RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Four children have small toys. The first child has 1/10 of the toys, the second child has 12 more toys than the first, the third child has one more toy of what the first child has and the fourth child has double the third child. How many toys are there?
A.20 toys
B.30 toys
C.40 toys
D.60 toys
Answer: B.30 toys
Explanation: x : the total number of toys
x/10 : the number of toys for first child
x/10 + 12 : the number of toys for second child
x/10 + 1 : the number of toys for the third child
2(x/10 + 1) : the number of toys for the fourth child
x/10 + x/10 + 12 + x/10 + 1 + 2(x/10 + 1) = x
x = 30 toys : solve for x
correct answer B
Question: A, B and C work on a task. To complete the task alone, B takes twice the time that A would take to complete the task alone and 2/5rd the time that C would take to complete the task alone. If B actually worked for half the number of days that A worked and 3/2 times the number of days that C worked, what proportion of the total work was completed by B?
A.1/3
B.2/9
C.9/49
D.25/129
Answer: D.25/129
Explanation: The first thing to notice is that A is faster than B and B is faster than C.
Since work is proportional to time, in 1 day lets say if A does 2 works, B does 1 work and C does 2/3rd of a work.
If A works for 2 days, B works for 1 day and C works for only 2/3 of the day.
Therefore total work done = (2*2) + (1*1) + (2/5*2/5) = 129/25
Proportion of work done by B = (1*1) / (129/25) =25/129
Hence Answer D.
Question: A card player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many hearts as clubs and twice as many diamonds as hearts. How many spades does he hold?
A.6
B.5
C.8
D.2
Answer: A.6
Explanation: A
6
The player holds 1 club, 2 hearts and 4 diamonds.
As he holds 13 cards (or seven black cards), it follows that there must be 6 spades.
Question: Two numbers are such that the ratio between them is 3 : 5, but if each is increased by 10, the ratio between them becomes 5:7. The numbers are
A.3, 5
B.7, 9
C.13, 22
D.15, 25
Answer: D.15, 25
Explanation: No's are in the ratio 3:5
Le the No's be 3x and 5x
ATQ. (3x+10) : (5x+10) = 5:7
? x = 5
No's are (15,25)
Answer: D.
Question: If the average of 5 positive integers is 50 and the difference between the largest and the smallest of these 5 numbers is 10, what is the maximum value possible for the largest of these 5 integers?
A.50
B.58
C.49
D.48
Answer: B.58
Explanation: Sum of 5 Integer (a, b, c, d, e) = 5*50 = 250
e - a = 10
i.e. e = a+10
For e to be maximum remaining 4 MUST be as small as possible
Since smallest of 5 numbers is a so to minimize other numbers we can take them equal to the smallest of 5 numbers
i.e. a+a+a+a+(a+10) = 250
i.e. 5a = 240
i.e. a =48
i.e. Largest e = 48+10 = 58
Answer: option B
Question: A boy has nine trousers and 10 shirts. In how many different ways can he select a trouser and a shirt?
A.90
B.98
C.106
D.108
Answer: A.90
Explanation: Explanation:
The boy can select one trouser in nine ways.
The boy can select one shirt in 10 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 10 = 90 ways
A)
Question: Find the value for m?
19(m + n) + 17 = 19(-m + n) - 97
A.-3
B.-1
C.1
D.2
Answer: A.-3
Explanation: 19m + 19n + 17 = -19m + 19n - 97
38m= -114 => m = -3
A
Question: A can do a work in 24 days and B can do it in 16 days. In how many days A and B can do the work?
A.20 days
B.10 days
C.6 days
D.9 3/5 days
Answer: D.9 3/5 days
Explanation: Explanation:
A's 1day's work = 1/24
B's 1day's work = 1/16
They work together = 1/24 + 1/16 = 5/48 = 48/5 = 9 3/5days
Answer: Option D
Question: In how many different ways can the letters of the word 'TAKING' be arranged in such a way that the vowels always come together?
A.A)360
B.B)480
C.C)720
D.D)5040
Answer: A.A)360
Explanation: The word 'TAKING' has 6 different letters.
When the vowels AI are always together, they can be supposed to form one letter.
Then, we have to arrange the letters TKNG (AI).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be arranged among themselves in 2! = 2 ways.
Required number of ways = (120 x 2) = 360.
ANSWER:A
Question: A driver would have reduced the time it took to drive from home to the store by 1/3 if the average speed had been increased by 12 miles per hour. What was the actual average speed, in miles per hour, when the driver drove from home to the store?
A.16
B.20
C.24
D.28
Answer: C.24
Explanation: Since the distance remains the same (we're just changing the rate and time), any increase in rate or time is met with a decrease in the other term. Decreasing the time by 1/3 would give us:
D = (R)(T) = (2T/3)(x*R)
x = 3/2 since (2T/3)(3R/2) = (R)(T) = D
3R/2 = R + 12
R/2 = 12
R= 24
The answer is C.
Question: The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:
.
A.28
B.32
C.40
D.64
Answer: C.40
Explanation: Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Answer: Option C
Hence, required sum = (16 + 24) = 40.
Question: A dog takes 4 leaps for every 5 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is :
A.12:5
B.4:3
C.9:5
D.9:1
Answer: A.12:5
Explanation: Explanation:
Dog : Hare = (4*3) leaps of hare : 5 leaps of hare = 12 : 5.
Answer: A) 12:5
Question: A person travels from P to Q at a speed of 40 km/hr and returns by increasing his speed by 50%.
What is his average speed for both the trips ?
A.44 km/hour
B.46 km/hour
C.48 km/hour
D.50 km/hour
Answer: C.48 km/hour
Explanation: Explanation:
Speed while going = 40 km/hr
Speed while returning = 150% of 40 = 60 km/hr
Average speed =
2xyx+y=2
∗
40
∗
6040+60=4800100=48Km/hr
Answer: C
Question: The cab company gets a discount at the fuel center when they fill up more than 2 cars at a time. The service is $1.05 per vehicle and .30 cents per liter of fuel. On Saturday , they will fill 2 vans and 3 smaller cars. The cars are 28 liters each and the vans are 80% bigger. How much will it cost to fill up all vehicles if they are empty?
A.$68.00
B.$60.69
C.$71.27
D.$72.36
Answer: B.$60.69
Explanation: Lots of calculations.
1.05*5 + 3*28*.30+ 28*(9/5)*2*.30
Answer=$60.69
The correct option is B.
Question: Six mobsters have arrived at the theater for the premiere of the film “Goodbuddies.” One of the mobsters, Frankie, is an informer, and he's afraid that another member of his crew, Joey, is on to him. Frankie, wanting to keep Joey in his sights, insists upon standing behind Joey in line at the concession stand, though not necessarily right behind him. How many ways can the six arrange themselves in line such that Frankie’s requirement is satisfied?
A.6
B.24
C.120
D.360
Answer: D.360
Explanation: Total arrangement of 6 = 6!. In half of the cases Frankie will be behind Joey and in half of the cases Joey will be behind Frankie (as probability doesn't favor any of them). So, the needed arrangement is 6!/2=360.
Answer: D (360)
Question: A sun is divided among X, Y and Z in such a way that for each 2 rupees X gets, Y gets 80 paisa and Z gets 60 paisa. If the share of Y is RS. 40, what is the total amount?
A.160
B.155
C.150
D.170
Answer: D.170
Explanation: x:y:z = 200:80:60
10:4:3
4 --- 40
17 --- ? => 170
Answer: D
Question: In how many ways can live boys and three girls sit in a row such that all boys sit together?
A.4800
B.5760
C.2880
D.15000
Answer: C.2880
Explanation: Treat all boys as one unit. Now there are four students and they can be arranged in 4! ways. Again five boys can be arranged among themselves in 5! ways.
Required number of arrangements = 4! * 5! = 24 * 120 = 2880.
ANSWER:C
Question: Driver A passes a milestone at a constant speed of 50 miles per hour. Then, 15 minutes later, Driver B passes the same milestone at a constant speed of 60 miles per hour. If both drivers maintained their speeds and both remained on the highway for at least 2 hours, how long after Driver B passed the gas station did he catch up with Driver A?
A.30 min
B.45 min
C.1 hr 15 min
D.2 hrs
Answer: C.1 hr 15 min
Explanation: When Driver A is at the station, Driver B is 50/4 miles ahead on the highway. (the distance driven in 15 min)
every hour, Driver B drives 10miles more than Mary. how many hours will it takes him to drive 50/4 miles more? the answer is (50/4)/10 = 25/20=1h15min.
Answer C
Question: Private Benjamin is a member of a squad of 10 soldiers, which must volunteer 4 of its members for latrine duty. If the members of the latrine patrol are chosen randomly, what is the probability E that private Benjamin will be chosen for latrine duty?
A.1/10
B.1/5
C.2/5
D.3/5
Answer: C.2/5
Explanation: Easier way : Desired probability = 1- 'excluded' probability
In this case, Excluded probability = probability of Benjamin not being a part of the 4 volunteers. We can choose 4 out of 9 remaining soldiers in 9C4 ways. total ways possible = 10C4.
Thus excluded probability = 9C4/10C4 = 3/5
Thus, the desired probability E= 1- 3/5 = 2/5. Thus C is the correct answer.
Question: In an election, candidate Douglas won 60 percent of the total vote in Counties X and Y. He won 72 percent of the vote in County X. If the ratio of people who voted in County X to County Y is 2: 1, what percent of the vote did candidate Douglas win in County Y?
A.18%
B.30%
C.36%
D.48%
Answer: C.36%
Explanation: given voters in ratio 2:1
let X has 200 votersY has 100 voters
for X 72% voted means 72*200=144 votes
combined for XY has 300 voters and voted 60% so total votes =180
balance votes=180-144=36
As Y has 100 voters so 36 votes means 36% of votes required
Ans C
Question: The average of a couple was 20Yrs when they were married 8Yrs ago.The avg age of
the couple and a child, who was born during the interval, is 21Yrs now. How old is the
child now ?
A.2 Yrs
B.4 Yrs
C.3 Yrs
D.1 Yrs
Answer: A.2 Yrs
Explanation: (a+b-8-8)/2=21;
a+b=58;
a+b+c/3=20;
solving both c=2
ANSWER:A
Question: What is the largest sum of money-all in current coins and no silver dollars-that I could have in my pocket without being able to give change for a dollar, half dollar, quarter, dime, or nickel?
A.$2.28
B.$3.31
C.$1.19
D.$1.28
Answer: C.$1.19
Explanation: C
$1.19
The largest sum is $1.19, composed of a half dollar, quarter, four dimes, and four pennies.
Question: If a light flashes every 6 seconds, how many times will it flash in 1/5 of an hour?
A.81
B.101
C.121
D.141
Answer: C.121
Explanation: In 1/5 of an hour there are 12*60 = 720 seconds
The number of 6-second intervals = 720/6 = 120
After the first flash, there will be 120 more flashes for a total of 121.
The answer is C.
Question: The average age of father and his two sons is 32 Years. Five years ago, the average age of the two sons was 14 Years. If the difference between the ages of the two sons is four years, what is the present age of the father?
A.45
B.46
C.47
D.60
Answer: D.60
Explanation: The total present age of father and two sons is 3x32 = 96 yrs
The total present age of sons is (12+5) X 2 = 38Years
so, present age of father is 96 â€“ 36 = 60 yrs
Answer D
Question: (2^2+4^2+6^2+.....+10^2)=?
A.220
B.440
C.660
D.880
Answer: A.220
Explanation: =(1x2)^2+(2x2)^2,+(2x3)^3+......(2x5)^2
=2^2 x (1^2+2^2+3^2+.......+5^2)
formula is =1/6 n(n+1)(2n+1)
=(4x1/6x5x6x11)
=(4x55)=220
Answer is A
Question: 50% of all students in a class commute by public transportation. If 20% of the students aspire to be scientists, which of the following can be the percentage of students who do not commute by public transportation and do not aspire to be scientists?
I.	15%
II.	40%
III.	70%
A.I ONLY
B.II ONLY
C.III ONLY
D.I AND II
Answer: B.II ONLY
Explanation: 50% Students use public transportation. This means 50% students do not use public transportation. 20% students aspire to be scientists means even if all these students use public transportation, minimum 50% - 20% = 30% students do not use public transportation and do not aspire to be scientists.This means correct answer is between 30% and 50%
Answer : B.
Question: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
A.35
B.36
C.37
D.40
Answer: D.40
Explanation: According to given condition
vt=(v+3)(t-2/3)
vt=(v-2)(t+2/3)
here v is velocity in kmph, t is time in hours and 2/3 is value of 40 min in hour
on solving we will get t=10/3 and and v = 12 so distance = (10/3) * 12 = 40 kms
ANSWER:D
Question: Each student is given a four-character identification code. The first three characters are selected from the numbers 0 to 9 inclusive, and the last character is selected from the 26 letters of the alphabet. If characters may be repeated and the same characters used in a different order constitute a different code, how many different identification codes can be generated following these rules?
A.25,700
B.26,000
C.26,300
D.26,600
Answer: B.26,000
Explanation: The number of possible codes is 10*10*10*26=26,000.
The answer is B.
Question: If the function Q is defined by the formula Q = 5w/(4h(z^2)), by what factor will Q be multiplied if w is quadrupled, h is doubled, and z is tripled?
A.1/9
B.2/9
C.4/9
D.3/9
Answer: B.2/9
Explanation: We just need to find the factor thats all,
w -> quadrupled -> 4w
h-> doubled -> 2h
z-> tripled -> 3Z
Hence, Z^2 = 9Z^2
W is in numerator, and h*z in denominator.
Hence,
Additional factor being introduced = 4/2*9
=4/18 = 2/9 = B
Question: The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
A.27 m
B.24 m
C.18 m
D.21 m
Answer: C.18 m
Explanation: Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l2 = 324 => l = 18.
ANSWER:C
Question: The cricket team of 11members is 24yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ?
A.21
B.22
C.23
D.25
Answer: A.21
Explanation: Let the average age of the whole team be x years.
11x - (24 + 27) = 9 (x - 1)
=> 11x - 9x = 42
=> 2x = 42
=> x = 21.
So, average age of the team is 21 years.
A
Question: The measurements obtained for the interior dimensions of a rectangular box are 150 cm by 150 cm by 225cm. If each of the three measurements has an error of at most 1 centimeter, which of the following is the closes maximum possible difference, in cubic centimeters, between the actual capacity of the box and the capacity computed using these measurements?
A.90,000
B.95,000
C.93,000
D.92,000
Answer: A.90,000
Explanation: The options are well spread so we can approximate.
Changing the length by 1 cm results in change of the volume by 1*150*225 = 33,750 cubic centimeters;
Changing the width by 1 cm results in change of the volume by 150*1*225 = 33,750 cubic centimeters;
Changing the height by 1 cm results in change of the volume by 150*150*1 = 22,500 cubic centimeters.
So, approximate maximum possible difference is 33,750 + 33,750 + 22,500 = 90,000 cubic centimeters.
Answer: A
Question: Three friends had dinner at a restaurant. When the bill was received, Akshitha paid 2/3 as much as Veena paid and Veena paid 1/2 as much as Lasya paid. What fraction of the bill did Veena pay ?
A.3/19
B.3/12
C.3/11
D.3/10
Answer: C.3/11
Explanation: Let Veena paid x,
so Akshitha paid 2x/3 , and Lasya paid 2x,
So total bill paid is given by
x+(2x/3) +2x = 1, we get
i.e. x = 3/11
Answer: C
Question: Two assembly line inspectors, Lauren and Steven, inspect widgets as they come off the assembly line. If Lauren inspects every fifth widget, starting with the fifth, and Steven inspects every fourth, starting with the fourth, how many of the 98 widgets produced in the first hour of operation are not inspected by either inspector?
A.66
B.68
C.70
D.64
Answer: D.64
Explanation: Widgets inspected by Lauren: ((95-5)/5)+1=18+1=19
Widgets inspected by Steven: ((96-4)/4)+1 =23+1 =24
Widgets inspected by both: ((96/12)+1 =9
Total : 19+24 -9=34
hence, widgets not inspected: 98-34=64
Option D
Question: Machine P and Machine Q are each used to manufacture 880 sprockets. It takes Machine P 10 hours longer to produce 880 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce?
A.2
B.4
C.6
D.8
Answer: D.8
Explanation: P makes x sprockets per hour.
Then Q makes 1.1x sprockets per hour.
880/x = 880/1.1x + 10
1.1(880) = 880 + 11x
11x = 88
x = 8
The answer is D.
Question: In a game of billiards, A can give B 30 points in 50 and he can give C 40 points in 50. How many points can B give C in a game of 100?
A.18
B.27
C.50
D.21
Answer: C.50
Explanation: A scores 50 while B score 20 and C scores 10.
The number of points that C scores when B scores 100 = (100 * 10)/20 = 50.
In a game of 100 points, B gives (100 - 50) = 50 points to C.
Answer: C
Question: Four brothers Adam, Bill, Charles and David together contributed certain amount of money and purchased a car. The contribution made by Adam is half that of the total contribution made by the other three brothers, contribution made by Bill is one-fourth of the total contribution made by the other three brothers and the contribution made by Charles is two-third of the total contribution made by the other three brothers. If the total price of the car is $9450, find the contribution made by David.
A.$540
B.$580
C.$600
D.$630
Answer: D.$630
Explanation: Given that A:(B+C+D)= 1:2.
Hence A contributed 1/3rd of the total price.
Given B:(A+C+D)=1:4
Hence B contributed 1/5th of the total price.
Given C:(A+B+D)=2:3
Hence C contributed 2/5th of the total price.
Thus the contribution made by A,B and C= 1/3+1/5+2/5=14/15
So, the remaining 1/15th of the price is contributed by David.
Hence David's contribution= 1/15×9450=$630.
The answer is D.
Question: If a new town has 250 residents, and the population doubles every 10 years, what will be its population after 75 years?
A.6034 residents
B.9051 residents
C.45255 residents
D.15075 residents
Answer: C.45255 residents
Explanation: 250*2^(75/10)=250*2^7.5=100*181.02=45255
The answer is C.
Question: The cost price of a radio is Rs.1500 and it was sold for Rs.1260, find the loss %?
A.18
B.16
C.26
D.17
Answer: B.16
Explanation: Explanation:
1500 ---- 240
100 ---- ? => 16%
Answer:B
Question: The odds in favour of an event A are 3:4.The odds against anotehr independent event B are 7:4. What is the probability that at least one of the events will happen ?
A.1/11
B.7/11
C.6/11
D.8/11
Answer: B.7/11
Explanation: Explanation :
The odds in favour of an event A are 3:4.
=> Probability of A = P(A) = 3/(3+4) = 3/7.
The odds against an event B are 7 : 4.
=> Probability of B = P(B) = 4/(7+4) = 4/11.
The probability of occurrence of at least one of the events A and B,
P(A+B) = P(A) + P(B) - P(AB).
=>P(A+B) = P(A) + P(B) - P(A) x P(B).
=> (3/7) + (4/11) - (3/7)(4/11).
=> 7/11.
Hence, the required probability is 7/11.
Answer : B
Question: A car after covering Â½ of a journey of 100 km develops engine trouble and later travels at Â½ of its original speed. As a result, it arrives 2 hours late than its normal time. What is the normal speed of the car is?
A.50 kmph
B.40 kmph
C.30 kmph
D.25 kmph
Answer: D.25 kmph
Explanation: Explanation:
[50/x + 50/(x/2)] â€“ 100/x = 2
x = 25
ANSWER IS D
Question: Each of the integers from 1 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 10?
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: Answer is 6. In the worst case, you could end up drawing 1,2,3,4,5. 7th draw will result in either of 6,7,8,9 which would result in the numbers adding to 10.
D
Question: A watch which gains 5 seconds in 3 minutes was set right at 7 a.m. In the afternoon of the same day, when the watch indicated quarter past 4 o'clock, the true time is:
A.3 p.m.
B.6 p.m.
C.7 p.m.
D.4 p.m.
Answer: D.4 p.m.
Explanation: Time from 7 a.m. to 4.15 p.m. = 9 hrs 15 min. =	37/4 hrs.
3 min. 5 sec. of this clock = 3 min. of the correct clock.
37/720 hrs of this clock =	1/20	hrs of the correct clock.
37/4	hrs of this clock = 1/20 x 720/37 x 37/4 hrs of the correct clock.
= 9 hrs of the correct clock.
The correct time is 9 hrs after 7 a.m. i.e., 4 p.m.
Answer D
Question: The mean of 1^2,2^2,3^2,4^2,5^2,6^2,7^2 is?
A.15
B.18
C.20
D.25
Answer: C.20
Explanation: 1^2+2^2+3^2+-----+n^2 = n(n+1)(2n+1)/6
1^2+2^2+3^2+-----+7^2 = 7*8*156 = 140
Required average is = 140/7 = 20
Answer is C
Question: The difference in compound interest earned on a deposit (compounded annually) in year 1 and year 2 is $ 40. Had the interest rate been three times its present value, the difference c would have been how much?
A.40/3
B.40
C.120
D.360
Answer: D.360
Explanation: CASE 1:
Deposit = $x;
Rate of increase = r.
Interest yearned in 1 year = xr. Deposit in 1 year = x + xr.
Interest yearned in 2 year = (x + xr)r.
The difference c = (x + xr)r - xr = xr^2 = 40.
CASE 2:
Deposit = $x;
Rate of increase = 3r.
Interest yearned in 1 year = x(3r). Deposit in 1 year = x + 3xr.
Interest yearned in 2 year = (x + 3xr)3r.
The difference = (x + 3xr)3r - 3xr = 9xr^2. Since from CASE 1 we know that xr^2 = 40, then 9xr^2 = 9*40 = 360.
Answer: D.
Question: A standard Veggiematik machine can chop 32 carrots in 4 minutes. How many carrots can 6 standard Veggiematik machines chop in 6 minutes?
A.36
B.54
C.288
D.108
Answer: C.288
Explanation: Direct Relationship:-
1 standard Veggiematik machine - 32 Carrots - 4 minutes,
1 standard Veggiematik machine - 8 Carrots - 1 minute,
Now
6 standard Veggiematik machine - ? Carrots - 6 minutes,
Hence = 8X6X6 =288 Carrots
Answer C
Question: What is the area of the square with the following coordinates: (x, y), (20, 20), (20, 11), (x, 11)?
A.49
B.64
C.75
D.81
Answer: D.81
Explanation: To find the area of a square, knowing the length of one side is sufficient.
From the coordinates given, we can see that one side equals 9.
The area is 9*9 = 81.
The answer is D.
Question: If,
1 * 3 * 5 = 16
3 * 5 * 7 = 38
Then find,
5 * 7 * 9 =?
A.89
B.49
C.68
D.38
Answer: C.68
Explanation: C
68
(9 * 7) + 5 = 68
Question: The ratio of the present ages of a man and his wife is 8 : 7. Which of the following can't be a possible ratio of their ages 45 years ago?
A.6: 8
B.7: 8
C.8:8
D.9: 8
Answer: D.9: 8
Explanation: 8x-45/7x-45 = 9/8
Therefore x=-45
Age cannot be negative.
Answer: D
Question: A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 180 m in 18 sec. then find the length of the train?
A.189m
B.180m
C.100m
D.480m
Answer: B.180m
Explanation: Length of the train be ‘X’
X + 120/15 = X + 180/18
6X + 720 = 5X + 900
X = 180m .Answer: B
Question: The average age 9 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
A.18
B.99
C.77
D.26
Answer: A.18
Explanation: 9 * 2 = 18 years
Answer: A
Question: In how many ways can three boys can be seated on five chairs?
A.10
B.20
C.60
D.40
Answer: C.60
Explanation: There are three boys.
The first boy can sit in any of the five chairs (5 ways).
5
Now there are 4 chairs remaining. The second boy can sit in any of the four chairs (4 ways).
5	4
Now there are 3 chairs remaining. The third boy can sit in any of the three chairs (3 ways).
5	4	3
Hence, total number of ways in which 3 boys can be seated on 5 chairs
=5×4×3=60
Ans: C