RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: There are 3 persons Sudhir, Arvind, and Gauri. Sudhir lent cars to Arvind and Gauri as many as they had already. After some time Arvind gave as many cars to Sudhir and Gauri as many as they have. After sometime Gauri did the same thing. At the end of this transaction each one of them had 24. Find the cars each originally had.
A.Sudhir had 34 cars, Arvind had 21 cars and Gauri had 12 cars.
B.Sudhir had 38 cars, Arvind had 21 cars and Gauri had 12 cars.
C.Sudhir had 39 cars, Arvind had 21 cars and Gauri had 12 cars.
D.Sudhir had 32cars, Arvind had 21 cars and Gauri had 12 cars.
Answer: C.Sudhir had 39 cars, Arvind had 21 cars and Gauri had 12 cars.
Explanation: Sudhir Arvind Gauri
Finally 24 24 24
Before Gauri’s transaction 12 12 48
Before Arvind’s transaction 6 42 24
Before Sudhir’ s transaction 39 21 12
Answer:C
Question: Cindy has her eye on a sundress but thinks it is too expensive. It goes on sale for 15% less than the original price. Before Cindy can buy the dress, however, the store raises the new price by 25%. If the dress cost $71.4 after it went on sale for 15% off, what is the difference between the original price and the final price?
A.$5.625
B.$1.00
C.$3.40
D.$5.25
Answer: D.$5.25
Explanation: 0.85*{Original Price} = $71.4 --> {Original Price} = $84.
{Final Price} = $71.4*1.25 = $89.25.
The difference = $89.25 - $84 = $5.25
Answer: D.
Question: In how many ways can 2 men & 4 women can be made from a gang of 4 men & 7 women ?
A.100
B.41
C.45
D.78
Answer: B.41
Explanation: Explanation:
4C2 * 7C4 = 41
B
Question: Mr. Thomas invested an amount of 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be 3508, what was the amount invested in Scheme B?
A.4800
B.6500
C.2280
D.3400
Answer: B.6500
Explanation: B
6500
Let the sum invested in Scheme A be x and that in Scheme B be (13900 - x).
Then, (x x 14 x 2)/100 + ((13900 - x) x 11 x 2)/100 = 3508
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = (13900 - 7500) = 6400.
Question: Joe has a bunch of change in his pocket? Which of the following choices is the correct amount of change?
A.75 cents
B.85 cents
C.29 cents
D.39 cents
Answer: C.29 cents
Explanation: 29 is the only prime number, so answer C is the correct answer.
Question: How much interest can a person get on Rs. 8600 at 17.5% p.a. simple interest for a period of two years and six months?
A.3587.58
B.3587.59
C.3587.5
D.3762.5
Answer: D.3762.5
Explanation: I = (8600 * 2.5 * 17.5)/100 = (8600 * 5 * 35)/(100 * 2 * 2) = Rs. 3762.50.Answer: D
Question: A shirt goes on sale for 80% of its original price. One week later, the sale price is marked down 20%. The final price is what percent of the original price?
A.72%
B.70%
C.52%
D.64%
Answer: D.64%
Explanation: Just assume original price is 100.
Sale price = 80
Then it is marked down by 20% = 80-16=64.
Hence it is 64% od the original price. Hence answer is D.
Question: Excluding stoppages, the speed of a train is 54 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour?
A.20
B.17
C.15
D.18
Answer: A.20
Explanation: T = 18/54 * 60
= 20
Answer: A
Question: Insert the missing number. 12, 25, 49, 99, 197, 395, (...)
A.789
B.1579
C.12
D.23
Answer: A.789
Explanation: Each number is twice the previous one with 1 added or subtracted alternatively. Missing Number is 789
Answer is A
Question: If 3 persons can do 3 times of a particular work in 3 days, then, 7 persons can do 7 times of that work in
A.6 days
B.2 days
C.3 days
D.5 days
Answer: C.3 days
Explanation: That is, 1 person can do one time of the work in 3 days.
Therefore, 7 persons can do 7 times work in the same 3 days itself.
C
Question: If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively?
A.Rs.300
B.Rs.360
C.Rs.389
D.Rs.368
Answer: B.Rs.360
Explanation: (A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4
A:B = 2:3 and B:C = 1:4 = 3:12
A:B:C = 2:3:12
A;s share = 510 * 2/17 = Rs. 60
B's share = 510 * 3/17 = Rs. 90
C's share = 510 * 12/17 =Rs.360.
Answer:B
Question: IF A fair coin with sides marked heads and tails is to be tossed eight times. What is the probability that the coin will land tails side up more than five times?
A.A)37/256
B.B)56/256
C.C)65/256
D.D)70/256
Answer: A.A)37/256
Explanation: More than 5 times tails = 6times +7times+8times = 8C6 + 8C7 + 8C8 = 37
- - - - - - - -
2 2 2 2 2 2 2 2
2^8 times total events and 37 events where tails side up .
So probability = 37/2^8 = 37/256 (Answer A)
Question: If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?
A.22 1/6 %
B.22 8/2 %
C.25 1/2 %
D.22 1/2 %
Answer: D.22 1/2 %
Explanation: 9 = (1*40*R)/100
R = 22 1/2 %
Answer: D
Question: If a = (1/2)b and c = 5a, then which of the following represents the average (arithmetic mean) of a, b, and c, in terms of a ?
A. (8/3)a
B. (11/3)a
C. 4a
D. (4 1/7)a
Answer: A. (8/3)a
Explanation: Official Answer: A
The average of the three variables isa + b + c/3. However, we need to solve in terms of a, which means we must convert b and c into something in terms of a.
Were told that a =1/2b, which is equivalent to b = 2a. We can plug that in and simplify the average to:a + 2a + c/3
We also know that c = 5a, which we can plug directly into the average expression:
a + 2a + 5a/3
= 8a/3 = (8/3)a, choiceA.
Question: In how many ways can 4 arts and 5 science students be arranged in a row so that the arts and the science students are placed alternately?
A.2880
B.1850
C.3260
D.5200
Answer: A.2880
Explanation: The four art students can be arranged in those 4 A-slots in 4! = 24 ways.
The five science students can be arranged in those 5 S-slots in 5! =120 ways.
Total arrangements = 24 *120 = 2880
Answer =(A)
Question: A certain list consists of 21 different numbers. If n is in the list and n is 6 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?
A.1/20
B.1/6
C.1/5
D.3/13
Answer: D.3/13
Explanation: series : a1, a2....a20,n
sum of a1+a2+...+a20 = 20*x (x = average)
so, n = 6*x
Hence, a1+a2+..+a20+n = 26x
So, the fraction asked = 6x/26x = 6/26=3/13
D
Question: S = { 1,2,3,5,6}
T = { 2,3,6,7 }
what is the probability that x chosen from S and y chosen from T will result x*y = even
A.2/7
B.3/8
C.7/10
D.10/7
Answer: C.7/10
Explanation: p: the probability that x*y is even, then p=1-p(x*y is odd)
p(x*y odd)=p(x odd)*p(y odd)=3/5*2/4=3/10
And p=1-3/10=7/10.
Option: C
Question: What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit?
A.1
B.14
C.20
D.21
Answer: C.20
Explanation: Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number =14
Required percentage =(14x 100)/70% = 20%.
Answer :C
Question: Three different containers contain 496 litres, 403 litres and 713 litres of mixture of milk and water respectively. What is the biggest measure can measure all the different quantities exactly ?
A.29 litres
B.31 litres
C.35 litres
D.19 litres
Answer: B.31 litres
Explanation: M1 = 496 litres
M2 = 403 litres
M3 = 713 litres
Required measurement = H.C.F. of M1,M2,M3 = 31 litres
Answer is B
Question: A train running at the speed of 60 km/hr crosses a pole in 15 seconds. Find the length of the train?
A.250 meter
B.876 meter
C.167 meter
D.719 meter
Answer: A.250 meter
Explanation: Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 15
= 250 meter
Answer: A
Question: In a race with 30 runners where 4 trophies will be given to the top 6 runners (the trophies are distinct: first place, second place, etc), how many ways can this be done?
A.8^8 ways
B.8^9 ways
C.6^4 ways
D.8^7 ways
Answer: C.6^4 ways
Explanation: 6 people can be prized with 4 distinct prizes in 6^4 ways
ANSWER:C
Question: If the area of a square with sides of length 3 centimeters is equal to the area of a rectangle with a width of 3 centimeters, what is the length of the rectangle, in centimeters?
A.3
B.8
C.12
D.16
Answer: A.3
Explanation: Let length of rectangle = L
3^2 = L*3
=> L = 9/3 = 3
Answer A
Question: Some times small town drivers can be very rude. One taxi driver I had the occasion to travel with was particularly lacking in courtesy, and so I asked for his number.
The driver gave me a sardonical smile and said. 'Well, if you divide my number by 2, 3, 4, 5 or 6 you will find there is always 1 remaining. But if you divide it by 11 there is no remainder. Do you want to know something more? There is no other cabby in this town with a lower number than---who can say the same.,' and he drove off, while I stood there completely baffled.
What was the man's number?
A.121
B.143
C.165
D.133
Answer: A.121
Explanation: A
The driver's number was 121.
Question: If a tap could fill entire tank in 18 hrs due to leakage, then in how much time
tank can be emptied by leakage if tap can fill entire tank in 14 hrs without leakage
A.12hrs
B.63hrs
C.36hrs
D.48hrs
Answer: B.63hrs
Explanation: time take to fill[withleakage] =18hrs so workdone in 1hr=1/18
time tkae to fill[without leakage]=14hrs so workdone in 1hr=1/14
if u subtract both u'll get time taken by leakage to empty...
1/18-1/14=2/126 = 1/63 so 63hrs
ANSWER:B
Question: A camera lens filter kit containing 5 filters sells for $67.50. If the filters are purchased individually, 2 of them are priced at $7.45 each, 2 at $10.05 each, 1 at $14.50. The amount saved by purchasing the kit is what percent of the total price of the 5 filters purchased individually?
A.25.66%
B.26.66%
C.27.66%
D.28.66%
Answer: B.26.66%
Explanation: Cost of kit = $67.50
If filters are purchased individually - $7.45*2 + $10.05*2 + $14.50 = $49.50
Amount saved = $67.50 - $49.50 = $18
Required %age = ($18/$67.50)*100 = 26.66%
So, the correct answer is B.
Question: The equation (M )/63 = (p )/21 relates two temperature scales, where M is the number of degrees on one scale and P is the number of degrees on the other scale. Which of the following equations can be used to convert temperatures from the P scale to the M scale?
A.P
B.2P
C.4P
D.3P
Answer: D.3P
Explanation: M/63 =(P)/21
M = (P)*63/21
=(P)*3 =3P
D
Question: what is the unit digit in [(6273)^1793x(625)^317x(341)^491]?
A.0
B.2
C.3
D.5
Answer: A.0
Explanation: Unit digit in (6374)^1793=Unit digit in (4)^1793
=Unit digit in [(4^2)^896 x 4]
=Unit digit in (6x4)=4
Unit digit in (625)^317=Unit digit in (5)^317=5
Unit digit in (341)^491=Unit digit in (1)^491=1
Required digit = Unit digit in (4x5x1)=0
Answer is 0
Question: A and B start a business with Rs.6000 and Rs.8000 respectively. Hoe should they share their profits at the end of one year?
A.1:2
B.3:4
C.2:5
D.3:7
Answer: B.3:4
Explanation: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
6000 : 8000 => 3:4
ANSWER:B
Question: A sum was put at simple interest at certain rate for 3 years. Had it been put at 1% higher rate it would have fetched Rs. 66 more. The sum is: A. Rs. 2,400 B. Rs. 2,100 C. Rs. 2,200 D.Rs. 2,480
A.2000
B.2100
C.2200
D.2300
Answer: C.2200
Explanation: 1 percent for 3 years= 66
1 percent for 1 year = 22
=> 100 percent = 2200
ANSWER:C
Question: A property decreases in value every year at the rate of 6 1/4% of its value at the beginning of the year its value at the end of 3 years was Rs.21093. Find its value at the beginning of the first year?
A.25600.24
B.25600.27
C.25600.28
D.25600.21
Answer: A.25600.24
Explanation: 6 1/4% = 1/16
x *15/16 * 15/16 * 15/16 = 21093
x = 25600.24
Answer:A
Question: When working alone, painter W can paint a room in 2 hours, and working alone, painter X can paint the same room in e hours. When the two painters work together and independently, they can paint the room in 3/4 of an hour. What is the value of e?
A.3/4
B.1[1/5]
C.1[2/5]
D.1[3/4]
Answer: B.1[1/5]
Explanation: Rate*Time=Work
Let Painter W's rate be W and Painter X's rate be X
R*T = Work
W * 2 = 1 (If the work done is same throughout the question then the work done can be taken as 1) => W = 1/2
X * e = 1 => X = 1/e
When they both work together then their rates get added up
Combined Rate = (W+X)
R*T = Work
(W+X) * 3/4 = 1
=> W+X = 4/3
=> 1/2 + 1/e = 4/3
=> 1/e = (8-3)/6 = 5/6
=> e = 6/5 = 1[1/5]
Answer B
Question: The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:
A.28
B.32
C.40
D.53
Answer: C.40
Explanation: Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
Answer: Option C
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 48, the dividend is?
A.5808
B.5825
C.5830
D.5835
Answer: A.5808
Explanation: Divisor = (5 * 48) = 240
= 10 * Quotient = Divisor
=> Quotient = 240/10 = 24
Dividend = (Divisor * Quotient) + Remainder
Dividend = (240 * 24) + 48 = 5808
A
Question: In a graduating class, 40 percent of the students are male. In this class, 40 percent of the male students and 20 percent of the female students are 25 years old or older. If one student in the class is randomly selected, approximately what is the probability that he or she will be less than 25 years old?
A.0.9
B.0.72
C.0.45
D.0.35
Answer: B.0.72
Explanation: Let x be the total number of students.
The number students who are younger than 25 is 0.6*0.4x+0.8*0.6x = 0.72x
The answer is B.
Question: What will come in place of the x in the following Number series? 2, 2, 4, 12, 48, 240, x
A.2560
B.960
C.1440
D.480
Answer: C.1440
Explanation: There is one series here
(the multiply by number increases by 1 to get the next number)
2 x 1 = 2
2 x 2 = 4
4 x 3 = 12
12 x 4 = 48......
Hence: 240 x 6= 1440
C is the correct choice
Question: Two good train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km / hr and 30 km /hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
A.12 sec
B.24 sec
C.48 sec
D.60 sec
Answer: C.48 sec
Explanation: Sol.
Relative Speed = (45 + 30) km / hr
= (75 x 5 / 18) m/sec
= (125/6) m/sec.
Distance covered = (500 + 500) m = 1000 m.
Required time = (1000 x 6 / 125) sec = 48 sec.
Answer C
Question: Due to 10% decrease in the price of sugar and John can buy 5kg more sugar in Rs.100, then find the CP of sugar?
A.Rs. 1(1/9)
B.Rs. 2(2/9)
C.Rs. 2(2/7)
D.Rs. 2
Answer: B.Rs. 2(2/9)
Explanation: Here r = 10 % ,x = 100 and A = 5 kg
Actual price of sugar = 10*100/((100-10 )*5) = Rs. 2(2/9)
B
Question: A 70 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?
A.12
B.20
C.88
D.77
Answer: B.20
Explanation: 1: 2/5 = 5: 2
2/7 * 70 = 20
Answer: B
Question: A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
A.4991
B.5991
C.5491
D.6991
Answer: A.4991
Explanation: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991
Answer: Option A
Question: With out any halt a train travels a certain distance with an average speed of 40 km ph , and with halts it covers the same distance at an average speed of 25 kmph. When it is traveling with halts, how many minutes/per hour does the train halt on an average ?
A.48 min.
B.12min.
C.15min.
D.36min.
Answer: D.36min.
Explanation: With halt in 1 hour the train travels 60km
With out halt for traveling same distance it take 40/25 = 8/5 = 96 minutes
:. 36 minutes is the halting time per hour
ANSWER:D
Question: A milkman sells his milk at CP but he mixes it with water and thereby gains 25%. What is the % of water in the mixture?
A.10%
B.12%
C.20%
D.25%
Answer: C.20%
Explanation: Here Gain= 25%
error = quantity of water he mixes in the milk =x
true value = true quantity of milk = T
So the formula becomes, 25=x(T−x)×100
⇒1=x(T−x)×4⇒T−x=4x⇒T=5x
Percentage of water in the mixture
=xT×100=x5x×100=15×100=20%
C
Question: A person has four iron bars whose lengths are 24 m, 36 m, 48 m and 72 m respectively. This person wants to cut pieces of same length from each of four bars. What is the least number of total pieces if he is to cut without any wastage?
A.11
B.12
C.15
D.13
Answer: C.15
Explanation: C
15
24 = 12 × 2,
36 = 12 × 3,
48 = 12 × 4,
and 72 = 12 × 6
∴ HCF (24, 36, 48, 72) = 12
Total pieces = 2 + 3 + 4 + 6 = 15
Question: 165 liters of a mixture of milk and water contains in the ratio 3:2. How much water should now be added so that the ratio of milk and water becomes 3:4?
A.66 liters
B.32 liters
C.41 liters
D.50 liters
Answer: A.66 liters
Explanation: Milk = 3/5 * 165 = 99 liters
Water = 66 liters
99 : (66+P) = 3:4
198 + 3P = 396 => P = 66
66 liters of water are to be added for the ratio become 3:4.
Answer:A
Question: The present worth of Rs.338 due in 2 years at 4% per annum compound interest is
A.Rs.312.5
B.Rs.154.75
C.Rs.156.25
D.Rs.158
Answer: A.Rs.312.5
Explanation: Solution
Present Worth	= Rs.[338/(1+4/100)²]
= Rs.(338x25/26x25/26)
= Rs.312.5
Answer A
Question: How many numbers between 100 and 600 are divisible by 2, 3, and 7 together?
A.11
B.12
C.14
D.16
Answer: B.12
Explanation: Explanation:
As the division is by 2, 3, 7 together, the numbers are to be divisible by: 2*3*7 = 42
The limits are 100 and 600
The first number divisible is 42*3 = 126
To find out the last number divisible by 42 within 600:
600/42 = 14.28
Hence, 42*14 = 588 is the last number divisible by 42 within 600
Hence, total numbers divisible by 2, 3, 7 together are (14 – 2) = 12
ANSWER: B
Question: A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
A.230 m
B.240 m
C.260 m
D.320 m
Answer: A.230 m
Explanation: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x = 230.
ANSWER:A
Question: Which one of the given numbers is divisible by 11?
A.4823718
B.8423718
C.8432718
D.4238718
Answer: D.4238718
Explanation: Explanation:
4238718 = (4+3+7+8) – (2+8+1) = 11
So, the given number is divisible by 11
Answer:D
Question: If a certain toy store's revenue in November was 3/5 of its revenue in December and its revenue in January was 1/6 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?
A.3/2
B.5/4
C.10/3
D.20/7
Answer: D.20/7
Explanation: N = 3D/5
J = N/6 = D/10
The average of November and January is (N+J)/2 = 7D/10 / 2 = 7D/20
D is 20/7 times the average of November and January.
The answer is D.
Question: Divide Rs.32000 in the ratio 3:7?
A.12000, 20000
B.9600, 22400
C.12000, 20007
D.12000, 20006
Answer: B.9600, 22400
Explanation: 3/10 * 32000 = 9600
7/8 * 32000 = 22400
Answer: B
Question: The three digits of a number add up to 17. The number is divisible by 5. The leftmost digit is double the middle digit. What is the product of the three digits?
A.160
B.72
C.78
D.88
Answer: A.160
Explanation: Say the three-digit number is abc.
The leftmost digit is double the middle digit --> a=2b;
The number is divisible by 5 --> c is either 0 or 5;
The three digits of a number add up to 17 --> a+b+c=17
So, either a+b+c=2b+b+0=17 or a+b+c=2b+b+5=17. The first equation does not give an integer value of b, so it's not the case. From the second we get that b=4 --> a=8 and c=5 --> a*b*c=160.
Answer: A.
Question: Peter's One tap, working alone at its maximum constant rate, can fill a certain sink in 220 seconds. A second tap, working alone at its maximum constant rate, can fill the same sink in 224 seconds. If both taps work together at their respective maximum constant rates, the time it will take to fill the sink is closest to
A.111 seconds
B.130 seconds
C.177 seconds
D.200 seconds
Answer: A.111 seconds
Explanation: Tap 1 : 220 secs
Tap 2 : 224 secs
Considering the average of these 2 taps : 222 secs.
So 1 tap can fill the tank in 222 secs, so 2 taps can fill the tank in 222/2 = 111 secs.
Closest answer is A.
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 52 years now, the son's age five years back was?
A.18years
B.19years
C.20years
D.21years
Answer: D.21years
Explanation: Let the son's present age be x years. Then, (52 - x) = x
2x = 52.
x = 26.
Son's age 5 years back (26 - 5) = 21 years.
D)
Question: A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
A.7 km/h
B.5 km/h
C.3 km/h
D.2 (1/2) km/h
Answer: D.2 (1/2) km/h
Explanation: 100 --- 10 DS = 10
? ---- 1
75 ---- 15 US = 5
? ----- 1 S = (10 - 5)/2
= 2 2 ½ kmph
ANSWER:D
Question: The average of first six multiples of 3 is
A.10.5
B.6
C.9
D.12
Answer: A.10.5
Explanation: Solution
Average	= 3(1+2+3+4+5+6) / 6
= 63 / 6.
= 10.5.
Answer A
Question: x varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to?
A.1/6
B.1/3
C.1/0
D.1/9
Answer: D.1/9
Explanation: Given x = k/y2, where k is a constant.
Now, y = 2 and x = 1 gives k = 4.
x = 4/y2 => x = 4/62, when
y = 6 => x = 4/36 = 1/9.
Answer:D
Question: What is the approximate value of b in the following equation?
18% of 4514 + 25% of 3415 = b
A.1620
B.1670
C.1680
D.1690
Answer: B.1670
Explanation: b = 18% of 4514 + 25% of 3415
b = 18/100* 4514 + 25/100* 3415
b = 1666.27
≈ 1670
Answer B
Question: A certain sum amounts to Rs.1725 in 3 years and Rs.1875 in 5 years. Find the rate % per annum?
A.3%
B.5%
C.6%
D.4%
Answer: B.5%
Explanation: 3 --- 1725
5 --- 1875
--------------
2 --- 150
N = 1 I = 75 R = ?
P = 1725 - 225 = 1500
75 = (1500*1*R)/100
R = 5%
Answer :B
Question: John bought a shirt on sale for 25% off the original price and another 25 % off the discounted price. If the final price was $16, what was the price before the first discount?
A.$18.44
B.$28.44
C.$48.44
D.$58.44
Answer: B.$28.44
Explanation: let x be the price before the first discount. The price after the first discount is
x - 25%x (price after first discount)
A second discount of 25% of the discounted price after which the final price is 16
(x - 25%x) - 25%(x - 25%x) = 16
Solve for x
x = $28.44
correct answer B
Question: When the positive integer x is divided by the positive integer y, the quotient is 3 and the remainder is z. When z is divided by y, the remainder is 2. Which of the following could be the value of x?
I. 5
II. 8
III. 32
A.I only
B.II only
C.III only
D.I and II only
Answer: C.III only
Explanation: When x is divided by y, the quotient is 3 and the remainder is z: x=3y+z, where 0≤z<y (the remainder must be less than the divisor).
When z is divided by y, the remainder is 2: when divisor (y in our case) is more than dividend (z in our case), then the reminder equals to the dividend (for example, 2 divided by 5 gives the remainder of 2). Therefore, z=2 and 2<y.
So, we have that x=3y+2 and 2<y. This implies that the least value of x is x=3∗3+2=11: x cannot be 5 or 8.
Could x be 32? Yes. If y=10, then x=3∗10+2=32.
Answer: C.
Question: The C.P of 15 books is equal to the S.P of 18 books. Find his gain% or loss%?
A.16 2/3% loss
B.16 2/9% loss
C.16 2/2% loss
D.16 2/3% loss
Answer: A.16 2/3% loss
Explanation: 15 CP = 18 SP
18 --- 3 CP loss
100 --- ? => 16 2/3% loss
Answer: A