RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: 25 people went to a hotel for combine dinner party 15 of them spent Rs. 5 each on their dinner and rest spent 4 more than the average expenditure of all the 25. What was the total money spent by them.
A.1628.4
B.1534
C.1492
D.158.25
Answer: D.158.25
Explanation: Solution: Let average expenditure of 25 people be x.
then,
25x = 15*5+10*(x+4);
Or, 25x = 15*5+10x+20;
Or, x = 6.33;
So, total money spent = 6.33*25 = Rs. 158.25.
Answer: Option D
Question: In how many ways can the letters of the word CODD be arranged?
A.15
B.16
C.12
D.13
Answer: C.12
Explanation: CODD has 4 words, but d is repeated two times. Thus ways = 4! / 2! = 12 ways
C
Question: {1/(5-√24)}^2 =
A.a. 16+16√15
B.b. 31- 10√15
C.c. 49 - 10√24
D.d. 32- 4√15
Answer: C.c. 49 - 10√24
Explanation: 1 / (25 - 10 root24 + 24)
= 1 / (49 - 10 root24)
Multiply numeratordenominator by (49 + 10 root24)
= (49 - 10root24)
Answer = C
Question: A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
A.90 m
B.100 m
C.120 m
D.140 m
Answer: C.120 m
Explanation: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 6 = 120 m.
ANSWER:C
Question: A pump can fill a tank with water in 8 hours. Because of a leak, it took 9 hours to fill the tank. The leak can drain all the water in ?
A.15hr 10min
B.16hr 20min
C.17hr 30min
D.72hr
Answer: D.72hr
Explanation: Work done by the leak in 1 hour = 1/8 - 1/9 = 1/72
Leak will empty the tank in 72 hrs =
Answer is D
Question: Of the integers between 200 and 799, inclusive, how many do not have digit 2 and 5?
A. 316
B. 256
C. 410
D. 426
Answer: B. 256
Explanation: Options for the first digit 6-2(2 and 5)=4;
Options for the second digit 10-2=8;
Options for the third digit 10-2=8;
Total numbers possible 4*8*8=256.
Answer: B.
Question: Find the ones digit of 73^355
A.3
B.5
C.6
D.7
Answer: D.7
Explanation: The units digit of 73^355 will be the same as the units digit of 3^355.
3^1=3 --> the units digit is 3;
3^2=9 --> the units digit is 9;
3^3=27 --> the units digit is 7;
3^4=81 --> the units digit is 1;
3^5=243 --> the units digit is 3 AGAIN;
...
So, as you can see the units digit repeats in blocks of 4: {3, 9, 7, 1}, {3, 9, 7, 1}, ... Now, since 355=352+3=(multiple of 4)+2, then the units digit of 3^355 will be the third number in the pattern thus 7.
Answer: D.
Question: The ratio of radius of a circle and the side of a square is 2 : 5. Find the ratio of their areas:
A.2 : 1
B.4 : 25
C.8 : 77
D.4 : 121
Answer: B.4 : 25
Explanation: radius/side = 2/5
â‡’ area of circle/area of square= 4/25
Answer: B
Question: A can do a job in 15days and B in 20days. If they work on it together for 3 days, then the fraction of the work that is left is?
A.2/15
B.8/15
C.13/20
D.1/12
Answer: C.13/20
Explanation: A's 1 day work = 1/15
B's 1day work = 1/20
A+B 1day work = 1/15 + 1/20 = 7/60
A+B 3days work = 7/60*3 = 7/20
Remaining work = 1 - 7/20 = 13/20
Answer is C
Question: In a certain company, a third of the workers do not have a retirement plan.60% of the workers who do not have a retirement plan are women, and 40% of the workers who do have a retirement plan are men. If 120 of the workers of that company are men, how many of the workers are women?
A.80
B.95
C.180
D.120
Answer: C.180
Explanation: Set up equation:
x = total number of workers
120 = 0,4 * 2/3 * x + 0,4* 1/3 * x
120 = 12/30 x
x = 300
300 - 120 = 180
Answer C
Question: There are two concentric circles with radii 8 and 4. If the radius of the outer circle is increased by 25% and the radius of the inner circle decreased by 25%, by what percent does the area between the circles increase?
A.75
B.80
C.85
D.90
Answer: D.90
Explanation: The area of a circle is piR^2, where R is the radius.
The area of the big circle is 64pi.
The area of the small circle is 16pi.
The area A1 between the circles is 48pi.
When the big circle's radius increases, the new area is 100pi.
When the small circle's radius decreases, the new area is 9pi.
The area A2 between the circles is 91pi.
The ratio of A2/A1 is 91/48 = 1.9 which is an increase of 90%.
The answer is D.
Question: You and your friend spent a total of $15 for lunch. Your friend spent $1 more than you. How much did your friend spend on their lunch?
A.$9
B.$8
C.$4
D.$6
Answer: B.$8
Explanation: My lunch = l, my friends lunch = l+1
(l)+(l+1)=15
l+l+1-1=15-1
2l=14
l=7
My friends lunch l+1 = 7+1=$8, the answer is B
Question: There is a 100 pound watermelon laying out in the sun. 99 percent of the watermelon's weight is water. After laying out for a few hours 98 percent of the watermelon's weight is water.
How much water evaporated?
A.20
B.30
C.40
D.50
Answer: D.50
Explanation: In the beginning it is 99 pounds water and 1 pound other stuff. At the end the 1 pound other stuff is 2 percent so the total weight is 50 pounds. 50 pounds - 1 pound other stuff = 49 pounds water. So 99 pounds - 49 pounds = 50 pounds water lost.
Question: 5 identical snow plows can clear an iced parking lot in 4 hours. How long would it take 6 such snow plows to clear the same parking lot?
A.3 hour, 10 minutes
B.2 hours, 30 minutes
C.3 hours
D.7 hours, 30 minutes
Answer: A.3 hour, 10 minutes
Explanation: 6/5 as many plows will take 5/6 as many hours --> 4*5/6=10/3 hours =3 hours, 10 minutes.
Answer: A.
Question: In a class of 210 students, 70 did not opt for math. 55 did not opt for science and 42 did not opt for either. How many students of the class opted for both math and science?
A.123
B.125
C.127
D.137
Answer: C.127
Explanation: 210 students total
70 did not opt for math
55 did not opt for science
42 did not opt for either
Total of 140 students in math and 13 did not opt for sci but did for math
140-13=127
127 students of the class opted for both math and science
Answer:C
Question: A departmental store charges the commission of 15 percent on the first sale of items worth $50,000 and then an additional 10 percent on any sale price that exceeds the initial $50,000. If the department store earned $26,000 in commissions for the sale of a series of diamonds, what was the sale price of the diamond set?
A. $235,000
B. $365,000
C. $115,000
D. $240,000
Answer: A. $235,000
Explanation: 26,000 = 0.15 *(50000) + 0.10 (x - 50000)
26000 - 7500 = 0.10 (x-50000)
185000 = x - 50000
x = 2,35,000
Answer : A
Question: 3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day should 4 pumps work in order to empty the tank in 1 day?
A.10
B.12
C.8
D.15
Answer: B.12
Explanation: Explanation:
Let the required hours needed be x
More pumps, less hours (Indirect proportion)
More Days, less hours (Indirect proportion)
Hence we can write as
(pumps)3:4
(days) 2:1}: : x : 8
⇒3×2×8=4×1 × x
⇒3×2×2= x
⇒x=12
Answer: Option B
Question: A set of numbers has the property that for any number t in the set,t+4 is in the set. If -3 is in the set, which of the following must also be in the set? I. 9 II. 2 III. 4
A.II,III only
B.I only
C.I,III only
D.II only
Answer: B.I only
Explanation: question is asking for must be there elements.
According to the question if t is there t+4 must be there.
if -3 is the starting element the sequence is as follows.
S ={-3,1,5,9....}
if -3 is not the starting element the sequence is as follows
S = {...-7,-3,1,5,9...}
By observing the above two sequences we can say that 9 must be there in set S.
Answer : B
Question: If k > 0, x + 2k = y, and y + 4k = z, what is the ratio between z - x and y - x ?
A.1 to 4
B.1 to 2
C.2 to 1
D.3 to 1
Answer: D.3 to 1
Explanation: y-x = 2k
z-y = 4k
Let's add the two equations together:
z-x = 6k
The ratio of z-x to y-x is 6:2 = 3:1.
The answer is D.
Question: When a=4+(3/4) and b=4-(3/4), (2^a^2)/(2^b^2)=?
A.496
B.486
C.4096
D.456
Answer: C.4096
Explanation: --> (2^a^2)/(2^b^2) ={(2)^(a^2-b^2)}=2^(a-b)(a+b). Since a-b=6/4 and a+b=8, 2^(a-b)(a+b)=2^(6/4)(8)=2^12=4096
Therefore, the answer is C
Question: What is the remainder when you divide 2^200+2 by 7?
A.1
B.2
C.3
D.6
Answer: D.6
Explanation: answer is D. this is very similar to the 32^32^32+2 divided by 7 question.
Question: A part of certain sum of money is invested at 9% per annum and the rest at 12% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
A.4:5
B.4:2
C.4:3
D.4:9
Answer: C.4:3
Explanation: 12:9
= 4:3
Answer:C
Question: Laura can paint 1/x of a certain room in 20 minutes. What fraction Q of the same room can Joseph paint in 20 minutes if the two of them can paint the room in an hour, working together at their respective rates?
A.1/(3x)
B.3x/(x-3)
C.(x – 3)/(3x)
D.x/(x-3)
Answer: C.(x – 3)/(3x)
Explanation: Options with variables are often done by plugging in numbers.
Both working together can paint the room in 1 hr so if their individual rates were equal, each would take 2 hours alone.
2 hours is 120 mins so in 20 mins each would complete Q=120/20 = 1/6th of the room alone.
So if x = 6 (Laura completes 1/6th of the room in 20 mins), the correct option will give 1/6. (Joseph will also paint 1/6th of the room if their rates are same)
If you put x = 6 in the options, only option (C) will give 1/6
Answer (C)
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.2120?
A.Rs.1000.15
B.Rs.1100.95
C.Rs.1892.85
D.Rs.1050.85
Answer: C.Rs.1892.85
Explanation: 2120 = P [1 + (5*12/5)/100]
P= 1892.85
ANSWER:C
Question: The diagonal of a rhombus are 65 m and 60 m. Its area is:
A.1940
B.1950
C.1960
D.1990
Answer: B.1950
Explanation: Area of the rhombus = 1/2 d1d2 = ( 1/2 × 65 × 60 ) Cm(power)2
= 65 × 30 = 1950 Cm(power)2
Answer is B.
Question: If 7a = 8b and ab ≠0, what is the ratio of a/8 to b/7?
A.16/14
B.8/7
C.1
D.7/8
Answer: C.1
Explanation: A nice fast approach is the first find a pair of numbers that satisfy the given equation: 7a = 8b
Here's one pair: a =8 and b =7
What is the ratio of a/8 to b/7?
In other words, what is the value of (a/8)/(b/7)?
Plug in values to get: (a/8)/(b/7) = (8/8)/(7/7)
= 1/1
= 1
C
Question: There are 35 students in a hostel. If the no. of students increases by 4, the expenses of the mess increase by Rs.42/day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess?
A.s. 99.75
B.s. 89.75
C.s. 72.75
D.s. 58.75
Answer: A.s. 99.75
Explanation: Suppose the average join the mess , total expenditure = 35x + 42
Now, the average expenditure = (35x + 42)/ (35 + 4) = x – 1
or, 35x + 42 = 39x – 39
or, x = 20.25
Thus the original expenditure of the mess = 35 x 20.25=708.75
Therefore x-1 = 19.25
hence 42 x 19.25 = 808.50
808.50 - 708.75 = Rs. 99.75
A
Question: A total of 520 players participated in a single tennis knock out tournament. What is the total number of matches played in the tournament? (Knockout means if a player loses, he is out of the tournament). No match ends in a tie.
A.511
B.519
C.256
D.255
Answer: B.519
Explanation: There are 520 players, only 1 person wins, 519 players lose. in order to lose, you must have lost a game.
519 games.
Ans- B
Question: A number when divided by 342 gives a remainder 38, what remainder will be obtained by dividing the same number 21?
A.7
B.6
C.9
D.2
Answer: D.2
Explanation: Explanation:
342 + 38 = 380/21 = 2 (Remainder)
Answer: D
Question: A policeman spotted a criminal from a distance of 200 metres. When the policeman starts the chase, the criminal also starts running. If the criminal was running at 10 km/hr and the policeman was chasing at the speed of 12 km/hr, find the distance the criminal will run before he is catched by the policeman ?
A.1.5 km
B.700 m
C.900 m
D.1 km
Answer: D.1 km
Explanation: Explanation :
Solution: Relative speed = (12 - 10) = 2 km/hr.
Time taken by policeman to cover 200 m = (200/1000 * 1/2) hr
= 1/10 hr.
In 1/10 hrs, the criminal covers a distance of (10*1/10) km = 1 km.
Answer : D
Question: Gokul had 100 currency notes in all, some of which are of Rs 60 denomination and the remaining of Rs 50 denomination. The total amount of all these currency notes was Rs. 5000. How much amount (in Rs) did he have in the denomination of Rs 50?
A.109
B.95
C.106
D.100
Answer: D.100
Explanation: Let the number of 50-rupee notes = x
Then, the number of 60-rupee notes = (100 – x)
50x + 60(100 – x) = 5000 : x = 71
ANSWER:D
Question: A departmental store has 9 managers and 18 associates. The 9 managers have an average salary of $1300. The 18 associates have an average salary of $12,000. What is the average salary for the departmental store?
A.$3556.25
B.$3988.89
C.$3836.56
D.$3745.56
Answer: B.$3988.89
Explanation: Number of managers is 9
Their average salary is $1300
Number of associates is 18
Their average salary is $12,000
Total salary of managers is 9*1300=$11700
Total salary of associates is 18*12,000=$96,000
Total salary for the departmental store is 96,000+11700=107700
Average salary for the departmental store is 107700/9+18=3988.89
Answer is B
Question: The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
A.21
B.56
C.18
D.25
Answer: B.56
Explanation: 1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 – 550 = 56
Answer:B
Question: A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
A.10
B.6
C.5
D.4
Answer: C.5
Explanation: Explanation :
Speed of the motor boat = 15 km/hr
Let speed of the stream = v
Speed downstream = (15+v) km/hr
Speed upstream = (15-v) km/hr
Time taken downstream = 30/(15+v)
Time taken upstream = 30/(15−v)
total time = (30/(15+v)) + (30/(15−v))
It is given that total time is 4 hours 30 minutes = 4(1/2) hour = 9/2 hour
i.e.,(30/(15 + v)) + (30/(15 − v)) = 9/2
⇒ (1/(15+v)) + (1/(15−v)) = 9/(2×30) = 3/20
⇒ (15 − v + 15 + v)/(15+v)(15−v) = 3/20
⇒ (30/152)− (v2) = 3/20
⇒ (30/225−v2) = 3/20
⇒ 10/(225−v2) = 1/20
⇒225 − v2= 200
⇒ v2 = 225 − 200 = 25
⇒ v = 5 km/hr. Answer : Option C
Question: How many words can be formed by using all letters of the word ‘JUPITER’ ?
A.3220
B.3640
C.4420
D.5040
Answer: D.5040
Explanation: The word contains 7 different letters.
The number of permutations is 7! = 5040
The answer is D.
Question: The difference between 3/5 of 2/3 of a number and 2/5 of 1/4 of the same number is 288. What is the number?
A.960
B.850
C.895
D.955
Answer: A.960
Explanation: according to the given condition
x*(2/3)*(3/5) - x*(2/5)*(1/4) = 288
so 2x/5 - x/10 = 288
or 3x/10 = 288
or x = 2880/3 = 960
ANSWER:A
Question: A school having three classes only have student strength of 40, 20 and 40 respectively. The pass percentages of these classes are 20%, 30% and 100% respectively. What is the pass percentage for the entire school?
A.54%
B.76%
C.34%
D.66%
Answer: A.54%
Explanation: 20% of 40+30% of 20+100% of 40
=8+6+40 =
now 54 of 100
= 54%
ANSWER:A
Question: There is a total of 90 marbles in a box, each of which is red, green, blue, or white. If one marble is drawn from the box at random, the probability that it will be white is 1/6 and the probability that it will be green is 1/5. What is the probability that the marble will be either red or blue?
A.3/5
B.7/15
C.11/15
D.19/30
Answer: D.19/30
Explanation: P(red or blue) = 1 - P(white) - P(green) = 30/30 - 5/30 - 6/30 = 19/30
The answer is D.
Question: Tough and Tricky questions: Word Problems.
ABZ Car Company wants to manufacture a new car known as Model X, and it is trying to determine how many cars it needs to sell in order to make an annual profit of $30,500,000. The annual fixed costs for Model X total $50,200,000. In addition, each Model X car has an average cost of $5,000 per vehicle to manufacture. If the Company forecasts it will sell 20,000 Model X cars this year, at what price must the Company sell the car to achieve the desired annual profit?
A.$4,035
B.$4,036
C.$9,035
D.$16,140
Answer: C.$9,035
Explanation: The ABZ company plans to make a profit of $30,500,000 and it needs to earn the fixed costs of $50,200,000, so it needs to earn $80,700,000 on top of the costs for the production of the 20,000 cars.
Therefore, price of each car needs to be the unit costs plus $80,700,000/20,000. After removing the 0's, we end with the unit costs plus $8,070/2, which is $5,000 plus $4,035. Therefore, Answer C is correct.
Question: The sum of the present ages of a father and his son is 47 years. Six years ago, father's age was four times the age of the son. After 6 years, son's age will be:
A.13
B.15
C.17
D.19
Answer: D.19
Explanation: Let the present ages of son and father be x and (47 - x) years respectively.
Then, (47 - x) - 6 = 4(x - 6)
41 - x = 4x - 24
x = 13
The son's age after 6 years will be 19.
The answer is D.
Question: A pet store regularly sells pet food at a discount of 10 percent to 30 percent from the manufacturer’s suggested retail price. If during a sale, the store discounts an additional 20 percent from the discount price, what would be the lowest possible price of a container of pet food that had a manufacturer’s suggested retail price o f $ 20.00?
A.$ 10.00
B.$ 11.20
C.$ 14.40
D.$ 16.00
Answer: B.$ 11.20
Explanation: For retail price = $20
First maximum discounted price = 20 - 30% of 20 = 20-6 = 14
Price after additional discount of 20% = 14 - 20% of 14 = 14 - 2.8 = 11.2
Answer: Option B
Question: Population of a city decreases by 10% at the end of first year and increases by 10% at the end of second year and again decreases by 10% at the end of third year. If the population of the city at the end of third year is 4455, then what was the population of the city at the beginning of the first year?
A.5,000
B.4,500
C.4,950
D.1,000
Answer: A.5,000
Explanation: M. F = 90/100*110*100*90/100 = 81*11/1000
Population before 3Yrs = I.Q /M. F = 4455*1000/81*11
= 5000
ANSWER:A
Question: If N = 2^0.15 and N^b = 8, b must equal
A.3/80
B.3/5
C.20
D.5/3
Answer: C.20
Explanation: 15/100 = 3/20
N = 2 ^ 3/20
N^b = 2^3
(2^3/20)^b = 2^3
b = 20
Answer: C
Question: An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases?
A.8:4
B.8:7
C.8:2
D.8:3
Answer: B.8:7
Explanation: Let the length and breadth of the carpet in the first case be 3x units and 2x units respectively.
Let the dimensions of the carpet in the second case be 7y, 3y units respectively.
From the data,.
2(3x + 2x) = 2(7y + 3y)
=> 5x = 10y
=> x = 2y
Required ratio of the areas of the carpet in both the cases
= 3x * 2x : 7y : 3y
= 6x2 : 21y2
= 6 * (2y)2 : 21y2
= 6 * 4y2 : 21y2
= 8:7
Answer: B
Question: There is 60 lit of milk and water in which milk forms 84%.Howmuch water must be added to this solution to make it solution in which milk forms 64%
A.18.75
B.19.75
C.20.75
D.21.75
Answer: A.18.75
Explanation: 60*84/100=50.40 lit milk that is 9.60 lit water
let x lit water will be added then
(60+x)*64/100=50.40
so x=18.75
ANSWER:A
Question: 270 candidates appeared for an examination, of which 252 passed. The pass percentage is :
A.(93 + 1/9 )%
B.(93 + 1/3 )%
C.(93 + 9/3 )%
D.(94 + 9/3 )%
Answer: B.(93 + 1/3 )%
Explanation: Answer: B) (93 + 1/3 )%
Question: In an examination 80% pass in english, 70%pass in maths , 10%fail in both ,
144 pass in both . How many all appeared to the test?
A.260
B.240
C.370
D.120
Answer: B.240
Explanation: E : 80%, Fail in both: 10%, therefore only M pass is 10%
M: 70%, fail in both: 10%, therefore only E pass is 20%
100% = all fail + only E pass + only M pass + both E and M
pass
100%=10%+20%+10% + both E and M pass
Therefore, both E and M pass = 60%
60%=> 144
100% => 240
Answer: B
Question: A taxi charges p dollars for the first two miles and c cents per quarter mile for every mile after the first two. Which equation describes cost of a taxi ride of n miles in dollars.
A.pn – c/8(100)
B.cp + 4n-8/200
C.p + (4cn-8c)/100
D.p + 100cn/4
Answer: C.p + (4cn-8c)/100
Explanation: This is about as complicated as these types of problems come, but it is essentially the same as any problem which has an initial cost which is added to a dependent additional cost. Looking at the problem, we notice that the cost p is added to the mile dependent cost, which is some combination of the other terms listed in the problem. With just that knowledge we can eliminate all but two of the answer choices! Choices (A), (B), and (E) either do some strange calculation with the initial cost p, or subtract the additional cost from p. Both of these circumstances would be next to impossible if there is an initial cost being added to another cost. Thus, we only have to choose between choice (C) and choice (D). We can easily find the right answer by plugging in real numbers and checking which choice yields a correct answer. We can also see that answer choice (D) seems to be multiplying the cost in cents by 100, which, if the trip was 6 miles and the charge per mile was 25 cents, would make the taxi cost an additional $3750! This seems impossible, and leaves only the correct answer choice, (C).
Question: How many words can be formed from the letters of the word ‘DIRECTOR’
So that the vowels are always together?
A.1240
B.2630
C.4702
D.2160
Answer: D.2160
Explanation: In the given word, we treat the vowels IEO as one letter.
Thus, we have DRCTR (IEO).
This group has 6 letters of which R occurs 2 times and others are different.
Number of ways of arranging these letters = 6!/2! = 360.
Now 3 vowels can be arranged among themselves in 3! = 6 ways.
Required number of ways = (360x6) = 2160.
ANSWER D 2160
Question: If the sides of two cubes are in the ratio 3: 1 the ratio of their total surface area is?
A.3:1
B.8:1
C.9:1
D.12:1
Answer: C.9:1
Explanation: a1 : a2 = 3 : 1
6 a12 : 6 a22 = 9: 1
ANSWER:C
Question: A bag is filled with pennies and nickels in the ratio of 2 to 1. There are 10 nickles in the bag, how many coins are there in that bag?
A.30
B.50
C.65
D.70
Answer: A.30
Explanation: A ratio of pennies to nickels of 2 to 1 means that we can write the number of pennies and nickels in the form
number of pennies = 2x and number of nickels = x
But we know the number of nickels, 10. Hence
x = 10
The total number of coins is given by
2x + x = 3x = 3 × 10 = 30
Answer : A
Question: On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 3 cups of tea. Last week Mo drank a total of 26 cups of tea and hot chocolate together. If during that week Mo drank 10 more tea cups than hot chocolate cups, then how many rainy days were there last week?
A.0
B.1
C.4
D.5
Answer: B.1
Explanation: T= the number of cups of tea
C= the number of cups of hot chocolate
T+C = 26 T-C=10 -> T= 18. C=8.
Mo drinks 3 cups of tea a day then number of days that are not rainy = 18/3 = 6
So number of rainy days = 7-6 = 1
B is the answer.
Question: There are 5 orators A, B, C, D, E. In how many ways can the arrangements be made so that A always comes before B and B always comes before C.
A.5! / 3!
B.8! / 6!
C.5! x 3!
D.8! / (5! x 3!)
Answer: A.5! / 3!
Explanation: Select any three places for A, B and C. They need no arrangement amongst themselves as A would always come before B and B would always come before C.
The remaining 2 people have to be arranged in 2 places.
Thus, 5C3 x 2! = 5! / 3!
ANSWER:A
Question: A sum of money amounts to Rs. 9800 after 5 years and Rs. 12015 after 8 years at the same rate of simple interest. The rate of interest per annum is?
A.12.05%
B.5%
C.13.05%
D.22.05%
Answer: A.12.05%
Explanation: S.I. for 3 years = (12015 - 9800) = Rs. 2215
S.I. for 5 years = Rs. 2215/3 * 5 = Rs. 3691.
Principal = (9800 - 3675) = Rs. 6108
Hence, rate = (100 * 3691) / (6125 * 5) = 12.05%
ANSWER:A
Question: If the two hands in a clock are 11 minutes divisions apart,then the angle between them is
A.66Â°
B.18Â°
C.24Â°
D.60Â°
Answer: A.66Â°
Explanation: In a clock, each minute makes 6Â°
âˆ´ 11 minutes will make 6 Ã— 11 = 66Â°
Answer A