RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The average weight of a class is x pounds. When a new student weighing 60 pounds joins the class, the average decreases by 1 pound. In a few months the student’s weight increases to 110 pounds and the average weight of the class becomes x + 4 pounds. None of the other students’ weights changed. What is the value of x?
A.85
B.86
C.88
D.90
Answer: C.88
Explanation: When the student weighs 80 pounds the average weight is x - 1 pounds;
When the student weighs 110 pounds the average weight is x + 4 pounds.
So, the increase in total weight of 110 - 80 = 30 pounds corresponds to the increase in average weight of (x + 4) - (x - 1) =5 pounds, which means that there are 30/5 = 6 students (including the new one). So, initially there were 5 student.
Total weight = 5x + 80 = 6(x-1) --> x = 88 pounds.
Answer: C.
Question: A man's age is 125% of what it was 10 years ago, but 83 1/3%
of what it will be after 10 years. What is his present age?
A.70
B.60
C.50
D.40
Answer: C.50
Explanation: Age before 10 years =x
125x/100=x+10
125x=100x+1000
x=1000/25=40
Present age =x+10=40+10=50
answer :C
Question: If the speed of X inch per second is equivalent to the speed of Y meter per hour, what is Y in terms of X? (1 meter=39.3701 inch)
A.21.44X
B.33.35X
C.67.77X
D.91.44X
Answer: D.91.44X
Explanation: X inch per second -->
--> 3,600X per hour(as there are 3,600 seconds in one hour);
--> 3,600X/39.3701=91.44X meter per hour (as there are 39.3701 inch in one meter).
Answer: D.
Question: A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 3500. The difference between the profit shares of A and C is?
A.621
B.1400
C.236
D.600
Answer: B.1400
Explanation: Explanation:
Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 3500
=> 5 parts out of 15 parts is Rs. 3500
Now, required difference is 6 - 4 = 2 parts
Required difference = 2/5 (3500) = Rs. 1400
Answer:B
Question: If x = a!, which of these following values of a is the least possible value (in this list) for which the last 9 digits of the integer x will all be zero?
A.26
B.32
C.37
D.44
Answer: D.44
Explanation: 2*5 will give one 0 at the end. We need 2^9*5^9 to get 9 zeroes at the end.
There are many 2's, so we need to find the first 9 appearances of 5.
These multiples of 5 are: 5, 10, 15, 20, 5*5, 30, 35, 40...which gives us 9.
To have at least 9 zeroes at the end, a => 40.
The answer is D.
Question: Machine A can finish a job in 4 hours, Machine В can finish the job in 12 hours, and Machine С can finish the job in 6 hours. How many hours will it take for A, B, and С together to finish the job?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: The combined rate is 1/4+1/12+1/6 = 1/2 of the job per hour.
The time to complete the job is 2/1 = 2 hours.
The answer is B.
Question: A certain protective additive increases from 20 days to 25 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive?
A.25%
B.33 1/3%
C.50%
D.66 2/3%
Answer: A.25%
Explanation: General formula for percent increase or decrease, (percent change):
percent=Change/Original∗100
So, the time between maintenance checks increased by 25−20/20∗100=25
Answer: A.
Question: Rahul went to a shop and bought things worth Rs. 30, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
A.Rs 15
B.Rs 12.10
C.Rs 24.70
D.Rs 36.80
Answer: C.Rs 24.70
Explanation: Explanation :
Let the cost of the tax items = x
Given that tax rate = 6%
Cost of tax items, x*(6/100) = 30/100
x = 5 rs
Now non taxable item = total cost - cost for taxable item - tax
= 30 - 5 - 0.30
=24.70
Answer : C
Question: A 360 meter long train crosses a man standing on the platform in 6 sec. What is the speed of the train?
A.229
B.108
C.278
D.216
Answer: D.216
Explanation: S = 360/6 * 18/5 = 216 kmph
Answer: D
Question: 7 points are marked on a straight line and another 5 points are marked on a second straight line with no points in common. How many triangles can be constructed with vertices from among the above points?
A.91
B.105
C.175
D.21
Answer: C.175
Explanation: getting the answer 175 which is not in the choices, what is the source of the problem?
7C2* 5C1 + 5C2* 7C1 = 175
C
Question: It takes 30 days to fill a laboratory dish with bacteria. If the size of the bacteria doubles each day, how long did it take for the bacteria to fill 1/32 of the dish?
A.25
B.26
C.27
D.28
Answer: A.25
Explanation: The bacteria doubles each day, so after 29 days, the dish was half full.
After 28 days, the dish was one quarter full.
After 27 days, the dish was one eighth full.
After 26 days, the dish was one sixteenth full.
After 25 days, the dish was 1/32 full.
The answer is A.
Question: Mr. Evans will states that each of his children will receive an equal share of his estate and that his grandchildren will split a portion of the estate that is equal to the share received by each of his children. If Mr. Evans has 3 children and 5 grandchildren, then approximately what percentage of Mr. Evans estate will each grandchild receive?
A.20%
B.17%
C.5.0%
D.3.3%
Answer: C.5.0%
Explanation: 25/5=5
Answer : C
Question: Farmer Charlie has a chicken farm. On a certain day, Charlie calculates in how many days he will run out of chicken-food. He notices that if he would sell 75 of his chickens, he could feed the remaining chickens twenty days longer with the chicken-food he has, and that if he would buy 100 extra chickens, he would run out of chicken-food fifteen days earlier.
How many chickens does farmer Charlie have?
A.100
B.500
C.300
D.400
Answer: C.300
Explanation: C
300
Let n be the number of chickens and let d be the number of days in which Charlie will run out of chicken-food with this number of chickens. The total amount of chicken-food always equals the number of chickens multiplied by the number of days the food lasts. Therefore, the total amount of chicken-food equals n × d.
If Charlie would sell 75 of his chickens, he could feed the remaining chickens twenty days longer, so the total amount of chicken-food would then equal
( n - 75 ) × ( d + 20 ).
But the total amount of chicken-food does not change, so
( n - 75 ) × ( d + 20 ) = n × d
which can be rewritten to equation 1:
d = 4/15 × n - 20.
If Charlie would buy 100 extra chickens, he would run out of chicken-food fifteen days earlier, so the total amount of chicken-food would then equal
( n + 100 ) × ( d - 15 ).
But the total amount of chicken-food does not change, so
( n + 100 ) × ( d - 15 ) = n × d
which can be rewritten to equation 2:
d = 3/20 × n + 15.
Combining equations 1 and 2 gives:
4/15 × n - 20 = 3/20 × n + 15.
Solving this equations gives n = 300, so farmer Charlie has 300 chickens.
Question: If the perimeter of a rectangular garden is 800 m, its length when its breadth is 100 m is?
A.300 m
B.777 m
C.200 m
D.167 m
Answer: A.300 m
Explanation: 2(l + 100) = 800 => l
= 300 m
Answer:A
Question: At an election 2 candidates are participated a candidate got 30% of votes and defeated by 5000 votes. 100 votes are invalid. Find the total polled votes?
A.11520
B.12600
C.15000
D.13560
Answer: B.12600
Explanation: winners votes = 100-30 = 70%
invalid votes = 100
polled votes = [(100*5000)/(2*70-100)]+100 = 12600
Answer is B
Question: If the average (arithmetic mean) of 5 positive temperatures is y degrees Fahrenheit, then the sum of the 3 greatest of these temperatures, in degrees Fahrenheit, could be:
A.6y
B.4y
C.5y/3
D.3y/2
Answer: B.4y
Explanation: The sum of three greatest should be more than sum of two lowest.
The total sum is; 5y
A. 6y; 6y is more than 5y. Not possible.
B. 4y; 5y-4y=y(Possible)
C. 5y/3; 10y/3; 10y/3 > 5y/3. Not possible
D. 3y/2; 7y/2; 7y/2 > 3y/2. Not possible
E. 3y/5; 22y/5; 22y/5 > 3y/5. Not possible.
Ans:B
Question: A trade analyst announced 10% reduction in the unit price of bike. As a result, the sales volume went up by 5%. What was the net effect on the sales revenue?
A.no change
B.decreases by 5.5%
C.increases by 5.5%
D.increases by 5%
Answer: B.decreases by 5.5%
Explanation: Explanation :
Reduction of price = (100 -10)% = 90% = 0.9
Increase of sale = (100+5)% = 105% = 1.05
Total effect = 0.9 X 1.05 =94.5%, Decreases by 5.5%
Answer : B
Question: E is the sister of F and G. H is F's daughter. I is F's son. Which of the following statements is definitely false?
A.E is F's sister
B.G is E's uncle
C.F is G's brother
D.G is I's uncle
Answer: B.G is E's uncle
Explanation: Explanation:
E,F and G are children of same parents. So. G cannot be E's uncle.
Answer: B
Question: Three partner’s A,B,C start a business. Twice A’s capital is equal to thrice B’s capital and B’s capital is four times C’s capital. Out of a total profit of Rs.16500 at the end of the year, B’s share is:
A.Rs.4000
B.Rs.6000
C.Rs 7500
D.Rs 7500
Answer: B.Rs.6000
Explanation: Let C = x. Then B = 4x and 2A = 3 * 4x = 12x. or A = 6x.
Therefore, A : B : C = 6x : 4x : x = 6 : 4 : 1.
Therefore, B’s capital = Rs. 16500 * 4/11
= Rs.6000.
ANSWER:B
Question: If 3<x<6<y<7, then what is the greatest possible positive integer difference of x and y?
A.3
B.4
C.5
D.6
Answer: A.3
Explanation: 3 < x < 6 < y < 7;
3 < x
y < 7
3 + y < x + 7
y - x < 4.
Positive integer difference is 3(for example y = 6.5 and x = 3.5)
Answer:A.
Question: N, which is a set of natural numbers is partitioned into subsets S1 = {1}, S2 = {2,3}, S3 = {4,5,6}, S4 = {7,8,9,10} and so on. The sum of the elements of the subset S50 is
A.(a) 61250
B.(b) 65525
C.(c) 42455
D.(d) 62525
Answer: D.(d) 62525
Explanation: The question is based heavily on pattern-matching skills, and is far more 'layered' than what you would likely see on the Official GMAT on this subject. You'll likely find it easiest to define the patterns one-at-a-time, so that you can see how they impact the question.
To start, we're given information on the sub-sets of numbers:
-The 1st set has 1 number
-The 2nd set has 2 numbers
-The 3rd set has 3 numbers
Etc.
So the 50th set will have 50 numbers in it.
Since the numbers in the subsets are consecutive, we can figure out ALL of the numbers that show up BEFORE we get to the 50th set by usingbunching...
The 1st set has 1 number and the 49th set has 49 numbers....1 + 49 = 50 numbers
The 2nd set has 2 numbers and the 48th set has 48 numbers...2 + 48 = 50 numbers
Etc.
This pattern will continue all the way down to...
The 24th set has 24 numbers and the 26th set has 26 numbers...24 + 26 = 50 numbers
Thus, we have 24 'pairs' of 50 numbers and one set (the 25th set with 25 numbers) that doesn't have a 'pair-match'...
So 24(50) + 25 = 1225 consecutive numbers exist in the 49 sets BEFORE the 50th set - that's the numbers 1 to 1225, inclusive...
Thus, the 50th set starts with 1226 and ends with 1275. We can use 'bunching' again to figure out the sum of this group (although there's no 'middle term' this time)...
25(1226+1275) =
25(2501) =
62525
D
Question: A train overtakes 2 girls who are walking inthe opposite direction in which the train is going at the rate of 3 km/hour & 6km/hour and passes them completely in 36sec & 30 sec respectively. Find the length of the train is?
A.90 m
B.100 m
C.150 m
D.180 m
Answer: C.150 m
Explanation: Let the length of the train e x meter, and let the speed of train be y km/h, then
\inline x=\left ( y+3 \right )\frac{5}{18}\times 36 ........(1)
and \inline x=\left ( y+6\right )\frac{5}{18}\times 30 ........(2)
From eq (1) and (2), we get
\inline (y+3)\times 36 = ( y+6)\times 30
y = 12 km/h
\inline \therefore \inline x=(y+3)\times \frac{5}{18}\times 36
x= 150 m
C
Question: Ram and Shakil run a race of 2000m. First Ram gives Shakil a start of 200m and beats him by 1 minute.Next Ram gives shakil a start of 6 min and is beaten by 1000 meters . Find the time in minutes in which Ram and Shakil can run the race seperately.
A.12,18
B.10,18
C.10,12
D.8,10
Answer: D.8,10
Explanation: let speed of ram and shakil be x and y resp.
case1: ram gives a start of 200m and beats shakil by 1 minute.
2000/x - 1800/y= -60
2000/x= 1800/y -60---------------------(1)
case2: ram gives shakil a start of 6 min and is beaten by 1000 meters
distance travelled by shakil in 6 minutes= (6*60*y) meters = 360y meters
1000/x = (2000- 360y)/y------------------(2)
solve for x, y..
answer is x=8minutes, y= 10minutes
ANSWER:D
Question: A company plans to award prizes to its top 3 salespeople, with the largest prize going to the top salesperson, the next-largest prize to the next salesperson, and a smaller prize to the third-ranking salesperson. If the company has 6 salespeople on staff, how many different arrangements of winners are possible?
A.120
B.1,440
C.1,320
D.220
Answer: A.120
Explanation: [quote=Bunuel]A company plans to award prizes to its top 3 salespeople, with the largest prize going to the top salesperson, the next-largest prize to the next salesperson, and a smaller prize to the third-ranking salesperson. If the company has 6 salespeople on staff, how many different arrangements of winners are possible?
6*5*4
=120
Answer : A
Question: If you roll one fair six-sided die, what is the probability that the number is even or greater than 3?
A.1/2
B.1/3
C.2/3
D.3/4
Answer: C.2/3
Explanation: The numbers which satisfy the conditions are 2, 4, 5, and 6.
The probability is 4/6=2/3
The answer is C.
Question: If x/4 years ago Roger was 14 years old and x/4 years from now he will be 4x years old, how old will he be 4x years from now?
A.31
B.35
C.30
D.40
Answer: A.31
Explanation: Assume the current age = a
a - x/4 = 14 (i)
a + x/4 = 4x
Or a = 15x/4 (ii)
Putting the value of a from (ii) in (i)
15x/4 - x/4 = 14
Or 14x/4 = 14 Therefore x = 4 and a = 15
4x years from now, age will be 15 + 4*4 = 31
Option A
Question: In a forest 110 deer were caught, tagged with electronic markers, then released. A week later, 50 deer were captured in the same forest. Of these 50 deer, it was found that 5 had been tagged with the electronic markers. If the percentage of tagged deer in the second sample approximates the percentage of tagged deer in the forest, and if no deer had either left or entered the forest over the preceding week, what is the approximate number of deer in the forest?
A.150
B.750
C.1,250
D.1,500
Answer: D.1,500
Explanation: The percentage of tagged deer in the second sample = 5/50*100=10%.
So, 150 tagged deers comprise 10% of total # of deers --> total # of deers = 110*10 = 1,100.
Answer: D.
Question: Each of the 47 members in a high school class is required to sign up for a minimum of one and a maximum of three academic clubs. The three clubs to choose from are the poetry club, the history club, and the writing club. A total of 14 students sign up for the poetry club, 22 students for the history club, and 20 students for the writing club. If 3 students sign up for exactly two clubs, how many students sign up for all three clubs?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: The total number in the three clubs is 14+22+20=56.
All 47 students signed up for at least one club.
3 of those students signed up for exactly one more club.
56 - 50 = 6 so 3 students must have signed up for exactly three clubs.
The answer is C.
Question: The product of x and y is a constant. If the value of x is increased by 30%, by what percentage must the value of y be decreased?
A.16%
B.23.07%
C.25%
D.30%
Answer: B.23.07%
Explanation: x*y = constt.
Let x = y = 100 in beginning
i.e. x*y = 100*100 = 10000
x (100) ---becomes---> 1.3x (130)
i.e. 130*New 'y' = 10000
i.e. New 'y' = 10000/130 = 76.92
i.e. y decreases from 100 to 76.92 i.e. Decrease of 23.07%
B
Question: On multiplying a number by 3, the product is a number each of whose digits is 7. What is the smallest such number?
A.259129
B.259219
C.259279
D.259259
Answer: D.259259
Explanation: Explanation:
Let's use hit and trial method here.
Smallest number from the given choices = 259129
259129 × 3 = 777387
Next highest number from the given choices = 259219
259219 × 3 = 777657
Next highest number from the given choices = 259259
259259 × 3 = 777777
Hence 259259 is the answer.
Answer: D
Question: A teacher will pick a group of 9 students from a group of 14 students that includes Bart and Lisa. If one of all the possible 9-student groups is picked at random, what is the probability of picking a group that includes both Bart and Lisa?
A.11/70
B.36/91
C.21/47
D.121/390
Answer: B.36/91
Explanation: Probability = Favorable Outcomes / Total Outcomes
Total Outcomes= Total No. of ways of Picking Group of 9 out of 14 = 14C9 = 14! / (9! * 5!) = 2002
Favorable Outcomes= Total No. of ways of Picking Group of 9 out of 14 such that B and L are always in the group (i.e. we only have to pick remaining two out of remaining 12 as B and L must be there is group) = 12C7 = 792
Hence,Probability=792/2002=36/91
Answer: Option B
Question: The radius of a semi circle is 6.3 cm then its perimeter is?
A.12.9
B.32.4
C.32.1
D.32.2
Answer: B.32.4
Explanation: 36/7 r = 6.3
= 32.4
Answer: B
Question: Find the odd man out
10,20,40,80,90,160
A.10
B.90
C.20
D.80
Answer: B.90
Explanation: 10*2 = 20
20*2 =40
40*2=80
80*2=160
160*2=320
ANSWER:B
Question: Rs. 6000 is lent out in two parts. One part is lent at 5% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?
A.1:1
B.5:6
C.5:2
D.5:8
Answer: A.1:1
Explanation: Let the amount lent at 5% be Rs. x
Amount lent at 10% is Rs. (6000 - x)
Total interest for one year on the two sums lent
= 5/100 x + 10/100 (6000 - x) = 600 - 3x/100
=> 600 - 3/100 x = 450 => x = 3000
Amount lent at 10% = 3000
Required ratio = 1:1
Answer:A
Question: The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 45 kg. What might be the weight of the new person?
A.65 kg
B.90 kg
C.85 kg
D.Data inadequate
Answer: A.65 kg
Explanation: A
65 kg
Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (64 + 20) kg = 65 kg.
Question: Ms. Popez deposits $ 130 in an account that pays 20% interest, compounded semiannually. How much money will there be in the account at the end of one year?
A.$118.00
B.$120.00
C.$157.30
D.$122.00
Answer: C.$157.30
Explanation: Using Formula - A = P(1+r/n)^nt
Given
P=130
n=2
t=1
r=0.2
Substituting value in formula
A = 130(1+0.2/2)^2
A= 157.30$=C
Question: Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 192 as interest at the end of the loan period, what was the rate of interest?
A.4
B.6
C.18
D.Cannot be determined
Answer: A.4
Explanation: let rate = R% and time = R years
Then ( 1200 x R x R /100) = 192
=> 12R2= 192
=> R2= 16
=> R= 4
Answer A
Question: The difference of the squares of two consecutive even integers is divisible by which of the following numbers?
A.4
B.3
C.7
D.6
Answer: A.4
Explanation: Let the consecutive even integers are n and (n + 2)
difference of the squares = (n + 2)^2 - n^2 = (n^2 + 4n + 4) - n^2 = 4n + 4 = 4(n + 1)
which is divisible by 4
Answer is A
Question: Two trains 170 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
A.10.9
B.10.7
C.10.3
D.11.88
Answer: D.11.88
Explanation: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 170 + 160 = 330 m.
Required time = 330 * 9/250 = 297/25 = 11.88 sec.
'Answer: D
Question: How many different combinations of outcomes can you make by rolling three standard (6-sided) dice if the order of the dice does not matter?
A.24
B.30
C.56
D.120
Answer: C.56
Explanation: 1) All dice have the same number:
you have 6 possibilities.
2) 2 dice have the same number, but the 3rd is different:
you have 6*5
3) 3 dice are all different:
you have 6*5*4/3! = 20.
Because the question says the order does not matter, u have to divide it by 3!.
so totally you have 56.
ANS:C. 56.
Question: The sale price sarees listed for Rs.600 after successive discount is 10% and 5% is?
A.227
B.513
C.342
D.787
Answer: B.513
Explanation: 600*(90/100)*(95/100)
= 513
Answer: B
Question: The cost of 8 sharpeners and 12 pens is Rs.76/-. What is the cost of 20 sharpeners and 30 pens?
A.Rs.172
B.Rs.186
C.Rs.190
D.Rs.195
Answer: C.Rs.190
Explanation: Explanation:
From the above statement we have,
The cost of 4 sharpeners + 6 pens = Rs.38/-
Multiplying each term by 5, we get
20 sharpeners + 30 pens = Rs.38x5 =Rs.190
Answer: Option C
Question: If r is the square of a positive integer, which of the following must be equal to the square of the next positive integer?
A.√n + 1
B.n + 1
C.n^2 + 1
D.r + 2√r + 1
Answer: D.r + 2√r + 1
Explanation: If r is the square of a positive integer, which of the following must be equal to the square of the next positive integer?
r = (x)^2 where x is a positive integer
To calculate -
(x+1)^2 = x^2 + 2x + 1
root(r) = x
Ans - r + 2 root(r) + 1
This should be D
Question: Robert spent $104 in buying raw materials, $175 in buying machinery and 10% of the total amount he had as cash with him. What was the total amount?
A.A)$150
B.B)$210
C.C)$250
D.D)$310
Answer: D.D)$310
Explanation: Let the total amount be x
then, (100-10)% of x = 104+175
90% of x = 279
90x/100 = 279
x = $310
Answer is D
Question: In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 5:6:2. If there are in all Rs.42, the number of 25 paisa coins is?
A.40
B.42
C.43
D.45
Answer: B.42
Explanation: 5x 6x 2x
50 25 100
250x + 150x + 200x = 4200
600x = 4200
x = 7 => 6x = 42
B
Question: A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. Find the average
speed for first 320 km of tour.
A.70.11 km/hr
B.71.11 km/hr
C.72.11 km/hr
D.73.11 km/hr
Answer: B.71.11 km/hr
Explanation: Explanation:
We know Time = Distance/speed
So total time taken =
(16064+16080)=92hours Time taken for 320 Km = 320
∗
29=71.11km/hr
Answer: B
Question: A no.when divided by 125 gives a remainder 40, what remainder will be obtainedby dividingthe same no.15?
A.10
B.11
C.12
D.13
Answer: B.11
Explanation: 125 + 40 = 165/15 = 11 (Remainder)
B
Question: A man bought 10 crates of pine apples for $160 total. If he lost 2 of the crates, at what price would he have to sell each of the remaining crates in order to earn a total profit of 30 percent of the total cost?
A.$36
B.$46
C.$26
D.$16
Answer: C.$26
Explanation: As given, after lost, the remaining 8 crates total cost = $160
So, 1 crate cost = 160/8 =20
To get 30% profit, 1 crate cost should be =20+20*30/100 =$26
Answer : C
Question: The cost price of an article is 64% of the marked price. Calculate the gain percent after allowing a discount of 14%?
A.34.375%
B.48%
C.50.5%
D.52%
Answer: A.34.375%
Explanation: Explanation:
Let marked price = Rs. 100.
Then, C.P. = RS. 64, S.P. = Rs. 86
Gain % = 22/64 * 100 = 34.375%.
Answer: Option A
Question: How much interest can a person get on Rs. 8200 at 17.5% p.a. simple interest for a period of two years and six months?
A.3587.58
B.3587.52
C.3587.5
D.3587.51
Answer: C.3587.5
Explanation: I = (8200 * 2.5 * 17.5)/100
= (8200 * 5 * 35)/(100 * 2 * 2)
= Rs. 3587.50
Answer: C
Question: In the last set of tests, a student scored marks in each of 5 subjects in the ratio 4:5:6:7:8 and got an overall average score of 60%. If a mark of 50% in a subject is a pass and the maximum marks of each subject is the same, how many subjects did the student pass?
A.1
B.2
C.3
D.4
Answer: D.4
Explanation: The tests scores are 4k, 5k, 6k, 7k, and 8k.
The sum of the test scores is 30k.
The average test score is 30k/5 = 60. Then k = 10.
The test scores are 40, 50, 60, 70, and 80.
The student passed 4 subjects.
The answer is D.
Question: Albert invested Rs. 1000 in a scheme for 3 years at compound interest rate 10% p.a. How much amount will Albert get on maturity of the fixed deposit?
A.s.1300
B.s.1005
C.s.1031
D.s 1331
Answer: D.s 1331
Explanation: Amount = [1000 * (1 + 10/100)3]
= 1000 * 11/10 * 11/10 * 11/10
= Rs.1331
Answer:D