RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A starts a business with a capital of Rs. 85,000. B joins in the business with Rs.42500 after some time. For how much period does B join, if the profits at the end of the year are divided in the ratio of 3 : 1?
A.8 months
B.9 months
C.1months
D.12months
Answer: A.8 months
Explanation: Let B joins for x months. Then
A:B = 85000*12 : x* 42500 = 3 : 1
=> 850*12 : 425x= 3 : 1
=> 850*12/ 425x = 3/1 = 3
=> 850*4 /425x = 1
=> 2*4/x = 1
=> x = 8
Answer is A
Question: Of three numbers, the third is four times the second and the second is two times the first. If their average is 165, the smallest of the three numbers is:
A.18
B.19
C.45
D.21
Answer: C.45
Explanation: Explanation:
Let first number be x.
So,2nd no. = 2x & 3rd no.=8x.
So,x+2x+8x=165 × 3 = 495
11x = 495/11
x = 495/11
Hence,smallest Number x=45
Answer: C
Question: Using all the letters of the word "NOOKIASS", how many words can be formed, which begin with N and end with S?
A.550
B.160
C.720
D.620
Answer: C.720
Explanation: There are five letters in the given word.
Consider 8 blanks ....
The first blank and last blank must be filled with N and S all the remaining three blanks can be filled with the remaining 6 letters in 6! ways.
The number of words = 6! = 720.
Answer: C
Question: A 75m long train is running at 54 km/hr. In how much time will it cross an electric pole?
A.5
B.10
C.15
D.20
Answer: A.5
Explanation: Speed of the train = ( 54 * 5 / 18) m/sec = 15 m / sec. Length of the train = (Speed x Time)
Time = (Length of the train / Speed)
=(75/ 15) = 5sec
Answer: A
Question: At what time between 9’o clock and 10’o clock will the hands of a clock point in the opposite directions?
A.16 4⁄11 minutes past 9
B.16 4⁄11 minutes past 8
C.55 5⁄61 minutes past 7
D.55 5⁄61 minutes past 8
Answer: A.16 4⁄11 minutes past 9
Explanation: At 9’o clock, the Minute Hand is ahead of Hour Hand by 45 minutes. The hands will be opposite to each other when there is a space of 30 minutes between them.
This will happen when the Minute Hand gains 15 minutes space over Hour Hand.
Time taken by Minutes Hand to gain 15 minutes
= 15 × (1 + 1⁄11) = 15 + 15⁄11 = 15 + 14⁄11 + 16 4⁄11 minutes.
Hence the Hands are opposite to each other at 16 4⁄11 minutes past 9.
Answer A
Question: Lina works 10 days a month at d dollars per day for m months out of the year. Which of the following represents her monthly pay?
A.m/(10d)
B.5md/6
C.10d
D.10d/m
Answer: B.5md/6
Explanation: Total income of Lina in a year = d*10*m dollars. Now Monthly income = Total/12 = d*10*m / 12 = 5md/6 Answer is B
Question: If 9x^2-16y^2=3x+4y,then what will give the answer?
A.3x-4y=0
B.3x-4y=2
C.3x-4y=1
D.3x+4y=0
Answer: C.3x-4y=1
Explanation: 9x^2-16y^2=3x+4y
(3x+4y)(3x-4y)=3x+4y
3x-4y=(3x+4y)/(3x+4y)
3x-4y=1
Answer is option C
Question: During one month at a particular restaurant, 1/5 of the burgers sold were veggie burgers and 1/4 of the rest of the burgers sold were double-meat. If x of the burgers sold were double-meat, how many were veggie burgers?
A.x/8
B.x
C.2x/3
D.3x/4
Answer: B.x
Explanation: Let y be the number of total burgers.
veggie = y/5 , non veggie = 4y/5
1/4 of the rest of the burgers sold were double-meat
=> 4y/5 * 1/4 = double meat = x
=> y/5 = x= veggie
Hence B
Question: A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
A.15 sec
B.16 sec
C.18 sec
D.20 sec
Answer: B.16 sec
Explanation: Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 280 * 2/35 = 16 sec
ANSWER:B
Question: Tough and Tricky questions: Work/Rate Problems.
A group of 4 junior lawyers require 3 hours to complete a legal research assignment. How many hours would it take a group of three legal assistants to complete the same research assignment assuming that a legal assistant works at two-thirds the rate of a junior lawyer?
Source: Chili Hot GMAT
A.13
B.10
C.9
D.6
Answer: D.6
Explanation: # of people times the # of hours:
4*3 = 12 --> 3 lawyers do 12worksin 3 hours.
3*6/3 = 6 --> 3 assistants do 6 worksin 2 hours
So, since the amount of work the assistants do is half the work the lawyers do, the time will be double, soANS D
Question: A bowl contains 3 parts of which are milk and 5 parts water. How much of the mixture must be drawn off and replaced with milk sothat the mixture may be half milk and half water?
A.2/5
B.3/5
C.1/5
D.1/7
Answer: C.1/5
Explanation: Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture = 3 -	3x	+ x litres
8
Quantity of syrup in new mixture = 5 -	5x litres
8
3 -	3x	+ x = 5 -	5x
8	8
5x + 24 = 40 - 5x
10x = 16
x =	8	.
5
So, part of the mixture replaced = 8	x	1 =	1/5
5	8	5
C
Question: Mr. Smith calculated the average of 10three digit numbers. But due to a mistake he reversed the digits of a number and thus his average increased by 59.4. The difference between the unit digit and hundreds digit of that number is :
A.a) 6
B.b) 3
C.c) 2
D.d) 1
Answer: A.a) 6
Explanation: Since the average increased by 59.4 and there were a total of 10 numbers, it means the incorrect number was 594 greater than the correct number.
Say, the correct number was abc (where a, b and c are the digits of the 3 digit number)
Then the incorrect number was cba.
100c + 10b + a - (100a + 10b + c) = 594
99c - 99a = 99(c - a) = 594
594 = 99*6 = 99(c - a)
So c - a = 6
Answer (A)
Question: A crate of apples contains 1 bruised apple for every 30 apples in the crate. Three out of every 4 bruised apples are considered not fit to sell, and every apple that is not fit to sell is bruised. If there are 15 apples not fit to sell in the crate, how many apples are there in the crate?
A.270
B.360
C.480
D.600
Answer: D.600
Explanation: as given 3 out of every 4 bruised apple is not fit to sell
or, 75% of the bruised apples are not fit to sell.
as per the question 15 are not fit to sell
or,
0.75x=15
x=1500/75=20
thus total number of bruised apples =20
total number of apples =30*20=600
Answer: D
Question: Find the SI on Rs 8000 for 4 yrs at 10% per annum rate of interest?
A.Rs 3000
B.Rs 3500
C.Rs 4000
D.Rs 4400
Answer: C.Rs 4000
Explanation: Simple Interest =
PTR
100
= 8000 X 5 X
10
100
= Rs 4000
C
Question: In the xy-coordinate plane, the graph of y = -x^2 + 9 intersects line L at (p,5) and (t,-8). What is the least possible value of the slope of line L?
A.-6.5
B.2
C.-2
D.-6
Answer: A.-6.5
Explanation: We need to find out the value of p and L to get to the slope.
Line L and Graph y intersect at point (p,5). hence, x= p and Y=5 should sactisfy the graph. soliving
5 = -p2 +9
p2 = 4
p = + or - 2
simillarly point (t,-8) should satisfy the equation. hence x=t and Y=-8.
-7 = -t2+9
t = +or - 4
considering p = -2 and t =4, the least slope is (-8-5)/(4-2) = -6.5
IMO option A is correct answer.
Question: A began a business with Rs.85,000. He wasjoined afterwards by B with Rs.42,500. For how muchperiod does B join, if the profits at the end of the yr are dividedin the ratio of 3:1?
A.5 months
B.8 months
C.9 months
D.11 months
Answer: B.8 months
Explanation: Suppose B joined for x months. Then,
Then, 85000 x 12	=	3
42500 x x	1
x = 85000 x 12 = 8.
42500 x 3
So, B joined for 8 months.
B
Question: A batsman makes a score of 56 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning?
A.25
B.8
C.27
D.29
Answer: B.8
Explanation: Let the average after 17 innings = x
Total runs scored in 17 innings = 17x
Average after 16 innings = (x-3)
Total runs scored in 16 innings = 16(x-3)
Total runs scored in 16 innings + 56 = Total runs scored in 17 innings
=> 16(x-3) + 56 = 17x
=> 16x - 48 + 56 = 17x
=> x = 8
Answer is B.
Question: At present, the ratio between the ages of Arun and Deepak is 4:3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present?
A.15
B.12
C.13
D.18
Answer: A.15
Explanation: Let the present ages of Arun and Deepak be 4x and 3x years respectively.
Then, 4x + 6 = 26 => x = 5
Deepak's age = 3x = 15 years.
ANSWER A
Question: If x is real, find the maximum value of the expression -2x^2 + 9x + 11.
A.12.125
B.15.125
C.18.125
D.21.125
Answer: D.21.125
Explanation: This is an equation of a downward facing parabola.
The maximum value is the top point of the parabola.
-2x^2+9x+11 = (-2x+11)(x+1)
The roots are 11/2 and -1.
The maximum value must be when x is halfway between these two points.
x = 2.25
The maximum value is -2(2.25)^2+9(2.25)+11 = 21.125
The answer is D.
Question: A pump can fill a tank with water in 4 hours. Because of a leak, it took 7 hours to fill the tank. The leak can drain all the water in ?
A.15hr 10min
B.16hr 20min
C.9hr 20min
D.15hr
Answer: C.9hr 20min
Explanation: Work done by the leak in 1 hour = 1/4 - 1/7 = 3/28
Leak will empty the tank in 28/3 hrs = 9hr 20min
Answer is C
Question: A box contains five bulbs out of which 3 are defective. If four bulbs are chosen at random, find the probability that atleast one bulb is good.
A.39/10
B.29/10
C.19/10
D.9/10
Answer: D.9/10
Explanation: Required probability
= 1 - 1/10
= 9/10
Answer: D
Question: The L.C.M. of 2 numbers is 30. The numbers are in the ratio 2:3. Find their sum?
A.36
B.25
C.48
D.32
Answer: B.25
Explanation: Let the numbers be 2x and 3x
L.C.M. = 6x
6x = 30
x = 5
The numbers are = 10 and 15
Required sum = 10+15 = 25
Answer is B
Question: If an average hard drive had a capacity of 0.4 TB in 2000, and average hard drive capacities double every 5 years, what will be the average hard drive capacity in 2050?
A.256
B.512
C.4096
D.1024
Answer: C.4096
Explanation: 0.4*2^10=0.4*1024=409.6
The answer is C.
Question: A new tower has just been built at the Verbico military hospital; the number of beds available for patients at the hospital is now 4 times the number available before the new tower was built. Currently, 1/3 of the hospital's original beds, as well as 1/5 of the beds in the new tower, are occupied. For the purposes of renovating the hospital's original wing, all of the patients in the hospital's original beds must be transferred to beds in the new tower. If patients are neither admitted nor discharged during the transfer, what fraction of the beds in the new tower will be unoccupied once the transfer is complete?
A.11/30
B.29/60
C.17/30
D.31/45
Answer: D.31/45
Explanation: I think D - 31/45 is the correct answer.
Here goes:
Lets assume originally the number of beds = x
After the new tower, the total combined no of beds = 4x
So old = x, New = 3x
Now 1/3 of x are occupied and 1/5 of 3x are occupied which simplifies to (3/5)x
We are shifting 1/3 of x to the new ward so there will now be:
1/3 of x plus 3/5 of x occupied in the new ward. Add them up to get 14/15 of x
There are 3x beds in New Tower so ratio is:
(14/15)x / 3x = 14/45 of x
Subtract that from 45/45 of x and you get the number of un-occupied beds to total capacity of New Tower =31/45
D
Question: A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
A.20%
B.30%
C.35%
D.40%
Answer: B.30%
Explanation: Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = 0.59x x 100 % = 30% (approx.)
2x
B)
Question: Find the number which is nearest to 3105 and is exactly divisible by 21.
A.3104
B.3106
C.3108
D.3109
Answer: C.3108
Explanation: On dividing 3105 by 21, we get 18 as remainder.
Number to be added to 3105 = (21 - 18) - 3.
Hence, required number = 3105 + 3 = 3108.
ANSWER C 3108
Question: The Royal Hawaiian Hotel decorates its Rainbow Christmas Tree with non-flashing white lights and a series of colored flashing lights - red, blue, green, orange, and yellow. The red lights turn red every 20 seconds, the blue lights turn blue every 30 seconds, the green lights turn green every 45 seconds, the orange lights turn orange every 60 seconds, and yellow lights turn yellow every 1 minute and 20 seconds. The manager plugs the tree in for the first time on December 1st precisely at midnight and all lights begin their cycle at exactly the same time. If the five colored lights flash simultaneously at midnight, what is the next time E all five colored lights will all flash together at the exact same time?
A.0:03 AM
B.0:04 AM
C.0:06 AM
D.0:12 AM
Answer: D.0:12 AM
Explanation: Time taken by each light to on
Red = 20 secs
Blue = 30 secs
Green = 45 secs
Orange = 60 secs
Yellow = 80 secs
We need to take LCM to find the time all five colored lights will flash together.
LCM = 720 secs
=12 mins
=0.12 AM
Ans = D
Question: If 7% of the sale price of a watch is equivalent to 8% of its cost price and 9% of its sale price exceeds 10% of its cost price by Re 1, then what is the cost price of the watch?
A.Rs 400
B.Rs 350
C.Rs 300
D.Rs 280
Answer: B.Rs 350
Explanation: Let C.P. = X and S.P. = Y
=> 7 % of Y = 8% of X and 9% of Y =10% of X + 1
=> 7Y = 8X and 9Y = 10X + 100
=> 9 x (8X / 7) = 10 X + 100
=> X = Rs. 350
ANSWER:B
Question: Ratio between two numbers is 3: 4 and their sum is 420. Find the smaller number?
A.150
B.125
C.140
D.180
Answer: D.180
Explanation: 3x+4x = 420
x=60== 3x=180
ANSWER D
Question: A 2member committee comprising of one male & one female member is to be constitute out of 5 males and 3females. Among st the females. Ms.A refuses to be a member of the committee in which Mr.B is taken as the member. In how many different ways can the committee be constituted ?
A.10
B.14
C.16
D.18
Answer: B.14
Explanation: 5C1 * 3C1 -1
= 15-1
= 14
B
Question: The speed of a boat in still water in 42 km/hr and the rate of current is 8 km/hr. The distance travelled downstream in 44 minutes is:
A.86.6 km
B.46.6 km
C.36.6 km
D.35.6 km
Answer: C.36.6 km
Explanation: Speed downstream = (42 + 8) = 50 kmph
Time = 44 minutes =44/60 hour = 11/15 hour
Distance travelled = Time × speed =11/15×50 = 36.6 km
ANSWER:C
Question: In a graduating class of 232 students, 144 took geometry and 119 took biology. What is the difference between the greatest possible number P and the smallest possible number of students that could have taken both geometry and biology?
A.144
B.119
C.113
D.88
Answer: D.88
Explanation: OFFICIAL SOLUTION:
First of all, notice that since 144 took geometry and 119 took biology, then the number of students who took both geometry and biology cannot be greater than 119.
{Total} = {geometry} + {biology} - {both} + {neither};
232 = 144 + 119 - {both} + {neither};
{both} = 31 + {neither}.
{both} is minimized when {neither} is 0. In this case {both} = 31.
The greatest possible number of students P that could have taken both geometry and biology, is 119.
Thus, the answer is 119 - 31 = 88.
Answer: D.
Question: Anand and Deepak started a business investing Rs. 40,000 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Deepak's share is?
A.2777
B.2888
C.6440
D.2882
Answer: C.6440
Explanation: Ratio of their shares =40000 : 35000 = 8:7
Deepak's share = 13800 * 7/15 = Rs. 6440.
Answer: C
Question: Oranges are bought at 7 for Rs.2. At what rate per hundred must they be sold to gain 33%?
A.27
B.38
C.39
D.44
Answer: B.38
Explanation: 7 oranges bought for rs 2
1 orange cost =2/7
therefore for 100 oranges =100*(2/7)
gain =33%
200/7+(33/100)*200/7=rate per hundred he want to sell
ans :38
ANSWER:B
Question: A metal company's old machine makes bolts at a constant rate of 100 bolts per hour. The company's new machine makes bolts at a constant rate of 150 bolts per hour. If both machines start at the same time and continue making bolts simultaneously, how many minutes will it take the two machines to make a total of 350 bolts?
A. 84
B. 72
C. 120
D. 144
Answer: A. 84
Explanation: Old Machine
100 bolts in 60 mins
so,
5/3 bolts in 1 min
New Machine
150 bolts in 60 mins
so,
5/2 bolts in 1 min
together,
5/3 + 5/2 =
25/6 bolts in 1 min
so, for 350 bolts
350 * 6 / 25 = 84 mins
Ans A
Question: A math teacher has 25 cards, each of which is in the shape of a geometric figure. Half of the cards are rectangles, and a third of the cards are rhombuses. If 8 cards are squares, what is the maximum possible number of cards that re circles.
A.8
B.10
C.11
D.12
Answer: A.8
Explanation: a square is a special kind of rhombus (sides are perpendicular)
a square is a special kind of rectangles (sides with same length)
Among the 25 cards with have:
15 rectangles
10 rhombus
8 squares
Among the 15 rectangles, there could be 8 special ones (with sides of same length) that are squares. That lets at least 7 rectangles that are not square.
Among the 10 rectangles, there could be 8 special ones (with sides perpendicular) that are squares. That lets at least 2 rhombus that are not square.
We have 8 squares.
So the minimum different cards that represent a square, a rhombus or a rectangle is 2 + 7 + 8 = 17
Which means that the maximum number of circles that you could have is 25 - 17 = 8
Answer (A)
Question: If x and y are positive integers greater than 1 such that x – y and x/y are both even integers, which of the following numbers must be non-prime integers?
I. x
II. x + y
III. y/x
A.I only
B.II only
C.III only
D.I and II
Answer: D.I and II
Explanation: Ans:
from the conditions given to us we get x>y and the min value of y can be 2 , therefore x will be a multiple of 4 so both I and ii will always be non-prime but iii will not be an integer. Answer (D).
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions.
A.288
B.704
C.777
D.662
Answer: B.704
Explanation: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm = 704 m
Answer:B
Question: Nine carpenters can individually complete a particular task in 3, 4, 5, and 7 hours, respectively. What is the maximum fraction of the task that can be completed in forty-five minutes if eight of the carpenters work together at their respective rates ?
A.11/15
B.3/5
C.11/30
D.47/135
Answer: D.47/135
Explanation: Farmer A, B, C, and D
A's rate: 1/3 job/hour
B's rate: 1/4 job/hour
C's rate: 1/5 job/hour
D's rate: 1/7 job/hour
By intuition we know that the three fastest farmers are A B and C.
As such
(1/3 + 1/4 + 1/5)*(8/9) = ?
47/135 or (D)
Question: A train speeds past a pole in 15 sec and a platform 110 m long in 25 sec, its length is?
A.100
B.150
C.160
D.165
Answer: D.165
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 110)/25 = x/15 => x = 165 m.
Answer: Option D
Question: An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases.
A.8:8
B.8:7
C.8:2
D.8:1
Answer: B.8:7
Explanation: Let the length and breadth of the carpet in the first case be 3x units and 2x units respectively.
Let the dimensions of the carpet in the second case be 7y, 3y units respectively.
From the data,.
2(3x + 2x) = 2(7y + 3y)
=> 5x = 10y
=> x = 2y
Required ratio of the areas of the carpet in both the cases
= 3x * 2x : 7y : 3y
= 6x2 : 21y2
= 6 * (2y)2 : 21y2
= 6 * 4y2 : 21y2
= 8 :7
Answer:B
Question: Sneha went to the stationers and bought things worth Rs. 50, out of which 50 paise went on sales tax on taxable purchases. If the tax rate was 5%. then what was the cost of the tax free items?
A.Rs. 39.60
B.Rs. 39.50
C.Rs. 39.80
D.Rs. 49.50
Answer: B.Rs. 39.50
Explanation: Solution
Let the amount of taxable purchases be Rs.x.
Then, 5% of x	= 50/100
x ‹=› (50/100×100/5)
= 10
Cost of tax free items	= Rs.[50 - (10 + 0.50)]
= Rs. 39.50
Answer B
Question: How Many 7â€™s are there in the following sequence which are immediately preceded by 6 but not immediately followed by 4?
6 7 4 2 7 4 9 3 6 7 1 9 4 7 2 9 6 7 1 3 6 7 4 3 6
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: Answer: B . 2
Question: If 31/198 = 0.1565, what is the 97nd digit to the right of the decimal point of the fraction?
A.1
B.2
C.6
D.7
Answer: C.6
Explanation: we are not concerned what 31/198 means..
we have to look at the decimal..
0.1565 means 0.1565656....
so leaving girst and second digit to the right of decimal, all ODD numbered are 6 and all EVEn numbered are 5..
here 97 is ODD, so ans is 6
C
Question: A drink vendor has 10 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required?
A.135
B.261
C.422
D.430
Answer: B.261
Explanation: The number of liters in each can = HCF of 10, 144 and 368 = 2 liters.
Number of cans of Maaza = 10/2 = 5
Number of cans of Pepsi = 144/2 = 72
Number of cans of Sprite = 368/2 = 184
The total number of cans required = 5 + 72 + 184 = 261 cans.
ANSWER:B
Question: What will be the difference in simple and compound interest on 5000 after three years at the rate of 10 percent per annum?
A.155
B.42
C.62
D.20
Answer: A.155
Explanation: For 3 years:
Diff.=Sum×(rate)2(300+rate)/(100)3
= 5000×10×10×310/100×100×100 = 155
Answer A
Question: How many such letter-pairs are there in the word MONKEY having same no. of letters left between them as they have in the series?
A.3
B.4
C.1
D.5
Answer: C.1
Explanation: only 1
i.e (n,o)
ANSWER:C
Question: 21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement?
A.9/31
B.8/45
C.9/42
D.8/111
Answer: C.9/42
Explanation: The probability that first toy shows the even number,
=1021=1021
Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.
Hence, probability that second toy shows the even number,
=920=920
Required probability,
=(1021)×(920)=(1021)×(920)
=9/42
C
Question: List R contains five numbers that have an average value of 70. If the median of the numbers in the list is equal to the mean and the largest number is equal to 20 more than two times the smallest number, what is the smallest possible value in the list?
A.28
B.31
C.34
D.37
Answer: C.34
Explanation: The middle number is 70.
Let the smallest number be x. Then the largest number is 2x+20.
To make x as small as possible, let's make the remaining numbers as large as possible.
So the second largest = the largest = 2x+20.
The second smallest should be equal to the median.
The numbers are x, 70, 70, 2x+20, 2x+20.
x + 70 + 70 + 2x + 20 + 2x + 20 = 5*70 = 350
5x = 170
x = 34
The answer is C.
Question: The number of arrangements that can be made with the letters of the word MEADOWS so that the vowels occupy the even places?
A.122
B.134
C.144
D.156
Answer: C.144
Explanation: Explanation:
The word MEADOWS has 7 letters of which 3 are vowels.
-V-V-V-
As the vowels have to occupy even places, they can be arranged in the 3 even places in 3! i.e., 6 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways.
Hence the total ways are 24 * 6 = 144.
C)
Question: Molly can do a task in 10 days while Sandy can do the task in 30 days. How many days will it take to complete the task if both work together?
A.4.5
B.6
C.7.5
D.8
Answer: C.7.5
Explanation: Each day, Molly can do 1/10 of the task.
Each day, Sandy can do 1/30 of the task.
Each day, they can do 1/10 + 1/30 = 2/15 of the task.
The task will be completed in 15/2 = 7.5 days.
The answer is C.
Question: Simplify: 72519 x 9999
A.725142989
B.725117481.
C.725117482
D.725111748
Answer: B.725117481.
Explanation: 72519 x 9999 = 72519 x (10000 - 1)
= 72519 x 10000 - 72519 x 1
= 725190000 - 72519
= 725117481.
Answer is B
Question: If p/q = 3/7 , then 2p+q= ?
A.12
B.14
C.13
D.15
Answer: C.13
Explanation: let p=3, q=7 then 2*3+7=13
so 2p+q=13.
ANSWER:C
Question: 3 candidates in an election and received 1136, 7636 and 11628 votes respectively. What % of the total votes did the winningcandidate got in that election?
A.34%
B.54%
C.57%
D.78%
Answer: C.57%
Explanation: Total number of votes polled = (1136 + 7636 + 11628) = 20400
So, Required percentage = 11628/20400 * 100 = 57%
C