RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A shop keeper sell an article gets profit of 20% had he bought it for 20% less and sold it for Rs 120 less he would have still bought profit of 20% what is the cost price of article
A.500
B.600
C.700
D.750
Answer: A.500
Explanation: let c.p be x,
1st s.p =(120/100)x=6x/5
2nd s.p=(80/100)x=4x/5
filnal profit 20% so
120/100 * 4x/5
120 rs less so
6x/5 - 24x/25 =120
x=500
ANSWER:A
Question: The area of a triangle will be when a = 1m, b = 2m, c = 5m, a, b, c being lengths of respective sides?
A.3
B.6
C.4
D.9
Answer: C.4
Explanation: S = (1 + 2 + 5)/2= 4 Answer:C
Question: If the speed of x meters per second is equivalent to the speed of Y mile per hour, what is y in terms of x? (1 mile = 1609.34 meter)
A.1.21x
B.1.33x
C.2.23x
D.2.84x
Answer: C.2.23x
Explanation: x meters per second -->
--> 3,600x meters per hour(as there are 3,600 seconds in one hour);
--> 3,600x/1,609.34=2.236x miles per hour (as there are 1,609.34 meters in one mile).
Answer: C.
Question: Number X is 30% more than that of Number Y . Find what percent of Number Y is less than Number X ?
A.25 1/3%
B.26 1/3%
C.24 1/3%
D.23 1/3%
Answer: D.23 1/3%
Explanation: Explanation:
y=100 x=130
130---------30
100---------? => 23 1/3%
Answer D
Question: A house of 4 rooms is designed from 4 types of bedrooms and 3 types of bathrooms. The house must have at least 2 types of bedrooms and at least 1 type of bathroom. How many ways can this house be designed?
A.3
B.4
C.12
D.30
Answer: D.30
Explanation: Solution: We have two possibilities 3Bed 1Bath or 2Bed 2Bath
(4C3)(3C1)+(4C2)(3C2)=30
D) 30
Question: Ram and Krishna start from A and B respectively at the same time and travel towards each other at constant speeds along the same route. Ram meets Krishna at point C on the road which is 1000m away from starting point A and 500m away from point B. The time taken by Ram to reach point B is 10minutes. Find the time taken by krishna to go from B to A.?
A.45 minutes
B.35 minutes
C.50 minutes
D.52 minutes
Answer: C.50 minutes
Explanation: total distance from A to B-
A - C = 1000m, B - C = 500m;
therefore A-B = 1500m;
Vr=1500/25=60 m/m;
t-time taken by Ram for AB meet,
t=1000/60=16.67 minutes = Time taken by Krishna for AB meet.
therefore,
Vk=500/16.67=30m/m.
time taken by krishna for B-A = 1500/30 =50 minutes
option C
Question: In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 130 marks, the no of questions he attempts correctly is :
A.33
B.38
C.99
D.27
Answer: B.38
Explanation: Let the number of correct answers be X.
Number of incorrect answers = (60 – X).
4x – (60 – x) = 130
=> 5x = 190
=> x = 38
Answer: B
Question: The difference between two numbers is 1365. When the larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number is
A.240
B.270
C.295
D.360
Answer: B.270
Explanation: Sol.
Let the smaller number be x.
Then, larger number = (1365 + x).
∴ 1365 + x = 6x + 15
⇔ 5x = 1350
⇔ x = 270.
Hence, the required number is 270.
Answer B
Question: Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and they are sold fetching the profit 25% and 20% respectively. If the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4/3 and 5/3 times respectively, then the mixture will fetch the profit of
A.18%
B.20%
C.21%
D.25%
Answer: D.25%
Explanation: Answer: D.
Question: How many odd 4-digit positive integers Q that are multiples of 5 can be formed without using the digit 3?
A.648
B.729
C.900
D.1296
Answer: A.648
Explanation: I choose A.
Possible n° of 1st digit: 8 (0 can't be the first number, or else it wouldn't have 4 digits. 3 is exlcuded)
Possible n° of 2nd digit: 9 (3 is excluded)
Possible n° of 3rd digit: 9 (3 is excluded)
Possible n° of 4th digit: 1 (a number is a multiple of 5 if it ends in 5 or 0, here we are asked for the odd numbers, hence the last digit can't be 0)
So, Q=8*9*9*1=648 (A)
Question: A shopkeeper cheats both his supplier and customer by using faulty weights. When he buys from the supplier, he takes 20% more than the indicated weight. When he sells to his customer, he gives the customer a weight such that 10% of that is added to the weight, the weight claimed by the trader is obtained. If he charges the cost price of the weight that he claims, find his profit percentage.
A.20%
B.32%
C.23.365%
D.22.109%
Answer: B.32%
Explanation: Anyways, one can infer that he 'steals' 20% from suppliers and then charges 10% extra to customers
So basically 1.2 * 1.1 = 1.32
Given that 1 is start point, we get 32% more
Hence answer is B
Question: Among all sales staff at Listco Corporation, college graduates and those without college degrees are equally represented . Each sales staff member is either a level-1 or level-2 employee. Level-1 college graduates account for 10% of Listco's sales staff. Listco employs 72 level-1 employees, 20 of whom are college graduates. How many sales staff members without college degrees are level-2 employees ?
A.46
B.48
C.56
D.32
Answer: B.48
Explanation: I'm going in on this one.
So let's say that we have the following
So we know that L1 = 72 and that C and L1 = 0.10X , we should set up a double set matrix btw but anyways, I'm just explaining the point with this problem. Now we are told that 0.1x = 20, therefore the grand total is 200. Now we know that L2 is 200 - 72 = 128. We also learn that C and No C are equally represented thus 100 each. Therefore No C and No L2 will be 100 - 52 = 48.
Thus B is the correct answer choice
Question: A's salary is 50% more than B's. How much percent is B's salary less than A's?
A.25.5%
B.33.3%
C.45.6%
D.50%
Answer: B.33.3%
Explanation: B's salary is less than A's salary by 50/(100+50) * 100% = 100/3% = 33.3%
Answer is B
Question: 66 small identical cubes are used to form a large cube. How many more cubes are needed to add one top layer of small cube all over the surface of the large cube ?
A.64
B.150
C.152
D.216
Answer: B.150
Explanation: 66 small cube will make a large cube with 4 cubes in each line i.e.
Adding one layer will require one cube at each end and hence new cube will have 6 cubes in each line.
Total number of small cubes in new cube = 6^3 = 216
Extra cube required = 216 - 66 = 150
Hence, B is the answer.
Question: If the sum of two numbers is 20 and the sum of their squares is 200, then the product of the numbers is
A.40
B.44
C.100
D.88
Answer: C.100
Explanation: according to the given conditions x+y = 20
and x^2+y^2 = 200
now (x+y)^2 = x^2+y^2+2xy
so 20^2 = 200 + 2xy
so xy = 200/2 = 100
ANSWER:C
Question: A container contains 40 liters of milk, From this container 4 liters of milk was taken out and replaced by water. This process was repeated further 2 times. How much milk is now contained by the container?
A.25.5 liters
B.29.16 liters
C.30.98 liters
D.42.15 liters
Answer: B.29.16 liters
Explanation: Amount of milk left after 3 operations = 40 (1 - 4/40)^3 = 40 * 9/10 * 9/10 * 9/10 = 29.16 liters
Answer is B
Question: There are 6 periods in each working day of a school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period?
A.1800
B.3200
C.2600
D.3600
Answer: A.1800
Explanation: There are 5 subjects and 6 periods. Each subject must be allowed in at least one period. Therefore, two periods will have same subject and remaining four periods will have different subjects.
Select the two periods where the same subject is taught. This can be done in 6C2 ways.
Allocate a subject two these two periods(5C1 ways).
Remaining 4 subjects can be arranged in the remaining 4 periods in 4! ways.
Required number of ways
= 6C2 × 5C1 × 4! = 1800
Answer : A.
Question: In a 100 m sprint race Kelly was given a 3 m head start by Abel. If Abel lost the race to Kelly by a distance of 0.50 m, how many meters more would Abel need to overtake Kelly?
A.20.5
B.18.4
C.17.5
D.19.9
Answer: D.19.9
Explanation: Distance Abel ran before completion of race---100 m-0.50m=99.5m
Distance gained on Kelly over 99.5m---3m-0.50m=2.50m
then Abel gains 99.5m/2.50m = 1m on Kelly every 39.8 meters.
Therefore 39.8 divided by half a meter ( i.e the 0.50 m Abel was defeated with)
ANSWER: D. 19.9m
Question: Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
A.39, 30
B.41, 32
C.42, 33
D.43, 34
Answer: C.42, 33
Explanation: C
Let their marks be (x + 9) and x.
Then, x + 9 = 56/100(x + 9 + x)
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Question: What is the tens' digit Q of the sum of the first 40 terms of 1, 11, 111, 1111, 11111, 111111, ...?
A.Q=2
B.Q=3
C.Q=4
D.8
Answer: B.Q=3
Explanation: All of the first 40 terms have 1 at the units place.
Except the first term, the tens digit of all the remaining 39 terms is 1.
So now if you do the addition
1 1
1 1
. . .
. . .
. . .
1 1
0 1
3 0
Answer is B
Question: If q>0, which of the following must be true?
A.1 <q
B.0 < q < 2
C.-1 < q < 1
D.-10 < q
Answer: D.-10 < q
Explanation: All we know is that q is some positive number. Right away we can see that D must be true: if q is positive then it MUST be true that it's greater than -10. Still let's check each option.
A. 1 < q. We don't know whether the number is greater than 1, it could be a positive number less than or equal to 1. Discard.
B. 0 < q < 2. The same here: we don't know whether the number is less than 2, it could be more than or equal to 2. Discard.
C. -1 < q < 1. The same as A. Discard.
E. 1/100 < q. We don't know whether the number is greater than 1/100, it could be a positive number less than or equal to 1/100. Discard.
Answer: D.
Question: If there is an equal probability of a child being born a boy or a girl, what is the probability that a couple who have 7 children have two children of the same sex and one of the opposite sex?
A.1/3
B.2/3
C.1/4
D.7/64
Answer: D.7/64
Explanation: No of ways of selecting a gender - 2C1
No of ways of selecting any 2 children out of 7 = 7C2
Total possible outcomes - 2^7 (each child can be either a girl or a boy)
Probability=2C1*7C2/2^7= 2*7/2*2*2*2*2*2*2=7/64
Ans=D
Question: Two whole numbers whose sum is 100 cannot be in the ratio
A.2:23
B.5:45
C.10:10
D.2:6
Answer: D.2:6
Explanation: D) 2:6
Question: If Dale works at full efficiency he needs a break of 1 day after every 2 days of work and he completes a job in a total of 5 days. If he works at reduced efficiency, he can work without break and finish that same job in 5 days. Dale's output at reduced efficiency is what fraction of his output at full efficiency?
A.5/2
B.4/1
C.9/5
D.4/5
Answer: B.4/1
Explanation: We're told that there are 2 ways for Dale to complete a job:
1) Full Efficiency: 2 days of work followed by 1 dayofffor a total of 5 days.
2) Reduced Efficiency: 5 straight days with no days off.
Working at Full Efficiency creates the following pattern:
2 days on, 1 day OFF, 2 days on, 1 day OFF, 2 days on, 1 day OFF, 2 days on = 2+1+2= 5 days
Totals: 4 days on, 1 days off
Reduced Efficiency means that Dale will do 6 days of work in 5 days, thus those Reduceddaysare 4/1 of Full Efficiency.
Answer : B
Question: If x is divisible by 2, 14, and 11, which of the following must be the least multiple of x?
A.308
B.154
C.70
D.44
Answer: B.154
Explanation: We are looking for the LCM (which is not 0) of 2, 11, 14:
2 * 11 * 7 = 154
ANSWER:B
Question: To fill a cistern, pipes A,B and C take 20 minutes, 15 minute and 12 minutes resp. The time in minutes that the three pipes together will take to fill the cistern is
A.5
B.6
C.8
D.3
Answer: A.5
Explanation: A
5
Question: Excluding stoppages, the speed of a bus is 58 kmph and including stoppages, it is 40 kmph. For how many minutes does the bus stop per hour?
A.19
B.19.13
C.10.5
D.11.35
Answer: A.19
Explanation: Due to stoppages, it covers 18 km less.
Time taken to cover 18 km = ((18/58)Ã—60) = 19 min.
Option(A) is correct
Question: If 5 < x < 11 and y = x + 6, what is the greatest possible integer value of x + y?
A.25
B.26
C.27
D.28
Answer: C.27
Explanation: x+y = x+x+6 = 2x+6
We need to maximize this value and it needs to be an integer.
2x is an integer when the decimal of x is .0 or .5
The largest such value is 10.5
Then x+y = 10.5 + 16.5 = 27.
The answer is C.
Question: Two whole numbers whose sum is 24 is the ratio
A.1:3
B.2:8
C.1:6
D.2:3
Answer: A.1:3
Explanation: A) 1:3
Question: Reena took a loan of 1200 with simple interest for as many years as the rate of interest. If she paid 432 as interest at the end of the loan period, what was the rate of interest?
A.6
B.3
C.7
D.8
Answer: A.6
Explanation: A
6
Let rate = R% and time = R years.
Then, (1200 x R x R)/100 = 432
12R² = 432
R² = 36
R = 6.
Question: In a recent election, Ms. Robinson received 3200 voters cast by independent voters, that is, voters not registered with a specific political party. She also received 10 percent of the votes cast by those voters registered with a political party. IF N is the total number of votes cast in the election and 40 percent of the votes cast were cast by independent voters, which of the following represents the number of votes that Mrs. Robbins received?
A. 0.06N+3200
B. 0.1N+7200
C. 0.4N+7200
D. 0.1N+8000
Answer: A. 0.06N+3200
Explanation: 40% of N are independent voters, hence 60% of N are not independent voters. From this group she received 10% votes so, 0.1*0.6*N plus 3,200 votes from independents: total=0.1*0.6*N+3,200=0.06*N+3,200.
Answer: A.
Question: If Leo gains 10 pounds, he will weigh 50% more than his sister Kendra. Currently their combined weight is 140 pounds. What is Leo's current weight?
A.80
B.90
C.100
D.110
Answer: A.80
Explanation: L+K = 140 and so K = 140-L
L+10 = 1.5K = 1.5(140-L)
2.5L = 200
L = 80
The answer is A.
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
A.8
B.7
C.6
D.9
Answer: D.9
Explanation: 1/10 + 1/15 - 1/x = 1/18
x = 9
Answer:D
Question: One side of a triangle has length 6 and a second side has length 4. Which of the following could be the area of the triangle?
I. 15
II. 12
III. 5
A.I only
B.II only
C.III only
D.II and III only
Answer: D.II and III only
Explanation: The triangle will have a maximum area when it is a right angled triangle
The largest triangle will be formed when 6 and 4 are the base and height of triangle .
Area = 1/2 * 6 * 4 = 12
There is no lower limit on the area of any triangle whose only 2 sides are known.
Then 0 < Area <= 12
The answer is D.
Question: A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
A.22 sec
B.16 sec
C.17 sec
D.88 sec
Answer: B.16 sec
Explanation: Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 280 * 2/35 = 16 sec
Answer:B
Question: There are 100 students in a college class of which 36 are boys studying Tamil & 13 girls not studying Tamil. If there are 55 girls in all, then the probability that a boy picked up at random is not studying Tamil, is
A.1/5
B.2/5
C.3/5
D.3/7
Answer: A.1/5
Explanation: There are 55 girls and 45 boys in the college. Out of 45 boys, 36 are studying Tamil and 9 are not studying Tamil. The probability that a boy picked up at random is not studying Tamil= 9/45 = 1/5
A
Question: The factorial expression 18!/12! is not divisible by which of the following integers?
A.3
B.5
C.19
D.14
Answer: C.19
Explanation: 18!/12! => 18 x 17 x 16 x 15 x 14 x 13
(A) 3 Can divide 18 or 15
(B) 5 Can divide 15
(C) 19 None of the Multiplicands present
(D) 14 Can divide 14
(E) 9 Can divide 9
Hence answer will be (C)
Question: John invested part of his savings into a investment X that earned a profit of 10% and the rest of the savings into an investment W that lost 15%. If John neither made a profit nor a loss, then what fraction of his savings was invested in investment X?
A.a. 3/5
B.b.2/3
C.c.7/10
D.d.3/4
Answer: A.a. 3/5
Explanation: X(10) --- Net(0) --- W(-15) = -15/-10 = 3/2.
So, John invested 3/3+2 = 3/5 of his savings in investment X. Ans (A).
Question: If the ratio of x to y is 4 to 5, then (y-x)/(x+y)?
A.-7/3
B.-3/7
C.1/9
D.1
Answer: C.1/9
Explanation: I believe this problem can be solved using algebra.
The ratio of x to y is 4 to 5 means
(x/y)=(4/5)
Cross-multiply
4x = 5y
x = (4/5)*y
Then, substitute x in the original equation in the problem with the value we just found.
(y - (4/5)*y) / ((4/5)*y + y)
= ((1/5)*y) / ((9/5)*y)
Simplify by canceling the y in the numerator with the y in the denominator.
(1/5) / (9/5)
= (1/5) * (9/7)
The 5s cancel each other out, and you are left with 1/9.
Question: In 10 years, A will be twice as old5as B was 10 years ago. If A is now 7 years older than B, the present age of B is
A.35
B.37
C.39
D.41
Answer: B.37
Explanation: Explanation:
Let B's age = x years.
Then, As age = (x+ 7) years.
(x+7+10)=2(x—10)
hence x=37.
Present age of B = 37 years
Answer: Option B
Question: The average weight of a group of boys is 30 kg. After a boy of weight 35 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
A.4
B.8
C.6
D.9
Answer: A.4
Explanation: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 35 kg joins the group, total weight of boys = 30x + 35
So 30x + 35 + 31(x + 1) = > x = 4.
Answer: A
Question: A large tanker can be filled by two pipes A and B in 60 and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?
A.14 min
B.15 min
C.16 min
D.30 min
Answer: D.30 min
Explanation: Part filled by (A + B) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
x/2 * 1/15 = 1 => x = 30 min.Answer: D
Question: A car after covering ½ of a journey of 100 km develops engine trouble and later travels at ½ of its original speed. As a result, it arrives 2 hours late than its normal time. What is the normal speed of the car is?
A.15 kmph
B.25 kmph
C.28 kmph
D.29 kmph
Answer: B.25 kmph
Explanation: B
25 kmph
[50/x + 50/(x/2)] – 100/x = 2
x = 25
Question: How many terms are there in 2, 4, 8, 16,..., 1024?
A.14
B.11
C.12
D.10
Answer: D.10
Explanation: 2, 4, 8, 16, ..., 1024 is a G.P with a =2
and r =4/2 =2
Let the number of terms be n. Then
2 x 2 ^n-1 = 1024
or 2^n-1 = 512 = 2^9
Thus n - 1 =9
n= 10
ANSWER:D
Question: What is the 14th digit to the right of the decimal point in the decimal equivalent of 82/11?
A.4
B.3
C.1
D.5
Answer: D.5
Explanation: 82/11 = 7.4545....
45 is non-repeating terminating decimal.
The 14th digit to the right of decimal point will be 5.
Answer D
Question: Find the area of a parallelogram with base 22 cm and height 21 cm?
A.462 cm2
B.478 cm2
C.490 cm2
D.268 cm2
Answer: A.462 cm2
Explanation: Area of a parallelogram = base * height
= 22 * 21
= 462 cm2
Answer: A
Question: If B takes 20% less time than A, to cover the same distance. What should be the speed of B, if A works at a rate of 10 km/hr?
A.12.5 km/hr
B.10 km/hr
C.15 km/hr
D.20 km/hr
Answer: A.12.5 km/hr
Explanation: Explanation:
S1 = 10 kmph
if T1 = 100
T2 = 80
10 x 100 = 80 x S2
S2 = 12.5 km/hr
Answer: Option A
Question: A sequence of numbers a1a1, a2a2, a3a3,…. is defined as follows: a1=3a1=3, a_2 = 5, and every term in the sequence after a2a2 is the product of all terms in the sequence preceding it, e.g, a3=(a1)(a2)a3=(a1)(a2) and a4=(a1)(a2)(a3)a4=(a1)(a2)(a3). If an=tan=t and n>2n>2, what is the value of an+2an+2 in terms of t?
A.4t
B.t^2
C.t^3
D.t^4
Answer: D.t^4
Explanation: An = (A1)(A2)......(An-1) = t
An+1 = t * An = t^2
An+2 = t * An * An+1 = t * t * t^2 = t^4
Answer: D
Question: If a boat goes 7km upstream in 42 minutes and the speed of the stream is 3 kmph, then the speed of the boat in still water is ?
A.13km/hr
B.52km/hr
C.85km/hr
D.2.8km/hr
Answer: A.13km/hr
Explanation: Rate upsteram =(7/42*60)kmph=10kmph.
speed of the stream =3kmph let speed in still water be xkm/hr. then speed upstream=(x-3)km/hr. x-3=10==>x=13km/hr Answer(A)
Question: The ratio between speed of the two trains is 7:8. If the 2nd train runs 400 km in 4 hrs, what is the speed of the 1st train?
A.87.9
B.87.5
C.87.7
D.87.6
Answer: B.87.5
Explanation: Answer: b
Explanation:
Speed of 2nd train = 400/4 = 100 kmph
Since the ratios are in 7 : 8
Speed of First train = 7/8 × 100 = 87.5 kmph
Answer:B
Question: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?
A.2 : 3 : 4
B.6 : 7 : 8
C.6 : 8 : 9
D.4 : 6 : 8
Answer: A.2 : 3 : 4
Explanation: Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).
(140/100 * 5x), (150/100 * 7x) and (175/100* 8x)
7x, 21x/2 and 14x
The required ratio = 7x : 21x/2 : 14x
14x : 21x : 28x
2 : 3 : 4
Answer = A
Question: A loan shark made a loan of $100 to be repaid with $120 at the end of one month. What was the annual interest rate?
A.210%
B.220%
C.230%
D.240%
Answer: D.240%
Explanation: Explanation:
r=I/PT
Answer: D
Question: In how many different orders can the people Alice, Benjamin, Charlene, David, Elaine, Frederick, Gale, and Harold be standing on line if each of david, Benjamin, Charlene must be on the line before each of Frederick, Gale, and Harold?
A.1,008
B.1,296
C.2016
D.2,018
Answer: C.2016
Explanation: Place A and E first: 8 options for D, 7 options for E.
We are left with 6 empty places. D, B and C must take first 3 places and F, G, H must take the remaining three.D, B and C can be arranged in their places in 3! ways. The same for F, G, and H.
Total = 8*7*3!*3! = 2,016.
Answer: C
Question: Two squares are chosen on a chessboard at random. What is the probability that they have a side in common?
A.1/18
B.64/4032
C.63/64
D.1/9
Answer: A.1/18
Explanation: In 64 squares, there are:
(1) 4 at-corner squares, each has ONLY 2 squares each having a side in common with...
(2) 6*4 = 24 side squares, each has ONLY 3 squares such that each has a side in common with...
(3) 6*6 = 36 inner squares, each has 4 squares such that each has a side in common with...
So we have the calculation:
P = (4/64)*(2/63) + (24/64)*(3/63)+ (36/64)*(4/63)
P = 1/18
ANSWER:A
Question: The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 45kg. What is the weight of the new person?
A.75 Kg
B.65 Kg
C.85 Kg
D.80 Kg
Answer: B.65 Kg
Explanation: Explanation:
Total increase in weight = 8 Ã— 2.5 = 20
If x is the weight of the new person, total increase in weight = xâˆ’45
=> 20 = x - 45
=> x = 20 + 45 = 65
Answer: Option B
Question: It takes John 15 minutes to walk to the car park and 45 to drive to work. At what time should he get out of the house in order to get to work at 9:00 a.m.?
A.8:50 a.m
B.8:00 a.m
C.7:50 a.m
D.6:50 a.m
Answer: B.8:00 a.m
Explanation: The time it takes John to get to work: time to walk to car park + time to drive
15 + 45 = 60 minutes = 1 hour
John needs to get out of the house 1 hour before 9:00 am at
9:00 - 1:00 = 8:00 a.m
correct answer B
Question: A class consists of 100 students, 25 of them are girls and 75 boys; 20 of them are rich and remaining poor; 10 of them are fair complexioned. The probability of selecting a fair complexioned rich girl is
A.1/200
B.1/59
C.1/56
D.1/54
Answer: A.1/200
Explanation: The probability of selecting girl is: 25/100 = 1/4
The probability of selecting rich is: 20/100 = 1/5
The probability of selecting fair complexioned is: 10/100 = 1/10
Three are independent;probability of rich and fair complexioned girl is:
(1/4) Ã—(1/5) Ã— (1/10) = 1/200
Answer: A