RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The length of a room is 10 m and width is 4.75 m. What is the cost of paying the floor by slabs at the rate of Rs. 900 per sq. metre.
A.25650
B.25750
C.26550
D.42750
Answer: D.42750
Explanation: Area = 10 × 4.75 sq. metre.
Cost for 1 sq. metre. = Rs. 900
Hence total cost = 10 × 4.75 × 900
= 10 × 4275 = Rs. 42750
Answer is D.
Question: Every ten years, the Indian government counts all the people living in the country. Suppose that the director of the census has reported the following data on two neighbouring villages Chota Hazri and Mota Hazri :
Chota Hazri has 4,522 fewer males than MotaHazri.
Mota Hazri has 4,020 more females than males.
Chota klazri has twice as many females as males.
Chota Hazri has 2,910 fewer females than Mota Hazri.
What is the total number of males in Chota Hazri?
A.11,264
B.14,174
C.5,632
D.10,154
Answer: C.5,632
Explanation: Explanation :
Let ‘x’ be the number of males in Mota Hazri.
=> x + 4020 – 2(x – 4522) = 2910 .
=> x = 10154
∴ Number of males in Chota Hazri = 10154 – 4522 = 5632.
Answer : C
Question: A and B start a business with Rs.7000 and Rs.9000 respectively. Hoe should they share their profits at the end of one year?
A.7:9
B.9:7
C.3:9
D.3:1
Answer: A.7:9
Explanation: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
7000 : 9000 => 7:9,Answer: A
Question: How long does a train 110 m long traveling at 60 kmph takes to cross a bridge of 140 m in length?
A.16.5
B.16.0
C.15
D.16.8
Answer: C.15
Explanation: D = 110 + 140 = 250 m
S = 60 * 5/18 = 50/3
T = 250 * 3/50 = 15 sec
Answer: C
Question: In a series of football matches, the probability that Team P wins a match against Team Q is 1/5 and the probability that the match ends in a draw is 1/2. If the two teams play five matches, what is the probability that all five matches end in a draw?
A.1/64
B.1/32
C.1/16
D.1/8
Answer: B.1/32
Explanation: P(5 draws)=(1/2)^5=1/32
The answer is B.
Question: What is the 2532nd position of the number in the sequence
1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4,1,1,1,2,2,2,2,2,2,3,3,3,3,3,3,3,3,3,4,4,4,4,4,4,4,4,4,4,4,4,…..
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: 10,20,30,40...
10(1+2+3----+22)=2530
That mean upto 22 th pos total numbers are 2530
2532 th numner must be 1..
ANSWER:A
Question: If 4^(2x + 2) = 16^(3x − 1), what is the value of x ?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: 2^(4x+4) = 2^(12x-4)
4x+4=12x−4
x=1
Answer B
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
A.1/455
B.1/467
C.1/427
D.1/419
Answer: A.1/455
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue
= ³C₃/¹⁵C₃
= (1 * 3 * 2 * 1)/(15 * 14 * 13)
= 1/455
Answer: A
Question: In a building there are 5 rooms.Each having a equal area .The length of the room is 4m and breadht is 5 m.The height of the rooms are 2m. If 17 bricks are needed to make a square meter then how many bricks are needed to make the floor of a particular room ?
A.320
B.340
C.300
D.330
Answer: B.340
Explanation: Explanation :
Area of the floor = 4m x 5m = 20 m2
17 bricks are needed to make 1 m2 area.
So to make 20 m2 no of bricks needed = 17 x 20 = 340
Answer : B
Question: Working alone, machine X can manufacture 1,000 nails in 10 hours. Working together, machines X and Y can manufacture 1,000 nails in 5 hours. How many hours does it take machine Y to manufacture 1,000 nails working alone?
A.3 9/17
B.5 1/3
C.10
D.11 1/5
Answer: C.10
Explanation: rate of machine x = 1000/10
(1000/10 + y)5=1000
y=100
100 * t = 1000
t=10
C.
Question: Two good train each 250 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km / hr and 30 km /hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
A.12 sec
B.24 sec
C.48 sec
D.60 sec
Answer: B.24 sec
Explanation: Sol.
Relative Speed = (45 + 30) km / hr
= (75 x 5 / 18) m/sec
= (125/6) m/sec.
Distance covered = (250 + 250) m = 1000 m.
Required time = (500 x 6 / 125) sec = 24 sec.
Answer B
Question: A train 360 m long is running at a speed of 36 km/hr. In what time will it pass a bridge 140 m long?
A.50 sec
B.29 sec
C.26 sec
D.27 sec
Answer: A.50 sec
Explanation: Speed = 36 * 5/18 = 10 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 1/10
= 50 sec
Answer: A
Question: A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
A.648
B.849
C.600
D.849
Answer: C.600
Explanation: Explanation:
D = 30 * 5 = 150
RS = 40 – 30 = 10
T = 150/10 = 15
D = 40 * 15 = 600 km
Answer: Option C
Question: Walking across campus, a student interviewed a group of students. 25% of the students took a finance class last semester, 45% took a marketing class last semester, and 50% took neither a finance nor a marketing class last semester. What percent of the students in the group took both a finance and a marketing class?
A.60%
B.50%
C.20%
D.15%
Answer: C.20%
Explanation: {Total} = {finance} + {marketing} - {both} + {neither}
100 = 25 + 45 - {both} + 50
{both} = 20%.
The answer is C.
Question: 10 distinct integers are arranged in ascending order. The range of the first 7 is 25 and that of last 7 is 30. What is the maximum range U of the 10 numbers?
A.25
B.27
C.30
D.52
Answer: D.52
Explanation: Positions: 1 2 3 4 5 6 7 8 9 10
Given: 1st position = x; 4th position = a; 7th position = y; 10th position = b
y - x = 25
Let x be 0 and y = 25. We are asked to maximize the range and the integers are distinct.
b - a = 30 --> b = 30 + a
In order to increase the range, we have to maximize the value of 'b'.
'b' can be maximized by taking the max value of 'a'.
From the assumed values, maximum value of 'a' can be 22.
Therefore, b = 30 + 22 = 52
Range U= 52 - 0 = 52
Answer: D
Question: Sequence F consists of 16 consecutive integers. If -6 is the least integer in sequence F, what is the range of the positive integers in sequence F?
A. 16
B. 15
C. 9
D. 8
Answer: D. 8
Explanation: Since set F consists of 16 consecutive integers and -6 is the least integer then set F is consecutive integers from -6 to 9, inclusive: 9-(-6)+1=16.
The range of positive integers in sequence F is 9-1=8.
Answer: D.
Question: A tourist purchased a total of $1,500 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was three more or three less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
A.$1,230
B.$1,310
C.$1,290
D.$1,270
Answer: A.$1,230
Explanation: Let the number of $10 checks cashed beT
Let the number of $50 checks cashed beF
7 checks cashed;
T+F=7
Now; T can be F+3 OR T can be F-3
Let's check both conditions;
T=F+3
T+F=7
F+3+F=7
2F=4
F=2
T=5
Value cashed = 2*50+5*10=$150
Let's check the other condition as well;
T=F-3
T+F=7
F-3+F=7
2F=10
F=5
T=2
Value cashed = 5*50+2*10=$270
The more money he cashes, the less loss he incurs. Thus, we must consider the latter case.
Value cashed = $270
Value lost = 1500-270 = $1230
Ans:A
Question: A man buys 100 lts of liquid which contains 25% of the liquid and the rest is water. He then mixes it with 90 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?
A.81
B.75
C.72.63
D.73
Answer: C.72.63
Explanation: 25% in 100 lts is 25. So water = 100-25 = 75 lts. 30% of 90 lts = 27. So water in 2nd mixture = 90-27 = 63 lts. Now total quantity = 100 + 90 = 190 lts. Total water in it will be 75 + 63 = 138 lts. % of water = (100*138)/190 = 72.63
ANSWER:C
Question: What will be the next sequence in this series?
10,24,130,336,1342,_____?
A.2174
B.2184
C.2284
D.2884
Answer: B.2184
Explanation: 2^3 + 2 = 10
3^3 - 3 = 24
5^3 + 5 = 130
7^3 - 7 = 336
11^3 + 11 = 1342
2,3,5,7,11,13,... prime no.s
next is ( 13^3 - 13 ) = 2184
ANSWER:B
Question: A grocer has a sale of Rs. 6345, Rs. 6927, Rs.6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
A.Rs. 3000
B.Rs. 4991
C.Rs. 5991
D.Rs. 6001
Answer: B.Rs. 4991
Explanation: Sol.
Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562)
= Rs. 34009.
∴ Required sale = Rs.[(6500 x 6) - 34009]
= Rs. (39000 - 34009)
= Rs. 4991.
Answer B
Question: What is the CP of Rs 100 stock at 9 discount, with 1/5% brokerage?
A.96.9
B.96.3
C.91.2
D.96.7
Answer: C.91.2
Explanation: Explanation:
Use the formula,
CP= 100 â€“ discount + brokerage%
CP= 100-9+1/5
91.2
Thus the CP is Rs 91.2.
ANSWER: C
Question: By travelling at 40 kmph, a person reaches his destination on time. He covered two-third the total distance in one-third of the total time. What speed should he maintain for the remaining distance to reach his destination on time?
A.20 kmph
B.15 kmph
C.17 kmph
D.16 kmph
Answer: A.20 kmph
Explanation: Let the time taken to reach the destination be 3x hours. Total distance = 40 * 3x = 120x km
He covered 2/3 * 120x = 80x km in 1/3 * 3x = x hours So, the remaining 40x km, he has to cover in 2x hours. Required speed = 40x/2x
=20 kmph.
Answer: A
Question: If s, t, and p are consecutive integers such that s > t > p and the sum of s, t, and p is a multiple of 10, which of the following could be the value of s?
A.0
B.1
C.9
D.10
Answer: B.1
Explanation: We're given a very specific set of restrictions in this prompt:
1) S, T and P are CONSECUTIVE INTEGERS
2) S > T > P
3) S+T+P = a multiple of 10
We're asked which of the 5 answer COULD be the value of S given these restrictions. Rather than staring at the screen or doing layered math, we canbrute forcethe answers until we find one that fits these restrictions..
Answer A: S = 0
In this case, the numbers would be 0, -1, and -2. The sum = -3 which is NOT a multiple of 10. Eliminate A.
Answer B: S = 1
In this case, the numbers would be 1, 0, and -1. The sum = 0 which IS a multiple of 10. B IS the answer.
Final Answer:
B
Question: Divide Rs.32000 in the ratio 1:9?
A.12000, 20000
B.12000, 200098
C.12000, 20007
D.3200, 28800
Answer: D.3200, 28800
Explanation: 1/10 * 32000 = 3200
9/10 * 32000 = 28800
Answer: D
Question: In a certain game, you perform three tasks. You flip a quarter, and success would be heads. You roll a single die, and success would be a even. You pick a card from a full playing-card deck, and success would be picking a ten with red color card. If exactly one of these three tasks is successful, then you win the game. What is the probability of winning?
A.9/104
B.51/104
C.25/52
D.1/52
Answer: B.51/104
Explanation: Event(1): Probability of getting head in a flip of coin = 1/2
Event(2): Probability of getting even in a roll of dice = 3/6 = 1/2
Event(3): Probability of getting ten with red color in a pack of card = 2/52 = 1/26
Probability of winning is having exactly one successful event is:
P(success 1)* P(Fail 2)* P(Fail 3) + P(Fail 1)* P(Success 2)* P(Fail 3) + P(Fail 1)* P(Fail 2)* P(Success 3)
= 1/2*1/2*25/26 +1/2*1/2*25/26 +1/2*1/2*1/26
=25/104 + 25/104 +1/104
=51/104
Answer :B
Question: When tossing two coins once, what is the probability of heads on both the coins?
A.1/4
B.1/2
C.3/4
D.None of these
Answer: A.1/4
Explanation: Total number of outcomes possible when a coin is tossed = 2 (∵ Head or Tail)
Hence, total number of outcomes possible when two coins are tossed, n(S) = 2 × 2 = 4
(∵ Here, S = {HH, HT, TH, TT})
E = event of getting heads on both the coins = {HH}
Hence, n(E) = 1
P(E) = n(E)n(S)=1/4
Answer is A
Question: One night 20 percent of the female officers on a police force were on duty. If 100 officers were on duty that night and half of these were female officers, how many female officers were on the police force?
A.90
B.180
C.250
D.500
Answer: C.250
Explanation: Let total number of female officers in the police force = F
Total number of officers on duty on that night = 100
Number of female officers on duty on that night = 100/2 = 50
(20/100)*F =50
=>F = 250
Answer C
Question: What is the greater of the two numbers whose product is 2496, given that the sum of the two numbers exceeds their difference by 64?
A.A)96
B.B)108
C.C)110
D.D)78
Answer: D.D)78
Explanation: Let the greater and the smaller number be g and s respectively.
gs = 2496
g + s exceeds g - s by 64 i.e., g + s - (g - s) = 64
i.e., 2s = 64 => s = 32.
g = 2496/s = 78.
ANSWER:D
Question: On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
A.Tuesday
B.Monday
C.Sunday
D.Wednesday
Answer: C.Sunday
Explanation: The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.
Hence, this day is Sunday.
Answer: Option C
Question: The function f is defined for all positive integers n by the following rule: f(n) is the number of positive integers each of which is less than n and has no positive factor in common with n other than 1. If p is prime, then f(p) =
A.P-1
B.P-2
C.(P+1)/2
D.(P-1)/2
Answer: A.P-1
Explanation: This question is wordy and confused me at first. If P is prime it's only factors are P and 1. So no number below it will have a common factor with it except 1. Therefore answer should just be P-1.
ANS = A
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1680?
A.1500
B.2777
C.2889
D.27670
Answer: A.1500
Explanation: 1680 = P [1 + (5*12/5)/100]
P= 1500.Answer:A
Question: 21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement.
A.5/34
B.3/37
C.9/42
D.5/41
Answer: C.9/42
Explanation: The probability that first toy shows the even number,
=1021=1021
Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.
Hence, probability that second toy shows the even number,
=920=920
Required probability,
=(1021)×(920)=(1021)×(920)
=9/42
C
Question: The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?
A.8m
B.7m
C.5m
D.2m
Answer: D.2m
Explanation: Let the sides of the rectangle be l and b respectively.
From the given data,
(√l2 + b2) = (1 + 108 1/3 %)lb
=> l2 + b2 = (1 + 325/3 * 1/100)lb
= (1 + 13/12)lb
= 25/12 lb
=> (l2 + b2)/lb = 25/12
12(l2 + b2) = 25lb
Adding 24lb on both sides
12l2 + 12b2 + 24lb = 49lb
12(l2 + b2 + 2lb) = 49lb
but 2(l + b) = 28 => l + b = 14
12(l + b)2 = 49lb
=> 12(14)2 = 49lb
=> lb = 48
Since l + b = 14, l = 8 and b = 6
l - b = 8 - 6 =2m.
Answer:D
Question: Find the value of 582964 x 99999 = m?
A.58210607666
B.58310607896
C.58295817036
D.58591650836
Answer: C.58295817036
Explanation: 582964 x 99999 = 582964 x (10000 - 1)
= 582964 x 100000 - 582964 x 1
= 58296400000 - 582964
= 58295817036
C
Question: Maddie has 4 apples, if she give 2 to mike, how many does she have left?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: 4-2=2
B. 2
Question: The distance of the college and home of Rajeev is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed (or increased) speed of Rajeev?
A.60 km/h
B.10 km/h
C.60 km/h
D.20 km/h
Answer: D.20 km/h
Explanation: Explanation:
Let the normal speed be x km/h, then
x = 16 km/h
(x + 4) = 20 km/h
Therefore increased speed = 20 km/h
Answer: D
Question: loga(ab)=x then logb(ab) is
A.x/x-1
B.x/x+1
C.x(x-1)
D.x(x+1)
Answer: A.x/x-1
Explanation: loga(ab)=x
log(ab)/log(a)=x
log(b)/log(a)=x-1
log(a)/log(b)=1/x-1
1+log(a)/log(b) = 1+ 1/x-1
logb(ab) = x/x-1
ANSWER A
Question: The greatest possible length which can be used to measure exactly the length 9m, 4m 90cm, 11 m 20 cm is
A.15 cm
B.25 cm
C.10 cm
D.12 cm
Answer: C.10 cm
Explanation: Explanation:
Required Length = H.C.F of 900 cm, 490 cm and 1120 c
= 10 cm. Answer: C
Question: For any positive number x, the function [x] denotes the greatest integer less than or equal to x. For example, [1] = 1, [1.367] = 1 and [1.999] = 1. If k is a positive integer such that k^2 is divisible by 45 and 80, what is the units digit of k^3/4000 ?
A.0
B.1
C.27
D.54
Answer: D.54
Explanation: Factorization of 45 = 3*3*5
Factorization of 80 = 5 * 2^4
Means the smallest value of K is \sqrt{3^2*5*2^4}=3*5*2^2
K^3=3^3*5^3*2^6*X=3^3*2*4000*X where X can be any integer
K^3/4000=3^3*2*X=54X which obviously has different units digit depending on X
ANSWER:D
Question: A 2-year certificate of deposit is purchased for W dollars. If the certificate earns interest at a n annual rate of 6 percent compound quarterly, which of the following represents the value, in dollars, of the certificate at the end of 2 years?
A.k(1.06)^2
B.k(1.06)^8
C.k(1.015)^2
D.W(1.015)^8
Answer: D.W(1.015)^8
Explanation: Annual Rate of interest= 6%
Quaterly rate of interest= 6/4% = 1.5%
Now, periods of compounding in 2 years= 8 (8 quarters)
Thus W(1.015)^8
Answer: D
Question: If difference between compound interest and simple interest on a sum at 10% P.a. for 2 years is Rs.65 then sum is
A.s.5000
B.s.6500
C.s.5800
D.s.6000
Answer: B.s.6500
Explanation: p(r/100)^2=C.I-S.I
P(10/100)^2=65
6500
ANSWER:B
Question: Find the number of zeroes in the expression 15*32*25*22*40*75*98*112*125
A.9
B.8
C.7
D.6
Answer: A.9
Explanation: Maximum power of 5 in the above expression can be calculated like this. Count all the powers of 5 in the above expression. So number of zeroes are 9.
Answer: A
Question: A trader marks his books 10% more than the cost price. If he allows 20% discount, then find his gain or loss percent?
A.2% profit
B.12% loss
C.4% loss
D.No profit No loss
Answer: B.12% loss
Explanation: Let CP of an book = 100
MP of an book = 110
Discount 20 % on 110 = 22
SP of the book = 110 - 22 = 88
LOSS = 12%
Answer : B
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?
A.33/67
B.33/91
C.33/19
D.33/18
Answer: B.33/91
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is
= ¹²C₄/¹⁵C₄
= (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12)
= 33/91
Answer: B
Question: Robin is traveling from one end of a forest to the other. In order to find her way back, she is leaving morsels of bread in the following pattern: 2 morsels of wheat, 3 morsels of white, and 1 morsel of rye. The pattern repeats after she leaves the morsel of rye. If Robin drops 1994 morsels of bread, what are the last 3 morsels of bread that she drops?
A.R,w,w
B.wheat − wheat − white
C.white − rye − wheat
D.white − white − white
Answer: A.R,w,w
Explanation: Q is nothing BUT asking about remainder..
total morsels thrown before the pattern is repeated = 2+3+1 = 6..
so REMAINDER when 1994 is div by 6..
1992 is EVEN and also div by 3, so remainder is 2..
Last 3 of morsels are 1992-1993-1994
so he uses the last of morsel of pattern in 1992 two of the first morsels of the pattern in 1993 and 1994, and the pattern is w, w, W, W, W, R..
ans R-w-w
A
Question: A rectangular of certain dimensions is chopped off from one corner of a larger rectangle as shown. AB = 8 cm and BC = 4 cm. The perimeter of the figure ABCPQRA (in cm) is :
A.24
B.28
C.36
D.48
Answer: A.24
Explanation: Solution
Required perimeter = (AB + BC +CP + PQ + QR + RA)
= AB + BC + (CP + QR) + (PQ + RA)
= AB + BC + AB + BC = 2(AB + BC)
= [2(8 + 4 )] cm = 24 cm. Answer A
Question: Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/8 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent?
A.11/30
B.29/60
C.17/24
D.19/30
Answer: C.17/24
Explanation: Let s assume the platinum card spending limit =x
Gold card spending limit will be =x/2
balance on gold card is =x/2*1/3=x/6
Platinum card unspent limit is= x-1/8x=7/8x
So if gold card balance is transferred then the rest unspent will be
7/8x-x/6=17/24x
So the ans is C
Question: At a certain laboratory, chemical substance are identified by an unordered combination of three different colors. If no chemical may be assigned the same three colors as any other, what is the maximum number of substances that can be identified using seven colors?
A.21
B.35
C.105
D.135
Answer: B.35
Explanation: Combinations = N!/[K!(N-K)!] where N is the total number of items and K is the size of the subgroup
Here, we have 7 colors and we're choosing combinations of 3. Plugging those values in, we get...
7!/(3!4!) = (7)(6)(5)/(3)(2)(1) = (7)(5) = 35 combinations of 3 colors.
Final Answer:B
Question: A sum of money at simple interest amounts to Rs. 840 in 3 years and to Rs. 854 in 4 years. The sum is:
A.647
B.798
C.654
D.847
Answer: B.798
Explanation: S.I. for 1 year = Rs. (854 - 840) = Rs. 14.
S.I. for 3 years = Rs.(14 x 3) = Rs. 42.
Principal = Rs. (840 - 42) = Rs. 798.
Answer:B
Question: A hardware store purchased tools at 1/4 of their list price and sold them for 75% of the list price. What is his percent gain?
A.75
B.125
C.200
D.225
Answer: C.200
Explanation: Cost = 1/4 List Price = .25*LSale = .75 List Price = .75*LGain Ratio = (Sale - Cost) / Cost = (.75*L - .25*L) / .25*L = .5*L / .25*L = 2.0Gain Percent = 100 * Gain Ratio = 100 * 2.0 = 200% = Answer C
Question: A football coach must choose 5 freshers from a team of 11 players. How many different ways can the coach choose the freshers?
A.462
B.650
C.729
D.800
Answer: A.462
Explanation: Choose 5 starters from a team of 11 players. Order is not important.
\inline {\color{Black} 11C_{5}}=462
A
Question: The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 756. What is the banker's discount?
A.1240
B.1120
C.1190
D.1806
Answer: D.1806
Explanation: Explanation :
TD = (BG ×100)/TR = (756×100)/(6×12) = Rs. 1050
BG = BD – TD
=> 756 = BD - 1050
=> BD = 1050+ 756 = 1806 Answer : Option D
Question: The smallest number when increased by " 1 " is exactly divisible by 2, 8, 24, 36 is:
A.71
B.70
C.72
D.73
Answer: A.71
Explanation: LCM = 72
72 - 1 = 71
ANSWER:A
Question: A house wife saved $5 in buying an item on sale. If she spent $48 for the item, approximately how much percent she saved in the transaction?
A.8%
B.9%
C.10%
D.11%
Answer: C.10%
Explanation: Actual price = 48+5 = $53
Saving = 5/48 * 100 = 100/11 = 10% approximately
Answer is C
Question: Which of the following numbers is the largest?
A.10000-100
B.2-10000
C.1000-1000
D.5-4000
Answer: B.2-10000
Explanation: The choices are a little easier to compare written this way:
(a) (104)100 = 10400 (b) (210)1000 > (103)1000 = 103000 (c) (103)1000 = 103000
(d) (54)1000 < (103)1000 = 103000 (e) (32)1000 < 101000
The answer is clear
correct answer B
Question: Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years
A.306.09
B.306.07
C.306.04
D.306.03
Answer: C.306.04
Explanation: A = 5000(51/50)3
= 5306.04
5000
-----------
306.04
Answer:C
Question: A certain sum of money at simple interest amounted Rs.640 in 10 years at 3% per annum, find the sum?
A.442.3
B.492.3
C.592.3
D.402.3
Answer: B.492.3
Explanation: 640 = P [1 + (10*3)/100]
P = 492.30
ANSWER:B
Question: By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 30%?
A.s.429
B.s.480
C.s.429
D.s.488
Answer: D.s.488
Explanation: SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 30% = 30% of 640 = Rs.192
SP = CP - Loss = 640 - 192
= Rs.448
Answer:D