RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: One-fourth of certain journey is covered at the rate of 25 km/h, one-third at the rate of 30 km/h and the rest at 50 km/h. Find the average speed for the whole journey.
A.600/53km/h
B.1200/53 km/h
C.1800/53 km/h
D.1600/53 km/h
Answer: C.1800/53 km/h
Explanation: Solution: Let distance be 120 KM, hence 30 KM is covered by @ 25 kmph and 40 km covered by @ 30 kmph and rest 50 km has been covered@ 50 km.
Now, average = (120/total time taken);
= {120/[(30/25)+(40/30)+(50/50)}]
= 3600/106 = 1800/53 km/h.
Answer: Option C
Question: I travel the first part of my journey at 40 kmph and the second part at 60 kmph and cover the total distance of 240 km to my destination in 5 hours. How long did the first part of my journey last?
A.4 hours
B.2 hours
C.3 hours
D.2 hours 24 minutes
Answer: C.3 hours
Explanation: Explanatory Answer
The total time of journey = 5 hours.
Let 'x' hours be the time that I traveled at 40 kmph
Therefore, 5 - x hours would be time that I traveled at 60 kmph.
Hence, I would have covered x*40 + (5 - x)60 kms in the 5 hours = 240 kms.
Solving, for x in the equation 40x + (5 - x)*60 = 240, we get
40x + 300 - 60x = 240
=> 20x = 60 or x = 3 hours.
Answer C
Question: A popular website requires users to create a password consisting of the digits {1,2,3,4,5,6,7,8,9}. If no digit may be repeated and each password must be at least 8 digits long, how many passwords are possible?
A.8! + 9!
B.2 x 9!
C.8! x 9!
D.17!
Answer: B.2 x 9!
Explanation: If we choose the 9 different digits then they can be arranged in 9! ways.
The number of possible 8-digit passwords is 9*8*...*2 = 9!
The total number of passwords is 9! + 9! = 2*9!
The answer is B.
Question: A woman sold 300 oranges at $12.10, some at the rate of 3 for 35 cents and the rest at 4 for 85 cents. How many were sold at the first rate?
A.45
B.21
C.9
D.16
Answer: D.16
Explanation: This can be solved like a classical mixture problem but numbers are awkward to deal with.
It's easier to just look at the answer choices. You know that a multiple of 3 oranges has to be sold at the first rate, and a multiple of 7 at the second rate. You simple subtract the answer choices for the first rate from 100 and check whether the remainder (i.e. the number of oranges sold at the second rate) is a multiple of 4.
100 - 45 = 255 => not a multiple of 4 so exclude
100 - 21 = 279 => not a multiple of 4 so exclude
100 -9 = 291 => not a multiple of 4 so exclude
100 - 16 = 284 => a multiple of 4 so keep
100 - 13 = 287 => not a multiple of 4 so exclude
Hence, answer choice 16 is correct.
D
Question: If 8 boys can color 48 m long cloth in 2 days, then 6 boys can color 36 m long cloth in
A.day
B.days
C.days
D.days
Answer: A.day
Explanation: The length of cloth painted by one boy in one day = 96 / 8 × 2 = 6 m
No. of days required to paint 36 m cloth by 6 boys = 36/ 6 × 6 = 1 day.
A)
Question: If the price of a certain computer increased 20 percent from d dollars to 351 dollars, then 2d =
A.540
B.585
C.619
D.649
Answer: B.585
Explanation: Before Price increase Price = d
After 30% Price increase Price = d+(20/100)*D = 1.2d = 351 (Given)
i.e. d = 351/1.3 = $292,5
i.e. 2d = 2*292.5 = 585
Answer: option B
Question: an article with cost price of 280 is sold at 30% profit. what is the selling price?
A.198
B.364
C.369
D.207
Answer: B.364
Explanation: sp=1.30*280=364
ANSWER:B
Question: After successive discounts of 20%, 10% and 5% a certain good is sold for Rs. 6500. Find the actual price of the good.
A.s. 6000
B.s. 9000
C.s. 10800
D.s. 9503
Answer: D.s. 9503
Explanation: Let actual price was 100.
After three successive discount this will become,
100 ==20% discount => 80 ==10% discount => 72 ==5% discount = 68.4
Now Compare,
68.4 = 6500
1 = 6500/68.4
100 = (6500*100)/68.4 = Rs. 9503.
Answer: Option D
Question: In the gure below, arc SBT is one quarter of a circle with center R and radius
r. The length plus the width of rectangle ABCR is 8, and the perimeter of the shaded region
is 10 + 3. Find the value of r.
A.6
B.6:25
C.6:5
D.6:75
Answer: A.6
Explanation: Set x = RC and y = AR. It must then be x+y = 8 (by hypothesis) and x2+y2 = r2
(since the rectangle ABCR has one vertex in the circle). The perimeter of the shaded area is
then AS + SBT + TC + AC = (r 􀀀 y) + r=2 + (r 􀀀 x) +
p
x2 + y2 = 3r + r=2 􀀀 (x + y) =
3r + r=2 􀀀 8. All we need to so is solve for r in the equation 18 + 3 = (3 +
2 )r.
correct answer A
Question: If k, (k+200), (k+350), and 15*K are all multiples of V, then V could equal which of the following ?
A.20
B.V=25
C.V=75
D.100
Answer: B.V=25
Explanation: {Multiple of V} - {Multiple of V} = {Multiple of V}.
(K+200) - k = 200 = {Multiple of V}.
(K+350) - k = 350 = {Multiple of V}.
Both 200 and 350 are multiples of only option B.
Answer: B.
Question: list of salaries of 8 employees are listed below. What is the median salary?
$40,000, $29,000, $35,500, $31,000, $43,000, $30,000, $27,000, $33,000
A.$32,000
B.$28,500
C.$30,200
D.$30,800
Answer: A.$32,000
Explanation: Ordering the data from least to greatest, we get:
$27,000, $29,000, $30,000, $31,000, $33,000, $35,500, $40,000, $43,000
Since there is an even number of items in the data set, we compute the median by taking the mean of the two middlemost numbers.
$31,000 + $33,000 = $64,000
The median salary is $32,000.
Answer : A
Question: Tharak covers a part of the journey at 20 kmph and the balance at 70 kmph taking total of 8 hours to cover the distance of 400 km. How many hours has been driving at 20 kmph?
A.3 hours 12 minute
B.2 hours
C.4 hours 40 minutes
D.3 hours 20 minutes
Answer: A.3 hours 12 minute
Explanation: Let x be no. Of hours, and he travelled at 20kmph.
And balance distance (8-x)hr at 70kmph.
Total distance=20x+(8-x)hr =400
20x+(8-x)70=400
20x+560-70x=400
20x-70x=400-560
-50x=-160
x=3.2 =3 hr 12minutes
ANSWER:A
Question: In how many different ways can 5 girls and 4 boys form a circle such that the boys and the girls alternate?
A.576
B.425
C.215
D.321
Answer: A.576
Explanation: Explanation :
In a circle, 5 boys can be arranged in 4! ways
Given that the boys and the girls alternate.
Hence there are 4 places for girls which can be arranged in 4! ways
Total number of ways = 4! x 4! = 24 x 24 = 576. Answer : Option A
Question: Find the C.I. on Rs. 15,625 for 9 months at 16% per annum compounded quarterly?
A.Rs. 1851
B.Rs. 1941
C.Rs. 1951
D.Rs. 1961
Answer: C.Rs. 1951
Explanation: P = Rs. 15625, n = 9 months = 3 quarters, R = 16% p.a. per quarter.
Amount = [15625 * (1 + 4/100)3]
= (15625 * 26/25 * 26/25 * 26/25) = Rs. 17576 C.I. = 17576 - 15625 = Rs. 1951.
ANSWER:C
Question: In order to obtain an income of Rs. 650 from 10% stock at Rs. 96, one must make an investment of:
A.Rs. 3100
B.Rs. 6240
C.Rs. 6500
D.Rs. 9600
Answer: B.Rs. 6240
Explanation: To get Rs. 10, Investment is 96
To get Rs. 650, investment is (96/10)*650 = 6240
ANSWER:B
Question: Find the product of place value and face value of 5 in 65231
A.28000
B.25000
C.27000
D.26000
Answer: B.25000
Explanation: Place value of 5 in 65231 = 5 x 1000 = 5000
Face value = 5
required product = 5000 x 5 = 25000
Answer :B
Question: The average weight of 4 students decreases by 8 kg when one of them weighing 96 kg is replaced by a new student. The weight of the student is
A.62 kg
B.60 kg
C.64 kg
D.72 kg
Answer: C.64 kg
Explanation: Explanation :
Let the weight of student be x kg.
Given, Difference in average weight = 8 kg
=> (96-x)/4 = 8
=> x = 64
Answer : C
Question: The cost of 4 bags and 12 purses is Rs.1520, what is the cost of 10 bags and 30 purses?
A.Rs.3600
B.Rs.3500
C.Rs.3800
D.Rs.3900
Answer: C.Rs.3800
Explanation: Explanation:
Cost of 4 bags + 12 purses = Rs.1520
Multiply each term by 5/2, we get,
Cost of 10 bags + 30 purses = Rs.3800.
Answer: Option C
Question: Johnny travels a total of one hour to and from school. On the way there he jogs at 4 miles per hour and on the return trip he gets picked up by the bus and returns home at 20 miles per hour. How far is it to the school?
A.2 miles
B.6.6 miles
C.4.8 miles
D.8 miles
Answer: B.6.6 miles
Explanation: Answer: B) 6.6 miles.
Average speed for round trip = 2*a*b/(a+b), where a,b are speeds
so, average speed was = 2*4*20/(4+20) = 6.6m/hr
the distance between schoolhome should be half of that. ie. 6.6 miles
answer B
Question: If two numbers are in the ratio 4:7. If 10 is added to both of the numbers then the ratio becomes 6:10 then find the largest number?
A.80
B.40
C.140
D.100
Answer: C.140
Explanation: Explanation:
4:7
4x + 10 : 7x + 10 = 6 : 10
10[4x + 10] = 6[7x + 10]
40x + 100 = 42x + 60
100 – 60 = 42x – 40x
2x = 40
X = 20
Then the first number is = 4
7x = 140
Short cut method:
a:b = 4:7
c:d = 6:10
1.Cross multiplication with both ratios
a * d ~ b * c = 4 * 10 ~ 7 * 6 = 40 ~ 42 = 2
2. If 10 is added both the number means 10 * 6 = 60 and 10 * 10 = 100,
Then 60 ~ 100 = 40
===> 2 -----> 40
===> 1 -----> 20
==> 7 -----> 140
Answer: Option C
Question: The price of 80 apples is equal to that of 120 oranges. The price of 60 apples and 75 oranges together is Rs.1320. The total price of 25 apples and 40 oranges is
A.Rs. 660
B.Rs. 620
C.Rs. 820
D.Rs. 780
Answer: B.Rs. 620
Explanation: Explanation :
Let the price of one apple = a and price of one orange = b
The price of 80 apples is equal to that of 120 oranges
80a = 120b
=> 2a = 3b
⇒b=2a3-----(Equation 1)
price of 60 apples and 75 oranges together is Rs.1320
=>60a + 75b = 1320
=> 4a + 5b = 88
⇒4a+5(2a)3=88(∵ Substituted the value of b from equation 1)
=> 12a + 10a = 88 × 3
=> 6a + 5a = 44 × 3
=> 11a = 44 × 3
=> a = 4 × 3 = 12
b=2a3=2×123=8
Total price of 25 apples and 40 oranges
= 25a + 40b = (25 × 12) + (40 × 8) = 300 + 320 = 620
Answer : B
Question: A cylinder is being filled with sand weighing 200 kg per cubic foot. The cylinder has a diameter of 1 foot and is 5 feet tall. How much sand is being used??
A.250pi kg
B.500pi kg
C.500pi^2 kg
D.1000pi kg
Answer: A.250pi kg
Explanation: Answer is A.
Volume of Cylinder = Pi*r^2 *h --------> Pi * (1/2)^2 * 5 --------> Pi * (1/4) * 5 --------> (5/4)Pi cubic feet.
1 cubic feet = 200 kg. so (5/4)Pi cubic feet = ((200*5)/4)Pi ---------> 250Pi
Regards,
Abhijit answer is A
Question: How many 3-digit numbers are completely divisible 6 ?
A.25
B.78
C.93
D.150
Answer: D.150
Explanation: Explanation:
3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
D)
Question: Speed of a boat in standing water is 10kmph and speed of the stream is 1.5kmph. A man can rows to a place at a distance of 105km and comes back to the starting point. The total time taken by him is?
A.20.48hours
B.21.48hours
C.22.48hours
D.23.48hours
Answer: B.21.48hours
Explanation: Speed upstream = 8.5kmph
Speed downstream = 11.5kmph
Total time taken = 105/8.5 + 105/11.5 = 21.48 hours
Answer is B
Question: A candidate got 35% of the votes polled and he lost to his rival by 2250 votes. How many votes were cast?
A.7500
B.2028
C.2775
D.5496
Answer: A.7500
Explanation: 35%-----------L
65%-----------W
------------------
30%----------2250
100%---------? => 7500
Answer:A
Question: John was thrice as old as Tom 6 yrs back. He will be 5/3 times as old as Tom 6 years hence. How old is Tom today?
A.10
B.11
C.12
D.14
Answer: C.12
Explanation: Sol. RMBflSk -6 = 3 (Ravi - 6) ...(j)
and Rupesh + 6 = | (Ravi + 6) ...(ii)
Solving both the equations we get,
Ravi = 12 years.
C
Question: On what dates of April, 2001 did Wednesday fall?
A.2nd, 9th, 16th, 23rd
B.4th, 11th, 18th, 25th
C.3rd, 10th, 17th, 24th
D.1st, 8th, 15th, 22nd, 29th
Answer: B.4th, 11th, 18th, 25th
Explanation: Explanation:
We need to find out the day of 01-Apr-2001
01-Apr-2001 = (2000 years + period from 1-Jan-2001 to 01-Apr-2001)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Days from 1-Jan-2001 to 01-Apr-2001 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 1(Apr) = 91
91 days = 13 weeks = 0 odd day
Total number of odd days = (0 + 0) = 0 odd days
0 odd day = Sunday. Hence 01-Apr-2001 is Sunday.
Hence first Wednesday of Apr 2011 comes in 04th and successive Wednesdays come in 11th, 18th and 25th
Answer: Option B
Question: Rs 1000 is invested at 5% pa simple interest. If interest is added to principal after every 10 yr. Then we will get amount 2000 after how many year?
A.12 years.
B.13.66 years.
C.14 years.
D.16.66 years.
Answer: D.16.66 years.
Explanation: P = 1000.
R = 5%.
T = 10 years.
I = PTR/100 = (1000 * 5*10)/100 = 500.
Now,
Principal = 1000 + 500 = 1500.
A = 2000
I = 500
R = 5%
T = (100 * I)/PR = (100 * 500)/(1500 *5) = 6.66 Years.
Total Time = 10 + 6.66 = 16.66 years.
ANSWER : OPTION D
Question: Which of the following functions does not intersect with T = 3x^2 + 2x + 1
A.T = 3x^2 + 3x + 1
B.T = 2x^2 + 3x + 1
C.T = 3x^2 + 2x + 3
D.T = 4x^2 + 2x - 3
Answer: C.T = 3x^2 + 2x + 3
Explanation: Let’s find the actual intersecting point of given function and each choice T.
A. 3x^2 + 2x + 1 = 3x^2 + 3x + 1 --> x=0
B. 3x^2 + 2x + 1 = 2x^2 + 3x + 1 --> x^2 – x =0 --> x=0 or 1
C. 3x^2 + 2x + 1 = 3x^2 + 2x + 3 --> 1=3(X) --> they don’t have any intersect.
D. 3x^2 + 2x + 1 = 4x^2 + 2x - 3 --> x^2 –4=0 --> x= 2 or -2
E. 3x^2 + 2x + 1 = x^2 + 2x + 3 --> 2x^2 –2 =0 --> x= 1 or –1.
So only choice (C) has no intersecting point. The answer is (C).
Question: 40% of Ram's marks is equal to 20% of Rahim's marks which percent is equal to 30% of Robert's marks. If Robert's marks is 80, then find the average marks of Ram and Rahim?
A.76
B.56
C.56
D.90
Answer: D.90
Explanation: Given, 40% of Ram's marks = 20% of Rahim's marks = 30% of Robert's marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 40% of Ram's marks = 24.
=> Ram's marks = (24 * 100)/40 = 60
Also, 20% of Rahim's marks
= 24
=> Rahim's marks
= (24 * 100)/20 = 120
Average marks of Ram and Rahim
= (60 + 120)/2 = 90.
Answer: D
Question: A and B enter into partnership with capital as 7:9. At the end of 8 months, A withdraws. If they receive the profits in the ratio of 8:9 find how long B's capital was used?
A.7
B.9
C.10
D.12
Answer: A.7
Explanation: Explanation:
7 * 8 : 9 * x = 8:9 => x= 7
A)
Question: The average of numbers 0.64206, 0.64207, 0.64208 and 0.64209 is ?
A.0.64202
B.0.64204
C.0.642022
D.0.642075
Answer: D.0.642075
Explanation: Answer
Average = (0.64206 + 0.64207 + 0.64208 + 0.64209)/ 4
=2.5683/ 4
=0.642075
Correct Option: D
Question: Pid intended to type a seven-digit number, but the two 3's he meant to type did not appear. What appeared instead was the five-digit number 52115. How many different seven-digit numbers could Pid have meant to type?
A.10
B.16
C.21
D.24
Answer: C.21
Explanation: Should be 21.
Pid intended to type a seven-digit number there are two possibilities for placing 2 3s .
case 1: two 3s were missed consecutively. i.e. he typed 33 and it came blank on screen.
-5-2-1-1-5- in this arrangement we can fit 33 in 6 ways . (Six dashes, each dash represent one possible place for placing 33)
case 2: two 3s are not together, i.e. they have one or more digits between them .
-5-2-1-1-5- , in this arrangement
if we place first 3 at first dash i.e. 35-2-1-1-5- then the other 3 can fit into 5 places.
if we place first 3 at second dash i.e. -532-1-1-5- then the other 3 can fit into 4 places.
if we place first 3 at third dash i.e. -5-231-1-5- then the other 3 can fit into 3 places.
if we place first 3 at fourth dash i.e. -5-2-131-5- then the other 3 can fit into 2 places.
if we place first 3 at Fifth dash i.e. -5-2-1-135- then the other 3 can fit into 1 place.
so total 15 ways.
case 2 + case 1 = 6+ 15 = 21 ways
Answer C
Question: In a class, there are 18 boys who are over 160 cm tall. If these constitute three-fourths of the boys and the total number of boys is two-thirds of the total number of students in the class, what is the number of girls in the class ?
A.6
B.12
C.18
D.19
Answer: B.12
Explanation: In a class, there are 18 boys who are over 160 cm tall. If these constitute three-fourths of the boys , then total no of boys = 18*4/3 = 24 boys.
the total number of boys (24)is two-thirds of the total number of students in the class, then total students = 24*3/2= 36
no. of girls = 36-24=12
ANSWER:B
Question: 0.04 x 0.0162 is equal to:
A.6.48 x 10(power -4)
B.6.48 x 10(power -3)
C.9.48 x 10(power -4)
D.5.48 x 10(power -4)
Answer: A.6.48 x 10(power -4)
Explanation: 4 x 162 = 648. Sum of decimal places = 6.
So, 0.04 x 0.0162 = 0.000648 = 6.48 x 10(power -4)
Answer is A.
Question: The speed of a boat in still water is 80kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
A.22 kmph
B.40 kmph
C.60 kmph
D.15 kmph
Answer: C.60 kmph
Explanation: Speed downstream = 80 + 20 = 100 kmph
Speed upstream = 80 - 20 = 60 kmph
Answer:C
Question: What is the total number of integers between 20 and 70 that are divisible by 2?
A.19
B.25
C.24
D.26
Answer: B.25
Explanation: 22, 24, 26, ..., 56,58
This is an equally spaced list; you can use the formula:
n = (largest - smallest) / ('space') + 1 = (70 - 22) / (2) + 1 = 48/2 + 1 = 24 + 1 = 25
Answer is B
Question: A room 4 m 47 cm long and 7m 77 cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor.
A.38636
B.38640
C.38647
D.38591
Answer: D.38591
Explanation: Explanation:
Area of the room = (447 x 777) cm2.
Size of largest square tile = H.C.F. of 447 cm and 777 cm = 3 cm.
Area of 1 tile = (3 x 3) cm2.
Number of tiles required =(447×777)/(3×3)=38591
Answer: Option D
Question: A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
A.16
B.14
C.15
D.18
Answer: C.15
Explanation: A's 2 day's work= (1/20)*2=1/10
(A + B + C)'s 1 day's work =(1/20+1/30+1/60) = 6/60 =1/10
Work done in 3 days = (1/10+1/10) = 1/5
Now,	1/5 work is done in 3 days.
Whole work will be done in (3 x 5) = 15 days.
ANSWER:C
Question: A certain number of donkeys and an equal number of men are going to a village. Half of the men are on their donkey's back while the remaining are walking along leading their donkeys. If the number of legs walking on the ground is 70. How many donkeys are there?
A.218
B.277
C.299
D.267
Answer: B.277
Explanation: Answer:B
Question: Two numbers are respectively 20% and 25% more than a third number. The percentage that is first of the second is?
A.33
B.71
C.96
D.55
Answer: C.96
Explanation: I II III
120 125 100
125----------120
100-----------? => 96%
\Answer:C
Question: A certain research group plans to create computer models of x% of a list of 10,000 bacterial species known to inhabit the human body. After a budget cut, the group finds it must reduce this selection by (x − 7)%. In terms of x, how many species of bacteria will the group be able to model?
A.x*x – 5x
B.(x)*(107 – x)
C.(100)(105 – x)
D.(100)(95 – x)
Answer: B.(x)*(107 – x)
Explanation: Initial: (x/100)*10000 = 100x (bacterial species)
After reduce BY (x - 7)%, the percentage of bacterial species = 1 - (x - 7)% = 1 - (x - 7)/100 = (107 - x)/100
Note: Difference between reduce to[means: the remain] and reduce by[means: the remain = 1 -reduce by]
So, the number of bacterial species after reducing: 100x*(107 - x)/100 = (x)*(107 - x)
Ans is B.
Question: In each of the following questions a number series is given with one term missing. Choose the correct alternative that will continue the same pattern and fill in the blank spaces.
2, 7, ?, 23, 34, 47
A.31
B.14
C.36
D.31
Answer: B.14
Explanation: B
14
The given sequence is +5, +7, +9, ——
ie. 2+ 5 = 7, 7 + 7 = 14, 14 + 9 = 23
Question: Mid intended to type a seven-digit number, but the two 3's he meant to type did not appear. What appeared instead was the five-digit number 52115. How many different seven-digit numbers could Mid have meant to type?
A.10
B.16
C.21
D.24
Answer: C.21
Explanation: Should be 21.
Mid intended to type a seven-digit number there are two possibilities for placing 2 3s .
case 1: two 3s were missed consecutively. i.e. he typed 33 and it came blank on screen.
-5-2-1-1-5- in this arrangement we can fit 33 in 6 ways . (Six dashes, each dash represent one possible place for placing 33)
case 2: two 3s are not together, i.e. they have one or more digits between them .
-5-2-1-1-5- , in this arrangement
if we place first 3 at first dash i.e. 35-2-1-1-5- then the other 3 can fit into 5 places.
if we place first 3 at second dash i.e. -532-1-1-5- then the other 3 can fit into 4 places.
if we place first 3 at third dash i.e. -5-231-1-5- then the other 3 can fit into 3 places.
if we place first 3 at fourth dash i.e. -5-2-131-5- then the other 3 can fit into 2 places.
if we place first 3 at Fifth dash i.e. -5-2-1-135- then the other 3 can fit into 1 place.
so total 15 ways.
case 2 + case 1 = 6+ 15 = 21 ways
Answer C
Question: A computer was sold at a loss of 20%. If it was sold for Rs.3200 more, there would have been a gain of 12%. What is the cost price?
A.Rs.12000
B.Rs. 8000
C.Rs.10000
D.Rs. 20000
Answer: C.Rs.10000
Explanation: 80%
112%
--------
32% ---- 3200
100% ---- ? => Rs.10000
Answer:C
Question: Sum of the squares of three numbers is 138 and the sum of their products taken two at a time is 131. Find the sum?
A.20
B.22
C.24
D.26
Answer: A.20
Explanation: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 138 + 2* 131
a + b + c = √400 = 20
A
Question: Given two fair dice, what is the probability W that the sum of their numbers is 4 if exactly one die shows a 3?
A.a) 2/11
B.b) 1/18
C.c) 3/11
D.d) 2/39
Answer: A.a) 2/11
Explanation: If exactly one die shows 3, there are 10 such combinations (given that we have 2 fair dice).
1:3, 2:3, 4:3, 5:3, 6:3,
3:1, 3:2, 3:4, 3:5, 3:6
The sum of numbers would be 4 for two events: 1:3, 3:1.the probability W that the sum of their numbers is 4 if exactly one die shows a 3
2/11 would be the answer if 'at least one of the die shows a 3'.A
Question: If a tire rotates at 400 revolutions per minute when the car is traveling 96km/h, what is the circumference of the tire?
A.2
B.1
C.4
D.3
Answer: C.4
Explanation: 400 rev / minute = 400 * 60 rev / 60 minutes
= 24,000 rev / hour
24,000 * C = 96,000 m : C is the circumference
C = 4 meters
correct answer C
Question: An design manager has 10patterns of chairs & 7patterns of tables. In how many ways can he make a pair of table & chair?
A.70
B.40
C.80
D.90
Answer: A.70
Explanation: He has has ten patterns of chairs and eight patterns of tables
Hence, A chair can be arranged in 10 ways and
A table can be arranged in 7 ways
Hence one chair and one table can be arranged in 10 x 7 ways = 70 ways
A
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?
A.3630
B.2879
C.289
D.279
Answer: A.3630
Explanation: 6300:4200:10500
3:2:5
3/10 * 12100 = 3630
Answer:A
Question: Two brothers were expected to return here on the same day. Rajat returned 3 days earlier but Rohit returned 4 days later. If Rajat returned on Tuesday, what was the expected day when both the brothers were to return home and when did Rohit Return?
A.Wednesday, Sunday
B.Thursday, Monday
C.Friday, Tuesday
D.Monday, Friday
Answer: C.Friday, Tuesday
Explanation: Rajat returned on Tuesday -i.e. 3 days earlier
so actual day to return home is Friday.
Rohit returned after days so Tuesday.
ANSWER:C
Question: How many seconds will a 700 meter long train moving with a speed of 63 km/hr take to cross a man walking with a speed of 3 km/hr in the direction of the train ?
A.48
B.36
C.42
D.11
Answer: C.42
Explanation: Explanation:
Here distance d = 700 mts
speed s = 63 - 3 = 60 kmph = 60 x 5/18 m/s
time t = = 42 sec.
Answer: C
Question: Suppose five circles, each 4 inches in diameter, are cut from a rectangular strip of paper 12 inches
long. If the least amount of paper is to be wasted, what is the width of the paper strip?
a=sqrt(3)
A. 5
B. 4 +2a
C. 8
D. 4(1+ a)
Answer: B. 4 +2a
Explanation: Also if we dont go by 30:60:90 rule, we can arrive at the length of by pythagoras theorem.
(AC)^2 + (BC)^2 = AB^2
(AC)^2 + 2^2 = 4^2
AC = 2 root b.
so the width of paper = 2 + 2 + 2 root 3 --> 4 + 2 root 3.
which is B.