RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: It takes Joey the postman 1 hours to run a 2 mile long route every day. He delivers packages and then returns to the post office along the same path. If the average speed of the round trip is 5 mile/hour, what is the speed with which Joey returns?
A.10
B.12
C.13
D.14
Answer: A.10
Explanation: let his speed for one half of the journey be 2 miles an hour
let the other half be x miles an hour
now,
avg speed =5 mile an hour
2*2*x/2+x=5
4x=5x+10=>x=10
A
Question: Find the odd man out. 12, 24, 36, 48, 61, 72, 84
A.15
B.25
C.61
D.90
Answer: C.61
Explanation: Explanation :
All except 61 are multiples of 7
Answer : Option C
Question: In how many different ways can the letters of the word 'CORPORATION' be arranged so that the vowels always come together?
A.50400
B.5040
C.5004
D.7007
Answer: A.50400
Explanation: In the word 'CORPORATION', we treat the vowels OOAIO as one letter.
Thus, we have CRPRTN (OOAIO).
This has 7 (6 + 1) letters of which R occurs 2 times and the rest are different.
Number of ways arranging these letters =	7!/2!	= 2520.
Now, 5 vowels in which O occurs 3 times and the rest are different, can be arranged
in	5!/3!	= 20 ways.
Required number of ways = (2520 x 20) = 50400.
ANSWER A
Question: A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum mark is
A.600
B.500
C.400
D.300
Answer: B.500
Explanation: The student got 125 marks and still failed by 40 marks
= 125+40 = 165
therefore 33% of the total marks = 165
100% of the total = 165*100/33=55
max mark = 500
ANSWER B
Question: Thurston wrote an important seven-digit phone number on a napkin, but the last three numbers got smudged. Thurston remembers only that the last three digits contained at least one zero and at least one non-zero integer. If Thurston dials 30 phone numbers by using the readable digits followed by 30 different random combinations of three digits, each with at least one zero and at least one non-zero integer, what is the probability that he will dial the original number correctly?
A.1/9
B.10/243
C.1/27
D.10/271
Answer: A.1/9
Explanation: If the last three digits have 1 zero (XX0), the total # of numbers possible is 9*9*3 (multiply by 3 since XX0 can be arranged in 3 ways: XX0, X0X, or 0XX).
If the last three digits have 2 zeros (X00), the total # of numbers possible is 9*3 (multiply by 3 since X00 can be arranged in 3 ways: X00, 00X, or X0X).
P = 30/(9*9*3+9*3) = 1/9.
Answer:A.
Question: trees of heights 30 and 40 sepatated by a river. fish in the river is at equal dis from top of the trees where two birds are there.ratio of the distances from fish to the root of the trees?
A.4:3
B.1:2
C.2:1
D.3:4
Answer: A.4:3
Explanation: 40/30 is the ratio of distance from fish to root of trees
4:3
ANSWER:A
Question: Jim Pete’s only source of income comes from his job as a question writer. In this capacity, Jim earns a flat salary of $200 per week plus a fee of $9 for every question that he writes. Every year, Jim takes exactly two weeks of unpaid vacation to visit his uncle, a monk in Meivazhi Salai, and get inspired for the next year. If a regular year consists of 52 weeks and the number of questions that Jim wrote in each of the past 5 years was an odd number greater than 20, which of the following could be Jim’s median annual income over the past 5 years?
A.$22,474
B.$25,673
C.$27,318
D.$28,459
Answer: D.$28,459
Explanation: Okay u just need less than one min to answer this question. any odd number greater than 20 means that that last digit must be 1,3,5,7, or 9. 9$ per week for every question. So (odd)(odd) will give odd digit. A and C out. (50 weeks) (200) = 10,000. subtract this amount from option B, D and E and u will find that only option D is divisible by 9 (once 10,000 is subtracted from 28459) so its the right choice..D
Question: If T divided by B equals 9.16 what is a possible remainder?
A.8
B.9
C.2
D.6
Answer: A.8
Explanation: With the decimal being 16/100, the simplest form is 4/25. If the divisor is a multiple of 25, the remainder must be a multiple of 4. The only number that is so is 8. Answer A.
Question: A train 200 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
A.11
B.10
C.5
D.9
Answer: A.11
Explanation: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [200 * 3/55] sec = 11 sec
ANSWER:A
Question: If |4x+10| = 46, what is the sum of all the possible values of x?
A.2
B.-2
C.4
D.-5
Answer: D.-5
Explanation: There will be two cases
4x+10= 46 or 4x+10 = -46
=> x =9 or x= -14
sum of both the values will be -14 +9 = -5
Answer is D
Question: S is the infinite sequence S1 = 2, S2 = 22, S3 = 222,...Sk = Sk–1 + 2(10k–1). If p is the sum of the first 30 terms of S, what is the seventh digit of p, counting right to left from the units digit?
A.1
B.2
C.3
D.6
Answer: C.3
Explanation: C
Sum of unit digits of first 30 terms = 60
Sum of tens digits of first 30 terms = 58
Sum of thousands digits of first 30 terms = 56
and so on..
p1 = 0
p2 = (6+58) = 4
p3 = (6+56) = 2
p4 = (6+54) = 0
p5 = (6+52) = 8
p6 = (5+50) = 5
p7 = (5+48) = 3
ANSWER: C
Question: The ratio between the present ages of A and B is 6:3 respectively. The ratio between A's age 4 years ago and B's age 4 years hence is 1:1. What is the ratio between A's age 4 years hence and B's age 4 years ago?
A.5:4
B.3:0
C.5:1
D.3:2
Answer: C.5:1
Explanation: Let the present ages of A and B be 6x and 3x years respectively.
Then, (6x - 4)/(3x + 4) = 1/1
3x = 8 => x = 2.67
Required ratio = (5x + 4):(3x - 4) = 20:4 =5:1.Answer: C
Question: Of the seven-digit positive integers that have no digits equal to zero, how many have two digits that are equal to each other and the remaining digit different from the other two?
A.24
B.36
C.72
D.152409600
Answer: D.152409600
Explanation: Of the seven-digit positive integers that have no digits equal to zero, how many have two digits that are equal to each other and the remaining digit different from the other two?
A. 24
B. 36
C. 72
D. 144
E. 216
Choosing the digit for p - 9 ways;
Choosing the digit for q - 8 ways;
Choosing the digit for r - 7ways;
Choosing the digit for s - 6ways;
Choosing the digit for t - 5ways;
Choosing the digit for u- 4ways;
# of permutations of 3 digits in ppqrstu - 7!/2!
Total: 9*8*7*6*5*4*7!/2!=152409600.
Answer: D.
Question: 3 cooks have to make 80 burgers.They are known to make 20 pieces every minute working together.The 1st cook began workin alone and made 20 pieces having worked for sometime more than 3 mins.The remaining part of the work was done by second and 3rd cook working together.It took a total of 8 minutes to complete the 80 burgers.How many minutes would it take the 1st cook alone to cook 160 burgers?
A.16 minutes
B.24 mins
C.32 mins
D.40 mins
Answer: C.32 mins
Explanation: Denote by A, B, C the rates of the three cooks in units of burgers/minute.
A + B + C = 20.
Let t be the time in minutes it took the first cook A to make the 20 burgers. So, A*t = 20, and we know that t > 3.
We need to find 8t, as 160 burgers will be made by A in 8 times more than making 20 burgers.
We already know that 8t > 8*3 = 24, so we can eliminate answers (A) and (B).
In addition, (B + C)(8 - t) = 60, or (20 - A)(8 - t) = 60.
Since 20 - A < 20 and 8 - t < 5, looking for integer solutions, we find the only acceptable solution 20 - A = 15 and 8 - t = 4, so t = 4.
I am assuming integer numbers for the solutions based on the answer choices.
Anyway, testing the answer choices, only (C) is a solution.
Therefore, A will make 160 burgers in 8*4 = 32 minutes.
Answer C
Question: There are 20 students in a class. In how many different ways can a committee of 3 students be formed?
A.650
B.730
C.980
D.1140
Answer: D.1140
Explanation: 20C3 = 20*19*18 / 6 = 1140
The answer is D.
Question: The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 72. What is the difference between the two digits of that number?
A.4
B.5
C.6
D.8
Answer: D.8
Explanation: Sol.
Let the ten’s digit be x and unit’s digit be y,
Then, (10x + y) - (10y + x) = 72 ⇔ 9 (x - y) = 72
⇔ x - y = 8
Answer D
Question: In traveling from a dormitory to a certain city, a student went 1/5 of the way by foot, 2/3 of the way by bus, and the remaining 12 kilometers by car. What is the distance, in kilometers, from the dormitory to the city?
A.30
B.45
C.60
D.64
Answer: D.64
Explanation: I believe there is a better way to do it.
Basically one of the options should satisfy the given criteria.
60 did
1/5 *60 =12
2/3*60=40
so total distance
52 + remaining 12 =64
Answer D
Question: Mangala completes a piece of work in 12 days, Raju completes the same work in 36 days. If both of them work together, then the number of days required to complete the work is
A.6 days
B.7 days
C.8 days
D.9 days
Answer: D.9 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 12 Ã— 36/48 = 9 days.
D
Question: Two sets of 6 consecutive positive integers have exactly one integer in common. The sum of the integers in the set with greater numbers is how much greater than the sum of the integers in the other set?
A.14
B.42
C.28
D.12
Answer: B.42
Explanation: A=(1,2,3,4,5,6), sum of this=21
B=(6,7,8,9,10,11,12), sum of this=63,
The differenct between 63-21=42
Hence,42 is the answer i.e.B
Question: From a pack of 52 cards, if 2 cards are selected one after the other without replacement, then what is the probability that the 1st card is a queen and the 2nd card is a heart.
A.1/52
B.5/52
C.3/4
D.5/7
Answer: A.1/52
Explanation: Explanation :
Let the selected card be queen of heart so,we can select it in one way 1/52
Now the second card be a heart as there is no replacement no of ways 12/51
i.e 1/52*12/51t;(independent event);
Now let the card selected is not a queen of heart so we can select it in 3/52 ways
The probability of second card i.e heart is 13/51
i.e 3/52*13/51;(independent event)
Now both the independent events are combined
i.e (1/52*12/51) + ( 3/52*13/51)
= (12+39)/(52*51)
=1/52
Hence (A) is correct answer.
Answer : A
Question: If 12 men can reap 120 acres of land in 16 days, how many acres of land can 36 men reap in 32 days?
A.269
B.512
C.369
D.720
Answer: D.720
Explanation: 12 men 120 acres 16 days
36 men ? 32 days
120 * 36/12 * 32/16
120 * 3 * 2
120 * 6 = 720
Answer:D
Question: Limited resolution of early microscopes was one of the reasons of _________ understanding of cells.
A.discredited
B.increased
C.contradicted
D.restricted
Answer: D.restricted
Explanation: Explanation:
it should be restricted because of limited resolution
Answer:D
Question: A company spends an average of $500 for its 20 employees's salaries and an average of $100 for its 5 drivers' salaries. What is the average expenditure of the company?
A.$360
B.$290
C.$420
D.$600
Answer: C.$420
Explanation: Number of employees is 20
Their average salary is $500
Number of drivers is 5
Their average salary is $100
Total salary of the employees is 20*500=$10,000
Total salary of the drivers is 5*100=$500
Total expenditure for company is 10,000+500=$10,500
Average expenditure is 10,500/20+5=$420
Answer is C
Question: -69*39+450=?
A.2736
B.2309
C.-2801
D.-2241
Answer: D.-2241
Explanation: => -69*(40-1)+450;
=> -(69*40)+69+450;
=> -2760+519=-2241.
Correct Option: D
Question: A train of 25 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 2.5 km long?
A.4
B.3
C.5
D.7
Answer: A.4
Explanation: D = 25 * 60 + 2500 = 4000 m
T = 4000/60 * 18/5 = 240 sec = 4 mins
Answer: A
Question: Everyone shakes hands with everyone else in a room. Total number of handshakes is 55. Number of persons=?
A.14
B.12
C.11
D.15
Answer: C.11
Explanation: In a room of n people, the number of possible handshakes is C(n,2) or n(n-1)/2
So n(n-1)/2 = 55 OR n(n-1)=110 OR n=11
Answer is (C)
Question: Jasmine had this problem on her math test: y= (15x+75)-(8x+15). She came up with the answer y= 25x-36. Jasmine has gotten the wrong answer. Can you help Jasmine correctly solve the math problem for y if x=8?
A.y=256
B.y=96
C.y=116
D.y=10
Answer: C.y=116
Explanation: C
Question: A box contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the box, if at least one black ball is to be included in the draw?
A.32
B.48
C.64
D.96
Answer: C.64
Explanation: We may have(1 black and 2 non-black) or (2 black and 1 non-black) or (3 black).
Required number of ways	= (3C1 x 6C2) + (3C2 x 6C1) + (3C3)
= 3 x((6 x 5)/(2x1))	+((3 x 2)/(2x1))x 6+ 1
= (45 + 18 + 1)
= 64.
Option C
Question: In X game of billiards, X can give Y 10 points in 60 and he can give Z 30 points in 60. How many points can Y give Z in X game of 100?
A.30
B.20
C.25
D.40
Answer: D.40
Explanation: X scores 60 while Y score 50 and Z scores 30.
The number of points that Z scores when Y scores 100 = (100 * 30)/50 = 60.
In X game of 100 points, Y gives (100 - 60) = 40 points to C.
D
Question: Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in scheme B?
A.Rs. 6400
B.Rs. 6500
C.Rs. 7200
D.Rs. 7500
Answer: A.Rs. 6400
Explanation: Let the sum invested in scheme A be Rs. x and that in scheme B be Rs. (13900 - x). Then,
(x * 14 * 2)/100 + [(13900 - x) * 11 * 2]/100 = 3508
28x - 22x = 350800 - (13900 * 22)
6x = 45000 => x = 7500
So, sum invested in scheme B = (13900 - 7500) = Rs. 6400.
ANSWER:A
Question: 63 + 5 * 12 / (180/3) = ?
A.22
B.77
C.29
D.64
Answer: D.64
Explanation: 63 + 5 * 12 / (180/3) = 63 + 5 * 12 / (60)
= 63 + (5 * 12)/60 = 63 + 1 = 64.Answer:D
Question: A rectangular football field is fenced on all four sides. The length of the football field is twice the length of its breadth. The cost of fencing the field was $300. The football management has decided to change the dimensions of field by increasing the breadth by 5% of its original value and reducing the length by 20% of its original value and fence the field again.. What will be the cost of the new fencing?
A.$360
B.$265
C.$425
D.$405
Answer: B.$265
Explanation: Let's take x to be the breadth. Then the length of the football field is 2x.
The perimeter of the old football field is x + 2x + x + 2x = 6x.
Now, for the new football field:
The new breadth = 1.05 times old breadth = 1.05x
The new length is 0.8 times old length = (.8)2x = 1.6x
So the new perimeter is 1.6x + 1.6x + 1.05x + 1.05x =5.3x.
for old perimeter rate is $300
For new perimeter = (300 * 5.3)/6
= 265
Ans - B
Question: A watch was sold at a loss of 10%. If it was sold for Rs.210 more, there would have been a gain of 4%. What is the cost price?
A.s:1000
B.s:1500
C.s:1278
D.s:1028
Answer: B.s:1500
Explanation: 90%
104%
--------
14% ---- 210
100% ---- ? =>
Rs:1500
Answer: B
Question: I gain 70 paise on Rs.70.My gain percent is :
A.0.1%
B.1%
C.7%
D.10%
Answer: B.1%
Explanation: Solution
11.1
Gain% = (0.70/70x100)% = 1%.
Answer B
Question: Evaluate: 986 x 237 + 986 x 863
A.956000
B.996000
C.986000
D.976000
Answer: C.986000
Explanation: = 986 x 137 + 986 x 863
= 986 x (137 + 863)
= 986 x 1000 = 986000.
Answer is C.
Question: Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 462?
A.25.6%
B.21%
C.20%
D.19%
Answer: A.25.6%
Explanation: CP = Rs. 540, MP = 540 + 15% of 540 = Rs. 621
SP = Rs. 462, Discount = 621 - 462 = 159
Discount % = 159/621 * 100 = 25.6%
ANSWER:A
Question: Find the last digit of
1!+2!+3!+4!+...............100!
A.0
B.1
C.2
D.3
Answer: D.3
Explanation: 5! +6! .... = always unit digit o.
1!+2!+3!+4! = 33
so, 33 + *0 = *3
so the unit digit will be 3
ANSWER:D
Question: Seven friends are living in 7 different flats of an apartment. Each of them was allotted a parking slot to park their cars in the ground floor. But they used to park their cars randomly in any of the seven slots. In how many ways can they park their cars so that exactly five persons park their cars in the slots allotted to them?
A.14
B.21
C.35
D.42
Answer: B.21
Explanation: C57=21 : choosing which of the 7 persons will be on the slots allocates to them, the remaining 2 will be parked on each others slots.
Answer: B.
Question: Jim is twice as old as Stephanie, who, four years ago, was three times as old as Kate. If, five years from now, the sum R of their ages will be 51, how old is Stephanie ?
A.6
B.10
C.14
D.20
Answer: B.10
Explanation: 1) take C (14y.o.), so mean that S=14, J=28, their sum itself is 42+10 years from now is 52, it is over the 51,
so eliminate C,D,E
2) take B (10y.o.), R=meaning S=10,J=20, so 20+10+10=40 and for K=10-4/3=2+9=11, finally 40+11=51. It is correct
B
Question: One fourth of one third of two fifth of a number is 20. What will be40% of that number
A.240
B.150
C.180
D.200
Answer: A.240
Explanation: Explanation:
(1/4) * (1/3) * (2/5) * x = 20 then x = 20 * 30 = 600
40% of 600 = 240
Answer: Option A
Question: The area of a square garden is A square feet and the perimeter is p feet. If a=p+5, what is the perimeter of the garden, in feet?
A.28
B.20
C.40
D.56
Answer: B.20
Explanation: Perimeter of square = P
Side of square = P/4
Area of Square = (P^2)/16 =A
Given that A = P + 5
(P^2)/16 = P + 5
P^2 = 16P + 80
P^2 -16P -80 = 0
P^2 -20P + 4P -80 = 0
P(P-20)+4(P+20) = 0
(P-20)(P+4) = 0
P = 20 o r- 4
Discarding negative value , P = 20
Answer is B
Question: A boy has eight trousers and 10 shirts. In how many different ways can he select a trouser and a shirt?
A.80 ways
B.86 ways
C.88 ways
D.108 ways
Answer: A.80 ways
Explanation: The boy can select one trouser in eight ways.
The boy can select one shirt in 10 ways.
The number of ways in which he can select one trouser and one shirt is 8 * 10 = 80 ways.
Answer:A
Question: Cereal A is 10% sugar by weight, whereas healthier but less delicious Cereal B is 2% sugar by weight. To make a delicious and healthy mixture that is 5% sugar, what should be the ratio of Cereal A to Cereal B, by weight?
A. 3:5
B. 2:7
C. 1:6
D. 1:4
Answer: A. 3:5
Explanation: (10/100)A+(2/100)B = (5/100)(A+B)
5A =3B
=> A/B = 3/5
Answer is A.
Question: The average amount with a group of seven numbers is Rs. 30. If the newly joined member has Rs. 60 with him, what was the average amount with the group before his joining the group?
A.s. 25.6
B.s. 25
C.s. 16.6
D.s. 26
Answer: B.s. 25
Explanation: Total members in the group = 7
Average amount = Rs. 30
Total amount with them = 7 * 30 = Rs. 210
One number has Rs. 60. So, the amount with remaining 6 people = 210 - 60 = Rs. 150
The average amount with them = 150/6 = Rs. 25
ANSWER:B
Question: A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?
A.270.
B.480
C.920
D.280
Answer: A.270.
Explanation: Speed = 72 x 5/18 m/sec = 20 m/sec.
Time = 26 sec.
Let the length of the train be x metres.
Then, x + 250/26 = 20
x + 250 = 520
x = 270.
Answer: A
Question: In how many ways can the letters of the word BCGOI be rearranged such that the consonants always appear together?
A.12
B.36
C.48
D.60
Answer: B.36
Explanation: BCGOI
BCG will come together as a group which can be arranged in 3!=6ways.
BCG,O,I can be arranged in 3!=6 ways.
total possible arrangements = 6*6=36 ways
ANSWER:B
Question: The difference in compound interest earned on a deposit (compounded annually) in year 1 and year 2 is $ 40. Had the interest rate been three times its present value, the difference w would have been how much?
A.40/3
B.40
C.120
D.360
Answer: D.360
Explanation: CASE 1:
Deposit = $x;
Rate of increase = r.
Interest yearned in 1 year = xr. Deposit in 1 year = x + xr.
Interest yearned in 2 year = (x + xr)r.
The difference w= (x + xr)r - xr = xr^2 = 40.
CASE 2:
Deposit = $x;
Rate of increase = 3r.
Interest yearned in 1 year = x(3r). Deposit in 1 year = x + 3xr.
Interest yearned in 2 year = (x + 3xr)3r.
The difference = (x + 3xr)3r - 3xr = 9xr^2. Since from CASE 1 we know that xr^2 = 40, then 9xr^2 = 9*40 = 360.
Answer: D.
Question: In a function they are distributing noble prize. In how many ways can 4 prizes be distributed among 8 boys when a boy gets any no. of prizes?
A.4890
B.5095
C.4096
D.4089
Answer: C.4096
Explanation: Ans.(C)
Sol. In this case, repetitions are allowed, so all the four prizes can be given in 8 ways, i.e. (8 x 8 x 8 x 8) ways = 84 ways = 4096 ways Or nr ways = 84 ways = 4096 ways
Question: Sachin can cover a distance in 1hr 24 min by covering 2/3 of the distance at 4 kmph and the rest at 5 kmph. The total distance is?
A.6 km
B.8 km
C.9 km
D.11 km
Answer: A.6 km
Explanation: Let total distance =D=D
Distance travelled at 4 kmph speed =(23)D=(23)D
Distance travelled at 5 kmph speed =(1−23)D=(13)D=(1−23)D=(13)D
Total time =1 hr 24 min = (60+24) min =8460=8460 hr =2115=2115 hr
We know,
Time=DistanceSpeedTime=DistanceSpeed
Total time
2115=2/34D+1/35D2115=2/34D+1/35D
2115=2D12+D152115=2D12+D15
84=14D84=14D
D=6 km
Option A is correct
Question: How many minutes does Aditya take to cover a distance of 400 m, if he runs at a speed of 20 km/hr?
A.1 min
B.1 (1/5) min
C.2 min
D.3 min
Answer: B.1 (1/5) min
Explanation: Adityaâ€™s speed = 20 km/hr = {20 *5/18}min=50/9 m/s
Time taken to cover 400 m={ 400*9/50} sec= 72 sec=1 (1/5) min
ANSWER B
Question: A grocer stacked oranges in a pile. The bottom layer was rectangular with 4 rows of 6 oranges each. In the second layer from the bottom, each orange rested on 4 oranges from the bottom layer, and in the third layer, each orange rested on 4 oranges from the second layer. Which of the following is the maximum number of oranges that could have been in the third layer?
A. 3
B. 5
C. 6
D. 8
Answer: D. 8
Explanation: Bottom Layer = 6 x 4 = 24
IInd Layer = (6-1) x (4-1) = 15
IIIrd Layer = (5-1) x (3-1) = 8
Answer = 8 = D
Question: If shares of two persons in profits are Rs.700 and Rs. 300 then ratio of their capitals is
A.3:4
B.2:3
C.7:3
D.1:3
Answer: C.7:3
Explanation: total profit =1000
ratio=700/300
=7:3
ANSWER:C
Question: A rectangular tank measuring 5 m × 4.5 m × 2.1 m is dug in the centre of the field measuring 13.5 m × 2.5. The earth dug out is spread evenly over the remaining portion of a field. How much is the level of the field raised ?
A.4.0 m
B.4.1 m
C.4.2 m
D.4.3 m
Answer: C.4.2 m
Explanation: Area of the field = 13.5 × 2.5 = 33.75 m2
Area covered by the rectangular tank
= 5 × 4.5 = 22.50 m2
Area of the field on which the earth dug out is to be spread = 33.75 – 22.50 = 11.25 m2
Let the required height be h.
Then, 11.25 × h = 5 × 4.5 × 2.1
or h = 4.2 m
Answer C
Question: A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.2662 in 3 years. Find the rate percent?
A.17%
B.10%
C.20%
D.18%
Answer: B.10%
Explanation: 2420 --- 242
100 --- ? => 10%
Answer: B
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:
A.8 years
B.14 years
C.4 years
D.2 years
Answer: B.14 years
Explanation: Explanation:
Let the son's present age be x years. Then, (38 - x) = x
2x = 38.
x = 19.
Son's age 5 years back (19 - 5) = 14 years.
Answer: B
Question: A shopkeeper buys mangoes at the rate of 5 a rupee and sells them at 4 a rupee. Find his net profit or loss percent?
A.33 1/8 %
B.33 7/3 %
C.33 1/3 %
D.25 %
Answer: D.25 %
Explanation: The total number of mangoes bought by the shopkeeper be 20.
If he buys 5 a rupee, his CP = 4
He selling at 4 a rupee, his SP = 5
Profit = SP - CP = 5 - 4 = 1
Profit Percent = 1/4 * 100 = 25 %
Answer: D
Question: From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?
A.756
B.700
C.650
D.640
Answer: A.756
Explanation: We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).
Required number of ways	= (7C3 x 6C2) + (7C4 x 6C1) + (7C5)
= (525 + 210 + 21) = 756
ANSWER A