RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Ms. Lopez deposits $ 100 in an account that pays 20% interest, compounded semiannually. How much money will there be in the account at the end of one year?
A.$118.00
B.$120.00
C.$121.00
D.$122.00
Answer: C.$121.00
Explanation: et me explain the concept for those who are not familiar with compounded semi annually/ quarterly etc..
it basically means, here, that the interest will be paid twice, after 6 months and at the end of year..so twice..
but interest is 20%, which will get distributed semiannually that is 10%...
so the Q literally means ..
after 6 months..
100*10/100 + 100=110..
at the end of year
110*10/100 + 110= 121..
or we put it in compound interest formula..
where CI=10%, T is 2 and P=100..
so amount = 100(1 + 10/100)^2=100*1.1*1.1=121..
ANSWER:C
Question: In a parking lot, there are some cars with a spare tire others don't. All together there are 43 tires and 9 cars. How many cars have a spare tire?
A.5
B.6
C.7
D.8
Answer: C.7
Explanation: Let's assume we are talking about 4 wheels car only.
9 cars, 4 tires per car, 9 x 4 = 36 tires.
There are total of 43 tires, 43 - 36 = 7 extra tires.
Let's assume each car has only one spare tire. ==> 7 cars with a spare tire
Answer C
Question: In how many different number of ways a Committee of 4 person of can be selected from 6 boys and 4girls such that at least 1 girl is included in the committee
A.195
B.200
C.80
D.15
Answer: A.195
Explanation: 1G 3B 2G 2B 3G B 4G
= (4C1*6C3)+(4C2*6C2)+(4C3*6C1)+4C4
= (4*20)+(6*150+(4*6)+1
= 80+90+24+1=195
Total 5M 3W
10C4=210
6C4=15
At least one girl = total - with out girl
At least one girl = 210-15=195
A)
Question: If doubling a number and adding 20 to the result gives the same answer as multiplying the number by 8 and taking away 4 from the product, the number is
A.2
B.3
C.4
D.5
Answer: C.4
Explanation: Sol.
Let the number be x.
Then, 2x + 20 = 8x - 4
⇔ 6x = 24
⇔ x = 4.
Answer C
Question: The perimeter of one square is 48 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?
A.13√7
B.13√2
C.13√1
D.13√6
Answer: B.13√2
Explanation: 4a = 48 4a = 20
a = 12 a = 5
a2 = 144 a2 = 25
Combined area = a2 = 169 => a = 13
d = 13√2
Answer: B
Question: A class has 10 students.Teacher decided to go the tour.But the seats are available only 7.What is the probability that 7 students have to go out of 10 students?
A.150
B.125
C.120
D.105
Answer: C.120
Explanation: out of 10 students, 7 students must be go to tour.
The probablity is 10C7=120
120 possible ways to go to tour
Question: The sum of five numbers is 800. The average of the first two numbers is 100 and the third number is 150. Find the average of the two numbers?
A.225
B.250
C.240
D.260
Answer: A.225
Explanation: Let the five numbers be P, Q, R, S and T.
=> P + Q + R + S + T = 800
(P + Q)/2 = 100 and R = 150
P + Q = 200 and R = 150
P + Q + R = 350
S + T = 800 - (P + Q + R) = 450
Average of the last two numbers
= (S + T)/2 = 225
Answer:A
Question: In a class of students, the ratio of girls to boys is 2:5. If 4 more girls joined the class, the ratio would be 3:5. How many students are in the class?
A.16
B.20
C.24
D.28
Answer: D.28
Explanation: Let x be the number of students in the class.
(2/7)*x=(3/8)(x+4)-4
16x=21x+84-224
5x=140
x=28
The answer is D.
Question: The amount of water (in ml) that should be added to reduce 9 ml. Lotion, containing 50% alcohol, to a lotion containing 45% alcohol, is?
A.1
B.4
C.5
D.6
Answer: A.1
Explanation: 4.5 4.5
45% 55%
45% ----- 4.5
55% ------? => 5.5 - 4.5 = 1 ml
ANSWER:A
Question: The base of a parallelogram is twice its height. If the area of the parallelogram
is 72 sq. cm, find its height.
A.5 cm
B.6 cm
C.7 cm
D.8 cm
Answer: B.6 cm
Explanation: Let the height of the parallelogram be x. cm. Then, base = (2x) cm.
2x X x =72 => 2x^2 = 72
X ^2=36
x=6
Hence, height of the parallelogram = 6 cm
Option B
Question: A and B can do a piece of work in 7 days. With the help of C they finish the work in 5 days. C alone can do that piece of work in?
A.76 days
B.86 days
C.30 days
D.57 days
Answer: C.30 days
Explanation: C = 1/5 – 1/6 = 1/30
=> 30 days
Answer: C
Question: At an Iron factory, each employee working the second shift produced 2/3 as many widgets as each employee working the first shift. If the first shift has 3/4 as many employees, what fraction of the total widgets did the second shift produce?
A.8/17
B.1/2
C.8/9
D.9/8
Answer: A.8/17
Explanation: At an Iron factory, Let the first shift have 3 employee and each produce 3 widgets, so the total number of widgets produced by the first shift is 3*3=9;
Then the second shift would have 4 employees and each second shift employee would produce 3*2/3=2 widgets, so the total number of widgets produced by the second shift employees would be 4*2=8;
The ratio of the second shift production to the total is 8/(9+8)=8/17.
Answer: A.
Question: When Tom works alone he chops 3 lb. salad in 2 minutes, and when Tammy works alone she chops 2 lb. salad in 3 minutes. They start working together, and after some time finish chopping 65 lb. of salad. Of those 80 lb., the salad quantity chopped by Tammy is what percent Lesser than the quantifying chopped by Tom?
A.44%
B.100%
C.15%
D.125%
Answer: D.125%
Explanation: Tom chops 4 lbs in 6 minutes
Tammy chops 9 lbs in 6 minutes
So in the same amount of time, Tammy chops 125% more than Tom, since 9 is 125% greater than 4. So 125% is the answer.
Note that the actual time doesn't matter. If you multiply the time each work by x, you'll multiply the work each does by x, and 9x is still 125% greater than 4x.
125% lesser than Tom
Ans:D
Question: A and B put in Rs.300 and Rs.400 respectively into a business. A reinvests into the business his share of the first year's profit of Rs.210 where as B does not. In what ratio should they divide the second year's profit?
A.39:40
B.39:45
C.39:49
D.39:44
Answer: A.39:40
Explanation: 3: 4
A = 3/7*210 = 90
390: 400
39:40
Answer: A
Question: A bag contains 6 black balls and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
A.2/3
B.3/5
C.4/7
D.5/9
Answer: C.4/7
Explanation: Total number of balls = 6+8 = 14
no. of white balls = 8
probability of drawing a white ball = 8/14 = 4/7
Answer is C
Question: A train has a length of 150 metres. It is passing a man who is moving at 22 km/hr in the same direction of the train, in 33 seconds. Find out the speed of the train.
A.182 km/hr
B.180 km/hr
C.152 km/hr
D.169 km/hr
Answer: A.182 km/hr
Explanation: Explanation:
Length of the train =150=150 m
Speed of the man =2=2 km/hr
Relative speed =1503=50 m/s=1503=50 m/s
=50Ã—185=180 km/hr=50Ã—185=180 km/hr
Relative speed = Speed of train - Speed of the man (as both are moving in the same direction). Therefore,
Speed of the train = Relative speed + Speed of the man
=180+2=182 km/hr=180+2=182 km/hr
ANSWER IS A
Question: In how many a committee of 5 members can be selected from 6men 5 ladies consisting of 3 men and 2 ladies
A.451
B.175
C.154
D.200
Answer: D.200
Explanation: (3 men out of 6) and (2 ladies out of 5) are to be chosen
Required number of ways
=(6C3 * 5C2)
= 200
Ans: D
Question: Each of the integers from 2 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 10?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: Answer is 5. In the worst case, you could end up drawing 2,3,4,5. 7th draw will result in either of 6,7,8,9 which would result in the numbers adding to 10.
C
Question: If number x is 10% less than another number y and y is 10% more than 125, then find out the value of x
A.123.85
B.130.5
C.120.2
D.150.4
Answer: A.123.85
Explanation: Consider as w
x=10%
y=10%+125
==>123.85
ANSWER A
Question: P alone can complete a piece of work in 11 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?
A.6 (1/4) days
B.33/4) days
C.7 (3/4) days
D.8 (3/4) days
Answer: B.33/4) days
Explanation: Work done by P alone in one day = 1/11 th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/11 of the total) = 1/33 of the total.
Work done by P and Q, working together in one day = 1/11 + 1/33 = 4/33 of the total
They would take 33/4 days to complete the work working together.
ANSWER:B
Question: The perimeter of a rhombus is 68 cm and one of its diagonals is 16 cm. Find its area?
A.229
B.240
C.228
D.218
Answer: B.240
Explanation: 4a = 68 => a = 17
172 – 82 = 152
1/2 * 16 * 30 = 240
Answer: B:
Question: What is the greatest possible length which can be used to measure exactly the lengths 12 m, 6 m and 40 m?
A.2m
B.5m
C.3m
D.10 m
Answer: A.2m
Explanation: Required length = HCF of 12 m, 6 m, 40m = 2m
Answer is A
Question: If $0.60 is the commission for sales of $2,000, what percent of the sales amount is the commission?
A.3%
B.0.3%
C.0.03%
D.0.003%
Answer: C.0.03%
Explanation: % of sales amount of commission
= (Commission/Total Value) *100
= (0.6/2000) * 100
= 0.03%
The answer is C.
Question: Raju and Reenu are standing in a row there are 9 peoples. what is the probability that at least 3 people will stand between Raju and Reenu
A.5/12
B.6/12
C.7/12
D.8/12
Answer: A.5/12
Explanation: 9C2=36
3 people between Raju and Reena 7+5+3=15
15/36=5/12
ANSWER:A
Question: The banker's gain on a sum due 3 years hence at 12% per annum is Rs. 360. The banker's discount is:
A.Rs. 1360
B.Rs. 1000
C.Rs. 360
D.Rs. 640
Answer: A.Rs. 1360
Explanation: Explanation :
BG = Rs. 360
T = 3 years
R = 12%
TD = (BG ×100)/TR = (360×100)/(3×12) = Rs. 1000
BG = BD – TD
=> BD = BG + TD = 360 + 1000 = Rs. 1360 Answer : Option A
Question: In Smithtown, the ratio of right-handed people to left-handed people is 3 to 1 and the ratio of men to women is 3 to 2. If the number of right-handed men is maximized, then what q percent of all the people in Smithtown are left-handed women?
A. 50%
B. 40%
C. 25%
D. 20%
Answer: C. 25%
Explanation: looking at the ratio we can take total number of people q=20..
ans 5/20 or 25% C
Question: Two dice are thrown together.What is the probability that the sum of the number on the two faces divided by 4?
A.3/9
B.4/9
C.1/9
D.2/9
Answer: D.2/9
Explanation: n(s)=6*6=36
Let e be the event that the sum of the numbers on the two faces is divisible by 4
E={(1,3),(2,2),(3,1),(2,6),(3,5),(4,4),(5,3),(6,2)}
n(e)=8
p(e)=n(e)/n(s)
=8/36
=2/9
Answer is option D
Question: A cab on its way to Bangalore overtakes an auto also going in the same direction at 11 am. The cab reaches Bangalore at 1.30 pm and starts the return journey after taking a break of 1 hour. On its way back it meets the auto at 3 pm. At what time will the auto reach Bangalore?
A.8 p.m
B.7 p.m
C.4 p.m
D.1 p.m
Answer: C.4 p.m
Explanation: Explanation:
The time interval is shown below with an interval of half hour.
11 am ------- 11:30 ------- 12 ------- 12:30 ------- 1-------1:30
At 11 the cab overtakes the auto and reaches Bangalore at 1:30. Hence, the cab travels 5 segments in two and a half hour assuming the cab to be travelling at constant
speed.
On its way back, the cab commences its journey at 2:30 and meets the auto at 3 p.m. In half an hour the cab travels one segment and hence the auto in one segment away
from Bangalore.
Therefore, the auto travels 4 segments from 11 am to 3 pm assuming it to be travelling at a constant speed. Hence, the speed of auto is 4/4 = 1 segment per hour.
As the auto is one segment away from Bangalore, it will take another 1 hour for the auto to reach Bangalore and hence the auto will reach Bangalore at 4 p.m.
ANSWER:C
Question: Two men and three women working 7 hours a day finish a work in 5 days. Four men and four women working 3 hours a day complete the work in 7 days. The number of days in which only 7 men working 4 hours a day will finish the work is?
A.6 days
B.2 days
C.7 days
D.5 days
Answer: D.5 days
Explanation: D
2M + 3W ----- 35 h
4M + 4W ------- 21 h
7M -------? d
70M + 105W = 84M +84M
21W = 14M => 2M = 3W
4 * 35 = 7 * x => x = 20 hours
20/4 = 5 days
Question: If I walk at 6 km/h, I miss the bus by 12 minutes. If I walk at 5 km/h, I reach 14 minutes before the arrival of the bus. How far I walk to reach the bus stand ?
A.13km
B.12 km
C.11 km
D.6.5 km
Answer: A.13km
Explanation: d = product of speed difference of time /difference of speed
[Here, â€“ve sign indicates before the schedule time]
d = 6Ã—5/60[12âˆ’(âˆ’14)/6-5]
â‡’ d = 13 km
Answer A
Question: The present population of a town is 60,000. The population increases annually at 10%. Find the population after 3 years.
A.86000
B.79860
C.76300
D.82900
Answer: B.79860
Explanation: Explanation :
Solution: The required population is 60000(1 + 10/100)^3 = 60000 * 110/100 * 110/100 * 110/100 = 79,860
Answer : B
Question: Of the 4 distinguishable wires that lead into an apartment, 2 are for cable television service, and 4 are for telephone service. Using these wires, how many distinct combinations of 3 wires are there such that at least 1 of the wires is for cable television?
A.6
B.7
C.8
D.9
Answer: A.6
Explanation: Given:
Total number of wires = 5
Number of cable wires = 2
Number of telephone wires = 3
To find:
Number of combination which has at least one cable wires
Solution:
No of ways of selecting'at least'1 cable wire means, we can select more than one as well. The minimum we can select is one and the maximum we can select, given the constraints that 3 wires need to be selected in total and there are 2 cable wires, is 2
Since it is a combination of wires, the arrangement is not important
Approach 1:
Number of ways of selecting at least one cable wire in a selection of 3 wires from 5 wires =Selection 1(Number of ways of selecting one cable wire and two telephone wires )+Selection 2(Number of ways of selecting two cable wires and 1 telephone wire)
Selection 1
Number of ways of selecting one cable wire = 2C1 = 2
Number of ways of selecting 2 telephone wires = 3C2 = 3
Total = 2C1 * 3C2 = 6 ( m ways of doing something and n ways of doing something else together give m*n ways of doing - the holy grail rule in Combinatorics)
Selection 2
Number of ways of selecting one cable wire = 2C2 = 1
Number of ways of selecting 2 telephone wires = 3C1 = 3
Total = 2C2 * 3C1 = 3 ( m ways of doing something and n ways of doing something else together give m*n ways of doing - the holy grail rule in Combinatorics)
Selection 1 + Selection 2 = 9 ways of selecting 3 wires out of 5 such that at least one is a cable wire
Approach 2
Number of ways of selecting 3 wires out of 5 such that at least one is a cable wire =Selection X(Total number of ways of selecting 3 wires from the 5) -Selection Y(total ways of selecting 3 wires such that none is a cable i.e all the three are telephone wires)
Total number of ways of selecting 3 wires out of 5 = 5C2 = 10
Number ways of selecting 3 wires such that none is a cable i.e all the three are telephone wires = 3C3 ( 3 telephone wires and we are selecting all the three at once) = 1
Selection X - Selection Y = 6
Answer is Option A
Question: Oak trees line both sides of a street for a length of 4/10 of a kilometer. If there is 15 meters of space between the trees, and each tree is 1 meter wide, how many trees are there along the street?
A.a)	26
B.b)	23
C.c)	24
D.d)	44
Answer: A.a)	26
Explanation: There is a gap of 15 m between every 2 trees , each tree is 1 m wide.
4/10 of 1 km = 400 m
Lets assume that x trees are planted So equation is
x*1 +(x-1)*15 = 400
Solve for x and we get x = 26, answer is A
Question: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is?
A.6
B.8
C.9
D.4
Answer: A.6
Explanation: S = 1
M = x
DS = x + 1
US = x - 1
35/(x + 1) + 35/(x - 1) = 12
x = 6
Answer:A
Question: David mixed 10 kg of ghee at Rs. 200 per kg with 30 kg ghee at the rate of Rs. 100 per kg. At what price per kg should he sell the mixture to make a profit of 50% in the transaction?
A.Rs. 180.50
B.Rs. 187.50
C.Rs. 107.50
D.Rs. 188.50
Answer: B.Rs. 187.50
Explanation: Cost of Ghee = 10*200+ 30*100 /40 =5000/40 = 125
50% of 125 = 62.50
S.P. should be = 125+62.50= Rs. 187.50/ kg
Answer : B
Question: In the faculty of Reverse-Engineering, 226 second year students study numeric methods, 423 second year students study automatic control of airborne vehicles and 134 second year students study them both. How many students are there in the faculty if the second year students are approximately 90% of the total?
A.515.
B.572.
C.618.
D.644.
Answer: B.572.
Explanation: Answer is B :572
Solution : Total number of students studying both are 423 + 226 - 134 = 515 (Subtracting the 134 since they were included in the both the other numbers already).
So 90% of total is 515, so 100% is approx. 572.
Question: Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is?
A.17/26
B.17/25
C.17/22
D.17/20
Answer: D.17/20
Explanation: n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 - 1/20 = 17/20.
Answer: D
Question: the cost if hiring a bus is shared equally by all passengers.the bus has seats for 40 passengers and the total bill comes to rs.70.37.How many seats went unoccupied?
A.13
B.11
C.10
D.9
Answer: D.9
Explanation: 70.37/31=2.27
so 31 passengers give 2.27/- each..so 9 seats unoccupied
ANSWER:D
Question: A Classroom contains 20 students. Eleven of the students are girls, nine are boys. If two students are randomly selected from the classroom, one after the other, what is the probability that both will be girls?
A.1/11
B.11/38
C.1/3
D.21/47
Answer: B.11/38
Explanation: Probability of getting the first girl student - 11/20
Probability of getting the second girl student - 10/19
total probability = 11/20*10/19 = 11/38
correct option B
Question: At 1:00 pm, a truck left city P and headed toward City Q at a constant speed of 45 km/h. One hour later, a car left City Q and headed toward City P along the same road at a constant speed of 40 km/h. If the distance between City P and City Q is 300 km, at what time will the truck and the car meet each other?
A.4:30
B.5:00
C.5:30
D.6:00
Answer: B.5:00
Explanation: At 2:00 pm, the truck and the car are 255 km apart.
The truck and the car complete a distance of 85 km each hour.
The time it takes to meet is 255/85 = 3 hours.
They will meet at 5:00 pm.
The answer is B.
Question: A bag contains five white and four red balls. Two balls are picked at random from the bag. What is the probability that they both are different color?
A.5/8
B.5/9
C.5/2
D.5/1
Answer: B.5/9
Explanation: Two balls can be picked from nine balls in ways.
We select one white ball and one red ball from five white balls and four red balls. This can be done ₁ ways.
The required probability = (5 * 4)/ = 20/36 = 5/9
Answer:B
Question: Of the 100 athletes at a soccer club, 40 play defense and 64 play midfield. If at least 20 of the athletes play neither midfield nor defense, the number of athletes that play both midfield and defense could be any number between
A.10 to 20
B.10 to 40
C.24 to 40
D.30 to 70
Answer: C.24 to 40
Explanation: First of all notice that since only 40 athletes play defense, then the number of athletes that play both midfield and defense cannot possibly be greater than 40.Eliminate D and E.
{Total} = {defense} + {midfield} - {both} + {neither}
100 = 40 + 64 - {both} + {neither}
{both} = {neither} + 4.
Since the least value of {neither} is given to be 20, then the least value of {both} is 20+4=24.Eliminate A and B.
Answer: C.
Question: An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases.
A.8:6
B.8:7
C.8:9
D.8:1
Answer: B.8:7
Explanation: Let the length and breadth of the carpet in the first case be 3x units and 2x units respectively.
Let the dimensions of the carpet in the second case be 7y, 3y units respectively.
From the data,.
2(3x + 2x) = 2(7y + 3y)
=> 5x = 10y
=> x = 2y
Required ratio of the areas of the carpet in both the cases
= 3x * 2x : 7y : 3y
= 6x2 : 21y2
= 6 * (2y)2 : 21y2
= 6 * 4y2 : 21y2
= 8:7
Answer: B
Question: 2 students gave an examination. One of them scored 9 marks more than other and his marks were 56% of the sum of total of both their marks. What are their individual marks?
A.42,38
B.42,31
C.42,32
D.42,33
Answer: D.42,33
Explanation: Explanation:
Let marks of one of the students be X.
The marks of the other will be X+9
According to question, X+9 = 56% of X+ (X+9)
Solving, X + 9 = 56/100* (2X + 9)
=> 25X + 225 = 28X + 126
=> 3X = 99
=> X = 33
Marks of one are 33, while of the other are 33+9 = 42.
ANSWER: D
Question: If the weight of 12 meters long rod is 13.4 kg. What is the weight of 6 meters long rod ?
A.6.7 kg.
B.10.8 kg.
C.12.4 kg.
D.18.0 kg
Answer: A.6.7 kg.
Explanation: Answer
∵Weight of 12 m long rod = 13.4 kg
∴ Weight of 1 m long rod = 13.4 / 12 kg
∴ Weight of 6 m long rod = 13.4 x 6 / 12
= 6.7 kg
Option: A
Question: If two numbers are in the ratio 2:3. If 15 is added to both of the numbers then the ratio becomes 3:4 then find the smallest number?
A.A)10
B.B)20
C.C)25
D.D)30
Answer: D.D)30
Explanation: 2:3
2x + 15 : 3x + 15 = 3 : 4
4[2x + 15] = 3[3x + 15]
8x + 60 = 9x + 45
9x - 8x = 60 - 45
x = 15
Then smallest number is = 2
2x = 30
Correct Option D
Question: A 25 cm wide path is to be made around a circular garden having a diameter of 4 meters. Approximate area of the path is square meters is?
A.3.34 sq m
B.4.98 sq m
C.2.88 sq m
D.2.98 sq m
Answer: A.3.34 sq m
Explanation: Area of the path = Area of the outer circle - Area of the inner circle
= ∏{4/2 + 25/100}2 - ∏[4/2]2
= ∏[2.252 - 22] = ∏(0.25)(4.25) { (a2 - b2 = (a - b)(a + b) }
= (3.14)(1/4)(17/4)
= 53.38/16
= 3.34 sq m
Answer:A
Question: If a trader sold two cars each at Rs. 325475 and gains 11% on the first and loses 11% on the second, then his profit or loss percent on the whole is?
A.1.21%
B.1.74%
C.1.84%
D.1.47%
Answer: A.1.21%
Explanation: SP of each car is Rs. 325475, he gains 11% on first car and losses 11% on second car.
In this case, there will be loss and percentage of loss is given by
= [(profit%)(loss%)]/100
= (11)(11)/100 % = 1.21%
Answer:A
Question: If a and b are both odd prime numbers and a < b, then how many different positive integer factors does 2ab have?
A.3
B.4
C.6
D.8
Answer: D.8
Explanation: a and b are both odd prime numbers- It means either a or b is not 2
and since prime numbers have only two factors - 1 and the number itself
a and b each will have (1+1)= 2 factors
Hence 2ab will have (1+1)(1+1)(1+1)= 8 factors
D is the answer
Question: A corporation triples its annual bonus to 50 of its employees. What percent R of the employees’ new bonus is the increase?
A.50%
B.662⁄3%
C.100%
D.200%
Answer: B.662⁄3%
Explanation: R of the employees’ new bonus is the increase Hence B.
Question: The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
A.348
B.177
C.342
D.165
Answer: C.342
Explanation: 400*(90/100)*(95/100)
= 342
Answer:C
Question: A tradesman by means of his false balance defrauds to the extent of 28%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
A.37
B.27
C.68.84
D.78.45
Answer: C.68.84
Explanation: Explanation:
g% = 28 + 28 + (28*28)/100
= 63.84%
Answer: C
Question: There are 5person among whom 2are brother. The total no.of ways in which these persons can be seated around a round table so that exactly 1person sit between the brothers, is equal to?
A.4!*2!
B.2!*2!
C.6!*1!
D.2!*1!
Answer: B.2!*2!
Explanation: Total number of ways = 2!*2!.
B