RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there in the committee. In how many ways can it be done?
A.1000
B.756
C.480
D.660
Answer: B.756
Explanation: Total Men = 7
Total Women = 6
Persons in committee = 5
No. of ways to select at least 3 men = 7C5 + 7C4 * 6C1 + 7C3*6C2
= 756
Ans - B
Question: Consider the sets Tn= {n, n + 1, n + 2, n + 3, n + 4), where n = 1, 2, 3, … , 96. How many of these sets contain 6 or any integral multiple thereof (i.e., any one of the numbers 6, 12, 18, …)?
A.80
B.81
C.82
D.83
Answer: A.80
Explanation: Explanation :
If n = 1, then the set T1 = {1,2,3,4,5}, and it does not have 6 or any multiples.
n = 2 to n = 6 has 6 in the set.
n = 7, has the set T7 = {7,8,9,10,11}, and no 6 or multiples.
So 1 in every 6 members do not have 6 or multiples of 6.
So, till n = 96, there are 16 sets of “6 members” (16*6 = 96) and 16 sets do not have 6 or its multiples, while the remaining 80 sets have.
Answer : A
Question: A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corner, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is
A.6420
B.8960
C.5120
D.4830
Answer: C.5120
Explanation: Sol.
Clearly, l = (48 - 16) m = 32 m,
b = (36 - 16) m = 20 m,
h= 8 m.
∴ Volume of the box = (32 x 20 x 8) m3 = 5120 m3
Answer C
Question: f(x) is a function such that f(2x + 1) = 2f(x) + 1 for all real numbers x and f(0) = 2. Find the value of f(3).
A.10
B.11
C.12
D.13
Answer: B.11
Explanation: f(2x + 1) = 2f(x) + 1 : given
f(3) = 2f(1) + 1 : x = 1 in A
f(1) = 2f(0) + 1 : x = 0 in A
f(3) = 11 : substitute
correct answer B
Question: How many triples (a, b, c) of real numbers satisfy the equations
ab = c, ac = b, and bc = a ?
A.2
B.4
C.5
D.6
Answer: C.5
Explanation: Observe that (0, 0, 0) is a triple as in the problem. Now, if one of a, b and c is 0, then the given
equations imply each of them is 0. So we suppose next that each is non-zero. The equations ab = c
and ac = b imply a2bc = bc so that a2 = 1. Hence, a 2 {1,−1}. Similarly, b 2 {1,−1} and
c 2 {1,−1}. One checks that these imply that either (a, b, c) = (1, 1, 1) or exactly one of a, b and
c is 1 and the other two are −1. These observations lead to the total number of tuples being 5.
correct answer C
Question: An office supply store stocks two sizes of notebooks, each in five colors: blue, green, yellow, red, or pink. The store packs the notebooks in packages that contain either 3 notebooks of the same size and the same color or 3 notebooks of the same size and of 3 different colors. If the order in which the colors are packed is not considered, how many different packages of the types described above are possible?
A.15
B.20
C.24
D.30
Answer: D.30
Explanation: First let's consider the small notebooks.
There are 5 ways to choose 3 notebooks of the same color.
The number of ways to choose 3 notebooks with different colors is 5C3=10.
There are 15 different packages we can make with the small notebooks.
We can use the same process to find 15 different packages with large notebooks.
The total number of different packages is 30.
The answer is D.
Question: 445, 221, 109, 53,...
A.8
B.7
C.42
D.25
Answer: D.25
Explanation: Explanation :
To obtain next number, subtract 3 from the previous number and divide the result by 2
445
(445-3)/2=221
(221-3)/2=109
(109-3)/2=53
(53-3)/2=25
ANSWER:D
Question: You have to send 3,000 grapes 1,000 kilometers from grapecity to appleland. Your truck can carry 1,000 grapes at a time. Every time you travel a kilometer towards appleland you must pay a tax of 1 grape but you pay nothing when going in the other direction (towards grapecity).
What is highest number of grapes you can get to appleland?
A.833
B.765
C.665
D.679
Answer: A.833
Explanation: Step one: First you want to make 3 trips of 1,000 grapes 333 kilometers. You will be left with 2,001 grapes and 667 kilometers to go.
Step two: Next you want to take 2 trips of 1,000 grapes 500 kilometers. You will be left with 1,000 grapes and 167 kilometers to go (you have to leave a grape behind).
Step three: Finally, you travel the last 167 kilometers with one load of 1,000 grapes and are left with 833 grapes in appleland.
correct answer is A)833
Question: A shepherd had n goats in the year 2000. In 2001 the no. of goats increased by 40%. In 2002 the no. of goats declined to 70%. In 2003 the no. of goats grew up 30%. In 2004, he sold 10% goats and then he had only 34,398 goats. The percentage increase of the no. of goats in this duration was :
A.16.66%
B.14.66%
C.11.33%
D.20%
Answer: B.14.66%
Explanation: Solution: There is no need of the number of goats given i.e. 34,398.
Initially, let there be 100 goats. Then
100 == 40% ↑==> 140 ==30%↓(declined to 70%)==> 98 ==30%↑ ==> 127.4 ==10%↓(sold)==> 114.66
Hence, % increase = 14.66% [As 100 becomes 114.66].
Answer: Option B
Question: On a track for remote controlled racing cars, racing car A completes the track in 58 seconds, while racing car B completes it in 35 seconds. If they both start at the same time after how many seconds will they be side by side again.
A.275
B.325
C.2030
D.425
Answer: C.2030
Explanation: Time required in seconds will be LCM ( 35, 58 ) = 2030
Hence, answer will be (C) 2030
Question: A sports retailer ordered white and yellow tennis balls in equal number but the dispatch clerk of the tennis ball company erred and dispatched 20 extra yellow balls and making ratio of white balls to yellow balls 8/13. How many tennis balls did the retailer order originally.
A.64
B.130
C.140
D.160
Answer: A.64
Explanation: White:Yellow = x:(x+20) = 8:13 --> 13x = 8x + 160 --> x = 32.
The total # of balls originally x + x = 32 + 32 = 64.
Answer: A.
Question: The sum of ages of 5 children born at the intervals of 3 years each is
50 years. Find out the age of the youngest child?
A.6 years
B.5 years
C.4 years
D.2 years
Answer: C.4 years
Explanation: Let the age of the youngest child =x
Then, the ages of 5 children can be written as x,(x+3),(x+6),(x+9) and (x+12)
x+(x+3)+(x+6)+(x+9)x+(x+3)+(x+12)=50
5x+30=50
5x=20
x=20/5=4 Answer: Option C
Question: Robert is traveling on his cycle and has calculated to reach point A at 2 p.m. if he travels at 10 km/hr; he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 p.m.?
A.22
B.88
C.12
D.77
Answer: C.12
Explanation: Let the distance traveled be x km.
Then, x/10 - x/15 = 2
3x - 2x = 60 => x = 60 km.
Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.
So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.
Required speed = 60/5 = 12 kmph.
Answer:C
Question: Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is ?
A.5/19
B.5/12
C.5/29
D.5/20
Answer: B.5/12
Explanation: Using question number 11 and 12, we get the probability as
1 - (1/36 + 5/9)
= 5/12
Answer:B
Question: A total of 502 players participated in a single tennis knock out tournament. What is the total number of matches played in the tournament? (Knockout means if a player loses, he is out of the tournament). No match ends in a tie.
A.501
B.512
C.256
D.255
Answer: A.501
Explanation: There are 502 players, only 1 person wins, 501 players lose. in order to lose, you must have lost a game.
501 games.
ANs- A
Question: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
A.20
B.70
C.77
D.26
Answer: B.70
Explanation: Let C.P. = Rs. 100. Then, profit = Rs. 320, S.P. = Rs. 420
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 420
Profit = 420 - 125 = Rs. 295
Required percentage = 295/420 * 100 = 1475/21 = 70%
Answer:B
Question: Out of three consecutive odd numbers fifteen times the first number is equal to addition of thrice the third number and adding 15 to six times the second . What is the first number?
A.11/3
B.12/5
C.13/6
D.13/2
Answer: D.13/2
Explanation: Description :
=> 15x=6(x+2)+15+3(x+4)
=> 15x=9x+39
=>6x = 39
X=13/2
Answer D
Question: Difference between the length &breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is?? We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103?
A.2300 m^2
B.2350 m^2
C.2520 m^2
D.2620 m^2
Answer: C.2520 m^2
Explanation: Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) m2 = 2520 m^2
C
Question: The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be
A.15 years
B.18 years
C.20 years
D.22 years
Answer: C.20 years
Explanation: Explanation:
Clue : (60 - x) - 6 = 5(x - 6)
Option C
Question: Four car rental agencies A, B, C and D rented a plot for parking their cars during the night. A parked 15 cars for 12 days, B parked 12 cars for 20 days, C parked 18 cars for 18 days and D parked 16 cars for 15 days. If A paid Rs. 1125 as rent for parking his cars, what is the total rent paid by all the four agencies?
A.Rs.6119
B.Rs.6129
C.Rs.6115
D.Rs.6150
Answer: D.Rs.6150
Explanation: The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15
= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60
Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.
The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k
It is given that A paid Rs. 1125
45k = 1125 => k = 25
246k = 246(25) = Rs. 6150
Thus the total rent paid by all the four agencies is Rs.6150.
Answer: D
Question: 33 1/3% OF 210?
A.70
B.90
C.110
D.120
Answer: A.70
Explanation: 33 1/3 % = 1/3
1/3 × 210 = 70
A)
Question: A 4% stock yield 5%. The market value of the stock is ?
A.Rs. 125
B.Rs. 80
C.Rs. 99
D.Rs. 109
Answer: B.Rs. 80
Explanation: For an income of Rs. 5, investment = Rs. 100
For an income of Rs. 4, investment = Rs. (100/5) x 4 = Rs. 80
Answer : B
Question: The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 13 runs. Find his average in all the 30 matches?
A.31
B.86
C.82
D.15
Answer: A.31
Explanation: Total score of the batsman in 20 matches = 800.
Total score of the batsman in the next 10 matches = 130.
Total score of the batsman in the 30 matches = 930.
Average score of the batsman = 930/30 =31.
Answer:A
Question: Raman mixed 24 kg of butter at Rs. 150 per kg with 36 kg butter at the rate of Rs. 125 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
A.129
B.128
C.189
D.187
Answer: C.189
Explanation: CP per kg of mixture = [24(150) + 36(125)]/(24 + 36) = Rs. 135
SP = CP[(100 + profit%)/100]
= 135 * [(100 + 40)/100] = Rs. 189.
Answer: C
Question: In a two-digit, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is:
A.24
B.26
C.42
D.46
Answer: A.24
Explanation: Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2.
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2)(2x + 2) = 144
22x2 + 26x - 140 = 0
11x2 + 13x - 70 = 0
(x - 2)(11x + 35) = 0
x = 2.
Hence, required number = 11x + 2 = 24.
ANSWER : A
Question: In the arithmetic sequence t1, t2, t3, ..., tn, t1=23 and tn= tn-1 - 3 for each n > 1. What is the value of n when tn = -1?
A.-1
B.9
C.10
D.14
Answer: B.9
Explanation: We know that t1 = 23
So, using the given formula we have:
t1=(t1-1) -3 =23
t0 - 3 = 23
t0= 26
The same way we find that t2= 20
It seems that the sequence goes like this:
t0 = 26
t1 = 23
t2 = 20
t3 = 17
t4 = 14
t5 = 11
t6 = 8
t7 = 5
t8 = 2
t9 = -1
So, ourANS is B.
Question: Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.441 in 2 years?
A.Rs.900
B.Rs.800
C.Rs.500
D.Rs. 400
Answer: D.Rs. 400
Explanation: Explanation:
441 = P(21/20)2
P =Rs.400
Answer:D
Question: When a random experiment is conducted, the probability that event A occurs is 1/5. If the random experiment is conducted 4 independent times, what is the probability that event A occurs exactly twice?
A.16/625
B.56/625
C.96/625
D.126/625
Answer: C.96/625
Explanation: One case is: 1/5*1/5*4/5*4/5=16/625
The total number of possible cases is 4C2 = 6
P(event A occurs exactly twice) = 6*(16/625) = 96/625
The answer is C.
Question: The events A and B are independent, the probability that event A occurs is greater than 0, and the probability that event A occurs is twice the probability that event B occurs. The probability that at least one of events A and B occurs is 14 times the probability that both events A and B occur. What is the probability that event A occurs?
A.77/2
B.1/7
C.78/85
D.1/5
Answer: D.1/5
Explanation: Let us say probability of A occuring is a.
Let us say probability of B occuring is b.
a = 2b
Probability (either A or B or both) =14 times Probability (A and B)
a*(1-b) + b*(1-a) + ab = 14*ab
Substituting a=2b in the second equation:
2b*(1-b) + b*(1-2b) + 2b*b = 14*2b*b
3b-2b^2 = 28b^2
3b = 30b^2
b = 3/30 = 1/10
So, a = 2b = 1/5
THE CORRECT ANSWER IS D.
Question: A train travelled from point A to point B at 160 Km/h. On its way back the train travelled at 120 Km/h and therefore the trip back lasted one hour longer. What is the distance (in Km) between A and B?
A.480.
B.500.
C.510.
D.600.
Answer: A.480.
Explanation: distance=speed*time
d1=s1t1
d2=s2t2
The distance from point A to point B is the same for each trip so,
d1=d2 and
t2=t1+1
thus,
s1t1=s2(t1+1)
160t1=120(t1+1)
t1=3
160*3=480
Answer: A
Question: In how many ways 6 boys and 6 girls can be seated in a row so that boys and girls are alternate?
A.1063800
B.1083600
C.1036800
D.1053800
Answer: C.1036800
Explanation: number of ways = 2*6!*6! = 1036800
Answer is C
Question: The cost price of 17 articles is equal to the selling price of 11 articles. Find the profit percent?
A.18 2/15
B.36 2/11
C.45 2/14
D.54 6/11
Answer: D.54 6/11
Explanation: 17 CP = 11 SP
11 --- 2 CP
100 --- ? =>54 6/11%.Answer: D
Question: A part of certain sum of money is invested at 9% per annum and the rest at 12% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
A.4:7
B.4:0
C.4:3
D.4:1
Answer: C.4:3
Explanation: 12:9
= 4:3
Answer: C
Question: Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 5625 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.
A.2304
B.2305
C.2309
D.2310
Answer: A.2304
Explanation: Trees increase by 1/4 the number of trees in preceding year. Hence, correct answer must be divisible by 4. Based on divisibility rules, if last 2 digits are divisible by 4 then the number is divisible by 4. Thus, we can eliminate B, C,D,E The answer to be A
Again, trees increase by 1/4 the number of trees in preceding year. Hence, the number of trees increase by 5/4 times the number of trees the preceding year.
If x = initial number of trees = 2304
Year 1 = 5/4x
Year 2 = (5/4)(5/4)x
Year 3 = (5/4)(5/4)(5/4)x
Year 4 = (5/4)(5/4)(5/4)(5/4)x
Only for Answer D: (5/4)(5/4)(5/4)(5/4)2304 = 5625
Hence, correct answer = A
Question: A number exceeds by 35 from its 3/8 part. Then the number is?
A.A)56
B.B)35
C.C)39
D.D)40
Answer: A.A)56
Explanation: x – 3/8 x = 35
x = 56
ANSWER:A
Question: A shopkeeper sells 10% of his stock at 20% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock?
A.20000
B.16000
C.18000
D.17000
Answer: B.16000
Explanation: Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/10 * x * 6/5 = 6x/50
The SP of 80% of the stock = 9/10* x * 0.95 = 171x/200
Total SP = 24x/200+171/200= 49x/50
Overall loss = x - 195/20050 = 5x/200
5x/200 = 400 => x = 16000
Answer:B
Question: Find the ratio of speed of truck to train if truck covers 550m in 1 minute and train covers 33 km in 45 min.
A.3:9
B.8
C.3:2
D.3:4
Answer: D.3:4
Explanation: Explanation:
Using the formula, speed=distance/time
Speed of truck = 550/60 m/s
Speed of train= 33000/(45*60) m/s
Ratio of speed of truck to train= (550/60 ) / [33000/(45*60)]
=3:4
Hence, the ratio is 3:4
ANSWER: D
Question: If a quality control check is made inspecting a sample of 2 light bulbs from a box of 12 lighbulbs, how many different samples can be chosen?
A.6
B.24
C.36
D.66
Answer: D.66
Explanation: Try using the formula for combinations:
n!/r!(n-r)!
12!/2!(12-2)!
12!/2!*10!
12*11/2*1
=66
ANSWER:D
Question: The population of a city increases by 5% per year but due to migration it decrease by 1% per years. What will be the percentage increase in population in 3 years?
A.9%
B.9.27%
C.27%
D.12.48%
Answer: D.12.48%
Explanation: Actual increase in population=4%
Let, earlier population=100 then the population after 3 years
=100(1+4/100)^3=112.4864
∴Required percentage=12.48%
ANSWER:D
Question: A wheel that has 12 cogs is meshed with a larger wheel of 21 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions made by the larger wheel is:
A.12
B.10
C.6
D.8
Answer: A.12
Explanation: Explanation :
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
21:12::21:x => 21 * x = 21 * 12
=> x = (21 * 12)/21
=> x = 12
Answer : A
Question: Anand and Deepak started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Deepak's share is:
A.Rs. 5400
B.Rs. 7200
C.Rs. 8400
D.Rs. 9600
Answer: C.Rs. 8400
Explanation: Ratio of their shares = 22500 : 35000 = 9:14
Deepak's share = 13800 * 14/23 = Rs. 8400.
ANSWER:C
Question: A student took 6 courses last year and received an average (arithmetic mean) grade of 100 points. The year before, the student took 5 courses and received an average grade of 70 points. To the nearest tenth of a point, what was the student’s average grade for the entire two-year period?
A.79
B.89
C.95
D.86.36
Answer: D.86.36
Explanation: Let the 6 courses that were taken last year be A1 , A2, A3 , A4 , A5 , A6
A1+A2+A3+A4+A5+A6 = 100*6 = 600
The year before , the 5 courses be B1, B2 , B3 , B4 , B5
B1+B2+B3+B4+B5 = 70*5 = 350
Student's average = (600+350)/11 = 86.36
Answer D
Question: A man said to his son, "I was two-third of your present age when you were born". If the present age of the man is 48 years, find the present age of the son?
A.28.9
B.28.0
C.28.4
D.28.8
Answer: D.28.8
Explanation: Present age of the son be P, he was born P years ago.
The age of the man was: (48 - P).
His age when the son was born should be equal to 2/3 of P.
(48 - P) = 2/3 P
5P = 144 => P = 28.8
Answer: D
Question: Insert the missing number
17, 7, 24, 19, 9, 28, ..., 8, 31
A.20
B.21
C.18
D.23
Answer: D.23
Explanation: 17+7=24
19+9=28
x+8=31
therefore x=23
ANSWER:D
Question: In what ratio should a variety of rice costing Rs. 6 per kg be mixed with another variety of rice costing Rs. 8.75 per kg to obtain a mixture costing Rs. 7.50 per kg?
A.5/6
B.5/9
C.5/2
D.5/1
Answer: A.5/6
Explanation: Explanation:
Let us say the ratio of the quantities of cheaper and dearer varieties = x : y
By the rule of allegation, x/y = (87.5 - 7.50) / (7.50 - 6) = 5/6
Answer: A
Question: What is the remainder of Q= 3^19 when divided by 10?
A.0
B.1
C.5
D.7
Answer: D.7
Explanation: I looked for patterns:
^2 - units digit 9
^3 - units digit 7
^4 - units digit 1
^5 - units digit 3
hence, we can see that when raised to a power which is multiple of 4, the units digit is 1, and when to an even power not multiple of 4, the units digit is 9
and we can then see:
^16 - units digit 1, or
^18 - units digit 9
and ^19 - units digit 7
therefore, Q=when divided by 10, the remainder must be 7.D
Question: If Samson's home is 100 meters to his workplace and he trek's to work everyday, which of the following could be true?
I. Samson treks at least a distance of 200 meters everyday.
II. In 3 days, Samson would have covered a distance of 600 meters.
III. Daniel's work place is less than 100 meters from Samson's home.
A. I only
B. I and II only
C. I and III only
D. II and III only
Answer: B. I and II only
Explanation: Let's Check each Statement.
Statement I: Samson treks at least a distance of 200 meters everyday. He treks 100 meters to work and 100 meters back to work. 100meters + 100 meters = 200 meters, in which case Statement I is True.
Statement II: In 3 days, Samson would have covered a distance of 600 meters. Each day he treks 200 meters. 3 days will be 200 meters * 3 = 600 meters, in which case Statement II is TRUE.
Statement III: Daniel's work place is less than 100 meters from Samson's home. Distance from work to school is equal to distance from school to work, in which case Statement III can NEVER BE TRUE.
Only Statement I and II are True. So, the Correct answer is B
Question: A man has Rs. 720 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
A.33
B.38
C.135
D.90
Answer: C.135
Explanation: Let number of notes of each denomination be x.
Then x + 5x + 10x = 720
⇒ 16x = 720
∴ x = 45.
Hence, total number of notes = 3x = 135
Answer:C
Question: When asked what the time is,a person answered that the amount of time left is 4/8 of the time already completed.what is the time.
A.2 PM
B.9 PM
C.4 PM
D.8 PM
Answer: C.4 PM
Explanation: A day has 24 hrs. Assume x hours have passed. Remaining time is (24 - x)
24−x=4/8x⇒x=20
Time is 4 PM
Answer:C
Question: Two years ago, Arthur gave each of his five children 20 percent of his fortune to invest in any way they saw Fit. In the first year, three of the children, Alice, Bob, and Carol, each earned a profit of 50 percent on their Investments, while two of the children, Dave and Errol, lost 40 percent on their investments. In the second Year, Alice and Bob each earned a 20 percent profit, Carol lost 60 percent, Dave earned 25 percent in profit, And Errol lost all the money he had remaining. What percentage of Arthur's fortune currently remains?
A.99%
B.97%
C.100%
D.107%
Answer: A.99%
Explanation: Say Arthur's fortune was $100. Then:
A = 20*1.5*1.2 = 36
B = 20*1.5*1.2 = 36
C = 20*1.5*0.4 = 12
D = 20*0.6*1.25 = 15
E = 0
Total 39 + 39 + 12 + 15 = 99.
Answer: A.
Question: If .08216 and 68.01 are multiplied to give x as product , how many digit to the right of the decimal point does x have?
A.8
B.7
C.6
D.8
Answer: B.7
Explanation: Product of .08216 and 68.01 is 5.5877016.
Therefore number of digits to right of decimal point is 7
Answer is B.
Question: The sum of ages of 4 children born at the intervals of 10 years each is 80 years. What is the age of the youngest child?
A.4
B.5
C.6
D.7
Answer: B.5
Explanation: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 10) + (x + 20) + (x + 30) = 80
4x = 20
x = 5.
Age of the youngest child = x = 5 years.
Answer:B
Question: A CAN FINISH A WORK IN 9 DAYS AND B CAN DO THE SAME WORK IN15 DAYS. B WORKED FOR 10 DAYS AND LEFT THE JOB. IN HOW MANY DAYS, A ALONE CAN FINISH THE REMAINING WORK?
A.3
B.5 1/2
C.6
D.8
Answer: A.3
Explanation: B'S 10 DAY'S WORK=(1/15*10)=2/3 REMAINING WORK = (1-2/3)=1/3
NOW, 1/18 WORK IS DONE BY A IN 1 DAY
1/3 WORK IS DONE BY A IN (9*1/3)=3 DAYS.
CORRECT OPTION:A
Question: Stuart bought a sweater on sale for 30% off the original price and another 25% off the discounted price. If the original price of the sweater was $40, what was the final price of the sweater?
A.$25.75
B.$35.75
C.$15.75
D.$ 21
Answer: D.$ 21
Explanation: The price with 30% off
40 - 30% of 40 = 40 - (30 / 100) *40 = 40 - 12 = 28
The price with another 25% off
28 - 25% of 28 = 28 - (25/100)* 28
= $21
correct answer D
Question: When 21 is divided by the positive integer k, the remainder is 3, for how many different values of k is this true?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: This means that 18 must be a multiple of k.
The factors of 18 are 1, 2, 3, 6, 9, and 18.
Out of these, k can be 6, 9, and 18.
The answer is C.