RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the rate in the remaining 40 overs to reach the target of 282 runs?
A.6.25
B.6.22
C.6.29
D.6.39
Answer: A.6.25
Explanation: Required run rate
= [282 - (3.2 * 10)]/40
= 250/40
= 6.25
Answer: A
Question: Visitors to show were charged Rs.15 each on the first day. Rs.7.50 on the second day, Rs.2.50 on the third day and total attendance on the three days were in ratio 2:5:13 respectively. The average charge per person for the whole show is?
A.2
B.7
C.5
D.6
Answer: C.5
Explanation: 2: 5: 13
2x 5x 13x
15 7.5 2.5
30x + 37.5x + 32.5x = 100x/20x
Average = 5
Answer: C
Question: There were two candidates in an election. Winner candidate received 55% of votes and won the election by 100 votes. Find the number of votes casted to the winning candidate?
A.550
B.744
C.255
D.199
Answer: A.550
Explanation: W = 55% L = 45%
55% - 45% = 10%
10% -------- 100
55% -------- ? => 550
Answer:A
Question: A person invested in all 2600 at 4%, 6% and 8% per annum simple interest. At the end of the year, he got the same interest in all the three cases. The money invested at 4% is:
A.200
B.600
C.800
D.1200
Answer: D.1200
Explanation: Let the parts be x, y and [2600 – (x + y)].Then,
x×4×1/100=y×6×1/100=[2600−(x+y)]×8×1/100
∴ y⁄x = 4⁄6 = 2⁄3 or y = 2⁄3x.
So, x×4×1100=[2600−53x]×8100x×4×1100=[2600−53x]×8100
⇒ 4x = (7800−5x)×8/3⇒52x=(7800×8)
⇒ x = (7800×8/52)=1200.
∴ Money invested at 4% = 1200.
Answer D
Question: There are 23 students in a class. In how many different ways can a committee of 3 students be formed?
A.1254
B.1482
C.1771
D.1875
Answer: C.1771
Explanation: 23C3 = 23*22*21 / 6 = 1771
The answer is C.
Question: What will come in place of the x in the following Number series? 2, 4, 8, x , 22
A.33
B.16
C.12
D.14
Answer: D.14
Explanation: (D)
The pattern is + 2, + 4, + 6, +8 â€¦â€¦â€¦..
So the missing term is = 8 + 6= 14
Question: A pair of articles was bought for $50 at a discount of 20%. What must be the marked price of each of the article?
A.$25
B.$31.25
C.$29.65
D.$35.95
Answer: B.$31.25
Explanation: S.P. of each of the article = 50/2 = $25
Let M.P = $x
80% of x = 25
x = 25*100/80 =$31.25
Answer is B
Question: If Rs.450 amount to Rs.540 in 4 years, what will it amount to in 6 years at the same rate % per annum?
A.227
B.887
C.585
D.2679
Answer: C.585
Explanation: 90 = (450*4*R)/100
R = 5%
I = (450*6*5)/100 = 135
450 + 135 = 585
Answer:C
Question: A man swims downstream 30 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water?
A.2
B.8
C.9
D.6
Answer: B.8
Explanation: 30 --- 3 DS = 10
? ---- 1
18 ---- 3 US = 6
? ---- 1 M = ?
M = (10 + 6)/2 = 8
Answer: B
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?
A.30/45 hours
B.30/14 hours
C.37/13 hours
D.30/13 hours
Answer: D.30/13 hours
Explanation: Speed downstream = 20 + 6 = 26 kmph.
Time required to cover 60 km downstream = d/s = 60/26
= 30/13 hours.
Answer: D
Question: A 300 meter long train crosses a platform in 30 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
A.287m
B.278m
C.350m
D.200m
Answer: D.200m
Explanation: Speed = [300 / 18] m/sec = 50/3 m/sec.
Let the length of the platform be x meters.
Then, x + 300 / 30
= 50/3
3(x + 300)
= 1500 è x
= 200m.
Answer:D
Question: Find the least number of complete years in which a sum of money put out at 15% compound interest will be more than double of itself?
A.5
B.6
C.7
D.8
Answer: A.5
Explanation: 5 years
Answer: A
Question: A baker filled with a measuring cup with 2/5 cup water. He poured 1/2 of the water into the batter, and then spilled 1/8 of the water on the floor. How much water will the baker needed to add what is left in the cup to have 50% more than what he started with?
A.1/8 cup
B.3/8 cup
C.21/40 cup
D.1/2 cup
Answer: C.21/40 cup
Explanation: 2/5 is the original water in cup .half in batter.So left is 1/5 out which 1/8 is spilled out.So again left with 3/40.
so 50% more than what he started was =2/5+1/2*(2/5)=3/5
Amount of water needed to add = 3/5 - 3/40=21/40
C
Question: A man walks at a speed of 3 km/hr and runs at a speed of 6 km/hr. How much time will the man require to cover a distance of 10 1/2 km, if he completes half of the distance, i.e., (5 1/4) km on foot and the other half by running?
A.2.62
B.2.56
C.2.5
D.2.8
Answer: A.2.62
Explanation: Required time = (5 1/4)/3 + (5 1/4)/6 = 2.625 hours.
Answer:A
Question: do you know how many 2's are there between the terms 112 to 375?
A.A)156
B.B)157
C.C)158
D.D)159
Answer: A.A)156
Explanation: Let us calculate total 2's in the units place. (122, 132, 142 ... 192), (201, 212, 222, ... 292), (302, 312, ... 372) = 8 + 10 + 8 = 26
Total 2's in tenth's place, (120, 121, 122, ..., 129) + (220, 221, ..., 229) + (320, 321, ..., 329) = 30
Total 2's in hundred's place = (200, 201, ... 299) = 100.
Total 2's between 112 and 375 = 26 + 30 + 100 = 156
Answer:A
Question: Today Jim is twice as old as Fred, and Sam is 2 years younger than Fred. Five years ago Jim was 5 times as old as Sam. How old is Jim now?
A.8
B.12
C.16
D.20
Answer: D.20
Explanation: We're asked how old Jim is NOW. We're given three facts to work with:
1) Today, Jim is TWICE as old as Fred
2) Today, Sam is 2 years younger than Fred
3) Five years ago, Jim was 5 times as old as Sam.
let's TEST Answer D: 20
IF....Jim is currently 20 years old....
Fred is 10 years old
Sam is 8 years old
5 years ago, Jim was 15 and Sam was 3, so Jim WAS 5 times Sam's age. This is an exact MATCH for what we were told, so this MUST be the answer.
D
Question: A shopkeeper sold an article offering a discount of 10% and earned a profit of 25%. What would have been the percentage of profit earned if no discount was offered?
A.39%
B.52%
C.15%
D.21%
Answer: A.39%
Explanation: Let C.P. be $100.
Then, S.P. = $ 125
Let marked price be $ x. Then, 90/100 * x = 125
x = 12500/90 = $ 139
Now, S.P. = $ 139, C.P. = Rs. 100
Profit % = 39%.
Answer: A
Question: A man purchased some fruits for Rs. 1000. He sold fruits worth 400 at 10% profit. At what profit per cent, must he sell the rest in order to gain 20% on the whole?
A.26(2/3)%
B.25%
C.30%
D.33(1/3)%
Answer: A.26(2/3)%
Explanation: Solution: To get 20 % profit on whole,
1000(CP)==20%(gain)==>1200(SP).
Total Profit = 1200 - 1000 = Rs. 200.
400 ==10%(gain)==>440.
He gets Rs. 40 profit on 400 hundred. Rest Profit = 200 - 40 = 160.
Then he must get Rs. 160 as profit on Rs. 600;
Hence, % profit = 160*100/600 = 26.66%.
Answer: Option A
Question: Find the volume , curved surface area and the total surface area of a cylinder with diameter of base 7 cm and height 40 cm.
A.952cm^2
B.957cm^2
C.954cm^2
D.958cm^2
Answer: B.957cm^2
Explanation: Volume = ∏r2 h = ((22/7)x(7/2)x(7/2)x40) = 1540 cm^3. .
Curved surface area = 2∏rh = (2x(22/7)x(7/2)x40)= 880 cm^2 .
Total surface area = 2∏rh + 2∏r2 = 2∏r (h + r)
= (2 x (22/7) x (7/2) x (40+3.5)) cm2
= 957 cm^2
Answer is B
Question: A thief is noticed by a policeman from a distance of 250 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
A.100
B.277
C.2987
D.150
Answer: D.150
Explanation: Relative speed of the thief and policeman = 11 - 10 = 1 km/hr.
Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.
Distance between the thief and policeman = 250 - 100 = 150 m.
Answer: D
Question: Working simultaneously and independently at an identical constant rate, 20 machines of a certain type can produce a total of x units of product P in 4 days. How many of these machines, working simultaneously and independently at this constant rate, can produce a total of 3x units of product P in 8 days?
A.30
B.32
C.35
D.38
Answer: A.30
Explanation: The rate of 20 machines is rate=job/time=x/4 units per day --> the rate of 1 machine 1/20*(x/4)=x/80 units per day;
Now, again as {time}*{combined rate}={job done}
then 8*(m*x/80)=3x --> m=30.
Answer: A.
Question: (6+√3+√5)^2-(√3+√5)^2=?
A.1+2√3+2√5
B.36+12√3+12√5
C.1-√3+√5
D.1+√3-√5
Answer: B.36+12√3+12√5
Explanation: (6+√3+√5)^2-(√3+√5)^2
(6+√3)^2 + 5 +2 (6+√3) (√5) - ( 3 +5 + 2√3√5)
36+ 3+ 12√3 +5 +12 √5 + 2 √15 - 3-5 -2√15
36+12√3+12√5
B is the answer
Question: Two unbiased coins are tossed. Find the probability of getting two heads?
A.1/2
B.1/3
C.1/4
D.2/3
Answer: C.1/4
Explanation: S = {HH,HT,TH,TT}
E = Event of getting two heads
E = {TT}
P(E) = 1/4
Answer is C
Question: Find the odd man out. 742, 743, 633, 853, 871, 990, 532
A.532
B.990
C.633
D.742
Answer: D.742
Explanation: Explanation :
In all numbers except 742, the difference of third and first digit is the middle digit.
Answer : Option D
Question: The average monthly salary of 18 employees in an organisation is Rs. 2000. If the manager's salary is added, then the average salary increases by Rs. 200. What is the manager's monthly salary?
A.Rs.5800
B.Rs.3618
C.Rs.3600
D.Rs.3619
Answer: A.Rs.5800
Explanation: Manager's monthly salary
= Rs. (2200 * 19 - 2000 * 18)
=Rs.5800 Answer:A
Question: The area of a square is equal to nine times the area of a rectangle of dimensions 121 cm * 144 cm. What is the perimeter of the square?
A.1500 cm
B.1800 cm
C.1584 cm
D.1718 cm
Answer: C.1584 cm
Explanation: Area of the square = s * s = 9(121 * 144)
=> s = 3* 11 * 12 = 396 cm
Perimeter of the square = 4 * 396 = 1584 cm.
Answer: C
Question: (.24 x .35 ) / (.14 x .15 x .02) is equal to ?
A.2
B.20
C.200
D.2000
Answer: C.200
Explanation: Answer
(.24 x .35) / (.14 x .15 x .02)
= (24 x 35 x 100 ) / (14 x 15 x 2)
=200
Correct Option: C
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 50 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
A.21
B.88
C.45
D.99
Answer: C.45
Explanation: Relative speed = 50 + 30 = 80 km/hr.
80 * 5/18 = 200/9 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 9/200 = 45 sec
Answer: C
Question: A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 424. What is the sum of the last 8 of the even integers?
A.488
B.540
C.552
D.568
Answer: C.552
Explanation: Sum of n even consecutive integers = n(n+1)
Sum of 8 consecutive even integers that start at some point after n = (n+8)(n+9)
Given => (n+8)(n+9) - n(n+1) = 424
16n +72 = 424 - General equation for sum of consecutive 8 digits where n is where counting starts
Solving we get n = 22 (Where the count starts)
Sum of 8 consecutive integers after n = 22 will be count starting at n1 = 22+8 = 30
So Answer = 16*30 +72 = 552
ANSWER:C
Question: In an election, candidate A got 70% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favor of candidate.
A.330000
B.340000
C.347000
D.333200
Answer: D.333200
Explanation: Total number of invalid votes = 15 % of 560000
= 15/100 × 560000
= 8400000/100
= 84000
Total number of valid votes 560000 – 84000 = 476000
Percentage of votes polled in favour of candidate A = 70 %
Therefore, the number of valid votes polled in favour of candidate A = 70 % of 476000
= 70/100 × 476000
= 33320000/100
= 333200
D)
Question: For any integer k greater than 1, the symbol k* denotes the product of all integers between 1 and k, inclusive. If k* is a multiple of 2835 what is the least possible value of k?
A.5
B.7
C.9
D.11
Answer: C.9
Explanation: 2835 = 3*3*3*3*5*7
Thus k must include numbers at least up to the number 9 so that there are at least four appearances of 3 (that is: 3, 6, and 9=3*3).
The answer is C.
Question: On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent E of thatbeforeJuly 1 last year?
A.90%
B.99%
C.100%
D.101%
Answer: B.99%
Explanation: the total number of employees = n
the average salary = x
total salary to all emplyoees = xn
after
the total number of employees = n - 0.1n = 0.9n
the average salary = x + 10% of x = 1.1x
total salary to all emplyoees = 0.9n (1.1x)
total salary after as a % of total salary before E = [0.9n (1.1x)]/xn= 0.99 or 99%=B
Question: An exam paper consists of 5 problems, each problem having 3 internal choices. In how many ways can a candidate attempt one or more problems?
A.1020
B.1023
C.1030
D.1054
Answer: B.1023
Explanation: Given that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.
Hence, the required number of ways = 45 - 1.
= 210 - 1 = 1024 - 1 = 1023
B
Question: A 300 m long train crosses a platform in 42 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.286 m
B.350 m
C.277 m
D.400 m
Answer: D.400 m
Explanation: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/42 = 50/3
x = 400 m.
Answer:D
Question: If a 9 ton whale is divided into 2 equal large pieces and 3 equal small pieces, how much does a small piece weigh if all of the small pieces put together weigh as much as one of the large pieces?
A.1 ton
B.1 1/2 tons
C.2 tons
D.2 1/2 tons
Answer: A.1 ton
Explanation: A. Each large piece is a third of the whale. Each small piece is a third of the remaining third of the whale. One third of one third is one ninth. One ninth of nine tons is one ton, so the answer is A
Question: W, S, Q, M, ?
A.M
B.K
C.H
D.Y
Answer: B.K
Explanation: Explanation:
No explanation is available for this question!
ANSWER: B
Question: The sum of digits of a two digit number is 12,The difference between the digits is 6. Find the number
A.85
B.93
C.83
D.72
Answer: B.93
Explanation: Description :
=> x+y=12, x-y=6
Adding these 2x =18
=> x=9, y=3.
Thus the number is 93
Answer B
Question: ax ± b = c. All problems like the following lead eventually to an equation in that simple form.
Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse. How much was the blouse?
A.28
B.26
C.24
D.22
Answer: A.28
Explanation: Every word problem has an unknown number. In this problem, it is the price of the blouse. Always let x represent the unknown number. That is, let x answer the question.
Let x, then, be how much she spent for the blouse. The problem states that "This" -- that is, $42 -- was $14 less than two times x.
Here is the equation:
2x − 14 = 42.
2x=42+14
=56.
x=56/2
= 28
The blouse cost $28.
Answer is A.
Question: The daily high temperatures were recorded at an Antarctic weather station. If a temperature of -38.2 degrees Celsius is 2 units of standard deviation below the mean temperature, and a temperature of -22.6 degrees Celsius is 4 units of standard deviation above the mean, which of the following temperatures is 5 unit of standard deviation above the mean?
A.-35.6 degrees Celsius
B.-20.0 degrees Celsius
C.-30.4 degrees Celsius
D.-27.8 degrees Celsius
Answer: B.-20.0 degrees Celsius
Explanation: Let us suppose mean = M and SD = d.
So, we are given M - 2d = -38.2
and M + 4d = -22.6
solving both the equations, we will get M = -33 an d = 2.6
So, we need to find out M + 5d = -33 +5* 2.6 = -20. Hence, B
Question: A license plate in the country Kerrania consists of four digits followed by two letters. The letters A, B, and C are used only by government vehicles while the letters D through Z are used by non-government vehicles. Kerrania's intelligence agency has recently captured a message from the country Gonzalia indicating that an electronic transmitter has been installed in a Kerrania government vehicle with a license plate starting with 79. If it takes the police 15 minutes to inspect each vehicle, what is the probability that the police will find the transmitter within three hours?
A.18/79
B.1/75
C.1/25
D.1/50
Answer: B.1/75
Explanation: If it takes 15 minutes to inspect one vehicle, the # of vehicles that can be inspected in 3 hours (180 minutes) = 180/15 = 12. Hence, for calculating the probability that the police will find the transmitter within three hours, the favorable cases = 12. Now, we need to figure out the total # of cases.
The total # of cases = Total # of such cars possible. The details given about the car is that it starts with 79, which leaves 2 more digits, both of which can be filled by all 10 numbers (0-9). In addition, we have 3 letters, each of which can be filled by any from the set {A,B,C}. Hence the total # of such cars possible = 10*10*3*3 = 900
So, the probability that the police will find the transmitter within three hours = 12/900 = 1/75. Option B
Question: Let y = 2g + x^2 and g = 4x + 1.
If g^2 = 289, then which of the following can be a value of 2y + 3g?
A.100
B.130
C.141
D.151
Answer: D.151
Explanation: 800score Official Solution:
First note that g can either be 17 or -17. We are going to have to use both to find all solutions before we can choose a final answer. We begin by substituting g = 17 and then g = -17. If g = 17, then x = 4. If g = -17, then x = -18/4. Since all of our solutions are whole numbers, we can dismiss -18/4. We use g = 17 and x = 4 to determine the value of y: y = 2(17) + 16 =50. Finally, we substitute the values for y and g into the last expression to determine its value : 2(50) + 3(17) = 100 + 51 = 151;the correct answer is (D).
Question: For any number y, y* is defined as the greatest positive even integer less than or equal to y. What is the value of 6.2 – 6.2*?
A.0.2
B.1.2
C.1.8
D.2.2
Answer: D.2.2
Explanation: Since y* is defined as the greatest positive even integer less than or equal to y, then 6.2* = 4 (the greatest positive even integer less than or equal to 6.2 is 4).
Hence, 6.2 – 6.2* = 6.2 - 4 = 2.2
Answer: D.
Question: A high school had 1200 students enrolled in 2003 and 1500 students in 2006. If the student population P ; grows as a linear function of time t, where t is the number of years after 2003.
a) How many students will be enrolled in the school in 2010?
A.1800
B.1900
C.1700
D.1500
Answer: B.1900
Explanation: a) The given information may be written as ordered pairs (t , P). The year 2003 correspond to t = 0 and the year 2006 corresponds to t = 3, hence the 2 ordered pairs
(0, 1200) and (3, 1500)
Since the population grows linearly with the time t, we use the two ordered pairs to find the slope m of the graph of P as follows
m = (1500 - 1200) / (6 - 3) = 100 students / year
The slope m = 100 means that the students population grows by 100 students every year. From 2003 to 2010 there are 7 years and the students population in 2010 will be
P(2010) = P(2003) + 7 * 100 = 1200 + 700 = 1900 students
Answer B
Question: If selling price is doubled, the profit triples. Find the profit percent.
A.200/3
B.100
C.316/3
D.120
Answer: B.100
Explanation: Explanation :
Let the C.P. be x and the S.P. be y
So the profit is (y - x) ---------------------------- (1)
Now, the S.P. is doubled. So the new S.P. = 2y
The new profit = (2y - x)
Given that when S.P. is doubled, profit increases 3 times
=> New profit = 3 * old profit
=> (2y - x) = 3(y - x)
=> y = 2x
So, the profit = (y - x) = (2x - x) = x
% profit = (x/x∗100)% = 100%
Answer : B
Question: There are 20 boys and 15 girls are present in a class. If 5 student will chosen for a competition an at least two students must be girl?
A.309128
B.320000
C.251230
D.301000
Answer: A.309128
Explanation: 15 girls and 20 boys. Five students needed
It is always better to subtract the total from none in case of at least one problems.
Total ways = 35C5 = 324632
Total ways without any girl = 20C5 = 15504
Hence ways in which at least one women will be present = 324632 - 15504 = 309128
Correct option: A
Question: Find avrg speed if a man travels at speed of 32km/hr up and 48km/hr dawn at an altitude of 230m.
A.25.8
B.26.8
C.38.4
D.34.4
Answer: C.38.4
Explanation: avg speed=2*x*y/(x+y)
=2*32*48(32+48)=38.4
ANSWER:C
Question: 22 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be :
A.84 m
B.28 m
C.120 m
D.137 m
Answer: B.28 m
Explanation: Sol.
Let the length of the wire b h.
Radius = 1/2 mm = 1/20 cm. Then,
22/7 * 1/20 * 1/20 * h = 22 ⇔ = [22 * 20 * 20 * 7 / 22] = 2800cm = 28 m.
Answer B
Question: A farmer has three different crops on his farm; cabbage, carrots, and parsnips, where 10 percent of the crops are cabbage and 35 percent are carrots. If the farm produces 650 pounds of parsnips, and the weight of all crops are evenly distributed, how many pounds of crops are produced in total?
A. 6,500 pounds
B. 2,000 pounds
C. 10 pounds
D. 1,000 pounds
Answer: D. 1,000 pounds
Explanation: Let the total pounds of crops be x
% of cabbage = 10%
% of carrots = 35%
% of parsnips = 100% - 45% = 65%
But this number is given as 500 pounds
so 65% of x = 650 and x = (650)(100/65)
x = 1,000
Therefore there a total of 1,000 pounds of crops.
Correct answer - D
Question: How many times are the hands of a clock at right angle in 2 weeks?
A.616
B.611
C.661
D.116
Answer: A.616
Explanation: In 1 day, they are at right angles 44 times.
In 14 days, they are at right angles 616 times. Answer: Option A
Question: The number of stamps that P and Q had were in the ratio of 7:2 respectively. After P gave Q 15 stamps, the ratio of the number of P's stamps to the number of Q's stamps was 2:1. As a result of the gift, P had how many more stamps than Q?
A.25
B.35
C.45
D.55
Answer: C.45
Explanation: P started with 7k stamps and Q started with 2k stamps.
(7k-15)/(2k+15) = 2/1
3k = 45
k = 15
P has 7(15) - 15 = 90 stamps and Q has 2(15)+15 = 45 stamps.
The answer is C.
Question: If the radii of umbra and penumbra cast by an object on a wall are of the ratio 2:6, what is the area of the penumbra ring around the umbra of the latter’s radius is 40 cms?
A.40288.57cm^2
B.40388.57cm^2
C.40488.57cm^2
D.40588.57cm^2
Answer: A.40288.57cm^2
Explanation: et the radius of umbra and penumbra are 2k and 6k.
Then as given radius of umbra=40cm
so 2k=40
k=20
radius of penumbra=20*6=120
area of penumbra ring around the umbra=area of penumbra-area of umbra
22/7*[(120)^2-(40)^2]
=40288.57cm^2
ANSWER:A
Question: A, B and C start a business each investing 20,000. After 5 months A withdrew 5000, B withdrew 4000 and C invests 6000 more. At the end of the year, a total profit of 69,900 was recorded. Find the share of B.
A.20,000
B.21,200
C.28,200
D.20,500
Answer: C.28,200
Explanation: Ratio of the capitals of A, B and C
= 20000 × 5 + 15000 × 7 : 20000 × 5 + 16000 × 7 : 20000 × 5 + 26000 × 7
= 205000 : 212000 : 282000 = 205 : 212 : 282.
B’s share = (69900 × 212⁄699) = 21200;
Answer C
Question: There are 36 carpenters in a crew. On a certain day, 29 were present. What percent showed up for work? (round to the nearest tenth)
A.50.6%
B.60.6%
C.70.6%
D.80.6%
Answer: D.80.6%
Explanation: x/100=29/36
Multiply the opposites:
29 x 100 = 2900
Divide by the remaining number:
80.55/2900.00
80.6%
correct answer D
Question: In a 100 m race, A runs at 8km per hour. If A gives B a start of 6 m and still him by 15 seconds, what is the speed of B ?
A.5.56 km/hr.
B.5.06 km/hr.
C.5.64 km/hr.
D.6.76 km/hr.
Answer: C.5.64 km/hr.
Explanation: Time taken by A to cover 100 m =(60 X 60 / 8000)	x 100 sec = 45 sec.
B covers (100 - 6) m = 94m in (45 + 15) sec = 60 sec.
B's speed = (94 x 60 x 60)/(60 x 1000)km/hr = 5.64 km/hr.
Answer is C
Question: A can finish a work in 10 days and B can do same work in half the time taken by A. then working together, what part of same work they can finish in a day?
A.1/5
B.1/6
C.1/7
D.3/10
Answer: D.3/10
Explanation: Explanation:
Please note in this question, we need to answer part of work for a day rather than complete work. It was worth mentioning here because many do mistake at this point in hurry to solve the question
So lets solve now,
A's 1 day work = 1/10
B's 1 day work = 1/5 [because B take half the time than A]
(A+B)'s one day work =
(1/10+1/5)=3/10
So in one day 3/10 work will be done
Answer: D