RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A coin is tossed live times. What is the probability that there is at the least one tail?
A.31/32
B.31/36
C.31/30
D.31/36
Answer: A.31/32
Explanation: Let P(T) be the probability of getting least one tail when the coin is tossed five times.
= There is not even a single tail.
i.e. all the outcomes are heads.
= 1/32 ; P(T) = 1 - 1/32 = 31/32
Answer:A
Question: A department of ten people - five men and five women - needs to send a team of five to a conference. If they want to make sure that there are no more than three members of the team from any one gender, how many distinct groups are possible to send?
A.100
B.126
C.200
D.252
Answer: C.200
Explanation: We are given 5 men and 5 Women, out of which we need to select 5 People such that no more than 3 of any gender are selected.
So, We can have Either 3 Men + 2 Women Selected or 2 Men + 3 Women Selected.
Thus, Number of ways for selecting 3 Men + 2 Women = 5C3 * 5C2 = 10*10=100
AND Number of ways for selecting 2 Men + 3 Women = 5C2 * 5C3 = 10*10=100
Thus, total ways to get the distinct groups will be 100+100=200.
Hence, Ans will be C.
Question: An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is
A.2%
B.2.02%
C.4%
D.4.04%
Answer: D.4.04%
Explanation: 100 cm is read as 102 cm.
A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.
(A2 - A1) = [(102)2 - (100)2]
= (102 + 100) x (102 - 100)
= 404 cm2.
Percentage error = [(404/100x100)x 100]%
= 4.04%
Answer : D
Question: A man decides to buy a nice horse. He pays $60 for it, and he is very content with the strong animal. After a year, the value of the horse has increased to $70 and he decides to sell the horse. However, already a few days later he regrets his decision to sell the beautiful horse, and he buys it again. Unfortunately, he has to pay $80 to get it back, so he loses $10. After another year of owning the horse, he finally decides to sell the horse for $90.
What is the overall profit the man makes?
A.$70
B.$70
C.$20
D.$89
Answer: C.$20
Explanation: C
$20
n the first trade, the man buys something for $60 and sells it again for $70, so he makes a profit of $10.
In the second trade, the man buys something for $80 and sells it again for $90, so he makes again a profit of $10.
Conclusion: The man makes an overall profit of $10 + $10 = $20.
You can also look at the problem as follows: the total expenses are $60 + $80 = $140 and the total earnings are $70 + $90 = $160. The overall profit is therefore $160 - $140 = $20.
Question: A company that ships boxes to a total of 12 distribution centers uses color coding to identify each center. If either a single color or a pair of two different colors is chosen to represent each center and if each center is uniquely represented by that choice of one or two colors, what is the minimum number of colors needed for the coding? (assume that the order of the colors in a pair does not matter)
A.4
B.5
C.6
D.12
Answer: B.5
Explanation: Back-solving is the best way to solve this problem.
You basically need 12 combinations (including single colors)
If we start from option 1->
1=> 4C2 + 4 = 10 (Not enough)
2=> 5C2 + 5 = 15 (Enough)
Since the minimum number is asked. It should be 5.
Answer - B
Question: A student's mark was wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by
1/2. What is the number of students in the class?
A.45
B.40
C.35
D.30
Answer: B.40
Explanation: Explanation:
Let the total number of students = x
The average marks increased by 1/2 due to an increase of 83 - 63 = 20 marks.
But total increase in the marks = 1/2×x=x/2
Hence we can write as
x/2=20
⇒x=20 x 2=40
Answer: Option B
Question: A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.286 m
B.350 m
C.277 m
D.278 m
Answer: B.350 m
Explanation: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.
Answer:B
Question: Anne traveled from City A to City B in 4 hours, and her speed was between 29 miles per hour and 61 miles per hour. John traveled from City A to City B along the same route in 2 hours, and his speed was between 50 miles per hour and 61 miles per hour. Which of the following could be the distance, in miles, from City A to City B?
A.95
B.115
C.125
D.120
Answer: D.120
Explanation: Using the given options,
A.95. If distance=95 miles, and Anne takes 4 hours, then her speed=95/4=23.xx(Her speed is b/w 25 and 45 miles per hour) . So this is out
B 115. If distance=115 miles, and Anne takes 4 hours, then her speed=115/4=28.75 (Her speed is b/w 25 and 45 miles per hour) . So this is out
C 125 if distance is 125 and anne takes 4 hours her speed is 125/4=31.5, ok. Bob travels 125/2 hours or 62.5 mph this is too high
D 120 if distance is 120 and anne takes 4 hours her speed is 120/4=30, ok. Bob travels 120/2 hours or 60 mph this is also good.
D is the answer
Question: Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Seven years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?
A.A)84
B.B)89
C.C)67
D.D)56
Answer: A.A)84
Explanation: Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then,	(5x + 7/4x + 7)=11/9
9(5x + 7) = 11(4x + 7)
45x + 63 = 44x + 77
45x - 44x = 77 - 63
x = 14.
Anand's present age = 4x = 84 years.
Answer:A
Question: John walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 8 minutes earlier. How far is the office from his house?
A.3 2/5 Km
B.3 1/5 Km
C.3 1/7 Km
D.4 1/5 Km
Answer: B.3 1/5 Km
Explanation: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 16/6
= 24/2 * 16/60
= 8 * 2/5
= 16/5 = 3 1/5 Km
B)
Question: John purchased 8kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper?
A.1045
B.1050
C.1055
D.1060
Answer: C.1055
Explanation: Cost of 8 kg grapes = 70 × 8 = 560.
Cost of 9 kg of mangoes = 55 × 9 = 490.
Total cost he has to pay = 560 + 490 = 1055
C
Question: Ram professes to sell his goods at the cost price but he made use of 800 grms instead of a kg, what is the gain percent?
A.25%
B.11 1/8%
C.11 9/9%
D.11 5/9%
Answer: A.25%
Explanation: 800 --- 200
100 --- ? => 25%
Answer:A
Question: Find the cost of fencing around a circular field of diameter 30 m at the rate of Rs.2 a meter?
A.100.5
B.188.5
C.190.5
D.168.5
Answer: B.188.5
Explanation: 2 * 22/7 * 15 = 94.25
94.25 * 2 = Rs.188.5
Answer: B
Question: Jayant opened a shop investing Rs. 30,000. Madhu joined him 2 months later, investing Rs. 45,000. They earned a profit of Rs. 58,000 after completion of one year. What will be Madhu's share of profit?
A.Rs. 27,000
B.Rs. 24,000
C.Rs. 30,000
D.Rs. 29,000
Answer: D.Rs. 29,000
Explanation: 30,000 *12=45,000*8
1:1
Madhu's share=1/2*58,000
i.e. Rs. 29,000
ANSWER:D
Question: A can contains a mixture of liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter of liquid A was contained by the can initially?
A.10
B.20
C.21
D.25
Answer: C.21
Explanation: Using the values here might be the most straightforward way for this question.
As A:B::7:5 ---> only option C is a multiple of 7 and hence it is a good place to start. Also A:B::7:5 means that , A = (712)*Total and B = (5/12)*Total
If A = 21 , B = 15 ---> remove 9 litres ---> you remove (7/12)*9 of A ---> A remaining = 21-(7/12)*9 = 63/4
Similarly, for B, you remove (5/12)*9 ---> B remaining = 15 - (5/12)*9 = 45/4 and then add 9 more litres of B ---> 9+45/4 = 81/4
Thus A/B (final ratio) = (45/4)/(81/4) = 7:9 , the same as the final ratio mentioned in the question.
Hence C is the correct answer.
FYI, the algebraic equations will become:
A/B = 7/9 = (7x-(7/12)*9)/ (5x-(5/12)*9+9), where 7x and 5x are initial quantities of A and B respectively.
Thus, 7/9 = (7x-(7/12)*9)/ (5x-(5/12)*9+9) ---> giving you x=3. Thus A (original) = 7*3 = 21.
ANSWER:C
Question: Using all the letters of the word "THURSDAY", how many different words can be formed?
A.7
B.8!
C.8
D.7!
Answer: B.8!
Explanation: Explanation:
Total number of letters = 8
Using these letters the number of 8 letters words formed is ⁸P₈ = 8!.
Answer: Option B
Question: 38 69 22 73 31 47 13 52
Which of the following numbers is greater than three fourths of the numbers but less than one fourth of the numbers in the list above?
A.41
B.68
C.67
D.69
Answer: C.67
Explanation: Arrange the numbers in ascending order:
13, 22, 31, 38, 47, 52, 69, 73 (Just cross check the count to ensure that you didn't miss anything)
How many numbers do we see?
8, alright.
What's (1/4)8?
2.
What's (3/4)8?
6.
We're asked to find a number that are greater than 6 numbers in the list AND smaller than the remaining two.
13, 22, 31, 38, 47, 52, 69,73
13, 22, 31, 38, 47, 52: Find a number greater than any of these numbers.
69, 73: Find a number smaller than any of these numbers.
Only 67 fits the description.
Ans:C
Question: Judges will select 4 finalists from the 8 contestants entered in a singing competition. The judges will then rank the contestants and award prizes to the 3 highest ranked contestants: a blue ribbon for first place, a red ribbon for second place, and a yellow ribbon for third place. How many different arrangements of prize-winners are possible?
A.10
B.21
C.280
D.420
Answer: C.280
Explanation: First Select 5 from 7 contestants and then select top 3 from those 5 =
8C4*4C3 = 70 * 4 = 280
ANS:C
Question: Jack has two dice, one has six equally probable sides, labeled 1, 2, 3, 4, 5, 6, and the other has seven equally probable sides, labeled 1, 2, 3, 4, 5, 6, 7. If Jack rolls both dice what is the probability that both of the numbers will be 3?
A.3/14
B.2/7
C.1/3
D.1/42
Answer: D.1/42
Explanation: METHOD-1
Probability that the number on first die is 3 = 1/6
Probability that the number on Second die is 3 = 1/7
Probability that Both Dice result in odd numbers = (1/6)*(1/7) = 1/42
Answer: Option D
Question: 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.120 only. Menâ€™s wages are?
A.6Rs
B.7Rs
C.8Rs
D.4Rs
Answer: C.8Rs
Explanation: 5M = xW = 8B
5M + xW + 8B ----- 120 Rs.
5M + 5M + 5M ----- 120 Rs.
15M ------ 120 Rs. => 1M = 8Rs.
Answer:C
Question: Three 6 faced dice are thrown together. The probability that all the three show the same number on them is ?
A.1/37
B.1/36
C.1/38
D.1/11
Answer: B.1/36
Explanation: It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36
Answer:B
Question: The value of a machine depreciates at 20% per annum. If its present value is Rs. 1,50,000, at what price should it be sold after two years such that a profit of Rs. 24,000 is made?
A.Rs.1,20,050
B.Rs.1,20,000
C.Rs.1,20,008
D.Rs.1,22,000
Answer: B.Rs.1,20,000
Explanation: The value of the machine after two years
= 0.8 * 0.8 * 1,50,000
= Rs. 96,000
SP such that a profit of Rs. 24,000 is made
96,000 + 24,000
= Rs.1,20,000
Answer: B
Question: Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
A.9
B.10
C.12
D.20
Answer: B.10
Explanation: Due to stoppages, it covers 9 km less.
Time taken to cover 9 km =(9/54x 60)min	= 10 min.
Answer :B
Question: If x is an odd negative integer and y is an even integer, which of the following statements must be true? I. (3x + 2y) is positive integer II. (xy)^2 is positive integer III. (y^2 - x) is negative integer
A.I only
B.II only
C.III only
D.I,II only
Answer: B.II only
Explanation: I. It is true if 3x < 2y
II. It is always positive
III. It is not true
Answer : B
Question: 9 basketball players are trying out to be on a newly formed basketball team. Of these players, 5 will be chosen for the team. If 6 of the players are guards and 3 of the players are forwards, how many different teams of 3 guards and 2 forwards can be chosen?
A.23
B.30
C.42
D.60
Answer: D.60
Explanation: Out of 6 gaurds we have to select 3 -> selection means we use C -> so 6C3
Out of 3 forwards we have to select 2 -> selection means we use C -> so 3C2
Total ways = 6C3 x 3C2 = 60
ANSWER:D
Question: Six children — A, B, C, D, E, and F — are going to sit in six chairs in a row. Child E must be somewhere to the left of child F. How many possible configurations are there for the children?
A.60
B.180
C.240
D.360
Answer: D.360
Explanation: F is in first position from the right, then the rest 5 positions can be filled in 5! ways=120
If F is in Second position; then the first position can be filled in 4 ways, and the rest 4 positions in 4! ways; i.e. 24*4=96
If F is in Third position; then the first and second position can be filled in 4 and 3 ways, and the rest 3 positions in 3! ways; i.e. 4*3*3!=72
If F is in Fourth position; then the first, second and the third position can be filled in 4, 3, and 2 ways ways, and the rest 2 positions in 2! ways; i.e. 4*3*2*2!=48
If F is in Fifth position; then the first, second third and the fourth position can be filled in 4, 3, 2 and 1 way, and the rest 1 positions in 1! ways; i.e. 4!=24
Hence, answer should be 360. answer D
Question: If the first day of a year (other than leap year) was Tuesday, then which was the last day of that year?
A.Saturday
B.Friday
C.Tuesday
D.Monday
Answer: C.Tuesday
Explanation: Explanation :
Given that first day of a normal year was Tuesday
Odd days of the mentioned year = 1 (Since it is an ordinary year)
Hence First day of the next year = (Tuesday+ 1 Odd day) = Wednesday
Therefore, last day of the mentioned year = Tuesday. Answer : Option C
Question: If f(x)= 5x^2- 2x+6 and g(y)= 3y-6, then g(f(x))
A.82x^2-9x+38
B.15x^2-6x+12
C.58x^2-4x+58
D.87x^2-5x+96
Answer: B.15x^2-6x+12
Explanation: g(f(x))=3(5x^2-2x+6)-6
=15x^2-6x+18-6
=15x^2-6x+12
the answer is B
Question: Bullock likes to keep a spare tyre in his car every time. On a certain day, he travels 1, 00,000 km and just to make the most of all the tyres, he changes the tyres between his journey such that each tyre runs the same distance.
What is the distance traveled by each tyre?
A.75000
B.80000
C.90000
D.67800
Answer: B.80000
Explanation: B
80,000.
The distance traveled by each tyre:
4/5 * 1, 00, 000km = 80,000 km.
Question: If x/y = 0.3, then (2x - y)/(2x + y) = ?
A.0.25
B.0.5
C.0.4
D.0.45
Answer: A.0.25
Explanation: Explanation:
x = 0.3y
Then, (y - 2x)/(y + 2x)
= y - 2(0.3y)/y + 2(0.3y)
= y - 0.6y/y + 0.6y
= 0.4y/1.6y
= 0.4/1.6 = 0.25
Answer: Option A
Question: Suppose you want to buy three loaves of bread that cost $1.50 each
and a jar of peanut butter that costs $4. A jar of jelly is $2.75, but you
don’t need any jelly. You have $10. How much money will you have left
over?
A.$1.50
B.$2.50
C.$3.50
D.$4.50
Answer: A.$1.50
Explanation: The jelly is extra information. 10.00 – 3 x 1.50 – 4.00 =
10.00 – 4.50 – 4.00 = 1.50.
You have $1.50 left.
correct answer A
Question: The side of a rhombus is 28 m and length of one of its diagonals is 12 m. The area of the rhombus is?
A.326.2
B.324.2
C.328.2
D.338.2
Answer: C.328.2
Explanation: area of the rhombus = 1/2 * p * √4(a)2 - (p)2
a= 28 ; p = 12
A=1/2 * 12 *√4(28)2 - (12)2
=1/2 * 12 *√3136 - 144
=1/2 * 12 *√2992
A =328.2
Answer : C
Question: From the set of numbers x, y, t, z and w, how many different combinations can we have without the t in them? Ex:. (x,y), (x), (w,z,y,x), etc and (x,y)=(y,x)
A.10
B.14
C.15
D.16
Answer: C.15
Explanation: There are 4 letter without t: x, y, z, and w, so:
C14+C24+C34+C44=4+6+4+1=15
Any letter (x, y, z, w) can be included or not. So, we have 2^4 combinations - 1 empty combination = 15 combinations
Answer: C
Question: A number is four less than six times the other number. If the sum of both the number is 38, what are the numbers?
A.6,32
B.7,31
C.5,33
D.4,34
Answer: A.6,32
Explanation: that numbers are x,6x-4
so sum =x+6x-4=38
7x=42 ==> x=6
another no is 32
answer is 6, 32
ANSWER:A
Question: How many digits are in (8×10^8)(10×10^10)?
A.20
B.25
C.26
D.27
Answer: A.20
Explanation: The question simplfies to (8×10^8)(10^11)
=> 8*10^19
=> Will contain 19 zeros +1 digit 8
=>20
Ans A
Question: In a 200 meters race A beats B by 35 m or 7 seconds.A’s time over the course is :
A.40 sec
B.47 sec
C.33 sec
D.35 sec
Answer: C.33 sec
Explanation: Solution
B runs 35 m in 7 sec.
∴ B covers 200 m in (7/35x200) =40 sec
B’s time over the course = 40 sec.
∴ A’s time over the course = (40-7)sec =33sec
Answer C
Question: In a theatre all rows have same no. Of . One family buys 10 tickets of first two row. 3 members want to sit in first row and 2 in second row. In how many ways they can be seated.
A.5400
B.5500
C.5600
D.5700
Answer: A.5400
Explanation: 10c3x10c2= 5400
ANSWER:A
Question: If x = y^2, and x and y are positive integers, which of the following could be the value of x?
A.24,336
B.36,847
C.42,007
D.49,003
Answer: A.24,336
Explanation: A square of an integer can have units digit as 0, 1, 4, 5, 6, 9.
B, C, D and E do not have the units digit as 0, 1, 4, 5, 6 or 9. Only option A has the units digit as 6.
Answer: A
Question: The cost per unit of electricity during a 4 year period is as follows:
Year 1, $0.5 per unit;
Year 2, $1.0 per unit;
Year 3, $1.5 per unit;
Year 4, $2 per unit.
If a factory spent equal dollars on electricity each year, what was the average cost of a unit of electricity during the 4 year period?
A.$1.96
B.$0.96
C.$1.56
D.$1.46
Answer: B.$0.96
Explanation: Let money spent each year = $6
Units bought first year = 12
Units bought second year = 6
Units bought third year = 4
Units bought fourth year = 3
Total number of units = 25
Total money spent = 6*4 = 24
Average = 24/25 = 0.96
Answer : B
Question: Divide $600 among A,B in the ratio 1:3. How many $ that A get?
A.$50
B.$500
C.$150
D.$250
Answer: C.$150
Explanation: Sum of ratio terms = 1+3= 4
A = 600*1/4 = $150
Answer is C
Question: A father was as old as his son's present at the time of your birth. If the father's age is 38 years now, the son's age two years back was?
A.17 years
B.12 years
C.14 years
D.16 years
Answer: A.17 years
Explanation: Let the son's present age be x years. Then, (38 - x) = x
2x = 38.
x = 19.
Son's age 2 years back (19 - 2) = 17 years.
A
Question: What will come in place of the x in the following Number series? 18, 22, 30, x ,78, 142
A.23
B.25
C.46
D.49
Answer: C.46
Explanation: (C)
The pattern is +4, +8, +16, +32, +64
So the missing term is = 30 + 16 = 46 .
Question: A can run a kilometer race in 4 1/2 min while B can run same race in 5 min. How many meters start can A give B in a kilometer race, so that the race mat end in a dead heat?
A.150
B.200
C.130
D.100
Answer: D.100
Explanation: A can give B (5 min - 4 1/2 min) = 30 sec start.
The distance covered by B in 5 min = 1000 m.
Distance covered in 30 sec = (1000 * 30)/300 = 100 m.
A can give B 100m start.
ANSWER D
Question: What is the tens digit of 36^10?
A.1
B.3
C.5
D.7
Answer: D.7
Explanation: 36^10 = 6^20
If you type powers of six they end in
6
36
16
96
76
56
the pattern is 3-->1-->9-->7-->5 so for 36 we start with 3-->9-->5-->1-->7 and repeat.
36^10 will come at 7.
Answer D.
Question: The slant height of a right circular cone is 10 m and its height is 8 m. Find the area of its curved surface.
A.30 pi m^2
B.40 pi m^2
C.60 pi m^2
D.80 pi m^2
Answer: C.60 pi m^2
Explanation: l = 10 m
h = 8 m
r = root(i^2-h^2) = root(10^2 - 8^2) = 6 m
curved surface area = pi ri=60 pi m^2
ANSWER C
Question: a and b are two numbers selected randomly from 1,2,3.... 25 what is the probability of a and b are not equal.
A.24/28
B.24/25
C.24/209
D.22/43
Answer: B.24/25
Explanation: Explanation:
Total outcomes = 25 × 25 = 625
Probability of getting a and b are equal= 25 [ ∴ (1,1),(2,2),(3,3).....(25,25)]
Probability of a and b or not equal = 1−256251−25625 = 600625600625 = 24/25
Answer: B
Question: A batsman scored 160 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets.
A.64%
B.66%
C.60%
D.68%
Answer: D.68%
Explanation: Explanation:
Number of runs made by running = 160 - (3 x 4 + 8 x 6)
= 160 - (60)
= 100
Now, we need to calculate 100 is what percent of 160.
=> 100/160 * 100 = 68
Option D
Question: A hall is 15 m long and 12 m broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume of the hall is
A.2451
B.1200
C.1234
D.5874
Answer: B.1200
Explanation: Explanation:
2(15 + 12) x h = 2(15 x 12)
h =	180/27m =20/3m.
Volume =	15 x 12 x	20/3	m	= 1200 m^3.
Ans: B
Question: A man buys Rs. 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:
A.22
B.15
C.66
D.88
Answer: B.15
Explanation: Explanation:
Dividend on Rs. 20 = Rs. (9/100)x 20 = Rs.9/5.
Rs. 12 is an income on Rs. 100.
Rs.9/5 is an income on Rs.[ (100/12) x (9/5)] = Rs. 15.
Answer: B) 15
Question: The average of 10 numbers is calculated as 15. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is?
A.44
B.87
C.16
D.88
Answer: C.16
Explanation: 10 * 15 + 36 – 26
= 160/10
= 16
Answer:C
Question: Shawn invested one half of his savings in a bond that paid simple interest for 2 years and received $550 as interest. He invested the remaining in a bond that paid compound interest, interest being compounded annually, for the same 2 years at the same rate of interest and received $605 as interest. What was the value of his total savings before investing in these two bonds?
A.$2,750
B.$5,500
C.$11,000
D.$22,000
Answer: A.$2,750
Explanation: SI for 1st year = 550/2=275
275+275+SI on (275)=605==> SI on 275=55==>
SI on 275 = 275*R*1/100=55
R=20%
Now using SI for 2 years on T/2 of the money
(T/2)*20*2/100=550
T=550*5= 2750
ANSWER:A
Question: Find the compound interest accrued on an amount of Rs.14,800 at 13.5% p.a at the end of two years. (Round off your answer to nearest integer)
A.4299
B.4228
C.4287
D.4266
Answer: D.4266
Explanation: CI = 14800{ [ 1 + 13.5/100]2 - 1 }
= 14800 { [1 + 27/200]2 - 1
= 14800 { 2 + 27/200}{27/200}
= (74)[2 + 27/200](27) =
1998[2 + 27/200] = 3996 + 269.73
= Rs.4266
Answer: D
Question: A local bank that has 23 branches uses a two-digit code to represent each of its branches. The same integer can be used for both digits of a code, and a pair of two-digit numbers that are the reverse of each other (such as 17 and 71) are considered as two separate codes. What is the fewest number of different integers required for the 23 codes?
A.3
B.4
C.6
D.5
Answer: D.5
Explanation: Pick any two integer.
Integers: 12
Code: 11, 12, 21, 22 = 4 Codes
Add one more integer: 3
13, 31, 33, 23, 32 = 5 Codes
Add one more integer: 4
44, 14, 41, 24, 42, 34, 43 = 7 Codes
Add one more integer: 5
55, 15, 51, 25, 52, 35, 53,54,45 = 9 Codes
Total = 25 Codes. Enough.
Answer: D
Question: Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 35000. What was Simran's share in the profit?
A.Rs. 9423
B.Rs. 10,250
C.Rs. 12,500
D.Rs. 15,000
Answer: D.Rs. 15,000
Explanation: Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran's share = 35000 * 3/7 = Rs. 15000
ANSWER:D
Question: What is the least number of squares tiles required to pave the floor of a room 2 m 25 cm long and 1 m 35 cm broad?
A.15
B.20
C.40
D.44
Answer: A.15
Explanation: Length of largest tile = H.C.F. of 225 cm and 135 cm = 45 cm.
Area of each tile = (45 x 45) cm2.
Required number of tiles =225 x 135/(45^2)= 15.
ANSWER:A
Question: X can finish a work in 20 days. Y can finish the same work in 15 days. Yworked for 9 days and left the job. how many days does X alone need to finish the remaining work?
A.3
B.5
C.6
D.8
Answer: D.8
Explanation: Work done by X in 1 day = 1/20
Work done by Y in 1 day = 1/15
Work done by Y in 9 days = 9/15 = 3/5
Remaining work = 1 – 3/5 = 2/5
Number of days in which X can finish the remaining work = (2/5) / (1/20) = 8
D