RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Mary invested a certain sum of money in a bank that paid simple interest. The amount grew to $260 at the end of 2 years. She waited for another 3 years and got a final amount of $350. What was the principal amount that she invested at the beginning?
A.$220
B.$230
C.$240
D.$200
Answer: D.$200
Explanation: What shall be the rate of interest.? Does that is not required for the calculation?
Not really!
Keep in mind that the interest earned each year will be the same in Simple Interest.
At the end of 2 years, Amount = $260
At the end of 5 years, Amount = $350
This means she earned an interest of $90 in 3 years. Or $30 in each year.
We know that the interest earned each year will be the same.
Therefore she must have earned $60 in 2 years.
Hence Principal Amount = $260 - $60 = $200 Option D
Question: Read the following three equations:
5 ~ 4 ~ 3 ~ 9 = 4215
6 ~ 9 ~ 2 ~ 6 = 3816
4 ~ 7 ~ 3 ~ 3 = 1122
Now based on the rule that has been used, solve the following equation:
7 ~ 2 ~ 7 ~ 4 = ____
A.2418
B.2910
C.2940
D.3749
Answer: A.2418
Explanation: A
2418
2418
The rule that is being followed here is
P ~ Q ~ R ~ S = [first digit of (P * S)] [last digit of (Q * R)] [first digit of (Q * R)] [last digit of (P * S)]
Using the same rule in the incomplete equation,
7 ~ 2 ~ 7 ~ 4 = [first digit of (7 * 4)] [last digit of (2 * 7)] [first digit of (2 * 7)] [last digit of (7 * 4)]
= 2418
Thus 2418 is the missing number.
Question: A Zayn's company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio of revenue from car sales in 1996 to revenue from truck sales in 1996?
A. 1:2
B. 4:5
C. 1:1
D. 3:2
Answer: A. 1:2
Explanation: A Zayn's company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996.1996- x----- y------- x+y
1997- x1---- y1-- x1+y1
x1= a*x .....(P)
y1= 1.07*y...(Q)
x1+y1/x+y = 1.01
solve using P and Q and find x/y
Question: Alan buys 4 TVs, a 26 inch, a 28 inch, a 30 inch, and a 32 inch, for his new house. Each TV costs $200 more than the size below it. Alan spends a total of $3,200. How much would he have spent if he had bought only the 28 inch and 30 inch TVs?
A.850
B.1,600
C.1,700
D.2,550
Answer: B.1,600
Explanation: Assume the cost of the least sized (26 Inch) TV = x
Cost of 28 inches TV = x + 200
Cost of 30 inches TV = x + 400
Cost of 32 inches TV = x + 600
Total cost = 4x + 1200 = 3200
Therefore x = 2000/4 = 500
Price of 28inch + 30 inch = 700 + 900 = 1600
Option B
Question: If a and b are consecutive integers (b>a), which of the following statements could be false? 1. a^2+b is an even number. 2. ab is even number 3. (a + b) is always an odd number.
A.II only
B.III only
C.I,II only
D.I only
Answer: D.I only
Explanation: 1^2+2 = 1+2 =3
So Option I false.
odd*even = even. Option II is true
odd + even = odd. Option III is true
Answer : D
Question: In a class, there are 27 boys who are over 160 cm tall. If these constitute three-fourths of the boys and the total number of boys is two-thirds of the total number of students in the class, what is the number of girls in the class ?
A.6
B.12
C.18
D.24
Answer: C.18
Explanation: Explanation:
Let the number of boys be x. Then, (3/4)x = 27 or x = 27 x(4/3) = 36.
If total number of students is y, then (2/3) y = 36 or y = 36 x (3/2) = 54.
Therefore Number of girls in the class = (54 - 36) = 18.
Answer: C
Question: The difference between simple and compound interest on Rs. 1200 for one year at 10% per annum reckoned half-yearly is?
A.Rs.7
B.Rs.3
C.Rs.8
D.Rs.1
Answer: B.Rs.3
Explanation: S.I. = (1200 * 10 * 1)/100
= Rs. 120
C.I. = [1200 * (1 + 5/100)2 - 1200]
= Rs. 123 Difference = (123 - 120)
= Rs. 3.
Answer:B
Question: Two men and three women working 7 hours a day finish a work in 5 days. Four men and four women working 3 hours a day complete the work in 7 days. The number of days in which only 7 men working 4 hours a day will finish the work is?
A.5 days
B.3 days
C.2 days
D.9 days
Answer: A.5 days
Explanation: Answer: Option A
2M + 3W ----- 35 h
4M + 4W ------- 21 h
7M -------? d
70M + 105W = 84M +84M
21W = 14M => 2M = 3W
4 * 35 = 7 * x => x = 20 hours
20/4 = 5 days
Question: The S.I. on a certain sum of money for 6 years at 14% per annum is half the C.I. on Rs. 7000 for 2 years at 7% per annum. The sum placed on S.I. is?
A.603.75
B.555.75
C.569.55
D.256.25
Answer: A.603.75
Explanation: C.I. = [7000 * (1 + 7/100)2 - 7000]= (7000 * 11/10 * 11/10 - 7000) = Rs. 1014.3.Sum = (507.15 * 100)/(6 * 14)= Rs.603.75Answer:A
Question: A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
A.Rs.1678
B.Rs.1640
C.Rs.2341
D.Rs.3041
Answer: B.Rs.1640
Explanation: Explanation:
(x*8*3)/100 = ((2665 - x)*3*5)/100
24x/100 = 39975/100 - 15x/100
39x = 39975 => x = 1025
Second sum = 2665 â€“ 1025 = 1640
ANSWER IS B
Question: What is the difference between the largest number and the least number written with the digits 5, 3, 1, 4?
A.6084
B.3788
C.4086
D.2721
Answer: C.4086
Explanation: Explanation:
1345
5431
------------
4086
Answer:C
Question: By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?
A.38028
B.38000
C.32977
D.38128
Answer: B.38000
Explanation: CP + CP/8 = 45000
CP = 40000
SP = 40000*(95/100)
= 38000
Answer:B
Question: A can contains a mixture of liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter Q of liquid A was contained by the can initially?
A.10
B.20
C.21
D.25
Answer: C.21
Explanation: As A:B::7:5 ---> only option C is a multiple of 7 and hence it is a good place to start. Also A:B::7:5 means that , A = (712)*Total and B = (5/12)*Total
If A = 21 , B = 15 ---> remove 9 litres ---> you remove (7/12)*9 of A ---> A remaining = 21-(7/12)*9 = 63/4
Similarly, for B, you remove (5/12)*9 ---> B remaining = 15 - (5/12)*9 = 45/4 and then add 9 more litres of B ---> 9+45/4 = 81/4
Thus A/B (final ratio) = (45/4)/(81/4) = 7:9 , the same as the final ratio mentioned in the question.
Hence C is the correct answer.
A/B = 7/9 = (7x-(7/12)*9)/ (5x-(5/12)*9+9), where 7x and 5x are initial quantities of A and B respectively.
Thus, 7/9 = (7x-(7/12)*9)/ (5x-(5/12)*9+9) ---> giving you x=3. Thus A (original) Q= 7*3 = 21.C
Question: In a school of 850 boys, 40% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
A.A)125
B.B)627
C.C)187
D.D)721
Answer: C.C)187
Explanation: 40 + 28 + 10 = 78%
100 – 78 = 22%
850 * 22/100 = 187
Answer:C
Question: If the area of circle is 440 sq cm then its circumference?
A.74.2
B.88
C.99
D.266
Answer: A.74.2
Explanation: 22/7 r2 = 440 => r = 11.8
2 * 22/7 * 11.8 = 74.2 Answer: A
Question: Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?
A.Rs.1261
B.Rs.9261
C.Rs.9621
D.Rs.9162
Answer: B.Rs.9261
Explanation: Explanation:
A = 8000(21/20)3 = 9261
ANSWER IS B
Question: If 'A' runs faster than ‘E’ but not as fast as 'D' and 'D' runs faster than 'C' but not as fast as' ‘B’, then the person who runs the fastest is
A.A
B.B
C.C
D.D
Answer: B.B
Explanation: B is the fastest
ANSWER:B
Question: A car started running at a speed of 30 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey.
A.890 km
B.390 km
C.890 km
D.990 km
Answer: B.390 km
Explanation: The total distance covered by the car in the first 10 hours
= 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44 + 46 + 48
= sum of 10 terms in AP whose first term is 30 and last term is 48
= 10/2 [30 + 48] = 390 km.
Answer:B
Question: Solve the quickfire maths brain teaser âˆš36% = ?
A.30%
B.40%
C.60%
D.19%
Answer: C.60%
Explanation: âˆš36%
=> âˆš36/âˆš100
=> 6/10
=> 60/100
=> 60%
C
Question: Find 4consecutive even integers so that the sum of the 1st two added to twice the sum of the last 2 is equal to 742.
A.340
B.540
C.742
D.780
Answer: C.742
Explanation: Let x, x + 2, x + 4 and x + 6 be the four integers. The sum of the first two
x + (x + 2)
twice the sum of the last two is written as
2 ((x + 4) + (x + 6)) = 4 x + 20
sum of the first two added to twice the sum of the last two is equal to 742 is written as
x + (x + 2) + 4 x + 20 = 742
Solve for x and find all four numbers
x = 120 , x + 2 = 122 , x + 4 = 124 , x + 6 = 126
As an exrcise, check that the sum of the first two added to twice the sum of the last two is equal to 742
C
Question: The ratio of two numbers is 2:3 and the sum of their cubes is 945. The difference of number is?
A.3
B.4
C.5
D.6
Answer: A.3
Explanation: 2x 3x
8x cube + 27x cube = 945
35x cube = 945
x cube = 27 => x = 3
Answer: A
Question: A certain number of workers can do a work in 25 days. If there were 10 workers more it could be finished in 10 days less. How many workers are there?
A.15
B.30
C.28
D.24
Answer: A.15
Explanation: number of workers = 10* (25-10)/10 = 15
Answer is A
Question: If an article is sold at 19% profit instead of 12% profit, then the profit would be Rs. 105 more. What is the cost price?
A.3388
B.2788
C.1500
D.2792
Answer: C.1500
Explanation: Let the cost price of an article be Rs. x.
(19% of x) - (12% of x) = 105
19x/100 - 12x/100 = 105 => 7x = 105 * 100
=> x = 1500
Cost price = Rs. 1500'
Answer:C
Question: A and B invests Rs.5000 and Rs.6000 in a business. After 6 months, A withdraws two-fifth of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?
A.3:5
B.7:8
C.5:6
D.3:4
Answer: D.3:4
Explanation: A : B
(5000*6)+(3000*6) : (6000*8)+(4000*4)
48000 : 64000
3 : 4
Answer: D
Question: A certain car uses 12 gallons of gasoline in traveling 300 miles. In order for the car to travel the same distance using 10 gallons of gasoline, by how many miles per gallon must the car’s gas mileage be increased?
A.2
B.4
C.5
D.8
Answer: C.5
Explanation: 300/10 = 30. The difference is 30 - 25 = 5.
Answer C
Question: Out of 10 persons working on a project, 4 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?
A.5/9
B.5/2
C.5/1
D.5/6
Answer: D.5/6
Explanation: Explanation:
P(at least one graduate) = 1 - P(no graduates) =
1 - â¶Câ‚ƒ/Â¹â°Câ‚ƒ = 1 - (6 * 5 * 4)/(10 * 9 * 8) = 5/6
Answer:D
Question: Which of the following is not a leap year?
A.1200
B.800
C.700
D.2000
Answer: C.700
Explanation: Explanation:
Remember the leap year rule (Given in the formulas)
1. Every year divisible by 4 is a leap year, if it is not a century.
2. Every 4th century is a leap year, but no other century is a leap year.
800,1200 and 2000 comes in the category of 4th century (such as 400,800,1200,1600,2000 etc).
Hence 800,1200 and 2000 are leap years
700 is not a 4th century, but it is a century. Hence it is not a leap year
Answer: Option C
Question: How many seconds does Sandy take to cover a distance of 500 meters, if Sandy runs at a speed of 15 km/hr?
A.100
B.120
C.140
D.160
Answer: B.120
Explanation: 15 km/hr = 15000 m / 3600 s = (150 / 36) m/s = (25 / 6) m/s
time = 500 / (25/6) = 120 seconds
The answer is B.
Question: There are deer and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there ?
A.22
B.38
C.32
D.60
Answer: D.60
Explanation: Let x and y be the number of deer and peacocks in the zoo respectively. Then,
x + y = 80 ...(i) and
4x + 2y = 200 or 2x + y = 100 ...(ii)
Solving (i) and (ii), we get) x = 20, y = 60.
Answer: D
Question: 1, ? , 9,7,7,9,1310,9,1,4,9,16,16,.... what comes in ?
A.3
B.4
C.5
D.6
Answer: B.4
Explanation: 1,4,9,7,7,9,13,10,9,1,4,9,16,16,....
ANSWER:B
Question: Rs.1170 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share?
A.Rs.720
B.Rs.920
C.Rs.537
D.Rs.540
Answer: D.Rs.540
Explanation: A+B+C = 1170
4A = 3B = 2C = x
A:B:C = 1/4:1/3:1/2 = 3:4:6
6/13 * 1170 = Rs.540
Answer:D
Question: A woman borrowed some amount, after 3 years he paid Rs.10,400/- with 10% interest, then how much Amount she borrowed?
A.Rs.7000/-
B.Rs.8000/-
C.Rs.8800/-
D.Rs.8900/-
Answer: B.Rs.8000/-
Explanation: principal P = ?
Rate of interest R = 10%
Time T = 3 years
Accumulated Amount A = Rs.10400/-
A = P + I
A = P + PTR/100
A = P(1+ TR/100)
Rs.10400/- = P [1 + 3*10/100]
Rs.10400/- = P [1/1 + 3/10]
Rs.10400/- = P [10+3/10] = P[13/10]
Rs.10400/- = P * 13/10
==> P = Rs.104000/13
==> P = Rs.8000/-
B
Question: Gasoline varies in cost from $0.97 to $1.17 per gallon. If a car’s mileage varies from 16 to 24 miles per gallon, what is the difference between the most and least that the gasoline for a 480-mile trip will cost?
A.$15.07
B.$15.23
C.$15.50
D.$15.70
Answer: D.$15.70
Explanation: Solution:
We know that the per gallon cost of gasoline varies from $0.97 - $1.17.
Now we want to find the MAXIMUM difference between the least amount of money spent on gasoline and the largest amount of money spent i.e. to calculate max. trip cost - min. trip cost.
Mileage is given to be 16 to 24 miles per gallon, thus to travel 480 miles you will need gasoline in the range 480/24 to 480/16 which is 20 to 30 gallons.
So, for these 20 gallons and 30 gallons of gasoline the cost is as follows: (divide this task into 2 parts, 1 for 30 gallons and 2nd one for 20 gallons).
Case 1: for 30 gallons the cost is 30*0.97 to 30*1.17 which is $29.10 to $35.10
Case 2: for 20 gallons the cost is 20*0.97 to 20*1.17 which is $19.40 to $23.40
Thus, the maximum cost of the 480 mile trip is $35.10 and minimum is $19.40
so the difference is $35.10 - $19.40 = $15.70
Answer: D
Question: There were two candidates in an election. Winner candidate received 62% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate?
A.456
B.744
C.912
D.1200
Answer: B.744
Explanation: W = 62% L = 38%
62% - 38% = 24%
24% -------- 288
62% -------- ? => 744
ANSWER:B
Question: . In digging a pond 20 m * 10 m * 5 m the volumes of the soil extracted will be?
A.3323
B.1000
C.2877
D.2992
Answer: B.1000
Explanation: 20 * 10 * 5 = 1000
Answer: B
Question: Find the distance covered by a man walking for 10min at a speed of 6km/hr?
A.1km
B.2km
C.3km
D.1.5km
Answer: A.1km
Explanation: Distance = 6*10/60 = 1km
Answer is A
Question: On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 320 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school?
A.600
B.640
C.500
D.520
Answer: B.640
Explanation: Let the number of children in the school be x. Since each child gets 2 bananas, total number of bananas = 2x.
2x/(x - 320) = 2 + 2(extra)
=> 2x - 640 = x => x = 640.
ANSWER:B
Question: Ramesh spends 40% of his monthly salary on food, 40% of the remaining on conveyance and clothes and saves 50% of the remaining amount. If his monthly salary is Rs.17,000, how much money does he save every month ?
A.3060
B.2787
C.2697
D.2671
Answer: A.3060
Explanation: Explanation:
Ramesh's monthly income = Rs.17,000
He spends 40% on food.
The total money spent on food = 40/100 * 17000 = Rs. 6800
Now, his monthly remaining income = Rs.17000 – Rs.6800 = Rs. 10200
Out of Rs. 10200, he spends 40% on conveyance and clothes.
The total money spent on conveyance and clothes = 40/100 * 10200 = Rs. 4080
Now, his monthly remaining income = Rs.10200 – Rs.4080 = Rs. 6120
Out of Rs. 6120, he saves 50%.
Amount saved = 50/100 * 6120 = Rs. 3060
ANSWER:A
Question: A set S = {x, -8, -5, -2, 2, 6, 9, y} with elements arranged in increasing order. If the median and the mean of the set are the same, what is the value of |x|-|y|?
A.1
B.0
C.2
D.-1
Answer: C.2
Explanation: Median of the set = (-2+2)/2 = 0
As per statement, Mean of the set = 0
Mean of the set
|y|- |x| +17-15 = 0 (where x is negative n y is positive)
|y|- |x| = -2
So the absolute difference between two numbers is 2
Answer C
Question: A thief steals at a car at 2.30 p.m. and drives it at 60 km/hr. The theft is discovered at 3 p.m. and the owner sets off in another car at 70 km/hr. When will he overtake the thief?
A.6:34 p.m
B.9:34 p.m
C.6:00 p.m
D.2:30 p.m
Answer: C.6:00 p.m
Explanation: :
Suppose the thief is overtaken x hrs after 2.30 p.m.
Then, distance covered by the owner in (x - 1/2) hrs.
60x = 70(x - 1/2) => x = 7/2 hrs.
So, the thief is overtaken at 5:34 p.m.'
Answer: C
Question: If two numbers x, a perfect square and y, a perfect cube are added results a two digit number, whose digits if reversed, difference is 36, Find x and y ?
A.x=4,y=8
B.x=9,y=64
C.x=4,y=7
D.x=4,y=9
Answer: B.x=9,y=64
Explanation: 9+64=73
when reversed 37
73-37=36
x=9,y=64
ANSWER:B
Question: If P(A) = 2/15, P(B) = 4/15, and P(A ∪ B) = 6/15 Find P(A|B)
A.1/2
B.2/3
C.3/2
D.4/5
Answer: C.3/2
Explanation: P(A|B) = P(A ∪ B)/P(B)
P(A|B) = (6/15)/(4/15) = 3/2.
C
Question: If 16% of 40% of a number is 8, then the number is
A.200
B.225
C.125
D.320
Answer: C.125
Explanation: Explanation:
Let 16/100×40/100×a=8
a = 8×100×100/16×40=125
Correct Option: C
Question: P and Q started a business investing Rs 60000 and Rs 15000 resp. In what ratio the profit earned after 2 years be divided between P and Q respectively.
A.7:5
B.17:3
C.4:1
D.17:7
Answer: C.4:1
Explanation: Explanation:
In this type of question as time frame for both investors is equal then just get the ratio of their investments.
P:Q = 60000:15000
= 60:15
= 4:1
Option C
Question: In a two-digit, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is?
A.24
B.26
C.28
D.30
Answer: A.24
Explanation: Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2.
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2)(2x + 2) = 144
22x2 + 26x - 140 = 0
11x2 + 13x - 70 = 0
(x - 2)(11x + 35) = 0
x = 2.
Hence, required number = 11x + 2 = 24.
Option A
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
A.778
B.280
C.288
D.111
Answer: B.280
Explanation: x*(85/100) = (480 - x)119/100
x = 280
Answer: B
Question: A shopkeeper buys mangoes at the rate of 8 a rupee and sells them at 3 a rupee. Find his net profit or loss percent?
A.33 4/3 %
B.33 1/7 %
C.62.5 %
D.32 1/3 %
Answer: C.62.5 %
Explanation: The total number of mangoes bought by the shopkeeper be 24.
If he buys 8 a rupee, his CP = 3
He selling at 3 a rupee, his SP = 8
Profit = SP - CP = 8 - 3 = 5
Profit Percent = 5/8 * 100 = 62.5 %
Answer:C
Question: A man bought pens at 3 for a dollar. How many for a dollar must he sell to gain 50%?
A.3
B.1
C.2
D.4
Answer: C.2
Explanation: C.P. of 3 pens = $1
S.P. of 3 pens = 150% of $1 = 3/2
for $3/2 pens sold = 3
for $1 pens sold = 3*2/3 = 2
Answer is C
Question: If the price of an item is decreased by 10% and then increased by 10%, the net effect on the price of the item is
A.A decrease of 99%
B.No change
C.A decrease of 1%
D.A increase of 1%
Answer: C.A decrease of 1%
Explanation: initially assume 100 rupees
10% discount in 100 gives price of 90 rupees
then 10% raise in 90 is only 9 rupees.
therefore total price =99 rupees.
hence 1% is the loss
ANSWER:C
Question: the reciprocal of the hcf and lcm of two are 1/17 and 1/312 .if one of the number is 24 then other no. is
A.126
B.136
C.146
D.221
Answer: D.221
Explanation: reciprocal of the hcf and lcm of two are 1/17 and 1/312
so, HCF = 17 , LCM = 312
LCM * HCF = product of two numbers = a*b => b = LCM * HCF / a
so, other = 17*312 / 24 = 221
ANSWER:D
Question: A departmental store bought some grapes at a rate of 5 for a dollar. They were separated into two stacks, one of which was sold at a rate of 3 for a dollar and the other at a rate of 6 for a dollar. What was the ratio of the number of grapes in the two stacks if the store broke even after having sold all of its grapes?
A.1:6
B.1:4
C.2:3
D.1:2
Answer: B.1:4
Explanation: To avoid fractions, assume there were 45 mangoes. So the store bought them for 45/5 = 9 dollars.
To break even, the selling price should be $9 too. 45 mangoes can be split into 1:4, 2:3 or 1:2. So let's try these.
45 split in the ratio 1:4 gives 9 and 36.
9 grapes split into 3 grapes each will give $3.
36 grapes split into 6 grapes each will give $6.
They add up to $9 so we have hit the right answer.
Answer (B)
Question: If the arithmetic mean of p and q is 10 and the arithmetic mean of q and r is 24, what is the value of r-p?
A.28
B.10
C.30
D.40
Answer: A.28
Explanation: Arithmetic mean expression for p and q:
(p+q)/2=10 ; p+q=20 ----eq1
Arithmetic mean expression for q and r:
(q+r)/2=20 ; q+r=48 ----eq2
Subtracting eq1 from eq2 we get: r-p=28
Hence, the correct answer is A
Question: Simplify: 702 x 698
A.489996
B.490000
C.492800
D.487200
Answer: A.489996
Explanation: 702 x 698 = (700 + 2)(700 - 2)
= 490000 + 1400 -1400 -4
=489996
Answer is A
Question: When two dice are rolled, what is the probability that the difference between the two numbers is 4?
A. 1/9
B. 2/9
C. 1/3
D. 2/3
Answer: A. 1/9
Explanation: We have 4 outcomes that satisfy the question:
1-5
2-6
5-1
6-2.
the probability is (1/6*1/6)*4= 1/9.
I think the answer is A
Question: If 8 workers can build 8 cars in 8 days, then how many days would it take 5 workers to build 5 cars?
A.4
B.5
C.8
D.10
Answer: C.8
Explanation: 8 workers can build 1 car per day on average.
1 worker can build 1/8 of a car per day.
5 workers can build 5/8 car per day.
The time required to build 5 cars is 5 / (5/8) = 8 days
The answer is C.
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
A.48
B.93
C.26
D.23
Answer: A.48
Explanation: Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 6/125 = 48 sec.
Answer:A
Question: A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
A.277
B.288
C.600
D.273
Answer: C.600
Explanation: D = 30 * 5 = 150
RS = 40 – 30 = 10
T = 150/10 = 15
D = 40 * 15 = 600 km
Answer: C
Question: A paint store mixes 3/4 pint of red paint and 2/3 pint of white paint to make a new paint color called Perfect Pink. How many pints of red paint would be needed to make 34 pints of Perfect Pink paint?
A.9
B.16
C.18
D.25 1/3
Answer: C.18
Explanation: 3/4 pint is required to make 3/4 + 2/3 = 17/12 pint of perfect pink
so 17/12 pint requires 3/4 pint of red..
1 pint will require 3/4 * 12/17=9/17..
34 pints will require 9/17 * 34= 18 points..
Second way..
get both red and white paints in same denominator...
3/4 + 2/3 = (9/12)+(8/12) pints..
from here we get the ratio of red:white = 9:8..
so in 34 pints red will be 9/(9+8) * 34 =18..
ANSWER:C
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
A.90, 40 kmph
B.80, 40 kmph
C.80, 70 kmph
D.80, 80 kmph
Answer: B.80, 40 kmph
Explanation: Speed downstream
= 60 + 20 = 80 kmph
Speed upstream
= 60 - 20 = 40 kmph
Answer:B
Question: A and B are two multiples of 14, and Q is the set of consecutive integers between A and B, inclusive. If Q contains 11 multiples of 14, how many multiples of 7 are there in Q?
A.19
B.20
C.21
D.22
Answer: C.21
Explanation: Halfway between the multiples of 14, there will be another multiple of 7.
The total number of multiples of 7 is 11+10 = 21.
The answer is C.