RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The majority owner of a business received 25% of the profit, with each of 4 partners receiving 25% of the remaining profit. If the majority owner and two of the owners combined to receive $46,875, how much profit did the business make?
A.$55,000
B.$75,000
C.$95,000
D.$115,000
Answer: B.$75,000
Explanation: Let P be the total profit.
P/4 + 1/2*(3P/4) = P/4 + 3P/8 = 5P/8 = 46875
P = $75,000
The answer is B.
Question: When the price of an article was reduced by 40% its sale increased by 80%. What was the net effect on the sale?
A.8% increase
B.4% decrease
C.6% increase
D.66% increase
Answer: A.8% increase
Explanation: if n items are sold for $p each, revenue is $np. If we reduce the price by 40%, the new price is 0.6p. If we increase the number sold by 80%, the new number sold is 1.8n. So the new revenue is (0.6p)(1.8n) = 1.08np, which is 1.08 times the old revenue, so is 8% greater.
ANSWER:A
Question: If (20)² is subtracted from the square of a number, the answer so obtained is 4321. What is the number?
A.68
B.69
C.70
D.71
Answer: B.69
Explanation: x^2=4321+400=4721
4761=69*69
x=69
ANSWER:B
Question: In a certain large company, the ratio of college graduates with a graduate degree to non-college graduates is 1:8, and ratio of college graduates without a graduate degree to non-college graduates is 2:3. If one picks a random college graduate at this large company, what is the probability T this college graduate has a graduate degree?
A.1/11
B.1/12
C.1/13
D.3/19
Answer: D.3/19
Explanation: In believe the answer is D. Please see below for explanation.
0) we are told the following ratios
CGD - College Graduate with Degree
NCG - Non College Graduate
CGN - College Graduate no Degree
CGD NCG CGN
1 8
3 2
In order to make CGD and CGN comparable we need to find the least common multiple of 8 and 3 and that is 24 multiplying the first ratio by 3 and the second ratio by 8 we get
CGD NCG CGN
3 24 16
If one picks a random college graduate at this large company, what is the probability this college graduate has a graduate degree?
Nr of CGD = 3
Nr of CG = 3+ 16 = 19
Probability T of CGD / (CG) -> 3/19
Answer D
Question: The greatest common factor of positive integers m and n is 14. What is the greatest common factor of (2m^2, 2n^2)?
A.14
B.28
C.196
D.392
Answer: D.392
Explanation: m = 14j and n = 14k, where the greatest common factor of j and k is 1.
2m^2 = 2*14*14*j^2 and 2n^2 = 2*14*14*k^2
The greatest common factor of 2m^2 and 2n^2 is 2*14*14 = 392
The answer is D.
Question: A sun is divided among X, Y and Z in such a way that for each 5 rupees X gets, Y gets 3 rupees and Z gets 2 rupees. If the share of Z is RS. 200, what is the total amount of X and Y?
A.650
B.800
C.600
D.700
Answer: B.800
Explanation: x:y:z = 500:300200
5:3:2
2 --- 200
8 --- ? => 800
Answer: B
Question: If n is a prime number and n ≠ 3, which of the following could be the remainder when 100! + n is divided by 3?
I. 2
II. 1
III. -2
A.II only
B.III only
C.I and II only
D.II and III only
Answer: C.I and II only
Explanation: Notice that we are told that n is a prime number and n ≠ 3. Thus, n cannot be 1.
n also cannot be 6 or any other multiple of 3, thus the remainder cannot be 0.
It can be 1 for n=2 and 2 for n=5.
Answer: C.
Question: If xy > 0, 1/x + 1/y = 15, and 1/xy = 5, then (x+y)/5 = ?
A.1/25
B.1/6
C.3/5
D.5
Answer: C.3/5
Explanation: (1/X+1/Y)=15 canbe solved as {(x+y)/xy}=5. Substituting for 1/xy=5, we get
x+y=15/5
==> (x+y)/5= 15/(5*5)=3/5.
C
Question: A farmer sells his strawberries through a distributor, which take a commission of 12% of the price set by the farmer. The distributor obtains the product from a farmer at the price of $35 per bushel. What is the price that the buyer observers if the distributor wants to maintain a 12% profit on the cost of a bushel?
A.66.22
B.44.55
C.44.05
D.66.02
Answer: B.44.55
Explanation: Farmer price = $35;The distributor wants to maintain a 12% profit on the cost of each strawberry bushel, thus he must get $35*1.12 = $39.20 after the distributor takes a commission of 12% of the final price --> (final price)*0.88 = $39.20 --> (final price) = $44.55Answer: B.
Question: A train passes a man standing on the platform. If the train is 160 meters long and its speed is 72 kmph, how much time it took in doing so?
A.5 sec
B.6 sec
C.8 sec
D.9 sec
Answer: C.8 sec
Explanation: D = 160
S = 72 * 5/18 = 20 mps
T = 160/20 = 8 sec
ANSWER:C
Question: Length of a rectangular plot is 12 mtr more than its breadth. If the cost of fencing the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
A.56 m
B.60 m
C.80 m
D.82 m
Answer: A.56 m
Explanation: Let breadth = x metres.
Then, length = (x + 12) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 12) + x] = 200
2x + 12 = 100
2x = 88
x = 44
Hence, length = x + 12 = 56 m
A
Question: How much time does a train 125 metres long running at 60 km/hr take to pass a pole?
A.7.9s
B.2.5s
C.7.5s
D.7.6s
Answer: C.7.5s
Explanation: Explanation:
60 km/hr = 60 * 5/18 = 16.67 m/s
Speed = distance/time; v = d/t
16.67 = 125/t
t = 7.5s
ANSWER: C
Question: A car travels uphill at 30 km/hr and downhill at 90 km/hr. It goes 100 km uphill and 50 km downhill. Find the average speed of the car?
A.32kmph
B.39kmph
C.34kmph
D.35kmph
Answer: B.39kmph
Explanation: avg speed=total distance/total time.
total distance traveled=100+50=150km;
time taken for uphill journey=100/30=10/3;
time taken for down hill journey=50/90=5/9;
avg speed=150/(10/3+5/9)=39kmph
ANSWER:B
Question: 4,25,49,121,169,289,361,
A.149
B.169
C.189
D.529
Answer: D.529
Explanation: 23^2= 529 because follow sequence of square of the prime numbers
ANSWER:D
Question: The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 13 runs. Find his average in all the 30 matches?
A.31
B.66
C.55
D.77
Answer: A.31
Explanation: Total score of the batsman in 20 matches = 800.
Total score of the batsman in the next 10 matches = 130.
Total score of the batsman in the 30 matches = 930.
Average score of the batsman = 930/30 = 31.
Answer: A
Question: Two men and three women can repair a bridge in 10 days while three men and two women can do same work in 8 days. If two men and one woman are used to finish this work, in how many days they will complete it?
A.9.7 days
B.12.5 days
C.10 days
D.11.3 days
Answer: B.12.5 days
Explanation: Work done by 2 men and 3 women in 1 day = 1/10
Work done by 3 men and 2 women in 1 day = 1/8
Let 1 men does m work in 1 day and 1 women does w work in 1 day. The above equations can be written as
2 m + 3 w = 1/10 ---(1)
3 m + 2 w = 1/8 ---(2)
Solving equation (1) and (2) , we get m=14/200 and w=1/100
2 men and 1 woman together can finish the work in =14/200+1/100=2/25=12.5 days
B
Question: A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is?
A.16
B.13
C.15
D.18
Answer: C.15
Explanation: Suppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x - 5) and (x - 9) hours respectively to fill the tank.
1/x + 1/(x - 5) = 1/(x - 9)
(2x - 5)(x - 9) = x(x - 5)
x2 - 18x + 45 = 0
(x- 15)(x - 3) = 0 => x = 15
Answer: C
Question: Andrew is selling fruit to be able to buy a new bike. The bike costs 400. He sells a large bag of fruit for $8. He so far has sold 32 bags, how many more need to be sold in order to buy the bike.
A.3
B.18
C.15
D.12
Answer: B.18
Explanation: 8*32=256
400-256=144
144Ã·8=18
18 more bags of fruit need to be sold in irder for the bike to be purchased.
Therefore answer B is correct.
Question: A number increased by 10% gives 660. The number is?
A.200
B.300
C.500
D.600
Answer: D.600
Explanation: Formula = TOTAL=100% ,INCREASE = "+" DECREASE= "-"
A number means = 100 %
That same number increased by 10 % = 110 %
110 % -------> 660 (110 Ã— 6 = 660)
100 % -------> 600 (100 Ã— 6 = 600)
Option 'D'
Question: A driver covers a certain distance by car driving at 60 km/hr and returns back to the starting point riding on a scooter at 10 km/hr. What was the average speed for the whole journey?
A.14.2 km/h
B.17.1 km/h
C.19.3 km/h
D.21.7 km/h
Answer: B.17.1 km/h
Explanation: time 1 = d / 60
time 2 = d / 10
total time = d/60 + d/10 = 7d/60
average speed = total distance / total time = 2d / (7d/60) = 17.1 km/h
The answer is B.
Question: Walking at 3/4 of her normal speed, a worker is 12 minutes later than usual in reaching her office. The usual time (in minutes) taken by her to cover the distance between her home and her office is
A.36
B.48
C.60
D.62
Answer: A.36
Explanation: Let V be her normal speed and let T be her normal time.
D = (3/4)V * (T+12)
Since the distance is the same we can equate this to a regular day which is D = V*T
V*T = (3/4)V * (T+12)
T/4 = 9
T=36
The answer is A.
Question: The ratio of a to b to c is 2 to 3 to 4, and a, b, c are positive integers. If the average (arithmetic mean) of the three numbers is 27, what is the value of a?
A.18
B.20
C.21
D.22
Answer: A.18
Explanation: Let a=2k, b=3k, and c=4k.
a+b+c = 2k+3k+4k = 9k
Since the average is 27:
9k/3 = 27
3k = 27
k=9
Then a=18.
The answer is A.
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is?
A.188 m
B.876 m
C.251 m
D.150 m
Answer: D.150 m
Explanation: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m.
Answer: D
Question: According to a survey, at least 55% of people like apples, at least 75% like bananas and at least 80% like cherries. What is the minimum percentage of people who like all three?
A.10%
B.20%
C.25%
D.0%
Answer: A.10%
Explanation: To minimize the percentage who like all three, let's maximize the percentage who like 2 out of 3.
80% like cherries and 20% don't like cherries.
Let's combine this with the people who like bananas.
20% don't like cherries but do like bananas.
55% like cherries and bananas.
25% like cherries but not bananas.
Now let's distribute the people who like apples.
20% like bananas and apples, but not cherries.
25% like cherries and apples, but not bananas.
10% like all three.
45% like cherries and bananas, but not apples.
The answer is A.
Question: The positive integers p and q leave remainders of 2 and 3, respectively, when divided by 6. p > q. What is the remainder when p – q is divided by 6?
A.5
B.4
C.3
D.2
Answer: A.5
Explanation: Let's test out some values of p and q that satisfy the given information.
p leaves are remainder of 2 when divided by 6
So, p COULD equal 8
q leaves are remainder of 3 when divided by 6
So, q COULD equal 3
What is the remainder when p – q is divided by 6?
So, p - q = 8 - 3 = 5, and when we divide 5 by 6, we get 0 with remainder 5
Answer: A
Question: To complete a work A and B takes 8 days, B and C takes 12 days, A,B and C takes 6 days. How much
time A and C will take
A.24 days
B.16 days
C.12 days
D.8 days
Answer: D.8 days
Explanation: Explanation:
A+B 1 day work = 1/8
B+C 1 day work = 1/12
A+B+C 1 day work = 1/6
We can get A work by (A+B+C)-(B+C)
And C by (A+B+C)-(A+B)
So A 1 day work =
16−112=112
Similarly C 1 day work =
16−18=4−324=124
So A and C 1 day work =
112+124=324=18
So A and C can together do this work in 8 days
Answer: D
Question: The current birth rate per certain number of people is 32, whereas corresponding death rate is 11 per same number of people. If the net growth rate in terms of population increase is 2.1 percent, find number of persons.(initally)
A.1000
B.10000
C.100
D.2000
Answer: A.1000
Explanation: Sol.
Net growth on X = (32- 11) =21.
Net growth on 100 = (21/X Ã— 100)% = 2.1%. Then X = 1000
Answer:A
Question: A and B together can do a piece of work in 10 days. B alone can finish it in 20 days. In how many days can A alone finish the work ?
A.10
B.20
C.21
D.22
Answer: B.20
Explanation: Time taken by A to finish the work = XY/(Y-X)
= 10 x 20 / (20-10)
= 200/10
= 20 days
ANSWER : OPTION B
Question: 5358 x 52 = ?
A.273762
B.278616
C.273298
D.273258
Answer: B.278616
Explanation: B
5358 x 52 = 5358 x (50 + 2)
= 5358 x 50 + 5358 x 2
= 267900 + 10716
= 278616.
Question: A can do a piece of work in 12 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in ?
A.3 days
B.5 days
C.6 days
D.7 days
Answer: A.3 days
Explanation: B's 9 day's work = 9 x (1/12) = 3/4
Remaining work = (1 - 3/4) = 1/4
1/4 work is done by A in = 12 x (1/4) = 3 days.
answer : A
Question: A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.700, what is the reduced price for kg?
A.35
B.60
C.70
D.80
Answer: A.35
Explanation: A
700*(25/100) = 175 ---- 5
? ---- 1 => Rs.35
Question: In the first 10 overs of a cricket game, the run rate was only 3.8. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
A.4.25
B.5
C.6.1
D.7
Answer: C.6.1
Explanation: Required run rate = 282 - (3.8 x 10) =	244
244/40= 6.1
C)
Question: The average age of 20 students in a class is 15 years. If the age of teacher is also included, the average becomes 16 years, find the age of the teacher.
A.35
B.38
C.45
D.36
Answer: D.36
Explanation: Explanation:
If teacher's age is 15 years, there is no change in the average. But teacher has contributed 1 year to all the students along with maintaining his age at 16.
Age of teacher = Average age of all + Total increase in age
= 16 + (1 x 20 ) = 36 years
Answer:D
Question: A, B and C run around a circular track starting from the same point simultaneously and in the same direction at speeds of 4 kmph, 6 kmph and 8 kmph respectively. If the length of the track is 400 meters, when will A, B and C meet at the starting point for the first time after they started the race?
A.1 minute
B.5 minutes
C.12 minutes
D.20 minutes
Answer: C.12 minutes
Explanation: 4 kmph, 6 kmph and 8 kmph is equal to 4000/60 mtrs/min, 6000/60 mtrs/min and 8000/60 mtrs/min or 200/3, 100, 400/3 mtrs/min respectively.
Seeing this we can infer that the answer should be at least divisible by 3. (minutes in options are integers. So if the answer is not divisible by 3, we will have 200/3*answer = distance traveled by A in fractions whereas 100*answer = distance traveled by A as integer)
So, A,B and D are out.
At 12 min A,B and C will travel 800, 1200 and 1600 mtrs respectively. Length of the circle is given as 400 mtrs.
As 800, 1200 and 1600 are divisible by 400, we can say that A,B and C will be at starting point after 12 min.
Hence, C will be the answer.
Question: There is a unique number which when multiplied by any number from 1 to 6, we will get the new number that contains same digits only.Can you find that number ?
A.142857
B.135957
C.123354
D.114457
Answer: A.142857
Explanation: 142857 * 1 = 142857
142857 * 2 = 285714
142857 * 3 = 428571
142857 * 4 = 571428
142857 * 5 = 714285
142857 * 6 = 857142
These number are considered as cyclic numbers.
correct answer is A)142857
Question: The area of a sector of a circle of radius 5 cm formed by an arc of length 3.5 cm is?
A.8.78
B.8.67
C.8.75
D.8.98
Answer: C.8.75
Explanation: (5 * 3.5)/2
= 8.75
Answer:C
Question: A man traveled a total distance of 1800 km. He traveled one-third of the whole trip by plane and the distance traveled by train is three-fifth of the distance traveled by bus. If he traveled by train, plane and bus, then find the distance traveled by bus?
A.450 km
B.850 km
C.1200 km
D.750 km
Answer: D.750 km
Explanation: Total distance traveled = 1800 km.
Distance traveled by plane = 600 km.
Distance traveled by bus = x
Distance traveled by train = 3x/5
=> x + 3x/5 + 600 = 1800
=> 8x/5 = 1200 => x = 750 km.
ANSWER:D
Question: Of the 3,600 employees of Company X, 1/3 are clerical. If the clerical staff were to be reduced by 1/6, what percent of the total number of the remaining employees would then be clerical?
A. 25%
B. 22.2%
C. 20%
D. 29.4%
Answer: D. 29.4%
Explanation: Welcome, just post the question and the choices
Let's see, the way I did it was
1/3 are clerical out of 3600 so 1200 are clerical
1200 reduced by 1/6 is 1200*1/6
so it reduced 200 people , so there is 1000 clerical people left
but since 200 people left, it also reduced from the total of 3600 so there are 3400 people total
since 1000clerical left / 3400 people total
you get (A) 29.4%
Answer : D
Question: 3 buffaloes eat as much as 4 cows or 2 oxen. At a farm there are 15 buffaloes, 8 oxen and 24 cows. The fodder for these cattle is available for 24days. If 8 more cows & 9 more buffaloes are brought in, how long will the fodder last?
A.11
B.12
C.14
D.18
Answer: D.18
Explanation: Sol. 2 oxen = 3 buffaloes = 4 cows 8 oxen = 16 cows and 15 buffaloes = 20 cows 16 cows + 20 cows + 24 cows = 60 cows Since fodder is available for 60 cows for 24 days
So fodder will be available for (60 + 8 + 12) = 80 cows c 24x60 .0 .
for-^—=18 days.
D
Question: Which is greater 2/3 or 3/4?
A.2/3
B.3/4
C.both are equal
D.Cannot be determined
Answer: B.3/4
Explanation: To know which is greater 2/3 or 3/4
= Multiply both by 4*3 = 12 ( Product of denominator)
= 2/3 * 12 and 3/4 * 12 respectively
= 8 and 9 respectively
which means 3/4 is greater.
Ans: B
Question: A money lender lent a total of $1700 to two of his customers. He charged at the rate of 5%p.a. to one of them and 6% p.a. to the other. If he earned an average of 5.67% on $1700, how much did he lend to each of the two customers?
A.700; 1100
B.1139; 561
C.1000; 800
D.1200; 800
Answer: B.1139; 561
Explanation: The method given above is the one given in the book.
However the method I used was
(1*x*5)/100 + (1700-x)*6/100 = 1700*5.67/100
Simplifying we get x=561
B
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 sec. What is the length of the fast train?
A.27 7/8 m
B.77 7/9 m
C.27 8/9 m
D.27 7/9 m
Answer: D.27 7/9 m
Explanation: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5 = 250/9
= 27 7/9 m.
Answer: D
Question: A class average mark in an exam is 70. The average of students who scored below 60 is 50. The average of students who scored 60 or more is 75. If the total number of students in this class is 20, how many students scored below 60?
A.10
B.20
C.38
D.42
Answer: B.20
Explanation: Let n the number of students who scored below 60 and N the number of students who scored 60 or more. Xi the grades below 60 and Yi the grades 60 or above.
[sum(Xi) + sum(Yi)] / 20 = 70 : class average
sum(Xi) / n = 50 : average for less that 60
sum(Yi) / N = 75 : average for 60 or more
50n + 75N = 1400 : combine the above equations
n + N = 20 : total number of students
n = 4 and N = 16 : solve the above system
correct answer B
Question: In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?
A.5/21
B.5/14
C.9/14
D.16/21
Answer: A.5/21
Explanation: Explanation:
Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)
As remaining person can be any one among three couples left.
Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅
= (10 * 6)/252 = 5/21
ANSWER IS A
Question: It is currently 9:53 PM. What time was it in the morning exactly 149,061 minutes ago?
A.9:12
B.9:18
C.9:26
D.9:32
Answer: D.9:32
Explanation: Divide by 60 to convert 149,061 minutes to hours: 149,061/60 = 2,484 R21. That is 2,484 hours and 21 minutes. All of the answers are in the 9AM hour before :53, thus we can assume 2,484 previous must be 9:53 AM. 21 minutes before that is 9:32 AM. D
Question: Express of the following as a fraction: 0.6%
A.1/500
B.7/500
C.3/500
D.8/500
Answer: C.3/500
Explanation: 0.6 =6/1000 = 3/500
Answer is C.
Question: The ratio between the speeds of two trains is 7: 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is ?
A.83.5 km/hr
B.84.5 km/hr
C.86.5 km/hr
D.87.5 km/hr
Answer: D.87.5 km/hr
Explanation: Explanation:
Let the speeds of two trains be 7X and 8X km/hr.
8/X=400/4=>X=12.5Km/hr
So speed of first train is 12.5*7 = 87.5 km/hr
Option D
Question: Adding two non multiples of W always results in a multiple of W; which of the following must be the value of W ?
A.[A] two
B.[B] three
C.[C] five
D.[D] ten
Answer: A.[A] two
Explanation: NON- multiples of 2 would always be ODD and sum of two odd would be EVEN.
so irrespective of value of non-multiples, sum of two them would always be even and thus multiple of 2..
A
Question: The first three terms of an infinite sequence are 2, 7, and 22. After the first term, each consecutive term can be obtained by multiplying the previous term by 3 and then adding 1. What is the sum of the tens digit and the units digit of the fortythird term in the sequence?
A.2
B.3
C.6
D.4
Answer: D.4
Explanation: Following the rule of Infinite sequence we obtain the terms of the sequence as mentioned below
02,07,22,67, 202, 607, 1822, 5467...
Observe the last two digits of the sequence which have the cyclicity of4and the last two digits repeat in the order {02, 07, 22, 67}
Also 43rd Term =5*8 +3
i.e. 35th Terms will have same Last two digits as 3rd term of the sequence = 22
i.e. Sum of lat two digits of 35th Term = 2+2 = 4
D
Question: How many terminating zeroes Q does 200! have?
A. 40
B. 48
C. 49
D. 55
Answer: C. 49
Explanation: You have 40 multiples of 5, 8 of 25 and 1 of 125. This will give 49 zeros.C
Question: Evaluate ((5.68)2 – (4.32)2)/5.68- 4.32
A.8
B.9
C.10
D.11
Answer: C.10
Explanation: Given Expression = a2-b2/ a-b = (a+b) (a-b)/ a-b = (a+b)
(5.68)2 – (4.32)2/5.68- 4.32 = (5.68+ 4.32) = 10
ANSWER:C
Question: A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
A.22
B.23
C.24
D.26
Answer: D.26
Explanation: Explanation:
Let the number of hens be x and the number of cows be y.
Then, x + y = 48 .... (i)
and 2x + 4y = 140 x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
ANSWER IS D
Question: Skier SARAH completes a straight 300-meter downhill run in t seconds and at an average speed of (x + 10) meters per second. She then rides a chairlift back up the mountain the same distance at an average speed of (x - 8) meters per second. If the ride up the mountain took 135 seconds longer than her run down the mountain, what was her average speed, in meters per second, during her downhill run?
A. 10
B. 15
C. 20
D. 25
Answer: C. 20
Explanation: Backsolving is the preferred approach for this one
300/(x-8) - 300/(x+10) = 135
We are asked for the value of x+10
So we can start with C = X+10 = 20
So x = 10
300/2 - 300 / 20 = 135
Hence answer is C
Question: John is measuring a banner for the school play and needs to know how many inches are in 5 yards and 2 feet. Can you help him out?
A.235 inches.
B.204 inches.
C.220 inches.
D.206 inches.
Answer: B.204 inches.
Explanation: B
204 inches.
5 yards is the same as 15 feet(3 feet = 1 yard).15 feet +2 feet = 17 feet. There are 12 inches in each foot. So 17 feet x 12 = 204 inches.
Question: A train 150 m long running at 72 kmph crosses a platform in 25 sec. What is the length of the platform?
A.443 m
B.354 m
C.450 m
D.350 m
Answer: D.350 m
Explanation: D
350
D = 72 * 5/18 = 25 = 500 – 150 = 350
Question: The diagonals of a rhombus are 13 cm and 20 cm. Find its area?
A.329
B.288
C.150
D.130
Answer: D.130
Explanation: 1/2 * 13 * 20 = 130
Answer: D
Question: Find the area of trapezium whose parallel sides are 10 cm and 18 cm long, and the distance between them is 10 cm.
A.140 cm2
B.185 cm2
C.185 cm2
D.185 cm2
Answer: A.140 cm2
Explanation: Explanation:
Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (10 + 18) * (10) = 140 cm2
Answer: Option A
Question: On a ferry, there are 32 cars and 8 trucks. The cars have an average mass of 900 kg and the trucks have an average mass of 3000 kg. What is the average mass of all 40 vehicles on the ferry?
A.1200
B.1240
C.1280
D.1320
Answer: D.1320
Explanation: The total mass of the vehicles is 32*900+8*3000=52800
The average mass is 52800/40=1320
The answer is D.