RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In how many ways can you sit 6 people on a bench if 3 of them must sit together?
A.144
B.160
C.400
D.320
Answer: A.144
Explanation: In such questions, always tie the person that have to sit together. So we have effectively 3+1= 4 persons to arrange.
They can be arranged in 4! ways.
Now the 3 persons can themselves be arranged in 3! ways.
Total ways: 4!*3! = 144.
A is the answer.
Question: A train 300 m long can cross an electric pole in 20 sec and then find the speed of the train?
A.72
B.67
C.54
D.26
Answer: C.54
Explanation: Length = Speed * time
Speed = L/T
S = 300/20
S = 15 M/Sec
Speed= 15*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 54 Kmph
Answer:C
Question: By selling an article at Rs.600, a profit of 25% is made. Find its cost price?
A.228
B.267
C.287
D.480
Answer: D.480
Explanation: SP = 600
CP = (SP)*[100/(100+P)]
= 600 * [100/(100+25)]
= 600 * [100/125] = Rs.480
Answer: D
Question: A 100-litre mixture of milk and water contains 36 litres of milk. 'x' litres of this mixture is removed and replaced with an equal quantum of water. If the process is repeated once, then the concentration of the milk stands reduced at 25%. What is the value of x?
A.17.5 litres
B.16.67 litres
C.17.67 litres
D.16.5 litres
Answer: B.16.67 litres
Explanation: In 100L mixture we have 36 L milk and 64 L water.
Hence M and W are in the ratio of 9:16.
x L of solution has been removed.
Hence we have 36-9/25x of milk and 64- 16/25x of water.
FOR CALCULATION SIMPLICITY multiply and divide 9/25x by 4 WE GET 36/100x
Since this procedure is repeated 2 times.
This was my equation
25=36*(36-36/100x)^2)/(36)^2
By solving it.
We get x=100/6 OR 50/3 OR 16.67
ANSWER:B
Question: he difference between the compound and simple interest on a certain sum for 2 years at the rate of 8% per annum is Rs.80,What is the sum?
A.23798
B.27789
C.27889
D.12,500
Answer: D.12,500
Explanation: ifference in simple and compound interest at the end of 2 years occurs because there is interest on first year interest. So Difference = P×(R100)2P×(R100)2
⇒ 80 = P×(8100)2P×(8100)2
⇒ P=80×(1008)2P=80×(1008)2 = 12,500
Answer:D
Question: If three numbers are added in pairs, the sums equal 10,19 and 21. Find the numbers?
A.5, 10, 15
B.6, 4, 15
C.2, 4, 8
D.15, 20, 25
Answer: B.6, 4, 15
Explanation: Sol.
Let the numbers be x, y and z.
Then, x + y = 10 ............(i) and
y + z = 19 ....................(II) and
x + z =21 ...............(III)
Adding (i),(ii) and (iii), we get : 2(x+y+z) = 50 or (x+y+z) = 25.
Thus, x = (25 - 19) = 6;
y = (25 - 21) = 4;
z = (25 - 10) = 15.
Hence, the required numbers are 6, 4 and 15.
Answer B
Question: Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and they are sold fetching the profit 10% and 20% respectively. If the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4/3 and 5/3 times respectively, then the mixture will fetch the profit of
A.18%
B.20%
C.21%
D.23%
Answer: B.20%
Explanation: Mixture 1 and 2 having individual profit % of 10 and 20 respectively.
individual profits of vodka A for mixture 1 = 1/3 * 10 = 3.33
individual profits of vodka B for mixture 1 = 2/3 * 10 = 6.77
Individual profits for A and B are increased 4/3 and 5/3 times.
Means profits of mixtures 1 and 2 will increase too.
Increased profits of Vodka A for mixture 1 = 4/3 * 3.33 = 4.44
Increased profits of Vodka B for mixture 2 = 5/3 * 6.77 = 10.55
total increased profits for mixture 1 = 14.99
Similarly
total increased profits for mixture 2 = 24.42
using allegation formula
Va: Vb = 1:1 = [24.42 - (profit of mixture)] / [(profit of mixture)- 14.99]
hence profit of mixture = 19.705 approx = 20%
ANSWER:B
Question: A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?
A.1/20
B.1/6
C.1/5
D.4/21
Answer: B.1/6
Explanation: Series : a1, a2....a20,n
sum of a1+a2+...+a20 = 20*x (x = average)
so, n = 4*x
Hence, a1+a2+..+a20+n = 24x
So, the fraction asked = 4x/24x = 1/6;
Answer: B.
Question: Calculate the time it will take for a train that is 220 meter long to pass a bridge of 120 meter length, if the speed of the train is Ckm/hour ?
A.16.32 seconds
B.12.32 seconds
C.13.32 seconds
D.15.32 seconds
Answer: A.16.32 seconds
Explanation: Speed = 65 Km/hr = 75*(5/18) m/sec = 20.8333 m/sec
Total distance = 220+120 = 340 meter
Time = Distance/speed
= 340 * (1/20.8333) =16.32 seconds
Answer: A
Question: A team of eight entered for a shooting competition. The best marks man scored 82 points. If he had scored 92 points, the average scores for. The team would have been 83. How many points altogether did the team score?
A.662
B.672
C.654
D.642
Answer: C.654
Explanation: 8 * 83 = 664 – 10 = 654
ANSWER:C
Question: An aeroplane covers a certain distance of 530 Kmph in 5 hours. to cover the same distance in 3 2/3 hours, it Must travel at a speed of
A.440
B.540
C.640
D.722
Answer: D.722
Explanation: Speed of aeroplane = 530 Kmph
Distance travelled in 5 hours
= 530 * 5 = 2650 Km
Speed of aeroplane to acver 2650 Km in 11/3
= 2650*3/11 = 722 Km
Answer D
Question: 10 play kabadi, 15 play kho kho only, 5 play both gmaes. Then how many in total?
A.25
B.35
C.38
D.40
Answer: A.25
Explanation: 10 play kabadi =>n(A)=10,
5 play both gmaes.=> n(AnB)=5
15 play kho kho only,=>n(B)=n(B only)+n(AnB)=15+5=20
Total => n(AUB)= n(A)+n(B)-n(AnB)
= 10+20-5
= 25
ANSWER:A
Question: A train 100 meters long completely crosses a 300 meters long bridge in 24 seconds. What is the speed of the train is?
A.60 kmph
B.76 kmph
C.34 kmph
D.43 kmph
Answer: A.60 kmph
Explanation: S = (100 + 300)/24
= 400/24 * 18/5
= 60
Answer:A
Question: Tom and Jerry are running on the same road towards each other. If Tom is running at a speed of 2.5 meters per second and Jerry is running 36% slower, how much time R will it take them to meet if the initial distance between the two is 50 meters and Tom started running 20 seconds before Jerry did?
A.2 minute and 12 seconds.
B.two minutes.
C.44 seconds.
D.20 seconds.
Answer: D.20 seconds.
Explanation: Tom is running alone for 20 seconds.
So he will cover a distance of 20*2.5 = 50 m in 20 seconds=R
Basically, Jerry has not started yet , and Tom has covered the distance alone and met Jerry on the other side
D is the answer
Question: In a bag, there are four 6-sided dice (numbered 1 to 6), three 12-sided dice (numbered 1 to 12), and two 20-sided dice (numbered 1 to 20). If four of these dice are selected at random from the bag, and then the four are rolled and we find the sum of numbers showing on the four dice, how many different possible totals are there for this sum?
A.60
B.61
C.424
D.840
Answer: B.61
Explanation: As 'complex-looking' as this question might appear, it's actually rather simple. Pay careful attention to what the specific questions asks for - the number of DIFFERENT possible SUMS from 4 dice. Since we're dealing with some 'special' dice (some 12-sided and 20-sided dice), we have to adjust out math accordingly, but the possibilities are rather limited:
1) The minimum number on any given die is 1
2) The maximum possible sum would only occur if we took the 4 biggest possible dice and rolled the highest possible number on each.
With 4 dice, we could end up with any SUM between:
4 (if we rolled 1s on all 4 dice)
to
64 (if we rolled two 20s on the 20-sided dice and two 12s on the 12-sided dice).
Thus, there are only 61 possible sums.
B
Question: If a motorist had driven 1 hour longer on a certain day and at an average rate of 5 miles per hour faster, he would have covered 70 more miles than he actually did. How many more miles would he have covered than he actually did if he had driven 1 hours longer and at an average rate of 10 miles per hour faster on that day?
A. 100
B. 120
C. 130
D. 150
Answer: C. 130
Explanation: Case 1:
let rate = R, Time = T, and Distance =D
so D=RT
Case 2:
(D+70)=(R+5)(T+1)
Case 3:
(D+X)=(R+10)(T+1)
X=130
Ans C
Question: The average marks of a class of 20 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students?
A.44.28
B.54.28
C.34.28
D.64.28
Answer: B.54.28
Explanation: Sum of the marks for the class of 20 students = 20 * 40 = 800
Sum of the marks for the class of 50 students = 50 * 60 = 3000
Sum of the marks for the class of 70 students =
800 + 3000 = 3800
Average marks of all the students = 3800/70 = 54.28
ANSWER:B
Question: The value of x + x(xx) when x = 2 is
A.6
B.2
C.8
D.10
Answer: D.10
Explanation: x + x(xx)
Put the value of x = 2 in the above expression we get,
2 + 2(22)
= 2 + 2(2 × 2)
= 2 + 2(4)
= 2 + 8
= 10.
Answer is D.
Question: 897.7 – 573.07 – 95.007 = ?
A.229.623
B.224.777
C.233.523
D.414.637
Answer: A.229.623
Explanation: Solution
Given expression = 897.7 - (573.07 + 95.007) = 897.7 - 668.077 = 229.623. Answer A
Question: A man can swim in still water at 6 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
A.2
B.1.4
C.1.2
D.1.5
Answer: A.2
Explanation: M = 6
S = x
DS = 6 + x
US = 6 + x
6 + x = (6 - x)2
6 + x = 12 -2x
3x = 6
x = 2
Answer: A
Question: The average of 9 results is 50. The average of first four results is 52 and average of last four results is 49 . what is the fifth result?
A.46
B.82
C.26
D.11
Answer: A.46
Explanation: Total of results = 50 x 9 = 450
Total of first four results = 52 x 4 = 208
Total of Last four results = 49 x 4 = 196
Hence the fifth result = 450 - (208 + 196) = 46
ANSWER=A
Question: .3+33+333+3.33=?
A.369.63
B.372.33
C.702.33
D.702
Answer: A.369.63
Explanation: .3
33
333
3.33
----------
369.63
----------
Answer is A
Question: An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metres of cloth?
A.488
B.204
C.195
D.178
Answer: C.195
Explanation: Let the required time be x seconds.
More metres, More time (Direct Proportion)
0.128 : 25 :: 1 : x 0.128x = 25 x 1
x =25/0.128 =	(25 x 1000)/128
x = 195.31.
Required time = 195 sec (approximately).
Answer is C.
Question: Find the odd man out. 1050, 510, 242, 106, 46, 16, 3
A.46
B.106
C.510
D.1050
Answer: B.106
Explanation: Explanation :
1050
(1050 - 30)/2 = 510
(510 - 26)/2 = 242
(242 - 22)/2 = 110
(110 - 18)/2 = 46
(46- 14)/2 = 16
(16- 10)/2 = 3
Hence, 110 should have come in place of 106. Answer : Option B
Question: If (200)(900) = (180)(10^x), what is the value of x?
A.5
B.4
C.3
D.2
Answer: C.3
Explanation: (200)(900) = (180)(10^x)
=> (200)(900)/180 = 10^x
=> 1,000 = 10^x
=> 10^3 = 10^x
Since, base is same so powers will be same too.
So, x=3
Answer will be C
Question: What is the sum of all the multiples of 10 between 0 and 99?
A.500
B.620
C.450
D.340
Answer: C.450
Explanation: The multiples of 10 between 0 and 99 are 10, 20, 30, 40, 50, 60, 70, 80, and 90. If these are all added together, the result is 450.
Final Answer:
C
Question: Mohan purchased 15 kgs of rice at the rate of Rs.26 per kg and 15 kgs of pulses at the rate of Rs.26 per kg. Whaat is the total amount that he paid to the shopkeeper?
A.A)Rs.780
B.B)Rs.760
C.C)Rs.700
D.D)Rs.595
Answer: A.A)Rs.780
Explanation: Explanation:
Price of 15 kgs of rice at Rs.26/kg = 15x26 = Rs.390
Price of 15 kgs of pulses at Rs.26/kg = 15x26 = Rs.390
Therefore, Total amount = Rs.390+Rs.390 = Rs.780
Answer: Option A
Question: If 5^21 x 8^7 = 10^n what is the value of n?
A.26
B.24
C.21
D.28
Answer: C.21
Explanation: 5^21* (2^3)^7 = 10^n
or 5^21* 2^21 = 10^n
or 10^21 =10^n
n=21
C
Question: The difference between two integers is 5. Their product is 500. Find the numbers.
A.15, 20
B.20, 25
C.30, 25
D.21, 26
Answer: B.20, 25
Explanation: Let the integers be x and (x + 5). Then,
x(x + 5) = 500
x2 + 5x - 500 = 0
(x + 25)(x - 20) = 0
x = 20
So, the numbers are 20 and 25.
ANSWER:B
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 10 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
A.s.9060
B.s.4520
C.s.4527
D.s.4530
Answer: A.s.9060
Explanation: Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls
= 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3)
= 906 sq.ft.
Total cost = 906 * 10
= Rs.9060
Answer:A
Question: A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
A.65 sec
B.16 sec
C.87 sec
D.99 sec
Answer: B.16 sec
Explanation: Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 280 * 2/35 = 16 sec
Answer: B
Question: What is the difference between the place value of 2 in the numeral 7229?
A.150
B.160
C.180
D.190
Answer: C.180
Explanation: 200 - 20 = 180
C
Question: The total of 324 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is :
A.50
B.100
C.150
D.200
Answer: D.200
Explanation: Explanation:
Let the number of 20 paise coins be x. Then the no of 25 paise coins = (324 - x).
0.20 × (x) + 0.25 (324 - x) = 71 => x = 200.
Answer: D
Question: A sum of money becomes 7/6 of itself in 4 years at a certain rate of simple interest. The rate per annum is?
A.25/6
B.5 5/7
C.5 5/2
D.5 5/8
Answer: A.25/6
Explanation: Let sum = x. Then, amount = 7x/6
S.I. = 7x/6 - x = x/6; Time = 4 years.
Rate = (100 * x) / (x * 6 * 4) = 25/6 %.
Answer:A
Question: A technology company made a $5 million profit on its first $15 million in sales and a $12 million profit on its next $30 million in sales. By what percent did the ratio of profit to sales increase from the first $15 million in sales to the next $30 million in sales?
A.10%
B.20%
C.30%
D.40%
Answer: B.20%
Explanation: Solution:
This is a percent increase problem. We will use the formula: percent change = (new – old)/old x 100 to calculate the final answer.
We first set up the ratios of profits to sales. The first ratio will be for the first 15 million in sales, and the second ratio will be for the next 30 million in sales. Because all of the sales are in millions, we do not have to express all the trailing zeros in our ratios.
First 15 Million
profit/sales = 5/15 =1/3
Next 30 Million
profit/sales = 12/30 = 2/5
We can simplify each ratio by multiplying each by the LCM of the two denominators, which is 15. Keep in mind that we are able to do this only because our answer choices are expressed in percents.
First 15 Million
royalties/sales = (1/3) x 15 = 5
Next 30 Million
royalties/sales = (2/5) x 15 = 6
We can plug 5 and 6 into our percent change formula:
(new – old)/old x 100
[(6 – 5)/5] x 100
1/5 x 100, so a 20% increase.
Answer B.
Question: J is 25% less than P and 20% less than T. T is e% less than P. What is the value of e?
A.93.5
B.90
C.6.75
D.6.25
Answer: D.6.25
Explanation: Usually We can solve every question of this type by choosing appropriate value of the Variable and deriving the value of other related variables.
Let, P = 400
then J = (75/100)*400 = 300
also J = (80/100)*T
i.e. T = 300*100/80 = 375
and T = [1-(e/100)]*P
i.e. 100-e = 100*T/P = 100*375/400 = 93.75
i.e. e = 6.25
Answer: Option D
Question: A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
A.21
B.12
C.9
D.108
Answer: D.108
Explanation: Explanation:
The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12 = 108 ways.
Answer is D
Question: The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is:
A.1439
B.1500
C.1440
D.1450
Answer: A.1439
Explanation: LCM = 1440
1440 - 1 = 1439
ANSWER A
Question: A clock is started at noon. By 10 minutes past 3, the hour hand has turned through how many degrees?
A.95Â°
B.100Â°
C.105Â°
D.110Â°
Answer: A.95Â°
Explanation: The angle traced by the hour hand in 12 hrs is 360Â°
The angle traced by the hour hand in 1 hour is 30Â°
The angle traced by the hour hand in 10 minutes is 5Â°
The angle traced by the hour hand in 3 hours and 10 minutes is 3*30Â° + 5Â° = 95Â°
The answer is A.
Question: A started a business with an investment of Rs. 70000 and after 6 months B joined him investing Rs. 120000. If the profit at the end of a year is Rs. 52000, then the share of B is?
A.22772
B.24000
C.23877
D.23789
Answer: B.24000
Explanation: Explanation:
Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6
Total profit = Rs. 52000
Share of B = 6/13 (52000) = Rs. 24000
Answer: B
Question: The average Weight of 15 students in a class is increased by 3 Kg. when a student who weights 48 Kg. is replaced by a new student. Find the weight of new student?
A.39
B.83
C.88
D.93
Answer: D.93
Explanation: Explanation:
New weight = Old weight +- no . of item * decrease (or) increase in average
= 48 + 15 *3= 93
Answer: Option D
Question: A dog takes 5 leaps for every 7 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is :
A.16 : 7
B.15 : 7
C.20 : 7
D.7 :15
Answer: B.15 : 7
Explanation: Explanation:
Dog : Hare = (5*3) leaps of hare : 7 leaps of hare = 15 : 7
Answer: B
Question: How many cubes of 10 cm edge can be put in a cubical box of 1 m edge.
A.10000 cubes
B.1000 cubes
C.100 cubes
D.50 cubes
Answer: B.1000 cubes
Explanation: Explanation:
Number of cubes =(100∗100∗100)/(10∗10∗10)=1000
Note: 1 m = 100 cm
ANSWER IS B
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?
A.2.85
B.2.88
C.2.89
D.2.83
Answer: B.2.88
Explanation: M = 6
S = 1.2
DS = 6 + 1.2 = 7.2
US = 6 - 1.2 = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
Answer: B
Question: workers in a notebook factory stores the notebooks in two different sized boxes. the bigger box contains 18 notebooks while the smaller box contains 10 notebooks. If the workers were to store 89 notebooks in total, what is the least number of notebook that will remain unboxed?
A.10
B.14
C.12
D.17
Answer: D.17
Explanation: Total notebook to be stored 89
The big box can store 18
small box can store 10
storing 18 notebook in big box 84/18 =4 r 12
least number of notebook that will be left unboxed=17
Answer: D
Question: In what time will a train 320 m long cross an electric pole, it its speed be 144 km/hr?
A.2.5 sec
B.8.0 sec
C.3.5 sec
D.2.9 sec
Answer: B.8.0 sec
Explanation: Speed = 144 * 5/18 = 40 m/sec
Time taken = 320/40
= 8.0 sec.
Answer: B
Question: A grandpa called all his grandsons and decided to give them a total of $100 to spend in their vacations. He decided that the elder ones must receive more. So he planned to give a sum to the youngest one and then increase $2 with every elder one.
Can you calculate how much he gave to the youngest one if he gave all and only $100 to them in total?
A.$17
B.$15
C.$21
D.$16
Answer: D.$16
Explanation: D
$16
Question: 7, 10, 8, 11, 9, 12, ?
A.9
B.8
C.11
D.10
Answer: D.10
Explanation: D
10
This is a simple alternating addition and subtraction series. In the first pattern, 3 is added; in the second, 2 is subtracted.
Question: Two cyclists start from the same place to ride in the same direction. A starts at noon at 8 kmph and B at 1.30 pm at 10 kmph. How far will A have ridden before he is over taken by B ?Find also at what times A and B will be 5 km apart.
A.5pm and 10pm
B.6pm and 10pm
C.4pm and 8 pm
D.5pm and 8 pm
Answer: A.5pm and 10pm
Explanation: Sol. If A rides for X hours before he is overtaken, then B rides for(X – 15) hrs.
=> 8X = 10 (X – 1.5) => X = 7.5
=> A will have ridden 8 × 7.5 km ro 60 km.
For the second part, if Y = the required number of hours after noon, then
8X = 10 (X – 1.5) ± 5
=> X = 10 or 5 according as B is ahead or behind A.
=> The required times are 5 p.m. and 10 p.m. Answer A
Question: A train crosses a platform of 120 m in 15 sec, same train crosses another platform of length 180 m in 18 sec. then find the length of the train?
A.277m
B.180m
C.272m
D.278m
Answer: B.180m
Explanation: Length of the train be ‘X’
X + 120/15 = X + 180/18
6X + 720 = 5X + 900
X = 180m
Answer: B
Question: If w/x = 1/6 and w/y = 1/5, then (x + y)/y =
A.4/5
B.6/5
C.7/5
D.11/5
Answer: D.11/5
Explanation: W/X = 1/6=>x=6w and W/Y = 1/5=>y=5w
(X+Y)/Y = (6w+5w)/5w = 11w/5w = 11/5
Correct Option: D
Question: If the number 517*324 is completely divisible by 5, then the smallest whole number in the place of * will be:
A.3
B.1
C.2
D.4
Answer: A.3
Explanation: Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = (22 + x), which must be divisible by 5.
x = 3.
A
Question: A boat having a length 4 m and breadth 2 m is floating on a lake. The boat sinks by 1cm when a man gets on it. The mass of the man is:
A.12 kg
B.60 kg
C.72 kg
D.80 kg
Answer: D.80 kg
Explanation: Explanation:
Volume of water displaced = (4 x 2 x 0.01) m3
= 0.08 m3.
∴ Mass of man = Volume of Water displaced x Density of water
= (0.08 x 1000)kg
= 80 kg.
Answer: D
Question: If 5* nP3 = 4* (n+1)P3, find n?
A.10
B.11
C.12
D.14
Answer: D.14
Explanation: Solution:
nP3 = n*(n–1)*(n–2).
(n+1)P3 =(n+1)*n*(n–1).
Now,
5*n*(n–1)*(n–2) = 4* (n+1)*n*(n–1).
Or, 5(n−2) = 4(n+1).
Or, 5n−10 = 4n+4.
Or, 5n−4n = 4+10.
Hence, n = 14.
Note: nPr = [n! /(n -r)!].
Answer: Option D
Question: Each digit in the two-digit number G is halved to form a new two-digit number H. Which of the following numbers could be the sum of G and H?
A.156
B.150
C.137
D.132
Answer: D.132
Explanation: Let x be the original 2-digit number.
If each digit is halved, then the sum of G and H is 3x/2.
Note the sum must be a multiple of 3 and less than 150.
Only 132 satisfies these two conditions.
The answer is D.
Question: The price of a T.V. set worth Rs. 20000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be?
A.29997
B.28088
C.27098
D.19000
Answer: D.19000
Explanation: Money paid in cash = Rs. 1000
Balance payment = (20000 - 1000) = Rs. 19000.Answer:D
Question: A merchant marks his goods up by 50% and then offers a discount of 10% on the marked price. What % profit does the merchant make after the discount?
A.21%
B.25%
C.69%
D.35%
Answer: D.35%
Explanation: Let the price be 100.
The price becomes 150 after a 50% markup.
Now a discount of 10% on 150.
Profit=135-100
35%
answer D
Question: In a certain school, the ratio of boys to girls is 5 to 13. If there are 160 more girls than boys, how many boys are there?
A.100
B.36
C.45
D.72
Answer: A.100
Explanation: The ratio of b to G is 5:13 and the other data point is G are more than boys by 160...
Looking at the ratio we can say that the 8(13-5) extra parts caused this diff of 160. so 1 part corresponds to 160/8=20 and so
5 parts correspond to 5*10 = 100.
A
Question: If p and q are both odd prime numbers andp < q, then how many different positive integer factors does2pqhave?
A. 3
B. 4
C. 6
D. 8
Answer: D. 8
Explanation: p and q are both odd prime numbers- It means either p or q is not 2
and since prime numbers have only two factors - 1 and the number itself
p and q each will have (1+1)= 2 factors
Hence 2pq will have (1+1)(1+1)(1+1)= 8 factors
D is the answer
Question: If a no. when divided by 44, gives 432 as quotient and 0 as remainder. What will be the remainder when dividing thesame no. by 31
A.2
B.3
C.5
D.7
Answer: C.5
Explanation: P ÷ 44 = 432
=> P = 432 * 44 = 19008
P / 31 = 19008 / 31 = 613, remainder = 5
C
Question: If the cost price of 35 chocolates is equal to the selling price of 21 chocolates, the gain percent is :
A.66.55%
B.66.66 %
C.66 %
D.55%
Answer: B.66.66 %
Explanation: Explanation :
Solution: Let C.P. of each chocolate be Re. 1. then, C.P. of 21 chocolates = Rs. 21;
S.P. of 21 chocolates =Rs. 35.
.'. Gain% = 14*100/21 = 66.66%
Answer : B
Question: A coin is tossed 6 times. What is the probability that the number of Heads is equal to the number of Tails?
A.5/16
B.4/13
C.7/16
D.5/12
Answer: A.5/16
Explanation: We have to find the probability that we get 3 heads and 3 tails in 6 tosses of the coin.
Using the binary formula and defining a head as a success,
P(3 heads in 6 tosses) = 6C3* (1/2)^2 * (1/2)^2*(1/2)^2
= 20/64
= 5/16
The answer is A
Question: (1000)7÷(10)19=?
A.10
B.100
C.1000
D.10000
Answer: B.100
Explanation: Explanation:
=(103)7/(10)19
=(10)21/(10)19=10(2)=100
Option B