RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A small company employs 3 men and 5 women. If a team of 4 employees is to be randomly selected to organize the company retreat, what is the probability F that the team will have exactly 2 women?
A.1/14
B.1/7
C.2/7
D.3/7
Answer: D.3/7
Explanation: 5C2 * 3C2 -> it gives combination of exactly 2 women and 2 men.
8C4 -> gives total possibilities of 4 people from 5 women and 3 men.
Probability = 5C2* 3C2 / 8C4 = 3/7
SECOND METHOD:
Probability of two women -> 5/8 * 4/7.
probability of two men -> 3/6 * 2/5.
Probability: (5/8 * 4/7) * (3/6 * 2/5) = 1/14.
Question: If the sides of a cube are in the ratio 4:3. What is the ratio of their diagonals?
A.4:3
B.4:8
C.4:1
D.4:2
Answer: A.4:3
Explanation: a1:a2 = 4:3
d1:d2 = 4:3
Answer:A
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
A.30/90 kmph
B.80,40 kmph
C.24,98 kmph
D.30,54 kmph
Answer: B.80,40 kmph
Explanation: Speed downstream = 60 + 20 = 80 kmph
Speed upstream = 60 - 20 = 40 kmph
Answer:B
Question: A student has to obtain 33% of the total marks to pass. He got 175 marks and failed by 89 marks. The maximum marks are?
A.450
B.300
C.800
D.610
Answer: C.800
Explanation: Let the maximum marks be x
Then, 33% of x = 175+89
33x/100 = 264
x = 800
Answer is C
Question: A $500 investment and a $1,500 investment have a combined yearly return of 8.5 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1 ,500 investment have?
A.9%
B.10%
C.10 5/8%
D.11%
Answer: A.9%
Explanation: The ratio of investments is 500:1,500 = 1:3.
The deviation from the average return from $500 investment and $1,500 investment must be in the ration 3:1.
$500 investment return has the deviation from the mean of 8.5-7=1.5%, thus $1,500 investment return must have the deviation from the mean equal to 0.5%, which means that $1 ,500 investment has 8.5+0.5=9% yearly return.
Answer: A.
Question: A wolf eats 5.5 Kg of meat in 3 days. A baby tiger eats 3 Kg of meat in 4 days. How much meat can the two combined eat in three days?
A.10.
B.9.
C.8.
D.7.75
Answer: D.7.75
Explanation: 3/3*5.5+3/4*3=7.75 kg
D
Question: Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?
A.3.6
B.6
C.18
D.22
Answer: B.6
Explanation: Let rate = R% and time = R years.
Then, (1200 x R x R)/100	= 432
12R^2 = 432
R^2 = 36
R = 6.
Answer: Option B
Question: What is the units digit of 23^2 * 17^2 * 39^2?
A.1
B.3
C.5
D.7
Answer: A.1
Explanation: The units digit of 23^2 is the units digit of 3*3 = 9 which is 9.
The units digit of 17^2 is the units digit of 7*7 = 49 which is 9.
The units digit of 39^2 is the units digit of 9*9 = 81 which is 1.
The units digit of 9*9*1 = 81 is 1.
The answer is A.
Question: John found that the average of 15 numbers is 40. If 10 is added to each number then the mean of number is?
A.50
B.60
C.70
D.80
Answer: A.50
Explanation: (x+x1+...x14)/15 = 40
50
Option A
Question: A merchant has selected two items to be placed on sale, one of which currently sells for 20 percent less than the other. If he wishes to raise the price of the cheaper item so that the two items are equally priced, by what percentage must he raise the price of the less expensive item?
A.23 %
B.24%
C.25%
D.26%
Answer: C.25%
Explanation: Expensive item = $100;
Cheap item = $80;
We must increase $80 to $100, so by $20, which is 25% increase: (100-80)/80 = 1/4 = 0.25
Answer: C.
Question: Country X taxes each of its citizens an amount equal to 15 percent of the first $40,000 of income, plus 20 percent of all income in excess of $40,000. If a citizen of Country X is taxed a total of $8,000, what is her income?
A.$40,000
B.$50,000
C.$64,000
D.$66,667
Answer: B.$50,000
Explanation: Equation is correct, so math must be a problem.
0.15*40,000+0.2*(x-40,000)=8,000 --> 6,000+0.2x-8,000=8,000 --> 0.2x=10,000 --> x=50,000.
Answer: B.
Question: The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of $600 per sq. metre.
A.$12375
B.$13575
C.$16575
D.$14575
Answer: A.$12375
Explanation: A
Area =5.5×3.75 sq. metre.
Cost for 1 sq. metre. = $600
Hence, total cost
=5.5×3.75×600= $12375
A
Question: If the price of petrol increases by 25% and Benson intends to spend only an additional 15% on petrol, by how much % will he reduce the quantity of petrol purchased?
A.8%
B.7%
C.10%
D.6%
Answer: A.8%
Explanation: Explanation :
Assume that the initial price of 1 Litre petrol = Rs.100 ,Benson spends Rs.100 for petrol,
such that Benson buys 1 litre of petrol
After the increase by 25%, price of 1 Litre petrol = 100 × (100+25)/100 = Rs.125
Since Benson spends additional 15% on petrol,
amount spent by Benson = 100×(100+15)/100 = Rs.115
Hence Quantity of petrol that he can purchase = 115/125 Litre
Quantity of petrol reduced = 1 − (115/125) Litre
Percentage Quantity of reduction =(1−115/125)1×100
=(10/125) × 100 = (10/5) × 4 = 2×4 = 8%
Answer : Option A
Question: A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.340 less than the sum lent. What was the sum lent?
A.Rs.400
B.Rs.450
C.Rs.550
D.Rs.500
Answer: D.Rs.500
Explanation: Explanation:
P - 340 = (P*4*8)/100
P = 500
ANSWER IS D
Question: What is the x-intercept of a line that passes
through the point (3, 4) and has a slope of 2?
A.-2
B.-1
C.0
D.1
Answer: D.1
Explanation: First, plot the point (3, 4) on a graph. A slope of 2 means “up 2, over 1,” so plot this point
on a graph, too. Here’s the resulting graph:
y over 1
up 2
(1, 0)
(2, 2)
(3, 4)
(4, 6)
x
The line passes through the x-axis at 1, making the correct answer D)1
Question: Which of the following is the Highest Common Factor of 18, 24 and 36?
A.8
B.10
C.6
D.14
Answer: C.6
Explanation: Ans is :C
actors of 18 = {1 , 2 , 3 , 6 , 9 , 18} Factors of 24 = {1 , 2 , 3 , 4 , 6 , 8 , 12 , 24} Factors of 36 = {1 , 2 , 3 , 4 , 6 , 9 , 12 , 18 , 36} => the Highest Common Factor is 6
Question: A, B and C can do a piece of work in 24 days, 30 days and 60 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed?
A.10 days
B.11 days
C.13 days
D.21 days
Answer: B.11 days
Explanation: One day work of A, B and C = 1/24 + 1/30 + 1/60 = 11/120 Work done by A and B together in the last 4 days = 4*(1/24 + 1/30) = 3/10
Remaining work = 7/10
The number of days required for this initial work = 7 days.
The total number of days required = 4 + 7 = 11 days.
ANSWER:B
Question: If one-third of one-fourth of the number is 10, then two-fifth of that number is
A.80
B.70
C.60
D.None of these
Answer: D.None of these
Explanation: Explanation:
None of these
Answer: Option D
Question: At a certain hospital, 75% of the interns receive fewer than 6 hours of sleep and report feeling tired during their shifts. At the same time, 70% of the interns who receive 6 or more hours of sleep report no feelings of tiredness. If 80% of the interns receive fewer than 6 hours of sleep, what percent F of the interns report no feelings of tiredness during their shifts?
A.6
B.14
C.19
D.20
Answer: C.19
Explanation: < 6 hours sleep>= 6 hours sleepTOTAL
Tired75--
Not Tired-0.7*X?
TOTAL80X100
Interns who receive< than 6 hours sleepandNot Tired= 80 - 75 = 5;
TOTAL interns who receive >= 6 hours sleep= 100 - 80 = 20, so interns who receive>= 6 hours sleepand areNot Tired= 0.7 * 20 =14;
Interns who areNot Tired F= 5 + 14 = 19.
Answer: C.
Question: Mike drives his new Corvette from San Francisco to Las Vegas, a journey of 640 miles. He drives the first half of the trip at an average rate of 80 miles per hour, but has to slow down for the second half of his journey. If the second half of the trip takes him 200 percent longer than the first half, what is his average rate Z in miles per hour for the entire trip?
A.26.7
B.Z=30.0
C.Z=40.0
D.Z=53.3
Answer: C.Z=40.0
Explanation: VERITAS PREPOFFICIAL SOLUTION
Correct Answer: C
Using the formula: Time = Distance/Rate, we find that Mike takes 4 hours to cover the first 320 miles of his trip. Since the 2nd 320 miles take 200% longer than the first, it takes Mike 8 hours longer, or 12 hours. (Note: 200% longer than the first half is not 200% of the first half.) The overall time is 4 hours + 12 hours or 16 hours. Since the definition of Average Rate = Total Distance Traveled/Total Time of Travel, Mike's average rate = 640/16 or 40 miles per hour.
Answer choice C is correct.
Question: Find the odd one out
A.ctyugg
B.crusade
C.campaign
D.cruise
Answer: D.cruise
Explanation: Explanation:
Cruise = a sea voyage for pleasure.
All other words are related to ‘journey on land, sea with an aim’
Answer: D)
Question: (1/35)+(1/36)+……+(1/65)+(1/66) is including in which of the following ranges?
A.2
B.1
C.2~ 3
D.1/2~1
Answer: D.1/2~1
Explanation: Number of terms in the given series = 32.
The lowest term is 1/65 , the largest being 1/35.
Thus, the sum of the given series will be more than
1/65 + 1/65.....1/65 (32 times)
---> 32*(1/65) = 32/65
less than 1/35 + 1/35...... 1/35 (32 times)
---> 32*(1/35) = 32/35 = 1 (approx)
D is thus the correct answer.
Question: The sides of a triangle are in the ratio 5: 12: 13 and its perimeter is 300 m, its area is?
A.3000 sq m
B.2887 sq m
C.6296 sq m
D.2587 sq m
Answer: A.3000 sq m
Explanation: 5x + 12x + 13x = 300 => x = 10
a = 50, b = 120, c = 130
S = (50 + 120 + 130)/2 = 150
3000 sq m
Answer: A
Question: A particular library has 75 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 70 percent of books that were loaned out are returned and there are 63 books in the special collection at that time, how many books of the special collection were loaned out during that month?
A.20
B.30
C.35
D.40
Answer: D.40
Explanation: I didn't understand How did we get 100?
Total = 75 books.
65% of books that were loaned out are returned --> 100%-70%=30% of books that were loaned out are NOT returned.
Now, there are 63 books, thus 76-63=12 books are NOT returned.
{loaned out}*0.30=7 --> {loaned out}=40.
Answer: D.
Question: A man purchases 2 watches for $ 600. He sells one at 15% profit and the other at a loss of 10%. He neither gains nor loses on the whole. Thus, the cost price of two watches are :
A.$ 260 and $ 300
B.$210 and $ 350
C.$240 and $360
D.$560 and $560
Answer: C.$240 and $360
Explanation: x + y = 600 --- (1)
1.15x + 0.9y = 600 --- (2)
(2) - (1) --> 0.15x - 0.1y = 0
15x = 10y
x/y = 2/3 = (2*120)/(3*120) = 240/360
Answer: C
Question: In a lottery, there are 8 prizes and 24 blanks. A lottery is drawn at random. What is the probability of getting a prize?
A.1/4
B.1/8
C.1/12
D.1/16
Answer: A.1/4
Explanation: P(winning a prize) = 8 / (8+24) = 8/32 = 1/4
The answer is A.
Question: Lines y=√2·x+5 and y=3√2·x−1 intersect at what height above the x axis?
A.-8√2
B.0
C.7√2
D.8
Answer: D.8
Explanation: Solve two equations for y
y=√2·x+5
y=3√2·x−1
Set the two equations equal to each other and solve for x
√2·x+5 = 3√2·x−1
6 = 2√2·x
6/(2√2) = x
3/√2 = x
Plug x = 3/√2 into any one of the original equations to find the y value (height above x axis) where the two lines intersect
y=√2·x+5
y=√2·(3/√2)+5
y = 3 + 5
y = 8
Final answer:
D) 8
Question: A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?
A.310
B.320
C.305
D.315
Answer: D.315
Explanation: Average of the two areas =7002=350
one-fifth of the average of the two areas=3505=70
⇒ Difference of the two areas =70
Let area of the smaller part =x hectares.
Then, area of the larger part =x+70 hectares.
x+(x+70)=700⇒2x=630⇒x=315
Answer is D.
Question: If s / t is an integer, which of the following statements must be true?
A.s = nt where n is an integer
B.both s and t are integers
C.either s or t is negative
D.t is an integer
Answer: A.s = nt where n is an integer
Explanation: Let s = 1/4; t = 1/8 -->s/t = 2
s= nt where n is an integer --> 1/4 = 2*(1/8) --> Correct
Answer: A
Question: A bus trip of 210 miles would have taken 1 hour less if the average speed V for the trip had been greater by 5 miles per hour. What was the average speed V, in miles per hour, for the trip?
A.25
B.30
C.35
D.40
Answer: B.30
Explanation: The time is the distance/speed. The time difference is 1 hour.
210/V - 210/(V+5) = 1
210(V+5) - 210V = (V)(V+5)
1050 = (V)(V+5)
30*35 = (V)(V+5)
V = 30 mph
The answer is B.
Question: Each writer for the local newspaper is paid as follows: a dollars for each of the first z stories each month, and a + b dollars for each story thereafter, where a > b. How many more dollars will a writer who submits z + a stories in a month earn than a writer who submits z+ b stories?
A.(a – b)( a + b + z)
B.a – b
C.a^2 – b^2
D.z( a – b)
Answer: C.a^2 – b^2
Explanation: total earned for z+a stories =a + a(a+b)
total earned for z+b stories =a+ b(a+b)
difference = a+a(a+b) -a -b(a+b)
=(a+b)(a-b) =a^2-b^2
answer is C
Question: A basketball is dropped from a height of 40 feet. If it bounces back up to a height that is exactly half of its previous height, and it stops bouncing after hitting the ground for the fourth time, then how many total feet will the ball have traveled after 3 full bounces.
A.50
B.55
C.110
D.75
Answer: C.110
Explanation: Initial distance = 40 feet
first bounce = 20 feet up + 20 feet down = 40 feet
second bouche = 10 feet up + 10 feet down = 20 feet
third bounce = 5 feet up and 5 feet down= 10 feet
total distance covered = 40+40+20+10= 110
ANSWER IS C
Question: P can complete a work in 12 days working 8 hours a day.Q can complete the same work in 8 days working 10 hours a day. If both p and Q work together,working 8 hours a day,in how many days can they complete the work?
A.60/11
B.60/12
C.60/18
D.60/16
Answer: A.60/11
Explanation: Explanation:
P can complete the work in (12 * 8) hrs = 96 hrs
Q can complete the work in (8 * 10) hrs=80 hrs
\inline {\color{Black}\therefore } P's 1 hour work=1/96 and Q's 1 hour work= 1/80
(P+Q)'s 1 hour's work =\inline {\color{Black} \left ( \frac{1}{96}+\frac{1}{80} \right )} =\inline {\color{Black} \frac{11}{480}}
so both P and Q will finish the work in \inline {\color{Black} \frac{480}{11}} hrs
\inline {\color{Black} \therefore } Number of days of 8 hours each = \inline {\color{Black} \left ( \frac{480}{11} \times \frac{1}{8}\right )=\frac{60}{11}}
Answer: A) 60/11
Question: The wages earned by Robin is 40% more than that earned by Erica. The wages earned by Charles is 60% more than that earned by Erica. How much % is the wages earned by Charles more than that earned by Robin?
A.23%
B.18.75%
C.28.57%
D.50%
Answer: C.28.57%
Explanation: Explanatory Answer
Let the wages earned by Erica be $100
Then, wages earned by Robin and Charles will be $140 and $160 respectively.
Charles earns $40 more than Robin who earns $140.
Therefore, Charles' wage is 40/140*100 = 28.57%.
The correct choice is (C)
Question: If the price has fallen by 11% what percent of its consumption be: increased so that the expenditure may be the same as before?
A.A)11/89%
B.B)10%
C.1/9 %
D.1/11 %
Answer: A.A)11/89%
Explanation: 100 – 11 = 89
89------11
100------? => 11/89%
ANSWER:A
Question: The average of 25 results is 20. The average of first 12 of those is 14 and the average of last 12 is 17. What is the 13th result?
A.128
B.75
C.69
D.78
Answer: A.128
Explanation: Solution: Sum of 1st 12 results = 12*14
Sum of last 12 results = 12*17
13th result = x (let)
Now,
12*14+12*17+x = 25*20
Or, x = 128.
Answer: Option A
Question: 1 Decade ago, Karthik’s mother was quadrice older than her son. After one decade, the mother will be two times older than her son. The current age of Karthik is?
[Decade = 10 Years; quadrice= 4 times]
A.20 years
B.60 years
C.80 years
D.40 years
Answer: A.20 years
Explanation: A
20 years
Let Karthikh’s age 10 years ago be A year
His mother’s age 1 decade ago = 4A
(4A + 10) + 10 = 2 (A + 10 +10)
2A = 20 or A =10
Current age of Karthikh = (A + 10)
= 20 years
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 40% profit on the first article and 40% loss on second article. Find the net profit or loss percent?
A.200
B.278
C.282
D.400
Answer: D.400
Explanation: Profit on first article = 40% of 1000 = 400.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer: D
Question: Find the invalid no.from the following series 13, 18, 25, 30, 37, 40
A.23
B.35
C.40
D.45
Answer: C.40
Explanation: The differences between two successive terms from the beginning are 7, 5, 7, 5, 7, 5. So, 40 is wrong.
C
Question: ACME’s manufacturing costs for sets of horseshoes include a $11,450 initial outlay, and $19.75 per set. They can sell the sets $51.00. If profit is revenue from sales minus manufacturing costs, and the company producessells 987 sets of horseshoes, what was their profit?
A.$19,393.75
B.$30,943.25
C.$41,308.50
D.$51,817.50
Answer: A.$19,393.75
Explanation: its A
since options are not so close we can solve this by uniting calculation and guessing
total sales will be bit lower than 51000
from that initial outlay will get deducted 11500 so we left with 31500
variable cost say 20 X 1000 = 20000 will be deducted so finally we left with 19500
since we have considered the price greater than it actually is, the correct answer will certainly not cross the threshold of 19500.
Question: In a company of 180 employees, 110 are females. A total of 90 employees have advanced degrees and the rest have a college degree only. If 35 employees are males with a college degree only, how many employees are females with advanced degrees?
A.50
B.55
C.60
D.65
Answer: B.55
Explanation: The number of males is 180-110=70.
The number of males with advanced degrees is 70-35=35.
The number of females with advanced degrees is 90-35=55.
The answer is B.
Question: The probability that A speaks truth is 2/5 and that of B speaking truth is 3/7. What is the probability that they agree in stating the same fact?
A.18/35
B.17/35
C.18/36
D.18/16
Answer: B.17/35
Explanation: If both agree stating the same fact, either both of them speak truth of both speak false.
Probability
= 2/5 * 4/7 + 3/5 * 3/7
= 8/35 + 9/35
= 17/35
Answer: B
Question: When a plot is sold for Rs.18,700,the owner loses 15%.At what price must the plot be sold in order to gain 15% ?
A.Rs.21,000
B.Rs.22,500
C.Rs.25,300
D.Rs.25,800
Answer: C.Rs.25,300
Explanation: Solution
85 : 18700 = 115 : x or x =(18700x115/85) = 25300.
Hence, S.P. = Rs. 25,300.
Answer C
Question: A person has to cover the fixed distance through his horses. There are five horses in the cart. They ran at the full potential for the 24 hours continuously at constant speed and then two of the horses ran away to some other direction. So he reached the destination 48 hours behind the schedule. If the five horses would have run 50 miles more, then the person would have been only 24 hours late. Find the distance of the destination.
A.200/3
B.400/3
C.500/3
D.600/8
Answer: B.400/3
Explanation: Suppose his actual speed is 'v' with 5 horses,
If he travelled that 50 miles with 5 horses the time taken wud b 50/v, which equals time taken with 3/5th speed minus 24hrs
50/v = 50/(3v/5) - 24;
so, v = 25/18;
Now, suppose after 1st 24 hrs he takes 't' hrs toreach his destination, then
vt = (3v/5)(t + 48);
vt = (3v/5)(t+48)
t = 72
total time = 72+24 = 96
distance = 400/3
ANSWER:B
Question: Arjun leaves home everyday at 4 p.m to pick his son from school and returns home at 6 p.m. One day, the school was over at 4 p.m and the son started walking home from school. Arjun, unaware of this, starts from home as usual and meets his son on the way and returns home with him 15 minutes early. If the speed of Arjun is 30 km\hr, find the speed of his son.
A.15km/hr
B.6 km/hr
C.4.28 km/hr
D.9 km/hr
Answer: C.4.28 km/hr
Explanation: Arjun leaves home everyday at 4 p.m to pick his son from school and returns home at 6 p.m. One day, the school was over at 4 p.m and the son started walking home from school. Arjun, unaware of this, starts from home as usual and meets his son on the way and returns home with him 15 minutes early. If the speed of Arjun is 30 km\hr, find the speed of his son.
The distance from home to school is 30 km. The round trip distance = 60 km. Because he returns home 15 minutes early, I thought it might be easier to break his trip up into 8 identical 15 minute blocks, each of which he traveled at 7.5 km/hour.
Because we are dealing with a round trip here, Arjun would have stopped 7.5 minutes short of the school. This means he traveled Distance=rate* time .5Km/hour*52.5 minutes or 26.25 KM. His son therefore traveled 3.75km/hour by the time he met his dad at 4:52.5. It took the son 52.5 minutes to travel 3.75 km. Because we are trying to find the son's rate per hour (i.e. 60 minutes) and we have his speed for 52.5 minutes it's best to convert to km/minute then multiply by 60 to get km/hour
3.75km/52.5 = .07 km/minute
.07km/minute*60 minutes = 4.28 km/hour.
Answer: C. 4.28 km/hr
Question: If 49(7^x) = 1 then x=
A.–2
B.–1
C.0
D.1
Answer: A.–2
Explanation: 7^x = 1/49
7^x = 1/7^2
7^x= 7^-2
x = -2
A
Question: A store’s selling price of $2240 for a certain computer would yield a profit of 30 percent of the store’s cost for the computer. What selling price would yield a profit of 40 percent of the computer’s cost?
A.	$2400
B.	$2412
C.	$2650
D.	$2732
Answer: B.	$2412
Explanation: 1.3x = 2240
x=2240/1.3
so, 1.4X = 2240*1.4/1.3= 2412
Answer:- B
Question: A person purchases 90 clocks and sells 40 clocks at a gain of 10% and 50 clocks at a gain of 20%. If he sold all of them at a uniform profit of 15%, then he would have got Rs. 40 less. The cost price of each clock is:?
A.40
B.60
C.80
D.67
Answer: C.80
Explanation: Let C.P. of clock be Rs. x.
Then, C.P. of 90 clocks = Rs. 90x.
[(110% of 40x) + (120% of 50x)] - (115% of 90x) = 40
44x + 60x - 103.5x = 40
0.5x = 40 => x = 80
Answer: C
Question: Joe drives 180 miles at 60 miles per hour, and then he drives the next 120 miles at 40 miles per hour. What is his average speed for the entire trip in miles per hour?
A.42
B.50
C.50
D.54
Answer: B.50
Explanation: t1= 180/60=3 hours
t2=120/40=3 hours
T=t1+t2=6 hours
Avg speed = Total Distance/T
= 300/6 = 50mph=B
Question: On average, the bottle-nosed dolphin comes up for air once every five minutes; the beluga whale, a close relative, comes up for air on average once every eight minutes. The number of times a bottle-nosed dolphin would come up for air in a 24 hour period is approximately what percent greater than the number of times a beluga whale would come up for air in that same period?
A.50%
B.75%
C.100%
D.150%
Answer: D.150%
Explanation: Dolphin once in 5 min;
Beluga once in 8 min;
So, dolphin comes up 1.6 times frequently than beluga, which is 150% (8-5)/2*100.
Answer: D.
Question: What is the sum of all possible 3-digit numbers that can be constructed using the digits 1, 3, and 4 if each digit can be used only once in each number?
A.1443
B.1554
C.1665
D.1776
Answer: D.1776
Explanation: There are 6 possible arrangements of the three numbers.
Then each number will be in the hundreds, tens, and ones place two times each.
The sum is 2(111) + 2(333) + 2(444) = 1776
The answer is D.
Question: An amount of Rs. 100000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 3/4 %, then the amount invested in each share was?
A.37583
B.37500
C.37507
D.37508
Answer: B.37500
Explanation: Let the sum invested at 9% be Rs. x and that invested at 11% be Rs. (100000 - x). Then,
(x * 9 * 1)/100 + [(100000 - x) * 11 * 1]/100 = (100000 * 39/4 * 1/100)
(9x + 1100000 - 11x)/100 = 39000/4 = 9750
x = 62500
Sum invested at 9% = Rs. 62500
Sum invested at 11% = Rs. (100000 - 62500) = Rs. 37500.
Answer:B