RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A certain family has 3 sons: Richard is 6 years older than David, and David is 8 years older than Scott. If in 8 years, Richard will be twice as old as Scott, then how old was David 2 years ago?
A.8
B.12
C.12
D.14
Answer: B.12
Explanation: Let's say
Age of Richard is "R"
Age of David is "D"
Age of Scott is "S"
Now
Richard is 6 years older than David,
i.e. R = D +6
David is 8 years older than Scott
i.e. D = S +8
If in 8 years, Richard will be twice as old as Scott
i.e. R+8 = 2x(S+8)
i.e. R+8 = 2S + 16
i.e. R = 2S+8
But R = D+6 = (S+8)+6 = S+14
therefore, 2S + 8 = S +14
i.e. S = 6
i.e. R = 20
i.e. D = 14
Now,
how old was David 2 years ago?
i.e. D-2= 14-2 = 12 years
ANSWER:B
Question: A single discount equivalent to the discount series of 20%, 10% and 5% is?
A.31.7
B.31.2
C.31.6
D.31.1
Answer: C.31.6
Explanation: 100*(80/100)*(90/100)*(95/100) = 68.4
100 - 68.4 = 31.6
Answer: C
Question: What is the remainder when 1034*1047*1050*1053 is divided by 33?
A.0
B.27
C.30
D.21
Answer: A.0
Explanation: take the remainder from each of 1034/33, 1047/33 and so on..
1034/33 gives remainder = 11
1047/33 gives remainder = 24
1050/33 gives remainder = 27
1053/33 gives remainder = 30
the net remainder is the product of above individual remainders. i.e = 11*24*27*30
break them into pairs 11*24/33 gives remainder 0
and 27*30/33 gives remainder 18
so 0*18/33 gives remainder 0.
A
Question: A radio station has to choose 2 weeks of the four in a month to broadcast a certain program, and that set will repeat each month. The program can be broadcast equally on any of the four week —- 1st week vs. last week don’t matter at all —- nor does it matter whether the week the program airs are adjacent or not. Absolutely any 2 weeks of the 4 weeks can be chosen. How many different week combinations of the 4 weeks can be constructed?
A.6
B.8
C.10
D.12
Answer: A.6
Explanation: Pick 2 weeks out of 4.. 4C2 =6
Answer : A
Question: The average age of a husband and his wife was 32 years at the time of their marriage. After five years they have a one-year old child. The average age of the family now is :
A.11
B.53/3
C.19
D.25
Answer: D.25
Explanation: Explanation:
Sum of the present ages of husband, wife and child = (32 * 2 + 5 * 2) + 1 = 75 years.
Required average = 75/3= 25 years.
Answer: D
Question: What is the radius of the incircle of the triangle whose sides measure 5, 12 and 13 units?
A.2 units
B.12 units
C.6.5 units
D.6 units
Answer: A.2 units
Explanation: Explanatory Answer
In a right angled triangle, the radius of the incircle = s - h, where 's' is the semi perimeter of the triangle and 'r' is the radius of the inscribed circle.
The semi perimeter of the triangle = a + b + c /2=5+12+13 /2 = 15
Therefore, r = 15 - 13 = 2 units.
Choice A
Question: There are 6 people in the elevator. Their average weight is 152 lbs. Another person enters the elevator, and increases the average weight to 151 lbs. What is the weight of the 7th person.
A.145
B.168
C.189
D.190
Answer: A.145
Explanation: Solution
Average of 7 people after the last one enters = 151 .
âˆ´ Required weight = (7x151)-(6x152)
= 1057- 912
= 145.
Answer A
Question: Find the area of the quadrilateral of one of its diagonals is 20 cm and its off sets 9 cm and 6 cm?
A.128
B.150
C.278
D.268
Answer: B.150
Explanation: 1/2 * 20(9 + 6)
= 150 cm2
Answer:B
Question: John and Karen begin running at opposite ends of a trail until they meet somewhere in between their starting points. They each run at their respective constant rates until John gets a cramp and stops. If Karen runs 50% faster than John, who is only able to cover 25% of the distance y before he stops, what percent longer would Karen have run than she would have had John been able to maintain his constant rate until they met.
A.25%
B.50%
C.75%
D.100%
Answer: A.25%
Explanation: John and Karen begin running at opposite ends of a trail until they meet somewhere in between their starting points. They each run at their respective constant rates until John gets a cramp and stops. If Karen runs 50% faster than John, who is only able to cover 25% of the distance y before he stops, what percent longer would Karen have run than she would have had John been able to maintain his constant rate until they met.
Lets say the distance of the trail is 100 miles. Lets also say that J rate = 10 miles/hour and K rate = 15 miles/hour.
If John stops at the 25% mark that means he travels 25 miles in 2.5 hours. It would take Karen t=d/r t=75/15 = 5 hours to reach john. If John had not stopped, their combined rate would 10+15 = 25 miles/hour meaning they would have met in 4 hours. Therefore, she ran one hour longer (25%) longer than she would have needed to if John ran for the entire time.
ANSWER: A) 25%
Question: 75% of x is greater than 1/3rd of x by 110.what is x?
A.160
B.264
C.360
D.354
Answer: B.264
Explanation: 75x/100-x/3=110
5x/12=110
x=264
ANSWER:B
Question: An entrepreneurship competition requires registering teams to have 3 team members, at least one of which must be a technology co-founder. If all team members must come from the auditorium during the meet and greet event which has 4 technologists and 8 businessmen, how many possible team submissions are possible?
A.76
B.100
C.164
D.198
Answer: C.164
Explanation: We have 3 scenarios here:
1) 1 tech2 businessmen: 4C1 x 8C2 = 112
2) 2 tech1 businessman: 4C2 x 8C1 = 48
3) 3 tech0 businessmen: 4C3 = 4
Total: 112+48+4 = 164
Answer: C
Question: Solution A contains 15% bleach per liter and solution B contains 45% bleach per liter. If solution A and solution B are mixed in a 1 to 1 ratio, what fraction of the mixed solution is NOT bleach?
A.1/3
B.7/10
C.2/5
D.1/4
Answer: B.7/10
Explanation: Amount of bleach in solution A: 15/100
Amount of bleach in solution B: 45/100
Amount of bleach in 1 liter of mixed solution: 1/2 x (15/100) + 1/2 x (45/100) = 60/200 = 3/10
Amount of solution that is not bleach: 1-3/10=7/10
Answer is B
Question: Rahul went to a shop and bought things worth Rs. 25, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
A.19.7
B.19.9
C.21.9
D.21.8
Answer: A.19.7
Explanation: Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (25−30/100−x)6/100 = 30/100
⇒ 6(25 −0.3 −x) = 30
⇒ (25 − 0.3 − x) = 5
⇒ x = 25 − 0.3 − 5 = 19.7
A
Question: The price of a car is Rs. 3,25,000. It was insured to 85% of its price. The car was damaged completely in an accident and the insurance company paid 90% of the insurance. What was the difference between the price of the car and the amount received ?
A.Rs. 76,375
B.Rs. 34,000
C.Rs. 82,150
D.Rs. 70,000
Answer: A.Rs. 76,375
Explanation: Explanation :
Price of the car = Rs.3,25,000
Car insured to 85% of its price
=>Insured price=325000 × (85/100)
Insurance company paid 90% of the insurance
⇒Amount paid by Insurance company = Insured price × (90/100)
= 325000 × (85/100) × (90/100) = 325 × 85 × 9 = Rs.248625
Difference between the price of the car and the amount received
= Rs.325000 - Rs.248625 = Rs.76375
Answer : Option A
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
A.11
B.50
C.88
D.27
Answer: B.50
Explanation: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 => x = 50 km/hr.
Answer:B
Question: A man's speed with the current is 15 km / hr and the speed of the current is 2.5 km / hr. The man's speed against the current is
A.8.5 km / hr
B.9 km / hr
C.10 km / hr
D.12.5 km / hr
Answer: C.10 km / hr
Explanation: Sol.
Man's rate in still in water = (15 - 2.5) km / hr = 12.5 km / hr.
Man's rate against the current = (12.5 - 2.5) km / hr = 10 km / hr.
Answer C
Question: There are three positive intigers such that 70% of the first number , 58 1/3% of second number and 38 8/9% of the third number are all equal. Which of the following can those three numbers be?
A.5,6,9
B.10,12,18
C.15,18,27
D.All the three
Answer: D.All the three
Explanation: All the three are in the same ratio
ANSWER:D
Question: A drink vendor has 60 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required?
A.135
B.137
C.143
D.310
Answer: C.143
Explanation: The number of liters in each can = HCF of 60, 144 and 368 = 4 liters.
Number of cans of Maaza = 60/4 = 15
Number of cans of Pepsi = 144/4 = 36
Number of cans of Sprite = 368/4 = 92
The total number of cans required = 15 + 36 + 92 = 143 cans.
ANSWER:C
Question: The number of singles that a baseball player hit increased 5 percent from her first season to her second season, and the number of doubles that she hit in the same time period decreased by 2 percent. If the total number of singles and doubles that she hit increased 2 percent from her first season to her second season, what is the ratio of the number of singles she hit in her first season to the number of doubles she hit in her first season?
A.4:3
B.9:11
C.3:1
D.2:1
Answer: A.4:3
Explanation: Soln:-
1.05S + 0.98D = 1.02[S + d]
0.03S = 0.04D
S/D = 4/3
ANSWER:A
Question: Sakshi invests a part of Rs. 12,000 in 12% stock at Rs. 120 and the remainder in 15% stock at Rs. 125. If his total dividend per annum is Rs. 1350, how much does he invest in 12% stock at Rs. 120?
A.s. 4000
B.s. 4500
C.s. 5500
D.s. 6000
Answer: B.s. 4500
Explanation: Let investment in 12% stock be Rs. x.
Then, investment in 15% stock = Rs. (12000 - x).
12/120 * x + 15/125 * (12000- x) = 1350
x/10 + 3/25(12000-x) = 1350
5x + 72000 - 6x = 1350 x 50
x = 4500.
Answer = B
Question: A small company is planning to rent either computer A or computer B to print customer mailing lists. Both computer A and computer B must be rented on an hourly basis. The rental fee is based only on the amount of time the computer is turned on. It will cost 40 percent more per hour to rent computer A than to rent computer B. Computer B would, however, require 20 hours more than computer A to do the job. If either computer A, or computer B were rented the total cost to rent the computer would be $700.00. What would be the approximate hourly charge to rent computer B?
A.$9.40
B.$10.00
C.$13.20
D.$17.80
Answer: B.$10.00
Explanation: Pa = price of A
Pb = price of B
Ta = time for A to complete the job
Tb = time for B to complete the job
Given
Pa = 1.4 Pb
Ta+20 = Tb
Pa*Ta = Pb*Tb=700
1.4Pb * (Tb-20) = Pb*Tb
1.4 Pb Tb - Pb Tb = 1.4 Pb * 20
0.4PbTb = 28Pb
Tb = 28/0.4 = 70
Pb=700/70 =10
B
Question: A husband and wife can complete a certain task in 1 and 2 hours respectively. Their children, Rae and Herman, can complete the same task in 4 and 7 hours, respectively. What is the ratio of the couple's time working together to complete the task to the children's time working together to complete the task?
A.a)11:42
B.b)3:10
C.c)12:23
D.d)5:18
Answer: A.a)11:42
Explanation: couples one hour work=1/1+1/2=3/2
so total time=2/3..
now, kids one hour work=1/4+1/7=11/28
so total time=28/11..
ratio=2/3:28/11=11:42
ans A
Question: In how many different ways can the letters of the word â€˜DIVIDEDâ€™ be arranged?
A.250
B.280
C.300
D.420
Answer: D.420
Explanation: Number of ways = 7!/3!2! = 7X6X5X4X3X2X1/3X2X1X2X1 = 420
D
Question: If p and q are two different odd prime numbers, such that p < q, then which of the following must be true?
A.(2p + q) is a prime number
B.p + q is divisible by 4
C.q - p is divisible by 4
D.(p + q + 1) is the difference between two perfect squares of integers
Answer: D.(p + q + 1) is the difference between two perfect squares of integers
Explanation: 1. (2p + q) for sure is an odd number , but may or may not be a prime number .
Eg - if we take 3 and 5 as p and q resp, we get 11, which is a prime number.
But if we take 7 and 11, we get 25, which is not a prime number.
2. p + q for sure gives us an even number. It may or may not be divisible by 4.
Eg - (7 + 5) = 12 , which is divisible by 4. But (11 + 7) = 18 , not divisible by 4
3. Same way as 2nd.
4. (p + q + 1) gives us an odd number.
Lets see the trend of difference between squares of consecutive integers.
2^2 - 1^2 = 3
3^2 - 2^2 = 5
4^2 - 3^2 = 7
5^2 - 4^2 = 9
6^2 - 5^2 = 11 and so on.
The trend is : The difference between squares of consc. integers is always odd number. And it covers all the odd numbers.
However , when we don't take consecutive integers, this trend is not followed.
Eg : 5^2 - 3^2 = 16 , which is an even number
3^2 - 1^2 = 8 , again not an odd number
Hence : Any odd number can be expressed as the difference of the squares of integers.
5. (p^2 + q^2) gives an even number.
ANSWER:D
Question: If 0 < p < 1 < q< 5, which of the following must be less than 1? I. p/q II. pq III. q - p
A.III only
B.II only
C.I only
D.II,III only
Answer: C.I only
Explanation: q > 1. So, option II, III is not possible.
So, Option I is correct.
Answer : C
Question: John bought a shirt on sale for 25% off the original price and another 25 % off the discounted price. If the final price was $14, what was the price before the first discount?
A.$45.10
B.$34.31
C.$24.88
D.$67.54
Answer: C.$24.88
Explanation: let x be the price before the first discount. The price after the first discount is
x - 25%x (price after first discount)
A second discount of 25% of the discounted price after which the final price is 14
(x - 25%x) - 25%(x - 25%x) = 14
Solve for x
x = $24.88
correct answer C
Question: In a games hour 4 different types of players came to the ground? cricket 12, hokey 17, football 11, softball 10. How many players are present in the ground?
A.70
B.50
C.62
D.49
Answer: B.50
Explanation: total number of players= 12+17+11+10= 50
Answer is B
Question: A team of 8 students goes on an excursion, in two cars, of which one can seat 5 and the other only 4. In how many ways can they travel?
A.126
B.277
C.188
D.171
Answer: A.126
Explanation: There are 8 students and the maximum capacity of the cars together is 9.
We may divide the 8 students as follows
Case I: 5 students in the first car and 3 in the second
Or Case II: 4 students in the first car and 4 in the second
Hence, in Case I: 8 students are divided into groups of 5 and 3 in8C3 ways.
Similarly, in Case II: 8 students are divided into two groups of 4 and 4 in 8C4ways.
Therefore, the total number of ways in which 8 students can travel is:
8C_{3}+8C_{4}}=56 + 70= 126
Answer: A
Question: The ages of two person differ by 20 years. If 7 years ago, the elder one be 5 times as old as the younger one, their present ages(in years) are respectively
A.30, 10
B.32, 12
C.29, 9
D.50, 30
Answer: B.32, 12
Explanation: Let their ages be x and (x + 20) years.
Then, 5(x - 7) = (x + 20 - 7)
=> 4x = 48
=>x =12
Their present ages are 32 years and 12 year.
ANSWER:B
Question: Peter has 9 candies, rina has 5 candies. Totally how many candies they have in all?
A.14
B.4
C.23
D.12
Answer: A.14
Explanation: 9+5=14. Answer is A
Question: The length of a rectangle is reduced by 20%. By what % would the width have to be increased to maintainthe original area?
A.14%
B.15%
C.25%
D.30%
Answer: C.25%
Explanation: Sol. Required change = (20*100)/(100-20)=25%
C
Question: 11, 10, ?, 100, 1001, 1000, 10001
A.1000
B.121
C.111
D.101
Answer: D.101
Explanation: The pattern is - 1, × 10 + 1, - 1, × 10 + 1, - 1, × 10 + 1, ....
Answer : D.
Question: For any non-zero a and b that satisfy |ab| = ab and |a| = -a
|b - 6| + |ab - b| = ?
A.a) ab - 2b + 6
B.b) 2b - ab - 4
C.c) ab + 4
D.d) ab - 2b + 4
Answer: A.a) ab - 2b + 6
Explanation: |a| = -a Suggests that 'a' is Negative
|ab| = ab Suggests that 'ab' is Positive
'ab' is Positive Suggests that 'a' and 'b' have same Sign i.e. either both positive or both negative
But since 'a' is Negative therefore 'b' is Negative too.
Since b is negative so |b - 6| = -b+6
Since ab is Positive and b is Negative so |ab - b| = ab - b
i.e. |b - 6| + |ab - b| = -b+6 + ab - b =ab - 2b + 6
Answer: Option A
Question: A, B and C invested Rs.6500, Rs.1300 and Rs.7800 respectively, in a partnership business. Find the share of B in profit of Rs.11700 after a year?
A.1300
B.3877
C.1170
D.975
Answer: D.975
Explanation: Explanation:
6500:1300:7800
5:1:6
1/12 * 11700 = 975
Answer:D
Question: 6 mangoes are equal to as many apples as are equal to 4 kiwi. All of them weigh 90kg only. Mango’s weighs are?
A.6
B.5
C.2
D.7
Answer: B.5
Explanation: 6M = xA = 4K
6M + xA + 4K ----- 90 Rs.
6M+6M+6M----- 90 Rs.
18M ------ 90 Rs. => 1M = 5Rs.
Answer: B
Question: The probability that a brand A widget is defective is x, the probability that a brand B widget is defective is 0.06, and the probability that a brand C widget is defective is 0.08. There are 40 brand A widgets, 30 brand B widgets, 30 brand C widgets, and nothing else in a container. If a widget is selected at random from the container, the probability that the widget selected is defective is 0.053. What is the value of x?
A.0.02
B.0.095
C.0.03
D.0.0275
Answer: D.0.0275
Explanation: Given probability of defective items in each brand,
So, the number of items defective in brand A=x*40, in brand B=0.06*30 and brand C=0.08*30
Total number of widgets=40+30+30=100
the probability that the widget selected is defective is 0.053=(x*40+0.06*30+0.08*30)/100
=> 40x+1.8+2.4 =5.3
=>40x=1.1
>x=1.1/40=0.0275
Ans D
Question: Three numbers are in the ratio 5 : 6 : 7. The sum of its longest and smallest numbers equals the sum of the third number and 48. Find the third number?
A.54
B.75
C.48
D.46
Answer: C.48
Explanation: Let the numbers be 5x, 6x, 7x.
Largest number = 7x.
Smallest number = 5x.
Third number = 6x.
7x + 5x = 6x + 48
6x = 48 => third number is 48.
Answer:C
Question: If two typists can type two pages in two minutes, how many typists will it take to type 22 pages in eleven minutes?
A.3
B.4
C.6
D.12
Answer: B.4
Explanation: In 2 minutes 2 typists type 2 pages which means that in 11 minutes they will type 11 pages but to type 22 pages (2 times) we need 2 times more typists i.e. 2 x 2 = 4 typists.
B
Question: How many figures are required for numbering the pages of a book containing 1000 pages?
A.2726
B.2878
C.2893
D.2765
Answer: C.2893
Explanation: Explanation:
1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 999 = 900 * 3 =2700
1000 = 4
-----------
2893
Answer:C
Question: 18 beavers, working together in a constant pace, can build a dam in 8 hours. How many hours will it take 36 beavers that work at the same pace, to build the same dam?
A.2.
B.4.
C.5.
D.6
Answer: B.4.
Explanation: Total Work = 18*8= 144 Beaver hours
36 Beaver * x =144Beaver hours
x=144/36 = 4
ANSWER:B
Question: A certain city with a population of 72,000 is to be divided into 11 voting districts , and no district is to have a population that is more than 10 percent greater than the population of any other district What is the minimum possible population that the least populated district could have ?
A.a) 6,000
B.b) 10,800
C.c) 10,900
D.d) 11,000
Answer: A.a) 6,000
Explanation: Let x = number of people in smallest district
x*1.1 = number of people in largest district
x will be minimised when the number of people in largest district is maximised
10*x*1.1 = 11x = total number of people in other districts
So we have 11x + x = 72k
x = 6,000
Answer : A
Question: Excepting B, the rest of the sentences can be the beginners of a paragraph. Excepting in the first answer choice–a, sentence B breaks the sequence of the rest of the choices.
A.87
B.9
C.917
D.777
Answer: C.917
Explanation: Answer:C
Question: A retailer sells pashminas at a ten percent discount. If a pashmina cost him $75 and he wants to make a profit of no less than twenty percent on the cost (after the discount), what is the minimum tag price he needs to put on a pashmina?
A.90
B.100
C.120
D.140
Answer: B.100
Explanation: The minimum tagged price the retailer needs to sell at to make a profit of at least 20%, after offering a 10% discount on tagged price is 1.2*CP(90).
Since, he has to sell the pashmina at 10% discount.
Marked price is 100$
ANS (Option B)
Question: Here 10 programmers, type 10 lines with in 10 minutes then 60lines can type within 60 minutes. How many programmers are needed?
A.16
B.6
C.10
D.60
Answer: C.10
Explanation: formulas for it (men1*time1)/work1=(m2*t2)/w2
(10*10)/10=(m2*60)/60
(10*10*60)/(10*60)
ans is 10.
ANSWER:C
Question: A bank lent $250 to a customer for a one-month loan. At the end of the month, the bank received y dollars more than than the amount that was lent due to interest. The bank also charged a service fee $5. In terms of y, what fraction of the amount that the bank received was the service fee?
A.5/(255+y)
B.5y-1
C.5y/(250-y)
D.5/(250-y)
Answer: A.5/(255+y)
Explanation: The amount of money the bank received was (250 + 5+ y) dollars. The $5 service fee as a fraction of the amount received was, therefore, 5/(255+y).
Answer: A.
Question: In what time will Rs.4800 lent at 3% per annum on simple interest earn as much interest as Rs.5000 will earn in 5 years at 4% per annum on simple interest?
A.7
B.7 1/6
C.7 1/3
D.7 1/2
Answer: A.7
Explanation: (4800*3*R)/100 = (5000*5*4)/100
R = 7
Answer: A
Question: Find the value(s) of k for which there is no solution for the given set of equations.
2x - ky = -3 and 3x + 2y = 1
A.4/9
B.2/9
C.2/1
D.4/3
Answer: D.4/3
Explanation: 3x + 2y = 1
If there are no set of solutions, then 2−k=322−k=32 or k = −43−43
For k = −43−43, the two lines in the coordinate planes are parallel to each other.
Answer:D
Question: Four people each roll a four die once. Find the probability that at least two people will roll the same number ?
A.3378
B.27778
C.2211
D.1318
Answer: D.1318
Explanation: The number of ways of rolling a dice where no two numbers probability that no one rolls the same number = 6 x 5 x 4 x 3
Now total possibilities of rolling a dice = 64
The probability that a no one gets the same number = 6×5×4×364=518
So the probability that at least two people gets same number = 1−518=1318
Answer:D
Question: How many numbers amongst the numbers 6 to 45 are there which are exactly divisible by 15 but not by 10?
A.Nil
B.1
C.2
D.3
Answer: C.2
Explanation: 15,30,45 are divisible by 15.
30 is divisible by 10 also.
So there are 2 numbers exactly divisible by 15 but not by 10
ANSWER:C
Question: Roy opened a shop investing Rs.20000. Alex joined him 8 months later, investing Rs.34000. They earned a profit of Rs.32000 after completion of two years. What will be Roy's share of profit?
A.18000
B.19000
C.20000
D.15000
Answer: D.15000
Explanation: SoL = ~s- So Roy's share = [15/32] x 32000 = 15000
Answer : D
Question: A group of men decided to do a work in 10days, but 5 of them became absent. If the rest of the group did the work in 12days, Find the original number of men?
A.15
B.20
C.30
D.25
Answer: C.30
Explanation: Original number of men = 5*12 / (12-10) = 30
Answer is C
Question: Martin bought 10 concert tickets, some at the full price of $2.00 per ticket, and some at a discounted price of $1.60 per ticket. If he spent a total of $18.00, how many discounted tickets did he buy?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: Let x be the number of tickets he bought at $2 per ticket.
then 2 x + (10-x)1.6 = 18
0.4x = 2 => x = 5
discounted tickets = 10 -x = 5
Ans : C
Question: Sum of two consecutive even terms lacks by 98 from their product. Find the sum of these numbers?
A.22
B.38
C.22
D.98
Answer: D.98
Explanation: Explanation:
x(x + 2) â€“ (x + x + 2) = 98
Answer: D
Question: Siddharth wants to borrow Rs.6000 at rate of interest 6% p.a. at S.I and lend the same amount at C.I at same rate of interest for two years. What would be his income in the above transaction?
A.Rs.21.60
B.Rs.21.68
C.Rs.21.18
D.Rs.21.98
Answer: A.Rs.21.60
Explanation: Amount of money Siddharth borrowed at S.I at 6% p.a. for two years = Rs.6,000
He lend the same amount for C.I at 6% p.a. for two years.
=> Siddharth's income = C.I - S.I
= p[1 + r/ 100]n - p - pnr/100
= p{ [1 + r/ 100]2 - 1 - nr/100
= 6,000{ [1 + 6/100]2 - 1 - 12/100}
= 6,000 {(1.06)2- 1 - 0.12} = 6,000(1.1236 - 1 - 0.12)
= 6,000 (0.0036) = 6 * 3.6
= Rs.21.60
Answer: A