RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Seven students are trying out for the school soccer team, on which there are three available positions: fullback, sweeper, and goalie. Each student can only try out for one position. The first two students are trying out for fullback. The next two students are trying out for sweeper. The remaining three students are trying out for goalie. However, the fourth student will only play if the second student is also on the team, and the third student will only play if the fifth student is on the team. How many possible combinations of students are there to fill the available positions?
A.3
B.5
C.7
D.10
Answer: B.5
Explanation: Based on the information in the prompt, we have seven players (A,B,C,D,E,F,G). We're asked for the total groups of 3 that can be formed with the following restrictions:
1) Only 1 player per position
2) A and B are trying out for fullback
C and D are trying out for sweeper
E, F and G are trying out for goalie
3) D will only play if B is also on the team
C will only play if E is also on the team
The big restrictions are in the two 'formal logic' rules....
-We can put E with ANYONE, but we can only put in C if E is ALSO there.
-We can put B with ANYONE, but we can only put in D if B is ALSO there.
By extension....
D can NEVER be with A (because then B would not be in the group)
C can NEVER be with F or G (because then E would not be in the group)
As such, there are only a few possibilities. We can have...
ACE
BCE
BDE
BDF
BDG
Final Answer:5 ANSWER:B
Question: The cricket team of 11members is 26yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ?
A.20
B.21
C.23
D.26
Answer: C.23
Explanation: Let the average age of the whole team be x years.
11x - (26 + 29) = 9 (x - 1)
=> 11x - 9x = 46
=> 2x = 46
=> x = 23.
So, average age of the team is 23 years.
C
Question: An equilateral triangle T2 is formed by joining the mid points of the sides of another equilateral triangle T1. A third equilateral triangle T3 is formed by joining the mid-points of T2 and this process is continued indefinitely. If each side of T1 is 45 cm, find the sum of the perimeters of all the triangles.
A.180 cm
B.220 cm
C.240 cm
D.270 cm
Answer: D.270 cm
Explanation: We have 45 for first triangle, when we join mid-points of first triangle we get the second equilateral triangle then the length of second one is 22.5 and continues.
So we have 45,22.5,11.25,...
We have ratio = 1/2, and it is GP type.
Sum of infinite triangle is a/1-r = 45/1-(1/2) = 90
Equilateral triangle perimeter is 3a = 3*90 = 270.
So option D.
Question: If a man buys 10 lollipops for $80 and sold them for $4 dollars determine his loss.
A.50
B.40
C.70
D.80
Answer: B.40
Explanation: Cost of 10 lollipops = $80
Sold each lollipop for $4
So he sold 10 lollipops for $(10 × 4) = $40
Loss = $(80 – 40) = $40
answer :B
Therefore, loss = $ 40.
Question: What should come in place of the question mark (?) in the following equation?
47(7.5) ÷ 47 3⁄2 × 4 7-3 = (√47)?
A.3
B.2 1⁄2
C.6
D.3.5
Answer: C.6
Explanation: (47)3 = [(47)1/2]6
Answer C
Question: A 250 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
A.230
B.288
C.250
D.256
Answer: C.250
Explanation: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 250)/9 = 500/9 => x = 250.
Answer: C
Question: a men walked 30m west 5m south 10m west 35m north to tollgate find the distance from the start gate?
A.40m
B.50m
C.60m
D.70m
Answer: B.50m
Explanation: The man is toward West = 30+10 = 40m
The man is towards North = 35m(N) - 5m(S) = 30m
Therefore, the distance from the start gate = sqrt(40^2+30^2)
= sqrt(2500) = 50m
ANSWER:B
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 4 kmph, what is the time taken to row a distance of 60 km downstream?
A.30/18 hours
B.37/13 hours
C.80/13 hours
D.5/2 hours
Answer: D.5/2 hours
Explanation: Speed downstream = 20 + 4 = 24 kmph.
Time required to cover 60 km downstream
= d/s = 60/24
= 5/2 hours.
Answer: D
Question: The average of 11 numbers is 10.9. If the average of first six is 10.5 and that of the last six is 11.4 the sixth number is?
A.11.9
B.11.0
C.11.2
D.11.5
Answer: D.11.5
Explanation: 1 to 11 = 11 * 10.9 = 119.9
1 to 6 = 6 * 10.5 = 63
6 to 11 = 6 * 11.4 = 68.4
63 + 68.4 = 131.4 – 119.9 = 11.5
6th number = 11.5
Answer:D
Question: X and Y invested in a business. They earned some profit which they divided in the ratio of 1 : 3. If X invested Rs.10,000. the amount invested by Y is
A.Rs.30,000
B.Rs.50,000
C.Rs.60,000
D.Rs.80,000
Answer: A.Rs.30,000
Explanation: Solution
Suppose Y invested Rs.y
Then,	10000 /y = 1 / 3
â€¹=â€º y=(10000Ã—3 / 1).
â€¹=â€º y=30000.
Answer A
Question: The average of first six prime numbers which are odd is?
A.7.55
B.9.33
C.6.56
D.8.23
Answer: B.9.33
Explanation: Explanation:
Sum of first 6 prime no. which are odd = 56
Average = 56/6 = 9.33
Answer:B
Question: In a certain city, 75 percent of the households have cable television, and 60 percent of the households have videocassette recorders. If there are 150,000 households in the city, then the number of households that have both cable television and videocassette recorders could be any number from:
A.52,500 to 90,000 inclusive
B.37,500 to 120,000 inclusive
C.60,000 to 90,000 inclusive
D.72,500 to 120,000 inclusive
Answer: A.52,500 to 90,000 inclusive
Explanation: The maximum percentage with both is 60% which is 90,000 households.
This means that every household with a recorder also has cable television.
The minimum percentage with both is 35% which is 52,500 households.
This means that 25% of households have only recorders but not cable television.
The other 35% of households with recorders have cable television.
The answer is A.
Question: A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
A.4800
B.4991
C.5004
D.5000
Answer: B.4991
Explanation: Explanation:
Let the sale in the sixth month =x
Then 6435+6927+6855+7230+6562+x/6=6500
x=39000−34009=4991
ANSWER IS B
Question: Two pipes can fill a tank in 10 minutes and 15 minutes. An outlet pipe can empty the tank in 45 minutes. If all the pipes are opened when the tank is empty, then how many minutes will it take to fill the tank?
A.30 minutes
B.8 minutes
C.15 minutes
D.10 minutes
Answer: B.8 minutes
Explanation: Part of the filled by all the three pipes in one minute
= 1/10 + 1/15 - 1/45 = (9 + 6 - 2)/90 = 13/90
So, the tank becomes full in 8 minutes.
Answer: B
Question: An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq m?
A.Rs.4082.29
B.Rs.4082.27
C.Rs.4082.26
D.Rs.4082.40
Answer: D.Rs.4082.40
Explanation: Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 * 7)
= 315 (13 - 0.04)
= 4095 - 12.6
= Rs.4082.40
Answer: D
Question: if ratio of total amount and principal amount is 3:2.rate of interest 5%.calculate the time.
A.10
B.6
C.5
D.8
Answer: A.10
Explanation: s.i=p*r*t/100
(total amount-p)/p=5t/100
t.a/p-1=5t/100
1.5-1=5t/100
50=5t
t=10
answer A
Question: How many real roots does the equation x^2y+16xy+62y=0 have if y < 0?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: x^2y+16xy+62y=0
=> y ( x^2 + 16x + 62) = 0
=> y (x+8)^2 = 0
if y<0 , then x=-8
So although there are 2 factors , they are the same x=-10 .
The equations has 2 distinct real root .
Answer C
Question: If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 4 and 5K + 1 is 63, what is the value of K?
A. 22 10/11
B. 15 3/4
C. 22
D. 23
Answer: A. 22 10/11
Explanation: K + 2K +3 + 3K - 4 + 5K +1 = 11K
(11K -1)/4 = 63
11K = 63 * 4 = 252
K = 252 / 11 = 22 10/11
Answer A.
Question: A and B together can complete a work in 12 days. A alone can complete it in 20 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work?
A.11 days
B.77 days
C.15 days
D.18 days
Answer: C.15 days
Explanation: B's 1 day work = (1/12 - 1/20) = 1/30
Now, (A + B)'s 1 day work = (1/20 + 1/60) = 1/15
So, A and B together will complete the work in 15 days.
Answer:C
Question: In digging a pond 30m*10m*5m the volumes of soil extracted will be ?
A.2000 cu.m
B.2500 cu.m
C.15000 cu.m
D.1500 cu.m
Answer: D.1500 cu.m
Explanation: 30*10*5= 1500Answer : D
Question: If the units digit of n^26 is 7, which of the following could be the value of n?
I. n = 41
II. n = 49
III. n = 47
A.Only I
B.Only II
C.Only III
D.I and II
Answer: B.Only II
Explanation: I tried in this way.
Given n^26 units digit is 7.
If at all we have to get 7 as units digits only 3 and 7 series has 7
3^! = 3 , 3^2 = 9 , 3^3 = 27 , 3^4 = 81
7^1 = 7, 7^2 = 49 , 7^3 = 3 (units ) , 7^4 = 1 (units)
We have n^26 - then divide 26 by 4 = reminder 2.
Then we have for only 7^2 - we have units digit as 9.
Hence 47^26 = 7 (units).
Option B is correct answer , and with 41^26 we always get 1 as units digit and 49^26- we get units as 9.
Question: A bag contains 3 red balls, 5 green balls and 6 white balls. A ball is drawn at
random from the box. What is the probability that the ball drawn is either red or green?
A.2/5
B.3/5
C.4/7
D.7/15
Answer: C.4/7
Explanation: Total number of balls = (3 + 5 + 6) = 14.
Therefore, n(S) = 14.
Let E1 = event of drawing a red ball.
and E2 = event of drawing a green ball.
Then, E1 n E2 = f.
P (E1 n E2) = P(E1) + P(E2) = (3/14 + 5/14) = 4/7.
ANSWER:C
Question: Narendra started a business, investing 30000. Six months later, Chandan joined him with 15000. If they make a profit of 10000 at the end of the year, what should be the share of Narendra?
A.Rs.7000
B.Rs.8000
C.Rs.9000
D.Rs.10000
Answer: B.Rs.8000
Explanation: The ratio of their investments = 30000 × 12 : 15000 × 6 = 4 : 1.
:. Narendra’s share on profit of Rs.10000 = 10000 × 4/5 = Rs.8000.
B)
Question: The fraction 101 27/100000 in decimal for is:
A.101.027
B.101.00027
C.101.0027
D.10100027
Answer: B.101.00027
Explanation: 101 27/100000
= 101 + 27/ 100000
= 101 + .00027
= 101.00027
Answer is B.
Question: If 0.4 of a number is equal to 0.07 of another number, the ratio of the numbers i
A.2 : 3
B.7 : 40
C.3 : 20
D.20 : 3
Answer: B.7 : 40
Explanation: Sol.
0.4A = 0.08 B â‡” A / B = 0.07 / 0.40 = 7/40.
âˆ´ A : B = 7 : 40.
Answer B
Question: What is the largest 4 digit number exactly divisible by 48?
A.4676
B.4678
C.9984
D.9504
Answer: C.9984
Explanation: Largest 4 digit number = 9999
9999 ÷ 48 = 208, remainder = 15
Hence largest 4 digit number exactly divisible by 48
= 9999 - 15 = 9984
answer :C
Question: Last year’s receipts from the sale of greeting cards during the week before Mother’s Day totaled $189 million, which represented 9 percent of total greeting card sales for the year. Total greeting card sales for the year totaled how many million dollars?
A.17,010
B.2,100
C.1,890
D.1,701
Answer: B.2,100
Explanation: 9% ---- 189 millions
for 100% => ( 189 * 100% )/9% = 2100.
Option B.
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 70 km downstream?
A.30/83 hours
B.33/13 hours
C.31/13 hours
D.35/13 hours
Answer: D.35/13 hours
Explanation: Speed downstream = 20 + 6 = 26 kmph.
Time required to cover 70 km downstream = d/s = 70/26
= 35/13 hours.
Answer:D
Question: In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. States B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State ?
A.7600
B.8000
C.8400
D.Data inadequate
Answer: B.8000
Explanation: Solution
Let the number of candidates appeared from each State be x.
Then, 7 % of x -6% of x = 80 ⇔ 1% of x = 80 ⇔ x = 80 × 100 = 8000.
Answer B
Question: Starting with 0, a mathematician labels every non-negative integer as one of five types: alpha, beta, gamma, delta, or epsilon, in that repeating order as the integers increase. For instance, the integer 8 is labeled delta. What is the label on an integer that is the sum of an alpha raised to the seventh power and another alpha raised to the seventh power?
A.alpha.
B.beta.
C.gamma.
D.delta.
Answer: A.alpha.
Explanation: Let the two alphas be 5k and 5j.
(5k)^7 + (5j)^7 is a multiple of 5 so it is an alpha.
The answer is A.
Question: if log 6 = 0.778151, the number of digits in 6128 is
A.22
B.39
C.88
D.100
Answer: D.100
Explanation: Explanation:
log(6128) = 128log(6) = 128 × 0.778151 ≈ 99.60
ie, its characteristic = 99
Hence, number of digits in 2128 = 99+1 = 100
Answer: Option D
Question: Martha has the unique talent of being able to guess other people’s height and weight. For every four people that Martha meets, she consistently guesses the people’s correct height three times, and for every five people that she meets, she consistently guesses the people’s correct weight four times. If Martha meets three people and her success rate remains constant, what is the probability that Martha correctly guesses a person’s weight and height at least once?
A.8/27
B.117/125
C.49/81
D.98/125
Answer: B.117/125
Explanation: Probability that she guesses the height correctly P(h)=3/4
Probability that she guesses the weight correctlyP(w)=4/5
Probability that she guesses both weight and height correctly(P(h)*P(w))=3/4 * 4/5= 12/20
Now the Q asks about the probability of this happening atleast once.
We calculate it by finding the probability of not being able to guess in any of the three occasions.
Probability of not being able to guess any no. of times =1-12/20=8/20=2/5
For all three occasions P(A)=2/5 * 2/5 * 2/5=8/125
Probability of the event happening atleast once=1- P(A)=1-8/125=117/125
Ans should be B
Question: A train passes a platform in 16 seconds. The same train passes a man standing on the platform in 10 seconds. If the speed of the train is 54 km/hr, The length of the platform is
A.40
B.50
C.90
D.30
Answer: C.90
Explanation: Speed of the train = 54 km/hr = (54×10)/36 m/s = 15 m/s
Length of the train = speed × time taken to cross the man = 15×10 = 150 m
Let the length of the platform = L
Time taken to cross the platform = (150+L)/15
=> (150+L)/15 = 16
=> 150+L = 15×16 = 240
=> L = 240-150 = 90 meter
Answer is C
Question: The average of first five multiples of 4 is
A.3
B.6
C.9
D.12
Answer: D.12
Explanation: Solution
Average	= 4(1+2+3+4+5) / 5
= 60 / 5.
= 12
Answer D
Question: Subtracting 7% of A from A is equivalent to multiplying A by how much ?
A.0.93
B.9.4
C.0.094
D.94
Answer: A.0.93
Explanation: Answer
Let A - 7% of A = AB.
⇒ (93 x A) / 100 = AB
∴ B = 0.93
Correct Option: A
Question: In a certain game, you pick a card from a standard deck of 52 cards. If the card is a spade, you win. If the card is not a spade, the person replaces the card to the deck, reshuffles, and draws again. The person keeps repeating that process until he picks a spade, and the point is to measure how many draws did it take before the person picked a spade and won. What is the probability that there will be at least three draws involved in a win, i.e. someone picking her first spade on the third draw or later?
A. 1/2
B. 11/16
C. 9/16
D. 13/16
Answer: C. 9/16
Explanation: Probability of picking a spade on any draw = 1/4
Probability of NOT picking a spade on the first draw AND on the second draw = [1-(1/4)] X [1-(1/4)] = 3/4 X 3/4 = 9/16
Answer : C
Question: What is the number that should come in the place of question mark?
1050	420	168	67.2	?
A.29.88
B.10.752
C.4.3008
D.26.88
Answer: D.26.88
Explanation: 1050/2.5 = 420
420/2.5 = 168
168/2.5 = 67.2
so 67.2/2.5 = 26.88
ANSWER:D
Question: A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train ?
A.230 m
B.240 m
C.260 m
D.270 m
Answer: D.270 m
Explanation: Explanation:
Speed = 72*5/18m/sec = 20 m/sec; Time = 26 sec.
Let the length of the train be x metres.
Then,X+250/26=20
x = 270.
ANSWER IS D
Question: Patrick is an avid star gazer and wants to make his own constellation. He is using a star chart that has 7 stars on it and decides that he will draw a continuous line using 3 of those 7 stars to make his constellation. There will be no closed shapes in his constellation. How many possible paths could his contstellation follow?
A.15
B.21
C.97
D.210
Answer: D.210
Explanation: This is a simple permutation calcPermutation calc is: n P r = n! / (n-r)! 4 P 3 = 7!/(7-3)! = 7x6x5x(4x3x2x1)/4!=7X6X5=210 Correct answer is D (210)
Question: if 16 girls take eight hours to complete a task, then how long should 40 girls take to complete the same task?
A.180 min
B.194 min
C.192 min
D.196 min
Answer: C.192 min
Explanation: if 16 girls take eight hours to complete a task, then
40 girls will take 16*480/40 = 192 mins to complete the same task.
ANSWER:C
Question: A car covers a distance of 624 km in 6 ½ hours. Find its speed?
A.104
B.288
C.271
D.276
Answer: A.104
Explanation: 624/6 = 104 kmph
Answer: A
Question: The sum of all the integers k such that –24 < k < 24 is
A.0
B.-2
C.-45
D.-49
Answer: C.-45
Explanation: -23------------------0-----------------23
values upto+23 cancels outwe are left with only -23-22 sum of which is - 45. hence option D.
C
Question: Which of the statements can be dispensed with while answering the above question?
A.A only
B.B only
C.A or C only
D.B or C only
Answer: A.A only
Explanation: Explanation:
Justification:
We can find the code for 'home' from the second and third statements.
For finding the code for 'they', we need the code for 'go' which cannot be determined from the given data.
Clearly, statement A is not necessary.
Answer: A
Question: If six persons sit in a row, then the probability that three particular persons are always together is
A.1/2
B.1/7
C.1/5
D.1/9
Answer: C.1/5
Explanation: Explanation:
Six persons can be arranged in a row in 6! ways. Treat the three persons to sit together as one unit then there four persons and they can be arranged in 4! ways. Again three persons can be arranged among them selves in 3! ways. Favourable outcomes = 3!4! Required probability = 3!4!/6! = 1/5
Answer: C
Question: The average height of 50 pupils in a class is 150 cm. Five of them whose height is 146 cm, leave the class and five others whose average height is 156 cm, join. The new average height of the pupils of the class (in cm) is ?
A.287 cm
B.151 cm
C.276 cm
D.287 cm
Answer: B.151 cm
Explanation: Total height = 150 * 50 = 7500 cm.
New average = [7500 - 5 * 146 + 5 * 156 ] / 50
= 151 cm.
Answer:B
Question: Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
A.2:5
B.3:5
C.4:5
D.7:5
Answer: C.4:5
Explanation: Let the third number be x.
Then, first number = 120% of x =	120x	=	6x
100	5
Second number = 150% of x =	150x	=	3x
100	2
Ratio of first two numbers = 6x	:	3x = 12x : 15x = 4 : 5.
5	2
so the correct answer is option C)
Question: If the first day of a year (other than leap year) was Friday, then which was the last day of that year?
A.Saturday
B.Friday
C.Tuesday
D.Monday
Answer: B.Friday
Explanation: Explanation:
Given that first day of a normal year was Friday
Odd days of the mentioned year = 1 (Since it is an ordinary year)
Hence First day of the next year = (Friday + 1 Odd day) = Saturday
Therefore, last day of the mentioned year = Friday
Answer: Option B
Question: On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 5 cups of tea. Last week Mo drank a total of 36 cups of tea and hot chocolate together. If during that week Mo drank 14 more tea cups than hot chocolate cups, then how many rainy days were there last week?
A.5
B.3
C.4
D.2
Answer: D.2
Explanation: T= the number of cups of tea
C= the number of cups of hot chocolate
T+C = 36 T-C=14 -> T= 25. C=11.
Mo drinks 5 cups of tea a day then number of days that are not rainy = 25/5 = 5
So number of rainy days = 7-5 = 2
D is the answer.
Question: If x and y are integers such that x^2-2x+2y+4=2x^2-3x+y-2, we can deduce that y is
A.not an even
B.an even
C.a perfect square
D.an odd
Answer: B.an even
Explanation: x^2 - 2x + 2y + 4 = 2x^2 - 3x + y - 2
y = x^2 - x - 6
y = (x-3)(x+2) (Note that one factor is even and one factor is odd.)
Then y must be even.
The answer is B.
Question: Divide Rs. 1600 among A, B and C so that A receives 1/4 as much as B and C together and B receives 3/4 as A and C together. A's share is?
A.350
B.375
C.320
D.530
Answer: C.320
Explanation: A+B+C = 1600
A = 1/4(B+C); B = 3/4(A+C)
A/(B+C) = 1/4
A = 1/5 * 1600 => 320
Answer: C
Question: Let us say that a table tennis tournament was going on with knock out terms which means the one who loses the match is out of the tournament. 100 players took part in that tournament.
How many matches were played?
A.88
B.99
C.50
D.85
Answer: B.99
Explanation: B
The number of matches will always sum up to one less than the number of players in a knock out tournament. You may calculate it in any manner. Thus 99 matches were played.
Question: In a certain game, you perform three tasks. You flip a quarter, and success would be heads. You roll a single die, and success would be a six. You pick a card from a full playing-card deck, and success would be picking a Hearts card. If any of these task are successful, then you win the game. What is the probability of winning?
A.1/48
B.5/16
C.11/12
D.11/16
Answer: D.11/16
Explanation: First lets get the overview
Event 1(A) = Flipping the quarter( Probability of both winning/loosing = 1/2)
Event 2(B) = Rolling a dice( Probability of winning = 1/6 ;Probability of loosing= 1 - 1\6 =5\6)
Event 3(C) = Drawing a card( SPADES) Probability of winning = 13/52=3/4 ;Probability of loosing= 1 - 3/4 =1/4)
So now as above we have three events A,BC.
1st method(This is lengthy method)
Possible cases in which it's a win( the highlighted green event is a win and red is loose.
1.ABC= 1/2*5/6*3/4
OR
2.ABC= 1/2*1/6*3/4
OR
3.ABC= 1/2*5/6*1/4
OR
4.ABC= 1/2*1/6*3/4
OR
5.ABC= 1/2*5/6*1/4
OR
6.ABC= 1/2*5/6*1/4
OR
7.ABC= 1/2*1/6*1/4
As we now OR means add
Adding up all of them we'll get the probability of winning ie 11/16
Answer : D
Question: Mangala completes a piece of work in 10 days, Raju completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is
A.7 days
B.8 days
C.9 days
D.10 days
Answer: B.8 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 × 40/50 = 8 days.
B
Question: In the xy-coordinate system, if (m, n) and (m + 2, n + k) are two points on the line with the equation x = 2y + 3, then k =
A.1/2
B.1
C.2
D.5/2
Answer: B.1
Explanation: Since (m, n) and (m + 2, n + k) are two points on the line with the equation x = 2y + 5 they should satisfy m=2n +3 and m+2 =2 *(n+k)+3.
By 1st equation we have m-2n=3 and by 2nd equation m-2n = 2k+1 --->3 =2k+1 --->k=1.
The answer is, therefore, (B).
Question: Mrs. Rodger got a weekly raise of $145. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.
A.$225
B.$165
C.$234
D.$145
Answer: D.$145
Explanation: D
$145
Let the 1st paycheck be x (integer).
Mrs. Rodger got a weekly raise of $ 145.
So after completing the 1st week she will get $ (x+145).
Similarly after completing the 2nd week she will get $ (x + 145) + $ 145.
= $ (x + 145 + 145)
= $ (x + 290)
So in this way end of every week her salary will increase by $ 145.