RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What is the probability of getting a sum 9 from two throws of a dice?
A.1/6
B.1/9
C.1/8
D.5/8
Answer: B.1/9
Explanation: In two throws of a dice, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
P(E)=n(E)/n(S)
=4/36
=1/9
The answer should be B
Question: A shopkeeper purchased 70 kg of potatoes for Rs. 420 and sold the whole lot at the rate of Rs. 6.70 per kg. What will be his gain percent?
A.8 1/7 %
B.2 1/3 %
C.11 2/3 %
D.8 1/8 %
Answer: C.11 2/3 %
Explanation: C.P. of 1 kg = 420/70 = Rs. 6
S.P. of 1 kg = Rs. 6.70
Gain % = 0.70/6 * 100 = 35/3
= 11 2/3 %
Answer:C
Question: There are 20 brown dogs, 10 white dogs, 15 black dogs.Totally how many dogs are there in all?
A.45
B.15
C.25
D.5
Answer: A.45
Explanation: 20+10+15=45. Answer is A
Question: A goods train runs at the speed of 72 km/hr and crosses a 270 m long platform in 26 sec. What is the length of the goods train?
A.278
B.166
C.151
D.250
Answer: D.250
Explanation: Speed = 72 * 5/18 = 20 m/sec.
Time = 26 sec.
Let the length of the train be x meters.
Then, (x + 270)/26 = 20
x = 250 m.
Answer:D
Question: A, B and C rent a pasture. A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing. If the rent of the pasture is Rs. 175, how much must C pay as his share of rent?
A.45
B.50
C.55
D.65
Answer: A.45
Explanation: Sol.
A : B : C = 10 * 7 : 12 * 5 : 15 * 3 = 70 : 60 : 45 = 14 : 12 : 9.
∴ C’s rent = Rs. [175 * 9/35] = Rs. 45.
Answer A
Question: In how many different ways can the letters of the word 'LEADING' be arranged in such a way that the vowels always come together?
A.720 ways
B.735 ways
C.767 ways
D.723 ways
Answer: A.720 ways
Explanation: The word 'LEADING' has 7 different letters.
When the vowels EAI are always together, they can be supposed to form one letter.
Then, we have to arrange the letters LNDG (EAI).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (120 x 6) = 720.
Answer:A
Question: A rectangular farm has to be fenced one long side, one short side and the diagonal. If the cost of fencing is Rs.13 per meter. The area of farm is 1200 m2 and the short side is 30 m long. How much would the job cost?
A.1276
B.1560
C.2832
D.1299
Answer: B.1560
Explanation: Explanation:
l * 30 = 1200 è l = 40
40 + 30 + 50 = 120
120 * 13 = 1560
Answer: Option B
Question: Difference between the length &breadth of a rectangle is 10 m. If its perimeter is 60 m, then its area is??
A.2000 m^2
B.200 m^2
C.2520 m^2
D.2556 m^2
Answer: B.200 m^2
Explanation: l -b = 10
2 (l+b)= 60 => l + b = 30
2 l = 40 => l = 20 so b = 10
area of the rectangle = l x b = 20 x 10 = 200 m^2
Answer : B
Question: In how many ways Chief Minister and Minister be elected from a team of 12 members?
A.124
B.129
C.132
D.142
Answer: C.132
Explanation: To do this, if captain is elected first, then we have 12 ways of doing this.
For election of vice-captain, we have only 11 ways left, coz 1 way is already consumed. (Situations like this is called dependent situation. One selection depends upon other selection.)
So, the ans is 12*11 = 132 ways.
C
Question: Shawn invested one half of his savings in a bond that paid simple interest for 2 years and received $550 as interest. He invested the remaining in a bond that paid compound interest, interest being compounded annually, for the same 2 years at the same rate of interest and received $605 as interest. What was the value of his total savings before investing in these two bonds?
A.$5500
B.$11000
C.$22000
D.$2750
Answer: D.$2750
Explanation: Explanatory Answer
Shawn received an extra amount of ($605 - $550) $55 on his compound interest paying bond as the interest that he received in the first year also earned interest in the second year.
The extra interest earned on the compound interest bond = $ 55
The interest for the first year = $550/2 = $ 275
Therefore, the rate of interest = (55/275)*100 = 20% p.a.
20% interest means that Shawn received 20% of the amount he invested in the bonds as interest
If 20% of his investment in one of the bonds = $275, then his total investment in each of the bonds = (275/20)*100 = $ 1375
As he invested equal sums in both the bonds, his total savings before investing = 2*1375 = $ 2750.
correct choice is (D)
Question: How is 4% expressed as a decimal fraction?
A.0.4
B.0.04
C.0.004
D.0.0004
Answer: B.0.04
Explanation: 4/100= 0.04
ANSWER:B
Question: Adam sat with his friends in the Chinnaswamy stadium at Madurai to watch the 100 metres running race organized by the Asian athletics Association. Five rounds were run. After every round half the teams were eliminated. Finally, one team wins the game. How many teams participated in the race?
A.32
B.77
C.279
D.27
Answer: A.32
Explanation: Total five rounds were run. So in the final round 2 teams must have participated. In the penultimate round 4 teams, and 3rd round 8, 2nd round 16 and in the first round 32 teams must have participated as in each round half of the teams got eliminated.
Answer:A
Question: In how many ways can a committee of 4 people comprising at least 3 boys be formed using a group of 4 boys and 6 girls?
A.67
B.64
C.65
D.66
Answer: B.64
Explanation: There are 2 options: the selected groups have no girls or one girls.
-First case: 1 girl + 3 boys: 6C1 * 5C3 = 6*10 = 60
-Second case: 4 boys: 5C4 = 5
So there are 60 + 5 = 64 ways in total.
B
Question: A sporting goods store sold 64 Frisbees in one week, some for $3 and the rest for $4 each. If receipts from Frisbee sales for the week totaled $204, what is the fewest number of $3 Frisbees that could have been sold?
A.24
B.12
C.8
D.52
Answer: D.52
Explanation: In this question however, because we are told that exactly 64 Frisbees have been sold and revenue was exactly $204, there is only one possible solution for the number of $3 and $4 Frisbees sold.
To solve, we have 2 equations and 2 unknowns
Let x = number of $3 Frisbees sold
Let y = number of $4 Frisbees sold
x + y = 64
3x + 4y = 204
x = 64 - y
3(64-y) + 4y = 204
192 - 3y + 4y = 204
y = 12 x= 64-12= 52
D
Question: water is continuously poured from a reservoir to a locality at the steady rate of 10,000 liters per hour. When delivery exceeds demand the excess water is stored in a tank. If the demand for 8 consecutive three-hour periods is 10000,10000,45000,25000,40000,15000,60000 and 35000 liters respectively, what will be the minimum capacity required of the water tank (in 1000 litres) to meet the demand?
A.20
B.30
C.40
D.50
Answer: C.40
Explanation: in the period of first 3 hrs, the demand of water = 10000.
but the water poured by 10000 per hour.
Thus the end of 3 hours it will poured 30000 ltr then the excess of water = 20000.
Similarly at the end of 2nd 3 hr period the excess of water 20000+20000 = 40000.
Third, 3 hrs water poured = 30000
already we have 40000 of excess water and demand 45000.
Then the excess water at the end of 3rd 3 hrs
= 40000+30000–45000
= 25000
Fourth 3 hrs. water = 25000+30000–25000
= 30000
Fifth = 30000+30000–40000
= 20000
Sixth = 20000+30000–15000=35000
Seventh = 35000+30000–60000
= 5000
Eighth = 5000+30000–35000
= 0
By analyzing the above results, we have 40000 ltrs is the highest measure of excess water.
So the minimum capacity of water tank = 40000 litres = 40
i.e. = 40
ANSWER:C
Question: If an article is sold at 18% profit instead of 11% profit, then the profit would be $56 more. What is the cost price?
A.$600
B.$800
C.$1000
D.$1200
Answer: B.$800
Explanation: 7% * cost price = $56
1% * cost price = $56 / 7 = $8
The cost price is $800.
The answer is B.
Question: If the tens digit of positive integers x, y are 6, how many values of the tens digit of 2(x+y) can be there?
A.2
B.3
C.4
D.5
Answer: C.4
Explanation: If X=y=60, 2(x+y)=240 is derived. If x=y=69, 2(x+y)=276 is derived, which makes 4,5,6,7 possible for the tens digit. Therefore, the answer is C.
Question: Three-fourth of a positive number and 25/216 of its reciprocal are equal. The number is:
A.5/12.72
B.12/5
C.25/144
D.144/25
Answer: A.5/12.72
Explanation: Let the number be x. Then,
3/4 x = 25/216 * 1/x
x2 = 25/216 * 4/3 = 25/162
x = 5/12.72
ANSWER:A
Question: The guidelines at a certain college specify that for the introductory English class, the professor may choose one of six specified novels, and choose two plays from a list of 6 specified plays. Thus, the reading list for this introductory class has one novel and two plays. How many different reading lists could a professor create within these parameters?
A.60
B.70
C.80
D.90
Answer: D.90
Explanation: 6C1*6C2 = 6*15 = 90
The answer is D.
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
A.Rs.4589
B.Rs.4528
C.Rs.4528
D.Rs.4530
Answer: D.Rs.4530
Explanation: Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5 = Rs.4530
Answer:D
Question: In N is a positive integer less than 200, and 27N/60 is an integer, then N has how many different positive prime factors?
A.2
B.3
C.5
D.6
Answer: A.2
Explanation: (A).
27n/60 must be an integer. => 9n/20 must be an integer. Hence n must be a multiple of 2*5.
=> n has 2 different prime integers.
Question: Adding 20% of x to x is equivalent to multiplying x by which of the following?
A.12.5
B.1.05
C.1.15
D.1.2
Answer: D.1.2
Explanation: 120x/100= 1.2*x
ANSWER:D
Question: Dan has a membership at a local gym that also gives classes three nights a week. On any given class night, Dan has the option of taking yoga, weight training, or kickboxing classes. If Dan decides to go to either one or two classes per week, how many different combinations T of classes are available?
A.3
B.T=6
C.T=7
D.T=9
Answer: D.T=9
Explanation: I think it should be E only.
No where it is given that he attends different classes on each day.
Experts please provide your views.
--- EDITED my Response. It was a typo. I meant 12 is the answer.
If only Day 1 : 3 options
If Day 1 and Day 2 : 3*3 = 9 Options
So, Total = 3+9= 12.
Question: How many different possible arrangements A can be obtained from the letters G, M, A, T, I, I, and T, such that there is at least one character between both I's?
A.360
B.720
C.900
D.1800
Answer: C.900
Explanation: Total ways for arranging without restriction = 7!/ (2!2!) { 2! is becoz of two T's and other 2! for two I's)
Restriction : atleast one character between I's = Possible ways - both I's together i.e.o character between I's
_ _ _ _ _ (I I)
Both I's Together = 6! (Assuming 2 I's as one unit) /2!(for 2 T's) * 2! (No of arrangements of 2 I's)/2! (for 2 I's)
=6!/2!
Therefore ans A= 7!/ (2!2!) -6!/2! = 900
HENCE C.
Question: Find the simple interest on Rs.500 for 9 months at 6 paisa per month?
A.278
B.270
C.876
D.279
Answer: B.270
Explanation: I = (500*9*6)/100
= 270
Answer: B
Question: . Ram sold two bicycles, each for Rs.990. If he made 10% profit on the first and 10% loss on the second, what is the total cost of both bicycles?
A.2000
B.2009
C.2007
D.20054
Answer: A.2000
Explanation: (10*10)/100 = 1%loss
100 --- 99
? --- 1980 => Rs.2000
Answer: A
Question: At 6′o a clock ticks 6 times. The time between first and last ticks is 20 seconds. How long does it tick at 12′o clock
A.47
B.76
C.44
D.66
Answer: C.44
Explanation: Explanation:
For ticking 6 times, there are 5 intervals.
Each interval has time duration of 20/5 = 4 secs
At 12 o'clock, there are 11 intervals,
So total time for 11 intervals = 11 × 4 = 44 secs.
Answer: C
Question: How much 50% of 56 is greater than 30% of 50?
A.18
B.99
C.13
D.55
Answer: C.13
Explanation: (50/100) * 56 – (30/100) * 50
28 - 15 = 13
Answer: C
Question: A and B together can do a work in 6 days. If A alone can do it in 15 days. In how many days can B alone do it?
A.10
B.15
C.12
D.16
Answer: A.10
Explanation: Explanation:
1/6 â€“ 1/15 = 1/10 => 10
ANSWER IS A
Question: The closest approximation of F(69.28 × 0.004)/0.03 is
A.0.092
B.0.92
C.9.2
D.92
Answer: C.9.2
Explanation: F(69.28 × 0.004)/0.03
1. 0.004 = 4 × 10^(-3)
2. 0.03 = 3 × 10^(-2)
3. (a × b)/c = a × (b/c)
4. 0.004/0.03 = 4 × 10^(-3)/ (3 × 10^(-2)) = 4 × 10^( -3 - (-2))/3 = 4 × 10^(-1) / 3 = (4/3) × 10^(-1) = 1.333 × 10^(-1)
Therefore,
(69.28 × 0.004)/0.03 = 69.28 × (0.004/0.03) = 69.28 × 1.33 × 10^(-1) = 69.28 × 1.33/10 = 6.928*1.33
Now,
7 × 2 = 14
7 × 1 = 7
or better:
6.9 × 1 = 6.9
6.9 × 2 = 13.8
hence,
6.9 <6.928 × 1.33 < 13.8
9.2 is the only answer that satisfies this condition.C
Question: The number of natural numbers n such that (n+1)^2/(n+7) is an integer, is ?
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: we can use (n+1)^2 greater than (n+7) which gives n>2,-3........now there are four integers -2.-1,0,1 in between -3 and 2.
so answer is 4.
ANSWER:A
Question: Mary, Peter, and Lucy were picking chestnuts. Mary picked twice as much chestnuts than Peter. Lucy picked 2 kg more than Peter. Together the three of them picked 26 kg of chestnuts. How many kilograms did each of them pick?
A.5, 12, and 8 kg
B.6, 12, and 8 kg
C.7, 12, and 8 kg
D.8, 12, and 8 kg
Answer: B.6, 12, and 8 kg
Explanation: Solution:
Let x be the amount Peter picked. Then Mary and Lucy picked 2x and x+2x+2, respectively. So
x+2x+x+2=26
4x=24
x=6
Therefore, Peter, Mary, and Lucy picked 6, 12, and 8 kg, respectively.
Answer B
Question: If a = 105 and a^3= 21 * 25 * 315 * b, what is the value of b?
A.35
B.7
C.45
D.49
Answer: B.7
Explanation: First step will be to break down all the numbers into their prime factors.
105 = 3 * 5 * 7
21 = 7 * 3
25 = 5 * 5
315 = 3 * 3 * 5*7
so, (105)^3 = 3 * 7 * 5 * 5 * 3 *3 *5*7 *b
Therefore (3 * 5 * 7) ^ 3 = 3^3 * 5^3 * 7^2 *b
Therefore, b = 3^3 * 5^3 * 7 ^3/3 ^3 * 5 ^3 * 7^2
b = 7
Correct answer B.
Question: A chair is bought for Rs.600/- and sold at a loss of 10% find its selling price?
A.Rs.540/-
B.Rs.560/-
C.Rs.580/-
D.Rs.590/-
Answer: A.Rs.540/-
Explanation: 100 % ------> 600 (100 * 6 = 600)
90 % ------> 540 (90 * 6 = 540)
Selling price = Rs.540/-
Option 'A'
Question: A single discount equivalent to the discount series of 15%, 10% and 5% is?
A.27.325
B.31.0
C.31.6
D.31.1
Answer: A.27.325
Explanation: 100*(85/100)*(90/100)*(95/100)
= 68.4
100 - 72.675 = 27.325
Answer: A
Question: If n is a prime number, which of the following could be true
A.n^n=n
B.n^2/4= is even
C.(n)(n^n) = is negative
D.n^n/4 = 1^(n-1)
Answer: D.n^n/4 = 1^(n-1)
Explanation: D should be the answer.
2^2/4 = 1^(2-1)
Question: What is the product of the greatest 2 digit multiple of 13 and the greatest 2 digit prime number?
A.9,312
B.9,408
C.9,506
D.8,827
Answer: D.8,827
Explanation: the greatest 2 digit multiple of 13: 91
the greatest 2 digit prime numebr: 97
97*91.
8827
D
Question: In the rectangular coordinate system, what is the area of triangle CDE with points
C=(3,3)
D=(1,4)
E=(8,0)
A.0.6
B.0.75
C.0.9
D.0.5
Answer: D.0.5
Explanation: Use the formula of the distance formula
square root (x2-x1)^2+(y2-y1)^2
Do this for each of the sides and then the value is given as D.
Question: H, Be, F, S, Mn, Kr, In, Gd, Tl, ?
What's the next in the sequence ?
A.Fm
B.Ks
C.gh
D.kl
Answer: A.Fm
Explanation: A
Fm.
These are the chemical elements whose atomic numbers are perfect squares.
1, 4, 9, 16, 25, 36, 49, 64, 81, 100
Question: Pipe A can fill a tank in 12 hours. Due to a leak at the bottom, it takes 18 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank?
A.36
B.87
C.40
D.37
Answer: A.36
Explanation: Let the leak can empty the full tank in x hours 1/12 - 1/x = 1/18
=> 1/x = 1/12 - 1/18 = (3 - 2)/36 = 1/36
=> x = 36.
Answer: A
Question: A man has Rs. 160 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
A.45
B.60
C.30
D.90
Answer: C.30
Explanation: Let number of notes of each denomination be x.
Then x + 5x + 10x = 160
16x = 160
x = 10.
Hence, total number of notes = 3x = 30.
Answer: Option C
Question: A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water in ?
A.10hr
B.14hr
C.12hr
D.9hr
Answer: B.14hr
Explanation: Work done by the leak in 1 hour = 1/2 - 3/7 = 1/14
Leak will empty the tank in 14 hrs
Answer is B
Question: Two trains are running in opposite directions in the same speed. The length of each train is 120 meter. If they cross each other in 12 seconds, the speed of each train (in km/hr) is
A.42
B.36
C.28
D.20
Answer: B.36
Explanation: Explanation:
Distance covered = 120+120 = 240 m
Time = 12 s
Let the speed of each train = v. Then relative speed = v+v = 2v
2v = distance/time = 240/12 = 20 m/s
Speed of each train = v = 20/2 = 10 m/s
= 10×36/10 km/hr = 36 km/hr
Answer: Option B
Question: If 5a + 7b = l, where a and b are positive integers, what is the largest possible value of l for which exactly one pair of integers (a, b) makes the equation true?
A.35
B.48
C.69
D.70
Answer: D.70
Explanation: 5*a1 + 7*b1 = l
5*a2 + 7*b2 = l
5*(a1 - a2) = 7*(b2 - b1)
since we are dealing with integers we can assume that a1 - a2 = 7*q and b2 - b1 = 5*q where q is integer, so whenever we get a pair for (a;b) we can find another one by simply adding 7 to a and subtracting 5 from b or vice versa, subtracting 7 from a and adding 5 to b.
Lets check how it works for our numbers, starting from the largest:
E)74 = 5*12 + 7*2 (a1 = 12, b1 = 2), subtract 7 fromaand add 5 tobrespectively, so a2 = 5 and b2 = 7, second pair - bad
D)70 = 5*7 + 7*5 (a1 = 7, b1 = 5), if we add 7 toawe will have to subtract 5 from b but b can't be 0, so - no pair, if we subtract 7 froma, we'll get a = 0 which also isn't allowed - no pair, thus this is the only pair for (a;b) that works,good!, thus
D is the answer
Question: 6 boys and 4 girls appeared in a exam. If 4 students are failed how many chances at least one girl is failed?
A.198
B.200
C.190
D.195
Answer: D.195
Explanation: 4 girls and 6 boys. Four students is failed
It is always better to subtract the total from none in case of at least one problems.
Total ways = 10C4 = 210
Total ways without any girls = 6C4 = 15
Hence ways in which at least one man will be present = 210 - 15 = 195
Correct option: D
Question: A motor pool has 800 vehicles of which 30 percent are trucks. 20 percent of all the vehicles in the motor pool are diesel, including 15 trucks. What percent of the motor pool is composed of vehicles that are neither trucks nor diesel?
A.65%
B.52%
C.45%
D.30%
Answer: B.52%
Explanation: Trucks = 30% of 800 = 240
Other Vehicles (Excluding Trucks) = 800-240 = 560
Diesel Vehicle = 20% of 800 = 160 (Including 15 Trucks)
Other Diesel Vehicles (Excluding Trucks) = 160-15 = 145
Trucks that are NOT diesel = 240 - 15 = 225
Other Vehicles that are NOT diesel Vehicles = 560-145 = 415
Required % = (415/800)*100 = 51.87%=52%
Answer: option B
Question: Angelo and Isabella are both salespersons. In any given week, Angelo makes $570 in base salary plus 8 percent of the portion of his sales above $1,000 for that week. Isabella makes 10 percent of her total sales for any given week. For what amount of weekly sales would Angelo and Isabella earn the same amount of money?
A.23,500
B.24,500
C.25,500
D.26,500
Answer: B.24,500
Explanation: Let the weekly sales of both = x
570+(x−1000)8/100=10/100x
x = 24500
ANSWER:B
Question: 46-3*4^2+15 = ?
A.287
B.-13
C.-73
D.13
Answer: D.13
Explanation: 46-3*4^2+15
= 46-3*16+15=20-48+15=13..
D
Question: What is the next number of the following sequence
5, 25, 61, 113,?
A.118
B.181
C.132
D.144
Answer: B.181
Explanation: 5, 25, 61, 113, x
1^2 + 2^2 = 5
3^2 + 4^2 = 25
5^2 + 6^2 = 61
7^2 + 8^2 = 113
9^2 + 10^2 = x ====> x = 181
ANSWER:B
Question: A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.350
B.300
C.400
D.450
Answer: A.350
Explanation: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.
ANSWER A
Question: The probability that a brand A widget is defective is x, the probability that a brand B widget is defective is 0.06, and the probability that a brand C widget is defective is 0.08. There are 40 brand A widgets, 35 brand B widgets, 25 brand C widgets, and nothing else in a container. If a widget is selected at random from the container, the probability that the widget selected is defective is 0.053. What is the value of x?
A.0.03
B.0.04
C.0.048
D.0.05
Answer: A.0.03
Explanation: Probability of Brand A defective is x
Probability of Brand B defective is 0.06 which 6/100. Which tells you there are 2 defective piece in a lot of 33, for 35 lot it is approx - 2.12
Probability of Brand C defective is 0.08 which 8/100. Which tells you there are 2 defective piece in a lot of 25
Total = 40 + 25 + 25 = 100
Probability of having defective piece in a lot of 100 ( All brands ) = 0.053
Hence 5.3 defective piece out 100 lot.
So 40x + 2.12 + 2 = 5.3
x = 0.03
ANSWER :Opt A.
Question: Victor gets 80 % marks in examinations. If these are 240 marks, find the maximum marks.
A.334
B.300
C.376
D.288
Answer: B.300
Explanation: Let the maximum marks be m
Then 80 % of m = 240
⇒ 80/100 × m = 240
⇒ m = (240 × 100)/80
⇒ m = 24000/80
⇒ m = 300
Therefore, maximum marks in the examinations are 300
Answer:B
Question: Mr. Smith calculated the average of 10 three digit numbers. But due to a mistake he reversed the digits of a number and thus his average increased by 59.4. The difference between the unit digit and hundreds digit of that number is :
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: Since the average increased by 59.4 and there were a total of 10 numbers, it means the incorrect number was 297 greater than the correct number.
Say, the correct number was abc (where a, b and c are the digits of the 3 digit number)
Then the incorrect number was cba.
100c + 10b + a - (100a + 10b + c) = 594
99c - 99a = 99(c - a) = 594
594 = 99*6 = 99(c - a)
So c - a = 6
Answer (D)
Question: If a train, travelling at a speed of 90 kmph, crosses a pole in 5 sec, then the length of train is?
A.128 m
B.125 m
C.198 m
D.276 m
Answer: B.125 m
Explanation: D = 90 * 5/18 * 5
=125 m
Answer: B
Question: John has taken four (8) tests that have an average of 82. In order to bring his course grade up to a ‘B’, he will need to have a final average of 87. What will he need to average on his final two tests to achieve this grade?
A.87
B.90
C.92
D.107
Answer: D.107
Explanation: 87-82=5*8=40 points
2*87=174
174+40=214 points to be scored in the 2 tests.
Avg of 2 tests = 214/2=107
Answer: D
Traditional Method:
Total scored till now 82*8=656
Total score to avg 87 in 10 tests = 87*10=870
Total to be scored on 2 tests = 870-656=214
Avg on 2 tests = 214/2 = 107
Answer D
Question: If the average (arithmetic mean) of a list of numbers is 12 and the standard deviation of that list of numbers is 1.3, then which of the following numbers is more than two standard deviations from the mean?
I. 13.2
II. 12.3
III. 9.3
A.I only
B.I and II only
C.II only
D.III only
Answer: D.III only
Explanation: Mean = 12
SD = 1.3
2 SD above mean = 12+2*1.3 = 14.6
2 SD below mean = 12-2*1.3 = 9.4
12.3 and 13.2 lies in the range of 2SD from mean
Answer: Option D
Question: If Shreehari walks in the speed of 4.5 km/hr from his house, in what time will he reach his school which is 750 m long from his house?
A.5
B.30
C.10
D.12
Answer: C.10
Explanation: Speed = 4.5 * 5/18 = 1.25 m/sec
Time taken = 750/1.25 = 600 sec ie. 10 mins.
Answer:C
Question: At Company K, 15 percent of the employees are secretaries and 60 percent are salespeople. If there are 60 other employees of Company K, how many employees does Company K have?
A. 240
B. 180
C. 190
D. 200
Answer: A. 240
Explanation: Let the total number of employees in the company be x
% of secretaries = 15%
% of salespeople = 60%
% of of employees other than secretaries and salespeople = 100 - 75 = 25%
But this number is given as 60
so 25% of x = 60
x = 240
Therefore there a total of 240 employees in the company K
Correct answer - A