RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The radius of a circle is increased by 1%. Find how much % does its area increases?
A.2.01
B.2.08
C.2.065
D.2.04
Answer: A.2.01
Explanation: r = 100 r = 101
r2 = 10000 r2 = 10201
10000 ---- 201
100 ---- ? => 2.01%
Answer:A
Question: At a circular table for seven will sit five adults and two small children. The two children will sit next to each other, and the two parents of the children will sit next to the children so that there is one parent on each side of the two children. If rotating their positions around the table is not considered changing the arrangement, in how many different ways can the seven people be arranged around the table.
A.16
B.24
C.32
D.48
Answer: B.24
Explanation: Consider the two parents and two children as one unit.
Then there are three adults and one family unit.
The number of ways 4 can form a line is 4!
Around a circular table, there would be 4 rotations so we divide this number by 4.
There are 3! ways for 4 to sit around the circular table.
Then the two children have two options and the two parents have two options.
Then the total number of ways is 3!*2*2= 24
The answer is B.
Question: A coin has two sides. One side has the number 1 on it and the other side has the number 2 on it. If the coin is flipped three times what is the probability that the sum of the numbers on the landing side of the coin will be greater than 3?
A.3/8
B.7/8
C.1/8
D.1/2
Answer: B.7/8
Explanation: There are 8 possible outcomes and only one (111) has a sum equal or less than 3.
P(the sum is greater than 3) = 1 - 1/8 = 7/8
The answer is B.
Question: The number x of cars sold each week varies with the price y in dollars according to the equation x = 800,000 – 50y. What would be the total weekly revenue, in dollars, from the sale of cars priced at $ 14,000?
A.50,000
B.750,000
C.850,000
D.1,400,000,000
Answer: D.1,400,000,000
Explanation: number of cars sold = x=800000-50y
y=14000
x=800000-700000=100000
revenue from 100000 cars=14000*100000=1400000000 D
Question: (x + 7) is a factor in x^2 - mx - 35. What is the value of m?
A.-3
B.-2
C.-4
D.-5
Answer: B.-2
Explanation: I solved the second degree equation and found it like this:
x^2 - mx - 35
(x-5)(x+7)
x=5 or x= -7
Substituting both values for x in the equation we find:
x^2 - mx - 35
=> (-7)^2 - m(-7) = 35
=> 49 + 7m =35
=> 7m = 35-49 = -14
=> m = -2
And with 5, using a similar process we end up with:
(5)^2 - m(5) = 35
-10=5m
m=-2
Ao,ANS B
Question: If the arithmetic mean of p and q is 10 and the arithmetic mean of q and r is 22, what is the value of r-p?
A.20
B.10
C.30
D.24
Answer: D.24
Explanation: Arithmetic mean expression for p and q:
(p+q)/2=10 ; p+q=20 ----eq1
Arithmetic mean expression for q and r:
(q+r)/2=20 ; q+r=44 ----eq2
Subtracting eq1 from eq2 we get: r-p=24
Hence, the correct answer is D
Question: A and B together invested Rs. 12,000 in a business. At the end of the year, out of total profit is Rs. 2,000 B's share was Rs. 500. A's investment was
A.s. 4,500
B.s. 9,000
C.s. 10,500
D.s. 11,250
Answer: B.s. 9,000
Explanation: A+B=12000
total profit=2000
2000-500=1500
1500;500=3:1
then 3*12000/4=9000
ANSWER:B
Question: What is the smallest integer that is the sum of 2 distinct prime integers, each greater than 70 ?
A.147
B.142
C.173
D.144
Answer: D.144
Explanation: A prime number (or a prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself. Here are the first few prime numbers: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, etc.
Immediate two prime numbers after 70 are - 71 and 73
Sum = 71 + 73 = 144
Answer - D
Question: Three is the largest number that can be divided evenly into 27 and the positive integer x, while 10 is the largest number that can be divided evenly into both 100 and x. Which of the following is the largest possible number that could be divided into x and 2400
A.30
B.70
C.210
D.240
Answer: D.240
Explanation: 27 = 3*3*3, and its GCF with x is 3, which implies that x has ONE factor of 3, but not TWO factors of 3.
100 and x have a GCF of 10, which implies that x has ONE factor of 10, but not TWO factors of 10.
Then we want to know what is the largest possible GCF of x and 2100.
Well 2400 = 6 * 4 * 10 * 10
We want x to include as many factors in common with 2100 as possible, to make the GCF with 2100 as big as possible.
We know x has one factor of 3, but not two factors --- that takes the 3.
We know x has one factor of 10, but not two factors --- we can take one of those 10's, but we have to leave the other
No other restrictions, so we can also grab that factor of 7 --- nothing saying that we can't, and it's there for the taking.
6*4*10 = 240
If we allow x to include as many factors as possible, within the constraints given, that is the most x could have in common with 2100.
D
Question: One fourth of one third of two fifth of a number is 14. What will be40% of that number
A.168
B.150
C.180
D.200
Answer: A.168
Explanation: Explanation:
(1/4) * (1/3) * (2/5) * x = 14 then x = 14 * 30 = 420
40% of 420 = 168
Answer: Option A
Question: A goods train runs at the speed of 72 km/hr and crosses a 250 m long platform in 26 sec. What is the length of the goods train?
A.230 m
B.240 m
C.260 m
D.270 m
Answer: D.270 m
Explanation: Speed = 72 * 5/18 = 20 m/sec.
Time = 26 sec.
Let the length of the train be x meters.
Then, (x + 250)/26 = 20
x = 270 m.
ANSWER:D
Question: A and B complete a work in 6 days. A can alone can do it in 10 days. If both can together can do the work in how many days?
A.7
B.3.75
C.2
D.1
Answer: B.3.75
Explanation: 1/6 + 1/10 = 8/30 = 4/15
15/4 = 3.75 days
ANSWER B
Question: In what time will a railway train 60 m long moving at the rate of 36 kmph pass a telegraph post on its way?
A.9
B.8
C.7
D.6
Answer: D.6
Explanation: T = 60/36 * 18/5
= 6 sec
Answer:D
Question: At a certain automobile dealership that sells only Tajima's and Franks, the number of non hybrid Tajima's is 35 less than 3 times the number of hybrid Tajima's. 205 total Tajima's are currently owned by the dealership. If the ratio of hybrid Tajima's to non hybrid Franks is 5:4 and there are 280 total automobiles owned by the dealership, how many hybrid Franks are there?
A.20
B.27
C.48
D.60
Answer: C.48
Explanation: First, I only focus on Tajima's. Let x be hybrid Tajima's and y be non hybrid Tajima's. We know that x + y = 205 and we know that y=3x-35, Therefore we can conclude that x= 60 and y= 145
Next, let a be the number of non hybrid franks, we know the ratio, 60/a = 5/4, therefore a=48
Total number of franks is 75, so 75 - 48 = 27
Took me 47 sec
ANSWER:C
Question: 27 * 27* 27 * 27 = 3^ ?
A.7
B.12
C.5
D.6
Answer: B.12
Explanation: 3^3 * 3^3 * 3^3 * 3^3 = 3^ (3+3+3+3) = 3^12
Answer : 12
Option : B
Question: Find the simple interest on Rs.500 for 9 months at 6 paisa per month?
A.Rs.345
B.Rs.270
C.Rs.275
D.Rs.324
Answer: B.Rs.270
Explanation: Explanation:
I = (500*9*6)/100 = 270
ANSWER IS B
Question: 21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement.
A.7/41
B.9/42
C.3/47
D.3/49
Answer: B.9/42
Explanation: The probability that first toy shows the even number,
=1021=1021
Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.
Hence, probability that second toy shows the even number,
=920=920
Required probability,
=(1021)×(920)=(1021)×(920)
=9/42
B
Question: How many 1/12s are there in 37 1/2?
A.350
B.450
C.500
D.650
Answer: B.450
Explanation: Required number = (75/2)/(1/12)
= (75/2 x 12/1)
= 450.
ANSWER:B
Question: Three people each took 5 tests. If the ranges of their scores in the 5 practice tests were 10, 20 and 32, what is the minimum possible range in scores of the three test-takers?
A.15
B.35
C.50
D.20
Answer: C.50
Explanation: I simply looked at the 3 different possible scores for each individual test: 10,32,20
We have to find the minimum range:
32-10=22
32-20=12
20-10=10
The find the minimum range, you have to make the set of the 5 scores as small as possible.
Which means that 4 of the 5 scores of each individual person is zero.
10*5 = 50.
Answer:C
Question: The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275, then the other is?
A.288
B.277
C.308
D.988
Answer: C.308
Explanation: Other number = (11 * 7700)/275
= 308.
Answer: C
Question: A test has a mean of 220 and a standard deviation of 10, find the corresponding z score for: a) a test score of 232?
A.1.2
B.2.4
C.5
D.5.6
Answer: A.1.2
Explanation: A test has a mean of 220 and a standard deviation of 10,
find the corresponding z score for:
a) a test score of 232,
z(232) = (232-220)/10 = 12/10 = 1.2
Option A
Question: A man's regular pay is $3 per hour up to 40 hours. Overtime is twice the payment for regular time. If he was paid $168, how many hours overtime did he work?
A.8
B.21
C.14
D.12
Answer: A.8
Explanation: Answer is: B
At $3 per hour up to 40 hours, regular pay = $3 x 40 = $120 If total pay = $168, overtime pay = $168 - $120 = $48 Overtime rate (twice regular) = 2 x $3 = $6 per hour => number of overtime hours = $48/$6 = 8
Question: Nikhilesh invested certain amount in three different schemes A, B and C with the rate of interest 10 p.c.p.a., 12 p.c.p.a.and 15 p.c.p.a. respectively. If the total interest accrued in one year was 3200 and the amount invested in scheme C was 150% of the amount invested in scheme A and 240% of the amount invested in scheme B, what was the amount invested in scheme B?
A.8000
B.5000
C.6500
D.Cannot be determined
Answer: B.5000
Explanation: Ratio of Nikhilesh’s investments in different schemes
= 100:150×100/240:150=8:5:12
Now, according to the question,
8k×10/100+5k×12/100+12k×15/100 = 3200
or, 80k + 60k + 180k = 3200 × 100
or, 320k = 3200 × 100
or, k = 1000
∴ amount invested in scheme B will be = 1000 × 5 = 5000
Answer B
Question: In a series of consecutive odd numbers, 27 is the sixth smallest number and 25 is the tenth largest number. What is the range of the series?
A. 32
B. 26
C. 28
D. 16
Answer: B. 26
Explanation: Imp:All are consecutive odd numbers.
27 is the 6th smallest ,there are 5 numbers smaller then 27 ,smallest number :27-10=17
25 is the 10th largest ,so there are 9 numbers larger then 25, largest number:25+18=43
Range:43-17=26
Ans : B
Question: A couple spent $132 in total while dining out and paid this amount using a credit card. The $132 figure included a 20 percent tip which was paid on top of the price which already included a sales tax of 10 percent on top of the price of the food. What was the actual price of the food before tax and tip?
A.$100
B.$104
C.$108
D.$112
Answer: A.$100
Explanation: Let the price of the meal be x.
After a 10% sales tax addition, the price is 1.1*x
After a 20% tip on this amount, the total is 1.2*1.1*x = 1.32x
1.32x = 132
x = 100
The correct answer is A.
Question: Three hundred students at College Q study a foreign language. Of these, 160 of those students study French, and 190 study Spanish. If at least 90 students who study a foreign language at College Q study neither French nor Spanish, then the number of students who study Spanish but not French could be any number from
A.30 to 50
B.40 to 100
C.60 to 100
D.60 to 110
Answer: A.30 to 50
Explanation: 160 students study French
140 students do not study French
190 students study Spanish
110 students do not study Spanish
90 students study neither French nor Spanish
140-110=30
140-90=50
A. 30 to 50
Question: A Bird is flying into the wind going 6 Km/Hr, and with the wind going 26 Km/Hr, What is his Rate?
A.10 Km/Hr
B.12 Km/Hr
C.5 Km/Hr
D.15 Km/Hr
Answer: A.10 Km/Hr
Explanation: DW=26
UW=6
s=?
s= (26-6)/2 = 20 / 2 = 10
Answer = A
Question: The diameter of a cylindrical tin is 4cm and height is 5 cm. Find the volume of the cylinder?
A.33
B.45
C.20
D.77
Answer: C.20
Explanation: r = 2 h = 5
π * 2 * 2 * 5 = 20 π cc
Answer:C
Question: Of the following, which is nearly equal to √12?
A.1.5
B.2.8
C.3.4
D.3.5
Answer: D.3.5
Explanation: Correct answer is 3.5
Let us take the square roots of all the numbers
3.4*3.4=11.56
3.5*3.5=12.25
Difference
12 - 11.56=0.44
12.25 - 12=0.25
Since 0.25 is lesser of both, 3.5 is closer
Answer is D
Question: Half of 2 percent written as decimal is
A.5
B.0.01
C.0.05
D.0.005
Answer: B.0.01
Explanation: Explanation:
It will be 1/2(2%) = 1/2(2/100) = 2/200 = 0.01
Answer: Option B
Question: Three blocks of different colors are to be placed on a row. How many different sitting arrangements are possible if red must be placed next to blue ?
A.2
B.4
C.6
D.8
Answer: B.4
Explanation: Consider red and blue as one. But, in this arrangement they can be placed in two different combinations.
Red first and Blue second or blue first and red second.
Total we have (R and B) and third color = 2 arrangements to do.
Total arrangements= 2*2= 4
B is the answer
Question: What is the unit digit of (6!*3! / 3!*4!)?
A.5
B.6
C.0
D.3
Answer: C.0
Explanation: (6!*3! /3!*4!)
=(6! / 4!)
=5*6
=30
Units digit of the above product will be equal to 0
Answer C
Question: Divide Rs. 2800 among A, B and C so that A receives 3/4 as much as B and C together and B receives 1/4 as A and C together. A's share is?
A.1300
B.1200
C.1375
D.1400
Answer: B.1200
Explanation: A+B+C = 2800
A = 3/4(B+C); B = 1/4(A+C)
A/(B+C) = 3/4
A = 1/7 * 8400 => 1200
Answer: B
Question: Two bullet train s 140 m and 200 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
A.15.8 sec.
B.12.24 sec.
C.11.8 sec.
D.10.8 sec.
Answer: B.12.24 sec.
Explanation: Relative speed = (60 + 40) km/hr = 100x5/18 = 250/9 m/ sec.
Distance covered in crossing each other = (140 + 200) m = 340 m.
Required time = 340x9/250 = 54/5 = 12.24 sec.
ANSWER B
Question: At what rate percent per annum will a sum of money double in 8 years.
A.12.5%
B.13.5%
C.11.5%
D.14.5%
Answer: A.12.5%
Explanation: Let principal = P, Then, S.I.=P and Time=8 years
Rate = [(100 x P)/ (P x 8)]% = 12.5% per annum. Answer: A
Question: The time taken to travel from city X to city Y is 12 hrs.if a person starts at 6 a.m from city x and another person leaves in city y at 8 p.m .when they will meet.
A.6 A.M
B.7 A.M
C.8 A.M
D.9 A.M
Answer: B.7 A.M
Explanation: i-X- 6 A.M 7 A.M 8 A.M 9 A.M 10 A.M 11 A.M 12 P.M 1 P.M 2 P.M 3 P.M 4 5 6 P.M -Y
x- 8 A.M 7 A.M 6 A.M 5 A.M 4 A.M 3 A.M 2 A.M 1 A.M 12 A.M 11 P.M 10 9 8P.M-Y
SO THEY MEET AT 7 A.M
ANSWER:B
Question: In a partnership between A, B and C. A's capital is Rs.8000. If his share of a profit of Rs.800 is Rs.200 and B's share is Rs.130, what is C's capital?
A.Rs.18800
B.Rs.18700
C.Rs.18600
D.Rs.17500
Answer: A.Rs.18800
Explanation: 200 + 130 = 330
800 - 330 = 470
200 ---- 8000
470 ---- ? => Rs.18800
ANSWER:A
Question: If x is the interest on y and y is the interest on z, the rate and time is the same on both the cases. What is the relation between x, y and z?
A.Y2=XY
B.X2=YZ
C.Y2=XZ
D.Z2=XZ
Answer: C.Y2=XZ
Explanation: X = (Y*NR)/100 Y = (Z*NR)/100
X/Y = NR/100 Y/Z = NR/100
X/Y = Y/Z
Y2 = XZ
Answer:C
Question: The average age of a group of n people is 14 years old. One more person aged 34 joins the group and the new average is 16 years old. What is the value of n?
A.7
B.8
C.9
D.10
Answer: C.9
Explanation: 14n + 34 = 16(n+1)
2n = 18
n = 9
The answer is C.
Question: How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches?
A.50%
B.87%
C.100%
D.187%
Answer: C.100%
Explanation: Area of sheet A = 11*17
Area of sheet B = 11*8.5
Difference in Area = 11*8.5
Required % = (11*8.5)*100/(11*8.5)% = 100%
ANSWER:C
Question: An Olympic diver received the following scores: 4, 2, 5, 1. The standard deviation of her scores is in which of the following ranges?
A.2.01 to 2.99
B.4.01 to 4.99
C.1.01 to 1.99
D.3.01 to 3.99
Answer: C.1.01 to 1.99
Explanation: 4+2+5+1/4=3
∣4−3∣^2 =1^2 = 1
∣2−3∣^2 =1^2 = 1
∣5−3∣^2 =2^2 = 4
∣1−3∣^2 =2^2 = 4
sqrt 10/4 =1.58
Answer : C
Question: A train 140 m long running at 84 kmph crosses a platform in 16 sec. What is the length of the platform?
A.287
B.298
C.233
D.726
Answer: C.233
Explanation: D = 84 * 5/18 = 16
= 373 â€“ 140
= 233
Answer: C
Question: A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
A.Rs 72
B.Rs 88.20
C.Rs 79.15
D.Rs 93
Answer: A.Rs 72
Explanation: C.P. = Rs.	(100/122.5)x 392	= Rs.	(1000/1225)x 392= Rs. 320
Profit = Rs. (392 - 320) = Rs. 72.
ANSWER :A
Question: The average speed of a car is 1 3/5 times the avg speed of a bike. A tractor covers 575km in 23hrs. How much distance will the car cover in 4hrs if the speed of the bike is twice speed of the tractor?
A.400 km
B.320 km
C.360 km
D.550 km
Answer: B.320 km
Explanation: Sol. Average speed of a tractor = 25 km / h
The speed of a bike in an hour = 25 × 2 = 50 km
The speed of a car in an hour = 8/5 * 50 = 80 km
So, the distance covered by car in 4 h is
80 × 4 = 320 km
Ans.(B)
Question: How many integers E are prime numbers in the range 200 < E < 220?
A. 1
B. 2
C. 3
D. 4
Answer: A. 1
Explanation: My friend, every single odd number greater than can be written either as 4E+1 or as 4E+3. If you divide any odd number by 4, you will get a remainder of either 1 or 3. That's not a rule unique to prime numbers at all.
The 6E+1 or 6E-1 rule is basically every odd number that is not divisible by three, so it narrows the search a little.
Here's how I thought about the problem. First, eliminate all the even numbers and the odd multiples of 5 in that range. That leaves us with:
{201, 203, 207, 209, 211, 213, 217, 219}
Eliminate the four multiples of 3. Notice that 21 is a multiple of 3, so 210 is also a multiple of 3. If we add or subtract 3 or 9, we get more multiples of three. When we eliminate those, we are left with.
{203, 209, 211, 217}
Now, notice that a cool thing about this range is that 210 is also a multiple 7 (again, because 21 is a multiple of 7). This means that
210 - 7 = 203
210 + 7 = 217
Those two numbers are also multiples of 7, so eliminate them from the list. Now, we are left with
{209, 211}.
We've already checked all the prime numbers less than 10, so we know that neither of these numbers is divisible by anything less than 10. We have to check 11 now. We know that 22 is a multiple of 11, so 220 is also a multiple of 11. This means that
220 - 11 = 209
is also a multiple of 11. We can eliminate this from the list also.
That leaves us with just 211. There's no zero option in the question, so this must be a prime number.
Answer = (A)
Question: The Price of 357 apples is Rs.2499. What will be the price of 49 dozens of such apples?
A.Rs.3800
B.Rs.2816
C.Rs.4116
D.Rs.3116
Answer: C.Rs.4116
Explanation: Expl : More apples, more cost(Direct)
357 *588 : : 2499 : x
x = (588*2499)/357 = 4116
Answer: C
Question: A cycle is bought for Rs.900 and sold for Rs.1100, find the gain percent?
A.11
B.22
C.99
D.77
Answer: B.22
Explanation: 900 ---- 200
100 ---- ? => 22%
Answer: B
Question: Sum of even numbers between 15 and 25 is
A.70
B.80
C.130
D.100
Answer: D.100
Explanation: Explanation: 16 + 18 + .......24.
Taking 2 common we get = 2 ( 8 + 9 + 10 +.....+ 12)
Sum of n natural numbers upto 12
8 + 9 + 10 +.....+ 12 = (1 + 2 + 3 + ......+ 12) - ( 1 + 2 + 3 + ....+ 7)
By applying the formula for the first n natural numbers sum n (n+1)/2we get, =50
So 16 + 18 + .......24 = 2 Ã— 50 = 100
ANSWER IS D
Question: A pair of prime numbers that can be expressed in the form E{p, (p + 6)} is deﬁned as a pair of “sexy primes.” A “sexy triplet” is a group of three primes that can be expressed in the form {p, (p + 6), (p + 12)}. All of the following prime numbers are the middle term of a sexy triplet EXCEPT
A. 11
B. 13
C. 17
D. 19
Answer: D. 19
Explanation: definetly a sitter.plug in the values for middle term and calculate.We can see clearly that E for 19 , 19+6 gives 25 which is not a prime
therefore correct answer D
Question: If g and h are positive integers, and 3 is not a factor of h, then h may be which of the following?
A.(g−1)·g·(g+1)
B.(g−3)·(g−1)·(g+1)
C.(g−2)·g·(g+2)
D.(g−1)·g·(g+2)
Answer: D.(g−1)·g·(g+2)
Explanation: Plugged in values :
let g=5
A. (g−1)·g·(g+1) --> divisible by 3
B. (g−3)·(g−1)·(g+1) --> divisible by 3
C. (g−2)·g·(g+2) --> divisible by 3
D. (g−1)·g·(g+2) --> not divisible. Hence the answer.
Question: What is the area of a square field whose diagonal of length 20 m?
A.150
B.300
C.200
D.450
Answer: C.200
Explanation: Explanation:
d^2/2 = (20 * 20)/2 = 200
Answer: C
Question: When average age of 20 members are 0, how many members greater than 0?
A.17
B.19
C.21
D.24
Answer: B.19
Explanation: Average of 20 numbers = 0.
Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a)
Answer is 19 (B)
Question: Evaluate
248+64−−√−−−−−−−−−√
A.14
B.26
C.16
D.36
Answer: C.16
Explanation: Explanation:
=248+64−−√−−−−−−−−−√
=248+8−−−−−−√
=256−−−√
=16
Answer: C
Question: The last day of a century cannot be
A.Monday
B.Wednesday
C.Tuesday
D.Friday
Answer: C.Tuesday
Explanation: Explanation:
We know that number of odd days in 100 years = 5
Hence last day of the first century is Friday
Number of odd days in 200 years = 5 x 2 = 10 = 3 (As we can reduce multiples of 7 from odd days which will not change anything)
Hence last day of the 2nd century is Wednesday
Number of odd days in 300 years = 5 x 3 = 15 = 1
Hence last day of the 3rd century is Monday
We know that number of odd days in 400 years = 0. (∵ 5 x 4 + 1 = 21 = 0)
Hence last day of the 4th century is Sunday
Now this cycle will be repeated. Hence last day of a century will not be Tuesday or Thursday or Saturday.
Answer: Option C
Question: 325 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees
A.10
B.12
C.13
D.16
Answer: C.13
Explanation: 26 trees have 25 gaps between them,
Required distance (325/25) = 13
C
Question: The toll for crossing a certain bridge is $0.70 each crossing. Drivers who frequently use the bridge may instead purchase a sticker each month for $13.00 and then pay only $0.30 each crossing during that month. If a particular driver will cross the bridge twice on each of x days next month and will not cross the bridge on any other day, what is the least value of x for which this driver can save money by using the sticker?
A.14
B.15
C.16
D.28
Answer: C.16
Explanation: Option #1: $0.75/crossing....Cross twice a day = $1.5/day
Option #2: $0.30/crossing....Cross twice a day = $0.6/day + $13 one time charge.
If we go down the list of possible answers, you can quickly see that 14 days will not be worth purchasing the sticker. 1.5x14 (21) is cheaper than 0.6x14 +13 (21.4)...it's pretty close so let's see if one more day will make it worth it... If we raise the number of days to 15, the sticker option looks like a better deal...1.5x15 (22.5) vs 0.6x15 + 13 (22). Answer: C
Question: he total marks obtained by a student in Physics, Chemistry and Mathematics is 140 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics?
A.55
B.70
C.75
D.85
Answer: B.70
Explanation: Let the marks obtained by the student in Physics, Chemistry and Mathematics be P, C and M respectively.
P + C + M = 140 + P
C + M = 140
Average mark obtained by the student in Chemistry and Mathematics = (C + M)/2 = 140/2 = 70.
ANSWER:B
Question: 4y - 4x = xy and x ≠ 0. If x and y are integers, which of the following could equal y?
A.2
B.1
C.0
D.5
Answer: A.2
Explanation: Plug in the answer choices in the equation from the question stem.
A) y = 2 >>> 4-x = 4x >>> No value of x will satisfy this, not even 0. POE
B) y = 1 >>> 2 - x = 2x >>> Same, POE
C) y = 0 >>> -x = 0 >>> x can not equal 0
D) y = -1 >>> 8 - 4x = 4x >>> Holds true for x = 1, no need to check E. This is the answer.
Answer A