RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Fourteen years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages
A.A)35
B.B)34
C.C)45
D.D)49
Answer: D.D)49
Explanation: Explanation:
Let the present age of P and Q be 3x and 4x respectively.
Fourteen years ago, P was half of Q in age
=> 2(3x – 14) = (4x – 14)
=> 6x – 28 = 4x – 14
=> 2x = 14
=> x = 7
7*x = 7*7 = 49
Answer: Option D
Question: What is the area of a square field whose diagonal of length 14 m?
A.160 sq m
B.140 sq m
C.200 sq m
D.400 sq m
Answer: B.140 sq m
Explanation: d2/2 = (14 * 14)/2 = 140
ANSWER:B
Question: A person can row at 9 kmph and still water. He takes 6 1/2 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 1 kmph?
A.32
B.28
C.29
D.54
Answer: C.29
Explanation: Let the distance between A and B be x km.
Total time = x/(9 + 1) + x/(9 - 1) = 6.5
=> x/10 + x/8 = 13/2 => (4x + 5x)/40 = 13/2 => x
= 29 km.
Answer:C
Question: Three walls have wallpaper covering a combined area of 300 square meters. By overlapping the wallpaper to cover a wall with an area of 180 square meters, the area that is covered by exactly two layers of wallpaper is 40 square meters. What is the area that is covered with three layers of wallpaper?
A.5 Square Meters
B.36 Square Meters
C.40 Square Meters
D.83.3 Square Meters
Answer: C.40 Square Meters
Explanation: 300 - 180 = 120 sq m of the wallpaper overlaps (in either two layers or three layers)
If 36 sq m has two layers, 120 - 40 = 80 sq m of the wallpaper overlaps in three layers. 80 sq m makes two extra layers hence the area over which it makes two extra layers is 40 sq m.
Answer (C).
Question: How long does a train 165 meters long running at the rate of 54 kmph take to cross a bridge 660 meters in length?
A.50 sec
B.45 sec
C.55 sec
D.65 sec
Answer: C.55 sec
Explanation: C
55 sec
T = (660 + 165)/54 * 18/5
T = 55
Question: In a factory, there are 50% technicians and 50% non-technicians. If the 50% of the technicians and 50% of non-technicians are permanent employees, then the percentage of workers who are temporary is?
A.50%
B.57%
C.52%
D.22%
Answer: A.50%
Explanation: Total = 100
T= 50 NT= 50
50*(50/100)=25 50*(50/100)=25
25 + 25 = 50 => 100 - 50 = 50%
Answer:A
Question: In how many ways can 3 men and 3 women be seated around a round table if each women is to be between 2 men.
A.12
B.14
C.16
D.18
Answer: A.12
Explanation: 1-2-3-4-5-6-1 (assume this to be a closed circle)
Lets assume the position of the first man to be "fixed" at 1, then there are two remaining positions for the remaining two men: 3rd and 5th seat.
Number of ways of seating a man in 3rd seat = 2
As only one man is left, number of ways of seating a man in 5th seat is 1.
Number of ways that three men can be seated first at the round table = 1*2*1=2
There are three remaining seats 2,4, and 6.
Number of options for 2 = 3
Number of options for 4 = 2 (only 2 women are left)
Number of options for 6 = 1 (only 1 woman left)
i.e. The three women can be seated in 3! ways = 6
Total number of possibilities = 2*6 = 12
ANS:A
Question: If a man buys 1 liter of milk for 12 rs. and mixes it with 20% water and sells it for 15 rs then what is the %age of gain...
A.30
B.40
C.50
D.60
Answer: C.50
Explanation: Quantity after adding 20% water=1.2 liter
SP of 1.2 lit.@15 Rs./liter=15*1.2=18 Rs
CP=12 Rs/lit.
% profit=100*(18-12)/12=50
ANSWER:C
Question: if 1/8 of a pencil is black 1/2 of the remaining is white and the remaining 7/2 is blue find the total length of the pencil?
A.7.33cm
B.6.33cm
C.5.33cm
D.9.33cm
Answer: D.9.33cm
Explanation: (1/8)p + (1/2)p + (7/2)= p
on solving the above for p we get 9.333
Now checking for the answer:
9.333/8=1.166 cm
9.333/2=4.665 cm
now 1.166+4.665+(7/2) = 9.33cm
ANSWER:D
Question: Given a spinner with four sections of equal size labeled W, B, C, and D, what is the probability of NOT getting an W after spinning the spinner two times?
A.15/16
B.9/16
C.1/2
D.1/4
Answer: B.9/16
Explanation: The probability of NOT getting an W after spinning the spinner two times is 3/4*3/4=9/16 (so getting any of the remaining 3 letters out of 4).
Answer: B.
Question: Average of five numbers is -10, and the sum of three of the numbers is 16, wat is the average of the other 2 numbers?
A.-33
B.34
C.-34
D.35
Answer: A.-33
Explanation: Let the five numbers be a, b, c, d, e. Then their average is (a+b+c+d+e5)=10.(a+b+c+d+e5)=10.
Now three of the numbers have a sum of 16, say, a+b+c=16a+b+c=16.
So substitute 16 for a+b+ca+b+c in the average above: (16+d+e5)=10.(16+d+e5)=10.
Solving this equation for d+ed+e gives d+e=−66d+e=−66.
Finally, dividing by 2 (to form the average) gives (d+e2)=−33.(d+e2)=−33.
Hence, the answer is A: -33
Question: In how many different ways can the letters of the word "BICYCLE" be rearrangement?
A.5040
B.5045
C.5140
D.5010
Answer: A.5040
Explanation: Option 'A'
The total number of arrangements is
7P7 = 7! = 5040
Question: An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, is
A.10:28 am
B.10:30 am
C.10:31 am
D.None of above
Answer: C.10:31 am
Explanation: Explanation:
L.C.M. of 60 and 62 seconds is 1860 seconds
1860/60 = 31 minutes
They will beep together at 10:31 a.m.
Sometimes questions on red lights blinking comes in exam, which can be solved in the same way
Option C
Question: In how many ways, a committee of 5 members can be selected from 6 men and 5 ladies, consisting of 3 men and 2 ladies?
A.220
B.175
C.145
D.200
Answer: D.200
Explanation: (3 men out 6) and (2 ladies out of 5) are to be chosen.
Required number of ways = (6c3x5c2)
= [6x5x4/3x2x1] x [5x4/2x1] = 200.
Ans: D
Question: Which of the following fractions can be written as the difference of reciprocals of two consecutive integers?
A.1/100
B.1/121
C.1/45
D.1/56
Answer: D.1/56
Explanation: =1/n - 1/(n+1)
=1/n(n+1)
Only answer choice that satisfies above equation is D
1/7*8
ANSWER:D
Question: Two dice are thrown together. What is the probability that the sum of the number on the two faces is divisible by 4?
A.2/9
B.1/9
C.1/4
D.1/3
Answer: C.1/4
Explanation: Clearly n(S) = 6 x 6 = 36
Let E be the event that the sum of the numbers on the two faces is divided by 4.
E= {(1,3), (2,2), (2,6), (3,1), (3,5), (4,4), (5,3), (6,2), (6,6)}
n(E) = 9
Hence, P(E) = n(E)/n(S) = 9/36 = 1/4
ANSWER:C
Question: The average of first five prime numbers greater than 20 is?
A.32.9
B.32.7
C.32.8
D.32.2
Answer: D.32.2
Explanation: 23 + 29 + 31 + 37 + 41 = 161/5
= 32.2
Answer:D
Question: List I: 4, 6, 8, 10
List II: x, 4, 6, 8, 10
A.7
B.4
C.3
D.5
Answer: A.7
Explanation: List I has even number of terms, thus its median is the average of two middle terms (when arranged in ascending/descending order), so median=(6+8)/2=7.
List II has odd number of terms, thus its median is the middle term (when arranged in ascending/descending order). As no other number in the list equal to 7, then x=7.
Answer: A
Question: By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%?
A.228
B.480
C.267
D.288
Answer: B.480
Explanation: SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 25% = 25% of 640 = Rs.160
SP = CP - Loss = 640 - 160 = Rs.480
Answer: B
Question: One-third of Rahul's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,50,000 as total savings, how much has he saved in Public Provident Fund ?
A.80000
B.60000
C.50000
D.75000
Answer: B.60000
Explanation: Let savings in N.S.C and P.P.F. be Rs. x and Rs. (150000 - x) respectively. Then,
=1/3 x = 1/2 (150000 - x)
=x/3 + x/2 = 75000
=5x/6 = 75000
=x = 75000 x 6 /5	= 90000
Savings in Public Provident Fund = Rs. (150000 - 90000) = Rs. 60000
Answer is B.
Question: The ratio of number of students studying Arts, Commerce and Science in a College is 3 : 6 :8. What is the new ratio of the number of students studying Arts, Commerce and Science respectively if there is an increase of 20%, 40% and 25% in the number of students studying Arts, Commerce and Science?
A.18 : 21 : 50
B.3 : 10 : 10
C.4 : 8 : 5
D.32 : 35 : 25
Answer: A.18 : 21 : 50
Explanation: Suppose the number of students studying Arts, Commerce and Science be 3x, 6x and 8x respectively.
When their numbers are increased by 20%, 40% and 25% respectively the new ratio becomes
3x × 120% : 6x × 140% :
8x × 125% = 36 : 84 : 100
= 18 : 21 : 50
Answer A
Question: The spinner shown is divided into 6 sections of equal
size. What is the probability of landing on a section that
contains the letter P using this spinner?
A.3/6
B.4/6
C.5/6
D.2/6
Answer: D.2/6
Explanation: The spinner has 6 sections in total and 2 of these sections contain the letter P.
Sections are equal to one another in size and thus they are each equally likely to be landed on.
Therefore, the probability of landing on a section that contains the letter P is 2/6 .
correct answer D
Question: A rectangular farm has to be fenced one long side, one short side and the diagonal. If the cost of fencing is Rs.10 per meter. The area of farm is 1200 m2 and the short side is 30 m long. How much would the job cost?
A.6
B.9
C.3
D.5
Answer: D.5
Explanation: x * 1 = 3 * 5/3
x = 5
Answer:D
Question: One out of every 500 light bulbs are defected. If 2 out of every 10 defected light bulbs have a broken glass and there are 20 broken glass light bulbs in the shipment, how many light bulbs total are there in the shipment?
A.2,000
B.5,000
C.10,000
D.50,000
Answer: D.50,000
Explanation: 20 broken glasses indicates that 10*10= 100 defected bulbs are present.
100 defected bulbs indicates that 100*500= 50,000 light bulbs are present.
D is the answer
Question: The volume of the sphere QQ is (dfrac{37}{64}%)less than the volume of sphere PP and the volume of sphere RR is (dfrac{19}{27}%) less than that of sphere QQ. By what is the surface areaof sphere RR less than the surfacearea of sphere PP?
A.35%
B.65%
C.75%
D.90%
Answer: C.75%
Explanation: Let the volume of sphere PP be 64 parts.
Therefore volume of sphere QQ
=64−3764%=64−3764% of 6464
=64−37=27=64−37=27 parts.
The volume of RR
=27−1927×27=27−1927×27
=27−19=8=27−19=8 parts.
Volume ratio:
=P:Q:R=64:27:8=P:Q:R=64:27:8
Radius ratio:
=P:Q:R=4:3:2=P:Q:R=4:3:2
The surface area will be 16:9:516:9:5
Surface area of RR is less than the surface area of sphere PP
16k−4k=12k16k−4k=12k
Now,
=12k16k×100=12k16k×100
=75%=75%
Thus surface area of sphere RR is less than the surface area of sphere P by 75%
C
Question: One number will be chosen randomly from each of the sets below . If x represents the chosen member of Set X and y represents the chosen member of Set Y, what is the probability that x/yx/y will be an integer?
X = {9, 10, 11, 12}
Y = {2, 3, 4, 5}
A.1/16
B.3/8
C.1/2
D.3/4
Answer: B.3/8
Explanation: (x, y), for which x/y = integer:
(9; 3)
(10; 2)
(10; 5)
(12; 2)
(12; 3)
(12; 4)
6 pairs out of 4*4 = 16, so the probability is 6/16 = 3/8.
Answer: B.
Question: A vessel of capacity 30 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution?
A.14.7
B.2.9
C.38.3
D.78.3
Answer: A.14.7
Explanation: Explanation:
Let the initial quantity of milk in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T - y)/T]^n * T
For the given problem, T = 30, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(30 - 9)/30]^2 (30) = 14.7 litres.
Answer: Option A
Question: If a car had traveled 10 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 30 km, at what speed did it travel?
A.20 kmh
B.25 kmh
C.30 kmh
D.35 kmh
Answer: A.20 kmh
Explanation: Time = Distance/Speed
Difference in time = 1/2 hrs
30/x - 30/(x + 10) = 1/2
Substitute the value of x from the options. --> x = 20 --> 30/20 - 30/30 = 3/2 - 1 = 1/2
Answer: A
Question: If a = 1 and b = -2, then (2a^2 + b)(r + y) + (a + b)(r - y) =
A.0
B.2x
C.y - r
D.x - y
Answer: C.y - r
Explanation: Putting A=1 and B = -2 => 2A^2-B=0 ; so the first part of the term is zero
with second term => (1-2) *(r+y)=y-r => Smash C
Question: A man's age is 125% of what it was 10 years ago, but 8313% of what it will be after 10 years. What is his present age?
A.30
B.40
C.50
D.60
Answer: C.50
Explanation: Let the age before 10 years =x. Then,
125x100=x+10⇒125x=100x+1000⇒x=100025=40
Present age =x+10=40+10=50.
Answer is C.
Question: What least number mustbe subtracted from 427398 so that remaining no.is divisible by 15
A.3
B.5
C.6
D.7
Answer: A.3
Explanation: Explanation:
On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted
Answer: Option A
Question: (500 + 200)x (2+3)Ã— 4 Ã— (3 + 2) = ?
A.17500
B.70000
C.14000
D.65000
Answer: B.70000
Explanation: (500 + 200) Ã— 5Ã—4x5 = ?
or, ? = 700 Ã—5x 4 Ã— 5 = 70000
Answer B
Question: If Reneesh earns a raise of between 5% and 10%, non-inclusive, by what fraction could her salary have increased?
A.1/4
B.1/5
C.7/100
D.3/25
Answer: C.7/100
Explanation: Perhaps it is also easy to just translate the % into fractions:
6%: 6/100 = 3/50
7%: 7/100
8%: 8/100 = 4/50 =2/25
9%: 9/100
Only 7/100 exists in the answer choices, so ANS C
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is?
A.4:9
B.4:3
C.4:6
D.4:2
Answer: B.4:3
Explanation: Let us name the trains A and B.
Then, (A's speed) : (B's speed)
= √b : √a = √16 : √9 = 4:3
Answer: B
Question: In an effort to plan out expenses, the Roberts family is representing its annual budget as a circle graph. Each sector of the graph is proportional to the amount of the budget it represents. If “clothes and shoes” takes up 36° of the chart, how much of the Roberts’s $40,000 annual budget is dedicated to clothes and shoes?
A.$1,500
B.$3,000
C.$4,500
D.$4,000
Answer: D.$4,000
Explanation: Given for clothes and shoes” takes up 36° of the circular chart.
Then clothes and shoes = 36/360 * 40000.
=> 4000.
IMO option D is correct answer...
Question: Ajay spends 25 per cent of his salary on house rent, 5 percent on food, 15 percent travel, 10 percent on clothes and the remaining amount of Rs.27000 is saved. What is Ajay’s income?
A.Rs.60000
B.Rs.80500
C.Rs.60700
D.Rs.70500
Answer: A.Rs.60000
Explanation: Explanation:
Savings = Income – expenditure
100 – (25+5+15+10) = 45%
45% of income = Rs.27000
:. Income = 27000 x 100/45 = Rs. 60000.
Answer: Option A
Question: During the last four years, a large truck company purchased diesel at rates of $1.2, $1.4, $1.7 and $2.1 per gallon. What was the mean cost of diesel over the four-year period if the company spends the same amount of dollars on diesel each year?
A.$2.5
B.$2.55
C.$1.53
D.$3.25
Answer: C.$1.53
Explanation: finding the Harmonic mean here.
HM = 4/(1/12 + 1/14 + 1/17 + 1/21) = 15.31
The calculation is the same either way.
C
Question: Two dice are thrown together .What is the probability that the sum of the number on the two faces is divided by 4 or 6
A.5/7
B.3/4
C.7/18
D.5/17
Answer: C.7/18
Explanation: Clearly n(S)=6*6=36
Let E be the event that the sum of the numbers on the two faces is divided by 4 or 6.Then
E={(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(5,3),(6,2),
(6,6)}
n(E)=14.
Hence p(e)=n(e)/n(s)=14/36=7/18
Ans: C
Question: A can do a work in 4 days. B can do the same work in 6days. Both A&B together will finish the work and they got $1000 from that work. Find their shares?
A.600,400
B.500,500
C.300,700
D.800,200
Answer: A.600,400
Explanation: Ratio of their works A:B = 4:6
Ratio of their wages A:B = 3:2
A's share = (3/5)1000 = 600
B's share = (2/5)1000 = 400
correct option is A
Question: Find the odd man out. 742, 743, 633, 853, 871, 990, 532
A.532
B.742
C.990
D.633
Answer: B.742
Explanation: In all numbers except 742, the difference of third and first digit is the middle digit.
Answer is B
Question: A man sells a horse for Rs.800 and loss something, if he had sold it for Rs.820, his gain would have been trible the former loss. Find the cost price of the horse?
A.605
B.905
C.815
D.805
Answer: D.805
Explanation: CP = SP + 1CP = SP - g
800 + x = 820 - 3x
4x = 20 => x = 5
CP = 800 + 5 = 805
Answer: D
Question: The speed of a car is 90 km in the first hour and 80 km in the second hour. What is the average speed of the car?
A.12
B.75
C.85
D.54
Answer: C.85
Explanation: S = (90 + 80)/2
= 85 kmph
Answer: C
Question: How many pieces of 85 cm length can be cut from a rod of 34 meters long?
A.50
B.40
C.30
D.20
Answer: B.40
Explanation: Number of pieces = 3400/85 = 40
The answer is B.
Question: Reema took a loan of Rs 800 with simple interest for as many years as the rate of interest. If she paid Rs. 632 as interest at the end of the loan period, what was the rate of interest.
A.8.62%
B.8.88%
C.8.32%
D.8%
Answer: B.8.88%
Explanation: Explanation:
Let rate = R% then Time = R years.
=>800∗R∗R /100=632
=>R2=79
=>R=8.88%
Option B
Question: In the youth summer village there are 175 people, 100 of them are not working,75 of them have families and 125 of them like to sing in the shower. What is the largest possible number of people in the village, which are working, that don't have families and that are singing in the shower?
A.70
B.75
C.85
D.80
Answer: B.75
Explanation: total =175
not working =100
having family=75
like to sing in shower = 125
working=175-100=75
not having family = 175-75=100
like to sing in shower = 100
largest possible number is the lowest possible among the above
Thus 75
B
Question: If a man buys 1 lt of milk for Rs.12 and mixes it with 20% water and sells it for Rs.15, then what is the percentage of gain?
A.25%
B.28%
C.29%
D.50%
Answer: D.50%
Explanation: cp=1*12=12
sp=1.2*15=18
gain=sp-cp=6
gain%=(6/12)*100=50%
ANSWER:D
Question: A gardener sells 100 metres of fencing for Rs. 7500 at a loss of Rs. 3 per metre. Find his cost price for one metre of fencing?
A.54
B.67
C.62
D.78
Answer: D.78
Explanation: SP per metre = 7500/100 = Rs. 75 Loss per metre = Rs. 3 CP per metre = 75 + 3= Rs. 78Answer: D
Question: In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. What is the length of the garden?
A.30 m
B.28 m
C.26 m
D.24 m
Answer: D.24 m
Explanation: Explanation :
Between the 12 mango trees, there are 11 gaps and each gap has 2 meter length
Also, 1 meter is left from all sides of the boundary of the garden.
Hence, length of the garden = (11 × 2) + 1 + 1 = 24 meter
Answer :D
Question: Find the area of a parallelogram with base 24 cm and height 16 cm?
A.281
B.284
C.288
D.255
Answer: B.284
Explanation: Area of a parallelogram = base * height
= 24 * 16
= 384 cm2
Answer: B
Question: If 45% of z is 39% of y and y is 75% of x, what percent of x is z?
A.200
B.160
C.100
D.65
Answer: D.65
Explanation: (45/100)z = (39/100)y
and y = (75/100)x i.e. y = (3/4)x
i.e. (45/100)z = (39/100)*(3/4)x
i.e. z = (39*3)x/(45*4)
i.e. z = (0.65)x = (65/100)x
i.e. z is 65% of x
Answer: Option D
Question: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?
A.1.9
B.1.5
C.1.7
D.1.4
Answer: B.1.5
Explanation: 72 --- 9 DS = 8
? ---- 1
45 ---- 9 US = 5
? ---- 1 S = ?
S = (8 - 5)/2 = 1.5
Answer:B
Question: A student scored an average of 80 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics?
A.54
B.76
C.87
D.80
Answer: D.80
Explanation: Given M + P + C = 80 * 3 = 240 --- (1)
M + P = 90 * 2 = 180 --- (2)
P + C = 70 * 2 = 140 --- (3)
Where M, P and C are marks obtained by the student in Mathematics, Physics and Chemistry.
P = (2) + (3) - (1) = 180 + 140 - 240 = 80
Answer: D
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
A.28 sec
B.19 sec
C.48 sec
D.18 sec
Answer: C.48 sec
Explanation: Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 6/125
= 48 sec.
Answer: C
Question: In a stack of cards, 8 cards are blue and the rest are red. If 2 cards are to be chosen at random from the stack without replacement, the probability that the cards chosen will both be blue is 1/2. What is the number of cards in the stack?
A.10
B.11
C.12
D.15
Answer: B.11
Explanation: This question can be solved by TESTing THE ANSWERS.
We're told that we have 9 blue cards and an unknown number of red cards. We're also told that if 2 cards are to be chosen at random from the stack WITHOUT replacement, then the probability that the cards chosen will BOTH be BLUE is 1/2. We're asked for the TOTAL number of cards.
Normally, when TESTing THE ANSWERS, we should start with either B or D. Answer B looks easier, so let's start there.
Answer B: 11 total cards
With 11 total cards, and 8 blue cards, the probability of pulling two blue cards is...
(8/11)(7/10) = 56/110~0.509
Since 1/2 = 0.5, this is clearly the answer.
B
Question: Machine P and Machine Q are each used to manufacture 770 sprockets. It takes Machine P 10 hours longer to produce 770 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce?
A.3
B.5
C.7
D.9
Answer: C.7
Explanation: P makes x sprockets per hour.
Then Q makes 1.1x sprockets per hour.
770/x = 770/1.1x + 10
1.1(770) = 770 + 11x
11x = 77
x = 7
The answer is C.
Question: In a certain accounting class of 100 students, 70% of the students took the final exam on the assigned day while the rest of the students took the exam on a make-up date. If the students on the assigned day had an average score of 60%, and the students on the make-up date had an average score of 90%, what was the average score for the entire class?
A.65%
B.67%
C.69%
D.72%
Answer: C.69%
Explanation: 70% of the class scored 60% and 30% of the class scored 90%.
The difference between 60% and 90% is 30%.
The average will be 60% + 0.3(30%) = 69%.
The answer is C.
Question: A mixture contains alcohol and water in the ratio 4 : 3. If 5 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture.
A.10
B.12
C.15
D.18
Answer: A.10
Explanation: Explanation:
Let the quantity of alcohol and water be 4x litres and 3x litres respectively
4x/(3x+5) = 4/5
20x = 4(3x+5)
8x = 20
x = 2.5
Quantity of alcohol = (4 x 2.5) litres = 10 litres.
Answer: A
Question: A man spends 10% of his income on food and 80% of the remaining income on clothing. If he still has a balance of Rs. 180. what is his total income?
A.1100
B.1000
C.804
D.934
Answer: B.1000
Explanation: Total Income = 180 x 100100âˆ’10Ã—100100âˆ’80
= 180 x 10090Ã—10020 = Rs. 1000
correct answer - B
Question: An analyst will recommend a combination of 1 industrial stocks, 1 transportation stocks, and 1 utility stocks. If the analyst can choose from 5 industrial stocks, 4 transportation stocks, and 3 utility stocks, how many different combinations of 3 stocks are possible?
A.12
B.19
C.60
D.180
Answer: C.60
Explanation: 5C1 * 4C1 * 3C1 = 5*4*3 = 60.
Answer: C
Question: If x is an even integer, which of the following is an odd integer?
A.3x + 2
B.7x
C.8x +5
D.x^2
Answer: C.8x +5
Explanation: Soln:-
A) 3x + 2
3*Even +2
= Even +Even = Even
(B) 7x
7*Even= Even
(C) 8x +5
8*Even +5
= Even +5
= Odd
(D) x^2
= Even * Even = Even
(E) x^3
= Even *Even * Even
= Even
Answer C