RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What is the smallest positive integer x such that 507+x is the cube of a positive integer?
A.15
B.5
C.50
D.2
Answer: B.5
Explanation: Given 507+x is a perfect cube
so we will take 512 = 8*8*8
507+x = 512
x = 512-507 = 5
correct option is B
Question: There are two shelves A and B.The number of books in shelf A is 50 more than in shelf B..Then 20 books are removed from each shelf..Then the number of books in shelf A is twice the number of books in shelf..what are the number of books in shelf A originally?
A.100
B.115
C.130
D.120
Answer: D.120
Explanation: consider the books in B is x,then A has x+50,now 20 books are removed from both A&B then A has x+30,B has x-20,now books in A will be twice of books in shelf B
so x+30=2(x-20) solve this eq gives x=70 so initially A has 120 books
ANSWER:D
Question: If 60 percent of 600 is 50 percent of x, then x=?
A.600
B.720
C.820
D.800
Answer: B.720
Explanation: 0.6 * 600 = 0.5 * x
x = 6/5 * 600 = 720
Question: One train is traveling 45 kmph and other is at 10 meters a second. Ratio of the speed of the two trains is?
A.5:4
B.5:9
C.5:6
D.5:1
Answer: A.5:4
Explanation: 45 * 5/18 = 10
25:20 => 5:4
Answer: A
Question: The current of a stream runs at the rate of 3 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
A.A)7.24
B.B)2
C.C)8.5
D.D)6.67
Answer: A.A)7.24
Explanation: S = 3
M = x
DS = x + 3
US = x - 3
6/(x + 3) + 6/(x - 3) = 2
x = 7.24
Answer:A
Question: Fresh grapes contain 80% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 40 kg of fresh grapes?
A.10 kg
B.12 kg
C.15 kg
D.16 kg
Answer: A.10 kg
Explanation: From the question we know: 40kg * 80% = 32kg of water in the fresh grapes
40kg - 32kg of water = 8kg of non-water mass
We are looking for the weight of the dry grapes (X).
Since the question tells us that 20% of the weight of the dry graps is water and we know that 8kg is non-water mass we can set up the following equation:
X = 1/5(X) + 8kg
4/5(X) = 8kg
X = 10 kg
Answer- A
Question: In how many ways can the letters of the word RECPECT be arranged?
A.2580
B.2500
C.2000
D.2520
Answer: C.2000
Explanation: RECPECT has 7 words, but E is repeated two times. Thus ways = 7! / 2! = 2520 ways
C
Question: Janet has to pay back her bank loan over 8 months following the below sequence.
$50, $55, $65, $80, $85, $95, $110, ?
How much will she pay back on the eigthmonth?
A.$115
B.$145
C.$135
D.$125
Answer: A.$115
Explanation: The sequence progresses +5, +10, +15 repeated; The amount to pay back on the 8th Month is $115
Ans A
Question: Can you find the missing number in the sequence?
7 12 37 ? 9142
A.1262
B.2189
C.1132
D.1214
Answer: A.1262
Explanation: A
1262
Sequence is based on formula:
Next = (1st Number)^2 - (2nd number)
7 12 37 ? 9142
7^2 - 12 = 37
12^2 - 37 = 107
37^2 - 107 = 1262 (Answer)
102^2 - 1262 = 9142
Question: In a multiple choice test comprising 5 Questions, each with 4 choices, what is the probability of a student getting 3 or more questions correct? Each question has only one correct answer and the student is equally likely to choose any of the four choices.
A.24/256
B.53/512
C.105/512
D.459/512
Answer: B.53/512
Explanation: Probability for choosing correct answer is 1/4 and incorrect answer is 3/4
For 3 correct answers,
C(5,3)*(1/4)^3*(3/4)^2=90/(4^5)
For 4 correct answers,
C(5,4)*(1/4)^4*(3/4)^1=15/(4^5)
For 5 correct answers,
C(5,5)*(1/4)^5*(3/4)^0=1/(4^5)
So total probability
=106/1024
=53/512
Ans B
Question: There are 10 women and 8 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different such committees are possible?
A.1040
B.1260
C.1480
D.1620
Answer: B.1260
Explanation: 10C2 * 8C2 = 45*28 = 1260
The answer is B.
Question: Given that 0 < a < b < c < d, which of the following the largest ?
A.(c+d) / (a+b)
B.(c+d) / (a+c)
C.(c+d) / (a+q)
D.(c+d) / (a+o)
Answer: A.(c+d) / (a+b)
Explanation: Explanation: Take a = 1, b = 2, c = 3, d = 4. option A is clearly true.
Sol: A
Question: if a@b = a * b^(1/2) then 2@25 = ?
self made
A.2
B.6
C.10
D.8
Answer: C.10
Explanation: 2* (25)^1/2= 2*5= 10
C is the answer
Question: At a tanning salon, customers are charged $10 for their first visit in a calendar month and $7 for each visit after that in the same calendar month. In the last calendar month, 100 customers visited the salon, of which 30 made a second visit, and 10 made a third visit. All other customers made only one visit. If those visits were the only source of revenue for the salon, what was the revenue for the last calendar month at the salon?
A.$1220
B.$1280
C.$1300
D.$1340
Answer: B.$1280
Explanation: I get B. This question seems too straightforward for 600+. Am I missing something?
100 first-time visits --> 100(10) = $1000
30 + 10 = 40 subsequent visits --> 40(7) = $280
Total revenue: 1000+ 280 = $1280
The answer is B.
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 1250 resolutions?
A.1277 m
B.1760 m
C.1278 m
D.1288 m
Answer: B.1760 m
Explanation: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 1250 resolutions.
= 1250 * 2 * 22/7 * 22.4 = 176000 cm
= 1760 m
Answer: B
Question: The average height of 35 boys in a class was calculated as 183cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places?
A.187.89 cm
B.181.29 cm
C.123.98 cm
D.149.98 cm
Answer: B.181.29 cm
Explanation: Calculated average height of 35 boys = 183 cm.
Wrong total height of 35 boys = 183 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 183 cm - (166 cm - 106 cm)/35
= 183 cm - 60 /35 cm
= 183 cm - 1.71 cm = 181.29 cm.
Answer: B
Question: A sum of Rs. 2743 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
A.1642
B.1640
C.1632
D.1688
Answer: D.1688
Explanation: (x*8*3)/100 = ((2743 - x)*3*5)/100
24x/100 = 41145/100 - 15x/100
39x = 41145 => x = 1055
Second sum = 2743 – 1055
=1688
Answer:D
Question: A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits $ 1600 each on 1stJanuary and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is:
A.$120
B.$121
C.$122
D.$123
Answer: B.$121
Explanation: Amount	= $ 1600 x 1 +	5 2	+ 1600 x 1 +	5
2 x 100 2 x 100
= $ 1600 x	41	x	41	+ 1600 x	41
40 40 40
= $ 1600 x	41 41	+ 1
40 40
= $ 1600 x 41 x 81
40 x 40
= $ 3321.
C.I. = $. (3321 - 3200) = $ 121
ANSWER : B $ 121
Question: India has a run rate of 3.2 in the first 10 overs. What should be the run rate in remaining 40 overs to win a game of 282 runs?
A.6.25
B.6.27
C.6.22
D.6.21
Answer: A.6.25
Explanation: Explanation:
Runs scored in first 10 overs:
=> Rate*Overs= 3.2*10 = 32 runs
=> Required runs = 282-32 = 250
=> Left overs= 40
Required rate = runs/overs
= 250/40
= 6.25
=> 6.25 runs per over is needed to win the game.
ANSWER: A
Question: In how many ways can 21 books on English and 19 books on Hindi be placed in a row on a shelf so that two books on Hindi may not be together?
A.1540
B.2314
C.5420
D.1240
Answer: A.1540
Explanation: We must place all these books as under:
XEXEX….XEX
There are 21 books on English, 19 books on Hindi
19 places out of 22 can be chosen 22C19=22C3=1540 ways
ANS: A
Question: Two trains A and B starting from two points and travelling in opposite directions, reach their destinations 9 hours and 4 hours respectively after meeting each other. If the train A travels at 110kmph, find the rate at which the train B runs.
A.40
B.165
C.120
D.80
Answer: B.165
Explanation: If two objects A and B start simultaneously from opposite points and, after meeting, reach their destinations in ‘a’ and ‘b’ hours respectively (i.e. A takes ‘a hrs’ to travel from the meeting point to his destination and B takes ‘b hrs’ to travel from the meeting point to his destination), then the ratio of their speeds is given by:
Sa/Sb = √(b/a)
i.e. Ratio of speeds is given by the square root of the inverse ratio of time taken.
Sa/Sb = √(4/9) = 2/3
This gives us that the ratio of the speed of A : speed of B as 2:3.
Since speed of A is 110 kmph, speed of B must be 110*(3/2) = 165 kmph
Answer B
Question: Rs. 800 becomes Rs. 956 in 3 years at a certain rate of simple interest.If the rate of interest is increased by 4% ,What amount will Rs. 800 become in 3 years ?
A.Rs. 1020.80
B.Rs. 1025
C.Rs. 1052
D.Data inadequate
Answer: C.Rs. 1052
Explanation: Solution
S.I. = Rs.(956-800 )=Rs.156
Rate = (100x156/800x3) = 6 1/2%
New rate = (6 1/2 +4)% = 10 1/2%
New S.I. = Rs.(800 x21/2x3/100) Rs. 252.
∴ New amount = Rs.(800+252)= Rs. 1052.
Answer C
Question: A sum of money is put out at compound interest for 2 years at 20%. It would fetch Rs.482 more if the interest were payable half-yearly, then it were pay able yearly. Find the sum.
A.3377
B.6886
C.2788
D.2000
Answer: D.2000
Explanation: P(11/10)4 - P(6/5)2 = 482
P = 2000
Answer:D
Question: There stand nine temples in a row in a holy place. All the nine temples have 100 steps climb. A fellow devotee comes to visit the temples. He drops a Re. 1 coin while climbing each of the 100 steps up. Then he offers half of the money he has in his pocket to the god. After that, he again drops Re. 1 coin while climbing down each of the 100 steps of the temple.
If he repeats the same process at each temple, he is left with no money after climbing down the ninth temple. Can you find out the total money he had with him initially?
A.143700
B.146900
C.376190
D.248117
Answer: B.146900
Explanation: B
146900
Whenever you face such type of questions, it is wise to begin from the last thing. Here in this question the last thing will be the 9th temple. He climbed down 100 steps and thus you know, he had Rs. 100 before beginning climbing down. Thus, he must have offered Rs. 100 to the god in that temple too (he offered half of the total amount). Also, he must have dropped Rs. 100 while climbing the steps of the ninth temple. This means that he had Rs. 300 before he begand climbing the steps of the ninth temple.
Now, we will calculate in the similar manner for each of the temples backwards.
Before the devotee climbed the eight temple: (300+100)*2 + 100 = 900
Before the devotee climbed the seventh temple: (900+100)*2 + 100 = 2100
Before the devotee climbed the Sixth temple: (2100+100)*2 + 100 = 4300
Before the devotee climbed the fifth temple: (4300+100)*2 + 100 = 8900
Before the devotee climbed the fourth temple: (8900+100)*2 + 100 = 18100
Before the devotee climbed the third temple: (18100+100)*2 + 100 = 36,500
Before the devotee climbed the second temple: (36500+100)*2 + 100 = 73300
Before the devotee climbed the first temple: (73300+100)*2 + 100 = 146900
Therefore, the devotee had Rs. 146900 with him initially.
Question: The average of first 20 natural numbers is?
A.10.5
B.11.4
C.5.3
D.5.9
Answer: A.10.5
Explanation: Sum of 20 natural no. = 420/2 = 210
Average = 210/20 = 10.5
Answer:A
Question: a dog have birth to 12 puppies, 2 female and 10 male. what is the ratio of the female puppies to the male?
A.1/5
B.1/6
C.1/10
D.2/12
Answer: A.1/5
Explanation: If female is 2 and male is 10, then 1/5.
so ratio of female to male is = 2/10 = 1/5
ANSWER:A
Question: A small water pump would take 3 hours to fill an empty tank. A larger pump would take 3/4 hour to fill the same tank. How many hours would it take both pumps, working at their respective constant rates, to fill the empty tank if they began pumping at the same time?
A.3/4
B.3/5
C.5/7
D.1/2
Answer: B.3/5
Explanation: Rate of the small pump is 1/3 tank/hour
Rate of the larger pump is 1/(3/4) or 4/3 tank/hour;
Combined rate of the two pumps is 1/3+4/3=5/3 tank/hour, together they will fill the empty tank in 1/(5/3)) = 3/5 hours (time=job/rate).
Answer: B
Question: P is five times as old as Q, and Q is six years older than R. If R is z years old, what is P’s age in terms of z?
A.5z + 6
B.5z − 30
C.5z + 30
D.(z + 6)/5
Answer: C.5z + 30
Explanation: P = 5Q
Q = R+6 = z+6
P = 5(z+6) = 5z + 30
The answer is C.
Question: A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangule, whose length and breadth are in the ratio of 6 : 5. What is the area of the rectangle?
A.54 cm2
B.30 cm2
C.17 cm2
D.26 cm2
Answer: B.30 cm2
Explanation: The circumference of the circle is equal to the permeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=> x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle
= 6 * 5
= 30 cm2
Answer: B
Question: R=(429)^2 * 237 * (1243)^3 is thrice of ?
A.33605 * 31960 * (1243)^2
B.33654 * 538219 * (1243)^2
C.33891 * 533247 * (1243)^2
D.34122 * 532004 * (1243)^2
Answer: C.33891 * 533247 * (1243)^2
Explanation: R=(429)^2*237*(1243)^3 is an odd number.
Among answer choices only C is an odd number, (so thrice C also will be an odd number).
Answer: C.
Question: The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?
A.5
B.4
C.7
D.2
Answer: D.2
Explanation: Let the sides of the rectangle be l and b respectively.
From the given data,
(√l2 + b2) = (1 + 108 1/3 %)lb
=> l2 + b2 = (1 + 325/3 * 1/100)lb
= (1 + 13/12)lb
= 25/12 lb
=> (l2 + b2)/lb = 25/12
12(l2 + b2) = 25lb
Adding 24lb on both sides
12l2 + 12b2 + 24lb = 49lb
12(l2 + b2 + 2lb) = 49lb
but 2(l + b) = 28 => l + b = 14
12(l + b)2 = 49lb
=> 12(14)2 = 49lb
=> lb = 48
Since l + b = 14, l = 8 and b = 6
l - b = 8 - 6 = 2m.Answer: D
Question: Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
Year	Item of Expenditure
Salary	Transport and Fuel	Bonus	Interest on Loans	Taxes
1998	288	98	3.00	23.4	83
1999	342	112	2.52	32.5	108
2000	324	101	3.84	41.6	74
2001	336	133	3.68	36.4	88
2002	420	142	3.96	49.4	98
The total amount spent for transport by the company during the given period is approximately what percent of the total amount of salary paid during this period?
A.A)0.5%
B.B)1.24%
C.C)1%
D.D)3%
Answer: C.C)1%
Explanation: Required percentage
=	(288 + 342 + 324 + 336 + 420)
=	[	17	x 100	]	%
1710
~= 1%.
Answer : C
Question: The length of the bridge, which a train 150 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
A.76 m
B.178 m
C.225 m
D.187 m
Answer: C.225 m
Explanation: Speed = [45 X 5/18] m/sec
= [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (150 + x)/30 = 25/2
=> 2(150 + x)= 750 => x = 225 m.
Answer: C
Question: If a two-digit positive integer has its digits reversed, the resulting integer differs from the original by 36. By how much do the two digits differ?
A.3
B.4
C.5
D.6
Answer: B.4
Explanation: we are given that if the integer N has its digits reversed the resulting integer differs from the original by 25. First let’s express the reversed number in a similar fashion to the way in which we expressed the original integer.
10B + A = reversed integer
Since we know the resulting integer differs from the original by 27 we can say:
10B + A – (10A + B) = 36
10B + A – 10A – B = 36
9B – 9A = 36
B – A = 4
Since B is the tens digit and A is the units digit, we can say that the digits differ by 4.
The answer is B.
Question: Eighty percent of the lights at Hotel California are on at 8 p.m. a certain evening. However, forty percent of the lights that are supposed to be off are actually on and ten percent of the lights that are supposed to be on are actually off. What percent X of the lights that are on are supposed to be off?
A.22(2/9)%
B.16(2/3)%
C.11(1/9)%
D.10%
Answer: D.10%
Explanation: Is the Answer D.
let me try..
Let the light which are supposed to be OFF = SO
Let the light which are supposed to be ON = SN
Let the light which are ACTUALLY OFF = AO
Let the light which are ACTUALLY ON = AN
Let the total no. of lights be 100,
So ACTUALLY ON lights = 80
And ACTUALLY OFF lights = 20
Also given >> forty percent of the lights that are supposed to off are actually on >>> (40/100)*SO are ACTUALLY ON
it means >>> (60/100)*SO are ACTUALLY OFF
Also given >> ten percent of the lights that are supposed to be on are actually off >>> (10/100)*SN are ACTUALLY OFF
it means >>> (90/100)*SN are ACTUALLY ON
So, Total ACTUALLY ON lights = (40/100)*SO + (90/100)*SN = 80
and Total ACTUALLY OFF lights = (60/100)*SO + (10/100)*SN = 80
From here we get SO = 20
we need to find: What percent of the lights that are on are supposed to be off >>> So light ACTUALLY ON are 80 and light which are ACTUALLY ON, which are supposed to be OFF = (40/100)*SO = 8.
So (8/80)*100 X= 10%.D
Question: What is the lowest possible common multiple of 2 distinct integers, each greater than 145?
A.146
B.147
C.292
D.146*146
Answer: C.292
Explanation: The least common multiple of two numbers greater than 145 is 2(146) = 292, where the two distinct integers are 146 and 292.
The answer is C.
Question: The numerator of a fraction is increased by 200% and denominator is increased by 250% the resultant fraction is 3/14. What is the original fraction?
A.1/2
B.3/4
C.1/4
D.1/8
Answer: C.1/4
Explanation: if the original fraction is x/y then after increasing numerator by 200% and denomenator by 250% new fraction will become 3x/3.5y
3x/3.5y = 3/14 => x/y = 1/4 , Hence original fraction is 1/4
ANSWER:C
Question: Which of the following does NOT have a decimal equivalent that is a terminating decimal?
A.1/2^25
B.5^3/2^7
C.3^8/6^10
D.3^9/6^7
Answer: C.3^8/6^10
Explanation: For a fraction to have terminating decimal, it must either have only 2 and/or 5 in the denominator. All other values in the denominator leads to non terminating decimal values
Hence,
1. A has 2 in the denominator, Hence it is terminating
2. B is also terminating
3. 3^8/(6^10) can be written as 3^8/ (2^10 * 3^10) => 1/(2^10 * 3^2). There is 3 in the denominator. Hence it is non terminating decimal
4. 3^9/(2^7 * 3^7) => 3^2/2^7. Hence Terminating
5. Has both 2 & 5 in the denominator. Hence Terminating.
Option C
Question: In Company J, the total monthly payroll for the 15 factory workers is $30,000 and the total monthly payroll for the 30 office workers is $75,000. By how much does the average (arithmetic mean) monthly salary of an office worker exceed that of a factory worker in this company?
A.$450
B.$500
C.$600
D.$650
Answer: B.$500
Explanation: The average monthly salary of a factory worker is: $30,000 / 15 = $2000.
The average monthly salary of an office worker is: $75,000 / 30 = $2500.
The difference in average salary is: $2500 - $2000 = $500.
The answer is B.
Question: There are two numbers. If 50% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?
A.A)1/2
B.B)5/8
C.C)6
D.D)6/7
Answer: A.A)1/2
Explanation: Let the two numbers be x and y.
50/100 * x + y = 5/4y
=> 1/2 x = 1/4 y => x/y = 1/2
A)
Question: A technical support team of 6 agents is chosen from 9 senior-level agents and 5 junior-level agents. The team must have at least 2 seniors and at least 3 juniors. How many ways can this team be created?
A.140
B.320
C.1015
D.1020
Answer: D.1020
Explanation: Solution: We have two possibilities 2S 4J or 3S 3J
(9C2)(5C4)+(9C3)(5C3)=700
D) 1020
Question: The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is:
A.3
B.4
C.5
D.6
Answer: B.4
Explanation: Explanation:
P(1 + 20/100)n >2P => (6/5)n >2
Now,(6/5 x 6/5 x 6/5 x	6/5	)>2
So, n = 4 years.
ANSWER IS B
Question: How many figures are required to number the pages the pages of a book containing 223 pages?
A.372
B.661
C.561
D.467
Answer: C.561
Explanation: 1 to 9 = 9 * 1 = 9
10 to 99 = 90 * 2 = 180
100 to 223 = 124 * 3 = 372
-----------
561
ANSWER:C
Question: Find L.C.M of 852 and 1491
A.5964
B.5664
C.4964
D.4664
Answer: A.5964
Explanation: 852) 1491 (1
852
639) 852 (1
639
213) 639 (3
639
0
H.C.F of 852 and 1491 is 213
: . L.C.M = 852*1491/213 = 5964
Answer is A.
Question: In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit 3?
A.180
B.288
C.286
D.284
Answer: B.288
Explanation: We have to find the total number of 3-digit odd numbers not having 3 as a digit.
Units digits will be among 1,5,7,9
Tenth digits will be among 0,1,2,5,4,6,7,8,9
Hundredth digits will be among 1,2,5,4,6,7,8,9
So total numbers = 4*9*8 =288
Answer : B
Question: By selling an umbrella for Rs. 300, a shop keeper gains 10%. During a clearance sale, the shopkeeper allows a discount of 5% on the marked price. His gain percent during the sale is?
A.5.56%
B.2%
C.8%
D.3%
Answer: A.5.56%
Explanation: Marked price = Rs. 300
C.P. = 100/110 * 300 = Rs. 270
Sale price = 95% of Rs. 300 = Rs. 285
Required gain % = 15/270 * 100 =5.56%.
Answer: A
Question: 3/4 of 1/2 of 2/5 of 5020 = ?
A.392
B.229
C.753
D.493
Answer: C.753
Explanation: C
753
? = 5020 * (2/5) * (1/2) * (3/4) = 753
Question: Solve(0.76 × 0.76 × 0.76 − 0.008)/(0.76 × 0.76 + 0.76 × 0.2 + 0.04)
A.0.56
B.0.62
C.0.5
D.0.48
Answer: A.0.56
Explanation: 0.56
Option 'A'
Question: The average of runs of a cricket player of 10 innings was 18. How many runs must he make in his next innings so as to increase his average of runs by 4?
A.87
B.16
C.62
D.76
Answer: C.62
Explanation: Average after 11 innings = 22
Required number of runs
= (33* 11) - (18* 10) = 242 - 180
= 62.
Answer: C
Question: A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 5:3. The ratio of economy cars to sport utility vehicles is 4:3. What is the ratio of luxury cars to sport utility vehicles?
A.12:15
B.8:9
C.3:2
D.2:3
Answer: A.12:15
Explanation: The ratio of economy to luxury cars is 5:3 --> E:L = 5:3 = 20:12.
The ratio of economy cars to sport utility vehicles is 4:3 --> E:S = 4:3 = 20:15.
Thus, L:S = 12:15.
Answer: A.
Question: Graph G has a line of symmetry of x = –2. Graph G passes through the point (3, 3). What is the x-coordinate of another point that must have a y-coordinate of 3?
A. –8
B. –7
C. –5
D. –4
Answer: B. –7
Explanation: Line of symmetry is X=-2; one point is (3,3)
Right side distance =2+3(distance from origin) = 5; therefore Left side distance should be same from line of symmetry =5;
therefore left side co-ordinate=5+ 2(distance from origin) = 7; as the X coordinate is in 2nd quadrant hence -7
Therefore answer is B
Question: The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 44 kg, then the weight of B is:
A.31 kg
B.32 kg
C.33 kg
D.34 kg
Answer: C.33 kg
Explanation: Explanation:
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 …. (i)
A + B = (40 x 2) = 80 …. (ii)
B + C = (44 x 2) = 88 ….(iii)
Adding (ii) and (iii), we get: A + 2B + C = 168 …. (iv)
Subtracting (i) from (iv), we get : B = 33.
B’s weight = 33 kg.
Answer: C
Question: Find the L.C.M of 16,24,36,54
A.528
B.432
C.528
D.456
Answer: B.432
Explanation: The l.c.m of 16,24,36,54=2^4*3^3=432
Answer(B)
Question: A man wears socks of two colours - Black and brown. He has altogether 20 black socks and 20 brown socks in a drawer. Supposing he has to take out the socks in the dark, how many must he take out to be sure that he has a matching pair ?
A.3
B.20
C.39
D.45
Answer: A.3
Explanation: Explanation:
Since there are socks of only two colours, so two out of any three socks must always be of the same colour.
Answer: A
Question: A coin is tossed live times. What is the probability that there is at the least one tail?
A.31/32
B.31/39
C.31/31
D.61/32
Answer: A.31/32
Explanation: Explanation:
Let P(T) be the probability of getting least one tail when the coin is tossed five times.
= There is not even a single tail.
i.e. all the outcomes are heads.
= 1/32 ; P(T) = 1 - 1/32 = 31/32
Answer:A