RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Rs.320 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins?
A.388
B.266
C.120
D.240
Answer: D.240
Explanation: 4x 5x 6x
100 50 25
400x + 250x + 150x = 32000
x = 40
6x = 240
Answer: D
Question: Tough and Tricky questions: Work/Rate Problems.
If it takes 70 workers 3 hours to disassemble the exhibition rides at a small amusement park, how many hours would it take 15 workers to do this same job?
A.14
B.11
C.7
D.7/3
Answer: A.14
Explanation: 70 Workers = 3 hours then,
1 Worker = 3*70 Hours
30 Workers = (3*70) /(15) = 14 Answer. A
Question: Tom found a box of 220 baseball cards. Being a thoughtful older brother, he wanted to save at least 40 percent of the cards for himself and split the remaining cards evenly among his 4 younger brothers. What is the lowest possible number of cards that Tom can save for himself that will also allow each of his 4 younger brothers to get an equal number of cards?
A.110
B.112
C.116
D.118
Answer: A.110
Explanation: This question can be easily solved by looking at the options.
Assuming number of cards to be x
We need to find the option for which (1/4)*(2x/5) is an integer
Or x/10 is an integer.
Hence we need the lowest multiple of 10 from the given options.
Let us start from the lowest value:
Option A: 110. This is not a multiple of 10
Option B: 112 = 10*11. This is a multiple of 10. Hence the correct answer.
Correct Option: A
Question: A train passes a man standing on the platform. If the train is 130 meters long and its speed is 72 kmph, how much time it took in doing so?
A.6 Â½ sec
B.6 Â½ sec
C.9 Â½ sec
D.8 Â½ sec
Answer: B.6 Â½ sec
Explanation: B
6 Â½ sec
S = 72 * 5/18 = 20 mps
T = 130/20 = 6 Â½ sec
Question: In an election between two candidates, 10% of votes are were declares invalid. First candidate got 1800 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was?
A.10000
B.12000
C.13000
D.14000
Answer: A.10000
Explanation: 100 % - 10 % = 90 %
54%-36%=18%
18% ------> 1800 ( 18 × 100 = 1800)
100% -------> 10000 votes (100 × 100 = 10000)
A)
Question: There are cats got together and decided to kill the mice of 999919. Each cat kills equal number of mice and each cat kills more number of mice than cats there were. Then what are the number of cats?
A.941,1009
B.991,1001
C.991,1009
D.791,1009
Answer: C.991,1009
Explanation: 999919 can be written as 1000000 – 81
= 10002 – 92 ie of the form a2-b2=(a+b)(a-b)
=(1000+9)*(1000-9)
= (1009)*(991)
Given that number of cats is less than number if mice.
So number of cats is 991 and number of mice were 1009
Answer C
Question: In an election between two candidates, 75 % of the voters cast their votes, out of which 2% of the votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the total number of votes.
A.16800
B.15800
C.16700
D.15700
Answer: A.16800
Explanation: Explanation:
Let the total number of votes enrolled are x.
Number of votes cast = 75% of x
Valid votes = 98% of 75% of x
Now, as 9261 is the 75% of valid casted votes so,
75% of 98% of 75% of x = 9261 [imporant]
=>75Ã—98Ã—75Ã—x/100Ã—100Ã—100=9261
=>x=16800
ANSWER IS A
Question: Two trains which have lengths of 150 m are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?
A.7.6
B.7.1
C.6.8
D.7.2
Answer: D.7.2
Explanation: D = 150m + 150m = 300m * 1/1000 = 0.3 kms
RS = 70 + 80 = 150 kmph
T = (0.3/150) * 3600 = 7.2 sec
ANSWER:D
Question: In the parking lot there are 38 vehicles, 21 of them are buses, and the rest are cars. The color of 23 vehicles is red, of which 15 are buses. How many cars can be found in the parking lot which are not colored red?
A.7
B.8
C.9
D.10
Answer: C.9
Explanation: The number of cars is 38-21 = 17.
The number of red cars is 23-15=8.
The number of cars which are not red is 17-8=9.
The answer is C.
Question: A person spends 1/5th of his income on the education of his children, and 20% of the remaining on food. If he is left with Rs.576 find his income?
A.900
B.906
C.988
D.917
Answer: A.900
Explanation: X * 4/5 * 80/100 = 576
X = 14400/16
X = 900
Answer: A
Question: On a certain plane, 2/5 of the passengers speak Hindi and 3/4 speak Hebrew. If all of the passengers on the plane speak at least one of these languages, what is the smallest number of passengers that could be on the plane?
A.12
B.15
C.60
D.74
Answer: C.60
Explanation: Assume the total members = x
Hindi = .4x
Hebrew = .75x
Hindi + Hebrew = 1.15x, but this is not possible hence 15 people speak both languages.
Only Hindi= .25x, Only Hebrew = .6x, both = .15x
Since these are all people, all of these should be whole numbers.
Checking the options:
A. 12. Only Hebrew = 12*0.6 = 7.2 We do not get the people as whole numbers. INCORRECT
B. 15. Only Hindi= 0.25*15 Again we do not get the people as whole numbers. INCORRECT
C. 60 Only Hindi= .25*60 = 15, Only Hebrew = .6*60 = 36, both = .15*60 = 9. We have the people as whole numbers. CORRECT
D.74
E. 80
Since we have to find the lowest number, no need to calculate for the rest of the options.
Correct Option: C
Question: The true discount on Rs. 2562 due 4 months hence is Rs. 122. The rate percent is?
A.33
B.38
C.15
D.36
Answer: C.15
Explanation: Explanation:
P.W = 2562-122 =Rs.2440
\inline \fn_jvn Rate=\frac{100\times 122}{2440\times \frac{1}{3}}
=15%
Answer: C) 15%
Question: In a particular 100 meter race, 4 athletes are participating that are numbered 1-4. In how many ways can athlete #4 finish ahead of #2 provided there's no tie among the athletes?
A.8
B.12
C.16
D.20
Answer: B.12
Explanation: The total number of ways for the athletes to finish is 4! = 24.
#4 will be ahead of #2 in exactly half of these possibilities.
24/2 = 12
The answer is B.
Question: There are 4 more women than there are men on a local co-ed softball team. If there are a total of 20 players on the team, what is the ratio of men to women?
A.8/12
B.6/16
C.4/16
D.6/10
Answer: A.8/12
Explanation: w = m+4
w+m = 20
m+4+m = 20
2m = 16
m = 8
w = 12
ratio:8:12
Ans: A
Question: How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 13 inches than that of a rectangular sheet of paper measuring 6.5 inches by 11 inches?
A.50%
B.87%
C.100%
D.187%
Answer: C.100%
Explanation: Let's just look at the dimensions (no calculation needed).
With dimension 11 the same, the other dimension 13 is twice 6.5
Then the area will be double which means 100% greater.
The answer is C.
Question: The amount of time that three people worked on a special project was in the ratio of 4 to 3 to 5. If the project took 120 hours, how many more hours did the hardest working person work than the person who worked the least?
A.25 hours
B.30 hours
C.20 hours
D.26 hours
Answer: C.20 hours
Explanation: Let the persons be A, B, C.
Hours worked:
A = 4*120/12 = 40 hours
B = 3*120/12 = 30 hours
C = 5*120/12 = 50 hours
C is the hardest worker and B worked for the least number of hours. So the difference is 50-30 = 20 hours.
Answer : C
Question: Certain stocks in January were 10% less than they were in February and 20% greater than they were in March. What was the percentage decrease in the stocks from February to March?
A.5%
B.10%
C.20%
D.25%
Answer: D.25%
Explanation: Let J,F,M be the values of the stock in Jan,Feb and March.
Thus, per the question, J = 0.9F = 1.2M ----> M =0.75F
Thus the % decrease from F to M = (F-M)/(F) *100 = (F-0.75F)/F * 100 = 0.25*100 = 25 %, D is the correct answer.
Question: If a man walks at the rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at the rate of 6 kmph, he reaches the station 5 minutes before the arrival of the train. Find the distance covered by him to reach the station.
A.8 km
B.6 km
C.12 km
D.9 km
Answer: B.6 km
Explanation: Sol. Let the required distance be x km
Difference in the time taken at two speeds=1 min =1/2 hr
Hence x/5-x/6=1/5<=>6x-5x=6
x=6
Hence, the required distance is 6 km
Ans:B
Question: A, B and C shared the profit in a business in the ratio 5 : 7 : 8. They had partnered for 14 months, 8 months and 14 months respectively. What was the ratio of their investments?
A.10:12:14
B.12:24:28
C.20:22:12
D.20:49:32
Answer: D.20:49:32
Explanation: Explanation :
Ratio in which A,B and C shared the profit = 5 : 7 : 8
Assume that the ratio of their investment = a:b:c
Then 14a : 8b : 14c = 5 : 7 : 8
Good to go, we got the equation. Now it's a matter of time to find a, b and c
14a/8b = 5/7
=> 98a = 40b
=> b = 98a/40 = 49a/20 ---(1)
14a/14c =5/8
=> a/c =5/8
=>8a = 5c
=> c = 8a/5 ---(2)
a : b : c = a : 49a/20 : 8a/5 = 1 : 49/20 : 8/5 = 20 : 49 : 32. Answer : Option D
Question: a father is 5 times as faster as son in doing a work. Father completes a particular work in 40 days before son.If both of them work together in how many days can they complete the work?
A.8.33days
B.9.33days
C.10.33days
D.7.33days
Answer: A.8.33days
Explanation: f=5*s
f(t-40)=w=s*t
5*s*(t-40)=s*t
5t-t=200
t=50
father takes 10 day
son takes 50 days
together=50/6=8.33days
ANSWER:A
Question: The radius of a sphere is increased by 10%. The surface area increases by?
A.21%
B.31%
C.41%
D.51%
Answer: A.21%
Explanation: Since 4 x pi x radius x radius = surface area.
Therefore, net % change in area
= ( x + y + xy/100) %
= [10 + 10 + (10 x 10)/100]% or 21%.
ANSWER:A
Question: the hiker walking at a constant rate of 4 miles per hour is passed by a cyclist traveling in the same direction along the same path at 15 miles per hour. the cyclist stops to wait for the hiker 5 minutes after passing her, while the hiker continues to walk at her constant rate, how many minutes must the cyclist wait until the hiker catches up?
A.20
B.55/4
C.25
D.14
Answer: B.55/4
Explanation: After passing the hiker the cyclist travels for 5 minutes at a rate of 15 miles/hour.
In those 5 mins the cyclist travels a distance of 5/4 miles.
In those 5 mins the hiker travels a distance of 1/3 miles.
So the hiker still has to cover 11/12 miles to meet the waiting cyclist.
The hiker will need 55/4 mins to cover the remaining 11/12 miles.
So the answer is B.
Question: Two pipes P and Q can fill a cistern in 12 and 17 minutes respectively. Both are opened together, but at the end of 3 minutes the first is turned off. How much longer will the cistern take to fill?
A.11 1/2 min
B.11 1/4 min
C.12 3/4 min
D.11 1/5 min
Answer: C.12 3/4 min
Explanation: 3/12 + x/17 = 1
x= 12 3/4
Answer: C
Question: If 4 (A's capital) = 6 (B's capital) = 10 (C's capital), then out of a profit of Rs. 930, C will receive
A.233
B.180
C.900
D.287
Answer: B.180
Explanation: Explanation:
Let 4A = 6B = 1OC = k. Then, A = k/4, B = k/6, and C =k/10 .
A : B :C = k/4 : k/6 : k/10 = 15 : 10 : 6.
Hence, C's share (930 * 6/31) = Rs, 180.
Answer: B) Rs.180
Question: Two numbers are in the ratio of 5:7. If 25 be subtracted from each, they are in the ratio of 35:59. Find the numbers?
A.60,88
B.60,86
C.60,82
D.60,84
Answer: D.60,84
Explanation: (5x-25):(7x-25)
= 35:59
x = 12
=>60,84
Answer: D
Question: Three persons A, B and C divide a certain amount of money such that A's share is Rs.4 less than half of the total amount. B's share is Rs.8 more than half of what is left and finally C takes the which is Rs.14. Find the total amount they initially had with them?
A.77
B.66
C.80
D.99
Answer: C.80
Explanation: Let the total amount be Rs.P
Let shares of A and B be Rs.X and Rs.Y respectively.
Given, C's share was Rs.14.
X + Y + 14 = P --- (1)
From the given data, X = P/2 - 4 --- (2)
Remaining amount = P - (P/2 - 4) = P/2 + 4
Y = 1/2(P/2 + 4) + 8
=> P/4 + 10 --- (3)
From (1), (2) and (3)
P/2 - 4 + P/4 + 10 + 14 = P
=> 3P/4 + 20 = P
=> P - 3P/4 = 20
=> P/4 = 20 => P = Rs.80
Answer:C
Question: A student chose a number, multiplied it by 5, then subtracted 138 from the result and got 102. What was the number he chose?
A.48
B.120
C.130
D.140
Answer: A.48
Explanation: Solution:
Let xx be the number he chose, then
5⋅x−138=102
5x=240
x=48
Answer A
Question: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?
A.3 kmph
B.1.5 kmph
C.13 kmph
D.6.5 kmph
Answer: B.1.5 kmph
Explanation: Explanation:
72 --- 9 DS = 8
? ---- 1
45 ---- 9 US = 5
? ---- 1 S = ?
S = (8 - 5)/2 = 1.5
Answer: Option B
Question: Let S be the set of values which can be written as the sum of 5 consecutive perfect squares.
What is the smallest element of S which is divisible by 17?
A.255
B.355
C.522
D.355
Answer: A.255
Explanation: Each element of S can be written in the form
(x- 2)2 + (x - 1)2 + x2 + (x + 1)2 + (x + 2)2 = x2 + 2x2 + 2 + 2x2 + 8
= 5x2 + 10
= 5(x2 + 2)
where x is some positive integer with x 3. By iterating over values of x, we observe that when
x = 7, x2 + 2 = 51 = 3 * 17; no smaller value of x exists which satisfies the problem statement.
Hence, the solution is 5(x2 + 2) = 5 *51 = 255
correct answer A
Question: Joe went on a diet 4 months ago when he weighed 212 pounds. If he now weighs 188 pounds and continues to lose at the same average monthly rate, in approximately how many months will he weigh 160 pounds?
A. 3
B. 3.5
C. 4
D. 4.5
Answer: D. 4.5
Explanation: 212 - 188 = 24 pounds lost in 4 months
24/4 = 6, so Joe is losing weight at a rate of 6 pounds per month.
...in approximately how many months will he weigh 160 pounds?
A simple approach is to just list the weights.
Now: 188 lbs
In 1 month: 182 lbs
In 2 months: 176 lbs
In 3 months: 170 lbs
In 4 months: 164 lbs
In 5 months: 158 lbs
Since 160 pounds is halfway between 164 and 158, the correct answer must be 4.5 months.
Answer: D
Question: At a recent small town election for mayor a total of 975 votes were cast for the four candidates, the winner exceeding his opponents by 53, 79 and 105 votes, respectively. How many votes were cast for the candidate in fourth place?
A.134
B.178
C.198
D.166
Answer: C.198
Explanation: The number of votes the winning candidate received was
975 + 53 + 79 + 105	/4= 303.
The second received 303 – 53 = 247,
The fourth place received 303 – 105 = 198.
C
Question: Find the value of x from the below equation? : x^2-16 = 0
A.8
B.16
C.-4
D.1
Answer: C.-4
Explanation: a = 1, b = 0, c = -16
x1,2 = (0 Â± âˆš(0^2 - 4Ã—1Ã—-16)) / (2Ã—1) = (0Â± âˆš(64)) / 2 = (0 Â± 8) / 2
x1 = (0 + 8)/2 = 8/2 = 4
x2 = (0-8)/2 = -8/2 = -4
C
Question: The compounded ratio of (2 : 3), (6: 11) and (11 :2) is :
A.1:2
B.5:9
C.2:1
D.11:24
Answer: C.2:1
Explanation: Answer: Option C
2/3 : 6/11 : 11/2 = 2:1
Question: Excluding stoppages, the speed of a bus is 90 km/hr and including stoppages, it is 84 km/hr. For how many minutes does the bus stop per hour?
A.18 min
B.4 min
C.8 min
D.6 min
Answer: B.4 min
Explanation: Due to stoppages, it covers 6 km less.
Time taken to cover 6 km = 6/90 * 60
= 4 min.
Answer:B
Question: In how many ways can the letters of the word ABCdef be rearranged such that the lower case letters always appear together?
A.196
B.255
C.299
D.144
Answer: D.144
Explanation: ABCdef
def will come together as a group which can be arranged in 3!=6ways.
def,A,B,C can be arranged in 4!=24 ways.
total possible arrangements = 6*24=144ways
ANSWER:D
Question: Positive Integer A gives the remainder of 9 when divided by another positive Integer B. If A/B = 47.45, what is the value of B?
A.96
B.75
C.48
D.20
Answer: D.20
Explanation: I think the answer should be 25.
This is how i solved.
.45 of B = Remainder
.45 of B = 9
B = (9 *100) / 45 = 20.
D
Question: If Mason is now twice as old as Gunther was 5 years ago, and G is Gunther's current age in years, which of the following represents the sum of Mason and Gunther's ages 10 years from now?
A.3G+14
B.3G+8
C.3G+15
D.3G+10
Answer: D.3G+10
Explanation: G is Gunther's current age.
Let Mason's current age be M.
given M = 2(G-5).
four years from now Mason's age will be = 2(G-5) + 10 = 2G
four years from now Gunther's age will be = G+10
Sum of ages of Mason and Gunther's after 4 years = 2G+G+10 = 3G+10
Ans : D
Question: A sum of Rs. 1000 amounts to Rs. 1200 in 4 years at the rate of simple interest. What is the rate of interest?
A.7%
B.9%
C.5%
D.6%
Answer: C.5%
Explanation: S.I. = (1200 - 1000) = Rs. 200\
Rate = (100 * 200) / (1000* 4)
= 5%
Answer: C
Question: If a(a - 6) = 7and b(b -6) = 7, where a ≠ b, then a + b =
A.−48
B.−2
C.6
D.9
Answer: C.6
Explanation: i.e. if a = -1 then b = 7
or if a = 7 then b = -1
But in each case a+b = -1+7= 6
Answer: option C
Question: Molly is rolling a number cube with faces numbered 1 to 6 repeatedly. When she receives a 2, she will stop rolling the cube. What is the probability that Molly will roll the die less than 3 times before stopping?
A.11/180
B.11/36
C.25/216
D.91/216
Answer: B.11/36
Explanation: The probability that Molly will roll the die less than 4 times before stopping is the sum of the following:
The probability that Molly will roll the die once: P=1/6 (she gets 2 on the first roll);
The probability that Molly will roll the die twice: P=5/6*1/6 (not 2, 2);
P = 1/6 + 5/6*1/6 = 11/36
Answer: B
Question: On a Monday in a certain restaurant, 30 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?
A.15%
B.16%
C.18%
D.22%
Answer: D.22%
Explanation: 30% of 180= 54
10% of 120=12
Total =66
percent for 2 days combined =66/300=0.22. so it should be less than 0.22 so it is 22%
Answer:D
Question: Find large number from below question The difference of two numbers is 1015. On dividing the larger number by the smaller, we get 9 as quotient and the 15 as remainder
A.1209
B.1324
C.1245
D.1140
Answer: D.1140
Explanation: Let the smaller number be x. Then larger number = (x + 1015).
x + 1015 = 9x + 15
8x = 1000
x = 125
Large number = 125+1015= 1140
Answer : D
Question: Albert buys 4 horses and 9 cows for Rs. 13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs. 1880. The cost of a horse is:
A.Rs.2007
B.Rs.2000
C.Rs.2089
D.Rs.2067
Answer: B.Rs.2000
Explanation: Let C.P. of each horse be Rs. x and C.P. of each cow be Rs. y.
Then, 4x + 9y = 13400 -- (i)
And, 10% of 4x + 20% of 9y = 1880
2/5 x + 9/5 y = 1880 => 2x + 9y = 9400 -- (ii)
Solving (i) and (ii), we get : x = 2000 and y = 600.
Cost price of each horse = Rs.2000.
Answer:B
Question: Three coins are tossed. Find the probability of at most 2 tails ?
A.1/2
B.1/4
C.2/3
D.7/8
Answer: D.7/8
Explanation: n(s) = 2^3 = 8
let E is the event of getting at most 2 tails
n(E) = HHH, TTH , HTT, THT, HHT, HTH, THH = 7
P(E) = n(E) / n(s)
= 7/8
Ans- D
Question: A trader marked the selling price of an article at 40% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of :
A.10 %
B.7.8 %
C.11 %
D.12.5 %
Answer: B.7.8 %
Explanation: Sol.
Let C.P. = Rs. 100. Then, Marked Price = Rs. 140, S.P. = Rs. 99.
∴ Discount % = [11/140 * 100] % = 7.8%
Answer B
Question: The price of an item is discounted 10 percent on day 1 of a sale. On day 2, the item is discounted another 10 percent, and on day 3, it is discounted an additional 30 percent. The price of the item on day 3 is what percentage of the sale price on day 1?
A.28%
B.63%
C.64.8%
D.70%
Answer: B.63%
Explanation: Let initial price be 1000
Price in day 1 after 10% discount = 900
Price in day 2 after 10% discount = 810
Price in day 3 after 30% discount = 567
So, Price in day 3 as percentage of the sale price on day 1 will be = 567/900*100 => 63%
Answer will definitely be (B)
Question: Two friends P & Q started a business investing amounts in the ratio of 5 : 6. R joined them after six months investing an amount equal to that of Qâ€™s amount. At the end of the year 28% profit was earned which was equal to 98,000. What was the amount invested by R?
A.2,10,000
B.1,05,000
C.75,000
D.Data inadequate
Answer: C.75,000
Explanation: Ratio for amount invested by P, Q & R
= 5x Ã— 12 : 6x Ã— 12 : 6x Ã— 6
= 60x : 72x : 36x
= 5x : 6x : 3x
Profit = 98000 = 28% of T
where, T = Total amount
T = 350000
Amount received by
R = 3x /3x+6x+5x(350000)
= 75000
Answer C
Question: A man sold 20 articles for $60 and gained 20%. How many articles should he sell for $40 to incur a loss 20%?
A.20
B.36
C.40
D.50
Answer: A.20
Explanation: Production cost per article: $60*(100%-20%) / 20 = $2.40
Required production costs for a loss of 20%: $40*(100% + 20%) = $48
Number of articles to be sold for $48 to incur a 20% loss: $48 / $2.40 = 20
Thus, solution A is correct.
Question: If three people (A,B,C) want to raise $30000.00 capital to start a business as below: A raises half the amount of B and C raises 3 times the amount of A, how much A will raise?
A.A - $5000
B.B - $5005
C.C - $5010
D.D - $5015
Answer: A.A - $5000
Explanation: Let the capital raised by A is x, the capital raised by B is 2x and capital raised by C is 3x. Then, total amount raised by A, B, C is x+2x+3x = 6x = $30000.00 Hence x = $30000.00/6 = $5000.00 Answer is A.
Question: In a room filled with 6 people, all 6 people have exactly 2 siblings in the room. If two individuals are selected from the room at random, what is the probability that those two individuals are NOT siblings?
A.3/5
B.3/7
C.4/7
D.5/6
Answer: A.3/5
Explanation: The 6 people consist of two sets of 3 siblings.
The number of ways to choose 2 people is 6C2 = 15.
The number of ways to choose 2 from the first group of siblings is 3C2 = 3.
The number of ways to choose 2 from the second group of siblings is 3C2 = 3.
The number of ways to choose 2 people who are siblings is 3+3 = 6.
The number of ways to choose 2 people who are not siblings is 15-6=9.
P(the two people are not siblings) = 9/15 = 3/5
The answer is A.
Question: What is the sum of the greatest common factor and the lowest common multiple of 72 and 36?
A.120
B.150
C.145
D.108
Answer: D.108
Explanation: Prime factorization of 36 = 2 x 2 x 3 x 3
Prime factorization of 72 = 2 x 2 x 2 x 3 x 3
GCF = 36
LCM = 72
Sum = 108
Ans: D
Question: The timing of a college is from 12 p.m to 4.20 p.m. Six lectures are held in the given duration and a break of 5 minutes after each lecture is given to the students. Find the duration of each lecture.
A.52 minutes
B.45 minutes
C.30 minutes
D.39 minutes
Answer: D.39 minutes
Explanation: Explanation:
Total time a student spends in college = 4 hours 20 minutes = 260 minutes
As there are 6 lectures, the number of breaks between lectures is 5. Total time of the break = 25 minutes
Hence, the duration of each lecture is = (260 â€“ 25)/6
= 39 minutes
ANSWER D
Question: The length of the room is 10m and width is 20m. Find the cost of paving the floor by slabs at the rate of Rs.400 per sq meter?
A.70000
B.80000
C.60000
D.50000
Answer: B.80000
Explanation: l=10m w=20m
area of the floor = 10 x 20 = 200 sq m
cost of paving = 400 x 200= Rs. 80000
Answer: B
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a gain ?
A.A)657
B.B)200
C.C)438
D.D)290
Answer: B.B)200
Explanation: x = price of a book sold at loss
x*(85/100)
= (480 - x)119/100
x = 280
Price of book sold at gain = 480 - 280 = 200
Answer:B
Question: 10% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 2907, how much was it in the beginning?
A.A)3800
B.B)4200
C.C)4400
D.D)4500
Answer: A.A)3800
Explanation: X * (90/100) * (85/100) = 2907
X = 3800
ANSWER:A
Question: Which of the following cannot be divided by 3 (the sum of 3 different prime numbers)?
A.10
B.23
C.14
D.15
Answer: A.10
Explanation: Option A: 10 = 2+3+5. Sum of 3 different prime numbers.
Option B: 15 = 7+5+3. Sum of 3 different prime numbers
Option C: 24 = 19+3+2. Sum of 3 different prime numbers
Option D: 12 = this is not a sum of 3 different prime numbers.
Option E: 18 = 3 + 5 + 11. Sum of 3 different prime numbers
Since 24, 15, 12, 18 divided by 3
Correct Option: A