RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: There are five thieves, each loot a bakery one after the other such that the first one takes 1/2 of the total no. of the breads plus 1/2 of a bread. Similarly 2nd, 3rd,4th and 5fth also did the same. After the fifth one no. of breads remained are 3. Initially how many breads were there?
A.124
B.125
C.126
D.127
Answer: D.127
Explanation: Let the Number of Breads Initial be x
You Should Go in Reverse Order as left Bread is 3
i.e x=?
After 1st person ate A=x-(x/2)-(1/2)
i.e A=(2x-x)/2-(1/2)
i.e A=(x/2)-(1/2)
i.e A=(2x-2)/4
i.e A=(x-1)/2
like wise ----After 2nd person ate B=(A-1)/2
like wise ----After 3rd person ate C=(B-1)/2
like wise ----After 4th person ate D=(C-1)/2
like wise ----After 5th person ate E=(D-1)/2
Now as after 5th person ate the Value of remaining Bread is ---3
therefore the value of E=3;
Now go Reverse from botom to top to get the value of X after calcuating
Value of D=7
Value of C=15
Value of B=31
Value of A=63
Value of X=127
SO the Final answer is 127 breads were there
ANSWER:D
Question: 3 candidates in an election and received 1136, 7636 and 11628 votes respectively. What % of the total votes did the winningcandidate got in that election?
A.45%
B.47%
C.57%
D.48%
Answer: C.57%
Explanation: Total number of votes polled = (1136 + 7636 + 11628) = 20400
So, Required percentage = 11628/20400 * 100 = 57%
C
Question: In a joint business, the capital of A, B and C were Rs. 45000, Rs. 30000 and Rs. 22500 respectively. A withdrew half of his capital after 4 months. After 9 months of this withdrawal, there was a total profit of Rs. 28400. Find the A share of profit?
A.10600
B.10400
C.10200
D.12200
Answer: C.10200
Explanation: Given A=45000 B=30000 C=22500
A:B:C= 450:300:225
As A withdrew its half of capital after 4 months,it can withdraw 22500 rupees
But before 4 months, it is 45000 only and the profit is calculated after withdrwal it is almost 9+4=13 months.For that 9 months, the capital for A is half of its original capital,
So A= 450*4+ 225*9= 1800+2025= 3825
Similarly, B= 300*13=3900
Similarly,C= 225*13= 2925
Therefore, ratio of A:B:C= 3825: 3900 : 2925= 51:52:39
A's share=51/142(28400)=10200
ANSWER:C
Question: A train 125 m long passes a man, running at 11 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
A.37 km/hr
B.50 km/hr
C.56 km/hr
D.26 km/hr
Answer: C.56 km/hr
Explanation: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 11 = 45 => x = 56 km/hr.
Answer:C
Question: A sum of money at simple interest amounts to Rs. 825 in 3 years and to Rs. 854 in 4 years. The sum is?
A.Rs. 738
B.Rs. 638
C.Rs. 650
D.Rs. 730
Answer: A.Rs. 738
Explanation: S.I. for 1 year = (854 - 825) = Rs. 29
S.I. for 3 years = 29 * 3 = Rs. 87
Principal = (825 - 87) = Rs. 738.
ANSWER:A
Question: A vessel was filled with 10 ounces of liquid, and 0.008 ounce of the liquid evaporated each day during a 50-day period. What % of the original amount of liquid evaporated during this period?
A.0.004%
B.4%
C.5%
D.60%
Answer: B.4%
Explanation: Total amount of water evaporated each day during a 50-day period = .008 * 50
=.008 * 100/2
= .8/2
= .4
percent of the original amount of water evaporated during this period = (.4/10) * 100%
= 4 %
Answer B
Question: If SAVOURY is coded as OVUARSY then how will RADIATE be coded?
A.AIDARET
B.IDARATE
C.ARIADTE
D.IDAATRE
Answer: D.IDAATRE
Explanation: Comparing the positions of letters S,A,V,O,U,R,Y in SAVOURY and OVUARSY :-
letters at 1,2,3,4,5,6,7 position in SAVOURY have their sequence changed as 4352617 in OVUARSY(4th letter O comes at 1st position, 3rd at 2nd,..)
Similarly, juxtapositioning the letters of RADIATE, i.e. keeping 4th letter(I) at 1st position, 3rd (D) at 2nd position,... and so on..we get
IDAATRE
ANSWER:D
Question: Mrudul invested an amount of Rs.29500/- in order to start a business. Shalaka joined her 4 months later by investing an amount of Rs.33500/-. If the business earned a profit of Rs.120575/- at the end of two years, what was Mrudul’s share of the profit?
A.Rs.60725/-
B.Rs.61950/-
C.Rs.59250/-
D.Rs.58625/-
Answer: B.Rs.61950/-
Explanation: Explanation:
Ratio of Mrudul’s profit and Shalaka’s profit = 29500x24/33500x20 = 354 : 335
:. Mrudul’s share out of total profit = 120575x354/689 = Rs.61950
Answer: Option B
Question: A can do a piece of work in 8 days and B alone can do it in 12 days. How much time will both take to finish the work ?
A.A)4.8
B.B)6.333
C.C)7.333
D.D)8.5
Answer: A.A)4.8
Explanation: This question can be solved by different methods. We need to conserve time in exams so solving this problem using equations is the good idea.
Time taken to finish the job = XY / (X + Y)
= 8 x 12 / (8 + 12)
= 96 / 20
= 4.8 days
Answer: A
Question: A no. when divided successively by 4 and 5 leaves remainders 1&4 respectively. What willbe the respective remainders if it is successively divided by 5 and 4?
A.1, 2
B.2, 3
C.2, 5
D.2, 7
Answer: B.2, 3
Explanation: Let
p
p be the number
Suppose,
p
÷
4
=
q
p÷4=q, remainder = 1
q
÷
5
=
1
q÷5=1, remainder = 4. (Note that we assumed the quotient as 1 for the ease of calculations.)
Hence,
q
=
1
×
5
+
4
=
9
q=1×5+4=9
p
=
4
q
+
1
=
4
×
9
+
1
=
37
p=4q+1=4×9+1=37
Now divide 37 successively by 5 and 4 respectively.
37÷5=7
37÷5=7, remainder = 2
7÷4=1
7÷4=1, remainder = 3
B
Question: Murthy secured 70% of the votes in an election and was elected by a majority of 168 votes. All of the votes polled were valid. Find out number of votes polled if there were only two contestants ?
A.410
B.420
C.430
D.440
Answer: B.420
Explanation: Let the No. of votes polled is x
Then, Murthy got=(7/10)x
and the loser got=(3/10)x
As per the condition
(7/10)x-(3/10)x=168
Solving, we get x = 420
Thus, the no. of votes polled =420
ANSWER:B
Question: The distance between 2 cities A and B is 330km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet?
A.9a.m.
B.10a.m.
C.10.30a.m.
D.11a.m.
Answer: D.11a.m.
Explanation: Suppose they meet x hrs after 8 a.m.
Distance moved by first in x hrs + Distance moved by second in (x-1)hrs = 330
60x + 75 (x-1) = 330
x = 3
They meet at 8+3 = 11 a.m.
Answer is D
Question: Three partners A,B,C starts a business. Twice A's capital is equal to thrice B's capital and B's capital is four times C's capital. Out of a total profit of Rs.17000 at the end of the year, B's share is
A.Rs.4000
B.Rs.6120
C.Rs.7500
D.Rs.6600
Answer: B.Rs.6120
Explanation: Solution
Let C = x.
Then, B = 4x and 2A = 3x4x = 12x or A = 6x.
âˆ´ A : B : C = 6x : 4x : x	= 6 : 4 : 1.
So B's capital	= Rs(17000 x 4 / 11)
= Rs.6120.
Answer B
Question: A and B can do a piece of work in 12 days and 16 days respectively. Both work for 3 days and then A goes away. Find how long will B take to complete the remaining work?
A.6 days
B.9 days
C.18 days
D.24 days
Answer: B.9 days
Explanation: Explanation:
3/12 + (3 + x)/16 = 1
x = 9 days
Answer B
Question: A car covers a distance of 424 km in 6 ½ hours. Find its speed?
A.65.9 kmph
B.75.2 kmph
C.65.2 kmph
D.66.2 kmph
Answer: C.65.2 kmph
Explanation: 424/(13/2) = 424*2/13
=65.2 kmph
ANSWER:C
Question: The distance between two towns is 380 km. At the same moment, a passenger car and a truck start moving towards each other from different towns. They meet 4 hours later. If the car drives 5 km/hr faster than the truck, what is the speed of the car?
A.30km/h
B.40km/h
C.50km/h
D.60km/h
Answer: C.50km/h
Explanation: The main idea used in this kind of problems is that the distance equals speed multiplied by time S=V⋅t
Car	x + 5 (V (km/hr)) 4 t (hr) 4(x +5) S (km)
Truck X V (km/hr) 4 t (hr) 4x S (km)
4(x+5)+4x=380
4x+4x=380−20
8x=360
x=3608
x=45
Therefore the truck's speed is 45 km/hr, and the car's speed is 45+5=50 km/hr
correct answer is C)50km/hr
Question: If m = 3^n, what is the greatest value of n for which m is a factor of 22!
A.8
B.10
C.9
D.14
Answer: C.9
Explanation: Solution-
Consider multiples of 25!=> 3,6,9,12,15,18,21
Count no. of 3 in each multiple.
3=3x1->1
6=3x2->1
9=3x3->2
12=3x4->1
15=3x5->1
18=3x3x2->2
21=3x7->1
---- count 3's =9 so answer is 9
Answer : C
Question: Each writer for the local newspaper is paid as follows: a dollars for each of the first y stories each month, and a + b dollars for each story thereafter, where a > b. How many more dollars will a writer who submits y+ a stories in a month earn than a writer who submits y+ b stories?
A.(a – b)( a + b + y)
B.a – b
C.a^2 – b^2
D.y( a – b)
Answer: C.a^2 – b^2
Explanation: total earned for y+a stories =a + a(a+b)
total earned for y+b stories =a+ b(a+b)
difference = a+a(a+b) -a -b(a+b)
=(a+b)(a-b) =a^2-b^2
answer is C
Question: If it would take one machine 20 minutes to fill a large production order and another machine 30 minutes to fill the same order, how many minutes would it take both machines working together, at their respective rates, to fill the order?
A.10min
B.12min
C.15min
D.20min
Answer: B.12min
Explanation: This question can be solved using the Work Formula:
Work = (A)(B)/(A+B) where A and B are the individual completion rates of the respective entities (for the same job).
We're told that one machine takes 10 minutes to complete a job and another machine takes 12 minutes to complete the same job. Plugging in those values gets us...
(20)(30)/(20+30) = 600/50 = 12 minutes
Answer is B
Question: There are five boxes in cargo hold. The weight of the first box is 200 kg and the weight of the second box is 20% higher than the weight of the third box, whose weight is 25% higher than the first box's weight. The fourth box at 350 kg is 30% lighter than the fifth box. Find the difference in the average weight of the four heaviest boxes and the four lightest boxes.
A.51.5 kg
B.75 kg
C.37.5 kg
D.112.5 kg
Answer: B.75 kg
Explanation: Solution: The weight of boxes is;
1st box = 200 kg;
3rd box = 250 kg;
2nd box = 300kg;
4th box = 350 kg;
5th box = 500 kg.
Hence, difference between heavier 4 and lighter 4 is 300.
Hence, difference in average is 75.
Answer: Option B
Question: Simple interest on a sum at 4% per annum for 2 years is Rs.80. The C.I. on the same sum for the same period is?
A.81.6
B.81.9
C.81.3
D.81.1
Answer: A.81.6
Explanation: SI = 40 + 40
CI = 40 + 40 + 1.6 = 81.6
Answer:A
Question: Ram spends 30% of his salary on house rent, 30% of the rest he spends on his children's education and 24% of the total salary he spends on clothes. After his expenditure, he is left with Rs. 2500. What is Ram's salary?
A.Rs. 11,494.25
B.Rs. 20,000
C.Rs. 10,000
D.Rs. 15,000
Answer: C.Rs. 10,000
Explanation: Solution: Let Ram's salary be x.
He spends on rent = 30% of x = 30x/100.
He spends on education = 30% from rest of the salary= (30*70x)/(100*100) = 21x/100.
He Spends on clothes = 24% of total salary = 24x/100.
Saving = 2500.
Salary of ram = x.
(30x/100) + (21x/100) + (24x/100) + 2500 = x.
(75x/100) = x-2500.
75x = 100x-250000.
Or, 100x-77x = 250000.
Or, x = 250000/25.
Or, x = 10000.
Ram's salary = Rs. 10000.
Answer: Option C
Question: Look at this series: 58, 52, 46, 40, 34, ... What number should come next?
A.26
B.28
C.30
D.32
Answer: B.28
Explanation: Explanation: This is a simple subtraction series. Each number is 6 less than the previous number.
Answer: Option B
Question: The symphony sells two kinds of tickets: orchestra, for $30, and upper tiers, for $12. On a certain night, the symphony sells 90 tickets and gets $1980 in revenue from the sales. How many orchestra tickets did they sell?
A.20
B.30
C.40
D.50
Answer: D.50
Explanation: Let x be the number of orchestra tickets.
Then 90-x is the number of upper tier tickets.
30x + 12(90-x) = 1980
18x = 1980-1080
x = 50
The answer is D.
Question: If, 6 years ago, Jamie was half as old as he is now, how old will he be in x years?
A.x + 12
B.x + 5
C.x + 2
D.x – 5
Answer: A.x + 12
Explanation: let his age be a. a-6=a/2 hence a=12. 12 years hence, a =x+12
Answer A
Question: Evaluate: 20 - 16÷4×3 =
A.16
B.10
C.4
D.8
Answer: D.8
Explanation: According to order of operations, 16÷4×3 (division and multiplication) is done first from left to right
16÷4×3 = 4 × 3 = 12
Hence
20 - 16÷4×3 = 20 - 12 = 8
correct answer D) 8
Question: The incomes of A and B are in the ratio 3:2 and their expenditure are in ratio 5:3. If each saves Rs. 1000, then, A's income can be:
A.Rs. 3000
B.Rs. 4000
C.Rs. 6000
D.Rs. 9000
Answer: C.Rs. 6000
Explanation: Solution: Let income of A and B be 3x and 2x respectively. Also, their expenditure is 5y and 3y.
Now, according to question,
3x-5y = 1000 ------- (i)*3
2x-3y = 1000	---------- (ii)*5
9x-15y-10x+15y = 3000-5000;
Or, -x = -2000;
Or, x = 2000;
Then, income of A = 3x = 3*2000 = Rs. 6000.
Answer: Option C
Question: In her backyard, Florry grows only yellow roses and white roses. Some of the rose bushes have flowers of both colors, and some have flowers of one color only. The number of rose bushes that have only yellow roses is 50% greater than the number of rose bushes that have only white roses. If there are yellow roses on 80% of Florry's rose bushes, then what percent W of her bushes have only yellow roses?
A.20
B.30
C.50
D.70
Answer: B.30
Explanation: let, the number of bushes with only yellow flowers be x
so, number of bushes with only yellow flowers will be 1.5x
if total number of bushes of flowers= T
then total number of bushes with yellow flowers= 0.8T
we can say that total number of bushes with yellow flowers+ bushes with only white flowers= total number of bushes with flowers
so, W=0.8T+x=T
x=0.2T
so, 1.5x=0.3T
30% flowers are yellow flowers
OA B
Question: A shopkeeper fixes the marked price of an item 25% above its cost price. The percentage of discount allowed to gain 8% is
A.11.59%
B.12.59%
C.13.59%
D.14.59%
Answer: B.12.59%
Explanation: Explanation:
Let the cost price = Rs 100
then, Marked price = Rs 125
Required gain = 8%,
So Selling price = Rs 108
Discount = 125 - 108 = 17
Discount% = (17/135)*100 = 12.59%
Option B
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
A.23
B.5
C.9
D.28
Answer: C.9
Explanation: 1/10 + 1/15 - 1/x = 1/18
x = 9
ANSWER C
Question: 2 persons can finish a job in 8 days. First person alone can finish the work in 24 days. How many days does the second person take to finish the job?
A.10 days
B.12 days
C.14 days
D.16 days
Answer: B.12 days
Explanation: 2 persons can do work in 1 day = 1/8
First person can do work in 1 day = 1/24
Second person can do work in 1 day = 1/8-1/24 = 1/12
So Second person can finish work in 12 days
ANSWER:B
Question: Mother, daughter and an infant combined age is 74, and mother's age is 46 more than daughter and infant. If infant age is 0.4 times of daughter age, then find daughters age.
A.22
B.10
C.37
D.38
Answer: B.10
Explanation: Assume M + D + I = 74; .................(1)
Also given M - D - I = 46 ⇒⇒ M = D + I + 46
Also I = 0.4 D ⇒⇒ I = 2/5 D
Substituting M and I values in the first equation we get D - 2525D - 46 + D + 2525D = 74
Solving D = 10
Answer:B
Question: On day one, a store sold 125 bags. On each of the next d days, the company sold 83 bags. If the average daily sales of bags over this time period (including day one) is 90 bags, what is the value of d?
A.4
B.5
C.6
D.7
Answer: B.5
Explanation: 125 + 83d = 90(d+1).
7d = 35.
d = 5.
The answer is B.
Question: Walking at 8KMPH From Point T to Point railway station, mike will miss the train by 5 minutes. If he walks at 10KMPH he will reach the station by 5 minutes early.What is the distance between Point T to Railway station?
A.A)9KM
B.B)6.66KM
C.C)7.25KM
D.D)12.40KM
Answer: B.B)6.66KM
Explanation: Since time differences given are in minutes so let's convert speed in Km per minute
8 kmph = 8/60 km per minute = (2/15) km per minute
10 kmph = 10/60 km per minute = (1/6) km per minute
Let, Time of train to depart from station = t minutes
Distance between Point T and Railway Station = Speed*Time = (2/15)*(t+5)
Distance between Point T and Railway Station = Speed*Time = (1/6)*(t-5)
i.e. (2/15)*(t+5) = (1/6)*(t-5)
i.e. 12t+60 = 15t - 75
i.e. 3t = 135
i.e. t = 45 minutes
i.e. Distance = (1/6)*(t-5) = (1/6)*(45-5) = 40/6 = 20/3 Km = 6.66 Km
Answer: Option B
Question: A number is doubled and 7 is added. If resultant is trebled, it becomes 99. What is that number
A.8
B.10
C.14
D.13
Answer: D.13
Explanation: Explanation:
=> 3(2x+7) = 99
=> 2x+7 = 33
=> x = 13
Option D
Question: A book club rented the party room of a local restaurant to meet and discuss its current novel over dinner. The total charge, including food and service, was $ 780. If each member of the club paid at least $ 42, then what is the greatest possible number of members in the club?
A.19
B.20
C.21
D.23
Answer: A.19
Explanation: Given: Each person spends $42.
By looking at the options, we see that if there were 20 members, each person will spend atleast $42.
Hence the greatest number of members = 19. Option A
Question: x is a positive integer less than 300. When x is divided by 7, the remainder is 1; when x is divided by 3, the remainder is 2. How many x are there?
A.21
B.22
C.23
D.24
Answer: B.22
Explanation: the nubmer which when divided by 7 leaves remainder 1 should be of the form 7k+1
this number when divided by 3 leaves remainder 2.
so,
(7k+1)-2 should be divisible by 3 or 7k-1 should be divisible by 3.
we now put the values of k starting from 0 to find first number divisible by 3
we find 1st number at k= 1
thus smallest number will be 7(1)+1 = 8
now,
next number will be = 8+ lcm of 37
i.e 29
now we will find number of all such values less than 500 by using the formula for last term of an a.p
8+(n-1)21=300
n=22.13
or n= 22
Answer:- B
Question: In an election between two candidates, 10% of votes are were declares invalid. First candidate got 1800 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:
A.9000
B.98000
C.10000
D.11000
Answer: C.10000
Explanation: 100 % - 10 % = 90 %
54%-36%=18%
18% ------> 1800 ( 18 × 100 = 1800)
100% -------> 10000 votes (100 × 100 = 10000)
C
Question: If A:B = 1/2: 1/3 B:C = 1/2:1/3 then A:B:C?
A.9:6:7
B.9:6:9
C.9:2:4
D.9:6:4
Answer: D.9:6:4
Explanation: A:B = 1/2:1/3 = 3:2
B:C = 1/2:1/3 = 3:2
--------------------
A:B:C = 9:6:4
Answer:D
Question: David and Rachel are getting married. The extended family wants to have its picture taken, but David's father is unwilling to stand next to Rachel's mother. How many options does the photographer have to arrange the 9 family members in a row for the picture?
A.7x8!
B.9×8!
C.8×9!
D.10!/2!
Answer: A.7x8!
Explanation: In how many ways David's father and Rachel's mother can stand together? Consider them as one unit: {F, M}. So, we'd have 9 units {F, M}, 1, 2, 3, 4, 5, 6, 7, which can be arranged in 8! ways. David's father and Rachel's mother within their unit can be arranged in 2! ways. Therefore, David's father and Rachel's mother can stand together in 8!*2! ways.
Total - Restriction =
= 9! - 8!*2! =
= 8!(9 - 2!) =
= 7*8!.
Answer: A.
Question: A group of three women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?
A. 7! – 2!3!2!
B.6! – 4!3!
C. 7! – 5!3!
D. 7 × 2!3!2!
Answer: B.6! – 4!3!
Explanation: 6 people can sit in 6! different ways. But because 3 men cannot sit together, we take them as a unit.
This unit of men, among themselves can sit in 3! ways.
Hence, 6! - 3!.
This unit of men along with3 women can sit in 4! different ways which also needs to be eliminated.
Hence 6! - 4!3!
B
Question: Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 480 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)
A.32/15
B.3/8
C.8/5
D.5/8
Answer: A.32/15
Explanation: Distance traveled by Eddy = 480 km
Time taken by Eddy = 3 hours
Average speed of Eddy = 480/3 = 160 km/hour
Distance traveled by Freddy = 300 km
Time taken by Freddy = 4 hours
Average speed of Freddy = 300/4 = 75 km/hour
Ratio of average speed of Eddy to Freddy = 160/75 = 32/15
Answer A
Question: A person covered one-fourth of the total distance at 26 kmph and remaining distance at 24 kmph. What is the average speed for the total distance?
A.21 (1/3) kmph
B.25 (1/3) kmph
C.29 (1/3) kmph
D.20 (1/3) kmph
Answer: A.21 (1/3) kmph
Explanation: A
Let the total distance be x km
total time taken = (x/4)/16 + (3x/4)/24 = x/64 + x/32 = 3x/64
Average speed = x/(3x/64) = 64/3kmph = 21 (1/3)kmph.
Question: P invested $2000 in a business and Q invested $4000 in a business. At the end of the year they got $6000 as the profit. Find their share?
A.$1000,$2000
B.$2000,$4000
C.$3000,$4000
D.$2000,$3000
Answer: B.$2000,$4000
Explanation: P:Q = 2000:4000
P:Q = 1:2
P's share = 6000*1/3 = $2000
Q's share = 6000*2/3 = $4000
Answer is B
Question: A team won 40 percent of its first 30 games in a particular season, and 80 percent of its remaining games. If the team won a total of 50 percent of its games that season, what was the total number of games that the team played?
A.40
B.50
C.60
D.70
Answer: A.40
Explanation: 50% is 10%-points above 40% and 30%-points below 80%.
Thus the ratio of "the first 30 games" to "remaining games" is 3:1.
So the team played a total of 30+10 = 40 games.
The answer is A.
Question: Solve the equation for x : 8(x + y + 2) = 8y - 8
A.-3
B.-2
C.-1
D.1
Answer: A.-3
Explanation: A
-3
8(x + y + 2) = 8y - 8
8x + 8y + 16 = 8y - 8
8x + 16 = -8
8x = -24
=> x = -3
Question: An article is bought for Rs.675 and sold for Rs.900, find the gain percent?
A.73 1/3%
B.63 1/3%
C.33 1/3%
D.93 1/3%
Answer: C.33 1/3%
Explanation: Explanation:
675 ---- 225
100 ---- ? => 33 1/3%
Answer:C
Question: A candidate got 34% of the votes polled and he lost to his rival by 640 votes. How many votes were cast?
A.2000
B.2400
C.2800
D.3200
Answer: A.2000
Explanation: Let x be the total number of votes.
0.34x + 640 = 0.66x
0.32x = 640
x = 640/0.32 = 2000
The answer is A.
Question: In a certain city each of 15 Girl Scout troops is represented by a colored flag. Each flag consists of either a single color or a pair of two different colors. If each troop has a different flag, what is the minimum number of colors needed for the flags. (Assume that the order of colors in a pair on a flag does not matter.)
A.3
B.4
C.6
D.5
Answer: D.5
Explanation: D.5:
if we have 5 colors we can choose pairs in 5C2 ways = 10 and single color flags are 5. Therefore total number of flags = 15.
ANS D.
Question: The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.6 years, The ratio of the number of boys to the number of girls in the class is
A.7 : 3
B.1 : 3
C.9 : 3
D.6 : 3
Answer: B.1 : 3
Explanation: Explanation:
Let the ratio be k : 1. Then,
k * 16.4 + 1 * 15.6 = (k + 1) * 15.8
<=> (16.4 - 15.8) k = (15.8 - 15.6) <=> k = 0.2/0.6 = 1/3.
Required ratio = 1/3 : 1 = 1 : 3.
Answer: B
Question: If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 5:7 then find the largest number?
A.40
B.42
C.44
D.48
Answer: A.40
Explanation: 2:3
2x + 10 : 3x + 10 = 5 : 7
7[2x + 10] = 5[3x + 10]
14x + 70 = 15x + 50
15x - 14x = 70 - 50
x = 20
Then the first number is = 2
2x = 40
A
Question: Pipes A and B can fill a tank in 5 and 6 hours. Pipe C can empty it in 12 hours. If all pipes are opened together, then the tank will be filled in?
A.60/17 hr
B.13/12 hr
C.52/11 hr
D.6 hr
Answer: A.60/17 hr
Explanation: Net part filled in 1 hour = 1/5 + 1/6 - 1/12 = 17/60
The tank will be full in 60/17 hr
Answer is A