RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A university cafeteria offers 22 flavors of pizza - Hawaiian and vegetarian. If a customer has an option (but not the obligation) to add extra cheese, mushrooms or both to any kind of pizza, how many different pizza varieties are available ?
A.41
B.8
C.12
D.4
Answer: D.4
Explanation: 2 flavours * 2 choices = 2C1*2C1 = 2*2=4=D
Question: In a question on division with zero remainder, a candidate took 12 as divisor instead of 21. The quotient obtained by him was 35. The correct quotient is:
A.15
B.18
C.20
D.22
Answer: C.20
Explanation: Number = (35 * 12) = 420
Correct quotient = 420/21 = 20
C
Question: If x and y are positive integers that have remainders of 2 and 5, respectively, when divided by 7, which of the following could be the sum of x and y?
A.16
B.19
C.40
D.49
Answer: D.49
Explanation: Minimum value of x = 9 and y = 12=>
x + y = 21 ( Divisible by 7 )
So, The correct answer choice will be one that will be divisible by 7..
Among the given options only (D) satisfies, hence answer must be (D)
Question: The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years
A.7:8
B.7:9
C.7:6
D.7:2
Answer: A.7:8
Explanation: Let P age and Q age is 6x years and 7x years.
Then 7x - 6x = 4 <=> x = 4
So required ratio will be (6x+4): (7x+4) => 28:32 => 7:8
Answer: A
Question: If x^2 = 111, which of the following is closest to a potential value of x?
A.-127
B.-11
C.12
D.13
Answer: B.-11
Explanation: Here the thing we must not forget is that X^even has two potential solutions
=> x =+- √111 => +- 11
this value is closer to -11
Hence B is correct.
Question: A box contains 5 green balls, 4 red balls and 6 white balls. A ball is drawn at random from the box. What is the probability that the ball drawn is either red or green?
A.2/3
B.1/4
C.3/5
D.1/2
Answer: C.3/5
Explanation: Total number of balls = 4+5+6 = 15
n(s)=15
E1 = event of drawing a red ball = 4/15
E2 = event of drawing a green ball = 5/15
P(E1)+P(E2) = (4/15)+(5/15) = 9/15 = 3/5
Answer is C
Question: There are some pigeons and hares in a zoo. If heads are counted, there are 200. If legs are counted, there are 580. The number of hares in the zoo is?
A.20
B.82
C.90
D.37
Answer: C.90
Explanation: 200*2 = 400
580
-----
180
1----2
?----180 = 90
Answer:C
Question: A man swims downstream 36 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water?
A.7
B.8
C.9
D.2
Answer: C.9
Explanation: 36 --- 3 DS = 12
? ---- 1
18 ---- 3 US = 6
? ---- 1 M = ?
M = (12 + 6)/2 = 9
Answer:C
Question: he ratio between the sale price and the cost price of an article is 5:6. What is the ratio between the profit and the cost price of that article?
A.2:6
B.1:8
C.1:6
D.2:1
Answer: C.1:6
Explanation: Let C.P. = Rs. 6x and S.P. = Rs. 5x.
Then, Gain = Rs. x
Required ratio = x : 6x = 1:6.
Answer:C
Question: In a class of 40 students, 12 enrolled for both English and German. 22 enrolled for German. If the students of the class enrolled for at least one of the two subjects, then how many students enrolled for only English and not German?
A.30
B.10
C.18
D.8
Answer: C.18
Explanation: Let A be the set of students who have enrolled for English and B be the set of students who have enrolled for German.
Then, (A U B) is the set of students who have enrolled at least one of the two subjects. As the students of the class have enrolled for at least one of the two subjects, A U B = 40
We know A U B = A + B - (A n B)
i.e, 40 = A + 22 - 12
or A = 30 which is the set of students who have enrolled for English and includes those who have enrolled for both the subjects.
However, we need to find out the number of students who have enrolled for only English = Students enrolled for English - Students enrolled for both German and English= 30 - 12 = 18.
ANSWER:C
Question: The population of a town is 20000. It increases annually at the rate of 20% p.a. What will be its population after 2 years?
A.24440
B.24800
C.28400
D.28800
Answer: D.28800
Explanation: Explanation:
Formula: (After =100 denominator
Ago = 100 numerator)
20000 * 120/100 * 120/100 = 120 * 120 * 2 = 28800
Answer: Option D
Question: Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 21,000. What was Simran's share in the profit?
A.Rs. 9423
B.Rs. 10,250
C.Rs. 9000
D.Rs. 14,000
Answer: C.Rs. 9000
Explanation: Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4
Simran's share = 21000 * 3/7 = Rs. 9000
ANSWER:C
Question: How many three-digit numbers ABC, in which A, B, and C are each digits, satisfy the equation 2B = A + C?
A.33
B.36
C.41
D.45
Answer: D.45
Explanation: Possible solutions are
Diff of 0 --
111,222,........,999 = 9
Diff of 1 --
123, 234, ....., 789 =7x2 = 14
Diff of 2 --
135, 246.......579 = 5x2 = 10
Diff of 3 --
147,258,369 = 3x2 = 6
Diff of 4 --
159 = 1x2 = 2
Last
210, 420,630,840 = 4
So total is 9+14+10+6+2+4 = 45.
ANSWER:D
Question: The price of a cycle is reduced by 25 % The new price is reduced by a further 20 %. The 2reductions together are equalto a single reduction of
A.39
B.45
C.60
D.56
Answer: C.60
Explanation: Let the original price of the cycle be 100. After the first reduction the price will be 75.
This new price is then reduced by 20% = 0.8 x 75 = 60
60 represents a reduction of 40 percent on the original.
C
Question: A small college reduced its faculty by approximately 14 percent to 195 professors. What was the original number of faculty members?
A.182
B.208
C.227
D.254
Answer: C.227
Explanation: If x is the original number of faculty members, then after 14% reduction in faculty members number is .86x
but we are given .86x = 195
x = 227
So the original number of faculty members is 227
Correct Answer - C
Question: A bowl of nuts is prepared for a party. Brand P mixed nuts are 20% almonds and Brand Q's Deluxe nuts are 25% almonds. If a bowl contains a total of 67 ounces of nuts, representing a mixture of both brands, and 15 ounces of the mixture are almonds, how many ounces of Brand Q's Deluxe mixed nuts are used?
A. 16
B. 20
C. 32
D. 44
Answer: C. 32
Explanation: lets say x ounces of P is mixed with Q.
=> 67-x ounces of Q is present in the mixture (as the total = 67 ounces)
given total almond weight = 15 ounces
(20x/100)+(25/100)(67-x) = 15
=> x = 35
=> 67-35 = 32 ounces of Q is present in the mixture.
Answer is C.
Question: 21 buses are running between two places P and Q. In how many ways can a person go from P to Q and return by a different bus?
A.None of these
B.420
C.212
D.224
Answer: B.420
Explanation: Explanation :
He can go in any bus out of the 21 buses.
Hence He can go in 21 ways.
Since he can not come back in the same bus that he used for travelling,
He can return in 20 ways.
Total number of ways = 21 x 20 = 420. Answer : Option B
Question: Exactly two sides of a certain 10-sided die are red. What is the probability that Kumar rolls the die 4 times and the die lands with a red side up for the first time on the fourth roll?
A.0.1026
B.0.01024
C.0.02
D.0.03
Answer: B.0.01024
Explanation: Total no. of sides = 10
Sides that are red = 2
Probability that the die lands with red side up = 2/10
Therefore, Probability that the die does not land with red side up = 1 - 2/10 = 8/10
Probability that Kumar rolls the die 3 times and the die lands with a red side up for the first time on the third roll
= (1st roll - non red face) X (2nd roll - non red face) X (3rd roll - non red face)x (4th roll- red face)
= (8/10) X (8/10) X (8/10) x(2/10)
= 1024/10000
= 0.01024
B
Question: In a certain game, each player scores either 2 or 5 points. If n players score 2 points and m players score 5 points and the total number of points scored is 45, what is the least possible difference between n and m.
A.a.1
B.b.2
C.c.5
D.d.7
Answer: B.b.2
Explanation: 2n+5m=45
try with n=5 and m=7 the equation will be satisfied
2(5)+5(7)=45
so difference between M and N is 2,
Answer B
Question: The chance of rain on any given day in Tel-Aviv is 50%. What is the probability Z that it rained in Tel-Aviv on exactly 4 out of 6 randomly chosen days?
A.15/64
B.30/64
C.1/2
D.1/4
Answer: A.15/64
Explanation: chances of rain on exactly 4 days and not rain on 2 days = (1/2)^4* (1/2)^2 = 1/64
Chosing 4 days out of 6 = 6!/(4!*2!) = 15
chances of rain on exactly 4 days out of 6 days Z = 15/64
Ans A it is.
Question: Which of the following fractions is the largest?
A.1/24
B.7/30
C.1/45
D.13/56
Answer: B.7/30
Explanation: For larger fraction, the numerator should be larger (denominators are same) and/or denominator should be smaller (numerators are same).
So comparing 1/24, 1/45 and 1/72, we ignore 1/45 and 1/72.
7/30 = 1/ (30/7) = 1/4.29
13/56 = 1/ (56/13) = 1/4.3
Since 1/4.29 has the smallest denominator, the largest fraction will be 7/30.
Answer (B)
Question: The cost price of 15 articles is equal to the selling price of 11 articles. Find the profit percent?
A.18 2/15
B.36 4/11
C.36 2/14
D.18 2/16
Answer: B.36 4/11
Explanation: 15 CP = 11 SP
11 --- 2 CP
100 --- ? =>36 4/11%.Answer: B
Question: Find the sum of first 10 odd numbers
A.10
B.40
C.200
D.100
Answer: D.100
Explanation: Explanation:
n2 = 102 = 100
Answer: Option D
Question: From a pack of cards, two cards are drawn one after the other, with replacement. What is the probability that the first card is a black card and the second card is a king or queen?
A.1/52
B.1/13
C.1/26
D.3/26
Answer: B.1/13
Explanation: P(black card) = 1/2
P(king or queen) = 2/13
P(black card then a king/queen) = 1/2 * 2/13 = 1/13
The answer is B.
Question: For my anniversary, I decided to surprise my wife. Since she is a voracious reader, I decided to collect a lot of books for her. On the first day of the month, I bought one book, on the second, I bought two and on the third, I bought three. This process went on till the anniversary and on the day, I had 190 books with me to gift her.
Can you calculate, on which day is our anniversary?
A.31
B.28
C.19
D.33
Answer: C.19
Explanation: C
19rd day
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 = 190
Thus our anniversary falls on the 19rd day of the month.
You can apply other formulas to shorten the process but that is the simplest way to do it.
Question: Two pipe A and B can fill a empty tank in 1 hour and 75 minute respectively.and there is pipe C for empty.if all three pipe open together in empty tank then tank get fill in 50 minutes.then in how much time pipe C take to empty the full tank?
A.100
B.90
C.80
D.70
Answer: A.100
Explanation: The work of pipe C in 1 hour=[1/60+1/75-1/50]=1/100
so,pipe C will empty that tank in 100 minute.
answer A
Question: A trader bought a car at 20% discount on its original price. He sold it at a 70% increase on the price he bought it. What percent of profit did he make on the original price?
A.18%
B.13%
C.12%
D.36%
Answer: D.36%
Explanation: Original price = 100
CP = 80
S = 80*(170/100) = 136
100 - 136= 36%
Answer: D
Question: Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 42 white marbles. How many red marbles could be in bag A?
A.1
B.3
C.4
D.10
Answer: D.10
Explanation: 6 is the answer.
Bag A-
R:W:B = 2:6:9
Let W in bag A be 6K
Bab B -
R:W = 1:4
Let W in bag B be 4P
W = 42= 6K+4P
=> K =5, P=3
Total Red's in bag A will be 2K = 10
D
Question: Each student at a certain business school is assigned a 6-digit student identification number. The first digit of the identification number cannot be zero, and the last digit of the identification number must be prime. How many different student identification numbers can the school create?
A.9,000
B.3,600
C.2,700
D.360,000
Answer: D.360,000
Explanation: The identification number is of the form _ _ _ _
1. First digit cannot be 0
2. Middle digits can be anything
3. Last digit has to be prime - 2, 3, 5, 7
We can have the following number of possibilities for each space
__ __ __ __
9 10 10 10 10 4
Total cases = 360000
Option D
Question: A man took a loan at rate of 12% per annum simple interest. After 3 years he had to pay 6480 interest. The principal amount borrowed by him was.
A.Rs 14000
B.Rs 15000
C.Rs 16000
D.Rs 18000
Answer: D.Rs 18000
Explanation: Explanation:
S.I.=Pâˆ—Râˆ—T/100
=>P=S.I.âˆ—100/Râˆ—T
=>P=6480âˆ—100/12âˆ—3=Rs18000
Option D
Question: A boat goes 100 km downstream in 10 hours, and 45 m upstream in 15 hours. The speed of the stream is?
A.22 1/7
B.22 1/4
C.3 1/2
D.22 1/1
Answer: C.3 1/2
Explanation: 100 --- 10 DS = 10
? ---- 1
45 ---- 15 US = 3
? ----- 1 S = (10 - 3)/2
= 3 1/2 kmp Answer: C
Question: 40% of Ram's marks is equal to 20% of Rahim's marks which percent is equal to 30% of Robert's marks. If Robert's marks is 80, then find the average marks of Ram and Rahim?
A.70
B.97
C.87
D.90
Answer: D.90
Explanation: Given, 40% of Ram's marks = 20% of Rahim's marks = 30% of Robert's marks.
Given, marks of Robert = 80
30% of 80 = 30/100 * 8 = 24
Given, 40% of Ram's marks = 24.
=> Ram's marks = (24 * 100)/40 = 60
Also, 20% of Rahim's marks = 24
=> Rahim's marks = (24 * 100)/20 = 120
Average marks of Ram and Rahim = (60 + 120)/2 = 90.
Answer:D
Question: When Sourav increases his speed from 20 Km/hr to 25 Km/hr, he takes one hour less than the usual time to cover a certain distance. What is the distance usually covered by him?
A.125 Km
B.100 Km
C.80 Km
D.120 Km
Answer: B.100 Km
Explanation: DETAILED SOLUTION
Here, the distance travelled by Sourav is constant in both the cases. So,
20 x t = 25 x (t-1) = D
=) 20t = 25t - 25
=) 5t = 25
=) t = 5 hrs So, Distance travelled = 20 X 5 = 100 Km.
CORRECT ANSWER B.
Question: Stock / Number of shares
V ------------ 68
W ---------- 112
X ------------ 56
Y ------------ 94
Z ------------ 45
The table shows the number of shares of each of the 5 stocks owned by Mr Sami. If Mr. Sami was to sell 20 shares of Stock X and buy 19 shares of stock Y, what would be the increase in the range of the numbers of shares of the 5 stocks owned by Mr. Sami?
A.4
B.6
C.9
D.10
Answer: D.10
Explanation: Based on the original number of shares, the range would be: 112 - 45 = 67
However, the prompt tells us that two of the values in the table are going to change. After the changes, the values will be:
V 68
W 112
X 36
Y 113
Z 45
Now the range is 113 - 36 = 77
The INCREASE in the range requires us to compare thenewrange to theoldrange: 77 - 67 = 10
D
Question: 360 metres long yard, 31 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees
A.10
B.12
C.14
D.16
Answer: B.12
Explanation: 31 trees have 30 gaps between them,
Required distance (360/30) = 12
B
Question: The no. of girls in a class are seven times the no. of boys, which value cannever be the of total students?
A.2
B.5
C.8
D.9
Answer: C.8
Explanation: Let the boys are X, then girls are 7X, total = X+7X = 8X
So it should be multiple of 8, 30 is not a multiple of 8.
C
Question: A 360 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 520 m in ?
A.57.6 sec
B.20.2 sec
C.31.8 sec
D.50.4 sec
Answer: A.57.6 sec
Explanation: Speed = 55 Km/hr
(to convert km/hr in to M/s)
= 55 x 5/18 M/s
Distance = 360 m + 520 m ( If questions is about train crossing a post you need to consider only the length of Train, )
= 880 m
Time = Distance / Speed
= 880 x 18 / (5 x 55)
= 57.6 sec
Ans is :A
Question: What is the value of: 2^6 + 2^9 ?
A. 5(2^6)
B. 3(2^6)
C. 2^15
D. 2^84
Answer: A. 5(2^6)
Explanation: 2^6 + 2^9 = 2^6 (1 + 2^2) = 2^6 (1 + 4) = 5 (2^6), Answer A.
Question: Two brothers A and B leave point A and point B simultaneously and travel towards Point B and Point A on the same route at their respective constant speeds. They meet along the route and immediately proceed to their respective destinations in 32 minutes and 50 minutes respectively. How long will B take to cover the entire journey between Point B and point A?
A.65
B.70
C.75
D.90
Answer: D.90
Explanation: Let x per minute be the speed of A and y per minute be the speed of B.
After meeting at a point, A travels for 32 mins and B travels for 50 mins. So distance covered by each of them post point of crossing
A= 32x and B=50y
The distance covered by A and B before they cross each would be distance covered by B and A post crossing respectively.
Therefore distance covered by B before he meets A= 32x
Time taken by B cover 32x distance= 32x/y mins
Therefore total time taken by B= 32x/y + 50 mins ................. I
We need to find value of x in terms of y to arrive at final answer.
Total distance= 32x+50y
Combined speed of A and B= x+y
Therefore time taken before A and B meet en-route= (32x+50y)/(x+y)
Time taken by B reach destination after meeting A= 50 mins
Total travel time for B= [(32x+50y)/(x+y)]+50 mins ...................II
Equate I and II
32x/y+50= [(32x+50y)/(x+y)]+50
(32x+50y)/y=(82x+100y)/(x+y)
32x^2+50xy+32xy+50y^2=82xy+100y^2
32x^2+82xy-82xy+50y^2-100y^2=0
32x^2-50y^2=0
32x^2=50y^2
16x^2=25y^2
Taking square root.. (since x and y denote speed, square root can't be negative)
4x=5y
y=4x/5 ............ III
substitute in I
=32x/(4x/5) + 50
=32x*5/4x + 50
=40+50
=90 mins
D
Question: An enterprising businessman earns an income of Re 1 on the first day of his business. On every subsequent day, he earns an income which is just double of that made on the previous day. On the 20th day of business, he earns an income of:
A.Rs 219
B.Rs 220
C.Rs 20²
D.Rs 20
Answer: A.Rs 219
Explanation: 2nd day he earns = 2 = 2(2 – 1)
3rd day he earns = 2(3 – 1)
On 20th day he earns 2(20 -1) = 219 rupees
ANSWER:A
Question: In the reading room of a library, there are 23 reading spots. Each reading spot
consists of a round table with 9 chairs placed around it. There are some readers such
that in each occupied reading spot there are different numbers of readers. If in all there
are 36 readers, how many reading spots do not have even a single reader?
A.12
B.13
C.14
D.15
Answer: D.15
Explanation: 1+2+3+4+5+6+7+8 = 36
so, 8 spots are occupied by users
23-8 = 15
ANSWER:D
Question: A man's speed with the current is 20 kmph and speed of the current is 3 kmph. The Man's speed against the current will be
A.11 kmph
B.12 kmph
C.14 kmph
D.17 kmph
Answer: C.14 kmph
Explanation: Explanation:
If you solved this question yourself, then trust me you have a all very clear with the basics of this chapter.
If not then lets solve this together.
Speed with current is 20,
speed of the man + It is speed of the current
Speed in still water = 20 - 3 = 17
Now speed against the current will be
speed of the man - speed of the current
= 17 - 3 = 14 kmph
ANSWER IS C
Question: How many of the positive factors of 42 , 104 and how many common factors are there in numbers?
A.4
B.2
C.3
D.5
Answer: B.2
Explanation: factors of 42 - 1,2,3,6,7,14,21,42
factors of 104 - 1,2,4,8,13,26,52,104
Comparing both, we have two common factors of 40 and 104- 1,2,
Answer(B)
Question: 4,8,16,32,....
A.64
B.60
C.61
D.62
Answer: A.64
Explanation: 2*2=4
4*2=8
8*2=16
16*2=32
32*2=64
ANSWER:A
Question: Evaluate permutation equation
59P3
A.195052
B.195053
C.195054
D.185054
Answer: C.195054
Explanation: Explanation:
nPr=n!/(n−r)!
59P3=59!/(56)!
=59∗58∗57∗56!/(56)!=195054
Option C
Question: A mobile battery in 1 hour charges to 20 percent.How much time (in minute) will it require more to charge to 65 percent.
A.145
B.150
C.195
D.160
Answer: C.195
Explanation: 1 hr =20 percent.Thus 15 min=5 percent .Now to charge 65 percent 195 min.Answer:C
Question: Find the invalid no.from the following series 15 46 63 71 75 77 78
A.15
B.46
C.75
D.77
Answer: B.46
Explanation: In this question, if you start from the beginning, firstly the difference is 31, then the difference is 17, then the difference is 8. So there is no logic. If you start backwards,you can see that firstly, 1 is added, then 2 is added, then 4 is added, then 8,16 and 32 should have been added. So you have got the right clue. So 15 + 32 the first number should be 47 and afterwards, the series becomes + 16, + 8, + 4and so on.
B
Question: A train running at the speed of 50 km/hr crosses a pole in 18 seconds. Find the length of the train.
A.150
B.188
C.250
D.288
Answer: C.250
Explanation: Speed = 50*(5/18) m/sec = 125/9 m/sec
Length of Train (Distance) = Speed * Time
(125/9) * 18 = 250 meter
Answer: C
Question: Find the number of factors of 300 excluding 1 and itself.
A.18
B.17
C.16
D.14
Answer: C.16
Explanation: 300 = 4.75 = 4.25.3 = 22.52.31
Number of factors of 300 = (2 + 1)(2 + 1)(1 + 1) = 18.
There are 16 factors of 300 excluding 1 and itself.
ANSWER:C
Question: The average marks of a class of 35 students is 45 and that of another class of 55 students is 65. Find the average marks of all the students?
A.52.6
B.52.4
C.52.1
D.57
Answer: D.57
Explanation: Sum of the marks for the class of 35 students = 35 * 45 = 1575
Sum of the marks for the class of 55 students = 55 * 65 = 3575
Sum of the marks for the class of 90 students =
1575 + 3575 = 5150
Average marks of all the students = 5150/90 = 57.Answer: D
Question: The average of five results is 46 and that of the first four is 45. The fifth result is?
A.23
B.27
C.21
D.50
Answer: D.50
Explanation: 5 * 46 – 4 * 45
= 50
Answer: D
Question: The smallest ratio out of 1:1, 2:1, 1:3,4:1 and 3:1 is?
A.1:1
B.1:3
C.2:1
D.3:1
Answer: B.1:3
Explanation: 1/1=1
1/3=0.333
2/1=2
3/1=3
4/1=4
ANSWER:B
Question: A can complete a project in 10 days and B can complete the same project in 30 days. If A and B start working on the project together and A quits 10 days before the project is completed, in how many days will the project be completed?
A.18 days
B.15 days
C.26.67 days
D.16 days
Answer: B.15 days
Explanation: Let X = the number of days taken to complete the project.
The amount of work done by A is (x-10) * (1/20).
The amount of work done by B is (x) * (1/30).
(1/10)*(x-10) + (1/30)*(x) = 1
(x/10) + (x/30) - 1) = 1
4x/30 = 2
x = 15
Therefore, the answer is B: 15.
Question: A and B go around a circular track of length 1500 m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point?
A.120 sec
B.165 sec
C.300 sec
D.167 sec
Answer: C.300 sec
Explanation: Time taken to meet for the first time at the starting point
= LCM { length of the track / speed of A , length of the track / speed of B}
= LCM { 1500/ (36 * 5/18) , 1500/ (54 * 5 /18) }
= LCM (150, 100)
=300sec.
Answer:C
Question: In a country there are 2 hospitals for every 1000 citizens. If there are 50,000 citizens, how many hospitals are there in that country?
A.50
B.100
C.60
D.75
Answer: B.100
Explanation: 2/1000=x/50,000
x=100
Answer is B
Question: A student was asked to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and x. He found the mean to be 12. What should be the number in place of x ?
A.2
B.7
C.8
D.9
Answer: B.7
Explanation: Explanation:
Clearly, we have (3 + 11 + 7 + 9 + 15 + 13 + 8 + 19 + 17 + 21 + 14 + x) / 12 = 12.
or 137 + x = 144 or x = 144 - 137 = 7.
Answer: B) 7
Question: A student has to obtain 35% of the total marks to pass. He got 100 marks and failed by 40 marks. The maximum marks are?
A.280
B.400
C.420
D.480
Answer: B.400
Explanation: Let the maximum marks be x
Then, 35% of x = 100+40
35x/100 = 140
35x= 140*100= 14000
x = 400
Answer is B
Question: A rectangular-shaped carpet that measures x feet by y feet is priced at $24. What is the cost of the carpet, in dollars per square yard? (1 square yard = 9 square feet)
A.180xy
B.216/(xy)
C.20xy
D.20xy/9
Answer: B.216/(xy)
Explanation: The area of the carpet in feet is xy.
The area in square yards is xy / 9.
The price per square yard is 24 / (xy/9) = 216/(xy).
The answer is B.
Question: What is the remainder when 3^86 is divided by 5 ?
A.1
B.2
C.4
D.0
Answer: C.4
Explanation: 3^0 = 1
3^1 = 3
3^2 = 9
3^3 = 27
3^4 = ...1
3^5 = ....3
3^6 = ......9
and so on.
86/4 = 21 (with a remainder 2) so the last number is a 9.
so when 3^86 is divided by 5 the remainder is 4, ANS = C