RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A certain roller coaster has 6 cars, and a passenger is equally likely to ride in any 1 of the 6 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 6 times, what is the probability that the passenger will ride in each of the 6 cars?
A.3/1944
B.1/96
C.2/96
D.1/1944
Answer: A.3/1944
Explanation: If he is to ride 6 times and since he can choose any of the 6 cars each time, total number of ways is
= 6 * 6 * 6 * 6 * 6 * 6
= 46656
Now the number of ways if he is to choose a different car each time is
= 6 * 5 * 4 * 3 * 2 * 1
= 720
So the probability is
= 720/46656 = 3/1944
Answer : A
Question: For every integer n ≥ 3, the function g(n) is defined as the product of all the odd integers from 1 to n, inclusive. What is the value of g(99) – g(97)?
A.98
B.100
C.0
D.99
Answer: A.98
Explanation: g(99) = 1*3*5*7*9*...*99
g(97) = 1*3*5*7*9*...*97
g(99) - g(97) = 1*3*5*7*9*...*99 - 1*3*5*7*9*...*97 = 1*3*5*7*9*...*97*(99 - 1) = 1*3*5*7*9*...*97*98
hence:A.
Question: The juice stall at the circus stocked just 2 brands of orange juice tetra packs. Brand A costs $1 per pack and brand B costs $1.5 per pack. Last week , brand A contributed to q% of stall’s revenue and accounted for r% of sales of juice tetra packs. Which of the following expresses q in terms of r?
A.100r/(150 – r)
B.200r/(250-r)
C.200r/(300-r)
D.250r/(400-r)
Answer: C.200r/(300-r)
Explanation: 1. Let the number of units sold be 100. Then n units of A are sold and (100-n) units of B are sold.
Total revenue= Revenue due to A + Revenue due to B
= (No.of units of A sold * Cost/unit of A) + (No.of units of B sold * cost/unit of B)
= r *1 + (100-r) *1.5
= r + (150-1.5r) --- (1)
2. But we know, revenue due to A = q %. of the total revenue --- (2)
3. To express q in terms of r we need to relate (1) and (2)
4. q % = r / ( r + (150-1.5r))
or q = 100r / 150-0.5r = 200r/(300-r)
C
Question: The area of circle O is added to its diameter. If the circumference of circle O is then subtracted from this total, the result is 2. What is the radius of circle O?
A.–2/pi
B.1
C.3
D.4
Answer: B.1
Explanation: pi*r^2 + 2r -2*pi*r = 2
Simplifying the equation: pi*r(r-2)+2r=2
Without much algebraic: We can Test the answers quickly, then 1 is the only possible answer that will eliminate pi from equation.
Answer is B
Question: BCB, DED, FGF, HIH, ___
A.KOP
B.QLM
C.JKJ
D.PSQ
Answer: C.JKJ
Explanation: This series consists of a simple alphabetical order with the first two letters of all segments: B, C, D, E, F, G, H, I, J, K. The third letter of each segment is a repetition of the first letter.
ANSWER:C
Question: All the faces of cubes are painted with red colour.It is then cut into 64 equal small cubes.Find How many small cubes are there whose three faces are coloured ?
A.4
B.8
C.16
D.24
Answer: B.8
Explanation: There are 64 small cubes,Hence one side side of the big cube is 3√64=4 cm
Number of small cubes having three faces coloured = No. of corners = 8
Answer: B
Question: Jerry has 3 flavors of ice cream in his parlor. How many options are there for George to pick a one-flavor, two-flavor or three-flavor order?
A.2
B.3
C.4
D.7
Answer: D.7
Explanation: 3C1 + 3C2+ 3C3 = 7.
Ans D.
Question: A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
A.229
B.288
C.600
D.888
Answer: C.600
Explanation: D = 30 * 5 = 150
RS = 40 – 30 = 10
T = 150/10 = 15
D = 40 * 15 = 600 km
Answer: C
Question: In a group of 1 boy and 9 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be selected?
A.60
B.68
C.76
D.84
Answer: D.84
Explanation: Number of ways to select four children is 10C4 = 210
Number of ways to choose only girls is 9C4 = 126
Number of ways that at least one boy is selected is 210 - 126 = 84
The answer is D.
Question: How much 60% of 50 is greater than 45% of 30?
A.18
B.91
C.16.5
D.17
Answer: C.16.5
Explanation: (60/100) * 50 – (45/100) * 30
30 - 13.5 = 16.5
Answer: C
Question: If 3-X < (2-5X)/3, which of the following is correct?
A.X < -7/2.
B.X > -5.
C.X > 5.
D.-5 < X < 0.
Answer: A.X < -7/2.
Explanation: 3-X < (2-5X)/3
9-3X < 2- 5X
7 < -2X
-7/2>X
A is the answer
Question: The New York Classical Group is designing the liner notes for an upcoming CD release. There are 10 soloists featured on the album, but the liner notes are only 5 pages long, and therefore only have room for 5 of the soloists. The soloists are fighting over which of them will appear in the liner notes, though not about which page they appear on. How many different combinations R of soloists can appear in the liner notes?
A.5!
B.10!/(5!5!)
C.10!/5!
D.10!
Answer: B.10!/(5!5!)
Explanation: Total Soloists to choose from = 10
Soloist Required = 5
Question : How many different combinations R of soloists can appear in the liner notes?
The language of the question clearly mentions that only the combinations need to be calculated
i.e. Arrangement of the Soloists does NOT matter(Refer theHighlightedpart of the question)
Method-1:
Total Ways to Choose 5 out of 10 soloists = 10C5 = 10! / (5!*5!)
Method-2:
No. of ways to select and arrange 5 soloist on 5 Page = 10*9*8*7*6
Since the arrangement of 5 selected Notes (which can happen in 5! ways) doesn't NOT matter,
Therefore total ways to pick 5 out of 10 soloists = 10*9*8*7*6 / 5! = 10*9*8*7*6 *5! / (5!*5!) = 10! / (5!*5!)
Answer: Option B
Question: In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk?
A.1/80
B.1
C.40
D.1/40
Answer: C.40
Explanation: Let the required number of days be x.
Less cows, More days (Indirect Proportion)
Less bags, Less days (Direct Proportion)
Cows	1:40 :: 40 : x
Bags 40:1
1 * 40 * x = 40 * 1 * 40
x = 40.
Answer is C.
Question: A snooker tournament charges $45.00 for VIP seats and $20.00 for general admission (“regular” seats). On a certain night, a total of 320 tickets were sold, for a total cost of $7,500. How many fewer tickets were sold that night for VIP seats than for general admission seats?
A.200
B.276
C.230
D.240
Answer: B.276
Explanation: let no of sits in vip enclosure is x then x*45 +20( 320-x) =7500 or 25x = 7500 -6400 , x = 1100/25 =44
vip =44 general 320-44 = 276
B
Question: A boat goes 8 km upstream in 24 minutes. The speed of stream is 4 km/hr. The speed of boat in still water is:
A.24 km/hr
B.25 km/hr
C.26 km/hr
D.23 km/hr
Answer: A.24 km/hr
Explanation: Speed upstream =8/(24/60) = 20 km/hr
Speed of the stream = 4 km/hr
speed of boat in still water = (20+4) = 24 km/hr
Answer : Option A
Question: If by reduction of rupee 1 per kg in the price,a person can buy one kg more for Rs.56. find the original price of the per kg?
A.7rs/kg
B.8rs/kg
C.9rs/kg
D.6rs/kg
Answer: B.8rs/kg
Explanation: for Rs.56 he can buy = 56/8rs = 7kg rice. (Original Price)
By reduction of Rs.1 per kg, = 56/7rs = 8kg rice. (As per reduction)
Original Price(8rs), he can buy = 7kg of rice
ANSWER:B
Question: one kilo gram coffee is Rs. 126 and Rs. 135 are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the 3rd variety per kilo gram is?
A.150
B.133
C.175.5
D.178
Answer: C.175.5
Explanation: Since first and second varieties are mixed in equal proportions.
So, their average price = Rs. 126 + 135 = Rs. 130.50
2
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
By the rule of alligation, we have:
Cost of 1 kg of 1st kindCost of 1 kg tea of 2nd kind
Rs. 130.50	Mean Price
Rs. 153	Rs. x
(x - 153)	22.50
x - 153	= 1
22.50
x - 153 = 22.50
x = 175.50
C
Question: A train covers a distance of 36 km in 12 min. If it takes 7 sec to pass a telegraph post, then the length of the train is?
A.330
B.340
C.350
D.360
Answer: C.350
Explanation: Speed = (36/12 * 60) km/hr = (180 * 5/18) m/sec = 50 m/sec.
Length of the train = 50 * 7 = 350 m.
Answer: Option C
Question: Ram's age and Shyam's age are in the ratio 3:4. Seven years ago the ratio of their ages was 2:3. Find the ratio of their ages five years hence?
A.26/36
B.26/31
C.26/19
D.26/33
Answer: D.26/33
Explanation: Let ages of Ramu and Shyam be x and y respectively.
x/y = 3/4 => x = 3/4 y
(x- 7)/(y - 7) = 2/3
=> 3x - 21 = 2y - 14 => 3x = 2y + 7
But x = 3/4 y
3 * 3/4 y = 2y + 7
9y = 8y + 28 => y = 28years
=> x = 21 years
Ratio of their ages five years hence, (21 + 5)/(28 + 5) = 26/33.
Answer:D
Question: The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:
A.1510
B.1315
C.1015
D.1215
Answer: C.1015
Explanation: Required number = (L.C.M. of 12,16, 18, 21, 28) + 7
= 1008 + 7
= 1015
Answer: Option C
Question: 15 : 5 seconds :: ? : 10 minutes
A.10
B.15
C.30
D.25
Answer: C.30
Explanation: 15*10=5*x
x=30
ANSWER:C
Question: Certain sum becomes 3 times it self at compound interest in 10 years. In how many years it becomes 9 times?
A.10 Years
B.20 Years
C.30 Years
D.40 Years
Answer: B.20 Years
Explanation: P(1 + R/100)10 = 3P
=> P(1 + R/100)10 = 3
Let P(1 + R/100)n = 9P
=> (1 + R/100)n = 9
=> 32 = [(1 + R/100)10]2
=> (1 + R/100)n => (1 + R/100)20
=> n = 20 Years.
B
Question: Two circles are there one with arc area 60digree equal to 45digree of another circle find the area of circle1:circle2 ratio
A.3:4
B.1:4
C.1:2
D.2:3
Answer: A.3:4
Explanation: area for first circle=(3.14*r^2)/6
area of second circke=(3.14*R^2)/8
therefore, ratio=3:4
ANSWER:A
Question: A $500 investment and a $1,500 investment have a combined yearly return of 22 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have?
A.29%
B.20%
C.27%
D.25%
Answer: C.27%
Explanation: The equation we can form the question :
Return on Total Investment = Sum of individual Investments
(500+1500)(22)=(500âˆ—7)+(1500x), where x is the return on investment of 1500.
Solving the equation, we get x = 27% ( Option C )	ANSWER:C
Question: Robert tossed a fair coin 3 times. What is the probability that the coin landed heads up exactly twice?
A.0.125
B.0.250
C.0.375
D.0.75
Answer: C.0.375
Explanation: Total number of outcomes = 2 * 2 * 2 = 8
Out of 3 times we need heads exactly 2 times = 3C2 = 3
Probability = 3/8 = 0.375
The answer is, therefore, (C).
Question: Two unbiased coins are tossed. What is probability of getting at most one tail ?
A.1/2
B.1/3
C.3/2
D.3/4
Answer: D.3/4
Explanation: Explanation:
Total 4 cases = [HH, TT, TH, HT]
Favourable cases = [HH, TH, HT]
Please note we need atmost one tail, not atleast one tail.
So probability = 3/4
Option D
Question: Sara and Alan start a company with Rs.100000 and Rs.50000 respectively. how should they share their profits at the end of one year?
A.1:2
B.3:4
C.3:8
D.3:1
Answer: A.1:2
Explanation: The ratio of the investments made by A and B =
100000: 50000=> 2:1.Answer: A
Question: The radius of a cylindrical water tank is reduced by 50%. However, the speed by which water is filled into the tank is also decreased by 50%. How much more or less time F will it take to fill the tank now?
A. 50% less time
B. 50% more time
C. 75% less time
D. 75% more time
Answer: A. 50% less time
Explanation: (VC)Volume of the cylinderical vessal is directly proportional to R^2.
So if radius is 50% less volume will be 1/4th of the original volume.(VC/4)
Now if with velocity V tank can be filled in T1 time of volume VC
So now Velocity is 50% less i..e V/2
So time taken to fill the capacity VC/4 by V/2 velocity is T2.
VT1 = VC
V/2*T2 = VC/4
So T1/T2 = 1/2
So Tank will be filled in less time. that is F=50 % less.A
Question: There are 5 marbles in a bag - 2 are orange and 3 are blue. If two marbles are pulled from the bag, what is the probability Y that at least one will be orange?
A.Y=7/10
B.Y=3/5
C.Y=2/5
D.3/10
Answer: A.Y=7/10
Explanation: Method 1
Probability that at least one out of two marbles will be orange = 1 - Probability that both marbles are blue = 1- P(First marble is blue) * P (Second Marble is Blue) = 1- (3/5)(2/4) = 7/10
Method 2
Probability that at least one marble will be orange = P( First Marble is Orange)*P(Second Marble is Blue) + P (First Marble is Blue)*P(Second Marble is Orange) + P(First Marble is Orange) *P(Second Marble is Orange) = (2/5)*(3/4)*2 + (2/5)*(1/4) = 7/10
Method 3
Probabilty that at least one marble will be orange = 1 - Probability that both marbles are blue
= 1 - (Number of ways 2 blue marbles out of 3 can be pulled)/(Number of ways 2 marbles out of 5 can be pulled)
= 1 - 3C2/5C2
= 1-(3/10) = 7/10
Answer :A
Question: How many numbers between 10 - 99 yield a reminder of 8 when divided by 10 and also yield a remainder of 2 when divided by 8?
A.One
B.Three
C.Two
D.Five
Answer: B.Three
Explanation: Answer = B) Three
Numbers between 10 - 99 giving remainder 8 when divided by 10 = 18, 28, 38, 48, 58, 68, 78, 88, 98
The above Numbers giving remainder 2 when divided by 8 = 18, 58, 98 = 3
Question: In how much time will a train of length 100 m, moving at 54 kmph cross an electric pole?
A.sec
B.sec
C.sec
D.sec
Answer: D.sec
Explanation: Convert kmph to mps. 54 kmph = 54 * 5/18 = 15 mps.
The distance to be covered is equal to the length of the train.
Required time t = d/s = 100/15= 6.7 sec.
Answer:D
Question: There are 10 books on a shelf, of which 4 are paperbacks and 6 are hardbacks. How many possible selections of 5 books from the shelf contain at least one paperback and at least one hardback?
A.75
B.120
C.210
D.246
Answer: D.246
Explanation: Paperbacks - 4, hardbacks - 6
5 books in total and at least 1 from each.
Total combinations for 5 books = (1pb, 4 hb) + (4pb, 1hb) + (3pb, 2hb) + (2pb, 3hb)
1pb, 4hb = 4c1*6c4 = 60
4pb,1hb = 4c4*6c1 = 6
3pb,2hb = 4c3*6c2 = 60
2pb,3hb = 4c2*6c3 = 120
Total combinations of 5 books = 60+6+60+120 = >246
Ans D.
Question: If an integer n is to be chosen at random from the integers 1 to 84, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8?
A.9/14
B.3/8
C.1/2
D.5/8
Answer: A.9/14
Explanation: n(n+1)(n+2) will be divisible by 8 when n is a multiple of 2 or when (n+1) is a multiple of 8.
Thus when n is even, this whole expression will be divisible by 8.
from 1 to 84, there are 42 even integers.
Now when (n+1) is multiple by 8, we have 12 such values for (n+1)
probability that n(n+1)(n+2) will be divisible by 8
= (42 + 12)/84
= 54/84
= 9/14
Ans is A
Question: What is the average (arithmetic mean) of all the multiples of ten from 10 to 190 inclusive?
A.90
B.95
C.100
D.105
Answer: C.100
Explanation: 10 and 190 inclusive would mean there are 19 terms.
No need to add up all the terms and further divide by 19 since the terms are evenly spaced in ascending order from 10, 20, 30........190
The middle term is the average which is the tenth term = 100
C is the answer.
Question: 82*83*84*..89 what is the digit in units place?
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: In the product
82*83*84 *85*86......*89
last( unit) digit will be zero as 82 * 85 will give zero as last (unit ) digit and further multiplication with any number will also give zero at unit place.
ANSWER:A
Question: A certain company’s profit in 1996 was 25 percent greater than its profit in 1995, and its profit in 1997 was 30 percent greater than its profit in 1996. The company’s profit in 1997 was what percent greater than its profit in 1995?
A.5%
B.62.5%
C.33%
D.35%
Answer: B.62.5%
Explanation: Profit in 1995 - 100
Profit in 1996 - 125
%increae Profit in 1997 in comparison to 1995 = 25 + 125*30%= 62.5
Correct Option : B
Question: Average age of students of an adult school is 40 years. 120 new students whose average age is 32 years joined the school. As a result the average age is decreased by 4 years. Find the number of students of the school after joining of the new students.
A.1200
B.120
C.360
D.240
Answer: D.240
Explanation: Explanation :
Let the original no. of students be x.
According to situation, 40x + 120*32 = (x + 120)36 ⇒ x = 120
So, Required no. of students after joining the new students
= x + 120 = 240.
Answer : D
Question: A sum of money is sufficient to pay A's wages for 20 days and B's wages for 30 days. The same money is sufficient to pay the wages of both for?
A.12days
B.15days
C.20days
D.18days
Answer: A.12days
Explanation: Let the total money be $x
A's 1day work = $ x/20
B's 1day work = $ x/30
A+B 1day work = $ x/12
Money is sufficient to pay the wages of both for 12days
Answer is A
Question: On a sum of money, the simple interest for 2 years is Rs. 326, while the compound interest is Rs. 340, the rate of interest being the same in both the cases. The rate of interest is
A.15%
B.14.25%
C.8.58%
D.10.5%
Answer: C.8.58%
Explanation: Explanation:
The difference between compound interest and simple interest on Rs. P for 2 years at R% per annum
= (R Ã— SI)/(2 Ã— 100)
Difference between the compound interest and simple interest = 340 - 326 = 14
(R Ã— SI)/(2 Ã— 100) = 14
(R Ã— 326)/(2 Ã— 100) = 14
R = 8.58%
Answer: Option C
Question: If 2x + 3y = 15; 2y + z = 19 and x + 2z = 29, what is the value of x + y + z ?
A.19
B.32
C.26
D.22
Answer: A.19
Explanation: On solving equation we get
x = 3, y = 3, z = 13
Answer A
Question: There are 10 members from that a total of 6 men & 4 ladies a committee of 3 is to be formed. If Mrs. A is not willing to join the committee in which Mr. B is a member, whereas Mr.B is willing to join the committee only if Mrs C is included, how many such committee are possible?
A.71 ways
B.83 ways
C.85 ways
D.91 ways
Answer: D.91 ways
Explanation: We first count the number of committee in which
(i). Mr. Y is a member
(ii). the ones in which he is not
case (i): As Mr. Y agrees to be in committee only where Mrs. Z is a member.
Now we are left with (6-1) men and (4-2) ladies (Mrs. X is not willing to join).
We can choose 1 more in5+\inline {\color{Blue} 2C_{1}}=7 ways.
case (ii): If Mr. Y is not a member then we left with (6+4-1) people.
we can select 3 from 9 in \inline {\color{Blue} 9C_{3}}=84 ways.
Thus, total number of ways is 7+84= 91 ways.
D
Question: An amount of Rs.3120 was divided among A, B and C, in the ratio 1/2 : 1/3 : 1/4. Find the share of C?
A.720
B.360
C.250
D.280
Answer: A.720
Explanation: Let the shares of A, B and C be a, b and c respectively.
a : b : c = 1/2 : 1/3 : 1/4
Let us express each term with a common denominator which is the last number divisible by the denominators of each term i.e., 12.
a : b : c = 6/12 : 4/12 : 3/12 = 6 : 4 : 3.
Share of C = 3/13 * 3120 = Rs. 720
Answer: A
Question: The length of the bridge, which a train 170 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
A.239
B.277
C.205
D.88
Answer: C.205
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (170 + X)/30
= 25/2 ==> 2(170 + X) = 750 ==> X = 205 m.
Answer: C
Question: A man swims downstream 28 km and upstream 12 km taking 2 hours each time, what is the speed of the man in still water?
A.10
B.8
C.5
D.2
Answer: A.10
Explanation: 28 --- 2 DS = 14
? ---- 1
12 ---- 2 US = 6
? ---- 1 M = ?
M = (14 + 6)/2 = 10
Answer:A
Question: Combine terms: 12a + 26b -4b – 16a.
A.4a + 22b
B.-28a + 30b.
C.-4a + 22b
D.28a + 30b.
Answer: C.-4a + 22b
Explanation: 12a + 26b -4b – 16a.
= 12a – 16a + 26b – 4b.
= -4a + 22b
correct answer C
Question: Kanul spent $35000 in buying raw materials, $40000 in buying machinery and 20% of the total amount he had as cash with him. What was the total amount?
A.$87952
B.$93750
C.$89542
D.$95820
Answer: B.$93750
Explanation: Let the total amount be x
then, (100-20)% of x = 35000+40000
80% of x = 75000
80x/100 = 75000
x = $93750
Answer is B
Question: In an examination paper, there are two groups each containing 4 questions. A candidate is required to attempt 5 questions but not more than 3 questions from any group. In how many ways can 5 questions be selected?
A.24
B.48
C.96
D.64
Answer: B.48
Explanation: Solution:
5 questions can be selected in the following ways,
2 question from first group and 3 question from second group Or 3 question from first group and 2 question from second group.
(4C2 * 4C3) +(3C4 *2C4),
= 24 +24 = 48
Answer: Option B
Question: A worker's daily wage is increased by 40% and the new wage is $35 per day. What was the worker's daily wage before the increase?
A.$20
B.$21
C.$24
D.$25
Answer: D.$25
Explanation: Let x be the daily wage before the increase.
1.4x = $35
x = $25
The answer is D.
Question: A division of a company consists of six men and six women. If two of these twelve employees are randomly selected as representatives of the division, what is the probability that both representatives will be female?
A.5/22
B.7/22
C.5/33
D.7/33
Answer: A.5/22
Explanation: The total number of ways to choose two representatives is 12C2=66.
The number of ways to choose two females is 6C2=15.
P(choosing two female representatives)=15/66=5/22
The answer is A.
Question: There are 12 towns grouped in four zones with three towns per zone. It is intended to connect the towns with a telephone lines such that each every two towns are connected with three direct lines if they belong to the same zone, and with only one direct line otherwise. How many direct telephone lines are required ?
A.72
B.90
C.96
D.144
Answer: B.90
Explanation: Explanation :
There are 3 towns.
Each town connects with the other town in 3 lines.
Hence total number of lines is 3 x 3 = 9.
Hence 1 zone has 9 direct links within it.
So 4 zones have 9 x 4 = 36 direct links within it.
Now, between zones/ interzone:
Consider a town in Zone 1. There are 9 towns outside this zone.
Hence 9 lines are required to connect between this town and the other 9 towns.
Similarly, there are 12 towns, each with 9 towns outside its own zone.
So, totally, there will be 9 x 12 / 2 = 9 x 6 = 54 lines inter zone (Divided by 2 comes here because, after half, it is repeated).
So, the total number of lines will be 36 (within zone) + 54 ( inter zone) = 90.
Answer : B
Question: In an examination, 25% of total students failed in Hindi, 48% failed in English and 27% in both. The percentage of these who passed in both the subjects is :
A.23
B.54
C.28
D.40
Answer: B.54
Explanation: Explanation:
Formula n(aâˆªb) = n(a) + n(b) âˆ’ n(aâˆ©b)
Fail in Hindi or English = 25 + 48 â€“ 27 = 46
Therefore students who passed = 100 â€“ 46 = 54.
Answer: B
Question: A bag contains a total of 93 coins in the form of one rupee and 50 paise coins. If the total value of coins in the bag is Rs.56, find the number of 50 paise coins in the bag?
A.60
B.56
C.64
D.74
Answer: D.74
Explanation: Let the number of one rupee coins in the bag be x.
Number of 50 paise coins in the bag is 93 - x.
Total value of coins
[100x + 50(93 - x)]paise = 5600 paise
=> x = 74
ANSWER:D
Question: A train is moving at 6/7 of its usual speed. The train is 10 minutes too late. What is the usual time (in hours) for the train to complete the journey?
A.0.5
B.1
C.1.5
D.2
Answer: B.1
Explanation: new time = d / (6v/7) = 7/6 * usual time
10 minutes represents 1/6 of the usual time.
The usual time is 1 hour.
The answer is B.
Question: A, B and C invested Rs.2400, Rs.7200 and Rs.9600 respectively, in a partnership business. Find the share of A in profit of Rs.9000 after a year?
A.1125
B.2400
C.7200
D.2500
Answer: A.1125
Explanation: Explanation:
2400:7200:9600
1:3:4
1/8 * 9000 = 1125
Answer: A
Question: 4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days?
A.4
B.16
C.8
D.1
Answer: B.16
Explanation: Explanation :
Let the required number of mats be x
More mat-weavers, more mats (direct proportion)
More days, more mats (direct proportion)
⇒ 4 × 4 × x = 8 × 8 × 4
⇒ x = 2 × 2 × 4 = 16. Answer : Option B
Question: Sandy bought 65 books for $1180 from one shop and 55 books for $860 from another shop. What is the average price that Sandy paid per book?
A.$13
B.$15
C.$17
D.$19
Answer: C.$17
Explanation: average price per book = (1180 + 860) / (65 + 55) = 2040 / 120 = $17
The answer is C.