RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If Rs. 64 amount to Rs. 83.20 in 2 years, what will Rs. 86 amount to in 4 years at the same rate percent per annum ?
A.Rs. 114.80
B.Rs. 86.70
C.Rs. 55.40
D.Rs. 51.60
Answer: D.Rs. 51.60
Explanation: Solution
P = Rs. 64,S.I. = Rs. (83.20 - 64) = Rs. 19.20, T= 2 years.
So, rate = (100x19.20/64x2)= 15%.
Now, P = Rs. 86, R = 15% ,T = 4 years.
∴ S.I. = Rs.(86x15x4/100) Rs. 51.60.
Answer D
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
A.276 m
B.167 m
C.245 metres
D.167 m
Answer: C.245 metres
Explanation: Speed = [45 X 5/18] m/sec
= [25/2] m/sec Time
= 30 sec Let the length of bridge be x metres. Then, (130 + x)/30
= 25/2 => 2(130 + x) = 750 => x
= 245 m.
Answer:C
Question: Which of the following correctly lists the data sets in order of least to greatest standard deviation?
I. 8, 9, 10, 11, 12, 13
II. 12, 12, 12, 12, 12, 12
III. 47, 56, 58, 60, 64, 69
A.I, II, III
B.II, I, III
C.III, I, II
D.II, III, I
Answer: B.II, I, III
Explanation: out of three given sets,
II has all numbers same, so it has zero standard deviation hence it is Least
I has consecutive numbers , hence all are closedly spaced hence std deviation will be less
while in III,numbers are spread widely hence std deviation should be more than III
hence order should be II, I,III
IMO B
Question: Suresh started a business with Rs.20,000. Kiran joined him after 4 months with Rs.30,000. After 2 more months, Suresh withdrew Rs.5,000 of his capital and 2 more months later, Kiran brought in Rs.20,000 more. What should be the ratio in which they should share their profits at the end of the year?
A.21:32
B.32:21
C.12:17
D.17:12
Answer: A.21:32
Explanation: Explanation:
Here capital is not the same.
Suresh invested 20000 for initial 6 months and 15000 for the next 6 months. Hence his term of ratio
=(20000Ã—6+15000Ã—6)=(20000Ã—6+15000Ã—6)
Kiran invested Rs.30000 for 4 months and Rs.50000 for next 4 months. Hence his term of ratio
=(30000Ã—4+50000Ã—4)=(30000Ã—4+50000Ã—4)
Suresh : Kiran
=(20000Ã—6+15000Ã—6)=(20000Ã—6+15000Ã—6) :(30000Ã—4+50000Ã—4):(30000Ã—4+50000Ã—4)
=(20Ã—6+15Ã—6):(30Ã—4+50Ã—4)=(20Ã—3+15Ã—3):(30Ã—2:50Ã—2)=105:160=21:32
ANSWER IS A
Question: If each participant of a chess tournament plays exactly one game with each of the remaining participants, then 276 games will be played during the tournament. Find the number of participants.
A.20
B.22
C.24
D.26
Answer: C.24
Explanation: Let P be the number of participants.
PC2 = 276
(P)(P-1) = 552 = 24*23
P = 24
The answer is C.
Question: The overall age of X and Y is 19 year greater than the overall age of Y and Z. Z is how many decades younger that X?
A.11
B.15
C.12
D.19
Answer: D.19
Explanation: D
19
(X + Y) â€“ (Y + Z) = 19
X â€“ Z = 19
Question: When 5% is lost in grinding wheat, a country has to import 20 million bags; but when only 2% is lost, it has to import only 15 million bags. Find the quantity of wheat, which grows in the country?
A.166 2/7
B.166 2/3
C.166 2/9
D.166 2/3
Answer: D.166 2/3
Explanation: 5% - 2% = 3%
3% ---- 5
100% ---- ? => 166 2/3
Answer: D
Question: Last year, Company Z made q dollars in profit. Half of the profit went to the company’s founder. The rest was split evenly among his two other partners. In terms of q, how much did each of the other partners receive?
A.q/4
B.q/5
C.q/6
D.q/7
Answer: A.q/4
Explanation: Profit = q
Profit to company founder = q/2
Profit to other partners = q/2
Number of other partners = 2
Profit to each partner = (q/2)/2 = q/4
Answer: A
Question: The speed of a boat in upstream is 100 kmph and the speed of the boat downstream is 120 kmph. Find the speed of the boat in still water and the speed of the stream?
A.70, 10 kmph
B.35, 27 kmph
C.110, 10 kmph
D.45, 55 kmph
Answer: C.110, 10 kmph
Explanation: Speed of the boat in still water = (100+120)/2 = 110 kmph. Speed of the stream = (120-100)/2 = 10 kmph
ANSWER:C
Question: In a workshop there are 2 kinds of beds, 3 kinds of closets, 2 kinds of shelves and 7 kinds of chairs. In how many ways can a person decorate his room if he wants to buy in the workshop one shelf, one bed and one of the following: a chair or a closet?
A.168.
B.80.
C.56.
D.40.
Answer: D.40.
Explanation: ways to select one shelf = 2
ways to select one bed = 2
ways to select one of the following: a chair or a closet = 7+3 = 10
ways to select all of them together = 2*2*10 = 40
Hence, D is the answer.
Question: A man bought an article and sold it at a gain of 5 %. If he had bought it at 5% less and sold it for Re 1 less, he would have made a profit of 10%. The C.P. of the article was
A.Rs 100
B.Rs 150
C.Rs 200
D.Rs 250
Answer: C.Rs 200
Explanation: Explanation:
Let original Cost price is x
Its Selling price = 105/100 * x = 21x/20
New Cost price = 95/100 * x = 19x/20
New Selling price = 110/100 * 19x/20 = 209x/200
[(21x/20) - (209x/200)] = 1
=> x = 200
Option C
Question: The average weight of a group of 30 friends decreases by 1 kg when the weight of one of them was removed. If average weight of the group after removing the weight of this one person is 29 kg, what is the weight of their new friend ?
A.31 kg
B.60 kg
C.59 kg
D.62 kg
Answer: C.59 kg
Explanation: let n= weight of one person who was removed from group
original total weight=(30 friends)(30 kg avge)=900kg
(900-n)/(30-1)=29 kg avg.
n=59 kg
Answer = C
Question: 1/0.025 is equal to
A.25.5
B.2.5
C.40
D..25
Answer: C.40
Explanation: Explanation:
1/0.025 = (1 * 1000)/25 = 1000/25 = 40
Option C
Question: In Orange County one fifth of the people are gathering mushrooms and one seventh of the people are collecting apples. What can be the number of people in Orange County?
A.60.
B.42.
C.85
D.140.
Answer: D.140.
Explanation: 1/5 mush --> 7/35
1/7 apples -->5/35
We know that we must have a multiple of 35.
D is the only choice that gives us that. 35x4=140
ANSWER:D
Question: Amar takes as much time in running 12 meters as a car takes in covering 48 meters. What will be the distance covered by Amar during the time the car covers 1.6 km?
A.600 m
B.200 m
C.300 m
D.400 m
Answer: D.400 m
Explanation: D
400 m
Distance covered by Amar = 12/4.8 (1.6km) = 2.5(1600) = 400 m
Answer is D
Question: Set A consists of integers -9, 8, 3, 10, and J; Set B consists of integers -2, 5, 0, 7, -6, and Y. If R is the median of Set A and W is the mode of set B, and R^W is a factor of 34, what is the value of Y if J is negative?
A.-2
B.Y=0
C.1
D.2
Answer: B.Y=0
Explanation: since j is negative, therefore median of the set will be 3. which is an odd number. also, we know that odd^n will always be odd. now since 34 is even, therefore 3^w will have only one factor with 34 for w=0.
mode of the set is a number which occurs maximum number of time in the set. now, since Y is the mode of the set. therefore Y=0. hence answer is B
Question: A boat having a length 7 m and breadth 2 m is floating on a lake. The boat sinks by 1cm when a man gets on it. The mass of the man is:
A.140 kg
B.60 kg
C.72 kg
D.96 kg
Answer: A.140 kg
Explanation: Explanation:
Volume of water displaced = (7 x 2 x 0.01) m3
= 0.14 m3.
∴ Mass of man = Volume of Water displaced x Density of water
= (0.14 x 1000)kg
= 140 kg.
Answer: A
Question: The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
A.4 years
B.8 years
C.6 years
D.5 years
Answer: A.4 years
Explanation: Let the ages of the children be x, (x + 3), (x + 6), (x + 9) and (x +12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20 => x = 4.
Age of youngest child = x = 4 years.
Answer: A
Question: How many differently shaped triangles exist in which no two sides are of the same length, each side is of integral unit length and the perimeter of the triangle is less than 14 units?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: Explanation :
Let the lengths of the sides be a, b and c.
Given, Triagle's perimeter < 14
=> a+b+c < 14 ----------(i)
From triangle Inequality theorem,
c < a+b
=> 2c < a+b+c. ----------(ii)
From (i) and (ii), 2c < a+b+c < 14.
=> c < 7 ----------(iii)
=> By similarity, we can say that length of any side must be less than 7.
Keeping these in mind, we can find the following possibilities :-
(2,3,4) (2,4,5) (2,5,6) (3,4,5) (3,4,6)
=> Total 5 possibilities.
Answer : C
Question: A certain meter records voltage between 0 and 10 volts inclusive. If the average value of 3 recordings on the meter was 5 volts, what was the smallest possible recording in volts?
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: if average of 3 is 5 so sum of 3 should be 15
3 recording can be from 0-10 inclusive
to find one smallest other two should be highest
so, lets assume three var are a,b,c
say a is smallest and give b and c greatest readings say 6 and 6
so a has to be 3
B
Question: What is the difference between the compound interest on Rs.12000 at 26% p.a. for one year when compounded yearly and half yearly?
A.399.8
B.383.8
C.120.8
D.202.8
Answer: D.202.8
Explanation: When compounded annually, interest
= 12000[1 + 26/100]1 - 12000 = Rs.3120
When compounded semi-annually, interest
= 12000[1 + 13/100]2 - 12000 = Rs.3322.80
Required difference = 3322.80 - 3120 = Rs.202.80
Answer: D
Question: A is thrice as good a workman as B and therefore is able to finish a job in 80 days less than B. working together, they can do it in
A.days
B.½ days
C.days
D.days
Answer: D.days
Explanation: Explanation:
B = 3A
3A – A =80 days
A = 40days
Then, B = 90 days
(A + B) = 40 × 90/ 120 = 30 days .
Answer: Option D
Question: One boy forgot the last digit of a 7digit telephone no. If he randomly dial the final 3digits after correctly dialing the 1st 4, then what is the chance of dialing the correct no.?
A.1/989
B.2/890
C.1/1000
D.3/890
Answer: C.1/1000
Explanation: it is given that last 3 digits are randomly dialed
Then, each of the digit can be selected out of 10 digits in 10 ways. Hence, required probability
= 1/(10)3 = 1/1000
C
Question: On 4th Jan, 2009 Sunday falls. What day of the week was it on 4th Jan, 2008?
A.Wednesday
B.Thursday
C.Friday
D.Saturday
Answer: D.Saturday
Explanation: Explanation:
4th Jan 2009 – 4th Jan 2008 = 52 weeks 1 day. So Jan 4th 2008 is behind one day = Saturday
Answer: D
Question: A certain sum of money is divided among A, B and C such that A gets one-third of what B and C together get and B gets two-seventh of what A and C together get. If the amount received by A is $35 more than that received by B, find the total amount shared by A, B and C.
A.$1360
B.$1250
C.$1260
D.$1270
Answer: C.$1260
Explanation: A = 1/3 (B+C) => C = 3A - B ---(1)
B = 2/7 (A+C) => C = 3.5 B - A --(B)
A-B = $35
A = 35+B
(1)===> C = 105+3B - B = 2B+105 ==> 2B-C = -105 ---(3)
(2)===> C = 3.5 B - B-35 = 2.5B-35==>2.5B-C = 35---(4)
from (4) and (3) 0.5B = 140
B = $280
A= $315
C =945-280=$665 Total amount = 315+280+665 = $1260
Answer: C
Question: 2/[(1/0.03) + (1/0.37)] = ?
A.0.004
B.0.05555
C.2.775
D.3.6036
Answer: B.0.05555
Explanation: Approximate.
1/.03 = 100/3 = 33
1/.37 = 100/37 = 3
Denominator becomes 33 + 3 = 36
2/36 = .05 something
Answer (B)
Question: A car has been driven with an average speed of 30 kilometers per hour during the first 30 kilometers of a journey. Upon reaching the 30th kilometer, the car then travels at 45 kilometers per hour for the next 30 kilometers. Find out the average speed of the car if it has not been stopped at all during the journey.
A. 35
B. 36
C. 37.5
D. 38
Answer: B. 36
Explanation: R * T = D
30 * a = 30 => a=1
45 * b = 30 => b= 2/3
(1*30 + 2/3*90)/5/3 = 36 => B
Question: The mall charges 40 cents for the first hour of parking and $3 for each additional hour until the customer reaches 4 hours, after that the parking fee is $2 per hour. If Mr.Park parked his car in the mall for 7 hours and 30 minutes, how much is he going to pay?
A.$6.8
B.$12.
C.$13.
D.$14.5.
Answer: A.$6.8
Explanation: 0.40+2*2+1*2+0.40= $6.8
Answer : $6.8
Question: The banker's gain of a certain sum due 2 years hence at 10% per annum is Rs.24. The present worth is
A.Rs. 480
B.Rs. 520
C.Rs. 600
D.Rs. 960
Answer: C.Rs. 600
Explanation: Solution
T.D	= (B.G x 100/Rate x Time)
= Rs.(24x100 / 10x 2)
= Rs.120.
P.W	= (100 x T.D/Rate x Time)
= Rs.(100x120 / 10x 2)
= Rs.600.
Answer C
Question: Rohit spent 50 percent of his earning last month on rent and 30 percent less than what he spent on rent to purchase a new dishwasher. What percent of last month's earning did John have left over?
A.15%
B.25%
C.35%
D.55%
Answer: A.15%
Explanation: SayRohit's earning last month was $100.
Rohit spent 50 percent of his earning last month on rent --> $50 on rent;
30 percent less than what he spent on rent to purchase a new dishwasher --> $50*0.7=$35 on the dishwasher.
Left over amount 100 - (50 + 35) = $15.
Answer: A.
Question: If after 200 grams of water were added to the 30%-solution of alcohol, the strength of the solution decreased by one-third, how much of the 30%-solution was used?
A.100 grams
B.220 grams
C.250 grams
D.350 grams
Answer: A.100 grams
Explanation: The 30% alcohol solution decreases by 1/3 once the 200 grams of water is added so 200/.1 =2000*.05% (2/3 of 30%) is 100 grams, thus answer is A.
Question: There are 8 letters and corresponding 8 envelopes. If 8 letters are placed into 8 envelopes randomly, find the number of ways that exactly one letter is placed into wrong envelope.
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: in 8 letter one letter is placed into wrong envelop means balance 7 are in correct place. so all 7 letters are in correct place means definitely the remaining 8th one is also placed correctly. so ans is 0
ANSWER:A
Question: With a uniform speed a car covers the distance in 8 hours. Had the speed been increased by 4 km/hr, the same distance could have been covered in 7 1/2 hours. What is the distance covered?
A.187 km
B.480 km
C.278 km
D.297 km
Answer: B.480 km
Explanation: Let the distance be x km. Then,
x/(7 1/2) - x/8 = 4
2x/15 - x/8 = 4 => x = 480 km.
Answer:B
Question: A can do a half of certain work in 70 days and B one third of the same in 35 days. They together will do the whole work in.
A.35 days
B.60 days
C.79 days
D.70 days
Answer: B.60 days
Explanation: B
60 days
A = 140 days
B = 105 days
1/140 + 1/105 = 7/420 = 1/60
=>60 days
Question: If m is an integer such that (-2)^2m=2^(15-m) then m=?
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: 2m = 15-m
3m = 15
m = 5
The answer is D.
Question: Two numbers A and B are such that the sum of 5% of A and 3% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B.
A.2 : 1
B.1 : 2
C.7 : 3
D.1 : 1
Answer: C.7 : 3
Explanation: Explanation:
5% of A + 3% of B = 2/3(6% of A + 8% of B)
5A/100 + 3B/100 = 2/3(6A/100+8B/100)
⇒5A + 3B = 2/3(6A + 8B)
⇒15A + 9B = 12A + 16B
⇒ 3A = 7B
⇒ AB = 7/3
⇒ A:B=7:3
Answer: Option C
Question: All numbers from 1 to 150 (in decimal system) are written in base 6 notation. How many of these will contain zero's?
A.25
B.20
C.35
D.45
Answer: D.45
Explanation: DETAILED SOLUTION
Any multiple of 6 will end in a zero. There are 25 such numbers. Beyond this, we can have zero as the middle digit of a 3-digit number.
This will be the case for numbers from 37 - 41, 73 - 77, 109 - 113 and 145 - 149. There are 20 such numbers.
Overall, there are 45 numbers that have a zero in them.
Correct Answer : D
Question: Malar and Roja combined will complete a task in 35 days, but Malar alone can complete same work in 60 days. Calculate in how many days Roja can complete this work ?
A.85 days
B.45 days
C.90 days
D.84 days
Answer: D.84 days
Explanation: Malar - 35 days =>1/35
Roja - 60 days =>1/60
Malar one day work = 1/35-1/60
=1/84
==>84 days
ANSWER D
Question: The value of (9x10^8)(5x10^9) is closest to which of the following?
A.10^19
B.10^15
C.10^16
D.10^14
Answer: A.10^19
Explanation: multiplying these we get,
45 x 10^8 x 10^9
= 4.5 x 10^18
which is closer to 10^19
Answer: A
Question: A certain company charges $6 per package to ship packages weighing less than 2 pounds each. For a package weighing 2 pounds or more, the company charges an initial fee of $6 plus $2 per pound. If the company charged $36 to ship a certain package, which of the following was the weight of the package, in pounds?
A.15
B.17
C.19
D.21
Answer: A.15
Explanation: Let the weight of the package be X.
2X + 6= 36
X = 15
The answer is A.
Question: If x is a positive, single-digit integer such that 4/3*x, 2x, x, and x + 2, and 5x – 2 form a non-ordered list of consecutive integers, which of the following could be the median of that list?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: The big hints are thatx is a 1-digit integerAND (4/3)x, 2x, x, and x + 2, and 5x – 2 are ALLintegers
For (4/3)x to be an integer, x MUST BE A MULTIPLE OF 3. So, x can equal 3, 6, or 9.
Now let's plug each possible value of x into the terms and see which one yields a list ofconsecutive integers
When x =3, we get the following terms: (4/3)(3), 2(3),3,3+ 2, and 5(3) – 2.
When we evaluate these terms we get: 4, 6, 3, 5 and 13
Rearrange to get: 3, 4, 5, 6, 13. So, when x = 3, we get consecutive integers.
In this case, the MEDIAN = 5
Since 5 is among the answer choices, we need not test the other 2 values of x (i.e., x = 6 and x = 9)
Answer:
C
Question: If abcd represents a positive four-digit number, where a, b, c and d are one-digit integers, which of the following CANNOT be true?
A.a + b + c + d = 9
B.abcd = 9
C.a – b - c - d = 9
D.b – a - c - d = 9
Answer: D.b – a - c - d = 9
Explanation: The (thousands place digit, a) cannot be zero, but (hundreds, tens and ones place digits; b, c and d) can be zero.
A is possible
B is possible
C is possible
D is NOT possible
E is possible
Answer: D
Question: The distance light travels in one year is approximately 5,870,000,000,000 miles. The distance light travels in 100 years is:
A.587 × 108 miles
B.587 × 1010 miles
C.587 × 10-10 miles
D.587 × 1012 miles
Answer: D.587 × 1012 miles
Explanation: The distance of the light travels in 100 years is:
5,870,000,000,000 × 100 miles.
= 587,000,000,000,000 miles.
= 587 × 1012 miles.
Answer: (D)
Question: The sum of ages of 5 children born at theintervals of 3 years each is 50 years. what is the age of the youngest child?
A.4
B.5
C.9
D.8
Answer: A.4
Explanation: the age of children x, (x+3), (x+6) , (x+9) and (x+12) years.
x+(x+3)+(x+6)+(x+9)+(x+12)= 50
5x= 20 , x=4. correct answer (A)
Question: The distance between two villages P and Q is 330 Km. A train starts from P at 8 a.m. and travel towards Q at 60 km/hr. Another train starts from Q at 9 a.m and travels towards P at 75 Km/hr. At what time do they meet?
A.11 am
B.10 am
C.9 am
D.12 pm
Answer: A.11 am
Explanation: meet x hrs after 8 a.m.
(Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs]
= 330
==>60x+75(x-1) = 330
x=3.
So,they meet at (8+3). i.e 11a.m.
ANSWER A
Question: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?
A.9:1
B.3:2
C.9:4
D.9:2
Answer: A.9:1
Explanation: Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 - 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Answer: Option A
Question: Round trip time of 110 meters in a river is 16 min. the velocity of stream is 3m/min. what is the velocity of the person in the still water?
A.6
B.7
C.8
D.9
Answer: C.8
Explanation: let speed of boat be x.hence upstream=x-3 and downstream=x+3..so we have
55/x+3 + 55/x-3 = 16...solving we get x=8
ANSWER:C
Question: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 800 m?
A.122.9 m
B.170 m.
C.122.2 m
D.222.9 m
Answer: B.170 m.
Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800
= 6300/8
= 787.5 m.
In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C.
In a race of 800 m, the number of meters by which A beats C = (800 * 212.5)/1000
= 170 m.
Answer:B
Question: If there is an equal probability of a child being born a boy or a girl, what is the probability that a couple who have 4 children have two children of the same sex and one of the opposite sex?
A.1/3
B.2/3
C.1/4
D.1/2
Answer: D.1/2
Explanation: No of ways of selecting a gender - 2C1
No of ways of selecting any 2 children out of 4 = 4C2
Total possible outcomes - 2^4 (each child can be either a girl or a boy)
Probability=2C1*4C2/2^4= 2*4/2*2*2*2=8/16=1/2
Ans=D
Question: A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
A.22 sec
B.16 sec
C.77 sec
D.55 sec
Answer: B.16 sec
Explanation: Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 280 * 2/35 = 16 sec
Answer:B
Question: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.80. How much was lent at 5%?
A.299
B.666
C.878
D.1000
Answer: D.1000
Explanation: (x*5*1)/100 + [(1500 - x)*6*1]/100 = 80
5x/100 + 90 – 6x/100 = 80
x/100 = 10
=> x = 1000
Answer:D
Question: If 9a - b = 10b + 70 = -12b - 2a, what is the value of 2a + 22b?
A.-4
B.-70
C.0
D.2
Answer: B.-70
Explanation: This implies 9a - b = 10b + 70, 9a -b = -12b -2a, 10b + 70 = -12b -2a
Manipulating the second equation gives us 10b + 70 = -12b - 2a ==> 2a + 22b = -70
Answer is B
Question: The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?
A.3209
B.3291
C.3600
D.2997
Answer: C.3600
Explanation: P = 144(100/5)2 => P
= 3600
Answer: C
Question: If the cost price is 25% of selling price. Then what is the profit percent.
A.150%
B.200%
C.300%
D.350%
Answer: C.300%
Explanation: Explanation:
Let the S.P = 100
then C.P. = 25
Profit = 75
Profit% = (75/25) * 100 = 300%. Answer: C
Question: Of the 320 people attending a conference, 180 have signed up for the Marketing workshop and 250 have signed up for the Accounting workshop. If 40 of the people attending did not sign up for either workshop, then the number of people who signed up for both the Marketing and the Accounting workshops is:
A.110
B.125
C.130
D.150
Answer: D.150
Explanation: Since the information in the prompt refers to the 'standard' 5 groups, you can use the Overlapping Sets Formula to get to the solution:
Total = Gp.1 + Gp.2 - Both + Neither
320 = 180 + 250 - Both + 40
320 = 470 - Both
Both = 150
Final Answer:
D
Question: If positive integer k is divided by 12, the quotient is m and the remainder is 2, then which of the following must be true?
I. k + m is even
II. k cannot be a prime number
III. k is divisible by 4
A.None
B.I
C.II
D.III
Answer: A.None
Explanation: k = 12m+2 = 2(6m+1)
I. k + m = 2(6m+1) + m => even if only m is even, however m can be odd => not always true
II. k can not be a prime: not always true:
m=0 => k=2 : a prime
III. not true if m is even
Ans: none of the above
Question: If a class of 10 students has six men, how many ways can the men and women be arranged in a circle so that no two men sit next to each other?
A.5!4!
B.6!5!
C.4!4!
D.10!
Answer: B.6!5!
Explanation: for no two men to sit together, either all are in even or odd position
fix one at any one position then rest five can be fixed in 5! ways...
also rest six position of women can be fixed in 6!..
total ways 6!5!
B
Question: Find the remainder when 4*4! + 5*5! + 6*6! +...................+ 19*19! is divided by 64.
A.22
B.27
C.40
D.28
Answer: C.40
Explanation: 8*8! and its subsequent terms are exactly divisible by 64. As highest power of 2 in 64 is 6 and highest power of 2 in 8! is 7 which is greater than 6. So we have to find the remaidner when 4*4! + 5*5! + 6*6! + 7*7! is divided by 64 which is 40.
Elitmus model questions
Answer:C