RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Working together, Jose and Jane can complete an assigned task in 30 days. However, if Jose worked alone and complete half the work and then Jane takes over the task and completes the second half of the task, the task will be completed in 45 days. How long will Jose take to complete the task if he worked alone? Assume that Jane is more efficient than Jose
A.90 days
B.30 days
C.60 days
D.65 days
Answer: A.90 days
Explanation: Assume:
Jose does 1 job in x days, so Jose does 1/x job in a day
Jane does 1 job in y days, so Jane does 1/y job in a day
Together, they does (x+y)/xy job in a day. This is equals to 1/20. So
(x+y)/xy = 1/30
30(x+y) = xy
Next, we're told 1 job takes 45 days to complete if Jose and Jane each does half the work. So since Jose does 1 job in x days, he wil need x/2 days to do half the job. Jane similarly will need y/2 days to do the other half.
x/2 + y/2 = 45
x+y = 90
So
xy = 30 *90 =2700
The answer choices are:
90 days
30 days
60 days
65 days
36 days
From the answer choices, So I'll go for 90 days for Jose and 30 days for Jane.
Answer : A
Question: The sum of the ages of Latha and Geetha is 60years. Also 5 years ago, the Latha's age was 5 times the age of the Geetha. What is the age of the Geetha?
A.13years
B.15yeas
C.20years
D.18years
Answer: B.15yeas
Explanation: Let the age of the Geetha be x years
The age of the Latha is 60-x years
5 years ago 5(x-5) = 60-x-5
x = 13 approximately
Geetha's age = 13years
Answer is B
Question: The speed at which a man can row a boat in still water is 150 kmph. If he rows downstream, where the speed of current is 48 kmph, what time will he take to cover 390 metres?
A.10
B.11
C.12
D.13
Answer: D.13
Explanation: Speed of the boat downstream = 150 + 48 = 198 kmph
= 198 * 5/18 = 30 m/s
Hence time taken to cover 390 m = 390/30 = 13 seconds. Answer: D
Question: The 15 homes in a new development are each to be sold for one of three different prices so that the developer receives an average (arithmetic mean) of $200,000 per home. If 4 of the homes are to be sold for $170,000 each and 5 are to be sold for $200,000 each, what will be the selling price of each of the remaining 16 homes?
A.$200,000
B.$210,000
C.$215,000
D.$207,500
Answer: D.$207,500
Explanation: IMO the answer has to be D.
5 houses are being sold for 200,000. 4 houses are being sold for $30,000 less, resulting in a loss of $120,000. To make the average selling price intact i.e. $200,000, the remaining 16 houses must be sold at such a profit that it compensates for the loss of 120,000. Hence 16x=120,000.
x=7500.
The 16 houses are sold at $7,500 profit or at $207,500. (ANSWER D)
Question: Simple interest on a certain amount is 9/16 of the principal. If the numbers representing the rate of interest in percent and time in years be equal, then time, for which the principal is lent out, is :
A.6 1/2
B.7 1/2
C.8
D.9 1/2
Answer: B.7 1/2
Explanation: Sol.
Let sum = x. Then, S.I. = 9/16 x.
Let rate = R% and time = R years.
∴ [x * R * R / 100] = 9x / 16 ⇔ R² = 900/16
⇔ R = 30/4 = 7 1/2
Hence, time = 7 1/2 years.
Answer B
Question: A bacteria gives birth to two new bacteria in each second and the life span of each bacteria is 5 seconds. The process of the reproduction is continuous until the death of the bacteria. initially there is one newly born bacteria at time t = 0, the find the total number of live bacteria just after 10 seconds :
A.3 10 /2
B.(3)10 - (2)10
C.243 *(35 -1)
D.(3)10 -(2)5
Answer: C.243 *(35 -1)
Explanation: Solution: Total number of bacteria after 10 seconds,
= (3)10 - (3)5
= (3)5 *(3)(5 -1)
= 243 *(3)(5 -1)
Since, just after 10 seconds all the bacterias (i.e. 35 ) are dead after living 5 seconds each.
Answer: Option C
Question: A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.65 less, he could have gained 25%. What is the cost price?
A.325
B.375
C.278
D.267
Answer: A.325
Explanation: CP1 = 100 SP1 = 120
CP2 = 80 SP2 = 80 * (125/100) = 100
20 ----- 100
65 ----- ? => 325
Answer:A
Question: How many numbers from 10 to 50 are exactly divisible by 3?
A.13
B.15
C.16
D.17
Answer: A.13
Explanation: 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45,48.
13 Numbers.
10/3 = 3 and 50/3 = 16 ==> 16 - 3 = 13. Therefore 13 digits
A)
Question: The speed of a boat in still water in 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is:
A.1.2 km
B.2.4 km
C.3.2 km
D.3.6 km
Answer: D.3.6 km
Explanation: Speed downstream = (15 + 3) kmph = 18 kmph.
Distance travelled = 18 x 12/60	km = 3.6 km.
ANSWER:D
Question: The average of first 40 prime numbers is?
A.15.41
B.16.41
C.15.61
D.15
Answer: B.16.41
Explanation: Explanation:
Average = (2+3+5+7+11+13+17+19+23+29+31+37)/12= 197/12= 16.41(Approx)
Answer is B
Question: A thief steals at a car at 2.00 p.m. and drives it at 60 km/hr. The theft is discovered at 3 p.m. and the owner sets off in another car at 75 km/hr. When will he overtake the thief?
A.1 p.m
B.3 p.m
C.4 p.m
D.4.30 p.m
Answer: D.4.30 p.m
Explanation: D
4.30 p.m
Suppose the thief is overtaken x hrs after 2.00 p.m.
Then, distance covered by the owner in (x - 1/2) hrs.
60x = 75(x - 1/2) => x = 5/2 hrs.
So, the thief is overtaken at 4.30 p.m.
Question: If TIER is written as 7163 and BRAIN is written as 23415, how is RENT coded ?
A.7536
B.7653
C.3657
D.3765
Answer: C.3657
Explanation: Explanation:
Given :
Letter : T I E R B A N
Code : 7 1 6 3 2 4 5
Thus, the code for RENT is 3657.
ANSWER C
Question: How much time will it take for an amount of Rs. 900 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
A.2 years
B.3 years
C.1 year
D.4 years
Answer: A.2 years
Explanation: Solution:
P = Rs.900
SI = Rs.81
T = ?
R = 4.5%
T= 100×SI/PR=100×81/900×4.5=2 years
Answer : Option A
Question: One side of a rectangular field is 14 m and one of its diagonal is 17 m. Find the area of the field.
A.134.4
B.120
C.150
D.180
Answer: A.134.4
Explanation: Solution
Other side = √(17)2 - (14)2
= √289 - 196
= √93
= 9.6 m.
∴ Area = (14 x 9.6)m2 = 134.4 m2.
Answer A
Question: 337.62+8.591+34.4=?
A.370.611
B.380.511
C.380.611
D.426.97
Answer: C.380.611
Explanation: 337.62
8.591
34.4
----------
380.611
Answer is C
Question: In the next Cricket World Cup T-20, Team W has decided to score 200 runs only through 4s and 6s. In how many ways can the Team W score these 200 runs?
A.13
B.15
C.16
D.17
Answer: D.17
Explanation: Team W can score a maximum of 50 fours and a minimum of 2 fours with an interval or spacing of 3 units to accommodate the 6's.
So the number of fours scored forms an AP 2, 5, 8, ... 50 with a common difference of 3.
Number of ways of scoring 200 only through 4's and 6's = (50 - 2)/3 + 1 = 17
Answer: D
Alternate solution: 4x + 6y = 200 --> 2x + 3y = 100
x = (100 - 3y)/2 --> 100 - 3y should be even. This is possible when 3y is even.
There are 17 even multiples of 3 between 0 and 100.
Answer: D
Question: Suresh borrowed some money at the rate of 4% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years. If the total interest paid by him at the end of 11 years is Rs.8160, how much money did he borrow?
A.s.8500
B.s.6000
C.s.8500
D.s.9000
Answer: C.s.8500
Explanation: using the formula S.I=P*T*R/100
(x*4*3/100)+(x*9*5/100)+(x*13*3/100)=8160
x=8500
i.e money borrowed is Rs.8500
ANSWER:C
Question: Convert the 11/36 m/s into kilometers per hour?
A.1.7
B.1.5
C.1.3
D.1.1
Answer: D.1.1
Explanation: 11/36 m/s = 11/36 * 18/5 = 11/10
= 1.1 kmph.
Answer: D
Question: The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides?
A.area=3
B.4
C.5
D.6
Answer: A.area=3
Explanation: S = (1 + 2 + 3) /2 = 3
=> No triangle exists
Answer: A
Question: The cost of registration at a professional association meeting was $50 per person; a lunch for registrants only was available for an additional $22 per person. If the number of registrants who paid for lunch was 30 more than the number who did not, and if receipts for registration and lunch totaled $75,360, how many people paid just for registration at the meeting?
A.700
B.800
C.600
D.1,500
Answer: C.600
Explanation: Hope this might be useful to you.
Let the number of people who have opted only to register = x
Now since the registration cost is 50$ per person, the total amount sums to = 50x $
As per the information given in the question, the number of registrants who paid for lunch was 30 more than the number who did not. That means, total number of people who registered and paid for lunch = 30 + x.
For the people who registered for lunch the cost is 50 $ (for the event registration) + 22 $ (for lunch) = 72 $.
Total amount in this case sums to = 72(30 + x) = 2160 + 72x
Now, total amount received was 75360.
Thus, from the above data,
50x + 2160 + 72x = 75360
122x = 75360 - 2160
122x = 73200
x = 600.
Hence the correct Ans is C
Question: You have been given a physical balance and 5 weights of 45, 42, 37, 36 and 67 kgs. Keeping weights on one pan and object on the other, what is the maximum you can weigh less than 157 kgs.
A.160
B.151
C.154
D.153
Answer: C.154
Explanation: 45+42+67 = 154
Answer: C
Question: Three numbers are in the ratio 4 : 5 : 6 and their average is 42 . The largest number is:
A.28
B.32
C.36
D.50.4
Answer: D.50.4
Explanation: Explanation:
Let the numbers be 4x, 5x and 6x. Therefore,
(4x+5x+6x)/3 = 42
15x = 126
x = 8.4
Largest number = 6x = 50.4.
ANSWER D
Question: The cross-section of a cannel is a trapezium in shape. If the cannel is 10 m wide at the top and 6 m wide at the bottom and the area of cross-section is 640 sq m, the depth of cannel is?
A.20 m
B.60 m
C.40 m
D.80 m
Answer: D.80 m
Explanation: 1/2 * d (10 + 6) = 640
d = 80
ANSWER:D
Question: In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 2 to the thrice of the remainder. The dividend is?
A.80
B.86
C.92
D.94
Answer: B.86
Explanation: Divisor = (6 * 3) + 2 = 20
5 * Quotient = 20
Quotient = 4.
Dividend = (Divisor * Quotient) + Remainder
Dividend = (20 * 4) + 6 = 86
B)
Question: If n = 2×3×5×7×11×13, then which of the following statements must be true?
I. n2 is divisible by 600
II. n + 19 is divisible by 19
III. is even n+4 / 2 = even
IV . n is Divisible by 35
A.none and IV only
B.b- II only
C.III only
D.I and III only
Answer: A.none and IV only
Explanation: 2×3×5×7×11×13= 2310
I. not divisible by 600
II 2310+19=2329 not divisible by 19
III. 2310+4/2= odd
iv. divisible by 35
A
Question: A group of 16 people plan to rent a van and agree to share equally the total cost of the rental, which is E dollars. If n of the people decide not to participate at the last minute, by how many dollars will each remaining person's share of the total cost increase?
A. E/(12 - n)
B. nE / [16(16-n)]
C. E/[12(12-n)]
D. (12 - n)/E
Answer: B. nE / [16(16-n)]
Explanation: total cost =E
no of people willing to participate initially =16
initial cost for each =E/16
when n people decided not to participate
Cost for each =E/16-n
B
Question: Mangala completes a piece of work in 10 days, Raju completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is?
A.8 days
B.10 days
C.11 days
D.12 days
Answer: A.8 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 × 40/50 = 8 days
A)
Question: In how much time will a train of length 100 m, moving at 36 kmph cross an electric pole?
A.27
B.29
C.17
D.10
Answer: D.10
Explanation: Convert kmph to mps. 36 kmph = 36 * 5/18 = 10 mps.
The distance to be covered is equal to the length of the train.
Required time t = d/s = 100/10 = 10 sec.
Answer:D
Question: The side of a square has the length of 5. What is the area of the region shaded?
A.48-8π
B.48-6 π
C.24+6π
D.16-5π
Answer: D.16-5π
Explanation: The area of a square whose side is 5 – (the area of a square whose side is 4 + the area of the semi-circle whose side is 4) = the area of the region shaded
The correct answer is D.
Question: A card from a pack of 52 cards is lost. From the remaining cards of the pack, two cards are drawn and are found to be both spade. Find the probability of the lost card being a spade.
A.10/50
B.10/53
C.11/50
D.11/53
Answer: C.11/50
Explanation: total cards:52
drawn cards(spade):2
now, actual present total cards=total cards-drawn cards=52-2=50
total spade=spade-drawn cards(spade)=13-2=11
so,probability=11/50
ANSWER:C
Question: Lucy invested $10,000 in a new mutual fund account exactly three years ago. The value of the account increased by 10 percent during the first year, increased by 5 percent during the second year, and decreased by 15 percent during the third year. What is the value of the account today?
A.$10,350
B.$9817.50
C.$10,500
D.$11,500
Answer: B.$9817.50
Explanation: Value after 1 year: 10,000 * 1.1 = 11,000
Value after 2 years: 11,000 * 1.05 = 11,550
Value today: 11,550 * 0.85 = 10,395
Answer B is correct.
Question: Integer d is the product of the integers a,b, and c and 1<a<b<c. If the remainder when 233 is divided by d is 79, what is the value of a+c?
A.7
B.9
C.13
D.14
Answer: C.13
Explanation: 79 is the remainder, therefore the number(a*b*c) or multiple of the number we need is 79 less than 233
Hence 233- 79 = 154
Therefore, 154 is either a number we want or it is a multiple of the number we want
But the largest factor of 154 is 77 because 77 * 2 =154
But 77 is less than 79 hence it can not be a number
Thus 154 is the number we want
a*b*c= 154
now factorize 154 =1*2*7*11 all are prime
Also we know 1<a<b<c
thus a = 2 and c = 11
therefore a+c= 2+11= 13
ANSWER:C
Question: If 2/X - 2 = 3/X - 3, then X =
A.-3/2
B.2/3
C.-1
D.1
Answer: D.1
Explanation: We're given the equation 2/X - 2 = 3/X - 3. We're asked for the value of X.
The common-denominator of these 4 numbers is X, so we need to multiply both sides of the equation by X, giving us...
2X/X - 2X = 3X/X - 3X
We can then eliminate that denominator, which gives us....
2 - 2X = 3 - 3X
1 = X
D
Question: A train running at the speed of 60 km/hr crosses a pole in 6 sec. What is the length of the train?
A.535 m
B.100 m
C.186 m
D.168 m
Answer: B.100 m
Explanation: Speed = 60 * 5/18
= 50/3 m/sec
Length of the train
= speed * time
= 50/3 * 6
= 100 m
Answer:B
Question: The edges of a cuboid are 4 cm, 5 cm and 6 cm. Find the volume of the cuboid?
A.120
B.388
C.278
D.298
Answer: A.120
Explanation: 4*5*6 = 120
Answer: A
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:
A.30
B.36
C.40
D.45
Answer: B.36
Explanation: Speed => x
two trains = 2x
2x = 120+120/12==>2x=20
x=10
speed = 10 m/sec = 10*18/5=36
ANSWER B
Question: A water tank is two-fifth full. Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes. If both the pipes are open, how long will it take to empty or fill the tank completely?
A.6 min
B.7 min
C.9 min
D.4 min
Answer: A.6 min
Explanation: Clearly, pipe B is faster than pipe A and so, the tank will be emptied.
Part to be emptied = 2/5
Part emptied by (A + B) in 1 minute
= (1/6 - 1/10)
= 1/15
1/15 : 2/5 :: 1 : x
x = (2/5 * 1 * 15) '
= 6 min.
So, the tank will be emptied in 6 min.
Answer:A
Question: The speed of a boat in still water is 30 kmph. What is the speed of the stream if the boat can cover 80 km downstream or 40 km upstream in the same time?
A.11 kmph
B.10 kmph
C.12 kmph
D.16 kmph
Answer: B.10 kmph
Explanation: X = the speed of the stream
(30 + X) / (30 - X) = 2/1
30+ X = 60 - 2X
3X = 30
X = 10 km/hour
If the speed of the stream is 10km/hour, then the 'downstream' speed of the boat is 30+10= 40km/hour and the 'upstream' speed of the boat is 30-10 = 20km/hour. In that way, if the boat traveled for 2 hours, it would travel 2x40 = 80km downstream and 2x20 = 40 km/hour upstream.
Answer : B
Question: A and B start a business with Rs.6000 and Rs.8000 respectively. Hoe should they share their profits at the end of one year?
A.3:5
B.3:4
C.3:8
D.3:9
Answer: B.3:4
Explanation: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B
=6000 : 8000 => 3:4
Answer:B
Question: Jill has 21 gallons of water stored in quart, half-gallon, and one gallon jars. She has equal numbers of each size jar holding the liquid. What is the total number of water filled jars?
A.3
B.6
C.9
D.36
Answer: D.36
Explanation: Let the number of each size of jar = wthen 1/4w + 1/2w + w = 21 1 3/4w = 21w=12The total number of jars = 3w =36Answer: D
Question: There are 10 magazines lying on a table; 6 are sports magazines and the other 4 are current affairs magazines. If 4 magazines are to be selected at random from the 10 magazines, what is the probability that at least one of the current affairs magazines will be selected?
A.2/5
B.3/5
C.4/5
D.6/5
Answer: B.3/5
Explanation: Total probability=10C4=210
4C4 +4C3*6C1+4C2*6C2+4C1*6C3=1+24+21+80=126
therefore the probability that at least one of the current affairs magazines will be selected= 126/210=3/5
answer is B
Question: 5a=15625. Find 5a-3
A.125
B.228
C.270
D.778
Answer: A.125
Explanation: ANSWER : A
Question: A factory has a fixed cost of $41,000 a month, and a cost of $2.5 for every item produced. If the selling price of a single item is $5, what is the number of items must be sold monthly for the factory to cover its cost exactly?
A.9,000
B.14,000
C.16,400
D.22,500
Answer: C.16,400
Explanation: selling price - Cost price = 2.5 so per unit profit =2.5
cost to recover =41000
no of items required = 41000/2.5 = 16400
Answer: C
Question: Find the area of trapezium whose parallel sides are 20 cm and 10 cm long, and the distance between them is 10 cm.
A.187 cm2
B.185 cm2
C.150 cm2
D.185 cm2
Answer: C.150 cm2
Explanation: Explanation:
Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (20 + 10) * (10) = 150 cm2
Answer: Option C
Question: The perimeter of a rhombus is 68 cm and one of its diagonals is 16 cm. Find its area?
A.260 cm2
B.240 cm2
C.280 cm2
D.220 cm2
Answer: B.240 cm2
Explanation: 4a = 68 => a = 17
172 – 82 = 152
1/2 * 16 * 30 = 240
ANSWER:B
Question: The ratio of investments of A, B and C is 5:6:7. If they share the profit in the ratio of 5:9:14, then find the ratio of their periods of investments.
A.2:3:4
B.3:5:6
C.3:2:4
D.2:4:3
Answer: A.2:3:4
Explanation: The ratio of investments of A, B and C is 5:6:7.
The ratio of shares of A, B and C is 5:9:14.
Therefore, Ratio of their periods of investments is
(5/5) : (9/6) : (14/7) = 1:3/2:2 = 2:3:4.
ANSWER:A
Question: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected?
A.159
B.194
C.210
D.209
Answer: C.210
Explanation: Out of 10 students 4 children should to be selected.
So the combination will be 10C4.
10C4=10!/6!*4!=10*9*8*7*6!/6!*(4*3*2*1)
10C4=210
There are 210 differect possible ways to select 4 children out of 10 students.
Question: At Jerri’s Pet Shop, 60 cups of bird seed are used every 5 days to feed 20 parakeets. How many cups of bird seed would be required to feed 10 parakeets for 5 days?
A.45.6
B.20
C.9
D.30
Answer: D.30
Explanation: Let's go step-by-step.
60 cups are used over a 5 day period, which means 12 cups a day. This feeds 20 parakeets, which means each parakeet needs .60 of a cup every day.
For 10 parakeets, we need 10*.60cups = 6 cups a day. Over 5 days, we need 30 cups. Choice D.
Question: Which of the following must be subtracted from 2^48 so that the resulting integer will be a multiple of 3?
A.2
B.1
C.3
D.4
Answer: B.1
Explanation: {4^1} / 3 =4/3 remainder 1
{4^2} / 3 = 16/3 remainder 1
{4^3} / 3 = 64/3 remainder 1
{4^4} / 3 = 256/3 remainder 1
Actually the same remainder keeps repeating .....
Try with a diff no, say 2
{2^1}/3 = remainder 2
{2^2}/3 = remainder 1
{2^3}/3 = remainder 2
{2^4}/3 = remainder 1
Answer : B
Question: Three persons invested Rs.9000 in a joint business. The second person invested Rs.1000 more than the first and the third Rs.1000 more than second. After two years, they gained Rs.5400. How much third person will get?
A.2400
B.2408
C.2487
D.2429
Answer: A.2400
Explanation: First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 54000 = 2400
Answer:A
Question: A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. After what time will they again at the starting point ?
A.26 minutes and 18 seconds
B.45 minutes
C.42 minutes and 36 seconds
D.46 minutes and 12 seconds
Answer: D.46 minutes and 12 seconds
Explanation: L.C.M. of 252, 308 and 198 = 2772.
So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
answer :D
Question: What is the greatest number of four digits which is divisible by 15, 25, 40 and 75 ?
A.9800
B.9600
C.9400
D.9200
Answer: B.9600
Explanation: Greatest number of four digits = 9999
LCM of 15, 25, 40 and 75 = 600
9999 ÷ 600 = 16, remainder = 399
Hence, greatest number of four digits which is divisible by 15, 25, 40 and 75
= 9999 - 399 = 9600
Answer: Option B
Question: If the average (arithmetic mean) of (2a+16) and (3a-8) is 69, what is the value of a?
A.26
B.30
C.28
D.36
Answer: A.26
Explanation: ((2a+16) + (3a-8)) / 2 = (5a+8)/2 = 69
a= 26
The answer is A.
Question: Two trains, each 100 m long, moving in opposite directions, cross other in 5 sec. If one is moving twice as fast the other, then the speed of the faster train is?
A.22
B.96
C.60
D.88
Answer: B.96
Explanation: Let the speed of the slower train be x m/sec.
Then, speed of the train = 2x m/sec.
Relative speed = ( x + 2x) = 3x m/sec.
(100 + 100)/5 = 3x => x = 40/3.
So, speed of the faster train = 80/3 = 80/3 * 18/5 = 96 km/hr.
Answer:B
Question: 1, 0.2, 0.08, 0.48, 0.0384, ____
A.0.0584
B.0.0484
C.0.0434
D.0.0384
Answer: D.0.0384
Explanation: 1, 0.2, 0.08, 0.48, 0.0384, .....
1*0.2=0.2
0.2*0.4=0.08
0.08*0.6=0.048
0.048*0.8=0.0384
So 0.0384*1=0.0384
ANSWER:D
Question: The weights of three boys are in the ratio 4 : 5 : 6. If the sum of the weights of the heaviest and the lightest boy is 45 kg more than the weight of the third boy, what is the weight of the lightest boy?
A.32 kg
B.36 kg
C.40 kg
D.44 kg
Answer: B.36 kg
Explanation: Let the weights of the three boys be 4k, 5k and 6k respectively.
4k + 6k = 5k + 45
=> 5k = 45 => k = 9
Therefore the weight of the lightest boy
= 4k = 4(9) = 36 kg.
ANSWER:B
Question: A set of numbers has the property that for any number t in the set, t + 2 is in the set. If -1 is in the set, which of the following must also be in the set?
I. 1
II. -4
III. 5
A.I only
B.II only
C.I and III only
D.II and III only
Answer: C.I and III only
Explanation: The question is which of the following must be in the set, not could be in the set.
If -1 is in the set so must be -1+2=1, as 1 is in the set so must be 1+2=3, as 3 is in the set so must be 3+2=5 and so on. So basically knowing that -1 is in the set we can say that ALL odd numbers more than -1 are also in the set.
Answer: C.
Question: Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 2 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is?
A.19 : 9
B.19 : 1
C.19 : 2
D.19 : 5
Answer: D.19 : 5
Explanation: Explanation:
Quantity of alcohol in vessel P = 62.5/100 * 2 = 5/4 litres
Quantity of alcohol in vessel Q = 87.5/100 * 4 = 7/2 litres
Quantity of alcohol in the mixture formed = 5/4 + 7/2 = 19/4 = 4.75 litres
As 6 litres of mixture is formed, ratio of alcohol and water in the mixture formed = 4.75 : 1.25 = 19 : 5.
Answer:D