RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: in 10 year, A willbe twice as old as B was 10 year ago. if A is now 9 year older then B, the present age of B is
A.19 years
B.29 years
C.39 years
D.49 years
Answer: C.39 years
Explanation: Solution
Let B's present age = x years. then, A's present age = ( x + 9 ) years.
∴ (x + 9) + 10 = 2 (x - 10) ⇔ x + 19 = 2 x - 20 ⇔ x = 39. Answer C
Question: 20% of a number is added to 120, the result is the same number. Find the number?
A.150
B.288
C.1687
D.997
Answer: A.150
Explanation: (20/100) * X + 120 = X
2X = 300
X = 150
Answer:A
Question: What is the number of integers from 1 to 900 (inclusive) that are divisible by neither 11 nor by 35?
A.884
B.890
C.892
D.910
Answer: C.892
Explanation: Normally, I would use the method used by Bunuel. It's the most accurate. But if you are looking for a speedy solution, you can use another method which will sometimes give you an estimate. Looking at the options (most of them are spread out), I wont mind trying it. (Mind you, the method is accurate here since the numbers start from 1.)
In 1000 consecutive numbers, number of multiples of 11 = 1000/11 = 90 (Ignore decimals)
In 1000 consecutive numbers, number of multiples of 35 = 1000/35 = 28
Number of multiples of 11*35 i.e. 385 = 1000/385 = 2
Number of integers from 1 to 1000 that are divisible by neither 11 nor by 35 = 1000 - (90 + 28 - 2) {Using the concept of sets here) = 892
Think: Why did I say the method is approximate in some cases?
Think what happens if the given range is 11 to 1010 both inclusive (again 1000 numbers)
What is the number of multiples in this case?
C
Question: Shreyas bought an article and sold it for 140% of its cost price. What was the cost price of the article, if Shreyas sold it for Rs.29750/-?
A.Rs.24600
B.Rs.21250
C.Rs.24250
D.Rs.23200
Answer: B.Rs.21250
Explanation: Explanation:
140% of CP = Rs.29750
:. CP = Rs.29750x100/140 = Rs.21250.
Answer: Option B
Question: The sum of the present ages of A, B, C is 51 years. Three years ago their ages were in the ratio 1:2:3. What is the present age of A?
A.7
B.8
C.9
D.10
Answer: D.10
Explanation: Three years ago:
a:b:c = 1:2:3
Let a = 1x, b = 2x, and c = 3x.
Today:
(x+3) + (2x+3) + (3x+3) = 51
x = 7
So the present age of A is x+3 = 10
The answer is D.
Question: Insert the missing number
9, 12, 11, 14, 13, ..., 15
A.12
B.16
C.10
D.17
Answer: B.16
Explanation: The sequence is consider into two series..
First series(odd) starting with 9 and increasing 2 as follows.
Second series(even) starting with 12 and increasing with 2 as follows.
i.e. 9 = 9 (odd)
12 = 12(even)
9 + 2 = 11(odd series)
12 + 2 = 14(even series)
11 + 2 = 13(odd series)
14 + 2 = 16(even series)
ANSWER:B
Question: what is the unit digit in (4137)^754?
A.1
B.3
C.7
D.9
Answer: D.9
Explanation: Unit digit in (4137)^754=Unit digit in [(4137)^4]^188 x (4137)^2 = (1x9)=9
Answer is D
Question: A dog breeder currently has 9 breeding dogs. 6 of the dogs have exactly 1 littermate, and 3 of the dogs have exactly 2 littermates. If 2 dogs are selected at random, what is the probability W that both selected dogs are NOT littermates?
A.1/6
B.2/9
C.5/6
D.7/9
Answer: C.5/6
Explanation: We have three pairs of dogs for the 6 with exactly one littermate, and one triplet, with each having exactly two littermates.
So, in fact there are two types of dogs: those with one littermate - say A, and the others with two littermates - B.
Work with probabilities:
Choosing two dogs, we can have either one dog of type B or none (we cannot have two dogs both of type B).
The probability of choosing one dog of type B and one of type A is 3/9 * 6/8 * 2 = 1/2 (the factor of 2 for the two possibilities BA and AB).
The probability of choosing two dogs of type A which are not littermates is 6/9 * 4/8 = 1/3 (choose one A, then another A which isn't the previous one's littermate).
The required probability is 1/2 + 1/3 = 5/6.
Find the probability for the complementary event: choose AA or BB.
Probability of choosing two dogs of type A who are littermates is 6/9 * 1/8 = 1/12.
Probability of choosing two dogs of type B (who necessarily are littermates) is 3/9 * 2/8 = 1/12.
Again, we obtain 1 - (1/12 + 1/12) W= 5/6.
Answer: C
Question: Find the value of x: x² − 3x + 2
A.-1
B.1
C.2
D.3
Answer: C.2
Explanation: (x − 1)(x − 2)
x = 1 or 2.
C
Question: A train 1200 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
A.2898
B.277
C.500
D.100
Answer: D.100
Explanation: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (1200 + x)/60 = 65/3
x = 100 m.
Answer: D
Question: If 1 pound of dried apricots that cost x dollars per pound are mixed with 2 pounds of prunes that cost y dollars per pound, what is the cost, in dollars, per pound of the mixture?
A.(x + 2y)/5
B.(x + 2y)/(x + y)
C.(x + 2y)/(xy)
D.5(x + 2y)
Answer: A.(x + 2y)/5
Explanation: Total Cost = Weight(in pounds) * Price/pound;
To find Total cost/pound, Divide by total pounds.
Cost of Dried apricots = x;
Cost of prunes = 2y;
Cost per pound = (x + 2y)/5;
Ans is (A).
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.75 km and 1.25 km respectively. The time taken by the slower train to cross the faster train in seconds is?
A.12
B.72
C.48
D.99
Answer: B.72
Explanation: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.75 + 1.25 = 3 km = 3000 m.
Required time = 3000 * 3/125 = 72 sec.
Answer: B
Question: Every digit of a number written in binary is either 0 or 1. To translate a number from binary, multiply the nth digit (reading from right to left) by 2^(n-1)
What is the largest prime number (written in binary) that is a factor of both 1010000 and 10100000 ?
A. 10
B. 11
C. 101
D. 1011
Answer: C. 101
Explanation: Binary Divison can provide a quick answer if you are comfortable with it.
as option E is the biggest binary number we try with it first :
100010000/ 101 =10000
1000100000/ 101 =100000
so answer is option is C
Question: An optometrist charges $150 per pair for soft contact lenses and $85 per pair for hard contact lenses. Last week she sold 5 more pairs of soft lenses than hard lenses. If her total sales for pairs of contact lenses last week were $2,160, what was the total number of pairs of contact lenses that she sold?
A. 11
B. 13
C. 15
D. 17
Answer: D. 17
Explanation: (x+5)*150 +x*85=2160
=>x=6
total lens=6+(6+5)= 17
Answer D
Question: One pump drains one-half of a pond in 2 hours, and then a second pump starts draining the pond. The two pumps working together finish emptying the pond in one-half hour. How long would it take the second pump to drain the pond if it had to do the job alone?
A.1.3 hour
B.1.2 hour
C.3 hours
D.5 hours
Answer: A.1.3 hour
Explanation: The tricky part here, I believed is one half hour = 1/2. Then everything would be easy.
We have the 1st pump working rate/hour = 1/2 : 2 = 1/4
Working rate of 2 pumps: 1/2 : 1/2 = 1.
Working rate of 2nd pump: 1 -1/4 = 3/4 --> Time taken for the 2nd pump to finish: 1 : 3/4 = 4/3 = 1.3 hours.
A
Question: Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 14 inches on a side and costs $10, and a large pizza that measures 21 inches on a side and costs $20. If two friends go to Huey's with $30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?
A.5 square inches
B.10 square inches
C.49 square inches
D.25 square inches
Answer: C.49 square inches
Explanation: In the first case each can buy one pizza of $10 and one pizza of $20.
In square inches that would be (14*14=196) for the small pizza and (21*21=441) for the large pizza. In total sq inches that would be (196+441)*2= 1274 sq inches.
In the second case if they pool their money together they can buy 3 large pizzas. In terms of square inches that would be 3*441= 1323 sq inches.
Hence, the difference is 49 square inches more (1323-1274).
The correct answer is C
Question: Find a sum for 1st 7 prime number's?
A.25
B.28
C.58
D.34
Answer: C.58
Explanation: Required sum = (2 + 3 + 5 + 7 + 11 + 13 + 17) = 58
Note: 1 is not a prime number
Option C
Question: If x is a positive number and 2 the square root of x is equal to x/2, then x =
A.1/16
B.4
C.1
D.2
Answer: C.1
Explanation: 2 of sqrt(x) = x/2, which means that sqrt(x) = x
or x = x^2 -> divide by x
1= x
x=1
C.
Question: There are two circles of different radii. The are of a square is 784 sq cm and its side is twice the radius of the larger circle. The radius of the larger circle is seven - third that of the smaller circle. Find the circumference of the smaller circle?
A.18
B.16
C.12
D.10
Answer: C.12
Explanation: :
Let the radii of the larger and the smaller circles be l cm and s cm respectively. Let the side of the square be a cm.
a2 = 784 = (4)(196) = (22).(142)
a = (2)(14) = 28
a = 2l, l = a/2 = 14
l = (7/3)s
Therefore s = (3/7)(l) = 6 Circumference of the smaller circle = 2∏s = 12∏ cm.
Answer: C
Question: If p is not equal to zero, and p+1/p = 5, then what is the value of p^4 + (1/p)^4?
A.527
B.247
C.547
D.527
Answer: D.527
Explanation: p + 1/p=5
we square both sides so we have p^2 + 1/p^2 +2 = 25
or p^2 + 1/p^2= 23
squaring again we have p^4 + 1/p^4 + 2 = 529
or p^4 + 1/p^4 = 527
answer =527 (D)
Question: Doug bought bananas on sale for 5% off the original price and another 10% off the discounted price. If the final price was $5, what was the price before the first discount?
A.$5.15
B.$5.35
C.$5.85
D.$6.14
Answer: C.$5.85
Explanation: let x be the price before the first discount. The price after the first discount is x - 5%x The second discount was 10%, after which the final price was $5 (x - 5%x) - 10%(x - 5%x) = 5 Solve for x x = $5.85correct answer C
Question: Sequence W consists of 16 consecutive integers. If -6 is the least integer in sequence W, what is the range of the positive integers in sequence W?
A. 16
B. 15
C. 9
D. 8
Answer: D. 8
Explanation: Since set W consists of 16 consecutive integers and -6 is the least integer then set W is consecutive integers from -6 to 9, inclusive: 9-(-6)+1=16.
The range of positive integers in sequence W is 9-1=8.
Answer: D.
Question: A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 6km?
A.3
B.4
C.5
D.8
Answer: A.3
Explanation: M = 4
S = 2
US = 4 - 2 = 2
D = 6
T = 6/2 = 3
Answer: A
Question: Three cards are randomly selected, one at a time (without return), from a standard deck of 52 cards. What is the probability that the last two of the three cards are spades? (Answer in lowest terms).
A.18/750
B.19/750
C.18/850
D.39/850
Answer: D.39/850
Explanation: A standard deck has 52 cards of which 13/52 are spades, so the probability of not getting a spade is P(NS) = (52-13)/4 on the first selected card.
Because selection is (without return), the P(S) has changed for following selections. Now, there are 51 cards and number spades is dependent upon whether first card was a spade, or not... and so on.... Therefore, conditional probability! The probability that event B occurs, given that event A has already occurred is:
Formula = P(A\B) = P(A and B)/P(B).
P(A\B) = (39/52)(13/51)(12/50) = 6084/132600 = 39/850
Answer: D
Question: A pineapple costs Rs 7 each and a watermelon costs Rs. 5 each. If I spend Rs 38 on total what is the number of pineapple I purchased?
A.7
B.6
C.5
D.2 pineapples
Answer: D.2 pineapples
Explanation: Explanation:
The equation for this problem can be made as:
5x + 7y =38
Where x is the number of watermelons and y is the number of pineapples.
Now test for 2, 3 and 4:
For y = 2
5x + 14 =38
x is not an integer
For y = 3
5x = 17
X not an integer
For y =4
X = 2
So 4 pineapples and 2 watermelons can be bought by 38 Rs.
ANSWER:D
Question: If the set S is composed of the following numbers {99, 100, 100, 105, 106, 115, 124}, which of the following is largest?
A.The average (arithmetic mean) of set S
B.The median of set S
C.The mode of set S
D.The range of set S
Answer: A.The average (arithmetic mean) of set S
Explanation: A) 99, 100, 100, 105, 106, 115, 124 = 749 and its mean is 749/7 = 107.
B) The list is of 7 numbers and median is 105.
C) Mode is number of repetition of a number in the list , here it is 100.
D) Range = Max value - min value = 124 -99 = 25.
E) SD = square root of (sum of ( mean of series - number)^2 ) / n => < 100
IMO option A is correct answer..
Question: If f(x)= 2x^2- 3x+5 and g(y)= 2y-4, then g(f(x))
A.7x^2+45x+9
B.9x^2-15x+4
C.4x^2-6x+6
D.8x^2-9x+6
Answer: C.4x^2-6x+6
Explanation: g(f(x)) = 2(f(x)) -4
=2(2x^2-3x+5)-4
=4x^2-6x+10-4
=4x^2-6x+6
the answer is C
Question: Jack and Dick work at a hospital with 4 other workers. For an internal review, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that Jack and Dick will both be chosen?
A.A)1/3
B.B)1/4
C.C)1/15
D.D)3/8
Answer: C.C)1/15
Explanation: Total number of people = 6
Probability of selecting Jack first and then Dick is 1/6∗1/5=1/30
Probability of selecting Dick first and then Jack is 1/6∗1/5=1/30
Therefore probability of selecting Jack and Dick for the review is 1/30+1/30=1/15
Answer is C
Question: Sripad has scored average of 60 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ?
A.79
B.64
C.38
D.27
Answer: B.64
Explanation: Assuming Sripad has scored the least marks in subject other than science,
Then the marks he could secure in other two are 58 each.
Since the average mark of all the 3 subject is 60.
i.e (58+58+x)/3 = 60
116 + x = 180
x = 64 marks.
Therefore, the maximum marks he can score in maths is 64.
Answer: B
Question: (a/2)/(b/c)
In the expression above, a, b, and c are different numbers and each is one of the numbers 1, 2, or 4. What is the largest possible value of the expression?
A.8/2
B.2/4
C.1/8
D.2/4
Answer: A.8/2
Explanation: (a/2)/(b/c)
= (a*c)/2b
The expression will have the largest value when numerator (a*c) is the largest.
= (2*4)/2*1
=8/2
Answer A
Question: Find the unit's digit in (264)^102 + (264)^103
A.0
B.2
C.5
D.3
Answer: A.0
Explanation: Required unit's digit = unit's digit in (4)^102 + (4)^103.
Now, 4^2 gives unit digit 6.
(4)102 gives unjt digit 6.
(4)103 gives unit digit of the product (6 x 4) i.e., 4.
Hence, unit's digit in (264)m + (264)103 = unit's digit in (6 + 4) = 0.
Answer is A
Question: How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 40 m long and 16 1/2 m board?
A.99
B.132
C.16
D.10
Answer: B.132
Explanation: 40 * 33/2 = 5/2 * 2 * x => x
= 132
Answer:B
Question: Last year a certain bond yielded 5 percent of its face value in interest. If that interest was approximately 4 percent of the bonds selling price of $8,500, what is the bonds face value?
A. $6,000
B. $6,800
C. $7,425
D. $7,500
Answer: B. $6,800
Explanation: Interest = 0.05*face value = 0.04*8,500 --> face value = 0.04*8,500/0.05 = 6,800.
Answer: B.
Question: What will be the compound interest earned on an amount of Rs. 5000 in 2 years?
I.	The simple interest on the same amount at the same rate of interest in 5 years is Rs. 2000.
II.	The compound interest and the simple interest earned in one year is the same.
III.	The amount becomed more than double on compound interest in 10 years.
A.I only
B.I and II only
C.II and III only
D.I and III only
Answer: A.I only
Explanation: EXPLANATION
P = Rs. 5000 & T = 2 years.
I. S.I. on Rs. 5000 in 5 years is Rs. 2000.
5000 x R x 5/ 100 = 2000 = R = 8
Thus I only gives the answer.
answer is (A).
Question: A polling company reports that there is a 20% chance that a certain candidate will win the next election. If the candidate wins, there is a 60% chance that she will sign Bill X and no other bills. If she decides not to sign Bill X, she will sign either Bill Y or Bill Z, chosen randomly. What is the chance that the candidate will sign Bill Z?
A.10
B.8
C.6
D.4
Answer: D.4
Explanation: 20% - Candidate Elected
100%-60% = 40% - Candidate doesnotsigh Bill X
50% - Candidate randomly chooses between two bills.
These are multiplicative:
20% x 40% x 50%
0.2 x 0.4 x 0.5 = 0.04 = 4%
Answer (D)
Question: Two pipes A and B can fill a cistern in 22 and 44 minutes respectively, and a third pipe C can empty it in 48 minutes. How long will it take to fill the cistern if all the three are opened at the same time?
A.18 1/9 min
B.21 1/8 min
C.21 3/25 min
D.18 8/7 min
Answer: C.21 3/25 min
Explanation: 1/22 + 1/44 - 1/48
=25/528
528/25 = 21 3/25
Answer:C
Question: How many positive integers will divide evenly into 230?
A.4
B.6
C.8
D.12
Answer: C.8
Explanation: The question is asking how many factors 230 has.
230 = 2*5*23
The number of factors is 2^3 = 8
The answer is C.
Question: If $0.40 is the commission for sales of $1,000, what percent of the sales amount is the commission?
A.4%
B.0.4%
C.0.04%
D.0.004%
Answer: C.0.04%
Explanation: % of sales amount of commission
= (Commission/Total Value) *100
= (0.4/1000) * 100
= 0.04%
The answer is C.
Question: A reduction of 20% in the price of salt enables a lady to obtain 10kgs more for Rs.100, find the original price per kg?
A.2.6
B.2.0
C.2.5
D.2.1
Answer: C.2.5
Explanation: 100*(20/100) = 20 --- 10
? --- 1 => Rs.2
100 --- 80
? --- 2 => Rs.2.5.Answer: C
Question: A problem in mathematics is given to three students A, B and C whose chances of solving it are 1/2, 3/4 and 1/4 respectively. What is the probability that the problem will be solved if all of them try independently.
A.29/32
B.30
C.31/33
D.31/35
Answer: A.29/32
Explanation: The probability that the problem is not solved by any of them:
(1 - P(A))*(1 - P(B))* (1 - P(C)) = (1 - 1/2)(1 - 3/4)(1 - 1/4) = 1/2*1/4*3/4 = 3/32
Hence, the probability that the problem will be solved is
1 - 3/32 = 29/32.
A)
Question: Large number of people went to an party and they decided to make some fun at the bar.
The first person asks the barman for half a pint of beer.
The second person asks for a quarter pint of beer
The third person asks for one-eighth of beer and so on ...
How many pints of beer will the barman need to fulfill the people need of beer ?
A.1
B.3
C.6
D.2
Answer: A.1
Explanation: A
Just 1
Question: What will come in place of the x in the following Number series? 1. 0, 6, 24, 60, 120, 210, x
A.336
B.430
C.530
D.560
Answer: A.336
Explanation: (A)
The given series is : 13 – 1, 23 – 2, 33 – 3, 43 – 4, 53 – 5, 63 – 6,
So the missing term = 73 – 7 = 343 – 7 = 336
Question: The distance traveled by Helicopter in one year approximately 750,000,000 miles.The distance traveled by helicopter in 15 years?
A.10<4>
B.10<6>
C.10<7>
D.10<9>
Answer: B.10<6>
Explanation: The distance traveled by Helicopter in one year = 75,000,000 miles
The distance traveled by Helicopter in 15 years =75,000,000 miles * 15 years = 1125000000
= 1125*10<6> (exponent miles) Answer =B
Question: A does a work in 10days and B does the same work in 15days. In how many days they together will do the same work?
A.3
B.5
C.6
D.8
Answer: C.6
Explanation: A+B can finish =AB/A+B = 10*15/(10+15) = 6days
Answer is C
Question: A set consist of 2k-1 element. What is the number of subsets of this set which contain at most k-1 elements?
A.2^(2k-2)
B.2^(2k) - 2
C.2^(2k) -1
D.2^(2k)
Answer: A.2^(2k-2)
Explanation: I used k=3, so then we have
5!/2!3! + 5!/4!1! + 5!/0!5!
10 + 5 + 1 = 16
So our target is 16
Now replace in answer choices
A gives us 2^4 = 16
Hence A is the correct option
Read carefully it says at most so keep in mind that picking a small number such as 3 will help you save time since you have to list fewer outcomes
Avoid 2 since you will get 1 arrangement (k-1) and may be risky since 1 is a number with certain unique properties
Question: A box contains 10 tablets of medicine A and 10 tablets of medicine B. What is the least number of tablets that should be taken from the box to ensure that at least two tablets of each kind are among the extracted.
A.12
B.15
C.17
D.19
Answer: A.12
Explanation: The worst case scenario will be if we remove all 15 tablets of medicine B first. The next 2 tablets we remove have to be of medicine A, so to guarantee that at least two tablets of each kind will be taken we should remove minimum of 10+2=12 tablets.
Answer: A.
Question: Two trains each 170m in length each, are running on two parallel lines in opposite directions. If one goes at the speed of 55km/h while the other travels at 50km/h. how long will it take for them to pass each other completely.
A.15 sec
B.11.6 sec
C.31.6 sec
D.12.6 sec
Answer: B.11.6 sec
Explanation: Explanation:
D = 170 m + 170 m = 340 m
RS = 55 + 50 = 105 * 5/18 = 146/5
T = 340 * 5/146 = 11.6 sec
Answer: Option B
Question: Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 19 boys and 41 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad?
A.2
B.7
C.6
D.8
Answer: B.7
Explanation: Venn diagrams are useful for multiple values of a single variable e.g. State of mind - happy/sad/neither. When you have two or more variables such as here where you have gender - boy/girl too, it becomes unwieldy. In this case, either use the table or logic.
Table method is shown above; here is how you will use logic:
There are 6 happy boys.
There are 4 sad girls but total 10 sad children. So rest 6 sad children must be sad boys.
We have 6 happy boys and 6 sad boys. Total we have 19 boys. So 19 - 6 - 6 = 7 boys must be neither happy nor sad.
Answer (B)
Question: Hillary and Eddy are climbing to the summit of Mt. Everest from a base camp 4,900 ft from the summit. When they depart for the summit at 06:00, Hillary climbs at a rate of 800 ft/hr with Eddy lagging behind at a slower rate of 500 ft/hr. If Hillary stops 900 ft short of the summit and then descends at a rate of 1,000 ft/hr, at what time do Hillary and Eddy pass each other on her return trip?
A.10.0
B.11.0
C.13.0
D.12.0
Answer: D.12.0
Explanation: Solution:H stopped 900 ft before reaching the final point, time taken to reach 4000 ft= 4000/800= 5hrs.
this means she reached there at 11:00.
speed difference between them is 800-500=300 ft/hr
so by the time H stops they have 1500 ft of distance
so now here we use relative speed formula they both are travelling toward each other with speed of 1000 and 500 total 1500 ft/hr and distance bwn them is 1500 ft so time taken to meet = 1 hr from 11:00
means 12:00 is the answer.
D
Question: A began business with Rs.36000 and was joined afterwards by B with Rs.54000. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
A.1
B.6
C.7
D.8
Answer: D.8
Explanation: 36*12 : 54*x = 2: 1
x = 4
12 -4 = 8
Answer: D
Question: A district hospital treated 290 patients today, and each of them were either man, woman, or child. If it treated 10 more men than of children, and in equal as many men as women, how many children were treated ?
A.90
B.80
C.100
D.110
Answer: A.90
Explanation: x = the number of men
y = the number of women
z = the number of children
From the first sentence we have
Equation #1: x + y + z = 290
...A district hospital treated 70 more men than children...
Equation #2: x = 10 + z
...in equal as many men as women...
Equation #3: x = y
Now, we can replace x with y in Equation #2
Equation #4: x - z = 10
Now, we can replace x with y in Equation #1
y + y + z = 290
Equation #5: 2y + z = 290
by adding equation #4 and equation #5 we get
x = 100
There are 100 men treated. This is 10 more than the number of children treated, so z = 90. That's the answer. Just as a check, y = 100, and 100 + 100 + 90 = 290.
Answer = 90,(A)
Question: What annual installment will discharge a debt of Rs. 1008 due in 3 years at 12% simple interest?
A.300
B.345
C.325
D.335
Answer: A.300
Explanation: Let each Installment be Rs. x
Then, ( x+ ((x*12*1)/100)) + (x+ ((x*12*2)/100) ) + x = 1008
=((28x/25) + (31x/25) + x) = 1008 ïƒ› (28x+31x+25x)=(1008*25)
x= (1008*25)/84 = Rs.300.
Therefore,	Each installment = Rs. 300.
Answer is A.