RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A woman named Ranjani started a business investing Rs. 5,000. Roja joined him after six months with an amount of Rs. 5,000 and Sachin joined them with Rs. 10,000 after another six months. The amount of profit earned should be distributed in what ratio among Ranjani, Roja and Sachin respectively, 3 years after A woman started the business ?
A.7:6:10
B.12:15:16
C.42:45:56
D.6 : 5 : 8
Answer: D.6 : 5 : 8
Explanation: Explanation :
Akash : Roja : Sachin = (5,000 x 36) : (5,000 x 30) : (10,000 x 24)
= 36 : 30 : 48 => 6 : 5 : 8
Answer : D
Question: In printing test papers for Excel, Gayatri found that if she used Arial font size 10 instead of Times Roman font size 10 there was a reduction of 18% in the number of pages required for test papers. Further, if she reduced the font size from 10 to 9, the savings were 14% and 10% in Times Roman and Arial fonts respectively. If an test papers printing in Times Roman font size 9 is converted to Arial font size 9, what is the percentage reduction in the number of pages?
A.14.1
B.14.2
C.14.3
D.14.4
Answer: A.14.1
Explanation: Ans.
From TR-10 to A - 10 there is a reduction of 18% in the number of pages. and From TR-10 to TR-9 14% reduction, A - 10 to A - 9 10% reduction.
Assume Test paper in TR- 10 is 100 pages. So in TR- 9 the number of pages are 100X 86% = 86
Now in A-10 total pages are 100 X 82% = 82
Now in A - 9 total pages are 82 X 90% = 73.8
So total change in the number of pages = (86−73.8)/86×100 = 14.1
Answer A
Question: If 4 spiders make 4 webs in 4 days, then 1 spider will make 1 web in how many days?
A.1
B.3
C.5
D.4
Answer: D.4
Explanation: Explanation :
Let the required number days be x.
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)
Spiders 1:4|
|::4:1
Webs 4:1|
=> 1 * 4 * x = 4 * 1 * 4
=> x = 4
Answer : D
Question: The ratio of investments of A, B and C is 5:6:7. If they share the profit in the ratio of 5:12:14, then find the ratio of their periods of investments.
A.1:2:2
B.3:5:6
C.3:2:4
D.2:4:3
Answer: A.1:2:2
Explanation: The ratio of investments of A, B and C is 5:6:7.
The ratio of shares of A, B and C is 5:12:14.
Therefore, Ratio of their periods of investments is
(5/5) : (12/6) : (14/7) = 1:2:2
ANSWER:A
Question: Which of the following is closest to (9!-8!)/(9!+8!)?
A.0.01
B.0.8
C.0.2
D.1
Answer: B.0.8
Explanation: (9!-8!)/(9!+8!)
8! (9-1)/8! (9+1)
8/9 = 0.8
B is the answer
Question: How many digits are there in the integer 8^7 × 25^12?
A.27
B.24
C.21
D.19
Answer: B.24
Explanation: 8^7 × 25^12
This can be simplified to
2^21 × 5^24 (since 2^3 = 8 and 5^2 = 25)
Now 2 x 5 =10
So, simplifying further
(2^21 × 5^21) x 5^3
= 10^21 x 5^3
= 125 x 10^21
10^21 has 1 one and 21 zeros which when multiplied with 125 gives 125 followed by 21 zeros
So, in total, 24 digits
Correct Option: B
Question: Tickets numbered from 1 to 21 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3?
A.1/3
B.2/5
C.3/10
D.3/7
Answer: A.1/3
Explanation: Here, S = [1, 2, 3, 4, …., 19, 20, 21]
Let E = event of getting a multiple of 3 = [3, 6, 9, 12, 15, 18, 21]
P (E) = n (E) / n (S) = 7 / 21 = 1/3
The answer is A.
Question: The average of 11numbers is 60. Out of 11numbers the average of first 6no. is 78, and last 6numbers is 75 then find 6th number?
A.A)258
B.B)65
C.C)58
D.D)62
Answer: A.A)258
Explanation: 6th number = sum of 1st 6no.s + sum of last 6no.s - sum of 11no.s
answer = 6*78+6*75-11*60 = 258
Answer is A
Question: A, B and C invests Rs.4000, Rs.3000 and Rs.2000 in a business. After one year B removed his money; A and C continued the business for one more year. If the net profit after 2 years be Rs.2400, then B's share in the profit is?
A.276
B.289
C.480
D.400
Answer: C.480
Explanation: 4*24 : 3*12 : 2*24
8: 3: 4
3/15 * 2400 =480
Answer: C
Question: Which of the following numbers is the biggest => [-5/7 , -7/8 , -9/10 , -12/13 , -34/35]
A.A)-5/7
B.B)-7/8
C.C)-9/10
D.D)-12/13
Answer: A.A)-5/7
Explanation: If we observe all the fractions just differ by one i.e denominator vs numerate.. in such case the biggest will be with large values... here all values are with -ve value...the least value is biggest. i.e. -5/7..
Hence A is correct answer...
Question: What is the difference between 38% of 80 nd 12% of 160.
A.11.3
B.12.4
C.12.7
D.11.2
Answer: D.11.2
Explanation: (38/100) * 80 â€“ (12/100) * 160
30.4 - 19.2 = 11.2
Answer: D
Question: What is the minimum value of |x-4| + |x+8| + |x-5| ?
A.-13
B.13
C.5
D.7
Answer: B.13
Explanation: A cannot be the answer as all the three terms are in modulus and hence the answer will be non negative.
|x-4| >= 0 --> Minimum occurs at x = 4
|x+8| >= 0 --> Minimum occurs at x = -8
|x-5| >= 0 --> Minimum occurs at x = 5
x = -8 --> Result = 12 + 0 + 13 = 25. Also any negative value will push the combined value of |x-4| + |x-5| to a value > 9.
x = 4 --> Result = 0 + 12 + 1 = 13
x = 5 --> Result = 1 + 13 + 0 = 14
x = 8 --> Result = 4 + 16 + 3 = 23
So minimum value of the expression occurs at x = 4 and the resultant value = 13
Answer: B
Question: Linda bought 3 notebooks at $1.20 each; a box of pencils at $1.50 and a box of pens at $1.70. How much did Linda spend?
A.$6.80
B.$2.80
C.$4.80
D.$7.80
Answer: A.$6.80
Explanation: Linda spent
1.20 ? 3 = $3.60 on notebooks
The total amount of money that Linda spent is equal to
3.60 + 1.50 + 1.70 = $6.80
correct answer A
Question: If x is an odd negative integer and y is an even integer, which of the following statements must be true? I. (3x + 2y) is positive integer II. (xy)^2 is positive integer III. (y^2 - x) is even integer
A.I only
B.III only
C.II only
D.I,III only
Answer: C.II only
Explanation: I. It is true if 3x < 2y
II. It is always positive
III. It is not always true
Answer : C
Question: Pary,INC recently conducted a survey and found that 75,000 of its customers live in rural areas. if the number of it customers who live in urban areas is 200 percents grater than the numbers of customers who live in rural areas, how many of Pary,INC customers live in urban areas ?
A.200,000
B.216,000
C.225,000
D.480,000
Answer: C.225,000
Explanation: Let's say that we have a starting value of X...
100% of X = X
100% MORE than X = X + X = 2X
200% MORE than X = X + 2X = 3X
300% MORE than X = X + 3X = 4X
Etc.
Here, we're told that 75,000 customers live in rural areas and the number who live in urban areas is 200% GREATER than the number who live in rural areas. That means that the number who are in urban areas is 3 times the number in rural areas...
3(75,000) = 225,000
Final Answer:C
Question: A sum of Rs. 427 is to be divided among A, B and C in such a way that 3 times A’s share, 4 times B’s share and 7 times C’s share are all equal. The share of C is
A.82
B.83
C.84
D.85
Answer: C.84
Explanation: A + B + C = 427
3A = 4B = 7C
=> (7C/3) + (7C/4) + C = 427
=> C = 84
ANSWER:C
Question: A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by:
A.3
B.5
C.9
D.11
Answer: D.11
Explanation: Explanation:
Let the ten's digit be x and unit's digit be y.
Then, number 10x + y.
Number obtained by interchanging the digits = 10y + x.
(10x + y) + (10y + x) = 11(x + y)
which is divisible by 11.
ANSWER IS D
Question: What amount does Kiran get if he invests Rs. 18000 at 15% p.a. simple interest for four years?
A.29893
B.27773
C.29989
D.28800
Answer: D.28800
Explanation: Simple interest = (18000 * 4 * 15)/100 = Rs. 10800
Amount = P + I = 18000 + 10800 = Rs. 28800
Answer: D
Question: How many positive integers less than 100 are there such that they are multiples of 8 or multiples of 7 but not both?
A.21
B.22
C.25
D.24
Answer: D.24
Explanation: for 8: 8...100=8*12
for 7: 7...98=7*14
but there is one integer 8*7. so
N=(12-1)+(14-1)=24
D
Question: There are 11 dozen mangoes in a box. If there are 39
such boxes, how many mangoes are there in all the
boxes together?
A.516
B.5148
C.6192
D.628
Answer: B.5148
Explanation: Number of mangoes = 11 dozens
= 12 × 11 = 132
∴ Number of mangoes in 39 boxes
= 39 × 132 = 5148
Answer B
Question: In an examination 35% of the students passed and 455 failed. How many students appeared for the examination?
A.540
B.400
C.700
D.650
Answer: C.700
Explanation: Let the number of students appeared be x
then, 65% of x = 455
65x/100 = 455
x = 455*100/65 = 700
Answer is C
Question: If cement, gravel and sand are to be mixed in 7:10:13 and 5 tons of cement is available how many tons of mixture can be produced assuming that sufficient gravel and sand is readily available.
A.35 7/8
B.36
C.21 3/7
D.34 5/7
Answer: C.21 3/7
Explanation: Cement:Gravel:Sand = 7:10:13 --> total of 7+10+13 = 30 parts.
If we use 8 tons of cement, then we'll get 5/7*30 = 21 3/7 tons of mixture.
Answer: C.
Question: A person crosses a 1000 m long street in 10 minutes. What is his speed in km per hour?
A.7.1
B.8.2
C.4.6
D.6.0
Answer: D.6.0
Explanation: distance = 1000 meter
time = 10 minutes = 10 x 60 seconds = 600 seconds
Speed = distance/time=1000/600=1.67m/s=1.67Ã—18/5 km/hr=6.0 km/hr
Answer :D
Question: If f(y)=y^2 and y is a positive integer, which of the following CANNOT be the value of f(f(y))?
A.1
B.144
C.81
D.16
Answer: B.144
Explanation: f(y)=y^2
f(f(y)) = (y^2)^2
=y^4
A. 1 , y=1
D. 16 , y=2
C. 81 , y=3
B. 144
f(y)=12
Square root of 12 is not a positive integer . Hence 144 can not be the value of f(f(y)) .
E. 256 , y=4
Answer B
Question: The sum of two numbers is twice their difference. If one of the numbers is 10, the other number is
A.3 1/3
B.30
C.−3 1/3
D.a or b
Answer: D.a or b
Explanation: Explanation:
Let the other number be a.
Given that, 10+a=2(a−10)⇒a=30
or if the other number is less than 10, 10+a=2(10−a)⇒a=10/3=3 1/3
Correct Option: D
Question: If the positive integer x is a multiple of 9/15 and the positive integer y is a multiple of 5/3, then xy must be a multiple of which of the following?
I. 5
II. 3
III. 1
A.II only
B.I and II only
C.I only
D.III only
Answer: D.III only
Explanation: x=9/15a
y=5/3b
xy=3/3ab=ab
where a,b are integers
Hence , xy will always be divisible by 1.
D is the answer.
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 500 m long?
A.176 Sec
B.190 Sec
C.170 Sec
D.267 Sec
Answer: C.170 Sec
Explanation: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 1700 m
T = D/S
T = 1700/10
T = 170 Sec
Answer:C
Question: A scale 7 ft. 6 inches long is divided into 5 equal parts. Find the length of each part.
A.20 inches
B.77 inches
C.66 inches
D.18 inches
Answer: D.18 inches
Explanation: Explanation:
Total length of scale in inches = (7*12) + 6 = 90 inches
Length of each of the 5 parts = 90/5 = 18 inches
ANSWER:D
Question: A man goes from A to B at a speed of 20 kmph and comes back to A at a speed of 30 kmph. Find his average speed for the entire journey?
A.17 kmph
B.24 kmph
C.16 kmph
D.19 kmph
Answer: B.24 kmph
Explanation: Distance from A and B be 'd'
Average Speed = total distance/total time
Average Speed = (2d)/[(d/20) + (d/30)]
= (2d)/[5d/60) => 24 kmph.
Answer:B
Question: If 8^x = 2^15, what is x?
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: 2^3x= 2^15
3x=15, therefore x=5
Answer D
Question: The ratio of money with Ram and Gopal is 7 : 17 and that with Gopal and Krishan is 7: 17. If Ram has Rs. 588, Krishan has ?
A.s. 2890
B.s. 2330
C.s. 1190
D.s. 3468
Answer: D.s. 3468
Explanation: Ram : Gopal = 7 : 17 = 49 : 119
Gopal : Krishan = 7 : 17 = 119 : 289
Ram : Gopal : Krishan = 49 : 119 : 289
Ram : Krishan = 49 : 289
Thus, 49 : 289 = 588 : N
&there N = 289 x 588 / 49
= Rs. 3468
Answer :D
Question: A waiter's salary consists of his salary and tips. During one week his tips were 9/4 of his salary. What fraction of his income came from tips ?
A.4/9
B.5/4
C.9/13
D.5/9
Answer: C.9/13
Explanation: Income = salary (s) +tips = s + s*9/4 = s*13/4
Tips = s*9/4
fraction of his income came from tips = (s*9/4)/(s*13/4)= 9/13
ANSWER:C
Question: A trumpet section includes seven musicians. If they hold an audition to determine chair order within the section, and there are to be no ties, how many distinct chair orders can result?
A.240
B.125
C.5040
D.100
Answer: C.5040
Explanation: We have a word problem using permutations. We must identify the number of total items in the group. There are seven possible musicians who could be placed in the first chair, six possible musicians for the second, five for the third, four for the fourth, and three for the fifth, and two for the sixth and one for the seventh. To determine the number of possible orderings, we multiply these numbers, which we can express as 7!. Now 7! = (7)(6)(5)(4)(3)(2)(1) = 5040=C
Question: Which of the following numbers is two more than the square of an odd integer?
A.14,115
B.14,163
C.14,577
D.14,737
Answer: B.14,163
Explanation: If a square has an odd unit's digit, then its ten's digit must be even.
Only 14,163-2 = 14,161 satisfies this condition.
The answer is B.
Question: A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 600 m long?
A.80sec
B.84sec
C.90sec
D.94sec
Answer: B.84sec
Explanation: Speed = 240/24 = 10 m/sec.
Required time = (240 + 600)/10 = 84 sec.
Answer:B
Question: A certain company consists of 3 managers and 8 non-managers. How many different teams of 3 employees can be formed in which at least one member of the team is a manager and at least one member of the team is not a manager? (Two groups are considered different if at least one group member is different)
A.84
B.108
C.135
D.270
Answer: B.108
Explanation: Total # of teams of 3 possible is C311=165
# of teams with only managers or only non-managers is: C33+C38=1+56=57;
# of teams of 3 with at least one manager or at least one non-manager is: 165-57=108.
ANSWER:B
Question: A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
A.33
B.38
C.87
D.cannot be determined
Answer: D.cannot be determined
Explanation: Explanation:
We need to know the S.I, principal and time to find the rate. Since the principal is not given, so data is inadequate.
Answer: D)
Question: The bankerâ€™s discount on Rs. 1600 at 6% per annum is the same as true discount on Rs. 1680 for the same time and at the same rate. The time is :
A.2 months
B.4 months
C.6 months
D.10 months
Answer: D.10 months
Explanation: Sol.
S.I. on Rs. 1600 = R.D. on Rs. 1680.
âˆ´ Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is S.I. on Rs. 1600 at 6%.
âˆ´ Time = [100 * 80 / 1600 * 6] year = 5/6 year = 10 months.
Answer D
Question: One vessel contains a mixture of 5 parts pure wine and 3 parts soda, whereas the other vessel contains a mixture of 9 parts pure wine and 5 parts soda. Compare the strength of the wine.
A.35;36
B.7 : 8
C.7 : 4
D.14 : 5
Answer: A.35;36
Explanation: 5/8 : 9/14
LCM of 8,14 = 56
(5/8)*56 : (9/14)*56
35:36
Answer is A
Question: Currently, y percent of the members on the finance committee are women and next month, z percent of the men on the finance committee will resign. If no other personnel changes occur, then after the resignations next month, the men who remain on the finance committee will represent what percent of the total finance committee members?
A.(100)(100 - z)(100 - y)/(100^2 - z(100 - y))
B.(100 - z)(100 - y)/100
C.(100 - z)(100 - y)
D.zy/100 - z
Answer: A.(100)(100 - z)(100 - y)/(100^2 - z(100 - y))
Explanation: Let's say that there are a total of 100 members
Let's also say that y = 50
So there are 50 men
Now z = 10 so 45 men are left
(45/95)*100 = 9/19 *100 = 900/19
Now let's plug answer choices
Target 900/19
Inputs
y=50
z=10
Only A gives the correct answer
Question: A wooden box of dimensions 8 m x 7 m x 6 m is to carry rectangularboxes of dimensions 2 cm x 7 cm x 3 cm. The maximum number ofboxes that can be carried in the wooden box, is
A.8000000
B.1000000
C.7500000
D.1200000
Answer: A.8000000
Explanation: Explanation: Number = (800*700*600)/2*7*3 = 8000000 Answer: A
Question: Bruce purchased 8kg of grapes at the rate of 70 per kg and 11 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper?
A.A)1040
B.B)1165
C.C)1055
D.D)1065
Answer: B.B)1165
Explanation: Cost of 8 kg grapes = 70 × 8 = 560.
Cost of 11 kg of mangoes = 55 × 11 = 605.
Total cost he has to pay = 560 + 605 = 1165
B
Question: As a treat for her two crying children, a mother runs to the freezer in which she has two cherry ice pops, three orange ice pops, and five lemon-lime ice pops. If she chooses two at random to bring outside to the children, but realizes as she runs out the door that she cannot bring them different flavors without one invariably being jealous of the other and getting even more upset, what is the probability that she has to return to the freezer to make sure that they each receive the same flavor?
A.1/9
B.1/6
C.5/18
D.31/360
Answer: D.31/360
Explanation: Probability of not getting the same flavor ->
Favorable -> Cherry - orange [ 2C1 * 3C1 [or simply 2*3 ] or Cherry - lemon [ 2*5] or orange - lemon [3*5]
Prob = (2*3 + 2*5 + 3*5 ) / 9C2 = 31/360
Answer -> D
Question: Find the number of subsets of the set {1,2,3,4,5,6,7,8,9,10,11} having 4 elements.?
A.1320
B.660
C.165
D.330
Answer: D.330
Explanation: Explanation :
Here the order of choosing the elements doesn’t matter and this is a problem in combinations.We have to find the number of ways of choosing 4 elements of this set which has 11 elements.This can be done in:11C4=11*10*9*81*2*3*4= 330 ways
Answer : D
Question: In the rectangular coordinate system Point O has coordinates (0,0) and Point B has coordinates (3,3) and if point A is equidistant from points O and B and the area of the triangle OAB is 16, which of the following are the possible coordinates of point A.
A.(-2,6)
B.(0,4)
C.(2,-6)
D.(2,6)
Answer: D.(2,6)
Explanation: Area.pngSince A is equidistant from points O and B, then it must be somewhere on the green line (perpendicular bisector of OB).
(2,-6) and (2,6) are not on that line. If A is at (0,3) or (3,0), then the area is 1/2*3*3=9/2. Thus A must be at (2,6).
Answer: D.
Question: In 1990 the budgets for projects Q and V were $660,000 and $860,000, respectively. In each of the next 10 years, the budget for Q was increased by $30,000 and the budget for V was decreased by $10,000. In which year was the budget for Q equal to the budget for V ?
A. 1992
B. 1993
C. 1994
D. 1995
Answer: D. 1995
Explanation: Let the no of years it takes is x.
660+30x = 860-10x --> 40x = 200 and x=5.
Thus, it happens in 1995.
D.
Question: The sum of one-half, one-third and one-fourth of a number exceeds the number by 12. The number is
A.144
B.154
C.90
D.174
Answer: A.144
Explanation: x/2+x/3+x/4=x+12
13x/12=x+12
x=144
ANSWER:A
Question: 12 spheres of the same size are made from melting a solid cylinder of 8 cm diameter and 27 cm height. What is the diameter of each sphere?
A.2 cm
B.4 cm
C.6 cm
D.8 cm
Answer: C.6 cm
Explanation: Volume of cylinder = pi*r^2*h
Volume of a sphere = 4*pi*R^3 / 3
12*4*pi*R^3 / 3 = pi*r^2*h
R^3 = r^2*h / 16 = 27 cm^3
R = 3 cm
D = 6 cm
The answer is C.
Question: If x*y = xy – 2(x + y) for all integers x and y, then 5* (–3) =
A.–19
B.–11
C.–4
D.4
Answer: A.–19
Explanation: 5*(-3) = 5*(-3) - 2 (5 + (-3) ) = -15 -4 = -19
Option (A)
Question: How many numbers from 10 to 100 are exactly divisible by 9?
A.9
B.10
C.11
D.12
Answer: B.10
Explanation: 10/9 = 1 and 100/9 = 11 ==> 11 - 1 = 10. Therefore 10 digits
B)
Question: If sum of the first 11 terms of arithmetic progression equals that of the first 19 terms, then what is the sum of the first 30 terms?
A.0
B.-1
C.1
D.Not unique
Answer: A.0
Explanation: Explanation :
Given,
t1 + t2 + ........t11 = t1 + t2 + ........t19 (for an AP)
=> (11/2) [ 2a + (11-1)d = (19/2) [ 2a + (19-1)d ]
=> 22 a + 110d = 28 a + 342 d
=> 16 a + 232 d = 0
=> 2a + 29 d = 0
=> (30/2)[ 2a + (30-1)d = 0.
S30 terms = 0.
Answer : A
Question: There are two sections B and C of a class, consisting of 46 and 54 students respectively. If the average weight of sections B is 50 kg and that of sections C is 45 kg. Find the average weight of the whole class
A.47.3
B.48.3
C.49.3
D.50.3
Answer: A.47.3
Explanation: Solution
Total weight of(46+54)Students	= (46x50+54x45)Kg
= 4730 kg.
Average weight of the whole class	= (4730 / 100)
= 47.30.
Answer A
Question: If 8000 books need to be placed in boxes and each box can contain at most 9 books. How many books will be in the last unfilled box?
A.8 books
B.9 books
C.1 book
D.5 books
Answer: A.8 books
Explanation: The number of books that can be placed in boxes of 9 books is the first number that is divisible by 9 that occurs before 8000.
In order to divide the sum in 9 parts, the amount must be divisible by 9
Divisibility rule of 9: The sum of the digits must be divisible by 9
Sum of digits of 8000 = 8 and 0 is divisible by 9.
Hence, we need to remove 8 to this number for it to be divisible by 9
Correct Option:A
Question: There are 193 items that are members of set U. Of these items, 41 are members of set B, 59 are not members of either of set A or set B, and 23 are members of both sets A and B. How many of the members of set U are members of set A ?
A.116
B.85
C.94
D.98
Answer: A.116
Explanation: You had the answer almost right. The x = 93 refers to ONLY set A.
However what's being asked is how many members are part of set A. This will include:
1. Only Set A
2. Set A and Set B
So the answer is Set A = 93 + Set AB = 93+23 = 116
A
Question: Sand is poured into a box so that the box is being filled at the rate of 4 cubic feet per hour. If the empty rectangular box is 7 feet long, 6 feet wide, and 2 feet deep, approximately how many hours does it take to fill the box?
A.20
B.21
C.22
D.23
Answer: B.21
Explanation: The volume the box is: length*width*depth = 7*6*2= 84 cubic feet.
84 cubic feet / 4 cubic feet per hour = 21 hours.
It will take 21 hours to fill the box.
The answer is B.
Question: While working alone at their respective constant rates, server M uploads 480 files in 4 hours and server Y uploads 480 files in 8 hours. If all files uploaded by these servers are the same size, how long would it take the two servers, working at the same time and at their respective constant rates, to process a total of 480 files?
A. 2 hr
B. 2hr 20 min
C. 2hr 40 min
D. 5 hr 40 min
Answer: C. 2hr 40 min
Explanation: Server M processes 480/4 files per hour = 120 per hour
Server Y processes 180/8 files per hour = 60 per hour
Total files processed per hour when M and Y work together = 120+60 per hour = 180 files per hour
480/180 = 2 2/3 hours=C