RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If X is the least common multiple of 90,196, and 300, which of the following is NOT a factor of X?
A.600
B.700
C.900
D.2,100
Answer: A.600
Explanation: IF X is the least common multiple of 90,196 and 300, which of the following is NOT a factor of X?
A- 600
B- 700
C- 900
D- 2100
E- 4900
90 = 2 * 3 * 3 * 5
196 = 2 * 2 * 7 * 7
300 = 2 * 2 * 3 * 5 * 5
LCM = 2 * 2 * 3 * 3 * 5 * 5 * 7 * 7
(TWO 2, TWO 3, TWO 5, TWO 7)
600 = 2 * 2 * 2 * 3 * 5 * 5
700 = 2 * 2 * 5 * 5 * 7
900 = 2 * 2 * 3 * 3 * 5 * 5
2100 = 2 * 2 * 3 * 5 * 5 * 7
4900 = 2 * 2 * 5 * 5 * 7 * 7=A
Question: A number whose fifth part increased by 2 is equal to its fourth part diminished by 2 is ?
A.160
B.80
C.200
D.220
Answer: B.80
Explanation: Answer
Let the number be N.
Then, (N/5) + 2 = (N/4) - 2
â‡’ (N/4) - (N/5) = 4
â‡’ (5N - 4N)/20 = 4
âˆ´ N = 80
Option: B
Question: A football player scores 3 goals in his fifth match thus increasing his average goals score by 0.2. The total number of goals in his 5 matches would be
A.4
B.6
C.8
D.11
Answer: D.11
Explanation: While this question can be solved with a rather straight-forward algebra approach (as the other posters have noted), it can also be solved by TESTing THE ANSWERS. One of those numbers MUST be the total number of goals...
From a tactical standpoint, it's best to TEST either Answer B or Answer D, so if the answer is not correct, then you would have a gauge for whether you should go higher or lower with your next TEST.
Here, I'll start with Answer D = 11 goals
If....
Total goals = 11 goals
5th game = 3 goals
1st 4 games = 8 goals
Avg. for 4 games = 8/4 = 2 goals/game
Avg. for all 5 games = 6/5 = 2.2 goals/game
2.2*5=11
so Answer D
Question: A heap of coconuts is divided into groups of 2, 3 and 7 and each time one coconut is left over. The least number of Coconuts in the heap is?
A. 31 B. 41 C. 51 D. 61
A.A)31
B.B)43
C.C)51
D.D)61
Answer: B.B)43
Explanation: LCM = 42
=> 42 + 1 = 43
ANSWER:B
Question: If b is an integer greater than 6, which of the following must be divisible by 3?
A.b (b+3) (b-5)
B.b (b+2) (b-1)
C.b (b+1) (b-4)
D.b (b+4) (b-2)
Answer: C.b (b+1) (b-4)
Explanation: anything in the form of (b-1) (b) (b+1) is divisible by 3. in other word, a product of any 3 consecutive intevers is divisible by 3.
b (b+1) (b-4) = b (b+1) ((b-1)-3) is equivalant to (b-1) (b) (b+1)
b (b+2) (b-1) is equivalant to (b+1) missing.
b (b+3) (b-5) is equivalant to (b-1) missing and b repeating.
b (b+4) (b-2) is equivalant to odd/even consqcutive integers
b (b+5) (b-6) is equivalant to (b+1) missing and b repeating.
Answer : C
Question: If 144/0.144 = 14.4/x, then the value of x is:
A.2.
B.1.
C.-1.
D.-2.
Answer: B.1.
Explanation: Given Expression
=[a(Power2) - b(Power 2)]/(a + b)(a - b)
=[a(Power 2 - b(Power 2)]/[a(Power 2) - b(Power 2)]
= 1.
Answer is B.
Question: The average of 1st 3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 15. What is the last numbers?
A.2
B.4
C.6
D.5
Answer: C.6
Explanation: A + B + C = 48
B + C + D = 45
A + D = 13
A – D = 3
A + D = 15
2D = 12
D = 6
ANSWER C
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?
A.2.89
B.2.88
C.2.85
D.2.81
Answer: B.2.88
Explanation: Answer & M = 6
S = 1.2
DS = 6 + 1.2 = 7.2
US = 6 - 1.2 = 4.8
x/7.2 + x/4.8 = 1
x = 2.88.Answer: B
Question: If f(x) = 3x − √x and g(x) = x^2, what is f(g(2))?
A.-4
B.10
C.16
D.32
Answer: B.10
Explanation: g(x) = x²
g(2) = 2² = 4
So, f(g(2)) = f(4)
f(x) = 3x − √x
So, f(4) = 3(4) − √4
= 12- 2
= 10
= B
Question: How many possible ways are there to select 2 stocks at random from 8 stocks?
A.26
B.28
C.30
D.32
Answer: B.28
Explanation: 8C2 = 28
The answer is B.
Question: The current birth rate per thousand is 32, whereas corresponding death rate is 11 per thousand. The net growth rate in terms of population increase in percent is given by
A.0.0021%
B.0.021%
C.2.1%
D.21%
Answer: C.2.1%
Explanation: Sol.
Net growth on 1000 = (32 - 11) = 21.
Net growth on 100 = (21/1000 × 100)% = 2.1 %.
Answer C
Question: In the Biotechnology class of 2000, there were C graduates. 32 of the graduates found a job, 45 continued on to their second degree and 13 did both. If only 9 people didn't do both, What is C equal to?
A.69.
B.71.
C.73.
D.75.
Answer: C.73.
Explanation: Total = 32 +45 -13 + 9 = 73 .... My first post on the forum... I hope I am correct
C is correct choice.
Question: A, B and C can do a work in 6 days, 8 days and 12 days respectively. In how many days can all three of them working together, complete the work?
A.2 2/3
B.2 2/8
C.2 2/0
D.2 2/2
Answer: A.2 2/3
Explanation: Work done by all three of them in one day = 1/6 + 1/8 + 1/12 = 3/8.
The number of days required = 8/3 = 2 2/3 days.
Answer:A
Question: A can do a piece of work in 5 days and B can do it in 4 days how long will they both work together to complete the work?
A.6/11
B.8/9
C.7/9
D.2/9
Answer: D.2/9
Explanation: Explanation:
A’s one day work = 1/5
B’s one day work = 1/4
(A+B)’s one day work = 1/5 + 1/4 = 9/20 => time = 20/9 = 2 2/9 days
Answer: Option D
Question: If a 3-member subcommittee is to be formed from a certain 10-member committee, how many different such subcommittee are possible?
A.6
B.18
C.20
D.120
Answer: D.120
Explanation: 1st member can be selected in 10 ways
2nd can be selected in 9 ways
3rd can be selected in 8 ways
So total ways : 720
But to avoid the similar scenarios 720/3!=120
ANS:D
Question: On an article ,the manufacturer gains 10%, the wholesale dealer 15%, and the retailer 25%, If its retail price is 1265, what is the cost of its production?
A.1000
B.800
C.1100
D.900
Answer: B.800
Explanation: 110/100*115/100*125/100*C.P =1265,
11/10*23/20*5/4 C.P =1265
C.P = 800
ANSWER:B
Question: The timing of a college is from 12 p.m to 4.20 p.m. Five lectures are held in the given duration and a break of 5 minutes after each lecture is given to the students. Find the duration of each lecture.
A.76 minutes
B.66 minutes
C.88 minutes
D.48 minutes
Answer: D.48 minutes
Explanation: Explanation:
Total time a student spends in college = 4 hours 20 minutes = 260 minutes
As there are 5 lectures, the number of breaks between lectures is 4. Total time of the break = 20 minutes
Hence, the duration of each lecture is = (260 – 20)/5
= 48 minutes
ANSWER: D
Question: Choose the missing terms out of the given alternatives.
AZ, BY, CX, DW, EV, FU, GT?
A.HS
B.GH
C.ED
D.DW
Answer: A.HS
Explanation: A
HS
The first letter moves one step forward. The second letter moves one step backward.
Question: Ahok will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him or her. How many such arrangements of the 6 people are possible?
A.5
B.6
C.9
D.24
Answer: A.5
Explanation: Ahok will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing is standing in front of someone in the second row. person with max height is in the second row, person with min height is in the first row. We need to select 1 person in the middle of each row... In the middle of the first row we can put only 2, 3 or 4. In the middle of the second row we can put only 3, 4, 5. If we select {3 in the sec. row, 2 in the first}, {4,2}, {5,2}, {4,3}, {5,3}, {5,4}. So, there are 0*1 + 1*1 + 2*1 + 1*1 + 1*1 + 0*1 = 5 cases...A
Question: Tough and Tricky questions: Number Properties.
What is the smallest positive integer x such that 225x is the cube of a positive integer?
A.5
B.15
C.30
D.60
Answer: B.15
Explanation: We want to know the smallest x that will make 225x a CUBE of some number. Let's call that number y.
Let's first figure out what we're working with. The prime factorization of 225 can be visualized:
...........225
......../.......\
......25.......9
...../..\....../...\
...5....5...3.....3
So, we have 5 * 5 * 3 * 3 that can be multiplied together to get 225. Now we need to figure out what we need to make 225 * x into a cube of y (y^3=225*x).
We have two 5s and two 3s. To arrange these numbers in identical sets (3,5), we need at least one more 5 and one 3. Each of these numbers will give us the value of y (3*5=15), which, multiplied by itself three times, gives us 225 * x.
Looking at the factors we need to complete the triples, we get 5 * 3 = 15. We know this is the smallest number possible because prime factors by definition cannot be broken down any further.
Therefore, we can go with answer choice B.
If time permits, we can do a sanity check. We calculated that y should be 3 * 5, or 15. 15 * 15 * 15 = 3375. Also, 225 * 15 = 3375.
Answer: B
Question: If ay > 0 and yz < 0, which of the following must be negative:
A.ayz
B.ay(z^2)
C.a(y^2)z
D.x(y^2)(z^2)
Answer: C.a(y^2)z
Explanation: ay > 0 means that ay is positive.
yz < 0 means that yz is negative.
a(y^2)z = (ay)(yz) = positive*negative = negative. Thus option C is always negative.
Question: By selling 150 mangoes, a fruit-seller gains the selling price of 30 mangoes. Find the gain percent?
A.22%
B.25%
C.28%
D.29%
Answer: B.25%
Explanation: SP = CP + g
150 SP = 150 CP + 30 SP
120 SP = 150 CP
120 --- 30 CP
100 --- ? => 25%
Answer: B
Question: How many numbers from 10 to 46 are exactly divisible by 3?
A.13
B.12
C.16
D.17
Answer: B.12
Explanation: 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45.
12 Numbers.
10/3 = 3 and 46/3 = 15 ==> 15 - 3 = 12. Therefore 12 digits
B)
Question: How much time will an express train of length 200 m moving at a speed of 72 kmph take to cross another express train of length 300 m, moving at 36 kmph in the same direction?
A.sec
B.sec
C.sec
D.sec
Answer: A.sec
Explanation: The distance to be covered = Sum of their lengths = 200 + 300 = 500 m.
Relative speed = 72 -36 = 36 kmph = 36 * 5/18 = 10 mps.
Time required = d/s = 500/10 = 50 sec.
Answer: A
Question: Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 17 boys and 43 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad?
A.5
B.4
C.6
D.8
Answer: A.5
Explanation: Venn diagrams are useful for multiple values of a single variable e.g. State of mind - happy/sad/neither. When you have two or more variables such as here where you have gender - boy/girl too, it becomes unwieldy. In this case, either use the table or logic.
Table method is shown above; here is how you will use logic:
There are 6 happy boys.
There are 4 sad girls but total 10 sad children. So rest 6 sad children must be sad boys.
We have 6 happy boys and 6 sad boys. Total we have 17 boys. So 17 - 6 - 6 = 5 boys must be neither happy nor sad.
Answer (A)
Question: Find the invalid no.from the following series 3, 8, 15, 31, 63, 127, 255
A.11
B.8
C.27
D.63
Answer: B.8
Explanation: Go on multiplying the number by 2 and adding 1 to it to get the next number.So, 8 is wrong.
B
Question: 7/10 of the population of the country of Venezia lives in Montague Province, while the rest lives in Capulet Province. In the upcoming election, 80% of Montague residents support Romeo, while 70% of Capulet residents support Juliet; each resident of Venezia supports exactly one of these two candidates. Rounded if necessary to the nearest percent, the probability that a Juliet supporter chosen at random resides in Capulet is
A.28%
B.41%
C.60%
D.72%
Answer: C.60%
Explanation: Total population = 100 (assume).
7/10*100=70 people from Montague.
3/10*100=30 people from Capulet.
0.2*70=14 people from Montague support Juliet.
0.7*30=21people from Capulet support Juliet.
The probability that a Juliet supporter chosen at random resides in Capulet is 21/(14+21)=~60.
Answer: C
Question: In an election between two candidates, the winner has a margin of 10% of the votes polled. If 2000 people change their mind and vote for the loser, the loser would have won by a margin of 10% of the votes polled. Find the total number of votes polled in the election?
A.20000
B.25000
C.24000
D.23000
Answer: A.20000
Explanation: Winner - Looser
55% - 45%
If 2000 people change their mind and vote for the loser:
Winner - Looser
45% - 55%
Thus 2,000 people compose 10% of all voters, which means that the total number of votes is 20,000.
Answer: A.
Question: John has Rs 360 for his expenses. If he exceeds his days by 4 days he must cut down daily expenses by Rs 3. The number of days of John 's tour program is
A.10
B.15
C.20
D.24
Answer: C.20
Explanation: Let John under takes a tour of x
days.
Then, expenses for each day = 360x
360x+4=360x−3
x=20
and −24
Hence, x
= 20 days.
C
Question: What will be the fraction of 75%
A.3/4
B.1/5
C.1/10
D.1/11
Answer: A.3/4
Explanation: Explanation:
It will 75*1/100 = 3/4
Option A
Question: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3?
A.3/10
B.1/2
C.2/5
D.3/7
Answer: A.3/10
Explanation: Here, S = {1,2,3,......,19,20}
E= event getting a multiple of 3 = {3,6,9,12,15,18}
probability = 6/20 = 3/10
correct option is A
Question: A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is :
A.1/4
B.1/10
C.7/15
D.8/15
Answer: D.8/15
Explanation: A's 1 day's work =1/15;
B's 1 day's work =1/20;
(A + B)'s 1 day's work =(1/15)+(1/20)=7/60
(A + B)'s 4 day's work =(7/60)*4=7/15
Therefore, Remaining work =(1-(7/15))=8/15
Option D
Question: If the perimeter of a rectangular garden is 600 m, its length when its breadth is 150 m is?
A.150 m
B.778 m
C.200 m
D.276 m
Answer: A.150 m
Explanation: 2(l + 150)
= 600 => l
= 150 m
Answer:A
Question: A 6% stock yields 8%. The market value of the stock is:
A.Rs. 48
B.Rs. 75
C.Rs. 96
D.Rs. 133.33
Answer: B.Rs. 75
Explanation: Explanation:
For an income of Rs. 8, investment = Rs. 100.
For an income of Rs. 6, investment = Rs.100/8*6= Rs. 75.
Market value of Rs. 100 stock = Rs. 75.
ANSWER IS B
Question: Find the average of all numbers between 1 and 76 which are divisible by 5
A.40
B.20
C.25
D.30
Answer: A.40
Explanation: Explanation:
Average=(5+10+15+20+25+30+35+40+45+50+55+60+65+70+75)/15=600/15=40
Answer: Option A
Question: For all positive integers m, [m]=3m when m is odd and [m]=(1/2)*m when m is even. What is [5]*[8] equivalent to?
A.[40]
B.[60]
C.[80]
D.[120]
Answer: D.[120]
Explanation: [5]*[8] = 15*4 = 60 = (1/2)(120) = [120]
The answer is D.
Question: If a > 1, which of the following is equal to (2a - 2)/(a^2 + 2a - 3)?
A.a
B.a + 3
C.2/(a - 1)
D.2/(a + 3)
Answer: D.2/(a + 3)
Explanation: Here's the algebraic approach:
(2A - 2)/(A^2 + 2A - 3) can be rewritten as...
2(A - 1)/(A+3)(A-1)
We can simplify the fraction, which leaves us with...
2/(A+3)
Ans : D
Question: Four children have small toys. The first child has 1/10 of the toys, the second child has 12 more toys than the first, the third child has one more toy of what the first child has and the fourth child has double the third child. How many toys are there?
A.10
B.20
C.30
D.40
Answer: C.30
Explanation: x : the total number of toys
x/10 : the number of toys for first child
x/10 + 12 : the number of toys for second child
x/10 + 1 : the number of toys for the third child
2(x/10 + 1) : the number of toys for the fourth child
x/10 + x/10 + 12 + x/10 + 1 + 2(x/10 + 1) = x
x = 30 toys : solve for x
Question: Two boys starting from the same place walk at a rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5km apart, if they walk in the same direction?
A.15 hours
B.16 hours
C.17 hours
D.18 hours
Answer: C.17 hours
Explanation: Explanation:
In this type of questions we need to get the relative speed between them,
The relative speed of the boys = 5.5kmph – 5kmph
= 0.5 kmph
Distance between them is 8.5 km
Time = Distance/Speed
Time= 8.5km / 0.5 kmph = 17 hrs
Option C
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 24 kmph, find the speed of the stream?
A.18 kmph
B.6 kmph
C.8 kmph
D.10 kmph
Answer: C.8 kmph
Explanation: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 24/3 = 8 kmph.
Answer: C
Question: What range of values of 'x' will satisfy the inequality 15x - 2/x > 1?
A.x > 0.4
B.x < 1/3
C.-1/3 < x < 0.4, x > 15/2
D.-1/3 < x < 0, x > 2/5
Answer: D.-1/3 < x < 0, x > 2/5
Explanation: This will hold true for the following values of 'x': -1313 < x < 2/5 and x < 0.
Combining, we get -1/3 < x < 0.
Therefore, the range of values of x for which the above inequality will hold true is:
-1/3 < x < 0 âˆª x > 2/5.
ANSWERT : D
Question: In a jar there are 28 white balls, 32 green balls and 41 blue balls. How many balls must be taken out in order to make sure we have 30 balls of the same color?
A.a)	23
B.b)	46
C.c)	57
D.d)	66
Answer: D.d)	66
Explanation: Here, we need to find minimum number of marbles to be taken out to get 30 marbles of same color.
For a instance, if we take 2 white marbles 1st and followed by 22 Green and then 22 Blue.
Total will be 21 + 22+ 22= 65 draws.
If we choose either Green or Blue next time. This will bring the total of either of these colored marble to 30.
So Minimum we need to take 65+1 = 66 Times to get 30 marbles of same color(either Green or Blue).
Answer : D.
Question: When 23 is divided by the positive integer k, the remainder is 3, for how many different values of k is this true?
A.1
B.2
C.3
D.4
Answer: D.4
Explanation: This means that 20 must be a multiple of k.
The factors of 20 are 1, 2, 4, 5, 10, and 20.
Out of these, k can be 4, 5, 10, and 20.
The answer is D.
Question: Tough and Tricky questions: Ratios
3/5 of a certain class left on a field trip. 2/3 of the students who stayed behind did not want to go on the field trip (all the others did want to go). When another vehicle was located, 1/2 of the students who did want to go on the field trip but had been left behind were able to join. What fraction of the class ended up going on the field trip?
A.1/2
B.2/3
C.11/15
D.23/30
Answer: B.2/3
Explanation: let total no. of students be 30
students left on a field trip = 3/5(30) =18
thus 12 students left behind
2/3(12)=8 students did not want to go. thus 4 students want to go on the trip
1/2(4)=2 were able to join the other students on the field trip.
thus total number of students that went on a field trip =18+2 =20
thus required fraction = 20/30 =2/3
B
Question: A car started running at a speed of 30 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 7 hours of the journey.
A.342 km
B.352 km
C.252 km
D.742 km
Answer: C.252 km
Explanation: The total distance covered by the car in the first 7 hours = 30 + 32 + 34 + 36 + 38 + 40 + 42 = sum of 7 terms in AP whose first term is 30 and last term is 42 = 7/2 [30 + 42] = 252 km.
ANSWER:C
Question: John has 10 pairs of matched socks. If he loses 11 individual socks, what is the greatest number of pairs of matched socks he can have left?
A. 7
B. 6
C. 5
D. 4
Answer: D. 4
Explanation: Because we have to maximize the pair of matched socks, we will remove 5 pairs(10 socks) out of 10 pairs 1 sock from the 6th pair.
Thus the no of matching socks pair remaining = 10 -6 = 4
Answer D
Question: How many 3-letter words can be formed out of the letters of the word ‘CORPORATION’, if repetition of letters is not allowed?
A.336
B.297
C.266
D.259
Answer: A.336
Explanation: Explanation:
There are in all 11 letters in the word ‘CORPORATION’. Since repetition is not allowed, there are 8 different letters that can be used to form 3-letter word.
Therefore, total number of words that can be formed = 8P3 = (8*7*6)
= 336
ANSWER: A
Question: The price of the jewel, passing through three hands, rises on the whole by 62%. If the first and the second sellers 20% and 25% profit respectively find the percentage profit earned by the third seller.
A.20
B.8
C.5
D.2
Answer: B.8
Explanation: Let the original price of the jewel be $ p and let the profit earned by the third seller be x% Then, (100+x)% of 125% of 120% of P =162% Of P ((100+X)/100*125/100*120/100*P)=(162/100*P)
==> (100+X)=(162*100*100)/(125*120)=108=>X=8%
Answer B)
Question: What is the value of 8 1/3% of 600+ 37 ½ of 400
A.100
B.300
C.150
D.200
Answer: D.200
Explanation: 25*600/300 + 75*400/200 =50+150
= 200
ANSWER:D
Question: If one-third of one-fourth of a number is 15, then three-tenth of that number is:
A.48
B.40
C.50
D.54
Answer: D.54
Explanation: Let the number be x.
Then 1/3 of 1/4 of x =15
X=15x12 = 180
Required Number = (3/10)x180 =54
Answer : D
Question: Sam purchased 20 dozens of toys at t he rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?
A.3.5
B.4.5
C.5.6 percent
D.6.5
Answer: C.5.6 percent
Explanation: Solution
C.P of 1 toy	= Rs.(375/12)
= Rs.31.25
S.P of 1 toy	= Rs.33.
Therefore,Profit	= (1.75/31.25×100)%
=(28/5)%
=5.6%.
Answer C
Question: A pump can fill a tank with water in 5 hours. Because of a leak, it took 7 hours to fill the tank. The leak can drain all the water in ?
A.15hr 10min
B.16hr 20min
C.17hr 30min
D.15hr
Answer: C.17hr 30min
Explanation: Work done by the leak in 1 hour = 1/5 - 1/7 = 2/35
Leak will empty the tank in 35/2 hrs = 17hr 30min
Answer is C
Question: what is the least number. which should be added to 221 to make it a perfect square?
A.5
B.8
C.4
D.6
Answer: C.4
Explanation: 221+4=225
15^2
ANSWER:C
Question: How many numbers from 10 to 100 are exactly divisible by 9?
A.10
B.12
C.14
D.16
Answer: A.10
Explanation: 10/9 = 1 and 100/9 = 11 ==> 11 - 1 = 10. Therefore 10 digits.
A)
Question: A person incurs 5% loss by selling a watch for $1140 . At
what price should the watch be sold to earn 5% profit?
A.1160
B.1150
C.1260
D.1260
Answer: C.1260
Explanation: Let the new S.P be $ x then,
(100-loss%):(1st S.P)=(100+gain%):(2nd S.P)
(100-5)/1140=(100+5)/x
x=(105*1140)/95=$1260
ANSWER C 1260
Question: 12,21,48,87,__
A.176
B.186
C.184
D.174
Answer: B.186
Explanation: 21=12*2-3
48=21*2+6
87=48*2-9
so next number is 87*2+12=186
ANSWER:B
Question: In a certain region, the number of children who have been vaccinated against rubella is twice the number who have been vaccinated against mumps. The number who have been vaccinated against both is twice the number who have been vaccinated only against mumps. If 9,000 have been vaccinated against both, how many have been vaccinated only against rubella?
A.18,000
B.7,500
C.10,000
D.15,000
Answer: A.18,000
Explanation: Use a single variable as far as possible.
Number vaccinated only against mumps = x
Number vaccinated against both = 2x = 9000 (so x = 4500)
Then, number vaccinated against mumps (including both) = x + 2x = 3x
Number vaccinated against rubella = 2*3x = 6x
Then, number vaccinated against only rubella = 6x - 2x = 4x = 4*4500 = 18,000
Answer (A)
Question: g(x) is defined as the product of all even integers k such that 0 < k ≤ x. For example, g(14) = 2 × 4 × 6 × 8 × 10 × 12 × 14. If g(a) is divisible by 4^11, what is the smallest possible value for a?
A. 22
B. 24
C. 28
D. 32
Answer: B. 24
Explanation: g(a)=4^11=2^22. So we have to find a product with atleast 22 2's in it.
in option 1 22 the total no of 2's = [22/2] + [22/4] +[22/8] +[22/16] = 11+5+2+1 = 19
in option 2 24 the total no of 2's = [24/2] + [24/4] +[24/8] +[24/16] = 12+6+3+1 = 22 . Hence B
Question: In the Excel Manufacturing Company, 46 percent of the employees are men. If 60 percent of the employees are unionized and 70 percent of these are men, what percent of the non-union employees are women?
A.90%
B.87.5%
C.66.7%
D.50%
Answer: A.90%
Explanation: Lets say there are total 100 employees
Then men = 46 & women = 54
Unionized Emp = 60 & non unionized emp = 40
Men Unionized = .7 * 60 = 42
Women Unionized = 18
Women non-unionized = 54-18 = 36
Percentage of Women non unionized = 36/40 * 100 = 90%
The answer is Option A