RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The average age of 15 students of a class is 15 years. Out of these, the average age of 5 students is 14 years and that of the other 9 students is 16 years. Tee age of the 15th student is:
A.18 years.
B.11 years.
C.21 years.
D.36 years.
Answer: B.11 years.
Explanation: Age of the 15th student=
[15 * 15 - (14 * 5 + 16 * 9)] = (225 - 214) = 11 years.
Answer: B
Question: Of the 150 employees at company X, 80 are full-time, and 100 have worked at company X for at least a year. There are 20 employees at company X who aren’t full-time and haven’t worked at company X for at least a year. How many full-time employees of company X have worked at the company for at least a year?
.
A.20
B.30
C.50
D.80
Answer: C.50
Explanation: 150 employees
80 are full-time
100 have worked at company X for at least a year
20 employees at company X who aren’t full-time and haven’t worked at company X for at least a year.
How many full-time employees of company X have worked at the company for at least a year?
150-80=70 employees not full time
70-20= 50 employees not full time who worked over a year
100 employees have worked at company X for at least a year-50 employees not full time who worked over a year = 50 full-time employees of company X have worked at the company for at least a year
ANSWER:C
Question: The speed of a car is 90 km in the first hour and 60 km in the second hour. What is the average speed of the car?
A.75
B.72
C.30
D.80
Answer: A.75
Explanation: Explanation:
speed= Distance/ Time
S = (90 + 60)/2 = 75 kmph
Answer: A
Question: Ana is 5 years more than Jack. The sum of their ages is 29. Find the ages of Jack.
A.10
B.11
C.12
D.13
Answer: C.12
Explanation: Let Jack's age = x
And Ana's age, y = x+5---->(1)
Sum of their ages, x+y = 29----->(2)
substitute equation 1 in 2,
x+(x+5)=29
2x+5=29
2x=29-5
2x=24 ==>x=12(Jack's age)
ANSWER:C
Question: If a solid sphere of radius 10 cms is moulded into 8 spherical solid balls of equal radius, then surface area of each ball (in cm2) is?
A.100π
B.7π
C.60π
D.50π
Answer: A.100π
Explanation: 4/3 π * 10 * 10 * 10 = 8 * 4/3 πr3
r = 5
4π * 5 * 5 = 100π
ANSWER:A
Question: Find the odd man out. 7,13,19,25,29,37,43
A.19
B.29
C.25
D.43
Answer: C.25
Explanation: Explanation :
All given numbers except 25 are prime numbers. Answer : Option C
Question: The radius of a wheel is 22.5 cm. What is the distance covered by the wheel in making 500 resolutions?
A.708 m
B.707.14 m
C.774 m
D.714 m
Answer: B.707.14 m
Explanation: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.5 = 70714 cm
= 707.14 m
Answer:B
Question: Solution A is 20% ammonia and Solution B is 80% ammonia. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% ammonia solution?
A.6:4
B.6:14
C.4:4
D.4:6
Answer: C.4:4
Explanation: Forget the volumes for the time being.
You have to mix 20% and 80% solutions to get 50%. This is very straight forward since 50 is int he middle of 20 and 80 so we need both solutions in equal quantities. If this doesn't strike, use
w1/w2 = (A2 - Aavg)/(Aavg - A1)
w1/w2 = (80 - 50)/(50 - 20) = 1/1
So the volume of the two solutions will be equal. Answer has to be 4:4=C
Question: 10 distinct integers are arranged in ascending order. The range of the first 7 is 25 and that of last 7 is 30. What is the maximum range W of the 10 numbers?
A.25
B.27
C.30
D.52
Answer: D.52
Explanation: Positions: 1 2 3 4 5 6 7 8 9 10
Given: 1st position = x; 4th position = a; 7th position = y; 10th position = b
y - x = 25
Let x be 0 and y = 25. We are asked to maximize the range and the integers are distinct.
b - a = 30 --> b = 30 + a
In order to increase the range, we have to maximize the value of 'b'.
'b' can be maximized by taking the max value of 'a'.
From the assumed values, maximum value of 'a' can be 22.
Therefore, b = 30 + 22 = 52
Range W= 52 - 0 = 52
Answer: D
Question: If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 4 years the amount to be paid is?
A.8118
B.8127
C.8618
D.8774
Answer: D.8774
Explanation: A = 7500(26/25)4
= 8774
Answer: D
Question: If the annual rate of simple interest increases from 10% to 12 1/2 %, a man's yearly income increases by Rs. 1250. His principal in Rs. is?
A.10000
B.30000
C.50000
D.60000
Answer: C.50000
Explanation: Let the sum be Rs. x. Then,
(x * 25/2 * 1/100) - (x * 10 * 1)/100 = 1250
25x - 20x = 250000
x = 50000
Option C
Question: The ratio of the number of red cars in a certain parking lot to the number of black cars is 3 to 8. If there are 75 black cars in the lot, how many red cars are there in the lot?
A.11
B.28
C.24
D.29
Answer: B.28
Explanation: B is correct
R/B = 3/8 and B =75
R = 75*3/8 = 28
Question: Mr. Donald has $900 in ten, twenty, fifty and one hundred dollar bills. He has an equal number of each denomination of bill. How many total bills does Mr. Donald have?
A.10
B.20
C.30
D.40
Answer: B.20
Explanation: Let the number of each type of bill = bThen 10b + 20b + 50b + 100b = 900180b = 900b = 5So: The total number of bills that Mr. Donald has = 4b = 20Answer: B
Question: By selling 50 meters of cloth. I gain the selling price of 15 meters. Find the gain percent?
A.42 6/9%
B.42 5/7%
C.42 6/8%
D.42 6/7%
Answer: D.42 6/7%
Explanation: SP = CP + g
50 SP = 50 CP + 15 SP
35 SP = 50 CP
35 --- 15 CP gain
100 --- ? => 42 6/7%
Answer: D
Question: How many pairs (w, w+1) have one or more prime factors common, where w is an integer and 2 ≤ w ≤9 ?
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: w and w+1 are consecutive integers.
Two consecutive integers are co-prime, which means that they don't share ANY common factor but 1. For example 20 and 21 are consecutive integers, thus only common factor they share is 1.
Answer: A.
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1120?
A.1000
B.2777
C.2688
D.2772
Answer: A.1000
Explanation: 1120 = P [1 + (5*12/5)/100]
P= 1000
Answer: A
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
A.Rs.4528
B.Rs.4520
C.Rs.4527
D.Rs.4530
Answer: D.Rs.4530
Explanation: Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls
= 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3)
= 906 sq.ft.
Total cost = 906 * 5
= Rs.4530
Answer:D
Question: If m, n, and o are three different positive integers whose sum is prime, which of the following statements could be true?
A.Each of m + n, m + o, and n + o is prime.
B.Each of m + 3, n + 3, and o + 3 is prime.
C.Each of m, n, and o is prime.
D.The average (arithmetic mean) of m, n, and o is prime.
Answer: C.Each of m, n, and o is prime.
Explanation: the question asks could be!!!!
this means that if at least one option works, it is the answer.
3, 7, 19 satisfies the condition, since 29 is a prime number. Since the question asks for a could be - we know automatically that C is the answer.
Question: A basketball is dropped from a height of 30 feet. If it bounces back up to a height that is exactly half of its previous height, and it stops bouncing after hitting the ground for the fourth time, then how many total feet will the ball have traveled after 2 full bounces.
A.50
B.55
C.60
D.75
Answer: D.75
Explanation: Initial distance = 30 feet
first bounce = 15 feet up + 15 feet down = 30 feet
second bouche = 7.5 feet up + 7.5 feet down = 15 feet
total distance covered = 30+30+15=75
Answer : D
Question: The difference between a number and its two fifth is 510. What is 10% of that number?
A.12.75
B.50
C.85
D.204
Answer: C.85
Explanation: Solution
Let the number be x.
Then, x - 2 / 5 x = 510.
‹=›3 / 5 x = 510
‹=›x = [510 x 5 / 3] = 850.
Therefore 10% of 850 = 85.
Answer C
Question: Four of the following five are alike in a certain way and so form a group. which one does not belong to that group?
A.Tooth
B.Chin
C.Nose
D.Eye
Answer: B.Chin
Explanation: All others have two vowels each
Answer :B
Question: The average score of a cricketer for ten matches is 38.9 runs. If the average for the first six matches is 42, what is the average for the last four matches?
A.34.25
B.36.4
C.40.2
D.32.25
Answer: A.34.25
Explanation: Explanation:
Total runs scored in 10 matches = 10 × 38.9
Total runs scored in first 6 matches = 6 × 42
Total runs scored in the last 4 matches = 10 × 38.9 - 6 × 42
Average of the runs scored in the last 4 matches = 10×38.9−6×42/4
=389−252/4=137/4=34.25
Answer: Option A
Question: A grocer purchased a quantity of bananas at 3 pounds for $0.50 and sold the entire quantity at 4 pounds for $1.00. How many pounds did the grocer purchase if the profit from selling the bananas was $11.00?
A. 40
B. 60
C. 90
D. 132
Answer: D. 132
Explanation: Cost price of 1 pound of bananas = 0.5/3 = 1/6
Selling price of 1 pound of bananas = 1/4
Profit per pound = (1/4 - 1/6) = (1/12)
Total profit is given as 11
(1/12)*x = 11
x = 132
Answer: D
Question: Pipe A can fill a tank in 6 hours, pipe B in 4 hours, and pipe C in 12 hours. If all the pipes are open, in how many hours will the tank be filled?
A.1.5
B.2
C.2.5
D.3
Answer: B.2
Explanation: The part filled by A + B + C in 1 hour
= 1/6 + 1/4 + 1/12
= 12/24 = 1/2
All the three pipes together will fill the tank in 2 hours.
The answer is B.
Question: We have 7770 balls available, and there is 1 ball on d top of rack and then 3 balls on d 1st floor behind the top rack (horizontal rack) and then 6 balls on 2nd floor then 10 balls on 3rd floor,
How many floors can be accomdated with the given no of balls...???
A.36
B.35
C.34
D.33
Answer: B.35
Explanation: 1+3+6+10+........=7770 sum of triangular number
n*(n+1)*(n+2)/6 gives 35
ANSWER:B
Question: A is thrice as good as B in work. A is able to finish a job in 60 days less than B. They can finish the work in - days if they work together.
A.18 days
B.22 ½ days
C.24 days
D.26 days
Answer: B.22 ½ days
Explanation: Explanation :
If A completes a work in 1 day, B completes the same work in 3 days
Hence, if the difference is 2 days, B can complete the work in 3 days
=> if the difference is 60 days, B can complete the work in 90 days
=> Amount of work B can do in 1 day= 1/90
Amount of work A can do in 1 day = 3 × (1/90) = 1/30
Amount of work A and B can together do in 1 day = 1/90 + 1/30 = 4/90 = 2/45
=> A and B together can do the work in 45/2 days = 22 ½ days
ANSWER IS B
Question: If 3a – 2b – 2c = 32 and √3a-√(2b+2c)=5, what is the value of a + b + c?
A.3
B.9
C.10
D.12
Answer: B.9
Explanation: when we look at the two equations, we can relize some similarity, so lets work on it..
3a – 2b – 2c = 32 can be written as √3a^2-√(2b+2c)^2=32
{√3a-√(2b+2c)}{√3a+√(2b+2c)}=32..
or 4*√3a+√(2b+2c)=32..
or √3a+√(2b+2c)=8..
now lets work on these two equations
1)√3a-√(2b+2c)=4..
2)√3a+√(2b+2c)=8..
A) add the two eq..
√3a+√(2b+2c)+√3a-√(2b+2c)=12..
2√3a=12..
or √3a=6..
3a=36..
a=12.
B) subtract 1 from 2..
√3a+√(2b+2c)-√3a+√(2b+2c)=4..
2√(2b+2c)=4..
√(2b+2c)=2..
2b+2c=4..
or b+c=2..
from A and B a+b+c=12+2=14..
B
Question: A group of men decided to do a work in 12days, but 6 of them became absent. If the rest of the group did the work in 14days, Find the original number of men?
A.15
B.42
C.44
D.45
Answer: B.42
Explanation: Original number of men = 6*14 / (14-12) = 42
Answer is B
Question: Two numbers are in the ratio 5:8 and thier H.C.F is 4. Find the numbers.
A.25 and 40
B.20 and 32
C.30 and 48
D.15 and 24
Answer: B.20 and 32
Explanation: Explanation:
Let two numbers 5x, 8x their H.C.F = 4
Therefore H.C.F is 4
i.e, x in this case.
Therefore The numbers are 5 x 4 = 20
8 x 4 = 32
Answer: Option B
Question: Find the number, when 15 is subtracted from 7 times the number, the result is 10 more than twice of the number
A.5
B.15
C.7.5
D.4
Answer: A.5
Explanation: Explanation:
Let the number be x.
7x -15 = 2x + 10 => 5x = 25 => x = 5
Answer: Option A
Question: By selling 18 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
A.8
B.9
C.7
D.12
Answer: D.12
Explanation: 80% --- 18
120% --- ?
80/120 * 18 = 12
Answer: D
Question: A machine puts c caps on bottles in m minutes. How many Q hours will it take to put caps on b bottles?
A.60bm/c
B.Q=bm/60c
C.bc/60m
D.60b/cm
Answer: B.Q=bm/60c
Explanation: The machine puts c caps in m minutes or c caps in m/60 hours.
Rate = c/m/60 = 60c/m.
To put b caps the machine will take:-
Time = Work/Rate
T = b/60c/m = bm/60c
Answer is B.
Question: Of the students at a certain high school, 100 percent took a course in algebra or geometry and 20 percent took courses in both. If the percent of students who took a course in algebra was 2 times the percent of students who took a course in geometry, what percent of the students took a course in algebra but not geometry?
A.50%
B.60%
C.45%
D.40%
Answer: B.60%
Explanation: You can also just use the formula
n(A or B) = n(A) + n(B) - n(A and B)
100 = 2X + X - 20
X = 40
2X = 80
This is the number of people who took algebra including those who took both. To get the number of people who took only algebra, 80 - 20 = 60%
Answer (B)
Question: The radius of a semi circle is 3.1 cm then its perimeter is?
A.15.94
B.12.41
C.16.1
D.32.92
Answer: A.15.94
Explanation: 36/7 r = 6.3 = 15.94
Answer:A
Question: I chose a number and divide it by 6. Then I subtracted 189 from the result and got 3. What was the number I chose?
A.1200
B.1152
C.1189
D.1190
Answer: B.1152
Explanation: Let x be the number I chose, then
x/6−189=3
x/6=192
x=1152
Answer is B.
Question: In a group of hats consisting of only blue hats, green hats, and purple hats, the ratio of blue hats to green hats to purple hats is 7:4:12. If there are a total of 69 hats in this group, how many of these hats are not blue?
A.28
B.42
C.48
D.64
Answer: C.48
Explanation: B:G:P = 7:4:12 --> total of 23 parts.
Not blue = (G + P)/(total)*92 = 16/23*69 = 48.
Answer: C.
Question: Find the compound interest on Rs. 25000 in 2 years at 4% per annum. The interest being compounded half yearly.
A.Rs 2060.808
B.Rs 2060.801
C.Rs 2060.804
D.Rs 2060.802
Answer: C.Rs 2060.804
Explanation: Explanation:
Given:
Principal = Rs. 25000, Rate = 4 % per half year, Time = 2 years = 4 half years
Therefore,
Amount = P( 1 + (R/2)/100)2n
Amount = Rs. [25000*(1+ 2/100)4] = Rs. (25000 * 51/50*51/50*51/50* 51/50)
= Rs. 27060.804
Therefore,
C.I. = Rs. ( 27060.804 – 25000)
= Rs 2060.804
ANSWER: C
Question: Choose the missing terms out of the given alternatives.
BXJ, ETL, HPN, KLP, ?
A.MHQ
B.MIP
C.NIR
D.NHR
Answer: D.NHR
Explanation: D
NHR
The first, second and third letters move three steps forward, four steps backward and two steps forward respectively.
Question: In how many ways 4 boys and 4 girls can be seated in a row so that boys and girls are alternate?
A.1152
B.1987
C.2012
D.1856
Answer: A.1152
Explanation: number of ways = 2*4!*4! = 1152
Answer is A
Question: The speed of a subway train is represented by the equation z=s^2+2s for all situations where 0≤s≤7, where z is the rate of speed in kilometers per hour and s is the time in seconds from the moment the train starts moving. In kilometers per hour, how much faster is the subway train moving after 5 seconds than it was moving after 3 seconds?
A.4
B.9
C.15
D.20
Answer: D.20
Explanation: Given: z=s^2+2s for 0≤s≤7
z(3) = 3^2 + 2*3 = 15
z(5) = 5^2 + 2*5 = 35
Therefore z(7) - z(3) = 35 - 15 = 20 km/hr
Option D
Question: A college starts from 10 AM continues till 1:30 PM. In this duration there are five periods. If 5 minutes are provided before each period to leave the room and enter the other, then what is the duration of each period?
A.38 min
B.41 min
C.40 min
D.42 min
Answer: A.38 min
Explanation: before first period no need to leave the room and enter the room.
so,for 5 periods 4 times 5 minutes break will be provided. that is 20 mins.
10 A.M-1:30 P.M=210mins
210-20=190
therefore 190/5=38 mins.
ANSWER:A
Question: John has taken four (4) tests that have an average of 90. In order to bring his course grade up to a ‘B’, he will need to have a final average of 87. What will he need to average on his final two tests to achieve this grade?
A.81
B.90
C.82
D.94
Answer: A.81
Explanation: Traditional Method:
Total scored till now 90*4=360
Total score to avg 87 in 6 tests = 87*6=522
Total to be scored on 2 tests = 522-360=162
Avg on 2 tests = 162/2 = 81
Answer: A
Question: If 2x + y = 7 and x + 2y = 10, then (x + y)/3 =
A. 1
B. 4/3
C. 17/9
D. 18/5
Answer: C. 17/9
Explanation: We have two equations:
2x + y = 7
x + 2y = 10
Notice that something nice happens when we ADD them. We get:
3x + 3y = 17
Divide both sides by 3 to get:x + y = 17/3
So, (x + y)/3 =17/9
Answer: C
Question: A man buys an article for $20. and sells it for $25. Find the gain percent?
A.25%
B.50%
C.20%
D.15%
Answer: A.25%
Explanation: C.P. = $20
S.P. = $25
Gain = $5
Gain% = 5/20 *100 =25%
Answer is A
Question: The distance between Delhi and Mathura is 185 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet?
A.10.50 a.m.
B.11.40 a.m.
C.10.30 a.m.
D.11.50 a.m.
Answer: B.11.40 a.m.
Explanation: D = 185 â€“ 20 = 165
RS = 20 + 25 = 45
T = 165/45 = 3 2/3 hours
8 a.m. + 3 hrs 40 min = 11.40 a.m.
ANSWER:B
Question: A car runs at the speed of 50 km per hour when not serviced and runs at 60 kmph when serviced. After servicing the car covers a certain distance in 6 hours. How much time will the car take to cover the same distance when not serviced?
A.8 hours 12 minutes
B.6 hours 15 minutes
C.8 hours 15 minutes
D.7 hours 12 minutes
Answer: D.7 hours 12 minutes
Explanation: Explanation :
Time = 60*6 / 50 = 7 hours 12 mins
Answer – D
Question: Answer: Option D
Explanation:
A.11 3/3
B.11 3/8
C.11 3/2
D.11 3/7
Answer: D.11 3/7
Explanation: (x – 5)/15 + x/20 = 1
x = 11 3/7 days
Answer: D
Question: A train 300 m long, running with a speed of 54 km/hr will pass a tree in?
A.17 sec
B.16 sec
C.20 sec
D.14 sec
Answer: C.20 sec
Explanation: Speed =54 * 5/18
= 15 m/sec
Time taken = 300 * 1/15
= 20 sec
Answer: C
Question: A fort of 3000 soldiers has provisions for 75 days. After 15 days some of them left and the food was now enough for the same period of 75 days as before. How many of them left?
A.500
B.550
C.600
D.650
Answer: C.600
Explanation: 2000 ---- 50
3000 ---- 60
x ----- 75
x*75 = 3000*60
x=2400
3000
-------
600
Answer: C
Question: P can do a certain work in 9 days. Q is 60% more efficient than P. How many days does Q alone take to do the same job?
A.60/9
B.45/8
C.30/7
D.25/6
Answer: B.45/8
Explanation: Each day, P can do 1/9 of the work.
Each day, Q can do 1.6/9 of the work = 16/90 of the work
The time taken by B alone to complete the total work is 90/16 = 45/8 days.
The answer is B.
Question: The value of a machine depreciates at 20% per annum. If its present value is Rs. 1,50,000, at what price should it be sold after two years such that a profit of Rs. 26,000 is made?
A.328897
B.122000
C.877888
D.277768
Answer: B.122000
Explanation: The value of the machine after two years = 0.8 * 0.8 * 1,50,000 = Rs. 96,000
SP such that a profit of Rs. 26,000 is made = 96,000 + 26,000 = Rs. 1,22,000
Answer: B
Question: If n is an integer, f(n) = f(n-1) - n and f(4)=13. What is the value of f(6)?
A.-1
B.0
C.1
D.2
Answer: D.2
Explanation: Since f(n)=f(n-1)-n then: f(6)=f(5)-6 and f(5)=f(4)-5.
As given that f(4)=13 then f(5)=13-5=8 --> substitute the value of f(5) back into the first equation: f(6)=f(5)-6=8-6=2.
Answer: D.
Questions on funtions to practice:
Question: Hari and Giri started a business by investing Rs.45000 and Rs.54000 respectively. What is the share of Giri out of annual profit of Rs.13200 ?
A.6000
B.5400
C.6200
D.7200
Answer: A.6000
Explanation: Investment Ratio = Profit Sharing Ratio.
Ratio of Investments Hari : Giri = Rs.45000 : 54000 => 5 : 6.
Giri share =
13200
× 6 / 11 = Rs.7200
Hari share =
13200 × 5 / 11 = Rs.6000
Option A
Question: If mno < 0 and no > 0, which of the following must be positive?
A. xy
B. xz
C. (m^2)no
D. m(n^2)o
Answer: C. (m^2)no
Explanation: Given that no is positive and mno is negative, you can say that m MUST be negative. As for n and o either they are both positive or both negative.
Option (C) has m^2 which is positive and no which is positive. So (C) must be positive.
Question: The points A(0, 0), B(0, 4a - 2) and C(2a + 1, 2a + 6) form a triangle. If angle ABC = 90, what is the area of triangle ABC?
A.58
B.70
C.63
D.65
Answer: C.63
Explanation: 1/2bh=1/2(2a+1)(2a+6)
Now 4a-2=2a+6
2a=8 . a=4
Therefore,
A(0,0); B(0,14); C(9,14)
1/2*9*14=63
Answer: C
Question: On increasing the price of T.V. sets by 60%, their sale decreases by 20%. What is the effect on the revenue receipts of the shop ?
A.4
B.5
C.56
D.28
Answer: D.28
Explanation: Explanation:
Let the price be = Rs.100, and number of units sold = 100
Then, sale value = Rs.(100 × 100) = Rs.10000
New sale value = Rs.(160 × 80) = Rs.12800
Increase% = 2800/10000 × 100 = 28%
Answer: D
Question: A sum of money becomes double itself in 8 years at simple interest. How many times will it become 10 years at the same rate?
A.2 1/4
B.3 1/4
C.4 1/3
D.6 1/2
Answer: A.2 1/4
Explanation: P ---- 2P ---- 8 years
2 1/4 P ---- 10 years
ANSWER A
Question: Three 6 faced dice are thrown together. The probability that no two dice show the same number on them is
A.5/5
B.5/9
C.5/3
D.5/2
Answer: B.5/9
Explanation: No two dice show same number would mean all the three faces should show different numbers. The first can fall in any one of the six ways. The second die can show a different number in five ways. The third should show a number that is different from the first and second. This can happen in four ways.
Thus 6 * 5 * 4 = 120 favourable cases.
The total cases are 6 * 6 * 6 = 216.
The probability = 120/216 = 5/9.
Answer: B
Question: A watch passes through three hands and each person gains 25%. If the third person sells it for $312.50, what did the first person pay for it?
A.$148
B.$152
C.$156
D.$160
Answer: D.$160
Explanation: 1.25*1.25*1.25 * original price = 312.5
(5/4)^3 * original price = 312.5
original price = 64*312.5 / 125 = $160
The answer is D.
Question: Eight identical machines can produce 360 aluminum cans per hour. If all of the machines work at the same constant rate, how many cans could 5 such machines produce in 6 hours?
A.675
B.750
C.1,800
D.1,350
Answer: D.1,350
Explanation: 8 machines/ 360 cans = 5 machines/ x cans
8x= 1800
x=225
(225)(6 hours)= 1350 cans. The answer is D.
Question: A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. What is the selling price of the cycle?
A.Rs.500
B.Rs.1190
C.Rs.1200
D.Rs.163
Answer: B.Rs.1190
Explanation: Explanation:
S.P. = 85% of Rs. 1400 = Rs(85/100*1400)=Rs.1190
ANSWER:B
Question: A number is doubled and 9 is added. If resultant is trebled, it becomes 51. What is that number
A.4
B.10
C.12
D.14
Answer: A.4
Explanation: Explanation:
=> 3(2x+9) = 51
=> 2x+9 = 17
=> x = 4
Answer: Option A
Question: 8 years ago there were 5 members in the Arthur's family and then the average age of the family was 36 years. Mean while Arthur got married and gave birth to a child. Still the average age of his family is same now. What is the age of his wife at the time of his child's birth was.If the difference between the age of her child and herself was 26 years?
A.16 years
B.26 years
C.36 years
D.66 years
Answer: B.26 years
Explanation: Since we know that the difference b/w the age of any two persons remains always constant, while the ratio of their ages gets changed as the time changes.
so, if the age of his child be x (presently)
Then the age of wife be x + 26 (presently)
Thus the total age = x + ( x + 26) = 32 [\inline \because 252-220 =32]
Rightarrow x = 3
age of her child is 3 years and her self is 29 years. Hence her age at the time of the birth of her child was 26 years.
Answer: B
Question: What percent of a day is 8 hours?
A.12%
B.12.5%
C.33.3%
D.11.3%
Answer: C.33.3%
Explanation: Explanation :
Solution: required percentage = (8/100 * 24) = 33.3%
Answer : C