RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: On a journey across Bombay, a tourist bus averages 10 km/h for 20% of the distance, 30 km/h for 60% of it and 20 km/h for the remainder. The average speed for the whole journey was
A.10 km/h
B.30 km/h
C.5 km/h
D.20 km/h
Answer: D.20 km/h
Explanation: explanation
Let the average speed be x km/h.
and Total distance = y km. Then,
0.2⁄10y + 0.6⁄30y + 0.2⁄20y = y⁄x
⇒ x = 1⁄0.05 = 20 km/h
Answer D
Question: If a tire rotates at 400 revolutions per minute when the car is traveling 24km/h, what is the circumference of the tire?
A.1 meters
B.9 meters
C.8 meters
D.5 meters
Answer: A.1 meters
Explanation: 400 rev / minute = 400 * 60 rev / 60 minutes
= 24,000 rev / hour
24,000 * C = 24,000 m : C is the circumference
C = 1 meters
correct answer A
Question: What is the remainder when 3^33 is divided by 5?
A.0
B.1
C.2
D.3
Answer: D.3
Explanation: The units digit of powers of 3 follow a repeating cycle of four: {3, 9, 7, 1}
33 has the form 4k+1, so the units digit of 3^33 is 3.
The remainder when dividing by 5 is 3.
The answer is D.
Question: Three numbers are in the ratio 3:5:7. The largest number value is 42. Find difference between Smallest & largest number is?
A.difference=24
B.26
C.28
D.30
Answer: A.difference=24
Explanation: == 3:5:7
Total parts = 15
= The largest number value is 42
= The largest number is = 7
= Then 7 parts -----> 42 ( 7 * 6 = 42 )
= smallest number = 3 & Largest number = 7
= Difference between smallest number & largest number is = 7 - 3 = 4
= Then 4 parts -----> 24 (4 * 6 = 24)
A
Question: A man in a train notices that he can count 21 telephone posts in one minute.If they are known to be 50 meters apart , then at what speed is the train travelling ?
A.55 km/hr
B.57 km/hr
C.60 km/hr
D.63 km/hr
Answer: C.60 km/hr
Explanation: Solution
Number of gaps between 21 telephone posts = 20.
Distance travelled in 1 minute =(50x20)m = 1000 m = 1 km.
∴ Speed = 60 km/hr.
Answer C
Question: Prove the theorem, due to Kraitchik, asserting that 13|2^70+3^70
A.1^70+3^70 == 0 (mod 13), or 1|2^70+3^70
B.2
C.1
D.2^70+3^70 == 0 (mod 13), or 13|2^70+3^70
Answer: D.2^70+3^70 == 0 (mod 13), or 13|2^70+3^70
Explanation: By Fermat's theorem we have 2^12 == 1 (mod 13), hence 2^60 == 1 (mod 13), and since 2^5 == 6 (mod 13), which implies 2^10 == -3 (mod 13), we get 2^70 == -3 (mod 13). On the other hand, 3^3 == 1 (mod 13), hence 3^69 == 1 (mod 13) and 3^70 == 3 (mod 13). Therefore 2^70+3^70 == 0 (mod 13), or 13|2^70+3^70, which was to be proved.
So Answer is D 2^70+3^70 == 0 (mod 13), or 13|2^70+3^70
Question: If selling price is doubled, the profit triples. Find the profit percent
A.128%
B.100%
C.126%
D.276%
Answer: B.100%
Explanation: Explanation:
Let C.P. be Rs. x and S.P. be Rx. y.
Then, 3(y - x) = (2y - x) => y = 2x
Profit = (y - x) = Rs. (2x - x) = Rs. x
Profit % = x/x * 100 = 100%
.Answer:B
Question: 10 one question was x*y^2*z<0 then
A.x<0
B.xyz<0
C.xz<0
D.xy<0
Answer: C.xz<0
Explanation: if we take y^2 then it will always greater than zero so only one option z left i.e. xz
ANSWER:C
Question: How long does a train 165 meters long running at the rate of 36 kmph take to cross a bridge 660 meters in length?
A.82.5
B.27
C.55
D.18
Answer: A.82.5
Explanation: T = (660 + 165)/36 * 18/5
T = 82.5
Answer: A
Question: Which of the following is an irrational numbers?
A.√16
B.√25
C.√45
D.√64
Answer: C.√45
Explanation: Clearly √45 is an irrational number. Ans : C
Question: A bakery opened yesterday with its daily supply of 50 dozen rolls. Half of the rolls were sold by noon, and 84 percent of the remaining rolls were sold between noon and closing time. How many dozen rolls had not been sold when the bakery closed yesterday?
A. 5
B. 4
C. 3
D. 2
Answer: B. 4
Explanation: answer is B ...4 dozens ....
half sold by noon --> 25 dozens (25 *12 =300)
remaining --> 25 dozens i.e 300 eggs...
84% sold --> 84*300/100 =252 eggs
remaining 16% --> 48 eggs (4 dozens ) --> answer
Question: A certain fruit stand sold apples for $0.70 each and cherry for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ?
A.12
B.11
C.13
D.14
Answer: B.11
Explanation: Some multiple of 7 + Some multiple of 5 should yield 63. To get to a some multiple of 5, we should ensure that a 3 or 8 (5+3) should be a multiple of 7.
63 is a direct multiple of 7, however in this case there won't be any cherry. Hence the next option is to look for a multiple of 7 that has 8 as the unit digit. 28 satisfies this hence no. of apples is 4 and no of bananas is 7
B
Question: Three flats of the same type were advertised to be let in a housing complex. Three men made separate applications for a flat. What is the probability that each of them applied for the same house.
A.1/4
B.1/5
C.1/6
D.1/3
Answer: D.1/3
Explanation: Since each of the flat has same probability of getting selected so for each men proability of selecting a flat out of 3 flats
Let us consider case where all 3 men choose flat no 1
So for First men it will be 1/3,second men 1/3 and third men also 1/3
So probability of selecting flat no 1 is 1/3*1/3*1/3= 1/27
And since there are 3 such flats so probability that each men select the same flat is 3*1/27 or 1/9
Ans is D
Question: Today is Thursday. A person wants to meet a lawyer and as that lawyer is busy he asks him to come three days after the before day of the day after tomorrow? On which day the lawyer asks the person to come?
A.SUNDAY
B.MONDAY
C.TUESDAY
D.WEDNESDAY
Answer: B.MONDAY
Explanation: Today is Thursday
after three days--->Sunday
now, (sunday)after before day--->saturday
then, (saturday)day after tomorrow--->monday
ANSWER:B
Question: Mapy bought shares for a total value of $1000. Next day, the price of shares is reduced by 10%. With the same $1000, he could now buy 10 more shares. Which of the following is closest to the original price per share?
A.$10
B.$11
C.$12
D.$13
Answer: B.$11
Explanation: From the given information,we can conclude that Mapy bought x number of shares for $1000. With a 10% reduction in price, he could buy the same x number of shares for 1000*.90 = $900 . With the remaining money ($1000 - $900 = $100), he can buy 10 more shares. So, the reduced price per share = $100/10 = $10.
Therefore, if the reduced price of $10 equals the original price * 9/10, then the original price is approximately $11=B
Question: Students are asked to create a record of the recital of a poem for English class in groups of three. The tape length should be 1,200 seconds. The students assigned different stanzas of the poem to each member, and the individual records were compiled. If member three took 3 times longer than member two, and member two took equal time as member one, how many seconds did member three record for his/her reading?
A.720
B.240
C.1200
D.40
Answer: A.720
Explanation: member one, two and three as m1, m2 and m3 respectively.
m2=m1 as eq.a
m3=m2*3 as eq.b
m3+m2+m1=1,200 as eq.c
Substitute eq.b into eq. c, making (m2*3) + m2+ m2=1,200
(m2*5)/5=1,200/5 reduces to m2=240 seconds.
m3 is then m2*3, which is 720 seconds.
Answer is A.
Question: There are 7 teams in a certain league and each team plays each of the other teams exactly twice. If each game is played by 2 teams, what is the total number of games played?
A.15
B.16
C.28
D.42
Answer: D.42
Explanation: Every team plays with 6 teams...so total no of matches = 7 x 6 = 42.
Now, each match is played twice => 42 x 2
But 2 teams play a match => 42 x 2 /2 = 42.
Answer: D
Question: The percentage increase in the area of rectangle , if each of its side is increased by 10% is?
A.21%
B.30%
C.25%
D.40%
Answer: A.21%
Explanation: Let original length = x meters
original breadth = y meters
original area = xy m^2
New length = 110x/100
New breadth = 110y/100 = 11y/10
New area = 11x/10 * 11y/10 = 121xy/100 m^2
Increase percent = 21xy/100 * 1/xy *100 = 21%
Answer is A
Question: The sum of the digits of a two-digit number is 15 and the difference between the digits is 3. What is the two-digit number?
A.38
B.37
C.22
D.69
Answer: D.69
Explanation: Let the ten's digit be x and unit's digit by y
Then, x + y = 15 and x - y = 3 or y - x = 3
Solving x + y = 15 and x - y = 3, we get: x = 9, y = 6
Solving x + y = 15 and y - x = 3, we get: x = 6, y = 9
So, the number is either 96 or 69.
Hence, the number cannot be determined.
Answer: D
Question: If 50% of (x-y) = 30% of (x+y), then what percent of x is y?
A.20%
B.30%
C.25%
D.15%
Answer: C.25%
Explanation: 50% of (x-y) = 30% of (x+y)
50/100 (x-y) = 30/100 (x+y)
x = 4y
Required percentage = y/x *100 = y/4y * 100 = 25%
Answer is C
Question: The average of five results is 46 and that of the first four is 45. The fifth result is?
A.22
B.02
C.78
D.50
Answer: D.50
Explanation: 5 * 46 – 4 * 45 = 50
Answer: D
Question: The difference between two numbers 1365.When the larger
number is divided by the smaller one the quotient is 6 and
the remainder is 15.The smaller number is?
A.270
B.170
C.230
D.130
Answer: A.270
Explanation: Let the smaller number be x, then larger number =1365+x
Therefore 1365+x=6x+15
5x=1350 => x=270
Required number is 270.
ANSWER A 270
Question: Find the perimeter and area of a square of side 11 cm.
A.11 cm²
B.81 cm²
C.121cm²
D.144 cm²
Answer: C.121cm²
Explanation: We know that the perimeter of square = 4 × side
Side= 11 cm
Therefore, perimeter = 4 × 11 cm = 44 cm
Now, area of the square = (side × side) sq. units
= 11 × 11 cm²
= 121 cm²
ANSWER : C
Question: Tim and Stacy need to select seats in a row of chairs that are numbered in order from 1 to 5. If Tim cannot sit in an even-numbered seat and Stacy cannot sit in an odd-numbered seat, how many arrangements are possible if the two cannot sit adjacent to each other and Tim and Stacy are the only people to be seated?
A.1
B.2
C.3
D.5
Answer: B.2
Explanation: The total number if there is no restriction is = 2X3= 6
and if both are sitting together, the combination is = 2X2= 4
So, the way they can not sit together is 6-4=2
ANSWER:B
Question: A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 36 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d ?
A. 16%
B. 32%
C. 68%
D. 84%
Answer: C. 68%
Explanation: This is easiest to solve with a bell-curve histogram. m here is equal to µ in the Gaussian normal distribution and thus m = 50% of the total population.
So, if 36% is one st.Dev, then on either side of m we have 36/2 = 18%. So,18% are to the right and left of m (= 50%). In other words, our value m + d = 50 + 18= 68% goingfrom the mean m, to the right of the distributionin the bell shaped histogram.. This means that 68% of the values are below m + d.
Like I said, doing it on a bell-curve histogram is much easier to fullygethow this works, or you could apply GMAT percentile jargon/theory to it
C
Question: A can do a certain job in 14 days. B is 60% more efficient than A. How many days does B alone take to do the same job?
A.7 1/2 days
B.8 3/4 days
C.5 days
D.9 days
Answer: B.8 3/4 days
Explanation: Ratio of times taken by A and B = 160 : 100 = 8 : 5.
Suppose B alone takes x days to do the job.
Then, 8 : 5 :: 14 : x = 8x = 5 x 14 =x = 8 3/4 days.
Answer is B.
Question: The cross-section of a water channel is a trapezium in shape. If the channel is 12 meters wide at the top and 6 meters wide at the bottom and the area of cross-section is 630 square meters, what is the depth of the channel (in meters)?
A.50
B.60
C.70
D.80
Answer: C.70
Explanation: 1/2 * d * (12 + 6) = 630
d = 70
The answer is C.
Question: Set J consists of 18 consecutive even numbers. If the smallest term in the set is -12, what is the range of the positive integers in set J?
A.16
B.18
C.20
D.22
Answer: C.20
Explanation: Since there are only 18 integers, another approach is the just list all 18.
We get:-12, -10, -8, -6, -4, -2,0,2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22
Range of POSITIVE INTEGERS =22 - 2= 20
Answer: C
Question: Abbey has $460 in 5-and 10-dollar bills only. If she has fewer 10-than 5-dollar bills, what is the least possible number of 5-dollar bills she could have?
A. 32
B. 30
C. 29
D. 28
Answer: A. 32
Explanation: 5c + 10d= 460
c > d
Pick an easy number to work with.
suppose c=30.
Then you have 150.
You need another 310 and that means you need d=31 which is greater than c.
Therefore, c > 30.
The only answer choice where c > 30 is if c = 32.
A is the answer.
Question: In the xy-coordinate system, what is the slope of the line that goes through the point (1, 1) and is equidistant from the two points P = (3, 7) and Q = (9, 11)?
A.0.5
B.0.625
C.0.75
D.0.875
Answer: B.0.625
Explanation: First, get the middle coordinate between (3,7) and (9,11)...
x = 3 + (9-3)/2 = 6
y = 7 + (11-7)/2 = 9
Second, get the slope of (9,6) and (1,1). m = 6-1 / 9-1 = 5/8 = 0.625
Answer: B
Question: A tank has a capacity of 20 gallons and is full of spirit. 4 gallons of spirit is drawn out and the container is again filled with water. This process is repeated 5 times. Find how much spirit is left in the resulting mixture finally?
A.6(257/525) gallons
B.20(346/625) gallons
C.6.5 gallons
D.6.25 gallons
Answer: B.20(346/625) gallons
Explanation: There is a direct formula to calculate such repetition:
Left QTY / Orig QTY = ( (Orig QTY - Rep QTY) / Orig QTY )^n
where n is number of times mixing done:
Left QTY / 20 = (20 -4)^5 / 20^5
Left QTY = 20 (16/20)^5
Left QTY = 20 ( 4/5 )^5
Left QTY = 20(346/625)
Answer is B
Question: A club with a total membership of 30 has formed 3 committees, M, S and R, which have 8, 12 and 5 members respectively. If no members of committee M is on either of the other 2 committees, what is the greatest possible number of members in the club who are on none of the committees?
A.5
B.7
C.8
D.10
Answer: D.10
Explanation: {total} = {M} + {S} + {R} - {Both} + {Neither}
We want to maximize Neither, so Both has to be as large as possible. The max of {Both} is 5 because {R} = 5.
30 = 8 + 12 + 5 - 5 + Neither
Neither = 10
ANSWER:D
Question: N and M are each 3-digit integers. Each of the numbers 2, 3,4,5, 6, and 7 is a digit of either N or M. What is the smallest possible positive difference between N and M?
A.59
B.49
C.58
D.113
Answer: B.49
Explanation: You have 6 digits: 2, 3, 4, 5, 6, 7
Each digit needs to be used to make two 3 digit numbers. This means that we will use each of the digits only once and in only one of the numbers. The numbers need to be as close to each other as possible. The numbers cannot be equal so the greater number needs to be as small as possible and the smaller number needs to be as large as possible to be close to each other.
The first digit (hundreds digit) of both numbers should be consecutive integers
Now let's think about the next digit (the tens digit). To minimize the difference between the numbers, the tens digit of the greater number should be as small as possible and the tens digit of the smaller number should be as large as possible . So let's not use 2 and 7 in the hundreds places and reserve them for the tens places . Now what are the options?
Try and make a pair with (3** and 4**). Make the 3** number as large as possible and make the 4** number as small as possible.
376 and 425 (difference is 49) or
Try and make a pair with (5** and 6**). Make the 5** number as large as possible and make the 6** number as small as possible. We get 574 and 623 (difference is 49)
B
Question: A baseball team won 45 percent of the first 80 games it played. How many of the remaining 85 games will the team have to win in order to have won exactly 40 percent of all the games it played?
A.30
B.45
C.50
D.55
Answer: A.30
Explanation: Games won out of first 80 questions = (45/100)*80 = 36
Total Games = 80+85 = 165
Games to be won = (40/100)*165 = 66
Remaining games to be won = 66-36 = 30
Answer: Option A
Question: A person decided to build a house in 100 days. He employed 100 men in the beginning and 100 more after 20 days and completed the construction in stipulated time. If he had not employed the additional men , how many days behind schedule would it have been finished?
A.40
B.80
C.70
D.60
Answer: D.60
Explanation: 200 men do the rest of the work in 100-40 = 60 days
100 men can do the rest of the work in 60*200/100 = 120 days
Required number of days = 120-60 = 60 days
Answer is D
Question: The CI on a certain sum for 2yrs at 10 percent/annum is Rs. 525. The SI on the same sum for double the time at 1/2 the rate % per annum is:
A.Rs. 100
B.Rs. 300
C.Rs. 400
D.Rs. 500
Answer: D.Rs. 500
Explanation: Let the sum be Rs. P.
Then, P 1 +	10 2	- P = 525
100
P 11 2	- 1 = 525
10
P = 525 x 100 = 2500.
21
Sum = Rs . 2500.
So, S.I. = Rs. 2500 x 5 x 4 = Rs. 500
100
D
Question: The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. What is the average of the remaining two numbers ?
A.4.9
B.4.6
C.4.1
D.4.2
Answer: B.4.6
Explanation: Explanation:
Sum of the remaining two numbers = (3.95 * 6) - [(3.4 * 2) + (3.85 * 2)]
= 23.70 - (6.8 + 7.7) = 23.70 - 14.5 = 9.20.
Required average = (9.2 / 2) = 4.6.
Answer: B
Question: The difference between compound interest and simple interest on a certain amount of money at 5% per annum for 2 years is 18. Find the sum :
A.4500
B.7500
C.5000
D.7200
Answer: D.7200
Explanation: Sol.(d) Let the sum be 100.
Therefore, SI = 100×5×2100=10100×5×2100=10
and CI = 100(1+5100)2−100100(1+5100)2−100
∴ =100×21×2120×20−100=414=100×21×2120×20−100=414
Difference of CI and SI = 41⁄4 - 10 = 1⁄4
If the difference is 1⁄4 , the sum = 100
=> If the difference is 18, the sum
= 400 × 18 = 7200 Answer D
Question: Two numbers have a H.C.F of 20 and a product of two numbers is 2560. Find the L.C.M of the two numbers?
A.140
B.150
C.160
D.128
Answer: D.128
Explanation: L.C.M of two numbers is given by
(Product of the two numbers) / (H.C.F of the two numbers) = 2560/20 = 128.
ANSWER:D
Question: Out of 10 persons working on a project, 5 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?
A.A)5/7
B.B)5/12
C.C)5/1
D.D)1/12
Answer: D.D)1/12
Explanation: P(at least one graduate) = 1 - P(no graduates)
= 1 - 5C₃/¹⁰C₃
= 1 - (3 * 5 * 4)/(10 * 9 * 8)
= 1/12
Answer:D
Question: If the probability W of rain on any given day in city x is 50% what is the probability it with rain on exactly 3 days in a five day period?
A.8/125
B.2/25
C.5/16
D.8/25
Answer: C.5/16
Explanation: 5C3 (1/2)^3(1/2)^2
= (5 * 4 * 3!)/2!3! * 1/32
W= 5/16
Answer - C
Question: If a man lost 5% by selling oranges at the rate of 8 a rupee at how many a rupee must he sell them to gain 52%?
A.5
B.8
C.7
D.4
Answer: A.5
Explanation: 95% ---- 8
152% ---- ?
95/152* 8 =5
Answer: A
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green?
A.23/35
B.23/356
C.23/36
D.23/32
Answer: A.23/35
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green
= (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂
= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7
= 46/70 = 23/35
Answer:A
Question: at a time A,do 20% less work than B.if A do any work in 15/2 hour,then in how many hour B will finish work?
A.5 hour
B.11/2 hour
C.6 hour
D.13/2 hour
Answer: C.6 hour
Explanation: let B will finish a work in x hour.then,in x hour A,80/100=4/5 work do
ratio of work done by A and B=inverse ratio of time taken
4/5:1=2/15:1/x
4/5*1/x=1*2/15=4/5x=2/15;x=6.
time= 6 hour
answer C
Question: John can eat a quarter of a pizza in one minute. How long does it take John to eat one pizza and a half?
A.10 minutes.
B.8 minutes.
C.12 minutes.
D.6 minutes.
Answer: D.6 minutes.
Explanation: The above problem could also be solved by dividing the mixed number 1 and 1/2 by 1/4
1 (1/2) * 1 / 4 = 3 / 2 *4 / 1 = 6 minutes.
correct answer D
Question: A group consists of 4 men, 6 women and 5 children. In how many ways can 3 men, 2 women and 3 children selected from the given group?
A.300
B.450
C.600
D.750
Answer: C.600
Explanation: Explanation:
The number of ways of selecting three men, two women and three children is:
= â´Câ‚ƒ * â¶Câ‚‚ * âµCâ‚ƒ
= (4 * 3 * 2)/(3 * 2 * 1) * (6 * 5)/(2 * 1) * (5 * 4 * 3)/(3 * 2 * 1)
= 4 * 15 * 10
= 600 ways.
ANSWER IS C
Question: A tradesman sold an article at a loss of 20%. If the selling price had been increased by $100, there would have been a gain of 5%. What was the cost price of the article ?
A.$100
B.$200
C.$300
D.$400
Answer: D.$400
Explanation: Let C.P. be $x
then, (105% of x)-(80% of x) = 100 or 25% of x=100
x/4 = 100
x=400
C.P. = $400
correct option is D
Question: A train 460 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
A.40
B.87
C.48
D.21
Answer: C.48
Explanation: Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 460 + 140 = 600 m
Required time = 600 * 2/25 = 48 sec
Answer:C
Question: 12 men work 8 hours per day to complete the work in 10 days. To complete the same work in 8 days, working 10 hours a day, the number of men required?
A.10days
B.12days
C.13days
D.11days
Answer: B.12days
Explanation: That is, 1 work done = 12 × 8 × 10
Then, 12 8 × 10 = ? × 10 × 8
? (i.e. No. of men required) = 12 × 8 × 10/10× 8 = 12 days
B)
Question: A train which has 400 m long, is running 50 kmph. In what time will it cross a person moving at 14 kmph in same direction ?
A.40 sec
B.35 sec
C.33 sec
D.42 sec
Answer: A.40 sec
Explanation: Time taken to cross a moving person = length of train/ relative speed
Time taken = 400/((50-14) (5/18) = 400/ 36*(5/18) = 400/10 = 40 sec
Answer: A
Question: The average mark of a class of twenty students is 64. If three students whose marks are 32,28 and 34 are removed , then find the approximate average mark of the remaining students of the class.
A.71
B.74
C.57
D.70
Answer: D.70
Explanation: Total mark of 20 students = 64*20 = 1280,
Total mark after the removal of 3 students = 1280 –(32 +28+34 )
= 1280 – 94 = 1186
Approximate average mark = 1186/(20-3)
= 1186/ 17
= 70
ANSWER:D
Question: The salary of a person was reduced by 10%. By what percent should his reduced salary be raised so as to bring it at par with his original salary?
A.10.1%
B.9.68%
C.11.11%
D.8.62%
Answer: C.11.11%
Explanation: Let the original salary be $100
new salary = $90
increase on 90 = 10
increase on 100 = [(10/90)100]% = (100/9)% = 11.11%
Answer is C
Question: If you write down all the numbers from 1 to 100, then how many times do you write 2 ?
A.A)11
B.B)18
C.C)20
D.D)21
Answer: C.C)20
Explanation: Explanation:
Clearly, from 1 to 100, there are ten numbers with 2 as the unit's digit- 2, 12, 22, 32, 42, 52, 62, 72, 82, 92; and ten numbers with 2 as the ten's digit - 20, 21, 22, 23, 24, 25, 26, 27, 28, 29.
So, required number = 10 + 10 = 20.
Answer: C
Question: I forgot the last digit of a 7-digit telephone number. If 1 randomly dial the final 3 digits after correctly dialing the first four, then what is the chance of dialing the correct number?
A.1/1002
B.1/1028
C.1/1000
D.1/1287
Answer: C.1/1000
Explanation: Explanation:
It is given that last three digits are randomly dialled. then each of the digit can be selected out of 10 digits in 10 ways.
Hence required probability = = 1/1000
Answer: C) 1/1000
Question: In a 200 meters race, A beats B by 20 meters, while in a 100 meters race, B betas C by 5 meters. A beats C in a kilometer race by
A.105 meters
B.225 meters
C.205 meters
D.145 meters
Answer: D.145 meters
Explanation: When A = 200, B = 180.
When B = 100, C = 95.
Make B = 900. A will be 1000. C will be 855.
Answer: D.
Question: A boat goes 100 km downstream in 10 hours, and 60 m upstream in 15 hours. The speed of the stream is?
A.3
B.22 1/4
C.22 1/2
D.22 1/1
Answer: A.3
Explanation: 100 --- 10 DS = 10
? ---- 1
60 ---- 15 US = 4
? ----- 1 S = (10 - 4)/2
= 3 kmp Answer: A
Question: If the price of 357 apples is Rs.1517.25, what will be the approximate price of 49 dozens of such apples?
A.Rs. 2500
B.Rs. 2300
C.Rs. 2200
D.Rs. 1400
Answer: A.Rs. 2500
Explanation: Explanation:
Price of 357 apples = Rs.1517.25
price of 1 apple = Rs. 1517.25/357
price of 49 dozens apples = Rs (49×12×1517.25/357)≈Rs. 2500
Answer: Option A