RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: When x is divided by y, the quotient is z with remainder f. Which of the following is equal to f?
A.yz – x
B.y/x−z
C.x – y – z
D.x – yz
Answer: D.x – yz
Explanation: (x/y)=z(+f)
(18/8)=2(+2)
x-yz
which is 18-(8*2)=2
Answer is D
Question: At the first meeting of the amputees’ support group, there were
93 fewer handshakes than there would have been if everyone
had at least one arm and shook hands once with everyone else.
The people with less than one arm made up 1/11 of the group.
How many of them were there?
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: perfect example to use the units digit to get the answer quick.
let's assume the answer is A, then (22*21)/2 - (20*19)/2 = 93?
we can actually ignore the second part (after the minus) of the equation because it will always end with a units digit of 0.
the first part will have a units digit of 1 --> (units digit of 2 * units digit of 1) / 2
for the rest
B) (33*32) / 2 --> (units digit 3 * units digit 2) / 2 = 3 (success)
C) (44*43) / 2 --> (units digit 4 * units digit 3) / 2 = 6 (fail)
D) (55*54) / 2 --> (units digit 5 * units digit 4) / 2 = 0 (fail)
E) (66*65) / 2 --> (units digit 6 * units digit 5) / 2 = 0 (fail)
Interesting approach, but I don't think the unit digit is correct for B, D and E. The even number will become half and that reduced number should be used to get the unit digit.
B) (33*32) / 2 --> (units digit 3 * units digit 6) = 8
D) (55*54) / 2 --> (units digit 5 * units digit 7) = 5
E) (66*65) / 2 --> (units digit 3 * units digit 5) = 5
answer is B
Question: Find the value of (1-(1/3))(1-(1/4))(1-(1/5))….(1-(1/100)).
A.1/50
B.3/50
C.4/50
D.6/50
Answer: A.1/50
Explanation: Answer is A.
Question: Find the missing number:
6 13 25 51 101 ?
A.201
B.202
C.203
D.204
Answer: C.203
Explanation: C
203
6x2+1=13
13x2-1=25
25x2+1=51
51x2-1=101
101x2+1=203
Question: There are 6 people in the elevator. Their average weight is 150 lbs. Another person enters the elevator, and increases the average weight to 151 lbs. What is the weight of the 7th person.
A.157
B.168
C.189
D.190
Answer: A.157
Explanation: Solution
Average of 7 people after the last one enters = 151 .
âˆ´ Required weight = (7x151)-(6x150)
= 1057- 900
= 157.
Answer A
Question: Simplify: (7+2) – (5+3+1)-1.
A.-1
B.–2
C.1
D.2
Answer: C.1
Explanation: Solution:
(7+2) – (5+3+1)-1
=9-5-3+1-1
=9-8+1-1
=2-1
=1
Answer: (C)
Question: A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
A.26
B.25
C.23
D.22
Answer: A.26
Explanation: Let the number of hens be x and the number of cows be y.
Then, x + y = 48 .... (i)
and 2x + 4y = 140
x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
Answer is A.
Question: By mixing two brands of tea and selling the mixture at the rate of Rs. 177 per kg. a shopkeeper makes a profit of 18%. If to every 2 kg of one brand costing Rs. 200 per kg, 3 kg of the other brand is added, then how much per kg does the other brand cost?
A.Rs.116.69
B.Rs.116.60
C.Rs.116.62
D.Rs.116.66
Answer: D.Rs.116.66
Explanation: Let the cost of the brand be Rs. X per kg.
C.P. of 5 kg = (2 * 200 + 3 * x) = Rs. (400 + 3x)
S.P of 5 kg = Rs. (5 * 177) = Rs. 885
[885 - (400 + 3x)]/(400 + 3x) * 100 = 18
24250 - 150x = 3600 + 27x
177x = 20650 => x = 116 2/3
So, cost of the other brand = Rs.116.66.
Answer: D
Question: Out of a classroom of 6 boys and 4 girls the teacher picks a president for the student board, a vice president and a secretary.
What is the probability that only girls will be elected?
A.1/30
B.4/30
C.5/30
D.7/30
Answer: A.1/30
Explanation: GBB (girl,boy,boy)
GGB (girl,girl,boy)
GGG (girl,girl,girl)
the probability of GGG is already known - 1/30.
ANS:A
Question: The owner of a cell phone shop charges his customer 23% more than the cost price. If a customer paid Rs.8,517 for a cell phone, then what was the cost price of the cell phone?
A.Rs.5,845
B.Rs.6,750
C.Rs.5,700
D.Rs.6,925
Answer: D.Rs.6,925
Explanation: Explanation:
123% of CP =SP
Therefore, CP = Rs.8,517x100/123 = Rs.6925
Answer: Option D
Question: If the sum of a number and its square is 72, what is the number?
A.15
B.26
C.8
D.91
Answer: C.8
Explanation: Let the number be x. Then,
x + x2 = 72
(x + 9)(x - 8) = 0
x = 8
ANSWER:C
Question: A number when divided successively by 4 and 5 leaves remainder 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will be?
A.0
B.1
C.2
D.3
Answer: D.3
Explanation: Trying to get back the number first.
5x+4
4*[5x+4] + 1
so number is 20x +17
now divide it successively by 5 and then 4
(20x + 17)/ 5 = 2 remainder and 4x + 3is number left
now divide it by 4 we will get 3 remainder
ANSWER:D
Question: Diesel costs Rs.4 per lit and petrol costs 6.23 per litre. If the price of diesel rise by 10% a month and the price of petrol is unchanged.How many months will it take until a litre of Diesel costs more than a litre of petrol.
A.9 months
B.5 months
C.6 months
D.3 months
Answer: B.5 months
Explanation: Explanation :
=>In the First Month the price of the diesel would be 4*110/100 = 4.4
=>In the Second Month the price of the diesel would be 4.4*110/100 = 4.84
=>In the Third Month the price of the diesel would be 4.84*110/100 = 5.324
=>In the fourth Month the price of the diesel would be 5.324*110/100 = 5.85
=>In the fifth Month the price of the diesel would be 5.85*110/100 = 6.44 which is higher than the price of petrol
Answer : B
Question: A trader sold an article on a certain price with 20% profit. If he sold double of previous selling price then find its profit %
A.140%
B.120%
C.100%
D.90%
Answer: A.140%
Explanation: let cost price = 100%
selling price = 120%
new s.p. = 240%
p% = 240-100 = 140%
Answer is A
Question: Efrida and Frazer who live 12 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home?
A.6
B.7
C.8
D.10
Answer: D.10
Explanation: It's a simple geometry problem. Look at the diagram below:
Answer: D.
Question: A contractor undertakes to complete the construction of a tunnel 720 meters long in 240 days and employs 50 men for the purpose. After 120 days, he finds that only 240 meters of the tunnel is complete. How many more men should be employ in order to complete the work in time?
A.75 men
B.80 men
C.70 men
D.60 men
Answer: C.70 men
Explanation: In 120days, only 240m of the tunnel is constructed by 50 men.
The remaining 120days, 480m of the tunnel can be constructed by 120 men.
Additional number of men required = 120 - 50 = 70 men.
ANSWER:C
Question: If 9 - 4/X = 7 + 8/X, then X =
A.15
B.6
C.1
D.5
Answer: B.6
Explanation: We're given the equation 9 - 4/X = 7 + 8/X. We're asked for the value of X.
The common-denominator of these 4 numbers is X, so we have to multiple 2 of the numbers to give them that denominator...
9X - 4X/X = 7X + 8X/X
We can then eliminate that denominator, which gives us....
9X - 4 = 7X + 8
12 = 2X
Both 2X and 12 have a common denominator of 2, so we divide both sides by 2 for our final answer...
6 = X
B
Question: A person travelled from his house to office at 35km/hr and office to house at 65km/hr. Then find the average speed?
A.30km/hr
B.45.5km/hr
C.48km/hr
D.50.5km/hr
Answer: B.45.5km/hr
Explanation: Average speed = (2*35*65)/(35+65)= 45.5km/hrAnswer is B
Question: Two trains of equal length are running on parallel lines in the same directions at 46km/hr. and 36km/hr. The faster trains pass the slower train in 18 seconds. The length of each train is:
A.25m
B.50m
C.72m
D.80m
Answer: A.25m
Explanation: Explanation:
The relative speed of train is 46-36 = 10 Km/hr = (10 X 5) / 18 = 25/9 m/s10×518=259m/s
In 18 secs the total distance traveled is 18x25/9 = 50 m.
Therefore the length of each train is = 50/2 = 25 m.
Answer A
Question: Find large no. from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 5 as remainder
A.1637
B.1456
C.1567
D.1678
Answer: A.1637
Explanation: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 5
5x = 1360
x = 272
Large number = 272+1365 = 1637
A
Question: How much interest can a person get on Rs. 8200 at 17.5% p.a. simple interest for a period of two years and six months?
A.3000
B.4000.75
C.3587.5
D.3500
Answer: C.3587.5
Explanation: I = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50
ANSWER C
Question: Mohit sold an article for Rs. 18000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
A.15000
B.15002
C.26879
D.26992
Answer: A.15000
Explanation: Let the CP be Rs. x.
Had he offered 10% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x
= Rs. 1.08x = 18000 - 10/100(18000)
= 18000 - 1800 = Rs. 16200
=> 1.08x = 16200
=> x = 15000
Answer: A
Question: The average age of 8 men increases by 2 years when two women are included in place of two men of ages 20 and 24 years. Find the average age of the women?
A.27
B.21
C.30
D.27
Answer: C.30
Explanation: 20 + 24 + 8 * 2
= 60/2
= 30
Answer:C
Question: The average of first five multiples of 3 is?
A.6
B.8
C.9
D.5
Answer: B.8
Explanation: Average = 3(1 + 2 + 3 + 4 + 5)/5
= 45/5
= 9.
Answer:B
Question: A bowl of fruit contains 14 apples and 23 oranges. How many oranges must be removed so that 70% of the pieces of fruit in the bowl will be apples?
A.3
B.6
C.14
D.17
Answer: D.17
Explanation: Number of apples = 14
number of oranges = 23
let number of oranges that must be removed so that 70% of pieces of fruit in bowl will be apples = x
Total number of fruits after x oranges are removed = 14+(23-x) = 37-x
14/(37-x) = 7/10
=>20 = 37-x
=>x= 17
Answer D
Question: The milk level in a rectangular box measuring 58 feet by 25 feet is to be lowered by 6 inches. How many gallons of milk must be removed? (1 cu ft = 7.5 gallons)
A.100
B.250
C.750
D.5437.5
Answer: D.5437.5
Explanation: 6 inches = 1/2 feet (there are 12 inches in a foot.), so 58*25*1/2=725 feet^3 of milk must be removed, which equals to 725*7.5=5437.5 gallons.
Answer: D.
Question: According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make an orange juice. How many 12 ounce cans of concentrate are required to prepare 200 6-ounce servings of orange juice.
A.25
B.34
C.50
D.67
Answer: A.25
Explanation: A =25
1 oz concentrate + 3 oz ofwater = 4 oz jucie
300 oz concentrate +900 oz of waer = 1200 oz juice
no of cans==300/12=25
Ratio of juice to water ===> 1:3
total 200*6 ounces
12 ounce juice cans ==> 1200/12 == 100*1/4 (ratio of jiuce to total) == 25
Question: The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 70% profit?
A.220
B.1088
C.960
D.780
Answer: B.1088
Explanation: C.P. = Rs. x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 170% of Rs. 640 = 170/100 * 640 = Rs. 1088.
B
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 390 sq. feet, how many feet of fencing will be required?
A.34
B.59
C.68
D.88
Answer: B.59
Explanation: Given that length and area, so we can find the breadth.
Length x Breadth = Area
20 x Breadth = 390
Breadth = 19.5 feet
Area to be fenced = 2B + L = 2 (19.5) + 20 = 59 feet answer : B
Question: Find the largest number of four digits which is exactly divisible by 27,18,12,15
A.9700
B.9710
C.9720
D.9730
Answer: C.9720
Explanation: Explanation:
LCM of 27-18-12-15 is 540.
After dividing 9999 by 540 we get 279 remainder.
So answer will be 9999-279 = 9720
Option C
Question: If x and y are integers and x=50y + 69, which of the following must be odd?
A.xy
B.x + y
C.x + 2y
D.3x-1
Answer: C.x + 2y
Explanation: x = 50y + 69, since y is integer, 50y will always be even hence 50y + 69 will be odd hence x = odd
you don't know whether Y is even or odd, so you need to try.
A: odd * even = even ; odd*odd= odd ->not true
B: odd + odd = even ; odd+even = odd -> not true
C: odd + 2*odd = odd ; odd + 2*even = odd -> TRUE, stop here.
Answer C
Question: If A speaks the truth 30% of the times, B speaks the truth 40% of the times. What is the probability that at least one will tell the truth
A.0.58
B.0.9
C.1.9
D.2.2
Answer: A.0.58
Explanation: probability of A speaks truth p(A)=3/10;false=7/10
probability of B speaks truth p(B)=4/10;false=6/10.For given qtn
Ans=1-(neither of them tell truth).Because A & B are independent events
=1-[(7/10)*(6/10)]=1-42/100=1-0.42=0.58
ANSWER:A
Question: If x + |x| + y = 7 and x + |y| - y =6 , then x + y =
A.3
B.4
C.5
D.6
Answer: A.3
Explanation: If x + |x| + y = 7 and x + |y| - y =6 , then x + y =
can be done in 2.3 mins :
there are 4 cases to be tested :
1) x is -ve and y is -ve
substituting in the equation , we get x-x+y=7 and x-y-y=6 solve for x and y we get x=20 and y=7 , so x+y=27 REJECT
2)x is +ve and y is +ve
substitute in the equation, we ger x+x+y=7 and x+y-y=6 solve for x and y we get x=6 and y=-5 ,therefore x+y=1 not on list so REJECT
3) x is -ve and y is +ve
substitute , we get x-x=y=7 and x+y-y=6 solve fo x and y we get x=6 and y=7, x+y=13 not on list so REJECT
4) x is +ve and y is -ve
substitute , we get x+x=y=7 and x-y-y=6 solve for x and y , we get x=4 and y= -1 ,x+y=3 , ANSWER CHOICE ANSWER A
Question: The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
A.20
B.200
C.300
D.400
Answer: B.200
Explanation: Let length of plot = L meters, then breadth = L - 20 meters
and perimeter = 2[L + L - 20] = [4L - 40] meters
[4L - 40] * 26.50 = 5300
[4L - 40] = 5300 / 26.50 = 200
4L = 240
L = 240/4= 60 meters. Answer: B
Question: Anand and Deepak started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 14,720, Deepak's share is:?
A.s.8467
B.s.8428
C.s.8400
D.s.8960
Answer: D.s.8960
Explanation: Ratio of their shares
= 22500 : 35000
= 9:14
Deepak's share
= 14720 * 14/23
= Rs.8960.
Answer:D
Question: Pipe A can fill in 20 minutes and Pipe B in 30 mins and Pipe C can empty the same in 40 mins.If all of them work together, find the time taken to fill the tank
A.17 1/7 mins
B.20 mins
C.8 mins
D.9 mins
Answer: A.17 1/7 mins
Explanation: A = 20
B = 30
C = -40
LCM = 120
=> A = 6,TIMES
B = 4
C = -3
=> A+B-C
= 7
TIME TAKEN TO FILL THE TANK = 120/7 MINS = 17 1/7 MINS
ANSWER:A
Question: A boy has 5 trousers and 13 shirts. In how many different ways can he select a trouser and a shirt?
A.299
B.65
C.68
D.67
Answer: B.65
Explanation: The boy can select one trouser in 5 ways.
The boy can select one shirt in 13 ways.
The number of ways in which he can select one trouser and one shirt is 5 * 13
= 65 ways.
Answer: B
Question: A and B are positive two-digit integers such that the tens digit in A is the same as the units digit in B, and the units digit in A is the same as the tens digit in B. Which of the following CANNOT be the difference of A and B ?
A.72
B.45
C.33
D.27
Answer: C.33
Explanation: A and B are positive two-digit integers such that the tens digit in A is the same as the units digit in B, and the units digit in A is the same as the tens digit in B:
A = 10x + y
B = 10y + x
A - B = (10x + y) - (10y + x) = 9(x - y). As you can see the difference must be a multiple of 9. Only option C is not a multiple of 9.
Answer: C.
Question: A shopkeeper wants to make a minimum net profit of 5% on a pair of jeans she is selling, which she bought for $100. If originally, she was selling the pair at 20% gain, what is the largest discount she can allow?
A.12.5%
B.8%
C.8.3%
D.15%
Answer: A.12.5%
Explanation: A
If she bought the jeans at $100, she is currently selling them at (120/100)*100 = $120.
She wants to make a profit of 5%, which means she needs to sell them at (105/100)*100 = $105
The max discount she can allow is thus ((120-105)/120)*100 = 12.5%
Question: If the original mass of an element, in grams, is a whole number and the element has decayed by exactly 93 percent in some time period, which of the following could be the final mass of that element?
A.27 grams
B.28 grams
C.29 grams
D.31 grams
Answer: B.28 grams
Explanation: Let original mass be 100
The final mass of that element will be 7
So whatever option we have it will be divisible by 7
Check for the options the one that doesn't produce non terminating decimal is our answer
A. 27 grams
27/7 = 3.857...
B. 28 grams
28/7 = 4
C. 29 grams
29/7 = 4.142.......
D. 31 grams
31/7 = 4.428.....
E. 32 grams
32/7 = 4.571....
Hence our answer will be (B)
Question: A girl goes to her school from her house at a speed of 6km/hr and returns at a speed of 4 km/hr. If she takes 10 hours in going and coming back, the distance between her school and house is
A.12km
B.16 km
C.20 km
D.24 km
Answer: D.24 km
Explanation: Explanation :
Let distance be D
10 = D/4 + D/6
Answer – D
Question: Students at a school were on average 180 cm tall. The average female height was 170 cm, and the average male height was 182 cms. What was the ratio of men to women?
A. 5:2
B. 5:1
C. 4:3
D. 4:1
Answer: B. 5:1
Explanation: We're given a few facts to work with:
1) The average height of the females is 170cm
2) The average height of the males is 182cm
3) The average of the GROUP is 180cm
We're asked for the RATIO of men to women.
W = number of Women
M = number of Men
(170W + 182M)/(W+M) = 180
170W + 182M = 180W + 180M
2M = 10W
M = 5W
M/W = 5/1
The ratio of men to women is 5 to 1.
B
Question: Three distinct single-digit numbers. A,B,C are in GP. If abs(x) for real x is the absolute value of x(x if x is +ve or 0 and -x if x is -ve), then the number of different possible values of abs(A+B+C) is
A.1
B.2
C.3
D.4
Answer: D.4
Explanation: A,B,C may be
(1,2,4) & (4,2,1)
(1,3,9) & (9,3,1)
(2,4,8) & (8,4,2)
(4,6,9) & (9,6,4)
find abs(A+B+C) for these 8 GPs
7,13,15,19
So,we get 4 different values
ANSWER:D
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 120 m and they cross each other in 12 sec, then the speed of each train is?
A.10
B.18
C.63
D.36
Answer: D.36
Explanation: Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/12 => x = 10
Speed of each train = 10 m/sec.
= 10 * 18/5 =- 36 km/hr.
ANSWER:D
Question: Evaluate: 30 - 12÷3×2 =
A.11
B.22
C.33
D.44
Answer: B.22
Explanation: According to order of operations, 12÷3×2 (division and multiplication) is done first from left to right
12÷3×2 = 4 × 2 = 8
Hence
30 - 12÷3×2 = 30 - 8 = 22
correct answer is B) 22
Question: A train running at the speed of 72 km/hr crosses a pole in 8 seconds. Find the length of the train.
A.150 meter
B.145 meter
C.160 meter
D.135 meter
Answer: C.160 meter
Explanation: Explanation:
Speed = 72*(5/18) m/sec = 20 m/sec
Length of Train(Distance) = Speed * Time
=20*8=160 meter
Option C
Question: Last September the sales total for a certain car dealership was 400% greater than the average monthly sales total for the other 11 months. The sales total for September was approximately what percent of the year´s sales?
A.15 %
B.27%
C.31%
D.42%
Answer: C.31%
Explanation: 11 moth avg = x
11 month total = 11x
sept = 400% of x + x = 5x
sept/total = =5x/(11x+5x) = =31%
ANSWER:C
Question: The supplementary of an angle is thrice its complimentary. Find the angle.
A.60
B.45
C.90
D.180
Answer: B.45
Explanation: let angle=x;
by question--
180-x=3(90-x)
x=45
ANSWER:B
Question: The average weight of 25 girls increases by 1 kg when a new girl comes in place of one of them weighing 55 kg. What might be the weight of the new girl?
A.85 kg
B.90 kg
C.83 kg
D.80 kg
Answer: D.80 kg
Explanation: Total weight increased = 25 x 1 kg = 25 kg.
Weight of new person = 55 + 25 kg =80 kg
Answer : D
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 44 years now, the son's age five years back was:
A.A)14
B.B)17
C.C)56
D.D)89
Answer: B.B)17
Explanation: Let the son's present age be x years. Then, (44 - x) = x
2x = 44.
x = 22.
Son's age 5 years back (22 - 5) = 17 years.
Answer:B
Question: L = {3, 4, 5, 5, 6, 7}
M = {2, 2, 2, 8, 8, 8}
N = {15, 15, 15, 15, 15, 15}
Rank those three sets from least standard deviation to greatest standard deviation.
A.L, M, N
B.M, L, N
C.M, N, L
D.RANKING=N, L, M
Answer: D.RANKING=N, L, M
Explanation: Square of Standard deviation is sum of squares of deviation from the mean divided by the number of terms.
If deviation from the mean is higher for the same number of elements, standard deviation will be higher.
L = {3, 4, 5, 5, 6, 7}
Mean is 5 and deviation of 2 elements from mean is 0, of 2 elements is 1 and of 2 elements is 2.
M = {2, 2, 2, 8, 8, 8}
Mean is 5 and deviation of all elements from the mean is 3. So SD here will be higher than SD of L.
N = {15, 15, 15, 15, 15, 15}
Mean is 15 here and all elements have 0 deviation from mean so SD = 0 here. This is the minimum possible SD.
Answer N, L, M
Answer (D)
Question: The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
A.4years
B.8years
C.10years
D.12years
Answer: A.4years
Explanation: Explanation:
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Answer: A
Question: The difference between a two-digit number and the number obtained by interchanging the digit is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1:2?
A.4
B.8
C.16
D.18
Answer: B.8
Explanation: Explanation:
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let the ten's and unit's digits be 2x and x respectively.
Then, (10 * 2x + x) - (10x + 2x) = 36
9x = 36
x = 4
Required difference = (2x + x) - (2x - x) = 2x = 8.
ANSWER IS B
Question: Find the area of a parallelogram with base 20 cm and height 10 cm?
A.287 cm2
B.887 cm2
C.200 cm2
D.250 cm2
Answer: C.200 cm2
Explanation: Area of a parallelogram = base * height
= 20 * 10
= 200 cm2
Answer: C
Question: The angle of elevation of the sun, when the length of the shadow of a tree 3 times the height of the tree, is:
A.30º
B.45º
C.60º
D.90º
Answer: A.30º
Explanation: shadow of the tree is √3 times the height of the tree.
shadow of a tree will be = √3x.
tan θ = AB/AC = x/√3x.
tan θ =1/√3.
tan θ = tan 1/√3.
tan θ = tan30°.
θ = 30° ANSWER : A
Question: A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
A.2.2 m
B.2.4 m
C.3 m
D.3.4 m
Answer: C.3 m
Explanation: Area of the park = (60 x 40) m2= 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2= 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
ANSWER : C
Question: If a refrigerator contains 12 cans such that there are 7 blue cans and 5 red cans. In how many ways can we remove 8 cans so that at least 1 blue can and 1 red can remains in the refrigerator.
A.452
B.453
C.454
D.455
Answer: D.455
Explanation: The possible cases of (b,r) draws are (6,2) (5,3) (4,4)
6 2---->7c6*5c2--->7*10=70
5 3---->7c5*5c3--->21*10=210
4 4---->7c4*5c4--->35*5=175
70+210+175=455
ANSWER:D
Question: 60% of Ram's marks is equal to 20% of Rahim's marks which percent is equal to 30% of Robert's marks. If Robert's marks is 80, then find the average marks of Ram and Rahim?
A.70
B.97
C.80
D.90
Answer: C.80
Explanation: Given, 60% of Ram's marks = 20% of Rahim's marks = 30% of Robert's marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 60% of Ram's marks = 24.
=> Ram's marks = (24 * 100)/60 = 40
Also, 20% of Rahim's marks = 24
=> Rahim's marks = (24 * 100)/20 = 120
Average marks of Ram and Rahim = (40 + 120)/2 = 80.
Answer:C