RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The true discount on Rs. 1760 due after a certain time at 12% per annum is Rs. 160. The time after which it is due is
A.11
B.66
C.77
D.10
Answer: D.10
Explanation: P.W. = Rs. (1760 -160) = Rs. 1600.
S.I. on Rs. 1600 at 12% is Rs. 160.
Time = 100 x 160 =	5	years = 5	x 12	months = 10 months.
1600 x 12	6	6
Answer: D
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?
A.180 sec
B.190 sec
C.170 sec
D.175 sec
Answer: B.190 sec
Explanation: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 1900 m
T = D/S
T = 1900/10
T = 190 Sec
ANSWER:B
Question: If one positive integer is greater than another positive integer by 4, and the difference of their cubes is 208, what is their sum?
A.8
B.10
C.12
D.14
Answer: A.8
Explanation: 1^3 = 1
2^3 = 8
3^3 = 27
4^3 = 64
5^3 = 125
6^3 = 216
The two numbers are 2 and 6.
The answer is A.
Question: There are 5women and 6 men in an office. In how many ways can a person can be selected?
A.10
B.11
C.12
D.15
Answer: B.11
Explanation: Number of ways in which a person can be selected = 5+6 = 11 ways
Answer is B
Question: The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 72% of the required amount. What is the net difference in the expenditure on that product?
A.12.5%
B.10%
C.15%
D.17%
Answer: B.10%
Explanation: Quantity X Rate = Price
1 x 1 = 1
0.72 x 1.25 = 0.9
Decrease in price = (0.1/1) × 100 = 10%
B)
Question: In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?
A.5/21
B.5/27
C.5/97
D.5/22
Answer: A.5/21
Explanation: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)
As remaining person can be any one among three couples left.
Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅
= (10 * 6)/252 = 5/21
Answer: A
Question: Monica planned her birthday party. She prepared 5 muffins for each of her guests and kept aside two additional muffins in case someone will want extra. After the party, it turned out that one of the guests didn't come but every one of the guests that did come ate six muffins and 4 muffins remained. How many guests did Monica plan on?
A.3.
B.5.
C.4.
D.6.
Answer: C.4.
Explanation: 5N +2 = 4 + 6(N-1)
Solving N= 4
Hence C
Question: Eleven bags are bought for Rs.1000 and sold at 10 for Rs.1400. What is the gain or loss in percentage?
A.10%
B.21%
C.24%
D.20%
Answer: C.24%
Explanation: Explanation:
As selling price is Rs.1400 for 10 bags, each bag is sold at Rs.140.
Hence, the profit is Rs.100 after selling 10 bags plus the selling price of 1 bag = 100 + 140 = Rs.240.
%profit = 240/1000 *100
= 24%
ANSWER C
Question: A, B and C enter into a partnership and their shares are in the ratio 1/2 : 1/3 : 1/4. After 2 months, A withdraws half of his capital and after 10 months, a profit of Rs. 378 is divided among them. What is B's share ?
A.144
B.378
C.217
D.299
Answer: A.144
Explanation: Explanation:
Ratio of initial investments = 1/2 : 1/3 : 1/4 = 6 : 4 : 3.
Let their initial investments be 6x, 2x and 3x respectively.
A : B : C = (6x * 2 + 3x * 10) : (4x * 12) : (3x * 12) = 42 : 48 : 36 = 7 : 8 : 6.
B's share = = Rs. 144.
Answer: A) 144
Question: Including Cara and Dan, there are seven members on the board of directors for a company. If the board is to be split up into a four-person subcommittee, what fraction of all the possible subcommittees that include Cara, also include Dan?
A.1/5
B.1/4
C.1/3
D.1/2
Answer: D.1/2
Explanation: The number of possible subcommittees with Cara is 6C3=20.
The number of possible subcommittees with Cara and Dan is 5C2=10.
The fraction of Cara's subcommittees which include Dan is 10/20=1/2.
The answer is D.
Question: In a deck of cards there are 52 cards numbered from 1 to 13. There are 4 cards of each number in the deck. If you insert 10 more cards with the number 10 on them and you shuffle the deck really good, what is the probability to pull out a card with a number 10 on it?
A.1/4.
B.7/31.
C.5/29.
D.4/13.
Answer: B.7/31.
Explanation: 4+10 tens/52+10 total cards=14/62=7/31
B
Question: A certain number when divided by 65 leaves a remainder 25, what is the remainder if the same no.be divided by 15?
A.4
B.5
C.6
D.8
Answer: C.6
Explanation: Explanation:
65 + 25 =90/15 =6 (Remainder)
C
Question: Which of the following must be divisible by 2 if z is a positive integer?
A.z^2*(z−5)
B.(z^2−2)
C.z(z+2)^3
D.(z−1)*z*(z+1)
Answer: D.(z−1)*z*(z+1)
Explanation: option D) (z−1)*z*(z+1) which represents the product of three consecutive integers
the product of 3 consecutive integers is divisible by both 2 and 3.
Answer is D
Question: A sum of money is borrowed and paid back in two annual installments of Rs. 882 each allowing 5% C.I. The sum borrowed was?
A.Rs.1648
B.Rs.1640
C.Rs.1289
D.Rs.1282
Answer: B.Rs.1640
Explanation: Principal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)
= [882/(1 + 5/100) + 882/(1 + 5/100)2]
= (882 * 20)/21 + (882 * 400)/441
= Rs.1640.
Answer:B
Question: Six lights begin to flash together at 12:00 noon and flash respectively at intervals of 4, 5, 6, 7, 8, and 9 seconds. Not including the flash at 12:00 noon, how many more times will all six lights flash together before 4:00 pm (i.e. four hours later)?
A.3
B.5
C.7
D.9
Answer: B.5
Explanation: The least common multiple is 2*2*2*3*3*5*7=2520.
14400 seconds / 2520 = 5 + remainder.
The answer is B.
Question: A and B rent a pasture for 10 months. A put in 80 cows for 7 months. How many can B put in for the remaining 3 months, if he pays half as much again as A?
A.388
B.277
C.266
D.280
Answer: D.280
Explanation: 80* 7: x* 3 = 1:1 1/2
560: 3x = 2: 3
x = 280
Answer: D
Question: Sahil took a loan for 6 years at the rate of 5% per annum on Simple Interest, If the total interest paid was Rs. 1230, the principal was
A.4100
B.4200
C.4300
D.4400
Answer: A.4100
Explanation: Explanation:
S.I.=P∗R∗T /100=>P=S.I.∗100/ R∗T
By applying above formula we can easily solve this question, as we are already having the simple interest.
=>P=1230∗100/ 6∗5
=>P=4100
Option A
Question: In March, Kurt ran an average of 2 miles an hour. If by June he had increased his pace by 10 seconds per mile, then which of the following expresses the number of hours it would take Kurt to complete one mile in June?
A.3590/60^2
B.2410/60^2
C.1790/60^2
D.3586/60
Answer: C.1790/60^2
Explanation: Kurt ran at an average of 2 miles/hour in march. So to run 1 mile he would take 1/2 hours = (60 * 60)/2 seconds = 1800 seconds.
If he increases his speed by 10 seconds, he will complete a mile in 1790 seconds. Converting in hours = 1790/(60 * 60) = 1790/(60^2)
ANSWER: C
Question: A can do a certain job in 20 days. B is 60% more efficient than A. How many days does B alone take to do the same job?
A.7 1/2 days
B.8 days
C.12 1/2 days
D.9 days
Answer: C.12 1/2 days
Explanation: Ratio of times taken by A and B = 160 : 100 = 8 : 5.
Suppose B alone takes x days to do the job.
Then, 8 : 5 :: 20 : x = 8x = 5 x 20 =x = 12 1/2 days.
Answer is C.
Question: The length and breadth of a rectangle are raised in the proportion 3:4 and 4:5 correspondingly. What is the proportion of the previous place to the new?
A.2:3
B.3:5
C.5:7
D.7:9
Answer: B.3:5
Explanation: Explanation :
-> If the real length = 3a
And the real breadth = 4a
Area = (3a)*(4a)
=12 a2
-> New Length is 4a and New breadth is 5a
New area is (4a)*(5a)
= 20 a2
Ratio of previous place to new place = 12 a2 : 20 a2
= 12 : 20
= 3 : 5
Answer : B
Question: A ship sails out to a mark at the rate of 18 kmph. and sails back at the rate of 14 kmph. The average rate of sailing is ?
A.5 km/hr
B.12 km/hr
C.16 km/hr
D.25 km/hr
Answer: C.16 km/hr
Explanation: Answer
Average = ( 2uv / u +v ) km/hr
= ( 2 x 18 x 14 ) / (18 +14 ) km/hr.
= 16 km/hr.
Correct Option: C
Question: A batsman in his 17th innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17thinnings?
A.88
B.16
C.128
D.37
Answer: D.37
Explanation: 16x + 85 = 17(x + 3)
x = 34 + 3 = 37
Answer:D
Question: A merchant has selected two items to be placed on sale, one of which currently sells for 25 percent less than the other. If he wishes to raise the price of the cheaper item so that the two items are equally priced, by what percentage must he raise the price of the less expensive item?
A.52 %
B.40%
C.30%
D.20%
Answer: C.30%
Explanation: Expensive item = $100;
Cheap item = $75;
We must increase $75 to $100, so by $25, which is approximately 30% increase: (100-75)/75 = 1/3 = ~0.33
Answer: C.
Question: The ages of two persons differ by 16 years. 6 years ago, the elder one was
3 times as old as the younger one. What are their present ages of the elder person?
A.10
B.20
C.30
D.40
Answer: C.30
Explanation: Let present age of the elder person =x and
present age of the younger person =x−16
(x−6)=3(x−16−6)
x−6=3x−66
2x=60
x=60/2=30 Answer: Option C
Question: How many prime numbers D exist such that 90 < D < 106 and D is a factor of 99999919?
A.1. Zero
B.2. One
C.3. Two
D.4. Three
Answer: C.3. Two
Explanation: I found that considering the constraint..D is a prime num in between 90 to 106 not inclusive , only 3 numbers (91,97 and 101) are present but those numbers are not the factors of the number mentioned....Therefore, i doubt the answer.C
Question: A man bring 2 cats to his home to eliminate all the mice. They do a half of the work in 5 days, then the man brings 3 more cats. If they hunt at the same rate, how many days will take to hunt all the mice, since the first day?
A. 7 days
B. 8 days
C. 9 days
D. 10 days
Answer: A. 7 days
Explanation: We have that: 2 cats----- 5 days, (2+3) C ----- X d, that is: (X d/ 2C) = (5 d/5P), then: X d = (5 d/5C)2C = 2d. Is to say, the 5 cats hunt the same quantity in 2 days; as it is only 1/2 of the work, all the mice would be hunt in: M = 5 d + 2 d = 7 days. Answer A.
Question: next term in series 3,32,405
A.5144
B.6144
C.7144
D.7582
Answer: B.6144
Explanation: first term 3*1^2=3
second term 4*2^3=32
third term 5*3^4=405
fourth term 6*4^5=6144
ANSWER:B
Question: A shopkeeper fixes the marked price of an item 40% above its cost price. The percentage of discount allowed to gain 8% is
A.23.85%
B.22.85%
C.21.85%
D.20.85%
Answer: B.22.85%
Explanation: Explanation:
Let the cost price = Rs 100
then, Marked price = Rs 140
Required gain = 8%,
So Selling price = Rs 108
Discount = 140 - 108 = 32
Discount% = (32/140)*100 = 22.85%
Option B
Question: A single reservoir supplies the petrol to the whole city, while the reservoir is fed by a single pipeline filling the reservoir with the stream of uniform volume. When the reservoir is full and if 40,000 liters of petrol is used daily, the suply fails in 90 days.If 32,000 liters of petrol is used daily, it fails in 60 days. How much petrol can be used daily with out the supply ever failing?
A.64000 liters
B.56000 liters
C.78000 liters
D.60000 liters
Answer: B.56000 liters
Explanation: Explanation:
Let x liter be the per day filling and v litr be the capacity of the reservoir, then
90x + v = 40000 × 90 -----(1)
60x + v= 32000 × 60 ------(2)
solving eq.(1) and (2) , we get
x = 56000
Hence , 56000 liters per day can be used without the failure of supply.
Answer: B
Question: A box contains 5 green, 4 yellow and 3 white balls. Three balls are drawn at random. What is the probability that they are not of same colour.
A.52/55
B.3/55
C.41/44
D.3/44
Answer: C.41/44
Explanation: Explanation:
Total cases =12C3=12∗11∗10/3∗2∗1=220
Total cases of drawing same colour =5C3+4C3+3C3
5∗4/2∗1+4+1=15
Probability of same colur ==15/220=3/44
Probability of not same colur =1−3/44=41/44
Option C
Question: A man can row 7.5 km/hour in still water & he finds that it takes him twice aslong to row up as to row down the river. Find the rate of stream?
A.2 km/hr
B.2.5 km/hr
C.3 km/hr
D.4 km/hr
Answer: B.2.5 km/hr
Explanation: Given that, time taken to travel upstream = 2 × time taken to travel downstream
When distance is constant, speed is inversely proportional to the time
Hence, 2 × speed upstream = speed downstream
Let speed upstream =x
Then speed downstream =2x
we have, 12(x+2x) = speed in still water
⇒12(3x)=7.5⇒3x=15⇒x=5
i.e., speed upstream = 5 km/hr
Rate of stream =12(2x−x)=x2=52=2.5 km/hr
B
Question: A bag contains 6 black and 3 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
A.3/4
B.1/3
C.1/7
D.1/8
Answer: B.1/3
Explanation: Let number of balls = (6 + 3) = 9.
Number of white balls = 3.
P (drawing a white ball) =3/9=1/3.
Option B.
Question: If a chair was sold for $ 990 at a loss of $ 110. Find the cost price of the chair.
A.$ 1000
B.$ 1100
C.$ 1200
D.$ 1300
Answer: B.$ 1100
Explanation: Selling Price = $ 990,
Loss = $ 110
Cost Price = Selling Price + Loss
Cost Price = 990 + 110
= $ 1100
Therefore, cost price of the chair = $ 1100
Answers: B
Question: a, b, c and d are four consecutive numbers. If the sum of a and dis 111, what is the product of b and c?
A.2652
B.2578
C.2534
D.3080
Answer: D.3080
Explanation: Here d = a + 3
a + a + 3 = 111
2a = 108
a = 54
So, numbers are 54, 55, 56 and 57
∴ b × c= 55 × 56 = 3080
D
Question: A and B invests Rs.10000 each, A investing for 8 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.25000, find their shares?
A.22277
B.26782
C.22882
D.15000
Answer: D.15000
Explanation: The ratio of their profits A:B = 8:12 = 2:3
Share of A in the total profit = 2/5 * 25000 = Rs.10000 Share of A in the total profit = 3/5 * 25000
= Rs.15000
Answer: D
Question: It costs $18 for the first 1/2 hour to rent a bike. After the first 1/2 hour it costs $10 per hour. If a certain customer uses the bike for 2 hours, how much will it cost him?
A.$12
B.$45
C.$33
D.$95
Answer: C.$33
Explanation: 2 hours = 120 minutes
First 30 min ------> $18
Time left is 90 min...
Now, 60 min costs $ 10
1 min costs $ 10/60
90 min costs $ 10/60*90 => $ 15
So, Total cost will be $15 + $18 => $ 33
The answer will be (C) $ 33
Question: What will come in place of the x in the following Number series? 11, 14, 19, 22, 27, 30, 35,x
A.23
B.26
C.38
D.35
Answer: C.38
Explanation: (C)
The pattern is + 3, + 5, + 3, + 5, …………
So the missing term is = 35 + 3 = 38.
Question: In an examination a pupil's average marks were 63 per paper. If he had obtained 20 more marks for his Geography paper and 2 more marks for his History paper, his average per paper would have been 65. How many papers were there in the examination?
A.10
B.11
C.8
D.9
Answer: B.11
Explanation: Let the number of papers be x. Then,
63x + 20 + 2 = 65x
= 2x = 22
= x = 11.
ANSWER B
Question: The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
A.5
B.6
C.8
D.4
Answer: C.8
Explanation: S = 4
M = x
DS = x + 4
US = x - 4
6/(x + 4) + 6/(x - 4) = 2
x = 8
Answer:C
Question: On a race track a maximum of 5 horses can race together at a time. There are a total of 25 horses. There is no way of timing the races. What is the minimum number Y of races we need to conduct to get the top 3 fastest horses?
A.5
B.7
C.8
D.10
Answer: B.7
Explanation: Y=7 is the correct answer.
Good solution Buneul.B
Question: A, B, C subscribe Rs. 50000/- for a business. A subscribes Rs. 4000/- more than B and B Rs. 5000/- more than C. out of a total profit of Rs. 35,000/- A receives:
A.Rs. 8400/-
B.Rs. 11900/-
C.Rs. 13600/-
D.Rs. 14700/-
Answer: D.Rs. 14700/-
Explanation: Explanation:
Let the investments of C, B and A be Rs. X,
Rs. (x + 5000) and (x + 9000) = 50000
3x = 36000
X = 12000
C = Rs. 12000/- , B = Rs. 17000/- and A = Rs. 21000/-
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12
A’s share = Rs. (35000 * 21/50) = Rs. 14700/-
Answer: Option D
Question: Which of the following values is the greatest
A.a) 11% of 89
B.b) 22% of 78
C.c) 33% of 67
D.d) 65% of 45
Answer: D.d) 65% of 45
Explanation: Are you sure that you checked the answer key correctly? I just signed up forVeritas(haven't started yet, not until March) but I have access to the materials and the answer key I'm looking at says D.
Question: The average age of 22 students in a group is 12 years. when teacher's age is included to it, the average increases by one.What is the teacher's age in years?
A.31
B.36
C.35
D.53
Answer: C.35
Explanation: age of the teacher=(23*13-22*12)
=35 years.
ANSWER:C
Question: Raju age after 4 years will be 10 times his age 5 years back, What is the present age of Raju
A.9 years
B.10 years
C.7 years
D.6 years
Answer: D.6 years
Explanation: Explanation:
Clearly,
x+4= 10(x-5)
<=> 9x = 54 => x = 6
Option D
Question: If n divided by 8 has a remainder of 1, what is the remainder when 3 times n is divided by 8?
A.1
B.3
C.7
D.5
Answer: B.3
Explanation: As per question => N=8P+1 for some integer p
hence 3N => 24Q + 3 => remainder => 3 for some integer Q
hence B
Question: Certain number of worms are placed in a container. The number of worms increases by three times every day and the container is completely filled with worms in 12 days. On what day, the worms were
1/3rd of the container ?
A.9 days
B.3 days
C.4 days
D.11 days
Answer: D.11 days
Explanation: As every day the worms increases by 3 times
1/3 × 3 = 1 [full]
Therefore on 11th day
Option D
Question: Which of the following is always true?
(I) The average (arithmetic mean) of five negative consecutive integers is equal to the average of the largest and smallest of them.
(II) The average (arithmetic mean) of four positive consecutive integers is equal to the average of the largest and smallest of them.
(III) The average (arithmetic mean) of five consecutive integers is equal to the average of the largest and smallest of them.
A.I and III
B.I, II and III
C.II
D.I and II
Answer: B.I, II and III
Explanation: he average (arithmetic mean) of five negative consecutive integers is equal to the average of the largest and smallest of them.
(-10+-9+-8+-7+-6)/5 = -40/5 = -8 same as (-10+-6)/2 = -8 True
The average (arithmetic mean) of four positive consecutive integers is equal to the average of the largest and smallest of them.
(2+3+4+5)/4 = 14/4 same as (5+2)/2 = 7/2 always true
(1+2+3+4)/4 = 10/4 same as (4+1)/2 = 5/2
The average (arithmetic mean) of five consecutive integers is equal to the average of the largest and smallest of them.
(3+4+5+6+7)/5 = 5 same as (7+3)/2 = 5 True
ANSWER:B
Question: A can do a work in 20 days and B can do it in 8 days. In how many days A and B can do the work?
A.5 5/7 days
B.10 days
C.6 days
D.8 days
Answer: A.5 5/7 days
Explanation: Explanation:
A's 1day's work = 1/20
B's 1day's work = 1/8
They work together = 1/20 + 1/8 = 7/40 = 40/7 = 5 5/7days
Answer: Option A
Question: A man counted his animals, 80 heads and 260 legs (ducks and goats). how many goats are there?
A.30
B.40
C.50
D.60
Answer: C.50
Explanation: let no of ducks=d and no of goat=g
d+g=80(heads)----------> eq 1
each duck has 2 legs and goat has 4 legs
2d+4g=260 and divide 2d+4g=260 by 2 we get d+2g=130 -----------> eq2
subtract eq1 from eq2
we get no of goats=50
ANSWER:C
Question: Two dice are tossed once. The probability of getting an even number at the first die or a total of 8 is
A.1/36
B.3/36
C.11/36
D.20/36
Answer: D.20/36
Explanation: 1. The probability of getting an even number at the first die is 1/2 (as the probability of even = the probability of odd = 1/2);
2. The probability of getting a total of 8 is 5/6^2, as there are 5 different favorable scenarios: (2,6), (6,2), (3,5), (5,3) and (4,4);
3. The probability of getting an even number at the first die AND a total of 8 is 3/6^2 (from above case);
Hence, The probability of getting an even number at the first die OR a total of 8 is 1/2+5/36-3/36=20/36.
Answer: D
Question: In a certain pond, 60 fish were caught, tagged, and returned to the pond. A few days later, 60 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what`s the approximate number of fish in the pond?
A.400
B.625
C.1818
D.2500
Answer: C.1818
Explanation: The percent of tagged fish in the second catch is 2/60*100 = 3.33%.
We are told that 3.33% approximates the percent of tagged fish in the pond. Since there are 60 tagged fish, then we have 0.033x = 60 --> x = 1,818.
Answer: C.
Question: The distance between 2 cities A and B is 1000km. A train starts from A at 10 a.m. and travels towards B at 100 km/hr. Another starts from B at 11 a.m. and travels towards A at 150 km/hr. At what time do they meet?
A.11am.
B.12p.m.
C.3pm.
D.2p.m.
Answer: C.3pm.
Explanation: Suppose they meet x hrs after 10 a.m.
Distance moved by first in x hrs + Distance moved by second in (x-1)hrs = 1000
100x + 150 (x-1) = 1000
x = 4.60 = 5 hrs
They meet at 10+5 = 3 p.m.
Answer is C
Question: Find the sum of first 70 odd numbers
A.4900
B.4970
C.4990
D.4980
Answer: A.4900
Explanation: Explanation:
n2 = 702 = 4900
Answer: Option A
Question: (39,897)(0.0096)/198.76 is approximately
A.0.02
B.0.2
C.2
D.20
Answer: C.2
Explanation: 39,897 can be written as 40,000 (approximately)
0.0096 can be written as 0.01 (approximately
198.76 can be written as 200 (approximately)
40,000*0.01/ 200= 2 (approximately)
C is the answer
Question: Tough and Tricky questions: Exponents.
If a and b are positive integers and x = 8^a and y = 7^b, which of the following is a possible units digit of xy?
A.1, 4
B.4, 1, 2
C.5, 8
D.2, 4, 6 and 8
Answer: D.2, 4, 6 and 8
Explanation: Only Units digit of X and Y contribute to the Units digit of XY.
Finding all values ofXfor positive values ofa
When,
a=1; X=8
a=2; X=64
a=3; X=512
a=4; X=2048........ Units digit repeat in a cycle of 8,4,2,8......
Similarly, Finding all values ofYfor positive values ofb
When,
b=1; Y=7
b=2; Y= 49
b=3; Y= 343
b=4; Y=2041
b=5; Y=16807....... Units digit repeat in cycle of 7,9,3,1,7,9,3....
So, possible value of Units digit of XY can be found by considering all possibilities of Units digit of X and Y
When X=8 and Y=7: Units digit of XY = 56
When X=8 and Y=9: Units digit of XY = 72
When X=8 and Y=3: Units digit of XY = 24
When X=4 and Y=7: Units digit of XY = 28
When X=4 and Y=9: Units digit of XY = 36
When X=4 and Y=3: Units digit of XY = 12
When X=2 and Y=7: Units digit of XY = 14
When X=2 and Y=9: Units digit of XY = 18
When X=2 and Y=3: Units digit of XY = 6
Only four possibilities for Units digit of XY i.e. 2, 4, 6 and 8
therefore answer is D
Question: In a consumer survey, 82% of those surveyed liked at least one of three products: 1, 2, and 3. 45% of those asked liked product 1, 30% liked product 2, and 20% liked product 3. If 4% of the people in the survey liked all three of the products, what percentage of the survey participants liked more than one of the three products?
A.9
B.11
C.13
D.15
Answer: A.9
Explanation: 45 + 30 + 20 = 95
The number 95 includes some people counted twice and some people counted three times.
95 - 82 = 13, and this number represents people counted twice or three times.
4% of the people are counted two extra times.
The percentage of people counted one extra time is 13 - 4(2) = 5.
The percentage of people who liked more than one product is 4% + 5% = 9%.
The answer is A.
Question: How many words can be formed by using all the letters of the word, 'ALLAHABAD' ?
A.3780
B.1890
C.7560
D.2520
Answer: C.7560
Explanation: The word 'ALLAHABAD' contains 9 letters, namely 4A, 2L, 1H, 1B and 1D.
Requisite number of words =9!/(4!)(2!)(1!)(1!)(1!) =7560
Answer is C
Question: Kavi had a stock of 600 bags in his bookshop. He sold 25 on Monday, 70 on Tuesday, 100 on Wednesday, 110 on Thursday and 145 on Friday. What percentage of the bags were not sold?
A.10%
B.25%
C.64%
D.42%
Answer: B.25%
Explanation: Let N be the total number of bags sold. Hence
N = 25 + 70 + 100 +110 + 145 = 450
Let M be the bags NOT sold
M = 600 - N = 600 - 450 = 150
Percentage
Bags not sold / total number of bags = 150/600= 0.25 = 25%
correct answer B