RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A pump can fill a tank with a water in 2 hours. Because of a leak, it took 6 hours to fill the tank. The leak can drain all the water of the full tank in how many hours?
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: The rate of the pump + leak = 1/6
1/2 - leak's rate = 1/6
leak's rate = 1/2 - 1/6 = 1/3
The leak will empty the tank in 3 hours.
The answer is B.
Question: A toy store sells small, medium, large, and super-large toy trucks in each of the colors red, blue, black, green, orange, pink, and yellow. The store has an equal number of trucks of each possible color-size combination. If Paul wants a medium, red truck and his mother will randomly select one the trucks in the store, what is the probability that the truck she selects will have at least one of the two features Paul wants?
A.3/7
B.4/7
C.3/14
D.5/14
Answer: D.5/14
Explanation: Probability of NOT selecting medium out of 4 sizes = 3/4
Probability of NOT selecting red out of 7 colours = 6/7
Total probability of NOT selecting red and medium = (3/4)*(6/7) = 9/14
Required probability = 1 - 9/14 (this will select at least one of red and medium)
= 5/14
The answer is D.
Question: In how many ways can nine different rings be worn on four fingers of one hand?
A.10
B.129
C.135
D.126
Answer: D.126
Explanation: Required number of ways = ways of selecting 4 objects out of 9 given objects
= 9C4 = 9*8*7*6/24= 126
Answer D
Question: If 5x+2y=3x-4y,then what equation will arise?
A.x=-y
B.y=-x
C.A and B
D.x=y
Answer: D.x=y
Explanation: 5x+2y=3x-4y
5x-3x=4y-2y
2x=2y
x=y
Option:D
Question: United Telephone charges a base rate of $11.00 for service, plus an additional charge of $0.25 per minute. Atlantic Call charges a base rate of $12.00 for service, plus an additional charge of $0.20 per minute. For what number of minutes would the bills for each telephone company be the same?
A.2 minutes
B.10 minutes
C.20 minutes
D.40 minutes
Answer: C.20 minutes
Explanation: Lets take number of minutesx.
Given that, 11+0.25x=12+0.2x ->0.05x=2 -> x=20minutes
ANS C
Question: In a colony of 70 residents, the ratio of the number of men and women is 3 : 4. Among the women, the ratio of the educated to the uneducated is 1 : 4. If the ratio of the number of educated to uneducated persons is 8 : 27, then find the ratio of the number of educated to uneducated men in the colony?
A.A)1:6
B.B)1:2
C.C)1:8
D.D)1:9
Answer: B.B)1:2
Explanation: Number of men in the colony = 3/7 * 70 = 30.
Number of women in the colony = 47 * 70 = 40.
Number educated women in the colony = 1/5 * 30 = 6.
Number of uneducated women in the colony = 4/5 * 50 = 24.
Number of educated persons in the colony = 8 /35 * 70 = 16.
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 30 - 10 = 20.
Number of educated men and uneducated men are in the ratio 10 : 20 i.e., 1:2.
Answer:B
Question: Of the 400 members at a health club, 280 use the weight room and 300 use the pool. If at least 60 of the members do not use either, then the number of members using both the weight room and the pool must be between:
A.200 to 260
B.240 to 280
C.220 to 260
D.220 to 300
Answer: B.240 to 280
Explanation: W=280
P=300
ALL=400
N(NEITHER)=AT LEAST 60
BOTH=?
W+P-BOTH+N=ALL
280+300-BOTH+60=400
BOTH=240
now pay attention to the fact, that both at most can be 280, since W=280
B
Question: A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
A.14 years
B.18 years
C.20years
D.22 years
Answer: D.22 years
Explanation: Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
ANSWER:D
Question: Two train 200 m and 150 m long are running on parallel rails at the rate of 40 kmph and 45 kmph respectively. In how much time will they cross each other, if they are running in the same direction?
A.80 sec
B.252 sec
C.320 sec
D.330 sec
Answer: B.252 sec
Explanation: Sol.
Relative speed = (45 - 40) kmph = 5 kmph = [5 * 5/18] m/sec = 25/18 m/sec.
Total distance covered = Sum of lengths of trains = 350 m.
∴ Time taken = [350 * 18/25] sec = 252 sec.
Answer B
Question: 85% of the population of a city is 85000. The total population of the city is?
A.95000
B.97500
C.100000
D.105000
Answer: C.100000
Explanation: X * (85/100) = 85000
X = 1000 * 100
X = 100000
Answer: C
Question: 2,200 has how many positive divisors?
A.12
B.16
C.20
D.24
Answer: D.24
Explanation: By factorization, we can write 2200 as 2200=2^3*5^2*11.
The number of factors is (3+1)(2+1)(1+1) = 24
The answer is D.
Question: At exactly what time past 6:00 will the minute and hour hands of an accurate working clock be precisely perpendicular to each other for the first time?
A.20 13/21 minutes past 7:00
B.20 13/17 minutes past 7:00
C.21 9/11 minutes past 6:00
D.21 9/11 minutes past 7:00
Answer: C.21 9/11 minutes past 6:00
Explanation: 5.5 is the angle between minute n hour, this is what I was taught...so shouldn't it be solve by dividing 90 with 5.5?
That would have been the case if your initial difference between the hour and the minute hand was = 0 degrees or in other words, both minute and hour hands were at the same location. But as per the question, you are asked for time AFTER 6:00. At 6:00, the angle between the hour and the minute hand is 210 degrees. you need to take this into account as well.
So in order for the difference to decrease to 90 degrees, the minute hand must eat away this difference of 210-90 = 120 degree at the rate of 5.5 degrees per minute ---> 120/5.5 = 21 9/11 minutes.
Thus, C is the correct answer.
Question: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
A.87 Kmph
B.68 Kmph
C.67 Kmph
D.57 Kmph
Answer: B.68 Kmph
Explanation: Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X - 48 = 180
1000/x - 48 * 5/18 = 180
50 = 9X - 120
X = 68 Kmph
Answer: B
Question: What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 5?
A.897
B.98,910
C.64,749
D.49,700
Answer: B.98,910
Explanation: Find the number , Upon Sum of 3 Digits of a number Gives a Reminder 2 when it is Divided by 5
Seeing the Options After Dividing and Finding the Reminder of 2
My Answer was B
Question: Sam invested $15000 @10% per annum for one year. If the interest is compounded half yearly, then the amount received by Sam at the end of the year will be?
A.$16537.50
B.$24512.56
C.$18475.89
D.$15478.56
Answer: A.$16537.50
Explanation: P = $15000
R = 10%
p.a. = 5%
T = 2 half years
Amount = 15000 * (1 + 5/100)^2 = 15000* 21/20 * 21/20 = $16537.50
Answer is A
Question: Two trains of equal lengths take 10 sec and 12 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
A.11 sec
B.12 sec
C.17 sec
D.21 sec
Answer: A.11 sec
Explanation: Speed of the first train = 120/10 = 12 m/sec.
Speed of the second train = 120/12 = 10 m/sec.
Relative speed = 12 + 10 = 22 m/sec.
Required time = (120 + 120)/22 = 11 sec.
Answer: A
Question: Find how many positive integers less than 10,000 are there suchthat the sum of the digits of the no. is divisible by 3?
A.1256
B.2354
C.2678
D.3334
Answer: D.3334
Explanation: If sum of the digits is divisible by 3, the number is divisible by 3.
Therefore, required number of non-negative integers is equal to count of numbers less than 10,000 which are divisible by 3.
Such numbers are (3, 6, 9, ... , 9999) (arithmetic progression with first term=3, last term=9999, common difference=3).
Count of such numbers =
9999
3
=
3333
99993=3333
But zero is also divisible by 3.
This makes our total count 3334
D
Question: On eight consecutive flips of a coin, what is the probability that all eight produce the same result?
A.1/16
B.1/128
C.1/8
D.1/4
Answer: B.1/128
Explanation: TTTTTTTT case --> P = (1/2)^8 = 1/256
HHHHHHHH case --> P = (1/2)^8 = 1/256
P(TTTTTTTT or HHHHHHHH) = 1/8 + 1/8 = 1/128
Answer: B
Question: Pradeep has to obtain 20% of the total marks to pass. He got 390 marks and failed by 25 marks. The maximum marks are
A.300
B.2075
C.800
D.1000
Answer: B.2075
Explanation: Explanation :
Let their maximum marks be x.
Then, 20% of x = 390 + 25
=>20/100x= 415
x = (41500/20)
x= 2075.
Answer : B
Question: Which of the following is a prime number ?
A.65
B.35
C.97
D.35
Answer: C.97
Explanation: C
97
Explanation: Clearly, 97 is a prime number.
Question: The population of a town increased from 1,33,400 to 1,93,500 in a decade. The average percent increase of population per year is:
A.4.5%
B.5.5%
C.6.5%
D.8.75%
Answer: A.4.5%
Explanation: Explanation: Increase in 10 years = (193500 - 133400) = 60100.
Increase% = (60100/133400 x 100)% = 45%.
Required average = (45/10)% = 4.5%.
Answer: Option A
Question: Ratio between Rahul and Deepak is 4:3, After 22 Years Rahul age will be 26 years. What is Deepak present age
A.10
B.3
C.5
D.7
Answer: B.3
Explanation: Explanation:
Present age is 4x and 3x,
=> 4x + 22 = 26 => x = 1
So Deepak age is = 3(1) = 3
Answer: Option B
Question: 75 people are being divided into committees. However, the project calls for 9 teams of 9 people each. How many more people are needed to reach this quota?
A.6
B.8
C.19
D.10
Answer: A.6
Explanation: 9 x 9 = 81
81 - 75 = 6
The answer is A.
Question: Due to construction, the speed limit along an 7-mile section of highway is reduced from 55 miles per hour to 35 miles per hour. Approximately how many minutes more will it take to travel along this section of highway at the new speed limit than it would have taken at the old speed limit ?
A. 2
B. 3
C. 4
D. 5
Answer: C. 4
Explanation: 7/35 - 7/55 = 7/5 * ( 11 - 7)/77
= 7/5 * 4/77 * 60 min
= 7 * 12 * 4/77
= 336/77 ~ 4.3
Answer - C
Question: The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:10. If P invested the money for 2 months, find for how much time did Q invest the money?
A.8
B.10
C.18
D.4
Answer: D.4
Explanation: 7*5: 2*x = 7:10
x = 4
Answer:4
Answer is D
Question: Ram sold two bicycles, each for Rs.990. If he made 10% profit on the first and 10% loss on the second, what is the total cost of both bicycles?
A.Rs.2000
B.Rs.1980
C.Rs.1891
D.Rs.1750
Answer: A.Rs.2000
Explanation: Explanation:
(10*10)/100 = 1%loss
100 --- 99
? --- 1980 => Rs.2000
ANSWER IS A
Question: The value of 99^(93/99) x 99 is:
A.9989
B.9896
C.9894
D.9809
Answer: C.9894
Explanation: (100 â€“ 6/99) x 99 = 9900 â€“ 6
= 9894.
ANSWER:C
Question: A man can do a piece of work in 6 days, but with the help of his son, he can do it in 3 days. In what time can the son do it alone?
A.5
B.7
C.6
D.8
Answer: C.6
Explanation: Son's 1day's work = (1/3)-(1/6) = 1/6
The son alone can do the work in 6 days
Answer is C
Question: In how many ways can the letters of the word REPEATED be arranged?
A.1206
B.1348
C.6720
D.3000
Answer: C.6720
Explanation: REPEATED has 8 words, but E is repeated three times. Thus ways = 8! / 3! = 6720 ways
C
Question: If the LCM of two integers I, J (where J> I and I>1) is I*J, then which of the following can not be true?
A.All Prime factors of I must be Prime factors of J.
B.Both I and J can be consecutive integers.
C.Both I and J can be Prime Numbers.
D.I and J do not share any Prime factors.
Answer: A.All Prime factors of I must be Prime factors of J.
Explanation: If LCM of two numbers I and J is the product IJ then both numbers are Co- prime.
(Co-prime numbers are any two numbers which have an HCF of 1 i.e. when two numbers have no common prime factor apart from the number 1).
Numbers that can be Co-Prime are :
1) Two consecutive natural numbers.
2) Two consecutive odd numbers.
3) Two prime numbers.
4) One prime number and the other a composite number such that the composite number is not a multiple of the prime number.
With above four statements it can be concluded that Options B,C,D and E are all true.
Only Option A cannot be true.
Hence answer is A
Question: Total of ages of A,B and C at present is 90 years. If ratio of this ages is 2 : 3 : 4 what will be the age of C after 6 years?
A.45 years
B.42 years
C.46 years
D.37 years
Answer: C.46 years
Explanation: 2+3+4=9
4*(90/9)=40yrs
after 6yrs=46
ANSWER:C
Question: In a colony of 70 residents, the ratio of the number of men and women is 5 : 2. Among the women, the ratio of the educated to the uneducated is 1 : 4. If the ratio of the number of educated to uneducated persons is 8 : 27, then find the ratio of the number of educated to uneducated men in the colony?
A.A)1:4
B.B)1:1
C.C)1:8
D.D)1:9
Answer: A.A)1:4
Explanation: Number of men in the colony = 5/7 * 70 = 50.
Number of women in the colony = 2/7 * 70 = 40.
Number educated women in the colony = 1/5 * 30 = 6.
Number of uneducated women in the colony = 4/5 * 50 = 24.
Number of educated persons in the colony = 8 /35 * 70 = 16.
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 50 - 10 = 40.
Number of educated men and uneducated men are in the ratio 10 : 40 i.e., 1:4.
Answer:A
Question: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 100 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
A. 280
B. 400
C. 540
D. 500
Answer: D. 500
Explanation: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month:
2/3*3/4 = 1/2 survived the first month.
Of the geese that survived the first month, 3/5 did not survive the first year:
(1-3/5)*1/2 = 1/5 survived the first year.
100 geese survived the first year:
1/5*(total) = 100 --> (total) = 500.
Answer: D.
Question: A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and
second half at the rate of 24 km/hr. Find the total journey in km
A.200 Km
B.222 Km
C.224 Km
D.248 Km
Answer: C.224 Km
Explanation: Explanation:
Let time taken to travel the first half = x hr
Then time taken to travel the second half = (10 - x) hr
Distance covered in the the first half = 21x [because, distance = time*speed]
Distance covered in the the second half = 24(10 - x)
Distance covered in the the first half = Distance covered in the the second half
So,
21x = 24(10 - x)
=> 45x = 240
=> x = 16/3
Total Distance = 2*21(16/3) = 224 Km [multiplied by 2 as 21x was distance of half way]
Answer: C
Question: A semicircle has a radius of 9. What is the approximate perimeter of the semicircle?
A.16
B.25
C.33
D.46
Answer: D.46
Explanation: The perimeter of a circle is 2*pi*r.
The perimeter of a semicircle is 2*pi*r/2 + 2r = pi*r + 2r
The perimeter is pi*9 + 2*9 which is about 46.
The answer is D.
Question: The probability of two events A and B are 0.20 and 0.40 respectively. The probability that both A and B occur is 0.15. The probability that neither A nor B occur is _________
A.0.45
B.0.4
C.0.5
D.0.55
Answer: D.0.55
Explanation: we are apply that formula..............
P(AorB)=P(A)+P(B)-P(A AND B)
=.20+.40-.15
=.45
but the probability of neither A nor B=1-.45
=0.55
ANSWER:D
Question: A can work four times as fast as B. Together they can finish a job in 12 days. In how many days can A complete the job alone?
A.14
B.15
C.16
D.17
Answer: B.15
Explanation: B's rate is x and A's rate is 4x.
x + 4x = 1/12
x = 1/60
A's rate is 4x = 1/15
A can complete the job in 15 days.
The answer is B.
Question: 100 identical coins each with probability 'pp' showing up heads & tossed.
A.13/101
B.11/101
C.51/101
D.53/102
Answer: C.51/101
Explanation: Let aa be the number of coins showing heads
Then, P(A=50)=P(A=51)P(A=50)=P(A=51)
⇒100C50×P50×(1−P)50⇒100C51×P51×(1−P)49⇒100C50×P51×(1−P)50=100C51×P⇒51(1âˆ′P)=50P⇒P=51/101
C
Question: If a#b = ab – b + b^2, then 3#4 =
A.2
B.8
C.15
D.24
Answer: D.24
Explanation: Solution -
Simply substitute 3 and 4 in equation in the place of a and b respectively.
3#4 = 3*4 - 4 + 4^2 = 12 - 4 + 16 = 24. ANS D
Question: How many different four letter words can be formed (the words need not be meaningful using the letters of the word "MEDITERRANEAN" such that the first letter is E and the last letter is R?
A.59
B.77
C.36
D.99
Answer: A.59
Explanation: Explanation:
The first letter is E and the last one is R.
Therefore, one has to find two more letters from the remaining 11 letters.
Of the 11 letters, there are 2 Ns, 2Es and 2As and one each of the remaining 5 letters.
The second and third positions can either have two different letters or have both the letters to be the same.
Case 1: When the two letters are different. One has to choose two different letters from the 8 available different choices. This can be done in 8 * 7 = 56 ways.
Case 2: When the two letters are same. There are 3 options - the three can be either Ns or Es or As. Therefore, 3 ways.
Total number of possibilities = 56 + 3 = 59
Answer: A) 59
Question: Find the value of 85P3 .
A.565350
B.595650
C.535950
D.565350
Answer: B.595650
Explanation: 85P3 = 85!/(85-3)!
= 85!/82!
= 85*84*83*82!/82!
= 85*84*83
= 595650
ANSWER:B
Question: A pet store regularly sells pet food at a discount of 10 percent to 30 percent from the manufacturer’s suggested retail price. If during a sale, the store discounts an additional 20 percent from the discount price, what would be the lowest possible price of a container of pet food that had a manufacturer’s suggested retail price o f $ 30.00?
A.$ 10.00
B.$ 11.20
C.$ 14.40
D.$ 16.80
Answer: D.$ 16.80
Explanation: For retail price = $30
First maximum discounted price = 30 - 30% of 30 = 30-9 = 21
Price after additional discount of 20% = 21 - 20% of 21 = 21 - 4.2 = 16.8
Answer: Option D
Question: If two different solutions of alcohol with a respective proportion of water to alcohol of 3:1 and 2:3 were combined, what is the concentration of alcohol in the new solution if the original solutions were mixed in equal amounts?
A.30.0%
B.36.6%
C.42.5%
D.44.4%
Answer: C.42.5%
Explanation: Alcohol: Water
First mixture -- 3:1 -- 15:5
Second mixture -- 2:3 -- 8:12
Equal amounts of the mixture were combined, hence the final mixture will be in the ratio -- (15+8): (5+12) -- 23:17
% of alcohol -- 17/(23+17) * 100
= (17/40) * 100
= 42.5
ANSWER:C
Question: How many prime numbers are between 25/8 and 213/6?
A.6
B.7
C.8
D.9
Answer: D.9
Explanation: 25/8 = 4-
213/6 = 36-
Prime numbers between 4 and 36 are 5, 7, 11, 13, 17, 19, 23, 29, and 31
- sign signifies that the number is marginally less .
Answer D
Question: Rs.20 is the true discount on Rs. 260 due after a certain time. What will be the true discount on the same sum due after half of the former time, the rate of interest being the same?
A.10.4
B.11
C.14.8
D.15.4
Answer: A.10.4
Explanation: Sol.
S.I. on Rs. (260 - 20) for a given time = Rs. 20.
S.I. on Rs. 240 for half the time = Rs. 10.
T.D. on Rs. 250 = Rs. 10.
∴ T.D. on Rs. 260 = Rs. [10/250 * 260] = Rs. 10.40
Answer A
Question: If the cost price of 165 chocolates is equal to the selling price of 150 chocolates, the gain percent is
A.8
B.9
C.10
D.11
Answer: C.10
Explanation: Let C.P. of each chocolate be Re. 1.
Then, C.P. of 150 chocolates = Rs. 150; S.P. of 150 chocolates = Rs. 165.
Gain % = 15/150 * 100 = 10%
Answer:C
Question: What number comes next?
284, 693, 712, 846, 937, ?
A.113
B.231
C.245
D.128
Answer: D.128
Explanation: D
128
The numbers 28469371 are being repeated in the same sequence.
Question: In a farm, 2000 seeds were planted wheat and 3000 rice seeds were planted. If 57 percent of the seeds in plot I germinated and 42 percent of the seeds in plot II germinated, what percent of the total number of planted seeds germinated?
A. 45.5%
B. 46.5%
C. 48.0%
D. 49.5%
Answer: C. 48.0%
Explanation: Plot I: 57% of 2000 wheat seeds germinated, hence 0.57*2000 = 1140 seeds germinated.
Plot II: 42% of 3000 rice seeds germinated, hence 0.42*3000 = 1260 seeds germinated.
Thus (germinated)/(total) = (1140 + 1260)/(2000 + 3000) = 2400/5000 = 48% seeds germinated.
Answer: C.
Question: Of the students at a certain high school, 90 percent took a course in algebra or geometry and 30 percent took courses in both. If the percent of students who took a course in algebra was 2 times the percent of students who took a course in geometry, what percent of the students took a course in algebra but not geometry?
A.50%
B.40%
C.45%
D.35%
Answer: A.50%
Explanation: You can also just use the formula
n(A or B) = n(A) + n(B) - n(A and B)
90 = 2X + X - 30
X = 40
2X = 80
This is the number of people who took algebra including those who took both. To get the number of people who took only algebra, 80 - 30 = 50%
Answer (A)
Question: David obtained 72, 60, 35, 62 and 84 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ?
A.75
B.62.6
C.87
D.165
Answer: B.62.6
Explanation: Explanation:
Average = (72 +60+ 35+ 62+84 )/ 5 = 313/5 = 62.6.
Answer:B
Question: If a = (3)b and c = 5b, then which of the following represents the average (arithmetic mean) of a, b, and c, in terms of b ?
A.b/3
B.b/4
C.2b
D.3b
Answer: D.3b
Explanation: a = (3)b and c =5b.
The mean = (a + b + c)/3 = (3b + b + 5b)/3 = 3b.
Answer is D
Question: By selling an umbrella for Rs. 300, a shop keeper gains 20%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
A.5
B.6
C.8
D.9
Answer: C.8
Explanation: Marked price = Rs. 300
C.P. = 100/120 * 300 = Rs. 250
Sale price = 90% of Rs. 300 = Rs. 270
Required gain % = 20/250 * 100 = 8%.
Answer:C
Question: In a workshop there are 3 kinds of beds, 3 kinds of closets, 2 kinds of shelves and 7 kinds of chairs. In how many ways can a person decorate his room if he wants to buy in the workshop one shelf, one bed and one of the following: a chair or a closet?
A.168.
B.80.
C.60.
D.48.
Answer: C.60.
Explanation: ways to select one shelf = 2
ways to select one bed = 3
ways to select one of the following: a chair or a closet = 7+3 = 10
ways to select all of them together = 2*3*10 = 60
Hence, C is the answer.
Question: The simple form of the ratio 4/3:3/7 is?
A.7:3
B.10:3
C.15:3
D.25:3
Answer: A.7:3
Explanation: 4/3 : 3/7 = 21:9 = 7:3
ANSWER:A
Question: A vessel of capacity 90 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution?
A.72.9
B.78.5
C.25.4
D.31.5
Answer: A.72.9
Explanation: Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T - y)/T]n * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(90 - 9)/90]2 (90) = 72.9 litres.
ANSWER A
Question: The calendar for the year 2001 is same for which of the following year?
A.2005
B.2007
C.2011
D.2006
Answer: B.2007
Explanation: SOLUTION :
The total number of odd days from 2001 onwards should be zero.
Now, as an ordinary year adds 1 odd day and a leap year adds 2 odd days, we have:
2001, 2002, 2003, 2005, 2006 – 1 odd day each
2004 – 2 odd days
Hence, at the end of 2006 total number of odd days = 7 or 0
Therefore, the calendar for the year 2001 is repeated in the year 2007.
ANSWER IS B
Question: A seven-digit phone number is divisible by 4. After adding the two digits of the area code the number is not divisible by 4, which of the following cannot be the area code?
A.07.
B.06.
C.05.
D.04.
Answer: D.04.
Explanation: Given that 7 digit number is divisible by 4
we know any number will not be divisible by 4 if the sum of all digits of the number is not the multiple of 4.
Hence looking at the option we can say that the number that should be added to the seven digit number must be 04 as adding it will make it divisible by 4... hence answer is D
Question: How many trucks are there if each truck carrying 70 packages and total of 490 packages?
A.A)7
B.B)6
C.C)9
D.D)11
Answer: A.A)7
Explanation: Sol.
Total packages 490
Each truck carries 70 packages
= 490 / 70
= 7
Answer : A