RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A number exceeds by 25 from its 3/8 part. Then the number is?
A.40
B.25
C.20
D.30
Answer: A.40
Explanation: x â€“ 3/8 x = 25
x = 40
ANSWER A
Question: one out of five employees are capable of doing a certain task. 50 percent of the five employees, including the one who are capable, are assigned to a project involving this task. what percentage of employees assigned to the project are not capable?
A.43.33%
B.33.33%
C.50%
D.38.33%
Answer: C.50%
Explanation: Given 40% of 5 employees including 1 who are capable of doing task.
40% of 5 employeees
= 40/100 * 5
= 2 employees
===> 1 employees who are capable of doing the task and one employee who is not capable.
percentage of employees assigned who are not capable
= 1/2 * 100
= 50%
ANSWER:C
Question: A man spends Rs. 1600 per month on an average for the first three months, Rs 1550 for next four months and Rs. 1800 per month for the last five months and saves Rs . 4000 a year. What is his average monthly income?
A.2000
B.2010
C.2100
D.2200
Answer: A.2000
Explanation: Total expenditure for the first 3 months = 3 × 1600 = 4800
Total expenditure for 4 months = 4 × 1550 = 6200
Total expenditure for 5 months = 5 × 1800 = 9000
Total expenditure and saving (which is income for one year)
= 4800 + 6200 + 9000 + 4000 = Rs. 24000
So, Average monthly income = 24000/12 = Rs. 2000
A
Question: At 1:00 PM, Train X departed from Station A on the road to Station B. At 1:10 PM, Train Y departed Station B on the same road for Station A. If Station A and Station B are p miles apart, Train X’s speed is r miles per hour, and Train Y’s speed is s miles per hour, how many hours after 1:00 PM, in terms of p, r, and s, do the two trains pass each other?
A.0.5 + (p - 0.5s)/(r + s)
B.(p - 0.5s)/(r + s)
C.0.5 + (p - 0.5r)/r
D.(p - 0.5r)/(r + s)
Answer: A.0.5 + (p - 0.5s)/(r + s)
Explanation: The distance A is going to cover between 1:00 and 1:30
= .5r
now the distance between the two trains = (p-.5r)
the relative velocity = (r-(-s)) = r+s
From 1:30, time is going to take when they meet = (p-.5r)/(r+s)
so the ans is .5+((p-.5r)/(r+s)) [.5 is added for the time from 1:00 to 1:30]
ans is A
Question: The average age of 17 students of a class is 17 years. Out of these, the average age of 5 students is 14 years and that of the other 9 students is 16 years, The age of the 17th student is
A.62
B.66
C.18
D.75
Answer: D.75
Explanation: Explanation:
Age of the 17th student = [17 * 17 - (14 * 5 + 16 * 9)] = (289-214) = 75 years.
Answer: D
Question: If the consumer price index for a sample of goods and services purchased in Dallas rose from 100 at the end of 1967 to x at the end of 1985, what was the average Y (arithmetic mean) annual increase in the index over this period?
A. (x + 100)/18
B. x/18
C. (100 − x)/18
D. (x − 100)/18
Answer: D. (x − 100)/18
Explanation: CPI in end of 1967 = 100
CPI in end of 1985 = x
Number of years = 18
Average annual increase in CPI Y= (x-100)/18
Answer D
Question: If 1,000 microns = 1 decimeter, and 1,000,000 angstroms = 1 decimeter, how many angstroms equal 1 micron?
A.100
B.10
C.1,000
D.10,000
Answer: C.1,000
Explanation: Given that 1,000 microns = 1 decimeter =1,000,000 angstroms
So, 1 micron = 1,000,000/1,000
=1,000
Answer : C
Question: Kate and Danny each have $10. Together, they flip a fair coin 5 times. Every time the coin lands on heads, Kate gives Danny $1. Every time the coin lands on tails, Danny gives Kate $1. After the five coin flips, what is the probability M that Kate has more than $10 but less than $15?
A.5/16
B.1/2
C.M=12/30
D.M=15/32
Answer: D.M=15/32
Explanation: For 21 heads Kate will end up with < $10 and we want her to win. Therefore, only possibilities are 3 or 4 heads.
I made an educated guess and it worked fine.
Ans- 'D'
MGMAT's anagram helped here as well.
HHHHT = 5!/4!*1! = 5
HHHTT = 5!/3!*2! = 10
Total acceptable cases = 15
Total cases = 32
P = 15/32.D
Question: If we listed all numbers from 100 to 10,000, how many times would the digit 3 be printed?
A.3980
B.3700
C.3840
D.3780
Answer: A.3980
Explanation: DETAILED SOLUTION
We need to consider all three digit and all 4-digit numbers.
Three-digit numbers: A B C. 3 can be printed in the 100’s place or 10’s place or units place.
=> 100’s place: 3 B C. B can take values 0 to 9, C can take values 0 to 9. So, 3 gets printed in the 100’s place 100 times
=> 10’s place: A 3 C. A can take values 1 to 9, C can take values 0 to 9. So, 3 gets printed in the 10’s place 90 times
=> Unit’s place: A B 3. A can take values 1 to 9, B can take values 0 to 9. So, 3 gets printed in the unit’s place 90 times
So, 3 gets printed 280 times in 3-digit numbers
Four-digit numbers: A B C D. 3 can be printed in the 1000’s place, 100’s place or 10’s place or units place.
=> 1000’s place: 3 B C D. B can take values 0 to 9, C can take values 0 to 9, D can take values 0 to 9. So, 3 gets printed in the 100’s place 1000 times.
=> 100’s place: A 3 C D. A can take values 1 to 9, C & D can take values 0 to 9. So, 3 gets printed in the 100’s place 900 times.
=> 10’s place: A B 3 D. A can take values 1 to 9, B & D can take values 0 to 9. So, 3 gets printed in the 10’s place 900 times.
=> Unit’s place: A B C 3. A can take values 1 to 9, B & C can take values 0 to 9. So, 3 gets printed in the unit’s place 900 times.
3 gets printed 3700 times in 4-digit numbers.
So, there are totally 3700 + 280 = 3980 numbers.
CORRECT ANSWER : A
Question: The price of rice falls by 20%. How much rice can be bought now with the money that was sufficient to buy 20 kg of rice previously?
A.5 kg
B.15 kg
C.25 kg
D.30 kg
Answer: C.25 kg
Explanation: Solution: Let Rs. 100 be spend on rice initially for 20 kg.
As the price falls by 20%, new price for 20 kg rice,
= (100 -20% of 100) = 80
New price of rice = 80/20 = Rs. 4 per kg.
Rice can bought now at = 100/4 = 25 kg.
Answer: Option C
Question: In a group of cows and chickens, the number of legs was 14 more than twice the number of heads. The number of cows was:
A.5
B.7
C.10
D.12
Answer: B.7
Explanation: Let the number of cows be x and their legs be 4x.
Let the number of chicken be y and their legs be 2x.
Total number of legs = 4x + 2y.
Total number of heads = x + y.
The number of legs was 14 more than twice the number of heads.
Therefore, 2 × (x + y) + 14 = 4x + 2y.
or, 2x + 2y + 14 = 4x + 2y.
or, 2x + 14 = 4x [subtracting 2y from both sides].
or, 14 = 4x – 2x [subtracting 2x from both sides].
or, 14 = 2x.
or, x = 7 [dividing by 2 on both sides].
Therefore, the number of cows = 7.
Correct Answer:B)7
Question: If N = 1000x + 100y + 10z, where x, y, and z are different positive integers less than 4, the remainder when N is divided by 9 is
A.2
B.4
C.6
D.8
Answer: C.6
Explanation: Since we cannot have more than one correct answers in PS questions, then pick some numbers for x, y, and z and find the reminder when 1000x + 100y + 10z is divided by 9.
Say x=1, y=2, and z=3, then 1000x + 100y + 10z = 1,230 --> 1,230 divide by 9 yields the remainder of 6 (1,224 is divisible by 9 since the sum of its digit is a multiple of 9, thus 1,230, which is 6 more than a multiple of 9, yields the remainder of 6 when divided by 9).
Answer; C.
Question: Three times a number is 20% more than twice another number when increased by 105. If twice the first number increased by 36 is 20% less than three times of the second number, then what is the first number?
A.150
B.162
C.180
D.170
Answer: B.162
Explanation: Let the two numbers be x and y.
3x = 1.2( 2y +105)
3x = 2.4y +126 ………………..(1)
2x +36 = 0.8(3y)
2x +36 =2.4y ………………..(2)
x = 162
ANSWER:B
Question: Ram sold two bicycles, each for Rs.990. If he made 10% profit on the first and 10% loss on the second, what is the total cost of both bicycles?
A.2000
B.2879
C.2700
D.2797
Answer: A.2000
Explanation: (10*10)/100 = 1%loss
100 --- 99
? --- 1980 => Rs.2000
Answer:A
Question: When a Mobile is sold for Rs. 24000, the owner loses 40%. At what price must that Mobile be sold in order to gain 40%?
A.54,000
B.56,000
C.58,000
D.60,000
Answer: B.56,000
Explanation: 60 : 24000 = 140 : x
x = (24000 x 140)/60 = 56000.
Hence, S.P. = Rs. 56,000.
Answer: Option B
Question: A can empty the tank in 28 hrs, B can fill the tank in 14 hrs, and C takes 7 hrs for filling.
If all three pipes are opened simultaneously ,how long it will take to fill the tank?
A.4 hr 36 minutes
B.5 hr 36 minutes
C.6 hr 36 minutes
D.7 hr 36 minutes
Answer: B.5 hr 36 minutes
Explanation: Solution:time taken=(28*14*7*)/(28*14 - 14*7 + 28*7)
To solve this quicker find out LCM(28,14,7)
we get 28
Time taken =28/(-28/28 +28/14 + 28/7)
=28/(-1+2+4)
=28/5
=5.6 hrs
=5 hr 36 minutes
Answer B
Question: Vijay bought 160 shirts at the rate of Rs. 225 per shirt. The transport expenditure was Rs. 1400. He paid an octroi at the rate of Rs. 1.75 per shirt and labour charges were Rs. 320. What should be the selling price of one shirt, if he wants a profit of 60%?
A.282
B.229
C.277
D.380
Answer: D.380
Explanation: Total CP per shirt = 225 + 1400/160 + 1.75 + 320/160 = Rs. 237.5
SP = CP[(100 + profit%)/100]
= 237.5 * [(100 + 60)/100] = Rs. 380.
Answer:D
Question: If a and b are mixed in 3:5 ration and b and c are mixed in 8:5 ration if the final mixture is 35 liters, find the amount of b?
A.13.73 ltrs
B.14.73 ltrs
C.15.73 ltrs
D.16.73 ltrs
Answer: C.15.73 ltrs
Explanation: Ratio of abc will be 24 :40:25,
Amt of b in 35 litr of mixture of a,b,c = 40*35/89 =15.73 ltrs
ANSWER:C
Question: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
A.28
B.68
C.66
D.51
Answer: B.68
Explanation: Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X - 48 = 180
1000/x - 48 * 5/18 = 180
50 = 9X - 120
X = 68 Kmph
Answer: B
Question: The simple interest and the true discount on a certain sum for a given time and at a given rate are Rs. 85 and Rs. 75 respectively. The sum is:
A.1360
B.637.5
C.1600
D.1800
Answer: B.637.5
Explanation: Sol.
Sum = S.I. * T.D. / (S.I)-(T.D.) = 85 * 75 / (85 - 75) = Rs.637.5.
Answer B
Question: Ramu bought an old car for Rs. 42000. He spent Rs. 8000 on repairs and sold it for Rs. 64900. What is his profit percent?
A.29.8%
B.16%
C.18%
D.82%
Answer: A.29.8%
Explanation: Total CP = Rs. 42000 + Rs. 8000 = Rs. 50000 and SP
= Rs. 64900
Profit(%) = (64900 - 50000)/50000 * 100
= 29.8%
Answer:A
Question: a certain organization has three committees. only two persons are members of all committees, but every pair of committees have three members in common. what is the least possible no of member of members on any one committee?
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: Total 4 members minimum required to serve only on one committee.
ANSWER:A
Question: A sum of money is borrowed and paid back in two annual installments of Rs. 882 each allowing 5% C.I. The sum borrowed was?
A.1277
B.1640
C.2877
D.1882
Answer: B.1640
Explanation: Explanation:
Principal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)
= [882/(1 + 5/100) + 882/(1 + 5/100)2]
= (882 * 20)/21 + (882 * 400)/441 = Rs. 1640.
Answer: B
Question: The present worth of a certain bill due sometime hence is Rs. 400 and the true discount is Rs. 20. What is the banker's discount?
A.Rs. 19
B.Rs. 22
C.Rs. 20
D.Rs. 21
Answer: D.Rs. 21
Explanation: Explanation :
BG = (TD)2/PW=202/400= Rs. 1
BG = BD – TD
=> 1 = BD - 20
=> BD = 1 + 20 = Rs. 21 Answer : Option D
Question: In how many years will a sum of money doubles itself at 5% per annum on simple interest?
A.80%
B.20%
C.29%
D.30%
Answer: B.20%
Explanation: P = (P*5*R)/100
R = 20%
Answer: B
Question: Two trains 121 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
A.7.16
B.7.12
C.7.11
D.7.15
Answer: D.7.15
Explanation: T = (121 + 165)/ (80 + 65) * 18/5
T = 7.15
Answer: D
Question: From a total of 7 men and 3 women, how many ways to form a group of 5 men and 2 women ?
A.53
B.57
C.61
D.63
Answer: D.63
Explanation: Explanation :
Required number of ways = (7C5 3C2)
= (21*3)
= 63.
Answer : D
Question: Pipe A usually fills a tank in 2 hours. On account of a leak at the bottom of the tank, it takes pipe A 30 more minutes to fill the tank. How long will the leak take to empty a full tank if pipe A is shut?
A.7 hours
B.8 hours
C.9 hours
D.10 hours
Answer: D.10 hours
Explanation: Pipe A fills the tank normally in 2 hours. Therefore, it will fill ½ of the tank in an hour.
Let the leak take x hours to empty a full tank when pipe A is shut. Therefore, the leak will empty of the tank in an hour.
The net amount of water that gets filled in the tank in an hour when pipe A is open and when there is a leak = of the tank. — (1)
When there is a leak, the problem states that Pipe A takes two and a half hours to fill the tank. i.e. hours. Therefore, in an hour, of the tank gets filled. – (2)
Equating (1) and (2), we get => => x = 10 hours.
The problem can also be mentally done as follows.
Pipe A takes 2 hours to fill the tank. Therefore, it fills half the tank in an hour or 50% of the tank in an hour.
When there is a leak it takes 2 hours 30 minutes for the tank to fill. i.e hours to fill the tank or or 40% of the tank gets filled.
On account of the leak, (50 - 40)% = 10% of the water gets wasted every hour. Therefore, the leak will take 10 hours to drain a full tank.
ANSWER:D
Question: A telephone number contains 10 digit, including a 3-digit area code. Bob remembers the area code and the next 5 digits of the number. He also remembers that the remaining digits are not 1, 6, or 7. If Bob tries to find the number by guessing the remaining digits at random, the probability that he will be able to find the correct number in at most 2 attempts is closest to which of the following?
A.1/7
B.1/14
C.1/28
D.2/49
Answer: D.2/49
Explanation: There are 7*7 = 49 possibilities.
Bob has 2 chances so the probability is 2/49.
The answer is D.
Question: 5n + 7 > 12 and 7n - 5 < 44; n must be between which numbers?
A.1 and 8
B.2 and 6
C.0 and 9
D.1 and 7
Answer: D.1 and 7
Explanation: 5n > 5 --> n > 1
7n < 49 --> n < 7
1 < n < 7
Answer: D
Question: A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
A.35 hrs
B.20 hrs
C.10 hrs
D.15 hrs
Answer: A.35 hrs
Explanation: Pipe A alone take x hrs
then pipe B and C will take x/2 and x/4 hrs
=>1/x+2/x+4/x=1/x=>7/x=1/5
x = 35 hrs
ANSWER A
Question: The weight of four dogs is determined to be 25 pounds, 31 pounds, 35 pounds and 33 pounds respectively. The weight of a fifth dog is determined to be y pounds. If the average (arithmetic mean) weight of the first four dogs is the same as that of all five dogs what is the value of y?
A.31
B.33
C.35
D.37
Answer: A.31
Explanation: Total weight of the 4 dogs = (25+31+35+33) = 124
Avg = 124/4 = 31
Total weight of 5 dogs = 124+y or 4(31)+y
Average of 5 dogs as per Question = 31
Equation:
4(31) + y = 5 (31), or y = 31.
Choose A
Question: 200 liters of a mixture contains milk and water in the ratio 4:1. If 20 liters of this mixture be replaced by 20 liters of milk, the ratio of milk to water in the new mixture would be?
A.6:1
B.1:6
C.2:3
D.3:2
Answer: A.6:1
Explanation: Quantity of milk in 200 liters if mix = 200*4/5 =160 liters
Quantity of milk in 210 liters of new mix = 160+20 = 180 liters
Quantity of water in it = 210-180 = 30 liters
Ratio of milk and water in new mix = 180:30 = 6:1
Answer is A
Question: a, b, c, and d are positive integers where a is a factor of b and c is a factor of d. Which of the following is NOT necessarily an integer?
A.(ac)/(bd)
B.(bd)/(ac)
C.(bcd)/a
D.d/c + b/a
Answer: A.(ac)/(bd)
Explanation: As per the question, let a = 2, b = 6, c = 5, and d = 10. Plugging these into the answer choices, only A does not yield an integer.
Question: Operation#is defined as adding a randomly selected two digit multiple of 14 to a randomly selected two digit prime number and reducing the result by half. If operation#is repeated 10 times, what is the probability that it will yield at least two integers?
A.0%
B.10%
C.20%
D.30%
Answer: A.0%
Explanation: Any multiple of 14 is even.
Any two-digit prime number is odd.
(even+odd)/2 is not an integer. Thus # does not yield an integer at all.
Therefore P=0.
Answer: A.
Question: Kim finds a 4-meter tree branch and marks it off in thirds and fifths. She then breaks the branch along all the markings and removes one piece of every distinct length. What fraction of the original branch remains?
A.2/5
B.7/5
C.3/5
D.8/15
Answer: C.3/5
Explanation: 3 pieces of 1/5 length and two piece each of 1/15 and 2/15 lengths. removing one piece each from pieces of each kind of lengths the all that will remain will be
2 pieces of 1/5 i.e 2/5, 1 piece of 1/15, and 1 piece of 2/15
Which gives us 2/5 + 1/15 + 2/15 -----> 3/5
Answer is C
Question: A group of 10 representatives is to be selected out of 12 seniors and 10 juniors. In how many different ways can the group be selected if it should have at least one senior?
A.22C10 - 6
B.22C10 - 4
C.22C12 - 1
D.22C10 - 1
Answer: D.22C10 - 1
Explanation: The total number of ways of forming the group of ten representatives is 22C10.
The total number of ways of forming the group that consists of no seniors is 10C10 = 1 way
The required number of ways
= 22C10 - 1
Answer: D
Question: A 750 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.300
B.875
C.360
D.770
Answer: B.875
Explanation: Speed = 750/18 = 125/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 750)/39 = 125/3
=> x = 1625 m.
L=1625-750=875
Answer: Option B
Question: The average age of a group of 12 students was 20. The average age increased by 2 years when two new students joined the group. What is the average age of the two new students who joined the group?
A.22 years
B.30 years
C.34 years
D.32 years
Answer: C.34 years
Explanation: Answer
The average age of a group of 12 students is 20.
Therefore, the sum of the ages of all 12 of them = 12 * 20 = 240
When two new students join the group, the average age increases by 2.
New average = 22.
Now, there are 14 students.
Therefore, the sum of the ages of all 14 of them = 14 * 22 = 308
Therefore, the sum of the ages of the two new students who joined = 308 - 240 = 68
And the average age of each of the two new students = 68/2 = 34 years.
Answer C
Question: A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
A.22
B.23
C.24
D.26
Answer: D.26
Explanation: EXPLANATION
Let the number of hens be x and the number of cows be y.
Then, x + y = 48 …. (i)
and 2x + 4y = 140 x + 2y = 70 …. (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
Answer D
Question: What will be the compound interest on a sum of Rs. 30,000 after 3 years at the rate of 12% p.a.?
A.s.10123.77
B.s.10123.21
C.s.10123.20
D.s.12147.84
Answer: D.s.12147.84
Explanation: Amount = [30000 * (1 + 12/100)3]
= 30000 * 28/25 * 28/25 * 28/25
= Rs. 42147.84
C.I. = (42147.84 - 30000)
= Rs. 12147.84
Answer:D
Question: Lionel left his house and walked towards Walt's house, 48 miles away. Two hours later, Walt left his house and ran towards Lionel's house. If Lionel's speed was 3 miles per hour and Walt's 3 miles per hour, how many miles had Lionel walked when he met Walt?
A.12
B.16
C.20
D.27
Answer: D.27
Explanation: In the first 2 hours Lionel at the rate of 3 miles per hour covered distance=rate*time=3*2=6 miles. So, the distance between him and Walt was 48-6=42 miles when Walt left his house. Now, their combined rate to cover this distance was 3+3=6 miles per hour, hence they will meet (they will cover that distance) in time=distance/rate=42/6=7 hours. Total time that Lionel was walking is 2+7=9 hours, which means that he covered in that time interval distance=rate*time=3*9=27 miles.
Answer: D.
Question: In a box, there are 12 red, 6 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
A.12/23
B.10/21
C.7/12
D.11/31
Answer: A.12/23
Explanation: Total number of balls = 10+6+5 = 23
E = event that the ball drawn is neither red nor green
= event that the ball drawn is red
n(E) = 12
P(E) = 12/23
Answer is A
Question: A and B can do a piece of work in 18 days; Band C can do it in 24 days A and C can do it in 36 days. In how many days will A, Band C finish it together?
A.16 days
B.12 days
C.3 days
D.5 days
Answer: A.16 days
Explanation: Sol. (A + B)'s 1 day's work = (1/18) (B + C)'s 1 day's work = (1/24)
and (A + C)'s 1 day's work = (1/36)
Adding, we get: 2 (A + B + C)'s 1 day's work =¬(1/18 + 1/24 + 1/36)
=9/72 =1/8
(A +B + C)'s 1 day's work =1/16
Thus, A, Band C together can finish the work in 16 days.
Ans: A
Question: A, Band C can do a piece of work in 11 days, 20 days and 67 days respectively, working alone. How soon can the work be done if A is assisted by Band C on alternate days?
A.7.1 days
B.8.1 days
C.9.1 days
D.10 days
Answer: B.8.1 days
Explanation: (A+B)'s 1 day's work = 1/11+1/20 = 31/220
(A+C)'s 1 day's work = 1/11+1/67 = 78/737
work done in 2 day's = 31/220+78/737 = 19/77
19/77th work done in 2 days
work done= 77/19*2 = 8.1 days
ANSWER:B
Question: After the typist writes 12 letters and addresses 12 envelopes, she inserts the letters randomly into the envelopes (1 letter per envelope). What is the probability that exactly 1 letter is inserted in an improper envelope?
A.1/12
B.0
C.12/212
D.11/12
Answer: B.0
Explanation: 0
If one letter is in wrong envelope, the letter corresponding to that letter will also be in wrong envelope.
ANSWER:B
Question: In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was
A.2500
B.2700
C.3000
D.3100
Answer: B.2700
Explanation: Solution
Number of valid votes = 80% of 7500
= 6000.
Valid votes polled by other candidates	= 45% of 6000
(45/100×6000)
= 2700.
Answer B
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions?
A.287 m
B.704 m
C.278 m
D.298 m
Answer: B.704 m
Explanation: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm
= 704 m
Answer:B
Question: Victor's job requires him to complete a series of identical jobs. If Victor is supervised at work, he finishes each job three days faster than if he is unsupervised. If Victor works for 144 days and is supervised for half the time, he will finish a total of 36 jobs. How long T would it take Victor to complete 10 jobs without any supervision?
A.34
B.52
C.60
D.70
Answer: C.60
Explanation: Rate when supervised = (job)/(time) = 1/t.
Rate when unsupervised = (job)/(time) = 1/(t+3).
For 144/2=72 days he is supervised and for 144/2=72 days he is unsupervised and does 36 jobs:
72/t + 72/(t+3) = 36 --> t=3 days --> t+3 = 6 days.
Victor to complete 10 jobs without any supervision will need T 10(t + 3) = 60 days.
Answer: C.
Question: how many three digit number are thre in which if one digit is 3 then it must be follwed by 7 . repetetion is not allowed
A.466
B.463
C.14
D.17
Answer: B.463
Explanation: 1st case: three digits no without considering 3
first place can be filled using 8 numbers (excluding 0 and 3)=8
second place can be filled using 8 numbers (excluding 3 and digit filled in first place)=8
last place can be filled using 7 numbers (excluding 3 and digit filled in first place & second place)=7
therefore, three digits formed are= 8*8*7=448
2nd case: now consider number using 3
if 3 and 7 are first two digit then last digit can be filled using 8 digits
if 3 and 7 are last two digits then first place can be filled using 7 digits
therefore, total 3 digit no including 3 are= 8+7=15
hence, total 3 digits numbers are= 448+15=463
ANSWER:B