RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Without stoppages, a train travels certain distance with an average speed of 100 km/h, and with stoppages, it covers the same distance with an average speed of 95 km/h. How many minutes per hour the train stops ?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: Due to stoppages, it covers 5 km less .
Time taken to cover 5 km = 5â„100h = 1â„20h
= 1â„20 Ã— 60 min = 3 min
Answer C
Question: A man leaves a point P at 6 a.m. and reaches the point Q at 10 a.m. another man leaves the point give at 8 a.m. and reaches the point P at 12 noon. At what time do they meet?
A.6
B.7
C.8
D.9
Answer: C.8
Explanation: 9 a.m.
Answer: C
Question: Two drivers began their journey with the same amount of petrol in their cars at the same time. The only difference is that the first driver�s car could drive 4 hours in that amount of petrol and the second one could drive 5 hours.
However, they only drove for some time and found that the amount of petrol that was left in one of the cars was four times the petrol left in the other one.
For how long had they driven at this point of time?
A.2.75 hours
B.3.75 hours
C.4.75 hours
D.5.75 hours
Answer: B.3.75 hours
Explanation: Solution:
3.75 hours
Explanation:
While you can solve it as you like, a simple mathematical equation can be used to find out.
Let M be the amount of petrol initially.
Let N be the time for which they drove.
According to the question, the amount of petrol used by first car in N hours = MN / 4
The amount of petrol used by second car in N hours = MN / 5
Hence, the amount of petrol left in the first car = (M - MN / 4)
The amount of petrol left in the second car = (M - MN / 5)
AS per the details given in the question, we can form the below equation:
M - MN / 5 = 4(M - MN / 4)
N = 15 / 4 or 3.75 hours.
Hence, both the drivers have driven the car for 3.75 hours at that particular time.
Answer B
Question: Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
A.5/11
B.6/11
C.7/11
D.8/11
Answer: B.6/11
Explanation: PART filled (A+B+C) in 3 min = 3(1/30+1/20+1/10)=(3*11/60)=11/20
=>3/10
req ratio = 6/11
ANSWER B
Question: A,B,C subscribe Rs.50,000 for a business.A subscribes Rs.4000 more than B and B Rs.5000 more than C.Out of a total profit of Rs.35,000,A receives :
A.Rs.8400
B.Rs.11,900
C.Rs.13,600
D.Rs.14,700
Answer: D.Rs.14,700
Explanation: Solution
Let C = x.Then, B = x + 5000 and A = x + 5000 + 4000 - x + 9000.
So, x + x + 5000 + x + 9000 - 50000 3x - 36000 x =12,000.
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
∴ A’s share = Rs. (35000x21/50) = Rs. 14,700. Answer D
Question: A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the Length of the other train?
A.230 m
B.240 m
C.260 m
D.320 m
Answer: A.230 m
Explanation: Solution
Relative Speed	= (120 + 80)km/hr
= (200 x 5/18)m/sec
= (500 / 9)m/sec
Let the length of the other train be x metres
Then, x + 270 / 9
x + 270 = 500
x = 230.
Answer A
Question: A photographer is to take group photographs of a class of students for the school magazine such that each photograph should have five students. If there are four girls and four boys in the class and each photograph must not have two girls or two boys standing together, how many different photographs can the photographer take?
A.80
B.288
C.4^4
D.576
Answer: D.576
Explanation: The condition that TWO boys or TWO girls cannot be together means they should be alternate..
Total five means 3 of one and 2 of other..
1) choose 3 girls and arrange them... 4C3*3! = 4!= 24
2 boys can be choosen in 4C2 and arrange them in 2! Ways... 4C2*2!= 12
Total ways = 24*12 = 288..
2) same as above.. 2 girls and 3 boys.. 288
Total 288*2=576
ANS:D
Question: Let R1 and R2 respectively denote the maximum and minimum possible remainders when (276)n is divided by 91 for any natural number n , n>= 144. Find R1+R2.
A.90
B.82
C.84
D.64
Answer: B.82
Explanation: Explanation :
The remainder when 276 divided by 91 is 3 hence
remainder of (276)n/91 = remainder 3n/91
Taking n = 1,2,3,4,5
We get the possible remainders as 3, 9, 27, 81, 61, 1 respectively.
For n>5, the pattern repeats
Hence R1 = 81 and R2 = 1
R1+R2 = 81+1 = 82
Answer : B
Question: A person starting with Rs.64 and making 6 bets, wins 3times and loses 3times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is?
A.Rs.37
B.Rs.45
C.Rs.47
D.Rs.53
Answer: A.Rs.37
Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply initial amount by 1.5 thrice and by 0.5 thrice (in any order).
The overall resultant will remain same.
So final amount with the person will be (in all cases):
=64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)==64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs 2727
Hence the final result is:
64−27=3764−27=37:
A loss of Rs.37
A
Question: A train 420 m long is running at a speed of 48 km/hr. In what time will it pass a bridge 60 m long?
A.40 sec
B.36sec
C.60 sec
D.48 sec
Answer: B.36sec
Explanation: total length= 420+60=480
speed=48km/h=(48*5)/18= 40/3 m/s
time=(480*3)/40=36 sec.
ANSWER:B
Question: If books bought at prices ranging from Rs 200 to Rs 350 are sold at prices ranging from Rs 300 to Rs 425, what is the greatest possibleprofit that might be made in selling eight books.
A.800
B.1200
C.1600
D.1800
Answer: D.1800
Explanation: Explanation:
least cost price = 200*8 = 1600
greatest sold price = 425 * 8 = 3400
profit required = 3400- 1600 = 1800. Answer: D
Question: On his drive to work, Leo listens to one of three radio stations A, B or E. He first turns to A. If A is playing a song he likes, he listens to it; if not, he turns it to B. If B is playing a song he likes, he listens to it; if not, he turns it to E. If E is playing a song he likes, he listens to it; if not, he turns off the radio. For each station, the probability is 0.30 that at any given moment the station is playing a song Leo likes. On his drive to work, what is the probability that Leo will hear a song he likes?
A.0.027
B.0.09
C.0.417
D.0.657
Answer: D.0.657
Explanation: Probability he hears a song is like:
Tune to A and likes what he is hearing = 0.3
Tune to A, don't find he like what they are airing, then tune to B and likes what he finds there = 0.7 * 0.3 = 0.21
Tune to A, finds crap there, Tune to B, hears a similar crap, Tune to E and finally falls in love with the program = 0.7^2 * 0.3 = 0.147
Total = 0.657
Ans D
Question: If 8^x = 2^6, what is x?
A.2
B.3
C.4
D.5
Answer: A.2
Explanation: 2^3x= 2^6
3x=6, therefore x=2
Answer A
Question: There are 3 numbers A, B and C. If A:B = 3/4, B:C = 4/5, C:D = 5/6, then B:D will be?
A.1 : 2
B.3 : 5
C.2:3
D.6 : 11
Answer: C.2:3
Explanation: Sol. A : B = 3 : 4, B : C = 4 : 5, C : D = 5 : 6
∴A∶B∶C∶D= 3 : 4 : 5 : 6.
Thus, B : D = 4 : 6 or, 2:3
C
Question: A collection of books went on sale, and 2/3 of them were sold for $5 each. If none of the 50 remaining books were sold, what was the total amount received for the books that were sold?
A.$550
B.$600
C.$500
D.$400
Answer: C.$500
Explanation: If 50 books constitute 1/3rd of the total, then 2/3rd of the total = 100 books
Amount received for sold books = 100 * 5 = $500
Answer :C
Question: A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
A.100 kmph
B.110 kmph
C.120 kmph
D.130 kmph
Answer: C.120 kmph
Explanation: Let speed of the car be x kmph.
Then, speed of the train=(150/100)*x=(3/2)*x kmph
(75/x)-(75/(3/2x))=125/(10*60)
(75/x)-(50/x)=5/24
x = 25x24/5 = 120kmph.
Answer : C.
Question: In a pack of playing cards a card is drawn at random. What is the probability that the card selected is a red king card?
A.1/26
B.1/13
C.3/26
D.2/13
Answer: A.1/26
Explanation: Total cards=52. Number of red king cards=2. Probability of selecting a red king card=2/52=1/26.
Correct Answer: A
Question: A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 5:2. The ratio of economy cars to sport utility vehicles is 4:3. What is the ratio of luxury cars to sport utility vehicles?
A.9:8
B.8:15
C.3:2
D.2:3
Answer: B.8:15
Explanation: The ratio of economy to luxury cars is 5:2 --> E:L = 5:2 = 20:8.
The ratio of economy cars to sport utility vehicles is 4:3 --> E:S = 4:3 = 20:15.
Thus, L:S = 8:15.
Answer: B.
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?
A.33/96
B.33/91
C.33/18
D.33/87
Answer: B.33/91
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is = ¹²C₄/¹⁵C₄
= (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12)
= 33/91
Answer:B
Question: The sum of Two Numbers X, Y is 54. The Difference is 28 what is the square value of Y?
A.169
B.225
C.144
D.256
Answer: A.169
Explanation: X + Y = 54
X - Y = 28
2X = 82
X = 41
Y = 54 - 41 = 13. The square of 13 is 169
so the answer is option A.
Question: A pipe can empty 2/3rd of a cistern in 12mins. In 8 mins, what part of the cistern will be empty?
A.2/3
B.3/7
C.4/9
D.3/8
Answer: C.4/9
Explanation: 2/3 ---- 12
? ----- 8 ==> 4/9
C
Question: Two electronic musical instruments were purchased for Rs. 8000. The first was sold at a profit of 40% and the second at a loss of 40%. If the sale price was the same in both the cases, what was the cost price of the electronic musical instruments?
A.1400,5600
B.3400,5600
C.2400,5600
D.2400,4600
Answer: C.2400,5600
Explanation: let cost prices be x and 8000-x
s.p1=s.p2
(140/100)*x=(60/100)*(8000-x)
x=2400
cost prices are 2400,5600
ANSWER:C
Question: The sum of ages of 4 children born 1 years different each is 38 years. What is the age of the Elder child?
A.8
B.11
C.10
D.16
Answer: B.11
Explanation: Let the ages of children be x, (x + 1), (x + 2), (x + 3) years.
Then, x + (x + 1) + (x + 2) + (x + 3) = 38
4x = 32
x = 8.
x+3= 8+3=11
Answer : B
Question: In how many ways a committee, Consisting of 4 men and 6 women can be formed from 8 men and 10 women?
A.266
B.86400
C.11760
D.14700
Answer: D.14700
Explanation: To choose Required number of ways to form a committee:
Select 4 men out of 8 men and 6 women out of 10 women.
That is 8C4 * 10C6.
8C4=8!/4!*4!
=70
10C6=10!/6!*4!
=210
The Required number of ways=210*70=14700
D
Question: Two pipes A and B can fill a tank in 2 and 6 minutes respectively. If both the pipes are used together, then how long will it take to fill the tank?
A.2.5 min
B.1.8 min
C.1.5 min
D.3.5 min
Answer: C.1.5 min
Explanation: Part filled by the first pipe in 1 minute = 1/2
Part filled by the second pipe in 1 minute = 1/6
Net part filled by pipe A and pipe B in 1 minute = (1/2)+(1/6)=2/3
i.e, pipe A and B together can fill the tank in 3/2 minutes = 1.5 minutes
Answer is C
Question: A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
A.65 hrs
B.99 hrs
C.35 hrs
D.45 hrs
Answer: C.35 hrs
Explanation: Suppose pipe A alone takes x hours to fill the tank.
Then, pipes B and C will take x/2 and x/4 hours respectively to fill the tank.
1/x + 2/x + 4/x = 1/5
7/x = 1/5 => x = 35 hrs.Answer: C
Question: How many ways could three bottle caps can be used to close five bottles of which two of the bottles will remain opened?
A.8
B.12
C.60
D.118
Answer: C.60
Explanation: ways in which 3 bottles out of 5 can be selected = 5C3
ways in which 3 caps can be used to close 3 bottles = 3!
Total ways of arrangement = 5C3*3!
=5*4/2*6
=10*6
=60
Ans = C
Question: If the simple interest on a sum of money for 4 years at 8% per annum is Rs. 560, what is the compound interest on the same sum at the rate and for the same time?
A.Rs. 640.86
B.Rs. 430.86
C.Rs. 330.86
D.Rs. 630.86
Answer: D.Rs. 630.86
Explanation: Sum = (50 * 100) / (2 * 5) = Rs. 1,750.00
C.I. on Rs. 1,750.00 for 4 years at 8% = Rs. 2,380.86.
= Rs. 2,380.86 - 1,750.00 = Rs. 630.86
ANSWER:D
Question: A certain industrial loom weaves 0.128 meters of cloth every second. Approximately how many seconds will it take for the loom to weave 25 meters of cloth?
A.205
B.200
C.180
D.195
Answer: D.195
Explanation: Explanation:
Let the required number of seconds be x
More cloth, More time, (direct proportion)
Hence we can write as
(cloth) 0.128 : 25 :: 1 : x
⇒0.128x=25
⇒x=25/0.128
=25000/128
=3125/16≈195
Answer: Option D
Question: How many 5 letter combinations can be made from the letters of the word VERMONT if the first letter has to be a vowel and the last letter has to be a consonant, and each letter can be used only once?
A.21
B.42
C.120
D.600
Answer: D.600
Explanation: VERMONT consists of 2 vowels and 5 consonants:
The number of way to choose a vowel for the first letter = C12==2.
The number of way to choose a consonant for the last letter= C15==5.
The number of ways to choose middle three letters out of 5 remaining letters = C35==10.
The number of arrangements of these three letters = 3! = 6.
Total = 2*5*10*6 = 600.
Answer: D.
Question: A and B can do a piece of work in 6 2/3 days and 5 days respectively. They work together for 2 days and then A leaves. In how many days after that B will complete the work alone.
A.2 days
B.1 ½ days
C.3 days
D.3 ½ days
Answer: B.1 ½ days
Explanation: Explanation:
3/20 * 2 + (2 + x)/5 = 1
x = 1 ½ days
Answer: Option B
Question: 10 people are assigned a library of audio clips to be transcribed in 100 days. If 2 people have to take 25 days leave in between, how many more people should be added on the last day to complete the task in 100 days itself?
A.25
B.50
C.75
D.100
Answer: B.50
Explanation: B
For 25 days, instead of 10, only 8 people were transcribing the audio clips.
If 1 person transcribes N number of audio clips in 1 day, additional backlog, 25 X N X 2
10 : M :: 10 X N : 25 X 2 X N = 10 : 50
Thus, M = 10 X 50 / 10 = 50
Question: In a group of 120 people, 90 have an age of more 30 years, and the others have an age of less than 20 years. If a person is selected at random from this group, what is the probability the person's age is less than 20?
A.0.25
B.0.55
C.0.65
D.0.75
Answer: A.0.25
Explanation: Number of people whose age is less than 20 is given by
120 - 90 = 30
Probability P that a person selected at random from the group is less than 20 is gieven by
30 / 120 = 0.25
correct answer A
Question: A car travels first half distance between two places with a speed of 40 kmph and the rest half distance with a speed of 60 kmph. The average speed of the car is
A.48 kmph
B.37 kmph
C.44 kmph
D.45 kmph
Answer: A.48 kmph
Explanation: we know that speed = distance traveled/time taken
let the total distance traveled by the car is 2x km.
then time taken by it to cover first half is x/60 hour.
and for second half is x/40 hour.
then average speed= total distance traveled/ total time
taken.
=2x/[(x/60) + (x/40)]
=2x/[5x/120] (on simplification)
=48 kmph
ANSWER:A
Question: Ron begins reading a book at 2: 30 p.m. and reads at a steady pace of 30 pages per hour. Michelle begins reading a copy of the same book at 4: 00 p.m. If Michelle started 5 pages behind the page that Ron started on and reads at an average pace of 50 pages per hour, at what time would Ron and Michelle be reading the same page?
A.5: 00 p.m.
B.6: 30 p.m.
C.7: 45 p.m.
D.8: 00 p.m.
Answer: B.6: 30 p.m.
Explanation: M gains 50-30=20 pages per hour on R
at 4pm R has read 45 pages and M is 45+5=50 pages behind him
time=50/20=2.5 hours
they are on the same page at 6:30pm
B
Question: In a class there are 20 boys and 21 girls. In how many ways can a boy and a girl be selected?
A.508
B.420
C.800
D.570
Answer: B.420
Explanation: We can select one boy from 20 boys in 20 ways.
We select one girl from 21 girls in 21 ways
We select a boy and girl in 20 * 21 ways i.e., = 420 ways.
Answer:B
Question: In a class of 36 students 26 play football and play 20 long tennis, if 17 play above, many play neither?
A.7
B.8
C.10
D.12
Answer: A.7
Explanation: 26 + 20 - 17 = 29
36 - 29 = 7 play neither
Answer is A
Question: if (p/q)-(q/p)=21/10
then what ia the value of(4p/q)+(4q/p)
A.58/5
B.59/5
C.121/105
D.101/105
Answer: A.58/5
Explanation: p/q =a then q/p = 1/a
a+1/a=21/10
by solving this we get a=5/2
then 4*5/2+4*2/5 = 58/5
ANSWER:A
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8339 for a computer table, then what was the cost price of the computer table?
A.2299
B.2699
C.2670
D.6725
Answer: D.6725
Explanation: CP = SP * (100/(100 + profit%))
= 8339(100/124) = Rs. 6725.
Answer:D
Question: The average age of 32 students in a group is 16 years. When teacher’s age is included to it, the average increases by one. What is the teacher’s age in years?
A.cannot be determined
B.None of these
C.48
D.49
Answer: D.49
Explanation: Age of the teacher = (33 × 17 – 32 × 16) years
= 49 years.
Answer D
Question: Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
A.11
B.13
C.44
D.55
Answer: B.13
Explanation: Explanation:
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A. Then, 2x + 3y = 77 ...(i) and 3x + 2y = 73 ...(ii) Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17. Putting y = 17 in (i), we get: x = 13.
Answer: B
Question: A shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net profit or loss that he makes?
A.6%
B.7%
C.8%
D.4%
Answer: D.4%
Explanation: SP of first article = 1000
Profit = 20%
CP = (SP)*[100/(100+P)] = 5000/6 = 2500/3
SP of second article = 1000
Loss = 20%
CP = (SP)*[100/(100-L)] = 5000/4 = 1250
Total SP = 2000
Total CP = 2500/3 + 1250 = 6250/3
CP is more than SP, he makes a loss.
Loss = CP-SP = (6250/3)- 2000 = 250/3
Loss Percent = [(250/3)/(6250/3)]*100
=0.04 * 100
= 4%
Answer: D
Question: Two trains 100 m and 60 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
A.10.9 sec
B.5.76 sec
C.10.6 sec
D.10.8 sec
Answer: B.5.76 sec
Explanation: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 100 + 60 = 160 m.
Required time = 160 * 9/250 = 5.76
= 5.76 sec.
Answer: B
Question: From a group of 25 astronauts that includes 13 people with previous experience in space flight, a 3-person crew is to be selected so that exactly 1 person in the crew has previous experience in space flight. How many different crews of this type are possible?
A.785
B.858
C.864
D.964
Answer: B.858
Explanation: number of astronauts with previous experience = 13
Remaining =12
we need to pick exactly one from the first group
and 2 from the second group
(13C1)*(12C2)
=13*66= 858
Answer : B
Question: A high school has 400 students 1/2 attend the airthmetic club, 5/8 attend the biology club and 3/4 attend the chemistry club. 1/4 attend all 3 clubs. If every student attends at least one club how many students attend exactly 2 clubs.
A.100
B.150
C.140
D.120
Answer: B.150
Explanation: A-Club has 200 members (1/2 of 400)
B-Club has 250 members (5/8 of 400)
C-Club has 300 members (3/4 of 400)
We can create an equation to solve this:
200+250+300 = n + x + 2y
where n is the number of students, x is the number of students in two clubs, and y is the number of students in three clubs.
The question provides y for us (100).
750 = 400 + x + 200
x = 150
B
Question: Tough and Tricky questions: Combinations.
Five contestants representing four different countries advance to the finals of a fencing championship. Assuming all competitors have an equal chance of winning, how many possibilities are there with respect to how a first-place and second-place medal can be awarded?
A.6
B.7
C.12
D.15
Answer: D.15
Explanation: Four contestants representing four different countries advance to the finals of a fencing championship. Assuming all competitors have an equal chance of winning, how many possibilities are there with respect to how a first-place and second-place medal can be awarded?
We have 2 slots to be filled using 5 contestants:5 options for slot1*3 option for slot2
= 5* 3
= 15
Ans. D) 15
Question: A local business made a $125,000 profit on its first $1 million in sales and a $80,000 profit on its next $2 million in sales. By approximately what percent did the ratio of profit to sales decrease from the first $1 million in sales to the next $2 million in sales?
A.100%
B.150%
C.200%
D.250%
Answer: C.200%
Explanation: Solution:
This is a percent decrease problem. We will use the formula: percent change = (new – old)/old x 100 to calculate the final answer.
We first set up the ratios of profits to sales. The first ratio will be for the first 1 million in sales, and the second ratio will be for the next 2 million in sales. Because all of the sales are in millions, we do not have to express all the trailing zeros in our ratios.
First 1 Million
profit/sales = 125/1000 = 1/8
Next 2 Million
profit/sales = 8/200 = 2/50
We can simplify each ratio by multiplying each by the LCM of the two denominators, which is 400. Keep in mind that we are able to do this only because our answer choices are expressed in percents.
First 1 Million
royalties/sales = (1/8) x 400 = 50
Next 2 Million
royalties/sales = (2/50) x 400 = 16
We can plug 5 and 6 into our percent change formula:
(new – old)/old x 100
[(16 – 50)/16] x 100
=-34/16 x 100 so approximately a 200% decrease.
Answer C.
Question: A 6 litre sol is 20% alcohol .How many litres of pure alcohol must be added to produce a sol that is 50% alcohol ?
A.A.0.6
B.B.1
C.C.2.1
D.D.3.6
Answer: D.D.3.6
Explanation: 20% of 6 = 1.2
50% of 6 = 3
shortage is 1.8
so we need to have 1.8/50% to get 50% alcohol content.
= 3.6 D
Question: A college has raised 75% of the amount it needs for a new building by receiving an average donation of Rs. 600 from the people already solicited. The people already solicited represent 60% of the people the college will ask for donations. If the college is to raise exactly the amount needed for the new building, what should be the average donation from the remaining people to be solicited?
A.Rs 300
B.Rs 250
C.Rs 400
D.Rs 500
Answer: A.Rs 300
Explanation: Explanation :
Let x be the total no. of people the college will ask for donation.
The people already solicited 0.6x.
Amount raised from the people solicited 600 x 0.6x = 360x.
Now, 360 constitutes 75% of the amount.
Hence, the remaining 25% = 120x.
Hence, the average donation from remaining people
= 120x / 0.4x = 300.
Answer : A
Question: For any two numbers X and Y , define X# Y=X+Y -XY . If X,Y>0.5, then X#X < Y#Y if
i. 1>X>Y
ii. 1>Y>X
iii. Y>X>1
A.i only
B.option ii only
C.i and ii only
D.ii and iii only
Answer: B.option ii only
Explanation: X#X = 2X-X^2 and Y#Y=2Y-Y^2
X#X <Y#X
=> 2X - X^2 < 2Y - Y^2
=> 2(X-Y) < (X-Y)(X+Y)
=> X+Y>2 and X-Y>0 or X+Y<2 and X-Y<0
=> X+Y>2 and X>Y or X+Y<2 and X<Y
Using (i), if 1>X>Y, then the first case applies but X+Y>2 is not satisfied. False.
Using (ii), if 1>Y>X, then the second case applies and X+Y<2 is satisfied. True.
Using (iii), if Y>X>1, then the second case applies but X+Y<2 is not satisfied. False.
Therefore only (ii) is true, and choice (B) is correct.
Question: Find the distance covered by a man walking for 24min at a speed of 10km/hr?
A.1km
B.3km
C.4km
D.5km
Answer: C.4km
Explanation: Distance = 10*24/60 = 4 km
Answer is C