RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: √7 percent of 7√7 =
A.0.55
B.0.96
C.0.1
D.0.45
Answer: D.0.45
Explanation: The other solutions are great, but here's one more approach.
First, we scan the answer choices to see that they are quite spread apart. This means we can also use someAPPROXIMATION
All test-takers must memorize the following approximations:
√2 ≈ 1.4
√3 ≈ 1.7
√5 ≈ 2.2
√6 ≈ 2.4
√7 ≈ 2.6
So, √7 percent of 7√7 ≈ 2.6 percent of (7)(2.6)
≈ (2.6/100)(18.2)
≈ 47.32/100
≈ 0.47
Check the answer choices to see that D is the only answer that's close.
Answer: D
Question: The average amount with a group of seven numbers is Rs. 30. If the newly joined member has Rs. 65 with him, what was the average amount with the group before his joining the group?
A.s. 25.6
B.s. 145/6
C.s. 16.6
D.s. 26
Answer: B.s. 145/6
Explanation: Total members in the group = 7
Average amount = Rs. 30
Total amount with them = 7 * 30 = Rs. 210
One number has Rs. 50. So, the amount with remaining 6 people = 210 - 65 = Rs. 145
The average amount with them = 145/6
ANSWER:B
Question: Find the nearest to 25268 which is exactly divisible by 467?
A.1278
B.8100
C.1287
D.1771
Answer: B.8100
Explanation: Explanation:
900 * 3 * 3 = 8100
Answer: B
Question: BOQD : ERTG :: ANPC : ?
A.DQSF
B.FSHU
C.SHFU
D.DSQF
Answer: A.DQSF
Explanation: BOQD : ERTG::ANPC:DQSF
B-E:+3 A-D:+3
O-R:+3 N-Q:+3
Q-T:+3 P-S:+3
D-G:+3 C-F:+3
ANSWER:A
Question: A 300 m long train crosses a platform in 36 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.288
B.300
C.889
D.276
Answer: B.300
Explanation: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/36 = 50/3
3x + 900 = 1800 => x = 300 m.
Answer:B
Question: The salaries of A, B, and C are in the ratio of 1 : 2 : 3. The salary of B and C together is Rs. 6000. By what percent is the salary of C more than that of A?
A.209%
B.200%
C.290%
D.600%
Answer: B.200%
Explanation: Explanation:
Let the salaries of A, B, C be x, 2x and 3x respectively.
Then,2x + 3x = 6000 => x = 1200.
A's salary = Rs. 1200, B's salary = Rs. 2400, and Cs salary Rs. 3600.
Excess of C's salary over A's=[ (2400 /1200) x 100] = 200%.
Answer: B) 200%
Question: A train consists of 48 boxcars pulled by 2 engines. The boxcars are 15 meters long and the two engines are each 20 meters long. It crosses over a highway 24 meters wide at a speed of 14 m/s. How long does it take for the entire train to cross?
A.56 sec
B.63 sec
C.72 sec
D.81 sec
Answer: A.56 sec
Explanation: A
56 sec
d = 48 * 15 m + 2 * 20 m + 24 m= 784 m
T = 784 m / 14 m/s = 56 s
Question: If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 5:7 then find the largest number?
A.36
B.34
C.40
D.42
Answer: C.40
Explanation: 2:3
2x + 10 : 3x + 10 = 5 : 7
7[2x + 10] = 5[3x + 10]
14x + 70 = 15x + 50
15x - 14x = 70 - 50
x = 20
Then the first number is = 2
2x = 40
Short cut method:
a:b = 2:3
c:d = 5:7
1.Cross multiplication with both ratios
a * d ~ b * c = 2 * 7 ~ 3 * 5 = 14 ~ 15 = 1
2. If 10 is added both the number means 10 * 5 = 50 and 10 * 7 = 70,
Then 50 ~ 70 = 20
===> 1 -----> 20
===> 2 -----> 40 (Answer is = 40)
C
Question: A cyclist covers a distnce of 750 m in 2 min 30 sec. What is the speed in km/hr of the cyclist?
A.28 km/hr
B.18 km/hr
C.20 km/hr
D.22 km/hr
Answer: B.18 km/hr
Explanation: Speed = { 750 } m/sec =5 m/sec = { 5 * 18 } km/hr =18km/hr
Option B
Question: A certain car can travel 40 minutes on a gallon of gasoline at 80 miles per hour. If the car had started with a full tank and had 8 gallons of gasoline left in its tank at the end, then what percent of the tank was used to travel 80 miles at 80 mph?
A.15%
B.16%
C.25%
D.30%
Answer: B.16%
Explanation: Total time for travelling 80 miles @ 60 mph = 80/80 = 1 hour = 60 minutes.
Given, the car uses 1 gallon for every 40 minutes of driving @ 80 mph. Thus in 60 minutes it will use = 1.5 gallons. Thus, full tank = 1.5+8 = 9.5 gallons ---> 1.5/9.5= 16% of the fuel used. B is the correct answer.
Question: A tradesman sold an article at a loss of 10%. If the selling price had been increased by $50, there would have been a gain of 10%. What was the cost price of the article ?
A.$150
B.$200
C.$250
D.$120
Answer: C.$250
Explanation: Let C.P. be $x
Then 110% of x - 90% of x = 50
20% of x = 50
x/5 = 50
x = 250
Answer is C
Question: A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is?
A.6 hrs
B.10 hrs
C.15 hrs
D.30 hrs
Answer: C.15 hrs
Explanation: Suppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x - 5) and (x - 9) hours respectively to fill the tank.
1/x + 1/(x - 5) = 1/(x - 9)
(2x - 5)(x - 9) = x(x - 5)
x2 - 18x + 45 = 0
(x- 15)(x - 3) = 0 => x = 15
ANSWER:C
Question: The tax on a commodity is diminished by 20% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it?
A.22%
B.15%
C.19%
D.12%
Answer: D.12%
Explanation: 100 * 100 = 10000
80 * 110 = 8800
10000------- 1200
100 ------- ? = 12%
Answer:D
Question: Which of the following is a parallelogram?
A.115,65,115,65(angle in deg)
B.120,30,130,20(angle in deg)
C.80,80,80,80(angle in deg)
D.a & c
Answer: A.115,65,115,65(angle in deg)
Explanation: sum of adjacent angles is 180 degrees.
ANSWER:A
Question: Alok ordered 16 chapatis, 5 plates of rice, 7 plates of mixed vegetable and 6 ice-cream cups. The cost of each chapati is Rs.6, that of each plate of rice is Rs.45 and that of mixed vegetable is Rs.70. The amount that Alok paid the cashier was Rs.883. Find the cost of each ice-cream cup?
A.25
B.76
C.29
D.12
Answer: D.12
Explanation: Explanation:
Let the cost of each ice-cream cup be Rs.x
16(6) + 5(45) + 7(70) + 6(x) = 883
96 + 225 + 490 + 6x = 883
6x = 72 => x = 12.
Answer:D
Question: If an item that originally sold for z dollars was marked up by x percent and then discounted by y percent, which of the following expressions T represents the final price of the item?
A.T=(10,000z + 100z(x – y) – xyz)/10,000
B.T=(10,000z + 100z(y – x) – xyz)/10,000
C.T=(100z(x – y) – xyz)/10000
D.(100z(y – x) – xyz)/10000
Answer: A.T=(10,000z + 100z(x – y) – xyz)/10,000
Explanation: -A-
z=Original Price
x=MU
y=MD
New price with MU:
z (x/100+1)
New price with MD:
z[(x/100+1)(-y/100+1)]
Solvingâ€¦
=z[((x+100)/100)((-y+100)/100)]
=z(x100-xy+10000-100y)/10000
=(zx100-xyz+10000z-100yz)/10000 --> similar to A
Question: How many three-digit integers between 313 and 401, exclusive, are divisible by 3 when the tens digit and the hundered digit are switched?
A.3
B.30
C.22
D.29
Answer: B.30
Explanation: Answer is 30
No of digits between 310 and 400 (exclusive) = 401-313-1 = 88
No Intergers divisble by 3 =~ 88/3 ~ 30
Divsiblivity rule for 3 is Sum of all digits must be divisble by 3. It doesn't matter if hundred digit and tens digits are switched.
e.g 372 is divisble by 3 (becae 3+7+2= 12 (divisble by 3))
switch digits 732 also divisble by 3 (becae 7+3+2= 12 (divisble by 3))
Divsiblivity rule for 3 is Sum of all digits must be divisble by 3. It doesn't matter if hundred digit and tens digits are switched.
You have right. So it is enough to proceed like usual to find the numbers in a given range that are divisible by 3. So 399-312/3 +1 =30.
Answer : B
Question: A certain sum of money is divided among A, B and C such that A gets one-third of what B and C together get and B gets two-seventh of what A and C together get. If the amount received by A is $10 more than that received by B, find the total amount shared by A, B and C.
A.$260
B.$360
C.$160
D.$460
Answer: B.$360
Explanation: A = 1/3 (B+C) => C = 3A - B ---(1)
B = 2/7 (A+C) => C = 3.5 B - A --(B)
A-B = $10
A = 10+B
(1)===> C = 30+3B - B = 2B+30 ==> 2B-C = -30 ---(3)
(2)===> C = 3.5 B - B-10 = 2.5B-10==>2.5B-C = 10---(4)
from (4) and (3) 0.5B = 40
B = $80
A= $90
C =270-80=$190 Total amount = 90+80+190 = $360
Answer: B
Question: A sum of money place at compound interest doubles itself in 5 years. In how many years will it amount to eight times itself?
A.12
B.13
C.14
D.15
Answer: D.15
Explanation: 100 ---- 200 ---- 5
400 ---- 5
800 ---- 5
------
15 years
Answer: D
Question: The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages?
A.16, 26, 36
B.16, 28, 36
C.16, 28, 38
D.16, 28, 32
Answer: B.16, 28, 36
Explanation: Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
20x = 80 => x = 4
Their present ages are 16, 28 and 36 years respectively.
Answer: B
Question: During a certain two-week period, 75 percent of the movies rented from a video store were comedies, and of the remaining movies rented, there were 2/3 times as many dramas as action movies. If no other movies were rented during that two-week period and there were A action movies rented, then how many comedies, in terms of A, were rented during that two-week period?
A.5 A
B.10 A
C.15 A
D.18 A
Answer: A.5 A
Explanation: Movies: 75 % comedies. 25 % remaining genre.
Now in this 25 %, there are only 2 categories. Action movies and Drama Movies.
If Action = x; Drama movies = 2x/3. Total 5x/3.
5x/3 = 25; x = 15
Action movies: 15 %
Drama movies: 10 %
we can say that out of 100 z,:
comedies: 75 z
action: 15 z
drama: 10 z
Now action movies were A
This means:
A = 15 z.
z = A/ 15
Comedies: 75 z = 75 * (A/15)
5 A
A is the answer.
Question: The average of Pratyush's marks in 7 subjects is 75. His average in six subjects excluding Science is 72. How many marks did he get in Science?
A.72
B.93
C.99
D.100
Answer: B.93
Explanation: Explanation :
Marks in Science (7*75 - 6*72) = 93.
Answer : B
Question: a, b, c are three distinct integers from 2 to 10 (both inclusive). Exactly one of ab, bc and ca is odd. abc is a multiple of 4. The arithmetic mean of a and b is an integer and so is the arithmetic mean of a, b and c. How many such triplets are possible (unordered triplets) ?
A.3
B.4
C.5
D.2
Answer: B.4
Explanation: Explanation :
Exactly one of ab, bc and ca is odd⇒ Two are odd and one is evenabc is a multiple of 4⇒ the even number is a multiple of 4The arithmetic mean of a and b is an integer⇒ a and b are oddand so is the arithmetic mean of a, b and c.⇒ a+ b + c is a multiple of 3c can be 4 or 8.c = 4; a, b can be 3, 5 or 5, 9c = 8; a, b can be 3, 7 or 7, 9Four triplets are possible
Answer : B
Question: Jamshid and Irwin decided to make up their own version of basketball. In addition to being able to score 2-point baskets, they created ways to score 5-, 11-, and 13-point baskets. If at halftime the product of the point values of Irwin’s baskets was 2,420, how many 11-point baskets W did Irwin score?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: First thing I noticed was that all these numbers are prime...
Prime factorization gives the following
Step 1:2*1210
Step 2:2*11*110
Step 4:2*11*11*10
Step 5:2*11*11*2*5
So he scored W=2 11-point baskets in my opinion.
Answer C
Question: An unbiased die is tossed .find the probability of getting a multiple of 3
A.3/9
B.2/4
C.1/3
D.4/6
Answer: C.1/3
Explanation: . Here S={1,2,3,4,5,6}
Let E be the event of getting the multiple of 3
then ,E={3,6}
P(E)=n(E)/n(S)=2/6=1/3
Ans: C
Question: Two variants of the CAT paper are to be given to 12 students. In how many ways can the students be placed in two rows of six each so that there should be no identical variants side by side and that the students sitting one behind the other should have the same variant. Find the number of ways this can be done
A.2 x 12C6 x (6!)2
B.2 x 6! x 6!
C.2 x 12C6 x 6!
D.2 x 6! x 8!
Answer: A.2 x 12C6 x (6!)2
Explanation: First select 6 people out of 12 for the first row.
The other six automatically get selected for the second row.
Arrange the two rows of people amongst themselves. Besides, the papers can be given a pattern of 121212 or 212121.
Hence the answer is 2 x 12C6 x (6!)2
ANSWER:A
Question: The total age of A and B is 16 years more than the total age of B and C. C is how many year younger than
A.14 years
B.12 years
C.56 years
D.16 years
Answer: D.16 years
Explanation: Given that A+B = 16 + B + C
=> A â€“ C = 16 + B â€“ B = 16
=> C is younger than A by 16 years
Answer:D
Question: Calculate the share of X , if Rs. 1628 is divided among X, Y and Z in the ratio 2 : 3 : 5?
A.321.6
B.325.6
C.305.6
D.125.6
Answer: B.325.6
Explanation: 2 + 3 + 5 =10
1628/10=162.8
so X's share=2*162.8
=325.6
ANSWER:B
Question: Train A leaves the station traveling at 30 miles per hour. Two hours later train В leaves the same station traveling in the same direction at 38 miles per hour. How many miles from the station was train A overtaken by train B?
A.205
B.245
C.285
D.325
Answer: C.285
Explanation: After two hours, Train A is ahead by 60 miles.
Train B can catch up at a rate of 8 miles per hour.
The time to catch up is 60/8 = 7.5 hours.
In 7.5 hours, train A travels another 30*7.5 = 225 miles for a total of 285 miles.
The answer is C.
Question: The entire contents of a full sack of flour can be used to make 15 cupcakes and 8 pizzas. The same full sack of flour can be used to make 3 cupcakes and 14 pizzas. If a full sack of flour is used to make only pizzas, how many pizzas can be made?
A.18 1/4
B.15 1/2
C.18 3/4
D.19
Answer: B.15 1/2
Explanation: 15x+8y=3x+14y
x=1/2y. Answer B
Question: How many integerskgreater than 100 and less than 800 are there such that if the hundreds and the units digits ofkare reversed, the resulting integer is k+99?
A.50
B.60
C.70
D.80
Answer: B.60
Explanation: Numbers will be like 102 => 201 = 102 + 99
203 => 302 = 103 + 99
so the hundereth digit and units digit are consecutive where unit digit is bigger than hundred digit.
There will be six pairs of such numbers
for every pair there will 10 numbers like for 12 => 102, 112,132,142,152, 162,172,182,192.
Total = 6 *10 = 60 hence B.
Question: A table is bought for Rs.600/- and sold at Rs.700/- find gain or loss percentage
A.25% loss
B.30% gian
C.25% gian
D.30% loss
Answer: C.25% gian
Explanation: Explanation:
Formula = (Selling price ~ Cost price)/Cost price * 100
= (700 - 600)/400 = 25% gain
Answer: Option C
Question: A train covers a distance of 12 km in 10 minutes. If it takes 6 seconds to pass a telegraph post, then the length of the train is
A.100m
B.120m
C.140m
D.160m
Answer: B.120m
Explanation: Explanation:
Speed =12/10x 60 km/hr = 72 x5/18m/sec = 20 m/sec.
Length of the train = (Speed x Time) = (20 x 6) m = 120 m
Answer: Option B
Question: Calculate the number of bricks, each measuring 25 cm * 15 cm * 8 cm required to construct a wall of dimensions 10 m * 4 m * 5 m when 10% of its volume is occupied by mortar?
A.4000
B.5000
C.6000
D.7000
Answer: C.6000
Explanation: 10 * 4/100 * 5 * 90/100 = 25/100 * 15/100 * 8/100 * x
10 * 20 * 90 = 15 * 2 * x => x = 6000
ANSWER:C
Question: The sum of the two digits of a number is 10. If the number is subtracted from the number obtained by reversing its digits, the result is 54. Find the number?
A.34
B.28
C.12
D.17
Answer: B.28
Explanation: Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.
P + Q = 10 ----- (1)
(10Q + P) - (10P + Q) = 54
9(Q - P) = 54
(Q - P) = 6 ----- (2)
Solve (1) and (2) P = 2 and Q = 8
The required number is = 28
ANSWER:B
Question: A train covers a distance of 280 km in 4 hrs. What is its speed?
A.70 km/hr
B.60 km/hr
C.50 km/hr
D.40 km/hr
Answer: A.70 km/hr
Explanation: Distance covered =280 km. Time taken =4 hrs. Speed =Distance/time =280/4 km=70 km/hr. Answer : A
Question: The bus that travels from St. Louis to Chicago and back comes to St. Louis every 6 hours while the bus that travels from St. Louis to Springfield and back comes to St. Louis every 2 hours. If at 12:00 o'clock both bused arrived at St. Louis, at what time will they meet in St. Louis again?
A.16:00.
B.18:00
C.20:00
D.22:00.
Answer: B.18:00
Explanation: Time taken by bus to travel from St. Louis to Chicago and back comes to St. Louis = 6 hours
Time taken by bus to travel from St. Louis to Springfield and back comes to St. Louis = 2 hours
Time taken by both buses to meet again in St. Louis will be LCM of 6 and 2 = 6
If the buses start at 12:00 o'clock from St. Louis , they will meet again in St. Louis at 18:00 hours
Answer B
Question: In covering a distance of 30 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:
A.5 km/h
B.8 km/h
C.10 km/h
D.15 km/h
Answer: A.5 km/h
Explanation: Let A's speed be X km/hr.
Then, 30/x - 30/2x = 3
6x = 30
x = 5 km/hr.
Answer : A
Question: In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
A.6.5
B.6.25
C.6.75
D.6.0
Answer: B.6.25
Explanation: Runs scored in the first 10 overs = 10 × 3.2 = 32
Total runs = 282
Remaining runs to be scored = 282 - 32 = 250
Remaining overs = 40
Run rate needed = 25040=6.25
Answer is B.
Question: If three sides of the triangle are 8 , 15 and D respectively then the how many values can D ?
A.[A] 6
B.[B] 7
C.[C] 8
D.[D]9
Answer: D.[D]9
Explanation: Needed: How many Values can D take
Concept: Sum of any two sides of a triangle is greater then the third side.
Case 1: 8+5 > D => D<13
Case 2: 5+D > 8 => D >3
Case 3: 8+D > 5 => D > -3 (Always true since D is one side of a Triangle)
Finally, 3 < D < 13. So, we can have infinite number of sides between 3 and 13.
Answer = E
PS: If question said D can take only integer value, the D = 9. Answer choice D.
Question: Carl is facing very difficult financial times and can only pay the interest on a $10,000 loan he has taken. The bank charges him a quarterly compound rate of 6%. What is the approximate interest he pays annually?
A.$1200
B.$2000
C.$2150
D.$2500
Answer: D.$2500
Explanation: An easy way too attempt this is by approximation:
For the first quarter, he pays 6% of 10,000 which is $600.
So for the four quarters in the year, he will approximately play 600*4=2400 over the entire year.
The compound interest will be more than 2400. All other options are not right except D.
Answer : D
Question: A farmer with 1,350 acres of land had planted his fields with corn, sugar cane, and tobacco in the ratio of 3:2:4, respectively, but he wanted to make more money, so he shifted the ratio to 2:2:5, respectively. How many more acres of land were planted with tobacco under the new system?
A.90
B.150
C.270
D.300
Answer: B.150
Explanation: Originally (4/9)*1350 = 600 acres were planted with tobacco.
In the new system (5/9)*1350 = 750 acres were planted with tobacco.
Thus 750-600 = 150 more acres were planted with tobacco.
The answer is B.
Question: What is the sum of all possible solutions to |x - 2|^2 + |x - 2| = 20 ?
A.-1
B.6
C.7
D.8
Answer: D.8
Explanation: Denote |x - 2| as y: y^2 + y = 20 --> y = -5 or y = 4. Discard the first solution since y = |x - 2|, so it's an absolute value and thus cannot be negative.
y = |x - 2| = 4 --> x = 6 or x = -2. The sum = 8
Answer: D.
Question: Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
A.15
B.16
C.22
D.18
Answer: B.16
Explanation: Work done by Sakshi in 1 day = 1/20
Since Tanya is 25% efficient than Sakshi, she completes 25% more work in a day than Sakshi.
=> Tanya's 1 day work = 1/20 + 1/20 * 25/100 = 1/16
So time taken by Tanya to finish the work = 16 days answer : B
Question: A train speeds past a pole in 15 sec and a platform 100 m long in 25 sec, its length is?
A.228
B.150
C.88
D.17
Answer: B.150
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 100)/25 = x/15 => x = 150 m.
Answer: B
Question: Find the odd man out. 1050, 510, 242, 105, 46, 16, 3
A.46
B.106
C.105
D.1050
Answer: C.105
Explanation: Explanation :
1050
(1050 - 30)/2 = 510
(510 - 26)/2 = 242
(242 - 22)/2 = 110
(110 - 18)/2 = 46
(46- 14)/2 = 16
(16- 10)/2 = 3
Hence, 110 should have come in place of 105. Answer : Option C
Question: A train passes a man standing on a platform in 8 seconds and also crosses the platform which is 270 metres long in 20 seconds. The length of the train (in metres) is:
A.180
B.176
C.175
D.96
Answer: A.180
Explanation: Explanation:
Let the length of train be L m.
Acc. to question
(270+L)/20 = L/8
2160+8L=20L
L= 2160/12 = 180 m
Answer A
Question: If there are 30 numbers and the average of the first 10 numbers is equal to the average of last 20 number what is the sum of last 20 numbers
A.same as the sum of first 10 numbers
B.2 times the sum of first 10 numbers
C.average of first 10 numbers
D.3 times the sum of first 10 numbers
Answer: B.2 times the sum of first 10 numbers
Explanation: avg of first 10 no.s= sum of 10 no./10
avg of last 20 no.s= sum of 20 no./20
as gven in question,
sum of first 10 no./10= sum of last 20 no./20
so asnwr comes b)
2 times sum of first 10 no.s
ANSWER:B
Question: If x#y is defined to equal x/y for all x and y, then (-1#2)#3 =
A.4/3
B.-1/6
C.1/12
D.-1/12
Answer: B.-1/6
Explanation: (-1)/ 2 = -1/2
(-1/2) / 3 = -1/6
so B is my answer
Question: In a St.Johns college students, 50 percent are third year students and 80 percent are not second-year students. What fraction of those students who are not third-year students are second-year students?
A. 3/4
B. 2/5
C. 4/7
D. 1/2
Answer: B. 2/5
Explanation: = 20/50. = 2/5
my answer is B too
Question: The mass of the sun is approximately 2 × 10^30 kg and the mass of the moon is approximately 4 × 10^12 kg. The mass of the sun is approximately how many times the mass of the moon?
A.4.0 × 10^(−18)
B.2.5 × 10^17
C.4.0 × 10^18
D.5 × 10^17
Answer: D.5 × 10^17
Explanation: Mass of sun = x * Mass of moon
x = Mass of sun / Mass of moon = (2 × 10^30) / (4 × 10^12) = 2*2^-2*10^18 = 10^18/2 = 5*10^17
Ans. D) 5 × 10^17
Question: A can run a kilometer race in 4 1/2 min while B can run same race in 5 min. How many meters start can A give B in a kilometer race, so that the race mat end in a dead heat?
A.159 m
B.167 m
C.156 m
D.100 m
Answer: D.100 m
Explanation: A can give B (5 min - 4 1/2 min) = 30 sec start.
The distance covered by B in 5 min = 1000 m.
Distance covered in 30 sec = (1000 * 30)/300 = 100 m.
A can give B 100m start.
Answer: D
Question: While playing a certain dice game, Chris wins if the sum of the two dice is 8, at which point the game is over. If the game allows Chris three rolls in an attempt to win, what is the probability that Chris will win?
A.1/2
B.17/36
C.137/379
D.11/36
Answer: C.137/379
Explanation: Probability of winning game = 1- Probability of losing game
Probability of losing game = (Probability of not getting sum 7 in any of the three attempts)
Ways of getting sum 8 = (2,6)(3,5)(4,4)(5,3)(6,2)= 5 ways
Total ways of getting outcome on two dice =6*6=36
Probability of getting sum as 8 in any attempt =5/36
Probability of NOT getting sum as 8 in any attempt = 1-(5/6)= 31/36
Probability of losing game =(31/36)*(31/36)*(31/36)=242/379
I.e. Probability of wining game = 1-(242/379) = 137/379
Answer : Option C
Question: The population of a town is 10000. It increases annually at the rate of 20% p.a. What will be its population after 1 year?
A.12300
B.12350
C.12000
D.12500
Answer: C.12000
Explanation: Formula :
( After =100 denominator
Ago = 100 numerator)
10000 Ã— 120/100 = 12000
C
Question: The value of x + x(x^x) when x = 10 is
A.100000000010
B.10000000010
C.10000000000
D.1200000000
Answer: A.100000000010
Explanation: Solution:
x + x(x^x)
Put the value of x = 10 in the above expression we get,
10 + 10(10^10)
= 10 + 10(10 Ã— 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10)
= 10 + 10(10000000000)
= 10 + 100000000000
= 100000000010
Answer: (a)
Question: If x is 30 percent more than y and y is 40 percent less than z, then x is what percent of z?
A.78%
B.250%
C.500/3%
D.125%
Answer: A.78%
Explanation: Z = 100 ; Y = 60 so X = 78
X as % of Z = 78/100 * 100 => 78%
Answer will be (A)