RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Bruce and Bhishma are running on a circular track of length 600m. Speed of Bruce is 30 m/s and that of Bhishma is 20 m/s .They start fro the same point at the same time in the same direction. When will they meet again for the first time?
A.40
B.45
C.50
D.60
Answer: D.60
Explanation: Actually Arjun has to make a lead of 600 m, because when Arjun will be 600m ahead of Bhishma, they will be together again as a person when completes the total length it starts retracing he same path and thus Arjun and Bhishma can be together again.
Since , they make a difference of 10 m in 1 second. so, he will create 600m difference in 60 second.
D
Question: A snail, climbing a 20 feet high wall, climbs up 4 feet on the first day but slides down 2 feet on the second. It climbs 4 feet on the third day and slides down again 2 feet on the fourth day. If this pattern continues, how many days will it take the snail to reach the top of the wall?
A.12
B.16
C.17
D.20
Answer: C.17
Explanation: total transaction in two days = 4-2 = 2 feet
in 16 days it will climb 16 feet
on the 17th day , the snail will climb 4 feet , thus reaching the top
therefore , total no of days required =17
ANSWER:C
Question: Of the 300 employees of a certain company, 65 are accountants. Two employees of the company will be selected at random. Which of the following is closest to the probability that neither of the employees selected will be an accountant?
A.0.3
B.0.4
C.0.5
D.0.6
Answer: D.0.6
Explanation: Total = 300
Accountants = 65
Non Accountants = 300 - 65= 235
Two employees of the company will be selected at random so probability that neither of the employees selected will be an accountant is
235 C 2 / 300 C 2 = 235 * 234 / 300 * 299 = 0.611 ~ 0.6
Hence D 0.6 is the correct answer
Question: A number when multiplied by 3 and then subtracted by 2 becomes the reverse of itself. Can you find out which smallest number is that?
A.28
B.11
C.10
D.35
Answer: A.28
Explanation: A
28 is the required number.
28 * 3 - 2 = 82.
Question: In country Z, 10% of the people do not have a university diploma but have the job of their choice, and 30% of the people who do not have the job of their choice have a university diploma. If 40% of the people have the job of their choice, what percent of the people have a university diploma?
A.35%
B.48%
C.55%
D.65%
Answer: B.48%
Explanation: Setting up a matrix is how I solve this one.
Diploma No Diploma Totals
Job of Choice w/Diploma
Job of Choice w/o Diploma = 10%
Job of Choice Total = 40%
Not Job of Choice with Diploma =.3X
Not Job of Choice w/o Diploma= .7X
Total Not Job of Choice = X
Total with Diploma
Total without Diploma
Total citizen = 100
If 40% of people have their job of choice, then 60% of people do NOT have their job of choice. 30% of 60% = 18%. We can also see that 30% of the people have their job of choice and a diploma (40%-10%=30%). 30% + 18% = 48%. Therefore 48% of the people in Country Z have a diploma.
Ans B
Question: A salesmanâ€™s terms were changed from a flat commission of 5% on all his sales to a fixed salary of Rs.1000 plus 2.5% commission on all sales exceeding Rs. 4,000. If his remuneration as per new scheme was Rs. 100 more than that by the previous schema, his sales were worth?
A.s. 14,000
B.s. 12,000
C.s. 32,000
D.s. 40,000
Answer: C.s. 32,000
Explanation: [1000 + (X-4000) * (2.5/100)] - X * (5/100) = 100
X = 32000
ANSWER:C
Question: In one alloy there is 10% chromium while in another alloy it is 6%. 15 kg of the first alloy was melted together with 35 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy.
A.7.2%
B.9%
C.9.2%
D.8.6%
Answer: A.7.2%
Explanation: The amount of chromium in the new 15+35=50 kg alloy is 0.10*15+0.06*35=3.6 kg, so the percentage is 3.6/50*100=7.2%.
Answer: A.
Question: A pharmaceutical company received $2 million in royalties on the first $12; million in sales of generic equivalent of one of its products and then $4 million in royalties on the next $48 million in sales. By approximately what percent did the ratio of royalties to sales decrease from the first $12 million in sales to the next $48 million in sales?
A.20%
B.25%
C.30%
D.50%
Answer: D.50%
Explanation: change in ratio of royalties to sales = 2/12 -4/48 = 1/12
% decrease = (1/12)/(2/12) *100 = 50% (approx)
Answer: D)
Question: A do 2/5 part of work in 12 days and B do 3/4 part of work in 15 days.so,both together in how many days can finish the work?
A.15
B.8
C.10
D.12
Answer: D.12
Explanation: work of A in 12 days=2/5,work of A in 1 days=1/30
work of B in 15 days =3/4,work of B in 1 days=1/20
(A+B) work in 1 days=[1/30+1/20]=1/12
so,both together finish the work in 12 days
answer D
Question: Two pipes A and B can fill a cistern in 37 1/2 minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if pipe B is turned off after
A.5 min
B.9 min
C.10 min
D.15 min
Answer: B.9 min
Explanation: Explanation:
Solution 1
Pipe A alone can fill the cistern in 37 1/2 = 75/2 minutes. Since it was open for 30 minutes, part of the cistern filled by pipe A =2/75 X 30 =4/5
So the remaining 1/5 part is filled by pipe B.
Pipe B can fill the cistern in 45 minutes. So, time required to fill 1/5 part
=45/5 =9 minutes.
i.e., pipe B is turned off after 9 minutes.
ANSWER IS B
Question: Which of the following best approximates the value of q if 5^29+5^11=5^q ?
A.40
B.30
C.29
D.27
Answer: C.29
Explanation: We have: 5^29+5^11=5^q
==> because 5^11 > 0 --> 5^q MUST be equal or greater than 5^29 ==>q MUST be equal or greater than 29
==> Option D and E are out immediately.
Divide both sides by 5^q and q >= 29
We have:
5^(29-q) + 5^11/5^q = 1
Because q >= 29 ==>5^11/5^q = 0.0000xyz, that is very small,we can ignore it.
Thus, 5^(29-q) must be approximately 1
==> 29-q = 0 ==> q is approximately 29
C is the answer.
Question: Which is the smallest no which divides 2880 and gives a perfect square?
A.4
B.9
C.3
D.5
Answer: D.5
Explanation: Breaking 2880 into multiples:
2880 = 5*9*64 = 5 * 3^2 * 8^2 = 5* 24^2
5 being a prime number with only one multiple will divide 2880 & result in 9*64 which is a perfect square (9*64= 24^2 = 576)
ANSWER:D
Question: One morning is starts to snow at a constant rate. Later, at 6:00am, a snow plow sets out to clear a straight street. The plow can remove a fixed volume of snow per unit time, in other words its speed it inversely proportional to the depth of the snow. If the plow covered twice as much distance in the first hour as the second hour, what time did it start snowing?
A.2:22:55am
B.5:22:55am
C.1:22:55am
D.6:22:55am
Answer: B.5:22:55am
Explanation: Let the depth of snow at time t to be t units. The speed of the plow at time t will be 1/t. Define t=0 as the time it started snowing and t=x the time the plow started.
The distance covered in the first hour is the integral from x to x+1 of 1/t dt. The antiderivative of 1/t is ln(t) so the total distance covered in the first hour is ln((x+1)/x).
By the same reasoning the distance covered in the second hour in ln((x+2)/(x+1)).
Using the fact that it the plow traveled twice as far in the first hour as the second: ln((x+1)/x) = ln((x+2)/(x+1))2
Exp both sides and you have (x+1)/x = ((x+2)/(x+1))2.
Solving for x you get x=(51/2-1)/2, which is the number of hours that elapsed between the time it started snowing and the snow plow left.
It started snowing at (51/2-1)/2 hours before 6:00am, or 5:22:55am.
correct answer B
Question: If (2 to the x) - (2 to the (x-2)) = 3 (2 to the 9), what is the value of x?
A.9
B.11
C.13
D.15
Answer: B.11
Explanation: (2 to the power x) - (2 to the power (x-2)) = 3 (2 to the power 9)
2^x - 2^(x-2) = 3. 2^9
Hence x = 11.
Answer is B
Question: Joe went on a diet 4 months ago when he weighed 222 pounds. If he now weighs 198 pounds and continues to lose at the same average monthly rate, in approximately how many months will he weigh 180 pounds?
A. 3
B. 3.5
C. 3
D. 4.5
Answer: C. 3
Explanation: 222 - 198 = 24 pounds lost in 4 months
24/4 = 6, so Joe is losing weight at a rate of 6 pounds per month.
...in approximately how many months will he weigh 180 pounds?
A simple approach is to just list the weights.
Now: 198 lbs
In 1 month: 192 lbs
In 2 months: 186 lbs
In 3 months: 180 lbs
Answer: C
Question: Three consecutive odd integers are in increasing order such that the sum of the last two integers is 13 more than the first integer. Find the three integers?
A.7, 9, 29
B.7, 2, 10
C.7, 9, 10
D.7, 9, 11
Answer: D.7, 9, 11
Explanation: Explanation:
Let the three consecutive odd integers be x, x + 2 and x + 4 respectively.
x + 4 + x + 2 = x + 13 => x = 7
Hence three consecutive odd integers are 7, 9 and 11.
Answer:D
Question: Dave has no fashion sense, and will wear any combination of garments regardless of whether someone thinks they “match.” Every day Dave chooses an outfit consisting of one of each of the following garments: jacket, tie, shirt, pants, boxers, right sock, left sock, right shoe, left shoe. If Dave has more than one of each of the listed garments, and can make 2400 different outfits, then for how many garments does Dave have exactly five choices?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: 2400 = 24*100 = 24*5^2*2^2
Dave has exactly 5 choices for two garments.
The answer is C.
Question: In Arun's company 60% of the employees earn less than $50,000 a year, 60% of the employees earn more than $40,000 a year, 11% of the employees earn $43,000 a year and 5% of the employees earn $49,000 a year. What is the median salary for the company?
A.43.0
B.45.5
C.46.0
D.49.0
Answer: A.43.0
Explanation: In Arun's company 60% of the employees earn less than $50,000 a year, 50 and 51 employee will be each 43K. hence median = (43K+43k)/2
Question: Look at this series: V, VIII, XI, XIV, XVII, __, ... What number should fill the blank?
A.IX
B.XXIII
C.XV
D.XX
Answer: D.XX
Explanation: Explanation: This is a simple addition series; each number is 3 more than the previous number.
Answer: D
Question: A is a working partner and B is a sleeping partner in the business. A puts in Rs.15000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?
A.2775
B.2888
C.1888
D.4200
Answer: D.4200
Explanation: 15:25 => 3:5
9600*10/100 = 960
9600 - 960 = 8640
8640*3/8 = 3240 + 960
= 4200
Answer:D
Question: The cost of Type 1 material is Rs. 15 per kg and Type 2 material is Rs.20 per kg. If both Type 1 and Type 2 are mixed in the ratio of 2 : 3, then what is the price per kg of the mixed variety of material?
A.Rs. 19
B.Rs. 16
C.Rs. 18
D.Rs. 17
Answer: C.Rs. 18
Explanation: Explanation:
Solution 1
Cost Price(CP) of Type 1 material is Rs. 15 per kg
Cost Price(CP) of Type 2 material is Rs. 20 per kg
Type 1 and Type 2 are mixed in the ratio of 2 : 3.
Hence Cost Price(CP) of the resultant mixture
=(30+60)/5=90/5=18
=> Price per kg of the mixed variety of material =Rs.18
Answer IS C
Question: Sabrina is contemplating a job switch. She is thinking of leaving her job paying $85,000 per year to accept a sales job paying $40,000 per year plus 15 percent commission for each sale made. If each of her sales is for $1,500, what is the least number of sales she must make per year if she is not to lose money because of the job change?
A.200
B.177
C.178
D.377
Answer: A.200
Explanation: Lets say she sales x items so her commission will be : x * 1500*15/100 = 225x
Salary difference is: 85000 - 40000 = 45000
So commission must at least be equal to salary difference i.e. x = 45000/225 = 200 (Approx).
Hence answer is A
Question: The perimeter of a semi circle is 144 cm then the radius is?
A.87
B.28
C.26
D.27
Answer: B.28
Explanation: 36/7
r = 144
=> r = 28
Answer: B
Question: In a store the product A costs twice as much as the product B minus the cost of product C, If 4 products B plus 2 products C bought the price is $ 8, if 2 products you buy A plus 2 products B the price is $ 6, which is the price of the product C?
A.1.2
B.2
C.1.5
D.1.8
Answer: A.1.2
Explanation: We propose equations products
A = 2B-C
4B + 2C = 8 $
2A + 2B = 6 $
substituting
C = 1.2 $
Answer: A
Question: How long will a boy take to run round a square field of side 40 meters, if he runs at the rate of 12km/hr?
A.52sec
B.48sec
C.60sec
D.25sec
Answer: B.48sec
Explanation: Speed = 12 km/hr = 12*5/18 = 10/3 m/sec
Distance = 40*4 = 160m
Time taken = 160*3/10 = 48sec
Answer is B
Question: 3 friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order In 7 rounds. A, B, C, AB, BC, AC, ABC. Final round measure is 155kg then find the average weight of all the 7 rounds?
A.98.5 kgs
B.88.5 kgs
C.86.5 kgs
D.67.5 kgs
Answer: B.88.5 kgs
Explanation: Average weight = [(a + b + c + (a+b) + (b+c) + (c+a)+(a+b+c)] / 7 = 4 (a+b+c) /7 = 4 x 155/7 = 88.5 kgs
Answer:B
Question: Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 10 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her?
A.8 mph
B.5.5 mph
C.3.5 mph
D.4 mph
Answer: B.5.5 mph
Explanation: (1 mph +10 mph)/2 = 5.5 mph
Correct option is: B
Question: Using all the letters of the word "WEDNESDAY", how many different words can be formed?
A.A)7
B.B)9!
C.C)8
D.D)7!
Answer: B.B)9!
Explanation: Explanation:
Total number of letters = 9
Using these letters the number of 9 letters words formed is 8!.
Answer: Option B
Question: If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
A.Sunday
B.Saturday
C.Tuesday
D.Wednesday
Answer: A.Sunday
Explanation: Solution
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004. Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005) Answer A
Question: How many three digits number can be formed by using the digits 4,5,6,7,8,9 if the repetition of digits allowed?
A.106
B.108.
C.109
D.110
Answer: B.108.
Explanation: For a number to be odd we must have 5,7 or 9 at the unit place. So there 3 ways of filling the unit place. Since the repetion of digits is allowed, each of the tens and hundreds place can filled in 6ways. Hence required number of numbers = 3x6x6=108. Answer : B
Question: If 4<x<6<y<10, then what is the greatest possible positive integer difference of x and y?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: 4 < x < 6 < y < 10;
4 < x
y < 10
4 + y < x + 10
y - x <6.
Positive integer difference is 5 (for example y = 9.5 and x = 4.5)
Answer: C.
Question: In a certain school, there are 80 Freshmen, 100 Sophomores, and 220 Upperclassmen, drawn from three cities: A, B, and C. Sixty percent of students are from A, 30% from B, the rest from C, and all these students from C are freshmen. Half the student from B are upperclassman, and the rest are split evenly between the other two grades. How many sophomores are from A?
A. 60
B. 70
C. 80
D. 90
Answer: B. 70
Explanation: Answer = B = 70
Question: A chair is bought for Rs.200/- and sold at Rs.320/- find gain or loss percentage
A.75% loss
B.20% gain
C.60% gain
D.30% gain
Answer: C.60% gain
Explanation: Formula = (Selling price ~ Cost price)/Cost price * 100
= (320- 200)/200 = 60% gain
C
Question: If the selling price of 50 articles is equal to the cost price of 45 articles, then the loss or gain percent is:
A.45%
B.10%
C.20%
D.60%
Answer: B.10%
Explanation: C.P. of each article be Re. 1.
Then, C.P. of 50 articles = Rs. 50;
S.P. of 50 articles = Rs. 45.
Loss % = 5/50 * 100 = 10%
ANSWER B
Question: A rectangular rug with side lengths of 6 feet and 6 feet is placed on a square floor that has an area of 64 square feet. If the surface of the rug does not extend beyond the area of the floor, what fraction of the area of the floor is not covered by the rug?
A.A.3/16
B.1/4
C.C.1/2
D.7/16
Answer: D.7/16
Explanation: Area of the rectangular rug = 6*6 = 36
Fraction not covered by the rug = (Total Area - Rug area) / Total Area
= (64 - 36)/64
= 7/16=D
Question: A car travels the first 1/2 of certain distance with a speed of 15 km/hr the next 1/4 distance with a speed of 20 km/hr, and the last 1/4 distance with a speed of 60 km/hr. the average speed of the car for the whole journey is?
A.12km/hr
B.20km/hr
C.89km/hr
D.52km/hr
Answer: B.20km/hr
Explanation: Let the whole distance travelled be x km
and the average speed of the car for he whole journey be y km/hr
then (x/2)/15+(x/4)/20+(x/4)/60=x/y
x/30+x/80+x/240=x/y
1/20y=1
y=20km/hr
Answer(B)
Question: A bag contains 4 white balls, 4 black balls, and 3 red balls. One by one, three balls are drawn out without replacement. What is the probability that the third ball is red?
A.1/2
B.1/4
C.3/11
D.5/16
Answer: C.3/11
Explanation: The probability for each ball to be drawn third is equal.
Then the probability a red ball is drawn third is 3/11.
The answer is C.
Question: Larry, Michael, and Jack have five donuts to share. If any one of the men can be given any whole number of donuts from 0 to 5, in how many different ways can the donuts be distributed?
A. 21
B. 42
C. 120
D. 504
Answer: A. 21
Explanation: Larry, Michael, and Jack have five donuts to share. to get the answer, see how can we get sum5with 3 numbers.
1) 0,0,5 = 3 combinations or 3! /2!
2) 0,1,4 = 6 combinations or 3!
similarly
3) 0,2,3 = 6 combinations
4) 1,1,3 = 3 combination
5) 2,2,1 = 3 combination
total =21=A
Question: X and Y started a business by investing Rs.36000 and Rs.42000 respectively after 4 months Z joined in the business with an investment of Rs.48000, then find share of Z in the profit of Rs.13750 ?
A.3200
B.4000
C.3250
D.3825
Answer: B.4000
Explanation: Ratio of investment, as investments is for different time.
Investment x Number of units of time.
Ratio of investments X : Y : Z = 36000 : 42000 : 48000 => 6 : 7 : 8.
X = 6 x 12 Months = 72, Y = 7 x 12 = 84, Z = 8 X 8 = 64 => 18 : 21 : 16.
Ratio of investments => X : Y : Z = 18 : 21 : 16.
Investment Ratio = Profit sharing Ratio.
Z = 13750 × 16/55 = Rs.4000.
Share of Z in the profit is Rs.4000.
Option B
Question: The present ages of three persons in proportions 4 : 1 : 3. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
A.8, 20, 28
B.16, 28, 36
C.16, 28, 35
D.40, 10, 30
Answer: D.40, 10, 30
Explanation: Let their present ages be 4x, x and 3x years respectively.
Then, (4x - 8) + (x - 8) + (3x - 8) = 56
8x = 80
x = 10.
Their present ages are 4x = 40 years, 1x = 10 years and 3x = 30 years respectively.
Answer:D
Question: If set A={4,4,4,....,n times} , set B={3,3,3,3....m times} and set C={11,11,11...k time} , then in terms of m,n and k , how many possible subsets from sets A,B, and C can be created ?
A.a) k(n+m+mn)+ k
B.b) (1+n+m+mn)(k+1)
C.c) k^2(mn+n/m)
D.d) kmn(k+m+n)
Answer: B.b) (1+n+m+mn)(k+1)
Explanation: a) how many 2's are included?
b) how many 3's are included?
and
c) how many 11's are included?
For the number of 2, we could have zero 2's, or one 2, or two 2's, all the way up to n 2's. That's (n + 1) possibilities for the 2's. Similarly, (m + 1) possibilities for the 3's and (k + 1) possibilities for the 11's. We simply multiply these three numbers.
NOTICE that one set, the set that includes no 2's, no 3's, and no 11's, is included. This is known in mathematics as thenull set, sometimes called the empty set, a set with no members. Technically, this is a subset of every possible set, but that's a technical detail of set theory that goes well beyond what the GMAT would expect students to know. Even the the calculation is not that difficult, some of the technical aspects of this question are not in line with the GMAT's expectations.
The number of subsets is (m + 1)(n + 1)(k + 1). The answer is not given in that form. Instead, the first two factors have been FOILed together:
(mn + m + n + 1)(k + 1).
Mike
B
Question: How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 60 m long and 16 1/2 m board?
A.99
B.18
C.16
D.198
Answer: D.198
Explanation: 60 * 33/2 = 5/2 * 2 * x => x
= 198
Answer:D
Question: John has 10pairs of dark blue socks and 10pairs of black socks. He keeps them all in the same bag. If he picks out 3socks at random, then what is the probability thathe will get a matching pair?
A.1
B.3
C.5
D.6
Answer: A.1
Explanation: If he draws any combination of 3 socks he will definitely have the matching pair of either colour.
A
Question: A dishonest dealer professes to sell his goods at Cost Price but still gets 15% profit by using a false weight. What weight does he substitute for a kilogram?
A.869 1/7 grams
B.869 13/23 grams
C.869 8/3 grams
D.869 1/3 grams
Answer: B.869 13/23 grams
Explanation: If the cost price is Rs.100, then to get a profit of 15%, the selling price should be Rs.115.
If 115kg are to be sold, and the dealer gives only 100kg, to get a profit of 15%.
How many grams he has to give instead of one kilogram(1000 gm).
115 gm ------ 100 gm
1000 gm ------ ?
(1000 * 100)/115 = 869 13/23 grams.
Answer:B
Question: If the radius of a circle is decreased 10%, what happens to the area?
A.10% decrease
B.19% decrease
C.36% decrease
D.40% decrease
Answer: B.19% decrease
Explanation: Area of Square = Pi* radius^2
New Radius = 0.9 * old radius
so new area = (0.9)^2 old area => 0.81 of old area =>81% old area
Ans : B
Question: Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 22 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
A.288
B.516
C.877
D.278
Answer: B.516
Explanation: 1h ----- 5
? ------ 60
12 h
RS = 22 + 21 = 43
T = 12
D = 43 * 12 = 516
Answer: B
Question: On a 20 mile course, Pat bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course?
A.75
B.105
C.117
D.150
Answer: C.117
Explanation: At an average rate of 30 miles per hour in 12 minute (1/5 hours) Pat covers (distance) = (time) * (rate) = 1/5*30 = 6 miles, thus she should cover the remaining distance of 20 - 6 = 14 miles at an average rate of 8 miles per hour.
To cover 14 miles at an average rate of 8 miles per hour Pat needs (time) = (distance)/(rate) = 14/8 = 1.75 hours = 105 minutes.
Therefore Pat needs total of 12 + 105 = 117 minutes to cover the entire course.
Answer: C.
Question: Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 2 : 3?
A. 48 kmph
A.33
B.50
C.28
D.27
Answer: B.50
Explanation: Let the distances between city A to B and B to C be 2x km and 3x km respectively.
Total time taken to cover from A to C
= (2x)/40 + (3x)/60 = (6x + 6x)/120 = 12x/120 = x/10 Average speed = (2x + 3x)/(x/10) = 50 kmph.
Answer: B
Question: A rectangular grass field is 75 m * 40 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m?
A.s.1350
B.s.1327
C.s.1200
D.s.1397
Answer: C.s.1200
Explanation: Area = (l + b +2d) 2d
= (75 + 40 +2.5 * 2) 2*2.5 => 600
600 * 2 = Rs.1200
Answer: C
Question: John and David were each given X dollars in advance for each day they were expected to perform at a community festival. John eventually performed on all 30 days of the festival, while David performed on 5 fewer days than John performed. If David gives John y dollars of her advance payment so that they would have each received the same daily rate, what was John paid in advance, in terms of Y?
A.11Y
B.15Y
C.13Y
D.10Y
Answer: A.11Y
Explanation: Both of them were given X $ each
David to adjust Y $ in advance to John
So David now has (X-Y)$ and John has (X+Y) $ such that their daily rate becomes same
So Rate of David= Rate of John
Also , David works for 25 days and John works for full 30 days
(X-Y) / 25 = (X+Y) / 30
Solving 30x-30y=25x+25y =>5x=55y => x=55/5y
X= 11Y
Answer : A