RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a class of 40 students, 2 students did not borrow any books from the library, 12 students each borrowed 1 book, 12 students each borrowed 2 books, and the rest borrowed at least 3 books. If the average number of books per student was 2, what is the maximum number of books any single student could have borrowed?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: The class borrowed a total of 40*2 = 80 books.
The 26 students who borrowed 0, 1, or 2 books borrowed a total of 12 + 12*2 = 36.
To maximize the number of books borrowed by 1 student, let's assume that 13 students borrowed 3 books and 1 student borrowed the rest.
80 - 36 - 3*13 = 5
The maximum number of books borrowed by any student is 5.
The answer is C.
Question: A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.2662 in 3 years. Find the rate percent?
A.12%
B.10%
C.90%
D.80%
Answer: B.10%
Explanation: 2420 --- 242
100 --- ? => 10%
Answer: B
Question: Rs.1690 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share?
A.s.528
B.s.542
C.s.780
D.s.540
Answer: C.s.780
Explanation: A+B+C = 1690
4A = 3B = 2C = x
A:B:C = 1/4:1/3:1/2 = 3:4:6
6/13 * 1690 = Rs.780
Answer: C
Question: Three unbiased coins are tossed. What is the probability of getting at most two heads?
A.3/4
B.7/8
C.3/8
D.5/6
Answer: B.7/8
Explanation: Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P(E)=n(E)/n(S)
=7/8
The answer should be B
Question: A test has a mean of 110 and a standard deviation of 5, find the corresponding x score for: a) a test score of 116?
A.A)6/5
B.B)2.4
C.C)5
D.D)5.6
Answer: A.A)6/5
Explanation: A test has a mean of 110 and a standard deviation of 5,
find the corresponding x score for:
a) a test score of 116,
x(116) = (116-110)/5= 6/5
Option A
Question: 8, 19, 30, 41, 52, ….
Given the sequence above, what is the sum of the 13th and the 20th terms?
A.324
B.335
C.346
D.357
Answer: D.357
Explanation: The first term is 8 = 11 – 3. The second term is 19 = 22 – 3, the third term is 30 = 3 × 11 – 3, the fourth term is 41 = 4 × 11 – 3, etc.
Thus, 11n – 3 describes the values in the sequence where n is the number of the term.
The 13th term is 13 × 11 – 3 = 140
The 20th term is 20 × 11 – 3 = 220 – 3 = 217.
The sum of these two values is 357
The correct answer is choice (D).
Question: A train 440 meters long is running with a speed of 54 kmph. The time taken by it to cross a tunnel 180 meters long is?
A.40.33 sec
B.41.33 sec
C.42.33 sec
D.40 sec
Answer: B.41.33 sec
Explanation: D = 440 + 180 =620
S = 54 * 5/18 = 15 mps
T = 620/15 = 41.33 sec
ANSWER:B
Question: Maney bought shares for a total value of $1000. Next day, the price of shares is reduced by 10%. With the same $1000, he could now buy 10 more shares. Which of the following is closest to the original price per share?
A.$10
B.$11
C.$12
D.$13
Answer: B.$11
Explanation: From the given information,we can conclude that Maney bought x number of shares for $1000. With a 10% reduction in price, he could buy the same x number of shares for 1000*.90 = $900 . With the remaining money ($1000 - $900 = $100), he can buy 10 more shares. So, the reduced price per share = $100/10 = $10.
Therefore, if the reduced price of $10 equals the original price * 9/10, then the original price is approximately $11=B
Question: The closest approximation of W(69.28 × 0.004)/0.03 is
A.0.092
B.0.92
C.9.2
D.92
Answer: C.9.2
Explanation: W(69.28 × 0.004)/0.03
1. 0.004 = 4 × 10^(-3)
2. 0.03 = 3 × 10^(-2)
3. (a × b)/c = a × (b/c)
4. 0.004/0.03 = 4 × 10^(-3)/ (3 × 10^(-2)) = 4 × 10^( -3 - (-2))/3 = 4 × 10^(-1) / 3 = (4/3) × 10^(-1) = 1.333 × 10^(-1)
Therefore,
(69.28 × 0.004)/0.03 = 69.28 × (0.004/0.03) = 69.28 × 1.33 × 10^(-1) = 69.28 × 1.33/10 = 6.928*1.33
Now,
7 × 2 = 14
7 × 1 = 7
or better:
6.9 × 1 = 6.9
6.9 × 2 = 13.8
hence,
6.9 <6.928 × 1.33 < 13.8
9.2 is the only answer that satisfies this condition.C
Question: Simplify: 99^48/49 * 245.
A.23345
B.26695
C.24495
D.25575
Answer: C.24495
Explanation: Given expression = (100-1/49) * 245=(4899/49) * 245 = 4899 * 5=24495.
Answer is C.
Question: If x and y are integers and x=50y + 59, which of the following must be odd?
A.xy
B.x +2y
C.x + y
D.3x-1
Answer: B.x +2y
Explanation: x = 50y + 59, since y is integer, 50y will always be even hence 50y + 59 will be odd hence x = odd
you don't know whether Y is even or odd, so you need to try.
A: odd * even = even ; odd*odd= odd ->not true
C: odd + odd = even ; odd+even = odd -> not true
B: odd + 2*odd = odd ; odd + 2*even = odd -> TRUE, .
D&E WILL BE EVEN IF X IS ODD
Answer B
Question: By selling an article at Rs.600, a profit of 25% is made. Find its cost price?
A.Rs.482
B.Rs.429
C.Rs.480
D.Rs.408
Answer: C.Rs.480
Explanation: SP = 600
CP = (SP)*[100/(100+P)]
= 600 * [100/(100+25)]
= 600 * [100/125] = Rs.480
Answer:C
Question: The diagonal of a rhombus are 62 m and 80 m. Its area is:
A.1940
B.2480
C.2460
D.2500
Answer: B.2480
Explanation: Area of the rhombus = 1/2 d1d2 = ( 1/2 Ã— 62 Ã— 80) Cm(power)2
= 62 Ã— 40 = 2480 Cm(power)2
Answer is B.
Question: What is the value of 10^6 - 6^4?
A.9,97,111
B.9,97,322
C.9,98,704
D.9,98,851
Answer: C.9,98,704
Explanation: As 10^n will always have last digit as 0 AND 6^n will always as last digit 6.. hence difference of such sum should always be ending with 4 and there is only on option ..
Answer C
Question: There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of $ 12,000 after 3 years at the same rate?
A.$2160
B.#3120
C.$3972
D.$6240
Answer: C.$3972
Explanation: Let P = $ 100. Then, S.I. $. 60 and T = 6 years.
R = 100 x 60 = 10% p.a.
100 x 6
Now, P = $ 12000. T = 3 years and R = 10% p.a.
C.I.	= $ 12000 x 1 +	10 3	- 1
100
= $ 12000 x	331
1000	=3972
ANSWEWR : C 3972
Question: When 1/10 percent of 2,000 is subtracted from 1/10 of 2,000, the difference is
A.1980
B.1998
C.198
D.200
Answer: C.198
Explanation: (1/10)*2000 - (1/10)%*2000 =
200 - (1/1000)*2000 =
200 - 2 = 198
The answer is C.
Question: The price of a jacket is reduced by 25%. During a special sale the price of the jacket is reduced another 25%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount?
A.32.5
B.77.78
C.48
D.65
Answer: B.77.78
Explanation: 1) Let the price of jacket initially be $100.
2) Then it is decreased by 25% , therefore bringing down the price to $75.
3) Again it is further discounted by 10%, therefore bringing down the price to $56.25
4) Now 56.25 has to be added byX %in order to equal the original price.
56.25 + ( X% ) 56.25 = 100.
Solving this eq for X, we get X = 77.78
Ans is B.
Question: A single discount equivalent to the discount series of 20%, 15% and 8% is?
A.37.4
B.31.8
C.31.6
D.31.3
Answer: A.37.4
Explanation: 100*(80/100)*(85/100)*(92/100)
= 62.6
100 - 62.6 = 37.4
Answer:A
Question: Natasha climbs up a hill, and descends along the same way she went up. It takes her 4 hours to reach the top and 2 hours to come back down. If her average speed along the whole journey is 2 kilometers per hour, what was her average speed (in kilometers per hour) while climbing to the top?
A.1.5
B.2.5
C.3.75
D.5
Answer: A.1.5
Explanation: Let the distance to the top be x, so the total distance traveled by Natasha is 2x.
The total time is 4 + 2 = 6 hours
The average speed = total distance/total time taken = 2x/6 = x/3
The average speed of the complete journey is 2 km/hour
x/3 = 2
x = 6 km
The average speed while climbing = distance/time = 6/4 = 1.5 km/h
The answer is A.
Question: In a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 200-gram mixture, 50 grams of pure milk is added, what would be the percentage of milk in the resulting mixture?
A.84%
B.85%
C.86%
D.87%
Answer: A.84%
Explanation: The amount of milk is 0.8(200) + 50 = 210 grams.
The proportion is 210/250 = 0.84 which is 84%
The answer is A.
Question: On multiplying a number X by 153, the result obtained was 102325. However, it is found that both the 2's are wrong. Find the correct result.
A.104345
B.107375
C.108385
D.109395
Answer: D.109395
Explanation: The only thing you actually know about the correct number X is that it is divisible by 153 and has 5 as a factor.
You should immediately try to find the factors of 153 and look for them in the options.
153 = 9*17
Divisibility by 9 is easy to check. Only (D) satisfies.
Question: A train 260 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
A.40
B.32
C.26
D.21
Answer: B.32
Explanation: Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 260 + 140 = 400 m
Required time = 400 * 2/25 = 32 sec
Answer:B
Question: The cost price of a radio is Rs.2400 and it was sold for Rs.1980, find the loss %?
A.17%
B.12%
C.22%
D.24%
Answer: A.17%
Explanation: 2400 ---- 420
100 ---- ? => 17%
Answer:A
Question: 107 Ã— 107 + 93 Ã— 93 = ?
A.20198
B.20098
C.20000
D.20088
Answer: B.20098
Explanation: Explanation :
(a + b)2 + (a âˆ’ b)2 = 2(a2 + b2)
(Reference : Basic Algebraic Formulas)
1072 + 932 = (100 + 7)2 + (100 âˆ’ 7)2 = 2(1002 + 72) = 2(10000 + 49) = 20098. Answer : Option B
Question: Solve the given two equations and find the inequality of X and Y.(a) x^2-7x+12=0 and (b) y^2-12y+32=0
A.If x>y
B.If x>=y
C.If x < y
D.If X<= Y
Answer: D.If X<= Y
Explanation: Solution:-
X=3,4 and Y= 4,8
X<= Y
D
Question: Jonathan can type a 30 page document in 40 minutes, Susan can type it in 30 minutes, and Jack can type it in 24 minutes. Working together, how much time will it take them to type the same document?
A.5 minutes
B.10 minutes
C.15 minutes
D.18 minutes
Answer: B.10 minutes
Explanation: You may set up common equation like this:
job/A+job/B+job/C=job/x
Memorize this universal formula, you will need it definitely for GMAT.
and find x from this equation
In this specific case, the equation will look like this:
30/40+30/30+30/24=30/x
If you solve this equation, you get the same answer B (10)
Question: In how many years Rs 200 will produce the same interest at 10% as Rs. 1000 produce in 2 years at 12%
A.13
B.9
C.11
D.12
Answer: D.12
Explanation: Explanation:
Clue:
Firstly we need to calculate the SI with prinical 1000,Time 2 years and Rate 12%, it will be Rs. 240
Then we can get the Time as
Time = (100*240)/(200*10) = 12
Option D
Question: The amount of an investment will double in approximately 70/ p years, where p is the percent interest, compounded annually. If Thelma invests $ 60,000 in a long-term CD that pays 5 percent interest, compounded annually, what will be the approximate total value of the investment when Thelma is ready to retire 42 years later?
A.$ 280,000
B.$ 320,000
C.$ 360,000
D.$ 480,000
Answer: D.$ 480,000
Explanation: The amount of an investment will double in approximately 70/ p years, where p is the percent interest, compounded annually. If Thelma invests $ 60,000 in a long-term CD that pays 5 percent interest, compounded annually, what will be the approximate total value of the investment when Thelma is ready to retire 42 years later?
The investment gets doubled in 70/p years. Therefore, the investment gets doubled in 70/5= every 14 years. After 42 years, the investment will get doubled 42/14= 3 times.
So the amount invested will get doubled thrice.
So, 60000 *2^3 = 480000
Hence, the answer is D.
Question: A invested some money in 8% stock at 96.If B wants to invest in an equally good 10% stock ,he must purchase a stock worth of :
A.Rs. 120
B.Rs. 60
C.Rs. 128
D.Rs. 130
Answer: A.Rs. 120
Explanation: Solution
For an income of Rs. 8, investment = Rs. 96.
For an income of Rs. 10, investment = Rs.(96/8x10) = Rs. 120
Answer A
Question: The fourth proportional to 18, 14 and 18 is?
A.14
B.66
C.77
D.88
Answer: A.14
Explanation: (14*18)/18 = 14
Answer: A
Question: 17200 x 223 + 17200 x 77 = ?
A.2736900
B.2738800
C.2658560
D.5160000
Answer: D.5160000
Explanation: =17200 x (223+77) (by distributive law)
=17200 x 300
=5160000
Answer is D
Question: Aishwarya was first to board to her flight to delhi.
She forgot her seat number and picks a random seat for herself.
After this, every single person who get to the flight sits on his seat if its available else chooses any available seat at random.
Abhishek is last to enter the flight and at that moment 99/100 seats were occupied.
Whats the probability what Abhishek gets to sit in his own seat ?
A.1/2
B.3/2
C.3/2
D.2/2
Answer: A.1/2
Explanation: A
1/2
one of two is the possibility
1. If any of the first 99 people sit in Abhishek seat, Abhishek will not get to sit in his own seat.
2. If any of the first 99 people sit in Aishwarya's seat, Abhishek will get to sit in his seat.
Question: A person want to give his money of $15800 to his 4 children A,B,C,D in the ratio 5:9:6:5. What is the A+C share?
A.$4000
B.$2890
C.$3005
D.$6952
Answer: D.$6952
Explanation: A's share = 15800*5/25= $3160
C's share = 15800*6/25 = $3792
A+C = $6952
Answer is D
Question: Pipe A can fill a tank in 3 hours, pipe B in 4 hours, and pipe C in 12 hours. If all the pipes are open, in how many hours will the tank be filled?
A.1.1
B.1.3
C.1.5
D.1.7
Answer: C.1.5
Explanation: The part filled by A + B + C in 1 hour is 1/3 + 1/4 + 1/12 = 2/3
All the three pipes together will fill the tank in 1.5 hours.
The answer is C.
Question: If 10 litres of an oil of Rs.50 per litres be mixed with 5 litres of another oil of Rs.68 per litre then what is the rate of mixed oil per litre?
A.Rs.49.17
B.Rs.51.03
C.Rs.56
D.Rs.55.33
Answer: C.Rs.56
Explanation: 50*10 = 500
68*5 = 340
840/15 = 56
ANSWER:C
Question: The difference between compound and simple interest on a certain sum of money for 3 years at 6 2/3% p.a is Rs.184. Find the sum?
A.22887
B.28779
C.27677
D.13500
Answer: D.13500
Explanation: P = (184*106) / [6 2/3 * 6 2/3 *(300*6 2/3)]
P = 13500
Answer:D
Question: Ashley and Betty start a business with $9000 each, and after 3 months, Betty adds another $5000. How should they share the profits at the end of the 24 months?
A.72:107
B.4:5
C.17:23
D.3:4
Answer: A.72:107
Explanation: Ashley invests $9000 for 24 months, but Betty invests $9000 for the first 3 months and then adds $5000. So, the investment of Betty for remaining 21 months is $14000.
Ashley:Betty
9000*24 : (9000*3) + (14000*21)
216000 : 321000
A:B = 72:107
Answer: A
Question: The profit earned by selling an article for 872 is equal to the loss incurred when the same article is sold for 448. What should be the sale price of the article for making 50 per cent profit?
A.960
B.990
C.1,200
D.920
Answer: B.990
Explanation: Let the profit or loss be x
and 872 – x = 448 + x or, x = 424⁄2 = 212
\ Cost price of the article = 872 – x = 448 + x = 660
\ SP of the article = 660 × 150⁄100 = 990
Answer B
Question: x is the product of each integer from 1 to 75, inclusive and y=100^k, where k is an integer . What is the greatest value of k for which y is a factor of x?
A.8
B.7
C.6
D.9
Answer: D.9
Explanation: The number of trailing zeros in the decimal representation of n!, the factorial of a non-negative integer n, can be determined with this formula:
n5+n52+n53+...+n5k, where k must be chosen such that 5k≤n
x = 1*2*3....*75 = 50!
No. of trailing zeros in 75! = 75/5 + 75/5^2 = 15+3 = 18
100^k = 10^2k → k = 18/2 = 9
D
Question: Each of the numbers x1, x2...., xn, n > 4, is equal to 1 or –1.
Suppose, x1x2x3x4 + x2x3x4x5 + x3x4x5x6 + ... + xn–3xn–2xn–1xn + xn–2xn–1xnx1 + xn–1xnx1x2 + xnx1x2x3= 0, then,
A.n is even
B.n is odd.
C.n is an odd multiple of 3.
D.n is prime
Answer: A.n is even
Explanation: Explanation :
Every term of the eq : x1x2x3x4 + x2x3x4x5 + x3x4x5x6 + ... + xn–3xn–2xn–1xn + xn–2xn–1xnx1 + xn–1xnx1x2 + xnx1x2x3= 0, would either be 1 or -1 (product of 1's and -1's would never be anything else).
Now for the equation to be true number of 1's would have to be equal to number -1's thus there would always be even number of terms in the equation. Now for that to be true n would have to be even.
Say for example n=6: x1x2x3x4 + x2x3x4x5 + x3x4x5x6 + x6x1x2x3.
We see there are 4 terms in the equation, we can have 2 1's and 2 -1's. So , n is even.
Answer : A
Question: A six faced die is so biased that it is twice as likely to show an even number as an odd. It is thrown twice. What is the probability that the sum of the numbers is even?
A.1/3
B.2/3
C.5/9
D.6/11
Answer: C.5/9
Explanation: Probability of getting an even number = 2/3
Probability of getting an odd number = 1/3
since the dice is biased.
The sum is even if
(even,even) or (odd,odd)
[P(even).P(even)] + [P(odd).P(odd)]
2/3 * 2/3 + 1/3 * 1/3 = 4/9 + 1/9 = 5/9
ANSWER:C
Question: Look at this series: 664, 332, 340, 170, ____, 89, ... What number should fill the blank?
A.85
B.97
C.109
D.178
Answer: D.178
Explanation: Answer: Option D
This is an alternating division and addition series: First, divide by 2, and then add 8.
Question: If the price has fallen by 12% what percent of its consumption be: increased so that the expenditure may be the same as before?
A.11 1/8%
B.11 1/5%
C.11 1/9%
D.13 7/11%
Answer: D.13 7/11%
Explanation: 100 â€“ 12 = 88
88------12
100------? => 13 7/11%
Answer: D
Question: What is the greatest 6-digit number when divided by 8 , 9, and 10 leaves a remainder of 6, 7, and 8 respectively?
A.456780
B.678918
C.997479
D.997916
Answer: B.678918
Explanation: When you divide a positive integer by 10, the remainder will just be the units digit. We know the remainder is 8 when we divide by 10, so B is the only possible answer.
Question: If a code word is defined to be a sequence of different letters chosen from the 10 letters A, B, C, D, E, F, G, H, I, and J, what is the ratio of the number of 5-letter code words to the number of 3-letter code words?
A.5 to 4
B.3 to 2
C.42 to 1
D.5 to 1
Answer: C.42 to 1
Explanation: Number of ways to form 5-letter code: 10!/5! = 10*9*8*7*6
Number of ways to form 3-letter code: 10!/7! = 10*9*8
Ratio: 42 to 1
Answer : C
Question: After getting 2 successive discounts, a shirt with a list price of Rs 150 is available at Rs 105. If the second discount is 12.55,find the first discount
A.22%
B.23%
C.21%
D.20%
Answer: D.20%
Explanation: Let the first discount be x%
Then,87.5% of (100-x)% of 150= 105
87.5/100*(100-x)/100*450=150=>105=>100-x=(105*100*100)/(150*87.5)=80
x=(100-80)=20
first discount = 20%
Option D
Question: A 360 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
A.220 meter
B.225 meter
C.140 meter
D.235 meter
Answer: C.140 meter
Explanation: Explanation:
As trains are running in opposite directions so their relative speed will get added
So, Relative speed = 120 +80 = 200 kmph
= 200*(5/18) = 500/9 m/sec
Let the length of other train is x meter then
x+360 /9=500 /9
=>x+360=500
=>x=140
So the length of the train is 140 meters
Option C
Question: If p and q are positive integers, how many integers are larger than pq and smaller than p(q + 1)?
A.3
B.P + 2
C.p – 1
D.2p – 1
Answer: C.p – 1
Explanation: The number of integers between x and y, where x>y is (x-y)-1. For example, the number of integers between 1 and 5 is (5-1)-1=3: 2, 3, and 4.
Thus, the number of integers between pq and p(q+1)=pq+p is (pq+p-pq)-1=p-1.
Answer: C.
Question: The speed of a boat in still water is 15 km/hr and the rate of the current is 3 km/hr. The distance travelled downstream in 12 minutes is
A.1.2 km
B.1.8 km
C.2.4 km
D.3.6 km
Answer: D.3.6 km
Explanation: Speed Downstream = (15 + 3) km/hr
= 18 km/hr.
Distance travelled = (18 x 12/60) hours
= 3.6km.
Answer D
Question: At what rate percent of simple interest will a sum of money double itself in 12 years?
A.8 1/6 %
B.8 1/3 %
C.8 8/3 %
D.8 3/3 %
Answer: B.8 1/3 %
Explanation: Let sum = x. Then, S.I. = x.
Rate = (100 * S.I.) / (P * T) = (100 * x) / (x * 12)
= 25/3 = 8 1/3 %.Answer: B
Question: A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group?
A.400
B.600
C.287
D.278
Answer: B.600
Explanation: Explanation:
Two men, three women and one child can be selected in â´Câ‚‚ * â¶Câ‚ƒ * âµCâ‚ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways.
Answer:B
Question: If a - b = 3 and a^2 + b^2 = 28, find the value of ab.
A.19
B.15
C.10
D.8
Answer: D.8
Explanation: 2ab = (a^2 + b^2) - (a - b)^2
= 25 - 9 = 16
ab = 8.
Answer is D.
Question: At an examination in which full marks were 500. A got 10% less than B, B got 25% more than C and C got 20% less than D. If A got 360marks, what percentage of full marks was obtained by D?
A.70%
B.90%
C.80%
D.75%
Answer: C.80%
Explanation: A B C D
90 100 80 100
A D
90 ----- 100
360 ------ ? = 400
500 ------ 400
100 ------- ? => 80%
ANSWER:C
Question: What will be the compound interest on a sum of Rs. 22,000 after 3 years at the rate of 12% p.a.?
A.s.8908.41
B.s.1823.20
C.s.6123.20
D.s.10123.29
Answer: A.s.8908.41
Explanation: Explanation:
Amount = [22000 * (1 + 12/100)3]
= 22000 * 28/25 * 28/25 * 28/25 = Rs. 35123.20
C.I. = (35123.20 - 22000) = Rs.8908.41
Answer:A
Question: What will be the area of a semi-circle of 14 metres diameter?
A.154 sq metres
B.77 sq metres
C.308 sq metres
D.22 sq metres
Answer: B.77 sq metres
Explanation: Area of semicircle = ½πr2
= ½ × 22⁄7 × 7 × 7 = 77 m2
Answer B
Question: A man whose bowling average is 12.4, takes 6 wickets for 26 runs and there by decreases his average by 0.4. the number of wickets taken by him before his last match is?
A.113
B.114
C.115
D.116
Answer: C.115
Explanation: 12.4*x+26=(6+x)12
solve equation x=115
ANSWER:C
Question: Find the greatest number that, while dividing 47, 215 and 365, gives the same remainder in each case?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: Calculate the differences, taking two numbers at a time as follows:
(215-47) = 168
(365-215) = 150
(365-47) = 318
HCF of 168, 150 and 318 we get 6, which is the greatest number, which while dividing 47, 215 and 365 gives the same remainder in each cases is 5.
ANSWER:C
Question: pipes P and Q would fill a cistern 18 and 24 minutes respectively. Both pipes being opened, find when the first pipe must be turned off so that the cistern may be just filled in 12 minutes?
A.6
B.9
C.5
D.4
Answer: B.9
Explanation: x/18 + 12/24 = 1
x = 9
Answer:B
Question: A set of football matches is to be organized in a "round-robin" fashion, i.e., every
participating team plays a match against every other team once and only once. If 6
matches are totally played, how many teams participated?
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: 2 ways to solve this problem..
summation(x)=n(n-1)/2
n(n-1)/2=6;
n^2-n-12=0
Ans : 4
ANSWER:A
Question: Pooja is selling her books at puzzles land at a strange price as
* she sells her book "Vanity" at $30
* she sells her book "Sybil" at $25
* she sells her book "xmen" at $20
At what price does she sell her book "twilight" ?
A.54
B.23
C.40
D.87
Answer: C.40
Explanation: C
40
Cost of each alphabet is 5
Question: Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 30 percent was planted with soybeans and 60 percent of the cleared land was planted with wheat. If the remaining 540 acres of cleared land was planted with corn, how many acres did the farmer own?
A.7200
B.6000
C.3500
D.5000
Answer: B.6000
Explanation: 30% od 90% = 27%, 60% 0f 90% = 54% so the remaining 90-27-54=9%=540 acres or 10% of 90%=9% --> 540/9*100=6000 acres Answer (B)
Question: John spent 40 percent of his earning last month on rent and 30 percent less than what he spent on rent to purchase a new dishwasher. What percent of last month's earning did John have left over?
A.30%
B.32%
C.45%
D.68%
Answer: B.32%
Explanation: Say John's earning last month was $100.
John spent 40 percent of his earning last month on rent --> $40 on rent;
30 percent less than what he spent on rent to purchase a new dishwasher --> $40*0.7=$28 on the dishwasher.
Left over amount 100 - (40 + 28) = $32.
Answer: B.
Question: A shopkeeper sells 600 metres of cloth for Rs. 36000 at a loss of Rs.10 per metre. Find his cost price for one metre of cloth?
A.s.59
B.s.58
C.s.09
D.s.70
Answer: D.s.70
Explanation: SP per metre = 36000/600
= Rs. 60 Loss per metre
= Rs. 10 CP per metre = 60 + 10
= Rs.70
Answer: D