RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 55 kg. What might be the weight of the new person?
A.56 kg
B.90 kg
C.75 kg
D.Data inadequate
Answer: C.75 kg
Explanation: C
75 kg
Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (55 + 20) kg = 75 kg.
Question: If x is divisible by 5, 20, and 125, which of the following must be the least multiple of x?
A.12500
B.1250
C.500
D.100
Answer: C.500
Explanation: If x is divisible by 5, 20, and 125, then x must be a multiple of 5,4and 25.
Hence,the least multiple of x will be 5*4*25=500.
ANSWER:C
Question: Which of the following has 21^20 as a factor?
A.15^60
B.30^20
C.40^80
D.42^20
Answer: D.42^20
Explanation: Here 21^20 = 3^20 * 7^20 Only Option D has both .
Smash D
Question: Mary and Mike enter into a partnership by investing $650 and $350 respectively. At the end of one year, they divided their profits such that a third of the profit is divided equally for the efforts they have put into the business and the remaining amount of profit is divided in the ratio of the investments they made in the business. If Mary received $600 more than Mike did, what was the profit made by their business in that year?
A.$3000
B.$3200
C.$3300
D.$3400
Answer: A.$3000
Explanation: Explanatory Answer
Let the profit made during the year be $3x
Therefore, $x would have been shared equally and the remaining $2x would have been shared in the ratio 6.5 : 3.5
i.e., 65% of 2x would go to Mary and 35% of 2x would go to Mike.
Hence, Mary would get (65 - 35)% of 2x more than Mike
Or30% of 2x = $600
i.e.,(30/100)*2x = 600
or 2x = 2000.
Hence, the profit made by the company during the year $3x = $3000.
Answer : A
Question: A can knit a pair of socks in 3 days. B can knit the same thing in 6 days. If they are knitting together, in how many days will they knit two pairs of socks?
A.4 days
B.2 days
C.4 1⁄2 days
D.3 days
Answer: A.4 days
Explanation: ExplanationA’s one day’s work = 1⁄3 rd work.
B’s one day’s work = 1⁄6 rd work.
(A + B)’s one day’s work = 1⁄3 + 1⁄6 = 1⁄2 nd work.
∴ A and B together can complete the work (knit a pair of socks) in 2 days.
∴ They together knit two pair of socks in 4 days.
Answer A
Question: If 12 : 8 :: x : 16, then find the value of x
A.18
B.24
C.28
D.16
Answer: B.24
Explanation: Explanation:Treat 12:8 as 12/8 and x:16 as x/16, treat :: as = So we get 12/8 = x/16=> 8x = 192=> x = 24 Option B
Question: Reema can complete a piece of work in 12 days while Seema can the same work in 18 days. If they both work together, then how many days will be required to finish the work?
A.6 days
B.7.2 days
C.9.5 days
D.12 days
Answer: B.7.2 days
Explanation: EXPLANATION:
Hint:
A's one day work =	1/12
B's one day work =	1/18
(A + B)'s one day work =	1/12	+	1/18	=	(18 + 12)/(12 x 18)=	30/216=	1/7.2
Together, A & B will finish the work in 7.2 days.
ANSWER IS B
Question: Calculate the sum of first 39 natural numbers.
A.780
B.891
C.812
D.847
Answer: A.780
Explanation: Solution
We know that(1+2+3+.....+39)	= n(n+1)/2
Therefore (1+2+3+....+39)	=(39×40 / 2)
= 780.
Answer A
Question: Which is largest prime number?
A.653
B.857
C.859
D.523
Answer: C.859
Explanation: Answer:C
Question: Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 42 kmph. Of how many minutes does the train stop per hour?
A.16
B.4
C.15
D.18
Answer: B.4
Explanation: T = 3/45 * 60
= 4
Answer: B
Question: A sum of money is to be distributed among A, B, C, D in the proportion of 6 : 2 : 4 : 3. If C gets $500 more than D, what is D's share?
A.$2000
B.$2500
C.$3000
D.$3600
Answer: C.$3000
Explanation: Let the shares of A, B, C and D be 6x, 2x, 4x and 3x respectively.
Then, 4x - 3x = 500
x = $500
A's share = 6x = 6*$500 = $3000
The answer is C.
Question: If A lends Rs.2000 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?
A.90
B.122.5
C.132.5
D.114.5
Answer: A.90
Explanation: (2000*1.5*3)/100 => 90
ANSWER:A
Question: Kim purchased n items from a catalog for $8 each. Postage and handling charges consisted of $6 for the first item and $1 for each additional item. Which of the following gives the total dollar amount for Kim’s purchase, including postage and handling, in terms of n ?
A.8n + 2
B.8n + 4
C.9n + 2
D.9n + 5
Answer: D.9n + 5
Explanation: its C
n items for $8 each
total price $8n
postage and handling of $3 for 1st item and $1 for the rest
total postage and handling = $ [6+ (n-1)]
= $ n+5
total cost
8n+n+5 = 9n+5
D
Question: Claire has a total of 92 pets consisting of gerbils and hamsters only. One-quarter of the gerbils are male, and one-third of the hamsters are male. If there are 25 males altogether, how many gerbils does Claire have?
A.39
B.68
C.54
D.57
Answer: B.68
Explanation: G+H =92 ...1 ; G/4 +H/3 =25 ....2 OR 3G +4H =25*12 =300
G =92-H OR 3(92-H) +4H =300 H = 300-276 =24 THEN G= 92-24 = 68
B
Question: A car driver travels from the plains to the hill station, which are 200 km apart at an average speed of 50km/hr. in return trip, he covers the same distance at an average speed of 20km/hr. the average speed of the car over the entire distance of 400 km is
A.8.95km/hr
B.26.7km/hr
C.27.8km/hr
D.28.5km/hr
Answer: D.28.5km/hr
Explanation: average speed = (2*50*20)/50+20 km/hr
=28.5 km/hr
Answer (D)
Question: The mass of 1 cubic meter of a substance is 400 kg under certain conditions. What is the volume in cubic centimeters of 1 gram of this substance under these conditions? (1 kg =1,000 grams and 1 cubic meter = 1,000,000 cubic centimeters)
A.1.5
B.2.5
C.3.5
D.4.5
Answer: B.2.5
Explanation: 400 kg - 1 cubic meter;
400,000 g - 1 cubic meter;
400,000 g - 1,000,000 cubic centimeters;
1 g - 1,000,000/400,000 = 10/4 = 2.5 cubic centimeters.
Answer: B.
Question: Manoj received Rs. 6000 as his share out of the total profit of Rs. 9000 which he and Ramesh earned at the end of one year. If Manoj invested Rs.120000 for 6 months, whereas Ramesh invested his amount for the whole year, what was the amount invested by Ramesh
A.Rs. 2000
B.Rs. 3000
C.Rs. 4000
D.Rs. 5000
Answer: D.Rs. 5000
Explanation: Explanation:
Suppose Ramesh invested Rs. x. Then,
Manoj : Ramesh = 20000 * 6 : x * 12.
120000/12x : 6000/3000
=> x = 120000/24 = 5000
Option D
Question: A cistern is normally filled in 8 hours but takes two hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in?
A.87
B.09
C.40
D.42
Answer: C.40
Explanation: 1/8 - 1/x
= 1/10
x = 40
Answer:C
Question: Two trains 500 m and 750 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
A.10.6
B.45
C.10.4
D.10.8
Answer: B.45
Explanation: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 500 + 750 = 1250 m.
Required time = 1250 * 9/250 = 45 sec.
Answer: B
Question: Machine M, N, O working simultaneously Machine M can produce x units in 3/4 of the time it takes machine N to produce the same amount of units. Machine N can produce x units in 2/5 the time it takes machine O to produce that amount of units. If all three machines are working simultaneously, what fraction of the total output is produced by machine N?
A.1/2
B.5/11
C.4/13
D.8/29
Answer: B.5/11
Explanation: Now ultimately the speed of every machine is given with respect to Mach O.
So lets assume the speed of O, say 12 hrs to make x units (assuming 6 because we can see we will need to divide by 3 and 4
Mach O makes x units in 12 hrs
So, Mach N = 2/5 of O = 2/5*12 = 4.8 hrs to make x units
and Mach M = 3/4 of N = 3/4*4.8 = 6 hrs to make x units
No they are running simultaneously. Lets see how much each mach makes in 1 hr
Mach O = x/12 units
Mach N = 5x/24 units
Mach M = x/6 units
In 1 hr, together they make - x/12+5x/24+x/6 = 11/24
So what ratio of this has Mach N made?
(5x/24) / (11/24) = 5/11
Ans:B=5/11
Question: How many words can be formed from the letters of the word ‘DIRECTOR’ So that the vowels are always together?
A.1524
B.7845
C.2160
D.2541
Answer: C.2160
Explanation: In the given word, we treat the vowels IEO as one letter.
Thus, we have DRCTR (IEO).
This group has 6 letters of which R occurs 2 times and others are different.
Number of ways of arranging these letters = 6!/2! = 360.
Now 3 vowels can be arranged among themselves in 3! = 6 ways.
Required number of ways = (360x6) = 2160.
Ans: C
Question: Ramu bought an old car for Rs. 42000. He spent Rs. 13000 on repairs and sold it for Rs. 60900. What is his profit percent?
A.10.7%
B.19%
C.18%
D.14%
Answer: A.10.7%
Explanation: Total CP = Rs. 42000 + Rs. 13000
= Rs. 55000 and SP
= Rs. 60900
Profit(%) = (60900 - 55000)/55000 * 100
= 10.7%
Answer: A
Question: The length of the bridge, which a train 110 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
A.255
B.265
C.245
D.277
Answer: B.265
Explanation: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (110 + x)/30 = 25/2 => 2(110 + x) = 750 => x = 265 m.
Answer:B
Question: A shopkeeper loses 15%,if an article is sold for Rs. 102. What should be the selling price of the article to gain 20%?
A.Rs.148
B.Rs.144
C.Rs.120
D.Rs.129
Answer: B.Rs.144
Explanation: Given that SP = Rs. 102 and loss = 15%
CP = [100(SP)]/(100 - l%) = (100 * 102)/85 = 20 * 6 = Rs. 120.
To get 20% profit, New SP = [(100 + p%)CP]/100 = (120 * 120)/100
= Rs.144
Answer:B
Question: 1907 x 1907 = ?
A.A)3623216
B.B)3624216
C.C)3624316
D.D)3636649
Answer: D.D)3636649
Explanation: 1907 x 1907 = (1907)2
= (1900 + 7)2
= (1900)2 + (7)2 + (2 x 1900 x 7)
= 3610000 + 49 + 26600.
= 3636649.
D)
Question: Given f(x) = 3x – 5, for what value of x does 2*[f(x)] – 19 = f(x – 4) ?
A.2
B.4
C.6
D.8
Answer: B.4
Explanation: 2(3x-5)-19 = 3(x-4) - 5
3x = 12
x = 4
The answer is B.
Question: 3 person can fill tank in 25 min, a can fill in 30 min , b can fill in 35 min and c can empty the 5 gallon per min then what is the capacity of tank?
A.208.26 gallons
B.218.26 gallons
C.228.26 gallons
D.238.26 gallons
Answer: C.228.26 gallons
Explanation: A can fill the tank in 30 minutes
B can fill the same tank in 35 minutes
A B C together fill the tank in 25 minutes
Equating we get,
1050/23*5 = 228.26 gallons
ANSWER:C
Question: The edge of three cubes of metal is 3 dm, 4 dm and 5 dm. They are melted and formed into a single cube. Find the edge of the new cube?
A.1
B.9
C.4
D.6
Answer: D.6
Explanation: 33 + 43 + 53 = a3 => a
= 6
Answer: D
Question: A man gains 30% by selling an article for a certain price. If he sells it at double the price, the percentage of profit will be.
A.130%
B.140%
C.150%
D.260%
Answer: D.260%
Explanation: Explanation:
Let the C.P. = x,
Then S.P. = (130/100)x = 13x/10
New S.P. = 2(13x/10) = 26x/10
Profit = 26x/10 - x = 26x/10
Profit% = (Profit/C.P.) * 100
=> (26x/10) * (1/x) * 100 = 260 %
Option D
Question: A doctor prescribed 20 cubic centimeters of a certain drug to a patient whose body weight was 120 pounds. If the typical dosage is 2 cubic centimeters per 15 pounds of the body weight, by what percent was the prescribed dosage greater than the typical dosage?
A.25%
B.9%
C.11%
D.12.5%
Answer: A.25%
Explanation: Typical dosage per 15 pound of the body weight = 2 c.c
Typical dosage per 120 pound of the body weight = 2 *(120/15)
= 2 * 8
= 16 c.c
Dosage prescribed by doctor for 120 pound patient = 20 c.c
% prescribed dosage greater than the typical dosage = (20-16/16) *100%
=(2/16) *100%
= 25%
Answer A
Question: The price of lunch for 15 people was $208.00, including a 15 percent gratuity for service. What was the average price per person, EXCLUDING the gratuity?
A. $11.73
B. $12.60
C. $13.80
D. $14.00
Answer: B. $12.60
Explanation: Take the initial price before the gratuity is 100
The gratuity is calculated on the final price, so as we assumed the final bill before adding gratuity is 100 so gratuity is 15% of 100 is 15 so the total price of meals is 115 so the given amount i.e 208 is for 115 then we have to calculate for 100
for 115 208
for 100 x
so by cross multiplication we get 115x=100*208 => x=100*208/110 by simplifying we get x as 189 which is the price of lunch before gratuity so the gratuity is 19 so
as the question ask the average price person excluding gratuity is 189/15=12.6 so our answer is B)
Question: An adventuring party consists of 4 white mages, 6 warriors, and 4 archers. In how many ways can 3 white mages, 2 warriors and 2 archers be selected from the given group?
A.987 ways
B.446 ways
C.360 ways
D.157 ways
Answer: C.360 ways
Explanation: The number of ways of selecting three white mages, two warriors and two archers is:
= ⁴C₃ * ⁶C₂ * ⁴C₂
= (4 * 3 * 2)/(3 * 2 * 1) * (6 * 5)/(2 * 1) * (4 * 3)/( 2 * 1)
= 4 * 15 * 6
= 360 ways.
Answer: C
Question: If x is equal to the sum of the integers from 60 to 80, inclusive, and y is the number of even integers from 60 to 80, inclusive, what is the value of x + y?
A.1361
B.1481
C.1601
D.1721
Answer: B.1481
Explanation: x = 60 + 61 +...+ 80 = 21(70) = 1470
y = 11
x+y = 1481
The answer is B.
Question: A and B rent a pasture for 10 months. A put in 80 cows for 7 months. How many can B put in for the remaining 3 months, if he pays half as much again as A?
A.299
B.277
C.281
D.280
Answer: D.280
Explanation: 80* 7: x* 3 = 1:1 1/2
560: 3x = 2: 3
x = 280
Answer: D
Question: A group of n students can be divided into equal groups of 4 with 2 student left over or equal groups of 5 with 2 students left over. What is the sum of the two smallest possible values of n?
A.33
B.46
C.49
D.64
Answer: D.64
Explanation: 4x+2 = 5y+2...........ie: 4x-5y = 0
x,y must be >1 and y is even ie ( 2,4,6,..etc)
if y = 2 thus x is fraction
if y = 4 thus x =5 n =22
if y = 6 thus x = not possible fraction
if y =8 thus x = 10 n =42
n= 22+42= 64
D
Question: What is the number which when multiplied by 13 is increased by 180?
A.13
B.15
C.23
D.35
Answer: B.15
Explanation: 13 × 15 = 195
Answer: B
Question: Over a three-week period, the price of an ounce of gold increased by 10% in the first week, decreased by 20% in the following week, and increased by 10% in the third week. If the price of gold was G dollars per ounce at the beginning of the three weeks, what was the price at the end of the three weeks?
A.0.968G
B.0.978G
C.0.988G
D.0.998G
Answer: A.0.968G
Explanation: After 3 weeks, the price was 1.1*0.8*1.1*G=0.968G
The answer is A.
Question: A man can do a piece of work in 5 days, but with the help of his son he can do it in 3 days. In what
time can the son do it alone ?
A.712days
B.612days
C.512days
D.412days
Answer: A.712days
Explanation: Explanation:
In this type of question, where we have one person work and together work done. Then we can easily
get the other person work just by subtracting them. As
Son's one day work =
(13−15)=(5−315)=215
So son will do whole work in 15/2 days
which is =
712days
Answer: A
Question: Solve the given two equations and find the inequality of X and Y. (a) 2x^2 + 11x + 14 = 0 and (b) 4y^2 + 12y +9 =0
A.If x>y
B.If x>=y
C.If x<y
D.If x<=y
Answer: C.If x<y
Explanation: Solution:-
X=-7/2 or -2
Y=-3/2
If x<y
C)
Question: Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Eight years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?
A.Can't be determined
B.40
C.27
D.64
Answer: D.64
Explanation: Explanation:
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then, (5x+8)/(4x+8)=11/9
⇒ 45x + 72 = 44x + 88⇒ 9(5x + 8) = 11(4x + 8)
⇒ 45x - 44x = 88 - 72
⇒ x = 16.
Anand's present age = 4x = 64 years.
Answer: D
Question: An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:
A.4.00%
B.4.14%
C.4.04%
D.4.26%
Answer: C.4.04%
Explanation: 100 cm is read as 102 cm.
A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.
(A2 - A1) = [(102)2 - (100)2]
= (102 + 100) x (102 - 100)
= 404 cm2.
Percentage error = 404	x 100	%	= 4.04%
100 x 100
C
Question: A man can row upstream at 25 kmph and downstream at 35 kmph, and then find the speed of the man in still water?
A.18 kmph
B.20 kmph
C.30 kmph
D.19 kmph
Answer: C.30 kmph
Explanation: US = 25
DS = 35
M = (35 + 25)/2 = 30
Answer:C
Question: The original price of a suit is $200. The price increased 30%, and after this increase, the store published a 30% off coupon for a one-day sale. Given that the consumers who used the coupon on sale day were getting 30% off the increased price, how much did these consumers pay for the suit?
A.$182
B.$191
C.$200
D.$209
Answer: A.$182
Explanation: Given the foregoing discussion, it may be obvious now the trap-mistake answer is (C). Even if you can’t remember the correct thing to do, at the very least, learn to spot the trap!
The multiplier for a 30% increases is 1 + 0.30 = 1.3, and the multiplier for a 30% decrease is 1 – 0.30 = 0.70, so the combined change is 1.3*0.7 = 0.91, 91% percent of the original, or a 9% decreases. Now, multiply $200*0.91 = $182. Answer = (A).
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 240 m and they cross each other in 12 sec, then the speed of each train is?
A.72
B.89
C.36
D.34
Answer: A.72
Explanation: Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (240 + 240)/12 => x = 20
Speed of each train = 20 m/sec.
= 20 * 18/5 =72 km/hr.
Answer: Option A
Question: What is the banker's discount if the true discount on a bill of Rs.540 is Rs.90 ?
A.108
B.120
C.102
D.106
Answer: A.108
Explanation: Explanation:
Present Worth, PW = F - TD = 540 - 90 = Rs. 450
Simple Interest on the Present Worth = True Discount
Hence Simple Interest on 450 = 90 ------(Equation 1)
Simple Interest on the face value = Bankers Discount
=> Simple Interest on 540 = Bankers Discount
From Equation 1, Simple Interest on 450 = 90
Hence, Simple Interest on 540 = 90/450×540=540 = Rs. 108
=> Bankers Discount = Rs. 108
Answer: Option A
Question: Each of the integers from 0 to 8, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 10?
A.8
B.9
C.7
D.6
Answer: C.7
Explanation: You should consider the worst case scenario: if you pick numbers 0, 1, 2, 3, 4 and 5 then no two numbers out of these 6 add up to 10.
Now, the next, 7th number whatever it'll be (6,7, or 8) will guarantee that two number WILL add up to 10. So, 7 slips must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 10
Answer: C
Question: The average weight of 10 men is increased by 1 ½ kg when one of the men who weighs 48 kg is replaced by a new man. What is the weight of the new man?
A. 80 kg
B. 63 kg
C. 70 kg
D. 75 kg
Answer: B. 63 kg
Explanation: Since the average has increased by 1.5 kg, the weight of the man who stepped in must be equal to 48+10x1.5
48+15=63 Kg
Ans: 'B'
Question: If an article is sold at 19% profit instead of 12% profit, then the profit would be Rs. 105 more. What is the cost price?
A.Rs. 1505
B.Rs. 1510
C.Rs. 1500
D.Rs. 1490
Answer: C.Rs. 1500
Explanation: Let the cost price of an article be Rs. x.
(19% of x) - (12% of x) = 105
19x/100 - 12x/100 = 105 => 7x = 105 * 100
=> x = 1500
Cost price = Rs. 1500
ANSWER:C
Question: .005/?= .01
A..5
B..05
C..005
D..0005
Answer: A..5
Explanation: Let .005/x = .01;
Then x = .005/.01
= .5/1
= .5
Answer is A
Question: The seats in an Engineering college for Computer science, electronics and civil are in the ratio of 5 : 7 :8. There is a proportion to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats ?
A.2 : 3 : 4
B.6 : 7 : 8
C.6 : 8 : 9
D.6 : 8 : 7
Answer: A.2 : 3 : 4
Explanation: Originally, let the number of seats for Computer science, electronics and civil are 5x : 7x : 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x)
7x : 21x/2 : 14x = 14x : 21x : 28x = 2 : 3 : 4.
ANSWER:A
Question: The average weight of 4 persons increases by 1.5 kg. If a person weighing 65 kg is replaced by a new person, what could be the weight of the new person?
A.71 kg
B.77 kg
C.76.5 kg
D.Data inadequate
Answer: A.71 kg
Explanation: total weight increases = 4 × 1.5 = 6 kg
so the weight of new person = 65 + 6 = 71 kg
Answer A
Question: The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction?
A.3/11
B.4/11
C.5/11
D.6/13
Answer: A.3/11
Explanation: Explanation:
The denominator be P, the numerator will be (P - 8).
The fraction will be (P - 8)/P.
Adding 3 to the numerator and subtracting 3 from the denominator, (P - 8 + 3)/(P - 3) = 3/4.
(P - 5)/(P - 3) = 3/4
P = 20 - 9 => P = 11.
The fraction is: 3/11.
A)
Question: Which of the following leads to the correct mathematical solution for the number of ways that the letters of the word RADAR could be arranged to create a five-letter code?
A.5!/(2! x 2!)
B.6! − (3! + 2!)
C.6! − (3! × 2!)
D.6!/(3! + 2!)
Answer: A.5!/(2! x 2!)
Explanation: Number of letters in word 'RADAR' = 5.
The letters 'A' and 'R' appear 2 times and 2 times respectively in the word 'RADAR'.
Therefore the mathematical solution for number of ways that the letters of the word RADAR can be arranged to create five-letter code
= 5!/(2!*2!)
Answer:A
Question: The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 2 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
A.23 years
B.22 years
C.25 years
D.26 years
Answer: B.22 years
Explanation: EXPLANATION
Let the average age of the whole team by x years.
11x â€“ (26 + 28) = 9(x -1)
11x â€“ 9x = 45
2x = 45
x = 22.
So, average age of the team is 22 years.
Answer B
Question: In covering a distance of 30 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:
A.5 km/hr.
B.3 km/hr.
C.1 km/hr.
D.7 km/hr.
Answer: A.5 km/hr.
Explanation: C
5 km/hr.
Let A's speed be X km/hr.
Then, 30/x - 30/2x = 3
6x = 30
x = 5 km/hr.
Question: One half of a two digit number exceeds its one third by 8. What is the sum of the digits of the number?
A.A)3
B.B)5
C.C)12
D.D)9
Answer: C.C)12
Explanation: x/2 – x/3 = 8 => x =48
4 + 8 = 12
ANSWER:C
Question: The ages of two persons differ by 16 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively
A.20,20
B.20,10
C.25,9
D.30,10
Answer: C.25,9
Explanation: Explanation:
Let their ages be x and (x + 16) years.
5 (x - 5) = (x + 16 - 5) or 4x = 36 or x = 9.
Their present ages are 25 years and 9 years
Option C
Question: Mandy drove from point A to point B at 60 Km/h. On her way back she drove at 80 Km/h and therefore her way back lasted one hour less. What is the distance (in Km) between A and B?
A.140.
B.200.
C.240.
D.300.
Answer: C.240.
Explanation: distance=speed*time
d1=s1t1
d2=s2t2
The distance from point A to point B is the same for each trip so,
d1=d2 and
t2=t1-1
thus,
s1t1=s2(t1-1)
60t1=80(t1-1)
t1=4
60*4= 240
Answer: C
Question: S is the infinite sequence S1 = 2, S2 = 22, S3 = 222,...Sk = Sk–1 + 2(10k–1). If p is the sum of the first 30 terms of S, what is the eighth digit of p, counting right to left from the units digit?
A.1
B.2
C.4
D.6
Answer: A.1
Explanation: C
Sum of unit digits of first 30 terms = 60
Sum of tens digits of first 30 terms = 58
Sum of thousands digits of first 30 terms = 56
and so on..
p1 = 0
p2 = (6+58) = 4
p3 = (6+56) = 2
p4 = (6+54) = 0
p5 = (6+52) = 8
p6 = (5+50) = 5
p7 = (5+48) = 3
p8 = (5+46) = 1
ANSWER : A
Question: Find the number of square tiles to cover the floor of a room measuring 10 m * 12 m leaving 0.25 m space around the room. A side of square tile is given to be 50 cms?
A.277
B.476
C.437
D.257
Answer: C.437
Explanation: 9 1/2 * 11 1/2 = 1/2 * 1/2 * x => x = 437
Answer:C