RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A train travels from city C to city D. The average speed of the train is 60 miles/hr and it travels the first quarter of the trip at a speed of 90 mi/hr. What is the speed of the train in the remaining trip?
A.30
B.45
C.54
D.72
Answer: C.54
Explanation: Using the RTD chart, with A being the first quarter, B the rest of the trip and All the combinedtrip.
_______R_____T______D
C.........90........3..........270
D.........54.......15.........810
All........60.......18........1080
Let me explain how we fill in the chart:
1) Starting with what we know, we add 90 and 60
2) Picking an easy number for the total distance (6*9=54), so I chose 540. Multiply by 2 to get the whole trip, and we get 1080. Add 1080 for all-distance.
3) 1/4 of the whole distance happened at a Rate of 90. So, 1080/4=270, add 270 under A-D.
4) 2080 - 270 = 810, for the rest of the trip. Add 810 under B-D.
5) Claculate the individual Times for A and All, using T=D/R. Add the results, 3 and 18, under A-T and All-T.
6) 18-3=15, this is the remaining Time for B. Add 15 under B-T.
7) Finally, 15R=810 -->R=810/15 --> R= 54ANS C
Question: A man spends Rs. 1600 per month on an average for the first three months, Rs 1550 for next four months and Rs. 1800 per month for the last five months and saves Rs . 2800 a year. What is his average monthly income?
A.1900
B.2010
C.2100
D.2200
Answer: A.1900
Explanation: Total expenditure for the first 3 months = 3 × 1600 = 4800
Total expenditure for 4 months = 4 × 1550 = 6200
Total expenditure for 5 months = 5 × 1800 = 9000
Total expenditure and saving (which is income for one year)
= 4800 + 6200 + 9000 + 2800 = Rs. 22800
So, Average monthly income = 22800/12 = Rs. 1900
A
Question: A bag contains 64 balls of eight different colours. There are eight of each colour (including red). What is the least number you would have to pick, without looking, to be sure of selecting 3 red balls?
A.49
B.37
C.59
D.72
Answer: C.59
Explanation: C
59
The first 56 balls could be of all colours except red. This would leave 8 balls, all of which are red. so any three chosen would be red.
Question: A student chose a number, multiplied it by 6, then subtracted 138 from the result and got 102. What was the number he chose?
A.40
B.120
C.130
D.140
Answer: A.40
Explanation: Solution:
Let xx be the number he chose, then
6⋅x−138=102
6x=240
x=40
Answer A
Question: In a lottery there are 20 prizes and 35 blanks. A lottery is drawn at random. What is the probability of getting a prize
A.2/13
B.4/11
C.5/11
D.6/11
Answer: B.4/11
Explanation: total draws = prizes+blanks= 20+35=55
probability of getting a prize = 20/55 = 4/11
correct option is B
Question: 4 dice are thrown simultaneously on the board. Find the probability show the same face.
A.2/113
B.2/141
C.1/216
D.2/115
Answer: C.1/216
Explanation: The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:
=6×6×6×6=64=6×6×6×6=64
n(S)=64n(S)=64
Let XX be the event that all dice show the same face.
X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}
n(X)=6n(X)=6
Hence required probability,
=n(X)n(S)=664=n(X)n(S)=664
=1/216
C
Question: Of the 200 students at University XYZ majoring in one or more of the engineering disciplines, 160 are majoring in electrical and 150 are majoring in mechanical. If at least 30 of the students are not majoring in either electrical or mechanical, then the number of students majoring in both electrical and mechanical could be any number from
A.50 to 70
B.70 to 100
C.110 to 130
D.130 to 150
Answer: A.50 to 70
Explanation: if there are 1630 students majoring in electrical then there must be 70 person not majoring electrical at all, since both of the student not majoring electrical and mechanical is at least 30, so the number of the student who are not majoring electrical but majoring mechanical will be at least 10.
if there are 150 students majoring in mechanical there must be 50 students who are not majoring mechanical at all, since the number of the student who are not majoring electrical but majoring mechanical will be at least 10, hence the number of students both majoring mechanical and electrical will be at least 50
so there must be at least 50 students who major in both
see the answers option the only possible answer is A !
Question: n∑n=1 1/log2n(a) =?
A.n(n + 1)/2 loga2
B.n(n - 1)/2 log2a
C.n(n + 1)2n2/4 loga2
D.n(n + 1)2n2/4 loga3
Answer: A.n(n + 1)/2 loga2
Explanation: n∑n=11/log2n(a) = n∑n=1loga(2n)
=n∑n=1nloga2
=n(n + 1)/2 loga2
ANSWER:A
Question: A sum of money deposited at compound interest (compounded yearly) amounts to $3200 in 2 years and to $3296 in 3 years. What is the interest rate?
A.2%
B.3%
C.4%
D.5%
Answer: B.3%
Explanation: 3296 - 3200 = 96
96 / 3200 = 0.03 = 3%
The answer is B.
Question: Two brothers took the GMAT exam, the higher score is X and the lower one is Y. If the difference between the two scores is equal to their average, what is the value of X/Y ?
A.3.
B.2.
C.1/2.
D.1/3.
Answer: A.3.
Explanation: Answer is A : 3
X - Y = (X + Y)/2
Solving for X/Y =3
Question: A person goes to his office at 1/3rd of the speed at which he returns from his office. If the avg speed during the whole trip is 15m/h. what is the speedof the person while he was going to his office?
A.8km/h
B.10km/h
C.12km/h
D.13km/h
Answer: B.10km/h
Explanation: u = k , v= 3k
\inline \therefore \frac{2uv}{u+v}\: \: \Rightarrow \frac{2\times k\times 3k}{(k+3k)}=15
\inline \Rightarrow 1.5k = 15
\inline \Rightarrow k=10km/h
B
Question: The “connection” between any two positive integers a and b is the ratio of the smallest common multiple of a and b to the product of a and b. For instance, the smallest common multiple of 8 and 12 is 24, and the product of 8 and 12 is 96, so the connection between 8 and 12 is 24/96 = 1/4
The positive integer y is less than 20 and the connection between y and 6 is equal to 1/1. How many possible values of y are there?
A.7
B.8
C.9
D.10
Answer: A.7
Explanation: Since “connection” between y and 6 is 1/1 then LCM(6, y)=6y, which means that 6 and y are co-prime (they do not share any common factor but 1), because if the had any common factor but 1 then LCM(6, y) would be less than 6y.
So, we should check how many integers less than 20 are co-prime with 6, which can be rephrased as how many integers less than 20 are not divisible by 2 or 3 (6=2*3).
There are (18-2)/2+1=9 multiples of 2 in the range from 0 to 20, not inclusive;
There are (18-3)/3+1=6 multiples of 3 in the range from 0 to 20, not inclusive;
There are 3 multiples of 6 in the range from 0 to 20, not inclusive (6, 12, 18) - overlap of the above two sets;
Total multiples of 2 or 6 in the range from 0 to 20, not inclusive is 9+6-3=12;
Total integers in the range from 0 to 20, not inclusive is 19;
Hence, there are total of 19-12=7 numbers which have no common factor with 6 other than 1: 1, 5, 7, 11, 13, 17 and 19.
Answer: A.
Question: Mrs. Rodger got a weekly raise of $135. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.
A.$ 145.
B.$ 146
C.$ 135
D.$ 148
Answer: C.$ 135
Explanation: Solution:
Let the 1st paycheck be x (integer).
Mrs. Rodger got a weekly raise of $ 135.
So after completing the 1st week she will get $ (x+135).
Similarly after completing the 2nd week she will get $ (x + 135) + $ 135.
= $ (x + 135 + 135)
= $ (x + 270)
So in this way end of every week her salary will increase by $ 135.
Answer C
Question: How many revolutions will it take for a circular wheel of 1.95 m radius make in traveling a distance of 1 km?
A.14557.1
B.24257.1
C.11257.1
D.12257.1
Answer: D.12257.1
Explanation: 2 * 22/7 * 1.95 * x = 12257.1
x = 1000
Answer: D
Question: A customer pays 50 dollars for a coffee maker after a discount of 20 dollars
What is the original price of the coffe maker?
A.$50
B.$60
C.$70
D.$80
Answer: C.$70
Explanation: Let x be the original price.
x - 20 = 50
x - 20 + 20 = 50 + 20
x + 0 = 70
x = 70
correct answer is C)$70
Question: The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?
A.22
B.25
C.70
D.27
Answer: C.70
Explanation: A + B = 60, A = 2B
2B + B = 60 => B = 20 then A = 40.
5 years, their ages will be 45 and 25.
Sum of their ages = 45 + 25 = 70.Answer:C
Question: Ms. Harris invested in Fund X and Fund B. The total amount she invested, in both funds combined, was $100,000. In one year, Fund X paid 23% and Fund B paid 17%. The interest earned in Fund B was exactly $200 greater than the interest earned in Fund X. How much did Ms. Morris invest in Fund X?
A. $32,000
B. $36,000
C. $40,000
D. $42,000
Answer: D. $42,000
Explanation: 0.17B-0.23X = 200 | * 100
17B-23X=20,000
X+B=100,000
B=100,000 - X
17(100,000 - X) - 23X = 20,000
1,700,000 - 17X - 23X = 20,000
1,680,000 = 40X
divide by 40
first two digits: 42...so answer is D.
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
A.35, 25 kmph
B.80, 40 kmph
C.40, 60 kmph
D.50, 55 kmph
Answer: B.80, 40 kmph
Explanation: Speed downstream = 60 + 20 = 80 kmph
Speed upstream = 60 - 20 = 40 kmph
ANSWER:B
Question: Working together, Tim and Tom can type 15 pages in one hour. If they would be able to type 18 pages in one hour if Tom increases his typing speed by 60%, what is the ratio of Tom's normal typing speed to that of Tim?
A.1/2
B.1/3
C.1/4
D.1/5
Answer: A.1/2
Explanation: Lets say Tim types x pages an hour and Tom types y pages an hour.
We know that x+y=15
Tom increase speed by 60% means he will type 1.6 y pages an hour.
So we get x+1.6 y=18
We need to know the ratio of Tom's speed to Tim's speed. This is going to be proportional to the number of pages each can type in an hour, hence (y/x).
Subtracting both : 0.6 y=3 so y=5 ... so x=10
(y/x)=5/10 =1/2
Answer is (A)
Question: Bob finishes the first half of an exam in two-sixth the time it takes him to finish the second half. If the whole exam takes him an hour, how many minutes does he spend on the first half of the exam?
A.15
B.24
C.27
D.36
Answer: A.15
Explanation: Many times, it is easiest to think of problems like this conceptually (as opposed to formulaically). Conceptually, if the first half of the exam takes 2/6's the time of the second half (6/6's), we can see that the hour the entire exam took to finish can be broken down into eight's. (Another way to look at this problem is via ratio's - first half is 2:8 and the second half is 6:8). With each sixth of an hour being 15/2 minutes (60/8), the first half of the exam would have taken 15 minutes. Correct answer is A.
Question: Find the prodect of the local value and absolute value of 4 in 23468
A.400
B.1600
C.1200
D.80
Answer: B.1600
Explanation: Explanation:
Local value of 4 = 4 x 100 = 400
Place value of 4 = 4
There fore = 4 x 400 = 1600
Answer: Option B
Question: How many kg of salt at 42 paise per kg must a man mix with 25 kg of salt at 24 paise per kg so that he may, on selling the mixture at 40 paise per kg gain 25% on the outlay?
A.15 kg
B.18 kg
C.20 kg
D.24 kg
Answer: C.20 kg
Explanation: Here, cost price of mixture = 100×100/100+25 = 32 paise
∴q1q2=32−24/42−32=810=45
and hence q1 = 4⁄5 × 25 = 20 kg
Answer C
Question: At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years?
A.5%
B.4%
C.2%
D.6%
Answer: C.2%
Explanation: Let sum = x. Then, S.I. = 2x/5, Time = 20 years.
Rate = (100 * 2x) / (x * 5 * 20) = 2%
ANSWER:C
Question: There are 200 female managers in a certain company. Find the total number R of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers.
A.R=300
B.R=400
C.R=500
D.600
Answer: C.R=500
Explanation: {Managers} = {Female Managers} + {Male Managers};
We are told that the total number of managers in the company is 2/5 of all the employees , thus{Managers} = 2/5 (M + F), where M and F are number of female and male employees, respectively.
Also, we know that 2/5 of all male employees are managers:{Male Managers} = 2/5 * Mas well as there are total of 200 female managers:{Female Managers} = 200;
Thus:2/5 (M + F) = 200 + 2/5 * M-->F = 500.
Answer: C.
Question: A committee of 6 people is to be selected from 8 people. How many different committees are possible?
A.28
B.40
C.56
D.D.168
Answer: A.28
Explanation: Because the order does not matter in selecting 6 people for the committee, this is a combination question.
The number of ways to select 6 people from 8 = 8C6 = 8!/6!*2! = 28. Hence A.
Question: A student has 7 trousers and 10 shirts. In how many different ways can the student select a trouser and a shirt?
A.52
B.58
C.64
D.70
Answer: D.70
Explanation: The student can select one trouser in 7 ways.
The student can select one shirt in 10 ways.
The number of ways to select one trouser and one shirt is 7 * 10 = 70 ways
The answer is D.
Question: The average mark obtained by 22 candidates in an examination is 47. The average of the first ten is 55 while the last eleven is 40 .The marks obtained by the 11th candidate is ?
A.22
B.44
C.49
D.68
Answer: B.44
Explanation: It is clear that 22 x 47 = 10 x 55 + K + 11 x 40 ⇒⇒ K = 44
Answer:B
Question: Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 63, the three numbers in order are?
A.27, 54, and 108
B.54, 27, and 108
C.108, 27, and 54
D.108, 54, and 27
Answer: B.54, 27, and 108
Explanation: Let the numbers be 2x, x and 4x
(2x + x + 4x)/3 = 63
7x/3 = 63
x = 27
The numbers in order are 54, 27, and 108
The answer is B.
Question: A’s speed is 51/44 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat?
A.1/51
B.4/51
C.7/51
D.3/44
Answer: C.7/51
Explanation: We have the ratio of A’s speed and B’s speed. This means, we know how much distance A covers compared with B in the same time.
This is what the beginning of the race will look like:
(Start) A_________B______________________________
If A covers 51 meters, B covers 44 meters in that time. So if the race is 51 meters long, when A reaches the finish line, B would be 7 meters behind him. If we want the race to end in a dead heat, we want B to be at the finish line too at the same time. This means B should get a head start of 7 meters so that he doesn’t need to cover that. In that case, the time required by A (to cover 51 meters) would be the same as the time required by B (to cover 44 meters) to reach the finish line.
So B should get a head start of 7/51th of the race.
Answer (C)
Question: Andrea and Zach are both waiting for an
appointment with a guidance counselor.
When they arrived, each received a card
from the secretary, telling the hour and
minute of his or her arrival. Two minutes
ago, Andrea had been waiting exactly as
many minutes as Zach. Three minutes from
now, Andrea will have been waiting exactly
2/3 as long as Zach. If the time is now 11:30,
at what time did Andrea arrive?
A.11:16
B.11:18
C.11:20
D.11:23
Answer: D.11:23
Explanation: Let a equal the number of minutes that Andrea had been waiting two minutes ago. At
that time, Zach had been waiting for twice as long as Andrea, so he had been waiting for
2a minutes. Three minutes from now, both Andrea and Zach will each have been waiting
for 5 minutes longer:
Two minutes ago Three minutes from now
Andrea a a + 5
Zach 2a 2a + 5
Three minutes from now, Andrea will have been waiting for 23
as long as Zach, so make an equtation as follows:
a+5=2/3(2a+5)
3a+15=2(2a+5)
3a+15=4a+10
3a+5=4a
5=a
Thus, two minutes ago, at 11:28, Andrea had been waiting for 5 minutes. So she arrived at 11:23.
correct answer D)11.23
Question: A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?
A.63
B.511
C.1023
D.15
Answer: C.1023
Explanation: Given that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.
Hence, the required number of ways = 45 - 1.
= 210 - 1 = 1024 - 1 = 1023
ANSWER:C
Question: A committee of 7 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed?
A.308
B.700
C.1404
D.2620
Answer: A.308
Explanation: The only cases possible are :
1. 2 men and 5 women : 8C2 * 5C5 = 28
2. 4 men and 3 women: 8C4*5C3 = 280
Rest of the cases will either have 1 or 0 men (not allowed) or will have 1 or 2 or 0 women (not allowed)
Total possible combinations = 28+280 = 308. Thus A is the correct answer.
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 20 minutes. The waste pipe can empty the full cistern in?
A.2.8
B.8
C.6
D.9
Answer: A.2.8
Explanation: 1/10 + 1/15 - 1/x = 1/20
x = 20/7 = 2.8
Answer: A
Question: If x is divisible by 9, 108, and 36, which of the following must be the least multiple of x?
A.108
B.36
C.9
D.324
Answer: A.108
Explanation: If x is divisible by 9, 108, and 36, then x must be a multiple of 9,4 and 3.
Hence,the least multiple of x will be 9*4*3=108.
ANSWER:A
Question: If q and b are positive numbers, and q^3 + b^3 = 75, then the greatest possible value of q is between:
A.0 and 3
B.3 and 5
C.4 and 5
D.5 and 7
Answer: C.4 and 5
Explanation: Yes the question is ambiguous, and the answer is certainly not C between 4 and 5 .
The question stated: q and b are positive numbers but not positive integers.
so fractions are allowed to be a part of calculation.
So if the answer is C then the value 4.5 = 9/2 must comply the equation.
(9/2)^3 + b^3 = 75
so, b^3 = -129/8 , which is not possible according to the question.
Moreover the question didn't mentioninclusive or not, so we can't assume that b is 4 .
hi asif,
question is correct IMO.
Sincemaximumvalues areuniqueso you cant take any value and make it satisfy with equation
question is asking that maximum value ofa(means that unique value ofa) is between...
its not saying all value of that range will satisfy.
Question: A farmer wishes to start a 100 square metres rectangular vegetable garden. Since he has only 30 m barbed wire, he fences three sides of the garden letting his house compound wall act as the fourth side fencing. The dimension of the garden is:
A.15 m × 6.67 m
B.20 m × 5 m
C.30 m × 3.33 m
D.40 m × 2.5 m
Answer: B.20 m × 5 m
Explanation: We have : 2b + l = 30 ⇒ l = 30 – 2b.
Area = 100 m2 ⇒ l × b = 100 ⇒ b(30 – 2b) = 100
⇒ b2 – 15b + 50 = 0 ⇒ (b – 10)(b – 5) = 0
⇒ b = 10 or b = 5.
When b = 10, l = 10 and when b = 5, l = 20.
Since the garden is rectangular,
so its dimension is 20 m × 5 m.
Answer B
Question: Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds ?
A.11:9
B.11:20
C.9:20
D.11:8
Answer: A.11:9
Explanation: Explanation :
In the same time, they cover 110 km and 90 km respectively.
=> Ratio of their speeds = 110 : 90 = 11 : 9
Answer : A
Question: Oil is poured in a cylindrical barrel at a rate of 5 cubic meters per hour, the level of oil in the tank rises at a rate of 1 meters per hour. Which of the following best approximates the radius of the tank in meters?
A.√35/22
B.√10/3
C.4
D.5
Answer: A.√35/22
Explanation: Here's my re-worked solution:
volume = 5 = pi (r^2)(1)
5 = 22/7 (1)(r^2)
35/22 = r^2
r = sqrt(35/22)
Ans: A
Question: A tank is filled in 10 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
A.70 hours
B.30 hours
C.35 hours
D.50 hours
Answer: A.70 hours
Explanation: 1/A + 1/B + 1/C = 1/10 ( a, b and c 1 hour work)
given.. 1/B= 2/A and 1/C = 2/B = 4/A
hence 1/A + 2/A + 4/A = 1/10
on solving.... we get 1/A = 1/70 ( work done by A in 1 hour)
therefore time taken by A is 70 hours to finish the whole work
ANSWER:A
Question: In a sports club with 30 members, 17 play badminton and 17 play tennis and 2 do not play either. How many members play both badminton and tennis?
A.4
B.8
C.9
D.10
Answer: A.4
Explanation: Let x play both badminton and tennis so 17-x play only badminton and 19-x play only tennis. 2 play none and there are total 30 students. hence,
(17-x)+(17-x)+x+2=30
34-2x+x=30
34-x=30
x=4
So 4 members play both badminton and tennis.
A
Question: A train 146 m long is running at a speed of 98 kmph. How long does it take to pass a man who is running at 12 kmph in the same direction as the train?
A.6 sec
B.9 sec
C.12 sec
D.18 sec
Answer: A.6 sec
Explanation: Answer : A.
Speed of the train relative to man = (98 - 12) kmph
= (86* 5/18) m/sec = (215/9)m/sec
Time taken by the train to cross the man
= Time taken by It to cover 146 m at 219/9 m / sec = 146 *9/ 219 sec = 6sec
Question: A circular box kept around a circular place. If the difference between the circumference of the outer circle and the inner circle is 44m, find the width of the box?
A.6 m
B.9 m
C.10 m
D.7 m
Answer: D.7 m
Explanation: Let radius of the outer circle be R and radius of the inner circle be r.
Circumference of the outer circle =
Circumference of the inner circle =
But,
or, R - r =
Thus, width of the road = 7 m
D
Question: The soldiers of Ghost platoon want to call in some mortars on Taliban fighters shooting at them from a mud compound. The compound is 300m away at 5 deg (compass heading). Firebase Darvishan is 10 kilometers away at 290 deg from Ghost platoon. If the mortar shells are landing 100m directly east of the compound, how should Ghost platoon tell the gunnser at Firebase Darvishan to make corrections on their shots?
A.Drop 100.1M Right .27 deg
B.Drop 106.771M Right 3 deg
C.Drom 91.501M, Left .34 deg
D.Drop 99.918M Right .24deg
Answer: D.Drop 99.918M Right .24deg
Explanation: Drop 99.918M Right .24deg
Question: The sum of the first 40 positive even integers is 2,550. What is the sum of the odd integers from 101 to 200, inclusive?
A. 6,500
B. 7,500
C. 10,500
D. 15,000
Answer: A. 6,500
Explanation: 101+103+.......199
If we remove 100 from each of these it will be sum of 1st 100 odd numbers.
so 101+103+.......199 = 40 * 100 + (1+3+5+7+......)
sum of 1st 100 natural numbers = (100 * 101) / 2 = 5050
Sum of 1st 40 positive even integers = 2550
sum of 1st 100 odd numbers = 5050 - 2550 = 2500
so 101+103+.......199 = 40 * 100 + (1+3+5+7+......) = 4000 + 2500 =6500
A is the answer.
Question: It was calculated that 50 men could complete a piece of work in 10 days. When work was scheduled to commence, it was found necessary to send 25 men to another project. How much longer will it take to complete the work?
A.20 days.
B.15 days.
C.22 days.
D.30 days.
Answer: A.20 days.
Explanation: One day work = 1 / 10
One man’s one day work = 1 / ( 10 * 50)
Now:
No. Of workers = 25
One day work = 25 * 1 / ( 10 * 50)
The total no. of days required to complete the work = (50 * 10) / 25 = 20
Answer:A
Question: A retail appliance store priced a video recorder at 20 percent above the wholesale cost of $200. If a store employee applied the 25 percent employee discount to the retail price to buy the recorder, how much did the employee pay for the recorder?
A. $198
B. $216
C. $220
D. $180
Answer: D. $180
Explanation: Wholesale cost of video recorder = 200 $
Video recorder was priced at 20 percent above 200 = 240 $
% discount given by store employee = 25
Emlpoyee paid = .75 * 240 = 180 $
Answer D
Question: A room 5m 55cm long and 3m 74 cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor
A.176
B.170
C.160
D.179
Answer: A.176
Explanation: Let x and y be the sides of the rectangle. Then, Correct area = xy.
Area of the room = (544 x 374) cm2.
Size of largest square tile = H.C.F. of 544 cm and 374 cm = 34 cm.
Area of 1 tile = (34 x 34) cm2.
Number of tiles required =(544*374)/(34*34)=176
ANSWER A 176