RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: How many cases do you need if you have to pack 112 pairs of shoes into cases that each hold 28 shoes?
A.4
B.9
C.8
D.4
Answer: C.8
Explanation: C
8
112 pairs of shoes = 224 shoes.
224 ÷ 28 = 8.
Question: The concentration of spirit in three different vessels A, B and C are 45%, 30% and 16% respectively. If 4 litres from vessel A, 5 litres from vessel B and 6 litres from vessel C are mixed, find the concentration of spirit in the resultant solution.
A.32.10%
B.33.60%
C.34%
D.28.40%
Answer: D.28.40%
Explanation: Quantity of spirit in new solution=(4*45/100)+(5*30/100)+(6*16/100)=1.8+1.5+1.5=4.26 liters
So % concentration of spirit=100*4.26/(4+5+6)=28.40%
ANSWER:D
Question: In a BCCI meeting there are 13 people. All shake hands with each other once. How many handshakes will be there altogether?
A.28
B.12
C.13
D.19
Answer: B.12
Explanation: There will be n-1 handshakes as A person will shake hands with all the other members.
=13-1=12
Answer:B
Question: Bill has a small deck of 12 playing cards made up of only 2 suits of 6 cards each. Each of the 6 cards within a suit has a different value from 1 to 6; thus, there are 2 cards in the deck that have the same value. Bill likes to play a game in which he shuffles the deck, turns over 5 cards, and looks for pairs of cards that have the same value. What is the chance that Bill finds at least one pair of cards that have the same value?
A.15/23
B.25/33
C.35/43
D.45/53
Answer: B.25/33
Explanation: P(no pairs) = 10/11*8/10*6/9*4/8 = 8/33
P(at least one pair) = 1 - 8/33 = 25/33
The answer is B.
Question: If MELT is coded as 54 and WATER is coded as 42, then PRESSED is coded as
A.39
B.44
C.48
D.56
Answer: C.48
Explanation: MELTS = 13+5+12+20+19=69 i.e 6*9=54
WATER= 23+1+20+5+18=67 i.e 6*7=42
PRESSED= 16+18+5+19+19+5+4=86 8*6=48
ANSWER:C
Question: A guy was asked to specify his age in years. He said, “Take my age 7 years hence, multiply it by seven and subtract seven times of my age 7 years ago and get the half of the result , you will know my age.” What was the age of that guy?
A.18
B.25
C.33
D.49
Answer: D.49
Explanation: Current age of the guy = A years.
Then, 7 (A + 7) – 7 (A – 7) = A
(7A + 49) – (7A – 49) = A
A = 98/2=49
D
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?
A.180
B.190
C.120
D.130
Answer: B.190
Explanation: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 1900 m
T = D/S
T = 1900/10
T = 190 Sec
Answer: Option B
Question: Profit earned by an organization is distributed among officers and clerks in the ratio of 5:3 respectively. If the number of officers is 45 and the number of clerks is 80 and the amount received by each officer is Rs.25,000/-, what was the total amount of profit earned?
A.Rs.22 lakhs
B.Rs.18.25 lakhs
C.Rs.18 lakhs
D.Rs.23.25 lakhs
Answer: C.Rs.18 lakhs
Explanation: Explanation:
The total amount distributed among 45 officers = Rs.45x25000 = Rs.1125000.
Let the amount distributed to 80 clerks be ‘x’.
Then 1125000/x = 5/3, therefore, x = Rs.675000.
Therfore, the Total profit = Rs.1125000 + 675000 = Rs.18 lakhs
Answer: Option C
Question: The traffic lights at 3 different roads change after every 12 sec, 15 sec, 21 sec respectively. If they all change simultaneously at 8 AM then at what time will they again change simultaneously.
A.8:15
B.8:42
C.8:07
D.9:01
Answer: C.8:07
Explanation: LCM of 12,15,21 = 420 = 7mnts
The lines will change every 7m
The light will change again after 8 AM is = 9:00+0:07 = 8:07
Answer is C
Question: A sum of Rs. 2500 amounts to Rs. 3875 in 4 years at the rate of simple interest. What is the rate of interest?
A.12.25%
B.12%
C.6%
D.13.75%
Answer: D.13.75%
Explanation: Explanation :
Simple Interest, SI = (3875 - 2500) = Rs.1375
Principal, P = Rs. 2500
Time, T = 4 years
R = ?
R=100×SI/PT
=100×1375/2500×4
100×1375/10000
=13.75%
Question: If Rs. 782 is divided into three parts, proportional to
1/2:2/3:3/4
A.190
B.204
C.220
D.230
Answer: B.204
Explanation: Explanation:
1/2:2/3:3/4
=6:8:9
First part =782∗6/23
=204
ANSWER IS B
Question: Share Rs.6600 among John, Jose & Binoy in the ration 2 : 4 : 6.Find the amount received by John?
A.2200
B.980
C.1200
D.1240
Answer: A.2200
Explanation: Amount received by sanjay.
4 / 12 X 6600 = 2200= ( related ratio / sum of ratio ) x Total amount
So, the Amount received by sanjay is 2200.
A
Question: John earned 40% more per month than Oscar. If john salary is decreased 10% and Oscar’s salary is increased by 10%, then john would be earning what percent more than Oscar?
A.10%
B.9.09%
C.15.54%
D.14.54%
Answer: D.14.54%
Explanation: This Q is all about taking the correct BASE for taking %s..
the very first step requires taking some numbers for each..
ONE should be 100...
it is easy to take 60 and 100 here..
but the BASE is 100 here, so the salary can be 100 and 140..
100 increases 10% =110..
140 decreases 10%=126..
so the increase is 16..
again the BASE is 110, so answer 16/110 * 100= 14.54% C
without calculations,
answer cannot be equal to or greater than 16, as 16 is on 110..
so D is the only one left
Question: In what time will a train 100 m long cross an electric pole, it its speed be 216 km/hr?
A.2.5 sec
B.2.9 sec
C.1.7 sec
D.7.5 sec
Answer: C.1.7 sec
Explanation: Speed = 215 * 5/18 = 60 m/sec
Time taken = 100/60
= 1.7 sec.
Answer: C
Question: There is a 30% chance Sandy will visit China this year, while there is a 60% chance that she will visit Malaysia this year. What is the probability that Sandy will visit either China or Malaysia this year, but NOT both?
A.42%
B.48%
C.54%
D.60%
Answer: C.54%
Explanation: P(China and not Malaysia) = 0.3*0.4 = 0.12
P(Malaysia and not China) = 0.6*0.7 = 0.42
Total probability = 0.12 + 0.42 = 0.54 = 54%
The answer is C.
Question: The average of 11numbers is 60. Out of 11numbers the average of first 6no. is 88, and last 6numbers is 65 then find 6th number?
A.A)258
B.B)65
C.C)58
D.D)62
Answer: A.A)258
Explanation: 6th number = sum of 1st 6no.s + sum of last 6no.s - sum of 11no.s
answer = 6*88+6*65-11*60 = 258
Answer is A
Question: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
A.7
B.4
C.9
D.3
Answer: B.4
Explanation: M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9 = 4
Answer:B
Question: A starts business with a capital of Rs.1200 B and C join with some investments after 3 and 6 months respectively. If the end of a year, the profit is divided in the ratio 2:3:5 respectively. What is B's investment in the business?
A.2400
B.2880
C.2787
D.3087
Answer: A.2400
Explanation: 1200 * 12: x * 9 = 2:3
x = 2400
Answer: A
Question: If x^3 is divisible by 240 what is the least possible value of integer x?
A.12
B.30
C.60
D.90
Answer: C.60
Explanation: 240 can be written as (2^4)*3*5.
For k^3 to be divisible by 240 it should contain atleast 2^4 and 3 and 5 in its factors. We can leave out option A because 12 doesnt have 5 as one of its factor. Now if we check for option B, 30 can be written as 2*3*5, hence 30^3 will have 3 as the maximum power of 2, so we can leave out this option too.
Option C is the right answer if we follow the same method as we followed for other two previous options.
60 = (2^2)*3*5; 60^3 = (2^6)*(3^3)*(5^3). So it shows that 60^3 is divisible by 240 and hence the answer.
Answer : C
Question: Monica planned her birthday party. She prepared 5 muffins for each of her guests and kept aside two additional muffins in case someone will want extra. After the party, it turned out that one of the guests didn't come but every one of the guests that did come ate six muffins and 5 muffins remained. How many guests did Monica plan on?
A.9.
B.4.
C.3.
D.6.
Answer: C.3.
Explanation: 5N +2 = 5 + 6(N-1)
Solving N= 3
Hence C
Question: What will Rs.1500 amount to in three years if it is invested in 20% p.a. compound interest, interest being compounded annually?
A.Rs.2592
B.Rs.2492
C.Rs.2352
D.Rs.2382
Answer: A.Rs.2592
Explanation: The usual way to find the compound interest is given by the formula A = .p(1+r/100)^n
In this formula,
A is the amount at the end of the period of investment
P is the principal that is invested
r is the rate of interest in % p.a
And n is the number of years for which the principal has been invested.
In this case, it would turn out to be A =1500(1+20/100)3
= 2592. Answer: A
Question: If xy ≠ 0 and x^2y^2 − xy = 30, which of the following could be y in terms of x?
I. 6/x
II. -5/x
III. 3/x
A.I only
B.II only
C.I and II only
D.I and III
Answer: C.I and II only
Explanation: (x^2)(y^2) – xy - 30 = 0
(xy – 6)(xy + 5) = 0
xy – 6 = 0 or xy + 5 = 0
xy = 6 or xy = -5
Since we need y in terms of x, we can isolate y in both of our equations.
y = 6/x or y = -5/x
Answer: C
Question: The C.I. on a certain sum for 2 years at 10% per annum is Rs. 525. The S.I. on the same sum for double the time at half the rate percent per annum is?
A.2387
B.500
C.286
D.298
Answer: B.500
Explanation: Let the sum be Rs. P. Then,
[P(1 + 10/100)2 - p] = 525
P[(11/10)2 - 1] = 525
P = (525 * 100) / 21 = 2500
Sum = Rs. 2500
So, S.I. = (2500 * 5 * 4)/100 = Rs. 500
Answer: B
Question: Working alone at their respective constant rates, A can complete a task in ‘a’ days and B in ‘b’ days. They take turns in doing the task with each working 2 days at a time. If A starts they finish the task in exact 8 days. If B starts, they take a day more. How long does it take to complete the task if they both work together?
A.6
B.7
C.8
D.4
Answer: D.4
Explanation: Work done by AB in a day = xy respectively.
When A starts:
No. of days when A works = 4No. of days when B works = 4 → 4x + 4y = 1
When B starts:
No. of days when A works = 5No. of days when B works = 3 → 5x + 3y = 1
Solving the above two equations for xy
x = 1/8 y = 1/8
→ Total work done by AB in a day = 1/8 + 1/8 = 1/4
→ No. of days to complete the work when both work together = 4
Answer: D
Question: The compound ratio of 2/3, 6/7, 1/3 and 1/9 is given by?
A.7/98
B.1/48
C.4/189
D.1/96
Answer: C.4/189
Explanation: 2/3 * 6/7 * 1/3 * 1/9 = 12/567 = 4/189
ANSWER:C
Question: A man sold 20 articles for $60 and gained 10%. How many articles should he sell for $90 to incur a loss 20%?
A.45
B.36
C.40
D.50
Answer: C.40
Explanation: Production cost per article: $60*(100%-10%) / 20 = $2.70
Required production costs for a loss of 20%: $90*(100% + 20%) = $108
Number of articles to be sold for $108 to incur a 20% loss: $108 / $2.70 = 40
Thus, solution C is correct.
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 420 m and they cross each other in 24 sec, then the speed of each train is?
A.63
B.89
C.36
D.34
Answer: A.63
Explanation: Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (420 + 420)/24 => x = 17.5
Speed of each train = 17.5 m/sec.
= 17.5 * 18/5 =63 km/hr.
Answer: Option A
Question: The radius of the two circular fields is in the ratio 3: 10 the area of the first field is what percent less than the area of the second?
A.71%
B.51%
C.91%
D.81%
Answer: C.91%
Explanation: r = 3 Ï€r2 = 9
r = 10 Ï€r2 = 100
100 Ï€ â€“ 9Ï€=91
100 ---- ? => 91%.Answer:C
Question: The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.1045.What was his original salary?
A.1009
B.1018
C.1000
D.1082
Answer: C.1000
Explanation: X * (110/100) * (95/100) = 1045
X * (11/10) * (1/100) = 11
X = 1000
Answer:C
Question: A man on tour travels first 120 km at 60 km/hr and the next 160 km at 80 km/hr. Find the average speed for first 280 km of tour.
A.70.00 km/hr
B.71.11 km/hr
C.72.11 km/hr
D.73.11 km/hr
Answer: A.70.00 km/hr
Explanation: Explanation:
We know Time = Distance/speed
So total time taken =
(120/60+160/80)=4hours
Time taken for 280 Km = 280/4=70.km/hr
Option A
Question: Anne bought doughnuts for a class breakfast party. She bought 15 chocolate doughnuts, 12 coconut doughnuts, and 14 jam-filled doughnuts. How many doughnuts did Anne buy in all?
A.41
B.36
C.39
D.21
Answer: A.41
Explanation: Add the numbers of doughnuts.
15 + 12 + 14 =41.
Answer is A.
Question: A salt manufacturing company produced a total of 3000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its ave66rage daily production for that year?
A.119
B.185
C.190
D.116
Answer: D.116
Explanation: Total production of salt by the company in that year = 3000 + 3100 + 3200 + .... + 4100 = 42600.
Average monthly production of salt for that year = 42600/365 â‰ˆ 116
ANSWER:D
Question: In an increasing sequence of 8 consecutive even integers, the sum of the first 4 integers is 248. What is the sum of all the integers in the sequence?
A.528
B.568
C.574
D.586
Answer: A.528
Explanation: let the first term of the sequence be x
since it is consecutive even integers the terms be we x, x+2,x+4...x+14 (up to 8 terms)
now,
sum of first 4 terms =248
or,
4x+12=248
x=236/4=59
Thus the answer can now be calculated by either summing up 59+61+63+... 8th term
or
s=n/2(2a+(n-1)d
=8/2(2*59+(7*2))
=4(118+14)=528
A
Question: Find the average of all the numbers between 11 and 36 which are divisible by 5
A.15
B.20
C.25
D.30
Answer: C.25
Explanation: Explanation:
Average = (15 + 20 + 25 + 30 + 35) / 5 = 125/5 = 25
ANSWER C
Question: If log10 2 = 0.3010, the value of log10 80 is:
A.1.5252
B.1.903
C.3.9252
D.3.903
Answer: B.1.903
Explanation: = log10 8 + log10 10
= log10 (23 ) + 1
= 3 log10 2 + 1
= (3 x 0.3010) + 1
= 1.9030.
ANSWER B
Question: In how many ways can 3 black and 5 white chess pieces be arranged in a row such that they occupy alternate places? Assume that the pieces are distinct.
A.720
B.30
C.120
D.15
Answer: A.720
Explanation: 3 black chess pieces can be arranged in 3! ways and 5 white pieces can be arranged in 5! ways.
W_W_W_W
Number of ways = 3!*5! = 6 * 120 = 720
Answer A
Question: A dishonest dealer professes to sell goods at the cost price but uses a false weight and gains 25%. Find his false weight age?
A.338
B.278
C.800
D.269
Answer: C.800
Explanation: 25 = E/(1000 - E) * 100
1000 - E = 4E
1000 = 5E => E = 200
1000 - 200 = 800
Answer: C
Question: Village X has a population of 68000, Which is decreasing at the rate of 1200 per year. Village Y has a population of 42000, which is increasing at the rate of 800 per year. In how many years will the population of the two villages be equal ?
A.7 years
B.6 years
C.9 years
D.13 years
Answer: D.13 years
Explanation: Let the population of village X and Y be equal after p years
Then, 68000-1200P=42000 + 800P
2000P=2600
P=13
so, their population will be equal after 13 years
ANSWER: D
Question: Dividing by 3⁄7 and then multiplying by 5⁄6 is the same as dividing by what number?
A.35⁄18
B.16⁄5
C.20⁄9
D.9⁄20
Answer: A.35⁄18
Explanation: say X/3/7*5/6 = x*7/3*5/6 = x*35/18
A
Question: A work which could be finished in 9 days was finished 3 days earlier after 10 more men joined. The number of men employed was?
A.18
B.20
C.22
D.24
Answer: B.20
Explanation: x ----- 9
(x + 10) --- 6
x * 9 = (x + 10)6
x = 20
ANSWER B
Question: If each side of a right triangle is increased by 10% and the base(b) is half of the height, find the percentage change in its area?
A.26%
B.21%
C.15%
D.18%
Answer: B.21%
Explanation: a =1/2 x b x h or 1/2 x 2a x a(for simplification)
New h = 220a / 100 = 22a / 10
New b =(110a x 100) ==11a/10
New area = 1/2 (22a x 11a) / (10 x 10) = (121a²/100)
increased area== (121a²/100) - a²
Increase %= [(21a²/100 ) x (1/a² ) x 100]% = 21%
answer :B
Question: A dog takes 5 leaps for every 6 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is :
A.1:6
B.5:6
C.6:1
D.5:1
Answer: D.5:1
Explanation: Explanation:
Dog : Hare = (5*3) leaps of hare : 6 leaps of hare = 15 : 3-->5:1
Answer: D
Question: Ram professes to sell his goods at the cost price but he made use of 750 grms instead of a kg, what is the gain percent?
A.11 1/7%
B.11 7/7%
C.11 1/9%
D.33.33%
Answer: D.33.33%
Explanation: 750 --- 250
100 --- ? => 33.33%
Answer:D
Question: John has on his shelf three books of poetry, four novels, and three reference works. Suppose from these ten books, we were to pick two books at random. What is the probability that we pick one novel and one reference work?
A.12/45
B.2/5
C.3/10
D.7/20
Answer: A.12/45
Explanation: When we are picking two books, one novel and one reference work, we could either pick a novel first and then a reference book or pick a reference book and then a novel. Therefore the answer is 4/10*3/9 + 3/10*4/9 = 12/45.
Answer: A
Question: In how many ways a committee,consisting of 5 men and 6 women can be formed from 8 men and 10 women?
A.266
B.5040
C.11760
D.86400
Answer: C.11760
Explanation: Solution
Required number of way = (8 C 5 × 10 C 6) = (8 C 3 × 10 C 4)
=( 8x7x6/3x2x1x 10x9x8x7/4x3x2x1) = 11760
Answer C
Question: In what ratio mental A at Rs.68 per kg be mixed with another metal at Rs.96 per kg so that cost of alloy (mixture) is Rs.78 per kg?
A.5:8
B.4:7
C.3:7
D.9:5
Answer: D.9:5
Explanation: (96-78)/(78-68)=18/10=9/5
ANSWER:D
Question: A pipe can fill a cistern in 20 minutes whereas the cistern when fill can be emptied by a leak in 45 minutes. When both pipes are opened, find when the cistern will be full?
A.17 minutes
B.87 minutes
C.36 minutes
D.27 minutes
Answer: C.36 minutes
Explanation: 1/20 - 1/45 = 1/36
36 minutes
Answer:C
Question: If NOIDA is written as STNIF, how MEERUT can be written in that code?
A.RJJWZY
B.RIJWZY
C.RJJWZX
D.RJJWZZ
Answer: A.RJJWZY
Explanation: N + 5 = S
O + 5 = T
I + 5 = N
D + 5 = F
SO,
M + 5 = R
E + 5 = J
E + 5 = J
R + 5 = W
U + 5 = Z
T + 5 = Y
RJJWZY ANSWER:A
Question: If a rectangle have length 16 cm and diagonal 20cm.calculate its area.
A.185
B.132
C.165
D.192
Answer: D.192
Explanation: breadth=√20^2-16^2=√144=12cm
Area=16*12=192 sq.cm
Answer D
Question: How many total numbers of seven-digit numbers can be formed having sum of whose digits is even is
A.9000000
B.4500000
C.8100000
D.4400000
Answer: B.4500000
Explanation: Suppose x1 x2 x3 x4 x5 x6 x7 represents a seven digit number. Then x1 takes the value 1, 2, 3, ....., 9 and x2, x3,....., x7 all take values 0, 1, 2, 3, ......, 9.
If we keep x1, x2, ......, x6 fixed, then the sum x1 + x2 + ......+ x6 is either even or odd. Since x7 takes 10 values 0, 1, 2, ....., 9, five of the numbers so formed will have sum of digits even and 5 have sum odd.
Hence the required number of numbers
= 9 . 10 . 10 . 10 . 10 . 10 . 5 = 4500000
Answer B
Question: Which fraction should be added to:
1/(2 Ã— 3) + 1/(3 Ã— 4) + 1/(4 Ã— 5) + ....... + 1/(29 Ã— 30)
so that the result is equal to 1?
A.4/15
B.7/15
C.8/15
D.11/30
Answer: C.8/15
Explanation: The given expression
= 1/(2 Ã— 3) + 1/(3 Ã— 4) + 1/(4 Ã— 5) + ...... + 1/(29 Ã— 30)
= (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + .......... + (1/29 - 1/30)
= 1/2 - 1/30 = 14/30
Thus, the fraction we should add = 1 - 14/30 = 16/30 = 8/15
The answer is C.
Question: There were two candidates in an election. Winner candidate received 62% of votes and won the election by 384 votes. Find the number of votes casted to the winning candidate?
A.288
B.744
C.992
D.298
Answer: C.992
Explanation: W = 62% L = 38%
62% - 38% = 24%
24% -------- 384
62% -------- ? => 992
Answer: C
Question: A man buys two articles for Rs.1980 each and he gains 10% on the first and loses 10% on the next. Find his total gain or loss percent?
A.9
B.8
C.7
D.6
Answer: A.9
Explanation: (30*30)/100 = 9%loss.Answer: A
Question: How many of the positive factors of 24 are not factors of 30
A.2
B.3
C.4
D.1
Answer: C.4
Explanation: factors of 24 - 1, 2, 3, 4, 6, 8, 12,24
factors of 30 -1, 2, 3, 5, 6, 10, 15 and 30.
Comparing both, we have four factors of 24 which are not factors of 30- 4,8,12,24
Answer(C)
Question: How many ways could three people sit at a table with five seats in which two of the five seats will remain empty?
A.8
B.12
C.60
D.118
Answer: C.60
Explanation: ways in which 3 seats out 5 can be selected = 5C3
ways in which 3 people can be arranged in 3 seats = 3!
Total ways of arrangement = 5C3*3!
=5*4/2*6
=10*6
=60
Ans = C
Question: Find the number of zeroes at the end of 50!
A.10
B.11
C.12
D.13
Answer: C.12
Explanation: calculate division by 5 and 25
50/5=10
50/25=2
total=12
ANSWER:C
Question: Which of the following integers is NOT a divisor of x if x = (21)(3^7) + (23)?
A.2
B.5
C.9
D.10
Answer: C.9
Explanation: (21)(3^7) is divisible by 3 but 23 is not divisible by 3.
Therefore (21)(3^7) + 23 is not divisible by 3 and thus not divisible by 9.
The answer is C.
Question: A starts business with Rs. 3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2:3. What is B's contribution in the capital
A.Rs 9000
B.Rs 7000
C.Rs 5000
D.Rs 4000
Answer: A.Rs 9000
Explanation: Explanation:
Let B contribution is x.
3500*12/7x =2/3
=>14x=126000=>x=Rs9000
Option A
Question: A Private Limited company have 20 staffs and they celebrated one festival. Director gives Rs.10000/- to his accountant and told him to 4500/- to each staff Rs. 2000/- each to cleaning staff and cooking staff and balance for you. Then how much amount accountant received?
A.10500
B.20000
C.4500
D.6500
Answer: A.10500
Explanation: Total amount paid for 20 Staffs : 4500 * 19= 85500/-
Paid to Cleaning & Cooking Staff : 2000/- * 2 = 4000/-
Total amount paid for both : 85500/- + 4000/- =89500/-
Balance with Accountant : 100000 - 89500 = 10500/-
Answer is (A)
Question: What is the sum of natural numbers between 50 and 100
A.4800
B.4860
C.3825
D.5500
Answer: C.3825
Explanation: a = first number
l = last number
Sn = n/2[a + l]
between 50 and 100 numbers = 51 => 100 - 50 = 50 + 1 = 51
Sn = 51/2 Ã— 150 = 51 Ã— 75 = 3825
Answer : C
Question: if log10 7 = a then log10 (1/70) equal to
A.-(1+a)
B.(1+a)
C.(1+2a)
D.(2+a)
Answer: A.-(1+a)
Explanation: log10(1/70) = log10 1 - log10 70
= - log10 (7*10)
= -(log10 7 + log10 10) = -(a+1)
ANSWER A
Question: A train travelled from station P to Q in 8 hours and came back from station Q to P is 6 hours. What would be the ratio of the speed of the train while traveling from station P to Q to that from station Q to P?
A.3 : 4
B.4 : 3
C.1 : 4
D.2 : 3
Answer: A.3 : 4
Explanation: Since S # 1/t
S1 : S2 = 1/t1 : 1/t2 = 1/8 : 1/6 = 3 : 4
Answer : A
Question: The three digits of a number add up to 20. The number is divisible by 5. The leftmost digit is double the middle digit. What is the product of the three digits?
A.175
B.250
C.78
D.225
Answer: B.250
Explanation: Say the three-digit number is abc.
The leftmost digit is double the middle digit --> a=2b;
The number is divisible by 5 --> c is either 0 or 5;
The three digits of a number add up to 20 --> a+b+c=20
So, either a+b+c=2b+b+0=20 or a+b+c=2b+b+5=20. The first equation does not give an integer value of b, so it's not the case. From the second we get that b=5 --> a=10 and c=5 --> a*b*c=250.
Answer: B.
Question: During a Pizza buffet where A eats more times 2.5 than B, and B eats 7 times less than C.find the least number of times all the three has to eat
A.50
B.60
C.70
D.80
Answer: C.70
Explanation: A eats more than B if B eats 1 times than the ratio of A and B is A:B is 2.5:1 or 5:2 and as B eat 7 times less the C the the ratio of B : C is 2:14 the the least number of times all three has eat is the LCM of A,B,C that is 70 ..
ANSWER:C
Question: A sum of Rs.5000 was divided into 30 persons such that each man gets Rs.200 and each woman gets Rs.150. Find the number of women.
A.20
B.15
C.18
D.24
Answer: A.20
Explanation: m+w=30,
200m+150w=5000
By solving we get men=10,women=20
ANSWER:A
Question: What least number must be added to 3000 to obtain a number exactly divisible by 19 ?
A.2
B.1
C.4
D.18
Answer: A.2
Explanation: On dividing 3000 by 19, we get 17 as remainder.
Number to be added = (19 - 17) = 2.
ANSWER A 2
Question: A vessel has 300 ml of pure milk. 30 ml of milk is removed and 30 ml of water is added into the vessel. If this operation is repeated another 2 times, what is the % of milk in the vessel at the end?.
A.50
B.60
C.70
D.80
Answer: C.70
Explanation: Total MIlk Removed= 30+30+30=90 ml
Remaining Milk= 300-90 = 210 ml
% of Milk = 210/300=7/10=70%
ANSWER:C