RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A farming field can be ploughed by 6 tractors in 4 days. When 6 tractors work together, each of them ploughs 120 hectares a day. If two of the tractors were moved to another field, then the remaining 4 tractors could plough the same field in 5 days. How many hectares a day would one tractor plough then?
A.144
B.121
C.256
D.320
Answer: A.144
Explanation: If each of 6 tractors ploughed 120 hectares a day and they finished the work in 4 days, then the whole field is: 120⋅6⋅4=720⋅4=2880 hectares. Let's suppose that each of the four tractors ploughed x hectares a day. Therefore in 5 days they ploughed
5⋅4⋅x=20⋅x hectares, which equals the area of the whole field, 2880 hectares.
So, we get 20x=2880
x=288020=144. Hence, each of the four tractors would plough 144 hectares a day.
So answer is A
Question: subash can copy 50 pages in 10 hrs.subash and prakash together can copy 300 pages in 40 hours.in how much time prakash can copy 10 pages.
A.8
B.10
C.12
D.4
Answer: D.4
Explanation: subhas 's 1 hr copy page=50/10=5 page
(subhas+prakash)'s 1 hr copy page=300/40=7.5 page
from above prakash's 1 hr copy page= 2.5 page
so time taken in 30 page's copy =(10/2.5)=4 hrs
ANSWER:D
Question: The product Z of two prime numbers is between 15 and 36. If one of the prime numbers is greater than 2 but less than 6 and the other prime number is greater than 8 but less than 24, then what is Z?
A.35
B.33
C.28
D.21
Answer: B.33
Explanation: The smallest possible product is 33 which is 3*11.
All other products are too big.
The answer is B.
Question: Laura can paint 1/x of a certain room in 20 minutes. What fraction Z of the same room can Joseph paint in 20 minutes if the two of them can paint the room in an hour, working together at their respective rates?
A.1/(3x)
B.3x/(x-3)
C.(x – 3)/(3x)
D.x/(x-3)
Answer: C.(x – 3)/(3x)
Explanation: Options with variables are often done by plugging in numbers.
Both working together can paint the room in 1 hr so if their individual rates were equal, each would take 2 hours alone.
2 hours is 120 mins so in 20 mins each would complete Z=120/20 = 1/6th of the room alone.
So if x = 6 (Laura completes 1/6th of the room in 20 mins), the correct option will give 1/6. (Joseph will also paint 1/6th of the room if their rates are same)
If you put x = 6 in the options, only option (C) will give 1/6
Answer (C)
Question: If one-third of one-fourth of a number is 25, then three-tenth of that number is:
A. 35
A.23
B.90
C.26
D.54
Answer: B.90
Explanation: Explanation:
The number is 1/3 of 1/4 is =15 then 1/3 Ã— 1/4 = 25
Number is 300 then 300 Ã— 3/10 = 90
Answer: B
Question: 13 sheeps and 9 pigs were bought for Rs. 1291.85.If the average price of a sheep be Rs. 74. What
is the average price of a pig.
A.Rs. 26.65
B.Rs. 36.55
C.Rs. 35.65
D.Rs. 36.65
Answer: D.Rs. 36.65
Explanation: Average price of a sheep = Rs. 74
: . Total price of 13 sheeps
= (74*13) = Rs. 962
But, total price of 13 sheeps and 9 pigs
= Rs. 1291.85
Total price of 9 pigs
= Rs. (1291.85-962) = Rs. 329.85
Hence, average price of a pig
= (329.85/9) = Rs. 36.65
Answer is D.
Question: The probability that a number selected at random from the first 50 natural numbers is a composite number is ?
A.17/27
B.17/25
C.17/17
D.17/88
Answer: B.17/25
Explanation: The number of exhaustive events = ⁵⁰C₁ = 50.
We have 15 primes from 1 to 50.
Number of favourable cases are 34.
Required probability = 34/50 =17/25.
Answer:B
Question: What percent is 36 paisa's of 12 rupees?
A.3 %
B.4 %
C.5 %
D.6 %
Answer: A.3 %
Explanation: 12 Rupees = 1200paisa's
36/1200 × 100 = 3/12
12/3 = 3 %
A
Question: add 11% of 36 and 12% of 64.
A.9.5
B.10.5
C.11.5
D.12
Answer: C.11.5
Explanation: 11% of 36 + 12% of 64
36*11/100+64*12/100
3.9+7.6=11.5
answer C
Question: Without stoppages, a train travels certain distance with an average speed of 400 km/h, and with stoppages, it covers the same distance with an average speed of 360 km/h. How many minutes per hour the train stops ?
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: Due to stoppages, it covers 40 km less .
Time taken to cover 40 km = 40â„400h = 1â„10h
= 1â„10 Ã— 60 min = 6 min
Answer D
Question: 30 buses are running between two places P and Q. In how many ways can a person go from P to Q and return by a different bus?
A.625
B.870
C.576
D.676
Answer: B.870
Explanation: we can go in any bus out of the 30 buses.
Hence He can go in 30 ways.
Since we can not come back in the same bus that he used for travelling,
we can return in 29 ways.
Total number of ways = 30 x 29 = 870
ANSWER:B
Question: A man buys 25 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 25 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?
A.55
B.82
C.73
D.75
Answer: D.75
Explanation: 20% in 25 lts is5. So water = 25-5 = 20 lts. 30% of 25 lts =7.5. So water in 2nd mixture = 25-7.5 =17.5 lts. Now total quantity = 25 + 25 =50 lts. Total water in it will be 20 + 17.5= 37.5 lts. % of water = (100*37.5)/50 = 75.
ANSWER:D
Question: 1300 boys and 700 girls are examined in a test; 52% of the boys and 43% of the girls pass. The percentage of the total who failed is ?
A.A)63.3%
B.B)52.4%
C.C)81.2%
D.D)51.15%
Answer: D.D)51.15%
Explanation: Total number of students = 1300+700 = 2000
Number of students passed = (52% of 1300+43% of 700) = 676+301 = 977
number of failures = 1023*100/2000= 51.15%
Answer is D
Question: he population of a city is 160,000. If it increases at the rate of 6% per annum, then what will be its population 2 years hence?
A.1797787
B.1797723
C.179776
D.179728
Answer: C.179776
Explanation: Population after n years = P [1 + (R/100)]2
Population after 2 years = 160000 * [1 + 6/100]2 = (160000 x 53/50 x 53/50) = 179776
ANSWER: C
Question: Rewrite (10^38) – 85 as a base 10 integer, what is the sum of the digits in that integer?
A.354
B.357
C.330
D.370
Answer: C.330
Explanation: We know that (10^38) is ending 00, so (10^38) – 85=9....9915
total number of digits in (10^38) – 85 is 38, or 36 digits of 9 and two digits 1 and 5.
answer choice is 36*9+6=330
Answer is C 330
Question: JC has to visit at least 2 European cities on his vacation trip. If he can visit only London, Paris, Rome, or Madrid, how many different itineraries, defined as the sequence of visited cities, can JC create?
A.12
B.36
C.48
D.60
Answer: D.60
Explanation: The question asks the different itineraries, and we need to count the order. For example, visiting city A first and visiting city B later is different from visiting city B first and visiting city A later.
To visit 2 cities from 4 cities, there are 4Ã—3=124Ã—3=12 different itineraries
To visit 3 cities from 4 cities, there are 4Ã—3Ã—2=244Ã—3Ã—2=24 different itineraries
To visit 4 cities from 4 cities, there are 4Ã—3Ã—2Ã—1=244Ã—3Ã—2Ã—1=24 different itineraries
The total different itineraries are 12+24+24=6012+24+24=60 different itineraries.
Answer: D
Question: If two of the four expressions a + b , b + 7b, a - b, and 7a - b are chosen at random, what is the probability that their product will be of the form of a^2-(xb)^2, where x is an integer?
A.1/2
B.1/7
C.1/6
D.1/8
Answer: C.1/6
Explanation: Total number of expressions if 2 are multiplied = 4C2 = 4!/2!*2! = 6
now we have to find the expressions that are in form of x^2 - (by)^2
one is (a+b)(a-b) = a^2 - (1b)^2
If you see any other combination we are always going to have one term of ab since 7a and 7b are there, so there can be only one type of combination like this.
therefore, probablity is 1/6
Answer : C
Question: Shiwani thought of a two-digit number and divided the number by the sum of the digits of the number. He found that the remainder is 3. Devesh also thought of a two-digit number and divided the number by the sum of the digits of the number. He also found that the remainder is 3. Find the probability that the two digit number thought by Shiwani and Devesh is TRUE?
A.1/15
B.1/14
C.1/12
D.1/13
Answer: B.1/14
Explanation: Explanation :
Let two digit number that Shiwani thought be 'xy', where x and y are single digit number.
Therefore, 10x+y=p(x+y)+3, where p is a natural number
p=10x+y−3x+y.
Also, y+x>3.
Possible values of x and y for which p is a natural number are :-
(x=1,y=5),(x=2,y=3),(x=3,y=1,3,5,9),
(x=4,y=7),(x=5,y=1,2,9),(x=6,y=Null),
(x=7,y=3,5,8),(x=8,y=Null),(x=9,y=4)
There are 14 such two digit numbers that give a remainder of 3 when divided by the sum of the digits.
Probability that Devesh thought of the same number as Shiwani = 1/14
Answer : B
Question: How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.338
B.277
C.500
D.127
Answer: C.500
Explanation: Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
800+x = (65/3) * 60
800+x = 20 * 65 = 1300
x = 1300 - 800 = 500 meters
Answer:C
Question: In how many of ways can 4 balls be placed in 3 tins if any number of balls can be placed in any tin?
A. 5C4
B. 5P4
C. 3^4
D. 4^5
Answer: C. 3^4
Explanation: Now, each of the 4 different balls has 3 choices (3 tins to go to), so total # of distribution is 3*3*3*3=3^4.
Answer: C.
Question: If the number 653ab is divisible by 90, then (a + b) = ?
A.2
B.3
C.4
D.6
Answer: C.4
Explanation: 90 = 10 x 9
Clearly, 653ab is divisible by 10, so b = 0
Now, 653a0 is divisible by 9.
So, (6 + 5 + 3 + a + 0) = (14 + a) is divisible by 9. So, a = 4.
Hence, (a + b) = (4 + 0) = 4.
ANSWER:C
Question: For all positive integers x, f(x)=f(x+1). If f(3)=15, then what is f(7)?
A.8
B.12
C.15
D.21
Answer: C.15
Explanation: Here we go---
f(x) = f(x+1) ---(1)
f(3) = 15 ----(2)
Now
f(7) = f(6+1)-----> f(6) = f(5+1)-------> f(5) = f(4+1) ------> f(4) = F(3+1)---> f(3) = 15
Now backtrack
f(4) = 15-----> f(5) = 15 ------> f(6) = 15 ----> f(7) = 15
Though I picked option C
I am still not 100% sure of the answer(don't know why)
My bets on C.
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
A.337
B.280
C.299
D.266
Answer: B.280
Explanation: x*(85/100) = (480 - x)119/100
x = 280
Answer: B
Question: In the new budget the price of milk rose by 20%. By how much percent must a person reduce his consumption so that his expenditure on it does not increase?
A.7.5%
B.9.1%
C.10.9%
D.16.67%
Answer: D.16.67%
Explanation: Reduce in consumption = R/(100+R) *100% = 20/120 *100 = 16.67%
Answer is D
Question: A car is running at a speed of 90 kmph. What distance will it cover in 15 second?
A.375 m
B.395 m
C.373 m
D.372 m
Answer: A.375 m
Explanation: Explanation:
Given : Speed = 108 kmph = (90 x (5/18)) m/sec = 25 m/sec
Distance covered in 15 second = (25 x 15) m = 375 m.
ANSWER: A
Question: A motor car starts with the speed of 70km/hr with its speed increasing every two hours by 10kmph. In how many hours will it cover 345 kms
A.4 hrs
B.5 hrs
C.6 hrs
D.4 ½ hrs
Answer: D.4 ½ hrs
Explanation: Explanation:
Distance covered in first 2 hours = 70×2 =140km
Distance covered in next 2 hours = 80×2 =160km
Remaining distance = 345 -140-160 =45km
Speed of the fifth hour =90km/hr
Time taken to cover 45km = 45/90 = ½ hr
Total time taken = 2+2+ ½ = 4 ½ hrs
Answer: Option D
Question: A military commander has to choose 2 soldiers out of a company of 4 for guarding the headquarters. How many different group combinations of 2 does he have to choose from?
A.4
B.10
C.12
D.15
Answer: B.10
Explanation: A military commander has to choose 2 soldiers out of a company of 5.
different group combinations of 2
He can do this in 5C2 ways
5*4/2*1= 10 ways
ANSWER:B
Question: In a group of 140 people, 90 have an age of more 30 years, and the others have an age of less than 20 years. If a person is selected at random from this group, what is the probability the person's age is less than 20?
A.0.35
B.0.55
C.0.65
D.0.75
Answer: A.0.35
Explanation: Number of people whose age is less than 20 is given by
140 - 90 = 50
Probability P that a person selected at random from the group is less than 20 is given by
50 / 140 = 0.35
correct answer A
Question: In a apartment, 30% of the people speak English, 20% speak Hindi and 10% speak both. If a people is selected at random, what is the probability that he has speak English or Hindi?
A.1/3
B.2/7
C.2/5
D.3/7
Answer: C.2/5
Explanation: P (E) = 30 / 100 = 3 / 10 , P (H) = 20 / 100 = 1 / 5 and P (E ∩ H) = 10 / 100 = 1 / 10
P (E or H) = P (E U H)
= P (E) + P (H) - P (E ∩ H)
= (3 / 10) + (1 / 5) - (1 / 10) = 4 / 10 = 2/5
C
Question: If a fraction is multiplied by itself and then divided by the reciprocal of the same fraction, the result is 18 26/27. Find the fraction.
A.8/27
B.1 1/3
C.2 2/3
D.3 /3
Answer: C.2 2/3
Explanation: Answer
If the required fraction be P
According to the question
(P x P) / (1/P) = 1826/27
⇒ P3 = 512/27
∴ P = 8/3 = 2 2/3
Correct Option: C
Question: If 6 spiders make 3 webs in 7 days, then how many days are needed for 1 spider to make 1 web?
A.10
B.12
C.14
D.15
Answer: C.14
Explanation: Explanation:
Let, 1 spider make 1 web in x days.
More spiders, Less days (Indirect proportion)
More webs, more days (Direct proportion)
Hence we can write as
(spiders)6:1
(webs) 1:7}::x:3
â‡’6Ã—1Ã—7=1Ã—3 Ã— x
â‡’x=14
Answer: Option C
Question: The salary of a worker is first increased by 30% and afterwards reduced by 30%. What is net change in his salary?
A.910% increase
B.10% increase
C.9% decrease
D.12% decrease
Answer: C.9% decrease
Explanation: (30 * 30)/100 = 9% decrease
ANSWER C
Question: Set A consists of integers -9, 8, 3, 10, and J; Set B consists of integers -2, 5, 0, 7, -6, and Q. If R is the median of Set A and W is the mode of set B, and R^W is a factor of 34, what is the value of Q if J is negative?
A.-2
B.Q=0
C.1
D.2
Answer: B.Q=0
Explanation: since j is negative, therefore median of the set will be 3. which is an odd number. also, we know that odd^n will always be odd. now since 34 is even, therefore 3^w will have only one factor with 34 for w=0.
mode of the set is a number which occurs maximum number of time in the set. now, since Q is the mode of the set. therefore Q=0. hence answer is B
Question: To asphalt 1km road, 30 men spent 12 days working 8 hours per day. How many days, 20 men will spend to asphalt a road of 2km working 14 hours a day?
A.24
B.23
C.24
D.20.57
Answer: D.20.57
Explanation: Man-hours required to asphalt 1 km road=30*12*8=2880
Man-hours required to asphalt 2 km road=2880*2=5760
Man-hours available per day=20*14=280
Therefore number of days=5760/280=20.57 days
Ans=D
Question: The average age of a committee of 10 members is 25 years. A member aged 55 years retired and his place was taken by another member aged 35 years . The average age of
present committee is;
A.23 years
B.38 years
C.36 years
D.35 years
Answer: A.23 years
Explanation: Total age of the committee = 25*10 = 250,
Total age when a member is retired
and a new one was joined = 250-55 +35, =230
Average age of present committee = 230/10 = 23.
ANSWER:A
Question: A board 6ft. 9 inches long is divided into 3 equal parts . What is the length of each part?
A.5ft. 7 inches
B.3ft. 7 inches
C.2ft. 3 inches
D.2ft. 7 inches
Answer: C.2ft. 3 inches
Explanation: Length of board=6ft. 9 inches=(6*12+9)inches=81 inches.
Therefore, Length of each part = (81/3) inches = 27 inches = 2ft. 3 inches
Answer is C.
Question: A company pays 18.5% dividend to its investors. If an investor buys Rs.50 shares and gets 25% on investment, at what price did the investor buy the shares?
A.25
B.66
C.18
D.37
Answer: D.37
Explanation: Explanation:
Dividend on 1 share = (18.5 * 50)/100 = Rs.9.25
Rs.25 is income on an investment of Rs.100
Rs.9.25 is income on an investment of Rs. (9.25 * 100)/25 = Rs.37
ANSWER: D
Question: A man saves 30% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 30%, he is only able to save Rs. 300 per month. What is his monthly salary?
A.Rs. 4000
B.Rs. 3750
C.Rs. 5000
D.Rs. 5500
Answer: B.Rs. 3750
Explanation: Income = Rs. 100
Expenditure = Rs. 70
Savings = Rs. 30
Present Expenditure 70+70*(30/100) = Rs. 91
Present Savings = 100 – 91 =Rs. 8
If savings is Rs. 8, salary = Rs. 100
If savings is Rs.300, salary = 100/8*300 = 3750
Answer : B
Question: What least number should be subtracted from 3,381 so that the remainder when divided by 9, 11, and 17 will leave in each case the same remainder 8 ?
A.6
B.7
C.8
D.12
Answer: B.7
Explanation: The LCM of 9, 11 and 17 is 1,683. The next multiple is 2*1,683 = 3,366.
3,366 + {remainder} = 3,366 + 8 = 3,374, which is 7 less than 3,381.
Answer: B.
Question: Company X provides bottled water to its employees in 10 liter bottles, $2 each. At least how many 10L bottles must Company X buy monthly, so that new contract with $50 fixed monthly rate and $1 for 50L bottle each paid off? (Assume that no other costs apply)
A. 28
B. 29
C. 30
D. 31
Answer: A. 28
Explanation: let the no. of 10 liter bottles be x, so the no. of 50l bottles will be x/5 (to equate the vol.) since the total cost will be equal , 2x= 50+x/5 so x= 27.77 or 28. Answer is (A).
Question: X completes a work in 120 days and Y complete the same work in 30 days. If both of them work together, then the number of days required to complete the work will be?
A.24 days.
B.22days.
C.34 days.
D.40 days.
Answer: A.24 days.
Explanation: If X can complete a work in x days and Y can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days
Therefore, here, the required number of days = 120Ã— 30/ 150 = 24 days.
A)
Question: The LCM of two numbers is 2310 and HCF is 30. If one of the numbers is 210. Then what is the other number ?
A.715
B.825
C.330
D.582
Answer: C.330
Explanation: First number * Second Number = LCM * HCF
Other number = 2310 * 30 / 210 = 11*30 = 330
ANSWER :C
Question: Between 100 and 200, how many numbers are there in which one digit is the average of the other two?
A.11
B.12
C.10
D.8
Answer: A.11
Explanation: Answer is 11 :A
Let's list the numbers between 100 and 200 that have digits in which one of them is average of the other 2.
(One rule before listing, it should always start with 1XX)
{102, 111, 123, 135, 147, 159 } in these five, except 111, the others has 2 ways of rearranging, i.e., 123 can also be written as 132, and so is for 135 as 153.
Therefore 1 + 2 * 5 numbers = 11
Question: mixture contains alcohol and water in the ratio 4 : 3. If 8 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture.
A.10
B.99
C.27
D.4
Answer: D.4
Explanation: Let the quantity of alcohol and water be 4x litres and 3x litres respectively
32x = 4(3x+5)
20x = 20
x = 1
Quantity of alcohol = (4 x 1) litres = 4 litres.
Answer: D
Question: A is 20 percent more efficient than B. If the two person can complete a piece of work in 60 days.in how many days. A working alone can complete the work
A.110
B.277
C.287
D.279
Answer: A.110
Explanation: As A is 20% more efficient than B, If B's per day work is 100 units then A's 120.
Both persons together completes (100 + 120) units = 220 units a day.
They took 60 days to complete the work. So total work = 60 x 220
If A alone set to complete the work, he takes = 60×220120=11060×220120=110 days
Answer:A
Question: Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $6 more than 1/4 of the fine and Peter paid $6 less than 1/3 of the fine, leaving pay $10 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?
A.$50
B.$40
C.$35
D.$44
Answer: A.$50
Explanation: Call the fine F. Joe paid (1/4)F + 4 and Peter paid (1/3)F – 4, leaving (1/2)F – 5 left. If we add those three up, they should add up to F.
F = [(1/4)F + 6] + [(1/3)F – 6] + [(1/2)F – 10]
F = (1/4)F + (1/3)F + (1/2)F – 10
Multiply all terms by 12 to clear the fractions.
12F = 3F + 4F + 6F – 120
12F = 13 F – 120
–F = – 120
F = 120
Well, if the fine cost $120, then Sam paid the part not covered by Joe or Peter. Half the fine is $60, and Sam paid $10 less than this: $50.
Answer = A
Question: A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?
A.32 : 48
B.32 : 42
C.32 : 45
D.32 : 41
Answer: C.32 : 45
Explanation: Explanation:
A : B
(8000*4)+(4000*8) : (9000*6)+(6000*6)
64000 : 90000
32 : 45
Answer:C
Question: 65 + 5 * 12 / (180/3) = ?
A.22
B.77
C.29
D.66
Answer: D.66
Explanation: 65 + 5 * 12 / (180/3) = 65 + 5 * 12 / (60)
= 65 + (5 * 12)/60 = 65 + 1 = 66.Answer:D
Question: Mother is aged 3times more than her daughter Rose. After 8 years, she would be two and a 1/2times of Rose's age. After further 8 years, how many times would he be of Rose's age?
A.1
B.2
C.3
D.5
Answer: B.2
Explanation: Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
(4x + 8) = 5 (x + 8)
2
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = (4x + 16)/(x + 16) = 48/24= 2.
B
Question: What approximate value should come in place of the question mark (?) in the following equation ?
2⁄7 of 1596 + 3015 = ? – 2150
A.7200
B.48000
C.5610
D.58000
Answer: C.5610
Explanation: ? ≈ 2 × 230 + 3000 + 2150
= 460 + 3000 + 2150 = 5610
Answer C
Question: If a and b are positive integers, which of the following cannot be odd?
A.(2+4a)/(4+4b)
B.(4a)/(b)
C.a/b
D.(4+a)/(2+4b)
Answer: A.(2+4a)/(4+4b)
Explanation: A. (2+4a)/(4+4b) - Under any condition this can't be odd. Answer
B. (4a)/(b) = 4.1/4 = 1 = Odd
C. a/b = 4/4 = Odd
D.(4+a)/(2+4b) = (4+2)/(2+4.1) = 1 = Odd
E.(4+a)/(1+4b) = (4+1)/(1+4.1) = 1 = Odd
ANSWER:A
Question: The telephone bill of a certain establishment is party fixed and partly varies as the number of calls consumed. When in a certain month 540 calls made the bill is Rs.1800. In another month 620 calls are consumed then the bill becomes Rs.2040. In another month 500 units are consumed due to more holidays. The bill for that month would be :
A.Rs.1560
B.Rs.1680
C.Rs.1840
D.Rs.1950
Answer: B.Rs.1680
Explanation: Let the fixed amount be Rs. X and the cost of each unit be Rs. Y.
Then, 540y + x = 1800 …. And 620y + x = 2040
On subtracting (i) from (ii), we get 80y = 240 -> y = 3
Putting y = 3 in (i) we get :
540 * 3 + x = 1800 x = (1800-1620) = 180
. : Fixed charges = Rs.180, Charge per unit = Rs.3.
Total charges for consuming 500 units = 180 +(500*3) = Rs.1680
ANSWER:B
Question: Three people each took 4 tests. If the ranges of their scores in the 4 practice tests were 17, 28 and 35, what is the minimum possible range in scores of the three test-takers?
A.a 17
B.b) 28
C.c) 35
D.d) 45
Answer: B.b) 28
Explanation: It is finding the minimum range between all their scores, if all test taker scores are between 0 and maximum range we will have:
A- 0 and 17
B- 0 and 28
therefore the minimum range is 28, it cant be any lower however you play with the numbers.
B
Question: Mary rolls a die 5 times. What is the probability that she gets a one on the last one of the five rolls?
A.100/1000
B.7775/7776
C.none
D.1
Answer: B.7775/7776
Explanation: the die has 6 sides and it was rolle 5 times, then 6*6*6*6*6=7776
the number of ways to get 1 is 1
then 1/7776
the probability would be
1-1/7776=7775/7776
Answer B
Question: Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is?
A.15
B.16
C.18
D.25
Answer: B.16
Explanation: Explanation:
Ratio of times taken by Sakshi and Tanys = 125:100 = 5:4
Suppose Tanya takes x days to do the work.
5:4 :: 20:x => x= 16 days.
Hence, Tanya takes 16 days to complete the work.
ANSWER IS B
Question: Peter bought an item at 20% discount on its original price. He sold it with 40% increase on the price he bought it. The sale price is by what percent more than the original price?
A.7.2
B.7.5
C.10
D.12
Answer: D.12
Explanation: Sol.
Let the original price be Rs. 100. Then, C.P. = Rs. 80.
S.P. = 140% of Rs. 80 = Rs. [112-100%] = 12%.
Answer D