RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a meeting of 4 representatives from each of 5 different companies, each person shook hands with every person not from his or her own company. If the representatives did not shake hands with people from their own company, how many handshakes took place?
A.170
B.160
C.180
D.190
Answer: B.160
Explanation: In fact, all 20 people will shake hands with 16 others.
So, it SEEMS like the TOTAL number of handshakes = (20)(16)
HOWEVER, we need to keep in mind that we have counted each handshake TWICE.
To account for this DUPLICATION, we must divide (20)(16) by 2.
So, the TOTAL # of handshakes = (20)(16)/2 = 160
Answer : B
Question: It is being given that (2^32 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
A.(2^16 + 1)
B.(2^16 - 1)
C.(7 x 2^23)
D.(2^96 + 1)
Answer: D.(2^96 + 1)
Explanation: Let 2^32 = x. Then, (2^32 + 1) = (x + 1).
Let (x + 1) be completely divisible by the natural number N. Then,
(2^96 + 1) = [(2^32)^3 + 1] = (x^3 + 1) = (x + 1)(x^2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
Answer:D
Question: Rosy has 8 shirts and 9 pants. How many clothing combinations does Barbara have, if she doesn’t wear 6 specific shirts with 5 specific pants?
A.41
B.66
C.42
D.70
Answer: C.42
Explanation: Total no of combinations available is= 8 shirts X 9 pants = 72
Eliminate the 6 shirts X 5 pants combo = 30 which gives.......>> 72-30=42
ANSWER: C
Question: A certain set of numbers has an average (arithmetic mean) of 50 and a standard deviation of 50.5. If c and n, two numbers in the set, are both within 2 standard deviations from the average, then which of the following could be the sum of c and n?
A.-200
B.-130
C.-104
D.51
Answer: D.51
Explanation: 2 standard deviations from the average is frommean - 2*SDtomean + 2*SD, thus from 50-2*50.5=51 to 50+2*50.5=151:
-51 < c < 151
-51 < n < 151
-102 < c+n < 302.
Only option D is in this range.
Answer: D.
Question: Seven machines at a certain factory operate at the same constant rate. If six of these machines, operating simultaneously, take 42 hours to fill a certain production order, how many fewer hours does it take all seven machines, operating simultaneously, to fill the same production order?
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: The total work is 6*42 = 252 machine hours
The time required for seven machines is 252/7 = 36 hours, thus 6 fewer hours.
The answer is D.
Question: How many cubes of 5 cm edge can be put in a cubical box of 1 m edge.
A.1770cm
B.8000 cm
C.7860 cm
D.6170 cm
Answer: B.8000 cm
Explanation: Number of cubes =100âˆ—100âˆ—100/5*5*5=8000
Note: 1 m = 100 cm
Answer:B
Question: A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.18000. A's share is?
A.9887
B.2792
C.6000
D.2876
Answer: C.6000
Explanation: x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 18000 = 6000
Answer: C
Question: X starts a business with Rs.45000. Y joins in the business after 7 months with Rs.30000. What will be the ratio in which they should share the profit at the end of the year?
A.1:2
B.18:5
C.1:5
D.3:1
Answer: B.18:5
Explanation: Explanation:
Ratio in which they should share the profit
= Ratio of the investments multiplied by the time period
=45000Ã—12:30000Ã—5
=45Ã—12:30Ã—5
=3Ã—12:2Ã—5
=18:5
Answer: Option B
Question: Brenda caught three less than twice as many fish as Olga. Together they caught 33 fish. How many fish did Olga catch?
A.21
B.20
C.13
D.12
Answer: D.12
Explanation: If Olga = f, Brenda= 2(f)-3
Brenda+Olga =33
(2f-3)+(f) =33
2f+f-3+3=33+3
3f=36
f=12
Olga has 12 fish, the answer is D)
Question: A train 150 m long running at 72 kmph crosses a platform in 25 sec. What is the length of the platform?
A.287
B.298
C.350
D.726
Answer: C.350
Explanation: D = 72 * 5/18 = 25
= 500 – 150
= 350
Answer: C
Question: A train speeds past a pole in 11 seconds and a platform 120 m long in 22 seconds. Its length is?
A.128
B.177
C.199
D.120
Answer: D.120
Explanation: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 11 => y = x/11
x + 120 / 22 = x / 11
x = 120 m.
Answer:D
Question: Pavan travelled for 15 hours. He covered the first half of the distance at 30 kmph and remaining half of the distance at 25 kmph. Find the distance travelled by Pavan.
A.408 km
B.409 km
C.410 km
D.412 km
Answer: B.409 km
Explanation: Let the distance travelled be x km.
Total time = (x/2)/30 + (x/2)/25 = 15
=> x/60 + x/50 = 15
=> (5x + 6x)/300 = 15
=> x = 409 km
ANSWER:B
Question: The ratio of radius of a circle and the side of a square is 2 : 13. Find the ratio of their areas:
A.2 : 1
B.4 : 7
C.8 : 77
D.4 : 169
Answer: D.4 : 169
Explanation: radius/side = 2/13
â‡’ area of circle/area of square= 4/169
Answer: D
Question: Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2% more. She would get how much?
A.9680
B.2277
C.2999
D.2774
Answer: A.9680
Explanation: (8000*3*2)/100 = 480
9200
--------
9680
Answer:A
Question: A contractor hires 100 men to finish a job in 50 days. After 24 days, n men leave. After some more days, the contractor hires 2n more men to complete the job on time. For how many days did these 2n men work?
A.20
B.18
C.16
D.13
Answer: D.13
Explanation: Step1: Find Each day what % of work is finished ; it requires 50 days to complete which means each day 1/50= 2% work will be completed.
Step 2 : After 24 Days = 24* 2= 48% of work is finished. remaining is 52% ( which means if same 100 men were about to complete the job they would have required 26 more days)
Step3: Let us assume all people have left job. therefore contractor hires 2n people. initially it was taking 26 days to compete for n people. at present 2n people are present to finish job. hence 13 more days.
D
Question: A $500 investment and a $1,500 investment have a combined yearly return of 13 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have?
A.9%
B.15%
C.105/8%
D.11%
Answer: B.15%
Explanation: The equation we can form the question :
Return on Total Investment = Sum of individual Investments
(500+1500)(13)=(500âˆ—7)+(1500x), where x is the return on investment of 1500.
Solving the equation, we get x = 15% ( Option B)	ANSWER:B
Question: Three people with different speeds of 4.5kmph,0.5kmph and 8kmph move around a circular track of 11km.at what time they meet each other?
A.21 hours
B.22 hours
C.20 hours
D.23 hours
Answer: B.22 hours
Explanation: Time taken by 1st person to cover the circular track = 11/4.5 = 22/9
Time taken by 2nd person to cover the circular track = 11/0.5 = 22
Time taken by 3rd person to cover the circular track = 11/8
They meet for the 1st time after
time t = LCM (22/9,22,11/8)
= 22 hours
ANSWER:B
Question: January 1, 2007 was Monday. What day of the week lies on Jan. 2, 2008?
A.Monday
B.Tuesday
C.Wednesday
D.Friday
Answer: C.Wednesday
Explanation: The year 2007 is an ordinary year. So, it has 1 odd day.
day of the year 2007 was Monday
day of the year 2008 will be 2 days beyond Monday
Hence, It will be Wednesday. answer : C
Question: What is the smallest number which when diminished by 16, is divisible 4, 6, 8 and 10?
A.136
B.192
C.198
D.122
Answer: A.136
Explanation: Required Number
= (LCM of 4,6,8, and 10) + 16
= 120 + 16 = 136
Option A
Question: The probability that event M will not occur is 0.6 and the probability that event R will not occur is 0.6. If events M and R cannot both occur, which of the following is the probability that either event M or event R will occur?
A.1/5
B.2/5
C.3/5
D.4/5
Answer: D.4/5
Explanation: p(m) =0.4
p(r) =0.4
p(m intersection r) = 0 (If events M and R cannot both occur)
p(m or r) = 0.4+0.4 =0.8
Corrected !!
Answer D
Question: To save money, Arkadelphia Cream Cheese will reduce each dimension of its rectangular box container (which is entirely full of cream cheese) by 60%, and reduce the price it charges its consumers by 60% as well. By what percentage does this increase the price-per-cubic-inch that each consumer will pay for cream cheese?
A.1. No change
B.2. 50%
C.3. 525%
D.4. 300%
Answer: C.3. 525%
Explanation: Take smart numbers
Let,
L = 20: B = 10: H= 10 of initial box and Price = 100$
Therefore Price / cubic inch = 100 / (20*10*10) =0.05
Now, when dimensions are reduced by 60% and price also reduced by 60%
L = 8; B=4; H=4 and Price = 40$
Therefore price / cubic inch = 40 / (8*4*4) =0.3125
Percentage change = (0.3125- 0.05) *100/ 0.05 = 525%
Answer is C
Question: A rower can row upstream at 7 km/hr and downstream at 12 km/hr. What is the rower's rate in still water?
A.8.0 km/hr
B.8.5 km/hr
C.9.0 km/hr
D.9.5 km/hr
Answer: D.9.5 km/hr
Explanation: The rate in still water is 1/2 * (12 + 7) = 9.5 km/hr
The answer is D.
Question: How many trailing Zeroes does 53! + 54! have?
A. 12
B. 13
C. 14
D. 15
Answer: B. 13
Explanation: 53! + 54! = 53! + 54 * 53!
= 53! (1 + 54)
= 53! * 55
Number of trailing 0s in 53! = number of 5s in the expansion of 53!
= 10 + 2 = 12
There is 1 more 5 in 55.
Hence, total number of trailing 0s = 12 + 1 = 13
Answer (B).
In most cases, when we are adding multiple terms, all of which have trailing 0s, the sum will have as many trailing 0s as that in the lowest term. Example: 20 + 2300 + 34210000 = 34212320 -> one 0 because lowest term 20 has one 0.
This case has an exception because of an additional 5 in 55. answer is B
Question: A computer factory produces 5376 computers per month at a constant rate, how many computers are built every 30 minutes assuming that there are 28 days in one month?
A.2.25.
B.3.125.
C.4.5.
D.4.00.
Answer: D.4.00.
Explanation: Number of hours in 28 days = 28*24
Number of 30 mins in 28 days = 28*24*2
Number of computers built every 30 mins = 5376/( 28*24*2) = 4.00
Answer D
Question: A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
A.65 liters
B.44
C.10 liters water
D.45 liters
Answer: C.10 liters water
Explanation: Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters. Answer: C
Question: If x > 7, which of the following is equal to (x^2 + 10x + 25)/(x^2 - 25) ?
A.(x + 5)/(x - 5)
B.(x - 4)/(x + 4)
C.(x - 2)/(x + 4)
D.(x + 4)/(x - 4)
Answer: A.(x + 5)/(x - 5)
Explanation: (x^2 + 10x + 25)/(x^2 - 25)
= (x + 5)(x + 5) / (x + 5)(x - 5)
=(x + 5)/(x - 5)
A. (x + 5)/(x - 5)
Question: A certain sum of money at simple interest amounted Rs.900 in 9 years at 5% per annum, find the sum?
A.337
B.268
C.198
D.620
Answer: D.620
Explanation: 900 = P [1 + (9*5)/100]
P = 620'
Answer:D
Question: In an election, candidate Douglas won 66 percent of the total vote in Counties X and Y. He won 74 percent of the vote in County X. If the ratio of people who voted in County X to County Y is 2: 1, what percent of the vote did candidate Douglas win in County Y?
A.25%
B.30%
C.50%
D.75%
Answer: C.50%
Explanation: given voters in ratio 2:1
let X has 200 votersY has 100 voters
for X 66% voted means 74*200=148 votes
combined for XY has 300 voters and voted 66% so total votes =198
balance votes=198-148=50
As Y has 100 voters so 50 votes means 50% of votes required
Ans C
Question: A & B started one company. They invest Rs. 1,00,000/- each. They deposit the money to Bank. Bank give 1% interest per month. After 2 years B left from company and asked A to return the money with interest. A says it will take time to release the FD and he assure B to give the money withinterest @0.5%. B Agreed this. What is the profit of A?
A.A)48000
B.B)12000
C.C)36000
D.D)24000
Answer: C.C)36000
Explanation: Total Investment : 100000/-*2=200000/-
Interest rate @ 1%= 200000*1%*12*2= 48000/-
Total : 248000/-
Interest to B : 100000/-*0.5%*12*2 = 12000/-
Paid to B : 100000/- + 12000/- = 112000/-
profit of A : 36000/-
Answer is C
Question: How many seconds will a 620 metre long train take to cross a man running with a speed of 8 km/hr in the direction of the moving train if the speed of the train is 80 km/hr?
A.25
B.30
C.31
D.45
Answer: C.31
Explanation: Explanation :
Speed of train relatively to man = ( 80- 8)km/hr
= 72 km /hr
= (72 x 5 / 18)m/sec
= 20 m/sec
Time taken to pass the man = (620/ 20)sec = 31 sec.
Answer : C
Question: In how many ways, a committee of 5 members can be selected from 6 men and 5 ladies, consisting of 3men and 2 ladies?
A.75
B.152
C.175
D.200
Answer: D.200
Explanation: (3 men out 6) and (2 ladies out of 5) are to be chosen
Required number of ways = (6C3 * 5C2) = 200
Answer is D
Question: By selling a house for Rs.35000, it was found that 1/6 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?
A.38020
B.28500
C.38028
D.38019
Answer: B.28500
Explanation: CP + CP/6 = 35000
CP = 30000
SP = 30000*(95/100)
=28500
Answer: B
Question: There are 5 sweets – Milk peda, Ice cream, Rasagulla Paper sweet and Rasamalai that I wish to eat on 5 consecutive days – Monday through Friday, one sweet a day, based on the following self imposed constraints:
1) Paper sweet is not eaten on Monday
2) If Milk peda is eaten on Monday, then Paper sweet must be eaten on Friday
3) If Paper sweet is eaten on Tuesday, Ice cream should be eaten on Monday
4) Rasagulla should be eaten on the day preceding to the day of eating Milk peda.
Based on the above, Rasagulla can be eaten on any day except?
A.Tuesday
B.Monday
C.Wednesday
D.Friday
Answer: D.Friday
Explanation: as Milk peda is eaten on Monday, then Paper sweet must be eaten on Friday
and Rasagulla should be eaten on the day preceding to the day of eating Milk peda
so milk peda cannot be eaten on monday as day preceding it is friday and condition 2 denies rasagulla on friday
ANSWER:D
Question: Average of all prime numbers between 35 to 50
A.42
B.37.8
C.39
D.39.8
Answer: A.42
Explanation: Explanation:
Prime numbers between 35 and 50 are:
37, 41, 43, 47
Average of prime numbers between 35 to 50 will be
(37+41+43+47 / 4)=168 / 4=42
Option A
Question: If a bicyclist in motion increases his speed by 30 percent and then increases this speed by 10 percent, what percent of the original speed is the total increase in speed?
A.10%
B.40%
C.43%
D.64%
Answer: C.43%
Explanation: let the sped be 100
an increase of 30%
the speed now is 130
a further increase of 10% on 130 =13
total increase =43 on 100 =43% C
Question: Find the least number with which 16200 should be multiplied, to make it a perfect cube.
A.36
B.48
C.45
D.360
Answer: C.45
Explanation: 16200 = 23 * 34 * 52
A perfect cube has a property of having the indices of all its prime factors divisible by 3.
Required number = 32 * 5 = 45.
ANSWER:C
Question: A train 280 m long passed a pole in 28 sec. How long will it take to pass a platform 650 m long?
A.93 sec
B.89 sec
C.54 sec
D.27 sec
Answer: A.93 sec
Explanation: Speed = 280/28 = 10 m/sec.
Required time = (280 + 650)/10
= 93 sec.
Answer: A
Question: What is the remainder when you divide 2^200-3 by 7?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: answer is A. this is very similar to the 32^32^32-3 divided by 7 question.
Question: A particular library has 75 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 60 percent of books that were loaned out are returned and there are 65 books in the special collection at that time, how many books of the special collection were loaned out during that month?
A.20
B.25
C.35
D.40
Answer: B.25
Explanation: Total = 75 books.
60% of books that were loaned out are returned --> 100%-60%=40% of books that were loaned out are NOT returned.
Now, there are 68 books, thus 75-65=10 books are NOT returned.
{loaned out}*0.4=10 --> {loaned out}=25.
Answer: B.
Question: The ratio of the number of students appearing for examination in the year 1998 in the states A, Band C was 3 : 5 : 6. Next year if the number of students in these states increases by 20%, 10% and 20% respectively, the ratio in states A and C would be 1 : 2. What was the number of students who appeared for the examination in the state A in 1998?
A.7200
B.6000
C.7500
D.Data inadequate
Answer: D.Data inadequate
Explanation: Let the number of students appearing for examination in the year 1998 in the states A, B and C be 3x, 5x and 6x respectively.
According to the question,
3x×120/100 /6x×120/100=12
Hence data inadequate.
Answer D
Question: How many positive integers less than 5,000 are evenly divisible by neither 15 nor 20?
A.4,514
B.4,477
C.4,521
D.4,428
Answer: B.4,477
Explanation: integers less than 5000 divisible by 15 5000/15 =333.something , so 333
integers less than 5000 divisible by 20 5000/20 = 238.## , so 238
we have double counted some, so take LCM of 15 and 20 =105 and divide by 5000, we get 47. so all numbers divisible by 15 and 20 = 333 +238 -47 =524
now subtract that from 4999. 4999- 524 = 4477 answer B.
Question: In what proportion water must be added to spirit to gain 20% by selling it at the cost price ?
A.1 : 9
B.1 : 1
C.1 : 5
D.1 : 3
Answer: C.1 : 5
Explanation: Let the C.P of spirit be = Rs.10 per litre
S.P of the mixture = Rs. 10 per litre
Profit = 20
C.P of the mixture = Rs. = Rs. per litre
Ratio of water and spirit = 1 : 5
Answer:C
Question: 12 men working 8 hours per day complete a piece of work in 10 days.To complete the same work in 8 days,working 15 hours a day,the number of men required,is
A.4
B.5
C.6
D.8
Answer: D.8
Explanation: Solution
Let the required number of men be x.
Less days,More men (Indirect Propertion)
More working hrs per days,Less men (Indirect Propertion)
∴ 8 × 15 × x = 10 × 8 × 12 ⇔ x = 10x8x12/8x15= x= 8. Answer D
Question: There are 5 red shoes & 4 green shoes . If two of red shoes are drawn what is the probability of getting red shoes
A.1/18
B.1/14
C.5/18
D.1/15
Answer: C.5/18
Explanation: taking 2 red shoe the probability is 5C2
from 9 shoes probability of taking 2 red shoes is 5C2/9C2=5/18
ANSWER:C
Question: 40% of Ram's marks is equal to 20% of Rahim's marks which percent is equal to 30% of Robert's marks. If Robert's marks is 80, then find the average marks of Ram and Rahim?
A.87
B.87
C.87
D.90
Answer: D.90
Explanation: Given, 40% of Ram's marks = 20% of Rahim's marks = 30% of Robert's marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 40% of Ram's marks = 24.
=> Ram's marks = (24 * 100)/40 = 60
Also, 20% of Rahim's marks = 24
=> Rahim's marks = (24 * 100)/20 = 120
Average marks of Ram and Rahim = (60 + 120)/2 = 90.
Answer: D
Question: What is the units digit of (3^11)(4^13)?
A.2
B.4
C.6
D.7
Answer: A.2
Explanation: -> The ones place of (~3)^n repeats after 4 times like 39713.
The ones place of (~4)^n repeats after 2 times like 464.
Then, 3^13=3^4*3+13^1.,
4^13=4^2*6+1=4^1=~4
which is (3^13)(4^13) (3^1)(~4)=(~3)(~4)=~2. Therefore, the answer is A.
Question: A space shuttle orbits the earth at about 2 kilometers per second. This speed is equal to how many kilometers per hour?
A. 7,200
B. 8,880
C. 10,800
D. 28,800
Answer: A. 7,200
Explanation: Seconds in 1 hours:
60s in 1 min
60 min in 1 hr
60*60=3600 sec in 1 hr
2*3600=28,800
Answer: A
Question: A five digit number is to be formed using each of the digits 1, 2, 3, 4 and 5 ONLY ONCE. How many numbers can be formed when 3 and 5 are not together ?
A. 72
B. 36
C. 48
D. 60
Answer: A. 72
Explanation: Reqd ways = (Total No. of ways - cases when both 3 and 5 are together)
5 numbers can be arranged in 5 places in 5! ways. Now tie 3 and 5 together so effectively there are 4 nos. they can be arranged in 4! ways. 1 and 2 can be arranged within themselves in 2!ways.
Reqd. Answer = 5! - 4!2! = 120 - (24*2) = 72
Answer: A
Question: FOG + FOG + FOG + FOG = 1456.
If F,O and G are digits in a three-digit number in the preceding equation the F + O + G = ?
A.11
B.12
C.13
D.14
Answer: C.13
Explanation: given,FOG + FOG + FOG + FOG = 1456
4(FOG)=1456
=>FOG=364
Face value of F is:3
Face value of O is:6
Face value of G is:4
so F+O+G=3+6+4=13
ANSWER:C
Question: Which of the following fractions is at least thrice greater than 7/50?
A.2/5
B.11/34
C.43/99
D.8/21
Answer: C.43/99
Explanation: Answer C
7/50=0.14
43/99=0.45 which is 0.01434 greater than thrice times of 0.14
Question: 36 * 36 * 36 = 6^ ?
A.3
B.2
C.6
D.1
Answer: C.6
Explanation: 6^2 * 6^2 * 6^2 = 6^(2+2+2) = 6^6
Answer : 6
Answer : C
Question: The number 523rbc is divisible by 7,8,9. Then what is the value of r*b*c
A.504
B.532
C.210
D.180
Answer: D.180
Explanation: LCM of 7, 8 and 9 is 504, thus 523rbc must be divisible by 504.
523rbc=523000+rbc
523000 divided by 504 gives a remainder of 352.
Hence, 352+rbc=k*504.
k=1 rbc=152 --> r*b*c=10
k=2 rbc=656 -->r*b*c=180
As rbc is three digit number k can not be more than 2.
Two answers? Well only one is listed in answer choices, so D.
Answer: D.
Question: A is a working partner and B is a sleeping partner in a business. A puts in 60,000 and B 40,000. A gets 20% of the profit for managing the business, and the rest is divided in proportion to their capitals. Find the share of A in profit of 10000.
A.6800
B.5800
C.4800
D.6500
Answer: A.6800
Explanation: The amount A gets for managing
= 20% of Rs. 10000 = 2000
Remaining profit = 10000 – 2000 = 8000
This is to be divided in the ratio 3 : 2.
Share of A = 3/5 of 8000 = 4800
⇒ Total share of A = 4800 + 2000 = 6800.
Answer A
Question: A train 480 m in length crosses a telegraph post in 16 seconds. The speed of the train is?
A.22 kmph
B.108 kmph
C.54 kmph
D.71 kmph
Answer: B.108 kmph
Explanation: S = 480/16 * 18/5 = 108 kmph
Answer:B
Question: A certain hall contains two cuckoo clocks. If the first clock chirps 20 times per hour and the second clock chirps 8 times per hour, and both clocks chirp for the first time at 2:03 pm, at what time will the first clock have chirped three times as many times as the second clock can chirp per hour?
A.2:40 pm
B.2:55 pm
C.3:12 pm
D.3:24 pm
Answer: C.3:12 pm
Explanation: The question is asking when the first clock will have chirped 24 times (3*8 chirps).
The first clock chirps once every 3 minutes.
If the first chirp is at 2:03, then the 24th chirp is at 72 minutes after 2:00.
The answer is C.
Question: The G.C.D. of 1.08, 0.36 and 0.3 is?
A.0.06
B.0.9
C.0.18
D.0.108
Answer: A.0.06
Explanation: Given numbers are 1.08,0.36 and 0.30.
H.C.F of 108, 36 and 30 is 6
H.C.F of given numbers=0.06.
Correct Options:A
Question: If n is an integer and n^4 is divisible by 8, which of the following could be the remainder when n is divided by 8?
A.1
B.2
C.3
D.5
Answer: B.2
Explanation: option 1
Remainder 1 means 8+1=9
n^4= 9^4= 9*9*9*9/8 is not an integer
option 2
Remainder 2 means 8+2=10
n^4= 10*10*10*10/8 is an integer means n^4 is divisible by 8 if we take n=2
so B is correct
Question: In a 200m race, if A gives B a start of 25 metres, then A wins the race by 10 seconds. Alternatively, if A gives B a start of 45 metres the race ends in a dead heat. How long does A take to run 200m?
A.100 seconds
B.112.5 seconds
C.77.5 seconds
D.87.5 seconds
Answer: C.77.5 seconds
Explanation: Explanatory Answer
A gives B a start of 25 metres and still wins the race by 10 seconds.
Alternatively, if A gives B a start of 45 metres, then the race ends in a dead heat.
Therefore, the additional 20 metres start given to B compensates for the 10 seconds.
i.e., B runs 20 metres in 10 seconds.
Hence, B will take 100 seconds to run 200 metres.
We know that A gives B a start of 45 metres. B will take 22.5 seconds to run this 45 metres as B runs 20 metres in 10 seconds or at the speed of 2 m/s.
Hence, A will take 22.5 seconds lesser than B or 100 - 22.5 = 77.5 seconds to complete the race.
Answer C
Question: A bus can hold 40 passengers. If there are 10 rows of seats on the bus, how many seats are in each row?
A.0
B.2
C.4
D.6
Answer: C.4
Explanation: No. of seats = 40/10 = 4
There are 4 seats in each row
Answer : C
Question: The first three terms of a proportion are 2, 8 and 16. The fourth term is?
A.22
B.64
C.67
D.60
Answer: B.64
Explanation: (8*16)/2 = 64
Answer:B