RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: After an ice began to melt out from the freezer, in the first hour lost 3/4, in the second hour lost 3/4 of its remaining. If after two hours, the volume is 0.2 cubic inches, what is the original volume of the cubic ice, in cubic inches?
A.2.5
B.3.2
C.4.0
D.6.5
Answer: B.3.2
Explanation: Let initial volume of ice be = x
Ice Remaining after 1 hour = x - 0.75x = 0.25x
Ice Remaining after 2 hour = (1/4)x - (3/4 * 1/4 * x) = (1/16)x
(1/16)x = 0.2
x = 3.2
Alternate solution: Try to backsolve.
Initial volume = 3.2
After one hour --> (1/4)3.2 = 0.8
After two hours --> (1/4)0.8 = 0.2
Answer: B
Question: 5, 25, 61, 113, ?
A.182
B.337
C.278
D.266
Answer: A.182
Explanation: ANSWER: A
Question: In a box, there are 10 red, 6 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor blue?
A.4/51
B.10/21
C.7/12
D.6/21
Answer: D.6/21
Explanation: Total number of balls = 10+6+5 = 21
E = event that the ball drawn is neither red nor blue
= event that the ball drawn is blue
n(E) = 6
P(E) = 6/21
Answer is D
Question: A man has Rs. 192 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
A.37
B.36
C.22
D.90
Answer: B.36
Explanation: Let number of notes of each denomination be x.
Then, x + 5x + 10x = 192 16x = 192 x = 12.
Hence, total number of notes = 3x = 36.
Answer:B
Question: If a, b, q are integers, 33 = abq, and a < b < q, what is the smallest possible value of a?
A.-33
B.-3
C.1
D.3
Answer: A.-33
Explanation: Given : a * b * q = 33.
33 is a Positive Odd number.Side Note:Thus, all 3 numbers will be odd.
Prime factorization will also give you numbers. 1, 3, 11. The 3 numbers will be combination of these 3 numbers with possible variation in sign(+/-).
We could have any 2 digits as negative. --> negative * negative * positive. We have negative values in answer option, so eliminate C, D and E from answer choices.
-33 * -1 * 1 = 33.
Correct answer is A
Question: Six points lie on the circumference of a ellipse. What is the positive difference between the number of triangles and the number of quadrilaterals that can be created by connecting these points?
A.4
B.6
C.5
D.15
Answer: C.5
Explanation: Number of triangles can be formed out of 6 points= 6C3=20
Number of quadrilaterals can be formed out of 6 points= 6C4=15
20-15=5.
Answer=C
Question: What is the value of: 7^9 - 7^11 ?
A. -7^20
B. 7^-3
C. -49^20
D. -48(7^9)
Answer: D. -48(7^9)
Explanation: 7^9 - 7^11 = 7^9 (1 - 7^2) = 7^9 (1 - 49) = -48 (7^9), Answer D.
Question: Two letters from the word FARTHING are selected at random. What is the probability that at least one of the selected letters is a consonant?
Two letters from the word FARTHING are selected at random. What is the probability that at least one of the selected letters is a consonant?
A.A)1/500
B.B)1/28
C.C)27/28
D.D)124/125
Answer: C.C)27/28
Explanation: There are 6 consonants and 2 vowels in FARTHING.
probability that at least one of the selected letters is a consonant = 1 - (Probability of both vowels)
Probability of both vowels = 2C2/8C2 = 1/28
So, Answer is 1 - 1/28 = 27/28 ------> C.
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train.
A.150 m
B.155 m
C.180 m
D.190 m
Answer: A.150 m
Explanation: Answer: Option A
Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (distance) = speed * Time
(50/3) * 9 = 150 meter
Question: To reach her destination, Jeanette must drive 90 miles. If she drives 6 miles every 7 minutes, how much time will it take her to reach her destination?
A.2 hours and 2 minutes
B.hours and 45 minutes
C.2 hours and 10 minutes
D.2 hours and 12 minutes
Answer: B.hours and 45 minutes
Explanation: 7 minute for 6 miles how much for 90? minutes for 1(7/5) mile multiplied by 90 miles.
7*90/6= 105> 1 hours 45 min answer is B
Question: Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2% more. She would get how much?
A.9680
B.9687
C.96809
D.9683
Answer: A.9680
Explanation: (8000*3*2)/100 = 480
9200
--------
9680
Answer: A
Question: If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p ?
A.10
B.12
C.14
D.16
Answer: B.12
Explanation: Thus proceeding with the "300 + k" assumption, we get:
P = 30!
Option A: 310
=> 310 = 2 * 5 * 31
=> 31 is a prime and is not present in 30!
Thus 310 is not a factor of P
=> A is Eliminated
Option B: 312
=> 312 = 2^3 * 3 * 13
Thus 312 is a factor of P
=> B is the correct answer !
Option C: 314
=> 314 = 2 * 157
=> 157 is a prime and is not present in 30!
Thus 314 is not a factor of P
=> C is Eliminated
Option D: 316
=> 316 = 2^2 * 79
=> 79 is a prime and is not present in 30!
Thus 316 is not a factor of P
=> D is Eliminated
Option E: 318
=> 310 = 2 * 3 * 53
=> 53 is a prime and is not present in 30!
Thus 318 is not a factor of P
=> E is Eliminated
ANS: B
Question: A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?
A.111.12
B.888.55
C.200.05
D.400.04
Answer: A.111.12
Explanation: A runs 1000 m while B runs 900 m and C runs 800 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 800)/900 = 8000/9 = 888.88 m.
B can give C = 1000 - 888.88 = 111.12 m.
ANSWER A
Question: A train 2500 m long can cross an electric pole in 50 sec and then find the speed of the train?
A.178
B.180
C.182
D.184
Answer: B.180
Explanation: Length = Speed * time
Speed = L/T
S = 2500/50
S = 50 M/Sec
Speed= 50*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 180 Kmph
Answer:B
Question: How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10 % by selling the mixture at Rs. 9.24 per kg?
A.60
B.50
C.55
D.63
Answer: D.63
Explanation: Selling price of 1kg = 924
profit = 10%
cost = 100/(100+profit%)*SP
100/(100+10)*9.24= 8.4
Mean price = (8.4-7=1.4) (9-8.4=0.6)
=>1.4:0.6=14:6 = 7:3
3x=27*7=63
ANSWER D
Question: A train traveling at 100 kmph overtakes a motorbike traveling at 64 kmph in 40 seconds. What is the length of the train in meters?
A.1777 meters
B.1822 meters
C.400 meters
D.1111 meters
Answer: B.1822 meters
Explanation: Explanation :
When a train overtakes another object such as a motorbike, whose length is insignificant compared to the length of the train, the distance traveled by the train is equal to the length of the train.
Because the motorbike is also moving, we have to take the relative speed between the train and the motorbike and not just the speed of the train.
The length of the train = distance traveled by the train while overtaking the motorbike = relative speed between the train and the motorbike * time taken
In this case, as both the objects i.e., the train and the motorbike are moving in the same direction, the relative speed between them = difference between their respective speeds = 100 - 64 = 36 kmph.
Distance traveled by the train while overtaking the motorbike = 36 kmph * 40 seconds.
The final answer is in meters and the speed is given in kmph and the time in seconds.
So let us convert the given speed from kmph to m/sec.
1 kmph = 518518 m/sec
Therefore, 36 kmph = 36 * 518518 = 10 m/sec.
Relative speed = 10 m/sec. Time taken = 40 seconds.
Therefore, distance traveled = 10 * 40 = 400 meters.
Question: A man can row 9 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man?
A.6.24 km
B.6 km
C.8.84 km
D.5.66 km
Answer: C.8.84 km
Explanation: M = 9
S = 1.2
DS = 10.2
US = 7.8
x/10.2 + x/7.8 = 1
x = 4.42
D = 4.42 * 2 = 8.84
ANSWER:C
Question: 32% of 5/8 =
A.0.2
B.0.5
C.0.6
D.0.75
Answer: A.0.2
Explanation: Should be simple.
0.32*5/8 = 1.6/8 = 0.2
Correct Option : A
Question: The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:
A.17 kg
B.20 kg
C.26 kg
D.31 kg
Answer: D.31 kg
Explanation: Explanation:
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 .... (i)
A + B = (40 x 2) = 80 .... (ii)
B + C = (43 x 2) = 86 ....(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)
Subtracting (i) from (iv), we get : B = 31.
B's weight = 31 kg.
ANSWER IS D
Question: A piece of work can finish by a certain number of men in 100 days. If however, there were 10 men less,
it would take 10 days more for the work to be finished. How many men were there originally?
A.75
B.82
C.100
D.110
Answer: D.110
Explanation: Expl: Originally let there be x men.
Less men, more days (Indirect)
:. (x-10): x : : 100 :110 or x-10/x = 100/110
or 11x-110 = 10x or x =110
So, originally there were 110 men.
Answer: D
Question: There are 24 students in Chad’s class. He brought 29 cookies to pass out
for his birthday. How many cookies will each student get? Will there be
any cookies left over?
A.1-9
B.1-7
C.2-8
D.1-5
Answer: D.1-5
Explanation: 29/24 = 1 R 5 Chad will give each student 1 cookie and there will be 5
cookies left over
correct answer D
Question: A magician holds one six-sided die in his left hand and two in his right. What is the probability the number on the dice in his left hand is greater than the sum of the dice in his right?
A.7/108
B.5/54
C.1/9
D.2/17
Answer: B.5/54
Explanation: The least sum of the numbers of the two dice in the right hand is 2. The maximum sum of the numbers on these two dice can be 5, for the left hand dice to be able to have a greater number.
Therefore the number on the dice in the left hand must be 3 or more.
Number of ways to get a sum of 2 with the two dice in the right hand= 1
Number of ways to get a sum of 3 with the two dice in the right hand= 2
Number of ways to get a sum of 4 with the two dice in the right hand= 3
Number of ways to get a sum of 5 with the two dice in the right hand= 4
Therefore required probability = P(two right dice have a sum of 2)*P(left dice has 3) + P(right dice have sum of 2 or 3)*P(left dice has 4) + P(two right dice have a sum of 2,3, or 4)*P(left dice has 5) + P(two right dice have a sum of 2,3,4,or 5)*P(left dice has 6)
= (1/36)*(1/6) + (3/36)*(1/6) + (6/36)*(1/6) + (10/36)*(1/6)
= (1/216) * (1+3+6+10)
= 20/216
= 5/54
Option B
Question: There are 6 ladies and 4 gents to dine at a round table. In how many ways can they seat themselves so that no two gents are seated together.
A.85400
B.36400
C.86400
D.14400
Answer: D.14400
Explanation: First arrange the ladies. This is a circular arrangment. 6 Gents can be arranged in 5! ways.
Now there are 6 spaces (space in between two ladies) and we have to seat 5 gents there.
First select 4 places out of 5 available places. can be done in 5C4ways. Then arrange 5 gents there in 5! ways.
Total: 5!*5C4*4! = 14400
D is the answer.
Question: A man covered a certain distance at some speed. If he had moved
3 kmph faster, he would have taken 40 minutes less. If he had moved
2 kmph slower, he would have taken 40 minutes more. What is the distance in km?
A.40
B.30
C.35
D.60
Answer: A.40
Explanation: speed= 2v1v2/v1-v2=2*3*2/3-2=12 km/hr
dist=12*40/16(1+12/3)=40 km
ANSWER A
Question: The average score of a cricketer for twelve matches is 48 runs. If the average for first eight matches is 40, then average for last four matches is
A.33.25
B.89
C.64
D.68
Answer: C.64
Explanation: Explanation:
=(48×12)−(40×8)/4
=(576−320)/4=64
Answer: Option C
Question: Last year’s receipts from the sale of greeting cards during the week before Mother’s Day totaled $239 million, which represented 10 percent of total greeting card sales for the year. Total greeting card sales for the year totaled how many million dollars?
A.2,390
B.2,100
C.1,890
D.1,701
Answer: A.2,390
Explanation: 10% ---- 239 millions
for 100% => ( 239 * 100% )/10% = 2390.
Option A.
Question: If A^5 + B^5 = 2500, then the greatest possible value of A is between
A.0 and 3
B.3 and 6
C.6 and 9
D.9 and 12
Answer: B.3 and 6
Explanation: for the greatest possible value of A^5, we must minimize the value of B^5 i.e. lets say B^5 = 0
then we need to find a number A such that A^5 < 2500. 4^5 = 1024 and 5^5 = 3125 so we can say that the maximum possible value of A can be a little more than 4 hence answer = between 3 and 6
hence B
Question: Two trains of equal are running on parallel lines in the same direction at 52 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
A.50 m
B.72 m
C.80 m
D.82 m
Answer: C.80 m
Explanation: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 52 - 36 = 16 km/hr.
= 16 * 5/18 = 40/9 m/sec.
2x/36 = 40/9 => x = 80.
ANSWER:C
Question: If 6 (A's capital) = 8 (B's capital) = 10 (C's capital). Then the ratio of their capitals is:
A.3:4:5
B.12:15:20
C.20:15:12
D.6:8:10
Answer: C.20:15:12
Explanation: Explanation:
6A = 8B = 10 C
A:B:C = 1/6:1/8:1/10
= 20:15:12
ANSWER IS C
Question: Find the probability that a leap year selected at random will not have 53 Sundays
A.6/7
B.5/7
C.4/7
D.3/7
Answer: B.5/7
Explanation: There are 366 days in a leap year: 52 weeks and 2 more days. So, 52 Sundays and 2 days.
These 2 days can be: {Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat,Sun} and {Sun, Mon} (7 cases). In order to have 53 Sundays we should have either {Sat,Sun} or {Sun, Mon} case.
The probability of that is 2/7.
So, probability of not having 53 sundays is 1 - 2/7 = 5/7
Answer: B.
Question: Seven children â€” A, B, C, D, E, F, and G â€” are going to sit in seven chairs in a row. Children A & B must sit next to each other, and child C must be somewhere to the right of A & B. How many possible configurations are there for the children?
A.600
B.720
C.1440
D.4320
Answer: B.720
Explanation: This problem is a notch harder than anything you are likely to see on the GMAT. If you can master the principles in this problem, you certainly will be able to handle almost any problem the GMAT could concoct.
First, consider the restriction of A & B. As with problem #1 above, there are 12 possibilities for A & B, counting both position and order.
Now, put the other five in any order â€” thatâ€™s 120 possibilities, for a total number of configurations of 1440. That number does not take into account the restriction with C.
Think about those 1440 configurations. In exactly half of them, C will be to the right of A & B, and exactly half, C will be to the left of A & B. Therefore, in (1/2)*1440 = 720 configurations, C will be to the right of A & B. Answer = B
Question: On an order of 4 dozen boxes of a consumer product, a retailer receives an extra dozen free. This is equivalent to allowing him a discount of:
A.10%
B.20%
C.30%
D.40%
Answer: B.20%
Explanation: Clearly, the retailer gets 1 dozen out of 5 dozens free.
Equivalent discount = 1/5 * 100 = 20%.
Answer B) 20%
Question: Pipe A runs 60 liters of water per minute into a pool that has a total volume of 3,600 liters. Pipe B fills a third of the pool in 12 hours.
Working together how long will it take both pipes to fill the pool?
A.2 hours and 36 minutes
B.36/37 hours
C.9 hours and 12 minutes
D.15 hours
Answer: B.36/37 hours
Explanation: Pipe A has a rate of 60 liters per minute which equals a rate of 3600 liters per hour.
Pipe B has a rate of 100 liters per hour.
100 + 3600 (A+B) = Together they have a rate of 3700 liters per hour.
3600 (The pool) / 3700 = 36/37 hours
Answer -B
Question: Angela, Bernie, and Colleen can complete a job, all working together, in 3 hours. Angela and Bernie, working together at their respective rates, can complete the same job in 5 hours. How long would it take Colleen, working alone, to complete the entire job?
A.7.5 hours
B.10 hours
C.12 hours
D.16 hours
Answer: A.7.5 hours
Explanation: A+B+C complete the job in 3 hours.
A+B complete the job in 5 hours.
A+B and C complete the job in 3 hours -->1/(A+B) + 1/C = 1/3-->1/5+1/C=1/3 ----> C=7.5 hours. ANS A
Question: HCF and LCM two numbers are 16 and 396 respectively. If one of the numbers is 36, then the other number is?
A.36
B.66
C.132
D.176
Answer: D.176
Explanation: 16 * 396 = 36 * x
x = 176
ANSWER:D
Question: A man has Rs. 312 in the denominations of one-rupee notes, five-rupee notes and twenty-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
A.36
B.24
C.28
D.32
Answer: A.36
Explanation: Explanation :
Let the number of notes of each denomination be x
Then, x + 5x + 20x = 312
=> 26x = 312
=> x = 312/26 = 12
the total number of notes that he has = 3x = 3 × 12 = 36
Answer : A
Question: If shares of two persons in profits are Rs.400 and Rs.500 then ratio of their capitals is
A.3:4
B.4:5
C.4:3
D.1:3
Answer: B.4:5
Explanation: profit=time*capital
so 400:500=4:5
ANSWER:B
Question: Brian is analyzing the performance of certain stocks. He finds that for the first fifteen days of a 30 day period, the daily closing price per share of Phoenix Pharma Inc. conformed to the function f(x)=0.4x+2f(x)=0.4x+2 , where x represents the day in the period. He found that for the last 15 days in the same period, the stock followed the function f(x)=(−1/7)x+9f(x)=(−1/7)x+9, where x represents the day in the period. Approximately what is the median closing price per share of Phoenix Pharma Inc. for the entire 30 day period?
A.4.7
B.5.55
C.6.71
D.8
Answer: B.5.55
Explanation: First 15 days: F1, x= 1 to 15 and f(x)= 2.4 to 8
Last 15 days: F2, x= 16 to 30 and f(x) = ~4.7 to ~6.7 (30th to 16th)
Median is average of 15th and 16th value when all of the above values are arranged in order
Do not try to calculate all the values. Go for the choices.
11.1 - outside the range of values
8- last value
6.71 - last value for the F2, so already we have 15 values less than 6.71. Additionally F1 has some values less.
4.7 - First value for the F2, so already we have 15 values greater than 4.7. Additionally F1 has some values greater.
Hence 5.55 must be the answer.
ANSWER:B
Question: Set J consists of 10 consecutive even numbers. If the smallest term in the set is -4, what is the range of the positive integers in set J?
A.8
B.12
C.14
D.16
Answer: B.12
Explanation: Since there are only 10 integers, another approach is the just list all 10.
We get: -4, -2,0,2, 4, 6, 8, 10, 12, 14
Range of POSITIVE INTEGERS =14-2= 12
Answer: B
Question: Someone on a skateboard is traveling 15 miles per hour. How many feet does she travel in 30 seconds? (1 mile = 5280 feet)
A.600 ft
B.660 ft
C.670 ft
D.680 ft
Answer: B.660 ft
Explanation: per second => 15*5280 ft/60*60 =22 ft
30 seconds => 22 * 30 = 660 ft
Answer : B
Question: A ratio between two numbers is 3 : 4 and their L.C.M. is 84. The first number is
A.60
B.45
C.21
D.15
Answer: C.21
Explanation: Sol.
Let the required numbers be 3x and 4x. Then, their L.C.M. is 12x.
∴ 12x = 84⇔ x = 7. Hence, the first number is 21.
Answer C
Question: On Saturday morning, Malachi will begin a camping vacation and he will return home at the end of the first day on which it rains. If on the first three days of the vacation the probability of rain on each day is 0.2, what is the probability that Malachi will return home at the end of the day on the following Monday?
A.0.008
B.0.128
C.0.488
D.0.512
Answer: C.0.488
Explanation: Probability of rain on Saturday OR Probability of rain on Sunday (given that it didn't rain on Saturday) OR Probability of rain on Monday (given that it didn't rain on Sunday)
= 0.2 + (0.8 x 0.2) + (0.8 x 0.8 x 0.2)
= 0.2 + 0.16 + (0.128 <- The actual answer!)
=0.488
ANSWER:C
Question: What will come in place of the x in the following Number series? 6, 12, 21, x , 48
A.33
B.45
C.75
D.56
Answer: A.33
Explanation: (A)
The pattern is + 6, + 9, + 12, +15 ………..
So the missing term is = 21 + 12 = 33
Question: A person sells 36 oranges per rupee and suffers a loss of 4%. Find how many oranges per rupee to be sold to have again of 8%?
A.30
B.31
C.32
D.33
Answer: C.32
Explanation: 1⁄36 : (100 - 4) :: x : (100 + 8)
⇒ x = 108/96×36=132
He sells 32 oranges per rupee.
Answer C
Question: A can do a job in 20 days and B can do it in 30 days. A and B working together will finish twice the amount of work in days?
A.22 1/6
B.24
C.22 1/0
D.22 1/9
Answer: B.24
Explanation: 1/20 + 1/30 = 5/60 = 1/12
12 = 12 *2 = 24 days
Answer: B
Question: A walks at 10 kmph and 7 hours after his start, B cycles after him at 20 kmph. How far from the start does B catch up with A?
A.100km
B.140km
C.50km
D.120km
Answer: B.140km
Explanation: Suppose after x km from the start B catches up with A. Then, the difference in the time taken by A to cover x km and that taken by B to cover x km is 7 hours.
x/10 - x/20 = 7
x = 140 km
Answer is B
Question: A car travells the first 1/2 of certain distance with a speed of 10km/hr the next 1/4 distance witha a speed of 20 km/hr, and the last 1/4 distance with a speed of 60 km/hr. the average speed of the carfor the whole journey is?
A.12km/hr
B.15km/hr
C.89km/hr
D.52km/hr
Answer: B.15km/hr
Explanation: Let the whole distance travelled be x km
and the average speed of the car for he whole journey be y km/hr
then (x/2)/10+(x/4)/20+(x/4)/60=x/y
x/20+x/80+x/240=x/y
1/15y=1
y=15km/hr
Answer(B)
Question: Two carpenters, working in the same pace, can build 2 desks in two hours and a half. How many desks can 4 carpenters build in 3 hours?
A.2.4.
B.3.6.
C.4.8.
D.5.5.
Answer: C.4.8.
Explanation: W = 2 desks
T = 2.5 hrs
Rate of 2 carpenters = 2×R
Rate = work done/ time
2xR = 2/2.5
R = 1/2.5 = 2/5 (this is the rate of each carpenter)
Work done by 4 carpenters in 3 hrs = 4 × rate of each carpenter x time = 4× 2/5 × 3 =4.8 desks
C is the correct answer.
Question: The average of four results is 222 and that of the first three is 219. The fourth result is?
A.231
B.201
C.85
D.192
Answer: A.231
Explanation: 4 * 222 â€“ 3 * 219 = 231
Answer: A
Question: A train passes a man standing on a platform in 8 seconds and also crosses the platform which is 267 metres long in 20 seconds. The length of the train (in metres) is:
A.178
B.176
C.175
D.96
Answer: A.178
Explanation: Explanation:
Let the length of train be L m.
Acc. to question
(267+L)/20 = L/8
2136+8L=20L
L= 2136/12 = 178 m
Answer A
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
A.76 km/hr
B.50 km/hr
C.17 km/hr
D.18 km/hr
Answer: B.50 km/hr
Explanation: Speed of the train relative to man
= (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr
= 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed
= (x - 5) km/hr. x - 5
= 45 ==> x = 50 km/hr.
Answer: B
Question: In a cinema hall for the matinee show which started at 2.30 pm and ended at 5.30 pm the vehicle parking lot had only three wheelers (auto rickshaws) and four wheelers. Today the wheels of the vehicles parked was counted and found to be 240. What could be the number of three wheelers parked therein ?
A.10
B.48 wheelers
C.37
D.97
Answer: B.48 wheelers
Explanation: 3X + 4y = 240
by substitute through options 48 is correct
Answer: B
Question: To fill an art exhibit, the students in an art course are assigned to create one piece of artwork each in the following distribution: 1/3 are sculptures, 1/8 are oil paintings, 1/2 are watercolors, and the remaining 10 pieces are mosaics. How many students are in the art class?
A.80
B.120
C.240
D.320
Answer: C.240
Explanation: Let the total number of students in the art class = s
Distribution of artwork is as
1/3 are sculptures
1/8 are oil paintings
1/2 are watercolors, and the remaining 10 pieces are mosaics
(1/3)s +(1/8)s +(1/2)s + 10 = s
Since remaining 10 pieces are mosaics , (1/24)s = 10
s = 240
Answer C
Question: A garrison of 400 men had a provision for 31 days. After 26 days 275 persons re-enforcement leave the garrison. Find the number of days for which the remaining ration will be sufficient?
A.16 days
B.45 days
C.10 days
D.17 days
Answer: A.16 days
Explanation: 400 --- 31
400 --- 5
125 --- ?
400*5 = 125*x => x =16 days.
Answer: A
Question: Simplify: 0.4*0.5+0.3*0.2
A.0.52
B.0.26
C.0.48
D.0.64
Answer: B.0.26
Explanation: Given exp. = 0.4*0.5+(0.3*0.2) = 0.2+0.06 = 0.26
Answer is B.