RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A baseball team won 40 percent of the first 80 games it played. How many of the remaining 82 games will the team have to win in order to have won exactly 50 percent of all the games it played?
A.36
B.45
C.49
D.55
Answer: C.49
Explanation: Games won out of first 80 questions = (40/100)*80 = 32
Total Games = 80+82 = 162
Games to be won = (50/100)*162 = 81
Remaining games to be won = 81-32 = 49
Answer: Option C
Question: If there are 9 pairs of twins, and a committee will be formed with 3 members. In how many ways this committee formed in a way that no siblings in a group?
A.632
B.672
C.756
D.744
Answer: B.672
Explanation: Firstly, there are 9 ways to choose 3 groups from the 4 groups. Hence 9C3.
Next, with the 3 groups chosen, there are 2^3 choices of choosing either one of the siblings.
Hence, the total number of ways are 9C3 * (2^3) = 672
B
Question: A number x is multiplied by 7, and this product is then divided by 3. If the positive square root of the result of these two operations equals x, what is the value of x if x≠0 ?
A.25/9
B.7/3
C.5/3
D.3/5
Answer: B.7/3
Explanation: sqrt(7x/3) to be perfect square x has to 7/3
Ans: B
Question: If 4 boys can color 48 m long cloth in 2 days, then 6 boys can color 36 m long cloth in
A.1 day
B.2 days
C.3 days
D.4 days
Answer: A.1 day
Explanation: The length of cloth painted by one boy in one day = 48 / 4 × 2 = 6 m
No. of days required to paint 36 m cloth by 6 boys = 36/ 6 × 6 = 1 day.
A)
Question: 7, 10, 8, 11, 9, 12, ___
A.10
B.11
C.12
D.13
Answer: A.10
Explanation: 10= 7+3
8 = 10-2
11= 8+3
9 = 11-2
12 =9+3
Similarly 12-2=10
ANSWER:A
Question: In Hockey game, one player throws two fair, six-sided die at the same time. If the player receives at least a five or a one on either die, that player wins. What is the probability that a player wins after playing the game once?
A.1/3
B.4/9
C.5/9
D.2/3
Answer: C.5/9
Explanation: In Hockey game, Probably the easiest approach would be to find the probability of the opposite event and subtract it from 1:
P(win) = 1- P(not win) = 1 - 4/6*4/6 = 5/9.
Answer: C.
Question: A bowl contains equal numbers of red, orange, green, blue, and yellow candies. Kaz eats all of the green candies and half of the orange ones. Next, he eats half of the remaining pieces of each color. Finally, he eats red and yellow candies in equal proportions until the total number of remaining candies of all colors equals 20% of the original number. What percent of the red candies remain?
A.5%
B.7.5%
C.10%
D.12.5%
Answer: D.12.5%
Explanation: Let x be the original number of each color.
Kaz eats all of the green candies and half of the orange ones.
There are 0 green candies and 0.5x orange candies remaining.
He eats half of the remaining pieces of each color.
There are 0.25x orange candies, and 0.5x each of red, yellow, and blue candies.
He eats red and yellow candies in equal proportions.
orange+blue+red+yellow = 0.75x + red + yellow = x
red + yellow = 0.25x
red = 0.125x, since red = yellow.
The answer is D.
Question: Find the perimetri of trapezium with sides 4,6,12 and distance between two parallel side is 3.
A.27
B.26
C.28
D.25
Answer: A.27
Explanation: 1/2*(6+12)*3=27
ANSWER:A
Question: A gardener wants to plant trees in his garden in rows in such away that the number of trees in each row to be the same. If there are 24 rows the number of trees in each row is 42 if there are 12 more rows find the number of trees in each row?
A.21
B.28
C.34
D.32
Answer: B.28
Explanation: Required number of trees
= 24/36 * 42 = 28.
Answer:B
Question: Find the compound interest on Rs.16,000 at 20% per annum for 9 months, compounded quarterly
A.Rs 2520
B.Rs 2521
C.Rs 2522
D.Rs 2523
Answer: C.Rs 2522
Explanation: Explanation:
Please remember, when we have to calculate C.I. quarterly then we apply following formula if n is the number of years
Amount=P(1+R/4 /100)4n
Principal	= Rs.16,000;
Time=9 months	= 3 quarters;
Rate = 20%, it will be 20/4 = 5%
So lets solve this question now,
Amount=16000(1+5/100)3=18522
C.I=18522−16000=2522
Option C
Question: In the coordinate plane, the points F (-1,1), G (1,3), and H (3,1) lie on a circle with center P. What are the coordinates of point P ?
A.(0,0)
B.(1,1)
C.(1,2)
D.(1,-2)
Answer: B.(1,1)
Explanation: I thought I need to find the 4th point that would lie on the circle
Hence my answer was D (1,-1)
But the the center of the circle will lie on (1,1)
Question: A man rows to a place 48 Km distance and back in 14 hours. He finds that he can row 4 Km with the stream in the same time 3 Km against the stream. The rate off the stream is?
A.5
B.3
C.2
D.1
Answer: D.1
Explanation: Let be moves 4km downstream in X Hours
Then in speed downstream = Kmph
Speed in upstream = 4/X Kmph
==> 48/4/X + 48/3/X = 14
==> 12X + 16X =14
==> X = 1/2
Speed in downstream = 8 Kmph
Speed in up stream = 6 Kmph
Then the Rate of stream = 1/2 (8 - 6) = 1 Kmph
Answer is D.
Question: If a(a + 8) = 9 and b(b + 8) = 9, where a ≠ b, then a + b =
A. −8
B. −2
C. 2
D. 46
Answer: A. −8
Explanation: a(a + 8) = 9
=> we have a = 1 or -9
also b(b + 8) = 9
=> b = 1 or -9
given a ≠ b
1) when a =1, b= -9 and a + b = -8
1) when a = -9, b= 1 and a + b = -8
Answer choice A
Question: A man took a loan from a bank at the rate of 10% p.a. simple interest.After 3 years he had to pay Rs. 5400 interest only for the period.The principal amount borrowed by him was :
A.Rs. 2000
B.Rs. 10,000
C.Rs. 18,000
D.Rs. 20,000
Answer: C.Rs. 18,000
Explanation: Solution
Principal = Rs.(100x5400/10x3)= Rs. 18000.
Answer C
Question: The speed of a boat in upstream is 100 kmph and the speed of the boat downstream is 170 kmph. Find the speed of the boat in still water and the speed of the stream?
A.10 kmph
B.17 kmph
C.19 kmph
D.35 kmph
Answer: D.35 kmph
Explanation: Speed of the boat in still water
= (100+170)/2
= 135 kmph. Speed of the stream
= (170-100)/2
=35kmph.
Answer: D
Question: If the average (arithmetic mean) of x + 3, x + 4, and x + 5 is 0, then x =
A.–4
B.–3
C.–2
D.–1
Answer: A.–4
Explanation: (x+3 + x+4 + x+5)/3 = 0
=>3x + 12 = 0
=>x = -4
Answer A
Question: 1/3 +1/2 - 5/6 + 1/5 + 1/4 - 9/20 -9/20=
A.0
B.2/15
C.2/5
D.9/20
Answer: D.9/20
Explanation: We need to determine the result of 1/3 + 1/2 - 5/6 + 1/5 + 1/4 - 9/20
Let’s add the given fractions in two groups. In the group of the first three fractions, notice that1/3 and 1/2 share a common denominator of 6 with 5/6.
1/2 + 1/3 = 3/6 + 2/6 = 5/6
Thus, 5/6 – 5/6 = 0
Looking at the 2nd group of the fractions (1/5, 1/4, and 9/20), notice that1/5 and 1/4 share a common denominator of 20 with 9/20.
1/5 + 1/4 = 4/20 + 5/20 = 9/20
Thus, 9/20 – 9/20 = 0.
Thus, the result of 1/3 + 1/2 – 5/6 + 1/5 + 1/4 – 9/20 is 9/20.
Answer: D
Question: There is an unlimited stock of blue, red, white, and grey coloured balls. What is the number of ways of selecting 12 balls from the stocks?
A.735
B.445
C.455
D.475
Answer: C.455
Explanation: Let us say that we have selected 'x1' blue balls, 'x2' red balls, 'x3' white balls and 'x4' grey coloured balls.
This means, x1+x2+x3+x4 = 12
Now, for an intance, 1+2+3+6 can be an answer. 0+0+0+12 can also be another answer
Hence, we need to find the non-negative integral solution for the equation
x1+x2+x3+x4 = n is
(n+k-1)C(k-1)
Here, n=12 and k=4
(12+4-1)C(4-1) = 15C3 = 455
ANSWER:C
Question: The vertex of a rectangle are (1, 0), (5, 0), (1, 2) and (5, 2) respectively. If line L passes through the origin and divided the rectangle into two identical quadrilaterals, what is the slope of line L?
A.3
B.6
C.1/3
D.1/2
Answer: C.1/3
Explanation: If line L divides the rectangle into two identical quadrilaterals, then it must pass through the center (3, 1). The slope of a line passing through (0,0) and (3, 1) is 1/3.
The answer is C.
Question: The value of land increases by r% during June and decreases by s% during July. If the value of the land is the same at the end of July as at the beginning of June, what is s in terms of r?
A.200r/(100+2r)
B.100r/(100+r)
C.r(2+r)/(1+r)2
D.r(200+r)/10000
Answer: B.100r/(100+r)
Explanation: The simplest pairing is a 25% increase will be offset by a 20% decrease.
Here's the proof:
Starting value = 100
25% increase = 100 + (.25)(100) = 125
20% decrease = 125 - (.2)(125) = 100
Ending value = 100
So we would be looking for an answer that equals 20 when A=25. While the answers might appear 'complex', you can actually avoid much of the 'math' if you just fill in the parts and take a good look at what you have...
Answer A: (200)(25)/(150) ... since 200>150, this answer will be greater than 25. ELIMINATE A.
Answer B: (100)(25)/125) = (100)(1/5) = 20 This is a MATCH.
Answer C: (25)(27)/(26)2 ... nothing 'cancels out', so this cannot = 20. ELIMINATE C.
Answer D: (25)(225)/10000... the 'units' digit of the numerator is a 5; when dividing by 10,000, this won't end in a 0. ELIMINATE D.
Answer E: (50/25) + 50 = 52. ELIMINATE E.
ans B
Question: Jayant opened a shop investing Rs. 30,000. Madhu joined him 2 months later, investing Rs. 45,000. They earned a profit of Rs. 54,000 after completion of one year. What will be Madhu's share of profit?
A.Rs. 27,000
B.Rs. 24,000
C.Rs. 30,000
D.Rs. 36,000
Answer: A.Rs. 27,000
Explanation: 30,000 *12=45,000*8
1:1
Madhu's share=1/2*54,000
i.e. Rs. 27,000
ANSWER:A
Question: Jack purchased two chairs at a discount of 50%. Sally purchased a table at a discount of 80%. Jack spent more on his two chairs than Sally did on her table. If Jack had purchased his two chairs at a discount of 60%, he would have spent less than Sally. If z represents the undiscounted price of Sally's table, which of the following could be the average undiscounted price of Jack's two chairs, in terms of z?
A.0.25z
B.0.22z
C.0.19z
D.0.15z
Answer: B.0.22z
Explanation: Let the average undiscounted price of Jack's two chairs be x, so 2 undiscounted chairs cost 2x.
Jack purchased two chairs at a discount of 50% --> he paid 0.5*2x = x.
Sally purchased a table at a discount of 80% --> she paid 0.2z.
Jack spent more on his two chairs than Sally did on her table --> x > 0.2z. Eliminate options C, D and E.
If Jack had purchased his two chairs at a discount of 60%, so for 0.4*2x = 0.8x, he would have spent less than Sally --> 0.8x < 0.2z --> x < 0.25z. Eliminate A.
Answer: B.
Question: In measuring the sides of a rectangle, one side is taken 5% in excess and the other 4% in deficit. Find the error percent in the area, calculate from the those measurements.
A.0.9%
B.0.8%
C.0.3%
D.0.2%
Answer: B.0.8%
Explanation: Explanation:
let x and y be the sides of the rectangle then
correct area =
=
Error% =
Answer: B) 0.8%
Question: The ratio of the earnings of P and Q is 9 : 10. If the earnings of P increases by one-fourth and the earnings of Q decreases by one-fourth, then find the new ratio of their earnings?
A.3/9
B.3/2
C.3/5
D.3/6
Answer: B.3/2
Explanation: Let the earnings of P and Q be Rs. 9x and Rs. 10x respectively.
New ration = [9x + 1/4(9x)]/[10x - 1/4(10x)]
=> [9x(1 + 1/4)]/[10x(1 - 1/4)]
= 9/10 * (5/4)/(3/4) => 3/2.
Answer:B
Question: When x is divided by 2, the quotient is y and the remainder is 1. When x is divided by 5, the quotient is z and the remainder is 6. Which of the following is the value of y in terms of z?
A.4z/7 + 5
B.(7z + 5) / 6
C.(6z + 7) / 4
D.(5z + 5) / 2
Answer: D.(5z + 5) / 2
Explanation: When x is divided by 2, the quotient is y and the remainder is 1: x = 2y + 1.
When x is divided by 5, the quotient is z and the remainder is 6: x = 5z + 6.
Equate those two:
2y + 1 = 5z + 6;
y = (5z + 5)/2.
Answer: D.
Question: If a > 1, which of the following is equal to (2a + 4)/(a^2 + 2a - 3)?
A.2(a+2)/(a+3)(a-1)
B.a + 3
C.2/(a - 1)
D.2a/(a - 3)
Answer: A.2(a+2)/(a+3)(a-1)
Explanation: Here's the algebraic approach:
(2A + 4)/(A^2 + 2A - 3) can be rewritten as...
2(A + 2)/(A+3)(A-1)
We can simplify the fraction, which leaves us with...
Ans : A
Question: What is the CP of Rs 100 stock at 7 discount, with 1/5% brokerage?
A.93.2
B.96.2
C.97.5
D.98.25
Answer: A.93.2
Explanation: Explanation:
Use the formula,
CP= 100 â€“ discount + brokerage%
CP= 100-7+1/5
93.2
Thus the CP is Rs 93.2.
ANSWER A
Question: If a fair die is rolled five times, what is the probability that a 3 occurs on at least one roll?
A.25/36
B.125/216
C.64/107
D.11/36
Answer: C.64/107
Explanation: Questions such as these that talk aboutat leastormaximumorminimumin probability questions should make sure realize that probability of any event (N) to occur = 1- P(Not N)
Thus, the probability of at least 1 roll = 1- Probability of NO 3s = 1-(5/6)(5/6)(5/6)(5/6)(5/6) = 1-43/107 = 64/107.
5/6 is the probability of NOT getting a 3 in any 1 roll with 5 allowed numbers (=1,2,4,5,6) out of a total of 6 possibilities.
C is thus the correct answer.
Hope this helps.
Question: A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 180 m in 18 sec. then find the length of the train?
A.160 m
B.190 m
C.120 m
D.180 m
Answer: D.180 m
Explanation: Length of the train be ‘X’
X + 120/15 = X + 180/18
6X + 720 = 5X + 900
X = 180m
Answer: D
Question: Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran's share in the profit ?
A.10590
B.10500
C.10129
D.11129
Answer: B.10500
Explanation: Simran : Nanda = (50000 * 36) : (80000 * 30) = 3 : 4.
Simran's share = Rs. ( 24500 * 3/7)
= Rs. 10500.
Answer: B
Question: 3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 2 men and 2 women will do that task.
A.3/7
B.3/10
C.3/18
D.3/16
Answer: A.3/7
Explanation: 3 m + 8 w = 6 m + 2 w
3 m = 6 w
1 m = 2 w
Therefore 3 m + 8 w = 14 w
2 m + 2 w =6 w
Answer is 6/14 =3/7
Answer: A
Question: What is the probability for a family with three children to have a girl and two boys (assuming the probability of having a boy or a girl is equal)?
A.1/8
B.1/4
C.1/2
D.3/8
Answer: D.3/8
Explanation: One possible case is: girl - boy - boy
The probability of this is 1/2*1/2*1/2= 1/8
There are 3C2 = 3 such cases so we should multiply by 3.
P(one girl and two boys) = 3/8
The answer is D.
Question: Which of the following fractions is greater than 1/2 and less than 9/10?
1. 1/2 2. 9/10 3. 1/3 4. 1/9 5. 3/4 6. 1/10
A.1/2
B.3/5
C.1/10
D.1/3
Answer: B.3/5
Explanation: 1/2= 0.5, 9/10 = 0.9, 1/3= 0.33, 1/9= 0.11, 3/5= 0.6, 1/10= 0.1
Clearly, 0.6 lies between 0.50 and 0.9.
Therefore, 3/5 lies between 1/2 and 9/10
Answer is B.
Question: The difference between the squares of two consecutive odd integers
is a square<1000 whose root equals the combined sum of the digits
of the two integers. What is the sum of the digits of the larger integer?
A.2
B.5
C.8
D.10
Answer: A.2
Explanation: Assume two odd integers to be (2x-1) and (2x+1).
Difference of their squares = (2 x+1)^2 - (2x-1)^2
= 4x^2 + 1 + 4x - (4x^2 + 1 - 4x)
= 4x^2 + 1 + 4x - 4x^2 - 1 + 4x
= 8x
Now root of 8x needs to be an integer such that it is equal to the sum of the digits of the two odd integers.
8 = 2^3, so x needs to be such that it "completes" a perfect square.
If we find x, we can find the value of 2x+1 (larger integer) and then sum of its digits.
Let's check the options, starting with c.
For sum to be 8, few possibilities are: 17, 35, 53, 71
If we take 17, the pair is 15 and 17, meaning x = 8.
8x = 64
root of 64 = 4 but 4 is not equal to 1+5+1+7.
Reject.
If we take 35, the pair is 33 and 35, meaning x = 17.
8x = 8*17
Reject since perfect square is not possible.
If we take 53, the pair is 51 and 53, meaning x = 26.
8x = 8*26
Reject since perfect square is not possible.
If we take 71, the pair is 69 and 71, meaning x = 35.
8x = 8*35
Reject since perfect square is not possible.
I tried each option and the possibilities and then got lost.
Then, it occurred to me that I was only checking 2-digit integers. What about 3-digits?
Starting with option a, only 2-digit odd integer whose sum is 2 is 101.
If we take 101, the pair is 99 and 101, meaning x = 50.
8x = 8*50 = 400
root of 400 = 20 which is indeed equal to 9+9+1+1.
Answer (A).
Question: P , Q and R started a business by investing Rs 120000 , Rs 135000 & Rs 150000 respectively. Find the share of each, out of the annual profit of Rs 56700
A.16800 , 18900 , 21000
B.17850 , 18900 , 21000
C.16800 , 18900 , 22000
D.17850, 18500 , 22000
Answer: A.16800 , 18900 , 21000
Explanation: Explanation :
P : Q : R = 120000 : 135000 : 150000 = 120:135:150
= 24:27:30
= 8:9:10
Share of P= 56700*8/27 = 2100*8 = 16800
Share of Q = 56700*9/27 = 2100*9 = 18900
Share of R = 56700*10/27 = 2100*10 = 21000. Answer : Option A
Question: A bookseller has two display windows. She plans to display 5 new fiction books in the left window, and 3 new non-fiction books in the right window. Assuming she can put the three fiction books in any order, and separately, the three non-fiction books in any order, how many total configurations will there be for the two display windows?
A.240
B.720
C.144
D.336
Answer: B.720
Explanation: Two displays books could be arranged n! # of total arrangements are combinations multiplied together,
5!*3! =120*6=720
Answer is B
Question: A student multiplied a number by 3/5 instead of 5/3, What is the percentage error in the calculation ?
A.22
B.64
C.365
D.29
Answer: B.64
Explanation: Let the number be x.
Then, ideally he should have multiplied by x by 5/3. Hence Correct result was .
By mistake he multiplied x by 3/5 . Hence the result with error =
Then, error =
Error % = = 64 %
Answer: B
Question: Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 4 to 2 and the ratio of Indian to British stamps is 5 to 1, what is the ratio of US to British stamps?
A.5 : 1
B.10 : 5
C.15 : 2
D.20 : 2
Answer: D.20 : 2
Explanation: U/I = 4/2
I/B = 5/1
Since I is multiple of both 2 (as per first ratio) and 5 (as per second ratio) so let's assume that I = 10
i.e. Multiplying teh first ratio by 5 and second ration by 2 in each numerator and denominator
then, U : I : B = 20 : 10 : 2
i.e. U : B = 20 : 2
Answer: Option D
Question: If A speaks the truth 20% of the times, B speaks the truth 80% of the times. What is the probability that at least one will tell the truth
A.0.82
B.0.84
C.1.5
D.1.2
Answer: B.0.84
Explanation: probability of A speaks truth p(A)=2/10;false=8/10
probability of B speaks truth p(B)=8/10;false=2/10.For given qtn
Ans=1-(neither of them tell truth).Because A & B are independent events
=1-[(8/10)*(2/10)]=1-16/100=1-0.16=0.84
ANSWER:B
Question: A man saved $2.50 in buying some lumber on sale. If he spent $25 for the lumber, which of
the following is closest to the percentage he saved?
A.8%
B.9%
C.10%
D.11%
Answer: B.9%
Explanation: 2.5/27.5 = 1/11 = 9/99 which is close to 9%.
correct answer B
Question: If a student loses 6 kilograms, he will weigh twice as much as his sister. Together they now weigh 126 kilograms. What is the student's present weight in kilograms?
A.82
B.84
C.86
D.88
Answer: C.86
Explanation: Let x be the weight of the sister.
Then the student's weight is 2x+6.
x + (2x+6) = 126
3x = 120
x = 40 kg
Then the student's weight is 86 kg.
The answer is C.
Question: If (x + 1) times (2x + 1) is an odd integer, then x must be
A.an odd integer
B.an even integer
C.a prime number
D.a composite number
Answer: B.an even integer
Explanation: (x + 1) times (2x + 1) means (x + 1) * (2x + 1)..
(x + 1)*(2x + 1)= 2x^2+3x+1...
for 2x^2+3x+1 to be odd, 3x+1 should be odd..
hence 3x should be even, which further leads to x as even..
so x is even integer..
ANSWER:B
Question: A certain sum of money doubles itself in 15 years in how much many years will it trible itself at the same rate?
A.20 years
B.30 years
C.88 years
D.44 years
Answer: B.30 years
Explanation: 100 ---- 100 --- 15
100 --- 15
--------------------
300 ---- 30 years
Answer: B
Question: If a·b·c·d=330, where a, b, c and d are positive integers, and a<b<c<d, which of the following could be the value of d−a?
A.9
B.10
C.11
D.13
Answer: A.9
Explanation: prime factorize : 330 = 2*3*5*11
Hence a = 2 and d = 11 .
Hence answer is 11 - 2 = 9
Answer A
Question: Evaluate: 983 x 207 - 983 x 107
A.98300
B.98500
C.98600
D.98900
Answer: A.98300
Explanation: 983 x 207 - 983 x 107 = 983 x (207 - 107) = 983 x 100 = 98300.
Answer is A.
Question: Caleb and Kyle built completed the construction of a shed in 10 and half days. If they were to work separately, how long will it take each for each of them to build the shed, if it will take Caleb 2 day earlier than Kyle?
A.10 and 12
B.9 and 11
C.20 and 22
D.8 and 10
Answer: C.20 and 22
Explanation: Work = (A)(B)/(A+B) where A and B are the individual times of each entity.
Here, we're told that (working together) the two workers would complete a job in 12 days. This means that (individually) each of them would take MORE than 10 days to do the job.
Answers E, A and C are illogical, since the individual times must both be greater than 10 days.
so we can TEST the values for Answers B and D.
Using the values for Answers B and D...
Answer B: (20)(22)/(20+22) = 440/42 = 10.5 This is a match
Final Answer:
C
Question: A & B started a partnership business. A's investment was thrice the investment of B and the period of his investment was two times the period of investments of B. If B received Rs 6000 as profit , what is their total profit?
A.28000
B.30000
C.42000
D.34000
Answer: C.42000
Explanation: Explanation :
Suppose B's investment = x. Then A's investment= 3x
Suppose Bs period of investment = y, then A's period of investment = 2y
A : B = 3x * 2y : xy
= 6 : 1
Total profit * 1/7 = 6000
=> Total profit = 6000*7 = 42000. Answer : Option C
Question: In one hour, a boat goes 9 km along the stream and 5 km against the stream. The speed of the boat in still water (in km/hr) is:
A.2
B.4
C.7
D.12
Answer: C.7
Explanation: Sol.
Speed in still water = 1/2 (9+5) kmph = 7 kmph.
Answer C
Question: Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 496.80?
A.18%
B.21%
C.20%
D.19%
Answer: C.20%
Explanation: CP = Rs. 540, MP = 540 + 15% of 540 = Rs. 621
SP = Rs. 496.80, Discount = 621 - 496.80 = 124.20
Discount % = 124.2/621 * 100 = 20%
ANSWER:C
Question: In the last set of tests, a student scored marks in each of 5 subjects in the ratio 4:5:6:7:8 and got an overall score of 72%. If a mark of 50% in a subject is a pass and the maximum marks of each subject is the same, how many subjects did the student pass?
A.1
B.2
C.3
D.4
Answer: D.4
Explanation: The tests scores are 4k, 5k, 6k, 7k, and 8k.
The sum of the test scores is 30k.
The average test score is 30k/5 = 72. Then k = 12.
The test scores are 48, 60, 72, 84, and 96.
The student passed 4 subjects.
The answer is D.
Question: 7^6n -1^ 6n When n is an integer > 0 is divisible by
A.119
B.127
C.141
D.154
Answer: B.127
Explanation: 127
B
Question: What annual installment will discharge a debt of Rs. 1428 due in 3 years at 12% simple interest?
A.315
B.345
C.425
D.335
Answer: C.425
Explanation: Let each Installment be Rs. x
Then, ( x+ ((x*12*1)/100)) + (x+ ((x*12*2)/100) ) + x = 1428
=((28x/25) + (31x/25) + x) = 1428 ïƒ› (28x+31x+25x)=(1428*25)
x= (1428*25)/84 = Rs.425.
Therefore,	Each installment = Rs. 425.
Answer is C.
Question: A sells a Cricket Bat to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays $228 for it, the cost price of the Cricket Bat for A is:
A.152
B.120
C.130
D.160
Answer: A.152
Explanation: A
152
125% of 120% of A = 228
125/100 * 120/100 * A = 228
A = 228 * 2/3 = 152.
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 14%?
A.20%
B.28%
C.29%
D.40%
Answer: C.29%
Explanation: SP2 = 2/3 SP1
CP = 100
SP2 = 86
2/3 SP1 = 86
SP1 = 129
100 --- 29 => 29%
Answer:C