RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8748, its purchase price was
A.Rs.12008
B.Rs.12000
C.Rs.12002
D.Rs.1229
Answer: B.Rs.12000
Explanation: Explanation:
= Rs.12000
Answer: B
Question: On the x-y coordinate plane there is a parabola, y=x(6-x). Which of the following points is in the region that is enclosed by this parabola and the x-axis?
I. (1, 6) II. (3, 11) III. (5, 4)
A.I only
B.II only
C.III only
D.I and II
Answer: C.III only
Explanation: Since co-efficient of x^2 is negative, the parabola will be downward facing. So the parabola and the x axis will enclose some points where the y-values of the parabola are positive.
When x = 1, y = 5 lies on the parabola, so (1, 6) will not be enclosed by the parabola and x axis.
When x = 3, y = 9 lies on the parabola, so (3, 11) will not be enclosed by the parabola and x axis.
When x = 5, y = 5 lies on the parabola, so (5, 4) will be enclosed by the parabola and x axis.
The answer is C.
Question: In some quantity of ghee, 50% is pure ghee and 50% is vanaspati. If 20kg of pure ghee is added, then the strength of vanaspati ghee becomes 30%. The original quantity was?
A.25
B.15
C.30
D.45
Answer: C.30
Explanation: Let the original quantity be x
then, vanaspati ghee in xkg = 50x/100 kg= x/2kg
(x/2)/(x+20) = 30/100
x/(2x+40) = 3/10
x = 30
Answer is C
Question: Raj goes to market to buy oranges. If he can bargain and reduce the price per orange by Rs.2, he can buy 30 oranges instead of 20 oranges with the money he has. How much money does he have ?
A.28
B.2
C.6
D.8
Answer: B.2
Explanation: Explanation: Let the money with Raj is M. So M/20−M/30=M/20−M/30=2. Check options. Option D satisfies.
Answer:B
Question: A side of beef lost 25 percent of its weight in processing. If the side of beef weighed 540 pounds after processing, how many pounds did it weigh before processing?
A.191
B.355
C.720
D.840
Answer: C.720
Explanation: Let weight of side of beef before processing = x
(75/100)*x = 540
=> x = (540 * 100)/75 = 720
Answer C
Question: A restaurant meal cost $36.50 and there was no tax. If the tip was more than 10 percent but less than 15 percent of the cost of the meal, then total amount paid must have been between:
A.$40 and $42
B.$39 and $42
C.$38 and 40
D.$37 and $39
Answer: A.$40 and $42
Explanation: let tip=t
meal cost=36.50
range of tip = from 10% of 36.5 to 15% of 36.5 = 3.55 to 5.325
hence range of amount paid= 36.5+T= 40.05 to 41.825
ANSWER:A
Question: There is 60 lit of milk and water in which milk forms 84%.Howmuch water must be added to this solution to make it solution in which milk forms 50%
A.40.8
B.19.75
C.20.75
D.21.75
Answer: A.40.8
Explanation: 60*84/100=50.40 lit milk that is 9.60 lit water
let x lit water will be added then
(60+x)*50/100=50.40
so x=40.8
ANSWER:A
Question: On a certain transatlantic crossing, 40 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 50 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?
A.40%
B.50%
C.60%
D.80%
Answer: D.80%
Explanation: Let T be the total number of passengers.
Let x be the number of people with round trip tickets.
0.4T had round trip tickets and took their cars.
0.5x had round trip tickets and took their cars.
0.5x = 0.4T
x = 0.8T
The answer is D.
Question: 12 men complete a work in 9 days. After they have worked for 6 days, 6 more men join them. How many days will they take to complete the remaining work?
A.2 days
B.7 days
C.8 days
D.9 days
Answer: A.2 days
Explanation: 1 man's 1 day work = 1/108
12 men's 6 day's work = 1/9 * 6 = 2/3
Remaining work = 1 - 2/3 = 1/3
18 men's 1 day work = 1/108 * 18 = 1/6
1/6 work is done by them in 1 day.
1/3 work is done by them in 6 * 1/3 = 2 days.
Answer:A
Question: Find the invalid no.from the following series 3, 7, 15, 31 , 63, 127, 257
A.3
B.7
C.257
D.63
Answer: C.257
Explanation: Go on multiplying the number by 2 and adding 1 to it to get the next number.So, 257 is wrong.
C
Question: Find a positive number, which when increased by 8 is equal to 128 times reciprocal of the number.
A.5
B.6
C.8
D.7
Answer: C.8
Explanation: Explanation:
Let the number be x. Then,
x + 8 = 128 x (1/x) => x<sup>2</sup> + 8x - 128 = 0
=> (x + 16)(x - 8) = 0
=> x = 8
Answer: Option C
Question: If x and y are positive integers, then x/y is
A.Always even
B.Always odd
C.Even whenever x+y is Even
D.Odd whenever x and y is odd
Answer: D.Odd whenever x and y is odd
Explanation: x and y are positive integers, then x/y is
Let's take odd as 25 and odd as 5.
IMO option B is correct answer..
If you consider your fourth scenario, that turns out to be even.
Hence option D should be correct.
Question: 1395 x 1395 = ?
A.A)1951609
B.B)1946025
C.C)1951602
D.D)1951603
Answer: B.B)1946025
Explanation: 1395 x 1395	= (1395)2
= (1400 - 5)2
= (1400)2 + (5)2 - (2 x 1400 x 5)
= 1960000 + 25 - 14000
= 1960025 - 14000
= 1946025.
Answer:B
Question: A circular logo is enlarged to fit the lid of a jar. The new diameter is 50 per cent larger than the original. By what percentage has the area of the logo increased?
A.50
B.80
C.100
D.125
Answer: D.125
Explanation: Let old diameter be 4 , so radius is 2
Old area = 4π
New diameter is 6 , so radius is 3
New area = 9π
Increase in area is 5π
% increase in area = 5/4*100
So, % increase is 125%
Answer will be (D)
Question: A man performs 1/2 of the total journey by rail, 1/3 by bus and the remaining 3km on foot. His total journey is
A.18km
B.10km
C.12km
D.24km
Answer: A.18km
Explanation: Explanation:
Let the journey be x km
Then, 1x/2 + 1x/3 +3 =x
5x +18 =6x
X = 18km
Answer: Option A
Question: The sum of the ages of 5 children born at the intervals of 3 year each is 60 year. what is the age of the youngest child ?
A.4 year
B.6 year
C.10 year
D.None of these
Answer: B.6 year
Explanation: Solution
let the ages of the children be x,(x + 3),(x + 6),(x + 9) and (x + 12) year.
then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 60 â‡” 5 x = 30 â‡” x= 6.
âˆ´ Age of the youngest child = x = 6 years. Answer B
Question: Mani paid a sum of money for purchasing 40 pens, which he recovered in full when he sold 25 of them. What was his percentage of profit or loss per pen?
A.50%
B.60%
C.70%
D.65%
Answer: B.60%
Explanation: B
33.33%
If the sum he paid whilst purchasing 40 pens = A,
Then the Cost Price of each pen = A/40.
Since the amount he got whilst selling 25 pens is also = A
Then the Selling Price of each pen = A/25.
Since Selling Price > Cost Price, he made a profit.
Profit per pen = Selling Price - Cost Price = A/25 - A/40 = 3A/200.
Profit percentage per pen = Profit per pen / Cost per pen x 100 = (3A/200) / (A/40) x 100 = 60%. Answer : B
Question: Narasimha, Madhu and pavan started a business by investing Rs.1,20,000, Rs.1,35,000 and Rs 1, 50,000 respectively. Find the share of Pavan, out of an annual profit of Rs.56,700.
A.21,0009
B.21,008
C.21,000
D.21,002
Answer: C.21,000
Explanation: Explanation:
Ratio of their investments = 120000 : 135000 : 150000 = 8 : 9 : 10
Share of Pavan = 10271027 × 56700 = 21,000
Answer: C
Question: TOM has 13 ten-dollar bills, 11 five-dollar bills, and 17 one-dollar bills. If TOM needs to pay exactly $128, what is the least number of bills he will need to use?
A.557
B.456
C.16
D.577
Answer: C.16
Explanation: 128 is the total sum of money.
as we have 13 10 dollar bills so the closest we can get to 128 using the 10 dollar bills is by using 12 * 10 dollar bils
128-120 = 8
so now we need to get 8 from either 5 dollar bills or 1 dollar bills
8 - 5 (use only 1 5 dollar bill) = 3
so we can get 3 from using 3 $1 bills.
Hence 16 ( 12+1+3 )
ANSWER IS C
Question: Which of the following is a composite number ?
A.2
B.7
C.15
D.13
Answer: C.15
Explanation: Clearly 15 is a composite number. All others are prime. Ans : C
Question: What is the least value of x, So that 2x5472 is divisible by 9
A.7
B.8
C.9
D.3
Answer: A.7
Explanation: Explanation:
The sum of the digits of the number is divisible by 9.
Then the number is divisible by 9.
2 + x + 5 + 4 + 7 + 2 = 20 + x
Least value of x may be '7',
So that the total 20 + 7 = 27
is divisible by 9.
Answer: Option A
Question: A searchlight on top of the watchtower makes 4 revolutions per minute. What is the probability that a man appearing near the tower will stay in the dark for at least 5 seconds?
A.5/6
B.4/5
C.3/4
D.2/3
Answer: D.2/3
Explanation: The searchlight completes one revolution every 15 seconds.
The probability that the man's area will be lit up is 5/15=1/3.
The probability that he will stay in the dark is 1-1/3=2/3
The answer is D.
Question: What could be the range of a set consisting of odd multiples of 3?
A.21
B.24
C.35
D.62
Answer: B.24
Explanation: Range = the difference between the greatest and the smallest numbers in the sequence. Our sequence is odd and is a multiple of 7. Every number in that sequence can be represented like this: 3*(2n+1) where n is any positive integer.
Range = 3*(2m + 1) - 3*(2n + 1) = 3*2*(m-n) = 6 * (m-n).
m, n - any positive integers
The answer must be divisible by 6, which is only 24.
The correct answer is B
Question: Marge has 3 pumps for filling her swimming pool. When all 3 pumps work at their maximum rates, the swimming pool is filled in 56 minutes. Pump 1's maximum rate is twice the maximum rate of pump 2 and four times the maximum rate of pump 3. How long would it take Marge to fill the pool if she used only pump 3 at its maximum rate ?
A.2hrs, 48mins
B.6hrs, 32mins
C.7hrs, 12mins
D.13hrs, 4mins
Answer: B.6hrs, 32mins
Explanation: The rate of pump 1 = 4x job/minute.
The rate of pump 2 = 2x job/minute.
The rate of pump 3 = x job/minute.
Given that x+2x+4x=1/56 --> x=1/392 --> (time) = (reciprocal of rate) = 392 minutes = 6 hours and 32 minutes.
Answer: B.
Question: The average age of three boys is 15 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy?
A.6
B.9
C.8
D.4
Answer: B.9
Explanation: 3x + 5x + 7x = 45
x =3
3x = 9
Answer: B
Question: Fill in the sequence:
10 10 22 9 24 8 26 ?
A.1
B.3
C.5
D.7
Answer: D.7
Explanation: D
7
There are two series - 20, 22, 24, 26 and 10, 9, 8, 7.
Question: If it is 7:03 in the evening on a certain day, what time in the morning was it exactly 1,440,706 minutes earlier? (Assume standard time in one location.)
A.7:09
B.7:11
C.7:17
D.7:22
Answer: C.7:17
Explanation: 7:03 minus 1,440,706 must end with 7, the only answer choice which ends with 7 is C.
Answer: C.
Question: If the selling price of 8 articles is same as the cost price of 12 articles. Find the gain or loss percentage?
A.30% gain
B.30% loss
C.50% gain
D.50% loss
Answer: C.50% gain
Explanation: Explanation:
Let the C.P of each article be Re 1. Then,
S.P of 8 articles = C.P of 12 articles = Rs. 12/-
Now, C.P of 8 articles = Rs. 8/-, S.p of 8 articles = Rs 12/-
Gain = Rs ( 12 - 10 ) = Rs 4/-.
Gain% = ( 4/8 * 100 ) % = 50% Gain
Answer: Option C
Question: A train started from station 'A' and proceeded towards station 'B' at a speed of 48 Km/hr. Forty-five minutes later another train started from station 'B' and proceeded towards station 'A' at 50 Km/hr. If the distance between the two stations is 232 Km, at what distance from station 'A' will the trains meet?
A.160KM
B.108KM
C.132KM
D.144KM
Answer: C.132KM
Explanation: Train A started 45 min ago,by the time train B started,
It means Distance covered by the Train A in 45 min is 48*45/60=36km covered,
now remaining distance=196km
since they are moving towards each other relative speed=48+50=98kmph
and time=196/98=2hrs
In 2hrs trainAcovered 96km distance and 36 km already covered
=>96=36=132km
Hence,132 km from station A, trains meet eachother.
ANSWER:C
Question: Find the coordinates
of the midpoint of the line segment joining the points
A(–3,2) and B(7,8)
A.(2,5)
B.(1,5)
C.(2,4)
D.(3,5)
Answer: A.(2,5)
Explanation: mid point of A(x1,y1) and B(x2,y2) can be calculated by
(x1+y1/2,x2+y2/2) hence ((-3+7)/2,(2+8)/2)=(2,5)
ANSWER:A
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
A.225 km/hr
B.50 km/hr
C.99 km/hr
D.88 km/hr
Answer: B.50 km/hr
Explanation: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 => x = 50 km/hr.
Answer: B
Question: A grocery store priced a gallon of milk at 25% above the wholesale price of $4. If a customer comes in with a coupon for 5% off milk, how much does that customer pay?
A.$4.95
B.$4.75
C.$5.05
D.$4.50
Answer: B.$4.75
Explanation: Wholesale cost of milk = $4
Milk was priced at 25% above $4 = $5
% discount given by coupon = 5%
Customer paid = .95 * 5 = $4.75
Answer B
Question: What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?
A.289
B.500
C.188
D.666
Answer: B.500
Explanation: 70 = (P*4*7/2)/100
P = 500
Answer:B
Question: If x and y are even integers, which of the following is an odd integer?
A.xy +3
B.x(y − 2)
C.x(x + 5)
D.3x + 4y
Answer: A.xy +3
Explanation: If a and b are even integers, then:
A. xy + 3: even + odd = odd
B. x(y− 2): even(even) = even
C. x(x+ 5): even(odd) = even
D. 3x + 4y: even + even = even
E. (x + 2)(y + 1): (even)(odd) = even
Answer is A
Question: If a number N is chosen at random from the set of two-digit integers whose digits are both prime numbers, what is the probability W that N is divisible by 3?
A.1/3
B.¼
C.9/25
D.5/16
Answer: D.5/16
Explanation: Prime digits are: 2, 3, 5, 7
Total number of 2 digit #s with both digits prime are: 4*4 = 16
out of these numbers divisible by 3 = 33, 27, 57, 72 and 75. I had to find the numbers manually using the 4 numbers above.
=> prob = 5/16.
Ans D. Took me 3:20 mins.
Question: In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 10 percent of revenues. The profits in 2009 were what percent of the profits in 2008?
A.80%
B.105%
C.120%
D.124.2%
Answer: A.80%
Explanation: x = profits
r= revenue
x/r = 0,1
x= 10
r=100
2009:
r=80
x/80 = 0,10 = 10/100
x= 80*10/100
x= 8
8/10 = 0.8 = 800%, Answer A
Question: An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq m?
A.4882.40
B.8082.40
C.4002.40
D.4082.40
Answer: D.4082.40
Explanation: Explanation:
Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 * 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40
Answer: Option D
Question: A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 7 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
A.9.5
B.9.4
C.9.3
D.9.2
Answer: C.9.3
Explanation: Net part filled in 1 hour = (1/4 - 1/7) = 3/28
The cistern will be filled in 28/3 hrs i.e., 9.3 hrs.Answer: C
Question: A dishonest person wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing 33 $ per litre so as to make a profit of 70% on cost when he sells the resulting milk and water mixture for 36$. In what ratio should he mix the water and milk?
A.1:120
B.67:120
C.67:8
D.8:120
Answer: B.67:120
Explanation: First of all, let's consider 1 liter of the stuff he is going to sell --- naive customers think it's pure milk, but we know it's some milk-water mixture. He is going to sell this liter of milk-water for $36.
This $36 should be a 20% increase over cost. Here, we need to think about percentage increases as multipliers.
Using multipliers
(cost)*1.70 = $36
cost = 36/1.7= 360/12 = $30
If he wants a 70% increase over cost on the sale of one liter of his milk-water, the cost has to be $21.17
Well, a liter of milk costs $33, so if he is going to use just $30 of milk in his mixture, that's 21.17/33 = 120/187 of a liter. If milk is 120/87 of the liter, then water is 67/187 of the liter, and the ratio of water to milk is 67:120. Answer choice(B)
Question: The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 60 percent of the pollutant?
A. $300,000
B. $100,000
C. $50,000
D. $10,000
Answer: A. $300,000
Explanation: To remove 90% of pollutant
C= 100,000(90)/(100-90) = 900,000
To remove 60% of pollutant
C' = 100,000(60)/(100-60) = 600,000
Difference = C - C' = 300,000
Answer - A
Question: A fruit seller sells mangoes at the rate of Rs.13 per kg and thereby loses 25%. At what price per kg, he should have sold them to make a profit of 15%?
A.Rs.11.81
B.Rs.19.93
C.Rs.12.25
D.Rs.12.31
Answer: B.Rs.19.93
Explanation: Solution
75 : 13 = 115 : x
x= (13Ã—115/75)
= Rs.19.93
Hence, S.p per Kg	= Rs.19.93
Answer B
Question: Beverley rode 5 1/4 miles in 1 hours and 30 minutes. What was her average rate of speed in miles per hour?
A.3
B.3 1/4
C.3 1/2
D.3 3/4
Answer: D.3 3/4
Explanation: D = 5(1/4) = 21/4
T = 1(1/2) = 3/2 = 6/4
S = D/T = 3 3/4
Answer = D
Question: In a class of 50 students, 20 play SNOOKER, 15 play Cricket and 11 play Football. 7 play both SNOOKER and Cricket, 4 play Cricket and Football and 5 play SNOOKER and football. If 18 students do not play any of these given sports, how many students play exactly two of these sports?
A.10
B.12
C.34
D.45
Answer: A.10
Explanation: Notice that7 play both SNOOKER and Cricket does not mean that out of those 7, some does not play Football too. The same for Cricket/Football and SNOOKER/Football.
[color=#ffff00]{Total}={SNOOKER}+{Cricket}+{Football}-{HC+CH+HF}+{All three}+{Neither}For more check ADVANCED OVERLAPPING SETS PROBLEMS
[/color]
50=20+15+11-(7+4+5)+{All three}+18 --> {All three}=2;
Those who play ONLY SNOOKER and Cricket are 7-2=5;
Those who play ONLY Cricket and Football are 4-2=2;
Those who play ONLY SNOOKER and Football are 5-2=3;
Hence, 5+2+3=10 students play exactly two of these sports.
Answer: A.
Question: How many numbers from 2 to 8 are exactly divisible by 2?
A.A)2
B.B)4
C.C)5
D.D)7
Answer: B.B)4
Explanation: 2/2 = 1 and 8/2 = 4
4- 1 = 3
3 + 1 = 4 Numbers.
Answer : B
Question: If set A={2,2,2,....,n times} , set B={3,3,3,3....m times} and set C={13,13,13...k time} , then in terms of m,n and k , how many possible subsets from sets A,B, and C can be created ?
A.a) k(n+m+mn)+ k
B.b) (1+n+m+mn)(k+1)
C.c) k^2(mn+n/m)
D.d) kmn(k+m+n)
Answer: B.b) (1+n+m+mn)(k+1)
Explanation: a) how many 2's are included?
b) how many 3's are included?
and
c) how many 11's are included?
For the number of 2, we could have zero 2's, or one 2, or two 2's, all the way up to n 2's. That's (n + 1) possibilities for the 2's. Similarly, (m + 1) possibilities for the 3's and (k + 1) possibilities for the 11's. We simply multiply these three numbers.
NOTICE that one set, the set that includes no 2's, no 3's, and no 11's, is included. This is known in mathematics as thenull set, sometimes called the empty set, a set with no members. Technically, this is a subset of every possible set, but that's a technical detail of set theory that goes well beyond what the GMAT would expect students to know. Even the the calculation is not that difficult, some of the technical aspects of this question are not in line with the GMAT's expectations.
The number of subsets is (m + 1)(n + 1)(k + 1). The answer is not given in that form. Instead, the first two factors have been FOILed together:
(mn + m + n + 1)(k + 1).
Mike
B
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train?
A.150
B.872
C.287
D.288
Answer: A.150
Explanation: Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 9 = 150 meter
Answer:A
Question: Cecilia, Robbie, and Briony all bought stamps. The number of stamps Cecilia purchased was equal to a single digit. The number of stamps only one of them purchased was divisible by 7. The number of stamps one of them bought was an even number. Which of the following could represent the numbers of stamps each purchased?
A.3, 8, 24
B.7, 9, 17
C.6, 9, 12
D.5, 15, 18
Answer: D.5, 15, 18
Explanation: I didnt get your point on eliminating D.
The number of stamps only one purchased was divisible by 7.Could that not be Cecilia with 9 stamps.
I choose this and marked D.
Question: The profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448. What should be the sale price for making 45% profit?
A.$480
B.$450
C.$928
D.$870
Answer: C.$928
Explanation: Let C.P. = $ x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 145% of $ 640 = $ 928.
C
Question: If the sides of a cube are in the ratio 9:5. What is the ratio of their diagonals?
A.9:5
B.16:9
C.4:
D.3:4
Answer: A.9:5
Explanation: Explanation:
Diagonal of a Cube=a√3 where a is side
a1:a2 = 9:5
d1:d2 = 9:5 where√3 cancelled both side
ANSWER:A
Question: Both Robert and Alice leave from the same location at 8:00 a.m. driving in the same direction, but in separate cars. Robert drives 60 miles per hour while Alice drives 80 miles per hour. After 6 hours, Alice’s car stops. At what time will Robert’s car reach Alice’s car?
A.1 p.m.
B.3 p.m.
C.4 p.m.
D.8 p.m.
Answer: C.4 p.m.
Explanation: 8:00 am so 6 hours later is 2:00 pm
In six hours, Robert will have driven 6*60 = 360 miles
In six hours, Alive will have driven 6*80 = 480 miles
So Robert needs 480-360 = 120 miles do catch Alice up.
So at 60 mph, he will need 2 hours
2:00 pm + 2 hours = 4:00 pm
ANS : C
Question: X percents of the rooms are suits, Y percent of the rooms are painted light blue. Which of the following best represents the least percentage of the light blue painted suits?
A.X-Y
B.Y-X +100
C.100X-Y
D.X+Y-100
Answer: D.X+Y-100
Explanation: Using the simple formula
100 = X + Y - BOTH - > Here X = % of Suits , Y = % of light blue painted rooms and BOTH = % of suits painted in light blue colour
So now, BOTH = X+Y -100 and now you can manipulate the value of X and Y to get the max and minimum values.
Hence Answer D
Question: In a store, the profit is 320% of the cost. If the cost increases by 25% but the SP remainsconstant, approximately what %of the sp is the profit?
A.30%
B.70%
C.80%
D.90%
Answer: B.70%
Explanation: Let C.P. = Rs. 100. Then, profit = Rs. 320, S.P. = Rs. 420
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 420
Profit = 420 - 125 = Rs. 295
Required percentage = 295/420 * 100 = 1475/21 = 70%
B
Question: ashok and pyarelal invested money together in a business and share a capital of ashok is 1/9 of that of pyarelal.if the incur a loss of Rs 1000 then loss of pyarelal?
A.600
B.700
C.800
D.900
Answer: D.900
Explanation: Let the capital of Pyarelal be x, then capital of Ashok=x/9
So ratio of investment of Pyarelal and Ashok = x : x/9 =9x : x
Hence out of the total loss of 1000, loss of Pyarelal= 1000*9x/10x=900
ANSWER:D
Question: A and B start from Opladen and Cologne respectively at the same time and travel towards each other at constant speeds along the same route. After meeting at a point between Opladen and Cologne, A and B proceed to their destinations of Cologne and Opladen respectively. A reaches Cologne 40 minutes after the two meet and B reaches Opladen 70 minutes after their meeting. How long did A take to cover the distance between Opladen and Cologne?
A.1 hour
B.1 hour 10 minutes
C.2 hours 30 minutes
D.1 hour 20 minutes
Answer: D.1 hour 20 minutes
Explanation: v1 and V2 are speeds.
v1.t /70 = v2
v2.t/40 = v1
v1/v2 = 7/4
which train A would 70. 4/7 mins to cover the same distance
40 + 40 = 80 mins (ANS D)