RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 300 milliliters of solution X to create a solution that is 25 percent alcohol by volume?
A.250/3
B.500/3
C.900
D.480
Answer: C.900
Explanation: we know that X is 10% , Y is 30% and W.Avg = 25% . what does this mean with respect to W.Avg technique ?
W.Avg is 1 portion away from Y and 3 portion away from X so for every 1 portion of X we will have to add 3 portions of Y.
If X = 300 then Y = 900
ANSWER:C
Question: A mixture of 85 kg contains milk and water in the ratio 27 : 7. How much more water is to be added to
get a new mixture containing milk and water in the ratio 3:1?
A.5 kg
B.6.5 kg
C.7.5 kg
D.8 kg
Answer: A.5 kg
Explanation: Explanation :
Expl : Milk in 85 kg of mix = 85* (27/34) = 135/2 kg.
Water in it = 85-135/2 = 35/2 kg.
Let x kg of water be added to it.
Then, (135/2)/(35/2 + x) = 3/1; 135/(35 +2x) = 3/1;
105 + 6x = 135 ; 6x = 30; x = 5
The quantity of water to be added = 5 kg
Answer :A
Question: I chose a number and divide it by 5. Then I subtracted 154 from the result and got 6. What was the number I chose?
A.200
B.800
C.400
D.500
Answer: B.800
Explanation: Let x be the number I chose, then
x/5−154=6
x/5=160
x=800
Answer is B.
Question: If (n+2)!/n!=72, n=?
A.7
B.9
C.10
D.11
Answer: A.7
Explanation: (n+2)!/n!= 72
Rewrite as:[(n+2)(n+1)(n)(n-1)(n-2)....(3)(2)(1)]/[(n)(n-1)(n-2)....(3)(2)(1)]= 132
Cancel out terms: (n+2)(n+1) = 72
From here, we might just TEST the answer choices.
Since (9)(8) = 72, we can see that n = 7
A
Question: How many integers are between 4 and 88/9, inclusive?
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: 88/9 = 9.xx
We are not concerned about the exact value of 88/9 as we just need the integers.
The different integers between 4 and 88/9 would be 4, 5, 6, 7, 8, 9
Total number of integers = 6
Option D
Question: The sum of the two numbers is 14 and their product is 35. What is the sum of the reciprocals of these numbers?
A.12/35
B.14/35
C.35/8
D.7/32
Answer: B.14/35
Explanation: Let the numbers be a and b. Then, a+b=14 and ab =35.
a+b/ab=14/35; (1/b+1/a)=14/35
Sum of reciprocals of given numbers=14/35.
Correct Option: B
Question: What is the probability of rolling the same number exactly three times with five six-sided dice?
A.1/5
B.5/18
C.35/216
D.125/648
Answer: D.125/648
Explanation: Explanations:
1. Rolling any number on a dice three times in a row is equal to the number of throws {{1/6}^3}*6 = 1/36, where 3 represents the number of throws and 6 is the number of different ways to get three of the same number (e.g. 1, 1, 1 2, 2, 2 3, 3, 3…).
Next we have to use the combinations formula to determine how many ways three out of five can be the same. {5!}/{3!*2!}=10. We want to multiply this number to {1/36}*10=10/36
We are not finished yet – there is one little twist to the problem. The question says “exactly three times.” Meaning we have to discount all the instances in which we roll the same number four times and those instance in which we roll the same number five times.
One way to do so is by multiplying by the probability that the fourth and fifth dice will NOT land on the same number as the three dice. Because there are five other possibilities on dice that will not compromise “exactly three numbers” we can multiply by {5/6{*{5/6}=25/36
Finally this gives us {10/36}*{25/36}={125/648}
Answer D
Question: David and Rachel are getting married. The extended family wants to have its picture taken, but David's father is unwilling to stand next to Rachel's mother. How many options does the photographer have to arrange the 11 family members in a row for the picture?
A.12!
B.10×9!
C.9×10!
D.11!/2!
Answer: C.9×10!
Explanation: The number of ways to arrange 11 people is 11!
We need to subtract the arrangements when these two people are together.
Let's think of these two people as a single unit so there are 10 units.
The number of ways to arrange 10 units is 10!
We need to multiply this by 2 since these two people could switch places.
The total number of valid arrangements is 11! - 2*10! = 10!*(11-2) = 9x10!
The answer is C.
Question: If a light flashes every 10 seconds, how many times will it flash in 2/3 of an hour?
A.152
B.241
C.345
D.451
Answer: B.241
Explanation: There are 60 minutes in an hour.
In 2/3 of an hour there are (60 * 2/3) minutes = 40minutes.
In 2/3 of an hour there are (60 * 40) seconds = 2400 seconds.
Light flashed for every 10 seconds.
In 2400 seconds 2400/10 = 240 times.
The count start after the first flash, the light will flashes 241 times in 2/3 of an hour.
Answer:B
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
A.1 : 3
B.3 : 2
C.3 : 4
D.2 : 1
Answer: B.3 : 2
Explanation: Let the speeds of the two trains be S1 m/sec and S2 m/sec respectively. Then, length of the first train = 27S1 metres, and length of the second train = 17S2 metres.
∴ 27S1+17S2/S1+S2=23 ⇒ 27S1 + 17S2 = 23S1 + 23S2
⇒ 4S1 = 6S2 ⇒ S1⁄S2 = 3⁄2
Answer B
Question: Solve:-
444 x 444 x 444 + 555 x 555 x 555 = ?(444 x 444 - 444 x 555 + 555 x 555)
A.888
B.333
C.999
D.988
Answer: C.999
Explanation: Given Exp. = (a3 + b3) = (a + b) = (444 + 555) = 999(a2 - ab + b2)
Answer C
Question: If n is a 45-digit positive integer, all of whose digits are the same, which of the following must be true?
I. n is divisible by 3
II. n is divisible by 9
III. n is divisible by 5
IV n is divisible by 45
A.I only
B.I and II only
C.I and III only
D.I .II, III and IV only
Answer: D.I .II, III and IV only
Explanation: Rule for divisibility by 3: The sum of the digits of the number should be multiple of 3
Rule for divisibility by 9: The sum of the nos digits of the number should be divisible by 9 or the number should be divisible by 3 two times.
Rule for divisibility by 5: The sum of the digits of the number should be multiple of 5
Rules for divisibility by 45: The sum of the digits should a multiple of 45
Consider no 11111111...45 times = The sum 45*1=45----> divisbible by 3,9,5 and 45
consider number to be 222....45 times, then sum of the no. 45*2=90 divisibly by 3,9,5 and 45
So why so because when you sum the numbers either you can add the digits 45 times or multiply the digit *45..
Note that since 45 is divisble by 27,9 ,5 and 3 and thus the sum of the nos will be divisible by all the nos.
Ans is D
Question: How many different words beginning with O and ending with E can be formed with the letters of the word ORDINATE, so that the words are beginning with O and ending with E?
A.8!
B.6!
C.7!
D.7!/2!
Answer: B.6!
Explanation: Solution
6! ways, O fixed 1st and E fixed in last. Answer B
Question: What is the average (arithmetic mean) of the numbers 16, 17, 17, 18, 19, 19 and 20?
A.18
B.17
C.16
D.15
Answer: A.18
Explanation: {16, 17, 17, 18, 19, 19, 20}={18-2,18-1,18-1, 18, 18+1, 18+1,18+2} --> the average = 18.
Answer: A.
Question: Joe is painting a rectangular room whose dimensions are given by a, b and c meters. Joe takes 4 hours to paint a wall with dimensions a and c. He takes 2 hours to paint a wall with dimensions b and c and 6 hours to paint the ceiling with dimensions a and b. If Joe works at a constant rate and a = 6, then what is the volume of the room?
A.18 cubic meters
B.24 cubic meters
C.36 cubic meters
D.30 cubic meters
Answer: C.36 cubic meters
Explanation: Time to paint each wall as given in problem:
AC = 4 hours
BC = 2 hours
AB = 6 hours
Since he works at constant rate and it takes him twice as long to paint AC compared to BC
AC=2BC
Plug in 6 for A and you find that B=3
Since painting AB takes 3 times as long compared to BC,
AB=3BC
Plug in 6 for A and 3 for B and you find that C=2
A*B*C=6*3*2=36 cubic meters
Answer: C
Question: In how many years will the benefit Janet receives from her work double given that she receives a simple interest of 10% per annum on the initial agreed paid benefit.
A.15
B.10
C.5
D.12
Answer: B.10
Explanation: P = (P*10*R)/100
100P = P*10*R
100 = 10R
Therefore R = 10 Years
B = 10
Question: If C is the temperature in degrees Celsins and F is the temperature in degrees Fahrenheit, then the relationship between temperatures on the two scales is expressed by the equation 9C=5(F-32). In two sets of experiment, the temperature recorded for a chemical reaction to complete differed by 40 degrees on the Fahrenheit scale, by how many degrees did the temperature extremes differ on the Celsius scale?
A.a) 65/9
B.b) 13
C.c) 22
D.d) 45
Answer: C.c) 22
Explanation: The relationship is 9/5 - 32, so approximately half of difference in Celsius (the -32 part won't be used in this case).
Just looking at the answer choices you can pick C which is the only number near half of 40. The other answer choices are too far apart so no need to calculate.
Question: Reena took a loan of 1400 with simple interest for as many years as the rate of interest. If she paid 224 as interest at the end of the loan period, what was the rate of interest?
A.3.6
B.4
C.14
D.Cannot be determined
Answer: B.4
Explanation: Explanation: Let rate = R% and time = R years.
Then, (1400 x R x R)/100 = 224
14RÂ² = 224
RÂ² = 16
R = 4.
Answer: Option B
Question: How many times do the hands of a clock coincide in a day?
A.33
B.77
C.22
D.23
Answer: C.22
Explanation: The hands of a clock coincide 11 times in every 12 hours
(Since between 11 and 1, they coincide only once,
i.e. at 12 o'clock).
==> The hands coincide 22 times in a day.
Answer: Option 'C'
Question: How many bricks, each measuring 40 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm?
A.1400
B.2400
C.4000
D.7000
Answer: C.4000
Explanation: Number of bricks = Volume Of the wall / Volume of 1 brick = (800 x 600 x 22.5) / (40 x 11.25 x 6) = 4000
ANSWER:C
Question: A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled ?
A.4.5 hrs
B.5 hrs
C.6.5 hrs
D.7.2 hrs
Answer: D.7.2 hrs
Explanation: Solution
Net part filled in 1 hour	= (1/4 - 1/9)
= 5/36.
Therefore,the cistern will be filled in 36/5 hrs i.e, 7.2 hrs.
Answer D
Question: Nine men went to a hotel. Eight of them spent Rs.3 each over their meals and the ninth spent Rs.2 more than the average expenditure of all the nine. Determine the total money spent by them?
A. Rs.29.25
A.29.25
B.29.28
C.29.27
D.29.22
Answer: A.29.25
Explanation: Average of 9 = x
9x = 8 * 3 + x * 2 x = 3.25
Total = 9 * 3.25 = 29.25.Answer: A
Question: On a magical-intellectual land of gpuzzles , all the animal are rational(real smart).
There are six leopards and one sheep.
Leopard can eat sheep but since as the land is magical, the leopards who eats the sheep , turns into sheep and then can be eaten by the remaining leopard(s).
If we leave them for some time then how many sheep and leopard will be there , when we come back ?
A.8 leopard and 1 sheep
B.3 leopard and 3 sheep
C.6 leopard and 2 sheep
D.5 leopard and 1 sheep
Answer: D.5 leopard and 1 sheep
Explanation: D
5 leopard and one sheep
since all animal are rational , once 1st leopard eats the sheep all the rest of leopard would know about this.
Question: There are 6 people in the elevator. Their average weight is 160 lbs. Another person enters the elevator, and increases the average weight to 151 lbs. What is the weight of the 7th person.
A.97
B.168
C.189
D.190
Answer: A.97
Explanation: Solution
Average of 7 people after the last one enters = 151 .
âˆ´ Required weight = (7x151)-(6x160)
= 1057- 960
= 97.
Answer A
Question: The guidelines at a certain college specify that for the introductory English class, the professor may choose one of four specified novels, and choose two plays from a list of 5 specified plays. Thus, the reading list for this introductory class has one novel and two plays. How many different reading lists could a professor create within these parameters?
A.15
B.40
C.90
D.150
Answer: B.40
Explanation: 4C1*5C2 = 4*10 = 40
The answer is B.
Question: Consider a right triangle AQC with length of sides being x,y and z where y represents the hypotenuse , Which of these represent the radius of the circle which is inscribed in triangle AQC
A.[A] x+y+z/3
B.[B] x-y+z/3
C.[C] x-y+z/2
D.[D] (x^2 + y^2 + z^2)/3
Answer: C.[C] x-y+z/2
Explanation: Radius of a circle inscribed in the right triangle AQC r = (x + z - y)/2 where y is the hypotenuse and x and y are other two sides.
Answer: C
Question: A charitable association sold an average of 66 raffle tickets per member. Among the female members, the average was 70 raffle tickets. The male to female ratio of the association is 1:2. What was the average number E of tickets sold by the male members of the association
A.50
B.56
C.58
D.62
Answer: C.58
Explanation: Given that, Total average E sold is 66, Male/Female = 1/2 and Female average is 70. Average of Male members isX.
(70*F+X*M)/(M+F) = 66 -> Solving this equation after substituting 2M=F, X = 58. ANS C.
Question: A can do a certain job in 25 days which B alone can do in 20 days. A started the work and was joined
by B after 10 days. The number of days taken in completing the wotk were ?
A.1423kmph
B.1523kmph
C.1623kmph
D.1723kmph
Answer: C.1623kmph
Explanation: Explanation:
Work done by A in l0 days = (1/25) *10 = 2/5
Remaining work = 1 - (2/5) = 3/5
(A+B)s 1 days work = (1/25) + (1/20) = 9/100
9/100 work is done by them in 1 day
hence 3/5 work will be done by them in (3/5)*(100/9)
= 20/3days.
Total time taken = (10 + 20/3) = 16*(2/3) days
Answer: C
Question: The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team ?
A.20 years
B.21 years
C.23 years
D.25 years
Answer: C.23 years
Explanation: Explanation:
Let the average age of the whole team be x years.
11x - (26 + 29) = 9 (x - 1)
=> 11x - 9x = 46
=> 2x = 46
=> x = 23.
So, average age of the team is 23 years. Answer: C
Question: A train 100 m long crosses a platform 125 m long in 15 sec; find the speed of the train?
A.767 kmph
B.55 kmph
C.54 kmph
D.33 kmph
Answer: C.54 kmph
Explanation: D = 100 + 125 = 225
T = 15
S = 225/15 * 18/5 = 54 kmph
Answer: C
Question: Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 80 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad?
A.16
B.18
C.40
D.24
Answer: C.40
Explanation: Time taken = Total Distance / Relative Speed
Total Distance = 80 kms
Relative Speed (Opposite side) (As they are moving towards each other speed would be added ) = 6+ 4 = 10 kms/hr
Time taken = 80 / 10 = 8 hrs
Distance traveled by Brad = Brad's speed * time taken = 6 * 8 = 40 kms... Answer - C
Question: Car A runs at the speed of 42km/hr & reaches its destination in 6hr. Car B runs at the speed of 52 km/h & reaches its destination in 9h. What is the respective ratio of distances covered by Car A & Car B?
A.11 : 6
B.7 : 13
C.13 : 7
D.15 : 6
Answer: B.7 : 13
Explanation: Sol. Distance travelled by Car A = 42 × 6 = 252 km
Distance travelled by Car B = 52 × 9 = 468 km
Ratio = 252/468= 7 : 13
B
Question: From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?
A.2/1223
B.1/122
C.1/221
D.3/1253
Answer: C.1/221
Explanation: Let s is the sample space. then
n(s ) = 52C2 = 1326
E = event of getting 2kings out of 4
n(E) = 4C2 = 6
P(E) = 6/1326 = 1/221
Answer is C
Question: IF
1= O
2= T
3= T
4=F
5= F
THEN 6=?
A.S
B.J
C.K
D.L
Answer: A.S
Explanation: IF
1= O... First letter of ONE.
2= T.... First letter of TWO.
3= T
4=F
5= F
THEN 6=S ... First letter of SIX.
ANSWER:A
Question: The sum of the mean, the median, and the range of the set {1, 2, 4,6,8,10,12} equals which one of the following values?
A.2.6
B.14.23
C.22.14
D.8.6
Answer: C.22.14
Explanation: set {1, 2, 4,6,8,10,12}
Mean = (1+2+4+6+8+10+12)/7 = 6.14
Meadian = Middle term = 6
Range = Highest - Lowest = 12-1 = 10
Mean+Median+Range = 6.14+6+10 = 22.14
Answer: Option C
Question: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?
A.9:1
B.9:2
C.9:8
D.9:5
Answer: A.9:1
Explanation: Explanation:
Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 - 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Answer: Option A
Question: 5, 11, 17, 25, 33, 43, ?
A.49
B.51
C.52
D.53
Answer: D.53
Explanation: The sequence is +6, +6, +8, +8, +10, ....
Answer : D.
Question: If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (x - 2y) is odd
II. xy^2 is an even negative integer
III. (y^2 - x) is an odd negative integer
A.I only
B.II only
C.I and II
D.I
Answer: D.I
Explanation: If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (x - 2y) is odd
x - is always negative and odd
2y - can be 0, when y=0, or always even integer (positivie or negative)
odd integer +/- even integer = always odd
I statement is always true
II. xy^2 is an even negative integer
y can be 0 => xy^2 = 0 (non-negative even) => II statement is not true
III. (y^2 - x) is an odd negative integer
y can be 0 => -x will be positive => III statement is not true
basing on above, only I statement will always be true
answer is D
Question: What is the remainder if 7^8 is divided by 100?
A.7
B.1
C.9
D.10
Answer: B.1
Explanation: 7^8 can be written as (7^4)^2
If we divide 7^4 by 100 the reminder is 1
So, (7^4)^2 by 100, the reminder is 1^2 = 1
Answer : B
Question: If it takes a machine 2⁄3 minute to produce one item, how many items will it produce in 1 hours?
A.1⁄3
B.4⁄3
C.90
D.120
Answer: C.90
Explanation: 1 item takes 2/3 min so it takes 60 min to produce x
2x/3=60 the x=90
Answer:C
Question: Two identical trains AA and BB running in opposite direction at same speed tale 2 min to cross each other completely. The number of bogies of AA are increased from 12 to 16. How much more time would they now require to cross each other?
A.40 Sec
B.50 sec
C.60 sec
D.20 sec
Answer: D.20 sec
Explanation: Total initial bogies is 12+12=2412+12=24
Additional bogies =16âˆ’12=4
24 bogies is 12+12=24
additional bogies = 16 - 12 = 4
24 bogies take 2 min
2*60/24 *4=20 sec
ANSWER D
Question: In how many Q ways can a four-letter password be chosen, using the letters A, B, C, D, E, and/or F, such that at least one letter is repeated within the password?
A.720
B.864
C.900
D.936
Answer: D.936
Explanation: Total number of four letter passwords = 6*6*6*6= 1296 ------(1)
Total number of passwords in which no letter repeats = 6C4*4!= 15*24=360------(2)
therefore required value Q= (1)-(2)= 1296-360=936.D
Question: When a person aged 39 is added to a group of n people, the average age increases by 2. When a person aged 15 is added instead, the average age decreases by 1. What is the value of W?
A. 7
B. 8
C. 9
D. 10
Answer: A. 7
Explanation: A simple and elegant solution.
As addition of 39, shifts mean by 2, and addition of 15, shifts mean by 1 to the other side, we have the mean lying between 3915, and in a ratio of 2:1
39-15 = 24
24 divide by 3 is 8.
Meaning mean of the n terms is 15+8 = 39-16 = 23
Now, from first statement, When a person aged 39 is added to a group of n people, the average age increases by 2.
W*23 +39 = 25*(W+1)
W = 7
Ans. (A)
Question: An item is being sold for $10 each. However, if a customer will “buy at least 3” they have a promo discount of 12%. Also, if a customer will “buy at least 10” items they will deduct an additional 8% to their “buy at least 3” promo price. If Sam buys 10 pcs of that item how much should he pay?
A.$92.00
B.$88.00
C.$87.04
D.$80.96
Answer: D.$80.96
Explanation: Without any discount Sam should pay 10*10=$100. Now, the overall discount would be slightly less than 20%, thus he must pay slightly more than $80. Only answer choice D fits.
Answer: D.
Question: The labeled price of a table is Rs. 6,000. The shopkeeper sold it by giving 5% discount on the labeled price and earned a profit of 15%. What approximately is the cost price of the table?
A.Rs. 4956
B.Rs. 6195
C.Rs. 6425
D.Rs. 7200
Answer: A.Rs. 4956
Explanation: Explanation:
Labeled price = Rs. 6,000
By giving 5% discount on labeled price, the selling price is
= 95 / 100 * 6,000 = Rs. 5700
By earning 15% profit on the selling of price Rs. 5700 the cost price is
= 100 / 115 * 5700 = Rs. 4956
Therefore, approximate cost is 4956
ANSWER A
Question: A certain amount earns simple interest of 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
A.35
B.350
C.245
D.Cannot be determined
Answer: D.Cannot be determined
Explanation: Let p and r be the principal amount and rate of interest respectively.
Then, p×r×7/100=1750
or, pr = 25000
Now, SI = p×(r+2)×7/100=1750
We have to find the value of
p×(r+2)×7/100−p×r×7/100= M - 1750
M = SI when the rate of interest is 2% more. When we solve this equation, we find that we have two variables and one equation. Therefore, can’t be determined the correct answer.
Answer D
Question: When the scores of the top four students are deleted, the average score of the remaining 66 students falls by 6 marks. Assume that it is possible for two or more students to have the same net score. What is the minimum score possible for the fourth ranking student if no student got a net score of more than 352?
A.280
B.320
C.300
D.340
Answer: C.300
Explanation: Explanation :
Sum of score of top four students = 1356
Maximum possible score possible for top three students = 352*3 = 1056
Hence the minimum possible score for the 4th student = 300
Answer : C
Question: A and B can do a work in 60 days; B and C can do it in 120 days; A and C can do it in 80 days. In what time A alone can do the work?
A.100
B.90
C.80
D.70
Answer: B.90
Explanation: (A+B)’s one day’s work = 1/60
(B+C)’s one day’s work = 1/120
(A+C)’s one day’s work = 1/80
Adding we get, 2(A+B+C)’ s one day’s work= 1/60 + 1/120 + 1/80
= 28/720
= 14/365
(A+B+C)’ s one day’s work = 14*1/365*2 = 14/720
So, A’s one day’s work = 14/720 - 1/120 = 1/90
A alone can do the work in 90 days.
ANSWER:B
Question: In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 200 m. Then, A wins by:
A.60 m
B.100 m
C.43m
D.20m
Answer: B.100 m
Explanation: To reach the winning post A will have to cover a distance of (500 - 200)m, i.e., 300 m.
While A covers 3 m, B covers 4 m.
While A covers 300 m, B covers 4 x 300/3	m	= 400 m.
Thus, when A reaches the winning post, B covers 400 m and therefore remains 100 m behind.
A wins by 100 m.
Answer:	B
Question: IN Common Wealth Games an athlete runs 280 meters in 24 seconds. Hisspeed is ?
A.25 km/hr
B.42.42 km/hr
C.30 km/hr
D.32 km/hr
Answer: B.42.42 km/hr
Explanation: Explanation :
(280/1000)/(24/3600)=42.42 km/hr
Answer : B
Question: Pipe A can fill a tank in 16 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes?
A.11
B.21
C.33
D.51
Answer: B.21
Explanation: Explanation:
Let the pipe B be closed after x minutes.
30/16 - x/24 = 1 => x/24 = 30/16 - 1 = 14/16
=> x = 14/16 * 24 = 21.
Answer:B