RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In three years, Janice will be three times as old as her daughter. Six years ago, her age was her daughter’s age squared. What would be the age of Janice Daughter after 3 years
A.18
B.36
C.40
D.42
Answer: A.18
Explanation: Let Jane's age be J and daughters' age be D...
Given J + 3 = 3(D + 3 ) => J - 6 = 3D -> Eq1.
Given J-6 = (D-6)^2 --> Eq 2..
sub J-6 value in eq 2... 3D = D^2 - 12D + 36.
0 = D^2 - 15D + 36 => D = 12 or D = 3.
When D = 12 we get from eq 1... J+3 = 45 => J =42..
When D = 3 ..we get from eq 1.. J+3 = 18 => J = 15...
IMO option A is correct answer..
Question: Given that x and y are nonnegative integers, compute the number of pairs (x; y) such that
5x + y = 20.
A.1
B.5
C.10
D.15
Answer: B.5
Explanation: For x = 0,1,2,3,4, there is a valid y, giving the answer 5 .
correct answer B
Question: If the speed of the boat in still water is 12km/hr and the speed of the stream is 5km/hr. Find the time taken to travel 34kms down stream.
A.4 hrs.
B.1 hrs.
C.3 hrs.
D.2 hrs.
Answer: D.2 hrs.
Explanation: DS =speed of the boat + speed of the stream 5+12 =17km/hr. Time taken to cover 34km down stream =34/17 =2hrs. Answer : D
Question: The sum of 5 hours 45 minutes and 55 minutes is approximately what percent of a day?
A. approx 27%
B. 16%
C. 24%
D. approx 18%
Answer: A. approx 27%
Explanation: Since the question is asking for an approximate percentage
5:45 + 0:45 ~ 6:30 hours
% of day = 6.5*100/24 = 7*100/24 ~ 27%
Answer is A.
If you had 27 and 29 as options you would probably need to do more accurate calculations. In this particular case while approximating values we increase both numerator and denominator so our calculations should be close
Question: Before being simplified, the instructions for computing income tax in country R were to add 5 percent of one's annual income to the average(arithmetic mean) of 100 units of Country R's currency and 1 percent of one's annual income. Which of the following represents the simplified formula for computing the income tax, in country R's currency, for a person in that country whose annual income is I?
A.50 + I/200
B.50 + 3I/100
C.50+ 11I/200
D.100+ I/50
Answer: C.50+ 11I/200
Explanation: Income of a person is I
5 percent of ones annual income = 5I/100
100 units of Country R's currency = 100
1 percent of one's annual income = I/100
Average of 100 units and 1 percent annual income = 50 + I/200
Sum of average and 5 percent = 5I/100 + 50 + I/200
= 50 + 11I/200
So answer is C.
Question: sale of Rs 6835, Rs. 9927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6500 ?
A.4966
B.2477
C.2877
D.2676
Answer: A.4966
Explanation: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6500 x 6) - 34009]
= Rs. (39000 - 34009)
= Rs. 4966
Answer: A
Question: The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field ?
A.18 meter
B.20 meter
C.22 meter
D.25 meter
Answer: B.20 meter
Explanation: Explanation:
Let breadth =x metres.
Then length =(115x/100)metres.
=x∗115x/100=460
x2=(460x100/115)x2=400x=20
ANSWER IS B
Question: A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 30 hrs and a machine of type S does the same job in 15 hours. If the company used the same number of each type of machine to do the job in 2 hours, how many machines of type R were used?
A.A)3
B.B)4
C.C)5
D.D)9
Answer: C.C)5
Explanation: Rate of machine R =1/30
Rate of machine S =1/15
since same no of machines used for R and S to do the same work in 2 hrs
So collective rate needed to finish the work in 2 hrs= 1/2
Let the no of machine be x
So, x/30 +x/15 =1/2
x3/30=1/2
x=30/6=5
So no of machine R is 5
Answer C
Question: x percent of y percent of z is decreased by y percent What is the result?
A.(100xyz - xy^z2) / 1,000,000
B.(xz - y) / 100
C.(xz - y) / 10,000
D.(xyz - 2y) / 100
Answer: A.(100xyz - xy^z2) / 1,000,000
Explanation: We're told that X percent of Y percent of Z is DECREASED by Y percent. We're asked for the result of all of this math.
IF....
X = 10
Y = 50
Z = 100
First, 50% of 100 = 50
Next, 10% of 50 = 5
Finally, 5 decreased by 50% of itself is 2.5
So we're looking for an answer that equals 2.5 when X=10, Y=50 and Z=100.
Answer A. (100xyz - xy^2z) / 1,000,000 = (5,000,000 - 2,500,000)/1,000,000 = 2,500,000/1,000,000 = 2.5 This is a MATCH
A
Question: How much time will take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
A.7
B.4
C.5
D.3
Answer: B.4
Explanation: Time = (100 * 81) / (450 * 4.5) = 4 years'
Answer:B
Question: Working individually, Jane can bake cakes for 4 hours and Roy can bake cakes in 5 hours. If Jane and Roy work together but independently at the task for 2 hours, at which point Roy leaves, how many remaining hours will it take Jane to complete the task alone?
A.1/2
B.2/5
C.3/4
D.1/4
Answer: B.2/5
Explanation: In first 2 hrs Roy will finish 2/5 = 2/5 of work and Jane will finish 2/4 work so total 2/5 + 1/2 = 9/10 work is finished and 1-9/10 = 1/10 work remaining. Now Jane will take (1/10)*4 = 2/5 hrs to finish it.
So answer is B.
Question: A Caterpillar crawls a distance with speed of 21inches/min in the one direction and after feeding moves back in the same direction with 7inches/min and what is the average speed of it?
A.11.5 inch/ min
B.10.5 inch/ min
C.12.5 inch/ min
D.13.5 inch/ min
Answer: B.10.5 inch/ min
Explanation: average speed = 2*21*7/(21+7) = 2*21*7/28 = 21/2 = 10.5 inch/ min
ANSWER:B
Question: The remainder obtained when a prime number greater than 8 is divided by 8 is
A.a) 1 or 3
B.b) 1 or 5
C.c) 3 or 5
D.d) 4 or 5
Answer: C.c) 3 or 5
Explanation: The easiest way to answer this question is probably to pick numbers. Use the next two prime numbers greater than 8, i.e. 13 and 11:
13/8 = 1 + remainder of 5
11 / 8 = 1 + remainder of 3
This is already sufficient to see that answer choice b) is correct.
C
Question: After working for 6 days, Ashok finds that only 1/3 rd of the work has been done. He employs Ravi who is 60% as efficient as Ashok. How many days more would Ravi take to complete the work?
A.20 days
B.24 days
C.27 days
D.21 days
Answer: A.20 days
Explanation: A
20 days
1/3 ---- 6
1 -------? A = 18
R = 1/18 * 60/100 = 1/30
1 ----- 1/30
2/3 ----? => 20 days
Question: 70,76, 74,85,90,105,105,130,130,130
The list consists of the times in seconds that it took each of the 10 school children to run a distance of 400 mts . If the standard deviation of the 10 running times is 22.4, rounded to the nearest tenth of a second, how many of the 10 running times are more than 1 standard deviation below the mean of the 10 running times.
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: How many of the 10 running times are more than one SD below the meanmeans how many data points from given 10 are less thanmean-1SD.
We are given that SD=22.4, so we should find mean --> mean=100 --> there are only 3 data points below 100-22.4=77.6, namely 70 75, and 74.
Answer: C.
Question: A student is ranked 6th from right and 5th from left. How many students are there in totality ?
A.10
B.19
C.20
D.21
Answer: A.10
Explanation: From right 6 , From left 5
Total = 6+5-1 = 10
ANSWER:A
Question: The diagonals of a rhombus are 17 cm and 20 cm. Find its area?
A.176
B.186
C.150
D.170
Answer: D.170
Explanation: 1/2 * 17 * 20
= 170
Answer:D
Question: (1^3 + 2^3 + 3^3 + ... + 10^3) = x?
A.360
B.380
C.420
D.440
Answer: C.420
Explanation: We know that (1^3 + 2^3 + 3^3 + ... + n^3) =	1	2n(n + 1)
6
Putting n = 10, required sum = 1	x 10 x 10 x 21 = 2100/5
420
C
Question: Caleb spends $68.50 on 50 hamburgers for the marching band. If single burgers cost $1.00 each and double burgers cost $1.50 each, how many double burgers did he buy?
A.5
B.10
C.37
D.40
Answer: C.37
Explanation: Solution -
Lets say, Single hamburgersxand Double hamburgersy
Given that,
x+y=50 and 1x+1.5y=68.50. By solving the equations y=37. ANS C.
Question: how many five digit numbers are there such that two left most digits are even and remaining are odd and 4 digit should not be repeated.
A.950
B.960
C.970
D.980
Answer: B.960
Explanation: even numbers are 2,4,6,8 and odd 1,3,5,7,9
so choice for first 2 digit 4 and 4
and for last 3 digit 5 ,4 ,3 coz not repeated
so ans 4*4*5*4*3 = 960
ANSWER:B
Question: In a chess competition involving some men and women, every player needs to play exactly one game with every other player. It was found that in 45 games, both the players were women and in 190 games, both players were men. What is the number of games in which one person was a man and other person was a woman?
A.40
B.120
C.180
D.200
Answer: D.200
Explanation: This is similar to handshake problem, If there are NN people, then number of handshakes = 1+2+...N=N∗(N−1)/2
No. of Women be xx and given x∗(x−1)/2=45 This gives x=10
|||y No. of Men : solve y∗(y−1)/2=190. This gives y=20
so total Men vs. Women = 10*20 = 200. Answer is D
Question: How many numbers between 200 and 700 begin or end with 5?
A.20
B.60
C.140
D.110
Answer: C.140
Explanation: How many numbers between 200 and 700 begin or end with 5?
Just think that those numbers are:
i) The ones ending in 5: 205, 215, 225, ... , 695 --> 50 numbers
ii) The ones beginning in 3: 300, 301, 302, 303, ... , 393, ... , 399 --> 100 numbers
BUT 10 out of the first 50 numbers are repeated in the second set.
THEREFORE, the solution is 140 numbers.
Answer: C
Question: A new home buyer pays 4% annual interest on her first mortgage and 9% annual interest on her second mortgage. If she borrowed a total of $340,000, 80% of which was in the first mortgage, what is her approximate monthly interest payment?
A.$1,416
B.$1,733
C.$3,466
D.$13,333
Answer: A.$1,416
Explanation: 0.04x + 0.09y = 340000 [1]
0.04x = 0.80 * 340000 = 272000 [2]
272000 + 0.09y = 340000 --> 0.09y = 64000 [3]
272000 / 12 = 22666.67 [4]
64000 / 12 = 5666.67 [5]
Adding [4,5] we get: 28333.33 [6]
Dividing [6] / 2 to get an average we get 1.416,ANS A
Question: Gasoline varies in cost from $0.93 to $1.13 per gallon. If a car’s mileage varies from 16 to 24 miles per gallon, what is the difference between the most and least that the gasoline for a 480-mile trip will cost?
A.$15.13
B.$15.30
C.$15.72
D.$16.01
Answer: B.$15.30
Explanation: Solution:
We know that the per gallon cost of gasoline varies from $0.93 - $1.13.
Now we want to find the MAXIMUM difference between the least amount of money spent on gasoline and the largest amount of money spent i.e. to calculate max. trip cost - min. trip cost.
Mileage is given to be 16 to 24 miles per gallon, thus to travel 480 miles you will need gasoline in the range 480/24 to 480/16 which is 20 to 30 gallons.
So, for these 20 gallons and 30 gallons of gasoline the cost is as follows: (divide this task into 2 parts, 1 for 30 gallons and 2nd one for 20 gallons).
Case 1: for 30 gallons the cost is 30*0.93 to 30*1.13 which is $27.90 to $33.90
Case 2: for 20 gallons the cost is 20*0.93 to 20*1.13 which is $18.60 to $22.60
Thus, the maximum cost of the 480 mile trip is $33.90 and minimum is $18.60
so the difference is $33.90 - $18.60 = $15.30
Answer: B
Question: Ramesh purchased a refrigerator for Rs. 14500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 10% if no discount was offered?
A.34778
B.26888
C.20350
D.17600
Answer: C.20350
Explanation: Price at which the TV set is bought = Rs. 14,500
Discount offered = 20%
Marked Price = 12500 * 100/80 = Rs. 18125
The total amount spent on transport and installation = 125 + 250 = Rs. 375\Total price of TV set = 18125 + 375 = Rs. 18500
The price at which the TV should be sold to get a profit of 10% if no discount was offered = 18500 * 110/100
= Rs. 20350
Answer: C
Question: A man starts walking at 3 pm . ha walks at a speed of 4 km/hr on level ground and at a speed of 3 km/hr on uphill , 6 km/hr downhill and then 4 km/hr on level ground to reach home at 9 pm. What is the distance covered on one way
A.10km
B.12km
C.14km
D.16km
Answer: B.12km
Explanation: avg speed=2*3*6/(3+6)=4
so speed of man=4km/hr
distance=4*6=24km
since we want one way distance it will be
24/2 =12km
ANSWER:B
Question: If 3 people a,b,c can do a work simultaneously in 6 days. a and b can do work in 10 days. b and c can do work in 15 days. c and a can do the same work in 20 days.In how many days that a can complete the same work alone?
A.20
B.25
C.30
D.24
Answer: D.24
Explanation: a+b+c=1/6(one day work)
a+b=1/10;b+c=1/15;c+a+1/20
b=1/15-c;c=1/20-a;---------(2)
substitute equation 2 in a+b=1/10
a=1/10-b;a=1/10-1/15+c;
a=1/10-1/15+1/20-a;
2a=1/10-1/15+1/20;
a=1/24(one day work)
That is the no of days that a can work alone is 24 days
The option D is answer
Question: How many prime numbers exist between 200 and 220?
A.None
B.1
C.2
D.3
Answer: B.1
Explanation: All the even numbers goes out of the window.
201,207,213,219 - Sum of digits = 3 so divisible by 3
All the numbers ending with 5 is obviously not prime
ANSWER:B
Question: An airline passenger is planning a trip that involves three connecting flights that leave from airports A, B and C, respectively. The First flight leaves Airport A every Hour, beginning at 8:00 a.m., and arrives at Airport B 2nd a half hours later. The second flight leaves Airport B every 20minutes, beginning at 8:00a.m, and arrives at Airport C 1h 10 minutes later. The third flight leaves Airport C every hour, beginning at 8.45 a.m. What is the least total amount of time the passenger must spend between flights if all flights keep to their schedules?
A.25min
B.1hr 5min
C.1hr 15min
D.2hr 20min
Answer: B.1hr 5min
Explanation: Following way may not be a pure mathematical approach to solve it but it got me the result within a minute.
A: Flight leaves every hour; 8,9,10,11,12,1,2,3
B: Flight leaves every 20min; 8:20,8:40,9,9:20,9:40,10,10:20,10:40,11
C: Flight leaves every hour: 8:45,9:45,10:45,11:45,12:45
Passenger leaves at 8:00AM from A; reaches B@ 10:30am - he will catch 10:40am flight from B{10 minutes spent at airport B}; reaches c after 1hour10minutes @11:50AM;his next flight at C is at 12:45 - he waits another 55minutes;
Total wait = 10+55= 65 minutes = 1hour 5 mins
Ans:B
Question: Divide Rs.118000 among three persons A, B and C such that the ratio of the shares of A and B is 3:4 and that of B:C is 5:6?
A.A = 30000 B = 40000 C = 48000
B.A = 30000 B = 40000 C = 48030
C.A = 30000 B = 40070 C = 48000
D.A = 30000 B = 40000 C = 48300
Answer: A.A = 30000 B = 40000 C = 48000
Explanation: Compound ratio of A:B:C
A:B = 3:4
B:C = 5:6
----------
A:B:C = 15:20:24
We can divide Rs.118000 in this ratio.
Share of A = 15/59 * 118000 = 30000
Share of B = 20/59 * 118000 = 40000
Share of C = 24/59 * 118000 = 48000
Answer: A
Question: If 0 < x ≤ 2, then which one of the following is the maximum value of (x – 1)^2 + x ?
A.–2
B.–1
C.0
D.2
Answer: D.2
Explanation: If you cannot spot that the maximum value of (x – 1)^2 + x for 0 < x ≤ 2 is when x=2 --> (x – 1)^2 + x = 2 you can do the following:
Since 0 < x ≤ 2, then (x – 1)^2 + x is positive --> discard A, B and C.
For the same reason: (x – 1)^2 is a non-negative fraction less than 1.
Thus (x – 1)^2 + x = (non-negative fraction less than 1) + (0 < x ≤ 2) < 3. Discard E.
Only D is left.
Answer: D.
Question: A and B started business in partnership investing Rs. 20,000 and Rs. 15,000 respectively. After six months, C joined them with Rs. 20,000. What will be B's share in the total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business?
A.Rs.7500
B.Rs.7502
C.Rs.7529
D.Rs.7596
Answer: A.Rs.7500
Explanation: A:B:C = (20000 * 24) : (15000 * 24) : (20000 * 18)
= 4:3:3
B's share = 25000 * 3/10
= Rs.7500.
Answer:A
Question: How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
A.8 years
B.4 years
C.7 years
D.6 years
Answer: B.4 years
Explanation: Explanation:
Time = (100 x 81)/(450 x 4.5) years
= 4 years.
Answer: B
Question: You add x ml of a 25% alcohol solution to a 200 ml of a 10% alcohol solution to obtain another solution. Find the amount of alcohol in the final solution in terms of x. Find the ratio, in terms of x, of the alcohol in the final solution to the total amount of the solution. What do you think will happen if x is very large? Find x so that the final solution has a percentage of 15%.
A.100 ml
B.200 ml
C.300 ml
D.400 ml
Answer: A.100 ml
Explanation: Let us first find the amount of alcohol in the 10% solution of 200 ml.
200 * 10% = 20 ml
The amount of alcohol in the x ml of 25% solution is given by
25% x = 0.25 x
The total amount of alcohol in the final solution is given by
20 + 0.25 x
The ratio of alcohol in the final solution to the total amount of the solution is given by
[ ( 20 + 0.25 x ) / (x + 200)]
If x becomes very large in the above formula for the ratio, then the ratio becomes close to 0.25 or 25% (The above function is a rational function and 0.25 is its horizontal asymptote). This means that if you increase the amount x of the 25% solution, this will dominate and the final solution will be very close to a 25% solution.
To have a percentage of 15%, we need to have
[ ( 20 + 0.25 x ) / (x + 200)] = 15% = 0.15
Solve the above equation for x
20 + 0.25 x = 0.15 * (x + 200)
x = 100 ml
Answer A
Question: John has 10 pairs of matched socks. If he loses 3 individual socks, what is the greatest number of pairs of matched socks he can have left?
A. 7
B. 8
C. 5
D. 4
Answer: B. 8
Explanation: Because we have to maximize the pair of matched socks, we will remove 1 pairs(2 socks) out of 10 pairs 1 sock from the 2th pair.
Thus the no of matching socks pair remaining = 10 - 2 = 8
Answer B
Question: 16384, 8192, 2048, 256, 16, ?
A.0.3
B.9.0
C.0.5
D.1.0
Answer: C.0.5
Explanation: 16384
16384 ÷ 2 = 8192
8192 ÷ 4 = 2048
2048 ÷ 8 = 256
256 ÷ 16 = 16
16 ÷ 32 = 0.5
Answer is C
Question: An advertising agency finds that, of its 170 clients, 115 use Television, 110 use Radio and 130 use Magazines. Also, 85 use Television and Magazines, 75 use Television and Radio, 95 use Radio and Magazines. How many use all the three?
A.56
B.70
C.90
D.98
Answer: B.70
Explanation: Total=170
Television=115
Radio=110
Magazine=130
All the three =170-115-110-130+85+75+95=70
ANSWER B
Question: The average height of 50 pupils in a class is 150 cm. Five of them whose height is 146 cm, leave the class and five others whose average height is 156 cm, join. The new average height of the pupils of the class (in cm) is?
A.718 cm
B.151 cm
C.627 cm
D.282 cm
Answer: B.151 cm
Explanation: Total height = 150 * 50 = 7500 cm.
New average
= [7500 - 5 * 146 + 5 * 156 ] / 50 = 151 cm.
Answer:B
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
A.76 sec
B.67 sec
C.98 sec
D.36 sec
Answer: C.98 sec
Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 =36 sec.
Answer:C
Question: If p is an odd integer and q is an even integer, which of the following must be an odd integer?
A.2q+2p
B.3(2p-q)
C.p^2+q^2
D.p+q+3
Answer: C.p^2+q^2
Explanation: p is odd; for this assume p=1
q is even; for this assume q = 2
(2*1)+(2*2) = 6 Even
3((2*1)-2) = 0 Even
1^2+2^2 = 5 Odd
1+2+3 = 6 Even
(5*1)-(2*2)+1 = 2 Even
Answer:C
Question: Suresh borrowed some money at the rate of 6% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years. If the total interest paid by him at the end of 11 years is Rs.8160, how much money did he borrow?
A.Rs.8500
B.Rs.6000
C.Rs.8000
D.Rs.9000
Answer: C.Rs.8000
Explanation: using the formula S.I=P*T*R/100
(x*6*3/100)+(x*9*5/100)+(x*13*3/100)=8160
x=8000
i.e money borrowed is Rs.8000
ANSWER:C
Question: If xy not equal 0 and x^2*y^2 -xy = 12, which of the following could be y in terms of x?
I. 1/2x
II. -4/x
III. 3/x
A.II and III
B.II
C.III
D.IV
Answer: A.II and III
Explanation: x2y2 - xy = 12
x2y2-xy-12 = 0
(xy-3)(xy+4)=0
xy = 3 or xy=-4
y = 3/x or y = -4/x
II and III only
A
Question: A reduction of 20% in the price of salt enables a lady to obtain 10kgs more for Rs.300, find the original price per kg?
A.s.7.7
B.s.7.4
C.s.7.5
D.s.7.1
Answer: C.s.7.5
Explanation: 100*(20/100) = 20 --- 10
? --- 1 => Rs.2
300 --- 80
? --- 2 => Rs.7.5
Answer:C
Question: A bottle is 80% full. The liquid in the bottle consists of 60% guava juice and 40% pineapple juice. The remainder of the bottle is then filled with 70 lm of rum. How much guava is in the bottle?
A.155 ml
B.158 ml
C.165 ml
D.168 ml
Answer: C.165 ml
Explanation: if the Bottle is 100ml:
we have 48% Guava, 32% Pineapple, and 20% Rum.
Now, is the bottle 20% of rum is represented by 70 ml. So, we have to find for the same bottle 48% guava is what ml?
therefore, Guava= (70*48)/20= 168 ml
ANSWER:C
Question: Which of the following will divide evenly into 607,406,520?
A.13
B.21
C.11
D.3
Answer: D.3
Explanation: Rule:
3: Sum of the digits should be divisible by 3
Given number : 6+7+4+6+5+2 = 30
Answer : D
Question: Find the mode of the given set of number
2, 2, 3, 5, 4, 3, 2, 3, 3, 5
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: Arranging the number with same values together, we get
2, 2, 2, 3, 3, 3, 3, 4, 5, 5
We observe that 3 occurs maximum number of times, i.e., four.
Therefore, mode of this data is 3. ANSWER :C
Question: The cash difference between the selling prices of an article at a profit of 4% and 8% is Rs. 3. The ratio of the two selling prices is?
A.52:56
B.52:53
C.52:54
D.22:56
Answer: C.52:54
Explanation: Let C.P. of the article be Rs. x.
Then, required ratio = 104% of x / 108% of x
= 104/108 = 52/54 = 52:54
Answer: C
Question: What is the unit’s digit of 7^7
A.9
B.5
C.3
D.7
Answer: C.3
Explanation: 7^1=7
7^2=49
7^3=343
7^4=1(last digit)
7^5=7(last digit) and the cycle repeats after every 4 powers
Therefore, last digit of 7^7=3
Answer C
Question: Ravi and sunil are partners in a business. Ravi invests Rs.15,000 for 8 months and Sunil invested Rs.8000 for 10 months then after one year ratio of their profits will be
A.1:3
B.2:3
C.3:2
D.3:1
Answer: C.3:2
Explanation: =(15000*8):(8000*10)
=120000:80000
=3:2
ANSWER:C
Question: Three walls have wallpaper covering a combined area of 280 square meters. By overlapping the wallpaper to cover a wall with an area of 180 square meters, the area that is covered by exactly two layers of wallpaper is 36 square meters. What is the area that is covered with three layers of wallpaper?
A.5 Square Meters
B.32 Square Meters
C.42 Square Meters
D.83.3 Square Meters
Answer: B.32 Square Meters
Explanation: 280 - 180 = 100 sq m of the wallpaper overlaps (in either two layers or three layers)
If 36 sq m has two layers, 100 - 36 = 64 sq m of the wallpaper overlaps in three layers. 64 sq m makes two extra layers hence the area over which it makes two extra layers is 32 sq m.
Answer (B).
Question: Which number should replace both the asterisks in (* /20) x (*/180) = 1 ?
A.20
B.40
C.60
D.90
Answer: C.60
Explanation: Let (y/20) x (y/180) = 1
y^2 = 20 x 180 = 20 x 20 x 9
y = (20 x 3) = 60
The answer is C.
Question: A rectangular field has to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?
A.88 Feet
B.66 Feet
C.77 Feet
D.99 Feet
Answer: A.88 Feet
Explanation: A
88 Feet
Area of the field =680 sq. feet.
Length of the adjacent sides are
20 feet and 680/20=34 feet.
Required length of the fencing
=20+34+34=88 feet
Question: Which of the following equations represents a line that is perpendicular to y=1/2*x+1?
A.y−2x=8
B.2x+4y=10
C.3y+6x=12
D.4y−8x=16
Answer: A.y−2x=8
Explanation: For two lines to be perpendicular, the product of slopes should be equal to -1.
Slope of line 1 = 1/2
Slope of the line perpendicular to line 1 must be -2. Option C can be rewritten as y = -2x + 4 --> Slope = -2
Answer: A
Question: Find the circumference and area of radius 6 cm.
A.113 cm²
B.144 cm²
C.154 cm²
D.184 cm²
Answer: A.113 cm²
Explanation: Area of circle = πr²
= 22/7 × 6 × 6 cm²
= 113 cm²
ANSWER:A