RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: How many cubes of 4 cm edge can be put in a cubical box of 1 m edge.
A.17725 cm
B.15625 cm
C.12786 cm
D.12617 cm
Answer: B.15625 cm
Explanation: Number of cubes =100âˆ—100âˆ—100/4*4*4=15625
Note: 1 m = 100 cm
Answer:B
Question: Rita and Sam play the following game with n sticks on a table. Each must remove 1,2,3,4, or 5 sticks at a time on alternate turns, and no stick that is removed is put back on the table. Tha one who removes the last stick (or sticks) from the table wins. If Rita goes first, which of the following is a value of n such that Sam can always win no matter how Rita plays?
A.7
B.10
C.11
D.12
Answer: D.12
Explanation: If the number of sticks on a table is a multiple of 6, then the second player will win in any case (well if the player is smart enough).
Consider n=6, no matter how many sticks will be removed by the first player (1, 2, 3 ,4 or 5), the rest (5, 4, 3, 2, or 1) can be removed by the second one.
The same for n=12: no matter how many sticks will be removed by the first player 1, 2, 3 ,4 or 5, the second one can remove 5, 4, 3, 2, or 1 so that to leave 6 sticks on the table and we are back to the case we discussed above.
Answer: D.
Question: Aparna cuts a cake into two halves and cuts one-half into smaller pieces of equal size. Each of the small pieces is twenty grams in weight. If she has seven pieces of the cake in all with her, how heavy was the original cake?
A.140 grams
B.280 grams
C.240 grams
D.120 grams
Answer: C.240 grams
Explanation: one cake =1/2 + 1/2
1/2------6 pieces
total pieces = (1/2)cake +(6 pieces of 1/2) = 7 pieces
then 6 small picese weight = half piece cake
So 2*(6*20) =240
ANSWER:C
Question: Steve traveled the first 2 hours of his journey at 50 mph and the last 3 hours of his journey at 80 mph. What is his average speed of travel for the entire journey?
A.60 mph
B.68 mph
C.53.33 mph
D.64 mph
Answer: B.68 mph
Explanation: Answer
Average speed of travel = Total distance travelled/Total time taken
Total distance traveled by Steve = Distance covered in the first 2 hours + distance covered in the next 3 hours.
Distance covered in the first 2 hours = speed * time = 50 * 2 = 100 miles.
Distance covered in the next 3 hours = speed * time = 80 * 3 = 240 miles.
Therefore, total distance covered = 100 + 240 = 340 miles.
Total time taken = 2 + 3 = 5 hours.
Hence, average speed = Total distance travelled/Total time taken=340/5 = 68 miles per hour.
Choice B
Question: In a rectangular coordinate system, what is the area of a rhombus whose vertices have the coordinates (0, 3.5), (10, 0), (0, -3.5), (-10, 0)?
A.56
B.88
C.70
D.116
Answer: C.70
Explanation: Area of rhombus= 1/2* D1 *D2
Length of 1st diagonal = 10+10= 20
Length of 2nd diagonal= 3.5+3.5= 7
Area= 1/2*20*7= 70
C is the answer
Question: Two painters 'P1' & 'P2' paint the bungalow in 3 days. If P1 alone can paint the bungalow in 12 days, in how many days can 'P2'' alone complete the same paint work?
A.4 days
B.6 days
C.9 days
D.12 days
Answer: A.4 days
Explanation: EXPLANATION:
Hint:
If a person can do a part of work in 'n' days, then person's work in 1 day =	1/n
As painters P1 & P2 paint the bungalows in 3 days, then work done by both painters =	1/3
As P1 paint it alone in 12 days, then work done by painter P1 =	1/12
Work done by painter P2 =	1/3	–	1/12	=	4 – 1/12	=	3/12	=	1/4
Therefore, same work will be completed by painter P2 in 4 days.
ANSWER IS A
Question: Let q represent the integer length of a side of a triangle. If r represents the number of distinct values for q such that we can create a triangle with lengths q, 12, and 16, what is the value of r?
A.18
B.20
C.22
D.23
Answer: D.23
Explanation: From the triangle inequality rule, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. So, the three inequalities are:
1. q + 12 > 16
2. 12 + 16 > q
3. q + 16 > 12
Equation 3 is true for any positive value of q.
From equation 1, q > 4
From equation 2, 28 > q
Then 28 > q > 4 so q can be any value from 5 to 27 inclusive.
The number of possible values is 23.
The answer is D.
Question: A number when successively divided by 3,5 and 8 leaves remainders 1,4 and 7 respectively. Find the respective remainders Q when the order of the divisors is reversed.
A.8,5,3
B.4,2,1
C.Q=3,2,1
D.Q=6,4,2
Answer: D.Q=6,4,2
Explanation: My approach would be
Three Divisors: 3, 5, 8
Three Remain: 1, 4, 7
Start from the bottom of the last column i.e. from the third remainder:
Go up diagonally and multiply by the second divisor: 5*7 = 35
Go down and add the second remainder: 35 + 4 = 39
Go up diagonally and multiply by the first divisor: 39* 3 = 117
Go down and add the first remainder: 117 + 1 = 118
Divide 118 by 8, 5, 3
118/8 gives quotient = 14 and remainder = 6
14/5 gives quotient = 2 and remainder = 4
2/3 gives quotient = 0 and remainder = 2
Ans is D i.e. 6,4,2
Question: If the numerator of a fraction is increased by 50% and denominator by 20%, the fraction become 9/15. What was the original fraction ?
A.12/25
B.13/25
C.3/5
D.6/7
Answer: A.12/25
Explanation: Explanation :
Let the fraction be x/y
We have 150x/120y = 9/15
= x/y = 12/25
Answer : Option A
Question: A 300 meter long train crosses a platform in 27 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
A.150m
B.278m
C.350m
D.228m
Answer: A.150m
Explanation: Speed = [300 / 18] m/sec = 50/3 m/sec.
Let the length of the platform be x meters.
Then, x + 300 / 27
= 50/3
3(x + 300)
= 1350 è x
= 150m.
Answer:A
Question: On June 1 a bicycle dealer noted that the number of bicycles in stock had decreased by 3 for each of the past 5 months. If the stock continues to decrease at the same rate for the rest of the year, how many fewer bicycles will be in stock on September 1 than were in stock on January 1?
A. 8
B. 12
C. 24
D. 32
Answer: C. 24
Explanation: Jan 1 = C
Feb 1 = C - 3
March 1 = C - 6
April 1 = C - 9
May 1 = C - 12
June 1 = C - 15
July 1 = C - 18
Aug 1 = C - 21
Sept 1 = C - 24
Difference between stock on September 1 than were in stock on January 1 will be -
C - ( C - 24 )= 24
Hence answer will be (C)
Question: If the cost price of 20 articles is equal to the selling price of 25 articles, what is the % profit or loss made by the merchant?
A.25% loss
B.20% loss
C.25% Profit
D.20% Profit
Answer: B.20% loss
Explanation: Let the cost price of 1 article be Rs. 1.
Therefore, cost price of 20 articles = 20 * 1 = Rs. 20
The selling price of 25 articles = cost price of 20 articles = Rs. 20.
Let us find the cost price of 25 articles.
Cost price of 25 articles = 25 * 1 = Rs. 25.
Therefore, profit made on sale of 25 articles = Selling price of 25 articles - cost price of 25 articles
= 20 - 25 = -Rs. 5.
Because the profit is in the negative, the merchant has made a loss of Rs.5.
Therefore, % loss = Loss /Cost Price∗100
% loss = 5/25∗100 =20% loss.
Answer : B
Question: 0---:-|---:--|-:--:-|--:---|-:----1
On the number line above, the segment from 0 to 1 has been divided into fifths, as indicated by the large tick marks, and also into sevenths, as indicated by the small tick marks. What is the LEAST possible distance W between any two of the tick marks?
A.1/70
B.1/35
C.2/35
D.1/12
Answer: B.1/35
Explanation: divisions are 0 1/7 2/7 3/7 4/7 5/7 6/7 1
1/5 2/5 3/5 4/5 5/5
expressing the same in terms of the lcm of 5,7 ,i.e 35
0 7/35 14/35 21/35 28/35 35/35
5/35 10/35 15/35 20/35 25/35 30/35
by comparing the divisions with each other we can see 1/35 is the shortest possible distance between any two selected divisions.
W=1/35
Answer is B.
Question: The average marks in mathematics scored by the pupils of a school at the public examination were 39. If four of these pupils who actually scored 5, 12, 15 and 19 marks at the examination had not been sent up, the average marks for the school would have been 44. Find the number of pupils sent up for examination from the school?
A.28
B.30
C.38
D.38
Answer: B.30
Explanation: 39x = 5 + 12 + 15 + 19 + (x – 4)44
x = 25
Answer:B
Question: 7^1+7^2+7^3+.......+7^205. Find out how many numbers present which unit place contain 3?
A.78
B.51
C.11
D.27
Answer: B.51
Explanation: Units digits of first 4 terms are 7, 9, 3, 1. and this pattern repeats. So for every 4 terms we get one term with 3 in its unit digit. So there are total of 205/4 = 51 sets and each set contains one terms with 3 in its unit digit.
Ans is 51.
Answer:B
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
A.19 sec
B.87 sec
C.36 sec
D.16 sec
Answer: C.36 sec
Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.
Answer: C
Question: The lowest number which should be added to 8247 so that the sum is exactly divisible by 5, 6, 7, 8 and 9 is:
A.1833
B.1853
C.1733
D.1233
Answer: A.1833
Explanation: L.C.M. of 5, 6, 7, 8 and 9 = 2520.
On dividing 8247 by 2520, the remainder is 687.
Number to be added = (2520 - 687) = 1833. Answer: Option 'A'
Question: A and B can do a piece of work in 5 days, B and C in 6 days, C and A in 7 days. How long will C take to do it?
A.260/19 days
B.240/23 days
C.220/17 days
D.200/19 days
Answer: B.240/23 days
Explanation: 2c = 1/6 + 1/7 – 1/5 = 23/210
c = 23/240 => 240/23 days
The answer is B.
Question: Annabelle was given a 8 m head start in a 100 m race with Gina. She won the race by 0.85 m. How many more meters would it take for Gina to overtake her?
A.7m
B.5m
C.6m
D.4m
Answer: C.6m
Explanation: Distance Gina ran before completion of race---100 m-0.85m=99.15m
Distance gained on Anabelle over 99.15m---8m-0.85m=7.15
then Gina gains 99.15/7.15m = 1m on Kelly every 13.87 meters.
Therefore 7.15m divided by 0.85 of 1 meter.
ANSWER: C. 6m
Question: The banker’s gain on a sum due 3 years hence at 12% per annum is Rs. 270. The banker’s discount is
A.Rs.960
B.Rs.840
C.Rs.1020
D.Rs.760
Answer: C.Rs.1020
Explanation: Solution
T.D	=(B.G x 100 / R x T)
= Rs.(270x100/12 x 3)
= Rs.750.
B.D
=Rs(750 + 270)
= Rs.1020.
Answer C
Question: Jacob is now 14 years younger than Michael. If 9 years from now Michael will be twice as old as Jacob, how old will Jacob be in 4 years?
A. 3
B. 7
C. 9
D. 21
Answer: C. 9
Explanation: Jacob=x years, Michael=x+14 years
9 years from now,
2(x+9)=x+23
2x+18=x+23
x=5
x+4=9 years
Answer C
Question: Pradeep has to obtain 35% of the total marks to pass. He got 150 marks and failed by 25 marks. The maximum marks are
A.300
B.600
C.800
D.500
Answer: D.500
Explanation: Explanation :
Let their maximum marks be x.
Then, 35% of x = 150 + 25
=>35/100x= 175
x = (17500/35)
x= 500.
Answer : D
Question: What is the smallest number which when diminished by 12, is divisible 8, 12, 22 and 24?
A.276
B.292
C.298
D.322
Answer: A.276
Explanation: Required Number
= (LCM of 8, 12, 22 and 24) + 12
= 264 + 12 = 276
Option A
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is?
A.3/4
B.3/2
C.3/6
D.3/3
Answer: B.3/2
Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y ==> 4 x
= 6 y ==> x/y = 3/2.
Answer: B
Question: Three partners shared the profit in a business in the ratio 4:6:8. They had partnered for 12 months, 8 months and 6 months respectively. What was the ratio of their investments?
A.4 : 9 : 19
B.4 : 9 : 12
C.4 : 9 : 11
D.4 : 9 : 16
Answer: D.4 : 9 : 16
Explanation: Let their investments be Rs. x for 12 months, Rs. y for 8 months and Rs. z for 6 months respectively.
Then, 12x : 8y : 6z = 4 : 6 : 8
Now, 12x/8y = 4/6 <=> 9x=4y <=> y=9x/4
And, 12x/6z = 4/8 <=> 4x=z <=> z=4x
Therefore, x : y: z = x : 9x/4: 4x = 4 : 9 : 16
Answer: D
Question: After decreasing 50% in the price of an article costs Rs.620. Find the actual cost of an article?
A.2777
B.2987
C.1200
D.1240
Answer: D.1240
Explanation: CP* (50/100) = 620
CP= 12.4 * 100 => CP = 1240
Answer: D
Question: How many pounds of salt at 50 cents/lb must be mixed with 40 lbs of salt that costs 25 cents/lb so that a merchant will get 20% profit by selling the mixture at 48 cents/lb?
A.20
B.15
C.40
D.60
Answer: D.60
Explanation: Selling price is 48 cents/lb
For a 20% profit, cost price should be 40 cents/lb (CP*6/5 = 48)
Basically, you need to mix 25 cents/lb (Salt 1) with 50 cents/lb (Salt 2) to get a mixture costing 40 cents/lb (Salt Avg)
weight of Salt1/weight of Salt2 = (Salt2 - SaltAvg)/(SaltAvg - Salt1) = (50 - 40)/(40 - 25) = 2/3
We know that weight of salt 1 is 40 lbs. Weight of salt 2 must be 60 lbs.
Answer (D)
Question: During a behavioral experiment in a psychology class, each student is asked to compute his or her lucky number by raising 7 to the power of the student's favorite day of the week (numbered 1 through 7 for Monday through Sunday respectively), multiplying the result by 3, and adding this to the doubled age of the student in years, rounded to the nearest year. If a class consists of 28 students, what is the probability that the median lucky number in the class will be a non-integer?
A.0%
B.10%
C.20%
D.30%
Answer: A.0%
Explanation: Student's age is integral value. In question, we are multiplying student's age by 2 and adding some 3* 7^x something over there.
It means Even (2* age of students) + Odd (3) * 7 ^x (where x is day of week).
We know that 7^x is always odd. (e.g. 7, 49, 243, 1701, and repeat).
=> 3* odd is again odd.
2 * age of students is always even.
So final equation is even +odd = odd.
Avg of any number of odd digits or any number of even digits can never be non integral value. So 0% is the answer A.
Question: Three numbers are in the ratio 3:5:7. The largest number value is 42. Find difference between Smallest & largest number is?
A.21
B.22
C.24
D.25
Answer: C.24
Explanation: == 3:5:7
Total parts = 15
= The largest number value is 42
= The largest number is = 7
= Then 7 parts -----> 42 ( 7 * 6 = 42 )
= smallest number = 3 & Largest number = 7
= Difference between smallest number & largest number is = 7 - 3 = 4
= Then 4 parts -----> 24 (4 * 6 = 24)
C
Question: A can do a piece of work in 6 days. B can do it in 6 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?
A.8 days
B.2 days
C.6 days
D.7 days
Answer: C.6 days
Explanation: C = 1/2 - 1/6 - 1/6= 1/6
=> 6 days
Answer: C
Question: In a candy dish the ratio of red to yellow candies is 2:5, the ratio of red to green candies is 3:8, and the ratio of yellow ot blue candies is 9:2.what is the maximum total number E of yellow and green candies combined if the maximum combined number of red and blue candies is fewer than 85?
A.144
B.189
C.234
D.279
Answer: D.279
Explanation: Given that Red is to yellow is 2:5, Red is to green is 3:8 and Yellow is to blue is 9:2.
Therefore, the total number of red, yellow, blue and green balls will be 18x, 45x, 10x and 48x respectively, where x is a constant.
If the combined number of red and blue balls is fewer than 85, i.e. max 84 balls, then the maximum number of yellow and green balls will be 279.
(10x+18x) < 85.
28x < 85, i.e. 28x <= 84 (Since number of balls cannot be in fraction). Thus, x<=3.
(45x+48x) = 93x.
Max (93x) E= 279.
Answer is D.
Question: A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in?
A.7
B.6
C.8
D.9
Answer: C.8
Explanation: (A + B + C)'s 1 day work = 1/6;
(A + B)'s 1 day work = 1/8
(B + C)'s 1 day work = 1/12
(A + C)'s 1 day work = (2 * 1/6) - (1/8 + 1/12)
= (1/3 - 5/24) = 1/8
So, A and C together will do the work in 8 days.
Answer:C
Question: Sandy invested a certain sum of money at 8% p.a. simple interest for 'n' years. At the end of 'n' years, Sandy got back 3 times the original investment. What is the value of n?
A.20
B.25
C.30
D.35
Answer: B.25
Explanation: n* 0.08 * principal + principal = 3 * principal
n * 0.08 = 2
n = 25 years
The answer is B.
Question: A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 450. Find the total worth of the stock?
A.20029
B.22500
C.20289
D.20027
Answer: B.22500
Explanation: Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x - 49x/50 = x/50
x/50 = 450 => x = 22500
Answer: B
Question: 17! is equal to which of the following?
A.355,687,428,096,622
B.355,687,428,096,245
C.355,687,428,096,000
D.355,687,428,096,924
Answer: C.355,687,428,096,000
Explanation: After 4!, the units digit of every factorial is 0.
5!=120
6!=720
etc...
The answer is C.
Question: What will come in place of the x in the following Number series? 279936, 46656, 7776, 1296, 216, x
A.24
B.26
C.36
D.42
Answer: C.36
Explanation: Go on dividing by 6 to the next number
C)
Question: If c and t are positive integers, ct +c + t cannot be
A.5
B.6
C.7
D.8
Answer: B.6
Explanation: Let ct + t + c = x
Add 1 on both sides:
ct + t + c + 1 = x + 1
t(c + 1) + c + 1 = x + 1
(c + 1)(t + 1) = x + 1
Minimum value of (c + 1) = 2
Minimum value of (t + 1) = 2
Hence x + 1 cannot be prime
Substitute x from the given options: 6 + 1 = 7 --> prime --> ct + t + s cannot be 6
Answer: B
Question: The HCF and LCM of two numbers are 21 and 4641 respectively. If one of number lies between 200 and 300, the two numbers are
A.273, 357
B.273, 361
C.273, 359
D.273, 363
Answer: A.273, 357
Explanation: Note that 273 is common in all the options
HCF × LCM Product of 2 numbers
21 × 4641 =273x, x = 357
Answer: A.
Question: Find the invalid no.from the following series 15, 17, 34, 105, 424, 2124, 12756
A.17
B.34
C.105
D.424
Answer: A.17
Explanation: 2nd term = (1st term) * 1 + 1 = 15 *1 + 1 = 16.
3rd term = (2nd term) * 2 + 2 = 16 * 2 + 2 = 34
4th term = (3th term) *3 + 3 = 34 * 3 + 3 = 105
5th term = (4th term) * 4 + 4 = 105 * 4 + 4 = 424
6th term = (5th term) * 5 + 5 = 424 * 5 + 5 = 2125
2nd term should 16 instead of 17.
A
Question: If the average of 12x and 8y is greater than 200, and x is twice y, what is the least integer value of x ?
A.20
B.30
C.40
D.25
Answer: D.25
Explanation: Substitution can be used in the following way:
Always start with the equation: x = 2y. It is more straight forward to manage as compared to the inequality.
Substitute y = x/2, not the other way because you need to find the minimum value of x. So you can get rid of y.
Now go on to the inequality. So 8y = 8x/2 = 4x
Now average of 12x and 4x is greater than 200. Average of 12x and 4x is 8x. So,
8x > 200
x > 25
Answer : D
Question: if a cow eat 3kg fodder which is mean of 7 days.if he eat 2 kg,1kg,3kg,4kg,2kg,3kg
on mon,tue,wed,thurs,fri and Saturday.how much cow eat on Sunday?
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: solution
let cow eat x kg on Sunday
(2+1+3+4+2+3+x)/7=3
15+x=21
x=6
answer D
Question: If a rectangular billboard has an area of 120 square feet and a perimeter of 46 feet, what is the length of each of the shorter sides?
A.4
B.7
C.8
D.13
Answer: C.8
Explanation: This question can be solved algebraically or by TESTing THE ANSWERS.
We're told that a rectangle has an area of 120 and a perimeter of 46. We're asked for the length of one of the SHORTER sides of the rectangle.
Since the answers are all INTEGERS, and the area is 120, the shorter side will almost certainly be less than 10 (since 10x10 = 100, but we're NOT dealing with a square). Answer B (7) does NOT divide evenly into 120,
Let's TEST Answer C: 8
IF...
The shorter side = 8...
The area = 120....120/8 = 15 = the longer side
Perimeter = 8+8+15+15 = 46
C
Question: If 0.75 : x :: 5 : 8, then x is equal to:
A.1.5
B.1.9
C.1.2
D.1.4
Answer: C.1.2
Explanation: ((x) x 5) = (0.75 x 8)
= x = 6/5
= 1.20
Answer is C.
Question: 12 men can complete a piece of work in 4 days, while 15 women can complete the same work in 4 days. 6 men start working on the job and after working for 2 days, all of them stopped working. How many women should be put on the job to complete the remaining work, if it is to be completed in 3 days.
A.15
B.18
C.22
D.25
Answer: A.15
Explanation: One man’s one day’s work = 1/48
One woman’s one day’s work = 1/60
6 men’s 2 day’s work = ((6/48) x 2) = 1/4
Remaining work = 3/4
Now, 1/60 work s done in 1 day by 1 woman.
Thus, 3/4 work will be done in 3 days by (60 x (3/4) x (1/3)) = 15 women.
ANSWER:A
Question: When positive integer A is divided by positive integer B, the remainder is 6. If A/B = 58.3, what is the value of B?
A.15
B.20
C.18
D.19
Answer: B.20
Explanation: When positive integer A is divided by positive integer B, the remainder is 6 --> A=qB+6;
A/B=58.3 --> A=58B+0.3B (so q above equals to 58);
0.3B=6 --> B=20.
Answer: B.
Question: If f(x)= 5x^2- 2x+6 and g(y)= 3y-8, then g(f(x))
A.82x^2-9x+38
B.15x^2-6x+10
C.58x^2-4x+58
D.87x^2-5x+96
Answer: B.15x^2-6x+10
Explanation: g(f(x))=3(5x^2-2x+6)-8
=15x^2-6x+18-8
=15x^2-6x+10
the answer is B
Question: Alex deposited x dollars into a new account that earned 8 percent annual interest, compounded annually. One year later Alex deposited an additional x dollars into the account. If there were no other transactions and if the account contained w dollars at the end of two years, which of the following expresses x in terms of w ?
A.w/(1+1.08)
B.w/(1.08+1.16)
C.w/(1.16+1.24)
D.w/(1.08+1.08^2)
Answer: D.w/(1.08+1.08^2)
Explanation: Account at the end of the first year would be 1.08x dollars. At this time x dollars was deposited, hence the account at the beginning of the second year would be (1.08x+x) dollars. Account at the end of the second year would be (1.08x+x)*1.08=w --> x(1.08^2+1.08)=w --> x=w/(1.08+1.08^2).
Answer: D.
Question: 734619
110907
524232
995001
678297
1548??
now what could be the missing area in the question
A.80
B.81
C.82
D.83
Answer: B.81
Explanation: there is a specific addition/subtraction in each two digits
73-27=46 46-27=19
11-2=9 9-2=7
same
67+15=82 82+15=97
15+33=48 48+33=81
ANSWER:B
Question: A set has exactly five consecutive positive integers starting with 1. What is the percentage decrease in the average of the numbers when the greatest one of the numbers is removed from the set?
A.8.54
B.12.56
C.15.25
D.16.66
Answer: D.16.66
Explanation: Explanation :
The average of the five consecutive positive integers 1,2,3,4 and 5 is:
(1+2+3+4+5)/5=15/5=3.
After removing the the greatest number i.e 5, the new average becomes:
(1+2+3+4)/4=104=2.5.
Now, % drop in the average =(Old average – New average)×100/Old average.
=>(3−2.5)×100/3.
=>100/6=16.66.
Answer : D
Question: In Cricket game, one player throws two fair, six-sided die at the same time. If the player receives at least a five or a one on either die, that player wins. What is the probability that a player wins after playing the game once?
A.1/3
B.4/9
C.5/9
D.2/3
Answer: C.5/9
Explanation: In Cricket game Probably the easiest approach would be to find the probability of the opposite event and subtract it from 1:
P(win) = 1- P(not win) = 1 - 4/6*4/6 = 5/9.
Answer: C.
Question: Reena took a loan of $. 1200 with simple interest for as many years as the rate of interest. If she paid $ 108 as interest at the end of the loan period, what was the rate of interest?
A.3.6
B.6
C.18
D.3
Answer: D.3
Explanation: Let rate = R% and time = R years.
Then,1200 x R x R/100= 108
12R2 = 108
R2 = 9
R = 3.
Answer:D
Question: There are 2 positive integers x and y. What is the probability that x+y is odd?
A.1/4
B.1/2
C.1/3
D.1/5
Answer: B.1/2
Explanation: Explanation :
The addition of two integer results in an odd number only if any one of the integers is an odd number.
The probability of an odd among the two integer is 1/2.
Hence, the required probability is 1/2.
Answer : B
Question: The product of two numbers is 120 and the sum of their squares is 289. The sum is:
A.23
B.21
C.43
D.56
Answer: A.23
Explanation: xy = 120 and x2 + y2 = 289.
(x + y)2 = x2 + y2 + 2xy = 289 + (2 x 120) = 529
x + y = 529 = 23.
ANSWER A