RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Which of the following inequalities has a solution set, when graphed on the number line, is a single line segment of finite length?
A.2 <= 3x+4 <= 6
B.3 <= 3x+4 <= 6
C.5 <= 3x+4 <= 6
D.5 <= 3x+4 <= 6
Answer: A.2 <= 3x+4 <= 6
Explanation: The key words in the stem are:a singleline segment offinite length
Now, answer choices A, B, and C can not be correct answers as solutions sets for these exponential functions are not limited at all (>= for even powers and <= for odd power) and thus can not be finite (x can go to + or -infinity for A and C and x can got to -infinity for B). As for D: we have thatabsolute valueof x is between two positive values, thus the solution set for x (because of absolute value) will be two line segments which will be mirror images of each other.
Answer: A.
Question: A train running at the speed of 60 km/hr crosses a pole in 3 sec. What is the length of the train?
A.85 m
B.70 m
C.115 m
D.50 m
Answer: D.50 m
Explanation: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 3 = 50 m
Answer: D
Question: Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 25 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
A.457 km
B.444 km
C.552 km
D.645 km
Answer: C.552 km
Explanation: 1h ----- 5
? ------ 60
12 h
RS = 25 + 21 = 46
T = 12
D = 46 * 12 = 552
Answer:C
Question: 25, 50, 100, 175, 275, (....)
A.400
B.300
C.425
D.450
Answer: A.400
Explanation: Explanation :
The pattern is 25, 50, 75, 100, etc.
Hence 125=400
Answer: A
Question: By selling 32 mangoes in a dollar, a man loses 40%. How many mangoes must he sell in a dollar to gain 20% profit?
A.16
B.18
C.20
D.25
Answer: A.16
Explanation: This is a question that is much easier than it first appears. If you work with the percents directly, you can solve it very quickly. If the man sells 32 mangoes for a dollar, he loses 40%. That means he is at 60% of his cost (100% - 40% = 60%). We are trying to figure out how many mangoes he has to sell in order to make a 20% profit, or be at 120% (100% + 20% = 120%). 120% is double 60%, meaning that we simply cut the number of mangoes in half to double our returns (from 60% to 120%), yielding 32/2 = 16 mangoes, or answer choice A.
Question: Two trains of equal lengths take 10 sec and 15 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
A.17 sec
B.12 sec
C.16 sec
D.15 sec
Answer: B.12 sec
Explanation: Speed of the first train = 120/10 = 12 m/sec.
Speed of the second train = 120/5 = 8 m/sec.
Relative speed = 12 + 8 = 20 m/sec.
Required time = (120 + 120)/20 = 12 sec.
Answer:B
Question: Calculate the average mark scored by Belinda if she had the following scores in an examination: 86, 50, 60, 67 and 79 marks (out of 100) in English Language, Spanish Language, Social Studies, Fine Art, and Physical Education respectively?
A.69.4
B.68.4
C.65.4
D.63.4
Answer: B.68.4
Explanation: Explanation:
Average mark = 86+50+60+67+79/5=68.4
Answer: Option B
Question: How many multiples of 10 are there between 81 and 358?
A.24
B.25
C.26
D.27
Answer: D.27
Explanation: 10 * 9 = 90
10 * 35 = 350
Total no of multiples = (35 - 9) + 1
= 27
Answer D
Question: 7^6n -1^ 6n When n is an integer > 0 is divisible by
A.120
B.127
C.143
D.164
Answer: B.127
Explanation: 127
B
Question: Find the middle one when The sum of three consecutive even numbers is 162?
A.51
B.50
C.58
D.54
Answer: D.54
Explanation: 3 consecutive numbers can be a - 1, a, a + 1
So sum of numbers = 3a = 162.
Hence a = 54.
D
Question: Mangala completes a piece of work in 30 days, Raju completes the same work in 30 days. If both of them work together, then the number of days required to complete the work is?
A.8 days
B.12 days
C.14 days
D.15 days
Answer: D.15 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 30 × 30/60 = 15 days
D
Question: If a 5 percent deposit that has been paid toward the purchase of a certain product is $70, how much more remains to be paid?
A.$1120
B.$1190
C.$1260
D.$1330
Answer: D.$1330
Explanation: 95% remains to be paid so the remaining amount is 19*70=$1330.
The answer is D.
Question: If a lemon and apple together costs Rs.12, tomato and a lemon cost Rs.4 and an apple costs Rs.8 more than a lemon. What is the cost of lemon?
A.8
B.2
C.3
D.5
Answer: B.2
Explanation: L + A = 12 ...(1)
T + L = 4 .....(2)
L + 8 = A
Taking 1 and 3, we get A = 10 and L = 2
Answer:B
Question: Of 50 applicants for a job, 30 had at least 5 years of prior work experience, 25 had advanced degrees, and 15 had at least 5 years of prior work experience and advanced degrees. How many of the applicants had neither 5 years of prior work experience nor advanced degrees?
A.10
B.12
C.15
D.18
Answer: A.10
Explanation: Had advanced degrees and 5 years work experience: 15
Only had 5 years work experience: 30-15 = 15
Only had advanced degrees: 25-15 = 10
50-15-15-10=10
Answer: A
Question: The average weight of 19 students is 15kg. by the admission of a new student the average weight is reduced to 14.2 kg. the weight of the new student is ?
A.1 kg
B.10.8 kg
C.11 kg
D.14.9 kg
Answer: A.1 kg
Explanation: Answer
Weight of new student = Total weight of all 20 students - Total weight of initial 19 students
= (20 x 14.2 - 19 x 15) kg
= 1 kg.
Correct Option: A
Question: The jogging track in a sports complex is 1000 meters in circumference. Deepak and his wife start from the same point and walk in opposite directions at 20 km/hr and 15 km/hr respectively. They will meet for the first time in?
A.50min
B.40min
C.35min
D.25min
Answer: C.35min
Explanation: Clearly, the two will meet when they are 1000 m apart
To be 20+15 = 35 km apart, they take 1 hour
To be 1000 m apart, they take 35 * 1000/1000 = 35 min.
Answer is C
Question: If the selling price of 50 articles is equal to the cost price of 40 articles, then the loss or gain percent is:
A.10
B.30
C.20
D.60
Answer: C.20
Explanation: C
20
Let C.P. of each article be $ 1.
Then, C.P. of 50 articles = $50;
S.P. of 50 articles = $40.
Loss % = 10/50 * 100 = 20%
Question: A trailer carries 3, 4 and 5 crates on a trip. Each crate weighs no less than 150 kg. What is the maximum weight of the crates on a single trip?
A.1250
B.625
C.600
D.750
Answer: D.750
Explanation: Max No. of crates=5.
Max Weight=150Kg
Max. weight carried = 5*150=750Kg=D
Question: A person crosses a 400m long street in 10minnutes. What is his speed in km per hour?
A.6.4km/hr
B.7.9km/hr
C.1.5km/hr
D.2.4km/hr
Answer: D.2.4km/hr
Explanation: Speed = 400/10*60 = 2/3m/sec
=2/3*18/5
=2.4km/hr
Answer is D
Question: Bony has twice as many marbles as Tony, and Tony has thrice as many marbles as Vinay. Which of the following cannot be the sum of marbles with all three of them ?
A.72
B.40
C.80
D.92
Answer: A.72
Explanation: Let each 1 marble that Vinay have Tony will have 3, Bony 6 marbles
Sum of units = 1 + 3 + 6 = 10 units, therefore the number must be a multiple of 10
Among the choices only 72 is not divisible by 10
Option A
Question: How many numbers between 100 and 756 are divisible by 2, 3, and 7 together?
A.112
B.77
C.267
D.16
Answer: D.16
Explanation: Explanation:
As the division is by 2, 3, 7 together, the numbers are to be divisible by: 2*3*7 = 42
The limits are 100 and 756
The first number divisible is 42*3 = 126
To find out the last number divisible by 42 within 756:
756/42 = 18
Hence, 42*16 = 756 is the last number divisible by 42 within 756
Hence, total numbers divisible by 2, 3, 7 together are (18â€“ 2) = 16
ANSWER: D
Question: A man can row a boat at 18 kmph in still water. If the speed of the stream is 3 kmph, what is the time taken to row a distance of 48 km downstream?
A.30/16 hours
B.30/33 hours
C.16/7 hours
D.16/13 hours
Answer: C.16/7 hours
Explanation: Speed downstream = 18 + 3 = 21 kmph.
Time required to cover 48 km downstream = d/s = 48/21 = 16/7 hours.Answer:C
Question: A student needs 30% of the marks on a test to pass the test. If the student gets 80 marks and fails the test by 100 marks, find the maximum marks set for the test.
A.400
B.600
C.800
D.1000
Answer: B.600
Explanation: 30% = 180 marks
1% = 6 marks
100% = 600 marks
The answer is B.
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?
A.33
B.28
C.12
D.88
Answer: C.12
Explanation: D = 250 m + 250 m = 500 m
RS = 80 + 70 = 150 * 5/18 = 125/3
T = 500 * 3/125 = 12 sec.Answer: C
Question: A photograph measuring 2 1''⁄2 × 1 7''⁄8 is to be enlarged so that the length will be 4”. How many inches will the enlarged breadth be?
A.1 1⁄2
B.2 1⁄8
C.3
D.3 3⁄8
Answer: C.3
Explanation: Let enlarged breadth be x inches. Then,
5⁄2 : 4 :: 15⁄8 : x
⇒ 5⁄2x = 4 × 15⁄8 ⇒ x = 3 inches.
Answer C
Question: January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?
A.Saturday
B.Wednesday
C.Thursday
D.Tuesday
Answer: C.Thursday
Explanation: Explanation:
Number of odd days in 2008 = 2 (since it is a leap year)
(we have taken the complete year 2008 because we need to find out the odd days from 01-Jan-2008 to 31-Dec-2008, that is the whole year 2008)
Given that January 1, 2008 is Tuesday.
Hence January 1, 2009 = (Tuesday + 2 odd days) = Thursday
Answer: Option C
Question: On dividing a number by 56, we get 29 as remainder. On dividing the same number by 8, what will be the remainder ?
A.2
B.6
C.4
D.5
Answer: D.5
Explanation: Formula: (Divisor*Quotient) + Remainder = Dividend.
(56*Q)+29 = D -------(1)
D%8 = R -------------(2)
From equation(2),
((56*Q)+29)%8 = R.
=> Assume Q = 1.
=> (56+29)%8 = R.
=> 85%8 = R
=> 5 = R. so the required remainder is 5.
Answer D)5
Question: In a kilometer race, If Abhishek gives Bharti a 40 m start, Abhishek wins by 19 sec. But if Abhishek gives Bharti a 30 sec start, Bharti wins by 40 m. Find the time taken by Bharti to run 5,000 m?
A.150 sec
B.750 sec
C.450 sec
D.825 sec
Answer: B.750 sec
Explanation: If Abhishek takes x seconds and Bharti takes y seconds to run 1 km, then:
=>y=150 sec and x=125 sec
=>x+19=960y/1000 and
=(960x/1000)+30=y
=>y=150 sec and x=125 sec
Answer =(150/1000)×500
= 750 sec Answer : B
Question: A man lent money of Rs. 2500 on simple interest for rate on interest being same as number of years. If he got Rs. 900 as interest amount at the end of the period then what is the rate of interest?
A.6%
B.4%
C.5%
D.3%
Answer: C.5%
Explanation: Explanation :
SI = pnr
SI = (2500*3r*3r)=900
r2 = 25
r = 5%
Answer : C
Question: The ratio of the number of females to males at a party was 1:2 but when 5 females and 5 males left, the ratio became 1:3. How many people were at the party originally?
A.26
B.28
C.30
D.32
Answer: C.30
Explanation: The total number of people are x females + 2x males.
3*(x-5) = 2x - 5
x = 10
There were 3x = 30 people at the party originally.
The answer is C.
Question: Evaluate: 30 - |-x + 6| for x = 10
A.23
B.24
C.25
D.26
Answer: D.26
Explanation: Substitute x by 10 in the given expression and evaluate
30 - |- (10) + 6| = 30 - |-10 + 6|
= 30 - | - 4 | = 30 - 4 = 26
correct answer D)26
Question: The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m < r < s < t. If t is 42, what is the greatest possible value of the median of the 5 integers?
A.17
B.18
C.19
D.20
Answer: A.17
Explanation: We need to find the median which is the third value when the numbers are in increasing order. Since k<m<r<s<t, the median would be r.
The average of the positive integers is 16 which means that in effect, all numbers are equal to 16. If the largest number is 42, it is 26 more than 16. We need r to be maximum so k and m should be as small as possible to get the average of 16. Since all the numbers are positive integers, k and m cannot be less than 1 and 2 respectively. 1 is 15 less than 16 and 2 is 14 less than 16 which means k and m combined are 29 less than the average. 42 is already 26 more than 16 and hence we only have 29 - 26 = 3 extra to distribute between r and s. Since s must be greater than r, r can be 16+1 = 17 and s can be 16+2 = 18.
So r is 17.
Answer (A)
Question: The difference between a two-digit number and the number after interchanging the position of the two digits is 45. What is the difference between the two digits of the number?
A.4
B.6
C.5
D.Cannot be determined
Answer: C.5
Explanation: Let the two-digit no. be l0x + y.
Then, (10x + y) â€“ (10y + x) = 45
or, 9(x â€“ y) = 45
or, x â€“ y = 5
Answer C
Question: A grocer has a sales of Euro 220, Euro 320, Euro 480, Euro 120and Euro 720 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Euro 620?
A.uro 1691
B.uro 4591
C.uro 1860
D.uro 7791
Answer: C.uro 1860
Explanation: C
Euro 1860
Total sale for 5 months = Euro (220 + 320 + 480 + 120 + 720) = Euro 1860.
Required sale = Euro [ (620 x 6) - 1860]
= Euro (3720 - 1860)
= Euro 1860.
Answer is C
Question: Carl is facing very difficult financial times and can only pay the interest on a $30,000 loan he has taken. The bank charges him a quarterly compound rate of 5%. What is the approximate interest he pays annually?
A.$1200
B.$2000
C.$2150
D.$6000
Answer: D.$6000
Explanation: Usually, you are given the annual rate of interest and it is mentioned that it is annual rate.
The bank charges him a quarterly compounded ANNUAL rate of 20%.
Here you find per quarter rate as (20/4)% = 5%
I have actually never seen a question with quarter rate given but since this question did not mentionannual rate of interestand since the options did not make sense with 5% annual rate of interest, it is apparent that the intent was a 5% quarterly rate. So the bank charges 5% every quarter and compounds it in the next quarter. Had it been a simple quarterly rate, we would have just found 4 * 5% of 30,000 = $6000 as our answer.
But since, the interest is compounded, it will be a bit more than $6000. Option (D) looks correct.
Question: The greatest possible (straight line) distance, in inches, between any two points on a certain cube is 10. If the cube is modified so that its length is doubled and its width is doubled while its height remains unchanged, then what is the greatest possible (straight line) distance, in inches, between any two points on the modified box?
A.10√2
B.10√3
C.20
D.30
Answer: B.10√3
Explanation: The greatest distance(straight line) between two points in a cube is its diagonal.
Here the length of the digaonal is 10. Side*sqrt(3) = 10
Side = 10/sqrt(3)
Since the length and breadth doubles, and height remains the same.
The new box is a cuboid with length = breadth = 20/sqrt(3) and height is 10/sqrt(3)
The straight line greatest distance is the diagonal.
Diagonal = sqrt(length^2 + breadth^2 + height^2)
Diagonal = sqrt(300) = 10*sqrt(3)
Ans : (Option B)
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 8 boys when No boy gets more than one prize?
A.212
B.214
C.317
D.336
Answer: D.336
Explanation: Sol. In this case, repetitions are not allowed. So, the first prize can be given in 8 ways. The second in 7 ways and the third in 6 ways. But fundamental principle, (8 x 7 x 6) ways = 336 ways
D
Question: The Jhon purchased 550 square feet of Kentucky Gem sod at $1.89 per square foot and 270 square feet of Blue sod at $1.38 per square foot. What was the approximate average price per square foot paid for all the sod?
A.$1.63
B.$1.64
C.$1.72
D.$1.74
Answer: C.$1.72
Explanation: Answer D
Average price = (550*1.89)+(270*1.38)/550+270=1.72 (Approx)
C)
Question: The value of (4.7×13.26 + 4.7×9.43+4.7×77.31) is
A.0.47
B.47
C.470
D.4700
Answer: C.470
Explanation: Solution
Given expression	= 4.7×(13.26+9.43+77.31)
= 4.7 ×100
= 470.
Answer C
Question: A, B and C are entered into a partnership. A invested Rs.6500 for 6 months, B invested Rs.8400 for 5 months and C invested for Rs.10000 for 3 months. A is a working partner and gets 5% of the total profit for the same. Find the share of C in a total profit of Rs.7400?
A.2887
B.1900
C.1892
D.1987
Answer: B.1900
Explanation: 65 * 6 : 84 * 5 : 100 * 3
26:28:20
C share = 74000 * 95/100 = 7030 * 20/74
=> 1900
Answer:B
Question: At present,the ratio between the ages of Arun and Deepak is 4:3. After 6 years, Arun’s age will be 26 years. What is the age of Deepak at present ?
A.12 years
B.15 years
C.19½ years
D.21 years
Answer: B.15 years
Explanation: Solution
Let the present ages of Arun and Deepak be 4x years and 3x years respectively.
Then, 4x +6 = 26 ⇔ 4x = 20 ⇔ x =5.
∴ Deepak's age =3x =15 years. Answer B
Question: Find the fourth proportional to 2.8, 4.6 and 7.6?
A.12.48
B.13.56
C.15.23
D.15.34
Answer: A.12.48
Explanation: Formula = Fourth propotional = (b Ã— c)/a
A = 2.8 , B = 4.6 and C = 7.6
(4.6 Ã— 7.6)/2.8 = 12.48
A
Question: In a certain boys camp, 20% of the total boys are from school A and 30% of those study science. If there are 21 boys in the camp that are from school A but do not study science then what is the total number of boys in the camp?
A.70
B.245
C.150
D.35
Answer: C.150
Explanation: Since 30% of the boys from school A study science, then 70% of the boys from school A do NOT study science and since 20% of the total number of boys are from school A, then 0.2*0.7 = 0.14, or 14% of the boys in the camp are from school A and do not study science.
We are told that this number equals to 21, so 0.14*{total} = 21 --> {total} = 150.
Answer: C.
Question: Tough and Tricky questions: Work/Rate Problems.
A group of 4 junior lawyers require 4 hours to complete a legal research assignment. How many hours would it take a group of three legal assistants to complete the same research assignment assuming that a legal assistant works at two-thirds the rate of a junior lawyer?
Source: Chili Hot GMAT
A.13
B.10
C.9
D.8
Answer: D.8
Explanation: # of people times the # of hours:
4*4 = 16 --> 4 lawyers do 16worksin 4 hours.
3*8/3 = 24/3 = 8 --> 3 assistants do 8 worksin 8/3 hours (2/3*5= 10/3)
So, since the amount of work the assistants do is half the work the lawyers do, the time will be double, soANS D
Question: Five people are on an elevator that stops at exactly 5 floors. What is the probability that exactly one person will push the button for each floor?
A.5!/5^5
B.5^5/5!
C.5/5!
D.5/5^5
Answer: A.5!/5^5
Explanation: Each person out of 5 has 5 options, hence total # of outcomes is 5^5;
Favorable outcomes will be 5!, which is # of ways to assign 5 different buttons to 5 people
So basically # of arrangements of 5 distinct objects: 5!.
P=favorable/total=5!/5^5
Answer: A.
Question: In a jar there are 3 red gumballs and 2 blue gumballs. What is the probability of drawing at least one red gumball when drawing two consecutive balls randomly?
A.2/5
B.16/20
C.9/10
D.3/5
Answer: C.9/10
Explanation: P(at least one red) = 1 - P(no red, so 2 blue) = 1- 2/5*1/4 = 9/10.
Answer: C.
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?
A.2.87
B.2.88
C.2.8
D.2.86
Answer: B.2.88
Explanation: M = 6
S = 1.2
DS = 6 + 1.2 = 7.2
US = 6 - 1.2 = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
Answer: B
Question: For any numbers a and b, a#b = ab(5 − b). If a and a#b both represent positive numbers, which of the following could be a value of b?
A.3,2
B.3,2,1
C.4,3,2,1
D.4.4
Answer: C.4,3,2,1
Explanation: a#b positive then b may be positive or negative. if positive then b< 5 may be 4,3,2 or 1 and if negative then it is more than or equal to -1 negative . ab will be -ve which is not possible as a and a#b should be positive.
ans 4 ,3,2 and 1
C
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is?
A.41 years
B.40 years
C.76 years
D.14 years
Answer: B.40 years
Explanation: Sum of the present ages of husband, wife and child
= (27 * 3 + 3 * 3) = 90 years.
Sum of the present age of wife and child
= (20 * 2 + 5 * 2) = 50 years.
Husband's present age
= (90 - 50) = 40 years.
Answer:B
Question: How many different positive integers exist between 10^5 and 10^6, the sum of whose digits is equal to 2?
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: 100001
100010
100100
101000
110000
200000
TOTAL NO =6
D
Question: A and B go around a circular track of length 200 m on a cycle at speeds of 36 kmph and 72 kmph. After how much time will they meet for the first time at the starting point?
A.120 sec
B.198 sec
C.178 sec
D.20 sec
Answer: D.20 sec
Explanation: Time taken to meet for the first time at the starting point
= LCM { length of the track / speed of A , length of the track / speed of B}
= LCM { 200/ (36 * 5/18) , 200/ (72 * 5 /18) }
= LCM (20, 10) = 20 sec.
Answer:D
Question: The quantities S and T are positive and are related by the equation S=K/T, where k is a constant. If the value of S increases by 40 percent, then the value of T decreases by what percent?
A.25%
B.33 ¹/₃%
C.25%
D.66 ²/₃%
Answer: C.25%
Explanation: We can assign numbers:
lets say S = 2, K = 6 (constant) and T = 3 (so that S=K/T)
Now increasing S by 40% gives S=4, K remains constant, so T = 2 (6/2=3)
decrease in T= 1, percent decrease in T = (1/4)*100 = 25%
Answer C
Question: The average of 15 numbers is 75. Average of the first 8 of them is 68 and that of the last 8 is 77. Find the 8th number?
A.51
B.87
C.35
D.75
Answer: C.35
Explanation: Sum of all the 15 numbers = 15 * 75 = 1,125Sum of the first 8 of them = 8 * 68 = 544Sum of the last 8 of them = 8 * 77 = 616So, the 8th number = 544 + 616 - 1,125= 35.Answer: C
Question: An unbiased die is tossed. Find the probability of getting a multiple of 3
A.1/3
B.2/5
C.1/4
D.2/3
Answer: A.1/3
Explanation: Here S = {1,2,3,4,5,6}
E = event of getting a multiple of 3
E = {3,6}
P(E) = 2/6 = 1/3
Answer is A
Question: The radius of a semi circle is 6.4cm then its perimeter is?
A.32.9
B.32.4
C.22.4
D.32.8
Answer: A.32.9
Explanation: 36/7 r = 6.4 = 32.9
Answer:A
Question: The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 10 minutes, then the area of the park (in sq. m) is
A.153200
B.240000
C.153600
D.154000
Answer: B.240000
Explanation: Perimeter = Distance covered in 10 min. = 12000 x 10 m = 2000 m.
60
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 2000 or x = 200.
Length = 600 m and Breadth = 400 m.
Area = (600 x 400) m2 = 240000 m2.
B
Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
A.10.5
B.10.0
C.10.3
D.10.8
Answer: D.10.8
Explanation: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5 = 10.8 sec.
Answer: D
Question: Abhi roll a dice and he will get money 3 times the outcome. He gives K to shaylendar for every roll. Finally he gets profit of 3 rupees in every roll. what is the value of k?
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: as for 1st roll he gets 3 rupees and if he give 3 to shylendar he will have =3
2 = 6, 6-3=3
3 = 9, 9-3=6
4 = 12, 12-3=9................
so he is getting profit of 3 in every roll....... ans=3
ANSWER:B
Question: There are three vessels of equal capacity .Vessel A contains Milk and water in the ratio 7:3 ;Vessel B contains Milk and water in the ratio 2:1 and Vessel C contains Milk and water in the ratio 3:2 .If the mixture in all the three vessels is mixed up.What will be the ratio of water to milk ?
A.31/59
B.59/31
C.18/62
D.62/18
Answer: A.31/59
Explanation: 7:3=>7x+3x=10x
2:1=>2y+1y=3y
3:2=>3z+2z=5z
10x=3y=5z
Take LCM of 10,3,5=30
Or simply;
x=3
y=10
z=6
So,
Ratio of Water:Milk= (3x+y+2z)/(7x+2y+3z)=31/59
Ans:A