RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Two trains are traveling from point A to point B such that the speed of first train is 65 kmph and the speed of 2 train is 29 kmph. Where is the distance b/w A and B such that the slower train reached 5 hrs late compared to the faster?
A.3
B.65
C.9
D.5
Answer: B.65
Explanation: Answer:B
Question: If m is the average (arithmetic mean) of the first 10 positive multiples of 3 and if M is the median of the first 10 positive multiples of 3, what is the value of M – m ?
A. –5
B. 5
C. 0
D. 25
Answer: C. 0
Explanation: The first 10 positive multiples of 3 is an evenly spaced set. One of the most important properties of evenly spaced set (aka arithmetic progression) is:in any evenly spaced set the arithmetic mean (average) is equal to the median.
Hence M=m --> M-m=0.
Answer: C.
Question: Two boys starting from the same place walk at a rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5km apart, if they walk in the same direction?
A.15 hours
B.16hours
C.17 hours
D.18 hours
Answer: C.17 hours
Explanation: Explanation:
In this type of questions we need to get the relative speed between them,
The relative speed of the boys = 5.5kmph – 5kmph
= 0.5 kmph
Distance between them is 8.5 km
Time = Distance/Speed
Time= 8.5km / 0.5 kmph = 17 hrs
Answer: C
Question: If 625^(-x) + 25^(-2x) + 5^(-4x) = 10, what is the value of x?
A.-4
B.-1/4
C.0
D.1/4
Answer: C.0
Explanation: We're told that 625^(-X) + 25^(-2X) + 5^(-4X) = 15. We're asked for the value of X.
Since each of the calculated terms MUST be positive (regardless of what the exponent is), we can use thebasesto our advantage.....
With Answer A, we'd have 625^4, which is MUCH BIGGER than 15 (and we'd be adding to that big number). Eliminate A.
With Answer E, we'd have 625^(-4), which would create a TINY fraction (and we'd add some other fractions to it, so the total would be MUCH TOO SMALL). Eliminate E.
With Answer D, we'd have 625^(-1/4), which will also be a fraction (just not as tiny as the one in answer E), but the total would still be TOO SMALL. Eliminate D.
With Answer C, anything to the '0 power' is 1, so we'd have 1+1+1 = 3. This is not 15. Eliminate C.
C
Question: If a new town has 200 residents, and the population doubles every 10 years, what will be its population after 75 years?
A.6034 residents
B.9051 residents
C.12068 residents
D.36204 residents
Answer: D.36204 residents
Explanation: 200*2^(75/10)=100*2^7.5=200*181.02=36204
The answer is D.
Question: Jim drove 923 miles of a 1200 miles journey. How many more miles does he need to drive to finish his journey?
A.113 miles
B.277 miles
C.456miles
D.887 miles
Answer: B.277 miles
Explanation: The number of miles to drive to finish his journey is given by
1200 - 923 = 277 miles
correct answer B
Question: An uneducated retailer marks all his goods at 65% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the marked price. What is his actual profit on the sales?
A.12.50 %
B.13.50 %
C.14 %
D.23.75%
Answer: D.23.75%
Explanation: Sol.
Let C.P. = Rs. 100. Then, marked price = Rs. 165.
S.P. = 75% of Rs. 165 = Rs. 123.75.
∴ Gain% = 23.75%.
Answer D
Question: Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 210 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 3 of the days were hot, then what was the price of 1 cup on a hot day?
A.$ 1.50
B.$ 1.64
C.$ 2.25
D.$ 2.50
Answer: B.$ 1.64
Explanation: 7 regular days --> sales = 7*32*x = 224x;
3 hot days --> sales = 3*32*(1.25x) = 120x;
Total sales = 224x+120x = 344x.
Total cost = 10*32*0.75 = 240.
Profit = 344x - 240 = 210 --> x=1.308.
1.25x=~1.64.
Answer: B.
Question: A man gains 10% by selling an article for a certain price. If he sells it at double the price, the percentage of profit will be.
A.130%
B.120%
C.150%
D.160%
Answer: B.120%
Explanation: Explanation:
Let the C.P. = x,
Then S.P. = (110/100)x = 11x/10
New S.P. = 2(11x/10) = 22x/10
Profit = 22x/10 - x = 12x/10
Profit% = (Profit/C.P.) * 100
=> (12x/10) * (1/x) * 100 = 120 %
Option B
Question: How many odd prime numbers are there less than 150?
A.24
B.34
C.44
D.54
Answer: B.34
Explanation: Odd prime number less than 150:3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149
There is 34 the odd prime number
Answer is B
Question: On dividing a number by 5, we get 2 as quotient and 0 as remainder. On dividing the same number by 4, what will be the remainder?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: Number = 5 * 2 + 0 = 10
4) 10(2
8
--------
2
Required number = 2.
ANSWER:C
Question: On 8th Feb,2005 it was Tuesday.What was the day of the week on 8th Feb,2004 ?
A.Tuesday
B.Monday
C.Sunday
D.Wednesday
Answer: C.Sunday
Explanation: The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.
Hence, this day is Sunday. Option C
Question: A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.340 less than the sum lent. What was the sum lent?
A.228
B.279
C.280
D.500
Answer: D.500
Explanation: P - 340 = (P*4*8)/100
P = 500
Answer: D
Question: Peter invests a sum of money and gets back an amount of $ 815 in 3 years . David invests an equal amount of money and gets an amount of $854 in 4 years. If both amounts were invested at the same rate (simple interest ) What was the sum of money invested ?
A.670
B.664
C.698
D.744
Answer: C.698
Explanation: Since both Peter and David invested the same amount of money at the same rate, they would earn same interest per year.
David invested for one year more than Peter and hence he got interest amount for one more year.
Interest earned per year = Amount received by David - Amount received by Peter = 854 - 815 = 39
Interest earned for 3 years = 39*3 = 117
Amount invested = 815 - 117 = 698
Answer: C
Question: P is four times as old as Q, and Q is four years older than R. If R is z years old, what is P’s age in terms of z?
A.4z + 16
B.4z + 4
C.(z+4) / 4
D.4z - 4
Answer: A.4z + 16
Explanation: P = 4Q
Q = R+4 = z+4
P = 4(z+4) = 4z + 16
The answer is A.
Question: Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both. If 62 percent of these who attended the meeting were stockholders and 47 percent were employees. What percent were stockholders, who were not employees?
A.52
B.53
C.54
D.55
Answer: B.53
Explanation: 100 = 62 + 47 - n(SnE) [where n represents intersection]
=> n(SnE) = 9
=> Number who were only stockholders = n(S) - n(SnE) = 53 percent
Option (B)
Question: In a phase III clinical trial of Dosaxin, a new drug, patients received a progressively growing dosage of Dosaxin for a few days. On the first day, each patient received 15 milligrams of Dosaxin. On each of the following days, the daily dosage was m milligrams greater than the dosage received the day before, reaching a dosage of 43 milligram on the last day of the trial. For how many days did the trial last, if each patient received a total amount of 145 milligrams of Dosaxin during the whole trial ?
A.4
B.5
C.6
D.7
Answer: B.5
Explanation: Its an arithmetic sequence where the first term is 15 and the last term is given as 43. We are also given the sum of the series as 145.
Sum of series = n*(a + l)/2
145 = n(15+43)/2
Solving for n, we get n = 5
Option B
Question: A and B enter into partnership with capital as 7:9. At the end of 8 months, A withdraws. If they receive the profits in the ratio of 8:9 find how long B's capital was used?
A.6 months
B.8 months
C.10 months
D.7 months
Answer: D.7 months
Explanation: Explanation:
7 * 8 : 9 * x = 8:9 => x= 7
ANSWER IS D
Question: A can finish a work in 4 days and B can do same work in half the time taken by A. then working together, what part of same work they can finish in a day?
A.1/4
B.1/6
C.1/7
D.3/4
Answer: D.3/4
Explanation: Explanation:
Please note in this question, we need to answer part of work for a day rather than complete work. It was worth mentioning here because many do mistake at this point in hurry to solve the question
So lets solve now,
A's 1 day work = 1/4
B's 1 day work = 1/2 [because B take half the time than A]
(A+B)'s one day work =
(1/4+1/2)=3/4
So in one day 3/4 work will be done
Answer: D
Question: There are some pigeons and hares in a zoo. If heads are counted, there are 200. If legs are counted, there are 580. The number of hares in the zoo is?
A.29
B.67
C.90
D.86
Answer: C.90
Explanation: 200*2 = 400
580
-----
180
1----2
?----180 = 90
Answer:C
Question: A bag contains 2 red, 3 green and 2 yellow balls. Two balls are drawn at random. What is the probability that none of the balls drawn is yellow?
A.10/15
B.10
C.11
D.10/21
Answer: D.10/21
Explanation: Total number of balls = (2 + 3 + 2) = 7.
Let S be the sample space.
Then, n(S) = Number of ways of drawing 2 balls out of 7
= 7C2 `
= (7 x 6)/(2 x 1)
= 21.
Let E = Event of drawing 2 balls, none of which is yellow.
n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls.
= 5C2
= (5 x 4)/(2 x 1)
= 10.
P(E) = n(E)/n(S) = 10/21
Hence answer is D
Question: Positive integer y is 50 percent of 50 percent of positive integer x, and y percent of x equals 100. What is the value of y?
A. 50
B. 100
C. 200
D. 1,000
Answer: A. 50
Explanation: y = 50% of 50% 0f x
= x/4
and
y/100 of x = 100
y /100 *4y =100
y = 50
Answer - A
Question: A man walks at a speed of 3 km/hr and runs at a speed of 7 km/hr. How much time will the man require to cover a distance of 10 1/2 km, if he completes half of the distance, i.e., (5 1/4) km on foot and the other half by running?
A.3 1/2 hours
B.5 1/2 hours
C.2 1/2 hours
D.7 1/2 hours
Answer: C.2 1/2 hours
Explanation: C
Required time = (5 1/4)/3 + (5 1/4)/7 = 2 1/2 hours
Question: the dairy condensed milk has only 20% water while the cow milk has 90% water. How many litres of milkmaid will be obtained from 72 litres of milk?
A.7.2l
B.8.2l
C.9l
D.14.4l
Answer: C.9l
Explanation: milk in 72 liters is7.2l (10%)
now 80% of x=7.2
so answer is 9L
ANSWER:C
Question: If y ≠ 3 and 2 x/y is a prime integer greater than 2, which of the following must be true?
I. x = y
II. y = 1
III. x and y are prime integers.
A.None
B.I only
C.II only
D.III only
Answer: A.None
Explanation: Let 2 x/Y = K , Where k is a prime number > 2 ( 3, 5, 7, 11 ...etc)
so 2x = Ky --> ( 3y or 5y or 7y or 11y etc...)
Which implies always X > Y
So answer is (A)
Question: A certain ski shop sells pairs of gloves in 16 different colors. If one pair of each color is dropped in a bag and a store clerk reaches in to draw two individual gloves simultaneously and at random, what is the probability that she draws two gloves of the same color?
A.1/144
B.1/31
C.1/24
D.1/23
Answer: B.1/31
Explanation: there are 16 different colours sothere are 16 pairs of gloves dropped..
first can be any of 32..so 32/32..
second has to be its pair, which will be just one out of remaining 31.. 1/31..
overall prob=32/32*1/31= 1/31..
B
Question: Seven years ago the average age of a family of 2 members was 32 years. A child has been born. due to Which the average age of the family is 23 years today. What is the present age of the child?
A.40years
B.46years
C.50years
D.52years
Answer: B.46years
Explanation: Explanation:
Average of the family of two numbers
7 years ago = 32
= (32+ 7) * 2 = 46 years
Average age of the family of three members at present = 23 years
= 23 * 3 = 69 YEARS
Age of child = 69 - 64 = 5 years
Answer: Option B
Question: You drive to the store at 20 kmph and return by the same route at 30 kmph. Discounting the time spent at the store, what was your average speed ?
A.14 kmph
B.24 kmph
C.74 kmph
D.64 kmph
Answer: B.24 kmph
Explanation: Explanation:
Average speed=total distance/total time
Let distance to store be K
then, total time =(K/20)+(K/30)=K/12
and, total time =(2K)
so average speed= 2K / (K/12) = 24kmph.
Answer: B
Question: A team of 6 cooks is chosen from 8 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created?
A.140
B.320
C.560
D.700
Answer: D.700
Explanation: Only possible combinations are a team of 2M, 4 W or 3M,3W.
Possible ways to make a team of 2M,4W = 8C2 * 5C4 =28*5 =140
Possible ways to make a team of 3M,3W = 8C3* 5C3 = 56*10 = 560
Total possible ways = 140+560 = 700
Ans D
Question: A tradesman by means of his false balance defrauds to the extent of 25%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
A.44%
B.48%
C.56%
D.45%
Answer: C.56%
Explanation: g% = 25 + 25+ (25*25)/100
= 56%
Answer: C
Question: Kavin has 8 pairs of shoes; each pair is a different color. If Kavin randomly selects 2 shoes without replacement from the 16 shoes, what is the probability that she will select 2 shoes of the same color?
A.2/5
B.1/5
C.1/19
D.1/15
Answer: D.1/15
Explanation: Can be tackled in this way as well: Probability of selecting any 1 out of 16 shoes = 16/16 = 1
Probability of selecting the next shoe (out of 15 available) having the same color = 1/15 (as after selecting the 1st one, there is only 1 another shoe left with the same color).
Thus the total probability = 1*1/15=1/15.
D is the correct answer.
Question: (17)4.5 x (17)? = 178
A.3.5
B.2.75
C.4.25
D.4.5
Answer: A.3.5
Explanation: Solution
let (17)4.5 * (17)x = 178. then, (17)4.5 + x = (17)8.
∴ 4.5 + x = 8 ⇔ x = (8 - 4.5) ⇔ x = 3.5
Answer A
Question: Rice weighing 25/4 pounds was divided equally and placed in 4 containers. How many ounces of rice were in each container? (Note that 1 pound = 16 ounces)
A.22
B.25
C.28
D.31
Answer: B.25
Explanation: 25/4 ÷ 4 = 25/16 pounds in each container
25/16 pounds * 16 ounces / pound = 25 ounces in each container
The answer is B.
Question: If a and b are positive integers and x = 4^a and y = 9^b, which of the following is a possible units digit of xy?
A.1
B.4
C.5
D.7
Answer: B.4
Explanation: unit digit of x=4^a will either be 4 or 6 (4 if a is odd and 6 if a is even)
and unit digit of y=9^b will either be 1 or 9 (9 if b is odd and 1 if b is even)
now we have total 4 possible combinations
1) a=odd, b=odd
unit digit=9*4=6
2)a=odd, b=even
unit digit=4*1=4
3) a=even,b=odd
unit digit=6*9=4
4)a=even, b=even
unit digit=6*1=6
thus, only two values are possible for the unit digits (4 or 6). out of these values only 4 is mentioned in the given choices. hence answer must be B.
Question: The average age of husband, wife and their child 3 years ago was 29 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is
A.22
B.46
C.38
D.21
Answer: B.46
Explanation: Explanation:
Sum of the present ages of husband, wife and child = (29 x 3 + 3 x 3) years = 96 years.
Sum of the present ages of wife and child (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (96 - 50) years = 46 years.
Answer: B
Question: Reena took a loan of 1300 with simple interest for as many years as the rate of interest. If she paid 325 as interest at the end of the loan period, what was the rate of interest?
A.3.6
B.5
C.25
D.Cannot be determined
Answer: B.5
Explanation: Explanation: Let rate = R% and time = R years.
Then, (1300 x R x R)/100 = 325
13RÂ² = 325
RÂ² = 25
R = 5.
Answer: Option B
Question: A fisherman's day is rated as good if he catches 9 fishes, fair if he catches 7 fishes and poor if he catches 5 fishes. The fisherman catches 53 fishes in a week that includes good, fair and poor days. How many poor days the fisherman had during the week?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: Good=9 fish on a days
Fair =7 fish on b days
Poor=5 fish on c days
9a+7b+5c=53
a+b+c=7
c=1
ANSWER:A
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?
A.17/91
B.33/91
C.51/91
D.65/91
Answer: B.33/91
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is = ¹²C₄/¹⁵C₄ = (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12) = 33/91
ANSWER:B
Question: What proximate value should come in place of the question mark (?) in the following question?
7.595 Ã— 1084 + 2568.34 â€“ 1708.34 = ?
A.6,000
B.12,000
C.10,000
D.9068
Answer: D.9068
Explanation: ? â‰ˆ 7.6 Ã— 1080 + 2560 â€“ 1700 â‰ˆ 8208 + 860 â‰ˆ 9068
Answer D
Question: The charge for a single room at Hotel P is 40 percent less than the charge for a single room at Hotel R and 10 percent less than the charge for a single room at Hotel G. The charge for a single room at Hotel R is what percent greater than the charge for a single room at Hotel G ?
A.15%
B.20%
C.40%
D.50%
Answer: D.50%
Explanation: Let rate in R = 100x
then P = 60x
G = 100y
P = 90y
Thus
60 x=90y
or x = 1.50 y
Ans R = 150y
so increase = 50%
Answer: D
Question: The radius of a circular wheel is 1.75 m, how many revolutions will it make in traveling 1 km?
A.1000
B.3898
C.7973
D.2703
Answer: A.1000
Explanation: 2 * 22/7 * 1.75 * x = 11000
x = 1000
Answer: A
Question: Four brothers Adam, Bill, Charles and David together contributed certain amount of money and purchased a car. The contribution made by Adam is half that of the total contribution made by the other three brothers, contribution made by Bill is one-fourth of the total contribution made by the other three brothers and the contribution made by Charles is two-third of the total contribution made by the other three brothers. If the total price of the car is $9600, find the contribution made by David.
A.$540
B.$580
C.$600
D.$640
Answer: D.$640
Explanation: Given that A:(B+C+D)= 1:2.
Hence A contributed 1/3rd of the total price.
Given B:(A+C+D)=1:4
Hence B contributed 1/5th of the total price.
Given C:(A+B+D)=2:3
Hence C contributed 2/5th of the total price.
Thus the contribution made by A,B and C= 1/3+1/5+2/5=14/15
So, the remaining 1/15th of the price is contributed by David.
Hence David's contribution= 1/15×9600=$640.
The answer is D.
Question: A die is thrown twice and the sum of the numbers appearing is observed to be 6.
find the conditional probability that the number 4 has appeared at least once?
A.2/5
B.3/5
C.3/11
D.3/13
Answer: A.2/5
Explanation: Let E be the event that ‘number 4 appears at least once’ and F be
the event
that ‘the sum of the numbers appearing is 6’.
Then, E = {(4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (1,4), (2,4), (3,4),
(5,4), (6,4)}
and F = {(1,5), (2,4), (3,3), (4,2), (5,1)}
We have P(E) = 11/36
and P (F) = 5/36
Also EnF = {(2,4), (4,2)}
Therefore P(EnF) = 2/36
the required probability
P(E|F) = P(EnF)/P(F) = (2/36)/(5/36) = 2/5.
A)
Question: What is the value of (44444445*88888885*44444442+44444438)/44444444^2
A.78888883
B.98888883
C.88888886
D.88888883
Answer: D.88888883
Explanation: let consider x=44444444
(x+1)*(2x-3)*(x-2)+(x-6)/x^2
=2x^3-5x^2/x^2
=2x-5
=2*44444444-5
=88888883
ANSWER:D
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 8 per square feet if there is one door of dimensions 6 feet * 3 feet and three WINDOWS of dimensions 4 feet * 3 feet each?
A.4000
B.345
C.5673
D.7248
Answer: D.7248
Explanation: Area of the four walls = 2h(l + b)
Since there are doors and WINDOWS, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 8 = Rs. 7248
Answer: Option D
Question: The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction?
A.5/4
B.5/5
C.5/2
D.5/9
Answer: D.5/9
Explanation: Let the numerator and denominator of the fraction be 'n' and 'd' respectively.
d = 2n - 1
(n + 1)/(d + 1) = 3/5
5n + 5 = 3d + 3
5n + 5 = 3(2n - 1) + 3 => n = 5
d = 2n - 1 => d = 9
Hence the fraction is : 5/9.
Answer:D
Question: One man adds 5 liters of water to 10 liters of milk and another 4 liters of water to 20 liters of milk. What is the ratio of the strengths of milk in 2 mixtures?
A.4:5
B.9:11
C.2:3
D.4:7
Answer: B.9:11
Explanation: Strength of milk in the mixture = Quantity of milk/total quantity of mixture
strength of milk in the 1st mixture = 10/15
strength of the milk 2nd mixture = 20/24
The ratio of their strengths = 10/15 : 20/24 = 4:5
Answer is B
Question: 7 does not occur in 1000. So we have to count the number of times it appears between 1 and 999. Any number between 1 and 999 can be expressed in the form of xyz where 0 < x, y, z < 9.
A.210
B.300
C.235
D.256
Answer: B.300
Explanation: 1. The numbers in which 7 occurs only once. e.g 7, 17, 78, 217, 743 etc
This means that 7 is one of the digits and the remaining two digits will be any of the other 9 digits (i.e 0 to 9 with the exception of 7)
You have 1*9*9 = 81 such numbers. However, 7 could appear as the first or the second or the third digit. Therefore, there will be 3*81 = 243 numbers (1-digit, 2-digits and 3- digits) in which 7 will appear only once.
In each of these numbers, 7 is written once. Therefore, 243 times.
2. The numbers in which 7 will appear twice. e.g 772 or 377 or 747 or 77
In these numbers, one of the digits is not 7 and it can be any of the 9 digits ( 0 to 9 with the exception of 7).
There will be 9 such numbers. However, this digit which is not 7 can appear in the first or second or the third place. So there are 3 * 9 = 27 such numbers.
In each of these 27 numbers, the digit 7 is written twice. Therefore, 7 is written 54 times.
3. The number in which 7 appears thrice - 777 - 1 number. 7 is written thrice in it.
Therefore, the total number of times the digit 7 is written between 1 and 999 is 243 + 54 + 3 = 300
Ans: B
Question: If x and y are different prime numbers, each greater than 12, which of the following must be true? I. x+y is an even integer II. xy is an odd integer III. (x/y) is not an integer
A.I only
B.I,II and III
C.II only
D.III only
Answer: B.I,II and III
Explanation: Given: x and y are different prime numbers, both greater than 12
Statement I: x+y is an even integer
Since x and y are prime numbers greater than 12, they will be odd
Therefore sum will be even.
Correct
Statement II: xy is an odd integer
Since x and y are prime numbers greater than 12, they will be odd
Therefore multiplication will be odd.
Correct
Statement III: (x/y) is not an integer
Since x and y are prime integers, therefore they will not have any common factor apart from 1
Hence (x/y) will not be an integer
Correct
Hence all three statements I, II and III are correct
Answer : B
Question: A certain truck uses 18 gallons of diesel fuel in traveling 270 miles. In order for the truck to travel the same distance using 10 gallons of diesel fuel, by how many miles per gallon must the truck’s fuel mileage be increased?
A.8
B.9
C.12
D.15
Answer: C.12
Explanation: There are two sets 18G1 gallons and 10G2 gallons details given.
18 gallons covering 270 miles
Then 1 G1 is used to cover 15 miles.
Now for 10 G2 covering 270 miles.
then 1 G2 is used to cover 27 miles.
There must 27 - 15 = 12 miles per gallon increment is needed for 10 gallons to improve the mileage to cover 270 miles.
Answer: C is correct answer.
Question: Set X consists of all two-digit primes and set Y consists of all positive odd multiples of 9 less than 100. If the two sets are combined into one, what will be the range of the new set?
A. 84
B. 89
C. 90
D. 92
Answer: C. 90
Explanation: Set X = {11, 13, 17,............., 83, 89, 97}
Set Y = {9, 27, 45,..............., 63, 81, 99}
Combining two sets, say Set Z
Set Z = {9, 11, 13, 17, 27,..................., 63, 81, 83, 89,97,99}
Range = Max Value - Min Value
Range (Z) = 99 - 9 = 90
OA C is the answer.
Question: What is the present worth of Rs. 165 due in 2 years at 5% simple interest per annum
A.110
B.120
C.130
D.150
Answer: D.150
Explanation: Explanation:
Let the present worth be Rs.x
Then,S.I.= Rs.(165 - x)
= (x*5*2/100) = 165 - x
= 10x = 16500 - 100x
= 110x = 16500
x= 150
Answer: D