RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Renu can do a piece of work in 6 days, but with the help of her friend Suma , she can do it in 3 days. In what time Suma can do it alone?
A.6
B.12
C.14
D.15
Answer: A.6
Explanation: Renuâ€™s one dayâ€™s work = 1/6
Sumaâ€™s one dayâ€™s work = 1/3 - 1/6 = 1/6
Suma can do it alone in 6 days.
ANSWER:A
Question: A certain sum of money doubles itself in 10 years in how much many years will it trible itself at the same rate?
A.20
B.99
C.88
D.77
Answer: A.20
Explanation: 100 ---- 100 --- 10
100 --- 10
--------------------
300 ---- 20 years
Answer: A
Question: In a race of 200 m. A can beat B by 15 m and C by 19 m then how much time C would take To beat B in the race of 3700 m ?
A.50
B.60
C.70
D.80
Answer: D.80
Explanation: In 200 race A:B=200/185 , A:C=200/181
than in 3700m race B beats by C,3700- (181/185)*3700=80
ANSWER:D
Question: If a and b are consecutive integers (b>a), which of the following statements could be false? 1. a^3+b is always even number. 2. ab is even number 3. (a + b) is always an odd number.
A.II only
B.III only
C.I only
D.I,II only
Answer: C.I only
Explanation: 2^3+3 =8+3 = 11 Option I false
odd*even = even. Option II is true
odd + even = odd. Option III is true
Answer : C
Question: Three numbers are such that the second is as much
lesser than the third as the first is lesser than
the second. If the product of the two smaller numbers
is 85 and the product of two larger numbers is 115.
Find the middle number?
A.10
B.11
C.12
D.13
Answer: A.10
Explanation: Let the three numbers be x,y,z
2y = x+z.....................1
Given that the product of two smaller numbers is 85
x y = 85................2
Given that the product of two larger numbers is 115
y z = 115...............3
Dividing 2 and 3 x y /y z = 85/115
x / z = 17 / 23
From 1
2y = x+z
2y = 85/y + 115/y
2y2 = 200
y2 = 100
y = 10
ANSWER: A 10
Question: The principal that amounts to Rs. 4913 in 3 years at 6 1/4 % per annum C.I. compounded annually, is?
A.4029
B.4089
C.4029
D.4096
Answer: D.4096
Explanation: Principal = [4913 / (1 + 25/(4 * 100))3]
= 4913 * 16/17 * 16/17 * 16/17
= Rs. 4096.
Answer: D
Question: A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?
A.2
B.3
C.4
D.1
Answer: C.4
Explanation: S = 600/40 = 15 mps
S = 3600/15 = 240 sec = 4 min
ANSWER C
Question: A store’s selling price of $2500 for a certain printer would yield a profit of 40 percent of the store’s cost for the printer. What selling price would yield a profit of 50 percent of the printer’s cost?
A.	$2400
B.	$2464
C.	$2650
D.	$2478
Answer: D.	$2478
Explanation: 1.4x = 2500
x=2500/1.4
so, 1.5X = 2500*1.5/1.4= 2478
Answer:- D
Question: A man buys an article for $100. and sells it for $115. Find the gain percent?
A.10%
B.15%
C.25%
D.20%
Answer: B.15%
Explanation: C.P. = $100
S.P. = $115
Gain = $15
Gain% = 15/100 *100 = 25%
Answer is B
Question: A reward of $1400 was divided among a group of 36 rescue workers such that each male in the group received $50. How much did each of the 16 females receive?
A.$10
B.$12.50
C.$25
D.$37.50
Answer: C.$25
Explanation: x = amount each female received
amount each male received = 50
number of females = 16
number of males = 36 - 16 = 20
total to males = 20(50) = 1000
total to females = 16x
reward = total to males + total to females
1400 = 1000 + 16x
1400 - 1000 = 16x
400 = 16x
25 = x
Answer: C
Question: A train passes a station platform in 62 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
A.615 m
B.240 m
C.168 m
D.444 m
Answer: D.444 m
Explanation: Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/62 = 15 => x
= 444 m
Answer: D
Question: The population of a town is 10000. It increases annually at the rate of 20% p.a. What will be its population after 4 years?
A.14300
B.20736
C.14500
D.14600
Answer: B.20736
Explanation: Formula :
( After =100 denominator
Ago = 100 numerator)
10000 × 120/100^4 = 20736
B)
Question: By selling an article at Rs.800, a shopkeeper makes a profit of 35%. At what price should he sell the article so as to make a loss of 25%?
A.s.416
B.s.480
C.s.429
D.s.128
Answer: A.s.416
Explanation: SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 35% = 35% of 640 = Rs.224
SP = CP - Loss = 640 - 224
= Rs.416
Answer:A
Question: John makes $60 a week from his job. He earns a raise andnow makes $70 a week. What is the % increase?
A.10.2%
B.16.66%
C.18.7%
D.19.24%
Answer: B.16.66%
Explanation: Increase = (10/60)*100 = (1/6)*100 = 16.66%.
B
Question: Nails and screws are manufactured at a uniform weight per nail and a uniform weight per screw. If the total weight of one screw and one nail is half that of 6 screws and one nail, then the total weight of 3 screws, and 3 nails is how many times that of 2 screws and 4 nails?
A.a. 4
B.b. 5/2
C.c. 2
D.d. 3/2
Answer: D.d. 3/2
Explanation: let the weight of nail be n and that of screw be s..
so s+w=1/2 * (6s+1n)...
or 1n = 4s..
lets see the weight of 3 s and 3n= 3s+3*4s=15s..
and weight of 2s and 4n= 2s+4*2s=10s..
ratio= 15s/10s=15/10=3/2
D
Question: A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
A.30
B.40
C.50
D.60
Answer: A.30
Explanation: Explanation:
Let the side of the square(ABCD) be x meters.
Then, AB + BC = 2x metres.
AC = √2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = 0.59x/2x × 100 % =30% (approx)
Answer: A
Question: Which of the following inequalities has a solution set, when graphed on the number line, is a single line segment of finite length?
A.2 <= 335x+4 <= 6
B.2 <= 32x+4 <= 6
C.2 <= 334x+4 <= 6
D.2 <= 3x+4 <= 6
Answer: D.2 <= 3x+4 <= 6
Explanation: The key words in the stem are:a singleline segment offinite length
Now, answer choices A, B, and C can not be correct answers as solutions sets for these exponential functions are not limited at all (>= for even powers and <= for odd power) and thus can not be finite (x can go to + or -infinity for A and C and x can got to -infinity for B). As for D: we have thatabsolute valueof x is between two positive values, thus the solution set for x (because of absolute value) will be two line segments which will be mirror images of each other.
Answer: D.
Question: The speed of a boat in upstream is 100 kmph and the speed of the boat downstream is 150 kmph. Find the speed of the boat in still water and the speed of the stream?
A.25 kmph
B.17 kmph
C.19 kmph
D.17 kmph
Answer: A.25 kmph
Explanation: Speed of the boat in still water
= (100+150)/2
= 125kmph. Speed of the stream
= (150-100)/2
=25 kmph.
Answer: A
Question: A car traveled 75% of the way from town A to town B at an average speed of 90 miles per hour. The car travels at an average speed of S miles per hour for the remaining part of the trip. The average speed for the entire trip was 40 miles per hour. What is S ?
A.15
B.20
C.25
D.30
Answer: A.15
Explanation: Total distance = 100 miles (easier to work with %)
75% of the distance = 75 miles
25% of the distance = 25 miles
1st part of the trip → 75/90 = 0.833
2nd part of the trip → 25/S = t
Total trip → (75+25)/40 = 0.833+ t » 100/40 = 0.833 + t » 2.5 = 0.833+ t » t = 1.667
Back to 2nd part of the trip formula: 25/S = 1.667 » S = 15
Ans A
Question: Find the least number which when divided by 31 and 9 leaves a remainder of 3 in each case.
A.280
B.282
C.284
D.286
Answer: B.282
Explanation: The least number which when divided by different divisors leaving the same remainder in each case
= LCM(different divisors) + remainder left in each case.
Hence the required least number
= LCM(31, 9) + 3 = 282.
ANSWER:B
Question: A rectangular lawn of length 200m by 120m has two roads running along its center, one along the length and the other along the width. If the width of the roads is 5m what is the area T covered by the two roads?
A.400
B.1550
C.1575
D.1600
Answer: C.1575
Explanation: Area Covered by Road Along the Length = 5*200 = 1000 Square Meter
Area Covered by Road Along the Width = 5*120 = 600 Square Meter
Common Area in both Roads (where the roads intersect) = Square with Side 5 meter = 5*5 = 25
Total Area of the Roads T= 1000+600-25 = 1575
Answer: option C
Question: Vincent has $12,731 dollars in his wallet. What is the least amount of money (in whole number of dollars) that he must add if he wants to split this money evenly among his nine friends?
A.$1
B.$2
C.$3
D.$4
Answer: D.$4
Explanation: In order to divide the sum in 9 parts, the amount must be divisible by 9
Divisibility rule of 9: The sum of the digits must be divisible by 9
Sum of digits of 12,731= 14 and 18 is divisible by 9.
Hence we need to add 4 to this number for it to be divisible by 9
Correct Option: D
Question: A person can row at 9 kmph and still water. He takes 4 1/2 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 1 kmph?
A.27
B.22
C.20
D.87
Answer: C.20
Explanation: Let the distance between A and B be x km.
Total time = x/(9 + 1) + x/(9 - 1) = 4.5
=> x/10 + x/8 = 9/2 => (4x + 5x)/40 = 9/2 => x = 20 km
Answer: C
Question: There are 13 South American countries, Anny has won a ticket to fly from Denver to one South American country and then directly to another South American Country before returning home to Denver again. Assuming there are four airports in each country, how many flights paths can Anny choose from?
A.13.12.11.10.4.4.
B.13.12.11.10.4
C.13.12.4.4.
D.13.12.4
Answer: C.13.12.4.4.
Explanation: flights paths can Anny choose from There are 13 ways to chose the first destination,
then, 12 ways to chose next destination, with option of 4 airports (13x4)
then, to return he has 4 options to chose the airports
Thus, 13*12*4*4 ways.
Using permutations:
If the solution had written 13P1 instead of 13C1 it won't matter. As per the definition - making arrangements of the combinations gives permutations.
Since there are no arrangement for 1 item, permutationscombinations are equal.C
Question: log4 2+log4 32 i equal to?
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: apply log(ab) for each term
then log4+log2+log4+log32
2log2+log2+2log2+5log2 add these==>10log2=10*0.3=3
ANSWER:B
Question: If 5400 mn = k^4, where m, n, and k are positive integers, what is the least possible value of 3m + n?
A.11
B.18
C.20
D.45
Answer: D.45
Explanation: k^4=5400∗mn
k^4=3^3.2^3.5^2.mn
In order to make RHS a perfect power of 4, we require it to be multiplied by 3, 2 & 5^2
mn=3.2.5^2
mn = 150 = 10 * 15 (Least possible)
Answer = 3*10 + 15 = 45
ANSWER:D
Question: Triangle XYZ is an isosceles right triangle. If side XY is longer than side YZ, and the area of the triangle is 9, what is the measure of side XY?
A.4
B.4√2
C.8
D.6
Answer: D.6
Explanation: ans D..6..
xy being larger means it is the hyp..
area =(1/2)*(yz)^2=9 or yz=3*\sqrt{2}..
therefore hyp=xy=6
Question: A train 310 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
A.4
B.6
C.5
D.17
Answer: D.17
Explanation: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [310 * 3/55] sec = 17 sec
ANSWER:D
Question: Find the number of square tiles to cover the floor of a room measuring 4 m * 9 m leaving 0.40 m space around the room. A side of square tile is given to be 40 cms?
A.164
B.476
C.268
D.208
Answer: A.164
Explanation: Area of the room =3.2 * 8.2 =26.24
Area of the tile = 0.4 *0.4=0.16
No. of tiles =26.24/0.16 =164
Answer : A
Question: Let the number which when multiplied by 15 is increased by 196.
A.14
B.20
C.26
D.28
Answer: A.14
Explanation: Solution
Let the number be x .
Then, 15x - x = 196
‹=›14x = 196
x ‹=› 14.
Answer A
Question: There are 35 students in a hostel. If the no. of students increases by 8, the expenses of the mess increase by Rs.42/day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess?
A.371.87
B.400.37
C.420.37
D.450.37
Answer: A.371.87
Explanation: Suppose the average join the mess , total expenditure = 35x + 42
Now, the average expenditure = (35x + 42)/ (35 + 8) = x – 1
or, 35x + 42 = 43x – 43
or, x = 10.625
Thus the original expenditure of the mess = 35 x 10.625 = Rs. 371.87
A
Question: In a company, 52 percent of the employees are men. If 60 percent of the employees are unionized and 70 percent of these are men, what percent of the non-union employees are women?
A.65%
B.70%
C.75%
D.80%
Answer: C.75%
Explanation: The percent of employees who are unionized and men is 0.7*0.6 = 42%
The percent of employees who are unionized and women is 60 - 42 = 18%
48% of all employees are women, so non-union women are 48%-18% = 30%
40% of all employees are non-union.
The percent of non-union employees who are women is 30%/40% = 75%
The answer is C.
Question: The average of 28 numbers is 45. If two numbers namely 40 and 45 are discarded, The average of
remaining numbers is?
A.35.5
B.37.5
C.45.1
D.34.5
Answer: C.45.1
Explanation: Total of 50 numbers = 28 * 45 = 1260
Average of 26 numbers = 1260-(40+55) / 26
= 1175 / 26= 45.1
Answer is C.
Question: If the sales tax be reduced from 3 (1/5) % to 2 (1/2) %, then what difference does it make to a person who purchases a bag with marked price of Rs. 6400?
A.Rs. 150.40
B.Rs. 44.80
C.Rs. 140.40
D.Rs. 50.48
Answer: B.Rs. 44.80
Explanation: Explanation:
Required difference = (3 (1/5) of Rs. 6400) - (2 (1/2) of Rs. 6400)
= (16/5 – 5/2) % of Rs. 6400
= (7/10) x (1/100) x 6400
= Rs. 44.80
ANSWER B
Question: In how many ways the letters of the word RAIXBON be arranged?
A.4354
B.8454
C.4356
D.5040
Answer: D.5040
Explanation: Total ways of arranging the letters = 7! = 5040 ways.
D)
Question: Paul's salary was decreased by 50% and subsequently increased by
50%.How much percent does he lose?
A.0
B.25
C.50
D.30
Answer: B.25
Explanation: Let the original salary = $100
New final salary=150% of (50% of Rs.100)=
$((150/100)*(50/100)*100)=$75.
Decrease = 25%
Answer option B)25.
Question: In how many different orders can the people Alice, Benjamin, Charlene, David, Elaine, Frederick, Gale, and Harold be standing on line if each of Alice, Benjamin, Charlene must be on the line before each of Frederick, Gale, and Elaine?
A.1,008
B.1,296
C.1,512
D.2*1008
Answer: D.2*1008
Explanation: Place D and H first: 8 options for D, 7 options for H
We are left with 6 empty places. A, B and C must take first 3 places and F, G, Emust take the remaining three. A, B and C can be arranged in their places in 3! ways. The same for F, G, and E
Total = 8*7*3!*3! = 2*1008
Answer: D.
Question: A room contains 180 people, 15 percent of whom are women. A group of people, 30 percent of whom are women, leaves the room. Of the people remaining in the room, 10 percent are women. How many people left the room?
A.25
B.35
C.45
D.55
Answer: C.45
Explanation: Say group of x people left the room.
# of women in the room was 0.15*180=27;
# of women in the group that left 0.3x;
# of women in the room after the group left it is 0.1(180-x);
So, 27-0.3x= 0.1(180-x) --> x=45.
Answer: C.
Question: A can finish a piece of work in 4 days. B can do it in 10 days. They work together for two days and then A goes away. In how many days will B finish the work?
A.3
B.5
C.6
D.7
Answer: A.3
Explanation: 2/4 + (2 + x)/10 = 1 => x = 3 days
Answer: A
Question: If a, b, c, and d are integers; w, x, y, and z are prime numbers; w < x < y < z; and (wa)(xb)(yc)(zd)=660(wa)(xb)(yc)(zd)=660, what is the value of (a + b) – (c + d)?
A.–1
B.0
C.1
D.2
Answer: C.1
Explanation: 660660= 2^2 x 3^1 x 5^1 x 11^1
w < x < y < z = 2 < 3 < 5 < 11
So, can can say -
w = 2
x = 3
y = 5
z = 11
Hence a = 2 , b = c = d = 1
(a + b) – (c + d) will be (2 + 1) – (1 + 1) = 1
Answer will be (C)
Question: 5358 x 51 = ?
A.273435
B.272651
C.273258
D.273898
Answer: C.273258
Explanation: C
5358 x 51 = 5358 x (50 + 1)
= 5358 x 50 + 5358 x 1
= 267900 + 5358
= 273258.
Question: HOW MANY KGS OF TEA WORTH RS.25/KG MUST BE BLENDED WITH 30 KGS OF TEA WORTH RS.30/KG SO THAT BY SELLING THE BLENDED VARIETY AT RS.30/KG THERE SHOULD BE A GAIN OF 10%
A.36
B.40
C.32
D.42
Answer: A.36
Explanation: Let the weight of tea(25 per kg) to be used - X
The total cost of the blend - total cost of 25 RS tea + total cost of 30 RS tea
- 25X + 900 ( as the total weight of 30 RS tea is already given i.e 30)
total weight of the blend = X + 30 ( which should be sold per 30 RS and result in 10% profit)
The equation follows like this
25X + 900 + (10 % of (25X + 900)) = 30( X + 30)
25X + 900 +2.5 X + 90 = 30 X + 900
27.5 X + 990 = 30 X + 900
2.5 X = 90
X= 90/2.5 = 36
ANSWER:A
Question: Round off the given number to nearest hundreds
10158
A.10000
B.10200
C.11000
D.10150
Answer: B.10200
Explanation: the given number is 10158
its tens digit is 5. so replace each of the tens and ones digit by 0 and increase the hundreds digit by 1 to get the rounded off number to the nearest hundred.
correct answer (B)
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 25 hours respectively. The ratio of their speeds is:
A.2 : 3
B.5 : 3
C.6 : 7
D.9 : 16
Answer: B.5 : 3
Explanation: Let us name the trains as A and B. Then,
(A's speed) : (B's speed) = âˆšb : âˆša = âˆš25 : âˆš9 = 5 : 3.
Answer B
Question: Each of 7 workers will pick a day of the week as his vacation day. What is the probability that exactly one worker will pick a different day?
A.7!/7^7
B.1/7!
C.1/7^7
D.7/7!
Answer: A.7!/7^7
Explanation: Each worker out of 7 has 7 options (Sunday, Monday, Tuesday,.., Saturday), hence total # of outcomes is 7^7;
Favorable outcomes will be 7!, which is # of ways to assign 7 different day to 7 workers.
P=favorable/total=7!/7^7
Answer: A.
Question: The H.C.F of two numbers is 8. Which of the following can never be their L.C.M?
A.24
B.48
C.56
D.60
Answer: D.60
Explanation: H.C.F of two numbers divides their L.C.M exactly. Clearly, 8 is not a factor of 60.
ANSWER:D
Question: Set Q consists of the following five numbers: Q = {7, 8, 13, 21, 34}. Which of the following sets has the same standard deviation as Set Q?
I. {35, 38, 43, 51, 64}
II. {10, 16, 26, 42, 68}
III. {46, 59, 67, 72, 75}
A. I only
B. III
C. IIII
D. IIIII
Answer: A. I only
Explanation: (1)	Multiplying all the numbers change Standard Deviation
(2)	Adding and subtracting all the numbers with the same number keeps the standard deviation same.
If you observe Set I and III are added versions of Set Q .
Set I: 5 has been added to the Set Q
Set III: Subtract each element from 80 and you would find a number there in the Set Q.
Set II: elements are multiplied by 2 and standard deviation changes.
Hence the answer is A.
Question: A dealer owns a group of station wagons and motorcycles. If the number of tires (excluding spare tires) on the vehicles is 30 more than twice the number of vehicles, then the number of station wagons the dealer owns is
A.10
B.15
C.20
D.30
Answer: B.15
Explanation: Assume X station wagons, Y motorcycles
Framing the equation.
2(X+Y)+30 = 4X + 2Y
=> X = 15
ANSWER:B
Question: What is the different between the place value and face value of 3 in the numeral 1375?
A.280
B.289
C.297
D.300
Answer: C.297
Explanation: place value of 3 = 3 * 100 = 300
face value of 3 = 3
300 - 3 = 297
C)
Question: If 4a = 5b = 30, then 40ab =
A.900
B.1800
C.2250
D.1650
Answer: B.1800
Explanation: 4a * 5b = 30 * 30 = 900
20 ab = 900
i.e. 30 ab = 1800
Answer: Option B
Question: In a room filled with 5 people, 3 people have exactly 2 siblings in the room and 2 people don't have any siblings in the room. If two individuals are selected from the room at random, what is the probability that those two individuals are NOT siblings?
A.3/5
B.4/5
C.3/10
D.7/10
Answer: D.7/10
Explanation: The 5 people consist of one set of 3 siblings and 2 other people who are not siblings.
The number of ways to choose 2 people is 5C2 = 10.
The number of ways to choose 2 from the group of siblings is 3C2 = 3.
The number of ways to choose 2 people who are not siblings is 10-3=7.
P(the two people are not siblings) = 7/10
The answer is D.
Question: A and B started a business with initial investments in the ratio 12 : 3, after some months B withdrawn his investment, and their share in the annual profits were in the ratio 8 : 7. Then how long B was in the business ?
A.42 months
B.8 months
C.9 months
D.5 months
Answer: A.42 months
Explanation: Let Sumit in the business for ‘a’ months.
Investment Ratio Amit to Sumith = 12:3
Profit sharing ratio = 8 : 7.
Amit is in the business for 12 months.
Then Sumit in the business for
(12 × 12) / (3 × a) = 8 / 7 => 24a = 1008 or
a = 1008 / 24 = 42 or 42 months
Option A
Question: What is the perimeter of a square field whose diagonal is 8√2?
A.33
B.32
C.88
D.99
Answer: B.32
Explanation: 4a = 32 m
Answer: B
Question: What are the last two digits of 5in2007th ?
A.75
B.65
C.55
D.25
Answer: D.25
Explanation: Just keep track of the last two digits of the consecutive powers of 5 and note
that 5-2round- = 25 and 5 × 25 = 125.
correct answer D
Question: The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
A.16
B.13
C.18
D.11
Answer: C.18
Explanation: Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l2 = 324 => l = 18.
Answer: C
Question: In Orange County one sixth of the people are gathering mushrooms and one seventh of the people are collecting apples. What can be the number of people in Orange County?
A.60.
B.42.
C.85.
D.140.
Answer: B.42.
Explanation: The number must be an integer and multiple of both 6 and 7.
Only option B fulfill this condition and hence is the answer.
Question: Pipe A can empty a tank in 12 hrs and pipe B can empty it in 24 hrs. If both the pipes are opened to empty in the fully filled tank . In how many hours will it be emptied tank?
A.6
B.7
C.8
D.9
Answer: C.8
Explanation: Part emptied A in 1 hr= (1/12)
Part emptied B in 1 hr= (1/24)
Part emptied by (A+B) together in 1 hr=(1/12)+(1/24)=1/8
So, The tank will be empty in 8 hrs
Answer : C
Question: Sum of two numbers is 25 and their difference is 13. Find their product.
A.104
B.108
C.114
D.124
Answer: C.114
Explanation: Explanation:
Friends, this sort of question is quite important in competitive exams, whenever any question come which have relation between sum, product and difference, this formula do the magic:
=>(x+y)2=(x−y)2+4xy
<=>(25)2=(13)2+4xy
<=>4xy=(25)2−(13)2
<=>xy=456/4=114
Option C
Question: What is the remainder when 617 + 1176 is divided by 7?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: 617 + 1176 mod 7
=> 617%7 + 1176%7
=> 1 + 0
=> 1%7
=> 1
ANSWER:A
Question: What percent of 60 is 100?
A.133 1⁄3
B.75
C.166.66
D.33 1⁄3
Answer: C.166.66
Explanation: % of 60 is 100?
= 100/60 = 5/3 = 166.66%
Thus C is the correct answer.
Question: If the average of ten numbers is 50, then which of the following could be the standard deviation of the ten numbers?
I. 0
II. 10
III. 50
A.I
B.II
C.III
D.all three options
Answer: D.all three options
Explanation: We know that we have 10 numbers (and they could be ANY values - including negatives and non-integers) and we know that the average of those numbers is 10. This is meant to say that there are an INFINITE number of possible sets of 10 numbers that fit this prompt.
IF all ten numbers were the same (meaning that we had ten 10s), then the SD would be 0. The more 'spread out' those ten numbers get, the higher the SD becomes. Since there's no limit to the 'spread', then there's no limit to what the SD could be either. Thus, it could be 10 or 20 or any other number.
D
Question: The ratio of two numbers is 2:3 and the sum of their cubes is 945. The difference of number is?
A.3
B.4
C.6
D.7
Answer: A.3
Explanation: 2x 3x
8x cube + 27x cube = 945
35x cube = 945
x cube = 27 => x = 3
Answer:A