RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold 9 times as many paperback copies as hardback copies were sold. If a total of 439,000 copies of the novel were sold in all, how many paperback copies were sold?
A.45,000
B.360,000
C.362,700
D.392,000
Answer: C.362,700
Explanation: Say x was the # of hardback copies sold from the time the first paperback copy was sold.
Then the total # of paperback copies sold was 9x;
Hence the total # of copies sold was (hardback)+(paperback)=(36+x)+(9x)=439 --> x=40.3.
So, the total # of paperback copies sold was 9x=9*40.3=362.7 or 362,700.
Answer: C.
Question: To furnish a room in a model home an interior decorator is to select 2 chairs and 2 tables from the collection of chairs and tables in a warehouse that are all different from each other. If there are 5 chairs in the warehouse and if 150 different combinations are possible, how many tables y are there in the warehouse?
A.6
B.8
C.10
D.15
Answer: A.6
Explanation: Total number of ways to choose 2 chairs from 5 y= 5C2=10
Total number of combination=150
That means we need get 15 combinations from the selection of tables....
Screening through the answers.... 6C2=15..... 15*10=150
Answer is 6... A
Question: A is a working partner and B is a sleeping partner in the business. A puts in Rs.2000 and B Rs.3000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?
A.1978
B.2707
C.7728
D.4416
Answer: D.4416
Explanation: 2:3 => 2:3
9600*10/100 = 960
9600 - 960 = 8640
8640*2/5 = 3456 + 960
= 4416
Answer: D
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 3000 resolutions?
A.2187 m
B.3704 m
C.4179 m
D.4224 m
Answer: D.4224 m
Explanation: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 3000 resolutions.
= 3000 * 2 * 22/7 * 22.4
= 422400 cm
= 4224 m
Answer:D
Question: In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 200 more than the correct answer. Find the number.
A.384
B.76
C.26
D.28
Answer: A.384
Explanation: Explanation:
Let the number be x.
5*x/6 = 5*x/16 + 200
25*x/48 = 200
x = 384
ANSWER: A
Question: Two men, 3 women working full time and 3 part times can complete a job in 20 days. Four men and 9 women working full time can complete the same job in 10 days. Find the ratio of the times taken by a woman (full-timer) and a part timer to complete the job.
A.1:2
B.2:1
C.1:3
D.3:1
Answer: B.2:1
Explanation: let X=single man one day work
y=single woman one day work
so single woman's part tym work will be y/2
so 1st equation is,
2x+3y+3(y/2)=1/20 (as they are completing in 20 days)
2nd equation wil be,
4x+9y=1/10 (as they are completing in 10 days)
solving both equations we will get,
y=1/90 (this is the single woman's full timer 1 day work)
so now taking the ratio of full-timer and a part timer we will get
90:45=2:1
ANSWER:B
Question: Griffin has a bag of marbles that contains 7 black marbles and 4 red marbles. If he removes 3 marbles at random without replacing any of the marbles, what is the probability that all 3 marbles selected will be black?
A.4/11
B.5/22
C.7/33
D.8/55
Answer: C.7/33
Explanation: P(3 black marbles) = 7/11*6/10*5/9 = 7/33
The answer is C.
Question: How many two-digit numbers are there whose remainder when divided by 12 is 1, and whose remainder when divided by 6 is 5?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: 2 digit numbers whose remainder when divided by 10 is 1 are
11 , 21 , 31 , 41 , 51 , 61 , 71 , 81 , 91
Out of above , numbers whose remainder when divided by 6 is 5 are
11 , 41 and 71
Answer C
Question: A and B invest money in the ratio 5:4 and they has loss of Rs.7200 at the end of year. what is the share of loss of B?
A.Rs.3200
B.Rs.3100
C.Rs.3000
D.Rs.2900
Answer: A.Rs.3200
Explanation: et ratio of A and B be 5x & 4x
so net loss = 5x+4x= 7200
x=800
A=5x=5(800)=4000
B= 4x=4(800)=3200
so, B= 3200
ANSWER:A
Question: If 3d + 1 < 2d < 9 - d, which of the following must be true?
I. -1 < d < 3
II. d < -1
III. d < 3
A. II only
B. III only
C. I and II only
D. II and III only
Answer: A. II only
Explanation: Just try plugging d in a number like 0 or 1, and you'll quickly find that the inequality doesn't hold.
So you can immediately cross out any answers with I or III, leaving just (A) II only.
Question: The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 6500, brokerage being 1/4%, is:
A.90.03
B.114
C.114.75
D.124
Answer: A.90.03
Explanation: Face Value = Rs. 6500.
Dividend = 10.5%.
Annual Income = Rs. 756.
Brokerage per Rs. 100 = Rs. 0.25.
Dividend is always paid on the face value of a share.
Face Value * Dividend / (Market Value + Brokerage per Rs. 100) = Annual income.
= 6500 * 10.5 / 756 = Market Value of Rs. 100 stock + Brokerage per Rs. 100.
= Market Value of Rs. 100 stock + Brokerage per Rs. 100 = Rs. 90.27.
= Market Value of Rs. 100 stock = Rs. 90.27 - Re. 0.25.
= Market Value of Rs. 100 stock = Rs. 90.03.
answer : A
Question: In how many different ways can the letters of the word "CLAIM" be rearrangement?
A.120
B.130
C.140
D.145
Answer: A.120
Explanation: Option 'A'
The total number of arrangements is
5P5 = 5! = 120
Question: In one day, Juan sends Keith three times as many messages as he sends Laurence, and Laurence sends Missy 2 times as many messages as he receives from Juan. If Missy received 18 messages from Laurence, how many messages does Keith receive from Juan?
A.3
B.12
C.16
D.27
Answer: D.27
Explanation: Juan --> Laurence = x messages;
Juan --> Keith = 3x messages (Juan sends Keith three times as many messages as he sends Laurence);
Laurence --> Missy = 2x =18 (Laurence sends Missy 2 times as many messages as he receives from Juan).
2x =18 --> x = 9 --> 3x = 27.
Answer: D.
Question: A metallic sphere of radius 12 cm is melted and drawn into a wire, whose radius of cross section is 12 cm. What is the length of the wire?
A.6 cm
B.14 cm
C.16 cm
D.23 cm
Answer: C.16 cm
Explanation: Volume of the wire (in Cylindrical shape) is equal to the volume of the sphere.
π(12)^2 * h = (4/3)π (12)^3 => h
= 16 cm
Answer:C
Question: In a six-sided polygon ZQRSTV ∠Z measures 48° less than the average (arithmetic mean) of the remaining five angles. What does ∠Z equal to, in degrees?
A. 72
B. 80
C. 88
D. 96
Answer: B. 80
Explanation: The sum of interior angle in a polygon is (n-2)*180
so for a six sided figure, (6-2)*180 = 720
let the A.M of the other 5 angles be 'm'
--> m*5 + ∠Z = 720, we know ∠Z=m-48
--> m*5 + m - 48 = 720, solving we get m=128
hence ∠Z= 128-48 = 80
Ans B.
Question: 45 girls and 60 boys are present at a party. There are 17 girl-boy are in relationship among them. If a girl and a boy is selected at random, what is the probability that they will be a couple?
A.1/200
B.1/100
C.90/2900
D.17/2700
Answer: D.17/2700
Explanation: In how many ways we can select a girl and a boy from 45 lady and 60 gentlemen? In 45*60 = 2,700 ways.
We have a total of 17 couples so, the probability of selecting a couple is 17/2,700 = 17/2700.
Ans- D
Question: In the equation 2x â€“ cy = 18, c is a constant. If the value of y is 2 when x is 6, what is the value of x when y is 7 ?
A.âˆ’9/2
B.-4
C.-3/2
D.4
Answer: C.-3/2
Explanation: 2x - cy = 18
x=6, y=2;
12-2c=18
c=-3
2x-cy=18
when y=7, c=-3, x=
x=-3/2
ANSWER:C
Question: Janice has divided her department of 12 employees into 4 teams of 3 employees each to work on a new project. Four new employees are to be added to Janice’s department, but the number of teams is to remain the same. If every employee must be on exactly 1 team, then the total number of different teams into which Janice can divide the enlarged department is approximately how many times the number of different teams into which Janice could have divided the original department?
A.16
B.170
C.340
D.1820
Answer: B.170
Explanation: we assume the four teams must always be of equal size, then when we pick the four teams in the 12-person department, we can pick the first team in 12C3 ways, the second in 9C3 ways, the third in 6C3 ways, and the fourth in 3C3 ways. So if we assume we're picking teams in order, we can pick them in:
12C3 * 9C3 * 6C3 * 3C3 = 12! / (3!)^4
ways. The order of the 4 teams presumably doesn't matter, so we'd divide this by 4! if this were a counting problem, but we'll also divide by 4! when we count how many teams we can make in the larger department, and those two 4!'s will cancel in the end anyway, so I'll just omit that term.
When we have 16 employees, and divide them into four teams of four, we can similarly do that in
16C4 * 12C4 * 8C4 * 4C4 = 16! / (4!)^4
ways if the order of the teams matters. We need to divide this by the result above, so we get:
16!(4!)4/12!(3!)^4=(16!)(3!)4/(12!)(4!)^4=(16)(15)(14)(13)/4^4=(15)(14)(13)/4^2
which is roughly equal to 170.
ANS:B
Question: In how many different number of ways a Committee of 4person of can be selected from 4boys and 4girls such that at least 1 girl is included in the committe
A.70
B.69
C.67
D.68
Answer: B.69
Explanation: 1G 3B 2G 2B 3G 1B 4G
=(4C1*4C3)+(4C2*4C2)+(4C3*4C1)+4C4
= (4*4)+(6*6)+(4*4)+1
= 16+36+16+1=69
Total 4M 4W
8C4=70
4C4=1
At least one girl = total - with out girl
At least one girl =70-1=69
B)
Question: The area of a sector of a circle of radius 4 cm formed by an arc of length 3.5 cm is?
A.7
B.7.67
C.8.75
D.8.98
Answer: A.7
Explanation: (4 * 3.5)/2
= 7
Answer:A
Question: What is the smallest no. which must be added to 53403977 so as to obtain a sum which is divisible by 11?
A.5
B.4
C.0
D.1
Answer: C.0
Explanation: For divisibility by 11, the difference of sums of digits at even and odd places must be either zero or divisible by 11.
For 53403977 , Difference =(5+4+3+7) -(3+0+9+7)=19-19=0.
=> 53403977 is also divisible by 11
C
Question: Of 67 players on a cricket team, 37 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total?
A.54
B.55
C.57
D.71
Answer: C.57
Explanation: Total = 67
Thrower = 37
Rest = 67 - 37 = 30
Left Handed = 30/3 = 10
Right handed = 20
If all Thrower are right handed then total right handed is 30 + 20 = 57
so C. 57 is the right answer
Question: Average of 17 results is 71. If the average of first eight results is 72 and average of last eight results is 69 Then find the ninth result?
A.79
B.81
C.77
D.72
Answer: A.79
Explanation: Option 'A'
Question: In a group of buffaloes and ducks, the number of legs are 24 more than twice the number of heads. What is the number of buffaloes in the group?
A.6
B.8
C.10
D.12
Answer: D.12
Explanation: Let the number of buffaloes be x and the number of ducks be y.
Then 4x+2y=2(x+y)+24
=>x=12
ANSWER D 12
Question: A and B started a business investing Rs. 50,000 and Rs 20,000 respectively. In what ratio the profit earned after 2 years be divided between A and B respectively?
A.5:2
B.9:2
C.18:20
D.1:4
Answer: A.5:2
Explanation: A: B = 50000 : 20000 = 5 : 2
ANSWER:A
Question: There are two numbers. If 40% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?
A.5/9
B.5/7
C.5/3
D.5/8
Answer: D.5/8
Explanation: Let the two numbers be x and y.
40/100 * x + y = 5/4y
=> 2/5 x = 1/4 y => x/y
= 5/8
Answer: D
Question: The average of 13 numbers is 60. Average of the first 7 of them is 57 and that of the last 7 is 61. Find the 8th number?
A.46
B.87
C.265
D.276
Answer: A.46
Explanation: Sum of all the 13 numbers = 13 * 60 = 780
Sum of the first 7 of them = 7 * 57 = 399
Sum of the last 7 of them = 7 * 61 = 427
So, the 8th number = 427 + 399 - 780
= 46.
Answer: A
Question: __2A
x__B
____
CC
In the multiplication problem above, A, B, and C represent distinct digits. If the sum of A and B is equal to 2, what is the value of C?
A.6
B.5
C.0
D.3
Answer: C.0
Explanation: If A+B=2
assuming A and B are positive then A*B<10 (they could be either 1)
therefore
A*B=C
2*B=C
A+B=2
Three simple equations - divide the 1st/2nd --> A=2 plug it the 3rd --> B=0 --> C=0 (ANSWER C)
Question: A contractor undertakes to do a job within 100 days and hires 10 people to do it. After 20 days, he realizes that one fourth of the work is done so he fires 2 people. In how many more days W will the work get over?
A.60
B.W=70
C.W=75
D.W=80
Answer: C.W=75
Explanation: We can also use the concept of man-days here
100 days -->10men so the job includes 100*10=1000 man-days
After 20 days
1/4 of Job is completed so 1/4 X 1000 man-days=250 man-days Job is done
Now the Balance Job=1000-250=750 man-days worth of Job
Since 2 men are fired so B/L men=8
Therefore Total no. of days of Job=750 man-day/8 days = 375/4=94 days (approx.)
Now since this is total and Ques. is asking for additional no. of days,
So 94-20=74 days
The nearest approx. to answer is 75
Ans: C (75 days)
Question: If a solid sphere of radius 10 cms is moulded into 8 spherical solid balls of equal radius, then surface area of each ball (in cm2) is?
A.100
B.277
C.267
D.898
Answer: A.100
Explanation: 4/3 π * 10 * 10 * 10 = 8 * 4/3 πr3
r = 5
4π * 5 * 5 = 100π
Answer: A
Question: A salesperson received a commission of 3 percent of the sale price for each of the first 100 machines that she sold and 4 percent of the sale price for each machine that she sold after the first 100. If the sale price of each machine was $10,000 and the salesperson received a $45,000 commission, how many machines did she sell?
A. 140
B. 103
C. 105
D. 115
Answer: A. 140
Explanation: First 100 machines = 3% commission = 0.03*100*10000 = 30000
Commission from sale of next machines = 46000 - 30000 = 16000
So 40 more machines..
Total = 140 machines
IMO A..
Question: Amar takes as much time in running 21 meters as a car takes in covering 54 meters. What will be the distance covered by Amar during the time the car covers 1.8 km?
A.700 m
B.500 m
C.670 m
D.700 m
Answer: D.700 m
Explanation: Distance covered by Amar
= 21/54 (1.8km)
= 7/18(1800) = 700 m
Answer: D
Question: How many of the positive factors of 25 , 15 and how many common factors are there in numbers?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: factors of 25 - 1, 5, and 25
factors of 15 - 1 , 3, 5 and 15
Comparing both, we have three common factors of 45,16-2
Answer B
Question: In a game of billiards, A can give B 20 points in 70 and he can give C 30 points in 70. How many points can B give C in a game of 100?
A.18
B.27
C.25
D.20
Answer: D.20
Explanation: A scores 70 while B score 50 and C scores 40.
The number of points that C scores when B scores 100 = (100 *40)/50 = 80.
In a game of 100 points, B gives (100 - 80) = 20 points to C.
Answer: D
Question: How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.25 sec
B.28 sec
C.30 sec
D.35 sec
Answer: C.30 sec
Explanation: Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
800+x = (65/3) * 60
800+x = 20 * 65 = 1300
x = 1300 - 800 = 500 meters
ANSWER:C
Question: The area of a circle is increased by 1500%. By what percent has the radius of the circle increased?
A. 100%
B. 200%
C. 300%
D. 600%
Answer: C. 300%
Explanation: The area of the circle is increased by 1500%, thus the area is increased 16 times.
The area of a circle it proportional to the square of the radius (area=πr^2), therefore the radius must increase 4 times (diameter increase 4 times = area increase 16 times), which is increase by 500%.
Answer: C
Question: The sides of a cube are in the ratio 1:2 the ratio of their volume is?
A.1:9
B.1:5
C.1:8
D.1:1
Answer: C.1:8
Explanation: 1:8
Answer: C
Question: A student got twice as many sums wrong as he got right. If he attempted 24 sums in all, how many did he solve correctly ?
A.12
B.16
C.8
D.24
Answer: C.8
Explanation: Explanation:
Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 24 3x = 24 x = 8.
Answer:C
Question: At Joes Steakhouse the hourly wage for a chef is 20% greater than that of a dishwasher, and the hourly wage of a dishwasher is half as much as the hourly wage of a manager. If a managers wage is $6.50 per hour, how much less than a manager does a chef earn each hour?
A.$2.6
B.$2.40
C.$3.40
D.$4.40
Answer: A.$2.6
Explanation: Manager wages per hour = $6.50
Dishwasher wages per hour = half of manager's wages. = 1/2($6.50) ==> $3.25
Chef wages per hour = 20% greater than Dishwasher wages
--> 20% of $3.25 = (20*($3.25)) /100
--> ($65)/100
--> $0.65
Therefore,
Chef wages per hour = $3.25 + $0.65 ==> $3.9
Difference of wages between manager and chef = $6.50 - $3.9 ==> $2.6
ANSWER:A
Question: If four students are made to sit in a row, then 7 don't have seats. If 7 students are made to sit in a row, then two rows are empty. How many students have to sit a row such that each row has equal number of students and all students are seated?
A.0
B.1
C.4
D.5
Answer: D.5
Explanation: Let there be a rows.
Then 4a + 7 = 7(a-2) [equating the number of students]
=> a= 7
and total number of students = 35
Therefore 5 students much sit in each row such that each row has an equal number of students and all students are seated.
Option (D)
Question: Find the odd man out. 1, 9, 16, 51, 121, 169, 225
A.169
B.51
C.16
D.1
Answer: B.51
Explanation: Explanation :
Each of the given numbers except 51 is a perfect square. Answer : Option B
Question: One man traveled a distance of 61 km in 9hrs. He traveled partly on footat 4 km/hr and partly on bicycle ta 9 km/hr. The distance traveled on foot is?
A.10 km
B.12 km
C.16 km
D.18 km
Answer: C.16 km
Explanation: Let the distance travelled on foot be x km.
Then, distance travelled on bicycle = (61 -x) km.
So, x + (61 -x) = 9
4 9
9x + 4(61 -x) = 9 x 36
5x = 80
x = 16 km.
C
Question: A train passes a station platform in 36 sec and a man standing on the platform in 21 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
A.288
B.225
C.881
D.1277
Answer: B.225
Explanation: Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 21 = 315 m.
Let the length of the platform be x m . Then,
(x + 315)/36 = 15 => x = 225 m.
Answer: B
Question: The area of the house of a hall is 20 m2 that of a longer wall 10 m2 and of the shorter wall 8 m2, find the edge of the new cube?
A.45 m3
B.40 m3
C.60 m3
D.600 m3
Answer: B.40 m3
Explanation: lb = 20 ; lh = 10 ; fh = 8
(lbh)2 = 20 * 10 * 8 => lbh = 40 m3
ANSWER:B
Question: A boat can move upstream at 40 kmph and downstream at 56 kmph, then the speed of the current is?
A.5
B.6
C.8
D.4
Answer: C.8
Explanation: US = 40
DS = 56
M = (56 - 40)/2 = 8 Answer:C
Question: A man swims downstream 30 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water?
A.2 kmph
B.8 kmph
C.16 kmph
D.4 kmph
Answer: B.8 kmph
Explanation: 30 --- 3 DS = 10
? ---- 1
18 ---- 3 US = 6
? ---- 1 M = ?
M = (10 + 6)/2 = 8
ANSWER:B
Question: What will be the ratio of simple interest earned by certain amount at the same rate of interest for 6 years and that for 9 years?
A.1 : 3
B.1 : 4
C.2 : 3
D.Data inadequate
Answer: C.2 : 3
Explanation: Let the principal be P and rate of interest be R%.
∴ Required Ratio = [(P×R×6/100) /(P×R×9/100)]=6PR/9PR=69=2:3
Answer C
Question: A bar over a sequence of digits in a decimal indicates that the sequence repeats indefinitely. What is the value of (10^4 -10^2)(0.0016)?
A.15
B.15.84
C.17
D.18.5
Answer: B.15.84
Explanation: You get 10^2 (100-1) (.0016)
we know 16/10000 = .0016
10^2 (99) * (16/10000)
10^2 = 100 and 100^2 = 10000
Cancel out the 100 with the 10^2
Left with 99(16/100).
0.99*16 = 15.84
Answer : B
Question: For any number y, y* is defined as the greatest positive even integer less than or equal to y. What is the value of 8.2 – 8.2*?
A.0.2
B.1.2
C.1.8
D.2.2
Answer: D.2.2
Explanation: Since y* is defined as the greatest positive even integer less than or equal to y, then 8.2* = 4 (the greatest positive even integer less than or equal to 5.2 is 4).
Hence, 8.2 – 8.2* = 8.2 - 6= 2.2
Answer: D.
Question: A bakery opened yesterday with its daily supply of 40 dozen rolls. Half of the rolls were sold by noon, and 65 percent of the remaining rolls were sold between noon and closing time. How many dozen rolls had not been sold when the bakery closed yesterday?
A. 5
B. 6
C. 7
D. 8
Answer: C. 7
Explanation: answer is C ...7 dozens ....
half sold by noon --> 20 dozens (20 *12 =240)
remaining --> 20 dozens i.e 240 eggs...
65% sold --> 65*240/100 =156 eggs
remaining 35 % --> 84 eggs (7 dozens ) --> answer
Question: A candy company sells premium chocolate at $5 per pound and regular chocolate at $2 per pound in increment of whole pound only.If Barrett buys a pack of candies which costs him $31, how many pounds of premium chocolates are in the box?
A.[A] 1
B.[B] 2
C.[C] 3
D.[D] 4
Answer: B.[B] 2
Explanation: This question is a bit of Special equations with a single set of unique values.
the Equation stands : 5X + 2Y = 31
Subtract multiple of 5 from 31 and check whether the remaining total is divisible by 4
31 - 5 = 26 -> Not divisible by 4
31 - 10 = 21 -> Not divisible by 4
31 - 15 =16 -> Divisible by 4
31 - 20 =11 -> Not divisible by 4
31 - 25 =6 -> Not divisible by 4
31 - 30 =1 -> Not divisible by 4
Any multiple of 5 hereon will give a negative value for regular chocolates bought and hence, inadmissible
Thus Amount spent on regular chocolate= $16
Amount spent on Premium chocolate= $15
Price per premium chocolate = $5
No. Of boxes of premium chocolate bought = 10 / 5 = 2
Correct Option : B
Question: Two cars start at the same time from opposite ends of a highway that is 105 miles long. One car is riding at 15 mph and the second car is riding at 20 mph. How long after they begin will they meet?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: As cars are moving in opposite directions their speeds will be added. So their relative speeds: 20+15 = 35 mph
Total distance to be covered = 105 miles.
Time taken would be: 105 miles/35 mph = 3 hours
C is the answer.
Question: A vendor bough toffees at 6 for a rupee. how many for a rupee must he sell to gain 20%?
A.3
B.8
C.5
D.9
Answer: C.5
Explanation: C.P or toffees = Rs.1, S.P of 6 toffee = 120% of Rs.1 = Rs.6/5
for Rs. 6/5, toffees sold=6, for Rs.1, toffees sold= (6*5/6)= 5
Correct answer (C)
Question: Each month a retailer sells 100 identical items. On each item he makes a profit of $30 that constitutes 10% of the item's price to the retailer. If the retailer contemplates giving a 5% discount on the items he sells, what is the least number of items he will have to sell each month to justify the policy of the discount?
A.191
B.213
C.221
D.223
Answer: D.223
Explanation: For this question, we'll need the following formula:
Sell Price = Cost + Profit
We're told that the profit on 1 item is $20 and that this represents 10% of the cost:
Sell Price = Cost + $30
Sell Price = $300 + $30
Thus, the Sell Price is $330 for each item. Selling all 100 items gives the retailer...
100($30) = $2,000 of profit
If the retailer offers a 5% discount on the sell price, then the equation changes...
5%(330) = $16.5 discount
$313.5 = $300 + $13.5
Now, the retailer makes a profit of just $13.5 per item sold.
To earn $2,000 in profit, the retailer must sell....
$13.5(X) = $2,000
X = 2,000/13.5
X = 222.222222 items
You'll notice that this is not among the answer choices.... 221 and 223 are.
Selling 221 items would get us 9(221) = $1989 which is NOT enough money. To get back to AT LEAST $2,000, we need to sell 223 items.
Final Answer:
D