RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Sound is said to travel in air at about 1100 feet per second. A man hears the axe striking the tree, 11/5 seconds after he sees it strike the tree. How far is the man from the wood chopper?
A.2197 feet
B.2420 ft
C.2500 feet
D.2629 feet
Answer: B.2420 ft
Explanation: Distance =(1100*11/5)feet=2420 feet.
Correct Option: B
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 15 seconds. The speed of the train is?
A.35
B.50
C.88
D.66
Answer: A.35
Explanation: Speed of the train relative to man
= (125/15) m/sec = (25/3) m/sec. [(25/3) * (18/5)] km/hr
= 30 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5
= 30 ==> x
= 35 km/hr.
Answer:A
Question: On a store counter are exactly two boxes containing only purple marbles and yellow marbles. Box A has 30 purple marbles and 20 yellow marbles; box B has 15 purple marbles and 35 yellow marbles. If Melanie randomly selects one of the boxes and then randomly selects one marble from the box, what is the probability that the marble selected will be purple?
A. 3/20
B. 3/10
C. 9/20
D. 3/5
Answer: C. 9/20
Explanation: We are given that box A has 30 purple marbles and 20 yellow marbles and that box B has 15 purple marbles and 35 yellow marbles. We need to determine the probability, when selecting one marble from the box, of selecting a purple marble. Since we have two boxes, A and B, there are multiple scenarios to account for when selecting the marbles. We must account for the probability of first selecting either box and then secondly for selecting a purple marble. Let’s start with Box A.
P(selecting box A) = ½
P(selecting a purple marble in box A) = 30/50 = ⅗
Thus, the probability of selecting a purple marble from box A is ½ x ⅗ = 3/10
Next we can determine the probability of selecting a purple marble from box B.
P(selecting box B) = ½
P(selecting a purple marble in box B) = 15/50 = 3/10
Thus, the probability of selecting a purple marble from box B is ½ x 3/10 = 3/20
Now we can determine the probability of selecting a purple marble from box A or box B:
3/10 + 3/20 = 6/20 + 3/20 = 9/20.
Answer: C
Question: $ represents addition and * represents subtraction,what is the value of the following expression?
15 * 5 $ 15 $ 10 $ 30 * 25 * 35 * 25 $ 20 * 25 * 20
A.-15
B.-35
C.-55
D.-45
Answer: D.-45
Explanation: 15-5+15+10+30-25-35-25+20-25-20
=10+15+10+30-25-35-25+20-25-20
=25+10+30-25-35-25+20-25-20
=35+30-25-35-25+20-25-20
=65-25-35-25+20-25-20
=40-35-25+20-25-20
=5-25+20-25-20
=-20+20-25-20
=0-25-20
=-45
ANSWER:D
Question: A player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many diamonds as spades and twice as many hearts as diamonds. How many clubs does he hold
A.4
B.5
C.6
D.7
Answer: C.6
Explanation: Explanation:
Clearly, the black cards are either clubs or spades while the red cards are either diamonds or hearts.
Let the number of spades be x. Then, number of clubs = (7 - x).
Number of diamonds = 2 x number of spades = 2x;
Number of hearts = 2 x number of diamonds = 4x.
Total number of cards = x + 2x + 4x + 7 - x = 6x + 7.
Therefore 6x + 7 = 13 6x = 6 x - 1.
Hence, number of clubs = (7 - x) = 6.
Answer: C
Question: The length of the bridge, which a train 160 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
A.239
B.277
C.215
D.88
Answer: C.215
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (160 + X)/30
= 25/2 ==> 2(160 + X) = 750 ==> X = 215 m.
Answer: C
Question: If x = 9/3 and y = 4/3, what is the value of the expression -2x – y^2?
A.-28/51
B.-70/9
C.45/87
D.13/21
Answer: B.-70/9
Explanation: x = 9/3 and y = 4/3
==> -2(9/3) - (4/3)^2 = -18/3 - 16/4 = -70/9
Ans: B
Question: A rower can row upstream at 22 kph and downstream at 34 kph. What is the speed of the rower in still water?
A.28
B.29
C.30
D.31
Answer: A.28
Explanation: Let V be the rower's speed in still water.
Let S be the speed of the current in the stream
V-S = 22
V+S = 34
When we add the two equations, we get: 2V = 56
Then V = 28 kph.
The answer is A.
Question: A truck driver drove for 2 days. On the second day, he drove 3 hours longer and at an average speed of 15 miles per hour faster than he drove on the first day. If he drove a total of 1,000 miles and spent 21 hours driving during the 2 days, what was his average speed on the first day, in miles per hour?
A.25
B.30
C.35
D.39
Answer: D.39
Explanation: Day 1
2t+3=21
t=9
Day 2
t+3
9+3=12
9r+12(r+15)=1000
r=39
Answer:D
Question: A man sells a horse for Rs.140 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?
A.420
B.299
C.277
D.860
Answer: A.420
Explanation: CP = SP + 1CP = SP - g
140 + x = 980 - 2x
3x = 840=> x = 280
CP = 280 + 140 = 420
Answer: A
Question: A box contains 3 red balls and 4 black balls. One by one, every ball is selected at random without replacement. What is the probability that the fourth ball selected is black?
A.7/4
B.1/2
C.1/2
D.5/8
Answer: A.7/4
Explanation: My complicated version of your simple approach
Let the 5 black balls be BBBBB and 3 Red Balls be RRR
They can be arranged in 8 slots _ _ _ _ _ _ _ _
in (7!)/ (4!x3!)
If the fourth slot is Black ball then the arrangement will be to fill
_ _ _ B _ _ _ _
we have 7 slots and 3 Black (BBB) and 3 Red (RRR)
They can be arranged in (6!)/ (3!x3!)
Hence required probability = [(7!)/ (4!x3!)]/[(6!)/ (3!x3!)]
Ans = 7/4
A
Question: A sum fetched total simple interest of 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?
A.8925
B.8032.5
C.4462.5
D.8900
Answer: A.8925
Explanation: Let the sums be P.
Now, 45% of P = 4016.25
or, P = 8925
Answer A
Question: When a merchant imported a certain item, she paid a 7 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that the merchant paid was $112.70, what was the total value of the item?
A.$2420
B.$2610
C.$2860
D.$3050
Answer: B.$2610
Explanation: Let x be the value of the item.
0.07*(x-1000) = 112.70
x = 2610
The answer is B.
Question: 121, 169, 225, 289, 361, ?, F ind the missing number(?).
A.529
B.441
C.390
D.411
Answer: B.441
Explanation: The series consists of squares of consecutive ODD numbers .
Answer : B.
Question: On a two-dimensional coordinate plane, the line z = x^2 - x^3 touches the x-axis in how many places?
A. 0
B. 1
C. 2
D. 3
Answer: C. 2
Explanation: Apparently it's z = x^2 - x^3 instead of z = x^2 - z^3.
In this case: the x-intercept is the value(s) of x for z = 0.
0 = x^2 - x^3;
0 = x^2(1 - x);
x = 0 or x = 1.
Answer: C.
Question: A string of 50 light bulbs is wired in such a way that if any individual light bulb fails, the entire string fails. If for each individual light bulb the probability of failing during time period T is 0.05, what is the probability that the string of light bulbs will fail during the time period T?
A.0.05
B.(0.05)^50
C.1 - (0.96)^50
D.1 - (0.95)^50
Answer: D.1 - (0.95)^50
Explanation: The string of light bulbs will fail if at least one light bulb fails. So, let's find the probability of the opposite event and subtract that value from 1.
The opposite event is when none of the 50 light bulbs fails, since the probability of each light bulb not to fail is 1-0.05=0.95 the the probability that none of the 50 light bulbs fails is 0.95^50.
Hence, the probability that at least one light bulb fails is 1-0.95^50.
Answer: D.
Now, you should have spotted that your reasoning was not right because of one simple thing, consider the case when we have 100 light bulbs instead of 50, then according to your logic the probability that the string of light bulbs will fail would be 100*0.05=5, which is not possible since the probability of an event cannot be more than 1 (100%).
Question: You own thirteen pairs of socks, all different, and all of the socks are individually jumbled in
a drawer. One morning you rummage through the drawer and continue to pull out socks until
you have a matching pair. How many socks must you pull out to guarantee having a matching
pair?
A.3
B.12
C.13
D.14
Answer: D.14
Explanation: You might be unlucky and have the first thirteen socks all different, but then the 14th
has to match one of them.
correct answer D
Question: A man sells a horse for Rs.800 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?
A.188
B.786
C.991
D.860
Answer: D.860
Explanation: CP = SP + 1CP = SP - g
800 + x = 980 - 2x
3x = 180 => x = 60
CP = 800 + 60 = 860
Answer: D
Question: If an integer n is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 16?
A.1/4
B.3/8
C.1/2
D.9/16
Answer: D.9/16
Explanation: I get 5/8 as well
1 to 96 inclusive means we have 48 odd and 48 even integers
E O E / 16 = Integer, therefore we have 48 / 96 numbers divisible by 8
O E O / 16 = Not Integer
We cannot forget multiples of 16 from 1 to 96
We have 6 numbers that are multiple of 16
Therefore, 48/96 + 6/96 = 54/96 = 9/16
answer : D
Question: Out of three consecutive odd numbers eleven times the first number is equal to addition of thrice the third number and adding 8 to five times the second . What is the first number?
A.10
B.6
C.11
D.8
Answer: A.10
Explanation: Description :
=> 11x=5(x+2)+8+3(x+4)
=> 11x=8x+30
=> 3x=30
X=10
Answer A
Question: In a game, one player throws two fair, six-sided die at the same time. If the player receives at least a three or a one on either die, that player wins. What is the probability that a player wins after playing the game once?
A.1/3
B.4/9
C.5/9
D.2/3
Answer: C.5/9
Explanation: We're looking for the number of outcomes that include AT LEAST a 1 or a 3.
#getting a one in 1st die = {(1,1), (1,2), ...(1,6) }= 6
#getting a one in 2nd die {(2,1), ...(5,1),(6,1) } = 4 [exclude 1,1 and 3,1] since it will be counted twice
#getting a three in 1st die {(3,1), (3,2), ...(3,6) }= 6
#getting a three in 1st die {(2,3), (4,3), ...(6,3) } = 4 [exclude 1,3 and 3,3] since it will be counted twice
Total possibities = 20
Probability of rolling at least a 1 or a 3 on two dice: 20/36 = 5/9
C
Question: What will come in place of the question mark (?) in the following questions?
18.2% of 890 = ?
A.161.98
B.234.98
C.642.98
D.141.98
Answer: A.161.98
Explanation: A
161.98
? = (890 * 18.2)/100
= 161.98
Question: In a hockey championship, there are 153 matches played. Every two team played one match with each other. The number of teams participating in the championship is:
A.16
B.17
C.18
D.19
Answer: C.18
Explanation: Let there were x teams participating in the games, then total number of matches,
nC2 = 153.
On solving we get,
=> n =−17 and n =18.
It cannot be negative so,
n = 18 is the answer.
OPTION:C
Question: Narendra started a business, investing 30000. Six months later, Chandan joined him with 15000. If they make a profit of 10000 at the end of the year, what should be the share of Narendra?
A.Rs.7000
B.Rs.8000
C.Rs.8500
D.Rs.8600
Answer: B.Rs.8000
Explanation: The ratio of their investments = 30000 × 12 : 15000 × 6 = 4 : 1.
:. Narendra’s share on profit of Rs.10000 = 10000 × 4/5 = Rs.8000.
B)
Question: John distributes his pencil among his 4 friends Rose, Mary, Ranjan, and Rohit in the ratio 1/5 : 1/3 :1/4:1/5 . What is the minimum no. of pencils that the person should have?
A.59
B.65
C.70
D.77
Answer: A.59
Explanation: Rakesh : Rahul : Ranjan : Rohit = 1 / 5 : 1 / 3 : 1 / 4 : 1 / 5
Step 1: At First we need to do is LCM of 2,3,4 and 5 is 60.
Step 2: Then pencil are distributed in ratio among friends,
Rakesh = ( 1 / 5 x 60 ) = 12
Rahul = ( 1 / 3 x 60 ) = 20.
Ranjan = ( 1 / 4 x 60 ) = 15.
Rohit = ( 1 / 5 x 60 ) = 12.
Step 3: Total number of pencils are ( 12 x + 20 x + 15 x + 12 x) = 59 x.
For minimum number of pencils x = 1 .
The person should have at least 59 pencils.
A)
Question: A research team is to consist of 3 scientists from Company A and 3 scientists from Company B. If the pool of available scientists from Company A is 5 and the pool of available scientists from Company B is 4 scientists, how many different research teams are possible?
A.84
B.40
C.30
D.20
Answer: B.40
Explanation: C35∗C34=40
Answer: B.
Question: The product of all the prime numbers less than 22 is closest to which of the following powers of 10?
A.10^9
B.10^8
C.1*10^7
D.10^6
Answer: C.1*10^7
Explanation: Quickly approximate
2, 3, 5, 7, 11, 13, 17, 19
=2.1x10^2*1.3*1.7*1.9
=9.69* 10^6
=1*10^7
C
Question: Tough and Tricky questions: Exponents.
If a and b are positive integers and x = 4^a and y = 3^b, which of the following is a possible units digit of xy?
A.1
B.8
C.5
D.7
Answer: B.8
Explanation: Only Units digit of X and Y contribute to the Units digit of XY.
Finding all values ofXfor positive values ofa
When,
a=1; X=4
a=2; X=16
a=3; X=64........ Units digit repeat in a cycle of 4,6,4,6......
Similarly, Finding all values of Y for positive values ofb
b=1; Y=3
b=2; Y= 9
b=3; Y= 27
b=4; Y=81
b=5; Y=243....... Units digit repeat in cycle of 3,9,7,1,3,9....
So, possible value of Units digit of XY can be found by considering all possibilities of Units digit of X and Y
When X=4 and Y=3: Units digit of XY = 12
When X=4 and Y=9: Units digit of XY = 36
When X=4 and Y=7: Units digit of XY = 28
When X=4 and Y=1: Units digit of XY = 4
Only four possibilities for Units digit of XY i.e. 4, 2, 8 and 6.
Only 8 is given in answer choices, therefore answer is B
Question: What is the remainder if 7^12 is divided by 100?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: 7^16 can be written as (7^4)^3
If we divide 7^4 by 100 the reminder is 1
So, (7^4)^3 by 100, the reminder is 1^3 = 1
Answer : A
Question: A retail item is offered at a discount of d percent (where d > 10), with a 5% state sales tax assessed on the discounted purchase price. If the state sales tax were not assessed, what percent discount from the item’s original retail price, in terms of d, would result in the same final price?
A.d+5/1.05
B.d/1.05 +5
C.1.05d-5
D.d-5/1.05
Answer: C.1.05d-5
Explanation: Let x be the price of the item.
Final price after discount and sales tax = x * (1 - d/100) * 1.05
Let e be the percent discount which would result in the same final price.
Then,
x * (1 - d/100) * 1.05 = x * (1 - e/100)
=> 1.05 - 1.05d/100 = 1 - e/100
=> e/100 = 1.05d/100 - .05
=> e = 1.05d - 5
Hence ,option C is correct.
Question: If a fair die is rolled once, what is the probability that a 3 occurs on at least one roll?
A.25/36
B.125/216
C.1/6
D.1/36
Answer: C.1/6
Explanation: Questions such as these that talk aboutat leastormaximumorminimumin probability questions should make sure realize that probability of any event (N) to occur = 1- P(Not N)
Thus, the probability of at least 1 roll = 1- Probability of NO 3s = 1- (5/6) = 1-5/6 = 1/6
5/6 is the probability of NOT getting a 3 in any 1 roll with 5 allowed numbers (=1,2,4,5,6) out of a total of 6 possibilities.
C is thus the correct answer.
Question: When Usha was thrice as old as Nisha, her sister Asha was 25, When Nisha was half as old as Asha, then sister Usha was 34. their ages add to 100. How old is Usha?
A.40
B.41
C.42
D.43
Answer: A.40
Explanation: Let the age of Usha is 3x then Nisha is x and Asha is 25
Also Usha 34, Nisha y, and Asha 2y.
We know that 3x - 34 = x - 2y = 25 - 2y
Solving above three equations we get x = 9, y = 16
Their ages are 34, 16, 32. whose sum = 82. So after 18 years their ages will be equal to 100. So Usha age is 34 + 6 = 40
Answer:A
Question: For every positive integer n, the nth term of a sequence is the total sum of three consecutive integers starting at n. What is the total sum of terms 1 through 80 of this series?
A.8990
B.9380
C.9630
D.9960
Answer: D.9960
Explanation: Each term of the series has the form (n+n+1+n+2) = 3n+3
Since the series goes from 1 to 80, the sum of the series is:
3(1+2+...+80) + 80(3) =
3(80)(81)/2 + 80(3) =
120*81 + 240 = 9960
The answer is D.
Question: A certain board game is played by rolling a pair of fair six-sided dice and then moving one's piece forward the number of spaces indicated by the sum showing on the dice. A player is "frozen" if her opponent's piece comes to rest in the space already occupied by her piece. If player A is about to roll and is currently six spaces behind player B, what is the probability that player B will be frozen after player A rolls?
A.1/12
B.5/36
C.1/6
D.1/3
Answer: B.5/36
Explanation: no. of possible outcomes = 6*6 = 36
no. of outcomes that result a total of 6 (as A is 6 spaces behind B) = 5 ( (1,5), (2,4), (3,3), (4,2), (5,1) )
So, the probability = 5/36 (Option B)
Question: Two spherical balls lie on the ground touching. If one of the balls has a radius of 6 cm, and the point of contact is 8 cm above the ground, what is the radius of the other ball?
A.12 cm
B.16 cm
C.18 cm
D.20 cm
Answer: A.12 cm
Explanation: similar triangle properties..
2/r+6 = 6/r-6
giving r = 12.
Answer: A
Question: What is the difference between the place value and the face value of 9 in the numeral 296827?
A.None of these
B.89993
C.89991
D.89994
Answer: C.89991
Explanation: Explanation:
Place value of 9 = 90000
Face value of 9 = 9
Difference = 9000 - 9 = 89991
Answer: C
Question: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 250 per month. What is his monthly salary?
A.5000
B.2999
C.2878
D.6250
Answer: D.6250
Explanation: Income = Rs. 100
Expenditure = Rs. 80
Savings = Rs. 20
Present Expenditure 80*(20/100) = Rs. 96
Present Savings = 100 â€“ 96 =Rs. 4
100 ------ 4
? --------- 250 => 6250
Answer: D
Question: If the average (arithmetic mean) of seven consecutive integers is k - 2, then the product of the greatest and least integer is
A.k2 - 9
B.k2 - 2k + 1
C.k2 - 4k - 5
D.k2 + 6k + 9
Answer: C.k2 - 4k - 5
Explanation: n = smallest number
n+6 = largest number
(n + n + 6)/2 = k - 2
=> (2n+6)/2 = k - 2
=> n + 3 = k - 2
=> n = k - 5
So Product of n and n+6 = (k-5)(k+1)
= k^2 - 5k + k - 5
= k^2 - 4k - 5
Answer - C
Question: Find the odd man out. 3, 8, 18, 38, 78, 158, 316
A.38
B.158
C.316
D.8
Answer: C.316
Explanation: Explanation :
3
3 × 2 + 2 = 8
8 × 2 + 2 = 18
18 × 2 + 2 = 38
38 × 2 + 2 = 78
78 × 2 + 2 = 158
158 × 2 + 2 = 318
Hence, 316 is wrong and 318 should have come in place of that. Answer : Option C
Question: Johnson has a corporate proposal. The probability that vice-president Adams will approve the proposal is 0.7. The probability that vice-president Baker will approve the proposal is 0.5. The probability that vice-president Corfu will approve the proposal is 0.4. The approvals of the three (vice presidents)/VPs are entirely independent of one another.
Suppose the Johnson must get VP Adam’s approval, as well as the approval of at least one of the other VPs, Baker or Corfu, to win funding. What is the probability that Johnson’s proposal is funded?
A.0.5
B.0.6
C.0.7
D.0.49
Answer: D.0.49
Explanation: probability of adams approval = 0.7
baker approval =0.5
corfu approval=0.4
proabability of approval is must adam approval and atleast one approval
= adam approval*baker approval*corfu approval(approval of both remaining)+adam approval*baker approval*corfu not approval(atleast one remaining approval)+
adam approval*baker not approval*coffu approval( atleast one remaining approval
= 0.7*0.5*0.4+0.7*0.5*0.6+0.7*0.5*0.4
=0.14+0.21+0.14
=0.49
D
Question: A train 130 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
A.4
B.7
C.5
D.9
Answer: B.7
Explanation: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [130* 3/55] sec = 7 sec
ANSWER:B
Question: An auction house charges a commission of 25% on the first $50,000 of the sale price of an item, plus 10% on the amount of of the sale price in excess of $50,000. What was the price of a painting for which the house charged a total commission of $24,000?
A.$115,000
B.$165,000
C.$215,000
D.$240,000
Answer: B.$165,000
Explanation: Say the price of the house was $x, then 0.25*50,000+0.1*(x-50,000)=24,000 --> x=$165,000 (25% of $50,000 plus 10% of the amount in excess of $50,000, which is x-50,000, should equal to total commission of $24,000).
Answer: B.
Question: A 250 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 520 m in ?
A.40.4 sec
B.40.5 sec
C.50.4 sec
D.50.5 sec
Answer: A.40.4 sec
Explanation: Speed = 55 Km/hr
(to convert km/hr in to M/s)
= 55 x 5/18 M/s
Distance = 250 m + 520 m ( If questions is about train crossing a post you need to consider only the length of Train, )
= 770 m
Time = Distance / Speed
= 770 x 18 / (5 x 55)
= 50.4 sec
correct Answer: option a
Question: A hall 36m long and 15m broad is to be paved with stones, each measuring 2dm by 5 dm. The number of stones required is:
A.180
B.1800
C.5400
D.18000
Answer: C.5400
Explanation: Area of the hall= 3600*1500
Area of each stone= (20*50)
Therefore, number of stones= (3600*1500/ 20*50)= 5400
ANSWER:C
Question: A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
A.1:2
B.1:5
C.1:9
D.1:3
Answer: A.1:2
Explanation: T = 192/32 = 6 h
T = 6 - 3 = 3
Time Ratio = 6:3 = 2:1
Speed Ratio = 1:2
Answer: A
Question: On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars abroad the ship. If 40 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship's passengers held round-trip tickets?
A.33.3%
B.40%
C.50%
D.60%
Answer: A.33.3%
Explanation: 0.20P = RT + C
0.4(RT) = no C
=> 0.60(RT) had C
0.20P = 0.60(RT)
RT/P = 1/3=33%
Answer - A
Question: Car Q and Car Y traveled the same 80-mile route. If Car Q took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car Q, how many hours did it take Car Y to travel the route?
A. 2/3
B. 1
C. 4/3
D. 8/5
Answer: C. 4/3
Explanation: The speed of car Q is (distance)/(time) = 80/2 = 40 miles per hour.
The speed of car Y = 3/2*40 = 60 miles per hour --> (time) = (distance)/(speed) = 80/60 = 4/3 hours.
Answer: C.
Or: to cover the same distance at 3/2 as fast rate 2/3 as much time is needed --> (time)*2/3 = 2*2/3 = 4/3 hours.
Answer: C.
Question: The price of stock increased by 8% last year and decreased by 6% this year. What is the net percentage change in the price of the stock?
A.0.2%
B.0.8%
C.1.2%
D.1.52%
Answer: D.1.52%
Explanation: (100% + 8%) * (100% - 6%) = 1.08 * 0.94 =1.0152 = 101.52%.
The net percentage change in the price of the stock is (+) 1.52%
The answer is D
Question: A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 15 per metre of cloth. What is the cost price of one metre of cloth?
A.22
B.28
C.90
D.27
Answer: C.90
Explanation: SP of 1m of cloth = 8925/85 = Rs. 105
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 15
= Rs.90.
Answer:C
Question: The distance between Delhi and Mathura is 110 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet?
A.11
B.77
C.16
D.10
Answer: D.10
Explanation: D = 110 – 20 = 90
RS = 20 + 25 = 45
T = 90/45 = 2 hours
8 a.m. + 2 = 10 a.m..Answer: D
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is?
A.3/6
B.3/2
C.3/4
D.3/1
Answer: B.3/2
Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train
= 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y
= 23 x + 23 y
==> 4 x = 6 y ==> x/y
= 3/2.
Answer: B