RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The following sets each have a mean of 10 and the standard deviations are given in variable form.
Set I = {10, 10, 10, 10, 10, 10}, standard deviation = P
Set II = { 7, 8, 9, 11, 12, 13}, standard deviation = R
Set III = {6, 6, 6, 14, 14, 14}, standard deviation = Q
Rank these three standard deviations from least to greatest.
A.P, Q, R
B.P, R, Q
C.R, Q, P
D.Q, R, P
Answer: C.R, Q, P
Explanation: SD is minimum when the terms are closer to the mean.
In set 1, we have all terms equal to mean. hence, its SD is 0.(The Lowest)
Comparing Set 2 and Set 3, Set 2 has terms more closer to mean than set 3. hence, Set 3 Sd is the highest.
So, Answer is C
Question: What percent is 400 gm of 1 kg?
A.25%
B.40%
C.10%
D.8%
Answer: B.40%
Explanation: 1 kg = 1000 gm
400/1000 Ã— 100 = 40000/1000
=40 %
Answer is B
Question: If pq = p + q^2 – 2pq, for what value of q is pq equal to p for all values of p?
A.-2
B.-1
C.1
D.0
Answer: D.0
Explanation: C
p + q2 â€“ 2pq = p
=> q2 - 2pq = 0
=> q (q - 2p) = 0
=> q = 0 or q = 2p
im not following the logic you used here.. how did you replace pq with 0 could someone help explain it in MORE DETAI
D
Question: A women sells 3 different size(in kgs) packs of sugar which are multiples of 1.A person who buys sugar should buy all types of packs.4 different people buys 20,21,23,29 kgs .what will the maximum and minimum amounts a person can buy??
A.22
B.33
C.34
D.54
Answer: B.33
Explanation: packet are 11,6 and 7
7+7+6=20
7+7+7=21
6+6+11=23
7+11+11=29
and min 6+6+6=18
and max 11+11+11=33
ANSWER:B
Question: A fence consists of m lengths of fence that are each n feet long. A fence post separates each length of fence by its width of x feet. What is the total length Q of the fence including the fence posts on each end?
A.mn
B.m(n + x)
C.Q=m(n + x) + x
D.m(n + x) + 2x
Answer: C.Q=m(n + x) + x
Explanation: Notice that since a fence post separates each length of fence, then there will be m+1 posts, for example if there are m=2 fences, then there will be 3 posts: PFPFP. Thus the total length of the posts is (m+1)x.
The total length Q of the fence is mn, therefore the total length of the fence including the fence posts on each end is (m+1)x+mn=mx+x+mn=m(n+x)+x.
Answer: C.
Question: At the end of the month, a certain ocean desalination plant’s reservoir contained 6 million gallons of water. This amount is twice the normal level. If this amount represents 60% of the reservoir’s total capacity, how many million gallons short of total capacity is the normal level?
A.15
B.10
C.5
D.20
Answer: C.5
Explanation: the Q talks of total capacity, normal level, present level, shortage etc..
so it is all about not going wrong in these terms
6 MG= 60% of Total..
total = 6/.6=10MG..
Normal level= 1/2 of 10=5MG..
shortage of normal level=10-5=5MG..
C
Question: A piece of work can be done by 6 men and 5 women in 6 days or 3 men and 4 women in 10 days. It
can be done by 9 men and 15 women in how many days ?
A.3 days
B.4 days
C.5 days
D.6 days
Answer: A.3 days
Explanation: Explanation:
To calculate the answer we need to get 1 man per day work and 1 woman per day work.
Let 1 man 1 day work =x
and 1 woman 1 days work = y.
=> 6x+5y = 1/6
and 3x+4y = 1/10
On solving, we get x = 1/54 and y = 1/90
(9 men + 15 women)'s 1 days work =
(9/54) + (15/90) = 1/3
9 men and 15 women will finish the work in 3 days
Answer: A
Question: A man can row at 4 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?
A.2.4 km
B.2.9 km
C.3.4 km
D.1.9 km
Answer: D.1.9 km
Explanation: Explanation:
Speed in still water = 4 kmph
Speed of the current = 1 kmph
Speed downstream = (4+1) = 5 kmph
Speed upstream = (4-1) = 3 kmph
Let the required distance be x km
Total time taken = 1 hour
â‡’ x/5+x/3=1
â‡’3x+5x=15
â‡’8x=15
â‡’x=1.9 km
Answer: Option D
Question: A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 64 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d ?
A. 16%
B. 32%
C. 48%
D. 82%
Answer: D. 82%
Explanation: This is easiest to solve with a bell-curve histogram. m here is equal to µ in the Gaussian normal distribution and thus m = 50% of the total population.
So, if 64% is one st.Dev, then on either side of m we have 64/2 = 32%. So, 32% are to the right and left of m (= 50%). In other words, our value m + d = 50 + 32 = 82% goingfrom the mean m, to the right of the distributionin the bell shaped histogram.. This means that 82% of the values are below m + d.
Like I said, doing it on a bell-curve histogram is much easier to fullygethow this works, or you could apply GMAT percentile jargon/theory to it
D
Question: If |x + 10| = 10 what is the sum of all the values of x.
A.20
B.40
C.-20
D.0
Answer: C.-20
Explanation: There will be two cases
x+10 = 10 and x+10 = -10
Solve for x => x=10-10=> x=0 or x= -10 - 10 => x= -20
The sum of both values will be 0 + -20 =-20
Answer is C
Question: How many positive integers Q less than 10,000 are such that the product of their digits is 210?
A.24
B.30
C.48
D.54
Answer: D.54
Explanation: 210 is the answer when 2, 3, 5 and 7 are multiplied. 210 can also be arrive using 5,6 and 7 and 1, 5, 6 and 7.
So sum of arrangements of 2357, 567 and 1567. This translates to 4! +3! + 4!, this equals to 24 + 6 + 24 = 54, D is the answer.
Question: A 50 ml after-shave lotion at 30% alcohol is mixed with 30 ml of pure water. What is the percentage of alcohol in the new solution?
A.16.75%
B.17.75%
C.18.75%
D.19.75%
Answer: C.18.75%
Explanation: The amount of the final mixture is given by
50 ml + 30 ml = 80 ml
The amount of alcohol is equal to the amount of alcohol in pure water ( which is 0) plus the amount of alcohol in the 30% solution. Let x be the percentage of alcohol in the final solution. Hence
0 + 30% 50 ml = x (80)
Solve for x
x = 0.1817 = 18.75%
Answer C
Question: We have 5 people and 3 chairs. In how many ways chairs can be occupy?
A.58
B.42
C.60
D.72
Answer: C.60
Explanation: no. of ways they can be occupy = 5*4*3 = 60
Answer is C
Question: Find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 760.
A.120 ,122 , 124 ,126
B.120 ,122 , 124 ,128
C.120 ,121 , 122 ,123
D.123 ,125 , 127 ,129
Answer: D.123 ,125 , 127 ,129
Explanation: Let x, x + 2, x + 4 and x + 6 be the four integers. The sum of the first two
x + (x + 2)
twice the sum of the last two is written as
2 ((x + 4) + (x + 6)) = 4 x + 20
sum of the first two added to twice the sum of the last two is equal to 760 is written as
x + (x + 2) + 4 x + 20 = 760
Solve for x and find all four numbers
x = 123 , x + 2 = 125 , x + 4 = 127 , x + 6 = 129
Answer D
Question: The value of a machine depreciates at 20% per annum. If its present value is Rs. 1,50,000, at what price should it be sold after two years such that a profit of Rs. 25,000 is made?
A.Rs. 1,10,000
B.Rs. 1,20,000
C.Rs. 1,24,000
D.Rs. 1,21,000
Answer: D.Rs. 1,21,000
Explanation: The value of the machine after two years = 0.8 * 0.8 * 1,50,000 = Rs. 96,000
SP such that a profit of Rs. 25,000 is made = 96,000 + 25,000 = Rs. 1,21,000
ANSWER:D
Question: The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 36. What is the difference between the two digits of that number?
A.3
B.4
C.9
D.11
Answer: B.4
Explanation: Answer: Option B
Let the ten's digit be x and unit's digit be y.
Then, (10x + y) - (10y + x) = 36
9(x - y) = 36
x - y = 4.
Question: A factory has a fixed cost of $44,000 a month, and a cost of $2.5 for every item produced. If the selling price of a single item is $5, what is the number of items must be sold monthly for the factory to cover its cost exactly?
A.9,000
B.14,000
C.17,600
D.22,500
Answer: C.17,600
Explanation: selling price - Cost price = 2.5 so per unit profit =2.5
cost to recover =44000
no of items required = 44000/2.5 = 17600
Answer: C
Question: Distance between two stations A and B is 778 km. A train covers the journey from A to B at 84 km per hour and returns back to A with a uniform speed of 56km per hour. Find the average speed of the train during the whole journey?
A.67.0 km /hr
B.67.2 km /hr
C.69.0 km /hr
D.69.2 km /hr
Answer: B.67.2 km /hr
Explanation: Solution
Required average speed	=(2xy / x+y)km/hr
= 2 x 84 x 56 /(84 + 56)
= (2 x 84 x 85 /140)
= 67.2 km/hr.
Answer B
Question: If the numerator of a fraction be increased by 20% and its denominator be diminished by 10%, the value of the fraction is 20/21. Find the original fraction ?
A.1/2
B.3/5
C.4/7
D.5/7
Answer: D.5/7
Explanation: Let the original fraction be x/y
Then, 120% of x/90% of y = 20/21
120x/90y = 20/21
x/y = 5/7
Answer is D
Question: The average of runs of a cricket player of 10 innings was 42. How many runs must he make in his next innings so as to increase his average of runs by 4?
A.87
B.86
C.28
D.76
Answer: B.86
Explanation: Average after 11 innings = 46
Required number of runs
= (46* 11) - (42* 10) = 506 - 420
= 86.
Answer: B
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either red or green?
A.53/105
B.43/105
C.42/105
D.32/105
Answer: B.43/105
Explanation: given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. Probability that both marbles are red = 4Câ‚‚/Â¹âµCâ‚‚ = (3 * 2)/(15 * 14) = 3/21
Probability that both are green = 6Câ‚‚/Â¹âµCâ‚‚ = (2 * 1)/(15 * 14) = 1/105
Probability that one red and other is green = (4Câ‚ * 6Câ‚)/Â¹âµCâ‚‚ = (2 * 3 * 2)/(15 * 14) = 27/105
Required probability = 3/21 + 1/105 + 27/105
= 43/105
Answer:B
Question: The area of one square is x^2 + 12x + 36 and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 64, what is the value of x?
A.0
B.4.3
C.2.5
D.4.67
Answer: B.4.3
Explanation: spotting the pattern of equations both are in form of (X+C)^2 so
A1= (x+6)^2A2= (2x-3)^2
L1= x+6 L2= 2x-3
P1 = 4( x+6)P2=4(2x-3)
P1+P2=64
4( x+6) +4(2x-3)=64..............> X=4.3
Answer: B
Question: By how much is 70% of 120 greater than 35% of 200.
A.15
B.14
C.13
D.16
Answer: B.14
Explanation: (70/100) * 120 â€“ (35/100) * 200
84 - 70 = 14
Answer: B
Question: Evaluate: |6 - 8(3 - 12)| - |5 - 11| = ?
A.40
B.50
C.72
D.70
Answer: C.72
Explanation: According to order of operations, inner brackets first. Hence
|6 - 8(3 - 12)| - |5 - 11| = |6 - 8*(-9)| - |5 - 11|
According to order of operations, multiplication within absolute value signs (which may be considered as brackets when it comes to order of operations) next. Hence
= |6 + 72| - |5 - 11|
= |78| - |-6|
= 78 - 6 = 72
correct answer C)72
Question: A vendor purchases binder clips at 12 for rs60.How many clips should he sell for rs60 to earn a profit of 20%?
A.5
B.8
C.6
D.10
Answer: D.10
Explanation: Profit of 20% means he should sell the 12 clips for 72 Rs
so for 60 Rs he should sell 10 clips
ANSWER:D
Question: Before being simplified, the instructions for computing income tax in Country R were to add 2 percent of one's annual income to the average (arithmetic mean) of 100 units of Country R's currency and 1 percent of one's annual income. Which of the following represents the simplified formula for computing the income tax, in Country R's currency, for a person in that country whose annual income is X?
A.50X/200
B.50+3X/100
C.50+X/40
D.100+X/50
Answer: C.50+X/40
Explanation: 50+X/40=C
Question: 35 percent of the women in a college class are science majors, and the non-science majors make up 70% of the class. What percentage of the men are non-science majors if 40% of the class are men?
A.37.5
B.27.5
C.77.5
D.87.5
Answer: C.77.5
Explanation: 3.5/k + 2/m = 6/t
Assuming total # is 100 :
[Science - Women] will have -> 0.35 * 60 = 21
[Non-Science-Women] will have -> 39
[Science-Men] will have = 30-21 = 9
[Non-Science-men] will have - 31
S0 31/40 * 100 = 77.5%
Answer -C
Question: Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/5, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?
A.11/8
B.3/80
C.9/64
D.5/64
Answer: B.3/80
Explanation: P(Xavier will solve)=1/5
P(Yvonne will solve)=1/2
P(Zelda will NOT solve) = 1- 5/8 = 3/8.
Now, we need to multiply all this Ps to find an answer:
p= (1/5)*(1/2)*(3/8) = 3/80.
Ans. B.
Question: A and B put in Rs.300 and Rs.400 respectively into a business. A reinvests into the business his share of the first year's profit of Rs.210 where as B does not. In what ratio should they divide the second year's profit?
A.39:40
B.39:48
C.39:43
D.39:46
Answer: A.39:40
Explanation: 3: 4
A = 3/7*210 = 90
390: 400
39:40
Answer: A
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 40, the dividend is:
A.A)5322
B.B)5330
C.C)4040
D.D)5340
Answer: C.C)4040
Explanation: Divisor = (5 * 40) = 200
= 10 * Quotient = Divisor
=> Quotient = 200/10 = 20
Dividend = (Divisor * Quotient) + Remainder
Dividend = (200 * 20) + 40 = 4040.
C
Question: A train running at the speed of 60 km/hr crosses a pole in 12 sec. What is the length of the train?
A.120 m
B.200 m
C.324 m
D.Cannot be determined
Answer: B.200 m
Explanation: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 12 = 200 m
ANSWER:B
Question: X and Y started a business with capitals Rs. 20000 and Rs. 25000. After few months Z joined them with a capital of Rs. 30000. If the share of Z in the annual profit of Rs. 50000 is Rs. 14000, then after how many months from the beginning did Z join?
A.1
B.5
C.6
D.8
Answer: B.5
Explanation: Investments of X, Y and Z respectively are Rs. 20000, Rs. 25000 and Rs. 30000
Let investment period of Z be x months.
Ratio of annual investments of X, Y and Z is (20000 * 12) : (25000 * 12) : (30000 * x)
= 240 : 300 : 30x = 8 : 10 : x
The share of Z in the annual profit of Rs. 50000 is Rs. 14000.
=> [x/ (18 + x)] 50000 = 14000 => [x/ (18 + x)] 25 = 7
=> 25x = 7x + (18 * 7) => x = 7 months.
Z joined the business after (12 - 7) months. i.e., 5 months.Answer: B
Question: Which one of the following is not a prime number?
A.88
B.60
C.73
D.91
Answer: D.91
Explanation: D
91
91 is divisible by 7. So, it is not a prime number.
Question: The average of non-zero number and its square is 5 times the number. The number is?
A.9
B.8
C.6
D.4
Answer: A.9
Explanation: Let the number be x. Then,
(x + x2)/2 = 5x => x2 - 9x = 0
=> x(x - 9) = 0
=> x = 0 or x = 9
So, the number is 9.
Answer:A
Question: Out of 7 constants and 4 vowels how many words of 3 consonants and 2 vowels can be formed?
A.210
B.25000
C.25200
D.250
Answer: C.25200
Explanation: Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)
= 7C3 * 4C2
= 210
Number of groups each having 3 consonants and 2 vowels = 210
Each group contains 5 letters
Number of ways of arranging 5 letters among themselves
= 5! = (5 * 4 * 3 * 2 * 1)
= 210
Required number of words = (210 * 210)
= 25200
ANSWER C 25200
Question: Pradeep has to obtain 40% of the total marks to pass. He got 200 marks and failed by 20 marks. The maximum marks are
A.300
B.600
C.550
D.1000
Answer: C.550
Explanation: Explanation :
Let their maximum marks be x.
Then, 40% of x = 200 + 20
=>40/100x= 220
x = (22000/40)
x= 550.
Answer : C
Question: A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long?
A.87 sec
B.89 sec
C.17 sec
D.18 sec
Answer: B.89 sec
Explanation: Speed = 240/24
= 10 m/sec.
Required time
= (240 + 650)/10
= 89 sec.
Answer:B
Question: Consider a right triangle YBC with length of sides being x,y and z where y represents the hypotenuse , Which of these represent the radius of the circle which is inscribed in triangle YBC
A.[A] x+y+z/3
B.[B] x-y+z/3
C.[C] x-y+z/2
D.[D] (x^2 + y^2 + z^2)/3
Answer: C.[C] x-y+z/2
Explanation: Radius of a circle inscribed in the right triangle YBC r = (x + z - y)/2 where y is the hypotenuse and x and y are other two sides.
Answer: C
Question: Ram and Shyam have a cube each. Ram paints four faces of cube with red color and rest with blue color. Ram asks Shyam to paint his cube as well with some sides red and some side blue. They now start rolling the cubes simultaneously. After doing this for very long Ram observes that probability of both cubes coming up with same color is 1/3. How many faces of his cube did Shyam paint red ?
A.0
B.2
C.3
D.4
Answer: A.0
Explanation: Explanation :
Let Shyam paints n faces of the cube red. So faces painted blue = (6-n)
Probability that both show up same color is: (probability both show red) + (probability both show blue)
= 4/6 * n/6 + 2/6 * (6-n)/6
= (2n + 6)/18
But as given, (2n + 6)/18 = 1/3 => n = 0
So Shyam hasn't painted any of the face with red color.
Answer : A
Question: A person goes to his office at 1/3rd of the speed at which he returns from his office. If the avg speed during the whole trip is 12m/h. what is the speedof the person while he was going to his office?
A.8km/h
B.9km/h
C.10km/h
D.11km/h
Answer: A.8km/h
Explanation: u = k , v= 3k
\inline \therefore \frac{2uv}{u+v}\: \: \Rightarrow \frac{2\times k\times 3k}{(k+3k)}=12
\inline \Rightarrow 1.5k = 12
\inline \Rightarrow k=8km/h
A
Question: An unbiased die is tossed.Find the probability of getting a multiple of 3.
A.1/3
B.1/9
C.1/2
D.7/3
Answer: A.1/3
Explanation: Explanation:
Here S = {1,2,3,4,5,6}
Let E be the event of getting the multiple of 3
Then, E = {3,6}
P(E) = n(E)/n(S) = 2/6 = 1/3
Answer: A) 1/3
Question: 1234+123+12+X=1221.Find the value of X.
A.10
B.148
C.12
D.13
Answer: B.148
Explanation: x=1234+123+12-1221
x=148
CORRECT ANSWER : B
Question: One of the below words are odd one out. can you identify it?
first second third forth fifth sixth seventh eighth nine ten eleven twelve thirteen fourteen fifteen sixteen
A.forth. It should be spelled as fourth
B.4
C.14
D.15
Answer: A.forth. It should be spelled as fourth
Explanation: Correct Answer : A
forth. It should be spelled as fourth
Question: Together, 15 type A machines and 7 type B machines can complete a certain job in 4 hours. Together 8 type B machines and 15 type C machines can complete the same job in 11 hours. How many hours T would it take one type A machine, one type B machine, and one type C machine working together to complete the job (assuming constant rates for each machine)?
A. 22 hours
B. 30 hours
C. 44 hours
D. 60 hours
Answer: C. 44 hours
Explanation: Say the rates of machines A, B and C are a, b, and c, respectively.
Together 15 type A machines and 7 type B machines can complete a certain job in 4 hours --> 15a + 7b = 1/4;
Together 8 type B machines and 15 type C machines can complete the same job in 11 hours --> 8b + 15c = 1/11.
Sum the above: 15a + 15b + 15c = 1/4 + 1/11 = 15/44 --> reduce by 15: a + b + c = 1/44 --> so, the combined rate of the three machines is 1/44 job/hour --> time is reciprocal of the rate, thus machines A, B and C can do the T job in 44 hours.
Answer: C.
Question: The area of a square is equal to five times the area of a rectangle of dimensions 125 cm * 64 cm. What is the perimeter of the square?
A.287
B.800
C.277
D.299
Answer: B.800
Explanation: Area of the square = s * s = 5(125 * 64)
=> s = 25 * 8 = 200 cm
Perimeter of the square = 4 * 200
= 800 cm.
Answer:B
Question: Three cars driven by Mike, Scott and Jenny start driving around a circular race course of length 540m from the same point simultaneously in the same direction at speeds of 9 m/s, 15 m/s and 27 m/s respectively. When will they meet for the first time after they started moving?
A.180 seconds
B.45 seconds
C.90 seconds
D.60 seconds
Answer: C.90 seconds
Explanation: If they all meet after T seconds, it means they covered the distances 9T, 15T, and 27T respectively.
Since they all arrive to the same spot, it means that the differences taken pairwise between the distances must be positive integer multiples of the length of the track, which is 540m. So, 6T, 12T, and 18T must all be multiples of 540. 6T multiple of 540 means T multiple of 90. The smallest T with this property is 90 and is on the list of answers.
Answer C.
Question: If the volume of the cube is 729, then the surface area of the cube will be
A.486
B.255
C.2866
D.265
Answer: A.486
Explanation: Explanation:
\inline \fn_jvn a^3=729; a=9
surface area= (6 x 9 x 9) = 486\inline \fn_jvn cm^2
Answer: A) 486 sq.cm
Question: Ravi can do a piece of work in 24 days while Prakash can do it in 40 days. In how many days will they finish it together?
A.15
B.16
C.17
D.18
Answer: A.15
Explanation: 1/24 + 1/40 = 1/15
15 days
Answer: A
Question: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 2.5 kmph, find his average speed for the total journey ?
A.3.1 kmph
B.5 kmph
C.6 kmph
D.4 kmph
Answer: A.3.1 kmph
Explanation: Explanation:
Speed of Man = 4.5 kmph
Speed of stream = 2.5 kmph
Speed in DownStream = 7 kmph
Speed in UpStream = 2 kmph
Average Speed = (2 x 7 x 2)/9 = 3.1 kmph.
Answer: A
Question: A driver covers a certain distance by car driving at 40 km/hr and returns back to the starting point riding on a scooter at 10 km/hr. What was the average speed for the whole journey?
A.12 km/h
B.14 km/h
C.16 km/h
D.18 km/h
Answer: C.16 km/h
Explanation: time 1 = d / 40
time 2 = d / 10
total time = d/40 + d/10 = d/8
average speed = total distance / total time = 2d / (d/8) = 16 km/h
The answer is C.
Question: At a certain restaurant, the ratio of the number of cooks to the number of waiters is 3 to 11. When 12 more waiters are hired, the ratio of the number of cooks to the number of waiters changes to 1 to 5. How many cooks does the restaurant have?
A.4
B.6
C.9
D.12
Answer: C.9
Explanation: Originally there were 3k cooks and 11k waiters.
The new ratio is 1:5 which equals 3:15.
15k = 11k+12
k=3
There are 9 cooks.
The answer is C.
Question: A sum of money place at compound interest doubles itself in 4 years. In how many years will it amount to eight times itself?
A.33
B.77
C.12
D.88
Answer: C.12
Explanation: 100 ---- 200 ---- 4
400 ---- 4
800 ---- 4
------
12 years
Answer: C
Question: How long does a train 150 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
A.14.1 sec
B.12.1 sec
C.16.1 sec
D.13.1 sec
Answer: A.14.1 sec
Explanation: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 150 + 132 = 282 m.
Required time = 282/20 = 14.1 sec.
Answer:A
Question: How many days are there in x weeks x days ?
A.7x2
B.8x
C.14x
D.7
Answer: B.8x
Explanation: Solution
x weeks x days = (7x+x) days = 8x days. Answer B
Question: In year Y imported machine tools accounted for 25 percent of total machine - tool sales in the United States, and Japanese imports accounted for 50 percent of the sales of imported machine tools. If the total sales of machine tools imported Japan that year was x billion dollars, then the total sales of all machine tools in the United States was how many billion dollars?
A.8X/1
B.13X/20
C.80/9X
D.20X/13
Answer: A.8X/1
Explanation: IMT = 0.25T
JI = 0.50 IMT
0.50 IMT = $x b
IMT = $x/(0.50) b
T = 4*IMT = 4x/0.50 = 4x*100/50 = 8x/1
Ans: "A"
Question: The average height of 50 pupils in a class is 150 cm. Five of them whose height is 142 cm, leave the class and five others whose average height is 156 cm, join. The new average height of the pupils of the class (in cm) is ?
A.287 cm
B.151 cm
C.151.4 cm
D.287 cm
Answer: C.151.4 cm
Explanation: Total height = 150 * 50 = 7500 cm.
New average = [7500 - 5 * 142 + 5 * 156 ] / 50
= 151.4 cm.
Answer:C
Question: Juan is a gold medalist in athletics. In the month of May, if Juan takes 10 seconds to run y yards, how many seconds will it take him to run x yards at the same rate?
A.10x/y
B.11x/y
C.9x/y
D.12x/y
Answer: A.10x/y
Explanation: velocity=distance/time;
since he ran at same rate both d tyms,
y/10=x/t
so t=10x/y
ANSWER:A