RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The average age of a family of four members is 25 years. If the age of the youngest member be 15 years then what was the average age of the family at the time of the birth of the youngest member?
A.13.5
B.14
C.15
D.13.33
Answer: D.13.33
Explanation: Explanation :
At present the total age of the family = 4 * 25 = 100
The total age of the family at the time of the birth of the youngest member = [100-15-(15*3)]
= 40
Therefore, average age of the family at the time of birth of the youngest member = 40/3
= 13.33
Answer : D
Question: Two trains A and B starting from two points and travelling in opposite directions, reach their destinations 9 hours and 4 hours respectively after meeting each other. If the train A travels at 100kmph, find the rate at which the train B runs.
A.40
B.60
C.150
D.80
Answer: C.150
Explanation: If two objects A and B start simultaneously from opposite points and, after meeting, reach their destinations in ‘a’ and ‘b’ hours respectively (i.e. A takes ‘a hrs’ to travel from the meeting point to his destination and B takes ‘b hrs’ to travel from the meeting point to his destination), then the ratio of their speeds is given by:
Sa/Sb = √(b/a)
i.e. Ratio of speeds is given by the square root of the inverse ratio of time taken.
Sa/Sb = √(4/9) = 2/3
This gives us that the ratio of the speed of A : speed of B as 2:3.
Since speed of A is 100 kmph, speed of B must be 100*(3/2) = 150 kmph
Answer C
Question: In the Johnsons' monthly budget, the dollar amounts allocated to household expenses, food, and miscellaneous items are in the ratio 5:4:1, respectively. If the total amount allocated to these three categories is $1,800, what is the amount allocated to food?
A. $900
B. $720
C. $675
D. $450
Answer: B. $720
Explanation: To solve this question, it will be best to first express the given ratio using variable multipliers. Thus, we have:
Household Expenses : Food : Miscellaneous = 5x : 4x : x
Since we are told that the TOTAL amount allocated to these categories is $1,800 we can set up the equation:
5x + 4x + x = 1,800
10x = 1,800
x = 180
Thus, the total amount allocated to food is 4 x 180 = $720.
Answer B.
Question: If Rs. 578 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively?
A.s.300
B.s.408
C.s.389
D.s.368
Answer: B.s.408
Explanation: (A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4
A:B = 2:3 and B:C = 1:4 = 3:12
A:B:C = 2:3:12
A;s share = 578 * 2/17 = Rs. 68
B's share = 578 * 3/17 = Rs. 102
C's share = 578 * 12/17 =Rs.408.
Answer:B
Question: Rectangle A has sides a and b, and rectangle B has sides c and d. If a/c=b/d=3/4, what is the ratio of rectangle A’s area to rectangle B’s area?
A.3/4
B.9/16
C.16/3
D.4/3
Answer: B.9/16
Explanation: The area of rectangle A is ab.
c=4a/3 and d=4b/3.
The area of rectangle B is cd=16ab/9.
The ratio of rectangle A's area to rectangle B's area is ab / (16ab/9) = 9/16.
The answer is B.
Question: If a sequence of 8 consecutive odd integers with increasing values has 3 as its 7th term, what is the sum of the terms of the sequence?
A.-16
B.-8
C.-4
D.4
Answer: A.-16
Explanation: Let x be the first term.
Then x + 12 = 3 and x = -9
The sum is: x + (x+2) +...+ (x+14) =
8x + 2(1+2+...+7) = 8x + 2(7)(8) / 2 = 8(-9) + 56 = -16
The answer is A.
Question: A and B can do a work in 18 day, B and C in 30 days, A and C in 22 (1/2) days. In how many days can A,B and C individually do the work?
A.30,45,90
B.30,45,60
C.30,45,40
D.30,43,60
Answer: A.30,45,90
Explanation: (A+B+C)'s two days work = 1/18 + 1/30 + 2/45
= (5 + 3 + 4)/90 = 2/15
(A+B+C)'s one day work = 2/15 * 1/2 = 1/15
A's one day's work = 1/15 - 1/30 = 1/30
B's one day's work = 1/15 - 2/45 = 1/45
C's one day's work = 1/15 - 1/18= 1/90
So, A,B and C can individually do the work in 30, 45 and 90 days.
Answer:A
Question: If points A and B are (8-3) units apart, which of the following can have only one possible value?
I. The area of a square region with side AB
II. The circumference of a circle passing through points A and B
III. The area of a rectangular region with diagonal AB
A.I only
B.II only
C.III only
D.I and II only
Answer: A.I only
Explanation: I. The area of a square region with side AB --> side=AB=(8-3) or 5 --> the area of a square is 5^2=25, so only one possible value;
II. The circumference of a circle passing through points A and B --> circle is not defined by only two points, hence the circumference of a circle passing through points A and B can take infinitely many values. For example consider when AB=diameter and when points A and B are not the endpoints of the diameter;
III. The area of a rectangular region with diagonal AB --> consider the case when AB is the diagonal of a square (the area is 25/2) and the case when AB is the diagonal of a rectangle with the sides equal to 3 and 4 (the area 12).
Answer: A.
Question: If six persons sit in a row, then the probability that three particular persons are always together is?
A.1/9
B.1/3
C.1/5
D.1/1
Answer: C.1/5
Explanation: Six persons can be arranged in a row in 6! ways. Treat the three persons to sit together as one unit then there four persons and they can be arranged in 4! ways. Again three persons can be arranged among them selves in 3! ways. Favourable outcomes = 3!4! Required probability = 3!4!/6! = 1/5
Answer:C
Question: The smallest 2 digit prime number is?
A.A)11
B.B)13
C.C)19
D.D)113
Answer: A.A)11
Explanation: The smallest 3-digit number is 10, which is divisible by 2.
10 is not a prime number.
11 is a prime number.
Hence 11 is the smallest 2-digit prime number.
A)
Question: A can do a piece of work in 90 days & Y can do it in 80 days. They began working together but A leaves after some days and then B completed the remaining work in 46 days. The number of days after which A left the work was?
A.12 days
B.18 days
C.16 days
D.19 days
Answer: C.16 days
Explanation: A and B did the work for some days.
After that , B completed the remaining work in 46 days .
In 46 days, word done by B =
1
80
x 46 =
23
45
Remaining work = 1 – 23/45
= 17/45
Remaining work is done by both A and B together =
17/45x 90 x 80/90 + 80
= 16 days
C
Question: If grapes are 92% water and raisins are 20% water, then how much did a quantity of raisins, which currently weighs 11 pounds, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)
A.25 pounds
B.46 pounds
C.92 pounds
D.110 pounds
Answer: D.110 pounds
Explanation: Since only water evaporates, then the weight of pulp (non-water) in grapes and raisins is the same. Thus 0.08*{weight of grapes}=0.8*{weight of raisins} --> 0.08x = 0.8*11 --> x = 110.
Answer: D.
Question: A furniture store owner decided to drop the price of her recliners by 20% to spur business. By the end of the week she had sold 50% more recliners. What is the percentage increase of the gross?
A.10%
B.15%
C.20%
D.25%
Answer: C.20%
Explanation: Say a recliner is actually worth $100
If she sells 100 recliners then she earns $10000
After the discount of 20%, she will earn $80 per recliner and she sells 50% more ie.,150 recliners
Hence her sales yields 150*80=$12000
Increase in sales=12000-10000=$2000
So% increase = 2000*100/10000 =20%
C is the answer
Question: Of the final grades received by the students in a certain math course, 1/5 are A's, 1/4 are B's, 1/2 are C's, and the remaining 5 grades are D's. What is the number of students in the course?
A. 80
B. 110
C. 160
D. 100
Answer: D. 100
Explanation: We start by creating a variable for the total number of students in the math course. We can say:
T = Total number of students in the math course
Next, we can use variable T in an equation that we translate from the given information. We are given that, of the final grades received by the students in a certain math course, 1/5 are A's, 1/4 are B's, 1/2 are C's, and the remaining 5 grades are D's. Since this represents all the grades in the class, it represents all the students in the class. Thus we know:
#A’s + #B’s + #C’s + #D’s = Total number of students in the class
1/5(T) + ¼(T) + ½(T) + 5 = T
We can multiply the entire equation by 20 to cancel out the denominators of the fractions and we have:
4T + 5T + 10T + 100 = 20T
19T + 100 = 20T
100 = T
There are a total of 100 students in the math class.
Answer is D.
Question: After decreasing 15% in the price of an article costs Rs.915. Find the actual cost of an article?
A.915
B.1000
C.1076
D.1067
Answer: C.1076
Explanation: CP* (85/100) = 915
CP= 10.76 * 100 => CP
= 1076
Answer:C
Question: In a recent election, James received 1.5 percent of the 2,000 votes cast. To win the election, a candidate needed to receive more than 50 percent of the vote. How many additional votes would James have needed to win the election?
A.901
B.989
C.990
D.971
Answer: D.971
Explanation: James = (1.5/100)*2000 = 30
Votes to win = (50/100)*Total Votes +1 = (50/100)*2000 +1 = 1001
Remaining Voted needed to win election = 1001 - 30 = 971
Answer: option D
Question: Victor's job requires him to complete a series of identical jobs. If Victor is supervised at work, he finishes each job three days faster than if he is unsupervised. If Victor works for 144 days and is supervised for half the time, he will finish a total of 36 jobs. How long R would it take Victor to complete 10 jobs without any supervision?
A.34
B.52
C.60
D.70
Answer: C.60
Explanation: Rate when supervised = (job)/(time) = 1/t.
Rate when unsupervised = (job)/(time) = 1/(t+3).
For 144/2=72 days he is supervised and for 144/2=72 days he is unsupervised and does 36 jobs:
72/t + 72/(t+3) = 36 --> t=3 days --> t+3 = 6 days.
Victor to complete 10 jobs without any supervision will need R 10(t + 3) = 60 days.
Answer: C.
Question: If Tim had lunch at $50.50 and he gave 10% tip, how much did he spend?
A.$30.60
B.$60.60
C.$70.60
D.$55.55
Answer: D.$55.55
Explanation: The tip is 20% of what he paid for lunch. Hence
tip = 20% of 50.50 = (10/100)*50.50 = $5.05
Total spent
50.50 + 5.05 = $55.55
correct answer D
Question: If two integers x, y (x>y) are selected from -10 to 10 (inclusive), how many possible cases are there?
A.150
B.180
C.190
D.210
Answer: D.210
Explanation: If two integers x, y (x>y) are selected from -10 to 9 (inclusive), how many possible cases are there?
A. 150
B. 180
C. 190
D. 210
E. 240
--> 21C2=21*20/2=210. Therefore, the answer is D
Question: When all the students in a school are made to stand in rows of 60, 35 such rows are formed. If the students are made to stand in rows of 25, how many such rows will be formed ?
A.31
B.84
C.78
D.19
Answer: B.84
Explanation: Explanation:
Total number of students = 60 x 35
When arranged in rows of 25, number of rows formed are,
= 84.
Answer: B
Question: A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 140 m long?
A.38 sec
B.35 sec
C.44 sec
D.40 sec
Answer: D.40 sec
Explanation: train length= 360m
platform length = 140m
time= ?
length = speed * time
total length =360+140 = 500m
speed = 45 km/hr =45 * (5/18) (m/sec) =12.5 m/sec
time = length/speed = 500/12.5 = 40sec
ANSWER:D
Question: A can finish a work in 21 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
A.6
B.5
C.5.5
D.7
Answer: D.7
Explanation: B's 10 day's work = ( 1 x 10 ) = 2 .
15 3
Remaining work = ( 1 - 2 ) = 1 .
3 3
Now, 1 work is done by A in 1 day.
21
Therefore 1 work is done by A in ( 21 x 1 ) = 7 days.
D
Question: A double decked bus can accomodate 120 passengers,50 in the upper deck and 70 in the lower deck.In how many ways can the passengers be accomodated if 15 refuse to be in the upper deck while 10 others refuse to be in the lower deck?
A.1. 95!/40!55!
B.2. 85!/40!45!
C.3. 110!/50!60!
D.4. 110!50!60!/40!45!
Answer: A.1. 95!/40!55!
Explanation: 120 passengers,50 in the upper deck and 70 in the lower deck.
25 passengers have issues as 15 refuse to be in the upper deck while 10 others refuse to be in the lower deck
So those 15 will be put in lower deck and 10 will be in upper deck
So from the rest 95 passengers(120-25), we need to find 40 people to put into upper deck and the rest go to lower deck
So the ways are: C(95,40) = 95!/40!55! . Answer A
Question: A student has 8 trousers and 11 shirts. In how many different ways can the student select a trouser and a shirt?
A.76
B.88
C.100
D.112
Answer: B.88
Explanation: The student can select one trouser in 8 ways.
The student can select one shirt in 11 ways.
The number of ways to select one trouser and one shirt is 8 * 11 = 88 ways
The answer is B.
Question: At what time between 5 and 6 o' clock are the hands of a 3 minutes apart ?
A.24min
B.12min
C.13min
D.14min
Answer: A.24min
Explanation: n this type of problems the formuae is
(5*x+ or - t)*12/11
Here x is replaced by the first interval of given time. Here x is 5.
t is spaces apart
Case 1 : (5*x + t) * 12/11
(5*5 + 3) * 12/11
28 * 12/11 = 336/11= min
therefore the hands will be 3 min apart at 31 5/11 min past 5.
Case 2 : (5*x - t) * 12/11
(5*5 -3 ) * 12/11
22 *12/11 = 24 min
therefore the hands will be 3 min apart at 24 min past 5 Answer: A
Question: A, B, C hired a car for Rs. 720 and used it for 9, 10 and 13 hours respectively. Hire charges paid by B are:
A.Rs 220
B.Rs.225
C.Rs.230
D.Rs.235
Answer: B.Rs.225
Explanation: A : B : C = 9 : 10 : 13.
Hire charges paid by B = Rs. 720 * 10/32
= Rs. 225.
ANSWER:B
Question: 10 machines, each working at the same constant rate, together can complete a certain job in 12 days. How many additional machines, each working at the same constant rate, will be needed to complete the Job in 8 days?
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: Another solution which is faster is Since each machine works at a constant rate. The time needs to bought down from 12 to 8. So the new time is 2/3 of the original time. Thus to achieve this we need the rate to be 3/2 of original.
So 3/2* 10 = 15
So we need 15-10 = 5 more machines.
Answer : D
Question: A man can place 6 large boxes or 9 boxes inside a carton. Can you calculate in how many cartons can he place 66 boxes ?
A.9
B.10
C.11
D.12
Answer: A.9
Explanation: A
5 cartons for large boxes = 5 * 6 = 30 boxes
4 cartons for small boxes = 4 * 9 = 36 boxes
He will need 9 cartons to place 66 boxes.
Question: The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent. The two reductions together are equal to a single reduction of
A.33
B.40
C.99
D.28
Answer: B.40
Explanation: Explanation:
Let the original price of the cycle be 100. After the first reduction the price will be 75.
This new price is then reduced by 20% = 0.8 x 75 = 60
60 represents a reduction of 40 percent on the original.
Answer: B) 40%
Question: If 2 is the remainder when m is divided by 5, what is the remainder when 3m is divided by 5?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: Let's find a number which when divided by 5 leaves remainder 2 = 5+2 = 7
i.e. one possible value of m = 7
value of 3m = 3*7 = 21
when em is divided by 5 then remainder = Rem (21/5) = 1
Answer: option B
Question: How many positive integers less than 254 are multiple of 4 but NOT multiples of 6?
A.20
B.31
C.42
D.43
Answer: D.43
Explanation: 252/4=63
Multiples of 4 which are a multiple of 6 will be of the form 2*2*3=12n where n>0
240/12=20
63-20=43
Answer: D
Question: In how many ways can you sit 8 people on a bench if 5 of them must sit together?
A.720
B.2,160
C.2,880
D.4,320
Answer: C.2,880
Explanation: In such questions, always tie the person that have to sit together. So we have effectively 3+1= 4 persons to arrange.
They can be arranged in 4! ways.
Now the 5 persons can themselves be arranged in 5! ways.
Total ways: 4!*5! = 2880.
C is the answer.
Question: Amit and Ananthu can do a work in 15 days and 25 days respectively. Amit started the work and left after 3 days. Ananthu took over and completed the work. In how many days was the total work completed?
A.28 days
B.20 days
C.23 days
D.25 days
Answer: A.28 days
Explanation: Amit’s one day’s work= 1/15
Amit’s 3 day’s work = 1/15 *3 = 1/5
Work left= 1-1/5 = 4/5
Ananthu’s one day’s work= 1/25
Ananthu can do work in = 4/5 *25 = 20/1 days
So total days = 25+3 = 28 days
ANSWER:A
Question: How many 4 digit numbers that do not contain the digit 2 are there?
A.5832
B.4332
C.6444
D.5854
Answer: A.5832
Explanation: Applying combinations....8 * 9 * 9 * 9 = 5832...
8 for first digit...cant be 0 or 2
9 and 9 for 2nd and 3rd....cant be 2
9 for fourth digit cannot be 2
ANSWER: A
Question: If an article is sold at 19% profit instead of 12% profit, then the profit would be Rs. 105 more. What is the cost price?
A.1890
B.2790
C.1990
D.1500
Answer: C.1990
Explanation: Let the cost price of an article be Rs. x.
(19% of x) - (12% of x) = 105
19x/100 - 12x/100 = 105 => 7x = 105 * 100
=> x = 1500
Cost price = Rs.1500
Answer: C
Question: The difference between the compound interest and the simple interest accrued on an amount of Rs. 18,000 in 2 years was Rs. 405. What was the rate of interest p.c.p.a. ?
A.33
B.38
C.37
D.15
Answer: D.15
Explanation: Explanation:
Let the rate be R% p.a. Then,
Rate = 15%.
Answer: D) 15%
Question: Look at this series: 664, 332, 340, 170, ____, 89, ... What number should fill the blank?
A.85
B.97
C.109
D.178
Answer: D.178
Explanation: 664/2=332
340/2=170
x/2=89 so x=2*89=178
ANSWER:D
Question: The avg weight of A,B & C is 84 kg. If D joins the group, the avg weight of the group becomes 80 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 79 kg. What is the weight of A?
A.45
B.65
C.75
D.89
Answer: C.75
Explanation: A + B + C = 3 *84 = 252
A + B + C + D = 4 * 80 = 320 ---- (i)
So, D = 68& E = 68 + 3 = 71
B + C + D +E = 79 * 4 = 316 --- (ii)
From Eq. (i) & (ii)
A-E = 320 – 316 = 4
A = E +4 = 71 + 4 = 75
C
Question: Of the 5 distinguishable wires that lead into an apartment, 2 are for cable television service, and 3 are for telephone service. Using these wires, how many distinct combinations of 3 wires are there such that at least 1 of the wires is for cable television?
A.6
B.7
C.8
D.9
Answer: D.9
Explanation: In these Q, where at least is used, the best is to find none and then subtract from total..
here total ways= 5C3=5!/3!2!=10..
ways where no cable television is used=3c3=1..
therefore ways containing at least one wire of cable tele=10-1=9..
Ans: D
Question: P is 30% more efficient than Q. P can complete a work in 23 days. If P and Q work together, how much time will it take to complete the same work?
A.9
B.10
C.11
D.13
Answer: D.13
Explanation: Work done by P in 1 day = 1/23
Let work done by Q in 1 day = q
q × (130/100) = 1/23
=> q = 100/(23×130) = 10/(23×13)
Work done by P and Q in 1 day = 1/23 + 10/(23×13) = 23/(23×13)= 1/13
=> P and Q together can do the work in 13 days
Option D
Question: A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 59.29, the number of the member is the group is
A.57
B.67
C.77
D.87
Answer: C.77
Explanation: Money collected = (59.29 x 100) paise = 5929 paise.
Number of members = 5929 = 77.
ANSWER :C
Question: The ratio of red, yellow, and green jelly beans in a jar is 2:4:5. If the number of jelly beans is increased by 60%, 50%, and 40% respectively, what will be the new ratio?
A.10:18:27
B.12:25:30
C.14:27:32
D.16:30:35
Answer: D.16:30:35
Explanation: The new ratio will be 3.2:6:7=32:60:70=16:30:35.
The answer is D.
Question: If the mean of weight of students in a class of weight 38, 50, 70, 88 and 110 is 71.5 kg, what is the mean of the class if student of weight 50 kg left the class?
A.72 kg
B.75 kg
C.68.5 kg
D.76.5 kg
Answer: D.76.5 kg
Explanation: Mean = (Sum of all weights in class)/(no. students)
M1 = (38+70+88+110)/(4)
= 76.5 kg
Answer =D
Question: If A speaks the truth 70% of the times, B speaks the truth 60% of the times. What is the probability that they tell the truth at the same time
A.0.49
B.0.48
C.0.41
D.0.42
Answer: D.0.42
Explanation: Explanation:
Probability that A speaks truth is 70/100 = 0.7
Probability that B speaks truth is 60/100 = 0.6
Since both A and B are independent of each other
So probability of A intersection B is P(A) × P(B) =0.7× 0.6 = 0.42
Answer: D
Question: Convert the following into a fraction:1.0%
A.1/1
B.10/1
C.1/10
D.1/100
Answer: A.1/1
Explanation: 1.0% =1/1
Answer is A.
Question: If four coins are tossed, the probability of getting two heads and two tails is ?
A.3/8
B.3/6
C.3/1
D.3/2
Answer: A.3/8
Explanation: Since four coins are tossed, sample space = 24
Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = 6/24 = 3/8
Answer: A
Question: The speed of a car is 90 km in the first hour and 60 km in the second hour. What is the average speed of the car?
A.12
B.75
C.88
D.54
Answer: B.75
Explanation: S = (90 + 60)/2
= 75 kmph
Answer: B
Question: A young girl counted in the following way on the fingers of her left hand. She started collang the thumb 1, the index finger 2, the middle finger 3, the ring finger 4, the little finger 5, then reversed direction calling the ring finger 6, the the middle finger 7, the index finger 8, the thumb 9 then back to the index finger for 10, the middel finger for 11, and so on. She counted up to 1993. She ended on her
A.a) thumb
B.b) the index finger
C.c) the middle finger
D.d) the ring finger
Answer: A.a) thumb
Explanation: Notice the pattern. The thumb lansd up at numbers 1,9,17,25,33,... so every 8th number
By this patter the thumb is also at number 1993 (multiple of 8 + 1)
Hence 1993 has to be thumb
Answer is (A)
Question: At an examination in which full marks were 500. A got 10% less than B, B got 25% more than C and C got 20% less than D. If A got 360marks, what percentage of full marks was obtained by D?
A.88%
B.90%
C.80%
D.87%
Answer: C.80%
Explanation: A B C D
90 100 80 100
A D
90 ----- 100
360 ------ ? = 400
500 ------ 400
100 ------- ? => 80%
Answer:C
Question: Twice as many students attend math class compared to people who attend history class. If 2 people began attending history class instead of math class, the ratio of math students to history students would be 1 to 1. How many students total attend these two classes? Hint: No students attend both math and history class.
A.12
B.16
C.90
D.36
Answer: A.12
Explanation: By checking the answer choices:
Since we have an initial ratio of 2:1, the total count should be divisible by 3.
A. 12/3=4, Math Students = 8, History Students = 4, Since 8-2 is equal to 4+2 this is the correct answer.
B. Out, Since not divisible by 3.
C. 90/3=30, Math Students = 60, History Students = 30, Since 60-2 is not equal to 30+2, this is not the answer.
D. 36/3=12, Math Students = 24, History Students = 12, Since 24-2 is not equal to 12+2 this as well can not be the answer.
E. Since choice A is correct, choice E is not correct.
A is the correct answer.
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?
A.3630
B.2881
C.2887
D.9977
Answer: A.3630
Explanation: 6300:4200:10500
3:2:5
3/10 * 12100 = 3630.Answer: A
Question: The cost price of a radio is Rs.4500 and it was sold for Rs.3200, find the loss %?
A.28.9%
B.22%
C.28%
D.45%
Answer: A.28.9%
Explanation: 4500 ---- 1300
100 ---- ? => 28.9%
Answer:A
Question: Of the teams competing in the world archery championships, Thirty percent are from Europe. Half as many are from the United States and one twentieth are from Africa. What fraction of teams are from neither Europe, the US or Africa.
A.10/20
B.30/20
C.13/15
D.17/20
Answer: A.10/20
Explanation: Half as manymeans half of EU, then
EU 30%
US 15%
AF 5%
the rest is 50%, answer A