RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a group of ducks and cows, the total number of legs are 26 more than thrice the number of heads. Find the total number of cows.
A.A)14
B.B)13
C.C)16
D.D)8
Answer: B.B)13
Explanation: Explanation :
Let the number of ducks be d
and number of cows be c
Then, total number of legs = 2d + 4c = 2(d + 2c)
total number of heads = c + d
Given that total number of legs are 26 more than twice the number of heads
=> 2(d + 2c) = 26 + 2(c + d)
=> d + 2c = 13 + c + d
=> 2c = 13 + c
=> c = 13
i.e., total number of cows = 13
Answer : B
Question: 49 Ã— 49 Ã— 49 Ã— 49 x 49 = 7?
A.4
B.7
C.8
D.10
Answer: D.10
Explanation: 49 Ã— 49 Ã— 49 Ã— 49 x 49= 7?
or, 7(2) Ã— 7(2) Ã— 7(2) Ã— 7(2) x 7(2)= 7?
or 7(10) = 7? or, ? = 10
Answer D
Question: The population of a town is 10000. It increases annually at the rate of 20% p.a. What will be its population after 2 years?
A.14300
B.14350
C.14400
D.14500
Answer: C.14400
Explanation: Formula :
( After =100 denominator
Ago = 100 numerator)
10000 × 120/100 × 120/100 = 14400
C
Question: A rainstorm increased the amount of water stored in State J reservoirs from 130 billion gallons to 160 billion gallons. If the storm increased the amount of water in the reservoirs to 60 percent of total capacity, approximately how many billion gallons of water were the reservoirs short of total capacity prior to the storm?
A.92
B.85
C.136.67
D.140.67
Answer: C.136.67
Explanation: Let total capacity be x
we know 160 = 0.60x
x = 160/0.60 = 266.67
Prior to storm, we had 130 bn gallons
266.67-130 = 136.67
Answer : C
Question: A farmer has 12 plots of land, arranged in a row. To ensure viability of the soil, the farmer
never uses two adjacent plots at the same time. This season, the farmer wishes to plant one
plot of each of the following: corn, wheat, soybeans, and rice. Each crop is assigned its own
plot of land. How many ways can the farmer allocate plots of land for these crops?
A.1680
B.3024
C.5040
D.7920
Answer: B.3024
Explanation: There is a natural one-to-one correspondence between all choices from a row of 9
plots, and all “legal” choices for the 12 plots in the problem: given a choice of four plots in 9,
insert a fallow plot after each of the first three plots. The number of ways to pick 4 plots of
land from 9 is
􀀀9
4. After the locations of plots have been selected, there are 4! ways to assign
the crops to the plots. The total number of ways is therefore 4!
􀀀9
4
or 3024.
correct answer B
Question: What is the dividend. divisor 17, the quotient is 9 and the remainder is 5
A.136
B.148
C.150
D.158
Answer: D.158
Explanation: D = d * Q + R
D = 17 * 9 + 5
D = 153 + 5
D = 158
Question: A cycle is bought for Rs.900 and sold for Rs.1080, find the gain percent?
A.22
B.20
C.99
D.88
Answer: B.20
Explanation: 900 ---- 180
100 ---- ? => 20%
Answer:B
Question: The sides of a rectangular region measured to the nearest centimeter are 8 cm and 5 cm. Out of the following which is the largest possible value of actual area of rectangle ?
A.48
B.55.25
C.52.29
D.44
Answer: D.44
Explanation: acan be anywhere between 7.5 and 8.4 andbcan be anywhere between 4.5 and 5.4.
Hence max area can be 8.4*5.4 eq 45.36.
largest value which is near to 45.36 is 44.
Hence D.
Question: The product of all positive even numbers less than or equal to 20 is closest to which of the following?
A.10^6
B.10^7
C.10^8
D.10^9
Answer: D.10^9
Explanation: 2 * 4 * 6 * 8 * 10 * 12 * 14 * 16 * 18 * 20
Replacing closest digits to 10 (6,8,12,14) with 10 and closest to 20 (16,18) with 20.
==>(2 * 4) * (10 * 10 * 10 * 10 * 10) * (20 * 20 * 20)
==>8 * (10^5) * (8 * 10^3)
==>64 * 10^8
==>64 is closest to 50
==>50 * 10^ 8
==>5 * 10^9
Answer D
Question: The tax on a commodity is diminished by 20% and its consumption increased by 15%. The effect on revenue is?
A.2% decrease
B.8% decrease
C.9% decrease
D.3% decrease
Answer: B.8% decrease
Explanation: 100 * 100 = 10000
80 * 115 = 9200
-----------
10000-----------800
100-----------? => 8% decrease
Answer: B
Question: A class consists of 100 students, 25 of them are girls and 75 boys; 20 of them are rich and remaining poor; 40 of them are fair complexioned. The probability of selecting a fair complexioned rich girl is
A.1/50
B.1/59
C.1/56
D.1/54
Answer: A.1/50
Explanation: The probability of selecting girl is: 25/100 = 1/4
The probability of selecting rich is: 20/100 = 1/5
The probability of selecting fair complexioned is: 40/100 = 2/5
Three are independent;probability of rich and fair complexioned girl is:
(1/4) ×(1/5) × (2/5) = 1/50
Answer: A
Question: Speed of a boat in standing water is 14 kmph and the speed of the stream is 1.2 kmph. A man rows to a place at a distance of 4864 km and comes back to the starting point. The total time taken by him is
A.700 hours
B.350 hours
C.1400 hours
D.1010 hours
Answer: A.700 hours
Explanation: Explanation :
Speed downstream = (14 + 1.2) = 15.2 kmph
Speed upstream = (14 - 1.2) = 12.8 kmph
Total time taken = (4864/15.2) + (4864/12.8) = 320 + 380 = 700 hours. Answer : Option A
Question: (xn - an) is completely divisible by (x - a), if
A.n is any natural number
B.n is an even natural number
C.n is and odd natural number
D.n is prime
Answer: A.n is any natural number
Explanation: (xn - an) is completely divisible by (x - a) for every natural number n
Answer is A
Question: In Country A, the unemployment rate among construction workers dropped from 16 percent on September 1, 1992, to 9 percent on September 1, 1996. If the number of construction workers was 20 percent greater on September 1, 1996, than on September 1, 1992, what was the approximate percent change in the number of unemployed construction workers over this period?
A. 50% decrease
B. 30% decrease
C. 15% decrease
D. 30% increase
Answer: B. 30% decrease
Explanation: Country A 1992 1996
No of construction workers 100 120
Unemployment Rate 16% 9%
Unemployed workers 16 11
% change in unemployed workers=(16-11)=5/16=~33% decrease
Closest ans=30% decrease
Ans=B
Question: Bruce and Anne can clean their house in 4 hours working together at their respective constant rates. If Anne’s speed were doubled, they could clean their house in 3 hours working at their respective rates. How many S hours does it currently take Anne to clean the house on her own?
A.6
B.7
C.8
D.12
Answer: D.12
Explanation: Lets suppose Anne and Bruce take A and B hrs working separately
So in 1 hour they can together finish 1/A + 1/B portion of the work which equals 1/4 (As the work is completed in 4 hours)
After anne doubles her rate of work the portion completed by the both is 1/A +2/B which is equal to 1/3 (As the work is completed in S= 3 hours)
Solving these 2 equations we can find B as 12
So, D
Question: if 15% of X is added to X and 5% of the result is subtracted from the result, then the value of X
A.increased
B.decreased
C.no change
D.depend on x
Answer: A.increased
Explanation: Let assume X =100
15% of 100 = 15
Now, new value X = 100+15 = 115
5% of 115(new result) = 5.75
So, 115-5.75 = 109.25
So, X is increased. (100 increased to 109.25)
ANSWER:A
Question: x =1 2 2.5
y= 27 4 5 then what is the relation between x and y
A.3*X)^4
B.3*X)^1
C.3*X)^2
D.3*X)^3
Answer: D.3*X)^3
Explanation: Y=(3*X)^3
27=(3*1)^3
27=27
ANSWER:D
Question: Alex age after 13years will be 10 times his age 10years back. What is the present age of Alex?
A.15
B.13
C.20
D.21
Answer: B.13
Explanation: Let Alex's present age be x
Alex's age after 17 years = x+17
Alex's age 10 years back = x-10
x+17= 10(x-10)
x = 13
Rajeev's present age = 13 years
Answer is B
Question: Sonika deposited Rs.12000 which amounted to Rs.19500 after 4 years at simple interest. Had the interest been 3% more. She would get how much?
A.20940
B.21009
C.23000
D.23450
Answer: A.20940
Explanation: (12000*4*3)/100 = 1440
19500
--------
20940
Answer: A
Question: A train 250 m long running at 72 kmph crosses a platform in 25 sec. What is the length of the platform?
A.150m
B.200m
C.250m
D.270m
Answer: C.250m
Explanation: D = 72 * 5/18 = 25 = 500 – 250 = 250m
ANSWER:C
Question: You have two jars, 50 red marbles and 50 blue marbles. A jar will be picked at random, and then a marble will be picked from the jar. Placing all of the marbles in the jars, how can you maximize the chances of a red marble being picked? What are the exact odds of getting a red marble using your scheme?
A.73/99
B.74/99
C.75/99
D.74/97
Answer: B.74/99
Explanation: one red ball in one jar. 49 red + 50 blue in second jar.
probability to get red ball is 1/2(1+49/99) = 74/99
ANSWER:B
Question: The speed of a car is 90 km in the first hour and 60 km in the second hour. What is the average speed of the car?
A.72 kmph
B.75 kmph
C.30 kmph
D.80 kmph
Answer: B.75 kmph
Explanation: S = (90 + 60)/2
= 75 kmph
ANSWER:B
Question: a piece of ribbon 4 yard long is used to make bows requiring 15 inches of ribbon for each.What is the maximum number of bows that can be made.
A.9
B.8
C.7
D.6
Answer: A.9
Explanation: 1 yard = 36 Inch
4 yard = 36*4 = 144 inch
15 inch req. for 1 bow
Max. no. of bows possible = 144/15 = 9 bows and 9 inch ribbon left.
ANSWER:A
Question: 1. Internet: $80, with no sales tax, plus $10 shipping fee
2. Store X: $80, a 10% discount, plus 10% tax on discounted price
3. Store Y: $90, no tax
4. Store Z: $90, a 10% sales tax, and $10 rebate after tax
Isaac can purchase a certain item in four different ways, as shown in the table. What is the lowest price for which he can purchase this item?
A.79.2
B.89.0
C.89.1
D.89.5
Answer: A.79.2
Explanation: Option 2 = (80 - 8) + 0.1 * 72=79.2
Option 4 = 90 + 0.1 * 90 - 10
= 89
So the OA is correct - A
Question: A, B, C subscribe Rs. 50,000 for a business. A subscribes Rs. 4000 more than B and B Rs. 5000 more than C. Out of a total profit of Rs. 35,000, A receives
A.Rs. 8400
B.Rs. 11,900
C.Rs. 13,600
D.Rs. 14,700
Answer: D.Rs. 14,700
Explanation: Solution: Let C = x.
Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.
So, x + x + 5000 + x + 9000 = 50000.
=> 3x = 36000.
=> x = 12000.
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
So A's share = Rs. (35000 x 21/50) = Rs. 14,700.
Answer: Option D
Question: The value of 99^(91/99) x 99 is:
A.9989
B.9896
C.9892
D.9809
Answer: C.9892
Explanation: (100 â€“ 8/99) x 99 = 9900 â€“ 8
= 9892.
ANSWER:C
Question: In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
A.21/46
B.25/117
C.1/50
D.3/25
Answer: A.21/46
Explanation: Let S be the sample space and E be the event of selecting 1 girl and 2 boys.
Then, n(S)	= Number ways of selecting 3 students out of 25
= 25C3 `
=	(25 x 24 x 23)
(3 x 2 x 1)
= 2300.
n(E)	= (10C1 x 15C2)
= 10 x	(15 x 14)
(2 x 1)
= 1050.
P(E) =	n(E)/n(S)	=	1050	/2300=	21/46	.
Answer : A.
Question: A container contains 40lit of milk. From this container
4 lit of milk was taken out and replaced by water.
This process was repeated further two times.
How much milk is now contained by the container?
A.29.16
B.29.19
C.30.0
D.25.3
Answer: A.29.16
Explanation: Amount of milk left after 3 operations = 40(1-4/40)3lit
=(40*9/10*9/10*9/10)
= 29.16 lit
ANSWER A
Question: The length of the bridge, which a train 180 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
A.388
B.167
C.195
D.288
Answer: C.195
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (180 + X)/30 = 25/2 ==> 2(180 + X) = 750 ==> X = 195 m.
Answer: C
Question: A sofa and a love seat together costs S444. The sofa costs double the love seat.
How much do they each cost?
A.love seat costs $148-sofa costs $296.
B.love seat costs $158-sofa costs $496.
C.love seat costs $170-sofa costs $500.
D.love seat costs $499-sofa costs $655.
Answer: A.love seat costs $148-sofa costs $296.
Explanation: Love Seat x With no information about the love seat, this is our x
Sofa 2x Sofa is double the love seat, sowemultiply by 2
S +L=444 Together they cost 444, sowe add.
(x)+(2x)=444 Replace S and Lwith labled values
3x=444 Parenthesis are not needed, combine like terms x+2x
3 3 Divide both sides by 3
x=148 Our solution for x
Love Seat 148 Replace xwith 148 in the origional list
Sofa 2(148)=296 The love seat costs $148 and the sofa costs $296.
correct answer A
Question: Evaluate: 6402.5 + 640.25 + 64.025 + 6.4025 + 0.64025
A.6819.59775
B.6981.59775
C.6918.59775
D.7113.81775
Answer: D.7113.81775
Explanation: 6402.5
640.25
64.025
6.4025
+ 0.64025
---------------
7113.81775
Answer is D.
Question: What least number should be added to 1056,So that the sum is completely divisible by 23?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: =>1056/23=45
Remainder=21=21+2
=23
Hence 2 should be added to 1056 so that the number divisible by 23
Option :B
Question: How many prime numbers between 0 to 50?
A. 11
B. 13
C. 14
D. 15
Answer: D. 15
Explanation: primes are of the form 6n+1 or 6n-1
Put n=0
6n+1=6*0+1=1 where 1 is not prime
for n=1
6n+1=6*1+1=7 and 6n-1= 6*1-1=5
for n=2
6n-1= 11 and 6n+1=13
for n=3 , ==> 19 and 17
for n = 4 ==> 23
for n =5 ==> 29 and 31
for n = 6 ==> 37
for n=7 ==> 41 and 43
for n = 8 ==> 47
therefore total number of prime numbers = 13 + 2(since 2 and 3 are prime numbers) =15
Ans - D
Question: The sum of ages of 4 children born at the intervals of 3 years each is 43 years. Find out the age of the youngest child?
A.8 1/4 years
B.6 1/4 years
C.6 2/4 years
D.6 3/4 years
Answer: B.6 1/4 years
Explanation: Let the age of the youngest child =a
Then, the ages of 4 children can be written as a,a+3,a+6 and a+9
a+a+3+a+6+a+9=43
4a+18=43
4a=25
a=6 1/4 years
ANSWER:B
Question: A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 5x km.
A.16
B.18
C.24
D.40
Answer: D.40
Explanation: Total time taken = x/40 + 2x/20 hours
= 5x/40 = x/8 hours
Average speed = 5x/(x/8) = 40 kmph
Answer: D
Question: The temperature of a certain cup of coffee 10 minutes after it was poured was 120 degrees Fahrenheit. If the temperature F of the coffee t minutes after it was poured can be determined by the formula F=120(2^-at) + 60, where F is in degrees Fahrenheit and a is a constant. Then the temperature of the coffee 60 minutes after it was poured was how many degrees Fahrenheit?
A.125
B.95
C.80
D.61.8
Answer: D.61.8
Explanation: Answer: B
The temperature of coffee 10 minutes after it was poured (120 F) will help in solving the constant “a”.
120 = 120(2 ^ 10a) + 60
2 ^ -1 = 2 ^ 10a
a = -1/10
The temperature of coffee 60 minutes after it was poured is:
F = 120 ( 2 ^ -60/10) + 60
F = 120 * 1/ 64 + 60
F = 15/8 + 60
F = 495/8=61.8
D
Question: 7589-?=3434
A.4242
B.4155
C.1123
D.11023
Answer: B.4155
Explanation: Let 7589-x=3434
then x=7589-3434
=4155
Answer is B
Question: Look at this series: 74, 71, 69, 66, 64, ... What number should come next?
A.60
B.61
C.59
D.58
Answer: B.61
Explanation: Explanation:
This is an alternating number subtraction series. First, 3 is subtracted, then 2, then 3, and so on.
Answer: Option B
Question: During a certain two-week period, 70 percent of the movies rented from a video store were comedies, and of the remaining movies rented, there were 4 times as many dramas as action movies. If no other movies were rented during that two-week period and there were A action movies rented, then how many comedies, in terms of A, were rented during that two-week period?
A.16A
B.13A
C.14A
D.11 2/3A
Answer: D.11 2/3A
Explanation: Total movies = 100.
Comedies = 70.
Action + Drama = 30. Since there were 5 times as many dramas as action movies, then Action + 4*Action = 30 --> Action = A = 6.
Comedies = 70 = 14A.
Answer: D.
Question: hree persons A, B and C divide a certain amount of money such that A's share is Rs. 4 less than half of the total amount, B's share is Rs. 8 more than half of what is left and finally C takes the rest which is Rs. 14. Find the total amount they initially had with them?
A. Rs. 61 B. Rs. 85
A.20
B.20
C.30
D.80
Answer: D.80
Explanation: Let the total amount be Rs. p.
Let shares of A and B be Rs. x and Rs. y respectively.
C's share was Rs. 14
we have, x + y + 14 = p ----- (1)
From the given data, x = (p/2) - 4 ----- (2)
Remaining amount = p - (p/2 - 4) => p/2 + 4.
y = 1/2(p/2 + 4) + 8 => p/4 + 10 ----- (3)
From (1), (2) and (3)
p/2 - 4 + p/4 + 10 + 14 = p
3p/4 + 20 = p
p/4 = 20 => p = Rs. 80.
Answer: D
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is
A.40
B.35
C.45
D.55
Answer: A.40
Explanation: Explanation:
Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) years = 90 years.
Sum of the present ages of wife and child = (20 * 2 + 5 * 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years
Option A
Question: If the probability of rain on any given day in City X is 60%, what is probability that it rains on exactly 3 days in a 4 day period?
A.16/25
B.86/125
C.96/125
D.216/625
Answer: D.216/625
Explanation: One possible way is rain-rain-rain-no rain.
The probability of this is 3/5*3/5*3/5*2/5 = 54/625
The number of possible ways is 4C3 = 4, so we multiply this by 4.
P(rain on exactly 3 days) = 4*54/625 = 216/625
The answer is D.
Question: A certain pair of used shoes can be repaired for $14.50 and will last for 1 year. A pair of the same kind of shoes can be purchased new for $32.00 and will last for 2 years. The average cost per year of the new shoes is what percent greater than the cost of repairing the used shoes?
A.16
B.10.34
C.12.46
D.11.2
Answer: B.10.34
Explanation: 1) Cost of repairing = 14.5 ( for one year ), Therefore for 2 years it would be$ 29.
2) Cost of new pair which will last for 2 years is$ 32.
Percentage change formula =( Final value - Initial value ) / ( Initial Value ) * 100. In this case the final value would be the price of new shoeinitial value would be the cost of repairing the old shoe.
I.e ( 32 - 29 ) / ( 29 ) * 100 = 10.34 %.
Ans is B
Question: Due to construction, the speed limit along an 9-mile section of highway is reduced from 45 miles per hour to 35 miles per hour. Approximately how many minutes more will it take to travel along this section of highway at the new speed limit than it would have taken at the old speed limit ?
A.A) 5.61
B.B) 3.42
C.C) 10
D.D) 15
Answer: B.B) 3.42
Explanation: Old time in minutes to cross 9 miles stretch = 9*60/45 = 9*4/3 = 12
New time in minutes to cross 9 miles stretch = 9*60/35 = 9*12/7 = 15.42
Time difference = 3.42
Ans:B
Question: Tough and Tricky questions: Geometry.
A cylindrical tank, with radius and height both of 10 feet, is to be redesigned as a cone, capable of holding twice the volume of the cylindrical tank. There are two proposed scenarios for the new cone: in scenario (1) the radius will remain the same as that of the original cylindrical tank, in scenario (2) the height will remain the same as that of the original cylindrical tank. What is the approximate difference in feet between the new height of the cone in scenario (1) and the new radius of the cone in scenario (2)?
A. 13
B. 25
C. 30
D. 35
Answer: D. 35
Explanation: volume of a cylinder = pi*r^2 *h
r=10
h=10
volume = 1000pi
volume of the cone: 2000pi
volume of the cone = pi*r^2 * h/3
2000=r^2 * h/3
1st case: r=10 -> h/3=20 => h=60
2nd case: h=10 -> r^2 = sqrt(600)
sqrt(600) = 10*sqrt(6)
sqrt(6)>sqrt(4)
sqrt(6)<sqrt(9)
so radius must be between 20 and 30. this approximation is enough.
60-30=30
60-20=40
so we are looking for smth between 30 and 40.
only D fits in here.
Question: In a chicken farm, due to certain disease 15% of chickens die every month. How many months it will take to the reduce the count of chicken by 50%?
A.4
B.5
C.6
D.7
Answer: B.5
Explanation: 1 year: 100*15/100= 15: Total: 85
2nd year: 85*15/100= 13: Total: 85-13= 72
3rd year: 72*15/100 = 11: Total: 72-11= 61
4th year: 61*15/100 = 9: Total: 61-9 = 52
5th month : 52*15/100 = 8 : Total: 52-8= 44
;4 months;
ANSWER:B
Question: P is three times as old as Q. In 7 years, P will be twice as old as Q. How old was P three years ago?
A.15
B.18
C.21
D.24
Answer: B.18
Explanation: P = 3Q so Q = P/3
P+7 = 2(Q+7) = 2(P/3+7)
P/3 = 7
P = 21
Three years ago, P was 18.
The answer is B.
Question: Which of the following cannot be the sum of 4 different prime numbers?
A.21
B.17
C.19
D.32
Answer: C.19
Explanation: Option A: 21 = 2+3+5+11. Sum of 4 different prime numbers
Option B: 17 = 2+3+5+7. Sum of 4 different prime numbers
Option C: 19 = 2+3+5+9. This cannot be expressed as a sum of 4 different prime numbers
Option D: 32 = 5+3+11+13. Sum of 4 different prime numbers
Option E: 31 = 5+2+11+13. Sum of 4 different prime numbers
Correct Option:C
Question: For an agricultural experiment, 300 seeds were planted in one plot and 200 were planted in a second plot. If exactly 30 percent of the seeds in the first plot germinated and exactly 35 percent of the seeds in the second plot germinated, what percent of the total number of seeds germinated?
A.12%
B.26%
C.29%
D.32%
Answer: D.32%
Explanation: In the first plot 30% of 300 seeds germinated, so 0.3 x 300 = 90 seeds germinated.
In the second plot, 35% of 200 seeds germinated, so 0.35 x 200 = 70 seeds germinated.
Since 90 + 70 = 260 seeds germinated out of a total of 300 + 200 = 500 seeds, the percent of seeds that germinated is (160/500) x 100%, or 32%.
Answer: D.
Question: Machines X and Y produce bottles at their respective constant rates. Machine X produces k bottles in 3 hours and machine Y produces k bottles in 2 hours. How many hours does it take machines X and Y , working simultaneously , to produce 12k bottles?
A. 16
B. 20
C. 15
D. 72/5
Answer: D. 72/5
Explanation: x rate = k/3
y rate = k/2
k/3 + k/2 = 12k / T
solving T = 72/5
Answer D
Question: 10 books are placed at random in a shelf. The probability that a pair of books will always be together i
A.1/6
B.1/0
C.1/5
D.1/2
Answer: C.1/5
Explanation: 10 books can be rearranged in 10! ways consider the two books taken as a pair then number of favourable ways of getting these two books together is 9! 2!
Required probability = 1/5
Answer: C
Question: Shahrukh starts from Barabanki to Fatehpur , 1 hour after Ajay starts. Shahrukh meets Kajol 1.5 hours after Shahrukh starts. If the speed of Shahrukh is at least 20km/h faster than the speed of Kajol.
What is the minimum speed of Shahrukh to overtake Ajay, before he meets Kajol?
A.32
B.21
C.27
D.None of these
Answer: D.None of these
Explanation: Explanation:
Let t be the time after Kajol starts, when she meets Ajay, then
\inline t=\frac{300}{(x+y)}
This should be less than 2.5 or (x+y)>120
Since y= \inline \frac{3x}{2} \inline \Rightarrow y>72
This (y>72) is greater than 67.5 km/h and hence Shahrukh will always overtake Ajay before he meets Kajol.
Answer: D
Question: United Telephone charges a base rate of $8.00 for service, plus an additional charge of $0.25 per minute. Atlantic Call charges a base rate of $12.00 for service, plus an additional charge of $0.20 per minute. For what number of minutes would the bills for each telephone company be the same?
A.25 minutes
B.10 minutes
C.20 minutes
D.80 minutes
Answer: D.80 minutes
Explanation: Lets take number of minutesx.
Given that, 8+0.25x=12+0.2x ->0.05x=2 -> x=80minutes
ANS D
Question: Find the odd man out 3, 5, 7, 12, 13, 17, 19
A.3
B.5
C.7
D.12
Answer: D.12
Explanation: 12 is an even number while the others are odd
ANSWER:D
Question: How many prime numbers W exist such that 90 < W < 106 and W is a factor of 99999919?
A.1. Zero
B.2. One
C.3. Two
D.4. Three
Answer: C.3. Two
Explanation: I found that considering the constraint..W is a prime num in between 90 to 106 not inclusive , only 3 numbers (91,97 and 101) are present but those numbers are not the factors of the number mentioned....Therefore, i doubt the answer.C
Question: If n is a natural number, then (6n2 + 6n) is always divisible by:
A.6 only
B.6 and 12 both
C.12 only
D.by 18 only
Answer: B.6 and 12 both
Explanation: EXPLANATION
(6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.
Answer B