RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A shop sells bicycles and tricycles. In total there are 9 cycles (cycles include both bicycles and tricycles) and 21 wheels. Determine how many of each there are, if a bicycle has two wheels and a tricycle has three wheels.
A.b=2,t=3
B.b=5,t=3
C.b=6,t=3
D.b=2,t=5
Answer: C.b=6,t=3
Explanation: Let b be the number of bicycles and let t be the number of tricycles.
Set up the equations
b+t=9............(1)
2b+3t=21............(2)
Rearrange equation (1) and substitute into equation (2)
2b+27-3b=21
-b=-6
b=6
Calculate the number of tricycles t
t=9−b
=9−6
=3
There are 3 tricycles and 6 bicycles.
Answer is C.
Question: By selling 15 pencils for a rupee a man loses 60%. How many for a rupee should he sell in order to gain 60%?
A.2.15
B.4.2
C.5.18
D.3.75
Answer: D.3.75
Explanation: 40% --- 15
160% --- ?
40/160 * 15 = 3.75
Answer: D
Question: A set of numbers has the property that for any number t in the set,t+3 is in the set. If -1 is in the set, which of the following must also be in the set?
I. 2
II. 5
III. 7
A.II only
B.I only
C.I,II only
D.II,III only
Answer: C.I,II only
Explanation: question is asking for must be there elements.
According to the question if t is there t+3 must be there.
if -1 is the starting element the sequence is as follows.
S ={-1,2,5,8,11....}
if -1 is not the starting element the sequence is as follows
S = {...-4,-1,2,5,8,11...}
By observing the above two sequences we can say that 2,5 must be there in set S.
Answer : C
Question: Nine persons went to a hotel for taking their meals 8 of them spent Rs.12 each on their meals and the ninth spent Rs.8 more than the average expenditure of all the nine.What was the total money spent by them?
A.Rs.117
B.Rs.100
C.Rs.110
D.Rs.107
Answer: A.Rs.117
Explanation: Let the average expenditure of all nine be Rs.x
Then 12*8+(x+8)=9x or 8x=104 or x=13.
Total money spent = 9x=Rs.(9*13)=Rs.117.
Answer is A.
Question: In what time will a train 200 meters long completely pass an electric pole, if it travels at a speed of 80kmph.
A.7
B.9
C.5
D.10
Answer: B.9
Explanation: Sol.
Speed = [ 80x5/18] m/sec =22.2 m / sec.
Time taken = (200/22.2)sec = 9 sec.
Answer B
Question: A student multiplied a number by 3/5	instead of	5/3.What is the percentage error in the calculation?
A.34%
B.44%
C.54%
D.64%
Answer: D.64%
Explanation: Let the number be x.
Then, error =(5/3)x -	(3/5)	x =(16/15)x.
Error% =((16/15)x)	x (3/5x)x 100% = 64%.
Answer:D
Question: Rose went to a shop and bought things worth Rs. 25, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
A.19
B.19.7
C.19.9
D.20.1
Answer: B.19.7
Explanation: Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (25−30/100−x)6/100 = 30/100
⇒ 6(25 −0.3 −x) = 30
⇒ (25 − 0.3 − x) = 5
⇒ x = 25 − 0.3 − 5 = 19.7
B)
Question: If y ≠ 3 and 2h/y is a prime integer greater than 2, which of the following must be true?
I. h = y
II. y = 1
III. h and y are prime integers.
A. None
B. I only
C. II only
D. III only
Answer: A. None
Explanation: Note that we are asked which of the following MUST be true, not COULD be true. For such kind of questions if you can prove that a statement is NOT true for one particular set of numbers, it will mean that this statement is not always true and hence not a correct answer.
So we should try to make the listed statements not true for some h and y (which satisfy y≠3 and 2h/y=prime>2).
I. h = y --> not necessarily true: h=3 and y=2 (2h/y=3=prime>2);
II. y=1 --> not necessarily true: h=3 and y=2 (2h/y=3=prime>2);
III. h and y are prime integers --> not necessarily true: h=10 and y=4 (2h/y=5=prime>2).
Answer: A.
Question: In what ratio should a variety of rice costing Rs. 6 per kg be mixed with another variety of rice costing Rs. 8.75 per kg to obtain a mixture costing Rs. 7.50 per kg?
A.5/6
B.5/9
C.5/1
D.5/3
Answer: A.5/6
Explanation: Let us say the ratio of the quantities of cheaper and dearer varieties
= x : y
By the rule of allegation, x/y
= (87.5 - 7.50) / (7.50 - 6) =5/6
Answer: A
Question: If m > 1 and n = 2^(m−2), then 4^m =
A.16n^2
B.4n^2
C.n^2
D.n^2/4
Answer: A.16n^2
Explanation: n = 2^(m-2) = 2^m/4
2^m = 4n
4^m = (2^m)^2 = (4n)^2 = 16n^2
The answer is A.
Question: If a light flashes every 6 seconds, how many times will it flash in 1/2 of an hour?
A.301 times
B.351 times
C.401 times
D.451 times
Answer: A.301 times
Explanation: In 1/2 of an hour there are 30*60 = 1800 seconds
The number of 6-second intervals = 1800/6 = 300
After the first flash, there will be 300 more flashes for a total of 301.
The answer is A.
Question: If the average (arithmetic mean) of a and b is 50 and the average of b and c is 70, what is the value of c − a?
A.40
B.50
C.90
D.140
Answer: A.40
Explanation: -(a + b = 100)
b + c=140
c-a=40
A.40
Question: If y is an integer and x = 3y + 2, which of the following CANNOT be a divisor of x?
A.4
B.6
C.8
D.9
Answer: B.6
Explanation: Just to add some more to Bunuel's explanation, if a number is a multiple of 3, it will be in a form:
n = 3*k, where k is an integer
And if a number is a multiple of 6, it will be in a form :
m = 6*l, where l is an integer
so m = 2 * 3 * l = (2*l) * 3 = 3 * p, where p is an integer.
In other words, the prime factorization of m must have 3 as a factor, if it's a multiple of 6, but the expression can't have that (as explained by Bunuel), so it can't be a multiple of 6 either.
Answer is B
Question: If 1/a + 1/a + 1/a is an integer, which of the following must also be an integer?
A.12/a
B.3/a
C.6/a
D.9/a
Answer: B.3/a
Explanation: 1/a + 1/a + 1/a
=3/a
Answer B
Question: List I: { y, 2, 4, 7, 10, 11}
List II: {3, 3, 4, 6, 7, 10}
If the median W of List I is equal to the sum of the median of list II and the mode of list II, then y equals
A.5
B.7
C.8
D.W=9
Answer: D.W=9
Explanation: mode of list ii =3
median W of list ii =4+6/2 =5
sum of mode + mean = 3+ 5=8
now to make 8 as the median we need to find a value of y such that if the no. of terms in list 1 are odd then y=8 else if even then 7+y /2=8
here its even so
7+y/2=8 from this y= 9 (D)
Question: If y exceeds x by 26%, then x is less than y by?
A.16 2/8%
B.20 8/3%
C.20 40/63%
D.76 2/3%
Answer: C.20 40/63%
Explanation: X=100	y=126
126------26
100-------? => 20 40/63%
Answer:C
Question: The average of 11 numbers is 10.9. If the average of first six is 10.5 and that of the last six is 11.5 the sixth number is?
A.11.4
B.11.3
C.11.8
D.12.1
Answer: D.12.1
Explanation: 1 to 11 = 11 * 10.9 = 119.9
1 to 6 = 6 * 10.5 = 63
6 to 11 = 6 * 11.5 = 69
63 + 69 = 132 – 119.9 = 12.1
6th number = 12.1
Answer: D
Question: A 70 cm long wire is to be cut into two pieces so that one piece will be 2/3th of the other, how many centimeters will the shorter piece be?
A.35
B.20
C.28
D.36
Answer: C.28
Explanation: 1: 2/3 = 3: 2
2/5 * 70 =28
Answer:C
Question: If the area of a circle decreases by 30%, then the radius of a circle decreases by
A.20%
B.16%
C.36%
D.64%
Answer: B.16%
Explanation: If area of a circle decreased by x % then the radius of a circle decreases by
(100−10√100−x)%=(100−10√100−30)%
= (100−10√70)%
= 100 - 84 = 16%
Answer B
Question: The ratio of two numbers is 2 : 5 and their H.C.F. is 5. Their L.C.M. is
A.50
B.22
C.56
D.27
Answer: A.50
Explanation: Explanation:
Let the numbers be 2x and 5x. Then, their H.C.F. = x. So, x = 5.
So, the numbers 10 and 25.
L.C.M. of 10 and 25 = 50.
Option A
Question: 60 is subtracted from 50% of a number, the result is 10. Find the number?
A.150
B.120
C.266
D.288
Answer: B.120
Explanation: (50/100) * X – 50 = 10
5X = 600
X = 120
Answer:B
Question: Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.130. How much was lent at 5%?
A.2000
B.2777
C.2688
D.1000
Answer: A.2000
Explanation: (x*5*1)/100 + [(2500 - x)*6*1]/100 = 130
X = 2000
Answer: A
Question: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?
A.2 : 3 : 4
B.6 : 7 : 8
C.6 : 8 : 9
D.6 : 8 : 7
Answer: A.2 : 3 : 4
Explanation: let 100% seats are there in all then mathematics increased by 40% then
5*140/100=7
physics is increased by 50% then
7*150/100=21/2
biology increased by 75% then
8*175/100=14
then ratios of increasing seats are 7:21/2:14
14:21:28
2:3:4
ANSWER:A
Question: 7M-20=2M,THEN M+7 IS EQUAL TO?
A.9
B.10
C.11
D.12
Answer: C.11
Explanation: 7m-20=2m
so, 5m=20
so, m+7=11
ANSWER:C
Question: Let A = {a, b, c, d, e, f} and B = {b, d, f, g}.Find B-A
A.{A}
B.{G}
C.{L}
D.{B}
Answer: B.{G}
Explanation: A = {a, b, c, d, e, f}
B = {b, d, f, g}
correct answer :B - A = {g)
B
Question: Deepak deposited $9,000 to open a new savings account that earned 12 percent annual interest, compounded semi-annually. If there were no other transactions in the account, what the amount of money in Deepak account one year after the account was opened?
A. $10,200
B. $10,092
C. $10,105
D. $9,405
Answer: B. $10,092
Explanation: Approach #1:
12 percent annual interest compounded semi-annually --> 6% in 6 moths.
For the first 6 moths interest was 6% of $9,000, so $540;
For the next 6 moths interest was 6% of $9,000,plus6% earned on previous interest of $540, so $540+$12=$552;
Total interest for one year was $540+$552=$1092, hence balance after one year was $9,000+ $1,092=$10,092.
Answer: B.
Question: A certain bag contains 100 balls â€” 50 white, 20 green, 10 yellow, 17 red, and 3 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?
A.0.9
B.0.75
C.0.6
D.0.8
Answer: D.0.8
Explanation: According to the stem the ball can be white, green or yellow, so the probability is (white + green + yellow)/(total) = (50 + 20 + 10)/100 = 80/100 = 0.8.
Answer is D
Question: A shopkeeper sold an article offering a discount of 5% and earned a profit of 38.7%. What would have been the percentage of profit earned if no discount had been offered?
A.28.5
B.46
C.30
D.Data inadequate
Answer: B.46
Explanation: Giving no discount to customer implies selling the product on printed price. Suppose the cost price of the article is 100.
Then printed price = 100Ã—(100+38.7)/(100âˆ’5) =146
Hence, required % Profit = 146 â€“ 100 = 46%
Answer B
Question: P alone can complete a piece of work in 12 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?
A.6 (1/4) days
B.9 days
C.7 (3/4) days
D.8 days
Answer: B.9 days
Explanation: Work done by P alone in one day = 1/12th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/12 of the total) = 1/36 of the total.
Work done by P and Q, working together in one day = 1/12 + 1/36 = 4/36=1/9 of the total
They would take 9 days to complete the work working together.
ANSWER:B
Question: A restaurant meal cost $18.5 and there was no tax. If the tip was more than 30 percent but less than 10 percent of the cost of the meal, then the total amount paid must have been between
A.$24 and $20
B.$25 and $23
C.$38 and $40
D.$37 and $39
Answer: A.$24 and $20
Explanation: The total amount for the meal was between 18.5*1.3=24.05 and 18.5*1.1=~20.35. Only option which covers all possible values of the meal is A.
Answer: A.
Question: A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
A.Rs.1000
B.Rs.1140
C.Rs.860
D.Rs.760
Answer: A.Rs.1000
Explanation: Explanation:
90%
104%
--------
14% ---- 140
100% ---- ? => Rs.1000
ANSWER IS A
Question: A man travels 250km by train at 50km/hr, 200km by ship at 20km/hr, 300km by aeroplane at 100km/hr and 100km by car at 50km/hr. What is the average speed for the entire distance?
A.35.3km/hr
B.42.5km/hr
C.48.9km/hr
D.52.6km/hr
Answer: B.42.5km/hr
Explanation: Total distance traveled = 250+200+300+100 = 850km
Total time taken = 250/50 + 200/20 + 300/100 + 100/50 = 20 hrs
Average speed =850/20 = 42.5km/hr approximately ;
Answer is B
Question: Rounded to three decimal places, 1.001^4 =
A.1.004
B.1.006
C.1.008
D.1.012
Answer: A.1.004
Explanation: As compared to 1, 0.001 is a very small quantity. Thus, we can write (1+0.001)^4 is nearly equal to (1+4*0.001) = 1.004.As the question asks for approximation to three decimal places, the further terms will anyways not come into picture.
A
Question: If 40% of a certain number is 160, then what is 90% of that number?
A.270
B.380
C.260
D.360
Answer: D.360
Explanation: Explanation:
40% = 40*4 = 160
90% = 90*4 = 360
Answer: Option D
Question: An electric pump can fill a tank in 3 hours. Because of a leak in the tank, it took 12 hours to fill the tank. If the tank is full, how much time will the leak take to empty it?
A.4 hours
B.12hours
C.8hours
D.5hours
Answer: A.4 hours
Explanation: Work done by the leak in 1 hour = 1/3 - 1/12 = 1/4
The leak will empty the tank in 4hours
Answer is A
Question: How many seconds does Sandy take to cover a distance of 600 meters, if Sandy runs at a speed of 18 km/hr?
A.100
B.120
C.140
D.160
Answer: B.120
Explanation: 18 km/hr = 18000 m / 3600 s = 5 m/s
time = 600 / 5 = 120 seconds
The answer is B.
Question: Four cups of milk are to be poured into a 3-cup bottle and a 6-cup bottle. If each bottle is to be filled to the same fraction of its capacity, how many cups of milk should be poured into the 6-cup bottle?
A. 2/3
B. 7/9
C. 24/9
D. 8/3
Answer: C. 24/9
Explanation: Let x be the # of cups going into the 6 cup bottle.
so.... x/6 = ((4-x)/3)
24 - 6x = 3x
24 = 9x
x = 24/9.
Answer : C
Question: A single discount equivalent to the discount series of 20%, 10% and 5% is?
A.31.7
B.31.1
C.31.6
D.31.4
Answer: C.31.6
Explanation: 100*(80/100)*(90/100)*(95/100)
= 68.4
100 - 68.4
= 31.6
Answer: C
Question: Let y = 2m + x^2 and m = 5x + 4. If m^2 =81, then which of the following can be a value of 2y + 3m?
A.65
B.130
C.141
D.142
Answer: A.65
Explanation: m^2 = 81 => m=9
9= 5x+4 => x=1
y= 2*9+1^2 = 19
2y+3m = 2*19+3*9 = 65
Answer : A
Question: The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 146, what is the difference between the ages of Patrick and Monica?
A.27
B.48
C.45
D.72
Answer: B.48
Explanation: Ages of P and Mi=3x+5x
Ages of Mi and Mo=3x:5x
Rationalizing their ages. ratio of their ages will be 9x:15x:25x
Sum=47x=146
x=3
Difference if ages of Pa and Mo=25x-9x=16x=16*3=48
Answer B
Question: At a certain conference, 150 students spoke one or more of the following languages: Spanish, English, and French. If 51 students spoke Spanish, 90 spoke English, 65 spoke French, and 32 spoke only 2 languages, how many students spoke three different languages?
A.7
B.9
C.12
D.15
Answer: C.12
Explanation: 150=51+90+65-32-2x
x=12
C. 12
Question: From the digits 2, 3, 4, 5, 6 and 7, how many 5-digit numbers can be formed that have distinct digits and are multiples of 12?
A.36
B.60
C.84
D.72
Answer: B.60
Explanation: DETAILED SOLUTION
Any multiple of 12 should be a multiple of 4 and 3. First, let us look at the constraint for a number being a multiple of 3. Sum of the digits should be a multiple of 3. Sum of all numbers from 2 to 7 is 27. So, if we have to drop a digit and still retain a multiple of 3, we should drop either 3 or 6.
So, the possible 5 digits are 2, 4, 5, 6, 7 or 2, 3, 4, 5, 7.
When the digits are 2, 4, 5, 6, 7. the last two digits possible for the number to be a multiple of 4 are 24, 64, 52, 72, 56, 76. For each of these combinations, there are 6 different numbers possible. So, with this set of 5 digits we can have 36 different numbers.
When the digits are 2, 3, 4, 5, 7. The last two digits possible for the number to be a multiple of 4 are 32, 52, 72, 24. For each of these combinations, there are 6 different numbers possible. So, with this set of 5 digits we can have 24 different numbers.
Overall, there are 60 different 5-digit numbers possible.
Correct Answer: B
Question: David invested certain amount in three different schemes. A, B and C with the rate of interest 10% p.a., 12% p.a. and 15% p.a. respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in scheme C was 150% of the amount invested in scheme A and 240% of the amount invested in scheme B, what was the amount invested in scheme B?
A.5000
B.5007
C.5006
D.5003
Answer: A.5000
Explanation: Let x, y and z be the amount invested in schemes A, B and C respectively. Then,
(x * 10 * 1)/100 + (y * 12 * 1)/100 + (z * 15 * 1)/100 = 3200
10x + 12y + 15z = 320000
Now, z = 240% of y = 12/5 y
And, z = 150% of x = 3/2 x
x = 2/3 z = ( 2/3 * 12/5) y = 8/5 y
16y + 12y + 36y = 320000
y = 5000
Sum invested in scheme B = Rs. 5000.
Answer:A
Question: A rope of which a calf is tied is increased from 12 m to 23 m, how much additional grassy ground shall it graze?
A.1218
B.1212
C.1210
D.277
Answer: C.1210
Explanation: π (232 – 122) = 1210
Answer: C
Question: In ΔPQS above, if PQ =5 and PS = 6, then
A. 9/4
B. 12/5
C. 16/5
D. 30/7
Answer: D. 30/7
Explanation: there are two ways to calculate area of PQS. area remains same, so both are equal.
5*6/2 = PR*7/2
PR = 30/7
D
Question: P and Q can do a work in 30 days. Q and R can do the same work in 24 days and R and P in 20 days. They started the work together, but Q and R left after 12 days. How many days more will P take to finish the work?
A.12
B.15
C.18
D.20
Answer: A.12
Explanation: Let work done by P in 1 day = p,
Work done by Q in 1 day = q,
Work done by R in 1 day = r
p + q = 1/30
q + r = 1/24
r + p = 1/20
Adding all the above, 2p + 2q + 2r = 1/30 + 1/24+ 1/20 = 15/120 = 1/8
=> p + q + r = 1/16
=> Work done by P,Q and R in 1 day = 1/16
Work done by P, Q and R in 12 days = 12 × (1/16) = 12/16 = 3/4
Remaining work = 1 = 3/4 = 1/4
Work done by P in 1 day = Work done by P,Q and R in 1 day - Work done by Q and R in 1 day
= 1/16 – 1/24 = 1/48
Number of days P needs to work to complete the remaining work = (1/4) / (1/48) = 12
Option A
Question: Some of the 50% solution of acid was removed and this was replaced with an equal amount of 10% solution of acid. As a result, a 20% solution of acid was obtained. What fraction of the original solution was replaced?
A.1/2
B.2/3
C.3/4
D.3/5
Answer: C.3/4
Explanation: Let x be the fraction of the original solution that was replaced.
0.5*(1-x)+0.1(x)=0.2
0.4x=0.3
x=3/4
The answer is C.
Question: Set C consists of the following unique integers: -2, 17, 3, n, 2, 15, -3, and -27; which of the following could be the median of set C?
A.5
B.6
C.7
D.1
Answer: D.1
Explanation: Whenever a question asks you to deal with the MEDIAN of a group of numbers, you MUST put the numbers in order from least to greatest (or at the very least,group offthe numbers so that you can restrict the potential value of the median).
Here, we have 8 values (one of the values is the variable N). We're told that the values are UNIQUE, so N CANNOT be any of the other 7 values listed. We're asked which of the following answers COULD be the median, so if we determine that one of the answer choices is a POSSIBLE median, then we can stop working....
Since the group includes 8 values, the median will be the AVERAGE of the 4th and 5th values...
Putting the 7 numbers in order, we have:
-27, -3, -2, 2, 3, 15, 17
This means that the2will either be the 4th term or the 5th term (depending on the value of N).
IF....
N is REALLY BIG, then the 4th and 5th terms will be 2 and 3, so the median will = 2.5
N is REALLY SMALL, then the 4th and 5th terms will be -2 and 2, so the median will = 0
Neither of those answers is among the choices though, so N must be something relativelycloseto 2.....
IF....
N = 0, then the 4th and 5th terms will be 0 and 2, so the median will = 1. That answer IS among the choices, so we're done.
D
Question: Printer P can print one lakh books in 8 hours. Printer Q can print the same number of books in 10 hours while Printer R can print the same in 12 hours. All the Printers started printing at 9 A.M. Printer P is stopped at 11 A.M. and the remaining 2printers complete work. Approximately at what time will the printing of 1 lac books be completed?
A.10 pm
B.1 pm
C.12 pm
D.2 pm
Answer: B.1 pm
Explanation: Work done by P in 1 hour = 1/8
Work done by Q in 1 hour = 1/10
Work done by R in 1 hour = 1/12
Work done by P,Q and R in 1 hour = 1/8 + 1/10 + 1/12 = 37/120
Work done by Q and R in 1 hour = 1/10 + 1/12 = 22/120 = 11/60
From 9 am to 11 am, all the Printer were operating.
Ie, they all operated for 2 hours and work completed = 2 × (37/120) = 37/60
Pending work = 1- 37/60 = 23/60
Hours taken by Q an R to complete the pending work = (23/60) / (11/60) = 23/11
which is approximately equal to 2
Hence the work will be completed approximately 2 hours after 11 am ; ie around 1 pm
B
Question: How many times the keys of a writter have to be pressed in order to write first 400 counting no.'s?
A.998
B.1000
C.1092 times
D.1100
Answer: C.1092 times
Explanation: 1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 400 = 301 * 3 = 903
-----------
1092
C
Question: Three types of tea the a,b,c costs Rs. 95/kg,100/kg and70/kg respectively.How many kgs of each should be blended to produce 100 kg of mixture worth Rs.90/kg, given that the quantities of band c are equal
A.70,15,15
B.50,25,25
C.60,20,20
D.40,30,30
Answer: B.50,25,25
Explanation: given quantities of b and c are equal .
therefore instead of considering them as a different quantities take average of both and consider it as a single entity .
so the cost of the mixture "D" (equal quantities of "B" and "C") is 170/2=85rs/kg
now the tea contains only "A" of 95 rs/per and "D" of 85 rs/kg.
it is clearly seen that "A" is 5 more and "D" is 5 less than the required cost per kg .
therefore 50/50 will go well .
A=50kg and D=50kg. (D= B&C in equal ratio). therefore B&C=25kg each .
(A:B:C)=(50,25,25)
ANSWER:B
Question: There are four members in a family. Their average income is Rs.10000 per month. Three members get Rs.8000, Rs.15000, Rs.6000 respectively. Therefore what is the income of the fourth member of the family?
A.Rs. 10000
B.Rs. 11000
C.Rs. 12000
D.Rs. 9000
Answer: B.Rs. 11000
Explanation: EXPLANATION
Total income of 3 members = Rs. (8000 + 15000 + 6000) = Rs. 29000.
Required income = Rs. [ (10000 x 4) – 29000 ]
= Rs. (40000 – 29000)
= Rs. 11000.
Answer B
Question: The cost price of 15 articles is equal to the selling price of 11 articles. Find the profit percent?
A.18 2/91%
B.36 4/11%
C.18 9/11%
D.18 2/91%
Answer: B.36 4/11%
Explanation: 15 CP = 11 SP
11 --- 2 CP
100 --- ? =>36 4/11%
Answer:B
Question: How many different number-plates for cars can be made if each number-plate contains four of the digits 0 to 9 followed by a letter A to Z, assuming that
(a) no repetition of digits is allowed?
A.131040
B.116700
C.142369
D.147225
Answer: A.131040
Explanation: we want 4 digit of cars and repetition is not allowed
1st digit can be fill with 0 to 9 i.e = 10
2nd digit can be fill with 0 to 9 except earlier selected i.e = 9
3rd digit can be fill with 0 to 9 except earlier selected i.e = 8
4th digit can be fill with 0 to 9 except earlier selected i.e = 7
No of ways = 10 * 9 * 8 * 7 * (total aplphabets)
= 5040 * 26
= 1,31,040
Ans - A
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 9 minutes. The waste pipe can empty the full cistern in?
A.18
B.17
C.16
D.19
Answer: A.18
Explanation: 1/10 + 1/15 - 1/x = 1/9
x = 18
Answer:A
Question: If john makes a contribution to a charity fund at school, the average contribution size will increase by 50% reaching $75 per person. If there were 3 other contributions made before john's, what is the size of his donation?
A.$100
B.$150
C.$200
D.$250
Answer: B.$150
Explanation: Cavg = average contribution before John
Cavg*1.5 = 75, therefore the average cont is $50 before John.
If he needs to increase the average contribution by $25, he must put in $25 for each of the 3 people.
so $75.
But, he also has to put in the average for himself (the fourth person), so add $75.
So $150 is your answer.
Answer B