RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A sum is invested at compounded interest payable annually. The interest in the first two successive years was Rs. 400 and Rs. 420. The sum is
A.Rs. 8000
B.Rs. 8200
C.Rs.7500
D.Rs. 8500
Answer: A.Rs. 8000
Explanation: Explanation:
his means that, simple Interest on Rs.400 for 1 year = 420 - 400 = 20
Rate = (100 ×SI)/PT = (100 × 20)/(400×1) = 5%
Rs.400 is the interest on the sum for 1st year
Hence, sum = (100 × SI)/RT = (100 × 400)/(5 × 1) = Rs. 8000
Answer: Option A
Question: 7 men, 5 women and 8 children were given as assignment of distributing 2000 books to students in a school over a period of 3 days. All of them distributed books on the 1st day. One of the 2nd day 2 women and 3 children remained absent and on the 3rd day 3 men and 5 children remained absent. If the ratio of the no. of books distributed in a day by a man, a woman & a child was 5 : 4 : 2 respectively, a total of approximately how many books were distributed on the second day?
A.540
B.560
C.670
D.650
Answer: D.650
Explanation: Sol. Let the books distributed by man, a woman and a child be 5x, 4x and 2x respectively.
∴ No. of books distributed in 1st day
= 7×5x+5×4x+8×2x=71x
No. of books distributed in 1Ind day
=7×5x+3×4x+5×2x=57x
And no. of books distributed in IIIrd day
=4×5x+5×4x+3×2x=46x
71x + 57x + 46x = 2000, x = 2000/174
57x=2000/174×57=650
D
Question: The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling alongthe boundary ofthe park at the speed of 12 km/hr completes one round in 8 min, then the area of the park (in sq. m) is?
A.13400 m
B.147600 m
C.153600 m
D.187500 m
Answer: C.153600 m
Explanation: Perimeter = Distance covered in 8 min. = 12000 x 8 m = 1600 m.
60
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 1600 or x = 160.
Length = 480 m and Breadth = 320 m.
Area = (480 x 320) m2 = 153600 m
C
Question: The cost price of 8 articles is equal to the selling price of 5 articles. What is the profit percent?
A.30%
B.40%
C.50%
D.60%
Answer: D.60%
Explanation: 5*SP = 8*CP
SP = 1.6*CP
The profit percent is 60%.
The answer is D.
Question: Efrida and Frazer who live 10 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is three miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home?
A.6
B.7
C.8
D.10
Answer: B.7
Explanation: It's a simple geometry problem. Look at the diagram below:
Answer: B.
Question: Goldenrod and No Hope are in a horse race with 6 contestants. How many different L arrangements of finishes are there if No Hope always finishes before Goldenrod and if all of the horses finish the race?
A. 720
B. 360
C. 120
D. 24
Answer: B. 360
Explanation: no hope finishing before goldenrod= 1/2 of the times
therefore the different L arrangements are 1/2* 6! = 360 = B
Question: Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.
A.3
B.5
C.7
D.12
Answer: A.3
Explanation: Sol.
Let the number be x.
Then, x+17 = 60/x
⇔ x2 + 17x - 60 = 0
⇔ (x+20)(x-3) = 0
⇔ x = 3.
Answer A
Question: A man can row 8 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?
A.3.58
B.3.68
C.3.78
D.3.88
Answer: B.3.68
Explanation: M = 8
S = 1.2
DS = 8 + 1.2 = 9.2
US = 8- 1.2 = 6.8
x/9.2 + x/6.8 = 1
x = 3.68.Answer: B
Question: 15 binders can bind 1400 books in 21 days. How many binders will be required to bind 1600 books in 20 days?
A.18
B.86
C.16
D.10
Answer: B.86
Explanation: Binders Books Days
15 1400 21
x 1600 20
x/15 = (1600/1400) * (21/20) => x
= 18
Answer: B
Question: In what ratio mental A at Rs.68 per kg be mixed with another metal at Rs.96 per kg so that cost of alloy (mixture) is Rs.75 per kg?
A.5:8
B.3:1
C.3:7
D.9:5
Answer: B.3:1
Explanation: (96-75)/(75-68)=21/7=3/1
ANSWER:B
Question: The difference between the value of a number increased by 25% and the value of the original number decreased by 30% is 22. What is the original number?
A.40
B.50
C.65
D.70
Answer: A.40
Explanation: Let the original # be x then 1.25x−0.7x=22 --> x=40
Answer: A.
Question: A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
A.4.5 hrs
B.5 hrs
C.6.5 hrs
D.7.2 hrs
Answer: D.7.2 hrs
Explanation: Net part filled in 1 hour = (1/4 - 1/9) = 5/36
The cistern will be filled in 36/5 hrs i.e., 7.2 hrs.
ANSWER:D
Question: The units digit of (35)^(87) + (93)^(53) is:
A.2
B.4
C.6
D.8
Answer: D.8
Explanation: The units digit of powers of 3, cycles in a group of 4: {3, 9, 7, 1}
53 has the form 4k+1, so the units digit of 93^53 is 3.
The units digit of powers of 5 is always 5.
3+5 = 8, so the units digit is 8.
The answer is D.
Question: A train covers a distance of 1000 km in 10hrs. Find the speed of the train?
A.100km/hr
B.120km/hr
C.150km/hr
D.50km/hr
Answer: A.100km/hr
Explanation: Speed = 1000/10 = 100km/hr
Answer is A
Question: The distance light travels in one year is approximately 5,870,000,000,000 miles. the distance light in 100 year is
A.587 x 10power9 miles
B.587 x 10power12 miles
C.587 x 10power8 miles
D.587 x 10power-12 miles
Answer: B.587 x 10power12 miles
Explanation: the distance of the light travels in 100 years is
5,870,000,000,000 x 100 miles= 587,000,000,000,000=587 x 10 power12 miles, correct answer will be (B)
Question: If Re.50 amounts to Rs.250 over a period of 30 years. What is the rate of simple interest?
A.13.99%
B.13.66%
C.13.33%
D.13.44%
Answer: C.13.33%
Explanation: 200 = (50*30*R)/100
R = 13.33%
Answer:C
Question: A train 440 meters long is running with a speed of 45 kmph. The time taken by it to cross a tunnel 180 meters long is?
A.40.6 sec
B.41.6 sec
C.42.6 sec
D.49.6 sec
Answer: D.49.6 sec
Explanation: D = 440 + 180 =620
S = 45 * 5/18 = 12.5 mps
T = 620/12.5 = 49.6 sec
ANSWER:D
Question: 4,25,49,121,169,289,
A.361
B.169
C.189
D.209
Answer: A.361
Explanation: 19^2= 361 because follow sequence of square of the prime numbers
ANSWER:A
Question: The price of commodity X increases by 45 cents every year, while the price of commodity Y increases by 20 cents every year. In 2001, the price of commodity X was $5.20 and the price of commodity Y was $7.30. In which year will the price of commodity X be 10 cents less than the price of commodity Y?
A.2008
B.2009
C.2010
D.2011
Answer: B.2009
Explanation: The price of commodity X increases 25 cents each year relative to commodity Y.
The price difference is $2.10 and commodity X needs to be 10 cents less than commodity Y.
$2.00 / 25 cents = 8 years
The answer is 2001 + 8 years = 2009.
The answer is B.
Question: If there are 80 red and blue marbles in a jar, and the ratio of red to blue marbles is 2:3, what is the probability that, drawing twice, you will select two red marbles if you return the marbles after each draw?
A.1/25
B.2/25
C.3/25
D.4/25
Answer: D.4/25
Explanation: 30 red and blue marbles in a jar, and the ratio of red to blue marbles is 2:3
So, 5x=80 ---> x=16
Red marbles = 2*x = 2*16 = 32
Blue marbles = 3*x = 3*16 = 48
Prob to select a red marble = 32/80 = 2/5
Prob to select 2 red marbles with replacement = 2/5*2*5 = 4/25
Hence, answer will be D.
Question: If 2994 ÷14.5 = 172, then 29.94 ÷ 1.45 = ?
A.172
B.0.172
C.1.72
D.17.2
Answer: D.17.2
Explanation: Solution
(29.94/1.45)	= 299.4/14.5
= (2994/14.5×1/10)
= 172/10
= 17.2.
Answer D
Question: John makes $45 a week from his job. He earns a raise andnow makes $75 a week. What is the % increase?
A.16%
B.46.66%
C.44.44%
D.36.98%
Answer: C.44.44%
Explanation: Increase = (20/45)*100 = (4/9)*100 = 44.44%.
C
Question: If the price of gasoline increases by 25% and a driver intends to spend only 20% more on gasoline, by how much percent should the driver reduce the quantity of gasoline that he buys?
A.2%
B.3%
C.4%
D.5%
Answer: C.4%
Explanation: Let x be the amount of gasoline the driver buys originally.
Let y be the new amount of gasoline the driver should buy.
Let P be the original price per liter.
(1.25*P)y = 1.2(P*x)
y = (1.2/1.25)x = 0.96x which is a reduction of 4%.
The answer is C.
Question: If a is a positive integer then 5^(2a) + (625^a)/(5^(2a)) =
A.25^a
B.24^a
C.2 × 25^a
D.55^a
Answer: C.2 × 25^a
Explanation: 5^(2a) + 625^a/ 5^(2a) = 25^a + 625^a/25^a = 25^a + (625/25)^a = 25^a + 25^a = 2 × 25^a
Answer : C
Question: A man walks at the speed of 5 km/hr and runs at the speed of 10 km/hr. How much time will the man require to cover the distance of 28 km, if he covers half (first 14 km) of his journey walking and half of his journey running ?
A.3.2 hrs
B.5.2 hrs
C.4.2 hrs
D.8.2 hrs
Answer: C.4.2 hrs
Explanation: C
4.2 hrs
Total time required = 14/5+14/10
28+14/10 = 4.2 hrs
Question: A and B invest money in the ratio 6:7 and they has loss of Rs.7800 at the end of year. what is the share of loss of B?
A.Rs.4200
B.Rs.4300
C.Rs.4400
D.Rs.4500
Answer: A.Rs.4200
Explanation: et ratio of A and B be 6x & 7x
so net loss = 6x+7x= 7800
x=600
A=6x=6(600)=3600
B= 7x=7(600)=4200
so, B= 4200
ANSWER:A
Question: Maddie has 15 apples, if she give 8 to mike, how many does she have left?
A.1
B.7
C.3
D.4
Answer: B.7
Explanation: 15-8=7
B. 7
Question: During a certain two-week period, 72 percent of the movies rented from a video store were comedies, and of the remaining movies rented, there were 6 times as many dramas as action movies. If no other movies were rented during that two-week period and there were A action movies rented, then how many comedies, in terms of A, were rented during that two-week period?
A.1/20 A
B.10 A
C.15 A
D.18 A
Answer: D.18 A
Explanation: Movies: 72 % comedies. 28 % remaining genre.
Now in this 28 %, there are only 2 categories. Action movies and Drama Movies.
If Action = x; Drama movies = 6x. Total 7x.
7x = 28; x = 4
Action movies: 4 %
Drama movies: 24 %
we can say that out of 100z,:
comedies: 72z
action: 4z
drama: 24 z
Now action movies were A
This means:
A = 4z.
z = (A/4)
Comedies: 72z = 72 * (A/4)
18 A
D is the answer.
Question: Ashok and Pyarelal invested money together in a business and share a capital of Ashok is 1/9 of that of Pyarelal.if the incur a loss of Rs 1200 then loss of Pyarelal?
A.600
B.700
C.1080
D.900
Answer: C.1080
Explanation: Let the capital of Pyarelal be x, then capital of Ashok=x/9
So ratio of investment of Pyarelal and Ashok = x : x/9 =9x : x
Hence out of the total loss of 1200, loss of Pyarelal= 1200*9x/10x=1080
ANSWER:C
Question: The profit earned by selling an article for 832 is equal to the loss incurred when the same article is sold for 448. What should be the sale price of the article for making 50 per cent profit?
A.960
B.1060
C.1,200
D.920
Answer: A.960
Explanation: Let the profit or loss be x
and 832 – x = 448 + x or, x = 384⁄2 = 192
\ Cost price of the article = 832 – x = 448 + x = 640
\ SP of the article = 640 × 150⁄100 = 960
Answer A
Question: Twenty percent of Country Y's yearly exports come from fruit exports. One-sixth of all fruit exports from Country Y are orange exports. If country Y generates $2.5 million from its orange exports, how much money does it generate from its yearly total of exports?
A.$21.25m
B.$75m
C.$106.25m
D.$127.5m
Answer: B.$75m
Explanation: 2/10*1/6*(total) = 2.5
1/30*(total) = 2.5
(total) = 2.5*30 = 75
Answer: B.
Question: Thirty percent of the members of a swim club have passed the lifesaving test. Among the members who have not passed the test, 26 have taken the preparatory course and 65 have not taken the course. How many members are there in the swim club?
A. 60
B. 80
C. 100
D. 130
Answer: D. 130
Explanation: 30% of the members have passed the test, thus 70% have not passed the test.
We also know that 65+26=91 members have not passed the test, thus 0.7*Total=91 --> Total=130.
Answer: D.
Question: Set A = {1, 2, 3, 4, 5, 6, e}
Which of the following possible values for e would cause Set A to have the smallest standard deviation?
A. 1
B. 2.5
C. 3
D. 3.5
Answer: D. 3.5
Explanation: I agree. The mean of the set e 1,2,3,4,5,6 is 3.5 . Now if we add one extra number to the set, in order for the standard deviation to be minimum, that number must be as close as possible to the original set (1,2,3,4,5,6). Therefore we have to choose the number closest to 3,5 from the options we have, leaving D as the best choice.
Answer D.
Question: Johnny makes $6.75 per hour at his work. If he works 10 hours, how much money will he earn?
A.$67.50
B.$54
C.$28.50
D.$12.50
Answer: A.$67.50
Explanation: 6.75*10=67.50. Answer is A.
Question: In a bag there are a certain number of black balls and blue balls. The probability of picking up exactly 1 blue ball when 2 balls are randomly drawn, is 1/2. Which of the following is the ratio of the number of black balls to blue balls in the bag
A.1:2
B.1:4
C.1:1
D.1:5
Answer: C.1:1
Explanation: since the probability of drawing a blue ball out of two picks is 1/2.
the ratio of the blue ball to black balls should be 1:1
Answer : C
Question: In a partnership between A, B and C. A's capital is Rs.5000. If his share of a profit of Rs.800 is Rs.200 and C's share is Rs.130, what is B's capital?
A.23676
B.19766
C.29172
D.11750
Answer: D.11750
Explanation: Explanation:
200 + 130 = 330
800 - 330 = 470
200 ---- 5000
470 ---- ? => 11750
Answer:D
Question: If x^2+(1/x^2)=6, x^4+(1/x^4)=?
A.10
B.11
C.12
D.34
Answer: D.34
Explanation: -> x^4+(1/x^4)=(x^2)^2+(1/x^2)^2=(x^2+1/x^2)^2-2x^2(1/x^2)=6^2-2=34.
Thus, the answer is D.
Question: If the length of a rectangle is doubled and its breadth is tripled, what is the percentage change in its area?
A.200% increase
B.345% increase
C.400% increase
D.125% increase
Answer: C.400% increase
Explanation: Length is halved.
i.e., length is increased by 200%
Breadth is tripled
i.e., breadth is increased by 200%
Change in area=(−200+200+(200×200)/100)%=400%
i.e., area is increased by 400%
ANSWER:C
Question: A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning?
A.39
B.88
C.3
D.7
Answer: A.39
Explanation: Let the average after 7th inning = x
Then average after 16th inning = x - 3
\inline \fn_jvn \therefore 16(x-3)+87 = 17x
\inline \fn_jvn \therefore x = 87 - 48 = 39
Answer:A
Question: A jar contains 3 red marbles, 7 green marbles and 10 white marbles. If a marble is drawn from the jar at random, what is the probability that this marble is white?
A.0.2
B.0.3
C.0.5
D.0.7
Answer: C.0.5
Explanation: color frequency
red 3
green	7
white 10
Let P(E) be the event of getting white marble
P(E) = Frequency for white color / Total frequencies in the above table
= 10 / (3+7+10)
= 10 / 20
= 0.5
My answer is (C)
Question: Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC = 4 cm, and BD = 8 cm, what is CD, in centimeters?
A. 7
B. 2
C. 3
D. 4
Answer: A. 7
Explanation: Putting a value to each point, lets use the following:
A - 0
B - 3 (AB = 3)
C - 4 (AC = 4)
D - 11 (BD = 8)
CD is 11-4 = 7.
Ans A
Question: Find the odd man out.
1, 9, 25, 4, 36, 65, 49
A.1
B.25
C.9
D.65
Answer: D.65
Explanation: Explanation:
Each of the numbers except 65 is a perfect squares.
Answer: D) 65
Question: here are 6 periods in each working day of a school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period?
A.2100
B.1800
C.1245
D.3210
Answer: B.1800
Explanation: 5 subjects can be arranged in 6 periods in 6P5 ways.
Any of the 5 subjects can be organized in the remaining period (5C1 ways).
Two subjects are alike in each of the arrangement. So we need to divide by 2! to avoid overcounting.
Total number of arrangements
= 6P5× 5C1 /2!=1800
Ans: B
Question: A pack of baseball cards consists of 12 outfielder cards and 8 infielder cards. What is the lowest number of outfielder cards that would have to be removed from the pack so that no more than 60 percent of the pack would be outfielder cards?
A.4
B.5
C.6
D.7
Answer: B.5
Explanation: let the number of O card to be removed=X
then remaning cards=12-X
now this 12-X cards should count less than 60% of toatal Ocards
12-X<.6*12
X>12-7.2
X>4.8
X=5
Ans B
Question: A train 540 meters long is running with a speed of 54 kmph. The time taken by it to cross a tunnel 180 meters long is?
A.287 sec
B.288 sec
C.48 sec
D.16 sec
Answer: C.48 sec
Explanation: D = 540 + 180 = 720
S = 54 * 5/18 = 15 mps
T = 720/15 = 48 sec
Answer: C
Question: Given f(x) = 3x – 5, for what value of x does 2*[f(x)] + 2 = f(3x – 6)
A.0
B.4
C.5
D.7
Answer: C.5
Explanation: Answer = C = 5
f(x) = 3x – 5
2*[f(x)] + 2 = f(3x – 6)
2(3x-5) + 2 = 3 (3x-6) - 5
6x - 8 = 9x - 23
x = 5
Question: Last year, for every 100 million vehicles that travelled on a certain highway, 94 vehicles were involved in accidents. If 3 billion vehicles travelled on the highway last year, how many of those vehicles were involved in accidents? (1 billion = 1,000,000,000)
A.288
B.320
C.2,820
D.3,200
Answer: C.2,820
Explanation: To solve we will set up a proportion. We know that “100 million vehicles is to 94 accidents as 3 billion vehicles is to x accidents”. To express everything in terms of “millions”, we can use 3,000 million rather than 3 billion. Creating a proportion we have:
100/94= 3,000/x
Cross multiplying gives us:
100x = 3,000 * 94
x = 30 * 94 = 2,820
Correct answer is C.
Question: X is able to do a piece of work in 14 days and Y can do the same work in 20 days. If they can work together for 5 days, what is the fraction of work completed?
A.15/28
B.17/28
C.13/28
D.19/28
Answer: B.17/28
Explanation: Explanation :
Amount of work X can do in 1 day = 1/14
Amount of work Y can do in 1 day = 1/20
Amount of work X and Y can do in 1 day = 1/14+ 1/20= 17/140
Amount of work X and Y can together do in 5 days = 5 × (17/140) = 17/28
Answer : Option B
Question: If six persons sit in a row, then the probability that three particular persons are always together is ?
A.1/6
B.1/0
C.1/5
D.1/4
Answer: C.1/5
Explanation: Six persons can be arranged in a row in 6! ways. Treat the three persons to sit together as one unit then there four persons and they can be arranged in 4! ways. Again three persons can be arranged among them selves in 3! ways. Favourable outcomes = 3!4! Required probability = 3!4!/6! = 1/5
Answer: C
Question: #p is defined as 2p+20 for any number p. What is p, if #(#(#p))=12?
A.–16
B.–44
C.10
D.16
Answer: A.–16
Explanation: #p = 2p+20 --->#(#p) = 2(2p+20)+20 = 4p+60 and thus #(4p+60) = 2(4p+60)+20 = 8p+140 = 12 ---> 8p= -128 ---> p = -16, A is the correct answer.
Question: Two motor bikes cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower bike takes 1 hour more than the faster bike ?
A.860 km
B.870 km
C.960 km
D.260 km
Answer: C.960 km
Explanation: Explanation:
60(x + 1) = 64x
X = 15
60 x 16 = 960 km
Answer: C
Question: Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 1 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is?
A.40 gallons
B.100 gallons
C.120 gallons
D.180 gallons
Answer: A.40 gallons
Explanation: Work done by the waste pipe in 1 minute = 1/15 - (1/20 + 1/24) = - 1/40
Volume of 1/40 part = 1 gallons\
Volume of whole = 1 * 40 = 40 gallons.
ANSWER:A
Question: If the first day of a year (other than leap year) was Thursday, then which was the last day of that year?
A.Saturday
B.Thursday
C.Tuesday
D.Monday
Answer: B.Thursday
Explanation: Explanation :
Given that first day of a normal year was Thursday
Odd days of the mentioned year = 1 (Since it is an ordinary year)
Hence First day of the next year = (Thursday+ 1 Odd day) = Friday
Therefore, last day of the mentioned year = Thursday. Answer : Option B
Question: A sum of money lent out at S.I. amounts to Rs. 720 after 2 years and to Rs. 1020 after a further period of 5 years. The sum is?
A.299
B.600
C.77
D.266
Answer: B.600
Explanation: S.I for 5 years = (1020 - 720) = Rs. 300.
S.I. for 2 years = 300/5 * 2 = Rs. 120.
Principal = (720 - 120) = Rs. 600.
Answer: B
Question: Average of five consecutive even numbers is 35. Find the greatest number in these five numbers?
A.27
B.29
C.39
D.42
Answer: C.39
Explanation: 39
Option 'C'
Question: The mean of 50 observations was 36. It was found later that an observation 28 was wrongly taken as 23. The corrected new mean is :
A.36.0
B.36.5
C.36.1
D.36.2
Answer: C.36.1
Explanation: Explanation:
Correct Sum = (36 * 50 + 28 - 23) = 1825.
Correct mean = = 1805/50 = 36.1
Answer: C) 36.1
Question: There is 7 friends (A1, A2, A3....A7).If A1 have to have shake with all without repeat. How many handshakes possible?
A.6
B.21
C.28
D.7
Answer: A.6
Explanation: a1 with (a2, a3,a4,a5,a6,a7)
6 handshakes
ANSWER:A
Question: A box measuring 27 inches long by 15 inches wide by 6 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest number of cubes that can accomplish this objective?
A.90
B.180
C.210
D.240
Answer: A.90
Explanation: least number of cubes will be required when the cubes that could fit in are biggest.
3 is the biggest number that could divide all three, 27, 15 and 6.
Thus side of cube must be 3, and total number of cubes = 27/3 * 15/3*6/3 = 90
Ans A it is.
Question: The difference between a two-digit number and the number obtained by interchanging the digit is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1:2?
A.4
B.8
C.16
D.24
Answer: B.8
Explanation: Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let the ten's and unit's digits be 2x and x respectively.
Then, (10 * 2x + x) - (10x + 2x) = 36
9x = 36
x = 4
Required difference = (2x + x) - (2x - x) = 2x = 8.
ANSWER:B
Question: 12.5 * 4.2 * 8.8 = ?
A.352
B.435
C.462
D.646
Answer: C.462
Explanation: C
462
? = 12.5 * 4.2 * 8.8 = 462
Question: A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 sec. What is the length of the goods train?
A.49 sec
B.50 sec
C.48 second
D.43 sec
Answer: C.48 second
Explanation: D = 540 + 180 = 720
S = 54 * 5/18 = 15 mps
T = 720/15 = 48 sec
Answer:C
Question: 50% of a number is added to 200, the result is the same number. Find the number?
A.300
B.288
C.400
D.129
Answer: C.400
Explanation: (50/100) * X + 200 = X
x/2 +200 = x
x+400=2x
x=400
Answer : C
Question: What is the probability of getting a number less than 4 when a die is rolled?
A.1/2
B.1/6
C.1/3
D.1/4
Answer: A.1/2
Explanation: Total number of outcomes possible when a die is rolled = 6 (âˆµ any one face out of the 6 faces)
i.e., n(S) = 6
E = Getting a number less than 4 = {1, 2, 3}
Hence, n(E) = 3
P(E) = n(E)/n(S)=3/6=1/2
Answer:A
Question: If the units digit of n^39 is 7, which of the following could be the value of n?
I. n = 41
II. n = 43
III. n = 47
A.Only II
B.Only I
C.Only III
D.I and II
Answer: A.Only II
Explanation: I tried in this way.
Given n^39 units digit is 7.
If at all we have to get 7 as units digits only 3 and 7 series has 7
3^! = 3 , 3^2 = 9 , 3^3 = 27 , 3^4 = 81
7^1 = 7, 7^2 = 49 , 7^3 = 3 (units ) , 7^4 = 1 (units)
We have n^39 - then divide 39 by 4 = reminder 3.
Then we have for only 7^3 - we have units digit as 3.
Hence 47^39 = 7 (units).
Option A is correct answer , and with 41^39 we always get 1 as units digit and 43^39 - we get units as 3.
Question: The numbers {1, 3, 6, 7, 7, 7} are used to form three 2-digit numbers. If the sum of these three numbers is a prime number p, what is the largest possible value of p?
A.97
B.151
C.209
D.211
Answer: D.211
Explanation: What is the largest possible sum of these three numbers that we can form? Maximize the first digit: 76+73+71=220=even, so not a prime. Let's try next largest sum, switch digits in 76 and we'll get: 67+73+71=211=prime.
Answer: D.
Question: Worker A takes 7 hours to do a job. Worker B takes 10 hours to do the same job. How long it take both A & B, working together but independently, to do the same job?
A.70/17
B.40/9
C.50/9
D.60/9
Answer: A.70/17
Explanation: one day work of A = 1/7
one day work of B = 1/10
so one day work of A and B together = 1/7 + 1/10 = 17/70
so total days required = 70/17
ANSWER:A