RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The H.C.F of two numbers is 23 and the other two factors of their L.C.M are 14 and 15. The larger of the two numbers is:
A.338
B.278
C.345
D.231
Answer: C.345
Explanation: Clearly, the numbers are (23 * 14) and (23 * 15). Larger number
= (23 * 15) = 345.
Answer: C
Question: If the ratio of the sum of the first 6 terms of a G.P. to the sum of the first 3 terms of the G.P. is 126, what is the common ratio of the G.P?
A.3
B.1/3
C.2
D.5
Answer: D.5
Explanation: 126=(a1+a2+a3+a4+a5+a6)/(a1+a2+a3)
Factorize the same terms
126=1+(a4+a5+a6)/(a1+a2+a3)
Write every term with respect to r
a1=a1
a2=a1*r^1
a3=a1*r^2
.........
126=1+(a1(r^3+r^4+r^5))/(a1(1+r^1+r^2))
125=(r^3 (1+r^1+r^2))/((1+r^1+r^2))
125=r^3
r=5
D
Question: A company has 50 employees, of which 22 studied accounting, 15 studied finance and 14 studied marketing. Ten employees have done just two courses and only one made ​​the three courses. How many employees have no training?
A.A)0
B.B)9
C.C)10
D.D)11
Answer: D.D)11
Explanation: Total employees=50
studied accounting=22
studied finance=15
studied marketing=14
10 employees have been double counted and one employee has been counted thrice.
Therefore employees who have received training=22+15+14-10-(2*1)
=51-12
=39
Employees with no training
=50-39
=11
Ans=D
Question: A train covers a certain distance at a speed of 320kmph in 6 hours. To cover the same distance in 1 2/3 hours, it must travel at a speed of
A.1152km/hr
B.1120km/hr
C.1650km/hr
D.1750km/hr
Answer: A.1152km/hr
Explanation: Explanation:
Distance = 320Ã—6 = 1920km
Required speed = (1920Ã— 3/5) = 1152km/hr
Answer: Option A
Question: The diameters of two spheres are in the ratio 1:2 what is the ratio of their volumes?
A.1:7
B.1:3
C.1:8
D.1:1
Answer: C.1:8
Explanation: 1:8
Answer: C
Question: How many integers are there between 42 and 97, inclusive?
A.51
B.55
C.56
D.57
Answer: C.56
Explanation: I guess the easiest way to answer this is -
Say you have two positive integers, x and y where y > x
Then the number of integers between x and y is given by - (y - x) + 1
In this case, it's (97 - 42) + 1 =56
Option C
Question: A man buys an item at Rs. 800 and sells it at the loss of 20 percent. Then what is the selling price of that item
A.Rs. 640
B.Rs. 760
C.Rs. 860
D.Rs. 960
Answer: A.Rs. 640
Explanation: Explanation:
Here always remember, when ever x% loss,
it means S.P. = (100 - x)% of C.P
when ever x% profit,
it means S.P. = (100 + x)% of C.P
So here will be (100 - x)% of C.P.
= 80% of 800
= 80/100 * 800
= 640
Option A
Question: A freight elevator can carry a maximum load of 1200 pounds. Sean, who weighs 200 pounds, is in the elevator with two packages weighing 150 pounds and 280 pounds. If he needs to fit three more packages in the elevator that weigh as much as possible without exceeding the elevator limit, what is the difference between their average and the average of the two packages already in the elevator?
A.25
B.85
C.190
D.215
Answer: A.25
Explanation: The average of existing 2 package is (150 + 280)/2 = 430/2 = 215
Remaining allowed weight = 1200 - 200 - 430 = 570
.
allowed per package = 570 / 3 = 190
So difference in average of existing and allowable = 215 - 190 = 25
Hence A
Question: A bag contains five white and four red balls. Two balls are picked at random from the bag. What is the probability that they both are different color?
A.5/7
B.5/9
C.5/1
D.5/2
Answer: B.5/9
Explanation: Two balls can be picked from nine balls in ⁹C₂ ways.
We select one white ball and one red ball from five white balls and four red balls. This can be done ⁵C₁ . ⁴C₁ ways.
The required probability
= (5 * 4)/⁹C₂ = 20/36 = 5/9
Answer:B
Question: Sujit incurred a loss of 45% on selling an article for Rs.3410/-. What was the cost price of the article?
A.Rs.6200/-
B.Rs.5080/-
C.Rs.6250/-
D.Rs.6750/-
Answer: A.Rs.6200/-
Explanation: Explanation:
45% loss means SP of Rs.3410/- is 55% of CP
:. CP = 3410x100/55 = Rs.6200/-
Answer: Option A
Question: Find the least number must be subtracted from 5474827 so that remaining no.is divisible by 12?
A.3
B.5
C.4
D.7
Answer: D.7
Explanation: On dividing 5474827 by 12 we get the remainder 7, so 7 should be subtracted
D
Question: Tap 'A' can fill the tank completely in 6 hrs while tap 'B' can empty it by 12 hrs. By mistake, the person forgot to close the tap 'B', As a result, both the taps, remained open. After 7 hrs, the person realized the mistake and immediately closed the tap 'B'. In how much time now onwards, would the tank be full?
A.2.5 hours
B.4.5 hours
C.5.5 hours
D.1.5 hour
Answer: A.2.5 hours
Explanation: Explanation :
Tap A can fill the tank completely in 6 hours
=> In 1 hour, Tap A can fill 1⁄6 of the tank
Tap B can empty the tank completely in 12 hours
=> In 1 hour, Tap B can empty 1⁄12 of the tank
i.e., In one hour, Tank A and B together can effectively fill 1⁄6 - 1⁄12 = 1⁄12 of the tank
=> In 7 hours, Tank A and B can effectively fill 1⁄12 × 7 = 7/12 of the tank.
Time taken to fill the remaining 1−(7/12) = 5/12 of the tank = (5/12)/(1/6) = 2.5 hours. Answer : Option A
Question: Among 250 viewers interviewed who watch at least one of the three TV channels namely A, BC. 116 watch A, 127 watch C, while 107 watch B. If 60 watch exactly two channels. How many watch exactly one channel?
A.185
B.180
C.170
D.190
Answer: C.170
Explanation: 250 = n(Exactly 1 channel) + n(Exactly 2 channels) + n(Exactly 3 channels)
250 = n(Exactly 1 channel) + 60 + n(Exactly 3 channels)
Let's find the value of n(Exactly 3 channels) = x
250 = n(A) + n(B) + n(C) - n(A and B) - n(B and C) - n(C and A) + n(A and B and C)
Note that each of n(A and B) is the sum of 'number of people watching exactly two channels A and B' and 'number of people watching all three channels'.
250 = 116 + 127 + 107 - n(Exactly 2 channels) - 3x + x
250 = 116 + 127 + 107 - 60 - 2x
x = 25
250 = n(Exactly 1 channel) + 60 + 25
n(Exactly 1 channel) = 170
Answer (C)
Question: In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk?
A.32
B.36
C.38
D.40
Answer: D.40
Explanation: Assume that in x days, one cow will eat one bag of husk.
More cows, less days (Indirect proportion)
More bags, more days (direct proportion)
Hence we can write as
(cows)40:1
(bags)1:40
x:40
=40×1×40=1×40×x
=x=40
ANSWER : D
Question: A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
A.Rs. 4991
B.Rs. 5991
C.Rs. 6001
D.Rs. 6991
Answer: A.Rs. 4991
Explanation: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991.
ANSWER:A
Question: If the wages of 6 men for 15 days be Rs.2100, then find the wages of
for 12 days.
A.Rs. 2530
B.Rs. 2520
C.Rs. 2500
D.Rs. 1520
Answer: B.Rs. 2520
Explanation: Let the required wages be Rs. x.
More men, More wages	(Direct Proportion)
Less days, Less wages	(Direct Proportion)
Men 6: 9 : :2100:x
Days 15:12
Therefore (6x15 x x)=(9x12x2100) <=> x=(9x12x2100)/(6x15) =2520
Hence the required wages are Rs. 2520.
Answer is B.
Question: what is the smallest integer that is multiple of 5,7,11
A.A)70
B.B)35
C.C)385
D.D)280
Answer: C.C)385
Explanation: It is the lcm of 5, 7 and 11 which is 385.
The answer is C.
Question: A and B together can complete one-ninth of a job in a day. What is the difference between the maximum and minimum number of days A could take to complete the job alone, if A and B take whole number of days to complete the job alone?
A.45
B.B.60
C.C.80
D.D.90
Answer: C.C.80
Explanation: A and B together can complete one-ninth of a job in a day means that AB together does one whole work in 9 days.
1/A +1/B = 1/9
The minimum value A can take is 10 days (Anything less than 10 days is not possible because in other case, no of days taken by B will become negative, which is not possible practically)
When A takes least time (10Days) then B would take the Max time (90 days) to complete the work alone.
In order to find the Max time taken by A, find out the min time taken by B as we did earlier.
The minimum value B can take is 10 days (Anything less than 10days is not possible because in other case, no of days taken by A will become negative, which is not possible practically)
When B takes least time (10Days) then A would take the Max time (90 days) to complete the work alone.
So the required difference = Max Time taken-Min Time taken
= 90 - 10
=80 Days
Option C
Question: What is the rate percent when the simple interest on Rs.910 amount to Rs.260 in 4 Years?
A.7.14
B.6.14
C.5.14
D.3.14
Answer: A.7.14
Explanation: 260 = (910*4*R)/100
R = 7.14%
Answer: A
Question: Evaluate permutation
8P8
A.40290
B.40300
C.40310
D.40320
Answer: D.40320
Explanation: Explanation:
nPn=n!
8P8=8*7*6*5∗4∗3∗2∗1=40320
Option D
Question: 1. If the product of 6 integers is negative, at most how many of the integers can be negative?
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: We're told that the product of 6 numbers is negative (the fact that they're integers is actually irrelevant). We're asked for the MAXIMUM number of those 6 that COULD be negative. We'll start with the largest and work our way down..
6 are negative: (-1)(-1)(-1)(-1)(-1)(-1) = + 1...which is NOT a negative product
5 are negative: (-1)(-1)(-1)(-1)(-1)(+1) = -1...which IS a negative product
D
Question: The ratio of the incomes of Rajan and Balan is 7:6 and the ratio of their expenditure is 6:5. If at the end of the year, each saves $1000 then the income of Rajan is?
A.$7600
B.$7000
C.$8000
D.$9000
Answer: B.$7000
Explanation: Let the income of Rajan and Balan be $7x and $6x
Let their expenditures be $6y and $5y
7x-6y = 1000-------1)
6x-5y = 1000-------2)
From 1) and 2)
x = 1000
Rajan's income = 7x = 7*1000 = $7000
Answer is B
Question: In a apartment, 30% of the people speak English, 20% speak Hindi and 10% speak both. If a people is selected at random, what is the probability that he has speak English or Hindi?
A.1/3
B.2/3
C.2/5
D.2/9
Answer: C.2/5
Explanation: P (E) = 30 / 100 = 3 / 10 , P (H) = 20 / 100 = 1 / 5 and P (E ∩ H) = 10 / 100 = 1 / 10
P (E or H) = P (E U H)
= P (E) + P (H) - P (E ∩ H)
= (3 / 10) + (1 / 5) - (1 / 10) = 4 / 10 = 2/5
C
Question: If a and b are integers and (a*b)^5 = 128y, y could be:
A.1
B.2
C.4
D.8
Answer: D.8
Explanation: Distribute the exponent.
a^5 * b^5 = 128 y
Find the prime factorization of 96. This is 2^5 *2^2.
We need 2^3 (or some other power of 2 that will give us a multiple of 2^5 as our second term).
2^3 = 8
The answer is D.
Question: A car rental company charges for mileage as follows: 10 dollars per mile for the first n miles and 11 dollars per mile for each mile over n miles. How much will the mileage charge be, in dollars, for a journey of d miles, where d > n ?
A.7d-n
B.5d-n
C.3*11d-n
D.11d-n
Answer: D.11d-n
Explanation: Total Distance in miles = d
Millage Charge = 10n + (d-n) 11
10n --> For the first n Miles
(d-n)11--> Total no of miles after traveling the first n miles is d-n and the rate after n miles is 11 .
If we solve the equation , We will get 11d-n
Answer : D
Question: On dividing a number by 357, we get 39 as remainder.On dividing the same number by 17, what will be the remainder ?
A.4
B.5
C.8
D.7
Answer: B.5
Explanation: Let x be the number and y be the quotient.Then,
x=357*y+39
=(17*21*y)+(17*2)+5
=17*(21y+2)+5.
Required number =5.
Answer is B
Question: The variables m and n are positive integers. When m is divided by 4, there is a remainder of 5, and when n is divided by 3, there is a remainder of 4. Which of the following are possible values of m + n?
I. 50
II. 70
III. 92
A.I only
B.III only
C.I and II
D.I​ and III
Answer: A.I only
Explanation: m = 4k + 5 --> Values are 5, 9, 13, 17
n = 3k + 4 --> Values are 4, 7, 10, 13
I. 16 --> 9 + 7 --> Possible
II. 24 --> Not possible
III. 29 --> Not possible
Answer: A
Question: If 34 men completed 2/5th of a work in 8 days working 9 hours a day. How many more man should be engaged to finish the rest of the work in 6 days working 9 hours a day?
A.100
B.102
C.104
D.106
Answer: B.102
Explanation: Using the chain rule,
M1 x T1 = M2 x T2
Thus, (34 x 8 x 9) / 2/5 = (M2 x 6 x 9) / 3/5
M2 = 68.
Therefore, required number of men = (68 + 34) = 102
ANSWER:B
Question: March 11, 2003 is a Tuesday. What will be the day on which march 11 2004 comes??
A.Thursday
B.Friday
C.Saturday
D.Sunday
Answer: A.Thursday
Explanation: 2004 is a leap year that means 29 days in feb.
so march 11,2003 to march 11, 2004 will be 366 days.
366/7=52 weeks + 2 days. Hence Thursday
ANSWER:A
Question: Two electronic musical instruments were purchased for 8000. The first was sold at a profit of 40% and the second at loss of 40%. If the sale price was the same in both the cases, what was the cost price of two electronic musical instruments?
A.2000, 5000
B.2200, 5500
C.2400, 5000
D.2400, 5600
Answer: D.2400, 5600
Explanation: Here, SP1 = SP2
⇒ 140 CP1 = 60CP2 ⇒ CP1/CP2=6/14=3/7
∴ CP1 = 3(3+7)×8000=24003(3+7)×8000=2400
and CP2 = 8000 – 2400 = 5600
Answer D
Question: What is the average of first 21 multiples of 7 ?
A.49
B.77
C.66
D.57
Answer: B.77
Explanation: Required average = 7(1+2+....+21) / 21
(7/21)X ( (21x22) / 2 ) (because sum of first 21 natural numbers)
= 77
ANSWER IS B
Question: A recipe for a large batch of fruit juice at a factory calls for 10% oranges, 20% lemons, and 70% limes. if 200 lemons are used, how many limes are needed?
A.100
B.200
C.300
D.700
Answer: D.700
Explanation: 20%= 200 fruit
100%=1000 fruit
70% of 1000 fruit=700 fruit
700 limes
ANSWER:D
Question: What is the compound interest paid on a sum of Rs.4500 for the period of 2 years at 10% per annum.
A.945
B.620
C.610
D.600
Answer: A.945
Explanation: Solution= Interest % for 1st year= 10
Interest % for 2nd year= 10+ 10% of 10= 10+ 10 *10/100=11
Total % of interest= 10 + 11=21
Total interest = 21 % 4500 = 4500* (21/100)= 945
Answer A
Question: Combine terms: 8a + 26b -4b – 16a.
A.4a + 22b
B.-28a + 30b
C.-8a + 22b
D.28a + 30b
Answer: C.-8a + 22b
Explanation: Solution:
8a + 26b -4b – 16a.
= 8a – 16a + 26b – 4b.
= -8a + 22b.
Answer: (C)
Question: 8 cups of milk are to be poured into a 4-cup bottle and a 8-cup bottle. If each bottle is to be filled to the same fraction of its capacity, how many cups of milk should be poured into the 8-cup bottle?
A. 16/3
B. 7/3
C. 5/2
D. 4/3
Answer: A. 16/3
Explanation: Let x be the # of cups going into the 8 cup bottle.
so.... x/8 = ((8-x)/4)
64 - 8x = 4x
64 = 12x
x = 16/3.
Answer : A
Question: Which number should replace both the asterisks in (* /20) x (*/80) = 1 ?
A.20
B.40
C.60
D.80
Answer: B.40
Explanation: Let (y/20) x (y/80) = 1
y^2 = 20 x 80 = 20 x 20 x 4
y = (20 x 2) = 40
The answer is B.
Question: Mrs. Rodger got a weekly raise of $148. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.
A.$140
B.$141
C.$142
D.$148
Answer: D.$148
Explanation: Let the 1st paycheck be x (integer).
Mrs. Rodger got a weekly raise of $ 148.
So after completing the 1st week she will get $ (x+148).
Similarly after completing the 2nd week she will get $ (x + 148) + $ 148.
= $ (x + 148 + 148)
= $ (x + 296)
So in this way end of every week her salary will increase by $ 148.
correct answer D)$148
Question: In a class there are 20 boys and 24 girls. In how many ways can a boy and a girl be selected?
A.508
B.480
C.800
D.570
Answer: B.480
Explanation: We can select one boy from 20 boys in 20 ways.
We select one girl from 24 girls in 24 ways
We select a boy and girl in 20 * 24 ways i.e., = 480 ways.
Answer:B
Question: The average temperature in Lincoln in July is 85 degrees. Last
Wednesday, it was 90 degrees. Today it was 15 degrees cooler than
last Wednesday. What was the temperature today?
A.15 degrees
B.25 degrees
C.75 degrees
D.45 degrees
Answer: C.75 degrees
Explanation: The July temperature is extra information. 90 – 15 = 75
It was 75 degrees today.
correct answer C
Question: Boys and girls in a class are writing letters. There are twice as many girls as boys in the class, and each girl writes 3 more letters than each boy. If boys write 24 of the 90 total letters written by the class, how many letters does each boy write?
A.3
B.4
C.6
D.8
Answer: D.8
Explanation: There are twice as many girls as boys in the class --> g = 2b.
Each girl writes 3 more letters than each boy --> boys write x letters, girls write x+3 letters.
Boys write 24 letters --> bx = 24.
Girls write 90-24=66 letters --> (2b)(x+3) = 66 --> 2bx + 6b = 66 --> 2*24 + 6b = 66 --> b = 3.
bx = 24 --> 3x = 24 --> x = 8.
Answer: D.
Question: In how many different orders can the people Alice, benjamin Charlene, David, Elaine, Frederick, Gale, and Harold be standing on line if each of Alice, David, Charlene must be on the line before each of Frederick, Gale, and Harold?
A.2016
B.1,296
C.1,512
D.2,018
Answer: A.2016
Explanation: Place B and E first: 8 options for B, 7 options for E.
We are left with 6 empty places. A, D and C must take first 3 places and F, G, H must take the remaining three. A, D and C can be arranged in their places in 3! ways. The same for F, G, and H.
Total = 8*7*3!*3! = 2,016.
Answer: A
Question: Deby normally drives to work in 45 minutes at an average speed of 40 miles per hour. This week, however, she plans to bike to work along a route that decreases the total distance she usually travels when driving by 20% . If Deby averages between 12 and 16 miles per hour when biking, how many minutes earlier will she need to leave in the morning in order to ensure she arrives at work at the same time as when she drives?
A.135
B.105
C.95
D.75
Answer: D.75
Explanation: Deby normally drives to work in 45 minutes at an average speed of 40 miles per hour.Use formula D = RT
Car:
T1: 45 min
R1: 40 mph
D1: [(40*45)/60] = 30 miles
Bike:
T1:?
R2: 12 - 16 mph
D2: 08*D1 = 24 miles
T1: [(24*60)/12] = 120 min (Only 12 mph speed yields an answer given in the choices)
Therefore, Deb has to leave 120 min - 45 min = 75 min early
ANSWER: D
Question: In a 100 m race, A runs at 8km per hour. If A gives B a start of 4 m and still him by 15 seconds, what is the speed of B ?
A.5.56 km/hr.
B.5.06 km/hr.
C.5.76 km/hr.
D.6.76 km/hr.
Answer: C.5.76 km/hr.
Explanation: Time taken by A to cover 100 m =(60 X 60 / 8000)	x 100 sec = 45 sec.
B covers (100 - 4) m = 96 m in (45 + 15) sec = 60 sec.
B's speed = (96 x 60 x 60)/(60 x 1000)km/hr = 5.76 km/hr.
Answer is C
Question: A boat running up stram takes 4 hours to cover a certain distance, while it takes 8 hours to cover the same distance running down stream. what is the ratio between the speed of the boat and the speed of water current respectively?
A.2 : 3
B.5 : 6
C.4 : 5
D.3 : 1
Answer: D.3 : 1
Explanation: Explanation:
Let speed of boat is x km/h and speed stream is y km/hr
4(x+y) = 8(x-y)
4x+4y = 8x-8y
12y = 4x
3y = x
x/y = 3/1
3 : 1
Answer: Option D
Question: Jane received an assorted bouquet of 25 flowers which included 8 white flowers,7 lavender flowers and 9 purple flowers.
She closed her eyes a pulled one flower from the bouquet. She opened her eyes, noticed that it was white and placed it aside. She closed her eyes and pulled a 2nd flower from the bouquet. What is the probability that the 2nd flower will also be white?
A.8/25
B.7/24
C.7/25
D.8/25
Answer: B.7/24
Explanation: Solution: Initially, there are 25 flowers total. After the first white flower is removed, 7 white flowers remain and a total of 24 flowers overall are left in the bouquet.
Probability = Favorable outcomes / Total out comes
Therefore, probability = 7/24
Answer Option: B
Question: A man travelled from the village to the post-office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village
A.20
B.87
C.276
D.198
Answer: A.20
Explanation: Explanation:
Average speed = (2 ×a × b)/(a + b) here a = 25 b = 4
Average speed = 2 × 25 × 4/(25 + 4) = 200/29 kmph.
Distance covered in 5 hours 48 minutes = Speed × time
Distance = (200/29) × (29/5) = 40 kms
Distance covered in 5 hours 48 minutes = 40 kms
Distance of the post office from the village = (40/2) =20 km.
Answer: A
Question: The mean of 50 observations is 200. But later he found that there is decrements of 15 from each observations. what is the the updated mean is ?
A.165
B.185
C.198
D.221
Answer: B.185
Explanation: 185
Answer is B
Question: Let R1 and R2 respectively denote the maximum and minimum possible remainders when (276)n is divided by 91 for any natural number n,n>= 144. Find R1+R2.
A.89
B.90
C.91
D.92
Answer: B.90
Explanation: But the least value for n can be= 144 (as given in question, n>=144)
So, 3n/91= 3*144/91= 68
now, the highest remainder can be when it reaches 68+3+3+3+3+3+3+3= 89
(as each time we increment n by 1 the remainder increases by 3,
3*145/91= 71- remiander
3*146/91= 74
3*147/91=77
... so on and so far upto 89 after which it becomes 89+3= 92 which means it crosses 91)
Hence least remainder would be 92 -91=1
and highest remainder = 89
R1+ R2= 89+1 = 90
ANSWER:B
Question: Set A contains all the even numbers between 12 and 60 inclusive. Set B contains all the even numbers between 62 and 110 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A?
A.850
B.1250
C.1650
D.2050
Answer: B.1250
Explanation: Each term in set B is 50 more than the corresponding term in set A.
The difference of the sums = 25 * 50 = 1250.
The answer is B.
Question: Here is a simple arithmetical puzzle in his own flowery, poetical language.
If one-fifth of a hive of bees flew to the badamba flower, one-third flew to the slandbara, three times the difference of these two numbers flew to an arbour, and one bee continued to fly about, attracted on each side by the fragrant Ketaki and Malati, what was the total number of bees?
A.11
B.15
C.18
D.17
Answer: B.15
Explanation: B
15
The number of bees was 15
Question: Machine A and machine R are each used to manufacture 660 sprockets. It takes machine A 10 hours longer to produce 660 sprockets than machine R. Machine R produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces?
A.6
B.6.6
C.60
D.100
Answer: A.6
Explanation: [Reveal]Spoiler:
TimeR: 660/x
TimeA: [660/x+10]
660/x = [660/x+10] *110/100
660/x =66*11/x+10
660x+10= 66*11*x
660x +6600 = 66*11*x
x= 100
plug in back to timeA
660/100+10 => 660/110 = 6
Question: For any a and b that satisfy |a – b| = b – a and a > 0, then |a + 2| + |-b| + |b – a| + |ab| =
A.-ab + 3
B.ab + 2b + 2
C.ab + 2b – 2a – 3
D.-ab + 2b + 3
Answer: B.ab + 2b + 2
Explanation: Observation-1: |a – b| = b – a
which is possible only when signs of a and b are Same
Since Given a > 0
so we figure out that a and b are both positive
Observation-2: |a – b| must be Non-Negative and so should be the value of b-a which is possible only when absolute value of b is greater than or equal to absolute value of a
Now you may choose the values of a and b based on above observations
e.g. b = 2 and a=1 and check the value of given functions and options
|a + 2| + |-b| + |b – a| + |ab| = |1 + 2| + |-2| + |2 – 1| + |1*2| = 8
-ab + 3 = -1*2+3=1
ab + 2b + 2= 1*2+4+2=8
ab + 2b – 2a – 3=1*2+2*2-2*1-3=1
-ab + 2b + 3=5
ab + 3=5
Answer : B
Question: Rathi took a loan for 6 years at the rate of 5% per annum on Simple Interest, If the total interest paid was Rs. 1230, Find the principal amount?
A.4000
B.3500
C.3100
D.4100
Answer: D.4100
Explanation: P = SI * 100/R*T
P = 1230*100/6*5==>4100
ANSWER D