RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A shopkeeper buys mangoes at the rate of 4 a rupee and sells them at 3 a rupee. Find his net profit or loss percent?
A.33 1/8 %
B.33 7/3 %
C.33 1/3 %
D.38 1/3 %
Answer: C.33 1/3 %
Explanation: The total number of mangoes bought by the shopkeeper be 12.
If he buys 4 a rupee, his CP = 3
He selling at 3 a rupee, his SP = 4
Profit = SP - CP = 4 - 3 = 1
Profit Percent = 1/3 * 100 = 33 1/3 %
Answer: C
Question: Simple interest on a certain sum of money for 4 years at 10% per annum is half the compound interest on Rs. 3000 for 3 years at 12% per annum. The sum placed on simple interest is
A.Rs.3000
B.Rs.607.39
C.Rs.1214.78
D.Rs.1518.48
Answer: D.Rs.1518.48
Explanation: Solution
C.I.	=Rs[3000x(1+12/100)3-3000]
Rs.(3000x112/100x112/100x112/100-3000)	= Rs.1214.78.
Sum	=Rs. [607.39x100 /4x10]
= Rs.1518.48.
Answer D
Question: If n is an integer, f(n) = f(n-1) - n and f(4)=20. What is the value of f(6)?
A.9
B.0
C.1
D.2
Answer: A.9
Explanation: Since f(n)=f(n-1)-n then: f(6)=f(5)-6 and f(5)=f(4)-5.
As given that f(4)=20 then f(5)=20-5=15 --> substitute the value of f(5) back into the first equation: f(6)=f(5)-6=15-6=9.
Answer: A.
Questions on funtions to practice:
Question: Bhuvnesh invests an amount for n years. If the rate of interest is 25% it becomes Rs. 5000. If the rate of interest is 5% it becomes Rs. 3000. For how long it is invested?
A.5
B.4
C.3
D.6
Answer: B.4
Explanation: Explanation :
n = ((p1-p2)/(p2r1-p1r2))*100
= ((5000-3000)/(3000*25-5000*5))*100
= (2000/50000)*100
= 4
Answer : B
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 12 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
A.40
B.44
C.66
D.52
Answer: C.66
Explanation: Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 12)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 12 = 4/9(T - 12)
10T = 1188 - 528 => T = 66.
ANSWER:C
Question: 10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?
A.7
B.9
C.21
D.3
Answer: A.7
Explanation: 1 woman's 1 day's work =	1/70
1 child's 1 day's work =	1/140
(5 women + 10 children)'s day's work =(5/70 + 10/140) = (	1/14 + 1/14) = 1/7
5 women and 10 children will complete the work in 7 days.
Answer: A
Question: The sum of the first 80 positive even integers is 2,550. What is the sum of the odd integers from 101 to 200, inclusive?
A. 5,050
B. 7,500
C. 10,500
D. 15,000
Answer: C. 10,500
Explanation: 101+103+.......199
If we remove 100 from each of these it will be sum of 1st 100 odd numbers.
so 101+103+.......199 = 80 * 100 + (1+3+5+7+......)
sum of 1st 100 natural numbers = (100 * 101) / 2 = 5050
Sum of 1st 80 positive even integers = 2550
sum of 1st 100 odd numbers = 5050 - 2550 = 2500
so 101+103+.......199 = 80 * 100 + (1+3+5+7+......) = 8000 + 2500 =10500
C is the answer.
Question: An empty bucket being filled with paint at a constant rate takes 6 minutes to be filled to 7/10 of its capacity. How much more time D will it take to fill the bucket to full capacity?
A.7/18
B.9/18
C.2
D.18/7
Answer: D.18/7
Explanation: Solution -
Work and Time are directly proportional. W1/W2=T1/T2
7/10 work in 6 mins
1 work in T mins
(7/10)/1 = 6/T -> T = 60/7 mins.
Remaining minutes to fill the tank D= 60/7 - 6 = 18/7 mins. ANS D.
Question: A certain club has 10 members, including Harry. One of the 10 members is to be chosen at random to be the president, one of the remaining 9 members is to be chosen at random to be the secretary, and one of the remaining 8 members is to be chosen at random to be the treasurer. What is the probability that Harry will be the member chosen to be the treasurer?
A. 1/10
B. 1/80
C. 1/20
D. 1/9
Answer: A. 1/10
Explanation: This question is much easier than it appears.
Each member out of 10, including Harry, has equal chances to be selected for any of the positions (the sequence of the selection is given just to confuse us). The probability that Harry will be selected to be the treasurer is also 1/10.
Answer: A
Question: In a mixture 60 litres, the raƟo of milk and water 2 : 1. If the this raƟo is to be 1 : 2, then the quanity
of water to be further added is
A.20 liters
B.30 liters
C.50 liters
D.60 liters
Answer: D.60 liters
Explanation: Explanation:
Quantity of Milk = 60*(2/3) = 40 liters
Quantity of water = 60-40 = 20 liters
Answer: D
Question: A tap can fill a tank in 2 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
A.1 hr 15 mins
B.2 hr 15 mins
C.3 hr 15 mins
D.1 hr 25 mins
Answer: A.1 hr 15 mins
Explanation: Explanation:
A tap can fill a tank in 2 hours.
Therefore the tap can fill half the tank in 1 hours.
One tap take time to fill half of the tank = 1 hrs
4 taps take time to fill half of the tank = 1/4 hrs = 15 minutes
Total time taken to fill the tank = 1 hr+15 mins = 1 hr 15 mins
Answer : A
Question: In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunch and 15% had both type of lunch. If 96 people were present, how many did not eat either type of lunch ?
A.27
B.26
C.25
D.24
Answer: D.24
Explanation: Explanation:
n(A)=(60/100âˆ—96)=288/5
n(B)=(30/100âˆ—96)=144/5
n(Aâˆ©B)=(15100âˆ—96)=72/5
People who have either or both lunch n(AâˆªB)=288/5+144/5âˆ’72/5
=360/5=72
So People who do no have either lunch were = 96 -72
= 24
ANSWER IS D
Question: 65% of x = 20% of 682.50. Find the value of x?
A.100
B.210
C.150
D.180
Answer: B.210
Explanation: 65% of x = 20% of 682.50
Then, 65/100 * x = 20/100 * 6825/10
x = 210
Answer is B
Question: The length of 3 rods are in the ratio 4 : 5 : 6. If the sum of the weights of the longest and the shortest rod is 10 metres more than the length of the third rod, what is the length of the shortest rod?
A.21m
B.20m
C.8m
D.18m
Answer: C.8m
Explanation: Let the length of the three rods be 4k, 5k and 6k respectively.
4k + 6k = 5k + 10
=> 5k = 10 => k = 2
Therefore the weight of the lightest boy
= 4k = 4(2) = 8 m.
ANSWER:C
Question: There is a sequence A(n) such that A(n+1)=2A(n)-1 and A(1)=3, where n is a positive integer. What is the value of A(56)-A(55)?
A.2^22+1
B.2^23
C.2^23+1
D.2^55
Answer: D.2^55
Explanation: A1= 3
A2= 2*3-1= 5
A3= 2*5-1= 9
A4= 2*9-1= 17
We can notice that there is a squence
A2-A1= 2^1
A3-A2= 2^2
A4-A3= 2^3
Hence A56-A55= 2^55
D is the answer
Question: What is 3/7 of 7/8 of 1/3?
A.1/4
B.3/8
C.9/16
D.1/8
Answer: D.1/8
Explanation: 3/7 * 7/8 * 1/3= 1/8
Answer: D
Question: The average earning of a mechanic for the first-four days of a week is Rs. 18 and for the last four days is Rs. 22. If he earns Rs . 34 on the fourth day, his average earning for the whole week is ?
A.Rs . 15.95
B.Rs 16
C.Rs. 18
D.Rs. 25.71
Answer: C.Rs. 18
Explanation: Answer
Total earning for the week = Sum of earning of first four days + Sum of earning of last four days - Earning of 4th day
= 4 x18 + 4 x 22 -34
= Rs. 126
âˆ´ Average earning = 126 / 7
= Rs. 18
Correct Option: C
Question: UBA Capital recently bought Brand new vehicles for office use. UBA capital only went for Toyota and Honda and bought less of Toyota than Honda at the ratio of 4:6. If 40% of the Toyota bought and 60% of the Honda bought were SUVÃ¢â‚¬â„¢s. How many SUVÃ¢â‚¬â„¢s did UBA capital buy in the aforementioned purchase?
A.66%
B.64%
C.68%
D.52%
Answer: D.52%
Explanation: let total no of Vehicles bought be 100, Toyota 40 and Honda 60, so total number of SUV's bought for Toyota and Honda respectively 40* 40/100=16 and 60* 60/100=36
so total 52 SUV's were bought out of 100 Vehicles bought..so required % is 52%
ANSWER:D
Question: If R is between (4) and (-4), which of the following can be greatest?
A.(7/(R+1))
B.R^2
C.R^3
D.R^4
Answer: A.(7/(R+1))
Explanation: 7/(R+1) - can be as large as possible.
for eg. if R = -1.000001 => 7/(R+1) = 7000000
Ans A
Question: In a school class of 30 youngsters , the average weight of male is 20 kg and the average weight of the female is 25 kg . The fraction of male out of the total youngsters of the class is
A.data insufficient
B.1/2
C.3/5
D.6/5
Answer: A.data insufficient
Explanation: the number of male = B and number of female = G.
=>B + G = 30
total weight of male = W1 and total weight of female = W2
average weight of male = total weight of male/number of male
total weight of male/number of male= 20
W1/B = 20
W1 = 20B
average weight of female = total weight of female/number of female
25 = W2/G
W2 = 25G
Data is not sufficient to solve the equation
ANSWER A
Question: A 300 metre long train crosses a platform in 39 seconds while it crosses a post in 18 seconds. What is the length of the platform?
A.150 m
B.350 m
C.420 m
D.600 m
Answer: B.350 m
Explanation: Explanation:
Length of the train = distance covered in crossing the post = speed × time = speed × 18
Speed of the train = 300/18 m/s = 50/3 m/s
Time taken to cross the platform = 39 s
(300+x)/(50/3) = 39 s where x is the length of the platform
300+x = (39 × 50) / 3 = 650 meter
x = 650-300 = 350 meter
Answer: Option B
Question: If (2x + 1) times (3x + 1) is an odd integer, then x must be:
A.an odd integer
B.an even integer
C.a prime number
D.a composite number
Answer: B.an even integer
Explanation: Solution:
(2x + 1) times (3x + 1) means (2x + 1)(3x + 1)
(2x + 1)(3x + 1) = 6x^2+5x+1
For 6x^2+5x+1 to be odd, 5x+1 must be odd since 6x^2 is always even.
So 5x must be even, hence x must be even.
Therefore x is an even integer.
Answer: B
Question: The probability of pulling a black ball out of a glass jar is 1/C. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
A.1/(XY)
B.C/Y
C.Y/X
D.1/(X+Y)
Answer: B.C/Y
Explanation: P of pulling a black ball out of a glass jar AND breaking the jar = 1/Y
P of pulling a black ball out of a glass jar is 1/C
Lets say P of breaking the jar = n
That means 1/C*n=1/Y
n= C/Y
B is the answer
Question: Mr Yadav spends 60% of his monthly salary on consumable items and 50% of the remaining on clothes and transport. He saves the remaining amount. If his savings at the end of the year were 38400, how much amount per month would he have spent on clothes and transport?
A.4038
B.8076
C.3200
D.4845.6
Answer: C.3200
Explanation: ∵ Amount, he have spent in 1 month on clothes transport = Amount spent on saving per month
∵ Amount, spent on clothes and transport
= 38400⁄12 = 3200
Answer C
Question: The speed of a boat in upstream is 100 kmph and the speed of the boat downstream is 130 kmph. Find the speed of the boat in still water and the speed of the stream?
A.170, 10 kmph
B.35, 27 kmph
C.50, 60 kmph
D.115, 15 kmph
Answer: D.115, 15 kmph
Explanation: Speed of the boat in still water = (100+130)/2 = 115 kmph. Speed of the stream = (100-130)/2 = 15 kmph
ANSWER:D
Question: Last year, sales at Company Dopler were 2% greater in February than in January, 4% less in March than in Feb, 20% greater in April than in March, 10% less in May than in April, and 10% greater in June than in May. In which month were sales closest to Jan?
A.Mar
B.April
C.Feb
D.May
Answer: C.Feb
Explanation: Jan = $100
2% greater in February than in January ---> Feb = $102
4% less in March than in Feb ---> Mar = $97.92
20% greater in April than in March ---> Apr = $117.50
10% less in May than in April ---> May $105.75
10% greater in June than in May --->Jun = $116.33
Answer : C
Question: Tom wants to buy items costing $25.35, $100.69, and $85.96. He earns $6.50 an hour doing
odd jobs. If ten percent of his income is put aside for other purposes, how many hours must he
work to earn the money he needs for his purchases? Round your answer to the nearest whole
hour.
A.8 hours
B.48 hours
C.36 hours
D.18 hours
Answer: C.36 hours
Explanation: $6.50 x .10 = $.65 is 10% of his hourly income
$6.50 - .65 = $5.85 hourly amount available to spend
$25.35 + $100.69 + $85.96 = $212 total needed
$212 ÷ $5.85 = 36.2... rounds to 36 hours
correct answer C
Question: A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, how many birds A has killed?
A.10
B.20
C.30
D.40
Answer: C.30
Explanation: Let the total number of shots=x
Shots fired by A=5x/8
Shots fired by B=3x/8
Killing shots by A=5x/8×1/3=5x/24
Missing shots by B=3x/8×1/2=3x/16
B has missed 27 times⇒3x/16=27
⇒x=27×16/3=144
Hence, killing shots by A=5x/24=(5×144)/24=5×12/2=30
i.e., A has killed 30 birds
Answer is C.
Question: The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 20% profit?
A.2000
B.2778
C.2299
D.1920
Answer: D.1920
Explanation: Let C.P. be Rs. x.
Then, (1920 - x)/x * 100 = (x - 1280)/x * 100
1920 - x = x - 1280
2x = 3200 => x = 1600
Required S.P. = 120 % of Rs. 1600 = 120/100 * 1600 = Rs. 1920.
Answer:D
Question: A and B can finish a work in 16 days while A alone can do the same work in 24 days. In how many days B alone will complete the work?
A.76 days
B.48 days
C.98 days
D.31 days
Answer: B.48 days
Explanation: B = 1/16 – 1/24 = 1/48 => 48 days
Answer: B
Question: From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done?
A.741
B.756
C.787
D.988
Answer: B.756
Explanation: We may have (3 men and 2 women) = (7C3 x 6C2) = 525
or (4 men and 1 woman) = (7C4 x 6C1) = 210
or (5 men only) = (7C5) = 21
Required ways = 756
ans - B
Question: If 20% of a number = 300, then 120% of that number will be?
A.20
B.120
C.360
D.1800
Answer: D.1800
Explanation: Let the number x. Then,
20% of x = 300
x = (300 * 100)/20 = 1500
120% of x = (120/100 * 1500) = 1800.
ANSWER:D
Question: 1 ÷ [1 + 1 ÷ {1 + 1 ÷ (1 ÷ 1)}] = ?
A.5/3
B.4/3
C.2/3
D.1/3
Answer: C.2/3
Explanation: Explanation:
1 ÷ [1 + 1 ÷ {1 + 1 ÷ (1 ÷ 1)}]
= 1 ÷ [1 + 1 ÷ {1 + 1 ÷ 1}]
= 1 ÷ [1 + 1 ÷ {1 + 1}]
= 1 ÷ [1 + 1 ÷ 2]
= 1 ÷ [1 + (1/2)] = 1 ÷ 3/2 = 1 × 3/2 = 1 × 2/3 = 2/3
Answer: Option C
Question: At what rate percent on simple interest will Rs.750 amount to Rs.900 in 2 years?
A.10%
B.2%
C.4%
D.5%
Answer: A.10%
Explanation: 150 = (750*2*R)/100
R = 10%
Answer: A
Question: The sum of two numbers is 16, and twice their difference is 4. What are the two numbers?
A.6,7
B.6,8
C.5,11
D.7,9
Answer: D.7,9
Explanation: Let the two numbers be x and y.
Equation (i): x + y = 16
Equation (ii): 2(x - y) = 4
Solve system of equations:
x=16-y
2(16-y-y)=4
16-2y=2 --- y=7
x+7=16 --- x=9
The two numbers are 7 and 9, so answer D is correct.
Question: P and Q started a business investing Rs 10000 and Rs 15000 resp. In what ratio the profit earned after 2 years be divided between P and Q respectively.
A.2:7
B.2:6
C.17:6
D.2:3
Answer: D.2:3
Explanation: Explanation:
In this type of question as time frame for both investors is equal then just get the ratio of their investments.
P:Q = 10000:15000
= 10:15
= 2:3
Option D
Question: The unit digit in the product 7858*1086*4582*9783 is?
A.0
B.1
C.8
D.3
Answer: C.8
Explanation: Unit digit in the given product = unit digit in 8*6*2*3 = 8
Answer is C
Question: A contest will contain n questions each of which is to be answered either true or false. Anyone who answers all n questions correctly will be a winner what is the least value of n for which the probability is less then 1/1000 then a person who randomly guesses the answer to each q's will be a winner?
A.5
B.10
C.50
D.100
Answer: B.10
Explanation: The probability that a person will randomly guess all nn questions correctly is 1/2n1, so we want the value of nmin for which 1/2n<1<11000 --> 2n>1000 as nn is an integer nmin==10 (2^10=1024>1000).
Answer: B.
Question: Solve the equation for x : 6x - 27 + 3x = 4 + 9 - x
A.1
B.2
C.3
D.4
Answer: D.4
Explanation: D
4
9 x + x = 13 + 27
10 x = 40 => x = 4
Question: An article is bought for Rs.600 and sold for Rs.350, find the loss percent?
A.16 1/8%
B.41 1/3%
C.19 2/3%
D.41 2/3%
Answer: D.41 2/3%
Explanation: 600 ---- 250
100 ---- ? => 41 2/3%
Answer: D
Question: If n is the smallest integer such that 72 times n is the square of an integer, what is the value of n?
A. 2
B. 3
C. 6
D. 12
Answer: A. 2
Explanation: 72 can written as = 2 * 2 * 2 * 3 * 3 --> 2^3 * 3^2---(1)
so for 72 * n to be a square of an integer, the integer should have even powers to the prime numbers it composed of.
here 2 already has even power -> So n has to be 3 to make the power of 2 in (1) even
Option A is correct
Question: Find the smallest +ve mathematical number which is spelled in an alphabetical order ?
A.Fifty
B.Twenty
C.Forty
D.Thirty
Answer: C.Forty
Explanation: C
Forty
Question: If 6 (A's capital) = 8 (B's capital) = 10 (C's capital). Then the ratio of their capitals is:
A.20:15:33
B.20:25:33
C.20:15:12
D.20:15:09
Answer: C.20:15:12
Explanation: Explanation:
6A = 8B = 10 C
A:B:C = 1/6:1/8:1/10
= 20:15:12
Answer: C
Question: A train passes a station platform in 42 seconds and a man standing on the platform in 22 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.299
B.277
C.240
D.300
Answer: D.300
Explanation: Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 22) m = 330 m.
Let the length of the platform be x meters.
Then, x + 330 / 42 = 15
x + 330 = 630
x = 300 m.
Answer:D
Question: The Product of two number is 20. The sum of square of the two number is 81. Find the sum of the numbers
A.21
B.19
C.9
D.11.
Answer: D.11.
Explanation: Solution
Let the numbers be x, y
= x2+y2= 81
=2(x+y)=40
=> (x+y)2=81+40=121,
=> x+y=sqrt(121)=11.
Answer D
Question: A young girl counted in the following way on the fingers of her left hand. She started collang the thumb 1, the index finger 2, the middle finger 3, the ring finger 4, the little finger 5, then reversed direction calling the ring finger 6, the the middle finger 7, the index finger 8, the thumb 9 then back to the index finger for 10, the middel finger for 11, and so on. She counted up to 1998. She ended on her
A.a) thumb
B.b) the index finger
C.c) the middle finger
D.d) the ring finger
Answer: C.c) the middle finger
Explanation: Notice the pattern. The thumb lansd up at numbers 1,9,17,25,33,... so every 8th number
By this patter the thumb is also at number 1993 (multiple of 8 + 1)
Hence 1998 has to be the middle finger
Answer is (C)
Question: A light has a rating of 60 watts, it is replaced with a new light that has 12% higher wattage. How many watts does the new light have?
A.105
B.67
C.80
D.60
Answer: B.67
Explanation: Final number = Initial number + 12%(original number) = 60 + 12%(60) = 60 + 7 = 67
Answer B
Question: A reduction of 10% in the price of a pen enabled a trader to purchase
9 more for Rs. 540. What is the reduced price of the pen?
A.8
B.6
C.5
D.4
Answer: B.6
Explanation: Due to 10% tot cost req to purchase the same no of pens will dec by rs 54
and tot add 9 pen eql this amt
=>54/9=6
ANSWER B
Question: The C.I. on a certain sum for 2 years Rs.41 and the simple interest is Rs.40. What is the rate percent?
A.4
B.5
C.6
D.1
Answer: B.5
Explanation: SI = 20 + 20
CI = 20 + 21
20 ---- 1
100 ---- ? => 5%.Answer: B
Question: Initially 150. Reduced by 20%. How it is to be reduced to become 108?
A.10%
B.20%
C.30%
D.40%
Answer: A.10%
Explanation: 150*20/100=30
so now we have 150-30=120 in hand
to make it 108, reduce 12
12=120*x/100,
x% is to be reduced
x=10%
ANSWER:A
Question: For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 95 units raises the average to 55 units per day, what is the value of n?
A.6
B.7
C.8
D.9
Answer: C.8
Explanation: The average daily production was raised by 5 units for n days, which has a weighting of 5n.
5n = 95-55 = 40
n = 8
The answer is C.
Question: The sum of the squares of two consecutive positive integers exceeds their product by 91. Find the integers?
A.9, 10
B.10, 11
C.11, 12
D.12, 13
Answer: A.9, 10
Explanation: Let the two consecutive positive integers be x and x + 1
x2 + (x + 1)2 - x(x + 1) = 91
x2 + x - 90 = 0
(x + 10)(x - 9) = 0 => x = -10 or 9.
As x is positive x = 9
Hence the two consecutive positive integers are 9 and 10.
ANSWER:A
Question: The average of five consecutive odd numbers A, B, C, D and E is 13. What percent of B is C ?
A.98.2
B.102.8
C.108.2
D.118.2
Answer: D.118.2
Explanation: Explanation :
In such a case the middle number (C) is the average
∴ C = 13 and B = 11
Required percentage = 13/11 x 100 = 118.2
Answer : Option D
Question: Cost of 16 mirror and 8 comb is Rs.336 and the cost of 4 mirror and 4 comb is Rs.96. Find the cost of each mirror?
A.10
B.18
C.20
D.21
Answer: B.18
Explanation: Let the cost of each pen and pencil be 'p' and 'q' respectively.
16m + 8c = 336 --- (1)
4m + 4c = 96
8m + 8c = 192 --- (2)
(1) - (2) => 8p = 144
=> m = 18
B
Question: In Goshawk-Eurasian nature reserve 30 percent of the birds are Hawks, and 40 percent of the non-Hawks are Paddyfield-Warblers. If there are 25 percent as many Kingfishers as Paddyfield-Warblers in the reserve, then what percent of the birds R in the nature reserve are not Hawks, Paddyfield-Warblers, or Kingfishers?
A.25%
B.35%
C.45%
D.70%
Answer: B.35%
Explanation: 1. We are given the following percentages: 30 (70), 40 (60), 25 (75). There are two threads from here. First starts at 30% and finishes there. Second one starts at 70, then 40, and then 25. We need a value that is divisible by 7, 2, and 5 at least once. lets pick a number now, say 700. So say if Non Hawks are 700 (this is 70% of the total, so total = 1000), then Paddy Warbs are 2/5 x 700 = 1400/5 = 280. Kingfishers, therefore, are 280/4 = 70. Lets add them up. 300 hawks + 280 Peddy Warbs + 70 kingsifhers = 650. So all others are 1000 - 650= 350 or 35% of total birds.
The main job here to to identify the smart number to start the question with. This can be time consuming, but once identified, this question can be solved fairly quickly.
2. Another method: If X is total --> Non Hawks = 0.7X --> Warbs = 0.4(0.7X) --> KFs = 0.25(0.4(0.7X)).
Our job is to find out R: (0.3X + 0.28X + 0.07X)/ X. OR 0.65X/X = 0.65. We need to find 1-0.65 = 0.35 or 35%.B
Question: A marketing survey of Anytown found that the ratio of trucks to sedans to motorcycles was 3:7:2, respectively. Given that there are 11,200 sedans in Anytown, how many motorcycles are there?
A.1260
B.2100
C.3600
D.3200
Answer: D.3200
Explanation: Let the total number of trucks = 3x
total number of sedans = 7x
total number of motorcycles = 2x
total number of sedans = 11200
=> 7x = 11200
=> x = 1600
total number of motorcycles =2x = 2*1600
=3200
Answer D
Question: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2475?
A.s.800
B.s.810
C.s.825
D.s.900
Answer: C.s.825
Explanation: 2475 * 1/3 = 825
Option C
Question: A boat can move upstream at 25 kmph and downstream at 35 kmph, then the speed of the current is?
A. 5 kmph
A.5
B.8
C.9
D.3
Answer: A.5
Explanation: US = 25
DS = 35
M = (35 - 25)/2
= 5
Answer:A
Question: The decimal 0.1 is how many times greater than the decimal (0.01)^3?
A.10
B.10^2
C.10^5
D.10^8
Answer: C.10^5
Explanation: 0.1 = 10^-1
(0.01)^3 = (10^-2)^3 = 10^-6
10^5 * 10^-6 = 10^-1
The answer is C.
Question: 60% of a number is added to 160, the result is the same number. Find the number?
A.300
B.400
C.266
D.99
Answer: B.400
Explanation: :
(60/100) * X + 160 = X
2X = 800
X = 400
Answer: B
Question: A box contains 20 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random form this box. The probability that at least one of these is defective is:
A.8/19
B.7/19
C.10/19
D.20/19
Answer: B.7/19
Explanation: P(none is defective)=16c2/20c2
=12/19
P( at least one is defective)= 1-12/19
=7/19
ANSWER B
Question: There are 2 sections A and B in a class, consisting of 50 and 50 students respectively. If the average weight of section A is 60kg and that of section B is 80kg, Find the average of the whole class?
A.50.78kg
B.49.32kg
C.61.67kg
D.70kg
Answer: D.70kg
Explanation: Total weight of 50+50 students = 50*60 + 50*80 = 3000+4000
Average weight of the class is = 7000/100 =70 kg
Answer is D