RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Birla company plans to assign identification numbers to its employees. Each number is to consist of four different digits from 0 to 9, inclusive, except that the first digit cannot be 0. How many different identification numbers are possible?
A. 3,024
B. 4,536
C. 5,040
D. 9,000
Answer: B. 4,536
Explanation: Birla company plans to assign identification numbers to its employees.The first digit can take 9 values from 1 to 9 inclusive;
The second digit can also take 9 values (9 digits minus the one we used for the first digit plus 0);
The third digit can take 8 values;
The fourth digit can take 7 values.
Total = 9*9*8*7 = something with the units digit if 6.
Answer: B.
Question: The duplicate ratio of 3:4 is?
A.9:19
B.9:13
C.9:16
D.9:12
Answer: C.9:16
Explanation: 32: 42 = 9:16
Answer: C
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8463 for a computer table, then what was the cost price of the computer table?
A.6825
B.2977
C.2871
D.6725
Answer: A.6825
Explanation: Explanation:
CP = SP * (100/(100 + profit%))
= 8463(100/124) = Rs. 6825.
Answer: A
Question: A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
A.1000
B.2777
C.2667
D.2908
Answer: A.1000
Explanation: 90%
104%
--------
14% ---- 140
100% ---- ? => Rs.1000
Answer: A
Question: Allay's internet provider offers unlimited traffic which costs $0.5 per day charged off at 12 a.m. The service is discontinued when client's debt exceeds $5. If today in the morning Allay makes a payment of $7, for how many days, including today, will she be connected to the internet without any additional payments, given her initial balance was $0?
A. 15
B. 24
C. 25
D. 26
Answer: C. 25
Explanation: day 0- payment of $7 is made in the morning (after 12 am midnight)
day 1 onwards(after 12 am midnight) internet service will begin and will run for 7*2=14 days i.e. at the end of day 15 balance will be zero.
now Allay can still use the internet till her debt reaches $5 which means total of 5*2=10 days.
now the question states for how many days, including today, will she be connected to the internet without any additional paymentsi.e. we will have to include day0 also in our final answer. therefore total no. of days =1+14+10=25=C
Question: A and B start a business with Rs.6000 and Rs.8000 respectively. Hoe should they share their profits at the end of one year?
A.3:4
B.3:6
C.3:1
D.3:2
Answer: A.3:4
Explanation: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
6000 : 8000 => 3:4 .
Answer:A
Question: Given that E and F are events such that P(E) = 0.16, P(F) = 0.4 and P(E n F) = 0.4,
find P (E|F) and P(F|E)
A.1/4
B.2/5
C.2/7
D.3/7
Answer: A.1/4
Explanation: Here, E and F are events
P(E|F) = P(EnF)/P(F) = 0.4/0.4 = 1
P(F|E) = P(EnF)/P(E) = 0.4/0.16 = 1/4.
A)
Question: Ten years ago, Kumar was thrice as old as Sailesh was but 10 years hence, he will be only twice as old. Find Kumar’s present age.
A.60 years
B.80 years
C.70 years
D.76 years
Answer: C.70 years
Explanation: Let Kumar’s present age be x years and Sailesh’s present age be y years.
Then, according to the first condition,
x - 10 = 3(y - 10) or, x - 3y = - 20 ..(1)
Now. Kumar’s age after 10 years = (x + 10) years
Sailesh’s age after 10 years = (y + 10)
(x + 10) = 2 (y + 10) or, x - 2y = 10 ..(2)
Solving (1) and (2), we get x = 70 and y = 30
Kumar’s age = 70 years and Sailesh’s age = 30 years.
ANSWER:C
Question: A cargo ship carrying four kinds of items, doohickies, geegaws, widgets, and yamyams, arrives at the port. Each item weighs 2, 11, 5, and 7 pounds, respectively, and each item is weighed as it is unloaded. If, in the middle of the unloading process, the product of the individual weights of the unloaded items equals 1,043,504,000 pounds, how many widgets have been unloaded?
A.2
B.3
C.4
D.625
Answer: B.3
Explanation: We need to know the number of widgets (which weigh 5 pounds each). The number of times that 5 divides the number is related to the number of times that 10 divides the number.
When we divide 1,043,504,000 by 1000, we get 1,043,504,000 = 1,043,504 * 5^3 *2^3.
1,043,504 is not divisible by 5, thus there are 3 widgets.
The answer is B.
Question: The digit in units place of the product 81 x 82 x ..... x 89 is
A.0
B.2
C.6
D.8
Answer: A.0
Explanation: Sol.
Required digit = unit digit in (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9) = 0.
Answer A
Question: In how many different ways can the letters of the word 'DETAIL' be arranged in such a way that the vowels occupy only the odd positions?
A.32
B.48
C.36
D.60
Answer: C.36
Explanation: 3 vowels can be arranged in odd positions in 6 ways
and
3 consonants can be arranged in even positions in 6 ways.
so total 6*6= 36 ways
ANSWER:C
Question: If a particular is never chosen, in how many ways can a cricketbe chosen out of 15 players?
A.234
B.256
C.364
D.378
Answer: C.364
Explanation: A particular players is never chosen, it means that 11 players are selected out of 14 players.
=> Required number of ways = 14C11
= 14!/11!x3! = 364
C
Question: 80% of the population of a village is 23040. The total population of the village is ?
A.28800
B.24000
C.24936
D.25640
Answer: A.28800
Explanation: Answer
∵ 80% of P = 23040
∴ P = (23040 x 100) / 80 = 28800
Correct Option: A
Question: If A,B,C are three integers and AB+C is even ; which of the following must be true? A)C is even B)B is even C)AB is Odd
A.None of the above
B.I only
C.II only
D.III only
Answer: A.None of the above
Explanation: If AB is Odd then C will not even. O+E = O
If B is even AB is even always. But If C is Odd E+O = O
None of the above are true.
Answer : A
Question: 21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement.
A.2/17
B.3/37
C.9/42
D.8/97
Answer: C.9/42
Explanation: The probability that first toy shows the even number,
=1021=1021
Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.
Hence, probability that second toy shows the even number,
=920=920
Required probability,
=(1021)×(920)=(1021)×(920)
=9/42
C
Question: If x > 0.3, which of the following could be the value of x?
A.√0.005
B.√0.0005
C.√0.3
D.√0.006
Answer: C.√0.3
Explanation: Answer : C
Question: Find the simple interest on $10000 at 5% per annum for 12 months?
A.$410
B.$500
C.$650
D.$710
Answer: B.$500
Explanation: P = $10000
R = 5%
T = 12/12 YEARS = 1 YEAR
S.I. = P*R*T/100 = 10000*5*1/100 = $500
Answer is B
Question: How much is 80% of 40 is greater than 4/5 of 25?
A.29
B.776
C.66
D.12
Answer: D.12
Explanation: (80/100) * 40 – (4/5) * 25
32 - 20 = 12
Answer: D
Question: The average of non zero number and its square is 5 times the number. The number is?
A.5
B.7
C.9
D.10
Answer: C.9
Explanation: Let the number be x
(x+x^2)/2 = 5x
x^2 - 9x = 0
x(x-9) = 0
x = 0 or x = 9
So the number is 9
Answer is C
Question: Carolina has 1 nickel and 5 pennies in her pocket. If she pulls 2 coins out of her pocket simultaneously and randomly, what is the probability that she will be holding exactly 6 cents?
A.1/3
B.4/15
C.5/6
D.6/10
Answer: A.1/3
Explanation: The probability is equal to the number of desired choices divided by the total number of possibilities.
Probability = Favorable/Total
Total = 6C2 = 6*5/2 = 15
Favorable:
Pick 1 penny out of 5 pennies
AND
Pick the 1 nickel
5C1*1C1 = 5*1 = 5
P = 5/15 = 1/3
When you use combination method, it is picking all possible cases and the order doesn't matter. Whereas, upon choosing probability method to solve, order matters.
Thus,
Total Probability:
Probability of choosing a penny first AND Probability of choosing the nickel
OR
Probability of choosing the nickel first AND Probability of choosing a penny
Answer: A
Question: A pipe can fill a cistern in 20 minutes whereas the cistern when fill can be emptied by a leak in 30 minutes. When both pipes are opened, find when the cistern will be full?
A.17 minutes
B.87 minutes
C.60 minutes
D.27 minutes
Answer: C.60 minutes
Explanation: 1/20 - 1/30 = 1/60
60 minutes
Answer:C
Question: The average marks obtained by 120 candidates in a certain examinationis 35.if the average marks of passed candidate is 39 and that of the failed candidates is 15,what is the no. of candidates who passed the examination?
A.880
B.100
C.110
D.109
Answer: B.100
Explanation: Let No. of passed candidates are x
So, x * 39 + (120 – x) 15= 120 * 35
x = 100
B
Question: The cost of an article is decreased by 15%. If the original cost is $80, find the decrease cost.
A.33
B.11
C.68
D.36
Answer: C.68
Explanation: Original cost = $80
Decrease in it = 15% of $80
= 15/100 × 80
= 1200/100
= $12
Therefore, decrease cost = $80 - $12 = $68
Answer:C
Question: If the average (arithmetic mean) of x + 1, x + 3, and x + 5 is 0, then x =
A.–4
B.–3
C.–2
D.–1
Answer: B.–3
Explanation: (x+1 + x+3 + x+5)/3 = 0
=>3x + 9 = 0
=>x = -3
Answer B
Question: Which of the following is a prime number
A.13
B.14
C.15
D.16
Answer: A.13
Explanation: Clearly, 13 is a prime number.
Option A
Question: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is?
A.6
B.7
C.8
D.9
Answer: A.6
Explanation: S = 1
M = x
DS = x + 1
US = x - 1
35/(x + 1) + 35/(x - 1) = 12
x = 6
Answer:A
Question: The price of lunch for 15 people was $207.00, including a 15 percent gratuity for service. What was the average price per person, EXCLUDING the gratuity?
A.$11.73
B.$12.00
C.$13.80
D.$14.00
Answer: B.$12.00
Explanation: If the amount spent excluding the gratuity was x, then x(1.15) = 207
=> x = 207/1.15 = 180
Then the average price per person = 180/15 = 12
Option (B)
Question: Divide Rs. 2379 into 3 parts so that their amounts after 2, 3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part is?
A.239
B.77
C.998
D.828
Answer: D.828
Explanation: Let the parts be x, y and [2379 - (x + y)]
x + (x * 2 * 5/100) = y + (y * 3 * 5/100) = z + (z * 4 * 5/100)
11x/10 = 23y/20 = 6z/5 = k
x = 10k/11, y = 20k/23, z = 5k/6
But x + y + z = 2379
10k/11 + 20k/23 + 5k/6 = 2379
k = (2379 * 11 * 23 * 6)/3965 = (3 * 11 * 23 * 6)/5
x = [10/11 * (3 * 11 * 23 * 6)/5] = 828
Hence, the first part is Rs. 828.
Answer: D
Question: A and B’s salaries together amount to Rs. 2,000. A spends 95% of his salary and B spends 85% of his. If now their savings are the same, what is A’s salary?
A.1888
B.2676
C.1297
D.1500
Answer: D.1500
Explanation: (5/100) A = (15/100) B
A = 3B
A + B = 2000
4B = 2000 => B = 500
A = 1500
Answer: D
Question: If (x^2 + x - 8)/2 ≤ x + 1, then x could be represented by which of the following?
A.− 4 ≤ x ≤ − 3
B.− 4 ≤ x ≤ 3
C.− 3 ≤ x ≤ 4
D.− 3 ≤ x ≤ 3
Answer: C.− 3 ≤ x ≤ 4
Explanation: IMO C is correct answer
solving through eqautions
x^2 +x-8<= 2x+2
(x+3)(x-4)<=0
Question: A cube with its sides numbered 1 through 6 is rolled twice, first landing on a and then landing on b. If any roll of the cube yields an equal chance of landing on any of the numbers 1 through 6, what is the probability E that a + b is prime?
A. 0
B. 1/12
C. 5/12
D. 7/18
Answer: C. 5/12
Explanation: Total # of outcomes is 6*6=36;
Favorable outcomes:
a-b --> prime
1-1 --> 2;
1-2 --> 3;
2-1 --> 3;
1-4 --> 5;
4-1 --> 5;
2-3 --> 5;
3-2 --> 5;
1-6 --> 7;
6-1 --> 7;
2-5 --> 7;
5-2 --> 7;
3-4 --> 7;
4-3 --> 7;
6-5 --> 11;
5-6 --> 11.
Total of 15 favorable outcomes
E=15/36.
Answer: C.
Question: During a special promotion, a certain filling station is offering a 10 percent discount on gas purchased after the first 10 gallons. If Kim purchased 20 gallons of gas, and Isabella purchased 25 gallons of gas, then Isabella‟s total per-gallon discount is what percent of Kim‟s total per-gallon discount?
A.80%
B.100%
C.116.7%
D.120%
Answer: D.120%
Explanation: Kim purchased 20 gallons of gas. She paid for 10 + 0.9*10 = 19 gallons, so the overall discount she got was 1/20 = 5%.
Isabella purchased 25 gallons of gas. She paid for 10 + 0.9*15 = 23.5 gallons, so the overall discount she got was 1.5/25 = 6%.
6 is 6/5*100 = 120% of 5.
Answer: D.
Question: In a queue if 30 children were made to stand in a column, 16 columns could be formed. If 24 children were made to stand in a column, how many columns could be formed?
A.15
B.20
C.22
D.26
Answer: B.20
Explanation: Sol. Required number = 16 *^30 = 20
B
Question: A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets into it. The mass of the man is :
A.50 kg
B.60 kg
C.70 kg
D.80 kg
Answer: B.60 kg
Explanation: Explanation:
In this type of question, first we will calculate the volume of water displaces then will multiply with the density of water.
Volume of water displaced = 3*2*0.01 = 0.06 m cube
Mass of Man = Volume of water displaced * Density of water
= 0.06 * 1000 = 60 kg
Option B
Question: A boat goes 100 km downstream in 10 hours, and 60 km upstream in 15 hours. The speed of the stream is?
A.3km/h
B.4km/h
C.6km/h
D.(1/2) km/h
Answer: A.3km/h
Explanation: 100 --- 10 DS = 10
? ---- 1
60 ---- 15 US = 4
? ----- 1 S = (10 - 4)/2
= 3 kmph
ANSWER:A
Question: In a urban village of india named "owlna" , 70% people have refrigerator , 75% people have television , 80% people got computers and 80% got Air-conditionor. how many people(minimum) got all these luxury.
A.23%
B.17%
C.11%
D.10%
Answer: D.10%
Explanation: D
10%
100 - [ (100-85)+(100-80)+(100-75) +(100-70)]
=100-(15+20+25+30)
=100-90
Question: A carpenter makes 6 bunk beds every day. A military school needs to organize a place to sleep for 143 soldiers. If there are 5 carpenters working on the job, how many whole days in advance should they receive the order and start working in order to finish the right number of beds assuming that each bunk- bed is used by two soldiers?
A.3.
B.4.
C.5.
D.6.
Answer: D.6.
Explanation: I believe it is C because if 1C makes 3 beds in 1 day then:
1C's rate = 3/1
So 5c's = 3/1 * 5 = 15/1 = 15 beds in a day.
Since we have 173 soldiers who need beds and bunk beds come in pairs, 72 is the least amount of beds needed.
Time = Amount / Rate
Time = 72 / (15/1) = 72/15, simplifying we get 72/15 = 24/5 = 5.7
So, in order for the carpenters to be able to finish they need 5 whole days. At first I made the mistake of thinking how many whole days it took them to finish (as in ignore the partial day) but the prompt clarifiesdays in advance, meaning how many days would they need to finish so even if they finish early, theyusedthat day.
D
Question: There are 15 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played?
A.110
B.130
C.105
D.60
Answer: C.105
Explanation: 10 players are there.
two players play one game with one another.
so 15C2=15*14/2
=105
SO OPTION C is correct
Question: Rohan's income doubles after every one year. If the initial income was Rs. 4 lakhs, What would be the income after 6 years?
A.Rs. 2.76 crores
B.Rs. 2.51 crores
C.Rs. 2.56 crores
D.Rs. 2.57 crores
Answer: C.Rs. 2.56 crores
Explanation: Explanation:
Income after 1 year = Rs. (4 * 21) lakhs
Income after 2 years = Rs. (4 * 2 * 2) lakhs = Rs. (4 x 22) lakhs
Income after 6 years = Rs. (4 * 26) lakhs = Rs. 256 lakhs = 2.56 crores.
ANSWER: C
Question: Evaluate: 6702.5 + 670.25 + 67.025 + 6.7025 + 0.67025
A.7447.14775
B.6981.59775
C.6918.59775
D.6198.59775
Answer: A.7447.14775
Explanation: 6702.5
670.25
67.025
6.7025
+ 0.67025
---------------
7447.14775
Answer is A.
Question: The difference of two numbers is 1365. on dividing the larger number by the smaller, we get 6 as quotient and 15 as remainder. What is the smaller number?
A.240
B.270
C.295
D.360
Answer: B.270
Explanation: Let the smaller number be x. Then larger number = (x+1365).
x+1365=6x+15, 5x=1350, x=270
Smaller number=270.
Correct Option: B
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 50% profit on the first article and 50% loss on second article. Find the net profit or loss percent?
A.500
B.768
C.276
D.280
Answer: A.500
Explanation: Profit on first article = 50% of 1000 = 500.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer: A
Question: In a graduating class, the difference between the highest and lowest salaries is $100,000. The median salary is $50,000 higher than the lowest salary and the average salary is $20,000 higher than the median. What is the minimum number of students R in the class?
A.A)10
B.B)12
C.C)15
D.D)20
Answer: C.C)15
Explanation: the difference between the highest and lowest salaries is $100,000.
So there are at least 2 people - say one with salary 0 and the other with 100k. No salary will be outside this range.
Median = 50k more than lowest. So median is right in the center of lowest and highest since lowest and highest differ by 100k. In our example, median = 50k. Since there are more than 2 people, there would probably be a person at 50k.
Mean = 20k more than median so in our example, mean salary = 70k
On the number line,
0........50k (median)........100k
Mean = 70k
So there must be people more toward 100k to bring the mean up to 70k. Since we want to add minimum people, we will add people at 100k to quickly make up the right side deficit. 0 and 50k are (70k + 20k) = 90k away from 70k. 100k is 30k away from 70k. To bring the mean to 70k, we will add two people at 100k each to get:
0....50k.....100k, 100k, 100k
But when we add more people to the right of 70k, the median will shift to the right. We need to keep the median at 50k. So every time we add people to the right of 70k, we need to add people at 50k too to balance the median. 50k is 20k less than 70k while 100k is 30k more than 70k. To keep the mean same, we need to add 2 people at 100k for every 3 people we add at 50k. So if we add 3 people at 50k and 2 people at 100k, we get:
0, ... 50k, 50k, 50k, 50k, ... 100k, 100k, 100k, 100k, 100k
the median is not at 50k yet.
Add another 3 people at 50k and another 2 at 100k to get
0, 50k, 50k, 50k, 50k, 50k, 50k, 50k, 100k, 100k, 100k, 100k, 100k, 100k, 100k
Now the median is 50k and mean is 70k.
Total number of people is 15.
Answer (C)
Question: A person incurs loss for by selling a watch for Rs1140.at what price should the watch be sold to earn a 5% profit ?
A.1542
B.3645
C.7845
D.1260
Answer: D.1260
Explanation: let the new sp be Rsx.then
(100-loss%) : (1st sp)=(100+gain%) (2nd sp)
	{(100-5)/1400}={(100+5)/x}=> x={(105*1140)/95} =1260.
Ans: D
Question: Find the odd man out
864, 420, 200, 94, 40, 16, 6
A.420
B.200
C.16
D.94
Answer: D.94
Explanation: 6x2+4=16
16x2+8=40
40x2+12=92
92x2+16=200.. and so on. 94
ANSWER:D
Question: Working simultaneously and independently at an identical constant rate, 6 machines of a certain type can produce a total of x units of product P in 5 days. How many of these machines, working simultaneously and independently at this constant rate, can produce a total of 4x units of product P in 10 days?
A.9
B.10
C.12
D.14
Answer: C.12
Explanation: The rate of 6 machines is rate=job/time=x/5 units per day --> the rate of 1 machine 1/6*(x/5)=x/30 units per day;
Now, again as {time}*{combined rate}={job done}
then 10*(m*x/30)=4x --> m=12.
Answer: C.
Question: A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year?
A.5520
B.2789
C.5550
D.2889
Answer: C.5550
Explanation: Total production of salt by the company in that year = 5000 + 5100 + 5200 + .... + 6100 = 66600.
Average monthly production of salt for that year = 66600/12 = 5550.
Answer: C
Question: The positive integers a and b leave remainders of 2 and 3, respectively, when divided by 6. a > b.
What is the remainder when a – b is divided by 6?
A.4
B.3
C.5
D.2
Answer: C.5
Explanation: Let's test out some values of m and n that satisfy the given information.
a leaves are remainder of 2 when divided by 6
So, a COULD equal 8
b leaves are remainder of 3 when divided by 6
So, b COULD equal 3
What is the remainder when a – b is divided by 6?
So, a - b = 8 - 3 = 5, and when we divide 5 by 6, we get 0 with remainder 5
Answer: C
Question: Given that f(x) = x×f(x - 1) for any natural number x. If f(x + 2) = 20*f(x), then what is the value of x?
A.5
B.6
C.7
D.8
Answer: B.6
Explanation: Given:f(x) = x××f(x - 1) ....(a)
and f(x + 2) = 20××f(x) ....(b)
Substitute x = x + 1 in (a)
Then, f(x + 1) = (x + 1)××f(x) .........(c)
Substitute x = x + 2 in (a)
Then, f(x + 2) = (x + 2)××f(x + 1) ......(d)
From (b), 20××f(x) = f(x + 2) = (x + 2)××f(x + 1)= (x + 2)(x + 1)××f(x)
⇒⇒ 20××f(x) = (x + 2) (x + 1)××(f(x)
Cancelling f(x) on both sides and upon simplification we get
or x2x2+ 3x - 18 = 0
or (x + 6)(x - 3) = 0
or x = -6 or 3. Hence the answer is option (e).
Answer:B
Question: In 1995 a total of 250 earthquakes occurred worldwide, some but not all of which occurred in Asia. If 100 of these earthquakes occurred in Asia, which of the following represents the ratio of the number of earthquakes that occurred in Asia to the number that did NOT occur in Asia?
A.2/3
B.1/3
C.1/4
D.3/4
Answer: A.2/3
Explanation: We're given a couple of facts to work with:
1) There were a total of 250 earthquakes
2) Of those earthquakes, 100 of them occurred in Asia
We're asked for the ratio of the number of earthquakes that occurred IN ASIA to the number of earthquakes that DID NOT occur in Asia.
Thus, there were 150 earthquakes that DID NOT occur in Asia....
The answer to the question is 100/150 = 2/3
Answer : A
Question: A shop owner sells 25mtr of cloth and gains SP of 10 mtrs. Find the gain %?
A.30%
B.40%
C.50%
D.66.67%
Answer: D.66.67%
Explanation: Here, selling price of 10 m cloth is obtained as profit.
Profit of 10 m cloth = (S.P. of 25 m cloth) – (C.P. of 25 m cloth)
Selling price of 15 m cloth = Selling Price of 25 m of cloth
Let cost of each metre be Rs. 100.
Therefore, cost price of 15 m cloth = Rs. 1500 and S.P. of 15 m cloth = Rs. Rs. 2500
Profit% = 10/15 × 100 =66.67%
Profit of 66.67% was made by the merchant.
D
Question: A batsman makes a score of 64 runs in the 16th innings and thus increased his average by 3. Find his average after the 16th inning?
A.22
B.299
C.277
D.19
Answer: D.19
Explanation: Let the average after the 16th inning be P.
So, the average after the 15th inning will be (P-3) Hence, 15(P-30) + 64 = 16P => P = 19.Answer:D
Question: Bookman purchased 30 copies of a new book released recently, 10 of which are hardback and sold for $20 each, and rest are paperback and sold for $10 each. If 14 copies were sold and the total value of the remaining books was 240, how many paperback copies were sold?
A.8
B.12
C.6
D.4
Answer: B.12
Explanation: The bookman had 10 hardback ad 30-10=20 paperback copies;
14 copies were sold, hence 30-14=16 copies were left. Let # of paperback copies left be p then 10p+20(16-p)=240 --> 10 p=80 --> p=8
# of paperback copies sold is 20-8=12
Answer: B
Question: Michael cashed a check for $1,240 and received only $10 and $50 bills in return. During the course of a day, he used 15 bills and then lost the rest of the money. If the number of $10 bills used was either one more or one less than the number of $50 bills used, what is the minimum possible amount of money that was lost?
A. $830
B. $800
C. $770
D. $730
Answer: C. $770
Explanation: 1. 15 bills spent
2. Number of $10 bills is one more or one less than number of $50 bills.
So, 2 choices
1. 7*10 + 8*50 = $470
2. 8*10 + 7*50 = $430
Least money lost implies most money spent. i.e $470
Therefore, lost money = 1240 - 470 = 770.
Answer C
Question: If the weight of 12 meters long rod is 12.2 kg. What is the weight of 6 meters long rod ?
A.7.2 kg.
B.10.8 kg.
C.12.4 kg.
D.6.1 kg
Answer: D.6.1 kg
Explanation: Answer
∵Weight of 12 m long rod = 12.2 kg
∴ Weight of 1 m long rod = 12.2 / 12 kg
∴ Weight of 6 m long rod = 12.2 x 6 / 12
= 6.1 kg
Option: D
Question: Convert the 13/36 m/s into kilometers per hour?
A.5.3 kmph
B.2.3 kmph
C.3.3 kmph
D.1.3 kmph
Answer: D.1.3 kmph
Explanation: D
1.3 kmph
13/36 m/s = 13/36 * 18/5 = 13/10 = 1.3 kmph.