RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Average families of 4 pay $3000 for their health insurance deductibles annually. There will be a 2/3 increase in the deductibles for next year. How much more will the average family pay in deductibles next year?
A. $1000
B. $2000
C. $3000
D. $4000
Answer: B. $2000
Explanation: A certain percentage of questions in the Quant section of the GMAT are just 'math questions' - you'll use a formula, do some calculations and you'll have the answer. This is one of those types of questions. You still have to write everything down and stay organized, but the work involved is relatively straight-forward.
Here, we're told that the current annual deductible is $3000 and that the deductible is to be increased by 2/3. We're asked how MUCH MORE will the deductible cost a family next year.
Original Deductible = $3000
Increase in Deductible = 2/3
The answer is calculated by the equation:
$3000 × 2/3 = $2000.
B
Question: Scott's average (arithmetic mean) golf score on his first four rounds was 78.What score does he need on his fifth round to drop his average score by 2 points?
A.68
B.72
C.78
D.88
Answer: A.68
Explanation: Average score for first 4 rounds = 78
Average score after 5 rounds = 76
Score Scott needs on his 5th round to drop average score by 2 points = 78 - (2*5) = 68
Answer A
Alternatively , sum of scores of first 4 rounds = 78*4 = 312
Sum of scores after 5 rounds = 76*5 = 380
Score Scott needs on his 5th round to drop average score by 2 points = 380 - 312 = 68
Answer A
Question: Two vertical poles 2 meter and 8 meter high stand apart on a horizontal plane. find the height in meters of the point of intersection of the lines joining the top of each pole to the bottom of the other pole.
A.1.8
B.1.9
C.1.6
D.1.7
Answer: C.1.6
Explanation: Let A be the point of the top of the 2m pole.
Let B be the point of the foot of the 2m pole.
Let C be the point of the top of the 8m pole.
Let D be the point of the foot of the 8m pole.
Let E be the point of intersection of the line segments AD and BC.
From E drop a perpendicular to the ground.
Let F be the point on the ground where perpendicular from E meets the ground.
Let X be the distance from E to F.
Let P be the distance from B to F.
Let Q be the distance from F to D.
Triangles BEF and BCD are similar so we get Equation 1:
X/P = 8/(P+Q)
Triangles DEF and DAB are similar so we get:
X/Q = 2/(P+Q)
Multiplying both sides by 4 we get Equation 2:
(4X)/Q = 8/(P+Q)
Combining Equations 1 and 2 we get:
X/P = (4X)/Q
Simplifying this we get:
1/P = 4/Q
And then we get:
Q = 4P
Substituting Q=4P into Equation 1 we get:
X/P = 8/(P+4P)
Simplifying this we get:
X/P = 8/(5P)
X = (8P)/(5P)
X = 8/5
X = 1.6
Therefore, the desired height is 1.6 meters.
ANSWER:C
Question: Find the odd man out
25, 49, 81, 121, 144, 169
A.49
B.121
C.144
D.169
Answer: C.144
Explanation: 144 is square of 12 which is even number where as all others are squares of odd numbers.
ANSWER:C
Question: You have a battery that is charged during the day by a solar panel. At night, 3 Iphones use that battery and deplete the charge after 4.8 hours. Your family shows up and they have brought 9 of their own Iphones. How many hours before the charge on the battery is depleted now?
A.5.3
B.1.2
C.1.8
D.2.2
Answer: B.1.2
Explanation: First set up a ratio with all the relevant values and also the unknown variable:
3*4.8 = 12*x
Now solve by multiplying 3 by 4.8 and then dividing that product by 12:
3*4.8 = 14.4
14.4/12 = x
x = 1.2
The value of x equals the number of hours the battery charge will last if 12 Iphones are connected to it.
Answer: B
Question: If 16^y = 4^16, what is y?
A.2
B.4
C.8
D.12
Answer: C.8
Explanation: 16^y = 4^2y = 4^16
2y=16
y = 8
The answer is C.
Question: Two trains of equal are running on parallel lines in the same direction at 48 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
A.60 m
B.72 m
C.80 m
D.82 m
Answer: A.60 m
Explanation: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 48 - 36 = 12 km/hr.
= 12 * 5/18 = 10/3 m/sec.
2x/36 = 10/3=> x = 60.
ANSWER:A
Question: To produce an annual income of Rs. 1200 from a 12 % stock at 90,the amount of stock needed is :
A.Rs. 10,000
B.Rs. 10,800
C.Rs. 14,400
D.Rs. 16,000
Answer: A.Rs. 10,000
Explanation: Solution
For an income of Rs. 12, stock needed = Rs. 100.
For an income of Rs. 1200, stock needed = Rs. 100/12x1200 = 10000
Answer A
Question: The banker's discount on Rs.1450 due a certain time hence is Rs.145. Find the true discount and the banker's gain.
A.13
B.15
C.18
D.21
Answer: A.13
Explanation: Solution
Sum	=B.D x T.D/ B.D - T.D
= B.D x T.D/ B.G
T.D / B. G	=Sum / B.D
= 1450 / 145
= 10 / 1
If B.D is Rs. 11,T.D= Rs.10.
If B.D is Rs.145,
T.D	= Rs.(10 / 11 x 145)
= Rs.132.
And, B.G	= Rs(165 - 132)
= Rs.13.
Answer A
Question: A certain theater has 100 balcony seats. For every $2 increase in the price of a balcony seat above $10, 5 fewer seats will be sold. If all the balcony seats are sold when the price of each seat is $10, which of the following could be the price of a balcony seat if the revenue from the sale of balcony seats is $1,460 ?
A.$12
B.$14
C.$18.6
D.$17
Answer: C.$18.6
Explanation: I solved it as follows:
10+2(x) = 100 -5(x)
x= 12
Equation should be (10+$2*x)(100-5x)=1,460, where x is the # of times we increased the price by $2. (10+$2*x)(100-5x)=1,460 --> (5+x)(20-x)=146 --> x=4.3 or x=10.7 --> price=10+$2*4.3=$18.6 or price=10+$2*10.7=$31.4.
Answer: C.
Question: A person took some amount with some interest for 2 years, but increase the interest for 1%, he paid Rs.130/- extra, then how much amount he took?
A.s.5500/-
B.s.6500/-
C.s.4000/-
D.s.7000/-
Answer: B.s.6500/-
Explanation: Explanation:
2 years = Rs.130/-
year = 130/2
Rate of Interest = 1%
100/1% × 130/2 = Rs.6500/-
P = Rs.6500/-
Answer: Option B
Question: If two times of the daughter’s age in years is included to the mother’s age, the total is 70 and if two times of the mother’s age is included to the daughter’s age, the total is 95. So the Mother’s age is,
A.30
B.40
C.50
D.60
Answer: B.40
Explanation: B
40
Let daughter’s age = A and mother’s age = B
Given:
2A+B = 70 and,
A+2B = 95
Solving B, we will get B = 40.
Question: How long does a train 110 meters long running at the speed of 72 km/hour take to cross a bridge 132
meters in length ?
A.15 seconds
B.12.1 seconds
C.10 seconds
D.8.1 seconds
Answer: B.12.1 seconds
Explanation: Explanation:
Speed = 72 km/hour = 72*(5/18) m/sec
= 20 m/sec
Total distance to be covered = 110+132 = 142 meters
Time = Distance/Speed
= 242/20 = 12.1 seconds
Answer: B
Question: A man whose bowling average is 12.4, takes 5 wickets for 26 runs and there by decreases his average by 0.4. The number of wickets taken by him before his last match is?
A.82
B.83
C.84
D.85
Answer: D.85
Explanation: 12.4x+26/(5+x)=12
12.4x+26=60+12x
x=34/0.4=85
ANSWER:D
Question: If the cost price of 30 articles is equal to the selling price of 45 articles, what is the % profit or loss made by the merchant?
A.33.33% loss
B.25% profit
C.20% loss
D.20% profit
Answer: A.33.33% loss
Explanation: Let the cost price of 1 article be $1.
Therefore, cost price of 30 articles = 30 * 1 = $30
The selling price of 45 articles = cost price of 30 articles = $30.
Now, we know the selling price of 45 articles. Let us find the cost price of 45 articles.
Cost price of 45 articles = 45 * 1 = $45.
Therefore, profit made on sale of 45 articles = Selling price of 45 articles - cost price of 45 articles
= 30 - 45 = -$15.
As the profit is in the negative, the merchant has made a loss of $15.
Therefore, % loss = loss/cp * 100
% loss = -15/45 * 100 = 33.33% loss.
A
Question: The 4 sticks in a complete bag of Pick-Up Sticks are all straight-line segments of negligible width, but each has a different length: 1 inch, 2 inches, 3 inches, and 4 inches, respectively. If Tommy picks a stick at random from each of 3 different complete bags of Pick-Up Sticks, what is the probability D that Tommy CANNOT form a triangle from the 3 sticks?
A.11/32
B.13/32
C.15/32
D.17/32
Answer: C.15/32
Explanation: In order to form a triangle, the sum of two sides must be greater than the third side.
So we can choose the combination of numbers which will NOT result in a triangle.
Favorable outcomes:
1,1,4 (4>1+1): 3 ways of arriving at this (1,1,4), (1,4,1), (4,1,1) or
1,2,4 (4>1+2): 6 ways of arriving at this (1,2,4), (1,4,2), (2,1,4), (2,4,1), (4,1,2), (4,2,1) which is same as 3!
1,3,4 (4=1+3): 6 ways of arriving at this
2,2,4 (4=2+2): 3 ways of arriving at this
1,1,3 (3>1+1): 3 ways of arriving at this
1,2,3 (3=1+2): 6 ways of arriving at this
1,1,2 (2+1+1): 3 ways of arriving at this
Overall favourable outcomes: 30
Total outcomes: 4*4*4 = 64 (4 ways of choosing a stick from each of the 3 bags)
Probability D that a triangle is not formed = 30/64 = 15/32
C is the correct option here.
Question: A confectioner decides to sell all of his pastry due to the coming holiday. His pastry goods are equally divided among a group of 30 regular customers. If only 49 customers come to the bakery, each one will receive 6 less pastry goods. How much pastry does the confectioner needs to sell?
A.450.
B.412.
C.432.
D.502.
Answer: A.450.
Explanation: Pastry is divided in 30 customers equally. So,total number of pastry must be a multiple of 30
Only option A satisfies the condition, and hence is the answer
Question: What is the total cost of 2 sandwiches at $2.44 each and 4 sodas at $0.87 each?
A.$3.36
B.$6.85
C.$8.36
D.$10.08
Answer: C.$8.36
Explanation: Answer = C
2 * 2.44 + 4 * 0.87
= 2 (2.50 - 0.06) + 4 (1.00 - 0.13)
= 5 + 4 - 0.12 - 0.52
= 9 - 0.64
= 8.36
Question: A class average mark in an exam is 70. The average of students who scored below 60 is 50. The average of students who scored 60 or more is 75. If the total number of students in this class is 20, how many students scored below 60?
A.5
B.10
C.15
D.20
Answer: D.20
Explanation: Let n the number of students who scored below 60 and N the number of students who scored 60 or more. Xi the grades below 60 and Yi the grades 60 or above.
[sum(Xi) + sum(Yi)] / 20 = 70 : class average
sum(Xi) / n = 50 : average for less that 60
sum(Yi) / N = 75 : average for 60 or more
50n + 75N = 1400 : combine the above equations
n + N = 20 : total number of students
n = 4 and N = 16 : solve the above system
correct answer D
Question: The average of ten numbers is 8. If each number is multiplied by 12, then what is the average of the new set of numbers?
A.8
B.12
C.20
D.96
Answer: D.96
Explanation: The sum of the ten numbers is 8*10 = 80
If each number is multiplied by 12, the new sum is 12*(80).
The average is then 12*8 = 96
The answer is D.
Question: 18 business executives and 7 chairmen meet at a conference. If each business executive shakes the hand of every other business executive and every chairman once, and each chairman shakes the hand of each of the business executives but not the other chairmen, how many handshakes would take place?
A.144
B.131
C.279
D.90
Answer: C.279
Explanation: there are 18 business exec and in each handshake 2 business execs are involved.
hence 18C2=153
Also, each of 18 exec will shake hand with every 7 other chairmen for total of 126 handshake.
total=153+126=279
ANS: C
Question: A and B can finish a work 30 days if they work together. They worked together for 20 days and then B left. A finished the remaining work in another 20 days. In how many days A alone can finish the work?
A.30
B.60
C.40
D.20
Answer: B.60
Explanation: Amount of work done by A and B in 1 day = 1/30
Amount of work done by A and B in 20 days = 20 × (1/30) = 20/30 = 2/3
Remaining work – 1 – 2/3 = 1/3
A completes 1/3 work in 20 days
Amount of work A can do in 1 day = (1/3)/20 = 1/60
=> A can complete the work in 60 days
Answer is B.
Question: Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?
A.648
B.1800
C.2700
D.10800
Answer: B.1800
Explanation: Let the number of required bottles be x
machine 6 : 10
Time 1: 4
= :: 270 : x
Therefore 6 x 1 x X = 10 x 4 x 270
=> x= (10 x 4 x 270) /(6)
=> x = 1800
Answer: Option B
Question: The average of six number is x and the average of three of these is y. if the average of the remaining three is z, then :
A.x = y+z
B.2x = y+z
C.x = 2y+2z
D.None of these
Answer: B.2x = y+z
Explanation: Solution
Clearly, we have X=(3y+3z/6) or 2x= y + z. Answer B
Question: If taxi fares were $10.00 for the first 1/5 mile and $1.00 for each 1/5 mile there after, then the taxi fare for a 10-mile ride was
A.$55.10
B.$59.20
C.$59.40
D.$59.00
Answer: D.$59.00
Explanation: In 10 miles , initial 1/5 mile charge is $10
rest of the distance = 10 - (1/5) = 49/5
rest of the distance charge = 49(1.00) = $49.00 (as the charge is 1.00 for every 1/5 mile)
=> total charge for 4 miles = 10+49.00 = 59.00
Answer is D
Question: The positive two-digit integers s and t have the same digits, but in reverse order. Which of the following must be a factor of s + t?
A.6
B.9
C.44
D.12
Answer: C.44
Explanation: Remember: When you take the difference between the two, it will always be 9. e.g 23-32=9, 89-98=9
and when you add both integers, the sum will always be a multiple of 11 e.g 23+32=55, 89+98= 187
44 is multiple of 11
Answer : C
Question: Find the fraction which has the same ratio to 2/5 that 3/8 has to 1/5
A.1/15
B.3/4
C.5/8
D.9/6
Answer: B.3/4
Explanation: P : 2/5 = 3/8 : 1/5
As the product of the means is equal to the product of the extremes.
P*1/5 = 2/5 * 3/8
P*1/5 = 6/40
P = 3/4 => P = 3/4
ANSWER:B
Question: Out of 9 persons, 8 persons spent Rs. 30 each for their meals. The ninth one spent Rs. 20 more than the average expenditure of all the nine. The total money spent by all of them was ?
A.Rs.292.50
B.Rs.292.56
C.Rs.292.12
D.Rs.292.27
Answer: A.Rs.292.50
Explanation: Let the average expenditure be Rs. x Then,
Total money spent = 9x = Rs. (9 x 32.5O) = Rs 292. 50
Answer: A
Question: How many ways can 10 letters be posted in 5 post boxes, if each of the post boxes can take more than 10 letters ?
A.5^10
B.5^19
C.5^18
D.5^12
Answer: A.5^10
Explanation: Explanation:
Each of the 10 letters can be posted in any of the 5 boxes.
So, the first letter has 5 options, so does the second letter and so on and so forth for all of the 10 letters.
i.e. 5*5*5*….*5 (upto 10 times)
= 5 ^ 10.
Answer: A) 5^10
Question: A trader bought a car at 5% discount on its original price. He sold it at a 60% increase on the price he bought it. What percent of profit did he make on the original price?
A.17%
B.62%
C.52%
D.19%
Answer: C.52%
Explanation: Original price = 100
CP = 95
S = 95*(160/100) = 152
100 - 152= 52%
Answer: C
Question: When p is divided by 9, the remainder is 5. All of the following are possible values of p, except for which of the following?
A.14
B.32
C.50
D.58
Answer: D.58
Explanation: Four of these numbers can be expressed in the form of 9x+5, where x can be 0,1,2,3,4....
However, 58 = 9(6) + 4
The answer is D.
Question: A can do a piece of work in 4 days. B can do it in 5 days. With the assistance of C they completed the work in 3 days. Find in how many days can C alone do it?
A.8 4/7 days
B.20 days
C.16 days
D.19 days
Answer: A.8 4/7 days
Explanation: C = 1/3 - 1/4 - 1/5 = 7/60
=> 60/7 = 8 4/7 days
Answer:A
Question: if each of its sides of a rectangle is increased by 25%, what is the percentage increase in the area of the rectangle, ?
A.59.25%
B.58.25%
C.56.25%
D.26.25%
Answer: C.56.25%
Explanation: Assume original length = 100m by 50m
original area = 100*50= 5000
25% increase on each side
l = 100 + 25 = 125
w = 50 + 12.5 = 62.5
new area = 125*62.5= 7812.5
increase in area = 7812.5 - 5000 = 2812.5
%increase =56.25%
Answer C
Question: The Tens digit of a two digit number is 4 times of its unit digit and the sum of the digits be 10. Then the first number is
A.67
B.73
C.53
D.82
Answer: D.82
Explanation: Let the number be 10x + y
According to the question
x = 4y
x + y = 10
4y + y = 10
or y = 2
and x = 8
So required number is = 10*8 + 2 = 82
answer :D
Question: After MM students took a test, there was a total of 64% of correct answers. If the test contains 50 questions, what is the least number of questions that the next student have to get right to bring the total of correct answers to 70% ?
A.3M + 20
B.3M + 35
C.4M + 15
D.4M + 20
Answer: B.3M + 35
Explanation: Denote xx as the required number of correct answers. xx must satisfy the equation 0.64∗M∗50+x/50M+50=7/10 or 350M+350=320M+10x or x=3M+35
Answer: B
Question: A necklace is made by stringing N individual beads together in the repeating pattern yellow bead, green bead, white bead, red bead, and blue bead. If the necklace design begins with a yellow bead and ends with a white bead, then N could equal
A.65
B.75
C.85
D.68
Answer: D.68
Explanation: Recognize that we are going to have to look for an answer thats a multiple of 5, plus 3.
Mutliple of 5 because there are 5 beads in the pattern, and plus 3 because the bead ends on white, which is 3 into the pattern.
I just went through all the answer choices, and only E fits. 5x13 = 65, and 65+3=68
Answer : D
Question: 222, 224, 228, 234, 242, (....)
A.260
B.258
C.252
D.250
Answer: C.252
Explanation: Explanation :
The pattern is 2, 4, 6, 8, 10, etc.
Hence 10=252
Answer: C
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 46, the dividend is?
A.5320
B.5328
C.5336
D.5340
Answer: C.5336
Explanation: Divisor = (5 * 46) = 230
= 10 * Quotient = Divisor
=> Quotient = 230/10 = 23
Dividend = (Divisor * Quotient) + Remainder
Dividend = (230 * 23) + 46 = 5336.
C)
Question: A basketball team plays games only against the other five teams in its league and always in the following order: Croton, Darby, Englewood, Fiennes, and Garvin. If the team’s final game of the season is against Fiennes, which of the following could be the number of games in the team’s schedule?
A.18
B.24
C.56
D.72
Answer: B.24
Explanation: Let "A" as the initial team which have to play against with Croton (C), Darby (D), Englewood (E), Fiennes (F), and Garvin (G);
According to the question, we have a column as below
Game 1st 2nd 3rd 4th 5th (Or final game)
A A A A A
C D E G F (fixed)
There are 4! ways to arrange a game with A - or 24 ways. -----> B is a correct answer.
Question: The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/2 of the area of the field. What is the length of the field?
A.13
B.16
C.34
D.43
Answer: B.16
Explanation: Explanation:
A/2 = 8 * 8 => A = 8 * 8 * 2
x * 2x = 8 * 8 * 2
x = 8 => 2x = 16
Answer: Option B
Question: A man sells a horse for Rs.800 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?
A.299
B.377
C.328
D.860
Answer: D.860
Explanation: CP = SP + 1CP = SP - g
800 + x = 980 - 2x
3x = 180 => x = 60
CP = 800 + 60
= 860
Answer: D
Question: Keats Library purchases a number of new books, all in the category of biography, and the library does not acquire any other books. With the addition of the new biographies, the biography collection of the library amounts to 35% of the total number of books in the library. If prior to the purchase, only 20% of the books in Keats Library were biographies, by what percent has the number of biographies in the library increased?
A.45%
B.65%
C.85%
D.115%
Answer: D.115%
Explanation: Let x be the number of new biographies added to the library.
Let b be the original number of biographies, so the original number of books was 5b.
0.35(5b+x) = b+x
0.75b = 0.65x
x = 1.15b
The answer is D.
Question: A train which has 420 m long, is running 45 kmph. In what time will it cross a person moving at 9 kmph in same direction ?
A.56 sec
B.42 sec
C.36 sec
D.29 sec.
Answer: B.42 sec
Explanation: Time taken to cross a moving person = length of train/ relative speed
Time taken = 420/((45-9) (5/18)
= 420/ 36*(5/18)
= 420/10
= 42 sec
ANSWER:B
Question: Husband and wife having average age of 26 years at their marriage time. After four years they have a two year old child. The average age of the family now
A.20.66 years
B.23 years
C.28.5 years
D.29.3 years
Answer: A.20.66 years
Explanation: Explanation :
Sum of the present ages on husband, wife and child =(26x2+4x2)+2
= 62 years
Required average
= (62/3)
= 20.66 years.
Answer : A
Question: Adding two non multiples of x always results in a multiple of x; which of the following must be the value of x ?
A.two
B.three
C.five
D.ten
Answer: B.three
Explanation: Take simple numbers to understand the concept before hitting it...
Say x = 2
The non multiple can be 1 (Definitely 1 is not a multiple of 2)
Now add two multiples of 2 , ie 1 + 1 = 2 ( Resulting in the number x )
[b]Thus the value of x can be 2 ad the non multiple can be 1 , satisfying the conditions stated in the question stem
ANSWER:B
Question: Nitin’s salary is reduced by 10% and then reduced salary is increased by 10%. Find ,how many percentage his present salary is less as compared to his previous salary?
A.Nothing
B.10%
C.1%
D.5%
Answer: C.1%
Explanation: 10*10
-------- = 1%
100
ANSWER:C
Question: Two years ago, Ram put $500 into a savings account. At the end of the first year, his account had accrued $100 in interest bringing his total balance to $600. The next year, his account balance increased by 10%. At the end of the two years, by what percent has Ram's account balance increased from his initial deposit of $500 ?
A.19%
B.28%
C.30%
D.32%
Answer: D.32%
Explanation: investment 500 dollars
1 st year total gained = 100
total amount end of first year = 600
second year account increased by 10 % = 600*0.1 = 60
therefore total amount by second year end = 660
so total percentage increase in money = (660-500)*100/500 = 32 %
Correct Answer D=32%
Question: How many positive integers less than 100 are neither multiples of 2 or 3?
A.30
B.31
C.32
D.33
Answer: D.33
Explanation: 1) multiples of 2 till 100 = 100/2 = 50
2) multiples of 3 till 100 = 100/3 = 33.33= 33
add the two 50+33=83 ;
subtract common terms that are multiple of both 2 and 3..
LCM of 2 and 3 = 6
Multiples of 6 till 100 = 100/6 = 16.66 = 16
so total multiples of 2 and 3 = 83-16 = 67
100-67 = 33
Answer : D
Question: A team scored a total of 118 points. If each player on the team scored at least 14 points, then what is the greatest possible number of players on the team?
A.6
B.7
C.8
D.9
Answer: C.8
Explanation: 118/14=8 plus remainder.
The answer is C.
Question: The parameter of a square is double the perimeter of a rectangle. The area of the rectangle is 480 sq cm. Find the area of the square?
A.298
B.288
C.480
D.28
Answer: B.288
Explanation: Let the side of the square be a cm. Let the length and the breadth of the rectangle be l cm and b cm respectively.
4a = 2(l + b)
2a = l + b
l . b = 480
We cannot find ( l + b) only with the help of l . b. Therefore a cannot be found .
Answer:B
Question: A certain quantity of 40% concentration solution is replaced with 20% concentration solution such that the concentration of the combined amount is 35%.
What's the ratio of the amount of solution that was replaced to the amount of solution that was not replaced?
A.1:3
B.1:2
C.2:3
D.2:1
Answer: A.1:3
Explanation: 20% - - - - - - - - - 35% - - - - - - 40%
From 20 to 35 =15
From 35 to 40 = 5
So the ratio is 15/5 = 3 to 1
A it is
Question: There are a total of 15 students in Mr. Sam's gym class. Over the course of a badminton unit, each of the 15 students will compete exactly once against every other student in the class. How many total games of badminton will be played?
A.105
B.171
C.190
D.110
Answer: A.105
Explanation: there are 15 students , if each play with all other members .
then total games can be calculated as 14+13....+1 = 105.
alternate approach is to choose 2 distinct out of 14 = 14c2 = 105
Answer is A.
Question: By selling 16 pencils for a rupee a man loses 10%. How many for a rupee should he sell in order to gain 20%?
A.8
B.9
C.12
D.89
Answer: C.12
Explanation: 90% --- 16
120% --- ?
90/120 * 16 = 12
Answer: C