RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The average speed of a car decreased by 3 miles per hour every successive 8-minutes interval. If the car traveled 3.6 miles in the sixth 8-minute interval, what was the average speed of the car, in miles per hour, in the first 8 minute interval?
A.30
B.34
C.38
D.42
Answer: D.42
Explanation: (3.6 miles / 8 minutes)*60 minutes/hour = 27 mph
Let x be the original speed.
x - 5(3) = 27
x = 42 mph
The answer is D.
Question: Working at constant rate, pump X pumped out half of the water in a flooded basement in 5 hours. The pump Y was started and the two pumps, working independently at their respective constant rates, pumped out rest of the water in 3 hours. How many hours would it have taken pump Y , operating alone at its own constant rate, to pump out all of the water that was pumped out of the basement?
A.a. 10
B.b. 12
C.c. 14
D.d. 26
Answer: D.d. 26
Explanation: rate of x=1/8
rate of x+y=1/6
rate of y=1/6-1/8=1/24
26 hours
D
Question: In a 200 metres race A beats B by 35 m or 7 seconds. A's time over the course is:
A.40 sec
B.47 sec
C.33 sec
D.35 sec
Answer: C.33 sec
Explanation: speed of B=s2.
A's time of course=t.
200=s2*(t+7) ---(eq 1)
200-35=s2*t ---(eq 2)
from these 2 eqs, we get t=33sec.
ANSWER:C
Question: Six children — A, B, C, D, E and F— are going to sit in six chairs in a row. The children B & F have to sit next to each other, and the others can sit in any order in any remaining chairs. How many possible configurations are there for the children?
A.240
B.720
C.1440
D.4320
Answer: A.240
Explanation: for such questions , we can treat both as one then total person=5.
these 5 can be arranged in 5! ways.. but within these 5 , one consists of two people who can be arranged in 2 ways BF or FB.. so ans =5!*2=240
ans A
Question: 220% of a number X is 44. What is 44% of X.
A.8.8
B.8.9
C.6.6
D.7.7
Answer: A.8.8
Explanation: Solution: Given,
220% of X = 44
Or, X = 20.
Thus,
44% of 20
= (44 *20) /100
= 8.8
Answer: Option A
Question: A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning?
A.39
B.42
C.58
D.62
Answer: A.39
Explanation: Let the average after 7th inning = x
Then average after 16th inning = x - 3
therefore 16(x-3)+87 = 17x
therefore x = 87 - 48 = 39
Answer A
Question: Two trains, each 100 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is?
A. 30 km/hr B. 45 km/hr
A.11
B.78
C.60
D.28
Answer: C.60
Explanation: Let the speed of the slower train be x m/sec.
Then, speed of the train = 2x m/sec.
Relative speed = ( x + 2x) = 3x m/sec.
(100 + 100)/8 = 3x => x = 25/3.
So, speed of the faster train = 50/3 = 50/3 * 18/5 = 60 km/hr.Answer: C
Question: If a is an integer greater than 8 but less than 15 and b is an integer greater than 6 but less than 21, what is the range of a/b?
A.140/217
B.156/185
C.217/140
D.263/149
Answer: C.217/140
Explanation: The way to approach this problem is 8<a<15 and 6<b<21
Minimum possible value of a is 9 and maximum is 14
Minimum possible value of b is 7 and maximum is 20
Range = max a/min b - min a/max b
(Highest - lowest)
14/7 - 9/20 = 217/140
Hence C
Question: sale of Rs 6835, Rs. 9927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6900 ?
A.4966
B.6477
C.7391
D.2676
Answer: C.7391
Explanation: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6900 x 6) - 34009]
= Rs. (41400 - 34009)
= Rs. 7391
Answer: C
Question: If x and t are integers and 2x–t= 11, then 4x+ t CANNOT be
A. –5
B. 1
C. 13
D. 17
Answer: D. 17
Explanation: 2x-t=11....t=2x-11
4x+t=4x+2x-11=6x-11
6x-11=-5...x=1
6x-11=1... x=2
6x-11=13...x=4
6x-11=17..X is not integer
6x-11=551..X is not integer
I think the choice E is 55 not 551. Otherwise both DE CANNOT be solution=D
Question: Find the unknown term 8,8,X,2,-4, -12
A.2
B.4
C.6
D.8
Answer: C.6
Explanation: 8,8,X,2,-4, -12
i guess each differ in d range of 2
8 - 8 = 0
8 - 6 = 2
6 - 2 = 4
2 - 6 = -4
-4 - 8 = -12
ANSWER:C
Question: Diana is painting statues. She has 7/8 of a gallon of paint remaining. Each statue requires 1/8 gallon of paint. How many statues can she paint?
A.7
B.20
C.28
D.14
Answer: A.7
Explanation: number of statues=all the paint÷amount used per statue
=7/8 ÷ 1/8
=7/8*8/1
=7/1
=7
Answer is A.
Question: Natasha climbs up a hill, and descends along the same way she went up. It takes her 4 hours to reach the top and 2 hours to come back down. If her average speed along the whole journey is 3.5 kilometers per hour, what was her average speed (in kilometers per hour) while climbing to the top?
A.2.125
B.2.375
C.2.625
D.2.675
Answer: C.2.625
Explanation: Let the distance to the top be x, so the total distance traveled by Natasha is 2x.
The total time is 4 + 2 = 6 hours
The average speed = total distance/total time taken = 2x/6 = x/3
The average speed of the complete journey is 3.5 km/hour
x/3 = 3.5
x = 10.5 km
The average speed while climbing = distance/time = 10.5/4 = 2.625 km/h
The answer is C.
Question: A sports retailer ordered white and yellow tennis balls in equal number but the dispatch clerk of the tennis ball company erred and dispatched 50 extra yellow balls and making ratio of white balls to yellow balls 8/15. How many tennis balls did the retailer order originally.
A.110
B.114.28
C.140
D.160
Answer: B.114.28
Explanation: White:Yellow = x:(x+50) = 8:15 --> 15x = 8x + 400 --> x = 57.14.
The total # of balls originally x + x = 57.14 + 57.14 = 114.28.
Answer: B.
Question: Ramesh has X rupees, on Monday beginning of the month. On every Monday his mother gives 10 rupees as pocket money. He spends half of what he had during that week on the 4th Monday of the month, when his mother gave his pocket Monday, he had 27 1/2 rupees . What was the Money he had in the beginning.
A.Rs.50
B.Rs.90
C.Rs.80
D.Rs.70
Answer: D.Rs.70
Explanation: on the 2nd Monday he will have 80. so he spends 40 and remaining is 40. the next Monday he will have 50. he spends 25 and remaining is 25. so on the 4th Monday he will have 35. he will spent half of it so remaining is 27 1/2.
ANSWER:D
Question: The center of a circle is (4, -2). (4, 7) is outside the circle, and (1, -2) is inside the circle. If the radius, r, is an
integer, how many possible values are there for r?
A. 4
B. 2
C. 1
D. 10
Answer: A. 4
Explanation: r must be greater than 3 and smaller than 9, hence r=4,5,6,7 or 8.
Answer A
Question: 4000 was divided into two parts such a way that when first part was invested at 3% and the second at 5%, the whole annual interest from both the investments is Rs.144, how much was put at 3%?
A.3377
B.2678
C.2800
D.2786
Answer: C.2800
Explanation: (x*3*1)/100 + [(4000 - x)*5*1]/100 = 144
3x/100 + 200 – 5x/100 = 144
2x/100 = 56 è x = 2800'
Answer: C
Question: Of the 17,210 employees of the anvil factory, 2/7 are journeymen. If half of the journeymen were laid off, what percentage of the total remaining employees would be journeymen?
A. 14.3%
B. 16.67%
C. 33%
D. 28.6%
Answer: D. 28.6%
Explanation: The exam gives us a number that is easily divisible by 7 to pique our curiosity and tempt us into calculating actual numbers (also because otherwise the ratio would be incorrect). Since the question is about percentages, the actual numbers will be meaningless, as only the ratio of that number versus others will be meaningful. Nonetheless, for those who are curious, each 1/7 portion represents (14210/7) 2,030 employees. This in turn means that 4,060 employees are journeymen and the remaining 10,150 are full time workers.
If half the journeymen were laid off, that would mean 1/7 of the total current workforce would be removed. This statistic is what leads many students to think that since half the journeymen are left, the remaining journeymen would represent half of what they used to be, which means 1/7 of the total workforce. If 1/7 of the workforce is journeymen, and 1/7 is roughly 14.3%, then answer choice A should be the right answer. In this case, though, it is merely the tempting trap answer choice.
What changed between the initial statement and the final tally? Well, you let go of 1/7 of the workforce, so the total number of workers went down. The remaining workers are still 1/7 of the initial workers, but the group has changed. The new workforce is smaller than the original group, specifically 6/7 of it because 1/7 was eliminated. The remaining workers now account for 1/7 out of 6/7 of the force, which if we multiply by 7 gives us 1 out of 6. This number as a percentage is answer choice B, 28.6%.
Using the absolute numbers we calculated before, there were 4,060 journeymen employees out of 14,210 total. If 2,030 of them are laid off, then there are 2,030 journeyman employees left, but now out of a total of (14,210-2,030) 12,180 employees. 2,030/12,180 is exactly 1/6, or 16.67%. The answer will work with either percentages or absolute numbers, but the percentage calculation will be significantly faster and applicable to any similar situation.
The underlying principle of percentages (and, on a related note, ratios) can be summed up in the brainteaser I like to ask my students: If you’re running a race and you overtake the 2nd place runner just before the end, what position do you end up in?
The correct answer is 2nd place.
Percentages, like ratios and other concepts of relative math, depend entirely on the context. Whether 100% more of something is better than 50% more of something else depends on the context much more than the percentages quoted. When it comes to percentages on the GMAT, the goal is to understand them enough to instinctively not fall into the traps laid out for you.
D
Question: How many 8's are present in the following sequence of numbers which are exactly divisible by both its preceding and following numbers ?
A.Less than 4
B.Less than 7
C.Less than 90
D.Less than 6
Answer: A.Less than 4
Explanation: Explanation:
3 8 6 8 8 7 6 8 3 4 8 2 5 6 2 8 2 4 8 6 3 7 4 8 4 5 8 4
We want a group of 3 numbers with “8” at the centre such that it would be exactly divisible by both its preceding and following numbers. There are 3 such groups. (See the underlined groups above).
ANSWER: A
Question: CONVERT 2.3 hectares in ares
A.130 ares.
B.160 ares.
C.180 ares.
D.230 ares.
Answer: D.230 ares.
Explanation: 2.3 hectares in ares
1 hectare = 100 ares
Therefore, 2.3 hectares = 2.3 × 100 ares
= 230 ares.
ANSWER- D
Question: A garrison of 400 men had a provision for 31 days. After 28 days 280 persons re-enforcement leave the garrison. Find the number of days for which the remaining ration will be sufficient?
A.10
B.88
C.77
D.51
Answer: C.77
Explanation: 400 --- 31
400 --- 3
120 --- ?
400*3 = 120*x => x =10 days
Answer: C
Question: A sum of money deposited at C.I. amounts to Rs.5000 in 5 years and to Rs.5750 in 6 years. Find the rate percent?
A.1%
B.5%
C.10%
D.15%
Answer: D.15%
Explanation: 5000 --- 750
100 --- ? => 15%
Answer: D
Question: With a uniform speed a car covers the distance in 8 hours. Had the speed been increased by 6 km/hr, the same distance could have been covered in 7 1/2 hours. What is the distance covered?
A.187 km
B.480 km
C.720 km
D.297 km
Answer: C.720 km
Explanation: Let the distance be x km. Then,
x/(7 1/2) - x/8 = 6
2x/15 - x/8 = 6 => x = 720 km.
Answer:C
Question: At Company K, 15 percent of the employees are secretaries and 60 percent are salespeople. If there are 50 other employees of Company K, how many employees does Company K have?
A. 160
B. 180
C. 190
D. 200
Answer: D. 200
Explanation: Let the total number of employees in the company be x
% of secretaries = 15%
% of salespeople = 60%
% of of employees other than secretaries and salespeople = 100 - 75 = 25%
But this number is given as 50
so 25% of x = 50
x = 200
Therefore there a total of 200 employees in the company K
Correct answer - D
Question: If (0.2)x = 2 and log 2 = 0.3010, then the value of x to the nearest tenth is:
A.-0.5
B.-0.2
C.-0.4
D.10.0
Answer: C.-0.4
Explanation: (0.2)x = 2.
Taking log on both sides
log (0.2)x = log 2.
x log (0.2) = 0.3010, [since log 2 = 0.3010].
x log (2/10) = 0.3010.
x [log 2 - log 10] = 0.3010.
x [log 2 - 1] = 0.3010,[since log 10=1].
x [0.3010 -1] = 0.3010, [since log 2 = 0.3010].
x[-0.699] = 0.3010.
x = 0.3010/-0.699.
x = -0.4306….
x = -0.4 (nearest tenth)
Question: If x and y are positive integers, which of the following CANNOT be the greatest common divisor of 35x and 20y?
A.5
B.5(x-y)
C.20x
D.20y
Answer: C.20x
Explanation: We are looking for a choice that CANNOT be the greatest common divisor of 35x and 20y ...which means 35x and 20y when divided by the answer choice the quotient should not be a integer.
lets check
a. 5 35x/5 = 7x and 20y/5 = 4y both are integers so eliminate
b. 5(x-y) when x = 2 and y = 1 it could be be the greatest common divisor ..so eliminate
c. 20x when x = 1 its 20 and 20 cannot be the greatest common divisor of 35x and 20y ...
or 35x/20x = 7/4 which is not a integer.
so answer is C.
Question: Two pipes A and B can separately fill a cistern in 20 min and 30 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 60 min. In how much time, the third pipe alone can empty the cistern?
A.16 min
B.20 min
C.25 min
D.15 min
Answer: D.15 min
Explanation: Work done by the third pipe in 1 min = 1/60 - (1/20 + 1/30) = - 1/15.
[-ve sign means emptying]
The third pipe alone can empty the cistern in 15 min.
ANSWER:D
Question: If ROSE is coded as 6821, CHAIR is coded as 73456 and PREACH is coded as 961473, what will be the code for SEARCH ?
A.233999
B.214673
C.277899
D.288889
Answer: B.214673
Explanation: Explanation:
The alphabets are coded as shown :
{\color{Blue} \begin{matrix} R & O & S & E & C& H & A & I & P\\ 6& 8& 2& 1& 7 & 3 & 4 & 5 & 9 \end{matrix}}
So, in SEARCH,
S ia coded as 2,
E as 1,
A as 4,
R as 6,
C as 7,
H as 3.
Thus, the code for SEARCH is 214673
Answer: B) 214673
Question: A new home buyer pays 4% annual interest on her first mortgage and 9% annual interest on her second mortgage. If she borrowed a total of $335,000, 80% of which was in the first mortgage, what is her approximate monthly interest payment?
A.$1,395
B.$1,733
C.$3,466
D.$13,333
Answer: A.$1,395
Explanation: 0.04x + 0.09y = 335000 [1]
0.04x = 0.80 * 335000 = 268000 [2]
268000 + 0.09y = 320000 --> 0.09y = 67000 [3]
268000 / 12 = 22333.3333 [4]
67000 / 12 = 5583.333 [5]
Adding [4,5] we get: 27916 [6]
Dividing [6] / 2 to get an average we get 1.395,ANS A
Question: A toy shop sells 4 types of dolls (doll A,B,C,D). If:
I) doll B cost 10% less than doll A
II) doll C cost 17% less than doll B
III) doll D cost 18% less than doll C
what percent of doll A 's cost is doll D?
A.25%
B.75.2%
C.60.2%
D.67.2%
Answer: D.67.2%
Explanation: Let the cost of doll A be $100
I) doll B cost 10% less than doll A--100-10=90
II) doll C cost 17% less than doll B--90-15.3=74.7
III) brand D cost 10% less than brand C--74.7-7.47=67.23
what percent of brand B's cost is brand D=67.23*100/100
Answer is D
Question: What is the square root of 144, divided by 6?
A.9
B.36
C.2
D.6
Answer: C.2
Explanation: Square root is a number times itself
Square root of 144=12, 12/6=2
(C)2
Question: Which of the following reaches the largest value over the range -1 <= R <= 1?
A.R+1
B.R+2
C.(R)^2
D.(R-1)^2
Answer: D.(R-1)^2
Explanation: Evaluate all of the expressions:
R+1 has a maximum value of 2, at R=1
R+2 has a maximum value of 3, at R=1
R^2 has a maximum value of 1, at R=+/-1
(R-1)^2 has a maximum value of 4, at R= -1
R^3 has a maximum value of 1, at R=1
Therefore, the answer is D
Question: If Albert’s monthly earnings rise by 14%, he would earn $678. If, instead, his earnings rise by only 15%, how much (in $) would he earn this month?
A.643
B.689
C.683
D.690
Answer: C.683
Explanation: =678/1.14∗1.15
=683=683
Answer is C
Question: Alice and Bob drive at constant speeds toward each other on a highway. Alice drives at a constant speed of 30 km per hour. At a certain time they pass by each other, and then keep driving away from each other, maintaining their constant speeds. If Alice is 100 km away from Bob at 7 am, and also 100 km away from Bob at 11 am, then how fast is Bob driving (in kilometers per hour)?
A.20
B.24
C.28
D.32
Answer: A.20
Explanation: Alice and Bob complete 200 km / 4 hours = 50 km/hour
Bob's speed is 50-30=20 km/hour
The answer is A.
Question: If the mode of Set R is equal to the median of Set R, Set R could be
A.[0, 1, 2, 2, 3, 4, 5, 6]
B.[2, 2, 5, 7, 9]
C.[x, x+1, x+2, x+2, x+3, x+3]
D.[10, 102, 105, 105]
Answer: C.[x, x+1, x+2, x+2, x+3, x+3]
Explanation: Correct Answer: (C)
Set R could be The mode is the most common number; the median is the middle number when the numbers are arranged from least to greatest. Any number plus an integer value is greater than the original number, so x + 1 is greater than x, x + 2 is greater than x + 1, etc., so set (C) is arranged from least to greatest. Its median is the average of (x+2) and (x+2), which must be (x+2). (x+2) is also the most common number, so the mode of set C is equal to the median of set C.
Question: Ritesh and Co. generated revenue of Rs. 1,700 in 2006. This was 12.5% of its gross revenue. In 2007, the gross revenue grew by Rs. 2,500. What is the percentage increase in the revenue in 2007?
A.18.38%
B.20%
C.25%
D.50%
Answer: A.18.38%
Explanation: Explanation :
Given, Ritesh and Co. generated revenue of Rs. 1,700 in 2006 and that this was 12.5% of the gross revenue.
Hence, if 1700 is 12.5% of the revenue, then 100% (gross revenue) is:
=>(100/12.5)×1700.
=>13,600.
Hence, the total revenue by end of 2007 is Rs. 13,600. In 2006, revenue grew by Rs. 2500. This is a growth of:
=>(2500/13600)×100.
=>18.38%.
Answer : A
Question: The number 0.127 is how much greater than 1/8 ?
A.½
B.2/10
C.1/50
D.1/500
Answer: D.1/500
Explanation: let x be the difference
then
.127-1/8=x
127/1000-1/8=x
127-125/1000=x
2/1000=x
x=1/500
ANSWER:D
Question: For a,w,d are the positive integers, and d|a means that “a is divisible by d”, if d|aw, which of the following must be true?
A.d|a
B.d|w
C.d|2aw
D.d|(a+w)
Answer: C.d|2aw
Explanation: d/a means a is divisible by d
d/aw means ab divisible by d.
all are integers so ,
if aw is divisible by d,
1 a can be divisible by d
or
2 w can be divisble by d.
so the question stem asks must true.
so option a and b are could but not must.
option c is 2aw divisible by d. if ab is divisible by d then 2aw is divisible by d.
option d and e we can't predict.
so option C is correct.
Question: How long will a boy take to run round a square field of side 60 meters, if he runs at the rate of 12km/hr?
A.52sec
B.45sec
C.72sec
D.25sec
Answer: C.72sec
Explanation: Speed = 12 km/hr = 12*5/18 = 10/3 m/sec
Distance = 60*4 = 240m
Time taken = 240*3/10 = 72sec
Answer is C
Question: Two pipes P and Q can fill a cistern in 12 and 18 minutes respectively. Both are opened together, but at the end of 3 minutes the first is turned off. How much longer will the cistern take to fill?
A.13 1/2 min
B.11 1/4 min
C.11 2/4 min
D.11 1/5 min
Answer: A.13 1/2 min
Explanation: 3/12 + x/18 = 1
x= 13 1/2
Answer: A
Question: 6 water pipes have an average length of 80 cm. If the average length of one third of the pipes is 70 cm, what is the average of the other pipes?
A.75.
B.85.
C.90.
D.94.
Answer: B.85.
Explanation: Edit:
Given ( X1 + X2 ... + X6 ) / 6 = 80
( X1 + X2 ... + X6 ) = 480 --> Eq 1.
Now given avg length of one third pipes is 70. That means out 6 / 3 = 2 pipes.
let the avg length of two pipes be ( X1 + X2 ) / 2 = 70 .
( X1 + X2 ) = 140. --> eq 2.
Now we are asked to find the average of the remaining i.e. ( X3 + X4 + X5 + X6 )
Substitute eq 2 in eq 1 then we get
140 + X3 + X4 + X5 + X6 = 480
=> X3 + X4 + X5 + X6 = 340
Now divide 340 by 4 we get 85.
=> ( X3 + X4 + X5 + X6) / 4 = 85 = avg length of remaining pipes.
IMO correct option is B.
Question: which of the following is exactly in the middle between 3 and 1 in below arrangement?
P R E 5 D A P $ 3 T I Q 7 9 B # 2 K % U 1 M W 4 * J 8 N
A.7
B.8
C.9
D.6
Answer: C.9
Explanation: 9. ITS THE 6TH LETTER FROM BOTH THE SIDE
ANSWER:C
Question: If two letters are chosen at random (without replacement) from the word JUPITER, what is the probability that none of the letters are vowels?
A.1/7
B.2/7
C.3/14
D.5/14
Answer: B.2/7
Explanation: The number of ways to choose two letters is 7C2 = 21
The number of ways to choose two consonants is 4C2 = 6.
P(no vowels) = 6/21 = 2/7
The answer is B.
Question: The average age of A and B is 13 years. If C were to replace A, the average would be 24 and if C were to replace B, the average would be 36. What are the age of A, B and C?
A.22, 18, 20
B.20, 20, 18
C.24, 0, 48
D.25, 01, 47
Answer: D.25, 01, 47
Explanation: Given A + B = 26â€¦(i)
C + B = 48 â€¦ (ii)
A + C = 72â€¦(iii)
(i) + (ii) + (iii) â‡’ A + B + C = 73â€¦(iv)
from (i) and (iv), we get
C = 47 years
âˆ´ B = 1 years and A = 25years
Answer D
Question: Given f(x) = 3x – 5, for what value of x does 2*[f(x)] – 4 = f(3x – 6)
A.3
B.4
C.6
D.7
Answer: A.3
Explanation: Answer = A = 3
f(x) = 3x – 5
2*[f(x)] – 4 = f(3x – 6)
2(3x-5) -4 = 3 (3x-6) - 5
6x - 14 = 9x - 23
x = 3
Question: Two cars of length 120 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?
A.10 sec
B.30 sec
C.40 sec
D.20 s
Answer: D.20 s
Explanation: D
Relative speed = (42 + 30) * 5/18 = 4 * 5 = 20 mps.
Distance covered in passing each other = 120 + 280 = 400 m.
The time required = d/s = 400/20 = 20 s.
Question: Faiza has 6 purses, she gives 3 purse as gift. Now how many purse did she have ?
A.2
B.3
C.11
D.9
Answer: B.3
Explanation: 6-3=3. Answer is B
Question: If x and y are positive integers such that (3x + 7y ) is a multiple of 11, then which of the following will also be divided by 11?
A.4x + 6y
B.x + y + 4
C.9x + 4y
D.4x - 9y
Answer: D.4x - 9y
Explanation: Keeping y =1, for x = 5, we have
3x + 7y =22
which is divisible by 11.
Now, substitute x =5 and y =1 in each alternative and find out
which expression becomes a multiple of 11?
Now, 4x + 6y = 4 x 5 + 6 = 26
x + y + 4 = 5 + 1 + 4 = 10
9x + 4y = 9 x 5 + 4 = 49
4x - 9y = 4 x 5 -9 = 20 -9 =11
which is divisible by 11
ANSWER:D
Question: What is the perimeter of a regular polygon with sides of length 15 cm and internal angles measuring 120° each?
A.90 cm
B.108 cm
C.120 cm
D.132 cm
Answer: A.90 cm
Explanation: Sum of all interior angles is given by:
180(n-2) = n is number of sides
180(n-2) = 120*n
from here
n = 6
So perimeter becomes 15*6 = 90
answer A
Question: Express a speed of 36 kmph in meters per second?
A.62kmp
B.73kmp
C.10kmp
D.37kmp
Answer: C.10kmp
Explanation: Answer:C
Question: A 270 metres long bullet train running at the speed of 120 kmph crosses another bullet train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other bullet train ?
A.226
B.230
C.430
D.310
Answer: B.230
Explanation: B
230
Relative speed = (120 + 80) km/hr
= 200 x 5/18
= 500/9 m/sec
Then, (x+270)/9 = 500/9
--> x + 270 = 500
--> x = 230.
Question: If a particular is never chosen, in how many ways can a cricketbe chosen out of 15 players?
A.234
B.254
C.364
D.389
Answer: C.364
Explanation: A particular players is never chosen, it means that 11 players are selected out of 14 players.
=> Required number of ways = 14C11
= 14!/11!x3! = 364
C
Question: If average of two positive number is 2 initially and one number is replaced then the average became twice the initial average. What is number replace.
A.1
B.2
C.3
D.6
Answer: A.1
Explanation: Since the average is 2 which gives (x+y)/2 = 2. X+Y = 4
the numbers must be 1+3 so if you replace 1 by 5 then average becomes 4
Answer: 1
Question: In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 10 percent of revenues. The profits in 2009 were what percent of the profits in 2008?
A.105%
B.80%
C.120%
D.124.2%
Answer: B.80%
Explanation: the profit 0f 2009 in terms of 2008 = (0.8*10/10)*100=80%
B