RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A , B , and C started a partnership business by investing $45,000 , $63,000 , and $72,000 respectively. At the end of the year, the profit was distributed among them. If C's share of profit is $24,000, what is the total profit?
A.$48,000
B.$52,000
C.$56,000
D.$60,000
Answer: D.$60,000
Explanation: A:B:C = 45000:63000:72000 which is a ratio of 5:7:8.
Let the total profit be x.
x * 8/20 = 24000
x = 24000*20/8 = 60,000.
The answer is D.
Question: At garage sale, all of the prices of the items sold were different. If the price of a radio sold at the garage sale was both the 15th highest price and the 25th lowest price among the prices of the items sold, how many items were sold at the garage sale?
A.33
B.34
C.35
D.39
Answer: D.39
Explanation: 14+24+1= 39
Answer: D
Question: A 4 digit number 8a43 is added to another 4 digit number 3121 to give a 5 digit number 11b64, which is divisible by 11, then (a+b)=?
A.3
B.4
C.7
D.5
Answer: A.3
Explanation: Solution: a+1=b
=> b-a=1.
and 11b64 is divisible by 11
=> (4+b+1)-(6+1)=0
=> b-2=0
=> b=2.
so, a=1
=>(a+b)= 3.
Answer A
Question: A man can row 30 km downstream and 20 km upstream in 4 hours. He can row 45 km downstream and 40 km upstream in 7 hours. Find the speed of man in still water?
A.12.8 kmph
B.23.9 kmph
C.21.9 kmph
D.12.5 kmph
Answer: D.12.5 kmph
Explanation: Let the speed of the man in still water be a kmph and let the speed of the stream be b kmph.
Now 30/(a + b) + 20/(a - b) = 4 and 45/(a + b) + 40/(a - b)
= 7
Solving the equation, the speed of man in still water is
12.5 kmph.
Answer: D
Question: A women has 3 purse and 4 paper. In how many ways can he put the paper in her purse?
A.78
B.80
C.81
D.82
Answer: C.81
Explanation: First paper can be put in 3 ways, similarly second, third and forth paper also can be put in 3 ways.
So total number of ways = 3 x 3 x 3 x 3 = 34 = 81
C
Question: 19 persons went to a hotel for a combined dinner party. 13 of them spent Rs 79 each for the dinner and the rest spent Rs 4 more than the average expenditure of all the 19. What was the total money spent by them?
A.Rs1628.40
B.Rs1536
C.Rs1492
D.Rs1498
Answer: B.Rs1536
Explanation: (13*79)+(6(x+4)) = 19x
1027 + 6x + 24 = 19x
1051 = 13x
x = 1051/13
total money = 19x = 1536
ANSWER:B
Question: If 10 gallons of grape juice are added to 50 gallons of a mixture, which contains 10 percent grape juice then what percent of the resulting mixture is grape juice?
A.14%
B.25%
C.28%
D.34%
Answer: B.25%
Explanation: OFFICIAL SOLUTION:
If we start with 40 gallons of a mixture that is 10% grape juice, then we have:
50 × 0.10 = 5 gallons of grape juice.
50 × 0.90 = 45 gallons of other components.
If we add 10 gallons of grape juice, we will end up with 15 gallons of grape juice and 45 gallons of other components, and we will have a total of 60 gallons of the mixture.
So 15/60 of the new mixture is grape juice. Now we convert this to a percent:Percent Grape Juice = 25/100= 25%.
The correct answer is choice (B)
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 10 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
A.40
B.44
C.48
D.55
Answer: D.55
Explanation: Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 10)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 10 = 4/9(T - 10)
10T = 990 - 440 => T = 55.
ANSWER:D
Question: The average age of a group of 5 members is 20 years. Two years later, a new member joins the group. The average age of the group becomes 25 years. What is the age of the new member ?
A.20 years
B.21 years
C.40 years
D.23 years
Answer: C.40 years
Explanation: The average age of a group of 5 members is 20 years --> the sum of the ages is 5*20=100;
Two years laterthe sum of the ages of these 5 members would be 100+5*2=110;
Now, say the age of the new member is x years, so the sum of the ages of a new 6 member group is 110+x. Since given that the average age of this group of 6 members is 25 years then: 25*6=110+x --> x=40.
Answer: C.
Question: A student needed to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and x. He found the mean to be 12. What is the value of x?
A.5
B.4
C.3
D.7
Answer: D.7
Explanation: 3+11+7+9+15+13+8+19+17+21+14+x/12=12
137+x/12=12
137+x=144
x=144-137=7
Option D
Question: Every year an amount increases by 1/9th of itself. How much will it be after two years if its present value is Rs.64000?
A.81000
B.81007
C.81008
D.79012.3
Answer: D.79012.3
Explanation: 64000* 10/9 * 10/9 = 79012.3
Answer:D
Question: certain office 1/3 of the workers are women ½ of the women are married and 1/3 of the married women have children if ¾ of the men are married and 2/3 of the married men have children what part of workers are without children?
A.11/8 of all workers
B.1/18 of all workers
C.11/18 of all workers
D.13/18 of all workers
Answer: C.11/18 of all workers
Explanation: Let the total no of workers be x
No of women =x/3
No of men =x-(x/3)=2x/3
No of women having children =1/3 of ½ ofx/3=x/18
No of men having children=2/3 of ¾ of2x/3=x/3
No of workers having children = x/8 +x/3=7x/18
Workers having no children=x-7x/18=11x/18=11/18 of all workers
Option C is answer
Question: A tyre has two punctures. The first puncture alone would have made the tyre flat in 12 minutes and the second alone would have done it in 8 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat ?
A.4 4/5min
B.3 2/5min
C.3 3/5min
D.3 4/5min
Answer: A.4 4/5min
Explanation: Explanation:
Do not be confused, Take this question same as that of work done question's. Like work done by 1st puncture in 1 minute and by second in 1 minute.
Lets Solve it:
1 minute work done by both the punctures =
(1/12+1/8)=(5/24)
So both punctures will make the type flat in
(24/5)mins=4 4/5mins
Option A
Question: (0.96)(power 3) - (0.1)(power 3)/ (0.96)(power 2) + 0.096 + (0.1)(power 2) is:
A.0.86
B.0.68
C.0.96
D.0.69
Answer: A.0.86
Explanation: Given expression
= (0.96) (power 3) - (0.1)(power 3) / (0.96)(power 2) + (0.96 x 0.1) + (0.1)(power 2)
= a (power 3) - b(power 3) / a(power 2) + ab + b(power 2)
= (a - b)
= (0.96 - 0.1)
= 0.86
Answer is A.
Question: What is the value of the following expression?
(1/ (2^2 – 1)) + (1/ (4^2 – 1)) + (1/ (6^2 – 1)) + .... + (1/ (18^2 – 1))
A.a. 9/19
B.b. 10/19
C.c. 10/21
D.d. 11/21
Answer: A.a. 9/19
Explanation: it can be written into
1/3+1/15+ 1/35.....1/323
i.e
1/3+1/2*(1/3-1/5)+1/2*(1/5-1/7).... til last term - 1/2*(1/19)
all terms from 1/5 .. to second last term get cancelled
left with
1/3+1/6-1/42=1/2-1/38=18/38=9/19
A
Question: Shannon and Maxine work in the same building and leave work at the same time. Shannon lives due north of work and Maxine lives due south. The distance between Maxine's house and Shannon's house is 60 miles. If they both drive home at the rate 2R miles per hour, Maxine arrives home 30 minutes after Shannon. If Maxine rider her bike home at the rate of R per hour and Shannon still drives at a rate of 2R miles per hour, Shannon arrives home 2 hours before Maxine. How far does maxine live from work?
A.20
B.34
C.30
D.40
Answer: C.30
Explanation: Nice question +1
We have that X/24 - (60-X)/2R = 30
Also X/R - (60-X)/2R = 120
So we get that 2x - 60 = 80R
3x - 60 = 240R
Get rid of R
120 = 3x
x = 30
Hence answer is C
Question: At what rate percent on simple interest will Rs.750 amount to Rs.900 in 10 years?
A.6%
B.2%
C.4%
D.5%
Answer: B.2%
Explanation: 150 = (750*10*R)/100
R = 2%
Answer: B
Question: A and B go around a circular track of length 900m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point?
A.120 sec
B.165 sec
C.186 sec
D.180 sec
Answer: D.180 sec
Explanation: Time taken to meet for the first time at the starting point
= LCM { length of the track / speed of A , length of the track / speed of B}
= LCM { 900/ (36 * 5/18) , 900/ (54 * 5 /18) }
= LCM (90, 60)
=180 sec.
Answer:D
Question: There are 200 female managers in a certain company. Find the total number T of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers.
A.300
B.T=400
C.T=500
D.600
Answer: C.T=500
Explanation: {Managers} = {Female Managers} + {Male Managers};
We are told that the total number of managers in the company is 2/5 of all the employees , thus {Managers} = 2/5 (M + F), where M and F are number of female and male employees, respectively.
Also, we know that 2/5 of all male employees are managers:{Male Managers} = 2/5 * Mas well as there are total of 200 female managers:{Female Managers} = 200;
Thus:2/5 (M + F) = 200 + 2/5 * M-->F = 500.
Answer: C.
Question: The ratio of the earnings of P and Q is 9:10. If the earnings of P increases by one-fourth and the earnings of Q decreases by one-fourth, then find the new ratio of their earnings?
A.2/9
B.3/2
C.3/8
D.3/4
Answer: B.3/2
Explanation: Let the earnings of P and Q be 9x and 10x respectively.
New ratio = [9x + 1/4 (9x)]/[10x - 1/4 (10x)]
=> 9*(1 + 1/4)/10*(1 - 1/4)
=> 9/10 * (5/4)/(3/4) = 3/2
Answer:B
Question: If (3/2)x - 3 = 15
what is the value of x ?
A.-12
B.12
C.-1/12
D.1/12
Answer: B.12
Explanation: (3/2)x - 3 = 15
=> 3x-6=30
=>3x = 36
=> x=12
Answer: B
Question: Robex traveled a distance of 30 km, covering the first 10 km in x minutes, the next 10 km in y minutes and the last 10 km in z minutes. If he totally took 3y minutes to cover the whole distance, then which of the following cannot be true? Assume x , y and z are different.
A.z=3x
B.x=3z
C.y=2x
D.x=2y
Answer: D.x=2y
Explanation: Robex Travelled for x,y and for z min.
Total Time : x + y + z
Which is equal to : 3y
Equating both sides we get
x+y+z = 3y
=> x+z =2y ........ Eqn 1
Looking out at options
D Says x =2y
Using it in Eqn 1
2y + z = 2y
=> Z = 0 mins, Which I guess is not possible.
The Ans isD
Question: The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?
A.275
B.270
C.279
D.263
Answer: B.270
Explanation: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Smaller number = 270.
Answer is B.
Question: If 20% of a = b, then b% of 20 is the same as:
A.4% of a
B.5% of a
C.20% of a
D.30% of a
Answer: A.4% of a
Explanation: Explanation:
20% of a = b =	(20/100)a=b.
b% of 20 =(b/100 x 20)=((20/100)a x 1/100 x 20)=(4/100)a=4% of a.
ANSWER IS A
Question: Calculate how long it will take a swimmer to swim a distance of 12km against the current of a river which flows at 1.2 km/hr, given that he can swim in still water at 5km/h
A.3.26
B.3.16
C.2.34
D.3.98
Answer: B.3.16
Explanation: swim in still water at = 5
speed of river= 1.2
US = 5 - 1.2= 3.8
Distance = 12
T = 12/3.8 = 3.16
Answer: B
Question: A train running at 1/6 of its own speed reached a place in 24 hours. How much time could be saved if the train would have run at its own speed?
A.8hrs
B.20hrs
C.12hrs
D.15hrs
Answer: B.20hrs
Explanation: time taken if run its own speed = 1/6*24 = 4 hrs
Time saved = 24 - 4 = 20 hrs
Answer : B
Question: An article is bought for Rs.675 and sold for Rs.1000, find the gain percent?
A.34%
B.44%
C.48%
D.32%
Answer: C.48%
Explanation: 675 ---- 325
100 ---- ? =>
=48%
Answer:C
Question: The salaries of A and B together amount to $6000. A spends 95% of his salary and B, 85% of his. If now, their savings are the same, what is A's salary?
A.$1000
B.$1250
C.$2500
D.$4500
Answer: D.$4500
Explanation: Let A's salary is x
B's salary = 6000-x
(100-95)% of x = (100-85)% of (6000-x)
x = $4500
Answer is D
Question: There is a 30% increase in the price of an article in the first year, a 20% decrease in the second year and a 10% increase in the next year. If the final price of the article is Rs. 2288, then what was the price of the article initially?
A.Rs.2008
B.Rs.2022
C.Rs.2000
D.Rs.2029
Answer: C.Rs.2000
Explanation: Let the price of the article, four years age be Rs. 100 in the 1st year, price of the article = 100 + 30 = Rs. 130. In the 2nd year, price = 130 - 20% of 130 = 130 - 26 = Rs. 104.
In the 3rd year, price = 104 + 10% of 104 = 104 + 10.4 = Rs. 114.40.
But present price of the article is Rs. 2288
for 114.4 ---> 100 ; 2288 ---> ?
Required price = (2288 * 100)/114.4 = 20 * 100 = Rs.2000.
Answer:C
Question: which one is odd?
4377
3954
9861
8454
9831
A.4377
B.3954
C.9861
D.8454
Answer: C.9861
Explanation: Correct Answer : C
sum of digit of all other number is 21, but sum of digit of 9861 is 24
Question: The product of two natural numbers is 19. The sum of the reciprocal of its square is
A.361/362
B.362/361
C.360/359
D.359/360
Answer: B.362/361
Explanation: Explanation:
Let the number be a and b. Then,
ab = 19 => a = 1, b = 19
So, 1/a2 + 1/b2 = (a2 + b2)/a2b2
= (12 + 192)/(1 x 19)2 = 362/361
Answer: Option B
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 30 metres?
A.22 seconds
B.6 seconds
C.7 seconds
D.1 seconds
Answer: B.6 seconds
Explanation: Speed of the boat downstream
= 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m
= 30/5 = 6 seconds.
Answer:B
Question: Find the odd man out. 23, 27, 36, 52, 77, 111, 162
A.111
B.162
C.52
D.27
Answer: A.111
Explanation: 23 + 22 = 27
27 + 32 = 36
36 + 42 = 52
52 + 52 = 77
77 + 62 = 113
113 + 72 = 162
Hence, 113 should have come in place of 111Answer is A
Question: Jaclyn buys $50 000 worth of debentures in a company. She earns 9.5% p.a. simple interest, paid to her quarterly (that is, every 3 months). If the agreed period of the debenture was 18 months: calculate the amount of interest Jaclyn will earn for each quarter
A.1187.5
B.1234
C.1289
D.1345
Answer: A.1187.5
Explanation: Explanation:
I=(p x r x t)/100
Answer: A
Question: If A = x% of y and B = y% of x, then which of the following is true?
A.A is smaller than B.
B.Relationship between A and B cannot be determined
C.If x is smaller than y, then A is greater than B.
D.None of these
Answer: D.None of these
Explanation: Explanation:
A = (x/100)y = (xy/100).................(Equation 1)
B = (y/100)x = (yx/100).................(Equation 2)
From these equations, it is clear that A = B
Answer: Option D
Question: The number of arrangements that can be made with the letters of the word MEAUDOWS so that the vowels occupy the odd places?
A.A)522
B.B)534
C.C)576
D.D)656
Answer: C.C)576
Explanation: Explanation:
The word MEAUDOWS has 8 letters of which 4 are vowels.
V-V-V-V-
As the vowels have to occupy odd places, they can be arranged in the 4 odd places in 4! i.e., 24 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways.
Hence the total ways are 24 * 24 = 576.
C)
Question: A scientist used a unique two-color code to identify each of the test subjects involved in a certain study. If the scientist found that choosing from among eight colors produced enough color codes to identify all but 5 of the test subjects, how many test subjects were in the study? (Assume that the order of the colors in the codes does not matter.)
A.32
B.33
C.34
D.35
Answer: B.33
Explanation: 8C2 = 28
The number of test subjects is 28 + 5 = 33
The answer is B.
Question: A monk has a very specific ritual for climbing up the steps to the temple. First he climbs up to the middle step and meditates for 1 minute. Then he climbs up 8 steps and faces east until he hears a bird singing. Then he walks down 12 steps and picks up a pebble. He takes one step up and tosses the pebble over his left shoulder. Now, he walks up the remaining steps three at a time which only takes him 9 paces.
How many steps are there?
A.50 steps
B.49 steps
C.44 steps
D.35 steps
Answer: B.49 steps
Explanation: B
There are 49 steps.
He hears the bird singing on step 33. He picks up the pebble on the 21st step and tosses it on the 22nd step. The remaining 27 steps are taken three at a time which is 9 pac
Question: Roberto has three children: two girls and a boy. All were born on the same date in different years. The sum of the ages of the two girls today is smaller than the age of the boy today, but a year from now the sum of the ages of the girls will equal the age of the boy. Three years from today, the difference between the age of the boy and the combined ages of the girls will be
A.1
B.2
C.3
D.–2
Answer: D.–2
Explanation: girl1: g1, girl2: g2, boy:b, these are the symbols for their ages today.
g1+g2<b
(1 year from now): (g1+1)+(g2+1) = b+1 ; g1+g2 = b-1
The difference between the girls's age and the boy's age is one today:
Assume ages, g1:20, g2:25, b:46 (notice the difference is currently 1); in 3 years the ages will be g1:23, g2:28, b:49 ; 49-(23+28) = -2
The Answer should be D.
Question: The average score of a cricketer in 2 matches is 20 and in other 3 matches is 30. Then find the average score in all the 5 matches?
A.26
B.27
C.30
D.35
Answer: A.26
Explanation: Average in 5 matches = (2*20 + 3*30)/2+3 = 40+90 / 5 = 130/5 = 26
Answer is A
Question: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey ?
A.1 kmph
B.5 kmph
C.6 kmph
D.4 kmph
Answer: D.4 kmph
Explanation: Explanation:
Speed of Man = 4.5 kmph
Speed of stream = 1.5 kmph
Speed in DownStream = 6 kmph
Speed in UpStream = 3 kmph
Average Speed = (2 x 6 x 3)/9 = 4 kmph.
Answer: D
Question: A die is rolled twice. What is the probability of getting a sum equal to 9?
A.2/3
B.2/9
C.1/3
D.1/9
Answer: D.1/9
Explanation: Explanation :
Total number of outcomes possible when a die is rolled = 6 (âˆµ any one face out of the 6 faces)
Hence, total number of outcomes possible when a die is rolled twice, n(S) = 6 Ã— 6 = 36
E = Getting a sum of 9 when the two dice fall = {(3, 6), {4, 5}, {5, 4}, (6, 3)}
Hence, n(E) = 4
P(E) = n(E)/n(S)=4/36=1/9
ANSWER IS D
Question: Bob invested $2000 in fund A and $1000 in fund B. Over the next two years, the money in Fund A earned a total interest of 12 percent for the two years combined and the money in fund B earned 30 percent annual interest compounded annually. Two years after bob made these investments. Bob's investment in fund A was worth how much more than his investment in fund B?
A.$500
B.$550
C.$600
D.$650
Answer: B.$550
Explanation: Bob earned 2000*(1+0.12) in total by fund A and earned 1000*(1+0.3)^2 in total by fund B.
So 2000*(1.12) - 1000*(1.69)= 550.
The answer is, therefore, (B).
Question: Four persons enter the lift of a seven storey building at the ground floor. In how many ways can they get out of lift on any floor other than ground floor
A.720
B.1296
C.1540
D.1478
Answer: B.1296
Explanation: Each person out of 4 has 6 floors (options) to get out of (since no one gets out on the ground floor), hence total ways is 6*6*6*6=6^4. Now, there is no need to actually calculate this value: 6^4 will have 6 as the units digit and there is only one option (B)
Answer: B.
Question: For any positive integer r, the sum of the first r positive integers equals r(r+1)/2 . If s and r are positive integers and s > r, what is the sum of all the integers between s and r, inclusive?
A. s(s+1)/2 + r(r+1)/2
B. s(s+1)/2 - r(r-1)/2
C. s(s+1)/2 - r(r+1)/2
D. s(s+1)/2 + r(r-1)/2
Answer: B. s(s+1)/2 - r(r-1)/2
Explanation: The sum of all the integers between s and r,inclusiveis the sum of the first s positive integersminusthe sum of the first r-1 positive integers.
The sum of the first s positive integers is s(s+1)/2;
The sum of the first r-1 positive integers is (r-1)r/2;
Therefore the answer is s(s+1)/2 - (r-1)r/2.
Answer: B.
Question: 24 machines can do a work in 10days. How many machines are needed to complete the work in 40days?
A.10
B.6
C.4
D.7
Answer: B.6
Explanation: Required number of machines = 24*10/40 = 6
Answer is B
Question: Firm A's revenues are described by the equation Ra = 17.12x and its costs by Ca = 12.87x + 2400.
Firm B's revenues are described by the equation Rb = 13.27x and its costs by Cb = 8.77x + 1500.
(x denotes the quantity of sales).
If A's volume of sales increases from 1000 to 2000 over the same period that B's volume increases from 2000 to 4000, the percent increase in profits for the firm with the biggest dollar increase in profits is
A.20%
B.30%
C.60%
D.50%
Answer: B.30%
Explanation: Ok, I do not know whether it is exactly what you want to hear but I did it that way: first look at difference between revenue and variable cost => take the bigger one (b) which gives you: 4.5x-1500 just plug in 2000 and 3000. you get 7500 and 12000 (difference 4500). 4500> 0.5*7500 so 30%
B
Question: Which of the following expressions CAN be equal to 0 when x^2 − x = 6 ?
A.x^2 − 3x +2
B.x^2 − 2x -4
C.x^2 − 5x +5
D.x^2 − 3x +1
Answer: A.x^2 − 3x +2
Explanation: x^2 − x = 6
x^2 − x - 6= 0
x=3 or x=-2
Only one choice results in a possibility of 0 when you plug in 3 or -2 for x except rest of all
x^2 − 3x + 2
Answer is A
Question: How many ltrs of water must beadded to 16 ltrs of milk and water containing 10% water to make it 20% water in it?
A.1 liter
B.2 liter
C.3 liter
D.4 liter
Answer: B.2 liter
Explanation: By rule of alligation,
% Concentration
of water in pure water (100) % Concentration
of water in the given mixture (10)
Mean % concentration
(20)
20 - 10 = 10 100 - 20 = 80
=> Quantity of water : Quantity of the mixture = 10 : 80 = 1 : 8
Here quantity of the mixture = 16 litres
=> Quantity of water : 16 = 1 : 8
=> Quantity of water =16×18=2 liter
B
Question: A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 28 years now, the son's age five years back was:
A.9 years
B.4 years
C.33 years
D.8 years
Answer: B.4 years
Explanation: Let the son's present age be x years.
Then, (28 - x) = x
2x = 28 => x = 14
Son's age 5 years back = (14 - 5) = 9 years.
ANSWER:B
Question: What Approximate Values should comein place of the question mark (?) in each of the following equations ?
85% of 225 + 56% of 450 + 32.98 x 5.001 = ?
A.600
B.625
C.608
D.605
Answer: C.608
Explanation: Explanation :
85x225/100+56x450/100+33x5 = 85 x 2.25 + 56 x 4.5 + 165 = 608
Answer : Option C
Question: Two concentric circles form a ring. The inner and outer circumferences of ring are (352/7) m and (518/7) m respectively. Find the width of the ring.
A.2
B.4
C.6
D.8
Answer: B.4
Explanation: Let the inner and outer radii be r and R meters.
Then 2(22/7)r = (352/7) = r =((352/7) X (7/22) X (1/2))=8m.
2(22/7)R=(528/7) = R=((528/7) X (7/22) X (1/2))= 12m.
Therefore, Width of the ring = (R - r) = (12 - 8) m = 4 m.
Answer is B.
Question: In the x-y plane, the area of the region bounded by the graph of |x+y| + |x-y| = 2 is
A.1
B.12
C.16
D.20
Answer: A.1
Explanation: I've never seen such kind of question in GMAT before.
OK there can be 4 cases:
|x+y| + |x-y| = 2
A. x+y+x-y = 2 --> x=1
B. x+y-x+y = 2 --> y=1
C. -x-y +x-y= 2 --> y=-1
D. -x-y-x+y=2 --> x=-1
The area bounded by 4 graphs x=1, x=-1, y=1, y=-1 will be square with the side of 4 so the area will be 1*1=1.
Answer: A
Question: Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
A.2 times
B.2 1/5 times
C.3 times
D.4 times
Answer: A.2 times
Explanation: Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
(4x + 8) = 5 (x + 8)
2
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = (4x + 16)/(x + 16) = 48/24	= 2.
A)
Question: emblem is coded as 216;
crude is coded as 125
Cricket will be ?
A.243
B.143
C.343
D.383
Answer: C.343
Explanation: coding follows (no. of letters)^3
emblem = 216 = 6^3
crude = 125 = 5^3
Cricket = 7^3 =343
ANSWER:C
Question: The difference between the place values of 7 and 3 in the prime number 527435 is
A.4
B.5
C.45
D.6970
Answer: D.6970
Explanation: Solution
(place value of 7)-(place value of 3)
= (7000 - 30)
= 6970.
Answer D