RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of odd all the integers between 10 and 100?
A.1345
B.1576
C.2475
D.2578
Answer: C.2475
Explanation: numbers are 11,13,15-------,97,99
Average of the set: (largest+smallest)/2=(99+11)/2=55;
# of terms: (largest-smallest)/2+1=(99-11)/2+1=45
The sum = 45*55= 2475
Answer: C
Question: Prove that there exists infinitely many positive integers n such that 4n^2 + 1 is divisible both by 5 and 13.
A.5
B.6
C.5|4n^2+ 1 and 13|4n^2+ 1
D.3|4n^2+ 1 and 10|4n^2+ 1
Answer: C.5|4n^2+ 1 and 13|4n^2+ 1
Explanation: For instance, all numbers n in the arithmetic progression 65k+56 (k = 0, 1, 2, ... ) have the desired property. Indeed, if n = 65k+56 with an integer k>=0, then n == 1 (mod 5) and n == 4 (mod 13), hence 4n^2+ 1 == o (mod 5) and 4n^2+ 1== 0 (mod 13). Thus, 5|4n^2+ 1 and 13|4n^2+ 1
Answer is C 5|4n^2+ 1 and 13|4n^2+ 1
Question: If |x – 9/2| = 5/2, and if y is the median of a set of u consecutive integers, where u is odd, which of the following must be true?
I. xyu is odd
II. xy(u^2 + u) is even
III. x^2y^2u^2 is even
A.II only is true
B.III only is true
C.I and III
D.II and III
Answer: A.II only is true
Explanation: given:
u is Odd
y is the median of odd numbers, hence y is Odd
x = solving the modulus you get 7 and 2. Hence x is Even or Odd
Therefore: u = O, y = O and x = O or E
Statement I = x*y*u = y*u*x = O x O x O/E = O x O/E = Odd or even. So False
Statement II = xy(u^2 + u) = O/E x O (O + O) = O/E x O(E) = O/E x E = Always Even. So true
Statement III. x^2y^2u^2 is even. E/O x O x O = Odd or even. Hence False.
Answer = A.
Question: By selling a watch for Rs.560/-, a man loses 20% what is that watch cost price
A.s. 700/-
B.s. 800/-
C.s. 880/-
D.s. 900/-
Answer: A.s. 700/-
Explanation: 80 % ------> 560 (80 * 7 = 560)
100 % ------>700 (100 * 7 = 700)
Cost price = Rs. 700/-
A
Question: In a rare coin collection, all coins are either pure gold or pure silver, and there is initially one gold coin for every three silver coins. With the addition of 12 more gold coins to the collection, the ratio of gold coins to silver coins is 1 to 2. Based on this information, how many total coins are there now in this collection (after the acquisition)?
A.72
B.84
C.96
D.108
Answer: D.108
Explanation: Initially the number of gold coins and silver coins is 2k and 6k.
After adding gold coins, the number of coins is 3k and 6k.
Thus k = 12 and the total number of coins is 9k = 108.
The answer is D.
Question: In how many ways can 6 boys and 3 girls be arranged at a table if 3 girls are never together?
A.47520
B.45620
C.47888
D.42156
Answer: A.47520
Explanation: Total ways of arranging 10 person in a circle = 9! = 51840 ways
If we consider three women as one, then we have 6+1=7 persons. Arranging these seven persons in circle will take = 6! = 720 ways
And three women can arrange themselves in 3! ways
Total ways in which three women sit together in circle = 6!*3! = 4320 ways
Total ways in which three women doesn’t sit together in circle = 9! - 6!*3! = 51840 - 4320 = 47520 ways
A
Question: A textile manufacturing firm employees 80 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 80 looms is Rs 5,00,000 and the monthly manufacturing expenses is Rs 1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs 75000. If one loom breaks down and remains idle for one month, the decrease in profit is:
A.13000
B.7000
C.10000
D.4375
Answer: D.4375
Explanation: Explanation :
Profit = 5,00,000âˆ’(1,50,000+75,000) =Rs. 2,75,000.
Since, such loom contributes equally to sales and manufacturing expenses.
But the monthly charges are fixed at Rs 75,000.
If one loan breaks down sales and expenses will decrease.
New profit :-
=>500000Ã—(79/80)âˆ’150000Ã—(79/80)âˆ’75000.
=>Rs 2,70,625.
Decrease in profit
=>2,75,000âˆ’2,70,625
=>Rs. 4,375
Answer : D
Question: In a apartment, 30% of the people speak English, 20% speak Hindi and 10% speak both. If a people is selected at random, what is the probability that he has speak English or Hindi?
A.2/3
B.1/3
C.2/5
D.2/7
Answer: C.2/5
Explanation: P (E) = 30 / 100 = 3 / 10 , P (H) = 20 / 100 = 1 / 5 and P (E ∩ H) = 10 / 100 = 1 / 10
P (E or H) = P (E U H)
= P (E) + P (H) - P (E ∩ H)
= (3 / 10) + (1 / 5) - (1 / 10) = 4 / 10 = 2/5
C
Question: The size of a flat-screen television is given as the length of the screen’s diagonal. How many square inches greater is the screen of a square 34-inch flat-screen television than a square 27-inch flat-screen television?
A.106.75
B.213.5
C.427
D.729
Answer: C.427
Explanation: Diagonal of a square =√2*side of square
=> side =Diagonal/(√2)
Area of square =s*s
=(diagonal^2)/2
Difference of both tv's =(34^2-27^2)/2
=427
ANSWER:C
Question: Equal amount of water were poured into two empty jars of different capacities, which made one jar 1/3 full and other jar 1/2 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water?
A.2/3
B.2/7
C.1/2
D.7/12
Answer: A.2/3
Explanation: Same amount of water made bigger jar 1/3 full, thenthe same amount of water(stored for a while in smaller jar) were added to bigger jar, so bigger jar is 1/3+1/3=2/3 full.
Answer: A.
Question: A can do a job in 20 days and B can do it in 30 days. A and B working together will finish twice the amount of work in ------- days?
A.14 days
B.16 days
C.24 days
D.11 days
Answer: C.24 days
Explanation: C
1/20 + 1/30 = 1/12
12 *2 = 24 days
Question: A man travels from A to B at a speed of 30 kmph and returns with a speed of 60 kmph. What is the average speed of the man?
A.47.5
B.50
C.45
D.40
Answer: D.40
Explanation: Explanation:
The average speed ‘v’, when a man travels two same distance with different speeds ‘v1’ and ‘v2’ is:
v = (2*v1*v2) / (v1 + v2)
In the above problem, v1 = 30 and v2 = 60
Therefore, v = (2*30*60)/(30 + 60) = 3600/90
v = 40
ANSWER D
Question: Ram and Raj start a business with investments of Rs. 2500 and Rs. 2250 respectively. After 2 months, Ram takes out Rs.1250 from his capital. After 1 more month, Raj takes out Rs.750 of his capital while Rakesh joins them with a capital of Rs. 3500. At the end of 6 months, they earn a profit of Rs. 2540. Which of the following is the share of each member in the profit ?
A.Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840
B.Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 821
C.Ram - Rs. 800, Raj - Rs. 200, Rakesh - Rs. 840
D.Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 811
Answer: A.Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840
Explanation: Initial investment of Ram = Rs.2500.
After 2 months he withdraw Rs.1250 from his capital.
Therefore, we have, Ram invested Rs.2500 for 2 months and Rs.(2500-1250=) 1250 for 4 months.
Raj invested Rs. 2250 for 3 months and Rs.(2250-750=) 1500 for 3 months.
And, Rakesh invested Rs.3500 for 3 months;
Their investing ratio:
Ram:Raj:Rakesh = (2500x2 + 1250x4):(2250x3 + 1500x3):(3500x3)
= (10,000):(11,250):(10,500) = 1000:1125:1050 = 40:45:42
Total profit for 6 months = Rs.2540
Therefore, Ram's share = Rs.(2540 x 40/(40+45+42)) = Rs.(2540 x 40/127) = Rs.800
Raj's share = Rs.(2540 x 45/127) = Rs.900
Rakesh's share = Rs.(2540 x 42/127) = Rs.840
Answer: A
Question: In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 5:6:2. If there are in all Rs.42, the number of 25 paisa coins is?
A.76
B.42
C.17
D.14
Answer: B.42
Explanation: 5x 6x 2x
50 25 100
250x + 150x + 200x = 4200
600x = 4200
x = 7 => 6x = 42
Answer:B
Question: The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.216. Find the principal?
A.2277
B.2667
C.5400
D.2766
Answer: C.5400
Explanation: P = 216(100/5)^2 => P = 5400
Answer: C
Question: The shopkeeper increased the price of a product by 25% so that customer finds difficult to purchase the required amount. But Somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product ?
A.55 more
B.10% more
C.12.5% less
D.17.5% less
Answer: C.12.5% less
Explanation: Solution: Let initially the quantity and rate be 100 each.
Quantity*rate = Expenditure
100*100 = 10000
Now, Increase in price is 25% and new quantity is 70% of original.
Quantity*rate = Expenditure
70*125 = 8750
Decreased expenditure,
= 10000-8750 = 1250
% decrease,
= (1250*100)/10000
= 12.5%.
Answer: Option C
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are drawn what is the probability that one is yellow and two are red?
A.12/455
B.24/455
C.3/91
D.15/91
Answer: A.12/455
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
When three marbles are drawn, the probability that one is yellow and two are red
= (²C₁)(⁴C₂)/¹⁵C₃
= (2 * 4 * 3 * 3 * 2)/(1 * 2 * 15 * 14 * 13) = 12/455
A)
Question: Audrey 4 hours to complete a certain job. Ferris can do the same job in 3hours. Audrey and Ferris decided to collaborate on the job, working at their respective rates. While Audrey worked continuously, Ferris took 6 breaks of equal length. If the two completed the job together in 2 hours, how many minutes long was each of Ferris’ breaks ?
A.2
B.5
C.15
D.20
Answer: B.5
Explanation: Audery and Ferris collective Work rate:
1/4 + 1/3 = 7/12
Collective work Time = 12/7 = 1.7 Hrs
Job Was actually done in = 2 (Includes breaks)
Breaks = Actual time taken - Collective work time
= 2 - 1.7
= .3 Hrs = 1/2
so ferrais took 6 breaks
=.3/6=.06 hrs = 5 m
so Answer is B) 10 mins
Question: There are eight leopards and one sheep.
Leopard can eat sheep but since as the land is magical, the leopards who eats the sheep , turns into sheep and then can be eaten by the remaining leopard(s).
If we leave them for some time then how many sheep and leopard will be there , when we come back ?
A.7 leopard and 1 sheep
B.4 leopard and 7 sheep
C.6 leopard and 4 sheep
D.5 leopard and 1 sheep
Answer: A.7 leopard and 1 sheep
Explanation: A
7 leopard and 1 sheep
since all animal are rational , once 1st leopard eats the sheep all the rest of leopard would know about this.
Question: X starts a business with Rs.52000. Y joins in the business after 6 months with Rs.26000. What will be the ratio in which they should share the profit at the end of the year?
A.1:2
B.2:3
C.1:3
D.4:1
Answer: D.4:1
Explanation: Explanation :
Ratio in which they should share the profit
= Ratio of the investments multiplied by the time period
= 52000 * 12: 26000 * 6
= 52 * 12: 26 * 6
= 24:6
= 4:1. Answer : Option D
Question: Positive integer n leaves a remainder of 2 after division by 6 and a remainder of 3 after division by 5. If n is greater than 30, what is the remainder that n leaves after division by 30?
A.3
B.12
C.18
D.22
Answer: B.12
Explanation: The theory says:
if a # x is devided by y and leave the positive # r as the remainder then it can also leave negative # (r-y) as the remainder.
e.g:
9 when devided by 5 leves the remainder 4 : 9=5*1+4
it can also leave the remainder 4-5 = -1 : 9=5*2 -1
back to the original qtn:
n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5
==> n leaves a remainder of -2 (i.e. 4-6) after division by 6 and a remainder of -2 (i.e. 3-5) after division by 5
==> n when devided by 5 and 6 leaves the same remainder -2.
what is n?
LCM (5,6)-2 = 30-2 = 28
CHECK: 28 when devided by 6 leaves the remainder 4 and when devided by 5 leaves the remainder 3
However, the qtn says n > 30
so what is the nex #, > 28, that can give the said remainders when devided by 6 and 5
nothing but 28 + (some multiple of 6 and 5) as thissome multiple of 6 and 5will not give any remainder when devided by 5 or 6 but 28 will give the required remainders.
hence n could be anything that is in the form 28 + (some multiple of 6 and 5)
observe thatsome multiple of 6 and 5is always a multiple of 30 as LCM (5,6) = 30.
hence when n (i.e. 28 + some multiple of 6 and 5) is devided by 30 gives the remainder 12.
B
Question: Out of 40 consecutive integers, two are chosen at random. Find the probability that their sum is odd?
A.21/40
B.19/39
C.21/39
D.20/39
Answer: D.20/39
Explanation: Explanation :
Forty consecutive integers will have 20 even and 20 odd integers. The sum of 2 chosen integers will be odd, only if:
First is even and second is odd
First is odd and second is even
Mathematically the probability will be given by:
P(First is even) * P(Second is odd) + P(First is odd) * P(Second is even)
= (20/40) * (20/39) + (20/40) * (20/39)
= 20/39
Answer : D
Question: At what price must an article costing Rs.47.50 be marked in order that after deducting 9% from the list price. It may be sold at a profit of 25% on the cost price?
A.65.25
B.62.6
C.62.1
D.62.7
Answer: A.65.25
Explanation: CP = 47.50
SP = 47.50*(125/100) = 59.375
MP*(91/100) = 59.375
MP = 65.25
Answer: A
Question: A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
A.2.91 m
B.3 m
C.5.82 m
D.6.72 m
Answer: B.3 m
Explanation: Explanation:
Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
Answer: B
Question: Two trains of equal lengths take 8 sec and 15 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
A.10.4
B.12
C.13
D.14
Answer: A.10.4
Explanation: Speed of the first train = 120/8 = 15 m/sec.
Speed of the second train = 120/15 = 8 m/sec.
Relative speed = 15 + 8 = 23 m/sec.
Required time = (120 + 120)/23 = 10.4 sec.
Answer: Option A
Question: The square root of 25=5. What does the square root of a multiple of 25 has to end in for it to be a correct square root?
A.1 or 0
B.5 or 3
C.5 or 0
D.4 or 0
Answer: C.5 or 0
Explanation: Any multiple of 5 has to end in a 5 or a 0
Ex) 10 is a multiple of 5 because it ends in a 5
Ex2) 5*8=40, which means that 40 is a multiple of 5 because it ends in a 0
Correct answer is (C)
Question: A student scored an average of 70 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics?
A.130
B.120
C.110
D.180
Answer: C.110
Explanation: Given M + P + C = 70 * 3 = 210 --- (1)
M + P = 90 * 2 = 180 --- (2)
P + C = 70 * 2 = 140 --- (3)
Where M, P and C are marks obtained by the student in Mathematics, Physics and Chemistry.
P = (2) + (3) - (1) = 180 + 140 - 210 = 110
ANSWER:C
Question: A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 100, the runs scored by B are?
A.24
B.18
C.13
D.17
Answer: A.24
Explanation: A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 100 = 24
Answer:A
Question: Jennifer had $90 to spend on herself. She spent 1/5 of the money on a sandwich, 1/6 for a ticket to a museum, and 1/2 of it on a book. How much money does Jennifer have left over?
A.$12
B.$14
C.$5
D.$15
Answer: A.$12
Explanation: 1/5 x $90 = $15 for sandwich
1/6 x $90 = $45 for museum
1/2 x $90 = $78 for book
$15 + $45 + $18 = $78 spent
$90 - $78= $12 left over
correct answer A
Question: What will be the vulgar fraction of 0.75
A.3/5
B.3/4
C.3/2
D.3/7
Answer: B.3/4
Explanation: Explanation:
0.75 = 75/100 = 3/4
Option B
Question: If five men together completes a job in 5 days then for the same job how many mens are required to complete it in a day.
A.20
B.10
C.25
D.15
Answer: C.25
Explanation: work completed in a day by one men = 1/25 = (1/5)*(1/5)
So it takes 25 men to complete this job = 25 * (1/25) = 1
Answer: C
Question: A and B enter into partnership. A supplies whole of the capital amounting to Rs. 45000 with the condition that the profits to be equally divided and that B pays A interest on half of the capital at 10% per annum, but receives Rs. 120 per month for carrying on the concern.Find their total yearly profit when B's income is one half of A's income.
A.2238
B.9180
C.2889
D.2780
Answer: B.9180
Explanation: Let the total profit be Rs. x
Amount paid to B as salary = (120 x 12)
= Rs.1440
Share of each = \inline (\frac{x-1440}{2})
Interest paid by B = \inline \frac{22500\times 10}{100}=Rs.2250
Total money received by A = \inline \frac{x-1440}{2}+2250
= Rs.\inline (\frac{x+3060}{2})
Total money received by B
\inline [(\frac{x-1440}{2})+1440-2250]= (\frac{x-3060}{2})
\inline \Rightarrow \frac{1}{2}-(\frac{x+3060}{2})-(\frac{x-3060}{2})
\inline \Rightarrow x=9180
Answer:B
Question: A 220 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
A.280
B.270
C.260
D.250
Answer: A.280
Explanation: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 220)/9 = 500/9 => x = 280.
Answer: Option A
Question: If Jack walked 8 miles in 1 hour and 15 minutes, what was his rate of walking in miles per hour?
A. 4
B. 4.5
C. 6
D. 6.4
Answer: D. 6.4
Explanation: Distance walked in 1 hour and 15 mins = 8 miles
Speed per hour = Distance/Time = 8/(5/4) = 6.4 miles per hour
Answer D
Question: The average of first ten prime numbers which are odd is?
A.15.5
B.15.0
C.15.9
D.15.8
Answer: D.15.8
Explanation: Sum of first 10 prime no. which are odd = 158
Average = 158/10 = 15.8
Answer:D
Question: There are some pigeons and hares in a zoo. If heads are counted, there are 140. If legs are counted, there are 580. The number of hares in the zoo is?
A.120
B.182
C.190
D.150
Answer: D.150
Explanation: 140*2 = 280
580
-----
300
1----2
?----300 = 150
Answer:D
Question: If a population of women in a town is 40% of men . What is the population of men as a % of population of women ?
A.A)200%
B.B)100%
C.C)50%
D.D)65%
Answer: A.A)200%
Explanation: We're told that the number of Women in a town is equal to 40% of the number of Men in that town.
IF....
Men = 10
Women = 4
We're asked for the number of Men, as a percentage of the number of Women.
M/W = 10/4=5/ 2 = 250%
Answer is A
Question: How can you get 81 using the digits 2, 3, 25, 50, 75, 100 only once using any of the arithmetic operators?
A.81
B.82
C.87
D.98
Answer: A.81
Explanation: since 3^2 = 9 and 9^2 = 81,
ie , (3^2)^2 = 81
(3*3)^2 = 81
so,
[3*{(100+50-75)/25}]^2 = 81
ANSWER:A
Question: John walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 8 minutes earlier. How far is the office from his house?
A.3 2/5 Km
B.3 1/5 Km
C.4 1/5 Km
D.5 1/5 Km
Answer: B.3 1/5 Km
Explanation: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 16/6
= 24/2 * 16/60
= 8 * 2/5
= 16/5 = 3 1/5 Km
B
Question: A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
A.767 m
B.240 m
C.187 m
D.176 m
Answer: B.240 m
Explanation: Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x = 240 m.
Answer:B
Question: There is a 50% chance Jen will visit Chile this year, while there is a 25% chance that she will visit Madagascar this year. What is the probability that Jen will visit either Chile or Madagascar this year, but NOT both?[/b]
A.25%
B.50%
C.62.5%
D.63.5%
Answer: B.50%
Explanation: The thing to note in the question is she would not be visiting both.
Thus p(Chile)*(1-p(Madagascar))+p(Madagascar)*(1-p(Chile))
which is
(1/2*3/4) + (1/4*1/2),
3/8*1/8=1/2 =50%
Answer: B
Question: Simple interest on a certain sum of money for 2 years at 12% per annum is half the compound interest on Rs. 6000 for 2 years at 15% per annum. The sum placed on simple interest is
A.Rs.6000
B.Rs.7935
C.Rs.8265.63
D.Rs.3967.5
Answer: C.Rs.8265.63
Explanation: Solution
C.I.	=Rs[6000x(1+15/100)Â²-4000]
Rs.(4000x115/100x115/100-6000)	= Rs.7935.
Sum	=Rs. [3967.5x100 /4x12]
= Rs.8265.63.
Answer C
Question: What is the smallest integer that is the sum of 2 distinct prime integers, each greater than 60 ?
A.170
B.128
C.173
D.129
Answer: B.128
Explanation: A prime number (or a prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself. Here are the first few prime numbers: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, etc.
Immediate two prime numbers after 60 are - 61 and 67
Sum = 61 + 67 = 128
Answer - B
Question: Find compound interest on Rs. 8000 at 15% per annum for 2 years 4 months, compounded annually
A.3489
B.3109
C.2788
D.2776
Answer: B.3109
Explanation: Explanation:
Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.
Amount = Rs'. [8000 X (1+(15/100))^2 X (1+((1/3)*15)/100)]
=Rs. [8000 * (23/20) * (23/20) * (21/20)]
= Rs. 11109. .
:. C.I. = Rs. (11109 - 8000) = Rs. 3109.
Answer: B) 3109
Question: The average consumption of petrol for a car for seven months is 110 litres and for next five months it is 86 litres. The average monthly consumption is ?
A.96 litres
B.98 litres
C.100 litres
D.102 litres
Answer: C.100 litres
Explanation: Answer
Average = ( sum of consumption of petrol in first 7 months + sum of consumption of petrol in last 5 months. ) / 12
Average = ( 110 x 7 + 86 x 5 ) / 12
=(1200 / 12 = 100 liters
Correct Option: C
Question: A train which has 430 m long, is running 45 kmph. In what time will it cross a person moving at 9 kmph in same direction ?
A.56 sec
B.43 sec
C.36 sec
D.29 sec.
Answer: B.43 sec
Explanation: Time taken to cross a moving person = length of train/ relative speed
Time taken = 430/((45-9) (5/18)
= 430/ 36*(5/18)
= 430/10
= 43 sec
ANSWER:B
Question: Tough and Tricky questions: Arithmetic.
(18^2 + 18^2)/6^2 =
A.4
B.8
C.27
D.58
Answer: C.27
Explanation: Ans is 27
my approach was:
(18^2 + 18^2)/6^2 =18(18+18)/6*6
=18*36/6*6=3*9=27
C
Question: Proportion of Yuvaraj’s age to Ganguly’s age is 4:3. Yuvaraj willl be 26 years old after 6 years. What is the age of Ganguly now ?
A.17 years
B.15 years
C.19 years
D.12 years
Answer: B.15 years
Explanation: Explanation:
Current ages of Yuvaraj = 4A and Ganguly = 3A
So that 4A + 6 = 26
A = 5
Current age of Ganguly = 3A
=> 3 x 5 = 15 years. Answer: B
Question: In a class of 78 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course?
A.26
B.27
C.24
D.18
Answer: C.24
Explanation: Explanation:
You could solve this by drawing a Venn diagram. A simpler way is to realize that you can subtract the number of students taking both languages from the numbers taking French to find the number taking only French. Likewise find those taking only German. Then we have:Total = only French + only German + both + neither
78 = (41-9) + (22-9) + 9 + neither.
Not enrolled students = 24
Answer: C
Question: The area of a square is equal to five times the area of a rectangle of dimensions 50 cm * 10 cm. What is the perimeter of the square?
A.289 cm
B.200 cm
C.829 cm
D.288 cm
Answer: B.200 cm
Explanation: Area of the square = s * s
= 5(50 * 10)
=> s = 50
= 50 cm
Perimeter of the square
= 4 * 50
= 200 cm.
Answer: B
Question: A can give B 50 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?
A.157.89
B.157.13
C.157.22
D.111.0
Answer: A.157.89
Explanation: A runs 1000 m while B runs 950 m and C runs 800 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 800)/950
= 842.10 m.
B can give C = 1000 - 842.10
=157.89m.
Answer:A