RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both BG, with these two children immediately adjacent to here on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations Q are there for the children?
A.240
B.480
C.720
D.1440
Answer: A.240
Explanation: MAGOOSHOFFICIAL SOLUTION:
First, we will consider the restricted elements — children ABG have to be in three seats in a row. How many “three in a row” seats are there in a row of seven seats?
X X X _ _ _ _
_ X X X _ _ _
_ _ X X X _ _
_ _ _ X X X _
_ _ _ _ X X X
There are five different “three in a row” locations for these three children. Now, for any given triplet of seats, we know A has to be in the middle, so the children could be seated B-A-G or G-A-B — just those two orders. This means the total number of configurations for these three children is 5*2 = 10.
Now, consider the non-restricted elements, the other four. Once ABG are seated, the remaining four children can be seated in any order among the remaining four seats — that’s a permutation of the 4 items —- 4P4 = 4! = 24. For any single configuration of ABG, there are 24 ways that the other children could be seated in the remaining seats.
Finally, we’ll combine with the Fundamental Counting Principle. We have 10 ways for the first three, and 24 ways for the remaining four. That’s a total number of configurations Q of 24*10 = 240.
Answer = A
Question: In a 1000 m race, A beats B by 320 meters or 25 seconds. Find the speed of B?
A.8
B.9
C.12.8
D.5
Answer: C.12.8
Explanation: Since A beats B by 320 m or 25 seconds, i
t implies that B covers 320 m in 25 seconds.
Hence speed of B = 320/25 = 12.8 m/s.
Answer: C
Question: There are 6 red balls and 4 blue balls in a jar. If 3 balls are selected from the jar, what is the probability that all 3 balls selected are red balls?
A.1/3
B.1/6
C.5/12
D.5/24
Answer: B.1/6
Explanation: The number of ways of choosing 3 balls from the jar is 10C3 = 120.
The number of ways of choosing 3 red balls is 6C3 = 20.
P(3 red balls) = 20/120=1/6.
The answer is B.
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
A.150
B.200
C.180
D.250
Answer: A.150
Explanation: speed = (60*5/18) = 50/3
length = (speed*time)
length = (50/3*9) = 150 m
ANSWER A
Question: The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 67 kg. What is the weight of the new person?
A.75
B.65
C.87
D.95
Answer: C.87
Explanation: Total increase in weight = 8 × 2.5 = 20
If x is the weight of the new person, total increase in weight = x−67
=> 20 = x - 67
=> x = 20 + 67 = 87
Answer is C.
Question: If p/4 = r/2 and r = 0.75s, what is the ratio of p to r to s?
A.2 : 3 : 4
B.8 : 12 : 9
C.12 : 6 : 8
D.6 : 4 : 3
Answer: C.12 : 6 : 8
Explanation: p/4=r/2, r=0.75s, what is p:r:s?
we get p/r=4/2 and r/s=3/4, so
4/3*3/2 and 2/2*3/4
12/6 and 6/8
C
Question: Adam is 40% more efficient than Blanc. How much time will they, working together, take to complete a job which Adam alone could have done in 20 days?
A.35 days
B.11 1â„3 days
C.11 2â„3 days
D.20 days
Answer: C.11 2â„3 days
Explanation: Ratio of times taken by Adam and Blanc = 100 : 140 = 5 : 7.
Suppose Blanc takes x days to do the work.
Then, 5 : 7 : : 20 : x â‡’ x = (20Ã—7)/5 â‡’ x = 28
Adamsâ€™s 1 dayâ€™s work = 1â„20; Blancâ€™s 1 days work = 1â„28
(Adam + Blanc)â€™s 1 dayâ€™s work = (1â„20 + 1â„28) = 3â„35
âˆ´ Adam and Blanc together can complete the job in 35â„3 days or 11 2â„3 days.
Answer C
Question: X and Y are both integers. If X/Y = 59.80, then what is the sum of all the possible two digit remainders of X/Y?
A.560
B.616
C.672
D.200
Answer: D.200
Explanation: Remainder = 0.80= --> 80/100 --> Can be written as (80/4) / (100/4) = 20/25
So remainders can be 20, 40, 60, 80
We need the sum of only 2 digit remainders --> 20 + 40 + 60 + 80 = 200
Answer: D
Question: 2/3rd of the boys and 3/4th of the girls of a school participate in a function. If the no.of participating students is 550, out of which 150 are girls, what is the total no.of students in the school?
A.500
B.600
C.800
D.900
Answer: C.800
Explanation: Let total number of boys be x and total number of girls be y. y=400=>x = 600and^= I50=>y = 200 Now, x + y = 800
C
Question: When x is divided by y, the quotient is t with remainder r. What is x in terms of r, y, and t?
A.y + r + t
B.yt + r
C.x/y+r
D.y/t+r
Answer: B.yt + r
Explanation: (x/y) = t + r
solve for x
x=(t*y)+r
Ans B.
Question: There were two candidates in an election. Winner candidate received 62% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate?
A.288
B.744
C.788
D.298
Answer: B.744
Explanation: W = 62% L = 38%
62% - 38% = 24%
24% -------- 288
62% -------- ? => 744
Answer: B
Question: The value for S=(0.889 × 55)/9.97 to the nearest tenth is
A.0.5
B.4.63
C.4.9
D.7.7
Answer: C.4.9
Explanation: if we read the Q, we can easily home on to the answer,,
the numerator is clearly between 40 and 50..
denomiator is close to 10..
so S=(0.889 × 55)/9.97 is between 4 and 5..
It may tempt us to solve it since ther are two values between 4 and 5..
but the catch is innearest tenth
4.63 can be called nearest to hundreth and no tenth, so can be eliminated..
4.9 is our answer...
C
Question: In a class of 20 students, 2 students did not borrow any books from the library, 10 students each borrowed 1 book, 5 students each borrowed 2 books, and the rest borrowed at least 3 books. If the average number of books per student was 2, what is the maximum number of books any single student could have borrowed?
A.12
B.13
C.14
D.15
Answer: C.14
Explanation: The total number of books the students borrowed is 20*2=40.
The students who borrowed zero, one, or two books borrowed 10*1+5*2=20 books.
The 3 students who borrowed at least three books borrowed 40-20=20 books.
If 2 of these students borrowed exactly 3 books, then the maximum that one student could have borrowed is 20-6= 14 books.
The answer is C.
Question: 20^10 / 120^5=?
A.6^5
B.5^6
C.(10/3)^5
D.6^3
Answer: C.(10/3)^5
Explanation: 20^10 / 120^5=?
A. 6^5
B. 5^6
C. (10/3)^5
D. 6^3
E. 15^3
-> 20^10 / 120^5=(20^10)/(6^5)(20^5)=(20^5)/(6^5)=(2^5)(10^5)/(2^5)(3^5)=(10/3)^5.
Thus, C is the answer.
Question: A tank 3 m long, 2 m wide and 1.5 m deep is dug in a field 20 m long and 14 m wide. If the earth dug out is evenly spread out over the field, the level of the field will raise by nearly?
A.1390
B.2887
C.2667
D.1898
Answer: A.1390
Explanation: 2(25 * 15 + 15 * 8 + 25 * 8)
2(375 + 120 + 200) => 1390
Answer: A
Question: The below sequence is a bit tricky. Can you solve it to find the next number?
5, 25, 325, 4325, ?
A.29816
B.38291
C.54325
D.38290
Answer: C.54325
Explanation: C
54325
Consider 1 = 5
2 = 25
3 = 325
4 = 4325
Then 5 = 54325
See the pattern. With every digit, the previous numbers are added after that digit
So the next number in the series is 54325
Question: Solve the equation for x : 19(x + y) + 17 = 19(-x + y) - 21
A.-1
B.-9
C.-7
D.-2
Answer: A.-1
Explanation: Explanation:
19x + 19y + 17 = -19x + 19y - 21
38x = -38 => x = -1
Answer:A
Question: In a class, the average age of 30 boys is 13 years and the average of 20 girls is 12 years. what is the average age of the whole class?
A.12 Years
B.12.6 Years
C.13 Years
D.13.5 Years
Answer: B.12.6 Years
Explanation: Total age of 50 students
(30X 13+20 X 12) = 630
Average = 630/50 = 12.6 Years
B
Question: Someone on a skateboard is traveling 13 miles per hour. How many feet does she travel in 25 seconds? (1 mile = 5280 feet)
A.476.75 ft
B.450 ft
C.480 ft
D.490 ft
Answer: A.476.75 ft
Explanation: per second => 13*5280 ft/60*60 =19.07 ft
25 seconds => 19.07 * 25 = 476.75 ft
Answer : A
Question: A and B can do a work in 5 days and 10 days respectively. A starts the work and B joins him after 2 days. In how many days can they complete the remaining work?
A.6
B.2
C.3
D.4
Answer: B.2
Explanation: Work done by A in 2 days = 2/5
Remaining work = 3/5
Work done by both A and B in one day = 1/5 + 1/10 = 3/10
Remaining work = 3/5 * 10/3 = 2 day
Answer: B
Question: A student missed 6% of the questions on a test. If the student missed 12 questions, how many questions were on the test?
A.100
B.150
C.200
D.250
Answer: C.200
Explanation: 12 is 6% of the total answers on the test.
If the total number of answers on the test is X then
6/100 = 12/X
100/6 * 12 = X
1200/6 = X
200 = X
C)
Question: There are two clocks that are set at 8 0'clock in the morning. One clock is correct and the other clock gains 5 minutes per hour. When the faster clock shows the time 12:20 in the afternoon, what does the correct clock show?
A.12:00:00
B.11:45
C.12:26
D.11:50
Answer: A.12:00:00
Explanation: Faster clock gains 5 minutes per hour
At 8 0'clock both the clocks are set
At 9 0'clock -
The correct clock shows 9:00:00
The faster clock is at 9:05:00 (1 hour + gained 5 minutes)
At 10 0'clock
The correct clock is at 10:00:00
The faster clock is at 10:10:00 (2 hours + gains 10 minutes)
At 11 0'clock -
The correct clock is at 11:00:00
The faster clock is at 11:15:00 (3 hours + gains 15 minutes)
In 4 hours the faster clock would gain 20 minutes and shows 12:20:00 at that point which is 12 0'clock in the correct clock.
The answer is A
Question: 80% of a number is added to 120, the result is the same number. Find the number?
A.600
B.288
C.1687
D.997
Answer: A.600
Explanation: (80/100) * X + 120 = X
2X = 1200
X = 600
Answer:A
Question: Mr. Srinivas saves one coin of 5 on first day of the
week, three coins of 5 on the second day of the week.
Five coins of 5 on third day and so on. How much money will he has at the end of the week?
A.238
B.245
C.2867
D.987
Answer: B.245
Explanation: Number of
5 coins with him at the end of week = 5 × (1 + 3 + 5 + 7 + 9 + 11 + 13) = 5 × (sum of first 7 odd numbers) (By using the formula discussed earlier). ∴ Sum of all numbers = 5 × 72 = 245.
Answer:B
Question: A popular website requires users to create a password consisting of the digits {1,2,3,4,5,6,7}. If no digit may be repeated and each password must be at least 6 digits long, how many passwords are possible?
A.6! + 7!
B.2 x 7!
C.6! x 7!
D.13!
Answer: B.2 x 7!
Explanation: If we choose the 7 different digits then they can be arranged in 7! ways.
The number of possible 6-digit passwords is 7*6*5*4*3*2 = 7!
The total number of passwords is 7! + 7! = 2*7!
The answer is B.
Question: A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
A.30
B.80
C.40
D.70
Answer: C.40
Explanation: Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (2/25) = 40 seconds
Answer: Option C
Question: A began business with 12500 and is joined afterwards by B with 50000. When did B join, if the profits at the end of the year are divided equally?
A.8 months
B.9 months
C.10 months
D.7 months
Answer: B.9 months
Explanation: Let B join after x months of the start of the business so that B’s money is invested for (12 – x) months.
∴ Profit ratio is 12 × 12500 : (12 – x) × 50000
or 12 : 4(12 – x)
Since profit is equally divided so
12 = 4(12 – x) or x = 9. Thus B joined after 9 months.
Answer B
Question: How many words can be formed by using all letters of the word 'BIHAR' ?
A.112
B.120
C.157
D.136
Answer: B.120
Explanation: The word BIHAR contains 5 different letters
Required number of words = 5P5 = 5! = 5*4*3*2*1 = 120
Answer is B
Question: Nina has exactly enough money to purchase 6 widgets. If the cost of each widget were reduced by $1.15, then Nina would have exactly enough money to purchase 8 widgets. How much money does Nina have?
A.$22
B.$27.6
C.$30
D.$36
Answer: B.$27.6
Explanation: B its is.
Let price = X
(x-1.15)8 = 6X
X= 4.6
hence total money = 6*4.6 = 27.6
Question: A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 180 m in 18 sec. then find the length of the train?
A.100
B.180
C.110
D.120
Answer: B.180
Explanation: Length of the train be ‘X’
X + 120/15 = X + 180/18
6X + 720 = 5X + 900
X = 180m
Answer: Option B
Question: Three hundred students at College Q study a foreign language. Of these, 130 of those students study French, and 190 study Spanish. If at least 50 students who study a foreign language at College Q study neither French nor Spanish, then the number of students who study Spanish but not French could be any number from
A.10 to 40
B.40 to 100
C.60 to 100
D.60 to 120
Answer: D.60 to 120
Explanation: 130 students study French
170 students do not study French
190 students study Spanish
110 students do not study Spanish
50 students study neither French nor Spanish
170-110=60
170-50=120
D. 60 to 120
Question: In how many different ways can the letters of the word MISSISSIPPI be arranged?
A.11!/(4!4!2!)
B.11!/4!
C.11!/2!
D.11!
Answer: A.11!/(4!4!2!)
Explanation: Number of ways 11 letter can be arranged = 11!
The 11! arrangement will also contain duplicates because of the characters
that are repeated
We have 4 S's =4! repeats
We have 4 I's =4! repeats
We have 2 P's =2! repeats
So the total possible arrangement will be 11!/4!4!2!
Ans A
Question: Find a a prime number from the options below.
A.58
B.59
C.60
D.62
Answer: B.59
Explanation: Clearly, 59 is a prime number.
B
Question: One water pump can fill half of a certain empty tank in 7 hours. Another pump can fill half of the same tank in 7.5 hours. Working together, how long will it take these two pumps to fill the entire tank?
A.7 7/13
B.1 5/8
C.3 1/4
D.7 7/29
Answer: D.7 7/29
Explanation: One pump can fill a tank in 7 hours and another in 7.5 hours
so the rate at which both can half fill the tank is (1/7+1/7.5) => 29/105
Thus half of the tank can be filled in 105/29
so for filling the complete tank => 105/29*2 = 210/29 =7 7/29
ANSWER:D
Question: If the annual interest on a principal is 4%, how many years before the amount is double?
A.22
B.25
C.12
D.13
Answer: B.25
Explanation: P = (P*4*R)/100
R = 20%
Answer: B
Question: A and B started a business with an investment of Rs.26000 and Rs.28000. After two months C joined in the business with an investment of Rs.32000, what is share of C in the half year profit of Rs.9040 ?
A.3360
B.3120
C.2940
D.2560
Answer: D.2560
Explanation: Investment x Time.
A = 26000 x 6 = 156000.
B = 28000 x 6 = 168000.
C = 32000 x 4 = 128000.
Ratio of shares A : B : C = 39 : 42 : 32 = [ Total 113 units ]
Share of C in the profit = 9040 × 32 / 113 = 2560
Option D
Question: A brick measures 20 cm * 10 cm * 7.5 cm how many bricks will be required for a wall 25 m * 2 m * 0.75 m?
A.22377
B.27782
C.27891
D.25000
Answer: D.25000
Explanation: 25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x
25 = 1/100 * x => x = 25000
Answer: D
Question: A,B,C together can do a work in 10 days. A alone can do the work in 50days and B alone can do the same work in 60 days. Find in what time C alone can do that work?
A.15.8days
B.17days
C.19.5days
D.20.6days
Answer: A.15.8days
Explanation: The required answer is = 10*50*60 / 50*60-10(50+60)
= 30000/1900 = 15.8days
Answer is A
Question: The cash difference between the selling prices of an book at a profit of 4% and 6% is $ 3. The ratio of the two selling prices is:
A.50:53
B.58:53
C.52:53
D.42:36
Answer: C.52:53
Explanation: C
52:53
Let C.P. of the book be $ x.
Then, required ratio = 104% of x / 106% of x
= 104/106 = 52/53 = 52:53
Question: The speed at which a man can row a boat in still water is 26 kmph. If he rows downstream, where the speed of current is 4 kmph, what time will he take to cover 150 metres?
A.18
B.27
C.28
D.12
Answer: A.18
Explanation: Speed of the boat downstream = 26 + 4 = 30 kmph= 30 * 5/18 = 8.33 m/sHence time taken to cover 150 m = 150/8.33= 18 seconds.Answer:A
Question: A T.V was sold at a loss of 10%. If it was sold for Rs.3500 more, there would have been a gain of 10%. What is the cost price?
A.Rs. 17000
B.Rs. 18500
C.Rs.17500
D.Rs. 15500
Answer: C.Rs.17500
Explanation: 90%
110%
--------
20% ---- 3500
100% ---- ? => Rs.17500
Answer:C
Question: At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.20000?
A.6620
B.6628
C.6629
D.6624
Answer: A.6620
Explanation: A = 20000(11/10)3
= 26620
= 20000
----------
6620
Answer: A
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.230
B.240
C.250
D.260
Answer: B.240
Explanation: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.
Answer: Option B
Question: Machine A can do a certain job in 8 hours. Machine B can do the same job in 10 hours. Machine C can do the same job in 12 hours. All three machines start the job at 9:00 a.m. Machine A breaks down at 11:00 a.m., and the other two machines finish the job. Approximately what time R will the job be finished?
A.Noon
B.12:30 p.m.
C.1:00 p.m.
D.1:30 p.m.
Answer: C.1:00 p.m.
Explanation: Ans: C (1:00pm)
From 9:00-11:00c(2 hrs)
A can do 1/8 Job/hr. so in 2 hours he can do 1/4 job.
B can do 1/10 job/hr so in 2 hrs. he can do 1/5 Job.
C can do 1/12 job/hr so in 2 hours he can do 1/6 job.
Total = 1/4+1/5+1/6 = 37/60 Job
Now balance work needs to be done by B and C.
Balance Work= 23/60 Job
Combined rate of B and C = 1/10+1/12 = 11/60 job/hr.
So they will do 22/60 work in 2 hrs (approx. to the balance work of 23/60)
Hence the Job will be completed 2hrs. after 11:00 i.e. @ 1:00pm=R
Ans: C (1:00pm)
Question: 6 friends went to a hotel and decided to pay the bill amount equally. But 5 of them could pay Rs. 100 each as a result 6th has to pay Rs. 100 extra than his share. Find the amount paid by him.
A.156
B.220
C.130
D.240
Answer: B.220
Explanation: Explanation:
Average amount paid by 5 persons = Rs. 100
Increase in average due to Rs. 120 paid extra by the 6th men = Rs. 100/5= Rs. 20
Therefore, Average expenditure of 6 friends = Rs. 100 + Rs. 20 = Rs. 120
Therefore, Amount paid by the 6th men = Rs. 120+ Rs. 100 = Rs. 220
Correct Option: B
Question: What is x if x + 2y = 12 and y = 3?
A.A)10
B.B)8
C.C)6
D.D)4
Answer: C.C)6
Explanation: x = 12 - 2y
x = 12 - 6.
x = 6
Answer : C
Question: The average of 11 numbers is 10.9. If the average of the first six numbers is 10.5 and that of the last six numbers is 11.4,then the middle number is?
A.11.5
B.12.6
C.15.3
D.9.3
Answer: A.11.5
Explanation: Middle number = 10.5*6 + 11.4*6 - 10.9*11 = 131.4-119.9 = 11.5
Answer is A
Question: If the mode of Set Q is equal to the median of Set Q, Set Q could be
A.[0, 1, 2, 2, 3, 4, 5, 6]
B.[2, 2, 5, 7, 9]
C.[x, x+1, x+2, x+2, x+3, x+3]
D.[10, 102, 105, 105]
Answer: C.[x, x+1, x+2, x+2, x+3, x+3]
Explanation: Correct Answer: (C)
Set Q could be The mode is the most common number; the median is the middle number when the numbers are arranged from least to greatest. Any number plus an integer value is greater than the original number, so x + 1 is greater than x, x + 2 is greater than x + 1, etc., so set (C) is arranged from least to greatest. Its median is the average of (x+2) and (x+2), which must be (x+2). (x+2) is also the most common number, so the mode of set C is equal to the median of set C.
Question: How many different 3 letter combinations can be created from the letters A,B and C?
A.81
B.3
C.9
D.27
Answer: D.27
Explanation: This is a case of number of arrangements possible with repetition.
Thus you have 3 options each for the 1st,2nd and 3rd letter giving you a total of 3*3*3 = 27 number of possible combinations.
Answer : D
Question: A farmer had d animals, all of which the farmer bought for the same price. The farmer decided to sell the animals. 16 of the animals were sold at a profit of 10% each while the rest were sold at a loss of 20% each. Overall, the farmer made neither a profit nor a loss. Which of the following is equal to d?
A.20
B.24
C.28
D.32
Answer: B.24
Explanation: Let P be the price the farmer paid for each animal.
The total profit on the 16 animals is 16*0.1*P.
The total loss on the other (d-16) animals is (d-16)*0.2*P.
(d-16)*0.2*P = 16*0.1*P
0.2*d = 1.6 + 3.2
d = 24
The answer is B.
Question: How many ways can six girls be selected from a group of ten girls?
A.⁶C₄
B.¹⁰C₄
C.4C₄
D.¹⁰P₄
Answer: B.¹⁰C₄
Explanation: Six members can be selected from ten members in
¹⁰C₆ = ¹⁰C₄ ways
B
Question: What is the sum of the multiples of 4 between 34 and 135 inclusive?
A.2000
B.2100
C.2150
D.2200
Answer: B.2100
Explanation: the fastest way in an AP is to find the average and multiply with total integers..
between 34 and 135, the smallest multiple of 4 is 36 and largest =132..
average=(36+132)/2=84..
total numbers = (132-36)/4 + 1= 24+1=25..
sum=25*84=2100
ans B
Question: A total of $20,000 was invested in two certificates of deposit at simple annual interest rates of 6 percent and 12 percent, respectively. If the total interest on the two certificates was $1,440 at the end of one year, what fractional part of the $20.000 was invested at the higher rate?
A. 3/8
B. 2/5
C. 1/5
D. 3/5
Answer: C. 1/5
Explanation: x * 6/100 * 1 + (20000 - x) * 12/100 * 1 = 1440
6x - 12x = 144000 - 240000
=> -6x = -96000
=> x = 16000
So 4000/20000 = 1/5
Answer - C
Question: How many seconds will a train 70 meters long take to cross a bridge 80 meters long if the speed of the train is 36 kmph?
A.22 sec
B.27 sec
C.25 sec
D.15 sec
Answer: D.15 sec
Explanation: Explanation:
D = 70 + 80 = 150
S = 36 * 5/18 = 10 mps
T = 150/10 = 15 sec
Answer: Option D
Question: Find a two digit number which is doubled and after that add +2 in it. and then reverse the number we would get the actual number.
A.23
B.24
C.25
D.26
Answer: C.25
Explanation: Let the two digit number be 10x+y
Adding 2 after doubling the number is reverse of the number.
So 2(10x+y)+2 = 10y+x
19x -8y +2=0
Above equation satisfies for the value, x=2, y=5
So the number is 10*2+5= 25
ANSWER:C
Question: Ten cards numbered 1 to 10 are placed in a box and then one card is drawn randomly. If it is known that the number on the drawn card is more than 4, what is the probability that it is an even number?
A.1/2
B.1/5
C.1/7
D.1/9
Answer: A.1/2
Explanation: There are 6 numbers higher than 4 and 3 of them are even.
The probability is 3/6=1/2.
The answer is A.
Question: Running at the same constant rate, 6 identical machines can produce a total of 300 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?
A.648
B.1800
C.2000
D.10800
Answer: C.2000
Explanation: Let the required number of bottles be x.
More machines, More bottles (Direct Proportion)
More minutes, More bottles (Direct Proportion)
Machines	6	:	10	:: 300 : x
Time (in minutes)	1	:	4
6 x 1 x x = 10 x 4 x 300
x =	(10 x 4 x 300)/(6)
x = 2000.
ANSWER:C
Question: A mixture of 50 litres of milk and water contains 10% water. How many litres of water should be added to the mixture so that the mixture contains 15% water?
A.15
B.20
C.25
D.30
Answer: C.25
Explanation: Quantity of milk in the mixture = 90/100 (50) = 45 litres.
After adding water, milk would form 60% of the mixture.
Hence, if quantity of mixture after adding x liters of water, (60) / 100 x = 45 => x = 75
Hence 75 - 50 = 25 litres of water must be added.
Answer: C
Question: What is the value of 3x^2 − 1.8x + 0.3 for x = 0.3?
A.−0.3
B.0
C.0.03
D.1.08
Answer: C.0.03
Explanation: 3x^2-1.8x+0.3 for x=0.6
=3(0.3*0.3)-6*0.3*(0.3)+0.3
=-3*0.3*0.3+0.3
=-0.27+0.3
= 0.03
Correct Option : C
Question: How many positive three-digit integers are divisible by both 4 and 5?
A.40
B.42
C.45
D.50
Answer: C.45
Explanation: A number to be divisible by both 4 and 5 should be divisible by the least common multiple of 4 and 5 so by 20.
Multiples of 20 between 100 and 999, inclusive is
(last-first)/multiple+1=(980-100)/20+1=44+1=45
Answer: C.
Question: A can finish a piece of work in 5 days. B can do it in 10 days. They work together for two days and then A goes away. In how many days will B finish the work?
A.4
B.5
C.6
D.8
Answer: A.4
Explanation: 2/5 + (2 + x)/10 = 1 => x = 4 days
Answer: A