RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a group of ducks and cows, the total number of legs are 28 more than twice the number of heads. Find the total number of cows.
A.14
B.12
C.16
D.8
Answer: A.14
Explanation: Explanation :
Let the number of ducks be d
and number of cows be c
Then, total number of legs = 2d + 4c = 2(d + 2c)
total number of heads = c + d
Given that total number of legs are 28 more than twice the number of heads
=> 2(d + 2c) = 28 + 2(c + d)
=> d + 2c = 14 + c + d
=> 2c = 14 + c
=> c = 14
i.e., total number of cows = 14
Answer : A
Question: If i is a positive integer and i^2 is divisible by 12, then the largest positive integer that must divide i ^3 is
A. 2^3
B. 2^6
C. 3^3
D. 6^3
Answer: D. 6^3
Explanation: Since i is an integer so i cannot have a 2 and sqrt 3 (because squaring this will give us a 2^2 and 3 (making the product as 12, and making i^2 as a multiple of 12))
i^2 is divisible by 12 (12 = 2*2*3), So, i should have at least one 2 and one 3 so that i^2 has a 2^2 and two 3
So, i will have a 2 and a 3. Or i will be a multiple of 6
So, largest possible integer than should divide i^3 is 6^3
So, Answer will be D
Question: What is the 4 digit number in which the 1st digit is 1/3 of the second, the 3rd is the sum of the 1st and 2nd, & the last is three times the second?
A.1234
B.1567
C.1349
D.1456
Answer: C.1349
Explanation: First digit is 1/3 second digit => The numbers can be 1 & 3, 2& 6, 3 & 9.
First + second = third => we can eliminate 3 & 9 since 3 + 9 = 12.
Last is 3 times the second => we can eliminate option 2 & 6 since 3 * 6 = 18.
Hence the number is 1349
C
Question: A number has exactly 32 factors out of which 4 are not composite. Product of these 4 factors (which are not composite) is 30. How many such numbers D are possible?
A.2
B.4
C.6
D.3
Answer: C.6
Explanation: Firstly , we should note that 1 is NEITHER a prime nor a composite number.The first composite number is 4.Thus, when the problem states that there are 4 factors that are not composite, these nos are 1,2,3,5. Thus, the given number = 2^a*3^b*5^c. Also, (a+1)*(b+1)*(c+1) = 32. We can break down 32 into 3 integers as : 2*2*8 or 4*4*2
Also, the only possible combinations for a,b,c are : 3,3,1 OR 1,1,7. Thus, each combination has 3 possible orders and we have a total D of 6 possibilities.
C.
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 600 m long?
A.266 Sec
B.180 Sec
C.776 Sec
D.166 Sec
Answer: B.180 Sec
Explanation: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 1800 m
T = D/S
T = 1800/10
T = 180 Sec
Answer: B
Question: A train 210 m in length crosses a telegraph post in 13 seconds. The speed of the train is?
A.77 kmph
B.55 kmph
C.54 kmph
D.58 kmph
Answer: D.58 kmph
Explanation: S = 210/13 * 18/5
= 58 kmph
Answer: D
Question: From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 30 percent. The enrollment on January 1, 1993, was 45 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ?
A. 35
B. 39
C. 40
D. 41
Answer: A. 35
Explanation: 1.30x=45 --> 13/10*x=45 --> x=45*10/13=450/13=~35.
Answer: A.
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. After how much time will the trains meet?
A.20/8 sec
B.20/4 sec
C.20/7 sec
D.22/7 sec
Answer: C.20/7 sec
Explanation: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (54 + 72)*5/18 = 7*5 = 35 mps.
The time required = d/s = 100/35 = 20/7 sec.Answer:C
Question: A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 36, what is the total amount?
A.166
B.140
C.178
D.177
Answer: B.140
Explanation: x:y:z = 100:45:30
20:9:6
9 --- 36
35 --- ? => 140
Answer: B
Question: If there are ten positive real numbers n1 < n2 < n3 … < n10, how many triplets of these numbers (n1, n2, n3), (n2, n3, n4) … can be generated such that in each triplet the first number is always less than the second number, and the second number is always less than the third number?
A.45
B.90
C.120
D.180
Answer: C.120
Explanation: Three numbers can be selected and arranged out of ten numbers in 10P3 ways=10!/7!=10*9*8. Now this arrangement is restricted to a given condition that first number is always less than the second number, and the second number is always less than the third number. Hence three numbers can be arranged among themselves in 3! ways.
Required number of arrangements=(10*9*8)/(3*2)=120
ANS:C
Question: A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
A.278
B.277
C.278
D.450
Answer: D.450
Explanation: 10 * 150 = 1500
3 * 100 + 5 * 150 = 1050
1500 – 1050 = 450
Answer:D
Question: If a tire rotates at 400 revolutions per minute when the car is traveling 48km/h, what is the circumference of the tire?
A.7 meters
B.9 meters
C.8 meters
D.2 meters
Answer: D.2 meters
Explanation: 400 rev / minute = 400 * 60 rev / 60 minutes
= 24,000 rev / hour
24,000 * C = 48,000 m : C is the circumference
C = 2 meters
correct answer D
Question: Anil and Suresh are working on a special assignment. Anil needs 6 hours to type 32 pages on a computer and Suresh needs 5 hours to type 40 pages. If both of them work together on two different computers, how much time is needed to type an assignment of 110 pages?
A.7 hour 15 minutes
B.7 hour 30 minutes
C.8 hour 15 minutes
D.8 hour 30 minutes
Answer: C.8 hour 15 minutes
Explanation: Explanation :
Pages typed by Anil in 1 hour = 32/6 = 16/3
Pages typed by Suresh in 1 hour = 40/5 = 8
Pages typed by Anil and Suresh in 1 hour = 16/3 + 8 = 40/3
Time taken to type 110 pages when Anil and Suresh work together = 110 × 3 /40 = 33/4
= 8 ¼ hours = 8 hour 15 minutes
Answer : Option C
Question: When positive integer X is divided by positive integer Y, the remainder is 5.76. If X/Y = 96.12, what is the value of Y?
A.96
B.75
C.48
D.25
Answer: C.48
Explanation: When positive integer x is divided by positive integer y, the remainder is 5.76 --> x=qy+5.76;
x/y=96.12 --> x=96y+0.12y (so q above equals to 96);
0.12y=5.76 --> y=48.
Answer: C.
Question: The sum of 33 consecutive integers is 3333. What is the greatest integer in the set?
A.113
B.115
C.117
D.119
Answer: C.117
Explanation: Let x be the first integer in the set, then x+32 is the largest integer.
The sum is: x+(x+1)+(x+2)+...+(x+32)
= 33x + 32*33/2
= 33(x+16)
Then x+16=101
x=85
The largest integer in the set is 85+32=117
The answer is C.
Question: Company S produces two kinds of stereos: basic and deluxe. Of the stereos produced by Company S last month, 2/3 were basic and the rest were deluxe. If it takes 1.3 as many hours to produce a deluxe stereo as it does to produce a basic stereo, then the number of hours it took to produce the deluxe stereos last month was what fraction of the total number of hours it took to produce all the stereos?
A.7/17
B.13/33
C.7/15
D.17/35
Answer: B.13/33
Explanation: The easiest way for me is to plug in numbers.
Let the number of basic stereos produced be 40, and number of delux stereos produced be 20. Total of 60 stereos.
If it takes an hour to produce a basic stereo then it will take 1.3 hours to produce a deluxe stereo.
40 basic stereos = 40 hours.
20 delux stereos = 26 hours.
Total hours = 66.
Then the fraction would be 26/66 = 13/33. Therefore answer B
B.
Question: A profit of Rs. 1000 is divided between X and Y in the ratio of 1/2:1/3 . What is the difference between their profit shares ?
A.s. 200
B.s. 100
C.s. 300
D.s. 50
Answer: A.s. 200
Explanation: A profit of Rs. 1000 is divided between X and Y in the ratio of 1/2 : 1/3 or 3:2.
so profits are 600 and 400.
difference in profit share = 600-400=200
ANSWER:A
Question: A store raised the price of an item by exactly 30 percent. Which of the following could NOT be the resulting price of the item?
A.19.5
B.195
C.325
D.168
Answer: D.168
Explanation: If it raised the value by 30% then the resulting price is 1.3 times the original price. So the final answer has to be a multiple of 1.3. Check the answers.
19.5 - Yes
195 - Yes
325 - Yes
168 - No
18.2 - Yes
Answer : D
Question: A man invested Rs. 14,400 in Rs. 100 shares of a company at 20% premium.If the company declares 8% dividend at the end of the year,then how much does he get ?
A.Rs. 500
B.Rs. 600
C.Rs. 960
D.Rs. 720
Answer: C.Rs. 960
Explanation: Solution
Number of shares = (14400/120) = 120.
Face value = Rs. (100x120 ) = Rs. 12000.
Annual income = Rs.(8/100x12000) = Rs. 960.
Answer C
Question: Of the following, which is the closest approximation of (50.2*0.49)/199.8 ?
A.0.121
B.0.125
C.0.122
D.0.123
Answer: B.0.125
Explanation: Ans: For approximation (50.2$ \times $0.49)/199.8 can be taken as
50$ \times $0.5/200 = 25/200 = 1/8 = 0.125
Answer:B
Question: At a dinner party, 5 people are to be seated around a circular table. 2 seating arrangements are considered different only when the positions of the people are different relative to each other. what is the total number T of different possible seating arrangements for the group?
A.5
B.10
C.24
D.32
Answer: C.24
Explanation: Circular arrangements= (n-1)!
Hence (4!) = 24=T
Answer is C
Question: A trader mixes 80 kg of tea at 15 per kg with 20 kg of tea at cost price of 20 per kg. In order to earn a profit of 35%, what should be the sale price of the mixed tea?
A.23.75
B.21.6
C.20
D.19.2
Answer: B.21.6
Explanation: C.P. of mixture = 80×15+20×20 /80+20=16
∴ S.P. = (100+35)/100×16=21.6
Answer B
Question: A train 125 m long passes a man, running at 8 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
A.36
B.53
C.88
D.66
Answer: B.53
Explanation: Speed of the train relative to man
= (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr
= 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 8) km/hr. x - 8
= 45 ==> x
= 53 km/hr.
Answer:B
Question: 2 pipes A and B can separately fill a cistern in 10 and 15 mins respectively. A person opens both the pipes together when the cistern should have beenwas full he finds the waste pipe open. He then closes the waste pipe and in another 4mins the cistern was full. In what time can the waste pipe empty the cistern when fill?
A.6
B.8
C.9
D.10
Answer: B.8
Explanation: 1/10 + 1/15 = 1/6 * 4 = 2/3
1 - 2/3 = 1/3
1/10 + 1/15 - 1/x = 1/3
x = 8
B
Question: An atom's atomic number is determined by the number of:
A.neutrons minus protons
B.protons
C.electrons
D.neutrons
Answer: B.protons
Explanation: protons
Answer:B
Question: A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
A.6
B.7
C.5
D.8
Answer: D.8
Explanation: Speed downstream = d/t = 85/(2 1/2) = 34 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (34 - 18)/2
= 8 kmph
Answer: D
Question: A, B and C can do a piece of work in 24, 30 and 40 days respectively. They start the work together but C leaves 4 days before the completion of the work. In how many days is the work done?
A.11
B.5
C.70
D.11
Answer: D.11
Explanation: x/24 + x/30 + x/40 = 1
x = 11 days
Answer:D
Question: A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangule, whose length and breadth are in the ratio of 6 : 5. What is the area of the rectangle?
A.65 cm2
B.30 cm2
C.76 cm2
D.68 cm2
Answer: B.30 cm2
Explanation: The circumference of the circle is equal to the permeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=> x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle
= 6 * 5
= 30 cm2
Answer: B
Question: If x > 0.6, which of the following could be the value of x?
A.√0.6
B.√0.007
C.√0.006
D.√0.008
Answer: A.√0.6
Explanation: Answer : A
Question: If 0.8 of a number is equal to 0.09 of another number, the ratio of the numbers i
A.2 : 3
B.3 : 4
C.9 : 80
D.20 : 3
Answer: C.9 : 80
Explanation: Sol.
0.8A = 0.09 B â‡” A / B = 0.09 / 0.8 = 9/80 = .
âˆ´ A : B = 9 : 80.
Answer C
Question: A, B, and C working alone can finish constructing a house in 6, 8, and 12 hours respectively. A starts alone and works for 1 hour. He is then joined by B and they work together for 1 hour. Finally C joins them and they all work together to finish the work. If they start working at 9 am, at what time will they finish?
A.11:36 am
B.11:48 am
C.12:05 pm
D.12:27 pm
Answer: D.12:27 pm
Explanation: A completes 1/6 of the job each hour.
B completes 1/8 of the work each hour.
C completes 1/12 of the work each hour.
A completes 1/6 of the work in the first hour.
Working together, A and B complete another 7/24 for a total of 11/24.
Working together, A, B, and C can complete 9/24 of the work each hour.
To complete 13/24, the time required is (13/24) / (9/24) = 13/9 hours.
The work will be completed at 12:00 plus 4*60/9 minutes which is about 12:27 pm.
The answer is D.
Question: Machine A working alone can complete a job in 10 hours. Machine A+B working alone can do the same job in 16 hours. How long will it take machine B working at their respective constant rates to complete the job?
A.20/3
B.80/3
C.50/4
D.90/11
Answer: B.80/3
Explanation: Machines ( A ) ( B ) (A+B)
---Time - 10 - ( - ) -(16)
---Rate 16--- 6 -- 10
--Work 160 --160 -160
A+B = (160/6) = 80/3
B
Question: When ticket sales began, Pat was the nth customer in line for a ticket, and customers purchased their tickets at the rate of y customers per minute. Of the following, which best approximates the time, in minutes, that Pat had to wait in line from the moment ticket sales began?
A.(n - 1) y
B.n + y –1
C.(n-1)/y
D.y/(n-1)
Answer: C.(n-1)/y
Explanation: C. (n - 1) / y
Question: If D is the product of all positive integers less than 31, than what is the greatest integer k for which D/18^k is an integer?
A.3
B.6
C.7
D.14
Answer: C.7
Explanation: 30! D must be divisible by (3*3*2)^k.
As I will find a lot of 2's among 30!'s factors I will focus on the 3's (that also occurs twice instead of only once as a factor in 18).
Every multiple of 3 will provide me with atleast one factor of 3. There aren't that many so I list them quickly.
3 6 9*
12 15 18*
21 24 27**
30
The stars are marked as they are multiples of 9* or 27** and thus provides two or three 3's respectively.
3=3 (occurs 10 times) +10
3*3=9 (occurs 3 times) +3(adding just one additional three each as they were not counted for in the multiples of 3)
3*3*3=27 (occurs 1 time) +1 (again, adding just one as they were previously not counted)
Total: 14.
For every k we add two 3's. So we must divide 14 by 2 to get the highest integer K before we receive a non-integer result.
Answer: 7 -> Answer choice: C.
Question: What is the sum of the greatest common factor and the lowest common multiple of 45 and 125?
A.1920
B.2201
C.3240
D.1130
Answer: D.1130
Explanation: Prime factorization of the given numbers
45= 3^2
125= 5^3
Greatest common factor =5
Lowest common multiple = 3^2*5^2 *5 =1125
Sum = 5+ 1125 = 1130
Answer D
Question: Two concentric circles form a ring. The inner and outer circumference of the ring are 352/7 m and 528/7m respectively.Find the width of the ring.
A.2
B.4
C.5
D.6
Answer: B.4
Explanation: Explanation:
let the inner and outer radii be r and R meters
then, \inline {\color{Black}2\prod r} = 352/7
=> r = (352/7) * (7/22) * (1/2) = 8m
\inline {\color{Black}2\prod R} = 528/7
=> R= (528/7) * (7/22) * (1/2)= 12m
width of the ring = R-r = 12-8 = 4m
Answer: B) 4
Question: Length of a rectangular plot is 20 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
A.30 m
B.60 m
C.65 m
D.70 m
Answer: B.60 m
Explanation: Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m
B
Question: If n is the smallest positive integer for which 2^n is a factor of 10!, then n =?
A.2
B.4
C.6
D.8
Answer: A.2
Explanation: 10! = 3628800
A. 2^2 = 4 (3628800/4) - this is a factor of 10!
A is answer
Question: A company has 540 employees, 40% of whom are employed part time. If it hires 30 new employees, 20% of whom are employed part time, what will be the percent increase in part time employees?
A.2 7/9 %
B.2 2/3 %
C.4 %
D.4 1/6 %
Answer: A.2 7/9 %
Explanation: Total employee = 540
Part time Empl = 540 * 40/100 =216
New part time empl = 30 * (20/100)
= 6
Total new part time Emp = 6+216= 222
Old part time Emp = 216
% increase = (new - old)*100/old
=6*100/216
= 2.777%
Ans-A
Question: A train 150 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
A.13 km/hr
B.59 km/hr
C.17 km/hr
D.18 km/hr
Answer: B.59 km/hr
Explanation: Speed of the train relative to man = (150/10) m/sec
= (15) m/sec. [15) * (18/5)] km/hr
= 54 km/hr. Let the speed of the train be x km/hr. Then, relative speed
= (x - 5) km/hr. x - 5 = 54 ==> x
= 59 km/hr.
Answer:B
Question: Jimâ€™s Taxi Service charges an initial fee of $2.35 at the beginning of a trip and an additional charge of $0.35 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles?
A.$3.15
B.$4.45
C.$4.80
D.$5.50
Answer: D.$5.50
Explanation: Let the fixed charge of Jimâ€™s Taxi Service = 2.35 $
and charge per 2/5 mile(.4 mile) = .35$
Total charge for a trip of 3.6 miles = 2.35 + (3.6/.4) * .35
= 2.35 + 9*.35
= 5.5 $
Answer D
Question: The average salary of workers in an industry is Rs.200 the average salary of technicians being Rs.400 and that of non-technicians being Rs.125. What is the total number of workers?
A.277
B.665
C.662
D.552
Answer: B.665
Explanation: 8 * 84 = 672 – 7 = 665
Answer:B
Question: The first three terms of a proportion are 5, 15 and 20. The fourth term is?
A.60
B.65
C.89
D.78
Answer: A.60
Explanation: (15*20)/5= 60
Answer:A
Question: A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 44 hrs and a machine of type S does the same job in 20 hours. If the company used the same number of each type of machine to do the job in 4 hours, how many machines of type R were used?
A.56/21
B.59/16
C.44/21
D.55/16
Answer: D.55/16
Explanation: Rate of machine R =1/44
Rate of machine S =1/20
since same no of machines used for R and S to do the same work in 4 hrs
So collective rate needed to finish the work in 4 hrs= 1/4
Let the no of machine be x
So, x/44 +x/20 =1/4
(5x+11x)/220=1/4
16x=55
x=55/16
So no of machine R is 55/16
Answer D
Question: If a boy travels with 5/6th of usual his speed,he is late by 10 mins.What is the usual time taken to travel?
A.44min
B.46min
C.48min
D.50min
Answer: D.50min
Explanation: speed=5/6*x
time=6/5t becz speed inversely proportional to time
6t/5-t=10
t=50min
ANSWER:D
Question: Sum of the squares of 3 no. is 138 and the sum of their products taken two at a time is 131. Find the sum?
A.20
B.21
C.25
D.26
Answer: A.20
Explanation: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 138 + 2* 131
a + b + c = √400 = 20
A
Question: A trader marked the price of his commodity so as to include a profit of 25%. He allowed discount of 16% on the marked price. His actual profit was :
A.4
B.5
C.10
D.12
Answer: B.5
Explanation: Sol.
Let C.P. be Rs. 100. Then, marked price = Rs. 125.
S.P. = 84% of Rs. 125 = Rs. [84 /100 * 125] = Rs. 105.
∴ Profit% = (105 - 100)% = 5%.
Answer B
Question: In a store, the total price for 20 shirts is $360 and the total price for 45 sweaters is $900. By how much does the average (arithmetic mean) price of a sweater exceed that of a shirt in this store?
A.$1
B.$2
C.$3
D.$4
Answer: B.$2
Explanation: The average price of a shirt is: $360 / 20 = $18.
The average price of a sweater is: $900 / 45 = $20.
The difference in price is: $20 - $18 = $2.
The answer is B.
Question: In a business school case competition, the top three teams receive cash prizes of $5,000, $3,000, and $2,000, respectively, while the remaining teams are not ranked and do not receive any prizes. There are 6 participating teams, named Team A, Team B, Team C, Team D, Team E, and Team F. If Team A wins one of the prizes, Team B will also win one of the prizes. How many outcomes Q of the competition are possible?
A.18
B.20
C.54
D.84
Answer: D.84
Explanation: the ways the three teams can be selected is..
i) A is selected, B is also selected, third can be any of the remaining 4.. so total ways 4.. they can be arranged in 4*3!=24 ways..
ii) A is not selected. threee teams can be selected from remaining 5 so total arrangements =5C3*3!=60
total Q=84 outcomes
D
Question: The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 50% profit?
A.277
B.960
C.277
D.266
Answer: B.960
Explanation: Let C.P. = Rs. x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 150% of Rs. 640 = 150/100 * 640 = Rs. 960.
Answer: B
Question: Find the odd man out.
1, 5, 2, 3, 6, 11, 13
A.6
B.5
C.1
D.13
Answer: A.6
Explanation: Explanation:
Each of the numbers except 6 is a prime number.
Answer: A) 6
Question: If 45% of a number is 36, then the number is
A.number is 60
B.number is 70
C.number is 90
D.number is 80
Answer: D.number is 80
Explanation: Solution:
Let "a" be the number we seek. We get
45% × a = 36
2 × 45% × a = 2 × 36 = 72
90% × a = 72
10% × a = 72 : 9 = 8
100% × a = 8 × 10 = 80
a = 80
Answer D
Question: A special municipal payroll tax charges not tax on a payroll less than $200,000 and only 0.2% on a company’s payroll above $200,000. If Belfried Industries paid $400 in this special municipal payroll tax, then they must have had a payroll of
A.$180,000
B.$400,000
C.$220,000
D.$402,000
Answer: B.$400,000
Explanation: ANSWER : B , ( with different approach) :
The 400 paid is 0.2% of the additional amount above 200,000. Let it be X
Now 0.2% of X = 400
Therefore X= 200,000
Total = 200,000 + X= 400,000
Question: If a * b = 2a – 3b + ab, then 5 * 7 + 7 * 5 is equal to:
A.34
B.18
C.72
D.78
Answer: A.34
Explanation: 5 * 7 + 7 * 5 = (2 * 5 – 5 * 7 + 5* 7) + (2 * 7 – 5 * 5 + 7 * 5)
= (10 + 14 – 25 + 35) = 34.
ANSWER:A
Question: The average monthly salary of 24 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 400. What is the manager's monthly salary ?
A.Rs. 11,300
B.Rs. 11,500
C.Rs. 11,302
D.Rs. 11,301
Answer: B.Rs. 11,500
Explanation: Explanation:
Manager's monthly salary
= Rs. (1900 x 25 - 1500 x 24) = Rs. 11,500
Answer:B
Question: How many four letter words are formed using the letters of the word PROBLEM?
A.760
B.800
C.840
D.880
Answer: C.840
Explanation: The number of letters in the given word is seven.
The number of four letter words that can be formed using these seven letters is 7P4
= 7 * 6 * 5 * 4 = 840.
Answer: C
Question: A batsman scored 120 runs whichincluded 3 boundaries and 8sixes. What % of his total score did he make by running between the wickets
A.40%
B.50%
C.55%
D.65%
Answer: B.50%
Explanation: Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 120 - (60)
= 60
Now, we need to calculate 60 is what percent of 120.
=> 60/120 * 100 = 50%
B
Question: A began business with 12500 and is joined afterwards by B with 50000. When did B join, if the profits at the end of the year are divided equally?
A.3 months
B.9 months
C.10 months
D.7 months
Answer: A.3 months
Explanation: Let B join after x months of the start of the business so that B’s money is invested for (12 – x) months.
∴ Profit ratio is 12 × 12500 : (12 – x) × 50000
or 12 : 4(12 – x)
Since profit is equally divided so
12 = 4(12 – x) or x = 3. Thus B joined after 8 months.
Answer A
Question: Working together, Wayne and his son can shovel the entire driveway in three hours. If Wayne can shovel eight times as fast as his son can, how many hours would it take for his son to shovel the entire driveway on his own?
A.4
B.6
C.8
D.9
Answer: D.9
Explanation: W: the time for Wyane to do the job
S: the time for his son to do the job
We have 1/W + 1/S = 1/8 and W = 8S
Then we have 1/(8*S) + 1/S = 1/8 <=> 9/(8*S) = 1/8 <=> S = 9
ANS: D