RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A motor car starts with a speed of 70km/hr with its speed increasing every 2hours by 10kmph. In how many hours will it cover 345kms?
A.3hours
B.2hours 30mnts
C.4hours
D.4hours 30mnts
Answer: D.4hours 30mnts
Explanation: Distance covered in first 2hours = 70*2 = 140km
Distance covered in next 2hours = 80*2 = 160km
remaining distance = 345- (140+160) = 45km
speed in the fifth hour = 90km/hr
total time to cover 45km = 45/90 = 1/2 hr
total time taken = 4+(1/2) = 4hours 30minutes.
correct option is D
Question: How many positive integers less than 256 are multiple of 4 but NOT multiples of 6?
A.20
B.31
C.42
D.43
Answer: D.43
Explanation: From here, it might be easier to go up in bounds of 60, so we know that 61-120 gives 10 more numbers. 121-180 and 181-240 as well. This brings us up to 240 with 40 numbers. A cursory glance at the answer choices should confirm that it must be 42, as all the other choices are very far away. The numbers 244 and 248 will come and complete the list that’s (naughty or nice) under 250. Answer choice D is correct here.
Question: A runs 1 ¾ times as fast as B. if A gives B a start of 84 m, bow far must
winning post be so that A and B might reach it at the same time?
A.196 m
B.194 m
C.186 m
D.296 m
Answer: A.196 m
Explanation: . Ratio of the rates of A and B = 7/4 : 1 = 7 : 4.
So, in a race of 7 m, A gains 3m over B.
:. 3 m are gained by A in a race of 7 m.
:. 84 m are gained by A in a race of (7/3 x 84) m = 196 m.
:. Winning post must be 196 m away from the starting point.
Answer is A.
Question: |x+3| – |4-x| = |7+x| How many solutions will this equation have?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: You have |x+3| - |4-x| = |8+x|
First, look at the three values independently of their absolute value sign, in other words:
|x+3| - |4-x| = |8+x|
(x+3) - (4-x) = (8+x)
Now, you're looking at x < - 8, số x is a number less than -8. Let's pretend x = -10 here to make things a bit easier to understand.
when x=-10
I.) (x+3)
(-10+3)
(-7)
II.) (4-x)
(4-[-10]) (double negative, số ít becomes positive)
(4+10)
(14)
III.) (8+x)
(8+-10)
(-2)
In other words, when x < -8, (x+3) and (8+x) are NEGATIVE. To solve problems like this, we need to check for the sign change.
Here is how I do it step by step.
I.) |x+3| - |4-x| = |8+x|
II.) IGNORE absolute value signs (for now) and find the values of x which make (x+3), (4-x) and (8+x) = to zero as follows:
(x+3)
x=-3
(-3+3) = 0
(4-x)
x=4
(4-4) = 0
(8+x)
x=-8
(8+-8) =1
C
Question: In a certain large company, the ratio of college graduates with a graduate degree to non-college graduates is 1:8, and ratio of college graduates without a graduate degree to non-college graduates is 2:3. If one picks a random college graduate at this large company, what is the probability W this college graduate has a graduate degree?
A.1/11
B.1/12
C.1/13
D.3/19
Answer: D.3/19
Explanation: In believe the answer is D. Please see below for explanation.
0) we are told the following ratios
CGD - College Graduate with Degree
NCG - Non College Graduate
CGN - College Graduate no Degree
CGD NCG CGN
1 8
3 2
In order to make CGD and CGN comparable we need to find the least common multiple of 8 and 3 and that is 24 multiplying the first ratio by 3 and the second ratio by 8 we get
CGD NCG CGN
3 24 16
If one picks a random college graduate at this large company, what is the probability this college graduate has a graduate degree?
Nr of CGD = 3
Nr of CG = 3+ 16 = 19
Probability W of CGD / (CG) -> 3/19
Answer D
Question: Set A contains all the even numbers between 2 and 50 inclusive. Set B contains all the even numbers between 102 and 150 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A?
A.2500
B.2550
C.5050
D.6275
Answer: A.2500
Explanation: Set A contains 2,4 , 6 ... 50
Set B contains 102 , 104 , 106 ... 150
Number of terms in each set = 25
Difference between corresponding terms in set A and B = 100
Difference between Sum of set B and set A = 100*25 = 2500
Answer A
Question: Aarti can do a piece of work in 8 days. In how many days will she complete three time of work of same type?
A.6 days
B.19 days
C.24 days
D.3 days
Answer: C.24 days
Explanation: We have the important relation, More work, More time (days)
A piece of work can be done in 8 days.
Three times of work of same type can be done in 8 x 3
= 24 days
Answer C
Question: There were 9 lottery ticket winners for payout of 4 million dollars. If the all winners get the same amount and none of them have bills smaller than $1, how much money would they have to pay?
A.4,000,000
B.4,000,001
C.4,000,005
D.4,000,008
Answer: C.4,000,005
Explanation: Divisibility rule of 9: The sum of the digits must be divisible by 9
Sum of digits of 4,000,000 = 4 and 9 is divisible by 9.
Hence, we need to add 5 to this number for it to be divisible by 9
Correct Option : C
Question: A salesperson receives a base salary of $700 per month and a commission of 7.5% of the selling price of each item sold above the first 50 item. If this month she sold 210 items for $150 each, what will her monthly salary be?
A.$1,500
B.$1,800
C.$2,100
D.$2,500
Answer: D.$2,500
Explanation: Ans : 700+ 7.5 % * 150 * (210-50) = $ 2500
Answer D
Question: Of the 120 passengers on Flight 750, 30% are female. 10% of the passengers sit in first class, and the rest of the passengers sit in coach class. If 1/3 of the passengers in first class are male, how many females are there in coach class?
A.44
B.28
C.50
D.52
Answer: B.28
Explanation: Number of passengers on flight = 120
Number of female passengers= .3*120 = 36
Number of passengers in first class = (10/100)* 120 = 12
Number of passengers in coach class = (90/100)* 120 = 108
Number of male passengers in first class = 1/3 * 12 = 4
Number of female passengers in first class = 12-4 = 8
Number of female passengers in coach class = 36 - 8 = 28
Answer B
Question: A merchant has selected two items to be placed on sale, one of which currently sells for 35 percent less than the other. If he wishes to raise the price of the cheaper item so that the two items are equally priced, by what percentage must he raise the price of the less expensive item?
A.30%
B.40%
C.50%
D.60%
Answer: C.50%
Explanation: Expensive item = $100;
Cheap item = $ 65;
We must increase $65 to $100, so by $35, which is approximately 50% increase: (100-65)/65 = ~0.53.
Answer: C.
Question: For all integers x>1. <x>=2x+(2x-1)+(2x-2)+......2+1. What is the value of <3>*<1>?
A. 60
B. 116
C. 63
D. 263
Answer: C. 63
Explanation: Since <x>=2x+(2x-1)+(2x-2)+......2+1=1+2+..+(2x-2)+(2x-1)+2x then<x> is basically the sum of all integers from 1 to 2x, inclusive.
Hence <3> is the sum of all integers from 1 to 2*3=6 and <1> is the sum of all integers from 1 to 2*1=2 --> <3>=21 and <2>=3 --> <3>*<2>=21*3=63
Answer: C.
Question: A pump can fill a tank with water in 5 hours. Because of a leak, it took 10 hours to fill the tank. The leak can drain all the water in ?
A.12hr
B.11hr
C.13hr
D.10hr
Answer: D.10hr
Explanation: Work done by the leak in 1 hour = 1/5 - 1/10 = 1/10
Leak will empty the tank in 10 hours
Answer is D
Question: College T has 1000 students. Of the 260 students majoring in one or more of the sciences,160 are majoring in Chemistry and 120 are majoring in Biology. If at least 50 of the students are not majoring in either Chemistry or Biology, then the number of students majoring in both Chemistry and Biology could be any number from?
A.60 to 110
B.70 to 130
C.80 to 130
D.70 to 120
Answer: D.70 to 120
Explanation: Total = Chemistry + Biology - Both + Neither
260 = 160 + 120 - Both + N
We know that N (Neither) must be at least 30, so set N=30 and solve:
260 = 160 + 120 - Both + 50
260 = 330 - Both
Both = 70
Even if you're not sure whether 70 is the highest or lowest Both could possibly be, it doesn't matter, because you know it's a boundary point of the range,
Both can not be greater than 120, because even if every biology major was also a chemistry major, there are only 120 biology majors total. D the solution.
Question: The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.3.00 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
A.s.1014
B.s.1140
C.s.1998
D.s.1085
Answer: C.s.1998
Explanation: a2 = 3136 => a = 56
56 * 4 * 3 = 672 – 6 = 666 * 3.0 = 1998
ANSWER:C
Question: Murali purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. Find out his profit percentage.
A.2.2%
B.5.9%
C.4.9%
D.5.6%
Answer: D.5.6%
Explanation: cost price of 12 toys =375
selling price of12 toys =33×12=396
profit =396−375=21
profit percentage =7*100/125=5.6%
Answer : D
Question: Of the female students at Barkely University, 3/5 are on the honor roll. Of the male students, 2/5 are on the honor roll. If 5/9 of the students are female, what fraction of all the students are on the honor roll?
A.5/9
B.3/15
C.23/45
D.43/60
Answer: C.23/45
Explanation: let the total students be 45
given 5/9 of the students are females = 25
then males = 4/9 = 20
3/5 of the females are on honor roll = 15
males on the honor roll = 2/5= 8
total students on honor roll = 15+8 =23
fraction = 23/45
C
Question: Suppose x is the product of all the primes less than or equal to 59. How many primes appear in the set {x + 2, x + 3, x + 4, …, x + 59}?
A.0
B.17
C.18
D.23
Answer: A.0
Explanation: Since 2 * 3* 5 *... *59 is even, x is even.
As x is even, so will be x+2, x+4, x+6...... x+58, so these numbers cannot be prime.
Now x+3 is nothing but (2*3*... 59) + 3. Rewriting this as {3 * (2 * 5*.... 59)} +3.
One can observe here that the term in the curly brace is a multiple of 3 and that term plus 3 will definitely be a multiple of 3 .
(Multiple of 3 + 3 is a multiple of 3, Multiple of 59 + 59 is a multiple of 59)
As x+3 is a multiple of 3 it cannot be a prime.
Similarly x+5 can be written as {5 * (2 * 3* 7*.... 59)} +5 which is a multiple of 5.
ANSWER:A
Question: In a certain egg-processing plant, every egg must be inspected, and is either accepted for processing or rejected. For every 96 eggs accepted for processing, 4 eggs are rejected. If, on a particular day, 12 additional eggs were accepted, but the overall number of eggs inspected remained the same, the ratio of those accepted to those rejected would be 99 to 1. How many W eggs does the plant process per day?
A. 100
B. 300
C. 400
D. 3,000
Answer: C. 400
Explanation: Straight pluggin in for me. As usual, I started with C and got the answer.
Lets' back calculate and see what we get
Let us consider eggs processed each day to be 400
So Initial ratio of eggs processed and rejected is 96:4 or 24:1
So out of 400 eggs, there will be 384 eggs processed and 16 rejected.
Now if the no. of eggs inspected remain and 12 more eggs get accepted that means there W= 384+12=396 eggs accepted and 4 rejected...and the ratio will be 99:1
Bingo...this is what the questions says....
Its always a good idea to start with C.
Question: A starts a business with Rs.3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the capital?
A.Rs.7500
B.Rs.8000
C.Rs.8500
D.Rs.9000
Answer: D.Rs.9000
Explanation: Solution
Let B's capital be Rs.x. Then,	3500×12 ⁄ 7x
=2⁄3
‹=›14x = 126000
x = 9000.
Answer D
Question: The surface area of a sphere is same as the curved surface area of a right circular cylinder whose height and diameter are 12 cm each. The radius of the sphere is
A.3 cm
B.4 cm
C.6 cm
D.8 cm
Answer: C.6 cm
Explanation: Solution
4ΠR2	= 2Π6x12
⇒ R2 = (6x12/2)
⇒ 36
⇒ R = 6 cm.
Answer C
Question: If the cost price of 20 articles is equal to the selling price of 16 articles, What is the percentage of profit or loss that the merchant makes?
A.20% loss
B.25% profit
C.33.33 % loss
D.30.33% loss
Answer: B.25% profit
Explanation: Explanation :
Let Cost price of 1 article be Re.1.
Therefore, Cost price of 20 articles = Rs. 20.
Selling price of 16 articles = Rs. 20
Therefore, Selling price of 20 articles is :-
=>20/16×20
=>25.
Therefore, Profit = Selling price - Cost price.
=>25−20=5.
Hence, the percentage of profit = profit x 100/C.P.
=>5/20×100.
=>25% Profit.
Answer : B
Question: A candidate who gets 30% of the marks fails by 50 marks. But another candidate who gets 45% marks gets 25 marks more than necessary for passing. Find the number of marks for passing?
A.150
B.200
C.250
D.275
Answer: B.200
Explanation: 30% ------------ 50
45% ------------ 25
----------------------
15% ------------- 75
30% -------------- ?
150 + 50 = 200 Marks
ANSWER:B
Question: 80% of the population of Albany Town lived in the East at the Beginning of the Year 1998 and the rest of the Town lived in the North. During the year 1998, the population of Town Albany grew by 9%. If the population in the East grew by 5.5%, by how much did the population in the North grow?
A.23%
B.23.5%
C.25%
D.11.25%
Answer: A.23%
Explanation: I prefer the weighted average method over dealing with creating and solving the algebraic expression:
Ratio of population in Albany Town = East:North :: 80%:20% = 4:1
Mean growth = 9.0%
East Growth: 5.5%
North Growth = ??
East-------------Average--------------North
5.5% __(1n)_____9.0%_____(4n)_____??
Since:
5.5 + 1n = 9
n = 3.5
Therefore:
North = 9 + 4n
North = 9 + 4(3.5) = 23%
The Population increased in the North of the Albany Town is 23% during 1998
Question: The cost of 6 bags and 8 purses is Rs.1300, what is the cost of 10 bags and 30 purses?
A.Rs.3600
B.Rs.3500
C.Rs.3800
D.Rs.3250
Answer: D.Rs.3250
Explanation: Explanation:
Cost of 6 bags + 8 purses = Rs.1300
Multiply each term by 5/2, we get,
Cost of 10 bags + 30 purses = Rs.3250.
Answer: Option D
Question: The Sum of first N consecutive odd integers is N^2. What is the sum of all odd integers between 11 and 41 inclusive.
A.351
B.364
C.416
D.424
Answer: C.416
Explanation: We're dealing with a sequence of CONSECUTIVE ODD INTEGERS: 11 to 41, inclusive. We're asked for the SUM of this group.
1) Start with the sum of the smallest and the biggest: 11 + 41 =52
2) Now look at the 'next smallest' and the 'next biggest': 13 + 39 = 52
Now we have proof that there is no middle term. We have 8 bunches of 52.
8(52) = 416
C
Question: Two twins sisters Sita and Geeta were standing back to back and suddenly they started running in opposite directions for 12 km each. Then they turned left and ran for another 9 km.
What is the distance (in kilometers) between the the two twins when they stop?
A.26
B.28
C.30
D.32
Answer: C.30
Explanation: The distance between them is the hypotenuse of a right angle triangle with sides 18 km and 24 km. The hypotenuse = sqrt(18^2 + 24^2) = 30
The answer is C.
Question: If 4a = 16b and 9b = 13c, Find a:b:c?
A.52:13:7
B.13:7:52
C.7:13:52
D.7:13:54
Answer: A.52:13:7
Explanation: Explanation:
(4a = 16b ==> a/b = 16/4)
and (9b = 13c ==> b/c = 13/7)
==> a:b = 16:4 and b:c = 13:7
a:b:c = 208:52:28 = 52:13:7
Answer: Option A
Question: In a certain mathematical activity, we start with seven cards, each with a different prime number written on it. These seven cards are randomly put into three boxes in the following way: one box must get four cards, one must get two, and one gets only one. Then, for each box, we find the product of all the cards in the box, and that’s the “number” of the box. Then, we put those three numbers in order, from lowest to highest, and that is our set. How many different sets Q can be created from this process?
A. 35
B. 105
C. 210
D. 420
Answer: B. 105
Explanation: Q=7C4 * 3C2 = 105 Answer B.
7C4 ways to choose 4 numbers for Box 1
3C2 ways to choose 2 numbers for Box2
1 way for Box 3 .B
Question: Given two fair dice, what is the probability that the sum of their numbers is 4 if exactly one die shows a 3?
A.2/11
B.1/18
C.3/11
D.2/39
Answer: A.2/11
Explanation: P(A|B) = Probability of event A occurring such that event B has already occurred
= P(A & B) / P(B)
Here, event A is getting a sum of 4
we'll have 3 possibilities : (1,3), (2,2), (3,1)
Event B => one of the 2 dices already shows a 3 [NOTE : there is NO restriction on the other dice => both dices CAN throw a 3]
we'll have 11 possibilities : (1,3),(2,3),(3,3),(4,3),(5,3),(6,3),(3,1),(3,2),(3,4),(3,5),(3,6)
So, P(B) = 11/36
Event A & B occurring => 2 possibilities => (1,3) & (3,1)
So, P(A & B) = 2/36
Therefore P(A|B) = 2/11
ANSWER:A
Question: The age of Somu is one-third his father's. 6 years back he was one-fifth of his father's age. What is his persent age ?
A.11
B.13
C.14
D.12
Answer: D.12
Explanation: Explanation :
Let Somu's age be x and that of his father be 3x.
So, x - 6 = 3x - 6/5 = x = 12
Answer : Option D
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?
A.30/19
B.30/17
C.30/18
D.30/13
Answer: D.30/13
Explanation: Speed downstream = 20 + 6 = 26 kmph.
Time required to cover 60 km downstream = d/s = 60/26 = 30/13 hours.
Answer: D
Question: What is the maximum number of pieces of birthday cake of size 10” by 10” that can be cut from a cake 20” by 20”?
A.4
B.10
C.16
D.20
Answer: A.4
Explanation: The prompt is essentially asking for the maximum number of 10 x 10 squares that can be cut from a larger 20 by 20square. Since each 'row' and each 'column' of the larger square can be sub-divided into 2 'pieces' each, we have (2)(2) = 4 total smaller squares (at maximum).
A
Question: Three numbers are in the ratio 5 : 6 : 9. The sum of its longest and smallest numbers equals the sum of the third number and 48. Find the third number?
A.A)30
B.B)75
C.C)48
D.D)46
Answer: A.A)30
Explanation: Let the numbers be 5x, 6x, 9x.
Largest number = 9x.
Smallest number = 5x.
Third number = 6x.
9x + 5x = 6x + 48
8x = 48 =>x=6
5x=30=> third number is 48.
Answer:A
Question: The average age 11 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
A.18
B.22
C.77
D.26
Answer: B.22
Explanation: 11 * 2 = 22 years
Answer: B
Question: Which of the following are/is prime?
I. 143
II. 147
III. 145
A. II only
B. III only
C. III
D. IIII
Answer: D. IIII
Explanation: 1) 143 = 13*11 so we know it is not prime quickly eliminate all options having 1 as a choice
which leaves us with 2 ) and 3) as possible answers
From here on we find 147 = 3* 49 so we eliminate 147 which leaves us with 149 as the only possible solution D
Question: A certain bakery has 6 employees. It pays annual salaries of $17,000 to each of 2 employees, $19,000 to 1 employee, and $20,000 to each of the remaining 3 employees. Which number is closest to the average (arithmetic mean) annual salary of these employees?
A.$18,200
B.$18,500
C.$18,800
D.$19,000
Answer: C.$18,800
Explanation: average = 2(17000)+(19000)+3(20000) / 6 = $18,833
The answer is C.
Question: The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?
A.3629
B.3608
C.3600
D.3613
Answer: C.3600
Explanation: P = 144(100/5)2 => P
= 3600
Answer:C
Question: The price of pulses has fallen by 18%. How many quintals can be bought for the same amount which was sufficient to buy 16 quintals at the higher price?
A.20.5
B.22.5
C.19.5
D.18.4
Answer: C.19.5
Explanation: 80% of original price can buy = 16 quintals.
Therefore, he can buy ( 16 x 100 )/ 82 = 19.5 quintals at the lower price.
ANSWER:C
Question: What is the value of 4^5+4^6?
A. 5(4^5)
B. 4^35
C. 17(4^5)
D. 8^12
Answer: A. 5(4^5)
Explanation: 4^5+4^6
=4^5(1+4^1)
=4^5 * 5
Answer A
Question: If A =x% of y and B =y% of x, then which of the following is true?
A.None of these
B.A is smaller than B
C.Relationship between A and B cannot be determined
D.If x is smaller than y, then A is greater than B
Answer: A.None of these
Explanation: Explanation:
A =x/100×y=xy/100 ⋯(1)
B = y/100×x=yx/100 ⋯(2)
Therefore A = B
ANSWER IS A
Question: Tim bought a new machine to help him picking apples from apple trees. If this new machine can pick 20 apples every 30 minutes and Tim wants to pick 500 apples today. How many hours he is going to take?
A.10
B.12.5
C.15
D.17.5
Answer: B.12.5
Explanation: The machine picks 20 apples every 30 minutes = 40 apples/hour. 500 apples is going to take 500/40 apples/hour = 12.5 hours. Correct Option: 12.5. Answer: B
Question: If the median of a list of numbers is m, the first quartile of the list is the median of the numbers in the list that are less than m. What is the first quartile of the list of numbers 42, 23, 30, 22, 26, 19, 33 and 35 ?
A.33
B.28
C.22.5
D.24
Answer: C.22.5
Explanation: It is given that a quartile is the middle number of all numbers less than median..
so lets arrange the number in ascending order- 42, 23, 30, 22, 26, 19, 33 and 35
19, 22, 23, 26, 30 , 33, 35, 42...
numbers less than median are 19, 22, 23, 26 ..
the median of these numbers = center of 22 and 23 = 22.5
C
Question: In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 30 percent, but profits were 20 percent of revenues. The profits in 1999 were what percent of the profits in 1998?
A.80%
B.105%
C.140%
D.124.2%
Answer: C.140%
Explanation: 0,14R = x/100*0.1R
Answer C
Question: A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 5 km/hr. find the time taken by the boat to go 68 km downstream?
A.2 hours
B.3 hours
C.3 hours 48 minutes
D.5 hours
Answer: C.3 hours 48 minutes
Explanation: Solution
Speed Downstream	= (13 + 5) km/hr
= 18 km/hr.
Time taken to travel 68 km downstream	=(68 / 18)hrs
= 3 hrs 48 minutes.
Answer C
Question: a school has 7 maths 6 physics and 5 chemistry teachers each teacher can teach 3 subjects max what is he minimum number of teachers required
A.3
B.5
C.6
D.7
Answer: C.6
Explanation: Total subjects = 7+6+5=18
Max subjects by 1 teacher = 3
So, min of teachers required = 18/3 = 6
ANSWER:C
Question: Two trains of length 120 m and 320 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?
A.10 sec
B.22 sec
C.82 sec
D.20 sec
Answer: B.22 sec
Explanation: Relative speed = (42 + 30) * 5/18 = 4 * 5 = 20 mps.
Distance covered in passing each other = 120 + 320 = 440 m.
The time required = d/s = 440 /20 = 22 sec.
Answer:B
Question: A wholesaler wishes to sell 100 pounds of mixed nuts at $2.00 a pound. She mixes peanuts worth $1.50 a pound with cashews worth $4.00 a pound. How many pounds of cashews must she use?
A.40
B.45
C.50
D.55
Answer: C.50
Explanation: From the question stem we know that we need a mixture of 100 pounds of peanuts and cashews. If we represent peanuts as x and cashews as y, we get x + y = 100. Since the wholesaler wants to sell the mixture of 100 pounds @ $2.50, we can write this as: $2.5 * (x + y) = $1.5x + $4y
From the equation x + y = 100, we can rewrite y as y = 100 - x and substitute this into our equation to get:
$2.5 * (x + 100 - x) = $1.5x + $4(100 - x)
If you solve for x, you will get x = 60, and therefore y = 40. So the wholesaler must use 40 pounds of cashews.
You can substitute into the original equation to see that: $250 = $1.5(60) + $4(40)
Answer is C.
Question: A train crosses a platform of 170 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
A.70
B.88
C.167
D.197
Answer: A.70
Explanation: Length of the train be ‘X’
X + 170/15 = X + 250/20
20X + 3400 = 15X + 3750
5x=350
X = 70m
Answer: A
Question: When 4 fair coins are tossed simultaneously, in how many outcomes will the first and the last coin turn up heads?
A.1
B.4
C.8
D.31
Answer: B.4
Explanation: Total outcome is 2^4 = 16
Favourable cases = H_ _ H
The second and third places can be occupied by either H or T
There are 2^2 =4 ways that can be done.
Hence, the correct option is B
Question: A $79.95 lawn chair was sold for $59.95 at a special sale. By approximately what percent was the price decreased?
A.15%
B.20%
C.25%
D.60%
Answer: C.25%
Explanation: Listed selling price of chair = 79.95 $
Discounted selling price of chair = 59.95 $
Discount = 79.95 - 59.95 = 20 $
% decrease in price of chair = (20/79.95) * 100% = 25 % approx
Answer C