RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: 1/(√2-1)=?
A.9+4√5
B.9-4√5
C.√2+1
D.9-2√5
Answer: C.√2+1
Explanation: This question requires us to rationalize (fix) the denominator.
For more on this technique, seehttps://www.gmatprepnow.com/module/gmat ... video/1044
Given: 1/(√2-1)
Multiply top and bottom by the CONJUGATE of √2-1, which is √2+1
So, 1/(√2-1) = (1)(√2+1)/(√2-1)(√2+1)
= (√2+1)/(1)
= √2+1
=
C
Question: Two machines, Y and Z, work at constant rates producing identical items. Machine Y produces 13 items in the same time Machine Z produces 14 items. If machine Y takes 28 minutes to produce a batch of items, how many minutes does it take for machine Z to produce the same number of items?
A.26
B.9
C.9 1/2
D.12
Answer: A.26
Explanation: rate z/rate y=14/13
time z/time y=13/14
(13/14)*28=26 minutes
A
Question: A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 472. What is the sum of the last 8 of the even integers?
A.588
B.594
C.600
D.606
Answer: C.600
Explanation: The sum of the first 8 numbers is: x + (x+2) +...+ (x+14) = 472
The sum of the next 8 numbers is: (x+16) + (x+2+16) +...+ (x+14+16) =
472 + 8(16) = 472 + 128 = 600
The answer is C.
Question: Last year, a certain public transportation system sold an average (arithmetic mean) of 41,000 tickets per day on weekdays (Monday through Friday) and an average of 15,000 tickets per day on Saturday and Sunday. Which of the following is closest to the total number of tickets sold last year?
A.1 million
B.1.25 million
C.10 million
D.12.2 million
Answer: D.12.2 million
Explanation: If you type that into the calculator, it results in 12.3 mil
[D], 12.2 mil, is the correct answer... see 2 posts above for quick approx method
Question: The sum of all the integers s such that -26 < s < 24 is
A.0
B.-2
C.-25
D.-49
Answer: D.-49
Explanation: Easy one -
-25, -24, -23,-22,...... -1,0, 1, 2...., 22, 23
Cancel everyhitng and we're left with - -25 and -24 s= -49.
D is the answer.
Question: 3 workers transfer a tool weighing 120kg in 12 seconds. How many men are required to transfer it in 9 seconds?
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: We have, M1D1H1 = M2D2H2
3*120*12 = M2*120*9
M2 = 3*120*12/120*9 = 4
ANSWER:A
Question: A batch of cookies was divided amomg 6 tins: 2/3 of all the cookies were placed in either the blue or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin
A.15/2
B.9/4
C.5/9
D.5/7
Answer: D.5/7
Explanation: This will help reduce the number of variables you have to deal with:
G + B = 2/3
R = 1/6
B = 1/4
We can solve for G which is 5/12
What fraction (let it equal X) of the cookies that were placed in the other tins were placed in the green tin?
So..
X*(G+R)=G
X*(5/12 + 1/6) = 5/12
X = 5/7
ANSWER: D
Question: Each child has 12 crayons and 24 apples. If there are 18 children, how many crayons are there in total?
A.220
B.65
C.216
D.219
Answer: C.216
Explanation: 12*18=216.Answer is C.
Question: If x and y are different prime numbers, each greater than 8, which of the following must be true? I. x+y is an even integer II. xy is an odd integer III. (x/y) is not an integer
A.I,II only
B.I,III only
C.II,III only
D.I,II and III
Answer: D.I,II and III
Explanation: Given: x and y are different prime numbers, both greater than 8
Statement I: x+y is an even integer
Since x and y are prime numbers greater than 8, they will be odd
Therefore sum will be even.
Correct
Statement II: xy is an odd integer
Since x and y are prime numbers greater than 8, they will be odd
Therefore multiplication will be odd.
Correct
Statement III: (x/y) is not an integer
Since x and y are prime integers, therefore they will not have any common factor apart from 1
Hence (x/y) will not be an integer
Correct
Hence all three statements I, II and III are correct
Answer : D
Question: In an examination, 25% of total students failed in Hindi, 35% failed in English and 40% in both. The percentage of these who passed in both the subjects is :
A.10%
B.20%
C.60%
D.80%
Answer: D.80%
Explanation: pass percentage = 100 - (25+35-40) = 100-20 = 80
ANSWER:D
Question: Ramesh starting from a fixed point goes 15 km towards North and then after turning to his right he goes 15 km. then he goes 10, 15 and 15 metres after turning to his left each time. How far is he from his starting point?
A.8 km
B.9 km
C.10 km
D.11 km
Answer: C.10 km
Explanation: he will be 10 km. away from his starting point.
ANSWER:C
Question: Copper is 7 times as heavy as water and gold is 13 times as heavy as water. In what ratio should these be mixed to get an alloy 11 times as heavy as water ?
A.2 : 1
B.1 : 2
C.2 : 3
D.3 : 2
Answer: B.1 : 2
Explanation: Explanation :
Solution: C = 7W and G = 13W.
Let 1 gm of copper be mixed with x gm of gold to get (1+x)gm of alloy.
(1gm copper)+(xgm gold) = (x+1)gm of alloy.
=>7W+13W*x = (x+1)*11W
=> 7+13x = 11(x+1)
=> 2x = 4 => x = 2.
.'. Ratio of copper and gold = 1 : 2
Answer : B
Question: A train running at the speed of 60 km/hr crosses a pole in 12 seconds. What is the length of the train?
A.200 metres
B.180 metres
C.324 metres
D.228 metres
Answer: A.200 metres
Explanation: Speed= 60 x	5/18	m/sec	= 50/3	m/sec.
Length of the train = (Speed x Time).
Length of the train = 50/3	x 9	m = 200 m.
Option A
Question: The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, what is the weight of B?
A.31 kg
B.28 1/2 kg
C.32 kg
D.30 1/2 kg
Answer: A.31 kg
Explanation: Explanation:
Let the weight of A, B and C are a,b and c respectively.
Average weight of A,B and C = 45
a + b + c = 45 × 3 = 135 --- equation(1)
Average weight of A and B = 40
a + b = 40 × 2 = 80 --- equation(2)
Average weight of B and C = 43
b + c = 43 × 2 = 86 --- equation(3)
equation(2) + equation(3) - equation(1)
=> a + b + b + c - (a + b + c) = 80 + 86 - 135
=> b = 80 + 86 -135 = 166 - 135 = 31
Weight of B = 31 Kg
Answer: Option A
Question: A milk man sells the milk at the cost price but he mixes the water in it and thus he gains 9.09%. The quantity of water in the mixture of 1 liter is?
A.83.33 ml
B.12.33 ml
C.77.33 ml
D.22.33 ml
Answer: A.83.33 ml
Explanation: Profit (%) = 9.09 % = \inline \frac{1}{11}
Since the ratio of water and milk is 1 : 11,
Therefore the ratio of water is to mixture = 1:12
Thus the quantity of water in mixture of 1 liter =
{1}/{12} = 83.33 ml
Answer: A
Question: A train 220 m long is running with a speed of 90 km/hr. In what time will it pass a bus that is running with a speed of 60 km/hr in the direction opposite to that in which the train is going?
A.4.37
B.5.28
C.6.75
D.8
Answer: B.5.28
Explanation: Speed of train relative to bus = 90 + 60 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Time taken to pass the bus = 220 * 3/125
= 5.28 sec.
Answer: B
Question: 50 litres of diesel is required to travel 600 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 800 km using 1200 cc engine?
A.80 litres
B.90 litres
C.100 litres
D.170 litres
Answer: C.100 litres
Explanation: Explanatory Answer
To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 800/600*50 = 66.67 litres.
However, the vehicle uses a 1200 cc engine and the question states that the amount of diesel required varies directly as the engine capacity.
i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too.
Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800*66.67 = 100 litres.
Answer C
Question: There are 5 bags three of which each contains 4 white and 2 black balls, and remaining 2 bags each contains 1 white and 4 black ball; a white ball has been drawn, find the chance that it came from first group.
A.2/7
B.6/35
C.8/25
D.5/6
Answer: D.5/6
Explanation: Please go through my solution and suggest any mistake.
Chances of selecting a white ball from group 1: 2/3---------------------Chances of selecting a white ball from group 2: 1/5
Thus combined probability of section of white ball from group 1:
3/5 x 2/3 = 2/5
Thus combined probability of section of white ball from group 2:
2/5 x 1/5 = 2/25
Out of these chances, chance of occurrence of first case : (2/5) / (2/5 + 2/25) = 5/6
D
Question: In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1400 employees, then the no. of female employees who are computer literate ?
A.588
B.674
C.672
D.960
Answer: A.588
Explanation: Solution: Total employees,
= 1400
Female employees, 60% of 1400.
= (60 *1400) /100 = 840.
Then male employees,
= 560
50 % of male are computer literate,
= 280 male computer literate.
62 % of total employees are computer literate,
= (62 *1400) /100 = 868 computer literate.
Thus, Female computer literate = 868 - 280
= 588.
Answer: Option A
Question: 9 - 3 ÷ 1/3 + 5 = ?
A.5
B.3
C.6
D.9
Answer: A.5
Explanation: 9 - 3 1/3 + 5
=9-3÷1/3+5
=9-(3X3) +5
=9-9+5
=5
CORRECT ANSWER : A
Question: a product of ages of ankit and nikita is 240. if twice the age of nikita is more than ankit's by 4 years. what is the nikita's age?
A.12yrs
B.13yrs
C.14yrs
D.15yrs
Answer: A.12yrs
Explanation: if ankit age=x
nikita age=240/x
then (2*(240/x))-x=4 so,x=20
ankit age=20yrs
nikita age=(240/20)=12yrs
ANSWER:A
Question: The average weight of 22 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.
A.48.89
B.42.25
C.50
D.51.25
Answer: A.48.89
Explanation: Explanation:
Average weight of 22 boys = 50.25
Total weight of 22 boys = 50.25 × 22
Average weight of remaining 8 boys = 45.15
Total weight of remaining 8 boys = 45.15 × 8
Total weight of all boys in the class = (50.25 × 16)+ (45.15 × 8)
Total boys = 22 + 8 = 30
Average weight of all the boys = ((50.25×22)+(45.15×8))/30
=48.89
Answer: Option A
Question: It rained as much as on Wednesday as on all the other days of the week combined. If the average rainfall for the whole week was 3 cms, How much did it rain on Wednesday?
A.10.9
B.10.5
C.10.2
D.10.1
Answer: B.10.5
Explanation: Explanation:
Let the rainfall on wednesday = 6x.
∴ Rainfall on the remaining days = 6x
Given,
(6x + 6x )/7 = 3
⇒12x = 21
⇒6x = 10.5
Answer: B
Question: Find the value of x from the below equation? : 3x^2+5x+2 = 0
A.-1
B.1
C.2
D.3
Answer: A.-1
Explanation: a = 3, b = 5, c = 2
x1,2 = (-5 ± √(52 - 4×3×2)) / (2×3) = (-5 ± √(25-24)) / 6 = (-5 ± 1) / 6
x1 = (-5 + 1)/6 = -4/6 = -2/3
x2 = (-5 - 1)/6 = -6/6 = -1
A
Question: The average weight of 8 girlsincreases by 2.5 kg when a new gitl comes in place of one of them weighing 65 kg. What might be the weight of the new girl?
A.65 kg
B.75 kg
C.85 kg
D.90 kg
Answer: C.85 kg
Explanation: Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (65 + 20) kg = 85 kg
C
Question: If money is invested at r percent interest, compounded annually, the amount of investment will double in approximately 70/r years. If Pat's parents invested $ 7000 in a long term bond that pays 8 percent interest, compounded annually, what will be the approximate total amount of investment 18 years later, when Pat is ready for college?
A.$28000
B.$15000
C.$12000
D.$10000
Answer: A.$28000
Explanation: Since investment doubles in 70/r years then for r=8 it'll double in 70/8=~9 years (we are not asked about the exact amount so such an approximation will do). Thus in 18 years investment will double twice and become ($7,000*2)*2=$28,000 (after 9 years investment will become $7,000*2=$14,000 and in another 9 years it'll become $14,000*2=$28,000).
Answer: A.
Question: From a Group of 9 People, Including George and Nina, 4 people are to be selected at random to work on a certain project. What is the probability that 4 people selected will include George but not Nina
A.5/56
B.9/56
C.15/56
D.35/120
Answer: D.35/120
Explanation: Number of ways of selecting 4 people out of 9 people = 9C4
In the three members George will always be there in the team. At this step we have vacancy for 3 more members and 8 members are available. Nina cannot be there in the team. So 3 members have to be selected and the number of available members = 8 - Nina = 7
Number of ways to form a 4 member team that includes George and excludes Nina = 7C3
Probability = 7C3/9C4 = 35/120
Answer: D
Question: A train crosses a platform in 25 sec, same train crosses another platform of length 400 m in 30 sec. If the length of the train is 200m , find the length of the platform?
A.280m
B.180m
C.350m
D.300m
Answer: D.300m
Explanation: Length of the platform be ‘X’
(X + 200)/25 = (200 + 400)/30
6X + 1200 = 3000
X = 300m
Answer: D
Question: In a class, the average age of 30 boys is 13 years and the average of 20 girls is 12 years. what is the average age of the whole class?
A.12.9
B.12.1
C.12.3`
D.12.6
Answer: D.12.6
Explanation: Total age of 50 students
(30X 13+20 X 12) = 630
Average = 630/50 = 12.6 Years
Answer: D
Question: A number x is 6 times another number y. The percentage that y is less than x is
A.12.5%
B.83.3%
C.80%
D.11%
Answer: B.83.3%
Explanation: Say y=1 and x=6.
Then y=1 is less than x=6 by (6-1)/6*100=5/6*100=83.3%.
Answer: B.
Question: Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R ?
A.377
B.500
C.287
D.179
Answer: B.500
Explanation: Let the amounts to be received by P, Q and R be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r
Adding 'p' both sides, 3p = p + q + r = 1200
=> p = Rs.400
q = 1/3 (p + r) => 3q = p + r
Adding 'q' both sides, 4q = p + q + r = 1200
=> q = Rs.300
r = 1200 - (p + q) => r = Rs.500.
Answer: B
Question: Rahul can do a work in 3 days while Rajesh can do the same work in 2days. Both of them finish the work together and get $170. What is the share of Rahul?
A.$68
B.$40
C.$60
D.$100
Answer: A.$68
Explanation: Rahul's wages: Rajesh's wages = 1/3 : 1/2 = 2:3
Rahul's share = 170*2/5 = $68
Answer is A
Question: The function F(n) is defined as the product of all the consecutive positive integers between 2 and n^2, inclusive, whereas the function G(n) is defined as the product of the squares of all the consecutive positive integers between 1 and n, inclusive. The exponent on 2 in the prime factorization of F(3)/G(3) is
A.	1
B.	2
C.	3
D.	4
Answer: C.	3
Explanation: F(3)/G(3)
=product(1 to 3 ^2) / 1.2^2.3^2
=1.2.3.4.5.6.7.8.9/1.4.9
=1.2.3.(2^2).5.(2.3).7.(2^3).9/1.(2^2).9
=1.(2^7).3.5.7.9/1.(2^2).9
Loof for 2^7/2^2=2^5 ----Exponent 3
Answer: C
Question: Positive integer y is 50 percent of 50 percent of positive integer x, and y percent of x equals 9. What is the value of x?
A.20
B.60
C.100
D.120
Answer: B.60
Explanation: y = 0.5*0.5*x = x/4
y%*x = 9
(y/100)*x = 9
(x/400)*x = 9
x^2 = 9*400
x = 60
The answer is B.
Question: One day a car rental agency rented 3/4 of its cars, including 2/3 of its cars with CD players. If 3/5 of its cars have CD players, what percent of the cars that were not rented had CD players?
A.1/2
B.2/3
C.3/4
D.4/5
Answer: D.4/5
Explanation: The cars with CD players which were not rented is (1/3)(3/5) = 1/5 of all the cars.
The cars which were not rented is 1/4 of all the cars.
The percent of non-rented cars which had CD players is (1/5) / (1/4) = 4/5
The answer is D.
Question: To produce an annual income of Rs. 1200 from a 12 % stock at 90,the amount of stock needed is :
A.Rs. 10,000
B.Rs. 10,800
C.Rs. 14,400
D.Rs. 16,000
Answer: A.Rs. 10,000
Explanation: Solution
For an income of Rs. 12, stock needed = Rs. 100.
For an income of Rs. 1200, stock needed = Rs. 10/12x12000=10,000
Answer A
Question: .007/?= .01
A..7
B..07
C..007
D..0007
Answer: A..7
Explanation: Let .007/x = .01;
Then x = .007/.01
= .7/1
= .7
Answer is A
Question: A and B have monthly incomes in the ratio 5:6 and monthly expenditures in the ratio 3:4. If they save Rs. 1800 and Rs. 1600 respectively, find the monthly income of B
A.Rs. 3400
B.Rs. 2700
C.Rs. 1720
D.Rs. 7200
Answer: D.Rs. 7200
Explanation: Explanation:
Incomes of A and B=5x and 6x and expenses of A and B = 3y and 4y
Then, savings of A = 5x-3y = 1800—?(1)
Savings of B = 6x-4y = 1600—?(2)
By solving equations (1) and (2)
y = 1400
Monthly income of B = Expenses of B + savings of B
= 4y+1600 = 4(1400) + 1600 = Rs. 7200
Answer: D
Question: John has 10 pairs of matched socks. If he loses 9 individual socks, what is the greatest number of pairs of matched socks he can have left?
A. 7
B. 6
C. 5
D. 4
Answer: C. 5
Explanation: Because we have to maximize the pair of matched socks, we will remove 4 pairs(8 socks) out of 10 pairs 1 sock from the 5th pair.
Thus the no of matching socks pair remaining = 10 -5 = 5
Answer C
Question: Jim takes a seconds to swim d meters at a constant rate from point P to point Q in a pool. Roger, who is faster than Jim, can swim the same distance in b seconds at a constant rate. If Jim leaves point P the same time that Roger leaves point Q, how many fewer meters will Jim have swum than Roger when the two swimmers pass each other?
A.c(b-a)/ a+b
B.d(a-b)/a+b
C.c(a+b)/a-b
D.ab(a-b)/a+b
Answer: B.d(a-b)/a+b
Explanation: Both JimRoger are travelling at constant speedin opposite direction:
So, speed of Jim = d/a speed of Roger = d/b
Let say Jim travelled distance x from P where it met Roger, it means that Roger travelled (c-x) from point Q
[x would be less than (c-x) as Jim is travelling slow]
From above, time taken by Jim to travel x = xa/d....................... (1)
Also, time taken by Roger to travel (c-x) = (d-x)b/d.....................(2)
Time taken by both JimRoger is same, so (1) = (2)
xa/d = (d-x)b/d,
Solving further, x = bd/(a+b).................... (3)
We require to find how many fewer meters will Jim have swum i.e
additional distance travelled by Roger = (d - x) - x
= d-2x
Substituting value of x from (3)solving the equation further, we get Answer = d(a-b)/a+b
Answer = (B)
Question: In the first 10 overs of a cricket game, the run rate was only 3.4. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
A.4.25
B.5
C.6.2
D.7
Answer: C.6.2
Explanation: Required run rate = 282 - (3.4 x 10) =	248
248/40 = 6.2
C)
Question: Which of the following equations describes a line that is perpendicular to y=x-7?
A.y = x + 7
B.y = −5 − x
C.y = 7x
D.y = 7x+1
Answer: B.y = −5 − x
Explanation: Two perpendicular lines have slopes that are inverse reciprocals of each other.
The slope of y=x-7 is 1 so the slope of a perpendicular line will be -1.
The answer is B.
Question: A taxi company with a fleet of 50 taxis, plans to replace all their taxis with electric cars. Every year it retires 10 of their old taxis and buys 12 electric cars to replace them. How many years will it take to reduce their old taxi fleet to below 50% of their entire fleet if they started in 2003.
A.3
B.4
C.1
D.2
Answer: A.3
Explanation: Total fleet--50
End of year 2003 -- (retires 10 and buys 12) total fleet--52(40 old 12 new).
End of year 2004 -- (retires 10 and buys 12) total fleet--54(30 old 24 new).
End of year 2005 -- (retires 10 and buys 12) total fleet--56(20 old 36 new).
Answer is A--after 3 years the company has a total of 56 taxis (20 old 36 new), the old taxis are already less than 50% of its fleet.
Question: A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group?
A.628 ways
B.600 ways
C.767 ways
D.762 ways
Answer: B.600 ways
Explanation: Two men, three women and one child can be selected in 4C2 * 6C3 * 5C1 ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 5
= 600 ways.
Answer:B
Question: If a man walks at the rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at the rate of 6 kmph, he reaches the station 5 minutes before the arrival of the train. Find the distance covered by him to reach the station.
A.10 km
B.8 km
C.6km
D.4km
Answer: C.6km
Explanation: Sol. Let the required distance be x km
Difference in the time taken at two speeds=1 min =1/2 hr
Hence x/5-x/6=1/5<=>6x-5x=6
x=6
Hence, the required distance is 6 km
Option C
Question: A husband and wife can complete a certain task in 1 and 3 hours respectively. Their children, Rae and Herman, can complete the same task in 4 and 6 hours, respectively. What is the ratio of the couple's time working together to complete the task to the children's time working together to complete the task?
A.a)15:46
B.b)3:10
C.c)12:23
D.d)5:16
Answer: D.d)5:16
Explanation: couples one hour work=1/1+1/3=4/3
so total time=3/4.
now, kids one hour work=1/4+1/6=5/12
so total time=12/5..
ratio=3/4:12/5=5:16
ans D
Question: How many different committees each composed of 2 Republicans and 3 Democrats can be formed from a group of 4 Republicans and 5 Democrats?
A.12
B.24
C.60
D.72
Answer: C.60
Explanation: Let's take the Republicans. How many combinations of 2 can be created.
There are four total so: 4!/2!2! = 6
Democrats: 5!/3!2! = 10
6 x 10 = 60
ANSWER:C
Question: 10^25 - 260 is divisible by all of the following except:
A.A.10
B.B.8
C.C.5
D.D.4
Answer: B.B.8
Explanation: The last three digits ( 1000 - 260 ) 740
740 is divisible by 10,4,2,5
740 is not evenly divisible by 8 so the answer is B) 8
Question: M = {-6, -5, -4, -3, -2}
T = {-2, -1, 0, 2, 3}
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative?
A.0
B.1/3
C.2/5
D.1/2
Answer: C.2/5
Explanation: Answer C.
Total # of outcomes: 5*5= 25
# of outcomes where Product is -ve : (-6,1) ,(-6,2), (-6,3)... Hence, total: 10
Probability: 10/25 = 2/5
Question: A train 600 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 15 seconds. The speed of the train is:
A.45 km/hr
B.149 km/hr
C.54 km/hr
D.55 km/hr
Answer: B.149 km/hr
Explanation: Speed of the train relative to man = (600/15) m/sec = 40 m/sec. [40 * (18/5)] km/hr = 144 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 144 ==> x = 149 km/hr.
ANSWER: B
Question: 3/4th of a number exceeds its 2/3rd by 8. What is the number?
A.96
B.36
C.72
D.144
Answer: A.96
Explanation: Explanation:
Let the number be x.
3/4x = 2/3x + 8
Multiply by 12
9x = 8x + 96
x = 96
ANSWER :A
Question: The total age of A and B is 13 years more than the total age of B and C. C is how many years younger than A?
A.13
B.24
C.C is elder than A
D.Data inadequate
Answer: A.13
Explanation: Solution
[(A+B) - (B+C)]	= 13
â€¹=â€ºA - C
= 13.
Answer A
Question: A group consists of 7 men, 7 women and 6 children. In how many ways can 2 men , 1 woman and 2 child selected from the given group?
A.2210
B.2205
C.2215
D.2230
Answer: B.2205
Explanation: Two men, one woman and two child can be selected in 7C2 * 7C1 * 6C2 ways
7*6/2*1*7*6*5/2*1
=2205 ways
Answer : B
Question: Suresh started a business, investing Rs.18000. After 3 months and 4 months respectively, Rohan and Sudhir joined him with capitals of 12000 and 9000. At the end of the year the total profit was Rs.3795. What is the difference between Rohan’s and Sudhir’s share in the profit?
A.s.345
B.s.350
C.s.352
D.s.362
Answer: A.s.345
Explanation: Suresh : Rohan : Sudhir
Ratio of their investments = 18000 × 12 : 12000 × 9 : 9000 × 8
= 6 : 3: 2
The difference between Rohan’s and Sudhir’s share = 1 share
:.i.e. = Rs. 3795 × 1/11 = Rs.345.
A
Question: The average weight of a group of 30 friends increases by 3 kg when the weight of their 3 football coaches was added. If average weight of the group after including the weight of the 3 football coach is 33 kg, what is the average weight of their football coaches ?
A.31 kg
B.63 kg
C.61 kg
D.62 kg
Answer: B.63 kg
Explanation: let c=coach's avg. weight
original total weight=(30 friends)(30 kg avge)=900kg
(900+3c)/(30+3)=33 kg avg.
c=63 kg
Answer B
Question: Today is Varun's birthday. One year, from today he will be twice as old as he was 12 years ago. How old is Varun today ?
A.20 years
B.22 years
C.25 years
D.27 years
Answer: C.25 years
Explanation: let varuns age =x
x+1=2(x-12)
der4 x=25..
ANSWER:C