RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: ABCD is a square where AB =âˆš4004. Let X be a point on AB and Y be a point on CD such that AX = CY . Compute the area of trapezoid AXYD.
A.3008
B.2002
C.1008
D.2016
Answer: B.2002
Explanation: Note that trapezoids AXY D and BXY C are congruent, so the area of AXY D is
always
4004/2= 2002 .
correct answer B
Question: A horse is tethered to one corner of a rectangular grassy field 46 m by 20 m with a rope 17 m long. Over how much area of the field can it graze?
A.154 cm2
B.308 m2
C.227 m2
D.407 m2
Answer: C.227 m2
Explanation: Area of the shaded portion
= 1⁄4 × π × (17)2 = 227 m2
Answer C
Question: .It was calculated that 75 men could complete a piece of work in 20 days. When work was scheduled to commence, it was found necessary to send 25 men to another project. How much longer will it take to complete the work?
A.20 days.
B.23 days.
C.30 days.
D.92 days.
Answer: C.30 days.
Explanation: One day work = 1 / 20
One man’s one day work = 1 / ( 20 * 75)
Now:
No. Of workers = 50
One day work = 50 * 1 / ( 20 * 75)
The total no. of days required to complete the work = (75 * 20) / 50 = 30
Answer:C
Question: The total price of a kilogram each of Shimla apples and Red Delicious apples is 250 rupees more than the total price of a kilogram each of Red Delicious apples and Fuji apples. Fuji apples is how much cheaper than Shimla apples?
A.250
B.125
C.500
D.100
Answer: A.250
Explanation: (Shimla + Red Delicious) - (Red Delicious + Fuji) = 250
Shimla - Fuji = 250
Answer: A
Question: On a class test there are 5 questions. One question has been taken from each of four chapters. The first two chapters have 3 questions each, the last two chapters have 6 questions each. The fourth question can be picked from any of the four chapters. How many different question papers could have been prepared?
A.
B.
C.
D.
E.
A.540
B.1260
C.2268
D.4000
Answer: C.2268
Explanation: nIf 2 questions are picked from the first chapter: C23∗3∗6∗6C32∗3∗6∗6;
If 2 questions are picked from the second chapter: 3∗C23∗6∗63∗C32∗6∗6;
If 2 questions are picked from the third chapter: 3∗3∗C26∗63∗3∗C62∗6;
If 2 questions are picked from the third chapter: 3∗3∗6∗C263∗3∗6∗C62.
Total = 2,268.
ANS:C
Question: In a group of ducks and cows, the total number of legs are 32 more than twice the no. of heads. Find the total no.of buffaloes.
A.11
B.12
C.14
D.16
Answer: D.16
Explanation: Let the number of buffaloes be x and the number of ducks be y
=> 4x + 2y = 2 (x + y) + 32
=> 2x = 32 => x = 16
D
Question: In a box of 11 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective?
A.1/25
B.28/55
C.2/35
D.2/55
Answer: B.28/55
Explanation: First, there are 9C3 ways you can select 3 good pencils from 4 good ones.
Second, there are 11C3 ways you select 3 pencils from 6 ones in the box.
Then, the probability that neither pen will be defective is: 9C3/11C3=84/165 = 28/55
Answer is B
Question: A, B, C subscribe Rs. 50,000 for a business, A Subscribes Rs. 4000 more than B and B Rs. 5000 more than C. Out of a total profit of Rs. 70,000, A receives :
A.14700
B.24703
C.29400
D.33777
Answer: C.29400
Explanation: Explanation:
Let C = x. Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.
So, x + x + 5000 + x + 9000 = 50000 <=> 3x = 36000 <=>
x = 12000.
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
A's share = Rs. (70000 * 21/50 ) = Rs. 29,400.
Answer: C)
Question: Rahul went to a shop and bought things worth Rs. 29, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
A.Rs 15
B.Rs 12.10
C.Rs 23.70
D.Rs 26.80
Answer: C.Rs 23.70
Explanation: Explanation :
Let the cost of the tax items = x
Given that tax rate = 6%
Cost of tax items, x*(6/100) = 30/100
x = 5 rs
Now non taxable item = total cost - cost for taxable item - tax
= 29 - 5 - 0.30
=23.70
Answer : C
Question: A certain family has 3 sons: Richard is 6 years older than David, and David is 8 years older than Scott. If in 8 years, Richard will be twice as old as Scott, then how old was David 5 years ago?
A. 9
B. 10
C. 12
D. 14
Answer: A. 9
Explanation: Let's say
Age of Richard isR
Age of David isD
Age of Scott isS
Now
Richard is 6 years older than David,
i.e. R = D +6
David is 8 years older than Scott
i.e. D = S +8
If in 8 years, Richard will be twice as old as Scott
i.e. R+8 = 2x(S+8)
i.e. R+8 = 2S + 16
i.e. R = 2S+8
But R = D+6 = (S+8)+6 = S+14
therefore, 2S + 8 = S +14
i.e. S = 6
i.e. R = 20
i.e. D = 14
Now,
how old was David 5 years ago?
i.e. D-5 = 14-5 = 9 years
Answer: Option
A
Question: A rectangular field has area equal to 150 sq m and perimeter 50 m. Its length and breadth must be?
A.15 m,17 m
B.85 m,10 m
C.15 m,80 m
D.15 m,10 m
Answer: D.15 m,10 m
Explanation: lb = 150
2(l + b) = 50 => l + b = 25
l – b = 5
l = 15 b = 10
Answer:D
Question: A can do a piece of work in 12 days and B can do it in 15 days and C can do it 20 days. They started the work together and A leaves after 2 days and B leaves after 4 days from the beginning. How long will work lost?
A.15 1/3
B.16 1/3
C.17 1/3
D.18 1/3
Answer: A.15 1/3
Explanation: 2/12 + 4/15 + x/20 = 1
x = 46/3 = 15 1/3
ANSWER:A
Question: If q and r are both odd numbers, which of the following must also be odd?
A.q – r
B.(q + r)^2
C.q(q + r)
D.(qr)^2
Answer: D.(qr)^2
Explanation: Since q and r are odd numbers we can put q and r as q=2*Q+1 and r=2*R+1, for some integers Q, R.
A. q-r=(2*Q+1)-(2*R+1)=2*(Q-R) ---> must be an even number.
B. (q + r)^2 =(2Q+2R+2)^2= 4*(Q+R+1)^2 ---> must be an even number.
C. q(q+r) = (2Q+1)(2Q+2R+2)= 2*(2Q+1)(Q+R+1) ---> must be an even number.
D. (qr)^2 = ((2Q+1)(2R+1))^2 = (4QR +2Q +2R +1)^2
by putting 2QR+Q+R = T we have (2T+1)^2= 4T^2 + 4T +1=2(2T^2 +2T)+1 ---> must be an odd number.
E. q/r cannot be an integer
The answer is, therefore, (D)
Question: Find out the wrong term in the series 2, 3, 4, 4, 6, 8, 9, 12, 16
A.9
B.8
C.7
D.6
Answer: A.9
Explanation: Explanation:
The given sequence is a combination of three series:
i)1st, 4th, 7th terms i.e, 2, 4, 9
ii)2nd, 5th, 8th terms i.e, 3, 6, 12
iii)3rd, 6th, 9th terms i.e, 4, 8, 16
In each one of i, ii, iii, each term is twice the preceding term.
So, 9 is wrong and must be replaced by (4*2) = 8
Answer: A) 9
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
A.1/455
B.1/429
C.1/408
D.1/421
Answer: A.1/455
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue
= ³C₃/¹⁵C₃ = (1 * 3 * 2 * 1)/(15 * 14 * 13)
= 1/455
Answer: A
Question: If a function f is defined by f(x)= -1/x for all non zero numbers x. If f(a) = -1/2 and f(ab) = 1/4 then b= ?
A.-1/2
B.1/2
C.2
D.-2
Answer: D.-2
Explanation: f(a) = -1/2 = -1/a, and thus a = 2
f(ab) = 1/4, and thus ab = -4
2b = -4
b = -2
The answer is D.
Question: Find the ones digit of 73^340
A.3
B.5
C.6
D.7
Answer: A.3
Explanation: Cyclicity of 3 is 3,9,7,1after 4 multiplication again the cycle repeats.
So divide 340 by 4 and we get 87 as quotient and 2 as remainder. So cycle will run for 87 times and then 2 times more. So pick up the 2nd item from the cycle.
Hence Answer A.
Question: The perimeter of a triangle is 35 cm and the inradius of the triangle is 4.5 cm. What is the area of the triangle?
A.22
B.75
C.78
D.54
Answer: C.78
Explanation: Area of a triangle = r * s
Where r is the inradius and s is the semi perimeter of the triangle.
Area of triangle = 4.5 * 35/2
= 78.75 cm2
Answer:C
Question: In a camp, there is a meal for 160 men or 220 children. If 160 children have taken the meal, how many men will be catered to with remaining meal?
A.20
B.43
C.50
D.10
Answer: B.43
Explanation: There is a meal for 220 children. 160 children have taken the meal.
Remaining meal is to be catered to 60 children.
Now, 220 children 160 men.
60 children (160/220)	* 60 = 43 men
Answer is B.
Question: A batsman played seven games and scored an average of 80 runs per game. If, in his first five games, he scored 75, 69, 81, 90, and 73 runs, what was the average (arithmetic mean) number of runs scored over the last two games?
A.65
B.81
C.82
D.86
Answer: D.86
Explanation: The first thing to recognize is that to find the average, you take the sum and divide by the number of inputs (games, in this case) you have. Here were have 7 inputs, or games. Therefore, I approach this problem by first writing the following:
(A+B+C+D+E+F+G)/7 = 80
Plug in the sum of the first 5 games (388) for (A+B+C+D+E)
[(388+F+G)/7]= 80
Multiply both sides by 7
388+F+G = 560
Subtract 388 on both sides
F+G = 172
Since the answer asks for the average of the last two games, F and G, all you need to do is take 172 and divide it by 2, giving 86.
The answer is D.
Question: Lori deposits $10,000 in a savings account at 10% annual interest, compounded annually.
After 3 years, what is the balance on the account?
A.13310
B.13410
C.13510
D.13610
Answer: A.13310
Explanation: The deposit of $10,000 increases by 10% every year. So use the formula for amount in case of CI.
Amount = P*(1 + r/100)^n
Amount = 10,000 * (1 + 10/100)^3
Amount = 10,000*(1.1)^3
Amount = 13310
ANSWER:A
Question: Attorneys are questioning 11 potential jurors about their ability to serve on a jury and decide a case fairly. Seven individuals will be selected to serve on the jury. If each potential juror has an equal chance of being selected, what is the probability that Tamara and Inga are chosen for the jury?
A.2/11
B.2/7
C.21/55
D.4/11
Answer: C.21/55
Explanation: First person to be chosen one of the two girls - 2/11
Second person to be chosen to be the other girl - 1/10
The probability to chose both girls - (2/11)*(1/10) = 1/55.
The two girls can be chosen anywhere in the list of the 7 jurors, therefore the final probability is (1/55)*7C2 = (1/55)*(7*6/2) = 21/55.
Combinatorial approach:
Total number of possibilities to choose the 7 jurors - 11C7 = 11*10*9*8/(2*3*4) = 11*10*3.
Number of possibilities to have the two girls among the final 7 jurors - 9C5 = 9*8*7*6/(2*3*4) = 9*2*7 (the two girls must be in, therefore we need to choose 5 more people from the remaining 9).
Required probability 9*2*7/(11*10*3) = 21/55.
(I prefer not to multiply before I express the final probability as a ratio, I always try to reduce a fraction whenever possible.)
Answer C.
Question: List R contains five numbers that have an average value of 60. If the median of the numbers in the list is equal to the mean and the largest number is equal to 20 more than two times the smallest number, what is the smallest possible value in the list?
A.25
B.28
C.31
D.34
Answer: B.28
Explanation: The middle number is 60.
Let the smallest number be x. Then the largest number is 2x+20.
To make x as small as possible, let's make the remaining numbers as large as possible.
So the second largest = the largest = 2x+20.
The second smallest should be equal to the median.
The numbers are x, 60, 60, 2x+20, 2x+20.
x + 60 + 60 + 2x + 20 + 2x + 20 = 5*60 = 300
5x = 140
x = 28
The answer is B.
Question: The sum of the first 50 positive even integers is 2550. What is the sum of the even integers from 202 to 300 inclusive?
A.5,150
B.7,550
C.10,150
D.12,550
Answer: D.12,550
Explanation: 2 + 4 + 6 + 8 +...+ 100 = 2550
202 + 204 + ... + 300 = 50(200) + (2+4+...+100) = 10,000 + 2550 = 12,550
The answer is D.
Question: A tank contains 10,000 gallons of a solution that is 7 percent sodium chloride by volume. If 2,500 gallons of water evaporate from the tank, the remaining solution will be approximately what percent sodium chloride?
A. 1.25%
B. 3.75%
C. 9.33%
D. 10.67%
Answer: C. 9.33%
Explanation: The remaining solution will be approximately what percent sodium chloride?means:what percent of the remaining solution is sodium chloride. Now, since the remaining solution is 10,000-2,500=7,500 gallons and sodium chloride is 700 gallons (7% of initial solution of 10,000 gallons) then sodium chloride is 700/7,500*100=~9.33% of the remaining solution of 7,500 gallons.
Answer: C.
Question: Barbata invests $2200 in the National Bank at 5%. How much additional money must she invest at 8% so that the total annual income will be equal to 6% of her entire investment?
A.1100
B.3000
C.1000
D.3600
Answer: A.1100
Explanation: Let the additional invested amount for 8% interest be x;
Equation will be;
2200+0.05*2200+x+0.08x = 2200+x+0.06(2200+x)
0.05*2200+0.08x = 0.06x+0.06*2200
0.02x = 2200(0.06-0.05)
x = 2200*0.01/0.02 = 1100
Ans: "A"
Question: The average age of the mother and her 6 children is 12 years which is reduced by 5 years if the age of the mother is excluded. How old is the mother?
A.42 years
B.40 years
C.48 years
D.50 years
Answer: A.42 years
Explanation: Total age of the mother and six children = 12 × 7 = 84 years.
Total age of six children = 7 × 6 = 42 years. (since average is reduced by 5)
Mother is 42 years old.
ANSWER:A
Question: When 1/10 percent of 3,000 is subtracted from 1/10 of 3,000, the difference is
A.2970
B.297
C.2997
D.300
Answer: B.297
Explanation: (1/10)*3000 - (1/10)%*3000 =
300 - (1/1000)*3000 =
300 - 3 = 297
The answer is B.
Question: A student is ranked 13th from right and 8th from left.how many are there?
A.18
B.19
C.20
D.21
Answer: C.20
Explanation: 13th from right means = x + 12
8th from left means = 7 + x
Total = 12+7+1 = 20
ANSWER:C
Question: How many five-digit numbers are there, if the two leftmost digits are even, the other digits are odd and the digit 4 cannot appear more than once in the number?
A.1375
B.8451
C.1546
D.2375
Answer: D.2375
Explanation: Total five-digit numbers with two even leftmost digits and with three odd last digits: EEOOO - 4*5*5*5*5=4*5^4 (notice that we have only 4 choices for the first digit since we cannot use zero);
Total five-digit numbers with two 4's as leftmost digits and with three odd last digits: 44OOO - 5*5*5=5^3;
So, the answer is 4*5^4-5^3=5^3(4*5-1)=125*19=2375.
Answer: D.
Question: A man buys Rs. 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:
A.15
B.10
C.20
D.25
Answer: A.15
Explanation: Dividend on rs 20 = (9/100*20) = 9/5
=>9/5 is an income on Rs (100/12 * 9/5) = 15
ANSWER A
Question: Find number which is 60% less than 80.
A.18
B.32
C.28
D.26
Answer: B.32
Explanation: Explanation:
60% less is 40% of the given number
Therefore, 40% of 80 is 32.
ANSWER: B
Question: The average weight of 6 persons increases by 1.5 kg. If a person weighing 65 kg is replaced by a new person, what could be the weight of the new person?
A.74 kg
B.77 kg
C.76.5 kg
D.Data inadequate
Answer: A.74 kg
Explanation: total weight increases = 6 × 1.5 = 9 kg
so the weight of new person = 65 + 9 = 74 kg
Answer A
Question: The area of a rectangular plot is 360 square metres. If the length is 25% less than the breadth, what is the breadth of the plot?
A.32 m
B.12 m
C.20 m
D.22 m
Answer: D.22 m
Explanation: length =75% of breadth.
length×breadth =360 m2
⇒ 75% of breadth×breadth =360 m2
⇒ 75/100× breadth×breadth =360 m2
⇒ breadth×breadth =480 m2
⇒ breadth =22 m
ANSWER:D
Question: Missing number in the series
4 9 20 43 90 185 ?
A.376
B.185
C.190
D.195
Answer: A.376
Explanation: 4*2+1=9
9*2+2=20
20*2+3=43
43*2+4=90
90*2+5=185
185*2+6=376
ANSWER:A
Question: Several people are sitting around a round table playing a card game with a deck of 67 cards. Each person is dealt one card per deal, and the cards are dealt in a clockwise fashion. If Martin is dealt both the first card of the deck and the last card of the deck, which of the following could be the total number of people sitting at the table?
A.4
B.5
C.7
D.11
Answer: D.11
Explanation: Let n be the number of people at the table.
If Martin gets the first and the last card, it means Martin got one more card than the others.
Thus 67/n has a remainder of 1 and so 67-1 = 66 is a multiple of n.
The answer is D.
Question: Matt and Peter can do together a piece of work in 20 days. After they have worked together for 12 days Matt stops and Peter completes the remaining work in 8 days. In how many days Peter complete the work separately.
A.21
B.24
C.20
D.25
Answer: C.20
Explanation: Together they complete the job in 20 days means they complete 12/20 of the job after 12 days.
Peter completes the remaining (8/20) of the job in 8 days which means that the whole job(1) can be completed in X days.
X=8/(8/20)=20
C
Question: In how many ways can the letters in MATHEMATICS be arranged?
A.4989060
B.4999980
C.4989600
D.4989800
Answer: C.4989600
Explanation: There are 11 letters in the word "MATHEMATICS" of which two are M's, two are A's, two are T's and all other are distinct. Therefore require number of arrangements =11!/2!*2!*2! =4989600 Answer : C
Question: A rectangular-shaped carpet that measures x feet by y feet is priced at $22. What is the cost of the carpet, in dollars per square yard? (1 square yard = 8 square feet)
A.xy/297
B.11xy/3
C.176/(xy)
D.297/(xy)
Answer: C.176/(xy)
Explanation: The area of the carpet in feet is xy.
The area in square yards is xy / 8.
The price per square yard is 22/ (xy/8) = 176/(xy).
The answer is C.
Question: Given that 2x + 9 > 5 and 5x - 13 < 7, all values of x must be between which of the following pairs of integers?
A.-4 and -1
B.-1 and 4
C.-4 and 1
D.-2 and 4
Answer: D.-2 and 4
Explanation: 2x + 9 > 5
i.e 2x >5-9
i.e. 2x > -4
i.e. x > -2
Also, 5x - 13 < 7
i.e. 5x <7+13
i.e 5x < 20
i.e x < 4
i.e. -2 < x < 4
Answer: Option D
Question: At 12.00 hours, J starts to walk from his house at 6 kmph. At 13.30, P follows him from J's house on his bicycle at 8 kmph. When will J be 3 km behind P?
A.19.39
B.19.3
C.19.32
D.19.33
Answer: B.19.3
Explanation: By the time P starts J is 1.5 hr x 6 = 9 km away from his house.
J is 3 km behind when P is 3 km ahead of him. ie., P has to cover 12 km. So he takes 12 / (8 - 6) = 6 hrs after 13.30. So the required time is 19.30Hrs
Answer:B
Question: A train overtakes two persons walking along a railway track. The first person walks at 4.5 km/hr and the other walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train?
A.80 km/hr
B.81 km/hr
C.85 km/hr
D.84 km/hr
Answer: B.81 km/hr
Explanation: Let x is the length of the train in meter and y is its speed in kmph
x/8.4 = (y-4.5)(10/36) ---(1)
x/8.5 = (y-5.4)(10/36) ---(2)
Dividing 1 by 2
8.5/8.4 = (y-4.5)/ (y-5.4)
=> 8.4y - 8.4 × 4.5 = 8.5y - 8.5×5.4
.1y = 8.5×5.4 - 8.4×4.5
=> .1y = 45.9-37.8 = 8.1
=> y = 81 km/hr
Answer is B.
Question: Jackson has $313,194 dollars in his investment accounts. What is the least amount of money (in whole number of dollars) that he must remove from his account if he wants to split this money evenly among nine new investors?
A.$1
B.$2
C.$3
D.$4
Answer: C.$3
Explanation: In order to divide the sum in 9 parts, the amount must also be divisible by 9
Divisibility rule of 9: The sum of the digits must be divisible by 9
Sum of digits of 313,194 = 21 and 18 is divisible by 9.
Hence we need to subtract 3 to this number for it to be divisible by 9
Correct Option: C
Question: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement?
A.1778
B.1682
C.9178
D.1900
Answer: D.1900
Explanation: 2000 ---- 54
2000 ---- 39
x ----- 20
x*20 = 2000*39
x = 3900
2000
-------
1900
Answer: D
Question: An amount of Rs. 100000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 1/4 %, then the amount invested at 11% was?
A.12500
B.37500
C.29977
D.26777
Answer: A.12500
Explanation: Let the sum invested at 9% be Rs. x and that invested at 11% be Rs. (100000 - x). Then,
(x * 9 * 1)/100 + [(100000 - x) * 11 * 1]/100 = (100000 * 37/4 * 1/100)
(9x + 1100000 - 11x) = 37000/4 = 925000
x = 87500
Sum invested at 9% = Rs. 87500
Sum invested at 11% = Rs. (100000 - 87500) = Rs. 12500.
Answer: A
Question: A WORKS TWICE AS FAST AS B. IF B CAN COMPLETE A WORK IN 8 DAYS INDEPENDENTLY, THE NUMBER OF DAYS IN WHICH A AND B CAN TOGETHER FINISH THE WORK IS:
A.8/3 DAYS
B.3/8 DAYS
C.1/4 DAYS
D.4/1 DAYS
Answer: A.8/3 DAYS
Explanation: RATIO OF RATES OF WORKING OF A AND B = 2:1. SO, RATIO OF TIME TAKEN = 1:2
A'S 1 DAY'S WORK = 1/4, B'S 1 DAY'S WORK = 1/8
(A+B)'S 1 DAY'S WORK = (1/4+1/8)=3/8=8/3
SO, A AND B TOGETHER CAN FINISH THE WORK IN 8/3 DAYS.
CORRECT OPTION: A
Question: Natasha carries a paintbrush of length 1 and walks around the perimeter of a regular 2016-gon
with side length 1, painting all of the area outside the polygon that she can reach. What is the
area that Natasha paints?
A.2014+π
B.2015+π
C.2016+π
D.2013+π
Answer: C.2016+π
Explanation: If the curve is convex, Natasha will only be turning one way, and by the time she
returns to the origin she will have turned exactly 2π radians. Therefore, she will paint the area
of a circle as she turns corners, because she paints a sector of the unit circle each time until the
sum of the sector angles is 2π. On each of the 2016 straight edges, she paints a rectangle of
length 1 and width 1, because the 2016-gon has side length 1 and the paintbrush also has length
1. Thus the total area is 2016 *1 + π* 12 = 2016 + π
correct answer C
Question: When a 160 meters long rod is cut down into small pieces of length 3.2 meters each. Then how many pieces are available ?
A.52
B.50
C.62
D.67
Answer: B.50
Explanation: Answer
No. of pieces = Total length / Length of each piece
= 160/3.2
= 50
Option: B
Question: A man swims downstream 30 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water?
A.5
B.8
C.9
D.1
Answer: B.8
Explanation: 30 --- 3 DS = 10
? ---- 1
18 ---- 3 US = 6
? ---- 1 M = ?
M = (10 + 6)/2 = 8
Answer:B
Question: In a room there are 7 people. Each person shook hands with every other person. How many hand shakes were there?
A.19
B.20
C.21
D.22
Answer: C.21
Explanation: 7C2 = 21
The answer is C.
Question: Jaclyn buys $30 000 worth of debentures in a company. She earns 9.5% p.a. simple interest, paid to her quarterly (that is, every 3 months). If the agreed period of the debenture was 18 months: calculate the amount of interest Jaclyn will earn for each quarter
A.712.5
B.1234
C.1289
D.1345
Answer: A.712.5
Explanation: Explanation:
I=(p x r x t)/100
= 30000*9.5/100*(18/12)^1/6 = 712.50
Answer: A
Question: Four staff members at a certain company worked on a project. The amounts of time that the four staff members worked on the project were in the ratio 2 to 3 to 5 to 6. If one of the four staff members worked on the project for 180 hours, which of the following CANNOT be the total number of hours that the four staff members worked on the project?
A.1440
B.960
C.576
D.192
Answer: D.192
Explanation: Four members worked in ration 2:3:5:6, hence as everyone mentioned, individual work could be taken as 2x, 3x,5x, and 6x. Also this gives us total work as 16x.
But we are told that one of these individual works is 30hrs. hence, possible scenarios, if
(1)2x =180 => 16x = 1440 (2) 3x =180 => 16x = 960 (3) 5x =180 => 16x = 576 (4) 6x =180 => 16x = 480
Hence Answer is D 192 which can not be any of these.
Question: If the 1st of the month occurs on a Monday, on which day of the week does the 19th occur?
A.Friday
B.Saturday
C.Sunday
D.Monday
Answer: A.Friday
Explanation: Each weekday is repeated every 7 days. The 19th of the month is 18 days after the 1st. 18 divided by 7 is 2, with a remainder of 4. Therefore, the 19th occurs on whichever day of the week is four days after the day we started on, meaning it is a Friday. Answer: A