RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If the operation @ is defined for all a and b by the equation a@b =(a^b)/2,then (3@2)=?
A.4
B.2
C.9/2
D.-9/2
Answer: C.9/2
Explanation: work within the parenthesis first so solve (3@2) first
(3@2)=(3^2)/2=9/2
so 9/2 is the answer....this question is merely testing order of operations
remember PEMDAS
Answer:C
Question: The length of the bridge, which a train 180 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
A.876 m
B.157 m
C.195 m
D.156 m
Answer: C.195 m
Explanation: Speed = [45 X 5/18] m/sec
= [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (180 + x)/30 = 25/2
=> 2(180 + x) = 750 => x
= 195 m.
Answer: C
Question: An alchemist discovered that the formula expressing the correct proportions needed to turn ordinary metal into gold is G = 3/2M + 25, where G is the number of gold bars and M is the number of metal bars. If a metal bar weighs twice as much as a gold bar, how many metal bars will yield an equal weight of gold?
A.a.	A - 10
B.b.	B - 15
C.c.	C – 22.5
D.d.	D – 30
Answer: A.a.	A - 10
Explanation: A --- 30/2 + 15 = 40 --- wrong
B --- 45/2 + 15 = not an integer --- wrong
C --- 22.5(3/2) + 15 = not an integer --- wrong
D --- 90/2+15 = 70 --- CORRECT
This is one of those problems that will probably be easiest to solve by plugging in numbers. The algebra is do-able, but it's not worth the effort (in my opinion). I was able to solve it in under 30 seconds total with this method.
A
Question: How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.176 sec
B.30 sec
C.766 sec
D.165 sec
Answer: B.30 sec
Explanation: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec.
Answer:B
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required ?
A.88 feet
B.86 feet
C.84 feet
D.82 feet
Answer: A.88 feet
Explanation: Explanation:
We are given with length and area, so we can find the breadth.
as Length * Breadth = Area
=> 20 * Breadth = 680
=> Breadth = 34 feet
Area to be fenced = 2B + L = 2*34 + 20
= 88 feet
Option A
Question: In a dance competition the points in each round for the first,second,third and fourth position were 1000,500,200,100 . No other points were given. Reney participated in several rounds in the competition and the product of her score was 100000. In How many rounds did she participate?
A.4
B.2
C.5
D.Cannot be determined
Answer: D.Cannot be determined
Explanation: Correct answer is D because we are given that there won't be any points awarded for rounds other than 1st four position.
Thus, it may happen that she played 50 rounds out of only 7 rounds were there in which she was awarded some points.
Question: What is the area of square field whose side of length 8 m?
A.225
B.64
C.772
D.882
Answer: B.64
Explanation: 8 * 8
= 64 sq m
Answer:B
Question: What distance will be covered by a bus moving at 54 kmph in 30 seconds?
A.287
B.900
C.289
D.276
Answer: B.900
Explanation: 54 kmph = 54 * 5/18
= 30 mps
D = Speed * time = 30 * 30
= 900 m.
Answer:B
Question: A man can row downstream at 18 kmph and upstream at 10 kmph. Find the speed of the man in still water and the speed of stream respectively?
A.8
B.9
C.6
D.4
Answer: D.4
Explanation: Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.
Given x + y = 18 --- (1)
and x - y = 10 --- (2)
From (1) & (2) 2x = 28 => x = 14, y = 4.
Answer:D
Question: x, y and z are consecutive positive integers such that x < y < z; which of the following must be true?
1. xyz is divisible by 8
2. (z-x)(y-x+1) = 4
3. xy is odd
A.I and II
B.II only
C.III only
D.I and II only
Answer: A.I and II
Explanation: Since x, y and z are consecutive integers such that x < y < z, we can say x = y-1 and Z = y+1
Statement 1 would be true as at least one of the three numbers is divisible by 2 and one by 4 so xyz would be divisible by 8.
Statement 2 can be simplified if we write everything in terms of y as ((y+1)-(y-1))*(y-(y-1)+1) = 2*2 = 4 So, always true
Statement 3 talks about xy Since x and y are consecutive integers one of them is odd and other is even so product would always be even and hence not true.
So, I and II are always true and hence answer
A
Question: When a certain number X is divided by 143, the remainder is 45. Which of the following numbers, if added to X, would result in a number divisible by 19?
A.7
B.21
C.13
D.47
Answer: C.13
Explanation: Số thẻ number given is N = 143Q + 45
If this number is divided by 13, the remainder would be R[(143Q + 45)/13]
Since 143 is divisible by 13 , the product 143Q gives no remainder
This means the remainder of 45/13 should be the remainder of the entire number N
which is 6
To make it divisible by 13 , the smallest number that can be added = 19 - 6 =13
Correct Option : C
Question: (3164 + 6160) / 28
A.380
B.350
C.333
D.310
Answer: C.333
Explanation: Explanation:
As per BODMAS rule, first we will solve the equation in bracket then we will go for division
= (9324)/28 = 333
Option C
Question: There are 193 items that are members of set U. Of these items, 47 are members of set B, 59 are not members of either of set A or set B, and 23 are members of both sets A and B. How many of the members of set U are members of set A ?
A.72
B.85
C.94
D.106
Answer: D.106
Explanation: You had the answer almost right. The x = 83 refers to ONLY set A.
However what's being asked is how many members are part of set A. This will include:
1. Only Set A
2. Set A and Set B
So the answer is Set A = 85 + Set AB = 83+23 = 106
D
Question: A batsman in his 12th innings makes a score of 75 and thereby increases his average by 1 runs. What is his average after the 12th innings if he had never been ‘not out’?
A.42
B.43
C.44
D.64
Answer: D.64
Explanation: Let ‘x’ be the average score after 12 th innings
⇒ 12x = 11 × (x – 1) + 75
∴ x = 64
Answer D
Question: One morning after sunrise, Suresh was standing facing a pole. The shadow of the pole fell exactly to his right. To which direction was he facing?
A.East
B.West
C.South
D.North
Answer: C.South
Explanation: Explanation:
Sun rises in the east in the morning. Since the shadow of Suresh falls to his right. So he is facing South.
Answer: C) South
Question: A certain drink of type A is prepared by mixing 4 parts milk with 3 parts fruit juice. Another drink of type B is prepared by mixing 4 parts of fruit juice and 3 parts of milk. How many liters of fruit juice must be added to 105 liters of drink A to convert it to drink B?
A.14
B.21
C.28
D.35
Answer: D.35
Explanation: In 105 liters of drink A, there are 60 liters of milk and 45 liters of juice.
With 60 liters of milk, we need a total of 80 liters of juice to make drink B.
We need to add 35 liters of juice.
The answer is D.
Question: Given positive even integer x, which of the following CAN NOT be evenly divisible by x?
A.x + 1
B.x + 2
C.2x + 4
D.3x − 2
Answer: A.x + 1
Explanation: This can be easily solved by substituting values:
Assume x to be 2
A. x + 1: 3 is not evenly divisible by 2
B. x + 2: 4 is evenly divisible by 2
C. 2x + 4: 8 is evenly divisible by 2
D. 3x − 2: 4 is evenly divisible by 2
E. 7x: 14 is evenly divisible by 2
Option A
Question: The avg weight of A,B & C is 84 kg. If D joins the group, the avg weight of the group becomes 80 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 79 kg. What is the weight of A?
A.56
B.65
C.75
D.89
Answer: C.75
Explanation: A + B + C = 3 *84 = 252
A + B + C + D = 4 * 80 = 320 ---- (i)
So, D = 68& E = 68 + 3 = 71
B + C + D +E = 79 * 4 = 316 --- (ii)
From Eq. (i) & (ii)
A-E = 320 – 316 = 4
A = E +4 = 71 + 4 = 75
C
Question: A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:
A.4 days
B.6 days
C.8 days
D.10 days
Answer: B.6 days
Explanation: Suppose A, B and C take x,x/2 and x/3	days respectively to finish the work.
Then,	1/x+2/x+3/x=1/2
6/x = 1/2
x = 12.
So, B takes (12/2) = 6 days to finish the work.
answer :B
Question: My grandson is about as many days as my son in weeks, and my grandson is as many months as I am in years. My grandson, my son and I together are 150 years. Can you tell my son age in years?
A.63 years
B.60 years
C.50 years
D.53 years
Answer: D.53 years
Explanation: Let m be my age in years. If s is my son's age in years, then my son is 52s weeks old. If g is my grandson's age in years, then my grandson is 365g days old. Thus,365g = 52s.Since my grandson is 12g months old,12g = m.Since my grandson, my son and I together are 150 years,g + s + m = 100.The above system of 3 equations in 3 unknowns (g, s and m) can be solved as follows:52s / 365 + s + 12 x (52s / 365) = 150 or52s + 365s + 365 x (624s / 365) = 365 x 150 ors = 54,750 / 1,041 = 53 yearsAnswer = D
Question: A boy is travelling from his home to school at 5km/hr and reached 5min late. Next day he travelled at 10km/hr and reached 10min early. Distance between home and school?
A.2.5km
B.3km
C.4km
D.5.6km
Answer: A.2.5km
Explanation: Let the distance be x
T1 = x/5 hr
T2 = x/10hr
Difference in time = 5+10 = 15 =1/4hr
x/5-x/10 = 1/4
x/10 = 1/4
x = 2.5 km
Answer is A
Question: If the average of 16x and 8y is greater than 80, and x is twice y, what is the least integer value of x ?
A.8
B.9
C.10
D.11
Answer: A.8
Explanation: Substitution can be used in the following way:
Always start with the equation: x = 2y. It is more straight forward to manage as compared to the inequality.
Substitute y = x/2, not the other way because you need to find the minimum value of x. So you can get rid of y.
Now go on to the inequality. So 8y = 8x/2 = 4x
Now average of 16x and 4x is greater than 80. Average of 16x and 4x is 10x. So,
10x > 80
x > 8
Answer : A
Question: A circular path of 13 m radius has marginal walk 2 m wide all round it. Find the cost of leveling the walk at 25p per m2?
A.22
B.77
C.44
D.88
Answer: C.44
Explanation: π (152 - 132) = 176
176 * 1/4 = Rs.44
Answer: C
Question: A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.340 less than the sum lent. What was the sum lent?
A.Rs. 500
B.Rs 569
C.Rs478
D.Rs369
Answer: A.Rs. 500
Explanation: Explanation:
P - 340 = (P*4*8)/100
P =Rs. 500
Answer: A
Question: Each shelf of a bookcase contained 12 books. If the librarian took out 21 books and rearranged the remaining books so that all shelves but the last one contained 8 books and that last shelf contained 15 books, how many shelves does the bookcase have?
A.5
B.6
C.7
D.8
Answer: C.7
Explanation: Let x be the number of shelves.
12x - 21 = 8(x-1) + 15
4x = 28
x= 7
The answer is C.
Question: The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is
A.35.2
B.36.1
C.36.2
D.36.5
Answer: D.36.5
Explanation: Solution
Correct sum	= (36x50+48-23)
= 1825.
∴ Correct mean	= 1825 / 50
= 36.5.
Answer D
Question: A trade analyst announced 10% reduction in the unit price of bike. As a result, the sales volume went up by 10%. What was the net effect on the sales revenue?
A.no change
B.decreases by 1%
C.increases by 1%
D.increases by 10%
Answer: B.decreases by 1%
Explanation: Explanation :
Reduction of price = (100 -10)% = 90% = 0.9
Increase of sale = (100+10)% = 110% = 1.1
Total effect = 0.9 X 1.1 = 99%, Decreases by 1%
Answer : B
Question: Tough and Tricky questions: Combinations.
Two contestants representing four different countries advance to the finals of a fencing championship. Assuming all competitors have an equal chance of winning, how many possibilities are there with respect to how a first-place and second-place medal can be awarded?
A.6
B.7
C.12
D.16
Answer: A.6
Explanation: Number of ways First-place medal can be awarded to four contestants = 2
Number of ways Second-place medal can be awarded to contestants after awarding First-place medal =3
Therefore number of possibilities = 2 *3 =6
Answer:A
Question: The W train leaves station A moving at a constant speed, and passes by stations B and C, in this order. It takes the W train 7 hours to reach station B, and 5 additional hours to reach station C. The distance between stations A and B is m kilometers longer than the distance between stations B and C. What is the distance between stations A and C in terms of m?
A.1.8m
B.6m
C.7m
D.9m
Answer: B.6m
Explanation: The reason it is failing for you is that you chose incorrect numbers. If the question says it W took 7 hrs to reach from A to B and 5 hrs to reach from B to C at a constant speed. It shows that distance AB and BC should be in ratio of 7/5.
If you take such numbers you can solve problem.
AB = 7, BC=5
Therefore
AB-BC = 2
But from question, AB-BC =m
=> m=2
Now total distance = AB+BC= 12
Substitute 12 to get answer in terms of m
Total distance =12 =6m
Ans B
Question: Given the positive integer x, which of the following must be divisible by 3?
A.x(x^2−2)
B.(x−1)*x*(x+1)
C.x(x+2)^3
D.x^2*(x−5)
Answer: B.(x−1)*x*(x+1)
Explanation: option B) (x−1)*x*(x+1) which represents the product of three consecutive integers, which will always be divisible by 3. hence answer should be B
Question: Which of the following is a prime number ?
A.9
B.8
C.4
D.2
Answer: D.2
Explanation: Explanation :
2 is a prime number
A prime number is a natural number greater than 1 which has no positive divisors
other than 1 and itself.
Hence the primer numbers are 2,3,5,7,11,13,17,... Answer : Option D
Question: The average weight of 29 students is 28 kg. By the admission of a new student, the average weight is reduced to 27.5 kg. The weight of the new student is
A.22 kg
B.21.6 kg
C.22.4 kg
D.13 kg
Answer: D.13 kg
Explanation: Exp . The total weight of 29 students = 29* 28
The total weight of 30 students = 30* 27.5
Weight of the new student = ( 30*27.5 – 29*28)
= 825 - 812 = 13
Answer:D
Question: How many bricks, each measuring 25 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm?
A.5600
B.6000
C.6400
D.7200
Answer: C.6400
Explanation: Solution
Number of bricks = Volume of the wall/Volume of 1 brick
=(800x600x22.5 /25x11.25x6)
= 6400.
Answer C
Question: Ayesha's father was 42 years of age when she was born while her mother was 30 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
A.12 years
B.14 years
C.16 years
D.17 years
Answer: C.16 years
Explanation: Explanation:
Mother's age when Ayesha's brother was born = 30 years.
Father's age when Ayesha's brother was born = (42 + 4) = 46 years.
Required difference = (46 - 30) = 16 years.
Answer: Option C
Question: If a trader sold two cars each at Rs. 325475 and gains 13% on the first and loses 13% on the second, then his profit or loss percent on the whole is?
A.1.69%
B.1.74%
C.1.84%
D.1.47%
Answer: A.1.69%
Explanation: SP of each car is Rs. 325475, he gains 13% on first car and losses 13% on second car.
In this case, there will be loss and percentage of loss is given by
= [(profit%)(loss%)]/100
= (13)(13)/100 % = 1.69%
Answer:A
Question: The average weight of 48 students in a class is 52 kg. 5 of them whose average weight is 48 kg leave the class and other 5 students whose average weight is 54 kg join the class. What is the new average weight (in kg) of the class ?
A.51 1⁄3
B.52 5/8
C.52 1⁄8
D.43.42
Answer: B.52 5/8
Explanation: Total weight of 48 students
= 48 × 52 = 2496 kg
Total weight of 5 students who leave
= 5 × 48 = 240 kg
Total weight of 5 students who join
= 5 × 54 = 270 kg
Therefore, new total weight of 48 students
= 2496 – 240 + 270 = 2526
⇒ New average weight = 2526⁄48 = 52 5/8 kg
Answer B
Question: Mike took 5 mock tests before appearing for the GMAT. In each mock test he scored 8 points more than the previous mock test. If he scored 760 on the GMAT and his average score for the mocks and the GMAT was 726.67, what was the difference in the score of his last mock and his GMAT score?
A.24
B.30
C.40
D.50
Answer: A.24
Explanation: One way to do this would be weighted average method..
1) let the average of 5 mocks be x...
so take it as a mix of5 quantitites of xand1 quantity of 760resulting in an average of 726.67...
By alligation/weighted average..
the difference in 760 and 726.67 is 5/6 of difference of 760 and x..
760-726.67 = 5/6 * (760-x)
760-x= 33.33*6/5=40...
so x = 720..
the last of mock test will be 720+8+8=736...
so ans = 760-736=24
A
Question: If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
A.120 cm2
B.187 cm2
C.178 cm2
D.189 cm2
Answer: A.120 cm2
Explanation: The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle
= 1/2 * 24 * 10
= 120 cm2
Answer: A
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when a boy gets any no. of prizes?
A.58
B.60
C.64 ways
D.68
Answer: C.64 ways
Explanation: Ans.(C)
Sol. In this case, repetitions are allowed, so all the three prizes can be given in 4 ways, i.e. (4 x 4 x 4) ways = 43 ways = 64 ways Or nr ways = 43 ways = 64 ways
Question: The average time of Izzy's past 3 100-meter sprints is 15 seconds. If the average falls 1 second after Izzy finishes another sprint, how many seconds did it take Izzy to run the most recent sprint?
A.16
B.11
C.15
D.14
Answer: B.11
Explanation: Total time to run 3 sprints = 3*15 = 45
Total time to run 4 sprints = 4*14 = 56
Time to run most recent sprint = 56-45 = 11 seconds
Answer is B
Question: From a Group of 10 People, Including George and Nina, 3 people are to be selected at random to work on a certain project. What is the probability that 3 people selected will include George but not Nina
A.5/56
B.9/56
C.28/120
D.21/56
Answer: C.28/120
Explanation: Number of ways of selecting 3 people out of 10 people = 10C3
In the three members George will always be there in the team. At this step we have vacancy for 2 more members and 9 members are available. Lina cannot be there in the team. So 2 members have to be selected and the number of available members = 9 - Nina = 8
Number of ways to form a 3 member team that includes George and excludes Nina = 8C2
Probability = 8C2/10C3 = 28/120
Answer: C
Question: What would be the missing number in the series: 1, 20, 266, 675,?
A.76
B.78
C.80
D.82
Answer: B.78
Explanation: 1,20,x,266,675
> 20-1,x-20,266-x,675-266.
>again doing the same upto
>325-3x, -143+3x.
>we get 6x-486 equate it with zero.
> 6x-486 = 0
>x = 78.
ANSWER:B
Question: What is difference between biggest and smallest fraction among 2/3, 3/4, 4/5 and 5/7
A.2/15
B.3/5
C.1/6
D.1/7
Answer: A.2/15
Explanation: Explanation:
2/3 = .66, 3/4 = .75, 4/5 = .8 and 5/7 = .71
So biggest is 4/5 and smallest is 2/3
Their difference is 4/5 - 2/3 = 2/15
Option A
Question: R = {2, 3, 4, 5}
B = {4, 5, 6, 7, 8}
Two integers will be randomly selected from the sets above, one integer from set R and one integer from set B. What is the probability that the sum of the two integers will equal 9 ?
A. 0.15
B. 0.20
C. 0.25
D. 0.30
Answer: B. 0.20
Explanation: The total number of pairs R,B possible is 4*5=20. Out of these 20 pairs only 4 sum up to 9: (2, 7); (3, 6), (4, 5) and (5, 4). The probability thus is 4/20=0.2.
Answer: B.
Question: An article is bought for Rs.705 and sold for Rs.900, find the gain percent?
A.27.65%
B.33 1/2%
C.33 1/3%
D.33 5/3%
Answer: A.27.65%
Explanation: 705 ---- 195
100 ---- ? => 27.65%
Answer:A
Question: Car A runs at the speed of 50 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 65 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B?
A.3 : 7
B.4 : 9
C.20 : 13
D.5 : 7
Answer: C.20 : 13
Explanation: Car A travels 50 × 8 = 400 km
Car B travels 65 × 4 = 260 km
The ratio is 400 : 260 = 40 : 26 = 20 : 13
The answer is C.
Question: What is the 10th digit to the right of the decimal point in the decimal equivalent of 124/22?
A.2
B.3
C.4
D.7
Answer: B.3
Explanation: 124/22 = 5.6363....
63 is non-terminating repeating decimal.
The 10th digit to the right of decimal point will be 3.
Answer B
Question: Find a two digit number, given that the sum of the digits is 12 and the difference of the digits is 2.?
A.66
B.87
C.75
D.88
Answer: C.75
Explanation: Using elimination method find which of the options fit the description of the number
... from the option only 75 meets this description
sum of digits---7+5 = 12
difference of digits ---7-5 = 2
Answer C.
Question: The probability that event M will not occur is 0.8 and the probability that event R will not occur is 0.7. If events M and R cannot both occur, which of the following is the probability that either event M or event R will occur?
A.1/2
B.2/5
C.3/5
D.4/5
Answer: A.1/2
Explanation: p(m) =0.2
p(r) =0.3
p(m intersection r) = 0 (If events M and R cannot both occur)
p(m or r) = 0.2+0.3 =0.5
Corrected !!
Answer A
Question: In how many different ways can the letters of the word 'LEADING' be arranged in such a way that the vowels always come together?
A.360
B.480
C.720
D.5040
Answer: C.720
Explanation: 5!*3!=720
ANSWER:C
Question: How many digits are required to number a book containing 220 pages?
A.674
B.604
C.552
D.372
Answer: C.552
Explanation: 9 pages from 1 to 9 will require 9 digits.
90 pages from 10 to 99 will require 90*2=180 digits.
220-(90+9)=121 pages will require 121*3=363 digits.
The total number of digits is 9+180+363=552.
The answer is C.
Question: The total marks obtained by a student in Mathematics and Physics is 60 and his score in Chemistry is 20 marks more than that in Physics. Find the average marks scored in Mathamatics and Chemistry together.
A.40
B.30
C.25
D.Data inadequate
Answer: A.40
Explanation: Let the marks obtained by the student in Mathematics, Physics and Chemistry be M, P and C respectively.
Given , M + C = 60 and C - P = 20 M + C / 2 = [(M + P) + (C - P)] / 2 = (60 + 20) / 2 = 40.
ANSWER:A
Question: Pipe A can fill a tank in 8 hours, pipe B in 4 hours and pipe C in 24 hours. If all the pipes are open, in how many hours will the tank be filled?
A.1.9 hour
B.2.1 hour
C.4.7 hour
D.2.4 hour
Answer: D.2.4 hour
Explanation: Part filled by pipe A in 1 hour =1/8
Part filled by pipe B in 1 hour =1/4
Part filled by pipe C in 1 hour =1/24
Part filled by pipes A,B,C together in 1 hour=1/8+1/4+1/24=10/24
i.e, pipes A,B,C together can fill the tank in = 24/10 hr =2.4 hour.
ANSWER:D
Question: a is the hundreds digit of the three digit integer x, b is the tens digit of x, and c is the units digit of x. a = 4b = 2c, and a > 0.
What is the difference between the two greatest possible values of x?
Tip: Dont stop till you have exhausted all answer choices to arrive at the correct one.
A.124
B.297
C.421
D.412
Answer: D.412
Explanation: Ratio of a:b:c= 4:1:2
Two possible greatest single digit values for a are 8 and 4
if a is 8, then x= 824
if a is 4, then x= 412
difference= 824-412= 412
D is the answer
Question: The average age of 3 girls is 18 years and their ages are in the proportion 1:2:3. The age of the youngest girl is?
A.10 years
B.9 years
C.12 years
D.14 years
Answer: B.9 years
Explanation: Total age of 3 boys = 18*3 =54
ratio of their ages = 1:2:3
Age of the youngest = 54*1/6 = 9 years
Answer is B
Question: How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction?
A.50 sec
B.17 sec
C.18 sec
D.10 sec
Answer: A.50 sec
Explanation: The distance to be covered = Sum of their lengths
= 200 + 300 = 500 m.
Relative speed = 72 -36 = 36 kmph
= 36 * 5/18 = 10 mps.
Time required = d/s
= 500/10 = 50 sec.
Answer: A
Question: Find large number from below question The difference of two numbers is 100. On dividing the larger number by the smaller, we get 9 as quotient and the 4 as remainder
A.120
B.100
C.112
D.150
Answer: C.112
Explanation: Let the smaller number be x. Then larger number = (x +100).
x +100 =9x + 4
8x = 96
x =12
Large number = 12+100 = 112
C