RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is
A.100 gallons
B.110 gallons
C.120 gallons
D.130 gallons
Answer: C.120 gallons
Explanation: Work done by the waste pipe in 1 minute = 1/15-(1/20+1/24)
= -1/40[-ve means emptying]
so, volume of 1/40 part =3 gallons
volume of whole = 3*40=120 gallons
ANSWER:C
Question: A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
A.39
B.27
C.40
D.88
Answer: C.40
Explanation: Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (2/25) = 40 seconds
Answer: C
Question: Of the 800 employees of Company X, 70 percent have been with the company for at least ten years. If y of theselong-termmembers were to retire and no other employee changes were to occur, what value of y would reduce the percent oflong-termemployees in the company to 40 percent ?
A.400
B.160
C.112
D.80
Answer: A.400
Explanation: Original (Long-Term is 70%)
Total = 800
Long-Term = .7(800) = 560
New (Long-Term is 40%)
New Total = 800 - y
New Long-Term = 560 - y
560 - y = .4 (800 - y)
y = 400
Answer: A
Question: 20% of an 30% salt solution is replaced with water. From the resulting solution, again 20% is replaced with water. This step is repeated once more. What is the concentration of salt in the final solution obtained
A.19.58%
B.15.36%
C.20%
D.9.72%
Answer: B.15.36%
Explanation: A quick answer: (30)(0.8)(0.8)(0.8)
Imagine you have 100 ml of 30% salt solution.
In step 1, 20% of the salt solution is replaced with water. This means 80% of the original salt quantity remains. Hence the resultant concentration is (30)(0.8)
This process is repeated for step 2 and three. Hence, we multiply 30 ml two more times with 0.8.
This gives the final concentration as 30x0.8x0.8x0.8 = 15.36%
Answer: B
Question: The difference between the simple interest received from two different sources on 1500 for 3 years is 13.50. The difference between their rates of interest is:
A.0.1%
B.0.2%
C.0.3%
D.0.4%
Answer: C.0.3%
Explanation: (1500×R1×3/100)−(1500×R2×3100)=13.50
⇒ 4500(R1 - R2) = 1350 ⇒ R1 - R2 = 1350⁄4500 = 0.3%
Answer C
Question: A team of 8 students goes on an excursion, in two cars, of which one can seat 5 and the other only 4. In how many ways can they travel?
A.392
B.126
C.26
D.9
Answer: B.126
Explanation: Solution:
There are 8 students and the maximum capacity of the cars together is 9.
We may divide the 8 students as follows:
Case I:
5 students in the first car and 3 in the second.
Hence, 8 students are divided into groups of 5 and 3 in 8C3 = 56 ways.
Case II:
4 students in the first car and 4 in the second.
So, 8 students are divided into two groups of 4 and 4 in 8C4 = 78 ways.
Therefore, the total number of ways in which 8 students can travel is:
56 +70 = 126
Answer: Option B
Question: (228% of 1265) ÷ 6 = ?
A.A)125
B.B)175
C.C)481
D.D)375
Answer: C.C)481
Explanation: Explanation :
? = (228 x 1265/100) ÷ 6 = 288420/600 = 481
Answer : Option C
Question: While flying over the Pacific, an airplane makes a 25° turn to the right to avoid a storm. If, as a result, the airplane is traveling in a direction 9° east of north, in what direction was it originally flying?
A.(a) 30° west of north
B.(b) 30° east of north
C.(c) 16° west of north
D.(d) 16° east of north
Answer: C.(c) 16° west of north
Explanation: If after a turn of 25° you are 9°NEast, with a 16° turn you would be perfectly pointing at north. So you were, before the turn, 16° to the other side (West).
Answer C)
Question: John left home and drove at the rate of 45 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 55 mph to reach his destination. How many miles did John drive?
A.250 miles
B.255 miles
C.258 miles
D.265 miles
Answer: B.255 miles
Explanation: 2*45=90;
3*55=165;
90+165=255 miles
ANSWER:B
Question: Two trains, each 100 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is?
A.22
B.77
C.60
D.88
Answer: C.60
Explanation: Let the speed of the slower train be x m/sec.
Then, speed of the train = 2x m/sec.
Relative speed = ( x + 2x) = 3x m/sec.
(100 + 100)/8 = 3x => x = 25/3.
So, speed of the faster train = 50/3 = 50/3 * 18/5 = 60 km/hr.
Answer:C
Question: Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 40 percent ryegrass, what percent of the weight of this mixture is X ?
A. 100%
B. 33.33 %
C. 40%
D. 50%
Answer: A. 100%
Explanation: ---------------->Ryegrass
X-------------->	40%
Y-------------->	25%
M(mixture)---->40%
0.4X + (M-X)0.25 = 0.4M
0.15X = 0.15M
X = 1M
X = 100% of M
A
Question: A 180 meter long train crosses a man standing on the platform in 6 sec. What is the speed of the train?
A.176 kmph
B.108 kmph
C.176 kmph
D.134 kmph
Answer: B.108 kmph
Explanation: S = 180/6 * 18/5
= 108 kmph
Answer: B
Question: If @ is a binary operation defined as the difference between an integer n and the product of n and 5, then what is the largest positive integer n such that the outcome of the binary operation of n is less than 18?
A.1
B.2
C.3
D.4
Answer: D.4
Explanation: @(n) = 5n - n
We need to find the largest positive integer such that 5n - n < 18.
Then 4n < 18 and n < 4.5
The largest possible integer is n = 4.
The answer is D.
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 15 sec. What is the length of the fast train?
A.83 7/6 m
B.83 7/4 m
C.83 7/2 m
D.83 1/3 m
Answer: D.83 1/3 m
Explanation: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 15 = 750/9 = 83 1/3 m.Answer:D
Question: A corporation double its annual bonus to 100 of its employees. What percent of the employees’ new bonus is the increase?
A.50%
B.12%
C.8%
D.6%
Answer: A.50%
Explanation: Let the annual bonus be X.
A corporation double its annual bonus.
So new bonus = 2X.
Increase = 2X-X =X
The increase is what percent of the employees’ new bonus
= (X/2X)*100
= 50%
Hence A.
Question: i row from a to b against the current in 8 hrs and from b to a in 2 hrs if speed of river is 9 m/sec.what is the speed of boat in still water.
A.10 m/sec
B.15 m/sec
C.25 m/sec
D.18 m/sec
Answer: B.15 m/sec
Explanation: If x m/sec is my speed in still water , then
(x+9)*2*3600= (x-9)*8*3600
6x=90
x= 15 m/sec
ANSWER:B
Question: 476 ** 0 is divisible by both 3 and 11. The non-zero digits in the hundred's and ten's places are respectively:
A.7 and 4
B.7 and 5
C.8 and 5
D.6 and 4
Answer: C.8 and 5
Explanation: Let the given number be 476 xy 0.
Then (4 + 7 + 6 + x + y + 0) = (17 + x + y) must be divisible by 3.
And, (0 + x + 7) - (y + 6 + 4) = (x - y -3) must be either 0 or 11.
x - y - 3 = 0 y = x - 3
(17 + x + y) = (17 + x + x - 3) = (2x + 14)
x= 2 or x = 8.
x = 8 and y = 5.
ANSWER C
Question: A man is 30 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?
A.23 years
B.28 years
C.21 years
D.20 years
Answer: B.28 years
Explanation: Let present age of the son =x years
Then, present age the man =(x+30) years
Given that, in 2 years, man's age will be twice the age of his son
â‡’(x+30)+2=2(x+2)
â‡’x=28
ANSWER:B
Question: After decreasing 24% in the price of an article costs Rs.912. Find the actual cost of an article?
A.1200
B.2899
C.1200
D.2781
Answer: C.1200
Explanation: CP* (76/100) = 912
CP= 12 * 100 => CP
= 1200
Answer:C
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?
A.3630
B.9232
C.8828
D.2387
Answer: A.3630
Explanation: 6300:4200:10500
3:2:5
3/10 * 12100 = 3630
Answer: A
Question: At a certain supplier, a machine of type A costs $25,000 and a machine of type B costs $50,000. Each machine can be purchased by making a 20 percent down payment and repaying the remainder of the cost and the finance charges over a period of time. If the finance charges are equal to 40 percent of the remainder of the cost, how much less would 2 machines of type A cost than 1 machine of type B under this arrangement?
A.$0
B.$11,200
C.$12,000
D.$12,800
Answer: A.$0
Explanation: Total Cost of 2 Machines of Type A
= 20% of (Cost of 2 machine A) + remainder + 40 % remainder
= 20% of 50000 + (50000 - 20% of 50000) + 40% of (50000 - 20% of 50000)
= 66000
Total Cost of 1 Machine of Type B
= 20% of (Cost of 1 machine B) + remainder + 40 % remainder
= 20% of 50000 + (50000 - 20% of 50000) + 40% of (50000 - 20% of 50000)
= 66000
Diff = 66000 - 66000 = 0
Hence, A.
Question: In a box, there are 3 grey, 5 brown and 2 yellow pencils. One pen is picked up randomly. What is the probability that it is neither brown nor yellow?
A.2/5
B.3/5
C.3/10
D.3/4
Answer: C.3/10
Explanation: Explanation :
Neither brown nor yellow means the pencils drawn is grey.
Total number of outcomes = (3+5+2) = 10.
Number of Favourable outcomes = 3 = Number of grey pencils.
Hence, Probability of the event = 3/10 = 3/10.
Answer : C
Question: A sum of money invested at C.I. amounts to Rs. 800 in 3 years to Rs. 840 in 4 years. The rate of interest per annum is?
A.6%
B.2%
C.5%
D.9%
Answer: C.5%
Explanation: S.I. on Rs. 800 for 1 year
= (840 - 800) = Rs. 40 Rate
= (100 * 40)/(800 * 1)
= 5%
Answer:C
Question: In 10 years, A will be twice as old as B was 10 years ago. If A is now 8 years older than B the present age of B is
A.37
B.38
C.39
D.40
Answer: B.38
Explanation: let present age of A be a and B be b
a+10 = 2*(b-10)
=> 2b-a = 30 ......(i)
a = b+8
=>2b-b-8 = 30
b=38
so the present age of b is 38 years
ANSWER:B
Question: If y^2 - x^2 = 2xy, then (x+y)^2 =
A.x^2
B.3x^2
C.4xy
D.2y^2
Answer: D.2y^2
Explanation: Its B
y^2 -x^2 = 2xy
y^2 = 2xy + x^2
Add y^2 on both sides we get
y^2 +y^2 = x^2+2xy+y^2
2y^2 = (x+y)^2
Correct Option : D
Question: If 1 persons can do 1 times of a particular work in 1 day, then, 7 persons can do 7 times of that work in
?
A.3 days
B.1 day
C.9 days
D.11 days
Answer: B.1 day
Explanation: That is, 1 person can do one time of the work in 1 day.
Therefore, 7 persons can do 7 times work in the same 1 day itself.
Option 'B'
Question: The speed of a train is 94 kmph. What is the distance covered by it in 12 minutes?
A.15 kmph
B.11 kmph
C.88 kmph
D.19 kmph
Answer: D.19 kmph
Explanation: 94 * 12/60
= 18.8 kmph
Answer:D
Question: 5, 9, 17, 29, 45, ?
A.65
B.56
C.74
D.57
Answer: A.65
Explanation: The pattern is + 4, + 8, + 12, + 16, ....
Answer : A.
Question: What is the two-digit number? I. The difference between the two-digit number and the number formed by interchanging the digits is 27. II. The difference between the two digits is 3. III. The digit at unit's place is less than that at ten's place by 3.
A.I and II
B.II and III only
C.all
D.Even with all I, II and III, answer cannot be give.
Answer: D.Even with all I, II and III, answer cannot be give.
Explanation: Let the tens and units digit be x and y respectively.
I. (10x + y) - (10y + x) x - y = 3.
II. x - y = 3.
III. x - y = 3.
Thus, even all the given three statements together do not give the answer.
Correct answer is (D).
Question: During a two-week period, the price of an ounce of silver increased by 10 percent by the end of the first week and then decreased by 10 percent of this new price by the end of the second week. If the price of silver was x dollars per ounce at the beginning of the two-week period, what was the price, in dollars per ounce, by the end of the period?
A.0.97x
B.0.98x
C.0.99x
D.x
Answer: C.0.99x
Explanation: The price at the end is 0.9(1.1x)=0.99x
The answer is C.
Question: By selling an article at Rs.600, a profit of 60% is made. Find its cost price?
A.228
B.267
C.375
D.480
Answer: C.375
Explanation: SP = 600
CP = (SP)*[100/(100+P)]
= 600 * [100/(100+60)]
= 600 * [100/160] = Rs.375
Answer: C
Question: The minute hand of a clock overtakes the hour hand at intervals of 65 minutes of the correct time. How much a day does the clock gain or lose?
A.(10 + 10/143 )min
B.(10 + 10/843 )min
C.(10 + 19/143 )min
D.(90 + 10/143 )min
Answer: A.(10 + 10/143 )min
Explanation: In a correct clock, the minute hand gains 55 min. spaces over the hour hand in 60 minutes.
To be together again, the minute hand must gain 60 minutes over the hour hand.
55 minutes are gained in 60 min.
60 min. are gained in [(60/55) * 60] min = min.
But they are together after 65 min.
Therefore, gain in 65 minutes = = min.
Gain in 24 hours = = 1440/143 min.
Therefore, the clock gains (10 + 10/143 )minutes in 24 hours.
Answer: A) (10 + 10/143 )min
Question: If d is the mean of x, y, and z, what is the mean of x + 5, y + 5, z + 5 ?
A.d
B.3d
C.15d
D.d + 5
Answer: D.d + 5
Explanation: If we add or subtract a constant to each term in a set:
Mean will increase or decrease by the same constant.
SD will not change.
If we increase or decrease each term in a set by the same percent (multiply by a constant):
Mean will increase or decrease by the same percent.
SD will increase or decrease by the same percent.
So in our case mean will increase by 5 as we are adding 5 to each term in a set --> Mean =d + 5.
Answer: D.
Question: The remainder of the division of a number by 63 is 27. What will be the remainder when that number is divided by 8?
Please explain
A.4
B.5
C.6
D.2
Answer: D.2
Explanation: The easiest way to solve this question is by plugging in a number. Here are the steps I followed:
1) Choose a number X that when divided by 63 gives you 27 as a remainder. So I did x = 63 + 27 = 90. (90/63 = 1R27)
2) Divide that number by 8. 90/8 = 11R2
Since the remainder is 2, the correct answer is choice D.
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?
A.2.29
B.2.88
C.2.2
D.2.12
Answer: B.2.88
Explanation: M = 6
S = 1.2
DS = 6 + 1.2 = 7.2
US = 6 - 1.2 = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
Answer: B
Question: The probability that a visitor at the mall buys a pack of candy is 30%. If three visitors come to the mall today, what is the probability that exactly two visitors will buy a pack of candy?
A.0.343
B.0.147
C.0.189
D.0.063
Answer: C.0.189
Explanation: 0.3*0.3*0.7 is equivalent to saying the the first person picks candy and second person picks candy and third person doesn't pick candy.
however this is a different case compared to
0.3*0.7*0.3 is equivalent to saying the the first person picks candy and second person doesn't pick candy and third person picks candy.
which in turn is a different case compared to
0.7*0.3*0.3 (I'll skip the verbose comments)
Hence the answer is 3*(0.3*0.3*0.7)=0.189
ANSWER C
Question: Which of the following is closest to the difference between sum R of all proper fractions (fractions less than 1) in the form 1/x , where x is a positive digit, and the product of all proper fractions in the form y/(y+1), where y is a positive digit?
A.2.82
B.2.72
C.1.82
D.1.72
Answer: D.1.72
Explanation: Sum R of all proper fractions (fractions less than 1) in the form 1/x, where x is a positive digit:
1/1 + 1/2 + 1/3 +.....+ 1/9
This is a harmonic progression. Harmonic progression is inverse of arithmetic progression.
Approximate sum of a harmonic progression with even number of terms = number of terms * (average of middle 2 terms)
Approximate sum of a harmonic progression with odd number of terms = number of terms * (middle term)
The actual sum will be slightly more than the approximation.
Here we have 9 terms (odd).
Sum = 9 * 1/5
= 9/5
Product of all proper fractions in the form y/(y+1), where y is a positive digit:
1/2 * 2/3 * 3/4 *.....*9/10
We will be left with 1/10.
Required = 9/5 - 1/10
= 1.8 - 0.1
= 1.7
Closest is 1.72
Answer (D).
Question: If a - b = 4 and a2 + b2 = 18, find the value of ab.
A.9
B.1
C.2
D.18
Answer: B.1
Explanation: 2ab = (a2 + b2) - (a - b)2
= 18 - 16 = 2
ab = 1.
Answer: B
Question: Two cars A and B start from Boston and New York respectively simultaneously and travel towards each other at constant speeds along the same route. After meeting at a point between Boston and New York the two cars A and B proceed to their respective destinations of New York and Boston. Car A reaches New York 60 minutes after the two cars have met and Car B reaches Boston 90 minutes after they have met. How long did Car A take to cover the distance between Boston and New York?
A.1 hour
B.1 hour 10 minutes
C.2 hours 30 minutes
D.2 hours
Answer: D.2 hours
Explanation: Both cars leave at the same time
Both cars travel at constant speed
Stealing a useful piece of information from Paragkan:
If two objects A and B start from opposite points and, after having met en route, reach their respective destinations in a and b mins (or any other measure of time) respectively, then the ratio of their speeds
ratio of speed: (a/b) = sq. rt(b/a)
sq. rt(b/a)
sq. rt(90/60)
sq. rt(3/2)
So, for every three units of distance A travels, B travels two. Because we know the ratio of speed and the time it took B to travel the distance A hasn't yet covered, we can find the time it took A to cover the distance B did in 90 minutes.
90*(2/3)where represents the lesser amount of time it took A to travel the distance B did in 90 minutes.
= 60 minutes.
Therefore, A took 60 minutes to travel the first portion then 60 minutes to travel the distance B did in 90 minutes. A spent (60+60)=120 minutes on the road.
D. 2 hours
Question: The marked price of an article is 10% higher than the cost price. A discount of 10% is given on the marked price. In this kind of sale, the seller:
A.bears no loss, no gain
B.gains 1%
C.loses 1%
D.None of these
Answer: C.loses 1%
Explanation: Let C.P.=Rs. 100. Then, marked price=Rs. 110.
S.P=90% of Rs. 110=Rs. 99. So, loss=1%
ANSWER:C
Question: A shopkeeper sold an book offering a discount of 5% and earned a profit of 30%. What would have been the percentage of profit earned if no discount was offered?
A.140
B.120
C.130
D.136.8
Answer: D.136.8
Explanation: Let C.P. be $100.
Then, S.P. = $130
Let marked price be $x. Then, 95/100 x = 130
x = 13000/95 = $136.8
Now, S.P. = $136.8, C.P. = $100
Profit % = 136.8%.
D
Question: How many digits 2^200 has?
A.31
B.61
C.50
D.99
Answer: B.61
Explanation: 2^10 = 1.024 * 10^3 => 2^100 = (1.024)^10 * 10^60
therefore 61 digits would be my best guess
B
Question: Before January, the price of a dress was D and the price of a matching pair of shoes was H. In January, the price of the dress increased by 40% and the price of the shoes increased by 50%. In March, Roberta bought both items with a 30% discount. If D = 4H, which of the following represents the amount that Roberta paid?
A.D + 40
B.D + H – 1
C.D + 2H
D.4.97H
Answer: D.4.97H
Explanation: before Discount price was: 1.4D+1.5H
After Discount: 1.4D +1.5H-.42D-.45H
substitute D=4H
final value: 4.97H
Ans Is D :
Question: Compare the rates of two trains, one travelling at 90 km/hr and other is at 50m/s?
A.2:1
B.1:2
C.1:3
D.3:1
Answer: B.1:2
Explanation: speed of the 1st train = 90km/hr
speed of the 2nd train = 50m/s = 50*18/5 = 180km/hr
ratio of the speeds of the train = 90:180 = 1:2
Answer is B
Question: The mean of set U does not exceed mean of any subset of set U. Which of the following must be true about set U?
I. Set U contains only one element
II. All elements in set U are equal
III. The median of set U equals the mean of set U
A.of the three qualities is necessary
B.II only
C.III only
D.II and III only
Answer: D.II and III only
Explanation: The only necessary condition seems to be II.
If all nos are equal.... them mean of any subset is the same.
I is obviously ruled out ( e.g. U = {1,1,1} )
But III, what about 3?
It is not necessary in itself, rather, is automatically implied by II.
All sets that satsify II satisfy III=D
Question: A car travels from P to Q at a constant speed. If its speed were increased by 20km/hr, it would have taken two hour lesser to cover the distance. It would have taken further 30 minutes lesser if the speed was further increased by 10 km/hr. The distance between the two cities
A.100 km
B.120 km
C.150 km
D.180 km
Answer: C.150 km
Explanation: Explanation :
Let the distance between two cities = D,
D = x*t (x = usual speed and t is the actual time)
D = (X + 20)*(T -2) and D = (X +30)*(T – 2.5)
Solve the above equation, u will get T = 5 and X = 30, so distance = 30*5 = 150 km
Answer – C
Question: A restaurant spends one third of its monthly budget for rent and one third of the rest for food and beverages. What percentage of the budget does the restaurant spend for food and beverages?
A.23.5%
B.32.5%
C.22.2%
D.37.5%
Answer: D.37.5%
Explanation: Spend on rent = 1/3
Spend on food and beverage= 1/3 of remaining = 1/3*2/3= 2/9
so 2/9= 22.2%
C is the answer
Question: The expression (5x+2)/(x+3) is equivalent to which of the following?
A.(5-2)/3
B.5 – (2/3)
C.5 – (x)/(x+3)
D.5 – (13)/(x+3)
Answer: D.5 – (13)/(x+3)
Explanation: Easiest way is to pick any number and put in (5x+2)/(x+3). Then check the options with the same number.
I took x=1 and got D as the answer.
Question: A person purchased a TV set for Rs. 16000 and a DVD player for Rs. 6250. He sold both the items together for Rs. 31150. What percentage of profit did he make?
A. 30% B. 35%
A.47%
B.50%
C.40%
D.48%
Answer: C.40%
Explanation: The total CP = Rs. 16000 + Rs. 6250
= Rs. 22250 and SP
= Rs. 31150
Profit(%) = (31150 - 22250)/22250 * 100
= 40%
Answer: C
Question: If the cost price is 98% of sp then what is the profit %
A.4.07%
B.4%
C.2.7%
D.2.04%
Answer: D.2.04%
Explanation: Sol. sp=Rs100 : then cp=Rs 98:profit =Rs 2.
Profit={(2/98)*100}%=2.04%
Answer is D.
Question: A and B entered into a partnership investing Rs.25000 and Rs.30000 respectively. After 4 months C also joined the business with an investment of Rs.35000. What is the share of C in an annual profit of Rs.47000?
A.Rs.8202
B.Rs.83902
C.Rs.14372
D.Rs.14000
Answer: D.Rs.14000
Explanation: 25*12: 30*12: 35*8
15:18:14
14/47 * 47000 = 14000
Answer:D
Question: A certain meter records voltage between 0 and 10 volts inclusive. If the average value of 3 recordings on the meter was 7 volts, what was the smallest possible recording in volts?
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: if average of 3 is 7 so sum of 3 should be 21
3 recording can be from 0-10 inclusive
to find one smallest other two should be highest
so, lets assume three var are a,b,c
say a is smallest and give b and c greatest readings say 9 and 9
so a has to be 3
B
Question: In what time will a train 150 m long cross an electric pole, it its speed be 144 km/hr?
A.2.50 sec
B.2.60 sec
C.3.75 sec
D.2.9 sec
Answer: C.3.75 sec
Explanation: Speed = 144 * 5/18 = 40 m/sec
Time taken = 150/40
= 3.75 sec.
Answer: C
Question: Population of a city in 20004 was 1000000. If in 2005 there isan increment of 20% , in 2006 there is a decrements of 35 % and in 2007 there is an increment of 45%, then find the population of city atthe end of the year 2007
A.1131000
B.979923
C.980241
D.2356677
Answer: A.1131000
Explanation: Required population = P (1 + R1/100)(1 - R2/100)(1 + R3/100)
= P (1 + 20/100)(1 - 35/100)(1 + 45/100)
= 1131000
A
Question: An unbiased coin is tossed 5 times. Find the chance that head will appear exactly 3 times.
A.18/32
B.10/16
C.5/16
D.5/32
Answer: C.5/16
Explanation: Explanation :
Reqd probability
= 5C3 x (1/2)3 x (1/2)2
= 5!/3!(5 - 3)! x (1/2)3 x (1/2)2
= 10 x 1/8 x 1/4 = 5/16
Answer : Option C
Question: 1600 men have provisions for 28 days in the temple. If after 4 days, 400 men leave the temple, how long will the food last now?
A.12 days
B.18 days
C.32 days
D.16 days
Answer: C.32 days
Explanation: 1600 ---- 28 days
1600 ---- 24
1200 ---- ?
1600*24 = 1200*x
x = 32 days
Answer: C
Question: In a garden, 26 trees are planted at equal distances along a yard 800 metres long, one tree being at each end of the yard. What is the distance between two consecutive trees?
A.10
B.8
C.32
D.14
Answer: C.32
Explanation: 26 trees have 25 gaps between them.
Length of each gap = 800/25 = 32
i.e., distance between two consecutive trees = 32
Answer is C.