RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If 20 men can build a water fountain 56 metres long in 21 days, what length of a similar water fountain can be built by 35 men in 3 days?
A.10 m
B.14 m
C.17 m
D.19 m
Answer: B.14 m
Explanation: Explanation :
Let the required length be x metres
More men, More length built (Direct Proportion)
Less days, Less length built (Direct Proportion)
Men 20: 35
Days 21: 3 : : 56 : x
Therefore (20 x 21 x x)=(35 x 3 x 56)
x=(35 x 3 x 56)/420=14
Hence, the required length is 14 m.
Answer : B
Question: A, B and C can do a piece of work in 7 days, 14 days and 28 days respectively. How long will they taken, if all the three work together?
A.3 days
B.4 days
C.5 days
D.6 days
Answer: B.4 days
Explanation: Explanation:
1/7 + 1/14 + 1/28 = 7/28 = 1/4 => 4 days
ANSWER IS B
Question: A password for a computer uses five digits from 0 to 9, inclusive. What is the probability that the digits of the password solely consist of prime numbers or zero?
A.1/32
B.1/16
C.1/8
D.2/5
Answer: A.1/32
Explanation: Favorable outcomes will be obtained by making Password using {0, 2, 3, 5, 7} i.e. 5 digits
Total Such Passwords = 5*5*5*5*5 = 5^5
Total Possible Password = 10*10*10*10*10 = 10^5
Probability = (5^5) / (10^5) = 1/2^5 = 1/32
Answer: option A
Question: A truck driver starts with the speed of 70 kmph with the truck driver decreasing speed every two hours by 10 kmph. The truck driver's speed does not drop below 50 kmph. In how many hours will it take the truck driver to travel 500 kms?
A.480 minutes
B.492 minutes
C.504 minutes
D.528 minutes
Answer: D.528 minutes
Explanation: Distance covered in first two hours = 70 Ã— 2 = 140 km
Distance covered in next two hours = 60 Ã— 2 = 120 km
Distance covered in next two hours = 50 Ã— 2 = 100 km
Distance covered in next two hours = 50 Ã— 2 = 100 km
Distance covered in first eight hours
140 + 120 + 100 + 100 = 460 km
Remaining distance = 500 â€“ 460 = 40 km.
Now, this distance will be covered at the speed of 50 km/hr.
âˆ´ Time taken = 40â„50 = 4â„5 hour.
Total time= 8 + 4â„5 = 8 4â„5 hour
Answer D
Question: In a game, a player can win by getting five consecutive tails in six throws of a coin. What is the probability of winning if the player gets a tail on the first throw?
A.1/32
B.1/16
C.3/16
D.1/8
Answer: B.1/16
Explanation: The only way to win is to get a tail on each of the next four throws.
P(four tails)=(1/2)^4=1/16
The answer is B.
Question: Consider the sequence of numbers beginning 23, 27, 28, 32, 33... It continues in such a way that by adding 5 to the nth term, one obtains the (n + 2)th term. What is the sum of the first 17 members of this sequence?
A.878
B.900
C.743
D.928
Answer: C.743
Explanation: I would split them up like this.
23 28 33 and so on (9 terms)....the 9th term = 23+8*5 = 63
27 32 37 and so on (8 terms)......the 8th term = 27+7*5 = 62
Since the distance between any two numbers is the same we can use arithmetics
first+last/2 times no of numbers = the sum
(23+63)/2 * 9 = 387
(27+62)/2 * 8 = 356
= 743
C
Question: Visitors to show were charged Rs.15 each on the first day. Rs.7.50 on the second day, Rs.2.50 on the third day and total attendance on the three days were in ratio 2:5:13 respectively. The average charge per person for the whole show is?
A.2
B.3
C.5
D.6
Answer: C.5
Explanation: 2: 5: 13
2x 5x 13x
15 7.5 2.5
30x + 37.5x + 32.5x = 100x/20x
Average = 5.Answer: C
Question: If A : B : C = 3 : 4 : 7, then what is the ratio of (A / B) : (B / C) : (C / A)?
A.63 : 48 : 196
B.63 : 48 : 18
C.63 : 48 : 1928
D.63 : 48 : 1918
Answer: A.63 : 48 : 196
Explanation: Hint: If a = kb for some constant k, then we can say that a is directly proportional to b.
A : B : C = 3 : 4 : 7
Assume, A = 3 k, B = 4 k, C = 7 k
Therefore,
A	=	(3k)	,	B	=	(4k)	,	C	=	(7k)
B	(4k)	C	(7k)	A	(3k)
A	=	(3)	,	B	=	(4)	,	C	=	(7)
B	(4)	C	(7)	A	(3)
L.C.M of 3, 4, 7 is 84
(3 x 84) / 4 = 63
(4 x 84) / 7 = 48
(7 x 84) / 3 = 196\
Correct option :A
Question: Along a road lie an odd number of stones placed at intervals of 10m. These stones have to be assembled around the middle stone. A person can carry only one stone at a time. A man carried out the job starting with the stone in the middle, carrying stones in succession, thereby covering a distance of 4.8 km. Then the number of stones is
A.35
B.15
C.29
D.31
Answer: D.31
Explanation: Explanation :
If he travels 10 m for the first stone he has to travel that dist back as well...so he travels 2 * 10 m dist for the first stone and so on.
=> 2400 = 2 * (10 + 20 + 30 .... 10n) using formula for AP
=> 2400 = 2 * n/2*(2*10 + (n-1)*10) .
=> 2400 = 10n2 + 10n .
On solving this, we get n = 15 as the positive root, so total numer of stones on both sides= 30.
and including the one which he was at = 31.
Answer : D
Question: How many words can be formed by using all letters of TIHAR
A.100
B.120
C.140
D.160
Answer: B.120
Explanation: Explanation:
First thing to understand in this question is that it is a permutation question.
Total number of words = 5
Required number =
5P5=5!=5∗4∗3∗2∗1=120
Option B
Question: How many odd prime numbers are there less than 100?
A.78
B.5
C.24
D.12
Answer: C.24
Explanation: Odd prime number less than 100:3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
There is 24 the odd prime number
Answer is C
Question: A newly-wed couple is using a website to design an eBook Wedding Album to distribute to their friends and families. The template they have chosen has places for 3 large photos and 19 smaller photos. The couple has 6 large photos they could use for those three slots, and 20 smaller photos they could use for those 19 slots. Given these choices, how many different possible albums could they create?
A.3,150
B.400
C.5,040
D.20,520
Answer: B.400
Explanation: MAGOOSHOFFICIAL SOLUTION:
For the large photos, we need 6C3, which we calculated in the article:
6C3 = 20
For the smaller photos, we need 20C19, which by symmetry must equal 20C1, and we have a formula for that. In fact, in the article above, we already calculated that 21C2 = 20.
Now, by the FCP, we just multiply these: total number of possible albums = 20*20 = 400.
Answer = B
Question: The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
A.202
B.278
C.377
D.750
Answer: D.750
Explanation: Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 25 è x = 25 * 60 / 2
= 750
Answer: D
Question: Marge has 3 pumps for filling her swimming pool. When all 3 pumps work at their maximum rates, the swimming pool is filled in 90 minutes. Pump 1's maximum rate is twice the maximum rate of pump 2 and four times the maximum rate of pump 3. How long would it take Marge to fill the pool if she used only pump 2 at its maximum rate ?
A.2hrs, 48mins
B.5hrs, 15mins
C.7hrs, 12mins
D.13hrs, 4mins
Answer: B.5hrs, 15mins
Explanation: The rate of pump 1 = 4x job/minute.
The rate of pump 2 = 2x job/minute.
The rate of pump 3 = x job/minute.
Given that x+2x+4x=1/90 --> x=1/630 --> (time) = (reciprocal of rate) = 630 minutes x/2 = 5 hours and 15 minutes.
Answer: B.
Question: Out of a group of 10 contestants, 2 are to be selected at random. What is the maximum number of male contestants possible if the probability that both selected contestants are male is less than 60% ?
A. 0
B. 1.66
C. 2.55
D. 1.22
Answer: D. 1.22
Explanation: Let x be the number of males.
Total contestants = 10
Probability that the first contestant selected is a male = x/10
Probability that the second contestant selected is also a male = x-1/9
Total probability = x(x-1)/ 90 < 1/60 (this probability is less than 60%)
Solving for x we get, x(x-1)< 3/2. This implies that the maximum value of x can be 1.22.
Answer D!
Question: A and B can do a piece of work in 6 2/3 days and 5 days respectively. They work together for 2 days and then A leaves. In how many days after that B will complete the work alone.
A.5 days
B.18 days
C.1 ½ days
D.25 days
Answer: C.1 ½ days
Explanation: Explanation:
3/20 * 2 + (2 + x)/5 = 1
x = 1 ½ days
Answer C
Question: Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 2 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is?
A.60 gallons
B.100 gallons
C.120 gallons
D.80 gallons
Answer: D.80 gallons
Explanation: Work done by the waste pipe in 1 minute = 1/15 - (1/20 + 1/24) = - 1/40
Volume of 1/40 part = 2 gallons\
Volume of whole = 2 * 40 =80 gallons.
ANSWER:D
Question: Sara and Alan start a company with Rs.100000 and Rs.50000 respectively. how should they share their profits at the end of one year?
A.2:1
B.3:4
C.3:8
D.3:1
Answer: A.2:1
Explanation: The ratio of the investments made by A and B =
100000: 50000=> 2:1.Answer: A
Question: In a question on division with zero remainder, a candidate took 15 as divisor instead of 5. The quotient obtained by him was 35. The correct quotient is?
A.A)105
B.B)24
C.C)28
D.D)29
Answer: A.A)105
Explanation: Number = (35 * 15) = 525
Correct quotient = 525/5 = 105
A)
Question: If John covers a certain distance in 1 hr. 24 min. by covering two third of the distance at 4 kmph and the rest at 5 kmph, then find the total distance
A.4 km
B.6 km
C.6.8 km
D.7.2 km
Answer: B.6 km
Explanation: Explanation:
Let the total distance be y km. Then,
(2/3)y/4 +(1/3)y/5 =7/5
y/6 + y/15 = 7/5
7y =42
y = 6 km
ANSWER B
Question: Which of the following options is equal to 3.75 x 10(power 5)?
A.175000
B.372000
C.375000
D.365000
Answer: C.375000
Explanation: = 3.75 x 10(power 5)
= 3.75 x 100000
= 375000.
Answer is C.
Question: A number is selected at random from the first 30 natural numbers. What is the probability that the number is a multiple of either 4 or 15?
A.17/30
B.2/5
C.3/10
D.4/15
Answer: C.3/10
Explanation: Number of Multiples of 4 from 1 through 30 = 30/4 = 7
Number of Multiples of 15 from 1 through 30 = 30/15 = 2
Number of Multiples of 4 and 15 both from 1 through 30 = Number of Multiples of 15*4(=60) = 0
Total favourable cases = 7 + 2 - 0 = 9
Probability = 9 / 30 = 3/10
Answer: option C
Question: Before a salary hike, the weekly salary of a worker for 40 hours in a week was as much as he is paid now for 35 hours of work in a week. What is the percent increase in his salary for an hour?
A.11 1/3
B.12 1/4
C.13 1/5
D.14 2/7
Answer: D.14 2/7
Explanation: 280 is multiple of both 40 and 35
so I would rather take this value as the salary.
40 hrs 280$
1 hr=7$
Similarly
35 hrs 280$
1 hr=8$
Now 8-7=1$ increase in salary per hour now to calculate %
1/7*100=14 2/7
ANSWER:D
Question: Length of a rectangular plot is 32 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
A.56 m
B.66 m
C.76 m
D.86 m
Answer: B.66 m
Explanation: Let breadth = x metres.
Then, length = (x + 32) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 32) + x] = 200
2x + 32 = 100
2x = 68
x = 34.
Hence, length = x + 32 = 66 m
B
Question: Two boys starts from the same place walking at the rate of 5 kmph and 5.5 kmph respectively in the same direction. What time will they take to be 8.5 km apart?
A.17hr
B.14hr
C.12hr
D.19hr
Answer: A.17hr
Explanation: Explanation:
relative speed =5.5−5=0.5 kmph (because they walk in the same direction)
distance =8.5 km
time=distance/speed=8.5/0.5=17 hr
ANSWER IS A
Question: In how many years will a sum of money doubles itself at 30% per annum on simple interest?
A.7%
B.3%
C.5%
D.8%
Answer: B.3%
Explanation: P = (P*30*R)/100
R = 3%
Answer:B
Question: A and B walk around a circular track. They start at 9 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m.?
A.8
B.7
C.6
D.5
Answer: B.7
Explanation: Sol.
Relative speed = (2 + 3) = 5 rounds per hour.
So, they cross each other 5 times in an hour and 2 times in half an hour.
Hence, they cross each other 7 times before 9.30 a.m.
Answer B
Question: The length of the bridge, which a train 160 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
A.388
B.267
C.215
D.288
Answer: C.215
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (160 + X)/30 = 25/2 ==> 2(160 + X) = 750 ==> X = 215 m.
Answer: C
Question: If the price has fallen by 15% what percent of its consumption be: increased so that the expenditure may be the same as before?
A.A)11%
B.B)10%
C.1/9 %
D.3/13 %
Answer: D.3/13 %
Explanation: 100 – 15 = 85
85------15
100------? => 3/13%
ANSWER:D
Question: If 7:13::301:x then the value of ‘x’ is:
A.493
B.537
C.559
D.587
Answer: C.559
Explanation: Given the question;
7:13::301:x
7/13 = 301/x
7x = 301*13
x = 301*13/7
x = 559
ANSWER:C
Question: If the S.P of Rs. 45 results in a 50% discount on the list price, What S.P would result in a 40% discount on the list price?
A.s. 54
B.s. 56
C.s. 58
D.s. 60
Answer: A.s. 54
Explanation: Let the list price be Rs. X,
50/100*x = 45, x = 45*100/50 = 90
Required S.P = 60% of Rs. 90
= 60*90/100
=54
ANSWER:A
Question: The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 12000, then find the annual income of A?
A.Rs. 420000
B.Rs. 403200
C.Rs. 201600
D.Rs. 504000
Answer: B.Rs. 403200
Explanation: B's monthly income = 12000 * 112/100 = Rs. 13440
B's monthly income = 2 parts ----> Rs. 13440
A's monthly income = 5 parts = 5/2 * 13440 = Rs. 33600
A's annual income = Rs. 33600 * 12 = Rs. 403200
ANSWER:B
Question: A coin is tossed live times. What is the probability that there is at the least one tail?
A.31/32
B.31/38
C.31/34
D.31/31
Answer: A.31/32
Explanation: Let P(T) be the probability of getting least one tail when the coin is tossed five times.
= There is not even a single tail.
i.e. all the outcomes are heads.
= 1/32 ; P(T) = 1 - 1/32 = 31/32
Answer: A
Question: If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4650 , R will receive
A.Rs. 600
B.Rs. 700
C.Rs. 800
D.Rs. 900
Answer: D.Rs. 900
Explanation: Solution: Let
P's capital = p,
Q's capital = q and
R's capital = r.
Then
4p = 6q = 10r
=> 2p = 3q = 5r
=>q = 2p/3
r = 2p/5
P : Q : R = p : 2p/3 : 2p/5
= 15 : 10 : 6
R's share = 4650 * (6/31) = 150*6 = Rs. 900.
Answer: Option D
Question: In how many different number of ways 8 men and 2 women can sit on a shopa which can accommodate persons?
A.151252
B.151225
C.151211
D.151200
Answer: C.151211
Explanation: 10p6 = 10 x 9 x 8 x 7 x 6 x 5 = 151200
C)
Question: The faces of Cuboid are to be painted by 6 different colors. In how many ways can be this be done?
A.A.720
B.B.256
C.C.1
D.D.12
Answer: A.A.720
Explanation: If I have to paint 6 sides with 6 different colour...
First face can have 6c1 options,
2nd would have 5c1, and subsequent ones would have 4c1, 3c1, 2c1 and 1 options respectively.
Total options = 6c1 X 5c1 x 4c1 x 3c1 x 2c1 x 1 = 720 distinct ways
Correct answer - A
Question: A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 36 seconds. What is the length of the goods train?
A.470 m
B.240 m
C.260 m
D.270 m
Answer: A.470 m
Explanation: Explanation:
Speed =[ 72 x (5/18) ]m/sec= 20 m/sec.
Time = 36 sec.
Let the length of the train be x metres.
Then,[ (x+250)/36 ]= 20
=> x + 250 = 720
=> x = 470. Answer: A
Question: If the sum of a set of 5 different positive prime numbers is 94, which of the following prime numbers must be in the set?
A.2,7,43
B.3,11,31
C.5,71,31
D.7,43,53
Answer: A.2,7,43
Explanation: All prime numbers apart from 2 are odd.
Even + Even = Even
Odd + Even = Odd
Odd + Odd = Even
We are given 5 different prime numbers, whose sum is 94 i.e even
If we include 2, we will have 4 odd prime numbers and one even.
This sum would be odd
If we exclude 2, we will have 5 odd numbers.
This sum would be even
Hence 2 is included.
Option A
Question: The average marks of a class of 30 students is 40 and that of another class of 50 students is 90. Find the average marks of all the students?
A.71.25
B.52.9
C.52.1
D.52.3
Answer: A.71.25
Explanation: Sum of the marks for the class of 30 students = 30 * 40 = 1200
Sum of the marks for the class of 50 students = 50 * 90 = 4500
Sum of the marks for the class of 80 students =
1200 + 4500 = 5700
Average marks of all the students = 5700/80
= 71.25
Answer:A
Question: A distributor sells a product through an on-line store, which take a commission of 20% of the price set by the distributor. The distributor obtains the product from a producer at the price of $15 per item. What is the price that the buyer observers on-line if the distributor wants to maintain a 10% profit on the cost of the item?
A.18
B.21.6
C.20
D.22.5
Answer: C.20
Explanation: Producer price = $15;
The distributor wants to maintain a 20% profit on the cost of the item, thus he must get $15*1.2 = $18 after the store takes a commission of 10% of the final price --> (final price)*0.9 = $18 --> (final price) = $20.
Answer: C.
Question: A man wants to sell his scooter .There are two offers one at Rs12000 cash and other at a credit of Rs12880 to be paid after 8 months ,money being at 18% per annum which is better offer?
A.24277
B.12000
C.28372
D.36788
Answer: B.12000
Explanation: Explanation:
PW of Rs.12,880 due 8 months hence
= Rs\inline \fn_jvn \left [ \left ( \frac{12880\times 100}{100+(18\times \frac{8}{12})} \right ) \right ] =Rs.11500
Clearly 12000 in cash is a better offer.
Answer: B) Rs.12000
Question: (6!-4!)/5!=?
A.29/5
B.28/3
C.27/6
D.25/4
Answer: A.29/5
Explanation: (6!-4!)/5!
(4!*5*6-4!)/5!
4!(5*6-1)/4!*5
29/5
answer A
Question: A scooter costs 20,000 when it is brand new. At the end of each year, its value is only 80% of what it was at the beginning of the year. What is the value of the scooter at the end of 3 years?
A.10,240
B.12,500
C.12,800
D.12,000
Answer: A.10,240
Explanation: After first year, the value of the scooter = 16,000
After second year, the value of scooter = 12,800
After third year, the value of scooter = 10,240
Answer A
Question: What is the least number should be added to 1056, so the sum of the number is completely divisible by 26?
A.10
B.20
C.30
D.40
Answer: A.10
Explanation: (1056 / 26) gives remainder 16
10 + 16 = 26, So we need to add 10
A
Question: Average of five numbers is 27. If one number is excluded the average becomes 25. The excluded number is
A.35
B.45
C.55
D.65
Answer: A.35
Explanation: Explanation:
Number is (5*27) - (4*25) = 135-100 = 35
Option A
Question: In how many ways can an answer key for a quiz be written if the quiz contains 5 true-false questions followed by 3 multiple-choice questions with 4 answer choices each, if the correct answers to all true-false questions cannot be the same?
A.1220
B.1650
C.1920
D.2440
Answer: C.1920
Explanation: There are 2^5 = 32 possibilities for the true-false answers.
However we need to remove two cases for TTTTT and FFFFF.
There are 4*4*4 = 64 possibilities for the multiple choice questions.
The total number of possibilities is 30*64 = 1920.
The answer is C.
Question: 1.	How much more would Rs.16000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly?
A.A)Rs.4,225.60
B.B)Rs.4226.60
C.C)Rs.4,227.60
D.D)Rs.4,228.60
Answer: A.A)Rs.4,225.60
Explanation: 16000(11/10)4 - 16000(6/5)2 = 4,225.60
ANSWER:A
Question: The average weight of a group of boys is 30 kg. After a boy of weight 39 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
A.A)4
B.B)8
C.C)6
D.D)2
Answer: B.B)8
Explanation: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 39 kg joins the group, total weight of boys = 30x + 39
So 30x + 39 = 31(x + 1) = > x = 8.
Answer:B
Question: The total of the ages of Arun, Ajith, Ajay is 90 years. Ten years ago, the ratio of their ages was 1:2:3. What is the present age of Ajay?
A.40years
B.35years
C.38years
D.30years
Answer: A.40years
Explanation: Let ages of Arun, Ajith, Ajay 10years ago be x,2x,3x
x+10 + 2x+10 +3x+10 = 90
x = 10
Ramesh present age = 3*10+10 = 40 years
Answer is A
Question: If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 4 is subtracted and divided by 10?
A.4
B.7
C.8
D.5
Answer: D.5
Explanation: Explanation:
Let the number be x. Then,
(x - 5)/7 = 7 => x - 5 = 49
x = 54
.: (x - 4)/10 = (54 - 4)/10 = 5
Answer: Option D
Question: A certain sum of money at simple interest amounted Rs.934 in 8 years at 2% per annum, find the sum?
A.338
B.805
C.890
D.870
Answer: B.805
Explanation: 934 = P [1 + (8*2)/100]
P = 805
Answer:B
Question: A certain airline's fleet consisted of 90 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the TYPE A planes and acquired 4 new type B plans. How many years did it take before the number of type A planes left in the airline's fleet was less than 50 percent of the fleet?
A.11
B.12
C.13
D.14
Answer: C.13
Explanation: Let x be the number of years.
4x > 90 - 3x
7x > 90
x > 12 + 6/7
The answer is C.
Question: Reduce
803/876
to the lowest terms.
A.11/12
B.23/24
C.26/27
D.4/7
Answer: A.11/12
Explanation: Explanation:
HCF of 803 and 876 is 73, Divide both by 73, We get the answer 11/12
Option A
Question: Rs.705 is divided amongst A, B, C so that 3 times A's share, 5 times B's share and 4 times C's share are all equal. Find B's share?
A.177
B.150
C.180
D.716
Answer: C.180
Explanation: A+B+C = 7053A = 5B = 4C = xA:B:C = 1/3:1/5:1/4= 20:12:1512/47 * 705= Rs.180Answer: C
Question: When 2 + 3 = 65, 3 + 4 = 125, 4 + 5 = 205, then 5 + 6 = ?
A.285
B.305
C.315
D.350
Answer: B.305
Explanation: 2 + 3 => 2 Ã— 3 = 6 => 6 Ã— 10 + 5 = 65
3 + 4 => 3 Ã— 4 = 12 => 12 Ã— 10 + 5 = 125
4 + 5 => 4 Ã— 5 = 20 => 20 Ã— 10 + 5 = 205
Then 5 + 6 => 5 Ã— 6 = 30 => 30 Ã— 10 + 5 = 305
Answer : B
Question: A city with a population of 173,460 is to be divided into 9 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?
A.17,400
B.17,500
C.17,600
D.17,700
Answer: D.17,700
Explanation: The minimum possible population occurs when all the other districts have a population that is 10% greater than the least populated district.
Let p be the population of the least populated district.
Then 173,460 = p + 8(1.1)p
9.8p=173,460
p = 17,700
The answer is D.
Question: Find the area of circle whose radius is 7m?
A.138
B.154
C.288
D.280
Answer: B.154
Explanation: 22/7 * 7 * 7
= 154
Answer:B
Question: A cube of edge 7 cm is cut into cubes each of edge 1 cm. The ratio of the total surface area of one of the small cubes to that of the large cube is equal to:
A.1:25
B.1:49
C.1:52
D.1:522
Answer: B.1:49
Explanation: Sol.
Required ratio = 6 * 1 * 1 / 6 * 7 * 7 = 1/49 = 1:49.
Answer B
Question: An art gallery has only paintings and sculptures. Currently, 1/3 of the pieces of art are displayed, and 1/6 of the pieces on display are sculptures. If 1/3 of the pieces not on display are paintings, and 800 sculptures are not on display, how many pieces of art does the gallery have?
A.360
B.1800
C.540
D.640
Answer: B.1800
Explanation: Too many words and redundant info there.
(i) 1/3 of the pieces of art are displayed, hence2/3 of the pieces of art are NOT displayed.
(ii) 1/6 of the pieces on display are sculptures, hence 5/6 of the pieces on display are paintings.
(iii) 1/3 of the pieces NOT on display are paintings, hence2/3 of the pieces NOT on display are sculptures.
800 sculptures are not on display, so according to (iii) 2/3*{not on display} = 800 --> {not on display} = 1200.
According to (i) 2/3*{total} = 1200 --> {total} = 1800.
Answer: B.