RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A certain college party is attended by both male and female students. The ratio of male to female students is 4 to 5. If 12 of the male students were to leave the party, the ratio would change to 1 to 2. How many total students are at the party?
A.64
B.72
C.80
D.88
Answer: B.72
Explanation: The ratio is 4:5 = 8:10, so there are 8k males and 10k females.
If 12 males left, the ratio would be 1:2 = 5:10, so there would be 5k males and 10k females.
8k-5k = 12
k = 4
8k + 10k = 32 + 40 = 72
The answer is B.
Question: Two pipes A and B can fill a cistern in 37 1/2 minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the pipe B is turned off after?
A.5 min
B.9 min
C.10 min
D.15 min
Answer: B.9 min
Explanation: Explanation:
Let B be turned off after x minutes. Then, part filled by (A + B) in x min + part filled by A in (30 - x) min = 1.
x(2/75 + 1/45) + (30- x) 2/75 = 1
11x + 180 - 6x = 225 => x = 9
ANSWER IS B
Question: A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 3 m, the volume of the box (in m3) is:
A.3780
B.5120
C.6420
D.8960
Answer: A.3780
Explanation: Clearly, l = (48 - 6)m = 42 m,
b = (36 -6)m = 30 m,
h = 8 m.
Volume of the box = (42 x 30 x 3) m3 = 3780 m3. Answer: Option A
Question: A and B are integers. The expression (A+1)(B+1) is even. What can be said about A and B?
A.They are both even numbers.
B.At least one of them is even
C.At least one of them is odd.
D.They are both odd.
Answer: C.At least one of them is odd.
Explanation: Odd x Odd = Odd
Odd x Even = Even
Even x Even = Even
To fulfill condition Either (A+1) or (B+1) needs to be Even
So either A or B needs to be odd
Or At Least one of them is odd.
ANSWER:C
Question: Using only the digits from 0 to 6 , how many 5 digit codes can be constructed, if the first digit can not be 4 and no digits is used more than once ?
A.1800
B.2160
C.7776
D.720
Answer: A.1800
Explanation: 5*6*5*4*3 = 1800
ANSWER:A
Question: How much is 50% of 40 is greater than 4/5 of 25?
A.0
B.67
C.88
D.12
Answer: A.0
Explanation: (50/100) * 40 – (4/5) * 25
= 0
Answer: A
Question: A person distributed 10% of his income to his 2 children each. He deposited 20% of his income to his wife's account. He donated 10% of remaining amount to an orphan house.Finally he has $500. Find his total income?
A.$900
B.$1000
C.$1200
D.$1150
Answer: B.$1000
Explanation: 2 children got = 2*10% = 20%
wife got = 20%
orphan house = 10%
total = 20+20+10= 50%
remaining = 100-50 = 50%
50% = 500
100% = 500*100/50 = $1000
Answer is B
Question: If a new town has 300 residents, and the population doubles every 10 years, what will be its population after 75 years?
A.6034 residents
B.9051 residents
C.54306 residents
D.15075 residents
Answer: C.54306 residents
Explanation: 300*2^(75/10)=300*2^7.5=100*181.02=54306
The answer is C.
Question: 3 men or 6 women can do a piece of work in 20 days. In how many days will 12 men and 8 women do the same work?
A.15/7 days
B.15/4 days
C.17/4 days
D.15/6 days
Answer: B.15/4 days
Explanation: 3M = 6W ---- 20 days
12M + 8W -----?
24W + 8 W = 32W ---?
6W ---- 20 32 -----?
6 * 20 = 32 * x => x = 15/4 days Answer: B
Question: Find the area, diameter = 12m.
A.113.00 square meter
B.113.04 square meter
C.113.08 square meter
D.113.24 square meter
Answer: B.113.04 square meter
Explanation: Diameter = 12 meter.
Radius = diameter/2.
= 12/2.
= 6 meter.
Area of a circle = πr2.
Here, pi (π) = 3.14 meter, radius (r) = 6.
Area of a circle = 3.14 × 6 × 6..
= 3.14 × 36.
= 113.04 square meter or 113.04 m2. ANSWER : B
Question: A salesman’s terms were changed from a flat commission of 5% on all his sales to a fixed salary of Rs.1200 plus 2.5% commission on all sales exceeding Rs. 4,000. If his remuneration as per new scheme was Rs. 1200 more than that by the previous schema, his sales were worth?
A.12028
B.12000
C.12019
D.16000
Answer: D.16000
Explanation: [1200 + (X-4000) * (2.5/100)] - X * (5/100)
= 600
X = 16000
Answer: D
Question: The speed of a boat in still water is 24 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 15 minutes is
A.1.6 km
B.2 km
C.3.6 km
D.6.75 km
Answer: D.6.75 km
Explanation: Explanation:
Speed downstreams	=(24 + 3)kmph
= 27 kmph.
Distance travelled	= (27 x 15/60)km
= 6.75 km
Option D
Question: Mr Yadav spends 60% of his monthly salary on consumable items and 50% of the remaining on clothes and transport. He saves the remaining amount. If his savings at the end of the year were 48456, how much amount per month would he have spent on clothes and transport?
A.4038
B.8076
C.9691.2
D.4845.6
Answer: A.4038
Explanation: ∵ Amount, he have spent in 1 month on clothes transport = Amount spent on saving per month
∵ Amount, spent on clothes and transport
= 48456⁄12 = 4038
Answer A
Question: A Japanese rock band made ¥3 million on their first album with sales of ¥12 million, and made ¥5 million on their second album with sales of ¥30 million. By approximately what percent did the ratio of profit to sales decrease from the first album to second album?
A.24%
B.27%
C.30%
D.33%
Answer: D.33%
Explanation: Solution:
This is a percent decrease problem. We will use the formula: percent change = (new – old)/old x 100 to calculate the final answer.
We first set up the ratios of profits to sales. The first ratio will be for the first album, and the second ratio will be for the next album. Because all of the sales are in millions, we do not have to express all the trailing zeros in our ratios.
First album
profit/sales = 3/12 = 1/4
Second album
profit/sales = 5/30 =1/6
We can simplify each ratio by multiplying each by the LCM of the two denominators, which is 12. Keep in mind that we are able to do this only because our answer choices are expressed in percents.
First album
profit/sales = (1/4) x 12 = 3
Next 2 Million
profit/sales = (1/6) x 12 = 2
We can plug 3 and 2 into our percent change formula:
(2 – 3)/3 x 100
=-1/3 x 100 so approximately a 33% decrease.
Answer D.
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?
A.15
B.19
C.14
D.18
Answer: C.14
Explanation: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 42/3 = 14 kmph.
Answer:C
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 800 m long?
A.266 Sec
B.200 Sec
C.776 Sec
D.166 Sec
Answer: B.200 Sec
Explanation: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 2000 m
T = D/S
T = 2000/10
T = 200 Sec
Answer: B
Question: If y exceeds x by 20%, then x is less than y by?
A.16%
B.16 1/3 %
C.16 2/3 %
D.16 3/5 %
Answer: C.16 2/3 %
Explanation: Explanation:
X=100	y=120
120------20
100-------? => 16 2/3%
ANSWER IS C
Question: 3 candidates in an election and received 2500, 5000 and 15000 votes respectively. What % of the total votes did the winningcandidate got in that election?
A.45%
B.50%
C.57%
D.66.6%
Answer: D.66.6%
Explanation: Total number of votes polled = (2500 + 5000 + 15000) = 22500
So, Required percentage = 11628/20400 * 100 = 66.6%
D
Question: Two musicians, Maria and Perry, work at independent constant rates to tune a warehouse full of instruments. If both musicians start at the same time and work at their normal rates, they will complete the job in 45 minutes. However, if Perry were to work at twice Maria’s rate, they would take only 30 minutes. How long would it take Perry, working alone at his normal rate, to tune the warehouse full of instruments?
A.1 hr 30 min
B.1 hr 45 min
C.2 hr
D.2 hr 20 min
Answer: A.1 hr 30 min
Explanation: Sol:
Lets Perry Rate be P and Rate of Maria be M
(rate)*(time)= Work or rate = work/time
first equation=> P+M = 1/45
converting it to hrs P+M= 1/(45/60) => 1/(3/4) =>4/3
second equation => M+2M =>1/30
converting it to hrs 3M=1/(30/60) =>1/(1/2) =>2
therefore M= 2/3 and P=2/3
Rate of Perry = 2/3
time= work/rate (work = 1 job)
Time= 1.5 hrs
Answer A
Question: Danny drove his old car 100 kilometers, from his home to a friend. To prevent the engine from overheating, he stopped his car for 13 minutes every time he completed 40 kilometers of continuous driving. When the car was moving, Danny drove it at an average speed of 60 kilometers per hour. What was Danny's average speed on that trip?
A.37.5 kilometers per hour
B.47.6 kilometers per hour
C.50 kilometers per hour
D.75 kilometers per hour
Answer: B.47.6 kilometers per hour
Explanation: Time taken to reach first 40 km is 40/60 = 2/3 hr
Time taken to reach next 40 km is 40/60 = 2/3 hr
Time taken to reach next 20 km is 20/60 = 1/3 hr
Danny stopped twice on his way at 40 km from starting point and at 80km from the starting point...
Each stop was of 13min , so two 13min break = 2*13/60 => 13/30 hr
Total time taken to reach 100 km is (2/3 + 2/3 + 1/3+13/30 ) =21/10 hrs
So, Average speed is 100/(21/10) = 47.6km/hour
Answer will be B
Question: The function g(p) is defined for integers p such that if p is even, g(p) = p/2 and if p is odd, g(p) = p + 5. Given that g(g(g(g(g(p))))) = 19, how many possible values for p would satisfy this equation?
A.1
B.5
C.7
D.8
Answer: D.8
Explanation: Let me define terms:
in g(p) = R
p is argument, R is result, g() is function,
in g(g(g(g(g(p))))), g1 is inner most, g5 is outermost for identification.
From definition of function g, we can deduce that:
If Result is even then two possibilities for argument = 1 Even 1 Odd
If Result is odd then one possibility for argument = 1 Even
Since final result = 19 = Odd
Possibilities:
g1:1 Even
g2: 1*(Even,Odd ) =1 Even 1 Odd
g3: 1*(Even,Odd) + 1 Even =2 Even 1 Odd
g4: 2*(Even, Odd) + 1 Even =3 Even 2 Odd
g5: 3*(Even, Odd) + 2 Even =5 Even 3 Odd = Total 8
Ans D it is!
Question: Jill invests $10000 in an account that pays an annual rate of 3.96%, compounding semi-annually. Approximately how much Q does she have in her account after two years?
A.$10079.44
B.Q=$10815.83
C.$12652.61
D.$14232.14
Answer: B.Q=$10815.83
Explanation: PS. I guess one can use simple interest to solve cause the answer choices are quite spread between you can easily arrive at something near 8%
Hence B the answer
Question: What is the least value of x. So that 30x55 is divisible by 3?
A.4
B.5
C.1
D.2
Answer: D.2
Explanation: The sum of the digits of the number is divisible by 3, then the number is divisible by3.
3 + 0+ x + 5 + 5 = 13+ x
Least value of x may be 2
Therefore 13+ 2 = 15 is divisible by 3.
D
Question: For positive x and y if x/y is n% of y, then what percent must x be of y?
A.(y × n)%
B.(n/y)%
C.(√n)%
D.(n^2)%
Answer: A.(y × n)%
Explanation: Solution -
The statement x/y is n% of y means that: x/y = (n / 100) × y
In order to find what percent must x be of y i.e., we need to divide x by y.
x/y %=(n / 100) × y *100 ---->(y*n)%
Therefore x/y is (y*n)%
ANSWER:A
Question: A “palindromic integer” is an integer that remains the same when its digits are reversed. So, for example, 43334 and 516615 are both examples of palindromic integers. How many 6-digit palindromic integers are both even and greater than 800,000?
A.60
B.100
C.160
D.240
Answer: B.100
Explanation: The first digit and last digit are the same so the only possibility is 8.
The second and third digits can be any number from 0 to 9.
The total number of palindromic integers is 1*10*10 = 100
The answer is B.
Question: An amount of Rs.1560 was divided among A, B and C, in the ratio 1/2 : 1/3 : 1/4. Find the share of C?
A.Rs.390
B.Rs.368
C.Rs.380
D.Rs.360
Answer: D.Rs.360
Explanation: Let the shares of A, B and C be a, b and c respectively.
a : b : c = 1/2 : 1/3 : 1/4
Let us express each term with a common denominator which is the last number divisible by the denominators of each term i.e., 12.
a : b : c = 6/12 : 4/12 : 3/12 = 6 : 4 : 3.
Share of C = 3/13 * 1560 = Rs. 360.
Answer: D
Question: There are some passengers riding on a bus. At the first stop, half the passengers get off and nobody gets on the bus. This pattern continues as the bus goes to the next stops. If only one passenger gets off at stop number 4, how many passengers were on the bus originally?
A.128
B.64
C.32
D.16
Answer: D.16
Explanation: Before stop 4, there were 2 passengers on the bus.
Before stop 3, there were 4 passengers on the bus.
Before stop 2, there were 8 passengers on the bus.
Before stop 1, there were 16 passengers on the bus.
The answer is D.
Question: In the Hillside summer camp there are 50 children. 90% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 20% of the total number of children in the camp. How many more boys must she bring to make that happen?
A.35.
B.45.
C.40.
D.30.
Answer: A.35.
Explanation: Given there are 50 students , 90% of 50 = 45 boys and remaining 5 girls.
Now here 90% are Boys and 10% are Girls.
Now question is asking about how many boys do we need to add, to make the girls percentage to or 20%..
If we add 35 to existing 45 then the count will be 80 and the girls number will be 20 as it.
Now boys are 80% and girls are 20%. ( out of 100 students = 80 boys + 20 girls ).
IMO option A is correct.
Question: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability taht the ticket drawn has a number which is a multiple of 3 or 5?
A.1/2
B.2/5
C.8/15
D.9/20
Answer: D.9/20
Explanation: Solution
Here S=(1,2,3,4,5,...,19,20).
Let E=event of getting a multiple of 3 or 5
= (3,6,9,12,15,18,5,10,20)
P(E)= n(E) / n(S)
= 9/20.
Answer D
Question: A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.21000. A's share is?
A.2999
B.2778
C.7000
D.2889
Answer: C.7000
Explanation: x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 21000 = 7000
Answer:C
Question: The total cost of 100 paper plates and 200 paper cups is $4.50 At the same rates what is the total cost of 20 of the plates and 40 of the cups?
A.$.90
B.$1.00
C.$1.20
D.$1.50
Answer: A.$.90
Explanation: U dont need to go through all this
What u have with u is
100 P + 200 C = $4.50
Just divide the equation by 5 and you will get what u are looking for
20P + 40 C = $0.90
Therefore OA is A
Question: If two numbers are in the ratio 2:3. If 7 is added to both of the numbers then the ratio becomes 3:4 then find the smallest number?
A.A)12
B.B)14
C.C)20
D.D)24
Answer: B.B)14
Explanation: 2:3
2x + 7 : 3x + 7 = 3 : 4
4[2x + 7] = 3[3x + 7]
8x + 28 = 9x + 21
9x - 8x = 28 - 21
x = 7
Then smallest number is = 2
2x = 14
Correct Option B
Question: What decimal of an hour is a second ?
A.0.00027
B.0.00029
C.0.00031
D.0.00025
Answer: A.0.00027
Explanation: Required decimal = 1/60x60 = 1/3600 = .00027
Answer is A.
Question: When the price of an article was reduced by 35% its sale increased by 80%. What was the net effect on the sale?
A.17% increase
B.44% decrease
C.60% increase
D.66% increase
Answer: A.17% increase
Explanation: if n items are sold for $p each, revenue is $np. If we reduce the price by 35%, the new price is 0.65p. If we increase the number sold by 80%, the new number sold is 1.8n. So the new revenue is (0.65p)(1.8n) = 1.17np, which is 1.17 times the old revenue, so is 17% greater.
ANSWER:A
Question: Teas worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs 152 per Kg , the price of the third variety per Kg will be?
A.Rs. 147.50
B.Rs. 785.50
C.Rs. 174.50
D.Rs. 258.50
Answer: C.Rs. 174.50
Explanation: Explanation :
Since first and second varieties are mixed in equal proportions.
So, their average price =Rs. (126+135)/2.
=>Rs. 130.50.
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1.
We have to find x.
By the rule of alligation, we have:
Cost of 1 kg Cost of 1 kg
of 1st kind of 2nd kind
(Rs. 130.50) (Rs. x)
\ /
Mean Price
(Rs. 152)
/ \
xâˆ’152 22.50
=>xâˆ’(152/22.50)=1.
=>xâˆ’152=22.50.
=>x= 174.50 Rs.
Answer : C
Question: One side of a triangle has length 5 and a second side has length 4. Which of the following could be the area of the triangle?
I. 15
II. 10
III. 5
A.I only
B.II only
C.III only
D.II and III only
Answer: D.II and III only
Explanation: The triangle will have a maximum area when it is a right angled triangle
The largest triangle will be formed when 5 and 4 are the base and height of triangle .
Area = 1/2 * 5 * 4 = 10
There is no lower limit on the area of any triangle whose only 2 sides are known.
Then 0 < Area <= 10
The answer is D.
Question: One card is drawn from a pack of 52 cards. What is the probability that the card drawn is a ten or a spade?
A.3/7
B.4/13
C.4/15
D.7/19
Answer: B.4/13
Explanation: Out of 52 cards there will be 13 spades including 1 ten and there are 3 more tens. Total 16
probability= 16/52 = 4/13
Answer is B
Question: There are m cities. What is the number of airlines that connected 2 different cities (airline from city A to city B is different with airline from city B to city A)?
A.n(n-1)
B.m(m-1)
C.n(n-1)/2
D.n(n+1)/2
Answer: B.m(m-1)
Explanation: First of all, the possible number of airlines is m. Then, the possible number of airlines departing from one city to another becomes (m-1). Hence, the answer is m(m-1), which makes A an answer choice.
B
Question: In how many ways can the integer 800 be expressed as a product of two different positive integers?
A.10
B.7
C.5
D.4
Answer: B.7
Explanation: 800=(2^5)*(5^2)
Since 800 is not a perfect square, no of ways=7
Answer B
Question: One day, Connie plays a game with a fair 6-sided die. Connie rolls the die until she rolls a 6, at
which point the game ends. If she rolls a 6 on her first turn, Connie wins 6 dollars. For each
subsequent turn, Connie wins 1
6 of the amount she would have won the previous turn. What is
Connie's expected earnings from the game?
A.32/31
B.33/31
C.34/31
D.36/31
Answer: D.36/31
Explanation: Connie has a 1
6 chance of winning 6 dollars her first turn. She has a 5/6
1/6 chance of
winning 1 dollar her second turn. Next, she has a 25
36
1/6 chance of winning 1/6 dollars her third turn.
Generalizing, Connie's expected earnings form a geometric series with initial term 1/6 *6 = 1 and
common ratio 5/6* 1/6 = 5/36 . Hence, Connie's expected earnings are
1/1- 5/36
=
36/31
correct answer D
Question: Visitors to show were charged Rs.15 each on the first day. Rs.7.50 on the second day, Rs.2.50 on the third day and total attendance on the three days were in ratio 2:5:13 respectively. The average charge per person for the whole show is?
A.Rs.6.00
B.Rs.5.50
C.Rs.5.00
D.Rs.7.00
Answer: C.Rs.5.00
Explanation: Answer: Option C
2: 5: 13
2x 5x 13x
15 7.5 2.5
30x + 37.5x + 32.5x = 100x/20x
average = 5
Question: The average weight of a group of boys is 30 kg. After a boy of weight 37 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
A.A)4
B.B)8
C.C)6
D.D)2
Answer: C.C)6
Explanation: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 37 kg joins the group, total weight of boys = 30x + 37
So 30x + 37 = 31(x + 1) = > x = 6.
Answer:C
Question: 6x – 5y + 3z = 23
4x + 8y – 11z = 7
5x – 6y + 2z = 11
Given the equations above, x + y + z = ?
A. 11
B. 12
C. 13
D. 14
Answer: B. 12
Explanation: (6x – 5y + 3z) - (5x – 6y + 2z ) = 23-11
or, x+y+z = 12
Option B is the ans
Question: Three coins are tossed. Find the probability of at least 2 tails ?
A.1/2
B.2/3
C.1/4
D.1/8
Answer: A.1/2
Explanation: n(s) = 2^3 = 8
let E is the event of getting at least 2 tails
n(E) = TTT, TTH , HTT, THT = 4
P(E) = n(E) / n(s)
= 4/8
= 1/2
Ans- A
Question: The amount of water (in ml) that should be added to reduce 12 ml. Lotion, containing 50% alcohol, to a lotion containing 30% alcohol, is?
A.8 ml
B.5 ml
C.4 ml
D.6 ml
Answer: A.8 ml
Explanation: 6 6
30% 70%
30% ----- 6
70% ------? => 14 - 6 = 8 ml
Answer:A
Question: Mary and Mike enter into a partnership by investing $550 and $450 respectively. At the end of one year, they divided their profits such that a third of the profit is divided equally for the efforts they have put into the business and the remaining amount of profit is divided in the ratio of the investments they made in the business. If Mary received $1000 more than Mike did, what was the profit made by their business in that year?
A.$8000
B.$10000
C.$15000
D.$12000
Answer: C.$15000
Explanation: Explanatory Answer
Let the profit made during the year be $3x
Therefore, $x would have been shared equally and the remaining $2x would have been shared in the ratio 5.5 : 4.5
i.e., 55% of 2x would go to Mary and 45% of 2x would go to Mike.
Hence, Mary would get (55 - 45)% of 2x more than Mike
Or10% of 2x = $1000
i.e.,(60/100)*2x = 1000
or 2x = 10000.
Hence, the profit made by the company during the year $3x = $15000.
Answer : C
Question: In an election, candidate A got 79% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favour of candidate.
A.357003
B.357090
C.37667
D.379888
Answer: B.357090
Explanation: Total number of invalid votes = 15 % of 560000
= 15/100 × 560000
= 8400000/100
= 84000
Total number of valid votes 560000 – 84000 = 476000
Percentage of votes polled in favour of candidate A = 75 %
Therefore, the number of valid votes polled in favour of candidate A = 75 % of 476000
= 75/100 × 476000
= 35700000/100
= 357090
Answer:B
Question: A plane flies 660 km with the wind and 570 km against the wind in the same length of time. If the speed of the wind is 15 km/h, what is the speed of the plane in still air?
A.185 km/h
B.195 km/h
C.205 km/h
D.215 km/h
Answer: C.205 km/h
Explanation: The speed of the plane in still air = x km/h
The speed of the wind is 15 km/h
Speed with the wind = (x + 15) km/h
Speed against the wind = (x â€“ 15) km/h
Time = Distance/ Speed
660 / (x+15) = 570 / (x-15)
660(x-15) = 570(x+15)
66x - 990 = 57x + 855
9x = 1845
x = 205
Therefore, the speed of the plane in still air is 205 km/h.
The answer is C.
Question: Quentin's income is 60% less than Rex's income, and Sam's income is 25% less than Quentin's income. If Rex gave 60% of his income to Sam and 40% of his income to Quentin, Quentin's new income would be what fraction of Sam's new income?
A.8/9
B.11/12
C.8/13
D.11/13
Answer: A.8/9
Explanation: We can take some easy numbers and make calculations simpler.
Let R ( Rex's income) = 100
Q (Quentin's income) = 40%R = 40
S (Sam's income) = 75% Q = (3/4)*40 = 30
Now, if Rex gives 40% to Quentin --> Q = 40 + 40 = 80
60% given to Sam --> S = 30+60 = 90
The ratio is : Q/S = 80/90 = 8/9
ANSWER:A
Question: What is the principal sum?
I. The sum amounts to Rs. 660 in 3 years at S.I.
II. The sum amounts to Rs. 700 at S.I.
III. The rate of interest is 6% p.a.
A.I and III only
B.II and III only
C.I and II only
D.Any two of the three
Answer: A.I and III only
Explanation: Explanation:
Clearly, I and III is needed to solve this question where as II is not needed
Answer: A
Question: The side of a rhombus is 26 m and length of one of its diagonals is 20 m. The area of the rhombus is?
A.388
B.267
C.298
D.480
Answer: D.480
Explanation: 262 – 102 = 242
d1 = 20 d2 = 48
1/2 * 20 * 48 = 480.Answer:D
Question: A shopkeeper wishes to give 5% commission on the marked price of an article but also wants to earn a profit of 10%. If his cost price is Rs. 95, then marked price is:
A.Rs. 100
B.Rs.110
C.Rs. 120
D.Rs. 130
Answer: B.Rs.110
Explanation: Solution: CP = Rs. 95.
Then SP = 95 + 10% of 95 = Rs. 104.5.
Let MP = X. He gives 5% commission on MP.
So,
SP = X - 5% of X
SP = 0.95X.
104.5 = 0.95X.
X = 104.5/0.95 = 110.
Thus, MP = Rs. 110.
Short-cut
95===10%(gain)===>104.5===5%(Commission)===>109.72( = 110)
Answer: Option B
Question: A and B together can do a work in 9 days. If A alone can do it in 18 days. In how many days can B alone do it?
A.10
B.99
C.18
D.55
Answer: C.18
Explanation: 1/9 – 1/18 = 1/18
=> 18
Answer: C