RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: When a student weighing 45 kgs left a class, the average weight of the remaining 59 students increased by 200g. What is the average weight of the remaining 59 students
A.55
B.56
C.57
D.58
Answer: C.57
Explanation: Explanation:
Let the average weight of the 59 students be A.
So the total weight of the 59 of them will be 59*A.
The questions states that when the weight of this student who left is added, the total weight of the class = 59A + 45
When this student is also included, the average weight decreases by 0.2 kgs
59A+45/60=A−0.2
=> 59A + 45 = 60A - 12
=> 45 + 12 = 60A - 59A
=> A = 57
Answer: Option C
Question: If a is a positive integer, and if the units digit of a^2 is 9 and the units digit of (a+1)^2 is 4, what is the units Z digit of (a+2)^2?
A.1
B.3
C.5
D.6
Answer: A.1
Explanation: I also got A. By punching in numers:
Z...7^2=...9
...8^2=...4
...9^2=...1.A
Question: Find the simple interest on Rs. 78000 at 15(2/5) % per annum for 9 months.
A.Rs. 7804
B.Rs. 8979
C.Rs. 8046
D.Rs. 9009
Answer: D.Rs. 9009
Explanation: Explanation:
P = Rs. 78000, R = 77/5 % p.a and T = 9/12 years = ¾ years
Therefore,
S.I = (P*R*T)/100
= (78000* 77/5 * ¾ * 1/100)
= Rs. 9009
ANSWER D
Question: A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?
A.32:46
B.32:42
C.32:45
D.32:40
Answer: C.32:45
Explanation: A : B
(8000*4)+(4000*8) : (9000*6)+(6000*6)
64000 : 90000
32 : 45
Answer: C
Question: A shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net profit or loss that he makes?
A.neither profit nor loss
B.3%
C.5%
D.4%
Answer: D.4%
Explanation: SP of first article = 1000
Profit = 20%
CP = (SP)*[100/(100+P)] = 5000/6 = 2500/3
SP of second article = 1000
Loss = 20%
CP = (SP)*[100/(100-L)] = 5000/4 = 1250
Total SP = 2000
Total CP = 2500/3 + 1250 = 6250/3
CP is more than SP, he makes a loss.
Loss = CP-SP = (6250/3)- 2000 = 250/3
Loss Percent = [(250/3)/(6250/3)]*100 =
0.04 * 100 = 4%
ANSWER:D
Question: In an election contested by two parties, Party ADMK secured 24% of the total votes more than Party DMK. If party DMK got 266,000 votes, by how many votes did it lose the election?
A.34,000
B.56,000
C.164,000
D.168,000
Answer: D.168,000
Explanation: ADMK + DMK = 100 ---- (1)
ADMK - DMK = 24 ---- (2)
Solving (1) and (2) ADMK = 62% and DMK = 38%
38% of Total = 266000
Total = 700000
ADMK = 434000
Difference = 434000 - 266000 = 168000
Answer: D
Question: A box contains 100 balls, numbered from 1 to 100. If three balls are selected at random and with replacement from the box, what is the probability J that the sum of the three numbers on the balls selected from the box will be odd?
A.1/4
B.3/8
C.1/2
D.5/8
Answer: C.1/2
Explanation: The sum of the three numbers on the balls selected from the box to be odd one should select either three odd numbered balls (Odd+Odd+Odd=Odd) or two even numbered balls and one odd numbered ball (Even+Even+Odd=Odd);
P(OOO)=(1/2)^3;
P(EEO)=3*(1/2)^2*1/2=3/8 (you should multiply by 3 as the scenario of two even numbered balls and one odd numbered ball can occur in 3 different ways: EEO, EOE, or OEE);
So finally J=1/8+3/8=1/2.
Answer: C.
Question: The average of seven numbers is 18. The average of first three numbers is 14 and the average of last three numbers is 19. What is the middle number?
A.25
B.27
C.29
D.32
Answer: B.27
Explanation: The total of seven numbers = 7X18 = 126
The total of first 3 and last 3 numbers is = 3 X 14+3 X 19 = 99
So, the middle number is (126 - 99 ) = 27
B
Question: find value for x from given equation? x + 1 = -3
A.1
B.x=-4
C.-3
D.-5
Answer: B.x=-4
Explanation: 1 . Subtract 1 from both sides:
x + 1 - 1 = -3 - 1
2. Simplify both sides:
x = -4
B
Question: If 25 typists can type 60 letters in 20 minutes, then how many letters will 75 typists working at the same rate complete in 1 hour?
A.270
B.540
C.610
D.510
Answer: B.540
Explanation: No. of letters typing by 25 typists in 20 minutes = 60
No. of letters typing by 25 typists in 60 minutes = 60*3 = 180
No. of letters typing by 75 typists in 60 minutes = 180/25*75 = 540
Answer : B
Question: If (2/5)^n=(5/2)^2, what is the value of n?
A.-2
B.-1
C.0
D.1
Answer: A.-2
Explanation: (2/5)^n = (5/2)^2
= (2/5)^-2
n = -2 (Answer = A)
Question: In one day, Juan sends Keith two times as many messages as he sends Laurence, and Laurence sends Missy 8 times as many messages as he receives from Juan. If Missy received 40 messages from Laurence, how many messages does Keith receive from Juan?
A.10
B.12
C.16
D.18
Answer: A.10
Explanation: Juan --> Laurence = x messages;
Juan --> Keith = 2x messages (Juan sends Keith two times as many messages as he sends Laurence);
Laurence --> Missy = 8x =40 (Laurence sends Missy 8 times as many messages as he receives from Juan).
8x =40 --> x = 5 --> 2x = 10.
Answer: A.
Question: Last year the range of the annual yield on equal amount of investments in 100 mutual funds was $10,000. If the annual yield this year for each of the 100 mutual funds has improved by 15 percent this year than it was last year, what is the range of the annual yield on mutual funds this year?
A. $12700
B. $13000
C. $23000
D. $11500
Answer: D. $11500
Explanation: let the lowest yield be x.
Therefore, highest yield is x +10000.
Now yield of each mutual fund investment is improved by 10%.
Therefore the yields will remain arranged in the same order as before.
or Lowest yield = 1.15x and Highest = 1.15 * (x+10000)
or Range = highest - lowest = 1.15* (x+10000) - 1.15x
= 11500, Hence, D
Question: How many diagonals does a 63-sided convex polygon have?
A.3780
B.1890
C.3843
D.3906
Answer: B.1890
Explanation: Explanatory Answer
The number of diagonals of an n-sided convex polygon = n(n−3)/2
This polygon has 63 sides. Hence, n = 63.
Therefore, number of diagonals = 63∗60 /2 = 1890.
Choice B
Question: Country X taxes each of its citizens an amount equal to 13 percent of the first $40,000 of income, plus 20 percent of all income in excess of $40,000. If a citizen of Country X is taxed a total of $8,000, what is her income?
A.$54,000
B.$56,000
C.$64,000
D.$66,667
Answer: A.$54,000
Explanation: Equation is correct, so math must be a problem.
0.13*40,000+0.2*(x-40,000)=8,000 --> 5,200+0.2x-8,000=8,000 --> 0.2x=10,800 --> x=54,000.
Answer: A.
Question: A student worked for 20 days. For each of the amounts shown in the first row of the table, the second row gives the number of days that the student earned that amount. What is the amount of money that the student earned per day for the 5th day?
Amounts earned per day : $96 $84 $80 $70 $48
Number of days : 4 7 4 3 2
A.(1) $96
B.(2) $84
C.(3) $80
D.(4) $70
Answer: D.(4) $70
Explanation: 4+7+4+3+2 = 20
The series is as follows. Arrange the terms in increasing order of amounts earned and cumulatively add up the number of days of each amount.
1st to 2nd term = 48 (2 days)
3rd to 5th term = 70 (3 days)
Pick D
Question: A sum of money is put out at compound interest for 2 years at 20%. It would earn Rs.482 more if the interest were paid half-yearly. Calculate the sum.
A.2878
B.279
C.279
D.482
Answer: D.482
Explanation: P(11/10)4 - P(6/5)2 = 482
P = 2000
Answer: D
Question: A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^11, respectively, what is the value of A?
A.-24(5^12)
B.-23(5^12)
C.-24(5^6)
D.23(5^12)
Answer: D.23(5^12)
Explanation: Ans : D
Assume that the numbers appear as shown below on the number line
A-----B-----C-----D-----E-----F-----G-----H
(5^12) (5^13)
As the values for G and H are given , we can calculate the difference between any two terms of the series .
Common Difference ,d = (5^13) - (5^12)
= (5^12) *[ 5-1 ]
= (5^12)*(4)
Also F + d = G as the terms are in equidistant and in increasing order.
So F + (5^12)*(4) = (5^12).
That is , F = (5^12) - (5^12)*(4)
= (5^12)[ 1-4]
= (5^12) (-3)
Similarly , E = F - d
= (5^12)[-3-4]
= (5^12)*(-7)
You can see a -4 getting added to the non-exponent part of the values . That is , according to the pattern , D SHOULD BE (5^12)*(-7-4)= (5^12)*(-11)
Following this pattern , A = (5^12)*(23)
D
Question: To be considered grade AB, an egg must weigh between 75 and 90 grams, including the shell. Shells of grade AB eggs weigh between 3 and 5 grams. What is the smallest possible mass, in grams, of a 12-egg omelet, assuming that only grade AB eggs are used, the shells are all discarded, and no mass is lost in the cooking process?
A.800
B.840
C.864
D.900
Answer: B.840
Explanation: We're asked for the smallest possible mass, so what could the lowest mass be per egg AB? A 75 gram egg, with a 5 gram shell, or 70 grams ofcookingmass. 12 x 70 = 840, so the answer is B.
Question: In how many different ways can 3 identical green shirts and 3 identical red shirts be distributed among 6 children such that each child receives a shirt?
A.20
B.40
C.216
D.720
Answer: A.20
Explanation: GGG RRR
Therefore total number of ways is
6! but there are two groups of 3 identical things.
Therefore total number of "different" ways is
6!/ (3!) (3!) = 20 ANS:A
Question: Find the unit's digit in 264 ^102+264^103
A.zero 0
B.1
C.2
D.4
Answer: A.zero 0
Explanation: Required unit's digit = unit's digit in 4102+4103.4102+4103.
Now, 4242 gives unit digit 6.
⇒ 41024102 gives unit digit 6.
⇒ 41034103 gives unit digit of the product 6×46×4 i.e., 4.
Hence, unit's digit in 264102+264103264102+264103
= unit's digit in (6+4)=0
A
Question: A boat can move upstream at 15 kmph and downstream at 35 kmph, then the speed of the current is?
A.5
B.6
C.7
D.10
Answer: D.10
Explanation: US = 15
DS = 35
M = (35 - 15)/2 = 10
Answer: D
Question: There are 12 magazines lying on a table; 6 are fashion magazines and the other 6 are sports magzines. If 5 magazines are to be selected at random from the 8 magazines, what is the probability that at least one of the fashion magazine will be selected?
A.521/525
B.522/525
C.520/525
D.519/525
Answer: A.521/525
Explanation: 1- 6c5/10c5 =1-4/525=521/525
Answer : A
Question: If {g} denote the remainder when 3g is divided by 2 then which of the following is equal to 1 for all positive integers g?
I. {2g+1}
II. {2g}+1
III. 2{g+1}
A.I only
B.II only
C.I and II
D.III only
Answer: C.I and II
Explanation: C - I and II
3g/2 = 0 or 1
I just substituted 1 in the equations and solved.
Question: If the price of an article went up by 25%, then by what percent should it be brought down to bring it back to its original price?
A.20%
B.2/8%
C.2/1%
D.1/3%
Answer: A.20%
Explanation: Let the price of the article be Rs. 100.
25% of 100 = 25.
New price = 100 + 25 = Rs. 125
Required percentage = (125 - 100)/125 * 100
= 25/125 * 100= 20%.
Answer:A
Question: A factory has 500 workers, 16 percent of whom are women. If 50 additional workers are to be hired and all of the present workers remain, how many of the additional workers must be women in order to raise the percent of women employees to 20 percent?
A. 3
B. 10
C. 25
D. 30
Answer: D. 30
Explanation: Currently the factory has 0.16*500=80 women.
After 50 additional workers are hired, there will be total of 550 workers and we need 0.2*550=110 of them to be women, so we need 110-80=30 more women.
Answer: D.
Question: The parameter of a square is double the perimeter of a rectangle. The area of the rectangle is 100 sq cm. Find the area of the square?
A.482
B.Cannot be determined
C.260
D.120
Answer: B.Cannot be determined
Explanation: Let the side of the square be a cm. Let the length and the breadth of the rectangle be l cm and b cm respectively.
4a = 2(l + b)
2a = l + b
l . b = 480
We cannot find ( l + b) only with the help of l . b. Therefore a cannot be found .
Area of the square cannot be found.
Answer: B
Question: A meeting has to be conducted with 5 managers. Find the number of ways in which the managers may be selected from among 8 managers, if there are 2 managers who refuse to attend the meeting together.
A.36
B.40
C.45
D.51
Answer: A.36
Explanation: The total number of ways to choose 5 managers is 8C5 = 56
We need to subtract the number of groups which include the two managers, which is 6C3 = 20.
56 - 20 = 36
The answer is A.
Question: A man buys 52 pens at marked price of 46 pens from a whole seller. If he sells these pens giving a discount of 1% , what is the profit percent?
A.7.6 %
B.7.7 %
C.11.32 %
D.11.91 %
Answer: D.11.91 %
Explanation: Explanation:
Let Marked price be Re. 1 each
C.P. of 52 pens = Rs. 46
S.P. of 52 pens = 99% of Rs. 52 = Rs. 51.48
Profit % = (Profit /C.P.) x 100
Profit% = (5.48/46) x 100 = 11.91 %
ANSWER: D
Question: The total cost of 100 paper plates and 200 paper cups is $7.50 At the same rates what is the total cost of 20 of the plates and 40 of the cups?
A.$.90
B.$1.00
C.$1.20
D.$1.50
Answer: D.$1.50
Explanation: U dont need to go through all this
What u have with u is
100 P + 200 C = $7.50
Just divide the equation by 5 and you will get what u are looking for
20P + 40 C = $1.50
Therefore OA is D
Question: Felix earned 60% more per month than Oscar. If Felix’s salary is decreased 10% and Oscar’s salary is increased by 10%, then Felix would be earning what percent more than Oscar?
A.20%
B.9.09%
C.34%
D.30.90%
Answer: D.30.90%
Explanation: This Q is all about taking the correct BASE for taking %s..
the very first step requires taking some numbers for each..
ONE should be 100...
it is easy to take 40 and 100 here..
but the BASE is 100 here, so the salary can be 100 and 160..
100 increases 10% =110..
160 decreases 10%=144..
so the increase is 34..
again the BASE is 110, so answer 34/110 * 100= 30.90% D
without calculations,
answer cannot be equal to or greater than 34, as 34 is on 110..
so D is the only one left
Question: 2 pipes can separately fill a tank in 20hrs and 30hrs respectively. Both the pipes are opened tofill the tank, a leak develops in the tank through which one-third of water supplied by both the pipes goes out. What is the total time taken to fill the tank?
A.12 hrs
B.14 hrs
C.16 hrs
D.18 hrs
Answer: C.16 hrs
Explanation: 1/20 + 1/30 = 1/12
1 + 1/3 = 4/3
1 --- 12
4/3 --- ?
4/3 * 12 = 16 hrs
C
Question: Find the 25% of Rs. 600.
A.s. 150
B.s. 70
C.s. 100
D.s. 80
Answer: A.s. 150
Explanation: Explanation :
25% of 600
=> 25/100 *600 = Rs. 150
Answer : A
Question: Ramu & Sangeetha went for biological analysis to an island which is 34km from their place. They traveled in a boat which went at a speed of 2m/s. when they are in half a distance in the boat Sangeetha noted there are 7 leg & 8 leg octopuses under the water. Ramu counted the total number of legs of octopuses and got 54. Sangeetha instantly said I know how many 7 legged octopuses are there under the water. They both reached the island after 20 min they left. How many seven legged octopuses does Sangeetha calculate?
A.2
B.5
C.6
D.7
Answer: A.2
Explanation: multiples of 7(legs) multiples of 8(legs)
7 8
14 16
21 24
28 32
Here only 14 legs(multiple of 7)+32 legs(multiple of 8)=54 legs
So the question is to find the number of 7 legged Octopus.
Then 14/7=2.
ANSWER:A
Question: Find the simple interest on Rs. 3000 at 6 1/4% per year for the period from 4th Feb., 2005 to 18th April, 2005.
A.36.5
B.33.5
C.35.5
D.37.5
Answer: D.37.5
Explanation: Time = (24+31+18)days = 73 days = 73/365 years = 1/5 years.
P = Rs.3000 and R = 6 ¼ %p.a = 25/4%p.a
Therefore, Simple Interest. = Rs.(3,000*(25/4)*(1/5)*(1/100))= Rs.37.50.
Answer is D.
Question: A company organized a recruiting process for 3 vacant positions of assistant manager for its product launches. The company's efforts yielded 9 eligible candidates. How many sets of 3 candidates can the company choose to fill the 3 assistant manager positions?
A. 84
B. 94
C. 545
D. 315
Answer: A. 84
Explanation: 9*8*7/3*2*1 = 84
A
Question: r, b, and c are positive integers. If r, b, and c are assembled into the six-digit number rbcrbc, which one of the following must be a factor of rbcrbc?
A. 16
B. 13
C. 5
D. 3
Answer: B. 13
Explanation: Plug in some values and check -
rbcrbc = 123123
Not divisible by 16 and 5
let rbcrbc = 125125
Not divisible by 3
Only option (B) and (E) is left in both the cases...
Check once more to marke (B) as correct answer
let rbcrbc = 135135
Again divisible by 13
So, mark answer as (B) 13
Question: What are the maximum value and minimum values of f(x) = |2sin(2x - pi/3) - 5| + 3
A.max 8-min 2
B.max 9-min 1
C.max 10-min 6
D.max 11-min 5
Answer: C.max 10-min 6
Explanation: -1 <= sin(2x - pi/3) <= 1 : range of a sine function
-2 <= 2sin(2x - pi/3) <= 2 : multiply all terms of the double inequality by 2
-2 - 5 <= 2sin(2x - pi/3) - 5 <= 2 - 5 : add -5 to all terms of the inequality.
-7 <= 2sin(2x - pi/3) - 5 <= -3
3 <= |2sin(2x - pi/3) - 5| <= 7 : change the above using absolute value.
3 + 3 <= |2sin(2x - pi/3) - 5| + 3 <= 7 + 3 : add 3 to all terms of the double inequality.
The maximum value of f(x) is equal to 10 and the minimum value of f(x) is equal to 6.
correct answer C
Question: The interest on Rs. 750 for 2 years is the same as the true discount on Rs. 960 due 2 years hence. If the rate of interest is the same in both cases, it is:
A.18%
B.14%
C.94%
D.11%
Answer: B.14%
Explanation: S.I. on Rs. 750 = T.D. on Rs. 960.
This means P.W. of Rs. 960 due 2 years hence is Rs. 750.
T.D. = Rs. (960 - 750) = Rs. 210.
Thus, S.I. on R.s 750 for 2 years is Rs. 210.
Rate = 100 x 210	%	= 14%
750 x 2
Answer: B
Question: A man purchased a grinder for Rs. 320 and sold it at a profit of 10%. The selling price is:
A.Rs. 736
B.Rs. 352
C.Rs. 684
D.None of these
Answer: B.Rs. 352
Explanation: s.p.=110/100 × 320 = 352
Answer: B
Question: A hare and a jackal are running a race. Three leaps of the hare are equal to four leaps of the jackal. For every three leaps of the hare, the jackal takes five leaps. Find the ratio of the speed of the hare to the speed of the jackal.
A.6:7
B.4:5
C.5:8
D.25:64
Answer: B.4:5
Explanation: The hare takes 3 leaps and the jackal takes 5 leaps.
1 hare leap = 4/3 jackal leaps
Thus the hare's 3 leaps = 3*(4/3) = 4 jackal leaps.
The ratio of their speeds is 4:5.
The answer is B.
Question: The length of a rectangular floor is more than its breadth by 300%. If Rs. 423 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
A.24
B.25
C.26.6m
D.26
Answer: C.26.6m
Explanation: Let the length and the breadth of the floor be l m and b m respectively.
l = b + 400% of b = l + 4b = 5b
Area of the floor = 423/3 = 141 sq m
l b = 141 i.e., l * l/5 = 141
l2 = 705 => l = 26.6m.
ANSWER:C
Question: What will be the output of the following code statements?
Integer a = 20, b = 30, c = 8 print (a × b / c) – c
A.65
B.67
C.70
D.26
Answer: B.67
Explanation: Explanation:
Apply BODMAS rule
20 × 30 = 600/8-8 =75 –8 =67
Answer:B
Question: A machine fills 150 bottles of water every 8 minutes. How many minutes it takes this machine to fill 675 bottles?
A.42 minutes
B.72 minutes
C.62 minutes
D.32 minutes
Answer: D.32 minutes
Explanation: 8 minutes are needed to fill 150 bottles. How many groups of 150 bottles are there in 675 bottles?
675 / 150 = 4.5 = 4 and 1/2
For each of these groups 8 minutes are needed. For 4 groups and 1/2
8 * 4 + 4 = 32 + 4 = 36 minutes. (4 is for 1/2 a group that needs half time)
We can also find the final answer as follows
4.5 x 8 = 32 minutes correct answer D
Question: The number of arrangements that can be made with the letters of the word MEADOWS so that the vowels occupy the even places?
A.117
B.144
C.177
D.155
Answer: B.144
Explanation: The word MEADOWS has 7 letters of which 3 are vowels.
-V-V-V-
As the vowels have to occupy even places, they can be arranged in the 3 even places in 3! i.e., 6 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways.
Hence the total ways are 24 * 6 = 144.
Answer:B
Question: 18 buckets of water fill a tank when the capacity of each bucket is 60 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 5 litres?
A.216
B.200
C.212
D.220
Answer: A.216
Explanation: Capacity of the tank = (18 Ã— 60) litre
Number of buckets required of capacity of each bucket is 17 litre = 18Ã—60/5=18Ã—12=216
Answer is A
Question: It takes 4 workers a total of 8 hours to build a giant machine with each worker working at the same rate. If four workers start to build the machine at 11:00 AM, and one extra worker per hour is added beginning at 3:00 PM, at what time will the machine be complete?
A.5:43
B.5:56
C.6:09
D.6:22
Answer: A.5:43
Explanation: 4 workers build 1/8 of a machine in one hour.
1 worker builds 1/32 of a machine in one hour.
In the first 4 hours, 4 workers build 4*(1/32)*4=16/32 of a machine
From 3:00 to 4:00, 5 workers build another 5/32. The total is 21/32.
From 4:00 to 5:00, 6 workers build another 6/32. The total is 27/32.
To build another 5/32, 7 workers need (5/7)*60 minutes which is about 43 minutes.
The machine is complete at about 5:43.
The answer is A.
Question: The cost price of 20 books is the same as the selling price of ’X’ books. If the profit is 40%, then the value of X is ?
A.25
B.18
C.16
D.8.9
Answer: D.8.9
Explanation: let S.P. of X books = Rs 100 = C.P. of 20 books
Therefore, C.P. of one book = Rs 8
Profit = 40 %
Therefore, S.P of one book = 11.2
S.P of X articles = 11.2 X
11.2 X = 100 => X = 8.9
ANSWER:D
Question: What is the value of 4^5+4^7?
A.4^12
B.4^35
C.17(4^5)
D.8^12
Answer: C.17(4^5)
Explanation: 4^5+4^7
=4^5(1+4^2)
=4^5 * 17
Answer C
Question: A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 10% less than the price each head sold for the day before.what was the gross profit W on this shipment?
A.a) $100
B.b) $115
C.c) $125
D.d) $130
Answer: C.c) $125
Explanation: I recommend one should use fractions to solve this one rather than converting it into decimals
Sol:
1500 heads -> $600
1 head -> $600/1500
1 head -> $(2/5)
25% more of (2/5) -> 125/100 * 2/5 = $(1/2)
He sold 2/3*1500 = 1000 heads for $(1/2) per head
Total revenue by selling 1000 heads = 1000 * 1/2 = $500
Heads left: 500
Cost per head: 90% of the previous price: 90/100 * 1/2 = $(9/20)
Total revenue by selling 500 heads = 9/20 * 500 = 225
Total revenue after selling 1500 cabbage heads - 225+500 = $725
Money spent on the purchase: $600
Profit W= 725-600 = $125
Ans:C
Question: In the equation x^2+bâ€¢x+c=0, b and c are constants, and x is a variable. If m is a root of x^2+bâ€¢x+c=0, and (x+n) is a factor of x^2+bâ€¢x+c=0, then b=
A.m:n
B.m-n
C.m+n
D.n-m
Answer: D.n-m
Explanation: the equation is x^2+bx+c=0..
this equation will have two roots...
it is given that m is a root ..
secondly (x+n) is a factor, which means -n is another root..
now we are asked what is b..
in x^2+bx+c=0, the sum of roots = -b/a...
here a=1, so sum of roots=-b..
roots are m and -n, so m+(-n)=-b..
m-n=-b, or b=n-m...
ANSWER D
Question: A woman sells an article at 5% loss. Had she sold it for Rs.60 more she could have gained 10%. What is the cost price of the article?
A.Rs.200/-
B.Rs.400/-
C.Rs.500/-
D.Rs.600/-
Answer: B.Rs.400/-
Explanation: Loss =====> 5 %
Profit ====> 10 %
~
----------------
15 % ---------> Rs.60/-
100 % --------> Rs.400/-
Option 'B'
Question: how many internal diagonals does a pentagon (five sided polygon) have?
A.5
B.8
C.9
D.10
Answer: A.5
Explanation: Number of diagonals in any polygon can be found using this formula: n(n-3)/2
Here n = 5
No. of diagonals = 5(5 - 3)/2
= 5
Ans A