RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A number when divided by 17 leaves 11 as a remainder. This number is greater than fifty but less than seventy. What will be the remainder if the number is divided by 10?
A.5
B.8
C.2
D.17
Answer: C.2
Explanation: Let 17 + 11 = 28 be the smallest number divisible by 17 with a remainder of 11.
Since 17 is prime, we need only add 17 to 28 until we enter the specified range.
17 + 17+ 11= 45 That doesn't fit.
17 +17 +17 +11=62 Bingo!
Now, 62 divided evenly into tens leaves a remainder of 2.
The answer is C.
Question: Two dogsled teams raced across a 700-mile course in Alaska. Team A finished the course in 7 fewer hours than team B. If team A’s average speed was 5 miles per hour greater than that of team B, what was team B’s average speed, in miles per hour?
A.12
B.15
C.18
D.20
Answer: D.20
Explanation: Let v be team B's average speed.
Time = Distance/Rate and the time difference was 7 hours.
700/v - 700/(v+5)= 7
700v + 3500 - 700v = 7(v)(v+5)
500 = (v)(v+5)
(20)(25) = (v)(v+5)
v = 20 mph
The answer is D.
Question: Find the invalid no.from the following series 3, 7, 15, 31, 61, 127, 255
A.3
B.61
C.27
D.63
Answer: B.61
Explanation: Go on multiplying the number by 2 and adding 1 to it to get the next number.So, 61 is wrong.
B
Question: Darcy lives 1.5 miles from work. She can walk to work at a constant rate of 3 miles per hour, or she can ride the train to work at a constant rate of 20 miles per hour. If she rides the train, there is an additional x minutes spent walking to the nearest train station, waiting for the train, and walking from the final train station to her work. If it takes Darcy a total of 25 more minutes to commute to work by walking than it takes her to commute to work by riding the train, what is the value of x?
A.10.5
B.0.5
C.25.5
D.30
Answer: B.0.5
Explanation: The time it takes Darcy to walk to work is (1.5/3)*60 = 30 minutes
The time it takes Darcy to take the train is (1.5/20)*60 + x = 4.5 + x minutes
It takes 15 minutes longer to walk, so 30 = 4.5 + x + 25
x=0.5 minutes
Answer: B
Question: Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2% more. She would get how much?
A.9680
B.96288
C.26667
D.1662
Answer: A.9680
Explanation: (8000*3*2)/100 = 480
9200
--------
9680
Answer:A
Question: The simple interest and the true discount on a certain sum for a given time and at a given rate are Rs. 85 and Rs. 80 respectively. The sum is:
A.Rs. 1800
B.Rs. 1450
C.Rs. 1360
D.Rs. 6800
Answer: C.Rs. 1360
Explanation: sum=si*td/(si-td)
sum=80*85/(85-80)
sum=1360
ANSWER:C
Question: 3 candidates in an election and received 1136, 7636 and 11628 votes respectively. What % of the total votes did the winning candidate gotin that election?
A.40%
B.55%
C.57%
D.60%
Answer: C.57%
Explanation: Total number of votes polled = (1136 + 7636 + 11628) = 20400
So, Required percentage = 11628/20400 * 100 = 57%
C
Question: What is the value of 3x^2 − 2.4x + 0.3 for x = 0.6?
A.−0.3
B.0
C.0.06
D.1.08
Answer: C.0.06
Explanation: 3x^2-2.4x+0.3 for x=0.6
=3(0.6*0.6)-4*0.6*(0.6)+0.3
=-0.6*0.6+0.3
=0.06
Correct Option : C
Question: Aman started a business investing Rs. 60,000. Rakhi joined him after six months with an amount of Rs. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business?
A.12:15:18
B.72:105:112
C.52:105:112
D.62:105:112
Answer: B.72:105:112
Explanation: Explanation:
Aman : Rakhi : Sagar = (60000 * 36) : (105000 * 30) : (140000 * 24)
= 72:105:112
Answer: B
Question: A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 42 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
A.229
B.288
C.787.5
D.888
Answer: C.787.5
Explanation: D = 30 * 5 = 150
RS = 42 – 30 = 8
T = 150/8 = 18.75
D = 42 * 18.75 = 787.5 km
Answer: C
Question: What is the sum of all 3 digit positive integers that can be formed using the digits 1, 4, and 8, if the digits are allowed to repeat within a number?
A.12,987
B.13,876
C.14,765
D.15,654
Answer: A.12,987
Explanation: The number of these 3-digit numbers is 3*3*3 = 27
Each digit 1, 4, and 8 will appear in the ones, tens, and hundreds place 9 times each.
The sum equals 9(111) + 9(444) + 9(888) = 12,987
The answer is A.
Question: What is the unit digit in the product (245 x 122 x 431)?
A.2
B.3
C.0
D.1
Answer: C.0
Explanation: Explanation:
Product of unit digits = 5 x 2 x 1 = 10
Required digit = 0
Answer: Option C
Question: A certain company employs 6 senior officers and 4 junior officers. If a committee is to be created, that is made up of 3 senior officers and 1 junior officer, how many different committee are possible?
A.8
B.24
C.58
D.80
Answer: D.80
Explanation: 6!/3!(6-3)! = 20
4!/1!(4-1)!=4
so number of different committees equals 20*4=80
ANS:D
Question: One fourth of a solution that was 10 percent RICE by weight was replaced by a second solution resulting in a solution that was 16 percent RICE by weight. The second solution was what percent RICE by weight ?
A.34%
B.24%
C.22%
D.18%
Answer: A.34%
Explanation: EQ can be written as ...
let sol be s... so (3/4)s*(.1)+(1/4)s*t=s*(.16).... we get t(% of RICE in 2nd sol)=34%=A
Question: In racing over a given distance d at uniform speed, A can beat B by 20 meters, B can beat C by 6 meters, and A can beat C by 23 meters. What is the distance d in meters?
A.32
B.36
C.40
D.48
Answer: C.40
Explanation: When A is at the finish line, B is 20 meters back, and C is 23 meters back.
When B runs another 20 meters to the finish line, C is 6 meters back.
So B gains 3 meters every 20 meters covered.
To gain a final difference of 6 meters, B runs a total of 40 meters.
The answer is C.
Question: A company decreased the price of its main product by 10%. Subsequently, the number of units sold increased such that the total revenue remained unchanged. What was the ratio of the percent increase in the units sold to the percent decrease of the original price for this product?
A.4.3
B.5.6
C.6.2
D.10.0
Answer: D.10.0
Explanation: For the total revenue to remain the same when the price is 1/10, the number of products sold must 1/10 times. Therefore increase in the number of products sold is 100%
=> The required ratio = 100%/10% = 10.0
Answer : D
Question: At Deluxe paint store, Fuchsia paint is made by mixing 6 parts of red paint with 3 parts of blue paint. Mauve paint is made by mixing 4 parts of red paint with 5 parts blue paint. How many liters of blue paint must be added to 24 liters of Fuchsia to change it to Mauve paint?
A.9
B.12
C.15
D.16
Answer: B.12
Explanation: in 24 liters, Red = 6/9 * 24 = 16 and Blue = 8
so, 16/(8+x) = 4/5
or, x = 12 (Answer B)
Question: A = {2, 3, 5, 7, 11}
B = {2, 4, 6, 19}
Two integers will be randomly selected from sets A and B, one integer from set A and one from set B, and then multiplied together. How many different products can be obtained?
A.15
B.16
C.19
D.24
Answer: D.24
Explanation: Step 1: Find out the number of products you get.
5 distinct numbers in set A and 4 distinct in set B so number of products = 5*4 = 20
Step 2: Remove the products that appear more than once.
Notice that 5, 7, 11 and 13 are primes and none of their multiples are in either set. So ignore them. We just need to focus on 2 and 3 of set A and 2, 4 and 6 of set B.
2, 3
2, 4, 6
The only product repeated when you take a number from each set is 12. (3*4 and 2*6) Rest all are distinct.
Answer = 20 - 1 = 24
Note here that the second step will involve manual calculation since it will depend on the specific numbers you have in the two sets.
D
Question: Some of the people in Town V are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town V, three times as many people are tall as are tall in Town V, three times as many people are both as are both in Town V, but no one is neither. If the total number of people in Town V is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town V who are neither left-handed nor tall?
A. 23
B. 39
C. 72
D. 143
Answer: D. 143
Explanation: Yes, correct answer is indeed D.
{V}={Left} + {Tall} - {Both} + {Neither};
{Y} = 3*{Left} + 3*{Tall} - 3*{Both};
Since the total number of people in Town V is four times greater than the total number of people in Town Y, then:
{Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});
{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town V who are neither left-handed nor tall must be a multiple of 11.
Only answer choice D, is a multiple of 11: 143=11*13.
Answer: D.
Question: There are 1000 buildings in a street. A sign-maker is contracted to number the houses from 1 to 1000. How many zeroes will he need?
A.190
B.191
C.192
D.193
Answer: C.192
Explanation: divide as (1-100)(100-200)....(900-1000)
total 192
ANSWER:C
Question: Seven years ago the average age of a family of 2 members was 22 years. A child has been born. due to Which the average age of the family is 23 years today. What is the present age of the child?
A.30years
B.33years
C.35years
D.37years
Answer: B.33years
Explanation: Explanation:
Average of the family of two numbers
7 years ago = 22
= (22+ 7) * 2 = 36 years
Average age of the family of three members at present = 23 years
= 23 * 3 = 69 YEARS
Age of child = 69 - 36 = 33 years
Answer: Option B
Question: Mr. Sane invested a total amount of 16,500 for two years in two schemes A and B with rate of simple interest 10 p.c.p.a. and 12 p.c.p.a. respectively. If the total amount of interest earned was 3,620, what was the amount invested in scheme B?
A.8,000
B.8,600
C.8,150
D.Data inadequate
Answer: A.8,000
Explanation: % interest on total amount per annum
= 3620×100/16500×2=362/33%
Now, use Alligation method.
Hence, ratio of amount invested in schemes A and B
= (12 - 362⁄33) : (362⁄33 - 10) = 17 : 16
Hence, amount invested in B = 16×16500/(17+16)=8000
Answer A
Question: A circular box kept around a circular place. If the difference between the circumference of the outer circle and the inner circle is 44m, find the width of the box?
A.5 m
B.6 m
C.4 m
D.7 m
Answer: D.7 m
Explanation: Let radius of the outer circle be R and radius of the inner circle be r.
Circumference of the outer circle =
Circumference of the inner circle =
But,
or, R - r =
Thus, width of the road = 7 m
D
Question: Five drainage pipes, each draining water from a pool at the same constant rate, together can drain a certain pool in 12 days. How many additional pipes Q, each draining water at the same constant rate, will be needed to drain the pool in 4 days?
A. 6
B. 9
C. 10
D. 12
Answer: C. 10
Explanation: This is an inverse proportional problem......
5 pipes in 12 days; So for 4 days, it will be = 12 x 5 / 4 = 15
So, Q=15-5 = 10.C
Question: If 2 tables and 3 chairs cost Rs, 3500 and 3 tables and 2 chairs cost Rs. 4000, then how much does a table cost ?
A.500
B.1000
C.1500
D.2000
Answer: B.1000
Explanation: Explanation:
Let the cost of a table and that of a chair be Rs. x and Rs, y respectively.
Then, 2x + 3y = 3500 ...(i)
and 3x + 2y = 4000 .....(ii)
solving (i) and (ii) we get x = 1000, y = 500
ANSWER IS B
Question: A boat can move upstream at 25 kmph and downstream at 30 kmph, then the speed of the current is?
A.5
B.6
C.7
D.2.5
Answer: D.2.5
Explanation: US = 25
DS = 30
M = (35 - 25)/2 = 2.5
Answer: D
Question: Ron has had 3 pay cuts in her salary in the past 6 months. If the first pay cut was 5%, the second pay cut was 10% and the third was 15%. What will be the percentage decrease, if the salary is decreased in a single shot?
A.29.33%
B.27.33%
C.17.33%
D.27.99%
Answer: B.27.33%
Explanation: Let Rs.100 be initial salary.
Salary After 1st decrease, 5% = 95
Salary After 2nd decrease, 10% = 85.5 i.e. reduced by 10 percent of 95
Salary After 3rd decrease, 15% = 72.675 i.e. reduced by 15 percent of 85.5
So if its decreased in single shot =
i = ( ( b - a ) /b ) * 100
=27.33%
ANSWER:B
Question: tipli and pikli are a married couple (dont ask me who he is and who she is)
They have two children, one of the child is a boy. Assume safely that the probability of each gender is 1/2.
What is the probability that the other child is also a boy?
Hint: It is not 1/2 as you would first think.
A.1/1
B.1/2
C.1/3
D.1/4
Answer: C.1/3
Explanation: Solution:
1/3
This is a famous question in understanding conditional probability, which simply means that given some information you might be able to get a better estimate.
The following are possible combinations of two children that form a sample space in any earthly family:
Boy - Girl
Girl - Boy
Boy - Boy
Girl - Girl
Since we know one of the children is a boy, we will drop the girl-girl possibility from the sample space.
This leaves only three possibilities, one of which is two boys. Hence the probability is 1/3
Answer C
Question: Find the sum of the following series,
1,4/5,16/25,64/125 ……………..
A.7
B.6
C.5
D.4
Answer: C.5
Explanation: It is a G.P with infinite terms. The common ratio is (4/5) and this is less than 1. The sum to infinity of a series with first term ‘a ‘ and common ratio ‘r’ =[ a/( 1-r) ], The sum to infinity = 1/ (1 – 4/5 ) = 5
ANSWER:C
Question: Evaluate combination
97C95=97/(95)!(2)!
A.4656
B.5176
C.4176
D.3176
Answer: A.4656
Explanation: Explanation:
nCr=n!/(r)!(n−r)!
97C95=97!/(95)!(2)!
=97*96*95!/(95)!(2)!
=97*96/2∗1
=4656
Option A
Question: A sum of money is to be distributed among A, B, C, D in the proportion of
5 : 2 : 4 : 3. If C gets Rs. 500 more than D, what is A's share?
A.Rs. 2500
B.Rs. 1000
C.Rs. 1500
D.Rs. 2000
Answer: A.Rs. 2500
Explanation: Sol.
Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x - 3x = 500 ⇔ x = 500.
∴ A's share = Rs. 5x= Rs. (5x500) = Rs. 2500.
Answer A
Question: If the average (arithmetic mean) of a and b is 45 and the average of b and c is 80, what is the value of c âˆ’ a?
A.25
B.70
C.90
D.140
Answer: B.70
Explanation: the arithmetic mean of a and b =(a+b)/2=45 -- a+b=90 --1
similarly for b+c=160 --2
subtracting 1 from 2 we have
c-a=70;
ANSWER:B
Question: A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
A.Rs. 4991
B.Rs. 4993
C.Rs. 4997
D.Rs. 4999
Answer: A.Rs. 4991
Explanation: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991.
Option A
Question: The amount of principal Rs.8000 at compound interest at the ratio of 5% p.a. for 3 years is
A.Rs.9621
B.Rs.6921
C.Rs.9261
D.Rs.6261
Answer: C.Rs.9261
Explanation: c.i=p(1+r/100)^n
=8000(1+5/100)^3
=8000(21/20*21/20*21/20)
=Rs9261
ANSWER:C
Question: The present worth of Rs.676 due in 2 years at 4% per annum compound interest is
A.Rs.150.50
B.Rs.154.75
C.Rs.156.25
D.Rs.625
Answer: D.Rs.625
Explanation: Solution
Present Worth	= Rs.[676/(1+4/100)²]
= Rs.(676x25/26x25/26)
= Rs.625
Answer D
Question: If 0.75: x :: 5:6, then x is equal to:
A.1.12
B.1.16
C.1.2
D.0.9
Answer: D.0.9
Explanation: Explanation:
(x * 5) = (0.75 *6)
X=4.5/5 = 0.9
Answer: D
Question: A 40-liter solution of alcohol and water is 5 percent alcohol. If 5.5 liters of alcohol and 4.5 liters of water are added to this solution, what percent of the solution produced is alcohol?
A.9%
B.11%
C.13%
D.15%
Answer: D.15%
Explanation: The percent of alcohol in the solution is (0.05(40) + 5.5) / 50 = 7.5/50 = 15%
The answer is D.
Question: If a-b= 3 and a^2+b^2=29, find the value of ab
A.10
B.12
C.15
D.18
Answer: A.10
Explanation: 2ab = (a^2 + b^2) - (a - b)^2
= 29 - 9 = 20
=> ab = 10.
ANSWER:A
Question: A sum of money deposited at C.I. amounts to Rs.2560 in 3 years and to Rs.2989 in 4 years. Find the rate percent?
A.30%
B.10%
C.20%
D.16%
Answer: D.16%
Explanation: 2560 --- 429
100 --- ? => 16%
Answer: D
Question: Machines P and Q are two different machines that cover jars in a factory. When Machine P works alone, it covers 15 jars in m hours. When Machines P and Q work simultaneously at their respective rates, they cover 15 jars in n hours. In terms of m and n, how many hours does it take Machine Q, working alone at its constant rate, to cover 15jars?
A.15n/225-mn
B.m
C.n
D.m+n
Answer: A.15n/225-mn
Explanation: working rate p = 15/m ; working rate pq =( 1/p +1/q)* n =15 or mn/15 +n/q =15 0r n/q = 15-mn/15 = 225-mn/15
q = 15n/225-mn
A
Question: Mike earns $14 per hour and Phil earns $12 per hour. Approximately how much less, as a percentage, does Phil earn than Mike per hour?
A.25%
B.32.5%
C.14%
D.37.5%
Answer: C.14%
Explanation: What % less of 14 is 12
let it be x % less ,then
=14(1-x/100)=12
1-x/100=12/14
x=100/7
x=14%
Ans C
Question: How many seconds will a train 100 meters long take to cross a bridge 120 meters long if the speed of the train is 36 kmph?
A.22 sec
B.27 sec
C.25 sec
D.24 sec
Answer: A.22 sec
Explanation: Explanation:
D = 100 + 120 = 220
S = 36 * 5/18 = 10 mps
T = 250/10 = 22 sec
Answer: Option A
Question: A certain industrial loom weaves 0.13 meters of cloth every second. Approximately how many seconds will it take for the loom to weave 15 meters of cloth?
A.114
B.115
C.116
D.117
Answer: B.115
Explanation: Let the required number of seconds be x
More cloth, More time, (direct proportion)
Hence we can write as
(cloth) 0.13 : 15 :: 1 : x
=>0.13*x=15
=>x=15/0.13
=>x=115
ANSWER:B
Question: 25 onions on a scale weigh 5.12 kg. When 3 onions are removed from the scale, the average weight of the 22 onions is 200 grams. What is the average weight (in grams) of the 3 onions which were removed?
A.200
B.220
C.240
D.260
Answer: C.240
Explanation: 22*200=4400.
The other 3 onions weigh a total of 720 grams.
The average weight is 720/3 = 240 grams.
The answer is C.
Question: From the sale of sleeping bags, a retailer made a gross profit of 14% of the wholesale cost. If each sleeping bag was sold for $28, what was the wholesale cost per bag?
A.3.0
B.3.36
C.24.56
D.25.0
Answer: C.24.56
Explanation: Cost price * 1.14 = Selling price --> Cost price * 1.14 = $28 --> Cost price = $24.56.
Answer: C.
Question: 275, 132, 462, 396, 327, 891, 121
A.327
B.228
C.2768
D.028
Answer: A.327
Explanation: Explanation:
In each number except 327, the middle digit is the sum of the other two.
ANSWER: A
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
A.280
B.999
C.277
D.277
Answer: A.280
Explanation: x*(85/100) = (480 - x)119/100
x = 280
Answer: A
Question: A sum of money becomes triple itself in 5 years at simple interest. How many years will it become six times at the same rate?
A.12 1/2
B.12 1/5
C.12 1/9
D.12 1/3
Answer: A.12 1/2
Explanation: 100 ---- 200 ---- 5
200 ---- 5
100 ---- 2 1/2
------------------
600 ---- 12 1/2 years.Answer: A
Question: A group of four Womens and three Mens have tickets for seven adjacent seats in one row of a theater. If the three mens will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?
A.7! – 5!3!
B.7! – 4!3!
C.7 × 2!3!2!
D.7! – 2!3!
Answer: A.7! – 5!3!
Explanation: There are 3 boys and 4 girls , we want to calculate the seating arrangements if three mens do not sit together, like MMM.
Let's calculate the # of arrangements when they SIT together and subtract from total # of arrangements of these 7 persons without restriction. Thus we'll get the # of arrangements asked in the question.
1. Total # of arrangements of 7 is 7!.
2. # of arrangements when 3 mens are seated together, like MMM;
Among themselves these 3 boys can sit in 3! # of ways,
Now consider these 3 boys as one unit like this {MMM}. We'll have total of 5 units: {MMM}{W}{W}{W}{W}. The # of arrangements of these 5 units is 5!.
Hence total # of arrangements when 3 men sit together is: 3!5!.
# of arrangements when 3 mens do not sit together would be: 7!-3!5!.
Answer: A).
Question: In an election between two candidates first candidate got 60% of votes polled and second Candidate got 240 votes. The total number of votes polled was?
A.votes
B.votes
C.votes
D.votes
Answer: A.votes
Explanation: Total = 100 %,
First person got 60%
second person got remaining 40 % of votes.
than 40 % = 240
40% = 40×7 = 240
100% =100×7 =700 votes
A)
Question: Thirty percent of the women in a college class are science majors, and the non-science majors make up 80% of the class. What percentage of the women are science majors if 40% of the class are men?
A.2%
B.5%
C.28%
D.30%
Answer: D.30%
Explanation: 3/k + 2/m = 6/t
Assuming total # is 100 :
[Science - Women] will have - 0.3 * 60 = 18
[Non-Science-Women] will have - 42
[Science-Men] will have = 20-18 = 2
S0 18/60 * 100 = 30%
Answer - D
Question: The true discount on Rs. 1760 due after a certain time at 12% per annum is Rs. 160.The time after which it is due is :
A.6 months
B.8 months
C.9 months
D.10 months
Answer: D.10 months
Explanation: Solution
P.W = Rs.(1760 - 160)= Rs.1600. ∴ S.I. on Rs.1600 at 12% is Rs.160. ∴ Time =(100x160/1600x12 ) = 5/6years = ( 5/6x12) months = 10 months
Answer D
Question: Albert invested amount of 24000 in a fixed deposit for 2 years at compound interest rate of 5 % per annum. How much Albert will get on the maturity of the fixed deposit
A.Rs. 8510
B.Rs. 26460
C.Rs. 8730
D.Rs. 8820
Answer: B.Rs. 26460
Explanation: Explanation:
=>(24000×(1+5/100)2)
=>24000×21/20×21/20
=>26460
Option B
Question: In a business A and C invested amounts in the ratio 2 : 1. Whereas the ratio between amounts invested by A and B was 3 : 2. If 1,57,300 was their profit, how much amount did B receive?
A.72,600
B.48,400
C.36,300
D.24,200
Answer: B.48,400
Explanation: Ratio A : B = 3 : 2 and A : C = 2 : 1
\ A : B : C = 6 : 4 : 3
Profit share of B = 4 × 1,57,300 = 48400
Answer B
Question: On a windy day, out of every 3 sand dunes formed, only 1 remains. Out of 5 blown-out
sand-dunes, 1 has treasure and only 3 out of 5 sand dunes formed have lucky coupons. Find
the probability that the blown-out sand dune will contain both the things.
A.2/25
B.4/75
C.7/75
D.3/5
Answer: A.2/25
Explanation: Probability of sand dune blown out = 2/3
Probability that it has treasure = 1/5
Probability that it has lucky coupon = 3/5
total probability = 2/3 * 1/5 * 3/5 = 2/25
ANSWER:A
Question: A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?
A.111.12
B.188.93
C.111.17
D.111.89
Answer: A.111.12
Explanation: A runs 1000 m while B runs 900 m and C runs 800 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 800)/900 = 8000/9
= 888.88 m.
B can give C = 1000 - 888.88
= 111.12 m.
Answer:A
Question: A radio station has to choose seven days of the seven in a week to broadcast a certain program, and that set will repeat each week. The program can be broadcast equally on any of the seven weekdays —- weekdays vs. weekends don’t matter at all —- nor does it matter whether the days the program airs are adjacent or not. Absolutely any three of the seven weekdays can be chosen. How many different three-day combinations of the seven weekdays can be constructed?
A.9
B.15
C.1
D.35
Answer: C.1
Explanation: Behind the story, we are really being asked to evaluate 7C7. We could use the factorial formula, but above we conveniently happen to have Pascal’s Triangle written out to the seventh row. We see that 7C7, the third entry of the seventh row, is 1. Answer = C.
Question: A man purchases the milk at Rs. x/litre and sells it at Rs. 2x/liter stillhe mixes 2liters water with every 6liters of pure milk. Whatis the profit %?
A.120%
B.145%
C.145.6%
D.166.66%
Answer: D.166.66%
Explanation: Let the cost price of 1 litre pure milk be Re.1, then
\inline{6litres(milk)→CP=Rs.62litres(water)→CP=Rs.0}{6litres(milk)→CP=Rs.62litres(water)→CP=Rs.0}\rightarrow CP=Rs.6 only
and 8 litre mixture \rightarrow SP \rightarrow 8 x 2 = Rs.16
Profit %= 166.66%
D