RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Two men X and Y started working for a certain company at similar jobs on January 1, 1950. X asked for an initial salary of Rs. 300 with an annual increment of Rs. 30. Y asked for an initial salary of Rs. 200 with a rise of Rs. 15 every 6 months. Assume that the arrangements remained unaltered till December 31, 1959. Salary is paid on the last day of the month. What is the total amount paid to them as salary during the period?
A.Rs. 93,300
B.Rs. 93,200
C.Rs. 93,100
D.None of these
Answer: A.Rs. 93,300
Explanation: Explanation :
Amount of money given to X
= 12 x 300 + 12 x 330 + ....... + 12 x 570.
= 12[ 300 + 330 + .........+ 540 + 570 ].
= 12 x (10/2) [ 600 + 9 x 30 ].
= 52200.
Amount of money given to Y is
= 6 x 200 + 6 x 215 + 6 x 230 + 6 x 245 + ... upto 20 terms
= 6 [ 200 + 215 + 230 + .....485 ]
= 6 x (20/2)[ 400 + 19 x 15]
= 6 x 10 [ 400 + 285 ] .
= 60 x 685 = 41110
Hence, the total amount paid is 52200 + 41110 = Rs 93,300.
Answer : A
Question: A is half good a work man as B and together they finish a job in 18 days. In how many days working alone B finish the job?
A.23
B.22
C.27
D.36
Answer: C.27
Explanation: C
27
WC = 1:2
2x + x = 1/18 => x = 1/54
2x = 1/27 => 27 days
Question: The sum of 55 consecutive integers is 5555. What is the greatest integer in the set?
A.126
B.128
C.130
D.132
Answer: B.128
Explanation: Let x be the first integer in the set, then x+54 is the largest integer.
The sum is: x+(x+1)+(x+2)+...+(x+54)
= 55x + 54*55/2
= 55(x+27)
Then x+27=101
x=74
The largest integer in the set is 74+54=128
The answer is B.
Question: On dividing a number by 999, the quotient is 366 and the remainder is 103. The number is:
A.364724
B.365387
C.365737
D.366757
Answer: C.365737
Explanation: Required number= 999*366+103= (1000-1)*366+103= 366000-366+103= 365737.
Answer: C
Question: The ratio of three numbers is 1:2:3 and their sum is 60. The second number of the three numbers is?
A.24
B.26
C.20
D.29
Answer: C.20
Explanation: 1:2:3
Total parts = 6
6 parts --> 60
1 part ---->10
The second number of the three numbers is =2 * 10 = 20
Answer : C
Question: Carl can wash all the windows of his house in 6 hours. His wife Maggie can wash all the windows in 7 hours. How many hours will it take for both of them working together to wash all the windows?
A.2
B.2 1/4
C.42 3/3
D.4 1/2
Answer: C.42 3/3
Explanation: Work hrs=AB/(A+B)= 42/13 =42 3/3
Answer is C
Question: Gordon is twice as old as Tony was when Gordon was as old as Tony is now. The combined age of Gordon and Tony is 112 years. How old are Gordon and Tony now?
A.Gordon 64 and Tony 48
B.Gordon 74 and Tony 38
C.Gordon 84 and Tony 48
D.Gordon 64 and Tony 58
Answer: A.Gordon 64 and Tony 48
Explanation: When Gordon was 48, Tony was 32(ie half the age Gordon is now).
Answer : A
Question: If an object travels 300 feet in 5 seconds, what is the object's approximate speed in miles per hour? (Note: 1 mile = 5280 feet)
A.39
B.38
C.40
D.41
Answer: D.41
Explanation: 1 mile = 5280 feet
=> 1 feet = 1/5280 miles
If the object travels 300 feet in 5 sec
then it travels 300/5 * 60 * 60 feet in 1 hour (1 hr = 60 min * 60 sec)
= 3600 * 60 feet in 1 hour
= 216000 feet in 1 hr
= 216000/5280 miles in 1 hour
= 21600/528 miles/hr ~ 41 miles/hr
Answer - D
Question: Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?
A.2977
B.9261
C.2890
D.2890
Answer: B.9261
Explanation: A = 8000(21/20)3
= 9261
Answer: B
Question: In a company 10% of male staff are same in number as 1/4th of the female staff. What is the ratio of male staff to female staff
A.3 : 2
B.5 : 2
C.2 : 1
D.4 : 3
Answer: B.5 : 2
Explanation: 10% of MS = 1/4th of FS
-> 10MS/100 = 1/4FS
-> MS = 5/2 FS
:. MS/FS = 5/2 = MS : FS = 5 : 2
ANSWER:B
Question: A train moves fast a telegraph post and a bridge 264 m long in 4 sec and 20 sec respectively. What is the speed of the train?
A.89
B.23
C.59.4
D.79.2
Answer: C.59.4
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 4 => x = 4y
(x + 264)/20 = y
y = 16.5
Speed = 16.5m/sec = 16.5 * 18/5 = 59.4 km/hr.
Answer: Option C
Question: There are 600 students in a school. The ratio of boys and girls in this school is 3:5. Find the total of girls & boys are there in this school?
A.243
B.265
C.375
D.390
Answer: C.375
Explanation: In order to obtain a ratio of boys to girls equal to 3:5, the number of boys has to be written as 3 x and the number of girls as 5 x where x is a common factor to the number of girls and the number of boys. The total number of boys and girls is 600. Hence
3x + 5x = 600
Solve for x
8x = 600
x = 75
Number of boys
3x = 3 × 75 = 225
Number of girls
5x = 5 × 75 = 375
C
Question: A 160 meter long train crosses a man standing on the platform in 9 sec. What is the speed of the train?
A.96 kmph
B.64 kmph
C.52 kmph
D.86 kmph
Answer: B.64 kmph
Explanation: S = 160/9 * 18/5 = 64 kmph
ANSWER:B
Question: If circles x and y have the same area and circle x has a circumference of 10π, half of the radius of circle y is:
A.16
B.8
C.4
D.2.5
Answer: D.2.5
Explanation: x be radius of circle x
y be radius of circle y
given:
pi*x^2 = pi*y^2
also,
2*pi*x = 10*pi
x =5
thus y = 5
y/2 = 2.5
Ans: D
Question: If $5,000 is invested in an account at a simple annual rate of r percent, the interest is $250. When $20,000 is invested at the same interest rate, what is the interest from the investment?
A.$700
B.$750
C.$800
D.$1000
Answer: D.$1000
Explanation: -> 250/5,000=5% and 20,000*5%=1000.
Thus, D is the answer.
Question: If the perimeter of a rectangular garden is 900 m, its length when its breadth is 190 m is?
A.338 m
B.778 m
C.200 m
D.260 m
Answer: D.260 m
Explanation: 2(l + 190)
= 900 => l
= 260 m
Answer:D
Question: A completes a piece of work in 3/4 of the time in B does, B takes 4/5 of the time in C does. They got a profit of Rs. 40000 how much B gets?
A.12765
B.121227
C.26887
D.19977
Answer: A.12765
Explanation: Assume C takes 20 Days. Now B takes 4/5 (20) = 16 days. A takes 3/4(16) = 12
Now their efficiencies ratio = 1/20 : 1/16 : 1/12 = 12 : 15 : 20
B's share in the profit of Rs.40000 = 15/47 (40000) = Rs.12765
Answer:A
Question: A tank is filled by 3 pipes A,B,C in 8 hours. Pipe C is twice as fast as B and B is twice as fast as A. How much will pipe A alone take to fill the tank ?
A.25hr
B.35hr
C.56hr
D.20hr
Answer: C.56hr
Explanation: Suppose pipe A alone take x hours to fill the tank
Then pipe B and C will take x/2 and x/4 hours respectively to fill the tank.
1/x + 2/x + 4/x = 1/8
7/x = 1/8
x = 56 hours
Answer is C
Question: Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 360 and for 36kgs of Apples is 420 then the cost of first 25kgs of Apples is
A.100
B.250
C.125
D.110
Answer: B.250
Explanation: Ans: By framing equations we get
30L+3Q=360
30L+6Q=420
Eliminate Q by multiplying the first equation by 2 and subtracting second equation from the first
Then we get L = 10
Cost of 10 kgs of apples =25x 10 = 250
Answer:B
Question: Approximately how many cubic feet of water are needed to fill a circular swimming pool that is 60 feet across and 6 feet deep?
A.900
B.4000
C.10000
D.17000
Answer: D.17000
Explanation: Answer Should be D.
V= \pir^2h= \pi*30^2*6= approximately 17000
Question: At what time between 8 and 9 o’clock will the hands of a watch be in straight line but not together?
A.10 11⁄10 min. past 8
B.10 10⁄11 min. past 8
C.11 10⁄11 min. past 8
D.12 10⁄11 min. past 8
Answer: B.10 10⁄11 min. past 8
Explanation: At 8 o’clock, the hands of the watch are 20 min. spaces apart.
To be in straight line but not together they will be 30 min. space apart.
∴ Minute hand will have to gain 10 min. spaces 55 min.spaces are gained in 60 min.
10 min. spaces will be gained in (60⁄55 × 50) min or 10 10⁄11 min
∴ Required time = 10 10⁄11 min. past 8
Answer B
Question: The cost price of an article is 55% of the marked price. Calculate the gain percent after allowing a discount of 15%.
A.40.5 %
B.48.7 %
C.54.5%
D.55.6% %
Answer: C.54.5%
Explanation: Sol.
Let marked price = Rs. 100. Then, C.P. = Rs. 55. S.P = Rs. 85.
âˆ´ Gain % = [30/55 * 100]% = 54.5%.
Answer C
Question: A sum of Rs. 25000 becomes Rs. 27250 at the end of 3 years when calculated at simple interest. Find the rate of interest.
A.1%
B.2%
C.3%
D.4%
Answer: C.3%
Explanation: Simple interest = 27250 – 25000 = 2250
Time = 3 years.
SI = PTR / 100 → R = SI * 100 / PT
R = 2250 * 100 / 25000 * 3 → R = 3%. ANSWER : C
Question: The age of father 7 years ago was five times the age of his son. Five years hence, father's age will be thrice that of his son. The ratio of their present ages is:
A.67 : 19
B.65 : 17
C.61 : 19
D.63 : 15
Answer: A.67 : 19
Explanation: Let the ages of father and son 7 years ago be 5x and x years respectively.
Then, (5x + 7) + 5 = 3[(x + 7) + 5]
5x + 12 = 3x + 36
x = 12.
Required ratio = (5x + 7) : (x + 7) = 67 : 19.
Answer: Option A
Question: Place a number in each of the following empty
boxes so that the sum of the numbers in any 3
consecutive boxes is 2015. What is the number
that should go in the box with the question
mark?
A.684
B.567
C.892
D.431
Answer: A.684
Explanation: To help illustrate the problem, we will label a few boxes as shown below.
Since the sum of the numbers in any 3 consecutive boxes is the same,
607 + A + B = A + B + C.
After taking away both A and B from the above equation we get 607 = C
Therefore, the number in box C should be 607.
Since the sum of the numbers in any 3 consecutive boxes is 2015,
C + 724 +? = 607 + 724 +? = 2015
Therefore, ? = 684
correct answer A
Question: Nirmala gains 10% by selling her bicycle for a certain price. If she sells it at 2 times the price, the percentage of profit will be :
A.130%
B.140%
C.160%
D.120%
Answer: D.120%
Explanation: Explanation :
Solution: Let C.P =Rs. x. then, S.P. = Rs. (110% of x) = Rs. 11x/10.
New S.P. = Rs. (2*11x/10) =Rs. 22x/10. profit = Rs. (22x/10 - x) = Rs. 6x/5.
.'. Profit% = (6x/5 *1/x * 100) = 120%.
Answer : D
Question: A question paper has 2 parts, A & B, each containing 8 questions. If a student has to choose 8 from part A &4 from part B, in how many ways can he choose the questions?
A.110
B.70
C.120
D.130
Answer: B.70
Explanation: There 8 questions in part A out of which 8 question can be chosen as = 8C8.
Similarly,4 questions can be chosen from 8 questions of Part B as = 8C4.
Hence, total number of ways,
=8C8*8C4
=[8!/(0!8!)]*[8!/(4!*4!)]
= {1}*{8*7*6*5/(4!)}
= 70.
B
Question: If 36x = 216^y, which of the following expresses x in terms of y?
A.6^(3y-2)
B.6^3y
C.6^(3y-1)
D.6^(y-36)
Answer: A.6^(3y-2)
Explanation: By exponential simplification. 36 = 6^2 and 216=6^3 therefore (6^2)x=(6^3)^y gives x=(6^3y)/(6^2) further simplified to x=(6^3y)(6^-2) which gives x=6^(3y-2) (because exponential is additive in multiplication. i.e. a^b*a^c=a^(b+c). Answer: A
Question: Two pipes A and B can fill a cistern in 37 1/2 minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the pipe B is turned off after?
A.7
B.6
C.9
D.7
Answer: B.6
Explanation: Let B be turned off after x minutes. Then, part filled by (A + B) in x min + part filled by A in (30 - x) min = 1.
x(2/75 + 1/45) + (30- x) 2/75 = 1
11x + 180 - 6x = 225 => x = 9
Answer: B
Question: 2, 3, 6, 0, 10, -3, 14, (...)
A.6
B.2
C.-2
D.-6
Answer: D.-6
Explanation: Explanation :
There are two series
2, 6, 10, 14, ... (Adding 4)
3, 0, -3, ... (Subtracting 3)
Hence, next term is -3 - 3 = -6
Answer : Option D
Question: Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 10 meters and a circumference of 6 meters, and the interior of tank B has a height of 6 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B?
A.60%
B.80%
C.100%
D.120%
Answer: A.60%
Explanation: The radius of tank A is 6/(2*pi).
The capacity of tank A is 10*pi*36 / (4*pi^2) = 180 / (2*pi)
The radius of tank B is 10 / (2*pi).
The capacity of tank B is 6*pi*100 / (4*pi^2) = 300 / (2*pi)
Tank A / Tank B = 180/300 = 6/10 = 60%
The answer is A.
Question: At what rate percent on simple interest will Rs.750 amount to Rs.900 in 5 years?
A.8%
B.3%
C.4%
D.2%
Answer: C.4%
Explanation: 150 = (750*5*R)/100
R = 4%
Answer:C
Question: On decreasing the price of a Air Conditioner by 20%, its sale is increased by 40%. The effect on the revenue is?
A.8 % decrease
B.4 % increase
C.16% decrease
D.12 % increase
Answer: D.12 % increase
Explanation: Net% change in revenue
= ( x + y + xy/100) %
= [-20 + 40 + ( -20 x 40)/100]% or 12%
ANSWER:D
Question: Three workers have a productivity ratio of 1 to 2 to 3. All three workers are working on a job for 5 hours. At the beginning of the 6th hour, the slowest worker takes a break. The slowest worker comes back to work at the beginning of the 9th hour and begins working again. The job is done in ten hours. What was the ratio of the work performed by the fastest worker as compared to the slowest?
A.42 to 1
B.30 to 7
C.5 to 1
D.1 to 6
Answer: B.30 to 7
Explanation: The fastest worker who does 3 units of job worked for all 10 hours, so he did 3*10=30 units of job;
The slowest worker who does 1 unit of job worked for only 5+2=7 hours (first 5 hours and last 2 hours), so he did 1*7=7 units of job;
The ratio thus is 30 to 7.
Answer: B.
Question: The cost price of 16 articles is equal to the selling price of 11 articles. Find the profit percent?
A.18 2/15
B.45 5/11
C.36 2/14
D.18 2/16
Answer: B.45 5/11
Explanation: 16 CP = 11 SP
11 --- 2 CP
100 --- ? =>45 5/11%.Answer: B
Question: For a party 240 guests were invited.Contracted have gained 12.5% profit but 30 guest were absent.He charged same cost , lost 100 rs. what is the meal cost?
A.20/3
B.80/3
C.10/3
D.40/3
Answer: B.80/3
Explanation: Let Cost of one meal be x.
Hence, C.P. of 240 meals = 240 x.
Since contractor gains 12.5 % profit therefore
total selling price = 240x + 240*12.5/100 x
= 270x.
Now 30 guest were absent.
Therefore C.P will remain same = 240x
And new S.P for 210 guest = (270/240 ) *
210 x
In this case he incurrs a loss of Rs 100.
240x - (9/8) x * 210 = 100
x=80/3.
So, cost of one meal is Rs. 80/3.
ANSWER:B
Question: Present ages of Sameer and Anand are in the ratio of 5:4 respectively. Three years hence, the ratio of their ages will become 11:9 respectively. What is Anand's present age in years?
A.24
B.25
C.26
D.27
Answer: A.24
Explanation: Let the present ages of Sameer and Anand be 5x and 4x years respectively.
Then, (5x + 3)/(4x + 3) = 11/9
9(5x + 3) = 11(4x + 3) => x = 6
Anand's present age = 4x = 24 years.
ANSWER:A
Question: A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 10 per metre of cloth. What is the cost price of one metre of cloth?
A.26
B.95
C.90
D.42
Answer: B.95
Explanation: SP of 1m of cloth = 8925/85 = Rs. 105
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 10 = Rs. 95
Answer:B
Question: The sum of the numbers is 550. If the first number be twice the second and third number be one-third of the first, then the second number is:
A.48
B.150
C.72
D.84
Answer: B.150
Explanation: Let the second number be x. Then, first number = 2x and third number = 2x/3.
2x + x + 2x/3 = 550
11x/3 = 550
x = 150
ANSWER:B
Question: In how many ways can a committee consisting of three men and four women be formed from a group of six men and seven women?
A.⁶C₄ ⁷C₃
B.⁶C₃ ⁷C₅
C.⁷C₄ ⁶C₃
D.⁶C₃ ⁷C₃
Answer: C.⁷C₄ ⁶C₃
Explanation: The group contain six men and seven women
Three men can be selected from six men in ⁶C₃ ways.
Four women can be selected from seven women in ⁷C₄ ways.
Total number of ways = (⁷C₄)(⁶C₃).
Answer:C
Question: A Sum of Rs.2600, is lent out in 2 parts SI at 10% for 5yrs is equal to SI on 2nd part at 9% rate for 6 yrs. find the ratio of parts.
A.13:15
B.27:25
C.15:17
D.17:19
Answer: B.27:25
Explanation: Solution :
Given SI1 = SI 2
P1 : P2 = 1/R1T1 : 1/R2T2
= 1/(10*5) : 1/(9:6)
27:25
B
Question: Anand and Deepak started a business investing Rs. 4,500 and Rs. 8,000 respectively. Out of a total profit of Rs. 3,000. Deepak's share is?
A.s. 1600
B.s. 1500
C.s. 2450
D.s. 1920
Answer: D.s. 1920
Explanation: Ratio of their shares = 4500 : 8000 = 9 : 16
Deepak's share = Rs. (3000 * 16/25) = Rs. 1920 ANSWER "D
Question: What will be the difference in simple and compound interest on 7000 after three years at the rate of 10 percent per annum?
A.160
B.42
C.62
D.217
Answer: D.217
Explanation: For 3 years:
Diff.=Sum×(rate)2(300+rate)/(100)3
= 7000×10×10×310/100×100×100 = 217
Answer D
Question: 16 men went to a restaurant. Fifteen of them paid Rs.80 each and the sixteenth man paid Rs.75 more than the average of all the 16 men. What is the total bill?
A.1360
B.1560
C.1660
D.1760
Answer: A.1360
Explanation: 15 paid Rs.80 each = 15*80 = 1200
total = x
then 16th man would have paid = x-1200
that is = 75+(x/16)
((x/16)=average)
equating these two
x-1200 = 75+(x/16)
x-(x/16)= 1275
15/16x = 1275
x = 1275*16/15
x = 1360
ANSWER:A
Question: A is thrice as efficient as B and is, therefore, able to finish a piece of work 10 days earlier than B. In how many days A and B will finish it together?
A.3 1/2 days
B.3 4/5 days
C.3 days
D.5 days
Answer: D.5 days
Explanation: Explanation:
WC = 3:1
WT = 1:3
x 3x
1/x – 1/3x = 1/10
x = 20/3
3/20 + 1/20 = 1/5 => 5 days
Answer: D
Question: A book store bought copies of a new book by a popular author, in anticipation of robust sales. The store bought 400 copies from their supplier, each copy at wholesale price x. The store sold the first 150 copies in the first week at 80% more than x, and then over the next month, sold a 100 more at 20% more than x. Finally, to clear shelf space, the store sold the remaining copies to a bargain retailer at 40% less than x. What was the bookstore’s net percent profit or loss on the entire lot of 400 books?
A. 30% loss
B. 10% loss
C. 10% profit
D. 20% profit
Answer: D. 20% profit
Explanation: [[x(150)(1.8)+x(100)(1.2)+x(150)(0.6)]/400x] - 1
[50[(3)(1.8) + (2)(1.2) + (3)(0.6)] / (50)(8)] - 1
[(5.4 + 2.4 + 1.8)/8] - [8/8]
+1.6/8
+20%
answer is D
Question: A dice is rolled 3times & sum of 3 no.'sappearing on the uppermost face is 15. The chance that the first roll was four is?
A.2/113
B.3/114
C.1/108
D.2/119
Answer: C.1/108
Explanation: Sol. Total number of favorable outcomes n(S) . e . 216 Combinations of outcomes for getting sum of 15 on uppermost face = (4, 5, 6) (5, 4, 6) (6, 5, 4) (5, 6, 4), (4, 6, 5), (6, 4, 5), (5, 5, 5), (6, 6, 3), (6, 3, 6) (3, 6, 6) Now outcomes on which first roll was a four, n(E) = (4, 5, 6), (4, 6, 5) P(E) n(E) 2 1 Pt') = n(S) = 216 = 1/108
C
Question: Two persons start running simultaneously around a circular track of length 300 m from the same point at speeds of 15 km/hr and 25 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions?
A.16 seconds
B.17 seconds
C.19 seconds
D.27 seconds
Answer: D.27 seconds
Explanation: Time taken to meet for the first time anywhere on the track
= length of the track / relative speed
= 300 / (15 + 25)5/18 = 300* 18 / 40 * 5
= 27 seconds.
Answer: D
Question: The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years
A.A)3:4
B.of these
C.C)4:3
D.inadequate
Answer: B.of these
Explanation: Let P's age and Q's age be 6x and 7x years respectively.
Then, 7x - 6x = 4 => x = 4
Required ratio = (6x + 4) : (7x + 4)
28 : 32 = 7:8
ANSWER:B
Question: If x is equal to the sum of the integers from 50 to 70, inclusive, and y is the number of even integers from 50 to 70, inclusive, what is the value of x + y?
A.1211
B.1231
C.1251
D.1271
Answer: D.1271
Explanation: x = 50 + 51 +...+ 70 = 21(60) = 1260
y = 11
x+y = 1271
The answer is D.
Question: Jordan took a bus from home to market, that travels at 20 kmph. While walking back at 2 kmph,
halfway through, he suddenly realized he was getting late and he cycled back the remaining distance in 10 kmph. Find the average speed.
A.2.9 kmph
B.4.3 kmph
C.5.1 kmph
D.1.8 kmph
Answer: A.2.9 kmph
Explanation: Let the distance be 2x(one way)
Time taken by bus = 2x/20, by walking =x/2, by cycling = x/10 hours
:. Average speed = Total Distance/Total time
= 2x / x/10 + x/2 + x/10
= 2 *60 / 6+30+6
= 2.9
ANSWER:A
Question: A is twice as good a workman as B and together they finish a piece of work in 18 days. In how many days will A alone finish the work?
A.27 days.
B.32 days.
C.18 days.
D.33 days.
Answer: A.27 days.
Explanation: A
27 days.
If A takes x days to do a work then B takes 2x days to do the same work.
--> 1/x+1/2x = 1/18
--> 3/2x = 1/18
--> x = 27 days.
Hence, A alone can finish the work in 27 days.
Question: What is the lowest positive integer that is divisible by each of the integers 1 through 9 inclusive?
A.420
B.840
C.1260
D.2520
Answer: D.2520
Explanation: We have to find the LCM of 1, 2, 3, 2^2, 5, 2*3, 7, 2^3, and 3^2.
The LCM is 1*2^3*3^2*5*7= 2520
The answer is D.
Question: At a recent small town election for mayor a total of 963 votes were cast for the four candidates, the winner exceding his opponents by 53, 79 and 105 votes, respectively. How many votes were cast for each candidate?
A.134
B.178
C.195
D.166
Answer: C.195
Explanation: C
195
The number of votes the winning candidate received was
963 + 53 + 79 + 105	/4= 300.
The second received 300 – 53 = 247,
The third received 300 – 105 = 195.
Question: A palindrome is a number that reads the same forward and backward, such as 242. How many even three-digit numbers are palindromes?
A.40
B.400
C.500
D.5,000
Answer: A.40
Explanation: if the palindrome must be even, it must begin and end in 2,4 6 and 8 ( 4 ways) e.g 212,414.
The middle number in the three-digit could be 0-9 ( 10 ways), e.g 252, 282
we thus have, 4 *10 = 40.
A
Question: A sum of money deposited at compound interest (compounded yearly) amounts to $1210 in 2 years and to $1452 in 3 years. What is the interest rate?
A.20%
B.10%
C.60%
D.70%
Answer: A.20%
Explanation: 1452 - 1210 = 242
242 / 1210 = 0.2 = 20%
The answer is A.
Question: Convert the following into a fraction: 0.3%
A.1/3
B.2/3
C.3/10
D.1/6
Answer: C.3/10
Explanation: 0.3 =3/10
Answer is C.
Question: In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100?
A.33
B.67
C.25
D.66
Answer: C.25
Explanation: A scores 60 while B score 40 and C scores 30.
The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.
In a game of 100 points, B gives (100 - 75) = 25 points to C.
Answer: C
Question: The value of 48 ÷ 12 x (9/8 of 4/3 ÷ 3/4 of 2/3) is ?
A.1 1/3
B.5 1/3
C.3
D.12
Answer: D.12
Explanation: Answer
Given expression = 48/12 x (3/2 ÷ 1/2)
= 4 x (3/2) x 2
= 12
Option: D
Question: There are a lot of houses such that the numbers of their doorplates are odd numbers and the first number of the doorplates is 685, the last number of the doorplates is 705. How many houses are there?
A.12
B.11
C.13
D.9
Answer: B.11
Explanation: So it starts from 685 and goes like 687, 689,...... 705. and both first and last number are inclusive. Since every other number is odd, it's just 1/2 of the numbers and since it starts with an odd and ends with an odd inclusive add one to the result.
i.e., ([705-685][/2]+1 = 11
Ans B
Question: A and B starts a business investing Rs.85000 and Rs.15000 respectively. Find out the ratio in which the profits should be shared.
A.3:17
B.17:3
C.10:3
D.3:10
Answer: B.17:3
Explanation: Here A's and B's capitals are there for equal time. Hence
A : B = 85000 : 15000
= 85 : 15
= 17 : 3
Answer is B.
Question: A jar is filled with red, white, and blue tokens that are equivalent except for their color. The chance of randomly selecting a red token, replacing it, then randomly selecting a white token is the same as the chance of randomly selecting a blue token. If the number of tokens of every color is a multiple of 5, what is the smallest possible total number of tokens in the jar?
A. 9
B. 12
C. 15
D. 18
Answer: B. 12
Explanation: (Red / Total Coins)*(White / Total Coins) = (Blue / Total Coins)
i.e. Red*White = Blue*Total Coins
Let, Red = 3a
White = 3b
Blue = 3c
Total Coins = 3(a+b+c)
i.e. 3a * 3b = 3c*3(a+b+c)
i.e. a*b = c*(a+b+c)
For smallest values of a, b and c
2*3 = 1*(1+2+3)
i.e. Minimum Total Coins = 3*(1+2+3) = 12
Answer: Option B