RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The average daily wages of A, B and C is Rs 120. If B earns Rs 40 more than C per day and ,A earns double of what C earns per day, the wage of A per day is?
A.Rs 80
B.Rs 120
C.Rs 160
D.Rs 100
Answer: C.Rs 160
Explanation: Let daily wages of C = X
Then, daily wages of A = 2X
and daily wages of B = X + 40
Hence, average daily wages of A, B and C
= (X + 2X + X + 40) / 3 = (4X + 40)/3
Thus, (4X + 40)/3 =120
=>4X + 40 = 360
=>4X = 320
X = 80.
Therefore, Wages of A per day = 2 x 80 = Rs 160.
ANSWER:C
Question: A political candidate collected $1,749 from a fund raising dinner. If each supporter contributed at least $50, what is the greatest possible number of contributors at the dinner?
A.33
B.34
C.35
D.36
Answer: B.34
Explanation: Nearest to 1749≈1750
175/50=35 (Caution: Collection is 1750 - 1 = 1749)
Counting 1 less = 50*34 = 1700 >> 49 remains which will be adjusted with the 34 members
51* 34 = 1734 >> 15 remains which will be adjusted with 15 members
52 * 15 + 51 * 19 = 780 + 969 = 1749
Answer = B
Question: The age of Somu is one-third his father's. 7 years back he was one-fifth of his father's age. What is his persent age ?
A.11
B.13
C.14
D.12
Answer: C.14
Explanation: Explanation :
Let Somu's age be x and that of his father be 3x.
So, x - 7 = 3x - 7/5 = x = 14
Answer : Option C
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
A.200m
B.225m
C.245m
D.250m
Answer: C.245m
Explanation: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.
ANSWER C
Question: The “length of integer x” refers to the number of prime factors, not necessarily distinct, that x has. (If x = 60, the length of x would be 4 because 60 = 2 × 2 × 3 × 5.) What is the greatest possible length of integer z if z < 800?
A.13
B.10
C.9
D.7
Answer: C.9
Explanation: To maximize the length of z, we should minimize its prime base. The smallest prime is 2 and since 2^9 = 512 < 800, then the greatest possible length of integer z is 9.
The answer is C.
Question: The rate of failure in an examination is 39.25%. Find the least number of total candidates appeared in the examination.
A.100
B.200
C.300
D.400
Answer: D.400
Explanation: if 100 student appear then failure=39.25 ......... which is not possible because number of student can not be fraction,like wise in 200 student,failure=78.5, so we have to make the failure percentage into a unit digit failure not fraction...so min no of student =400 so that no of failure=157..........so least no of student appeared in the exam= 400.
ANSWER:D
Question: In the word CONTRACTUAL, the positions of the first and the eleventh letters are interchanged. Similarly, the positions of the second and the tenth letters are interchanged, and so on, up to the positions of fifth and seventh letters are interchanged, keeping the position of sixth letter unchanged. Which letter will be the third to the right of the sixth letter from the left end?
A.U
B.N
C.T
D.A
Answer: B.N
Explanation: New word will be LAUTCARTNOC
6th letter from the left end is A,and and 3rd to the righ of thet letter is N.
ANSWER:B
Question: In an examination, 35% of students failed in quants and 42% of students failed in verbal while 14% failed in both the topics. If 222 students passed in both the topics, how many students appeared to write the examination?
A.500
B.600
C.700
D.800
Answer: B.600
Explanation: DETAILED SOLUTION
Percent of students failing quants = 35
Percent of students failing verbal = 42
Sum = 35 + 42 = 77
Percent of students failing both = 14
= ) Percent of students failing either one = 77 – 14 = 63. Thus, 37% students passed in both the topics
= ) 37% of x = 222 = ) x = 600
Correct Answer: B
Question: Three coins are tossed. What is the probability of getting at most two tails?
A.7/8
B.1/8
C.1/2
D.1/7
Answer: A.7/8
Explanation: Total number of outcomes possible when a coin is tossed = 2 (âˆµ Head or Tail)
Hence, total number of outcomes possible when 3 coins are tossed, n(S) = 2 Ã— 2 Ã— 2 = 8
(âˆµ i.e., S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH})
E = event of getting at most two Tails = {TTH, THT, HTT, THH, HTH, HHT, HHH}
Hence, n(E) = 7
P(E) = n(E)/n(S)=7/8
Answer:A
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
A.7 years.
B.8 years.
C.9 years.
D.10 years.
Answer: D.10 years.
Explanation: EXPLANATION
Let C’s age be x years. Then, B’s age = 2x years. A’s age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B’s age = 2x = 10 years.
Answer D
Question: A can do a work in 12 days. B is 60% more efficient than A. How many days does B alone take to do the same job?
A.15/2
B.10
C.7/2
D.12
Answer: A.15/2
Explanation: Ratio of times taken by A and B = 160:100 = 8:5
suppose B alone to take x days to do the work
then, 8:5::12:x
8x= 5*12
x=15/2 days
correct option is A
Question: In a 1000 m race, A beats B by 200 meters or 24 seconds. Find the speed of B?
A.6
B.8.3
C.7
D.5
Answer: B.8.3
Explanation: Since A beats B by 200 m or 24 seconds, i
t implies that B covers 200 m in 24 seconds.
Hence speed of B = 200/24 = 8.3 m/s.
Answer: B
Question: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is?
A.6
B.7
C.8
D.65
Answer: A.6
Explanation: S = 1
M = x
DS = x + 1
US = x - 1
35/(x + 1) + 35/(x - 1) = 12
x = 6
Answer: A
Question: In a recent head-to-head run-off election, 12,000 absentee ballets were cast. 1/6 of the absentee ballets were thrown out and 3/5 of the remaining absentee ballets were cast for Candidate A. How many absentee votes did Candidate B receive?
A.2,000
B.3,000
C.4,000
D.8,000
Answer: C.4,000
Explanation: 5/6 * 2/5 (total absentee votes) = 1/3 (total votes)=1/3*12000=4000
Answer is C
Question: The average height of 15 girls out of a class of 30 is 152 cm. and that of the remaining girls is 156 cm. The average height of the whole class is :
A.150 cms
B.151 cms
C.152 cms
D.154 cms
Answer: D.154 cms
Explanation: Explanation:
Average height of the whole class =(15×152+15×156/30)=154 cms
Answer D
Question: 10^25 - 360 is divisible by all of the following except:
A.A.7
B.B.8
C.C.5
D.D.4
Answer: A.A.7
Explanation: The last three digits ( 1000 - 360 ) 640
640 is divisible by 2,4,8,5
640 is not evenly divisible by 7 so the answer is A) 7
Question: The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?
A.150
B.250
C.270
D.280
Answer: C.270
Explanation: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Smaller number = 270.
Answer C)270.
Question: A, B and C started a shop by investing Rs. 10,000, Rs. 20,000 and Rs. 30,000 respectively. At the end of the year, the profits were distributed among them. If Câ€™s share of profit be Rs. 9,000, then the total profit was :
A.30,000
B.60,000
C.18,000
D.120,000
Answer: C.18,000
Explanation: Sol.
A : B : C = 10000 :20000 : 30000 = 1: 2 : 3. so, Câ€™s share : Total Profit = 3 : 6
Let the total profit be Rs. x. Then, 3/6 = 9000/x
x = 9000 * 6 / 3 = 18000.
Answer C
Question: problemsolvingproblemsolvingprob . . . . . . Find the 2015th term in the series?
A.23
B.26
C.13
D.76
Answer: C.13
Explanation: Sol.
Problemsolving = 14 letter word. So divide 2015 by 14 and find the remainder. Here remainder is 13. so 13th letter in problemsolving is 'n'
Answer:C
Question: If the area of circle is 1520 sq cm then its circumference?
A.221
B.138
C.166
D.116
Answer: B.138
Explanation: 22/7 r2 = 1520 => r = 22
2 * 22/7 * 22 = 138
Answer: B
Question: In how many ways can the letters of word EMULATION be arranged such that NO two vowels appear together?
A.9!
B.5!*4!
C.4!*5!
D.5!*4!*2!
Answer: C.4!*5!
Explanation: No 2 vowels together = the only arrangement possible will be V C V C V C V C V (with V=vowel, C=consonant). This is true as we have 5 vowels and 4 consonants and any other combination will force us to pair 2 vowels together.
Thus, the number of arrangements possible : 5 *4 *4 *3 *3 *2 *2*1 = 5!*4! ----> C is the correct answer.
Question: How many prime numbers are between 78/14 and 55/4?
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: 78/14= 39/7 = 6-
55/4 = 14-
Prime numbers between 6 and 14 are 7, 11 and 13
- sign signifies that the number is marginally less .
Answer B
Question: 5 pears and 2 apples cost $16. 3 pears and 3 apples cost $15. How much does one apple cost?
A.3.5
B.3.25
C.3
D.2.5
Answer: C.3
Explanation: Let cost of 1 pear = x, let cost of 1 apple = y
5x + 2y = 16
y = (16 - 5x)/2
Again,
3x + 3y = 15
3x + 3((16 - 5x)/2) = 15
3x + 24 - 7.5x = 15
3x + 24 = 15 + 7.5x
9 = 4.5x
x = 2
Now plug this value into one of the initial equations:
5x + 2y = 16
5(2) + 2y = 16
10 + 2y = 16
2y = 6
y = 3
Answer: C
ANSWER:C
Question: Which of the following is the lowest positive integer that is divisible by 6, 7, 8, 9, and 10?
A.2140
B.2520
C.2980
D.3260
Answer: B.2520
Explanation: The number needs to be divisible by 2*3, 7, 2^3, 3^2, and 2*5.
The lowest positive integer is 7 * 2^3 * 3^2 * 5 = 2520
The answer is B.
Question: If a coin is tossed three times, what is the probability that on the first toss the coin lands on tails and then lands on heads the next two tosses?
A.1/8
B.1/3
C.1/4
D.1/2
Answer: A.1/8
Explanation: P(THH) = 1/2*1/2*1/2=1/8
The answer is A.
Question: A certain research group plans to create computer models of x% of a list of 10,000 bacterial species known to inhabit the human body. After a budget cut, the group finds it must reduce this selection by (x − 6)%. In terms of x, how many species of bacteria will the group be able to model?
A.(x)*(106 - x)
B.(x)(105 – x)
C.(100)(105 – x)
D.(100)(95 – x)
Answer: A.(x)*(106 - x)
Explanation: Initial: (x/100)*10000 = 100x (bacterial species)
After reduce BY (x - 6)%, the percentage of bacterial species = 1 - (x - 6)% = 1 - (x - 6)/100 = (106 - x)/100
Note: Difference between reduce to[means: the remain] and reduce by[means: the remain = 1 -reduce by]
So, the number of bacterial species after reducing: 100x*(106 - x)/100 = (x)*(106 - x)
Ans is A.
Question: In Township K each property is taxed at 8 percent of its assessed value. If the assessed value of a property in Township K is increased from $18,000 to $28,000, by how much will the property tax increase?
A. $320
B. $800
C. $320
D. $600
Answer: B. $800
Explanation: Increase in house value = $28,000 - $18,000 =$10000
So, tax increase = 8% of$10000=$800
Answer: B
Question: The difference between C.I. and S.I. on an amount of Rs. 15,000 for 2 years is Rs. 24. What is the rate of interest per annum?
A.8
B.2
C.9
D.4
Answer: D.4
Explanation: Explanation:
[15000 * (1 + R/100)2 - 15000] - (15000 * R * 2)/100 = 104
15000[(1 + R/100)2 - 1 - 2R/100] = 24
15000[(100 + R)2 - 10000 - 200R]/10000 = 24
R2 = (24 * 2)/3 = 16 => R = 4
Rate = 4%
Answer: Option D
Question: A sum of Rs. 2691 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
A.1629
B.1656
C.1277
D.6298
Answer: B.1656
Explanation: (x*8*3)/100 = ((2691 - x)*3*5)/100
24x/100 = 40365/100 - 15x/100
39x = 40365 => x = 1035
Second sum = 2691 â€“ 1035 = 1656
Answer:B
Question: Find the area of a rhombus whose side is 25 cm and one of the diagonals is 30 cm?
A.876
B.268
C.269
D.600
Answer: D.600
Explanation: Consider the rhombus ABCD. Let the diagonals intersect at E. Since diagonals bisect at right angles in a rhombus.
BE2 + AE2 = AB2
252 = 152 + AE2 AE = √(625 - 225) = √400 = 20,
AC = 20 + 20 = 40 cm.
Area of a rhombus = 1/2 * d1d2
= 1/2 * 40 * 30 = 600 sq.cm.
Answer:D
Question: There are 4 runners on a track team who run an average of 4.5 seconds per 40 yards. If another runner joins their team who runs 4.3 seconds per 40 yards, what will the new average 40 yard time be?
A.4.46
B.4.39
C.4.42
D.4.49
Answer: A.4.46
Explanation: (sum of the 4 times)/4 = 4.5
sum of the 4 times = 18
new sum = 18+4.3 = 22.3
new average = 22.3/5 = 4.46
ans: A
Question: Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 15 inches by 20 inches and Jordan's rectangle is 6 inches long, how wide is Jordan's rectangle, in inches?
A.20
B.30
C.40
D.50
Answer: D.50
Explanation: Area of first rectangle is 15*20=300 hence area of second would be 6x=300x
x=50
answer is D
Question: A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 7 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
A.2.9 hrs
B.8.9 hrs
C.9.3 hrs
D.7.2 hrs
Answer: C.9.3 hrs
Explanation: Net part filled in 1 hour = (1/4 - 1/7)
= 3/28
The cistern will be filled in 28/3 hrs i.e., 9.3 hrs.
Answer:C
Question: The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
A.6 kmph
B.9 kmph
C.8 kmph
D.10 kmph
Answer: C.8 kmph
Explanation: S = 4
M = x
DS = x + 4
US = x - 4
6/(x + 4) + 6/(x - 4) = 2
x = 8
Answer:C
Question: On his drive to work, Leo listens to one of three radio stations A, B or W. He first turns to A. If A is playing a song he likes, he listens to it; if not, he turns it to B. If B is playing a song he likes, he listens to it; if not, he turns it to W. If W is playing a song he likes, he listens to it; if not, he turns off the radio. For each station, the probability is 0.30 that at any given moment the station is playing a song Leo likes. On his drive to work, what is the probability that Leo will hear a song he likes?
A.0.027
B.0.09
C.0.417
D.0.657
Answer: D.0.657
Explanation: Probability he hears a song is like:
Tune to A and likes what he is hearing = 0.3
Tune to A, don't find he like what they are airing, then tune to B and likes what he finds there = 0.7 * 0.3 = 0.21
Tune to A, finds crap there, Tune to B, hears a similar crap, Tune to W and finally falls in love with the program = 0.7^2 * 0.3 = 0.147
Total = 0.657
Ans D
Question: is twice as fast as B. If B alone can do a piece of work in 30 days, in what time can A and B together complete the work?
A.13 days
B.10 days
C.16 days
D.11 days
Answer: B.10 days
Explanation: B
10 days
A can do the work in 30/2 i.e., 15 days.
A and B's one day's work = 1/15 + 1/30 = (2 + 1)/30 = 1/10
So A and B together can do the work in 10 days.
Question: What will be the vulgar fraction of 0.70
A.3/5
B.7/10
C.3/2
D.3/7
Answer: B.7/10
Explanation: Explanation:
0.70 = 70/100 = 7/10
Option B
Question: 220, 218, 214, 208, 200, 190, ?
A.120
B.140
C.147
D.178
Answer: D.178
Explanation: 220
220 - 2 = 218
218 - 4 = 214
214 - 6 = 208
208 - 8 = 200
200 - 10 = 190
190 - 12 = 178
Answer is D
Question: If the President and Vice President must sit next to each other in a row with 6 other members of the Board, how many different seating arrangements are possible?
A.120
B.240
C.300
D.10080
Answer: D.10080
Explanation: We need to take President and VP as one unit. Therefore we have 7 people to arrange=7! ways
Also, we both President and VP can be arranged in 2 ! ways.
Reqd no of ways=7!*2!=10080 ways
Answer D
Question: Of the science books in a certain supply room, 50 are on botany, 62 are on zoology, 83 are on physics. 50 are on geology, and 110 are on chemistry. If science books are removed randomly from the supply room, how many must be removed to ensure that 80 of the books removed are on the same science?
A.321
B.159
C.166
D.285
Answer: A.321
Explanation: First, you can take all 50 Botany books, all 62 zoology books and all 50 geology books because you're sure to never pick 80 of them.
There are still 83 on physics and 110 on chemistry
The worst case could be that we pick 79 physics and 79 chemistry. So that the next book picked will necessary complete 80 books picked, either in physics or chemistry.
Minimum number of books picked to reach 80 in the same science should be : 50 + 62 + 50 + 79 +79 + 1 = 321
A
Question: The present worth of Rs.169 due in 2 years at 4% per annum compound interest is
A.Rs 155.25
B.Rs 156.25
C.Rs 157.25
D.Rs 158.25
Answer: B.Rs 156.25
Explanation: Explanation:
In this type of question we apply formula
Amount=P /(1+R/100)n
Amount=169 /(1+4/100)2
Amount=169∗25∗25/26∗26
Amount=156.25
Option B
Question: For prime numbers x and y, x^3*y^5=z^4. How many positive factors does positive integer z have?
A.One
B.Two
C.Three
D.Four
Answer: C.Three
Explanation: Solution: given x^3*y^5=z^4; here if x and y are two different prime numbers then z = x^3/4 * y^5/4
in this case z can not be and integer.
now to make z = (x^3*y^5)^1/4 an integer it is required to have x=y then equation will become z=x^2 or z=y^2
hence total positive factors will be 3.	ANSWER:C
Question: A dealer purchases 15 articles for Rs. 25 and sells 12 articles for Rs. 30. Find the profit percentage?
A.20%
B.40%
C.50%
D.80%
Answer: C.50%
Explanation: C
50%
L.C.M of 15 and 12 = 60
CP of 60 articles = Rs. 100 (25 * 4)
SP of 60 articles = Rs. 150 (30 * 5)
Profit percentage = (150 - 100)/100 * 100 = 50%
Question: A and B together can complete a work in 12 days. A alone can complete it in 20 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work?
A.10 days
B.11 days
C.15 days
D.20 days
Answer: C.15 days
Explanation: B's 1 day's work=(1/12-1/20)=2/60=1/30
Now, (A+B)'s 1 day's work=(1/20+1/60)=4/60=1/15
So, A and B together will complete the work in 15 days.
Correct Option: C
Question: Mike has forty-five cents. If mike gives away two nickles and a dime, how much money does he have left?
A.10 cents
B.16 cents
C.35 cents
D.25 cents
Answer: D.25 cents
Explanation: Nickle = 5 cents
Dime = 10 cents
45-(2)5-10 = 25
D.25 cents
Question: The value of a 10.5% stock, in which an income of Rs.756 is derived by investing Rs.9000, brokerage being% is :
A.Rs. 113.5
B.Rs. 119.7
C.Rs. 124.75
D.Rs. 130.75
Answer: C.Rs. 124.75
Explanation: For an income of Rs.756, investment = Rs.9000
For an income of Rs., investment = = Rs.125
For a Rs.100 stock, investment = Rs.125.
Market value of Rs. 100 stock = = Rs. 124.75
C
Question: Life expectancy is defined by the formula 2SB/G, where S = shoe size, B = average monthly electric bill in dollars, and G = GMAT score. If Melvin's GMAT score is twice his monthly electric bill, and his life expectancy is 60, what is his shoe size?
A.25
B.60
C.35
D.40
Answer: B.60
Explanation: Solution -
Given that, G = 2B and Life expectancy(L) = 60
L=2SB/G -> 60 = 2SB/2B --> S=60.
ANS B
Question: Look at this series: 70, 71, 76, __, 81, 86, 70, 91, ... What number should fill the blank?
A.70
B.71
C.80
D.90
Answer: A.70
Explanation: A
Question: The manager at a health foods store mixes a unique superfruit juice cocktail that costs $1399.45 per litre to make. The cocktail includes mixed fruit juice and açai berry juice, which cost $262.85 per litre and $3104.35 per litre, respectively. The manager has already opened 33 litres of the mixed fruit juice. How many litres of the açai berry juice does he need to add?
A.17 litres
B.22 litres
C.11 litres
D.07 litres
Answer: B.22 litres
Explanation: 262.85(33)+3,104.35x = 1,399.45(33 + x)
Solve the equation.
262.85(33)+3,104.35x = 1,399.45(33 + x)
8,674.05 + 3,104.35x = 46181.85 + 1,369.45x
8,674.05 + 1,704.9x = 46181.85
1,704.9x = 37,507.8
x = 22
Answer is B.
Question: If a fair coin is tossed six times, what is the probability of getting exactly five heads in a row?
A.1/64
B.1/32
C.1/16
D.3/64
Answer: B.1/32
Explanation: P(HHHHHT) = 1/64
P(THHHHH) = 1/64
The sum of these probabilities is 2/64 = 1/32
The answer is B.
Question: If an integer r is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that r(r + 1)(r + 2) will be divisible by 8?
A.1/4
B.3/8
C.1/2
D.5/8
Answer: D.5/8
Explanation: for r Total numbers 8*12
There are 12 numbers divisible by 8 -> 3*12 (if 8 is an example - (6,7,8), (7,8,9), (8,9,10))
and 12 numbers divisible by 4 but not divisible by 8 -> 2*12 (if 4 is an example (2,3,4) and (4,5,6))
The answer 5/8 -> D
Question: there are two sections A and B of a class consisting of 36 and 44 students respectively. If the average weight of section A is 40kg and that of section B is 35kg, find the average weight of the whole class?
A.15.42
B.37.25
C.12.54
D.32.37
Answer: B.37.25
Explanation: Sol: total weight of(36+44) students=(36*40+44*35)kg =2980kg.
Therefore weight of the total class=(2980/80)kg =37.25kg.
Ans: B
Question: One side of a rectangle is 3 cm shorter than the other side. If we increase the length of each side by 1 cm, then the area of the rectangle will increase by 18 cm2. Find the lengths of all sides.
A.10 and 3
B.7 and 10
C.10 and 7
D.3 and 10
Answer: C.10 and 7
Explanation: Let x be the length of the longer side x>3, then the other side's length is x−3 cm. Then the area is S1 = x(x - 3) cm2. After we increase the lengths of the sides they will become (x+1) and (x−3+1)=(x−2) cm long. Hence the area of the new rectangle will be A2=(x+1)⋅(x−2) cm2, which is 18 cm2 more than the first area. Therefore
A1+18=A2
x(x−3)+18=(x+1)(x−2)
x2−3x+18=x2+x−2x−2
2x=20
x=10. So, the sides of the rectangle are 10 cm and (10−3)=7 cm long.
So answer is C.
Question: Ella leaves her home and walks toward Ed's house. Two hours later, Ed leaves his home and walks toward Ella's house. The distance between their homes is 42 kilometers, Ella's walking speed is 5 km/h, and Ed's walking speed is 3 km/h. How many kilometers will Ella walk before she meets Ed?
A.28
B.29
C.30
D.31
Answer: C.30
Explanation: Ella walks 10 km in the first two hours so there are 32 km remaining.
When Ed starts walking, they complete a total of 8 km per hour.
They will meet four hours after Ed starts walking.
Since Ella walks for 6 hours, she walks 30 km.
The answer is C.
Question: John bought 9.25m of cloth for $407. Find the cost price per metre.
A.46
B.47
C.58
D.44
Answer: D.44
Explanation: Cloth bought by John = 9.25 m
Cost of 9.25 m = $407
Cost per metre = 407 ÷ 9.25
The cost of the cloth per metre = $ 44
Answers: D
Question: A crate of mangoes contains one bruised mango for every thirty mango in the crate. If three out of every four bruised mango are considerably unsaleble and there are 11 unsaleable mangoes in the crate then how msny mango are there in the crate?
A.100 mangoes
B.110 mangoes
C.120 mangoes
D.130 mangoes
Answer: B.110 mangoes
Explanation: 110 mangoes
ANSWER:B
Question: four children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Children AB must sit next to each other, and child C must be somewhere to the right of AB. How many possible configurations are there for the children?
A.560
B.720
C.1440
D.4320
Answer: A.560
Explanation: A, B, C, D, E, F, G- seven children, of which AB must sit next to each other. Considering them as one X (A, B), we have X, C, D, E, F, G. These can be arranged in 6! ways. But A,B can arrange themselves in 2! ways. So a total of 6!*2! ways = 1440. Since in exactly half of them, C will be to the right of AB, and exactly half, C will be to the left of AB, therefore 1440/2 = 560.
A is the right answer.
Question: n is a positive integer and k is the product of all integers from 1 to n inclusive. If k is a multiple of 1680, then what is the smallest possible value of n?
A.4
B.6
C.7
D.10
Answer: C.7
Explanation: 3360=2^4*3*5*7
2^4 means that n must be at least 6. That is, We need 2, 4, and 6.
However, we also need 7, so n must be at least 7.
The answer is C.
Question: The number of students in the three sections of a class are in the ratio 2:3:4. The average marks scored in each of these sections is in the ratio 4:3:1. By what percent is the average mark of the second section more than the class average?
A.23.27%
B.28.57%
C.32.38%
D.36.74%
Answer: B.28.57%
Explanation: Let the number of students be 2x, 3x, 4x.
Let the average marks be 4y,3y,y.
Average mark of class = ( 8xy+9xy+4xy)/(2x+3x+4x)
=21xy/9x=7y/3
Percentage difference = ( 3y - 7y/3)/7y/3 *100
= 28.57%
ANSWER:B
Question: If a*b=2a-3b+ab,then3*5+5*3 is equal to
A.22
B.24
C.26
D.28
Answer: A.22
Explanation: 3*5+5*3= (2x3-3x5+3x5)+(2x5-3x3+5x3)
=22
ANSWER A 22