RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: S is a set containing 8 different positive odd primes. T is a set containing 8 different numbers, all of which are members of S. Which of the following statements CANNOT be true?
A. The median of S is prime.
B. The median of T is prime
C. The median of S is equal to the median of T.
D. The sum of the terms in S is prime.
Answer: C. The median of S is equal to the median of T.
Explanation: Here is my explanation. The question states:S is a set containing 9 different positive odd primes. T is a set containing 8 different numbers, all of which are members of S. Which of the following statements CANNOT be true?
(A) The median of S is prime.
Thismust be true. If there are an odd number of members of a set, then the median is a member of the set: it's the middle number, when all the numbers are ranked from smallest to biggest. Every number in S is a positive odd prime, so the median is one of them, and is prime.
(B) The median of T is prime.
Thismay or may not be true. If a set has an even number of members, the median is average of the two numbers in the middle, when ranked from smallest to biggest. The average of two odd numberscould beeven (average of 71 and 73 is 72), and hence not prime, or itcould beodd (the average of 71 and 79 is 75). For particularly well chosen odd numbers, the average can be not only odd but also prime -- for example, the average of 89 and 113 is 101, another prime number. If the two middle numbers of T were 89 and 113, the median would be 101, a prime number.
(C) The median of S is equal to the median of T.
Under most configurations for S and T, this wouldn't happen. If you weren't trying to make it happen, it would be unlikely to happen by chance. BUT, if the number dropped going from from S to T was the median of S (say, 101), and if the two middle numbers of T happen to have an average of that number that was dropped (for example, if the two numbers were 89 and 113), then the medians would be equal. In other words, the three middle numbers of S would have to be {. . ., 89, 101, 133, . . .}, and when 101 is dropped in going to T, the median of two would be the average of 89113, which happens to be 101. It's an exceptional case, but itcouldbe true.
(D) The sum of the terms in S is prime.
Thismay or may not be true. The sum of 9 odd numbermustbe an odd number. That odd numbercould beprime. For example, the sum of the first nine odd prime numbers {3, 5, 11, 13, 17, 19, 23, 29} is 127, which is prime. If you drop 3 and include the next prime, 31, the set {5, 11, 13, 17, 19, 23, 29, 31} has a sum of 155, which is clearly not prime.
(E) The sum of the terms in T is prime.
Thismust be false. The sum of eight odd numbers must be an even number. Only 2 is prime, and all other even numbers are not. Therefore, the sum of eight odd prime numbers will be an even number bigger than two, and absolutely cannot be prime.
C
Question: Triathlete Dan runs along a 3-mile stretch of river and then swims back along the same route. If Dan runs at a rate of 10 miles per hour and swims at a rate of 6 miles per hour, what is his average rate for the entire trip in miles per minute?
A.1/8
B.2/15
C.3/15
D.1/4
Answer: A.1/8
Explanation: Dan travels 6 miles round trip.
Running part: (3/10*60 = 18 minutes)
Swimming Part: (3/6 *60 = 30 minutes)
6 miles in (18+30) minutes
6/48 = 1/8 mile per minute
Answer: 1/8 mile per minute
A
Question: A woodworker normally makes a certain number of parts in 24 days. But he was able to increase his productivity by 5 parts per day, and so he not only finished the job in only 22 days but also he made 80 extra parts. How many parts does the woodworker normally makes per day and how many pieces does he make in 24 days?
A.360
B.480
C.754
D.687
Answer: A.360
Explanation: Let x be the number of parts the woodworker normally makes daily. In 24 days he makes 24⋅x pieces. His new daily production rate is x+5 pieces and in 22 days he made 22⋅(x+5) parts. This is 80 more than 24⋅x. Therefore the equation is:
24⋅x+80=22(x+5)
30=2x3
x=15
Normally he makes 15 parts a day and in 24 days he makes 15⋅24=360 parts.
correct answer is A)360
Question: If you have 8 New Year greeting cards and you want to send them to 3 of your friends, in how many ways can this be done?
A.336
B.720
C.340
D.670
Answer: A.336
Explanation: Solution
We have to find number of permutations of 3 objects out of 8 objects. This number is 8P3=8(8-1)(8-2)=8*7*6=336
Answer A
Question: 6x − 12 = 6y
4y + 4x = 12
Which of the following is the number of solutions to the system of equations shown above?
A.More than three
B.Exactly one
C.Exactly two
D.Exactly three
Answer: B.Exactly one
Explanation: 6x − 12 = 6y
=> 6x - 6y = 12
=> x- y =2 -- 1
4y + 4x = 12
=>x + y = 3 -- 2
From equation 1 and 2 , we get
2x = 5
=> x=2.5
y=.5
Therefore , the given system will have Exactly one solution
Answer : B
Question: 115 liters of a mixture of milk and water contains in the ratio 3:2. How much water should now be added so that the ratio of milk and water becomes 3:4?
A.12 liters
B.32 liters
C.46 liters
D.50 liters
Answer: C.46 liters
Explanation: Milk = 3/5 * 115 = 69 liters
Water = 46 liters
69 : (46+P) = 3:4
138 + 3P = 276 => P = 46
46 liters of water are to be added for the ratio become 3:4.
Answer:C
Question: Let the number which when multiplied by 12 is increased by 198.
A.18
B.20
C.26
D.28
Answer: A.18
Explanation: Solution
Let the number be x .
Then, 12x - x = 198
‹=›11x = 198
x ‹=› 18.
Answer A
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
A.332
B.268
C.245
D.276
Answer: C.245
Explanation: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.
Answer: C
Question: How many seconds will a train 100 meters long take to cross a bridge 250 meters long if the speed of the train is 36 kmph?
A.54 sec
B.35 sec
C.25 sec
D.45 sec
Answer: B.35 sec
Explanation: D = 100 + 250 = 350
S = 36 * 5/18 = 10 mps
T = 350/10 = 35 sec
Answer:B
Question: Rs.8000 become Rs.9261 in a certain interval of time at the rate of 5% per annum of C.I. Find the time?
A.4 years
B.6 years
C.2 years
D.3 years
Answer: D.3 years
Explanation: Explanation:
9261 = 8000(21/20)N
(21/20)3 = (21/20)N => N = 3
Answer IS D
Question: In a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:
A.750 cu.m
B.75 cu.m
C.4500 cu.m
D.500 cu.m
Answer: A.750 cu.m
Explanation: hectare = 10,000 m^2
so area = (1.5 * 10000) m^2 = 15000 m^2
depth = 5/100m = 1/20m
volume = (area*depth) = 15000 * 1/20 = 750 m^3
ANSWER A
Question: Find the area of a parallelogram with base 30 cm and height 12 cm?
A.290 cm2
B.360 cm2
C.270 cm2
D.280 cm2
Answer: B.360 cm2
Explanation: Area of a parallelogram = base * height = 30 * 12
= 360 cm2
Answer:B
Question: a, b, c, d, and e are five consecutive numbers in increasing order of size. Deleting one of the five
numbers from the set decreased the sum of the remaining numbers in the set by 20%. Which one of
the following numbers S was deleted?
A. a
B. b
C. c
D. d
Answer: C. c
Explanation: a+b+c+d+e => 1+2+3+4+5=15
S=20%*15= 3 =>C
Question: Tough and Tricky questions: Number Properties.
What is the smallest positive integer x such that 324x is the cube of a positive integer?
A.9
B.12
C.18
D.24
Answer: C.18
Explanation: We want to know the smallest x that will make 324x a CUBE of some number. Let's call that number y.
Let's first figure out what we're working with. The prime factorization of 324 can be visualized:
...........324
......../.......\
......81.......4
...../..\....../...\
...27...3...2.....2
.../..\
..9....3
/\
.3 3
So, we have 3 * 3 * 3 * 3 * 2 * 2 that can be multiplied together to get 324. Now we need to figure out what we need to make 324 * x into a cube of y (y^3=324*x).
We have four 3s, and two 2s. To arrange these numbers in identical triples (2,3,3), we need at least one more 2 and two 3's. Each of these triples will give us the value of y (2*3*3=18), which, multiplied by itself three times, gives us 324 * x.
Looking at the factors we need to complete the triples, we get 3 * 3 * 2 = 18. We know this is the smallest number possible because prime factors by definition cannot be broken down any further.
Therefore, we can go with answer choice C.
If time permits, we can do a sanity check. We calculated that y should be 2 * 3 * 3, or 18. 18 * 18 * 18 = 5832. Also, 324 * 18 = 5832.
Answer: C
Question: Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 26 white marbles. How many red marbles could be in bag A?
A.1
B.3
C.4
D.2
Answer: D.2
Explanation: # of Red marbles in Bag A can be either 2 or 6. No 2 in the choices, so 6. D.
Bag A:
R:W:B = 2:6:9
Bag B
R:W = 1:4
6X + 4Y = 26 i.e 3X + 2Y = 13
X has to be odd to make an odd sum from the eq.
X = 1 , Y = 5 OR X = 3, Y = 2
So R can be 2X i.e 2 or 6.
Answer D
Question: The price of an article has been reduced by 25%. In order to restore the original price the new price must be increased by?
A.33 1/3 %
B.9 1/11 %
C.11 1/9 %
D.66 2/3 %
Answer: A.33 1/3 %
Explanation: 100
75
-------
75 ------- 25
100 ------ ? => 33 1/3%
ANSWER:A
Question: A man sells a horse for Rs.20 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?
A.227
B.340
C.277
D.860
Answer: B.340
Explanation: CP = SP + 1CP = SP - g
20 + x = 980 - 2x
3x = 960=> x = 320
CP = 320 + 20 = 340
Answer: B
Question: If x and y are prime numbers, which of the following CAN be the sum of x and y?
A.5
B.8
C.12
D.15
Answer: A.5
Explanation: Answer: A
Question: Aish started a business investing Rs. 25,000 in 2010, In 2011, he invested an additional amount of Rs. 10,000 and Roshan joined him with an amount of Rs. 35,000. In 2012, Aish invested another additional amount of Rs. 10,000 and Atul joined them with an amount of Rs. 35,000. What will be Roshan’s share in the profit of Rs. 2,10,000 earned at the end of 3 years from the start of the business in 2010?
A.Rs.45000
B.Rs.50000
C.Rs.60000
D.Rs.70000
Answer: D.Rs.70000
Explanation: Explanation :
Aish : Roshan : Atul
= (25000 x 12 + 35000 x 12 + 45000 x 12) : (35000 x 24) : (35000 x 12)
= 1260000 : 840000 : 420000 = 3 : 2 : 1
Roshan's share = Rs. 210000 x 2/6
= Rs. 70000.
Answer : D
Question: Eesha bought 18 sharpeners for Rs.100. She paid 1 rupee more for each white sharpener than for each brown sharpener. What is the price of a white sharpener and how many white sharpener did she buy ?
A.Rs.6, 19
B.Rs.6, 10
C.Rs.6, 16
D.Rs.6, 11
Answer: B.Rs.6, 10
Explanation: Explanation: Just check the options. If she bought 10 white sharpeners at Rs.6 per piece, She has spent Rs.60 already. And with the remaining Rs.40, she bought 8 brown sharpeners at 40/8 = Rs.5 which is Rs.1 less than White sharpener.
Sol: B
Question: Ann invested a certain sum of money in a bank that paid simple interest. The amount grew to $240 at the end of 2 years. She waited for another 3 years and got a final amount of $300. What was the principal amount that she invested at the beginning?
A.$200
B.$150
C.$210
D.$175
Answer: A.$200
Explanation: Answer
The sum grew to $240 at the end of 2 years.
At the end of another 3 years, the sum grew to $ 300.
i.e. in 3 years, the sum grew by $ 60.
Therefore, each year, it grew by $ 20.
Sum at the end of 2 years = $ 240
Sum grew by $ 20 each year.
Hence, in the first 2 years, sum grew by 2 * 20 = $ 40.
Therefore, sum at the beginning of the period = Sum at the end of 2 years - $40 = $ 240 - $ 40 = $ 200.
choice is (A)
Question: Tom drives from town A to town B, driving at a constant speed of 60 miles per hour. From town B Tom immediately continues to town C. The distance between A and B is twice the distance between B and C. If the average speed of the whole journey was 36 mph, then what is Tom's speed driving from B to C in miles per hour?
A.12
B.20
C.24
D.30
Answer: B.20
Explanation: Let's assume that it takes 4 hours to go from point A to B.
Then the distance between them becomes 240 which makes distance between B and C 120.
(240+120)/(4+x) gives us the average speed which is 36.
You find x=6. So the question simplifies itself to 120/6=20
Hence the answer is B
Question: 66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be:
A.84
B.90
C.94
D.95
Answer: A.84
Explanation: Let the length of the wire be h.
RADIUM = 1/2 mm = 1/20 cm then
22/7*1/20*1/20*h = 66
h=(66*20*20*7/22) = 8400 cm = 84m
ANSWER A
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
A.776
B.283
C.245
D.266
Answer: C.245
Explanation: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.
Answer: C
Question: Two trains of length 150 m and 250 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 18 kmph and 36 kmph. In how much time will the trains cross each other?
A.87/7 sec
B.80/7 sec
C.100/3 sec
D.80/5 sec
Answer: C.100/3 sec
Explanation: Relative speed = (18 + 36)* 5/18 = 3 * 5 = 15 mps.
The time required = d/s = (100 + 150 + 250)/15
= 500/15 = 100/3 sec.
Answer: C
Question: When 35 per cent of a number is added to another number,the second number increases by its 20 per cent. What is the ratio between the second number and the first number?
A.4 : 7
B.7 : 4
C.8 : 5
D.Data inadequate
Answer: B.7 : 4
Explanation: 35% of x + y = 120⁄100y
or 35x+100y/100=120y/100⇒35x=20y
y⁄x = 35⁄20 = 7 : 4
Answer B
Question: It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
A.(216 + 1)
B.(216 - 1)
C.(7 x 223)
D.(296 + 1)
Answer: D.(296 + 1)
Explanation: Explanation:
Let 232 = x. Then, (232 + 1) = (x + 1).
Let (x + 1) be completely divisible by the natural number N. Then,
(296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
ANSWER IS D
Question: How many pairs of letters are there in the word 'CASTRAPHONE' which have as many letters between them in the word as in the alphabet?
A.Four
B.One
C.Three
D.Seven
Answer: A.Four
Explanation: Looking into the alphabets there are four such pairs namely ON,EH,ST,TO.
ANSWER A
Question: For arranging a picnic, each student contributed an amount equal to the number of students while the teacher contributed an amount equal to twice the number of students. However, if each student would have contributed an amount equal to twice the number of students and the teacher would have contributed an amount equal to the number of students, they would have generated Rs. 1056 more. Find the number of students in the group?
A.54
B.56
C.33
D.18
Answer: D.18
Explanation: Explanation:
Let the number of students = x. Thus, we get,
[(2x2 + x) – (x2 + 2x)] = 1056
x2 - x - 1056 = 0
Solving the equation, we get, x = 33 or x = - 32.
Since the number of students are to be positive, number of students = x = 33
ANSWER: D
Question: A room is 5 meters 76 centimeters in length and 4 meters 32 centimeters in Width. Find the least number of square tiles of equal size required to cover the entire floor of the room.
A.12
B.15
C.17
D.137
Answer: B.15
Explanation: Let us calculate both the length and width of the room in centimeters.
Length = 5 meters and 76 centimeters = 576 cm
width = 4 meters and 32 centimeters = 432 cm
As we want the least number of square tiles required, it means the length of each square tile should be as large as possible.Further,the length of each square tile should be a factor of both the length and width of the room.
Hence, the length of each square tile will be equal to the HCF of the length and width of the room = HCF of 576 and 432 = 144
Thus, the number of square tiles required = (576 x 432 ) / (144 x 144) = 4 x 3 = 12
Answer: B
Question: A can complete a work in 15 days and B can do the same work in 9days. If A after doing 5days, leaves the work, find in how many days B will do the remaining work?
A.2days
B.4days
C.6days
D.7days
Answer: C.6days
Explanation: The required answer = (15-5)*9 / 15 = 40/10 = 6days
Answer is C
Question: A Cuban cigar would cost 1 dollar less than 1.5 times a French cigar, had the French cigar cost 0.7 dollar less than it does now. An Arabian cigar costs 50 cents more than 1.5 times the Cuban cigar. The three cigars together cost 74.7 dollars. What is the price of the French cigar?
A.16.7$.
B.23$.
C.25.5$.
D.35$.
Answer: A.16.7$.
Explanation: The three cigars together cost 74.7 dollars. If each cost the same , they would have cost a little less than 25 dollars each.
From the given data we know French cigar < Cuban cigar < Arabic cigar
and each is more expensive 1.5 times. Therefore eliminate options C,D,E straightaway . Since French cigar is at least 1.5 times cheaper we know B cannot be the answer.
Therefore A is the answer
Question: (X)+1789+9011-7819=90510. Calculate the value of X
A.87501
B.87599
C.87529
D.87520
Answer: C.87529
Explanation: x+1789+9011-7819=90510
=x+1789+9011=90510+7819
=x+10800=98329
=x=98329-10800
=87529
Answer is C
Question: If r is an even integer and q is an odd integer, which of the following must be an odd integer?
A.r/q
B.rq
C.2r+q
D.2(r+q)
Answer: C.2r+q
Explanation: this is a must question:
A. r/q
can be a non-integer
B.rq
always even
C. 2r+q
2r = even -> even+odd = odd
D. 2(r+q)
always even - r+q = odd *2 -> even
E. 3r/q
might be a non integer.
C
Question: A business executive and his client are charging their dinner tab on the executive's expense account.The company will only allow them to spend a total of 50$ for the meal.Assuming that they will pay 10% in sales tax for the meal and leave a 15% tip,what is the most their food can cost?
A.39.52$
B.40.63$
C.41.63$
D.42.15$
Answer: A.39.52$
Explanation: let x is the cost of the food
1.07x is the gross bill after including sales tax
1.15* 1.10x=50
x=39.52
Hence, the correct option is A
Question: Meg and Bob are among the 5 participants in a cycling race. If each participant finishes the race and no two participants finish at the same time, in how many different possible orders can the participants finish the race so that Meg finishes ahead of Bob?
A.24
B.30
C.60
D.90
Answer: C.60
Explanation: Let me redeem myself:
JXXXX => Bob can be in any X...Total 4! = 24
XJXXX => Bob can be in the last 3 Xs...Total 3! = 6. However, since the first person can change too and it cannot be Bob, it can only be 3 other people. So Total = 6*3 = 18
XXJBX => 3! = 6 total
XXJXB => 3! = 6 total
So this yields total of 12
XXXJB => 3! = 6
Ans = 24+18+12+6 = 60
answer is C
Question: In a cricket team, the average of eleven players is 28 years. Out of these, the average ages of three groups of three players each are 31 years, 28 years and 30 years respectively. If in these groups, the captain and the youngest player are not included, and the captain is eleven years older than the youngest player, what is the age of the captain ?
A.33 years
B.34 years
C.35 years
D.26 years
Answer: D.26 years
Explanation: Explanation :
Let the age of youngest player be x.
Then, age of the captain = (x + 11).
=> 3*31 + 3*28 + 3*30 + x + x + 11 = 11*28.
=> 93+84+90+2x+11=308
so 2x = 30
so x = 15.
Age of the captain = (x+11)
= 26 years.
Answer : D
Question: At what rate percent on simple interest will Rs.750 amount to Rs.1050 in 5 years?
A.8
B.3
C.4
D.5
Answer: A.8
Explanation: 300 = (750*5*R)/100
R = 8%.Answer: A
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 50 years now, the son's age five years back was:
A.15 years.
B.20 years.
C.25 years.
D.30 years.
Answer: B.20 years.
Explanation: Let the son's present age be x years. Then, (50 - x) = x
2x = 50.
x = 25.
Son's age 5 years back (25 - 5) = 20 years.
Answer: Option B
Question: There are 5 sweets – Jumun, Kulfi, Peda, Laddu and Jilabi that I wish to eat on 5 consecutive days – Monday through Friday, one sweet a day, based on the following self imposed constraints:
1) Laddu is not eaten on Monday
2) If Jamun is eaten on Monday, then Laddu must be eaten on Friday
3) If Laddu is eaten on Tuesday, Kulfi should be eaten on Monday
4) Peda is eaten the day following the day of eating Jilabi
Based on the above, peda can be eaten on any day except?
A.Tuesday
B.Monday
C.Wednesday
D.Friday
Answer: B.Monday
Explanation: Peda is eaten the day following the day of eating Jilabi, So Peda can never be had on the starting day, which is Monday.
ANSWER:B
Question: Mary jogs 9 km at a speed of 6kmph. at what speed would she need to jog during the next 1.5 hour to have an average of 9 km per hr at the entire jogging session?
A.12kmph
B.7kmph
C.87kmph
D.74kmph
Answer: A.12kmph
Explanation: let speed of the jogging be x kmph
total time taken=(9/6+1.5)=3 hrs
total distance covered=(9+1.5x)
9+1.5 x/3=9
9+1.5 x=27
3/2x=18
x=18*2/3=12 kmph
Answer(A)
Question: The average (arithmetic mean) of y numbers is x. If 15 is added to the set of numbers, then the average will be x - 5. What is the value of y in terms of x ?
A.x/6 - 6
B.x/6 - 5
C.x/7 - 5
D.x/5 - 4
Answer: D.x/5 - 4
Explanation: (A1 + A2 + .. + Ay)/y = x
(A1 + A2 + .. + Ay + 15)/(y+1) = x - 5
=> (xy + 15)/(y+1) = x - 5
=> xy + 15 = yx -5y + x - 5
=> 20 = x - 5y
=> 5y = x - 20
=> y = x/5 - 4
Answer - D
Question: A sequence of numbers is such that a1 = 11, a2 =16, and each subsequent an = an-2 + 9. Which of the following numbers is a member of the sequence?
A.216
B.246
C.289
D.299
Answer: D.299
Explanation: each odd term(1st , 3rd, 5th,...) of the sequence is given by 11 + 9*(something)
each even term(2nd, 4th, 6th...) of the sequence is given by 16 + 9*(something)
So if you subtract the numbers by 11 or 16 then it should be divisible by 9
216-11(=205) or 216-16(=200) are not divisible by 9
246-11(=235) or 246-16(= 240) are not divisible by 9
289-11(=278) or 289-16(=273) are not divisible by 9
299-11(=288) is divisible by 9ANSWER, 299-16(=283) are not divisible by 9
368-11(=357) or 368-16(=352) are not divisible by 9
So, Answer is D
Question: Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000?
A.81000
B.81027
C.81089
D.81027
Answer: A.81000
Explanation: 64000* 9/8 * 9/8
= 81000
Answer: A
Question: A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
A.11
B.16
C.188
D.199
Answer: B.16
Explanation: Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 280 * 2/35 = 16 sec
Answer: B
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
A.28
B.50
C.99
D.121
Answer: B.50
Explanation: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 => x = 50 km/hr.
Answer: B
Question: B @ K I 9 D Â© 5 2 T $ M 4 E J # U R 1 A Î´ K 5 W 6 % F Q 7 H P 8 Z How many such consonants are there in the above arrangement, each of which is immediately preceded by number and immediately followed by a symbol?
A.None
B.One
C.Two
D.Three
Answer: C.Two
Explanation: Explanation:
Number Consonant Symbol
Such combinations are:
9 D Â© : 2 T $
ANSWER IS C
Question: A bat is bought for Rs.400 and sold at a gain of 25% find its selling price?
A.s.460/-
B.s.480/-
C.s.500/-
D.s.520/-
Answer: C.s.500/-
Explanation: 100 % ------> 400 (100 * 4 = 400)
120 % ------> 500 (125 * 4 = 500)
Selling price = Rs.500/-
Option 'C'
Question: The average age of father and his two sons is 27 Years. Five years ago, the average age of the two sons was 12 Years. If the difference between the ages of the two sons is four years, what is the present age of the father?
A.45
B.46
C.47
D.48
Answer: C.47
Explanation: The total present age of father and two sons is 3S27 = 81 yrs
The total present age of sons is (12+5) X 2 = 34Years
so, present age of father is 81 – 34 = 47 yrs
Answer C