RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Three years ago the average age of a family of seven members was 22 years. A boy have been born, the average age of the family is the same today. What is the age of the boy?
A.A)1
B.B)2
C.C)3
D.D)4
Answer: A.A)1
Explanation: 7 * 25 = 175
8 * 22 = 176
--------------
1
Answer: A
Question: Of the 200 students at University XYZ majoring in one or more of the engineering disciplines, 120 are majoring in electrical and 150 are majoring in mechanical. If at least 30 of the students are not majoring in either electrical or mechanical, then the number of students majoring in both electrical and mechanical could be any number from
A.30 to 70
B.50 to 80
C.110 to 130
D.130 to 150
Answer: D.130 to 150
Explanation: if there are 120 students majoring in electrical then there must be 80 person not majoring electrical at all, since both of the student not majoring electrical and mechanical is at least 30, so the number of the student who are not majoring electrical but majoring mechanical will be at least 50.
if there are 150 students majoring in mechanical there must be 50 students who are not majoring mechanical at all, since the number of the student who are not majoring electrical but majoring mechanical will be at least 50, hence the number of students both majoring mechanical and electrical will be at least 130
so there must be at least 130 students who major in both
see the answers option the only possible answer is D !
Question: In a certain sequence, each term except for the first term is one less than twice the previous term. If the first term is 1, then the 3rd term is which of the following?
A.−1.5
B.−1
C.1.
D.0.5
Answer: C.1.
Explanation: First = 1
Second = 2*1-1 = 1.
Second = 2*1-1 = 1.
Answer: option C
Question: A group of 10 representatives is to be selected out of 12 seniors and 10 juniors. In how many different ways can the group be selected if it should have at least one senior?
A.²²C₁₀
B.²²C₁₀ + 1
C.²²C₉ + ¹⁰C₁
D.²²C₁₀ - 1
Answer: D.²²C₁₀ - 1
Explanation: The total number of ways of forming the group of ten representatives is ²²C₁₀.
The total number of ways of forming the group that consists of no seniors is ¹⁰C₁₀ = 1 way
The required number of ways = ²²C₁₀ - 1
ANSWER:D
Question: Number N is randomly selected from a set of all primes between 10 and 40, inclusive. Number G is selected from a set of all multiples of 5 between 10 and 40 inclusive. What is the probability that N+G is odd?
A. 1/2
B. 2/3
C. 3/4
D. 4/7
Answer: D. 4/7
Explanation: All primes except 2 are odd, thus N must be odd. For N + G = odd + G to be odd, G must be even.
There are 7 multiples of 5 between 10 and 40, inclusive: 10, 15, 20, 25, 30, 35, and 40. Out of them 3 (15, 25, and 35) are odd.
Therefore the probability that N + G is odd is 4/7.
Answer: D.
Question: If a person walks at 15 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is:
A.50 km
B.56 km
C.60 km
D.40 km
Answer: D.40 km
Explanation: Let the actual distance travelled be x km.
x/10 = (x+20)/15
15x = 10x + 200
5x = 200
x = 40 km.
answer :D
Question: Every digit of a number written in binary is either 0 or 1. To translate a number from binary, multiply the nth digit (reading from right to left) by 2^(n-1)
What is the largest prime number (written in binary) that is a factor of both 10010000 and 100100000 ?
A. 10
B. 11
C. 1001
D. 1011
Answer: C. 1001
Explanation: Binary Divison can provide a quick answer if you are comfortable with it.
as option E is the biggest binary number we try with it first :
100010000/ 1001 =10000
1000100000/ 1001 =100000
so answer is option is C
Question: According to a recent student poll, 5/6 out of 30 members of the finance club are interested in a career in investment banking. If two students are chosen at random, what is the probability that at least one of them is interested in investment banking?
A.1/14
B.4/49
C.2/7
D.28/29
Answer: D.28/29
Explanation: 25 students are interested, 5 are not interested
Prob = 1 - 5C2/30C2 = 1 - (5*4/(30*29))=1 - 20/580
= 1- 1/29 = 28/29
Answer : D
Question: Look at this series: 53, 53, 39, 39, 25, 25, ... What number should come next?
A.A)12
B.B)11
C.C)27
D.D)53
Answer: B.B)11
Explanation: In this series, each number is repeated, then 14 is subtracted to arrive at the next number.
Answer: B
Question: B and C work together can complete work in 8 days A and B together can complete same work in 12 days and A& C together complete in 16 days in total how many days A,B and C complete the same work together?
A.3 9/13
B.7 5/13
C.7 5/12
D.3 5/12
Answer: B.7 5/13
Explanation: Explanation:
(A+B+C)’s 2 day work = (1/8+1/12+1/16 ) = 13/48
on day work =13/96
so they complete work in 96 /13 = 7 5/13 days
Answer: Option B
Question: One card is drawn at random from a pack of 52 cards. What is the probability that the card drawn is a face card (Jack, Queen and King only)?
A.6/18
B.3/13
C.2/14
D.9/18
Answer: B.3/13
Explanation: Clearly, there are 52 cards, out of which there are 12 face cards.
P (getting a face card) = 12/52 = 3/13.
Answer B
Question: Two-third of a positive number and 16/216 of its reciprocal are equal. Find the positive number.
A.9/25
B.14/4
C.4 /12
D.144/25
Answer: C.4 /12
Explanation: Explanation:
Let the positive number be x.
Then, 2/3 x = 16/216 * 1/x
x2 = 16/216 * 3/2
= 16/144
x = √16/144 =4 /12.
ANSWER:C
Question: if a@b = a * b^(1/2) then 5@9 = ?
self made
A.12
B.16
C.13
D.15
Answer: D.15
Explanation: a@b = a * b^(1/2)
5@9 = 5*9^(1/2) = 5*3 = 15
Correct Option: D
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 sec. What is the length of the fast train?
A.35
B.24
C.27
D.27 7/9
Answer: D.27 7/9
Explanation: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5 = 250/9 = 27 7/9 m.
Answer: Option D
Question: Large, medium and small ships are used to bring water. 4 large ships carry as much water as 7 small ships; 3 medium ships carry as much water as 2 large ships and 1 small ship. If 15 large, 7 medium and 14 small ships, each made 36 journeys to bring a certain quantity of water, then in how many journeys will 12 large, 14 medium and 21 small ships bring the same quantity of water?
A.29 journeys
B.30
C.20
D.50
Answer: A.29 journeys
Explanation: Explanation :
Here, Large, Medium and Small ships are denoted by the symbol L, M and S.
Now, according to the question,
4L = 7S. ------(i)
3M = 2L + S. ------(ii)
Using above equations, the ratios of the capacity of the Large, Medium and Small ships are :-
7: 6 : 4.
Let, the number of journeys required be x. Since, quantity of water remains the same, so :-
=((15×7+7×6+ 14×4)36) = x (12×7+14×6+21×4).
=>((15×7+7×6+14×4)36) / (12×7+14×6+21×4)= x
=>x=7308/252
=>x=29.
Answer : A
Question: 30 square stone slabs of equal size were needed to cover a floor area of 50.7 sq.m. Find the length of each stone slab?
A.130cm
B.767cm
C.88cm
D.666cm
Answer: A.130cm
Explanation: Area of each slab
=50.7/30m2=1.69m2
Length of each slab √1.69=1.3m=130cm
Question: Six students wrote science exam. Their average marks are 70. Five Students got 65, 75, 55, 72 and 69 marks respectively. Therefore what is the marks of the sixth student?
A.84
B.68
C.85
D.75
Answer: A.84
Explanation: EXPLANATION
Total marks of 5 students = (65+75+55+72+69) = 336
Required marks = [ (70 x 6) – 336 ]
= (420 – 336)
= 84
Answer A
Question: Find the value of a/b + b/a, if a and b are the roots of the quadratic equation x2 + 8x + 4 = 0?
A.12
B.14
C.18
D.20
Answer: B.14
Explanation: a/b + b/a = (a2 + b2)/ab = (a2 + b2 + a + b)/ab
= [(a + b)2 - 2ab]/ab
a + b = -8/1 = -8
ab = 4/1 = 4
Hence a/b + b/a = [(-8)2 - 2(4)]/4 = 56/4 = 14.
B)
Question: Average weight of 10 people increased by 1.5 kg when one person of 45 kg is replaced by a new man. Then weight of the new man is
A.50
B.55
C.60
D.65
Answer: C.60
Explanation: Explanation:
Total weight increased is 1.5 * 10 = 15.
So weight of new person is 45+15 = 60
Option C
Question: If the probability of rain on any given day in Chicago during the summer is 25%, independent of what happens on any other day, what is the probability of having exactly 3 rainy days from July 4 through July 7 inclusive?
A.1/16
B.3/32
C.5/32
D.3/64
Answer: D.3/64
Explanation: One possible case is: rainy-rainy-rainy-not rainy.
The probability of this case is 1/4*1/4*1/4*3/4 = 3/256
The number of possible cases is 4C3 = 4.
P(exactly 3 rainy days) = 4*3/256 = 3/64
The answer is D.
Question: The value of each of 5 numbers is at least 8. The average (arithmetic mean) of these 5 numbers is 24. If the average of two of the numbers is 18, what is the largest possible value that any of these 5 numbers can have?
A.28
B.50
C.68
D.76
Answer: C.68
Explanation: Average => (a1+a2+a3+a4+a5)/5 =24
Thus => a1+a2+a3+a4+a5 = 120
now least value is 8, so let a1 = 8
average of 2 numbers is 18
thus , let (a2+a3) /2 =18
a2+a3 = 36
This tells that sum of last 2 numbers should be :
120 -8-36 =76
Then by elimination , eliminate 84 and 76
highest possible value of a5 should be 68 from the answer choice
Answer : C
Question: 1, 6, 13, 22, 33, ?
A.35
B.46
C.48
D.49
Answer: B.46
Explanation: The pattern is + 5, + 7, + 9, + 11,....
Answer : B.
Question: QUANT 4-PACK SERIES Problem Solving Pack 4 Question 2 For every positive integer n...
For every positive integer n that is greater than 1, the function f(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The f(n) could have any of the following units digits except…?
A.1
B.2
C.4
D.6
Answer: B.2
Explanation: For every positive integer n that is greater than 1, the function f(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The f(n) could have any of the following units digits except…?
Used brute force on this one to calculate. Not sure if there is a quicker way.
1+3=4 C is out
1+3+....15= 81 A is out
1+3+5+7=16 D is out
1+3+5=9 E i out
Answer: B
Question: Two dice are tossed simultaneously. Find the probability that the total is a prime number.
A.5/9
B.5/8
C.5/6
D.5/34
Answer: A.5/9
Explanation: ANSWER: A
Question: In a stockpile of products produced by three machines M1, M2 and M3, 40% and 30% were manufactured by M1 and M2 respectively. 3% of the products of M1 are defective, 1% of products of M2 defective, while 94% of the products of M3 III are not defective. What is the percentage of defective in the stockpile?
A.3.3%
B.5%
C.2.5%
D.4%
Answer: A.3.3%
Explanation: Explanation :
Let there be 100 products in the stockpile. 40% and 30% were manufactured by M1 and M2 respectively. So, 30% are manufactured by M3.
Products from M1 = 40, from M2 = 30 and from M3 = 30.
Number of defective products from M1 = 0.03 x 40 = 1.2, from M2 = 0.01 x 30 = 0.3 and from M3 = 0.06 x 30 = 1.8
Therefore, total number of defective products = 3.3
Answer : A
Question: In a college the ratio of the numbers of boys to the girls is 8:5. If there are 190 girls, the total number of students in the college is?
A.562
B.356
C.452
D.494
Answer: D.494
Explanation: Let the number of boys and girls be 8x and 5x
Then , 5x = 190
x= 38
Total number of students = 13x = 13*38 = 494
Answer is D
Question: A sum was put at simple interest at a certain rate for 9 years Had it been put at 5% higher rate, it would have fetched 1350 more. Find the sum.
A.3000
B.3100
C.3200
D.3300
Answer: A.3000
Explanation: Difference in S.I. = P×T/100(R1−R2)
⇒ 1350 = P×9x5/100(∵ R1 - R2 = 2)
⇒ P = 1350×100/9x5=3000
Answer A
Question: The remainder when W=1+3+3^2+3^3+..........+3^200 is divided 13.
A.12
B.7
C.0
D.5
Answer: C.0
Explanation: W=1+3+3^2+3^3+..................+3^200
Is a Geometric progression having common ratio as '3' and number of terms as '201'.
Since Sum to n terms in GP = a(r^n-1)/(r-1)
where a=First term and r =common ration
Hence,
1*(3^201 -1 )/(3-1)
Rem of (3^201-1)/2 divided by 13
3^201 -1 /26
WKT, 3^3 = 27 = 26+1
{(26+1)^67 - 1}/26
{1-1}/26
=>0.C
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is?
A.76 sec
B.88 sec
C.48 sec
D.44 sec
Answer: C.48 sec
Explanation: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 0.9 = 2 km = 2000 m.
Required time = 2000 * 3/125 = 48 sec.
Answer: C
Question: Find the least square number which is exactly divisible by 10,12,15 and 18.
A.900
B.120
C.103
D.140
Answer: A.900
Explanation: L.C.M. of 10, 12, 15, 18 = 180. Now, 180 = 2 * 2 * 3 * 3 *5 = 22 * 32 * 5.
To make it a perfect square, it must be multiplied by 5.
Required number = (22 * 32 * 52) = 900.
ANSWER A
Question: Currently apples cost 75 cents/pound. Due to a disease affecting the apple trees it is expected that next month apples will cost 150% more than they do currently. How much are apples expected to cost next month?
A.195 cents /pound
B.192 cents /pound
C.187.50 cents /pound
D.187 cents /pound
Answer: C.187.50 cents /pound
Explanation: If a new cost is p percent greater than the old cost, then (new cost) = (old cost) + (p/100)(old cost).
In this case, (new cost) = 75 cents/pound + (150/100)(75 cents/pound)
= 75 cents/pound + 112.50 cents/pound
= 187.50 cents /pound
Answer : C
Question: Find the number of ways in which 10 different beads can be arranged to form a necklace.
A.181440
B.245890
C.457890
D.124560
Answer: A.181440
Explanation: Since in forming a necklace clockwise and anticlockwise arrangements are not different, therefore,10 beads can be arranged to form a necklace in(10-1)! /2 ways
= 9!/2 = 181440ways
Answer is A
Question: A person takes 5hrs 45 min in walking to a place and ridingback. He would have gained 2hrs by riding both ways. The time he would take to walk both ways is?
A.5 hours 45 min
B.6 hours 30min
C.4 hours 50 min
D.7 hours 45 min
Answer: D.7 hours 45 min
Explanation: ----------------------------------------------------------------
Solution 1
----------------------------------------------------------------
Given that time taken for riding both ways will be 2 hours lesser than
the time needed for waking one way and riding back
From this, we can understand that
time needed for riding one way = time needed for waking one way - 2 hours
Given that time taken in walking one way and riding back = 5 hours 45 min
Hence The time he would take to walk both ways = 5 hours 45 min + 2 hours = 7 hours 45 min
In fact, you can do all these calculations mentally and save a lot of time
which will be a real benefit for you.
D
Question: If ab+bc+ca=0,What is the value of a^2+b^2+c^2?
A.(a^2+b^2+c^2)/2
B.(a+b+c)^2
C.(a^2+b^2+c^2)^2
D.a+b+c
Answer: B.(a+b+c)^2
Explanation: The option B is correct.
The formula (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca).
(a+b+c)^2=a^2+b^2+c^2+2(0).
a^2+b^2+c^2=(a+b+c)^2 is the answer
Question: A and B can finish a work 30 days if they work together. They worked together for 20 days and then B left. A finished the remaining work in another 20 days. In how many days A alone can finish the work?
A.60
B.50
C.40
D.30
Answer: A.60
Explanation: Explanation :
Amount of work done by A and B in 1 day = 1/30
Amount of work done by A and B in 20 days = 20 × (1/30) = 20/30 = 2/3
Remaining work – 1 – 2/3 = 1/3
A completes 1/3 work in 20 days
Amount of work A can do in 1 day = (1/3)/20 = 1/60
=> A can complete the work in 60 days
Answer : Option A
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 46 years now, the son's age five years back was
A.16years
B.17years
C.18years
D.19years
Answer: C.18years
Explanation: Let the son's present age be x years. Then, (46 - x) = x
2x = 46.
x = 23.
Son's age 5 years back (23 - 5) = 18 years.
C)
Question: A person was asked to state his age in years. His reply was, "Take my age three years hence, multiply it by 3 and then subtract three times my age three years ago and you will know how old I am." What was the age of the person?
A.18
B.87
C.26
D.27
Answer: A.18
Explanation: Let the present age of the person be x years.
Then, 3(x + 3) - 3(x - 3) = x
3x + 9 - 3x + 9 = x => x = 18'
Answer: A
Question: 8^100 is divisible by 17. Find the remainder?
A.8
B.12
C.16
D.18
Answer: C.16
Explanation: This is an extremely difficult problem to solve with out Fermat's little theorem. By applying Fermat's little theorem , We know that 816 when divided by 17, the remainder is 1.
So divide 100 by 16 and find the remainder. Remainder = 4
Therefore, 100 = (16 × 6) + 4
Now this problem can be written as 810017 = 816×6+417 = (816)6×8417
Now this problem simply boils down to (1)6×8417 = 8417
84 = 82×82, we need to find the remainder when 64 × 64 is divisible by 17. Or 13 × 13 = 169. When 169 is divided by 17, remainder is 16.
C
Question: Four of the five parts numbered (a), (b), (c), (d) and (e) in the following equation are exactly equal. Which of the parts is not equal to the other four? The number of that part is the answer.
A.371.587 + 46.32 – 217.907
B.4 × 125 – 75 × 4
C.58.25 × 4.5 – 65.875
D.25 × 12 – 2 × 5 × 10
Answer: C.58.25 × 4.5 – 65.875
Explanation: The other parts are equal to 200.
Answer C
Question: Two buses and a van were employed to transport a class of students on a field trip. 3/5 of the class boarded the first bus. 1/2 of the remaining students boarded the second bus, and the rest of the students boarded the van. When the second bus broke down, 1/2 of the students on the second bus boarded the first bus. What fraction of the class was on board the first bus?
A.a) 1/2
B.b) 7/10
C.c) 11/15
D.d) 23/30
Answer: B.b) 7/10
Explanation: This is a pure ratio question (we aren't given any numbers for anything), so you can just choose any starting number you like, and use it to solve the problem. The best number to pick is almost always the product of all the denominators of your fractions, so here we could start with 30 students. Then we have:
• 3/5 of these, or 18 students, board the first bus
• there are 12 students left. 1/2 of these, or 6 students, board the second bus
• this bus breaks down, and 1/2 of the 6 students, or 3 students, board the first bus
• the first bus now contains 21 out of the original 30 students, so the answer is 21/30 = 7/10
Answer B
Question: The average of 11 numbers is 30. If the average of first six numbers is 17.5 and that of last six is 42.5, then what is the sixth number?
A.30
B.36
C.45
D.47
Answer: A.30
Explanation: Given: Average of 11 numbers = 30
Step 1: Calculate total of 11 numbers by multiplying it by average value 30 = 11 x 30 = 330
Step 2: Calculate total of first six members by multiplying it by average value 17.5 = 17.5 x 6 = 105
Step 3: Calculate total of last six members by multiplying it by average value 42.5 = 42.5 x 6 = 255
Therefore, we can find sixth number by adding value of first six and last six numbers and subtracting it from the total value of 11 numbers.
Sixth number =(105 + 255)- 330 = 30
ANSWER IS A
Question: Mrs. Evans gave a test to her freshmen economics class, which has 40 students enrolled and 30 of them answered question 1 correctly. If 29 answered question 2 correctly and 10 did not take the test then how many answered both questions correctly?
A.24
B.27
C.29
D.31
Answer: C.29
Explanation: Total number of enrolled students = 40
Number of students who did not take test = 10
Hence, number of students who took test = 40 - 10 = 30
Number of students who answered Q2 correctly =29, therefore, all students who took test answered Q2 correctly.
So, number of students who answered Q1 correctly, also answered Q2 correctly = 29.
Number of students who answered both Q1 & Q2 correctly = 29.
ANSWER:C
Question: Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2% more. She would get how much?
A.9680
B.2338
C.1278
D.1098
Answer: A.9680
Explanation: (8000*3*2)/100 = 480
9200
--------
9680
Answer: A
Question: If x < y < 0, which of the following must be true?
A.2xy/3x is a negative integer
B.x-y is a positive integer
C.(-x)+ (-y) is positive integer
D.x/y is a negative integer
Answer: C.(-x)+ (-y) is positive integer
Explanation: Given x, y are less than 0. So both will be negative integers
negative + negative = negative
negative * negative = positive
negative / negative = positive
x-y is false since xSo, option C is true , because if we multiple negative number with negative it becomes positive(x, y are negative numbers)
Answer : C
Question: A bar over a sequence of digits in a decimal indicates that the sequence repeats indefinitely. What is the value of (10^4 -10^2)(0.0014)?
A.13.86
B.14.86
C.15.86
D.12.86
Answer: A.13.86
Explanation: You get 10^2 (100-1) (.0014)
we know 14/10000 = .0014
10^2 (99) * (14/10000)
10^2 = 100 and 100^2 = 10000
Cancel out the 100 with the 10^2
Left with 99(14/100).
.99*14 = 13.86
Answer : A
Question: In a rectangular coordinate system, what is the area of a rhombus whose vertices have the coordinates (0, 3.5), (11, 0), (0, -3.5), (-11, 0)?
A.56
B.77
C.112
D.116
Answer: B.77
Explanation: Area of rhombus= 1/2* D1 *D2
Length of 1st diagonal = 11+11= 22
Length of 2nd diagonal= 3.5+3.5= 7
Area= 1/2*22*7= 77
B is the answer
Question: Two pipes A and B can fill a tank in 20 and 30 minutes respectively. If both the pipes are used together, then how long will it take to fill the tank?
A.15 minutes.
B.17 minutes.
C.12 minutes.
D.10 minutes.
Answer: D.10 minutes.
Explanation: Part filled by A in 1 min =1/20
Part filled by B in 1 min =1/30	.
Part filled by (A + B) in 1 min =1/20+1/30=1/12	.
Both pipes can fill the tank in 12 minutes.
Answer is D
Question: A certain company reported that the revenue on sales increased 40 % from 2000 to 2003, and increased 60 % from 2000 to 2005. What was the approximate percent increase in revenue for this store from 2003 to 2005?
A. 50 %
B. 40 %
C. 14 %
D. 32 %
Answer: C. 14 %
Explanation: Assume the revenue in 2000 to be 100. Then in 2003 it would be 140 and and in 2005 160, so from 2003 to 2005 it increased by (160-140)/140=20/140=1/7=~14%.
Answer: C
Question: radius of a circle is 5cm , if we draw a rectangle of maximum size, what is the area of rectangle?
A.30
B.40
C.50
D.60
Answer: C.50
Explanation: Area of rectangle of max size inside circle will be a square with diagonal equal to 10 cms.
Then side of square = Root (100/2) = Root 50
Area of square = Root 50 * root 50 = 50 sq cms.
ANSWER:C
Question: If P represents the product of the first 13 positive integers, which of the following must be true?
I. P is an even number
II. P is a multiple of 17
III. P is a multiple of 24
A.I only
B.II only
C.III only
D.None of the above
Answer: A.I only
Explanation: Answer = A) Ionly
Question: Together, Andrea and Brian weigh p pounds; Brian weighs 14 pounds more than Andrea. Brian and Andrea's dog, Cubby, weighs p/4 pounds more than Andrea. In terms of p, what is Cubby's weight in pounds?
A. p/2 - 10
B. 3p/4 - 7
C. 3p/2 - 5
D. 5p/4 - 10
Answer: B. 3p/4 - 7
Explanation: Together, Andrea and Brian weigh p pounds --> A + B = p.
Brian weighs 10 pounds more than Andrea --> B = A + 14 --> A + (A + 14) = p --> A = (p - 14)/2 = p/2 - 7.
Brian and Andrea's dog, Cubby, weighs p/4 pounds more than Andrea --> C = A + p/4 = (p/2 - 7) + p/4 = 3p/4 -7.
Answer: B.
Question: 45% of the employees of a company are men. 60% of the men in the company speak French and 40% of the employees of the company speak French. What is % of the women in the company who do not speak French?
A.4%
B.10%
C.76.36%
D.90.16%
Answer: C.76.36%
Explanation: No of employees=100(say)
Men=45
Women=55
Men speaking french=0.6*45=27
Employees speaking french=0.55*100=55
Therefore women speaking French=55-42=13
And women not speaking French=55-13=42
% of women not speaking French=42/55*100=76.36%
Answer C