RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Which digits should come in place of @ and # if the number 62684@# is divisible by both 8 and 5?
A.4,0
B.0,4
C.4,4
D.0,0
Answer: A.4,0
Explanation: Explanation :
Since the given number is divisible by 5, so 0 or 5 must come in place of #.
But, a number ending with 5 is never divisible by 8.
So, 0 will replace #.
Now, the number formed by the last three digits is 4@0, which becomes divisible by 8, if @ is replaced by 4.
Hence, digits in place of @ and # are 4 and 0 respectively.
Answer : A
Question: A work which could be finished in 8 days was finished 3 days earlier after 10 more men joined. The number of men employed was?
A.22
B.30
C.88
D.71
Answer: B.30
Explanation: x ------- 8
(x + 10) ---- 6
x * 8 = (x + 10)6
x = 30
\Answer: B
Question: Each digit in the two-digit number G is halved to form a new two-digit number H. Which of the following could be the sum of G and H
A.153
B.159
C.137
D.121
Answer: B.159
Explanation: let the number be x, now x is halved => x/2..the question asks what is x?
x(number) + x/2 (half of that number) = something
=> 3x/2 = something
=> x = 2 (something) / 3
so the answer choice must be divisible by 3
eliminate C, E right away
check the rest
B satisfies
3x/ 2 = 159
=> x = 106
Verify. 106 + 53 = 159
Answer is B
Question: The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
A.9
B.2
C.7
D.8
Answer: B.2
Explanation: Let the numbers 13a and 13b.
Then, 13a x 13b = 2028
=>ab = 12.
Now, the co-primes with product 12 are (1, 12) and (3, 4).
[Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]
So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).
Clearly, there are 2 such pairs.
Answer: B
Question: Renu can do a piece of work in 8 days, but with the help of her friend Suma , she can do it in 4 days. In what time Suma can do it alone?
A.8
B.12
C.14
D.15
Answer: A.8
Explanation: Renuâ€™s one dayâ€™s work = 1/8
Sumaâ€™s one dayâ€™s work = 1/4 - 1/8 = 1/8
Suma can do it alone in 8 days.
ANSWER:A
Question: There are 4 people who has to cross a stretch of 300 km. They normally run at a speed of 10 kmph. One
of them has a bike that travels at 50 kmph. The bike first takes one person alone and crosses the
stretch while the other two keep running. Then he comes back without wasting time and picks up
another person from the way, drives him across the stretch, and does the same for the last person. How
long does this whole process take?
A.24 hrs
B.16 hrs
C.56/3 hrs
D.58/3 hrs
Answer: D.58/3 hrs
Explanation: Expl : Time taken to carry 2nd person = 300/50 = 6 hrs.
Time taken to meet 3rd person =(300-6*10)/(50+10) = 4 hrs
Time taken to carry 3rd person = 4 hours
Time taken to meet 4th person = (300 –140)/60 = 8/3
Total time = 6+4+4+8/3+8/3 = 58/3 hours
Answer :D
Question: If by selling an article for Rs.60, a person loses 1/7 of money, what would he have gained or lost % by selling it for Rs.77?
A.5%
B.10%
C.20%
D.30%
Answer: B.10%
Explanation: Sol. CP - = EC7 = 70 1-7 6 77-70 % Profit = 100 = 10%
B
Question: If a light flashes every 6 seconds, how many times will it flash in ¾ of an hour?
A.451 times
B.638 times
C.838 times
D.436 times
Answer: A.451 times
Explanation: There are 60 minutes in an hour.
In ¾ of an hour there are (60 * ¾) minutes = 45 minutes.
In ¾ of an hour there are (60 * 45) seconds = 2700 seconds.
Light flashed for every 6 seconds.
In 2700 seconds 2700/6 = 450 times.
The count start after the first flash, the light will flashes 451 times in ¾ of an hour.
Answer:A
Question: Revenues were recorded for Store A and Store B over a period of three months. In the first month, Store A's revenues were $40,000 higher than Store B's revenues. In the second month, Store A's revenues were $6,000 higher than Store B's revenues. If Store A's average (arithmetic mean) monthly revenue for the three months was $2,000 greater than Store B's average monthly revenue, then Store B's revenue in the third month was how much greater than Store A's revenue?
A. $14,000
B. $40,000
C. $42,000
D. $46,000
Answer: B. $40,000
Explanation: Answer: CIt may be tempting to come up with a lot of variables, one each for each month's revenue for each company. However, focus on the differences. In the first month, the difference was +40 in favor of A. (Note that we can drop the thousands since every number in the question is in terms of thousands.) In the second, the difference was +6 in favor of A. The average was +2 in favor of A. With these numbers, use the average formula to find the third month (T):
(40 + 6 + T)/3 = 2
46 + T = 6
T = -40
Since positive numbers indicate a difference in favor of A, negative numbers are in favor of B. -40 represents a $40,000 advantage in favor of Store B. Choice (B) is correct.
Question: some digits were given like 0 2 2 3 3 4 4 then how many no will be there which is greater than 1 lac ,all numbers are distinct
A.530
B.540
C.550
D.560
Answer: B.540
Explanation: ( 6*6*5*4*3*2)/(2! *2!*2!)= 540 ways
ANSWER:B
Question: A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
A.600
B.698
C.675
D.688
Answer: B.698
Explanation: 1 year = Rs. (854 - 815) = Rs. 39.
3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698
ANSWER B
Question: Each of the following equations has at least one solution EXCEPT D. Is it true?
A.-2*-a = 2a
B.2*a = (–2)*-a
C.-4*a = -3-a
D.-3*a = -3-a
Answer: D.-3*a = -3-a
Explanation: If we put a= 1 then
A. 2
B. 2
C. -4
E. -3
D. -3=-4 Not true
Question: 10 people went to a hotel for combine dinner party 5 of them spent Rs. 20 each on their dinner and rest spent 4 more than the average expenditure of all the 10. What was the total money spent by them.
A.1628.4
B.1534
C.1492
D.240
Answer: D.240
Explanation: Solution: Let average expenditure of 10 people be x.
then,
10x = 20*5+5*(x+4);
Or, 10x = 20*5+5x+20;
Or, x = 24;
So, total money spent = 24*10 = Rs. 240.
Answer: Option D
Question: If x is the product of the integers from 1 to 150, inclusive, and 5^y is a factor of x, what is the greatest possible value of y ?
A.30
B.34
C.36
D.37
Answer: D.37
Explanation: It basically asks for the number of 5s in 150!
150/5 + 150/25 + 150/125 = 30 + 6 + 1. Hence 37
Answer: D.
Question: Product M is produced by mixing chemical X and chemical Y in the ratio of 5 : 4. Chemical X is prepared by mixing two raw materials, A and B, in the ratio of 1 : 3. Chemical Y is prepared by mixing raw materials, B and C, in the ratio of 2 : 1. Then the final mixture is prepared by mixing 864 units of product M with water. If the concentration of the raw material B in the final mixture is 50%, how much water had been added to product M?
A.328 units
B.368 units
C.392 units
D.616 units
Answer: B.368 units
Explanation: The final product is obtained by mixing 864 units of product M with water.
In 864 units of Product M, amount of B = 864×77/108 = 616
In the final mixture, concentration of B is 50%.
Therefore, the total quantity of final mixture = 616 × 2 = 1232
Water added = 1232 – 864 = 368
The correct answer is Choice B.
Question: In a 4 person race, medals are awarded to the fastest 3 runners. The first-place runner receives a gold medal, the second-place runner receives a silver medal, and the third-place runner receives a bronze medal. In the event of a tie, the tied runners receive the same color medal. (For example, if there is a two-way tie for first-place, the top two runners receive gold medals, the next-fastest runner receives a silver medal, and no bronze medal is awarded). Assuming that exactly three medals are awarded, and that the three medal winners stand together with their medals to form a victory circle, how many Z different victory circles are possible?
A.24
B.52
C.96
D.144
Answer: B.52
Explanation: Possible scenarios are:
1. Gold/Silver/Bronze/No medal (no ties) - 4!=24;
2. Gold/Gold/Silver/No medal - 4!/2!=12;
3. Gold/Silver/Silver/No medal - 4!/2!=12;
4. Gold/Gold/Gold/No medal - 4!/3!=4.
Total Z: 24+12+12+4=52
Answer: B.
Question: X completes a work in 20 days and Y complete the same work in 30 days. If both of them work together, then the number of days required to complete the work will be?
A.10 days.
B.12 days.
C.14 days.
D.8 days.
Answer: B.12 days.
Explanation: If X can complete a work in x days and Y can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days
Therefore, here, the required number of days = 20Ã— 30/ 50 = 12 days.
B)
Question: A chair is bought for Rs.300/- and sold at Rs.420/- find gain or loss percentage
A.15% loss
B.40% gain
C.25% gain
D.30% gain
Answer: B.40% gain
Explanation: Formula = (Selling price ~ Cost price)/Cost price * 100
= (450- 300)/300= 40% gain
B
Question: What is the least number to be subtracted from 696 to make it a perfect square?
A.1
B.16
C.20
D.71
Answer: C.20
Explanation: The numbers less than 696 and are squares of certain numbers are 676, 625.
The least number that should be subtracted from 696 to make it perfect square = 696 - 676 = 20.
ANSWER:C
Question: There are 8 books on a shelf, of which 2 are paperbacks and 6 are hardbacks. How many possible selections of 3 books from this shelf include at least one paperback?
A.a) 40
B.b) 45
C.c) 36
D.d) 55
Answer: C.c) 36
Explanation: approach 1
at-least 1 paper back = total - no paper back
8c3-6c3 = 36
approach 2
at-least 1 paper back = 1 paper back , 3 hard back or 2 paper back 2 hard back
= 2c1*6c2+2c2*6c1 = 36
Answer is C
Question: If a sum of money doubles itself in 20 years at simple interest, the ratepercent per annum is
A.12
B.12.5
C.13
D.5
Answer: D.5
Explanation: Explanation:
Let sum = x then Simple Interest = x
Rate = (100 * x) / (x * 20) = 5
Option D
Question: In a fuel station the service costs $1.15 per car, every liter of fuel costs 0.4$. Assuming that you own 2 sports cars and 2 executive cars and all fuel tanks are empty. How much will it cost to fuel all cars together if a sports car tank is 32 liters and an executive car tank is 75% bigger?
A.37.5$
B.75$
C.87.5$
D.94.5$
Answer: B.75$
Explanation: Total cars=4
1.15*4=4.6->Service Cost
Fuel Cost in Sports Car = 2*32*0.4=25.6
Fuel Cost in Executive Car=25.6*7/4=44.8
Total Fuel Cost = 25.6+44.8=70.4
Cost to fuel car = 70.4+4.6=75
Answer: B
Question: Choose the missing terms out of the given alternatives.
AZ, BY, CX, DW ?
A.EF
B.GH
C.EV
D.DW
Answer: C.EV
Explanation: C
EV
The first letter moves one step forward. The second letter moves one step backward.
Answer is C
Question: Company Z spent 1/4 of its revenues last year on marketing and 1/7 of the remainder on maintenance of its facilities. What fraction of last year’s original revenues did company Z have left after its marketing and maintenance expenditures?
A.5/14
B.1/2
C.17/28
D.9/14
Answer: D.9/14
Explanation: Total revenues = x
Spent on marketing = x/4
Remaining amount = x-x/4 = 3x/4
1/7 of the remainder on maintenance of its facilities = 3x/4*1/7 = 3x/28
Amount left = 3x/4-3x/28 = 9x/14
Answer D
Question: A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
A.40 sec
B.42 sec
C.45 sec
D.48 sec
Answer: A.40 sec
Explanation: Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 2/25 = 40 sec
ANSWER:A
Question: What is the scope including 1/21+1/22+1/23+......+1/30?
A.1/6~1/5
B.1/5~1/4
C.1/4~1/3
D.1/3~1/2
Answer: D.1/3~1/2
Explanation: For Maximum value : It should be less than 1/21 + 1/21 +1/21... 10 times = 10/21 ~ 1/2
For Minimum Value : It should be greater than 1/30+ 1/30+ 1/30 .. 10 times = 10/30 = 1/3
Thus, the answer should lie between 1/3 and 1/2. Correct ans : D.
Question: A bag contains 5 red, 2 green balls. 3 balls are drawn randomly. What is the probability that balls drawn contain exactly two green balls?
A.1/7
B.2/9
C.3/11
D.4/17
Answer: A.1/7
Explanation: Total number of balls = 5+2 = 7
n(S) = 7C3 = 7*6*5 / 3*2 = 35
n(E) = 2C2* 5C1 = 5
Probability = 5/35 = 1/7
Answer is A
Question: A woman complete a journey in 20 hours. She travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
A.334 km.
B.216 km.
C.314 km.
D.448 km.
Answer: D.448 km.
Explanation: 0.5x/21 + 0.5x/24 = 20
--> x/21 + x/24 = 40
--> x =448 km.
D
Question: The average height in a group of 4 people is 175 cm. If the average height increased when 2 more people were added to the group, which of the following cannot be the heights of the two new people?
A.179 cm and 172 cm
B.181 cm and 169 cm
C.173 cm and 178 cm
D.176 cm and 176 cm
Answer: B.181 cm and 169 cm
Explanation: Denote X as the sum of the heights of the two new people. From the stem it follows that (700+X)6>175. This reduces to X>350. Only the heights from B add up to 350 cm. All other pairs add up to more than 350 cm.
Answer: B
Question: The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?
A.70
B.55
C.60
D.65
Answer: A.70
Explanation: A+B=60 A=2B
2B+B=60===>B=20
A=40
5 yrs ages 45 and 25
Sum of their ages = 70
ANSWER A
Question: Find the number which when multiplied by 15 is increased by 196.
A.14
B.20
C.26
D.28
Answer: A.14
Explanation: Let the number be x. Then, 15x - x = 196
<=> 14x = 196 <=> x = 14.
Answer :A
Question: A number X equals 80% of the average of 5, 7, 14 and a number Y. If the average of X and Y is 26, the value of Y is?
A.13
B.26
C.39
D.36
Answer: C.39
Explanation: Average of 5, 7, 14 and Y = ( 5 + 7 + 14 + Y )/ 4
Therefore, X = 80% of ( 5 + 7 + 14 + y )/ 4
= (80/100) x (26 + Y)/4
=> X = (26 + Y)/5
5X - Y = 26----- (i)
Also, (X + Y)/2 = 26 ----- (ii)
From (i)and (ii)
X = 13
Y = 39.
ANSWER:C
Question: A man covers a distance on scooter. Had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower, he would have taken 40min more. The distance is.
A.30 km
B.40 km
C.45 km
D.50 km
Answer: B.40 km
Explanation: Let distance = x m
Usual rate = y kmph
x/y – x/y+3 = 40/60 hr
2y(y+3) = 9x ---------------------------------(1)
x/y-2 – x/y = 40/60 hr y(y-2) = 3x -----------(2)
divide 1 & 2 equations
by solving we get x = 40 km
Answer : B
Question: The number of livestock in a farm at the beginning of year 2000 was 130,000. During the year, the number increased by p%. During the next year 2001, there was a famine and the number decreased by q%. A census at the end of year 2001 revealed that the number of livestock in the farm was 130,000. Which of the following expressions is correct?
A.With the exception of 1 instance, p will be equal to q
B.q > p
C.p = q
D.p > q
Answer: D.p > q
Explanation: Number plugging in will be best strategy for this question.
Let p = 5%,
Per the question 100000(1.05)(1-q/100) = 100000 ---> q = 4.7%. Thus p > q and hence D is the correct answer.
Question: If 3 men or 4 women can reap a field in 10 days how long will 5 men and 6 women take to reap it?
A.19/60
B.9/60
C.2/3
D.5/18
Answer: A.19/60
Explanation: Explanation:
3 men reap 1/10 field in 1 day
1 man reap 1/(3 x 10)
4 women reap 1/10 field in 1 day
1 woman reap 1/(10 x 4)
5 men and 6 women reap (5/(3 x 10)+ 6/(4 x 10)) =19/60 in 1 day
5 men and 6 women will reap the field in 19/60 days
Answer: Option A
Question: On Monday, a certain animal shelter housed 45 cats and dogs. By Friday, 1/5 of the cats and 1/4 of the dogs had been adopted; no new cats or dogs were brought to the shelter during this period. What is the greatest possible number of pets that could have been adopted from the animal shelter between Monday and Friday?
A.10
B.11
C.12
D.13
Answer: B.11
Explanation: To maximize the number of pets adopted, we should maximize the number of dogs adopted since 1/4 > 1/5.
The greatest multiple of 4 less than 45 is 40 (such that the remaining number is divisible by 5), so let's assume there were 40 dogs and 5 cats.
Then the maximum number of adopted pets is 1/4*(40) + 1/5*(5) = 10 + 1 = 11.
The answer is B.
Question: A shopkeeper gave an additional 20 per cent concession on the reduced price after giving 30 per cent standard concession on an article. If Arun bought that article for 1,120, what was the original price?
A.3,000
B.4,000
C.2,400
D.2,000
Answer: D.2,000
Explanation: Original price = 1120 × 100⁄70 × 100⁄80 = 2000
Answer D
Question: The total age of A and B is 10 years more than the total age of B and C. C is how many years younger than A.?
A.16
B.12
C.10
D.20
Answer: C.10
Explanation: (A+B)-(B-C)=10
A-C=10
Answer is C
Question: In an election between two candidates, 10% of votes are were declares invalid. First candidate got 3600 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:
A.9000
B.98000
C.20000
D.11000
Answer: C.20000
Explanation: 100 % - 10 % = 90 %
54%-36%=18%
18% ------> 3600 ( 18 × 200 = 3600)
100% -------> 20000 votes (100 × 200 = 20000)
C
Question: Find a 8 digit number that if multiplied by the number 9 or any of its multiplications products (18, 27, 36, 45,..) will result in the multiplication factor repeated (n) number of times.
A.12345679
B.42345675
C.22347379
D.52345673
Answer: A.12345679
Explanation: A
The number is: 12345679
12345679 * 9 = 111111111
12345679 * 18 = 222222222
12345679 * 27 = 333333333
And so on...
Question: A and B invests Rs.3000 and Rs.7000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit?
A.9:6
B.9:8
C.9:14
D.9:9
Answer: C.9:14
Explanation: (3*6 + 6*6): (7*12)
54:84 => 9:14.Answer:C
Question: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary?
A.5000
B.2889
C.2779
D.6257
Answer: A.5000
Explanation: Income = Rs. 100
Expenditure = Rs. 80
Savings = Rs. 20
Present Expenditure 80*(20/100) = Rs. 96
Present Savings = 100 – 96 =Rs. 4
100 ------ 4
? --------- 200 => 5000
Answer: A
Question: A boat covers a certain distance downstream in 1 hour, while it comes back in 11â„2 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?
A.31 kmph
B.16 kmph
C.19 kmph
D.15 kmph
Answer: D.15 kmph
Explanation: Let the speed of the water in still water =x
Given that speed of the stream = 3 kmph
Speed downstream =(x+3) kmph
Speed upstream =(xâˆ’3) kmph
He travels a certain distance downstream in 1 hour and come back in 11â„2 hour.
i.e., distance travelled downstream in 1 hour = distance travelled upstream in 11â„2 hour
Since distance = speed Ã— time, we have
(x+3)Ã—1=(x-3)3/2
2(x+3)=3(x-3)
2x+6=3x-9
x=6+9=15 kmph
Answer: D
Question: A and B invests Rs.4000 and Rs.6000 in a business. After 4 months, A withdraws three-fourth of his capital and 4 months later, B withdraws half of his capital. In what ratio should they share the profits at the end of the year?
A.2:5
B.3:5
C.4:5
D.3:7
Answer: A.2:5
Explanation: A : B
(4000*4)+(1000*8) : (6000*8)+(3000*4)
24000 : 60000
2 : 5
Answer: A
Question: 0.5, 0.55, 0.65, 0.8, ?
A.0.7
B.0.9
C.0.95
D.1
Answer: D.1
Explanation: The pattern is + 0.05, + 0.10, + 0.15, .....
Answer : D.
Question: If 15 women or 10 men can complete a project in 55 days, in how many days will 5 women and 4 men working together complete the same project ?
A.75
B.8
C.9
D.85
Answer: A.75
Explanation: 15 W = 10 M
Now, 5W + 4M = 5W + 4×15/10W = 5W + 6W = = 11 W
If 15 women can complete the project in 55 days,
11 women can complete the same project in
55×15/11=75days
Answer A
Question: If n is a positive integer and n^2 is divisible by 450, then what is the largest positive integer that must divide n?
A.10
B.20
C.30
D.40
Answer: C.30
Explanation: 450 = 2 * 3^2 * 5^2
If 450 divides n^2, then n must be divisible by 2 * 3 * 5 = 30
The answer is C.
Question: Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?
A.6
B.8
C.7
D.4
Answer: B.8
Explanation: 1/10 + 1/15 = 1/6 * 4 = 2/3
1 - 2/3 = 1/3
1/10 + 1/15 - 1/x = 1/3
x = 8
Answer:B
Question: A certain club has 14 members, including Harry. One of the 14 members is to be chosen at random to be the president, one of the remaining 13 members is to be chosen at random to be the secretary, and one of the remaining 12 members is to be chosen at random to be the treasurer. What is the probability that Harry will either be the secretary or the member chosen to be the treasurer?
A.5/7
B.4/7
C.3/7
D.1/7
Answer: D.1/7
Explanation: Each member out of 14, including Harry, has equal chances to be selected for any of the positions (the sequence of the selection is given just to confuse us). The probability that Harry will be selected to be the secretary is 1/14 and the probability that Harry will be selected to be the treasurer is also 1/14. So, the probability that Harry will be selected to be either the secretary or the the treasurer is 1/14+1/14=2/14.
Answer: D.
Question: Afreena walks 8 km towards East and then walks 13 km back, then she turns left and walks 4 km; then walks 5 km after turning left; she turns left again and walks 3 km. How far is she from the starting point ?
A.3 km
B.2 km
C.1 km
D.6 km
Answer: C.1 km
Explanation: Explanation:
From given details we know that she walks in square shaped path and will be in 1 km away from starting point.
ANSWER IS C
Question: A coed soccer team has W women and M men on the team. If 4 women and 2 men are added to the team roster, and if one person on the team is selected at random to serve as team captain, then the probability that the team captain will be a woman can be represented as
A.(W + 4)/(W + M + 6)
B.(W + 4)/(W + M + 2)
C.(W + 4)/(M + 2)
D.(W + 4)/(W + M)
Answer: A.(W + 4)/(W + M + 6)
Explanation: W women and M men..now 4 women and 2 men are added then total women = W+4 and total men = M+2.. if we club both as total one team (W + M + 6)
We need to find the probability that the team captain will be a woman => W+4 / (W + M + 6)..
IMO option A is correct answer...
Question: A man is 30 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is
A.14 years
B.28 years
C.20 years
D.22 years
Answer: B.28 years
Explanation: Solution
Let the son's present age be x years .Then, man's present age	= (x+30)years.
Then	â€¹=â€º(x+30)+2= 2(x+2)
â€¹=â€ºx+32=2x+4
x= 28.
Answer B
Question: Chris mixed 3 pounds of raisins with 3 pounds of nuts. If a pound of nuts costs 3 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture?
A. 1/7
B. 1/5
C. 1/4
D. 1/3
Answer: C. 1/4
Explanation: 1 lbs of raisin = $1
3 lbs of raisin = $3
1 lbs of nuts = $3
3 lbs of nuts = $9
Total value of mixture = 9+3 = 12
Fraction of the value of raisin = 3/12 = 1/4
Ans:C
Question: If 2^(2w) = 8^(w−2), what is the value of w?
A.3
B.6
C.9
D.12
Answer: B.6
Explanation: 2^(2w) = 8^(w−2)
2^(2w) = 2^(3*(w−2))
2^(2w) = 2^(3w-6)
Let's equate the exponents as the bases are equal.
2w = 3w-6
w = 6
The answer is B.
Question: A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?
A.2 p.m. on Tuesday
B.2 p.m. on Wednesday
C.3 p.m. on Thursday
D.1 p.m. on Friday
Answer: B.2 p.m. on Wednesday
Explanation: Solution
Time from 12 p.m. on Monday to 2 p.m. on the following Monday	= 7 days 2 hours.
=170 hours.
The watch gains	= (2 + 4 x4/5)min
= 34 / 5 min.in 170 hrs.
Now,34/5 min are gained in 170 hrs.
2 min are gained in(170x 5/34 x2)hrs.
Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m.on Wednesday.
Answer B