RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Joe invested a certain sum of money in a simple interest bond whose value grew to $260 at the end of 3 years and to $360 at the end of another 5 years. What was the rate of interest in which he invested his sum?
A.6%
B.8%
C.10%
D.12%
Answer: C.10%
Explanation: In 5 years, the value grew $100, so the simple interest was $20 per year.
In 3 years, the total interest was 3*$20 = $60
The principal is $260 - $60 = 200.
The interest rate is $20/$200 = 10%
The answer is C.
Question: The average salary of 15 people in the shipping department at a certain firm is $21,000. The salary of 5 of the employees is $25,000 each and the salary of 4 of the employees is $16,000 each. What is the average salary of the remaining employees?
A. $19,250
B. $18,500
C. $21,000
D. $15,850
Answer: C. $21,000
Explanation: total salary... 15*21k=315k
5 emp @ 25k =125k
4 emp @ 16k =64k
remaing 6 emp sal = 315k-125k-64k =126k
average=126k/6 = 21000
Ans: C
Question: How many multiples of 6 are less than 5000, and also multiples of 8?
A.104
B.208
C.625
D.832
Answer: B.208
Explanation: LCM of 6 & 8 = 24
Tried dividing 5000 by 24
Got quotient 208.33'So B is answer
Question: A train 500 meters long completely crosses a 300 meters long bridge in 45 seconds. What is the speed of the train is?
A.32
B.28
C.49
D.64
Answer: D.64
Explanation: S = (500 + 300)/45 = 800/45 * 18/5 = 64
Answer: D
Question: There are different 20 circles. What is the number of the greatest possible points with which the circles intersect?
A.380
B.200
C.110
D.180
Answer: A.380
Explanation: Maximum points of intersection between n different circles = n*(n - 1) = 20*19 = 380
Answer: A
Question: A gardener grows cabbages in her garden that is in the shape of a square. Each cabbage takes 1 square feet of area in her garden. This year, she has increased her output by 193 cabbages as compared to last year. The shape of the area used for growing the cabbages has remained a square in both these years. How many cabbages did she produce this year?
A.8,208
B.9,409
C.11,424
D.12,586
Answer: B.9,409
Explanation: Let the side for growing cabbages this year be X ft. Thus the area is X^2.
Let the side for growing cabbages last year be Y ft. Thus, the area was Y^2.
The area would have increased by 193 sq ft as each cabbage takes 1 sq ft space.
X^2 - Y^2 = 193
(X + Y)(X - Y) = 193
193 is a prime number and thus it will be (97+96)*(97-96).
Thus X = 97 and Y = 96
X^2 = 97^2 = 9409
The answer is B.
Question: In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
A.6.25
B.6.5
C.6.75
D.7
Answer: A.6.25
Explanation: Solution
Required run rate	= 282 - (3.2 x 10) / 40
= 250 / 40
= 6.25.
Answer A
Question: There are three rooms in a motel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ?
A.7! / 1! 2! 3!
B.7!
C.7! / 3
D.7! / 3!
Answer: A.7! / 1! 2! 3!
Explanation: Choose 1 person for the single room & from the remaining choose 2 for the double room & from the remaining choose 4 people for the four person room,
Then, 7C1 x 6C2 x 4C4 = 7! / 1! 2! 3!
ANSWER:A
Question: The principal that amounts to Rs. 3913 in 3 years at 6 1/4 % per annum C.I. compounded annually, is?
A.s. 3096
B.s. 4076
C.s. 4085
D.s. 4096
Answer: A.s. 3096
Explanation: Principal = [4913 / (1 + 25/(4 * 100))3]
= 3913 * 16/17 * 16/17 * 16/17 = Rs. 3096.
ANSWER:A
Question: During a sale of 20% on everything in a store, a kid is successful in convincing the store manager to give him 20 candies for the discounted price of 14 candies. The store still makes a profit of 18% on this sale. What is the mark up percentage on each candy?
A. 100%
B. 80%
C. 75%
D. 66+2/3%
Answer: D. 66+2/3%
Explanation: Hi Akhil, I can share the way I solved it..
Let's say Marked price = M
So, there's a discount of 20% on M So, new S.P. = 80% of M
Now, the child convinces the owner to sell 20 candies for the price of 14 candies .
Let's say each candy after discount is 1$. So, S.P. of 20 candies = 20$. THe child bought it for 14 $ So, he got a discount of 6/20 *100 = 30%
So, the latest S.P. = 70% of 80% of M = 0.7* 0.8 M
Now, we are given that the shopkeeper still makes a profit of 12%. So we have ,
0.7 * 0.8 * M = 1.12 C.P
So, we get, M= 2 C.P.
i.e. Marked price was kept 100% above C.P.
D
Question: A bat is bought for Rs.440 and sold at a gain of 20% find its selling price
A.s.430/-
B.s.480/-
C.s.400/-
D.s.528/-
Answer: D.s.528/-
Explanation: 100 % ------> 440
120 % ------> 440*120/100
Selling price = Rs.528/-
D
Question: A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
A.22
B.23
C.24
D.26
Answer: D.26
Explanation: let hens be x and cows be y
now,
feet: x*2+y*4=140
heads: x*1+y*1=48
implies, 2x+4y=140 and x+y=48
solving these two equations, we get x=26 and y=22
Therefore, hens are 26.
ANSWER:D
Question: Find the simple interest on Rs. 70,000 at 16 2/3% per year for 9 months.
A.7500
B.6500
C.8750
D.9500
Answer: C.8750
Explanation: P = Rs.70000,R = 50/3% p.a and T = 9/12 years = 3/4years.
Simple Interest = (P*R*T)/100 = Rs.(70,000*(50/3)*(3/4)*(1/100))= Rs.8750
Answer is C.
Question: 7858,3929,163.70,20.46, ?
A.1.25
B.2.69
C.3.87
D.2.04
Answer: D.2.04
Explanation: Explanation :
Terms are continuously divided by 2,4,6 ,8, and so on
7858
7858Ã· 2= 3929
3929 Ã· 4 =982.25
982.25 Ã· 6 = 163.70
163.70 Ã· 8= 20.46
20.46Ã·10=2.04
Answer : Option D
Question: The sum of the squares of the first 15 positive integers (1^2 + 2^2 + 3^2 + . . . + 15^2) is equal to 1280. What is the sum of the squares of the second 15 positive integers (16^2 + 17^2 + 18^2 + . . . + 30^2) ?
A. 2480
B. 3490
C. 6785
D. 8255
Answer: D. 8255
Explanation: You'll never need a formula for the sums of squares on the actual GMAT. You don't need to use that formula here, though it's not all that straightforward to solve without one. Two different approaches:
16^2 + 17^2 + 18^2 + ... + 30^2 = (15 + 1)^2 + (15 + 2)^2 + (15 + 3)^2 + ... + (15 + 15)^2
Now we can expand each square; they are all in the (x + y)^2 = x^2 + 2xy + y^2 pattern.
= (15^2 + 2*15 + 1^2) + (15^2 + 4*15 + 2^2) + (15^2 + 6*15 + 3^2) + ... + (15^2 + 30*15 + 15^2)
Now we have fifteen 15^2 terms, so adding these gives 15*15^2 = 15^3 = 3375. We also have the entire sum 1^2 + 2^2 + ... + 15^2, which we know is equal to 1240. Finally adding the middle terms, we have:
2*15 + 4*15 + 6*15 + ... + 30*15 = 15(2 + 4 + 6 + .... + 30) = 15*2*(1 + 2 + 3 + ... + 15) = 15*2*8*15 = 3600
So the sum must be 3375 + 1240 + 3600 = 8215
Alternatively, we can use a different factoring pattern. We want to find the value of 30^2 + 29^2 + ... + 17^2 + 16^2. Well if we subtract 15^2 + 14^2 + .... + 2^2 + 1^2 from this, the answer will be 1240 less than what we want to find. So if we can find the value of
30^2 + 29^2 + ... + 17^2 + 16^2 - (15^2 + 14^2 + .... + 2^2 + 1^2)
then we can add 1240 to get the answer. Now grouping the terms above to get differences of squares, we have
= (30^2 - 15^2) + (29^2 - 14^2) + ... + (16^2 - 1^2)
and factoring each of these using x^2 - y^2 = (x + y)(x - y), we have
= 45*15 + 43*15 + 41*15 + ... + 17*15 = 15(45 + 43 + 41 + ... + 17)
In brackets we have an equally spaced sum with fifteen terms, which we can evaluate using the familiar formula. So the above equals
15*15*62/2 = 6975
and adding back the 1280, we get the answer of 8255.(ANS D)
Question: John completes a piece of work in 10 days, Rose completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is?
A.6 days
B.8 days
C.10 days
D.12 days
Answer: B.8 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 × 40/50 = 8 days
B)
Question: A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in?
A.17
B.19
C.18
D.14
Answer: D.14
Explanation: Work done by the tank in 1 hour = (1/2 - 1/3) = 1/14 Leak will empty the tank in 14 hrs. Answer: D
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 25 hours and 16 hours respectively. The ratio of their speeds is?
A.4:5
B.4:3
C.4:4
D.4:9
Answer: A.4:5
Explanation: Let us name the trains A and B.
Then, (A's speed) : (B's speed)
= √b : √a = √16 : √25 = 4:5
Answer:A
Question: How many three-digit integers between 311 and 401, exclusive, are divisible by 3 when the tens digit and the hundered digit are switched?
A.30
B.19
C.22
D.3
Answer: A.30
Explanation: Answer is 30
No of digits between 311 and 401 (exclusive) = 401-311-1 = 89
No Intergers divisble by 3 =~ 89/3 ~ 30
Divsiblivity rule for 3 is Sum of all digits must be divisble by 3. It doesn't matter if hundred digit and tens digits are switched.
e.g 372 is divisble by 3 (becae 3+7+2= 12 (divisble by 3))
switch digits 732 also divisble by 3 (becae 7+3+2= 12 (divisble by 3))
Divsiblivity rule for 3 is Sum of all digits must be divisble by 3. It doesn't matter if hundred digit and tens digits are switched.
You have right. So it is enough to proceed like usual to find the numbers in a given range that are divisible by 3. So 399-312/3 +1 =30.
Answer : A
Question: Large, medium and small ships are used to bring water. 4 large ships carry as much water as 7 small ships; 3 medium ships carry as much water as 2 large ships and 1 small ship. If 15 large, 7 medium and 14 small ships, each made 36 journeys to bring a certain quantity of water, then in how many journeys will 12 large, 14 medium and 21 small ships bring the same quantity of water?
A.29
B.30
C.20
D.50
Answer: A.29
Explanation: Explanation :
Here, Large, Medium and Small ships are denoted by the symbol L, M and S.
Now, according to the question,
4L = 7S. ------(i)
3M = 2L + S. ------(ii)
Using above equations, the ratios of the capacity of the Large, Medium and Small ships are :-
7: 6 : 4.
Let, the number of journeys required be x. Since, quantity of water remains the same, so :-
=((15×7+7×6+14×4)36) = x (12×7+14×6+21×4).
=>((15×7+7×6+14×4)36) / (12×7+14×6+21×4)= x
=>x=7308/252
=>x=29.
Answer : A
Question: The sale price sarees listed for Rs.200 after successive discount is 20% and 5% is?
A.187
B.169
C.152
D.178
Answer: C.152
Explanation: 200*(80/100)*(95/100)
= 152
Answer:C
Question: Bhavan travelled for 20 hours. He covered the first half of the distance at 50 kmph and remaining half of the distance at 40 kmph. Find the distance travelled by Bhavan?
A.888.89
B.788.89
C.899.89
D.688.89
Answer: A.888.89
Explanation: Let the distance travelled be x km.
Total time = (x/2)/50 + (x/2)/40= 20 => x/100 + x/80 = 20 => (4x + 5x)/400 = 20
=> x = 888.89 km
Answer:A
Question: Mary purchased Brand X pens for $2 apiece and brand Y for $1 apiece. If Elena purchased a total of 12 of these pens for $20.00, how many brand X pens did she purchase?
A.8
B.9
C.5
D.4
Answer: A.8
Explanation: 2x+y=20 -only one positive integers solutions x=8 and y=4
Answer is A
Question: Of the families in City X in 1994, 35 percent owned a personal computer. The number of families in City X owning a computer in 1998 was 20 percent greater than it was in 1994, and the total number of families in City X was 4 percent greater in 1998 than it was in 1994. what percent of the families in City X owned a personal computer in 1998?
A.50.12%
B.40.52%
C.40.56%
D.40.38%
Answer: D.40.38%
Explanation: Say a 100 families existed in 1994 then the number of families owning a computer in 1994 - 40
Number of families owning computer in 1998 = 35 * 120/100 = 42
Number of families in 1998 = 104
The percentage = 42/104 * 100 = 40.38%.
Option: D
Question: six years ago, the ratio of the ages of kunal and sagar was 6:5. four years hence, the ratio of their ages will be 11:10. what is sagar's age at present?
A.18 years
B.16 years
C.22 years
D.20 years
Answer: B.16 years
Explanation: the age of kunal and sagar 6 years ago 6x and 5x respectively.
((6x+6)+4)/((5x+6)+4)=11/10
10(6x+10)=11(5x+10)
5x=10. x=2, sagar's present age = (5x+6)=16 years
correct answer (B)
Question: A’s speed is 20/14 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat?
A.1/17
B.3/17
C.1/10
D.6/20
Answer: D.6/20
Explanation: We have the ratio of A’s speed and B’s speed. This means, we know how much distance A covers compared with B in the same time.
This is what the beginning of the race will look like:
(Start) A_________B______________________________
If A covers 20 meters, B covers 14 meters in that time. So if the race is 20 meters long, when A reaches the finish line, B would be 6 meters behind him. If we want the race to end in a dead heat, we want B to be at the finish line too at the same time. This means B should get a head start of 6 meters so that he doesn’t need to cover that. In that case, the time required by A (to cover 20 meters) would be the same as the time required by B (to cover 14 meters) to reach the finish line.
So B should get a head start of 6/20th of the race.
Answer (D)
Question: A warehouse had a square floor with are 10,000 sq.metres. A rectangular addition was built along
one entire side of the warehouse that increased the floor by one-half as much as the original floor. How many metres did the addition extend beyond the original building?
A.10
B.20
C.50
D.200
Answer: C.50
Explanation: length=100,b=?
area of rectangle=l*b
original floor=10,000 sq.metres
increasing the original floor by half of the original floor=10000+1/2(10000)
=15000
so 15000-10000=5000(area of rectangular portion)
l*b=5000
l=100 so 100*b=5000 ->b=50
so extended part is of 50metres
ANSWER:C
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:
A.14 years
B.19 years
C.33 years
D.38 years
Answer: A.14 years
Explanation: Let the son's present age be x years. Then, (38 - x) = x
2x = 38.
x = 19.
Son's age 5 years back (19 - 5) = 14 years. Answer: Option A
Question: There are 3 numbers A, B and C. If A:B = 3/4, B:C = 4/5, C:D = 5/6, then C:D will be?
A.1 : 2
B.3 : 5
C.5 : 7
D.5:6
Answer: D.5:6
Explanation: Sol. A : B = 3 : 4, B : C = 4 : 5, C : D = 5 : 6
∴A∶B∶C∶D= 3 : 4 : 5 : 6.
Thus, C: D = 5 : 6
D
Question: In the xy plane line m has the equation 4x + y = e. Line n passes through the origin and is perpendicular to line m. If point p has the coordinates (r, r+1) and is on both line n and m what is the value of r?
A.-4/3
B.1/4
C.-4
D.3/4
Answer: A.-4/3
Explanation: The equation of line m is y=-4x+e. Now, since line n is perpendicular to line m, then its slope is negative reciprocal of the slope of line m, so the slope of n is 1/4. Next, as line n passes through the origin (0, 0) and has the slope of 1/4 then its equation is y=1/4*x.
Point (r, r+1) lies on line n means that (r+1)=1/4*r --> r=-4/3.
Answer: A.
Question: A train crosses a 120-metre and a 70-metre long plat form in 17 seconds and 12 seconds respectively. What is the speed of the train ?
A.10 ms-1
B.16 ms-1
C.20 ms-1
D.24 ms-1
Answer: A.10 ms-1
Explanation: Explanation :
let the length of the train be x
∴ 120+x/17 = 70+x/12
1440 + 12x = 1190 + 17x
∴ x = 250/5 = 50m
∴ Speed = 120+50/17 = 170/17 = 10 ms-1
Answer : Option A
Question: What is the dividend. divisor 17, the quotient is 9 and the remainder is 5?
A.150
B.54
C.158
D.160
Answer: C.158
Explanation: D = d * Q + R
D = 17 * 9 + 5
D = 153 + 5
D = 158
C)
Question: The cost of a car was $3,000 in 1960. In 2010, the price had increased to $5,000. What was the percent increase in the cost of the car?
A.33.3%
B.45%
C.60%
D.66.6%
Answer: D.66.6%
Explanation: Increase = 5000-3000 = 2000
% increase = 2000*100/3000 = 66.6%
Answer: option D
Question: A patient was given a bottle of tablets by the doctor and he was asked to take five tablets in a gap of 30 minutes.
In how much time will he be able to take all the five tablets?
A.1 Hour.
B.2 Hour.
C.3 Hour.
D.None
Answer: B.2 Hour.
Explanation: Suppose he takes the first tablet at 8:00 pm. Then the second will be consumed by him at 8:30, third at 9:00, fourth at 9:30 and fifth at 10:00.
Time = 2 hour
Answer B
Question: If n is a positive integer and n^2 is divisible by 150, then what is the largest positive integer that must divide n?
A.10
B.20
C.30
D.40
Answer: C.30
Explanation: 150 = 2 * 3 * 5^2
If 150 divides n^2, then n must be divisible by 2 * 3 * 5 = 30
The answer is C.
Question: A can do a piece of work in 10 days and B can do the same work in 12 days. A and B worked together for 3 days. How many more days are required to complete the remaining work if they work together?
A.3 (5/18)
B.3 (5/16)
C.2 (5/11)
D.3 (5/13)
Answer: C.2 (5/11)
Explanation: A can do 1/10 of the work in a day.
B can do 1/12 of the work in a 1 day.
Both of them together can do (1/10 + 1/12) part of work in 1 day = (6 + 5)/60 = 11/60
They take 60/11 days to complete the work together.
Given that they already worked for 3 days.
The number of days required to complete remaining work => 60/11 - 3 = 27/11 = 2 (5/11) days.
Answer:C
Question: How many factors of 240 are also multiples of 3 ?
A.5
B.8
C.9
D.10
Answer: D.10
Explanation: take factors of 240
240= 2^4*3^1*5^1
Total factors of 240= (4+1)*(1+1)*(1+1)
=5*2*2
=20
out of total factors of 20, half will have 0 as power of 3 and half will have 1 as power of 3. It is because we have considered only 0 and 1 as power of 3 to compute total factors of 240.
Therefore factors that are multiple of 3= 20/2= 10
Ans - D
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
A.243 m
B.240 m
C.245 m
D.249 m
Answer: C.245 m
Explanation: Speed =45 x5/18 m/sec=25/2m/sec.
Time = 30 sec.
Let the length of bridge be x metres.
Then,130 + x/30=25/2
2(130 + x) = 750
x = 245 m.
Answer C
Question: A sells a bike to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays Rs. 225 for it, the cost price of the bike for A is:
A.150
B.230
C.120
D.430
Answer: A.150
Explanation: A
125% of 120% of A = 225
125/100 * 120/100 * A = 225
A = 225 * 2/3 = 150.
Question: A train covers a distance in 50 min, if it runs at a speed of 48kmph on an average. The speed at which the train must run to reduce the time of journey to 40min will be
A.47 kmph
B.60 kmph
C.69 kmph
D.37 kmph
Answer: B.60 kmph
Explanation: B
60 kmph
Time = 50/60 hr = 5/6hr
Speed = 48mph
distance = S*T = 48 * 5/6 = 40km
time = 40/60hr = 2/3hr
New speed = 40* 3/2 kmph = 60kmph
Question: A certain collage has total of 600 seniors each majoring in exactly one of six subjects. A minimum of 20 seniors major in each six subjects. If three quarter of the seniors major in one of four subjects, what is the greatest possible number of seniors majoring in one of the other two subjects?
A.100
B.130
C.75
D.60
Answer: B.130
Explanation: Answer B
600 = 450 + 20 + x => x = 130
= 3/4 * 600 in 4 subjects + 20 min for 5th subject + x = 600
Question: Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 1.5% more. She would get how much?
A.9560
B.96288
C.26667
D.1662
Answer: A.9560
Explanation: (8000*3*1.5)/100 = 360
9200
--------
9560
Answer:A
Question: A textile worker’s wages are increased by 10% and afterwards decreased by 10 %. Find the change percentage in his wages.
A.1% decrease
B.2% decrease
C.5% decrease
D.7% decrease
Answer: A.1% decrease
Explanation: Explanation:
Let workers wages = X
A 10% increase would mean new wages
= (110/100) X
A 10% decrease would mean new wages
= (90/100) (110/100 X)
= 99/100 X which means a decrease of 1 %
ANSWER: A
Question: One week, a certain truck rental lot had a total of 18 trucks, all of which were on the lot Monday morning. If 50% of the trucks that were rented out during the week were returned to the lot on or before Saturday morning of that week, and if there were at least 12 trucks on the lot that Saturday morning, what is the greatest number of different trucks that could have been rented out during the week?
A.18
B.16
C.12
D.8
Answer: C.12
Explanation: N - Not rented trucks; R - Rented trucks
N + R = 18
N + R/2 = 12
R = 12
C
Question: In a village of 2,600 people, 800 people are over 70 years old and 850 people are female. It is known that 40 percent of the females are younger than 70 years old. If no one in the village is 70 years old, what is the probability that a person chosen at random is either a female or younger than 70 years old?
A.231/260
B.117/130
C.51/65
D.23/32
Answer: A.231/260
Explanation: The number of people younger than 70 years old is 2600-800 = 1800
The number of females older than 70 years old is 0.6*850 = 510
The number of people who are either female or younger than 70 is 1800+510 = 2310.
P(a person is younger than 70 or male) = 2310/2600 = 231/260
The answer is A.
Question: A manufacturer of a certain product can expect that between 0.4 percent and 0.5 percent of the units manufactured will be defective. If the retail price is $2,500 per unit and the manufacturer offers a full refund for defective units, how much money can the manufacturer expect to need to cover the refunds on 20,000 units?
A. Between $15,000 and $25,000
B. Between $30,000 and $50,000
C. Between $200,000 and $250,000
D. Between $150,000 and $250,000
Answer: C. Between $200,000 and $250,000
Explanation: Number of defective units is between = .4 % of 20000 and .5% of 20000
= 80 and 100
Retail Price per unit = 2500 $
Expected price of refund is between = 2500 x 80 and 2500 x 100
=2,00,000 and 2,50,000 dollars
Answer C
Question: Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is
A.17/28
B.17/27
C.17/19
D.probability of 17/20
Answer: D.probability of 17/20
Explanation: n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 - 1/20 = 17/20
Answer: D
Question: A certain factory produces buttons and buckles at a uniform weight. If the total weight of 2 buttons and 2 buckles is one third of 11 buckles and 3 buttons, then the weight of 3 buttons and 4 buckles is how many times that of 5 buckles and 6 buttons?
A.7/15.
B.4/9.
C.6/11.
D.3/5.
Answer: D.3/5.
Explanation: 2buttons + 2buckles = 1/3(11buckles + 3buttons)
6buttons + 6buckles = 11buckles + 3buttons
3buttons = 5buckles
Weight of 3buttons and 4buckles = 5buckles + 4buckles = 9buckles
Weight of 6buttons and 5buckles = 10buckles + 5buckles = 15buckles
(3buttons and 2buckles) = x * (6buttons and 5buckles)
9 = x*15
x = 9/15=3/5
Answer: D
Question: A truck travels 20 miles due north, 30 miles due east, and then 20 miles due north. How many miles is the truck from the starting point?
A.20.3
B.44.7
C.50
D.70
Answer: C.50
Explanation: We have two right angle triangles with sides 20 and 15
The distance between starting and end point = sum of the hypotenuse of both the triangles.
Hypotenuse = [400 + 225]^(1/2) = 25
Hence the total distance between end point and starting point = 25 + 25 = 50
Correct Option: C
Question: what is the next term of this series6,10,9,15,..?
A.9
B.10
C.11
D.12
Answer: D.12
Explanation: 3&2=6;
5*2=10;
3*3=9;
3*5=15.
3*4=12
ANSWER:D
Question: Suppose you answer the last three questions on this test at random. What is the most likely
number of these three questions that you will answer correctly?
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: There are five answers to each question The probabilities you will correctly answer
respectively 0, 1, 2, and 3 are
4/5
4/5
4/5
=
64/125
;
3
1/5
4/5
4/5
=
48/125
;
3
1/5
1/5
4/5
=
12/125
;
1/5
1/5
1/5
=
1/125
:
The first is the most likely possibility. Indeed, it is more probable than the other three combined
correct answer A