RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A man can hit a target once in 4 shots. If he fires 4 shots in succession, what is the probability that he will hit his target?
A.1
B.1/256
C.81/256
D.175/256
Answer: D.175/256
Explanation: Solution:
The man will hit the target even if he hits it once or twice or thrice or all four times in the four shots that he takes.
So, the only case where the man will not hit the target is when he fails to hit the target even in one of the four shots that he takes.
The probability that he will not hit the target in one shot =1 - Probability that he will hit target in exact one shot
=1 -1/4
=3/4
Therefore, the probability that he will not hit the target in all the four shots
=(3/4)Ã—(3/4)Ã—(3/4)Ã—(3/4)=81/256
Hence, the probability that he will hit the target at least in one of the four shots:
=1-81/256
=175/256
ANSWER IS D
Question: John's Bank's saving amount is decreased 50% due to loan payment and current balance is Rs.50000. Find the actual balance before deduction?
A.100000
B.8500
C.9000
D.9500
Answer: A.100000
Explanation: 50% decreased
50% Balance = 50000
100% = 50000/50*100 = 100000
Answer : A
Question: 16 balls are numbered 1 to 16. A ball is drawn and then another ball is drawn without replacement. What is the probability that both balls have even numbers?
A.4/11
B.5/17
C.6/25
D.7/30
Answer: D.7/30
Explanation: P(1st ball is even) = 8/16
P(2nd ball is also even) = 7/15
P(both balls are even) = 8/16 * 7/15 = 7/30
The answer is D.
Question: The wages earned by Robin is 35% more than that earned by Erica. The wages earned by Charles is 60% more than that earned by Erica. How much % is the wages earned by Charles more than that earned by Robin?
A.25.92%
B.18.75%
C.30%
D.50%
Answer: A.25.92%
Explanation: Explanatory Answer
Let the wages earned by Erica be $100
Then, wages earned by Robin and Charles will be $135 and $160 respectively.
Charles earns $35 more than Robin who earns $135.
Therefore, Charles' wage is 35/135*100 = 25.92%.
The correct choice is (A)
Question: A four-character password consists of one letter of the alphabet and three different digits between 0 and 9, inclusive. The letter must appear as the second or third character of the password. How many different passwords are possible?
A.5,040
B.18,720
C.26,000
D.37,440
Answer: D.37,440
Explanation: 4 character password: DLDD
First digit can be chosen in 10 ways.
The letter can be chosen in 26 ways.
Next digit can be chosen in 9 ways.
Next digit can be chosen in 8 ways.
This gives us 10*26*9*8ways
Now, the letter can also be DDLD so there will be another 10*9*26*8 ways
Total = 10*26*9*8*2 = 37,440 ways
ANS:D
Question: If a is a positive integer, and if the units digit of a^2 is 9 and the units digit of (a+1)^2 is 4, what is the units U digit of (a+2)^2?
A.1
B.3
C.5
D.6
Answer: A.1
Explanation: I also got A. By punching in numers:
U...7^2=...9
...8^2=...4
...9^2=...1.A
Question: How many of the positive divisors G of 120 are also multiples of 4 not including 120?
A.3.
B.4.
C.5.
D.7.
Answer: D.7.
Explanation: 4,8,12,20,24,40,60. (7) is the answer
Other way : factors of 120 = 2^3 * 3*5
Separate 2^2 ( which means 4)
Now, calculate the number of other factors.
G=2*3*5 = total positive factors are 2*2*2 = 8
This 8 factors include 120
So subtract 1 from 8
Ans is 7=D
Question: Look at this series: 439,404, 369, 334, 299, 264 ... What number should come next?
A.206
B.208
C.206
D.229
Answer: D.229
Explanation: 229
This is a simple subtraction series. Each number is 35 less than the previous number.
D
Question: The side of a square is increased by 25% then how much % does its area increases?
A.56.75 %
B.56.25 %
C.53.85 %
D.57.25 %
Answer: B.56.25 %
Explanation: a = 100 a2 = 10000
a = 125 a2 = 15625
----------------
10000 --------- 5625
100 -------? => 56.25 %
Answer:B
Question: A, B, C subscribe Rs. 50,000 for a business. A subscribes Rs. 4000 more than B and B Rs. 5000 more than C. Out of a total profit of Rs. 35,000, A receives:
A.Rs. 8400
B.Rs. 11,900
C.Rs. 13,600
D.Rs. 14,700
Answer: D.Rs. 14,700
Explanation: Let C = x.
Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.
So, x + x + 5000 + x + 9000 = 50000
3x = 36000
x = 12000
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
A's share = Rs.(35000 x21/50) = Rs. 14,700.
Answer:D
Question: A number x is multiplied with itself and then added to the product of 4 and x. If the result of these two operations is -3, what is the value of x?
A.-4
B.-1 and -3
C.2
D.4
Answer: B.-1 and -3
Explanation: A number x is multiplied with itself --> X^2
added to the product of 4 and x --> X^2+4X
If the result of these two operations is -3 --> X^2+4X=-3
i.e X^2+4X+3=0 is the Quadratic equation which needs to be solved.
(X+1)(X+3) = 0
Hence X=-1. X=-3
IMO B
Question: When y is divided by 276, the remainder is 44. What is the remainder when the same y is divided by 23?
A.19
B.20
C.21
D.22
Answer: C.21
Explanation: y = 276*a + 44 = (23*12)*a + 23 + 21
The answer is C.
Question: If the average of 5 positive integers is 45 and the difference between the largest and the smallest of these 5 numbers is 10, what is the maximum value possible for the largest of these 5 integers?
A.50
B.53
C.49
D.48
Answer: B.53
Explanation: Sum of 5 Integer (a, b, c, d, e) = 5*45 = 225
e - a = 10
i.e. e = a+10
For e to be maximum remaining 4 MUST be as small as possible
Since smallest of 5 numbers is a so to minimize other numbers we can take them equal to the smallest of 5 numbers
i.e. a+a+a+a+(a+10) = 225
i.e. 5a = 215
i.e. a = 43
i.e. Largest e = 43+10 = 53
Answer: option B
Question: Mary can divide his herd into 5 equal parts and also to 6 equal parts, but not to 9 equal parts. What could be the number of cows Mary has in his herd?
A.120
B.155
C.456
D.180
Answer: A.120
Explanation: On first look B,C,E are not divisible either by 5 or 6 - ruled out.
D,A divisible by both 5,6, but 180 is divisible by 9.
Answer : A
Question: An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the ?
A.8:6
B.8:7
C.8:1
D.8:2
Answer: B.8:7
Explanation: Let the length and breadth of the carpet in the first case be 3x units and 2x units respectively.
Let the dimensions of the carpet in the second case be 7y, 3y units respectively.
From the data,.
2(3x + 2x) = 2(7y + 3y)
=> 5x = 10y
=> x = 2y
Required ratio of the areas of the carpet in both the cases
= 3x * 2x : 7y : 3y
= 6x2 : 21y2
= 6 * (2y)2 : 21y2
= 6 * 4y2 : 21y2
= 8:7
Answer:B
Question: If 3 (A's capital) = 8 (B's capital) = 10 (C's capital). Then the ratio of their capitals is?
A.40:15:15
B.40:15:18
C.40:15:12
D.40:15:14
Answer: C.40:15:12
Explanation: 3A = 8B = 10 C
A:B:C = 1/3:1/8:1/10
= 40:15:12
Answer: C
Question: 3889 + 12.543 - ? = 3854.002
A.A)47.095
B.B)47.752
C.C)47.932
D.D)47.541
Answer: D.D)47.541
Explanation: Let 3889 + 12.543 - x = 3854.002.
Then x = (3889 + 12.543) - 3854.002
= 3901.543 - 3854.002
= 47.541.
Answer = D
Question: Yesterday's closing prices of 2,200 different stocks listed on a certain stock exchange were all different from today's closing prices. The number of stocks that closed at a higher price today than yesterday was 20 percent greater than the number that closed at a lower price. How many of the stocks closed at a higher price today than yesterday?
A. 484
B. 726
C. 1,200
D. 1,320
Answer: C. 1,200
Explanation: Lets consider the below -
The number of stocks that closed at a higher price = H
The number of stocks that closed at a lower price = L
We understand from first statement -> H+L = 2200 ----(1)
We understand from second statement -> H = (120/100)L => H = 1.2L ----(2)
Solve eq (1)(2) to get H = 1200.
C is my answer.
Question: In a group of people, if 30 people were made to stand in each column, 16 columns could be formed. If 60 people were made to stand in a column, how many columns could be formed?
A.6
B.8
C.10
D.12
Answer: B.8
Explanation: 16*30 = 60*n
n = 8
The answer is B.
Question: Each Machine of type A has 3 steel parts and 2 chrome parts. Each machine of type B has 2 steel parts and 4 chrome parts. If a certain group of type A and type B machines has a total of 50 steel parts and 66 chrome parts, how many machines are in the group
A.11
B.21
C.31
D.61
Answer: B.21
Explanation: Look at the below representation of the problem:
Steel Chrome total
A 3 2 50 >>no. of type A machines=50/5=10
B 2 4 66 >>no. of type B machines=66/6=11
So the answer is 21 i.e B.
Hope its clear .
Question: There are, in a certain league, 10 teams, and each team face another team for a total of 10 times. How many games are played in the season?
A.1000
B.450
C.720
D.180
Answer: A.1000
Explanation: By using the formula, t[n(n - 1) / 2], where t = no. of games between two teams and n = total no. of teams, we get: 450
Option A.
Question: The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 60% profit?
A.220
B.230
C.1024
D.780
Answer: C.1024
Explanation: C.P. = Rs. x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 160% of Rs. 640 = 160/100 * 640 = Rs. 1024.
C
Question: The fourth proportional to 12, 14 and 18 is?
A.twenty one
B.66
C.77
D.88
Answer: A.twenty one
Explanation: (14* 18) /12 = 21
Answer: A
Question: Divide Rs. 1500 among A, B and C so that A receives 1/3 as much as B and C together and B receives 2/3 as A and C together. A's share is?
A.s.360
B.s.400
C.s.375
D.s.500
Answer: C.s.375
Explanation: A+B+C = 1500
A = 1/3(B+C); B = 2/3(A+C)
A/(B+C) = 1/3
A = 1/4 * 1500 => 375
ANSWER:C
Question: Two pipes can separately fill a tank in 20 and 30 hours respectively. Both the pipes are opened to fill the tank but when the tank is full, a leak develops in the tank through which one-third of water supplied by both the pipes goes out. What is the total time taken to fill the tank?
A.22 hrs
B.16 hrs
C.77 hrs
D.99 hrs
Answer: B.16 hrs
Explanation: 1/20 + 1/30 = 1/12
1 + 1/3 = 4/3
1 --- 12
4/3 --- ?
4/3 * 12 = 16 hrs
Answer: B
Question: In a recent election, Ms. Robinson received 8000 voters cast by independent voters, that is, voters not registered with a specific political party. She also received 25 percent of the votes cast by those voters registered with a political party. IF N is the total number of votes cast in the election and 40 percent of the votes cast were cast by independent voters, which of the following represents the number of votes that Mrs. Robbins received?
A. 0.06N+3200
B. 0.1N+7200
C. 0.4N+7200
D. 0.15N+8000
Answer: D. 0.15N+8000
Explanation: 40% of N are independent voters, hence 60% of N are not independent voters. From this group she received 25% votes so, 0.25*0.6*N plus 8,000 votes from independents: total=0.25*0.6*N+8,000=0.15*N+8,000.
Answer: D.
Question: Two trains of length 250 m and 120 m are 50 m apart. They start moving towards each other on parallel tracks, at speeds 64 kmph and 42 kmph. After how much time will the trains meet?
A.15/10
B.17/10
C.16/10
D.18/10
Answer: B.17/10
Explanation: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (64 + 42)*5/18 = 7*5 = 29.4 mps.
The time required = d/s = 50/29.4 = 17/10 sec.
Answer:B
Question: The vertices of a rectangle in the standard (x,y) coordinate place are (0,0), (0,3), (6,0) and (6,3). If a line through (2,2) partitions the interior of this rectangle into 2 regions that have equal areas, what is the slope of this line?
A.1/2
B.2/5
C.4/7
D.1
Answer: A.1/2
Explanation: CONCEPT: The readers need to know that a rectangle can be divided into two equal area by a Straight line only when the straight line passes through the Centre of the Rectangle (Intersection of its two diagonals)Draw a figure and know it for yourself.
The point of Intersections of the diagonals will be the midpoint of any diagonal i.e. Midpoint of (0,0), and (6,3) OR Midpoint of (0,3) and (6,0)
i.e. Either [(0+6)/2, (0+3)/2] OR [(0+6)/2, (3+0)/2] =[3,1.5]
Slope of line passing through points (2,2) and (3,1.5) = (2-1.5)/(3-2) = 0.5/1 = 1/2
A
Question: The sum of ages of 5 children born at the intervals of 8 years each is 90 years. What is the age of the youngest child?
A.2
B.9
C.6
D.4
Answer: A.2
Explanation: Let the ages of children be x, (x +8), (x + 16), (x + 24) and (x + 32) years.
Then, x + (x + 8) + (x + 16) + (x + 24) + (x + 32) =90
5x = 10
x = 2.
Age of the youngest child = x = 2 years.
Answer:A
Question: Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/6 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent?
A.2/3
B.29/60
C.17/30
D.19/30
Answer: A.2/3
Explanation: Let s assume the platinum card spending limit =x
Gold card spending limit will be =x/2
balance on gold card is =x/2*1/3=x/6
Platinum card unspent limit is= x-1/6x=5/6x
So if gold card balance is transferred then the rest unspent will be
5/6x-x/6=2/3x
So the ans is A
Question: The average age of a family of 6 members is 28 years.If the age of the youngest member is 7 years,what was the average age of the family at the birth of the youngest member?
A.15
B.18
C.21
D.12
Answer: C.21
Explanation: Present age of total members = 6 X 28 = 168
7 yrs back their ages were = 6 x 7 = 42
Ages at the birth of youngest member = 168 - 42 = 126
Therefore, avg age at the birth of youngest member = 126/6 = 21.
ANSWER:C
Question: There are some passengers riding on a bus. At the first stop, half the passengers get off and nobody gets on the bus. This pattern continues as the bus goes to the next stops. If only one passenger gets off at stop number 7, how many passengers were on the bus originally?
A.128
B.64
C.32
D.16
Answer: A.128
Explanation: Before stop 7, there were 2 passengers on the bus.
Before stop 6, there were 4 passengers on the bus.
etc...
Before stop x, there were 2^(8-x) passengers on the bus.
Before stop 1, there were 2^7 = 128 passengers on the bus.
The answer is A.
Question: If √2n = 64, then the value of n is :
A.6
B.12
C.24
D.48
Answer: B.12
Explanation: Sol.
√2n = 64 ⇔ (2n)1/2 ⇔ 2n/2 = 26 ⇔ n/2
= 6 ⇔ n = 12.
Answer B
Question: The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 867 sq m, then what is the breadth of the rectangular plot?
A.18 m
B.17 m
C.26 m
D.27 m
Answer: B.17 m
Explanation: Let the breadth of the plot be b m.
Length of the plot = 3 b m
(3b)(b) = 867
3b2 = 867
b2 = 289 = 172 (b > 0)
b = 17 m.
Answer:B
Question: A rectangular box measures internally 1.6 m long, I m broad and 60 cm deep.The number of cubical blocks each of edge 20 cm that can be packed inside the box is
A.30
B.53
C.60
D.120
Answer: D.120
Explanation: Solution
Number of blocks	= (160×100×60 / 20×20×20)
= 120.
Answer D
Question: Louie takes out a three-month loan of $1000. The lender charges him 30% interest per month compounded monthly. The terms of the loan state that Louie must repay the loan in three equal monthly payments. To the nearest dollar, how much does Louie have to pay each month?
A.A)333
B.B)663
C.C)402
D.D)433
Answer: B.B)663
Explanation: Here's the calculation for that case, assume monthly payment is X.
After 1st month: (1000)(1.3)-X = 1300-X
After 2nd month: (1300-X)(1.3)-X = 1690-2.21X
After 3rd month: (1690-2.21X)(1.3)-X = 2197-3.31X
Now, the amount after the last payment in 3rd month must bring the total to 0. Hence:
2197-3.31X = 0
X = 2197/3.31 = 663.74
Answer B
Question: On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 20 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?
A.20%
B.25%
C.30%
D.35%
Answer: B.25%
Explanation: Let T be the total number of passengers.
Let x be the number of people with round trip tickets.
0.2T had round trip tickets and took their cars.
0.8x had round trip tickets and took their cars.
0.8x = 0.2T
x = 0.25T
The answer is B.
Question: If a committee of 4 people is to be selected from among 5 married couples so that the committee does not include two people who are married to each other, how many such committees are possible?
A.20
B.40
C.50
D.80
Answer: B.40
Explanation: Each couple can send only onerepresentativeto the committee. Let's see in how many ways we can choose 4 couples (as there should be 4 members) each to send onerepresentativeto the committee: 5C4=5.
But these 4 chosen couples can send two persons (either husband or wife): 2*2*2=2^3=8.
Total # of ways: 5C3*2^3=40.
Answer: B.
Question: a is the hundreds digit of the three digit integer x, b is the tens digit of x, and c is the units digit of x. 2a = b = 4c, and a > 0.
What is the difference between the two greatest possible values of x?
Tip: Dont stop till you have exhausted all answer choices to arrive at the correct one.
A.124
B.241
C.394
D.421
Answer: B.241
Explanation: Ratio of a:b:c= 2:4:1
Two possible greatest single digit values for b are 8 and 4
if b is 8, then x= 482
if b is 4, then x= 241
difference= 482-241= 241
B is the answer
Question: There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?
A.15
B.16
C.28
D.56
Answer: C.28
Explanation: Number of ways 2 teams can be selected out of 8 teams:
C8/2=8∗7/2=28
Ans:"C"
Question: The list price of an article is Rs.65. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?
A.8%
B.4%
C.5%
D.3%
Answer: B.4%
Explanation: 65*(90/100)*((100-x)/100) = 56.16
x = 4%
Answer: B
Question: Average of 7 numbers is zero. At most how many numbers may be greater than zero
A.0
B.1
C.6
D.9
Answer: C.6
Explanation: Answer: Option C
Question: A line that passes through (–1, –4) and (5, k) has a slope = k. What is the value of k?
A. 3/4
B. 1
C. 4/5
D. 2
Answer: C. 4/5
Explanation: Slope = (y2-y1)/(x2-x1)
=> k = (k+4)/(5+1)
=> 6k = k+4
=> k =4/5
Ans C it is!
Question: n a 1000m race, if A gives B a start of 40m, A wing by 19sec. But if A gives B start of 30sec, B wins by 40m.
Find the time taken by B to run 3000m race?
A.300
B.350
C.375
D.400
Answer: C.375
Explanation: then 960/B -1000/A = 19 => 24/B - 25/A = 19/40
and 1000/B - 960/A = 30 => 25/B - 24/A = 30/40
solving equation A speed =8 and B=20/3
for 1000m b will take 3000/20/3= 375 sec
C
Question: Tom wants to buy items costing $25.35, $70.69, and $85.96. He earns $6.50 an hour doing
odd jobs. If ten percent of his income is put aside for other purposes, how many hours must he
work to earn the money he needs for his purchases? Round your answer to the nearest whole
hour.
A.8 hours
B.48 hours
C.31 hours
D.18 hours
Answer: C.31 hours
Explanation: $6.50 x .10 = $.65 is 10% of his hourly income
$6.50 - .65 = $5.85 hourly amount available to spend
$25.35 + $70.69 + $85.96 = $182 total needed
$182 ÷ $5.85 = 31.11... rounds to 31 hours
correct answer C
Question: A and B invested Rs.15000 and Rs.20,000 respectively in a business. How should a loss of Rs.2800 be divided between them at the end of year? (in rupees)
A.1500,1300
B.1200,1600
C.1300,1500
D.1600,1200
Answer: B.1200,1600
Explanation: Ratio btwn invest is == 3:4
loss==2800
so 2800/7==400
A==3*400==1200
B==4*400==1600
ANSWER:B
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is?
A.3/5
B.3/2
C.3/9
D.3/6
Answer: B.3/2
Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y ==> 4 x = 6 y ==> x/y = 3/2.Answer: B
Question: If 70% of a number exceeds 28% of it by 39.9, then find the number?
A.65
B.67
C.100
D.95
Answer: D.95
Explanation: Use the elimination method to find the correct option.
Of all the options only 95 fits
70% of 95 = 66.5
28% of 95 = 26.6
66.5 - 26.6 = 39.9
Required number is 95.
ANSWER:D
Question: Find the ratio in which rice at Rs. 7.30 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg
A.2:0
B.2:3
C.3:5
D.2:2
Answer: C.3:5
Explanation: By the rule of alligation:
Cost of 1 kg rice of 1st kind Cost of 1 kg rice of 2nd kind
Required ratio = 60 : 100 = 3 : 5
Answer: C
Question: If S + A < S - A < A - S, which of the following is correct?
A.A < S < 0.
B.S < A < 0.
C.S < 0 < A.
D.0 < B < A.
Answer: B.S < A < 0.
Explanation: Check first inequality
S + A < S - A
A<-A
A is -ve
Check another equality
S - A < A - S
-2A<-2S
A>S
Combining both 0>A>S
Option B fits only
Ans B
Question: A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Dollar 5400 interest only for the period. The principal amount borrowed by him was:
A.Dollar 2000
B.Dollar 10,000
C.Dollar 15,000
D.Dollar 20,000
Answer: C.Dollar 15,000
Explanation: Explanation: Principal = Dollar (100 x 5400)/(12x3) = Dollar 15000.
Answer: Option C
Question: In a certain province in India there are 15 cities. If a single road segment connects only two cities, how many road segments are required in order to connect the cities so that each city is connected to all other cities with a single road segment?
A.30
B.105
C.330
D.14!
Answer: B.105
Explanation: Method-1:
India has Total Cities = 15 and each city should be connected with every other city
So Total Roads required to connect 1st City with other 14 cities = 14
Now 1st City is connected with all other cities so,
So Total Roads required to connect 2nd City with 13 cities (Other than 1st) = 13
Now 1st and 2nd Cities are connected with all other cities so,
So Total Roads required to connect 3rd City with 12 cities (Other than 1st, and 2nd) = 12
......and so on...
Total Roads required = 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 105=B
Question: There are 6 orators A, B, C, D, E, F. In how many ways can the arrangements be made so that A always comes before B and B always comes before C.
A.6! / 3!
B.8! / 6!
C.5! x 3!
D.8! / (5! x 3!)
Answer: A.6! / 3!
Explanation: Select any three places for A, B and C. They need no arrangement amongst themselves as A would always come before B and B would always come before C.
The remaining 3 people have to be arranged in 3 places.
Thus, 6C3 x 3! = 6! / 3!
ANSWER:A
Question: Which of the following is non-negative?
A.(a-0.9)(a-1)
B.(a+1)(a-1)
C.(a+0.7)(a+1)
D.(a-0.7)(a-0.7)
Answer: D.(a-0.7)(a-0.7)
Explanation: 5-sec approach:
D. (a-0.7)(a-0.7) = (a-0.7)^2. The square of a number is always non-negative.
Answer: D.
Question: In a group of 3 boys and 2 girls can be formed out of a total of 4 boys and4 girls?
A.20
B.22
C.24
D.26
Answer: C.24
Explanation: Solution: Total number of ways = (select 3 boys from group of 4 boys) * (2 girls from group of 4 girls)
=> (4c3) * (4c2) = 24
C
Question: What will come in place of the x in the following Number series? 5,28,57,88,125
A.122
B.324
C.166
D.175
Answer: C.166
Explanation: 28=23+5
57=29+28
88=31+57
125=37+88
166=41+125
=166
C
Question: A sun is divided among X, Y and Z in such a way that for each 2 rupees X gets, Y gets 1 rupee 50 paisa and Z gets 1 rupee 20 paisa. If the share of X is RS. 125, what is the total amount?
A.283.75
B.193.75
C.293.75
D.290.75
Answer: C.293.75
Explanation: x:y:z = 200:150:120
20:15:12
20 --- 125
47 --- ? => 293.75
Answer: C
Question: The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 42 degrees. Find the temperature on Friday?
A.227
B.268
C.127
D.150
Answer: D.150
Explanation: M + Tu + W + Th = 4 * 48 = 192
Tu + W + Th + F = 4 * 46 = 184
M = 42
Tu + W + Th = 192 -42 = 150
F = 184 – 150 = 34
Answer: D