RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The length of a rectangular hall is 5m more than its breadth. The area of the hall is 750 m. The length of the hall is?
A.22
B.25
C.27
D.19
Answer: B.25
Explanation: Let breadth = x m
Then, length = (x+5)m
x(x+5) = 750
x² + 5x - 750= 0
(x+30)(x-25)= 0
x = 25
Answer: B
Question: A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?
A.32:42
B.32:41
C.32:45
D.32:49
Answer: C.32:45
Explanation: A : B
(8000*4)+(4000*8) : (9000*6)+(6000*6)
64000 : 90000
32 : 45
Answer: C
Question: A sum of Rs.4500 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
A.Rs.2925
B.Rs.3120
C.Rs.3320
D.Rs.2760
Answer: A.Rs.2925
Explanation: Let A be the amount received at the end of the three years.
A = 4500[1 + 10/100][1 + 20/100][1 + 25/100]
A = (4500 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.7425
So the interest = 7425 - 4500 = Rs.2925
ANSWER:A
Question: If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
A.3 days
B.4 days
C.5 days
D.6 days
Answer: B.4 days
Explanation: Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.
Then, (6x + 8y) = 1/10 and (26x + 48y) = 1/2.
Solving these two equations, we get : x = 1/100	and y = 1/200.
(15 men + 20 boy)'s 1 day's work = (15/100 + 20/200) = 1/4.
Therefore, 15 men and 20 boys can do the work in 4 days.
CORRECT OPTION: "B".
Question: A train running at the speed of 180 km/hr crosses a pole in 18 seconds. What is the length of the train?
A.800
B.900
C.950
D.1000
Answer: B.900
Explanation: Speed=(180 x(5/18)m/sec	=(50)m/sec.
Length of the train = (Speed x Time).
Length of the train =	((50)x 18)m = 900 m
B
Question: If (4,000)(5,000) = (20)(1,000^x), what is the value of x?
A.5
B.4
C.3
D.2
Answer: D.2
Explanation: (4,000)(5,000) = (20)(1,000^x)
=> (4,000)(5,000)/20 = 1,000^x
=> 1,000,000 = 1,000^x
=> 1,000^2 = 1,000^x
Since, base is same so powers will be same too.
So, x=2
Answer will be D
Question: If a certain number of labours can dig earth 100m deep, 25m long, and 30m broad in 12 days, then find the number of days the same number of labours will require to dig earth 75m deep, 20m long and 50m broad.
A.12
B.18
C.6
D.1
Answer: A.12
Explanation: Explanation :
More number of days means more length, more depth and more width. Hence, its a direct proportion.
(100*25*30):(75*20*50) :: 12:x
75000:75000::12:x
x = 12
Answer : A
Question: In a bag there are a certain number of orange balls and blue balls. The probability of picking up exactly 1 blue ball when 2 balls are randomly drawn, is 1/2. Which of the following is the ratio of the number of orange balls to blue balls in the bag
A.2:1
B.1:1
C.1:31
D.1:3
Answer: B.1:1
Explanation: since the probability of drawing a blue ball out of two picks is 1/2.
the ratio of the blue ball to orange balls should be 1:1
Answer : B
Question: The simple interest on a sum of money will be Rs.400 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year?
A.2261
B.2888
C.1200
D.800
Answer: D.800
Explanation: P --- 10 ---- 400
P --- 5 ----- 200
3P --- 5 ----- 600
------
=> 800
Answer: D
Question: Club X has more than 20 but fewer than 50 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 4 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: The number of members is 4j+3 = 5k+4.
Let's start at 4(5)+3 = 23 and keep adding 4 until we find a number in the form 5k+4.
23, 27, 31, 35, 39 = 5(7) + 4
The club has 39 members.
39/6 = 6(6) + 3
The answer is C.
Question: What is the rate percent when the simple interest on Rs.800 amount to Rs.144 in 4 Years?
A.5%
B.8%
C.3%
D.4.5%
Answer: D.4.5%
Explanation: 144 = (800*4*R)/100
R = 4.5%
Answer: D
Question: A man can row upstream at 40 kmph and downstream at 52 kmph, and then find the speed of the man in still water?
A.27
B.40
C.42
D.46
Answer: D.46
Explanation: US = 40
DS = 52
M = (40 + 52)/2
= 46
Answer:D
Question: Find the value of x from the below equation: x^2−7x+10=0
A.5 or 2
B.1 or 3
C.1 or 7
D.3 or 5
Answer: A.5 or 2
Explanation: Here we need to find out a and b such that a + b = -7 and ab = +10
a = -5 and b = -2 satisfies the above condition.
Hence
x^2−7x+10=(x−5)(x−2)
x2−7x+10=(x−5)(x−2)
x^2−7x+10
=0
⇒(x−5)(x−2)
=0
x2−7x+10=0⇒(x−5)(x−2)=0
Step 3: Equate each factor to 0 and solve the equations
(x−5)(x−2)
=0
⇒(x−5)
=0or (x−2)=0
⇒x= 5 or 2
A
Question: In a certain store, the profit is 150% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
A.30%
B.70%
C.100%
D.50%
Answer: D.50%
Explanation: Let C.P. = Rs. 100. Then, profit = Rs. 150, S.P. = Rs. 250
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 250
Profit = 250 - 125 = Rs. 125
Required percentage = 125/250 * 100 = 50%
ANSWER:D
Question: What percent of a day is six hours?
A.20.83%
B.25%
C.18x2/3%
D.22x1/2%
Answer: B.25%
Explanation: Explanation :
Required percentage = (6/24100)%
= 25%.
Answer : B
Question: Pipe A fills a tank in 6 minutes. Pipe B can fill the same tank 2 times as fast as pipe A. If both the pipes are kept open when the tank is empty, how many minutes will it take to fill the tank?
A.0.5
B.1.0
C.1.5
D.2.0
Answer: D.2.0
Explanation: A's rate is 1/6 and B's rate is 1/3.
The combined rate is 1/6 + 1/3 = 1/2
The pipes will fill the tank in 2 minutes.
The answer is D.
Question: The C.P of 20 pens is equal to the S.P of 12 pens. Find his gain % or loss%?
A.10%
B.20%
C.30%
D.40%
Answer: D.40%
Explanation: 20 CP = 12 SP
20 --- 8 CPgain
100 --- ? => 40%
Answer: D
Question: Divide $5000 among X,Y in the ratio 2:8. How many $ that X get?
A.$1000
B.$1050
C.$1100
D.$1150
Answer: A.$1000
Explanation: Sum of ratio terms = 2+8 = 10
X = 5000*2/10 = $1000
Answer is A
Question: If an integer n is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8?
A.1/4
B.3/8
C.1/2
D.5/8
Answer: D.5/8
Explanation: total nos of ways in which we can choose n = 96
n(n + 1)(n + 2) will be divisible by 8?
case 1: n = odd then n+2 =odd & n+1 will be even i.e this needs get divided by 8, hence is a multiple of 8 so we have 8..96 = 12 multiples to fill the n+1 pos hence 12 ways
case 2: n is even then n+2 will be even & the product will be divisible by 24 & thus 8
so nos of values that can be used for n= 2....96 (all even nos) i.e 48 nos
total = 48+12 =60 ways
so reqd P =60/96 =5/8;
ANSWER:D
Question: There is 50% increase in an amount in 6 years at S.I. What will be the C.I. of Rs. 12,000 after 3 years at the same rate?
A.2160
B.3120
C.17988
D.6240
Answer: C.17988
Explanation: Let P = Rs. 100. Then, S.I. Rs. 50 and T = 6 years.
R = (100 * 50)/(100 * 6) = 10% p.a.
Now, P = Rs. 12000, T = 3 years and R = 8.33% p.a.
C.I. = [12000 * {(1 + 8.33/100)3 - 1}]
= Rs. 17988
ANSWER:C
Question: The average marks obtained by 50 candidates in a certain examination is 40.Find the total marks.
A.1800
B.2000
C.1640
D.2200
Answer: B.2000
Explanation: Following the above formula, we have the total marks =50*40=2000
Answer is B
Question: If 20% of (x-y) = 15% of (x+y), then what percent of x is y?
A.50.5%
B.44.4%
C.22.2%
D.14.3%
Answer: D.14.3%
Explanation: 20% of (x-y) = 15% of (x+y)
20/100 (x-y) = 15/100 (x+y)
5x = 35y
Required percentage = y/x *100 = 5y/35y * 100 = 14.28%
Answer is D
Question: 4,6,12,24,36,48....
A.58
B.60
C.61
D.62
Answer: B.60
Explanation: 2*2=4
3*2=6
6*2=12
12*2=24
18*2=36
24*2=48
30*2=60
ANSWER:B
Question: If a - b = 3 and a2 + b2 = 29, find the value of ab.
A.10
B.12
C.13
D.15
Answer: A.10
Explanation: 2ab = (a2 + b2) - (a - b)2
= 29 - 9 = 20
ab = 10.
answer :A
Question: A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline
than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type
of gasoline that costs 20% less per gallon than does the gasoline used by a T-Car. If the two
cars are driven the same distance, what percent less than the money spent on gasoline for the
T-Car is the money spent on gasoline for the P-Car?
A.16 2/3%
B.33 1/3 %
C.50%
D.55.56%
Answer: D.55.56%
Explanation: Assumption
Miles/Gallon
T = 100
P = 180 ( 80% more)
$/gallon
T = 100
P = 80 (20% less)
Miles
100 for both
Cost = (Miles X $/ Gallon)/ M/gallon
T = 100
P = 44.44
Hence 100 - 44.44 =55.56%
Ans D
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:
A.14
B.17
C.19
D.22
Answer: A.14
Explanation: Let the son's present age be x years. Then, (38 - x) = x
2x = 38.
x = 19.
Son's age 5 years back (19 - 5) = 14 years.
Answer : A
Question: he total marks obtained by a student in Physics, Chemistry and Mathematics is 110 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics?
A.55
B.65
C.75
D.85
Answer: A.55
Explanation: Let the marks obtained by the student in Physics, Chemistry and Mathematics be P, C and M respectively.
P + C + M = 110 + P
C + M = 110
Average mark obtained by the student in Chemistry and Mathematics = (C + M)/2 = 110/2 = 55.
ANSWER:A
Question: The investment of A, B, and C in a business are in the ratio 3:1:4. The total investment is Rs. 60,000. Find the investment made by each.
A.22500, 7500, 30000
B.22000, 8000, 30000
C.23500, 7500, 29000
D.23000, 8500, 28500
Answer: A.22500, 7500, 30000
Explanation: ratio of the investment is 3:1:4
Total investment =60000
so, 8x = 60000 ie)x =7500
so the investment of A, B,C are : A's investment 3x = 22500 B's investment x = 7500 C's investment 4x =30000
ANSWER:A
Question: On dividing 13698 by a certain number, we get 89 as quotient and 14 as remainder. What is the divisor?
A.743
B.154
C.852
D.741
Answer: B.154
Explanation: Divisor *quotient+remainder=dividend
divisor=(dividend)-(remainder)/quotient
(13698-14)/89=154
Answer(B)
Question: A train speeds past a pole in 15 sec and a platform 100 m long in 25 sec, its length is?
A.218
B.150
C.167
D.166
Answer: B.150
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 100)/25 = x/15 => x = 150 m.
Answer: B
Question: In a company with 48 employees, some part-time and some full-time, exactly (1/3) of the part-time employees and (1/4) of the full-time employees take the subway to work. What is the greatest possible number Q of employees who take the subway to work?
A.12
B.13
C.14
D.15
Answer: D.15
Explanation: P/3 + F/4 = P/3 + (48-P)/4 = 12 + P/2
P/3 + F/3 = (P+F)/3 = 48/3 = 16
P/4 + F/4 = 12
P/3 + F/3 > P/3 + F/4 > P/4 + F/4
--> 16> 12 + P/12 > 12
GREATEST Possible Q: 12 + p/12 = 15 --> p = 36 ( integer --> good)
15 or D is the answer
Question: A man is 26 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is?
A.16
B.19
C.15
D.24
Answer: D.24
Explanation: Let the son's present age be x years.
Then, man's present age = (x + 26) years.
(x + 26) + 2 = 2(x + 2)
x + 28 = 2x + 4
=> x =24 .
Answer: D
Question: Two numbers are in the ratio of 5:7. If 25 be subtracted from each, they are in the ratio of 35:59. Find the numbers?
A.60,89
B.60,88
C.60,86
D.60,84
Answer: D.60,84
Explanation: (5x-25):(7x-25) = 35:59
x = 12 => 60,84
Answer: D
Question: If u r genius solve it:-
40 * 14 = 11
30 * 13 = 12
20 * 12 = 6
10 * 11 = 2
9 * 10 = ?
A.2
B.4
C.6
D.9
Answer: D.9
Explanation: Logic :
40*14=560=5+6+0=11
30*13=390=3+9+0=12
20*12=240=2+4+0=6
10*11=110=1+1+0=2
So 9*10=90=9+0=9
Answer : D
Question: The simple interest accrued on an amount of Rs.49500 at he end of three is Rs.17820. What would be the compound interest accured on the same amount at teh same rate in the same period? (Round off your answer to two decimal places)
A.20043.94
B.38933.3
C.93832.39
D.29334.93
Answer: A.20043.94
Explanation: Let the rate of interest be R% p.a.
(49500)(3)(R)/100 = 17820
495R = 5940
R = 12
CI on Rs.49500 at 12% p.a. for three years
= 49500{[1 + 12/100]3 - 1} = 69543.936 - 49500 = Rs.20043.94
when rounded off to two decimal places.
Answer: A
Question: Bucket P has thrice the capacity as bucket Q. It takes 80 turns for bucket P to fill the empty drum. How many turns it will take for both the buckets P and Q, having each turn together to fill the empty drum?
A.30
B.45
C.60
D.80
Answer: C.60
Explanation: Explanation:
Let capacity of Q =1 litre.
Then, capacity of P =3 litre.
Given that it takes 80 turns for bucket P to fill the empty drum.
=> capacity of the drum =80×3=240 litre.
Number of turns required if both P and Q are used having each turn together
240/3+1 =60 litre.
Answer: Option C
Question: 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.90 only. Men’s wages are?
A.6Rs
B.8Rs
C.9Rs
D.1Rs
Answer: A.6Rs
Explanation: 5M = xW = 8B
5M + xW + 8B ----- 90 Rs.
5M + 5M + 5M ----- 90 Rs.
15M ------ 90 Rs. => 1M =6Rs.
Answer:A
Question: What is the sum of the different positive prime factors of 350?
A.10
B.11
C.14
D.16
Answer: C.14
Explanation: 350
35*10 --> 5*7*2*5 --> 5+7+2=14. Remember its asking for the DIFFERENT positive prime factors of 350.
C
Question: The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
A.328
B.279
C.245
D.288
Answer: C.245
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.Answer: C
Question: The manufacturing cost of a shoe is Rs.190 and the transportation lost is Rs.500 for 100 shoes. What will be the selling price if it is sold at 20% gains
A.s 234
B.s 216
C.s 220
D.s 210
Answer: A.s 234
Explanation: Explanation :
Total cost of a watch = 190 + (500/100) = 195.
Gain = 20% => SP = 1.2CP = 1.2 X 195 = 234
Answer : A
Question: One night 19 percent of the female officers on a police force were on duty. If 152 police officers were on duty that night and half of these were female officers, how many female officers were on the police force?
A.300
B.350
C.400
D.450
Answer: C.400
Explanation: Let x be the number of female police officers on the police force.
The number of female police officers on duty was 76.
0.19x = 76
x = 400
The answer is C.
Question: If the number is decreased by 5 and divided by 7 the result is 7. What would be the result if 14 is subtracted and divided by 10?
A.4
B.7
C.8
D.5
Answer: A.4
Explanation: Explanation:
Let the number be x. Then,
(x - 5)/7 = 7 => x - 5 = 49
x = 54
.: (x - 14)/10 = (54 - 14)/10 = 4
Answer: Option A
Question: What is the remainder of W=3^19 when divided by 10?
A.0
B.1
C.5
D.7
Answer: D.7
Explanation: I looked for patterns:
^2 - units digit 9
^3 - units digit 7
^4 - units digit 1
^5 - units digit 3
hence, we can see that when raised to a power which is multiple of 4, the units digit is 1, and when to an even power not multiple of 4, the units digit is 9
and we can then see:
^16 - units digit 1, or
^18 - units digit 9
and ^19 - units digit 7
therefore, W=when divided by 10, the remainder must be 7.D
Question: A, B and C enter into a partnership. A invests 3 times as much as B invests and 2/3 of what C invests. At the end of the year, the profit earned is Rs. 11000. What is the share of C?
A.Rs. 2250
B.Rs. 3000
C.Rs. 6750
D.Rs. 5625
Answer: B.Rs. 3000
Explanation: Explanation:
Let the investment of C be Rs. x.
The inverstment of B = Rs.(2x/3)
The inverstment of A = Rs. (3 × (2/3)x) = Rs. (2x)
Ratio of capitals of A, B and C = 2x : 2x/3 : x = 6 : 2 : 3
C's share = Rs. [(3/11) × 11000] = Rs. 3000
Answer: Option B
Question: If a car had traveled 40 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 120 km, at what speed did it travel?
A.50 kmh
B.60 kmh
C.70 kmh
D.80 kmh
Answer: D.80 kmh
Explanation: Time = Distance/Speed
Difference in time = 1/2 hrs
120/x - 120/(x + 40) = 1/2
Substitute the value of x from the options. --> x = 80 --> 120/80 - 120/120 = 3/2 - 1 = 1/2
Answer: D
Question: There are 8 men and 4 chairs. In how many ways men can occupy the chairs?
A.1760
B.8400
C.1680
D.1740
Answer: C.1680
Explanation: total men = 8
total chairs = 4
1st chair can be occupy in 8ways
2nd chair can be occupy in 7ways
3rd chair can be occupy in 6ways
4th chair can be occupy in 5ways
total number of ways = 8*7*6*5 = 1680 ways
correct option is C
Question: A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?
A.30
B.40
C.50
D.120
Answer: C.50
Explanation: So, (120+k)/(800+k)=20/100
Or, (120+k)/(800+k)=15
Or, 600+5k=800+k
Or, 4k=200
Or, k=50
Or, k=50k=50
So, 50 ml of Grape juice , must be added , answer must be (C)
Question: Of the 400 members at a health club, 260 use the weight room and 310 use the pool. If at least 60 of the members do not use either, then the number of members using both the weight room and the pool must be between:
A.40 to 100
B.240 to 280
C.230 to 260
D.220 to 300
Answer: C.230 to 260
Explanation: W=260
P=310
ALL=400
N(NEITHER)=AT LEAST 60
BOTH=?
W+P-BOTH+N=ALL
260+310-BOTH+60=400
BOTH=230
now pay attention to the fact, that both at most can be 260, since W=260
C
Question: The average age of 4 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is
A.22
B.30
C.99
D.26
Answer: D.26
Explanation: total age increased = (8 * 2) years = 8 years.
Sum of ages of two new men = (21 + 23 + 8) years = 52 years
Average age of two new men = (52/2) years = 26 years.
Answer: D
Question: A particular store purchased a stock of turtleneck sweaters and marked up its cost by 20%. During the New Year season, it further marked up its prices by 25% of the original retail price. In February, the store then offered a discount of 12%. What was its profit on the items sold in February?
A.27.5%
B.32%
C.35%
D.37.5%
Answer: B.32%
Explanation: Assume the total price = 100x
Price after 20% markup = 120x
Price after 25%further markup = 1.25*120x = 150x
Price after the discount = 0.88*150x = 132x
Hence total profit = 32%
Option B
Question: If the speed of Y meters per second is equivalent to the speed of X kilometers per hour, what is X in terms of Y? (1 kilometer=1000 meters)
A.15y/18
B.6y/5
C.18y/5
D.60y
Answer: C.18y/5
Explanation: If the speed of Y meters per second is equivalent to the speed of X kilometers per hour, what is X in terms of Y? (1 kilometer=1000 meters)
We need to find an equation with y in the answer...
convert all measurements so they are alike (i.e. convert km to m, seconds to hours, etc)
Speed = y/t
y meters/second
(3600) x meters/hour
Speed = x/t
x KM/hour
Speed = x(1000m)/hour
x(1000meters)/hour = (3600) x meters/hour
x(1000)/1hour = y(3600) / 1 hour
x(1000) = y(3600)
x = 3.6y
Answer: C. 18y/5
Question: On average, the bottle-nosed dolphin comes up for air once every three minutes; the beluga whale, a close relative, comes up for air on average once every nine minutes. The number of times a bottle-nosed dolphin would come up for air in a 24 hour period is approximately what percent greater than the number of times a beluga whale would come up for air in that same period?
A.150%
B.200%
C.250%
D.300%
Answer: D.300%
Explanation: Dolphin once in 3 min;
Beluga once in 9 min;
So, dolphin comes up 3 times frequently than beluga, which is 300% (9-3)/2*100.
Answer: D.
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?
A.16 kmph
B.19 kmph
C.14 kmph
D.11 kmph
Answer: C.14 kmph
Explanation: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream
= (2+1)/(2-1) = 3/1
= 3:1
Speed of the stream
= 42/3 = 14 kmph.
Answer: C
Question: Two dice are rolled. What is the probability the sum will be greater than 11?
A.1/9.
B.1/12.
C.1/36.
D.1/6.
Answer: C.1/36.
Explanation: Combinations possible: (6,6) = 1
Total combinations possible: 6*6=36
Answer = 1/36 Option C.
Question: A alone can finish a work in 10 days which B alone can finish in 15 days. If they work together and finish it, then out of a total wages of Rs.3500, A will get:
A.Rs.1200
B.Rs.1500
C.Rs. 2100
D.Rs.2000
Answer: C.Rs. 2100
Explanation: Explanation:
Ratio of working days of A : B = 10 : 15
Therefore, their wages ratio = reverse ratio = 15 : 10
Therefore, A will get 15 units of ratio
Total ratio = 25
1 unit of ratio =3500/25 = 140
So, A’s amount = 120 × 15 = Rs.2100.
Answer: Option C
Question: A train 220 m long is running with a speed of 59 kmph. In what time will it pass a man who is running at 7 kmph in the direction opposite to that in which the train is going?
A.7 sec
B.8 sec
C.10 sec
D.12 sec
Answer: D.12 sec
Explanation: Speed of the train relative to man = (59 + 7) kmph
= 66 *5/18 m/sec = 55/3 m/sec.
Time taken by the train to cross the man = Time taken by it to cover 220 m at (55/3) m / sec
= (220 *3/55) sec = 12 sec
Answer : D.
Question: All factors of a positive integer B are multiplied and the product obtained is B^3. If B is greater than 1, how many factors does B have?
A.2
B.3
C.6
D.7
Answer: C.6
Explanation: The question can be done in seconds if you understand the properties of factors of a number. Note that every distinct factor of a number which is not a perfect square has a complementary factor.
For example,
Factors of 6: 1, 2, 3, 6
1 has a complementary factor 6 such that 1*6 = 6 (the original number)
2 has a complementary factor 3 such that 2*3 = 6 (the original number)
So if you have a number, n, which is not a perfect square, and start multiplying its factors, you will get n to a certain power. the power will half of the number of factors. For example, 6 has 4 factors and when you multiply all 4 factors, you get 6^2 (2 is half of 4).
So if you know that the product of all factors is B^3, it means there must have been twice the number of factors i.e. 3*2 = 6 factors.
C)
Question: he average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women?
A.37
B.74
C.30
D.34
Answer: C.30
Explanation: 20 + 24 + 8 * 2
= 60/2
= 30
Answer:C
Question: How many positive integers less than 30 are either a multiple of 2, an odd prime number, of the sum of a positive multiple of 2 and an odd prime?
A.29
B.28
C.27
D.25
Answer: B.28
Explanation: Any odd number can be expressed as 2k+1 or 2k+(3-2) or 2(K-1)+3.
Thus, with the prime number 3,
we can express all the odd numbers.
Since, 1 i is the only number that cannot be expressed,
answer is numbers <30 =29-1.
ANSWER:B
Question: How many six-digit numbers that do not contain the digits 5 or 8 are there?
A.483224
B.156444
C.229376
D.816416
Answer: C.229376
Explanation: We can have 7 digits ( 1,2,3,4,6,7,9) for the first place ( hundred thousand's place).
and similarly 8 digits for ten thousands, thousands, hundred's, tenth's and unit digit. ( 0,1,2,3,4,6,7,9)
So in total 7*8*8*8*8*8= 229376
Hence C
Question: A train covers a distance of 12 km in 10 min. If it takes 10 sec to pass a telegraph post, then the length of the train is?
A.200
B.288
C.120
D.776
Answer: A.200
Explanation: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 10
= 200 m.
Answer:A