RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A certain bag contains 60 balls — 22 white, 18 green, 8 yellow, 5 red, and 7 purple. If a ball is to be chosen at random, what is the probability that the ball will be neither red nor purple?
A.0.09
B.0.15
C.0.54
D.0.8
Answer: D.0.8
Explanation: According to the stem the ball can be white, green or yellow, so the probability is (white + green + yellow)/(total) = (22 + 18 + 8)/60 = 48/60 = 0.8.
Answer: D.
Question: If a and b are both prime numbers greater than 10, which of the following CANNOT be true?
I. ab is an even number.
II. a - b = 117.
III. The sum of a and b is even.
A.I and II only
B. I only
C. I and III only
D. II and III only
Answer: A.I and II only
Explanation: MANHATTAN GMATOFFICIAL SOLUTION:
Since a and b are both prime numbers greater than 10, they must both be odd. Therefore ab must be an odd number, so Statement I cannot be true. Similarly, if a and b are both odd, then a - b cannot equal 117 (an odd number). This difference must be even. Therefore, Statement II cannot be true. Finally, since a and b are both odd, a + b must be even, so Statement III will always be true. Since Statements I and II CANNOT be true, but Statement III IS true,the correct answer is (A).
Answer : A
Question: The respective ages of father and his son are 40 and 16 years. In how many years will the father be twice as old as his son ?
A.19 years
B.8 years
C.10 years
D.15 years
Answer: B.8 years
Explanation: Suppose x years later the father will be twice as old as his son.
x + 40 = 2 (x + 16)
x = 40 - 32 = 8 years
answer : B
Question: Sonia's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
A.8 Years
B.6 Years
C.4 Years
D.2 Years
Answer: B.6 Years
Explanation: Explanation:
Mother's age when Sonia's brother was born = 36 years.
Father's age when Sonia's brother was born = (38 + 4) years = 42 years.
Required difference = (42 - 36) years = 6 years.
Answer: B
Question: If Jan 1, 2006 was a Sunday, What was the day of the week Jan 1, 2010?
A.Friday
B.Thursday
C.Tuesday
D.Saturday
Answer: A.Friday
Explanation: Explanation:
Given that Jan 1 2006 was a Sunday
Number of odd days in the period 2006-2009
= 3 normal years + 1 leap year
= 3 x 1 + 1 x 2 = 5 (note that we have taken the complete year 2006 because the period in 2006 is from 01-Jan-2006 to 31-Dec-2006, which is the whole year 2006. Then the complete years 2007, 2008 and 2009 are also involved)
Hence Jan 1 2010 = (Sunday + 5 odd days) = Friday
Answer: Option A
Question: A warehouse is labeling computer inventory with 5-digit codes. Each code is to consist of four digits between the numbers 0 and 9. The manager is debating whether to allow any 5-digit codes to have leading zero's before a non-zero number is used. If not allowed, then numbers like0025cannot be used.
The manager wants to measure the magnitude of the number of 5-digit code possibilities that are lost if he disallows the use of leading zero's. How many such codes would be lost?
A.981
B.1000
C.1011
D.10000
Answer: D.10000
Explanation: The number of codes possible if leading zero is allowed = 10*10*10*10*10=10^5
The number of codes possible if leading zero is NOT allowed = 9*10*10*10*10=9*10^4
The difference = 10^5 - 9*10^4 = 10^4(10-9) = 10^4.
Answer: D.
Similar questions to practice:
Hope it helps.
Question: The smallest prime number is?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: The smallest prime number is 2.
B)
Question: From a group of 14 astronauts that includes 5 people with previous experience in space flight, a 3-person crew is to be selected so that exactly 1 person in the crew has previous experience in space flight. How many different crews of this type are possible?
A.175
B.190
C.165
D.180
Answer: D.180
Explanation: number of astronauts with previous experience = 5
Remaining =9
we need to pick exactly one from the first group
and 2 from the second group
(5C1)*(9C2)
=5*36= 180
Answer : D
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 15 minutes. The waste pipe can empty the full cistern in?
A.A)7
B.B)6
C.C)8
D.D)10
Answer: D.D)10
Explanation: 1/10 + 1/15 - 1/x = 1/15
x = 10
Answer:D
Question: 3^(2x/3)=1^(5x)
What is the value of x ?
A.-1
B.2/3
C.0
D.1/2
Answer: C.0
Explanation: 3^(2x/3)=1
2x/3=0; x=0= ans C
Question: You have a bucket of jelly beans. Some are red, some are blue, and some green. With your eyes closed, pick out 2 of a like color. How many do you have to grab to be sure you have 2 of the same?
A.3
B.4
C.5
D.6
Answer: B.4
Explanation: If you grab 3 it might be all different. So take one extra to make sure you have two of the same.
So, take atleast 4
ANSWER:B
Question: 11234783131.What are the next three numbers?
A.145
B.178
C.176
D.191
Answer: D.191
Explanation: actually if we split up series then we get,
11,23,47,83,131
from this we see that,
23-11=12,
47-23=24,
83-47=36,
131-83=48,
from option we see that 191-131=60
so,191 is correct option
ANSWER:D
Question: What is the sum of the local values of the digits 2, 3, 4, 5 in the number 2345?
A.2345
B.2288
C.2977
D.1280
Answer: A.2345
Explanation: Explanation:
2000 + 300 + 40 + 5 = 2345
Answer: A
Question: In a series of football matches, the probability that Team P wins a match against Team Q is 1/4 and the probability that the match ends in a draw is 1/3. If the two teams play five matches, what is the probability that all five matches end in a draw?
A.1/243
B.1/81
C.1/27
D.1/9
Answer: A.1/243
Explanation: P(5 draws)=(1/3)^5=1/243
The answer is A.
Question: Ayesha’s father was 38 years of age when she was born while her mother was 32 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
A.2 years
B.4 years
C.6 years
D.10 years
Answer: D.10 years
Explanation: EXPLANATION
Mother’s age when Ayesha’s brother was born = 32 years.
Father’s age when Ayesha’s brother was born = (38 + 4) years = 42 years.
Required difference = (42 – 32) years = 10 years.
Answer D
Question: How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.767 meters
B.426 meters
C.500 meters
D.165 meters
Answer: C.500 meters
Explanation: Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
800+x = (65/3) * 60
800+x = 20 * 65 = 1300
x = 1300 - 800 = 500 meters
Answer: C
Question: A batsman scored 120 runs which included 6 boundaries and 4 sixes. What % of his total score did he make by running between the wickets
A.40%
B.60%
C.65%
D.70%
Answer: B.60%
Explanation: Number of runs made by running = 110 - (6 x 4 + 4 x 6)
= 120 - (48)
= 72
Now, we need to calculate 60 is what percent of 120.
=> 72/120 * 100 = 60 %
B
Question: Find the cost of fencing around a circular field of diameter 28 m at the rate of Rs.1.50 a meter?
A.A)Rs.150
B.B)Rs.132
C.C)Rs.100
D.D)Rs.125
Answer: B.B)Rs.132
Explanation: 2 * 22/7 * 14 = 88
88 * 1 1/2 = Rs.132
ANSWER:B
Question: N is the greatest number which divides 1305, 4665 and 6905 and gives the same remainder in each case. What is the sum of the digits in N?
A.4
B.3
C.6
D.5
Answer: A.4
Explanation: 6905 - 1305 = 5600
6905 - 4665 = 2240
4665 - 1305 = 3360
Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N
= HCF of 5600, 2240, 3360
= 1120
Sum of digits in N
= Sum of digits in 1120
= 1 + 1 + 2 + 0
= 4 Answer: Option A
Question: Operation#is defined as adding a randomly selected two digit multiple of 12 to a randomly selected two digit prime number and reducing the result by half. If operation#is repeated 10 times, what is the probability that it will yield at least two integers?
A.0%
B.10%
C.20%
D.30%
Answer: A.0%
Explanation: Any multiple of 12 is even.
Any two-digit prime number is odd.
(even+odd)/2 is not an integer. Thus # does not yield an integer at all.
Therefore P=0.
Answer: A.
Question: John had $100 to buy drinks and sandwiches for his birhtday party. He bought 5 small boxes of drinks at $4 each box and 8 boxes of sandwiches at $6 each box. How much money was left after the shopping?
A.$62
B.$92
C.$32
D.$22
Answer: C.$32
Explanation: Money spent on drinks
5 ? 4 = $20
Money spent on sandwiches
8 ? 6 = $48
Total money spent
20 + 48 = $68
Money left after shopping
100 - 68 = $32
correct answer C
Question: mr. depak has $429,774 in his bank account. What is the least amount of money (in whole number of dollars) that he must add to his account if he wants to split this money evenly among her six best friends?
Options:
A.$1
B.$2
C.$3
D.$4
Answer: C.$3
Explanation: To find the least amount deepak should add to his saving account to split the money evenly among his 6 best friends,
he needs to make the total divisible by 6
Simply add the individual digits of the total = 4+2+9+7+7+4 = 33
If you add 3 , the number is divisible by 6 (33+ 3)
Correct Option : C
Question: A man and his wife appear in an interview for two vacancies in the same post. The probability of husband’s selection is (1/7) and the probability of wife’s selection is (1/5). What is the probability that only one of them is selected?
A.1/7
B.4/7
C.5/7
D.2/7
Answer: D.2/7
Explanation: P(A)=1/7
P(B)=1/5
P(A’)=6/7
P(B’)4/5
Required probability= P((A and B’) or ( B and A’))
=(1/7x4/5)+(1/5x6/7)
=2/7
ANSWER D
Question: In a rectangular coordinate system, points O (2,2), P (2,6), and Q (10,2) represent the sites of three proposed housing developments. If a fire station can be built at any point in the coordinate system, at which point would it be equidistant from all three developments?
A.(3,7)
B.(5,3)
C.(3,4)
D.(6,4)
Answer: D.(6,4)
Explanation: All points equidistant from O and Q lie on the line x = 6, so the fire station should lie on this line.
All points equidistant from O and P lie on the line y = 4, so the fire station should lie on this line.
These two intersect at (6,4) and that will be the point equidistant from all 3 points.
The answer is D.
Question: 8 friends went to a hotel and decided to pay the bill amount equally. But 7 of them could pay Rs. 80 each as a result 8th has to pay Rs. 70 extra than his share. Find the amount paid by him.
A.140
B.121
C.110
D.160
Answer: D.160
Explanation: Explanation:
Average amount paid by 7 persons = Rs. 80
Increase in average due to Rs. 70 paid extra by the 8th men = Rs. 70/7= Rs. 10
Therefore, Average expenditure of 8 friends = Rs. 80 + Rs. 10 = Rs. 90
Therefore, Amount paid by the 11th men = Rs. 90 + Rs. 70 = Rs. 160
Correct Option: D
Question: Two identical circles intersect such that their centers and the points at which they intersect form a square of side 1 cm. What is the area of the region where the two circles intersect?
A.pi/2 - 1
B.pi/4 - 1
C.1 - pi/4
D.pi/8 + 1
Answer: A.pi/2 - 1
Explanation: Drawing a diagram, we see that the radius of the circle equals the side of the square.
The area of intersection is: pi*r^2/4 - (r^2-pi*r^2/4) = pi*r^2/2 - r^2 = pi/2 - 1
The answer is A.
Question: The population of a city increases by 8% per year but due to migration it decrease by 1% per years. What will be the percentage increase in population in 3 years?
A.9%
B.9.27%
C.22.50%
D.12%
Answer: C.22.50%
Explanation: Actual increase in population=7%
Let, earlier population=100 then the population after 3 years
=100(1+7/100)^3=122.5043
∴Required percentage=22.50%
ANSWER:C
Question: There are 25 balls in a jar. You take out 5 blue balls without putting them back inside, and now the probability of pulling out a blue ball is 1/5. How many blue balls were there in the beginning?
A.12.
B.9.
C.8.
D.7.
Answer: B.9.
Explanation: 9 = 5 blue balls + 20/ 5
Answer: B
Question: For every even positive integer m, f(m) represents the product of all even integers from 2 to m, inclusive. For example, f(12)=2x4x6x8x10x12. What is the greatest prime factor of f(26)?
A.23
B.19
C.17
D.13
Answer: D.13
Explanation: f(26) = 2*4*6*8*10*12*14*16*18*20*22*24*26
The greatest prime factor in this list is 13.
The answer is D.
Question: A double decked bus can accomodate 50 passengers,20 in the upper deck and 30 in the lower deck.In how many ways can the passengers be accomodated if 15 refuse to be in the upper deck while 10 others refuse to be in the lower deck?
A.1. 85!50!60!/40!45!
B.2. 85!/40!45!
C.3. 110!/50!60!
D.4. 25!/10!15!
Answer: D.4. 25!/10!15!
Explanation: 50 passengers,20 in the upper deck and 30 in the lower deck.
25 passengers have issues as 15 refuse to be in the upper deck while 10 others refuse to be in the lower deck
So those 15 will be put in lower deck and 10 will be in upper deck
So from the rest 25 passengers(50-25), we need to find 10 people to put into upper deck and the rest go to lower deck
So the ways are: C(25,10) = 25!/10!15! . Answer D
Question: Three persons A, B and C divide a certain amount of money such that A's share is Rs.4 less than half of the total amount. B's share is Rs.8 more than half of what is left and finally C takes the which is Rs.14. Find the total amount they initially had with them?
A.16
B.78
C.80
D.76
Answer: C.80
Explanation: Let the total amount be Rs.P
Let shares of A and B be Rs.X and Rs.Y respectively.
Given, C's share was Rs.14.
X + Y + 14 = P --- (1)
From the given data, X = P/2 - 4 --- (2)
Remaining amount = P - (P/2 - 4) = P/2 + 4
Y = 1/2(P/2 + 4) + 8
=> P/4 + 10 --- (3)
From (1), (2) and (3)
P/2 - 4 + P/4 + 10 + 14 = P
=> 3P/4 + 20 = P
=> P - 3P/4 = 20
=> P/4 = 20 => P = Rs.80
Answer: C
Question: There is a cycle race going on in a circular track and 1/5th of the total in front a person and 5/6th of the total behind that person gives up the total number of participants. Total how many participants are there?
A.30
B.31
C.32
D.33
Answer: B.31
Explanation: Assume there are x participants in the race.
participants in front of a person wil b x-1 and
that behind him wil b x-1.
so
1/5(x-1) + 5/6(x-1) = x
we get,
x=31
ANSWER:B
Question: If the sum of one-half, one-third and one-fourth of a number exceeds the number itself by 4, what could be the number ?
A.24
B.36
C.72
D.None of these
Answer: D.None of these
Explanation: Answer
Let the number be N
∴ (1/2 + 1/3 + 1/4)N = {(6 +4 +3) x N } / 12
= 13N / 12
According to the question,
13N/12 - N = 4
∴ N = 48
Option: D
Question: A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is
A.6%
B.5%
C.12%
D.10%
Answer: C.12%
Explanation: S.I. for 3 years = Rs. (12005 - 9800) = Rs. 2205.
S.I. for 5 years = Rs.	2205/3x 5= Rs. 3675
Principal = Rs. (9800 - 3675) = Rs. 6125.
Hence, rate =(100 x 3675)/(6125 x 5)%	= 12%
answer : C
Question: A sum amount to Rs.1344 in two years at simple interest. What will be the compound interest on the same sum at the same rate of interest for the same period?
A.10.28%
B.10.35%
C.10.25%
D.14.25%
Answer: C.10.25%
Explanation: 100
5 ---- I
5
0.25 --- II
-----------
10.25%
Answer: C
Question: A and B complete a job in 6 days. A alone can do the job in 24 days. If B works alone, how many days will it take to complete the job?
A.8
B.9
C.10
D.11
Answer: A.8
Explanation: The rate of A and B is 1/6
A's rate is 1/24
B's rate is 1/6 - 1/24 = 1/8
B can complete the job in 8 days.
The answer is A.
Question: How many odd three-digit integers greater than 800 are there such that all their digits are different?
A.40
B.60
C.72
D.81
Answer: C.72
Explanation: In the range 800 - 900:
1 choice for the first digit: 8;
5 choices for the third digit: 1, 3, 5, 7, 9;
8 choices for the second digit: 10 digits - first digit - third digit = 8 digits.
1*5*8 = 40.
In the range 900 - 999:
1 choice for the first digit: 9;
4 choices for the third digit: 1, 3, 5, 7 (9 is out as it's first digit);
8 choices for the second digit: 10 digits - first digit - third digit = 8 digits.
1*4*8 = 32.
Total: 40+32 = 72.
Answer: C
Question: For 1rs 1p interest
wat will be for 2000rs?
A.45Rs
B.50Rs
C.20Rs
D.30Rs
Answer: C.20Rs
Explanation: For 1rs , 1p interest
for 2000rs, x
x= 2000/1 * 1p ==> 2000 paise
To express in rs, 2000/100 = 20rs
ANSWER:C
Question: If the difference of two numbers is 3 and the difference of their square is 39, then the larger number is:
A.8
B.9
C.12
D.14
Answer: A.8
Explanation: Let the numbers be x and y
Then x2-y2=39
And x-y=3
We get x+y=13
Solving x-y=3, x+y=13
X=8, y=5
Larger number 8
ANSWER A 8
Question: 10+19
A.29
B.13
C.28
D.6
Answer: A.29
Explanation: A
Question: Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
A.2:5
B.3:5
C.4:5
D.6:7
Answer: C.4:5
Explanation: Explanation:
Let the third number be x.
Then, first number = 120% of x =120X/100=6X/5
Second number = 150% of x =150X/100=3X/2
Ratio of first two numbers =(6X/5-3X/2)= 12x : 15x = 4 : 5.
ANSWER IS C
Question: Ashle and Vinnie work on a sales staff with 8 other salespeople. If five members of the staff will be chosen at random to attend a sales workshop, what is the probability that both Ashle and Vinnie will be chosen?
A.1/10
B.3/28
C.2/9
D.1/4
Answer: C.2/9
Explanation: I did slightly different and hence obviously ended up with the answer 2/9.
I assumed that because Ashle and Winni have to be chosen, the remaining selection is 3 people from 8.
8C3/10C5= 2/9. Option C.
Question: Population of a city in 20004 was 1000000. If in 2005 there isan increment of 15% , in 2006 there is a decrements of 35 % and in 2007 there is an increment of 35%, then find the population of city atthe end of the year 2007
A.976374
B.979923
C.1009125
D.2356677
Answer: C.1009125
Explanation: Required population = P (1 + R1/100)(1 - R2/100)(1 + R3/100)
= P (1 + 15/100)(1 - 35/100)(1 + 35/100)
= 1009125
C
Question: The ratio between the present ages of A and B is 5:3 respectively. The ratio between A's age 4 years ago and B's age 4 years hence is 1:1. What is the ratio between A's age 4 years hence and B's age 4 years ago?
A.1:3
B.2:1
C.3:1
D.4:1
Answer: C.3:1
Explanation: Let the present ages of A and B be 5x and 3x years respectively.
Then, (5x - 4)/(3x + 4) = 1/1
2x = 8 => x = 4
Required ratio = (5x + 4):(3x - 4) = 24:8 = 3:1
ANSWER:C
Question: Abhijit started a business investing 70000. Anuja joined him after six months with an amount of 105000 and Sunil joined them with 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Abhijit, Anuja and Sunil respectively, two years after Abhijit started the business?
A.4 : 9 : 4
B.5 : 9 : 5
C.8 : 9 : 8
D.7: 9 : 7
Answer: C.8 : 9 : 8
Explanation: Ratio of their investments
= 70 × 24 : 105 × 18: 140 × 12 = 8 : 9 : 8
Answer C
Question: The population of a bacteria colony doubles every day. If it was started 8 days ago with 4 bacteria and each bacteria lives for 12 days, how large is the colony today?
A.512
B.768
C.1024
D.131072
Answer: D.131072
Explanation: 4^8(2) = 131072
The answer is D.
Question: 4 dice are thrown simultaneously on the board. Find the probability show the same face.
A.1/113
B.2/213
C.1/216
D.2/215
Answer: C.1/216
Explanation: The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:
=6×6×6×6=64=6×6×6×6=64
n(S)=64n(S)=64
Let XX be the event that all dice show the same face.
X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}
n(X)=6n(X)=6
Hence required probability,
=n(X)n(S)=664=n(X)n(S)=664
=1/216
C
Question: An article is bought for Rs.675 and sold for Rs.900, find the gain percent?
A.33 1/7%
B.33 0/3%
C.33 1/3%
D.37 1/3%
Answer: C.33 1/3%
Explanation: 675 ---- 225
100 ---- ? => 33 1/3%
Answer: C
Question: The average age of a group of 10 students is 14 years. If 5 more students join the group, the average age rises by 1 year. The average age of the new students is:
A.22
B.38
C.11
D.17
Answer: D.17
Explanation: Explanation:
Total age of the 10 students = 10 × 14 = 140
Total age of 15 students including the newly joined 5 students = 15 × 15 = 225
Total age of the new students = 225 − 140 = 85
Average age = 85/5 = 17 years
Answer: D
Question: A big container is 30% full with water. If 18 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container?
A.36 liters
B.40 liters
C.45 liters
D.54 liters
Answer: B.40 liters
Explanation: A big container is 30% full with water and after 18 liters of water is added, the container becomes 75% full. Hence these 18 liters account for 45% of the container, which means that the capacity of it is 18/0.45=40 liters.
OR: if the capacity of the container is x liters then: 0.3x+18=0.75x --> x=40 liters.
Answer: B.
Question: The average of first 10 odd numbers is?
A.44
B.10
C.99
D.77
Answer: B.10
Explanation: Sum of 10 odd no. = 100
Average = 100/10 = 10
Answer: B
Question: There are 24 students in Chadâ€™s class. He brought 26 cookies to pass out
for his birthday. How many cookies will each student get? Will there be
any cookies left over?
A.1-9
B.1-7
C.2-8
D.1-2
Answer: D.1-2
Explanation: 26/24 = 1 R 2 Chad will give each student 1 cookie and there will be 2
cookies left over
correct answer D
Question: if a@b = a * b^(1/2) then 4@9 = ?
self made
A.12
B.6
C.3
D.8
Answer: A.12
Explanation: a@b = a * b^(1/2)
4@9 = 4*9^(1/2) = 4*3 = 12
Correct Option: A
Question: If n is the product of the integers from 1 to 20 inclusive, what is the greatest integer k for which 2k2k is a factor of n?
A.10
B.12
C.15
D.18
Answer: D.18
Explanation: There are 10 numbers divisible by 2
There are 5 numbers divisible by 4
There are 2 numbers divisible by 8
There is 1 number divisible by 16.
Hence the total number of 2’s in 20! are 10+5+2+1=18
ANSWER:D
Question: A batch of widgets costs p + 15 dollars for a company to produce and each batch sells for p(11 – p) dollars. For which of the following values of p does the company make a profit?
A.8
B.9
C.10
D.11
Answer: A.8
Explanation: to make profit, selling price should be greater than cost price
p(11-p) - p-15 >0
=> p^2-10*p+15<0
hence p=8
A
Question: A certain automobile company’s best-selling model is the Speedster. The Speedster, like all of their other models, comes in coupe and convertible styles. 3/4 of the current inventory is Speedsters, of which 3/5 are convertibles. If there are 30 vehicles that are not Speedsters, how many Speedster convertibles are there?
A.30
B.54
C.60
D.70
Answer: B.54
Explanation: Total Vehicle = 3/4 of speedster + 1/4 of others.
Speedster convertibles = 3/4 total vehicle * 3/5
Given : 1/4 constitutes 30 Vehicles. hence 3/4 constitutes 90
Speedster convertibls = 90 * 3/5 = 54
B
Question: A and B started a business by investing Rs.6000 and Rs. 8000, respectively. After 6 months, B withdrew half of his investment. If after one year they get a profit of Rs.4000 then what is B's share?
A.Rs.2000
B.Rs.1000
C.Rs.3000
D.Rs.5000
Answer: A.Rs.2000
Explanation: B's share=2000
6000*12 :8000*6+4000*6=1:1
2 parts=4000
then 1 part=2000
ANSWER:A
Question: find missing number
-5 1 -11 23 29 17 -20 -14,?
A.-26
B.-27
C.-28
D.-29
Answer: A.-26
Explanation: (-5)+6 = 1 23+6=29 (-20)+6=(-14)
1-12= -11 29-12=17 (-14)-12=(-26)
ans is -26
ANSWER:A
Question: A vantakes 6 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
A.60 Kmph
B.61 Kmph
C.62 Kmph
D.64 Kmph
Answer: A.60 Kmph
Explanation: Time = 6
Distence = 540
3/2 of 6 hours = 6 * 3/2 = 9 Hours
Required speed = 540/9 = 60 Kmph
A)
Question: (0.756 x 3/4) terms of rate percent is equivalent to ?
A.18.9%
B.37.8%
C.56.7%
D.75%
Answer: C.56.7%
Explanation: Answer
(0.756 x 3/4) = (756/1000) x (3/4) x 100 % = 56.7%
Correct Option: C
Question: On dividing 15698 by a certain number, we get 89 as quotient and 14 as remainder. What is the divisor?
A.743
B.154
C.852
D.176
Answer: D.176
Explanation: Divisor *quotient+remainder=dividend
divisor=(dividend)-(remainder)/quotient
(15698-14)/89=176
Answer(D)
Question: How many days are there in x weeks x days?
A.8x
B.14x
C.7
D.7x
Answer: A.8x
Explanation: x weeks x days = (7x + x) days = 8x days.
Answer is A.