RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.12 of money?
A.1200
B.1992
C.9921
D.2798
Answer: A.1200
Explanation: P = 12(100/10)2
=> P = 1200
Answer: A
Question: A disease has infected an ant colony that consists ofworkersandsoldiers: 30% of the soldiers and 14% of theworkerswere infected. If that colony is inhabited by 7000 ants, out of which 1620 are infected, how manyworkersinhabit the colony?
A.1500
B.2500
C.2750
D.3000
Answer: D.3000
Explanation: From two question we get wo equations:
(1) 0,3s + 0,14w = 1620
(2) s + w = 7000
From (2) we get w=7000-s
In (1) 0,3s + 980-0,14s= 1620
0,16s=640
64000:16= 4000 =s
In (2) 4000 + w = 7000
w= 3000 D
Question: The below sequence is a bit tricky. Can you solve it to find the next number?
7, 25, 325, 4325, ?
A.29816
B.38291
C.54327
D.38290
Answer: C.54327
Explanation: See the pattern. With every digit, the previous numbers are added after that digit
So the next number in the series is 54327
Answer : C
Question: Which of the following fractions W, if written as a decimal, would have a 2 in the thousandths place ?
A. 3/11
B. 7/9
C. 1/8
D. 4/7
Answer: A. 3/11
Explanation: (A) W=3/11 = 0.2727272727....
Answer: A
Question: What will come in place of the question mark (?) in the following equation?
25(7.5) × 5(2.5) ÷ 125(1.5) = 5?
A.16
B.17.5
C.8.5
D.13
Answer: D.13
Explanation: 25(7.5) × 5(2.5) ÷ 125(1.5) = 5?
or, 5(2 × 7.5) × 5(2.5) ÷ 5(3 × 1.5) = 5?
or 5(15) × 5(2.5) × 1⁄54.5 = 5?
or, 5(13)= 5? or, ? = 13
Answer D
Question: Two numbers are in the ratio 3:5. If 9 be subtracted from each, they are in the ratio of 9:17. The first number is?
A.36
B.67
C.87
D.56
Answer: A.36
Explanation: (3x-9):(5x-9)
= 9:17
x = 12 => 3x
= 36
Answer:A
Question: Three numbers are in the ratio 1 : 2 : 3 and their H.C.F is 12. The numbers are
A.4, 8, 12
B.5, 10, 15
C.10, 20, 30
D.12, 24, 36
Answer: D.12, 24, 36
Explanation: Explanation:
Let the required numbers be x, 2x, 3x. Then, their H.C.F =x. so, x= 12
The numbers are 12, 24, 36. Answer: D
Question: if i sell two articles, one at 20% profit for rs.100 and the other at 20% loss for rs.100, what is my net profit/loss?
A.4.16 profit
B.4.00 loss
C.8.33 profit
D.8.33 loss
Answer: B.4.00 loss
Explanation: 20/100=(100-CP1)/CP1
20/100=(CP2-100)/CP2
CP1 = 500/6 = 83.33
CP2 = 500/4 = 125
Total CP = 208.33
Total SP = 200
Loss = 8.33
Loss % = Loss x 100 / CP
833.33/208.33
4.0004 % loss
ANSWER:B
Question: In a barrel of juice there is 30 liters; in a barrel of beer there are 80 liters. If the price ratio between barrels of juice to a barrel of beer is 3:4, what is the price ratio between one liter of juice and one liter of beer?
A.3:2.
B.2:1.
C.3:1.
D.4:3.
Answer: B.2:1.
Explanation: Price of 30 L juice= 3x
1L= 3x/30
Price of 80 L beer= 4x
1L= 4x/80
Ratio of 1 L price = 3x/30/4x/80= 2:1
B is the answer
Question: Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
A.2 years
B.4 years
C.6 years
D.7 years
Answer: C.6 years
Explanation: Explanation:
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) = 42 years.
Required difference = (42 - 36) = 6 years.
Answer: Option C
Question: How many positive integers will divide evenly into 410?
A.4
B.6
C.8
D.12
Answer: C.8
Explanation: The question is asking how many factors 410 has.
410 = 2*5*41
The number of factors is 2^3 = 8
The answer is C.
Question: The sum of money at compound interest amounts to thrice itself in 5 years. In how many years will it be 15 times itself?
A.8 years
B.9 years
C.10 years
D.25 years
Answer: D.25 years
Explanation: 100 ---- 300 --- 5
600 --- 5
900 ---5
1200 ---5
1500--- 5
25 years
Answer: D
Question: If the Average (mean ) of 9 positive temperatures is x degrees fahrenheit, then the sum of the 3 greatest of these temperatures, in degrees Fahrenheit, could be
A.8x
B.4x
C.5x/3
D.3x/2
Answer: A.8x
Explanation: Let the 5 numbers be 1,2,3,4,5,..9 (since no restrictions are given). There mean is 4 (x).
Now the sum of greatest three would be 7+8+9=24
so the answer has to be 8x....that is option A
Question: Factor: 2x4y3 â€“ 32y3
A.A) 3y3(x2 + 4)(x + 2)(x -2)
B.B) 2y3(x2 + 4)(x + 2)(x -2)
C.C) 3y3(x2 + 4)(x + 2)(x -3)
D.D) 3y3(x2 + 4)(x + 3)(x -2)
Answer: B.B) 2y3(x2 + 4)(x + 2)(x -2)
Explanation: 2x4y3â€“ 32y3.
= 2y3(x4 â€“ 16).
= 2y3[(x2)2 - 42].
= 2y3(x2 + 4)(x2 - 4).
= 2y3(x2 + 4)(x2 - 22).
= 2y3(x2 + 4)(x + 2)(x -2).
Answer: (B) 2y3(x2 + 4)(x + 2)(x -2)
Question: If there are 6 seats and 2 students, in how many ways can they be seated?
A.25
B.30
C.35
D.40
Answer: B.30
Explanation: The first student has 6 choices and the second student has 5 choices.
The number of ways to sit is 6*5 = 30.
The answer is B.
Question: David obtained 76, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ?
A.75
B.77
C.28
D.29
Answer: A.75
Explanation: Explanation:
Average = (76 + 65 + 82 + 67 + 85 )/ 5 = 375/5 = 75.
Answer: A) 75
Question: A runner runs the 40 miles from Marathon to Athens at a constant speed. Halfway through the run she injures her foot, and continues to run at half her previous speed. If the second half takes her 11 hours longer than the first half, how many hours did it take the runner to run the second half?
A.14
B.15
C.18
D.22
Answer: D.22
Explanation: The runner runs the first 20 miles at speed v and the second 20 miles at speed v/2.
The time T2 to run the second half must be twice the time T1 to run the first half.
T2 = 2*T1 = T1+11
T1 = 11 and so T2 = 22.
The answer is D.
Question: On a scale that measures the intensity of a certain phenomenon, a reading of f+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of f. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?
A. 5
B. 50
C. 10^5
D. 5^10
Answer: C. 10^5
Explanation: To solve this problem we need to examine the information in the first sentence. We are told that “a reading of f + 1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of f.”
Let’s practice this idea with some real numbers. Let’s say f is 2. This means that f + 1 = 3. With the information we were given we can say that a reading of 3 is ten times as great as the intensity of a reading of 2.
Furthermore, we can say that a reading of 4 is actually 10 x 10 = 10^2 times as great as the intensity of a reading of 2.
Increasing one more unit, we can say that a reading of 5 is 10 x 10 x 10 = 10^3 times as great as the intensity of a reading of 2.
We have found a pattern, which can be applied to the problem presented in the stem:
3 is “one” unit away from 2, and thus a reading of 3 is 10^1 times as great as the intensity of a reading of 2.
4 is “two” units away from 2, and thus a reading of 4 is 10^2 times as great as the intensity of a reading of 2.
5 is “three” units away from 2, and thus a reading of 5 is 10^3 times as great as the intensity of a measure of 2.
We can use this pattern to easily answer the question. Here we are being asked for the number of times the intensity corresponding to a reading of 8 is as great as the intensity corresponding to a reading of 3. Because 8 is 5 units greater than 3, a reading of 8 is 10^5 times as great as the intensity corresponding to a reading of 3.
Answer C.
Question: Michelle leaves home everyday at 4 p.m to pick his son from school and returns home at 6 p.m. One day, the school was over at 4 p.m and the son started walking home from school. Michelle, unaware of this, starts from home as usual and meets his son on the way and returns home with him 15 minutes early. If the speed of Michelle is 30 km\hr, find the speed of his son.
A.15km/hr
B.6 km/hr
C.4.28 km/hr
D.9 km/hr
Answer: C.4.28 km/hr
Explanation: Michelle leaves home everyday at 4 p.m to pick his son from school and returns home at 6 p.m. One day, the school was over at 4 p.m and the son started walking home from school. Michelle, unaware of this, starts from home as usual and meets his son on the way and returns home with him 15 minutes early. If the speed of Michelle is 30 km\hr, find the speed of his son.
The distance from home to school is 30 km. The round trip distance = 60 km. Because he returns home 15 minutes early, I thought it might be easier to break his trip up into 8 identical 15 minute blocks, each of which he traveled at 7.5 km/hour.
Because we are dealing with a round trip here, Michelle would have stopped 7.5 minutes short of the school. This means he traveled Distance=rate* time .5Km/hour*52.5 minutes or 26.25 KM. His son therefore traveled 3.75km/hour by the time he met his dad at 4:52.5. It took the son 52.5 minutes to travel 3.75 km. Because we are trying to find the son's rate per hour (i.e. 60 minutes) and we have his speed for 52.5 minutes it's best to convert to km/minute then multiply by 60 to get km/hour
3.75km/52.5 = .07 km/minute
.07km/minute*60 minutes = 4.28 km/hour.
Answer: C. 4.28 km/hr
Question: Two men and three women working 7 hours a day finish a work in 5 days. Four men and four women working 3 hours a day complete the work in 7 days. The number of days in which only 7 men working 4 hours a day will finish the work is?
A.5 days
B.7 days
C.8 days
D.6 days
Answer: A.5 days
Explanation: 2M + 3W ----- 35 h
4M + 4W ------- 21 h
7M -------? d
70M + 105W = 84M +84M
21W = 14M => 2M = 3W
4 * 35 = 7 * x => x = 20 hours
20/4 = 5 days
Answer:A
Question: Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.17 per cubic meter?
A.2998
B.2799
C.2890
D.1683
Answer: D.1683
Explanation: 22/7 * 14 * 3/2 * 3/2
= 99 m2
99 * 17
= 1683
Answer:D
Question: In a certain sequence of numbers, a1, a2, a3, ..., an, the average (arithmetic mean) of the first m consecutive terms starting with a1 is m, for any positive integer m. If a1=1, what is a14?
A.100
B.55
C.27
D.19
Answer: C.27
Explanation: As stated above, (a1+a2+a3......+a10)/10=10
therefore a1+a2+a3.......a14=196 (1)
using the same logic, we got a1+a2+a3..........+a13=169 (2)
(2)-(1) we got a14=27
C
Question: If s and t are positive integers, and 3 is not a factor of t, then t may be which of the following?
A.(s−1)·s·(s+1)
B.(s−3)·(s−1)·(s+1)
C.(s−2)·s·(s+2)
D.(s−1)·s·(s+2)
Answer: D.(s−1)·s·(s+2)
Explanation: Plugged in values :
let s=5
A. (s−1)·s·(s+1) --> divisible by 3
B. (s−3)·(s−1)·(s+1) --> divisible by 3
C. (s−2)·s·(s+2) --> divisible by 3
D. (s−1)·s·(s+2) --> not divisible. Hence the answer.
Question: A, B and C can do a piece of work in 7 days, 14 days and 28 days respectively. How long will they taken, if all the three work together?
A.3 days
B.4 days
C.5 days
D.6 days
Answer: B.4 days
Explanation: Explanation:
1/7 + 1/14 + 1/28 = 7/28 = 1/4 => 4 days
Answer: B
Question: What least no. must be subtracted from 101054 so that remaining no.is divisible by 10?
A.6
B.4
C.8
D.5
Answer: B.4
Explanation: Explanation:
On dividing 101054 by 10 we get the remainder 4, so 4 should be subtracted
Option B
Question: In triangle PQR, the angle Q = 90 degree, PQ = 7 cm, QR = 8 cm. X is a variable point on PQ. The line through X parallel to QR, intersects PR at Y and the line through Y, parallel to PQ, intersects QR at Z. Find the least possible length of XZ
A.5.6 cm
B.2.4 cm
C.4.8 cm
D.2.16 cm
Answer: A.5.6 cm
Explanation: Look at the diagram below:
Now, in case when QY is perpendicular to PR, two right triangles PQR and PQY are similar: QY:QP=QR:PR --> QY:7=8:10 --> QY=5.6.
Answer: A.
Question: What is y if y + 2x = 10 and x = 3?
A.A)10
B.B)8
C.C)6
D.D)4
Answer: D.D)4
Explanation: y = 10 - 2x
y = 10 - 8.
y = 2
Answer : D
Question: The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
A.276
B.299
C.322
D.345
Answer: C.322
Explanation: the numbers are (23 x 13) and (23 x 14).
Larger number = (23 x 14) = 322.
Answer: Option C
Question: Find the average of all numbers between 1 and 13 which are divisible by 2
A.15
B.21
C.25
D.30
Answer: B.21
Explanation: Explanation:
Average=(2+4+6+8+10+12 )/ 2=42 / 2=21
Option B
Question: If x is equal to the sum of the integers from 30 to 40, inclusive, and y is the number of EVEN integers from 30 to 40, inclusive, what is the value of x+y ?
A.171
B.281
C.391
D.591
Answer: C.391
Explanation: sum s= n/2{2a+(n-1)d} = 11/2{2*30+ (11-1)*1} =11*35=385 =X
number of even number =( 40-30)/2 +1 = 6= Y
X+Y = 385+6 =391
C
Question: There are 24 students in a seventh grade class. They decided to plant birches and roses at the school's backyard. While each girl planted 3 roses, every three boys planted 1 birch. By the end of the day they planted 2424 plants. How many birches were planted?
A.2
B.5
C.8
D.6
Answer: D.6
Explanation: Let x be the number of roses. Then the number of birches is 24−x, and the number of boys is 3×(24−x). If each girl planted 3 roses, there are x3girls in the class.
We know that there are 24 students in the class. Therefore x3+3(24−x)=24
x+9(24−x)=3⋅24
x+216−9x=72
216−72=8x
1448=x1
x=18
So, students planted 18 roses and 24 - x = 24 - 18 = 6 birches.
correct answer is D)6
Question: A and B started a partnership business investing capital in the ratio of 3 : 5. C joined in the partnership after six months with an amount equal to that of B. At the end of one year, the profit should be distributed among A, B and C in --- proportion.
A.10 : 5 : 4
B.5 : 3 : 4
C.3 : 4: 5
D.6 : 10 : 5
Answer: D.6 : 10 : 5
Explanation: Explanation :
Initial investment capital ratio of A and B = 3 : 5
Hence we can assume that initial capital of A and B are 3x and 5x respectively.
Amount that C invest after 6 months = 5x (Since it is equal to B's investment)
Ratio in which profit should be distributed after 1 year = 3x*12 : 5x * 12 : 5x*6
=> 3*12 : 5*12 : 5*6
= 6 : 10 : 5. Answer : Option D
Question: A dealer purchases 15 articles for Rs. 25 and sells 12 articles for Rs. 36. Find the profit percentage?
A.80%
B.50%
C.59%
D.40%
Answer: A.80%
Explanation: L.C.M of 15 and 12
= 60
CP of 60 articles
= Rs. 100 (25 * 4)
SP of 60 articles
= Rs. 180 (36 * 5)
Profit percentage
= (180 - 100)/100 * 100 = 80%
Answer: A
Question: If x and y are positive integers, which of the following CANNOT be the greatest common divisor of 35x and 20y?
A.5
B.5(x – y)
C.20x
D.20y
Answer: C.20x
Explanation: Looking at the list of answer choices, there are some that we can quickly eliminate...
IF
X = 1
Y = 1
Then we have 35 and 20, so the GCD = 5
Eliminate A.
X = 20
Y = 1
Then we have 700 and 20, so the GCD = 20
Eliminate D.
X = 1
Y = 35
Then we have 35 and 700, so the GCD = 35
Eliminate E.
With the remaining 2 answers, we have to think a little more.
To get a simple example of 5(X-Y) to be the GCD, we probably need 35X to be ODD
IF...
X = 3
Y = 2
Then we have 105 and 40, so the GCD = 5
5(X-Y) = 5(3-2) = 5
This can ALSO be the GCD
Eliminate B.
ANSWER:C
Question: The sum of three numbers is 98. If the ratio of the first to the second is 2 : 3 and that of the second to the third is 5 : 8,then the second number is :
A.20
B.30
C.38
D.48
Answer: B.30
Explanation: A : B = 2 : 3 = 2 × 5 : 3 × 5 = 10 : 15
and B : C = 5 : 8 = 5 × 3 : 8 × 3 = 15 : 24
Therefore, A : B : C = 10 : 15 : 24
∴ A : B : C = 10 : 15 : 24
Let the number be 10x, 15x and 24x.
Then, 10x + 15x + 24x = 98
or 49x = 98 or x = 2
⇒ Second number = 15x = 15 × 2 = 30
Answer B
Question: In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 6500, the number of valid votes that the other candidate got, was:
A.2800
B.2700
C.2900
D.2340
Answer: D.2340
Explanation: D
Number of valid votes = 80% of 6500 = 5200.
Valid votes polled by other candidate = 45% of 5200
= (45/100 x 5200) = 2340.
Question: How many terminating zeroes R does 200! have?
A. 40
B. 48
C. 49
D. 55
Answer: C. 49
Explanation: You have 40 multiples of 5, 8 of 25 and 1 of 125. This will give 49 zeros.C
Question: 75 men working 8 hours per day dig 50 m deep. How many extra men should be put to dig to a depth of 70 m working 6 hours per day?
A.75
B.45
C.55
D.65
Answer: D.65
Explanation: (75 * 8)/50
= (x * 6)/70
=> x =140
140 â€“ 65
= 65
Answer: D
Question: Rates for having a manuscript typed at a certain typing service are $10 per page for the first time a page is typed and $5 per page each time a page is revised. If a certain manuscript has 100 pages, of which 30 were revised only once, 20 were revised twice, and the rest required no revisions, what was the total cost of having the manuscript typed?
A.$1250
B.$1350
C.$1150
D.$1360
Answer: B.$1350
Explanation: 50 pages typed 1x
30 pages typed 2x (original + one revision)
20 pages typed 3x (original + two revisions)
50(10)+30(10+5)+20(10+5+5)=500+450+400=1350
Answer - B
Question: The water level in a reservoir has been dropping at the rate of 14 inches per day. Exactly 5 days ago, the water level was at w inches. What will be the water level exactly 3 days from now if the rate at which the level is dropping remains the same?
A.w − 126
B.w − 56
C.w − 112
D.w + 14
Answer: C.w − 112
Explanation: Drop=14 inches/day
5 Days ago=w, means now it's equal w-70 and in 3 days = w-70-42=w-112
Answer C
Question: If the sum of two numbers is 60 and the H.C.F and L.C.M of these numbers are 3 and 120 respectively, then the sum of the reciprocal of the numbers is equal to:
A.2/9
B.4/5
C.1/6
D.6/6
Answer: C.1/6
Explanation: Let the numbers be a and b.
Then, a + b = 60 and ab = 3 * 120 =360.
Required sum = 1/a + 1/b = (a + b)/ab = 60/360 = 1/6.
ANSWER:C
Question: A certain bus driver is paid a regular rate of $15 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $976 in total compensation, how many total hours did he work that week?
A.56
B.51
C.59
D.54
Answer: D.54
Explanation: For 40 hrs = 40*15=600
Excess = 976-600=376
For extra hours =.75(15)=11.25+15=26.25
Number of extra hrs =376/26.25=14.3=14 approx.
Total hrs =40+14=54
Answer D
Question: The mean of 20 values was 150. It was detected on rechecking that one value 160 was wrongly copied as 135 for the computation of the mean. Find the correct mean.
A.151
B.149
C.151.25
D.148
Answer: C.151.25
Explanation: Corrected mean = 150×20−135+160/20
= 3000−135+160/20
=3025/20=151.25
Answer C
Question: If the true discount on s sum due 2 years hence at 14% per annum be Rs. 168, the sum due is ?
A.Rs.948
B.Rs.876
C.Rs.768
D.Rs.658
Answer: C.Rs.768
Explanation: Explanation:
P.W. =(100*T.D)/R*T = (100*168)/14*2 = 600.
Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.
ANSWER IS C
Question: To fill a tank, 10 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present ?
A.25
B.50
C.75
D.100
Answer: A.25
Explanation: Let the capacity of 1 bucket = x.
Then, the capacity of tank = 10x.
New capacity of bucket = 2/5 x
Therefore, Required number of buckets = (10x)/(2x/5)
= (10x) x 5/2x
= 50/2
= 25
Answer is A.
Question: The youngest of 4 children has siblings who are 3, 5, and 8 years older than she is. If the average (arithmetic mean) age of the 4 siblings is 21, what is the age of the youngest sibling?
A.17
B.18
C.19
D.21
Answer: A.17
Explanation: Total age of the 4 sibling is 21 x 4 = 84 years ..
We already have the total age of all the children is 4y + 16
So, 4y + 16 = 84
Or, 4y = 68
Or, y = 17
So, Age of the youngest child is 17 years.
ANSWER:A
Question: The average temperature on Wednesday in Chicago, St. Louis, and Pittsburgh was 27Â°C. The average temperature that same day of St. Louis, Pittsburgh, and Jersey City was 30Â°C. If temperature in Jersey City was 32Â°C, what was the temperature on Wednesday in Chicago?
A.22Â°C
B.23Â°C
C.24Â°C
D.25Â°C
Answer: B.23Â°C
Explanation: Solution: Average temperature for Chicago, St. Louis and Pittsburgh = 27Â°C
Total temperature = 3*27 = 81
Average temperature for St. Louis, Pittsburgh and Jersey City = 30Â°C
Total temperature = 3*30 = 90
Temperature in Jersey City = 32Â°C
Now,
(Chicago+St. Louis+Pittsburgh)-(St. Louis+Pittsburgh+Jersey City) = 81-90
Chicago - Jersey City = -9
Chicago = Jersey City - 9 = 23Â°C
Answer: Option B
Question: At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years
A.3%
B.4%
C.5%
D.6%
Answer: D.6%
Explanation: Explanation:
Let Rate will be R%
1200(1+R100)2=134832100(1+R100)2=134832120000(1+R100)2=1123610000(1+R100)=106100=>R=6%
Answer: D
Question: There are 3 numbers A, B and C. If A:B = 3/4, B:C = 4/5, C:D = 5/6, then A:D will be?
A.1 : 2
B.2 : 3
C.3 : 5
D.3 : 7
Answer: A.1 : 2
Explanation: Sol. A : B = 3 : 4, B : C = 4 : 5, C : D = 5 : 6
∴A∶B∶C∶D= 3 : 4 : 5 : 6.
Thus, A : D = 3 : 6 or, 1 : 2
A
Question: A train 500 m long can cross an electric pole in 20 sec and then find the speed of the train?
A.17 Kmph
B.78 Kmph
C.90 Kmph
D.18 Kmph
Answer: C.90 Kmph
Explanation: Length = Speed * time
Speed = L/T
S = 500/20
S = 25 M/Sec
Speed= 25*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 90 Kmph
Answer: C
Question: Two spherical balls lie on the ground touching. If one of the balls has a radius of 3 cm, and the point of contact is 5 cm above the ground, what is the radius of the other ball?
A.3 cm
B.9 cm
C.12 cm
D.15 cm
Answer: D.15 cm
Explanation: similar triangle properties..
2/r+3 = 3/r-3
giving r = 15.
Answer: D
Question: Three workers have a productivity ratio of 1 to 3 to 5. All three workers are working on a job for 4 hours. At the beginning of the 5th hour, the slowest worker takes a break. The slowest worker comes back to work at the beginning of the 9th hour and begins working again. The job is done in ten hours. What was the ratio of the work performed by the fastest worker as compared to the slowest?
A.25 to 3
B.6 to 1
C.5 to 1
D.1 to 6
Answer: A.25 to 3
Explanation: The fastest worker who does 5 units of job worked for all 10 hours, so he did 5*10=50 units of job;
The slowest worker who does 1 unit of job worked for only 4+2=6 hours (first 4 hours and last 2 hours), so he did 1*6=6 units of job;
The ratio thus is 50 to 6, or 25 to 3.
Answer: A
Question: In a certain store, the profit is 1150% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
A.30%
B.70%
C.900%
D.250%
Answer: C.900%
Explanation: Let C.P. = Rs. 100. Then, profit = Rs. 1150, S.P. = Rs. 1250
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 1250
Profit = 1250 - 125 = Rs. 1125
Required percentage = 1125/1250 * 100 = 900%
ANSWER:C
Question: Two pipes can fill a tank in 15 minutes and 12 minutes. The outlet pipe can empty the tank in 20 minutes. If all the pipes are opened when, the tank is empty, then in how many minutes will it take to fill the tank?
A.12
B.13
C.11
D.10
Answer: D.10
Explanation: Part of tank filled by all three pipes in one minute =
1/15 + 1/12 – 1/20 = (8+10-6) / 120
= 18-6 / 120
= 1/10
So, the tank becomes full in 10 minutes.
ANSWER:D
Question: Jake can dig a well in 16 days. Paul can dig the same well in 24 days. Jake, Paul and Hari together dig the well in 8 days. Hari alone can dig the well in
A.48
B.99
C.22
D.27
Answer: A.48
Explanation: Explanation: Simple one. Let the total work to be done is 48 meters. Now Jake can dig 3 mts, Paul can dig 2 mts a day. Now all of them combined dug in 8 days so per day they dug 48/8 = 6 mts. So Of these 8 mts, Hari capacity is 1 mt.
So he takes 48 /1 = 48 days to complete the digging job.
Answer:A
Question: A train 150 m long pass a telegraph pole in 5 seconds. Find the speed of the train
A.66 km/hr
B.108 km/hr
C.72 km/hr
D.79.2 km/hr
Answer: B.108 km/hr
Explanation: Sol.
Speed = [150/5] m/sec = [30 * 18/5] km/hr = 108 km/hr.
Answer B