RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The food in a camp lasts for 30 men for 40 days. If ten more men join, how many days will the food last?
A.11
B.30
C.99
D.88
Answer: B.30
Explanation: one man can consume the same food in 30*40 = 1200 days.
10 more men join, the total number of men = 40
The number of days the food will last = 1200/40 = 30 days.
Answer: B
Question: For how many integers n is 2^y = y^2 ?
A.None of these
B.One
C.Four
D.Three
Answer: A.None of these
Explanation: draw a graph with y^2 and 2^y, you'll see 3 intercepts between the 2 curves, but one is in the 2nd quadrant, so it can't be an integer (for integer values of x, 2^x can be an integer only for x>0). Thus 2 are valid, and the answer is A
Question: A man took loan from a bank at the rate of 12% p.a. S.I. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was?
A.15028
B.15029
C.15000
D.13029
Answer: C.15000
Explanation: Principal = (100 * 5400) / (12 * 3)
= Rs.15000
Answer: C
Question: Excluding stoppages, the speed of a train is 48 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour?
A.16
B.17
C.15
D.18
Answer: C.15
Explanation: T = 12/48 * 60
= 15
Answer: C
Question: The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:
A.13
B.33
C.23
D.43
Answer: C.23
Explanation: L.C.M. of 5, 6, 4 and 3 = 60.
On dividing 2497 by 60, the remainder is 37.
Number to be added = (60 - 37) = 23. Answer: Option 'C'
Question: A shopkeeper forced to sell at cost price, uses a 900 grams weight for a kilogram. What is his gain percent?
A.10%
B.9%
C.11.11%
D.12 %
Answer: C.11.11%
Explanation: Shopkeeper sells 900g instead of 1000g.
So, his gain = 1000 - 900 = 100g.
Thus, %Gain = (100 *100)/900 = 11.11%.
answer : OPTION C
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.120 m
B.240 m
C.300 m
D.120 m
Answer: B.240 m
Explanation: Speed = 54 x	5/18	m/sec = 15 m/sec.
Length of the train = (15 x 20)m = 300 m.Let the length of the platform be x metres.
Then,	9x + 3000/36	= 15
x + 300 = 540
x = 240 m. Answer: Option B
Question: If a coin is tossed 4 times what is the probability that it will land either heads 4 times or tails 4 times?
A.1/4
B.1/8
C.1/16
D.1/2
Answer: B.1/8
Explanation: The probability of 4 heads is (1/2)^4 = 1/16
The probability of 4 tails is (1/2)^4 = 1/16
The probability of 4 heads or 4 tails is 1/16 + 1/16 = 1/8
The answer is B.
Question: K-numbers are positive integers with only 2's as their digits. For example, 2, 22, and 222 are K-numbers. The K-weight of a number n is the minimum number of K-numbers that must be added together to equal n. For example, the K-weight of 50 is 5, because 50 = 22 + 22 + 2 + 2 + 2. What is the K-weight of 450?
A.5
B.11
C.12
D.13
Answer: A.5
Explanation: 450 = 2*222 + 3*2
K weight of 600 = 2 +3 = 5
AnswerA
Question: 69 laboratories raise the bacterium, the laboratory have 48 culture dishes on average, which has about 25,075 bacteria each. How many bacteria are there approximately?
A.10^7
B.10^8
C.10^9
D.10^10
Answer: A.10^7
Explanation: 69 laboratories raise the bacterium, the laboratory have 48 culture dishes on average, which has about 25,075 bacteria each. How many bacteria are there approximately?
A. 10^7
B. 10^8
C. 10^9
D. 10^10
E. 10^11
-> Due to approximately, 69=70, 48=50, 25,075=25,000 are derived, which makes (69)(48)(25,075)=(70)(50)(25,000)=10^7. The answer is A.
Question: A vending machine randomly dispenses four different types of fruit candy. There are twice as many apple candies as orange candies, twice as many strawberry candies as grape candies, and twice as many apple candies as strawberry candies. If each candy cost $0.5, and there are exactly 90 candies, what is the minimum amount of money required to guarantee that you would buy at least three of each type of candy?
A.$3.00
B.$20.75
C.$22.50
D.$41.50
Answer: D.$41.50
Explanation: Let number of Apple , Orange , strawberry and grape candies be A, O ,S and G respectively .
A= 2O
S= 2G
A= 2S
A= 4G
A+O+S+G = 90
=>A + A/2 + A/2 +A/4 = 90
=> 9A/4 = 90
=> A = 40
O = 20
S = 20
G = 10
Cost of each candy = .5 $
Mininum amount of money required to guarantee that you would buy at least three of each type of candy
We can buy 40 Apple candies , 20 orange candies , 20 strawberry candies and 3 grape candies to ensure atleast 3 of each type of candies .
Total = 83 candies
Amount required = 83 * .5 = 41.50 $
Answer D
Question: If Aug 15th,2012 falls on Thursday then June 11th,2013 falls on which day ?
A.Wednesday
B.Monday
C.SaturdaY
D.Tuesday
Answer: A.Wednesday
Explanation: Explanation:
First,we count the number of odd days for the left over days in the given period.
Here,given period is 15.8.2012 to 11.6.2013
Aug Sept Oct Nov Dec Jan Feb Mar Apr May Jun
16 30 31 30 31 31 28 31 30 31 11(left days)
2 + 2 + 3 + 2 + 3 + 3 + 0 + 3 + 2 + 3 + 4 (odd days) = 6 odd days
So,given day Thursday + 6 = Wednesday is the required result.
Answer: A) Wednesday
Question: At a certain committee meeting only associate professors and assistant professors are present. Each associate professor has brought 2 pencils and 1 chart to the meeting, while each assistant professor has brought 1 pencil and 2 charts. If a total of 10 pencils and 8 charts have been brought to the meeting, how many people are present?
A.6
B.7
C.8
D.9
Answer: A.6
Explanation: Say there are 'A' associate professors. So we have 2A pencils and A charts.
Say there are 'B' assistant professors. So we have B pencils and 2B charts.
Total pencils are 10 so 2A + B = 10
Total charts are 11 so A + 2B = 8
Add both: 3A + 3B = 18 so A + B = 6
Total number of people = 6
A
Question: When x is divided by y, the quotient is z with remainder r. Which of the following is y in terms of r, x, and z? (Assume both y and z are nonzero.)
A.x – r – z
B.(x+r)/z
C.x/z−r
D.(x−r)/z
Answer: D.(x−r)/z
Explanation: When x is divided by y, the quotient is z with remainder r. Which of the following is y in terms of r, x, and z? (Assume both y and z are nonzero.)
A. x – r – z
B. (x+r)/z
C. x/z−r
D. (x−r)/z
E. xr – z
Given that when x is divided y, the quotient is z and remainder is r. This implies x-r is divisible by y and yz=(x-r) or y = (x-r)/z.
Answer D.
Question: A bullet train leaves Kyoto for Tokyo traveling 240 miles per hour at 12 noon. Ten minutes later, a train leaves Tokyo for Kyoto traveling 160 miles per hour. If Tokyo and Kyoto are 320 miles apart, at what time will the trains pass each other?
A.12:40pm
B.12:49pm
C.12:52pm
D.1:00pm
Answer: C.12:52pm
Explanation: Train A: going from K to T
Train B: going from T to K
First I calculated how far Train A will have travelled by the time Train B starts at 12:10:
10 minutes at 240 mph
1/6*240=40miles
They have 320-40=280 miles to travel to meet each other.
I found the combined rate of the two trains
Rate(A) + Rate(B) = 400mph
Divide Distance/Rate to find total time each will travel:
280/400>>> 42 Minutes to meet
12:10+42 minutes = 12:52 or Answer C
Question: Each person who attended a company meeting was either a stockholder in the company, an employee of the company, or both. If 62 percent of those who attended the meeting were stockholders and 46 percent were employees, what percent were stockholders who were not employees?
A. 34%
B. 38%
C. 54%
D. 53%
Answer: C. 54%
Explanation: Let M represent the number of meeting attendees. Then, since 62% of M or 0.62M
were stockholders and 46% of M or 0.47M were employees, it follows that 0.62M +
0.46M = 1.08M were either stockholders, employees, or both. Since 1.08M exceeds
M, the excess 1.08M − M = 0.08M must be the number of attendees who were both
stockholders and employees, leaving the rest 0.62M − 0.08M = 0.54M, or 54%, of
the meeting attendees to be stockholders but not employees.
The correct answer is C.
Question: A portion of the 90% solution of chemicals was replaced with an equal amount of 20% solution of chemicals. As a result, 40% solution of chemicals resulted. What part of the original solution was replaced?
A.5/7
B.6/7
C.9/5
D.13/9
Answer: A.5/7
Explanation: This is a weighted average question. Say x% of the solution was replaced --> equate the amount of chemicals: 0.90(1-x)+0.2*x=0.4 --> x=5/7.
Answer: A.
Question: Two Trains starting at same time from two stations 320km apart and going in opposite directions cross each other at a distance of 140km from first stations. What is the ratio of their speeds
A.6:7
B.4:7
C.7:9
D.7:11
Answer: C.7:9
Explanation: Explanation:
As the two trains are starting at same time
Total distance is 320km
Crossed each other 140km from first stations
Therefore first train speed = 140kmph
And other one is 320-140 = 180kmph
Ratio of the two train speeds 140:180 = 7:9
Answer: Option C
Question: Which of the following is closer to (9!+8!)-(9!-8!)?
A.80460
B.80640
C.80540
D.80440
Answer: B.80640
Explanation: 9!+8!)-(9!-8!)=362880+40320-362880+40320
= 80640
Answer: B
Question: A certain boxer has agreed to pay his opponent a fee of 3% of his total purse for every pound over the specified weight limit he weighs in. If the boxer pays his opponent a fee of $26,250 after weighing in seven pounds over the specified limit, what was the boxer's purse?
A.$65,625
B.$105,000
C.$125,000
D.$183,750
Answer: C.$125,000
Explanation: .03*7 = .21
26250/.21 = $125,000
Answer: C
Question: What number is that, to which if 1, 5, and 13, be severally added, the first sum shall be to the second, as the second to the third?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: Solution
Let x= the number required.
By the conditions, x+1:x+5 = a+5:x+13
Subtracting terms, (Art. 385,2.) x+1:4 = x+5:8
Therefore 8x+8 = 4x+20. And x = 3.
Answer C
Question: A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs.8.40 less, he would have gained 30%. Find the cost of the article.
A.30
B.40
C.50
D.60
Answer: B.40
Explanation: Let C.P=100
Gain=25%
S.P=125
Supposed C.P=80
Gain=30%
S.P=(130*80)/100=104
Diff=(125-104)=21
Diff 21 when C.P=100
then Diff 8.40 when C.P=(100*8.40)/21=40
ANSWER:B
Question: Find the least number which when divided by 12,24,36,42 leaves remainder 9,21,33,39 respectively.
A.499
B.501
C.452
D.365
Answer: B.501
Explanation: The difference of 12-9 = 3 , 24-21 = 3 , 36-33= 3 , 42-39 = 3
LCM of 12,24,36,42 = 504
Required number = 504 - 3 = 501
Answer is B
Question: Shweta buys a product at 25% discount rate. At what % over the cost price should she sell the product to make an overall 25% profit over the listed price?
A.25
B.33.333
C.66.667
D.40
Answer: C.66.667
Explanation: Explanation:
Let listed price of the product be x
Hence at 25% discount rate the Cost Price will become: 3x/4
Now to make an overall profit of 25% over listed price:
SP = CP+(25/100)CP
=> SP = x+x/4
=>SP = 5x/4
=>Selling Price over Cost price: (5x/4)-(3x/4)
=>x/2
=>%Selling price over Cost price: (x/2)/(3x/4)*100
=>66.67%
ANSWER C
Question: When n is divided by 24, the remainder is 3. Find thee difference between previous remainder and the remainder when 9n is divided by 7 ?
A.2
B.7
C.5
D.3
Answer: D.3
Explanation: Let n=3 (leaves a remainder of 3 when divided by 24)
9n = 9(3) =27, which leaves a remainder of 6 when divided by 7.
difference = 6 - 3 = 3.
Answer D
Question: Peter age after 5 years will be 5 times his age 5 years back. what is the present age of Peter?
A.A)20
B.B)25
C.C)15
D.D)22
Answer: A.A)20
Explanation: Peter present age= x
after 5 years = x+5
5 years back = x-5
x+5= 5(x-5)
x=20
Answer is A
Question: A reduction of 20% in the price of salt enables a lady to obtain 10kgs more for Rs.100, find the original price per kg?
A.Rs.2.8
B.Rs.2.4
C.Rs.2.5
D.Rs.2.2
Answer: C.Rs.2.5
Explanation: 100*(20/100) = 20 --- 10
? --- 1 => Rs.2
100 --- 80
? --- 2 => Rs.2.5
Answer:C
Question: What will be the output of the following code statements?
Integer a = 15, b = 30, c = 10 print (a × b / c) – c
A.35
B.26
C.29
D.26
Answer: A.35
Explanation: Explanation:
Apply BODMAS rule
15 × 30 = 450/10-10 =45 –10 =35
Answer:A
Question: A factory producing tennis balls stores them in either big boxes, 25 balls per box, or small boxes, 20 balls per box. If 126 freshly manufactured balls are to be stored, what is the least number of balls that can be left unboxed?
A.2
B.4
C.1
D.5
Answer: C.1
Explanation: We have to work with multiples of 20 and 25.
First, we must know the limits of this multiples, so:
126/25= 5....so the max is 5
126/20=6...so the max is 6
126-125 =1 (5 big box or 5 small box +1 big box)
Answer : C
Question: My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was bom. If my sister was 4 years of age when my brother was born, then, what was the age of my father and mother respectively when my brother was born?
A.32 yrs, 23 yrs
B.32 yrs, 29 yrs
C.35 yrs, 29 yrs
D.35 yrs, 33 yrs
Answer: A.32 yrs, 23 yrs
Explanation: Solution
Clearly,my mother was born 3 years before I was born and 4 years after my sister was born.
So, father's age when brother was born	=(28+4)
= 32 years.
mother's age when brother was born	=(26 - 3)
= 23 years.
Answer A
Question: How many 4 digit numbers are there, if it is known that the first digit is even, the second is odd, the third is prime, the fourth (units digit) is divisible by 3, and the digit 7 can be used only once?
A.20
B.150
C.304
D.310
Answer: C.304
Explanation: 4 options for the first digit: 2, 4, 6, 8;
5 options for the second digit: 1, 3, 5, 7, 9;
4 options for the third digit: 2, 3, 5, 7;
4 options for the fourth digit: 0, 3, 6, 9.
Four digit # possible without the restriction (about the digit 2): 4*5*4*4=320
Numbers with seven 7-s,7X7X 4*1*1*4=16.
Thus there are 320-16=304 such numbers.
Answer: C.
Question: Two pipes A and B can fill a tank is 8 minutes and 14 minutes respectively. If both the taps are opened simultaneously, and the tap A is closed after 3 minutes, then how much more time will it take to fill the tank by tap B?
A.6 min 45 sec
B.5 min 45 sec
C.2min 45 sec
D.5 min 55 sec
Answer: B.5 min 45 sec
Explanation: Part filled by pipe A in 1 minute = 18
Part filled by pipe B in 1 minute = 1/14
Part filled by pipe A and pipe B in 1 minute = 1/8+1/14=11/56
Pipe A and pipe B were open for 3 minutes
Part filled by pipe A and pipe B in 3 minutes = (3×11)/56=33/56
Remaining part = 1−(33/56)=23/56
Time taken by pipe B to fill this remaining part =(23×14)/56=23/4 minutes= 5 minutes 45 seconds
Answer is B
Question: Employees at a company will vote for an executive team of five people from eight qualified candidates. The executive team consists of a president, a treasurer, and three warrant officers. If an executive team is considered different if any of the same people hold different offices, then how many possible executive teams G could be selected from the eight candidates?
A.56
B.120
C.210
D.1120
Answer: D.1120
Explanation: If an executive team is considered different if any of the same people hold different offices,....
so you will not have answer as 6720..
president could be by any of 8 person..
treasurer could be any out of remaining 7 person..
remaining three order does not matter, so we have to choose 3 out of 6=6c3=20..
total ways G= 8*7*20=1120..
ans D...
Question: The probability that a visitor at the mall buys a pack of candy is 50%. If three visitors come to the mall today, what is the probability that exactly two will buy a pack of candy?
A.0.225
B.0.25
C.0.325
D.0.375
Answer: D.0.375
Explanation: One case is: candy - candy - no candy
The probability is 5/10*5/10*5/10 = 125/1000
There are 3 such cases, so we should multiply this probability by 3.
P(exactly 2 buy candy) = 125/1000 * 3 = 375/1000 = 0.375
The answer is D.
Question: A person has undertaken a construction job. The probabilities are 0.65 that there will be strike, 0.8 that the job will be completed on time if there is no strike, 0.32 that the job will be completed on time. If there is a strike. Determine the probability that the job will be completed on time.
A.0.488
B.0.485
C.0.486
D.0.458
Answer: A.0.488
Explanation: Assume A = There will be a strike
B = Construction Job will be completed on time
P(A) = 0.65 and P(A1)P(A1) = 1 - 0.65 = 0.35
P(B|A) = 0.32 and P(B|A1)=0.8
P(B)=P(A).P(B|A)+P(A1).P(B|A1)
= 0.65×0.32+0.35×0.8=0.488
Answer A
Question: In a company with 48 employees, some part-time and some full-time, exactly (1/3) of the part-time employees and (1/4) of the full-time employees take the subway to work. What is the greatest possible number W of employees who take the subway to work?
A.12
B.13
C.14
D.15
Answer: D.15
Explanation: P/3 + F/4 = P/3 + (48-P)/4 = 12 + P/2
P/3 + F/3 = (P+F)/3 = 48/3 = 16
P/4 + F/4 = 12
P/3 + F/3 > P/3 + F/4 > P/4 + F/4
--> 16> 12 + P/12 > 12
GREATEST Possible W: 12 + p/12 = 15 --> p = 36 ( integer --> good)
15 or D is the answer
Question: In a garments industry, a loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metre of cloth ?
A.194 sec
B.195 sec
C.196 sec
D.200 sec
Answer: B.195 sec
Explanation: Explanation :
Let the time required by x seconds.
Then, More cloth means More time (Direct Proportion)
So,
0.128 : 1 :: 25 : x
=> x = 25 * 1/0.128
=> x = 195.31
So time will be approx 195 seconds
Answer : B
Question: A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?
A.12
B.16
C.18
D.24
Answer: B.16
Explanation: Explanation:
Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 48 3x = 48 x = 16.
Answer:B
Question: If a:b=2:8 and b:c=3:4 find a:b:c?
A.3:12:16
B.12:3:6
C.6:12:3
D.4:3:14
Answer: A.3:12:16
Explanation: a:b = 2:8, b:c = 3:4
2:8
3:4
(a = a × b, b = b × b and c = b × c)
a:b:c = 3:12:16
A
Question: How many times will the digit 4 be written when listing the integers from 1 to 1000?
A.512
B.300
C.294
D.264
Answer: B.300
Explanation: Many approaches are possible. For example:
Consider numbers from 0 to 999 written as follows:
1. 000
2. 001
3. 002
4. 003
...
...
...
1000. 999
We have 1000 numbers. We used 3 digits per number, hence used total of 3*1000=3000 digits. Now, why should ANY digit have preferences over another? We used each of 10 digits equal # of times, thus we used each digit (including 4) 3000/10=300 times.
Answer: B.
Question: Find the odd man out
385, 462, 572, 427, 671, 264
A.385
B.427
C.671
D.264
Answer: B.427
Explanation: add 1st and 3rd term nd get mid term
3+5 = 8
4+2 = 6
5+2 = 7
4+7 = 11
6+1 = 7
2+4 = 6
ANSWER:B
Question: A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangule, whose length and breadth are in the ratio of 6 : 5. What is the area of the rectangle?
A.276
B.30
C.88
D.266
Answer: B.30
Explanation: The circumference of the circle is equal to the permeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=> x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm2
Answer:B
Question: If x - y =1 and
x2+y2=25
, find the value of ab.
A.8
B.12
C.16
D.32
Answer: B.12
Explanation: Explanation:
We know
2ab=(a2+b2)âˆ’(aâˆ’b)2
2xy=25âˆ’1=24
=>xy=12
OptionB
Question: A broker invested her own money in the stock market. During the first year, she increased her stock market wealth by 80 percent. In the second year, largely as a result of a slump in the stock market, she suffered a 30 percent decrease in the value of her stock investments. What was the net increase or decrease on her overall stock investment wealth by the end of the second year?
A.−5%
B.5%
C.15%
D.26%
Answer: D.26%
Explanation: The actual answer is obtained by multiplying 180% by 70% and subtracting 100% from this total. That is: 180% × 70% = 126%; 126% − 100% = 26%.
Answer: D
Question: There are cats got together and decided to kill the mice of 999936. Each cat kills equal number of mice and each cat kills more number of mice than cats there were. Then what are the number of cats?
A.941,1009
B.991,1001
C.991,1009
D.992,1008
Answer: D.992,1008
Explanation: 999936 can be written as 1000000 â€“ 64
= 10002 â€“ 82 ie of the form a2-b2=(a+b)(a-b)
=(1000+8)*(1000-8)
= (1008)*(992)
Given that number of cats is less than number if mice.
So number of cats is 992 and number of mice were 1008
Answer D
Question: The distance between X&Y is 600km. A person is traveling from X to Y at 60km/hr started at 10AM and another person is traveling from Y to X at 40km/hr and started at same time. Then at what time they meet together.?
A.A)2PM
B.B)4PM
C.C)1PM
D.D)3PM
Answer: B.B)4PM
Explanation: Let x hours be they will meet together
distance covered by 1st person+distance covered by 2nd person = 600km
60x+40x = 600
x= 6 hr
They will meet = 10AM +6hr = 4PM
Answer is B
Question: Double of Quarter of 3 percent written as a decimal is :
A.0.003
B.0.015
C.0.25
D.0.005
Answer: B.0.015
Explanation: Explanation :
Solution: (2)*(1/4)*3% = 2*(1/4 * 3/100) = 0.015.
Answer : B
Question: A person travels from P to Q a speed of 60 km/hr and returns by increasing his speed by 20%. What is his average speed for both the trips?
A.33
B.77
C.48
D.66
Answer: D.66
Explanation: Speed on return trip = 120% of 60 = 72 km/hr.
Average speed of trip = 60 + 72 /2 = 132/2 = 66 km/hr
Answer : D
Question: The least number which should be added to 3725 so that the sum is exactly divisible by 5, 6, 4 and 3 is?
A.45
B.55
C.65
D.75
Answer: B.55
Explanation: L.C.M. of 5, 6, 4 and 3 = 60.
On dividing 3725 by 60, the remainder is 5.
Number to be added = (60 - 5) = 55
B)
Question: A train 360 m long is running at a speed of 45 km / hr. In what time will be pass a bridge 140 m long?
A.40 sec
B.42 sec
C.45 sec
D.48 sec
Answer: A.40 sec
Explanation: Sol.
Speed = [45x5/18] m/sec = 25/2 m/sec.
Total distance covered = (360 + 140) m = 500 m.
∴ Required time = (500 x 2/25)sec = 40 sec.
Answer A
Question: The concentration of spirit in three different vessels A, B and C are 45%, 30% and 10% respectively. If 4 litres from vessel A, 5 litres from vessel B and 6 litres from vessel C are mixed, find the concentration of spirit in the resultant solution.
A.26%
B.33%
C.34%
D.35%
Answer: A.26%
Explanation: Quantity of spirit in new solution=(4*45/100)+(5*30/100)+(6*10/100)=1.8+1.5+0.6=3.9 liters
So % concentration of spirit=100*3.9/(4+5+6)=26%
ANSWER:A
Question: A water tank has two pipes to fill water in it. One of the pipes fills water at the rate of 100 litres per hour. The tank is filled by the other pipe in 6 hours and by both pipes together in 4.2 hours. What is the capacity of the tank in litres ?
A.860 litre
B.980 litre
C.1120 litre
D.1400 litre
Answer: D.1400 litre
Explanation: Explanation:
Let the time taken by the 1st pipe to fill the tank be x hours.
When both the pipes are open, it is given that:
1/x + 1/6 = 1/(4.2) of tank is filled in 1 hour.
1/x + 1/6 = 5/21
21(6 + x) = 30 x
9x = 126
x = 14 hours
Therefore, capacity of the tank = 100 * 14 = 1400 litres.
ANSWER D
Question: A bowl was filled with 10 ounces of water, and 0.00008 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period?
A.0.004%
B.0.04%
C.0.40%
D.4%
Answer: B.0.04%
Explanation: Total amount of water evaporated each day during a 50-day period = .00008 * 50
=.00008 * 100/2
= .008/2
= .004
percent of the original amount of water evaporated during this period = (.004/10) * 100%
= 0.04 %
Answer B
Question: How many 4-letter words can be formed using the letters of the English alphabet that contain 2 different vowels and 2 different consonants?
A.4!*5c2 *21c2
B.5P2 * 21P3 * 5!
C.5C2 * 21C3 * 5!
D.5P2 * 21P3
Answer: A.4!*5c2 *21c2
Explanation: combination for 2 vowels out of 5 =5c2 ways
combination for 2 consonants of 21 = 21c2 ways
Additionally the arrangement can be = 4!
total arrangements =4!*5c2 *21c2
A