RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If a:b=2:5, b:c=3:7 and c:d=1:3 find a:b:c:d?
A.6:15:25:115
B.6:15:35:115
C.6:15:35:105
D.6:15:35:125
Answer: C.6:15:35:105
Explanation: Explanation:
a:b = 2:5, b:c = 3:7, c:d = 1:3
2:5
3:7
( a = 2 × 3 = 6, b = 5 × 3 = 15 and c = 5 × 7 = 35)
(a = a × b, b= b × b and c= b × c)
a:b:c = 6 : 15 : 35
a:b:c = 6 : 15 : 35 and c:d = 1 : 3
(Note: First a,b,c multiplication with c means 1 and last c means 35
multiplication with d means 3
a:b:c:d = 6:15:35:105
Answer: Option C
Question: Which of the following is equal to 1(1/7)%?
A.0.012/100
B.0.12/100
C.1.14/100
D.12/100
Answer: C.1.14/100
Explanation: This notation may be confusing for some, since it looks like we're multiplying 1 and 1/7
How about adding a space:Which of the following is equal to (1 1/7)%
(1 1/7)% = 1.14% = 1.14/100
Answer:
C
Question: In a college of 525 students, each student takes at least 2 items from among idly, dosa, puri, and chapati for his breakfast. If 375 students take idly, 375 take dosa, 375 students take puri nad 375 students take chapati for their breakfast, the number of students who take all the four items is at most ?
A.275
B.300
C.225
D.325
Answer: C.225
Explanation: Explanation :
Let y students take all four items. Now, y is maximised when all students take either two or exactly four items each (i.e. no student take either three items). Total number of instances = 375 x 4 = 1500, of which 525 x 2 i.e. 1050 are accounted for by all students taking two items each.
Now let y studetns take lla four items (i.e. 2 items more than the initial assumption of 2 items each)
Then 1050 + 2y = 1500 => y = 225
Hence, at most 225 students can take all four items.
Answer : C
Question: Incomes of two companies A and B are in the ratio of 5 : 8. Had the income of company A been more by 30 lakh, the ratio of their incomes would have been 5 : 4. What is the income of company B?
A.80 lakh
B.50 lakh
C.48 lakh
D.60 lakh
Answer: C.48 lakh
Explanation: Let the incomes of two companies A and B be 5x and 8x respectively.
From the question,
5x+30/8x=5/4 ⇒ 20x + 120 = 40x
∴ x = 6
∴ Income of company B = 8x = 48 lakh
Answer C
Question: A man's speed with the current is 17.5 km / hr and the speed of the current is3.5 km / hr. The man's speed against the current is
A.8.5 km / hr
B.9 km / hr
C.10 km / hr
D.11.5 km / hr
Answer: D.11.5 km / hr
Explanation: Sol.
Man's rate in still in water = (17.5 - 3.5) km / hr = 14 km / hr.
Man's rate against the current = (14 - 3.5) km / hr = 11.5 km / hr.
Answer D
Question: Four female friends & four male friends will be pictured in a advertising photo. If the photographer wants to line them up in one row, with men & women alternating. How many possible arrangements may she chose?
A.40320
B.1680
C.1152
D.576
Answer: C.1152
Explanation: now any of the alternate 4 places can be filled by 4 male or female in 4!
similarly,
other 4 alternate places can be filled in 4!
hence required probability= 2*4!*4!=1152
hence C
Question: In each series, look for the degree and direction of change between the numbers. In other words, do the numbers increase or decrease, and by how much?Look at this series: 95, 10, 75, 20, 55, ... What number should come next?
A.35
B.40
C.30
D.25
Answer: C.30
Explanation: C30This is an alternating addition and subtraction series. In the first pattern, 20 is subtracted from each number to arrive at the next. In the second, 10 is added to each number to arrive at the next.
Question: The average of first 35 prime numbers is?
A.14.54
B.15.6
C.15.8
D.14.7
Answer: A.14.54
Explanation: Explanation:
Average = (2+3+5+7+11+13+17+19+23+29+31)/11= 160/11= 14.54(Approx)
Answer is A
Question: Ben bought 2Q steaks for W dollars. Jerome buys R steaks for a 50% discount, how much will the steaks cost him in cents?
A.50RW/Q.
B.50QR/W.
C.25RQ/W.
D.25RW/Q.
Answer: D.25RW/Q.
Explanation: Ben bought 2Q steaks for W dollars, so 1 steak = W/2Q
Jerome buys R steaks for a 50% discount: r* (W/4Q)
in cents the answer will be : r* (100 W/4Q)= 25 RW/Q= D
Question: calculate the profit loss percentage if a trader bought 7 balloons per rupee and sells the balloons at 6 per rupee.
A.13.7 %
B.12.7 %
C.15.3 %
D.16.7 %
Answer: D.16.7 %
Explanation: Let he total number of oranges bought by the shopkeeper be 12.
If he buys 7 a rupee, his CP =6
He selling at 6 a rupee, his SP = 7
Profit = SP - CP = 7 - 6 = 1
Profit Percent = 1/6 * 100 = 16.7 %
Answer: D
Question: The food in a camp lasts for 30 men for 40 days. If ten more men join, how many days will the food last?
A.22 days
B.30 days
C.87 days
D.16 days
Answer: B.30 days
Explanation: one man can consume the same food in 30*40 = 1200 days.
10 more men join, the total number of men = 40
The number of days the food will last = 1200/40 = 30 days.
Answer:B
Question: How much 60% of 50 is greater than 40% of 30?
A.18
B.28
C.29
D.11
Answer: A.18
Explanation: (60/100) * 50 – (40/100) * 30
30 - 12 = 18
Answer:A
Question: A list of measurements in increasing order is 4, 5, 6, 8, 10 and x. If the median of these measurements is 2/3 times their arithmetic mean, what is the value of x?
A.24
B.26
C.28
D.30
Answer: D.30
Explanation: The median is (6+8)/2 = 7
The mean is (4+5+6+8+10+x)/6 = (33+x)/6
(33+x) /6 * 2/3 = 7
x = 63-33 = 30
The answer is D.
Question: A necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead, and BLACK bead. If the necklace design begins with a red bead and ends with a white bead, then N could equal
A.16
B.32
C.33
D.54
Answer: C.33
Explanation: You can just write out the pattern and count: RGWBYRGWBYRGWBY... But to save time a good test taker will just look for a pattern. Min # is 3, because W is the third one. Then every 5 beads another white comes, so it must be 3+5+5+5.. and so on...
3+5 = 8
3+5+5 = 13
3+5+5+5=18
3+5+5+5+5=23
So you see it ends in either 8 or 3. Pick an answer that ends in either 8 or 3. Only one answer does, C.
Question: In a watch, the minute hand crosses the hour hand for the third time exactly after every 3 hrs., 18 min., 15 seconds of watch time. What is the time gained or lost by this watch in one day?
A.14 min. 10 seconds lost
B.13 min. 50 seconds lost
C.13 min. 20 seconds gained
D.14 min. 40 seconds gained
Answer: B.13 min. 50 seconds lost
Explanation: In a watch than is running correct the minute hand should cross the hour hand once in every 65 + 5⁄11 min.
So they should ideally cross 3 times once in
3×(720/11)−2060/11min=196.36minutes
But in the watch under consideration, they meet after every 3 hr,18 min and 15 seconds,
i.e, (3 × 60 + 18 + 15⁄60) = 793⁄4 min.
Thus, our watch is actually losing time (as it is slower than the normal watch). Hence when our watch elapsed
(1440×196.36/198.25)=1426.27.
Hence the amount of time lost by our watch in one day = (1440 - 1426.27) = 13.73 i.e. 13 min and 50s (approx).
Answer B
Question: Tough and Tricky questions: Absolute Values.
If |a| = 1/5 and |b| = 2/5, which of the following CANNOT be the result of a + b?
A.3/5
B.-3/5
C.-1/5
D.2/3
Answer: D.2/3
Explanation: |a| = 1/5
Absolute value of 'a' can have two values = 1/5 and -(1/5)
|b| = 2/5
Absolute value of 'b' can have two values = 2/5 and -(2/5)
Now different combinations of a + b are as follows:
a + b = (1/5) + (2/5) = 3/5
- a - b = -(1/5) - (2/5) = -3/5
a - b = (1/5) - (2/5) = -(1/5)
-a + b = -(1/5) + (2/5) = 1/5
Cross verifying with the given options, left over option is D.
Question: John bought a shirt on sale for 25% off the original price and another 25 % off the discounted price. If the final price was $16, what was the price before the first discount?
A.$45.10
B.$34.31
C.$28.44
D.$67.54
Answer: C.$28.44
Explanation: let x be the price before the first discount. The price after the first discount is
x - 25%x (price after first discount)
A second discount of 25% of the discounted price after which the final price is 16
(x - 25%x) - 25%(x - 25%x) = 16
Solve for x
x = $28.44
correct answer C
Question: A can do a half of certain work in 70 days and B one third of the same in 35 days. They together will do the whole work in.
A.77 days
B.55 days
C.44 days
D.60 days
Answer: D.60 days
Explanation: A = 140 days
B = 105 days
1/140 + 1/105 = 7/420 = 1/60
=>60 days
Answer: D
Question: 3, 4, 6, 10, 18, (...)
A.22
B.34
C.27
D.32
Answer: B.34
Explanation: Explanation :
3
3 × 2 - 2 = 4
4× 2 - 2 = 6
6× 2 - 2 = 10
10 × 2 - 2 = 18
18 × 2 - 2 = 34
Answer : Option B
Question: What is the radius of the circum circle of the triangle whose sides are 5, 12 and 13 units respectively?
A.2 units
B.12 units
C.6.5 units
D.6 units
Answer: C.6.5 units
Explanation: sides of triangle are 5,12,13
i.e triangle is right angled,hypotenuse=13
in case of a right angled triangle, the hypotenuse is the diameter of the circumcircle
so radius of the circum circle=13/2=6.5 units
ANSWER:C
Question: Find the odd man out. 3, 9, 12, 15, 18, 29
A.29
B.9
C.1
D.3
Answer: A.29
Explanation: 29 is an not multiple of 3 number. All other given numbers are multiples of 3
Answer : Option A
Question: In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
A.5
B.6.25
C.6.75
D.7
Answer: B.6.25
Explanation: Required run rate = 282 - (3.2 x 10)	/40	=	250/40 = 6.25
Option B
Question: X does a work in 15 days. Y does the same work in 30 days. In how many days they together will do the same work?
A.10
B.12
C.20
D.30
Answer: A.10
Explanation: X's 1day's work= 1/15
Y's 1 day's work=1/30
(X+Y)'s 1day's work= (1/15+1/30)=1/10
both together will finish the work in 10 days.
correct option is A
Question: Half of the workers in Palabras bookstore have read the latest book by J. Saramago, and 1/6 of the workers have read the latest book by H. Kureishi. The number of workers that have read neither book is one less than the number of the workers that have read the latest Saramago book and have not read the latest Kureishi book. If there are 150 workers in the Palabras bookstore, how many of them have read both books?
A.13
B.12
C.9
D.8
Answer: B.12
Explanation: There are total 150 workers.
Half of the workers in Palabras bookstore have read the latest book by J. Saramago,
So 75 have read Saramago.
1/6 of the workers have read the latest book by H. Kureishi.
So (1/6) * 150 = 25 have read Kureishi
The number of workers that have read neither book is one less than the number of the workers that have read the latest Saramago book and have not read the latest Kureishi book
If B workers have read both books, 20 - B have read Saramago but not Kureishi.
So, (75 - B - 1) have read neither.
Total = n(A) + n(B) - Both + Neither
150 = 75 + 25 - B + (75 - B - 1)
B = 12
Answer (B)
Question: Eight people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire cost of the car, then the share of each of the remaining persons increased by:
A.7/8
B.1/8
C.1/3
D.1/7
Answer: D.1/7
Explanation: Original share of 1 person =1/8
New share of 1 person =1/7
Increase =1/7 -	1/8	=1/56
Required fraction =	(1/56)/(1/8)=(1/56)*(8/1)	=1/7
Answer is D.
Question: A car traveling at a certain constant speed takes 2 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 60 kilometers per hour. At what speed, in kilometers per hour, is the car traveling?
A.59
B.57
C.59.5
D.58
Answer: D.58
Explanation: D
75 * T = 1 km => T = 1/60 km/h
V*(T+2/3600) = 1
V (1/60 + 2/3600) = 1 => V = 58 km/h
Question: A and B complete a work in 7 days. A alone can do it in 14 days. If both together can do the work in how many days?
A.4.6 days
B.4.78 days
C.5.65 days
D.3.77 days
Answer: A.4.6 days
Explanation: 1/7 + 1/14 = 3/14
14/3 = 4.6 days
Answer:A
Question: If a * b * c =(√(a + 2)(b + 3)) / (c + 1), find the value of 6 * 15 * 5.
A.2
B.5
C.11
D.3
Answer: A.2
Explanation: 6 * 15 * 5 = (√(6 + 2)(15 + 3) )/ (5 + 1)
= (√8 * 18) / 6
= (√144) / 6
= 12 / 6 = 2
Answer is A
Question: The watch store down the street from Wendy's house has 2 leather watches, 1 gold watch, and 1 silver watch. How many watches does the store have in all?
A.10
B.19
C.04
D.12
Answer: C.04
Explanation: Add the numbers of watches.
2 + 1 + 1 =4.
Answer is C.
Question: A man bought a bike at 40% discount on its original price. He sold it at a 80% increase on the price he bought it. What percent of profit did he make on the original price?
A.2%
B.8%
C.6%
D.4%
Answer: B.8%
Explanation: Original price = 100
CP = 60
S = 60*(180/100) = 108
100 - 108 = 8%
Answer: B
Question: If the graph of y = f(x) is transformed into the graph of 2y - 6 = - 4 f(x - 3), point (a , b) on the graph of y = f(x) becomes point (A , B) on the graph of 2y - 6 = - 4 f(x - 3) where A and B are given by
A.A = a - 3, B = b
B.A = a - 3, B = b2
C.A = a + 3, B = -2 b
D.A = a + 3, B = -2 b +3
Answer: D.A = a + 3, B = -2 b +3
Explanation: Solution
We first solve 2y - 6 = - 4 f(x - 3) for y.
y = - 2 f(x - 3) + 3
The graph of y = - 2 f(x - 3) + 3 is that of y = f(x) shifted 3 units to the right, stretched vertically by a factor of 2, reflected on the x axis and shifted up by 3 units. A point of y = f(x) will undergo the same transforamtions. Hence
Point (a , b) on the graph of y = f(x)
Becomes (a + 3 , b) on the graph of y = f(x - 3) : shifted 3 units to the right
Becomes ( a + 3 , 2 b) on the graph of y = 2 f(x - 3) : stretched vertically by 2
Becomes ( a + 3 , - 2 b) on the graph of y = - 2 f(x - 3): reflected on x axis
Becomes ( a + 3 , - 2 b + 3) on the graph of y = - 2 f(x - 3) + 3 : shifted up 3 units
Answer D
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 1200 m long?
A.200 Sec
B.240 Sec
C.167 Sec
D.197 Sec
Answer: B.240 Sec
Explanation: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 2400 m
T = D/S
T = 2400/10
T = 240 Sec
Answer: B
Question: If x is a sum of all even integers on the interval 13...61 and y is their number, what is the GCD (x, y)?
A. 1
B. 13
C. 26
D. 24
Answer: D. 24
Explanation: x = 14 + 16 + ... + 60 = (largest + smallest)/2 *(# of terms) = (14 + 60)/2*24= 37*24.
GCD of 24 and 37*22 is 24.
Answer: D.
Question: Tickets numbered 1 to 10 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 2?
A.1/3
B.2/5
C.1/2
D.2/3
Answer: C.1/2
Explanation: Here, S = {1,2,3,......,9,10}
E= event getting a multiple of 3 = {2,4,6,8,10}
probability = 5/10 = 1/2
correct option is C
Question: What is the dividend. divisor 17, the quotient is 9 and the remainder is 5?
A.150
B.154
C.158
D.160
Answer: C.158
Explanation: D = d * Q + R
D = 17 * 9 + 5
D = 153 + 5
D = 158
C)
Question: In the quadrilateral PQRS d=10 cm, h1=5 cm and
h2=2.5 cm. Find the area
A.21
B.22
C.37.5
D.24
Answer: C.37.5
Explanation: area of quad.=1/2*any diagonal*(sum of 2 perpendiculars which is drawn on that diagona)
so 1/2*10*(5+2.5)=37.5
ANSWER:C
Question: If (c - a)/(c - b) =1, then (5b - 4a)/(c - a) =
A.0.5
B.1
C.1.5
D.2
Answer: A.0.5
Explanation: Let's say c=3, b=1, a=1 so that our 1st expression holds true. Now, ibsert those numbers in the second expression and we'll get 0.5
Answer A (hopefully )))
Question: If n denotes a number to the left of 0 on the number line such that the square of n is less than 1/9, then the reciprocal of n must be
A.Less than -3
B.Between -1 and -1/3
C.Between -1/3 and 0
D.Between 0 and 1/3
Answer: A.Less than -3
Explanation: n^2 < 1/9
abs(n) < 1/3
Since n<0, then 0 > n > -1/3
1/n < -3
The answer is A.
Question: What is 0.02 percent of 12,356?
A.0.247
B.2.47
C.24.7
D.0.0247
Answer: B.2.47
Explanation: Since, Percent=1/100, what=something(s), and is:=. We can write the question as s=0.02(1/100)12,356. The answer is 2.47. Hence, the correct answer is B.
Question: What annual payment will discharge a debt of Rs. 1025 due in 2 years at the rate of 5% compound interest?
A.993.2
B.551.25
C.534.33
D.543.33
Answer: B.551.25
Explanation: Explanation:
Let each installment be Rs. x. Then,
x/(1 + 5/100) + x/(1 + 5/100)2 = 1025
820x + 1025 * 441
x = 551.25
So, value of each installment = Rs. 551.25
Answer: Option B
Question: A man engaged a servant on the condition that he would pay him Rs.900 and a uniform after 1year service. He served only for 9 months and receiveduniform and Rs.650, find the price of the uniform?
A.Rs.90
B.Rs.100
C.Rs.130
D.Rs.170
Answer: B.Rs.100
Explanation: 9/12 = 3/4 * 900 = 675
650
-------------
25
1/4 -------- 25
1 --------- ? => Rs.100
B
Question: A completes 80% of a work in 20 days. Then B also joins and A and B together finish the remaining work in 3 days. How long does it need for B if he alone completes the work?
A.37 ½ days
B.22 days
C.31 days
D.20 days
Answer: A.37 ½ days
Explanation: Explanation :
Work done by A in 20 days = 80/100 = 8/10 = 4/5
Work done by A in 1 day = (4/5) / 20 = 4/100 = 1/25 --- (1)
Work done by A and B in 3 days = 20/100 = 1/5 (Because remaining 20% is done in 3 days by A and B)
Work done by A and B in 1 day = 1/15 ---(2)
Work done by B in 1 day = 1/15 – 1/25 = 2/75
=> B can complete the work in 75/2 days = 37 ½ days
Answer : Option A
Question: In what ratio mental A at Rs.68 per kg be mixed with another metal at Rs.96 per kg so that cost of alloy (mixture) is Rs.82 per kg?
A.5:8
B.4:7
C.3:7
D.1:1
Answer: D.1:1
Explanation: (96-82)/(82-68)=14/14=1/1
ANSWER:D
Question: A boat can travel with a speed of 16 km/hr in still water. If the rate of stream is 5 km/hr, then find the time taken by the boat to cover distance of 63 km downstream.
A.3 hours
B.5 hours
C.6 hours
D.7 hours
Answer: A.3 hours
Explanation: Explanation:
It is very important to check, if the boat speed given is in still water or with water or against water. Because if we neglect it we will not reach on right answer. I just mentioned here because mostly mistakes in this chapter are of this kind only.
Lets see the question now.
Speed downstream = (16 + 5) = 21 kmph
Time = distance/speed = 63/21 = 3 hours
Option A
Question: A sum of Rs.1460 is divided into 13 students so that each boy gets Rs.120 while each girl gets Rs.100. Find the number of boys and number of girls
A.8B, 5G
B.5B, 8G
C.4B, 9G
D.9B, 4G
Answer: A.8B, 5G
Explanation: 120B+100G=1460-----i
B+G=13-------ii
from i
100B+20B+100G=1460
100(B+G)+20B=1460
100(13)+20B=1460
By simplifing we get
B=8;G=5
ANSWER:A
Question: A man can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
A.2:0
B.3:4
C.4:9
D.1.5
Answer: D.1.5
Explanation: M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 - x)2
4.5 + x = 9 -2x
3x = 4.5
x = 1.5
Answer: D
Question: A train covers a distance of 12 km in 10 min. If it takes 11 sec to pass a telegraph post, then the length of the train is?
A.298
B.220
C.120
D.776
Answer: B.220
Explanation: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 11
= 220 m.
Answer:B
Question: On January 1, 2010, Dolly invests 30% of his retirement savings in Antarctic largecap stocks, 30% in Antarctic midcaps, and 40% in Antarctic smallcaps. In 2010, largecaps rise 10%, midcaps rise 20%, and smallcaps rise 15% in the Antarctic stock market; however, in 2011, largecaps fall 20% and midcaps fall 10%, while smallcaps rise x% in Antarctica. If, on January 1, 2012, Dolly has the same total amount of retirement savings as he did two years before, then x is between
A.10 and 20
B.20 and 30
C.30 and 40
D.40 and 50
Answer: A.10 and 20
Explanation: Pick a smart number for the total retirement savings Dolly starts with—say, $10,000. (If you pick $100, you’ll wind up needing to track decimals, so give yourself more zeros to start with.)
Here are the starting values:
L = $3000
M = $3000
S = $4000
Apply the first year’s changes, so that you have these numbers on 1/1/2012:
Newer L = $3000 + 10% = $3300
Newer M = $3000 + 20% = $3600
Newer S = $4000 + 15% = $4600
Now apply the second year’s changes to L and M:
Newest L = $3300– 20% = $3300– $660 = $2640
Newest M = $3600– 10% = $3600– $360 = $3240
Add these to get $5880. So the newest S must be $10,000 (the target final total of Dolly’s retirement savings) minus $5880, $4120
The dollar change in S from 1/1/12 to 1/1/13 is $4600 – $480 = $4120. So the question is this: what percent change does $480 represent, from a starting point of $4600? Since $4600 is a nasty divisor, switch to benchmarks:
10% of $4600 = $460.
So 20% is just double that, or $920.
And so on.
From this $480 lies between $460 and $920
The correct answer is A.
Question: One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight?
A.34%
B.24%
C.22%
D.18%
Answer: A.34%
Explanation: et 100 be the total volume.
total salt = 10
salt taken out = 10/4 = 2.5
to make solution 16%, total salt = 16
salt added = 16-7.5 = 8.5
solution had = 8.5/25*100 = 34% sugar
ANSWER:A
Question: If a positive odd integer N has p positive factors, how many positive factors will N have ?
A.p
B.2p
C.P+1
D.2p+1
Answer: C.P+1
Explanation: I have added some extra text to make this question more GMAT-like:
Let's TEST some values of N
Try N = 3
The factors of 3 are {1, 3}. Here, p =2
So, 2N = (2)(3) = 6
The factors of 6 are {1, 2, 3, 6}. So, we have a total of4
Now check the answer choices:
A) p =2No good. We want an output of4. ELIMINATE
B) 2p = (2)(2) = 4. PERFECT! KEEP B
C) P+1 =2+ 1 = 3 No good. We want an output of4. ELIMINATE
D) 2p+1 = (2)(2) + 1 = 5 No good. We want an output of4. ELIMINATE
E) Cannot be determined. POSSIBLE. KEEP E
Let's TEST another value of N
Try N = 7
The factors of 7 are {1, 7}. Here, p =2
So, 2N = (2)(7) = 14
The factors of 14 are {1, 2, 7, 14}. So, we have a total of4
Now check the REMAINING answer choices:
B) 2p = (2)(2) =4. PERFECT! KEEP B
E) Cannot be determined. POSSIBLE. KEEP E
Let's TEST one more (non-prime) value of N
Try N = 9
The factors of 9 are {1, 3, 9}. Here, p =3
So, 2N = (2)(9) = 18
The factors of 18 are {1, 2, 3, 6, 9}. So, we have a total of6
Now check the REMAINING answer choices:
B) 2p = (2)(3) =6. PERFECT! KEEP B
E) Cannot be determined. POSSIBLE. KEEP E
At this point, it SEEMS LIKELY that the correct answer is C
Question: A man sells two articles for Rs.3600 each and he gains 42% on the first and loses 42% on the next. Find his total gain or loss?
A.9% loss
B.400
C.4000
D.17.64%loss
Answer: D.17.64%loss
Explanation: (42*42)/100 = 17.64%loss
ANSWER:D
Question: January 1, 2008 is Thursday. What day of the week lies on Jan 1, 2009?
A.Saturday
B.Wednesday
C.Thursday
D.Tuesday
Answer: A.Saturday
Explanation: Explanation:
Number of odd days in 2008 = 2 (since it is a leap year)
(we have taken the complete year 2008 because we need to find out the odd days from 01-Jan-2008 to 31-Dec-2008, that is the whole year 2008)
Given that January 1, 2008 is Thursday.
Hence January 1, 2009 = (Thursday + 2 odd days) = Saturday
Answer: Option A
Question: Robert spent $30 in buying raw materials, $105 in buying machinery and 10% of the total amount he had as cash with him. What was the total amount?
A.A)$150
B.B)$210
C.C)$250
D.D)$160
Answer: A.A)$150
Explanation: Let the total amount be x
then, (100-10)% of x = 30+105
90% of x = 135
90x/100 = 135
x = $150
Answer is A
Question: A and B started a business investing Rs. 60,000 and Rs 45,000 respectively. In what ratio the profit earned after 2 years be divided between A and B respectively?
A.3:2
B.4 : 3
C.18:20
D.1:4
Answer: B.4 : 3
Explanation: A: B = 60000 : 45000 = 4 : 3
ANSWER:B
Question: AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?
A.1
B.3
C.7
D.9
Answer: D.9
Explanation: AB and CD are two digit integers, their sum can give us only one three digit integer of a kind of AAA it's 111.
So, A=1. 1B+CD=111
Now, C can not be less than 9, because no to digit integer with first digit 1 (mean that it's<20) can be added to two digit integer less than 90 to have the sum 111 (if CD<90 meaning C<9 CD+1B<111) --> C=9
Answer: D.