RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: 7% of the total quantity of rice is lost in grinding when a country has to import 6 million tonnes, but when only 7 3/4% is lost, it can import 3 million tonnes. Find the quantity of rice grown in the country.
A.200
B.300
C.400
D.500
Answer: C.400
Explanation: Let x be the total grown quantity of wheat. According to the question
(7%of x)+ 64 31 %of x)+3 7x 31x => 100+ 6 = 400 + 3 1200 x = — 400 million tonnes rice grown
C
Question: In a sequence, each term is obtained by adding 2 to the preceding one. If the sum of the first 20 terms is equal to 140, what is the result of the addition of the first 40 terms?
A.1020
B.1080
C.1160
D.1240
Answer: B.1080
Explanation: a is first term and d = 2 since the preceding number is always greater than the previous one..
Now 20th term is a+19(2).
Sum of n terms is n/2(first term + last term)and here we have to get sum of 20 terms , we get 20/2 ( a + a+38) = 140 ( given sum of 20 terms is 140)
=> 10(2a+38) = 140
=> 2a+38 = 14
=> a = -12
Now to get sum of first 40 terms , we need to get 40th term value i.e. -12+39(2) = 66.
Sum of first 40 terms = 40/2( -12 + 66) = 1080.
Hence option B is correct answer..
Question: One-third of Rahul's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,75,000 as total savings, how much has he saved in Public Provident Fund ?
A.80000
B.60000
C.50000
D.70000
Answer: D.70000
Explanation: Let savings in N.S.C and P.P.F. be Rs. x and Rs. (175000 - x) respectively. Then,
=1/3 x = 1/2 (175000 - x)
=x/3 + x/2 = 87500
=5x/6 = 87500
=x = 87500 x 6 /5	= 105000
Savings in Public Provident Fund = Rs. (175000 - 105000) = Rs. 70000
Answer is D.
Question: Crazy Eddie has a key chain factory. Eddie managed to decrease the cost of manufacturing his key chains while keeping the same selling price, and thus increased the profit from the sale of each key chain from 30% of the selling price to 50% of the selling price. If the manufacturing cost is now $50, what was it before the decrease?
A.$20
B.$40
C.$50
D.$70
Answer: D.$70
Explanation: Deargoodyear2013,
I'm happy to help.This is a relatively straightforward problem, not very challenging. BTW,Crazy Eddiewas the actually name of an electronics chain on the East Coast of the USA back in the 1970s.
Manufacturing now is $50. They now are making a 50% profit, so the selling price must be $100.
They had this same selling price, $100, before they made the change, and had a profit of 30%, so the manufacturing must have been $70. Answer = (D).
Question: A class has 6 boys and x girls. Average score of boys and girls is 50 and 60 respectively. the average of the whole class is 55, what is the value of x?
A.5
B.6
C.10
D.12
Answer: B.6
Explanation: After you have got : 6(50)+60x/6+x=55
6*50 + 60x = 6*55 + 55x
x=6
Answer is B
Question: If 2x^2 + y^2 = 2xy, then (x - y)^2 =
A.-x^2
B.3x^2
C.4xy
D.2y^2
Answer: A.-x^2
Explanation: (x-y)^2 = x^2 + y^2 - 2xy = x^2 + y^2-2x^2-y^2 = -x^2
Correct option : A
Question: Find the least square number which is exactly divisible by 10,12,15 and 18.
A.900
B.120
C.103
D.104
Answer: A.900
Explanation: L.C.M. of 10, 12, 15, 18 = 180. Now, 180 = 2 * 2 * 3 * 3 *5 = 22 * 32 * 5.
To make it a perfect square, it must be multiplied by 5.
Required number = (22 * 32 * 52) = 900.
ANSWER A 900
Question: George went to a fruit market with certain amount of money. With this money he can buy either 50 oranges or 40 mangoes. He retains 15% of the money for taxi fare and buys 15 mangoes. How many oranges can he buy?
A.25
B.17.5
C.20
D.16
Answer: B.17.5
Explanation: Let the amount of money be 200
Let cost of 1 Orange be 4
Let cost of 1 mango be 5
He decides to retain 15% of 200 = 30 for taxi fare, so he is left with 170
He buys 20 mangoes ( @ 5) so he spends 100
Money left is 70 (170 - 100)
No of oranges he can buy = 70/4 =>17,5
So, George can buy 15 Oranges.
B
Question: In the interior of a forest, a certain number of apes equal to the square of one-fourth of the total number are playing and having great fun. The remaining four apes are on a hill and the echo of their shrieks by the adjoining hills frightens them. They came and join the apes in the forest and play with enthusiasm. What is the total number of apes?
A.48
B.8
C.64
D.80
Answer: B.8
Explanation: Let total number be x
No in the interior = (x/4)^2
No outside = 4
So : x - (x/4)^2=4
x^2-16x+64=0
(x-8)^2=0
So x=8
B
Question: Area of a square is 1/2 hectare. The diagonal of the square is?
A.250 meter
B.100 meter
C.50√ 2 meter
D.50 meter
Answer: B.100 meter
Explanation: Area = 1/2 hectare = 10000 / 2 m2
= 5000 m2
Again Area = 1/2 x (Diagonal)2
So 1/2 x (Diagonal)2 = 5000m2
Diagonal2= 10000
Diagonal = 100
Answer : B
Question: A box contains 9 apples, 8 of which are red. An apple is drawn from the box and its color is noted before it is eaten. This is done a total of n times, and the probability that a red apple is drawn each time is less than 0.5. What is the smallest possible value of n?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: P(choosing a red apple 5 times in a row) = 8/9*7/8*6/7*5/6*4/5 = 4/9 < 0.5
The answer is C.
Question: How much time will a train of length 400 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction?
A.40 sec
B.50 sec
C.60 sec
D.70 sec
Answer: D.70 sec
Explanation: The distance to be covered = Sum of their lengths = 400 + 300 = 700 m.
Relative speed = 72 -36 = 36 kmph = 36 * 5/18 = 10 mps.
Time required = d/s = 700/10 = 70 sec.
ANSWER:D
Question: If k is a non-negative integer and 21^k is a divisor of 435,961 then 7^k - k^7 =
A.0
B.1
C.42
D.118
Answer: B.1
Explanation: 4+3+5+9+6+1 = 28, so this number is not divisible by 3 and thus not divisible by 21.
Therefore, k=0
7^k - k^7 =1-0=1
The answer is B.
Question: What distance will be covered by a city bus moving at 72 kmph in 30 seconds?
A.200 m
B.300 m
C.600 m
D.500 m
Answer: C.600 m
Explanation: 72 kmph = 72 * 5/18 = 20 mps
Dist = Speed * time = 20 * 30 = 600 m.
ANSWER C
Question: In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 25 p coins are there?
A.155
B.100
C.125
D.150
Answer: D.150
Explanation: Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values = (25 x/100) + (20 x/100) + (15 x/100)
= 60 x /100
30 = 60 x / 100
x = 50 = 25 p coin
Hence, the number of 5 p coins = (3 * 50) = 150.
Ans - D
Question: What is the square root of 3,969?
A.A)18
B.B)9
C.C)45
D.D)63
Answer: D.D)63
Explanation: A square root of a number is a number times itself equals the original number.
Ex) The square root of 81 is 9 because 9 times itself(9) equals the original number(81).
63*63=3,969
3969 divided by x = 63
x=63
(D)63
Question: Which No. Replace in Question mark?
4,02,42,82,23,63,?
A.04
B.05
C.06
D.07
Answer: A.04
Explanation: 4*(4+0)=4
4*(4+1)=20 i.e 02
4*(4+2)=24 i.e 42
4*(4+3)=28 i.e 82
4*(4+4)=32 i.e 23
4*(4+5)=36 i.e 63
hence
4*(4+6)=40... i.e.ans:04
ANSWER:A
Question: What number has a 5:1 ratio to the number 11?
A.22
B.50
C.55
D.52
Answer: C.55
Explanation: 5:1 = x: 10
x = 55
Answer: C
Question: In how many ways can we put 4 different balls in 3 different boxes when any box can contain any number of balls?
A.80
B.81
C.64
D.63
Answer: B.81
Explanation: Stage 1: Select a box for the 1st ball to go into.
There are 3 available boxes, so we can complete stage 1 in 3 ways
Stage 2: Select a box for the 2nd ball to go into.
There are 3 available boxes, so we can complete stage 2 in 3 ways
Stage 3: Select a box for the 3rd ball to go into.
There are 3 available boxes, so we can complete stage 3 in 3 ways
Stage 4: Select a box for the 4th ball to go into.
There are 3 available boxes, so we can complete stage 4 in 3 ways
By the Fundamental Counting Principle (FCP), we can complete all 4 stages (and thus distribute all 4 balls) in (3)(3)(3)(3)(4) ways (= 81 ways)
Answer:B
Question: If m > 0 and y is m percent of x, then, in terms of m, x is what percent of y?
A.a) 100m
B.b) 1/100m
C.c) 10,000/m
D.d) 10/m
Answer: C.c) 10,000/m
Explanation: y= m/100 * x
So x= 100/m * y
So x= (10000/m)/100 *y
C
Question: What is the HCF of 2/3, 4/9 and 6/18
A.7/45
B.2/45
C.1/9
D.8/45
Answer: C.1/9
Explanation: Explanation:
HCF of Fractions = HCF of Numerators/LCM of Denominators
= (HCF of 2, 4, 6)/(LCM of 3, 9, 18) = 2/18 = 1/9
Answer: Option C
Question: A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
A.300
B.350
C.450
D.470
Answer: C.450
Explanation: Explanation:
10 * 150 = 1500
3 * 100 + 5 * 150 = 1050
1500 – 1050 = 450
C
Question: If x and y are odd integers, which of the following must always be a non-integer
A.-x^2y
B.y/x
C.xy/4
D.x/y
Answer: C.xy/4
Explanation: as X and Y are odd, multiplication of x and y would result in odd integer
(Odd Integer)/4 will always be non integer.
C
Question: David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross ?
A.19
B.28
C.30
D.37
Answer: C.30
Explanation: EXPLANATION
Suppose their paths cross after x minutes.
Then, 11 + 57x = 51 – 63x <=> 120x = 40
x= 1/3
Number of floors covered by david in (1/3) min = (1/3 x 57) = 19
So, their paths cross at (11 +19) i.e., 30th floor.
Answer C
Question: From below option 48 is divisible by which one?
A.A)3
B.B)5
C.C)9
D.D)7
Answer: A.A)3
Explanation: 48/3 = 16
A
Question: If (5^5)(9^3)=3(15^x), what is the value of x?
A. 5
B. 9
C. 11
D. 13
Answer: A. 5
Explanation: (5^5)(9^3)=3(15^x)
=> 5^5 * 3^6 = 3 * 3^x * 5^x
=> 5^5 * 3^6 = 3^(x+1) * 5^x
Value of x = 5
Answer A
Question: Find the odd man out. 12, 24, 34, 48, 64, 84
A.48
B.34
C.24
D.12
Answer: B.34
Explanation: Explanation :
All numbers except 34 are multiples of 4. Answer : Option B
Question: The ratio of the two natural numbers is 5 : 6. If a certain number is added to both the numbers, the ratio becomes 7 : 8. If the larger number exceeds the smaller number by 10, find the number added?
A.17
B.14
C.10
D.16
Answer: C.10
Explanation: Let the two numbers be 5x and 6x.
Let the numbers added to both so that their ratio becomes 7 : 8 be k.
(5x + k) / (6x + k) = 7/8
=> 40x + 8k = 42x + 7k => k = 2x.
6x - 5x = 10 => x = 10
k = 2x = 20.
Answer:C
Question: If N = 1/5 + 1/5^2 +1/5^3 , then N is multiplied by 100 , will the product be greater than 100?
A.Less than 100
B.Greater than 100
C.Indeterminate
D.Equal to 100
Answer: A.Less than 100
Explanation: We need to check if (1/5 + 1/5^2 +1/5^3) > 1
If it is greater than 1 then the product 100 * N will be greater than 1 else not
N = 1/5 + 1/5^2 +1/5^3
5^3 * N = 5^3 * 1/5 + 5^3 * 1/5^2 + 5^3 * 1/5 ^3
125 * N = 25 + 5 + 1
125 * N = 31
N = 31/125
N is less than 1 since numerator is less than denominator .
Therefore 100 N would be less than 100
Ans: A
Question: If x/4 + 24/x = 5, what are the values of 4x - 7?
A.8 and 9
B.8 and 24
C.25 and 41
D.12 and 29
Answer: C.25 and 41
Explanation: I got the same thing C is the answer 25 or 41
Question: A thief goes away with a SANTRO car at a speed of 22 kmph. The theft has been discovered after half an hour and the owner sets off in a bike at 72 kmph when will the owner over take the thief from the start?
A.5/3 hours
B.11/25 hours
C.2/3 hours
D.1/3 hours
Answer: B.11/25 hours
Explanation: -----------22--------------------|
72 22
D = 22
RS = 72 â€“ 22 = 50
T = 22/50 = 11/25 hours
ANSWER:B
Question: A tour group of 25 people paid a total of $1050 for entrance to a museum. If this price included a 5% sales tax, and all the tickets cost the same amount, what was the face value of each ticket price without the sales tax?
Choices
A.$22
B.$23.94
C.$40
D.$25.20
Answer: C.$40
Explanation: Soln:-
1050/25=x+0.05x
1050/25=1.05x
x=40
ANSWER:C
Question: John borrowed 3 soccer boots from Jake, and forgot them on the field, if peter came across a total of 15 boots on the field Jake's boots inclusive, and he took 4 boots at random, what is the probability that Jake's boots were not amongst the 4 taken?.
A.12/91
B.3/15
C.12/15
D.33/91
Answer: D.33/91
Explanation: Since Jake owns 3 of the boots, the subset from which the 4 boots should be chosen are the 12 boots not owned by Jake from the universe of 15.
The first boot can be one of the 12 from the 15 with probability 12/15.
The second boot can be one of the 11 from the 14 remaining with probability 11/14.
The third boot can be one of the 10 from the 13 remaining with probability 10/13.
The fourth boot can be one of the 9 from the 12 remaining with probability 9/12.
The total probability will be 12/15 × 11/14 × 10/13 × 9/12 . On cancellation, this comes to 33/91.
Thus, the answer is D - 33/91
Question: What will be the difference between simple and compound interest at 16% per annum on a sum of Rs. 1000 after 4 years?
A.164.19
B.164.12
C.170.6
D.167.1
Answer: C.170.6
Explanation: S.I. = (1000 * 16 * 4)/100 = Rs. 640
C.I. = [1000 * (1 + 16/100)4 - 1000] = Rs. 810.6 Difference = (810.6-640) = Rs. 170.6
Answer: C
Question: If paint costs $3.20 per quart, and a quart covers 1200 square feet, how much will it cost to paint the outside of a cube 10 feet on each edge?
A.$ 1.60
B.$ 16.00
C.$ 96.00
D.$108.00
Answer: A.$ 1.60
Explanation: total surface area = 6a^2 = 6*10*10 = 600
each quart covers 20 sqr ft
thus total number of quarts = 600/1200 = 0.5
cost will be 0.5*3.2 = $1.6
Ans: A
Question: A man started driving at a constant speed, from the site of a blast, the moment he heard the blast. He heard a second blast after a time of 30 mins and 20 seconds. If the second blast occurred exactly 30 mins after the first, how many meters was he from the site when he heard the second blast? ( speed of sound = 330 m/s)
A.4200
B.5400
C.6600
D.7800
Answer: C.6600
Explanation: The distance the sound traveled to the man is 20*330 = 6600 meters
The answer is C.
Question: a school has 6 maths 5 physics and 5 chemistry teachers each teacher can teach 4 subjects max what is he minimum number of teachers required
A.2
B.4
C.5
D.6
Answer: B.4
Explanation: Total subjects = 6+5+5=16
Max subjects by 1 teacher = 4
So, min of teachers required = 16/4 = 4
ANSWER:B
Question: A person, who decided to go to weakened trip should not exceed 8 hours driving in a day. Average speed of forward journey is 40 m/h. Due to traffic in Sundays, the return journey average speed is 30 m/h. How far he can select a picnic spot?
A.120 miles
B.between 120 and 140 miles
C.160 miles
D.180 miles
Answer: B.between 120 and 140 miles
Explanation: let dist travelled be 2x. hence destination is at dist x
x/40+x/30=8
x=137.14
ANSWER:B
Question: A thief is spotted by a policeman from a distance of 100 metres. When the policeman starts the chase, the thief also starts running. If the speed of the thief be 8km/hr and that of the policeman 10 km/hr, how far the thief will have run before he is overtaken?
A.100 m
B.200 m
C.400 m
D.500 m
Answer: C.400 m
Explanation: Relative speed of the policeman = (10-8) km/hr =2 km/hr.
Time taken by police man to cover 100m
100/1000 x 1/2 hr = 1/20 hr.
In 1/20 hrs, the thief covers a distance of 8x 1/20km =2/5km = 400 m
ANSWER C
Question: Mangala completes a piece of work in 18 days, Raju completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is
A.6 days
B.7 days
C.15 days
D.9 days
Answer: C.15 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 18 Ã— 40/48 = 15 days.
C
Question: The average weight of 8 person's increases by 5 kg when a new person comes in place of one of them weighing 35 kg. What might be the weight of the new person?
A.80 kg
B.85 kg
C.75 kg
D.100 kg
Answer: C.75 kg
Explanation: Total weight increased = (8 x 5) kg = 40 kg.
Weight of new person = (35 + 40) kg = 75 kg.
Answer : C
Question: What numbers should go on the bottom line?
3 6 9 15
8 2 10 12
11 8 19 27
19 10 29 39
? ? ? ?
A.20 18 48 61
B.50 18 48 62
C.10 18 48 68
D.30 18 48 66
Answer: D.30 18 48 66
Explanation: D
30 18 48 66.
Starting at the top, add pairs of numbers in each column to arrive at the next number.
Question: A tradesman sold an article at a loss of 20%. If the selling price had been increased by $100, there would have been a gain of 5%. What was the cost price of the article ?
A.$400
B.$150
C.$300
D.$550
Answer: A.$400
Explanation: Let C.P. be $x
Then 105% of x - 80% of x = 100
25% of x = 100
x/4 = 100
x = 400
Answer is A
Question: On January 1, 2011, James invests 80% of his retirement savings in Antarctic largecap stocks, 10% in Antarctic midcaps, and 10% in Antarctic smallcaps. In 2011, largecaps rise 10%, midcaps rise 10%, and smallcaps rise 20% in the Antarctic stock market; however, in 2012, largecaps fall 5% and midcaps fall 10%, while smallcaps rise x% in Antarctica. If, on January 1, 2013,James has the same total amount of retirement savings as he did two years before, then x is between
A.10 and 20
B.20 and 30
C.30 and 40
D.40 and 50
Answer: D.40 and 50
Explanation: Pick a smart number for the total retirement savings James starts with—say, $1,000. (If you pick $100, you’ll wind up needing to track decimals, so give yourself more zeros to start with.)
Here are the starting values:
L = $800
M = $100
S = $100
Apply the first year’s changes, so that you have these numbers on 1/1/2012:
Newer L = $800 + 10% = $880
Newer M = $100 + 10% = $110
Newer S = $100 + 20% = $120
Now apply the second year’s changes to L and M:
Newest L = $880 – 5% = $880 – $44 = $836
Newest M = $110 – 10% = $110 – $11 = $99
Add these to get $935. So the newest S must be $1,000 (the target final total of James’s retirement savings) minus $935, $65
The dollar change in S from 1/1/12 to 1/1/13 is $120 – $55 = $65. So the question is this: what percent change does $65 represent, from a starting point of $120? Since $120 is a nasty divisor, switch to benchmarks:
20% of $120 = $24.
So 40% is just double that, or $48.
And 50% is equal to or $60.
From this $55 lies between $48 and $60
The correct answer is D.
Question: √{(3.5)(10^9)} is closest to which of the following?
A.60,000
B.75,000
C.140,000
D.220,000
Answer: A.60,000
Explanation: √{(3.5)(10^9)} = √{(35)(10^8)} = √(35)√(10^8) = (√35) * 10,000 which is almost 60,000.
The answer is A.
Question: The volumes of two cones are in the ratio 1 : 10 and the radii of the cones are in the ratio of 1 : 2. What is the length of the wire?
A.2:5
B.2:7
C.4:3
D.2:4
Answer: A.2:5
Explanation: The volume of the cone = (1/3)πr2h
Only radius (r) and height (h) are varying.
Hence, (1/3)π may be ignored.
V1/V2 = r12h1/r22h2 => 1/10 = (1)2h1/(2)2h2
=> h1/h2 = 2/5
i.e. h1 : h2 = 2 : 5
Answer:A
Question: A tank is filled by 3 pipes A,B,C in 5 hours. Pipe C is twice as fast as B and B is twice as fast as A. How much will pipe A alone take to fill the tank ?
A.25hr
B.35hr
C.40hr
D.20hr
Answer: B.35hr
Explanation: Suppose pipe A alone take x hours to fill the tank
Then pipe B and C will take x/2 and x/4 hours respectively to fill the tank.
1/x + 2/x + 4/x = 1/5
7/x = 1/5
x = 35 hours
Answer is B
Question: A can run a kilometer race in 4 1/2 min while B can run same race in 5 min. How many meters start can A give B in a kilometer race, so that the race mat end in a dead heat?
A.200 m
B.700 m
C.800 m
D.100 metre
Answer: D.100 metre
Explanation: Explanation:
A can give B (5 min - 4 1/2 min) = 30 sec start.
The distance covered by B in 5 min = 1000 m.
Distance covered in 30 sec = (1000 * 30)/300 = 100 m.
A can give B 100m start.
Answer:D
Question: In a certain province in Russia there are 15 cities. If a single road segment connects only two cities, how many road segments are required in order to connect the cities so that each city is connected to all other cities with a single road segment?
A.30
B.105
C.330
D.14!
Answer: B.105
Explanation: Method-1:
Russia has Total Cities = 15 and each city should be connected with every other city
So Total Roads required to connect 1st City with other 14 cities = 14
Now 1st City is connected with all other cities so,
So Total Roads required to connect 2nd City with 13 cities (Other than 1st) = 13
Now 1st and 2nd Cities are connected with all other cities so,
So Total Roads required to connect 3rd City with 12 cities (Other than 1st, and 2nd) = 12
......and so on...
Total Roads required = 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 105=B
Question: In an apartment building that has 441 units, 4 out of every 7 units are currently rented, including 1/5 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented?
A.45
B.70
C.100
D.105
Answer: A.45
Explanation: rented = 4/7*441 = 252.
Rented two-bedroom = 6/7*252 = 216;
Rented one-bedroom = 1/7*252 = 36or 252-216=36).
Rented one-bedroom units are 1/5 of all one-bedroom: 1/5*{All one bedroom} = 36 --> {All one-bedroom} = 180.
{All two-bedroom} = 441 - 180 = 261.
Two-bedroom not rented = 261 - 216 = 45.
Answer: A.
Question: How many minutes does it take Dhoni to type 64 words if he types at the rate of 16 words per minute?
A.10
B.15
C.12
D.16
Answer: D.16
Explanation: time*rate=job --> time*16=64 --> time=64/4=16.
Answer: D.
Question: A and B start walking towards each other at 6pm at speed of 6kmph and 4kmph. They were initially 50km apart. At what time do they meet?
A.8pm
B.6pm
C.11pm
D.10pm
Answer: C.11pm
Explanation: Time of meeting = distance / relative speed = 50/4+6 = 50/10 = 5 hrs after 6pm = 11pm
Answer is C
Question: Manoj borrowed Rs.4200 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
A.22877
B.5855
C.2778
D.6787
Answer: B.5855
Explanation: Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 4200.3.6/100 = Rs.824.85
27P = 75600 = 82485
P = (82485 + 75600)/27 = 3055 + 2800 = Rs.5855
Answer: B
Question: Find the remainder of the division (3^50)/7.
A.5
B.3
C.2
D.1
Answer: C.2
Explanation: Find the pattern of the remainders after each power:
(3^1)/7 remainder 3
(3^2)/7 remainder 2
(3^3)/7 remainder 6
(3^4)/7 remainder 4
(3^5)/7 remainder 5
(3^6)/7 remainder 1 -->this is where the cycle ends
(3^7)/7 remainder 3 -->this is where the cycle begins again
(3^8)/7 remainder 2
Continuing the pattern to (3^50)/7 gives us a remainder of 2
Final Answer:
C) 2
Question: If the average (arithmetic mean) of 5 positive temperatures is x degrees Fahrenheit, then the sum Z of the 3 greatest of these temperatures, in degrees Fahrenheit, could be
A.6x
B.Z=4x
C.5x/3
D.3x/2
Answer: B.Z=4x
Explanation: OA please. Yeah so 5x is the sum of the 5, then I guess 4x could be the answer (B)
But what about C,D,E? Any ideas why these could be wrong?
Note that we have 5positivetemperatures.
Next, as the average is x then the sum of the temperatures is 5x and as all the temperatures are positive then the sum of the 3 greatest must be more than (or equal to) 3x (as the average of the 3 greatest must be at least x) and less than 5x: 3x<SUM<5x --> only option B fits.
Answer: B.
Question: The present population of a town is 1000. Population increase rate is 25% p.a. Find the population of town before 1 years?
A.800
B.1500
C.1000
D.750
Answer: A.800
Explanation: P = 1000
R = 25%
Required population of town = P/(1 + R/100)^T
= 1000/(1 + 25/100)
= 1000/(5/4)
= 800
Answer is A