RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In how many different ways can the letters of the word 'OPTICAL' be arranged so that the vowels always come together?
A.610
B.720
C.825
D.920
Answer: B.720
Explanation: Explanation :
The word 'OPTICAL' has 7 letters. It has the vowels 'O','I','A' in it and these 3 vowels
should always come together. Hence these three vowels can be grouped and considered as a
single letter. That is, PTCL(OIA).
Hence we can assume total letters as 5. and all these letters are different.
Number of ways to arrange these letters = 5! = [5 x 4 x 3 x 2 x 1] = 120
All The 3 vowels (OIA) are different
Number of ways to arrange these vowels among themselves = 3! = [3 x 2 x 1] = 6
Hence, required number of ways = 120 x 6 = 720. Answer : Option B
Question: A rectangular plot measuring 15 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?
A.46m
B.26m
C.26m
D.56m
Answer: B.26m
Explanation: Perimeter of the plot = 2(15+50) = 130m
no of poles =130/5 =26m
Answer: B
Question: How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction?
A.50
B.99
C.88
D.77
Answer: A.50
Explanation: The distance to be covered = Sum of their lengths = 200 + 300 = 500 m.
Relative speed = 72 -36 = 36 kmph = 36 * 5/18 = 10 mps.
Time required = d/s = 500/10 = 50 sec.
Answer: A
Question: In the manufacture of a certain product, 9 percent of the units produced are defective and 4 percent of the defective units are shipped for sale. What percent of the units produced are defective units that are shipped for sale?
A.0.125%
B.0.36%
C.0.8%
D.1.25%
Answer: B.0.36%
Explanation: Percent of defective produced = 9%
Percent of the defective units that are shipped for sale = 4%
Percent of units produced are defective units that are shipped for sale = (4/100)*(9/100)*100%
= (36/10000)*100%
= (36/100)%
= .36 %
Answer B
Question: Find all positive integers n such that n^2
+ 1 is divisible by n+ 1.
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: There is only one such positive integer : n = 1.
In fact, n^2+1= n(n+1)-(n-1);
thus, if n+1|n^2+1, then n+1|n-1 which for positive integer n is possible only if n-1 = 0,
hence if n = 1.
Answer is 1
Question: 5 men are equal to as many women as are equal to 7 boys. All of them earn Rs.90 only. Men’s wages are?
A.8Rs.
B.7Rs.
C.6Rs.
D.4Rs.
Answer: C.6Rs.
Explanation: 5M = xW = 7B
5M + xW + 7B ----- 90 Rs.
5M + 5M + 5M ----- 90 Rs.
15M ------ 90 Rs. => 1M = 6Rs.
ANSWER:C
Question: The height of the wall is 6 times its width and length of the wall is 7 times its height .if the volume of the wall be 6804 cu.m.its width is
A.3m
B.5m
C.6m
D.7m
Answer: A.3m
Explanation: Explanation:
Let width = x
Then, height=6x and length=42x
42x Ã— 6x Ã— x = 6804
x = 3
Answer: A
Question: In a village, there are four tribes located at different distances from each other. Tribe R is 60 miles away from Tribe P; Tribe S 40 miles away from Tribe B and Tribe R is 10 miles nearer to the Tribe S than it is to Tribe Q.
How far is the Tribe S located from the tribe P ?
A.23 km
B.24 km
C.25 km
D.26 km
Answer: C.25 km
Explanation: Solution:
25
Distance between Tribe Q and Tribe S = 40km
=> Distance between Tribe Q and Tribe R + Distance between Tribe R and Tribe S = 40km
=> Distance between Tribe Q and Tribe R + (Distance between Tribe Q and Tribe R - 10) = 40 km
=> 2 * Distance between Tribe Q and Tribe R = 50km
=> Distance between Tribe Q and Tribe R = 25km
Answer C
Question: In 1991, there are 28 days in February and there are 365 days in the year. In 1992, there are 29 days in February and there are 366 days in the year. If the date March 15, 1995 is a Tuesday, then which one of the following would the date March 15, 1996 be?
A.Thursday
B.Friday
C.Saturday
D.Sunday
Answer: A.Thursday
Explanation: From the information given,March 15, 1992 is 366 days after March 15, 1991.
366 days = 52 weeks and 2 more days. Therefore if March 15, 1995 is a Tuesday, then March 15, 1996 is Tuesday + 2 days = Thursday
Answer: A
Question: IF
20= W
21= W
22= W
23= W
24= W
THEN 25=?
A.I
B.J
C.W
D.L
Answer: C.W
Explanation: IF
21= W... Second letter of twenty one
22= W.... Second letter of Twenty two
23= W
24= W
25= W
THEN 26=W... Second letter of Twenty six
ANSWER:C
Question: Look at this series: U32, V29, __, X23, Y20, ... What number should fill the blank?
A.M43
B.D14
C.W26
D.F24
Answer: C.W26
Explanation: C
W26
In this series, the letters progress by 1; the numbers decrease by 3.
Question: If the length of the longest chord of a certain circle is 22, what is the radius of that certain circle?
A.11
B.5
C.10
D.15
Answer: A.11
Explanation: Longest chord of a circle is the diameter of the circle
diameter = 2 * radius
If diameter of the circle is given as 22 = 2 * 11
so radius of the circle = 11
correct answer - A
Question: What is the smallest number Y which when increased by 5 is completely divisible by 8, 11 and 24?
A.264
B.259
C.269
D.270
Answer: B.259
Explanation: This question includes a number of great Number Property shortcuts that you can take advantage of:
1) The question asks for the SMALLEST number that, when increased by 5 is divisible by 8, 11 and 24. Since the answers are numbers, we can TEST THE ANSWERS.
2) Any number that is divisible by 24 is ALSO divisible by 8, so we really just need to consider the 11 and the 24.
3) To be divisible by 24, the end number MUST be EVEN. Since we're adding 5 to get to that end number, the starting number MUST be ODD.
The last shortcut allows us to eliminate Answers A, D and E. Between Answers B and C, TESTING B first will prove that, when increased by 5, the end sum is divisible by both 11 and 24.
Final Answer:
B
Question: The average monthly salary of 25 employees in an organisation is Rs. 2500. If the manager's salary is added, then the average salary increases by Rs. 200. What is the manager's monthly salary?
A.Rs.7700
B.Rs.3618
C.Rs.3600
D.Rs.3619
Answer: A.Rs.7700
Explanation: Manager's monthly salary
= Rs. (2700 * 26 - 2500 * 25)
= Rs. 7700 Answer:A
Question: Mary, Peter, and Lucy were picking chestnuts. Mary picked three times as much as much chestnuts than Peter. Lucy picked 4 kg more than Peter. Together the three of them picked 29 kg of chestnuts. How many kilograms of chestnuts did Mary, Peter, and Lucy pick respectively?
A.9, 5 and 15
B.5, 15 and 9
C.15, 5 and 9
D.9, 15 and 5
Answer: C.15, 5 and 9
Explanation: M = 3P
L = P+4
M + P + L = 29
3P + P + (P+4) = 29
P = 5, M = 15, L = 9
Therefore, Mary, Peter, and Lucy picked 15, 5, and 9 kg, respectively.
The answer is C.
Question: Each shelf of a bookcase contained 11 books. If the librarian took out 18 books and rearranged the remaining books so that all shelves but the last one contained 7 books and that last shelf contained 17 books, how many shelves does the bookcase have?
A.5
B.6
C.7
D.8
Answer: C.7
Explanation: Let x be the number of shelves.
11x - 18 = 7(x-1) + 17
4x = 28
x= 7
The answer is C.
Question: A company seeks to hire a sales manager, a shipping clerk, and a receptionist. The company has narrowed its candidate search and plans to interview all remaining candidates including 7 persons for the position of sales manager, 5 persons for the position of shipping clerk, and 10 persons for the position of receptionist. How many different hirings of these three people are possible?
A.7 + 5 + 10
B.7 × 5 × 10
C.21 × 20 × 19
D.7! + 5! + 10!
Answer: B.7 × 5 × 10
Explanation: 1 sales manager can be selected out of 7 in 7 ways
1 clerk can be selected out of 5 in 5 ways
1 receptionist can be selected out of 10 in 10 ways
total no. of ways these 3 can be selected = 7 *4 * 10
Ans. B) 7 × 5 × 10
Question: Eight animals of a circus has to be placed inside in eight cages one in each cage. If 4 of the cage are too small for 6 of the animal then find the number of ways of caging the animal.
A.A.604
B.B.2880
C.C.502450
D.D.784200
Answer: B.B.2880
Explanation: ways for cages that are too small = 5*4*3*2=120
since we have 4 cages and 4 animal left therefore ways for 4 cages =4!
total ways =120*4!=2880
Answer B
Question: Sum of the squares of three numbers is 414 and the sum of their products taken two at a time is 131. Find the sum?
A.20
B.22
C.25
D.26
Answer: D.26
Explanation: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 414 + 2* 131
a + b + c = √676 = 26
D
Question: A certain animal shelter has 26 horses and 36 cows. How many horses must be taken away from the animal shelter so that 75 percent of the animals in the shelter will be cows?
A.12
B.13
C.14
D.15
Answer: C.14
Explanation: Suppose x horses need to be removed from the shelter.
After x horses are removed, the shelter shall have (26 - x) horses and the same 36 cows; and the total number of animals shall be (26 - x) + 36 = 62 - x
Now we want the 75 percent of animals in the shelter to be cows.
This means 75 percent of (62 - x) should be equal to the number of cows which is 36.
This means,
75 % of (62 - x) = 36
Solving above equation we get x = 14
x=14
Ans C
Question: Walking 7/6 of his usual rate, a boy reaches his school 2 min early. Find his usual time to reach the school?
A.14
B.28
C.99
D.77
Answer: A.14
Explanation: Speed Ratio = 1:7/6 = 6:7
Time Ratio = 7:6
1 -------- 7
2 --------- ? 14 m
Answer:A
Question: Company Z has 61 employees. If the number of employees having birthdays on Wednesday is more than the number of employees having birthdays on any other day of the week, each of which have same number of birth-days, what is the minimum number of employees having birthdays on Wednesday.
A.6
B.7
C.13
D.9
Answer: C.13
Explanation: Say the number of people having birthdays on Wednesday is x and the number of people having birthdays on each of the other 6 days is y. then x + 6y =61.
Now, plug options for x. Only C and E give an integer value for y. But only for C x > y as needed.
Answer: C.
Question: John is three times as old as Sam. If John will be twice as old as Sam in six years, how old was Sam four years ago?
A.2
B.4
C.6
D.8
Answer: A.2
Explanation: j= 3s
after 6 years
j +6 = 2(s+6)
j= 2s+6
2s +6 = 3s
s= 6
four years ago
s= 6-4= 2
A is the answer
Question: In 2008, the profits of Company M were 5 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 2009 were what percent of the profits in 2008?
A.80%
B.105%
C.124%
D.240%
Answer: D.240%
Explanation: the profit 0f 2009 in terms of 2008 = 0.8*15/5*100=240%
D
Question: The speed of a car is 85 km in the first hour and 45 km in the second hour. What is the average speed of the car?
A.72 kmph
B.65 kmph
C.30 kmph
D.80 kmph
Answer: B.65 kmph
Explanation: S = (85 + 45)/2
= 65 kmph
ANSWER:B
Question: A bowl of nuts is prepared for a party. Brand P mixed nuts are 20% almonds and Brand Q's Deluxe nuts are 25% almonds. If a bowl contains a total of 64 ounces of nuts, representing a mixture of both brands, and 14 ounces of the mixture are almonds, how many ounces of Brand Q's Deluxe mixed nuts are used?
A. 14
B. 20
C. 32
D. 44
Answer: A. 14
Explanation: lets say x ounces of P is mixed with Q.
=> 64-x ounces of Q is present in the mixture (as the total = 64 ounces)
given total almond weight = 14 ounces
(20x/100)+(25/100)(64-x) = 14
=> x = 40
=> 64-40 = 14 ounces of Q is present in the mixture.
Answer is A.
Question: If x is a prime number, and x-1 is the median of the set {x-1, 3x+3, 2x-4}, then what is the average (arithmetic mean) of the set?
A.2
B.5/3
C.3
D.10/3
Answer: D.10/3
Explanation: If x is a prime number, and x-1 is the median of the set {x-1, 3x+3, 2x-4}, then what is the average (arithmetic mean) of the set?
A. 2
B. 5/3
C. 3
D. 10/3
E. 14/3
Solution:
x-1 is the median of the set, implies if we arrange the set in ascending order, the set would be [2x-4, x-1, 3x+3]. This means that:
2x-4<x-2<3x+3
solving inequality gives x>-2 and x<3. Since x is prime number and the only prime number <3 is 2, so put x=2.
Hence set becomes: [ 0, 1, 9] and avg = 10/3.D
Question: The H.C.F. of two numbers is 12 and their L.C.M. is 600. If one of the number is 60, find the other?
A.100
B.240
C.120
D.200
Answer: C.120
Explanation: Other number = 12*600/60= 120
Answer is C
Question: A car salesman earns a base salary of $1,000 per month plus a commission of $200 for each car he sells. If the car salesman earned $2000 in March, how many cars does he need to sell in April in order to double his March earnings?
A.14
B.15
C.16
D.17
Answer: B.15
Explanation: 1000+200x=4000
x=15 cars.
The answer is B.
Question: Manoj borrowed Rs.3900 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
A.22877
B.5655
C.2778
D.6787
Answer: B.5655
Explanation: Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3900.3.6/100 = Rs.824.85
27P = 70200 = 82485
P = (82485 + 70200)/27 = 3055 + 2600 = Rs.5655
Answer: B
Question: The sum of two numbers is 40 and their product is 350. What will be the sum of their reciprocals?
A.4/35
B.8/75
C.75/4
D.75/8
Answer: A.4/35
Explanation: (1/a)+(1/b)=(a+b)/ab=40/350=4/35
ANSWER:A
Question: A person purchases 90 clocks and sells 40 clocks at a gain of 10% and 50 clocks at a gain of 20%. If he sold all of them at a uniform profit of 15%, then he would have got Rs. 40 less. The cost price of each clock is:
A.Rs.50
B.Rs.60
C.Rs.80
D.Rs.90
Answer: C.Rs.80
Explanation: Let C.P. of clock be Rs. x.
Then, C.P. of 90 clocks = Rs. 90x.
[(110% of 40x) + (120% of 50x)] - (115% of 90x) = 40
44x + 60x - 103.5x = 40
0.5x = 40 => x = 80
ANSWER:C
Question: If p/q = 3/5 , then 2p+q= ?
A.12
B.11
C.13
D.15
Answer: B.11
Explanation: let p=3, q=5 then 2*3+5=11
so 2p+q=11.
ANSWER:B
Question: Rs.800 amounts to Rs.920 in 3 years at simple interest. If the interest is increased by 3%, it would amount to how much?
A.299
B.277
C.266
D.992
Answer: D.992
Explanation: (800*3*3)/100 = 72
920 + 72 = 992
Answer:D
Question: X men can do a work in 120 days. If there were 20 men less, the work would have taken 60 days more. What is the value of X?
A.60
B.77
C.26
D.66
Answer: A.60
Explanation: We have M1 D1 = M2 D2
120X = (X - 20)180
=> 2X = (X - 20) 3 => 2X = 3X - 60
=> X = 60
Answer:A
Question: What number has a 5:1 ratio to the number 10?
A.36
B.50
C.76
D.56
Answer: B.50
Explanation: 5:1 = x: 10
x = 50
Answer: B
Question: How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.11
B.30
C.99
D.88
Answer: B.30
Explanation: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec.
Answer: B
Question: How many of the following numbers are divisible by 132 ?
264, 396, 462, 792, 968, 2178, 5184, 6336
A.2
B.4
C.6
D.8
Answer: B.4
Explanation: 132 = 4 x 3 x 11
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
264 11,3,4 (/)
396 11,3,4 (/)
462 11,3 (X)
792 11,3,4 (/)
968 11,4 (X)
2178 11,3 (X)
5184 3,4 (X)
6336 11,3,4 (/)
Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.
B
Question: If the wheel is 14 cm then the number of revolutions to cover a distance of 1056 cm is?
A.15
B.10
C.14
D.12
Answer: D.12
Explanation: 2 * 22/7 * 14 * x = 1056 => x = 12
ANSWER:D
Question: From a total of 4 boys and 4 girls, how many 4-person committees can be selected if the committee must have exactly 2 boys and 2 girls?
A.16
B.36
C.60
D.120
Answer: B.36
Explanation: Answer=B=36
No of 4 person committees that can be formed=4C2*4C2=36
Answer B
Question: A train 650 m long is running at a speed of 81 km/hr. In what time will it pass a bridge 340 m long?
A.42
B.43
C.44
D.45
Answer: C.44
Explanation: Speed = 81 * 5/18 = 45/2 m/sec
Total distance covered = 650 + 340 = 990 m
Required time = 990 * 2/45 = 44 sec
Answer: C
Question: A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 20% less than the price each head sold for the day before.what was the gross profit on this shipment?
A.$100
B.$115
C.$125
D.$130
Answer: A.$100
Explanation: Sol:
1500 heads -> $600
1 head -> $600/1500
1 head -> $(2/5)
25% more of (2/5) -> 125/100 * 2/5 = $(1/2)
He sold 2/3*1500 = 1000 heads for $(1/2) per head
Total revenue by selling 1000 heads = 1000 * 1/2 = $500
Heads left: 500
Cost per head: 80% of the previous price: 80/100 * 1/2 = $(2/5)
Total revenue by selling 500 heads = 2/5 * 500 = 200
Total revenue after selling 1500 cabbage heads - 200+500 = $700
Money spent on the purchase: $600
Profit = 700-600 = $100
Ans: A
Question: A man started a business investing Rs.70,000. Rakhi joined him after six months with an amount of Rs.1,05,000 and Sagar joined them with Rs.1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business?
A.7 : 6 : 10
B.12 : 15 : 16
C.42 : 45 : 56
D.cannot be determined
Answer: B.12 : 15 : 16
Explanation: Solution
Aman : Rakhi : Sagar	=(70,000 x 36):(1,05,000 x 30):(1,40,000 x 24)
= 12 : 15 : 16.
Answer B
Question: The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
A.1/(XY).
B.X/Y.
C.Y/X.
D.1/(X+Y).
Answer: B.X/Y.
Explanation: Let the probability of breaking the jar= n
n*1/X = 1/Y
n= X/Y
B is the answer
Question: Marts income is 30 percent more than Tims income and Tims income is 40 percent less than Juans income. What percentage of Juans income is Marts income
A.124%
B.b) 120 %
C.c) 78 %
D.d) 80 %
Answer: C.c) 78 %
Explanation: M = (130/100)T
T = (60/100)J
=> M = (78/100)J
Answer C.
Question: On a map, 1 inch represents 28 miles. How many X XXinches would be necessary to represent a distance of 383.6 miles?
A.5.2
B.7.4
C.13.7
D.21.2
Answer: C.13.7
Explanation: X inches necessary to represent a distance of 383.6 miles = 383.6/28
= 13.7
Answer C
Question: There are 6 people and 6 chairs. In how many different ways people can occupy the chairs?
A.12
B.15
C.720
D.36
Answer: C.720
Explanation: number of ways =6! = 720
Answer is C
Question: A, B and C start swimming in a pool simultaneously from the same end. To complete 12 laps, A takes 10 minutes, B takes 8 minutes and C takes 6 minutes. What is the ratio of speeds A:B:C?
A.3:4:5
B.10:15:20
C.5:4:3
D.4:6:5
Answer: B.10:15:20
Explanation: The slowest one is A, then comes B and the fastest one is C. So, the the ratio of speeds A:B:C must be in ascending order. Eliminate options C, D, and E.
A's speed (distance)/(time) = 12/10 = 6/5 lap per minute = 10 laps in 10 minute;
B's speed (distance)/(time) = 12/8 = 3/2 lap per minute = 15 laps in 10 minutes;
C's speed (distance)/(time) = 12/6 = 2 lap per minute = 20 laps in 10 minutes/
Therefore, the the ratio of speeds A:B:C is 12:15:20.
Answer: B.
Question: A woman complete a journey in 15 hours. She travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
A.336 km.
B.216 km.
C.314 km.
D.224 km.
Answer: A.336 km.
Explanation: 0.5x/21 + 0.5x/24 = 15
--> x/21 + x/24 = 30
--> x = 336 km.
A
Question: P can do a work in the same time in which Q and R together can do it. If P and Q work together, the work can be completed in 10 days. R alone needs 50 days to complete the same work. then Q alone can do it in
A.30 days
B.25 days
C.20 days
D.15 days
Answer: B.25 days
Explanation: Explanation :
Work done by P and Q in 1 day = 1/10
Work done by R in 1 day = 1/50
Work done by P, Q and R in 1 day = 1/10 + 1/50 = 6/50
But Work done by P in 1 day = Work done by Q and R in 1 day . Hence the above equation can be written as
Work done by P in 1 day × 2 = 6/50
=> Work done by P in 1 day = 3/50
=> Work done by Q and R in 1 day = 3/50
Hence work done by Q in 1 day = 3/50 – 1/50 = 2/50 = 1/25
So Q alone can do the work in 25 days
Answer : Option B
Question: How many three digit numbers V greater than 330 can be formed from the digits 1, 2, 3, 4, 5 and 6, if each digit can only be used once?
A.72
B.48
C.120
D.96
Answer: A.72
Explanation: Find the number of 3 digit numbers greater than 300, and then subtract from them the number of three digit numbers between 300 and 330 formed with the given 6 digits.
ABC three digit numbers greater than 300 - total of 4*5*4=80, because a must be greater than 2, so 4 possibilities left; B 5 remaining, and C 4 remaining possibilities to choose from.
Between 300 and 330 there are 1*2*4=8 numbers with the given property: A = 3, 1 possibility; B can be only 1 or 2 (ABC < 330), so two possibilities; C the remaining 4 possibilities after choosing A and B.
Total possible choice 80 - 8 =72=V
Answer: A.
Question: The length of the room is 5.5m and width is 3.75m. Find the cost of paving the floor by slabs at the rate of Rs.800 per sq meter?
A.16500
B.16299
C.22898
D.12929
Answer: A.16500
Explanation: l=5.5m w=3.75m
area of the floor = 5.5 x 3.75 = 20.625 sq m
cost of paving = 800 x 20.625 = Rs. 16500
Answer: A
Question: What is the average of 120, 130, 140, 510, 520, 530, 1115, 1120, and 1125?
A. 419
B. 551
C. 601
D.590
Answer: D.590
Explanation: Add 120, 130, 140, 510, 520, 530, 1115, 1120, and 1125
Grouping numbers together may quicken the addition
sum =5310
5310/9 =590
.D
Question: The Sum of first N consecutive odd integers is N^2. What is the sum of all odd integers between 9 and 39 inclusive.
A.351
B.384
C.410
D.424
Answer: B.384
Explanation: We're dealing with a sequence of CONSECUTIVE ODD INTEGERS: 9 to 39, inclusive. We're asked for the SUM of this group.
1) Start with the sum of the smallest and the biggest: 9 + 39 = 48
2) Now look at the 'next smallest' and the 'next biggest': 11 + 37 = 48
Now we have proof that there is no middle term. We have 8 bunches of 48
8(48) = 384
B
Question: SAKSHI CAN DO A PIECE OF WORK IN 20 DAYS. TANYA IS 25% MORE EFFICIENT THAN SAKSHI. THE NUMBER OF DAYS TAKEN BY TANYA TO DO THE SAME PIECE OF WORK IS:
A.15
B.16
C.18
D.25
Answer: B.16
Explanation: RATIO OF TIMES TAKEN BY SAKSHI AND TANYA = 125:100 = 5:4
SUPPOSE TANYA TAKES X DAYS TO DO THE WORK;
5:4::20:X, X=(4x20/5), X=16 DAYS.
CORRECT OPTION: B
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 5 kmph, what is the time taken to row a distance of 60 km downstream?
A.30/18 hours
B.37/13 hours
C.80/13 hours
D.12/5 hours
Answer: D.12/5 hours
Explanation: Speed downstream = 20 + 5 = 25 kmph.
Time required to cover 60 km downstream
= d/s = 60/25
= 12/5 hours.
Answer: D
Question: A tin of oil was 4/5full.when 6 bottles of oil were taken out and four bottles of oil were poured into it, it was ¾ full. how many bottles of oil can the tin contain?
A.20
B.40
C.60
D.80
Answer: B.40
Explanation: Suppose x bottles can fill the tin completely
Then4/5x-3/4x=6-4
X/20=2
X=40
Therefore required no of bottles =40
ANSWER B
Question: A can complete the job in 2 hours and B can complete the same job in 4 hours. A works for 1 hour and then B joins and both complete the job. What fraction of the job did B complete
A.1/6
B.3/10
C.1/2
D.5/6
Answer: A.1/6
Explanation: A=1/6
Question: At the end of a business conference the 20 people present all shake hands with each other once. How many handshakes will there be altogether ?
A.20
B.45
C.55
D.190
Answer: D.190
Explanation: number of handshakes = 20C2= 20*19/2 = 190
ANSWER:D
Question: 3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 6 pumps work to empty the tank in 1 day?
A.8
B.10
C.11
D.12
Answer: A.8
Explanation: 3 pumps take 16 hrs total (8 Hrs a day)
If 1 pump will be working then, it will need 16*3=48 hrs
1 pump need 48 Hrs
If I contribute 6 pumps then
48/6=8 hrs.
answer :A