RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What is the length of a bridge (in meters), which a train 166 meters long and travelling at 45 km/h can cross in 40 seconds?
A.310
B.318
C.326
D.334
Answer: D.334
Explanation: speed = 45 km/h = 45000 m / 3600 s = 25/2 m/s
In 40 seconds, the train can travel 25/2 * 40 = 500 meters
500 = length of train + length of bridge
length of bridge = 500 - 166 = 334 meters
The answer is D.
Question: I have Rs.450 in my pocket. I would like to give my mother, my brother and my friend the same amount, how much should I give to each of them?
A.120
B.70
C.90
D.150
Answer: D.150
Explanation: 450/3 = 150
The answer is D.
Question: The average of 10 numbers is calculated as 46. It is discovered later on that while calculating the average, the number 65 was incorrectly read as 25, and this incorrect number was used in the calculation. What is the correct average?
A.48
B.50
C.54
D.66
Answer: B.50
Explanation: The total sum of the numbers should be increased by 40.
Then the average will increase by 40/10 = 4.
The correct average is 50.
The answer is B.
Question: Two pipes A and B can fill a cistern in 20 and 30 minutes respectively, and a third pipe C can empty it in 40 minutes. How long will it take to fill the cistern if all the three are opened at the same time?
A.17 1/4 min
B.28 1/7 min
C.17 1/7 min
D.17 1/8 min
Answer: C.17 1/7 min
Explanation: 1/20 + 1/30 - 1/40 = 7/120
120/7 = 17 1/7
Answer:C
Question: The sum of two numbers is 528 and their H.C.F is 33. The number of pairs of numbers satisfying the above condition is
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: Let the required numbers be 33a and 33b.
Then 33a +33b= 528 \inline \fn_jvn \Rightarrow a+b = 16.
Now, co-primes with sum 16 are (1,15) , (3,13) , (5,11) and (7,9).
\inline \fn_jvn \therefore Required numbers are ( 33 x 1, 33 x 15), (33 x 3, 33 x 13), (33 x 5, 33 x 11), (33 x 7, 33 x 9)
The number of such pairs is 4
Answer: A
Question: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2460?
A.750
B.277
C.262
D.231
Answer: A.750
Explanation: 1/2:1/3:1/4 = 6:4:3
Ram = 6/13 * 3250 = 1500
Shyam = 4/13 * 3250 = 1000
Mohan = 3/13 * 3250 = 750
Answer: A
Question: If a can complete a work in x days and b can complete a work in y days. In how many days that they will work together simultaneously?
A.xy/(x+y)
B.(x+y)/xy
C.1/xy
D.xy
Answer: A.xy/(x+y)
Explanation: A's one day work=1/x
B's one day work=1/y
a+b=1/x+1/y=(x+y)/xy(for one day)
Total days=xy/(x+y)
Answer is option A
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
A.50 km/hr
B.15 km/hr
C.6 km/hr
D.8 km/hr
Answer: A.50 km/hr
Explanation: Explanation:
Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45 ==>
x = 50 km/hr.
Answer: A) 50 km/hr.
Question: The speed of a boat in still water is 40kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
A.kmph
B.kmph
C.kmph
D.kmph
Answer: B.kmph
Explanation: Speed downstream = 40 + 20 = 60 kmph
Speed upstream = 40 - 20 = 20 kmph
Answer:B
Question: The first flight out of Phoenix airport had a late departure. If the next three flights departed on-time, how many subsequent flights need to depart from Phoenix on-time, for the airport's on-time departure rate to be higher than 80%?
I will see what is the quickest way to solve it then I will provide the explanation
A.6
B.7
C.9
D.10
Answer: A.6
Explanation: The following approach might be the easiest one and less error prone.
We need on-time departure rate to be higher than 8/10, so it should be at least 9/11, which means that 9 out of 11 flights must depart on time. Since for now 3 out of 4 flights departed on time then 9-3=6 subsequent flights need to depart on-time.
Answer: A
Question: The average monthly income of A and B is Rs. 5050. The average monthly income of B and C is Rs. 6250 and the average monthly income of A and C is Rs. 5200. What is the monthly income of A?
A.2000
B.4000
C.5000
D.1000
Answer: B.4000
Explanation: Let monthly income A = a
monthly income of B = b
monthly income C= c
a+b=2*5050 --- 1
b+c=2*6250----2
a+c=2*5200----3
add 3 eqns
a=4000
monthly income of A = 4000
ANSWER B
Question: Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?
A.1/8
B.1/3
C.1/9
D.1/2
Answer: B.1/3
Explanation: 1/10 + 1/15 = 1/6 * 4 = 2/3
1 - 2/3 = 1/3
1/10 + 1/15 - 1/x = 1/3
x = 8
Answer:B
Question: Tina’s cat weighs 2.6 kilograms. Her dog weighs 4 times as much as her cat. How much does her dog weigh in kilograms?
A.10.4kg
B.38kg
C.22kg
D.48kg
Answer: A.10.4kg
Explanation: 2.6*4=10.4kg.Answer is A.
Question: Which of the following numbers is the biggest => [-4/7 , -7/8 , -9/10 , -12/13 , -34/35]
A.A)-4/7
B.B)-7/8
C.C)-9/10
D.D)-12/13
Answer: A.A)-4/7
Explanation: If we observe all the fractions just differ by one i.e denominator vs numerate.. in such case the biggest will be with large values... here all values are with -ve value...the least value is biggest. i.e. -4/7..
Hence A is correct answer...
Question: 3 pumps, working 8 hours a day, can empty a tank in 2 days . how many hours a day must 4 pumps work to empty the tank in 1 day?
A.9
B.10
C.11
D.12
Answer: D.12
Explanation: the required number of working hours per day x, more pumps , less working hours per day(indirect)
less days , more working hours per day (indirect)
pumps 4:3, days 1:2 } :: 8:x
therefore 4*1*x= 3*2*8, x= (3*2*8)/4
x=12
correct answer(D)
Question: If the average (arithmetic mean) of x, x + 2, and x + 4 is 103, what is the value of x?
A.95
B.97
C.101
D.85
Answer: C.101
Explanation: AM of x, x + 2, and x + 4 = x + (x + 2) + (x + 4) / 3 = 3x + 6 /3 = x + 2
Given that x + 2 = 103
x = 101
Answer : C
Question: If there is an equal probability of a child being born a boy or a girl, what is the probability that a couple who have 6 children have two children of the same sex and one of the opposite sex?
A.1/3
B.2/3
C.1/4
D.3/16
Answer: D.3/16
Explanation: No of ways of selecting a gender - 2C1
No of ways of selecting any 2 children out of 6 = 6C2
Total possible outcomes - 2^6 (each child can be either a girl or a boy)
Probability=2C1*6C2/2^6= 2*6/2*2*2*2*2*2=12/64=3/16
Ans=D
Question: Twelve identical machines, running continuously at the same constant rate, take 9 days to complete a shipment. How many additional machines, each running at the same constant rate, would be needed to reduce the time required to complete a shipment by three days?
A.2
B.3
C.4
D.6
Answer: D.6
Explanation: From the question you know that 12R = 1/9. The question asks you (partially) to make the rate from 1/9 to 1/6 (drop from 9 day to 6). So the only thing that you need to do is to find the magic number than can convert 1/9 to 1/6.
So 1/9 * x = 1/6 (1 equation with one unknown). So by solving this you get x = 9/6 or 3/2. Thats it then! Take the magic number 4/3 and multiply BOTH sides of the original equation and you have:
12*(3/2)*R = (3/2) * 1/9
6 * 3 * R = 1/6, Hence 18R = 1/6, therefore 6 more machines!
D
Question: The security gate at a storage facility requires a five-digit lock code. If the lock code must consist only of digits from 1 through 6, inclusive, with no repeated digits, and the first and last digits of the code must be even, how many lock codes are possible?
A.144
B.240
C.360
D.720
Answer: A.144
Explanation: X-X-X-X-X --> there are 3 even digits from 1 to 6, inclusive thus options for the first and the last X's are: 3-X-X-X-2. Other X's can take following values: 3-4-3-2-2 --> 3*4*3*2*2=144..
Answer: A.
Question: It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
A.Sunday
B.Saturday
C.Friday
D.Wednesday
Answer: C.Friday
Explanation: EXPLANATION
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Answer C
Question: Consider the word ROTOR. Whichever way you read it, from left to right or from right to left, you get the same word. Such a word is known as palindrome. Find the maximum possible number of 5-letter palindromes?
A.56678
B.16789
C.17576
D.35142
Answer: C.17576
Explanation: Explanation :
The first letter from the right can be chosen in 26 ways because there are 26 alphabets.Having chosen this, the second letter can be chosen in 26 ways.=> The first two letters can be chosen in 26*26=676 waysHaving chosen the first two letters, the third letter can be chosen in 26 ways.=> All the three letters can be chosen in 676*26=17576 ways.It implies that the maximum possible number of five letter palindromes is 17576 because the fourth letter is the same as the second letter and the fifth letter is the same as the first letter.
Answer : C
Question: There are cats got together and decided to kill the mice of 999984. Each cat kills equal number of mice and each cat kills more number of mice than cats there were. Then what are the number of cats?
A.941,1009
B.991,1001
C.996,1004
D.791,1009
Answer: C.996,1004
Explanation: 999984 can be written as 1000000 â€“ 16
= 10002 â€“ 42 ie of the form a2-b2=(a+b)(a-b)
=(1000+4)*(1000-4)
= (1004)*(996)
Given that number of cats is less than number if mice.
So number of cats is 996 and number of mice were 1004
Answer C
Question: A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 45 kmph. When and at what distance from Mumbai do the two trains meet?
A.287
B.279
C.270
D.278
Answer: C.270
Explanation: When the second train leaves Mumbai the first train covers 40 * 1 = 40 km
So, the distance between first train and second train is 40 km at 10.00am
Time taken by the trains to meet
= Distance / relative speed = 40 / (45 -40) = 8 hours
So, the two trains meet at 6 p.m. The two trains meet 6 * 45 = 270 km away from Mumbai.
Answer:C
Question: A can do a piece of work in 4 days. B can do it in 8 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?
A.87 days
B.20 days
C.8 days
D.19 days
Answer: C.8 days
Explanation: C = 1/2 - 1/4 - 1/8 = 1/8
=> 8 days
Answer:C
Question: A soccer team plays games only against the other five teams in its league and always in the following order: Gary, Howard, Robin, Fred and Jackie. If the team’s final game of the season is against Fred, which of the following could be the number of games in the team’s schedule?
A.24
B.66
C.56
D.72
Answer: A.24
Explanation: IMO 'A' is the answer.
Matches will be in multiples of 5x+4. The answer that satisfies this condition is A
Question: The standard serial numbers for medical licence are 3 letters followed by 5 digits. How many different medical licenses are possible if letters and digits can be repeated?
A.26 × × 3 × 5
B.26³ × 10 000
C.26³ x 100 000
D.26 × 25 × 24 × 10 × 9 × 8 × 7
Answer: C.26³ x 100 000
Explanation: OFFICIAL SOLUTION:
(C) The formula for permutations of events is the product of the number of ways each event can occur. There are 26 letters and 10 digits. So there are 26 × 26 × 26 options for the three letters, and 10 × 10 × 10 × 10 x 10 for the five digits. The number of different Medical license is 26 × 26 × 26 × 10 × 10 × 10 × 10 x 10= 26³ × 100 000.
The correct answer is choice (C).
Question: Speed of a boat in standing water is 16 kmph and the speed of the stream is 2 kmph. A man rows to a place at a distance of 7740 km and comes back to the starting point. The total time taken by him is:
A.914.2 hours
B.900 hours
C.915 hours
D.982.9 hours
Answer: D.982.9 hours
Explanation: Explanation:
Speed downstream = (16 + 2) = 18 kmph
Speed upstream = (16 - 2) = 14 kmph
Total time taken = 7740/18 + 7740/14 = 430 + 552.9 = 982.9 hours
Answer: Option D
Question: The average of 10 numbers was calculated as 18. It is discovered later on that while calculating the average, one number, namely 66, was incorrectly read as 26. What is the correct average?
A.20
B.21
C.22
D.23
Answer: C.22
Explanation: 10*18 - 26 + 66 = 220
220 / 10 = 22
The answer is C.
Question: How many positive integers less than 90 are multiples of 6 but NOT multiples of 9?
A.4
B.6
C.8
D.10
Answer: D.10
Explanation: The LCM of 6 and 9 is 18.
If x <90 and x is divisible by 6 not by 9 --> x is NOT divisible by 18.
From 1--> 90, we have 5 numbers which is divisible by 18: 18, 36, 54, 72, 90.
From 1-->90, we have (90-6)/6 +1 = 15 numbers divisible by 6.
Therefore, our answer is 15-5 = 10 numbers.
D
Question: If |z|/w = 4,which of the following must be true?
A.z = -4w
B.z = 4w
C.z^2 = 16w^2
D.z^2 = 16w^3
Answer: C.z^2 = 16w^2
Explanation: |z|/w = 4.
|z| = 4w.
Then z = 4w or -4w and so z^2 = 16w^2.
The answer is C.
Question: A total of 50 percent of the geese included in a certain migration study were male. If some of the geese migrated during the study and 20 percent of the migrating geese were male, what was the ratio of the migration rate for the male geese to the migration rate for the female geese? [Migration rate for geese of a certain sex = (number of geese of that sex migrating) / (total number of geese of that sex)]
A.1/4
B.7/12
C.2/3
D.7/8
Answer: A.1/4
Explanation: Let' take the Number of geese to be 100.
Male = 50. Female = 50.
Now the second part of the Q, Let's take the Number migrated to be 20.
So we have 20 geese that migrated and out of that 20% are male i.e 20/100 *20 = 4 Geese (Males)
And now we know out of the total 20 geese , 4 are male , then 16 have to be female.
Now the ratio part , Male Geese Ratios = 4/50 = 2/25. - A
Female Geese Ratios =16/50=8/25 - B
Cross Multiply Equations A and B and you get =1/4 .
Ans A
Question: 2 hours after train A leaves Lucknow a train B leaves the same stationtraveling in the same direction at an average speed of 32 km/hr. After traveling 6 hrsthe train B overtakes the train A. What is the average speed of the train A?
A.15 km/hr
B.24 km/hr
C.17 km/hr
D.18.75 km/hr
Answer: B.24 km/hr
Explanation: Explanation :
Total distance covered by B=32*6=192kmTotal time taken by A to cover same distance=2+6=8 hrsaverage speed of A=192/8=24 km/hr
Answer : B
Question: A train 1000 m long can cross an electric pole in 200 sec and then find the speed of the train?
A.12
B.14
C.16
D.18
Answer: D.18
Explanation: Length = Speed * time
Speed = L/T
S = 1000/200
S = 5 M/Sec
Speed= 5*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 18 Kmph
Answer:D
Question: For all integers a and b, a%b = (a + b)(a - b). If 4%x = 12, then which of the following could be a value of x?
A.-4
B.-3
C.2
D.3
Answer: C.2
Explanation: 4%x = (4+x)(4-x)
16-x^2 = 12
x^2 = 4
x=-2,2
Ans: C
Question: A man is 24 years older than his son. In three years, his age will be twice the age of his son. The present age of the son is
A.14 years
B.18 years
C.20 years
D.21 years
Answer: D.21 years
Explanation: Solution
Let the son's present age be x years .Then, man's present age	= (x+24)years.
Then	â€¹=â€º(x+24)+3= 2(x+3)
â€¹=â€ºx+27=2x+6
x= 21.
Answer D
Question: Kiran has 85 currency notes in all, some of which were of Rs. 100 denomination and the remaining of Rs. 50 denomination. The total amount of all these currency notes was Rs.5000. How much amount did she have in the denomination of Rs. 50?
A.1900
B.3500
C.4000
D.4200
Answer: B.3500
Explanation: Let the number of 50 – rupee notes be x.
Then, the number of 100-rupee notes = (85 – x)
50x + 100(85 – x) = 5000
= x + 2 (85 – x) = 100
= x =70
So, required amount = Rs. (50 x 70) = Rs. 3500
Answer: Option B
Question: A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 6000. With the help of C, they completed the work in 3 days. How much is to be paid to C?
A.s. 375
B.s. 400
C.s. 600
D.s. 750
Answer: D.s. 750
Explanation: C's 1 day's work = 1/3 - (1/6 + 1/8) = 1/3 - 7/24 = 1/24
A's wages : B's wages : C's wages = 1/6 : 1/8 : 1/24 = 4: 3 : 1
C's share (for 3 days) = Rs.	(3 * 1/24 * 6000) =Rs.750
Answer = D
Question: The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/8 of the area of the field. What is the length of the field?
A.29
B.32
C.19
D.77
Answer: B.32
Explanation: A/8 = 8 * 8 => A = 8 * 8 * 8
x * 2x = 8 * 8 * 8
x = 16 => 2x = 32
Answer:B
Question: If a two-digit positive integer has its digits reversed, the resulting integer differs from the original by 18. By how much do the two digits differ?
A. 2
B. 4
C. 5
D. 6
Answer: A. 2
Explanation: Given that (10a + b) - (10b + a) = 18 --> 9a - 9b =18 --> a - b = 2.
Answer: A.
Question: In a certain pond, 40 fish were caught, tagged, and returned to the pond. A few days later, 40 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what`s the approximate number of fish in the pond?
A.400
B.800
C.1250
D.2500
Answer: B.800
Explanation: The percent of tagged fish in the second catch is 2/40*100 = 5%.
We are told that 5% approximates the percent of tagged fish in the pond. Since there are 40 tagged fish, then we have 0.05x = 40 --> x = 800.
Answer: B.
Question: Ravi purchased a refrigerator and a mobile phone for Rs. 15000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 3 percent and the mobile phone at a profit of 10 percent. Overall he make a.
A.228
B.350
C.27
D.200
Answer: B.350
Explanation: Let the SP of the refrigerator and the mobile phone be Rs. r and Rs. m respectively.
r = 15000(1 - 3/100) = 15000 - 450
m = 8000(1 + 10/100) = 8000 + 800
Total SP - Total CP = r + m - (15000 + 8000) = -450 + 800 = Rs. 350
As this is positive, an overall profit of Rs. 350 was made.Answer:B
Question: At a casino in Mumbai, there are 3 tables A, B and C. The payoffs at A is 10 : 1, at B is 20 : 1 and C is 30 :1. If a man bets Rs. 200 at each table and win at two of the tables, what is the maximum and minimum difference between his earnings can be ?
A.Rs. 4000
B.Rs. 4500
C.Rs. 2500
D.Rs. 2000
Answer: A.Rs. 4000
Explanation: Solution: Maximum earning will be only possible when he will won on the maximum yielding table.
A → 10 :1
B → 20 :1
C → 30 :1
i.e., he won B and C but lost on A,
20 *200 +30 *200 - 1 *200 = 9800
Minimum earnings will be when he won on table A and B and lose on table 3.
10 *200 + 20 *200 - 1 *200 = 5800
Therefore, difference = 9800-5800 = Rs. 4000.
Alternatively,
The difference,
= [(30 +20 -1) - (10 +20 -1)] * 200
= Rs. 4000.
Answer: Option A
Question: Can you find the smallest non fractional number such that
If the number gets divided by 3 , we get the remainder of 1;
If the number gets divided by 4 , we get the remainder of 2
If the number gets divided by 5 , we get the remainder of 3;
If the number gets divided by 6 , we get the remainder of 4.
A.55
B.60
C.58
D.44
Answer: C.58
Explanation: C
58.
As we know LCM of the numbers 3 4 5 & 6 is 60.
So if i divide 60 by any of the four number , it gives remainder as 0.
Now to get reminder as desired, is should be 2 short of 60. (3-1,4-2,5-3,6-4 )
Question: A car is traveling 45 kilometers per hour. How many meters does the car travel in one minute?
A.750 meters / minute
B.850 meters / minute
C.950 meters / minute
D.550 meters / minute
Answer: A.750 meters / minute
Explanation: Convert hour into minutes ( 1 hour = 60 minutes) and kilometers into meters (1 km = 1000 m) and simplify
45 kilometers per hour = 45 km/hr
= (45 * 1000 meters) / (60 minutes) = 750 meters / minute
correct answer A
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
A.140 sq.units
B.176 sq.units
C.178 sq.units
D.189 sq.units
Answer: A.140 sq.units
Explanation: Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10 = 140 sq.units
Answer:A
Question: Find the number of ways of arranging the letters of the word "MATERIAL" such that all the vowels in the word are to come together?
A.1887 ways
B.1440 ways
C.1657 ways
D.1652 ways
Answer: B.1440 ways
Explanation: In the word, "MATERIAL" there are three vowels A, I, E.
If all the vowels are together, the arrangement is MTRL'AAEI'.
Consider AAEI as one unit. The arrangement is as follows.
M T R L A A E I
The above 5 items can be arranged in 5! ways and AAEI can be arranged among themselves in 4!/2! ways.
Number of required ways of arranging the above letters = 5! * 4!/2!
= (120 * 24)/2
=1440 ways.
Answer:B
Question: A worker can load one truck in 5 hours. A second worker can load the same truck in 4 hours. If both workers load one truck simultaneously while maintaining their constant rates, approximately how long, in hours, will it take them to fill one truck?
A.1.8
B.2.0
C.2.2
D.2.4
Answer: C.2.2
Explanation: The workers fill the truck at a rate of 1/5 + 1/4 = 9/20 of the truck per hour.
Then the time to fill one truck is 20/9 which is about 2.2 hours.
The answer is C.
Question: Two persons A and B take a field on rent. A puts on it 21 horses for 3 months and 15 cows for 2 months; B puts 15 cows for 6months and 40 sheep for 7 1/2 months. If one day, 3 horses eat as much as 5 cows and 6 cows as much as 10 sheep, what part of the rent should A pay?
A.1/3
B.1/7
C.1/4
D.1/2
Answer: A.1/3
Explanation: 3h = 5c
6c = 10s
A = 21h*3 + 15c*2
= 63h + 30c
= 105c + 30c = 135c
B = 15c*6 + 40s*7 1/2
= 90c + 300s
= 90c + 180c = 270c
A:B = 135:270
27:52
A = 27/79 = 1/3
Answer: a
Question: The arithmetic mean of the set S = {5, K, 4, 10, M, 5} is 6. If K and M are integers, and K ≠ M, what is the median of the numbers in the set?
A.4
B.4.5
C.5
D.5.5
Answer: C.5
Explanation: The sum of the numbers is 6*6 = 36
K+M = 36 - 10 - 5 - 5 - 4 = 12
Since K ≠ M, K and M do not equal 6.
Thus one of the two numbers is 5 or less and one is 7 or more.
Then middle two numbers in the set are 5 and 5.
The median is 5.
The answer is C.
Question: An ice cream store received shipments of ingredients on Tuesday and Wednesday. Tuesday's shipment had 6 different packages, with an average (arithmetic mean) of 11 and 2/3 pounds. Wednesday's shipment included 14 packages, weighing an average of 9 and 3/7 pounds. What was the average package weight, in pounds, of the shipments received on both days?
A.9 and 6/7 pounds
B.10 and 1/10 pounds
C.10 and 2/5 pounds
D.11 pounds
Answer: B.10 and 1/10 pounds
Explanation: Solution: Average weight = Total weight/number of packages. The total weight on Tuesday was 6 * (11 and 2/3 pounds), or 70 pounds. The total weight on Wednesday was 14 * (9 and 3/7 pounds), or 132 pounds. The sum of the weights for both days is 132 + 70, or 202 pounds. The average is 202 pounds/20 packages, or 10 and 1/10 pounds per package.
Correct answer: B
Question: Six computers, each working at the same constant rate, together can process a certain amount of data in 6 days. How many additional computers, each working at the same constant rate, will be needed to process the same amount of data in 4 days?
A.3
B.5
C.6
D.9
Answer: A.3
Explanation: Explanation: If six computers require 6 days to process the data, thats
a total of 36 computer-days the product of 6 and 6. If you change the number
of computers or the number of days, 36 will have to remain the product, whether
that means 36 days of one computer or one day with 36 computers.
In 4 days, the number of computers is:
4c = 36
c = 9
9 computers is 3 more than the 6 that it took to do the job in 6 days, so
the correct choice is (A).