RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If the sum of a number and its square is 240, What is the number?
A.15
B.77
C.25
D.87
Answer: A.15
Explanation: Explanation:
Let the integer be x.
Then, x + x2 = 240
x2 + x - 240 = 0
(x + 16) (x – 15) = 0
x = 15
ANSWER: A
Question: Present ages of Sameer and Anand are in the ratio of 5:4 respectively. Three years hence, the ratio of their ages will become 11:9 respectively. What is Anand's present age in years?
A.30
B.25
C.24
D.35
Answer: C.24
Explanation: Let the present ages of Sameer and Anand be 5x and 4x years respectively.
Then, (5x + 3)/(4x + 3) = 11/9
9(5x + 3) = 11(4x + 3) => x = 6
Anand's present age = 4x = 24 years.
ANSWER C
Question: 50% of major airline companies equip their planes with wireless internet access. 70% of major airlines offer passengers free on-board snacks. What is the greatest possible percentage of major airline companies that offer both wireless internet and free on-board snacks?
A.20%
B.30%
C.40%
D.50%
Answer: D.50%
Explanation: To maximize the percentage of companies offering both, let's assume that all 50% of companies which offer wireless internet also offer snacks.
The answer is D.
Question: A and B invests Rs.8000 and Rs.15000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?
A.32:75
B.82:31
C.32:45
D.34:89
Answer: A.32:75
Explanation: A : B
(8000*4)+(4000*8) : (15000*6)+(10000*6)
64000 : 150000
32 : 75
Answer:A
Question: The variables m and n are positive integers. When m is divided by 18, there is a remainder of 12, and when n is divided by 24, there is a remainder of 14. Which of the following are possible values of m + n?
I. 40
II. 70
III. 92
A.I only
B.III only
C.I and II
D.I only III
Answer: B.III only
Explanation: m = 18k + 12 --> Values are 12, 30, 48, 66, 84
n = 24k + 14 --> Values are 14, 38, 62, 86
I. 50 --> Not possible
II. 70 --> Not possible
III. 92 --> 30 + 62 --> Possible
Answer: B
Question: The edges of a cuboid are 4 cm, 5 cm and 6 cm. Find the volume of the cuboid?
A.120
B.278
C.378
D.368
Answer: A.120
Explanation: 4*5*6
= 120
Answer: A
Question: One fourth of a solution that was 11% salt by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent salt by weight?
A.24%
B.34%
C.22%
D.31%
Answer: D.31%
Explanation: consider total solution to be 100 liters and in this case you'll have: 75*0.11+25*x=100*0.16 --> x=0.31.
Answer:D.
Question: A train crosses a platform 100 m long in 60 seconds at a speed of 45 km/hr. The time taken by the train to cross an electric pole is :
A.36 sec
B.38 sec
C.44 sec
D.52 sec
Answer: D.52 sec
Explanation: Sol.
Speed = [45 * 5/18] m/sec = [25/2] m/sec.
Let the length of the train be x metres.
Then, x + 100 / [25/2] = 60 or x = 650 m
∴ time taken by the trian to cross an electric pole
= [650 * 2/25] sec =52 sec.
Answer D
Question: The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
A.166
B.178
C.342
D.199
Answer: C.342
Explanation: 400*(90/100)*(95/100)
= 342
Answer: C
Question: In a stack of boards at a lumber yard, the 13th board counting from the top of the stack is immediately below the 12th board counting from the bottom of the stack. how many boards are in the stack?
A.33
B.23
C.25
D.32
Answer: B.23
Explanation: 1 2 3 ....
..............13 12 ................. 1
So the number of boards = 13+10 =23.
Option: B
Question: Pary spent 2⁄5 of her money on new clothes and then deposited 1⁄2 of what remained into her savings account. If she then had $21 left, how much did she have at the start?
A.$30
B.$35
C.$70
D.$105
Answer: C.$70
Explanation: Pary spent 2⁄5 of her money on new clothes but if you see 21 is half of 3/5 money so 210 is too huge to be correct..
solution..
let the money be x..
2/5 is used...
1/2 of remaining 3/5 is put in savings account and remaining half is 21..
so 1/2 * 3/5 *x=21..
x=21*2*5/3=70..
C
Question: Dave has no fashion sense, and will wear any combination of garments regardless of whether someone thinks they “match.” Every day Dave chooses an outfit consisting of one of each of the following garments: jacket, tie, shirt, pants, boxers, right sock, left sock, right shoe, left shoe. If Dave has more than one of each of the listed garments, and can make 21,870 different outfits, then for how many garments does Dave have exactly five choices?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: 21,870 = 2187*10 = 2187*5*2
Dave has exactly 5 choices for one garment.
The answer is B.
Question: Using all the letters of the word "NOKIA", how many words can be formed, which begin with N and end with A?
A.7
B.6
C.4
D.3
Answer: B.6
Explanation: Explanation:
There are five letters in the given word.
Consider 5 blanks ....
The first blank and last blank must be filled with N and A all the remaining three blanks can be filled with the remaining 3 letters in 3! ways.
The number of words = 3! = 6.
Answer: B
Question: A water tank is four-fifths full. Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes. If both the pipes are open, how many minutes will it take to empty or fill the tank completely?
A.6
B.9
C.10
D.12
Answer: D.12
Explanation: The combined rate of filling/emptying the tank = 1/10 - 1/6 = -1/15
Since the rate is negative, the tank will be emptied.
A full tank would take 15 minutes to empty.
Since the tank is only four-fifths full, the time is (4/5) * 15 = 12 minutes
The answer is D.
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is
A.35 years
B.40 years
C.50 years
D.55 years
Answer: B.40 years
Explanation: Solution
Sum of the present ages of husband, wife and child	= (27x3+3x3) years
= 90 years.
Sum of the present ages of wife and child	= (20x2+5x2) years
= 50 years.
∴ Husband's present age	= (90 - 50) years
= 40 years.
Answer B
Question: The integer A has a tens digit of 6 and a units digit of 7. The units digit of integer y is 8. The product of A and y has a tens digit of 8. Which of the following is a possible tens digit of integer y?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: Let A be 67 and y be a8. Then the product of A and y can be written as (60+7)*(10a+8)=600a + 480+70a+56=600a+536+70a. Since 600a dose not affect on the tens digit we can ignore 600a.
So tens digit should be the unit of 3+7a. That means 3+7a =8, 18, 28, 38, 48 or 58 (since 3+7a<=3+7*9=66) --->7a=5, 15, 25, 35, 45, 55. So the only possibility is a=5.
So the answer is (C).
Question: A student has to obtain 30% of the total marks to pass. He got 150 marks and failed by 30 marks. The maximum marks are?
A.750
B.600
C.650
D.550
Answer: B.600
Explanation: Let the maximum marks be x
Then, 30% of x = 150+30
30x/100 = 180
30x= 180*100= 18000
x = 600
Answer is B
Question: A, B and C enter into a partnership. A invests 3 times as much as B invests and 2/3 of what C invests. At the end of the year, the profit earned is Rs. 66000. What is the share of C?
A.Rs. 15250
B.Rs. 13375
C.Rs. 16750
D.Rs. 18000
Answer: D.Rs. 18000
Explanation: Explanation:
Let the investment of C be Rs. x.
The inverstment of B = Rs.(2x/3)
The inverstment of A = Rs. (3 × (2/3)x) = Rs. (2x)
Ratio of capitals of A, B and C = 2x : 2x/3 : x = 6 : 2 : 3
C's share = Rs. [(3/11) × 66000] = Rs. 18000
Answer: Option D
Question: John makes $55 a week from his job. He earns a raise andnow makes $60 a week. What is the % increase?
A.16%
B.9.66%
C.9.09%
D.9.98%
Answer: C.9.09%
Explanation: Increase = (5/55)*100 = (1/11)*100 = 9.09%.
C
Question: The sum of the first k positive integers is equal to k(k+1)/2. What is the sum of the integers from r to s, inclusive, where 0<r<s?
A.s(s+1)/2 - (r+1)(r+2)/2
B.s(s+1)/2 - r(r+1)/2
C.s(s+1)/2 - (r-1)r/2
D.(s-1)s/2 - (r+1)(r+2)/2
Answer: C.s(s+1)/2 - (r-1)r/2
Explanation: Or try plug-in method: let s=4 and r=3 --> then s+r=7. Let see which option yields 7.
A. s(s+1)/2 - (r+1)(r+2)/2 = 10-10=0;
B. s(s+1)/2 - r(r+1)/2 = 10-6=4;
C. s(s+1)/2 - (r-1)r/2 = 10-3=7 --> OK;
D. (s-1)s/2 - (r+1)(r+2)/2 = 6-10=-4;
E. (s-1)s/2 - r(r+1)/2 = 6-6=0.
Answer: C.
Question: A shopkeeper sells 200 metres of cloth for Rs. 12000 at a loss of Rs.12 per metre. Find his cost price for one metre of cloth?
A.s.59
B.s.72
C.s.62
D.s.50
Answer: B.s.72
Explanation: SP per metre = 12000/200
= Rs. 60 Loss per metre
= Rs. 12 CP per metre = 60 + 12
= Rs.72
Answer: B
Question: What was the day of the week on, 20th July, 1776?
A.Tuesday
B.Wednesday
C.Monday
D.Saturday
Answer: D.Saturday
Explanation: 16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)
Counting of odd days :
1600 years have 0 odd day.
100 years have 5 odd days.
75 years = (18 leap years + 57 ordinary years) = [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days.
1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day.
Jan Feb Mar Apr May Jun Jul
31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 6 days)
Total number of odd days = (0 + 6) = 6.
Required day was 'Saturday'.
Answer:D
Question: There are two circles of different radii. The are of a square is 784 sq cm and its side is twice the radius of the larger circle. The radius of the larger circle is seven - third that of the smaller circle. Find the circumference of the smaller circle?
A.6
B.5
C.8
D.6
Answer: C.8
Explanation: Let the radii of the larger and the smaller circles be l cm and s cm respectively. Let the side of the square be a cm.
a2 = 784 = (4)(196) = (22).(142)
a = (2)(14) = 28
a = 2l, l = a/2 = 14
l = (7/3)s
Therefore s = (3/7)(l) = 6 Circumference of the smaller circle
= 2∏s = 12∏ cm.
Answer: C
Question: Hillary and Eddy are climbing to the summit of Mt. Everest from a base camp 4,700 ft from the summit. When they depart for the summit at 06:00, Hillary climbs at a rate of 800 ft/hr with Eddy lagging behind at a slower rate of 500 ft/hr. If Hillary stops 700 ft short of the summit and then descends at a rate of 1,000 ft/hr, at what time do Hillary and Eddy pass each other on her return trip?
A.14.0
B.13.0
C.12.0
D.11.0
Answer: C.12.0
Explanation: Solution:H stopped 700 ft before reaching the final point, time taken to reach 4000 ft= 4000/800= 5hrs.
this means she reached there at 11:00.
speed difference between them is 800-500=300 ft/hr
so by the time H stops they have 1500 ft of distance
so now here we use relative speed formula they both are travelling toward each other with speed of 1000 and 500 total 1500 ft/hr and distance bwn them is 1500 ft so time taken to meet = 1 hr from 11:00
means 12:00 is the answer.
C
Question: Students at a school were on average 180 cm tall. The average female height was 170 cm, and the average male height was 184 cms. What was the ratio S of men to women?
A. 5:2
B. 5:1
C. 4:3
D. 4:1
Answer: A. 5:2
Explanation: (A) S=184 x 5 + 170 x 2 = 1260.A
Question: If a and b are the roots of the equation x2 - 5x + 5 = 0, then the value of a2 + b2 is:
A.36
B.24
C.15
D.6
Answer: C.15
Explanation: Sol.(b) The sum of roots = a+ b = 5
Product of roots = ab = 5
Now, a2 + b2 = (a + b)2 - 2ab = 25 - 10 = 15
Answer C
Question: In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1300 employees, then the no. of female employees who are computer literate ?
A.546
B.674
C.672
D.960
Answer: A.546
Explanation: Solution: Total employees,
= 1300
Female employees, 60% of 1300.
= (60 *1300) /100 = 780.
Then male employees,
= 520
50 % of male are computer literate,
= 260 male computer literate.
62 % of total employees are computer literate,
= (62 *1300) /100 = 806 computer literate.
Thus, Female computer literate = 806 - 260
= 546.
Answer: Option A
Question: A 7% stock yields 10%. The market value of the stock is:
A.Rs 60
B.Rs 70
C.Rs 90
D.Rs 75
Answer: B.Rs 70
Explanation: Explanation:
For an income of Rs. 10, investment = Rs. 100.
For an income of Rs 7, investment =Rs.100/10 X7 =Rs 70
Market value of Rs. 100 stock = Rs. 70
Answer is B
Question: On a ferry, there are 20 cars and 10 trucks. The cars have an average mass of 1200 kg and the trucks have an average mass of 3000 kg. What is the average mass of all 30 vehicles on the ferry?
A.1800
B.1900
C.2000
D.2100
Answer: A.1800
Explanation: The total mass of the vehicles is 20*1200+10*3000=54000
The average mass is 54000/30=1800.
The answer is A.
Question: In a mixed college 160 students are there in one class. Out of this 160 students 1/4 students are girls. How many boys are there ?
A.A)40
B.B)60
C.C)80
D.D)120
Answer: D.D)120
Explanation: Total Number of Students :160
Total Girls : 160*1/4 =40
Total Boys : 160-40 = 120
Answer is D
Question: In how many ways can a teacher write an answer key for a mini-quiz that contains 3 true-false questions followed by 2 multiples-choice questions with 4 answer choices each, if the correct answers to all true-false questions cannot be the same?
A.88
B.90
C.96
D.98
Answer: C.96
Explanation: 2 multiples-choice questions can be answered in = 4 x 4 = 16 ways
3 true-false questions can be answered in = 2x2x2 = 8 ways
But out of the 8 ways, 2 ways [(True-True-True) (False-False-False)]will contain same answers
Thus 3 true-false questions can be answered in = 2x2x2 = 6 ways
Total ways to answer the quiz = 16 x 6 = 96
Answer C
Question: Of the 3,600 employees of Company X, 1/3 are clerical. If the clerical staff were to be reduced by 1/3, what percent of the total number of the remaining employees would then be clerical?
A.25%
B.22.2%
C.20%
D.12.5%
Answer: A.25%
Explanation: Let's see, the way I did it was
1/3 are clerical out of 3600 so 1200 are clerical
1200 reduced by 1/3 is 1200*1/3
so it reduced 400 people , so there is 800 clerical people left
but since 400 people left, it also reduced from the total of 3600 so there are 3200 people total
since 800 clerical left / 3200 people total
you get (A) 25%
Question: A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 250. Find the total worth of the stock?
A.12500
B.20000
C.20289
D.20027
Answer: A.12500
Explanation: Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x - 49x/50 = x/50
x/50 = 250 => x = 12500
Answer: A
Question: |-2| (|-25|-|5|)= ??
Source: Preparation Material MBA Center
A.40
B.–60
C.60
D.75
Answer: A.40
Explanation: Absolute value will turn negatives into their positive 'equivalents', and will leave positives unchanged, so |-2| = 2, |-25| = 25, and |5| = 5. Getting rid of our absolute values we have:
|-2| (|-25|-|5|) = (2) (25 - 5) = 2*20 = 40
Question: complete the numerical series with the correct number
5+3+3=151527
9+2+4=183652
8+6+5=484082
5+4+6=203046
9+5+4= ?
A.453676
B.454586
C.454585
D.454386
Answer: A.453676
Explanation: 9+5+4= 453676
Answer : A
Question: An analysis of the monthly incentives received by 5 salesmen : The mean and median of the incentives is $7000. The only mode among the observations is $12,000. Incentives paid to each salesman were in full thousands. What is the difference X between the highest and the lowest incentive received by the 5 salesmen in the month?
A.$4000
B.$5000
C.$9000
D.$11,000
Answer: D.$11,000
Explanation: Break down the question in to steps:
Step #1: incentives received by 5 salesmen -->abcde
Step #2: mean and median of the incentives is $7000: via number properties --> total incentives = 7,000 * 5 = 35, 000ab7,000de
Step #3: only mode among the observations is $12,000: mode is the value that appears most often in a set of data. Therefore 12,000 must occur more then once and since 12,000 is larger than the mean (7,000) the most it can occur is twice in our list. If we place the numbers in ascending order we haveab7,00012,00012,000
Step #4: What is the difference between the highest and the lowest incentive:
- The total paid has to equal mean * # of numbers = 7,000 * 5 = 35 000.
- The three values we have so far (12,000 12,000 and 7, 000) equal 31,000.
- Therefore the first two numbers( ab) must equal 4, 000
- There is only one mode which is 12,000, therefore 4,000 must be equal to a set of two numbers that are not the and a < b
if a = 1,000 b = 3,000 --> difference X between the highest and the lowest incentive = 12,000 - 1,000 =11, 000
no other options for a or b to fit the criteria
Final List:1,0003,0007,00012,00012,000
Answer D
Question: The rates of simple interest in two banks A and B are in the ratio 5 : 4. A person wants to deposit his total savings in two banks in such a way that he received equal half-yearly interest from both. He should deposit the savings in banks A and B in the ratio.
A.2 : 5
B.4 : 5
C.5 : 2
D.5 : 4
Answer: B.4 : 5
Explanation: Let the savings be X and Y and the rates of simple interest be 5x and 4x respectively.
Then, X × 5x × 1⁄2 × 1⁄100 = Y × 4x × 1⁄2 × 1⁄100 or X⁄Y = 4⁄5
i.e., X : Y = 4 : 5.
Answer B
Question: 81,162,49,98,25,50,56
A.112
B.127
C.129
D.128
Answer: A.112
Explanation: 81*2=162
49*2=98
25*2=50
56*2=112
ANSWER:A
Question: A 2member committee comprising of one male & one female member is to be constitute out of 5 males and 3females. Among st the females. Ms.A refuses to be a member of the committee in which Mr.B is taken as the member. In how many different ways can the committee be constituted ?
A.12
B.14
C.12
D.17
Answer: B.14
Explanation: 5C1 * 3C1 -1
= 15-1
= 14
B
Question: By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?
A.28000
B.29000
C.38000
D.40000
Answer: C.38000
Explanation: CP + CP/8 = 45000
CP = 40000
SP = 40000*(95/100) = 38000
C
Question: Suppose 7 students are staying in a hall in a hostel and they are allotted 7 beds. Among them, Parvin does not want a bed next to Anju because Anju snores. Then, in how many ways can you allot the beds?
A.2399
B.2887
C.3600
D.2882
Answer: C.3600
Explanation: Explanation:
Let the beds be numbered 1 to 7.Case 1 : Suppose Anju is allotted bed number 1.
Then, Parvin cannot be allotted bed number 2.
So Parvin can be allotted a bed in 5 ways.
After alloting a bed to Parvin, the remaining 5 students can be allotted beds in 5! ways.
So, in this case the beds can be allotted in 5´5!ways = 600 ways.
Case 2 : Anju is allotted bed number 7.
Then, Parvin cannot be allotted bed number 6
As in Case 1, the beds can be allotted in 600 ways.
Case 3 : Anju is allotted one of the beds numbered 2,3,4,5 or 6.
Parvin cannot be allotted the beds on the right hand side and left hand side of Anju’s bed. For example, if Anju is allotted bed number 2, beds numbered 1 or 3 cannot be allotted to Parvin.
Therefore, Parvin can be allotted a bed in 4 ways in all these cases.
After allotting a bed to Parvin, the other 5 can be allotted a bed in 5! ways.
Therefore, in each of these cases, the beds can be allotted in 4´ 5! = 480 ways.
The beds can be allotted in (2x 600 + 5 x 480)ways = (1200 + 2400)ways = 3600 ways
Answer: C) 3600
Question: A man covers a certain distance F in a train. If the train moved 4km/hr faster, it would take 30 min less. If it moved 2km/hr slower, it would take 20 mins more. Find the distance?
A.200 km
B.50 km
C.20 km
D.60 km
Answer: D.60 km
Explanation: Not really. When you solve the 2 equation above, you get,
6T-4/3 = 5R/6 from simplifying equation 1
4T-2=R/2 from simplifying equation 2
You can now multiply equation 2 by 5 to get
5(4T-2=R/2 ) = 20T-10=5R/2 and then subtract this new equation from equation 1 to get T=3, followed by R=20 to give you distance F= R*T=20*3=60 km.D
Question: Find the compound interest on $50000 in 2years at 4% per annum, the interest being compounded half-yearly?
A.$645.56
B.$4121.60
C.$954.26
D.$745.69
Answer: B.$4121.60
Explanation: Principle = $50000
Rate = 2% half yearly = 4 half years
Amount = 50000*(1 + 2/100)^4 = 50000 * 51/50 * 51/50 * 51/50 * 51/50
= $54121.60
C.I. = 54121.60-50000 = $4121.60
Answer is B
Question: The perimeter of a semi circle is 162 cm then the radius is?
A.31.5
B.28
C.98
D.37
Answer: A.31.5
Explanation: 36/7 r = 162
=> r
= 31.5
Answer: A
Question: By selling 32 cucumber in a dollar, a man loses 40%. How many cucumber must he sell in a dollar to gain 20% profit?
A.16
B.18
C.20
D.25
Answer: A.16
Explanation: This is a question that is much easier than it first appears. If you work with the percents directly, you can solve it very quickly. If the man sells 32 cucumber for a dollar, he loses 40%. That means he is at 60% of his cost (100% - 40% = 60%). We are trying to figure out how many cucumber he has to sell in order to make a 20% profit, or be at 120% (100% + 20% = 120%). 120% is double 60%, meaning that we simply cut the number of cucumber in half to double our returns (from 60% to 120%), yielding 32/2 = 16 cucumber, or answer choice A.
Question: V is the volume of a cylinder; the radius of the cylinder is 3.4. The height of the cylinder is 450% more than the radius. Which of the following is true?
A.700 < V < 900
B.300 < V < 500
C.500 < V < 700
D.100 < V < 300
Answer: A.700 < V < 900
Explanation: As we see the answers are in form of range we can use approximation
Volume of cylinder is πr^2h
Given π= 22/7 and r = 3.4 so r^2 ~ 12 and h = 5.5 * 3.4 ~ 19
So 22/7 * 12 * 19 ~ 717
so answer should be
A. 700 < V < 900
Answer : A
Question: Two pipes A and B can fill a tank in 8 hours and 16 hours respectively. If both pipes are opened simultaneously, how much time will be taken to fill the tank?
A.5 hours 20 min
B.5 hours 49 min
C.3 hours 50 min
D.3 hours 22 min
Answer: A.5 hours 20 min
Explanation: Explanation:
Part filled by A in 1 hour = 1/8
Part filled by B in 1 hour = 1/16
Part filled by (A + B) in 1 hour = ( 1/8 + 1/16) = (3/16)
Time taken to fill the tank is (16/3) = 16/3*60 = 320 mins = 5 hrs 20 mins
ANSWER A
Question: Cost is expressed by the formula tb^4. If b is doubled, the new cost W is what percent of the original cost?
A.W=200
B.W=600
C.W=800
D.W=1600
Answer: D.W=1600
Explanation: Original Cost W, C1=t1*b1^4
New Cost C2=t2*b2^4....only b is doubled so t2=t1 and b2=2b1
C2=t2*(2b1) ^4
=16(t1*b1^4)
=16C1
16 times C1=>1600% of C1
Ans D=1600
Question: Bob invested $3000 in fund A and $1000 in fund B. Over the next two years, the money in Fund A earned a total interest of 12 percent for the two years combined and the money in fund B earned 30 percent annual interest compounded annually. Two years after bob made these investments. Bob's investment in fund A was worth how much more than his investment in fund B?
A.1. $1500
B.2. $1550
C.3. $1600
D.4. $1670
Answer: D.4. $1670
Explanation: interest on fund A will be 360. rate of interest will be 6% per annum simple interest as 12% is for 2 year. this will make investment A 360 at the end of 2nd year.
interest on fund B will be 690 on 30% interest compounded annually. This will make investment B 1690 at the end of 2nd year.
Difference in investment A and investment B=3360-1690=1670
answer is D.
Question: A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent.
A.49%
B.18%
C.17%
D.13%
Answer: A.49%
Explanation: Let the number be 100.
Increase in the number = 70 % = 70 % of 100
= (70/100 Ã— 100)
= 70
Therefore, increased number = 100 + 70 = 170
This number is decreased by 70 %
Therefore, decrease in number = 70 % of 170
= (70/100 Ã— 170)
= 11900/100
= 119
Therefore, new number = 170 - 119 = 51
Thus, net decreases = 100 - 51 = 49
Hence, net percentage decrease = (49/100 Ã— 100) %
= (4900/100) %
= 49 %
Answer:A
Question: Present age of a father is 3 years more than 3 times theage of his son. 3 years hence, father's age will be 10 years more than twice the age of the son. What is father's present age?
A.28
B.29
C.33
D.36
Answer: C.33
Explanation: Let the present age the son =x
Then, present age of the father =3x+3
Given that, three years hence, father's age will be 10 years more than twice the age of the son
⇒(3x+3+3)=2(x+3)+10⇒x=10
Father's present age
=3x+3=3×10+3=33
C