RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In the number 11,0AB, A and B represent the tens and units digits, respectively. If 11,0AB is divisible by 50, what is the greatest possible value of B × A?
A.0
B.5
C.20
D.15
Answer: C.20
Explanation: You should notice that 50*2=110 so 11,000 is divisible by 55: 55*200=11,000 (or you can notice that 11,000 is obviously divisible by both 5 and 11 so by 55) --> B*A=0*0=0. Next number divisible by 55 is 11,000+55=11,055: B*A=5*4=20 (next number won't have 110 as the first 3 digits so we have only two options 0 and 25).
Answer: C.
!
Please post PS questions in the PS subforum:gmat-problem-solving-ps-140/
Please post DS questions in the DS subforum:gmat-data-sufficiency-ds-141/
No posting of PS/DS questions is allowed in the mainMath forum.
C
Question: If three sides of the triangle are 8 , 15 and G respectively then the how many values can G ?
A.[A] 6
B.[B] 7
C.[C] 8
D.[D]9
Answer: D.[D]9
Explanation: Needed: How many Values can G take
Concept: Sum of any two sides of a triangle is greater then the third side.
Case 1: 8+5 > G => G<13
Case 2: 5+G > 8 => G >3
Case 3: 8+G > 5 => G > -3 (Always true since G is one side of a Triangle)
Finally, 3 < G < 13. So, we can have infinite number of sides between 3 and 13.
Answer = E
PS: If question said G can take only integer value, the G = 9. Answer choice D.
Question: How long does a train 165 meters long running at the rate of 54 kmph take to cross a bridge 660 meters in length?
A.22
B.88
C.55
D.200
Answer: C.55
Explanation: T = (660 + 165)/54 * 18/5
T = 55.Answer: C
Question: Dan has a membership at a local gym that also gives classes three nights a week. On any given class night, Dan has the option of taking yoga, weight training, or kickboxing classes. If Dan decides to go to either one or two classes per week, how many different combinations E of classes are available?
A.3
B.6
C.E=7
D.E=9
Answer: D.E=9
Explanation: I think it should be E only.
No where it is given that he attends different classes on each day.
Experts please provide your views.
--- EDITED my Response. It was a typo. I meant 12 is the answer.
If only Day 1 : 3 options
If Day 1 and Day 2 : 3*3 = 9 Options
So, Total = 3+9= 12.
Question: How many independent words can 'HEARTLESS' be divided into without changing the order of the letters and using each letter only once ?
A.1
B.2
C.5
D.3
Answer: D.3
Explanation: Explanation:
The words are HE, ART and LESS.
Answer: D) 3
Question: A cylinder has a base with a circumference of 20pi meters and an equilateral triangle inscribed on the interior side of the base. A marker is dropped into the tank with an equal probability of landing on any point on the base. If the probability of the marker landing inside the triangle is (Sqrt 3)/4 , what is the length of a side of the triangle?
A.3(sqrt 2pi)
B.3(sqrt 3pi)
C.10*sqrt (pi)
D.10(sqrt 3pi)
Answer: C.10*sqrt (pi)
Explanation: Prob of marker landing in the triangle = area of triangle / area of base = sqrt(3)/4
Circumference of base = 20pi meters
=> Radius of base = 10 meters
=> Area of base = 100 pi sq m
Therefore area of the triangle = 100 pi * sqrt(3)/4
As the area of an equilateral triangle is sqrt(3)*(side^2)/4,
any side of the triangle = 10*sqrt(pi)
ANSWER:C
Question: Ten years ago, the age of Anand was one-third the age of Bala at that time. The present age of Bala is 12 years more than the present age of Anand. Find the present age of Anand?
A.22
B.16
C.82
D.27
Answer: B.16
Explanation: Explanation:
Let the present ages of Anand and Bala be 'a' and 'b' respectively.
a - 10 = 1/3 (b - 10) --- (1)
b = a + 12
Substituting b = a + 12 in first equation,
a - 10 = 1/3 (a + 2) => 3a - 30 = a + 2
=> 2a = 32 => a = 16.
Answer: B
Question: Solve: 387 x 387 + 114 x 114 + 2 x 387 x 114
A.251001
B.251000
C.251010
D.250101
Answer: A.251001
Explanation: = (387)2+ (114)2+ (2 x 387x 114)
= a2 + b2 + 2ab, where a = 387,b=114
= (a+b)2 = (387 + 114 )2 = (501)2 = 251001.
Answer is A
Question: There are d cities. What is the number of airlines that connected 2 different cities (airline from city A to city B is different with airline from city B to city A)?
A.n(n-1)
B.n(n+1)
C.d(d-1)
D.n(n+1)/2
Answer: C.d(d-1)
Explanation: First of all, the possible number of airlines is d. Then, the possible number of airlines departing from one city to another becomes (d-1). Hence, the answer is d(d-1), C
Question: For any integer n greater than 1, #n denotes the product of all the integers from 1 to n, inclusive. How many prime numbers E are there between #6 +2 and #6 +6 , inclusive?
A.None
B.One
C.Two
D.Three
Answer: A.None
Explanation: None is the answer. A.
Because for every k 6! + k :: k, because 6! :: k, since k is between 2 and 6.A
Question: A man cheats while buying as well as while selling. While buying he takes 10% more than what he pays for and while selling he gives 20% less than what he claims to. Find the profit percent, if he sells at 12% below the cost price of the claimed weight.
A.19.81%
B.21%
C.37.5%
D.25%
Answer: B.21%
Explanation: There is a one step calculation method too. It requires more thought but is faster.
The man takes 10% more than what he pays for. So if he claims to take 100 pounds, he pays $100 but he actually takes 110 pounds for which he will take from the customer $110. Hence, in effect, there is a 10% mark up.
While selling, he sells 20% less. This means, he claims to sell 100 pounds and gets $100 but actually sells only 80 pounds and should have got only $80 for it. So this is again a mark up of $20 on $80 which is 25%.
But he also sells at 12% less
(1 + m1%)(1 + m2%)(1 - d%) = (1 + p%)
11/10 * 5/4 * 22/25 = (1 + p%)
profit % = 21%
B
Question: For an employee to qualify for early retirement at a certain company, the sum of the employee’s age and years of service must be at least 75, If Sue was K years old when she was hired by the company, what is the minimum age at which she could possibly qualify for early retirement.
A.K+35
B.2K+35
C.(75+K)/2
D.(70-K)/2
Answer: C.(75+K)/2
Explanation: Say Sue was hired when she was already 75 years old (k=75), then she could retire right away, at the age of 75. Now, plug k=75 in the answer choices and see which yields 75. Only C fits.
Answer: C.
Question: A number when divided by 5 gives a number which is 8 more than the remainder obtained on dividing the same number by 34. Such a least possible number N is
A.74
B.N=75
C.N=175
D.N=680
Answer: B.N=75
Explanation: I solved this question by plugging in numbers from the answer choices.
A.) 74
Starting with answer choice A, I immediately eliminated it because 74 is not even divisible by 5.
B.) 75
I divide 75/5 and get 15 as an answer. I divide 75/34 and get a remainder of 7.
15-7 = 8 so I know the correct answer isB
Question: A jeep takes 9 hours to cover a distance of 480 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
A.48 Kmph
B.52 Kmph
C.35 Kmph
D.63 Kmph
Answer: C.35 Kmph
Explanation: Time = 9
Distance = 480
3/2 of 9 hours = 9 * 3/2 = 13.5 Hours
Required speed = 480/13.5 = 35 Kmph
C)
Question: The ratio of the volumes of two cubes is 1728 : 2197. What is the ratio of their total surface areas?
A.12:18
B.144:169
C.44:22
D.28:144
Answer: B.144:169
Explanation: Ratio of the sides = Â³âˆš1728 : Â³âˆš2197
= 12 : 13
Ratio of surface areas =144:169
Answer: B
Question: Points A, B, and, C have xy-coordinates (2,0), (8,12), and (14,0), respectively. Points X, Y, and Z have xy-coordinates (6,0), (8,4), and (10,0), respectively. What fraction S of the area of triangle ABC is the area of triangle XYZ?
A. 1/9
B. 1/8
C. 1/6
D. 1/5
Answer: A. 1/9
Explanation: If you notice, both triangles ABC and XYZ have a side on X axis. we can take these sides as bases for each triangle, therefore
Area of ABC is 1/2*12*12 (Height of ABC is the y coordinate of the third point (8,12))
similarly Area of XYZ is 1/2*4*4
dividing area of XYZ with that of ABC gives S=1/9.A
Question: a and b are two numbers selected randomly from 1,2,3.... 25 what is the probability of a and b are not equal.
A.1/25
B.24/25
C.13/25
D.2/25
Answer: B.24/25
Explanation: No of events=625((1,1),(1,2).......(25,25))
Probability of getting a&b are equal=(25/625)[(1,1),(2,2),(3,3).....(25,25)]
Probability of a and b or not equal=1-(25/625)
=600/625
=24/25
ANSWER:B
Question: Effective annual rate of interest corresponding to nominal rate of 6% per annum compounded half
yearly will be
A.6.09%
B.6.10%
C.6.12%
D.6.14%
Answer: A.6.09%
Explanation: Explanation:
Let the amount Rs 100 for 1 year when compounded half yearly, n = 2, Rate = 6/2 = 3%
Amount=100(1+3100)2=106.09
Effective rate = (106.09 - 100)% = 6.09%
Answer: A
Question: if log102 = 0.3010, what is the value of log101600 ?
A.3.208
B.3.202
C.3.209
D.3.204
Answer: D.3.204
Explanation: Explanation:
log101600
= log10(16 × 100)
= log10(16) + log10(100)
= log10(24) + log10(102)
= 4 log10(2) + 2
= (4 × 0.3010) + 2
= 1.204 + 2
= 3.204
Answer: Option D
Question: In 165 litres of mixtures of milk and water, water is only 28%. The milkman sold 40 litres of this mixture and then he added 30 litres of pure milk and 13 litres of pure water in the remaining mixture. What is the percentage of water in the final mixture?
A.29.35%
B.28. 57%
C.24. 57%
D.27. 75%
Answer: B.28. 57%
Explanation: Initially, milk = 118.2 l, and water = 46.2 l.
40 liters is withdrawn in same ratio as it was initially, i.e., 72:28.
Remaining milk = 90 l, and water = 35 l.
Now add 30 l of milk and 13 liter of water.
Then milk = 120 l and water = 48 l.
Percentage of water = 48*100/168 = 28.57 %
ANSWER:B
Question: John weighs twice as much as Susan. Susan's weight is 60% of Sam's weight. Mark weighs 50% of Lynn's weight. Lynn weighs 180% of John's weight. Which of these 5 people weighs the least?
A.John
B.Susan
C.Sam
D.Mark
Answer: B.Susan
Explanation: John weighs twice as much as Susan --> J=2S --> John cannot weigh the least;
Susan's weight is 60% of Sam's weight --> S=0.6*Sam --> Sam cannot weigh the least;
Mark weighs 50% of Lynn's weight --> M=0.5*L --> Lynn cannot weigh the least;
Lynn weighs 180% of John's weight --> L=1.8*J --> John cannot weigh the least (we already know that);
As you can see the answer is either Susan (S) or Mark (M). To compare their weights we should express their weights in regards of the same person: M=0.5*L=0.5*(1.8*J)=0.9*J and from J=2S, S=0.5*J --> Susan weights the least: Susan's weight is 50% of that of John and Mark's weight is more than 50%of that of John.
Answer: B.
Question: At the start of an experiment, a certain population consisted of 3 animals. At the end of each month after the start of the experiment, the population size was double its size at the beginning of that month. Which of the following represents the population size at the end of 9 months?
A. 2^3
B. 3^2
C. 2(3^10)
D. 3(2^9)
Answer: D. 3(2^9)
Explanation: 3*2^n where n is the #of month --> 3*2^9 Answer (D)
Question: Some part of a 50% solution of acid was replaced with an equal amount of 30% solution of acid. If, as a result, 40% solution of acid was obtained, what part of the original solution was replaced?
A.1/5
B.1/4
C.1/2
D.3/4
Answer: C.1/2
Explanation: Original Removed Added Result
Concentration 0.50 0.50 0.70 0.60
Amount 1 x x 1
Multiply 0.50 0.50x 0.70x 0.60
0.50 (Original amount) - 0.50x (Removed) + 0.70x (Added) = 0.60 (End Result)
0.20x = 0.10
x = 1/2
ANSWER:C
Question: Machine A takes 20 hours to complete a certain job and starts that job at 6AM. After four hour of working alone, machine A is joined by machine B and together they complete the job at 1PM. How long would it have taken machine B to complete the job if it had worked alone for the entire job?
A.9.99
B.3,615
C.3.62
D.4.62
Answer: D.4.62
Explanation: Let us assume total job = 100 units
A finishes 100 units in 20 hrs(given)
Hence A (working rate)= 5 units /hr
Now Given that A works for 4 hr( so 20 units done) then A and B finish total work in 7 hours. Hence A and B finish 80 units in 3 hours. Of these 3x5=15 units were done by A. Hence B did 65 units in 3 hours.
Hence B(working rate)= 65/3 units /hr
Hence B takes 100x3/65 = 4.62 hours to complete the job.
Answer D.
Question: A school has received 60% of the amount it needs for a new building by receiving a donation of $600 each from people already solicited. People already solicited represent 40% of the people from whom the school will solicit donations. How much average contribution is requited from the remaining targeted people to complete the fund raising exercise?
A.$200
B.$177.78
C.$100
D.$277.78
Answer: D.$277.78
Explanation: Let the amount school needs = X
Let total people school plans to solicit = T
School has received 60 % of X => (3/5) X
People already solicited = 40% of T => (2/5) T
Now, as per the information given in the question :
(3/5)X = $400 . (2/5) . T --------------------------- 1
Remaning Amount is 40 % i.e ( 2/5 ) X ------because school has already received 60%
And the remaining people are 60 % i.e (3/5) .T -----because 40% of the people are already solicited
So, average contribution required from the remaining targeted people is
(2/5) X = (Amount required) . (3/5) . T ----------------------------------- 2
Divide eqn 1 by eqn 2
Amount required = $277.78
D
Question: A store owner estimates that the average price of type A products will increase by 15% next year and that the price of type B products will increase by 18% next year. This year, the total amount paid for type A products was $4600 and the total price paid for type B products was $8400. According to the store owner's estimate, and assuming the number of products purchased next year remains the same as that of this year, how much will be spent for both products next year?
A.$15,202
B.$15,325
C.$16,000
D.$16,225
Answer: A.$15,202
Explanation: cost of type A products next year = 1.15 * 4600 = 5290
cost of type B products next year = 1.18 * 8400 = 9912
total 5290 +9912 = 15202
ANSWER:A
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
A.866 m
B.255 m
C.245 m
D.167 m
Answer: C.245 m
Explanation: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30
= 25/2 => 2(130 + x)
= 750 => x
= 245 m.
Answer:C
Question: A train 125m long takes 6 sec to cross a man walking at 5kmph in a direction opposite to that of the train. Find the speed of the train?
A.65kmph
B.70kmph
C.75kmph
D.80kmph
Answer: B.70kmph
Explanation: Let the speed of the train be x kmph
Speed of the train relative to man = x+5 = (x+5)*5/18 m/sec
125/[(x+5)*5/18] = 6
30(x+5) = 2250
x = 70kmph
Answer is B
Question: A jar of 312 marbles is divided equally among a group of marble-players today. If 2 people joined the group in the future, each person would receive 1 marble less. How many people are there in the group today?
A.18
B.20
C.22
D.24
Answer: D.24
Explanation: 312 = 24*13 = 26*12
There are 24 people in the group today.
The answer is D.
Question: A person incurs a loss of 5% be selling a watch for Rs. 1140. At what price should the watch be sold to earn 5% profit.
A.2227
B.1788
C.1260
D.2889
Answer: C.1260
Explanation: Explanation:
Let the new S.P be x, then
(100 - loss%) : (1st S.P.) = (100 + gain%) : (2nd S.P.)
\inline \fn_jvn {\color{Black} \Rightarrow (\frac{95}{1140}=\frac{105}{x})}
\inline \fn_jvn {\color{Black} \Rightarrow x=1260}
Answer: C) Rs.1260
Question: The population of a town increased from 50,000 to 80,000 in a decade. The average percent increase of population per year is :
A.4.37%
B.5%
C.6%
D.8.75%
Answer: C.6%
Explanation: Solution
Increase in 10 year= (80000 - 50000) = 30000.
Increase% =(30000/50000x 100 )% = 60%
âˆ´ Required average = ( 60/10 )% = 6%
Answer C
Question: If (x + 1)^2 = 144, which of the following could be the value of 2x?
A.–26
B.–13
C.–10
D.12
Answer: A.–26
Explanation: You can also get to the answer by backsolving using answer choices
Starting with choice B = -13
(x + 1)^2 = 144
(-13 + 1)^2 = 144 =====> (-12)^2 = 144 Bingo, Clearly, among the answer choices only -13 will result in 144 in the equation so x must be -11,
Then 2x = 2 * -13 = -26
Answer: A
Question: A trader sells 78 meters of cloth for Rs. 6788 at the profit of Rs. 29 per metre of cloth. What is the cost price of one metre of cloth?
A.22
B.75
C.60
D.58
Answer: D.58
Explanation: SP of 1m of cloth = 6788/78 = Rs. 87
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 87 - Rs. 29 = Rs. 58.
Answer: D
Question: Special codes are designated by either a 6-letter or a 7-letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different codes that can be designated with this system?
A.2 (26)^7
B.26(26)^6
C.27(26)^6
D.26(26)^7
Answer: C.27(26)^6
Explanation: 26^6+26^7 = 26^6(1+26)=27*26^6
The answer is C.
Question: In a certain alphabet, 11 letters contain a dot and a straight line. 24 letters contain a straight line but do not contain a dot. If that alphabet has 40 letters, all of which contain either a dot or a straight line or both, how many letters contain a dot but do not contain a straight line?
A.5
B.8
C.14
D.20
Answer: A.5
Explanation: We are told that all of the letters contain either a dot or a straight line or both, which implies that there are no letters without a dot and a line (no line/no dot box = 0).
First we find the total # of letters with lines: 11 +24 = 35;
Next, we find the total # of letters without line: 40 - 35 = 5;
Finally, we find the # of letters that contain a dot but do not contain a straight line: 5 - 0 = 5.
A
Question: 5 x 1.6 - 2 x 1.4/1.3 = ?
A.0.2
B.0.9
C.1.4
D.4
Answer: D.4
Explanation: Given Expression
= (8 - 2.8)/1.3
= 5.2/1.3
= 52/1.3
= 4.
Answer is D.
Question: A company, Chauncy Co., has an annual travel budget of $54,000. The accounting department estimates that transportation expenses will increase 5 percent in the coming year, and nontransportation travel expenses will increase by 15 percent in the coming year. Last year, Chauncy Co. spent $19,500 on transportation-related expenses, and $35,000 on nontransportation travel expenses. If the annual travel budget does not increase this year, and if the accounting department’s estimates are correct, how far over the annual travel budget will expenses be this year?
A.Expenses will not go over the budget.
B.$500
C.$4,225
D.$6,725
Answer: D.$6,725
Explanation: annual travel budget of $54,000
Let, Transportation expenses = T = 19500
and Non-Transportation expenses = N=35000
i.e. Increased Transportation expenses = 1.05T = 20475
and Increased Non-Transportation expenses = 1.15N = 40250
Total Expense = 20475+40250 = 60725
Expense over Budget = Budget - expense = 54000-60725 = 6725
Answer: Option D
Question: By selling 100 pencil, a trader gains the cost of 10 Pencil. Find his gain percentage?
A.26 1/3%
B.51 1/3%
C.10%
D.53 1/3%
Answer: C.10%
Explanation: C
10%
Let the CP of each pencil be Rs. 1.
CP of 100 pens = Rs. 100
Profit = Cost of 10 pencil = Rs. 10
Profit% = 10/100 * 100 = 10%
Question: Ifaequals the sum of the even integers from 2 to 20, inclusive, andbequals the sum of the odd integers from 1 to 19, inclusive, what is the value of (a + b)/2?
A.100
B.110
C.105
D.20
Answer: C.105
Explanation: Yes! there is really a faster way to solve it.
Sum of consecutive odd or even integers = (no. of odd or even ints) * (first int + last int) / 2
Here A = sum of even ints from 2 to 20, inclusive
number of even ints = 10,
first int + last int = 2+20 = 22
A = 10*22 / 2 = 110
B = sum of odd ints from 1 to 19, inclusive
number of odd ints = 10,
first int + last int = 1+19 = 20
A = 10*20 / 2 = 100
(A+B)/2 = 110 + 100 = 210/2=105
Ans : C
Question: SHOW TIMER STATISTICS
It takes 3 tons of copper ore and 5 tons of iron ore to make one ton of alloy A. How many tons of alloy A can be made from 60 tons of copper ore and 90 tons of iron ore?
A.18
B.18 3/4
C.20
D.30
Answer: B.18 3/4
Explanation: 3c + 5i = a
60c + 90i = ?
20(3c + 5i) = 60c + 100i = 20a, so the answer has to be less than 20 since we are dealing with 90i.
But, 18(3c + 5i) = 54c + 90i = 18a, here we get 54c < 60c. So answer must be 18 3/4 (B).
ANSWER:B
Question: How long does a train 110 m long traveling at 60 kmph takes to cross a bridge of 340 m in length?
A.18.9 sec
B.88.9 sec
C.22.9 sec
D.27.00 sec
Answer: D.27.00 sec
Explanation: D = 110 + 340 = 450 m
S = 60 * 5/18 = 50/3
T = 450 * 3/50 = 27.00 sec
Answer: D
Question: When an amount was distributed among 14 boys, each of them got $80 more than the amount received by each boy when the same amount is distributed equally among 18 boys. What was the amount?
A.5050
B.5020
C.5040
D.5030
Answer: C.5040
Explanation: Let the total amount be Rs. X the,
x/14 - x/18 = 80 ==> 2x/126 = 80 ==> x/63 = 63 x 80 = 5040.
Hence the total amount is 5040.
Answer C.
Question: If selling price is doubled, the profit triples. Find the profit percent?
A.100%
B.110%
C.120%
D.140%
Answer: A.100%
Explanation: Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
Profit % = x/x	x 100	% = 100%
A)
Question: A man can row upstream at 22 kmph and downstream at 42 kmph, and then find the speed of the man in still water?
A.29
B.92
C.30
D.32
Answer: D.32
Explanation: US = 22
DS = 42
M = (42 + 22)/2 = 32
Answer:D
Question: A batsman's avg in 12 innings is 24.00. If his avg is to be double of the no of innings (15 innings), what should he score in the remaining three innings (avg)?
A.143
B.144
C.145
D.146
Answer: B.144
Explanation: let total runs done by a batsman in 12 innings be x
therefore,
x/12=24 that means x=12*24=288 runs
for 15 innings, avg was doubled i.e.. 48.00
therefore,
(x+y)/15=48 where y is the no of runs done in last 3 innings
y=432
therefore average is 432/3=144
ANSWER:B
Question: A train running at a speed of 60 kmph crosses a pole in 18 seconds.What is the length of the train?
A.120 m
B.300 m
C.190 m
D.150 m
Answer: B.300 m
Explanation: 60 kmph=50/3 m/sec
50/3*18=300 m
ANSWER:B
Question: 1/3 of a certain journey is covered at the rate of 25km/hr,1/4 at the rate of 30 km/hr and the rest is 50 km/hr.the avg speed for the whole journey is :
A.30 km/hr
B.33 km/hr
C.33 1/3 km/hr
D.37 1/12 km/hr
Answer: C.33 1/3 km/hr
Explanation: let assume total distance will be 120km then
distance traveled at teh speed 25km/hr=1/3*120=40km the time=40/25=1.6hrs
distance traveled at the speed 30km/hr=1/4*120=30kmthe time is=30/30=1 hr
then remaining distance is 120-40-30=50km
the time taken to travel 50km=50/50=1hr
so total time is=1.6+1+1=3.6 hrs
so avg speed =120/3.6=33.33km/hr
ANSWER:C
Question: 5,7,13,20,33,53,86,?
A.135
B.139
C.130
D.120
Answer: B.139
Explanation: Each number is the sum of the previous two numbers, ie 53 + 86 = 139.
Answer : B
Question: In a partnership between Rose, Ben and Christine, Rose's capital is Rs.12000. If her share of a profit of Rs.6000 is Rs.3000 and Christine's share is Rs.1250, what is Ben's capital?
A.6200
B.5200
C.4500
D.6240
Answer: A.6200
Explanation: 3000 + 1250 = 330
6000 - 4250 = 1550
3000 ---- 12000
1550---- ? => 6200
ANSWER:A
Question: Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
Year	Item of Expenditure
Salary	Bonus Transport Fuel	Interest on Loans	Taxes
1998	288	98	3.00	23.4	83
1999	342	112	2.52	32.5	108
2000	324	101	3.84	41.6	74
2001	336	133	3.68	36.4	88
2002	420	142	3.96	49.4	98
The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?
A.A)1%
B.B)1.5%
C.C)1.25%
D.D)3%
Answer: A.A)1%
Explanation: Required percentage
=(288 + 342 + 324 + 336 + 420)
=	[	17	x 100	]	%
1710
~= 1%.
Answer : A
Question: Find the average of the series : 80, 320, 100, 328 and 147?
A.174
B.195
C.190
D.185
Answer: B.195
Explanation: Average = (80 + 320 + 100 + 328 + 147)/5
= 975/5
= 195
Answer: B
Question: At what price must an article costing Rs.200 be marked in order that after deducting 10% from the list price. It may be sold at a profit of 20% on the cost price?
A.62.5
B.62.0
C.266.67
D.62.1
Answer: C.266.67
Explanation: CP = 200
SP = 200*(120/100) = 240
MP*(90/100) = 240
MP = 266.67
Answer: C