RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Six years back, a father was 42 years older than his son. At present the father is 4 times as old as the son. How old will the son be three years from now?
A.20 years
B.19 years
C.18 years
D.17 years
Answer: D.17 years
Explanation: Using linear equations to convert the word problem:
** F = fathers current ageS = sons current age
#1 Six years back, a father was 42 years older than his son: F-6 = 42 + (S - 6)
#2 At present the father is 4 times as old as the son: F = 4*S
How old will the son be three years from now?: S + 3 = ?
With two variables and two linear equations we are able to solve the problem:
(S*4) - 6 = 42 +S -6
3S=42
S = 14
S + 3 = 14 + 3 = 17
Answer: D
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1904?
A.1700
B.2777
C.2889
D.27670
Answer: A.1700
Explanation: 1904 = P [1 + (5*12/5)/100]
P= 1700.Answer:A
Question: A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 340 m long?
A.56 sec
B.42 sec
C.45 sec
D.48 sec
Answer: A.56 sec
Explanation: Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 340 = 700 m
Required time = 700 * 2/25 = 56 sec
ANSWER:A
Question: Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he
A. broke even
B. lost 4 cents
C. gained 4 cents
D. lost 10 cents
Answer: A. broke even
Explanation: 20 % profit on $ 1.20
= $ 20/100 × 1.20
= $ 0.20 × 1.20
= $ 0.24
Similarly, 20 % loss on $ 1.20
= $ 20/100 × 1.20
= $ 0.20 × 1.20
= $ 0.24
Therefore, in one pipe his profit is $ 0.24 and in the other pipe his loss is $ 0.24.
Since both profit and loss amount is same so, it’s broke even.
The answer is (A)
Question: If 5 (A's capital) = 7 (B's capital) = 9 (C's capital). Then the ratio of their capitals is?
A.63:55:35
B.63:45:38
C.62:45:35
D.63:45:35
Answer: D.63:45:35
Explanation: 5A = 7B = 9C
A:B:C = 1/5:1/7:1/9
= 63:45:35
Answer: D
Question: At a dinner party, 7 people are to be seated around a circular table. Two seating arrangement are considered different only when the positions of the people are different relative to each other. What is the total number of different possible seating arrangements for the group?
A.5
B.10
C.720
D.32
Answer: C.720
Explanation: Has to be C.
Simple formula: There are (n - 1)! ways to arrange n distinct objects in a circle
hence (7-1)! = 6!= 720
Question: Find: S.l on Rs 68000 at 16 2/3%per annum for 9 months
A.6500
B.7500
C.8500
D.9500
Answer: C.8500
Explanation: Explanation:
P = 68000, R =50/3% & T=9 months (3/4 years)
S.I=(68000 *50/3 * 3/4)/100=Rs.8500
ANSWER IS C
Question: If four coins are tossed, the probability of getting two heads and two tails is ?
A.3/8
B.3/5
C.3/2
D.3/1
Answer: A.3/8
Explanation: Since four coins are tossed, sample space = 24
Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = 6/24 = 3/8
Answer:A
Question: A consignment of 20 picture tubes contains 5 defectives. Two tubes are selected one after the other at random. The probability that both are defective assuming that the first tube is not replaced before drawing
the second, would be:
A.1/16
B.1/19
C.1/4
D.1/3
Answer: B.1/19
Explanation: Probability of drawing a defective tube in first draw is 5/20
Probability of drawing a defective tube in second draw (without replacing first tube) is 4/19.
Therefore probability of getting both defective is = (5/20)*(4/19) = 1/19
ANSWER:B
Question: A grocer has 400 pounds of coffee in stock, 20 percent of which is decaffeinated. If the grocer buys another 100 pounds of coffee of which 50 percent is decaffeinated, what percent, by weight, of the grocer’s stock of coffee is decaffeinated?
A.26%
B.30%
C.32%
D.34%
Answer: A.26%
Explanation: 1. 20% of 400=80 pounds of decaffeinated coffee
2. 50% of 100=50 pounds of decaffeinated coffee
3. Wt have 130 pounds of decaffeinated out of 500 pounds, that means 130/500*100%=26%. The correct answer is A.
Question: A sum of money becomes 7/6 of itself in 3 years at a certain rate of simple interest. The rate per annum is?
A.5 5/9 %
B.5 5/6 %
C.5 8/9 %
D.5 1/9 %
Answer: A.5 5/9 %
Explanation: Let sum = x. Then, amount = 7x/6
S.I. = 7x/6 - x = x/6; Time = 3 years.
Rate = (100 * x) / (x * 6 * 3) = 5 5/9 %.
Answer: A
Question: By selling 12 pencils for a rupee a man loses 12%. How many for a rupee should he sell in order to gain 18%?
A.12
B.9
C.10
D.89
Answer: A.12
Explanation: 88% --- 12
112% --- ?
88/112 * 12 = 9
Answer: A
Question: On a certain island, 5% of the 10000 inhabitants are one-legged and half of the others go barefooted. What is the least number of Shoes needed in the island?
A.9000
B.10000
C.9500
D.9700
Answer: B.10000
Explanation: one-legged =5% of 10000=500
remaining=10000-500=9500
barefooted=9500/2=4750
remaining people= 9500-4750=4750
hence required number of shoes= 4750*2+500*1=10000
ANSWER:B
Question: In what ratio should a variety of rice costing Rs. 6 per kg be mixed with another variety of rice costing Rs. 8.75 per kg to obtain a mixture costing Rs. 7.50 per kg?
A.5/6
B.5/9
C.5/0
D.5/3
Answer: A.5/6
Explanation: Explanation:
Let us say the ratio of the quantities of cheaper and dearer varieties = x : y
By the rule of allegation, x/y = (87.5 - 7.50) / (7.50 - 6) = 5/6
Answer: Option A
Question: If the average (arithmetic mean) of a list of numbers is 12 and the standard deviation of that list of numbers is 1.3, then which of the following numbers is more than two standard deviations from the mean?
I. 14.7
II. 9.2
III. 9.7
A.I only
B.I and II only
C.II only
D.III only
Answer: B.I and II only
Explanation: Mean = 12
SD = 1.3
2 SD above mean = 12+2*1.3 = 14.6
2 SD below mean = 12-2*1.3 = 9.4
only 9.7 lies in the range of 2SD from mean
Answer: Option B
Question: Find the product of the localvalue and absolutevalue of 1 in 20168?
A.100
B.110
C.151
D.120
Answer: A.100
Explanation: Local value of 1 = 1 x 100 = 100
Place value of 1 = 1
There fore = 1 x 100 = 100
A
Question: On multiplying a number B by 153, the result obtained was 102325. However, it is found that both the 2's are wrong. Find the correct result.
A.104345
B.107375
C.108385
D.109395
Answer: D.109395
Explanation: The only thing you actually know about the correct number B is that it is divisible by 153 and has 5 as a factor.
You should immediately try to find the factors of 153 and look for them in the options.
153 = 9*17
Divisibility by 9 is easy to check. Only (D) satisfies.
Question: P , Q, R enter into a partnership & their share are in the ratio 1/2 : 1/3 : 1/4 , after two months , P withdraws half of the capitals & after 10 months , a profit of Rs 336 is divided among them . What is R's share?
A.96
B.120
C.134
D.144
Answer: A.96
Explanation: Explanation :
The ratio of their initial investment = 1/2 : 1/3 : 1/4
= 6 : 4: 3
Let's take the initial investment of P, Q and R as 6x, 4x and 3x respectively
A:B:C = (6x * 2 + 3x * 10) : 4x*12 : 3x*12
= (12+30) : 4*12 : 3*12
=(4+10) : 4*4 : 12
= 14 : 16 : 12
= 7 : 8 : 6
R's share = 336 * (6/21) = 96. Answer : Option A
Question: The income derived from a Rs. 100, 13% stock at Rs. 105,is :
A.Rs. 5
B.Rs. 8
C.Rs. 13
D.Rs. 18
Answer: C.Rs. 13
Explanation: Solution
Income on Rs. 100 stock = Rs. 13
Answer C
Question: If y = 2 + 2K and y≠0y≠0, then 5/y + 3/y + 1/y + 1/y = ?
A.1/(8+8k)
B.5/(1+k)
C.1/(8+k)
D.4/(8+k)
Answer: B.5/(1+k)
Explanation: 5/Y + 3/Y + 1/Y + 1/Y
= 10/Y
= 10/(2 + 2K)
= 5/(1 + K)
ANSWER:B
Question: If there are 6 men and 55 tasks , how many tasks will be left undone if they perform equal number of tasks?
A.5
B.2
C.3
D.1
Answer: D.1
Explanation: There are 6 men
There are 55 tasks
If they perform equal number of tasks, divide 55 by 6 and the remainder will be the number of tasks left undone
55 = (6 x 9) + 1
So 1 task is left undone
ANSWER D
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 900 m long?
A.266 Sec
B.210 Sec
C.776 Sec
D.166 Sec
Answer: B.210 Sec
Explanation: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 2100 m
T = D/S
T = 2100/10
T = 210 Sec
Answer: B
Question: The expression (a+b+c)10 is expanded and simplified. How many terms are in the resulting
expression?
A.30
B.44
C.55
D.66
Answer: D.66
Explanation: (a+b+c)10 = [(a+b)+c]10. Let x = a+b. We see that (x+c)10 = x10+10x9c+
+ c10 has 11 distinct terms. Also, the ith term of this expansion has 11 - i distinct terms
(since x10-i = (a + b)10-i has 11 - i distinct terms). Hence there are 11 + 10 +...+ 1 = 66
terms in this expansion.
correct answer D
Question: How many integer values Q are there for x such that 1 < 3x + 5 < 17?
A.Two
B.Three
C.Four
D.Five
Answer: D.Five
Explanation: 1 < 3x + 5 < 17
=> -4 < 3x < 12
=> -4/3 < x < 4
x can take integer values Q=-1,0 , 1 , 2 , 3
Answer D
Question: In a 500 m race, the ratio of speeds of two runners P and Q is 3:5. P has a start of 200 m then the distance between P and Q at the finish of the race is:
A.Both reach at the same time
B.P wins by 100 m
C.Q wins by 50 m
D.Q wins by 100 m
Answer: A.Both reach at the same time
Explanation: Explanation :
When P starts running for 300 m and Q for 500 m then, the ratio of speeds of P and Q is 3 : 5.
According to question P has already covered 200 m when Q is starting at starting point and Q needs to cove 300 m more mean while P covers this 300 m when Q can cover 500 m. So, both P and Q will reach the finishing point at the same time.
Thus, Both reach at the same time.
Answer : A
Question: Andy solves problems 75 to 125 inclusive in a Math exercise. How many problems does he solve?
A.53
B.52
C.51
D.50
Answer: C.51
Explanation: 125-75+1= 51
'C' is the answer
Question: 0,1,2.9,5.61,9.05,?
A.11.15
B.12.15
C.13.15
D.14.15
Answer: C.13.15
Explanation: The series is 0, 1, 2.9, 5.61, 9.05, ...
Fisrt oder differences are 1, 1.9, 2.71, 3.44, ...
Second order differences are 0.9, 0.81, 0.73, ...
Note that the second order differences are powers of 0.9 (0.9, 0.81, 0.729, ...), rounded off to two decimal digits. So next term in second order difference is 0.9^4 = 0.6561 = 0.66. Then, the next term in first order difference is 3.44+0.66 = 4.1. So, the term in the series is 9.05+4.1 = 13.15
ANSWER:C
Question: There are 6 boxes numbered 1, 2,…,.6. Each box is to be filled up either with a red or a green ball in such a way that at least 1 box contains a green ball and the boxes containing green balls are consecutively numbered. The total number of ways in which this can be done is
A.21
B.52
C.45
D.63
Answer: A.21
Explanation: List down possibilities: From only 1 box all the way to all 6
If only one of the boxes has a green ball, it can be any of the 6 boxes. So, we have 6 possibilities.
If two of the boxes have green balls and then there are 5 consecutive sets of 2 boxes. 12, 23, 34, 45, 56.
If 3 of the boxes have green balls, there are 4 possibilities: 123, 234, 345, 456.
If 4 boxes have green balls, there are 3 possibilities: 1234, 2345, 3456.
If 5 boxes have green balls, there are 2 possibilities: 12345, 23456.
If all 6 boxes have green balls, there is just 1 possibility.
Total number of possibilities = 6 + 5 + 4 + 3 + 2 + 1 = 21.
Ans: A
Question: How long does a train 110 m long traveling at 90 kmph takes to cross a bridge of 170 m in length?
A.sec
B.sec
C.sec
D.sec
Answer: D.sec
Explanation: D = 110 + 170 = 280 m
S = 90 * 5/18 = 50/2
T = 280 * 2/50= 11.2 sec
Answer: D
Question: A certain NYC taxi driver has decided to start charging a rate of r cents per person per mile. How much, in dollars, would it cost 6 people to travel x miles if he decides to give them a 50% discount?
A.3xr/100
B.3x/200r
C.3r/200x
D.3xr/200
Answer: A.3xr/100
Explanation: 6xr/2 is in cents - 6xr/200 dollars = 3xr/100 dollars
Answer : A
Question: In Township K each property is taxed at 8 percent of its assessed value. If the assessed value of a property in Township K is increased from $20,000 to $24,000, by how much will the property tax increase?
A.$32
B.$50
C.$320
D.$400
Answer: C.$320
Explanation: Property tax as a percentage of its assessed value = 8%
Increase in assessed value of the property = 24000 - 20000 = 4,000 $
Increase in property tax = (8/100)* 4000 = 320 $
Answer C
Question: A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
A.100
B.110
C.120
D.130
Answer: C.120
Explanation: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 6 = 120 m.
Answer: Option C
Question: A fruit vendor purchased 20 dozens of apples at $15 per dozen. But one-fourth of the apples were rotten and had to be thrown away. He sold two-third of the remaining apples at a$22.50 per dozen. At what price per dozen should he sell the remaining apples to make neither a profit nor a loss?
A.$17
B.$14
C.$15
D.$18
Answer: C.$15
Explanation: C
$15
CP of 20 dozen of apples = 15 * 20 = $300
Number of apples which are rotten = 1/4 * 20 = 5 dozen.
SP of two-third of remaining apples = (2/3 * 15) * 22.5 = $225
SP of remaining 5 dozens of apples to make no profit and no loss =(300 - 225) = $75.
SP of 1 dozen apples = 75/5 = $15.
Question: A person crosses a 1080 m long street in 10 minutes. What is his speed in km per hour?
A.4.1
B.6.4
C.4.8
D.5.4
Answer: B.6.4
Explanation: Speed = 1080/(10x60) m/sec
= 1.8 m/sec.
Converting m/sec to km/hr =1.8 x(18/5) km/hr
= 6.4 km/hr.
ANSWER :B
Question: If nn is a positive integer and (n+1)(n+3)(n+1)(n+3) is odd, then (n+2)(n+4)(n+2)(n+4) must be a multiple of which one of the following?
A.2
B.4
C.5
D.8
Answer: D.8
Explanation: (n+1)(n+3)(n+1)(n+3) is odd only when both (n+1)(n+1) and (n+3)(n+3) are odd. This is possible only when nn is even.
Hence, n=2mn=2m, where mm is a positive integer. Then,
(n+2)(n+4)=(2m+2)(2m+4)=2(m+1)2(m+2)=4(m+1)(m+2)(n+2)(n+4)=(2m+2)(2m+4)=2(m+1)2(m+2)=4(m+1)(m+2)
=4 * (product of two consecutive positive integers, one which must be even)=4 * (product of two consecutive positive integers, one which must be even) =4 * (an even number), and this equals a number that is at least a multiple of 8=4 * (an even number), and this equals a number that is at least a multiple of 8
Hence, the answer is (D).
Question: The ratio between the length and the breadth of a rectangular park is 1 : 2. If a man cycling along the boundary of the park at the speed of 6 km/hr completes one round in 6 min, then the area of the park (in sq. m) is?
A.600m
B.6000 m
C.20000 m
D.100 m
Answer: C.20000 m
Explanation: Perimeter = Distance covered in 6 min. = (6000 x 6)/60 m = 600 m.
Let length = 1x metres and breadth = 2x metres.
Then, 2(1x + 2x) = 600 or x = 100.
Length = 100 m and Breadth = 200 m.
Area = (100 x 200) m2 = 20000 m
C
Question: A standard-sized cigarette can be rolled out of 6 standard-sized cigarette butts. How many cigarettes can be made and smoked from 36 butts?
A.2
B.3
C.5
D.7
Answer: D.7
Explanation: D
No, 6 is not the answer! It is not correct, because after the 6 cigarettes have been smoked there will again be 6 butts which can be made into another cigarette.
The answer is 7
Question: A certain galaxy is known to comprise approximately 2x 10^11 stars. Of every 50 million of these stars, one is larger in mass than our sun. Approximately how many stars in this galaxy are larger than the sun?
A.800
B.1,250
C.8,000
D.4,000
Answer: D.4,000
Explanation: 2*10^11
50 mln = 5*10^7
we divide 10^11 by 10^7 and we get (10^4)*2 = 20,000 and divide by 5. the result is 4,000 (c)
D
Question: 3 singers will pick a song among a list of 3 songs. What is the probability that exactly one singer will pick a different song?
A.3!/3^3
B.1/3^3
C.3/3!
D.3/3^3
Answer: A.3!/3^3
Explanation: Each singer out of 3 has 3 options, hence total # of outcomes is 3^3;
Favorable outcomes will be 3!, which is # of ways to assign 3 different song to 3 singers.
P=favorable/total=3!/3^3
Answer: A.
Question: If in a certain code "RANGE" is coded as 12345 and "RANDOM" is coded as 123678. Then the code for the word
"ROD" would be
A.156
B.174
C.176
D.180
Answer: C.176
Explanation: R-1
O-7
D-6
so for mango the code is 176
ANSWER:C
Question: x and y are positive integers of J. If 1/x + 1/y < 2, which of the following must be true?
A. x + y > 4
B. xy>1
C. x/y + y/x < 1
D. (x - y)^2 > 0
Answer: B. xy>1
Explanation: Answer is B:
1/X + 1/Y < 2
The maximum value of 1/X is 1 because if X equals any other number greater than one it will be a fraction. The same is true with 1/Y.
So 1/X and 1/Y will always be less than 2 as long as both X and Y are not both equal to one at the same time.
Another way of putting it is:
X*Y>1.B
Question: Working alone at its constant rate, pump U pumped out ¼ of the water in a tank in 2 hours. Then pumps V and W started working and the three pumps, working simultaneously at their respective constant rates, pumped out the rest of the water in 3 hours. If pump V, working alone at its constant rate, would have taken 18 hours to pump out the rest of the water, how many hours would it have taken pump W, working alone at its constant rate, to pump out all of the water that was pumped out of the tank?
A.6
B.12
C.15
D.18
Answer: B.12
Explanation: Rate of pump U = 1/8
3 hours are required to pump out the remaining (3/4)ths of tank --> 1 hr to pump out 1/4
Rate of U + Rate of V + Rate of W = 1/4
Rate of V + Rate of W = 1/4 - 1/8 = 1/8
V takes 18 hours to pump out the remaining (3/4)ths of tank --> 6 hrs per (1/4)ths --> 24 hrs to pump out fully.
Rate of V = 1/24
1/24 + Rate of W = 1/8
Rate of W = 1/8 - 1/24 = 1/12
Time required to pump out all the water by W = 12 hrs
Answer: B
Question: A tourist does not have to pay tax on the first $600 of goods he purchases in Country B, but does have to pay a 7 percent tax on the portion of the total value that is in excess of $600. What tax must be paid by a tourist if he buys goods with a total value of $1720?
A.$54.00
B.$78.40
C.$90.00
D.$100.80
Answer: B.$78.40
Explanation: Correct Answer: B
The tourist must pay tax on $1720 - $600 = $1120. Thus, the amount of tax he has to pay is 0.07 ($1120) = $78.40. The correct answer is B.
Question: The average age of an adult class is 40years. 12new students with an avg age of 32years join the class. Therefore decreasing the average by 4year. Find what was theoriginal strength of class?
A.8
B.12
C.15
D.17
Answer: B.12
Explanation: Let original strength = y
Then , 40y + 12 x 32 = ( y + 12) x 36
⇒ 40y + 384 = 36y + 432
⇒ 4y = 48
∴ y = 12
B
Question: X is three times as fast as Y and working together, they can complete a work in 20 days. In how many days can Y alone complete the work?
A.11 days
B.80 days
C.13 days
D.15 days
Answer: B.80 days
Explanation: X = 3Y
X + Y = 3Y + Y = 4Y
These 4Y people together can do the work in 20 days, which means Y can alone do the work in 4*20 = 80 days.
Answer : B
Question: Find the area of circle whose radius is 9m?
A.138
B.154
C.254.6
D.280
Answer: C.254.6
Explanation: 22/7 * 9 * 9
= 254.6
Answer:C
Question: A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 63, what is the total amount?
A.115
B.273
C.117
D.118
Answer: B.273
Explanation: x:y:z = 100:45:50
20:9:10
9 --- 63
39 --- ? => 273
ANSWER:B
Question: The salaries of A, B and C are of ratio 2:3:5. If the increments of 15%, 10% and 20% are done to their respective salaries, then find the new ratio of their salaries
A.20:33:60
B.21:33:60
C.22:33:60
D.23:33:60
Answer: D.23:33:60
Explanation: Explanation:
Let A salary be 2k
B salary be 3k and C salary be 5k
A's new salary = 115/100∗2k=23/10k
B's new salary = 110/100∗3k=33/10k
C's new salary = 120/100∗5k=6k
New ratio = 23k/10: 33k/10: 6k=23:33:60
Option D
Question: When an amount was distributed among 14 boys, each of them got rs 80 more than the amount received by each boy when the same amount is distributed equally among 18 boys. What was the amount?
A.5040
B.5020
C.5010
D.5030
Answer: A.5040
Explanation: Let the total amount be Rs. X the,
x/14 - x/18 = 80<=> 2x/126 = 80 <=> x/63 =63 x 80 = 5040.
Hence the total amount is 5040.
Answer is A.
Question: The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8500. If his salary for the month of May is Rs.6500, find his salary for the month of January?
A.3999
B.7867
C.4500
D.2789
Answer: C.4500
Explanation: Sum of the salaries of the person for the months of January, February, March and April = 4 * 8000 = 32000 ----(1)
Sum of the salaries of the person for the months of February, March, April and May = 4 * 8500 = 34000 ----(2)
(2)-(1) i.e. May - Jan = 2000
Salary of May is Rs.6500
Salary of January
= Rs.4500
Answer: C
Question: Two trains 121 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 55 kmph. In what time will they be completely clear of each other from the moment they meet?
A.7.19
B.7.17
C.7.62
D.7.15
Answer: C.7.62
Explanation: T = (121 + 165)/ (80 + 55) * 18/5
T = 7.62
Answer:C
Question: How many of the integers between 25 and 95 are even ?
A.35
B.90
C.11
D.10
Answer: A.35
Explanation: Number start between 25 to 95 is 70 numbers
half of them is even..which is 35
ANSWER:A
Question: A cistern can be filled by a tap in 3 hours while it can be emptied by another tap in 6 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
A.5.2 hrs
B.2.9 hrs
C.1.9 hrs
D.6 hrs
Answer: D.6 hrs
Explanation: Net part filled in 1 hour = (1/3 - 1/6) = 1/6
The cistern will be filled in 6/1 hrs i.e., 6 hrs.
Answer:D
Question: In a certain corporation, there are 300 male employees and 150 female employees. It is known that 20% of the male employees have advanced degrees and 40% of the females have advanced degrees. If one of the 450 employees is chosen at random, what is the probability this employee has an advanced degree or is female?
A.7/15
B.3/10
C.3/5
D.2/5
Answer: A.7/15
Explanation: P(female) = 150/450 = 1/3
P(male with advanced degree) = 0.2*300/450 = 60/450 = 2/15
The sum of the probabilities is 7/15
The answer is A.
Question: A car finishes a journey in nine hours at the speed of 80 km/hr. If the same distance is to be covered in six hours how much more speed does the car have to gain?
A.8 km/hr
B.40 km/hr
C.12 km/hr
D.16 km/hr
Answer: B.40 km/hr
Explanation: Distance covered by the car = 80 × 9 = 720 km
\ Speed = 720⁄6 = 120 km/hr
\ Speed gain = 120 – 80 = 40 km/hr
Answer B
Question: How many times does the minute hand and the second hand make a straight line?
A.2844
B.2832
C.2855
D.2381
Answer: B.2832
Explanation: make a straight line 59 x 2 times = 118 times (both aligned, and in opposition) and there are 24 hours in a day, so in a day minutes and second hand make a straight line 24 x 118 times = 2832 times.
so answer is B
Question: A used-book dealer sells paperback books at 3 times dealer's cost and hardback books at 4 times the dealer's cost. Last week, the dealer sold a total of 140 books, each of which had cost the dealer $1. If the gross profit (sales revenue minus the dealer's cost) on the sale of all of these books was $400, how many of the books sold were paperbacks?
A.20
B.40
C.60
D.80
Answer: A.20
Explanation: The dealer earns a profit of $2 per paperback and $3 per hardback.
If all 140 books were paperbacks, the dealer would earn a profit of $280.
Since the actual profit was $400, the dealer must have sold 120 hardbacks.
Then the number of paperbacks sold was 140-120 = 20.
The answer is A.
Question: In how many ways can a group of 4 men and 2 women be made out of a total of 7 men and 3 women?
A.100
B.102
C.105
D.107
Answer: C.105
Explanation: We need to select 4 men from 7 men and 2 women from 3 women.
Number of ways to do this
= 7C4 × 3C2
= 7C4 × 3C1 [∵ nCr = nC(n-r)]
= 105
Ans- C