RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 300 m long?
A.176 Sec
B.190 Sec
C.178 Sec
D.150 Sec
Answer: D.150 Sec
Explanation: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 1500 m
T = D/S
T = 1500/10
T = 150 Sec
Answer:D
Question: Find the L.C.M of 12, 25, 24 and 20.
A.240
B.600
C.320
D.150
Answer: B.600
Explanation: Explanation:
6 x 2 x 2 x 5 x 5 = 600
Answer: Option B
Question: There are 6 red balls,8 blue balls and 7 green balls in a bag. If 5 are drawn with replacement, what is the probability at least three are red?
A.312/16808
B.312/16807
C.312/16805
D.312/16838
Answer: B.312/16807
Explanation: At least 3 reds means we get either : 3 red or 4 red or 5 red. And this is a case of replacement.
case 1 : 3 red balls : 6/21 x 6/21 x 6/21 x 15/21 x 15/21
case 2 : 4 red balls : 6/21 x 6/21 x 6/21 x 6/21 x 15/21
case 3 : 5 red balls : 6/21 x 6/21 x 6/21 x 6/21 x 6/21
Total probability = = (6/21 x 6/21 x 6/21 x 15/21 x 15/21)+(6/21 x 6/21 x 6/21 x 6/21 x (15 )/21)+ (6/21 x 6/21 x 6/21 x 6/21 x 6/21)
= 312/16807
Answer:B
Question: Contractor is engaged for 30days on the condition that he receives Rs.25 for eachday he works &isfined Rs.7.50 for each day is absent. He gets Rs.425 in all. For how many days was heabsent?
A.5
B.10
C.15
D.16
Answer: B.10
Explanation: 30 * 25 = 750
425
-----------
325
25 + 7.50 = 32.5
325/32.5 = 10
B
Question: Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour?
A.82
B.17
C.12
D.82
Answer: C.12
Explanation: Explanation:
T = 9/45 * 60 = 12
Answer: Option C
Question: From the beginning to the end of 2007, the price of a stock rose 20 percent. In 2008, it dropped 25 percent. In 2009, it rose 30 percent. What percent of the stockâ€™s 2007 starting price was the price of the stock at the end of 2009?
A.80
B.117
C.95
D.100
Answer: B.117
Explanation: Assume a value at the beginning of 2007. As this is a % question, assume P=100.
At the end of 2007 it becmae = 1.2*100=120
At the end of 2008 it decreased by 25% = 120*.75 = 90
At the end of 2009 it increased by 30% = 90*1.3 = 117
Thus ratio = 117/100 = 1.17 (in % terms = 117%). Thus B is the correct answer.
Question: 5 men and 12 boys finish a piece of work in 4 days, 7 men and 6 boys do it in 5 days. The ratio between the efficiencies of a man and boy is?
A.1:2
B.2:1
C.2:3
D.6:5
Answer: D.6:5
Explanation: Explanation:
5Men + 12Boys ----- 4 days
7Men + 6Boys ------- 5 days
20Men + 48Boys = 35Men + 30Boys
18Boys = 15Men => 5Men = 6Boys
Men : Boys = 6:5
Answer: D
Question: A reduction of 30% in the price of apples would enable a man to obtain 54 more for Rs.30, what is reduced price per dozen?
A.1
B.2
C.6
D.7
Answer: B.2
Explanation: B
30*(30/100) = 9 --- 54
? --- 12 => Rs.2
Question: Rain is falling at a rate of 36 centimeters per hour all over Springfield. Somewhere downtown in Springfield a group of old people is waiting for the rain to stop. If the rain filled a round tank the with a base area of 150 square centimeters and a depth of 6 centimeters, how long did the people wait for the rain to stop?
A.6 hours
B.7 hours 15 minutes
C.5 hours
D.12 hours
Answer: A.6 hours
Explanation: Answer is : A, 6 hours
The volume of the tank is irrelevant and only height matters since rain fell all over the city.
Thus, it takes only 36 / 6 = 6 hours of rain to fill the tank
Question: A boat can move upstream at 34 kmph and downstream at 30 kmph, then the speed of the current is?
A.2
B.9
C.5
D.9
Answer: A.2
Explanation: US = 34
DS = 30
M = (34 - 30)/2 = 2
Answer: A
Question: Of 58 players on a cricket team, 37 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total?
A.51
B.55
C.59
D.71
Answer: A.51
Explanation: Total = 58
Thrower = 37
Rest = 58 - 37 = 21
Left Handed = 21/3 = 7
Right handed = 14
If all Thrower are right handed then total right handed is 37 + 14 = 51
so A. 51 is the right answer
Question: If Rs. 544 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively?
A.s.300
B.s.360
C.s.389
D.s.384
Answer: D.s.384
Explanation: (A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4
A:B = 2:3 and B:C = 1:4 = 3:12
A:B:C = 2:3:12
A;s share = 544 * 2/17 = Rs. 64
B's share = 544 * 3/17 = Rs. 96
C's share = 544 * 12/17 =Rs.384.
Answer:D
Question: From a total of 5 boys and 3 girls, how many 4-person committees can be selected if the committee must have exactly 2 boys and 2 girls?
A.16
B.24
C.30
D.120
Answer: C.30
Explanation: Answer=C=30
No of 4 person committees that can be formed=5C2*3C2=30
Answer C
Question: Sandy can do a job in 18 days and Molly can do the same job in 36 days. If they work together, in how many days will they complete the job?
A.6
B.8
C.10
D.12
Answer: D.12
Explanation: Sandy can do 1/18 of the job each day.
Molly can do 1/36 of the job each day.
The combined rate is 1/18 + 1/36 = 1/12 of the job each day.
The job will take 12 days.
The answer is D.
Question: The cricket team of 11members is 29yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ?
A.21
B.22
C.23
D.26
Answer: D.26
Explanation: Let the average age of the whole team be x years.
11x - (29 + 32) = 9 (x - 1)
=> 11x - 9x = 52
=> 2x = 52
=> x = 26.
So, average age of the team is 26 years.
D
Question: A man can row at 5 kmph in still water .If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back ,how far is the place ?
A.2.4 km
B.2.5 km
C.3 km
D.3.6 km
Answer: A.2.4 km
Explanation: Answer A
Solution
Speed downstream = kmph = 6 kmph,Speed upstream = (5 - 1)
kmph = 4 kmph.
Let the required distance be x km.
Then,x/6 + x/4 = 1 => 2x + 3x = 12 5x = 12=> x = 2.4 km. Answer A
Question: he average marks of a class of 30 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students?
A.52.2
B.59.5
C.52.8
D.52.5
Answer: D.52.5
Explanation: Sum of the marks for the class of 30 students = 30 * 40 = 1200
Sum of the marks for the class of 50 students = 50 * 60 = 3000
Sum of the marks for the class of 80 students =
1200 + 3000 = 4200
Average marks of all the students = 4200/80
= 52.5
Answer:D
Question: A certain bakery baked a batch of 400 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
A.13
B.27
C.41
D.43
Answer: A.13
Explanation: Cookies which have both nuts and chocolate chips = 235
Let fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that
batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch = x
(235+x)/(400+x) = 6/10
=>2350 + 10x = 2400 + 6x
=> 4x = 50
=> x = 12.5
Therefore x = 13
Answer A
Question: A certain car uses one gallon of gasoline every 38 miles when it travels on highway, and one gallon of gasoline every 20 miles when it travels in the city. When a car travels 4 miles on highway and 4 additional miles in the city, it uses what percent more gasoline than if it travels 8 miles on the highway?
A.15%
B.20%
C.22.5%
D.45%
Answer: D.45%
Explanation: 4 miles on the highway = 4/38 gallons;
4 miles in the city = 4/20 gallons;
Total = 4/38 + 4/20 = 29/95 gallons.
8 miles on the highway = 8/38 gallons .
The % change = (29/95 - 8/38)/(8/38) = 0.45.
Answer: D.
Question: Victor's job requires him to complete a series of identical jobs. If Victor is supervised at work, he finishes each job three days faster than if he is unsupervised. If Victor works for 144 days and is supervised for half the time, he will finish a total of 36 jobs. How long Q would it take Victor to complete 10 jobs without any supervision?
A.34
B.52
C.60
D.70
Answer: C.60
Explanation: Rate when supervised = (job)/(time) = 1/t.
Rate when unsupervised = (job)/(time) = 1/(t+3).
For 144/2=72 days he is supervised and for 144/2=72 days he is unsupervised and does 36 jobs:
72/t + 72/(t+3) = 36 --> t=3 days --> t+3 = 6 days.
Victor to complete 10 jobs without any supervision will need Q 10(t + 3) = 60 days.
Answer: C.
Question: Each child has 6 crayons and 12 apples. If there are 12 children, how many crayons are there in total?
A.22
B.65
C.72
D.78
Answer: C.72
Explanation: 6*12=72.Answer is C
Question: If a town of 25,000 people is growing at a rate of approx. 1% per year, the population of the town in 5 years will be closest to?
A.26000
B.27000
C.28000
D.29000
Answer: A.26000
Explanation: Let population in the beginning = 100
at the end of 1st year population = 100+1% of 100 = 100+1 = 101
at the end of 2nd year population = 101+1% of 101 = 101+1 approx = 102 approx (on the lower side because 1% of 101 is greater than 1)
at the end of 3rd year population = 102+1% of 102 = 102+1 approx = 103 approx (on the lower side because 1% of 102 is greater than 1)
at the end of 4th year population = 103+1% of 103 = 103+1 approx = 104 approx (on the lower side because 1% of 103 is greater than 1)
at the end of 5th year population = 104+1% of 104 = 104+1 approx = 105 approx (on the lower side because 1% of 104 is greater than 1)
i.e. 5% greater than 25000 = 25000+5% of 25000 = 25000+1250 = 26250 (on the lower side)
i.e. Population must be greater than 26250 but since the closest option is 26000 so
Answer: option A
Question: The average age of a husband and his wife was 23 years at the time of their marriage. After five years they have a one-year old child. The average age of the family now is :
A.11
B.18
C.19
D.287
Answer: C.19
Explanation: Explanation:
Sum of the present ages of husband, wife and child = (23 * 2 + 5 * 2) + 1 = 57 years.
Required average = (57/3) = 19 years.
Answer: C) 19
Question: X can run a kilometer race in 4 1/2 min while Y can run same race in 5 min. How many meters start can X give Y in a kilometer race, so that the race mat end in a dead heat?
A.50 m
B.200 m
C.150 m
D.100 m
Answer: D.100 m
Explanation: D
100 m
X can give Y (5 min - 4 1/2 min) = 30 sec start.
The distance covered by Y in 5 min = 1000 m.
Distance covered in 30 sec = (1000 * 30)/300 = 100 m.
X can give Y 100m start.
Question: A boy has Seven trousers and 14 shirts. In how many different ways can he select a trouser and a shirt?
A.38 ways
B.87 ways
C.66 ways
D.98 ways
Answer: D.98 ways
Explanation: Explanation:
The boy can select one trouser in seven ways.
The boy can select one shirt in 14 ways.
The number of ways in which he can select one trouser and one shirt is 7 * 14 = 98 ways.
Answer: D
Question: On a certain date, Pat invested $10,000 at x percent annual interest, compounded annually. If the total value of the investment plus interest at the end of 12 years will be $40,000, in how many years, the total value of the investment plus interest will increase to $120,000?
A.15
B.21
C.18
D.20
Answer: B.21
Explanation: if i were to choose during the test, would go for 18 or 20. probably 18 cuz it wont take too long to get the value doubled....
I found a method: Rule of 72.
Given an x% return, it takes 10,000 to quadralope 12 years.
So according to the rule: 72/x is the no of years 10,000.00 took to double 20,000.00.
Again, 20,000.00 took to double 40,000.00 same (72/x) no of years.
72/x+ 72/x = 12
x = 12% (though rate here is not very much required).
Again, 40,000.00 takes the same (72/x) no of years to double 120,000.00.
72/x = 6 years.
So altogather:
10,000 - 20,000 = 6 years
20,000 - 40,000 = 6 years
40,000 - 80,000 = 6 years
80,000 - 120,000 = 3 years
total 21 years.
Answer B
Question: The compound ratio of 3:4, 3:2 and 4:5?
A.1:9
B.1:7
C.1:2
D.9:10
Answer: D.9:10
Explanation: 3/4 * 3/2 * 4/5
= 9/10
=9:10
Answer: D
Question: Ann and Bob drive separately to a meeting. Ann's average driving speed is greater than Bob's avergae driving speed by one-third of Bob's average driving speed, and Ann drives twice as many miles as Bob. What is the ratio R of the number of hours Ann spends driving to the meeting to the number of hours Bob spends driving to the meeting?
A.8:3
B.3:2
C.4:3
D.2:3
Answer: B.3:2
Explanation: Say the rate of Bob is 3mph and he covers 6 miles then he needs 6/3=2 hours to do that.
Now, in this case the rate of Ann would be 3+3*1/3=4mph and the distance she covers would be 6*2=12 miles, so she needs 12/4=3 hours for that.
The ratio R of Ann's time to Bob's time is 3:2.
Answer: B.
Question: A vessel of capacity 2 litre has 25% of alcohol and another vessel of capacity 6 litre had 40% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of Mixture?
A.31%.
B.71%.
C.49%.
D.29%.
Answer: D.29%.
Explanation: 25% of 2 litres = 0.5 litres
40% of 6 litres = 2.4 litres
Therefore, total quantity of alcohol is 2.9 litres.
This mixture is in a 10 litre vessel. Hence, the concentration of alcohol in this 10 litre vessel is 29%
ANSWER:D
Question: A pipe can fill a cistern in 18 minutes whereas the cistern when fill can be emptied by a leak in 36 minutes. When both pipes are opened, find when the cistern will be full?
A.17
B.36
C.70
D.13
Answer: B.36
Explanation: 1/18 - 1/36 = 1/36
36 minutes
Answer: B
Question: The area of one square is x^2 + 8x + 16 and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 32, what is the value of x?
A.0
B.2
C.2.5
D.7/3
Answer: D.7/3
Explanation: spotting the pattern of equations both are in form of (X+C)^2 so
A1= (x+4)^2A2= (2x-3)^2
L1= x+5L2= 2x-3
P1 = 4( x+4)P2=4(2x-3)
P1+P2=32
4( x+4) +4(2x-3)=32..............> X=7/3
Answer: D
Question: In a two-digit number, the digit in the unit’s place is four times the digit in ten’s place and sum of the digits is equal to 10. What is the number?
A.14
B.41
C.41
D.None of these
Answer: D.None of these
Explanation: Solution
Let the ten's digits be x. Then, unit's digit = 4x.
∴ x + 4x = 10 ⇔ 5x = 10 ⇔ x = 2.
So, ten's digit = 2, unit's digit = 8.
Hence, the required number is 28.
Answer D
Question: If p and q are integers, such that p < 4 < q, and s is a nonnegative integer, which of the following must be true?
A.p^2 < q^2
B.p + q = 0
C.sp < sq
D.sp ≠ sq
Answer: D.sp ≠ sq
Explanation: We're told that P < 0 < Q and that S is a NON-NEGATIVE INTEGER. We're asked which of the following MUST be true.
P = -2
Q = 5
S = 0
Answer A: P^2 < Q^2.... 4 < 1 NOT TRUE
Answer B: P+Q=0... -2+1 = -1 NOT TRUE
Answer C: SP < SQ... 0 < 0 NOT TRUE
Answer D: SP ≠ SQ... This is TRUE
Answer E: P/Q < S... not TRUE
D
Question: For any integer n greater than 1, #n denotes the product of all the integers from 1 to n, inclusive. How many prime numbers W are there between #6 +2 and #6 +6 , inclusive?
A.None
B.One
C.Two
D.Three
Answer: A.None
Explanation: None is the answer. A.
Because for every k 6! + k :: k, because 6! :: k, since k is between 2 and 6.A
Question: If 1 > 1 - ab > 0, which of the following must be true?
I. a/b > 0
II. ab < 1
III.a/b > 1
A.I only
B.II only
C.III only
D.I and II only
Answer: D.I and II only
Explanation: MANHATTAN GMATOFFICIAL SOLUTION:
You can manipulate the original compound inequality as follows, making sure to perform each manipulation on every term:
1 > 1 - ab > 0
0 > -a b > -1 Subtract 1 from all three terms.
0 < ab < 1 Multiply all three terms by -1 and flip the inequality signs.
Therefore you know that 0 < ab < 1. This tells you that ab is positive, so a/b must be positive (a and b have the same sign). Therefore, I must be true. However, you do not know whether a/b < 1, so II is not necessarily true. But you do know that ab must be less than 1, so III must be true.
Therefore, the correct answer is (D).
Question: If a radio is purchased for Rs 490 and sold for Rs 465.50
Find the loss%?
A.5%
B.4%
C.6%
D.8%
Answer: A.5%
Explanation: C.P=Rs 490 S.P=Rs 465.50
Loss=C.P-S.P=490-465.50=Rs 24.50
Loss%=(loss*100)/C.P%
=(24.50*100)/490%=5%
ANSWER A 5%
Question: An isosceles triangle those sides are 13cm,13cm,10cm long inscribed in a circle.find the radius of the circle
A.8 cm
B.9 cm
C.10 cm
D.11 cm
Answer: A.8 cm
Explanation: a,b,c are sides of triangle ,ad is the median, ad^2=ab^2-bd^2 then ad=12,the centriod median divides into 2:1 ratio so 12 will be divide into 2:1 ratio so 8 is radius.
so ans is 8 cm
ANSWER:A
Question: Two identical circles intersect such that their centers and the points at which they intersect form a square of side 4 cm. What is the area of the region where the two circles intersect?
A.16 - 4pi
B.4 - pi
C.2pi - 4
D.8pi - 16
Answer: D.8pi - 16
Explanation: Drawing a diagram, we see that the radius of the circle equals the side of the square.
The area of intersection is: pi*r^2/4 - (r^2-pi*r^2/4) = pi*r^2/2 - r^2 = 8pi - 16
The answer is D.
Question: A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit?
A.3366
B.2777
C.3001
D.3000
Answer: D.3000
Explanation: A:B:C = 5:6:4
Let the total profit = 100 - 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 - 160/3 = 140/3
A-(B+C) = 160/3 - 140/3 = 20/3
20/3 ---- 200
100 ---- ? => 3000
Answer:D
Question: If any amount is distributed among A ,B and C so that the part of A is doubled that of the part of B and part of b is 7 time the part of C .Find the ratio among their parts.
A.1:2:4
B.1:4:1
C.14:7:1
D.2:4:1
Answer: C.14:7:1
Explanation: By the assumptions as mentioned we have A=2B and B=7C. So A=2(7C) and we get A=14C. We have, therefore, A:B:C = 14C:7C:C. By cancelling the ratio with C we have 14:7:1. The answer is, therefore, C.
Question: a circular wheel radius is 1.75m.for covering 11k.m how much time it revolve?
A.10
B.100
C.1000
D.10000
Answer: C.1000
Explanation: distance traveled in 1 round=perimeter={2*22/7*175/100}m
=11 m
total no. of revolution in covering 11 km=11000/11=1000
answer C
Question: A rectangular plot measuring 90 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?
A.34
B.77
C.36
D.56
Answer: D.56
Explanation: Explanation:
perimeter of the plot = 2(90+50) = 280m
no of poles =280/5 =56m
Answer: D
Question: What will come in place of the x in the following Number series? X, 22, 30, 46 ,78, 142
A.35
B.56
C.18
D.87
Answer: C.18
Explanation: (C)
The pattern is +4, +8, +16, +32, +64
So the missing term is = 18
Question: A sum of Rs. 1550 is lent out into two parts, one at 8% and another one at 6%. If the total annual income is Rs. 106, find the money lent at each rate.
A.700
B.500
C.300
D.900
Answer: D.900
Explanation: Let the sum lent at 8% be Rs. x and that at 6% be Rs. (1550 - x).
=((x*8*1)/100) + ((1550-x)*6*1)/100=106
= 8x + 9300 –6x=10600  2x = 1300  x = 650.
Therefore, Money lent at 8% = Rs. 650. Money lent at 6% = Rs. (1550 - 650) = Rs. 900.
Answer is D.
Question: Find large number from below question The difference of two numbers is 1370. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
A.1641
B.1376
C.1456
D.1555
Answer: A.1641
Explanation: Let the smaller number be x. Then larger number = (x + 1370).
x + 1370 = 6x + 15
5x = 1355
x = 271
Large number = 271+1370 = 1641
A
Question: You have 6 sticks of lengths 20, 30, 40, 50, 60 and 70 centimeters. The number of non-congruent triangles that can be formed by choosing three of the sticks to make the sides is
A.3
B.6
C.7
D.13
Answer: D.13
Explanation: The length of any side of a triangle must be larger than the positive difference of the other two sides, but smaller than the sum of the other two sides.
Based on this there can be only 13 triangles formed: (20, 30, 40), (20, 40, 50), (20, 50, 60), (30, 40, 50), (30, 40, 60), (30, 50, 60), (40, 50, 60), (50, 60, 70), (40,60, 70), (30,60, 70), (20,60, 70). (30, 50, 70), (40, 50,70)
Answer; D.
Question: Cindy paddles her kayak upstream at x kilometers per hour, and then returns downstream the same distance at n kilometers per hour. How many kilometers upstream did she travel if she spent a total of p hours for the round trip?
A.mnp
B.mn/p
C.(x + n)/p
D.xnp/(x + n)
Answer: D.xnp/(x + n)
Explanation: let t1 and t2 be the time taken to row upstream and downstream respectively
now,
t1=distance/speed=d/x
similarly,
t2=d/n (as same distance has to be rowed)
also,
t1+t2=p
therefore,
p=(d/x)+(d/n)
=d(x+n)/xn
d=pxn/(x+n)=D
Question: If a man can cover 12 metres in one second, how many kilometres can he cover in 3 hours 30 minutes?
A.150km
B.151.2km
C.152.5km
D.153km
Answer: B.151.2km
Explanation: 12 m/s = 12 * 18/5 kmph
3 hours 45 minutes = 3 1/2 hours = 7/2 hours
Distance = speed * time = 12 * 18/5 * 7/2 km = 151.2 km.
Answer:B
Question: If x is the median the set {9/2, x,11/3, 28/9, 21/5}, x could be
A.16/5
B.17/5
C.21/7
D.4
Answer: D.4
Explanation: The median is the middle number once all the numbers are arranged in increasing/decreasing order.
We see that
11/3 = 3.something,
28/9 = 3.something
21/5 = 4.something
9/2 = 4.something
So x should greater than the smallest two numbers and smaller than the greatest two numbers. We can see that x = 4 is possible. (First look at the simplest option or the middle option since options are usually arranged in increasing/decreasing order)
Answer (D)
Question: In Kaya's teacher's desk there are 3 pink highlighters, 7 yellow highlighters, and 5 blue highlighters. How many highlighters are there in all?
A.11
B.15
C.77
D.33
Answer: B.15
Explanation: Add the numbers of highlighters.
3 + 7 + 5 =15.
Answer is B.
Question: A fair coin with sides marked heads and tails is to be tossed eight times. What is the probability that the coin will land tails side up more than five times?
A.A)37/256
B.B)56/256
C.C)65/256
D.D)70/256
Answer: A.A)37/256
Explanation: More than 5 times tails = 6times + 7times+8times = 8C6 + 8C7 + 8C8 = 37
- - - - - - - -
2 2 2 2 2 2 2 2
2^8 times total events and 37 events where tails side up .
So probability = 37/2^8 = 37/256 (Answer A)
Question: How many numbers from 2 to 15 are exactly divisible by 2?
A.A)2
B.B)3
C.C)5
D.D)7
Answer: D.D)7
Explanation: 2/2 = 1 and 15/2 = 7
7 - 1 = 6
6 + 1 = 7 Numbers.
Answer : D
Question: The contents of a certain box consist of 80 apples and 30 oranges. How many oranges must be added to the box so that exactly 50% of the pieces of fruit in the box will be apples?
A.45
B.50
C.55
D.60
Answer: B.50
Explanation: apple = (apple + orange + x)*0.5
80 = (30 + 80 + x)*0.5
x = 50
Answer: B
Question: The tax on a commodity is diminished by 20% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it?
A.18%
B.72%
C.32%
D.12%
Answer: D.12%
Explanation: 100 * 100 = 10000
80 * 110 = 8800
10000------- 1200
100 ------- ? = 12%
Answer:D
Question: A trained covered x km at 50 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km.
A.22
B.99
C.25
D.66
Answer: C.25
Explanation: Total time taken = x/50 + 2x/20 hours
= 6x/50 = 3x/25 hours
Average speed = 3x/(3x/25) = 25kmph
Answer: C
Question: Ramu bought an old car for Rs. 41000. He spent Rs. 13000 on repairs and sold it for Rs. 64900. What is his profit percent?
A.A)14%
B.B)16%
C.C)19.8%
D.D)22%
Answer: C.C)19.8%
Explanation: Total CP = Rs. 41000 + Rs. 13000 = Rs. 54000 and SP = Rs. 64900
Profit(%) = (64900 - 54000)/55000 * 100 = 19.8%
ANSWER:C
Question: If 7^k = 2, then 7^(4k+2) =
A.729
B.754
C.784
D.783
Answer: C.784
Explanation: 7^k=2
7^4k=2^4
7^4k=16
7^(4k+2)
=7^4k*7^2
=16*49
=784
Answer: C