RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If n is a positive integer and the product of all the integers from 1 to n, inclusive, is a multiple of 170, what is the least possible value of n?
A.14
B.13
C.15
D.17
Answer: D.17
Explanation: 17, since n needs to be the largest of the prime factors. Therefore, the answer is D.
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 sec. What is the length of the fast train?
A.27 7/8
B.27 9/9
C.28 7/9
D.27 7/9
Answer: D.27 7/9
Explanation: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5 = 250/9
= 27 7/9 m.
Answer: D
Question: Find the one which does not belong to that group ?
A.27
B.66
C.88
D.65
Answer: A.27
Explanation: Explanation:
37, 47, 67 and 17 are prime numbers but not 27.
Answer: A
Question: A fill pipe can fill 2/3 of cistern in 40 minutes in how many minutes, it can fill full of the cistern?
A.60min
B.36min
C.25min
D.30min
Answer: A.60min
Explanation: 2/3 of the cistern can fill in 40 min
3/3 of the cistern can fill in = 40*3/2*3/3 = 60min
Answer is A
Question: A man has some hens and cows. If the number of heads be 60 and the number of feet equals 200, then the number of hens will be:
A.22
B.25
C.24
D.20
Answer: D.20
Explanation: Explanation:
Let the number of hens be x and the number of cows be y.
Then, x + y = 60 .... (i)
and 2x + 4y = 200 x + 2y = 100 .... (ii)
Solving (i) and (ii) we get: x = 20, y = 40.
The required answer = 20.
Answer: D
Question: There are four prime numbers written in ascending order of magnitude. The product of the first three is 385 and of the last three is 1001. Find the fourth number?
A.5
B.7
C.11
D.13
Answer: A.5
Explanation: (385/1001) = 5/13 First Number is 5
ANSWER:A
Question: A group of 4th graders and 5th graders is going on a field trip to the zoo. Only 20% of the students remembered to bring written permission from their parents. If 40% of the students are 4th graders and 25% if the 4th graders remembered to bring written permission, what percentage of the students are 5th graders who forgot to bring written permission?
A.10%
B.30%
C.50%
D.60%
Answer: C.50%
Explanation: Assume that the total number of students is 100.
=> 20 students got permission from their parents, 40 students are 4th graders, and 10 of the 4th graders got permission from their parents
=> 30 of the 5th graders got written permission
=> 30 of the 5th graders did not get written permission (there are 60 students who are 5th graders)
=> 50% of the 5th graders didn't get permission
Option (C)
Question: If the probability of rain on any given day in Chicago during the summer is 50%, independent of what happens on any other day, what is the probability of having exactly 3 rainy days from July 4 through July 8, inclusive?
A.1/32
B.2/25
C.5/16
D.8/25
Answer: C.5/16
Explanation: From July 4 to July 8, we have total of 5 days. Prob of raining on exactly 3 days = 5C3∗(1/2)3∗(1/2)25C3∗(1/2)3∗(1/2)2
= 5/16
ANS: C
Question: What is the percentage increase in area when a triangle is cloned (so that we have two triangles in total) and the resulting two triangles are joined on their bases to form a parallelogram ?
A.100%
B.150%
C.300%
D.120%
Answer: A.100%
Explanation: area of a triangle having base b and height h given by 1/2(b*h)
when two triangles are mounted onto their bases to form a parallelogram, then area would become b*h
percentage increase of area= (new area- area of original triangle)/(area of the original triangle) X 100%
=(b * h)-1/2(b*h) /1/2(b * h) * 100%
= (1-1/2) / (1/2)X100%
=100%
ANSWER:A
Question: When a commodity is sold for Rs.34.80, there is a loss of 2%. What is the cost price of the commodity?
A.Rs.26.10
B.Rs.43
C.Rs.43.20
D.Rs.46.40
Answer: D.Rs.46.40
Explanation: Solution
C.P	= Rs.(100 / 75×34.80)
= Rs.46.40.
Answer D
Question: Mark bought a set of 6 flower pots of different sizes at a total cost of $8.25. Each pot cost 0.1 more than the next one below it in size. What was the cost, in dollars, of the largest pot?
A.$1.62
B.$1.85
C.$2.00
D.$2.15
Answer: A.$1.62
Explanation: This question can be solved with a handful of different Algebra approaches (as has been shown in the various posts). Since the question asks for the price of the largest pot, and the answers are prices, we can TEST THE ANSWERS.
We're told that there are 6 pots and that each pot costs 25 cents MORE than the next. The total price of the pots is $8.25. We're asked for the price of the largest (most expensive) pot.
Since the total price is $8.25 (a 10-cent increment) and the the difference in sequential prices of the pots is 10 cents, the largest pot PROBABLY has a price that is a 10-cent increment. From the answer choices, I would then TEST Answer A first
IF....
The largest pot = $1.625
1.125
1.225
1.325
1.425
1.525
1.625
Total = $8.25
So this MUST be the answer.
A
Question: Look at this series: F2, __, D8, C16, B32, ... What number should fill the blank?
A.A16
B.G4
C.E4
D.E3
Answer: C.E4
Explanation: Answer: Option C
The letters decrease by 1; the numbers are multiplied by 2.
Question: A certain car traveled twice as many miles from Town A to Town B as it did from Town B to Town C. From Town A to Town B, the car averaged 20 miles per gallon, and from Town B to Town C, the car averaged 24 miles per gallon. What is the average miles per gallon that the car achieved on its trip from Town A through Town B to Town C?
A.40
B.30
C.42
D.33
Answer: B.30
Explanation: step 1) took LCM of 20 and 24.. came as 120.
step 2) 120 distance between B to C... do 120/24 hence 5 gallons used
step 3) twice distance.. hence 120*2= 240... do as above.. 240/20= 7 gallons used
step 4) total gallons.. 5+7= 12 gallons
step ) total miles= 120+240= 360 miles
hence.. average of whole journey = 360/12 which comes to 30
Answer : B
Question: How much more would Rs.20000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly?
A.278
B.370
C.237
D.482
Answer: D.482
Explanation: 20000(11/10)4 - 20000(6/5)2
= 482
Answer:D
Question: The manager at a health foods store mixes a unique superfruit juice cocktail that costs $1399.45 per litre to make. The cocktail includes mixed fruit juice and açai berry juice, which cost $262.85 per litre and $3104.35 per litre, respectively. The manager has already opened 37 litres of the mixed fruit juice. How many litres of the açai berry juice does he need to add?
A.17 litres
B.24.67 litres
C.11 litres
D.24.07 litres
Answer: B.24.67 litres
Explanation: 262.85(37)+3,104.35x = 1,399.45(37 + x)
Solve the equation.
262.85(37)+3,104.35x = 1,399.45(37 + x)
9725.45+ 3,104.35x = 51779.65+ 1,399.45x
9725.45 + 1,704.9x = 51779.65
1,704.9x = 42054.2
x ≈ 24.67
Answer is B.
Question: Money invested at x%, compounded annually, triples in value in approximately every 112/x years. If $2200 is invested at a rate of 8%, compounded annually, what will be its approximate worth in 28 years?
A.$3,750
B.$19,800
C.$8,100
D.$15,000
Answer: B.$19,800
Explanation: x=8%
112/x years=112/8=14 years
Now, money triples every 14 years
Therefore, in 14 yrs , if $2200 triples to $6600, in 28 years, it will again triple to $6600*3=$19,800
Answer B
Question: a clock is such that it looses 4 min every day.the clock is set right on feb 25,2008 2 p.m.how many min should be added to get the right time when the clock shows 9 am on 3rd march 2008?
A.9:07am
B.9:17am
C.9:27am
D.9:37am
Answer: C.9:27am
Explanation: There are 6days from 25th feb to 2nd march i.e(25-26,26-27,27-28,28-29,29-1,1-2)
so (6*24)=144 hrs
and of 3rd march(24-5)=19hrs will be counted
so total hrs=163hrs
as mentioned in que clock looses 4 mins in 24hrs
In 24hrs clock looses =4mins
hence in 163 hrs clock looses=(4/24)*163=27 mins 16 secs
The Question is to calculate no. of minutes to be added when clock shows 9.00AM
Therefore,the correct time will be 9:27am
ANSWER:C
Question: Tom bought 2 shares and sold them for $91 each. If he had a profit of 30% on the sale of one of the shares but a loss of 9% on the sale of the other share, then on the sale of both shares Tom had
A. a profit of $12
B. a loss of $10
C. a loss of $12
D. a profit of $10
Answer: A. a profit of $12
Explanation: total CP = 9100/130 + 9100/91 = 70 + 100=170
SP=91*2=182
profit= Rs 12/+
Answer: A
Question: In 1991, there are 28 days in February and there are 365 days in the year. In 1992, there are 29 days in February and there are 366 days in the year. If the date September 15, 1995 is a Monday, then which one of the following would the date September 15, 1996 be?
A.Tuesday
B.Wednesday
C.Thursday
D.Friday
Answer: B.Wednesday
Explanation: From the information given,September 15, 1992 is 366 days after September 15, 1991.
366 days = 52 weeks and 2 more days. Therefore if March 15, 1995 is a Monday, then March 15, 1996 is Monday + 2 days = Wednesday
Answer: B
Question: In the rectangular coordinate system, what is the x-intercept of a line passing through (10, 3) and (−8, −6)?
A.4
B.2
C.0
D.−2
Answer: A.4
Explanation: slope = rise/run = 9/18 = 1/2
The equation of the line is y = (1/2)x + b
3 = (1/2)(10) + b
b = -2
The equation of the line is y = (1/2)x - 2
To find the x-intercept, let y = 0:
0 = (1/2)x - 2
x = 4
The answer is A.
Question: The edges of a cuboid are 4 cm, 5 cm and 7 cm. Find the volume of the cuboid?
A.140
B.278
C.378
D.368
Answer: A.140
Explanation: 4*5*7
= 120
Answer: A
Question: A box contains five bulbs out of which 2 are defective. If two bulbs are chosen at random, find the probability that all the two bulbs are defective?
A.1/12
B.1/10
C.1/19
D.1/13
Answer: B.1/10
Explanation: Out of five, three are good and two are defective. Required probability
= 2C2/5C2
= 1/10
Answer:B
Question: A and B are two circles. The radius of A is twice as large as the radius of B. What is the ratio between the areas of the circles?
A.1:8.
B.1:2.
C.1:4.
D.1:16.
Answer: C.1:4.
Explanation: Given : The radius of A is twice as large as the radius of B. => R(a) = 2*R(b). The radius are in ratio of 1:2 thus the area will be in the ratio of square of radius. 1:4. Hence C.
Question: A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.12000. A's share is?
A.s.4000
B.s.7200
C.s.6000
D.s.5750
Answer: A.s.4000
Explanation: x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 12000 = 4000
ANSWER:A
Question: Find the value of * in the following
(1 5/3) ÷ 3/11 × */11 = (2 2/3 × 7/5 × 6/7)
A.1.7
B.2.5
C.3.6
D.3.9
Answer: C.3.6
Explanation: Option 'C'
Question: If n = 10p, where p is a prime number greater than 2, how many different positive even divisors does n have, including n ?
A. Two
B. Three
C. Four
D. Six
Answer: C. Four
Explanation: If n = 10p, where p is a prime number greater than 2, how many different positive even divisors does n have, including n ?
(A) Two
(B) Three
(C) Four
(D) Six
(E) Eight
Since we cannot have two correct answers just pick a prime greater than 2, and see how many different positiveevendivisors will 10p have.
p = 3 --> 10p = 30--> 30 has 4 even divisors: 2, 6, 10,30.
Answer: C.
Question: How many positive integers less than 20 can be expressed as the sum of a positive multiple of 2 and a positive multiple of 3?
A.14
B.13
C.12
D.11
Answer: A.14
Explanation: The numbers must be of the form 2a+3b,2a+3b, where aa and bb are positive integers.
The smallest number is 5=2∗1+3∗1.5=2∗1+3∗1. Starting with 55, we can get all the other numbers by adding either 22 or 33 to the already existing numbers on our list. Adding either 22 or 33 to 2a+3b2a+3b will give another number of the same form.
So, after 55, we get 5+2=7,5+3=8,7+2=9,8+2=10,...5+2=7,5+3=8,7+2=9,8+2=10,... We will get all the numbers up to 1919 inclusive, except 1,2,3,4,1,2,3,4,and 6,6, because once we have 77 and 8,8, by adding 22 all the time we can get any odd or even number.
We get a total of 19−5=1419−5=14 numbers.
Answer A
Question: As x increases from 151 to 152, which of the following increases? I) x−1/x II) 17−1/x III) (17+x)/x
A.II only
B.II,III only
C.I,II only
D.I only
Answer: C.I,II only
Explanation: On Increasing the value of x from 151 to 152
I) x−1/x will increase as 1/x will be very small and x will increase by 1 unit
II) 17−1/x Will Increase as the value of 1/x will decrease thereby increasing the value of 17-(1/x)
III) (17+x)/x = (17/x)+1 will Decrease as 1/x will decrease thereby decreasing the value of (17/x)
Answer: C
Question: In what ratio must tea at Rs.64 per Kg be mixed with tea at Rs.74 per Kg so that the mixture must be worth Rs.69 per Kg?
A.1 : 1
B.3 : 2
C.4 : 3
D.5 : 3
Answer: A.1 : 1
Explanation: Required ratio = 500 : 500 = 1 : 1
Answer A
Question: Max left from a Pvt Company. Management hold his salary Rs. 35000/- for one month. Earlier Robert borrowed Rs. 17280/- from company. But Robert forgot that. After one month Robert asked his salary and accountant gives Rs.28500/- to him. What is the incentive amount given to Robert?
A.A)9500
B.B)12500
C.C)10780
D.D)10500
Answer: C.C)10780
Explanation: Total Salary = Rs.35000/-
Borrowed Money = 17280/-
Balance Salary = 35000-17280= 17720
Paid amount = 28500/-
Incentive amount = 28500-17720 = 10780/-
Answer is C
Question: In an examination, 32% candidates failed in one subject and 42% failed in another subject while 15% failed in both the subjects. If 2500 candidates appeared at the end of the examination how many passed in either subject but not in both?
A.975
B.1020
C.1100
D.1243
Answer: C.1100
Explanation: Failed in 1st subject = 32*2500/100 = 800
Failed in 2nd subject = 42*2500/100 = 1050
Failed in both = 15*2500/100 = 375
Failed in 1st subject only = 800-375 = 425
Failed in 2nd subject only = 1050-375 = 675
Passed in either subject but not in both = 675+425 = 1100
Answer is C
Question: How many days will there be from 26th January,1996 to 15th May,1996(both days included)?
A.102
B.132
C.111
D.132
Answer: C.111
Explanation: Number of days from 26-Jan-1996 to 15-May-1996 (both days included)
= 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May) = 111
Answer:C
Question: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs 8,748, its purchase price was?
A.Rs 16,000
B.Rs 18,000
C.Rs 12,000
D.Rs 14,000
Answer: C.Rs 12,000
Explanation: We have P = 8748, R = -10 and n = 3
Therefore, the purchase price of the machine
= P/(1 + (R/100))n = 8748/(1 - (10/100))3
= 8748 x (100/90) x (100/90) x (100/90)
= 12,000.
ANSWER:C
Question: The division of a whole number N by 13 gives a quotient of 15 and a remainder of 2. Find N.
A.897
B.197
C.697
D.997
Answer: B.197
Explanation: According to the division process of whole numbers, N can be written, using multiplication, as follows
N = quotient * divisor + remainder = 15 * 13 + 2 = 197
correct answer B
Question: Find the area of circle whose radius is 21m?
A.980 sq m
B.1892 sq m
C.1267 sq m
D.1386 sq m
Answer: D.1386 sq m
Explanation: r = 21
Area of Circle =∏r2
= (22/7)(21)(21)
= 1386 sq m.Answer: D
Question: Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is?
A.820 gallons
B.128 gallons
C.120 gallons
D.129 gallons
Answer: C.120 gallons
Explanation: Work done by the waste pipe in 1 minute = 1/15 - (1/20 + 1/24) = - 1/40
Volume of 1/40 part = 3 gallons\
Volume of whole = 3 * 40 = 120 gallons.
Answer: C
Question: If in a certain sequence of consecutive multiples of 50, the median is 625, and the greatest term is 1050, how many terms that are smaller than 625 are there in the sequence?
A.6
B.7
C.8
D.9
Answer: D.9
Explanation: Since the median is 625 we know there must be a even number of integers because 50 is not a multiple of 625.
So the list around 625 must go. 600 (625) 650 700 750 800 850 900 950 1000 1050
Since we know there are 9 numbers greater than 625 then there must be 9 numbers less then 625.
D
Question: A survey was sent to 60 customers, 7 of whom responded. Then the survey was redesigned and sent to another 63 customers, 9 of whom responded. By approximately what percent did the response rate increase from the original survey to the redesigned survey?
A.2%
B.5%
C.14%
D.28%
Answer: A.2%
Explanation: case 1: (7/60)=x/100
x=12%
case 2: (9/63)=y/100
y=14%
So percent increase is =(y-x)=(14-12)%=2%
Answer is A
Question: If x and y are integers, and 5x+7y=12, which of the following could be the value of y ?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: Use answer options to solve this problem -
Put y = 1
So, 5x+7(1)=12
Or, 5x=12-7
Or, 5x=5
Or, x = 1
Answer will be (B)
Question: If an integer n is to be selected at random from 1 to 400, inclusive, what is probability n(n+1) will be divisible by 8?
A.1/4
B.1/8
C.1/2
D.2/3
Answer: A.1/4
Explanation: For n(n+1) to be a multiple of 8, either n or n+1 has to be a multiple of 8.
Thus n must be of the form 8k or 8k-1.
The probability is 2/8 = 1/4.
The answer is A.
Question: Two pipes X and Y can separately fill a cistern in 18 and 24 hours respectively. If they are turned on alternately for one hour each, how long will it take to fill the cistern?
A.20 1/2 hours
B.20 1/8 hours
C.20 3/2 hours
D.80 1/2 hours
Answer: A.20 1/2 hours
Explanation: 1/18 + 1/24 = 7/72
72/7 = 10 2/7
7/72 * 10 = 35/36 ----- 20 hours
WR = 1 – 35/36 = 1/36
1 h ----- 1/18
? ----- 1/36 = 1/2 hours
=> 20 1/2 hours
Answer:A
Question: A certain music store stocks 800 cellos and 600 violas. Of these instruments, there are 70 cello-viola pairs, such that a cello and a viola were both made with wood from the same tree (each tree can make at most one viola and one cello, so there are no pairs other than these 90). If one viola and one cello are chosen at random, what is the probability that the two instruments are made with wood from the same tree?
A.3/16,000
B.1/8,100
C.7/48,000
D.1/90
Answer: C.7/48,000
Explanation: Solution provided by stanford2012 is correct: 70/800 choosing one of the cellos which has a pair viola, 1/600 choosing the viola which is the pair of chosen cello --> P=70/800*1/600=7/48,000.
Answer: C.
Question: In a carton there are balls of 10 different colors. What is the least number of balls that you have to take out so that you will have a matching pair?(Assuming that all the balls are of same size but different colors)
A.12
B.6
C.9
D.11
Answer: D.11
Explanation: Since there are 10 colors, if you take 10 balls, you could still have 1 ball per color and not have a match.
Therefore, upon taking the 11th ball, you will definitely have a match since the 11th ball will form at least a pair with the 1st 10
So 10+1 = 11
Answer is D
Question: If the sum of three consecutive even numbers is 44 more than the average of these numbers, then the largest of these numbers is?
A.20
B.24
C.22
D.26
Answer: B.24
Explanation: Explanation:
Let the smallest of these number be x. The other two numbers are (x + 2) and (x + 4).
x + (x + 2) + (x + 4) = (X + (X+2) + (x+4)) / 3 + 44
3x + 3*(x + 2) + 3*(x + 4) = x + (x + 2) + (x + 4) + 132
9x + 18 = 3x + 138
6x = 120
x = 20
Therefore, the largest number is 24.
ANSWER B
Question: If m is a positive integer and m^2 is divisible by 36, then the largest positive integer that must divide m is?
A. 3
B. 6
C. 8
D. 12
Answer: D. 12
Explanation: M^2 is divisible by 48 so M^2 must be multiple of 48.
If the value of M is Multiples of 12 then it will satisfy the condition. If we If M is 12 or 24 or 36 then it ans is D but if M = 48 then answer should be 16.
Is the question right? Or am i missing some thing?
D
Question: The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 7 consecutive integers that start with (m + 2)?
A.m + 3
B.n + 6
C.n + 3
D.m + 4
Answer: C.n + 3
Explanation: The average of consecutive numbers is the middle number.
Then n = m+2.
The average of 7 consecutive numbers starting from n is n+3.
The answer is C.
Question: In one hour, a boat goes 12 km/hr along the stream and 8 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
A.1 km/hr
B.2 km/hr
C.10 km/hr
D.11 km/hr
Answer: C.10 km/hr
Explanation: Let speed of the boat in still water = x and speed of the stream = y
Then
x + y = 12
x - y = 8
Adding these two equations, we get 2x = 20
=> x = 10
ie, speed of boat in still water = 10 km/hr
ANSWER:C
Question: A pizza is divided into 12 slices. If there are eight slices left, what fraction of the pizza is remaining?
A.1/2
B.1/3
C.2/7
D.2/3
Answer: D.2/3
Explanation: Ans is : D 2/3, Your child must reduce the fraction 8/12. Divide the numerator and denominator by four, which is 2/3.
Question: If air is called green , green is called blue, blue is called blue, sky is called yellow, yellow is called water and water is called pink, then what is the color of clear sky ?
A.Blue
B.Sky
C.Water
D.Yellow
Answer: A.Blue
Explanation: Explanation:The colour of clear sky is 'blue' and as given, 'blue' is called 'blue'.So, the colour of clear sky is 'blue'.Answer: A
Question: |x+1| – |4-x| = |8+x| How many solutions will this equation have?
A.0
B.1
C.2
D.3
Answer: D.3
Explanation: You have |x+3| - |4-x| = |8+x|
First, look at the three values independently of their absolute value sign, in other words:
|x+3| - |4-x| = |8+x|
(x+3) - (4-x) = (8+x)
Now, you're looking at x < - 8, so x is a number less than -8. Let's pretend x = -10 here to make things a bit easier to understand.
when x=-10
I.) (x+3)
(-10+3)
(-7)
II.) (4-x)
(4-[-10]) (double negative, so it becomes positive)
(4+10)
(14)
III.) (8+x)
(8+-10)
(-2)
In other words, when x < -8, (x+3) and (8+x) are NEGATIVE. To solve problems like this, we need to check for the sign change.
Here is how I do it step by step.
I.) |x+3| - |4-x| = |8+x|
II.) IGNORE absolute value signs (for now) and find the values of x which make (x+3), (4-x) and (8+x) = to zero as follows:
(x+3)
x=-3
(-3+3) = 0
(4-x)
x=4
(4-4) = 0
(8+x)
x=-8
(8+-8) = 3
D
Question: Speed of a boat in standing water is 14 kmph and the speed of the stream is 1.2 kmph. A man rows to a place at a distance of 4864 km and comes back to the starting point. The total time taken by him is:
A.200 hours
B.400 hours
C.900 hours
D.700 hours
Answer: D.700 hours
Explanation: Speed downstream = (14 + 1.2) = 15.2 kmph
Speed upstream = (14 - 1.2) = 12.8 kmph
Total time taken =4864/15.2+4864/12.8= 320 + 380 = 700 hours
Answer: D
Question: The cost price of an article is 25% of the marked price. Calculate the gain percent after allowing a discount of 50%.
A.25%
B.50%
C.100%
D.150%
Answer: C.100%
Explanation: Sol.
Let marked price = Rs. 100. Then, C.P. = Rs. 25. S.P = Rs. 50.
âˆ´ Gain % = [25/25 * 100]% = 100.0%.
Answer C
Question: What is the 23th digit to the right of the decimal point in the decimal form of 36/66?
A.3
B.4
C.8
D.9
Answer: B.4
Explanation: We first have to use some long division. This long division allows us to get 36/66 in decimal form, which is 0.545454… where “54” is repeating.
We can see that the 1st, 3rd, 5th digit to the right of the decimal point is a 5 and that the 2nd, 4th, 6th digit to the right of the decimal point is a 4. In other words, each odd-positioned digit is a 5, and each even-positioned digit is a 4.
Then about the 10 digit to the right of the decimal point and we see that 10 is even, we know that the 10th digit is a 4.
Answer B.
Question: A grocer is storing soap boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 6 inches by 10 inches, then what is the maximum number of soap boxes that can be placed in each carton?
A.210
B.252
C.280
D.150
Answer: D.150
Explanation: however the process of dividing the volume of box by the volume of a soap seems flawed but it does work in this case due to the numbers
Dimensions of the box =25*42*60
Dimensions of the soap = 10*6*7
we get = 5x6x5 = 150
so the question is why this particular arrangement, in order to maximize number of soaps we need to minimize the space wasted and this is the only config where we dont waste any space so we can expect the maximum number
the answer is (D)