RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 24 hrs and a machine of type S does the same job in 12 hours. If the company used the same number of each type of machine to do the job in 2 hours, how many machines of type R were used?
A.3
B.4
C.6
D.9
Answer: B.4
Explanation: Rate of machine R = 1/24
Rate of machine S = 1/12
Rate of R+S = 1/8
To finish the work in 2 hrs, the combined rate needs to be 1/2.
x * 1/8 = 1/2
x = 4
The answer is B.
Question: A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
A.88
B.98
C.106
D.108
Answer: D.108
Explanation: Explanation:
The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12 = 108 ways
D)
Question: Express 15 mps in kmph?
A.54
B.88
C.90
D.27
Answer: A.54
Explanation: 15 * 18/5 = 54 kmph
Answer:A
Question: A group of n students can be divided into equal groups of 4 with 1 student left over or equal groups of 5 with 2 students left over. What is the sum of the two smallest possible values of n?
A.33
B.46
C.49
D.54
Answer: D.54
Explanation: n = 4k+1 = 5j+2
Let's start at 1 = 4(0)+1 and keep adding 4 until we find a number in the form 5j+2.
1, 5, 9, 13, 17 = 5(3)+2
The next such number is 17 + 4*5 = 37.
17+37 = 54
The answer is D.
Question: A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
A.45%
B.45(5/11)%
C.54(6/11)%
D.55%
Answer: B.45(5/11)%
Explanation: Explanation:
Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 110 - (60)
= 50.
Required percentage = (50/110 x 100)% =45(5/11)%
ANSWER IS B
Question: If 60/x is an integer and 6/x is an integer, which of the following must be true? I. 6/x is an integer II. 12/x is an integer III. 15/x is an integer
A.II only
B.I only
C.III only
D.I, II only
Answer: B.I only
Explanation: The question asks which of the following MUST be true, not COULD be true. The largest possible value of x is 6, GCD of 60 and 6, and if x=6 then ONLY I is true.
Answer: B
Question: Due to construction, the speed limit along an 7-mile section of highway is reduced from 55 miles per hour to 35 miles per hour. Approximately how many minutes more will it take to travel along this section of highway at the new speed limit than it would have taken at the old speed limit ?
A. 4.37
B. 8
C. 10
D. 15
Answer: A. 4.37
Explanation: Old time in minutes to cross 7 miles stretch = 7*60/55 = 7*12/11 = 7.63
New time in minutes to cross 7 miles stretch = 7*60/35 = 7*12/7 = 12
Time difference = 4.37
Ans:A
Question: X and Y are positive two-digit integers such that the tens digit in X is the same as the units digit in Y, and the units digit in X is the same as the tens digit in Y. Which of the following could be the difference of X and Y ?
A.73
B.44
C.36
D.29
Answer: C.36
Explanation: X and Y are positive two-digit integers such that the tens digit in X is the same as the units digit in Y, and the units digit in X is the same as the tens digit in Y:
X = 10a + b
Y = 10a + b
X - Y = (10a + b) - (10a + b) = 9(a - b). As you can see the difference must be a multiple of 9. Only option C is a multiple of 9.
Answer: C.
Question: Jane covered a distance of 340 miles between city A and city B taking a total of 5 hours. If part of the distance was covered at 60 miles per hour speed and the balance at 80 miles per hour speed, how many hours did she travel at 60 miles per hour?
A.2 hours 30 minutes
B.3 hours
C.2 hours
D.1 hour 45 minutes
Answer: B.3 hours
Explanation: Explanatory Answer
Let Jane travel 'x' at 60 miles per hour.
As the total time taken to cover 340 miles is 5 hours, Jane would have traveled (5 - x) hours at 80 miles per hour.
Distance covered at 60 miles per hour = Speed * time = 60 * x = 60x miles.
Distance covered at 80 miles per hour = Speed * time = 80 (5 - x) = 400 - 80x miles.
Total distance covered = Distance covered at 60 miles per hour + Distance covered at 80 miles per hour.
Therefore, total distance = 60x + 400 - 80x.
Total distance travelled = 340 miles.
Therefore, 340 = 60x + 400 - 80x
20x = 60 or x = 3 hours.
Choice B is the correct answer.
Question: If 100<x<199 and 20<y<100, then the product xy CANNOT be equal to:
A.1900
B.19,303
C.19,356.732
D.19,502
Answer: A.1900
Explanation: Correct Answer: (A)
Determine the range of xy by multiplying the two extremes of each individual range together. The smallest value of xy must be greater than 100 * 20. The largest value must be less than 199 * 100. This means that 2000 < xy < 19,900. (A) is outside of this range, so it is not a possible product of xy.
Question: 26 buckets of water fill a tank when the capacity of each bucket is 13.5 litres. How many buckets will be required to fill the same tank if the capacity of each bucket is 9 litres?
A.30
B.39
C.60
D.Data inadequate
Answer: B.39
Explanation: Capacity of the tank = 26 Ã— 13.5= 351 litres
When the capacity of each bucket = 9 litres, then the required no. of buckets
= 351â„9 = 39
Answer B
Question: A train of length 250 m crosses a bridge of length 120m in 20 seconds. What is the speed of train?
A.33
B.27
C.66.6
D.22
Answer: C.66.6
Explanation: Sol : (length of train+ length of bridge) = speed of train x Time
(250+120) = 20 x Speed
Speed = 370/20= 18.5 m/s =66.6 km/h
ANSWER=C
Question: Two parallel sides of a trapezium are 4 cm and 5 cm respectively. The perpendicular distance between the parallel sides is 6 cm. Find the area of the trapezium.
A.24cm2
B.25cm2
C.26cm2
D.27cm2
Answer: D.27cm2
Explanation: Area of trapezium when height and two parallel sides are given = 1/2×h×(a+b)= 1/2x 6 x (4 + 5) = 27cm2
Answer D
Question: For how many values n is 2^x = x^2 ?
A.Three
B.One
C.Two
D.None
Answer: A.Three
Explanation: draw a graph with x^2 and 2^x, you'll see 3 intercepts between the 2 curves and the answer is A
Question: In a stockpile of products produced by three machines M1, M2 and M3, 40% and 30% were manufactured by M1 and M2 respectively. 3% of the products of M1 are defective, 1% of products of M2 defective, while 91% of the products of M3 III are not defective. What is the percentage of defective in the stockpile?
A.3%
B.5%
C.2.5%
D.4.2%
Answer: D.4.2%
Explanation: Explanation :
Let there be 100 products in the stockpile. 40% and 30% were manufactured by M1 and M2 respectively. So, 30% are manufactured by M3.
Products from M1 = 40, from M2 = 30 and from M3 = 30.
Number of defective products from M1 = 0.03 x 40 = 1.2, from M2 = 0.01 x 30 = 0.3 and from M3 = 0.09 x 30 = 2.7
Therefore, total number of defective products = 4.2.
Answer : D
Question: Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes. Find the amount of his profit or loss?
A.lost 10 cents
B.lost 4 cents
C.broke even
D.gained 4 cents
Answer: C.broke even
Explanation: 20 % profit on $ 1.20
= $ 20/100 × 1.20
= $ 0.20 × 1.20
= $ 0.24
Similarly, 20 % loss on $ 1.20
= $ 20/100 × 1.20
= $ 0.20 × 1.20
= $ 0.24
Therefore, in one pipe his profit is $ 0.24 and in the other pipe his loss is $ 0.24.
Since both profit and loss amount is same so, it’s broke even.
Answer is C.
Question: Find the area of a parallelogram with base 12 cm and height 10 cm?
A.297 cm2
B.384 cm2
C.120 cm2
D.267 cm2
Answer: C.120 cm2
Explanation: Area of a parallelogram
= base * height
= 12 * 10
= 120 cm2
Answer: C
Question: A license plate in the country Kerrania consists of four digits followed by two letters. The letters A, B, and C are used only by government vehicles while the letters D through Z are used by non-government vehicles. Kerrania's intelligence agency has recently captured a message from the country Gonzalia indicating that an electronic transmitter has been installed in a Kerrania government vehicle with a license plate starting with 79. If it takes the police 5 minutes to inspect each vehicle, what is the probability that the police will find the transmitter within three hours?
A.18/79
B.1/6
C.1/25
D.1/50
Answer: C.1/25
Explanation: If it takes 5 minutes to inspect one vehicle, the # of vehicles that can be inspected in 3 hours (180 minutes) = 180/5 = 36. Hence, for calculating the probability that the police will find the transmitter within three hours, the favorable cases = 36. Now, we need to figure out the total # of cases.
The total # of cases = Total # of such cars possible. The details given about the car is that it starts with 79, which leaves 2 more digits, both of which can be filled by all 10 numbers (0-9). In addition, we have 3 letters, each of which can be filled by any from the set {A,B,C}. Hence the total # of such cars possible = 10*10*3*3 = 900
So, the probability that the police will find the transmitter within three hours = 36/900 = 1/25. Option C
Question: Pipe P can drain the liquid from a tank in 3/4 the time that it takes pipe Q to drain it and in 1/3 the time that it takes pipe R to do it. If all 3 pipes operating simultaneously but independently are used to drain liquid from the tank, then pipe Q drains what portion of the liquid from the tank?
A.9/29
B.8/23
C.9/25
D.17/29
Answer: C.9/25
Explanation: Suppose Q can drain in 1 hr. So, rQ = 1/1 = 1
So, rP = 1/[(3/4)rQ] = 4/3
Also, rP = rR/(1/3) => 4/3 = rR/(1/3) => rR = 4/9
Let H is the time it takes to drain by running all 3 pipes simultaneously
So combined rate = rC = 1/H = 1 + 4/3 + 4/9 = 25/9 = 1/(9/25)
Thus running simultaneously, Pipe Q will drain 9/25 of the liquid.
Thus answer = C.
Question: In the kitchen of a busy restaurant, it takes M minutes to wash P pots. At this rate, how many hours does it take to wash 8P pots?
A.60/M
B.8M
C.2M/15
D.480M
Answer: C.2M/15
Explanation: The time it takes to wash 8P pots is 8M minutes which is 8M / 60 = 2M/15 hours.
The answer is C.
Question: The fourth proportional to 12, 16 and 18 is?
A.21
B.24
C.88
D.99
Answer: B.24
Explanation: (16*18)/12 = 24
Answer: B
Question: The sum of three numbers is 136. If the ratio between first and second be 2 : 3 and that between second and third is 5 : 3, then the second number is
A.38
B.27
C.99
D.60
Answer: D.60
Explanation: Explanation:
A : B = 2 : 3 and B : C = 5 : 3
=>A : B : C = = 10 : 15 : 9.
Second number = = 60.
Answer: D) 60
Question: sunil start from home at 4 pm and reaches school everyday at 5pm to pick up his children.on saturday the school got over ai 4 pm and children started walking towards home.sunil met them on the way and returned home 15min early.if speed of sunil is 35km/hr then for how many min did children walk? what is speed of children???
A.4 km/hr
B.5 km/hr
C.6 km/hr
D.7 km/hr
Answer: B.5 km/hr
Explanation: sunil reach 15 min early. it is time save at both for going to school and coming to home.
so, sunil meet children befor 15/2= 7.5 min.
speed of sunil is 35km/hr i.e. 583.33 m/min.
remaining distance to cover by sunil or else we can say total distance cover by children is 7.5*583.33=4375 m
Sunil meet children after 52.5 min i.e. (1hr-7.5min).
so 4375 is distance cover by children in 52.5min.
so, speed of children is 4375/52.5=83.33m/min=5 km/hr.
ANSWER:B
Question: A train 75 m long is running with a speed of 54 km per hour. In what time will it pass a telegraph post?
A.11 s
B.5 s
C.7 s
D.12 s
Answer: B.5 s
Explanation: We know from the formula Time = Distance/ Speed
Thus, Time = 75/ 54 x 5/18
or, Time = 5 sec.
ANSWER:B
Question: A man purchases 2 watches for $ 560. He sells one at 15% profit and the other at a loss of 10%. He neither gains nor loses on the whole. Thus, the cost price of two watches are :
A.$ 260 and $ 300
B.$210 and $ 350
C.$224 and $336
D.$560 and $560
Answer: C.$224 and $336
Explanation: x + y = 560 --- (1)
1.15x + 0.9y = 560 --- (2)
(2) - (1) --> 0.15x - 0.1y = 0
15x = 10y
x/y = 2/3 = (2*112)/(3*112) = 224/336
Answer: C
Question: A car travels 25km an hour faster than a bus for a journey of 500km. If the bus takes 10 hours more than the car, then the speeds of the bus and the car are
A.25km/hr and 40km/hr respectively
B.25km/hr and 60 km/hr respectively
C.25km/hr and 50km/hr respectively
D.None of these
Answer: C.25km/hr and 50km/hr respectively
Explanation: Let the speeds of bus and car be x and y. Here, y = x +25
As per the question, 500/x - 500/x+25 =10
⇒ 500(x + 25) − 500(x) =10x(x+25) ⇒ x = 25, y = 50.
Answer: C.
Question: A recycling facility is staffed by 7 floor workers and one manager. All of the floor workers are paid equal wages, but the manager is paid n times as much as a floor worker. If the manager’s wages account for 1/7 of all wages paid at the facility, what is the value of n?
A.3/7
B.4/5
C.7/5
D.7/6
Answer: D.7/6
Explanation: Say each floor worker is paid $x, then the manager is paid $xn.
Total salary would be 7x+xn and we are told that it equals to 7xn:
7x+xn=7xn --> reduce by x: 7+n=7n -->6n= 7
n = 7/6
Answer: D
Question: The difference between the squares of two consecutive numbers is 37. Find the numbers.
A.14-15
B.20-23
C.11-12
D.18-19
Answer: D.18-19
Explanation: If the difference between the squares of two consecutive numbers is x, then the numbers are (x-1)/2 and (x+1)/2
(37-1)/2 and (37+1)/2
36/2 and 38/2
Therefore the required answer = 18 and 19.
Question: A sells a bicycle to B at a profit of 75% and B sells it to C at a loss of 40%. Find the resultant profit or loss.
A.-4%
B.5%
C.-5%
D.6%
Answer: B.5%
Explanation: The resultant profit or loss = 75 - 40 - (75*40)/100 = 5%
Profit = 5%
Answer is B
Question: When 7 fair coins are tossed simultaneously, in how many outcomes will the first and the last coin turn up heads?
A.1
B.3
C.8
D.32
Answer: D.32
Explanation: Total outcome is 2^7 = 128
Favourable cases = H_ _ _ _ _ H
The second, to sixth places can be occupied by either H or T
There are 2^5 =32 ways that can be done.
Hence, the correct option is D
Question: Out of 17 applicants 8 boys and 9 girls. Two persons are to be selected for the job. Find the probability that at least one of the selected persons will be a girl.
A.27/34
B.25/34
C.19/34
D.21/34
Answer: A.27/34
Explanation: Explanation :
The probability that no girl is selected is :-
=>8C2/17C2.
=>28/136.
=>7/34.
Hence, the probability that atleast one girl is selected is :-
=>1- 7/34.
=>27/34.
Answer : A
Question: A certain university will select 1 of 3 candidates eligible to fill a position in the mathematics department and 2 of 10 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions?
A.42
B.70
C.140
D.135
Answer: D.135
Explanation: 1 of 3 will be chosen for the math
2 of 10 will be chosen for the computer
None of the 3 chosen people can be in more than one departments.
We can choose any of the 3 candidates for the math dep., which gives as 3 selections.
We can choose 2 of the 10 candidates for the computer dep., which gives us 2 selections and 8 rejections.
So, the way to find how many different selections of 2 candidates we can have for the computer dep., we do:
10! /2!*8!= (9*10) / 2 = 90 / 2 = 45.
We are multiplying our individual selections: 3*45 = 135
In the bolded part, we don't have to multiply all of the numbers, as those in 8! are included in 10!, so we simplify instead.
Ans D
Question: A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
A.220 meter
B.225 meter
C.230 meter
D.235 meter
Answer: C.230 meter
Explanation: Explanation:
As trains are running in opposite directions so their relative speed will get added
So, Relative speed = 120 +80 = 200 kmph
= 200*(5/18) = 500/9 m/sec
Let the length of other train is x meter then
x+270/9=500/9
=>x+270=500=>x=230 So the length of the train is 230 meters
ANSWER IS C
Question: How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per Kg so that there may be a gain of 10 % by selling the mixture at Rs. 9.24 per Kg ?
A.83 Kg
B.65 Kg
C.13 Kg
D.63 Kg
Answer: D.63 Kg
Explanation: By the rule of alligation:
C.P. of 1 kg sugar of 1st kind C.P. of 1 kg sugar of 2nd kind
Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.
Let x kg of sugar of 1st kind be mixed with 27 kg of 2nd kind.
Then, 7 : 3 = x : 27 or x = (7 x 27 / 3) = 63 kg.
Answer: D
Question: 22.32 + 583.122 + 42.42 = ?
A.622.441
B.647.862
C.622.233
D.622.443
Answer: B.647.862
Explanation: Explanation :
22.32 + 583.122 + 42.42 = 647.862. Answer : Option B
Question: Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
A.2 years
B.4 years
C.6 years
D.8 years
Answer: C.6 years
Explanation: Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
Required difference = (42 - 36) years = 6 years
Answer: Option C
Question: A salesman sold twice as much pears in the afternoon than in the morning. If he sold $360 kilograms of pears that day, how many kilograms did he sell in the morning and how many in the afternoon?
A.120
B.180
C.240
D.280
Answer: C.240
Explanation: Let x be the number of kilograms he sold in the morning.Then in the afternoon he sold 2x kilograms. So, the total is x+2x=3x. This must be equal to 360.
3x=360
x=3603
x=120
Therefore, the salesman sold 120 kg in the morning and 2⋅120=240 kg in the afternoon. So answer is C.
Question: Find the simple interest on $10000 at 8% per annum for 12 months?
A.$410
B.$500
C.$650
D.$800
Answer: D.$800
Explanation: P = $10000
R = 8%
T = 12/12 YEARS = 1 YEAR
S.I. = P*R*T/100 = 10000*8*1/100 = $800
Answer is D
Question: Johnny borrows $50,000 from Tony at 3% daily interest compounded daily. How much does Johnny owe Tony after 4 weeks?
A.50000*0.02^28
B.50000*1.12
C.50000*2.12
D.50000*1.03^28
Answer: D.50000*1.03^28
Explanation: A=A= P(1+r100)^n
So, A=50000(1+3/100)^7âˆ—4
So, A= 50000(1.03)^28
Hence answer will be (D)
Question: 893.7 – 573.07 – 95.007 = ?
A.225.623
B.224.777
C.233.523
D.414.637
Answer: A.225.623
Explanation: Solution
Given expression = 893.7 - (573.07 + 95.007) = 893.7 - 668.077 = 225.623. Answer A
Question: A snail, climbing a 36 feet high wall, climbs up 8 feet on the first day but slides down 4 feet on the second. It climbs 8 feet on the third day and slides down again 4 feet on the fourth day. If this pattern continues, how many days will it take the snail to reach the top of the wall?
A.12
B.14
C.15
D.20
Answer: C.15
Explanation: total transaction in two days = 8-4 = 4 feet
in 15 days it will climb 36 feet
thus reaching the top
therefore , total no of days required =15
C
Question: A man covers a distance of 1200 km in 70 days resting 9 hours a day, if he rests 10 hours a day and walks with speed 1½ times of the previous in how many days will he cover 750 km?
A.30
B.31.25
C.31
D.32
Answer: B.31.25
Explanation: Distance d = 1200km
let x be the speed
he walks 15 hours a day(ie 24 - 9)... so totally he walks for 1050hrs...
x = 1200/1050 => 120/105 = 24/21 => 8/7kmph
given 1 1/2 of prev speed
so 3/2 * 8/7= 24/14 = 12/7
new speed = 12/7kmph
now he rests 10 hrs a day ... means he walks 14 hrs a day...
time = 750 * 7 /12 => 437.5hrs
=> 437.5/14 = 31.25
ANSWER:B
Question: What is the tens digit of 7^1001?
A.0
B.0
C.2
D.3
Answer: B.0
Explanation: 7^1 = 7
7^2 = 49
7^3 = 343
7^4 = 2401
7^5 = 16807
7^6 = 117649
We should see this as pattern recognition . We have a cycle of 4 . (We can multiply the last 2 digits only as we care about ten's digit )
0 , 4 , 4 , 0 .
1001= 4*250 + 1
The ten's digit will be 1 .
Answer B
Question: A sum of Rs. 125000 amounts to Rs. 15500 in 4 years at the rate of simple interest. What is the rate of interest?
A.3%
B.2%
C.1%
D.6%
Answer: D.6%
Explanation: S.I. = (15500 - 12500) = Rs. 3000\
Rate = (100 * 3000) / (12500 * 4) = 6%
Answer: D
Question: The difference between a two-digit number and the number obtained by interchanging the two digits is 63. Which is the smaller of the two numbers ?
A.3
B.6
C.5
D.7
Answer: D.7
Explanation: Explanation:
Let the ten's digit be x and unit's digit be y.
Then, (10x + y) - (10y + x) = 63
=> 9 (x - y) = 63
=> x - y = 7.
Thus, none of the numbers can be deermined..
Answer: D
Question: A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 sec. What is the length of the goods train?
A.287 m
B.266 m
C.987 m
D.270 m
Answer: D.270 m
Explanation: Speed = 72 * 5/18 = 20 m/sec.
Time = 26 sec.
Let the length of the train be x meters.
Then, (x + 250)/26 = 20
x = 270 m.
Answer:D
Question: Three persons invested Rs.9000 in a joint business. The second person invested Rs.1000 more than the first and the third Rs.1000 more than second. After two years, they gained Rs.1800. How much third person will get?
A.400
B.800
C.600
D.1200
Answer: B.800
Explanation: First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 1800 = 800
Answer: B
Question: 4 shooters are hitting 1 out of 4 different targets. What is the probability that exactly one shooter will hit each target.
A.4/4^4
B.4^4/4
C.4!/4
D.4!/4^4
Answer: D.4!/4^4
Explanation: Each shooter out of 4 has 4 options, hence total # of outcomes is 4^4;
Favorable outcomes will be 4!, which is # of ways to assign 4 different targets to 4 shooters:
1-2-3-4 (targets)
A-B-C-D (shooters)
B-A-B-C (shooters)
C-B-A-B (shooters)
...
So basically # of arrangements of 4 distinct objects: 4!.
P=favorable/total=4!/4^4
Answer: D.
Question: Working alone, printers X, Y, and Z can do a certain printing job, consisting of a large number of pages, in 15, 12, and 18 hours, respectively. What is the ratio of the time it takes printer X to do the job, working alone at its rate, to the time it takes printers Y and Z to do the job, working together at their individual rates?
A.4/15
B.1/2
C.15/22
D.25/12
Answer: D.25/12
Explanation: The time it takes printer X is 15 hours.
The combined rate of Y and Z is 1/12 + 1/18 = 5/36
The time it takes Y and Z is 36/5
The ratio of times is 15 / (36/5) = 5*15/36 = 25/12
The answer is D.
Question: The average age 15 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
A.18
B.99
C.30
D.26
Answer: C.30
Explanation: 15 * 2 = 30 years
Answer: C
Question: The circulation for magazine Y in 1971 was 5 times the average (arithmetic mean) yearly circulation for magazine Y for the years 1972-1980. What is the ratio of the circulation in 1971 to the total circulation during 1971-1980 for magazine Y ?
A.3/14
B.5/14
C.9/14
D.11/14
Answer: B.5/14
Explanation: There are 9 years from 1972-1980, inclusive. Let's say the average circulation every year between 1972-1980 inclusive is x.
So the total circulation is 9x from 1972-1980, inclusive.
In 1971, the circulation is 5x.
So total circulation for 1971-1980 is 5x + 9x = 14x.
Ratio of circulation in 1971 to total circulation during 1971-1980 is 5x to 14x or 5/14.
Answer : B
Question: John has only pennies, dimes, and nickels in a jar. The jar has at least 1 but no more than 4 pennies. If the jar has at least 1 nickel and 1 dime, which of the following could NOT be the total amount of money in the jar?
A.54
B.55
C.56
D.57
Answer: B.55
Explanation: Let there be a pennies , b nickels and c dimes
so total amount can be 1+5b+10c cents to 4+5b+10c
as you can see the equation of total whenever divided by 5 would leave a remainder from 1 to 4 ( as pennies can only be from 1 to 4 and hence a is limited to values from 1 to 4)
So the total can never be divisible by 5 and hence only 55 that is c is the option which is divisible by 5.
so answer is B