RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Vijay bought 160 shirts at the rate of Rs. 215 per shirt. The transport expenditure was Rs. 1400. He paid an octroi at the rate of Rs. 1.75 per shirt and labour charges were Rs. 320. What should be the selling price of one shirt, if he wants a profit of 20%?
A.s.225
B.s.288
C.s.485
D.s.273
Answer: D.s.273
Explanation: Total CP per shirt = 215 + 1400/160 + 1.75 + 320/160 = Rs. 227.5
SP = CP[(100 + profit%)/100]
= 227.5 * [(100 + 20)/100] = Rs.273.
Answer:D
Question: 1, 13, 35, 67, 109, ____
A.161
B.154
C.216
D.158
Answer: A.161
Explanation: 1, 13, 35, 67, 109, .....
13=1+12
35=13+22
67=35+32
109=67+42
So 109+52=161
ANSWER:A
Question: For any number y, y* is defined as the greatest positive even integer less than or equal to y. What is the value of 9.2 – 9.2*?
A.0.2
B.1.2
C.1.8
D.2.2
Answer: B.1.2
Explanation: Since y* is defined as the greatest positive even integer less than or equal to y, then 9.2* = 8 (the greatest positive even integer less than or equal to 9.2 is 4).
Hence, 9.2 – 9.2* = 9.2 - 8 = 1.2
Answer: B.
Question: A sum of Rs.5800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
A.A)282
B.B)3770
C.C)8383
D.D)8383
Answer: B.B)3770
Explanation: Let A be the amount received at the end of the three years.
A = 5800[1 + 10/100][1 + 20/100][1 + 25/100]
A = 5800 * 1.65
A = Rs.9570
So the interest = 9570 - 5800 = Rs.3770
Answer: B
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
A.228
B.278
C.48
D.27
Answer: C.48
Explanation: Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 6/125 = 48 sec.
Answer:C
Question: A walk 20m towards north east.B walk towards east 8m and then 12m south.Now calculate Distance between A and B?
A.30m
B.20m
C.35m
D.40m
Answer: A.30m
Explanation: its coming 30.4m
since 1st triangle we get 18.31
and extra 12 so 18.31+12=30.31=30m
ANSWER:A
Question: There are 27 balls, of which 1 is heavier. given a balance how many times you need to weigh to find out the odd ball.
A.7 times
B.2 times
C.3 times
D.5 times
Answer: C.3 times
Explanation: first make 3 groups of 9 balls each...
then weight 2 group using balance which tells u which group is having the heavier ball...
then split dat group into 3 groups each containing 3 balls...
then follow same procedure...
in 3 times u get heavier ball
ANSWER:C
Question: The simple interest at c% for c years will be $c on a sum of
A.$ (1000)/c
B.$(100)c^2
C.$ c
D.$ (100)/c
Answer: D.$ (100)/c
Explanation: Principal =$(100*c)/(c*c)=$(100/c).
Answer is D
Question: In a fuel station the service costs $2.05 per car, every liter of fuel costs 0.8$. Assuming that you fill up 3 mini-vans and 2 trucks, how much money will the fuel cost to all the cars owners total, if a mini- van's tank is 65 liters and a truck's tank is 120% bigger and they are all empty-?
A.122.6$
B.228.9$
C.343.7$
D.395.05$
Answer: D.395.05$
Explanation: Service cost of 3 van and 2 truck = 2.05*(3+2)=10.5
Fuel in 3 Van = 3*65=195 litre
Fuel in 2 Trucks =2 * 65(1+120/100)= 286
Total fuel(Van+Truck) = 481 Litre
Total Fuel cost = 481*0.8 =384.8
TOTAL COST =FUEL+SERVICE=384.8+10.25=395.05
ANSWER IS D
Question: Solve the given two equations and find the inequality of X and Y. (a) 2x^2 + 11x + 14 = 0 and (b) 4y^2 + 12y +9 =0
A.If x>y
B.If x>y
C.If x<y
D.If x<=y
Answer: C.If x<y
Explanation: Solution:-
X=-7/2 or -2
Y=-3/2
If x<y
C)
Question: If a boat is moving in upstream with velocity of 14 km/hr and goes downstream with a velocity of 40 km/hr, then what is the speed of the stream ?
A.13 km/hr
B.26 km/hr
C.34 km/hr
D.44 km/hr
Answer: A.13 km/hr
Explanation: if the downstream is a km/hr and upstream is b km/hr then speed of stream is 1/2(a-b)
so, 1/2(40-14)=13 km/hr ANSWER:A
Question: If the integer N = 139k00 where k is the hundreds digit, N can always be divisible by which of the following?
A.2
B.4
C.3
D.6
Answer: B.4
Explanation: Apply the divisibility rule here that for a number to be divisible by 4 the last two digits must be divisible by 4
hence B is correct
Question: 5*2 is a three digit number with * is a missing digit. If the number is divisible by 6, the missing digit is
A.0
B.2
C.5
D.7
Answer: B.2
Explanation: Sol.
Let the number be 5x2. Clearly, it is divisible by 2.
Now, 5 + x + 2 = (7 + x) must be divisible by 3.
So, x = 2.
Answer B
Question: A cube of side 5.5 meter length is cut into small cubes of side 110 cm each. How many such small cubes can be obtained?
A.125
B.127
C.152
D.140
Answer: A.125
Explanation: Along one edge, the number of small cubes that can be cut
= 550/110 = 5
Along each edge 5 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut
= 5 * 5 * 5= 125
Answer:A
Question: 5 years ago Amith was three times as old as his daughter and 10 years hence, he will be two times as old as his daughter. Then Amith’s current age is,
A.10
B.50
C.40
D.20
Answer: D.20
Explanation: D
20
Amith’s age = A and
daughter’s age =B
Then, A – 5 = 3(B – 5)
=> A – 3B + 10 = 0 ……(1)
And, A + 10 = 2 (A + 10)
=> A – 2B – 10 = 0 ……(2)
Solving the 2 eqns, we will get
A = 50, B = 20.
Therefore,
Amith’s age is 50
And his Daughter’s age is 20
Question: The average age of X,Y & Z were 5 years ago was 25 years and the age of X and Y were 6 years ago was 18 years. The present age of the Z is?
A.52 Years
B.55 Years
C.42 Years
D.38 Years
Answer: C.42 Years
Explanation: Sum of the present ages of X,Y & Z = (25*3+5*3) = 90 years.
Sum of the present ages of X,Y = (18*2+6*2) = 48 years
Present age Z = (90- 48) = 42 years.
Answer : C
Question: 90 percent of your marbles are a solid color. 5 percent of your marbles are solid yellow. What percentage of your marbles are a solid color other than yellow?
A.5
B.15
C.85
D.90
Answer: C.85
Explanation: 90 percent are solid colors including solid yellow. 5 percent are solid yellow. 90% - 5% = 85%, so 85 percent are a solid color other than yellow => (C)
Question: The owner of an electronics shop charges his customer 25% more than the cost price. If a customer paid Rs.11,500 for a television set, then what was the cost price of the television set?
A.Rs.9200
B.Rs.7200
C.Rs.8600
D.Rs.9800
Answer: A.Rs.9200
Explanation: Explanation:
SP = Rs.11500
i.e. 125% of CP.
:. CP = 11500x100/125
= Rs.9200/-
Answer: Option A
Question: A bowl has only 5 apples and 5 bananas. If one piece of fruit is selected from the bowl at random, and a second piece is selected from the bowl without replacing the first, what is the probability that both pieces of fruit chosen are apples?
A.1/10
B.1/5
C.2/9
D.2/5
Answer: C.2/9
Explanation: A bowl has only 5 apples and 5 bananas. If one piece of fruit is selected from the bowl at random, and a second piece is selected from the bowl without replacing the first, what is the probability that both pieces of fruit chosen are apples?
5/10 * 4/9
=2/9
C. 2/9
Question: The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/8 of the area of the field. What is the length of the field?
A.73
B.32
C.34
D.43
Answer: B.32
Explanation: Explanation:
A/8 = 8 * 8 => A = 8 * 8 * 8
x * 2x = 8 * 8 * 8
x = 16 => 2x = 32
Answer: Option B
Question: AB
+BA
___
101
In the addition problem above, A and B represent digits in two different two-digit numbers. What is the sum of A and B?
A.6
B.8
C.10
D.11
Answer: C.10
Explanation: two ways to do it..
1) straight logic..
we can see that ones digit is 1 when units digit B and A are added..
only 10 fits in..
C
Question: For any integer m greater than 1, $m denotes the product of all the integers from 1 to m, inclusive. How many prime numbers are there between $7 + 2 and $7 + 10, inclusive?
A.None
B.One
C.Two
D.Three
Answer: A.None
Explanation: $ is basically a factorial of a number.
So, we are asked to find the number of primes between 7!+2 and 7!+10, inclusive.
From each number 7!+k were 2≤k≤102≤k≤10 we can factor out k, thus there are no pries in the given range.
For example:
7!+2=2(3*4*5*6*7+1) --> a multiple of 2, thus not a prime;
7!+3=3(2*4*5*6*7+1) --> a multiple of 3, thus not a prime;
...
7!+10=10(3*4*6*7+1) --> a multiple of 10, thus not a prime.
Answer: A.
Question: The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 5 years ?
A.3277
B.2977
C.9492
D.6077
Answer: C.9492
Explanation: Explanation: 40,000*(3/4)^5
Answer:C
Question: The tax on a commodity is diminished by 35% but its consumption is increased by 15%. Find the decrease percent in the revenue derived from it?
A.18%
B.72%
C.32%
D.25.25%
Answer: D.25.25%
Explanation: 100 * 100 = 10000
65 * 115 = 7475
10000------- 2525
100 ------- ? = 25.25%
Answer:D
Question: For the past 3 weeks, Rikki has gone to the gym an average of 2 times per week. After 1 more week, the average number of times Rikki goes to the gym increases to 3 times per week. How many times did Rikki visit the gym during the most recent week?
A.7
B.3
C.6
D.2
Answer: C.6
Explanation: Total times per week over 3 weeks = 3*2 = 6
Total times per week over 4 weeks = 4*3 = 12
Number of visits in most recent week = 12-6 = 6 visits
Answer is C
Question: If the sides of a triangle are 78 cm, 72 cm and 30 cm, what is its area?
A.120 cm2
B.765 cm2
C.1080 cm2
D.197 cm2
Answer: C.1080 cm2
Explanation: The triangle with sides 78 cm, 72 cm and 30 cm is right angled, where the hypotenuse is 78 cm.
Area of the triangle
= 1/2 * 72 * 30
= 1080 cm2
Answer: C
Question: If the perimeter of a rectangular garden is 480 m, its length when its breadth is 100 m is?
A.299 m
B.140 m
C.200 m
D.167 m
Answer: B.140 m
Explanation: 2(l + 100) = 480 => l
= 140 m
Answer:B
Question: A bag contains 1 white,3 red and 2 blue balls.Three balls are drawn at random from the bag.the probability that all of them are red are????
A.1/6
B.3/6
C.1/20
D.2/20
Answer: C.1/20
Explanation: 3c3/6c3=1/20
ANSWER:C
Question: An article was sold after a discount of 20% and there was a gain of 20%. If the profit made on it was Rs. 6 less than the discount offered on it, find its selling price?
A.7
B.8
C.9
D.5
Answer: A.7
Explanation: Let CP = Rs. 100x
SP = Rs. 120x
MP = 120x/80 * 100 = Rs. 150x
D = Rs. 150x - Rs. 120x = Rs. 30x
D - P = 30x - 20x = Rs. 6, 10x = Rs. 6
120x = 120/10 * 6 = Rs. 7
Answer:A
Question: Two diagonals of a rhombus are 72 cm and 30 cm respectively. What is its perimeter?
A.136 CM
B.156 CM
C.144 CM
D.121 CM
Answer: B.156 CM
Explanation: ALL SIDES OF RHOMBUS ARE CONGRUENT LET PR = 72 SQ = 30 CM
PO = 0R = 72/1 = 36 CM SO = 0Q = 30/2 = 15 CM
PQ = QR = RS = SP
= ROOT( 36^2 + 15^2) = RPPT(1296+225)=ROOT(1521) = 39 CM
PERIMETER = 4 * 39 = 156 CM
ANSWER B
Question: The average salary of the employees in a office is Rs.120/month.The avg salary of officers is Rs.440 and of non officers is Rs 110. If the no.of officers is 15,then find the No of nonofficers in the office.
A.400
B.420
C.480
D.450
Answer: C.480
Explanation: Let no. of non- officers be x
15 * 440 + x * 110 = (x + 15) 120
x = 480
C
Question: In how many different ways can the letters of the word "FAME" be rearrangement?
A.26
B.24
C.28
D.12
Answer: B.24
Explanation: Option 'B'
The total number of arrangements is
4P4 = 4! = 24
Question: Each night before he goes to bed, Jordan likes to pick out an outfit to wear the next day. He has 11 different shirts, 10 different pairs of jeans, and 8 pairs of sneakers. If an outfit consists of 1 shirt, 1 pair of jeans, and 1 pair of sneakers, how many different outfits does Jordan have?
A.30
B.90
C.240
D.880
Answer: D.880
Explanation: Total # of outfits = 11 * 10 * 8 = 880
Answer - D
Question: A student chose a number, multiplied it by 5, then subtracted 275 from the result and got 135. What was the number he chose?
A.80
B.82
C.84
D.86
Answer: B.82
Explanation: Let x be the number he chose, then
5⋅x−275=135
5x=410
x=82
correct answer B
Question: Stephen likes to bike after school, and he has to get home before dark, so he only bike for five hours. His favorite route is a 45 mile loop starting from his house. In the first hour, he travels nine miles. For the next two hours, he travels at 7 miles per hour. Compute the average speed Stephen has to ride for the last three hours to get home before dark.
A.10
B.11
C.12
D.13
Answer: B.11
Explanation: Stephen has to travel (45 - 9 - 7 * 2) = 22 miles in 2 hours
22 miles / 2 hours = 11 miles per hour
Correct answer B
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. What is the present age of the husband?
A.40
B.32
C.28
D.30
Answer: A.40
Explanation: Explanation:
Let the present age of the husband = h
Present age of the wife = w
Present age of the child = c
3 years ago, average age of husband, wife and their child = 27
=> Sum of age of husband, wife and their child before 3 years = 3 × 27 = 81
=> (h-3) + (w-3) + (c-3) = 81
=> h + w + c = 81 + 9 = 90 --- equation(1)
5 years ago, average age of wife and child = 20
=> Sum of age of wife and child before 5 years = 2 × 20 = 40
=> (w-5) + (c-5) = 40
=> w + c = 40 + 10 = 50 --- equation(2)
Substituting equation(2) in equation(1)
=> h + 50 = 90
=> h = 90 - 50 = 40
i.e., Present age of the husband = 40
Answer: Option A
Question: If a coin is tossed twice, what is the probability that on the first toss the coin lands tails and on the second toss the coin lands tails?
A.1/6
B.1/3
C.1/2
D.1/4
Answer: D.1/4
Explanation: Since there are two options for how a coin can land (heads or tails), that means there is a 1/2 chance to land on tails and a 1/2 chance to land heads. To solve this problem you multiply each probability for each flip together. (1/2) chance to land tails the first time * (1/2) chance to land tails the second time = (1/4) chance to land tails both times.
Answer: D
Question: A can do a piece of work in 4 days. B can do it in 6 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?
A.87 days
B.12 days
C.66 days
D.77 days
Answer: B.12 days
Explanation: C = 1/2 - 1/4 - 1/6 = 1/12
=> 12 days
Answer: B
Question: The speed of a boat in still water is 80kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
A.60 kmph
B.40 kmph
C.16 kmph
D.15 kmph
Answer: A.60 kmph
Explanation: Speed downstream = 80 + 20
= 100 kmph
Speed upstream = 80 - 20
= 60 kmph
Answer:A
Question: If the letters in the word RUTHENIUM are rearranged in the alphabatical order, which letter will be
second to the right of middle letter?
A.I
B.T
C.Y
D.H
Answer: B.T
Explanation: Alphabetical order of the letters of the word RUTHENIUM:
E H I M N R T U U
Middle Letter = N. will be second to the right of middle letter is T.
Answer: Option 'B'
Question: Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran's share in the profit ?
A.24884
B.10500
C.23878
D.29988
Answer: B.10500
Explanation: Explanation:
Simran : Nanda = (50000 * 36) : (80000 * 30) = 3 : 4.
Simran's share = Rs. ( 24500 * 3/7) = Rs. 10500.
Answer: B) 10500
Question: If two numbers are in the ratio 5:3. If 10 is Reduced to both of the numbers then the ratio becomes 2:1 then find the smallest number?
A.15
B.20
C.30
D.34
Answer: C.30
Explanation: 5:3
5x - 10 : 3x - 10 = 2 : 1
1[5x - 10] = 2[3x - 10]
5x - 10 = 6x - 20
6x - 5x = 20 - 10
x = 10
the small number is = 3
3x = 30 (Answer = 30)
Short cut method:
a:b = 5:3
c:d = 2:1
1.Cross multiplication with both ratios
a * d ~ b * c = 5 * 1 ~ 3 * 2 = 5 ~ 6 = 1
2. If 10 is reduced both the number means 10 * 2 = 20 and 10 * 1 = 10,
Then 20 ~ 10 = 10
===> 1 -----> 10
===> 3 -----> 30 (Answer is = 30)
C
Question: A tradesman by means of his false balance defrauds to the extent of 20%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
A.20%
B.45%
C.44%
D.48%
Answer: C.44%
Explanation: Explanation:
g% = 20 + 20 + (20*20)/100
= 44%
ANSWER IS C
Question: Which expression is the greatest
A.3252/3257
B.3456/3461
C.3591/3596
D.3641/3656
Answer: D.3641/3656
Explanation: Options can be re-written as (x-5)x => 1-(5/x)
A) 1- (5/3257)
B) 1- (5/3461)
C) 1- (5/3596)
D) 1- (5/3656)
E) 1- (5/3458)
To get the largest among these second half should be the least and so denominator to be largest. Hence 'D'.
Question: In ABC limited, 75% are using Samsung phone at the same time 70% using i phone; If in the same company 85% are using Samsung phone then, what is the percentage of i phone user?
A.55
B.68
C.38
D.34
Answer: D.34
Explanation: Samsung phone user = 75%; i phone user= 80%; Total = 85*100;Percentage of Samsung phone users = 85 - 75 = 10;
Percentage of i phone users = 100 - 80 =20; then total % of i phone users =0.70*20= 14;then total % of i phone users = 20+14 =34. Answer= D
Question: The value for D=(0.889 × 55)/9.97 to the nearest tenth is
A.0.5
B.4.63
C.4.9
D.7.7
Answer: C.4.9
Explanation: if we read the Q, we can easily home on to the answer,,
the numerator is clearly between 40 and 50..
denomiator is close to 10..
so D=(0.889 × 55)/9.97 is between 4 and 5..
It may tempt us to solve it since ther are two values between 4 and 5..
but the catch is innearest tenth
4.63 can be called nearest to hundreth and no tenth, so can be eliminated..
4.9 is our answer...
C
Question: All the stocks on the over-the-counter market are designated by either a 1 letter or 2 letter codes that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be designated with these codes?
A.2(26^5)
B.26(26^4)
C.27(26^1)
D.26(26^5)
Answer: C.27(26^1)
Explanation: with 1 letters: 26^1
with 2 letters: 26^2
26^1 + 26^2 = 27*(26^1)
C
Question: What is the area of rectangular field?
I.	The perimeter of the field is 110 metres.
II.	The length is 5 metres more than the width.
III.	The ratio between length and width is 6 : 5 respectively.
A.I and II only
B.Any two of the three
C.All I, II and III
D.I, and either II or III only
Answer: B.Any two of the three
Explanation: EXPLANATION
I. 2(l + b) = 110 l + b = 55.
II. l = (b + 5) l – b = 5.
III. l/b = 6/5 => 5l – 6b = 0.
These are three equations in l and b. We may solve them pairwise.
Any two of the three will give the answer.
answer is (B).
Question: If 27.5% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class?
A.638
B.330
C.550
D.430
Answer: A.638
Explanation: Students enrolled in biology are 27.5% and therefore not enrolled are 72.5%. so of 880 is 880*.225 = 638
Answer is A 638
Question: Sanoop bought 8 t-shirts at an average price (arithmetic mean) of Rs.526. If Sanoop returned 5 t-shirts to the retailer, and the average price of the remaining t-shirts was Rs.505, then what is the average price, of the three returned t-shirts?
A.560
B.561
C.562
D.538.6
Answer: D.538.6
Explanation: Total price of 8 t-shirts= 8*526=4208
Total price of 3 t-shirts=5*505=1515
Total price of 5 t-shirts=4208-1515=2693
Average price of 3 t-shirts=2693/5=538.6
Correct option Answer:D
Question: A student scored an average of 80 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics?
A.11
B.66
C.77
D.80
Answer: D.80
Explanation: Given M + P + C = 80 * 3 = 240 --- (1)
M + P = 90 * 2 = 180 --- (2)
P + C = 70 * 2 = 140 --- (3)
Where M, P and C are marks obtained by the student in Mathematics, Physics and Chemistry.
P = (2) + (3) - (1) = 180 + 140 - 240 = 80
Answer:D
Question: When p is divided by 9, the remainder is 4. All of the following are possible values of p, except for which of the following?
A.13
B.31
C.49
D.52
Answer: D.52
Explanation: If a number is divisible by 9, the sum of its digits must be divisible by 9. --> If a number leaves a remainder 4 when divided by 9 the sum of its digits must be 4.
52
Answer: D
Question: If the LCM of 2, 5, 6, and a is 210, which of the following could be a?
A.5
B.6
C.4
D.7
Answer: D.7
Explanation: Using elimination method, eliminate the option to arrive at
if a is replaced by 7 and the LCM is calculated you arrive at 210
D
Question: (178% of 1265) ÷ 5.96 = ?
A.125
B.175
C.225
D.375
Answer: D.375
Explanation: Explanation :
? = (178 x 1265/100) ÷ 6 = 2250/600 = 375
Answer : Option D
Question: The C.P of 10 pens is equal to the S.P of 12 pens. Find his gain % or loss%?
A.16 2/8%
B.16 8/3%
C.16 2/3%
D.16 4/3%
Answer: C.16 2/3%
Explanation: 10 CP = 12 SP
12 --- 2 CP loss
100 --- ? => 16 2/3%
Answer:C
Question: If s is an integer greater than 6, which of the following must be divisible by 3?
A.s (s+3) (s-5)
B.s (s+2) (s-1)
C.s (s+1) (s-4)
D.s (s+4) (s-2)
Answer: C.s (s+1) (s-4)
Explanation: anything in the form of (s-1) (s) (s+1) is divisible by 3. in other word, a product of any 3 consecutive intevers is divisible by 3.
s (s+1) (s-4) = s (s+1) ((s-1)-3) is equivalant to (s-1) (s) (s+1)
s (s+2) (s-1) is equivalant to (s+1) missing.
s (s+3) (s-5) is equivalant to (s-1) missing and s repeating.
s (s+4) (s-2) is equivalant to odd/even consqcutive integers
s (s+5) (s-6) is equivalant to (s+1) missing and s repeating.
Answer : C
Question: If four coins are tossed, the probability of getting two heads and two tails is
A.3/8
B.3/4
C.3/5
D.3/3
Answer: A.3/8
Explanation: Since four coins are tossed, sample space = 24
Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = 6/24
= 3/8
Answer:A
Question: If −y ≥ x, and −x < −8, then which of the following must be true?
A.y = −8
B.y > −8
C.−y > 8
D.y ≤ −8
Answer: C.−y > 8
Explanation: −y ≥ x, and −x < −8
y <= -x < -8
As '-x' is less than '-8' and Y is less than or equal to '-x'
we have y < -8 which is similar to -y > 8.
C) -y > 8
Question: A rectangular swimming pool is 20 feet by 18 feet. A deck that has uniform width surrounds the pool. The total area of the pool and deck is 624 square feet. What is the width of the deck?
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: Let the width =W
Total Area of the pool and deck= (2W+20)(2W+18)
We can Test the answer choices along with unit digit method
A) 2 feet ...........24*22 has unit digit 8..........Eliminate
B) 2.5 feet.........25*23 has unit digit 5..........Eliminate
C) 3 feet............26*24 has unit digit 4...........Hold
D) 4 feet............28*26 has unit digit 8...........Eliminate
E) 5 feet............30*38 has unit digit 0...........Eliminate
Answer: B w=3
Question: If 3 girls can do 3 times of a particular work in 3 days, then, 7 girls can do 7 times of that work in
A.1 1/5 days
B.2 days
C.2 1/5 days
D.3 days
Answer: D.3 days
Explanation: Answer: Option 'D'
That is, 1 girl can do one time of the work in 3 days.
Therefore, 7 girls can do 7 times work in the same 3 days itself.
Question: A dice is rolled 3times & sum of 3 no.'sappearing on the uppermost face is 15. The chance that the first roll was four is?
A.2/113
B.3/114
C.1/108
D.2/213
Answer: C.1/108
Explanation: Sol. Total number of favorable outcomes n(S) . e . 216 Combinations of outcomes for getting sum of 15 on uppermost face = (4, 5, 6) (5, 4, 6) (6, 5, 4) (5, 6, 4), (4, 6, 5), (6, 4, 5), (5, 5, 5), (6, 6, 3), (6, 3, 6) (3, 6, 6) Now outcomes on which first roll was a four, n(E) = (4, 5, 6), (4, 6, 5) P(E) n(E) 2 1 Pt') = n(S) = 216 = 1/108
C
Question: 2056 x 987 = ?
A.1936372
B.2029272
C.1896172
D.1923472
Answer: B.2029272
Explanation: =2056 x 987
=2056 x (1000 - 13)
=2056 x 1000 - 2056 x 13
=2056000 - 26728
=2029272
Answer is B
Question: Which of the following is not a composite number ?
A.234
B.211
C.525
D.603
Answer: A.234
Explanation: Clearly 211 is not a composite number. All others are divisible by 3. Ans : A