RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A sum of Rs.3800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
A.A)282
B.B)2470
C.C)8383
D.D)8383
Answer: B.B)2470
Explanation: Let A be the amount received at the end of the three years.
A = 3800[1 + 10/100][1 + 20/100][1 + 25/100]
A = 3800 * 1.65
A = Rs.6270
So the interest = 6270 - 3800 = Rs.2470
Answer: B
Question: Rs. 6000 is lent out in two parts. One part is lent at 6% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?
A.3750:2250
B.3751:2250
C.3752:2250
D.3760:2250
Answer: A.3750:2250
Explanation: Let the amount lent at 6% be Rs. x
Amount lent at 10% is Rs. (6000 - x)
Total interest for one year on the two sums lent
= 6/100 x + 10/100 (6000 - x) = 600 - 3x/100
=> 600 - 3/100 x = 450 => x = 3750
Amount lent at 10% = 2750
Required ratio = 3750:2750
Answer:A
Question: Two mechanics were working on your car. One can complete the given job in six hours, but the new guy takes 9 hours. They worked together for the first two hours, but then the first guy left to help another mechanic on a different job. How long will it take the new guy to finish your car?
A.7/4
B.32/9
C.15/4
D.10/3
Answer: B.32/9
Explanation: Rate(1)=1/6
Rate(2)=1/9
Combined = 5/18
Work done in 2 days=5/9
Work left = 4/9
Rate * Time = Work left
1/8 * Time = 4/9
Time=32/9
B
Question: P is four times as old as Q, and Q is five years older than R. If R is z years old, what is P’s age in terms of z?
A.4z + 5
B.4z + 20
C.4z - 20
D.(z + 5)/4
Answer: B.4z + 20
Explanation: P = 4Q
Q = R+5 = z+5
P = 4(z+5) = 4z + 20
The answer is B.
Question: A person is traveling at 20 km/hr and reached his destiny in 8 hr then find the distance?
A.180 km
B.200 km
C.160 km
D.220 km
Answer: C.160 km
Explanation: T = 8 hrs
D= T*S = 20*8 = 160 km
Answer is C
Question: In how many ways can 6 apples (identical) be distributed among 5 children? (Some children may get no apples.)
A.124
B.210
C.128
D.130
Answer: B.210
Explanation: Generalised form for n = number of identical objects, and r = number of children is n+r-1Cr-1.
n=6 r= 5
10C4 =210
Answer : B
Question: If Teena is driving at 55 miles per hour and is currently 7.5 miles behind Joe, who is driving at 40 miles per hour in the same direction then in how many minutes will Teena be 52.5 miles ahead of Joe?
A.15
B.240
C.75
D.90
Answer: B.240
Explanation: This type of questions should be solved without any complex calculations as these questions become imperative in gaining that extra 30-40 seconds for a difficult one.
Teena covers 55 miles in 60 mins.
Joe covers 40 miles in 60 mins
So teena gains 15 miles every 60 mins
Teena need to cover 7.5 +52.5 miles.
Teena can cover 7.5 miles in 30 mins
Teena will cover 52.5 miles in 210 mins
So answer 30+210= 240 mins. (ANSWER B)
Question: What is the rational number for recurring decimal 0.890890890.... ?
A.890890/1000
B.67/421
C.890/999
D.None of these
Answer: C.890/999
Explanation: Explanation :
0.890890890.... = 0.890¯=890/999. Answer : Option C
Question: If each side of a rectangle is increased by 100%, by what % the area increases?
A.100%
B.200%
C.250%
D.300%
Answer: D.300%
Explanation: if length is l and width is b then area=l*b
now new l and b is 2l and 2b respectively.
so new area is=4*l*b
% increase= 300%
ANSWER:D
Question: A man saves Rs 250 at the end of each year and lends the money at 5% compound interest. How
much will it become at the end of 3 years.
A.Rs 662
B.Rs 862.01
C.Rs 827.53
D.Rs 686.53
Answer: C.Rs 827.53
Explanation: Explanation:
=[250(21/20×21/20×21/20)+250(21/20×21/20)+250(21/20)]=827.53
Answer: C
Question: If x/y = 2/z, then 5x^2 =
A.y/z
B.20y²/z²
C.y²z²
D.5y²/z²
Answer: B.20y²/z²
Explanation: This question is most easily solved by isolating y in the equation and substituting into the expression 5x²:
x/y = 2/z
x = 2y/z
If we substitute 2y/z into the expression for x, we get:
5(2y/z)² = 5(4y²/z²) = 20y²/z².
The correct answer is choice (B)
Question: P, Q and R can do a work in 20, 30 and 60 days respectively. How many days does it need to complete the work if P does the work and he is assisted by Q and R on every third day?
A.10 days
B.14 days
C.15 days
D.9 days
Answer: C.15 days
Explanation: Explanation :
Amount of work P can do in 1 day = 1/20
Amount of work Q can do in 1 day = 1/30
Amount of work R can do in 1 day = 1/60
P is working alone and every third day Q and R is helping him
Work completed in every three days = 2 × (1/20) + (1/20 + 1/30 + 1/60) = 1/5
So work completed in 15 days = 5 × 1/5 = 1
Ie, the work will be done in 15 days
Answer : Option C
Question: A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
A.10/21
B.11/21
C.2/7
D.5/7
Answer: A.10/21
Explanation: Total number of balls = (2 + 3 + 2) = 7.
Let S be the sample space.
Then, n(S)	= Number of ways of drawing 2 balls out of 7
= 7C2 `
=(7 x 6)/(2 x 1)
= 21.
Let E = Event of drawing 2 balls, none of which is blue.
n(E)	= Number of ways of drawing 2 balls out of (2 + 3) balls.
= 5C2
=(5 x 4)/(2 x 1)
= 10.
P(E) =n(E)/n(S)=10/21
Answer :A
Question: In the biology lab of "Jefferson" High School there are 6.48*10^6 germs, equally divided among 10,800 Petri dishes. How many germs live happily in a single dish?
A.100
B.200
C.500
D.600
Answer: D.600
Explanation: 6.48*10^6/ 10800==> 64.8*10^3/108==> 64800/108= 600
ANSWER:D
Question: Of the science books in a certain supply room, 41 are on botany, 65 are on zoology, 90 are on physics. 50 are on geology, and 100 are on chemistry. If science books are removed randomly from the supply room, how many must be removed to ensure that 80 of the books removed are on the same science?
A.81
B.159
C.166
D.315
Answer: D.315
Explanation: First, you can take all 41 Botany books, all 65 zoology books and all 50 geology books because you're sure to never pick 80 of them.
There are still 90 on physics and 100 on chemistry
The worst case could be that we pick 79 physics and 79 chemistry. So that the next book picked will necessary complete 80 books picked, either in physics or chemistry.
Minimum number of books picked to reach 80 in the same science should be : 41 + 65 + 50 + 79 +79 + 1 = 315
D
Question: Tom read a book containing 480 pages by reading the same number of pages each day. If he would have finished the book 2 days earlier by reading 16 pages a day more, how many days did Tom spend reading the book?
A.12
B.15
C.10
D.20
Answer: A.12
Explanation: Actually u can set up 2 equation
P--stands for the pages
D--stands for the days
1) P*D=480 (we want to find the Days, soP=480/D)
2) (P+16)(D-2)=480 => PD-2P+16D-32=480
as the 1) stated u can put 1) into 2)
=> 480-2P+16D-32=480 => 16D-2P=32
put the bold one into it => 16D-2(480/D)=80
the we get the final equation 16D^2-960=80D (divide 16)
=> D^2-5D-60=0
(D-12)(D+5)=0 so D=12 days Ans: A
Question: If 625(5^x) = 1 then x=
A.–2
B.-4
C.0
D.-1
Answer: B.-4
Explanation: 5^x = 1/625
5^x = 1/5^4
5^x= 5^-4
x = -4
B
Question: Ten years ago, P was half of Q's age. If the ratio of their present ages is 3:4, what will be the total of their present ages?
A.35
B.38
C.37
D.36
Answer: A.35
Explanation: Let present age of P and Q be 3x and 4x respectively.
Ten years ago, P was half of Q's age
⇒(3x−10)=12(4x−10)⇒6x−20=4x−10⇒2x=10⇒x=5
Total of their present ages
=3x+4x=7x=7×5=35
Answer is A.
Question: (2^2+4^2+6^2+.....+40^2)=?
A.11480
B.76868
C.57898
D.68886
Answer: A.11480
Explanation: =(1x2)^2+(2x2)^2,+(2x3)^3+......(2x20)^2
=2^2 x (1^2+2^2+3^2+.......+20^2)
formula is =1/6 n(n+1)(2n+1)
=(4x1/6x20x21x41)
=(4x2870)=11480
Answer is A
Question: Using all the letters of the word "THURSDAY", how many different words can be formed?
A.8
B.8!
C.7!
D.7
Answer: B.8!
Explanation: Explanation:
Total number of letters = 8
Using these letters the number of 8 letters words formed is â¸Pâ‚ˆ = 8!.
ANSWER IS B
Question: A box contains 3 red chips and 2 blue chips. If two chips are selected at random without replacement, what is the probability that the chips are different colors?
A.1/2
B.3/5
C.7/12
D.2/3
Answer: B.3/5
Explanation: Total selection ways: 5C2=5!/2!3!=10
Selecting one blue chip out of two: 2C1=2!/1!1!=2
Selecting one red chip out of four: 3C1=3!/2!1!=3
Thus, (2C1*3C1)/5C2=(2*3)/10=6/10=3/5=B
Question: Two integers are in the ratio of 1 to 4. If 6 is added to the smaller number, the ratio becomes 1 to 2. Find the larger integer.
A.4
B.6
C.12
D.24
Answer: D.24
Explanation: Assume the integers to be x and y, where x < y
Given x/y = 1/4 - (i) or y = 4x
and x+6 / y = 1/2 - (ii) or y = 2x + 12
Substituting the value of y from (i), 4x = 2x + 12
x = 6
Hence y = 4*6 = 24
ANSWER D
Question: In the x-y plane, point (x, y) is a lattice point if both x and y are integers. Circle C has a center at (-2, -2) and a diameter of 8. Some points, such as the center (-2, -2), are inside the circle, but a point such as (-2, 2) is on the circle but not in the circle. How many lattice points are in circle C?
A.40
B.10
C.73
D.60
Answer: C.73
Explanation: The lattice points that are in the circle that lie on the perspective axes is as follows: since the diameter is 8, 9 points lie on the horizontal axis (8 + center), but the end points are not in the circle, so 9 - 2 (the same for the vertical axis, but don't count center again), 7 - 1. The lattice points in the circle and not on the horizontal and vertical axes is as follows: lattice points can be found at 45, 45/2 and 30 degrees of axes (30 and 45/2 degrees from horizontal and vertical axes), so same numbers as before, but don't count center again. So, 13 + 5 * 12 = 73
There are a total of 73 lattice points in the circle.
Answer: C
Question: A and B enter into partnership with capitals in the ratio 3 : 4. At the end of 10 months A withdraws,and the profits now are divided in the ratio of 5 : 6. Find how long B remained in the business?
A.9 months
B.8 months
C.6 months
D.7 months
Answer: A.9 months
Explanation: Initially A’s investment = 3x and B’s investment = 4x
Let B remain in the business for ‘n’ months.
⇒ 3x × 10 : 4x × n = 5 : 6
∴ 3x × 10 × 6 = 4x × n × 5
⇒ n = 9
Answer A
Question: 8103/x is a non-terminating decimal. Which of the following could be a value of x?
A.2
B.5
C.9
D.12
Answer: C.9
Explanation: Then:
c. 9=3*3
d. 12=3*2*2
e. 15=3*5
The sum of digits in 8103 is 12, it means that 8103 is divisible by 3 (i.e. 3 is one of the factors of 8103), which will eliminate one "3" from x, leaving us with only 2's or 5's in options d. and e. Only c is left.
ANSWER:C
Question: (208% of 1265) ÷ 6 = ?
A.A)125
B.B)439
C.C)225
D.D)375
Answer: B.B)439
Explanation: Explanation :
? = (208 x 1265/100) ÷ 6 = 263120/600 = 439
Answer : Option B
Question: Bill downloads the movieRevenge of the Avengersto his computer in 2.5 hours, using a download manager that downloads from 3 sources marked A, B and C. Each source provides download at a constant rate, but the rates of different sources are not necessarily identical. If the movie was downloaded from sources A and C alone, it would take 4 hours to complete the download. The next day, source B is available, but the other sources are inactive. How long will it take to download the trailer of the movie, a file that is 50 times smaller, from source B alone?
A.6 hours and 40 minutes
B.8 minutes
C.12 minutes
D.10 minutes
Answer: B.8 minutes
Explanation: Let the movie size be 400 u.
Given,A+C=4 hrs.
A+C=100 u/hr
And A+B+C=2.5 hrs or 400/2.5=160 u/hr
B alone=160-100=60 u/hr
Trailer=40 times smaller or400/50=8 u
B will take 8/60 hrs or 8 minutes.
Ans B
Question: A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 6600. What is the share of B ?
A.1100
B.800
C.1400
D.1200
Answer: D.1200
Explanation: Let C's capital = Rs. x. Then, B's capital = Rs. (2/3)x
A’s capital = Rs. (3 x (2/3).x) = Rs. 2x.
Ratio of their capitals = 2x : (2/3)x :x = 6 : 2 : 3.
Hence, B's share = Rs. ( 6600 x (2/11))= Rs. 1200.
Answer is D.
Question: The average salary of all the employees in a small organization is Rs 8,000. The average salary of 7 technicians is Rs 12,000 and the average salary of the rest is Rs 6,000. The total number of employees in the organisation is?
A.21
B.20
C.26
D.22
Answer: C.26
Explanation: Let total number of employees be X.
Then, 8000 x X = 7 x 12000 + (X - 7) x 6000
X = 26.
Thus, the total number of employees in the organization is 26.
ANSWER:C
Question: In a stack of boards at a lumber yard, the 24th board counting from the top of the stack is immediately below the 14th board counting from the bottom of the stack. how many boards are in the stack?
A.36
B.46
C.55
D.54
Answer: A.36
Explanation: 1 2 3 ... 14 15 16 ...................
..............24 23 ................. 1
So the number of boards = 24+12 =36
Option: A
Question: A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 245, then how much amount should C pay as his share of rent?
A.35
B.45
C.25
D.63
Answer: D.63
Explanation: A : B : C
=10×7:12×5:15×3
=2×7:12×1:3×3
=14:12:9
Amount that C should pay
=245×9/35=7×9=63
Answer is D
Question: The average age of A and B is 30 years. If C were to replace A, the average would be 25 and if C were to replace B, the average would be 40. What are the age of A, B and C?
A.45,15,35
B.35,15,45
C.30,25,53
D.40,30,25
Answer: A.45,15,35
Explanation: Given A + B = 60â€¦(i)
C + B = 50 â€¦ (ii)
A + C = 80â€¦(iii)
(i) + (ii) + (iii) â‡’ A + B + C = 95â€¦(iv)
from (i) and (iv), we get
C = 35years
âˆ´ B = 15 years and A = 45 years
Answer A
Question: Machine X can complete a job in half the time it takes Machine Y to complete the same job, and Machine Z takes 50% longer than Machine X to complete the job. If all three machines always work at their respective, constant rates, what is the ratio Q of the amount of time it will take Machines X and Z to complete the job to the ratio of the amount of time it will take Machines Y and Z to complete the job?
A.5 to 1
B.10 to 7
C.1 to 5
D.7 to 10
Answer: D.7 to 10
Explanation: Solutioning this exercise can be facilitated by using a R T W (rate time work) table:
We translate the exercise into the table:
R T W
X t/2 1
Y t 1
Z (t/2*3/2 =3t/4) 1
From this table we find the rates
Rx = 2/t
Ry = 1/t
Rz = 4/3t
The Q is what is the ratio of (Tx + Ty) / (Ty + Tz)
Rx + Ry = 2/t + 4/3t = 6/3t+4/3t = 10/3t
Ry+Rz = 1/t + 4/3t = 3/3t + 4/3t = 7/3t
The (10/3t)/(7/3t) = 10/7 then the work ratios is 10 to 7
Since Time Ratio Q is the inverse of work, the the answer is 7 to 10
CORRECT ANSWER D
Question: What is the sum of all the composite numbers up to 22?
A.228
B.277
C.153
D.132
Answer: C.153
Explanation: Explanation:
4 + 6 + 8 + 9 + 10 + 12 + 14 + 15 + 16 + 18 +21= 153
Answer: C
Question: 36 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work ?
A.24
B.77
C.88
D.29
Answer: A.24
Explanation: Explanation:
Less Men, means more Days {Indirect Proportion}
Let the number of days be x
then,
27 : 36 :: 18 : x
[Please pay attention, we have written 27 : 36 rather than 36 : 27, in indirect proportion, if you get it then chain rule is clear to you :)]
{\color{Blue} x=\frac{36\times 18}{27}}
x = 24
So 24 days will be required to get work done by 27 men.
Answer: A) 24 days
Question: Vijay lent out an amount Rs. 10000 into two parts, one at 8% p.a. and the remaining at 10% p.a. both on simple interest. At the end of the year he received Rs. 890 as total interest. What was the amount he lent out at 8% pa.a?
A.5529
B.5500
C.5529
D.5502
Answer: B.5500
Explanation: Let the amount lent out at 8% p.a. be Rs. A
=> (A * 8)/100 + [(10000 - A) * 10]/100 = 890
=> A = Rs. 5500.Answer:B
Question: When 999^500 is divided by 5, the remainder is
A.0
B.remainder is 1
C.2
D.3
Answer: B.remainder is 1
Explanation: 999^500 is to be divided by 5
We can reduce the number to 4^500 (as the remainder of 999/5 is 4 and we can get the same remainder for 4^500 and 999^500 regardless of which is divided 5 )
Now, let's notice the pattern of remainders of powers of 4 when divided by 5
R{(4^1)/5} = 4
R{(4^2)/5} = 1
R{(4^3)/5} = 4
R{(4^4)/5} = 1
and so on
So, even powers of 4 give a remainder of 1
Hence, R{(4^500)/5} will be 1
R{(999^500)/5} will also be 1
Correct Option : B
Question: If x, y, and z are positive integers, and 2x = 5y = 8z, then the least possible value of x + y + z is
A.15
B.28
C.33
D.42
Answer: C.33
Explanation: Take LCM of 2,5 and 8 = 40
Now 2x = 40 => x =20
5y = 40 => y = 8
8z = 40 => z =5
20+8+5 = 33.
Option C.
Question: 9, 12, 11, 14, 13, ?, 15
A.16
B.12
C.14
D.17
Answer: A.16
Explanation: A
16
Alternatively, 3 is added and one is subtracted.
Question: In a game of 70 points, A can give B 5 points and C 25 points. then how many points can B give C in a game of 50?
A.9.38
B.8.38
C.15.38
D.13.38
Answer: C.15.38
Explanation: In a game of 70 points,A give B 5 points and c 25 points means B=65,C=45
In 65 points B give 20 since 65-45=20
In 50 points B gives=50*20/65=15.38
ANSWER:C
Question: A cycle is bought for Rs.900 and sold for Rs.1080, find the gain percent?
A.26%
B.20%
C.21%
D.29%
Answer: B.20%
Explanation: 900 ---- 180
100 ---- ? => 20%
Answer: B
Question: A fruit seller sells mangoes at the rate of Rs.11 per kg and thereby loses 10%. At what price per kg, he should have sold them to make a profit of 10%?
A.Rs.13.44
B.Rs.12
C.Rs.12.25
D.Rs.12.31
Answer: A.Rs.13.44
Explanation: Solution
90 : 11 = 110 : x
x= (11Ã—110/90)
= Rs.13.44
Hence, S.p per Kg	= Rs.13.44
Answer A
Question: If 4 spiders make 4 webs in 4 days, then 1 spider will make 1 web in how many days?
A.4
B.6
C.5
D.4
Answer: A.4
Explanation: Let the required number days be x.
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)
spiders 1:4
Webs 4:1
1 x 4 x x = 4 x 1 x 4
=> x= 4
Answer is A
Question: The three sides of an acute angled triangle (all in cms) are 12, 19 and k. How many integer values can k take?
A.23
B.22
C.15
D.8
Answer: D.8
Explanation: In acute angle triangles all angles in the triangle should be less than 90.
The maximum length of k can be when it is the hypotenuse of the triangle.
So, k= sqrt(12^2 + 19^2) = 22.5 (approx)
The maximum length of k can be when side of length 12 is the hypotenuse of the triangle.
So, k = sqrt (19^2 - 12^2) = 14.7 (approx)
So, k>14.7 and k<22.5.
Hence, possible values for k can be 15,16,17,18,19,20,21 and 22. Total 8 values.
Answer D.
Question: A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 100, the runs scored by B are?
A. 15 B. 18
A.22
B.24
C.99
D.77
Answer: B.24
Explanation: A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 100 = 24
Answer: B
Question: The volume of a certain substance is always directly proportional to its weight. If 48 cubic inches of the substance weigh 112 ounces, what is the volume, in cubic inches, of 60 ounces of this substance?
A.27
B.36
C.25
D.64
Answer: C.25
Explanation: 112 ounces of a substance has a volume of 48 cubic inches
60 ounces of a substance has a volume of (48/112)*60 = 25 cubic inches
Answer A
Alternatively , we can use estimation
112 ounces of a substance has a volume of 48 cubic inches
56 ounces of a substance has a volume of 24 cubic inches
Therefore , 60 will have a volume a little more than 24 ,that is 25
C
Question: There are 3 red shoes, 2 green shoes. If one draw randomly a shoe what is the probability of getting a red shoe
A.3/5
B.2/9
C.5/9
D.4/9
Answer: A.3/5
Explanation: total 5 from take one.
5c1=5
red 3 from one
3c1=3
3/5
ANSWER:A
Question: If the sum of the two numbers is 22 and the sum of their squares is 404, then the product of the numbers is:
A.40
B.44
C.80
D.88
Answer: A.40
Explanation: Let the numbers be x and y.
Then, (x + y) = 22 and x2 + y2 = 404
Now,
2xy = (x + y)2 - (x2 + y2)
2xy= 222 - 404 = 484 - 404 = 80
xy = 40
ANSWER:A
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train.
A.150 meter
B.145 meter
C.140 meter
D.135 meter
Answer: A.150 meter
Explanation: Explanation:
Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train(Distance) = Speed * Time
=50/3âˆ—9=150meter
ANSWER IS A
Question: What is the greatest possible length that can be used to measure exactly the following Lengths 7m, 3m 85cm, 12m 95cm?
A.25 cms
B.30 cms
C.35 cms
D.38 cms
Answer: C.35 cms
Explanation: HCF of 7m, 3m 85cm, 12m 95cm is 35 cms.
ANSWER:C
Question: Which of the following is equal to 10^-(-2)^4?
A.1/(10^14)
B.1/(10^16)
C.1/(10^12)
D.1/(10^8)
Answer: B.1/(10^16)
Explanation: 10^-(-2)^4 => 10^-(-2^4) => 10^-(16) = 1/(10^16)
Answer : B
Question: The population of a town is 231400. If it increase at the rate of 3% per annum. What will be its population for 2years hence?
A.200000
B.245492
C.194582
D.194481
Answer: B.245492
Explanation: population after 2years = 231400*(1+ 3/100)^2 = 245492
Answer is B
Question: Ramu bought an old car for Rs. 42000. He spent Rs. 13000 on repairs and sold it for Rs. 64900. What is his profit percent?
A.16%
B.17%
C.18%
D.58%
Answer: C.18%
Explanation: Total CP = Rs. 42000 + Rs. 13000
= Rs. 55000 and SP = Rs. 64900
Profit(%)
= (64900 - 55000)/55000 * 100
= 18%
Answer: C
Question: The average of five consecutive odd numbers is 61. What is the difference between the highest and lowest numbers?
A.6
B.7
C.8
D.4
Answer: C.8
Explanation: Let the numbers x, x + 2, x + 4, x + 6 and x + 8
Then, [x + (x + 2) + (x + 4) + (x + 6) + (x + 8)]5 = 61
or 5x + 20 = 305 => x = 57
So, required difference = (57 + 8) - 57 = 8.
Answer: C
Question: The size of a television screen is given as the length of the screen's diagonal. If the screens were flat, then the area of a square 18-inch screen would be how many square inches greater than the area of a square 16-inch screen?
A.2
B.4
C.34
D.38
Answer: C.34
Explanation: Pythogoras will help here!
let the sides be x and diagonal be d
Then d ^2 = 2x^2
and
Area = x^2
Now plug in the given diagonal values to find x values
and then subtract the areas
Ans will be 18^2/2 - 16^2 /2 = 68 /2 = 34
Ans C.
Question: Find the area of a parallelogram with base 14 cm and height 24 cm.
A.336
B.384
C.345
D.244
Answer: A.336
Explanation: Area of a parallelogram = base * height = 14 * 24 = 336 cm2
Answer: Option A
Question: How many positive integers less than 300 can be formed using the numbers 1, 2, 3 a for the digits?
A. 30
B. 52
C. 66
D. 68
Answer: A. 30
Explanation: Notice that we can find the number of 2 and 3 digit numbers by just assuming the first digit can also be zero:
0 1 1
1 2 2
2 3 3
Number of possibilities = 3*3*3 = 27.
Then, just add up the number of 1 digits numbers = 3, so total is 27+3 = 30.
Answer: A
Question: What are the number of ways to select 3 men and 2 women such that one man and one woman are always selected?
A.17 ways
B.19 ways
C.30 ways
D.16 ways
Answer: C.30 ways
Explanation: The number of ways to select three men and two women such that one man and one woman are always selected = Number of ways selecting two men and one woman from men and five women
= ⁴C₂ * ⁵C₁ = (4 * 3)/(2 * 1) * 5
= 30 ways.
Answer:C
Question: A bus travels first one-fourth of the distance with a speed of 9 km/hr, next one fourth of the distance with 15 km/hr, third one-fourth distance with a speed of 20 km/hr and last one fourth with 30 km/hr. The average speed of the car for the whole journey is:
A.19.09 km/hr
B.29.09 km/hr
C.39.09 km/hr
D.49.09 km/hr
Answer: B.29.09 km/hr
Explanation: Explanation :
Let whole distance traveled be x
and average speed of the car be y
=> (x/4)/10+(x/4)/20+(x/4)/30+(x/4)/40=x/y
=> 1/10+1/20+1/30+x/40=4/y
=> (24+12+4+3)/240=4/y
=> 33/240=4/y
=> y=29.09
Answer : B