RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Two numbers are in the ratio 2 : 3. If eight is added to both the numbers, the ratio becomes 3 : 4. The numbers are ?
A.15 and 20.
B.16 and 24.
C.13 and 17.
D.17 and 9.
Answer: B.16 and 24.
Explanation: Let x and y be the two numbers
Therefore, (x/y) = (2/3),
(x + 8)/(y + 8) = 3/4
=> x = 16, y = 24
ANSWER:B
Question: Employees at a company will vote for an executive team of five people from eight qualified candidates. The executive team consists of a president, a treasurer, and three warrant officers. If an executive team is considered different if any of the same people hold different offices, then how many possible executive teams D could be selected from the eight candidates?
A.56
B.120
C.210
D.1120
Answer: D.1120
Explanation: If an executive team is considered different if any of the same people hold different offices,....
so you will not have answer as 6720..
president could be by any of 8 person..
treasurer could be any out of remaining 7 person..
remaining three order does not matter, so we have to choose 3 out of 6=6c3=20..
total ways D= 8*7*20=1120..
ans D...
Question: If a train, travelling at a speed of 90 kmph, crosses a pole in 5 sec, then the length of train is?
A.177 m
B.125 m
C.188 m
D.178 m
Answer: B.125 m
Explanation: D = 90 * 5/18 * 5
= 125 m
Answer: B
Question: A batsman scored 60 runs which included 2 boundaries and 2 sixes. What percent of his total score did he make by running between the wickets.
A.30%
B.33.33%
C.40%
D.60%
Answer: B.33.33%
Explanation: Explanation:
Number of runs made by running = 60- (2 x 4 + 2 x 6)
= 60 - (20)
= 20
Now, we need to calculate 20 is what percent of 60.
=> 20/60 * 100 = 33.33 %
Option B
Question: The product of two numbers is 2028 and their H.C.F is 13. The number of such pairs is:
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: Let the numbers be 13a and 13b.
Then, 13a * 13b = 2028 => ab = 12.
Now, co-primes with product 12 are (1, 12) and (3, 4).
So, the required numbers are (13 * 1, 13 * 12) and (13 * 3, 13 * 4).
Clearly, there are 2 such pairs.
ANSWER:B
Question: Fom the integer n, if n*n*n is odd, then what is true from below options?
A.n is odd and n*n is even
B.n is odd
C.n*n is odd
D.n is even
Answer: A.n is odd and n*n is even
Explanation: n is odd and n*n is even
Option A
Question: The area of a rectangular plot is 23 times its breadth. If the difference between the length and the breadth is 10 metres, what is its breadth?
A.13 metres
B.5 metres
C.7.5 metres
D.Data inadequate
Answer: A.13 metres
Explanation: L × B = 23 × B
∴ L = 23 m
and L – B = 10
∴ B = 23 – 10 = 13 m
Answer A
Question: 10 camels cost as much as 24 horses, 16 horses cost as much as 4 oxen and 6 oxen as much as 4 elephants. If the cost of 10 elephants is Rs. 170000, find the cost of a camel?
A.3278
B.2669
C.2770
D.Rs.6800
Answer: D.Rs.6800
Explanation: Cost of the camel = P
10 camels = 24 horses
16 horses = 4 oxen
6 oxen = 4 elephants
10 elephants = Rs.170000
P = Rs.[(24 * 4 * 4 * 170000)/(10 * 16 * 6 * 10)]
P = Rs.(65280000/9600) => P = Rs.6800
Answer: D
Question: A gang of 8 boys goes on an tour in 2 cars, of which 1 canseat 5 & the other only 4. In how many ways can they travel?
A.90
B.100
C.126
D.154
Answer: C.126
Explanation: There are 8 students and the maximum capacity of the cars together is 9.
We may divide the 8 students as follows
Case I: 5 students in the first car and 3 in the second
Or Case II: 4 students in the first car and 4 in the second
Hence, in Case I: 8 students are divided into groups of 5 and 3 in8C3 ways.
Similarly, in Case II: 8 students are divided into two groups of 4 and 4 in 8C4ways.
Therefore, the total number of ways in which 8 students can travel is:
\inline {\color{Blue}8C_{3}+8C_{4}}=56 + 70= 126
C
Question: The no. of gift pack bought by Dexter is 1 more than the price, in rupees, of each gift pack. The amount of Rs.380 which Dexter had, fell short of the required amount. What is theamount by which he might have fallen short.
A.Rs 30
B.Rs 40
C.Rs 50
D.Rs 60
Answer: B.Rs 40
Explanation: Let the price of gift pack be 'aa'
Then number of packs bought =a+1=a+1
Hence total cost is a(a+1)a(a+1)
It is given that 380<a(a+1)380<a(a+1)
If a=19a=19, the total cost =19×20=380=19×20=380
Dexter would not have fallen short, If:
a=20a=20, a(a+1)=420a(a+1)=420
So he would have fallen short by Rs 40.
This is the minimum amount by which he may have fallen short.
B)
Question: The simple interest accrued on an amount of Rs.49500 at he end of three is Rs.17820. What would be the compound interest accured on the same amount at teh same rate in the same period? (Round off your answer to two decimal places)?
A.20043.94
B.20043.92
C.20043.98
D.20043.21
Answer: A.20043.94
Explanation: Let the rate of interest be R% p.a.
(49500)(3)(R)/100 = 17820
495R = 5940
R = 12
CI on Rs.49500 at 12% p.a. for three years
= 49500{[1 + 12/100]3 - 1} = 69543.936 - 49500
= Rs.20043.94
when rounded off to two decimal places.
Answer: A
Question: An art gallery has only paintings and sculptures. Currently, 1/3 of the pieces of art are displayed, and 1/6 of the pieces on display are sculptures. If 1/3 of the pieces not on display are paintings, and 400 sculptures are not on display, how many pieces of art does the gallery have?
A.360
B.900
C.540
D.640
Answer: B.900
Explanation: Too many words and redundant info there.
(i) 1/3 of the pieces of art are displayed, hence2/3 of the pieces of art are NOT displayed.
(ii) 1/6 of the pieces on display are sculptures, hence 5/6 of the pieces on display are paintings.
(iii) 1/3 of the pieces NOT on display are paintings, hence2/3 of the pieces NOT on display are sculptures.
400 sculptures are not on display, so according to (iii) 2/3*{not on display} = 400 --> {not on display} = 600.
According to (i) 2/3*{total} = 600 --> {total} = 900.
Answer: B.
Question: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is?
A.6 kmph
B.8 kmph
C.9 kmph
D.10 kmph
Answer: A.6 kmph
Explanation: S = 1
M = x
DS = x + 1
US = x - 1
35/(x + 1) + 35/(x - 1) = 12
x = 6
Answer:A
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
A.50 m
B.150 m
C.200 m
D.data inadequate
Answer: B.150 m
Explanation: Explanation:
Let the length of the train be x metres and its speed be y m/sec.
Then, (x/y)= 15 y =(x/15)
=x+100/25=x/15
=> 15(x + 100) = 25x
=> 15x + 1500 = 25x
=> 1500 = 10x
=> x = 150 m.
Answer: B
Question: There is a work which can be completed by A with 12 days and B by 18 days. A and B works together for 3 days and B left. After that how many days for A to complete the work?
A.4
B.5
C.6
D.7
Answer: D.7
Explanation: work done by A per day=1/12
work done by B per day=1/18
work done by A and B per day=1/12+1/18=5/36
work done by A and B for 3 days=5*3/36=5/12
work remasining=1-5/12=7/12
. After that A takes 7days to complete the work
ANSWER:D
Question: A computer store offers employees a 10% discount off the retail price. If the store purchased a computer from the manufacturer for $800 dollars and marked up the price 10% to the final retail price, how much would an employee save if he purchased the computer at the employee discount (10% off retail price) as opposed to the final retail price.
A.86
B.88
C.90
D.92
Answer: B.88
Explanation: Cost price=800
Profit=10% =10% of 800=80
selling price=CP+ Profit
SP=880
a Discount of 10% to employees means 10% off on 880
so 10% of 880= 88
Ans B
Question: A single discount equivalent to the discount series of 25%, 10% and 5% is?
A.31.6
B.31.0
C.35.875
D.31.1
Answer: C.35.875
Explanation: 100*(75/100)*(90/100)*(95/100)
= 68.4
100 - 64.125 = 35.875
Answer: C
Question: If two painters can complete two rooms in two hours, how many painters would it take to do 18 rooms in 6 hours?
A.8
B.6
C.5
D.4
Answer: B.6
Explanation: Explanation:
Two painters can complete two rooms in two hours.So 18 rooms can be painted in 6 hrs by 6 painters
Answer: B) 6 painters
Question: Find the odd man out. 18, 16, 12, 24, 11, 34, 46
A.16
B.46
C.24
D.11
Answer: D.11
Explanation: Explanation :
11 is the only odd number in the given series
Answer : Option D
Question: The area of a triangle is with base 4m and height 5m?
A.11
B.10 m2
C.88
D.26
Answer: B.10 m2
Explanation: 1/2 * 4 * 5 = 10 m2
Answer: B
Question: The difference between the simple interest received from two different sources on Rs.2000 for 3 years is Rs.13.50. The difference between their rates of interest is
A.0.12%
B.0.22%
C.0.32%
D.0.42%
Answer: B.0.22%
Explanation: (2000xR1x3)/100-(100xR2x3)/100 =13.50
6000(R1-R2)=1350
R1-R2 = 1350/6000=0.22%
answer : B
Question: An urn contains g green marbles and b blue marbles. If 3 green marbles and 6 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn?
A.b+6/(b+g+9)
B.(b+5)/(g+3)
C.(b+5)/(b+g+8)
D.(b+5)/(b+g+3)
Answer: A.b+6/(b+g+9)
Explanation: no of fav outcomes i.e. blue MArbles = b+6
Total no of outcomes i.e. total Marbles = (b+6)+(g+3)= b+g+9
probability = (b+6) /(b+g+9)
Answer A
Question: P is able to do a piece of work in 15 days and Q can do the same work in 20 days. If they can work together for 4 days, what is the fraction of work left?
A.8/15
B.7/15
C.11/15
D.2/11
Answer: A.8/15
Explanation: Explanation :
Amount of work P can do in 1 day = 1/15
Amount of work Q can do in 1 day = 1/20
Amount of work P and Q can do in 1 day = 1/15 + 1/20 = 7/60
Amount of work P and Q can together do in 4 days = 4 Ã— (7/60) = 7/15
Fraction of work left = 1 â€“ 7/15= 8/15
Answer IS A
Question: 12 men can complete a piece of work in 4 days, while 15 women can complete the same work in 4 days. 6 men start working on the job and after working for 2 days, all of them stopped working. How many women should be put on the job to complete the remaining work, if it so to be completed in 3 days?
A.22
B.15
C.66
D.77
Answer: B.15
Explanation: 1 man's 1 day work = 1/48; 1 woman's 1 day work = 1/60.
6 men's 2 day's work = 6/48 * 2 = 1/4.
Remaining work = (1 - 1/4) = 3/4
Now, 1/60 work is done in 1 day by 1 woman.
So, 3/4 work will be done in 3 days by (60 * 3/4 * 1/3) = 15 women.
Answer: B
Question: There are 12 yes or no questions. How many ways can these be answered?
A.1024
B.2048
C.4096
D.144
Answer: C.4096
Explanation: Each of the questions can be answered in 2 ways (yes or no)
Therefore, no. of ways of answering 12 questions = 212 = 4096 ways.
Option C
Question: How many 4-letter word with or without meaning can be formed out of the letters of the word 'LOGARITHMS' if repetition of letters is not allowed
A.7845
B.1278
C.4561
D.5040
Answer: D.5040
Explanation: 'LOGARITHMS' contains 10 different letters
Required number of words
= Number of arrangements of 100 letters taking
4 at a time
= 10P4
= 10 * 9 * 8 * 7
= 5040
Ans: D
Question: A man gains 20% by selling an article for a certain price. If the sells it at double the price, the percentage of profit will be:
A.40
B.100
C.120
D.140
Answer: D.140
Explanation: Let C.P. = Rs. x.
Then, S.P. = Rs. (12% of x) = Rs. 6x/5
New S.P. = 2 * 6x/5 = Rs. 12x/5
Profit = 12x/5 - x = Rs. 7x/5
Profit = 7x/5 * 1/x * 100 = 140%.
ANSWER:D
Question: In a class of 10 students, a group of 4 will be selected for a trip. How many different groups are possible, if 2 of those 10 students are a married couple and will only travel together?
A.98
B.115
C.122
D.126
Answer: A.98
Explanation: We need to break the grouping down to 2 scenarios : with the married couple or without the married couple in the group of 4 people for the trip
1) With the married couple in the group, we have to find the number of possibilities for the other 2 spots in the group from the left 8 people = 8!/(2!*6!) = 28
2) Without the married couple in the group, we have to find the number of possibilities for picking 4 people from the 8 unmarried people from the group = 8!/(4! * 4! ) = 70
Total number of possibilities = 28 + 70 = 98 (A)
Question: Two pipes A and B can fill a tank in 20 and 30 minutes respectively. If both the pipes are used together, then how long will it take to fill the tank?
A.12 min
B.15 min
C.20 min
D.25 min
Answer: A.12 min
Explanation: art filled by A in 1 min. = 1/20
Part filled by B in 1 min. = 1/30
part filled by (A + B) in 1 min. = 1/20 + 1/30 = 1/12.
Both the pipes can fill the tank in 12 minutes.
ANSWER A
Question: Rachel has ribbons that are blue, green, red, orange, and yellow. To identify the plants in her garden, she ties either 1 ribbon, or 2 ribbons of different colors, to each plant. How many different plants can Rachel label in this way without labeling more than one plant the same way?
A.5
B.10
C.15
D.20
Answer: C.15
Explanation: Number of plants identified by one color= 5.
Number of plants identified by a combination of 2 colors= 5C2=105C2=10
Total number = 5+10=15.5+10=15.	ANS:C
Question: Which of the following equations represents a line that is perpendicular to the line described by the equation 4x + 3y = 9?
A.3x + 4y = 18
B.3x – 4y = 24
C.5y – 3x = 26
D.1.5y + 2x = 18
Answer: B.3x – 4y = 24
Explanation: Perpendicular lines have slopes which are negative reciprocals of each other.
The line 4x + 3y = 9 in slope-intercept form is y = -(4/3)x + 3
The slope of this line is -4/3.
The slope of a perpendicular line is 3/4.
3x - 4y = 24 in slope-intercept form is y = (3/4)x - 6
The answer is B.
Question: at a special sale 5 ticket can be purchased as a price of 3 ticket, if 5 ticket are purchased at the sale, the amount saved will be what % of the original price of the 5 ticket.
A.10%
B.20%
C.30%
D.40%
Answer: D.40%
Explanation: let the price of 1 ticket be Rs.10
Original C.P. of 5 tickets = Rs.50
After sale 5 Tickets were bought for Rs. 30
%amount saved = ((50-30)/50)*100 = 40%
ANSWER:D
Question: If x is equal to the sum of the integers from 40 to 50, inclusive, and y is the number of EVEN integers from 40 to 50, inclusive, what is the value of x+y ?
A.171
B.281
C.391
D.501
Answer: D.501
Explanation: sum s= n/2{2a+(n-1)d} = 11/2{2*40+ (11-1)*1} =11*45=495 =X
number of even number =( 50-40)/2 +1 = 6= Y
X+Y = 495+6 =501
D
Question: Sumit and Ravi started a business by investing Rs 85000 and 15000 respectively. In what ratio the profit earned after 2 years be divided between Sumit and Ravi respectively.
A.17:1
B.17:2
C.17:3
D.17:4
Answer: C.17:3
Explanation: Explanation:
Note: If you have clear concept of ratio and proportion chapter then it will really easy for you to solve partnership problems.
P:Q = 85000:15000 = 17:3
Important to note there that if both have invested for different period of times then we had to multiply with number of months to get the desired ratio.
Option C
Question: Find the average of all the numbers between 6 and 34 which are divisible by 5.
A.15
B.18
C.20
D.22
Answer: C.20
Explanation: Sol.
Average = (10 + 15 + 20 + 25 + 30 / 5) = 100 / 5 = 20.
Answer C
Question: Find the total number of prime factors in the expression (4)11 x (7)5 x (11)2.
A.27
B.28
C.29
D.30
Answer: C.29
Explanation: (4)11x (7)5 x (11)2 = (2 x 2)11 x (7)5 x (11)2 = 211 x 211 x75x 112 = 222 x 75 x112
Total number of prime factors = (22 + 5 + 2) = 29.
ANSWER C 29
Question: Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 44 hours. If one additional machine were used under the same operating conditions, in how manyfewerhours of simultaneous operation could the production order be fulfilled?
A.6
B.9
C.12
D.11
Answer: D.11
Explanation: If 3 Machines can do the work in 44 hr then 4 Machines can do the work in 3/4*44 = 33 Hrs. hence time saved will be 11hr
option D is the correct answer
Question: On flipping 3 coins together what is the outcomes for at least four tail?
A.1/7
B.0
C.1
D.4/13
Answer: B.0
Explanation: Sample space, S = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}
Favorable outcomes for at least two heads
= favorable outcomes for exactly two heads and favorable outcomes for more than two heads
= {0}
0
B
Question: In 1970 there were 8,902 women stockbrokers in the United States. By 1978 the number had increased to 22,947. Approximately what was the percent increase?
A. 45%
B. 125%
C. 145%
D. 158%
Answer: D. 158%
Explanation: The percent increase is (22947-8902)/8902=14045/8902=1.58
So the approximate answer is D
Question: (112% of 2348) ÷ 4.98 = ?
A.505
B.515
C.525
D.538
Answer: C.525
Explanation: Explanation :
? = (112x2348/100) ÷ 5
= 2630/5 = 526 = 525
Answer : Option C
Question: P can do a work in 24 days. Q can do the same work in 9 days and R can do the same in 12 days. Q and R start the work and leave after 3 days. P finishes the remaining work in --- days.
A.5
B.7
C.10
D.16
Answer: C.10
Explanation: Work done by P in 1 day = 1/24
Work done by Q in 1 day = 1/9
Work done by R in 1 day = 1/12
Work done by Q and R in 1 day = 1/9 + 1/12 = 7/36
Work done by Q and R in 3 days = 3×7/36 = 7/12
Remaining work = 1 – 7/12 = 5/12
Number of days in which P can finish the remaining work = (5/12) / (1/24) = 10
Answer is C.
Question: 12 year old Manick is three times as old as his brother Rahul. How old will Manick be when he is twice as old as Rahul ?
A.16
B.27
C.21
D.10
Answer: A.16
Explanation: Manick's present age = 12 years, Rahul's present age = 4 years.
Let Manick be twice as old as Rahul after x years from now.
Then, 12 + x = 2 (4 + x) 12 + x = 8 + 2x x = 4.
Hence, Manick's required age = 12 + x = 16 years.
Answer: A
Question: If A, B and C together can finish a piece of work in 4 days. A alone in 12 days and B in 18 days, then C alone can do it in?
A.8
B.6
C.5
D.9
Answer: D.9
Explanation: C = 1/4 - 1/12 – 1/18 = 1/9 => 9 days
Answer: D
Question: In a certain company 20% of the men and 40% of the women attended the annual company picnic.If 55% of all the employees are men .What % of all the employee went to the picnic?
A.29%
B.34%
C.35%
D.36%
Answer: A.29%
Explanation: total men in company 55% means total women in company 45%(assume total people in company 100%)
no of men employees attended picnic=55x(20/100)=11
no of women employees attend picnic=45x(40/100)=18
total percentage of employees attend the picnic=11+18=29%
ANSWER:A
Question: If p and r are positive integers such that (p2)/40=r(p2)/40=r, and p=/=r, then which of the following must also be an integer?
I. r/5r/5
II. r/(2x5)r/(2x5)
III. r/(3x5)r/(3x5)
A.I only
B.II only
C.I and II only
D.I and III only
Answer: C.I and II only
Explanation: (p^2)/40 = r;
p^2 = 40r = 2^3*5r.
2^3*5r equals to the square of an integer (p^2), thus r should complete the powers 2^3 and 5 to the even number, thus the least value of r is 2*5 (in this case p^2 = 2^3*5r = 2^4*5^2). So, r/5 and r/(2*5) must be also be integer.
Answer: C.
Question: A car covers a distance of 840 km in 8 hours. Find its speed?
A.104 kmph
B.105 kmph
C.288 kmph
D.277 kmph
Answer: B.105 kmph
Explanation: 840/8
= 105 kmph
Answer: B
Question: A cistern has three pipes,A, B and C. The pipes A and B can fill it in 8 and 12 hours respectively and C can empty it in 6 hours. If the pipes are opened in order at 1, 2 and 3 A.M. When will the cistern be empty?
A.9 AM
B.12 AM
C.8 AM
D.11 AM
Answer: D.11 AM
Explanation: 1 to 2 = 1/8
2 to 3 = 1/8 + 1/12 = 5/24
After 3 AM = 1/8 + 1/12 - 1/6 = 1/24
1/8 + 5/24 = 1/3
1 h ---- 1/24
? ----- 1/3
8 hours ==> 11 AM
Answer:D
Question: Sandy is younger than Molly by 18 years. If the ratio of their ages is 7:9, how old is Sandy?
A.42
B.49
C.56
D.63
Answer: D.63
Explanation: Let Sandy's age be 7x and let Molly's age be 9x.
9x - 7x = 18
x = 9
Sandy is 63 years old.
The answer is D.
Question: Two Guys A and B leave point A and point B simultaneously and travel towards Point B and Point A on the same route at their respective constant speeds. They meet along the route and immediately proceed to their respective destinations in 32 minutes and 50 minutes respectively. How long will B take to cover the entire journey between Point B and point A?
A.65
B.90
C.70
D.75
Answer: B.90
Explanation: Let x per minute be the speed of A and y per minute be the speed of B.
After meeting at a point, A travels for 32 mins and B travels for 50 mins. So distance covered by each of them post point of crossing
A= 32x and B=50y
The distance covered by A and B before they cross each would be distance covered by B and A post crossing respectively.
Therefore distance covered by B before he meets A= 32x
Time taken by B cover 32x distance= 32x/y mins
Therefore total time taken by B= 32x/y + 50 mins ................. I
We need to find value of x in terms of y to arrive at final answer.
Total distance= 32x+50y
Combined speed of A and B= x+y
Therefore time taken before A and B meet en-route= (32x+50y)/(x+y)
Time taken by B reach destination after meeting A= 50 mins
Total travel time for B= [(32x+50y)/(x+y)]+50 mins ...................II
Equate I and II
32x/y+50= [(32x+50y)/(x+y)]+50
(32x+50y)/y=(82x+100y)/(x+y)
32x^2+50xy+32xy+50y^2=82xy+100y^2
32x^2+82xy-82xy+50y^2-100y^2=0
32x^2-50y^2=0
32x^2=50y^2
16x^2=25y^2
Taking square root.. (since x and y denote speed, square root can't be negative)
4x=5y
y=4x/5 ............ III
substitute in I
=32x/(4x/5) + 50
=32x*5/4x + 50
=40+50
=90 mins
B
Question: A trader marks his books 20% more than the cost price. If he allows 20% discount, then find his gain or loss percent?
A.2% profit
B.2% loss
C.4% loss
D.No profit No loss
Answer: C.4% loss
Explanation: C
Let CP of an book = $100
MP= $120
Discount = 20%
SP = M[(100 - d%)/100] = 120(80/100) = $96
Clearly, the trader gets 4% loss.
Question: What is the median of a set of consecutive integers if the sum of nth number from the beginning and nth number from the end is 50?
A.10
B.25
C.50
D.75
Answer: B.25
Explanation: Surprisingly no one answered this easy one.
property of a set of consecutive integerz.
mean=median=(first element+last element)/2 = (second element+last but one element)/2 =(third element+ third last element)/2 Etc. Etc.
So mean=median=50/2=25
Answer is B
Question: In the annual Cultural Programme of indra prastha there was this Math Quiz going on.yudhisthir faced this last question that will bring the champion's trophy. What will be thesolution for the given problem?The function f is defined is defined asf(2x+3)= (x-3)(x+4)What is f(29)?
A.200
B.230
C.140
D.170
Answer: D.170
Explanation: Explanation :
f(2x+3)= (x-3)(x+4)put x=13f(2*13+3)=(13-3)*(13+4)=10*17f(29)=170
Answer : D
Question: The cost of an article was Rs.75. The cost was first increased by 20% and later on it was reduced by 20%. The present cost of the article is:
A.Rs. 72
B.Rs. 60
C.Rs. 75
D.Rs. 76
Answer: A.Rs. 72
Explanation: Solution: Initial Cost = Rs. 75
After 20% increase in the cost, it becomes,
(75+ 20% of 75) = Rs. 90
Now, Cost is decreased by 20%, So cost will become,
(90 - 20% of 90) = Rs. 72.
So, present cost is Rs. 72.
Mind Calculation Method: 75-----20%↑--→90-----20%↓-----→72.
Answer: Option A
Question: The probability of having a girl is identical to the probability of having a boy. In a family with two children, what is the probability that all the children are of the same gender?
A.1/2
B.1/16
C.1/9
D.1/4
Answer: A.1/2
Explanation: There are two cases. All boys and all girls.
case 1. all boys.
1/2*1/2= 1/4
case 2 .all girls.
1/2*1/2=1/4
We will add the cases to get 1/2
Question: The C.P of 15 books is equal to the S.P of 18 books. Find his gain% or loss%?
A.16 2/3%
B.16 2/8%
C.16 2/5%
D.16 2/1%
Answer: A.16 2/3%
Explanation: 15 CP = 18 SP
18 --- 3 CP loss
100 --- ? => 16 2/3% loss.Answer: A
Question: Paul sold an item for Rs.3600/- and incurred a loss of 40%. At what price should he have sold the item to have gained a profit of 40%?
A.8000
B.8200
C.8400
D.8600
Answer: C.8400
Explanation: Explanation:
40% loss means SP = 60% of CP
:. CP = Rs.3600x100/60 = Rs.6000.
The SP for a gain of 40% = 6000+40% of 6000 = 6000+2400 =Rs8400.
Answer: Option C
Question: There are 200 cats in Cat-City. Out of the 200, 70 are street cats and the rest are domestic cats. 110 cats are gray, 40 out of the gray cats are NOT domestic ones. How many domestic cats are there which are not gray in Cat-City?
A.90.
B.80.
C.60.
D.40.
Answer: C.60.
Explanation: STREET-CAT DOMESTIC-Cat
70 130
(40gray+30other) 70gray+60other
Answer:C