RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The price of a jewel, passing through three hands, rises on the whole by 65%. If the first and second sellers earned 20% and 25% profit respectively, find the percentage profit earned by the third seller.
A.10%
B.22%
C.18%
D.12%
Answer: A.10%
Explanation: Let the original price of the jewel be Rs. P and let the profit earned by the third seller
be x%.
Then, ( 100 +x )% of 125% of 120% of P = 165% of p
[ ( 100+x )/100*125/100*120/100* P ] = [ 165/100* P ]
( 100 + X ) = 165*100*100/125*120 = 110,
X = 10%.
ANSWER:A
Question: A ship sails out to a mark at the rate of 19 kmph. and sails back at the rate of 13 kmph. The average rate of sailing is ?
A.15 km/hr
B.12 km/hr
C.12.5 km/hr
D.25 km/hr
Answer: A.15 km/hr
Explanation: Answer
Average = ( 2uv / u +v ) km/hr
= ( 2 x 19 x 13 ) / (19 +13 ) km/hr.
= 15 km/hr.
Correct Option: A
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 30 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
A.12 sec
B.24 sec
C.48 sec
D.60 sec
Answer: D.60 sec
Explanation: Relative speed = 30 + 30 = 60 km/hr.
60 * 5/18 = 50/3 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 3/50 = 60 sec.
ANSWER:D
Question: If x is positive integer,y is negative integer, and 3x + 2y = 13, which of the following could be the value of x ?
A.9
B.10
C.12
D.13
Answer: A.9
Explanation: Use answer options to solve this problem -
Put x= 9
3x+2y=13
3(9)+2y=13
27+2y=13
2y=13-27;2y=-14
y=-7(y is negative integer)
Answer will be (A)
Question: Some of the workers at a hedge fund are analysts; the others are not analysts. There are a total of 2x/3 analysts at the hedge fund. A total of x hedge fund workers have an MBA. Furthermore, x/3 analysts have an MBA, y/4 of the hedge fund workers are neither analysts nor have an MBA, and 70 workers are not analysts. If there are y total workers at the hedge fund, x is equal to which of the following?
A.45
B.50
C.63
D.75
Answer: C.63
Explanation: AnalystsNot AnalystsTotal
MBAx/32x/3x
No MBAy/4
Total2x/350y
We are asked for the value of x.
From the table: 2x/3 = y - 70
y - 70 + (y/4) = 70
5y/4 = 140
y = 112
2x/3 = 112 - 70 = 42
x = 126/2 = 63
Answer: C
Question: Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
A.4
B.6
C.5
D.7
Answer: A.4
Explanation: N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Answer: Option A
Question: If the true discount on a sum due 3 years hence at 14% per annum be Rs. 168, the sum due is:
A.698
B.768
C.1430
D.1980
Answer: B.768
Explanation: Sol.
P.W. = 100 * T.D./R * T = 100 * 168 / 14 * 2 = 600.
∴ Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.
Answer B
Question: William earned $9.50 an hour. He worked 40 hours one week and received a bonus
of $75.00. How much did he earn that week?
A.$455.00
B.$555.00
C.$655.00
D.$755.00
Answer: A.$455.00
Explanation: Multiply $9.50 x 40 = $380.00
Add bonus $75.00 + $380.00= $455.00
$380.00
+ 75.00
$455.00
correct answer A
Question: Find the unit's digit in the product 2467 153 * 34172?
A.1
B.3
C.2
D.5
Answer: A.1
Explanation: Unit's digit in the given product=Unit's digit in 7 153 * 172
Now 7 4 gives unit digit 1
7 152 gives unit digit 1
7 153 gives 1*7=7.Also 172 gives 1
Hence unit's digit in the product =7*1=7.
Option A
Question: Find the surface area of a 10cm*4cm*3cm brick.
A.154 cm square
B.156 cm square
C.160 cm square
D.164 cm square
Answer: D.164 cm square
Explanation: Explanation:
Surface area of a cuboid = 2(lb+bh+hl) cm square
So,
Surface area of a brick = 2(10*4+4*3+3*10) cm square
= 2(82) cm square = 164 cm square
Option D
Question: The banker's discount on a sum of money for 3 years is Rs. 1116. The true discount on the same sum for 4 years is Rs. 1200. What is the rate per cent?
A.8%
B.12%
C.10%
D.6%
Answer: D.6%
Explanation: Explanation :
BD for 3 years = Rs. 1116
BD for 4 years = 11163 × 4 = Rs. 1488
TD for 4 years = Rs. 1200
F = BD × TD(BD – TD) = (1488 × 1200)/(1488–1200) = (1488×1200)/288
= (124 × 1200)/24 = (124 × 100)/2 = 62 × 100 = Rs. 6200
=> Rs.1488 is the simple interest on Rs. 6200 for 4 years
⇒ 1488 = (6200 × 4 × R)/100
⇒ R = (1488 × 100)/(6200 × 4)
= (372 × 100)/6200 = 372/62 = 6% Answer : Option D
Question: If the average (arithmetic mean) of a and b is 100, and c – a = 120, what is the average of b and c?
A.150
B.140
C.160
D.170
Answer: C.160
Explanation: a+b/2 = 100
=> a+b = 200
a = c - 120...sub this value
c-120+b = 200
=>c+b = 320
=>c+b/2 = 160
Answer : C
Question: In the x-y plane, the area of the region bounded by the graph of |x+y| + |x-y| = 8 is
A.8
B.12
C.256
D.20
Answer: C.256
Explanation: I've never seen such kind of question in GMAT before.
OK there can be 4 cases:
|x+y| + |x-y| = 8
A. x+y+x-y = 8 --> x=4
B. x+y-x+y = 8 --> y=4
C. -x-y +x-y= 8 --> y=-4
D. -x-y-x+y=8 --> x=-4
The area bounded by 4 graphs x=4, x=-4, y=4, y=-4 will be square with the side of 4 so the area will be 16*16=256
Answer: C
Question: There are 7 players in a bowling team with an average weight of 121 Kg. If two new players join the team, one weighs 110 Kg and the second weighs 60 Kg, what will be the new average weight?
A.115 Kg.
B.118 Kg.
C.113 Kg.
D.110 Kg.
Answer: C.113 Kg.
Explanation: The New average will be= (121*7+110+60)/9= 113 kgs
C is the answer
Question: Can you find next number in tricky mathematical series below?
111 , 113 , 117 , 119 , 123 , 137 ?
A.151
B.161
C.171
D.131
Answer: A.151
Explanation: Solution:
151 (131+20)
Explanation:
1st 7 prime numbers post 100 are
101 , 103 , 107 , 109 , 113 , 127 , 131
...Adding 20 to numbers
121 , 123 , 127 , 129 , 133 , 147 , 151
Answer A
Question: A and B working separately can do a piece of work in 9 and 12 days respectively, If they work for a day alternately, A beginning, in how many days, the work will be completed?
A.9 days
B.11 days
C.8 days
D.10 1/4 days
Answer: D.10 1/4 days
Explanation: (A + B)'s 2 days' work =(1/9+1/12)=7/36
Work done in 5 pairs of days =(5*7/36)=35/36
Remaining work =(1-35/36)=1/36
On 11th day, it is A’s turn. 1/9 work is done by him in 1 day.
1/36 work is done by him in(9*1/36)=1/4 day
Total time taken = (10 + 1/4) days = 10 1/4days.
Answer is D.
Question: If q is an odd integer, which of the following must also be odd?
A.6q + 4
B.q + q
C.3q + 3
D.2q + q
Answer: D.2q + q
Explanation: Things to keep in mind:
Odd + odd = even
Odd + even = odd
Odd*odd = odd
Odd*even = even
On checking each option
A. 6q + 4
6q = even, 6q + 4 = even + even = even.
B. q + q
Odd + odd = even. This will be even
C. 3q + 3
3q = odd, 3q + 3 = odd + odd = even
D. 2q + q
2q = even, 2q +q = even + odd = odd
E. q^2 + 1
q^2 = odd, q^2 + 1 = odd + odd = even
Correct option: D
Question: The average age of a group of 5 members is 20 years. Two years later, a new member joins the group. The average age of the group becomes 20 years. What is the age of the new member ?
A.20 years
B.21 years
C.10 years
D.23 years
Answer: C.10 years
Explanation: The average age of a group of 5 members is 20 years --> the sum of the ages is 5*20=100;
Two years later the sum of the ages of these 5 members would be 100+5*2=110;
Now, say the age of the new member is x years, so the sum of the ages of a new 6 member group is 110+x. Since given that the average age of this group of 6 members is 20 years then: 20*6=110+x --> x=10.
Answer: C.
Question: A is half good a work man as B and together they finish a job in 15 days. In how many days working alone B finish the job?
A.23
B.22
C.45/2
D.36
Answer: C.45/2
Explanation: C
45/2
WC = 1:2
2x + x = 1/15 => x = 1/45
2x = 2/45 => 45/2 days
Question: Bobby bought 2 shares, and which he sold for $96 each. If he had a profit of 80% on the sale of one of the shares but a loss of 80% on the sale of the other share, then on the sale of both shares Bobby had...
A.a profit of 10
B.a profit of 8
C.a loss of 800
D.a loss of 342
Answer: D.a loss of 342
Explanation: Cost of the first stock: 96/1.8=53.33, so profit from it 96-53.33=42.67
Cost of the second stock: 96/0.2=480, so loss from it 96-480=-384
Overall loss 42.67-384=-342
Answer: D.
Question: Denise is trying to open a safe whose combination she does not know.
IF the safe has 4000 possible combinations,and she can try 75 different
possibilities,what is the probability that she does not pick the one
correct combination.
A.1
B.159/160
C.157/160
D.4 3/160
Answer: C.157/160
Explanation: When trying the first time the probability Denise doesn't pick the correct combination=3999/4000
Second time, as the total number of possible combinations reduced by one, not picking the right one would be 3998/3999.
Third time 3997/3998
...
And the same 75 times.
So we get: 3999/4000∗3998/3999∗...∗3925/39263999/4000∗3998/3999∗...∗3925/3926 every denominator but the first will cancel out and every nominator but the last will cancel out as well.
We'll get 3925/4000=157/160.
Answer: C.
Question: A man purchased a grinder for Rs. 600 and sold it at a profit of 12%. The selling price is:
A.Rs. 672
B.Rs. 812
C.Rs. 684
D.None of these
Answer: A.Rs. 672
Explanation: s.p.=112/100 × 600=672
Answer: A
Question: Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is ?
A.5/16
B.5/12
C.5/87
D.5/56
Answer: B.5/12
Explanation: Using question number 11 and 12, we get the probability as
1 - (1/36 + 5/9) = 5/12
Answer:B
Question: If a train, travelling at a speed of 90 kmph, crosses a pole in 4 sec, then the length of train is?
A.281
B.125
C.288
D.100
Answer: D.100
Explanation: D = 90 * 5/18 * 4
= 100 m
Answer: D
Question: X divided by Y equals 6.32 what is a possible remainder?
A.2
B.4
C.6
D.8
Answer: D.8
Explanation: With the decimal being 32/100, the simplest form is 8/25. If the divisor is a multiple of 25, the remainder must be a multiple of 8. The only number that is so is 8. Answer D.
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 723 grams per kg, what is his percent?
A.38.3%
B.25%
C.77%
D.99%
Answer: A.38.3%
Explanation: 723 --- 277
100 --- ? => 38.3%
Answer: A
Question: Find the area of a parallelogram with base 32 cm and height 15 cm.
A.200
B.384
C.345
D.480
Answer: D.480
Explanation: Area of a parallelogram = base * height = 32 * 15 = 480 cm2
Answer: Option D
Question: A train covers a distance of 100km in 1 hour. If its speed is decreased by 10km/hr, the time taken by the car to cover the same distance will be?
A.1hr
B.1hr 6min
C.50min
D.1hr 30min
Answer: B.1hr 6min
Explanation: Speed = 100/1 = 100km/hr
New speed = 100-10 = 90 km/hr
Time taken = 100/90 = 1hr 6min
Answer is B
Question: If 8 men and 2 boys working together, can do seven times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time?
A.1:5
B.2:3
C.3:8
D.5:1
Answer: D.5:1
Explanation: 8M + 2B = 7(1M + 1B)
8M + 2B = 7M + 7B
1M = 5B
The required ratio of work done by a man and a boy = 5:1
Answer:D
Question: One train is traveling 72 kmph and other is at 10 meters a second. Ratio of the speed of the two trains is?
A.5:4
B.5:6
C.2:1
D.5:4
Answer: C.2:1
Explanation: 72 * 5/18 = 10
20:10 => 2:1
Answer: C
Question: 11 times a number gives 132. The number is
A.11
B.12
C.13.2
D.None
Answer: B.12
Explanation: Explanation:
Let the number be 'N'
11×N=132⇒N=12
Correct Option: B
Question: A present value of a machine is $12800. Its value depletiation rate is 25% per annum then find the machine value after 3 years?
A.A)$5400
B.B)$4800
C.C)$36520
D.D)$32450
Answer: A.A)$5400
Explanation: P= $12800
R = 25%
T = 3 years
Machine value after 3years = P/(1-R/100)^T
=12800*3/4 * 3/4 * 3/4
=$5400
Answer is A
Question: Two pipes P and Q can fill a cistern in 15 and 10 minutes respectively. Both are opened together, but at the end of 6 minutes the first is turned off. How much longer will the cistern take to fill?
A.6 1/7
B.6 1/4
C.6
D.6 1/2
Answer: C.6
Explanation: 6/15+ x/10= 1
x= 6.Answer: C
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
A.140 sq.units
B.268 sq.units
C.167 sq.units
D.197 sq.units
Answer: A.140 sq.units
Explanation: Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10
= 140 sq.units
Answer:A
Question: A cube of edge 12cm is immersed completely in a rectangular vessel containing water. If the dimensions of the base of vessel are 20cm * 15cm , find the rise in water level?
A.5.76cm
B.8.25cm
C.11.25cm
D.15.12cm
Answer: A.5.76cm
Explanation: Increase in volume = volume of the cube = 12*12*12 cm^3
Rise in water level = volume / area = 12*12*12/20*15 = 5.76cm
Answer is A
Question: A ship sails 4 degrees north, then 13 S. then 17 N. then 23 S. and has finally 11 degrees of south latitude. What was her latitude at starting ?
A.0
B.1
C.2
D.4
Answer: D.4
Explanation: Let x = the latitude sought.
Then marking the northings +, and the southings -;
By the statement x + 4 - 13 + 17 - 23 = -11
And x = 4.
Answer D
Question: In a competitive examination in a state A, 10% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 12% candidates got selected with 100 more candidates got selected than A. What was the number of candidates appeared from each state?
A.4000
B.5000
C.5500
D.6500
Answer: B.5000
Explanation: Let the number of candidates appeared be x
then, 12% of x - 10% of x = 100
2% of x = 100
x = 100*100/2 = 5000
Answer is B
Question: Three runners running around a circular track can complete one revolution in 2, 4 and 5.5 respectively. When will they meet at starting point ?
A.40 h
B.44 h
C.38 h
D.20 h
Answer: B.44 h
Explanation: Time at which they meet at starting point
= LCM of 2, 4 and 5.5
= 44 h
Answer : B
Question: How many cases do you need if you have to pack 500 same Dolls into cases that each hold five pair of Doll ?
A.25 cases
B.35 cases
C.50 cases
D.45 cases
Answer: D.45 cases
Explanation: D
45
500 Dolls = 225 pairs of Dolls.
225 ÷ 5= 45 cases.
Question: A candy company sells premium chocolate at $5 per pound and regular chocolate at $4 per pound in increment of whole pound only.If Barrett buys a pack of candies which costs him $30, how many pounds of premium chocolates are in the box?
A.[A] 1
B.[B] 2
C.[C] 3
D.[D] 4
Answer: B.[B] 2
Explanation: This question is a bit of Special equations with a single set of unique values.
the Equation stands : 5X + 4Y = 30
Subtract multiple of 5 from 31 and check whether the remaining total is divisible by 4
31 - 5 = 26 -> Not divisible by 4
31 - 10 = 21 -> Not divisible by 4
31 - 15 =16 -> Divisible by 4
31 - 20 =11 -> Not divisible by 4
31 - 25 =6 -> Not divisible by 4
31 - 30 =1 -> Not divisible by 4
Any multiple of 5 hereon will give a negative value for regular chocolates bought and hence, inadmissible
Thus Amount spent on regular chocolate= $16
Amount spent on Premium chocolate= $15
Price per premium chocolate = $5
No. Of boxes of premium chocolate bought = 14 / 7 = 2
Correct Option : B
Question: Two trains of length 150 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?
A.22 sec
B.77 sec
C.76 sec
D.21.5 sec
Answer: D.21.5 sec
Explanation: Relative speed = (42 + 30) * 5/18 = 4 * 5 = 20 mps.
Distance covered in passing each other = 150 + 280 = 430 m.
The time required = d/s = 430/20 = 21.5 sec.
Answer:D
Question: It takes 60 identical printing machines 2 hours to print 300 cards. How much more time would it take 50 of these machines to print the same total?
A.20 min
B.25 min
C.26 min
D.36 min
Answer: D.36 min
Explanation: 50% of 60 = 30% or 0.30
2 hr x 60 min = 120 min
120 min x 0.30 = 36 min
It will take 36 min longer to print them with only 50 printers.
Answer is D
Question: Mario and Nina each have a bag of marbles, each of which contains 5 blue marbles, 10 red marbles, and 5 white marbles. If Mario and Nina each select one marble from their respective bags, what is the probability that either Mario or Nina select a red marble?
A.3/4
B.1/4
C.2/4
D.1/8
Answer: C.2/4
Explanation: Mario and Nina each select one marble from their respective bags.
Probability that either Mario or Nina select a red marble = Probability that Mario selects a red marble + Probability that Nina selects a red marble
Probability that either Mario or Nina select a red marble = (10/20)*(10/20) + (10/20)*(10/20) = 2*(1/4)
Probability that either Mario or Nina select a red marble = 1/2
Answer would be C.
Question: A bag contains a certain number of 50 paise coins, 20 paise coins and 10 paise coins inthe ratio 3:4:5. If the total value of all the coins in the bag is Rs.420, find the number of 50 paise coins ?
A.498
B.488
C.450
D.528
Answer: C.450
Explanation: 50*3k + 20*4k + 10*5k = 42000
280k = 42000 => k = 150
50p coins = 3k = 3*150 = 450
ANSWER:C
Question: The average weight of the teacher and six students is 12 kg which is reduced by 5 kg if the weight of the teacher is excluded. How much does the teacher weigh ?
A.42
B.77
C.66
D.28
Answer: A.42
Explanation: lanation:
Total age of the students and teacher together = 7 × 12 = 84
New average after excluding teacher = 6 × 7 = 42
Teachers weight = 74 - 42 = 42
Answer:A
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
A.140
B.150
C.160
D.170
Answer: A.140
Explanation: Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10 = 140 sq.units
Answer: Option A
Question: The remainder when 1!+2!+3!...+50! divided by 7! will be
A.21
B.873
C.777
D.927
Answer: B.873
Explanation: The remainder when the terms greater than 7! are divided by 7! becomes 0 so we need to consider the terms upto 6!.
So remainder will be whatever is obtained by dividing 1!+2!+3!+4!+5!+6! with 7!.
So remainder is obtained by dividing (1+2+6+24+120+720)= 873 with 7! ( 5040)
So remainder is 873.
Answer:B
Question: In how many ways letters of the word POLICIES be arranged?
A.45326
B.28763
C.20160
D.45693
Answer: C.20160
Explanation: POLICIES has 8 letters, out of which I repeated 2 times. Hence total ways = 8! / 2! = 20160ways
C
Question: There are 70 supermarkets in the FGH chain. All of them are either in the US or Canada. If there are 14 more FGH supermarkets in the US than in Canada, how many FGH supermarkets are there in the US?
A.20
B.31
C.42
D.53
Answer: C.42
Explanation: x + (x - 14) = 70 --> x = 42.
Answer: C.
Question: The sector of a circle has perimeter 83 cm and central angle 225o. Find its radius?
A.21 cm
B.15 cm
C.14 cm
D.24 cm
Answer: C.14 cm
Explanation: Let radius = x cm
Perimeter of the sector = length of the arc + 2(radius)
83= (225/360 * 2 * 22/7 * x) + 2(x)
83= 55x/14 + 2x
83 = 83x/14
1162=83x
x = 14
Answer: C
Question: An automobile financier claims to be lending money at S.I., but he includes the interest every six months for calculating the principal. If he is charging an interest of 20%, the effective rate of interest becomes?
A.40.5%
B.20.5%
C.10%
D.30.5%
Answer: B.20.5%
Explanation: Let the sum be Rs. 100. Then,
S.I. for first 6 months = (100 * 20 *1) / (100 * 2) = Rs. 10
S.I. for last 6 months = (105 * 20 * 1) / (100 * 2) = Rs. 10.5
So, amount at the end of 1 year = (100 + 10+10.5) = Rs. 120.5
Effective rate = (120.5- 100) = 20.5%.
ANSWER:B
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?
A.867 Sec
B.190 Sec
C.686 Sec
D.686 Sec
Answer: B.190 Sec
Explanation: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 1900 m
T = D/S
T = 1900/10
T = 190 Sec
Answer:B
Question: Solve :
42 : 56 :: 110 : ?
A.121
B.111
C.132
D.143
Answer: C.132
Explanation: 6*7=42
7*8=56
10*11=110
11*12=132
ans 42:56::110:132
ANSWER:C
Question: There is a 50% chance that Alice will visit China this year, while there is a 20% chance that she will visit Brazil this year. What is the probability that Alice will visit either China or Brazil this year, but NOT both?
A.50%
B.45%
C.40%
D.35%
Answer: A.50%
Explanation: P(China but not Brazil)=0.5*0.8=0.4
P(Brazil but not China)=0.2*0.5=0.1
P(China or Brazil but not both)=0.4+0.1=0.5
The answer is A.
Question: A certain store sells only black shoes and brown shoes. In a certain week, the store sold x black shoes and y brown shoes. If 2/5 of all shoes sold that week were black, which of the following expressions represents the value of y, in terms of x?
A.x/3
B.x/2
C.2x/3
D.3x/2
Answer: D.3x/2
Explanation: x/(x+y) = 2/5
5x = 2x+2y
3x = 2y
y = 3x/2
Answer D
Question: The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of $300 per sq. metre.
A.$2587.50
B.$3587.50
C.$4187.50
D.$6187.50
Answer: D.$6187.50
Explanation: Area =5.5×3.75 sq. metre.
Cost for 1 sq. metre. = $300
Hence, total cost
=5.5×3.75×300= $6187.50
D
Question: 54671 - 14456 - 33490 = ?
A.2449
B.5449
C.6749
D.6725
Answer: D.6725
Explanation: D
If we calculate we will get 6725
Question: Find a number such that it exceeds 18 by three times the number by which it is less than 86?
A.67
B.68
C.69
D.70
Answer: C.69
Explanation: x-18=3[86-x]
x=69
ANSWER:C
Question: Three numbers are in the ratio 5 : 6 : 7. The sum of its longest and smallest numbers equals the sum of the third number and 85. Find the third number?
A.A)37
B.B)85
C.C)48
D.D)43
Answer: B.B)85
Explanation: Let the numbers be 5x, 6x, 7x.
Largest number = 7x.
Smallest number = 5x.
Third number = 6x.
7x + 5x = 6x + 85
6x = 85 => third number is 85.
Answer: Option B
Question: The ratio of football players, baseball players, soccer players, and basketball players in a school is 10:7:5:4. How many athletes are in the school if 16 players are on the basketball team?
A.40
B.92
C.104
D.208
Answer: C.104
Explanation: The ratio is 10 football players: 7 baseball players: 5 soccer players: 4 basketball players.
Divide 16 by 4 to find 1 "part" of the ratio.
16/4 = 4
Multiply 4 by 5 to find the number of soccer players.
4*5 = 20
Multiply 4 by 7 to find the number of baseball players.
4*7 = 28
Multiply 4 by 10 to find the number of football players.
4*10 = 40.
Add them all up to find total athletes.
16+20+28+40 = 104
The answer is C.
Question: Rectangle ABCD is constructed in the coordinate plane parallel to the x- and y-axes. If the x- and y-coordinates of each of the points are integers which satisfy 5 ≤ x ≤ 11 and -5 ≤ y ≤ 5, how many possible ways are there to construct rectangle ABCD?
A.396
B.1260
C.1155
D.7920
Answer: C.1155
Explanation: As the rectangle is parallel to coordinate axes, the coordinates of the points of the rectangle would be
(X1, Y1), (X2, Y1), (X2, Y2), (X1,Y2)
given that X1, X2 lie between 5 and 11..ie., 7 possible numbers
Possible combinations for X1,X2 would be 7C2 = 21
Similarly, Possible combinations for Y1, Y2 would be 11C2 = 55
Possible ways of constructing rectangle is by selecting any of the combination of X1,X2 and Y1,Y2
= 21 * 55 = 1155
Ans. C
Question: How much does a watch lose per day, if its hands coincide ever 64 minutes?
A.32x8/11 min
B.36x8/11 min
C.90 min
D.96 min
Answer: A.32x8/11 min
Explanation: 55 min. spaces are covered in 60 min. 60 min. spaces are covered in (60/55 x 60) min = 65x5/11 min. Loss in 64 min.(65x5/11 - 64). = 16/11 Loss in 24 hrs(16/11x1/64x24x60)min = 32x8/11.
Answer A