RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: An exam consists of 7 true/false questions. Brian forgets to study, so he must guess blindly on each question. If any score above 70% is a passing grade, what is the probability that Brian passes?
A.1/16
B.37/256
C.1/2
D.219/256
Answer: D.219/256
Explanation: If you have 8 T or F and Brian is going to guess then each question he has a 50% chance of getting correct.
If a passing score is 70% it means Brian needs to get 6/8=75%, 7/8=87.5%, or 8/8=100% to pass. Each is a possibility. If Brian gets a 5/8(=62.5%) or below he fails.
So first figure out the number of ways that Brian can get 6 out of 8, 7 out of 8, and 8 out of 8 questions correct.
Which is 8 choose 6, equals is 28, 8 choose 7, equals 8, and 8 choose 8, equals 1. This sums to 37.
The number of possible questions outcomes -the sum of 8 choose 8, 7 choose 8, 6 choose 8….2 choose 8, 1 choose 8, and 0 choose 8 is 256, so the chance of him passing is 219/256.
D
Question: a sales person was starting a business and giving everyone that worked there a salary of 50000 for the first 6 years and giving them 65000 after 12 years. what would the interest rate for each year?
A.7%
B.10%
C.15%
D.25%
Answer: A.7%
Explanation: for 6 years = (65000 - 50000 ) = 15000.
for 12 years = (15000x6)/6= 15000
Principal = (50000 - 15000) = 35000.
Hence, rate = (100 x 15000)/(35000x6) = 7% ANSWER: A
Question: If 25% of x is 15 less than 15% of 1500, then x is?
A.188
B.216
C.156
D.840
Answer: D.840
Explanation: 25% of x = x/4 ; 15% of 1500 = 15/100 * 1500 = 225
Given that, x/4 = 225 - 15 => x/4 = 210 => x = 840.
Answer: D
Question: Find the average of first 15 natural numbers.
A.10
B.120
C.15
D.8
Answer: D.8
Explanation: Explanation:
Sum of first n natural numbers = n(n+1)/2
Hence, sum of first 15 natural numbers = (15 x 16)/2 = 120
Therefore, required average of = 120/15 = 8
ANSWER: D
Question: What is |-26|?
A.(a) -26
B.(b) 26
C.(c) 0
D.(d) 1
Answer: B.(b) 26
Explanation: |-26|
= 26.
the answer is (B)
Question: A sum of money is borrowed and paid back in two annual installments of Rs. 882 each allowing 5% C.I. The sum borrowed was?
A.Rs. 1620
B.Rs. 1640
C.Rs. 1680
D.Rs. 1700
Answer: B.Rs. 1640
Explanation: Principal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)
= [882/(1 + 5/100) + 882/(1 + 5/100)2]
= (882 * 20)/21 + (882 * 400)/441 = Rs. 1640.
ANSWER:B
Question: In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 35 as quotient. What is the correct quotient ?
A.19
B.20
C.21
D.23
Answer: B.20
Explanation: Number = (12 x 35)
Correct Quotient = 420 ÷ 21 = 20
B)
Question: Anita, Indu and Geeta can do a piece of work in 18 days, 27 days and 36 days respectively. They start working together. After working for 4 days. Anita goes away and Indu leaves 7 days before the work is finished. Only Geeta remains at work from beginning to end. In how many days was the whole work done?
A.13 days
B.16 days
C.18 days
D.11 days
Answer: B.16 days
Explanation: B
16 days
4/18 + (x -7)/27 + x/36 = 1
x = 16 days
Question: The sale price sarees listed for Rs.560 after successive discount is 20% and 30% is?
A.321
B.314
C.316
D.265
Answer: B.314
Explanation: Explanation:
560*(80/100)*(70/100) = 314
Answer: B
Question: For a positive integer n, define S(n) to be the sum of the positive divisors of n. Which of the
following is the smallest?
A.S(2010)
B.S(2011)
C.S(2012)
D.S(2013)
Answer: B.S(2011)
Explanation: 2011 is prime, so that S(2011) = 1 + 2011 = 2012, the smallest.
But this answer can be verified without checking that 2011 is prime. Observe that
S(2010) > 2010 + 1005 > 3000
S(2013) > 2013 + 671 > 2600
and S(2012) and S(2014) are also larger than 3000.
Check by hand that 2, 3, 5, 7, and 11 do not divide 2011, and so if 2011 is not prime, then it
is a product of two primes p and q. If p 6= q, then
S(2011) = 2011 +
2011/p
+
2011/q
+ 1;
and p and q are greater than 11, so that this is smaller than 2600. If p = q then this is smaller
still.
correct answer B
Question: If the cost price of 15 articles is same as the selling price of 25 articles. Find the gain or loss percentage?
A.30% Gain
B.30% Loss
C.40% Gain
D.40% Loss
Answer: D.40% Loss
Explanation: Explanation:
15 cp = 25 sp
Cost price CP = 25
Selling price SP = 15
Formula = (SP-CP)/CP * 100 = (15 - 25)/25 * 100 = 40 % Loss
Answer: Option D
Question: If a sum of money at simple interest doubles in 6 years, it will become 4 times in
A.15years
B.16years
C.11years
D.18years
Answer: D.18years
Explanation: Explanation:
let sum =x . s.i.=x
rate =(100*x)/(x*6)=50/3%
now ,sum =x, s.i= 3x, rate =50/3%
time =(100*3x)/(x*50/3) = 18 years
Answer: D
Question: A photograph measuring 8.5 by 7.5 cm is to be enlarged. If the enlargement of the longer side is 13.6 cm, what is the length of the smaller side?
A.10
B.11
C.12
D.13
Answer: C.12
Explanation: Sol.
= (13.6 ÷ 8.5) × 7.5
= 12 cm.
Answer : C
Question: In how many ways the letters of the word RAIMBON be arranged?
A.4678
B.8754
C.5040
D.8658
Answer: C.5040
Explanation: Total ways of arranging the letters = 7! = 5040 ways.
C)
Question: ind the ratio of the curved surfaces of two cylinders of same heights if their radii are in the ratio 1:2?
A.18 kmph
B.19 kmph
C.24 kmph
D.17 kmph
Answer: C.24 kmph
Explanation: Total time taken = x/40 + 2x/20 hours
= 5x/40 = x/8 hours
Average speed = 3x/(x/8)
= 24 kmph
Answer: C
Question: A and B put in Rs.300 and Rs.400 respectively into a business. A reinvests into the business his share of the first year's profit of Rs.210 where as B does not. In what ratio should they divide the second year's profit?
A.39:40
B.39:30
C.39:47
D.39:45
Answer: A.39:40
Explanation: 3: 4
A = 3/7*210 = 90
390: 400
39:40
Answer: A
Question: Maru obtained 66, 65, 82, 67 and 75 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
A.71
B.38
C.39
D.37
Answer: A.71
Explanation: Average = (66 + 65 + 82 + 67 + 75)/5
= 71.
Answer: A
Question: A is twice as good as B. And together they finish a piece of work in 18days. In how many days will A alone finish the work
A.25
B.27
C.15
D.18
Answer: B.27
Explanation: (A's 1day work):(B's 1day work) = 2:1
A+B 1day work = 1/18
A's 1day work = (1/18)*(2/3) = 1/27
A alone can finish the work in 27 days
Answer is B
Question: What amount does Kiran get if he invests Rs. 18000 at 15% p.a. simple interest for four years?
A.22777
B.28877
C.26888
D.28800
Answer: D.28800
Explanation: Simple interest = (18000 * 4 * 15)/100 = Rs. 10800
Amount = P + I = 18000 + 10800 = Rs. 28800
Answer:D
Question: In track last week, the boys ran 27 laps. The girls ran 9 more
laps. Each lap is a three-fourth of a mile. How many miles did the girls run?
A.24 miles
B.25 miles
C.26 miles
D.27 miles
Answer: D.27 miles
Explanation: The girls ran 27 + 9 = 36 laps. 36 x3/4 = 108/4, which reduces to 27.
The girls ran 27 miles
correct answer D
Question: Dan can do a job alone in 15 hours. Annie, working alone, can do the same job in just 10 hours. If Dan works alone for 3 hours and then stops, how many hours will it take Annie, working alone, to complete the job?
A.2
B.4
C.6
D.8
Answer: D.8
Explanation: Dan can complete 1/15 of the job per hour.
In 3 hours, Dan completes 3(1/15) = 1/5 of the job.
Annie can complete 1/10 of the job per hour.
To complete the job, Annie will take 4/5 / 1/10 = 8 hours.
The answer is D.
Question: Hannah and Glen will throw three dice each. The score is the sum of points on all three dice. If Hannah scores 3 in her attempt, what is the probability that Glen will outscore Hannah in his attempt?
A.5/6
B.35/36
C.71/72
D.215/216
Answer: D.215/216
Explanation: The total number of ways the dice can land is 6*6*6=216.
There is only 1 way that Glen can get a score of 3 = 1+1+1
Glen wins for any other outcome.
P(Glen wins)=1-1/216=215/216
The answer is D.
Question: A train running at the speed of 60 km/hr crosses a pole in 15 seconds. Find the length of the train.
A.150
B.278
C.179
D.250
Answer: D.250
Explanation: :
Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 15 = 250 meter
Answer:D
Question: If each year the population of the country grows by 40%, how many years will elapse before the population of the country doubles?
A.3
B.4
C.5
D.6
Answer: A.3
Explanation: Till Year 2000, population is 100 .
Year 2001: Population becomes 140 ............. 1 Year elapsed
Year 2002: Population becomes 196 ............. 2 Year elapsed
Year 2003: Population > 200 .................. 3 year elapsed
Answer:A
Question: If 0.75 : x :: 5 : 8, then x is equal to:
A.1.12
B.1.2
C.1.25
D.1.3
Answer: B.1.2
Explanation: (x * 5) = (0.75 * 8)
x = 6/5
x = 1.20
Answer = B
Question: A train 125 m long passes a man, running at 8 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
A.37 km/hr
B.53 km/hr
C.36 km/hr
D.26 km/hr
Answer: B.53 km/hr
Explanation: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 8 = 45 => x = 53 km/hr.
Answer:B
Question: If in coded language
23 = 10
72 = 63
65 = 66
84 = 96
Then
97 = ?
A.141
B.142
C.143
D.144
Answer: D.144
Explanation: 2x(2+3)=10
7x(7+2)=63
6x(6+5)=66
8x(8+4)=96
9x(9+7)=144
ANSWER:D
Question: A rectangular paper when folded into two congruent parts had a perimeter of 34cm foer each part folded along one set of sides and the same is 38cm. When folded along the other set of sides. What is the area of the paper?
A.140
B.388
C.238
D.119
Answer: A.140
Explanation: when folded along the breadth
we have 2(l/2 +b) = 34 or l+2b = 34...........(1)
when folded along the length, we have 2(l+b/2)=38 or 2l+b =38.....(2)
from 1 &2 we get l=14 and b=10
Area of the paper = 14*10 = 140 sq cmV
Answer: A
Question: A family consists of two grandparents, two parents and six grandchildren. The average age of the grandparents is 65 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of family?
A.10/6years
B.B)31
C.C)30
D.D)33
Answer: A.10/6years
Explanation: Required average
= (65 x 2 + 35 x 2 + 6 x 6 )/(2 + 2 + 6)
= (134 + 70 + 18)/10
= 236/10
= 23 10/6years.
Answer is A
Question: The guidelines at a certain college specify that for the introductory English class, the professor may choose one of five specified novels, and choose two plays from a list of 5 specified plays. Thus, the reading list for this introductory class has one novel and two plays. How many different reading lists could a professor create within these parameters?
A.50
B.55
C.60
D.65
Answer: A.50
Explanation: 5C1*5C2 = 5*10 = 50
The answer is A.
Question: Difference between the length &breadth of a rectangle is 26 m. If its perimeter is 208 m, then its area is?? We have: (l - b) = 26 and 2(l + b) = 208 or (l + b) = 104?
A.2525 m^2
B.2625 m^2
C.2535 m^2
D.2553 m^2
Answer: C.2535 m^2
Explanation: Solving the two equations, we get: l = 65 and b = 39.
Area = (l x b) = (65 x 39) m2 = 2535 m^2
C
Question: If N = 5/6 + 6/7 + 7/8 + 8/9 + 9/10 + 10/11, then which of the following must be true of N?
A.5/6 < N < 10/11
B.21/10 < N < 9/2
C.5 < N < 5 1/11
D.5 < N < 5 5/11
Answer: D.5 < N < 5 5/11
Explanation: Each fraction is close to 1 so we know that the sum will be less than 6.
Lets just say they're each 1 so N=6.
But now we have to subtract the difference
1/6+1/7+1/8+1/9+1/10+1/11.
We can estimate these each as 1/10-->5/10 which is 1/2.
D is the closest representation
Question: 14, 23, 32, 41, 50, 59, …
In the sequence above, each term is 9 more than the previous term. What is the 41st term W of the sequence?
A.360
B.365
C.369
D.374
Answer: D.374
Explanation: First term , a= 14
Common difference , d = 9
nth term , tn = a + (n-1)d
41st term W , t41 = a+ 40*d = 14 + 40*9 = 374
Answer D
Question: How many 3-digit numbers are completely divisible 6 ?
A.100
B.150
C.200
D.250
Answer: B.150
Explanation: 3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
B)
Question: 12 spheres of the same size are made from melting a solid cylinder of 16 cm diameter and 2 cm height. Find the diameter of each sphere.
A.4 cm
B.6 cm
C.8 cm
D.10 cm
Answer: A.4 cm
Explanation: Explanation:
In this type of question, just equate the two volumes to get the answer as,
Volume of cylinder =πr2h
Volume of sphere =43πr3
=>12∗4/3πr3=πr2h
=>12∗4/3πr3=π∗8∗8∗2
=>r3=8∗8∗2∗3/12∗4
=>r3=8
=>r=2cm
=>Diameter =2∗2=4cm
Option A
Question: A school’s annual budget for the purchase of student computers increased by 20% this year over last year. If the price of student computers increased by 10% this year, then the number of computers it can purchase this year is what percent greater than the number of computers it purchased last year?
A.9%
B.9.09%
C.10%
D.10.09%
Answer: B.9.09%
Explanation: Pick numbers.
Lats year: budget = $100, price = $1 --> the number of computers purchased = 100/1 = 100;
This year: budget = $120, price = $1.1 --> the number of computers purchased = 120/1.1 = ~109.09
Increase in the number of computers purchased = 9.09%
Answer: B.
Question: There are 4 gold chain. 1 has 5links, other has 4 links and the other 2 have 3 links.
goldsmith takes 50 paise to open the link and 1.00/- to attach the link. what is least cost to
bake whole bracelet.
A.3.50 rupees
B.4.50 rupees
C.4.80 rupees
D.5.50 rupees
Answer: B.4.50 rupees
Explanation: Let,the shape of the bracelet is closed circle.[It is supposed to assume]
gold chain with 5 links: A_ _ _ _ _B
gold chain with 4 links: C_ _ _ _D
gold chain with 3 links: E_ _ _F
gold chain with 3 links: G_ _ _H
We,generally hold a common notion that since there are 4 gold chains and since we are to make a closed circular shaped bracelet, so,we have to join the ends namely :(B,C),(D,E),(F,G),(H,A),i.e, total 4 links have to be broken and further joined,i.e, total cost will then be 4(1+.50)= 6 rupees.
But,now we will tackle the problem in a different way.
Let, all the 3 links of GH chain are broken.
Then,
with the help of 1st broken link, B and C ends are joined.
with the help of 2nd broken link, D and E ends are joined.
and,
With the help of the remaining broken link, F and A ends are joined.
So, the above mentioned method explains us that breaking only 3 links and subsequently joining two free ends with each link facilitates us to make a whole closed circular shaped bracelet.
Therefore,the cost in this case : 3*(1+.50) = 3*(1.50)=4.50 rupees;
So,evidently,the least cost to make the whole bracelet :4.50 rupees .
ANSWER:B
Question: Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is
A.76 years
B.30 years
C.77 years
D.88 years
Answer: B.30 years
Explanation: Let their ages 10 years ago is x, 2x and 3x years.
10 + 2x + 10 + 3x + 10 = 90 hence x= 10
B’s present age = (2x + 10) =30 years
Answer: B
Question: Jake, Lena, and Inna need to drive home from a corporate reception in an SUV that can seat 5 people. If only Inna or Jake can drive, how many seat allocations are possible?
A.24
B.42
C.120
D.360
Answer: A.24
Explanation: 3 people ,5 seats, only 2 can drive
if inna is in one seat remaining, 2 people can be arranged in 2p2 i.e 2! =2 ways
since any one can drive total ways = 2 *2= 4 ways
4 seats can be chosen out of remaining 5 seats in 5c4 ways = 5!/(3!*2!)= 6 ways
4*6=24
A
Question: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?
A.1.8
B.1.5
C.1.9
D.1.2
Answer: B.1.5
Explanation: 72 --- 9 DS = 8
? ---- 1
45 ---- 9 US = 5
? ---- 1 S = ?
S = (8 - 5)/2 = 1.5
Answer: B
Question: In a urban village of india named "owlna" , 80% people have refrigerator , 82% people have television , 70% people got computers and 75% got Air-conditionor. how many people(minimum) got all these luxury.
A.3%
B.8%
C.7%
D.10%
Answer: C.7%
Explanation: C
7%
100 - [ (100-80)+(100-82)+(100-70) +(100-75)]
=100-(20+18+30+25)
=100-93
Question: If x - 8 = -|x|, then x=?
A.2
B.-4
C.4
D.3
Answer: C.4
Explanation: x - 8 = -|x| ...(given)
x^2 - 16x + 64 = x^2
0*x^2 + 16*x -64 = 0 ....(by solving above eq. we get) , x = 4 ===> Ans - C
Question: In a division, divident is 760, divisior is 36 and quotient is 21. Find the remainder.
A.A)4
B.B)3
C.C)2
D.D)5
Answer: A.A)4
Explanation: Explanation:
760 = 36 x 21 + r
760 = 756 + r
r = 760 - 756 = 4
Answer: Option A
Question: The simple interest accrued on an amount Rs.10,000 at the end of two years is same as the compound interest on Rs.8,000 at the end of two years. The rate of interest is same in both the cases. What is the rate of interest?
A.22
B.77
C.66
D.50
Answer: D.50
Explanation: Given that Rs.10,000 is invested in S.I for two years and Rs.8,000 in C.I for two years
=> C.I - S.I
=> 8,000 { [1 + r/100]2 - 1} = (10,000)2r /100
=> 8{ 1 + 2r/100 + r2 / (100)2 - 1} = r/5
=> 16r/100 + 8r2/(100)2 = 20r/100
=> 4r/10 = 8r2/(100)2
=> 8[r/100]2 - 4r/100 = 0
=> r/100 {8r/100 -4} = 0
=> r = 0% of 50%
Since r!= 0%, r =50%
Answer:D
Question: If y = 1296 * 125 * 4096 / 25, How many digits are in y,
A.4
B.8
C.2
D.6
Answer: B.8
Explanation: y = 1296 * 125 * 4096 / 25
y = 8^4 * 5^3 * 6^4 / 5^2
y = 48^4 * 5
y = 26542080
Ans: B
Question: Of 100 applicants for a job, 50 had at least 5 years of prior work experience, 40 had advanced degrees, and 10 had at least 5 years of prior work experience and advanced degrees. How many of the applicants had neither 5 years of prior work experience nor advanced degrees?
A.30
B.15
C.20
D.34
Answer: C.20
Explanation: Had advanced degrees and 5 years work experience: 10
Only had 5 years work experience: 50-10 = 40
Only had advanced degrees: 40-10 = 30
100-10-40-30=20
Answer: C
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 12%?
A.20%
B.25%
C.13 1/30%
D.32%
Answer: D.32%
Explanation: SP2 = 2/3 SP1
CP = 100
SP2 = 88
2/3 SP1 = 88
SP1 = 132
100 --- 32 => 32%
ANSWER:D
Question: In a group of 6 male and 4 female, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
A.200
B.209
C.207
D.300
Answer: B.209
Explanation: req no = 6C1*4C1 + 6C2*4C1 + 6C4
==6C1+4C1 + 6C2+4C2 + 6C3*4C1 + 6C4
(6*4) + (6*5/2*1 * 4*3/2*1) + 6*5*4/3*2*1*4 + 6*5/2*1
==> 209
ANSWER B
Question: A and B put in Rs.300 and Rs.400 respectively into a business. A reinvests into the business his share of the first year's profit of Rs.210 where as B does not. In what ratio should they divide the second year's profit?
A.39:40
B.39:86
C.39:18
D.39:10
Answer: A.39:40
Explanation: 3: 4
A = 3/7*210 = 90
390: 400
39:40
Answer: A
Question: If x and y are different integers and x^2 = xy, which of the following must be true ?
I. x = 0
II. y = 0
III. x = -y
A.I only
B.II only
C.III only
D.I and III only
Answer: A.I only
Explanation: Re-arrange equation: x^2 - xy = 0 => x*(x-y) = 0
Therefore, either x=0 or x=y. We know that x and y are different, so x must be equal to 0.
ANSWER:A
Question: A parking space have 8 different slots. 8 cars has to arrange in 8 slots. But there are exactly 4 cars between 1 specified cars. In how many ways cars can be arranged?
A.1210
B.120
C.1500
D.1640
Answer: B.120
Explanation: we arranged 1 specified cars in 1 slots = 1!
remaining 5 cars in 5 slots = 5!
number of ways = 1!*5! = 120
correct option is B
Question: A class of six students has to split into two indistinguishable teams of three people. Compute
the number of distinct team arrangements that can result.
A.2 distinct teams.
B.4 distinct teams.
C.10 distinct teams.
D.8 distinct teams.
Answer: C.10 distinct teams.
Explanation: Consider one specific person of the six students. There are
(5
2)
to choose the 2
partners on his team. Hence, there are
(5
2)
= 10 distinct teams.
correct answer C
Question: If x is divisible by 2, 14, and 10, which of the following must be the least multiple of x?
A.308
B.154
C.70
D.44
Answer: C.70
Explanation: We are looking for the LCM (which is not 0) of 2, 10 = 2*5, 14 = 2*7:
2 * 5 * 7 = 70
The answer is C.
Question: A person distributed 20% of his income to his 3 children each. He deposited 30% of his income to his wife's account. He donated 5% of remaining amount to an orphan house.Finally he has $50000. Find his total income?
A.A)452000
B.B)562000
C.C)800000
D.D)1000000
Answer: D.D)1000000
Explanation: 3 children got = 3*20% = 60%
wife got = 30%
orphan house = 5%
total = 60+30+5 = 95%
remaining = 100-95 = 5%
5% = 50000
100% = 50000*100/5 = $1000000
Answer is D
Question: If c equals the sum of the even integers from 2 to 504, inclusive, and m equals the sum of the odd integers from 1 to 297, inclusive, what is the value of c + 2m?
A.85957
B.108158
C.299376
D.107860
Answer: B.108158
Explanation: Use following formulae for such problems:
Sum of evenly spaced integers = (# of integers)*(mean of integers)
# of integers = [(last - first)/2] + 1
Mean of integers = (last + first)/2
In above problem:
# of integers = [(504 - 2)/2] + 1= 252 and [(297-1)/2]+ 1 = 149
Mean of integers = (504 + 2)/2 = 253 and (297 + 1)/2 = 149
Sum of integers = (252*253) = 63756 and (149*149) = 22201
Thus their sum (c + 2m) = 63756 + (2 * 22201) = 108258
ANSWER:B
Question: A boy gives 15 percent of a pie to his mother, 10 percent to his father and 25 percent to his sister. What fraction of the pie is leftover?
A.4/5
B.3/5
C.1/2
D.1/5
Answer: C.1/2
Explanation: 100%-(15%+10%+25%)=50% of the pie remains --> 50% = 20/100 = 1/5.
Answer: C.
Question: How many times are the hands of a clock at right angle in a day?
A.11
B.22
C.33
D.44
Answer: D.44
Explanation: Sol.
In 12 hours, they are at right angles 22 times.
∴ In 24 hours, they are at right angles 44 times.
Answer D
Question: If xy > 0, 1/x + 1/y = 2, and 1/xy = 8, then (x+y)/4 = ?
A.1/16
B.1/6
C.1/5
D.5
Answer: A.1/16
Explanation: (1/X+1/Y)=2 canbe solved as {(x+y)/xy}=8. Substituting for 1/xy=8, we get
x+y=2/8
==> (x+y)/4= 2/(8*4)=1/16.
A
Question: In 10 years, A will be twice as old5as B was 10 years ago. If A is now 5 years older than B, the present age of B is
A.35
B.37
C.39
D.41
Answer: A.35
Explanation: Explanation:
Let B's age = x years.
Then, As age = (x+ 5) years.
(x+5+10)=2(x—10)
hence x=35.
Present age of B = 35 years
Answer: Option A
Question: Harriet planned to complete a certain task on Friday, January 1, but because of illness the completion date was postponed 48 days. On which day of the week in February was the task completed?
A.Monday
B.Tuesday
C.Wednesday
D.Thursday
Answer: D.Thursday
Explanation: This type of story problem is essentially just about a repeating pattern and a 'remainder.'
We're told that Harriet planned to complete a certain task on FRIDAY, January 1, but because of illness the completion date was postponed 48 DAYS. We're asked on what day of the week the task was actually completed on.
Since the task was supposed to be completed on a Friday....
A 1 day postponement would be Saturday
A 2 day postponement would be Sunday
A 3 day postponement would be Monday
A 4 day postponement would be Tuesday
A 5 day postponement would be Wednesday
A 6 day postponement would be Thursday
A 7 day postponement would be Friday
A 8 day postponement would be Saturday
Etc.
So this question is ultimately asking how many 'groups of 7' are there, and how many 'leftover days' are there, when you postpone 48 days.
48/7 = 6 remainder 6
This means that there are 6 full weeks AND 6 extra days after a Friday....Thus, the task was completed on a Thursday.
D
Question: what is 66.67% of 804 of 0.1666 ?
A.19.33
B.54.55
C.89.33
D.97.21
Answer: C.89.33
Explanation: 66.67 % = 2/3
2/3 of 804 = 2/3 * 804 = 536
536 of 0.166 = 536 * (1/6) = 89.33
.... Ans - C
Question: A table is bought for Rs.1000/- and sold at Rs.1200/- find the loss percentage
A.10% Loss
B.10% Gain
C.20% Loss
D.20% Gain
Answer: D.20% Gain
Explanation: Formula = (Selling price ~ Cost price)/Cost price * 100
= (1200 ~ 1000)/1000 = 20% Gain
D