RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What is the remainder when 1041*1047*1050*1053 is divided by 33?
A.3
B.27
C.30
D.21
Answer: D.21
Explanation: take the remainder from each of 1041/33, 1047/33 and so on..
1044/33 gives remainder = 18
1047/33 gives remainder = 24
1050/33 gives remainder = 27
1053/33 gives remainder = 30
the net remainder is the product of above individual remainders. i.e = 18*24*27*30
break them into pairs 18*24/33 gives remainder 3
and 27*30/33 gives remainder 18
so 3*18/33 gives remainder 21.
D
Question: Find the number of ways you can fill a 3 x 3 grid (with 4 corners defined as a, b, c, d), if you
have 3 white marbles and 6 black marbles
A.9c3
B.9c2
C.9c4
D.8c3
Answer: A.9c3
Explanation: The area of the grid is = 9.
Now, No. of ways we can arrange 3 white balls in 9 places = 9c3.
and 6 black balls in (9-3) = 6 places = 6c6 = 1.
So total = 9c3 * 1 = 9c3.
In another way,
No ways we can arrange 6 black balls in 9 places = 9c6 = 9c3
and no ways 3 white balls in (9-6) places = 3c3 = 1
No. of ways we can arrange 3 white balls and 9 black balls in 3x3 grid is = 9c3*1 = 9c3
ANSWER:A
Question: The binary equivalent of 5.375 is
A.101.101110111
B.101.011
C.101011
D.None of above
Answer: B.101.011
Explanation: Explanation :
The process to convert a floating point number to its binary equivalent :
1. Separate the number, based on the decimal point.
Ex. : 5.375 => 5 and .375
3. Convert the whole number part to its binary equivalent. In this case it is 5, so 101.
The final result will be 101.(dot)(something) .
4. Now we have to convert .375 in to its decimal equivalent.
Step 1: Begin with the decimal fraction and multiply by 2. The whole number part of the result is the first binary digit to the right of the point.
.375*2 = 0.75
So the binary result till now is : 101.0
Step 2: Discard the whole number part and again multiply the decimal fraction by 2 and again append the whole number part to the right of the point. Follow this process until we get a zero as our decimal part or until we recognize an infinite repeating pattern.
0.75*2 = 1.50
So the Binary result till now is 101.01
.50 * 2 = 1.00
So, the Final result will 101.011 i.e. option B
Answer : B
Question: In how many ways 4 boys and 3 girls can be seated in a row so that they are alternative?
A.120
B.144
C.160
D.210
Answer: B.144
Explanation: 4 boys can be seated in 4!
three girls can be seated in 3!
Required number = 4!3! = 144
Answer is B
Question: Find the quadratic equations whose roots are the reciprocals of the roots of 2x2 + 5x + 3 = 0?
A.+ 5x - 2 = 0
B.+ 5x + 2 = 0
C.- 5x + 2 = 0
D.- 5x - 2 = 0
Answer: B.+ 5x + 2 = 0
Explanation: The quadratic equation whose roots are reciprocal of 2x2 + 5x + 3 = 0 can be obtained by replacing x by 1/x.
Hence, 2(1/x)2 + 5(1/x) + 3 = 0
=> 3x2 + 5x + 2 = 0
ANSWER:B
Question: To mail a package, the rate is 10 cents for the first pound and 5 cents for each additional pound. Two packages weighing 3 pounds and 5 pounds, respectively can be mailed seperately or combined as one package. Which method is cheaper and how much money is saved?
A.Combined, with a saving of 8 cents
B.Combined, with a saving of 5 cents
C.Separately, with a saving of 2 cents
D.Separately, with a saving of 4 cents
Answer: B.Combined, with a saving of 5 cents
Explanation: 3 pounds = 1*10+2*5 = 20
5 pounds = 1*10+4*5 =30
total = 50
8 pound = 1*10+7*5 = 45
dif. 5
Answer : B
Question: Laura has a deck of standard playing cards with 11 of the 55 cards designated as aheart.If Laura shuffles the deck thoroughly and then deals 10 cards off the top of the deck, what is the probability that the 10th card dealt is a heart?
A.1/4
B.1/5
C.5/26
D.12/42
Answer: B.1/5
Explanation: No replacement there, 10 cards are dealt and we are asked to find the probability that 10th card is a heart.
If there is no replacement then how is the (P) that the 10th card is 11/55 ??
there are many cases here to be considered here if there is no replacement such as:
H- Denotes heart X-may be any diamond, spade or club.
1. HXXXXXXXXH
2. HHXXXXXXXH
3. HHHXXXXXXH
.
.
.
.
.
9. HHHHHHHHHH
10. XXXXXXXXXH
All cases from 1 to 10 will have different probabilities for heart to be at the 10th place and it will take hell lot of time to calculate all of them.
For according to me the above solution by Ian is only valid if cards are replaced (Every card has a 11/55 = 1/5 chance of being a heart; it doesn't matter if it's the top card in the deck or the tenth card in the deck.)If that's the case that brings back me to my original question ----how do we determine that the cards are replaced or not?? based on the question given ....
B
Question: Out of 5 fruits in a basket, 2 are rotten. If two fruits are drawn at random from the basket, the probability of both being rotten is
A.1/10
B.10/21
C.20/21
D.11/21
Answer: A.1/10
Explanation: The number of exhaustive events = 5C2 = 10.
Let E be event of the 2 fruits being rotten. The number of favourable cases are
2C2 = 1 way.
Required probability = 1/10.
ANSWER:A
Question: A can do a piece of work in 10 days; B can do the same in 20 days. How many days will it take the work to get finished if A and B work together?
A.4.21
B.5.32
C.6.66
D.7.52
Answer: C.6.66
Explanation: A completes 1/10th of the work in one day and B completes 1/20th.
(1/10)+(1/20)=(1/x)
3/20=1/x => x=20/3=6.66 days
Answer: C
Question: A bullet train 220 m long is running with a speed of 59 kmph. In what time will it pass a man who is running at 7 kmph in the direction opposite to that in which the bullet train is going?
A.23 sec
B.15 sec
C.12 sec
D.11 sec
Answer: C.12 sec
Explanation: C
12 sec
Speed of the bullet train relative to man = (59 + 7) kmph
= 66 *5/18 m/sec = 55/3 m/sec.
Time taken by the bullet train to cross the man = Time taken by it to cover 220 m at (55/3) m / sec
= (220 *3/55) sec = 12 sec
Question: In an entrance exam, 3 marks is awarded for every correct answer and (-1) for every wrong answer. If a student gets 38 marks after attempting all questions, find the number of questions answered correctly if the total questions were 70.
A.27
B.88
C.26
D.29
Answer: A.27
Explanation: Explanation:
Let x be the number of questions answered correctly. Hence, number of questions whose answer were wrong = (70 – x)
3*x + (70 – x)*(-1) = 38
4x = 38 + 70 = 108
x = 27
ANSWER:A
Question: The mean of 50 observations is 200. But later he found that there is decrements of 15 from each observations. what is the the updated mean is ?
A.165
B.185
C.190
D.198
Answer: B.185
Explanation: 185
Answer is B
Question: A bag contains an equal number of one rupee, 50 paise and 25 paise coins respectively. If the total value is 35, how many coins of each type are there?
A.20 coin
B.30 coins
C.28 coins
D.25 coins
Answer: A.20 coin
Explanation: Let number of each type of coin = x. Then,
1 × x + .50 × x + .25x = 35
⇒ 1.75x = 35 ⇒ x = 20 coin
Answer A
Question: A basket of 2 apple is to be chosen from four apples. What is the probability ways of apples that can be chosen?
A.6
B.8
C.10
D.4
Answer: A.6
Explanation: The question is out of 4 apples 2 apples should be chosen.
Required probability is 4C2=4!/2!*2!=6
The option A is correct.
Question: AB
+BA
-----------
AAC
In the correctly worked addition problem shown here, where the sum of the two-digit positive integers AB and BA is the three-digit integer AAC, and A, B, and C are different digits, what is the units digit of the integer AAC?
A.9
B.6
C.3
D.0
Answer: D.0
Explanation: AB+BA = AAC -> EQ 1
EQ 1 IMPLIES: B+A = 10+C - EQ 2 (DIFFICULT TO INTERPRET. I AGREE. JUST SUM UP THE UNITS DIGIT IN EQ 1)
NOW SPLIT UP EQ 1
10A+B+10B+A = 100A+10A+C - EQ 3
EQ 3 IMPLIES: 11(A+B) = 110A+C
SUBSTITUTE EQ 2 (B+A = 10+C) IN ABOVE
11(10+C) = 110A+C => 110+11C = 110A + C
IMPLIES A = 1C = 0
D
Question: Triangle ABC will be constructed in a xy-plane according to the following conditions: Angle ABC is 90 degrees, and AB is parallel to the y-axis; for each of points A, B and C, both the x-coordinate and the y-coordinate must be integers; the range of possible x-coordinates is 0=<x=<5 and the range of possible y-coordinates is -4=<y=<6. Any two triangles with non-identical vertices are considered different. Given these constraints, how many different triangles could be constructed?
A.50
B.66
C.2500
D.3300
Answer: D.3300
Explanation: Since give that 0=<x=<5 and -4=<y=<6 then we have a rectangle with dimensions 6*11 (6 horizontal and 11 vertical dots). AB is parallel to y-axis, BC is parallel to x-axis and the right angle is at B.
Choose the (x,y) coordinates for vertex B: 6C1*11C1;
Choose the x coordinate for vertex C (as y coordinate is fixed by B): 5C1, (6-1=5 as 1 horizontal dot is already occupied by B);
Choose the y coordinate for vertex A (as x coordinate is fixed by B): 10C1, (11-1=10 as 1 vertical dot is already occupied by B).
6C1*11C1*5C1*10C1=3,300.
Answer: D
Question: Two trains of equal lengths take 10 sec and 15 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
A.22
B.12
C.77
D.99
Answer: B.12
Explanation: Speed of the first train = 120/10 = 12 m/sec.
Speed of the second train = 120/5 = 8 m/sec.
Relative speed = 12 + 8 = 20 m/sec.
Required time = (120 + 120)/20 = 12 sec.
Answer: B
Question: In a box, there are 10 red, 6 blue and 7 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
A.4/51
B.10/23
C.7/12
D.11/31
Answer: B.10/23
Explanation: Total number of balls = 10+6+7 = 23
E = event that the ball drawn is neither red nor green
= event that the ball drawn is red
n(E) = 10
P(E) = 10/23
Answer is B
Question: A bicyclist travels uphill from town A to town B for 2 hours at an average speed of 4 miles per hour and returns along the same road at an average speed of 5 miles per hour. What is the bicyclist’s average speed for the round trip, in miles per hour?
A.(a) 24/5
B.(b) 5
C.(c) 40/9
D.(d) 27/5
Answer: C.(c) 40/9
Explanation: from the uphill we can find out the distance = 4*2 = 8
average speed = total distance/total time
= 16/ (2+ (8/5)) = 40/9
Answer is C.
Question: The milk level in a rectangular box measuring 62 feet by 25 feet is to be lowered by 6 inches. How many gallons of milk must be removed? (1 cu ft = 7.5 gallons)
A.100
B.250
C.750
D.5812.5
Answer: D.5812.5
Explanation: 6 inches = 1/2 feet (there are 12 inches in a foot.), so 62*25*1/2=775 feet^3 of milk must be removed, which equals to 775*7.5=5812.5 gallons.
Answer: D.
Question: Goldman Limited has 5 Senior Managing Directors and 6 Managing Directors. Each investment banking deal requires the guidance of four managing directors, at least one of which must be a Senior Managing Director. How many possible investment banking deals can Morgan Limited possibly provide guidance for?
A. 116
B. 236
C. 315
D. 514
Answer: C. 315
Explanation: P(at least 1 S D) = P(Total) - P(0 Senior Director)
=11C4 - 6C4
= 315
Question: The sum of ages of 5 girls born at the intervals of 2 years each is 50 years. What is the age of the youngest girl?
A.years
B.years
C.years
D.years
Answer: A.years
Explanation: Let the ages of children be x, (x + 2), (x + 4), (x + 6) and (x + 8) years.
Then, x + (x + 2) + (x + 4) + (x +6) + (x + 8) = 50
5x = 30
x = 6.
Age of the youngest child = x =6 years.
A)
Question: If each day a tree loses half its remaining leaves, what fraction of its leaves will it have lost after 3 days ?
A.X-1/8
B.X/2
C.X/4
D.X/32
Answer: A.X-1/8
Explanation: LET NO OF LEAVES IX X ..IST DAY X/2 ..2ND DAY X/4 ..3RD DAY X/8 , FOURTH DAY X/16 , 5TH DAY X/32 , 6TH DAY X/64 SO ON SO FOURTH.
FINALLY ON LEAVE WILL BE LEFT ..SO ON 3RD DAY LEAVE LOST IS X-1/8 ANSWER A
Question: If Joanie puts $500 in a savings account that earns 10 percent annual interest compounded semiannually, how much money will be in the account after one year?
A.$51.25
B.$510
C.$550
D.$551.25
Answer: D.$551.25
Explanation: Since, money is compounded semiannually, rate of interest=10/2=5% and time =1*2=2
C.I=(5%of $500)+5%of(5%of $500)=$51.25
Amount=$500+51.25=$551.25
Answer D
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 16 hours and 4 hours respectively. The ratio of their speeds is:
A.2 : 4
B.4 : 3
C.6 : 7
D.9 : 16
Answer: A.2 : 4
Explanation: Let us name the trains as A and B. Then,
(A's speed) : (B's speed) = âˆšb : âˆša = âˆš4 : âˆš16 = 2 : 4.
Answer A
Question: Ramesh purchased a refrigerator for Rs. 12500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 12% if no discount was offered?
A.17608
B.17920
C.17604
D.17600
Answer: B.17920
Explanation: Price at which the TV set is bought = Rs. 12,500
Discount offered = 20%
Marked Price = 12500 * 100/80 = Rs. 15625
The total amount spent on transport and installation = 125 + 250 = Rs. 375\Total price of TV set = 15625 + 375 = Rs. 16000
The price at which the TV should be sold to get a profit of 10% if no discount was offered = 16000 * 112/100 = Rs. 17920.Answer: B
Question: One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill tank in 37 min, then the slower pipe alone will be able to fill the tank in?
A.229
B.787
C.144
D.148
Answer: D.148
Explanation: Let the slower pipe alone fill the tank in x min.
Then, faster pipe will fill it in x/3 min.
1/x + 3/x = 1/37
4/x = 1/37 => x = 148 min.
Answer: D
Question: If a person has two rectangular fields. The larger field has thrice the length and 4 times the width of the smaller field. If the smaller field has a length 50% more than the width.If a person takes 20 minutes to complete one round of a smaller field then what is the time required to complete one round of a larger field ?
A.69 minutes
B.68 minutes
C.58 minutes
D.48 minutes
Answer: B.68 minutes
Explanation: Let the width of the smaller rectangle is 4 units
then, the length of the smaller rectangle is 6 units(that is 50% more than the width)
Now the perimeter of the rectangle is 2(6+4)=20units
So, 20 units is covered in 20 units, implies covers one unit in one minute
So Now coming to the larger rectangle
The Width =16Units, Length =18units, perimeter=2(16+18)68 units
Thus, to cover the larger field, 68 minutes required to cover the rectangle.
ANSWER:B
Question: Three years ago the average age of a family of eight members was 20 years. A boy have been born, the average age of the family is the same today. What is the age of the boy?
A.A)4
B.B)3
C.C)2
D.D)1
Answer: A.A)4
Explanation: 8 * 23 = 184
9 * 20 = 180
--------------
4
Answer: A
Question: Mr. Moses made an investment of Rs.350. he receives a fixed interest which is compounded annually. His investment doubled after 3 years when compounded annual. How many more years will it take him to get another Rs.700 compound interest?
A.4 years
B.5 years
C.1 years
D.3 years
Answer: D.3 years
Explanation: Explanatory Answer
Rs.350 invested in compound interest becomes Rs.700 in 3 years.
The amount will double again in another 3 years.
i.e., the amount will become Rs.1400 in another 3 years.
So, to earn another Rs.700 interest, it will take another 3 years.
Answer D
Question: Which of the following numbers should not be included in the set?
331, 482, 551, 263, 381, 242, 111
A.263
B.381
C.242
D.111
Answer: B.381
Explanation: Solution
In each number except 381,the product of first and third digits is the middle one. Answer B
Question: Find the highest common factor of 36 and 84.
A.4
B.6
C.12
D.16
Answer: C.12
Explanation: 36 = 22 x 32
84 = 22 x 3 x 7
H.C.F. = 22 x 3 = 12.
Answer: Option C
Question: A and B complete a work in 10 days. A alone can do it in 40 days. If both together can do the work in how many days?
A.1.0875 days
B.0.125 days
C.0.0675 days
D.0.0875 days
Answer: B.0.125 days
Explanation: 1/10 + 1/40 = 0.125 days
ANSWER:B
Question: What will be the ratio of simple interest earned by certain amount at the same rate of interest for 4 years and that for 9 years?
A.1 : 3
B.2 : 3
C.1 : 2
D.4 : 9
Answer: D.4 : 9
Explanation: Let the principal be P and rate of interest be R%.
Required ratio =
(P x R x 4)/100 DIVIDED BY	(P x R x 9)/100
=	4PR/9PR	=	4/9	= 4 : 9.
ANSWER : D
Question: Hitesh is 40 years old and Ronnie is 60years old. How many years ago was the ratio of their ages 3:5?
A.10
B.15
C.20
D.8
Answer: A.10
Explanation: Suppose the ratio was 3:5, x years ago
40-x / 60-x = 3/5
5(40-x) = 3(60-x)
x = 10
Answer is A
Question: Peter mixed 24 kg of butter at $150 per kg with 36 kg butter at the rate of $125 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
A.$156
B.$177
C.$189
D.$190
Answer: C.$189
Explanation: C
$189
CP per kg of mixture = [24(150) + 36(125)]/(24 + 36) = $135
SP = CP[(100 + profit%)/100]
= 135 * [(100 + 40)/100] = $189.
Question: The largest number amongst the following that will perfectly divide 101100 – 1 is?
A.9000
B.91000
C.10000
D.11000
Answer: C.10000
Explanation: The easiest way to solve such problems for objective exam purposes is trial and error or by back
substituting answers in the choices given.
1012 = 10,201
1012 − 1 = 10,200.
This is divisible by 100.
Similarly try for 1013 − 1 = 1,030,301−1 = 1,030,300.
So you can safely conclude that (1011 − 1) to (1019 − 1) will be divisible by 100.
(10110 − 1) to (10199 − 1) will be divisible by 1000.
Therefore, (101100 − 1) will be divisible by 10,000
C)
Question: Harkamal purchased 8kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 75 per kg. How much amount did he pay to the shopkeeper?
A.A)1055
B.B)1075
C.C)1065
D.D)1235
Answer: D.D)1235
Explanation: Cost of 8 kg grapes = 70 × 8 = 560.
Cost of 9 kg of mangoes = 75 × 9 = 675.
Total cost he has to pay = 560 + 675 = 1235.
D)
Question: If a family spends 40 percent of its household budget on rent and utilities, 30 percent to food, and 20 percent on other bills, what fraction of their monthly budget is available for savings ?
A.4/5
B.1/10
C.3/5
D.1/10
Answer: D.1/10
Explanation: 100%-(40%+30%+20%)=10% of the budget is available --> 10% = 10/100 = 1/10.
Answer: D.
Question: A boat can move upstream at 25 kmph and downstream at 35 kmph, then the speed of the current is?
A.5
B.6
C.7
D.7
Answer: A.5
Explanation: US = 25
DS = 35
M = (35 - 25)/2 = 5
Answer: A
Question: A rectangular tiled patio is composed of 40 square tiles. The rectangular patio will be rearranged so that there will be 2 fewer columns of tiles and 4 more rows of tiles. After the change in layout, the patio will still have 40 tiles, and it will still be rectangular. How many rows are in the tile patio before the change in layout?
A.5
B.6
C.10
D.13
Answer: B.6
Explanation: r*c=70 and (6+4)(c-2)=70 --> r=6 and c=6.
Answer: B.
Question: Ram is able to sell a hand-carved statue for $770 which was a 10% profit over his cost. How much did the statue originally cost him?
A.$496.30
B.$512.40
C.$555.40
D.$700
Answer: D.$700
Explanation: Cost price = 770/110*100 = 700
Answer : D
Question: n a certain flower shop, which stocks four types of flowers, there are 1/3 as many violets as carnations, and 1/4 as many tulips as violets. If there are equal numbers of roses and tulips, what percent of the flowers in the shop are carnations?
A.62
B.63
C.64
D.66.66
Answer: D.66.66
Explanation: Given :-
Violets - C/3
Carnations - C
Tulip - C/12
Rose - C/12
Total flowers in terms of C = C/3+C+C/12+C/12 = 18C/12
Percentage of Carnations = C/3C/2 *100 =66.66%
Answer D
Question: PZQW : NXOU :: FISK :?
A.EFPJ
B.FERI
C.DGQI
D.HKUM
Answer: C.DGQI
Explanation: Difference of one alphabet on each side of proportion term. Answer is thus DGQI
ANSWER:C
Question: Machine X can complete a job in half the time it takes Machine Y to complete the same job, and Machine Z takes 50% longer than Machine X to complete the job. If all three machines always work at their respective, constant rates, what is the ratio J of the amount of time it will take Machines X and Z to complete the job to the ratio of the amount of time it will take Machines Y and Z to complete the job?
A.5 to 1
B.10 to 7
C.1 to 5
D.7 to 10
Answer: D.7 to 10
Explanation: Solutioning this exercise can be facilitated by using a R T W (rate time work) table:
We translate the exercise into the table:
R T W
X t/2 1
Y t 1
Z (t/2*3/2 =3t/4) 1
From this table we find the rates
Rx = 2/t
Ry = 1/t
Rz = 4/3t
The Q is what is the ratio of (Tx + Ty) / (Ty + Tz)
Rx + Ry = 2/t + 4/3t = 6/3t+4/3t = 10/3t
Ry+Rz = 1/t + 4/3t = 3/3t + 4/3t = 7/3t
The (10/3t)/(7/3t) = 10/7 then the work ratios is 10 to 7
Since Time Ratio J is the inverse of work, the the answer is 7 to 10
CORRECT ANSWER D
Question: A train 575 m long crosses a tunnel of length 325 in 90 sec. What is the speed of the train in kmph.
A.28
B.32
C.36
D.24
Answer: C.36
Explanation: Total distance traveled = Length of train + Length of tunnel = 575 + 325 = 900
Time taken to cross the tunnel = 90 sec.
Speed in kmph = distance/time *18/5 = 900/90 * 18/5
= 180/5 = 36 kmph
ANSWER:C
Question: If X and Y are both positive two-digit integers and share no digits, and X > Y, what is the smallest possible value of X - Y?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: Answer = B = 1
20 - 19 = 30-29 = 40-39 = 50-49 = 1
Question: Find the average of first 4 multiples of 9?
A.10
B.12.6
C.22.5
D.31.3
Answer: C.22.5
Explanation: average = (9+18+27+36)/4 = 22.5
Answer is C
Question: A table is bought for Rs.500/- and sold at a loss of 10% find its selling price
A.s.450/-
B.s.530/-
C.s.540/-
D.s.600/-
Answer: A.s.450/-
Explanation: 100 % ------> 500 (100 * 5 = 500)
90 % ------> 450 (90 * 5 = 450)
Selling price = Rs.450/-
A
Question: If the remainder is 11 when the integer n is divided by 20, what is the remainder when 2n is divided by 10?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: n = 20k+11
2n = 2(20k+11) = 4k*10 + 22 = 4k*10 + 2*10 + 2 = 10j + 2
The answer is C.
Question: The average age of 15 students of a class is 15 years. Out of these, the average age of 5 students is 14 years and that of the other 9 students is 16 years. Tee age of the 15th student is?
A.11 years
B.17 years
C.67 years
D.14 years
Answer: A.11 years
Explanation: Age of the 15th student
=[15 * 15 - (14 * 5 + 16 * 9)]
= (225 - 214)
= 11 years.
Answer:A
Question: On Children's Day, sweets were to be equally distributed among 175 children in a school. Actually on the Children's Day, 35 children were absent and therefore each child got 4 sweets extra. Total how many sweets were available for distribution ?
A.2400
B.2480
C.2680
D.2800
Answer: D.2800
Explanation: Let take X is the sweets received by each student.
Actually on the Children's Day, 35 children were absent and therefore each child got 4 sweets extra. means
35*x = 140*4 = 560. X= 16. total Sweets are 175*16 = 2800
ANSWER:D
Question: A circular well with a diameter of 6 metres , is dug to a depth of 24 metres. What is the volume of the earth dug out?
A.678.6 m3
B.36 m3
C.40 m3
D.44 m3
Answer: A.678.6 m3
Explanation: Solution
Volume	= πr2h
‹=› (22 /7 ×3×3×24)m3
‹=›678.6 m3.
Answer A
Question: Two men started from the same place walk at the rate of 10kmph and 12kmph respectively. What time will they take to be 30 km apart, if they walk in the same direction?
A.15hours
B.6hours
C.8hours
D.10hours
Answer: A.15hours
Explanation: To be 2km apart they take 1 hour
To be 10km apart they take = 1/2 * 30 =15 hours
Answer is A
Question: A total of 3000 chocolates were distributed among 120 boys and girls such that each boy received 2 chocolates and each girl received 3 chocolates. Find the respective number of boys and girls?
A.97
B.60
C.91
D.26
Answer: B.60
Explanation: Let the number of boys be x.
Number of girls is 120 - x.
Total number of chocolates received by boys and girls = 2x + 3(120 - x) = 300
=> 360 - x = 300 => x = 60.
So, the number of boys or girls is 60.
Answer: B
Question: A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
A.12 kg
B.60 kg
C.72 kg
D.80 kg
Answer: B.60 kg
Explanation: Volume of water displaced	= (3 x 2 x 0.01) m3
= 0.06 m3.
Mass of man	= Volume of water displaced x Density of water
= (0.06 x 1000) kg
= 60 kg. Answer: Option B