RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Mangala completes a piece of work in 10 days, Raju completes the same work in 50 days. If both of them work together, then the number of days required to complete the work is?
A.8 days
B.10 days
C.12 days
D.50/6 days
Answer: D.50/6 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 Ã— 50/60 = 50/6 days
D)
Question: If x is less than y by 40% then y exceed x by:
A.33.33%
B.25%
C.75%
D.66.66%
Answer: D.66.66%
Explanation: Using formula (x/(100-x)*100) where x is Percentage decrease (here it is 40%)
=> 40/(100-40)*100
=66.66%
ANSWER:D
Question: A triangle has sides 10, 17, and 21. A square is inscribed in the triangle. One side of the square lies on the longest side of the triangle. The other two vertices of the square touch the two shorter sides of the triangle. What is the length of the side of the square?
A.148/29
B.168/29
C.168/26
D.158/29
Answer: B.168/29
Explanation: By Heron's Formula, the area, A, of a triangle with sides a, b, c is given by A = square root[s(s − a)(s − b)(s − c)], where s = ½(a + b + c) is the semi-perimeter of the triangle.
Then s = ½(10 + 17 + 21) = 24, and A = 84.
A square inscribed in a 10 by 17 by 21 triangle, with perpendicular dropped onto the side of length 21.
Now drop a perpendicular of length h onto the side of length 21.
We also have A = ½ × base × perpendicular height.
Hence A = 21h/2 = 84, from which h = 8.
Notice that the triangle above the square is similar to the whole triangle. (This follows because its base, the top of the square, is parallel to the base of the whole triangle.)
Let the square have side of length d.
Considering the ratio of altitude to base in each triangle, we have 8/21 = (8 − d)/d = 8/d − 1.
Therefore the length of the side of the square is 168/29.
ANSWER:B
Question: A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
A.66
B.11
C.40
D.21
Answer: C.40
Explanation: Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (2/25) = 40 seconds.Answer: C
Question: When E is divided by 5, the remainder is 3. When y is divided by 5, the remainder is 4. What is the remainder when E + y is divided by 5?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: In my view the answer should be C
E/5 has Remainder=3 -> E = 5 x Q + 3
Y/5 has a Remainder=4 -> Y = 5 x Q + 3
Combining both
((5 x Q1 + 3) + (5 x Q2 + 3))/5 =
5(Q1+Q2)/5 + 7/5 =
Q1+Q2 + 7/5
7/5 = 1+ 2/5 => Remainder 2
Answer C
Question: David spends $350 buying his favorite dolls. If he buys only small LemonHead dolls, which are $2 cheaper than the large LemonHead dolls, he could buy 20 more dolls than if he were to buy only large LemonHead dolls. How much does a large LemonHead doll cost?
A.$5
B.$7
C.$6
D.$8
Answer: B.$7
Explanation: If large doll costs $5, then he can buy 350/5 = 70 large dolls and 350/3 =116 small dolls. Difference is more than 20. Discard.
If large doll costs $7, then he can buy 350/7 = 50 large dolls and 350/5 =70 small dolls.
Difference is 20, which is we wanted.
Answer B.
Question: There are three secretaries who work for four departments. If each of the four departments have one report to be typed out, and the reports are randomly assigned to a secretary, what is the probability Z that all three secretary are assigned at least one report?
A.8/9
B.64/81
C.4/9
D.16/81
Answer: C.4/9
Explanation: For each report there are three possible outcomes: Secretary A, Secretary B, Secretary C
Total outcome: 3^3=27
Total outcome that three secretary are assigned at least one report: P(3,3)=3!=6
Probability Z= 6/27=2/9=C
Question: A certain hospital has a policy that for every 50 patients there should be 2 doctors. If the number of patients visiting the hospital every day is 400, how many doctors are there in the hospital?
A.4
B.16
C.5
D.14
Answer: B.16
Explanation: 2/50=x/400
x=16
Answer is B
Question: There are two cars. One is 160 miles north of the other. Simultaneously, the car to the north is driven westward at 10 miles per hour and the other car is driven eastward at 30 miles per hour. How many miles apart are the cars after 3 hours?
A.180
B.200
C.220
D.240
Answer: B.200
Explanation: Here, drawing a quick sketch of the 'actions' described will end in a diagonal line that you canbuilda right triangle around:
The right triangle will have a base of 120 and a height of 160. The hidden pattern here is a 3/4/5 right triangle (the 120 lines up with the '3' and the 160 lines up with the '4'). In this way, you can deduce that each side is '40 times' bigger than it's corresponding side:
3/4/5 becomes
120/160/200
Thus the distance between the two cars is the length of the hypotenuse of this larger right triangle...
Final Answer:
B
Question: Tom can hit a target 3 times in 6 shots, Karan can hit the target 2 times in 6 shots & Ashwini can hit 4 times in 4shots. What is the probability that at least 2 shots hit the target ?
A.1/2
B.2/5
C.2/3
D.3/7
Answer: C.2/3
Explanation: Ashwini hits the target definitely, hence required probability that atleast 2 shots hit the target is given by
Karan hits tha target and Raja not hit the target.
or
Karan does not hit the target and Raja hits the target.
or.
Karan hits the target and Raja hits the target
= 2/6 x 3/6 + 4/6 x 3/6 + 2/6 x 3/6
= 24/36 = 2/3
C
Question: A car manufacturer produces only red and blue models which come out of the final testing area at random. What is the probability that five consecutive cars of same color will come through the test area at any one time?
A.1 in 16
B.1 in 125
C.1 in 32
D.1 in 25
Answer: A.1 in 16
Explanation: 2*(1/2)^5 =1 in 16
AS THERE ARE 5 CARS AND 2 TYPES
ANSWER:A
Question: A dice is rolled 3times & sum of 3 no.'sappearing on the uppermost face is 15. The chance that the first roll was four is?
A.1/21
B.1/31
C.1/108
D.1/113
Answer: C.1/108
Explanation: Sol. Total number of favorable outcomes n(S) . e . 216 Combinations of outcomes for getting sum of 15 on uppermost face = (4, 5, 6) (5, 4, 6) (6, 5, 4) (5, 6, 4), (4, 6, 5), (6, 4, 5), (5, 5, 5), (6, 6, 3), (6, 3, 6) (3, 6, 6) Now outcomes on which first roll was a four, n(E) = (4, 5, 6), (4, 6, 5) P(E) n(E) 2 1 Pt') = n(S) = 216 = 1/108
C
Question: Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
A.50
B.55
C.100
D.25
Answer: A.50
Explanation: Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
=10 x5/18	m/sec
=25/9m/sec
2 x/36=25/9
2x = 100
x = 50.
Answer A
Question: Sam invested Rs. 15000 @ 10% per annum for one year. If the interest is compounded half-yearly, then the amount received by Sam at the end of the year will be?
A.Rs.16,537.58
B.Rs.16,537.52
C.Rs.16,537.50
D.Rs.16,537.22
Answer: C.Rs.16,537.50
Explanation: P = Rs. 15000; R = 10% p.a. = 5% per half-year; T = 1 year = 2 half-year
Amount = [15000 * (1 + 5/100)2]
= (15000 * 21/20 * 21/20)
= Rs. 16537.50
Answer:C
Question: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.50 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
A.160
B.170
C.190
D.200
Answer: B.170
Explanation: Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.50 + X x 3.20 = 432
X = 10.
Hence, total hours of work = (160 + 10) = 170.
answer :B
Question: The number x of cars sold each week varies with the price y in dollars according to the equation x = 800,000 – 50y. What would be the total weekly revenue, in dollars, from the sale of cars priced at $ 13,000?
A.1,950,000,000
B.750,000
C.850,000
D.7,500,000
Answer: A.1,950,000,000
Explanation: number of cars sold = x=800000-50y
y=13000
x=800000-650000=150000
revenue from 150000 cars=13000*150000=1,950000000 A
Question: A grocer purchased 80 kg of sugar at 13.50 per kg and mixed it with 120 kg sugar at 16 per kg. At what rate should he sell the mixture to gain 16%?
A.17 per kg
B.17.40 per kg
C.16.5 per kg
D.16 per kg
Answer: B.17.40 per kg
Explanation: C.P. of 200 kg of mixture = (80 × 13.50 + 120 × 16)
= 3000.
S.P. = 116% of 3000 = (116⁄100 × 3000) = 3480
∴ Rate of S.P. of the mixture = (3480⁄200) per kg
= 17.40 per kg.
Answer B
Question: When q is divided by 5, the remainder is 3. When y is divided by 5, the remainder is 4. What is the remainder when q + y is divided by 5?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: In my view the answer should be C
q/5 has Remainder=3 -> q = 5 x Q + 3
Y/5 has a Remainder=4 -> Y = 5 x Q + 3
Combining both
((5 x Q1 + 3) + (5 x Q2 + 3))/5 =
5(Q1+Q2)/5 + 7/5 =
Q1+Q2 + 7/5
7/5 = 1+ 2/5 => Remainder 2
Answer C
Question: Find the cost of fencing around a circular field of diameter 35 m at the rate of Rs.1.50 a meter?
A.287
B.132
C.156
D.115.5
Answer: D.115.5
Explanation: 2 * 22/7 * 17.5 = 110
110 * 1 1/2 = Rs.115.5
Answer: D
Question: In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is 2/3 of the number of students of 8 years of age which is 24. What is the total number of students in the school?
A.50
B.80
C.120
D.150
Answer: A.50
Explanation: Explanation: Let the number of students be x.
Then, Number of students above 8 years of age = (100 - 20)% of x = 80% of x.
80% of x = 24 + 2/3 of 24
80/100x = 40
x = 50.
Answer: Option A
Question: .A man has Rs. 312 in the denominations of one-rupee notes, five-rupee notes and twenty-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
A.36
B.24
C.28
D.32
Answer: A.36
Explanation: Let number of notes of each denomination =x Then
x+5x+20x=312
⇒26x=312
⇒x=312/26=12
Total number of notes =3x=3×12=36
Answer: A
Question: A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 20 years now, the son's age five years back was:
A.2 years
B.14 years
C.5 years
D.38 years
Answer: C.5 years
Explanation: Let the son's present age be x years.
Then, (20 - x) = x
2x = 20 => x = 10
Son's age 5 years back = (10 - 5) = 5 years.
ANSWER:C
Question: A Sum of Rs.2600, is lent out in 2 parts SI at 10% for 5yrs is equal to SI on 2nd part at 9% rate for 6 yrs. find the ratio of parts.
A.21:25
B.27:25
C.21:23
D.31:25
Answer: B.27:25
Explanation: Solution :
Given SI1 = SI 2
P1 : P2 = 1/R1T1 : 1/R2T2
= 1/(10*5) : 1/(9:6)
27:25
B
Question: When a number is divided by 13, the remainder is 11. When the same number is divided by 17, then remainder is 9. What is the number ?
A.339
B.349
C.369
D.359
Answer: B.349
Explanation: Explanation:
x = 13p + 11 and x = 17q + 9
13p + 11 = 17q + 9
17q - 13p = 2
q =	2 + 13p
17
The least value of p for which q =	2 + 13p	is a whole number is p = 26
17
x = (13 x 26 + 11)
= (338 + 11)
= 349
Answer: B
Question: On a wedding catering service, An experienced chef can prepare a service for a wedding in 5 hours while an novice chef would finish the preparations in 9 hours.
If the catering service employs the same number of novice and experienced chefs, then how many chefs would it take to prepare a wedding service in 1 hour and 36 minutes?
A.2
B.3
C.4
D.6
Answer: C.4
Explanation: Experienced chefs work = 1 wedding/5 hours
Novice chefs work = 1 wedding/9 hours
Since we don't know the number of experienced or novice chefs but know that there is an equal number each, let the number of chefs for each group equalx
1hr and 36mins = 8/5 an hour
x/5 + x/9 = 1 wedding / (8/5)
x/5 + x/9 = 5/8
x=2
So there are 2 novice chefs and 2 experienced chefs. In total there are 4. The answer is C.
Question: After spending Rs. 5000 on rent, Rs. 1500 on milk, Rs. 4500 on groceries, Rs.2500 On childrens education Rs. 2000 on petrol and Rs. 5200 on miscellaneous expenses, Mr. Kishore saved 10% of his monthly salary. How much did he save in Rs. ?
A.2160
B.2350
C.2000
D.2300
Answer: D.2300
Explanation: Explanation :
Total Exp = 5000+1500+4500+2500+2000+5200 = 20700
Exp in % = 100-10 = 90%, 20700 = 90%
Saving = 10 % = 20700 X 10/90 = Rs. 2300
Answer : D
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
A.12.8
B.12.1
C.12.0
D.12.2
Answer: B.12.1
Explanation: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.
Answer:B
Question: A lady bought five books namely A,B,C,D,E to distribute her 7 friends. How many ways she can distribute books?
A.7^3
B.7^4
C.7^5
D.7^6
Answer: C.7^5
Explanation: 7*7*7*7*7
7^5
ANSWER:C
Question: What is the ratio between perimeters of two squares one having 4 times the diagonal then the other?
A.3: 8
B.3: 6
C.3: 7
D.4: 1
Answer: D.4: 1
Explanation: d = 4d d = d
a√2 = 4d a√2 = d
a = 4d/√2 a = d/√2 => 4: 1
Answer:D
Question: In how many ways can 5 man draw water from 5 taps if no tap can be used more than once?
A.None of these
B.720
C.60
D.120
Answer: D.120
Explanation: Explanation :
1st man can draw water from any of the 5 taps
2nd man can draw water from any of the remaining 4 taps
3rd man can draw water from any of the remaining 3 taps
4th man can draw water from any of the remaining 2 taps
5th man can draw water from remaining 1 tap
5	4	3	2	1
Hence total number of ways = 5 x 4 x 3 x 2 x 1 = 120. Answer : Option D
Question: Which number is the odd one out?
A.47632
B.36119
C.84129
D.67626
Answer: A.47632
Explanation: A
47632
All the others are three digit numbers followed by their square root, eg 361 followed by its square root, 19.
Question: The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?
A.23:33:60
B.10:11:20
C.3:4:5
D.10:20:11
Answer: A.23:33:60
Explanation: Let A = 2k, B = 3k and C = 5k.
The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?
[A].	3 : 3 : 10
[B].	10 : 11 : 20
[C].
23 : 33 : 60	@
[D].	Cannot be determined
Answer: Option C
Explanation:
Let A = 2k, B = 3k and C = 5k.
A sal = 115/100 of 2k = 23k/10
B sal = 110/100 of 3 k=33k/10
c sal= 6k
new ratio (23k/10:33k/10:6k) = 23:33:60
ANSWER A
Question: Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
A.5/5
B.5/9
C.3/4
D.5/7
Answer: C.3/4
Explanation: In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.
Then, E	= {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4),
(3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1),
(6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}=27
The probability = 27/36 = 3/4.
Answer: C
Question: The sum of the first 50 positive even integers is 2550. What is the sum of the even integers from 602 to 700 inclusive?
A.24,550
B.28,550
C.32,550
D.36,550
Answer: C.32,550
Explanation: 2 + 4 + 6 + 8 +...+ 100 = 2550
602 + 604 + ... + 700 = 50(600) + (2+4+...+100) = 30,000 + 2550 = 32,550
The answer is C.
Question: If x and y are positive integers, and 1 is the greatest common divisor of x and y, what is the greatest common divisor G of 2x and 3y?
A.G=1
B.G=Cannot be determined
C.G=2
D.5
Answer: B.G=Cannot be determined
Explanation: My explanation: from question stem we know that nothing is common between X and Y , X and Y are two prime numbers eg: X=2, Y=3 and their GCD(2,3) =1 and so 2X and 3Y will have a GCD(2X,3Y) = 1 . what if either X or Y was 1, eg: X=1,Y=4 then GCD (1,4) =1 , but GCD(2,12) = 2.
and hence answer B
Question: The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 20 are excluded, the average mark of the remaining will be 95. Find the number of students who wrote the exam.
A.15
B.45
C.35
D.25
Answer: D.25
Explanation: Let the number of students who wrote the exam be x.
Total marks of students = 80 x.
Total marks of (x - 5) students = 95(x - 5)
80x - (5 * 20) = 95(x - 5)
375 = 15x => x = 25
ANSWER:D
Question: How many of the positive factors of 10 , 16 and how many common factors are there in numbers?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: factors of 12 - 1, 2, 3, 4, 6, and 12
factors of 16 - 1 , 2, 4, 8 and 16
Comparing both, we have three common factors of 45,16-3
Answer C
Question: Which among the following is the greatest?
A.2^3^2
B.2^2^3
C.3^2^3
D.3^3^3
Answer: D.3^3^3
Explanation: 2^3^2 = 29
2^2^3 = 28
3^2^3 = 38
3^3^3 = 327
As 327 > 38, 29 > 28 and 327 > 29. Hence 327 is the greatest among the four.
ANSWER:D
Question: A and B invests Rs.3000 and Rs.6000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit?
A.3:4
B.9:8
C.9:9
D.9:5
Answer: A.3:4
Explanation: (3*6 + 6*6): (6*12)
54:72 => 3:4
Answer: A
Question: The difference between a two digit number and the number obtained by interchanging the digits is 72. What is the difference between the digits of the number?
A.7
B.5
C.6
D.8
Answer: D.8
Explanation: Description :
=> (10x+y)-(10y+x)=72
=> 9(x-y)=72
=> x-y = 8
Answer D
Question: Two dogsled teams raced across a 600-mile course in Alaska. Team A finished the course in 6 fewer hours than team B. If team A’s average speed was 5 miles per hour greater than that of team B, what was team B’s average speed, in miles per hour?
A.12
B.15
C.18
D.20
Answer: D.20
Explanation: Let v be team B's average speed.
Time = Distance/Rate and the time difference was 6 hours.
600/v - 600/(v+5)= 6
600v + 3000 - 600v = 6(v)(v+5)
500 = (v)(v+5)
(20)(25) = (v)(v+5)
v = 20 mph
The answer is D.
Question: An investor invests in a new fund. The fund averages 10% growth annually for the first three years, but it loses 25% of its value in the fourth year. At the end of four years, the value of the fund is approximately what percent of the original amount?
A.99.825%
B.97.785%
C.95.125%
D.93.675%
Answer: A.99.825%
Explanation: 0.75*1.1^3 = 0.99825
The answer is A.
Question: How many factors of 60 are odd numbers greater than 1?
A.3
B.4
C.5
D.3
Answer: D.3
Explanation: prime factors of 60 are 2^2,3^1,5^1
total divisors = (power if a prime factor+1)
total no. of odd factors(3,5,) = (1+1)(1+1)=4
since we need odd divisors other than 1 =>4-1 = 3 odd divisors
D is the answer
Question: The length of a rectangular plot is 10 meters more than its width. If the cost of fencing the plot at $15.50 per meter is $868, what is the length of the plot in meters?
A.17
B.19
C.21
D.23
Answer: B.19
Explanation: perimeter = 2L + 2W = 2L + 2(L-10) = 4L - 20
cost of fencing = (4L - 20) * 15.50 = 62L - 310 = 868
62L = 1178
L = 19 meters
The answer is B.
Question: In a class of 38 children,19 play tennis, 21 play squash and 10 play neither sport. (1)how many children play both sports?
A.11
B.12
C.14
D.15
Answer: B.12
Explanation: 28 play some sport
19+21-both=28
both = 12
Answer is B
Question: Sharron bakes 6 cookies for 6 friends. 2 of the friend arrive early and eat 3 cookies each. How many cookies are left over if the other friends all have the same number of cookies?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: Sharron made 6*6 cookies = 36 cookies. 2 friends eat 3 cookies, leaving 30 remaining for 4 friends.
30=2*3*5. 30 is not divisible by 4. The 4 friends ate a cumulative number of cookies less than 30 that must be divisible by 4, because the number is the same.
A 30 -1=29. 29=1*29, cannot be divided by four
B 30-2=28. 28=2*2*7, can be divided by four
C 30-3 = 27. 27=3*3*3, cannot be divided by four
D. Because there are 4 people, 4 cannot be a remainder (remainder = 0)
E. Because there are 4, people, 5 cannot be a remainder (remainder = 1)
B is the correct answer
Question: A trader sells 30 meters of cloth for Rs. 4500 at the profit of Rs. 10 per metre of cloth. What is the cost price of one metre of cloth?
A.Rs. 80
B.Rs. 185
C.Rs. 140
D.Rs. 295
Answer: C.Rs. 140
Explanation: SP of 1m of cloth = 4500/30 = Rs. 150
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 150 - Rs. 10 = Rs. 140.
ANSWER:C
Question: A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold?
A.480
B.992
C.772
D.662
Answer: A.480
Explanation: 1/x - 1/20 = -1/24
x = 120
120 * 4 = 480
Answer:A
Question: What is the average (arithmetic mean) of all multiples of 10 from 10 to 600 inclusive?
A.190
B.195
C.305
D.205
Answer: C.305
Explanation: This question can be solved with the Average Formula and 'bunching.'
We're asked for the average of all of the multiples of 10 from 10 to 600, inclusive.
To start, we can figure out the total number of terms rather easily:
1(10) = 10
2(10) = 20
...
60(10) = 600
So we know that there are 60 total numbers.
We can now figure out the SUM of those numbers with 'bunching':
10 + 600 = 610
20 + 590 = 610
30 + 580 = 610
Etc.
Since there are 60 total terms, this pattern will create 30 'pairs' of 610.
Thus, since the average = (Sum of terms)/(Number of terms), we have...
(30)(610)/(60) =305
Final Answer: C
Question: Find the C.I. on a sum of Rs.1600 for 9 months at 20% per annum, interest being compounded quarterly?
A.2528
B.2526
C.2522
D.2722
Answer: C.2522
Explanation: A = 1600(21/20)3 = 2522
Answer: C
Question: The speed of a boat in still water in 26 km/hr and the rate of current is 6 km/hr. The distance travelled downstream in 20 minutes is:
A.10.4 km
B.10.66 km
C.11.4 km
D.11.22 km
Answer: B.10.66 km
Explanation: Explanation:
Speed downstream = (26 + 6) = 32 kmph
Time = 20 minutes = 20/60 hour = 1/3 hour
Distance travelled = Time × speed = (1/3)×32 = 10.66 km
Answer: Option B
Question: If I walk at 3 kmph, I miss the train by 2 min, if however, I walk at 4 kmph. I reach the station 2 min before the arrival of the train. How far do I walk to reach the station?
A.4/5
B.4/9
C.4/6
D.4/2
Answer: A.4/5
Explanation: x/3 – x/4 = 4/60
x = 4/5 km
Answer: A
Question: How many four digit numbers can be formed using the digits {1, 3, 4, 5, 7,9}(repetition of digits is not allowed)?
A.360
B.729
C.365
D.735
Answer: A.360
Explanation: The given digits are six.
The number of four digit numbers that can be formed using six digits is ⁶P₄
= 6 * 5 * 4 * 3 = 360.
Answer:A
Question: The average age of A, B and C is 26 years. If the average age of A and C is 29 years, what is the age of B in years ?
A.19
B.35
C.20
D.32
Answer: C.20
Explanation: C
20
Age of B = Age of (A + B + C) – Age of (A + C) = 26 × 3 – 29 × 2 = 78 – 58 = 20 years
Question: If -1<= x <= 2 and 3 <= y <= 8, which of the following represents the range of all possible values of y-x?
A. 5 <= y-x <= 6
B. 1 <= y-x <= 5
C. 1 <= y-x <= 6
D. 1 <= y-x <= 9
Answer: D. 1 <= y-x <= 9
Explanation: Maximum value of y-x= 8 - (-1)= 9
Minimum value of y-x= 3-2= 1
D mentions the correct range
Question: How many numbers up to 300 and 700 are divisible by 2, 3 and 7 both together?
A.9
B.12
C.5
D.8
Answer: A.9
Explanation: Answer: Option A
(700 â€“ 300)/42 = 9 22/42 => 9 Numbers
Question: A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 100. How much did he have with him in the beginning?
A.Rs 200
B.Rs 250
C.Rs 300
D.Rs 450
Answer: B.Rs 250
Explanation: Suppose the amount in the beginning was Rs ’x’
Money spent on clothes = Rs 1x/3 Balance = Rs 2x/3
Money spent on food = 1/5 of 2x/3 = Rs 2x/15
Balance = 2x/3 - 2x/15 = Rs 8x/15
Money spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5
Therefore 2x/5 = 100 = 250
ANSWER:B
Question: A man said to his son, "I was two-third of your present age when you were born". If the present age of the man is 48 years, find the present age of the son?
A.25.7 years
B.28 years
C.29.3 years
D.28.8 years
Answer: D.28.8 years
Explanation: Explanation:
Present age of the son be P, he was born P years ago.
The age of the man was: (48 - P).
His age when the son was born should be equal to 2/3 of P.
(48 - P) = 2/3 P
5P = 144 => P = 28.8
ANSWER IS D