RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If a:b = 3:1, then find (a - 3b)/(2a - b)?
A.0
B.1
C.2
D.1/7
Answer: A.0
Explanation: a/b = 3/1 => a = 3b
(a - 3b)/(2a - b) = (3b - 3b)/(6b - b)
= 0/7b => 0
ANSWER:A
Question: How many times will the digit 8 be written when listing the integers from 1 to 1000?
A.164
B.297
C.300
D.345
Answer: C.300
Explanation: Many approaches are possible. For example:
Consider numbers from 0 to 999 written as follows:
1. 000
2. 001
3. 002
4. 003
...
...
...
1000. 999
We have 1000 numbers. We used 3 digits per number, hence used total of 3*1000=3000 digits. Now, why should ANY digit have preferences over another? We used each of 10 digits equal # of times, thus we used each digit (including 8) 3000/10=300 times.
Answer: C.
Question: My name is AJEET. But my son accidentally types the name by interchanging a pair of letters in my name. What is the probability that despite this interchange, the name remains unchanged?
A.
B.
C.
D.
A.5%
B.10%
C.20%
D.25%
Answer: B.10%
Explanation: This is a very crude method but i guess it's effective for such small problems.
Possible pairs of letters that could be interchanged are:
AJ
AE
AE
AT
JE
JE
JT
EE
ET
ET
Out of the the ten possibilities, only 1 would lead to an unchanged name.
Therefore, the probability is 1/10 = 10 %.
A more general approach goes as follows:
Each letter can be interchanged in the following ways.
'A' can be interchanged with 4 letters,' 'J' with 3, 'E' with 2 and 'E' with 1.
Therefore total possibilities equal 4+3+2+1=10.
Again only 1 would lead to an unchanged name.
Therefore the answer is 1/10 =10% ANS:B
Question: Six years ago, the ratio of the ages of Vimal and Saroj was 6:5. Four years hence, the ratio of their ages will be 11:10. What is Saroj's age at present?
A.12
B.14
C.16
D.18
Answer: C.16
Explanation: Given that, six years ago, the ratio of the ages of Vimal and Saroj =6:5
Hence we can assume that
age of Vimal six years ago =6x
age of Saroj six years ago =5x
After 4 years, the ratio of their ages =11:10
⇒(6x+10):(5x+10)=11:10⇒10(6x+10)=11(5x+10)⇒5x=10⇒x=105=2
Saroj's present age
=(5x+6)=5×2+6=16
Answer is C.
Question: What is the thousandths digit in the decimal equivalent of 62/5000?
A.0
B.1
C.2
D.5
Answer: C.2
Explanation: 62/5000 = 62 /(5*10^3)
= (62/5) *10^-3
=12.4 * 10^-3
=.0124
Thousandths digit = 2
Answer C
Question: What is the 4 digit number in which the 1st digit is 1/3 of the second, the 3rd is the sum of the 1st and 2nd, and the last is three times the second?
A.1100
B.1349
C.1160
D.1450
Answer: B.1349
Explanation: First digit is 1/3 second digit => The numbers can be 1 & 3, 2& 6, 3 & 9.
First + second = third => we can eliminate 3 & 9 since 3 + 9 = 12.
Last is 3 times the second => we can eliminate option 2 & 6 since 3 * 6 = 18.
Hence the number is 1349
B
Question: If f(x) = k(x - k) and k is a constant, what is the value of f(3) - f(2), in terms of k?
A. 1
B. k
C. 7k - 1
D. k^2 + k
Answer: B. k
Explanation: First, distribute f(x). k(x - k) = kx - k^2. Now evaluate f(3) and f(2):
f(3) = k(3) - k^2 = 3k - k^2
f(2) = 2k - k^2
f(3)-f(2)=k .. Answer B
Question: A and B can do a piece of work in 10 days. With the help of C they finish the work in 3 days. C alone can do that piece of work in?
A.15.5 days
B.4.3 days
C.17.5 days
D.16.5 days
Answer: B.4.3 days
Explanation: C = 1/3 – 1/10 = 7/30 => 4.3 days
ANSWER:B
Question: A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3 . Find his average after 17th inning.
A.39
B.88
C.26
D.87
Answer: A.39
Explanation: Explanation:
Consider the avg for first 16 innings is x.
Then total runs scored till 16 innings is 16x.
Total runs after 17 innings = 16x + 87.
Thus, 16x+8717=x+316x+8717=x+3 ⇒ x = 36
So his average after 17 innings = 39.
Answer: A
Question: Sripad has scored average of 62 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ?
A.79
B.70
C.38
D.27
Answer: B.70
Explanation: Assuming Sripad has scored the least marks in subject other than science,
Then the marks he could secure in other two are 58 each.
Since the average mark of all the 3 subject is 62.
i.e (58+58+x)/3 = 62
116 + x = 186
x = 70 marks.
Therefore, the maximum marks he can score in maths is 70.
Answer: B
Question: If 3 men or 4 women can do a piece of work in 16 days, in how many days can 12 men and 8 women do the same piece of work?
A.8/3
B.6
C.5
D.4
Answer: A.8/3
Explanation: 3 men can finish a work in 16 days, so in 1 day 3 men finish 1/16th of work and in 1 day 1 men can finish, 1/48th of work.
similarly, in 1 day 1 women can finish 1/64th of work.
12 men in 1 day can finish, 12/48 = 1/4,
8 women in 1 day can finish = 8/64 = 1/8
1/4 + 1/8 = 3/8.
hence number of days to complete is 8/3 days.
ANSWER:A
Question: The average age of seven persons sitting in a row facing east is 28 years. If the average age of the first three persons is 25 years and the average age of the last three persons is 31 years, then find the age of the person sitting in the middle of the row?
A.9 years
B.29 years
C.28 years
D.19 years
Answer: C.28 years
Explanation: Total age seven persons = (28 * 7)years
Total age of the first three persons and the last three persons are (25 * 3) years and (31 * 3) years respectively.
Age of the person sitting in the middle of the row = 28 * 7 - 25 * 3 - 31 * 3 = 196 - 75 - 93 = 28 years.
ANSWER:C
Question: The prices of a scooter and a television set are in the ratio 3 : 2. If a scooter costs Rs. 6000 more than the television set, the price of the television set is ?
A.Rs. 6000
B.Rs. 10000
C.Rs. 12000
D.Rs 16000
Answer: C.Rs. 12000
Explanation: Let the price of a scooter be Rs. 3x and that of a television set Rs. 2x.
Then, 3x - 2x = 6000
x = 6000
∴ Cost of a television set = 2x
= Rs. 12000
Answer : C
Question: An emergency vehicle travels 10 miles at a speed of 50 miles per hour. How fast must the vehicle travel on return trip if the round trip travel time is to be 20 minutes?
A.75
B.26
C.20
D.12
Answer: A.75
Explanation: Explanation:
Going trip time = t = dsds = 1050×601050×60 = 12 minutes.
Given total time = 20 minutes
Return trip time = Total time – Going trip time = 20 – 12 = 8 minutes = 860860 hours.
As the distance is 10 miles during even return trip,
The return speed = dtdt = 1086010860 = 10×60810×608 = 75 mph
Answer: A
Question: What is the difference between the place value and face value of 3 in the numeral 1375?
A.296
B.297
C.298
D.29
Answer: B.297
Explanation: place value of 3 = 3 * 100 = 300
face value of 3 = 3
300 - 3 = 297
B
Question: P can do a piece of work in 18 days and Q can do in 22 days, with the help of C, they finish the work in 6 days. How long will it take R to finish the work?
A.17days
B.18days
C.16 ½ days
D.17 ½ days
Answer: C.16 ½ days
Explanation: Explanation:
(P+Q) 1 day work = 1/18 + 1/22 = 7/66
(P+Q+R) 1 day work = 1/6
R 1 day work =1/6 – 7/66 = 2/33
R can do piece of work in 16 ½ days
Answer: Option C
Question: The negative number c is divisible by 2. What is the remainder when dividing 5(7-c)(9+c) by 2?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: When we multiply any of these options: 5*11*5 (c=-4) or 5*17*-1 (c=-10) we end up with numbers ending in 5; so any number ending in 5 divided by 2 will always leave a remainder of 1. Hence the correct answer is B.
Question: In a 1000 m race, A beats B by 70 m and B beats C by 100 m. In the same race, by how many meters does A beat C?
A.145 m
B.176 m
C.168 m
D.163 m
Answer: D.163 m
Explanation: By the time A covers 1000 m, B covers (1000 - 70) = 930 m.
By the time B covers 1000 m, C covers (1000 - 100) = 900 m.
So, the ratio of speeds of A and C =
1000/930 * 1000/900 = 1000/837 So, by the time A covers 1000 m, C covers 837 m.
So in 1000 m race A beats C by 1000 - 837 = 163 m.
Answer:D
Question: A person covered one-fourth of the total distance at 26 kmph and remaining distance at 24 kmph. What is the average speed for the total distance?
A.27 (1/3)kmph
B.21 (1/3)kmph
C.21 (1/7)kmph
D.26 (1/3)kmph
Answer: B.21 (1/3)kmph
Explanation: Let the total distance be x km
total time taken = (x/4)/16 + (3x/4)/24 = x/64 + x/32 = 3x/64
Average speed = x/(3x/64) = 64/3kmph = 21 (1/3)kmph.
Answer:B
Question: The average age of a class of 25 students is 19 years. The average increased by 2 when the teacher's age also included. What is the age of the teacher?
A.40 years
B.41 years
C.47 years
D.43 years
Answer: C.47 years
Explanation: If age of the teacher was 19, average would not have changed.
Since average increased by 2,
Age of the teacher=25+22×1=47
ANSWER:C
Question: How many of the following numbers are divisible by 132 ?
264, 396, 462, 792, 968, 2178, 5184, 6336
A.3
B.4
C.5
D.6
Answer: B.4
Explanation: 132 = 4 x 3 x 11
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
264 11,3,4 (/)
396 11,3,4 (/)
462 11,3 (X)
792 11,3,4 (/)
968 11,4 (X)
2178 11,3 (X)
5184 3,4 (X)
6336 11,3,4 (/)
Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.
B)
Question: A car takes 4 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
A.92Kmph
B.98Kmph
C.90Kmph
D.80Kmph
Answer: C.90Kmph
Explanation: Time = 4
Distence = 540
3/2 of 4 hours = 4 * 3/2 = 6 Hours
Required speed = 540/6 = 90 Kmph
C)
Question: A test has 160 questions. Each question has 5 options, but only 1 option is correct. If test-takers mark the correct option, they are awarded 1 point. However, if an answer is incorrectly marked, the test-taker loses 0.25 points. No points are awarded or deducted if a question is not attempted. A certain group of test-takers attempted different numbers of questions, but each test-taker still received the same net score of 40. What is the maximum possible number of such test-takers?
A.23
B.25
C.27
D.29
Answer: B.25
Explanation: A correct answers get you 1 point, an incorrect answer gets you MINUS 1/4 point and a skipped question gets you 0 points. Since there are 200 total questions, there are a variety of ways to get a total of 40 points.
Let C be the number of correct answers and let I be the number of incorrect answers.
To get 40 points, a test taker must have at least 40 correct answers. Then C=> 40.
For every correct question above 40, the test taker has 4 incorrect answers.
Then, the I = 4*(C - 40).
Also, I + C <= 160. Thus 5C <= 320 and so C <= 64.
Then 40 <= C <= 64 and C can have 25 possible values.
The answer is B.
Question: Cheese, bologna, and peanut butter sandwiches were made for a picnic in a ratio of 1 to 7 to 8. If a total of 80 sandwiches were made, how many bologna sandwiches
were made?
A.15
B.30
C.35
D.42
Answer: C.35
Explanation: For deciding such task we should calculate all parts 1 + 7 + 8 = 16 parts
and we should calculate how many sandwiches holds 1 part:
80 / 16 = 5 sandwiches in one part
For bologna we have 7 parts so:
7 * 5 = 35
Answer is C
Question: In a class,12 students like to play Basketball and 8 like to play Cricket. 3 students like to play on both Basketball and Cricket. How many students like to play Basketball or Cricket or both?
A.12
B.15
C.17
D.18
Answer: C.17
Explanation: Draw a Venn Diagram yourself !
B + C - BC = Number of students that play either Basketball or Cricket
12 +8 - 3 = 17
C)
Question: A patient was given three pills which he is required to take one after every thirty-five minutes.
How long can the pills run for him?
A.1 hour and 10 minutes.
B.1 hour and 15 minutes.
C.1 hour and 20 minutes.
D.1 hour and 50 minutes.
Answer: A.1 hour and 10 minutes.
Explanation: He took the first pill at the zero minute.
He took the second pill after 20 minutes = 0+35=35
He took the third pill after 20 minutes = 35+35=70
Then it will last for 70 minutes or an hour and 10 minutes.
Answer A
Question: A family pays $800 per year for an insurance plan that pays 65 percent of the first $1,000 in expenses and 100 percent of all medical expenses thereafter. In any given year, the total amount paid by the family will equal the amount paid by the plan when the family's medical expenses total.
A.$1,000
B.$1,200
C.$1,400
D.$1,500
Answer: D.$1,500
Explanation: Upfront payment for insurance plan = 800$
Family needs to pay 35 % of first 1000 $ in expense = 350$
Total amount paid by family when medical expenses are equal to or greater than 1000 $ = 800 + 350 = 1150 $
Total amount paid by insurance plan for first 1000 $ = 800 $
Total amount paid by family will equal amount paid by plan when medical expense = 1500 $
(Since insurance plan will pay 100% of amount that exceeds 1150$ )
Answer D
Question: A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
A.900 km
B.800 km
C.600 km
D.690 km
Answer: C.600 km
Explanation: Explanation:
D = 30 * 5 = 150
RS = 40 – 30 = 10
T = 150/10 = 15
D = 40 * 15 = 600 km
Answer: Option C
Question: A car moves at 92 km/hr. What is the speed of the car in meters per second ?
A.20 2/9m sec
B.22 2/9m sec
C.25 5/9m sec
D.26 2/9m sec
Answer: C.25 5/9m sec
Explanation: Explanation:
Speed=(92∗5/18)m/sec
=230/9 m/sec
=25 5/9msec
Option C
Question: Each person who attended a company meeting was either a stockholder in the company, an employee of the company or both. If 62 percent of these who attended the meeting were stockholders and 46 percent were employees. What percent were stockholders, who were not employees?
A.52
B.54
C.59
D.55
Answer: B.54
Explanation: I came up with the same answer choice B, but my approach was slightly different!
46% were employees which shall cover those who were only employees and those who were both shareholders and employees.
Thus, the number of attendants who were only shareholders is 100% - 46% = 54%.
Question: The C.P of 14 books is equal to the S.P of 18 books. Find his gain% or loss%?
A.16 2/3% loss
B.16 2/8% loss
C.16 3/3% loss
D.22 2/9% loss
Answer: D.22 2/9% loss
Explanation: 14 CP = 18 SP
18 --- 4 CP loss
100 --- ? => 22 2/9% loss
Answer:D
Question: The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 8480, what is the length of the plot in metres?
A.20
B.200
C.300
D.90
Answer: D.90
Explanation: Let length of plot = L meters, then breadth = L - 20 meters
and perimeter = 2[L + L - 20] = [4L - 40] meters
[4L - 40] * 26.50 = 8480
[4L - 40] = 8480 / 26.50 = 320
4L = 360
L = 360/4= 90 meters. Answer: D
Question: If 10^(x-1)< 0.000125 <10^x, what is the value of an integer x?
A.-4
B.-3
C.-2
D.3
Answer: B.-3
Explanation: -> Multiply 10^6- > (10^6){10^(x-1)}<125<(10^6)(10^x) -> 125 is bigger than 100
-> (10^6)(10^(x-1))=100 -> 10^(6+x-1)=10^2, x+5=2 -> x=-3
Thus, the answer is B
Question: Of 90 applicants for a job, 42 had at least 4 years' experience, 54 had degrees, and 8 had less than 4 years' experience and did not have a degree.How many of the applicants had at least 4 years' experience and a degree?
A.10
B.8
C.14
D.16
Answer: C.14
Explanation: 90 - 8 = 82
82 - 42 - 54 = -14
Then 14 are in the intersection between 4 years experience and degree.
Answer : C
Question: What number is obtained by adding the units digits of 734^99 and 347^83?
A.7
B.8
C.9
D.10
Answer: A.7
Explanation: The units digit of 734^99 is 4 because 4 raised to the power of an odd integer ends in 4.
The units digit of 347^83 is 3 because powers of 7 end in 7, 9, 3, or 1 cyclically. Since 83 is in the form 4n+3, the units digit is 3.
Then 4+3 = 7.
The answer is A.
Question: A man has Rs. 512 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
A.80
B.90
C.96
D.98
Answer: C.96
Explanation: Let number of notes of each denomination be x.
Then x + 5x + 10x = 512
16x = 512
x = 32.
Hence, total number of notes = 3x = 96.
C
Question: A study group consists of 4 English majors, 6 biological sciences majors, and 5 engineers. In how many ways can 3 English majors, 3 biological science majors and 3 engineers selected from the given group?
A.987 ways
B.346 ways
C.600 ways
D.200 ways
Answer: D.200 ways
Explanation: The number of ways of selecting three English majors, two biological science majors and three engineers is:
= ⁴C₃ * ⁶C₂ * ⁵C₃
= (4 * 3 * 2)/(3 * 2 * 1) * (6 * 5)/(3 * 2 * 1) * (5 * 4 * 3)/(3 * 2 * 1)
= 4 * 5 * 10
= 200 ways.
Answer: D
Question: If the range T of the six numbers 4,3,14,7,10 and x is 12, what is the difference between the greatest possible value of x and least possible value of x?
A.	0
B.	2
C.	12
D.	13
Answer: D.	13
Explanation: The range T of a set is the difference between the largest and smallest elements of a set.
Without x, the difference between the largest and smallest elements of a set is 14-3=11<12, which means that in order 12 to be the range of the set x must be either the smallest element so that 14-x=12 ---> x=2 OR x must the largest element so that x-3=12 --> x=15.
The the difference between the greatest possible value of x and least possible value of x is 15-2=13.
Answer: D.
Question: A certain car dealership offers its newest model in ten exterior and ten interior colors. If the five interior colors are identical to the ten exterior colors, and the dealership sells every pair of colors except those that would result in a car with an identically colored interior and exterior, how many different color combinations are possible?
A.25
B.81
C.90
D.10!/2!
Answer: A.25
Explanation: I lined up the 10 different colours for Exterion and Interior like this:
E: A B C D E F G H I J
I: A B C D E F G H I J
I calculated the number of combinations: 10*10= 100 combinations.
But, from these 100 we need to delete sth: the same colours.
There are 10 possible pairs of coulours that will be the same. So, I deleted these 10 pairs from 100, resulting in 25.
Mind here, that the 10 do not result in 20 colours, because 1 pair is one unit that is not allowed. So, 10 units are not allowed (surprised that 80 wasn't among the answer options to confuse test takers...).
A
Question: In a soccer bet,we play 4 teams.first team odd 1.25,second 5.23,third 3.25,fourth 2.05.we place the bet with 5.00 euros.
how much money we expect to win?
A.217.78
B.225.5
C.235.01
D.266.74
Answer: A.217.78
Explanation: in the case we won the bet,we have:
1.25* 5.23* 3.25* 2.0*5.00=219.50
we will win 217.78
so correct answer is A
Question: 36 men can complete a piece of work in 18 days. In how many days will 81 men complete the same work ?
A.8
B.77
C.88
D.29
Answer: A.8
Explanation: Explanation:
Less Men, means more Days {Indirect Proportion}
Let the number of days be x
then,
81 : 36 :: 18 : x
x = 8
Answer: A) 8 days
Question: If the average (arithmetic mean) of 16 consecutive odd integers is 414, then the least of these integers is
A.a) 399
B.b) 418
C.c) 519
D.d) 521
Answer: A.a) 399
Explanation: A very helpful rule to know in arithmetic is the rule that in evenly spaced sets, average = median. Because the average will equal the median in these sets, then we quickly know that the median of this set of consecutive odd integer numbers is 414.
There are 16 numbers in the set, and in a set with an even number of terms the median is just the average of the two most median terms (here the 7th and 8th numbers in the set). This means that numbers 7 and 8 in this set are 413 and 415. Because we know that number 7 is 413, we know that the smallest number is 7 odd numbers below this, which means that it is 7*2 = 14 below this (every odd number is every other number). Therefore 413-14 = 399, answer choice A.
Question: A photography dealer ordered 30 Model X cameras to be sold for $250 each, which represents a 20 percent markup over the dealer’s initial cost for each camera. Of the cameras ordered, 6 were never sold and were returned to the manufacturer for a refund of 50 percent of the dealer's initial cost. What was the dealer's approximate profit or loss as a percent of the dealer’s initial cost for the 30 cameras?
A.7% loss
B.13% loss
C.6% profit
D.13% profit
Answer: C.6% profit
Explanation: Total cost 30*($250/1.2)=6250;
# of cameras sold is 30-6=24 total revenue is 24*250;
# of cameras returned is 6 total refund 6*(250/1.2)*0.5;
So, total income 24*250+ 6*(250/1.2)*0.5
The dealer's approximate profit is (24*250+ 6*(250/1.2)*0.5-6250)/(6250)*100= 6%
Answer: C.
Question: A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 980gm. for a kg.His gain is …%.
A.2.04%
B.5.36%
C.4.26%
D.6.26%
Answer: A.2.04%
Explanation: His percentage gain is 100*20/980 as he is gaining 20 units for his purchase of 980 units.
so 2.04%..ANSWER:A
Question: A sum 's' is divided into 4 parts. second person gets Rs 10
more than first.3rd person is Rs 10 more than second,4th is 10 more than 3rd.how much amount do 1st person get.?
A.x = (s-60)/4
B.x = (s-60)/5
C.x = (s-60)/3
D.x = (s-60)/2
Answer: A.x = (s-60)/4
Explanation: let x be amount getting by first person,
second person gets x +10,third person gets x + 20,fourth person gets x + 30,
now s = (x)+(x+10)+(x+20)+(x+30)
s = 4x + 60
s - 60 = 4x
or x = (s-60)/4
ANSWER:A
Question: For each hour of production, a certain factory requires 1 assembly line worker for every 10 units to be produced in that hour. The factory also requires 12 managers regardless of the number of units to be produced. Which of the following expressions represents the total number of assembly line workers and managers that this factory requires to produce 50N in one hour, where N is a positive integer?
A.12 + 5N
B.12 + 2N
C.62N
D.37N
Answer: A.12 + 5N
Explanation: 10 units = 1 worker;
50N units = 50N/01 = 5N workers.
So, the answer is 5N workers plus 12 managers.
Answer: A.
Question: A train is 360 meter long is running at a speed of 90 km/hour. In what time will it pass a bridge of 140 meter length?
A.65 seconds
B.46 seconds
C.40 seconds
D.20 seconds
Answer: D.20 seconds
Explanation: Speed = 90 Km/hr = 90*(5/18) m/sec = 25 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (1/25)
= 20 seconds
Answer:D
Question: How many 7 in between 1 to 130?
A.18
B.20
C.22
D.23
Answer: D.23
Explanation: 7,17,27,37,47,57,67,
70,71,72,73,74,75,76,77(two 7's),78,79,87,97,107,117,127
23 7's between 1 to 130
ANSWER:D
Question: A batsman makes a score of 64 runs in the 16th innings and thus increased his average by 3. Find his average after the 16th inning?
A.23
B.28
C.27
D.19
Answer: D.19
Explanation: Let the average after the 16th inning be P.
So, the average after the 15th inning will be (P-3) Hence, 15(P-30) + 64
= 16P => P
= 19.
Answer: D
Question: Monica planned her birthday party. She prepared 5 muffins for each of her guests and kept aside two additional muffins in case someone will want extra. After the party, it turned out that one of the guests didn't come but every one of the guests that did come ate six muffins and 6 muffins remained. How many guests did Monica plan on?
A.3.
B.4.
C.5.
D.6.
Answer: A.3.
Explanation: Let x be the number of guests.
Number of muffins prepared = 5x + 2
Number of muffins eaten + Number of muffins remaining = Number of muffins prepared
6(x - 1) + 6 = 5x + 2
6x - 6 = 5x + 2
x = 8
Answer: A
Question: The total age of A and B is 10 years more than the total age of B and C. C is how many year younger than
A.14 years
B.12 years
C.56 years
D.10 years
Answer: D.10 years
Explanation: Given that A+B = 10 + B + C
=> A â€“ C = 10 + B â€“ B = 10
=> C is younger than A by 10 years
Answer:D
Question: In a certain boys camp, 20% of the total boys are from school A and 30% of those study science. If there are 28 boys in the camp that are from school A but do not study science then what is the total number of boys in the camp?
A.70
B.245
C.150
D.200
Answer: D.200
Explanation: Since 30% of the boys from school A study science, then 70% of the boys from school A do NOT study science and since 20% of the total number of boys are from school A, then 0.2*0.7 = 0.14, or 14% of the boys in the camp are from school A and do not study science.
We are told that this number equals to 28, so 0.14*{total} = 28 --> {total} = 200.
Answer: D.