RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A total of 550 players participated in a single tennis knock out tournament. What is the total number of matches played in the tournament? (Knockout means if a player loses, he is out of the tournament). No match ends in a tie.
A.511
B.512
C.549
D.255
Answer: C.549
Explanation: There are 550 players, only 1 person wins, 549 players lose. in order to lose, you must have lost a game.
549 games.
Ans- C
Question: O(x) represents the least odd integer greater than x, whereas o(x) represents the greatest odd integer less than x. Likewise, E(x) represents the least even integer greater than x, whereas e(x) represents the greatest even integer less than x. According to these definitions, the value of O(11.6) + E(–10.4) + o(–9.2) + e(9.5) is:
A.-3
B.-1
C.0
D.1
Answer: C.0
Explanation: O(11.6) + E(–10.4) + o(–9.2) + e(9.5) = 13 + (-10) + (-11) + 8 = 0
The answer is C.
Question: After M students took a test, the average score was 66%. If the test has 50 questions, what is the least number of questions that the next student has to get right to bring the average score up to 68%?
A.2M-34
B.M+34
C.0.66M+0.68
D.0.33M+34
Answer: B.M+34
Explanation: The total number of correct answers for M students is (0.66)*50*M=33*M
For an average of 68%: (total correct answers) / (M+1) = 0.68*50=34
Let x be the number of correct answers for the next student.
(x + 33M) / M+1 = 34
x + 33M= 34M+34
x = M + 34
The answer is B.
Question: Express a speed of 54 kmph in meters per second?
A.10 mps
B.18 mps
C.15 mps
D.17 mps
Answer: C.15 mps
Explanation: 54 * 5/18
= 15 mps
Answer:C
Question: A completes a work in 10 days and B complete the same work in 15 days. If both of them work together, then the number of days required to complete the work will be
A.6 days
B.9 days
C.10 days
D.12 days
Answer: A.6 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days
Therefore, here, the required number of days = 10 × 15/ 25= 6 days.
Answer : A
Question: A train 125 m long passes a man, running at 4 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
A.28
B.49
C.88
D.22
Answer: B.49
Explanation: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 4) km/hr. x - 4 = 45 ==> x
= 49 km/hr.Answer:B
Question: Four people each roll a four die once. Find the probability that at least two people will roll the same number ?
A.13/18
B.13/17
C.13/11
D.13/19
Answer: A.13/18
Explanation: The number of ways of rolling a dice where no two numbers probability that no one rolls the same number = 6 x 5 x 4 x 3
Now total possibilities of rolling a dice = 6464
The probability that a no one gets the same number = 6×5×4×364=5186×5×4×364=518
So the probability that at least two people gets same number = 1−5/18=13/18
Answer:A
Question: In a consumer survey, 80% of those surveyed liked at least one of three products: 1, 2, and 3. 50% of those asked liked product 1, 30% liked product 2, and 20% liked product 3. If 5% of the people in the survey liked all three of the products, what percentage of the survey participants liked more than one of the three products?
A.5
B.10
C.15
D.20
Answer: C.15
Explanation: pick 100 and x= all set with exactly two items
80=30+50+20 -(X)-10
X=10
so the answer is 10+5/100= 15%
answer C
Question: A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 153, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?
A.27
B.33
C.55
D.77
Answer: A.27
Explanation: Let f = pure fuji , g = pure gala and c - cross pollinated.
c = 10% of x where x is total trees.
c = .1x
also 3x/4 = f and c+f = 153 => .1x + 3/4x = 153 => x = 180
180 - 153 = pure gala = 27.
Answer A
Question: If the operation Ø is defined for all positive integers x and w by x Ø w = (2^x)/(2^w) then (3 Ø 1) Ø 1 = ?
A.2
B.4
C.8
D.16
Answer: C.8
Explanation: 3 Ø 1 = 2^3/2^1 = 4
4 Ø 1 = 2^4/2 = 8
The answer is C.
Question: A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% of bananas were rotten. Find the percentage of fruits in good condition.
A.87.8%
B.87.9%
C.37.8%
D.87.7%
Answer: A.87.8%
Explanation: otal number of fruits shopkeeper bought = 600 + 400 = 1000
Number of rotten oranges = 15% of 600
= 15/100 × 600
= 9000/100
= 90
Number of rotten bananas = 8% of 400
= 8/100 × 400
= 3200/100
= 32
Therefore, total number of rotten fruits = 90 + 32 = 122
Therefore Number of fruits in good condition = 1000 - 122 = 878
Therefore Percentage of fruits in good condition = (878/1000 × 100)%
= (87800/1000)%
= 87.8%
Answer:A
Question: A can run 1 km in 3 min. 10 sec. and B can cover the same distance in 3 min. 20 sec. By what distance can A beat B ?
A.50 m
B.18 m
C.96 m
D.23 m
Answer: A.50 m
Explanation: Soln:Clearly, A beats B by 10 sec.
Distance covered by B in 10 sec. = (1000 x 10 )/200m = 50 m.
Therefore A beats B by 50 metres.
Option A
Question: Michael earns $7.00 per hour for the first 40 hours he works per week, and twice this rate for overtime. If Michael earned $320 last week, how many hours did he work?
A.43
B.44
C.45
D.46
Answer: A.43
Explanation: $7*40 + $12*x = $320 --> x = 3 hours.
Total working hours = 40 + 3 = 43.
Answer: A.
Question: At a certain high school, a student’s popularity is determined by his or her locker number. Whoever has the locker number with the greatest number of distinct prime factors is the most popular student in the school. If Johanna, Jamal, Brianna, and Dyson get lockers with the numbers 300, 400, 150, and 420, respectively, who is the most popular student?
A.Johanna
B.Jamal
C.Brianna
D.Dyson
Answer: D.Dyson
Explanation: Distinct prime factors of 300 (Johanna) : 3, 2 5
Distinct prime factors of 400 (Jamal): 2 and 5.
Distinct prime factors of 150 (Brianna): 2,3, and 5
Distinct prime factors of 420 (Dyson): 2,3,5 and 7.
So most popular student - Dyson
Answer D
Question: The distance light travels in one year is approximately 5,870,000,000,000 miles. Find the distance light travels in 100 years?
A.587 × 108 miles
B.587 × 10-12 miles
C.587 × 1010 miles
D.587 × 10-10 miles
Answer: B.587 × 10-12 miles
Explanation: The distance of the light travels in 100 years is:
5,870,000,000,000 × 100 miles.
= 587,000,000,000,000 miles.
= 587 × 1012 miles.
Answer is B.
Question: Jane makes toy bears. When she works with an assistant, she makes 80 percent more bears per week and works 10 percent fewer hours each week. Having an assistant increases Jane’s output of toy bears per hour by what percent?
A.20%
B.80%
C.100%
D.180%
Answer: C.100%
Explanation: Let's assume just Jane 40 bears per 40/hrs a week, so that is 1 bear/hr. With an assistant she makes 72 bears per 36 hours a week or 2 bears/hr ([40 bears * 1.8] / [40 hrs * .90]).
[(2 - 1)/1] * 100% = 100%
ANSWER:C
Question: What is the rate percent when the simple interest on Rs.900 amount to Rs.160 in 4 Years?
A.5%
B.7%
C.9%
D.4.4%
Answer: D.4.4%
Explanation: 160 = (900*4*R)/100
R = 4.4%
Answer: D
Question: The simple form of the ratio 2/3:2/5 is
A.5:7
B.5:2
C.5:9
D.5:3
Answer: D.5:3
Explanation: 2/3 : 2/5 = 10:6 = 5:3
Answer: D
Question: In a group of 68 students, each student is registered for at least one of three classes – History, Math and English. Twenty-five students are registered for History, twenty-five students are registered for Math, and thirty-nine students are registered for English. If only three students are registered for all three classes, how many students are registered for exactly two classes?
A.13
B.10
C.15
D.8
Answer: C.15
Explanation: A U B U C = A + B + C - AB-BC-AC + ABC
68 = 25 + 25+ 39 -AB-BC-AC +3 => AB+BC+AC = 24
Exactly Two classes = AB+BC+AC - 3ABC = 24 -3*3 = 15
Hence C
Question: SI on a certain sum of money for 3 yrs at 8 percent /annum is 1/2 the CI on Rs.4000 for 2 yrs at 10 percent/ annum. The sum placed on SI is?
A.Rs. 1650
B.Rs. 1700
C.Rs. 1750
D.Rs. 1950
Answer: C.Rs. 1750
Explanation: C.I.
= Rs. 4000 x 1 + 10 2 - 4000
100
= Rs. 4000 x 11 x 11 - 4000
10 10
= Rs. 840.
Sum = Rs. 420 x 100 = Rs. 1750.
3 x 8
C
Question: A retailer bought a hat at wholesale and marked it up 70% to its initial price of $34. By how many more dollars does he need to increase the price to achieve a 100% markup?
A.2
B.4
C.6
D.8
Answer: C.6
Explanation: Let x be the wholesale price.
Then 1.7x= 34 and x = 34/1.7 = 20.
To achieve a 100% markup, the price needs to be $40.
The retailer needs to increase the price by $6 more.
The answer is C.
Question: There are 6 books on a shelf, of which 2 are paperbacks and 4 are hardbacks. How many possible selections of 4 books from this shelf include at least one paperback?
A.a) 40
B.b) 14
C.c) 50
D.d) 55
Answer: B.b) 14
Explanation: approach 1
at-least 1 paper back = total - no paper back
6c4-4c4 = 14
approach 2
at-least 1 paper back = 1 paper back , 3 hard back or 2 paper back 2 hard back
= 2c1*4c3+2c2*4c2 = 14
Answer is B
Question: Average of five numbers is -10, and the sum of three of the numbers is 16, wat is the average of the other 2 numbers?
A.-33
B.33
C.32
D.-31
Answer: A.-33
Explanation: Let the five numbers be a, b, c, d, e. Then their average is (a+b+c+d+e5)=10.(a+b+c+d+e5)=10.
Now three of the numbers have a sum of 16, say, a+b+c=16a+b+c=16.
So substitute 16 for a+b+ca+b+c in the average above: (16+d+e5)=10.(16+d+e5)=10.
Solving this equation for d+ed+e gives d+e=−66d+e=−66.
Finally, dividing by 2 (to form the average) gives (d+e2)=−33.(d+e2)=−33.
Hence, the answer is A: -33
Question: In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
A.5 km/hr
B.15 km/hr
C.50 km/hr
D.20 km/hr
Answer: A.5 km/hr
Explanation: Let Abhay's speed be x km/hr.
Then,(30/x - 30/2x)= 3
6x = 30
x = 5 km/hr.
ANSWER A
Question: The wages earned by Robin is 30% more than that earned by Erica. The wages earned by Charles is 60% more than that earned by Erica. How much % is the wages earned by Charles more than that earned by Robin?
A.23%
B.18.75%
C.30%
D.50%
Answer: A.23%
Explanation: Explanatory Answer
Let the wages earned by Erica be $100
Then, wages earned by Robin and Charles will be $130 and $160 respectively.
Charles earns $30 more than Robin who earns $130.
Therefore, Charles' wage is 30/130*100 = 23.07%.
correct choice is (A)
Question: In a certain lottery, the probability that a number between 1 and 15, inclusive, is drawn is 1/3 . If the probability that a number 1 or larger is drawn is 2/3 , what is the probability that a number less than or equal to 15 is drawn?
A.2 by 3
B.1/3
C.1/4
D.1/6
Answer: A.2 by 3
Explanation: You can simply use sets concept in this question. The formula
Total = n(A) + n(B) - n(A and B) is applicable here too.
Set 1: Number 1 or larger
Set 2: Number 15 or smaller
1 = P(Set 1) + P(Set 2) - P(Set 1 and Set 2) (combined probability is 1 because every number will be either12 or moreOR20 or less OR both)
2/3 + P(Set 2) - 1/3 = 1
P(Set 2) = 2/3
Answer A
Question: When positive integer x is divided by 8, the quotient is y and the remainder is 2. When 2x is divided by 7, the quotient is 2y and the remainder is 4. What is the value of 6y – x?
A.-1
B.1
C.-2
D.2
Answer: C.-2
Explanation: (1) x = 8y+2
(2) 2x = 14y+4
(2)-(1): x=6y+2
6y-x=-2
The answer is C.
Question: If the range of the set of numbers {140, 90, 135, 110, 170, 145, x, 100, 140} is 100, which of the following could be x?
A.170
B.190
C.210
D.230
Answer: B.190
Explanation: The range of the other 8 numbers is 170-90 = 80, so x must be either the smallest number or the largest number in the set.
Then x = 170-100 = 70 or x = 90+100 = 190
The answer is B.
Question: Sum of two numbers is 50. Two times of the difference of first and seceond is 20. Then the numbers will be?
A.10, 40
B.20, 30
C.35, 15
D.30, 20
Answer: D.30, 20
Explanation: Explanation:
x + y = 50
2x Ã¢â‚¬â€œ 2y = 20
x = 30 y = 20
Answer: D
Question: B, C and D invested Rs.6400, Rs.1600 and Rs.2400 respectively, in a partnership business. Find the share of D in profit of Rs.26000 after a year?
A.6400
B.6300
C.6100
D.6000
Answer: D.6000
Explanation: Explanation:
6400:1600:2400
8:2:3
3/13 * 26000 = 6000
D)
Question: A, B, C enter into a partnership investing Rs. 35,000, Rs. 45,000 and Rs. 55,000 respectively. The respective shares of A, B, C in annual profit of Rs. 40,500 are?
A.Rs.10,500, Rs. 13,500, Rs. 16,500
B.Rs.10,500, Rs. 13,500, Rs. 16,580
C.Rs.10,500, Rs. 13,500, Rs. 16,560
D.Rs.10,500, Rs. 13,500, Rs. 16,509
Answer: A.Rs.10,500, Rs. 13,500, Rs. 16,500
Explanation: A:B:C = 35000 : 45000 : 55000 = 7:9:11
A's share = 40500 * 7/27 = Rs. 10500
B's share = 40500 * 9/27 = Rs. 13500
C's share = 40500 * 11/27 = Rs. 16500
Answer: A
Question: Two persons A and B take a field on rent. A puts on it 21 horses for 3 months and 15 cows for 2 months; B puts 15 cows for 6months and 40 sheep for 7 1/2 months. If one day, 3 horses eat as much as 5 cows and 6 cows as much as 10 sheep, what part of the rent should A pay?
A.1/3
B.1/6
C.1/8
D.1/7
Answer: A.1/3
Explanation: 3h = 5c
6c = 10s
A = 21h*3 + 15c*2
= 63h + 30c
= 105c + 30c = 135c
B = 15c*6 + 40s*7 1/2
= 90c + 300s
= 90c + 180c = 270c
A:B = 135:270
27:52
A = 27/79 = 1/3
Answer: A
Question: Jerry had an average score of 85 on his first eight quizzes. He had an
average score of 81 on his first nine quizzes. What score did he receive on
his ninth quiz?
A.49
B.51
C.53
D.55
Answer: A.49
Explanation: The sum of Jerry’s first 8 scores is 8 · 85 and the sum of his first 9 scores is 9 · 81, so he received
9 · 81 − 8 · 85 on his 9th quiz. You can do the arithmetic or note that the answer ends in a 9.
correct answer A
Question: There are 9 books on a shelf that consist of 2 paperback books and 7 hardback books. If 5 books are selected at random without replacement, how many different combinations are there which include at least one paperback book?
A.85
B.95
C.105
D.115
Answer: C.105
Explanation: The total number of ways to select 5 books is 9C5 = 126
The number of ways which do not include any paperbacks is 7C5 = 21
The number of combinations with at least one paperback is 126-21 = 105
The answer is C.
Question: The speed at which a man can row a boat in still water is 18 kmph. If he rows downstream, where the speed of current is 6 kmph, what time will he take to cover 100 metres?
A.6.67seconds
B.18 seconds
C.26 seconds
D.14.99 seconds
Answer: D.14.99 seconds
Explanation: Speed of the boat downstream = 18 +6
= 24 kmph
= 24 * 5/18 = 6.67m/s
Hence time taken to cover 100 m = 100/6.67
= 14.99 seconds.
Answer:D
Question: By selling 14 pencils for a rupee a man loses 22%. How many for a rupee should he sell in order to gain 22%?
A.10
B.9
C.7
D.6
Answer: A.10
Explanation: 88% --- 14
122% --- ?
88/122 * 14 = 10
Answer: A
Question: A tank holds x gallons of a saltwater solution that is 20% salt by volume. One Fourth of the water is evaporated, leaving all of the salt. When 8 Gallons of water and 16 gallons of salt are added, the resulting mixture is 33 1/3 % salt by volume. What is the value of x?
A.120
B.75
C.100
D.150
Answer: A.120
Explanation: Nope, 150. I can only get it by following PR's backsolving explanation. I hate that.
Original mixture has 20% salt and 80% water.
Total = x
Out of which Salt = 0.2x and water = 0.8x
Now, 1/4 water evaporates and all salt remains.
So what remains is 0.2x salt and 0.6x water.
Now 16 gallons salt is added and 8 gallons of water is added.
So salt now becomes -> (0.2x + 16) and water --> (0.6x+8)
Amount of salt is 33.33% of total. So amount of water is 66.66%. So salt is half of the volume of water.
So (0.2x+16) = (0.6x+8)/2 => 0.2x= 24
Solving, x = 120
Answer : A
Question: The distance between towns A and B is 300 km. One train departs from town A and another train departs from town B, both leaving at the same moment of time and heading towards each other. We know that one of them is 10 km/hr faster than the other. Find the speeds of both trains if 2 hours after their departure the distance between them is 40 km.
A.22
B.27
C.236
D.90
Answer: D.90
Explanation: Let the speed of the slower train be xx km/hr. Then the speed of the faster train is (x+10)(x+10) km/hr. In 2 hours they cover 2x2x km and 2(x+10)2(x+10)km, respectively. Therefore if they didn't meet yet, the whole distance from A to B is 2x+2(x+10)+40=4x+602x+2(x+10)+40=4x+60 km. However, if they already met and continued to move, the distance would be 2x+2(x+10)−40=4x−202x+2(x+10)−40=4x−20km. So we get the following equations:
4x+60=3004x+60=300
4x=2404x=240
x=60x=60 or
4x−20=3004x−20=300
4x=3204x=320
x=80x=80
Hence the speed of the slower train is 60 km/hr or 80 km/hr and the speed of the faster train is 70 km/hr or 90 km/hr.
Answer:D
Question: In Rwanda, the chance for rain on any given day is 1/2. What is the probability that it rains on 4 out of 6 consecutive days in Rwanda?
A.4/7
B.3/7
C.15/64
D.4/28
Answer: C.15/64
Explanation: using Binomial. theorem
nCr (p)^r (q)^n-r
6C4 (1/2)^4 (1/2)^r
which is 15/64
Answer is C.
Question: A certain bag of gemstones is composed of two-thirds diamonds and one-third rubies. If the probability of randomly selecting two diamonds from the bag, without replacement, is 5/12, what is the probability of selecting two rubies from the bag, without replacement?
A.5/36
B.5/24
C.1/12
D.1/6
Answer: C.1/12
Explanation: 2/3 * (2X-1) / (3X-1) = 5/ 12 => X = 3
So total gems = 9
and probability of ruby = 1/3 * 2/8 = 1/12
answer 1/12 C
Question: A set of numbers has the property that for any number t in the set, t - 2 is in the set. If -1 is in the set, which of the following must also be in the set?
I. -5
II. 11
III. 6
A. I only
B. II only
C. I and II only
D. II and III only
Answer: A. I only
Explanation: The question is which of the followingmustbe in the set, notcouldbe in the set.
If -1 is in the set so must be -1-2=-3, as -3 is in the set so must be -3-2=-5, as -5 is in the set so must be -5-2=5 and so on. So basically knowing that -1 is in the set we can say that ALL odd numbers less than -1 are also in the set.
Answer: A.
Question: At exactly what time past 9:00 will the minute and hour hands of an accurate working clock be precisely perpendicular to each other for the first time?
A.20 13/21 minutes past 7:00
B.20 13/17 minutes past 7:00
C.21 3/23 minutes past 7:00
D.21 9/11 minutes past 9:00
Answer: D.21 9/11 minutes past 9:00
Explanation: 5.5 is the angle between minute n hour, this is what I was taught...so shouldn't it be solve by dividing 90 with 5.5?
That would have been the case if your initial difference between the hour and the minute hand was = 0 degrees or in other words, both minute and hour hands were at the same location. But as per the question, you are asked for time AFTER 9:00. At 9:00, the angle between the hour and the minute hand is 210 degrees. you need to take this into account as well.
So in order for the difference to decrease to 90 degrees, the minute hand must eat away this difference of 210-90 = 120 degree at the rate of 5.5 degrees per minute ---> 120/5.5 = 21 9/11 minutes.
Thus, D is the correct answer.
Question: Working alone, printers X, Y, and Z can do a certain printing job, consisting of a large number of pages, in 16, 10, and 20 hours, respectively. What is the ratio of the time it takes printer X to do the job, working alone at its rate, to the time it takes printers Y and Z to do the job, working together at their individual rates?
A.7/4
B.10/3
C.12/5
D.15/7
Answer: C.12/5
Explanation: The time it takes printer X is 16 hours.
The combined rate of Y and Z is 1/10 + 1/20 = 3/20
The time it takes Y and Z is 20/3
The ratio of times is 16 / (20/3) = 3*16/20 = 12/5
The answer is C.
Question: Boy purchased two flats for Rs.5,00,000. On one he gains 15 % while on the other he losses 15%. How much does he gain or lose?
A.2.05%
B.2.10%
C.2.25%
D.2.30%
Answer: C.2.25%
Explanation: Generally in such cases, there is always loss.
So always remember, when two materials are sold and if one material gets profit and the other gets a loss, then use the trick shown below to calculate the loss.
Loss% = Common loss and gain% 2	= x 2
10 10
Therefore, here common loss and gain % = 15%
Hence,
Loss% = 15 2	= 2.25%
C
Question: A person is traveling at 35km/hr and reached his destiny in 5hr find the distance?
A.A)100km
B.B)95km
C.C)175km
D.D)80km
Answer: C.C)175km
Explanation: speed = 35km/hr
time = 5hr
distance = 35*5 = 175km
Answer is C
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 36 kmph and 72 kmph. In how much time will the trains cross each other?
A.70/3 sec
B.80/3 sec
C.40/3 sec
D.60/3 sec
Answer: C.40/3 sec
Explanation: C
Relative speed = (36 + 72)* 5/18 = 6 * 5 = 30 mps.
The time required = d/s = (100 + 100 + 200)/35
= 400/30 = 40/3 sec.
Question: Find the value of x from the below equation? : 3x^2+5x+2 = 0
A.-1
B.1
C.-2
D.2
Answer: A.-1
Explanation: a = 3, b = 5, c = 2
x1,2 = (-5 ± √(52 - 4×3×2)) / (2×3) = (-5 ± √(25-24)) / 6 = (-5 ± 1) / 6
x1 = (-5 + 1)/6 = -4/6 = -2/3
x2 = (-5 - 1)/6 = -6/6 = -1
A
Question: A sum of money place at compound interest doubles itself in 5 years. In how many years will it amount to eight times itself?
A.15 years
B.11 years
C.12 years
D.18 years
Answer: A.15 years
Explanation: 100 ---- 200 ---- 5
400 ---- 5
800 ---- 5
------
15 years
Answer: A
Question: A software programmer does 10% of the work in 80% of the time, and 80% of the work in the remaining 20% of the time. If the code he writes is X lines long and he was given one month (30 days) to accomplish the task, then, assuming that the programmer works at a constant rate in each of the two stages, How many lines of code were written in the last two weeks, in terms of X?
A.13x /15
B.15x/15
C.7x/15
D.2x/30
Answer: C.7x/15
Explanation: Take X=30 lines
80% of 30 = 24 lines
20% of 30 = 6 lines
W - R - T
6 lines - r1 - 24 (first 80% of the 30 days)
24 lines - r2 - 6 ( last 20% of the 20 days)
r1 = 1/4r2 = 4
Now Work in last 14 days = 6 days programmer worked at r2 + 8days programmer worked at r1
=> 6 * 4 + 8 * 1/4 = 24 + 2 = 26
Insert, X=30 in all options => C is the answer.
Question: On flipping 3 coins together what is the outcomes for exactly one head and one tail?
A.{HHH, HTH, THH, TTH, THT, HTT}
B.{HHT, HTH, THH, TTH, THT, TTT}
C.{HHT, HTH, THH, TTH, THT, HTT}
D.{HHT, HTH, THH, TTH, THT, TTT}
Answer: C.{HHT, HTH, THH, TTH, THT, HTT}
Explanation: Sample space, S = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}
Favorable outcomes for at least two heads
= favorable outcomes for one head and one tail and favorable outcomes for more than one head and one tail.
= {HHT, HTH, THH, TTH, THT, HTT}
C
Question: What is the lowest possible common multiple of 2 distinct integers, each greater than 67?
A.68
B.69
C.136
D.68^2
Answer: C.136
Explanation: In order to get the lowest LCM, we have to take the first number as 68 and the next number as its multiple.
So, I can take 68 and 136 as two distinct numbers, such that Lowest LCM = 136.
Answer should be C.
Question: A sum of money becomes triple itself in 5 years at simple interest. How many years will it become six times at the same rate?
A.12 1/2 years
B.2 1/2 years
C.12 1/5 years
D.12 6/2 years
Answer: A.12 1/2 years
Explanation: 100 ---- 200 ---- 5
200 ---- 5
100 ---- 2 1/2
------------------
600 ---- 12 1/2 years
Answer: A
Question: In a group of ducks and cows, the total number of legs are 24 more than twice the no. of heads. Find the total no.of buffaloes.
A.11
B.12
C.14
D.16
Answer: B.12
Explanation: Let the number of buffaloes be x and the number of ducks be y
=> 4x + 2y = 2 (x + y) + 24
=> 2x = 24 => x = 12
B
Question: The price of 357 mangoes is Rs. 1517.25. What will be the approximate price of 49 dozens of such mangoes?
A.Rs. 3000
B.Rs.2500
C.Rs 2700
D.Rs 2900
Answer: B.Rs.2500
Explanation: Explanation :
More mangoes, more cost (Direct)357 : 49 * 12 :: 1517.25 : xor 375 * x= 49 * 12 * 1517.25.49 * 12 * 15l7.25 / 357 = 2499Approximate cost = Rs. 2500.
Answer : B