RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: ((a+b)/c)/2
In the expression above, a, b, and c are different numbers and each is one of the numbers 2, 3, or 5. What is the least possible value of the expression?
A.2/10
B.5/10
C.10/5
D.7/6
Answer: B.5/10
Explanation: ((a+b)/c)/2
= (a+b)/2c
The expression will have the least value when numerator (a+b) is the smallest.
=(2+3)/2*5
=5/10
Answer B
Question: X, Y, and Z are different prime numbers. The product X^3*Y^2*Z^1 is divisible by how many different positive numbers?
A.24
B.30
C.36
D.42
Answer: A.24
Explanation: The exponents of X^3*Y^2*Z^1 are 3, 2, and 1.
The number of factors is (3+1)(2+1)(1+1) = 24
The answer is A.
Question: A machine puts c caps on bottles in m minutes. How many W hours will it take to put caps on b bottles?
A.60bm/c
B.W=bm/60c
C.bc/60m
D.60b/cm
Answer: B.W=bm/60c
Explanation: The machine puts c caps in m minutes or c caps in m/60 hours.
Rate = c/m/60 = 60c/m.
To put b caps the machine CCwill take:-
Time = Work/Rate
T = b/60c/m = bm/60c
Answer is B.
Question: The number of the members of a club is more than 50 and less than 80. When 5 people sit at a table, other people exactly divided to 8-people groups (8 people sit at a table) or 7-people groups (7 people sit at a table). If the members are divided to 9-people groups, how many people will be left?
A.4
B.5
C.6
D.7
Answer: D.7
Explanation: The number of members is 7k+5 = 8j+5
The only number in this range which satisfies this is 61.
61/9 = 6(9) + 7
The answer is D.
Question: A certain company consists of 5 managers and 8 non-managers. How many different teams of 3 employees can be formed in which at least one member of the team is a manager and at least one member of the team is not a manager? (Two groups are considered different if at least one group member is different)
A.84
B.108
C.135
D.220
Answer: D.220
Explanation: Total # of teams of 3 possible is 13C3=286
# of teams with only managers or only non-managers is: 5C3+8C3=10+56=66;
# of teams of 3 with at least one manager or at least one non-manager is: 286-66=220.
ANSWER:D
Question: 385, 462, 572, 396, 428, 671, 264
A.385
B.428
C.671
D.264
Answer: B.428
Explanation: Solution
In each number except 428,the middle digit is the sum of the other two. Answer B
Question: 8k8
+ k88
--------
1,6w6
If k and w represent non-zero digits within the integers above, what is w?
A.6
B.7
C.8
D.9
Answer: A.6
Explanation: 8k8
k88
--------
16w6
Trial and error or just plug-in method might be the shortest way to solve this problem. Though you can narrow down the possible values of k to just two: 7 and 8 --> 8**+7**=16** or 8**+8**=16** (k can not be less than 7 or 9, as the result won't be 16**). After that it's easy to get that k=7 and w=6.
Answer: A.
Question: If in a race of 110m, A covers the distance in 20 seconds and B in 25 seconds, then A beats B by:
A.20m
B.16m
C.11m
D.22m
Answer: D.22m
Explanation: Explanation:
The difference in the timing of A and B is 5 seconds. Hence, A beats B by 5 seconds.
The distance covered by B in 5 seconds = (110 * 5) / 25 = 22m
Hence, A beats B by 22m.
ANSWER D
Question: Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 8 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her?
A.8 mph
B.5.25 mph
C.3.5 mph
D.4.5 mph
Answer: D.4.5 mph
Explanation: (1 mph +8 mph)/2 = 4.5 mph
Correct option is: D
Question: Excluding stoppages, the speed of a bus is 62 kmph and including stoppages, it is 56 kmph. For how many minutes does the bus stop per hour?
A.70 min
B.16 min
C.7 min
D.6 min
Answer: D.6 min
Explanation: D
10 min
Due to stoppages, it covers 6 km less.
Time taken to cover 6 km = (6/62 x 60) min = 6 min
Question: A warehouse is labeling computer inventory with 4-digit codes. Each code is to consist of four digits between the numbers 0 and 8. The manager is debating whether to allow any 4-digit codes to have leading zero's before a non-zero number is used. If not allowed, then numbers like0025cannot be used.
The manager wants to measure the magnitude of the number of 4-digit code possibilities that are lost if he disallows the use of leading zero's. How many such codes would be lost?
A.981
B.2000
C.1011
D.1101
Answer: B.2000
Explanation: The number of codes possible if leading zero is allowed = 10*10*10*10=10^4
The number of codes possible if leading zero is NOT allowed = 8*10*10*10=9*10^3
The difference = 10^4 - 8*10^3 = 10^3(10-8) = 2*10^3.
Answer: B.
Similar questions to practice:
Hope it helps.
Question: A factory has 500 workers, 20 percent of whom are women. If 50 additional workers are to be hired and all of the present workers remain, how many of the additional workers must be women in order to raise the percent of women employees to 20 percent?
A. 3
B. 10
C. 25
D. 30
Answer: B. 10
Explanation: Currently the factory has 0.20*500=100 women.
After 50 additional workers are hired, there will be total of 550 workers and we need 0.2*550=110 of them to be women, so we need 110-100=10 more women.
Answer: B.
Question: In a certain province in Italy there are 15 cities. If a single road segment connects only two cities, how many road segments are required in order to connect the cities so that each city is connected to all other cities with a single road segment?
A.30
B.105
C.330
D.14!
Answer: B.105
Explanation: Method-1:
Italy Total Cities = 15 and each city should be connected with every other city
So Total Roads required to connect 1st City with other 14 cities = 14
Now 1st City is connected with all other cities so,
So Total Roads required to connect 2nd City with 13 cities (Other than 1st) = 13
Now 1st and 2nd Cities are connected with all other cities so,
So Total Roads required to connect 3rd City with 12 cities (Other than 1st, and 2nd) = 12
......and so on...
Total Roads required = 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 105=B
Question: If a number between 1 and 60 (inclusively) is chosen randomly, what are the odds that it is divisible by 5 or 8?
A.1/4
B.7/30
C.17/60
D.3/10
Answer: D.3/10
Explanation: P(5á´œ8) = P(5) + P(8) - P(5âˆ©8), where S denotes divisible by 5 and 8 denotes divisible by 8.
P(5á´œ8) = 12/60 + 7/60 - 1/60
= 3/10
Answer: D
Question: Sreenivas sells a table to Shiva at 10% profit and Shiva sells it to Mahesh at 10% loss. At what price did Sreenivas purchase the table if Mahesh paid Rs. 3168?
A.2277
B.3200
C.2200
D.2766
Answer: B.3200
Explanation: Let the cost price of table for Sreenivas be Rs. x and given that, cost price of table for Mahesh = Rs. 3168.
=> (90%) of (110%) of x = Rs. 3168.
=> (90/100)(110/100)x = 3168
=> x = (3168 * 100)/(9 * 11)
=> x = Rs. 3200
Answer: B
Question: Let T be the set of integers { 3, 11, 19, 27, ..., 451, 459, 467 } and S be a subset of T such that the sum of no two elements of S is 470. The maximum possible number of elements in S is
A.32
B.28
C.29
D.30
Answer: D.30
Explanation: Explanation :
At first, let's find the number fo integers in the given series.
=> Tn = a + (n - 1) d.
=> 467 = 3 + (n - 1) 8.
=> 464/8 = n - 1.
=> 58 + 1 = n. i.e n = 59.
If we closely observe the given set 3 + 467 = 11 + 459 = .... = 470.
The total number of elements in the given set = 59.
This means that we have 59/2 i.e 29 pairs of values that add to 470, and one lone number (235) that has no other number to pair up with.
So, We have 29 prohibited number pairs: (3 and 467), (11 and 459), (19 and 451), . . .
We can take 1 number from each of these pairs, so we can have 29 numbers in set S.
PLUS we can have the lone number 235.
So, set S can have a maximum of 29+1 i.e 30 numbers.
Answer : D
Question: What is the place value of 7 in the numeral 2734?
A.600
B.650
C.700
D.750
Answer: C.700
Explanation: Option 'C'
7 * 100 = 700
Question: what is the remainder when 50! is divided by 16^8??
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: 16 raise to 8=2 raise to 32, now highest power of 2 divisible by 50! Is 25+12+6+3+1=47
Since 2 raise to 47 is divisible, 2 raise to 32 also will be divisible
ANSWER:A
Question: 765.765 - ? + 46.82 = 437.785
A.A)374.80
B.B)752.804
C.C)714.642
D.D)629.906
Answer: A.A)374.80
Explanation: Explanation:
374.80
Answer: Option A
Question: There are 14 teams in a soccer league and each team plays each of the other teams once. How many games will be played in total?
A.87
B.91
C.95
D.99
Answer: B.91
Explanation: 14C2=91
The answer is B.
Question: With both inlets open, a water tank will be filled with water in 42 minutes. The first inlet alone would fill the tank in 2 hours. If in every minutes the second inlet admits 50 cubic meters of water than the first, what is the capacity of the tank ?
A.7,000
B.10,500
C.11,750
D.12,000
Answer: A.7,000
Explanation: The work Done by Inlet A and B together in 1 min = 1/42
The work Done by Inlet A (First Inlet) in 1 min = 1/120
The work Done by Inlet B (Second Inlet) in 1 min = (1/42)- (1/120) =1/65
DIfference of Work done by B and A = B - A = 50 Cubic meter
i.e. (1/65)- (1/120) = 50 Cubic meter
= 7000 Cubic Meter
Answer: option A
Question: How long will it take for a sum of money to grow from Rs.1250 to Rs.10,000, if it is invested at 12.5% p.a simple interest?
A.8 years
B.64 years
C.72 years
D.56 years
Answer: D.56 years
Explanation: Solution:
Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the number of years for which it is invested, r is the rate of interest per annum
In this case, Rs. 1250 has become Rs.10,000.
Therefore, the interest earned = 10,000 – 1250 = 8750.
8750 = [(1250*n*12.5)/100]
=> n = 700 / 12.5 = 56 years.
Answer D
Question: A Jon's company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio of revenue from car sales in 1996 to revenue from truck sales in 1996?
A. 1:2
B. 4:5
C. 1:1
D. 3:2
Answer: A. 1:2
Explanation: A Jon's company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996.1996- x----- y------- x+y
1997- x1---- y1-- x1+y1
x1= a*x .....(P)
y1= 1.07*y...(Q)
x1+y1/x+y = 1.01
solve using P and Q and find x/y
Question: A car moves at 98 km/hr. What is the speed of the car in meters per second ?
A.20 2/9m sec
B.22 2/9m sec
C.24 2/9m sec
D.27 2/9m sec
Answer: D.27 2/9m sec
Explanation: Explanation:
Speed=(98∗5/18)m/sec
=245/9 m/sec
=27 2/9msec
Option D
Question: By selling a bat for Rs. 640/- a man loses 20% what is that bat cost price
A.Rs.800/-
B.Rs.820/
C.Rs.840/
D.Rs.860/
Answer: A.Rs.800/-
Explanation: Explanation:
80 % ------> 640 (80 * 8 = 640)
100 % ------>800 (100 * 8 = 800)
Cost price = Rs.800/-
Answer: Option A
Question: The perimeter of a square is 28 cm. What is the perimeter of a circle whose radius is equal to the side of the square?(in cm)
A.14
B.28
C.42
D.44
Answer: D.44
Explanation: Side of the square=28/4=7
Diameter of the circle=7x2=14
Perimeter of the circle= Ï€xD=(22/7)x14 = 44cm
Answer: D
Question: How many zeros does 100! end with?
A.20
B.24
C.25
D.30
Answer: B.24
Explanation: According to above 100! has 100/5+100/25=20+4=24 trailing zeros.
Answer: B.
Question: E = {2, 3, 4, 5}
B = {4, 5, 6, 7, 8}
Two integers will be randomly selected from the sets above, one integer from set E and one integer from set B. What is the probability that the sum of the two integers will equal 9 ?
A. 0.15
B. 0.20
C. 0.25
D. 0.30
Answer: B. 0.20
Explanation: The total number of pairs E,B possible is 4*5=20. Out of these 20 pairs only 4 sum up to 9: (2, 7); (3, 6), (4, 5) and (5, 4). The probability thus is 4/20=0.2.
Answer: B.
Question: In how many years will a sum of money doubles itself at 25% per annum on simple interest?
A.8%
B.2%
C.3%
D.4%
Answer: D.4%
Explanation: P = (P*25*R)/100
R = 4%
ANSWER:D
Question: A,B,C together can do a work in 30 days. A alone can do the work in 80 days and B alone can do the same work in 100 days. Find in what time C alone can do that work?
A.75days
B.85.65days
C.88.50days
D.92.31days
Answer: D.92.31days
Explanation: The required answer is = 30*80*100 / 80*100-30(80+100)
= 240000/2600 = 92.31days
Answer is D
Question: An unbiased die is tossed. Find the probability of getting a multiple of 5
A.A)1/3
B.B)2/5
C.C)1/6
D.D)2/3
Answer: C.C)1/6
Explanation: Here S = {1,2,3,4,5,6}
E = event of getting a multiple of 5
E = {5}
P(E) = 1/6
Answer is C
Question: What will come in place of the question mark (?) in the following questions?
22% of ? + 166.64 = 340
A.790
B.548
C.888
D.788
Answer: D.788
Explanation: D
788
(?*22)/100 = 340 - 166.64 = 173.36
? = (173.36 * 100)/22
? = 788
Question: By selling 99 pens, a trader gains the cost of 33 pens. Find his gain percentage?
A.33 1/3%
B.33 1/9%
C.33 9/3%
D.32 1/3%
Answer: A.33 1/3%
Explanation: Let the CP of each pen be Rs. 1.
CP of 99 pens = Rs. 99
Profit = Cost of 33 pens = Rs. 33
Profit% = 33/99 * 100 = 33 1/3%
Answer: A
Question: A hat company ships its hats, individually wrapped, in 8-inch by 10-inch by 12-inch boxes. Each hat is valued at $7.50. If the company’s latest order required a truck with at least 192,000 cubic inches of storage space in which to ship the hats in their boxes, what was the minimum value of the order?
A.$960
B.$1,350
C.$1,500
D.$2,050
Answer: C.$1,500
Explanation: Number of boxes= Total volume/volume of one box= 192,000/ (8*10*12)= 200
One box costs 7.50, so 200 box will cost= 200*7.5= 1500
C is the answer
Question: A box contains 4 chocobars and 4 ice creams. Tom eats 3 of them, by randomly choosing. What is the probability of choosing 2 chocobars and 1 icecream?
A.9/3
B.1/7
C.2/8
D.2/7
Answer: B.1/7
Explanation: Probability of choosing 1 chocobar = 4/8 = 1/2
After taking out 1 chocobar, the total number is 7.
Probability of choosing 2nd chocobar = 3/7
Probability of choosing 1 icecream out of a total of 6 = 4/6 = 2/3
So the final probability of choosing 2 chocobars and 1 icecream = 1/2 * 3/7 * 2/3 = 1/7
B
Question: Ross is looking at Rachel, but Rachel is looking at Joey. Ross is married, but Joey is not. Is married person looking at the unmarried person?
A.Yes
B.No
C.Insufficient information
D.data irrelevant
Answer: A.Yes
Explanation: Explanation:
If Rachel is married, Joey who is unmarried is looking ar Rachel who is married.
If Rachel is unmarried, then Ross who is married is looking at Rachel who is unmarried.
Answer is A
Question: Rachel and Sarah spent $8 for gasoline, $15.65 for their lunch, and $5 apiece for gifts for Grandma.
Grandma gave each of them $10. If the girls left home with a total of $50, how much do they have for
the return trip?
A.$36.35
B.$26.35
C.$16.35
D.$46.35
Answer: A.$36.35
Explanation: $50 + $20 = $70 what they left with
plus $10 to each
$8 + $15.65 + $10 = $33.65 what they spent
(gifts are $5 + $5)
$70 - $33.65 = $36.35 left
correct answer A
Question: If the number 52,1n5, where n represents the tens digit, is a multiple of 3, then the value of n could be which of the following?
A.6
B.5
C.3
D.1
Answer: B.5
Explanation: The sum of the digits 5 + 2 + 1 + n + 5 must be a multiple of 3
13 + n must be a multiple of 3
substituting the numbers n must = 5
Answer B
Question: The average salary of all the workers in a workshop is Rs. 6750. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is?
A.A)23
B.B)21
C.C)52
D.D)56
Answer: D.D)56
Explanation: Let the total number of workers be x. Then,
6750x
= (12000 * 7) + 6000(x - 7)
=> 750x = 42000
= x =56.
Answer:D
Question: Evaluate: 12 + sqrt(- 5 + 7Ã—8Ã·4) =?
A.90
B.91
C.92
D.93
Answer: D.93
Explanation: According to order of operations, inner brackets first where 7x8Ã·4 is first calculated since it has a multiplication and a division.
7x8Ã·4 = 56Ã·4 = 14
Hence
12 + sqrt(- 5 + 7Ã—8Ã·4) = 12 + sqrt(- 5 + 14)
= 12 + sqrt(9) = 12 + 81 = 93
correct answer D)93
Question: An art gallery owner is hanging paintings for a new show. Of the four paintings she has to choose from, she can only hang three on the main wall of the gallery. Assuming that she hangs as many as possible on that wall, in how many ways can she arrange the paintings?
A.18
B.30
C.64
D.4
Answer: D.4
Explanation: Arrangement means permutations questions..
4P3 = 4!/3! = 4
.
ANS option D is correct answer..
Question: 1345 - (1002 / 20.04) = ?
A.2984
B.2983
C.2982
D.1295
Answer: D.1295
Explanation: 1345-50=1295
Answer :D
Question: Ramesh purchased a refrigerator for Rs. 12500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 20% if no discount was offered?
A.19200
B.17606
C.17604
D.17600
Answer: A.19200
Explanation: Price at which the TV set is bought = Rs. 12,500
Discount offered = 20%
Marked Price = 12500 * 100/80 = Rs. 15625
The total amount spent on transport and installation = 125 + 250 = Rs. 375\Total price of TV set = 15625 + 375 = Rs. 16000
The price at which the TV should be sold to get a profit of 20% if no discount was offered = 16000 * 120/100 = Rs. 19200.Answer: A
Question: 5 men 2 boys working together can do 4 times as much work as a man and a boy working capacities of a woman and boy are in ratio?
A.1:2
B.2:1
C.1:3
D.3:1
Answer: B.2:1
Explanation: Explanation:
1 man’s 1 day work = x
1 boy’s 1 day work = y
5x+2y = 4(x + y) => x = 2y => 2:1
Answer: Option B
Question: A boat crossed a lake from North to South at the speed of 4 km/h, entered a river and covered twice as much distance going upstream at 3 km/h. It then turned around and stopped at the south shore of the lake. If it averaged 3.5 km/h that day, what was its approximate downstream speed?
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: Another way will be:
Total time for the trip = distance covered in Lake/speed in still water +distance covered upstream/upstream speed + distance covered downstream/downstream speed
If 5D is the total distance, then distance covered in lake = D, distance covered upstream = 2D and distance covered downstream = 2D
=>5D/3.5 = D/4 + 2D/3 + 2D/x (where x is the downstream speed)
=> 5/3.5 = 1/4 + 2/3 +2/x (div. both sides by D)
=> 1.42 = .25+.66 +.51/x => x=3.9 ~ 4
option A
Question: The following sets each have a mean of 20 and the standard deviations are given in variable form.
Set I = {10, 10, 10, 30, 30, 30}, standard deviation = P
Set II = {14, 16, 18, 22, 24, 26}, standard deviation = Q
Set III = {20, 20, 20, 20, 20, 20}, standard deviation = R
Rank these three standard deviations from greatest to least.
A.R, P, Q
B.P, Q, R
C.R, Q, P
D.Q, R, P
Answer: B.P, Q, R
Explanation: The answer should be B as the mean is most deviated in Set I followed by Set II and then Set III.
Question: For what value of â€œkâ€ will the equation (2kx2 + 6kx +2)=0 have equal roots?
A.2/7
B.4/9
C.16/25
D.7/1
Answer: B.4/9
Explanation: for a 2nd degree equation ax2+bx_c=0 has equal roots the condition is b2-4ac =0
in the given equation
(6k)^2-4*2k*2=0
by solving this equation
we get k=0, k=4/9
ANSWER:B
Question: The average marks obtained by 120 candidates in a certain examinationis 35.if the average marks of passed candidate is 39 and that of the failed candidates is 15,what is the no. of candidates who passed the examination?
A.80
B.100
C.110
D.140
Answer: B.100
Explanation: Let No. of passed candidates are x
So, x * 39 + (120 – x) 15= 120 * 35
x = 100
B
Question: Elana was working to code protocols for computer processing. She did 11/18 of the job and allowed Andy to finish it. They both work at the same rate and receive the same hourly pay. If the difference between the amounts they were paid was $154, what was the total amount the two were paid for the entire coding job?
A.$252.00
B.$269.50
C.$369.00
D.$423.50
Answer: C.$369.00
Explanation: Elena did 11/18 of The job so 7/18 was done by Andy. As 11/18+7/18=1
Now difference between work done is 11/18-7/18=4/18.
So for this 4/18 work the difference is 154.
Hence x= 154*18/4 = 693
Option - C.
Question: A cube of side one meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?
A.2997
B.2799
C.1000
D.2272
Answer: C.1000
Explanation: Along one edge, the number of small cubes that can be cut
= 100/10 = 10
Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut = 10 * 10 * 10
=1000
Answer:C
Question: Ramu rides his bike at an average speed of 45 km/hr and reaches his desitination in four hours. Somu covers the same distance in five hours. If Ramu covered his journey at an average speed which was 9 km/hr less and Somu covered his journey at an average speed which was 10 km/hr more, then the difference in their times taken to reach the destination would be (in minutes).
A.65 minutes
B.66 minutes
C.56 minutes
D.69 minutes
Answer: B.66 minutes
Explanation: Distance travelled by Ramu = 45 * 4 = 180 km
Somu travelled the same distance in 5 hours.
His speed = 180/5 = 36 km/hr
Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 36 + 10 = 46km/hr.
Therefore travel time of Ramu and Somu would be 5 hours and 3.9 hours respectively. Hence difference in the time taken = 1.1 hours = 66 minutes.
ANSWER:B
Question: A batsman makes a score of 64 runs in the 16th innings and thus increased his average by 3. Find his average after the 16th inning?
A.22
B.77
C.26
D.19
Answer: D.19
Explanation: Let the average after the 16th inning be P.
So, the average after the 15th inning will be (P-3) Hence, 15(P-30) + 64 = 16P => P = 19.
Answer:D
Question: A person travelled from his house to office at 30km/hr and office to house at 50km/hr. Then find the average speed?
A.37.5km/hr
B.20km/hr
C.32km/hr
D.24km/hr
Answer: A.37.5km/hr
Explanation: Average speed = (2*30*50)/(30+50)
= 37.5km/hr
Answer is A
Question: A rectangle measures 8 Cm on length and its diagonal measures 17 Cm. What is the perimeter of the rectangle?
A.44cm
B.42cm
C.46cm
D.49cm
Answer: C.46cm
Explanation: Second side = √17power2-8power2
= √289-64
= 15 Cm
Perimeter = 2 (l+b) = 2(8+5) Cm = 2(23) = 46 Cm
Answer is C.
Question: 4% of the population of a certain country owns both a car and a boat. If 20% of those who own a boat, do not own a car, what percentage of the country's population owns a boat?
A.5%
B.7.5%
C.10%
D.12.5%
Answer: A.5%
Explanation: 0.04x has B+C ( x is total population)
Let # of people who own a boat = y
20% of those who own a boat, do not own a car
=> 0.2y do not have a car
=> 80% of those who own a boat own a car
=> 0.8y = 0.04x
=> y/x = 4/80
So %age = 4/80 * 100 = 5%
Answer - A
Question: A conference is to have eight presentations over the course of one day, consisting of three long presentations, and five short presentations. If the conference organizer doesn't want consecutive long presentations, and the conference is to start with a short presentation, how many schedules of presentations are possible?
A.1200
B.7200
C.2880
D.5760
Answer: B.7200
Explanation: S*S*S*S*S*
5 short presentations can be arranged in 5!=120 ways.
As for 3 long presentations: each can be placed instead of any of the 5 star, so in C35=10C53=10 ways, and they also can be arranged in 3!=6 ways.
Total = 120*10*6 = 7,200
Ans:B
Question: The ratio, in which tea costing Rs. 192 per kg is to be mixed with tea costing Rs. 150 per kg so that the mixed tea when sold for Rs. 194.40 per kg, gives a profit of 20%.
A.2:5
B.3:5
C.5:3
D.5:2
Answer: A.2:5
Explanation: Solution: CP of first tea = Rs. 192 per kg.
CP of Second tea = Rs. 150 per kg.
Mixture is to be sold in Rs. 194.40 per kg, which has included 20% profit. So,
SP of Mixture = Rs. 194.40 per kg.
Let the CP of Mixture be Rs. X per kg. Therefore,
X + 20% of X = SP
6X /5 = 194.40
6X = 194.40 *5
X = Rs. 162 per kg.
Let N kg of first tea and M kg of second tea to be added.
Now, Using Alligation,
We get,
N/M = 12/30
N : M = 2 : 5.
Answer: Option A
Question: Solve the following quadratic equation by factoring.
X^2+15X=-50
A.10,4
B.4,-10
C.5,10
D.-5,-10
Answer: D.-5,-10
Explanation: Now all we need to do is use the zero factor property to get,
X+5=0 X=-5 (OR) X+10 = 0 X=-10
ANSWER D -5,-10