RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A certain quantity is measured on two different scales, the T-scale and the S-scale, that are related linearly. Measurements on the T-scale of 6 and 24 correspond to measurements on the S-scale of 30 and 60, respectively. What measurement on the T-scale corresponds to a measurement of 100 on the S-scale?
A. 20
B. 36
C. 48
D. 60
Answer: C. 48
Explanation: First, we have to understand what linearly means. It's not a straight ratio (since 6:30 does NOT equal 24:60). We need to look at the increases in each measurement to see what the scalar actually is.
From 6 to 24 we have an increase of 18. From 30 to 60 we have an increase of 30. Therefore, the increase ratio is 18:30 or 3:5. In other words, for every 3 that T increases, S increases by 5.
We know that S is 100. To get from 60 to 100, we went up by 40, or 8 jumps of 5; therefore, T will go up by 8 jumps of 3.
24 + 8(3) = 24 + 24 = 48=C
Question: A, B and C can do a piece of work in 24, 30 and 40 days respectively. They start the work together but C leaves 4 days before the completion of the work. In how many days is the work done?
A.11 days
B.14 days
C.13 days
D.10 days
Answer: A.11 days
Explanation: x/24 + x/30 + x/40 = 1
x = 11 days
ANSWER A
Question: Set A {3,3,3,4,5,5,5} has a standard deviation of 1. What will the standard deviation be if every number in the set is multiplied by 8?
A.A)1
B.B)2
C.C)4
D.D)8
Answer: D.D)8
Explanation: Points to remember -
1. If oneAdd/Subtractthe same amont from every term in a set, SD doesn't change.
2. If oneMultiply/Divideevery term by the same number in a set, SD changes by same number.
Hence the answer to the above question is D
Question: Find the last 2 digits
65*29*37*63*71*87*62
A.70
B.30
C.10
D.90
Answer: C.10
Explanation: Similarly for this question,
Rof(201∗202∗203∗204∗246∗247∗248∗249)∗(201∗202∗203∗204∗246∗247∗248∗249)/100
=Rof(201∗101∗203∗204∗246∗247∗248∗249)∗(201∗202∗203∗204∗246∗247∗248∗249)/50
Note: I have left denominator as 50 since it will be easier in calculations.
=Rof[(1∗1∗3∗4∗(−4)∗(−3)∗(−2)∗(−1)]∗[(1∗2∗3∗4∗(−4)∗(−3)∗(−2)∗(−1)]/50
=Rof(12∗24∗24∗24)/50=Rof(6∗24∗24∗24)/25=Rof[6∗(−1)∗(−1)∗(−1)]/25=−6
Since remainder is coming negative, we add 25 to it.
Thus Remainder is 19. In decimal format, it is 19/25 or 0.76
Thus last two digits will be 0.76*100 = 76
[Note: Rather than calculating the decimal value first, it will be faster to combine the last two steps as follows: (19/25)*100 = 19*4 = 76. This is how I did it and it saved me valuable seconds!]
Answer should be (3).
ANSWER:C
Question: A thief is noticed by a policeman from a distance of 300 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
A.150 m
B.200 m
C.170 m
D.100 m
Answer: B.200 m
Explanation: Relative speed of the thief and policeman = 11 - 10 = 1 km/hr.
Distance covered in 6 minutes = 1/60 * 6 = 1/10 km = 100 m.
Distance between the thief and policeman = 300 - 100 = 200 m
B
Question: The jogging track in a sports complex is 660 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in?
A.5.29 min
B.5.28 min
C.5.08 min
D.4.8 min
Answer: D.4.8 min
Explanation: Clearly, the two will meet when they are 660 m apart.
To be (4.5 + 3.75) = 8.25 km apart, they take 1 hour.
To be 660 m apart, they take (100/825 * 660/1000) hrs = (660/8250 * 60) min = 4.8 min.
Answer: D
Question: If 30% of a number is 12.6, find the number?
A.42
B.40
C.26
D.36
Answer: A.42
Explanation: A
40
Question: If the wheel is 14 cm then the number of revolutions to cover a distance of 1056 cm is?
A.18
B.26
C.14
D.12
Answer: D.12
Explanation: 2 * 22/7 * 14 * x = 1056 => x
= 12
Answer: D
Question: Find the simple interest for Rs. 2000 at 8% p/a for 2years.
A.Rs.300
B.3Rs.20
C.Rs.420
D.Rs.520
Answer: B.3Rs.20
Explanation: S.I= (2000*8*2)/100
P = 320
Answer: B
Question: Which of the following is larger than 3/5?
A.1/2
B.39/50
C.7/25
D.3/10
Answer: B.39/50
Explanation: if we want to compare two fraction number
a/b =c/d
then a*d (answer to a/b)
c*b (ans to c/d) (apply this conditions to all the options)
Therefore (3*5=15) (39*5=195)
39/5 is greater than 3/5..
ANSWER:B
Question: A father was as old as his son's present at the time of your birth. If the father's age is 34 years now, the son's age 5years back was?
A.10 years
B.12 years
C.14 years
D.16 years
Answer: B.12 years
Explanation: Let the son's present age be x years. Then, (34 - x) = x
2x = 34.
x = 17.
Son's age 5 years back (17 - 5) = 12 years.
B
Question: At a contest with 3,500 participants, 1/2 of the people are aged 18 to 22. Next year, the number of people aged 18 to 22 will increase by 1/7. After this change, what percentage of the total 3,500 people will the 18- to 22-year-olds represent?
A.33%
B.40%
C.55%
D.57.14%
Answer: D.57.14%
Explanation: I just wanted to mention a couple of things here:
* this is a pure ratio question; the number 3,500 is completely irrelevant, and you can ignore it if you like. When we increase something by 1/7, we are multiplying it by 1 + 1/7 = 8/7, so the answer here must be (1/2)*(8/7) = 4/7 = 57.14 %.
Answer : D
Question: Bradley owns 3b video game cartridges. If Bradleyâ€™s total is one-fourth the total owned by Andrew and triple the total owned by Charlie, how many video game cartridges do the three of them own altogether, in terms of b?
A.16/3)b
B.17/4)b
C.13/4)b
D.16b
Answer: D.16b
Explanation: Step 1: Categorize the problem
This problem is testing basic algebra and equations, with an extra layer of complexity by having variables in the answer choices.
Step 2: Think like the test maker
What is the key detail or key details in the problem? The key detail to immediately recognize is that the problem gives you Andrew and Charlieâ€™s totals in relation to Bradleyâ€™s total rather than giving you Bradleyâ€™s total in relation to the other two; and then the problem asks you to solve the problem in terms of b. This means that you have to relate Andrew and Charlieâ€™s values in relation to Bradleyâ€™s total. The test maker is attempting to force you to structure the problem in the opposite way that most people are used to structuring information. By gaining this insight, it makes it easier to solve the problem.
Step 3: Solve the problem
3b = Bradleyâ€™s total
4*3b = Andrewâ€™s total
(1/3)*3b = Charlieâ€™s total
Add each total
3b + 4*3b+ (1/3)3b = 3b + 12b + b = 16b
Therefore,choose D.
Question: An auto assembly plant performs six functions with each frame that arrives: add axles, add wheels to the axles, install the windshield to the frame, install the instrument panel, install the steering wheel, and install the interior seating. Once those six tasks are performed, each car goes to a separate building for finishing touches. If these tasks can be arranged along a linear assembly line in any order, except that the axles must be installed before the wheels can be added, how many Y ways can the assembly line be arranged?
A.120
B.240
C.360
D.480
Answer: C.360
Explanation: C) 360
short way: there are 6C! ways to do the six tasks. Half will have wheels before axles and half will have axles before wheels. So we want Y=6C!/2 -> 720/2 = 360
Question: Of the 80 people in a room, 1/4 are women. If 3/4 of the people are married, what is the maximum number of women in the room who could be unmarried?
A.20
B.24
C.26
D.28
Answer: A.20
Explanation: women = 1/4 * 80 = 20
married = 3/4 * 80 = 60
unmarried = 20
max(un-married women) = 20
Answer A
Question: The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: Let the ages of the children be x, (x + 3), (x + 6), (x + 9) and (x +12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20 => x = 4.
Age of youngest child = x = 4 years.Answer: A
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 20% profit on the first article and 20% loss on second article. Find the net profit or loss percent?
A.200
B.99
C.88
D.77
Answer: A.200
Explanation: Profit on first article = 20% of 1000 = 200.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer:A
Question: David mixed 20 kg of butter at Rs. 200 per kg with 30 kg butter at the rate of Rs. 100 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
A.Rs. 96
B.Rs. 196
C.Rs. 296
D.Rs. 190
Answer: B.Rs. 196
Explanation: Cost of Butter = 20*200+ 30*100 /50 =7000/50 = 140
40% of 140 = 56
S.P. should be = 140+56 = Rs. 196/ kg
Answer : B
Question: A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 2/3 hours to fill the tank. The leak can drain all the water of the tank in
A.6 hours
B.8 hours
C.9 hours
D.10 hours
Answer: B.8 hours
Explanation: Explanation:
Solution 1
The pump can fill the tank in 2 hour. But, because of the leak, it took 2 2/3 hours to fill the tank.
i.e., the additional water filled by the pump in 2/3 hour is emptied by the leak in 2 2/3 = 8/3 hours.
Therefore, the water filled by pump in 2 bour can be emptied by the leak in 8/3 X 3 = 8 hours.
i.e., The leak can drain all the water of the tank in 8 hours.
ANSWER IS B
Question: When Ravi was 8 years old, his father was 31 years old,. Now his father is twice Ravi's age. How old is Ravi now?
A.45 yrs
B.46 yrs
C.47 yrs
D.48 yrs
Answer: B.46 yrs
Explanation: When Ravi was 8 years old, his father was 31 years old,.
Means father's age is 23 years more than Ravi.
Now his father is twice Ravi's age.
It means difference between their ages is equal to present age of Ravi.
So Ravi's present age = 23 years. and father's age = 2*23 = 46 yrs
ANSWER:B
Question: A no.when divided by 223 gives a remainder 43, what remainder will beobtained by dividingthe same no.17?
A.2
B.7
C.9
D.11
Answer: D.11
Explanation: 223 + 43 = 266/17 = 11 (Remainder)
D
Question: Dhoni spends $250 buying his favorite dolls. If he buys only small Barbie dolls, which are $5 cheaper than the large Barbie dolls, he could buy 25 more dolls than if he were to buy only large Barbie dolls. How much does a large Barbie doll cost?
A.$10.5
B.$10
C.$11
D.$12
Answer: B.$10
Explanation: A is not an integer. So we start with B.
If large doll costs $10, then he can buy 250/10 = 25 large dolls and 250/5 =50 small dolls.
Difference is 25, which is we wanted.
Answer B.
Question: Calculate the ratio between x and y if 25% of x equal to 40% of y?
A.5 : 8
B.5 : 9
C.5 : 7
D.5 : 6
Answer: A.5 : 8
Explanation: Explanation:
25 x = 40 y
x: y = 25 : 40 = 5 : 8
Answer:A
Question: Ayesha's father was 40 years of age when she was born while her mother was 32 years old when her brother six years younger to her was born. What is the difference between the ages of her parents?
A.6
B.14
C.5
D.1
Answer: B.14
Explanation: Mother's age when Ayesha's brother was born = 32 years.
Father's age when Ayesha's brother was born = (40 + 6) years = 46 years.
Required difference = (46 - 32) years = 14 years.
Answer:B
Question: 150 125 60 120 95 60 70 ? ?
A.25 15
B.25 85
C.35 25
D.60 60
Answer: D.60 60
Explanation: 150-25=125
again 60
125-25=120
120-25=95
again 60
95-25=70
70-25=55
again 60
then answer is 60 ,60
ANSWER:D
Question: There are 9 baskets with pebbles in it.Every basket have pebbles weighing 1gm except one which has pebbles weighing 2gm.There is a weighing machine. Use the weighing machine only once and find which basket have pebbles that weigh 2gm?
A.9th
B.8th
C.6th
D.4th
Answer: D.4th
Explanation: Take 1 pebble form 1st basket, 2 from 2nd, 3 from 3rd,...9 from the 9th basket and weigh them. If all the baskets contained 1gm pebbles the weight would have been 45 [ 1+2+3+..9 = 45]
Since 1 of the basket contains 2 gm pebbles the weight will be more than 45.
Subtract 45 from the weight to get the basket number.
ie
if the weight is 49
49 - 45 = 4
4th basket
ANSWER:D
Question: The five sides of a pentagon have lengths of 2, 3, 4, 5 and 6 inches. one pentagons are considered different only when the positions of the side lengths are different relative to each others. What is the total number of different possible pentagons that could be drawn using these five side lengths ?
A. 5
B. 12
C. 24
D. 32
Answer: A. 5
Explanation: CONCEPT: The number of ways to arrange n elements around a circular Manner is (n-1)!.
But the number of ways to arrange n elements in circular manner where the arrangement can be flipped around (e.g. Necklace, Garland, Bracelet) = (n-1)!/2.
The pentagon in the problem above can be flipped over (Clockwise Arrangement of Sides = Counter-clockwise arrangement), the number of distinct ways to arrange the 5 sides = (5-1)!/2 = 5.
Answer: option A
Question: Positive integer y is 50 percent of 50 percent of positive integer x, and y percent of x equals 4. What is the value of x?
A.40
B.100
C.200
D.400
Answer: A.40
Explanation: y = 0.5*0.5*x = x/4
y%*x = 4
(y/100)*x = 4
(x/400)*x = 4
x^2 = 4*400
x = 40
The answer is A.
Question: Tom, working alone, can paint a room in 6 hours. Peter and John, working independently, can paint the same room in 3 hours and 5 hours, respectively. Tom starts painting the room and works on his own for one hour. He is then joined by Peter and they work together for an hour. Finally, John joins them and the three of them work together to finish the room, each one working at his respective rate. What fraction of the whole job was done by Peter?
A.19/35
B.23/42
C.27/55
D.31/63
Answer: D.31/63
Explanation: Tom paints 1/6 of the room in the first hour.
Tom and Peter paint 1/6+1/3 = 1/2 of the room in the next hour for a total of 4/6.
The three people then paint the remaining 2/6 in a time of (2/6) / (21/30) = 10/21 hours
Peter worked for 31/21 hours so he painted 31/21 * 1/3 = 31/63 of the room.
The answer is D.
Question: Six persons in an organization including A and B were to be divided in two groups of 3 members each. The total number of groups containing both A and B is what fraction of the total number of groups which can be formed?
A.3/10
B.1/70
C.3/14
D.1/10
Answer: A.3/10
Explanation: The fraction is nothing but the probability..
Number to choose 3 out of 6= 6C3
Number to choose A and B and 2 from remaining 4=4C2..
prob of A and B choosen=4C2/6C3=3/10
Answer : A
Question: A rectangular block 15cm by 30cm by 75cm is cut into an exact number of equal cubes. Find the least possible number of cubes?
A.6
B.40
C.15
D.10
Answer: D.10
Explanation: Volume of the block = 15*30*75 = 33750 cm^3
Side of the largest cube = H.C.F of 15,30,75 = 15cm
Volume of the cube = 15*15*15 = 3375 cm^3
Number of cubes = 33750/3375 = 10
Answer is D
Question: The ratio between the speeds of two trains is 7 : 10. If the second train runs 400 kms in 8 hours, then the speed of the first train is
A.35 km/h
B.60 km/h
C.45 km/h
D.50km/h
Answer: A.35 km/h
Explanation: A
35 km/h
Question: The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 40 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B?
A.75.00%
B.56.80%
C.110%
D.150%
Answer: B.56.80%
Explanation: Let length of each side of square A be 10
Area of A = 10^2 = 100
Since , length of each side of square A is increased by 100 percent to make square B
length of each side of square B = 2*10 = 20
Area of B = 20^2 = 400
Since , length of the side of square B is increased by 40 percent to make square C
length of each side of square C= 1.4*20 = 28
Area of C= 28^2 = 784
Difference in areas of C and cummulative areas of A and B = 784 -(400+100) = 284
percent is the area of square C greater than the sum of the areas of squares A and B = (284/500) * 100 % = 56.80%
Answer B
Question: In a certain large company, the ratio of college graduates with a graduate degree to non-college graduates is 1:8, and ratio of college graduates without a graduate degree to non-college graduates is 2:3. If one picks a random college graduate at this large company, what is the probability R this college graduate has a graduate degree?
A.1/11
B.1/12
C.1/13
D.3/19
Answer: D.3/19
Explanation: In believe the answer is D. Please see below for explanation.
0) we are told the following ratios
CGD - College Graduate with Degree
NCG - Non College Graduate
CGN - College Graduate no Degree
CGD NCG CGN
1 8
3 2
In order to make CGD and CGN comparable we need to find the least common multiple of 8 and 3 and that is 24 multiplying the first ratio by 3 and the second ratio by 8 we get
CGD NCG CGN
3 24 16
If one picks a random college graduate at this large company, what is the probability this college graduate has a graduate degree?
Nr of CGD = 3
Nr of CG = 3+ 16 = 19
Probability R of CGD / (CG) -> 3/19
Answer D
Question: How many three letter words are formed using the letters of the word TIME?
A.25
B.29
C.25
D.24
Answer: D.24
Explanation: The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is 4P3
= 4 * 3 * 2
= 24.
Answer: D
Question: 3034−(1002÷20.04)=?
A.1964
B.1984
C.2964
D.2984
Answer: D.2984
Explanation: Explanation:
=3034−(1002/2004×100)
=3034−50=2984
Option D
Question: Replace the ? by the correct Mathematics symbol to make the expression true
18 ? 12 ? 4 ? 5 = 59
A.18 ÷ 12 x 4 - 5 = 59
B.18 + 12 ÷ 4 - 5 = 59
C.18 x 12 + 4 - 5 = 59
D.18 x 12 ÷ 4 + 5 = 59
Answer: D.18 x 12 ÷ 4 + 5 = 59
Explanation: D
Question: (x + 5) is a factor in x^2 - mx - 40. What is the value of m?
A.1
B.2
C.4
D.3
Answer: D.3
Explanation: I solved the second degree equation and found it like this:
x^2 - mx - 40 = 0
(x-8)(x+5) = 0
x=8 or x= -5
Substituting both values for x in the equation we find:
x^2 - mx -40
=> (-5)^2 - m(-5) = 40
=> 25+ 5m= 40
=> 5m = 40-25=15
=> m = 3
And with 8, using a similar process we end up with:
(8)^2 - m(8) =40
-8m = 40-64= -24
m=3
Ao,ANS D
Question: Braun invested a certain sum of money at 8% p.a. simple interest for 'n' years. At the end of 'n' years, Braun got back 2 times his original investment. What is the value of n?
A.50 years
B.25 years
C.12 years 6 months
D.37 years 6 months
Answer: C.12 years 6 months
Explanation: Explanatory Answer
Let us say Braun invested $100.
Then, at the end of 'n' years he would have got back $200.
Therefore, the Simple Interest earned = 200 - 100 = $100.
We know that Simple Interest = (Principal * number of years * rate of interest) / 100
Substituting the values in the above equation we get 100 = (100 * n * 8) / 100
Or 8n = 100
Or n = 12.5years.
correct choice is (C)
Question: What percent is 120 of 60?
A.133 1/3 %
B.134 1/3 %
C.200 %
D.140 1/3 %
Answer: C.200 %
Explanation: 120/60 = 2/1
2 × 100 = 200 %
C
Question: A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.327
B.350
C.276
D.287
Answer: B.350
Explanation: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.
Answer: B
Question: If x > y and y > z, which of the following represents the greatest number W?
A. x − z
B. x − y
C. y − x
D. z − y
Answer: A. x − z
Explanation: Because x>y>z
thus W=x- z wil lbe greatest
Ans: A
Question: A certain car can travel 40 minutes on a gallon of gasoline at 50 miles per hour. If the car had started with a full tank and had 8 gallons of gasoline left in its tank at the end, then what percent of the tank was used to travel 80 miles at 60 mph?
A.15%
B.20%
C.25%
D.30%
Answer: B.20%
Explanation: Let, Tank capacity = T gallon
Used Fuel = (T-8) gallons
Distance Travelled (@50 miles/hr) = 80 miles
Distance travelled in 1 gallon = Distance travelled in 40 mins (@50 miles/hr) = (50/50)*40 = 40 miles
Fuel used to travel 80 miles = (80/40) = 2 gallon
i.e. Used fuel = (T-8) = 2 gallon
i.e. T = 10 Gallons
i.e. Used Fuel = (2/10)*100 =20%
B
Question: If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number.
A.2:5
B.2:7
C.5:7
D.5:3
Answer: D.5:3
Explanation: Explanation:
Let the first number is A and second number is B.
As per question
40/100A=2/3B
A/B=2/3∗100/40
A/B=5/3
=>A:B=5:3
Option D
Question: A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 6 days before the completion of the work. In how many days was the work completed?
A.12 days
B.16 days
C.18 days
D.11.5 days
Answer: D.11.5 days
Explanation: One day work of A, B and C = 1/24 + 1/30 + 1/40 = 1/10 Work done by A and B together in the last 6 days = 6*(1/24 + 1/30) = 9/20
Remaining work = 11/20
The number of days required for this initial work = 5.5 days.
The total number of days required = 6 + 5.5 = 11.5 days.Answer: D
Question: In the infinite sequence 10, 15, 20, 25, 30, . . . , where each term is 5 greater than the previous term, the 32th term is
A.183
B.178
C.165
D.139
Answer: C.165
Explanation: T(n) = a + (n-1) d
Here d =5, a=10, n=32
Solving we get T(n) = 165.
Answer: C
Question: 6.2 is what percent of 1000?
A.62%
B.6.2%
C.0.62%
D.0.062%
Answer: C.0.62%
Explanation: 10% of 1000 is 100.
6.2 is way less than 100 (10% of 1000).So it cannot be 62% of 1000. eliminate option a
1% of 1000 is 10.
6.2 is less than 10. So it cant be 6.2%.eliminate option b
(0.5%) i.e. half of 1% of 1000 is 5.
but 6.2 is greater than 5..
So it has to be greater than 0.5%...hence answer is 0.62%,
ANSWER:C
Question: What will be the reminder when (27^27+27) is divided by 28?
A.92
B.43
C.71
D.26
Answer: D.26
Explanation: (x^n+1) will be divisible by (x+1) only when n is odd;
(27^27+1) will be divisible by (27+1);
(27^27+1)+26 when divided by 28 will give 26 as remainder.
Correct Option : D
Question: If x is an integer, then x(x – 1)(x – k) must be evenly divisible by six when k is any of the following values EXCEPT
A.-4
B.-2
C.-1
D.2
Answer: D.2
Explanation: We have the product of 3 integers: (x-1)x(x-k).
Note that the product of 3 integers is divisible by 6 if at least one multiple is divisible by 6. Now, to guarantee that at least one integer out of x, (x – 1), and (x – k) is divisible by 6 these numbers must have different remainders upon division by 3, meaning that one of them should have remainder of 1, another reminder of 2 and the last one remainder of 0, so be divisible by 6.
Next, if k=2 then we'll have (x-1)x(x-2)=(x-1)x(x-2) --> which means that (x-1) and (x-2) will have the same remainder upon division by 6. Thus for k=2 we won't be sure whether (x-1)x(x-k) is divisible by 6.
Answer: D.
Question: Potatoes are made up of 99% water and 1% potato matter. Jack bought 100 pounds of potatoes and left them outside in the sun for a while. When he returned, he discovered that the potatoes had dehydrated and were now only made up of 98% water. How much did the potatoes now weigh?
A.50 pounds
B.80 pounds
C.90 pounds
D.100 pounds
Answer: A.50 pounds
Explanation: initially water weigh 99 pounds & patato matter weigh 1 pound.
after dehydration
water = 98%
=> potato matter = 2% = 1 pound
100% = (1/2) * 100 = 50 pounds
So, potato now weigh 50 pounds.
ANSWER:A
Question: Excluding stoppages, the speed of a bus is 54 km/hr and including stoppages, it is 45 km/hr. For how many minutes does the bus stop per hour?
A.15 min
B.10 min
C.17 min
D.20 min
Answer: D.20 min
Explanation: D
10 min
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = 9/54 * 60 = 10 min.
Question: if x:y = 1:3, then find the value of
(7x+3y):(2x+y)
A.14:5
B.15:5
C.16:5
D.17:5
Answer: C.16:5
Explanation: Explanation:
let x = 1k and y = 3k, so
=7(k)+3(3k)/ 2(k)+1(3k)
=16k/5k
=16:5
Option C
Question: Two water pumps, working simultaneously at their respective constant rates, took exactly six hours to fill a certain swimming pool. If the constant rate of one pump was 1.5 times the constant rate of the other, how many hours would it have taken the slower pump to fill the pool if it had worked alone at its constant rate?
A.9
B.12
C.15
D.18
Answer: C.15
Explanation: Let x be the rate of the slower pump. Then 1.5x is the rate of the faster pump.
Both pumps together can fill 1/6 of the pool each hour.
2.5x = 1/6
x = 1/15
The slower pump could fill the pool in 15 hours.
The answer is C.