RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Kim bought a total of $2.65 worth of postage stamps in four denominations. If she bought an equal number of 5-cent and 25-cent stamps and twice as many 10-cent stamps as 5-cent stamps, what is the least number of 5-cent stamps she could have bought ?
A. 5
B. 3
C. 15
D. 20
Answer: B. 3
Explanation: 2.65 = 0.05x + 0.25x + 2 * 0.10x + 0.05y
=> 2.65 = 0.30x + 0.20x + 0.05y
=> 265 = 50x + 5y
So Max value of 50x < 265 = 250
Hence y = 3
Answer - B
Question: S is the set of all fractions defined by the formula n/(n + 1), where n is a positive integer less than 20. What is the product C of all the fractions that are in S?
A.1) 1/20
B.2) 1/21
C.3) 1/2
D.4) 19/40
Answer: A.1) 1/20
Explanation: 1/2 * 2/3 * 3/4 * ... 19/20
= 1/20
Answer - A
Question: Find the area of a parallelogram with base 24 cm and height 16 cm.
A.379
B.384
C.345
D.342
Answer: B.384
Explanation: Area of a parallelogram = base * height = 24 * 16 = 384 cm2
Area of a parallelogram = base * height = 24 * 16 = 384 cm2
Answer: Option B
Question: The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?
A.1/5
B.1/3
C.2/5
D.1/2
Answer: D.1/2
Explanation: Let weight of jar filled with beans = 100 g
Weight of jar = 20 g
Weight of coffee beans = 80 g
Weight of jar and remaining beans = 60 g
Weight of remaining beans = 40 g
Fraction remaining = 40/80 = 1/2
Answer is D.
Question: The greatest common factor of 16 and the positive integer n is 4, and the greatest common factor of n and 45 is 3. Which of the following could be the greatest common factor of n and 60?
A.5
B.8
C.12
D.15
Answer: C.12
Explanation: n includes the factors 2^2 (but not 2^3) and 3 (but not 3^2 or 5)
60 = 4*3*5
The GCF is 12.
The answer is C.
Question: If a man rows at the rate of 5 kmph in still water and his rate against the current is 3.5 kmph, then the man’s rate along the current is
A.4.25 kmnph
B.6 kmph
C.6.5 kmph
D.8.5 kmph
Answer: C.6.5 kmph
Explanation: Solution
Let the rate along the current be x kmph.
Then,	= (1 / 2(x+3.5))= 5
x= 6.5 kmph.
Answer C
Question: The batting average of a particular batsman is 60 runs in 46 innings. If the difference in his highest and lowest score is 150 runs and his average excluding these two innings is 58 runs, find his highest score.
A.179
B.208
C.210
D.223
Answer: A.179
Explanation: Explanation:
Total runs scored by the batsman = 60*46 = 2760 runs
Now excluding the two innings the runs scored = 58*44 = 2552 runs
Hence the runs scored in the two innings = 2760 – 2552 = 208 runs.
Let the highest score be x, hence the lowest score = x – 150
x + (x - 150) = 208
2x = 358
x = 179 runs
ANSWER A
Question: A 75-liter solution of cool-drink is made from 10% jasmine water. If 3.5 liters of jasmine and 9.5 liters of water were added to the solution, what percent of the solution is jasmine?
A.12.5%
B.14%
C.15.5%
D.17%
Answer: A.12.5%
Explanation: The percent of jasmine in the resulting solution is: (amount of jasmine) / (total volume)
(0.1(75) + 3.5) / 88 = 11/88 = 1/8 = 12.5%
The answer is A.
Question: workers decided to raise Rs.3 lacs by equal contribution from each. Had they contributed Rs.50 eachextra, the contribution would have been Rs.3.25 lacs. How many workers were they?
A.250
B.400
C.500
D.560
Answer: C.500
Explanation: N * 50 = (325000 - 300000) = 25000
N = 25000 / 50
= 500
C
Question: Carolyn bought 16 gumballs, Lew bought 14 gumballs, and Carey bought X gumballs. The average (arithmetic mean) number of gumballs the three bought is between 19 and 25, inclusive. What is the difference between the greatest number and the smallest number of gumballs Carey could have bought?
A.20
B.18
C.24
D.26
Answer: B.18
Explanation: Smallest gumballs = (19-16) + (19-14) +19= 27
Largest gumballs = (25-16) + (25-14) +25= 45
Difference = 45 - 27 = 18
B
Question: In a financial company investment compounds annually at an interest rate of 34.1% What is the smallest investment period by which time the investment will more than triple in value?
A.1.2
B.1
C.2
D.4
Answer: D.4
Explanation: Assume initial amount is x
Annual Interest is 34.1% so after 1 year the amount will become x * (100+34.1)/100 => x*4/3
now we need to find n for x * (4/3)^n = 3x
or in other words n = 4
D
Question: In a group of 12 engineers, 4 engineers have a PHD degree; the others have only an MS or BS degree. A team of 4 engineers is to be chosen which must have at least 1 engineer with a PHD, how many different teams can be chosen?
A.495
B.70
C.245
D.425
Answer: D.425
Explanation: The problem asks for a combination, since order doesn't matter. Now, selecting r items from a set of n gives the Combination Formula: nCr= n!/r!(n-r)!
n = 12
r = 4
So, total teams is 12C4 = 12!/(4!(12 - 4)!) = 495, and
n = 12 - 4 = 8
r = 4
for teams without a PHD is 8C4 = 8!/(4!(8 - 4)!) = 70,
so, teams with at least 1 PHD = 495 - 70 = 425
Answer: D
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 4 per square feet if there is one door of dimensions 6 feet * 3 feet and three WINDOWS of dimensions 4 feet * 3 feet each?
A.4000
B.3624
C.5673
D.4530
Answer: B.3624
Explanation: Area of the four walls = 2h(l + b)
Since there are doors and WINDOWS, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 4 = Rs. 3624
Answer: Option B
Question: Vessel ‘A’ contains 150 litres of mixture of milk and water in the ratio of 3:1. Vessel ‘B’ contains 200 litres of the mixture in the ratio of 5:2. If the mixture from both the vessels are poured into vessel ‘C’, find the ratio of the resulting mixture.
A.15 : 7
B.8 : 3
C.15 : 2
D.143 : 53
Answer: D.143 : 53
Explanation: Explanation:
As vessel A contains 150 litres of mixture of milk and water in the ratio 3:1, the quantity of milk is 3*150/4 litres, and that of water is 150/4 litres.
Similarly, as vessel B contains 200 litres of mixture of milk and water in the ratio 5:2, the quantity of milk is 5*200/7, and that of water is 2*200/7 litres.
After mixing the total quantity is 350 litres.
The quantity of milk is {(3*150/4) + (5*200/7)} = 7150/28
The quantity of water is {(150/4) + (2*200/7)} = 2650/28
The ratio of the resulting mixture = 7150/2650 = 143 : 53
ANSWER D
Question: One packet contains 2 black, 3 white and 2 red rubbers. 2 rubbers are drawn at random. What is the probability that none of the rubbers drawn is red?
A.10/21
B.21/23
C.23/25
D.21/20
Answer: A.10/21
Explanation: Total number of rubbers = (2 + 3 + 2) = 7.
Let S be the sample space.
Then, n(S)	= Number of ways of drawing 2 rubbers out of 7
= 7C2 `
=	(7 x 6)
(2 x 1)
= 21.
Let E = Event of drawing 2 rubbers, none of which is blue.
n(E)	= Number of ways of drawing 2 rubbers out of (2 + 3) rubbers.
= 5C2
=	(5 x 4)
(2 x 1)
= 10.
P(E) =	n(E)	=	10/21.
n(S)
A
Question: A library has an average of 510 visitors on Sundays and 240 on other day. The average number of visitors in a month of 50 days starting with sunday is
A.280
B.285
C.171
D.295
Answer: C.171
Explanation: Explanation:
As the month begin with sunday, so there will be five sundays in the month. So result will be:
=(510×5+240×25/30)=(8550/50)=171
Answer: Option C
Question: A card board of size 34*14 has to be attached to a wooden box and a total of 35 pins are to
be used on the each side of the card box. find the total number of pins used.
A.135
B.136
C.137
D.138
Answer: B.136
Explanation: total 35 pins are there and 4 sides of card board...so 35X4=140
now in the rectangle 4 vertices have 4 pins which is common to the sides....so 140-4=136
ANSWER:B
Question: A started a business with Rs. 21,000 and is joined afterwards by B with Rs. 36,000. After how many months did B join if the profits at the end of the year are divided equally?
A.4
B.5
C.6
D.7
Answer: B.5
Explanation: Sol.
Suppose B joined after x months.
Then, 21000 * 12 = 36000 * (12 - x) ⇔ 36x = 180 ⇔ x = 5.
Hence, B joined after 5 months.
Answer B
Question: 0---:-|---:--|-:--:-|--:---|-:----1
On the number line above, the segment from 0 to 1 has been divided into fifths, as indicated by the large tick marks, and also into sevenths, as indicated by the small tick marks. What is the LEAST possible distance A between any two of the tick marks?
A.1/70
B.1/35
C.2/35
D.1/12
Answer: B.1/35
Explanation: divisions are 0 1/7 2/7 3/7 4/7 5/7 6/7 1
1/5 2/5 3/5 4/5 5/5
expressing the same in terms of the lcm of 5,7 ,i.e 35
0 7/35 14/35 21/35 28/35 35/35
5/35 10/35 15/35 20/35 25/35 30/35
by comparing the divisions with each other we can see 1/35 is the shortest possible distance between any two selected divisions.
A=1/35
Answer is B.
Question: Which of the following triples of numbers have the same standard deviation as the numbers m, n and o?
I. m-2, n-2, o-2
II. 0, m-n, o-n
III. m-4, n+5, o-1
A.I only
B.II only
C.I and III only
D.II and I only
Answer: D.II and I only
Explanation: If we add or subtract a constant to each term in a set the standard deviation will not change.
Set {m-2, n-2, o-2} is obtained by subtracting 2 from each term of {m, n, o}.
Set {0, m-n, o-n} is obtained by subtracting s from each term of {m, n, o}.
Set {m-4, n+5, o-1} is totally different from {m, n, o}.
Thus the answer is I and II only.
Answer: D.
Question: There are 11 points in a given plane, no three of which are on the same line. If one of the points is represented as 'A', then how many triangles can be determined with the 11 points that contain the point A?
A.45
B.105
C.182
D.210
Answer: A.45
Explanation: Any 2 points out 10 points will create triangle with third point A, so the answer is 10C2=45.
Answer: A.
Question: Alice has a jar of juice, and she drank 1/6 of the juice for lunch. If Alice drank 2/5 of the remaining juice for dinner, what fraction of the juice was left after dinner?
A.1/2
B.2/3
C.1/4
D.2/5
Answer: A.1/2
Explanation: Let x be the amount of juice at the beginning.
After lunch, the remaining juice was (5/6)x.
After dinner, the remaining juice was (3/5)(5/6)x = (1/2)x.
The answer is A.
Question: A, B and C invests Rs.4000, Rs.2000 and Rs.6000 in a business. After one year A removed his money; B and C continued the business for two more year. If the net profit after 3 years be Rs.3300, then A's share in the profit is?
A.6000
B.4000
C.2000
D.600
Answer: D.600
Explanation: 4*12 : 2*36 : 4*36
2: 3: 6
2/11 * 3300 = 600
Answer: D
Question: A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 140, then how much amount should C pay as his share of rent?
A.35
B.45
C.25
D.36
Answer: D.36
Explanation: A : B : C
=10×7:12×5:15×3
=2×7:12×1:3×3
=14:12:9
Amount that C should pay
=140×9/35=4×9=36
Answer is D
Question: If mn represents a positive two digit number, where m and n are single digit integers, which of the following cannot be true?
A.m+n =9
B.(m)(n)=9
C.m-n = 9
D.n-m= 9
Answer: D.n-m= 9
Explanation: (A) mn = 45 or 63 or 27
(B) mn = 33 or 19
(C) 90
(D) impossible
(E) mn = 91
(D) is impossible because 09 is not a valid two digit number --- if there's a zero in the ten's place, that's just 9, a single digit number. Therefore, no valid two digit number would satisfy (D).
ans D
Question: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did C get in a profit of Rs.2430 ?
A.s. 432
B.s. 486
C.s. 822
D.s. 812
Answer: B.s. 486
Explanation: Let the total amount in the partnership be 'x'.
Then A's share = x/3
B's share = x/4
C's share = x/5
D's share = x - (x/3 + x/4 +x/5) = 13x/60
A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13
A's share in the profit of Rs. 2430 = 12 (2430/60) = Rs. 486
Answer: B
Question: A photography dealer ordered 60 Model X cameras to be sold for $250 each, which represents a 10 percent markup over the dealer’s initial cost for each camera. Of the cameras ordered, 6 were never sold and were returned to the manufacturer for a refund of 50 percent of the dealer's initial cost. What was the dealer's approximate profit or loss as a percent of the dealer’s initial cost for the 60 cameras?
A.7% loss
B.13% loss
C.4% profit
D.13% profit
Answer: C.4% profit
Explanation: Total cost 60*($250/1.1)=54.54*250;
# of cameras sold is 60-6=54 total revenue is 54*250;
# of cameras returned is 6 total refund 6*(250/1.1)*0.5;
So, total income 54*250+ 6*(250/1.1)*0.5
The dealer's approximate profit is (54*250+ 6*(250/1.1)*0.5-54.54*250)/(54.54*250)*100=4%
Answer: C.
Question: Because he’s taxed by his home planet, Mork pays a tax rate of 40% on his income, while Mindy pays a rate of only 30% on hers. If Mindy earned 2 times as much as Mork did, what was their combined tax rate?
A. 32.5%
B. 34%
C. 22.5%
D. 33.3%
Answer: D. 33.3%
Explanation: Say Morks income is - 100
So tax paid will be 40
Say Mindys income is 2*100 = 200
So tax paid is 30% * 200 = 60
Total tax paid = 40+60 = 100.
Combined tax % will be 100/100+200 = 33.3%
Question: Some persons can do a piece of work in 12 days. Two times the number of these people will do half of that work in?
A.3
B.4
C.5
D.6
Answer: A.3
Explanation: 12/ (2 * 2) = 3 days
Answer:A
Question: If two integers x,y (x>y) are selected from -6 to 6 (inclusive), how many cases are there?
A.70
B.74
C.78
D.82
Answer: C.78
Explanation: There are 13 integers from -6 to 6 inclusive.
13C2 = 78.
The answer is C.
Question: A and B can do a work in 18 day, B and C in 30 days, A and C in 22 (1/2) days. In how many days can A,B and C individually do the work?
A.60,90,128
B.60,90,120
C.60,90,127
D.60,90,118
Answer: B.60,90,120
Explanation: (A+B+C)'s two days work = 1/18 + 1/30 + 2/45
= (5 + 3 + 4)/90 = 2/15
(A+B+C)'s one day work = 2/15 * 1/2 = 1/15
A's one day's work = 1/15 - 1/30 = 1/30
B's one day's work = 1/15 - 2/45 = 1/45
C's one day's work = 1/15 - 1/18= 1/90
So, A,B and C can individually do the work in 30, 45 and 90 days.
Answer:B
Question: In how many ways can the letters of word BISECTION be arranged such that NO two vowels appear together?
A.9!
B.5!*4!
C.4!*5!
D.5!*4!*2!
Answer: C.4!*5!
Explanation: No 2 vowels together = the only arrangement possible will be C V C V C V C V C (with V=vowel, C=consonant). This is true as we have 4 vowels and 5 consonants and any other combination will force us to pair 2 vowels together.
Thus, the number of arrangements possible : 5 *4 *4 *3 *3 *2 *2*1 = 4!*5! ----> C is the correct answer.
Question: If a, b, and c are consecutive even integers and a < b < c, all of the following must be divisible by 4 EXCEPT
A.a + c
B.b + c
C.ac
D.(bc)/2
Answer: B.b + c
Explanation: Let integers be a= x-2, b= x, c= x+2
Now by options
a+c = 2x (has to be divisible by 4 as x is an even no.)
b+c = 2x +2 = 2(x+1) as x is an even no. x+1 is odd, so eq. becomes 2 * odd hence cannot be divisible by 4
ANSWER:B
Question: A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 3600 interest only for the period. The principal amount borrowed by him was:
A.s. 2000
B.s. 10,000
C.s. 15,000
D.s. 18,000
Answer: B.s. 10,000
Explanation: Principal = Rs. (100 x 3600)/(12X3) = Rs. 10000. Answer: Option B
Question: To be eligible for retirement benefits at the Mankind Corporation, the sum of an employee's age, in years, and the number of years employment must be at least 60. If a, where a <60, is a certain employee's age when hired and b is the minimum number of years of employment required for the employee to be eligible for retirement benefits, which of the following equations represents the relationship between a and b?
A.2a+2b=60
B.ab=60
C.a+2b=60
D.a+b=60
Answer: C.a+2b=60
Explanation: We are told that when a certain employee was hired he was a years old and that the he needed minimum b years to be eligible for benefits.
Now,after b years of employment, when the employee will be be eligible for benefits, the employee will be a+b years old and will have b years of employment, thus{age after b years}+{employment years}=(a+b)+b=a+2b=60
Answer: C
Question: A boat takes 19 hours for travelling downstream from point A to point B and coming back to a point C which is at midway between A and B. If the velocity of the stream is 4 kmph and the speed of the boat in still water is 14 kmph, what is the distance between A and B ?
A.180 km
B.127 km
C.178 km
D.188 km
Answer: A.180 km
Explanation: Explanation:
Speed in downstream = (14 + 4) km/hr = 18 km/hr;
Speed in upstream = (14 â€“ 4) km/hr = 10 km/hr.
Let the distance between A and B be x km. Then,
x/18 + (x/2)/10 = 19 â‡” x/18 + x/20 = 19 â‡’ x = 180 km.
Answer: A
Question: Two cars are driving toward each other. The first car is traveling at a speed of 90 km/h, which is 50% faster than the second car's speed. If the distance between the cars is 975 km, how many hours will it take until the two cars meet?
A.6
B.6.5
C.7
D.7.5
Answer: B.6.5
Explanation: The speed of the first car is 90 km/h.
The speed of the second car is 90 / 1.5 = 60 km/h.
The two cars complete a total of 150 km each hour.
The time it takes the cars to meet is 975 / 150 = 6.5 hours.
The answer is B.
Question: Twenty four men can do a work in 35 days. How many men are required to complete the work in 21 days?
A.20
B.10
C.50
D.40
Answer: D.40
Explanation: D
40
We have M1 D1 = M2 D2
So, 24 * 35 = M2 * 21 => M2 = 40.
Question: If a + b > 0 and a * b < 0, which of the following must be true?
I. a > 0 or b > 0
II. a < 0 or b < 0
III. a and b have the same sign
A.I only
B.II only
C.III only
D.I and II only
Answer: D.I and II only
Explanation: I. True, for the sum to be greater than 0, at least one of a or b has to be positive
II. True, for the product to be less than 0, one of a or b has to be negative
III. Not true, by the previous two, one of a or b has to be positive and the other has to be negative
D
Question: What is the sum of the different positive prime factors of 640?
A.5
B.7
C.10
D.15
Answer: B.7
Explanation: The prime factorization of 640
= 64 * 10
= 2^6 * 2*5
The sum of the different positive prime factors = 2+5 = 7
The answer is B.
Question: If two painters can complete two rooms in two hours, how many rooms painted if 10 painters work for 6 hours?
A.35
B.25
C.20
D.30
Answer: D.30
Explanation: Explanation:
Two painters can complete two rooms in two hours.So 30 rooms can be painted in 6 hrs by 10 painters
Answer: D) 10 painters
Question: A person travels equal distances with speeds of 3km/hr, 6km/hr, 9km/hr. and takes a total time of 11minutes. Find the total distance ?
A.1km
B.500mts
C.900mts
D.2km
Answer: C.900mts
Explanation: Let the each distance be x km
total distance = 3x
then total time,
(x/3)+(x/6)+(x/9) = 11/60
x=0.3
total distance = 3*0.3 = 0.9km = 900meters
correct option is C
Question: At a certain company, each employee has a salary grade s that is at least 1 and at most 5. Each employee receives an hourly wage p, in dollars, determined by the formula p = 7.50 + 0.25(s – 1). An employee with a salary grade of 5 receives how many more dollars per hour than an employee with a salary grade of 1?
A.$0.50
B.$1.00
C.$1.25
D.$1.50
Answer: C.$1.25
Explanation: OA is definitely wrong. The answer should be C.
Question: A student gets 50% in one subject, 70% in the other. To get an overall of 70% how much should get in third subject.
A.90%
B.25%
C.45%
D.55%
Answer: A.90%
Explanation: Let the 3rd subject % = x
50+70+x = 3*70
120+x =210
x = 210-120 = 90
Answer : A
Question: A square is drawn inside a right-angled triangle with the two perpendicular sides as 12 cm and 8 cm. what is the side of the largest possible square that can be drawn?
A.4.8 cm
B.4.4 cm
C.4.9 cm
D.5.0 cm
Answer: A.4.8 cm
Explanation: Area of triangle is 1/2 * 12 * 8 = 48
Side of square = x
The entire triangle split into two right angled triangle and one square with dimensions as follows
i) square with side x
ii) Right angled triangle with perpendicular sides x and 12-x
iii) Right angled triangle with perpendicular sides 8-x and x
Sum of area of all three = 48
= x2 + 1/2*x*(12-x) + 1/2*x*(8-x) = 48
= x = 4.8 cm
answer : A
Question: If (0.2)x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is:
A.-10.0
B.-0.5,
C.-0.4
D.-0.2,
Answer: C.-0.4
Explanation: Solution:
(0.2)x = 2.
Taking log on both sides
log (0.2)x = log 2.
x log (0.2) = 0.3010, [since log 2 = 0.3010].
x log (2/10) = 0.3010.
x [log 2 - log 10] = 0.3010.
x [log 2 - 1] = 0.3010,[since log 10=1].
x [0.3010 -1] = 0.3010, [since log 2 = 0.3010].
x[-0.699] = 0.3010.
x = 0.3010/-0.699.
x = -0.4306….
x = -0.4 (nearest tenth)
Answer: C
Question: If 3 persons can do 3 times of a particular work in 3 days, then, 7 persons can do 7 times of that work in
A.3 days
B.4 days
C.5 days
D.6 days
Answer: A.3 days
Explanation: Answer: Option 'A'
That is, 1 person can do one time of the work in 3 days.
Therefore, 7 persons can do 7 times work in the same 3 days itself.
Question: On the number line, if x is halfway between -8 and 4, and if y is halfway between -2 and 6, what number is halfway between x and y?
A.-2
B.-1
C.0
D.1
Answer: C.0
Explanation: x= -2 and y = 2.
The answer is C.
Question: A car covers a distance of 624 km in 6 ½ hours. Find its speed?
A.104
B.376
C.1267
D.198
Answer: A.104
Explanation: 624/6 = 104 kmph
Answer: A
Question: The ratio 5:20 expressed as percent equals to
A.50 %
B.125 %
C.25 %
D.None of above
Answer: C.25 %
Explanation: Explanation:
Actually it means 5 is what percent of 20, which can be calculated as,
(5/20)*100 = 5 * 5 = 25
Option C
Question: A woman on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
A.71.11 km/hr.
B.68.11 km/hr.
C.44.11 km/hr.
D.88.11 km/hr.
Answer: A.71.11 km/hr.
Explanation: A
71.11 km/hr.
Total time taken = 160/64 + 160/80 = 9/2 hours
--> Average speed = 320 x 2/9 = 71.11 km/hr.
Question: The average (arithmetic mean) of the even integers from 24 to 48 inclusive is how much greater than the average (arithmetic mean) of the even integers from 12 to 24 inclusive?
A.14
B.16
C.18
D.20
Answer: C.18
Explanation: So, according to A mean of a set of even numbers from 24 to 48 =(24+48)/2=36 and mean of a set of even numbers from 12 to 24 =(12+24)/2=18
Difference=36-18=18
Answer: C.
Question: The following sets each have a mean of 10 and the standard deviations are given in variable form.
Set I = {7, 8, 9, 11, 12, 13}, standard deviation = A
Set II = {10, 10, 10, 10, 10, 10}, standard deviation = B
Set III = {6, 6, 6, 14, 14, 14}, standard deviation = C
Rank these three standard deviations from least to greatest.
A.A, B, C
B.A, C, B
C.B, A, C
D.B, C, A
Answer: C.B, A, C
Explanation: SD is minimum when the terms are closer to the mean.
In set 2, we have all terms equal to mean. hence, its SD is 0.(The Lowest)
Comparing Set 1 and Set 3, Set 1 has terms more closer to mean than set 3. hence, Set 3 Sd is the highest.
So, Answer is C
Question: There are 200 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of managers to 98%?
A.150
B.100
C.99
D.50
Answer: B.100
Explanation: There are 198 managers and 2 others. The 2 others would compose 2% of the total number of people if there were 100 people in the room. Thus 100 managers must leave.
The answer is B.
Question: welve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. Sixteen adults left and four children joined them. How many days will they take to complete the remaining work?
A.3 days
B.4 days
C.6 days
D.8 days
Answer: C.6 days
Explanation: One child’s one day work = 1/192.
One adult’s one day’s work = 1/96.
Work done in 3 days = ((1/96) x 16 x 3) = 1/2
Remaining work = 1 – 1/2 = 1/2
(6 adults+ 4 children)’s 1 day’s work = 6/96 + 4/192 = 1/12
1/12 work is done by them in 1 day.
1/2 work is done by them in 12 x (1/2) = 6 days
ANSWER:C
Question: A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 38 years now, the son's age five years back was:
A.76 years.
B.14 years.
C.55 years.
D.45 years.
Answer: B.14 years.
Explanation: Let the son's present age be x years.
Then, (38 - x) = x
2x = 38 => x = 19
Son's age 5 years back = (19 - 5) = 14 years.
Answer: B