RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?
A.111.12
B.111.18
C.111.11
D.111.98
Answer: A.111.12
Explanation: A runs 1000 m while B runs 900 m and C runs 800 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 800)/900 = 8000/9 = 888.88 m.
B can give C = 1000 - 888.88 = 111.12 m.Answer: A
Question: A person's salary is getting reduced by 20%. What percentage should be added to get back his
original salary?
A.25%
B.50%
C.75%
D.85%
Answer: A.25%
Explanation: Salary he get after reduced 20% = 100-20% = 80%
So,percentage should be added to get back his salary = (20/80)*100 = 25%
ANSWER:A
Question: If 10 men do a work in 80 days, in how many days will 20 men do it?
A.18 days
B.38 days
C.40 days
D.48 days
Answer: C.40 days
Explanation: 10 * 80 = 20 * x
x = 40 days
ANSWER:C
Question: The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
A.74
B.94
C.184
D.364
Answer: D.364
Explanation: L.C.M. of 6, 9, 15 and 18 is 90.
Let required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
Required number = (90 x 4) + 4 = 364. Answer: Option D
Question: The minute hand of a clock overtakes the hour hand at intervals of 65 minutes of correct time. How much does the clock gain or lose in 12 hours?
A.27.273 seconds
B.29.273 seconds
C.37.273 seconds
D.47.273 seconds
Answer: A.27.273 seconds
Explanation: After 60 minute rotation the minute hand will make an angle of 30 degree with hour hand.After that let the time required to make an overtake is t minute
in this time angle covered by minute hand = (360/60)t = 6t
similarly angle covered by hour hand = (30/60)t = t/2
so for overtake 6t = 30 + t/2 or t = 60/11 min = 5 min and 5/11 min = 5 min and 300/11 sec = 5 min and 27.273 sec so clock loses 27.273 seconds
ANSWER:A
Question: A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
A.65 seconds
B.86 seconds
C.40 seconds
D.43 seconds
Answer: C.40 seconds
Explanation: Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (2/25) = 40 seconds
Answer: C
Question: Pooja is twice as efficient as Aarti and takes 90 days less than Aarti to complete the job. Find the time in which they can finish the job together.
A.30 days
B.45 days
C.60 days
D.90 days
Answer: C.60 days
Explanation: EXPLANATION:
Hint:
Assume that Pooja completes the job in 'x' days.
So, Aarti will take '2x' days to complete the same job.
As Pooja takes 90 days less than Aarti, we get
x = 2x – 90
By solving this equation, we get x = 90 .
Thus, 2x = 2 x 90 = 180
Part of job done by Pooja in 1 day = 1/ 90
Part of job done by Aarti in 1 day = 1/180
(Part of job done together in 1 day) = (Part of job done by Pooja in 1 day) + (Part of job done by Aarti in 1 day)
= (1/90) + (1/180)
= 3/180
=1/60
(1/60)th part of whole job will be completed by Pooja and Aarti together in one day.
Therefore, the whole job will be completed in 60 days together.
ANSWER IS C
Question: Haris can wash all the windows of his house in 10 hours. His wife Maggie can wash all the windows in 5 hours. How many hours will it take for both of them working together to wash all the windows?
A.2
B.3 1/3
C.4 1/4
D.5
Answer: B.3 1/3
Explanation: Work hrs=AB/(A+B)= 50/15 =3 1/3
Answer is B
Question: What is the smallest positive integer x, such that √392x is an integer?
A.2
B.4
C.7
D.8
Answer: A.2
Explanation: For a perfect square, the powers of prime factors should be even. 392 can be broken up as 2^3 * 7^2. You just need 2 to be multiplied to this number so that the number finally becomes 2^4 * 7^2 which is a perfect square.
Therefore x = 2.
Answer: A
Question: If the cost price of 110 chairs is equal to the selling price of 88 chairs, the gain percent is
A.25
B.30
C.35
D.40
Answer: A.25
Explanation: Let C.P. of each pen be Re. 1.
Then, C.P. of 88 chairs = Rs. 88; S.P. of 88 chairs = Rs. 110.
Gain % = 22/88 * 100 = 25%
Answer:A
Question: If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is ?
A.1/7
B.1/2
C.1/9
D.1/1
Answer: B.1/2
Explanation: The number of exhaustive outcomes is 36.
Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then
= 18/36 = 1/2
P(E) = 1 - 1/2
= 1/2.
Answer: B
Question: 75% of the guestrooms at the Stagecoach Inn have a queen-sized bed, and each of the remaining rooms has a king-sized bed. Of the non-smoking rooms, 60% have a queen-sized bed. If 24% of the rooms at the Stagecoach Inn are non-smoking rooms with king-sized beds, what percentage of the rooms permit smoking?
A.25%
B.40%
C.50%
D.55%
Answer: B.40%
Explanation: Let x be the number of non-smoking rooms.
Let N be the total number of rooms at the inn.
40% of non-smoking rooms have a king-sized bed.
0.4x = 0.24N
x = 0.6N
The percentage of rooms which permit smoking is 1 - 0.6 = 40%
The answer is B.
Question: Sum of the squares of three numbers is 225 and the sum of their products taken two at a time is 200. Find the sum?
A.20
B.22
C.25
D.26
Answer: C.25
Explanation: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 225 + 2* 200
a + b + c = √625 = 25
C
Question: What is the sum of all the numbers between 300 and 1000 which are divisible by 179?
A.2506
B.2578
C.2589
D.2530
Answer: A.2506
Explanation: 358/179 â€¦.. 895/179
179(2 + 3 + 4 + 5) => 2506
ANSWER A
Question: The average temperature of the town in the first four days of a month was 58 degrees. The average for the second, third, fourth and fifth days was 60 degrees. If the temperatures of the first and fifth days were in the ratio 7 : 8, then what is the temperature on the fifth day ?
A.33
B.64
C.38
D.37
Answer: B.64
Explanation: Sum of temperatures on 1st, 2nd, 3rd and 4th days = (58 * 4) = 232 degrees ... (1)
Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees ....(2)
Subtracting (1) From (2), we get :
Temp, on 5th day - Temp on 1st day = 8 degrees.
Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively.
Then, 8x - 7x = 8 or x = 8.
Temperature on the 5th day = 8x = 64 degrees.
Answer: B
Question: Find the odd man out. 241, 263, 248, 271, 255, 277, 262
A.277
B.271
C.263
D.241
Answer: B.271
Explanation: Explanation :
Alternatively 22 is added and 15 is subtracted from the terms. Hence, 271 is wrong
241
241 + 22 = 263
263 - 15 = 248
248 + 22 = 270
270 - 15 = 255
255 + 22 = 277
277 - 15 = 262. Answer : Option B
Question: A rectangular grassy plot 100 m. by 70 m has a gravel path 2.5 m wide all round it on the inside. Find the cost of gravelling the path at 90 paise per sq. metre.
A.Rs.700
B.Rs.708.50
C.Rs.732.50
D.Rs.742.50
Answer: D.Rs.742.50
Explanation: Explanation:
Area of the plot = (100 x 70) m2 = 7000 m2
Area of the plot excluding the path = [(100 - 5) * (70 - 5)] m2 = 6175 m2.
Area of the path = (7000 - 6175) m2 = 825 m2.
Cost of gravelling the path = Rs.825 * (90/100)= Rs.742.50
Answer: Option D
Question: A man buys an article for 13% less than its value and sells it for 13% more than its value. His gain or loss percent is:
A.no profit, no loss
B.20% profit
C.less than 25% profit
D.more than 25% profit
Answer: D.more than 25% profit
Explanation: Let the article be worth Rs. x.
C.P. 87% of Rs. x = Rs. 87x/100
S.P. = 113% of Rs. x = Rs. 113x/100
Gain = (113x/100 - 87x/100) = Rs. 13x/50
Gain % = 13x/50 * 100/87x * 100 = 29 77/87 % > 25%
ANSWER:D
Question: The length of the bridge, which a train 130 m long and traveling at 45 km/hr can cross in 30 sec is?
A.25/5
B.25/3
C.25/2
D.25/1
Answer: C.25/2
Explanation: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (130 + x)/30 = 25/2
x = 245 m.Answer:C
Question: From a group of 21 astronauts that includes 12 people with previous experience in space flight, a 3-person crew is to be selected so that exactly one person in the crew has previous experience in space flight. How many different crews of this type are possible?
A.432
B.94
C.864
D.1330
Answer: A.432
Explanation: COMB(ENN) where E=experienced and N=no previous experience
12*9*8/(2!). We divide by 2! because there are 2! ways to choose the astronauts without previous experience.
=12*9*4 = 48*9
Because 48*9 ends with a 2, look for the answer that ends with a 2. Only A suffices.
Question: A coin is tossed two times. What is the probability that there is at the least one tail?
A.3/4
B.31/37
C.31/18
D.31/10
Answer: A.3/4
Explanation: Let P(T) be the probability of getting least one tail when the coin is tossed two times.
= There is not even a single tail.
i.e. all the outcomes are heads.
= 1/4 ; P(T) = 1 - 1/4 = 3/4
Answer: A
Question: P and Q can complete a work in 20 days and 12 days respectively. P alone started the work and Q joined him after 4 days till the completion of the work. How long did the work last?
A.5
B.10
C.12
D.15
Answer: B.10
Explanation: Work done by P in 1 day = 1/20
Work done by Q in 1 day = 1/12
Work done by P in 4 days = 4 × (1/20) = 1/5
Remaining work = 1 – 1/5 = 4/5
Work done by P and Q in 1 day = 1/20 + 1/12 = 8/60 = 2/15
Number of days P and Q take to complete the remaining work = (4/5) / (2/15) = 6
Total days = 4 + 6 = 10
Answer is B.
Question: [(9/2 ÷ 1/2 × 9/2)]/[(9/2 × 1/2 ÷ 9/2)] = ?
A.71
B.61
C.51
D.81
Answer: D.81
Explanation: Explanation:
[(9/2 ÷ 1/2 × 9/2)]/[(9/2 × 1/2 ÷ 9/2)]
= [9/2 × 2/1 × 9/2]/[9/2 × 1/2 × 2/9]
= 81/2 / 1/2 = 81/2 x 2/1 = 81
Answer: Option D
Question: A fruit-salad mixture consists of apples, peaches, and grapes in the ratio 6:5:2, respectively, by weight. If 78 pounds of the mixture is prepared, the mixture includes how many more pounds of apples than grapes?
A.24
B.12
C.9
D.6
Answer: A.24
Explanation: We can first set up our ratio using variable multipliers. We are given that a fruit-salad mixture consists of apples, peaches, and grapes, in the ratio of 6:5:2, respectively, by weight. Thus, we can say:
apples : peaches : grapes = 6x : 5x : 2x
We are given that 39 pounds of the mixture is prepared so we can set up the following question and determine a value for x:
6x + 5x + 2x = 78
13x = 78
x = 6
Now we can determine the number of pounds of apples and of grapes.
pounds of grapes = (2)(6) = 12
pounds of apples = (6)(6) = 36
Thus we know that there are 36 -12 = 24 more pounds of apples than grapes.
Answer is A.
Question: A number when divided by a divisor leaves a remainder of 24.
When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor?
A.35
B.37
C.41
D.43
Answer: B.37
Explanation: Let the original number be 'a'
Let the divisor be 'd'
Let the quotient of the division of aa by dd be 'x'
Therefore, we can write the relation as a/d = x and the remainder is 24.
i.e., a=dx+24 When twice the original number is divided by d, 2a is divided by d.
We know that a=dx+24. Therefore, 2a = 2dx + 48
The problem states that (2dx+48)/d leaves a remainder of 11.
2dx2dx is perfectly divisible by d and will therefore, not leave a remainder.
The remainder of 11 was obtained by dividing 48 by d.
When 48 is divided by 37, the remainder that one will obtain is 11.
Hence, the divisor is 37.
B
Question: In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter’s age squared. How old is Janice's Daughter?
A.12
B.36
C.40
D.42
Answer: A.12
Explanation: Let Jane's age be J and daughters' age be D...
Given J + 3 = 3(D + 3 ) => J - 6 = 3D -> Eq1.
Given J-6 = (D-6)^2 --> Eq 2..
sub J-6 value in eq 2... 3D = D^2 - 12D + 36.
0 = D^2 - 15D + 36 => D = 12 or D = 3.
When D = 12 we get from eq 1... J+3 = 45 => J =42..
When D = 3 ..we get from eq 1.. J+3 = 18 => J = 15..
IMO option A is correct answer..
Question: The cost of 3 kg of sugar is $12. What will the cost of 8 kg of sugar be?
A.32
B.48
C.64
D.120
Answer: A.32
Explanation: 3 kg costs $12
1 kg costs $4
8 kg costs $32
The answer is A.
Question: A boat goes 8 km upstream in 24 minutes. The speed of stream is 4 km/hr. The speed of boat in still water is:
A.25 km/hr
B.26 km/hr
C.22 km/hr
D.24 km/hr
Answer: D.24 km/hr
Explanation: rate upstream =8/24*60=20kmph
speed of stream=4kmph
let speed of boat in still water=xkmph
speed upstream=x-4kmph
x-4=20
x=24kmph
ANSWER:D
Question: A person borrows Rs.5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 5% p.a for 2 years. Find his gain in the transaction per year.
A.50
B.150
C.225
D.112.5
Answer: A.50
Explanation: Explanation :
The person borrows Rs. 5000 for 2 years at 4% p.a. simple interest
Simple interest that he needs to pay = PRT/100=5000×4×2/100=400
He also lends it at 5% p.a for 2 years
Simple interest that he gets = PRT/100=5000×5×2/100=500
His overall gain in 2 years = Rs.500 - Rs.400 = Rs.100
His overall gain in 1 year = 100/2 = Rs.50
Answer : Option A
Question: A chair is bought for Rs.500/- and sold at a loss of 20% find its selling price
A.Rs.500/-
B.Rs.600/-
C.Rs.400/-
D.Rs.700/-
Answer: C.Rs.400/-
Explanation: Loss = 500*20/100 = 100
S.P = C.P - Loss
= 500- 100
=Rs.400/-
Answer :C
Question: In a group of 400 players some are outdoor players, some are indoor players and some plays both. 350 plays outdoors and 110 plays indoor. How many plays indoor as well as outdoor games.
A.70
B.60
C.90
D.100
Answer: B.60
Explanation: Consider total number of players n(O U I) = 400
Players who plays outdoors n(O) = 350
Players who plays indoors n(I) = 110
Players who plays both n(O âˆ© I) = ?
n(O U I) = n(O)+ n(I) - n(O âˆ© I)
400 = 350 + 110 - n(O âˆ© I)
n(O âˆ© I) = 460 - 400
n(O âˆ© I) = 60
SO People read both science fiction and literacy works are 60
ANSWER:B
Question: Let n~ be defined for all positive integers n as the remainder when (n - 1)! is divided by n.
What is the value of 30~ ?
A.1
B.0
C.2
D.8
Answer: B.0
Explanation: n~ = (n-1)!
so 30~ = (30-1)! = 29!
when 29!/30 we have 16*2 inside 29!
hence 30 gets cancelled and we get remainder as 0
B
Question: If x^2 − 2x − 15 = (x + r)( x + s) for all values of x, and if r and s are constants, then which of the following is a possible value of (r − s)^2?
A.8
B.2
C.64
D.− 3
Answer: C.64
Explanation: We know that given ax^2 + bx + c = 0, Sum of the roots = -b/a and product of the roots = c/a.
The roots here are -r and -s.
-r - s = -(-2)/1 = r + s = -2
(-r)*(-s) = -15/1 = rs
So one of r and s is -5 and the other is 3. So
(r - s)^2 could be 64.
Answer (C)
Question: in base 7, a number is written only using digits 0,1,2,3,4,5,6. the number 135 in base 7 is 1*72+3*7+5=75 in base 10. what is the sum of the base 7 numbers 1234 & 6543 in base 7?
A.11101
B.11110
C.10111
D.11011
Answer: B.11110
Explanation: 4+3=7 since base is 7 so it will become 0 giving 1 carry to next digits(so 4+7=0)
3+4 + 1 carry from above step= 1 and 1 carry to next digit
2+5 + 1 carry to next digit= 1 and 1 carry
1+6= 11
so ans=11110
ANSWER:B
Question: Notebooks are sold in packages of four or seven only. If Wilson bought 69 notebooks exactly, what could be the number of large packs Wilson bought?
A.3
B.4
C.7
D.8
Answer: C.7
Explanation: Let number of packs of four = f
let number of packs of seven = s
4f + 7s = 69
Now , we need to test for values of s .
Since sum 69 is odd and 4f will always be even , e can't be even .
Now , we can test for values e = 3 , 7 and 9
4*5 + 7*7 = 20 + 49 = 69
Answer C
Question: A and B start walking towards each other at 6pm at speed of 4kmph and 6kmph. They were initially 18km apart. At what time do they meet?
A.8pm
B.6pm
C.7pm
D.10pm
Answer: A.8pm
Explanation: Time of meeting = distance / relative speed = 18/6+3 = 18/9 = 2 hrs after 6pm = 8pm
Answer is A
Question: Which of the following number is divisible by 4 and 9?
A.2377
B.2736
C.2876
D.1988
Answer: B.2736
Explanation: Explanation:
For a number to be divisible by 4, the number formed by the last two digits of that number must be divisible by 4.
For a number to be divisible by 9, the sum of its digits must be divisible by 9.
Among the choices, choices (a) and (b) are divisible by 4 but of the first two choices, only choice (b) is divisible by 9.
Hence choice (b) is divisible by both 4 and 9.
Answer: B
Question: Find the perimeter and area of a square of side 13 cm.
A.121
B.144
C.169
D.196
Answer: C.169
Explanation: We know that the perimeter of square = 4 Ã— side
Side= 13 cm
Therefore, perimeter = 4 Ã— 13 cm = 52 cm
Now, area of the square = (side Ã— side) sq. units
= 13 Ã— 13 cmÂ²
= 169 cmÂ²
ANSWER : C
Question: Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 7 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B?
A.56%
B.80%
C.100%
D.120%
Answer: A.56%
Explanation: For A, r=8/2pi. Its capacity = (4pi)^2 * 7= 112pi
For B, r=10/pi. Its capacity = (5pi)^2 *8 = 200pi
A/B = 112pi/200pi = 0.56
A
Question: The sum of first nine prime numbers is?
A.12
B.100
C.24
D.28
Answer: B.100
Explanation: Required sum = (2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23) = 100.
Note: 1 is not a prime number.
Definition: A prime number (or a prime) is a natural number that has exactly two distinct natural number divisors: 1 and itself.
B
Question: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
A.30%
B.70%
C.100%
D.250%
Answer: B.70%
Explanation: Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.
New C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs. 420.
Profit = Rs. (420 - 125) = Rs. 295.
Required percentage=295/420x100%=1475/21%= 70%
Answer is B.
Question: How many words can be formed by using all letters of the word â€œBIHARâ€
A.320
B.200
C.420
D.120
Answer: D.120
Explanation: Sol. The word BIHAR contains 5 different letters.
Required number of words = 5p5 = 5! = (5x4x3x2x1) = 120
ANSWER D
Question: The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: EXPLANATION
Let the numbers 13a and 13b.
Then, 13a x 13b = 2028
ab = 12.
Now, the co-primes with product 12 are (1, 12) and (3, 4).
[Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]
So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).
Clearly, there are 2 such pairs.
Answer B
Question: K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ?
A.12 pm
B.22 pm
C.72 pm
D.92 pm
Answer: A.12 pm
Explanation: Explanation:
let 't' be the time after which they met since L starts.
Given K is 50% faster than L
50 t + 1.5*50(t-1) = 300
50 t +75 t = 300 + 75
t = 375 / 125 = 3 hrs past the time that L starts
So they meet at (9 + 3)hrs = 12:00 noon.
Answer: A
Question: A farmer built a fence around his square plot. He used 27 fence poles on each side of the square. How many poles did he need altogether ?
A.100
B.104
C.108
D.106
Answer: B.104
Explanation: Explanation:
Since each pole at the corner of the plot is common to its two sides, so we have :
Total number of poles needed = 27 x 4 - 4 = 108 - 4 = 104.
Answer: B
Question: The ratio of the earnings of P and Q is 9:10. If the earnings of P increases by one-fourth and the earnings of Q decreases by one-fourth, then find the new ratio of their earnings?
A.4/7
B.3 by 2
C.3/5
D.9/4
Answer: B.3 by 2
Explanation: Let the earnings of P and Q be 9x and 10x respectively.
New ratio = [9x + 1/4 (9x)]/[10x - 1/4 (10x)]
=> 9*(1 + 1/4)/10*(1 - 1/4)
=> 9/10 * (5/4)/(3/4) = 3/2
Answer: B
Question: A man decided to cover a distance of 80km in 8 hrs. He can walk at a speed of 6 km/hr and cycle at 8 km/hr successively. How long will he walk and how long will he cycle ?
A.26.6km,53.3km
B.27.6km,53.3km
C.26.6km,54.3km
D.26.6km,55.3km
Answer: A.26.6km,53.3km
Explanation: as speed in 80km/8hrs=10 km/hr
as ques solve through mixture and alligation method
6 km/hr and 8km/hr
10km/hr
10-8 10-6
2km/hr 4km/hr
so the ratio is 1:2
ahd we have to find the distance through walk and through cycle
1/3*80=26.6km
2/3*80=53.3km
ANSWER:A
Question: By selling 20 pens for a rupee a man loses 30%. How many for a rupee should he sell in order to gain 30%?
A.8.76
B.10.76
C.8.76
D.9.76
Answer: B.10.76
Explanation: 70% --- 20130% --- ?70/130 * 20 = 10.76Answer: B
Question: A mixture contains alcohol and water in the ratio 4 : 3. If 5 litres of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture
A.15 litres
B.10 litres
C.30 litres
D.22 litres
Answer: B.10 litres
Explanation: Let the quantity of alcohol and water be 4x litres and 3x litres respectively
4x/(3x+5)=4/5
20x=4(3x+5)
8x=20
x=2.5
Quantity of alcohol = (4 x 2.5) litres = 10 litres.
Answer is B.
Question: 3,6,9,12,15....
A.58
B.60
C.18
D.62
Answer: C.18
Explanation: 1*3=3
2*3=6
3*3=9
4*3=12
5*3=15
6*3=18
ANSWER:C
Question: A man spend 1/5 of his salary on food , 1/10 of his salary on house rent and 3/5 salary on clothes. he still has $18000 left with him. find salary..
A.$10800
B.$18000
C.$180000
D.$1800
Answer: C.$180000
Explanation: [1/(x1 / y1 + x2/y2 + x3/y3)] * Total amount= Balance amount
[1-(1/5 + 1/10 + 3/5)} * total salary= $18000, = [1-9/10] * Total salary = $18000, Total salary = $18000*10 = $180000, correct answer (C)
Question: For an agricultural experiment, 300 seeds were planted in one plot and 200 were planted in a second plot. If exactly 25 percent of the seeds in the first plot germinated and exactly 35 percent of the seeds in the second plot germinated, what percent of the total number of seeds germinated?
A.12%
B.26%
C.29%
D.30%
Answer: C.29%
Explanation: In the first plot 25% of 300 seeds germinated, so 0.25 x 300 = 75 seeds germinated.
In the second plot, 35% of 200 seeds germinated, so 0.35 x 200 = 70 seeds germinated.
Since 75 + 70 = 145 seeds germinated out of a total of 300 + 200 = 500 seeds, the percent of seeds that germinated is (145/500) x 100%, or 29%.
Answer: C.
Question: The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 50 percent of the pollutant?
A. $400,000
B. $100,000
C. $50,000
D. $10,000
Answer: A. $400,000
Explanation: To remove 90% of pollutant
C= 100,000(90)/(100-90) = 900,000
To remove 50% of pollutant
C' = 100,000(80)/(100-80) = 500,000
Difference = C - C' = 400,000
Answer - A
Question: Which of the following is not a leap year?
A.700
B.800
C.1000
D.1100
Answer: A.700
Explanation: The century divisible by 400 is a leap year.
The year 700 is not a leap year. ANSWER : A
Question: The average age of 8 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is
A.38
B.30
C.39
D.12
Answer: B.30
Explanation: Explanation:
Total age increased = (8 * 2) years = 16 years.
Sum of ages of two new men = (21 + 23 + 16) years = 60 years
Average age of two new men = (60/2) years = 30 years.
Answer: B
Question: The probability that A speaks truth is 3/5 and that of B speaking truth is 4/7. What is the probability that they agree in stating the same fact?
A.18/35
B.18/22
C.18/29
D.18/12
Answer: A.18/35
Explanation: If both agree stating the same fact, either both of them speak truth of both speak false.
Probability = 3/5 * 4/7 + 2/5 * 3/7
= 12/35 + 6/35
= 18/35
Answer:A
Question: The sum of two numbers is 20 and their product is 375. What will be the sum of their reciprocals?
A.1/40
B.4/75
C.75/4
D.75/8
Answer: B.4/75
Explanation: (1/a)+(1/b)=(a+b)/ab=20/375=4/75
ANSWER:B
Question: 31, 29, 24, 22, 17, ?
A.12
B.14
C.15
D.17
Answer: C.15
Explanation: C
15
This is a simple alternating subtraction series, with a pattern -2, -5, -2, -5 ....