RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Due to 10% decrease in the price of sugar and John can buy 5kg more sugar in Rs100 , then find the CP of sugar?
A.Rs. 1(2/9)
B.Rs. 2(2/9)
C.Rs. 2(1/9)
D.Rs. 4(2/9)
Answer: B.Rs. 2(2/9)
Explanation: Here r = 10 % ,x = 100 and A = 5 kg
Actual price of sugar = 10*100/((100-10 )*5) = Rs. 2(2/9)
B
Question: A work which could be finished in 9 days was finished 3 days earlier after 10 more men joined. The number of men employed was?
A.8
B.9
C.10
D.20
Answer: C.10
Explanation: x ------- 6
(x + 10) ---- 3
x * 6 = (x + 10)3
x = 10
ANSWER:C
Question: 36 is divided in 2 parts such that 8 times the first part added to 3 times the second part makes 203. What is the first part?
A.19
B.88
C.267
D.26
Answer: A.19
Explanation: Explanation:
Let the first part be x.
8x + 3 (36 – x) = 203
8x + 108 – 3x = 203
5x + 108 = 203
5x = 95
x = 19
ANSWER: A
Question: In a nationwide poll, N people were interviewed. If 1/5 of them answered yes to question 1, and of those, 1/4 answered yes to question 2, which of the following expressions represents the number of people interviewed who did NOT answer yes to both questions?
A.N/9
B.8N/9
C.19N/20
D.31N/40
Answer: C.19N/20
Explanation: The number of people who answered yes to both questions is (1/4)(1/5)N = N/20
The number of people who did not answer yes to both is 1 - N/20 = 19N/20
The answer is C.
Question: The cost price of 60 articles is the same as the selling price of x articles. If the profit is 20%, what is x?
A.42
B.45
C.48
D.50
Answer: D.50
Explanation: Let the cost price = y
The cost price of 60 articles = 60y
The selling price of x articles = 1.20y*x
1.20y*x = 60y
x = 60 / 1.2 = 50
The answer is D.
Question: 2 – [2 – {2 – 2 (2 + 2)}] = ?
A.-4
B.4
C.6
D.None of these
Answer: D.None of these
Explanation: Solution
Given exp. = 2 - [2-{2-2×4}]
= 2 -[2-{2-8}]
= 2-[2-(-6)]
= 2-[2+6]
= 2-8
= -6
Answer D
Question: How many D ways are there of placing 6 marbles in 4 bowls, if any number of them can be placed in each bowl?
A.6C4
B.6P4
C.4^6
D.6^4
Answer: C.4^6
Explanation: Each marble has 4 options, so there are total of D=4*4*4*4*4*4=4^6 ways.
Answer: C.
The total number of ways of dividing n identical items among r persons, each one of whom, can receive 0,1,2 or more items is (n+r -1)C(r-1).
Question: Martin buys a pencil and a notebook for 80 cents. At the same store, Gloria buys a notebook and an eraser for 75 cents, and Zachary buys a pencil and an eraser for 35 cents. How many cents would it cost to buy three pencils, three notebooks, and three erasers? (Assume that there is no volume discount.)
A.285
B.295
C.305
D.315
Answer: A.285
Explanation: pencil + notebook = 80
notebook + eraser = 75
pencil + eraser = 35
Let's add all three equations.
2 pencils + 2 notebooks + 2 erasers = 190 cents
The cost to buy 3 of each would be (3/2)(190) = 285
The answer is A.
Question: judith is practicing her dance steps along with her friends. In a particular sequence, all of them form a row. At that point, judithis standing on the 8th position from either end of the row.
Can you find out how many girls are practicing together?
A.4
B.9
C.15
D.16
Answer: C.15
Explanation: As judith is 8th from either end of the row, it means that 7 girls are on one of her sides and 7 are present on the other.
7 + 7 + 1(judith herself) =15.
Hence, 15 girls are practicing the dance together.
correct answer is C)15
Question: One hundred multiples of seven are chosen at random, and 200 multiples of eight are chosen at random. Approximately what percentage of the 300 selected numbers are odd?
A.34.33%
B.16.67%
C.35.33%
D.36.33%
Answer: B.16.67%
Explanation: --> Multiples of 7 are 7, 14, 21, 28, 35, 42....
Out of first 4 multiples, 2 are odd; out of first 6 multiples, 3 are odd.
So approx. 50 % of the 100 multiples are odd i.e 50 multiples.
--> Similalrly, for 8 multiples are:8,16,24...
All are even so 0 % are odd.
Total odd= (50+0)/(100+200)= 50/300=(1/6) = 16.67%
Answer B
Question: A piece of work can be done by Ram and shyam in 12 days, By shyam Nad hari in 15 days and by hari and ram in 20 days. Ram alone can complete the work in how much days ?
A.30
B.35
C.25
D.32
Answer: A.30
Explanation: Rate*Time = Work
Since the work done is same throughout the question so we can take the work done as 1
Let Rate of Ram be R, Hari be H and Shaym be S
A piece of work can be done by Ram and shyam in 12 days
When Ram and Shyam will work together then their rate will be added. So combined rate will be R+S
(R+S)*12 = 1
R+S = 1/12 ...(1)
By shyam And hari in 15 days
Similarly
S+H = 1/15 ...(2)
hari and ram in 20 days
Similarly
H+R = 1/20 ...(3)
(2)-(3)
S+H - (H+R) = 1/15 - 1/20
=> S-R = 1/60 ..(4)
(1) - (4)
R + S - (S - R) = 1/12 - 1/60 = 4/60 = 1/15
2R = 1/15 => R = 1/30
Ram alone can complete the work in how much days ?
R * t = 1
t = 1/R = 1/ (1/30) = 30 days
So, Answer will be A
Question: There are 97 lights which are functional and each is controlled by a separate On/Off switch. Two children A and B start playing with the switches. A starts by pressing every third switch till he reaches the end. B, thereafter, presses every fifth switch till he too reaches the end. If all switches were in Off position at the beggining, How many lights are switched On by the end of this operation?
A.29
B.49
C.39
D.59
Answer: C.39
Explanation: Editing my solution:
Number of switches = 97
Number of switches turned on by A: 3, 6, ... 96 = 32
Number of switches turned on by B: 5, 10, ....95 = 19
Few switches are turned on by A and later turned off by B: LCM(3,5) = 15x = 15, 30,....90 = 6.
Subtract the above 6 switches from both A and B as they are turned off.
Number of switches that are turned on = (32 - 6) + (19 - 6) = 39
Answer: C
Question: Lucy invested $10,000 in a new mutual fund account exactly three years ago. The value of the account increased by 10 percent during the first year, increased by 5 percent during the second year, and decreased by 20 percent during the third year. What is the value of the account today?
A.$10,350
B.$9,240
C.$10,500
D.$11,500
Answer: B.$9,240
Explanation: Value after 1 year: 10,000 * 1.1 = 11,000
Value after 2 years: 11,000 * 1.05 = 11,550
Value today: 11,550 * 0.8 = 10,395
Answer B is correct.
Question: If Harsh sold a match ticket for Rs.340 at a profit of 25%, at what price did he purchased the ticket?
A.280
B.255
C.300
D.272
Answer: D.272
Explanation: Explanation:
Cost price = Selling price/(1 + profit percent)
= 340/(1 + 0.25) = 340/1.25
= Rs.272
ANSWER D
Question: The ratio of the volumes of two cubes is 125 : 216. What is the ratio of their total surface areas?
A.13:18
B.8:12
C.1:12
D.8:17
Answer: A.13:18
Explanation: Ratio of the sides = ³√125 : ³√216
= 5 : 6
Ratio of surface areas = 52:62
= 13:18
Answer: A
Question: Which of the following Equation is NOT equivalent to 25x^2 = y^2 - 4?Which of the following Equation is NOT equivalent to 25x^2 = y^2 - 4?
A.25x^2 + 4 = y^2
B.75x^2 = 3y^2 - 12
C.25x^2 = (y + 2)(y - 2)
D.5x = y - 2
Answer: D.5x = y - 2
Explanation: Let's Solve the given equation first
25x^2 = y^2 - 4
i.e. (5x)^2 - y^2 = -4
i.e. y^2 - (5x)^2 = 4
Let's Check the Options:
A) 25x^2 + 4 = y^2
This equation can be re-written as
25x^2 = y^2 - 4 which is same as Equation given in question hence Option ELIMINATED
B) 75x^2 = 3y^2 - 12
Divide the equation by 3 on both sides, we get
25x^2 = y^2 - 4 which is same as Equation given in question hence Option ELIMINATED
C) 25x^2 = (y + 2)(y - 2)
This equation can be re-written as
25x^2 = y^2 -2y+2y - 4
i.e. 25x^2 = y^2 - 4 which is same as Equation given in question hence Option ELIMINATED
D) 5x = y - 2 Hence, The correct Answer Option
E) x^2 = (y^2 - 4)/25
Multiply the equation on both sides by 25
i.e. 25x^2 = y^2 - 4 which is same as Equation given in question hence Option ELIMINATED
ANSWER:D
Question: X and Y started a business by investing Rs.36000 and Rs.42000 respectively after 4 months Z joined in the business with an investment of Rs.48000, then find share of Z in the profit of Rs.13970 ?
A.3200
B.4064
C.3250
D.3825
Answer: B.4064
Explanation: Ratio of investment, as investments is for different time.
Investment x Number of units of time.
Ratio of investments X : Y : Z = 36000 : 42000 : 48000 => 6 : 7 : 8.
X = 6 x 12 Months = 72, Y = 7 x 12 = 84, Z = 8 X 8 = 64 => 18 : 21 : 16.
Ratio of investments => X : Y : Z = 18 : 21 : 16.
Investment Ratio = Profit sharing Ratio.
Z = 13970 Ã— 16/55 = Rs.4064.
Share of Z in the profit is Rs.4064.
Option B
Question: If a= 3b, where b is a prime number greater than 2, how many different positive even divisors does a have, including a?
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: b is prime greater than 2 thus b is odd
3b is odd
Thus no even factors
Ans:A
Question: Total of ages of A,B and C at present is 90 years. If ratio of this ages is 3 : 3 : 4 what will be the age of C after 5 years?
A.45 years
B.42 years
C.40 years
D.41 years
Answer: D.41 years
Explanation: 3+3+4=10
4*(90/10)=36yrs
after 5yrs=41
ANSWER:D
Question: In a series of six consecutive even numbers, the sum of the second and sixth numbers is 24. What is the fourth number?
A.10
B.12
C.14
D.16
Answer: B.12
Explanation: B
12
Let the numbers be x, x + 2, x + 4, x + 6, x + 8 and x + 10.
Given (x + 2) + (x + 10) = 24
=> 2x + 12 = 24 => x = 6
The fourth number = x + 6 = 6 + 6 = 12.
Question: If f(x)=5x+6 and g(y)=2y^2+ 8y-5 then g(f(x))
A.52x^2+36x+85
B.50x^2+160x+115
C.85x^2+85x+85
D.68x^2+87x+69
Answer: B.50x^2+160x+115
Explanation: g(f(x))=2(5x+6)^2+8(5x+6)-5 =2(25x^2+60x+36)+40x+48-5 = 50x^2+120x+72+40x+43
=50x^2+160x+115
Answer is B
Question: Simplify :(log 75/16-2 log 5/9+log 32/243)
A.log 1
B.log 2
C.log 3
D.log 4
Answer: B.log 2
Explanation: log 75/16-2 log 5/9+log 32/243
= log 75/16-log(5/9)^2+log32/243
= log 75/16-log25/81+log 32/243
=log((75/16*32/243)/(25/81))
= log(75/16*32/243*81/25)=log 2
ANSWER:B
Question: A flagstaff 17.5 m high casts a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be
A.12.5 m
B.10m
C.17.5m
D.21.25m
Answer: A.12.5 m
Explanation: Let the height of the building x metres.
Less lengthy shadow, Less in the height (Direct Proportion)
40.25 : 28.75 :: 17.5 : x
40.25 * x = 28.75 * 17.5
x =	(28.75 x 17.5)/40.25
x = 12.5
Answer is A.
Question: Find the average of first 20 multiples of 7?
A.73.5
B.65.8
C.75.9
D.75
Answer: A.73.5
Explanation: Required average = 7(1+2+3---+20)/20 = 7*20*21/20*2 = 147/2 = 73.5
Answer is A
Question: A part-time employee whose hourly wage was increased by 10 percent decided to reduce the number of hours worked per week so that the employee's total weekly income would remain unchanged. By what percent should the number of hours worked be reduced?
A.9.09
B.10
C.11
D.12
Answer: A.9.09
Explanation: Let original hourly wage be x and let the no of hours worked be y
Total wage will be =x*y
After the increment the wage will be=1.1 x
Now we need to find number of hours worked so that
x*y=1.1x*z i.e z=x* y/1.1x= 1/1.1 y
%decrease = (y-1/1.1y)/y *100= 1-1/1.1 *100 =9.09%
Thus my answer is A.
Question: Given that p is a positive even integer with a positive units digit, if the units digit of p^3 minus the units digit of p^2 is equal to 0, what is the units digit of p + 4?
A.7
B.8
C.10
D.11
Answer: C.10
Explanation: p is a positive even integer with a positive units digit--> the units digit of p can be 2, 4, 6, or 8 -->
In order the units digit of p^3 - p^2 to be 0, the units digit of p^3 and p^2 must be the same. Thus the units digit of p can be 0, 1, 5 or 6.
Intersection of values is 6, thus the units digit of p +4 is 6 + 4 = 10.
Answer:C.
Question: The ratio between the radii of two spheres is 1:3. Find the ratio between their volumes?
A.27:1
B.1:27
C.1:9
D.9:1
Answer: B.1:27
Explanation: r1 : r2 = 1:3
r13 : r23 = 1:27
ANSWER:B
Question: Which of the following is a prime number
A.67
B.68
C.69
D.70
Answer: A.67
Explanation: Clearly, 67 is a prime number.
Option A
Question: What will come in place of the x in the following Number series? 6, 12, 21, 33 , 48 , 66 , 87, x
A.33
B.35
C.39
D.111
Answer: D.111
Explanation: The pattern is + 6, + 9, + 12, +15 + 18 +21 + 24 â€¦â€¦â€¦..
So the missing term is = 87 + 24 = 111
Answer : D
Question: What will be the day of the week on 15th August,2010 ?
A.Sunday
B.Monday
C.Tuesday
D.Friday
Answer: A.Sunday
Explanation: Solution
15th August,2010 = (2009 years + Period from 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years +7 ordinary years)
= (2 x 2 + 7 x 1)= 11 odd days = 4 odd days
Jan. Feb. March April May June July Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) =227 days
=(32 weeks + 3 days)=3 odd days.
Total number of odd days =(0 + 0 + 4 + 3)=7 = 0 odd days.
Given day is Sunday . Answer A
Question: n a 1000m race, if A gives B a start of 40m, A wing by 19sec. But if A gives B start of 30sec, B wins by 40m.
Find the time taken by B to run 2000m race?
A.300
B.250
C.400
D.450
Answer: B.250
Explanation: then 960/B -1000/A = 19 => 24/B - 25/A = 19/40
and 1000/B - 960/A = 30 => 25/B - 24/A = 30/40
solving equation A speed =8 and B=20/3
for 1000m b will take 2000/20/3= 250 sec
B
Question: 9, 16, 21, 25, 36,49
A.9
B.16
C.21
D.25
Answer: C.21
Explanation: Each of the numbers except 21, is perfect square.
Answer: Option C
Question: If the distance between A and B is 100m and that of B and C is 500. Then what is the distance between A and C ?
A.600m
B.more than 600m
C.Between 500m and 600m
D.700m
Answer: A.600m
Explanation: those options r not valid for all conditions.
because if A,B,C are on a straight line then the distance between A and C is may be minimum 400m or maximum 600m
ANSWER:A
Question: In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/3 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented?
A.50
B.70
C.100
D.130
Answer: D.130
Explanation: Rented = 4/7*490 = 280.
Rented two-bedroom = 6/7*280 = 240;
Rented one-bedroom = 1/7*280 = 40 (or 280-240=40).
Rented one-bedroom units are 1/3 of all one-bedroom: 1/3*{All one bedroom} = 40 --> {All one-bedroom} = 120
{All two-bedroom} = 490 - 120 = 370.
Two-bedroom not rented = 370 - 240 =130
Answer: D.
Question: How many positive integers less than 5,000 are evenly divisible by neither 18 nor 21?
A.4,514
B.4,475
C.4,521
D.4,428
Answer: D.4,428
Explanation: integers less than 5000 divisible by 18 5000/18 =333.something , so 333
integers less than 5000 divisible by 21 5000/21 = 238.## , so 238
we have double counted some, so take LCM of 18 and 21 =105 and divide by 5000, we get 47. so all numbers divisible by 18 and 21 = 333 +238 -47 =524
now subtract that from 4999. 4999- 524 = 4428 answer D.
Question: 5 people are sitting in a 4 seat row watching a football game. At halftime they all get up. When they return, they each randomly sit down on one of the 4 chairs. What is the likelihood that none of the 4 end up sitting in the same chair that they sat in during the first half?
A.3/24
B.9/120
C.15/24
D.18/24
Answer: B.9/120
Explanation: Originally seated A B C D
now when after they get up and when they sit back again .
1st- A has option to sit on 3 seats ( apart from his previous seat . thus he now sits on B's seat.)
2nd- Similarly B has option to sit on 3 seats ( because A has already occupied B's previous seat, thus B sits on a's seat.)
3rd- Now C has only 1 option to sit on D's seat . and similarly D also has one option to sit on C's seat.)
hence total favourable outcomes 3*3*1*1=9
and total possible outcomes =5!=120
probability of the favourable outcome= 9/120. B
Question: Three faces of a fair die are Yellow, three faces red and one blue.The die is tossed three
times. The probability that the colours, yellow, red and blue appear in the first, second and
third tosses respectively is
A.1/36
B.1/24
C.1/32
D.1/37
Answer: B.1/24
Explanation: Probability of getting yellow color = P(Y) = 3/6 = 1/2
Probability of getting red color = P(R) = 3/6 = 1/2
Probability of getting blue color = P(B) = 1/6
So, the probability that the colors yellow, red and blue appear in first, second and third toss respectively= P(Y ∩ R ∩ B) = P(Y) x P(R) x P(B) = 1/2 x 1/2 x 1/6 = 1/24
ANSWER:B
Question: Surface area of two spheres are in the ratio 1:4 what is the ratio of their volumes?
A.1:9
B.1:8
C.1:3
D.1:4
Answer: B.1:8
Explanation: 1:8
Answer: B
Question: For positive integers n, the integer part of the nth term of sequence E equals n, while the infinite decimal part of the nth term is constructed in order out of the consecutive positive multiples of n, beginning with 2n. For instance, E_1 = 1.2345678…, while E_2 = 2.4681012… The sum of the first seven terms of sequence E is between:
A.28 and 29
B.29 and 30
C.30 and 31
D.31 and 32
Answer: C.30 and 31
Explanation: First, construct the first seven terms, though only out to a few decimal places, following the given pattern.
E_1 = 1.23…
E_2 = 2.46…
E_3 = 3.69…
E_4 = 4.812…
E_5 = 5.10…
E_6 = 6.12…
E_7 = 7.14…
Now, to add up the first seven terms, you should be strategic about how many decimal places to keep. You can drop the hundredths place and get a good approximation with the tenths place—and if you find the sum too close to a boundary between choices, then you can refine your answer if necessary.
1.2 + 2.4 + 3.6 + 4.8 + 5.1 + 6.1 + 7.1 = 30.3
Including more decimal places would only add a couple of tenths to the sum—not enough to tip the sum over 31.
The correct answer is C.
Question: A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?
A.11 days
B.13 days
C.20 3/17 days
D.21 days
Answer: B.13 days
Explanation: Explanation:
Ratio of times taken by A and B = 100:130 = 10:13
Suppose B takes x days to do the work.
x = (23 * 13)/10 = 299/10
A's 1 day work = 1/23; B's 1 day work = 10/299
(A + B)'s 1 day work = (1/23 + 10/299) = 1/13
A and B together can complete the job in 13 days.
ANSWER IS B
Question: Nancy works 3 days per week at a rate of x dollars per day. If Nancy works more than 3 days per week, any extra days are paid at double her normal rate. Nancy worked 2 weeks with no overtime, and then worked 3 more weeks, each with y days of overtime. Which of the following represents Nancy’s total earnings over this period?
A.a) 3x(2y+5)
B.b) 3x+12y
C.c) 3xy(7x+2)
D.d) 3x(2y+7)
Answer: A.a) 3x(2y+5)
Explanation: Payment of a week for 3 days a week = $3x
Payment of 4 weeks for 3 days a week = $3x*2 = $6x
Payment of a week for y days overtime a week = $3x+$2xy
Payment of 3 weeks for y days overtime a week = ($3x+$2xy)*3
Total Earnings = $6x + ($3x+$2xy)*3 = 15x+6xy = 3x(2y+5)
Answer: option A
Question: In a race of length L metres, Johnson beats Lewis by Y metres and Greene by N metres, By how many metres does Lewis beat Greene in the same race ? (Y<N)
A.L(L-N) / L-Y
B.L(N-Y) / L-Y
C.L-N
D.Y-N
Answer: B.L(N-Y) / L-Y
Explanation: As the time is constant, the ratio of distances will be the same as the ratio of speeds.
If Sj,Sl,Sg are the speeds of Johnson, Lewis, and Greene respectively, then
Sj/Sl = L/(L-Y)
and Sj/Sg = L/(L-N)
=> Sg/Sl = (L-N)/(L-Y)
Therefore the speeds of Lewis and Greene are in the ratio (L-Y)/(L-N)
When Lewis finishes the race, the time run by him and Greene are same
=> The ratio of the speeds of Lewis and Greene will be the same as the ratio of distances run by them.
=> Distance run by Greene when Lewis finishes the race = (L-N)/(L-Y) * L
=> Lewis beats Greene by L - L*(L-N)/(L-Y) = L [ 1 - (L-N)/(L-Y)] = L (N-Y) / (L-Y)
Option (B) is therefore correct.
Question: In how many different ways can the letters of the word 'DEVELOP' be arranged?
A.10 ways
B.20 ways
C.30 ways
D.2520 ways
Answer: D.2520 ways
Explanation: Totally there are 7 letters on the word DEVELOP. it contains 1D,2E,1V,1L,1O,1P.
The no of ways is 7!/2!=2520 ways.
ANSWER:D
Question: Frances can complete a job in 10 hours, and Joan can complete the same job in 10 hours. Frances starts the job at 9 a.m., and stops working at 3 p.m. If Joan starts working at 6 p.m. to complete the job, at what time is the job finished?
A.6 p.m.
B.7 p.m.
C.8 p.m.
D.10 p.m.
Answer: D.10 p.m.
Explanation: Let the total work be 24 units.
Frances can complete 2.4 units/hr
Joan can complete 2.4 units/hr
Work done by Frances in 6 hours is 14.4 units ; work left for Joan is 9.6 units ( 24 - 14.4)
Time required by Jones to complete the remaining work will be 14.4/2.4 => 4 hours
Given Jones starts at 6 PM , so she would complete the work at 10 PM
Answer will be (D)
Question: How many multiples of 3 are there between 100 and 300 (both are inclusive)?
A.67.6
B.1.58
C.2.47
D.3.54
Answer: A.67.6
Explanation: the answer is (300-100)/3+1=67.6
Answer is A
Question: If the fractions 2/5, 3/8, 4/9, 5/13 and 6/11 are arranged in ascending order of their values, which one will be the fourth?
A.4/9
B.2/5
C.3/8
D.5/13
Answer: A.4/9
Explanation: Explanation:
2/5 = 0.4, 3/8 = 0.375,
4/9 = 0.44, 5/13 = 0.385 and 6/11 = 0.55
So, 3/8 < 5/13 < 2/5 < 4/9 < 6/11
So, the fourth fraction is = 4/9
Answer: Option A
Question: Sandy bought 65 books for $1380 from one shop and 55 books for $900 from another shop. What is the average price that Sandy paid per book?
A.$13
B.$15
C.$17
D.$19
Answer: D.$19
Explanation: average price per book = (1380 + 900) / (65 + 55) = 2280 / 120 = $19
The answer is D.
Question: 10 people went to a hotel for combine dinner party 8 of them spent Rs. 10 each on their dinner and rest spent 4 more than the average expenditure of all the 10. What was the total money spent by them.
A.1628.4
B.110
C.1492
D.1496
Answer: B.110
Explanation: Solution: Let average expenditure of 10 people be x.
then,
10x = 8*10+2*(x+4);
Or, 10x = 10*10+2x+8;
Or, x = 11;
So, total money spent = 11*10 = Rs. 110.
Answer: Option B
Question: Dawson and Henry are in a relay race. Dawson runs the first leg of the course in 38 seconds. Henry runs the second leg of the course in 7 seconds. What was the average time they took to run a leg of the course?
A.20.5
B.21.5
C.22.5
D.23.5
Answer: C.22.5
Explanation: (38 seconds +7 seconds)/2= 22.5 seconds
Correct option is: C
Question: Mangala completes a piece of work in 9 days, Raju completes the same work in 21 days. If both of them work together, then the number of days required to complete the work is?
A.8 days
B.6 days
C.11 days
D.12 days
Answer: B.6 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 9× 21/30 = 6 days
B)
Question: 139 persons have signed up for an elimination tournament. All players are to be paired up for the first round, but because 139 is an odd number one player gets a bye, which promotes him to the second round, without actually playing in the first round. The pairing continues on the next round, with a bye to any player left over. If the schedule is planned so that a minimum number of matches is required to determine the champion, the number of matches which must be played is
A.136
B.137
C.138
D.139
Answer: C.138
Explanation: Explanation :
This can be logically done in the following manner. There are 139 players in all. We want to determine 1 champion among them.
So all except 1 should lose. Since a player can lose only once and since any match produces only one loser, to produce 138 losers, there should be 138 matches that should be played.
Answer : C
Question: A certain bacteria colony doubles in size every day for 21 days, at which point it reaches the limit of its habitat and can no longer grow. If two bacteria colonies start growing simultaneously, how many days will it take them to reach the habitat’s limit?
A.6.33
B.7.5
C.20
D.15
Answer: C.20
Explanation: If there is one bacteria colony, then it will reach the limit of its habitat in 21 days.
If there are two bacteria colonies, then in order to reach the limit of habitat they would need to double one time less than in case with one colony. Thus colonies need to double 20 times.
Answer: C.
Similar questions to practice:
Hope it helps.