RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A , B , and C started a partnership business by investing $27,000 , $72,000 , and $81,000 respectively. At the end of the year , the profit was distributed among them. If C's share of profit is $18,000, what is the total profit?
A.$24,000
B.$32,000
C.$40,000
D.$48,000
Answer: C.$40,000
Explanation: A:B:C = 27000:72000:81000 which is a ratio of 3:8:9.
Let the total profit be x.
x * 9/20 = 18000
x = 18000*20/9 = 40,000.
The answer is C.
Question: An article is bought for Rs.605 and sold for Rs.900, find the gain percent?
A.30 1/3%
B.33 1/3%
C.48 92/121%
D.35 1/3%
Answer: C.48 92/121%
Explanation: C
48 92/121%
605 ---- 295
100 ---- ? => 48 92/121%
Question: A box has exactly 100 balls, and each ball is either red, blue, or white. If the box has 10 more blue balls than white balls, and thrice as many red balls as blue balls, how many white balls does The box has ?
A.8
B.10
C.12
D.14
Answer: C.12
Explanation: x = the number of red balls
y = the number of blue balls
z = the number of white balls
From the first sentence we have
Equation #1: x + y + z = 100
...the box has 10 more blue balls than white balls...
Equation #2: y = 10 + z
...thrice as many red balls as blue balls...
Equation #3: x = 3y
Solve equation #2 for z: z = y - 10
Now, we can replace both x and z with y in Equation #1
3y + y + (y - 10) = 100
5y - 10 = 100
5y = 110
y = 22
There are 22 blue balls. This is 10 more than the number of white balls, so z = 12. That's the answer. Just as a check, x = 66, and 66 + 22 + 12 = 100.
Answer = 12,(C)
Question: which of the following is correct formula for divisor rule ?
A.dividend = divisor * quotient + remainder
B.quotient = divisor * dividend + remainder
C.dividend = divisor * quotient - remainder
D.dividend = divisor * remainder + quotient
Answer: A.dividend = divisor * quotient + remainder
Explanation: option A is correct
Question: The number of people at Ovations Bar in the hour from 12 p.m. to 1 p.m. was 20% greater than the number of people there from 11 a.m. to 12 p.m. The number of the people at the bar from 11 a.m. to 12 p.m. was 10% more than the number there from 10 a.m. to 11 a.m. If 242 people were at the bar from 11 a.m. to 1 p.m., which of the following is the number of people in the bar from 10 a.m. to 11 a.m.?
A.100
B.20
C.30
D.40
Answer: A.100
Explanation: No of people from 10 - 11 is x
No of people from 11 - 12 is 11x/10
No of people from 12 to 1 is (6/5)(11x/10)
Given that 11x/10 + (6/5)(11x/10) = 121x / 50 = 242
Then x = 100
A
Question: A train running at the speed of 60 km/hr crosses a pole in 12 sec. What is the length of the train?
A.120 m
B.180 m
C.200 m
D.Cannot be determined
Answer: C.200 m
Explanation: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 12 = 200 m
ANSWER:C
Question: An inspector rejects 0.0008% of the meters as defective. How many will be examine to project ?
A.2000
B.2300
C.2700
D.250000
Answer: D.250000
Explanation: Let the number of meters to be examined be x.
Then, 0.0008% of x =2
[(8/10000)*(1/100)*x] = 2
x = [(2*100*10000)/8] = 250000
Answer is D.
Question: If 4 men can color 48 m long cloth in 2 days, then 6 men can color 36 m long cloth in?
A.1 day
B.2 days
C.3 days
D.4 days
Answer: A.1 day
Explanation: The length of cloth painted by one man in one day = 48 / 4 × 2 = 6 m
No. of days required to paint 36 m cloth by 6 men = 36/ 6 × 6 = 1 day
A)
Question: The greatest common factor of two positive integers is L. The least common multiple of these two integers is Y. If one of the integers is Z, what is the other?
A.LY⁄Z
B.XZ + YZ
C.X⁄Z + Y
D.X + Y⁄Z
Answer: A.LY⁄Z
Explanation: Say other integer is W
Formula
GCF(WZ)*LCM(WZ) = W*Z
L*Y = W*Z
So W= LY/Z
Answer A
Question: The slant height of a cone is 10 cm and radius of the base is 5 cm, find the curved surface of the cone.
A.250
B.170
C.148
D.157
Answer: D.157
Explanation: π * 5* 10=157
Answer:D
Question: if the ratio of two number is 2:3 and LCM of the number is 120 then what is the number.
A.15
B.20
C.25
D.30
Answer: B.20
Explanation: product of two no = lcm *hcf
2x*3x=120*x
x=20
ANSWER:B
Question: A car travels at a speed of 65 miles per hour. How far will it travel in 5 hours?
A.255 miles
B.325 miles
C.645 miles
D.121 miles
Answer: B.325 miles
Explanation: During each hour, the car travels 65 miles. For 5 hours it will travel
65 + 65 + 65 + 65 + 65 = 5 * 65 = 325 miles
correct answer B
Question: Of the 75 house in a development, 50 have a two-car garage, 40 have an in-the-ground swimming pool, and 35 have both a two-car garage and an in-the-ground swimming pool. How many houses in the development have neither a two-car garage nor an in-the-ground swimming pool?
A.10
B.15
C.20
D.25
Answer: C.20
Explanation: Neither Car nor Garage
= Total - Garage - (Swim - Common)
= 75 - 50 - (40-35) = 75-55 = 20
Answer C
Question: The average of 40 results is 30 and the average of other 30 results is 40 . what is the average of all the results?
A.34
B.25
C.48
D.50
Answer: A.34
Explanation: Answer
Sum of 70 result = sum of 40 result + sum of 30 result.
= 40 x 30 + 30 x 40
= 2400/70
Correct Option: A
Question: The price of a book is increased from $300 to $450. What is the % of increase in its price?
A.10%
B.20%
C.40%
D.50%
Answer: D.50%
Explanation: Explanation: Change in the price = Rs 450 â€“ Rs 300
= Rs 150
Percentage of increase = Change in the price Initial Price
* 100.
Percentage increase in price =( 150 300
) *100 = 50%
D
Question: From a salary of an officer, 10% is deducted as house rent, 15% of the rest he spend on children's education and 10% of the balance he spends on clothes. Then, he is left with Rs. 4131. Find his total salary?
A.6000
B.3788
C.9009
D.6788
Answer: A.6000
Explanation: Suppose his total salary be Rs.x, then
90% of 85% of 90% of x = 4131
\inline \Rightarrow \frac{90}{100}\times \frac{85}{100}\times \frac{90}{100}\times x=4131
\inline \therefore x=\frac{4131\times 100\times 100\times 100}{90\times 85\times 90}=6000
Hence , the salary of the officer is Rs.6000
Answer:A
Question: What is the largest integral value of 'k' for which the quadratic equation x2 - 6x + k = 0 will have two real and distinct roots?
A.9
B.7
C.3
D.8
Answer: D.8
Explanation: Explanatory Answer
Any quadratic equation will have real and distinct roots if the discriminant D > 0
The discriminant 'D' of a quadratic equation ax2 + bx + c = 0 is given by b2 - 4ac
In this question, the value of D = 62 - 4 * 1 * k
If D > 0, then 36 > 4k or k < 9.
Therefore, the highest integral value that k can take is 8.
correct choice is (D)
Question: The factorial expression 12!/6! is not divisible by which of the following integers?
A.3
B.5
C.13
D.10
Answer: C.13
Explanation: 12!/6! => 12 x 11 x 10 x 9 x 8 x 7
(A) 3 Can divide 12 or 9
(B) 5 Can divide 10
(C) 13 None of the Multiplicands present
(D) 10 Can divide 10
(E) 9 Can divide 9
Hence answer will be (C)
Question: An amount of Rs.1560 was divided among A, B and C, in the ratio 1/2 : 1/3 : 1/4. Find the share of C?
A.272
B.276
C.360
D.277
Answer: D.277
Explanation: Let the shares of A, B and C be a, b and c respectively.
a : b : c = 1/2 : 1/3 : 1/4
Let us express each term with a common denominator which is the last number divisible by the denominators of each term i.e., 12.
a : b : c = 6/12 : 4/12 : 3/12 = 6 : 4 : 3.
Share of C = 3/13 * 1560 = Rs. 360.
Answer: D
Question: Find the odd man out
125, 106, 88, 76, 65, 58, 53
A.125
B.106
C.88
D.76
Answer: C.88
Explanation: Add series of prime numbers starting from 5 to get the next number
53+5 =58
58+7= 65
65+11=76
76+13 =89
89+17=106
106+19 = 125
ANSWER:C
Question: How many integerskgreater than 100 and less than 700 are there such that if the hundreds and the units digits ofkare reversed, the resulting integer is k+99?
A.50
B.60
C.70
D.80
Answer: A.50
Explanation: Numbers will be like 102 => 201 = 102 + 99
203 => 302 = 103 + 99
so the hundereth digit and units digit are consecutive where unit digit is bigger than hundred digit.
There will be five pairs of such numbers
for every pair there will 10 numbers like for 12 => 102, 112,132,142,152, 162,172,182,192.
Total = 5 *10 = 50 hence A.
Question: If a and b are both prime numbers greater than 12, which of the following CANNOT be true?
I. ab is an even number.
II. The difference between a and b equals 117.
III. The sum of a and b is even.
A. I only
B. I and III only
C. I and II only
D. II and III only
Answer: C. I and II only
Explanation: MANHATTAN GMATOFFICIAL SOLUTION:
Since a and b are both prime numbers greater than 10, they must both be odd. Therefore ab must be an odd number, so Statement I cannot be true. Similarly, if a and b are both odd, then a - b cannot equal 117 (an odd number). This difference must be even. Therefore, Statement II cannot be true. Finally, since a and b are both odd, a + b must be even, so Statement III will always be true. Since Statements I and II CANNOT be true, but Statement III IS true,the correct answer is (C).
Answer : C
Question: A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
A.287 m
B.178 m
C.500 m
D.177 m
Answer: C.500 m
Explanation: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60 = 65/3
x = 500 m.
Answer: C
Question: The tax on a commodity is diminished by 40% but its consumption is increased by 25%. Find the decrease percent in the revenue derived from it?
A.18%
B.72%
C.25%
D.12%
Answer: C.25%
Explanation: 100 * 100 = 10000
60 * 125 = 7500
10000------- 2500
100 ------- ? =25%
Answer:C
Question: The price of commodity P increases by 40 paise every year, while the price of commodity Q increases by 15 paise every year. If in 2001, the price of commodity P was Rs. 4.20 and that of Q was Rs. 6.30, in which year commodity P will cost 40 paise more than the commodity Q ?
A.2008
B.2009
C.2010
D.2011
Answer: D.2011
Explanation: Let the commodity P costs 40 paise more than the commodity Q after n years.
Price of the commodity P in 2001 = Rs.4.20
Since the price of the commodity P increases by Rs 0.40 every year,
Price of the commodity P after n years from 2001 = Rs.4.20 + (n × .40)
Price of the commodity Q in 2001 = Rs.6.30
Since the price of the commodity Q increases by Rs 0.15 every year,
price of the commodity Q after n years from 2001 = Rs.6.30 + (n × .15)
Since the commodity P costs Rs. 0.40 more that the commodity Q after n years from 2001,
4.20 + (n × .40) = 6.30 + (n × .15) + 0.40
=> (40n - .15n) = 6.30 - 4.20 + 0.40 = 2.5
=> .25n = 2.5
=> n =2.5/.25
=10
=> Commodity P costs Rs.0.40 more that the commodity Q after 10 years from 2001.
i.e., in 2011
ANSWER:D
Question: If x/2 = y/5 = z/6, then (x + y + z)/x is equal to :
A.13
B.12
C.15/2
D.13/2
Answer: D.13/2
Explanation: Explanation :
Solution: Let x/2 = y/5 = z/6 = k => x =2k, y =5k, z = 6k.
.'. (x + y + z)/x = (2k + 5k + 6k)/2k
=> 13k/2k = 13/2
Answer : D
Question: In an examination, the percentage of students qualified to the number of students appeared from school A is 70%. In school B, the number of students appeared is 20% more than the students appeared from school A and the number of students qualified from school B is 50% more than the students qualified from school A. What is the percentage of students qualified to the number of students appeared from school B?
A.30%
B.70%
C.80%
D.87.5%
Answer: D.87.5%
Explanation: Solution
Let number of students appeared from school A = 100.
Then, number of students qualified from school A = 70.
Number of students appeared from school B = 120.
Number of students qualified from school B = [150 / 100 x 70] = 105.
Required percentage = [105/ 120 x 100]%
= 87.5%
Answer D
Question: Two goods trains each 75 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
A.2.3 sec
B.4.2 sec
C.48 sec
D.7.2 sec
Answer: D.7.2 sec
Explanation: Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 75 + 75 = 150 m.
Required time = 150 * 6/125 = 7.2 sec.
Answer:D
Question: The average weight of a group of boys is 30 kg. After a boy of weight 36 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
A.4
B.8
C.5
D.2
Answer: C.5
Explanation: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 36 kg joins the group, total weight of boys = 30x + 36
So 30x + 36 = 31(x + 1) = > x = 5
Answer: C
Question: Heinz produces tomato puree by boiling tomato juice. The tomato puree has only 20% water while the tomato juice has 90% water. How many liters of tomato puree will be obtained from 20 litres of tomato juice?
A.2.8 liters.
B.2.5 liters.
C.8.5 liters.
D.2.6 liters.
Answer: B.2.5 liters.
Explanation: Answer:
Explanation:
In each of the solutions, there is a pure tomato component and some water. So while boiling, water evaporates but tomato not. So we equate tomato part in the both equations.
⇒⇒ 10%(20) = 80%(x)
⇒⇒ x = 2.5 liters.
Answer:B
Question: A boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream, it takes 4 hours. What is the speed of the boat in still water?
A.4 km/hr
B.5 km/hr
C.6 km/hr
D.3 km/hr
Answer: C.6 km/hr
Explanation: Rate downstream = 16/2 kmph = 8 kmph.
Rate upstream = 16/4 kmph = 4 kmph.
Speed in still water =	1/2 (8 + 4) kmph = 6 kmph.
Answer : Option C
Question: Goldenrod and No Hope are in a horse race with 8 contestants. How many different arrangements of finishes are there if No Hope always finishes before Goldenrod and if all of the horses finish the race?
A.40320
B.20160
C.12000
D.2400
Answer: B.20160
Explanation: All 8 horses can finish the race in 8! way (assuming no tie).
If no tie is possible between No Hope and Goldenrod, then in half of these cases No Hope will be before Goldenrod and in half of these cases after (not necessarily right before or right after). How else? So, there are 8!/2=20160 different arrangements of finishes where No Hope always finishes before Goldenrod.
Answer: B.
Question: A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
A.1:2
B.1:5
C.1:3
D.1:1
Answer: A.1:2
Explanation: T = 192/32 = 6 h
T = 6 - 3 = 3
Time Ratio = 6:3 = 2:1
Speed Ratio = 1:2
Answer:A
Question: A person is traveling at 40km/hr and reached his destiny in 5hr find the distance?
A.A)200km
B.B)95km
C.C)135km
D.D)80km
Answer: A.A)200km
Explanation: speed = 40km/hr
time = 5hr
distance = 40*5 = 200km
Answer is A
Question: If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 30% of m is equal to what percent of 200% of j ?
A.0.35
B.3.5
C.525
D.350
Answer: C.525
Explanation: IMO answer should be 350...
consider j=10, then k=50, l=150 and m=350....
30% of 350, comes out to be 105....
200% of 10 is 20....
(105*100)/20=525....
Ans : C
Question: A salesman sells two kinds of trousers: cotton and woollen. A pair of cotton trousers is sold at 30 profit and a pair of woollen trousers is sold at 50 profit. The salesman has calculated that if he sells 100 more woollen trousers than cotton trousers, his overall profit will be 45. However he ends up selling 50 more cotton trousers than woollen trousers. What will be his overall profit?
A.37.5%
B.40%
C.41%
D.32.33%
Answer: B.40%
Explanation: Explanation :
Let the cost price of 1 cotton trouser and 1 woollen trouser be ‘C’ and ‘W’ respectively.
Case I: Number of woollen trousers sold is 100% more than cotton trousers.
1.3C+1.5×2×W=1.45(C+2W).
=>0.15C=0.1W.
=>3C=2W.
Case II: Number of cotton trousers sold is 50% more than woollen trousers.
S.P=1.3C + 1.5 x (2W/3).
=>S.P=1.3C+W=2.8C.
And, C.P.=C+(2W/3)=2C.
Profit :-
=>(2.8C-2C)X100/2C.
=>40%.
Answer : B
Question: Sixty men can stitch 200 shirts in 30 days working 8 hours a day. In how many days can 45 men stitch 300 shirts working 6 hours a day?
A.70
B.90
C.60
D.80
Answer: D.80
Explanation: D
80
We have M1 D1 H1 / W1 = M2 D2 H2 / W2 (Variation rule)
(60 * 30 * 8)/ 200 = (45 * D2 * 6) / 300
D2 = (60 * 30 * 8 * 300) / (200 * 45 * 6) => D2 = 80.
Question: In a certain code 'BEAMING' is written as 'BFCMHOJ' and 'CLEAR' is written as 'MDESB' How is 'TRAIL' written in that code?
A.ASKDJS
B.JKHHGJ
C.HJGGK
D.GKJJGG
Answer: C.HJGGK
Explanation: Answer: Option C
Question: In a friendship gang Andrew has 8 gang, in how many ways can he invite one or more of the gang to his house?
A.120
B.255
C.265
D.270
Answer: B.255
Explanation: Andrew can select one or more than one of his 8 gang.
=> Required number of ways = 28 – 1= 255.
B
Question: The height of two right circular cones are in the ratio 1:2 and their perimeters of their bases are in the ratio 3:4, the ratio of their volume is?
A.9:38
B.9:31
C.9:32
D.9:39
Answer: C.9:32
Explanation: 9:32
Answer:C
Question: For an agricultural experiment, 300 seeds were planted in one plot and 200 were planted in a second plot. If exactly 25 percent of the seeds in the first plot germinated and exactly 30 percent of the seeds in the second plot germinated, what percent of the total number of seeds germinated?
A.27%
B.26%
C.29%
D.30%
Answer: A.27%
Explanation: In the first plot 25% of 300 seeds germinated, so 0.25 x 300 = 75 seeds germinated.
In the second plot, 30% of 200 seeds germinated, so 0.30 x 200 = 60 seeds germinated.
Since 75 + 60 = 135 seeds germinated out of a total of 300 + 200 = 500 seeds, the percent of seeds that germinated is (135/500) x 100%, or 27%.
Answer: A.
Question: If -3 < x < 0, which of the following must be true?
I. x^5 < x^2
II. x^5 < 5 – x^2
III. x^4 < x
A.I only
B.I and II only
C.I and III only
D.II and III only
Answer: B.I and II only
Explanation: I. x^5 < x^2 --> from -3 < x < 0 it follows that LHS<0<RHS, so this statement is true.
II. x^5 < 1 – x --> x^2(x^3+1) < 5 --> positive*negative < 0 < 1, so this statement is also true.
III. x^4 < x --> since -3 < x< 0 means x is negative and x^4 would always be positive, then this statement is false
Answer: B.
Question: A patient was given a bottle of tablets by the doctor and he was asked to take five tablets in a gap of 10 minutes.
In how much time will he be able to take all the five tablets?
A.1 Hour.
B.40 min
C.50 min
D.None
Answer: B.40 min
Explanation: Suppose he takes the first tablet at 8:00 pm. Then the second will be consumed by him at 8:10, third at 8:20, fourth at 8:30 and fifth at 8:40.
Time = 40 min
Answer B
Question: If an item that originally sold for z dollars was marked up by x percent and then discounted by y percent, which of the following expressions represents the final price of the item?
A.(10,000z + 100z(x – y) – xyz)/10,000
B.(10,000z + 100z(y – x) – xyz)/10,000
C.(100z(x – y) – xyz)/10000
D.(100z(y – x) – xyz)/10000
Answer: A.(10,000z + 100z(x – y) – xyz)/10,000
Explanation: Z * (1+(x/100)) * (1-(y/100))
Z* (100+x/100) * (100-y/100)
(100Z + ZX)/100 * (100-y/100)
[10,000Z + 100 ZX - 100 ZY - XYZ] /10,000
[10,000Z +100Z (X - Y) - XYZ] / 10,000
Choice A
Question: What is the rate percent when the simple interest on Rs.2000 amount to Rs.320 in 4 Years?
A.4.5%
B.4.25%
C.4%
D.4.3%
Answer: C.4%
Explanation: Interest for 1 year = 320/4 = 80
Interest on Rs 2000 p/a = 80
interest rate = 80/2000*100 = 4%
Answer : C
Question: The perimeter of a triangle is 28 cm and the inradius of the triangle is 2.0 cm. What is the area of the triangle?
A.28 cm2
B.27 cm2
C.29 cm2
D.25 cm2
Answer: A.28 cm2
Explanation: Area of a triangle = r * s
Where r is the inradius and s is the semi perimeter of the triangle.
Area of triangle = 2.0 * 28/2
= 28 cm2
Answer: A
Question: In what time a sum of money double itself at 3% per annum simple interest?
A.36 1/3%
B.33 1/3%
C.33 1/6%
D.63 1/3%
Answer: B.33 1/3%
Explanation: P = (P*3*R)/100
R = 33 1/3%
Answer: B
Question: The distance between two cities A and B is 1140 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
A.09 AM
B.07 AM
C.11 AM
D.05 PM
Answer: D.05 PM
Explanation: Explanation:
Suppose they meet x hrs after 8 a.m
then,
[Distance moved by first in x hrs] + [Distance moved by second in (x-1) hrs] = 1140.
Therefore, 60x + 75(x-1) = 1140.
=> x=9.
So,they meet at (8+9) i.e, 5PM
Answer: D
Question: Car W and Car Y traveled the same 80-mile route. If Car W took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car W, how many hours did it take Car Y to travel the route?
A. 2/3
B. 1
C. 4/3
D. 8/5
Answer: C. 4/3
Explanation: The speed of car W is (distance)/(time) = 80/2 = 40 miles per hour.
The speed of car Y = 3/2*40 = 60 miles per hour --> (time) = (distance)/(speed) = 80/60 = 4/3 hours.
Answer: C.
Or: to cover the same distance at 3/2 as fast rate 2/3 as much time is needed --> (time)*2/3 = 2*2/3 = 4/3 hours.
Answer: C.
Question: Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?
A.56%
B.57%
C.54%
D.53%
Answer: B.57%
Explanation: Total number of votes polled = (1136 + 7636 + 11628) = 20400.
Required percentage = (11628/20400 * 100)% = 57%
Answer B)57%.
Question: A 11% stock yields 8%.The market value of the stock is :
A.Rs. 72
B.Rs. 137.50
C.Rs. 112.50
D.Rs. 116.50
Answer: B.Rs. 137.50
Explanation: solution
To obtain Rs. 8, investment = Rs. 100.
To obtain Rs. 11, investment = Rs.(100/8X11)= Rs. 137.50
∴ Market value of Rs. 100 stock = Rs.137.50
Answer B
Question: A train running at the speed of 60 km/hr crosses a pole in 6 seconds. Find the length of the train.
A.100
B.882
C.772
D.252
Answer: A.100
Explanation: Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 6 = 100 meter.Answer: A
Question: The lunch menu at a certain restaurant contains 4 different entrees and 5 different side dishes. If a meal consists of 1 entree and 2 different side dishes, how many different meal combinations R could be chosen from this menu?
A.10
B.20
C.40
D.80
Answer: C.40
Explanation: R=4C1 * 5C2
= 4 * (5*4*3!)/(3!2!)
= 4 * 10
= 40
Answer - C
Question: 2+2+2²+2³ ... +2^9
A.2^9
B.2^10
C.2^16
D.2^35
Answer: B.2^10
Explanation: 2+2=2^2
2^2+2^2=(2^2)*(1+1)=2^3
2^3+2^3=(2^3)*(1+1)=2^4
so you can notice the pattern... in the end you will have 2^9+2^9, which will give you 2^10
Answer B
Question: A pet store sells dog collars arranged on display such that each of the four different colors of dog collars, green, red, blue, and purple are consecutive in a repeating pattern. If five consecutively displayed collars are purchased, what is the probability that two of the collars are purple?
A.1/4
B.1/5
C.1/16
D.1/32
Answer: A.1/4
Explanation: After green, red, blue, and purple, the next dog collar can be of any given four colours, therefore we have total four possibilites, out of which we need purple i.e. 1 therefore prob is 1/4.
Question: If n = 2.0823 and n* is the decimal obtained by rounding n to the nearest hundredth, what is the value of n* – n?
A. -0.0053
B. -0.0023
C. 0.0007
D. 0.0047
Answer: B. -0.0023
Explanation: n*=2.08
n*-n=2.08-2.0823
-0.0023
Answer: B
Question: The ratio of 2 numbers is 4:6 and their H.C.F. is 8. Their L.C.M. is ?
A.20
B.24
C.52
D.96
Answer: D.96
Explanation: Let the numbers be 4x and 6x
Their H.C.F. = 8
so the numbers are 4*8 , 6*8 = 32,48
L.C.M. = 96
Answer is D
Question: A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
A.3hr
B.3hr 45min
C.4hr 15min
D.2hr 1min
Answer: B.3hr 45min
Explanation: Time taken by one tap to fill the half tank = 3 hr
part filled by the 4 taps in 1hour = 4*1/6 = 2/3
Remaining part = 1-1/2 = 1/2
2/3:1/2::1:x
x = 3/4hr = 45min
Total time taken = 3hr 45min
Answer is B