RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If December 3rd, 1999 is a Friday, what day is January 5th, 2000?
A.Wednesday
B.Thursday
C.Friday
D.Saturday
Answer: A.Wednesday
Explanation: There is difference of 33 days from Dec. 3rd 1999 to Jan. 5th 2000.
33/7 has a remainder of 5.
Jan. 5th is: Friday + 5 days = Wednesday
The answer is A.
Question: In a class of 40 students, 2 students did not borrow any books from the library, 12 students each borrowed 1 book, 11 students each borrowed 2 books, and the rest borrowed at least 3 books. If the average number of books per student was 2, what is the maximum number of books any single student could have borrowed?
A.3
B.4
C.5
D.6
Answer: B.4
Explanation: The class borrowed a total of 40*2 = 80 books.
The 25 students who borrowed 0, 1, or 2 books borrowed a total of 12 + 11*2 = 34.
To maximize the number of books borrowed by 1 student, let's assume that 14 students borrowed 3 books and 1 student borrowed the rest.
80 - 34 - 3*14 = 4
The maximum number of books borrowed by any student is 4.
The answer is B.
Question: If the price of petrol increases by 25% and Benson intends to spend only an additional 15% on petrol, by how much % will he reduce the quantity of petrol purchased?
A.A)8%
B.B)7%
C.C)10%
D.D)6%
Answer: A.A)8%
Explanation: Explanation:
Assume that the initia price of 1 Litre petrol = Rs.100 ,Benson spends Rs.100 for petrol,
such that Benson buys 1 litre of petrol
After the increase by 25%, price of 1 Litre petrol = 100 × (100+25)/100 = Rs.125
Since Benson spends additional 15% on petrol,
amount spent by Benson = 100× (100+15)/100 = Rs.115
Hence Quantity of petrol that he can purchase = 115/125 Litre
Quantity of petrol reduced = (1−115/125) Litre
Percentage Quantity of reduction = (1−115125)/1 × 100 = 10/125 × 100 = 105 × 4 = 2 × 4 = 8%
Answer: Option A
Question: If 50 apprentices can finish a job in 4 hours, and 30 journeymen can finish the same job in 6 hours, how much of the job should be completed by 10 apprentices and 15 journeymen in one hour?
A.1/9
B.29/180
C.26/143
D.2/15
Answer: D.2/15
Explanation: 50 apprentices can finish the job in 4 hours,thus:
10 apprentices can finish the job in 4*5 = 20 hours;
In 1 hour 10 apprentices can finish 1/20 of the job.
30 journeymen can finish the same job in 4,5 hours,thus:
15 journeymen can finish the job in 6*2 = 12 hours;
In 1 hour 15 journeymen can finish 1/12 of the job.
Therefore, in 1 hour 10 apprentices and 15 journeymen can finish 1/20+1/12=2/15 of the job.
Answer: D.
Question: A taxi leaves Point A 3 hours after a bus left the same spot. The bus is traveling 30 mph slower than the taxi. Find the speed of the taxi, if it overtakes the bus in three hours.
A.60
B.72
C.48
D.36
Answer: A.60
Explanation: Let the speed of bus be v - 30, speed of taxi be v
The bus travelled a total of 6 hrs and taxi a total of 3 hrs.
Hence 6 * (v-30) = 3v
6v - 180 = 3v
3v = 180
v = 60 mph
A
Question: What is the 8th digit to the right of the decimal point in the decimal equivalent of 73/11?
A.1
B.3
C.4
D.5
Answer: B.3
Explanation: 73/11 = 6.6363....
63 is non-terminating repeating decimal.
The 8th digit to the right of decimal point will be 3.
Answer B
Question: In a certain deck of cards, each card has a positive integer written on it. In a multiplication game, a child draws a card and multiples the integer on the card by the next larger integer. If each possible product is between 28 and 200, then the least and greatest integers on the card could be
A.3 and 15
B.3 and 20
C.5 and 13
D.4 and 14
Answer: C.5 and 13
Explanation: There child draws one number then multiplies that number by the number above it. The number must be more than 28 and less than 200.
x * (x+1)
Answer gives us choices of 3,4 and 5 (JUST ABOVE 28)
3*(3+1) =12 <- WRONG
4*(4+1) =20 <- WRONG
5*(5+1) =30 <- CORRECT AS IT IS ABOVE 28
Answer gives us choices 13,14,15 and 20 (BELOW 200)
Immediately by knowing squares you should be able to rule out 15 (225) and 20 (400). And common sense dictates that as 14^2 is 196 that 14*(14+1) is above 200.
13*(13+1)=182 <- CORRECT
Answer is C) 5 and 13
Question: Marcus deposited $8,000 to open a new savings account that earned five percent annual interest, compounded semi-annually. If there were no other transactions in the account, what the amount of money in Marcuss account one year after the account was opened?
A.$8,200
B.$8,205
C.$8,400
D.$8,405
Answer: D.$8,405
Explanation: Approach #1:
5 percent annual interest compounded semi-annually --> 2.5% in 6 moths.
For the first 6 moths interest was 2.5% of $8,000, so $200;
For the next 6 moths interest was 2.5% of $8,000, plus 2.5% earned on previous interest of $200, so $200+$5=$205;
Total interest for one year was $200+$205=$405, hence balance after one year was $8,000+ $405=$8,405.
Answer: D.
Question: If a is the interest on y and y is the interest on z, the rate and time is the same on both the cases. What is the relation between a, y and z?
A.Y^2 = aZ
B.Y^3 = aZ
C.Y^3 = aY
D.Y^1 = aZ
Answer: B.Y^3 = aZ
Explanation: a = (Y*NR)/100 Y = (Z*NR)/100
a/Y = NR/100 Y/Z = NR/100
a/Y = Y/Z
Y^2 = aZ
ANSWER:B
Question: If a > 1 and b = 2^(a −1), then 4^a =
A.16b^2
B.4b^2
C.b^2
D.b^2/4
Answer: B.4b^2
Explanation: If a > 1 and b = 2^(a −1), then 4^a
Given a>1, so let's assume a=2
b=2^(a-1) = 2^(2-1) = 2, so b=2
hence, 4^a = 4^2 = 16
only 1 ans. choice can satisfy this:
A) 16b^2 --> clearly > 16
B) 4b^2 --> 4*2^2 = 16(we can stop after this as there can be only 1 right answer)
C) b^2 --> clearly < 16
D) b^2/4 --> clearly < 16
E) b^2/16 --> clearly < 16
Ans. B) 4b^2
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 8 kmph, what is the time taken to row a distance of 60 km downstream?
A.30/18
B.30/29
C.30/14
D.30/13
Answer: C.30/14
Explanation: Speed downstream = 20 + 8 = 28 kmph.
Time required to cover 60 km downstream = d/s = 60/28
= 30/14 hours.
Answer:C
Question: A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 500. How much did he have with him in the beginning?
A.s 200
B.s 1250
C.s 300
D.s 450
Answer: B.s 1250
Explanation: Suppose the amount in the beginning was Rs ’x’
Money spent on clothes = Rs 1x/3 Balance = Rs 2x/3
Money spent on food = 1/5 of 2x/3 = Rs 2x/15
Balance = 2x/3 - 2x/15 = Rs 8x/15
Money spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5
Therefore 2x/5 = 500 = 1250
ANSWER:B
Question: If a store owner increases a product’s price by 20 percent and then increases this price by another 15 percent, what percent of the original price is the total price increase?
A.20%
B.35%
C.38%
D.65%
Answer: C.38%
Explanation: let the initial price be 100
1st increase =20 % the price now is 120
2nd increase of 15% on 120 =18
final price =138, total increase =38%
ANSWER:C
Question: Today is Peter's birthday. One year, from today he will be twice as old as he was 9 years ago. How old is Peter today ?
A.25 years
B.19 years
C.17 years
D.23 years
Answer: B.19 years
Explanation: let Peter's age=xx+1=2(x-9)x=19ANSWER:B
Question: In a certain game, you perform three tasks. You flip a coin, and success would be tail. You roll a single die, and success would be a six. You pick a card from a full playing-card deck, and success would be picking a spades card. If exactly one of these three tasks is successful, then you win the game. What is the probability of winning?
A.11/16
B.23/48
C.15/32
D.14/36
Answer: B.23/48
Explanation: The answer is B
Probability of just one enent will be happining
So, Probability heads=1/2
Probability number 6 =1/6
Probability picking a spades card =1/4
so, Probability win by getting tails= 1/2*5/6*3/4 = 15/48
Probability win by getting number 6 = 1/2*1/6*3/4 = 3/48
Probability win by picking a spades card =1/2*5/6*1/4=5/48
Probability wining= 15/48+3/48+5/48 =23/48
Question: Kathleen can paint a room in 3 hours, and Anthony can paint an identical room in 4 hours. How many hours would it take Kathleen and Anthony to paint both rooms if they work together at their respective rates?
A.8/15
B.4/3
C.15/8
D.24/7
Answer: D.24/7
Explanation: (1/3 + 1/4)t=2
t=24/7
Answer: D
Question: The marks obtained by Vijay and Amith are in the ratio 4:4 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of?
A.3:2
B.6:1
C.6:5
D.6:2
Answer: A.3:2
Explanation: 4:4
3:2
-------
12:12:8
12:8
3:2
Answer: A
Question: A work as fast as B. If B can complete a work in 24days independently,the number of days in which A and B can together finish the work in?
A.2days
B.3days
C.8days
D.5days
Answer: C.8days
Explanation: Ratio of rates of working of A and B = 2:1
ratio of times taken = 1:2
A's 1day work = 1/12
B's 1day work = 1/24
A+B 1day work = 1/12 + 1/24 = 3/24 = 1/8
A and B can finish the work in 8days
Answer is C
Question: one person Tharak speed with the current is 15 km/hr and the speed of the current is 6 km/hr. Tharak's speed against the current is:
A.0 km/hr
B.1 km/hr
C.2 km/hr
D.3 km/hr
Answer: D.3 km/hr
Explanation: Man's speed with the current = 15 km/hr
=> speed of the man + speed of the current = 15 km/hr
speed of the current is 6 km/hr
Hence, speed of the man = 15-6 = 9 km/hr
man's speed against the current = speed of the man - speed of the current
= 9-6 = 3 km/hr
ANSWER:D
Question: An investor bought 200 shares of stock in ABCD company in 1990. By 1992, the investment was worth only 2/3 of its original value. By 1995, the 200 shares were worth only 1/5 of their value in 1990. By what percent did the value of the investment drop from 1992 to 1995?
A.16 2/3%
B.70%
C.33 1/3%
D.50%
Answer: B.70%
Explanation: Let price of each share in 1990 = X.
Total cost in 1990 = 200X
Now Price in 1992 = 2/3 * 200X = 400/3 * X
Now price in 1995 = 1/5 *200X= 40X
%Change in 1995 from 1992 = [(400/3* X -40X) / (400/3 *X) ] *100 = 70%
Answer B
Question: Pat wants to invest at the local bank that offers a rate of 10% per annum per year. If the interest is compounded half-yearly, how much will Pat have to invest to get Rs. 20000 at the end of a year?
A.18,140.59
B.18,410.95
C.18,590.41
D.18,950.14
Answer: A.18,140.59
Explanation: Amount = 20000; R = 10% p.a. = 5% per half-year; T = 1 year = 2 half-year
20000 = [P * (1 + 5/100)2]
P = 20000 / (1.05)2 = 18140.59
Answer: A
Question: A train when moves at an average speed of 40 kmph, reaches its destination on time. When its average speed becomes 35 kmph, then it reaches its destination 15 minutes late. Find the length of the journey
A.40km
B.50km
C.60km
D.70km
Answer: D.70km
Explanation: Difference between timings = 15 min =0.25hr.
Let the length of journey be x km.
Then,
x/35-x/40=0.25
8x - 7x = 70
x = 70km.
ANSWER:D
Question: In a rectangular coordinate system, what is the area of a triangle whose vertices have the coordinates (2, 0), (7, 4), and (7, -4)?
A.18
B.19
C.20
D.21
Answer: C.20
Explanation: The triangle is symmetric about the x-axis.
The part above the x-axis forms a triangle with a base of 5 and a height of 4.
The area of this part is (1/2)(5)(4).
We can double this to find the area of the whole triangle.
The total area is (2)(1/2)(5)(4) = 20.
The answer is C.
Question: The area of square ABCD above is 22. The shaded region is the intersection of the square and a circular region centered at C. What is the area of the shaded region?
A.18−9/4∗π
B.22−11/2∗π
C.9+9/4∗π
D.9+9/2∗π
Answer: B.22−11/2∗π
Explanation: =Square - Quarter circle
=22- pi*22/4
=22- pi*11/2
ANSWER:B
Question: If 9 is added to twice a number and this sum is multiplied by 3, the result is the same as if the number is multiplied by 4 and 13 is added to the product. What is the number?
A.-7
B.-8
C.-9
D.-10
Answer: A.-7
Explanation: let the number be x;
3(9+2x)=4x+13;
x=-7
ANSWER:A
Question: A man can row with a speed of 14 kmph in still water. If the stream flows at 8 kmph, then the speed in downstream is?
A.22
B.28
C.20
D.82
Answer: A.22
Explanation: M = 14
S = 8
DS = 14 + 8 = 22. Answer:A
Question: The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction?
A.1/3
B.2/3
C.5/9
D.5/7
Answer: C.5/9
Explanation: Explanation:
Let the numerator and denominator of the fraction be 'n' and 'd' respectively.
d = 2n - 1
(n + 1)/(d + 1) = 3/5
5n + 5 = 3d + 3
5n + 5 = 3(2n - 1) + 3 => n = 5
d = 2n - 1 => d = 9
Hence the fraction is : 5/9
C
Question: How many different subsets of the set {0, 1, 2} do not contain 0?
A.A.6
B.B.7
C.C.1
D.D.4
Answer: D.D.4
Explanation: Number of subset
Since we have 2 digits other than 0, we can take any numbers from the set of 2 to make a subset. Also it is a matter of selection and not arrangement.So we will consider combinations.
2c1+2c2=3
And one set is the NULL set having no elements in it so
3+1=4.
ANSWER D.
Question: A, B and C completed a piece of work costing Rs.1800. A worked for 6 days, B for 4 days and C for 9 days. If their daily wages are in the ratio 5 : 6 : 4, how much amount will be received by A?
A.Rs.800
B.Rs. 600
C.Rs.900
D.Rs.750
Answer: B.Rs. 600
Explanation: Explanation:
The new ratio = wages ratio × No. of days
A = 5 × 6 = 30
B = 6 × 4 = 24
C = 4 × 9 = 36
Therefore, the ratio of the amount received = 30 : 24 : 36 = 5 : 4 :6
Total ratio = 15
1 unit of ratio = 1800/15 = Rs. 120
Therefore, amount received by A = 5 units = 5 × 120 = Rs.600.
Answer: Option B
Question: The number of defects in the first five cars to come through a new production line are 9, 7, 11, 4, and 6, respectively. If the sixth car through the production line has either 3, 7, or 12 defects, for which of theses values does the mean number of defects per car for the first six cars equal the median?
I. 3
II. 7
III. 12
A.I only
B.II only
C.III only
D.I and III only
Answer: C.III only
Explanation: C
for 7 we will have mean as 7.16(approx) and median as 7 but for 3 we will have mean and median = 6.5 and for 12 we will have median and mean =8
Question: If x and y are numbers such that (x+6)(y-6)=0, what is the smallest possible value of x^2 + y^2
A.0
B.16
C.25
D.36
Answer: D.36
Explanation: From (x+6)(y-6)=0 it follows that either x=-6 or y=6. Thus either x^2=36 or y^2=36.
Now, if x^2=36, then the least value of y^2 is 0, so the least value of x^2 + y^2 = 36 + 0 = 36.
Similarly if y^2=36, then the least value of x^2 is 0, so the least value of x^2 + y^2 = 0 + 36 = 36.
Answer: D.
Question: The ratio between the sale price and the cost price of an article is 8:5. What is the ratio between the profit and the cost price of that article?
A.23
B.1:2
C.2:5
D.3:5
Answer: D.3:5
Explanation: C.P. = Rs. 5x and S.P. = Rs. 8x.
Then, Gain = Rs. 3x
Required ratio = 3x : 5x = 3:5
D
Question: Which answer is closest to the √17?
A.a 4.1
B.b 4.2
C.c 4.4
D.d 4.5
Answer: A.a 4.1
Explanation: Try filling the numbers into the y's. y x y =
4.1 x 4.1= 16.81
4.2 x 4.2 = 17.64
Answer: A
Question: A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?
A.118
B.150
C.277
D.258
Answer: B.150
Explanation: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 9 = 150 m
Answer: B
Question: A man buys 58 pens at marked price of 46 pens from a whole seller. If he sells these pens giving a discount of 1% , what is the profit percent?
A.7.6 %
B.7.7 %
C.24.82 %
D.13.6 %
Answer: C.24.82 %
Explanation: Explanation:
Let Marked price be Re. 1 each
C.P. of 58 pens = Rs. 46
S.P. of 58 pens = 99% of Rs. 58 = Rs. 57.42
Profit % = (Profit /C.P.) x 100
Profit% = (11.42/46) x 100 = 24.82 %
ANSWER: C
Question: A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 100, the runs scored by C are?
A.59
B.58
C.60
D.61
Answer: C.60
Explanation: A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
15/25 * 100 = 60
Answer:C
Question: If 0.75: x :: 5:11, then x is equal to:
A.1.12
B.1.65
C.1.2
D.1.3
Answer: B.1.65
Explanation: Explanation:
(x * 5) = (0.75 *11)
X=8.25/5 = 1.65
Answer: B
Question: The size of a flat-screen television is given as the length of the screen’s diagonal. How many square inches greater is the screen of a square 28-inch flat-screen television than a square 25 -inch flat-screen television?
A.79.5
B.89.3
C.85.5
D.75.4
Answer: A.79.5
Explanation: If we take a square with side length x and draw a diagonal, we get two isosceles right triangles.
If we focus on one such right triangle, we see that the legs have length x.
square 28-inch flat-screen television
The diagonal (hypotenuse) = 28
So, we can apply the Pythagorean Theorem to get x² + x² = 28²
Simplify: 2x² = 28²
Divide both sides by 2 to get: x² = 28²/2
Since the area of the square = x², we can see that the area of this square is 28²/2
square 25-inch flat-screen television
The diagonal (hypotenuse) = 25
So, we can apply the Pythagorean Theorem to get x² + x² = 25²
Simplify: 2x² = 25²
Divide both sides by 2 to get: x² = 25²/2
Since the area of the square = x², we can see that the area of this square is 25²/2
DIFFERENCE IN AREAS =28²/2-25²/2
= (28²- 25²)/2 = (784-625)/2 =159/2=79.5
A
Question: If the C.I. on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the S.I. on the same sum at the same rate for the same period of time is?
A.Rs. 400
B.Rs. 450
C.Rs. 460
D.Rs. 480
Answer: D.Rs. 480
Explanation: Let the sum be Rs. P. Then,
[P(1 + 25/(2 * 100))2 - P] = 510
P[(9/8)2 - 1] = 510.
Sum = Rs. 1920
So, S.I. = (1920 * 25 * 2) / (2 * 100) = Rs. 480
ANSWER:D
Question: In how many different number of ways 6 men and 4 women can sit on a shopa which can accommodate persons?
A.200
B.210
C.90
D.250
Answer: C.90
Explanation: 10p2 = 10 X 9 = 90
C)
Question: Ayush was born two years after his father's marriage. His mother is five years younger than his father but 22 years older than Ayush who is 10 years old. At what age did the father get married ?
A.22years
B.23years
C.24years
D.25years
Answer: D.25years
Explanation: Explanation:
Ayush's present age = 10 years.
His mother's present age = (10 + 22) years = 32 years.
Ayush's father's present age = (32+ 5) years = 37 years.
Ayush's father's age at the time of Ayush's birth = (37 - 10) years = 27 years.
Therefore Ayush's father's age at the time of marriage = (27 - 2) years = 25 years.
Answer: D) 25 year
Question: Find the odd man out. 187, 264, 326, 473, 682, 781
A.187
B.326
C.781
D.682
Answer: B.326
Explanation: In all numbers except 326, the middle digit is the sum of other two digits.Answer is B
Question: An old priest fell on a bottom of the well of a church.
The well is 16 inches deep.
At day time, the old priest climbs 5-inches but when at dark he slip back 4 inches.
In how many days priest will come out of the well ?
A.12-days
B.14-days
C.11-days
D.19-days
Answer: A.12-days
Explanation: A
12-days
In 11-days, he will climb 11-inch and when he climbs 5 inch more, he will be out of the well :-)
Question: there is 6 letter d,f,g,h,r,t.then how many word of 2 letter can be form through these letters?
A.720
B.360
C.48
D.30
Answer: D.30
Explanation: it will comes like 6P2
6!/4!=(1*2*3*4*5*6)/1*2*3*4=30
answer D
Question: what is 5+7
A.2
B.4
C.10
D.12
Answer: D.12
Explanation: D
Question: If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is ?
A.1/6
B.1/2
C.1/9
D.1/5
Answer: B.1/2
Explanation: The number of exhaustive outcomes is 36.
Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2
P(E) = 1 - 1/2 = 1/2.
Answer:B
Question: If 233/0.233 = 23.3/x, what is the value of x
A.233
B.23.3
C.0.233
D.0.0233
Answer: D.0.0233
Explanation: Explanation :
233/0.233 = 23.3/x
⇒ 233000/233 = 23.3/x
⇒ 1000 = 23.3/x
⇒ x = 23.3/1000 = 0.0233. Answer : Option D
Question: Latha took a loan of Rs. 2000 with simple interest for as many years as the rate of interest. If she paid Rs.180 as interest at the end of the loan period, what was the rate of interest?
A.5
B.4
C.7
D.3
Answer: D.3
Explanation: Let rate = R% and time = R years.
Then, (2000 * R * R) / 100 = 180
20R2 = 180
R2 = 9 => R = 3
Answer:D
Question: A four years NSC certificate was purchased for Rs. 500 with Rs. 1000 being the maturity value. Find the rate of S.I.
A.24%
B.22%
C.16%
D.25%
Answer: D.25%
Explanation: Explanation:
P = Rs. 500
SI = Rs.500
T = 4
R = ?
R = (100×SI)/PT = (100×500)/(500×4) =100/4 = 25%
Answer: Option D
Question: The length of a bridge in meters, which a train 90-meters long and traveling at 45 km/hr can cross in 30 seconds is?
A.145
B.215
C.265
D.285
Answer: D.285
Explanation: 45 km/h = 45000 m/3600 s = 12.5 m/s
In 30 seconds, the train can go 30(12.5) = 375 meters
Let x be the length of the bridge.
x+90 = 375 meters
x = 285 meters
The answer is D.
Question: If 20 typists can type 60 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour?
A.240
B.200
C.270
D.300
Answer: C.270
Explanation: No. of letters typing by 20 typists in 20 minutes = 60
No. of letters typing by 20 typists in 60 minutes = 60*3 = 180
No. of letters typing by 30 typists in 60 minutes = 180/20*30 = 270
Answer : C
Question: I lost Rs 68 in two races. My loss in the second race is Rs 6 more than my lose in the first race. My friend lost Rs 4 more than me in the second race. Then what is the amount lost by my friend in the second race?
A.Rs 41
B.Rs 40
C.Rs 31
D.Rs 51
Answer: A.Rs 41
Explanation: I lost Rs 68 in two races. My loss in the second race is Rs 6 more than my lose in the first race.
so I lost Rs 31 in first race and Rs 37 in 2nd race.
My friend lost Rs 4 more than me in the second race.
My friend lost 37+4= Rs 41 in the second race.
ANSWER:A
Question: 1/0.08 is equal to
A.25.5
B.2.5
C.12.5
D..25
Answer: C.12.5
Explanation: Explanation:
1/0.08 = (1 * 100)/8 = 100/8 = 12.5
Option C
Question: T = {2, 3, 4, 5}
B = {4, 5, 6, 7, 8}
Two integers will be randomly selected from the sets above, one integer from set T and one integer from set B. What is the probability that the sum of the two integers will equal 9 ?
A. 0.15
B. 0.20
C. 0.25
D. 0.30
Answer: B. 0.20
Explanation: The total number of pairs T,B possible is 4*5=20. Out of these 20 pairs only 4 sum up to 9: (2, 7); (3, 6), (4, 5) and (5, 4). The probability thus is 4/20=0.2.
Answer: B.
Question: A batsman in his 12th innings makes a score of 70 and thereby increases his average by 3 runs. What is his average after the 12th innings if he had never been ‘not out’?
A.42
B.37
C.44
D.45
Answer: B.37
Explanation: Let ‘x’ be the average score after 12 th innings
⇒ 12x = 11 × (x – 3) + 70
∴ x = 37
Answer B
Question: A man can row upstream 10 kmph and downstream 20 kmph. Find the man rate in still water and rate of the stream.
A.0,5
B.5,5
C.15,5
D.10,5
Answer: C.15,5
Explanation: Explanation:
Please remember,
If a is rate downstream and b is rate upstream
Rate in still water = 1/2(a+b)
Rate of current = 1/2(a-b)
=> Rate in still water = 1/2(20+10) = 15 kmph
=> Rate of current = 1/2(20-10) = 5 kmph
Option C
Question: On an order of 5 dozen boxes of a consumer product, a retailer receives an extra dozen free. This is equivalent to allowing him a discount of?
A.16 2/6%
B.16 8/3%
C.16 2/3%
D.16 2/8%
Answer: C.16 2/3%
Explanation: Clearly, the retailer gets 1 dozen out of 6 dozens free.
Equivalent discount = 1/6 * 100 = 16 2/3%.
Answer: C
Question: Let ABCD be a convex quadrilateral with BA = BC and DA = DC. Let E and F be the
midpoints of BC and CD respectively, and let BF and DE intersect at G. If the area of CEGF
is 50, what is the area of ABGD?
A.100
B.200
C.300
D.400
Answer: B.200
Explanation: Let [XY Z] denote the area of a polygon XY Z.
Observe that BF and DE are two medians of 4BCD, so G is the centroid of 4BCD. Since
the medians of a triangle divide the triangle into six parts of equal area, we have
[CGF] = [CGE] =
1/2
[CEGF] = 25:
It follows that [CBD] = 6 25 = 150 and [BGD] = 2 25 = 50.
Furthermore, since BA = BC, DA = DC, and BD = BD, we have that 4ABD = 4CBD, so
[ABD] = [CBD] = 150. Finally,
[ABGD] = [ABD] + [BGD] = 150 + 50 = 200
correct answer B