RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A’s speed is 20/15 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat?
A.1/17
B.3/17
C.1/10
D.5/20
Answer: D.5/20
Explanation: We have the ratio of A’s speed and B’s speed. This means, we know how much distance A covers compared with B in the same time.
This is what the beginning of the race will look like:
(Start) A_________B______________________________
If A covers 20 meters, B covers 15 meters in that time. So if the race is 20 meters long, when A reaches the finish line, B would be 5 meters behind him. If we want the race to end in a dead heat, we want B to be at the finish line too at the same time. This means B should get a head start of 5 meters so that he doesn’t need to cover that. In that case, the time required by A (to cover 20 meters) would be the same as the time required by B (to cover 15 meters) to reach the finish line.
So B should get a head start of 5/20th of the race.
Answer (D)
Question: Lucy invested $10,000 in a new mutual fund account exactly three years ago. The value of the account increased by 10 percent during the first year, increased by 5 percent during the second year, and decreased by 10 percent during the third year. What is the value of the account today?
A.$10,350
B.$10,395
C.$10,500
D.$11,500
Answer: B.$10,395
Explanation: Value after 1 year: 10,000 * 1.1 = 11,000
Value after 2 years: 11,000 * 1.05 = 11,550
Value today: 11,550 * 0.9 = 10,395
Answer B is correct.
Question: The age of Somu is one-third his father's. 9 years back he was one-fifth of his father's age. What is his persent age ?
A.11
B.18
C.14
D.12
Answer: B.18
Explanation: Explanation :
Let Somu's age be x and that of his father be 3x.
So, x - 9 = 3x - 9/5 = x = 18
Answer : Option B
Question: In an examination it is necessary for a candidate to get 45 % of the maximum marks to pass. A candidate who gets 180 marks, fails by 45 marks. Find the maximum marks.
A.450
B.600
C.500
D.550
Answer: C.500
Explanation: Let max . mark = x
pass mark =45x/100
180 = 45x/100-45
x = 180*100-4500/45 =500
ANSWER:C
Question: In a kickball competition of 5 teams, how many possible matches can each team play with each other?
A. 10
B. 16
C. 24
D. 36
Answer: A. 10
Explanation: 5C2 = 10
Option A
Question: Find the missing in the series: 70, 54, 45, 41,___
A.22
B.287
C.2679
D.2767
Answer: B.287
Explanation: Answer:B
Question: If x and y are even integers, which of the following is an odd integer?
A.x+y+1
B.x+y
C.x-y
D.xy
Answer: A.x+y+1
Explanation: even + odd = odd
even + even = even
even - even = even
even * even = even
Answer : A
Question: In a simultaneous throw of pair of dice .find the probability of getting the total more than 7?
A.12/5
B.5/12
C.6/4
D.2/3
Answer: B.5/12
Explanation: Here n(S)=(6*6)=36
let E=event of getting a total more than 7
={(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)}
P(E)=n(E)/n(S)=15/36=5/12
Option B
Question: A shopkeeper sells 400 metres of cloth for $18000 at a loss of Rs.5 per metre. Find his cost price for one metre of cloth?
A.$20
B.$43
C.$50
D.$70
Answer: C.$50
Explanation: C
$50
SP per metre = 18000/400 = $45 Loss per metre = $5 CP per metre = 45 + 5 = $50
Question: Calculate the different number of ways 2 boys and 1 girls can sit on a bench?
A.6
B.4
C.5
D.3
Answer: A.6
Explanation: npn = n!
3p3 = 3 × 2 × 1 = 6
A
Question: Mr Sridharan invested money in two schemes A and B,offering compound interest @ 8 p.c.p.a. and 9 p.c.p.a.respectively. If the total amount of interest accured through the two schemes together in two years was 4818.30 and the total amount invested was 27,000, what was the amount invested in Scheme A?
A.15,000
B.13,500
C.12,000
D.Cannot be determined
Answer: C.12,000
Explanation: Let, in scheme A, Sridharan invest x.
Then, his investment in scheme B = (27000 – x).
Now,
x(1+8100)2+(2700−x)(1+9100)2
– 27000 = 4818.30
or, x(1.08)2 + (27000 – x)(1.09)2 = 31818.30
or, 1.1664x + 32078.7 – 1.1881x = 31818.30
or, 0.0217x = 260.4
or, x = 260.4⁄0.0217 = 12000
Answer C
Question: A windmill is taking advantage of strong air currents in order to produce electrical energy. On a typical day the wind speed is around 20 mph and in that speed the windmill produces 800 kw/h (kilowatts per hour). On a stormy day a windmill produces 20% more energy. How much kw/h can three windmills produce in two hours on a stormy day?
A.2880.
B.4860.
C.5780.
D.5760.
Answer: D.5760.
Explanation: 1 windmill:
Normal Day = 800 kw/h
Stormy Day = 800*1.2=960 kw/h
3 windmills for 2 hours on stormy day
960*3*2=5760
Answer: D
Question: For positive integers n, the integer part of the nth term of sequence C equals n, while the infinite decimal part of the nth term is constructed in order out of the consecutive positive multiples of n, beginning with 2n. For instance, C_1 = 1.2345678…, while C_2 = 2.4681012… The sum of the first seven terms of sequence C is between:
A.28 and 29
B.29 and 30
C.30 and 31
D.31 and 32
Answer: C.30 and 31
Explanation: First, construct the first seven terms, though only out to a few decimal places, following the given pattern.
C_1 = 1.23…
C_2 = 2.46…
C_3 = 3.69…
C_4 = 4.812…
C_5 = 5.10…
C_6 = 6.12…
C_7 = 7.14…
Now, to add up the first seven terms, you should be strategic about how many decimal places to keep. You can drop the hundredths place and get a good approximation with the tenths place—and if you find the sum too close to a boundary between choices, then you can refine your answer if necessary.
1.2 + 2.4 + 3.6 + 4.8 + 5.1 + 6.1 + 7.1 = 30.3
Including more decimal places would only add a couple of tenths to the sum—not enough to tip the sum over 31.
The correct answer is C.
Question: Annie and Sam set out together on bicycles traveling at 15 and 12 km per hour respectively. After 40 minutes, Annie stops to fix a flat tire. If it takes Annie 30 minutes to fix the flat tire and Sam continues to ride during this time, how many minutes will it take Annie to catch up with Sam assuming that Annie resumes riding at 15 km per hour?
A.20
B.40
C.60
D.80
Answer: D.80
Explanation: Annie gains 3 km per hour (or 1 km every 20 minutes) on Sam.
After 40 minutes Annie is 2 km ahead.
Sam rides 1 km every 5 minutes.
In the next 30 minutes, Sam rides 6 km so Sam will be 4 km ahead.
It will take Annie 80 minutes to catch Sam.
The answer is D.
Question: Twenty percent of Country Y's yearly exports come from fruit exports. One-fourth of all fruit exports from Country Y are orange exports. If country Y generates $40 million from its orange exports, how much money does it generate from its yearly total of exports?
A.$21.25m
B.$800m
C.$106.25m
D.$127.5m
Answer: B.$800m
Explanation: 20/100*1/4*(total) = 40
1/20*(total) = 40
(total) = 40*20 = 800
Answer: B
Question: P alone can complete a job in 4 days. The work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?
A.1.5
B.2.0
C.2.5
D.3.0
Answer: D.3.0
Explanation: P's rate is 1/4
Q's rate is 1/12
The combined rate is 1/4 + 1/12 = 1/3
If they work together, the job will take 3 days.
The answer is D.
Question: A man can do a piece of work in 5days, but with the help of his son, he can finish it in 2days. In what time can the son do it alone?
A.3 1/3
B.5 1/2
C.7 1/2
D.6
Answer: A.3 1/3
Explanation: Son's 1day work = 1/2 - 1/5 = 3/10
Son alone can do the work in 10/3days = 3 1/3 days
Answer is A
Question: A computer manufacturer produces a certain electronic component at a cost of $80 per component. Shipping costs for delivering the components are $3 per unit. Further, the manufacturer has costs of $16,500 a month related to the electronic component regardless of how many it produces. If the manufacturer produces and sells 150 components a month, what is the lowest price it can sell them for such that the costs don't exceed the revenues?
A.$193
B.$82
C.$110
D.$138
Answer: A.$193
Explanation: This question can be solved easily using a equation model.
150*p = 16500(fixed cost) + 150*80+150*3.
= 16500+ 12000+ 450
P = 193
A
Question: If a 3-member subcommittee is to be formed from a certain 8-member committee, how many different such subcommittee are possible?
A.6
B.18
C.56
D.108
Answer: C.56
Explanation: 1st member can be selected in 8 ways
2nd can be selected in 7 ways
3rd can be selected in 6 ways
So total ways : 336
But to avoid the similar scenarios 336/3!=56
ANS:C
Question: Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 7 days?
A.2/5
B.7/18
C.1/4
D.1/9
Answer: B.7/18
Explanation: A's one day's work = 1/30
B's one day's work = 1/45
(A + B)'s one day's work = 1/30 + 1/45 = 1/18
The part of the work completed in 7 days = 7 (1/18) = 7/18.
ANSWER B
Question: The sum of digits of a two digit number is 11,The difference between the digits is 5. Find the number
A.85
B.94
C.83
D.72
Answer: C.83
Explanation: Description :
=> x+y=11, x-y=5
Adding these 2x =16
=> x=8, y=3.
Thus the number is 83
Answer C
Question: A farmer is planting a row consisting of 5 unique apple trees and 4 unique orange trees. How many ways are there for the farmer to plant the trees such that no apple tree is adjacent to another apple tree and no orange tree is adjacent to another orange tree?
A.512
B.5760
C.1,024
D.1,152
Answer: B.5760
Explanation: 2 possible arrangements are possible
AOAOAOAO
OAOAOAOA
2 unique type of trees are present consisting of 4 trees each
4 apple trees can be arranged in 4! ways
4 orange trees can be arranged in 4! ways
as 2 arrangements are possible
total arrangements = 2 *5! * 4! = 5760
correct answer option B
Question: If -3x+4y=28 and 3x-2y=8, what is the product of x and y?
A.264.
B.428
C.464.
D.622
Answer: A.264.
Explanation: Given -3x+4y=28 ---Eq 1
3x -2y =8 -- Eq 2
Sum both eqns we get 2Y = 36 => Y = 18
Sub 2Y in eq 2 => 3X - 36 = 8.
=> X = 44/3
Now XY = 44/3 * 18 = 264.
Option A is correct answer.
Question: A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. If the smaller wheel has made 56 revolutions, what will be the number of revolutions made by the larger wheel?
A.15
B.24
C.21
D.9
Answer: B.24
Explanation: Explanation:
Let the number of revolutions made by the larger wheel be x
More cogs, less revolutions (Indirect proportion)
Hence we can write as
(cogs) 6 : 14 :: x : 56
â‡’6Ã—56=14 Ã— x
â‡’x = 24
Answer: Option B
Question: A man can row upstream at 7 kmph and downstream at 10kmph.find manâ€™s rate in still water and the rate of current.
A.1.5 km/hr
B.2.5 km/hr
C.3.5 km/hr
D.4.5 km/hr
Answer: A.1.5 km/hr
Explanation: Rate in still water=1/2(10+7)km/hr=8.5 km/hr.
Rate of current=1/2(10-7)km/hr=1.5 km/hr.
ANSWER A
Question: A ball is bought for Rs.400 and sold at a gain of 45% find its selling price?
A.A)Rs.480/-
B.B)Rs.580/-
C.C)Rs.500/-
D.D)Rs.520/-
Answer: B.B)Rs.580/-
Explanation: 100 % ------> 400 (100 * 4 = 400)
145 % ------> 580 (120 * 4 = 580)
Selling price = Rs.580/-
B
Question: The greatest ratio out of 2:3, 5:8, 3:2, 8:9 and 8:5 is?
A.2:3
B.3:2
C.5:8
D.8:5
Answer: D.8:5
Explanation: 2/3=0.666
5/8=0.625
3/2=1.5
8/9=0.888
8/5=1.6
ANSWER:D
Question: A thief steals at a car at 2.30 p.m. and drives it at 60 km/hr. The theft is discovered at 3 p.m. and the owner sets off in another car at 75 km/hr. When will he overtake the thief?
A.6 p.m
B.9 p.m
C.5 p.m
D.2 p.m
Answer: C.5 p.m
Explanation: :
Suppose the thief is overtaken x hrs after 2.30 p.m.
Then, distance covered by the owner in (x - 1/2) hrs.
60x = 75(x - 1/2) => x = 5/2 hrs.
So, the thief is overtaken at 5 p.m.'
Answer: C
Question: If 0 < x < 1 and x ≠ 0, which of the following inequalities must be true?
I. x^3 < x
II. x^2 < |x|
III. x^4 – x^5 > x^3 – x^2
A. I only
B. II only
C. III only
D. II and III only
Answer: B. II only
Explanation: Answer is D. Let's look at the statements one by one
Stmt I. x^3 < x
if 0<x<1 then x^3< x but if -1<x<0 then x^3>x
So this statement is not always true
Stmt II. x^2 < |x|
Because we know that x is a number less than one but not equal to zero then x^2 will always be less than |x|.
Why? think of positive fractions (and you can think in terms of positive fractions because the inequality is in regards to |x|). Lets set x = 1/2, then x^2 = 1/4 and 1/4<1/2
So Stmt II is always true
Stmt III. x^4 – x^5 > x^3 – x^2
This one may seem tricky but lets break it down. x^4 – x^5 > x^3 – x^2 = x^4(1-x)>x^2(x-1).
Because lets concentrate on (1-x) and (x-1). We are given that -1<x<1 which means that (1-x)>0 and (x-1)<0. x^4 will always be positive and x^2 will always be positive so without doing any math we are looking at positive > negative... which is always true.
So Stmt III is always true
B
Question: In how many M ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?
A. 736
B. 768
C. 792
D. 840
Answer: D. 840
Explanation: three letters can be arranged in 3! ways.
only one combination EIU is required.
7 letters can be arranged in 7! ways.
thus M=7!/ 3! * 1 = 840.
D
Question: Find the mean proportional between 49 & 81?
A.59
B.61
C.63
D.65
Answer: C.63
Explanation: Formula = √a×b
A = 49 and B = 81
√49×81 = 7 × 9 = 63
C
Question: X and Y started a business investing Rs. 24,000 and Rs. 40,000 respectively. Out of a total profit of Rs. 16,000, Y’s share is :
A.8500
B.9000
C.9500
D.10000
Answer: D.10000
Explanation: Ratio of their shares = 24000 : 40000 = 3 : 5.
B’s share = Rs. 16000 * 5/8
= Rs. 10000
ANSWER:D
Question: Express a speed of 90 kmph in meters per second?
A.25mps
B.20 mps
C.35 mps
D.19 mps
Answer: A.25mps
Explanation: 90 * 5/18 = 25 mps
Answer: A
Question: In the given series find the number which is wrong.
4,8,11,22,18,36,24,50
A.8
B.11
C.18
D.50
Answer: D.50
Explanation: Format : x and 2(x)
4 and 8
11 and 22
18 and 36
So,
24 and 48
ANSWER:D
Question: The speed at which a man can row a boat in still water is 20 kmph. If he rows downstream, where the speed of current is 4 kmph, what time will he take to cover 80 metres?
A.10.51
B.11.51
C.9.51
D.13.51
Answer: A.10.51
Explanation: Speed of the boat downstream = 20+ 4 = 24 kmph= 24 * 5/18 = 6.66 m/sHence time taken to cover 70 m = 70/6.66= 10.51 seconds.Answer:A
Question: A mobile battery in 1 hour charges to 20 percent.How much time (in minute) will it require more to charge to 40 percent.
A.120
B.150
C.175
D.160
Answer: A.120
Explanation: 1 hr =20 percent.Thus 15 min=5 percent .Now to charge 40 percent 120 min.Answer:A
Question: If the letters of the word CHASM are rearranged to form 5 letter words such that none of the word repeat and the results arranged in ascending order as in a dictionary what is the rank of the word CHASM ?
A.32
B.12
C.82
D.27
Answer: A.32
Explanation: The 5 letter word can be rearranged in 5!=120 Ways without any of the letters repeating.
The first 24 of these words will start with A.
Then the 25th word will start will CA _ _ _.
The remaining 3 letters can be rearranged in 3!=6 Ways. i.e. 6 words exist that start with CA.
The next word starts with CH and then A, i.e., CHA _ _.
The first of the words will be CHAMS. The next word will be CHASM.
Therefore, the rank of CHASM will be 24+6+2= 32
Answer: A
Question: The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit?
A.Rs. 500
B.Rs.2000
C.Rs.1000
D.Rs.693
Answer: B.Rs.2000
Explanation: Explanation:
Let C.P. be Rs. x.
Then,1920-x/x*100=(x-1280/x)*100
1920 - x = x - 1280
2x = 3200
x = 1600
Required S.P. = 125% of Rs. 1600 = Rs(125/100*1600)=Rs.2000.
Answer:B
Question: A marketing survey of Anytown found that the ratio of trucks to sedans to motorcycles was 3:7:2, respectively. Given that there are 9,800 sedans in Anytown, how many motorcycles are there?
A.2800
B.2100
C.3600
D.4200
Answer: A.2800
Explanation: Let the total number of trucks = 3x
total number of sedans = 7x
total number of motorcycles = 2x
total number of sedans = 9800
=> 7x = 9800
=> x = 1400
total number of motorcycles =2x = 2*1400
=2800
Answer A
Question: 1,3,3,9,27,243,?
A.6565
B.6661
C.6861
D.6561
Answer: D.6561
Explanation: Each number is the product of the previous two numbers, ie 27*243 = 6561.
Answer : D
Question: Two quarts containing 4⁄5 water and 2⁄5 formula are mixed with three quarts containing 7⁄10 water and 2⁄10 formula. Approximately what percent of the combined five-quart mixture is water?
A.50%
B.58%
C.54%
D.53%
Answer: B.58%
Explanation: 4/5 of 2 quarts = 4/5 quarts of water
7/10of 3 quarts = 21/10 quarts of water
4/5 = 0.8
21/10 = 2.1
Total water = 0.8 + 2.1= 2.9
Total quarts = 5
2.9/5 = 58%
Answer : B
Question: A certain sum is invested at simple interest at 18% p.a. for two years instead of investing at 12% p.a. for the same time period. Therefore the interest received is more by Rs. 840. Find the sum?
A.7000
B.2787
C.2799
D.2699
Answer: A.7000
Explanation: Let the sum be Rs. x.
(x * 18 * 2)/100 - (x * 12 * 2)/100 = 840 => 36x/100 - 24x/100 =840
=> 12x/100 = 840 => x = 7000.Answer:A
Question: How many of the positive factors of 42 are not factors of 56?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: Factors of 42 - 1,2,3,6,7,14,42
factors of 56 - 1,2,4,7,8,14,28,56
Comparing both, we have three factors of 42 which are not factors of 56 - 3,6,42 .
The answer is 3. Pls check your options again - D $ E are same.
ANSWER:C
Question: The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is:
A.70 km/hr
B.75 km/hr
C.84 km/hr
D.87.5 km/hr
Answer: D.87.5 km/hr
Explanation: Let the speed of two trains be 7x and 8x km/hr.
Then, 8x = 400/4 = 100
Let the speed of two trains be 7x and 8x km/hr.
--> x = 100/8 = 12.5
--> Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.
Answer : D.
Question: A sum of money place at compound interest doubles itself in 4 years. In how many years will it amount to eight times itself?
A.15 years
B.11 years
C.12 years
D.18 years
Answer: C.12 years
Explanation: 100 ---- 200 ---- 4
400 ---- 4
800 ---- 4
------
12 years
Answer: C
Question: If f(x)= 5x^2- 2x+6 and g(y)= 3y-5, then g(f(x))
A.82x^2-9x+38
B.15x^2-6x+13
C.58x^2-4x+58
D.87x^2-5x+96
Answer: B.15x^2-6x+13
Explanation: g(f(x))=3(5x^2-2x+6)-5
=15x^2-6x+18-5
=15x^2-6x+13
the answer is B
Question: Set #1 = {A, B}
Set #2 = {K, L, M, N, O, P}
There are these two sets of letters, and you are going to pick exactly one letter from each set. What is the probability of picking at least one vowel?
A.1/6
B.1/3
C.7/12
D.2/3
Answer: C.7/12
Explanation: So Not a vowel in Set-1 : 1/2
And not a vowel in Ser-2:5/6
Now,
1/2∗5/6=5/12
This is for not a vowel.
Then for at least one vowel will be = 1−5/12=7/12
Answer will be C.
Question: The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 30% profit?
A.220
B.230
C.960
D.832
Answer: D.832
Explanation: C.P. = Rs. x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 130% of Rs. 640 = 130/100 * 640 = Rs. 832.
D
Question: If A:B = 2:3, B:C = 4:5 and C:D = 5:9 then A:D is equal to:
A.11:17
B.8:27
C.5:9
D.2:9
Answer: B.8:27
Explanation: Solution:
A/D = (A/B)*(B*C)*(C/D)
= (2/3)*(4/5)*(5/9)
= (2*4*5)/(3*5*9)
= 8/27.
Answer: Option B
Question: Jim is able to sell a hand-carved statue for $670 which was a 35% profit over his cost. How much did the statue originally cost him?
A.$496.30
B.$512.40
C.$555.40
D.$574.90
Answer: A.$496.30
Explanation: 670 is the final price that is the selling price. now suppose, x is the cost price.
therefore 670 = 1.35 * x
now while doing x = 670/1.35 calculation. I saw that the answer choices begin with 5.
So i did 135 * 5 = 675. As 670 is less than 675. Therefore the quotient will be less than 5.
Which is only in the answer A.
Question: A box contains nine light out of which 4 are defective. If four light are chosen at random, find the probability that all the four light are defective?
A.2/113
B.3/121
C.1/126
D.3/101
Answer: C.1/126
Explanation: Out of nine light , five are good and four are defective.
Required probability = ⁴C₄/⁹C₄ = 1/126
C
Question: Insert the missing number.
3, 5, 6,10 , 9, 15, 12, 20, 15, (....)
A.25
B.20
C.10
D.30
Answer: A.25
Explanation: Explanation:
There are two series, beginning respectively with 3 and 5. In one 3 is added and in another 5 is added.
The next number is 20 + 5 = 25.
Answer: A) 25
Question: If a fair 6-sided die is rolled three times, what is the probability that exactly one 2 is rolled?
A.25/216
B.50/216
C.25/72
D.25/36
Answer: C.25/72
Explanation: Total ways in which a 6-sided die can be rolled three times = 6*6*6 = 216
To get exactly one 2, there are three ways:
A 2 on the first roll and non 2 on other two rolls. This can be done in 1*5*5 = 25 ways.
The 2 could be on the second or third roll too. So total favorable cases = 25*3 = 75
Required Probability = 75/216 = 25/72
Answer (C)
Question: An equal number of desks and bookcases are to be placed along a library wall that is 15 meters long. Each desk is 2 meters long, and each bookshelf is 1.5 meters long. If the maximum possible number of desks and bookcases are to be placed along the wall, then the space along the wall that is left over will be how many G meters long?
A.0.5
B.1
C.1.5
D.2
Answer: B.1
Explanation: Let x be the number of desks and bookcases that are placed along the library wall.
2x + 1.5x < 15
3.5x < 15
Since x is a non negative integer, the largest number x can be is 4.
When x is 4, the desks and bookcases take up 3.5 * 4 = 14m, leaving 1m of empty space.
Thus, I believe the answer is B) 1
Question: Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
A.17004
B.18000
C.18002
D.18004
Answer: D.18004
Explanation: Solution
L.C.M. of 16,18,20,25 = 3600. required number is of the form 3600 k + 4.
Least value of k for which (3600 k + 4 ) is divisible by 7 is k = 5.
So, Required number = (3600 × 5 + 4) = 18004. Answer D
Question: 53, 60, 56, 8, 54, 3, 8
Which of the following numbers is lower than the median but greater than the mean of the set of the numbers in the list?
A.18
B.29
C.46
D.53
Answer: C.46
Explanation: Yes, it can be solved with observation even without approximation in 30 sec.
Just observe given numbers: 3, 8, 8, 53, 54, 56, 60
Median is very easy to tell - its 53. Now we want a number lower than 55 and greater than mean. How many numbers are lower than 53? DE are already out.
Now, we have 18, 29 and 46 and we want a number among these which is greater than mean. logically whatever be the mean, if one value out of these 5 has to be greater than mean it has to be 46. (Notice, if 18 is more than mean then 46 is also. If 28 is more than mean, 46 is also. )
Hence C it is!
Question: Double of Quarter of 4 percent written as a decimal is :
A.0.003
B.0.0005
C.0.25
D.0.02
Answer: D.0.02
Explanation: Explanation :
Solution: (2)*(1/4)*4% = 2*(1/4 * 1/100)= 0.02.
Answer : D
Question: There are 10 points on a circle. A hexagon can be formed by linking 5 of the 10 points. How many such hexagons are possible?
A.60
B.120
C.200
D.252
Answer: D.252
Explanation: 5 points can be selected out of 10 points in 10C5 ways
=10 !/5!*5!=252
Ans D
Question: 20 throws of a die produces following results
SCORE -- NUMBER OF OCCURRENCES
---1-------------------4
---2-------------------3
---3-------------------5
---4-------------------2
---5-------------------2
---6-------------------4
What is the probability L that one more throw to this series will increase the mean score?
A.1/6
B.1/3
C.1/2
D.2/3
Answer: C.1/2
Explanation: I get the mean as 67/20 --> 3.35. Thus in order to raise this mean we would need a 4,5,or 6.
Thus probability L is 1/2.C
Question: A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:
A.29 1/5
B.37 1/4
C.42
D.54
Answer: C.42
Explanation: After 10 days : 150 men had food for 35 days.
Suppose 125 men had food for x days.
Now, Less men, More days (Indirect Proportion)
Therefore 125 : 150 :: 35 : x <=> 125 x x = 150 x 35
=> x =150 x 35/125
=> x = 42.
Correct answer is C