RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Which of the following is(are) true for a@b=b@a?
I. a@b=ab+ba
II. a@b=(a+b+1)(a-b)
III. a@b=(a/b)+(b/a)
A.only Ⅰ
B.only Ⅱ
C.only Ⅲ
D.only ⅠⅢ
Answer: D.only ⅠⅢ
Explanation: -> If I. a@b=ab+ba, a@b=ab+ba=ba+ab=b@a (O).
If II. a@b=(a+b+1)(a-b), a@b=(a+b)(a-b)≠(b+a)/(b-a)=b@a (X).
If III.a@b=(a/b)+(b/a), a@b=(a/b)+(b/a)=(b/a)+(a/b)=b@a (O).
Thus, ⅠⅢ are the answers. Therefore, D is the answer.
Question: How many integers from 1 to 100 exist such that each is divisible by 5 and also has 5 as a digit ?
A.10
B.12
C.11
D.20
Answer: C.11
Explanation: 5,15,25,35,40,50,55,65,75,85,95
So there are total 11 such type of numbers.
ANSWER :C
Question: The difference between a two-digit number obtained by interchanging the positions of its digits is 36. What is the difference between the two digits of that number?
A.4
B.9
C.3
D.Cannot be determined
Answer: A.4
Explanation: Let the two-digit number be 10x + y.
Then, (10x + y) – (10y + x) = 36
or x – y = 4
Answer A
Question: train having a length of 240 metre passes a post in 24 seconds. How long will it take to pass a platform having a length of 650 metre?
A.89 sec
B.100 sec
C.90 sec
D.85 sec
Answer: A.89 sec
Explanation: speed = 240/24 = 10 m/s
req time = 240+650/10 = 89 sec
ANSWER A
Question: A 2-year certificate of deposit is purchased for R dollars. If the certificate earns interest at a n annual rate of 6 percent compound quarterly, which of the following represents the value, in dollars, of the certificate at the end of 2 years?
A.k(1.06)^2
B.k(1.06)^8
C.k(1.015)^2
D.R(1.015)^8
Answer: D.R(1.015)^8
Explanation: Annual Rate of interest= 6%
Quaterly rate of interest= 6/4% = 1.5%
Now, periods of compounding in 2 years= 8 (8 quarters)
Thus R(1.015)^8
Answer: D
Question: The price of a vehicle, passing through three hands, rises on the whole by 65%. If the first and the second sellers earned 20% and 25% profit respectively. Find the percentage profit earned by the third seller.
A.20%
B.5%
C.15%
D.10%
Answer: D.10%
Explanation: Explanation :
Solution: Let the original price of the vehicle be Rs. X and let the profit earned by the third seller be Y%.
Then, (100+Y)% of 125% of 120% of X = 165% of X.
[(100+Y)/100 * 125/100 * 120/100 * X] =165/100 * X.
100+Y = 165*100*100/(125*120) = 110 => Y= 10%
Answer : D
Question: At 6'o clock clock ticks 6 times. The time between first and
last ticks was 30sec. How much time it takes at 12'o clock.
A.60sec
B.62sec
C.66sec
D.64sec
Answer: C.66sec
Explanation: At 6'0 clock, clock ticks 6 times.
So, there must be 5 intervals between clock ticks.
Time Between first and last ticks = 30sec
So, 1 interval = 30/5 = 6sec
So 6'o clock 5 *6=30sec
7'o clock 6 *6=36sec
.
.
.
10'o clock 9 *6=54sec
11'o clock 10*6=60sec
12'o clock 11*6=66sec
So, 66sec at 12'o clock.
ANSWER:C
Question: If A and B are two events such that P (A) = 3/4, P (B) = 1/2 and P (A n B) = 3/4,
find P (not A and not B).
A.A)1
B.B)1/2
C.C)1/3
D.D)1/4
Answer: B.B)1/2
Explanation: P(not A and not B) = 1 - (P(A) + P(B) - P(AB))
which you might find somewhere in your text.
Substituting in our probabilities we get:
P(not A and not B) = 1 - (3/4 + 1/2 - 3/4)
P(not A and not B) = 1 - (1/2)
P(not A and not B) = 1/2.
B
Question: What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?
A.263
B.500
C.367
D.368
Answer: B.500
Explanation: 70 = (P*4*7/2)/100
P = 500
Answer: B
Question: The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 8 years hence?
A.22
B.76
C.70
D.98
Answer: B.76
Explanation: A + B = 60, A = 2B
2B + B = 60 => B = 20 then A = 40.
8 years, their ages will be 48 and 28.
Sum of their ages = 48 + 28 = 76.
Answer: B
Question: Find HCF of 4/5, 8/35, 2/15, 6/25 ?
A.2/125
B.6/360
C.2/525
D.2/720
Answer: C.2/525
Explanation: We know that the HCF for fraction can be calculated as:
HCF = (HCF of numerators) / (LCM of denominators)
= (HCF of 4, 8, 2, 6) / (LCM of 5, 35, 15, 25)
= 2 / (5 x 7 x 3 x 5)
= 2 /525
Ans - C
Question: Two persons start running simultaneously around a circular track of length 520 m from the same point at speeds of 18 kmph and 30 kmph. When will they meet for the first time any where on the track if they
are moving in the opposite direction ?
A.144
B.39
C.124
D.32
Answer: B.39
Explanation: Time taken to meet the first time = length of track/relative speed
= 520/ (18 +30) (5/18)
= 520/48 *(18/5) = 39 sec.
Answer : B
Question: 14.02 Ã— 0.001 = ?
A.0.1402
B.0.001402
C.1.4021
D.0.01402
Answer: D.0.01402
Explanation: 14.02 Ã— 0.001 = 0.01402
The answer is D.
Question: If y is an integer, which of the following must also be an integer?
I. x/y
II. y/x
III. xy
A.I alone
B.II alone
C.III alone
D.I and III
Answer: C.III alone
Explanation: Lets take X = 5 and Y = 3
Then XY = 15 which is an integer.
But X/Y = 5/3 --> Not an integer.
Y/X = 3/5 --> Not an integer.
Hence C.
Question: A, B, K start from the same place and travel in the same direction at speeds of 30 km/hr, 40 km/hr, 160 km/hr respectively. B starts two hours after A. If B and K overtake A at the same instant, how many hours after A did K start?
A.5.0
B.5.5
C.6.0
D.6.5
Answer: D.6.5
Explanation: In 2 hours, A travels 60 km.
B can catch A at a rate of 10 km/hr, so B catches A 6 hours after B starts.
So A and B both travel a distance of 240 km.
C needs 1.5 hours to travel 240 km, so C leaves 6.5 hours after A.
The answer is D.
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 950 grams per kg, what is his percent?
A.5.3%
B.25%
C.65%
D.45%
Answer: A.5.3%
Explanation: Explanation:
950 --- 50
100 --- ? => 5.3%
Answer: A
Question: Having received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.64 at the candy store. What is John’s weekly allowance?
A.$2.40
B.$3.00
C.$3.20
D.$3.60
Answer: A.$2.40
Explanation: Total allowance=X
Amount spent at the arcade=3/5X
Amount Remaining=2/5X
Amount Spent at the toy store=2/5*1/3X=2/15X
Amount Remaining=2/5X-2/15X=4/15X
Now, 4/15X=$0.64
Therefore, X=$2.40. Answer A
Question: 3,7,12,18,26,__
A.36
B.38
C.39
D.40
Answer: A.36
Explanation: 7=3+4
12=7+5
18=12+6
26=18+8
36=26+10
ANSWER:A
Question: If Tim had lunch at $50.50 and he gave 40% tip, how much did he spend?
A.A)$57.45
B.B)$70.70
C.C)$60.60
D.D)$21.56
Answer: B.B)$70.70
Explanation: The tip is 40% of what he paid for lunch.
tip = 40% of 50.50 = (40/100)*50.50 = $20.20
Total spent
50.50 + 20.20 = $70.70
correct answer is B)$70.70
Question: tipli and pikli are a married couple (dont ask me who he is and who she is)
They have two children, one of the child is a boy. Assume safely that the probability of each gender is 1/2.
What is the probability that the other child is also a boy?
Hint: It is not 1/2 as you would first think.
A.1/9
B.1/3
C.3/5
D.1/8
Answer: B.1/3
Explanation: B
1/3
This is a famous question in understanding conditional probability, which simply means that given some information you might be able to get a better estimate.
The following are possible combinations of two children that form a sample space in any earthly family:
Boy - Girl
Girl - Boy
Boy - Boy
Girl - Girl
Since we know one of the children is a boy, we will drop the girl-girl possibility from the sample space.
This leaves only three possibilities, one of which is two boys. Hence the probability is 1/3
Question: A train covers a distance of 12 km in 10 min. If it takes 15 sec to pass a telegraph post, then the length of the train is?
A.250 m
B.300 m
C.120 m
D.200 m
Answer: B.300 m
Explanation: Speed = (12/10 * 60) km/hr
= (72 * 5/18) m/sec
= 20 m/sec.
Length of the train
= 20 * 15
= 300 m.
Answer:B
Question: Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?
A.10800
B.648
C.1800
D.2700
Answer: C.1800
Explanation: Let the required number of bottles be x.
More machines, More bottles (Direct Proportion)
More minutes, More bottles (Direct Proportion)
Machines	6: 10 :: 270 : x
Time (in minutes)	1	:	4
6 x 1 x x = 10 x 4 x 270
x =	(10 x 4 x 270)/(6)
x = 1800.
Answer is C.
Question: What is the twenty-eighth decimal to the right in the fraction 32/33?
A.1
B.2
C.4
D.6
Answer: D.6
Explanation: 32/33 = 0.96969696969696
The even-numbered decimal places are 6.
The answer is D.
Question: Aamir saves 32% of his monthly salary. If he spends Rs. 27200, then find his savings?
A.15400
B.14300
C.13200
D.12800
Answer: D.12800
Explanation: Let the monthly salary of Aamir be Rs. x.
68% of x = 27200
=> x = (27200 * 100)/68 = 40000
His savings = 32/100 * 40000 = 12800.
ANSWER:D
Question: The length of the bridge, which a train 130 m long and traveling at 45 km/hr can cross in 30 sec is?
A.247 m
B.275 m
C.245 m
D.285 m
Answer: C.245 m
Explanation: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (130 + x)/30 = 25/2
x = 245 m.
Answer: C
Question: what is rate of interest if principal.amount be 400,simple interest 180 and time 2year.
A.10
B.12.5
C.25
D.22.5
Answer: D.22.5
Explanation: s.i=(p*r*t)/100
180=800r/100
r=180/8=22.5%
answer D
Question: If a population of women in a town is 90% of men . What is the population of men as a % of population of women ?
A.108 %
B.105%
C.111%
D.112%
Answer: C.111%
Explanation: We're told that the number of Women in a town is equal to 90% of the number of Men in that town.
IF....
Men = 10
Women = 9
We're asked for the number of Men, as a percentage of the number of Women.
M/W = 10/9 = 1 1/9 = 1.111111 = 111%
ANSWER:C
Question: A clock shows the time as 3:30 P.m. If the minute hand gains 2 minutes every hour, how many minutes will the clock gain by 3 a.m.?
A.23 Minutes
B.24 Minutes
C.25 Minutes
D.26 Minutes
Answer: A.23 Minutes
Explanation: if the minute hand gains 2 minutes in 1 hour the from 3:30 p.m-4:00 p.m it gains 1 min
then from 4:00p.m-3:00 a.m =11*2=22 total=23
ANSWER:A
Question: $200 is divided amongst A,B and C so that A may get 2/3 as much as B and C together, B may get 6/9 as much as A and C together, then the share of A is
A.$80
B.$50
C.$25
D.$200
Answer: A.$80
Explanation: A:(B+C) = 2:3
A's share = 200*2/5 = $80
Answer is A
Question: Find the C.I. on a sum of Rs.2000 for 6 months at 20% per annum, interest being compounded quarterly?
A.205
B.305
C.3025
D.5540
Answer: A.205
Explanation: C.I.= 2000(21/20)^2-1800
= 205
Answer: A
Question: If there are 2 wheelers and 4 wheelers parked in a school located at the heart of the city, find the number of 4 wheelers parked there if there were 58 wheels are parked there
A.10
B.33
C.22
D.21
Answer: A.10
Explanation: let 2x be the number of cycles(2 wheelers) and 4x be the number of 4 wheelers.
2x+4y=58
make use of options given. compute options with y value since we need to find out numb of 4 wheelers...if we give 10 to y then equation becomes 2x+40=58 n 9 two wheelers..other options exceeds the total value
ANSWER:A
Question: If X:Y = 8:9 and Y:Z = 5:2 then X:Y:Z is
A.40:45:18
B.40:45:19
C.40:42:18
D.41:45:18
Answer: A.40:45:18
Explanation: Solution:
X/Y = 8/9;
Y/Z = 5/2;
X:Y:Z = 8*5:9*5:9*2 = 40:45:18
Answer: Option A
Question: A shopkeeper loses 15%,if an article is sold for Rs. 170. What should be the selling price of the article to gain 20%?
A.s.247
B.s.248
C.s.240
D.s.229
Answer: C.s.240
Explanation: Given that SP = Rs. 170 and loss = 15%
CP = [100(SP)]/(100 - l%) = (100 * 170)/85 = 20 * 6
= Rs. 200.
To get 20% profit, New SP = [(100 + p%)CP]/100
= (200 * 120)/100
= Rs.240
Answer:C
Question: Machine A can do a certain job in 8 hours. Machine B can do the same job in 10 hours. Machine C can do the same job in 12 hours. All three machines start the job at 9:00 a.m. Machine A breaks down at 11:00 a.m., and the other two machines finish the job. Approximately what W time will the job be finished?
A.Noon
B.12:30 p.m.
C.1:00 p.m.
D.1:30 p.m.
Answer: C.1:00 p.m.
Explanation: Ans: C (1:00pm)
From 9:00-11:00c(2 hrs)
A can do 1/8 Job/hr. so in 2 hours he can do 1/4 job.
B can do 1/10 job/hr so in 2 hrs. he can do 1/5 Job.
C can do 1/12 job/hr so in 2 hours he can do 1/6 job.
Total = 1/4+1/5+1/6 = 37/60 Job
Now balance work needs to be done by B and C.
Balance Work= 23/60 Job
Combined rate of B and C = 1/10+1/12 = 11/60 job/hr.
So they will do 22/60 work in 2 hrs (approx. to the balance work of 23/60)
Hence the Job will be completed 2hrs. after 11:00 i.e. @ 1:00pm=W
Ans: C (1:00pm)
Question: To furnish a room in a model home an interior decorator is to select 2 chairs and 2 tables from the collection of chairs and tables in a warehouse that are all different from each other. If there are 5 chairs in the warehouse and if 150 different combinations are possible, how many tables t are there in the warehouse?
A.6
B.8
C.10
D.15
Answer: A.6
Explanation: Total number of ways to choose 2 chairs from 5 t= 5C2=10
Total number of combination=150
That means we need get 15 combinations from the selection of tables....
Screening through the answers.... 6C2=15..... 15*10=150
Answer is 6... A
Question: 0.012 x 0.5 = ?
A.0.0006
B.0.06
C.0.6
D.0.006
Answer: D.0.006
Explanation: 12 x 5 = 60.
Sum of decimal places = 4
0.012 x 0.5 = 0.006
Answer: Option D
Question: If y is the smallest positive integer such that 7350 multiplied by y is the square of an integer, then y must be
A.2
B.5
C.6
D.7
Answer: C.6
Explanation: i just tried plugging in the numbers and found out that
6*7350 = 44, 100, which is a square of 210
C
Question: Numbers greater than 1000 but not greater than 4000 which can be formed with the digits 0, 1, 2, 3, 4 (repetition of digits is allowed), are.
A.350
B.375
C.450
D.576
Answer: B.375
Explanation: Explanation :
Numbers greater than 1000 and less than or equal to 4000 will be of 4 digits and will have either 1 (except 1000) or 2 or 3 in the first place with 0 in each of remaining places.
After fixing 1st place, the second place can be filled by any of the 5 numbers. Similarly third place can be filled up in 5 ways and 4th place can be filled up in 5 ways. Thus there will be ways in which 1 will be in first place but this include 1000 also hence there will be 124 numbers having 1 in the first pl
Answer : B
Question: Avg cost of 2 biscuitss and 4 choclates isRs. 60.The avg cost of 4 biscuitss and 6 choclates is Rs.100.Find the total cost of 20 biscuitss and 20 choclates?
A.90
B.180
C.150
D.200
Answer: D.200
Explanation: Avg cost of 2 biscuitss and 4 choclates is Rs. 60
(2 biscuits + 4 choclates) 6=60
therefore 1 biscuits cost is 60/6=10, so 2 biscuits cost is 2x10=20 and 4 choclates cost is 4x10=40
Again, avg cost of 4 biscuitss and 6 choclates is Rs.100
(4 biscuits + 6 choclates) 10=100
therefore 1 biscuits cost is 100/10=10, so 4 biscuits cost is 4x10=40 and 6 choclates cost is 6x10=60
So 20 biscuits cost is (20/a)=200 and 20 choclates cost is (20x10)=200
ANSWER:D
Question: The difference between C.I. and S.I. on an amount of $20,000 for 2 years is $98. What is the rate of interest per annum?
A.9%
B.8%
C.7%
D.6%
Answer: C.7%
Explanation: $98 is the interest on the first year of interest.
Let x be the interest rate.
The interest after the first year is 20000*x.
The interest on the first year's interest is 20000*x*x
20000*x^2 = 98
x = 0.07
The answer is C.
Question: Two trains 131 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
A.7.18
B.7.12
C.7.21
D.7.34
Answer: D.7.34
Explanation: T = (131 + 165)/ (80 + 65) * 18/5
T = 7.34
Answer:D
Question: For 15 people each has to pay Rs.20.For 20 people each has to pay Rs.18. For 40 people--how much has each to pay?
A.5
B.10
C.15
D.20
Answer: B.10
Explanation: 15-->20
20-->18
25-->16
30-->14
35-->12
40-->10
ANSWER:B
Question: The number of meters in EB is equal to the square root of the number of centimeters in EB. What is the length of EB (1 meter=100 centimeters)?
A.100 meters
B.10 meters
C.100 centimeters
D.10 centimeter
Answer: A.100 meters
Explanation: I'd plug in the options for this question.
Check option A: if the number of meters in EB is 100, then the number of centimeters is 100*100. The square root of 100*100 is 100: 100 = 100.
Answer: A.
Question: A business executive and his client are charging their dinner tab on the executive's expense account.The company will only allow them to spend a total of 50$ for the meal.Assuming that they will pay 7% in sales tax for the meal and leave a 20% tip,what is the most their food can cost?
A.39.55$
B.40.63$
C.38.63$
D.37.88$
Answer: C.38.63$
Explanation: let x is the cost of the food
1.07x is the gross bill after including sales tax
1.20* 1.07x=50
x=37.88
Hence, the correct option is C
Question: A train 400 m long can cross an electric pole in 10 sec and then find the speed of the train?
A.165 Kmph
B.144 Kmph
C.172 Kmph
D.175 Kmph
Answer: B.144 Kmph
Explanation: Length = Speed * time
Speed = L/T
S = 400/10
S = 40 M/Sec
Speed= 40*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 144 Kmph
ANSWER:B
Question: In 1982 and 1983, Company B’s operating expenses were $12.0 million and $15.0 million, respectively, and its revenues were $15.6 million and $18.8 million, respectively. What was the percent increase in Company B’s profit (revenues minus operating expenses) from 1982 to 1983 ?
A.3%
B.5 5/9%
C.25%
D.33 1/3%
Answer: B.5 5/9%
Explanation: Profit in 1982 = 15.6 - 12 = 3.6 million $
Profit in 1983 = 18.8 - 15 = 3.8 million $
Percentage increase in profit = (3.8-3.6)/3.6 * 100 %
= 5 5/9 %
Answer B
Question: A start walking from a place at a uniform speed of 5 kmph in a particular direction. After half an hour, B starts from the same place and walks in the same direction as A at a uniform speed and overtakes A after 1 hour 48 minutes. Find the speed of B.
A.4.7 kmph
B.5.6 kmph
C.4 kmph
D.7 kmph
Answer: B.5.6 kmph
Explanation: Distance covered by A in 30 min = 1 Km
B covers extra 1km in 1 hour 48 minutes (9/5 hr)
i.e. Relative speed of B over A = 1/(9/5) = 5/9
So the speed of B = Speed of A + 5/9
= 5 + 5/9
= 5.55
Answer B
Question: The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is
A.87.5 km/h
B.66.5 km/h
C.42.5 km/h
D.32.5 km/h
Answer: A.87.5 km/h
Explanation: A
87.5 km/h
Question: what is the total number of factor of 16!
A.4376
B.5376
C.6376
D.7376
Answer: B.5376
Explanation: 16! = 2^15 * 3^6 * 5^3 * 7^2 * 11^1 * 13^1
total number of factors = (15+1)*(6+1)*(3+1)*(2+1)*(1+1)*(1+1) = 5376
ANSWER:B
Question: 123 typists typeed 984 papers in 1/15 hour. The number of papers typed for minute by a average typist is
A.7
B.2
C.4
D.5
Answer: B.2
Explanation: Explanation:
Use unitary method:
{1}{15} hours, 123 typists can type 984 paper
123 typists can type e \frac{984}{4} = 246 papers
1 typist can typefrac{246}{123} =2 papers [ Hint{1}{15} hours = 4 minutes]
Answer: B
Question: A project scheduled to be carried out over a single fiscal year has a budget of $12,600, divided into12 equal monthly allocations. At the end of the sixth month of that fiscal year, the total amount actually spent on the project was $6,580. By how much was the project over its budget?
A. $380
B. $540
C. $280
D. $1,380
Answer: C. $280
Explanation: Difficulty level: 600
Each month's budget = 12600/12 = 1050
Budget for 6 months = 6*1050 = 6300
Actual amount spent = 6580
Amount spent over the budget = 6580 - 6300 = 280
Answer (C),
Regards,
Question: If a 10 percent deposit that has been paid toward the purchase of a certain product is $110, how much more remains to be paid?
A.$880
B.$990
C.$1,000
D.$1,100
Answer: B.$990
Explanation: 10/100P = 110 >> p= 110*100/10 = 1100
1100 - 110 = 990
ANSWER:B
Question: An alloy weighing 18 ounces is 70 percent gold. How many ounces of pure gold must be added to create an alloy that is 90 percent gold?
A.6
B.90
C.12
D.24
Answer: B.90
Explanation: In 24 ounces, gold is 18 * (70/100) = 12.6 ounces. Now we add x ounces of pure gold to make it 90% gold.
So 12.6 + x = (24 + x)* 90/100 => x =90.
Answer is B.
Question: A box contains six bulbs out of which 3 are defective. If three bulbs are chosen at random, find the probability that all the three bulbs are defective?
A.1/12
B.1/20
C.1/29
D.1/36
Answer: B.1/20
Explanation: Out of six, three are good and three are defective. Required probability
= 3C3/6C3
= 1/20
Answer:B
Question: The ratio of the ages of Mini and Minakshi is 4 : 3. The sum of their ages is 35 years. The ratio of their ages after 8 years will be
A.28 : 23
B.6 : 11
C.5 : 4
D.3 : 5
Answer: A.28 : 23
Explanation: Let Mini’s age = 4x and Minakshi’s age = 3x
Then 4x + 3x= 35
x = 5
Mini’s age = 20 years
And Minakshi’s age = 15 years
Ratio of their ages after 8 years = (20 + 8) : (15 + 8) = 28 : 23
ANSWER:A
Question: Who is to the immediate right of E?
A.221
B.II only
C.I and II
D.I and III
Answer: A.221
Explanation: Answer:A
Question: A Fruit store sells four varieties of Mangoes. A,B,C & D. IF A Costs 20% less than B, and C costs 25% less than A,and D costs 45% less than C what percent of B's cost is D?
A.40%
B.33%
C.44%
D.36%
Answer: B.33%
Explanation: Soln:-
B=100
A 20% less than B = 80
C 25% less than A = 60
D 45% less than C = 33
D is what percent of B = D/B * 100
= 33/100 * 100 = 33%
ANSWER:B
Question: Meg and Bob are among the 6 participants in a cycling race. If each participant finishes the race and no two participants finish at the same time, in how many different possible orders can the participants finish the race so that Meg finishes ahead of Bob?
A.24
B.30
C.360
D.90
Answer: C.360
Explanation: Total # of ways the race can be finished is 6!. In half of the cases Meg finishes ahead of Bob and in other half Bob finishes ahead of Meg. So, ways Meg to finish ahead of Bob is 6!/2=360.
Answer: C.
Question: A field of 40 meter long and 35 metre wide.The field is surronded by a path of uniform width of 2.5 metre runs round it on the outside.Find the Volume of the path?
A.Cannot be determine
B.400
C.500
D.100
Answer: A.Cannot be determine
Explanation: answer is option A.
we cannot determine the volume for the path.
Question: 54671 - 14456 - 33466 = ?
A.2449
B.5449
C.6749
D.6449
Answer: C.6749
Explanation: C
If we calculate we will get 6749
Question: Tea worth Rs.126 per kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs.157 per kg, the price of the third variety per kg will be
A.Rs.179.50
B.Rs.1700
C.Rs. 175.50
D.Rs. 180
Answer: A.Rs.179.50
Explanation: Solution
Since first second varieties are mixed in equal proportions, so their average price = Rs.(126+135/2) = Rs.130.50
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1. We have to find x.
x-157/22.50 = 1 =â€º x - 157 = 22.50 =â€º x=179.50.
Hence, price of the third variety = Rs.179.50 per kg.
Answer A
Question: Two positive integers differ by 4, and sum of their reciprocals is 1. Then one of the numbers is
A.2
B.b) 1
C.c) 5
D.d) 21
Answer: A.2
Explanation: Algebraic approach:
Let n be the smaller integer => 1/n + 1/(n+4) = 1 or ((n+4)+n)/n(n+4) =1 or n^2+4n =2n+4 or n=2 as n cannot be -negative
Solve for n => n=2. Hence,
A
Question: 60 percent of movie theatres in Town X have 1 screens or less. 20% of those theatres sell an average of more than $300 worth of popcorn per showing. 56 percent of all the movie theatres in Town X sell $300 or less of popcorn per showing. What percent of all the stores on the street have 4 or more screens and sell an average of more than $300 worth of popcorn per day?
A.12
B.18
C.32
D.40
Answer: D.40
Explanation: Lets take numbers here.
Assume that the total number of movie theaters in the town = 100
Then number of movie theaters with 3 screens or less = 60
=> Number of movie theaters with 4 screens or more = 40
Movie theaters with 3 screens or less selling popcorn at more than $300 = 20% of 60 = 12
Number of movie theaters selling popcorn at $300 or less = 56
=> Number of movie theaters selling popcorn at more than $300 = 100-56 = 44
Of these 44 theaters, 12 are those with 3 screens or less
Therefore 40 (44-12) must be those with four screens or more
D is the answer