RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If the ratio of the areas of two squares is 225:256, then the ratio of their perimeters is :
A.15:12
B.15:14
C.15:16
D.15:22
Answer: C.15:16
Explanation: Explanation:
a2/b2=225/256=15/16
<=>4a/4b=4∗15/4∗16
=15/16=15:16
Option C
Question: In a apartment, 40% of the people speak English, 10% speak Hindi and 20% speak both. If a people is selected at random, what is the probability that he has speak English or Hindi?
A.1/3
B.2/3
C.3/5
D.2/7
Answer: C.3/5
Explanation: P (E) = 40 / 100 = 4 / 10 , P (H) = 10 / 100 = 1 / 10 and P (E âˆ© H) = 20 / 100 = 2 / 10
P (E or H) = P (E U H)
= P (E) + P (H) - P (E âˆ© H)
= (4 / 10) + (1 / 10) - (2 / 10) = 4 / 10 = 3/5
C
Question: Which is better investment, 12% stock at par with an income tax at the rate of 5paise per rupee or 14 2/7 % stock at 120 free from income tax
A.12%
B.142/7 %
C.Both are qually good
D.cannot compared
Answer: B.142/7 %
Explanation: Let the investment in each (100*120)
Income in first case = (12/100*100*120)=1440
Net income =(1440-5/100*1440)=1368
Income in second case=((100/2*20)*100*120)=1428.57
Clearly, 14 2/7 % stock at 120 is better
ANSWER B
Question: It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
A.Tuesday
B.Saturday
C.Monday
D.Friday
Answer: D.Friday
Explanation: On 31st December, 2005 it was Saturday.
Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday
Answer is D.
Question: The cost of one photocopy is $0.02. However, a 25% discount is offered on orders of more than 100 photocopies. If Arthur and David have to make 80 copies each, how much will each of them save if they submit a single order of 160 copies?
A.$0.32
B.$0.40
C.$0.45
D.$0.48
Answer: B.$0.40
Explanation: If Arthur and David submit separate orders, each would be smaller than 100 photocopies, so no discount. Each would pay (80)*($0.02) = $1.60, or together, a cost of $3.20 --- that's the combined no discount cost.
If they submit things together as one big order, they get a discount off of that $3.20 price ---- 25% or 1/4 of that is $0.80, the discount on the combined sale. They each effective save half that amount, or $0.40. Answer =(B).
Question: Five friends are planning to attend a concert. If another friend also goes with them, they will get a group discount on their tickets. If the new total price of the tickets with the group discount is the same as the original total price of the tickets without the group discount, how much is the discount?
A.14%
B.17%
C.20%
D.25%
Answer: B.17%
Explanation: Let x be the original price of one ticket.
The total original cost is 5x.
The new cost is 6y, where y is the discounted price of one ticket.
5x = 6y
y = 5x/6 which is about 0.83x which is a discount of about 17%.
The answer is B.
Question: 0.009/x=0.02. find the value of X
A.0.045
B.0.09
C.0.9
D.9
Answer: A.0.045
Explanation: x=0.009/0.045=0.9
ANSWER:A
Question: A courtyard is 25 meter long and 16 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is?
A.22877
B.27778
C.20000
D.27999
Answer: C.20000
Explanation: Number of bricks =Courtyard area/1 brick area
=(2500×1600/20×10)=20000
Answer: C
Question: If Tim had lunch at $50.50 and he gave 20% tip, how much did he spend?
A.$30.60
B.$60.60
C.$70.60
D.$40.60
Answer: B.$60.60
Explanation: The tip is 20% of what he paid for lunch. Hence
tip = 20% of 50.50 = (20/100)*50.50 = 101/100 = $10.10
Total spent
50.50 + 10.10 = $60.60
correct answer B
Question: The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 30 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam.
A.15
B.30
C.35
D.45
Answer: B.30
Explanation: Let the number of students who wrote the exam be x.
Total marks of students = 80 x.
Total marks of (x - 5) students = 90(x - 5)
80x - (5 * 30) = 90(x - 5)
300 = 10x => x = 30
ANSWER:B
Question: Eden drove an average speed of 15 miles per hour for the first 20 miles of a tripthen at a average speed of 30 miles/hr for the remaining 20 miles of the trip if she made no stops during the trip what was eden's avg speed in miles/hr for the entire trip
A.35
B.20
C.45
D.50
Answer: B.20
Explanation: Avg. speed = total distance / total time
Total distance = 40 miles
Total time = 20 / 15 + 15/30 = 2
Avg. speed = 20.
Answer - B
Question: If the probability that Brendon, Daniel and Kane score more than 700 on the GMAT is 0.4, 0.5 and 0.6 respectively, what is the probability that at least 2 of them score less than 700?
A.0.12
B.0.38
C.0.40
D.0.5
Answer: D.0.5
Explanation: The probability that Brendon, Daniel and Kane score less than or equal to 700 on the GMAT is 0.4, 0.5 and 0.6 respectively,
All three score less than 700 = 0.6*0.5*0.4 = 0.12;
Brendon and Daniel score less than or equal to 700, while Kane scores more than 700 = 0.6*0.5*0.6 = 0.18;
Brendon and Kane score less than or equal to 700, while Daniel scores more than 700 = 0.6*0.4*0.5 = 0.12;
Kane and Daniel score less than or equal to 700, while Brendon scores more than 700 = 0.5*0.4*0.4 = 0.08.
The sum of the above = 0.5.
Answer: D.
Question: A father is now three times as old as his son. Five years back, he was four times as old as his son. The age of the son (in years) is?
A.12
B.15
C.72
D.16
Answer: B.15
Explanation: Let son's age be x years. Then, father's age = (3x) years.
Five years ago, father's age = (3x - 5) years and son's age = (x - 5) years.
So, 3x - 5 = 4 (x - 5) 3x - 5 = 4x - 20 x = 15.
Answer: B
Question: Consider another example where a pack contains 4 blue, 2 red and 3 black pens. If a pen is drawn at random from the pack, replaced and the process repeated 2 more times, What is the probability of drawing 2 blue pens and 1 black pen?
A.8/81
B.9/81
C.7/81
D.6/81
Answer: A.8/81
Explanation: EXPLANATION:
Here, total number of pens = 9
Probability of drawing 1 blue pen = 4/9
Probability of drawing another blue pen = 4/9
Probability of drawing 1 black pen = 3/9
Probability of drawing 2 blue pens and 1 black pen = 4/9 * 4/9 * 3/9 = 8/81
ANSWER IS A
Question: Find the unit digit in the product(2467)^153*(341)^72
A.7
B.18
C.25
D.63
Answer: A.7
Explanation: Explanation:
Unit's digit in the given product=7^153*1^72
7^153 gives unit's digit =(1*7)=7
1^72 unit's digit=1
Unit digit's in the product=(7*1)=7
Answer A
Question: Walking 7/6 of his usual rate, a boy reaches his school 4 min early. Find his usual time to reach the school?
A.22
B.28
C.99
D.77
Answer: D.77
Explanation: Speed Ratio = 1:7/6 = 6:7
Time Ratio = 7:6
1 -------- 7
4 --------- ? è 28 m
Answer:D
Question: All the students of class are told to sit in circle shape. Here the boy at the 7 th position is exactly opposite to 27 th boy. Total number of boys in the class?
A.25
B.40
C.35
D.30
Answer: B.40
Explanation: As half the circle shape consist of 27-7=20 boys,
So total number of boys in full circle=2*20=40
ANSWER: B
Question: The sum of ages of 5 kids born at the intervals of 3 years each is 50 years. Find the age of the youngest kid?
A.4 years
B.5 years
C.3 years
D.6 yeasr
Answer: A.4 years
Explanation: consider x as age and
(x+3)(x+6)(x+9) and (x+12)
5x = 20
x= 4
ANSWER A
Question: A certain bus driver is paid a regular rate of $14 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $998 in total compensation, how many total hours did he work that week?
A.54
B.51
C.58
D.55
Answer: C.58
Explanation: For 40 hrs = 40*14=560
Excess = 998-560=438
For extra hours =.75(14)=10.5+14=24.5
Number of extra hrs =438/24.5=17.8=18 approx.
Total hrs =40+18=58
Answer C
Question: A can do a piece of work in 4 days. B can do it in 10 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?
A.22 days
B.20/3 days
C.67 days
D.17/6 days
Answer: B.20/3 days
Explanation: C = 1/2 - 1/4 - 1/10 = 3/20
=> 20/3 days
Answer:B
Question: Two dice are thrown together .What is the probability that the sum of the number on the two faces is divided by 4 or 6
A.5/7
B.7/18
C.3/4
D.8/9
Answer: B.7/18
Explanation: Clearly n(S)=6*6=36
Let E be the event that the sum of the numbers on the two faces is divided by 4 or 6.Then
E={(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(5,3),(6,2),
(6,6)}
n(E)=14.
Hence p(e)=n(e)/n(s)=14/36=7/18
Ans: B
Question: The sum of 2 consecutive numbers is definitely:
A.Positive.
B.Divisible by 2.
C.Divisible by 3.
D.Divisible by 4.
Answer: A.Positive.
Explanation: If 1st term is x:
x+(x+1)=2x+1--->Positive
If 2nd term is x:
(x-1)+x=2x-1 --->Positive
A
Question: Bruno and Sacha are running in the same direction around a stadium. Sacha runs at a constant speed of 8 meters per second, and Bruno runs at a constant speed of 5 meters per second. At a certain point Sacha overtakes Bruno. If one minute afterward, Sacha stops and waits for Bruno to reach him, then how many seconds does he have to wait?
A.12
B.24
C.36
D.60
Answer: C.36
Explanation: the difference of the speed is 3m per second so in one minute Sacha will be 180 m ahead of Bruno..
Bruno will cover this in 180/5=36 secs..
C
Question: A person lent a certain sum of money at 5% per annum at simple interest and in 8 years the interest amounted to $360 less than the sum lent. What was the sum lent?
A.540
B.560
C.580
D.600
Answer: D.600
Explanation: P - 360 = (P*5*8)/100
P = 600
The answer is D.
Question: At exactly what time past 6:00 will the minute and hour hands of an accurate working clock be precisely perpendicular to each other for the first time?
A.20 13/21 minutes past 7:00
B.20 13/17 minutes past 7:00
C.21 3/23 minutes past 7:00
D.21 9/11 minutes past 6:00
Answer: D.21 9/11 minutes past 6:00
Explanation: A1 = hour angle
A2 = minute angle
A1-A2 = 90
Assume the minutes = M
A1 = (6*60+M)/12*60 )*360
A2 = M*360/60
Solving all three equation , results in the answer D
Question: Ajay spends 45% of his monthly income on household items, 25% of his monthly income on buying cloths, 7.5% of his monthly income on medicines and saves the remaining amount which is Rs. 9000. Find his monthly income.
A.Rs. 40000
B.Rs. 36000
C.Rs. 50000
D.Rs. 45000
Answer: A.Rs. 40000
Explanation: Let the monthly income of Ajay be Rs. x
Savings of Ajay = x - (45 + 25 + 7.5)/100 * x = 22.5/100 x
22.5/100 x = 9000
x = 40000.
ANSWER:A
Question: Out of first 30 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ?
A.6/30
B.2/30
C.4/90
D.24/30
Answer: D.24/30
Explanation: n(S) = 30
n(Even no) = 15 = n(E)
n(Prime no) = 10 = n(P)
P(EᴜP)
= 15/30 + 10/30 - 1/30
= 24/30
Answer:D
Question: In a class, 20% of the students were absent for an exam. 30% failed by 20 marks and 10% just passed. Find the average score of the class if the remaining students scored an average of 65 marks and the cut off for passing the exam is 40.
A.36
B.302
C.272
D.292
Answer: A.36
Explanation: Explanation:
Let total students be 100.
Hence, marks of 20 students is 0 as they were absent.
30 students scored 20 marks (as they failed by 20 marks)
10 students scored 40 marks (just passed)
40 students scored 65 marks (average of 65)
Therefore, average score of the class is: (0 + 600 + 400 + 2600)/100 = 3600/100
= 36
ANSWER: A
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
A.200 m
B.225 m
C.245 m
D.250 m
Answer: C.245 m
Explanation: Explanation:
Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.
ANSWER IS C
Question: How many 3 digit numbers can be formed from the digits 2,3,5,6,7 and 9 which are divisible by 5 and none of the digits is repeated?
A.16
B.12
C.20
D.25
Answer: C.20
Explanation: Since each desired number is divisible by 5,
so we much have 5 at the unit place.
The hundreds place
can now be filled by any of the remaining 4 digits .
so, there4 ways of filling it.
Required number of numbers = (1 * 5 * 4)
= 20
Ans: C
Question: The labeled price of a table is Rs. 6,500. The shopkeeper sold it by giving 5% discount on the labeled price and earned a profit of 15%. What approximately is the cost price of the table?
A.Rs. 5369
B.Rs. 6195
C.Rs. 6425
D.Rs. 7200
Answer: A.Rs. 5369
Explanation: Explanation:
Labeled price = Rs. 6,500
By giving 5% discount on labeled price, the selling price is
= 95 / 100 * 6500 = Rs. 6175
By earning 15% profit on the selling of price Rs. 6175 the cost price is
= 100 / 115 * 6175 = Rs. 5369
Therefore, approximate cost is 5369
ANSWER A
Question: An investor deposited $5,000 to open a new savings account that earned 4 percent annual interest, compounded quarterly. If there were no other transactions in the account, what was the amount of money in the account 6 months after the account was opened?
A.$5050.50
B.$5100.50
C.$5200.50
D.$5300.50
Answer: B.$5100.50
Explanation: The amount in the account after 6 months is 1.01*1.01($5,000) = $5100.50
The answer is B.
Question: What will be the fraction of 5%
A.1/20
B.1/50
C.1/75
D.1/25
Answer: A.1/20
Explanation: Explanation:
5*1/100 = 1/20.
Option A
Question: A committee is to be formed by randomly choosing 4 people from 7 candidates. If Alice and Bob are candidates, what is the probability that Alice will be selected but Bob will not?
A.2/5
B.2/7
C.3/7
D.3/35
Answer: B.2/7
Explanation: The total number of ways to form a committee is 7C4=35.
The number of committees which include Alice but not Bob is 5C3=10.
The probability that Alice is selected but Bob is not selected is 10/35=2/7.
The answer is B.
Question: Walking at 3/4 of her normal speed, a worker is 8 minutes later than usual in reaching her office. The usual time (in minutes) taken by her to cover the distance between her home and her office is
A.20
B.24
C.28
D.32
Answer: B.24
Explanation: Let V be her normal speed and let T be her normal time.
D = (3/4)V * (T+8)
Since the distance is the same we can equate this to a regular day which is D = V*T
V*T = (3/4)V * (T+8)
T/4 = 6
T=24
The answer is B.
Question: total 36 matches are conducted in Knockout match type. How many players will be participated in that tournament?
A.35
B.36
C.21
D.32
Answer: A.35
Explanation: 35 players
ANSWER:A
Question: Tough and Tricky questions: Exponents.
If a and b are positive integers and x = 2^a and y = 3^b, which of the following is a possible units digit of xy?
A.4, 2, 8, 6
B.4 and 2
C.2 and 8 only
D.6 and 4
Answer: A.4, 2, 8, 6
Explanation: Only Units digit of X and Y contribute to the Units digit of XY.
Finding all values of X for positive values of a
When,
a=1; X=2
a=2; X=4
a=3; X=8
a=4; X=16
a=5; x=32........ Units digit repeat in a cycle of 2,4,8,6,2,4......
Similarly, Finding all values of Y for positive values of b
When,
b=1; Y=3
b=2; Y= 9
b=3; Y= 27
b=4; Y=81
b=5; Y=243....... Units digit repeat in cycle of 3,9,7,1,3,9....
So, possible value of Units digit of XY can be found by considering all possibilities of Units digit of X and Y
When X=2 and Y=3: Units digit of XY = 6
When X=2 and Y=9: Units digit of XY = 18
When X=2 and Y=7: Units digit of XY = 14
When X=2 and Y=1: Units digit of XY = 2
When X=4 and Y=3: Units digit of XY = 12
When X=4 and Y=9: Units digit of XY = 36
When X=4 and Y=7: Units digit of XY = 28
When X=4 and Y=1: Units digit of XY = 4
When X=8 and Y=3: Units digit of XY = 24
When X=8 and Y=9: Units digit of XY = 72
When X=8 and Y=7: Units digit of XY = 56
When X=8 and Y=1: Units digit of XY = 8
When X=6 and Y=3: Units digit of XY = 18
When X=6 and Y=9: Units digit of XY = 54
When X=6 and Y=7: Units digit of XY = 42
When X=6 and Y=1: Units digit of XY = 6
There are 4 possibilities for Units digit of XY i.e. 4, 2, 8 and 6
Ans: A
Question: Two stations A and B are 200 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
A.9
B.10
C.11
D.12
Answer: D.12
Explanation: Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
Therefore 20x + 25(x - 1) = 200
45x = 225
x = 5.
So, they meet at 12 a.m.
Answer: Option D
Question: Find the no.of ways of arranging the boy and 10 guests at a circular table so that the boy always sits in a particular seat?
A.3!
B.10!
C.7!
D.9!
Answer: B.10!
Explanation: Ans.(B)
Sol. Total number of persons = 11 Host can sit in a particular seat in one way. Now, remaining positions are defined relative to the host. Hence, the remaining can sit in 10 places in 10P10 = 10! Ways ... The number of required arrangements = 10! x 1= 10! = 10! ways
Question: Some consecutive natural numbers, starting with 1, are written on the board. Now, one of the numbers was erased and the average of the remaining numbers is 800/39. Find the number which was erased.
A.20
B.87
C.266
D.288
Answer: A.20
Explanation: We know that average of n consecutive numbes average = n×(n+1)2n=(n+1)2n×(n+1)2n=(n+1)2
If the given n is sufficiently large, the average does not change much even though we exclude one or two numbers from it. So the approximate number of observations is almost double to the average (Remember: the average of consecutive numbers almost lies in the middle)
The approximate average is 800/39 = Approx 20. So the initial numbers may be nearer to 40.
In this question it is actually 40 as from the denominator of the new average 800/39. The initial numbers are 40.
Sum of 40 consecutive numbers = 40×(40+1)2=82040×(40+1)2=820
Sum of 39 numbers = average x numbenumber of observations = 80039×3980039×39 = 800
So the number excluded = 820 - 800 = 20
Answer:A
Question: Today Mary’s father is four times as old as Mary. Seven years ago, he was 7 times as old. How old is Mary today?
A.11
B.12
C.13
D.14
Answer: D.14
Explanation: Dad's age = 4M
7*(M-7) = 4M-7
3M = 42
M = 14
The answer is D.
Question: Find the odd man out
253, 136, 352, 328, 631, 244
A.328
B.136
C.352
D.631
Answer: A.328
Explanation: The sum all three digits comes to 10 except 328
ANSWER:A
Question: What will be the ratio of simple interest earned by certain amount at the same rate of interest for 6 years and that for 3 years?
A.1 : 3
B.2 : 1
C.1 : 2
D.3 : 2
Answer: B.2 : 1
Explanation: Let the principal be P and rate of interest be R%.
Required ratio =
(P x R x 6)/100 DIVIDED BY	(P x R x 3)/100
=	6PR/3PR	=	6/3	= 2 : 1.
ANSWER : B
Question: What is the smallest number which, when increased by 7, is divisible by 8, 11, and 24?
A.264
B.257
C.269
D.270
Answer: B.257
Explanation: LCM(8,11,24)=24x11=264
So the least divisible number is 264, and the number we are looking for is 264-7=257.
The answer is B.
Question: Which of the following must be non-negative number?
A.(a-0.9)(a-1)
B.(a+1)(a-1)
C.(a+0.9)(a+1)
D.(a-0.8)(a-0.8)
Answer: D.(a-0.8)(a-0.8)
Explanation: 5-sec approach:
D. (a-0.8)(a-0.8) = (a-0.8)^2.
The square of a number is always non-negative.
Answer: D.
Question: A dice is thrown. What is the probability that the number shown in the dice is divisible by 3?
A.5/5
B.5/9
C.5/1
D.1/3
Answer: D.1/3
Explanation: Total number of outcomes possible when a die is rolled, n(S) = 6 (∵ 1 or 2 or 3 or 4 or 5 or 6)
E = Event that the number shown in the dice is divisible by 3 = {3, 6}
The probability = 2/6 = 1/3.
Answer: D
Question: If n = 8^11 – 1, what is the units digit of n?
A.3
B.1
C.0
D.6
Answer: A.3
Explanation: 8 ^ 11 - 8 = 8 (8 ^ 10 - 1)
==> 8 (2 ^ 30 - 1)
Last digit of 2 ^ 30 is 4 based on what explanation LiveStronger is saying. 2 ^ 30 - 1 yields 4 - 1 = 3 as the unit digit. Now on multiply this with 1, we get unit digit as 3.
Answer : A
Question: A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.2783 in 3 years. Find the rate percent?
A.15
B.10
C.28
D.24
Answer: A.15
Explanation: Explanation:
2420 --- 363
100 --- ? => 15%
Answer: Option A
Question: Sum of two numbers is 25. Two times of the first exceeds by 5 from the three times of the other. Then the numbers will be?
A.A)5
B.B)9
C.C)11
D.D)13
Answer: B.B)9
Explanation: Explanation:
x + y = 25
2x – 3y = 5
x = 16 y = 9
B)
Question: Kiran had 85 currency notes in all , some of which were of Rs.100 denomination and the remaining of Rs.50 denomination the total amount of all these currency note was Rs.5000.how much amount did she have in the denomination of Rs.50?
A.3500
B.1500
C.2500
D.4500
Answer: A.3500
Explanation: Let the no of fifty rupee notes be x
Then,no of 100 rupee notes =(85-x)
50x+100(85-x)=5000
x+2(85-x)=100
x=70
so, required amount=Rs.(50*70)= Rs.3500
Answer is A.
Question: Cost is expressed by the formula tb^4. If b is doubled, the new cost is what percent of the original cost?
A.200
B.600
C.800
D.1600
Answer: D.1600
Explanation: Original Cost C1=t1*b1^4
New Cost C2=t2*b2^4....only b is doubled so t2=t1 and b2=2b1
C2=t2*(2b1)^4
=16(t1*b1^4)
=16C1
16 times C1=>1600% of C1
Ans D=1600
Question: The function g(a) is defined for integers a such that if a is even, g(a) = a/2 and if a is odd, g(a) = a + 5. Given that g(g(g(g(g(a))))) = 19, how many possible values for a would satisfy this equation?
A.1
B.5
C.7
D.8
Answer: D.8
Explanation: Let me define terms:
in g(a) = R
a is argument, R is result, g() is function,
in g(g(g(g(g(a))))), g1 is inner most, g5 is outermost for identification.
From definition of function g, we can deduce that:
If Result is even then two possibilities for argument = 1 Even 1 Odd
If Result is odd then one possibility for argument = 1 Even
Since final result = 19 = Odd
Possibilities:
g1:1 Even
g2: 1*(Even,Odd ) =1 Even 1 Odd
g3: 1*(Even,Odd) + 1 Even =2 Even 1 Odd
g4: 2*(Even, Odd) + 1 Even =3 Even 2 Odd
g5: 3*(Even, Odd) + 2 Even =5 Even 3 Odd = Total 8
Ans D it is!
Question: 125^n divides 325^325
A.216
B.217
C.218
D.219
Answer: A.216
Explanation: 325^325=(13*25)^325 = (13^325)*(5^650)
125^n=5^(3n)
power of 5 in numerator should be greater then denominator
so 650>3n and hence
n=216
ANSWER:A
Question: If a two-digit positive integer has its digits reversed, the resulting integer differs from the original by 36. By how much do the two digits differ?
A. 3
B. 4
C. 5
D. 6
Answer: B. 4
Explanation: Given that (10a + b) - (10b + a) = 36 --> 9a - 9b =36 --> a - b = 4.
Answer: B.
Question: If 3 workers collect 48 kg of cotton in 4 days, how many kg of cotton will 9 workers collect in 2 days?
A.32 kg
B.25 kg
C.72 kg
D.88 kg
Answer: C.72 kg
Explanation: C
72 kg
(3 * 4)/48 = (9 * 2)/ x
x = 72 kg
Question: If 0.60: x : : 6 : 4, then x is equal to
A.0.1
B.0.4
C.0.82
D.0.8
Answer: B.0.4
Explanation: Sol.
(x×6) = (0.60×4) ⇒ x = 2.4/6 = 0.40.
Answer B
Question: When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/7 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?
A.3/10
B.2/5
C.1/2
D.2/3
Answer: B.2/5
Explanation: Say, the tree grows by x feet every year.
Then, 4 + 6x = (1+1/7)(4+4x)
or, x = 2/5
Answer B
Question: A teacher prepares a test. She gives 9 objective type questions out of which 4 have to be answered. Find the total ways in which they can be answered if the first 6 questions have 3 choices and the last 3 have 4 choices.
A.7255
B.7632
C.7192
D.7100
Answer: B.7632
Explanation: Two cases.
First Case: 2 Questions - 3 Choices, 2 Questions - 4 Choices
6C2 * 3C2 ways to select the questions
3C1 * 3C1 * 4C1 * 4C1 ways to answer the questions
= 15 * 3 * 3 * 3 * 4 * 4
= 6480
Second Case: 1 Question - 3 Choices, 3 Questions - 4 Choices
6C1 * 3C3 ways to select the questions
3C1 * 4C1 * 4C1 * 4C1 ways to answer the questions
= 6 * 1 * 3 * 4 * 4 * 4
= 1152
Total = 6480 + 1152
= 7632
B
Question: The population of a bacteria colony doubles every day. If it was started 10 days ago with 2 bacteria and each bacteria lives for 12 days, how large is the colony today?
A.512
B.768
C.1024
D.2048
Answer: D.2048
Explanation: 2^10(2) = 2^11 = 2048
The answer is D.