RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Andrea wants to fill in two sections of her
backyard with sod that must be purchased
in 2-x-2-foot squares. If the two sections
measure 30 x 40 feet and 60 x 80 feet, how
many squares of sod does she need to buy?
A.1,000
B.1,250
C.1,500
D.1,600
Answer: C.1,500
Explanation: To begin, find the area of each of the two sections by multiplying the lengths of the sides:
30 feet × 40 feet = 1,200 square feet
60 feet × 80 feet = 4,800 square feet
The total area that needs sod has an area of 1,200 + 4,800 = 6,000 square feet. Each individual
square is 2 feet by 2 feet, so each has an area of 4 square feet. Because all the numbers are
even, there will be no waste when the squares of sod are placed. Therefore, you just have
to find the number of squares needed by dividing:
6,000 ÷ 4 = 1,500
correct answer C) 1,500
Question: A rectangular grass field is 75 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.10 per sq m?
A.6350
B.7357
C.6328
D.6750
Answer: D.6750
Explanation: Area = (l + b +2d) 2d
= (75 + 55 +2.5 * 2) 2*2.5 => 675
675 * 10 = Rs.6750
Answer:D
Question: P , Q, R enter into a partnership & their share are in the ratio 1/2 : 1/3 : 1/4 , after two months , P withdraws half of the capitals & after 10 months , a profit of Rs 336 is divided among them . What is P's share?
A.112
B.120
C.134
D.144
Answer: A.112
Explanation: Explanation :
The ratio of their initial investment = 1/2 : 1/3 : 1/4
= 6 : 4: 3
Let's take the initial investment of P, Q and R as 6x, 4x and 3x respectively
A:B:C = (6x * 2 + 3x * 10) : 4x*12 : 3x*12
= (12+30) : 4*12 : 3*12
=(4+10) : 4*4 : 12
= 14 : 16 : 12
= 7 : 8 : 6
P's share = 378 * (7/21) = 112. Answer : Option A
Question: The ratio of the length and the breadth of a rectangle is 4 : 3 and the area of the rectangle is 6912 sq cm. Find the ratio of the breadth and the area of the rectangle?
A.1: 96
B.1: 99
C.1: 94
D.1: 92
Answer: A.1: 96
Explanation: Let the length and the breadth of the rectangle be 4x cm and 3x respectively.
(4x)(3x) = 6912
12x2 = 6912
x2 = 576 = 4 * 144 = 22 * 122 (x > 0)
=> x = 2 * 12 = 24
Ratio of the breadth and the areas = 3x : 12x2 = 1 : 4x = 1: 96.
Answer: A
Question: A father in his will left all his money to his children in the following manner:
$1000 to the first born and 1/10 of what then remains, then
$2000 to the second born and 1/10 of what then remains, then
$3000 to the third born and 1/10 of what then remains, and so on.
When this was done each child had the same amount. How many children were there?
A.9
B.10
C.11
D.12
Answer: A.9
Explanation: Let x be the original amount.
Let y be the amount each child gets.
The first child got y = 1000+(x-1000)/10.
The second child got y = 2000+(x-2000-y)/10.
Here, we have two equations with two unknowns. This is enough to solve for x and y.
Using the substitution method,
1000+(x-1000)/10 = 2000+(x-2000-(1000+(x-1000)/10))/10
1000+x/10-100 = 2000+x/10-200-(100+(x/10-100)/10)
1000+x/10-100 = 2000+x/10-200-100-x/100+10
x/100 = 1000-200+10
x/100 = 810
x = 81,000
The amount each child gets can be calculated this way:
y = 1000 + (x-1000)/10 = 1000 + (81000 - 1000)/10 = 9000
The number of children is the original amount of money divided by the amount of money each child gets. That's 81,000 divided by 9,000, which is 9. So there are nine children.
Answer A
Question: If a particular is never chosen, in how many ways can a cricketbe chosen out of 15 players?
A.213
B.249
C.364
D.389
Answer: C.364
Explanation: A particular players is never chosen, it means that 11 players are selected out of 14 players.
=> Required number of ways = 14C11
= 14!/11!x3! = 364
C
Question: The Ghaziabad-Hapur-Meerut EMU and the Meerut-Hapur-Ghaziabad EMU start at the same time from Ghaziabad and Meerut and proceed towards each other at 16 km/hr and 21 km/hr respectively. When they meet, it is found that one train has travelled 60 km more than the other. The distance between two stations is:
A.445 km
B.444 km
C.400 km
D.524 km
Answer: B.444 km
Explanation: Explanation :
The two trains start simultaneously. Let they meet after a time ‘t’.
The train that has covered 60 km more must be the faster of the two.
Hence,
=>60=(21–16)×t.
=>t=12 hours.
Since they are traveling towards each other, total distance is the sum of the distances travelled by the two trains individually.
Total distance = 16×12+21×12 = 444 Km.
Answer : B
Question: If 80 lamps can be lighted 5 hours per day for 10 days for Rs. 21.25,then the number of lamps which can be lighted 4 hours daily for 30days for Rs. 76.50, is?
A.100
B.110
C.120
D.130
Answer: C.120
Explanation: Explanation :
(Hrs/Day 4: 5) : (Money 21.25 :76.50) : (Days 30:10) : : 80 : x4 * 21.25 * 30 * x = 5 * 76.50 * 10 * 80 so x = 120
Answer : C
Question: What should be added to 4329 so that it may become a perfect square?
A.24
B.25
C.26
D.27
Answer: D.27
Explanation: 66x66=4356
4356-4329 = 27
If added to 27 get perfect square
answer =D
Question: If anangletis defined as 1 percent of 1 degree, then how many anglets are there in one half circle?
A.0.36
B.3.6
C.360
D.18,000
Answer: D.18,000
Explanation: 1 degree * 1/100 = 1 anglet
So 1 degree = 100 anglets
=> 180 degrees = 18,000 anglets
Answer - D
Question: The number of new words that can be formed by rearranging the letters of the word 'ALIVE' is?
A.186
B.278
C.119
D.278
Answer: C.119
Explanation: Number of words which can be formed
= 5! - 1 = 120 - 1
= 119.
Answer:C
Question: If 6 spiders make 6 webs in 6 days, then 1 spider will make 1 web in how many days?
A.7
B.6
C.5
D.4
Answer: B.6
Explanation: Let the required number days be x.
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)
spiders 1:6
Webs 6:1
1 x 6 x x = 6 x 1 x 6
=> x= 6
Answer is B
Question: An astronomer noted that a grouping of red giant stars had an average solar mass of 8 M each, and a grouping of white dwarf stars had an average solar mass of 1.5 M each. If the astronomer calculated the total solar mass of both groupings to be 49 M, what total number of red giant stars and white dwarf stars did the astronomer note?
A.10
B.11
C.12
D.13
Answer: B.11
Explanation: We can determine quickly that total number should range between 49/8 <= N <=49/1.5 , so ans should be between 6 and 33.
Now solving the expression 8A+1.5B =49
decreasing 49 in multiple of 8 and checking divisibility of that number by 1.5. this way we get
2 red giants, 22 white dwarfs we get 49, but 2 + 22 = 24 and 24 is not an option.
Next we get 5 red giants and 6 white dwarfs to get 49, 5*8 + 6*1.5 = 49
Hence total number is 5 + 6 = 11
Ans B
Question: A train is travelling at 48 kmph. It crosses another train having half of its length, travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in
45 seconds. What is the length of the platform?
A.400 m
B.500 m
C.600 m
D.550 m
Answer: A.400 m
Explanation: speed of I train = 48kmph
length of I train = 2x m
speed of sec train = 42 kmph
length of seconf train = x m
dist = (2x+x) = 3x m
time = 12 sec
= 90 * 5/18 = 25m/s
x=100
length of first train = 2x = 200 m
time taken = 45 sec
speed of first train = 48 kmph = 48 * 5/18 = 40/3 m/s
length of the platform = y metre
200 + y = 45 * 45/3 = 600
y = 400
ANSWER A
Question: The compound ratio of 2/3, 6/7, 1/3 and 1/8 is given by?
A.1/48
B.1/42
C.1/40
D.1/41
Answer: B.1/42
Explanation: 2/3 * 6/7 * 1/3 * 1/8 = 1/42
Answer: B
Question: In an election, candidate A got 60% of the total valid votes. If 15% of the total votes were declared invalid and the total numbers of votes is 560000, find the number of valid vote polled in favor of candidate.
A.285600
B.340000
C.347000
D.356000
Answer: A.285600
Explanation: Total number of invalid votes = 15 % of 560000
= 15/100 × 560000
= 8400000/100
= 84000
Total number of valid votes 560000 – 84000 = 476000
Percentage of votes polled in favour of candidate A = 60 %
Therefore, the number of valid votes polled in favour of candidate A = 60 % of 476000
= 60/100 × 476000
= 28560000/100
= 285600
A)
Question: In a mixture of 45 litres the ratio of milk to water is 4:1. Additional 12 litres of water is added to the mixture. Find the ratio of milk to water in the resulting mixture.
A.12/7
B.4/1
C.2/3
D.3/4
Answer: A.12/7
Explanation: Given that Milk/Water=4x/x and 4x+x=45 --> x=9.
Thus Milk=4x=36 liters and Water=x=9 liters.
New ratio = 36/(9+12) = 36/21 = 12/7.
Answer: A.
Question: The banker’s discount on Rs.1600 at 15% per annum is the same as true discount on Rs.1680 for the same time and at the same rate. The time is
A.3 months
B.4 months
C.6 months
D.8 months
Answer: B.4 months
Explanation: Solution
S.I on Rs. 1600 = T.D on Rs. 1680.
Rs.1600 is the P.W of Rs.1680.
Rs.80 is S.I on Rs.1600 at 15%.
Time	= (100x80 / 600x15)
= 1/3 year
= 4 months.
Answer B
Question: Seed mixture X is 40% ryegrass and 60% bluegrass by weight; seed mixture Y is 24% ryegrass and 75% fescue. If a mixture of X and Y contains 36% ryegrass, what percent of the weight of the mixture is from mixture X?
A.25%
B.40%
C.60%
D.75%
Answer: D.75%
Explanation: 36% is 12%-points above 25% and 4%-points below 40%.
Thus the ratio of mixture Y to mixture X is 1:3.
The percent of mixture X is 3/4 = 75%.
The answer is D.
Question: The sale price sarees listed for Rs.350 after successive discount is 20% and 5% is?
A.266
B.278
C.342
D.787
Answer: A.266
Explanation: 350*(80/100)*(95/100)
= 266
Answer: A
Question: The perimeter of an equilateral triangle is 60. If one of the sides of the equilateral triangle is the side of an isosceles triangle of perimeter 45, then how long is the base of isosceles triangle?
A.5 units
B.10 units
C.15 units
D.20 units
Answer: A.5 units
Explanation: The base of the isosceles triangle is 45-20-20= 5 units
The answer is A.
Question: Arnold and Danny are two twin brothers that are celebrating their birthday. The product of their ages today is smaller by 5 from the product of their ages a year from today. What is their age today?
A.2.
B.4.
C.5.
D.7.
Answer: A.2.
Explanation: ad = (a+1) (d+1) -5
0= a+d-4
a+d = 4
a=d (as they are twin brothers)
a=d=2
A is the answer
Question: The sum of the present ages of a son and his father is 60 years. Six years ago, father's age was five times the age of the son. After
6 years, what will be son's age?
A.23 years
B.22 years
C.21 years
D.20 years
Answer: D.20 years
Explanation: Let the present age of the son = x
Then present age of the father = (60 - x)
six years ago father's age was 5 times the age of the son
(60-x)-6 = 5(x-6)
x = 84/6 = 14
son's age after 6 years
x+6 = 14 + 6 = 20
ANSWER D
Question: The average salary of all the workers in a workshop is Rs.8000. The average salary of 7 technicians is Rs.18000 and the average salary of the rest is Rs.6000. The total number of workers in the workshop is
A.20
B.21
C.42
D.23
Answer: C.42
Explanation: Solution
Let the toatl number of workers be x.
Then 8000x=(18000 x 7) + 6000 (x -7)
x= 42
Answer C
Question: A group of people were given 2 puzzles. 75% people solved puzzle X and 89% people solved puzzle Y. What is the maximum and minimum percentage of people who could have solved both the puzzles?
A. 11%, 0%
B. 49%, 33%
C. 68%, 57%
D. 75%, 68%
Answer: D. 75%, 68%
Explanation: To solve this question, we don't need any formulas. Just read the question carefully. If 75% of the people solved puzzle X and 89% solved puzzle Y, then maximum % that can solve both correctly can only be 75%. From the given options, only D looks good
Answer D
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 1000 resolutions?
A.1077 m
B.804 m
C.978 m
D.1048 m
Answer: D.1048 m
Explanation: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 1000 resolutions.
= 1000 * 2 * 22/7 * 22.4 = 104800 cm
= 1408 m
Answer: D
Question: One side of a rectangular field is 15 m and one of its diagonal is 18 m. Find the area of the field.
A.100
B.120
C.150
D.148.5
Answer: D.148.5
Explanation: Solution
Other side = √(18)2 - (15)2
= √324 - 225
= √99
= 9.9 m.
∴ Area = (15 x 9.9)m2 = 148.5 m2.
Answer D
Question: What is the maximum area that can be enclosed by a wire 44cm long ?
A.77
B.154
C.308
D.318
Answer: B.154
Explanation: Perimeter of circle=2*22/7*r=44cm
From this r=7
then area of circle=22/7*r^2=154
ANSWER:B
Question: A father is now three times as old as his son. Three years back, he was four times as old as his son. The age of the son (in years) is
A.A)12
B.B)9
C.C)18
D.D)20
Answer: B.B)9
Explanation: Explanation:
Let son's age be x years. Then, father's age = (3x) years.
Three years ago, father's age = (3x - 3) years and son's age = (x - 3) years.
So, 3x - 3 = 4 (x - 3)=> 3x - 3 = 4x - 12=> x = 9.
Answer: B
Question: The angles of a triangle are in the ratio 3: 4 : 2. Find the measurement of the 3 angles of triangle.
A.40°
B.25°
C.30°
D.75°
Answer: A.40°
Explanation: If the ratio of the three angles is 3:4:2, then the measures of these angles can be written as 3x, 4x and 2x. Also the sum of the three interior angles of a triangle is equal to 180°. Hence
3x + 4x + 2x = 180
Solve for x
9x = 180
x =20
The measures of the three angles are
3x =3 x20=60°
4x = 4 × 20= 80°
2x = 2 × 20 = 40°
A
Question: How many such 3's are there in the following number sequence which are immediately Preceded by an odd number and immediately f ollowed by an even number? 5 3 8 9 4 3 7 2 3 8 1 3 8 4 2 3 5 7 3 4 2 3 6
A.1
B.2
C.3 three
D.4
Answer: C.3 three
Explanation: A is followed by B means : A comes first,B comes next
A preceded by B means : B comes first, A comes next
The sets which satisfy the condition is: 5 3 8
1 3 8
7 3 4
ANSWER:C
Question: On a summer camp, 25% of the campers paid $120 each, 35% paid $60 each and the rest paid $65 each. What percentage of the total amount paid came from the campers who paid $60?
A.18%
B.27.27%
C.26%
D.33.3%
Answer: B.27.27%
Explanation: let the total no of campers be 100
total amount = (25*120)+(35*60)+(40*65) = 3000+2100+2600= $7700
required percentage = (21/77)*100=27.27%
B
Question: If there are 26 laborers in a crew, and on a certain day, 10 were present. Calculate the percentage that showed up for work? (round to the nearest tenth).
A.39.5%
B.38.5%
C.36.5%
D.37.5%
Answer: B.38.5%
Explanation: 10/26*100=38.46
38.5%
correct answer B
Question: Peter got married 0.8 decades ago. His current age is (6/5) times his age at the time of his marriage. Peter’s brother was ten years younger to him at the time of his marriage. What is the age of Peter’s Brother?[0.8 decades = 8 years]
A.38 years
B.34 years
C.28 years
D.43 years
Answer: A.38 years
Explanation: A
38 years
Let Peter’s current age is A years.
Then, his age at the time of marriage = (A – 8) years
A = (6/5)(A – 8)
5A = 6A – 48
A = 48
Peter’s sister’s age at the time of his marriage = (A – 8) – 10
= (A – 18) = 30 years.
Peter’s sister’s current age = (30 + 8) years
= 38 years.
Question: If an item that originally sold for A dollars was marked up by x percent and then discounted by y percent, which of the following expressions represents the final price of the item?
A.(A+ Ax/100) - Y/100 ( A +Ax/100)
B.(10,000z + 100z(y – x) – xyz)/10,000
C.(100z(x – y) – xyz)/10000
D.(100z(y – x) – xyz)/10000
Answer: A.(A+ Ax/100) - Y/100 ( A +Ax/100)
Explanation: value of item =A ..marked up by x% = Ax/100
total value = A +ax/100 .discounted by Y% on Total Y/100 * ( A+Ax/100)
Final price =(A+ Ax/100) - Y/100 ( A +Ax/100)
A
Question: The Sum of first N consecutive odd integers is N^2. What is the sum of all odd integers between 15 and 41 inclusive.
A.351
B.392
C.410
D.424
Answer: B.392
Explanation: We're dealing with a sequence of CONSECUTIVE ODD INTEGERS: 15 to 41, inclusive. We're asked for the SUM of this group.
1) Start with the sum of the smallest and the biggest: 15 + 41 = 56
2) Now look at the 'next smallest' and the 'next biggest': 17 + 39 = 56
Now we have proof that there is no middle term. We have 7 bunches of 56.
7(56) = 392
B
Question: A car takes 6 hours to cover a distance of 450 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
A.60
B.50
C.40
D.70
Answer: B.50
Explanation: Time = 6
Distance = 450
3/2 of 6 hours = 6 * 3/2 = 9 Hours
Required speed = 450/9 = 50 Kmph
Answer B.
Question: If a and b are digits, and the number a,11b is evenly divisible by 88, what are the values of a and b?
A.a = b = 9
B.a = b = 7
C.a = b = 5
D.a = b = 2
Answer: D.a = b = 2
Explanation: a,11b, divisible by 88.
Factors of 88 = (8)(11)
Divisible by 8: if the last 3 digits of the number are divisible by 8.
11b/8 => 112/8 = 14 => b = 2
Divisibe by 11: subtract the last digit from the number, over and over again, as necessary. If the remaining number is divisible by 11, the original number is divisible by 11.
a11-2 => a09 => 209/11 = 19.
So a = 2.
Answer: D
Question: Fom the integer n, if n*n*n is odd, then what is true from below options?
A.n is odd and n*n is even
B.n*n is odd
C.n is even
D.n is odd
Answer: A.n is odd and n*n is even
Explanation: n is odd and n*n is even
Option A
Question: The sum of three consecutive even numbers multiples of 3 is 72. what is the largest number ?
A.21
B.24
C.27
D.36
Answer: C.27
Explanation: Solution
let the number be x and x + 2.
Then, (x + 2)2 - x2 = 84 ⇔ 4 x + 4 = 84 ⇔ 4 x = 80 ⇔ x = 20.
∴ Required sum = x + (x + 2) = 2 x + 2 = 42.
Answer C
Question: The ratio of the radius of two circles is 1: 3, and then the ratio of their areas is?
A.1: 8
B.1: 6
C.1: 9
D.1: 3
Answer: C.1: 9
Explanation: r1: r2 = 1: 3
Πr12: Πr22
r12: r22 = 1: 9
Answer:C
Question: Seller selling an apple for Rs.17, a Seller loses 1/6th of what it costs him. The CP of the apple is?
A.10
B.12
C.18
D.19
Answer: C.18
Explanation: SP=17Loss=CP18Loss=CP−SP=CP−17⇒CP18=CP−17⇒17 CP18=17⇒CP18=1⇒CP=18
C
Question: A certain automobile company’s best-selling model is the Speedster. The Speedster, like all of their other models, comes in coupe and convertible styles. 1/3 of the current inventory is Speedsters, of which 4/5 are convertibles. If there are 30 vehicles that are not Speedsters, how many Speedster convertibles are there?
A.13
B.18
C.12
D.15
Answer: C.12
Explanation: Total Vehicle = 1/3 of speedster + 2/3 of others.
Speedster convertibles = 1/3 total vehicle * 4 /5
Given : 2/3 constitutes 30 Vehicles. hence 1/3 constitutes 15
Speedster convertibls = 15 * 4/5 = 12
C
Question: A man can row downstream at 18 kmph and upstream at 10 kmph. Find the speed of the man in still water and the speed of stream respectively?
A.6
B.5
C.3
D.4
Answer: D.4
Explanation: Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.
Given x + y = 18 --- (1)
and x - y = 10 --- (2)
From (1) & (2) 2x = 28 => x = 14, y = 4.
Answer: D
Question: The division of a whole number N by 13 gives a quotient of 15 and a remainder of 2. Find N.
A.197
B.198
C.199
D.200
Answer: A.197
Explanation: According to the division process of whole numbers, N can be written, using multiplication, as follows
N = quotient * divisor + remainder = 15 * 13 + 2 = 197
correct answer A
Question: Richard began driving from home on a trip averaging 30 miles per hour. How many miles per hour must Carla drive on average to catch up to him in exactly 3 hours if she leaves 30 minutes after Richard?
A.35
B.55
C.39
D.40
Answer: A.35
Explanation: After 30 mins, Richard travels 15 miles ahead Carla.
x = mph Carla need to catch up Richard in 3 hours. --> relative speed of them = x-30
Carla needs to catch up 15 miles in 3 hours --> (x−30)3=15--> x=35
Answer: A
Question: what is the probability of getting atmost one head when Two unbiased coin are tossed ?
A.3/4
B.3/2
C.4/3
D.1/2
Answer: A.3/4
Explanation: Here S={HH,HT,TH,TT}
Let Ee=event of getting one head
E={TT,HT,TH}
P(E)=n(E)/n(S)=3/4
Option A
Question: Pipe A fills a tank of capacity 850 liters at the rate of 40 liters a minute. Another pipe B fills the same tank at the rate of 30 liters a minute. A pipe at the bottom of the tank drains the tank at the rate of 20 liters a minute. If pipe A is kept open for a minute and then closed and pipe B is open for a minute and then closed and then pipe C is open for a minute and then closed and the cycle is repeated, when will the tank be full?
A.42 minutes
B.51 minutes
C.39 minutes
D.40 minutes 20 seconds
Answer: B.51 minutes
Explanation: In one cycle they fill 40+30-20 = 50 liters
850 = 50*n => n = 17
here n = number of cycles.
total time = 17*3 = 51 as in one cycle there are 3 minutes.
thus 51 minutes
ANSWER:B
Question: In a garden, there are yellow and green flowers which are straight and curved. If the probability of picking a green flower is 1/5 and picking a straight flower is 1/2, then what is the probability of picking a flower which is yellow and straight
A.1/7
B.1/8
C.2/5
D.3/4
Answer: C.2/5
Explanation: Good question.
So we have a garden where all the flowers have two properties: color (green or yellow) and shape (straight or curved).
We're told that 1/5 of the garden is green, so, since all the flowers must be either green or yellow, we know that 4/5 are yellow. We're also told there is an equal probability of straight or curved, 1/2.
We want to find out the probability of something being yellow and straight, Pr( Yellow and Straight ).
So if we recall, the probability of two unique events occurring simultaneously is the product of the two probabilities, Pr( A and B ) = P(A) * P(B). So we multiply the two probabilities, Pr(yellow)* Pr(straight) = 4/5 * 1/2 = 2/5, or C.
Question: A man can row with a speed of 15 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is?
A.22
B.27
C.20
D.99
Answer: C.20
Explanation: M = 15
S = 5
DS = 15 + 5 = 20
Answer: C
Question: A, B, C subscribe Rs. 50,000 for a business. A subscribes Rs. 4000 more than B and B Rs. 5000 more than C. Out of a total profit of Rs. 35,000, A receives:
A.Rs. 8400
B.Rs. 11,900
C.Rs. 13,600
D.Rs. 14,700
Answer: D.Rs. 14,700
Explanation: Let C = x.
Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.
So, x + x + 5000 + x + 9000 = 50000
3x = 36000
x = 12000
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
A's share = Rs. (35000 x	21/50) = Rs. 14,700.
THE CORRECT ANSWER IS D.
Question: If the sum of two positive integers is 22 and the difference of their squares is 44, what is the product of the two integers?
A.108
B.119
C.120
D.135
Answer: C.120
Explanation: Let the 2 positive numbers x and y
x+ y = 22 -- 1
x^2 - y^2 = 44
=> (x+y)(x-y)=44 -- 2
Using equation 1 in 2 , we get
=> x-y = 2 -- 3
Solving equation 1 and 3 , we get
x= 12
y= 10
Product = 12*10 = 120
Answer C
Question: A train running at the speed of 60 km/hr crosses a pole in 18 seconds. Find the length of the train.
A.150
B.278
C.179
D.300
Answer: D.300
Explanation: :
Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 18 = 300 meter
Answer:D
Question: In a party every person shakes hands with every other person. If there are 105 hands shakes, find the number of person in the party.
A.14
B.12
C.13
D.15
Answer: D.15
Explanation: Let n be the number of persons in the party. Number of hands shake = 105; Total number of hands shake is given by nC2.
Now, according to the question,
nC2 = 105;
Or, n!/[2!*(n-2)!] = 105;
Or, n*(n-1)/2 = 105;
Or, n2-n = 210;
Or, n2-n-210 = 0;
Or, n = 15, -14;
But, we cannot take negative value of n.
So, n = 15 i.e. number of persons in the party = 15.
Option D
Question: Krishan and Nandan jointly started a business. Krishan invested three times as Nandan did and invested his money for double time as compared to Nandan. Nandan earned Rs. 4000. If the gain is proportional to the money invested and the time for which the money is invested then the total gain was?
A.28,077
B.28,019
C.28,019
D.28,000
Answer: D.28,000
Explanation: 3:1
2:1
------
6:1
1 ----- 4000
7 ----- ? => Rs.28,000.Answer: D
Question: Of the diplomats who attended a summit conference: 20 spoke French, 32 did not speak Hindi and 20% of the diplomats spoke neither French nor Hindi. If 10% of the diplomats spoke both French and Hindi, then how many diplomats attended the conference?
A.70
B.96
C.108
D.120
Answer: D.120
Explanation: 2X2 matrix will be the easiest way to calculate this.
Text in black: given statements
Text in red: calculated values
Thus D=120 is the correct answer