RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If a, b, y are integers, 33 = aby, and a < b < y, what is the smallest possible value of a?
A.-33
B.-3
C.1
D.3
Answer: A.-33
Explanation: Given : a * b * y = 33.
33 is a Positive Odd number.Side Note:Thus, all 3 numbers will be odd.
Prime factorization will also give you numbers. 1, 3, 11. The 3 numbers will be combination of these 3 numbers with possible variation in sign(+/-).
We could have any 2 digits as negative. --> negative * negative * positive. We have negative values in answer option, so eliminate C, D and E from answer choices.
-33 * -1 * 1 = 33.
Correct answer is A
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?
A.15 sec
B.19 sec
C.12 sec
D.10 sec
Answer: C.12 sec
Explanation: Explanation:
D = 250 m + 250 m = 500 m
RS = 80 + 70 = 150 * 5/18 = 125/3
T = 500 * 3/125 = 12 sec
Answer: Option C
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 120 m and they cross each other in 8 sec, then the speed of each train is?
A.54
B.77
C.36
D.88
Answer: A.54
Explanation: Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/8 => x = 15
Speed of each train = 15 m/sec.
= 15 * 18/5 =- 54 km/hr.Answer: A
Question: If a tire rotates at 400 revolutions per minute when the car is traveling 168km/h, what is the circumference of the tire?
A.7 meters
B.9 meters
C.8 meters
D.5 meters
Answer: A.7 meters
Explanation: 400 rev / minute = 400 * 60 rev / 60 minutes
= 24,000 rev / hour
24,000 * C = 168,000 m : C is the circumference
C = 3 meters
correct answer A
Question: Each month, after Jill pays for rent, utilities, food, and other necessary expenses, she has one fifth of her net monthly salary left as discretionary income. Of this discretionary income, she puts 30% into a vacation fund, 20% into savings, and spends 35% on eating out and socializing. This leaves her with $105 dollar, which she typically uses for gifts and charitable causes. What is Jill’s net monthly salary?
A.$2400
B.$3200
C.$3500
D.$6400
Answer: C.$3500
Explanation: let x be the monthly salary
15%of 1/5*x=105
x=3500
answer C
Question: 75 persons Major in physics, 83 major in chemistry, 10 not at major in these subjects u want to find number of students majoring in both subjects
A.65
B.66
C.67
D.68
Answer: D.68
Explanation: Consider the number of total students = n(T) = 100
number of persons Major in physics = n(P) = 75
number of persons Major in chemistry = n(C) = 83
According to the question ;
10 not at major in these subjects = n(P'∩ C') = 10
n(P'∩ C') = n(P U C)' = 10
n(P U C)' = n(T) - n(P U C)
10 = 100 - n(P U C)
n(P U C) = 90
n(P U C) = n(P) + n(C) - n(P ∩ C)
90 = 75 + 83 - n(P ∩ C)
n(P ∩ C) = 158 - 90
n(P ∩ C) = 68
number of students majoring in both subjects WILL be 68
ANSWER:D
Question: A man, his wife and daughter worked in a graden. The man worked for 3 days, his wife for 2 days and daughter for 4 days. The ratio of daily wages for man to women is 5 : 4 and the ratio for man to daughter is 5 : 3. If their total earnings is mounted to Rs. 105, then find the daily wage of the daughter.
A.Rs. 15
B.Rs. 12
C.Rs. 10
D.Rs. 9
Answer: D.Rs. 9
Explanation: EXPLANATION:
Assume that the daily wages of man, women and daughter are Rs 5x, Rs. 4x, Rs 3x respectively.
Multiply (no. of days) with (assumed daily wage) of each person to calculate the value of x.
[3 x (5x)] + [2 x (4x)] + [4 x (3x)] = 105
[15x + 8x + 12x] = 105
35x = 105
x = 3
Hence, man's daily wage = 5x = 5 x 3 = Rs. 15
Wife's daily wage = 4x = 4 x 3 = Rs. 12
Daughter's daily wage = 3x = 3 x 3 = Rs. 9
ANSWER IS D
Question: Of the 160 people at a party, 70 were women, and 50 women tried the appetizer. If 50 people did not try the appetizer, what is the total number of men who tried the appetizer?
A.40
B.50
C.60
D.70
Answer: C.60
Explanation: Total people at party=160
Women=70
so Men 160-70=90
No. of pple who tried appetizer=160-50 (given info)=110
No of women who tried appetizer=50
So Remaining ppl(men) who tried the appetizer =110-50=60
Correct Option C
Question: One pipe can fill a pool 1.5 times faster than a second pipe. When both pipes are opened, they fill the pool in five hours. How long would it take to fill the pool if only the slower pipe is used?
A.11.25
B.11.52
C.12.5
D.9
Answer: C.12.5
Explanation: Say the rate of the slower pipe is R pool/hour, then the rate of the faster pipe would be 1.5R=3R/2. Since when both pipes are opened, they fill the pool in five hours, then their combined rate is 1/5 pool/hour.
Thus we have that R + 3R/2 = 1/5 --> R = 2/25 pool/hour --> time is reciprocal of rate thus it's 25/2 =12.5 hours.
Answer: C.
Question: Find the ratio between 1hr 30 minutes and 2hrs 40 minutes.
A.9:16
B.5:9
C.12:17
D.13:24
Answer: A.9:16
Explanation: Solution: The ratio = 1hr 30 min : 2hr 40 min. 90 min : 160 min = 9 : 16.
ANSWER IS A
Question: A man can row upstream at 25 kmph and downstream at 31 kmph, and then find the speed of the man in still water?
A.22
B.28
C.30
D.27
Answer: B.28
Explanation: US = 25
DS = 31
M = (31 + 25)/2 = 28
Answer:B
Question: The length of the bridge, which a train 130 m long and traveling at 45 km/hr can cross in 30 sec is?
A.187 m
B.279 m
C.245 m
D.279 m
Answer: C.245 m
Explanation: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (130 + x)/30 = 25/2
x = 245 m.
Answer: C
Question: A, B AND C TOGETHER EARN RS. 300 PER DAY WHILE A AND C TOGETHER EARN RS. 188 AND B AND C TOGETHER EARN RS. 152. THE DAILY EARNING OF C IS:
A.RS. 40
B.RS. 68
C.RS. 112
D.RS. 150
Answer: A.RS. 40
Explanation: B'S DAILY EARNING = RS. (300-188)=RS. 112
A'S DAILY EARNING = RS. (300=152)-RS. 148.
C'S DAILY EARNING = RS. (300-(112+148))=RS. 40
CORRECT OPTION: A
Question: A rectangular field has a length 10 meters more than it is width. If the area of the field is 119, what is the length (in meters) of the rectangular field?
A.13
B.15
C.17
D.19
Answer: C.17
Explanation: area = l * w = (L) * (L-10) = 171
trial and error:
20*10 = 200 (too high)
19*9 = 171 (too high)
18*8 = 144 (too high)
17*7 = 119
The length is 17 meters.
The answer is C.
Question: A tailor trims 6 feet from opposite edges of a square piece of cloth, and 5 feet from the other two edges. If 80 square feet of cloth remain, what was the length of a side of the original piece of cloth?
A.16
B.18
C.20
D.24
Answer: C.20
Explanation: Let the original side of the square be x.
(x-12)*(x-10) = 80 = 8*10
x = 20
The answer is C.
Question: How much pure alcohol should be added to 400ml of a 15% solution to make the strength of solution 28%?
A.100 ml
B.60 ml
C.120 ml
D.140 ml
Answer: D.140 ml
Explanation: we can also go by answer choices
Tke 100 ml for eg
400 (old)+100 (new concentr)ml
500*28/100 = 140 ml (40ml is de old concentration +100 ml (newly added)
Answer D
Question: The ratio of the ages of three people is 4:6:7. Six years ago, the sum of their ages was 50. Find their present ages.
A.12,18,21
B.16,24,28
C.20,30,35
D.24,36,42
Answer: B.16,24,28
Explanation: Let the present ages be 4x, 6x, 7x.
(4x-6) + (6x-6) + (7x-6) = 50
17x = 68
x = 4
Their present ages are 16, 24, and 28.
The answer is B.
Question: The symphony sells two kinds of tickets: orchestra, for $30, and upper tiers, for $12. On a certain night, the symphony sells 90 tickets and gets $1800 in revenue from the sales. How many orchestra tickets did they sell?
A.20
B.30
C.40
D.50
Answer: C.40
Explanation: Let x be the number of orchestra tickets.
Then 90-x is the number of upper tier tickets.
30x + 12(90-x) = 1800
18x = 1800-1080
x = 40
The answer is C.
Question: what is the sum of all 5 digits numbers which can be formed with the digits 0,1,2,3,4 without repetition
A.2599980
B.2699980
C.2799980
D.2509980
Answer: A.2599980
Explanation: There is a simplest formula for solving these type of questions when we are using numbers along with 0 for finding sum.
i,e........(sum of numbers)*{(n-1)!*(111...........n times)-(n-2)!*(111..........(n-1)times) }
so,here by putting the values as,
(0+1+2+3+4){(5-1)!*(11111)-(5-2)!*1111}
= 10{(4!*11111)-(3!*1111)}
= 10{266664-6666}
= 2599980
ANSWER:A
Question: A merchant sold two items for Rs.1700 each, and makes a profit of 25% from the first item and a loss of 20% from the second item. calculate the total gain or loss.
A.7
B.5
C.3
D.6
Answer: B.5
Explanation: (25*20)/100 = 5%loss
Answer: B
Question: I have only 1$ and 2$ note. I want to give 95$ to John. How many maximum number of 2$ note I need?
A.39
B.95
C.47
D.55
Answer: C.47
Explanation: Check whether 95 is divisible by 2 then that is maximum no of 2$ note
else check next maximum term before 95
so 94/2=47
ans is C
Question: An amount of money is to be divided among P, Q and R in the ratio of 4 : 9 : 16. If R gets 4 times more than P, what is Q’s share in it?
A.1,800
B.2,700
C.3,600
D.Data inadequate
Answer: D.Data inadequate
Explanation: Here, neither the total amount nor the individual amount is given. So the share of Q cannot be determined.
Answer D
Question: If x is an integer and y = 3x + 7, which of the following CANNOT be a divisor of y?
A.4
B.5
C.7
D.9
Answer: D.9
Explanation: For any value of x, the expression 3x + 2 would never be divisible by 3,6,9...... onwards
So answer = 6 = D
Question: Addison High School’s senior class has 200 boys and 160 girls. If 60% of the boys and 75% of the girls attended college, what percentage of the total class that did not attend college?
A.33.33
B.60
C.80
D.66.67
Answer: D.66.67
Explanation: Number of boys attending the college: 0.60*200 = 120
number of girls attending the college: 0.75*160 = 120
Total attending = 120+120 = 240
Total people = 200+160 = 360
% of people attending = 240/360 = 66.67%. D is the correct answer
Question: How many seconds will a 500 metre long train moving with a speed of 63 km/hr, take to cross a man walking with a speed of 3 km/hr in the direction of the train ?
A.30
B.40
C.50
D.20
Answer: A.30
Explanation: Dist = 500 m
relative speed = (63-3) = 60 km/hr
60*5/18 = 50/3 m/s
time taken = 500/(50/3) = 30 sec
ANSWER A
Question: If n^2 = m^2, which of the following must be true?
A.n = m
B.n = -m
C.n = |m|
D.|n| = |m|
Answer: D.|n| = |m|
Explanation: Solution:
We are given that n^2 = m^2, and we can start by simplifying the equation by taking the square root of both sides.
√n^2 = √m^2
When we take the square root of a variable squared, the result is the absolute value of that variable. Thus:
√n^2 = √m^2 is |n| = |m|
Note that answer choices A through D could all be true, but each of them would be true only under specific circumstances. Answer choice E is the only one that is universally true.
Answer: D
Question: If n is a positive integer, what is the remainder when (6^(4n+3))(6^n) is divided by 10?
A.7
B.2
C.4
D.6
Answer: A.7
Explanation: This one took me bout 3 1/2 min. Just testin numbers and what not.
First notice that n is positive. Save time by noticing thatI worked out one solution where n=0 only to find that thats not an option :p.
1-7 stands for ^1 thru 6
1: 7*1=7
2: 7*7=9
3: 7*9=3
4: 7*3=1
5: 7*1=7
6: 7*7=9
7: 7*9=3
Pattern repeats every @ 5. Notice every ^4 or multiple of 4 is always going to be 1. This is just for future notice for similar problems.
so 7^4n+3 ---> if n=1 then its ((7^7)*6))/10 which can say is going to be 3*8--> 18/10 --> R=8
Now from here if id double check just to make sure.
7^4(2)+3*6^2 ---> 7^11*36 or we can just say again 7^11*6 (b/c we are only interested in the units digit).
Since ^12 is going to be 1 that means ^11 is going to be 3 (as taken from our pattern)
so again 3*6=18/10 ---> R =7.
A or J in this problem.
Question: An amount of Rs. 55000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 3/4 %, then the amount invested in each share was?
A.s. 52500; Rs. 47500
B.s. 34375; Rs. 20625
C.s. 72500; Rs. 27500
D.s. 82500; Rs. 17500
Answer: B.s. 34375; Rs. 20625
Explanation: Let the sum invested at 9% be Rs. x and that invested at 11% be Rs. (55000 - x). Then,
(x * 9 * 1)/100 + [(55000 - x) * 11 * 1]/100 = (55000 * 39/4 * 1/100)
(9x + 605000 - 11x)/100 = 39000/4 = 10725/2
x =34375
Sum invested at 9% = Rs. 34375
Sum invested at 11% = Rs. (55000 - 34375) = Rs. 20625
ANSWER:B
Question: The greatest number of four digits which is divisible by 10, 13, 40 and 60 is:
A.9200
B.9300
C.9400
D.7800
Answer: D.7800
Explanation: Greatest number of 4-digits is 9999.
L.C.M. of 10, 13, 40 and 60 is 600.
On dividing 9999 by 7800, the remainder is 2199.
Required number (9999 - 2199) = 7800.
ANSWER :D
Question: If
1 = 3
2 = 6
3 = 9
4 = 12
5 = 15
Then 9 = ?
Hint: Its a logic Riddle not a mathematical riddle
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: C
3
As stated
3=9 => 9=3
Answer is C
Question: Simple interest on a sum at 4% per annum for 2 years is Rs.80.The compound interest on the same sum for the same period is :
A.Rs.81.60
B.Rs.160
C.Rs.1081.60
D.None of these
Answer: A.Rs.81.60
Explanation: Explanation:
Principal = Rs. (100×80/4×2) = Rs.1000
C.I = Rs. [{1000×(1+4/100)2−1000}] = Rs.81.60
Correct Option: A
Question: The charge for a single room at Hotel P is 25 percent less than the charge for a single room at Hotel R and 10 percent less than the charge for a single room at Hotel G. The charge for a single room at Hotel R is what percent greater than the charge for a single room at Hotel G ?
A.15%
B.20%
C.40%
D.50%
Answer: B.20%
Explanation: Let rate in R = 100x
then P = 75x
G = 100y
P = 90y
Thus
75 x=90y
or x = 1.20 y
Ans R = 120y
so increase = 20%
Answer: B.
Question: What is the scope including 1/41+1/42+1/43+......+1/50?
A.1/6~1/5
B.1/5~1/4
C.1/4~1/3
D.1/3~1/2
Answer: B.1/5~1/4
Explanation: For Maximum value : It should be less than 1/41 + 1/41 +1/41... 10 times = 10/41 ~ 1/4
For Minimum Value : It should be greater than 1/50+ 1/50+ 1/50 .. 10 times = 10/50 = 1/5.
Thus, the answer should lie between 1/5 and 1/4. Correct ans : B.
Question: The average age of a husband and a wife is 23 years when they were married five years ago but now the average age of the husband, wife and child is 20 years(the child was born during the interval). What is the present age of the child?
A.2 years
B.3 years
C.5 years
D.4 years
Answer: D.4 years
Explanation: Answer: Option D
28 * 2 = 56
20 * 3 = 60
-----------
4 years
Question: If x^2+(1/x^2)=5, x^4+(1/x^4)=?
A.23
B.11
C.12
D.14
Answer: A.23
Explanation: -> x^4+(1/x^4)=(x^2)^2+(1/x^2)^2=(x^2+1/x^2)^2-2x^2(1/x^2)=5^2-2=23.
Thus, the answer is A.
Question: In the xy-plane, the line y = k is the perpendicular bisector of the line segment PQ and the line x = d is the perpendicular bisector of the line segment RQ. If the coordinates of the point R are (-d, -k), then what are the coordinates of the point P?
A.(-5d, -5k)
B.(-3d, -3k)
C.(2d, 2k)
D.(3d, 3k)
Answer: D.(3d, 3k)
Explanation: firstly the Question tells us that RQ and PQ are perpendicular at Q..
Now the coordinates of the point R are (-d, -k), so R is at a distance of 2d from line x and at dist of 2k from line Y..
as line X bisect RQ .... length of RQ =4d and coord (3d,-k)..
as line Y bisect PQ .... length of PQ =4k and coord (3d,3k).ans D
Question: Ross has 60 shirts, 3/4 of the shirts are green and 1/10 is without buttons. Therefore Ross has between ___ and ___ shirts with buttons that are not green.
A.9 ; 15.
B.2 ; 15.
C.4 ; 10.
D.5 ; 25.
Answer: A.9 ; 15.
Explanation: Total shirts = 60
Green shirts = 3/4*60 = 45, Non green shirts = 15
Shirts without button = 1/10*60 = 6, shirts with button = 24
Required: Range of shirts with buttons that are not green.
Maximum non green shirts with buttons = number of non green shirts = 15
Minimum non green shirts with buttons (All without button shirts are non green) = Non green shirts - shirts without button = 15 - 6 = 6
Hence the range would be (9, 15)
Correct Option: A
Question: A is a working partner and B is a sleeping partner in the business. A puts in Rs.15000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?
A.1978
B.2707
C.7728
D.4200
Answer: D.4200
Explanation: 15:25 => 3:5
9600*10/100 = 960
9600 - 960 = 8640
8640*3/8 = 3240 + 960
= 4200
Answer: D
Question: What is the sum of the integers 45 through 175 inclusive?
A.12,295
B.13,000
C.14,300
D.14,410
Answer: D.14,410
Explanation: sum of n consecutive positive integers=n(n+1)/2..
in one case n=44 and other 175... subtract the sum to get the answer
sum of first 175 +ive numbers=175*176/2=15400..
sum of first 45 +i've numbers=45*44/2=990..
answer=15400-990=14410
ANSWER:D
Question: which of the following options must be accurate if given the equation below: h=-e^7
I. h is positive.
II. If e is negative then h is negative.
III. e is non-negative.
A.I only
B.II and III only
C.I and III only
D.II only
Answer: D.II only
Explanation: I. h is positive --> not true;
II. If h is negative then e is negative. h is negative means that e is not zero. ;
III. e is non-negative.
Answer: D (I only).
Question: 2 students appeared at an examination. 1 of them secured 9 marks more than the other one and hismarks was 56% of the sum of their marks. Find the marks obtained by them are?
A.39 and 31
B.40 and 33
C.42 and 33
D.37 and 31
Answer: C.42 and 33
Explanation: Let their marks be (x+9) and x.
Then, x+9 = 56/100(x + 9 +x)
=> 25(x+9)
=> 14 (2x + 9)
=> 3x = 99
=> x = 33.
So, their marks are 42 and 33
C
Question: a^2*b^2+a^2+b^2=259
b^2*c^2+b^2+c^2=1299
c^2*a^2+c^2+a^2=499
then find b=?
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: adding 1 to all equqtions.,we get them modified to the following form
(a^2+1)(b^2+1)=260
(b^2+1)(c^2+1)=1300
(c^2+1)(a^2+1)=500
by corresponding mul and div we get a=3,b=5,c=7
ANSWER:D
Question: John and Jane went out for a dinner and they ordered the same dish. Both used a 10% discount coupon. John paid a 15% tip over the original price of the dish, while Jane paid the tip over the discounted price for the coupon. If John paid $0.36 more than Jane, what was the original price of the dish?
A. 24
B. 34.8
C. 37.8
D. 42
Answer: A. 24
Explanation: The difference between the amounts John paid and Jane paid is the deference between 15% of p and 15% of 0.9p:
0.15p - 0.15*0.9p = 0.36 --> 15p - 13.5p = 36 --> p = 24.
Answer: A.
Question: If a population of women in a town is 50% of men . What is the population of men as a percentage of population of women ?
A.100%
B.120%
C.200%
D.150%
Answer: C.200%
Explanation: We're told that the number of Women in a town is equal to 50% of the number of Men in that town.
Men = 10
Women = 5
We're asked for the number of Men, as a percentage of the number of Women.
M/W %= 10/5 = 200%
Answer is C
Question: A sum of money is divided among A, B, C & D in the ratio 3:5:8:9 respectively. If the share of D Rs.1872 more than the share of A, then what is the total amount of money of B & C together?
A.Rs. 4000
B.Rs. 4056
C.Rs. 4060
D.Rs. 4100
Answer: B.Rs. 4056
Explanation: Sol. Share of B + C = -3 x (5 + 8) = Rs. 4056
B
Question: Train X and train Y pass one another traveling in opposite directions. Twenty minutes later they are 100 miles apart. If train X’s constant speed is 30 miles per hour greater than train Y’s, how far does train X travel during that time?
A.28
B.40
C.55
D.72
Answer: C.55
Explanation: Let the rate of the Train Y be R
Then the rate of the Train X will be R+30 (given)
As per relative rate concept, the rate at which they are increasing the distance between them is R+(R+30) [add the rates] i.e. 2R+30
d=100 and t = 20 min i.e 20/60 hr
using RTD table, (2R+30) * 20/60 = 100 ==> R= 135 miles/hr
So the rate of train X is 165 miles/hr (since R+30)
The distance traveled by Train X in 20 min is R*T = 165 * 20/60 = 55 miles (C)
Question: The speed of a boat in still water in 42 km/hr and the rate of current is 7 km/hr. The distance travelled downstream in 44 minutes is:
A.86.6 km
B.46.6 km
C.35.9 km
D.35.6 km
Answer: C.35.9 km
Explanation: Speed downstream = (42 + 7) = 49 kmph
Time = 44 minutes =44/60 hour = 11/15 hour
Distance travelled = Time × speed =11/15×49 = 35.9 km
ANSWER:C
Question: A man buys 60 pens at marked price of 46 pens from a whole seller. If he sells these pens giving a discount of 1% , what is the profit percent?
A.7.6 %
B.7.7 %
C.29.13 %
D.33.6 %
Answer: C.29.13 %
Explanation: Explanation:
Let Marked price be Re. 1 each
C.P. of 60 pens = Rs. 46
S.P. of 60 pens = 99% of Rs. 60 = Rs. 59.4
Profit % = (Profit /C.P.) x 100
Profit% = (13.4/46) x 100 = 29.13%
ANSWER: C
Question: What will be the difference between simple and compound interest at 10% per annum on a sum of Rs. 1000 after 4 years?
A.64.98
B.64.29
C.53.98
D.64.1
Answer: D.64.1
Explanation: n:
S.I. = (1000 * 10 * 4)/100 = Rs. 400
C.I. = [1000 * (1 + 10/100)4 - 1000]
= Rs. 464.10 Difference
= (464.10 - 400)
= Rs. 64.10
Answer:D
Question: Two faces of a fair die are Yellow, two faces red and one blue.The die is tossed three
times. The probability that the colours, yellow, red and blue appear in the first, second and
third tosses respectively is
A.1/36
B.1/18
C.1/32
D.1/54
Answer: D.1/54
Explanation: Probability of getting yellow color = P(Y) = 2/6 = 1/3
Probability of getting red color = P(R) = 2/6 = 1/3
Probability of getting blue color = P(B) = 1/6
So, the probability that the colors yellow, red and blue appear in first, second and third toss respectively= P(Y ∩ R ∩ B) = P(Y) x P(R) x P(B) = 1/3 x 1/3 x 1/6 = 1/54
ANSWER:D
Question: Find the middle one when The sum of three consecutive even numbers is 36?
A.10
B.12
C.13
D.15
Answer: B.12
Explanation: 3 consecutive numbers can be a - 1, a, a + 1
So sum of numbers = 3a = 36.
Hence a = 12.
B
Question: 10 men can complete a work in 7 days. But 10 women need 14 days to complete the same work. How many days will 5 men and 10 women need to complete the work?
A.5
B.6
C.7
D.8
Answer: C.7
Explanation: Work done by 10 men in 1 day = 1/7
Work done by 1 man in 1 day = (1/7)/10 = 1/70
Work done by 10 women in 1 day = 1/14
Work done by 1 woman in 1 day = 1/140
Work done by 5 men and 10 women in 1 day = 5 × (1/70) + 10 × (1/140)
= 5/70 + 10/140 = 1/7
= 5 men and 10 women can complete the work in 7 days Answer : Option C
Question: A couple decides to have 3 children. If they succeed in having 3 children and each child is equally likely to be a boy or a girl, What is the probability that they will have exactly 1 girl and 2 boys?
A.3/4
B.1/2
C.5/8
D.1
Answer: C.5/8
Explanation: Sample space = 2^3 = 8
Favourable events = {bgg}, {bgb}, {bbb}, {ggg}, {gbg},
Probability = 5/8 = 5/8.
Ans (C).
Question: The average of first five multiples of 3 is
A.3
B.6
C.9
D.12
Answer: C.9
Explanation: Solution
Average	= 3(1+2+3+4+5) / 5
= 45 / 5.
= 9.
Answer C
Question: In how many years, Rs. 200 will produce the same interest @ 5 % as Rs. 900 produce in 2 years @ 3 ½ %?
A.6.3 years
B.8.2 years
C.9 years
D.12 years
Answer: A.6.3 years
Explanation: Explanation:
P = Rs 900, R = 3 ½ % = 7/2 %, T = 2 years.
Therefore,
S.I. = PRT/100
S.I. = Rs. (900 x 7/2 x 2/100) = Rs. 63
Now, P = Rs. 200, S.I. = Rs. 63, R = 5 %
Time = ((100 x 63) / (200 x 5) ) years = 6.3 years
ANSWER A
Question: In the new budget the price of Petrol rose by 20%. By how much percent must a person reduce his consumption so that his expenditure on it does not increase?
A.16.67%
B.25%
C.20.45%
D.31.56%
Answer: A.16.67%
Explanation: Reduce in consumption = R/(100+R) *100% = 20/120 *100 = 16.67%
Answer is A
Question: If 3^e- 3^(e-1) = 162 then e(e-1) =
A.12
B.16
C.20
D.30
Answer: C.20
Explanation: It seems like you were really close but you solved for e - 1 instead. I am curious - how did you reason through the question? Perhaps you figured the answer has to be in the form of e(e -1), e.g. (3)(4) = 12. Even then, had you figured e has to be a little bigger (plugging in 4 for e gives you 81 which is too low), So when you reasoned the answer to be 4 you may have plugged the 4 in the (e - 1) exponent place.
Again, a quick plugging in should get you (C) 20 as the only other answer with consecutive integers as factors is far too big.