RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If two numbers are in the ratio 2:3. If 23 is added to both of the numbers then the ratio becomes 3:4 then find the smallest number?
A.A)10
B.B)46
C.C)25
D.D)30
Answer: B.B)46
Explanation: 2:3
2x + 23 : 3x + 23 = 3 : 4
4[2x + 23] = 3[3x + 23]
8x + 92 = 9x + 69
9x - 8x = 92 - 69
x = 23
Then smallest number is = 2
2x = 46
Correct Option B
Question: After running a series of television advertisements, a leading beverage producer saw its sales increase by 20% to $1 million dollars per month. Prior to the advertising campaign, about how many dollars in sales did the company average per day?
A.$1.25 million
B.$800,000
C.$750,000
D.$28,000
Answer: D.$28,000
Explanation: Let sales in previous month = X
1.2 X=1,000,000
6/5 X= 1,000,000 ..........> X=833,333
sales per day= 833,333/30= less than 30,000 so closest number is 27,000
Answer: D
Question: 2 pipes function simultaneously the reservoir will be filled in 12hrs. One pipe fills reservoir 10hrs faster than other. How many hours does the faster pipe take to fill the reservoir?
A.10
B.20
C.22
D.24
Answer: B.20
Explanation: 1/x + 1/(x + 10) = 1/12
x = 20
B
Question: A and B starts a business with Rs.8000 each, and after 7 months, B withdraws half of his capital . How should they share the profits at the end of the 18 months?
A.36:25
B.18:25
C.36:10
D.18:14
Answer: A.36:25
Explanation: A invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 7 months and then withdraws Rs.4000. So, the investment of B for remaining 11 months is Rs.4000 only.
A : B
8000*18 : (8000*7) + (4000*11)
14400 : 100000
A:B = 36:25
Answer: A
Question: Magnabulk Corp sells boxes holding d magnets each. The boxes are shipped in crates, each holding b boxes. What is the price charged per magnet, in cents, if Magnabulk charges n dollars for each crate?
A.100n/(bd)
B.100bd/n
C.bd/(100n)
D.n/(bd)
Answer: A.100n/(bd)
Explanation: crate has = bd magnates
C crate cost = n dollars = 100 m cents
each magnate cost for each crate = 100 n / bd
Ans; A
Question: A certain sum earns simple interest of Rs. 800 in 2 years at a certain rate of interest. If the same sum earns compound interest of Rs. 845 in the same period of 2 years, What must be the rate of interest?
A.5% p.a.
B.7.5% p.a.
C.10% p.a.
D.12.5% p.a.
Answer: C.10% p.a.
Explanation: Explanation:
Given: 800 = (P * R * 2) / 100
S.I. For 1 year = Rs. 400
Thus, (840 – 800) = S.I. on Rs. 400 for 1 year
40 = (400 * R * 1) / 100
R = 10% p.a.
ANSWER C
Question: The number 523gbc is divisible by 7,8,9. Then what is the value of g*b*c
A.504
B.532
C.210
D.180
Answer: D.180
Explanation: LCM of 7, 8 and 9 is 504, thus 523gbc must be divisible by 504.
523gbc=523000+gbc
523000 divided by 504 gives a remainder of 352.
Hence, 352+gbc=k*504.
k=1 gbc=152 --> g*b*c=10
k=2 gbc=656 --> g*b*c=180
As gbc is three digit number k can not be more than 2.
Two answers? Well only one is listed in answer choices, so D.
Answer: D.
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when a boy gets any no. of prizes?
A.36
B.42
C.64
D.69
Answer: C.64
Explanation: Ans.(C)
Sol. In this case, repetitions are allowed, so all the three prizes can be given in 4 ways, i.e. (4 x 4 x 4) ways = 43 ways = 64 ways Or nr ways = 43 ways = 64 ways
Question: A car salesman earns a base salary of $800 per month plus a commission of $200 for each car he sells. If the car salesman earned $2200 in July, how many cars does he need to sell in August in order to double his July earnings?
A.15
B.16
C.17
D.18
Answer: D.18
Explanation: 800+200x=4400
x=18 cars.
The answer is D.
Question: If (1/5)^n * (1/4)^18 = 1/(2*(10)^35), then n =
A.40
B.45
C.35
D.30
Answer: C.35
Explanation: (1/5)^m (1/4)^18 = 1/{2(10)^35}
2(10)^35/4^18 = 5^m
[2(2^35)(5^35)]/[2^36] = 5^m
5^35 = 5^m
n=35
C
Question: The mean daily profit made by a shopkeeper in a month of 30 days was Rs. 350. If the mean profit for the first fifteen days was Rs. 225, then the mean profit for the last 15 days would be
A.Rs. 200
B.Rs. 350
C.Rs. 475
D.Rs. 425
Answer: C.Rs. 475
Explanation: Average would be : 350 = (225 + x)/2
On solving, x = 475.
Answer: C
Question: Balloons and confetti are sold in different colours at a store. Balloons of three different colours and confetti of two different colours are to be bought by Jim Bob Jones from this store. If there are seven colours of balloons available and if there are a total of 350 combinations of different colours of balloons and confetti that can be purchased, how many colours of confetti are available at the store?
A.4
B.5
C.6
D.8
Answer: B.5
Explanation: 350 = Ways of choosing 3 balloon colors * ways of choosing 2 confetti colors
Jim can select 3 colors of balloons in 7C3 = 7*6*5/3*2 = 35 ways
So Ways of choosing 2 confetti colors = 350/35 = 10
If there are n different confetti colors, nC2 = 10 = n(n-1)/2
n = 5 satisfies this equation
Answer (B)
Question: What is the remainder when 45*49 is divided by 8?
A. 1
B. 3
C. 4
D. 5
Answer: D. 5
Explanation: we can make use of the rule :
Remainder of { (a * b)/n}} = Remainder of (a/n) * Remainder of (b/n)
Here
Remainder of { 45 * 49)/8}} = Remainder of (45/8) * Remainder of (49/8) = 5 * 1 = 7
Answer :D
Question: The length of the bridge, which a train 160 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
A.230
B.244
C.245
D.215
Answer: D.215
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (160 + X)/30 = 25/2 ==> 2(160 + X) = 750 ==> X = 215 m.
Answer: Option D
Question: When the price of a radio was reduced by 20%, its sale increased by 80%. What was the net effect on the sale?
A.44% increase
B.44% decrease
C.66% increase
D.75% increase
Answer: A.44% increase
Explanation: Let the original price be x and sale be of y units.
Then, the revenue collected initially = x × y
Now, new price = 0.8x, new sale = 1.8y
Then, new revenue collected = 1.44xy
% increase in revenue = 0.44xy/xy×100
= 44% increase
Answer A
Question: The simple interest accrued on an amount of Rs.49500 at he end of three is Rs.17820. What would be the compound interest accured on the same amount at teh same rate in the same period? (Round off your answer to two decimal places)
A.Rs.20043.94
B.Rs.20043.95
C.Rs.20043.91
D.Rs.20043.98
Answer: A.Rs.20043.94
Explanation: Explanation:
Let the rate of interest be R% p.a.
(49500)(3)(R)/100 = 17820
495R = 5940
R = 12
CI on Rs.49500 at 12% p.a. for three years
= 49500{[1 + 12/100]3 - 1} = 69543.936 - 49500 = Rs.20043.94
when rounded off to two decimal places.
Answer: A
Question: If x, y, and z are negative integers and 3x - 3y = -3z, then which of the following statements must be true?
I.	x > y> z
II.	x = z
III. x > y
A.I and II
B.I only
C.II only
D.III only
Answer: D.III only
Explanation: 3x-3y=-3z
x-y=-z
Since z<0; -z>0
x-y>0
x>y
III correct.
We can't say much about z though;
x=-5; y=-100; z=-95
I and II incorrect.
Ans:D
Question: A company seeks to hire a sales manager, a shipping clerk, and a receptionist. The company has narrowed its candidate search and plans to interview all remaining candidates including 3 persons for the position of sales manager, 4 persons for the position of shipping clerk, and 10 persons for the position of receptionist. How many different hirings of these three people are possible?
A.3 + 4 + 10
B.3 × 4 × 10
C.21 × 20 × 19
D.7! + 4! + 10!
Answer: B.3 × 4 × 10
Explanation: 1 sales manager can be selected out of 3 in 3 ways
1 clerk can be selected out of 4 in 4 ways
1 receptionist can be selected out of 10 in 10 ways
total no. of ways these 3 can be selected = 3 *4 * 10
Ans. B)3 × 4 × 10
Question: A certain store sold pens for $0.35 each and pencils for $0.25 each. If a customer purchased both pens and pencils from the store for a total of $2.00, what total number of pens and pencils did the customer purchase?
A.6
B.9
C.10
D.11
Answer: A.6
Explanation: Answer: AAlgebraically, the question looks like this: 2.5 = 0.35x + 0.25yThere are six possible numbers of pens that fit that requirement:
1 pen: $0.35
2 pens: $0.70
3 pens: $1.05
4 pens: $1.40
5 pens: $1.75 and 1 pencils for $0.25 each. That's 5 pens and 1 pencils for a total of 6 pens and pencils. Choice (A) is correct.
Question: Find the no.of ways of arranging the boy and 6 guests at a circular table so that the boy always sits in a particular seat?
A.7!
B.6!
C.9!
D.10!
Answer: B.6!
Explanation: Ans.(B)
Sol. Total number of persons = 7 Host can sit in a particular seat in one way. Now, remaining positions are defined relative to the host. Hence, the remaining can sit in 6 places in 6P6 = 6! Ways ... The number of required arrangements = 6! x 1= 6! = 6! ways
Question: Today is Monday. After 61 days, it will be:
A.Tuesday
B.Wednesday
C.SATURDAY
D.Thursday
Answer: C.SATURDAY
Explanation: If today is Monday ..after 7 days it will be monday..soo 56th day will be Monday..
57- Tues
58-Wed
59-Thurs
60-Fri
61- SATURDAY
ANSWER:C
Question: Each truck from Kanes Removal Company can haul 750 pounds of trash at a time.
On Wednesday the company has jobs to remove 1,500 pounds of trash from one
site, 750 from another site, and 3,000 from a third site. How many total pounds of
trash will be moved by Jones Company that day? How many trips will it take for the
Jones Company to remove all of the trash?
A.5500 lbs.-2 Trips
B.4500 lbs.-9 Trips
C.2500 lbs.-3 Trips
D.5250 lbs.-7 Trips
Answer: D.5250 lbs.-7 Trips
Explanation: Total trash = 1500+750+3000 = 5250
No. of trips = 5250/750 = 7
Answer : D
Question: A rectangular field is 52 yards long and 20 yards wide. A fence is needed for the perimeter of the
field. Fencing is also needed to divide the field into three square sections. How many feet of fencing
are needed? (It is a good idea to make a drawing for this one.)
A.552 ft
B.530 ft
C.430 ft
D.330 ft
Answer: A.552 ft
Explanation: 52 + 20 + 52 + 20 = 144 yds. for
outside of field.
20 + 20 = 40 yds. for dividing sections
144 + 40 = 184 yds. of fencing
184 x 3 = 552 ft. of fencing
correct answer A
Question: A rectangular parking space is marked out by painting three of its sides. If the length of the unpainted side is 9 feet, and the sum of the lengths of the painted sides is 37 feet, then what is the area of the parking space in square feet ?
A.46
B.81
C.126
D.252
Answer: C.126
Explanation: Solution
Clearly, we have : l = 9 and l + 2b = 37 or b = 14.
∴ Area = (l × b ) = (9 × 14 ) sq. ft. = 126 sq.ft. Answer C
Question: The principal that amounts to Rs. 4813 in 3 years at 6 1/4 % per annum C.I. compounded annually, is?
A.s. 3096
B.s. 4036
C.s. 4085
D.s. 4096
Answer: B.s. 4036
Explanation: Principal = [4913 / (1 + 25/(4 * 100))3]
= 4813 * 16/17 * 16/17 * 16/17 = Rs. 4036.
ANSWER:B
Question: In a family, there are six members A, B, C, D, E and F.
A and B are a married couple, A being the male member. D is the only son of C, who is the brother of A. E is the sister of D. B is the daughter-in-law of F, whose husband has died.
How many male members are there in the family ?
A.1
B.9
C.3
D.4
Answer: C.3
Explanation: Explanation:
A is a male and married to B. So, A is the husband and B is the wife. C is the brother of A. D is the son of C. E, who is the sister of D will be the daughter of C. B is the daughter-in-law of F whose husband has died means F is the mother of A.
A is a male. B. the wife, is female. C. the brother, is male. D. the son, is male. E, the sister, is female. F, the mother, is a female. So, there are three males.
Answer: C) 3
Question: If A's salary is 20% less than B's salary, by how much percentage is B's salary more than A's?
A.25%
B.15%
C.30%
D.32%
Answer: A.25%
Explanation: Required percentage = [100*20/(100-20)]% = 25%
Answer is A
Question: In the manufacture of a certain product, 10 percent of the units produced are defective and 5 percent of the defective units are shipped for sale. What percent of the units produced are defective units that are shipped for sale?
A.0.25%
B.0.5%
C.0.75%
D.1.25%
Answer: B.0.5%
Explanation: 0.1*0.05 = 0.005 = 0.5%
The answer is B.
Question: Cars emerging from a motorway arrive at a junction that splits the road into two separate lanes. The number of cars per hour that continue in either lane is constant. If 14 cars per hour were diverted from the left lane to the right lane, the number of cars entering the right lane per hour would be twice as big as the number of cars entering the left lane per hour. Alternatively, if 14 cars per hour were diverted from the right lane to the left lane, the number of cars entering the left lane per hour would be four times as great as the number of cars entering the right lane per hour. How many cars enter the left lane per hour?
A.14
B.22
C.20
D.21
Answer: D.21
Explanation: as per question 14 cars diverted from left lane to right lane. Thus we get equation R+14=2(L-14)
as per question 14 cars diverted from right lane to left lane .thus we get equation L+14=4(R-14)
by solving two equation i.e R +14 =2L-28 OR. R =2L -42 AND L+14= 4R -56 OR L= 4R -70
BY SOLVING WE GET L= 4( 2L -28) -35 OR L= 8L -112-35 OR 147 =7L THUS L =21
D
Question: (3x + 1) (2x - 5) = ax^2 + kx + n . What is the value of a - n + k ?
A.5
B.8
C.9
D.14
Answer: D.14
Explanation: Expanding we have 6x^2 - 15x + 2x -5
6x^2 - 13x - 5
Taking coefficients, a = 6, k= -13, n = -5
Therefore a - n + k = 6 - (-13) - 5 = 19 - 5 = 14
The answer is D.
Question: At a certain store, the price of a pair of shoes is twenty dollars more than three times the price of a pair of jeans and the price of a sweater is forty percent more than the price of a pair of shoes. If the price of a pair of jeans is j dollars at this store, then what is the price, in dollars, of a pair of shoes, a sweater and a pair of jeans, in terms of j ?
A.1.5j + 10
B.3j + 20
C.4.5j + 30
D.8.2j + 48
Answer: D.8.2j + 48
Explanation: Ans D
Given
Price of Jeans = J
Price of shoes = 20+3J
Price of Sweater = 1.5(20+3J)
Total Price of all three items = J+20+3J+1.4(20+3J) = 48+8.2J
Question: A trader bought a car at 5% discount on its original price. He sold it at a 40% increase on the price he bought it. What percent of profit did he make on the original price?
A.118
B.133
C.112
D.113
Answer: B.133
Explanation: Original price = 100
CP = 95
S = 95*(140/100) = 133
100 - 133= 5%
Answer: B
Question: 0.009/x=0.01. find the value of X
A.0.0009
B.0.09
C.0.9
D.9
Answer: C.0.9
Explanation: x=0.009/0.01=0.9
ANSWER:C
Question: What is the next number of the following sequence
1,3,4,1,9...
A.14
B.15
C.16
D.17
Answer: C.16
Explanation: (1, 3 ,4) (1, 9, x)
square of 1st group gives 2nd group
1^2 = 1
3^2 = 9
4^2 = 16
ANSWER:C
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?
A.200 Sec
B.190 Sec
C.167 Sec
D.197 Sec
Answer: B.190 Sec
Explanation: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 1900 m
T = D/S
T = 1900/10
T = 190 Sec
Answer: B
Question: By selling 99 pens, a trader gains the cost of 33 pens. Find his gain percentage?
A.33 1/3%
B.33 1/0%
C.33 4/3%
D.31 1/3%
Answer: A.33 1/3%
Explanation: Let the CP of each pen be Rs. 1.
CP of 99 pens = Rs. 99
Profit = Cost of 33 pens = Rs. 33
Profit% = 33/99 * 100 = 33 1/3%
Answer:A
Question: The profit earned by selling an article for Rs.832 is equal to the loss incurred when the same article is sold for Rs.448. What should be the sale price for making 50% profit?
A.Rs.760
B.Rs.860
C.Rs.950
D.Rs.960
Answer: D.Rs.960
Explanation: Let C.P=Rs.x
Then 832-x=x-448
2x=1280-->x=640
150% of Rs.640=(150/100*640=Rs.960
Required S.P=Rs.960
ANSWER:D
Question: A group of four women and two men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in two adjacent seats, how many possible different seating arrangements are there for these 6 theatre-goers?
A. 7! – 2!3!2!
B. 7! – 4!3!
C.6! – 5!2!
D. 7 × 2!3!2!
Answer: C.6! – 5!2!
Explanation: 6 people can sit in 6! different ways. But because 2 men cannot sit together, we take them as a unit.
This unit of men, among themselves can sit in 2! ways.
Hence, 6! - 2!.
This unit of men along with 4 women can sit in 5! different ways which also needs to be eliminated.
Hence 6! - 5!2!
C
Question: In the first 10 overs of a cricket game, the run rate was only 5.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
A.6.25
B.6.5
C.6.75
D.5.75
Answer: D.5.75
Explanation: 10 overs - run rate = 5.2
runs scored in first 10 overs = 52
remaining overs 40
total runs to be scored= 282
52 runs already scored 282-52=230
230 runs to be scored in 40 overs
let required runrate be x
40*x=230
x=230/40
x=5.75
the required runrate is 5.75
ANSWER:D
Question: If the average of 54, 55, 57, 58, 59, 62, 62, 63, 65 and x is 60, what is the value of x?
A.60
B.62
C.64
D.65
Answer: D.65
Explanation: Sum of the deviations of the numbers in the set from the mean is always zero
54, 55, 57, 58, 59, 62, 62, 63, 65
mean is 60
so the list is -6-5-3-2-1+2+2+3+5... this shud total to zero
but this is -5 , hence we need a number that is 5 more than the mean to get a +5 and make it zero
hence the answer is 60 + 5 = 65
D
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 62 km downstream?
A.30/83 hours
B.33/13 hours
C.31/13 hours
D.30/13 hours
Answer: C.31/13 hours
Explanation: Speed downstream = 20 + 6 = 26 kmph.
Time required to cover 62 km downstream = d/s = 62/26
= 31/13 hours.
Answer:C
Question: Each week, Harry is paid x dollars per hour for the first 12 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ?
A.32
B.36
C.37
D.38
Answer: A.32
Explanation: 42x=12x+1.5x(H-12)
==> 42=12+1.5(H-12)
==> H-12= 30/1.5=20 ==> H = 32
Answer is A
Question: 50 numbers average is 30. If two numbers, 35 and 40 discarded, then the average of the remaining numbers is nearly:
A.29.68
B.30.5
C.36.78
D.40.05
Answer: A.29.68
Explanation: Total sum of 48 = (50*30) - (35+40) = 1500 - 75
=>1425
=>1425/48 =>29.68
ANSWER A
Question: If a coin has an equal probability of landing heads up or tails up each time it is flipped , what is the probability that the coin will land heads up exectly twice in 3 consecutive flips ?
A.0.125
B.0.25
C.0.375
D.0.5
Answer: C.0.375
Explanation: P=nCm*p^m*q^(n-m)
n - the total number of trials.
m - the number of trials with heads.
n-m - the number of trials with tails.
p - probability of heads.
q - probability of tails.
P=3C2*(1/2)^2*(1/2)^1=3/8=0.375
ANSWER:C
Question: Which of the following cannot be the range of a set consisting of 5 odd multiples of 15?
A.60
B.120
C.180
D.324
Answer: D.324
Explanation: Solution: sequence of 15 lets say sequence is 15n, 15(n+1), 15(n+2), 15(n+3), 15(n+4)
so range is 15n+60-15n = 60
if we put the different values of n we will get different but the range will be multiple of 60
and only 324 is not multiple of 60
Ans: D
Question: If the area of a circle is 16pi square feet, find its circumference.
A.8 pi feet
B.28 pi feet
C.38 pi feet
D.48 pi feet
Answer: A.8 pi feet
Explanation: The area is given by pi *r* r. Hence
pi * r *r = 16 pi
r * r = 16; hence r = 16 feet
The circumference is given by
2 * pi * r = 2 * pi * 4 = 8 pi feet
correct answer A
Question: A number is doubled and 9 is added. If resultant is trebled, it becomes 63. What is that number
A.6
B.10
C.12
D.14
Answer: A.6
Explanation: Explanation:
=> 3(2x+9) = 63
=> 2x+9 = 21
=> x = 6
Answer: Option A
Question: How long does a train 100 m long traveling at 60 kmph takes to cross a bridge of 170 m in length?
A.sec
B.sec
C.sec
D.sec
Answer: D.sec
Explanation: D = 100 + 170 = 270 m
S = 60 * 5/18 = 50/3
T = 270 * 3/50 = 16.2 sec
Answer: D
Question: Find the fourth proportional to 2.6, 4.6 and 7.6?
A.13.45
B.15
C.15.45
D.15.85
Answer: A.13.45
Explanation: Formula = Fourth propotional = (b Ã— c)/a
A = 2.6 , B = 4.6 and C = 7.6
(4.6 Ã— 7.6)/2.6 = 13.45
A
Question: The population of a town is 45000; 5/9th of them are males and the rest females 40% of the males are married. What is the percentage of married females?
A.60%
B.50%
C.45%
D.40%
Answer: B.50%
Explanation: Male = 45,000* 5/9 = 25,000
Female = 45,000* 4/9 = 20,000
Married Male = 25,000* 40/100 = 10,000
Married Female = 10,000
20,000 ------------ 10,000
100 ------------- ? => 50%
ANSWER:B
Question: A fruit seller had some apples. He sells 60% apples and still has 300 apples. Originally, he had:
A.656 apples
B.700 apples
C.750 apples
D.780 apples
Answer: C.750 apples
Explanation: A fruit seller had some apples. He sells 60% apples and still has 300 apples. Originally, he had:
A.
656 apples
B.
700 apples
C.
750 apples
D.
780 apples
800 apples
Answer: Option D
Explanation:
Suppose originally he had x apples.
Then, (100 - 60)% of x = 300.
40/100 x x = 300
100
x = (300 x 1000)/40 = 750.
ANSWER :C
Question: If line L passes through point (m, n) and (– m, – n), where m and n are not 0, which of the following must be true?
I.	The slope of L is positive
II.	The slope of L is need not be negative
III.	L exactly passes through 2 quadrants
A.I only
B.II only
C.III only
D.I and II only
Answer: D.I and II only
Explanation: Let (m,n) = (2,3)
(-m,-n) = (-2,-3)
Slope = (3+3)/(2+2) = 6/4 = 3/2
So II may be true
Let (m,n) = (2,-3) then (-m,-n) = (-2,3)
So slope = (3 +3)/(-2-2) = -3/2
so I may not be true
So such a line would be -> (y - 3) = 3/2(x - 2)
=> 2y - 6 = 3x - 6
=> 2y - 3x = 0, hence no x or y intercept, so it passes through origin.
III is true.
Answer - D
Question: The cost of an article is decreased by 50%. If the original cost is $200, find the decrease cost.
A.330
B.200
C.150
D.100
Answer: D.100
Explanation: Original cost = $200
Decrease in it = 50% of $200
= 50/100 Ã— 200
= 10000/100
= $100
Therefore, decrease cost = $200 - $100 = $100
Answer:D
Question: A train 220 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
A.5
B.6
C.7
D.12
Answer: D.12
Explanation: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [220 * 3/55] sec = 12 sec
Answer: Option D
Question: The cross-section of a cannel is a trapezium in shape. If the cannel is 14 m wide at the top and 8 m wide at the bottom and the area of cross-section is 550 sq m, the depth of cannel is?
A.76
B.28
C.50
D.80
Answer: C.50
Explanation: 1/2 * d (14 + 8) = 550
d = 50
Answer: C
Question: A square, with perimeter 32, is inscribed in a circle. What is the area of the circle?
A.22π
B.28π
C.32π
D.30π
Answer: C.32π
Explanation: Area of circuscribed circle = pi/2*area of square
Area of square = (32/4)^2 = 8^2= 64
Area of circle = pi/2*64=32pi
Answer C
Question: Number between 1 to 301. Find the non prime numbers is not divisible by 2,3,5,7.
A.10
B.12
C.15
D.18
Answer: A.10
Explanation: 11*11=121
11*13=143
11*17=187
11*19=209
11*23=253
11*29=319 which is not in range of 1-301 so we cant conider it
13*13=169
13*17=221
13*19=247
13*23=299
17*17=289
17*19=323 which is not in range of 1-301 so we can't consider it
So total possible numbers are 10
ANSWER:A
Question: A circular road runs round a circular ground. If the difference between the circumferences of the outer circle and inner circle is 66 metres, the width of the road is:
A.5.25m
B.7m
C.10.5m
D.21m
Answer: C.10.5m
Explanation: 2π(R-r)=60 => 2*22/7 * (R-r)=60.
Therefore, (R-r)= (66*7/44)= 10.5m
ANSWER:C
Question: f the sum of a list of consecutive odd integers is 5, which of the following could be true?
I. The average (arithmetic mean) of the list is equal to 5.
II. The median of the list is equal to 5.
III. The range of the list is equal to 5.
A.None
B.I only
C.II only
D.I and II
Answer: A.None
Explanation: Let the numbers be x-4, x-2, x , x+2, x+ 4 and given sum of all 5 number is 5, which is 5x = 5 and meaning x is 1
So the list is -3, -1, 1, 3, 5
I) AM of the list is 1 not 5, so eliminate
II) median is 1, not 5 , so eliminate
III) range is 5 - -3=8, not 5, so eliminate
Answer is A, None