RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In what ratio should a mixture of milk and water in the ratio of 3:4 be mixed with another mixture of milk and water in the ratio 5:2 so that the resultant mixture contains equal quantities of milk and water?
A.3:1
B.3:5
C.7:8
D.7:9
Answer: A.3:1
Explanation: First mixture: milk and water in the ratio of 3x:4x.
Second mixture: milk and water in the ratio 5y:2y.
We want their mixture to have equal quantities of milk and water: 3x + 5y = 4x + 2y --> x/y = 3.
Answer: A.
Question: A man takes 3 hours 45 minutes to row a boat 15 km downstream of a river and 2hours30minutes to cover a distance of 5km upstream. find the speed of the river current in km/hr.
A.1 km/hr
B.2 km/hr
C.3 km/hr
D.4 km/hr
Answer: A.1 km/hr
Explanation: rate downstream=(15/3 Â¾)km/hr=(15*4/15)km/hr=4km/hr.
Rate upstream=(5/2 Â½)km/hr=(5*2/5)km/hr=2km/hr.
Speed of current=1/2(4-2)km/hr=1km/hr
ANSWER A
Question: In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1:2:3. If there are Rs. 30 in all, how many 5 p coins are there?
A.176
B.167
C.150
D.717
Answer: C.150
Explanation: Let the number of 25 p, 10 p and 5 p coins be x, 2x and 3x respectively.
Then, sum of their values
= [25x/100 + (10 * 2x)/100 + (5 * 3x)/100]
= Rs. 60x/100
60x/100 = 30 => x = 50.
Hence, the number of 5 p coins = 3 * 50 = 150.
Answer:C
Question: In one hour, a boat goes 8 km/hr along the stream and 2 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
A.3 km/hr
B.4 km/hr
C.5 km/hr
D.6 km/hr
Answer: C.5 km/hr
Explanation: Upstream relative speed is u + v=8km/hr
Downstream speed is u-v = 2
Where u = speed of boat in still water and v is speed of stream
Then adding two equations u+v + u-v =8+2
2u=10
Finally, u=5.
ANSWER : C
Question: Find the value of b from (15)^2 x 9^2 Ã· 356 = b.
A.53.2
B.52.2
C.51.2
D.8.2
Answer: C.51.2
Explanation: Given Exp. =(15)^2 x 9^2 Ã· 356= b
= 225 x 81 Ã· 356
= 51.2
C
Question: In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 4:3:2. If there are in all Rs.42, the number of one rupee coins is?
A.22
B.26
C.18
D.16
Answer: D.16
Explanation: 4x 3x 2x
50 25 100
200x + 75x + 200x = 3800
475x = 3800
x = 8 => 2x = 16
Answer: D
Question: A sum of money is divided among A, B, C & D in the ratio 3:5:8:9 respectively. If the share of D Rs.1872 more than the share of A, then what is the total amount of money of B & C together?
A.3000
B.Rs. 4056
C.5000
D.5400
Answer: B.Rs. 4056
Explanation: Sol. Share of B + C = -3 x (5 + 8) = Rs. 4056
B
Question: The diagonals of a rhombus are 15 cm and 20 cm. Find its area?
A.176
B.186
C.150
D.179
Answer: C.150
Explanation: 1/2 * 15 * 20
= 150
Answer:C
Question: Which of the following is divisible by the first ten positive integer multiples of 11?
(i) 18810
(ii) 263640
(iii) 3011010
A.None
B.ii only
C.i and ii only
D.i and iii only
Answer: A.None
Explanation: A positive integer x is divisible by the first five integer multiples of 23 if and only if it is divisible by their least common multiple, 8*9*5*7*11.
8*9*5*7*11 is less than 70*30*10=21000, (i) cannot possibly be divisible by 8*9*5*7*11.
The integers of 3011010 sum to 6, so 3011010 is divisible by 3, but not 9, so (iii) is not divisible by 8*9*5*7*11.
If (ii) is divisible by 8*9*5*7*11 then 26364 is divisible by 11. So 26364=11y=10y+y for some positive integer y. y must have initial digit 2 and final digit 4. Final and third digit of y must add to 6, so third digit of y is 2. Then similarly, second and third digit add to three, so second digit is 1. But then second and first digit must sum to 6, but first digit is 2, second is 1, so (ii) cannot be divisible by 11.
Answer A
Question: Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 70 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad?
A.42
B.18
C.20
D.24
Answer: A.42
Explanation: Time taken = Total Distance / Relative Speed
Total Distance = 70 kms
Relative Speed (Opposite side) (As they are moving towards each other speed would be added ) = 6+ 4 = 10 kms/hr
Time taken = 70 / 10 = 7 hrs
Distance traveled by Brad = Brad's speed * time taken = 6 * 7 = 42 kms... Answer - A
Question: A train 100 meters long completely crosses a 300 meters long bridge in 15 seconds. What is the speed of the train is?
A.32 kmph
B.96 kmph
C.34 kmph
D.43 kmph
Answer: B.96 kmph
Explanation: S = (100 + 300)/45
= 400/15 * 18/5
= 96
Answer:B
Question: Dan's age after 16 years will be 6 times his age 4 years ago. What is the present age of Dan?
A.8
B.10
C.12
D.14
Answer: A.8
Explanation: Let Dan's present age be x.
x+16 = 6(x-4)
5x = 40
x = 8
The answer is A.
Question: If e = 20! + 17, then e is divisible by which of the following?
I. 15
II. 17
III. 19
A. None
B. I only
C. II only
D. I and II
Answer: C. II only
Explanation: Another crude way to answer this, if you did not know the properties above would be to consider that that 20! will have the number ending in 00 due to 10 and 20 being included.
So e!+17 = xxxx00 +17 = xxxx17 which is only possibly divisible by 17. Hence Option C is the answer.
Question: A man can row 7.8 kmph in still water and he finds that it takes him twice as long to row up as to row down the river. Find the rate of stream.
A.2.6 km/hr
B.12.5 km/hr
C.1 2.6 km/hr
D.22.5 km/hr
Answer: A.2.6 km/hr
Explanation: Given that, time taken to travel upstream = 2 × time taken to travel downstream
When distance is constant, speed is inversely proportional to the time
Hence, 2 × speed upstream = speed downstream
Let speed upstream = x
Then speed downstream = 2x
we have, 1/2(x+2x) = speed in still water
⇒1/2(3x)=7.8
3x = 15.6
x = 5.2
i.e., speed upstream = 5.2 km/hr
Rate of stream = 1/2(2x−x)=x/2=5.2/2=2.6 km/hr
Answer is A
Question: What is the value of (P + Q)/(P - Q) if P/Q is 5?
A.4/3
B.3/2
C.2/6
D.7/8
Answer: B.3/2
Explanation: (P + Q)/(P - Q) = [(P/Q) + 1]/[(P/Q) - 1]
= (5 + 1)/(5 - 1)
= 6/4
= 3/2
ANSWER:B
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 324135, then population in 1978 was?
A.120000
B.228788
C.280000
D.267689
Answer: C.280000
Explanation: X * (105/100) * (105/100) * (105/100) = 324135
X = 324135/1.157625
X = 280000
Answer C
Question: The value of (0.137+0.098)²-(0.137 - 0.098)² / 0.137×0.098 is
A.0.039
B.0.235
C.0.25
D.4
Answer: D.4
Explanation: Solution
Given expression	= (a+b)² - (a-b)²/ab
= 4ab/ab
= 4.
Answer D
Question: Joe has candys on his pocket, 4 of those candies have lemon flavor, and 3 have caramel flavor. If Joe take one, what is the probability that he picks one caramel flavor?
A.1
B.2
C.none
D.3/7
Answer: D.3/7
Explanation: the total number of candies is 7
and the number of candies with lemon flavor is 3
then, in one chance the probability to pick one candie with lemon flavor is
3/7
Answer D
Question: Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.441 in 2 years?
A.227
B.400
C.277
D.686
Answer: B.400
Explanation: 441 = P(21/20)2
P = 400
Answer: B
Question: My grandson is about as many days as my son in weeks, and my grandson is as many months as I am in years. My grandson, my son and I together are 140 years. Can you tell me my age in years?
A.80
B.90
C.85
D.84
Answer: D.84
Explanation: let the age of the man = x years
so according to the given condition
age of my grandson = x/12 years
and age of my son = x30/52 = 15x/26
and x + (x/12) + (15x/26) = 140
or (156x+13x+90x)/156 = 140
or 259x = 156*140
or x = 156*140/259 = 84
ANSWER:D
Question: A man buys an article for $100. and sells it for $110. Find the gain percent?
A.10%
B.15%
C.25%
D.20%
Answer: A.10%
Explanation: C.P. = $100
S.P. = $110
Gain = $10
Gain% = 10/100 *100 = 10%
Answer is A
Question: A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is :
A.45.30 km/hr
B.55.15 km/hr
C.70.15 km/hr
D.71.11 km/hr
Answer: D.71.11 km/hr
Explanation: Sol.
Total time taken = [160/64 + 160/8] hrs = 9/2 hrs.
∴ Average speed = [320*2/9] km/hr = 71.11 km/hr.
Answer D
Question: Ram, who is half as efficient as Krish, will take 18 days to complete a task if he worked alone. If Ram and Krish worked together, how long will they take to complete the task?
A.16 days
B.12 days
C.8 days
D.6 days
Answer: D.6 days
Explanation: Number of days taken by Ram to complete task = 18
Since Ram is half as efficient as Krish , Amount of work done by Krish in 1 day = Amount of work done by Ram in 2 days
If total work done by Ram in 18 days is 18w
Amount of work done by Ram in 1 day = w
Amount of work done by Krish in 1 day = 2w
Total amount of work done by Krish and Ram in a day = 3w
Total amount of time needed by Krish and Ram to complete task = 18w/3w = 6 days
Answer D
Question: If x is a positive odd number, then each of the following is odd EXCEPT
A.(x + 3)(x + 5)
B.x^2 + 5
C.x^2 + 6x + 9
D.3x^2 + 4
Answer: B.x^2 + 5
Explanation: Since it is given tht x is even number, so any integer multiplied with x will also be even..
so, we should concentrate only on other terms..
lets see the choices..
A. (x + 3)(x + 5)
We have two terms with x and each is added with a odd number..
each bracket becomes odd and Odd*Odd=Odd
B. x^2 + 5
here we are adding an Odd number to even.. so E + O=O
C. x^2 + 6x + 9
here we are again adding an Odd number to even.. so E +E + O=O
D. 3x^2 + 4
here we are adding an Even number to even.. so E + E=E..
so tjis is our answer
E. 5(x + 3)
again O*O=O
B
Question: A man gave 1/8 of his property to his wife and 1/4 of the remaining to his daughter. What fraction of his property is he left with after giving to his wife and his daughter?
A.5/16
B.2/8
C.21/32
D.4/8
Answer: C.21/32
Explanation: A man gave 1/8 of his property to his wife, so remaining is 7/8
He gave 1/4 of the remaining property to his daughter, 1/4*7/8=7/32
Total property given to his wife and daughter is 1/8+7/32
To make the denominator common, we use 32=4/32
4/32+7/32=11/32 is given to his wife and daughter
Remaining property left with him is 21/32
Answer is C
Question: The average of 4,8,12 and x is 10. Find the value of x?
A.10
B.16
C.15
D.24
Answer: B.16
Explanation: average = (4+8+12+x)/4 = 10
x = 16
Answer is B
Question: If a man lost 4% by selling oranges at the rate of 12 a rupee at how many a rupee must he sell them to gain 44%?
A.2
B.8
C.6
D.4
Answer: B.8
Explanation: 96% ---- 12
144% ---- ?
96/144 * 12 = 8
Answer: B
Question: Two pumps are connected to an empty tank. Pump X fills the tank with water at a constant rate, while pump Y drains water out of the tank at a constant rate. The two pumps finish filling the tank in four times the duration it would take pump X alone to fill the tank. If pump Y alone can empty a whole tank in 44 minutes, then how many minutes does it take pump X alone to fill the tank?
A.27
B.30
C.33
D.36
Answer: C.33
Explanation: Let V be the volume of the tank.
Let R be the rate per minute that pump X fills the tank.
Let T be the time it takes pump X to fill the tank.
The rate at which pump Y empties the tank is V/44 per minute.
(R - V/44)*4T=V=RT.
(R-V/44)*4=R
3R=V/11.
R=V/33.
It takes pump X 33 minutes to fill the tank.
The answer is C.
Question: Cars emerging from a motorway arrive at a junction that splits the road into two separate lanes. The number of cars per hour that continue in either lane is constant. If 7 cars per hour were diverted from the left lane to the right lane, the number of cars entering the right lane per hour would be twice as big as the number of cars entering the left lane per hour. Alternatively, if 7 cars per hour were diverted from the right lane to the left lane, the number of cars entering the left lane per hour would be four times as great as the number of cars entering the right lane per hour. How many cars enter the left lane per hour?
A.21
B.18
C.17
D.19
Answer: C.17
Explanation: as per question 7 cars diverted from left lane to right lane. Thus we get equation R+7=2(L-7)
as per question 7 cars diverted from right lane to left lane .thus we get equation L+7=4(R-7)
by solving two equation i.e R +7 =2L-14 OR. R =2L -21 AND L+7= 4R -28 OR L= 4R -35
BY SOLVING WE GET L= 4( 2L -21) -35 OR L= 8L -84-35 OR 119 =7L THUS L =17
C
Question: Find the unit's digit from the given 264^102+264^103?
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: Required unit's digit = unit's digit in 4102+4103.4102+4103.
Now, 4242 gives unit digit 6.
⇒ 41024102 gives unit digit 6.
⇒ 41034103 gives unit digit of the product 6×46×4 i.e., 4.
Hence, unit's digit in 264102+264103264102+264103
= unit's digit in (6+4)=0
A
Question: Indu gave Bindu Rs.1250 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
A.7
B.2
C.9
D.5
Answer: B.2
Explanation: 1250
= D(100/4)2
D = 2
Answer: B
Question: Anand and Deepak started a business investing Rs. 27,500 and Rs. 33,000 respectively. Out of a total profit of Rs. 15,000, Deepak's share is?
A.Rs. 8181.81
B.Rs. 8900
C.Rs. 8400
D.Rs. 3400
Answer: A.Rs. 8181.81
Explanation: Ratio of their shares = 27500 : 33000 = 5 : 6
Deepak's share = 15000 * 6/11 = Rs. 8181.81
Answer:A
Question: At a dinner party, 4 people are to be seated around a circular table. 2 seating arrangements are considered different only when the positions of the people are different relative to each other. what is the total number of different possible seating arrangements for the group?
A.6
B.10
C.24
D.32
Answer: A.6
Explanation: Soln: Since the arrangement is circular and 2 seating arrangements are considered different only when the positions of the people are different relative to each other, we can find the total number of possible seating arrangements, by fixing one person's position and arranging the others.
Thus if one person's position is fixed, the others can be arranged in 3! =6 ways.
Ans is A.
Question: A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 20 sec respectively. What is the speed of the train?
A.89
B.23
C.56
D.79.2
Answer: D.79.2
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/20 = y
y = 22
Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.
Answer: Option D
Question: A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?
A.4 litres, 8 litres
B.6 litres, 6 litres
C.5 litres, 7 litres
D.7 litres, 4 litres
Answer: B.6 litres, 6 litres
Explanation: Let the cost of 1 litre milk be Re. 1
Milk in 1 litre mix. in 1st can = 3/4 litre, C.P. of 1 litre mix. in 1st can Re. 3/4
Milk in 1 litre mix. in 2nd can = 1/2 litre, C.P. of 1 litre mix. in 2nd can Re. 1/2
Milk in 1 litre of final mix. = 5/8 litre, mean price = Re. 5/8.
Ratio of two mixtures = 1/8 : 1/8 = 1:1.
So, quantity of mixture taken from each can = (1/2 X 12) = 6 litres.
Answer B
Question: what is the units digit of the expression 17^7-2?
A.1
B.2
C.3
D.7
Answer: A.1
Explanation: 7^1=7
7^2=49
7^3=343
7^4=1(last digit)
7^5=7(last digit) and the cycle repeats after every 4 powers
Therefore, last digit of 17^7=3
3-2=1
Answer A
Question: Which of the following points falls outside of the region defined by 2y≤6x−17?
A.(5, 1)
B.(3, -8)
C.(2, 0)
D.(1, -2)
Answer: D.(1, -2)
Explanation: Equation given is 2y<=6x-12
Simplifying this; y<=3x-6
Plug in the values provided in the options,
A. 1<=11
B. -8<=3
C. 0<=0
D.-2<=-4
E. -14<=-12
Option D is the answer.
Question: The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
A.500
B.342
C.250
D.362
Answer: B.342
Explanation: Explanation:
400*(90/100)*(95/100) = 342
Answer:B
Question: How many Books each of Volume 100 meter cube can be packed into a crate of volume 4000 meter cube?
A.100
B.120
C.cannot be determined
D.180
Answer: C.cannot be determined
Explanation: Gud question with a simple concept.
In geo if we want to insert one shape into another we need to know the dimensions of the two shapes.
In above with volume given , we can come up with different shapes, so we cant know the answer
For ex :4000 m3 can be 400*10 or 40*100 or just 4000*1 we don't know , so we cant calculate
Answer : C
Question: 5years ago, the age of Anand was one-forth of the age of Bala at that time. The present age of Bala is 13 years more than the present age of Anand. Find the present age of Anand?
A.11
B.21
C.19
D.22
Answer: C.19
Explanation: Explanation:
Let the present ages of Anand and Bala be 'a' and 'b' respectively.
a - 5 = 1/3 (b - 5) --- (1)
b = a + 13
Substituting b = a + 8 in first equation,
a - 10 = 1/3 (a +8) => 3a - 30 = a + 8=> 2a = 38 => a = 19.
Answer: C
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 8 kmph, what is the time taken to row a distance of 60 km downstream?
A.30/18 hours
B.15/7 hours
C.80/13 hours
D.30/13 hours
Answer: B.15/7 hours
Explanation: Speed downstream = 20 + 8 = 28 kmph.
Time required to cover 60 km downstream
= d/s = 60/28
= 15/7 hours.
Answer: B
Question: Simple interest on a sum at 2% per annum for 2 years is Rs.100. The C.I. on the same sum for the same period is?
A.101.8
B.101.4
C.101.2
D.100
Answer: A.101.8
Explanation: SI = 50 + 50
CI = 50 + 50 + 1.8 = 101.8
Answer: A
Question: If 100% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 125% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ?
A.0.35
B.3.5
C.350
D.35
Answer: C.350
Explanation: IMO answer should be 350...
consider j=10, then k=50, l=150 and m=350....
20% of 350, comes out to be 70....
200% of 10 is 20....
(70*100)/20=350....
Ans : C
Question: W and B are integers. The expression (W+1)(B+1) is even. What can be said about W and B?
A.They are both even numbers.
B.At least one of them is even.
C.At least one of them is odd.
D.They are both odd.
Answer: C.At least one of them is odd.
Explanation: Odd x Odd = Odd
Odd x Even = Even
Even x Even = Even
To fulfill condition Either (W+1) or (B+1) needs to be Even
So either W or B needs to be odd
Or At least one of them is odd.
At least one of them is odd=C
Question: Two friends want to buy a snack. They combine their money and find they have $4.15, consisting of quarters, dimes, and nickels. If they have 37 coins and the number of quarters is half the number of nickels, how many quarters do they have?
A.9
B.10
C.11
D.12
Answer: A.9
Explanation: Let x be the number of quarters. Then 2x is the number of nickels.
(1) 25x + 10x + 10D = 415. Then 7x + 2D = 83
(2) 3x + D = 37. Then 6x + 2D = 74
Let's subtract equation (2) from equation (1).
x = 9
The answer is A.
Question: Bobby bought 2 shares, and which he sold for $96 each. If he had a profit of 25% on the sale of one of the shares but a loss of 28% on the sale of the other share, then on the sale of both shares Bobby had...
A.a profit of 10
B.a profit of 8
C.a loss of 8
D.a loss of 18
Answer: D.a loss of 18
Explanation: Cost of the first stock: 96/1.25=76.8, so profit from it 96-76.8=19.2
Cost of the second stock: 96/0.72=133.33, so loss from it 96-133.33=-37.33
Overall loss 19.2 - 37.33=-18.13
Answer: D.
Question: Average monthly income of a family of 4 earning members was Rs. 735. One of the earning members died and therefore, the average income came down to Rs 590. The income of the deceased was?
A.Rs. 692.80
B.Rs. 820
C.Rs. 1170
D.Rs. 1385
Answer: C.Rs. 1170
Explanation: Answer
Income of the deceased = Total income of 4 members - total income of remaining 3 members.
= 735 x 4 - 590 x 3 Rs.
= 1170 Rs.
Correct Option: C
Question: There are 14 cans in the refrigerator. 7 of them are red and 7 of them are blue. In how many ways we can remove 8 cans so that at least one red and at least one blue cans to remain the refrigerator.
A.460
B.490
C.493
D.455
Answer: C.493
Explanation: Answer: C.
Question: The pilot of a small aircraft with a 40-gallon fuel tank wants to fly to Cleveland, which is 480 miles away. The pilot recognizes that the current engine, which can fly only 7 miles per gallon, will not get him there. By how many miles per gallon must the aircraft’s fuel efficiency be improved to make the flight to Cleveland possible?
A.2
B.4
C.5
D.40
Answer: C.5
Explanation: Actual miles/gallon is = 480/40 = 12 miles/gallon.
Current engine miles/gallon is 7 miles/gallon.
Additional 5 miles/gallon is required to match the actual mileage.
IMO option C.
Question: John has taken four (4) tests that have an average of 85. In order to bring his course grade up to a ‘B’, he will need to have a final average of 89. What will he need to average on his final two tests to achieve this grade?
A.87
B.90
C.92
D.97
Answer: D.97
Explanation: Traditional Method:
Total scored till now 85*4=340
Total score to avg 89 in 6 tests = 89*6=534
Total to be scored on 2 tests = 534-340=194
Avg on 2 tests = 194/2 = 97
Answer: D
Question: If the price of an article went up by 25%, then by what percent should it be brought down to bring it back to its original price?
A.20%
B.16 4/3%
C.16 7/3%
D.16 6/3%
Answer: A.20%
Explanation: Let the price of the article be Rs. 100.
25% of 100 = 25.
New price
= 100 + 25 = Rs. 125
Required percentage
= (125 - 100)/125 * 100
= 25/125 * 100
= 20%
Answer:A
Question: A paint crew gets a rush order to paint 80 houses in a new development. They paint the first y houses at a rate of x houses per week. Realizing that they'll be late at this rate, they bring in some more painters and paint the rest of the houses at the rate of 1.25x houses per week. The total time Q it takes them to paint all the houses under this scenario is what fraction of the time it would have taken if they had painted all the houses at their original rate of x houses per week?
A. 0.8(80 – y)
B. 0.8 + 0.0025y
C. 80/y – 1.25
D. 80/1.25y
Answer: B. 0.8 + 0.0025y
Explanation: This may be a case of bad numberpicking but it worked for me.
80 houses. Let's say that y=40 houses are painted at the rate x=10 houses per week <=> 1/10 week per house. 40*1/10 = 4 houses per week will be painted at this rate.
80-y = 80-40 = 40 houses are to be painted at the faster rate. X*1,25=12,5 houses per week <=> 1/12,5 weeks per house * 40 houses = 40/12,5 = 80/25 = 320/100 = 3,2 weeks.
Which means finishing all houses at normal rate Q=> 2*4 = 8 weeks. Faster rate = 4+3,2 = 7,2 weeks.
7,2/8 = 9/10 = 0,9. Insert y=40 in equations and it is clear that only (B) gives us 0,9.
Question: A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
A.33
B.38
C.37
D.90
Answer: D.90
Explanation: Let number of notes of each denomination be x.
Then x + 5x + 10x = 480
⇒ 16x = 480
∴ x = 30.
Hence, total number of notes = 3x = 90
Answer:D
Question: The average runs scored by a batsman in 22 matches is 28. In the next 13 matches the batsman scored an average of 15 runs. Find his average in all the 35 matches?
A.31.23
B.25.12
C.36.25
D.23.17
Answer: D.23.17
Explanation: Total score of the batsman in 22 matches = 616.Total score of the batsman in the next 13 matches = 195.Total score of the batsman in the 35 matches = 811.Average score of the batsman = 811/35 = 23.17.Answer: D
Question: Praveen starts business with Rs.3920 and after 5 months, Hari joins with Praveen as his partner. After a year, the profit is divided in the ratio 2 : 3. What is Hari’s contribution in the capital?
A.s.10080
B.s.8000
C.s.8500
D.s.9000
Answer: A.s.10080
Explanation: Let Hari’s capital be Rs. x. Then, 3920 * 12/7x = 2/3
=> 14x = 141120
=> x = 10080.
ANSWER:A
Question: Which one of the following numbers is completely divisible by 45?
A.202860
B.331145
C.1254186
D.2534164
Answer: A.202860
Explanation: 45 = 5 x 9, where 5 and 9 are co-primes.
Unit digit must be 0 or 5 and sum of digits must be divisible by 9.
Among given numbers, such number is 202860.
ANSWER A
Question: How many digits are required to number a book containing 300 pages?
A.792
B.684
C.492
D.372
Answer: A.792
Explanation: 9 pages from 1 to 9 will require 9 digits.
90 pages from 10 to 99 will require 90*2=180 digits.
300-(90+9)=201 pages will require 201*3=603 digits.
The total number of digits is 9+180+603=792.
The answer is A.