. Two arrangements of baseball players are considered different only when the relative positions of the players differ. How many different ways can the baseball players arrange themselves around the diamond?
A.40320
B.40213
C.40311
D.24089
Answer: A.40320
Explanation: it is like a circular arrangement.
total ways for n people to arrange in a circle is = factorial (n-1)
in this case n= 9
hence ans = 8 factorial = 40320
hence A
Question: Two numbers are respectively 20% and 25% more than a third number. The percentage that is first of the second is?
A.86%
B.98%
C.96%
D.36%
Answer: C.96%
Explanation: I II III
120 125 100
125----------120
100-----------? => 96%
Answer: C
Question: If y exceeds x by 30%, then x is less than y by?
A.1/7%
B.1/9%
C.1/11%
D.1/13%
Answer: D.1/13%
Explanation: X=100	y=130
130------30
100-------? => 23 1/13%
Answer:D
Question: How many multiples of 10 are there between 10 and 1000, exclusive?
A.98
B.99
C.100
D.101
Answer: A.98
Explanation: 98
multiples of 5 between 1 and 36 exclusive.
from 10 * 2 upto 10*99, (2,3,4,...,99). Hence, 98 multiples !
correct option is A
Question: In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 79 more candidates got selected than A. What was the number of candidates appeared from each State?
A.7000
B.7900
C.6000
D.5000
Answer: B.7900
Explanation: State A and State B had an equal number of candidates appeared.
In state A, 6% candidates got selected from the total appeared candidates
In state B, 7% candidates got selected from the total appeared candidates
But in State B, 79 more candidates got selected than State A
From these, it is clear that 1% of the total appeared candidates in State B = 79
=> total appeared candidates in State B = 79 x 100 = 7900
=> total appeared candidates in State A = total appeared candidates in State B = 7900
Question: Which of the following describes all values of x for which 1–x^2 <= 0?
A. x >= 1
B. x <= –1
C. 0 <= x <= 1
D. x <= –1 or x >= 1
Answer: D. x <= –1 or x >= 1
Explanation: Which of the following describes all values of x for which 1–x^2 >= 0?
(A) x >= 1
Plugged in 2. 1–(2)^2 >= 0 -3>=0? yes. But are these all the values? No. Wrong
(B) x <= –1
Plugged in -2. 1–(-2)^2 >= 0 -3>=0? yes. But are these all the values? No. Wrong.
(C) 0 <= x <= 1
Start with 0. 1-0 = 1. Wrong. All the other values wrong as well.
(D) x <= –1 or x >= 1
This is the Correct Answer as it captures both A and B. Answer is D.
(E) –1 <= x <= 1
Plug in 0. Value is greater than 0. Wrong.
Correct answer is D.
Question: Three years ago, John’s age was half of the age he will be in 8 years. How old is he now?
A.14years
B.15years
C.16years
D.17years
Answer: A.14years
Explanation: Let John=j,j-3=(j+8)/2,then j=14years
ANSWER:A
Question: If 9a - b = 10b + 70 = -12b - 2a, what is the value of 9a - 11b?
A.-4
B.70
C.0
D.2
Answer: B.70
Explanation: This implies 9a - b = 10b + 70, 9a -b = -12b -2a, 10b + 70 = -12b -2a
Manipulating the second equation gives us 9a - b = 10b + 70 ==> 9a - 11b = 70
Answer is B
Question: Ten years ago, the age of Anand was one-third the age of Bala at that time. The present age of Bala is 14 years more than the present age of Anand. Find the present age of Anand?
A.13
B.14
C.15
D.16
Answer: A.13
Explanation: Let the present ages of Anand and Bala be 'a' and 'b' respectively.
a - 10 = 1/3 (b - 10) --- (1)
b = a + 14
Substituting b = a + 12 in first equation,
a - 10 = 1/3 (a + 4) => 3a - 30 = a + 4
=> 2a = 26 => a = 13.
ANSWER:A
Question: In covering a distance of 30 km, Arun takes 22 hours more than Anil. If Arun doubles his speed, then he would take 1 hour less than Anil. What is Arun's speed?
A.8kmph
B.5kmph
C.4kmph
D.7kmph
Answer: B.5kmph
Explanation: Explanation:
If Arun doubles his speed, he needs 3 hour less. Double speed means half time. Hence, half of the time required by Arun to cover 30 km =3 hour
i.e., Time required by Arun to cover 30 km =6 hour
Arun's speed =30/6=5 kmph
ANSWER IS B
Question: Income and expenditure of a person are in the ratio 15 : 8. If the income of the person is Rs. 15000, then find his savings?
A.6999
B.7000
C.7001
D.7002
Answer: B.7000
Explanation: Let the income and the expenditure of the person be Rs. 15x and Rs. 8x respectively.
Income, 15x = 15000 => x = 1000
Savings = Income - expenditure = 15x - 8x = 7x = 7(1000)
So, savings = Rs. 7000.
Answer:B
Question: When two dice are rolled, what is the probability that the sum of the two numbers is 5?
A. 1/9
B. 2/9
C. 1/3
D. 2/3
Answer: A. 1/9
Explanation: We have 4 outcomes that satisfy the question:
1-4
2-3
3-2
4-1
the probability is (1/6*1/6)*4= 4/36= 1/9
I think the answer is A
Question: The average age of 50 students in a class is 10years. If teacher's age is also included then average increases 1year then find the teacher's age?
A.59
B.55
C.61
D.45
Answer: C.61
Explanation: Total age of 50 students = 50*10 = 500
Total age of 51 persons = 51*11 = 561
Age of teacher = 561-500 = 61years
Answer is C
Question: Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5/6 hour before the second horse reaches A. If the distance between A and B is 50 km. what is the speed of the slower horse?
A.30 km/h
B.15 km/h
C.25 km/h
D.20 km/h
Answer: D.20 km/h
Explanation: Explanation:
If the speed of the faster horse be \inline f_{s} and that of slower horse be Ss.then
Now, you can go through options.
The speed of slower horse is 20km/h
Since, 20+30=50 and 50/20=50/30=5/6
ANSWER IS D
Question: If a tank A can be filled within 10 hrs and 1/4th of tank B is filled in 19 hrs. Then what is the duration of the tank B to fill completely?
A.74
B.75
C.76
D.77
Answer: C.76
Explanation: 1/4th of tank B takes 19hrs then
to fill completely it takes 19*4 = 76hrs
ANSWER:C
Question: Find the area of the quadrilateral of one of its diagonals is 28 cm and its off sets 8 cm and 2 cm?
A.140 cm2
B.150 cm2
C.168 cm2
D.182 cm2
Answer: A.140 cm2
Explanation: 1/2 * 28(8 + 2)
= 140 cm2
Answer: A
Question: Two representatives must be selected from each of two groups of students. One group consists of four men and one woman, and the other group consists of two women and one man. What is the probability that 2 men and 2 women will be selected ?
A.1/6
B.1/4
C.2/7
D.7/15
Answer: D.7/15
Explanation: Group 1: 4 Men and 1 Woman
Group 2: 1 Men and 2 Woman
Need: 2 Men and 2 women
Case 1: 2 Men from Group 1 and 2 women from group 2 - 4C2*2C2 = 6 ways
Case 2: 1 Men and 1 Woman from Group 1 and 1 Man and 1 women from group 2 - 4*1*1*2 = 8 ways
Total Favorable cases = 6+8 = 14
Total Possible ways of selecting students 2 from each group = 5C2*3C2 = 10*3 = 30
Probability = 14/30 = 7/15
Answer : Option D
Question: A can do a piece of work in 40 days; B can do the same in 30 days. A started alone but left the work after 10 days, then B worked at it for 10 days. C finished the remaining work in 10 days. C alone can do the whole work in?
A.24 days
B.30 days
C.44 days
D.17 1/2 days
Answer: A.24 days
Explanation: Explanation:
10/40 + 10/30 + 10/x = 1
x = 24 days
Answer: A
Question: P is a prime number. If 6p is between 15 and 95, which of the following E can be a value of 7p + 2?
A.E.15
B.E.79
C.121
D.65
Answer: B.E.79
Explanation: [3,5,7,11,13] are prime numbers that fits this equation 15< 6X <95. Afterwards subtract 2 from all the answer n see if it's divisible by 7. Therefore A and E are out. Leaves out with B C D.
B =11
C =17
D = 9
Only 11 is the set of prime numbers that fit between 15 and 95. Therefore 79 is the answer.B
Question: here are 6 periods in each working day of a school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period?
A.4561
B.3564
C.1542
D.1800
Answer: D.1800
Explanation: 5 subjects can be arranged in 6 periods in 6P5 ways.
Any of the 5 subjects can be organized in the remaining period (5C1 ways).
Two subjects are alike in each of the arrangement. So we need to divide by 2! to avoid overcounting.
Total number of arrangements
= 6P5× 5C1 /2!=1800
Ans: D
Question: If money is invested at r percent interest, compounded annually, the amount of investment will double in approximately 70/r years. If Pat's parents invested $ 5000 in a long term bond that pays 8 percent interest, compounded annually, what will be the approximate total amount of investment 18 years later, when Pat is ready for college?
A.20000 dollars
B.$15000
C.$12000
D.$10000
Answer: A.20000 dollars
Explanation: Since investment doubles in 70/r years then for r=8 it'll double in 70/8=~9 years (we are not asked about the exact amount so such an approximation will do). Thus in 18 years investment will double twice and become ($5,000*2)*2=$20,000 (after 9 years investment will become $5,000*2=$10,000 and in another 9 years it'll become $10,000*2=$20,000).
Answer: A.
Question: If (x-12)(x-3) < 0, which of the following must be true?
A.x^2 + 5x + 6 < 0
B.x^2 + 5x + 6 > 0
C.12 - x > 0
D.x - 5 < 0
Answer: C.12 - x > 0
Explanation: (x-12)(x-3)<0 can be written as (12-x)(x-3)>0
So,to inequality hold true multiple of (12-x) and (x-3) must be positive and if I let both elements positive/negative then the range becomes 3<x<12
Answer Choice E matched which says 12-x>0 or x<12,which must be true (I started to look from E to A for making easy decision first)
Correct Answer C
Question: Two trains of length 120 m and 280 m are running towards each other on parallel lines at 32 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?
A.33 1/5 sec
B.23 1/5 sec
C.24 1/5 sec
D.23 3/5 sec
Answer: B.23 1/5 sec
Explanation: Relative speed = (32 + 30) * 5/18 = 4 * 5 = 17.22 mps.
Distance covered in passing each other = 120 + 280 = 400 m.
The time required = d/s = 400/20 = 23 1/5 sec.
ANSWER:B
Question: The 201st term of the series a, b , b, c, c, c, d, d, d, d, e, e, e, e, e, .... is
A.r
B.s
C.t
D.u
Answer: D.u
Explanation: a is one time, b,2 times so on...
so 201=n(n+1)/2..
0r n(n+1)= 402 ... now 19*20=380...20*21<402 so x= 20.. and 20th alphabet is T ans D
Question: If the average (arithmetic mean) of the four numbers K, 3K + 3, 3K – 4 and 5K + 1 is 60, what is the value of K?
A. 11
B. 15 3/4
C. 20
D. 23
Answer: C. 20
Explanation: K + 3K +3 + 3K - 4 + 5K +1 = 12K
(12K)/4 = 60
12K = 60 * 4 = 240
K = 240/ 12 = 20.
Answer C.
Question: Will must choose a 3-character computer password, consisting of 3 letter from the alphabet , in any order.From how many different passwords can Will choose?
A.390
B.2,340
C.93,600
D.7,020
Answer: C.93,600
Explanation: 26C1*25C1*24C1 = 15600
=> 2340 * 3 ! = 93,600.
Option E is correct answer...but OA is C.
Question: John's Ice Cream Shop sells ice cream at m cents a scoop. For an additional n cents, a customer can add 2 toppings to his or her sundae. How much would a sundae with 2 scoops and 2 toppings cost, in terms of m and n?
A.2m+2n
B.2m+n
C.3m+n
D.4m+n
Answer: B.2m+n
Explanation: Answer B 2m+n
Question: From a pack of 52 cards, one card is drawn. What is the probability that the card drawn is a face card (Jack, Queen and King only)?
A.1/13
B.3/13
C.13/13
D.8/13
Answer: B.3/13
Explanation: Answer:	Solution
Let S be the sample space. Then,
n(S) = 52C1	= 52.
Let E = event of getting 1 face card.
n(E) = number of ways of choosing 1 face card out of 12
=12C1 = 12
P(E) = n(E) / n(S)	= 12 / 52
= 3/13.
Answer B
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
A.Rs.4329
B.Rs.4529
C.Rs.4520
D.Rs.4530
Answer: D.Rs.4530
Explanation: Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5
= Rs. 4530
Answer:D
Question: The least number which should be added to 9422 so that the sum is exactly divisible by 5, 6, 4 and 3 is?
A.59
B.58
C.48
D.38
Answer: B.58
Explanation: L.C.M. of 5, 6, 4 and 3 = 60.
On dividing 9422 by 60, the remainder is 2.
Number to be added = (60 - 2) = 58
B)
Question: A man rows his boat 90 km downstream and 55 km upstream, taking 3 hours each time. Find the speed of the stream?
A.76 kmph
B.6 kmph
C.14 kmph
D.8 kmph
Answer: B.6 kmph
Explanation: Speed downstream = d/t = 90/(3)
= 30 kmph
Speed upstream = d/t = 55/(3)
= 18 kmph
The speed of the stream = (30 - 18)/2
= 6 kmph
Answer:B
Question: 3 candidates in an election and received 4136, 7636 and 11628 votes respectively. What % of the total votes did the winning candidate got in that election?
A.45%
B.49%
C.50%
D.59%
Answer: C.50%
Explanation: Total number of votes polled = (4136 + 7636 + 11628) = 23400
So, Required percentage = 11628/23400 * 100 = 50%
C
Question: Line m lies in the xy-plane. The y-intercept of line m is -2, and line m passes through the midpoint of the line segment whose endpoints are (2, 8) and (10,0). What is the slope of line m?
A.-1
B.0
C.1
D.2
Answer: C.1
Explanation: The midpoint of (2,8) and (10,0) is (6,4).
The slope of a line through (0,-2) and (6,4) is (4-(-2))/(6-0) = 6/6 = 1
The answer is C.