RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: 10% of employees are women with fair hair. 40% of fair-haired employees are women. What percent of employees have fair hair?
A.25
B.30
C.50
D.55
Answer: A.25
Explanation: I came up with (A) 25
Think of 100 people total:
From the first fact, 10 of these are women with fair hair.
From the second fact, these 10 women make up 40% of the total fair haired population.
We can then make a ratio of 60:40 fair haired men to fair haired women.
This means that (60/40)*10 equals the number of fair haired men, which is 15 men with fair hair.
Add this 15 to the 10 women and get 25 fair haired men and women out of 100 total men and women.
25%
A
Question: up to 20,how many no. are odd and prime both?
A.9
B.5
C.6
D.7
Answer: D.7
Explanation: we have to calculate it manually.
odd 1,3,5,7,9,11,13,15,17,19
prime 2,3,5,7,11,13,17,19
common 3,5,7,11,13,17,19
total no. 7
answer D
Question: Selling an kite for Rs. 30, a shop keeper gains 30%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
A.8%
B.10%
C.11%
D.17%
Answer: D.17%
Explanation: Explanation:
Marked price = Rs. 30
C.P. = 100/130 * 30 = Rs. 23.07
Sale price = 90% of Rs. 30 = Rs. 27
Required gain % = 3.92/23.07 * 100 = 17%.
Answer: D
Question: The area of circle O is added to its diameter. If the circumference of circle O is then subtracted from this total, the result is 6. What is the radius of circle O?
A.–2/pi
B.2
C.3
D.4
Answer: C.3
Explanation: pi*r^2 + 2r -2*pi*r =6
Simplifying the equation: pi*r(r-2)+2r=6
Without much algebraic: We can Test the answers quickly, then 3 is the only possible answer that will eliminate pi from equation.
Answer is C
Question: Machine X can complete a job in half the time it takes Machine Y to complete the same job, and Machine Z takes 50% longer than Machine X to complete the job. If all three machines always work at their respective, constant rates, what is the ratio L of the amount of time it will take Machines X and Z to complete the job to the ratio of the amount of time it will take Machines Y and Z to complete the job?
A.5 to 1
B.10 to 7
C.1 to 5
D.7 to 10
Answer: D.7 to 10
Explanation: Solutioning this exercise can be facilitated by using a R T W (rate time work) table:
We translate the exercise into the table:
R T W
X t/2 1
Y t 1
Z (t/2*3/2 =3t/4) 1
From this table we find the rates
Rx = 2/t
Ry = 1/t
Rz = 4/3t
The Q is what is the ratio of (Tx + Ty) / (Ty + Tz)
Rx + Ry = 2/t + 4/3t = 6/3t+4/3t = 10/3t
Ry+Rz = 1/t + 4/3t = 3/3t + 4/3t = 7/3t
The (10/3t)/(7/3t) = 10/7 then the work ratios is 10 to 7
Since Time Ratio L is the inverse of work, the the answer is 7 to 10
CORRECT ANSWER D
Question: The digit in unit's place of the product 81 ×82×.....×89 is
A.0
B.2
C.6
D.8
Answer: A.0
Explanation: Solution
Required digit	= Unit digit
=(1×2×3×4×5×6×7×8×9)	=0.
Answer A
Question: In the xy plane line m has the equation 4x + y = q. Line n passes through the origin and is perpendicular to line m. If point p has the coordinates (r, r+1) and is on both line n and m what is the value of r?
A.-4/3
B.1/4
C.-4
D.3/4
Answer: A.-4/3
Explanation: The equation of line m is y=-4x+q. Now, since line n is perpendicular to line m, then its slope is negative reciprocal of the slope of line m, so the slope of n is 1/4. Next, as line n passes through the origin (0, 0) and has the slope of 1/4 then its equation is y=1/4*x.
Point (r, r+1) lies on line n means that (r+1)=1/4*r --> r=-4/3.
Answer: A.
Question: In how many different ways can the letters of the word 'LEADING' be arranged in such a way that the vowels always come together?
A.360
B.480
C.720
D.5040
Answer: C.720
Explanation: Explanation:
The word 'LEADING' has 7 different letters.
When the vowels EAI are always together, they can be supposed to form one letter.
Then, we have to arrange the letters LNDG (EAI).
Now, 5 (4 + 1 = 5) letters can be arranged in 5! = 120 ways.
The vowels (EAI) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (120 x 6) = 720.
ANSWER IS C
Question: In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If a large bottle of the sport formulation contains 4 ounces of corn syrup, how many ounces of water does it contain?
A.15
B.30
C.45
D.60
Answer: D.60
Explanation: Standard:
Fl: Corn S: Water = 1:12:30
Sport:
Fl: Corn S: Water = 3:12:180
This simplifies to 1:4:60
If the large bottle has a capacity of x ounces, then
4x / 65 = 4.
So, x = 65 ounces.
Water = (60 / 65) * (65) = 60 ounces.
Ans D
Question: Find the number of digits that are to be used in numbering a book of 400 pages.
A.1094
B.1093
C.1092
D.1099
Answer: C.1092
Explanation: Explanation:
One digit numbers from 1 to 9 = 9
Two digit numbers from 10 to 99 = 90
Three digit numbers from 100 to 400 = 301
.:Total numbers of digits that are to be used
=(9 x 1) + (90 x 2) + (301 x 3) = (9 + 180 + 903) = 1092
Answer: Option C
Question: An alchemist discovered that the formula expressing the correct proportions needed to turn ordinary metal into gold is G = 3/2M + 10, where G is the number of gold bars and M is the number of metal bars. If a metal bar weighs twice as much as a gold bar, how many metal bars will yield an equal weight of gold?
A.a.	A - 10
B.b.	B - 15
C.c.	C – 22.5
D.d.	D – 20
Answer: D.d.	D – 20
Explanation: A --- 30/2 + 10 = 25 --- wrong
B --- 45/2 + 10 = not an integer --- wrong
C --- 22.5(3/2) + 10 = not an integer --- wrong
D --- 60/2+10 = 40 --- CORRECT
This is one of those problems that will probably be easiest to solve by plugging in numbers. The algebra is do-able, but it's not worth the effort (in my opinion). I was able to solve it in under 30 seconds total with this method.
D
Question: The cost of an article (which is composed of raw materials and wages) was 3 times the value of raw materials used. The cost of raw materials increased in the ratio 3 : 7 and wages increased in the ratio 4 : 9. Find the present cost of the article if its original cost was Rs. 18.
A.Rs. 41
B.Rs. 30
C.Rs. 40
D.Rs. 46
Answer: A.Rs. 41
Explanation: Assume the raw materials’ cost as Rs.150, then the total cost will be Rs. 450, (Thus, wages cost is Rs. 300)
Since, the cost of raw materials goes up in the ratio of 3 : 7, the new raw material cost would become Rs. 350
The new wages cost would be in the ratio 4 : 9 as Rs. 675.
The new total cost would become, Rs. 1025.
Since Rs 450 become Rs. 1025 (change in total cost),
Unitary method calculation would give us that Rs. 18 would become Rs. 41.
ANSWER:A
Question: If YWVSQ is 25 - 21 - 21 - 19 - 17, Then MKIGS
A.13 - 11 - 9 - 7 - 9
B.13 - 11 - 6 - 7 - 6
C.13 - 11 - 9 - 7 - 7
D.13 - 11 - 9 - 7 - 3
Answer: B.13 - 11 - 6 - 7 - 6
Explanation: MKIGS = 13 - 11 - 6 - 7 - 6
Note: this is a dummy question. Dont answer these questions
Answer:B
Question: Consider a square of diagonal length d. Let Another square be formed with d as its side. Find the ratio of the area of the bigger square to that of the smaller square.
A.2
B.3
C.4
D.16
Answer: A.2
Explanation: d^2/(1/2)*d^2= 2
ANSWER:A
Question: The length of the bridge, which a train 100 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
A.10 m
B.16 m
C.275 m
D.19 m
Answer: C.275 m
Explanation: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (100 + x)/30
= 25/2 => 2(100 + x) = 750 => x
= 275 m.
Answer: C
Question: If a randomly selected positive single digit multiple of 3 is multiplied by a randomly selected prime number less than 20, what is the probability T that this product will be a multiple of 45?
A.1/32
B.1/28
C.1/24
D.1/16
Answer: C.1/24
Explanation: There are 3 single digit multiple of 3, that is, 3,6,9.
There are 8 prime nos less than 20 - 2,3,5,7,11,13,17,19
Total outcome - 8*3 = 24
Favourable outcome = 1 (9*5)
Hence required probability T= 1/24. Answer C.
Question: A man can row 30 km downstream and 20 km upstream in 4 hours. He can row 45 km downstream and 40 km upstream in 7 hours. Find the speed of man in still water?
A.12.9 kmph
B.18.9 kmph
C.28.9 kmph
D.12.5 kmph
Answer: D.12.5 kmph
Explanation: Let the speed of the man in still water be a kmph and let the speed of the stream be b kmph.
Now 30/(a + b) + 20/(a - b)
= 4 and 45/(a + b) + 40/(a - b)
= 7
Solving the equation, the speed of man in still water is 12.5 kmph.
Answer: D
Question: The manager of a theater noted that for every 10 admissions tickets sold, the theater sells 3 bags of popcorn at 2.75 $ each, 4 sodas at 1.50 $ each and 2 candy bars at 1.00$ each. To the nearest cent, what is the average (arithmetic mean) amount of these snacks sales per ticket sold?
A.1.48$
B.1.58$
C.1.60$
D.1.63$
Answer: D.1.63$
Explanation: For every 10 tickets amount of snacks sold is 3*2.75+4*1.5+2*1=$16.25, hence amount of the snacks sales per ticket is $16.25/10=~$1.63.
Answer: D.
Question: Find the one which does not belong to that group ?
A.3
B.4
C.5
D.8
Answer: B.4
Explanation: Explanation:
3, 5, 9 and 7 are odd numbers, but not 4.
Answer: B
Question: A cistern which could be filled in 6 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it?
A.76 hrs
B.99 hrs
C.15 hrs
D.90 hrs
Answer: C.15 hrs
Explanation: 1/6 - 1/x = 1/10
=> 15 hrs
Answer: C
Question: A 1400 m long train crosses a tree in 100 sec, how much time will It take to pass a platform 700 m long?
A.288
B.190
C.150
D.188
Answer: C.150
Explanation: L = S*T
S= 1400/100
S= 14 m/Sec.
Total length (D)= 2100 m
T = D/S
T = 2100/14
T = 150 Sec
Answer:C
Question: A university cafeteria offers 6 flavors of pizza - pork,gobi-manjurian,pepperoni, chicken, Hawaiian and vegetarian. If a customer has an option (but not the obligation) to add extra cheese, mushrooms or both to any kind of pizza, how many different pizza varieties are available ?
A.4
B.8
C.12
D.36
Answer: D.36
Explanation: 6 flavours * 6 choices = 6C1*6C1 = 6*6=36=D
Question: Find the HCF of 54, 288, 360
A.18
B.36
C.54
D.108
Answer: A.18
Explanation: Explanation:
Lets solve this question by factorization method.
18=2×32,288=25×32,360=23×32×5
So HCF will be minimum term present in all three, i.e.
2×32=18
Answer: Option A
Question: Find the odd man out. 187, 264, 386, 473, 682, 781
A.187
B.386
C.781
D.682
Answer: B.386
Explanation: In all numbers except 386, the middle digit is the sum of other two digits.
Answer is B
Question: 3 numbers are randomly selected, with replacement, from the set of integers {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}. If the first number selected is w, the second number selected is x, and the third number is y, what is the probability that w < x < y ?
A.3/40
B.28/243
C.3/25
D.33/100
Answer: C.3/25
Explanation: Solution:
Total possible ways = 10*10*10 = 1000
Case1: w=0.
if x = 1, then y can have 8 ways.
if x =2 , then y can have 7 ways and so on.
So, no. of ways = 8+7+..+1
Case2 : w=1.
if x = 2, then y can have 7 ways.
if x =3 , then y can have 6 ways and so on.
So, no. of ways = 7+6 +..+1
There will be 8 cases in this way and they will follow a pattern which looks like this:
No. of ways for Case1 : 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8
No. of ways for Case2 : 1 + 2 + 3 + 4 + 5 + 6 + 7
No. of ways for Case3 : 1 + 2 + 3 + 4 + 5 + 6
No. of ways for Case4 : 1 + 2 + 3 + 4 + 5
No. of ways for Case5 : 1 + 2 + 3 + 4
No. of ways for Case6 : 1 + 2 + 3
No. of ways for Case7 : 1 + 2
No. of ways for Case8 : 1
____________________________________________________________
Total number of ways : 8(1) + 7(2) + 6(3) + 5(4) + 4(5) + 3(6) + 2(7) + 1(8) = 2(4(5) + 3(6) + 2(7) + 1(8)) = 2(60) = 120
Therefore, ans is 120/1000 = 3/25.
Option c.
Question: In the new budget the price of milk rose by 10%. By how much percent must a person reduce his consumption so that his expenditure on it does not increase?
A.7.5%
B.9.1%
C.10.9%
D.12.6%
Answer: C.10.9%
Explanation: Reduce in consumption = R/(100+R) *100% = 10/110 *100 = 9.1%
Answer is C
Question: xy+yx=46xy+yx=46 Find x & y values ?
A.45
B.878
C.66
D.88
Answer: A.45
Explanation: l: 145+451=46145+451=46
Hence x = 1, y = 45
AnswerA
Question: What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30?
A.228
B.630
C.998
D.267
Answer: B.630
Explanation: L.C.M of 12, 18, 21, 30
= 2 * 3 * 2 * 3 * 7 * 5 = 1260
Required number = 1260/2 = 630.
Answer:B
Question: a,b,c,d,e sitting in a row what is the probability that a & b sitting adjacent.
A.1/5
B.2/5
C.3/5
D.4/5
Answer: B.2/5
Explanation: total number of arrangement is= 5!= 120
Favorable event i.e a and b can be arranged in 2! and the remaining can be arranged in 4! since ab can be in any of the four positions.
so 4!*2!/5! = 2/5
ANSWER:B
Question: Solve the equation 2 – x = 2b – 2ax, where a and b are real parameters. Find for which values of a the equation has for solution a natural number, if b = 7
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: Solution:
We write the given equation like this (2a - 1)x = 2(b - 1)
The following cases are possible:
If 2a - 1 ≠ 0, i.e. a ≠ 1/2, the equation has single solution
x = 2(b - 1)/(2a - 1)
If a = 1/2 and b = 1, the equation gets the kind 0.x = 0 and every x is solution
If a = 1/2 and b ≠ 1, we get 0.x = 2(b - 1), where 2(b - 1) ≠ 0
In this case the equation has no solution.
If b = 7 and a ≠ 1/2 the single solution is
x = 2(7 - 1)/(2a - 1) = 12/(2a - 1)
If a is whole number, then 2a - 1 is also whole number and the solution
x = 12/(2a - 1) is natural number when
2a - 1 is positive divisor of 12.
To have a as whole number, the divisor of 12 mu be odd.But the only whole positive odd numbers divisible by 12 are 1 and 3.
Therefore 2a - 1 = 3 <=> a = 2 or 2a - 1 = 1 <=>
a = 1 a = 2 or 2a - 1 = 1 <=> a = 1
Answer B
Question: A basket has 5 apples and 4 oranges. Three fruits are picked at random. The probability that at least 2 apples are picked is?
A.25/42
B.25/49
C.25/46
D.25/48
Answer: A.25/42
Explanation: Total fruits = 9
Since there must be at least two apples,
(⁵C₂ * ⁴C₁)/⁹C₃ + ⁵C₃/⁹C₃
= 25/42.
Answer:A
Question: A can do a piece of work in 12 days. When he had worked for 2 days B joins him. If the complete work was finished in 8 days. In how many days B alone can finish the work?
A.18 days
B.12 days
C.24 days
D.10 days
Answer: A.18 days
Explanation: Explanation:
8/12 + 6/x = 1
X = 18 days
Answer: A
Question: Which of the following is the sum of all the even numbers between 3 and 99, inclusive?
A.2550
B.2449
C.2600
D.2499
Answer: B.2449
Explanation: This question can be solved withbunching.
We're asked for the SUM of all of the EVEN integers from 1 to 99, so we really want the sum of 2, 4, 6, 8.....98.
If you take the next smallest and next biggest numbers, you have...
4+96 = 100
This pattern will continue on, so we're going to have a bunch of 100s, BUT we have to be careful to make sure that we don't miss a number if it'sin the middleand doesn't get paired up. Since we know that the sum of each pair is 100, we can 'jump ahead' to find the last few pairs...
44+56 = 100
46+54 = 100
48+52 = 100
There IS a middle number: 50; this number does NOT get paired up.
Since 48 is the 24th even integer, we know there are twenty-four 100s + one 50. 2400+50-1 = 2449
Final Answer:
B
Question: Before 5 years, dog A’s age was 4 times of dog B’s age and after 4 years, dog A’s age will be 3 times of dog B’s age. What is the difference of dog A’s age and dog B’s now?
A.36
B.42
C.58
D.60
Answer: C.58
Explanation: A - 5 = 4(B - 5) --> A - 4B = -15.............1
A + 4 = 3(B + 4) --> A - 3B = 8.............2
(2) - (1) --> B = 23 --> A =3(27)=81
A - B = 81 - 23 = 58
Answer: C
Question: Edward has $732,391 dollars in his savings account. What is the least amount of money (in whole number of dollars) that he must add from his account if he wants to split this money evenly among his nine children?
A.$1
B.$2
C.$3
D.$4
Answer: B.$2
Explanation: In order to divide the sum in 9 parts, the amount must be divisible by 9
Divisibility rule of 9: The sum of the digits must be divisible by 9
Sum of digits of 732,391 = 25 and 27 is divisible by 9.
Hence we need to add 2 to this number for it to be divisible by 9
Correct Option: B
Question: In a group of 28 junior high school students, 7 take French, 10 take Spanish, and 4 take both languages. The students taking both French and Spanish are not counted with the 7 taking French or the 10 taking Spanish. How many students are not taking either French or Spanish?
A.7
B.6
C.9
D.4
Answer: A.7
Explanation: A
7
Add 7 + 10 + 4 to get 21.
Then subtract 21 from the total students ⇒ 28 – 21 = 7.
Question: What will be the reminder when (43^43+43) is divided by 44?
A.32
B.42
C.83
D.71
Answer: B.42
Explanation: (x^n+1) will be divisible by (x+1) only when n is odd;
(43^43+1) will be divisible by (43+1);
(43^43+1)+42 when divided by 44 will give 42 as remainder.
Correct Option : B
Question: An article is bought for Rs.680 and sold for Rs.900, find the gain percent?
A.33 1/8%
B.33 8/3%
C.33 1/3%
D.32 6/17%
Answer: D.32 6/17%
Explanation: 680---- 220
100 ---- ? => 32 6/17%
Answer: D
Question: Skier Lindsey Vonn completes a straight 300-meter downhill run in t seconds and at an average speed of (x + 10) meters per second. She then rides a chairlift back up the mountain the same distance at an average speed of (x - 8) meters per second. If the ride up the mountain took 135 seconds longer than her run down the mountain, what was her average speed, in meters per second, during her downhill run?
A. 10
B. 15
C. 20
D. 25
Answer: C. 20
Explanation: Backsolving is the preferred approach for this one
300/(x-8) - 300/(x+10) = 135
We are asked for the value of x+10
So we can start with C = X+10 = 20
So x = 10
300/2 - 300 / 20 = 135
Hence answer is C
Question: At a certain supplier, a machine of type A costs $23,000 and a machine of type B costs $50,000. Each machine can be purchased by making a 20 percent down payment and repaying the remainder of the cost and the finance charges over a period of time. If the finance charges are equal to 40 percent of the remainder of the cost, how much less would 2 machines of type A cost than 1 machine of type B under this arrangement?
A.$5,280
B.$11,200
C.$12,000
D.$12,800
Answer: A.$5,280
Explanation: Total Cost of 2 Machines of Type A
= 20% of (Cost of 2 machine A) + remainder + 40 % remainder
= 20% of 46000 + (46000 - 20% of 46000) + 40% of (46000 - 20% of 46000)
= 60720
Total Cost of 1 Machine of Type B
= 20% of (Cost of 1 machine B) + remainder + 40 % remainder
= 20% of 50000 + (50000 - 20% of 50000) + 40% of (50000 - 20% of 50000)
= 66000
Diff = 66000 - 60720 = 5280
Hence, A.
Question: If the numerator of a fraction is increased by 20% and its denominator is diminished by 25% value of the fraction is 2/15. Find the original fraction.
A.1/12
B.1/8
C.1/6
D.1/4
Answer: A.1/12
Explanation: Explanation:
X * (120/100)
---------------- = 2/15
Y * (75/100)
X/Y = 1/12
ANSWER IS A
Question: Fred and Frank are partners in a business. Frank runs the business and for this he gets 7% of the profit , and the rest is divided in proportion to their capitals. If Frank invested 15000 and Fred invested 35000, find the share of Frank in a profit of 10000.
A.1166.7
B.2266.7
C.2766.7
D.2466.7
Answer: C.2766.7
Explanation: The amount Frank gets for managing
= 7% of Rs. 10000 = 700
Remaining profit = 10000 â€“ 700 = 9300
This is to be divided in the ratio 10000:35000=10: 35=2:7
Share of Frank = 2/9 of 9300 = 2066.7
â‡’ Total share of Frank = 700 + 2066.7 = 2766.7.
Answer C
Question: Mukesh weight 56.7 kg. If he reduces his weight in the ratio 7:6. New weight of Mukesh is ?
A.47.6
B.48.6
C.49.6
D.50.6
Answer: B.48.6
Explanation: Given ratio is 7:6;
let weight before and after reduction be 7x and 6x respectively.
A/Q
7x=56.7
=> x=56.7/7
=> x= 8.1
Reduced weight= 6x= 6*8.1= 48.6;
hence reduced weight= 48.6
ANSWER:B
Question: Annie will be half as old as Larry in 3 years. Annie will also be one-third as old as Jerome in 5 years. If Jerome is 13 years older than Larry, how old is Annie?
A.6
B.8
C.19
D.26
Answer: A.6
Explanation: J = L+13
(1) 2(A+3) = L+3
(2) 3(A+5) = J+5 = L+18
Let's subtract equation (1) from equation (2)
A+9 = 15
A = 6
The answer is A.
Question: The sum of all two digit numbers divisible by 8 is
A.910
B.510
C.611
D.616
Answer: D.616
Explanation: Required numbers are 16,24 . . . . . 96
This is an A.P. in which a=16,d=8 and l=96.
Let the number of terms in it be n.Then t=96
So a+(n-1)d=96.
16+(n-1)*8=96
16+8n-8=96
8+8n=96
8n=96-8
n = 88/8
then n=11.
Required sum
=n/2(a+l)
=11/2(16+96)
=616
Answer is D
Question: Last year’s receipts from the sale of greeting cards during the week before Mother’s Day totaled $240 million, which represented 12 percent of total greeting card sales for the year. Total greeting card sales for the year totaled how many million dollars?
A.2,010
B.2,000
C.2,890
D.2,701
Answer: B.2,000
Explanation: 12% ---- 240 millions
for 100% => ( 240 * 100% )/12% = 2000.
Option B.
Question: I chose a number and divide it by 5. Then I subtracted 154 from the result and got 6. What was the number I chose?
A.800
B.700
C.900
D.1000
Answer: A.800
Explanation: Let x be the number I chose, then
x5−154=6
x5=160
x=800.
So answer is A.
Question: For positive integer x, if the sum of all the digit of x is 170 where x and y are positive integers and x=1020-y, which of the following can be the value of y?
A.41
B.47
C.50
D.55
Answer: B.47
Explanation: ->10^20-y=99999….9( )[ ] is derived.
In this case, the number of the first digits of 9 is 18, which is 9*18=162.
Also, the sum of all digits is 170.
That is, it should be ( )+[ ]=170-162=8.
Then, one should be selected amongst y=29,38,47,56,6,5,74,83,92.
Since 47 is in the option, the answer is B.
Question: Today Mary’s father is four times as old as Mary. Eight years ago, he was 12 times as old. How old is Mary today?
A.6
B.7
C.10
D.11
Answer: D.11
Explanation: Dad's age = 4M
12*(M-8) = 4M-8
8M = 88
M = 11
The answer is D.
Question: Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000?
A.81000
B.29899
C.26798
D.27799
Answer: A.81000
Explanation: 64000* 9/8 * 9/8 = 81000.Answer: A
Question: 4,64,256,1024,...?
A.1096
B.2096
C.3096
D.4096
Answer: D.4096
Explanation: 4
4*16=64
4*64=256
4*256=1024
4*1024=4096
ANSWER:D
Question: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.84. How much was lent at 5%?
A.600
B.2998
C.277
D.500
Answer: A.600
Explanation: (x*5*1)/100 + [(1500 - x)*6*1]/100 = 84
5x/100 + 90 – 6x/100 = 84
x/100 = 6
=> x = 600.Answer: A
Question: Given a two-digit number, the unit's digit exceeds its ten's digit by 4 and the product of the given number and the sum of its digits is equal to 90, which of the options is the number?
A.26
B.15
C.37
D.62
Answer: B.15
Explanation: Using the elimination method the option that fits this description is 15
5-1 = 4 (unit's digit that exceeds its ten's digit by 4)
15*6 = 90 (the product of the given number and the sum of its digits is equal to 175)
answer :B
Question: 18 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?
A.8 days
B.6 days
C.7 days
D.9 days
Answer: D.9 days
Explanation: 1 women's 1 day work = 1/126
1 child's 1 day work = 1/140
(5 women + 10 children)'s 1 day work
= (5/126+ 10/140) = 1/9
5 women and 10 children will complete the work in 9 days.
Answer: D
Question: The LCM of three numbers is four times their GCF. Which of the following must be true of the numbers?
I. At least one of the numbers is odd.
II. Two of the three numbers must be same.
III. At least one number is the same as GCF.
A.only
B.option II only
C.and III only
D.and II only
Answer: B.option II only
Explanation: Consider the following set: {2, 4, 8}.
GCF = 2.
LCM = 8 = 4*2.
The set discards options I and II. Only B fits.
Answer: B.