RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A textile manufacturing firm employees 100 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 100 looms is Rs 5,00,000 and the monthly manufacturing expenses is Rs 1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs 75000. If one loom breaks down and remains idle for one month, the decrease in profit is:
A.13000
B.7000
C.10000
D.3500
Answer: D.3500
Explanation: Explanation :
Profit = 5,00,000âˆ’(1,50,000+75,000) =Rs. 2,75,000.
Since, such loom contributes equally to sales and manufacturing expenses.
But the monthly charges are fixed at Rs 75,000.
If one loan breaks down sales and expenses will decrease.
New profit :-
=>500000Ã—(99/100)âˆ’150000Ã—(99/100)âˆ’75000.
=>Rs 2,68,000.
Decrease in profit
=>2,75,000âˆ’2,71,500
=>Rs. 3,500.
Answer : D
Question: The fourth proportional to 12, 20 and 30 is?
A.21
B.66
C.55
D.50
Answer: D.50
Explanation: (20*30)/12
= 50
Answer:D
Question: The sum of the present ages of father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be?
A.22
B.287
C.26
D.20
Answer: D.20
Explanation: Let the present ages of son and father be x and (60 - x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
6x = 84 => x = 14
Son's age after 6 years = (x + 6) = 20 years.Answer: D
Question: Three business people wish to invest in a new company. Each person is willing to pay one third of the total investment. After careful calculations, they realize that each of them would pay $8,200 less if they could find two more equal investors. How much is the total investment in the new business?
A.$61,500
B.$54,000
C.$21,000
D.$ 5,400
Answer: A.$61,500
Explanation: Total Investment between 5: (x/5)
Total investment including 8200 less between 3 people(x-(8200*3))/3
Set both eq. equal to each other.
61,500
Answer A)
Question: What should come in place of the question mark (?) in the following number series?
16 8 12 30 105 ?
A.387.5
B.470.5
C.367.5
D.472.5
Answer: D.472.5
Explanation: Explanation:
16*1/2=8
8*3/2=12
12*5/2=30
30*7/2=105
105*9/2=472.5
Answer:D
Question: While playing a certain dice game, Chris wins if the sum of the two dice is 5, at which point the game is over. If the game allows Chris three rolls in an attempt to win, what is the probability that Chris will win?
A.1/2
B.17/36
C.217/729
D.11/36
Answer: C.217/729
Explanation: Probability of winning game = 1- Probability of losing game
Probability of losing game = (Probability of not getting sum 7 in any of the three attempts)
Ways of getting sum 5 = (1,4)(2,3)(3,2)(4,1)= 4 ways
Total ways of getting outcome on two dice =6*6=36
Probability of getting sum as 5 in any attempt =4/36=1/9
Probability of NOT getting sum as 5 in any attempt = 1-(1/9)= 8/9
Probability of losing game =(8/9)*(8/9)*(8/9)=512/729
I.e. Probability of wining game = 1-(512/729) = 217/729
Answer : Option C
Question: How many 3 digit numbers are completely divisible 6 ?
A.146
B.148
C.150
D.152
Answer: C.150
Explanation: Explanation :
100/6 = 16, remainder = 4. Hence 2 more should be added to 100 to get the minimum
3 digit number divisible by 6.
=> Minimum 3 digit number divisible by 6 = 100 + 2 = 102
999/6 = 166, remainder = 3. Hence 3 should be decreased from 999 to get the maximum
3 digit number divisible by 6.
=> Maximum 3 digit number divisible by 6 = 999 - 3 = 996
Hence, the 3 digit numbers divisible by 6 are 102, 108, 114,... 996
This is Arithmetic Progression with a = 102 ,d = 6, l=996
Number of terms = (l−a)/d + 1 = (996 − 102)/6 + 1 = 894/6 + 1 = 149 + 1 = 150. Answer : Option C
Question: David invested certain amount in three different schemes. A, B and C with the rate of interest 10% p.a., 12% p.a. and 15% p.a. respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in scheme C was 150% of the amount invested in scheme A and 240% of the amount invested in scheme B, what was the amount invested in scheme B?
A.5000
B.5007
C.5006
D.5026
Answer: A.5000
Explanation: Let x, y and z be the amount invested in schemes A, B and C respectively. Then,
(x * 10 * 1)/100 + (y * 12 * 1)/100 + (z * 15 * 1)/100 = 3200
10x + 12y + 15z = 320000
Now, z = 240% of y = 12/5 y
And, z = 150% of x = 3/2 x
x = 2/3 z = ( 2/3 * 12/5) y = 8/5 y
16y + 12y + 36y = 320000
y = 5000
Sum invested in scheme B = Rs. 5000.
Answer:A
Question: The total age of A and B is 16 years more than the total age of B and C. C is how many year younger than A
A.11
B.16
C.13
D.14
Answer: B.16
Explanation: Explanation:
Given that A+B = 16 + B + C
=> A ? C = 16 + B ? B = 16
=> C is younger than A by 16 years
Answer: Option B
Question: Call a number parents if it is composite but not divisible by 2, 3, or 5. The three smallest guardian numbers are 49, 77, and 91. There are 168 prime numbers less than 1000. How many parent numbers are there less than 1000?
A.a) 90
B.b) 97
C.c) 100
D.d) 106
Answer: C.c) 100
Explanation: Start with the numbers from 1 - 1000. We have 1000 numbers.
Subtract the primes:
1000 - 168 = 832
Now, subtract the even numbers, divisible by 2. There are 500 even numbers in the set, but the first, 2 itself, has already been subtracted with the primes. There are 499 non-prime even numbers in the set, including 1000 itself. (1000 itself really shouldn't be included, because are looking for numbers less than 1000, but it gets subtracted in this step anyway, so it doesn't matter.)
832 - 499 = 333
Now, numbers divisible by 3. There are 333 factors of three between 1 and 1000, but first of all, one of those is the prime number 3, already subtracted, so exclude that --- 332. Of those, half are even, already counted, so that leaves 332/2 = 166 non-prime odd multiples of 3.
333 - 166 = 167
Now, multiples of 5. There are 200 multiples of 5 up to 1000. Half are even, divisible by 10, so eliminate them --- 100 odd multiples of 5. Eliminate the prime number 5 itself, already counted --- 99 non-prime multiples of 5. Now, 1/3 of these are divisible by three, already counted, so we 2/3 of this number ==> 66. There are 66 non-prime multiples of 5 that are not divisible by 3.
167 - 66 = 101
The last number that needs to be subtracted --- not prime, not composite, not a multiple of 2 or 3 or 5, is 1 itself. This is not composite, so it is not a parent.
101 - 1 = 100
That leaves 100 parent numbers. OA =(C)
Question: 0.003 * 0.5 = ?
A.0.00015
B.0.0015
C.0.015
D.0.15
Answer: B.0.0015
Explanation: Explanation:
3 * 5 = 15. Sum of decimal places = 4.
0.003 * 0.5 = 0.0015 = 0.0015
ANSWER B
Question: What is the next number: 3, 18, 258, __
A.2928
B.3638
C.4098
D.4418
Answer: C.4098
Explanation: 4^0 + 2 = 3
4^2 + 2 = 18
4^4 + 2 = 258
4^6 + 2 = 4098
The answer is C.
Question: What is remainder of the division (1525*1527*1529)/12?
A.0
B.1
C.2
D.3
Answer: D.3
Explanation: remainder will be number/ 100 here as the divisor is two digit number = 12.
hence checking for the last two digits = 5*7*9 = 15
Thus remainder = 3.
Answer : D
Question: One water pump can fill half of a certain empty tank in 8 hours. Another pump can fill half of the same tank in 8.5 hours. Working together, how long will it take these two pumps to fill the entire tank?
A.8 7/13
B.1 5/8
C.3 1/4
D.8 8/33
Answer: D.8 8/33
Explanation: One pump can fill a tank in 8 hours and another in 8.5 hours
so the rate at which both can half fill the tank is (1/8+1/8.5) => 33/136
Thus half of the tank can be filled in 136/33
so for filling the complete tank =>136/33*2 = 272/33 = 8 8/33
ANSWER:D
Question: By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?
A.38002
B.38000
C.38028
D.38289
Answer: B.38000
Explanation: CP + CP/8 = 45000
CP = 40000
SP = 40000*(95/100) = 38000
Answer: B
Question: The C.I. on a certain sum for 2 years Rs.41 and the simple interest is Rs.40. What is the rate percent?
A.3%
B.5%
C.6%
D.2%
Answer: B.5%
Explanation: SI = 20 + 20
CI = 20 + 21
20 ---- 1
100 ---- ? => 5%
Answer:B
Question: If x + 1/x = 2 then find x2 + 1/x2
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: If x+1/x= p
==> x^2+1/x^2=p^2-2
Ans= 2^2-2=2
ANSWER:B
Question: The average of numbers 0.34204, 0.34203, 0.34202 and 0.34201 is ?
A.0.34202
B.0.34204
C.0.342022
D.0.342025
Answer: D.0.342025
Explanation: Answer
Average = (0.34204 + 0.34203 + 0.34202 + 0.34201)/ 4
=1.3681/ 4
=0.342025
Correct Option: D
Question: Mary got a weekly raise of $384. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.
A.384
B.374
C.364
D.394
Answer: A.384
Explanation: Let the 1st paycheck be x (integer).
Mary got a weekly raise of $ 384.
So after completing the 1st week she will get $ (x+384).
Similarly after completing the 2nd week she will get $ (x + 384) + $ 384.
= $ (x + 384 + 384)
= $ (x + 768)
So in this way end of every week her salary will increase by (A)$ 384.
Question: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most ?
A.177
B.199
C.215
D.168
Answer: C.215
Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is
= 6 * 6 * 6 = 216. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts
= 216 - 1
= 215.
Answer: C
Question: A company has 2 directors and 5 managers. How many different committees with 5 people can be chosen having at least 1 director?
A.500
B.720
C.4500
D.20
Answer: D.20
Explanation: atleast one means exactly one and more than one.
different committees with 5 people can be chosen having at least 1 director is
(2c1*5c4) + (2c2*5c3) = 20;
Hence D.
Question: What should come in place of the question mark in the following questions?
?⁄24 = 72⁄√?
A.12
B.16
C.114
D.144
Answer: D.144
Explanation: ? × √? = 24 × 72 Squaring both the sides,
(?2 × ? ) = ?3 = (8 × (3) × (8 × 3) × (8 × 9) × (8 × 9)
= 2(3)8(3)9(3)
∴ ? = 2 × 8 × 9 = 144
Answer D
Question: The line K represented by which of the following equation does not intersect with the line represented by y = 3x^2+5x+1
A.y = 2x^2+5x+1
B.y = x^2+5x+2
C.y = 3x^2+5x+2
D.y = 3x^2+7x+2
Answer: C.y = 3x^2+5x+2
Explanation: concept of slope for linesparabolas are different. Bunuel, please correct if I am wrong. Also please help to solve this problem if its a GMAT type question.
The general form of parabolic equ. is y^2= 4ax which implies the axis is x or x^2 = 4ay where axis is y.
We have a similar form as x^2 = 4ay.
here the vertex is origin.
So if we have same values of x and y but constant term changes then we will have parallel parabolas.
This is same as for straight line K which are parallel for different values of constant term c
ax + by +c1 = 0 and ax +by+ c2 =0
We have quadratic equations. These equations when drawn give parabolas, not lines. The question is: which of the following parabolas does not intersect with the parabola represented by y=3x^2+5x+1.C
Question: A town's oldest inhabitant is x years older than the sum of the ages of the Lee triplets. If the oldest inhabitants is now J years old, how old will one of the triplets E be in 20 years?
J-X-40/3 is my answers.
J = X + L + L + L is the initial situation
After 20 years
J + 20 = X + L + L + L + 60 ...20 years for each triplet so 60 years totally.
J - X - 40/ 3 = L is my answer.
What wrong am i doing ? Since the age asked is after 20 years i also consider adding 20 years to J .
A.(J - 50)/3
B.3(J + 20)/x
C.(J + x - 50)/3
D.(J - x + 60)/3
Answer: D.(J - x + 60)/3
Explanation: here it goes:
Oldest inhabitant = sum of age of triplets + X
J = 3L + X so L = (J - X)/3
After 20 years = L + 20
E= (J - X)/3 + 20
= (J - X + 60)/3=D
Question: Circular gears P and Q start rotating at the same time at constant speeds. Gear P makes 10 revolutions per minute and Gear Q makes 40 revolutions per minute. How many seconds after the gears start rotating will gear Q have made exactly 5 more revolutions than gear P?
A.6
B.8
C.10
D.12
Answer: C.10
Explanation: Gear Q makes 30 more revolutions each 60 seconds.
The time to make 5 = 30/6 more revolutions is 60/6 = 10 seconds.
The answer is C.
Question: What is the least number should be added to 1056, so the sum of the number is completely divisible by 29?
A.17
B.27
C.37
D.47
Answer: A.17
Explanation: (1056 / 29) gives remainder 12
17 + 12 = 29, So we need to add 17
A
Question: If a is an integer, what is the greatest possible value for a that would still make the following statement true: 11*10^a < 1/10 ?
A. –4
B. –3
C. –2
D. –1
Answer: B. –3
Explanation: Just putting values, the LHS becomes
a=0 --> 11
a=-1 --> 11/10
a=-2 --> 11/100
a=-3 --> 11/1000
Anything lower will be smaller than 11/1000. a=-2, equality does not hold but it does for a=-3.
Answer is B.
Question: The average expenditure of the hotel when there are 10 guests is Rs. 60 per guests and the average expenditure is Rs.40 when there are 20 Guests. If it is known that there are some fixed expenses irrespective of the number of guests then the average expenditure per guest whe there are 40 guests in the hotel?
A.Rs.30
B.Rs.32
C.Rs.31
D.Rs.39
Answer: A.Rs.30
Explanation: Answer: A) Rs. 30
Explanation:
Let the fixed expenditure of the hotel be Rs.x and the variable expenditure ( which is dependent on the guest ) is Rs.y , then
x + 10y = 600 ---------(1)
x + 20y = 800 ----------(2)
10y = 200
y = Rs. 20 and x= 400
Hence the total expenditure when there are 40 guests = 400 + 40 x 20 = 1200
average expenditure ={1200}/{40}
= Rs. 30
Answer: A
Question: If x - 2 < 8 and x + 6 > 4, which of the following inequalities expresses all possible values of x?
A.2 < x < 10
B.4 < x < 8
C.-2 < x < 10
D.-4 < x < 8
Answer: C.-2 < x < 10
Explanation: x - 2 < 8
So, x < 10
2. x + 6 > 4
So, x > -2
Combine the two you get -2 < x < 10
Answer will be (C)
Question: Glen is having his big family over for Christmas. Out of 25 people coming, 40 percent are lactose intolerant and 72% are vegetarians. Glen wants to prepare the good in advance. Can you calculate how many of the guests are both vegetarians and lactose intolerant?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: The total number of guests coming over for Christmas is n=25.
The number of lactose intolerant guests is 40% of it, thus
n (A)=40/100×25=40/4=10.
The number of guests who are vegetarians is 72%, thus
n (B)=72/100×25=72/4=18.
In order to calculate the number of guests who are both lactose intolerant and vegetarians we can use the following equation:
n (AnB)=n (A)+n (B) -n =10+18-25=28-25=3.
So, 3 of Glen's guests are both lactose intolerant and vegetarians.
ANSWER: C
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
A.12.6
B.12.0
C.12.1
D.12.3
Answer: B.12.0
Explanation: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.Answer: B
Question: A bag contains 8 red and 3 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
A.4/7
B.2/3
C.8/11
D.1/4
Answer: C.8/11
Explanation: Total number of balls = 8+3 = 11
number of white balls = 8
Probability = 8/11 = 8/11
Answer is C
Question: Each term of a certain sequence is 3 less than the previous term. The first term of this sequence is 18. If the sum of the first n terms of the sequence is n, what is the value of positive integer n?
A.1
B.13
C.15
D.19
Answer: C.15
Explanation: We know that it is a decreasing sequence i.e. the terms keep decreasing till 0 and then negative terms start.
What does this imply?If the sum of the first n terms of the sequence is n
Since number of terms will definitely be positive, we are looking for a positive sum.
19 + 16 + 13 + 10 + 7 + 4 + 1 -2 -5 -7 -10 .... and so on
Note that the first 7 terms are positive and all others negative. Every negative term has greater absolute value than the corresponding positive terms i.e. -2 absolute value is greater than 1 absolute value, -5 absolute value is greater than 4 absolute value, and so on...
Since we have 7 positive terms, we must have less than 7 negative terms to get the sum as positive. If we have 6 negative terms, we will have a total of 13 terms. Of the given options, only 13 is possible and hence it must be the answer.
Answer (C)
Question: A shopkeeper bought 150 calculators at the rate of 250 per calculator.He spent 2500 on transportation and packing. If the marked price of calculator is 320 per calculator and the shopkeeper gives a discount of 5% on the marked price then what will be the percentage profit gained by the shopkeeper?
A.20%
B.14%
C.15%
D.16%
Answer: B.14%
Explanation: CP of 150 calculators = 150 × 250 = 37,500.
\ total CP = 37,500 + 2500 = 40,000
Marked price of 150 calculators = 150 × 320 = 48,000
Selling price after discount = 4800 × 95⁄100
= 45,600
\ Percentage profit = 45,600−40,000/40,000×100 = 14%
Answer B
Question: After decreasing 50% in the price of an article costs Rs.620. Find the actual cost of an article?
A.1400
B.1240
C.1200
D.1100
Answer: B.1240
Explanation: CP* (50/100) = 620
CP= 12.4 * 100 => CP = 1240
ANSWER:B
Question: A researcher computed the mean, the median, and the standard deviation R for a set of performance scores. If 5 were to be added to each score, which of these three statistics would change?
A.The mean only
B.The median only
C.The standard deviation only
D.The mean and the median
Answer: D.The mean and the median
Explanation: If we add or subtract a constant to each term in a set the standard deviation R will not change..
If we add (or subtract) a constant to each term in a set the mean and the median will increase (decrease) by the value of that constant.
Answer: D.
Question: Ben is driving on the highway at y miles per hour. (One mile equals 5,280 feet.) Ben's tires have a circumference of x feet. Which of the following expressions gives the number of revolutions each wheel turns in one hour?
A.5,280(x/y)
B.5,280(y/x)
C.5,280(xy)
D.5,280/(xy)
Answer: B.5,280(y/x)
Explanation: In one hour, at the rate of y miles per hour, Ben covers y miles, so 5,280y feet.
The number of revolutions = distance/circumference = 5,280y/x.
Answer: B.
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 20 seconds. Its length is?
A.188 m
B.876 m
C.251 m
D.300 m
Answer: D.300 m
Explanation: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 20 = x / 15
x = 300 m.
Answer: D
Question: If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $92. If $2,000 is the total amount invested, how much is invested at 8 percent?
A.$600
B.$700
C.$800
D.$900
Answer: A.$600
Explanation: 0.1x = 0.08(2000-x)+92
0.18x = 252
x = 1400
Then the amount invested at 8% is $2000 - $1400 = $600
The answer is A.
Question: A grocer has a sale of Rs. 5435, Rs. 5927, Rs. 5855, Rs. 6230 and Rs. 5562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 5500?
A.4991
B.5991
C.3991
D.6542
Answer: C.3991
Explanation: Total sale for 5 months = Rs. (5435 + 5927 + 5855 + 6230 + 5562) = Rs. 29009.
Required sale = Rs. [ (5500 x 6) - 29009 ]
= Rs. (33000 - 29009)
= Rs. 3991
Answer: Option C
Question: P is faster than Q. P and Q each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then, P's speed is equal to ?
A.9 km/hr
B.4 km/hr
C.6 km/hr
D.5 km/hr
Answer: B.4 km/hr
Explanation: Explanation:
Let P's speed = x km/hr. Then, Q's speed = (7 - x) km/ hr.
So, 24/x + 24/(7 - x) = 14
- 98x + 168 = 0
(x - 3)(x - 4) = 0 => x = 3 or 4.
Since, P is faster than Q,
so P's speed = 4 km/hr and Q's speed = 3 km/hr.
Answer: B
Question: John got Rs.6000 as his share out of a total profit of Rs.9000 which he and Rick earned at the end of one year. If John invested Rs.20,000 for 6 months, where as Rick invested his amount for the whole year, what was the amount invested by Rick?
A.3400
B.3500
C.4500
D.5000
Answer: D.5000
Explanation: (D)
Let the amount invested by Ramesh = Rs.x.Then, 20000×6 : 12x=6000:3000
or 12000012x=21 or x = 5000
Question: What is the greatest value of positive integer x such that 2^x is a factor of 100^70?
A.120
B.140
C.130
D.150
Answer: B.140
Explanation: Put in simple words, we need to find the highest power of 2 in 100^70
100 = 2^2*5^2
Therefore 100^70 = (2^2*5^2)^70 = 2^140*5^140
Answer : B
Question: A certain factory employed 600 men and 400 women and the average wager was Rs. 25.50 per day, If a woman got Rs. 5 less than a man, then what are their daily wages ?
A.M :23.50 w:22.50
B.M :27.50 w:22.50
C.M :27.50 w:22.51
D.M :27.50 w:22.53
Answer: B.M :27.50 w:22.50
Explanation: Let the daily wage of a man be Rs. x.
Then, daily wage of a woman = Rs. (x - 5).
Now, 600x + 400 (x - 5) = 25.50 * (600 + 400) <=> 1000x = 27500 <=> x = 27.50.
Man's daily wages = Rs. 27.50; Woman's daily wages = (x - 5) = Rs. 22.50.
Answer: B
Question: Two good train each 100 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km / hr and 30 km /hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
A.1.2 sec
B.2.4 sec
C.4.8 sec
D.9.6 sec
Answer: D.9.6 sec
Explanation: Sol.
Relative Speed = (45 + 30) km / hr
= (75 x 5 / 18) m/sec
= (125/6) m/sec.
Distance covered = (100+ 100) m = 1000 m.
Required time = (200 x 6 / 125) sec = 9.6 sec.
Answer D
Question: If PINTU is coded as 79523 in a certain code language, how would you code JUMBO in the same language?
A.13426
B.14236
C.13436
D.14263
Answer: A.13426
Explanation: 1 2 3 4 5 6 7 8 9
a b c d e f g h i
j k l m n o p q r
s t u v w x y z
sooo...JUMBO is 13426...
ANSWER:A
Question: A person crosses a 800 m long street in 6 minutes. What is his speed in km per hour?
A.5.2 km/hr.
B.8.0 km/hr.
C.7.2 km/hr.
D.3.2 km/hr.
Answer: B.8.0 km/hr.
Explanation: B
8.0 km/hr.
Speed=(800/6 * 60) m/sec
= 2.2 m/sec.
Converting m/sec to km/hr
=(2.2*18/5) km/hr
= 8.0 km/hr.
Answer is B
Question: Let us say that a table tennis tournament was going on with knock out terms which means the one who loses the match is out of the tournament. 100 players took part in that tournament.
How many matches were played?
A.99 matches
B.79 matches
C.69 matches
D.99 matches
Answer: D.99 matches
Explanation: D
99 matches.
The number of matches will always sum up to one less than the number of players in a knock out tournament. You may calculate it in any manner. Thus 99 matches were played.
Question: The average age of 5 boys is 25 years and their ages are in the proportion 3:5:7. The age of the youngest boy is?
A.10years
B.15years
C.20years
D.25years
Answer: D.25years
Explanation: Total age of 5 boys = 25*5 = 125
ratio of their ages = 3:5:7
Age of the youngest = 125*3/15 = 25 years
Answer is D
Question: What is the least integer that is a sum of four different prime numbers?
A.15
B.17
C.19
D.21
Answer: B.17
Explanation: The sum of the four smallest primes is 2+3+5+7=17.
The answer is B.
Question: The value of x + (xx) when x = 2 is:
A.A)36
B.B)6
C.C)18
D.D)64
Answer: B.B)6
Explanation: x + (xx)
Put the value of x = 2 in the above expression we get,
2 + (22)
= 2 +(2 × 2)
= 2 + (4)
= 2 + 4
= 6
B
Question: A tradesman by means of his false balance defrauds to the extent of 40%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
A.99%
B.47%
C.84%
D.96%
Answer: D.96%
Explanation: g% = 40 + 40 + (40*40)/100
= 96%
Answer: D