RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Find the largest number of four digit exactly divisible by 12,15,18 and 27?
A.1500
B.2579
C.9720
D.3697
Answer: C.9720
Explanation: Explanation:
The largest number of four digit is 9999.
LCM of 12,15,18 and 27 is 540
On dividing 9999 by 540 ,we get 279 is reminder
Required Number=(9999-279)=9720
Answer:C
Question: What is the value of x^2yz − xyz^2, if x =1, y = 1, and z = 3?
A. 20
B. -6
C. 30
D. 32
Answer: B. -6
Explanation: 1*1*3 -(1*1*9)
=3-9 = -6
Ans: B
Question: Positive integer y is 50 percent of 50 percent of positive integer x, and 2y percent of x equals 100. What is the value of x?
A. 50
B. 100
C. 140
D. 1,000
Answer: C. 140
Explanation: y = 50% of 50% 0f x
= x/4
and
2y/100 of x = 100
2y /100 *4y =5000
y = 35
and x= 140
Answer - C
Question: Alex deposited x dollars into a new account that earned 5 percent annual interest, compounded annually. One year later Alex deposited an additional x dollars into the account. If there were no other transactions and if the account contained w dollars at the end of two years, which of the following expresses x in terms of w ?
A.w/(1+1.08)
B.w/(1.05+1.05^2)
C.w/(1.16+1.24)
D.w/(1.08+1.16)
Answer: B.w/(1.05+1.05^2)
Explanation: Account at the end of the first year would be 1.05x dollars. At this time x dollars was deposited, hence the account at the beginning of the second year would be (1.05x+x) dollars. Account at the end of the second year would be (1.05x+x)*1.05=w --> x(1.05^2+1.05)=w --> x=w/(1.05+1.05^2).
Answer: B
Question: A certain industrial machine requires 20 quarts (640 ounces) of oil every day, and it is given a mixture of oil A and oil B. Oil A consists of 5% special additives while oil B consists of 9% special additives. If the machine needs exactly 50 ounces of the special additives to ensure smooth operation, then how much of oil A, in ounces, should be in the mixture?
A.a.	A – 60
B.b.	B – 180
C.c. C – 190
D.d.	D – 300
Answer: C.c. C – 190
Explanation: 5%*x + 9% *(640-x)=50
7.6 = 4 %*x
x=190
C
Question: There are 240 doctors and nurses at a hospital. If the ratio of doctors to nurses is 3 to 7, how many nurses are at the hospital?
A.168
B.172
C.176
D.180
Answer: A.168
Explanation: The number of nurses at the hospital is (7/10)*240=168.
The answer is A.
Question: Suresh can complete a job in 15 hours. Ashutosh alone can complete the same job in 20 hours. Suresh works for 9 hours and then the remaining job is completed by Ashutosh. How many hours will it take Ashutosh to complete the remaining job alone?
A.4
B.5
C.8
D.12
Answer: C.8
Explanation: The part of job that Suresh completes in 9 hours
= 9â„15 = 3â„5
Remaining job = 1 - 3â„5 = 2â„5
Remaining job can be done by Ashutosh in 2â„5 Ã— 20 = 8 hours
Answer C
Question: A and B start a business with Rs.15000 and Rs.18000 respectively. Hoe should they share their profits at the end of one year?
A.1:2
B.3:4
C.5:6
D.3:7
Answer: C.5:6
Explanation: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
15000 : 18000 => 5:6
ANSWER:C
Question: A company wants to spend equal amounts of money for the purchase of two types of computer printers costing $500 and $300 per unit, respectively. What is the fewest number of computer printers that the company can purchase?
A.2
B.3
C.4
D.6
Answer: D.6
Explanation: The smallest amount that the company can spend is the LCM of 500 and 300, which is 1500 for each, which is total 3000.
The number of 1st type of computers which costing $500 = 1500/500 = 3.
The number of 2nd type of computers which costing $300 = 1500/300 = 3.
Total = 3+3 = 6
Answer is D.
Question: The income tax in the area where the Jones family lives is scheduled to increase by 12% next year. Since the Jones family cannot afford an increase in their tax bill, how much will they have to reduce income by to keep their cost the same?
A.10.7%
B.10%
C.10.3%
D.10.9%
Answer: A.10.7%
Explanation: Solution: Let the current tax be represented by Rs. 100.
The tax rate rises 12%. So, to continue to have the same income, they need to increase their tax,
= (100 + 12% of 100) = Rs. 112.
But, they want to keep tax expense the same, so they have to cut Rs. by 12 to keep it to Rs. =100.
The % decrease in income is,
(12/112)*100 = 10.7%.
Mental Calculation Method;
100-----12%↑---→112------X%↓---→100.
Here, X = (12/112)*100 = 10.7%.
Answer: Option A
Question: At the end of a business conference the ten people present all shake hands with each other once. How many handshakes will there be altogether ?
A.20
B.45
C.55
D.90
Answer: B.45
Explanation: number of handshakes = 10C2= 10*9/2 = 45
ANSWER:B
Question: A tank is filled in eight hours by three pipes A, B and C. Pipe A is twice as fast as pipe B, and B is twice as fast as C. How much time will pipe B alone take to fill the tank?
A.18 hours
B.28 hours
C.98 hours
D.16 hours
Answer: B.28 hours
Explanation: 1/A + 1/B + 1/C = 1/8 (Given)
Also given that A = 2B and B = 2C
=> 1/2B + 1/B + 2/B = 1/8
=> (1 + 2 + 4)/2B = 1/8
=> 2B/7 = 8
=> B = 28 hours.
Answer:B
Question: Walking at 4/7 of its usual speed, a train is 9 minutes late. Find its usual time to cover the journey.
A.8min.
B.10min.
C.12min.
D.15min.
Answer: C.12min.
Explanation: Explanation :
Solution: New speed = 4/7 of the usual speed. Let usual time be x.
.'. New time taken = 7/4 of usual time = 7x/4
so, (7x/4 ) - x = 9 min.
=> 3x = 36
=> x = 12 min.
Answer : C
Question: Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is
A.17/28
B.17/27
C.17/19
D.17/20
Answer: D.17/20
Explanation: n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 - 1/20 = 17/20
Answer: D
Question: 7,11,19,35,67, (...)
A.131
B.245
C.142
D.76
Answer: A.131
Explanation: 7
7Ã— 2 - 3 =11
11 Ã— 2 - 3= 19
19 Ã— 2 - 3 = 35
35 Ã— 2 - 3 = 67
67 Ã— 2 - 3 = 131
Answer is A
Question: What is the greatest of 3 consecutive integers whose sum is 30 ?
A.11
B.7
C.8
D.9
Answer: A.11
Explanation: The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3
If the sum is 24, we need to solve the equation 3n + 3 = 30;
=> 3n = 27;
=> n = 9
The greatest of the three numbers is therefore 9 + 2 = 11 Answer: A
Question: A and B together can complete a piece of work in 4 days. If A alone can complete the same work in 12 days, in how many days can B alone complete that work?
A.2 days
B.3 days
C.6 days
D.5 days
Answer: C.6 days
Explanation: Sol. (A + B)'s 1 day's work = (1/4). A's 1 day's work = (1/12).
B's 1 day's work =((1/4)-(1/12))=(1/6)
Hence, B alone can complete the work in 6 days.
Ans: C
Question: Two cars are traveling in the same direction along the same route. The red car travels at a constant speed of 30 miles per hour, and the black car is traveling at a constant speed of 50 miles per hour. If the red car is 20 miles ahead of the black car, how many hours will it take the black car to overtake the red car?
A.0.1
B.0.6
C.1
D.1.2
Answer: C.1
Explanation: Option C
20+30t=50t
t=1
Question: The sale price sarees listed for Rs.540 after successive discount is 5% and 2% is?
A.288
B.500
C.502
D.540
Answer: C.502
Explanation: 540*(95/100)*(98/100)
= 502
Answer: C
Question: At what rate percent on simple interest will a sum of money double itself in 30 years?
A.3 1/3%
B.3 1/8%
C.3 7/3%
D.3 1/7%
Answer: A.3 1/3%
Explanation: P = (P*30*R)/100
R = 3 1/3%
Answer: A
Question: Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 900. What is their H.C.F.?
A.5
B.15
C.25
D.35
Answer: B.15
Explanation: Let the numbers be 3x, 4x and 5x.
Then, their L.C.M. = 60x
60x = 900
x = 15
The numbers are (3 x 15), (4 x 15) and (5 x 15).
The H.C.F. is 15.
The answer is B.
Question: If Jake loses 32 pounds, he will weigh twice as much as his sister. Together they now weigh 212 pounds. What is Jake’s present weight, in pounds?
A.131
B.135
C.139
D.152
Answer: D.152
Explanation: Lets say J is the weight of Jack and S is the wt of his sister.
If he loses 32 pounds, he s twice as heavy as his sister.
J-32=2*S
Also, together they weight 212 pounds
J+S=212
solvong the 2 equation ,we get J=152 pounds !
D
Question: Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
A.173 m
B.200 m
C.273 m
D.300 m
Answer: C.273 m
Explanation: Let AB be the lighthouse and C and D be the positions of the ships.
Then, AB = 100 m, ACB = 30° and ADB = 45°.
AB	= tan 30° =	1 AC = AB x 3 = 1003 m.
AC	3
AB	= tan 45° = 1 AD = AB = 100 m.
AD
CD = (AC + AD)	= (1003 + 100) m
= 100(3 + 1)
= (100 x 2.73) m
= 273 m.
Answer = C
Question: A candidate who gets 30% of the marks fails by 50 marks. But another candidate who gets 45% marks gets 25 marks more than necessary for passing. Find the number of marks for passing?
A.100 Marks
B.200 Marks
C.280 Marks
D.371 Marks
Answer: B.200 Marks
Explanation: 30% ------------ 50
45% ------------ 25
----------------------
15% ------------- 75
30% -------------- ?
150 + 50 = 200 Marks
Answer:B
Question: Lake A has a duck population of 30 females and 36 males. Lake B’s duck population consists of the same ratio of females to males. If 5 new female ducks are added to Lake B and no other ducks are added or removed, the new total duck population of Lake B could be which of the following?
A.144
B.105
C.77
D.51
Answer: C.77
Explanation: Lake A has a duck population of 30 females and 36 males --> the ratio is F:M = 30:36 = 5:6.
Lake B’s duck population consists of the same ratio of females to males --> F:M = 5:6.
C
Question: P, Q and R can do a work in 20, 30 and 60 days respectively. How many days does it need to complete the work if P does the work and he is assisted by Q and R on every third day?
A.15
B.24
C.78
D.96
Answer: A.15
Explanation: Explanation :
Amount of work P can do in 1 day = 1/20
Amount of work Q can do in 1 day = 1/30
Amount of work R can do in 1 day = 1/60
P is working alone and every third day Q and R is helping him
Work completed in every three days = 2 × (1/20) + (1/20 + 1/30 + 1/60) = 1/5
So work completed in 15 days = 5 × 1/5 = 1
Ie, the work will be done in 15 days
ANSWER:A
Question: A store owner estimates that the average price of type A products will increase by 30% next year and that the price of type B products will increase by 20% next year. This year, the total amount paid for type A products was $3200 and the total price paid for type B products was $5800. According to the store owner's estimate, and assuming the number of products purchased next year remains the same as that of this year, how much will be spent for both products next year?
A.$14,755
B.$15,325
C.$11,129
D.$16,225
Answer: C.$11,129
Explanation: cost of type A products next year = 1.3 * 3200 = 4160
cost of type B products next year = 1.2 * 5800 = 6960
total 4169 + 6960 = 11129
ANSWER:C
Question: What will come in place of the x in the following Number series? 18, 22, 30, x ,78, 142
A.35
B.38
C.46
D.49
Answer: C.46
Explanation: (C)
The pattern is +4, +8, +16, +32, +64
So the missing term is = 30 + 16 = 46 .
Question: A popular website requires users to create a password consisting of the digits {1,2,3,4,5}. If no digit may be repeated and each password must be at least 4 digits long, how many passwords are possible?
A.4! + 5!
B.2 x 5!
C.4! x 5!
D.9!
Answer: B.2 x 5!
Explanation: If we choose the 5 different digits then they can be arranged in 5! ways.
The number of possible 4-digit passwords is 5*4*3*2 = 5!
The total number of passwords is 5! + 5! = 2*5!
The answer is B.
Question: If x, y, and z are all factors of 15, which of the following must be true?
A.The product xyz > 15
B.Either x = y, y = z, or x = z
C.x – y – z = even
D.The product xyz is odd
Answer: D.The product xyz is odd
Explanation: All the factors of 15 are odd numbers.
The product of odd numbers is odd.
The answer is D.
Question: If n is an integer greater than 6, which of the following must be divisible by 10 ?
A.n(n + 1)(n – 4)
B.n(n + 2)(n – 1)
C.n(n + 3)(n – 5)
D.n(n + 4)(n – 2)
Answer: C.n(n + 3)(n – 5)
Explanation: If n= 7 , then n+3 is divisible by 10 .
C
Question: The workers of a factory is 10000. It decreases annually at the rate of 20% p.a. What will be its population after 4 years?
A.8500
B.7000
C.5282
D.4096
Answer: D.4096
Explanation: Formula :
( After =100 denominator
Ago = 100 numerator)
10000 Ã— 80/100 Ã— 80/100 x 80/100 x 80/100 = 4096
D
Question: Several people are sitting around a round table playing a card game with a deck of 51 cards. Each person is dealt one card per deal, and the cards are dealt in a clockwise fashion. If Martin is dealt both the first card of the deck and the last card of the deck, which of the following could be the total number of people sitting at the table?
A.4
B.5
C.7
D.11
Answer: B.5
Explanation: Let n be the number of people at the table.
If Martin gets the first and the last card, it means Martin got one more card than the others.
Thus 51/n has a remainder of 1 and so 51-1 = 50 is a multiple of n.
The answer is B.
Question: If twenty four men and sixteen women work on a day, the total wages to be paid is 11,600. If twelve men and thirty seven women work on a day, the total wages to be paid remains the same. What is the wages paid to a man for a day’s work?
A.33
B.38
C.37
D.299
Answer: B.38
Explanation: Answer:B
Question: Each of the 20 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and the average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the average weight of the boxes in the shipment is to be reduced to 16 pounds by removing some of the 20-pound boxes, how many 20-pound boxes must be removed?
A.8
B.10
C.12
D.14
Answer: B.10
Explanation: If the average of 10-pound and 20-pound boxes is 18, the ratio of 10-pound boxes:20-pound boxes is 1:4.
So out of 20 boxes, 4 are 10-pound boxes and 16 are 20-pound boxes.
If the average of 10 and 20-pound boxes is to be 16, the ratio of 10-pound boxes:20-pound boxes should be 2:3.
The number of 10 pound boxes remains the same so we still have 4 of them.
To get a ratio of 2:3, the number of 20-pound boxes must be 6.
We need to remove 10 of the 20-pound boxes.
The answer is B.
Question: Anne bought a computer for $2,000 and then paid a 5 percent sales tax, and Henry bought a computer for $1,800 and then paid a 12 percent sales tax. The total amount that Henry paid, including sales tax, was what percent less than the total amount that Anne paid, including sales tax?
A.3%
B.4%
C.7%
D.10%
Answer: B.4%
Explanation: Cost of Computer = $2000
Sales tax = (5/100)*2000 = $100
Total Cost of Computer = 2000 + 100 = 2100
For Henry
Cost of Computer = $1800
Sales tax = (12/100)*1800 = $216
Total Cost of Computer = 1800 + 216 = 2016
% that Henry paid less than Anne = (2100 - 2016)*100/2100 = 4%
Answer: Option B
Question: (2^2+4^2+6^2+.....+18^2)=?
A.1322
B.2356
C.6544
D.1140
Answer: D.1140
Explanation: =(1x2)^2+(2x2)^2,+(2x3)^3+......(2x9)^2
=2^2 x (1^2+2^2+3^2+.......+9^2)
formula is =1/6 n(n+1)(2n+1)
=(4x1/6x9x10x19)
=(4x285)=1140
Answer is D
Question: 1=5,2=10,3=253,4=254,5=255,6=256,7=257,8=258 then 10=?
A.2
B.255
C.345
D.445
Answer: A.2
Explanation: 1=5,2=10,3=253,4=254,5=255,6=256,7=257,8=258 then 10=?
10=2
check the first eqn.
ANSWER:A
Question: We can rent a bike for x cents per minute for the first 15 minutes and then y cents for each additional minute. How much will it cost to rent a bike for z minutes, where z>15?
A.15x+(z-15)y
B.15x + zy
C.15y +(z-15)x
D.x + zy
Answer: A.15x+(z-15)y
Explanation: The first 15 minutes cost 15x.
The next (z-15) minutes cost (z-15)y.
The total cost is 15x+(z-15)y.
The answer is A.
Question: In a kilometer race, If Abhishek gives Bharti a 40 m start, Abhishek wins by 19 sec. But if Abhishek gives Bharti a 30 sec start, Bharti wins by 40 m. Find the time taken by Bharti to run 5,000 m?
A.150 sec
B.750 sec
C.450 sec
D.825 sec
Answer: B.750 sec
Explanation: Explanation :
If Abhishek takes x seconds and Bharti takes y seconds to run 1 km, then:
=>y=150 sec and x=125 sec
=>x+19=960y/1000 and
=(960x/1000)+30=y
=>y=150 sec and x=125 sec
Answer =(150/1000)×500
= 750 sec
Answer : B
Question: Find the arithmetic mean B of all roots of the following equation- see an attachment.
A.2
B.1
C.0.5
D.-1/3
Answer: C.0.5
Explanation: arithmetic mean B your answer C and E are same, can you correct one of them please. thanks.C
Question: In a psychology school the grade of the students is determined by the following method: At the end of the first year the grade equals to twice the age of the student. From then on, the grade is determined by twice the age of the student plus half of his grade from the previous year. If Joey’s grade at the end of the first year is 44, what will be his grade at the end of the third year?
A.44
B.56
C.82
D.75
Answer: C.82
Explanation: Cool question!
There's a lot of information given here, so let's eat slow here.
Joey scores a 44 at the end of his first year. That means that he's currently 22 years old (since given per instruction, after the first year one's grade is determined by doubling his/her age).
Now, come next year, or his second year at this psychology school, he's technically 23 years old. To find out the second year's grade, we want to double his age PLUS half of his previous grade.
Well, his second year is then going to be 23(2) + 22 = 68.
Now let's tackle the main question: what's his grade going to be the third year?
Well, he will be at an age of 22 on his third year at this school. Again, to find out his third year's grade, you're going to double his age (24x2), plus half of his previous year's grade (as calculated for his second year, his grade is 68; therefore, 68/2)
Having said that, the final answer would be 24(2) + 68/2 = 48 + 34 = 82 --> (C)
Question: 2^(2x/3) = 2^(x/2)
What is the value of x ?
A.2
B.2/3
C.1
D.0
Answer: D.0
Explanation: 2x/3 = x/2
4x = 3x
4x-3x=0; x=0
Ans: D
Question: The product of the prime integers between 33 and 40, inclusive, is:
A.50! – 40!
B.99,029
C.1,221
D.2,021
Answer: C.1,221
Explanation: only prime number bet ween 43 and 50 inclusive are 43 and 47
thus 33*37 = 1221
Ans: C
Question: Simplify: 896 x 896 - 204 x 204
A.716200
B.761200
C.712600
D.710612
Answer: B.761200
Explanation: = (896)^2 - (204)^2
= (896 + 204) (896 - 204)
= 1100 x 692 = 761200.
Answer is B
Question: From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first is a red card and the second is a king is -
A.1/26
B.3/52
C.15/26
D.11/26
Answer: A.1/26
Explanation: Explanation:
Let E1 be the event of drawing a red card.
Let E2 be the event of drawing a king .
P(E1 âˆ© E2) = P(E1) . P(E2)
(As E1 and E2 are independent)
= 1/2 * 1/13 = 1/26
ANSWER IS A
Question: Of the 45 employees of a certain company, twice as many are in the sales department as are in all of the other departments combined. What is the number of employees in the sales department?
A.15
B.20
C.30
D.40
Answer: C.30
Explanation: This is ratio problem solving question.
I will prefer to use RMV box.
R M V
Sales 2 15 30
Other 1 15 15
Total 3 15 45
Answer is 30. i.e C
Question: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
A.5
B.4
C.6
D.7
Answer: B.4
Explanation: M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9 = 4
Answer:B
Question: A laborer is engaged for 30 days on the condition that he receives Rs.25 for each day he works and is fined Rs.7.50 for each day is absent. He gets Rs.425 in all. For how many days was he absent?
A.7
B.8
C.9
D.10
Answer: D.10
Explanation: 30 * 25 = 750
425
-----------
325
25 + 7.50 = 32.5
325/32.5 = 10
ANSWER:D
Question: If a2+b2=177and ab=54 then find the value of a+b/a-b?
A.5
B.4
C.2
D.1
Answer: A.5
Explanation: (a+b)2=a2+b2+2ab=117+2*24=225
a+b=15
(a-b)2=a2+b2-2ab=117-2*54
a-b=3
a+b/a-b=15/3=5
Answer is A.
Question: The area of rhombus is 150 cm square. The length of one of the its diagonals is 10 cm. The length of the other diagonal is:
A.15 cm
B.20 cm
C.25 cm
D.30 cm
Answer: D.30 cm
Explanation: Explanation:
We know the product of diagonals is 1/2*(product of diagonals)
Let one diagonal be d1 and d2
So as per question
1/2∗d1∗d2=150
1/2∗10∗d2=150
d2=150/5=30
Option D
Question: A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 180 kilometers?
A.4.5 gallons
B.8 gallons
C.9.5 gallons
D.10 gallons
Answer: A.4.5 gallons
Explanation: Each 40 kilometers, 1 gallon is needed. We need to know how many 40 kilometers are there in 180 kilometers?
180 / 40 = 4.5 *1 gallon correct answer A
Question: A man can row upstream at 7 kmph and downstream at 33 kmph, and then find the speed of the man in still water?
A.11
B.77
C.30
D.20
Answer: D.20
Explanation: US = 7
DS = 33
M = (33 + 7)/2 = 20
Answer:D
Question: (1+0.0001)/(0.04+100)
The value of the expression above is closet to which of the following?
A.0.0001
B.0.01
C.0.1
D.1
Answer: B.0.01
Explanation: Notice that we need approximate value of the fraction.
Now, the nominator is very close to 1 and the denominator is very close to 10, hence the value of the fraction is very close to 1/100=0.01.
Answer: B.
Question: The price of a certain painting increased by 20% during the first year and decreased by 25% during the second year. The price of the painting at the end of the 2-year period was what percent of the original price?
A.102%
B.90%
C.120%
D.85%
Answer: B.90%
Explanation: Easiest thing to do: Assume that price is 100
Price at the end of yr 1: 100+ 20 = 120
Price at the end of year 2 = 120 - 120*0.25 = 120*0.75 = 90
Hence required answer = (90/100)*100% = 90%
Answer is B.
Question: QUANT 4-PACK SERIES Problem Solving Pack 4 Question 2 For every positive integer n...
For every positive integer n that is greater than 1, the function s(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The s(n) could have any of the following units digits except…?
A.1
B.2
C.4
D.6
Answer: B.2
Explanation: For every positive integer n that is greater than 1, the function s(n) is defined to be the sum of all of the odd integers from 1 to n, inclusive. The s(n) could have any of the following units digits except…?
Used brute force on this one to calculate. Not sure if there is a quicker way.
1+3=4 C is out
1+3+....15= 81 A is out
1+3+5+7=16 D is out
1+3+5=9 E i out
Answer: B
Question: 1/4+[(2/3*3/8)+4]-9/16=
A.63/16
B.19/16
C.15/16
D.9/13
Answer: A.63/16
Explanation: 1/4+[(2/3*3/8)+4]-9/16=
1/4+[(1/4)+4]-9/16=
1/4+[17/4]-9/16=
4/16 + 68/16 - 9/16 = 63/16
A
Question: Two trains of equal lengths take 10 sec and 20 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
A.16 sec
B.13 sec
C.17 sec
D.21 sec
Answer: B.13 sec
Explanation: Speed of the first train = 120/10 = 12 m/sec.
Speed of the second train = 120/20 = 6 m/sec.
Relative speed = 12 + 6 = 18 m/sec.
Required time = (120 + 120)/18 = 13 sec.
Answer: B
Question: A palindrome is a word or a number that reads the same forward and backward. For example, 2442 and 111 are palindromes. If 5-digit palindromes are formed using one or more of the digits 1 and 2, how many palindromes are possible?
A.8
B.12
C.16
D.24
Answer: A.8
Explanation: There are 2 choices for each of the first three digits.
The number of possible palindromes is 2^3=8.
The answer is A.
Question: If a number is formed by writing integers 1 to 150 one after another, like 12345...150. How many E digits does this integer consists of?
A.150
B.339
C.342
D.359
Answer: C.342
Explanation: Number of single digit integers = 9
Number of 2 digit integers = 99 - 10 + 1 = 90
Number of 3 digit integers = 150 - 100 + 1 = 51
Number of digits in the integer E= 1*9 + 2*90 + 3*51 = 9 + 180 + 153 = 342
Answer: C
Question: If |y−12|<112|y−12|<112, which of the following could be a value of y?
A.-11
B.-11/2
C.11/2
D.11
Answer: C.11/2
Explanation: |y−12|<112|y−12|<112, is equivalent to −112<y−12<112−112<y−12<112.
Add 1212 to each part of the inequality: −112+12<y<112+12−112+12<y<112+12 --> −5<y<6−5<y<6.
Only answer C is from this range.
Answer: C.