RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 1100. How many workers were part of the latter production run?
A.26
B.B)10
C.C)11
D.D)15
Answer: A.26
Explanation: The daily average production is given by 5n + 20- given
In the first k days, 500 units are produced
= (5n+20)K =500
k = 500/5n+20...................................1
5 workers were added = 5(n+5)+20 = 5n +45
cumulative is 1100 .. thus for the current period = 1100 -500 = 600
(5n+45)K= 600
k = 600/5n+45........................................2
equate 1 and 2
500/5n+20 = 600 /5n+45
500(5n+45) = 600(5n+20)
2500n + 22500 = 3000n + 12000
-500n = -10500
n = 21
thus n+5 = 26
hence A
Question: A piece of ribbon 4 yards long is used to make bows requiring 15 inches of ribbon for each. What is the maximum number of bows that can be made?
A.8
B.9
C.10
D.11
Answer: B.9
Explanation: 1 Yard = 36 inches
Total length of ribbon = 4 yards = 4*36 inches = 144
Length of ribbon needed for 1 bow = 15 inches
Max number of bows that can be made = 144 / 15
= 9.6
Answer B
Question: If BURNER is coded as CASOIS then how will ALIMENT be coded?
A.BKJLFMU
B.EKOLIMS
C.EMONIOU
D.BRJSFTU
Answer: B.EKOLIMS
Explanation: You take the next consonant or vowel in alphabetical sequence.
Watch:
b - c (next consonant in sequence)
u - a (aeiou, u cycles back to beginning, or a)
r - s
n = o
e = i (next vowel)
r = s
therefore:
a = e (next vowel)
l = m
i = o
m = n
e = i
n = o
t = u
EMONIOU
ANSWER:B
Question: The total of a company's assets in 1994 was 50% greater than the total in 1993, which in turn was 400% greater than the total in 1992. If the total of the company's assets in 1992 was N dollars, what were the company's assets in 1994?
A.5.5N
B.7.5N
C.9.5N
D.11.5N
Answer: B.7.5N
Explanation: In 1992, the company's assets were N.
In 1993, the company's assets were N + 4N = 5N.
In 1994, the company's assets were 5N + 2.5N = 7.5N.
The answer is B.
Question: If the set S is composed of the following numbers {99, 100, 100, 105, 106, 112, 127}, which of the following is largest?
A.The average (arithmetic mean) of set S
B.The median of set S
C.The mode of set S
D.The range of set S
Answer: A.The average (arithmetic mean) of set S
Explanation: A) 99, 100, 100, 105, 106, 112, 127 = 749 and its mean is 749/7 = 107.
B) The list is of 7 numbers and median is 105.
C) Mode is number of repetition of a number in the list , here it is 100.
D) Range = Max value - min value = 127 -99 = 28.
E) SD = square root of (sum of ( mean of series - number)^2 ) / n =>< 100
IMO option A is correct answer..
Question: What is the dividend. divisor 13, the quotient is 17 and the remainder is 1
A.222
B.224
C.226
D.228
Answer: A.222
Explanation: A = d * Q + R
A = 13 * 17 + 1
A = 221 + 1
A = 222
Question: if the price of a book is first decreased by 15% and then increased by 10%, then the net change in the price will be :
A.10
B.388
C.6.5
D.29
Answer: C.6.5
Explanation: Explanation:
Let the original price be Rs. 100.
Decreased by 15% = 85
Then increased 10% on Rs 85 = 85 + 8.5 = 93.5
Net change in price = 100 - 93.5 = 6.5
Answer : C
Question: A truck covers a distance of 360 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 14 km more than that travelled by the truck ?
A.6 hours
B.5 hours
C.7 hours
D.8 hours
Answer: D.8 hours
Explanation: Explanation :
Speed of the truck = Distance/time = 360/8 = 45 kmph
Now, speed of car = (speed of truck + 18) kmph = (45 + 18) = 63 kmph
Distance travelled by car = 360 + 81 = 441 km
Time taken by car = Distance/Speed = 441/63 = 8 hours.
Answer – D
Question: A car crosses a 600m long bridge in 5 mins. What is the speed of car in km per hr?
A.7 km/hr
B.7.2 km/hr
C.7.5 km/hr
D.8 km/hr
Answer: B.7.2 km/hr
Explanation: Speed = 600 m/sec.
5 x 60
= 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
= 2 x 18 km/hr
5
= 7.2 km/hr
B
Question: A can contains a mixture of liquids A and B is the ratio 7:5. When 12 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter of liquid A was contained by the can initially?
A.25
B.27
C.29
D.28
Answer: D.28
Explanation: Ci*Vi = Cf*Vf
(7/12)*(V1 - 12) = (7/16)*V1
(V1 - 12)/V1 = 3/4
12 accounts for the difference of 1 on ratio scale so Initial volume = V1 = 4*12 = 48 litres.
7/12 of the initial mixture was liquid A so liquid A was (7/12)*48 = 28 litres.
Answer : D
Question: 10% of the inhabitants of village having died of cholera.,a panic set in , during which 25% of the remaining inhabitants left the village. The population is then reduced to 4050. Find the number of original inhabitants.
A.600
B.6500
C.6000
D.6500
Answer: C.6000
Explanation: Let the total number of orginal inhabitants be x.
((75/100))*(90/100)*x)=4050  (27/40)*x=4050
x=((4050*40)/27)=6000.
ANSWER C 6000
Question: John found that the average of 15 numbers is 40. If 12 is added to each number then the mean of number is?
A.52
B.45
C.65
D.78
Answer: A.52
Explanation: (x+x1+...x14)/15 = 40
52
Option A
Question: Two numbers are respectively 20% and 60% more than a third number. The percentage that is first of the second is?
A.34%
B.68%
C.51%
D.75%
Answer: D.75%
Explanation: I II III
120 160 100
160----------120
100-----------? => 75%
Answer:D
Question: If a train runs at 40 kmph ,it reach its destination late by 11 minutes but if it runs at 50kmph it is late by 5 minutes only . the correct time for a train to complete its journey is?
let the correct time to complete the journey be x min
distance covered in(x+11)min. at 40 kmph
distance covered in(x+5)min. at 50 kmph
(x+11)/60*40=(x+5)/60*50
x=19min
A.19 min
B.19hrs
C.52min
D.126min
Answer: A.19 min
Explanation: let the correct time to complete the journey be x min
distance covered in(x+11)min. at 40 kmph
distance covered in(x+5)min. at 50 kmph
(x+11)/60*40=(x+5)/60*50
x=19min
Answer(A)
Question: The traffic lights at 3 different roads change after every 14 sec, 72 sec, 108 sec respectively. If they all change simultaneously at 9:15 AM then at what time will they again change simultaneously.
A.9:22:12
B.9:42:15
C.10:15:24
D.9:40:12
Answer: D.9:40:12
Explanation: LCM of 14,72,108 = 1512 = 25mnts 12sec
The lines will change every 25m 12sec
The light will change again after 9:15 AM is = 9:15+0:25:12 = 9:40:12
Answer is D
Question: How many positive 5-digit integers have the odd sum Q of their digits?
A.9*10^2
B.9*10^3
C.10^4
D.45*10^3
Answer: D.45*10^3
Explanation: We are looking at numbers between 10000 and 99999 both inclusive.
There are 90000 numbers.
Now for
10000 : sum of digits is odd;
10001 :sum of digits is even;
10002 : sum of digits is odd ; so on and so forth. So every alternate number is such that the sum of digit is odd.
(Exception for the above statement :
When it is 10009 the sum is even and for 10010 again the sum is even; But if you look at 10019 :sum is odd; 10020 : sum is odd
and this pattern continues so basically the number of odd sum of digits and even sum of digits are equal)
This means exactly half of the numbers will have odd sum Q of their digits. i.e 45000
Answer :D
Question: How many inches are in 2000 millimeters? (round your answer to the nearest hundredth of of an inch).
A.48.74 inches
B.58.74 inches
C.78.74 inches
D.28.74 inches
Answer: C.78.74 inches
Explanation: One inch is the same as 25.4 mm. Let x inches be the same as 1000 mm
x = 1 inch * 2000 mm / 25.4 mm = 78.74 inches
correct answer C
Question: What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 4?
A.123,750
B.164,850
C.164,749
D.149,700
Answer: A.123,750
Explanation: Find the number , Upon Sum of 3 Digits of a number Gives a Reminder 2 when it is Divided by 4
Seeing the Options After Dividing and Finding the Reminder of 2
My Answer was A
Question: A bag contains 3 white balls, 3 black balls & 2 red balls. One by one three balls are drawn out without replacement. What is the probability that the third ball is red?
A.0.25
B.0.15
C.0.35
D.0.45
Answer: A.0.25
Explanation: Favorable outcomes :
WWR -> P(WWR)= 3/8 * 2/7 * 2/6 = 12/336
WRR -> P(WRR)= 3/8 * 2/7 * 1/6 = 6/336
RWR -> P(RWR)= 2/8 * 3/7 * 1/6 = 6/336
BBR -> P(BBR)= 3/8 * 2/7 * 2/6 = 12/336
BRR -> P(BRR)= 3/8 * 2/7 * 1/7 = 6/336
RBR -> P(RBR)= 2/8 * 3/7 * 1/6 = 6/336
WBR -> P(WBR)= 3/8 * 3/7 * 2/6 = 18/336
BWR -> P(BWR)= 3/8 * 3/7 * 2/6 = 18/336
So, P(Total) = 84/336 = 1/4 = 0.25
Answer is A
Question: If x is an integer such that 0 < x < 12, 1 < x < 15, 10 > x > 5, 11 > x > 8, and x + 2 < 12, then x is
A.3
B.5
C.7
D.9
Answer: D.9
Explanation: 0 < x < 12,
1 < x < 15,
-5 < x < 10
8< x < 11
x<10
From above: 8 < x < 10 --> x = 9.
Answer: D.
Question: If the Average of 10 consecutive integers is 24.5 then the 10th integer is :-
A.15
B.20
C.23
D.29
Answer: D.29
Explanation: The average falls between the 5th and 6th integers,
integer 5 = 24, integer 6 = 25.
Counting up to the tenth integer
we get 29.
ANSWER:D
Question: In a certain company, the ratio of the number of managers to the number of non-managers in any department must always be greater than 7 : 37. In the company, what is the maximum number of non-managers in a department that has 9 managers?
A.44
B.45
C.46
D.47
Answer: D.47
Explanation: 9/7 * 37 = 47.6
The answer is D.
Question: A certain list of 300 test scores has an arithmetic mean of 74 and a standard deviation of d, where d is positive. Which of the following two test scores, when added to the list, must result in a list of 302 test scores with a standard deviation less than d?
A. 75 and 80
B. 80 and 85
C. 74 and 74
D. 75 and 75
Answer: C. 74 and 74
Explanation: Ans: C
Deviation means spreading of the numbers from one median point value..
as the set is already established and we need to add only two numbers, this means we can only add numbers which are closer to the median to reduce the deviation.
so 74 and 74 are the most close numbers and they will increase the number of elements in the set without changing the median value.
C
Question: If m is a positive integer greater than 1, what is the sum of the multiples of m from m to m^2, inclusive?
A. m(m + 1)(m-1)
B. m^2(m + 1)/2
C. m^2(m-1)
D. (x^3 + 2x)/2
Answer: B. m^2(m + 1)/2
Explanation: Ans :- B=m^2(m + 1)/2
I substituted 3 in all answer choices.
Option B and C were both satisfying the condition.
So i substituted 4 instead of 3 in all answer choices,
Only B option satisfied.
Question: A can do a piece of work in 15 days. A does the work for 5 days only and leaves the job. B does the remaining work in 6 days.In how many days B alone can do the work?
A.5days
B.7 days
C.12 days
D.9 days
Answer: D.9 days
Explanation: Explanation:
A’s 5 day work = 5*1/15=1/3
Remaining work = 1-1/3=2/3
B completes 2/3 work in 6 days
B alone can do in x days
2/3*x=6
X=9 days
Answer: Option D
Question: If f(b)=b^2 and b is a positive integer, which of the following CANNOT be the value of f(f(b))?
A.1
B.81
C.200
D.256
Answer: C.200
Explanation: f(b)=b^2
f(f(b)) = (b^2)^2 = b^4
Therefore f(f(b)) will be numbers that are 4th power of other numbers.
Checking the options:
1 = 1^$
81 = 3^4
200. This cannot be written as the 4th power of any number
256 = 4^4
625 = 5^4
Answer: C
Question: I walk a certain distance and ride back taking a total time of 37 minutes. I could walk both ways in 55 minutes. How long would it take me to ride both ways?
A.12 mins
B.10 mins
C.19 mins
D.15 mins
Answer: C.19 mins
Explanation: Let the distance be x km. Then,
( Time taken to walk x km) + (time taken to ride x km) =37 min.
( Time taken to walk 2x km ) + ( time taken to ride 2x km )= 74 min.
But, the time taken to walk 2x km = 55 min.
Time taken to ride 2x km = (74-55)min =19 min.
Ans: C
Question: An investor receives a total combined return of 10% on his two different investments. On his $10,000 investment he receives a return of 6%. What is the return on his $20,000 investment?
A.7.25%
B.12%
C.8%
D.8.5%
Answer: B.12%
Explanation: 0.06 * 10000 + 20000x = 0.10(30000)
solving for x give x = 12%
option B
Question: Drum X is 1/2 full of oil and drum Y, which has twice the capacity of drum X, is 1/2 full of oil. If all of the oil in drum X is poured into drum Y, then drum Y will be filled to what capacity?
A.2/3
B.3/4
C.4/5
D.5/6
Answer: B.3/4
Explanation: (1/2)X = (1/4)Y
(1/4)Y + (1/2)Y = (3/4)Y
The answer is B.
Question: Thomas's age and Matt's age are in the ratio 2:3. Two years ago the ratio of their ages was 1:2. Find the ratio of their ages four years hence?
A.1:2
B.2:3
C.3:4
D.4:5
Answer: D.4:5
Explanation: Let ages of Thomas and Matt be x and y respectively.
x/y = 2/3 => x = 2/3 y
(x- 2)/(y - 2) = 1/2
=> 2x - 4 = y - 2 => 2x = y + 2
But x = 2/3 y
2 * 2/3 y = y + 2
4y = 3y + 6 => y = 6years
=> x = 4 years
Ratio of their ages five years hence, (4 +4)/(6 + 4) = 8/10. => 4:5
Answer:D
Question: The charge for a single room at Hotel P is 30 percent less than the charge for a single room at Hotel R and 10 percent less than the charge for a single room at Hotel G. The charge for a single room at Hotel R is what percent greater than the charge for a single room at Hotel G ?
A.28%
B.20%
C.40%
D.50%
Answer: A.28%
Explanation: Let rate in R = 100x
then P = 70x
G = 100y
P = 90y
Thus
70 x=90y
or x = 1.28 y
Ans R = 128y
so increase = 28%
Answer: A
Question: In an exam, A scored 75 percent, B scored 25 percent and C scored 32 percent. The maximum score awarded in the exam is 500. Find the average mark scored by all the three candidates?
A.190
B.200
C.210
D.220
Answer: D.220
Explanation: Average mark scored by all the three boys
= [75/100 (500) + 25/100 (500) + 32/100 (500)] / 3
= 220
Answer: D
Question: A candidate appearing for an examination has to secure 52% marks to pass paper I. But he secured only 45 marks and failed by 35 marks. What is the maximum mark for paper I?
A.110
B.154
C.130
D.140
Answer: B.154
Explanation: he secured 45 marks nd fail by 35 marks so
total marks for pass the examinatn=80
let toal marks x
x*52/100=80
x=154
ANSWER:B
Question: A certain kind of necklace is made from 9 green, 6 white, and 3 orange beads. What is the maximum number of these necklaces that can be made from 45 beads of each color ?
A.7
B.8
C.5
D.6
Answer: C.5
Explanation: Atleast 9 green breads are needed to make a necklace, so irrespective of the combinations of white and orange beads, the number of necklaces that can be formed will be
45/9 =5
Answer:- C
Question: A factory that employs 1000 assembly line workers pays each of these workers $5 per hour for the first 40 hours worked during a week and 1½ times that rate for hours worked in excess of 40. What was the total payroll for the assembly-line workers for a week in which 30 percent of them worked 10 hours, 50 percent worked 40 hours, and the rest worked 50 hours?
A. $180,000
B. $185,000
C. $170,000
D. $200,000
Answer: C. $170,000
Explanation: 30% of 1000 = 300 worked for 20 hours
Payment @ 5/hr
Total Payment = 300*10*5 = 15000
50 % of 1000 = 500 worked for 40 hours
Payment @ 5/hr
Total payment = 500*40*5 = 100000
Remaining 200 worked for 50 Hours
Payment for first 40 Hours @ 5 /hr
Payment = 200*40*5 = 40000
Payment for next 10 hr @ 7.5/hr
Payment = 200 * 10 * 7.5 = 15000
Total Payment = 15000+100000 + 40000 +15000 = 170000
Hence , answer is C
Question: COMPLETE THE SERIES..
1, 3, 7, 11, 13,... ?
A.16
B.17
C.18
D.19
Answer: D.19
Explanation: i think in this series we need to divide series in two parts i.e in terms of even place term and odd place term.i.e
1,7,13 so in odd term you see a difference of 6.
and in even terms there is difference of 8
3,11 so next term will be 11+8=19.
so series is like this
1,3,7,11,13,19.
ANSWER:D
Question: The average of ten numbers is 7 .If each number is multiplied by 12 , then the average of new set of numbers is
A.28
B.236
C.288
D.84
Answer: D.84
Explanation: Explanation:
If each number is multiplied by K, then the new average increases by K times. So new average = 84
Answer:D
Question: The closest approximation of (69.28 × 0.004)/0.03 is
A.0.092
B.0.92
C.9.2
D.92
Answer: C.9.2
Explanation: (69.28 × 0.004)/0.03
1. 0.004 = 4 × 10^(-3)
2. 0.03 = 3 × 10^(-2)
3. (a × b)/c = a × (b/c)
4. 0.004/0.03 = 4 × 10^(-3)/ (3 × 10^(-2)) = 4 × 10^( -3 - (-2))/3 = 4 × 10^(-1) / 3 = (4/3) × 10^(-1) = 1.333 × 10^(-1)
Therefore,
(69.28 × 0.004)/0.03 = 69.28 × (0.004/0.03) = 69.28 × 1.33 × 10^(-1) = 69.28 × 1.33/10 = 6.928*1.33
Now,
7 × 2 = 14
7 × 1 = 7
or better:
6.9 × 1 = 6.9
6.9 × 2 = 13.8
hence,
6.9 <6.928 × 1.33 < 13.8
9.2 is the only answer that satisfies this condition.
ANSWER:C
Question: A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
A.1888
B.1640
C.2768
D.2976
Answer: B.1640
Explanation: (x*8*3)/100 = ((2665 - x)*3*5)/100
24x/100 = 39975/100 - 15x/100
39x = 39975 => x = 1025
Second sum = 2665 – 1025
= 1640
Answer: B
Question: Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds?
A.21 : 9
B.11 : 9
C.71 : 9
D.91 : 9
Answer: B.11 : 9
Explanation: Explanation:
In the same time, they cover 110 km and 90 km respectively.
{\color{Blue} \therefore } Ratio of their speeds = 110 : 90 = 11 : 9
Answer: B
Question: If 0 < x ≤ 3, then which one of the following is the maximum value of (x – 1)^2 + x ?
A.–2
B.–1
C.7
D.1
Answer: C.7
Explanation: the maximum value of (x – 1)^2 + x for 0 < x ≤ 3 is when x=3 --> (x – 1)^2 + x =7
Answer C
Question: In Township K, 1/5 of the housing units are equiped with cable Tv. If 1/10 of the housing units, including 1/6 of those that are equiped with cable tv, are equipped with videocassette recorders, what fraction of the housing units have neither cable tv nor videocassette recorders?
A.23/30
B.11/15
C.7/10
D.1/6
Answer: B.11/15
Explanation: 1/5 -- cable TV (This includes some data from video cassette recorder)
1/10 -- video cassette recorder including 1/6(equiped with cable tv) i.e. 1/6(1/5) = 1/30
therefore only video cassette recorder = 1/10 - 1/30 = 1/15
Total = 1/5+1/15+neither cable tv nor videocassette recorders
1 = 4/15 + neither cable tv nor videocassette recorders
therefore neither cable tv nor videocassette recorders = 1-4/15 = 11/15
Hence B.
Question: A room has both an entrance and an exit door. The room can fill up with people in 5 hours. The room can be empty of people in 15 hours. If it is desired that the room should be filled, from empty, exactly 6 hours after people begin entering the room at 9:30am, then at what time should people begin exiting the room?
A.10:00am
B.10:45am
C.12:00pm
D.12:30pm
Answer: D.12:30pm
Explanation: In 6 hours the entrance door is opened to fill the room equal to 6*1/5 = 6/5 of the room. So, 1/5 more than necessary, which should be compensated by people using the exit door. To empty out 1/5 of the people, the exit door needs 15/5 = 3 hours.
Therefore, the exit door should be used at 9:30am + 6 hours - 3 hours = 12:30pm.
Answer: D.
Question: The dimensions of each book in an encyclopedia set measures 8 in x 4 in x 12 in. (l x w x h). Each shelf (i.e. each divider) has a surface area of 848 sq in., where the thickness is 1 in and the width is 16 in. Assuming there is enough space in between shelves, how many shelves are needed to fit all of the books?
A.7
B.12
C.13
D.5
Answer: D.5
Explanation: Surface area of each shelf= 2ab + 2ac + 2bc
848 = 2 x 1 x 16 + 2 x 1 x c + 2 x 16 x c
848 = 32 + 2c + 32c
816 = 34c
c = 24 in. (i.e. the length of each shelf)
Each book is 4 in thick
24/4 = 6 books per shelf
26/6 = 4.333=5 shelves
Answer is D
Question: From a Group of 8 People, Including Timo and Gary, 3 people are to be selected at random to work on a certain project. What is the probability that 3 people selected will include Timo but not Gary
A.5/56
B.9/56
C.15/56
D.21/56
Answer: C.15/56
Explanation: Number of ways of selecting 3 people out of 8 people = 8C3
In the three members Timo will always be there in the team. At this step we have vacancy for 2 more members and 7 members are available. Gary cannot be there in the team. So 2 members have to be selected and the number of available members = 7 -Gary = 6
Number of ways to form a 3 member team that includes Timo and excludes Gary = 6C2
Probability = 6C2/8C3 = 15/56
Answer: C
Question: The price of a car and AC are in the ratio 3:2. If the scooter costs $500 more than the AC. then the price of the AC?
A.1500
B.200
C.1700
D.2000
Answer: A.1500
Explanation: Let the price of the Car and AC is 3x and 2x
3x-2x = 500
x = 500
Price of AC = 3*500 = $1500
Answer is A
Question: The difference between the ages of two persons is 10 years.Fifteen years ago ,the elder one was twice as old as the younger one.The present age of the elder person is :
A.25 years
B.35 years
C.45 years
D.55 years
Answer: B.35 years
Explanation: Solution
Let their ages be x year and (x + 10) years respectively.
Then,(x + 10) - 15 = 2 (x - 15) ⇔ x-5 = 2x-30 ⇔ x =25.
∴ Present age of the elder person =(x + 10) =35 years. Answer B
Question: A dog takes 4 leaps for every 5 leaps of a hare but 3 leaps of a dog are equal to 4 leaps of the hare. Compare their speeds?
A.4:5
B.16:15
C.9:13
D.5:15
Answer: B.16:15
Explanation: Let the distance covered in 1 leap of the dog be x and that covered in 1 leap of the hare be y
Then 3x = 4y
x = 4/3 y
4x = 16/3 y
Ratio of speeds of dog and hare = Ratio of distances covered by them in the same time
= 4x:5y = 16/3 y : 5 = 16:15
Answer is B
Question: The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 47. The corrected new mean is?
A.36.7
B.36.1
C.36.5
D.36.02
Answer: D.36.02
Explanation: Correct sum
= (36 * 50 + 48 - 47)
= 1801.
Correct mean = 1801/50
= 36.02
Answer:D
Question: If a equals the sum of the even integers from 2 to 20, inclusive, and b equals the sum of the odd integers from 1 to 19, inclusive, what is the value of a - b ?
A.1
B.10
C.19
D.20
Answer: C.19
Explanation: Sum of consecutive odd or even integers = (no. of odd or even ints) * (first int + last int) / 2
Here A = sum of even ints from 2 to 20, inclusive
number of even ints = 10,
first int + last int = 2+20 = 22
A = 10*22 / 2 = 110
B = sum of odd ints from 1 to 19, inclusive
number of odd ints = 10,
first int + last int = 1+19 = 20
A = 10*20 / 2 = 100
A-B = 110 - 100 = 10
ANSWER:C
Question: The length of the longest tape in cm which can be used to measure exactly, the length 6m; 5m ; and 12m is:
A.200
B.100
C.50
D.1200
Answer: B.100
Explanation: The three lengths in cm are 600,500 & 1200.
HCF of 600, 500 & 1200 is 100
Hence, the answer is 100 cm.
ANSWER:B
Question: Find the numbers which are in the ratio 3:2:4 such that the sum of the first and the second added to the difference of the third and the second is 21.
A.9, 6, 16
B.9, 6, 19
C.9, 6, 16
D.9, 6, 12
Answer: D.9, 6, 12
Explanation: Let the numbers be a, b and c.
a:b:c = 3:2:4
Given, (a + b) + (c - b) = 21
=> a + c = 21
=> 3x + 4x = 21 => x = 3
a, b, c are 3x, 2x, 4x
a, b, c are 9, 6, 12.
Answer: D