RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: There are 13 hearts in a full deck of 52 cards. In a certain game, you pick a card from a standard deck of 52 cards. If the card is a heart, you win. If the card is not a heart, the person replaces the card to the deck, reshuffles, and draws again. The person keeps repeating that process until he picks a heart, and the point is to measure how many draws it took before the person picked a heart and, thereby, won. What is the probability that one will pick the first heart on the third draw or later?
A.1/2
B.9/16
C.11/16
D.13/16
Answer: B.9/16
Explanation: Here, we're told that 13 of the 52 cards are "hearts" - this is 1/4 of the deck. We're also told that after drawing a card, the card is PUT BACK in to the deck (so there will always be 52 cards to draw from).
To draw a heart for the first time on the 3rd draw (or later), the FIRST TWO draws MUST NOT be hearts....
Probability of NOT drawing a heart on the first draw = 3/4
Probability of NOT drawing a heart on the second draw = 3/4
(3/4)(3/4) = 9/16
From this point, you will eventually draw a heart (which is what the question is asking for), so the probability is 9/16.
ANSWER:B
Question: The value of {(.87)3 + (.13)3 + .87 × .39}0.5 is:
A.0.6
B.1
C.0
D.3
Answer: B.1
Explanation: (a^3 + b^3)=(a+b)(a^2-ab+b^2)
so, (a^2-ab+3ab+b^2) ^0.5 , here a+b=1
(0.87+0.13)^2*0.5
=1
ANSWER:B
Question: The difference between simple and compound interests on a certain sum for 2 years at 4% per annum is Rs.50. The sum is
A.Rs.20,400
B.Rs.25,000
C.Rs.31,250
D.Rs.38,000
Answer: C.Rs.31,250
Explanation: difference between 2yr CI and SI is given by PR^2 ..
PR^2= 50
P*R/100*R/100=50
P*4/100*4/100 =50
P=(50*100*100)/4*4
P= 31,250
ANSWER:C
Question: The sum of two consecutive even integers is 26. What are the two numbers?
A.14
B.15
C.16
D.17
Answer: A.14
Explanation: Solution
Let 2n be the first even integer and let 2n + 2 be the second integer
2n + 2n + 2 = 26
4n + 2 = 26
4n + 2 - 2 = 26 - 2
4n = 24
n = 6
So the first even integer is 2n = 2 × 6 = 12 and the second is 12 + 2 = 14
Answer A
Question: How many batteries will remain unboxed if in a factory that manufactures batteries 2 types of boxes are used to store batteries. the bigger box can store 25 batteries while the smaller box can store 18 batteries. The total number of batteries to be stored is 217.
A.0
B.1
C.2
D.7
Answer: A.0
Explanation: Total batteries to be stored 218
The big box can store 25
small box can store 18
storing 217 batteries in big box 218/25 =8 r 18
store remainder in small box 18/18=1 r 0
least number of batteries that will be left unboxed=0
Answer: A
Question: A packet of 10 electronic components is known to include 3 defectives. If 4 components are randomly chosen and tested, what is the probability of finding among them not more than one defective component.
A.0.6517
B.0.868
C.0.4483
D.None of these
Answer: A.0.6517
Explanation: Explanation :
Here, the trials are independent , since the probability of defective component in any trial is not affected by the occurrence or non-occurrence of a defective component in any other trial. So, it is a case of binomial distribution.
No. of trials = n = 4.
Occurrence of a defective component is a success.
Then, the probability of success = p = 3/10.
the probability of failure = 1- p = 7/10.
Components not more than one defective one means x ≤ 1 i.e x = 0.
Using the formula,
P(x) = ncxPx(1-P)n-x.
Since,
=> P(x ≤ 1) = P(x = 0) or P(x = 1)
= P(0) + P(1) .
= 4c0(3/10)0 x (7/10)4 + 4c1(3/10)1x (7/10)3 .
= (7/10)4 + 4 x (3/10) x (7/10)3.
= 0.6517
Hence, the required probability is 0.6517.
Answer : A
Question: The average age of a husband and a wife is 23 years when they were married five years ago but now the average age of the husband, wife and child is 22 years(the child was born during the interval). What is the present age of the child?
A.6
B.5
C.10
D.4
Answer: C.10
Explanation: 28 * 2 = 56
22 * 3 = 66
-----------
10 years.Answer: C
Question: The area of a parallelogram is 200sq m and its altitude is twice the corresponding base. Then the length of the base is?
A.8
B.9
C.7
D.10
Answer: D.10
Explanation: 2x * x = 200 => x= 10
Answer: D
Question: The sum of three integers is 19. The largest integer is 3 times the middle integer, and the smallest integer is 9 less than the largest integer. What is the product of the three integers?
A.132
B.144
C.156
D.168
Answer: B.144
Explanation: Let x be the middle integer. Then the largest is 3x and the smallest is 3x - 9.
3x - 9 + x + 3x = 19
x = 4
The three integers are 3, 4, and 12.
The product is 3*4*12 = 144
The answer is B.
Question: Which is the smallest fraction:
A.11/13
B.9/11
C.5/4
D.5/7
Answer: D.5/7
Explanation: 11/13=.846
9/11=.818
5/4=1.25
5/7=.714
So smallest is 5/7
ANSWER:D
Question: What is the length of the diagonal of a square whose area is 4 times of another square with diagonal as 5v2 cm?
A.20v2
B.10
C.10v2
D.20
Answer: C.10v2
Explanation: SOLUTION : 10v2
Area of square = 1/2 * (length of diagonal)2
Area of square 1 = * (5v2)2 = 25
Area of square 2 = 4*25 = 100
Length of diagonal of square 2 = v2 * area = v2 * 100 = v200 = 10v2 cm
ANSWER IS C
Question: The largest four digit number which is a perfect cube, is:
A.7000
B.8000
C.9261
D.9999
Answer: C.9261
Explanation: Explanation:
21*21*21 = 9261
Option C
Question: A large box contains 15 small boxes and each small box contains 25 chocolate bars. How many chocolate bars are in the large box?
A.A)220
B.B)490
C.C)375
D.D)450
Answer: C.C)375
Explanation: the only thing you have to do is a simple multiply
we have:
15*25
=375
correct answer is:
C) 375
Question: A person distributed 15% of his income to his 3 children each. He deposited 30% of his income to his wife's account. He donated 10% of remaining amount to an orphan house.Finally he has $40000. Find his total income?
A.A)266666.7
B.B)562000
C.C)800000
D.D)500000
Answer: A.A)266666.7
Explanation: 3 children got = 3*15% = 45%
wife got = 30%
orphan house = 10%
total = 45+30+10 = 85%
remaining = 100-85 = 15%
15% = 40000
100% = 40000*100/15 = $266666.7
Answer is A
Question: In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 100 more than the correct answer. Find the number.
A.192
B.280
C.384
D.400
Answer: A.192
Explanation: Explanation:
Let the number be x.
5*x/6 = 5*x/16 + 100
25*x/48 = 100
x = 192
ANSWER A
Question: One day Eesha started 30 min late from home and reached her office 50 min late while driving 25% slower than her usual speed. How much time in min does eesha usually take to reach her office from home?
A.22
B.60
C.99
D.17
Answer: B.60
Explanation: We know that Speed is inversely proportional to time
While she drives 25% slower means she drove at 3434(S)
We know that D = S x T
When speed became 3434(S) then Time taken should be 4343(T)
i.e, She has taken 4343(T) - T extra to cover the distance.
Extra Time = T3T3 = 20 min (as 20 min late due to slow driving)
Actual time T = 60 Minutes
Answer:B
Question: A dealer originally bought 70 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?
A.3q/140
B.3q/2
C.105q
D.q/70
Answer: A.3q/140
Explanation: The cost of each battery was q/70.
Each battery was sold for 1.5q/70 = 3q/140.
The answer is A.
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?
A.30/18
B.30/29
C.30/12
D.30/13
Answer: D.30/13
Explanation: Speed downstream = 20 + 6 = 26 kmph.
Time required to cover 60 km downstream = d/s = 60/26
= 30/13 hours.
Answer:D
Question: X can finish a work in 18 days. Y can finish the same work in 15 days. Yworked for 5 days and left the job. how many days does X alone need to finish the remaining work?
A.12
B.5
C.6
D.8
Answer: A.12
Explanation: Work done by X in 1 day = 1/18
Work done by Y in 1 day = 1/15
Work done by Y in 5 days = 5/15 = 1/3
Remaining work = 1 – 1/3 = 2/3
Number of days in which X can finish the remaining work = (2/3) / (1/18) = 12
A
Question: If the least common addition of two prime numbers x and y is 10, where x > y, then the value of 2x + y is
A.7
B.9
C.14
D.17
Answer: D.17
Explanation: (x+y) = 10 and both x an y are prime.
The only values of x and y can be 7 and 3 (x = 7 and y = 3)
2x + y = 2*7 + 3 = 17
Correct Option: D
Question: The area of the floor of a class room is 10 m2 that of a longer wall 15 m2 and of the shorter wall 6 m2, find the edge of the new cube?
A.50 m3
B.30 m2
C.60 m3
D.40 m3
Answer: B.30 m2
Explanation: lb = 10 ; lh = 15 ; fh = 6
(lbh)2 = 10 * 15 * 6 => lbh = 30 m3
ANSWER:B
Question: If x is an integer and 1 ≤ x ≤ 100, what is the probability that x(x + 1) is a multiple of 12 and 9?
A.1/25
B.1/20
C.2/25
D.11/100
Answer: A.1/25
Explanation: x(x+1) is a number that is divisible by both 12 and 9
for x = 27, 71,72, 80 we get number ie divisible by both 12 and 9
so probability would be 4/100 = 1/25
ANSWER:A
Question: 100 identical coins each with probability 'pp' showingup heads & tossed. If 0
A.21/311
B.23/321
C.51/101
D.55/413
Answer: C.51/101
Explanation: Let aa be the number of coins showing heads
Then, P(A=50)=P(A=51)P(A=50)=P(A=51)
⇒100C50×P50×(1−P)50⇒100C51×P51×(1−P)49⇒100C50×P51×(1−P)50=100C51×P⇒51(1âˆ′P)=50P⇒P=51/101
C
Question: Cricket match is conducted in US. The run rate of a cricket game was only 3.2 in first 10 over. What should be the run rate in the remaining 40 overs to reach the target of 272 runs?
A.6
B.6.25
C.7.25
D.7.5
Answer: A.6
Explanation: Required run rate = 272 - (3.2 x 10) =	240 = 6
40	40
A
Question: When 15 is subtracted from a number, it reduces to seven-twelve of the number. What is the sum of the digit of the number
A.20
B.24
C.36
D.48
Answer: C.36
Explanation: Explanation:
Let the number be x. Then,
x - 15 = 7x/12 => x - 7x/12 = 15
5x/12 = 15 => x = 36
Answer: Option C
Question: From the integer n, if n*n*n is odd, then what is true from below options?
A.n is odd and n*n is even
B.n*n is even
C.n is odd
D.n is even
Answer: A.n is odd and n*n is even
Explanation: n is odd and n*n is even
Option A
Question: 860% of 50 + 50% of 860 =?
A.430
B.516
C.660
D.860
Answer: D.860
Explanation: Solution
Given expression
= [860 / 100 x 50 + 50 / 100 x 860]
= 430 + 430
= 860.
Answer D
Question: The sum of first 45 natural numbers is:
A.1035
B.1038
C.1040
D.1045
Answer: A.1035
Explanation: Let Sn =(1 + 2 + 3 + ... + 45). This is an A.P. in which a =1, d =1, n = 45.
Sn = n [2a + (n - 1)d] = 45 x [2 x 1 + (45 - 1) x 1] = 45 x 46 = (45 x 23)
2 2 2
= 45 x (20 + 3)
= 45 x 20 + 45 x 3
= 900 + 135
= 1035.
Shorcut Method:
Sn = n(n + 1) = 45(45 + 1) = 1035.
2 2
A
Question: Mira is making telescopes, each consisting of 2 lenses, 1 tube, and 1 eyepiece. Lenses can be purchased only in packs of 50, tubes only in packs of 10, and eyepieces only in packs of 30. However, half of the lenses in each pack are not usable for telescopes. If all parts are used only for the telescopes, what is the minimum number of lenses Mira must purchase to make a set of telescopes with no leftover components other than the unusable lenses?
A.60
B.150
C.1800
D.700
Answer: C.1800
Explanation: I'd use backsolving for this question.
Check C:
1800 lenses = 900 usable lenses = 450 tubes = 450 eyepieces. We CAN buy 450 tubes and 450 eyepieces, so that not to have leftovers.
Answer: C.
Question: The difference between the simple interest received from two different sources on Rs. 1500 for 3 years is Rs. 13.50. The difference between their rates of interest is
A.A)2.4%
B.B)2.6%
C.C)2.0%
D.D)0.3%
Answer: D.D)0.3%
Explanation: (1500 * R1 * 3)/100 - (1500 * R2 * 3)/100 = 13.50 4500(R1 - R2) = 1350
R1 - R2 = 0.3%
Answer:D
Question: A restaurant meal cost $40 and there was no tax. If the tip was more than 12 percent but less than 13 percent of the cost of the meal, then the total amount paid must have been between
A.$40 and $42
B.$39 and $41
C.$38 and $40
D.$44 and $45
Answer: D.$44 and $45
Explanation: The total amount for the meal was between 40*1.12=44.8 and 40*1.13=~45.2. Only option which covers all possible values of the meal is D.
Answer: D.
Question: A meal cost $ 35.50 adn there was no tax. If the tip was more than 15 pc but less than 25pc of the price, then the total amount paid should be:
A.41-44
B.39-41
C.38-40
D.37-39
Answer: A.41-44
Explanation: 15%(35.5) = 5.325
25%(35.5) = 8.875
total amount could have been 35.5+5.325 and 35.5+8.875
=> could have been between 40.825 and 44.375
=> approximately between 41 and 44
Answer is A.
Question: One half of a two digit number exceeds its one third by 4. What is the sum of the digits of the number?
A.6
B.9
C.11
D.12
Answer: A.6
Explanation: Explanation:
x/2 – x/3 = 4 => x =24
2 + 4 =6
A
Question: It takes 6 beavers 10 hours to build a certain dam, working at a uniform rate. If seven beavers start to build the same dam at noon, and one beaver per hour is added beginning at 6:00 PM, at what time will the dam be complete?
A.7:24 PM
B.7:48 PM
C.8:06 PM
D.8:32 PM
Answer: C.8:06 PM
Explanation: The rate of 1 beaver is 1/60.
The amount of work done by 7 beavers in 6 hours is 7/60 *6 = 42/60
In the next hour, 8 beavers do 8/60 for a total of 50/60.
In the next hour, 9 beavers do 9/60 for a total of 59/60.
In the next 6 minutes, 10 beavers do 10/60 * 6/60 = 1/60 for a total of 60/60.
The dam will be completed at 8:06 pm.
The answer is C.
Question: A train crosses a platform of 160 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
A.110
B.887
C.167
D.197
Answer: A.110
Explanation: Length of the train be ‘X’
X + 160/15 = X + 250/20
20X + 3200 = 15X + 3750
5x=550
X = 110m
Answer: A
Question: Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 496.80?
A.22
B.88
C.20
D.88
Answer: C.20
Explanation: CP = Rs. 540, MP = 540 + 15% of 540 = Rs. 621
SP = Rs. 496.80, Discount = 621 - 496.80 = 124.20
Discount % = 124.2/621 * 100 = 20%
Answer:C
Question: A man can swim in still water at 15 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
A.3.9
B.5
C.5.3
D.1.5
Answer: B.5
Explanation: M = 15
S = x
DS = 15 + x
US = 15 - x
15 + x = (15 - x)2
15 + x = 30 -2x
3x = 15
x = 5
Answer:B
Question: The total of company C's assets in 1994 was 200% greater than the total in 1993, which in turn was 400% greater than the total in 1992. If the total of company C's assets in in 1992 was N dollars, which one of the following represents company C's assets in 1994:
A.7N
B.8N
C.9N
D.15
Answer: D.15
Explanation: Let's use actual numbers. Starting in 1992, let's say company C had $100 in assets.
In 1993, the total assets were 400% GREATER, which means 1992 PLUS 400% of 1992:
$100 + 4x$100 = $100 + $400 =$500
In 1994, the total assets were 200% GREATER than they were in 1993, which means 1993 PLUS 200% of 1993:
$500 + 2x$500 = $500 + $1000 =$1500
This is 15 times the 1992 number, so the correct answer is 15N.
D
Question: Four car rental agencies A, B, C and D rented a plot for parking their cars during the night. A parked 15 cars for 12 days, B parked 12 cars for 20 days, C parked 18 cars for 18 days and D parked 16 cars for 15 days. If A paid Rs. 1215 as rent for parking his cars, what is the total rent paid by all the four agencies?
A.Rs. 4500
B.Rs. 4800
C.Rs. 5250
D.Rs. 6642
Answer: D.Rs. 6642
Explanation: The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15
= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60
Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.
The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k
It is given that A paid Rs. 1215
45k = 1215 => k = 27
246k = 246(27) = Rs. 6642
Thus the total rent paid by all the four agencies is Rs. 6642.
ANSWER:D
Question: How many 5 digit nos are there if the 2 leftmost digits are odd and the digit 4 can't appear more than once in the number ?
Could someone please provide a solution using a approach other than ( 1-x(none)) approach?
A.24300
B.25700
C.26500
D.24400
Answer: A.24300
Explanation: A. 4 is used once: OO**4 --> (5*5*9*9)*3: 5 choices for the first digit as there are 5 odd numbers, 5 choices for the second digit for the same reason, 9 choices for one of the two * (not-4 digit), 9 choices for another * (not-4 digit), multiplied by 3 as 4 can take the place of any of the three last digits (OO**4, OO*4*, OO4**);
B. 4 is not used: OO*** --> 5*5*9*9*9: the same logic as above.
5*5*9*9*3+5*5*9*9*9=24,300.
ANSWER:A
Question: A baseball team won 35 percent of the first 80 games it played. How many of the remaining 82 games will the team have to win in order to have won exactly 50 percent of all the games it played?
A.36
B.45
C.53
D.55
Answer: C.53
Explanation: Games won out of first 80 questions = (35/100)*80 = 28
Total Games = 80+82 = 162
Games to be won = (50/100)*162 = 81
Remaining games to be won = 81-28 = 53
Answer: Option C
Question: What is the probability that a 4 person committee chosen at random from a group consisting of 6 men, 7 women, and 2 children contains exactly 1 woman?
A.77/204
B.56/195
C.11/77
D.308/1411
Answer: B.56/195
Explanation: Total possible selections = 4 out of 15 group members = 15C4
Favorable selections = 1 out of 7 women and 3 out of 8 (= 6 men + 2 children) = 7C1 * 8C3
Thus the required probability = 7C1*8C3 / 15C4 = 56/195. Thus B is the correct answer.
Question: A wooden cube whose edge length is 9 inches is composed of smaller cubes with edge lengths of one inch. The outside surface of the large cube is painted red and then it is split up into its smaller cubes. If one cube is randomly selected from the small cubes, what is the probability that the cube will have at least one red face?
A.52.9%
B.55.4%
C.58.3%
D.61.7%
Answer: A.52.9%
Explanation: There are a total of 9*9*9 = 729 cubes.
All the exterior cubes will have at least one face painted red.
The interior is formed by 7*7*7 = 343 cubes.
The number of cubes with at least one side painted red is 729 - 343 = 386 cubes
The probability that a cube has at least one side painted red is 386/729 which is about 52.9%
The answer is A.
Question: If two of the four expressions a+b, 3a+b, a-b, and a-3b are chosen at random, what is the probability that their product will be of the form of a^2 + kb^2, where k is a positive integer?
A.1/2
B.1/6
C.1/4
D.1/3
Answer: B.1/6
Explanation: *3=12 --> total number of outcomes
but only two of the expressions will result in desired form -->so the probability of choosing the right pair is 2/12=1/6
ANS:B
Question: The perimeter of a triangle is 44 cm and the in radius of the triangle is 2.5 cm. What is the area of the triangle?
A.76
B.88
C.66
D.55
Answer: D.55
Explanation: Area of a triangle = r * s
Where r is the in radius and s is the semi perimeter of the triangle.
Area of triangle = 2.5 * 44/2 = 55 cm2
Answer:D
Question: If a and b are Positive Integers and a<b, b is not equal to zero, which of the following can give NEGATIVE answer?
A.a+b
B.ab
C.a/2+b/2
D.a-b
Answer: D.a-b
Explanation: (A)a+b
This cannot be answer. Because a and b are positive integers
All the following options (Except D) should not be an answer.
(D) a-b
If a>0,a-b gives a negative answer.
So the option D is answer
Question: John was thrice as old as Tom 6 yrs back. He will be 5/3 times as old as Tom 6 years hence. How old is Tom today?
A.10
B.11
C.12
D.15
Answer: C.12
Explanation: Sol. RMBflSk -6 = 3 (Ravi - 6) ...(j)
and Rupesh + 6 = | (Ravi + 6) ...(ii)
Solving both the equations we get,
Ravi = 12 years.
C
Question: A single discount equivalent to the discount series of 20%, 12% and 5% is?
A.31.6
B.31.0
C.31.6
D.33.12
Answer: D.33.12
Explanation: 100*(80/100)*(88/100)*(95/100)
= 68.4
100 - 66.88 = 33.12
Answer: D
Question: Calculate how long it will take a swimmer to swim a distance of 3km against the current of a river which flows at 1.7km/hr, given that he can swim in still water at 3km/h
A.2.31
B.9.31
C.1.31
D.4.31
Answer: A.2.31
Explanation: swim in still water at = 3
speed of river= 1.7
US = 3 - 1.7= 1.3
Distance = 3
T = 3/1.3 = 2.31
Answer: A
Question: Find the odd man out. 3, 5, 15, 75, 1120, 84375
A.84375
B.1120
C.15
D.3
Answer: B.1120
Explanation: Explanation :
Pattern : 1st * 2nd = 3rd, 2nd * 3rd = 4th, etc.
3
5
3 × 5 = 15
5 × 15 = 75
15 × 75 = 1125
75 × 1125 = 84375
Hence, 1120 is wrong. 1125 should have come in place of 1120
Answer : Option B
Question: A company, Chauncy Co., has an annual travel budget of $53,000. The accounting department estimates that transportation expenses will increase 5 percent in the coming year, and nontransportation travel expenses will increase by 15 percent in the coming year. Last year, Chauncy Co. spent $19,500 on transportation-related expenses, and $35,000 on nontransportation travel expenses. If the annual travel budget does not increase this year, and if the accounting department’s estimates are correct, how far over the annual travel budget will expenses be this year?
A.Expenses will not go over the budget.
B.$500
C.$4,225
D.$7,725
Answer: D.$7,725
Explanation: annual travel budget of $53,000
Let, Transportation expenses = T = 19500
and Non-Transportation expenses = N=35000
i.e. Increased Transportation expenses = 1.05T = 20475
and Increased Non-Transportation expenses = 1.15N = 40250
Total Expense = 20475+40250 = 60725
Expense over Budget = Budget - expense = 53000-60725 = 7725
Answer: Option D
Question: The forth proportional to 10,20,30 is?
A.20
B.60
C.45
D.75
Answer: B.60
Explanation: Let the fourth proportional to 10,20,30 be x
then 10:20::30:x
10x = 20*30
x = 60
Answer is B
Question: If â€œ*â€ is called â€œ+â€, â€œ/â€ is called â€œ*â€, â€œ-â€ is called â€œ/â€, â€œ+â€ is called â€œ-â€. 120/40 â€“ 30 * 20 - 5 = ?
A.178.5
B.156.6
C.160.4
D.163.6
Answer: D.163.6
Explanation: Explanation:
Given : 120/40 â€“ 30 * 20 - 5 = ?
Substituting the coded symbols for mathematical operations, we get,
120 * 40/30 +20 / 5 = ?
120 * 1.33 + 4 = ?
159.6 + 4 = 163.6
ANSWER : D
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 120 m and they cross each other in 12 sec, then the speed of each train is?
A.10
B.18
C.36
D.72
Answer: C.36
Explanation: Explanation:
Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/12 => x = 10
Speed of each train = 10 m/sec.
= 10 * 18/5 =- 36 km/hr.
ANSWER IS C
Question: .003/?= .01
A..3
B..09
C..009
D..0009
Answer: A..3
Explanation: Let .003/x = .01;
Then x = .003/.01
= .3/1
= .3
Answer is A
Question: Find the fourth proportion to 2,4,6
A.18
B.12
C.9
D.6
Answer: B.12
Explanation: Explanation:
2:4 :: 6:x
=> 2/4= 6/x
=> x = 24/2
=> x = 12
Answer:B
Question: A man takes 6 hours 15 minutes in walking a distance and riding back to the starting place. He could walk both ways in 7 hours 45 minutes. The time taken by him to ride both ways, is
A.4 hours
B.4 hours 30 minutes
C.4 hours 45 minutes
D.5 hours
Answer: C.4 hours 45 minutes
Explanation: Explanation:
Time taken in walking both ways = 7 hours 45 minutes --------(i)
Time taken in walking one way and riding back= 6 hours 15 minutes-------(ii)
By equation (ii)*2 -(i), we have
Time taken to man ride both ways, = 12 hours 30 minutes - 7 hours 45 minutes
= 4 hours 45 minutes
ANSWER IS C
Question: In a psychology school the grade of the students is determined by the following method: At the end of the first year the grade equals to twice the age of the student. From then on, the grade is determined by twice the age of the student plus half of his grade from the previous year. If Joey's grade at the end of the first year is 40, what will be his grade at the end of the third year?
A.74
B.75
C.76
D.77
Answer: B.75
Explanation: let the age is 'x' so after 1st yr 2x=40 and x=20
after 2nd year (now age become 21)
2*21+ 20=62 grades
after 3rd year(now age becomes 22)
2*22+31=75
ANSWER:B
Question: Find smallest prime number is:
A.13
B.21
C.14
D.18
Answer: A.13
Explanation: A
13
Question: The radius of a cylindrical vessel is 7cm and height is 2cm. Find the whole surface of the cylinder?
A.281
B.396
C.440
D.767
Answer: B.396
Explanation: r = 7 h = 2
2πr(h + r) = 2 * 22/7 * 7(9) = 396
Answer:B