RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If the 1st of the month occurs on a Thursday, on which day of the week does the 20th occur?
A.Wednesday
B.Saturday
C.Tuesday
D.Thursday
Answer: C.Tuesday
Explanation: Each weekday is repeated every 7 days. The 20th of the month is 19 days after the 1st. 19 divided by 7 is 2, with a remainder of 5. Therefore, the 20th occurs on whichever day of the week is five days after the day we started on, meaning the 20th is a Tuesday. Answer: C
Question: The difference of two numbers is 1340. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?
A.A)265
B.B)280
C.C)290
D.D)300
Answer: A.A)265
Explanation: Let the smaller number be x. Then larger number = (x + 1340).
x + 1340 = 6x + 15
5x = 1325
x = 265
Smaller number = 265.
A)
Question: A FIVE DIGIT NUMBER IS FORMED BY USING THE DIGITS 1,2,3,4 WITH OUT REPETITIONS . WHAT IS THE PROBABILITY THE NUMBER IS DIVISIBLE BY2?
A.1/4
B.5/6
C.4/5
D.7/3
Answer: A.1/4
Explanation: If a number is divisible by 2 the last 2 digits of the number has to be divisible by 2
If the number ends with 12: Number of possibilities = 3 * 2 * 1 = 6
number ends with 14: Possibilities = 6
number ends with 32: Possibilities = 6
number ends with 34: Possibilities = 6
number ends with 24: Possibilities = 6
Total number of possibilities with restriction = 6 *5 =30
Total number of possibilities without restriction = 5! = 120
Probability = 30/120 = 1/4
Answer: A
Question: Two numbers are in the ratio of 15:11. If their H.C.F. is 13, find the numbers.
A.195,143
B.185,133
C.175,123
D.165,113
Answer: A.195,143
Explanation: Let the required numbers be 15.x and llx.
Then, their H.C.F. is x. So, x = 13.
The numbers are (15 x 13 and 11 x 13) i.e., 195 and 143.
Answer is A.
Question: You enter a weight loss challenge game and manage to lose 15% of your body weight. For the final weigh in you are forced to wear clothes that add 2% to your weight. What percentage of weight loss is measured at the final weigh in?
A.13.3%
B.9.22%
C.9%
D.14%
Answer: A.13.3%
Explanation: (100%-15%)*(100%+2%) = 0.85*1.02 = 13.3%
The weigh in records your weight loss at 13.3%!
The Answer is A
Question: Score Interval Number of Scores
50-59 2
60-69 10
70-79 15
80-89 27
90-99 18
The table shows a distribution of test scores. Which score interval contains the median of the 72 scores?
A.a) 60-69
B.b) 70-79
C.c) 80-89
D.d) 90-99
Answer: C.c) 80-89
Explanation: 36th person
80-89 C
Question: A box contains2 blue marbles, 4 red marble, 3 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either green or yellow?
A.5/11
B.4/11
C.3/11
D.2/11
Answer: D.2/11
Explanation: Given that there are 2 blue marbles, 4 red marbles, 3 green marbles and 2 yellow marbles. Probability that both marbles are green = 3Câ‚‚/11Câ‚‚ = 3/55
Probability that both are yellow = Â²Câ‚‚/11Câ‚‚ = 1/55
Probability that one green and other is yellow = (3Câ‚ * Â²Câ‚)/11Câ‚‚ = 6/55
Required probability = 3/55 + 1/55 + 6/55
= 10/55=2/11
Answer:D
Question: Let C represent a set of four distinct prime numbers. If the sum of the numbers in C is even and x is a member of C, then what is the least possible value that x can be?
A.1
B.2
C.3
D.5
Answer: C.3
Explanation: We are told that C is a set of four distinct prime numbers, and the sum of the numbers in C is even. Since the question involves odds, evens and the smallest possible prime, you should immediately think of 2, the smallest prime number and the only even prime number.
If 2 were a member of the set, then we would have one even number and three odd numbers. Since such sum would always be odd, 2 cannot be a member of the set. Thus, all the members of C must be odd to yield an even sum.
Since all the members of the set must be odd prime numbers, the answer is the smallest odd prime number, which is 3.
The correct answer is choice (C).
Note:1 is not a prime number.
Question: The total age of A & B is 12 years more than the total age of B & C. C is how many year younger than A.
A.C is 12 years younger than A
B.C is 12 years younger than B
C.C is 12 years younger than C
D.C is 12 years younger than D
Answer: A.C is 12 years younger than A
Explanation: Explanation:
From the given data A+B = 12+(B+C) A+B-(B+C) = 12 A-C=12 years. C is 12 years younger than A
Answer: A
Question: New age consultants have three consultants Gyani, Medha, and Buddhi. The sum of the number of projects handled by Gyani and Buddhi individually is equal to the number of projects in which Medha involved. All three consultants are involved together in 6 projects. Gyani works with Medha in 14 projects. Buddhi has 2 projects with with Medha but without Gyani and 3 projects with Gyani but without Medha.
The total number of projects for New age consultants is one less than twice the number of projects in which more than one consultant is involved.
What is the number of projects in which Medha alone is involved?
A.Uniquely equal to zero
B.Uniquely equal to 1
C.Uniquely equal to 4
D.Cannot be determined uniquely
Answer: B.Uniquely equal to 1
Explanation: Explanation :
It is given that all the three consultants are involved in 6 projects together. So put 6 where all the three circles intersect.
Buddhi has 2 projects with Medha but without Gyani. i.e., Medha and Buddhi alone worked in 2 projects.
Also given, Buddi worked on 3 projects with Gyani but without Medha. i.e., Buddi and Gyani alone worked on 3 projects.
Gyani worked with Medha in 14 projects. These two worked together along with Buddhi in 6 projects. So Gyani and Medha alone worked on 14 - 6 = 8 Projects.
Lets us assume, Gyani, Buddhi and Medha alone worked on a, b, c projects.
It was given that The sum of the number of projects handled by Gyani and Buddhi individually is equal to the number of projects in which Medha involved.
=> a + b = 8 + 6 + 2 + c
=> a + b = 16 + c ------------------ (1)
Also given The total number of projects for New age consultants is one less than twice the number of projects in which more than one consultant is involved.
The projects in which more than 1 consultant involved = 6 + 3 + 2 + 8 = 19.
Total projects = a + b + c + 8 + 3 + 2 + 6 = a + b + c + 19
=> 2 × 19 - 1 = a + b + c + 19.
=> a + b + c = 18.
=> a + b = 18 - c.
Substituting this value in equation (1) we get,
=> 18 - c = 16 + c.
=> c = 1.
Answer : B
Question: The average expenditure of a man for the first five months is Rs.180 and for the next seven months it is Rs.130. If he saves Rs.290 in that year, his monthly average income is :
A.Rs.140
B.Rs.150
C.Rs.160
D.Rs.175
Answer: D.Rs.175
Explanation: Explanation:
Total income = Rs.(180Ã—5+130Ã—7+290)=Rs.2100
Average monthly income
= Rs. (2100/12)=Rs.175
Correct Option: D
Question: A train 240 m long passed a pole in 24 seconds. How long will it take to pass a platform 650 m long?
A.65 sec
B.89 sec
C.100 sec
D.150 sec
Answer: B.89 sec
Explanation: Sol.
Speed = [240/24] m/sec = 10 m/sec.
∴ Required time = [240 + 650 / 10] sec
= 89 sec.
Answer B
Question: A girl goes to her school from her house at a speed of 6km/hr and returns at a speed of 4 km/hr. If she takes 10 hours in going and coming back, the distance between her school and house is
A.12 kms
B.16 kms
C.20 kms
D.24 kms
Answer: D.24 kms
Explanation: Let distance be D10 = D/4 + D/6 Answer : D
Question: The bankerâ€™s discount on Rs. 1600 at 5% per annum is the same as true discount on Rs. 1680 for the same time and at the same rate. The time is :
A.2 months
B.4 months
C.6 months
D.12 months
Answer: D.12 months
Explanation: Sol.
S.I. on Rs. 1600 = R.D. on Rs. 1680.
âˆ´ Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is S.I. on Rs. 1600 at 15%.
âˆ´ Time = [100 * 80 / 1600 * 5] year = 1year = 12 months.
Answer D
Question: If a 36 inches long strip cloth shrinks to 33 inches after being washed, how many inches long will the same strip remain after washing if it were 48 inches long?
A.47 inches
B.44 inches
C.45 inches
D.46 inches
Answer: B.44 inches
Explanation: Solution: Shrinking of cloth,
= [(36-33)/36]*100.
= 100/12%
Second time the strip shrinks,
= (48*100)/1200 = 4 inches
hence , the cloth remains = 48-4 = 44.
Answer: Option B
Question: A is twice as fast as B. If B alone can do a piece of work in 30 days, in what time can A and B together complete the work?
A.10
B.99
C.72
D.26
Answer: A.10
Explanation: A can do the work in 30/2 i.e., 15 days.
A and B's one day's work = 1/15 + 1/30 = (2 + 1)/30 = 1/10
So A and B together can do the work in 10 days.
Answer: A
Question: 100 people are attending a newspaper conference. 40 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors?
A.21
B.24
C.28
D.30
Answer: A.21
Explanation: {Total}={Writers}+{Editors}-{Both}+{Neither}.
{Total}=100;
{Writers}=40;
{Editors}>38;
{Both}=x;
{Neither}=2x;
100=40+{Editors}-x+2x --> x=60-{Editors}. We want to maximize x, thus we should minimize {Editors}, minimum possible value of {Editors} is 39, thus x={Both}=60-39=21.
Answer: A.
Question: How many two-element subsets of <1, 2,3,4,5,6> are there that do not contain the pair of elements 2 and 4?
A.11
B.12
C.14
D.15
Answer: C.14
Explanation: 6C2 - 1 = 14 Answer is C
Question: A, B and C, each working alone can complete a job in 6, 8 and 12 days respectively. If all three of them work together to complete a job and earn $ 1170, what will be C's share of the earnings?
A.$1100
B.$260
C.$1080
D.$1170
Answer: B.$260
Explanation: Explanatory Answer
A, B and C will share the amount of $1170 in the ratio of the amounts of work done by them.
As A takes 6 days to complete the job, if A works alone, A will be able to complete 1/6 th of the work in a day.
Similarly, B will complete 1/8th and C will complete 1/12th of the work.
So, the ratio of the work done by A : B : C when they work together will be equal to 1/6 : 1/8 : 1/12
Multiplying the numerator of all 3 fractions by 24, the LCM of 6, 8 and 12 will not change the relative values of the three values.
We get 24/6 : 24/8 : 24/12 = 4 : 3 : 2.
i.e., the ratio in which A : B : C will share $1170 will be 4 : 3 : 2.
Hence, C's share will be 2*1170/9 = 260
correct choice is (B)
Question: A can do a piece of work in 4 hours . A and C together can do it in just 2 hours, while B and C together need 3 hours to finish the same work. B alone can complete the work in --- hours.
A.12 hours
B.6 hours
C.8 hours
D.10 hours
Answer: A.12 hours
Explanation: Explanation :
Work done by A in 1 hour = 1/4
Work done by B and C in 1 hour = 1/3
Work done by A and C in 1 hour = 1/2
Work done by A,B and C in 1 hour = 1/4+1/3 = 7/12
Work done by B in 1 hour = 7/12 – 1/2 = 1/12 => B alone can complete the work in 12 hours
Answer : Option A
Question: Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
A.39
B.10
C.88
D.12
Answer: B.10
Explanation: Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
Therefore 20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Answer:B
Question: Terry is having lunch at a salad bar. There are two types of lettuce to choose from, as well as three types of tomatoes, and four types of olives. He must also choose whether or not to have one of the two types of soup on the side. If Terry has decided to have the salad and soup combo and he picks one type of lettuce, one type of tomato, and one type of olive for his salad, how many total options does he have for his lunch combo?
A.9
B.11
C.24
D.48
Answer: D.48
Explanation: Terry can pick one lunch salad bar....we can choose lettuce 2c1 , tomatoes - 3c1 and olives - 4c1...
Two types of soups , if he picks one then 2c1 ways.
Terry decided to have the combo : Soup + salad...Hmmm...
Using the above information, we get ( 2c1 * 2c1* 3c1 * 4c1 ) = 48..
ANS option D is correct answer..
Question: s, q, and r are positive integers. If s, q, and r are assembled into the six-digit number sqrsqr, which one of the following must be a factor of sqrsqr?
A. 23
B. 19
C. 17
D. 7
Answer: D. 7
Explanation: One short way -
sqrsqr = 1000sqr + sqr = (1000+1)sqr = 1001sqr
Therefore any factor of 1001 is a factor of sqrsqr
7 is a factor of 1001
So D
Question: In a family, the father took 1/4 of the cake and he had 3 times as much as each of the other members had. The total number of family members is
A.3
B.7
C.10
D.12
Answer: C.10
Explanation: 1-1/4 = remain cake 3/4
3/4*3 = 9/4
9/4+1/4 = 10
ANSWER:C
Question: Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are
A.39, 30
B.41, 32
C.42, 33
D.43, 34
Answer: C.42, 33
Explanation: Solution
Let their marks be (x+9) and x.
Then, x+9	= 56/100(x + 9 +x)
‹=› 25(x+9)
‹=› 14 (2x + 9)
‹=›3x = 99
‹=›x = 33.
SO, their marks are 42 and 33.
Answer C
Question: Sn = n^2 + 5n + 94 and K = S6 – S5 + S4 – S3 + S2 + S1. What is the value of K?
A.67
B.50
C.45
D.236
Answer: D.236
Explanation: I used brute force for this question:
S6: 36+30+94=160
S5: 25+25+94=144
S4: 16+20+94=130
S3: 9+15+94=118
S2: 4+10+94=108
S1: 1+5+94=100
S6-S5+S4-S3+S2-S1= 16+12+208=236
Answer D
Question: What number has a 5:1 ratio to the number 10?
A.11
B.50
C.99
D.88
Answer: B.50
Explanation: 5:1 = x: 10
x = 50
Answer: B
Question: The sale price of a trolley bag including the sale tax is Rs. 560. The rate of sale tax is 12% . If the shopkeeper has made a profit of 25%, the cost price of the trolley bag is:
A.Rs 1000
B.Rs 900
C.Rs 400
D.Rs 600
Answer: C.Rs 400
Explanation: Explanation :
112% of S.P. = 560
S.P. = Rs.(560x 100/112) = Rs.500.
C.P. = Rs (100/125x 500) = Rs 400
Answer : C
Question: A square, with perimeter 8, is inscribed in a circle. What is the area of the circle?
A.36π
B.30π
C.26π
D.2π
Answer: D.2π
Explanation: Area of circuscribed circle = pi/2*area of square
Area of square = (8/4)^2 = 2^2= 4
Area of circle = pi/2*4=2pi
Answer D
Question: There are two positive numbers in the ratio 5:8. If the larger number exceeds the smaller by 15, then find the smaller number?
A.25
B.66
C.77
D.88
Answer: A.25
Explanation: Let the two positive numbers be 5x and 8x respectively.
8x - 5x = 15
3x = 15 => x = 5
=> Smaller number = 5x = 25.
Answer: A
Question: Find the odd man out. 3, 8, 18, 38, 78, 158, 316
A.38
B.158
C.316
D.8
Answer: C.316
Explanation: Explanation :
3
3 × 2 + 2 = 8
8 × 2 + 2 = 18
18 × 2 + 2 = 38
38 × 2 + 2 = 78
78 × 2 + 2 = 158
158 × 2 + 2 = 318
Hence, 316 is wrong and 318 should have come in place of that
Answer : Option C
Question: A can eat 10 burgers in 2 days and B can eat 20 burgers in 1 day. For how long will 250 burgers last is both start eating them together?
A.25 days
B.20 days
C.15 days
D.10 days
Answer: D.10 days
Explanation: Explanation:
A can eat 5 burgers in 1 day and B can eat 20 burgers in 1 day
A and B together can eat 25 burgers in 1 day
=>They can eat 250 burgers in 10 days.
Answer: D
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?
A.30/17
B.30/19
C.30/11
D.30/13
Answer: D.30/13
Explanation: Speed downstream = 20 + 6 = 26 kmph.
Time required to cover 60 km downstream = d/s
= 60/26
= 30/13 hours.
Answer: D
Question: What is the difference between the local values of 4 in the number 54404?
A.2992
B.3996
C.2877
D.2077
Answer: B.3996
Explanation: Explanation:
4000 â€“ 4 = 3996
Answer:B
Question: If x/|y| = -2 which of the following must be true?
A.x = -y
B.x = y
C.x = y^2
D.x^2 =4* y^2
Answer: D.x^2 =4* y^2
Explanation: x/|y| = -2
x= -2 |y|
Squaring both sides
x^2= (-2 |y|) ^2= 4*y^2
D is the answer
Question: W and X started a business by investing Rs.2100/- and Rs.4900/- respectively. Find the W’s share out of a total profit of Rs.6000:
A.1800
B.1850
C.1900
D.1950
Answer: A.1800
Explanation: W = Rs.2100/-
X = Rs.4900/-
W share 3 parts & X share 7 parts
Total 10 parts -----> Rs.6000/-
----> 1 part -------> Rs.600/-
W share = 3 parts -----> Rs.1800/-
A
Question: A three-digit number 4a3 is added to another three-digit number 984 to give a four digit number 13b7, which is divisible by 11. What is the value of (a + b)?
A.8
B.10
C.14
D.17
Answer: B.10
Explanation: 4 a 3
9 8 4
13 b 7
=> a + 8 = b ...(1)
13b7 is divisible by 11
=> (1 + b) - (3 + 7) is 0 or divisible by 11
=> (b - 9) is 0 or divisible by 11 ...(2)
Assume that (b - 9) = 0
=> b = 9
Substituting the value of b in (1),
a + 8 = b
a + 8 = 9
=> a = 9 - 8 = 1
If a = 1 and b= 9,
(a + b) = 1 + 9 = 10
10 is there in the given choices. Hence B is the answer.
Question: The simple interest on a sum of money is 4/9 of the principal and the number of years is equal to the rate percent. Find the rate and the time?
A.6 2/3%
B.6 8/3%
C.6 2/6%
D.6 3/3%
Answer: A.6 2/3%
Explanation: 4/9 P = (P*R*R)/100
R = 20/3
= 6 2/3%
Answer: A
Question: At the wholesale store you can buy an 8-pack of hot dogs for $1.55, a 20-pack for $3.05, and a 500-pack for $22.95. What is the greatest number of hot dogs you can buy at this store with $200?
A.1,108
B.4,100
C.2,108
D.2,124
Answer: B.4,100
Explanation: We have $200 and we have to maximize the number of hot dogs that we can buy with this amount.
Let's try to find out what is the maximum number of hot dogs that we can buy for a lesser amount of money, which in this case is 500 for $22.95.
For the sake of calculation, let's take $23. 23x8 gives 184 ,i.e. a total of 500x8 = 4000 hot dogs . We are left with ~$16. Similarly, let's use $3 for calculation. We can buy 5 20-pack hot dogs (3x5), a total of 20x5 = 100 hot dogs. So we have 4100 hot dogs.
2108 looks far-fetched (since we are not likely to be left with > $1.55). Hence, (b) 4100 (ANSWER B)
Question: The total of the ages of Amar, Akbar and Anthony is 45 years. What was the total of their ages four years ago ?
A.29 years
B.24 years
C.20 years
D.30 years
Answer: A.29 years
Explanation: Explanation:
Required sum = (45 - 4 x 4) years = (45 - 16) years = 29 years.
Answer: Option A
Question: It is the New Year and Mandy has made a resolution to lose weight this year. She plans to exercise and do yoga. For exercise she plans to workout at the gym and ride her bicycle in the ratio of 2:3 everyday. She will also do yoga in the ratio, yoga:exercise = 2:3. If she rides her bike for 14 minutes, how much time will she spend doing yoga? (rounded to minutes)
A.10 min.
B.41 min.
C.17 min.
D.23 min.
Answer: D.23 min.
Explanation: The ratio is 2:3 = gym:ride, so (14)(3/2) = 21 minutes at the gym, and 21 + 14 = 35 minutes exercise, so (2/3)(35) = 23 minutes yoga.
Answer: D
Question: A boy is travelling from his home to school at 3 km/hr and reached 7 min late. Next day he traveled at 6 km/hr and reached 8 min early. Distance between home and school?
A.1.2km
B.1.3km
C.1.4km
D.1.5km
Answer: D.1.5km
Explanation: Let the distance be x
T1 = x/3 hr
T2 = x/6hr
Difference in time = 7+8 = 15 =1/4hr
x/3-x/6 = 1/4
x/6 = 1/4
x = 1.5 km
Answer is D
Question: Two water pumps, working simultaneously at their respective constant rates, took exactly 7 hours to fill a swimming pool. If the constant rate of one pump was 1.5 times the constant rate of the other, how many hours would it have taken the faster pump to fill the pool if it had worked alone at its constant rate?
A.25/3
B.32/3
C.35/3
D.40/3
Answer: C.35/3
Explanation: Let the rate of the slow pump be x. Then the rate of the fast pump is 1.5x.
(x+1.5x) = 2.5x = 1/7 of the capacity of the whole pool per hour.
The rate of the fast pump is (1.5/2.5)*1/7 = 3/35 of the whole pool per hour.
The time it takes the faster pump to fill the pool would be 35/3 hours.
The answer is C.
Question: Number A is randomly selected from a set of all primes between 10 and 40, inclusive. Number K is selected from a set of all multiples of 5 between 10 and 40 inclusive. What is the probability that A+K is odd?
A. 1/2
B. 2/3
C. 3/4
D. 4/7
Answer: D. 4/7
Explanation: All primes except 2 are odd, thus A must be odd. For A + K = odd + K to be odd, K must be even.
There are 7 multiples of 5 between 10 and 40, inclusive: 10, 15, 20, 25, 30, 35, and 40. Out of them 3 (15, 25, and 35) are odd.
Therefore the probability that A + K is odd is 4/7.
Answer: D.
Question: Find the value of (1-(1/3))(1-(1/4))(1-(1/5))….(1-(1/100)).
A.1/50
B.4/50
C.9/50
D.7/50
Answer: A.1/50
Explanation: Given expression = (2/3)*(3/4)*(4/5) *…….* (99/100) = 2/100 = 1/50
Answer is A.
Question: On a business trip, 30 percent of 60 sales representatives will be given accommodations at Hotel XYZ and the remaining 70 percent will be given accommodations at Hotel ABC. However, 55 percent of the sales representatives prefer to stay at Hotel XYZ and 45 percent prefer to stay at Hotel ABC. What is the highest possible number of sales representatives NOT given accommodations at the hotel they prefer?
A.51
B.52
C.53
D.54
Answer: A.51
Explanation: 30% of 60 will be accommodated at XYZ = 18
70% of 60 will be accommodated at ABC = 42
55% of 60 prefer XYZ = 33
45% of 60 prefer ABC = 27
we were asked to find number of maximum possible people who were accommodated at hotels they dont prefer,
So for 18 XYZ accommodations , we can choose 18 ABC preferring people (so xyz is filled up) Here 18 were given to people who don't prefer XYZ
for 42 ABC accommodations, we can choose 33 ABC preferring people and rest to ABC. Here 33 were given to people who don't prefer ABC.
So total people who were accommodated at hotel they dont prefer = 18+33 = 51
So answer is A.
Question: Farmer Brown purchased several rabbits (male and female) and bred them on his farm. The rabbit population grew 500% the first year. The population grew 900% the second year. What was the percent, population growth for the two year?
A. 100%
B. 5,000%
C. 2000%
D. 2500%
Answer: B. 5,000%
Explanation: Let x be the initial population of rabbits Farmer Brown purchased; then, x + 5x is the rabbit population after the first year, and 5x + 9(5x) = 50x is the rabbit population after the second year.
Now, 50x/x = 50.
So, the percent, population growth is for the two years is 5,000%.
Answer is B
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.200
B.220
C.240
D.250
Answer: C.240
Explanation: Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m.
Answer: Option C
Question: If the sum of a number and its square is 182, what is the number?
A.13
B.15
C.17
D.19
Answer: A.13
Explanation: Sol.
Let the numbers be x.
Then, x + x2 = 182
⇔ x2 + x - 182 = 0
⇔ (x+14)(x-13) = 0
⇔ x = 13.
Answer A
Question: A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock?
A.20029
B.20000
C.20289
D.20027
Answer: B.20000
Explanation: Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x - 49x/50 = x/50
x/50 = 400 => x = 20000
Answer: B
Question: A bag contains 6 white and 4 black balls. 2 balls are drawn at random.
Find the probability that they are of same color.
A.7/15
B.8/15
C.6/15
D.3/5
Answer: A.7/15
Explanation: let S be the sample space
Then n(S)=no of ways of drawing 2 balls out of (6+4)=10C2=(10*9)/(2*1)=45
Let E=event of getting both balls of same color
Then n(E)=no of ways(2 balls out of six) or(2 balls out of 4)
=(6C2+4C2)=(6*5)/(2*1)+(4*3)/(2*1)=15+6=21
P(E)=n(E)/n(S)=21/45=7/15
answer option A)7/15