RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The amount of principal Rs.4000 at compound interest at the ratio of 10% p.a. for 3 years is
A.Rs.5342
B.Rs.4325
C.Rs.5324
D.Rs.3425
Answer: C.Rs.5324
Explanation: 5324
ANSWER:C
Question: A man can row a boat at 36 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 100 km upstream?
A.10/3
B.10/7
C.10/9
D.10/11
Answer: A.10/3
Explanation: Speed upstream = 36-6=30 kmph.
Time required to cover 100 km upstream = d/s = 100/30 = 10/3 hours. Answer:A
Question: A person got Rs.48 more when he invested a certain sum at compound interest instead of simple interest for two years at 8% p.a. Find the sum?
A.7500
B.2776
C.2877
D.2667
Answer: A.7500
Explanation: P = (d * 1002) / R2
=> (48 * 100 * 100) / 8 * 8 = Rs.7500
Answer:A
Question: Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?
A.42, 33
B.42, 36
C.44, 33
D.44, 36
Answer: A.42, 33
Explanation: Explanation:
Let the marks secured by them be x and (x+9)
sum of their marks =x+(x+9)=2x+9
Given that (x+9) was 56% of the sum of their marks
=X+9=56/100(2X+9)
X=33
Then (x+9)=33+9=42
Hence their marks are 33 and 42
ANSWER IS A
Question: In a bag containing 3balls, a white ball was placed and then 1ball was taken out at random. What is the probability that the extracted ball would turn on to be white, if all possible hypothesis concerning the color of theballs that initiallyin the bag were equally possible ?
A.2/3
B.5/8
C.5/9
D.3/7
Answer: B.5/8
Explanation: Since, all possible hypothesis regarding the colour of the balls are equally likely, therefore these could be 3 white balls, initially in the bag.
∴ Required probability = 1/4 [1 + 3/4 + 1/2 + 1/4]
= 1/4 [(4 + 3 + 2 + 1)/4] = 5/8
B
Question: The average mark of the students of a class in a particular exam is 90. If 2 students whose average mark in that exam is 45 are excluded, the average mark of the remaining will be 95. Find the number of students who wrote the exam?
A.10
B.40
C.20
D.30
Answer: C.20
Explanation: Let the number of students who wrote the exam be x.
Total marks of students = 90 x.
Total marks of (x - 2) students = 95(x - 2)
90x - (2 * 45) = 95(x - 2)
100 = 5x => x = 20
Answer: C
Question: The set S has 36 different subsets each of which contains exactly two elements. How many subsets of S could contain exactly six elements each?
A.96
B.80
C.84
D.88
Answer: C.84
Explanation: nC2 = 36
=> n*(n-1)/2 = 36 by middle term factor and n cannot be negative
=> n = 9
nC3 = 9C6 = 9!/6!*(9-6)!= 9*8*7*6!/6!*3*2 =84
So, Answer is C.
Question: The length, breadth and height of a room are in the ratio 4 : 4 : 2. If the breadth and height are halved while the length is doubled, then the total area of the four walls of the room will
A.(a) decrease by 37.5%
B.(b) decrease by 13.64%
C.(c) decrease by 15%
D.(d) decrease by 18.75%
Answer: A.(a) decrease by 37.5%
Explanation: Length (L) = 4
Breadth (B) = 4
Height (H) = 2
Total Area of Walls = 2(BH + LH) = 2*(4*2 + 4*2) = 2*(8+8) = 32
Then, Finally
Length (L) = 2*4 = 8
Breadth (B) = 4/2 = 2
Height (H) = 2/2 = 1
Total Area of Walls = 2(BH + LH) = 2*(2*1 + 8*1) = 2*(2+8) = 20
% change in Area of four walls = (Final Area-Initial Area)*100 /Initial Area
i.e. % change in Area of four walls = (20-32)*100 /32=- 37.5% (Decrease)
Answer: Option A
Question: If Z= Y^2 + d W+ 9 does not cut the x-axis, then which of the following could be a possible value of d?
I. 0
II. -3
III. 9
A.III only
B.II only
C.I and II only
D.II and III only
Answer: C.I and II only
Explanation: Here C is the answer as A and B statements will provide the discriminant to be negative thereby making the x axis cutting impossible.
Hence only 1 and 2
thus C
Question: The number of stamps that P and Q had were in the ratio of 7:4 respectively. After P gave Q 8 stamps, the ratio of the number of P's stamps to the number of Q's stamps was 6:5. As a result of the gift, P had how many more stamps than Q?
A.4
B.8
C.12
D.16
Answer: B.8
Explanation: P started with 7k stamps and Q started with 4k stamps.
(7k-8)/(4k+8) = 6/5
35k - 24k = 48 + 40
11k = 88
k = 8
P has 7(8) - 8 = 48 stamps and Q has 4(8)+8 = 40 stamps.
The answer is B.
Question: How many positive even integers less than 100 contain digits 5 or 7?
A.10
B.17
C.18
D.19
Answer: A.10
Explanation: Two digit numbers:
5 at tens place: 50,52,54,56,58
7 at tens place: 70,72,74,76,78
If 5 and 7 is at units place, the number cant be even
Total:5+5= 10
Answer A
Question: 3^b + 3^b + 3^b =
A.7^b
B.7^(b + 1)
C.7^(7b)
D.3^(b + 1)
Answer: D.3^(b + 1)
Explanation: Easy one.
3*3^b = 3^(b+1)
Ans. D
Question: A and B go around a circular track of length 150 m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point?
A.30 sec
B.198 sec
C.178 sec
D.665 sec
Answer: A.30 sec
Explanation: Time taken to meet for the first time at the starting point
= LCM { length of the track / speed of A , length of the track / speed of B}
= LCM { 150/ (36 * 5/18) , 150/ (54 * 5 /18) }
= LCM (15, 10) = 30 sec.
Answer:A
Question: Donna, Chris, and Austin have a total of $93 in their wallets. Donna has $7 more than Chris. Austin has 3 times what Donna has. How much do they have in their wallets?
A.D$20 C$13 Au$60
B.D$40 C$23 Au$40
C.D$60 C$33 Au$30
D.D$80 C$43 Au$20
Answer: A.D$20 C$13 Au$60
Explanation: Let the amount in Chris’s wallet be $x
Donna has $7 more than Chrish's wallet = $(x + 7)
Austin has 3 times than Donna's wallet = $3(x + 7)
According to the problem, Donna, chris, and Austin have a total of $93 in their wallets.
Therefore,
x + (x + 7) + 3(x + 7) = 93
x + x + 7 + 3x + 21 = 93
5x + 28 = 93
- 28 -28 (subtract 28 from both sides)
5x = 65
or, 5x/5 = 65/5 (Divide both sides by 5)
x = 13
Amount in Chris wallet = $x = $13
Amount in Donna's wallet = $(x + 7) = $(13 + 7) = $20
Amount in Austin 's wallet = $3(x + 7) = $3(13 + 7) = $3(20) = $ 60
Answer: Amount in Chris’s wallet: $13
Amount in Donna's wallet: $20
Amount in Austin's wallet: $60
correct answer A
Question: A grocer purchased 20 kg of rice at the rate of 15 per kg and 30 kg of rice at the rate of 13 per kg. At what price per kg should he sell the mixture to earn 331/3% profit on the cost price?
A.28.0
B.20.0
C.18.4
D.17.4
Answer: C.18.4
Explanation: CP= 20 ×15 + 30 ×13 = 690
\ sp = 4⁄3 of 690 × 1⁄50 = 18.40
Answer C
Question: Weights of two friends Ram and Shyam are in the ratio 4:5. If Ram's weight is increased by 10% and total weight of Ram and Shyam become 82.8 kg, with an increases of 15%. By what percent did the weight of Shyam has to be increased?
A.19%
B.10%
C.21%
D.16%
Answer: A.19%
Explanation: Solution:
given ratio of Ram and Shayam's weight = 4:5
Hence, (x-15)/(15-10) = 4/5
Or, x = 19%.
Answer: Option A
Question: The radius of a semi circle is 6.7 cm then its perimeter is?
A.32.75
B.32.45
C.22.45
D.34.45
Answer: D.34.45
Explanation: 36/7 r = 6.7 = 34.45
Answer:D
Question: The average weight of 8 person's increases by 3 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
A.60 kg
B.70 kg
C.80 kg
D.89 kg
Answer: D.89 kg
Explanation: Total weight increased = (8 x 3) kg = 24 kg.
Weight of new person = (65 + 24) kg = 89 kg.
D)
Question: The average marks of a class of 30 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students?
A.82.5
B.52.9
C.52.2
D.52.5
Answer: D.52.5
Explanation: Sum of the marks for the class of 30 students = 30 * 40 = 1200
Sum of the marks for the class of 50 students = 50 * 60 = 3000
Sum of the marks for the class of 80 students =
1200 + 3000 = 4200
Average marks of all the students = 4200/80 = 52.5
Answer:D
Question: 20 litres of mixture contains 40% alcohol and the rest water. If 8litres of water be mixed with it, the percentage of alcohol in the new mixture would be?
A.26.32%
B.35.14%
C.28.57%
D.25%
Answer: C.28.57%
Explanation: Alcohol in the 20litres of mix. = 40% of 20litres = (40*20/100) = 8litres
water in it = 20-8 = 12litres
new quantity of mix. = 20+8 = 28 litres
Quantity of alcohol in it = 8litres
Percentage of alcohol in new mix. = 8*100/28 = 50/3= 28.57%
Answer is C
Question: Three numbers are in the ratio 4 : 5 : 6 and their average is 25 . The largest number is:
A.28
B.30
C.36
D.42
Answer: B.30
Explanation: Explanation:
Let the numbers be 4x, 5x and 6x. Therefore,
(4x+5x+6x)/3 = 25
15x = 75
x = 5
Largest number = 6x = 30.
ANSWER B
Question: The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
A.448
B.488
C.542
D.548
Answer: D.548
Explanation: Required number = (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548.
answer :D
Question: Calculate the standard deviation of each data set {10,10,10,10,10}
A.8.05
B.9
C.10
D.15
Answer: A.8.05
Explanation: Standard Deviation Data set A
= √[ ( (9-10)2+(10-10)2+(11-10)2+(7-10)2+(13-10)2 )/5 ] = 2
Standard Deviation Data set B
= √[ ( (10-10)2+(10-10)2+(10-10)2+(10-10)2+(10-10)2 )/5 ] = 0
Standard Deviation Data set C
= √[ ( (1-10)2+(1-10)2+(10-10)2+(19-10)2+(19-10)2 )/5 ] = 8.05
Option A
Question: If x is a positive even number, then each of the following is odd EXCEPT
A.(x + 3)(x + 5)
B.x^2 + 5
C.x^2 + 6x + 9
D.3x^2 + 4
Answer: D.3x^2 + 4
Explanation: lets see the choices..
A. (x + 3)(x + 5)
We have two terms with x and each is added with a odd number..
each bracket becomes odd and Odd*Odd=Odd
B. x^2 + 5
here we are adding an Odd number to even.. so E + O=O
C. x^2 + 6x + 9
here we are again adding an Odd number to even.. so E +E + O=O
D. 3x^2 + 4
here we are adding an Even number to even.. so E + E=E..
so this is our answer
E. 5(x + 3)
again O*O=O
ANSWER:D
Question: A rectangular box of volume x has width, depth and height in the ratio of 5:1:2 (in that order). What is the width as a function of x?
A.(4x/12)^(1/2)
B.(10x/4)^(1/2)
C.(5x)^(1/2)
D.(2x/5)^(1/2)
Answer: B.(10x/4)^(1/2)
Explanation: We are given width = 5, depth = 1, height = 2
Then Volume x = Width x Depth x Height = 5*1*2 = 10
i.e. x = 10
i.e. The correct option should result in 5 (the width) on substituting the value of x=10
Checking options with x=10
A) (4x/12)^(1/2) = (4*10/12)^(1/2) = (40/12)^(1/2) INCORRECT ANSWER
B) (10x/4)^(1/2) = (10*10/4)^(1/2) = 25^(1/2) = 5 CORRECT ANSWER
C) (5x)^(1/2) = (5*10)^(1/2) = 50^(1/2) INCORRECT ANSWER
D) (2x/5)^(1/2) = (2*10/5)^(1/2) = 4^(1/2) = 2 INCORRECT ANSWER
E) (4x/3)^(1/2) = (4*10/3)^(1/2) = 40/3^(1/2) INCORRECT ANSWER
Answer: Option B
Question: A man has a job, which requires him to work 8 straight days and rest on the ninth day. If he started work on Monday, find the day of the week on which he gets his 12th rest day.
A.Thursday
B.Wednesday
C.Tuesday
D.Friday
Answer: B.Wednesday
Explanation: Explanation :
The man get his 1st rest on the ninth day,
So he will get his 12th rest on : 12x9 = 108th day
The first day is monday so 108th(15x7 + 3) day will be same as 3rd day which will be Wednesday.
Answer : B
Question: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?
A.9:1
B.9:9
C.9:7
D.9:5
Answer: A.9:1
Explanation: Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 - 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1 Answer:A
Question: By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 35%?
A.228
B.480
C.267
D.416
Answer: D.416
Explanation: SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 25% = 25% of 640 = Rs.224
SP = CP - Loss = 640 - 224 = Rs.416
Answer: D
Question: What is the smallest positive integer x for which x3+5xx3+5x has a value more than 80?
A.2
B.3
C.4
D.5
Answer: C.4
Explanation: 4^3 + 5*4 = 64 + 20 = 84
That's pretty close to 80 already so I can cancel D and E since they'll be more than 80. B just needs to be checked just in case so...
3^3 + 5*3 = 27 + 15 = not close to 80.
Therefore, 4 (C) is the smallest positive integer x for which x^3 + 5x has a value more than 80.ANSWER:C
Question: The cash realised on selling a 14% stock is Rs.109.25, brokerage being 1/4% is
A.123
B.109
C.100
D.156
Answer: B.109
Explanation: Explanation:
Cash realised= Rs. (109.25 - 0.25)
= Rs. 109.
Answer: B
Question: How many terminating zeroes W does 200! have?
A. 40
B. 48
C. 49
D. 55
Answer: C. 49
Explanation: You have 40 multiples of 5, 8 of 25 and 1 of 125. This will give 49 zeros.C
Question: P, Q and R can do a work in 20, 30 and 60 days respectively. How many days does it need to complete the work if P does the work and he is assisted by Q and R on every third day?
A.10 days
B.14 days
C.15 days
D.9 days
Answer: C.15 days
Explanation: Explanation :
Amount of work P can do in 1 day = 1/20
Amount of work Q can do in 1 day = 1/30
Amount of work R can do in 1 day = 1/60
P is working alone and every third day Q and R is helping him
Work completed in every three days = 2 × (1/20) + (1/20 + 1/30 + 1/60) = 1/5
So work completed in 15 days = 5 × 1/5 = 1
Ie, the work will be done in 15 days
Answer :C
Question: 30 buckets of water fill a tank when the capacity of each bucket is 13.5 litres. How many buckets will be required to fill the same tank if the capacity of each bucket is 9 litres?
A.30
B.32
C.45
D.Data inadequate
Answer: C.45
Explanation: Capacity of the tank = 30 Ã— 13.5= 405 litres
When the capacity of each bucket = 9 litres, then the required no. of buckets
=405â„9 = 45
Answer C
Question: Surekha started a business investing Rs.25,000 in 1999. In 2000, he invested an additional amount of Rs. 10,000 and Rajesh joined him with an amount of Rs. 35,000. In 2001, Surekha invested another additional amount of Rs.10,000 and Jay joined them with an amount of Rs.35,000. What will be Rajesh's share in the profit of Rs.1,20,000 earned at the end of 3 years from the start of the business in 1999?
A.Rs 40000
B.Rs 50000
C.Rs 70000
D.Rs 75000
Answer: A.Rs 40000
Explanation: Surekha:Rajesh:Jay= (25000×12+35000×12+45000×12):(35000×24) : (35000×12) = 1260000 : 840000 : 420000 = 3 : 2 : 1. Rajesh's share =Rs.(120000×2/6) = Rs.40000.
Answer A
Question: A boy rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. His average speed for the entire trip is approximately?
A.10.7 km/hr
B.10.8 km/hr
C.17.8 km/hr
D.10.5 km/hr
Answer: B.10.8 km/hr
Explanation: Total distance traveled = 10 + 12 = 22 km /hr.
Total time taken = 10/12 + 12/10 = 61/30 hrs.
Average speed = 22 * 30/61 = 10.8 km/hr.
Answer:B
Question: A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?
A.2.4 km
B.2.9 km
C.3.4 km
D.4.4 km
Answer: A.2.4 km
Explanation: Explanation:
Speed in still water = 5 kmph
Speed of the current = 1 kmph
Speed downstream = (5+1) = 6 kmph
Speed upstream = (5-1) = 4 kmph
Let the required distance be x km
Total time taken = 1 hour
⇒ x/6+x/4=1
⇒2x+3x=12
⇒5x=12
⇒x=2.4 km
Answer: Option A
Question: On Monday, Lou drives his vehicle with 27-inch tires, averaging x miles per hour. On Tuesday, Lou switches the tires on his vehicle to 30-inch tires yet drives to work at the same average speed as on Monday. What is the percent change from Monday to Tuesday in the average number of revolutions that Lou's tires make per second?
A.Decrease by 14.3%
B.Decrease by 10%
C.Increase by 14.3%
D.Increase by 12.5%
Answer: B.Decrease by 10%
Explanation: 270 the LCM
On Tuesday 270/30 =9
On Monday 270/27 = 10
Therefore, 9-10/10 = -10% decrease
Answer is B
Question: Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 3 days?
A.2/5
B.1/6
C.1/4
D.1/9
Answer: B.1/6
Explanation: B
1/6
A's one day's work = 1/30
B's one day's work = 1/45
(A + B)'s one day's work = 1/30 + 1/45 = 1/18
The part of the work completed in 3 days = 3 (1/18) = 1/6.
Question: At a certain company, each employee has a salary grade s that is at least 1 and at most 5. Each employee receives an hourly wage p, in dollars, determined by the formula p = 9.50 + 0.25(s – 1). An employee with a salary grade of 4 receives how many more dollars per hour than an employee with a salary grade of 1?
A.$0.75
B.$1.00
C.$1.25
D.$1.50
Answer: A.$0.75
Explanation: Salary grade of 4 is p(4)=9.50+0.25(4–1)=9.50+0.25*3;
Salary grade of 1 is p(1)=9.50 + 0.25(1–1)=9.50;
p(4)-p(1)=9.50+0.25*4-9.50=0.75.
Answer: A.
Question: A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 sec. What is the length of the goods train?
A.337
B.278
C.287
D.270
Answer: D.270
Explanation: Speed = 72 * 5/18 = 20 m/sec.
Time = 26 sec.
Let the length of the train be x meters.
Then, (x + 250)/26 = 20
x = 270 m.
Answer: D
Question: Take a marker and start from a corner of a cube. How many edges you can trace if you dont move the marker twice anywhere and never remove it? (You can move the marker only on the corner and edges)
A.7
B.8
C.9
D.10
Answer: C.9
Explanation: we can trace 9 edeges
ANSWER:C
Question: X and Y invest Rs.21000 and Rs.17500 respectively in a business. At the end of the year, they make a profit of Rs.26400. What is the share of X in the profit?
A.Rs 14400
B.Rs 26400
C.Rs 12000
D.Rs 12500
Answer: A.Rs 14400
Explanation: Ratio of the investment
=21000:17500=210:175 = 42:35 = 6:5
26400*6/11=2400*6 =14400
ANSWER A
Question: An article is bought for Rs.675 and sold for Rs.900, find the gain percent?
A.33 1/8%
B.33 3/3%
C.33 1/3%
D.32 1/3%
Answer: C.33 1/3%
Explanation: 675 ---- 225
100 ---- ? => 33 1/3%
Answer:C
Question: Two cups X and Y contain coffee and water combined in the ratio 8:5 and 5:2 correspondingly. What is the ratio in these 2 combinations be combined to get a new combination has coffee and a water in the ratio of 9:4?
A.2:5
B.2:3
C.2:7
D.2:9
Answer: C.2:7
Explanation: Explanation :
i) : If C.P. of coffee be Re.1
Given ratio of combination in X= 8:5
Coffee in 1 cup combination in X = (8/13)cups
C.P of 1 cup combination in X= Rs. 8/13
Therefore, The ratio of Combination in Y = 5:2
Coffee in 1 cup combination in Y – (5/7) cups
C.P of 1 cup combination in B = Rs. 5/7
Ratio of new combination = 9:4
milk in 1 cup combination = 9/13
C.P of 1 cup combination = Rs/ 9/13 (Mean price)
ii) : By the rule of allegation,
i. C.P of 1 cup of combination in X =8/13
ii. C.P of 1 cup of combination in Y = 5/7
iii. Mean price (p) = 9/13
iv. d – m = 9/13 – 5-7 = 2/91
v. m – c = 9/13 – 8/13 = 1/13
Needed ratio = 2/91 : 1/13 = 2:7
Answer : C
Question: A seller uses 840gm in place of 1kg to sell his goods. Find his actual % profit or loss, when he sells his article his article on 4% gain on cost price?
A.23 17/21%
B.25%
C.27 25/37%
D.30%
Answer: A.23 17/21%
Explanation: Selling price of 840gm = 100+4 = $104
Profit = 104-84 = $20
% of profit = 20*100/84 = 23 17/21 %
Answer is A
Question: Write 840,000,000,000 in scientific notation.
A.8.4 * 10^11
B.800.900 * 10^11
C.8.900 * 10^11
D.80.9000* 10^11
Answer: A.8.4 * 10^11
Explanation: a * 10 n , where a is a real number such that 1 * |a| < 10 and n is an integer.
840,000,000,000 = 8.4* 100,000,000,000 = 8.4 * 10 11**
correct answer A
Question: The product of all the prime numbers less than 20 is closest to which of the following powers of 20 ?
A. 10^9
B. 10^8
C. 10^7
D. 10^6
Answer: C. 10^7
Explanation: 2*3*5*7*11*13*17*19
2*19*3*17*5*13*7*11
38*51*65*77
By approximation
40*50*70*70
2000*4900
By approximation
2000*5000
10,000,000
C
Question: Tough and Tricky questions: Distance/Rate.
On a reconnaissance mission, a state-of-the-art nuclear powered submarine traveled 300 miles to reposition itself in the proximity of an aircraft carrier. This journey would have taken 1.5 hour less if the submarine had traveled 10 miles per hour faster. What was the average speed, in miles per hour, for the actual journey?
A.20
B.40
C.60
D.80
Answer: B.40
Explanation: Say, if speed is 60, 300/40 = 7.5 hrs and 300/50 = 6 hrs (a reduction of 1.5 hr -> Correct answer)
Answer (B)
Question: A merchant sells an item at a 20% discount, but still makes a gross profit of 20 percent of the cost. What percent W of the cost would the gross profit on the item have been if it had been sold without the discount?
A.20%
B.40%
C.50%
D.60%
Answer: C.50%
Explanation: Let the Market Price of the product is MP.
Let the Original Cost Price of the product is CP.
Selling Price (Discounted Price) = 100%of MP - 20%MP
= 80% of MP. ---------------- (1)
Profit made by selling at discounted price = 20% of CP -------------- (2)
Apply the formula:
Profit W= Selling Price - Original Cost Price
=> 20% of CP = 80% of MP - 100% CP
=> MP = 120CP/80 = 3/2 (CP)
Now if Product is sold without any discount, then,
Profit = Selling Price (without discount) - Original Cost Price
= Market Price - Original Cost Price
= MP - CP
= 3/2 CP - CP
= 1/2 CP
=50%of CP
Thus, Answer should beC.
Question: The expression 10^12−120 is divisible by all of the following integers EXCEPT
A.7
B.3
C.4
D.8
Answer: A.7
Explanation: Yeah. I agree this question has two answers which are (B) and (E). If 10 is power to odd number and equal or more than 5, then the answer choice (A) is correct.
Question: Seller selling an apple for Rs.19, a Seller loses 1/6th of what it costs him. The CP of the apple is?
A.10
B.12
C.20
D.18
Answer: C.20
Explanation: SP=19Loss=CP20Loss=CP−SP=CP−19⇒CP20=CP−19⇒19 CP20=19⇒CP20=1⇒CP=20
C
Question: Ifaequals the sum of the even integers from 2 to 60, inclusive, andbequals the sum of the odd integers from 1 to 59, inclusive, what is the value of a - b ?
A.1
B.10
C.30
D.20
Answer: C.30
Explanation: This is a solution from Beatthegmat:
even numbers:
(60-2)/2 + 1 = 30 even integers.
(60+2)/2 = 31 is the average of the even set.
sum = avg*(#of elements) = 31*30 = 930 = a
odd numbers:
(59-1)/2 + 1 = 30 odd integers.
(59+1)/2 = 30 is the average of the odd set.
sum = avg*(#of elements) = 30*30 = 900 = b
a-b = 930 - 900 = 30. Answer : C
Question: The value of (1/log3 60 + 1/log4 60 + 1/log5 60) is:
A.0
B.1
C.5
D.60
Answer: B.1
Explanation: log60 3 + log60 4 + log60 5 + log60 (3*4*5)
= log60 60 = 1
ANSWER:B
Question: Rich has 3 green, 2 red and 3 blue balls in a bag. He randomly picks 5 from the bag without replacement. What is the probability W that of the 5 drawn balls, Rich has picked 1 red, 2 green, and 2 blue balls?
A.8/28
B.W=9/28
C.W=10/28
D.10/18
Answer: B.W=9/28
Explanation: (3c2 *2c1*3c2)/8c5
=(3*2*3)/(8*7*6/3*2)
=18/56
=9/28
B
Question: Eight years ago, Ajay's age was 4/3 times that of Vijay. Eight years hence, Ajay's age will be 6/5 times that of Vijay. What is the present age of Ajay?
A.30 years
B.40 years
C.32 years
D.48 years
Answer: B.40 years
Explanation: Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively.
A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8)
3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8
V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8
=> 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8
=> 10 - 20/3 = 10/12 A - 9/12 A
=> 10/3 = A/12 => A = 40.
ANSWER:B
Question: A, B and C start a business each investing 20,000. After 6 months A withdrew 5000, B withdrew 4000 and C invests 6000 more. At the end of the year, a total profit of 67,600 was recorded. Find the share of B.
A.20,000
B.21,200
C.21,600
D.20,500
Answer: C.21,600
Explanation: Ratio of the capitals of A, B and C
= 20000 Ã— 6 + 15000 Ã— 6 : 20000 Ã— 6 + 16000 Ã—6 : 20000 Ã— 6 + 26000 Ã— 6
= 210000 : 216000 : 250000 = 210 : 216 : 250
Bâ€™s share = (67600 Ã— 216â„676) = 21600
Answer C