RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A circular swimming pool is surrounded by a concrete wall 4ft wide. If the area of the concrete wall surrounding the pool is 11/25 that of the pool, then the radius of the pool is?
A.10ft
B.20ft
C.30ft
D.40ft
Answer: B.20ft
Explanation: Explanation:
let the radius of the pool be Rft
radius of the pool including the wall = (R+4)ft
area of the concrete wall = π[(R + 4)2 - R2] = π[(R + 4 + R)(R + 4 - R)] = 8π(R + 2) sq feet
⇒ 8π(R + 2) = 11/25πR2 ⇒ 11 R2 = 200(R + 2)
Radius of the pool R = 20ft Answer: B
Question: A certain musical scale has has 13 notes, each having a different frequency, measured in cycles per second. In the scale, the notes are ordered by increasing frequency, and the highest freq is twice the lowest. For each of the 12 lower freq , the ratio of a frequency to the next higher freq is a fixed constant. If the lowest freq is 440 cycles per second, then the freq of the 7th note in the scale is how many cycles/second?
A.440 * sqrt 2
B.440 *2
C.400 * sqrt 2
D.320 * sqrt 3
Answer: A.440 * sqrt 2
Explanation: let the constant be k
F1 = 440
F2 = 440k
F3 = 440 k * k = 440 * k^2
F13= 440 * k^12
we know F13 = 2 *F1 = 2 * 440 = 880
880/440 = k^12
k = twelfth root of 2
for F7...
F7 = 440 * k^6 ( as we wrote for F2 and F3)
F7 = 440 * (twelfth root of 2) ^ 6
F7 = 440 * sqrt (2)
Answer A
Question: How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.22
B.30
C.88
D.266
Answer: B.30
Explanation: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec.
Answer:B:
Question: Manoj borrowed Rs.3750 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
A.22877
B.5555
C.2778
D.6787
Answer: B.5555
Explanation: Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3750.3.6/100 = Rs.824.85
27P = 67500 = 82485
P = (82485 + 67500)/27 = 3055 + 2500 = Rs.5555
Answer: B
Question: Find avrg speed if a man travels at speed of 16km/hr up and 30km/hr dawn at an altitude of 200m.
A.22.8
B.21.8
C.20.8
D.28.8
Answer: C.20.8
Explanation: avg speed=2*x*y/(x+y)
=2*16*30/(16+30)=20.8
ANSWER:C
Question: Nine coins are tossed simultaneously. In how many of the outcomes will the third coin turn up a head?
A.2^9
B.2^10
C.2^8
D.3 * 2^9
Answer: C.2^8
Explanation: Fix the third coin as H. The remaining 8 coins have 2^8 outcomes.
Ans:C
Question: The vertex of a rectangle are (1, 0), (9, 0), (1, 4) and (9, 4) respectively. If line L passes through the origin and divided the rectangle into two identical quadrilaterals, what is the slope of line L?
A.4
B.2
C.1/4
D.2/5
Answer: D.2/5
Explanation: If line L divides the rectangle into two identical quadrilaterals, then it must pass through the center (5, 2). The slope of a line passing through (0,0) and (5, 2) is 2/5.
The answer is D.
Question: Find 103 ×× 10
A.106/19
B.108/12
C.108/19
D.108/15
Answer: D.108/15
Explanation: By taking 100 as a base we can easily get the answer for the above question within seconds.
103 is 3 more than 100 and 105 is 5 more than 100 So we will write
Add the excess of the second number to first number or excess of first number to second number as show below to get left most digits and multiply the excesses to get the right most two digits.
Note: Always remember if you get a single digit number put zero in the left two make it a two digit number to get the right most two digits.
Answer:D
Question: Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 12 cm.
A.335 cm2
B.228 cm2
C.285 cm2
D.825 cm2
Answer: B.228 cm2
Explanation: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (20 + 18) * (12)
= 228 cm2
Answer: B
Question: A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit?
A.2679
B.2976
C.2690
D.3000
Answer: D.3000
Explanation: A:B:C = 5:6:4
Let the total profit = 100 - 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 - 160/3 = 140/3
A-(B+C) = 160/3 - 140/3 = 20/3
20/3 ---- 200
100 ---- ? => 3000
Answer:D
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 880 grams per kg, what is his percent?
A.15%
B.13.6%
C.65%
D.45%
Answer: B.13.6%
Explanation: Explanation:
880 --- 120
100 --- ? => 13.6%
Answer: B
Question: There are 5 marbles in a bag - 2 are orange and 3 are blue. If two marbles are pulled from the bag, what is the probability T that at least one will be orange?
A.T=7/10
B.T=3/5
C.T=2/5
D.3/10
Answer: A.T=7/10
Explanation: Method 1
Probability that at least one out of two marbles will be orange = 1 - Probability that both marbles are blue = 1- P(First marble is blue)* P(Second Marble is Blue) = 1- (3/5)(2/4) = 7/10
Method 2
Probability that at least one marble will be orange = P( First Marble is Orange)*P(Second Marble is Blue) + P (First Marble is Blue)*P(Second Marble is Orange) + P(First Marble is Orange) *P(Second Marble is Orange) = (2/5)*(3/4)*2 + (2/5)*(1/4) = 7/10
Method 3
Probabilty that at least one marble will be orange = 1 - Probability that both marbles are blue
= 1 - (Number of ways 2 blue marbles out of 3 can be pulled)/(Number of ways 2 marbles out of 5 can be pulled)
= 1 - 3C2/5C2
= 1-(3/10) = 7/10
Answer :A
Question: Judy ate 20g of chocolate on Monday, and 30g of chocolate on Tuesday. How much chocolate on average did she eat on those two days?
A.50g
B.6g
C.600g
D.25g
Answer: D.25g
Explanation: (20g + 30g)/2 = 25g
The correct answer is D
Question: Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is?
A.65 days
B.16 days
C.15 days
D.19 days
Answer: B.16 days
Explanation: Ratio of times taken by Sakshi and Tanys = 125:100 = 5:4
Suppose Tanya takes x days to do the work.
5:4 :: 20:x => x= 16 days.
Hence, Tanya takes 16 days to complete the work.
Answer: B
Question: The incomes of two persons A and B are in the ratio 3:4. If each saves Rs.100 per month, the ratio of their expenditures is 1:4 . Find their incomes?
A.112.5, 158.5
B.180.5, 150
C.100, 200
D.112.5, 150
Answer: D.112.5, 150
Explanation: The incomes of A and B be 3P and 4P.
Expenditures = Income - Savings
(3P - 100) and (4P - 100)
The ratio of their expenditure = 1:4
(3P - 100):(4P - 100) = 1:4
8P = 300 => P = 37.5
Their incomes = 112.5, 150
ANSWER:D
Question: If Jake loses 15 pounds, he will weigh twice as much as his sister. Together they now weigh 132 pounds. What is Jake’s present weight, in pounds?
A.63
B.93
C.139
D.147
Answer: B.93
Explanation: Lets say J is the weight of Jack and S is the wt of his sister.
If he loses 15 pounds, he s twice as heavy as his sister.
J-15=2*S
Also, together they weight 132 pounds
J+S=132
solvong the 2 equation ,we get J=93 pounds !
B
Question: The average of the two-digit numbers, which remain the same when the digits interchange their positions, is?
A.22
B.89
C.55
D.38
Answer: C.55
Explanation: Average = (11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99)/9
= [(11 + 99) + (22 + 88) + (33 + 77) + (44 + 66) + 55]/9
= [(4 * 110) + 55]/9 = 495/9
= 55.
Answer:C
Question: Salaries of Ram and Sham are in the ratio of 4 : 5. If the salary of each is increased by Rs. 5000, then the new ratio becomes 50 : 60. What is Sham's present salary?
A.Rs. 20,000
B.Rs. 25,000
C.Rs. 30,000
D.Rs. 35,000
Answer: C.Rs. 30,000
Explanation: EXPLANATION:
Assume original salaries of Ram and Sham as 4x and 5x respectively.
Therefore,
(4x + 5000)/(5x +5000)	=	50 /60
60 (4x + 5000) = 50 (5x + 5000)
10 x = 50,000
5x = 25, 000
Sham's present salary = 5x + 5000 = 25,000 + 5000
Sham's present salary = Rs. 30,000
ANSWER IS C
Question: How many different positive integers exist between 10^5 and 10^6, the sum of whose digits is equal to 2?
A.6
B.7
C.5
D.8
Answer: A.6
Explanation: So, the numbers should be from 100,000 to 1,000,000
The following two cases are possible for the sum of the digits to be 2:
1. Two 1's and the rest are 0's:
100,001
100,010
100,100
101,000
110,000
5numbers.
2. One 2 and the rest are 0's:
200,000
1 number.
Total = 6 numbers.
Answer: A
Question: A present value of a machine is $128000. Its value depletiation rate is 25% per annum then find the machine value after 3 years?
A.$54000
B.$48000
C.$36520
D.$32450
Answer: A.$54000
Explanation: P= $128000
R = 25%
T = 3 years
Machine value after 3years = P/(1-R/100)^T
=128000*3/4 * 3/4 * 3/4
=$54000
Answer is A
Question: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
A.187.5 m
B.127.5 m
C.127.3 m
D.122.5 m
Answer: B.127.5 m
Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8
= 787.5 m.
In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C
= (600 * 212.5)/1000
= 127.5 m.
Answer:B
Question: A parking space have 10 different slots. 10 cars has to arrange in 8 slots. But there are exactly 4 cars between 6 specified cars. In how many ways cars can be arranged?
A.17280
B.65000
C.1500
D.1640
Answer: A.17280
Explanation: we arranged 2 specified cars in 4 slots = 4!
remaining 6 cars in 6 slots = 6!
number of ways = 4!*6! = 17280
correct option is A
Question: There are 10 women and 15 men in an office. In how many ways a team of a man and a woman can be selected?
A.55
B.25
C.150
D.28
Answer: C.150
Explanation: Number of ways in which a team of a man and a woman can be selected
= 15 × 10 = 150
Answer is C
Question: In what time will a railway train 60 m long moving at the rate of 72 kmph pass a telegraph post on its way?
A.8 sec
B.3 sec
C.2 sec
D.6 sec
Answer: B.3 sec
Explanation: T = 60/72 * 18/5
= 3 sec
Answer:B
Question: A retailer bought a machine at a wholesale price of $90 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price of the machine?
A.81
B.100
C.120
D.135
Answer: C.120
Explanation: My solution: Wholesale Price= 90
Retail Price, be = x
He provides 10 % discount on Retail price= x-10 x/100
This Retail price = 20 % profit on Wholesale price
x-10 x/100 = 90+ 1/5(90)
x=120;
ANSWER:C
Question: Last year Manfred received 26 paychecks. Each of his first 6 paychecks was $750; each of his remaining paychecks was $50 more than each of his first 6 paychecks. To the nearest dollar, what was the average (arithmetic mean) amount of his pay checks for the year?
A. $752
B. $755
C. $765
D. $788
Answer: D. $788
Explanation: = (750*6+ 800 *20)/26
= 788
Answer is D.
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Question: In the reading room of a library, there are 24 reading spots. Each reading spot consists of a round table with 9 chairs placed around it. There are some readers such that in each occupied reading spot there are different numbers of readers. If in all there are 36 readers, how many reading spots do not have even a single reader?
A.8
B.16
C.15
D.14
Answer: B.16
Explanation: 1+2+3+4+5+6+7+8 = 36
so, 8 spots are occupied by users
24-8 = 16,
ANSWER:B
Question: A rope of which a calf is tied is increased from 12 m to 23 m, how much additional grassy ground shall it graze?
A.2989
B.2789
C.1210
D.1288
Answer: C.1210
Explanation: π (232 – 122)
= 1210
Answer: C
Question: Mr. Wayne bungee jumps from the top of a building straight to the ground at a constant speed. 3 seconds after he starts plummeting he passes the 20th floor. 15 seconds after he starts plummeting he passes the 5th floor. Each floor is 3.4 meters high. What is Mr. Wayne's speed in meters per second?
A.3
B.3.75
C.4
D.4.25
Answer: D.4.25
Explanation: IMO: D
15 Floors * 3.4 Meter/Floor = 51 Meters
Time= 12 sec
Rate * 12 = 51
Rate= 51/12
=4.25
Answer D
Question: If there is exactly one root of the equation ax^2 + x + b, where a and b are positive constants, what is b in terms of a?
A.1/4a
B.a
C.3a/2
D.a^2/2
Answer: A.1/4a
Explanation: one root for a quadratic equation ax^2+bx+c is possible only when b^2 = 4ac ---1
Here
c= b
b = 1
substituting these values in 1, we have
1^2 = 4ab => b =1/4a
Answer is A.
Question: A shopkeeper sells 400 metres of cloth for Rs. 18000 at a loss of Rs.5 per metre. Find his cost price for one metre of cloth?
A.35
B.77
C.28
D.50
Answer: D.50
Explanation: Explanation:
SP per metre = 18000/400 = Rs. 45 Loss per metre = Rs. 5 CP per metre
= 45 + 5
= Rs. 50
Answer: D
Question: How many of the following numbers are divisible by 132 ? 264, 396, 462, 792, 968, 2178, 5184, 6336
A.4
B.3
C.6
D.8
Answer: A.4
Explanation: Explanation :
Here 3, 4 and 11 are pairwise co-prime numbers. 132 = 3 × 4 × 11 . Also 3,4 and 11 are
factors of 132. Hence
if a number is divisible by 3, 4 and 11, the number will be divisible by their product 132 also.
If a number is not divisible by 3 or 4 or 11, it is not divisible by 132
You must learn Divisibility Rules to say whether a given number is divisible by another number
without actually performing the division.
further.
264 is divisible by 3, 4 and 11 => 264 is divisible by 132
396 is divisible by 3, 4 and 11 => 396 is divisible by 132
462 is divisible by 3 and 11, but not divisible by 4 => 462 is not divisible by 132
792 is divisible by 3, 4 and 11 => 792 is divisible by 132
968 is divisible by 4 and 11, but not divisible by 3 => 968 is not divisible by 132
2178 is divisible by 3 and 11, but not divisible by 4 => 2178 is not divisible by 132
5184 is divisible by 3 and 4, but not divisible by 11 => 5184 is not divisible by 132
6336 is divisible by 3, 4 and 11 => 6336 is divisible by 132
Hence, only 264, 396 ,792 and 6336 are divisible by 132. So the answer is 4. Answer : Option A
Question: A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train in going?
A.5 sec
B.7 sec
C.6 sec
D.10 sec
Answer: C.6 sec
Explanation: speed of train relative to man=(60+6)km/hr=66 km/ hr.
(66*5/18)m/sec.
(55/3)m/sec.
Time taken to pass the man=(110*3/55)sec=6 sec.
Answer: C
Question: Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 2 scones must be equal to which of the following?
A.Y/20
B.200/Y
C.100Y/(15X)
D.XY/250
Answer: A.Y/20
Explanation: Rachel eats 4 scones/10 minutes = 2/5 scones per minute
The time for Rachel to eat 1 scone is 5/2 minutes.
The time for Rachel to eat Y scones is 5Y/2 minutes.
The time for Henry to eat X scones is 5YX/200 minutes.
The time for Henry to eat 1 scone is 5Y/200 minutes.
The time for Henry to eat 2 scones is 10Y/200 = Y/20 minutes.
The answer is A.
Question: In what ratio must water be mixed with milk costing Rs.12 per litre in order to get a mixture worth of
Rs.8 per litre?
A.1 : 3
B.2 : 2
C.1 : 2
D.3 : 1
Answer: C.1 : 2
Explanation: Explanation :
By the rule of alligation, we have
Cost Price of 1 litre of water Cost Price of 1 litre of milk
0 12
Mean Price
8
12-8=4 8-0=8
Required Ratio = 4 : 8 = 1 : 2
Answer : Option C
Question: A person took some amount with some interest for 3 years, but increase the interest for 1%, he paid Rs.120/- extra, then how much amount he took?
A.s.5500/-
B.s.6000/-
C.s.4000/-
D.s.7000/-
Answer: C.s.4000/-
Explanation: Explanation:
3 years = Rs.120/-
year = 120/3
Rate of Interest = 1%
100/1% × 120/3 = Rs.4000/-
P = Rs.4000/-
Answer: Option C
Question: If 60 percent of 500 is 50 percent of x, then x=?
A.600
B.620
C.650
D.700
Answer: A.600
Explanation: 0.6 * 500 = 0.5 * x
x = 6/5 * 500 = 600
Question: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?
A.9:1
B.4:7
C.7:1
D.2:5
Answer: A.9:1
Explanation: Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 - 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
ANSWER:A
Question: A tank contains 9,000 gallons of a solution that is 6 percent sodium chloride by volume. If 3,000 gallons of water evaporate from the tank, the remaining solution will be approximately what percent sodium chloride?
A. 6%
B. 7%
C. 8%
D. 9%
Answer: D. 9%
Explanation: We start with 9,000 gallons of a solution that is 6% sodium chloride by volume. This means that there are 0.06 x 9,000 = 54 gallons of sodium chloride.
When 3,000 gallons of water evaporate we are left with 6,000 gallons of solution. From here we can determine what percent of the 6,000 gallon solution is sodium chloride.
(sodium chloride/total solution) x 100 = ?
(540/6,000) x 100 = ?
9/100 x 100 = ?
= 9%
Answer is D.
Question: Rs 3600 is divided into two parts such that one part is put out at 3% and the other at 5%. If the annual interest earned from both the investments be Rs 144, find the first part.
A.s 4000
B.s 2800
C.s 1800
D.s 3500
Answer: C.s 1800
Explanation: Explanation :
Average rate = (144/3600)*100 = 4
Ratio = 1:1
So, first part = (1/2)*3600 = Rs 1800.
Answer : C
Question: Alex takes a loan of $8,000 to buy a used truck at the rate of 6 % simple Interest.Calculate the annual interest to be paid for the loan amount.
A.480
B.520
C.460
D.400
Answer: A.480
Explanation: From the details given in the problem Principle = P = $8,000 and R = 6% or 0.06 expressed as a decimal.
As the annual Interest is to be calculated, the time period T =1.
Plugging these values in the simple Interest formula,
I = P x T x R
= 8,000 x 1 x 0.06
= 480.00
Annual Interest to be paid = $480
answer :A
Question: On a track for remote controlled racing cars, racing car A completes the track in 57 seconds, while racing car B completes it in 35 seconds. If they both start at the same time after how many seconds will they be side by side again.
A.275
B.325
C.1995
D.425
Answer: C.1995
Explanation: Time required in seconds will be LCM ( 35, 57 ) = 1995
Hence, answer will be (C) 1995
Question: A train covers a distance of 54 km in 15 min. If it takes 8 sec to pass a telegraph post, then the length of the train is?
A.470
B.480
C.490
D.500
Answer: B.480
Explanation: Speed = (54/15 * 60) km/hr = (216 * 5/18) m/sec = 60 m/sec.
Length of the train = 60 * 8 = 480 m.
Answer: Option B
Question: Four friends built a colony for themselves. They built their own houses at different distances from each other.
Chris lived 60 km away from Alex.
Darren lived 40 km away from Bill.
Chris lived 10 km nearer to Darren than he lived to Bill.
Can you find out how far was Darren's house from Alex?
A.75 km
B.60 km
C.45 km
D.50 km
Answer: A.75 km
Explanation: A
75 km
Explanation:
Distance between Bill and Darren = 40 km
Distance between Bill and Chris + Distance between Chris and Darren = 40 km
Distance between Bill and Chris + (Distance between Bill and Chris - 10) = 40 km
2 * Distance between Bill and Chris = 50 km
Distance between Bill and Chris = 25
Distance between Chris and Darren = 15 km
Therefore, distance between Darren's house and Alex's house = 60 + 15 = 75 km.
Question: Today is Monday. After 61 days, it will be:
A.SUNDAY
B.SATURSDAY
C.FRIDAY
D.THURSDAY
Answer: B.SATURSDAY
Explanation: Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.
Answer: Option B
Question: Which of the numbers below is the odd one out
1,5,13,17,25,41,61.
A.17
B.13
C.5
D.25
Answer: A.17
Explanation: 17 is the odd man.. diff between sucessive no.s are multiples of 4
ANSWER:A
Question: Today Roseline, who is 50 years old, and her daughter, who is 20 years old, celebrate their birthdays. How many years will pass before Roseline’s age is twice her daughter’s age?
A.12
B.13
C.10
D.15
Answer: C.10
Explanation: Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.
After x years passes Roseline’s age will be (50+x) years old, and her daughter’s age will be (20+x) years old. Since the Roseline’s age is twice her daughter’s age (50+x)= 2 * (20+x) ---> 50+x=40+2x ---> x= 10
The answer is (C).
Question: A photo-mat shop charges $0.55 for the first photo inside a film, and 40% cents less for each additional photo. How many photos can we develop with $52.52 if each film contains 36 photos?
A.4 films and 10 photos
B.5 films and 6 photos
C.5 films and 14 photos
D.6 films and 4 photos
Answer: A.4 films and 10 photos
Explanation: 1st photo = 0.55
Subsequent = 0.55*0.6=0.33
Price of 1 full film=0.55+0.33*35=12.1
Price of 4 full film = 12.1*4=48.4
52.52-48.4=4.18
4.18=0.55+0.33x
x=11
52.58--->4 full films and 1+11=12 photos
Answer: A
Question: In a simultaneous throw of a pair of dice, find the probability of getting a total more than 7
A.1/2
B.7/12
C.5/13
D.5/12
Answer: D.5/12
Explanation: Total number of cases = 6*6 = 36
Favourable cases = [(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,4),(5,6),(5,3),(5,5),(6,2),(6,3),(6,4),(6,5),(6,6)] = 15
So Probability = 15/36 = 5/12
Answer is D
Question: A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. What is the selling price of the cycle?
A.Rs. 1090
B.Rs. 1160
C.Rs. 1190
D.Rs. 1202
Answer: C.Rs. 1190
Explanation: since,c.p=1400
loss%=(c.p-s.p)/c.p*100
15=(1400-s.p)/1400*100
so,after solving answer=1190.
ANSWER:C
Question: total dinning bill of 8 people was $139.00 and 10% tip divided the bill evenly ?what is the bill amount each person shared .
A.11.84
B.12.84
C.23.84
D.19.11
Answer: D.19.11
Explanation: dinner bill of 8 person = 139 + 10% tip
so,
10% of 139 = (139*10)/100 = 13.9
So, the actual total amount = 139+13.9 = $ 152.9
so per head bill = 152.9/8 = $ 19.11
ANSWER:D
Question: The number of arrangements that can be made with the letters of the word JOHNNIE so that the vowels occupy the even places?
A.A)122
B.B)134
C.C)144
D.D)156
Answer: C.C)144
Explanation: Explanation:
The word JOHNNIE has 7 letters of which 3 are vowels.
-V-V-V-
As the vowels have to occupy even places, they can be arranged in the 3 even places in 3! i.e., 6 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways.
Hence the total ways are 24 * 6 = 144.
C
Question: In what proportion must wheat at Rs. 15 per kg. be mixed with wheat at Rs. 18 per kg. So that the mixture will be worth Rs. 17 per kg. ?
A.1 : 9
B.1 : 3
C.1 : 2
D.1 : 1
Answer: C.1 : 2
Explanation: Explanation:
Wheat/Rs. 15 per kg.
Wheat/Rs. 18 per kg.
For the mixture to be worth Rs. 17 per kg. The ratio should be:
(18 – 17) : (17 – 15)
1 : 2
ANSWER:C
Question: What is the remainder of R=3^19 when divided by 10?
A.0
B.1
C.5
D.7
Answer: D.7
Explanation: I looked for patterns:
^2 - units digit 9
^3 - units digit 7
^4 - units digit 1
^5 - units digit 3
hence, we can see that when raised to a power which is multiple of 4, the units digit is 1, and when to an even power not multiple of 4, the units digit is 9
and we can then see:
^16 - units digit 1, or
^18 - units digit 9
and ^19 - units digit 7
therefore, R=when divided by 10, the remainder must be 7.D