RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The perimeter of a rhombus is 120 feet and one of its diagonal has a length of 40 feet. Find the area of the rhombus.
A.100 sqrt(5) ft.sq
B.400 sqrt(5) ft.sq
C.500 sqrt(5) ft.sq
D.200 sqrt(5) ft.sq
Answer: B.400 sqrt(5) ft.sq
Explanation: A perimeter of 120 when divided by 4 gives the side of the rhombus 30 feet. The length of the side OC of the right triangle is equal to half the diagonal: 20 feet. Let us now consider the right triangle BOC and apply Pythagora's theorem to find the length of side BO.
30^2 = BO^2 + 20^2
BO = 10 sqrt(5) feet
We now calculate the area of the right triangle BOC and multiply it by 4 to obtain the area of the rhombus.
area = 4 ( 1/2) BO * OC = 4 (1/2)10 sqrt (5) * 20
= 400 sqrt(5) ft.sq
Answer is B
Question: How many positive integers less than 24 are prime numbers, odd multiples of 5, or the sum of a positive multiple of 2 and a positive multiple of 4?
A.19
B.25
C.24
D.22
Answer: A.19
Explanation: 9 prime numbers less than 28: {2, 3, 5, 7, 11, 13, 17, 19, 23}
2 odd multiples of 5: {5, 15}
9 numbers which are the sum of a positive multiple of 2 and a positive multiple of 4: {6, 8, 10, 12, 14, 16, 18, 20, 22}
Notice, that 5 is in two sets, thus total # of integers satisfying the given conditions is 9+2+9-1=19.
Answer: A.
Question: A newly-wed couple is using a website to design an eBook Wedding Album to distribute to their friends and families. The template they have chosen has places for 3 large photos and 19 smaller photos. The couple has 6 large photos they could use for those three slots, and 21 smaller photos they could use for those 19 slots. Given these choices, how many different possible albums could they create?
A.3,150
B.4,200
C.5,040
D.20,520
Answer: B.4,200
Explanation: For the big album they have to choose 3 out of their 6 photos, and leave out 3:
6! / 3!3! = 20
For the small album they have to choose 19 out of their 21 photos and leave out 2:
21! / 19!2! = 210
All combinations together: 210*20 = 4200, ANS B
Question: Find the average of the series : 235,222,125,135,123
A.168
B.308
C.267
D.207
Answer: A.168
Explanation: Average = (235+222+125+135+123)/5
= 840/5
= 168
Answer: A
Question: (0.5)(power 3) - (0.1)(power 3)/ (0.5)(power 2) + 0.05 + (0.1)(power 2) is:
A.0.8
B.0.4
C.0.96
D.0.69
Answer: B.0.4
Explanation: Given expression
= (0.5) (power 3) - (0.1)(power 3) / (0.5)(power 2) + (0.5 x 0.1) + (0.1)(power 2)
= a (power 3) - b(power 3) / a(power 2) + ab + b(power 2)
= (a - b)
= (0.5 - 0.1)
= 0.4
Answer is B
Question: At a certain ice cream parlor, customers can choose among five different ice cream flavors and can choose either a sugar cone or a waffle cone. Considering both ice cream flavor and cone type, how many distinct triple-scoop cones with three different ice cream flavors are available?
A.12
B.16
C.20
D.24
Answer: C.20
Explanation: Customer can choose 3 out of 5 flavors 5C3=10;
Customer can choose 1 out of 2 cone type 2C1=2;
Total # of combinations possible 10*2=20.
ANS:C
Question: Set K contains every multiple of 6 from 18 to 306 inclusive. If w is the median of set K, and x is the average (arithmetic mean) of set K, what is the value of w-x?
A.-6
B.-3
C.0
D.3
Answer: C.0
Explanation: Set K ={18,24,30,....306}
Let the no. of terms be n.
so we know the AP formulae to calculate the the tn term:
tn= a+(n-1)*d where d = common difference of the terms.
306= 18 +(n-1)*6
n=49.
So the set K consist of n terms.
The median of the set having odd nos of elements is (n+1)/2., which in this case is 25.
Let's find the 25th term using the same formulae again:
t25= 18+(25-1)*6
t25= 162
So , the median of the set K is 162 i.e. w=162.
Now. lets find the average (arithmetic mean) of the set. For that we need to find the sum of all the elements first, lets call it S.
Since, set k is nothing but a Arithmetic Progression series having first element(a) as 18, common difference (d) as 6 and no. of terms(n) as 49.
Using the formulae to calculate sum of an AP series, which is
S= n/2[2a + (n-1)*d], we will calculate the sum.
so, S= 49/2 [2*18 + (49-1)*6]
This gives us S= 7938.
Now Arithmetic mean of Set K = 7938/no. of terms= 7938/49= 162.
So x= 162.
Now, (w-x) = (162-162)= 0.
Therefore Correct Answer = C
Question: If 3 persons can do 3 times of a particular work in 3 days, then, 7 persons can do 7 times of that work in?
A.days
B.days
C.days
D.days
Answer: B.days
Explanation: That is, 1 person can do one time of the work in 3 days.
Therefore, 7 persons can do 7 times work in the same 3 days itself.
B)
Question: The labeled price of a table is Rs. 7,500. The shopkeeper sold it by giving 5% discount on the labeled price and earned a profit of 15%. What approximately is the cost price of the table?
A.Rs. 6195
B.Rs. 6199
C.Rs. 6192
D.Rs. 6191
Answer: A.Rs. 6195
Explanation: Explanation:
Labeled price = Rs. 7,500
By giving 5% discount on labeled price, the selling price is
= 95 / 100 * 7500 = Rs. 7125
By earning 15% profit on the selling of price Rs. 7125 the cost price is
= 100 / 115 * 7125 = Rs. 6195.65
Therefore, approximate cost is 6195.65
ANSWER: A
Question: From the set of numbers {t, u, v, w, x, y, z}, how many different combinations can we have without the t in them? Ex:. (x,y), (x), (w,z,y,x), etc... and note that (x,y)=(y,x)
A.16
B.31
C.32
D.63
Answer: D.63
Explanation: Any letter (u, v, w, x, y, z) can be included or not.
Thus there are 2^6 combinations - 1 empty combination = 63 combinations
The answer is D.
Question: Find out the C.I on Rs.3000 at 4% p.a. compound half-yearly for 1 1/2 years.
A.A)Rs.181.62
B.B)Rs.182.62
C.C)Rs.183.62
D.D)Rs.184.62
Answer: C.C)Rs.183.62
Explanation: A = 3000(51/50)3
= 3183.62
3000
-----------
183.62
ANSWER:C
Question: If a man can cover 20 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?
A.288
B.162
C.220
D.270
Answer: D.270
Explanation: 20 m/s = 20 * 18/5 kmph
3 hours 45 minutes = 3 3/4 hours = 15/4 hours
Distance = speed * time = 20 * 18/5 * 15/4 km = 270 km.
Answer: D
Question: What is the rate percent when the simple interest on Rs.5000 amount to Rs.2500 in 5 Years?
A.9%
B.8%
C.10%
D.10.5%
Answer: C.10%
Explanation: Interest for 1 year = 2500/5 = 500
Interest on Rs 5000 p/a = 500
interest rate = 500/5000*100 = 10%
Answer : C
Question: The speed of light is approximately 1,86 * 10^6 miles per second. This approximate speed is how many miles per hour?
A. 1,11 * 10^7
B. 6,70 * 10^7
C. 1,11 * 10^8
D. 6,,70 * 10^9
Answer: D. 6,,70 * 10^9
Explanation: The easiest way to answer this question is by POE, it does not require any calculation (answered in 30seconds). In one hour there are 3600 seconds, therefore speed in miles/hour will be.
(1.86*10^6)*3600 = (1.86*10^6)*(3.6*10^3) = some number*10^9..
The key is realizing that thesome numberhas to be bigger thatn 1.86 (because 1.86*3.6), and the only answer that fits that is D
Question: If y > 0, (8y)/20 + (3y)/10 is what percent of y?
A.40%
B.50%
C.60%
D.70%
Answer: D.70%
Explanation: can be reduced to 4y/10+3y/10 =7y/10=70%
Answer D
Question: If p, q and r are positive integers and satisfy x = (p + q -r)/r = (p - q + r)/q = (q + r - p)/p, then the value of x is?
A.-1
B.1
C.2
D.-2
Answer: B.1
Explanation: When two or more ratios are equal, each of the ratios are equal to sum of the numerators divided by the sum of the denominators, provided sum of the denominators is non-zero.
Hence, x = (p + q -r)/r = (p - q + r)/q = (q + r - p)/p
=> x = (p + q - r + p - q + r + q + r - p) / (r + q + p)
=> x = (r + q + p) / (r + q + p) = 1
p + q + r is non-zero.
Answer: B
Question: A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
A.999
B.279
C.120metre
D.99
Answer: C.120metre
Explanation: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 6
= 120 m.
Answer: C
Question: Ravi purchased a refrigerator and a mobile phone for Rs. 15000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 4 percent and the mobile phone at a profit of 10 percent. Overall he make a.?
A.277
B.209
C.121
D.200
Answer: D.200
Explanation: Let the SP of the refrigerator and the mobile phone be Rs. r and Rs. m respectively.
r = 15000(1 - 4/100) = 15000 - 600
m = 8000(1 + 10/100) = 8000 + 800
Total SP - Total CP = r + m - (15000 + 8000) = -600 + 800 = Rs. 200
As this is positive, an overall profit of Rs. 200 was made.
Answer: D
Question: A diagonal is a line segment that connects non-adjacent vertices in a polygon. How many diagonals does an octagon have?
A.20
B.40
C.60
D.90
Answer: A.20
Explanation: Select one vertex and you can draw 5 diagonals.
If you draw 5 such diagonals for each of the 8 vertices, you will draw a total of 5 × 8 = 40 diagonals. But you actually draw each diagonal twice, once from each of its ends. Therefore, there are a total of 40 ÷ 2 = 20 different diagonals
correct answer A
Question: The slant height of a cone is 18 cm and radius of the base is 8cm, find the curved surface of the cone?
A.26
B.452
C.450
D.440
Answer: B.452
Explanation: π * 18 * 8
= 452
Answer:B
Question: A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
A.1000
B.2287
C.2677
D.2887
Answer: A.1000
Explanation: 90%
104%
--------
14% ---- 140
100% ---- ? => Rs.1000
Answer: A
Question: What least value must be assigned to * so that the number 197*5462 is divisible by 9
A.0
B.2
C.4
D.9
Answer: B.2
Explanation: Let the missing digit be x.
Sum of digits = (1 + 9 + 7 + x + 5 + 4 + 6 +»2) = (34 + x).
For (34 + x) to be divisible by 9, x must be replaced by 2 .
Hence, the digit in place of * must be 2.
ANSWER B 2
Question: A bowl was filled with 120 ounces of milk, and 0.01 ounce of the milk evaporated each day during a 60-day period. What percent of the original amount of milk evaporated during this period?
A.A)0.005%
B.B)0.05%
C.C)5%
D.D)0.50%
Answer: D.D)0.50%
Explanation: Total amount of milk evaporated each day during a 60-day period = .01 * 60
= 0.6
percent of the original amount of milk evaporated during this period = (.6/120) * 100%
= 0.5 %
Answer D
Question: In how many ways Chief Minister and Minister be elected from a team of 12 members?
A.125
B.131
C.132
D.145
Answer: C.132
Explanation: To do this, if captain is elected first, then we have 12 ways of doing this.
For election of vice-captain, we have only 11 ways left, coz 1 way is already consumed. (Situations like this is called dependent situation. One selection depends upon other selection.)
So, the ans is 12*11 = 132 ways.
C
Question: Positive Integer A gives the remainder of 18 when divided by another positive Integer B. If A/B = 147.24, what is the value of B?
A.96
B.75
C.48
D.25
Answer: B.75
Explanation: .24 of B = Remainder
.24 of B = 18
B = (18*100) / 24 = 75.
B
Question: The average (arithmetic mean) of a normal distribution of a school's test scores is 65, and standard deviation of the distribution is 6.5. A student scoring a 77 on the exam is in what percentile of the school?
Choices
A.63rd percentile
B.68th percentile
C.84th percentile
D.96th percentile
Answer: D.96th percentile
Explanation: (78-65)/6.5 = 2 sigmas or 95.5th percentile for +-2 sigma but in our case we need only upper tail, so it's 100 - (100 - 95.5)/2 = 96th percentile
D
Question: A cistern which could be filled in 9 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it?
A.22
B.27
C.29
D.90
Answer: D.90
Explanation: 1/9 - 1/x = 1/10
=> 90 hrs
Answer: D
Question: The two lines y=x and x=-8 intersect on the coordinate plane. What is the value of the area of the figure formed by the intersecting lines and the x-axis?
A.28
B.32
C.36
D.40
Answer: B.32
Explanation: The point of intersection is (-8,-8).
The triangle has a base of length 8 and a height of 8.
area = (1/2)*base*height = (1/2)*8*8 = 32
The answer is B.
Question: One woman and one man can build a wall together in three hours, but the woman would need the help of two girls in order to complete the same job in the same amount of time. If one man and one girl worked together, it would take them five hours to build the wall. Assuming that rates for men, women and girls remain constant, how many hours would it take one woman, one man, and one girl, working together, to build the wall?
A.5/2
B.1
C.10/7
D.12/7
Answer: A.5/2
Explanation: Solution:Let work done by man, women and girl per hour be m,w,g respectively.
Then, m+w = 1/3-->(1) , w + 2g = 1/3-->(2) and m + g =1/5-->(3).
No. of hours it would take forone woman, one man, and one girl, working together, to build the wall,n = 1/m+w+g
From (1) and (2), m=2g and from (3) g=1/15,m=2/15 and w=1/5.
So, n = 1/(2/5) = 5/2
Option, A
Question: In how many ways can the letters of the word WAYS be arranged in a row so that the vowels appear in alphabetic order?
A.160
B.220
C.150
D.120
Answer: D.120
Explanation: three letters can be arranged in 1! ways.
only one combination AEI is required.
4 letters can be arranged in 4! ways.
D
Question: 5358 x 61 = ?
A.326838
B.323758
C.323298
D.273258
Answer: A.326838
Explanation: A
5358 x 61 = 5358 x (60 + 1)
= 5358 x 60 + 5358 x 1
= 321480 + 5358
= 326838.
Question: In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
A.6.25
B.5.5
C.7.4
D.5
Answer: A.6.25
Explanation: Runs scored in the first 10 overs = 10 × 3.2 = 32
Total runs = 282
Remaining runs to be scored = 282 - 32 = 250
Remaining overs = 40
Run rate needed = 250/40=6.25
ANSWER:A
Question: If Sn is the sum of the first n terms of a certain sequence and if Sn = n(n+3) for all positive integers n, what is the third term of the sequence?
A.3
B.4
C.6
D.8
Answer: D.8
Explanation: Tn = nth term
T1 = 1st term
T2 = 2nd term
and so on...
Sn = Sum of first n terms of the sequence
Sn = 1st term + 2nd term + 3rd term + ... + nth term
Sn = T1 + T2 + T3 + ....Tn
You are given here thatSn is the SUM of first n terms...So you have
Sn = T1 + T2 + T3 + ....Tn = n(n+1)
So S1 = T1
S2 = T1 + T2
S3 = T1 + T2 + T3
and so on
S1 = T1 = 1*(1+1) = 2
S2 = T1 + T2 = 2 + T2 = 2*(2+1) = 6
So T2 = 4
S3 = T1 + T2 + T3 = 2 + 4 + T3 = 3*(3+1) = 12
So T3 = 8
(This is what we wanted)
The third term is 8.
D
Question: On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 130 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school?
A.260
B.620
C.500
D.520
Answer: A.260
Explanation: Let the number of children in the school be x. Since each child gets 2 bananas, total number of bananas = 2x.
2x/(x - 130) = 2 + 2(extra)
=> 2x - 260 = x => x = 260.
ANSWER:A
Question: A school has received 60% of the amount it needs for a new building by receiving a donation of $300 each from people already solicited. People already solicited represent 40% of the people from whom the school will solicit donations. How much average contribution is requited from the remaining targeted people to complete the fund raising exercise?
A.$200
B.$177.78
C.$100
D.$277.78
Answer: B.$177.78
Explanation: Let the amount school needs = X
Let total people school plans to solicit = T
School has received 60 % of X => (3/5) X
People already solicited = 40% of T => (2/5) T
Now, as per the information given in the question :
(3/5)X = $400 . (2/5) . T --------------------------- 1
Remaning Amount is 40 % i.e ( 2/5 ) X ------because school has already received 60%
And the remaining people are 60 % i.e (3/5) .T -----because 40% of the people are already solicited
So, average contribution required from the remaining targeted people is
(2/5) X = (Amount required) . (3/5) . T ----------------------------------- 2
Divide eqn 1 by eqn 2
Amount required = $177.78
B
Question: 25 people are there, they are shaking hands together, how many hand shakes possible, if they are in pair of cyclic sequence.
A.24
B.25
C.44
D.48
Answer: B.25
Explanation: n for cyclic hand shake and n-1 for linear handshake.
so here no of hand shake is 25.
ANSWER:B
Question: A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 26 km/hr. Find the total journey in km.
A.220 km
B.224 km
C.230 km
D.200 km
Answer: D.200 km
Explanation: 0.5x/10 + 0.5x/10 = 20
--> x/10 + x/10 = 40
--> 2x = 10x40
--> x = (10x40)/2 =200 km.
Answer : D.
Question: A researcher computed the mean, the median, and the standard deviation for a set of performance scores. If18 were to be added to each score, which of these three statistics would change?
A.The mean only
B.The median only
C.The mean and the median
D.The standard deviation only
Answer: C.The mean and the median
Explanation: The correct answer is C.
Question: In how many ways can you line up 7 people in a row if one of them, Stephen, cannot be in the middle or at the either end?
A.2,880
B.92
C.1,100
D.2,990
Answer: A.2,880
Explanation: Since Stephen cannot be placed in the middle or at either end (3 spots), then he can choose 4 spots to sit. The remaining 6 apples can be placed in in 6! ways. Thus the # of arrangements is 4*6! = 2,880.
Answer: A.
Question: Arun borrowed a sum for 4 years on S.I. at 12%. The total interest paid was Rs. 360. Find the Principal.
A.Rs.700
B.Rs.650
C.Rs.800
D.Rs.750
Answer: D.Rs.750
Explanation: Explanation :
P=100×SI/RT
=100×360/12×4
=100×30/4
=25×30
=750
Answer : Option D
Question: 14 men and 3 boys finish a job in 7 days, 14 men and 14 boys finish it in 6 days. 13 men and 13 boys shall finish it in how many days?
A.18
B.07
C.12
D.19
Answer: B.07
Explanation: 14 M + 3 B ----- 7 days
14 M + 14 B ------- 6 days
13 M + 13 B -------?
196 M + 42 B = 182 M +182 B
14 M = 140 B => 1 M = 10 B
140 B + 3 B = 143 B ---- 7 days
130 B + 13 B = 143 B -----? => 7 days
Answer: B
Question: Jim wishes to buy 3 gifts that cost 23 dollars, 9 dollars, and 12 dollars. He has 1/4 of the money
he needs. How much more money must he earn in order to buy the gifts?
A.$57
B.$47
C.$33
D.$17
Answer: C.$33
Explanation: $23 + $9 + $12 = $44 needed
1/4 x $44 = $11 on hand
$44 - $11 = $33 to earn
correct answer C
Question: A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
A.77 hrs
B.81 hrs
C.35 hrs
D.17 hrs
Answer: C.35 hrs
Explanation: Suppose pipe A alone takes x hours to fill the tank.
Then, pipes B and C will take x/2 and x/4 hours respectively to fill the tank.
1/x + 2/x + 4/x = 1/5
7/x = 1/5 => x = 35 hrs.
Answer: C
Question: J and M were each paid x dollars in advance to do a certain job together. J worked on the job for 8 hours and M worked for 2 hours less than J. If M gave J y dollars of her payment so that they would have received the same hourly wage, what was the dollar amount, in terms of y, that J was paid in advance?
A.a)4y
B.b)5y
C.c)6y
D.d)7y
Answer: D.d)7y
Explanation: J and M were both paid x dollars
If M gave Y dollars from her X to J then at the end
J will have X+Y dollars
M will have X- Y dollars
Now since the hourly wages have to be same then
Hourly wage of J = (X+Y) / 8 (Since J worked for 8 hrs)
Hourly wage of M = (X-Y) / 6 (Since M worked 2 hrs less than J)
Equating both
(X+Y)/8=(X-Y)/6
on simplifying X=7Y
Answer D
Question: My grandson is about as many days as my son in weeks, and my grandson is as many months as I am in years. My grandson, my son and I together are 120 years. Can you tell me my age in years ?
A.56
B.72
C.68
D.91
Answer: B.72
Explanation: Let m be my age in years. If s is my son's age in years, then my son is 52s weeks old. If g is my grandson's age in years, then my grandson is 365g days old. Thus,
365g = 52s.
Since my grandson is 12g months old,
12g = m.
Since my grandson, my son and I together are 120 years,
g + s + m = 120.
The above system of 3 equations in 3 unknowns (g, s and m) can be solved as follows.
m / 12 + 365 m / (52 x 12) + m = 120 or
52 m + 365 m + 624 m = 624 x 120 or
m = 624 x 120 / 1041 = 72.
So, I am 72 years old.
correct answer is B)72
Question: A certain truck uses 18 gallons of diesel fuel in traveling 250 miles. In order for the truck to travel the same distance using 10 gallons of diesel fuel, by how many miles per gallon must the truck’s fuel mileage be increased?
A.8
B.10
C.12
D.15
Answer: B.10
Explanation: There are two sets 18G1 gallons and 10G2 gallons details given.
18 gallons covering 250 miles
Then 1 G1 is used to cover 15 miles.
Now for 10 G2 covering 2750 miles.
then 1 G2 is used to cover 25 miles.
There must 25- 15 = 10 miles per gallon increment is needed for 10 gallons to improve the mileage to cover 270 miles.
IMO B is correct answer.
Question: If all the sides of a right triangle increase in length by 5%, then by what percentage does the area of the triangle increase?
A.10.25%
B.20.50%
C.25.75%
D.30.25%
Answer: A.10.25%
Explanation: Let B be the base and H be the height of the original triangle.
The original area is (1/2)BH.
The area of the expanded triangle is (1/2)(1.05B)(1.05H) = (1.05)(1.05)(1/2)BH = 1.1025(1/2)BH
The answer is A.
Question: A certain junior class has 1,000 students and a certain senior class has 800 students. Among these students, there are 40 siblings pairs, each consisting of 1 junior and 1 senior. If 1 student is to be selected at random from each class, what is the probability that the 2 students selected at will be a sibling pair?
A.3/40,000
B.1/3,600
C.1/20,000
D.1/60
Answer: C.1/20,000
Explanation: Total number of ways of choosing one student from each group is = 800 * 1000
Number of cases in which a sibling pair will be got is = 40
Thus the probability that the 2 students selected will be a sibling pair is
= 40 /(800 * 1000)
= 1/20,000
C
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
A.140 m
B.150 m
C.160 m
D.240 m
Answer: B.150 m
Explanation: Sol.
Speed = [60 * 5/18] m/sec = [50/3] m/sec.
Length of the train = (Speed * Time) = [50/3 * 9] m = 150m.
Answer B
Question: John has both apples and bananas. The ratio of apples to bananas is 2 to 5. If there are 6 more bananas than apples, how many bananas are there?
A.8
B.10
C.12
D.14
Answer: B.10
Explanation: Let B be the number of bananas, and A be the number of apples.
Since the ratio of A to B is 2 to 5, that means that A = 2/5B.
We also know that A = B-6. Therefore we can substitute:
B-6 = 2/5B
Now we can solve for B:
If we isolate B, we see that:
3/5B = 6
And so
B = 10
Question: If the cost of x metres of wire is d rupees, then what is the cost of y metres of wire at the same rate?
A.Rs. (ydS
B.s.	(xy/d)
C.Rs. (xd)
D.Rs. (yd/x)
Answer: D.Rs. (yd/x)
Explanation: Explanation:
Cost of x metres = Rs. d.
Cost of 1 metre=Rs.(d/x)
Cost of y metres=Rs.[(d/x).y]=Rs.(yd/x)
Answer: D
Question: A company, Chauncy Co., has an annual travel budget of $60,000. The accounting department estimates that transportation expenses will increase 5 percent in the coming year, and nontransportation travel expenses will increase by 15 percent in the coming year. Last year, Chauncy Co. spent $19,500 on transportation-related expenses, and $35,000 on nontransportation travel expenses. If the annual travel budget does not increase this year, and if the accounting department’s estimates are correct, how far over the annual travel budget will expenses be this year?
A.Expenses will not go over the budget.
B.$725
C.$4,225
D.$5,725
Answer: B.$725
Explanation: annual travel budget of $60,000
Let, Transportation expenses = T = 19500
and Non-Transportation expenses = N=35000
i.e. Increased Transportation expenses = 1.05T = 20475
and Increased Non-Transportation expenses = 1.15N = 40250
Total Expense = 20475+40250 = 60725
Expense over Budget = Budget - expense = 60000-60725 = 725
Answer: Option B