RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Solution Y is 30 percent liquid J and 70 percent water. If 2 kilograms of water evaporate from 8 kilograms of solutions Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new liquid solution is liquid J?
A.30%
B.33 1/3%
C.37 1/2%
D.40%
Answer: C.37 1/2%
Explanation: Answer:C
Took time to solve this one, the statement2 kilograms of solution Y are added to the remaining 6 kilograms of liquidwas confusing to me. After thinking more deeply, it was clear to me that new 2 kg of solution Y will also be 30% liquid J and 70% water, and then I was able to get the answer. That was a bit tricky and nice question=C
Question: A and B working separately can complete a piece of work in 9 and 12 days respectively. If they work alternatively starting from A in how many days will the work be completed?
A.10.25 days
B.11.5 days
C.12.75 days
D.9 days
Answer: A.10.25 days
Explanation: Explanation:
A takes 9 days to complete a piece of work. B takes 12 days to complete a piece of work.
=> In one day A came complete 1/9th of the task(x/9)
=> In one day B can complete 1/12th of the job.(x/12)
First day x/9th work will be done next day x/12th and so on:
Together A and B can do x/9 + x/12 work.
=>(x/9) + (x/12) = 7/36th work done
In 10 days 35/36th of the work will be done.
On 11th day it will be A’s chance. It takes A 1 day to complete 1/9th work.
So, 1/36th work will be done in 1/4 days.
=>10.25 days
ANSWER A
Question: If D is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of D?
A.10
B.12
C.14
D.16
Answer: C.14
Explanation: D = 30!
8
D = 30 x 29 x 28 x 27 x 26 x 25 x 24 x 24 x 22 x 21 x 20 x 19 x 18 x 17 x 16 x 15 x 14 x 13 x 12 x 11 x 10 x 09 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
Out of these 30 , 27 , 24 , 21 , 18, 15 , 12 , 09 , 06 , 3 are factors of 3
3 x 10 , 3 x 3 x 3 , 3 x 8 , 3 x 3 x 2, 3 x 5 , 3 x 4 , 3 x 3 x 3 , 3 x 2 , 3
So we have a total of 14 three's ...
Therefore the maximum value of K can be 14 (C)
Question: If Rs.10 be allowed as true discount on a bill of Rs.110 due at the end of a certain time,then the discount allowed on the same sum due at the end of double the time is :
A.Rs. 20
B.Rs. 21.81
C.Rs. 22
D.Rs. 18.33
Answer: D.Rs. 18.33
Explanation: Solution
S.I. on Rs.(110 -10) for a certain time =Rs.10.
S.I. on Rs. 100 for double the time =Rs. 20.
T.D. on Rs. 120 =Rs.(120 -100)=Rs. 20.
T.D. on Rs. 110 =Rs.(20/120x120) =Rs.18.33.
Answer D
Question: Ram, Krish and Bhim can complete a work in 30 days. If Ram and Krish together can complete the same work in 40 days, then how long will Bhim take to complete it?
A.60
B.80
C.100
D.120
Answer: D.120
Explanation: Ram + Krish + Bhim’s work = 1/30
Ram and Krish’s work= 1/40
Bhim’s work = 1/30 - 1/40 = 1/120
ANSWER:D
Question: Alice and Paul have a plate with 37 cookies on it. They both eat cookies off of the plate every minute. Paul takes a drink of milk instead of eating a cookie every third minute. Alice eats two cookies instead of one every fourth minute. How many minutes does it take them to eat all of the cookies?
A.13 minutes
B.12 minutes
C.11 minutes
D.10 minutes
Answer: C.11 minutes
Explanation: Alice eats 6 cookies every 4 minutes. Paul eats 2 cookies every 3 minutes. In 9 minutes, Alice eats 6*2 + 1 = 13 cookies, and Paul eats 2*3 = 6 cookies, for a total of 13+6 = 19 cookies. In 10 minutes, Alice eats 6*2 + 2 = 14 cookies, and Paul eats 2*3 + 1= 7 cookies, for a total of 14+7 = 21 cookies. In 11 minutes, Alice eats 6*2 + 3 = 15 cookies, and Paul eats 2*3 + 2= 8 cookies, for a total of 15+8 = 23 cookies.Thus, the answer is C.
Question: A train running at the speed of 60 km/hr crosses a pole in 15 seconds. Find the length of the train?
A.150 meter
B.170 meter
C.250 meter
D.168 meter
Answer: C.250 meter
Explanation: Speed = 60*(5/18) m/sec
= 50/3 m/sec
Length of Train (Distance)
= Speed * Time
(50/3) * 15
= 250 meter
Answer:C
Question: Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds ?
A.11:9
B.11:20
C.9:20
D.11:8
Answer: A.11:9
Explanation: Sol.
In the same time, they cover 110 km and 90 km respectively.
∴ Ratio of their speeds = 110 : 90 = 11 : 9.
Answer A
Question: All of the stocks on the over the counter market are designated by either a 4 letter or a 5 letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be designated with these codes?
A.
B.
C.
D.
E.
A.2 (26)^5
B.26(26)^4
C.27(26)^4
D.26(26)^5
Answer: C.27(26)^4
Explanation: There are two slightly different ways of doing this question:
No of different four letter codes:
26*26*26*26 = 26^4
No of different five letter codes:
26*26*26*26*26 = 26^5
Total number of codes = 26^4 + 26^5 = 27*26^4
ANS:C
Question: (8956231 x 465) = ?
A.4584638125
B.4164647415
C.4584638135
D.4584638140
Answer: B.4164647415
Explanation: 8956231 x 465=4164647415Ans B
Question: Two numbers are 35% and 42% are less than a third number .How much percent is the second number less than the first ?
A.11.769%
B.10.769%
C.12.769%
D.11.69%
Answer: B.10.769%
Explanation: Explanation:
I II III
65 58 100
65 -------- 7
100 ------ ? => 10.769%
Answer B
Question: Find the average of the series : 256,254,350, 1110,1200 ?
A.129
B.308
C.634
D.207
Answer: C.634
Explanation: Average = (256+254+350+1110+1200) /5
= 3170/5
= 634
Answer: C
Question: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
A.57 .6 m
B.127.5 m
C.87 .9 m
D.123.5 m
Answer: B.127.5 m
Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8 = 787.5 m.
In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000 =127.5 m
Answer:B
Question: Amar, Bhavan and Chetan divide an amount of Rs.5600 among themselves in the ratio 3:6:5. If an amount of Rs.400 is deducted from each of their shares, what will be the new ratio of their shares of the amount?
A.2:5:6
B.2:5:0
C.2:5:4
D.2:5:3
Answer: C.2:5:4
Explanation: Let the shares of Amar, Bhavan and Chetan be 3x, 6x and 5x respectively.
3x + 6x + 5x = 5600
14x = 5600 => x = 400
Required ratio = 3x - 400 : 6x - 400 : 5x - 400
= 3x - x : 6x - x : 5x - x
= 2x : 5x : 4x => 2:5:4
Answer:C
Question: A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?
A.40
B.50
C.54
D.60
Answer: D.60
Explanation: (A + B)'s 20 day's work =	(1/30 x 20	)	=	2/3	.
Remaining work =	(1 -	2/3 )	=	1/3	.
Now,	1/3	work is done by A in 20 days.
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
Answer : D
Question: Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
A.50
B.60
C.70
D.80
Answer: A.50
Explanation: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 - 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50.
Answer: Option A
Question: P and Q walk around a circular track. They start at 7 a.m from the same point in the opposite directions. P and Q walk at a speed of 4 rounds per hour and 7 rounds per hour respectively. How many times shall they cross each other before 10 a.m
A.30
B.31
C.32
D.33
Answer: D.33
Explanation: Explanation:
Relative speed = (4+7) =11 rounds per hour
So, they cross each other 11 times in an hour hence, they cross 33 times before 10 a.m
Answer: Option D
Question: Of the 30 employees of a certain company, 10 are accountants. 2 employees of the company will be selected at random. Which of the following is closest to the probability that neither of the employees selected will be an accountant?
A.0.43
B.0.36
C.0.31
D.0.52
Answer: A.0.43
Explanation: We can Solve this by two ways:
either find the probability by = 1-(both accountant+atleast one accountant)
or direct from = P(both non accountant)
second is easier but requires calculation if don't do the approximation.
So probability= (20/30)*(19/29) = 0.43
so the answer is A
Question: Marcella has 27 pairs of shoes. If she loses 9 individual shoes, what is the greatest number of matching pairs she could have left?
A.22
B.20
C.19
D.16
Answer: A.22
Explanation: Marcella has 27 pairs of shoes and loses 9 shoes.
To minimize the loss of identical pairs of shoes we want Marcella to lose as many identical pairs as possible. This would yield 4 identical pairs and 1 additional shoe (destroying 5 pairs of shoes).
The 27 pairs of shoes minus the 5 'destroyed' pairs yields 22 pairs that still fulfill the requirements.
Answer: A
Question: Sonika bought a V.C.R. at the list price of 18,900. If the rate of sales tax was 8%, find the amount she had to pay for purchasing the V.C.R.
A.20,412
B.19,780
C.19,680
D.19,380
Answer: A.20,412
Explanation: Sol. List price of V.C.R. =18,900
Rate of sales tax = 8%
∴ Sales tax = 8% of 18,900
= 8⁄100 × 18500 = 1512
So, total amount which Sonika had to pay for purchasing the V.C.R. = 18,900 + 1512
= 20,412. Answer A
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in teh same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
A.27 7/9 m
B.28 m
C.29
D.30
Answer: A.27 7/9 m
Explanation: Sol.
Relative speed = (40-20) km/hr = [20 * 5/18] m/sec = [50/9] m/sec.
Length of faster train = [50/9 * 5] m = 250/9 m = 27 7/9 m.
Answer A
Question: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 180 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
A. 280
B. 400
C. 540
D. 900
Answer: D. 900
Explanation: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month:
2/3*3/4 = 1/2 survived the first month.
Of the geese that survived the first month, 3/5 did not survive the first year:
(1-3/5)*1/2 = 1/5 survived the first year.
180 geese survived the first year:
1/5*(total) = 180 --> (total) = 900.
Answer: D.
Question: Three people took GMAT practice tests in which the minimum and maximum possible scores are 200 and 800, respectively. They each took a test 4 times, and no one scored below 450 or over 650. If the individual ranges of the three people's scores in those 4 practice tests were 30, 80 and 110, what is the difference between the maximum and minimum possible ranges of all their scores put together.
A.90
B.120
C.50
D.70
Answer: A.90
Explanation: According to the information in the question the maximum range would be between 450 and 650(200). The minimum range would be the greatest range for any one individual, which is listed in the problem as 110. So the difference between these would be 200-110 or 90.
Answer: A
Question: The average of four consecutive odd numbers is 24. Find the largest number?
A.25
B.29
C.27
D.31
Answer: C.27
Explanation: Let the numbers are x, x+2, x+4, x+6, then
x+(x+2)+(x+4)+(x+6)/4=24
4x+12/4=24
x+3=24
x=21
So largest number is 21 + 6 = 27
Answer C
Question: If (2^x)(3^y) = 432, where x and y are positive integers, then (2^x-1)(3^y-2) equals:
A.16
B.24
C.48
D.96
Answer: B.24
Explanation: So I would start attacking this problem by quickly performing the prime factorization of 288. With that it is easy to count the 5 twos and the 2 threes that are the prime factors. So x=4, y=3. now quickly 2^3(3^1)=24. Than answer should be number 2.
B
Question: A train 300 m long is running at the speed of 30 km / hr. Find the time taken by it to pass a man standing near the railway line in seconds
A.15 sec
B.16 sec
C.17 sec
D.18 sec
Answer: D.18 sec
Explanation: Explanation:
Speed of the train = (60 x 5/18m / sec = 50/3 m/ sec.
Distance moved in passing the standing man = 300 m.
Required time taken = 300/(50/3) = (300 Ã—(3/50)) sec =6 sec
Answer: Option D
Question: The volumes of two cones are in the ratio 1 : 20 and the radii of the cones are in the ratio of 1 : 4. What is the length of the wire?
A.A)2:5
B.B)2:7
C.C)2:2
D.D)4:5
Answer: D.D)4:5
Explanation: The volume of the cone = (1/3)πr2h
Only radius (r) and height (h) are varying.
Hence, (1/3)π may be ignored.
V1/V2 = r12h1/r22h2 => 1/20 = (1)2h1/(4)2h2
=> h1/h2 = 4/5
i.e. h1 : h2 = 4 : 5
Answer: D
Question: From the integer n, if n*n*n*n*n is odd, then what is true from below options?
A.n is odd
B.n*n is even
C.n is odd, n*n is even, n*n*n is odd, n*n*n*n is even and n*n*n*n*n is odd
D.n is even
Answer: A.n is odd
Explanation: n is odd
Option A
Question: A dishonest dealer uses a scale of 90 cm instead of a metre scale and claims to sell at cost price. His profit is
A.9%
B.10%
C.12%
D.None of these
Answer: D.None of these
Explanation: Solution
Gain%	= (10 / 90 x 100)%
= 11 1/9.
Answer D
Question: The cross-section of a cannel is a trapezium in shape. If the cannel is 5 m wide at the top and 3 m wide at the bottom and the area of cross-section is 3800 sq m, the depth of cannel is?
A.920
B.930
C.940
D.950
Answer: D.950
Explanation: 1/2 * d (5+3)
= 3800
d = 950
Answer: D
Question: The number of sequences in which 7 players can throw a ball, so that the youngest player may not be the last is ?
A.4328
B.4328
C.4320
D.7862
Answer: C.4320
Explanation: x Not younger
The last ball can be thrown by any of the remaining 6 players. The first 6 players can throw the ball in 6P6 ways.
The required number of ways = 6(6!)
= 4320
Answer:C
Question: There are n members in a certain department, including Michael. Two representatives are to be selected to attend a company conference. If there are 66 possible combinations in which Michael is not selected, what is the value of n?
A.11
B.12
C.13
D.14
Answer: C.13
Explanation: The combinations of two people, in which Michael was not selected = 28
The number of ways two people can be selected from m people = m*(m-1)/2
Let m be the number of people excluding Michael.
Then m*(m-1) = 132 = 12*11
Thus, n = m + 1(Michael) = 13
The answer is C.
Question: In the equation s = 36.12t, t and s are integers. If s/t leaves a remainder of r, which of the following must divide into r?
A.2
B.3
C.4
D.6
Answer: B.3
Explanation: 1) It says it is a equation, so s=36.12t should be 36.12 * t..
2) It says t is an integer, again it means 36.12 * t..
Otherwise t would be just a digit and it would be mentioned..
Although not clearly mentioned that 36.12t is actually 36.12 * t, BUT entire info points towards that..
and that is why I have taken s/t = 36.12
Question: In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C :
A.10 m
B.15 m
C.20 m
D.30 m
Answer: C.20 m
Explanation: "A can give B 10 m".
In a 100 m race, while A starts from the starting point, B starts 10 meters ahead from the same starting point at the same time.
"A can give C 28 m"
In a 100 m race, while A starts from the starting point, C starts 28 meters ahead from the same starting point at the same time.
i.e., in a 100-10=90 m race, B can give C 28-10=18 m
In a 100 m race, B can give C18/90×100 = 20 m
Answer is C
Question: Find 94 ×× 97
A.93/198
B.93/12
C.93/18
D.93/10
Answer: C.93/18
Explanation: Here both numbers are less than 100. So they are deficient of - 6 and - 3 compared with 100. So
Answer:	C
Question: A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
A.177
B.168
C.120
D.882
Answer: C.120
Explanation: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 6 = 120 m.Answer:C
Question: The ratio of number of boys and girls in a school is 1:2. If there are 90 students in the school, find the number of girls in the school?
A.45
B.50
C.60
D.75
Answer: C.60
Explanation: Let the number of boys and girls be x and 2x
Total students = 100
Number of girls in the school = 2*90/3 = 60
Answer is C
Question: If you roll a fair-sided die twice, what is the probability of getting a double?
A.1/3
B.1/6
C.1/12
D.1/24
Answer: B.1/6
Explanation: ways you can get double - 6...as each dice showing any number from 1 to 6...
total ways = 6∗6=36.6∗6=36..
P=6/36=1/6
ANSWER: B
Question: What is 35% of 4/13 of 715?
A.44
B.55
C.66
D.77
Answer: D.77
Explanation: This problem can be solved easily if we just use approximation: 35% is a little over 1/3, while 4/13 is a little less than 4/12, which is 1/3. Thus, the answer is about 1/3 of 1/3 of 715, or 1/9 of 715. Since the first 1/3 is a slight underestimate and the second 1/3 is a slight overestimate, the errors will partially cancel each other out. Our estimate will be relatively accurate.
The number 715 is about 720, so (1/9)*715 will be a bit less than 80.
Keeping track not only of your current estimate, but also of the degree to which you have overestimated or underestimated , can help you pinpoint the correct answer more confidently.
The closest answer is 77, so this is the answer to choose.
The answer is D.
Question: Dinesh speaks truth in 3/4 cases and Abhishek lies in 1/5 cases. What is the percentage of cases in which both Dinesh and Abhishek contradict each other in stating a fact?
A.60%
B.35%
C.20%
D.15%
Answer: B.35%
Explanation: Explanation :
D and A will contradict each other when one speaks truth and other speaks lies.
Probability of D speak truth and A lies
=>(3/4)×(1/5).
=>3/20.
Probability of A speak truth and D lies
=>(4/5)×(1/4).
=>1/5.
The two probabilities are mutually exclusive. Hence, probabilities that D and A contradict each other:
=>(3/20)+(1/5).
=>7/20.
=>0.35×100%
=>35%
Answer : B
Question: A man drive his car to the office at 20miles/hr.
After reaching office, he realize that its a new year holiday so he went back home at a speed of 30miles/hr.
Discounting the time spent in the stoppage what was his average speed of his journey ?
A.23miles
B.25miles
C.22miles
D.24miles
Answer: D.24miles
Explanation: D
24miles/hr (not 25miles/hr which might be guessed by many)
D : distance traveled
T1 : time of going to office
T2 : time of returning back
Y : Average Speed
D = 20 * T1
T1 = D/20
D = 30 * T2
T2 = D/30
2D = Y(T2 + T1)
2D = Y(D/20 + D/30)
2D = Y(3D/60 + 2D/60)
2D = Y(5D/60)
Y = 120D/5D
=> Y = 24
Question: The average (arithmetic mean) of 22, 33, and 53 is 8 less than the average of 30, 56, and x. What is x?
A.42
B.44
C.46
D.48
Answer: C.46
Explanation: The average of 22, 33, and 53 is 108/3 = 36.
The average of 30, 56 and x is 44.
Then 30 + 56 + x = 132.
x = 46.
The answer is C.
Question: Abby and Bobby type at constant rates of 80 words per minute and 60 words per minute, respectively. Bobby begins typing before Abby and has typed 600 words when Abby begins typing at 1:30 pm. If they continue typing at their respective rates, at what time will Abby have typed exactly 300 more words than Bobby?
A.1:40 PM
B.1:50 PM
C.2:00 PM
D.2:15 PM
Answer: D.2:15 PM
Explanation: Say time needed for Abby to type 200 more words than Bobby is t. In that time she would type 80t words and Bobby would type 60t words.
Now, total words typed by Bobby would be 600+60t and we want that number to be 200 less than 80t: 600+60t=80t-300 --> t=45.
1:30 PM + 45 minutes = 2:15 PM.
Answer: D.
Question: Three runners E, B and C run a race, with runner E finishing 12m ahead of runner B and 18m ahead of runner C, while runner B finishes 8m ahead of runner C. Each runner travels entire distance at a constant speed. What was the length of the race?
A.36m
B.48m
C.60m
D.72m
Answer: B.48m
Explanation: Let distance of race be x mtrs. Then when E finishes x m , B has run (x- 12)mtrs and C has run x-18 mtrs. so at this point B is 6 m ahead of C. Now to finish race b needs to run another 12 m, so he runs another 12 m. when B finishes race he is 8 m ahead of C. so last 12 m B has run, C has run 10 m.
as speeds are constant, we have equation,
x-12/ x-18 = 12/10 > x = 48.
Answer B
Question: letters in the word ABUSER are permuted in all possible ways and arranged in alphabetical order then find the word at position 49 in the permuted alphabetical order?
A.KASJJHJ
B.DGUJKL
C.ARBESU
D.ILUGUO
Answer: C.ARBESU
Explanation: Ans: The best way to solve this problems is Just ask how many words starts with A. If we fix A, then the remaining letters can be arranged in 5! ways = 120. So the asked word must start with A.
Arrange all the given letters in alphabetical order. ABERSU
Let us find all the words start with AB. AB**** = 4!= 24 ways
Now we find all the words start wit AE. AE****= 4!= 24 ways
So next word start with AR and remaining letters are BESU
Answer:C
Question: If it takes 6 identical printing presses exactly 4 hours E to print 5,000 newspapers, how long would it take 3 of these presses to print 3,000 newspapers?
A.3 hours, 20 minutes
B.4 hours, 20 minutes
C.4 hours, 48 minutes
D.5 hours, 48 minutes
Answer: C.4 hours, 48 minutes
Explanation: 6 presses - 5,000 newspapers - 4 hours ;
3 presses - 2,500 newspapers - 4 hours ;
3 presses - 3,000 newspapers - 4 hours + 1/5*4 hours = 4 hours, 48 minutes (since 2,500+1/5*2,500=3,000) = E.
Answer: C.
Question: A fast food hotel sells chicken in orders of 6, 9, and 20.
What is the largest number of pieces of chicken you cannot order from this hotel ?
A.A)23
B.B)33
C.C)43
D.D)53
Answer: C.C)43
Explanation: 43.
After 6 all numbers divisible by 3 can be ordered (because they can all be expressed as a sum of 6's and 9's). After 26, all numbers divisible by three when subtracted by 20 can be obtained. After 46, all numbers divisible by three when subtracted by 40 can be obtained. After 46, all numbers fit into one of these 3 categories, so all numbers can be obtained. 43 is the last number that doesn't fall into one of these categories (44 = 20 + 6 * 4, 45 = 6 * 6 + 9). answer is C
Question: A person walks at a speed of 4 km/hr and runs at a speed of 8 km/hr. How many hours will the person require to cover a distance of 8 km, if the person completes half of the distance by walking and the other half by running?
A.0.5
B.1.5
C.2.5
D.3.5
Answer: B.1.5
Explanation: time = 4/4 + 4/8 = 12/8 = 1.5 hours
The answer is B.
Question: How many positive integers less than 200 are there such that they are multiples of 13 or multiples of 12?
A.28
B.29
C.30
D.31
Answer: C.30
Explanation: Total Multiples of 13: 15 (First multiple:13, last multiple:195)
Total Multiples of 12:16 (First multiple: 12,Last multiple: 192)
Multiple of 12 and 13: 1 (156)
15+16-1=30
ANSWER:C
Question: Find the sum of all odd numbers upto 100.
A.2200
B.2900
C.2700
D.2500
Answer: D.2500
Explanation: The given numbers are 1, 3, 5, 7, ..., 99.
This is an A.P. with a = 1 and d = 2.
Let it contain n terms. Then,
1 + (n - 1) x 2 = 99 or n = 50.
Therefore, Required sum = n/2 (first term + last term)
= 50/2 (1 + 99) = 2500.
Answer is D.
Question: A and B can together finish a work in 40days. They worked together for 10days and then B left. After another 9days, A finished the remaining work. In how many days A alone can finish the job?
A.12
B.25
C.60
D.30
Answer: A.12
Explanation: A+B 10days work = 10*1/40 = 1/4
Remaining work = 1-1/4 = 3/4
3/4 work is done by A in 9 days
whole work will be done by A in 9*4/3 = 12 days
Answer is A
Question: The sum of the squares of three consecutive natural number is 2030. What is the middle number?
A.25
B.26
C.27
D.28
Answer: B.26
Explanation: Let the numbers be x, x+1 and x+2
X2+(x+1)2+(x+2)2=2030
3x2+6x-2025=0
(x+27)(x-25)=0
X=25
The middle number is 26
ANSWER B 26
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 47, then how old is B?
A.17 years
B.19 years
C.18 years
D.10 years
Answer: C.18 years
Explanation: Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 47
5x = 45 => x = 9
Hence, B's age = 2x = 18 years.
Answer: C