RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The jogging track in a sports complex is 726 m in circumference. Suresh and his wife start from the same point and walk in opposite direction at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in:
A.5.5 min.
B.6 min.
C.4.9 min.
D.5.28 min.
Answer: D.5.28 min.
Explanation: Let both of them meet after T min
4500 m are covered by Suresh in 60 m.
In T min he will cover 4500T/60
Likewise, In T min Suresh's wife will cover 3750T/60
Given,
(4500T/60)+(3750T/60)=726
T = 5.28 minutes
Answer : D
Question: Rs.100 amounts to Rs.320 in 4 years at simple interest. If the interest is increased by 3%, it would amount to how much?
A.246
B.650
C.110
D.240
Answer: C.110
Explanation: (100*4*3)/100=12
100+ 12 = 112
Answer: C
Question: A circular ground whose diameter is 40 metres, has a garden of area 1100m^2around it. What is the wide of the path of the garden ?
A.8.07
B.7.07
C.6.07
D.7.0
Answer: B.7.07
Explanation: Req. area = Ï€[(20)2 â€“ (r)2]
= 22â„7 Ã— (400- r^2)[since a2 - b2 = (a + b)(a - b)]
ie)22/7(400-r^2)=1100 , ie) r^2=50, r=7.07m
Answer B
Question: what is rate of interest if principal.amount be 400,simple interest 140 and time 2year.
A.10
B.17.5
C.25
D.12
Answer: B.17.5
Explanation: s.i=(p*r*t)/100
140=800r/100
r=140/8=17.5%
answer B
Question: A prize of $400 is to be distributed among 20 winners, each of whom must be awarded at least $20. If 2/5 of the prize will be distributed to 3/5 of the winners, what is the greatest possible individual award?
A.$100
B.$220
C.$280
D.$300
Answer: A.$100
Explanation: Total value of the prize =$400
Number of people = 20
2/5 of 400 (=$160) should be distributed among 3/5 of 20 (=12 people ) with each getting $20 each. Remaining money = 400-160 = $240. Now in order to 'maximize' 1 prize, we need to minimise the others and we have been given that each should get $20. Thus, minimising the remaining 7 people (=20-12-1. '-1' to exclude 1 that needs to be maximised) = 7*20=140.
Thus the maximum award can be = 240-140 = $100, hence A is the correct answer.
Question: For an integer n greater than 1, n* denotes the product of all the integers from 1 to n inclusive. How many prime numbers are there between 6*+3 and 6*+6, inclusive ?
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: Given that n* denotes the product of all the integers from 1 to n, inclusive so, 6* + 3 = 6! + 3 and 6* + 6 = 6! + 6.
Now, notice that we can factor out 3 our of 6! + 3 so it cannot be a prime number, we can factor out 4 our of 6! + 4 so it cannot be a prime number, ... The same way for all numbers between 6! + 3 and 6! +6, inclusive. Which means that there are no primes in this range.
Answer: A.
Question: Two trains, each 120 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is?
A.72 km/hr
B.17 km/hr
C.60 km/hr
D.77 km/hr
Answer: A.72 km/hr
Explanation: Let the speed of the slower train be x m/sec.
Then, speed of the train = 2x m/sec.
Relative speed = ( x + 2x) = 3x m/sec.
(120 + 120)/8 = 3x => x = 10.
So, speed of the faster train = 20 = 20 * 18/5
= 72 km/hr.
Answer:A
Question: Three unbiased coins are tossed, what is the probability of geƫng at least 2 tails ?
A.1/3
B.1/6
C.1/2
D.1/8
Answer: C.1/2
Explanation: Explanation:
Total cases are = 2*2*2 = 8, which are as follows
[TTT, HHH, TTH, THT, HTT, THH, HTH, HHT]
Favoured cases are = [TTH, THT, HTT, TTT] = 4
So required probability = 4/8 = 1/2
Answer: C
Question: In a neighborhood having 90 households, 11 did not have either a car or a bike. If 20 households had a both a car and a bike and 44 had a car, how many had bike only?
A.30
B.35
C.20
D.18
Answer: B.35
Explanation: {Total}={Car}+{Bike}-{Both}+{Neither} --> 90=44+{Bike}-20+11 --> {Bike}=55 --> # those who have bike only is {Bike}-{Both}=55-20=35.
Answer: B.
Question: Find the sum of the local value and absolute value of 4 in 564823
A.4004
B.8000
C.16000
D.12000
Answer: A.4004
Explanation: Explanation:
Place value = Local value
Face value = Absolute value
The place value of 4 in 564823 is 4 x 1000 = 4000
The face value of 4 in 564823 is nothing but 4.
=> 4000 + 4 = 4004
Answer: Option A
Question: The length of the bridge, which a train 180 meters long and travelling at 48 km/hr can cross in 70 seconds, is:
A.245
B.276
C.987
D.168
Answer: A.245
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.
Answer: A
Question: When positive integer m is divided by positive integer x, the reminder is 7 and when positive integer n is divided by positive integer y, the reminder is 11. Which of the following Q is a possible value for x + y?
I. 18
II. 19
III. 20
A.I only
B.II only
C.Q=III only
D.II and III only
Answer: C.Q=III only
Explanation: TIP FOR SUCH QUESTIONS:Make Algebraic Equation in the beginning to understand how to proceed further. Then Start thinking the possible values of variables asked about
i.e.When positive integer m is divided by positive integer x, the reminder is 7can be understood as
m = ax +7which means thevalue of x must be greater than 7as the remainder 7 is possible only when the Divisor is bigger than the Remainder 7
i.e. Min Value of x = 8
AND
i.e.When positive integer n is divided by positive integer y, the reminder is 11can be understood as
n = by +11which means thevalue of y must be greater than 11as the remainder 11 is possible only when the Divisor is bigger than the Remainder 11
i.e. Min Value of y = 12
i.e. Minimum Value of x+y = 8+12 = 20
Hence III only can be True
Answer: Option
C
Question: If x < 0 and 0 < y < 1, which of the following has the greatest value L?
A.x^2
B.(xy)^2
C.(x/y)^2
D.x^2/y
Answer: C.(x/y)^2
Explanation: Given, x < 0 and 0 < y < 1
Let, x = -2 and y = 1/2
A. x^2 = (-2)^2 =4
B. (xy)^2 = (-2*1/2)^2 =1
C. (x/y)^2 = {-2/(1/2)}^2 = (-4)^2 =16
D. x^2/y = (-2)^2 / (1/2) = 4*2 =8
E. x^2*y = (-2)^2*(1/2) =2
Answer: option C
Question: The current birth rate per thousand is 52, where as corresponding death rate is 11 per thousand. The net growth rate in terms of population increase in percent is given by?
A.4.1%
B.3.2%
C.3.9%
D.4%
Answer: A.4.1%
Explanation: Net growth on 1000 = 52-11 = 41
Net growth on 100 = 41*100/1000 = 4.1%
Answer is A
Question: There are 6 girls and 6 boys. If they are to be seated in a row, what is the probability that no two boys sit together?
A.A)2*6!6!/12!
B.B)6!5!/12!
C.C)6!6!/12!
D.D)6!/12!
Answer: A.A)2*6!6!/12!
Explanation: If girls are alternate, then only no 2 boys can be together.
So among 12 places, boys can be seated in 6 alternate places in 6! ways.
And girls can be seated in the remaining 6 places in 6! ways.
Therefore total number of ways = 6! * 6!
But there could be 2 such arrangements-->
1. When first place is filled by a girl
2. When first place is filled by a boy
Therefore total number of ways = 2*6! * 6!
Also total number of ways to fill 12 places = 12!
Hence probability =2∗6!6!/12!
Answer:A
Question: A fill pipe can fill 1/4 of cistern in 16 minutes. In how many minutes, it can fill 3/4 of the cistern?
A.24min
B.30min
C.48min
D.26min
Answer: C.48min
Explanation: Required time = 16*4*3/4 = 48 minutes
Answer is C
Question: Find the area of the quadrilateral of one of its diagonals is 20 cm and its off sets 9 cm and 6 cm?
A.188 cm2
B.150 cm2
C.168 cm2
D.198 cm2
Answer: B.150 cm2
Explanation: 1/2 * 20(9 + 6)
= 150 cm2
Answer: B
Question: Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 30% profit?
A.66.3
B.76.3
C.86.3
D.16.3
Answer: D.16.3
Explanation: Explanation:
C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.
S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819.
S.P. per kg = 819/50 = Rs. 16.38 = 16.30.
Answer: D
Question: Calculate the HCF of 16, 108, 220
A.3
B.5
C.4
D.1
Answer: C.4
Explanation: Explanation:
Lets solve this question by factorization method.
The factors of 16 are: 1, 2, 4, 8, 16
The factors of 108 are: 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108
The factors of 220 are: 1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110, 220
Then the greatest common factor is 4.
Answer: Option C
Question: Each of the 39 points is placed either inside or on the surface of a perfect sphere. If 72% or fewer of the points touch the surface, what is the maximum number of segments which, if connected from those points to form chords, could be the diameter of the sphere?
A.7
B.11
C.13
D.14
Answer: D.14
Explanation: Maximum number of points on the surface is 72%*39 = 28.08 ... or 28 since it has to be an integer
Now note that if two points form a diameter, they cannot be part of any other diameter.
So in the best case we can pair up the points
We have 28 points, so at best we can form 14 pairs (28).
So, answer is (D)
Question: Sum of the digits number is 8 and their product is 12. Find the difference between the digits?
A.4
B.5
C.3
D.7
Answer: A.4
Explanation: Explanation:
x + y = 8
xy = 12
(x â€“ y)2 = (x + y)2 â€“ 4xy
(x â€“ y)2 = 64 â€“ 48 => (x â€“ y) = 4
Answer:A
Question: The length of the bridge, which a train 120 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
A.328
B.279
C.255
D.288
Answer: C.255
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (120 + X)/30 = 25/2 ==> 2(120 + X) = 750 ==> X = 255 m.Answer: C
Question: Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively.
A.1394
B.1294
C.1194
D.1094
Answer: A.1394
Explanation: Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6.
Therefore, Required number = (L.C.M. of 20,25,35,40) – 6 =1394.
Answer is A.
Question: present ages of sameer and anand are in the ratio of 5:4 respectively. three years hence, the ratio of their ages will become 11:9 respectively . what anand's present age in years
A.27
B.24
C.40
D.32
Answer: B.24
Explanation: sameer and anand be 5x years and 4x years respectively
(5x+3)/(4x+3)=11/9
9(5x+3)= 11(4x+3), 45x+27=44x+33
45x-44x=33-27
x=6, therefore anand's present age : 4x=24 years
correct answer(B)
Question: Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 5 to 2 and the ratio of Indian to British stamps is 4 to 1, what is the ratio of US to British stamps?
A.5 : 1
B.10 : 5
C.15 : 2
D.20 : 2
Answer: D.20 : 2
Explanation: U/I = 5/2
I/B = 4/1
Since I is multiple of both 2 (as per first ratio) and 5 (as per second ratio) so let's assume that I = 10
i.e. Multiplying teh first ratio by 5 and second ration by 2 in each numerator and denominator
then, U : I : B = 20 : 8: 2
i.e. U : B = 20 : 2
Answer: Option D
Question: Two twins sisters Sita and Geeta were standing back to back and suddenly they started running in opposite directions for 2 km each. Then they turned left and ran for another 1.5 km.
What is the distance (in kilometers) between the the two twins when they stop?
A.5
B.7
C.9
D.11
Answer: A.5
Explanation: The distance between them is the hypotenuse of a right angle triangle with sides 3 km and 4 km.
hypotenuse = sqrt(3^2 + 4^2) = 5
The answer is A.
Question: A wheel rotates 10 times every minute and moves 10 cm during each rotation. How many metres does
the wheel move in one hour?
A.6 metre
B.60 metre
C.1500 metre
D.1200 metre
Answer: B.60 metre
Explanation: Expl : Number of times wheel moves in 1 hour = 10 * 60 = 600
:. Distance moves = (600 *10) cms = 6000 cms
In metres = 60 metre
Answer: B
Question: If x > y^3 > z^4, which of the following statements could be true?
I. x>y>z
II. x>z
III.y=z
A.III only
B.I,II only
C.II only
D.I only
Answer: B.I,II only
Explanation: Answer : B
Question: A local restaurant recently renovated its dining space, purchasing new tables and chairs to use in addition to the original tables and chairs. The new tables each seat six customers, while the original tables each seat four customers. Altogether, the restaurant now has 40 tables and is capable of seating 206 customers. How many more new tables than original tables does the restaurant have?
A.6
B.9
C.12
D.15
Answer: A.6
Explanation: If all the tables seated 4, the number of customers could be 4*40 = 160.
206-160 = 46, so 46/2 = 23 tables must be new tables seating 6 people.
The number of tables seating 4 people is 40-23 = 17.
The number of new tables is 23-17 = 6 more than the number of old tables.
The answer is A.
Question: what is the angle between the hands of a clock when time is 8:30?
A.65deg
B.75deg
C.45deg
D.15deg
Answer: B.75deg
Explanation: Angle between two hands =
30h - 11/2 m = 30*8 - 30*11/2 = 240 - 165 = 75deg
ANSWER:B
Question: If the price of an article went up by 20%, then by what percent should it be brought down to bring it back to its original price?
A.16 2/3%
B.20%
C.22 1/3%
D.15%
Answer: A.16 2/3%
Explanation: Let the price of the article be Rs. 100.
20% of 100 = 20.
New price = 100 + 20 = Rs. 120
Required percentage = (120 - 100)/120 * 100
= 20/120 * 100 = 50/3 = 16 2/3%.
ANSWER:A
Question: In a camp,there is a meal for 120 men or 200 children.If 160 children have taken the meal,how many men will be catered to with the remaining meal ?
A.20
B.24
C.40
D.50
Answer: B.24
Explanation: Solution
There is a metal for 200 children. 160 children have taken the meal.
Remaining meal is to be catered to 40 children.
Now, 200 children = 120 men
40 children =( 120/200x40)men= 24 men. Answer B
Question: Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?
A.Rs.1261
B.Rs.9261
C.Rs.9621
D.Rs.9162
Answer: B.Rs.9261
Explanation: A = 8000(21/20)3 = 9261
ANSWER:B
Question: If the perimeter and diagonal of a rectangle are 14 and 5 cms respectively, find its area.
A.12 cm2
B.16 cm2
C.20 cm2
D.24 cm
Answer: A.12 cm2
Explanation: In a rectangle,
(Perimeter)2/4=(diagonal)2+2×area
⇒ (14)2/4=5(2)+2×area
49 = 25 + 2 × area
∴ Area = 49−25/2=24/2=12cm2
Answer A
Question: The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 867 sq m, then what is the breadth of the rectangular plot?
A.19 m
B.17 m
C.10 m
D.12 m
Answer: B.17 m
Explanation: Answer: Option B
Explanation:
Let the breadth of the plot be b m.
Length of the plot = 3 b m
(3b)(b) = 867
3b2 = 867
b2 = 289 = 172 (b > 0)
b = 17 m.
Answer: Option B
Question: An empty fuel tank is filled with brand Z gasoline. When the tank is half empty, it is filled with brand Y gasoline. When the tank is half empty again, it is filled with brand Z gasoline. When the tank is half empty again, it is filled with brand Y gasoline. At this time, what percent Q of the gasoline in the tank is brand Z?
A.50%
B.40%
C.37.5%
D.331⁄3%
Answer: C.37.5%
Explanation: Work with fraction of brand Z in the tank.
1st step: brand Z is 1
2nd step: brand Z is 1/2
3rd step: brand Z is (1/2)*(1/2) + 1/2 = 3/4
4th step: brand Z is (1/2)*(3/4) Q= 3/8 = 37.5%
Answer (C)
Question: The age of father 4 years ago was four times the age of his son. Five years hence, father's age will be twice that of his son. The ratio of their present ages is:
A.41 : 17
B.42 : 17
C.44 : 19
D.44 : 17
Answer: D.44 : 17
Explanation: Let the ages of father and son 4 years ago be 4x and x years respectively.
Then, (4x + 4) + 5 = 2[(x + 4) + 5]
4x + 9 = 2x + 18
x = 4.5.
Required ratio = (4x + 4) : (x + 4) = 22 : 8.5 = 44 : 17.
Answer: Option D
Question: Mrs. Rodger got a weekly raise of $155. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.
A.$204
B.$231
C.$156
D.$155
Answer: D.$155
Explanation: Let the 1st paycheck be x (integer).
Mrs. Rodger got a weekly raise of $ 155.
So after completing the 1st week she will get $ (x+155).
Similarly after completing the 2nd week she will get $ (x + 155) + $ 155.
= $ (x + 155 + 155)
= $ (x + 310)
So in this way end of every week her salary will increase by $ 155.
D
Question: When 242 is divided by a certain divisor the remainder obtained is 12. When 698 is divided by the same divisor the remainder obtained is 16. However, when the sum of the two numbers 242 and 698 is divided by the divisor, the remainder obtained is 10. What is the value of the divisor?
A.11
B.18
C.13
D.23
Answer: B.18
Explanation: let that divisor be x
since remainder is 12 or 16 it means divisor is greater than 16.
now 242-12=230 =kx (k is an integer and 234 is divisble by x)
similarly 698-16=682 = lx (l is an integer and 689 is divisible by x)
adding both 698 and 242
= (230+682)+12+16
=x(k+l) + 28
when we divide this number by x then remainder will be equal to remainder of (28 divided by x) = 10 hence x = 28-10 = 18
hence B
Question: 10 women can complete a work in 5 days and 10 children take 10 days to complete the work. How many days will 5 women and 10 children take to complete the work?
A.4
B.5
C.7
D.8
Answer: B.5
Explanation: 1 women's 1 day work = 1/50
1 child's 1 day work = 1/100
(5 women + 10 children)'s 1 day work
= (5/50 + 10/100) = 1/5
5 women and 10 children will complete the work in 5 days.
B
Question: Molly is rolling a number cube with faces numbered 1 to 6 repeatedly. When she receives a 1, she will stop rolling the cube. What is the probability that Molly will roll the die less than 3 times before stopping?
A.11/180
B.125/216
C.25/216
D.11/216
Answer: D.11/216
Explanation: The probability that Molly will roll the die less than 4 times before stopping is the sum of the following:
The probability that Molly will roll the die once: P=1/6 (she gets 1 on the first roll);
The probability that Molly will roll the die twice: P=5/6*1/6 (not 1, 1);
P = 1/6 + 5/6*1/6 = 11/216.
Answer: D.
Question: Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together ?
A.120/11 min past 9
B.120/11 min past 8
C.120/11 min past 5
D.120/11 min past 3
Answer: B.120/11 min past 8
Explanation: In this type of problems the formulae is
x is replaced by the first interval of given time Here i.e 8
= min
Therefore the hands will be in the same straight line but not
together at min.past 8.
Answer: B
Question: The perimeter of one square is 48 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?
A.5 cm
B.13√2 cm
C.12 cm
D.6 cm
Answer: B.13√2 cm
Explanation: Explanation:
4a = 48 4a = 20
a = 12 a = 5
a^2 = 144 a^2 = 25
Combined area = a^2 = 169 => a = 13
d = 13√2 cm
Answer : B
Question: A man takes 5 hours 45 min in walking to a certain place and riding back. He would have gained 2 hours by riding both ways. The time he would take to walk both ways is
A.7 hrs 95 min
B.7 hrs 49 min
C.7 hrs 45 min
D.7 hrs 15 min
Answer: C.7 hrs 45 min
Explanation: Given that time taken for riding both ways will be 2 hours lesser than
the time needed for waking one way and riding back
From this, we can understand that
time needed for riding one way = time needed for waking one way - 2 hours
Given that time taken in walking one way and riding back = 5 hours 45 min
Hence The time he would take to walk both ways = 5 hours 45 min + 2 hours = 7 hours 45 min
In fact, you can do all these calculations mentally and save a lot of time
which will be a real benefit for you.
Answer:C
Question: An advertising agency finds that, of its 105 clients, 115 use Television, 110 use Radio and 130 use Magazines. Also, 85 use Television and Magazines, 75 use Television and Radio, 95 use Radio and Magazines. How many use all the three?
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: Total=105
Television=115
Radio=110
Magazine=130
All the three =105-115-110-130+85+75+95=5
ANSWER D
Question: In a certain year, the population of a certain town was 9000. If in the next year the population of males increases by 2% and that of the females by 8% and the total population increases to 9600, then what was the ratio of population of males and females in that given year?
A.4 : 5
B.5 : 4
C.2 : 7
D.Data inadequate
Answer: C.2 : 7
Explanation: Let the population of males = x; then the population of females = 9000 – x
Now, 2% of x + 8% of (9000 – x)
= (9600 – 9000 ) = 600
or 0.02x + 720 – 0.08x = 600
or 720 – 600 = 0.08x – 0.02x
or, 120 = 0.06x
x = 2000
Reqd ratio of population of males and females
2000/9000−2000=2000/7000=2:7
Answer C
Question: If the price of gasoline increases by 25% and Ron intends to spend only 15% more on gasoline, by how much percent should he reduce the quantity of gasoline that he buys?
A.6.66%
B.8%
C.10%
D.12%
Answer: B.8%
Explanation: Let price of original price of gasoline = 10$
and let original consumption of gasoline = 10
Amount spend on gasoline originally = 10*10 = 100$
the price of gasoline increases by 25% and Ron intends to spend only 15% more on gasoline
Increased price of gasoline = 12.5$
Now Ron intends to spend on gasoline =1.15*100 = 115$
Consumption of gasoline needs to be = 115/12.5
= 1150/125
= 46/5 = 9.2
Reduction in consumption of gasoline = 10-9.2 = .8
% reduction in consumption of gasoline = .8/10 * 100%
= 8%
Answer B
Question: P and Q started a business investing Rs. 48,000 and Rs. 24,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively?
A.2:6
B.2:3
C.2:1
D.17:9
Answer: C.2:1
Explanation: P:Q = 48000 : 24000
= 2:1.
Answer:C
Question: On a trip covering 850 km, a bicyclist travels the first 400 km at 20 km per hour and the remainder of the distance at 15 km per hour. What is the average speed, in km per hour, for the entire trip?
A.16.0
B.16.5
C.17.0
D.17.5
Answer: C.17.0
Explanation: time 1 = 400 / 20 = 20 hours
time 2 = 450 / 15 = 30 hours
total time = 50 hours
average speed = 850 / 50 = 17 km/hr
The answer is C.
Question: The average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
A.76 kg
B.76.5 kg
C.85 kg
D.90 kg
Answer: C.85 kg
Explanation: Sol.
Total weight increased
= (8 × 2.5) kg
= 20 kg.
Weight of new person
= (65 + 20) kg
= 85 kg.
Answer C
Question: A ladder 25m long reaches a window of building 20m above the ground. Then the distance of the foot of the ladder from the building is?
A.35m
B.45m
C.30m
D.15m
Answer: D.15m
Explanation: let it forms a right angled triangle and follow c^2=a^2+b^2
then 25^2=20^2+b^2
b^2=625-400
b=15
ANSWER:D
Question: Roja and Pooja start moving in the opposite directions from a pole. They are moving at the speeds of 2 km/hr and 3 km/hr respectively. After 4 hours what will be the distance between them?
A.11
B.20
C.77
D.26
Answer: B.20
Explanation: Distance = Relative Speed * Time
= (2 + 3) * 4 = 20 km
[ They are travelling in the opposite direction, relative speed = sum of the speeds].
Answer: B
Question: A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 588, what was his profit?
A.s. 64
B.s. 69
C.s.108
D.s.75
Answer: C.s.108
Explanation: C.P. = Rs. (100/122.5)x588
= Rs. (1000/1225)x588
= Rs. 480
Profit = Rs. (588 - 480) = Rs. 108.
Answer:C
Question: A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 29.16, the number of the member is the group is:
A.57
B.54
C.77
D.87
Answer: B.54
Explanation: Money collected =(29.16 x 100) paise = 29.16 paise
numbers of members = 2916 squareroot = 54
Answer B
Question: If 15% of 30% of 50% of a number is 90, then what is the number?
A.4000
B.3050
C.4400
D.4500
Answer: A.4000
Explanation: Let the number be a
Given, 15/100 * 30/100 * 50/100 * a = 90
=> 3/20 * 3/10 * 1/2 * a = 90
=> a = 10 * 20 * 10 * 2 = 4000.
ANSWER:A
Question: There are three places P, Q and R such that 3 roads connects P and Q and 4 roads connects Q and R. In how many ways can one travel from P to R?
A.32
B.75
C.12
D.51
Answer: C.12
Explanation: Number of ways in which one can travel from P to R
=3×4=12=3×4=12
Ans: C