RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A group of men decided to do a work in 55 days, but 15 of them became absent. If the rest of the group did the work in 60 days, Find the original number of men?
A.180
B.150
C.140
D.100
Answer: A.180
Explanation: Original number of men = 15*60 / (60-55) = 180
Answer is A
Question: A group consists of 4 couples in which each of the 4 boys have one girl friend.In how many ways they can be arranged in a straight line such that boys and girls occupies alternate positions?
A.1142
B.1152
C.1252
D.1342
Answer: B.1152
Explanation: Total positions are 8.
In that boys can be arranged in 4 places and girls can be arranged in 4 places and hence this can be done in 2 ways.
i.e => 4! * 4! * 2 = 24*24*2=1152.
ANSWER:B
Question: What is the probability of rolling a total of 9 with a single roll of two fair six-sided dice, each with the distinct numbers 1 through 6 on each side?
A.1/12
B.1/6
C.1/9
D.1/3
Answer: C.1/9
Explanation: Totalsample spacefrom two fair six-sided dice is 36.
There are six possible ways to be 7 i.e. (3+6), (4+5), (5+4), (6+3)
So, total probability is 4/36 or 1/9.
Answer is C.
Question: What is the angle of degree suspended when two hands of clock showing the time 2.30.
A.95 degree
B.105 degree
C.115 degree
D.125 degree
Answer: B.105 degree
Explanation: angle between 2 and 6 =30*4=120
andin half an hour hour hand moves forward by 30/2=15 degree
hence required ans= 120-15=105 degree
ANSWER:B
Question: If m and n are positive integers and n ≠ 1, then mn(n −1) is
A.m-n
B.m+n
C.mn
D.mn^2 -mn
Answer: D.mn^2 -mn
Explanation: mn(n-1) = mn^2 -mn
Answer : D
Question: Seema took a loan of 1800 with simple interest for as many years as the rate of interest. If she paid 162 as interest at the end of the loan period, what was the rate of interest?
A.4
B.3
C.5
D.Can not be determined
Answer: B.3
Explanation: Explanation: Let rate = R% and time = R years.
Then, (1800 x R x R)/100 = 162
18RÂ² = 162
RÂ² = 9
R = 3.
Answer: B
Question: If J is the interest on K and K is the interest on L, the rate and time is the same on both the cases. What is the relation between J, K and L ?
A.JxJ = KL
B.KxK= JL
C.LxL = JK
D.JKL = 1
Answer: B.KxK= JL
Explanation: Explanation:
Let the Time be 'N' and Rate be 'R'
J = (K x NR)/100 K = (L x NR)/100
J/K = NR/100 K/L = NR/100
J/K = K/L
K2= JL
ANSWER IS B
Question: P is 50% more efficient than Q. P can complete a work in 25 days. If P and Q work together, how many days will it take to complete the same work?
A.11
B.13
C.15
D.17
Answer: C.15
Explanation: The work done by P in 1 day = 1/25
Let work done by Q in 1 day = q
q × (150/100) = 1/25
q = 100/(25×150) = 10/(25×15)
The work done by P and Q in 1 day = 1/25 + 10/(25×15) = 25/(25×15)= 1/15
P and Q together can do the work in 15 days.
The answer is C.
Question: The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
A.10 a.m
B.09 a.m
C.11 a.m
D.05 a.m
Answer: C.11 a.m
Explanation: Explanation:
Suppose they meet x hrs after 8 a.m
then,
[Distance moved by first in x hrs] + [Distance moved by second in (x-1) hrs] = 330.
Therefore, 60x + 75(x-1) = 330.
=> x=3.
So,they meet at (8+3) i.e, 11a.m.
Answer: C
Question: A set A consists of 7 consecutive odd integers. If the sum of 5 largest integers of set A is -185 what is the sum of the 5 smallest integers of set A?
A.165
B.175
C.195
D.205
Answer: D.205
Explanation: Average of largest 5 = -185/5 =-37
So the largest numbers are -41, -39, -37, -35, -33
Now if we consider smallest 5, we have to eliminate last 2 numbers, which are -35 and -33
Notice here that the numbers are equally spaced.
So the average of smallest number will just shift 2 place to the left.
Avg= -41
Therefore, total = -41*5= -205
Answer:D
Question: Four brothers Adam, Bill, Charles and David together contributed certain amount of money and purchased a car. The contribution made by Adam is half that of the total contribution made by the other three brothers, contribution made by Bill is one-fourth of the total contribution made by the other three brothers and the contribution made by Charles is two-third of the total contribution made by the other three brothers. If the total price of the car is $9750, find the contribution made by David.
A.$540
B.$580
C.$600
D.$650
Answer: D.$650
Explanation: Given that A:(B+C+D)= 1:2.
Hence A contributed 1/3rd of the total price.
Given B:(A+C+D)=1:4
Hence B contributed 1/5th of the total price.
Given C:(A+B+D)=2:3
Hence C contributed 2/5th of the total price.
Thus the contribution made by A,B and C= 1/3+1/5+2/5=14/15
So, the remaining 1/15th of the price is contributed by David.
Hence David's contribution= 1/15×9750=$650.
The answer is D.
Question: If 1^3 + 2^3 + 3^3 +......+ 10^3 = 516 then the value of 2^3 + 4^3 + 63 + ..... + 203 is
A.1032
B.1030
C.1034
D.1035
Answer: A.1032
Explanation: 2(13 + 23 + 33 + ---------- + 103)
2 × 516 = 1032
A
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.248 m
B.240 m
C.277 m
D.765 m
Answer: B.240 m
Explanation: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x
= 240 m.
Answer: B
Question: Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is
A.2:5
B.3:5
C.4:5
D.6:5
Answer: C.4:5
Explanation: Explanation:
Let the third number be x.
First Number (120/100)*x = 6x/5
Second Number (150/100)*x = 3x/2
Ratio = 6x/5:3x/2
=> 4:5
Option C
Question: Quentin's income is 60% less than Rex's income, and Ram's income is 25% less than Quentin's income. If Rex gave 60% of his income to Ram and 40% of his income to Quentin, Quentin's new income would be what fraction of Ram's new income?
A.8/9
B.11/12
C.8/13
D.11/13
Answer: A.8/9
Explanation: We can take some easy numbers and make calculations simpler.
Let R ( Rex's income) = 100
Q (Quentin's income) = 40%R = 40
S (Ram's income) = 75% Q = (3/4)*40 = 30
Now, if Rex gives 40% to Quentin --> Q = 40 + 40 = 80
60% given to Ram --> S = 30+60 = 90
The ratio is : Q/S = 80/90 = 8/9=A
Question: A watch is sold for Rs.440 cash or for Rs.200 cash down payment together with Rs.244 to be paid after one month. Find the rate of interest charged in the installment scheme.
A.10%
B.15%
C.20%
D.25%
Answer: C.20%
Explanation: Explanation:
Principal for the next month = 440 - 200 = 240
Amount paid after next month = 244
Therefore interest charged at Rs.240 = 240×1×R/12×100=4
Rate of interest (R) = 20% per annum
Answer C
Question: The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 108° of the circle, what percentage of MegaTek employees are in manufacturing?
A.20%
B.25%
C.30%
D.35%
Answer: C.30%
Explanation: ANSWER: C
108° divided by 360° equals 0.3, therefore the sector is equal to 30% of the total
Question: Jagtap purchases 30 kg of wheat at the rate of 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately at what price per kg should he sell the mixture to make 30 per cent profit?
A.16.3
B.18.2
C.15.6
D.14.8
Answer: A.16.3
Explanation: CP = 30 × 11.50 + 20 × 14.25 = 630
SP = 630 × 130⁄100 × 1⁄50 ≈ 16.30
Answer A
Question: Ram professes to sell his goods at the cost price but he made use of 900 grms instead of a kg, what is the gain percent?
A.11 1/8
B.11 1/7
C.11 1/9
D.11 1/1
Answer: C.11 1/9
Explanation: 900 --- 100
100 --- ? => 11 1/9%.Answer: C
Question: If the C.I. on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the S.I. on the same sum at the same rate for the same period of time is?
A.488
B.485
C.470
D.480
Answer: D.480
Explanation: Let the sum be Rs. P. Then,
[P(1 + 25/(2 * 100))2 - P] = 510
P[(9/8)2 - 1] = 510.
Sum = Rs. 1920
So, S.I. = (1920 * 25 * 2) / (2 * 100) = Rs. 480.Answer: D
Question: In a group of 100 adults, 75 percent of the women are left-handed. If there are 11 right-handed women in the group, how many men are in the group?
A.48
B.52
C.56
D.60
Answer: C.56
Explanation: 12 left-haded women compose 100-75=25% (or 1/4) of all women, so there are total of 4*11=44 women --> 100-44=56 men.
Answer: C.
Question: An unbiased die is tossed. Find the probability of getting a multiple of 3
A.1/3
B.2/3
C.1
D.4/3
Answer: A.1/3
Explanation: Here S={1,2,3,4,5,6}
Let E be the event of getting the multiple of 3
then ,E={3,6}
P(E)=n(E)/n(S)=2/6=1/3
answer option A) 1/3.
Question: A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
A.100
B.377
C.399
D.277
Answer: A.100
Explanation: Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr
Distance covered in 6 minutes = {\color{Blue} \left ( \frac{1}{60}\times 6 \right )} km = {\color{Blue} \frac{1}{10}} km = 100 m
{\color{Blue} \therefore } Distance between the thief and policeman = (200 – 100) m = 100 m.
Answer: A) 100 m
Question: If Bob has $20 in his pocket and a bowl of ice creams sells for $5 and pizza sells for $12, which of the following COULD be true?
I. Bob can buy 4 bowls of ice cream.
II. Bob can buy 2 bowls of ice cream and pizza.
III. Bob can buy 3 bowls of ice cream and pizza.
A. I only
B. I and II only
C. I and III only
D. II and III only
Answer: A. I only
Explanation: Let’s check each statement.
Statement I:Bob can buy 4 bowls of ice cream. the cost of one bowl of ice cream is $5, 4 bowls of ice cream will cost $5 * 4 = $20, in which case Statement I is be TRUE.
Statement II: Bob can buy 2 bowls of icecream and pizza. The cost of ice cream is $5 and pizza is $12, 2 bowls of ice cream will cost $5 * 2 = $10 and Pizza will cost $12. Total is $10 + $12 = $22 in which case Statement II can NEVER BE TRUE.
Statement III: Bob can buy 3 bowls of ice cream and pizza. 3 bowls of ice cream = $5 * 3 = $15 and pizza = $12. Total = $15 + $12 = $27, in which case Statement III ca NEVER BE TRUE.
Only Statement I is true.
So,the correct answer is A
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 22 seconds. The ratio of their speeds is?
A.3/1
B.3/1
C.1/1
D.3/5
Answer: C.1/1
Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train
= 27 x meters, and length of the second train
= 17 y meters. (27 x + 17 y) / (x + y) = 22 ==> 27 x + 17 y = 22 x + 22 y
==> 5 x = 5 y ==> x/y
= 1/1.
Answer:C
Question: An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases?
A.8:7
B.8:7
C.8:3
D.8:1
Answer: B.8:7
Explanation: Let the length and breadth of the carpet in the first case be 3x units and 2x units respectively.
Let the dimensions of the carpet in the second case be 7y, 3y units respectively.
From the data,.
2(3x + 2x) = 2(7y + 3y)
=> 5x = 10y
=> x = 2y
Required ratio of the areas of the carpet in both the cases
= 3x * 2x : 7y : 3y
= 6x2 : 21y2
= 6 * (2y)2 : 21y2
= 6 * 4y2 : 21y2
= 8:7
Answer:B
Question: A certain store sells only black shoes and brown shoes. In a certain week, the store sold x black shoes and y brown shoes. If 1/4 of all shoes sold that week were black, which of the following expressions represents the value of y, in terms of x?
A.x/3
B.x/2
C.2x/3
D.3x
Answer: D.3x
Explanation: x/(x+y) = 1/4
4x = x+y
3x = y
y = 3x
Answer D
Question: Suppose we have six marbles: 3 blue marbles, 2 yellow marbles, and one green marble. Suppose we are going to put them into three cups: a black cup, a white cup, and a purple cup. We could put all six in any cup and leave two cups empty; or we could put marbles in two cups and leave one cup empty; or we could put some marbles in each of the three cups. How many combinations are possible?
A.190
B.180
C.200
D.240
Answer: B.180
Explanation: # ways to distribute Blue marbels(3) is :
1 in each cup= 1
2 in one cup and 1 in other=6
all 3 in one cup = 3
total 1+6+3=10 possibilities
# ways to distribute yellow marbels(2) is :
1 in each cup = 3 ways
all in one cup = 3ways
total 6ways.
# ways to distribute Green marbels(1) is :
3 ways
total number of ways = 10*6 *3 = 180
B
Question: If s is the product of the integers from 10 to 20 inclusive, and if t is the product of the integers from 10 to 21 inclusive, what is 1/s + 1/t in terms of t?
A.22/t
B.24/t
C.26/t
D.28/t
Answer: A.22/t
Explanation: Similarly in the actual problem
s =t/21. 1/s = 1/(t/21) or 1/s = 21/t
1/s + 1/t = 21/t + 1/t = 22/t
A
Question: Sam purchased 20 dozens of shirts at the rate of $ 375 per dozen. He sold each one of them at the rate of $ 33. What was his percentage profit?
A.5%
B.4.8%
C.5.6%
D.8.2%
Answer: C.5.6%
Explanation: C
5.6%
C.P. of 1 shirt = 375/12 = $ 31.25
S.P of 1 shirt = $ 33
Profit = 1.75/31.25 * 100 = 28/5 = 5.6%
Question: If t= 4p, where p is a prime number greater than 2, how many different positive even divisors does t have, including t ?
A. Two
B. Three
C. Four
D. Six
Answer: C. Four
Explanation: t=4p
since t = 4p thenevendivisors are:
4p/4p= 1
4p/2p= 2
4p/4= p
4p/2= 2p
so the answer is (C)
Question: A bag contains 50 tickets numbered 1,2,3,4......50 of which five are drawn at random and arranged in ascending order of magnitude.Find the probability that third drawn ticket is equal to 30.
A.551/15134
B.551/15139
C.551/15132
D.551/15196
Answer: A.551/15134
Explanation: Explanation:
Total number of elementary events = \inline {\color{Black}50C_{5}}
Given,third ticket =30
=> first and second should come from tickets numbered 1 to 29 = \inline {\color{Black}29C_{2}} ways and remaining two in \inline {\color{Black}20C_{2}} ways.
Therfore,favourable number of events = \inline {\color{Black}29C_{2}\times 20C_{2}}
Hence,required probability = \inline {\color{Blue}(29C_{2}\times 20C_{2})/50C_{5}} =551 / 15134
Answer: A) 551/15134
Question: R is the set of positive odd integers less than 50, and S is the set of the squares of the integers in R. How many elements does the intersection of R and S contain ?
A.None
B.Two
C.Four
D.Five
Answer: C.Four
Explanation: squares < 50 {1,4,9,16,25,36,49 }
S = {1,9,25,49}
R = {1,3,.....49}
Hence C.
Question: In how many different ways can the letters of the word 'CORPORATION' be arranged so that the vowels always come together?
A.50028
B.50035
C.50400
D.50723
Answer: D.50723
Explanation: This has 7 (6 + 1) letters of which R occurs 2 times and the rest are different.
Number of ways arranging these letters =	7!/2!	= 2520.
Now, 5 vowels in which O occurs 3 times and the rest are different, can be arranged
in	5!/3!	= 20 ways.
Required number of ways = (2520 x 20) = 50400.
Answer:D
Question: 2 hours after train A leaves Lucknow a train B leaves the same stationtraveling in the same direction at an average speed of 24 km/hr. After traveling 6 hrsthe train B overtakes the train A. What is the average speed of the train A?
A.15 km/hr
B.16 km/hr
C.17 km/hr
D.18 km/hr
Answer: D.18 km/hr
Explanation: Explanation :
Total distance covered by B=24*6=144kmTotal time taken by A to cover same distance=2+6=8 hrsaverage speed of A=144/8=18 km/hr
Answer : D
Question: Three years ago the average age of a family of six members was 19 years. A boy have been born, the average age of the family is the same today. What is the age of the boy?
A.1 year
B.3 year
C.6 year
D.8 year
Answer: A.1 year
Explanation: 6 * 22 = 132
7 * 19 = 133
--------------
1
Answer:A
Question: C is a working partner and B and A is a sleeping partner in a business. A puts in 50,000 and B 60,000 and C puts in 40000. C gets 25% of the profit for managing the business, and the rest is divided in proportion to their capitals. Find the share of A in profit of 20000.
A.4800
B.4500
C.5400
D.5000
Answer: D.5000
Explanation: The amount C gets for managing
= 25% of Rs. 20000 = 5000
Remaining profit = 20000 – 5000 = 15000
This is to be divided in the ratio 5 : 6 : 4
Share of A = 5/15 of 15000 = 5000
Answer D
Question: By selling 24 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
A.8
B.9
C.16
D.6
Answer: C.16
Explanation: 80% --- 24
120% --- ?
80/120 * 24 = 16
Answer: C
Question: A sum of money is distributed among A,B,C,D in the proportion of 5:2:4:3. If C gets $1000 more than D, what is the B's share?
A.$1000
B.$2000
C.$2500
D.$2850
Answer: B.$2000
Explanation: Let the shares of A,B,C,D are 5x,2x,4x,3x
4x-3x = 1000
x = 1000
B's share = 2x = $2000
Answer is B
Question: If Renee earns a raise of between 5% and 10%, non-inclusive, by what fraction could her salary have increased?
A.1/4
B.1/5
C.1/10
D.2/25
Answer: D.2/25
Explanation: 5% is 5/100 = 1/20
10% is 10/100 = 1/10
The increase must be greater than 1/20 and less than 1/10.
1/4, 1/5, and 1/10 are not less than 1/10.
1/20 is not greater than 1/20.
The only option left is 2/25, which is in the specified range.
ANSWER:D
Question: In a box, there are 4 blue, 6 white and 5 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?
A.3/16
B.5/15
C.8/32
D.2/32
Answer: B.5/15
Explanation: Total number of bulbs = (4 + 6 + 5) = 15.
Let E = event that the bulb drawn is neither white nor blue = event that the bulb drawn is yellow.
Therefore, P(E)=5/15
ANSWER:B
Question: A man bought 10 crates of bananas for $100 total. If he lost 2 of the crates, at what price would he have to sell each of the remaining crates in order to earn a total profit of 100 percent of the total cost?
A.$35
B.$45
C.$50
D.$25
Answer: D.$25
Explanation: As given, after lost, the remaining 8 crates total cost = $100
So, 1 crate cost = 100/8 = 12.5
To get 100% profit, 1 crate cost should be =12.5+12.5*100/100 =$25
Answer : D
Question: How many five digit numbers can be formed using digits 0,1,2,3,4,5, Which are divisible by 11, without any of the digits repeating?
A.216
B.96
C.81
D.72
Answer: B.96
Explanation: 0,1,2,3,4,5
One digit will have to remain out for all 5 digit numbers;
if 0 is out; Leftover digits will be 1,2,3,4,5 = Sum(1,2,3,4,5)=15. ignore
if 1 is out; Leftover digits will be 0,2,3,4,5 = Sum(0,2,3,4,5)=14. Ignore
if 3 is out; Leftover digits will be 0,1,2,4,5 = Sum(0,1,2,4,5)=12. ignore
if 4 is out; Leftover digits will be 0,1,2,3,5 = Sum(0,1,2,3,5)=11. =96
if 5 is out; Leftover digits will be 0,1,2,3,4 = Sum(0,1,2,3,4)=10. Ignore
Total count of numbers divisible by 11 = 96 = 96
Ans:B
Question: If n = 2.0423 and n* is the decimal obtained by rounding n to the nearest hundredth, what is the value of n* – n?
A. -0.0053
B. -0.0023
C. 0.0007
D. 0.0047
Answer: B. -0.0023
Explanation: n*=2.04
n*-n=2.04-2.0423
-0.0023
Answer: B
Question: A seven-digit number comprises of only 2's and 3's. How many of these are multiples of 12?
A.11
B.12
C.10
D.22
Answer: A.11
Explanation: DETAILED SOLUTION
Number should be a multiple of 3 and 4. So, the sum of the digits should be a multiple of 3. WE can either have all seven digits as 3, or have three 2's and four 3's, or six 2's and a 3. (The number of 2's should be a multiple of 3).
For the number to be a multiple of 4, the last 2 digits should be 32. Now, let us combine these two.
All seven 3's - No possibility.
Three 2's and four 3's - The first 5 digits should have two 2's and three 3's in some order. No of possibilities = 5!3!2! = 10
Six 2's and one 3 - The first 5 digits should all be 2's. So, there is only one number 2222232.
So, there are a total of 10 + 1 = 11 solutions.
CORRECT ANSWER : A.
Question: Which of the following fractions is the largest ?
A.7/8
B.13/16
C.31/40
D.63/80
Answer: A.7/8
Explanation: LCM of 8, 16, 40 , 80 is 80
7/8 * 10/10 = 70/80
16/16 * 5/5 = 65/80
31/40 * 2/2 = 62/80
63/80
Clearly 70/80 > 65/80 >63/80 >62/80
hence 7/8 is largest ANSWER : A
Question: A woman is 18 years older than her son. In two years, her age will be twice the age of her son. The present age of her son is:
A.20
B.16
C.22
D.23
Answer: B.16
Explanation: Let the son's present age be x years. Then, woman's present age = (x + 18) years.
(x + 18) + 2 = 2(x + 2)
x + 20 = 2x + 4
x = 16.
Answer:B
Question: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 4, what is the probability that one of the two cards drawn is numbered 2 ?
A.1/3
B.1/2
C.1/4
D.1/5
Answer: A.1/3
Explanation: (2,2) (3,1) (1,3) – only 3 possible scenarios for sum to be 4.
From this three cases, only one we have 2. So, the probability is 1 chances out of 3 that the one that occurred had 2: P=1/3.
Answer: A.
Question: A vendor buys 10 t-shirts at an average price of $14 per t-shirt. He then buys 15 more t-shirts at an average price of $11 per t-shirt. What is the average price V per t-shirt that the vendor paid for these purchases?
A.$12.20
B.$12.50
C.$12.55
D.$12.70
Answer: A.$12.20
Explanation: Correct Answer: A
Explanation: The relevant formula for this problem is Average V= (Sum)/(Number of Terms). Another way to look at the formula is Sum = Average x Number of Terms. For the first purchase, the vendor's sum (total cost) was $140, since 14 x 10 = 140. For the second purchase, the vendor's cost was $165, since 11 x 15 = 165. The grand sum is then $140 + $165, which equals $305. The total number of shirts purchased was 25, so to get the average price per shirt, we divide 305 by 25, which equals $12.20. As a result, the correct answer is A.
NOTE: A relative understanding of weighted average offers a shortcut to this problem. Because the true average of 11 and 14 is 12.5, but the vendor sells more shirts at the lower price than at the higher price, the weighted average must be less than $12.50; only answer choice A is a possibility.
Question: A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
A.3
B.5
C.7
D.8
Answer: A.3
Explanation: Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 - 2109) m2 = 291 m2.
Let the width of the road be x metres. Then,
60x + 40x - x2 = 291
x2 - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.
A)
Question: A boat covers a distance of 30 km downstream in 2 hours while it take 6 hours to cover the same distance upstream. If the speed of the current is half of the speed of the boat then what is the speed of the boat in km per hour?
A.15 kmph
B.5 kmph
C.10 kmph
D.Data inadequate
Answer: C.10 kmph
Explanation: Here downstream speed = 15 km/hr and upstream speed = 5 km/hr
∴ Speed of the boat = 15+5/2=10km/h
Answer C
Question: A boat can move upstream at 50 kmph and downstream at 30 kmph, then the speed of the current is?
A.10
B.9
C.5
D.9
Answer: A.10
Explanation: US = 50
DS = 30
M = (50 - 30)/2 = 10
Answer is A
Question: In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100?
A.14
B.61
C.25
D.72
Answer: C.25
Explanation: A scores 60 while B score 40 and C scores 30.
The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.
In a game of 100 points, B gives (100 - 75) = 25 points to C.
Answer:C
Question: Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 56, the three numbers in order are?
A.48,96,24
B.48,24,96
C.96,24,48
D.96,48,24
Answer: B.48,24,96
Explanation: Let the numbers be 2X, X and 4X
Average = (2X + X + 4X)/3
=> 7X/3 = 56
=> X = (3 x 56)/7 = 24
Hence, the numbers in order are 48, 24 and 96
ANSWER:B