RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A train left station X at A hour B minutes. It reached station Y at B hour C minutes on the same day, after travelling C hours A minutes (clock shows time from 0 hours to 24 hours). Number of possible value(s) of A is:
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: Let's try to get hours and minutes values separately..
Starting time + time taken = Reaching time..
A hours + C hours = B hours -------- (i)
A, C and B cannot have values greater than or equal to 24
B minutes + A minutes = C minutes -------- (ii)
Looking at the two equations, we get that no value of A satisfies both the equations.
Hence, option A
Question: A = {2, 3, 5, 7, 11}
B = {2, 4, 6, 17}
Two integers will be randomly selected from sets A and B, one integer from set A and one from set B, and then multiplied together. How many different products can be obtained?
A.15
B.16
C.25
D.20
Answer: C.25
Explanation: By looking at Set A, we can see that it's all primes. Thus, we should immediately break down the elements in Set B to their prime factors. That gives :
Set A = {2,3,5,7,11}
Set B = {2, 2x2, 3x2, 13}
Apart from 2x3x2 (taking 2 from set A) which is the same as 3x2x2(taking 3 from set A); there is nothing which can be repeated. Thus, the total unique product = 20-1 = 25.
C
Question: In the first hour of a two-hour trip, a car traveled 3d kilometers, and in the second hour of the trip, the car traveled one-half that distance. What is the average rate at which the car traveled during the trip, in kilometers per hour?
A. d
B. 1/3*d
C. 1/2*d
D. 5/4*d
Answer: D. 5/4*d
Explanation: Solution:
Lets look at the information given in the question...
Total time travelled = 2 hrs
Distance travelled first hour = 3d
Distance travelled second hour = 3d/2
The question is asking for the avg speed at which the car travels for 2 hrs
We know that avg speed = total distance/total time
Lets place the information given in the question to the formula above = (d+3d/2)/2
= 5/4*d
We find that option D is the answer as it gives the same expression as found in our calculation above. Answer option D.
Question: Walking across campus, a student interviewed a group of students. 25% of the students took a finance class last semester, 53% took a marketing class last semester, and 40% took neither a finance nor a marketing class last semester. What percent of the students in the group took both a finance and a marketing class?
A.60%
B.50%
C.25%
D.18%
Answer: D.18%
Explanation: {Total} = {finance} + {marketing} - {both} + {neither}
100 = 25 + 53 - {both} + 40
{both} = 18%.
Answer: D.
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 sec. What is the length of the fast train?
A.27 7/6
B.27 7/5
C.27 7/3
D.27 7/9
Answer: D.27 7/9
Explanation: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5 = 250/9 = 27 7/9 m.
Answer: D
Question: The sum of three consecutive odd natural numbers, each divisible by 3 is 72. What is the largest among them?
A.21
B.24
C.27
D.36
Answer: C.27
Explanation: Let the 3 consecutive odd numbers each divisible by 3 be X, X+3, X+6
Given, X + X+3 + X+6 = 72
3X = 63
X = 21
The numbers are 21, 24, 27
Therefore the largest number is 27
Answer C.
Question: Which of the following statements must be true?
1) If x/y is a fraction and y has 17 as one of its prime factors then the resulting decimal will be terminating
2) If x/y is a fraction where 2 and 5 are the only two prime factors of y then the resulting decimal will be terminating.
3) If x/y is a fraction such that y=(10^n -1) for n≥1 then the repeating decimals in the result would just be the digits of the numerator.
4) If the interest is accounted annually then for the first compounded interest would be equal to the simple interest.
A.2,3
B.2,3,4
C.1,2,3
D.2,4
Answer: B.2,3,4
Explanation: Statement 3: Let's try some examples:
1/9 = 0.11111.....
23/99 = 0.2323232323.....
61/999 = 0.061061061061061.....
Statement 3 is always true.
Statement 4: I think first year is implied by the word "first".
Let's take principal = 100 and interest rate = 20%
Compound interest after 1 year = 100*(1+1/5) - 100 = 20
Simple interest after 1 year = (100*20*1)/100 = 20
Let's take principal = 300 and interest rate = 50%
Compound interest after 1 year = 300*(1+1/2) - 300 = 150
Simple interest after 1 year = (300*50*1)/100 = 150
Statement 4 is always true.
Answer (B).
Question: There are 5 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 16 other amateurs, what is the total number of chess games possible to be played in the tournament?
A.10
B.20
C.40
D.60
Answer: C.40
Explanation: Each person is one participant of 4 games. So there are in all 16*5 = 80 instances of one participant games. But each game has 2 participants so total number of games = 80/2 = 40
C
Question: The unit digit in the product (293 * 567 * 917 * 343) is:
A.2
B.1
C.6
D.8
Answer: B.1
Explanation: Explanation:
Unit digit in the given product = Unit Digit in (3*7*7*4) = 1
ANSWER: B
Question: Three people are playing cards. What is the probability that a card drawn from a pack of 52 cards will be a diamond or a king?
A.2/11
B.2/9
C.4/13
D.3/14
Answer: C.4/13
Explanation: Here, n(S) = 52
There are 13 cards of diamond (including one king) and there are 3 more kings.
Let E = event of getting a diamond or a king.
Then, n(E) = (13 + 3) = 16
P (E) = 16 / 52 = 4/13
C
Question: What is the sum of the prime factors of1549 and the prime factors of 5049?
A.73
B.63
C.65
D.74
Answer: A.73
Explanation: The prime factors of 5049 are 3*3*3*11*17
The prime factors of 1549 are 3*3*7*23
3+3+3+3+3+11+17+7+23 = 73. A is the correct answer
Question: Look at this series: 14, 28, 20, 40, 32, 64, ... What number should come next?
A.52
B.56
C.96
D.128
Answer: B.56
Explanation: Explanation: This is an alternating multiplication and subtracting series: First, multiply by 2 and then subtract 8.
Answer: Option B
Question: 96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
A.76
B.76
C.42
D.58
Answer: C.42
Explanation: x/7 = y/9
=> x:y
= 7:9
7/16 * 96
= 42
Answer: C
Question: How many 1/6s are there in 37 1/2?
A.225
B.425
C.520
D.600
Answer: A.225
Explanation: Required number = (75/2)/(1/6)
= (75/2 x 6/1)
= 225.
ANSWER:A
Question: P works 25% more efficiently than Q and Q works 50% more efficiently than R. To complete a certain project, P alone takes 50 days less than Q alone. If, in this project P alone works for 60 days and then Q alone works for 135 days, in how many days can R alone complete the remaining work?
A.50 days
B.92.4 days
C.100 days
D.150 days
Answer: B.92.4 days
Explanation: P works 25% more efficiently than Q: Something that takes Q 5 days, takes P 4 days
Q works 50% more efficiently than R: Something that takes R 7.5 days, takes Q 5 days
P alone takes 50 days less than Q: For every 4 days P works, Q has to work an extra day. Hence P alone can do it in 200 days and Q alone in 250 days and hence R alone in 385 days
P works for 60 days--> 60/200 work done => 30%
Q works for 135 days--> 135/250 work done => 54%
24% work left ... R alone will take 24% * 385 = 92.4 days
Answer is (B)
Question: Carina has 115 ounces of coffee divided into 5- and 10-ounce packages. If she has 2 more 5-ounce packages than 10-ounce packages, how many 10-ounce packages does she have?
A.5
B.7
C.6
D.4
Answer: B.7
Explanation: Lets say 5 and 10 ounce packages be x and y respectively.
Given that, 5x+10y=115 and x=y+2. What is the value of y.
Substituting the x in first equation, 5y+10+10y=85 ->y=105/15.=7
B
Question: A can complete a work in 12 days with a working of 8 hours per day. B can complete the same work in 8 days when working 10 hours a day. If A and B work together, working 8 hours a day, the work can be completed in --- days.
A.5 5⁄11
B.4 5⁄11
C.6 4⁄11
D.6 5⁄11
Answer: A.5 5⁄11
Explanation: Explanation :
A can complete the work in 12 days working 8 hours a day
=> Number of hours A can complete the work = 12×8 = 96 hours
=> Work done by A in 1 hour = 1/96
B can complete the work in 8 days working 10 hours a day
=> Number of hours B can complete the work = 8×10 = 80 hours
=> Work done by B in 1 hour = 1/80
Work done by A and B in 1 hour = 1/96 + 1/80 = 11/480
=> A and B can complete the work in 480/11 hours
A and B works 8 hours a day
Hence total days to complete the work with A and B working together
= (480/11)/ (8) = 60/11 days = 5 5⁄11 days
Answer : Option A
Question: If a certain sample of data has a mean of 20.0 and a standard deviation of 4.0, which of the following values is more than 2.5 standard deviations from the mean?
A. 12.0
B. 13.5
C. 17.0
D. 23.5
Answer: A. 12.0
Explanation: The standard deviation is 4. 2.5 standard deviations, which is just 2.5 x 4.0 is 10.0. The only answer more than 10.0 away from the mean is A.
Question: A group of 7 teenagers recently visited the Japanese Restaurant. The total bill for the meal, including 20% gratuity, came to $840. On average, how much did the meal of each individual cost before gratuity?
A.$160
B.$96
C.$90
D.$10
Answer: D.$10
Explanation: 7 teenagers - so total 7 people
The bill $840 includes 20% gratuity... so the actual cost of dinner was $700
Now, the cost per person will be $700/7 which is $10
Option D
Question: If 48 machine can finish a job in 80 days, then how many more machines would be needed to finish the job in one -fifth less time?
A.a. 4
B.b. 8
C.c. 10
D.d. 12
Answer: D.d. 12
Explanation: You might think of this in a management context - we can use the principle of 'person-hours' to solve any problem where we have identical workers. So, using simpler numbers, suppose you know that 6 identical employees, working simultaneously, would finish a job in 5 hours. Then that job requires 6*5 = 30 total hours of person-work. If instead you wanted the job done in 3 hours, you'd assign 30/3 = 10 employees to do the job, because you want to get a total of 30 hours of work from the employees.
We can solve this problem identically. If 48 machines (identical ones, I assume) work simultaneously for 80 days, they will do a total of 48*80 machine-days of work. So the job requires 48*80 days of machine work in total. We instead want the job done in 1/5 less time, so in 64 days. So we'll need 48*80/64 = 60 machines, or 12 additional machines.
D
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 100 kmph. Find the speed of the boat in still water and the speed of the stream?
A.10 kmph
B.20 kmph
C.16 kmph
D.18 kmph
Answer: B.20 kmph
Explanation: Speed of the boat in still water = (60+100)/2 = 80 kmph. Speed of the stream = (100-60)/2 = 20 kmph.Answer: B
Question: By travelling at 40 kmph, a person reaches his destination on time. He covered two-third the total distance in one-third of the total time. What speed should he maintain for the remaining distance to reach his destination on time?
A.20
B.99
C.88
D.77
Answer: A.20
Explanation: Let the time taken to reach the destination be 3x hours. Total distance = 40 * 3x = 120x km
He covered 2/3 * 120x = 80x km in 1/3 * 3x = x hours So, the remaining 40x km, he has to cover in 2x hours. Required speed = 40x/2x = 20 kmph.
Answer: A
Question: How many numbers between 100 and 600 are divisible by 2, 3, and 7 together?
A.112
B.77
C.267
D.12
Answer: D.12
Explanation: Explanation:
As the division is by 2, 3, 7 together, the numbers are to be divisible by: 2*3*7 = 42
The limits are 100 and 600
The first number divisible is 42*3 = 126
To find out the last number divisible by 42 within 600:
600/42 = 14.28
Hence, 42*14 = 588 is the last number divisible by 42 within 600
Hence, total numbers divisible by 2, 3, 7 together are (14 – 2) = 12
ANSWER: D
Question: the average distance between the sun and a certain planet is approximatly 2.7 10^10 inches. which of the following is the closest to the average distence between sun and the planet in kelometers? (1 km is approx 3.9 x 10^4 inches)
A.6.9 x(10)^6
B.6.9 x(10)^4
C.6.9 x(10)^3
D.6.9 x(10)^5
Answer: D.6.9 x(10)^5
Explanation: No need to solve entire problem.
Distance in KM = 27*(10)^10/39*(10)^4 which is -270*(10)^9/39*(10)^4 = 6.9 x(10)^5
Answer : D
Question: A company D has 10 percent of the employees are secretaries and 20 percent are salespeople. If there are 70 other employees of Company D, how many employees does Company D have?
A.100
B.162
C.180
D.152
Answer: A.100
Explanation: Let the total number of employees in the company be x
% of secretaries = 10%
% of salespeople = 20%
% of of employees other than secretaries and salespeople = 100 -30 = 70%
But this number is given as 70
so 70% of x = 70
x = 100
Therefore there a total of 100 employees in the company D
Correct answer - A
Question: A train 160m long is running at 30kmph. In how much time will it pass a platform 120m long?
A.15.89 seconds
B.24.36 seconds
C.15.96 seconds
D.14.93 seconds
Answer: D.14.93 seconds
Explanation: Distance travelled = 160 + 120m = 280mSpeed = 30 * 5/8 = 75/4mTime = 280 * 4/75 = 14.93 SecondsAnswer : D.
Question: A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is
A.3220
B.4830
C.5120
D.6420
Answer: C.5120
Explanation: Solution
Clearly,l = (48 - 16)m = 32 m
‹=›b = (36 -16)m = 20 m,
‹=›h = 8 m..
Volume of the box =(32x20x8) m3	= 5120 m3.
Answer C
Question: What is the difference between the place value of 7 in the numeral 894577?
A.83
B.77
C.53
D.63
Answer: D.63
Explanation: Difference between the place values of 7 =70-7 = 63
Answer is D
Question: Pipe A can fill a tank in 8 hours, pipe B in 4 hours and pipe C in 24 hours. If all the pipes are open, in how many hours will the tank be filled?
A.3.4 hr
B.2.4 hr
C.2 hr
D.2.8 hr
Answer: B.2.4 hr
Explanation: Part filled by pipe A in 1 hour = 1/8
Part filled by pipe B in 1 hour = 1/4
Part filled by pipe C in 1 hour = 1/24
Part filled by pipe A, pipe B and pipe C in 1 hour = (1/8)+(1/4)+(1/24)=1024
i.e, pipe A, pipe B and pipe C together can fill the tank in 24/10 hours = 2.4 hour
Answer is B
Question: W=√[2√63 + 2/(8+3√7)] =
A.8 + 3√7
B.4 + 3√7
C.8
D.4
Answer: D.4
Explanation: In these type of question u multiply the nominator and denominator with conjugate...Conjugate of 8 +3sqrt(7) is 8 -3sqrt(7)
sqrt[2sqrt(63) + 2 { 8 - 3sqrt(7)}/{64 - 63}]
W=sqrt[2sqrt(63) +16 - 2sqrt(63)] =4
Answer is 4.D
Question: If the units digit of n^31 is 7, which of the following could be the value of n?
I. n = 41
II. n = 43
III. n = 47
A.Only I
B.Only II
C.Only III
D.I and II
Answer: B.Only II
Explanation: I tried in this way.
Given n^31 units digit is 7.
If at all we have to get 7 as units digits only 3 and 7 series has 7
3^! = 3 , 3^2 = 9 , 3^3 = 27 , 3^4 = 81
7^1 = 7, 7^2 = 49 , 7^3 = 3 (units ) , 7^4 = 1 (units)
We have n^31 - then divide 31 by 4 = reminder 3.
Then we have for only 7^3 - we have units digit as 3.
Hence 47^31 = 7 (units).
Option B is correct answer , and with 41^31 we always get 1 as units digit and 43^31 - we get units as 3.
Question: .
On dividing a number by 357, we get 37 as remainder. On dividing the same number 17, what will be the remainder ?
A.0
B.3
C.5
D.3
Answer: D.3
Explanation: Let x be the number and y be the quotient. Then,
x = 357 x y + 37
= (17 x 21 x y) + (17 x 2) + 3
= 17 x (21y + 2) + 3)
Required remainder = 3.
Answer: Option D
Question: The value of 1/(1-x) + 1/ (1+x) + 2/(1+x^2) + 4/(1+x^4)
A.8/(1-x^8)
B.4x/(1+x^2)
C.4/(1-x^6)
D.4/(1+x^4)
Answer: A.8/(1-x^8)
Explanation: Highlighted part has mistake as the exponent of x must be 4 in last term
CORRECT QUESTION ISThe value of 1/(1-x) + 1/(1+x) + 2/(1+x^2) + 4/(1+x^4) = ?
Solution is as mentioned below...
one more way that could get the answer in the type of eqn and choices given is to substitute some value for x...
0 would be better as the eq has constant term free of term 'x'..
the Eq gives us 8 as the ans , as also only choice A..
Question: What is the tens digit of 36^5?
A.1
B.7
C.5
D.3
Answer: D.3
Explanation: 36^5 = 6^7
(6^2)=6*6 = 36
(6^3)= 36*6 = .16
(6^4)= .16*6 = ..96
(6^5) = ..96*6 = ..76
(6^6) = ..76*6 = ...56
(6^7) = ....56*6 = ....36
If you see there is a pattern here in tens digits 3,1,9,7,5,3,1 and so on...
Continue the pattern up to 6^7 ( dont actually calculate full values) and answer is D: 3
Question: For any integer k greater than 1, the symbol k* denotes the product of all integers between 1 and k, inclusive. If k* is a multiple of 945 what is the least possible value of k?
A.5
B.7
C.9
D.11
Answer: C.9
Explanation: 945 = 3*3*3*5*7
Thus k must include numbers at least up to the number 9 so that there are at least three appearances of 3 (that is: 3, 6, and 9).
The answer is C.
Question: Find the compound interest accrued on an amount of Rs.14,800 at 13.5% p.a at the end of two years. (Round off your answer to nearest integer?
A.2828
B.2338
C.377
D.4266
Answer: D.4266
Explanation: CI = 14800{ [ 1 + 13.5/100]2 - 1 }
= 14800 { [1 + 27/200]2 - 1
= 14800 { 2 + 27/200}{27/200}
= (74)[2 + 27/200](27) =
1998[2 + 27/200] = 3996 + 269.73 = Rs. 4266.Answer: D
Question: A couple who own an appliance store discover that if they advertise a sales discount of 10% on every item in the store, at the end of one month the number of total items sold increases 25%. Their gross income from sales for one month increases by what percent?
A.5%
B.7.5%
C.10%
D.12.5%
Answer: D.12.5%
Explanation: Let P be the original price and let x be the number of items sold originally.
The original income is P*x.
After the changes, the income is 0.9P*1.25x = 1.125*(P*x), an increase of 12.5%.
The answer is D.
Question: If $ 5,000 is invested in an account that earns 12% interest compounded semi-annually, then the interest earned after one year would be how much greater than if the $ 5,000 had been invested at 8% simple yearly interest?
A.$ 4
B.$ 8
C.$ 12
D.$ 16
Answer: C.$ 12
Explanation: Solution
Amount (CI) = P+(1+r/n)^nt = 5000+(1+0.12/2)^2= 5412
Amount (SI) = P+PTR/100 = 5000+(5000*1*12/100)=5400
Difference = 5412-5400=12 $
C
Question: If you roll a fair-sided die twice, what is the probability of getting a (4.4) double?
A.1/2
B.1/4
C.1/12
D.1/3!
Answer: D.1/3!
Explanation: total no. in two dice (1,1) ,(2,2) .....(6,)
Total number of events= 6*6
Total events of getting same pair(4, 4) = 6
Probability= 6/6*6= 1/6=1/3!
D
Question: A man misses a bus by 40 minutes if he travels at 30 kmph. If he travels at 40 kmph, then also he misses the bus by 10 minutes. What is the minimum speed required to catch the bus on time?
A.17 kmph
B.45 kmph
C.17 kmph
D.19 kmph
Answer: B.45 kmph
Explanation: Let the distance to be travelled to catch the bus be x km
x/30 - x/40 = 30/60 => (4x - 3x)/120 = 1/2 => x = 60 km
By traavelling 30 kmph time taken = 60/30 = 2 hours
By taking 2 hours, he is late by 40 min. So, he has to cover 60 km in at most speed = 60/(4/3)
= 45 kmph.
Answer: B
Question: A motorist travel to a place 150 km away at an average speed of 120 km/hr and returns at 30 km/hr.His average speed for the whole journey in km/hr is
A.36 km/hr
B.37 km/hr
C.45 km/hr
D.48 km/hr
Answer: D.48 km/hr
Explanation: Explanation:
Average speed will be
2xy/x+y km/hr
= {2(120)(30)}/{120+30} km/hr
= 48 km/hr
Answer: Option D
Question: A can do a work in 7 days B in 12 days and C in 5 days. If they work on it together then in how many days required to complete the work?
A.420/177
B.420/179
C.410/87
D.90/14
Answer: B.420/179
Explanation: Person ( A ) ( B ) ( C ) (A+B+C)
Time - ( 7 ) ( 12 ) ( 5 )
Rate - (60) (35) ( 84 ) (179)
Work - (420) (420) (420) (420)
therefore A+B+C requires (420/179) days to complete entire work
= 420/179
Answer is B
Question: 2, 6, 12, 20, 30, 42, 56, ?
A.84
B.37
C.72
D.35
Answer: C.72
Explanation: C
72
The pattern is 1 × 2, 2 × 3, 3 × 4, 4 × 5, 6 × 7, 7 × 8,....
Question: 85% of a number is added to 24, the result is the same number. Find the number?
A.338
B.277
C.160
D.882
Answer: D.882
Explanation: (85/100) * X + 24 = X
3X = 480
X = 160
Answer:D
Question: The sum of a number and its reciprocal is one-eighth of 34. What is the product of the number and its square root?
A.8
B.27
C.32
D.42
Answer: A.8
Explanation: Let the number be x. Then,
x + 1/x = 34/8
8x2 - 34x + 8 = 0
4x2 - 17x + 4 = 0
(4x - 1)(x - 4) = 0
x = 4
required number = 4 * √4 = 4 * 2 = 8.
ANSWER:A
Question: A man covers a certain distance C in a train. If the train moved 4km/hr faster, it would take 30 min less. If it moved 2km/hr slower, it would take 20 mins more. Find the distance?
A.200 km
B.50 km
C.20 km
D.60 km
Answer: D.60 km
Explanation: Not really. When you solve the 2 equation above, you get,
6T-4/3 = 5R/6 from simplifying equation 1
4T-2=R/2 from simplifying equation 2
You can now multiply equation 2 by 5 to get
5(4T-2=R/2 ) = 20T-10=5R/2 and then subtract this new equation from equation 1 to get T=3, followed by R=20 to give you distance C= R*T=20*3=60 km.D
Question: Which number is the odd one out?
159
642
693
537
289
582
A.916
B.345
C.895
D.642
Answer: D.642
Explanation: D
642
In the rest there is the same difference between each digit, eg: 6 (Ã¢â‚¬â€œ2) 4 (Ã¢â‚¬â€œ2)2
Question: sue has 3 apples. Billy has 5 apples. If billy steals all of sues apples and eats 4 how many does he have left?
A.2
B.5
C.6
D.4
Answer: D.4
Explanation: 4 D
Question: A thief goes away with a SANTRO car at a speed of 40 kmph. The theft has been discovered after half an hour and the owner sets off in a bike at 50 kmph when will the owner over take the thief from the start?
A.2
B.5
C.7
D.5
Answer: A.2
Explanation: Explanation:
|-----------20--------------------|
50 40
D = 20
RS = 50 – 40 = 10
T = 20/10 = 2 hours
Answer: Option A
Question: 11^9 - 11^2 is approximation of which of the following?
A.9^7
B.9^8
C.9^9
D.11^9
Answer: D.11^9
Explanation: => Since 9^2 is a small number compared to 11^9, it can be disregarded. Thus, 11^9-11^2=11^9 is derived and the answer is D.
Question: (?) + 3699 + 1985 - 2047 = 31111
A.27460
B.27474
C.27485
D.27490
Answer: B.27474
Explanation: x + 3699 + 1985 - 2047 = 31111
x + 3699 + 1985 = 31111 + 2047
x + 5684 = 33158
x = 33158 - 5684 = 27474.
B)
Question: A man takes
5
5 hours
45
45 min in walking to a certain place and riding back. He would have gained
2
2 hours by riding both ways. The time he would take to walk both ways is
A.11 hrs
B.8 hrs 45 min
C.7 hrs 45 min
D.9 hrs 20 min
Answer: C.7 hrs 45 min
Explanation: Explanation:
Solution 1Given that time taken for riding both ways will be 22 hours lesser than the time needed for waking one way and riding back.
Therefore,
time needed for riding one way = time needed for waking one way - 22 hours
Given that time taken in walking one way and riding back =5=5 hours 4545 min
Hence, the time he would take to walk both ways
=5=5 hours 4545 min + 22 hours
=7=7 hours 4545 min
Answer is C
Question: Henry completes a piece of work in 640 days, Rose completes the same work in 960 days. If both of them work together, then the number of days required to complete the work is?
A.384
B.385
C.386
D.387
Answer: A.384
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 640 × 960/1600 = 384 days
Answer is A
Question: What are the next two letters in the following series and why?
W A T N T L I T F S _ _
*Hint : Look into the title of the Riddle
A.A and W
B.A and E
C.B and W
D.A and C
Answer: A.A and W
Explanation: A
A and W.
The letters are the first letters of the words in the question. Thus, the next two letters are A and W.
Question: An outlet pipe empties a tank which is full in 8 hours. If the inlet pipe is kept open, which lets water in at the rate of 8 litres/min then outlet pipe would take 4 hours longer. Find the capacity of the tank.
A.8600 litres
B.200 litres
C.12800 litres
D.11520 litres
Answer: D.11520 litres
Explanation: Let the rate of outlet pipe be x liters/hour;
Rate of inlet pipe is 8 litres/min, or 8*60 = 480 liters/hour;
Net outflow rate when both pipes operate would be x-480 liters/hour.
Capacity of the tank = x*8 hours = (x-480)*(8+4) hours
8x=(x-480)*12 --> x=1440 --> capacity = 8x = 11520 liters.
Answer: D.