RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A number when divided by 44, gives 400 as quotient and 0 as remainder. What will be the remainder when dividing the same number by 35
A.A)30
B.B)3
C.C)4
D.D)6
Answer: A.A)30
Explanation: Explanation:
P ÷ 44 = 400
=> P = 400 * 44 = 17600
P / 35 = 17600 / 35 = 502, remainder = 30
Answer: Option A
Question: Out of four numbers ,the average of first three is 16 and that of the last three is 15. If the last number is 18,the first number is :
A.22
B.21
C.77
D.99
Answer: B.21
Explanation: Explanation:
Let the numbers be a,b,c,d
Given, a + b + c = 48, b + c + d = 45
Now, d = 18
thus, b + c + 18 = 45 ⇒ b + c = 27
Putting the value of b + c in a + b + c = 48
a + 27 = 48 ⇒ a = 21
Answer: B
Question: A certain bus driver is paid a regular rate of $16 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $1340 in total compensation, how many total hours did he work that week?
A.76
B.60
C.65
D.48
Answer: C.65
Explanation: For 40 hrs = 40*16=640
Excess = 1340-640=700
For extra hours =.75(16)=12+16=28
Number of extra hrs =700/28=25
Total hrs =40+25=65
Answer C 65
Question: The average age of a committee of 8 members is 44 years. A member aged 56 years retired and his place was taken by another member aged 44 years . The average age of
present committee is;
A.39 years
B.38 years
C.42.5 years
D.35 years
Answer: C.42.5 years
Explanation: Total age of the committee = 44*8 = 352,
Total age when a member is retired
and a new one was joined = 352-56 +44, =340
Average age of present committee = 340/8 = 42.5.
ANSWER:C
Question: A typist uses a paper 12" by 5" length wise and leaves a margin of 1" at the top and the bottom and a margin of ½" on either side. What fractional part of the paper is available to him for typing ?
A.2⁄3
B.1⁄2
C.1⁄3
D.5⁄7
Answer: A.2⁄3
Explanation: Area of paper = 12 × 5 = 60 sq. inch
Area of typing part = (12 - 1 × 2) × (5 - 1⁄2 × 2)
= (12 – 2) × (5 – 1) = (10 × 4) sq. inch
∴ Required fraction = 40⁄60 = 2⁄3
Answer A
Question: A rectangular-shaped carpet remnant that measures x feet by y feet is priced at $60. What is the cost of the carpet, in dollars per square yard? (9 square feet = 1 square yard)
A.540/(xy)
B.540xy
C.xy/9
D.xy/60
Answer: A.540/(xy)
Explanation: xy sq ft = $60
1 sq ft = $60/xy
multiplying by 9 on both side
9 sq ft = $540/xy
or 1 sq yard = $540/xy
Hence A
Question: The average of seven numbers is 18. The average of first three numbers is 14 and the average of last three numbers is 19. What is the middle number?
A.23
B.27
C.28
D.29
Answer: B.27
Explanation: The total of seven numbers = 7X18 = 126
The total of first 3 and last 3 numbers is = 3 X 14+3 X 19 = 99
So, the middle number is (126 - 99 ) = 27
B
Question: what is the remainder when 789456123 is divided by 999
A.359
B.369
C.379
D.388
Answer: B.369
Explanation: 789456123 / 999
789456123 / 9*111
87717347 / 111 => rem = 41
we have cancelled it by 9
reqd remainder = 9*41 = 369
ANSWER:B
Question: A mixture of 150 liters of water and milk contains 20% milk. How much more milk should be added so that milk becomes 25% of the new mixture?
A.10
B.20
C.30
D.40
Answer: A.10
Explanation: A
10 liters
Number of liters of milk in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of milk added to the mixture to make milk 25% of the new mixture.
Total amount of milk becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters.
Question: 8 men, working 7 hours a day can complete a work in 18 days. How many hours a day must 12 men work to complete the same work in 12 days?
A.6
B.7
C.8
D.9
Answer: B.7
Explanation: The number of hours required to complete the work is 8*7*18 = 1008
12 × 12 × (x) = 1008
x = 7
The answer is B.
Question: The salary of a person was reduced by 20%. By what percent should his reduced salary be raised so as to bring it at par with his original salary?
A.50%
B.32%
C.25%
D.43%
Answer: C.25%
Explanation: Let the original salary be $100
New salary = $80
Increase on 80 = 20
increase on 100 = 20/80 *100 = 25%
Answer is C
Question: A, B, C, D and E are 5 consecutive points on a straight line. If BC = 2CD, DE = 8, AB = 5 and AC = 11, what is the length of AE?
A.18
B.20
C.22
D.24
Answer: C.22
Explanation: AC = 11 and AB = 5, so BC = 6.
BC = 2CD so CD = 3.
The length of AE is AB+BC+CD+DE = 5+6+3+8 = 22
The answer is C.
Question: The population of a town was 1,60,000 three years ago, If it increased by 3%, 2.5% and 5% respectively in the last three years, then the present population in
A.177369
B.177329
C.177629
D.177366
Answer: D.177366
Explanation: Explanation:
Present population = 160000 * (1 + 3/100)(1 + 5/200)(1 + 5/100)
= 177366.
Answer: D) 177366
Question: If n divided by 7 has a remainder of 2, what is the remainder when 6 times n is divided by 7?
A.1
B.2
C.3
D.5
Answer: D.5
Explanation: As per question => N=7P+2 for some integer p
hence 6N => 42Q + 12 => remainder =>12 for some integer Q
Alternatively => N=2 > 6N=> 12 =>12 divided by 7 will leave a remainder 5
hence D
Question: Peter's internet provider offers unlimited traffic which costs $0.5 per day charged off at 12 a.m. The service is discontinued when client's debt exceeds $5. If today in the morning Peter makes a payment of $7, for how many days, including today, will she be connected to the internet without any additional payments, given her initial balance was $0?
A. 15
B. 24
C. 25
D. 26
Answer: C. 25
Explanation: day 0- payment of $7 is made in the morning (after 12 am midnight)
day 1 onwards(after 12 am midnight) internet service will begin and will run for 7*2=14 days i.e. at the end of day 15 balance will be zero.
now Peter can still use the internet till her debt reaches $5 which means total of 5*2=10 days.
now the question states for how many days, including today, will she be connected to the internet without any additional paymentsi.e. we will have to include day0 also in our final answer. therefore total no. of days =1+14+10=25=C
Question: The probability that a number selected at random from the first 50 natural numbers is a composite number is ?
A.17/29
B.17/25
C.17/27
D.17/29
Answer: B.17/25
Explanation: The number of exhaustive events = ⁵⁰C₁ = 50.
We have 15 primes from 1 to 50.
Number of favourable cases are 34.
Required probability = 34/50 = 17/25
Answer: B
Question: Rs.880 is divided amongst A, B, C so that 4 times A's share, 5 times B's share and 10 times C's share are all equal. Find C's share?
A.177
B.150
C.817
D.160
Answer: D.160
Explanation: A+B+C = 8804A = 5B = 10C = xA:B:C = 1/4:1/5:1/10= 5:4:22/11 * 880= Rs.160Answer: D
Question: A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share?
A.Rs. 500
B.Rs. 1500
C.Rs. 2000
D.Rs. 2200
Answer: C.Rs. 2000
Explanation: Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x - 3x = 1000
x = 1000.
B's share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.
ANSWER : OPTION C
Question: There is an increase of 30% in the production of milk chocolates in Amul Dairy in one month. If now it is 3,900 milk chocolates per month, what was it one month ago?
A.10,000 chocolates
B.3000 chocolates
C.8000 chocolates
D.7000 chocolates
Answer: B.3000 chocolates
Explanation: Let one month ago, production be x chocolates.
Then, 130 % of x = 3900
⇒ x = 3900×100/130=3000 chocolates
Answer B
Question: 5 cars are to be parked in 5 parking slots. there are 3 red colour cars, 1 blue colour car and 1 green car. how many ways the car can be parked?
A.10 ways
B.15 ways
C.20 ways
D.25 ways
Answer: C.20 ways
Explanation: total ways to park the cars having same colour =5!
but according to question ,there are 3 red cars,so no. of ways for parking
3 red cars=3!
and both blue & green in 1 ways
so, 5!/1!*3!*1! = 20 ways
hence correct answer must be 20 ways.
ANSWER:C
Question: A cab driver 5days income was $45, $50, $60, $65 , $80. Then his average income is?
A.A)$58
B.B)$42
C.C)$60
D.D)$48
Answer: C.C)$60
Explanation: avg = sum of observations/number of observations
avg income=(45+50+60+65+80)/5 = 60
Answer is C
Question: A man can row downstream at 18 kmph and upstream at 6 kmph. Find the speed of the man in still water and the speed of stream respectively?
A.3
B.5
C.6
D.4
Answer: C.6
Explanation: Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.
Given x + y = 18 --- (1)
and x - y = 6 --- (2)
From (1) & (2) 2x = 24 => x = 12, y = 6. Answer: C
Question: Factor | Percent of Respondents |
User-friendly | 56% |
Fast response time | 48% |
Bargain prices | 42% |
The table gives three factors to be considered when choosing an Internet service provider and the percent of the 1,500 respondents to a survey who cited that factor as important. If 30 percent of the respondents cited both “user-friendly” and “fast response time,” what is the maximum possible number of respondents who cited “bargain prices,” but neither “user-friendly” nor “fast response time?”
A.312
B.336
C.360
D.390
Answer: D.390
Explanation: The way I looked at is is as follows:
UserFriendly(UF) + FastResponse (FR) = 30%
UF leftover = 56 - 30 = 26%
FR leftover = 48 - 30 = 18%
Sum these = 74% (ie. 74% were either UF+FR, UF, FR)
26% leftover is the maximum number for Bargain Price
26/100 * 1500 = 26 * 15 = 390 (D).
Question: The average price of an decoration piece increases over the years. If from 1990 to 1996, the price of the decoration piece increased by 13% and from 1996 to 2001 it increased by 20%, what is the price of the decoration piece in 2001 if the price in 1990 was $11,500?
A.$15,594.
B.$15,322.
C.$14,786.
D.$14,543.
Answer: A.$15,594.
Explanation: Whenever you have a question in which a value is increased by x% and then increased by y% then the overall effective increase = (x + y + xy/100 ) %
The effective increase = 13 + 20 + (13×20/100) = 35.6%
This is a little more 33% or 1/3 the original value.
THE QUICKEST WAY TO SOLVE THIS QUESTION IS TO USE APPROXIMATION.
11500 + 1/ 3 (12000) = 15500
Therefore option A is the answer.
I selected 12000 because it's value is a little more 11500 and it's easier to divide by 3 ( ie to calculate 1/3 or 33%).
Question: In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 14 percent of revenues. The profits in 2009 were what percent of the profits in 2008?
A.80%
B.112%
C.120%
D.124.2%
Answer: B.112%
Explanation: x = profits
r= revenue
x/r = 0,1
x= 10
r=100
2009:
r=80
x/80 = 0,14 = 14/100
x= 80*14/100
x= 11.2
11.2/10 = 1,12 = 112%, Answer B
Question: 3 man had collected 65 apples by visiting different tress. At tree 1 the collected some apples. At tree 2 they had 3 times the apple that they collected in tree 1. At tree 3 they had 5 times the no of apples when they reach there. At tree 4 they could collect only 5 apples. What was the no of apples they had in tree 1
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: At tree 1: x
At tree 2: 3x
At tree 3: 5(3x+x)
At tree 4: 20x + 5
20x+5=65
x=3
ANSWER:C
Question: What is the dividend from Tony's stock, if he invested Rs. 3200 at 85 to obtain an income of Rs. 250.
A.4
B.7.6
C.6.6
D.7.6
Answer: C.6.6
Explanation: By investing Rs.3200, income = Rs.250
By investing Rs.85, income = 250Ã—85/3200=6.6
ie, dividend = 6.6%
Answer is C.
Question: There is a road beside a river.two friends started from a place A,moved to a temple situated at another place B and then returned to A again.one of them moves on a cycle at a speed of 12 km/hr,while the other sails on a boat at a speed of 10 km/hr.if the river flows at the speed of 4 km/hr,which of the two friends will return to placeA first?
A.cyclist and boat sailor
B.boat sailor
C.none
D.cyclist
Answer: D.cyclist
Explanation: Clearly the cyclist moves both ways at a speed of 12 km/hr.
The boat sailor moves downstream @ (10+4)i.e.,14 km/hr and upstream @ (10-4)i.e., 6km/hr.
So,average speed of the boat sailor=(2*14*6/14+6)km/hr
=42/5 km/hr=8.4 km/hr.
since the average speed of the cyclist is greater ,he will return ta A first.
Answer is D.
Question: What is the difference between the largest number and the least number written with the digits 7, 3, 1, 4?
A.6084
B.3788
C.2077
D.2721
Answer: A.6084
Explanation: Explanation:
1347
7431
------------
6084
Answer:A
Question: How many 4-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed?
A.5040
B.40
C.400
D.5000
Answer: A.5040
Explanation: LOGARITHM => 10 diff letters
req no of words = No of arrangements of 10 letters taking 4 at a time
=> 10P4 = (10*9*8*7)
==> 5040
ANSWER A
Question: Bexy walks 5 miles from point A to point B in one hour, then bicycles back to point A along the same route at 15 miles per hour. Ben makes the same round trip, but does so at half of Bexy’s average speed. How many minutes does Ben spend on his round trip?
A.40
B.80
C.120
D.160
Answer: D.160
Explanation: Bexy walks 5 miles from point A to point B in one hour, then bicycles back to point A along the same route at 15 miles per hour. Ben makes the same round trip, but does so at half of Bexy’s average speed. How many minutes does Ben spend on his round trip?
Average speed = total distance/total time
We know the total distance is 5+5 (going from A to B then from B to A)
Time = distance/speed
Time = 5/15
Time = 1/3 hour
Average speed = (10)/(1hr + 1/3hr)
Average speed (Bexi) = 10 / 1.33
Therefore, if Ben's average speed is 1/2 of Bexi's then his speed = 10/2.66.
This means it took him 2.66 hours to cover the same 10 miles Bexi did. 2.66 hours = roughly 160 minutes.
Answer: D). 160
Question: The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y?
A.2010
B.2001
C.2012
D.2011
Answer: D.2011
Explanation: Suppose commodity X will cost 40 paise more than Y after z years.
Then, (4.20 + 0.40z) - (6.30 + 0.15z) = 0.40
0.25z = 0.40 + 2.10
z = 2.50/0.25
= 250/25
= 10.
Therefore, X will cost 40 paise more than Y 10 years after 2001 i.e., 2011.
Answer is D.
Question: A certain school implemented a reading program for its students, with the goal of getting each student to read 4 books per month year-round. If the school has c classes made up of s students in each class, how many books will the entire student body read in one year?
A.20cs
B.cs/2
C.48cs
D.(2cs)/12
Answer: C.48cs
Explanation: Ans: C
Solution: simple multiplication s students , c classes , 4 books/ month= 48 books a year
total number of books = 48cs
Question: Solve the equation: -3(-x + 5) + 20 = -10(x - 3) + 4
x=?
A.28/12
B.12/28
C.13/29
D.29/13
Answer: D.29/13
Explanation: Expand the expressions with brackets in the given equation
3x - 15 + 20 = -10x + 30 + 4
Group like terms
3x + 5 = -10x + 34
Solve
13 x = 29 , x = 29 / 13
correct answer D)29/13
Question: Avinash covers a distance of 8km in 50 minutes. If he covers 3km distance in 2/5th of time then, What speed should he maintain to cover the remaining distance in the remaining time?
A.15 Kmph
B.17 Kmph
C.18 Kmph
D.19 Kmph
Answer: A.15 Kmph
Explanation: Total distance = 8 Km
Total time = 50 Km
Time taken to cover the distence of 3 Km = 50*2/5 = 20 min = 1/3 hours
Remaining distance = 8 - 3 = 5 Km
Required speed = 5/1/3 = 15 Kmph
A)
Question: if set a ={2,3,5,7} and two numbers are selected at random from A(duplicates allowed), then what is the probability that the sum of the numbers is even?
A.1/8
B.13/16
C.5/12
D.5/8
Answer: D.5/8
Explanation: Sum of the two numbers would be even if
(1) Both digits are even.
(2) Both digit are odd.
(1) only one case is there: 22
(2) Following cases are there: 33, 35, 37 - 3 nos. Similarly 3 nos, with 5 (53, 55, 57) and 3 nos. with 7 (73, 75, 77)
Total 10 nos.
Total nos. that can be formed (repetition is allowed)
{1st no. can be chosen in 4 ways. Similarly 2nd no. can be chosen in 4 ways. Total 4*4 = 16 ways}
Prob : 10/16 = 5/8
D is the answer.
Question: A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
A.1000
B.2876
C.1977
D.2778
Answer: A.1000
Explanation: 90%
104%
--------
14% ---- 140
100% ---- ? => Rs.1000
Answer: A
Question: C & D started one company. They invest Rs. 100,000/- each. They deposit the money to Bank. Bank give 1% interest per month. After 2 years D left from company and asked C to return the money with interest. C says it will take time to release the FD and he assure D to give the money withinterest @0.5%. D Agreed this. What is the profit of C ?
A.A)48000
B.B)12000
C.C)3600
D.D)24000
Answer: C.C)3600
Explanation: Total Investment : 10000/-*2=20000/-
Interest rate @ 1%= 20000*1%*12*2= 4800/-
Total : 248000/-
Interest to B : 10000/-*0.5%*12*2 = 1200/-
Paid to B : 10000/- + 1200/- = 11200/-
profit of A : 3600/-
Answer is C
Question: Henry answered 4/5 of the questions he was given for homework in the first hour, 5/17 of the remaining questions in the second hour and the remaining x questions in the third hour where x is an integer. How many questions was Henry given for homework?
A.x
B.(85/12)*x
C.(85/24)*x
D.(85/36)*x
Answer: B.(85/12)*x
Explanation: Let Q be the number of homework questions.
Q = 4Q/5 + (5/17)(Q/5) + x
Q = 68Q/85 + 5Q/85 + x
12Q/85 = x
Q = (85/12)*x
The answer is B.
Question: All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 148 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?
A.1884 liters
B.1180 liters
C.1984 liters
D.1184 liters
Answer: D.1184 liters
Explanation: B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k - 5k = 3k.
Quantity of water in container C = 8k - 3k = 5k
Container: A B C
Quantity of water: 8k 3k 5k
It is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.
5k - 148 = 3k + 148 => 2k = 296 => k = 148
The initial quantity of water in A = 8k = 8 * 148 = 1184 liters.
Answer:D
Question: Students of three different classes appeared in common examination. Pass average of 10 students of first class was 70%, pass average of 15 students of second class was 60% and pass average of 25 students of third class was 80% then what will be the pass average of all students of three classes?
A.74%
B.75%
C.69%
D.72%
Answer: D.72%
Explanation: Solution:
Sum of pass students of first, second and third class,
= (70% of 10) + (60% of 15)+ (80% of 25)
= 7+9+20 = 36
Total students appeared,
= 10+15+25 = 50
Pass average,
= 36*100/50 = 72%.
Answer: Option D
Question: In traveling from a dormitory to a certain city, a student went 1/5 of the way by foot, 2/3 of the way by bus, and the remaining 10 kilometers by car. What is the distance, in kilometers, from the dormitory to the city?
A.30
B.45
C.62
D.90
Answer: C.62
Explanation: I believe there is a better way to do it.
Basically one of the options should satisfy the given criteria.
60 did
1/5 *60 =12
2/3*60=40
so total distance
52 + remaining 10 =62
Answer C
Question: The average age of four children in a family is 12 years. If the spacing between their ages is 4 years, the age of the youngest child is ?
A.6 years
B.7 years
C.8 years
D.9 years
Answer: A.6 years
Explanation: Answer
Let the age of youngest child be y.
so from question y + (y + 4) + (y + 8) + (y + 12) = 4 x 12
⇒ 4y + 24= 48
∴ y = 6 years
Correct Option: A
Question: Sum of the squares of three numbers is 267 and the sum of their products taken two at a time is 131. Find the sum?
A.20
B.25
C.26
D.23
Answer: D.23
Explanation: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 267 + 2* 131
a + b + c = √529 = 23
D
Question: A man can row his boat with the stream at 16 km/h and against the stream in 6 km/h. The man's rate is?
A.5 kmph
B.6 kmph
C.7 kmph
D.4 kmph
Answer: A.5 kmph
Explanation: Explanation:
DS = 16
US = 6
S = ?
S = (16 - 6)/2 =5 kmph
Answer: A
Question: In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 70 as quotient. What is the correct quotient ?
A.0
B.12
C.13
D.40
Answer: D.40
Explanation: 12*70=840
840%21=40
ANSWER:D
Question: Two buses each 3125 m long are running in opposite directions on parallel roads. Their speeds are 40 km/hr and 35 km/hr respectively. Find the time taken by the slower bus to pass the driver of the faster one?
A.50 sec
B.66 sec
C.48 sec
D.55 sec
Answer: A.50 sec
Explanation: Relative speed = 40 + 35 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 3125+3125 = 6250 m.
Required time = 6250 * 6/125 = 50 sec.
Answer: A
Question: From the integer n, if n*n*n is odd, then what is true from below options?
A.n is odd
B.n is odd and n*n is even
C.n is even
D.n*n is even
Answer: B.n is odd and n*n is even
Explanation: n is odd and n*n is even
Option B
Question: Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is ?
A.5/16
B.5/12
C.5/19
D.5/17
Answer: B.5/12
Explanation: Using question number 11 and 12, we get the probability as
1 - (1/36 + 5/9) = 5/12
Answer: B
Question: Find the HCF of 2.1, 1.05 and 0.63
A.0.44
B.0.64
C.0.21
D.0.24
Answer: C.0.21
Explanation: Explanation:
To solve this question quickly, first remove decimal by multiplying each term with 100,
Then terms become 210, 105, 63
Then HCF of above terms is 21,
So Answer is 0.21
Answer: Option C
Question: There are 4 red shoes & 6 green shoes . If two of red shoes are drawn what is the probability of getting red shoes
A.1/13
B.1/14
C.1/2
D.2/15
Answer: D.2/15
Explanation: taking 4 red shoe the probablity is 4C2
from 10 shoes probablity of taking 2 red shoe is 4C2/10C2=2/15
ANSWER:D
Question: The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 41 kg, then the weight of B is:
A.27 kg
B.20 kg
C.26 kg
D.31 kg
Answer: A.27 kg
Explanation: let d sum of a, b, c is 3*45=135
and sum of a and b s 2*40=80
sum of b and c is 2*41=82
hence 80+82-135=27
ans=27
ANSWER:A
Question: In the junior basketball league there are 18 teams, 2/3 of them are bad and ½ are rich. What can't be the number of teams that are rich and bad
A.4.
B.6.
C.7.
D.10.
Answer: D.10.
Explanation: total teams =18
bad teams=(2/3)*18=12
rich teams=9
so maximum value that the both rich and bad can take will be 9. so E= 10 can not be that value.
ans D.
Question: In a public show 75 % of the seats were filled. If there were 700 seats in the hall, how many seats were vacant?
A.100
B.110
C.120
D.175
Answer: D.175
Explanation: 75 % of 600
= 75/100 × 700
= 450
Therefore, the number of vacant seats = 700 - 450 = 175.
Answer:D
Question: The average of 9 observations was 9, that of the 1st of 5 being 10 and that of the last 5 being 8. What was the 5th observation?
A.9
B.11
C.13
D.15
Answer: A.9
Explanation: 1 to 9 = 9 * 9 = 81
1 to 5 = 5 * 10 = 50
5 to 9 = 5 * 8 = 40
5th = 50 + 40 = 90 – 81 = 9
A)
Question: Replace the ? by the correct Mathematics symbol to make the expression true
16 ? 10 ? 4 ? 5 = 45
A.16 ÷ 10 x 4 - 5 = 45
B.16 + 10 ÷ 4 - 5 = 45
C.16 x 10 + 4 - 5 = 45
D.16 x 10 ÷ 4 + 5 = 45
Answer: D.16 x 10 ÷ 4 + 5 = 45
Explanation: Answer : D
Question: A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
A.230
B.228
C.268
D.279
Answer: A.230
Explanation: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x
= 230.
Answer: A
Question: How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 30 m long and 16 1/2 m board?
A.99
B.18
C.26
D.17
Answer: A.99
Explanation: 30 * 33/2 = 5/2 * 2 * x => x
= 99
Answer: A