RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A bat is bought for Rs.400 and sold at a gain of 15% find its selling price?
A.s.460/-
B.s.480/-
C.s.500/-
D.s.520/-
Answer: A.s.460/-
Explanation: 100 % ------> 400 (100 * 4 = 400)
115 % ------> 460 (120 * 4 = 460)
Selling price = Rs.460/-
Option 'A'
Question: If 17^4*13^4*9^4*8^4 = x, what is the units digit of x ?
A.8
B.3
C.6
D.7
Answer: C.6
Explanation: 17^4*13^4*9^4*8^4 = x
Units digit of x will be
7^4 * 3^4 * 9^4*8^4
=1 * 1 * 1 * 6
=6
Therefore , units digit of x = 6
Answer C
Question: If A:B is 2:3 and B:C is 3:4 then A:C is equal to
A.2:3
B.6:7
C.5:6
D.1:2
Answer: D.1:2
Explanation: Since A:B = 2:3 and B:C = 3:4,
We can deduce that A:B:C = 2:3:4
So, A:C = 2:4 = 1:2.
D is the correct answer.
Question: The average age of 17 persons in a office is 15 years. Out of these, the average age of 5 of them is 14 years and that of the other 9 persons is 16 years. The age of the 15th person is?
A.39
B.41
C.45
D.42
Answer: B.41
Explanation: Age of the 15th student = 17*15 - (14*5+16*9) = 255-214 = 41 years
Answer is B
Question: A particular parking garage is increasing its rates by 10 percent per month. Bob decides to reduce the number of days he uses the garage per month so that the amount he spends at the garage per month remains unchanged. Which of the following is closest to Bob’s percentage reduction in the number of days he uses the garage each month?
A.8%
B.9%
C.10%
D.11%
Answer: B.9%
Explanation: Let x be the original number of days that Bob used the garage.
Let P be the original cost per day.
Let N*x be the new number of days that Bob uses the garage.
N*x*1.1P = x*P
N*x = x/1.1 which is about 0.91x, thus a 9% reduction.
The answer is B.
Question: Pablo plays 3 rounds of a game, in which his chances of winning each round are 1/3, 1/4, and 1/n, respectively. If n ≠ 0, what is the probability that Pablo wins the first two rounds, but loses the third?
A.1/9n
B.(n-1)/12n
C.1/6n
D.(n+2)/3n
Answer: B.(n-1)/12n
Explanation: 1/3 * 1/4 * (1-1/n)
= 1/12 * (n-1)/n
= (n-1)/12n
Answer - B
Question: A merchant gets a 5% discount on each meter of fabric he buys after the first 2,000 meters and a 7% discount on every meter after the next 1,500 meters. The price, before discount, of one meter of fabric is $2, what is the total amount of money the merchant spends on 6,500 meters of fabric?
A.$11,320
B.$12,430
C.$13,540
D.$14,650
Answer: B.$12,430
Explanation: For first 2000 meters he does not get any discount.
The price is 2*2000 = $4000
For next 1500 meters, he gets a 5% discount.
The price is 1.9*1500 = $2850
For the next 1500 meters, he gets a 7% discount.
The price is 1.86*3000 = $5580
The total price is $4000 + $2850 + $5580 = $12,430
The answer is B.
Question: If an article with marked price of $420 is sold at successive discount of 10%,25% and 15%,what is the price the customer has to pay?
A.360
B.247
C.239
D.268
Answer: C.239
Explanation: discount=0.9*.75*.85=.57
so .57*420=230
ANSWER:C
Question: If any amount is distributed among A ,B and C so that the part of A is doubled that of the part of B and part of b is 5 time the part of C .Find the ratio among their parts.
A.10:5:1
B.1:4:1
C.8:4:1
D.2:4:1
Answer: A.10:5:1
Explanation: By the assumptions as mentioned we have A=2B and B=5C. So A=2(5C) and we get A=10C. We have, therefore, A:B:C = 10C:5C:C. By cancelling the ratio with C we have 10:5:1. The answer is, therefore, A.
Question: If y is an integer, then the least possible value of |23 - 4y| is
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: We know that 4y is a multiple of 4, so let’s first look at the multiples of 4 closest to 23. We have “20” and “24”. Let’s subtract both of these from 23 and see which one produces the smallest result. When 4y = 20, y is 5 and when 4y = 24, y is 5. Let’s start with letting y = 4.
|23-4(5)|
|23-20|
|3| = 3
Next, let’s let y equal 5.
|23-4(6)|
|23-24|
|-1| = 1
We see that the smallest possible value of |23-4y| is 1.
Answer A.
Question: Trapezoid JKLM in the x-y plane has coordinates J = (–2, –4), K = (–2, 2), L = (6, 8), and M = (6, –4). What is its perimeter?
A. 34
B. 36
C. 38
D. 40
Answer: B. 36
Explanation: JK = 6
LM = 12
KL =using distance formula 10
JM = using distance formula 8
Sum of all is 36
B
Question: An escalator moves towards the top level at the rate of 12 ft.sec and its length is 150 feet. If a person walks on the moving escalator at the rate of 3 feet per second towards the top level, how much time does he take to cover the entire length.
A.10sec
B.20sec
C.15sec
D.16sec
Answer: A.10sec
Explanation: Explanation :
Time taken to cover the entire length = tot.dist/resultant speed = 150/ (12+3) = 10sec
Answer : A
Question: 10 books are placed at random in a shelf. The probability that a pair of books will always be together is?
A.1/5
B.1/10
C.1/11
D.3/10
Answer: A.1/5
Explanation: 10 books can be rearranged in 10! ways consider the two books taken as a pair then number of favourable ways of getting these two books together is 9! 2!
Required probability = 1/5
A)
Question: A 70 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?
A.20
B.99
C.88
D.77
Answer: B.99
Explanation: 1: 2/5 = 5: 2
2/7 * 70 = 20
Answer: B
Question: In a certain Parallelogram the degree measure of one angle exceeds that of the other by 40 what is the degree measure of the smaller angle?
A.70
B.80
C.85
D.90
Answer: A.70
Explanation: In a parallelogram opposite angles are equal and the angles at each side are supplementary to each other (supplementary angles are two angles that add up to 180°).
Given: x+(x+40)=180 --> x=70.
Answer: A.
Question: Five drainage pipes, each draining water from a pool at the same constant rate, together can drain a certain pool in 12 days. How many additional pipes R, each draining water at the same constant rate, will be needed to drain the pool in 4 days?
A. 6
B. 9
C. 10
D. 12
Answer: C. 10
Explanation: This is an inverse proportional problem......
5 pipes in 12 days; So for 4 days, it will be = 12 x 5 / 4 = 15
So, R=15-5 = 10.C
Question: The difference between a 7 digit number and the number formed by reversing its digit is not a multiple of
A.121
B.11
C.9
D.10
Answer: A.121
Explanation: Another approach is to TEST a number.
Let's say the original number is 1231231
So, the REVERSED number is 1321321
The DIFFERENCE = 1321321-1231231 =90090
No check the answer choices
90090 is a multiple of 3,9,10,11
121 is NOT a multiple of 90090
Answer:A
Question: The unit digit in the product (115 * 297 * 196 * 108) is:
A.2
B.7
C.6
D.0
Answer: D.0
Explanation: Explanation:
Unit digit in the given product = Unit Digit in (5*7*6*8) = 0
ANSWER: D
Question: Two numbers A and B are such that the sum of 5% of A and 2% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B.
A.2 : 1
B.1 : 2
C.4 : 3
D.10 : 3
Answer: D.10 : 3
Explanation: Explanation:
5% of A + 2% of B = 2/3(6% of A + 8% of B)
5A/100 + 2B/100 = 2/3(6A/100+8B/100)
⇒5A + 2B = 2/3(6A + 8B)
⇒15A + 6B = 12A + 16B
⇒ 3A = 10B
⇒ AB = 10/3
⇒ A:B=10:3
Answer: Option D
Question: Source: Knewton
A cyclist's speed varies, depending on the terrain, between 5.0 miles per hour and 14.0 miles per hour, inclusive. What is the maximum distance, in miles, that the cyclist could travel in 7 hours?
A. 42
B. 56
C. 70
D. 98
Answer: D. 98
Explanation: We are told that:generallya cyclist's speed varies, depending on the terrain, between 5.0 miles per hour and 14.0 miles per hour, inclusive. Is it possible the cyclist to travel with maximum speed for some time? Why not, if there is right terrain for that. So, if there is long enough terrain for the maximum speed of 14 mph then the maximum distance, in miles, that the cyclist could travel in 7 hours would be 7*14=98 miles.
Answer: D.
Question: In an examination, 35% candidates failed in one subject and 43% failed in another subject while 15% failed in both the subjects. If 2500 candidates appeared at the end of the examination how many passed in either subject but not in both?
A.975
B.1020
C.1175
D.1200
Answer: D.1200
Explanation: Failed in 1st subject = 35*2500/100 = 875
Failed in 2nd subject = 43*2500/100 = 1075
Failed in both = 15*2500/100 = 375
Failed in 1st subject only = 875-375 = 500
Failed in 2nd subject only = 1075-375 = 700
Passed in either subject but not in both = 700+500 = 1200
Answer is D
Question: A and B starts a business with Rs.8000 each, and after 8 months, B withdraws half of his capital . How should they share the profits at the end of the 18 months?
A.18:11
B.18:13
C.23:12
D.11:9
Answer: B.18:13
Explanation: A invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 8 months and then withdraws Rs.4000. So, the investment of B for remaining 10 months is Rs.4000 only.
A : B
8000*18 : (8000*8) + (4000*10)
144000 : 104000
A:B = 18:13
ANSWER:B
Question: In a kilometer race, A beats B by 50 meters or 20 seconds. What time does A take to complete the race?
A.380 sec
B.190 sec
C.726 sec
D.127 sec
Answer: A.380 sec
Explanation: Time taken by B run 1000 meters
= (1000 * 20)/50 = 400 sec.
Time taken by A = 400 - 20
= 380 sec.
Answer: A
Question: A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long?
A.76 sec
B.89 sec
C.16 sec
D.14 sec
Answer: B.89 sec
Explanation: Speed = 240/24 = 10 m/sec.
Required time = (240 + 650)/10 = 89 sec.
Answer:B
Question: Three numbers are in the ratio 3:5:7. The largest number value is 42. Find difference between Smallest & largest number is?
A.24
B.26
C.28
D.30
Answer: A.24
Explanation: == 3:5:7
Total parts = 15
= The largest number value is 42
= The largest number is = 7
= Then 7 parts -----> 42 ( 7 * 6 = 42 )
= smallest number = 3 & Largest number = 7
= Difference between smallest number & largest number is = 7 - 3 = 4
= Then 4 parts -----> 24 (4 * 6 = 24)
A
Question: In the xy-coordinate system, line k passes through points (-8m, 0) and (0, 2m). Which of the following is a possible equation of line k?
A.y = -4x + 2m
B.y = 1/4*x - 8m
C.y = 4x + 2m
D.y = 1/4*x + 2m
Answer: D.y = 1/4*x + 2m
Explanation: The slope of the line is 2m/8m=1/4.
The y-intercept is 2m.
the equation of the line is: y = 1/4*x +2m
The answer is D.
Question: Find the median and mean of the following test scores:
75, 40, 100, 50, 45, 60, 50, 70, 45, 95
Which score falls in between the two scores?
A.40
B.50
C.60
D.70
Answer: C.60
Explanation: List in order: 40,45,45,50,50,60,70,75,95,100
The median = (the average of two middle terms) = (50 + 60)/2 = 55.
The mean = (the sum)/(# of terms) = 630/10 = 63.
The Test Score between 55 and 63 is 60.
Answer: C.
Question: A, B and C, each working alone can complete a job in 6, 8 and 12 days respectively. If all three of them work together to complete a job and earn $ 4680, what will be A's share of the earnings?
A.$1100
B.$520
C.$2080
D.$1170
Answer: C.$2080
Explanation: Explanatory Answer
A, B and C will share the amount of $4680 in the ratio of the amounts of work done by them.
As A takes 6 days to complete the job, if A works alone, A will be able to complete 1/6 th of the work in a day.
Similarly, B will complete 1/8th and C will complete 1/12th of the work.
So, the ratio of the work done by A : B : C when they work together will be equal to 1/6 : 1/8 : 1/12
Multiplying the numerator of all 3 fractions by 24, the LCM of 6, 8 and 12 will not change the relative values of the three values.
We get 24/6 : 24/8 : 24/12 = 4 : 3 : 2.
i.e., the ratio in which A : B : C will share $4680 will be 4 : 3 : 2.
Hence, A's share will be 4*4680/9 =2080.
correct choice is (C)
Question: How many terms are there in 2, 4, 8, 16,..., 4096?
A.14
B.11
C.12
D.10
Answer: C.12
Explanation: 2, 4, 8, 16, ..., 4096 is a G.P with a =2
and r =4/2 =2
Let the number of terms be n. Then
2 x 2 ^n-1 = 4096
or 2^n-1 = 2048 = 2^11
Thus n - 1 =11
n= 12
ANSWER:C
Question: A and B are two multiples of 14, and Q is the set of consecutive integers between A and B, inclusive. If Q contains 9 multiples of 14, how many multiples of 7 are there in Q?
A.20
B.19
C.18
D.17
Answer: D.17
Explanation: Lets Q's first number be 14
As per question, Q contains 9 multiples of 14 , so let Q's last number be 126. (14∗9)
We have,
a n = a+(n−1)d
Then
126 = 14 + (n-1)7
Solving for n , we get n = 17
ANSWER:D
Question: The length of a rectangle is 3 times its width. If the width of the rectangle is 5 inches, what is the rectangle's area, in square inches?
A.30 square inches
B.75 square inches
C.68 square inches
D.89 square inches
Answer: B.75 square inches
Explanation: If the width is 5 in and the length is 3 times the width, then the length is
3 * 5 = 15 in
The area is given by
5 * 15 = 75 square inches
correct answer B
Question: A speed of 20 metres per second is the same as :
A.72 km/hr
B.66 km/hr
C.60 km/hr
D.77.5 km/hr
Answer: A.72 km/hr
Explanation: Sol.
20 m/sec = [20 * 18/5] km/hr = 72 km/hr.
Answer A
Question: simplify : 3x - 5 + 23x - 9
A.2(14x-9)
B.2(13x-7)
C.(14-5x)
D.2(10-7x)
Answer: B.2(13x-7)
Explanation: 3x -5 +23x-9 , = 3x+23x - 5 - 9
= 26x - 14, = 2(13x - 7). correct answer : (B)
Question: A tea expert claims that he can easily find out whether milk or tea leaves were added first to water just by tasting the cup of tea. In order to check this claims 10 cups of tea are prepared, 5 in one way and 5 in other. Find the different possible ways of presenting these 10 cups to the expert.
A.252
B.240
C.300
D.340
Answer: A.252
Explanation: Solution:
Since, there are 5 cups of each kind, prepared with milk or tea leaves added first, are identical hence, total number of different people ways of presenting the cups to the expert is,
[10!/(5!�5!)]= 252
Answer: Option A
Question: A fort of 5000 soldiers has provisions for 125 days. After 25 days some of them left and the food was now enough for the same period of 125 days as before. How many of them left?
A.900
B.1000
C.1100
D.1200
Answer: B.1000
Explanation: 2000 ---- 50
5000 ---- 100
x ----- 125
x*125 = 5000*100
x=4000
5000
-------
1000
Answer: B
Question: A, B and C enter into a partnership. They invest Rs. 90,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. In what ratio will the profit be shared at the end of 3 years?
A.12 : 3 : 4
B.23 : 2 : 4
C.22: 2 : 1
D.27: 16 : 28
Answer: D.27: 16 : 28
Explanation: Sol.
A : B : C = (40000 * 36) : (80000 * 12 + 40000 * 24)
: (120000 * 24 + 40000 * 12) =324 : 192 : 336 = 27 : 16 : 28
Answer D
Question: A boy has 9 trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
A.100
B.102
C.104
D.108
Answer: D.108
Explanation: The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12 = 108 ways.
D
Question: If a#b = ab – b + b^2, then 2#3 =
A.2
B.8
C.12
D.21
Answer: C.12
Explanation: Solution -
Simply substitute 2 and 3 in equation in the place of a and b respectively.
2#3 = 2*3 - 3 + 3^2 = 6 - 3 + 9 = 12. ANS C
Question: A man’s speed with the current is 19 km/hr and the speed of the current is 2.5 km/hr. the man’s speed against the current is :
A.8.5 km/hr
B.9.5 km/hr
C.10 km/hr
D.14 km/hr
Answer: D.14 km/hr
Explanation: Solution
Man's rate in still water = (19-2.5) km/hr = 16.5 km/hr.
Man's rate against the current = (16.5-2.5) km/hr = 14 km/hr Answer D
Question: If p and y are positive integers such that p > y > 1, what is the remainder when 92p × 5p+y + 11y × 6py is divided by 10?
A.A.0
B.B.1
C.C.3
D.D.4
Answer: B.B.1
Explanation: 92p × 5p+y + 11y × 6py--1=B
Question: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 700 m?
A.148.75 m
B.127.5 m.
C.122.2 m
D.222.9 m
Answer: A.148.75 m
Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800
= 6300/8
= 787.5 m.
In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C.
In a race of 700 m, the number of meters by which A beats C = (700 * 212.5)/1000
= 148.75 m.
Answer:A
Question: If the ratio of apples to bananas is 4 to 3 and the ratio of bananas to cucumbers is 1 to 5, what is the ratio of apples to cucumbers?
A.4:15
B.1:3
C.2:5
D.4:5
Answer: A.4:15
Explanation: Apples : Bananas = 4:3
Bananas : Cucumbers = 1:5 = 3:15
So if I have Bananas, I'd have 4 apples and 15 cucumbers
Apples : Cucumbers = 4:15
Answer: A
Question: The average of 11 results is 42, if the average of first five results is 49 and that of the last seven is 52. Find the fifth result?
A.145
B.146
C.147
D.148
Answer: C.147
Explanation: 1 to 11 = 11 * 42= 462
1 to 5 = 5 * 49 = 245
5 to 11 = 7 * 52 = 364
5th = 245 + 364 – 462 = 147
ANSWER:C
Question: There is a 30 % chance of rain and a 70% chance of shine. If it rains there is a 50% chance that Bob will cancel his picnic but if the sun is shining he will definitely have his picnic. What is the chance that Bob will have his picnic?
A.70 %
B.75 %
C.80 %
D.85 %
Answer: D.85 %
Explanation: Chance of no picnic+chance of picnic= 100% ... (i)
Chance of picnic=100%-Chance of no picnic ... (ii)
Chance of no picnic= 50% of 30%= 15%
Therefore, According to (ii), Chance of picnic= 100%-15%= 85%.
Answer D
Question: The present ages of Lewis and Brown are in the ratio 1:2. Three years from now, the ages will be in the ratio 3:5. Find the present age of Lewis.
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: l:b=1:2 & (l+3):(b+3)=3:5
then 2l=b & 5l+15=3b+9
by solving above we get
l=6
ANSWER:D
Question: Today is John's birthday. Three years from today he will be twice as old as he was 14 years ago. How old is John today ?
A.29 years
B.26 years
C.28 years
D.31 years
Answer: D.31 years
Explanation: let John's age=xx+3=2(x-14)x=31ANSWER:D
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. In how much time will the trains cross each other?
A.80/8
B.80/7
C.80/5
D.80/3
Answer: B.80/7
Explanation: Relative speed = (54 + 72)* 5/18 = 7 * 5 = 35 mps.
The time required = d/s = (100 + 100 + 200)/35
= 400/35 = 80/7 sec.
Answer: B
Question: A 16% stock yielding 14% is quoted at:
A.s. 83.33
B.s. 110
C.s. 114
D.s. 120
Answer: C.s. 114
Explanation: Income of Rs 14 on investment of Rs 100
Income of Rs 16 on investment of ?
= (16*100)/14=114
ANSWER:C
Question: If 15% of a class averages 100% on a test, 50% of the class averages 78% on the test, and the remainder of the class averages 63% on the test, what is the overall class average? (Round final answer to the nearest percent).
A.76%
B.77%
C.78%
D.79%
Answer: A.76%
Explanation: This question is a Weighted Average question with a series of dependent variables.
The remaining portion of the class represents 100% - 15% - 50% = 35% of the class
Converting the portions of the class population to decimal weights, we find:
Class Average = 0.15x100 + 0.50x78 + 0.35x63 = 76.05
The class average (rounded) is 76%
Final Answer
A) 76%
Question: 7 carpet-weavers can weave 7 carpets in 7 days. At the same rate, how many carpets would be woven by 14 carpet-weavers in 14 days?
A.14
B.28
C.21
D.35
Answer: B.28
Explanation: Explanation :
Solution: Let the required number of carpets be x.
More weavers, more carpets (Direct proportion)
more days, more carpets (Direct proportion)
weavers 7 :14
} : : 7 : x
days 7 : 14
.'. 7*7*x = 14*14*7 <=> x = 14*14*7/7*7 = 28.
Answer : B
Question: The average of 35 students in a class is 16 years. The average age of 21 students is 14. What is the average age of remaining 14 students?
A.16 years
B.76 years
C.14 years
D.19 years
Answer: D.19 years
Explanation: Sum of the ages of 14 students
= (16 * 35) - (14 * 21) = 560 - 294 = 266
Required average = (266/14) = 19 years.
Answer: D
Question: A train , having a length of 110 meter is running at a speed of 60 kmph. In what time, it will pass a man who is running at 6 kmph in the direction opposite to that of the train
A.4 sec
B.2 sec
C.6 sec
D.8 sec
Answer: C.6 sec
Explanation: Distance = 110 m
Relative speed = 60+6 = 66 kmph (Since both the train and the man are in moving in opposite direction)
= 66×10/36 mps = 110/6 mps
Time = distance/speed = 110/(110/6) = 6 s
Answer is C.
Question: In what time a sum of money double itself at 7% per annum simple interest?
A.33 1/8%
B.33 1/3%
C.14 2/7%
D.33 4/3%
Answer: C.14 2/7%
Explanation: P = (P*7*R)/100
R = 14 2/7%
Answer:C
Question: Find the ratio in which rice at Rs.7.20 a kg be mixed with rice at Rs.5.60 a kg to produce a mixture worth Rs.6.30 a kg?
A.1 : 3
B.2 : 3
C.3 : 4
D.7 : 9
Answer: D.7 : 9
Explanation: Solution
Required ratio = 70 : 90 = 7 : 9
Answer D
Question: If x is 20 percent greater than 88, then x =
A.68
B.70.4
C.86
D.105.6
Answer: D.105.6
Explanation: X is 20% greater than 88 means X is 1.2 times 88 (in other words 88 + 20/100 * 88 = 1.2 * 88)
Therefore, X = 1.2 * 88 = 105.6
ANSWER:D
Question: There are 300 seniors at Morse High School, and 40% of them have cars. Of the remaining grades (freshmen, sophomores, and juniors), only 10% of them have cars. If 20% of all the students at Morse have cars, how many students are in the three lower grades?
A.600
B.900
C.1200
D.1350
Answer: A.600
Explanation: Let x be the number of students in the lower three grades.
0.1x + 120 = 0.2(x+300)
0.1x = 60
x = 600
The answer is A.
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 5 boys when a boy gets any no. of prizes?
A.55
B.58
C.25
D.65
Answer: C.25
Explanation: Ans.(C)
Sol. In this case, repetitions are allowed, so all the three prizes can be given in 4 ways, i.e. (5x5) ways = 52 ways = 25 ways Or nr ways = 52 ways = 25 ways
Question: When positive integer N is divided by positive integer J, the remainder is 28. If N/J = 154.04, what is value of J?
A.400
B.350
C.700
D.750
Answer: C.700
Explanation: When a number is divided by another number, we can represent it as : Dividend = Quotient * Divisor + Remainder
So, Dividend/Divisor = Quotient + Remainder/Divisor
Given that N/J = 154.04
Here 154 is the quotient.
Given that Remainder = 28
So, 154.04 = 154 + 28/J
So, J = 700
Answer: C
Question: A man recites the alphabet N times. What is the equation for the amount of every odd letter he said?
A.25/2*N
B.13N
C.27/2*N
D.26N
Answer: A.25/2*N
Explanation: 13N is th Answer A
Question: The ratio of a compound, by weight, consisting only of substances x, y, and z is 4:6:10,
respectively. Due to a dramatic increase in the surrounding temperature, the composition of the
compound is changed such that the ratio of x to y is halved and the ratio of x to z is tripled. In the
changed compound, if the total weight is 116 lbs, how much does substance x weigh?
A.48
B.36
C.24
D.12
Answer: C.24
Explanation: x:y=4:6
if the ratio is halevd then x:y=2:6
The old ratio of x to z was 4:10. If this ratio is tripled, then the new ratio of x to z is 12:10.
x:y=2:6=12:36 ( multiplied the ration with 6/6 to have a common co eff x in both the rations x:y and x:z)
so x:y:z= 12:36:10
and we know x + y + z = 116 lbs
from the ratio of x ,y and z we have x=12k y=36k z=10K
put it in the equation we have 12k+36k+10k=116
k=2
Hence x=12(2)=24
Ans C
Question: Albert buys 4 horses and 9 cows for Rs. 13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs. 1880. The cost of a horse is?
A.1299
B.2788
C.2000
D.2981
Answer: C.2000
Explanation: Explanation:
Let C.P. of each horse be Rs. x and C.P. of each cow be Rs. y.
Then, 4x + 9y = 13400 -- (i)
And, 10% of 4x + 20% of 9y = 1880
2/5 x + 9/5 y = 1880 => 2x + 9y = 9400 -- (ii)
Solving (i) and (ii), we get : x = 2000 and y = 600.
Cost price of each horse = Rs. 2000.
Answer: C