RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Given that there are 6 basketball players per team, how many ways can you select 3 basketball players from 3 teams if no more than one player can be selected from each team?
A. 15
B. 216
C. 60
D. 75
Answer: B. 216
Explanation: 3 teams can be selected from 3 teams in 3C3 ways = 1 ways
as the condition is that the 2 players should be from different teams
one player can be chosen from 1st team in 6 ways
similarly another player can be chosen from 2nd team in 5 ways
Total number of ways to choose the player = 6 * 6 * 6 = 216 ways
Correct Answer - B
Question: Look at this series: 75000,25000,5000... What number should come next?
A.1000
B.10
C.15
D.18
Answer: A.1000
Explanation: 1000
This is a simple division series. Each number is divided by 5.
ANSWER A
Question: An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq. m ?
A.Rs. 4082.40
B.Rs. 1024.21
C.Rs. 2810.6
D.Rs. 3214
Answer: A.Rs. 4082.40
Explanation: Explanation:
Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 x 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40
Answer IS A
Question: By selling 150 mangoes, a fruit-seller gains the selling price of 10 mangoes. Find the gain percent?
A.7%
B.25%
C.21%
D.85%
Answer: A.7%
Explanation: SP = CP + g
150 SP = 150 CP + 10 SP
140 SP = 150 CP
140 --- 10 CP
100 --- ? => 7%
Answer:A
Question: a man buys postage stamps of denomination of 30ps. and 50 ps. for rs.10.00. he buys 22 stamps in all. find the no of 30ps. stamps bought by him.
A.5
B.6
C.17
D.8
Answer: A.5
Explanation: 50ps stamp = 17 (17*.50 = 8.50rs)
30ps stamp = 5 (5*.30 = 1.50rs)
ANSWER:A
Question: If the ratio of a to b is 5 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c?
A.4/15
B.1/3
C.2/5
D.4/5
Answer: B.1/3
Explanation: a:b = 5:3 -- 1
b:c = 1:5
=>b:c = 3 :15 --2
From 1 and 2 , we get
a:c = 4:15
Answer B
Question: A, B AND C ARE EMPLOYED TO DO A PIECE OF WORK FOR RS. 529. A AND B TOGETHER ARE SUPPOSED TO DO 19/23 OF THE WORK AND B AND C TOGETHER 8/23 OF THE WORK. WHAT AMOUNT SHOULD A BE PAID?
A.RS. 315
B.RS. 345
C.RS. 355
D.RS. 375
Answer: B.RS. 345
Explanation: WORK DONE BY A=(1-8/23)=15/23.
A:(B+C)=15/23:8/23=15:8
SO, A'S SHARE=RS. (15/23*529)=RS. 345.
CORRECT OPTION: B
Question: The sum of all the digits of the integers from 18 to 21 inclusive is 24 (1 + 8 + 1 + 9 + 2 + 0 + 2 + 1 = 24). What is the sum W of all the digits of the integers from 0 to 99 inclusive?
A.450
B.810
C.900
D.1000
Answer: C.900
Explanation: We want the sum of the digits from 0 to 99, so I approximated:
0-9 ->45-> (9+0)*10/2
40-49 ->85(13+4)*10/2
90-99 ->135(18+9)*10/2
We can see at a glance that theweightgoes up as the numbers go up (meaning the difference between 85 and 45 is 40, while 135-85 is 50, this means that the second part of this sequence carries more weight for our result), so we know that the final answer has to be more than 850 (85*10) but close to it, and that's just W= 900:the answer is C.
Question: A certain Sky Blue paint contains 10 percent blue pigment and 90 percent red pigment by weight. A certain green paint contains 70 percent blue pigment and 30 percent yellow pigment. When these paints are mixed to produce a brown paint, the brown paint contains 40 percent blue pigment. If the brown paint weighs 10 grams, then the red pigment contributes how many grams of that weight?
A.1.5
B.2.5
C.3.5
D.4.5
Answer: D.4.5
Explanation: 10 Grams of combined mixture and 40% blue pigment means that the mixtures were mixed 50% each. Thus 5 grams a piece. Out of the 5 grams of the Dark Blue paint, 60% is red. Therefore, 5*.9 =4.5 Grams of red pigment
Question: A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 Â½ hours after the first, and reaches Pune Â½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
A.1:2
B.1:3
C.10:27
D.5:4
Answer: A.1:2
Explanation: Explanation:
T = 192/32 = 6 h
T = 6 - 3 = 3
Time Ratio = 6:3 = 2:1
Speed Ratio = 1:2
ANSWER IS A
Question: Set X consists of 15 integers and has median of 20 and a range of 20. What is the value of the greatest possible integer that can be present in the set?
A.32
B.37
C.C.40
D.60
Answer: D.60
Explanation: Note that both median and range do not restrict too many numbers in the set. Range is only concerned with the smallest and greatest. Median only cares about the middle.
Quick check of each option starting from the largest:
(E) 50
Range of 20 means the smallest integer will be 30. So 20 cannot lie in between and hence cannot be the median.
(D) 43
Range of 20 means the smallest integer will be 23. So 20 cannot lie in between and hence cannot be the median.
(C) 40
Range of 20 means the smallest integer will be 20. 20 can lie in between such as:
20, 20, 20, 20, 20, 20, 20, 20, 20, 40, 40, 40, 50, 60
This is possible. Hence it is the greatest such number.
Answer (D)
Question: In a T.V. factory, an average of 60 TVs are produced per day for the fist 25 days of the months. A few workers fell ill for the next five days reducing the daily average for the month to 58 sets per day . The average production per day for day last 5 days is ?
A.45
B.48
C.52
D.58
Answer: B.48
Explanation: Production during these 5 days = Total production in a month - production in first 25 days.
= 30 x 58 - 25 x 60
= 240
∴ Average for last 5 days = 240 / 5
= 48
Correct Option: B
Question: The music class consists of 4 girls and 5 boys. How many ways can a group of 3 be formed if it has to include at least one boy?
A.80
B.158
C.161
D.165
Answer: A.80
Explanation: Reverse combinatorics approach is preferred method on this one
Note that at least 1 boy gives clue to using this method
All combinations - four girls = answer
All combinations is 9C3 = 84
All girls 4C3 = 4
So our answer is 84-4 = 80
Hence, answer is (A)
Question: How many digits are in the number 50^8 × 8^3 × 11^3?
A.22
B.20
C.19
D.18
Answer: B.20
Explanation: Whenever you are asked to find the number of digits, try to bring the number in multiples of 10. This way, we can wasily calculate the umber of 0's through the powers of 10
50^8 × 8^3 × 11^3 = (5^2*2)^8*2^9*11^3 = 5^16*2^17*11^3 = 2*11^3*10^16 = 2662*10^16
Hence we would have 16 trailing 0's and the three digits from 2662
Total digits = 4 + 16 = 20
Correct Option: B
Question: There are 10 oranges in a basket. Find the no. of ways in which 3 oranges are chosen from the basket?
A.60
B.90
C.120
D.150
Answer: C.120
Explanation: Required number of ways = 10C3 = 10!/3!7! = 10*9*8/3*2 = 120
Answer is C
Question: The mean of 30 values was 140. It was detected on rechecking that one value 145 was wrongly copied as 135 for the computation of the mean. Find the correct mean.
A.151
B.140.33
C.152
D.148
Answer: B.140.33
Explanation: Corrected mean = 140×30−135+145/30
= 4200−135+145/30
=4210/30=140.33
Answer B
Question: A person took some amount with some interest for 2 years, but increase the interest for 1%, he paid Rs.120/- extra, then how much amount he took?
A.Rs.5500/-
B.Rs.6000/-
C.Rs.4000/-
D.Rs.7000/-
Answer: B.Rs.6000/-
Explanation: Explanation:
2 years = Rs.120/-
year = 120/2
Rate of Interest = 1%
100/1% × 120/2 = Rs.6000/-
P = Rs.6000/-
Answer: Option B
Question: The mantissa of log 3274 is 0.5150. The value of log(0.3274) is
A.1.5150
B.1.5150
C.2.515
D.None of these
Answer: A.1.5150
Explanation: Solution
Since, 0.3274 gives characteristic 1. Therefore value of log (0.3274) = 1.5150. Answer A
Question: A,B, and C are on a trip by a car. A drives during the 1st hour at an average speed of 50km/hr. B drives during the next 2 hours at an average speed of 48km/hr. C drives for the next 3 hours at an average speed of 52km/hr. They reached their destination exactly after 6 hours. Their mean speed is?
A.45.5km/hr
B.50.3km/hr
C.56.9km/hr
D.62.5km/hr
Answer: B.50.3km/hr
Explanation: Total distance traveled = 50*1 + 48*2 + 52*3 = 302km
Total time taken = 6hrs
Mean speed = 302/6 = 50.3km/hr
Answer is B
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
A.140 sq.units
B.170 sq.units
C.190 sq.units
D.940 sq.units
Answer: A.140 sq.units
Explanation: Explanation:
Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10 = 140 sq.units
Answer: Option A
Question: The tax on a commodity is diminished by 20% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it?
A.18%
B.82%
C.72%
D.12%
Answer: D.12%
Explanation: 100 * 100 = 10000
80 * 110 = 8800
10000------- 1200
100 ------- ? = 12%
Answer: D
Question: You roll P (P > 1) number of Q (Q > 1) sided dice at once. What is the probability that at least two of the P dice will land on difference numbers.
A.1 - P/(Q^P)
B.1 - Q/(P^Q)
C.1 - 1/(P^(Q-1))
D.1 - 1/(Q^(P-1))
Answer: D.1 - 1/(Q^(P-1))
Explanation: This can be calculated by first finding the probability of all dice landing on the same number, and taking 1 - it:
The incorrect rolls are any Q-ples: 11...1, 22...2, ..., PP...P. This is makes Q possibilities. The P dice can roll Q*Q*...*Q (Q^P) number of ways. Thus the probability of landing on the same number is Q/(Q^P) = 1/(Q^(P-1)). Therefore, the probability of at least two of the P dice landing on different numbers is:
1 - 1/(Q^(P-1))
Answer: D.
Question: Julie put half of her savings in a savings account that pays an annual simple interest and half in a savings account that pays an annual compound interest. After two years she earned $112 and $120 from the simple interest account and the compound interest account respectively. If the interest rates for both accounts were the same, what was the amount of Julie's initial savings?
A.600
B.784
C.1080
D.1200
Answer: B.784
Explanation: $112 for 2 years = $56 per year.
Extra $8 yearned with the compound interest is the percent yearned on percent. So, $8 is yearned on $56, which means that the interest = 7%.
This on the other hand means that half of the savings = 56*7 = $392. Twice of that = $784.
Answer: B.
Question: Solution Y is 30 percent liquid A and 70 percent water. If 2 kilograms of water evaporate from 8 kilograms of solutions Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new liquid solution is liquid A?
A.30%
B.33 1/3%
C.37 1/2%
D.40%
Answer: C.37 1/2%
Explanation: Answer:C
Took time to solve this one, the statement2 kilograms of solution Y are added to the remaining 6 kilograms of liquidwas confusing to me. After thinking more deeply, it was clear to me that new 2 kg of solution Y will also be 30% liquid A and 70% water, and then I was able to get the answer. That was a bit tricky and nice question.=C
Question: Working together, Wayne and his son can shovel the entire driveway in three hours. If Wayne can shovel six times as fast as his son can, how many hours would it take for his son to shovel the entire driveway on his own?
A.4
B.6
C.8
D.7
Answer: D.7
Explanation: W: the time for Wyane to do the job
S: the time for his son to do the job
We have 1/W + 1/S = 1/6 and W = 6S
Then we have 1/(6*S) + 1/S = 1/6 <=> 7/(6*S) = 1/6 <=> S = 7
ANS: D
Question: Which of the following inequalities is equivalent to –2 < x < 4 ?
A.| x – 2 | < 4
B.| x – 1 | < 3
C.| x + 1 | < 3
D.| x + 2 | < 4
Answer: B.| x – 1 | < 3
Explanation: Soln:-
(A) | x – 2 | < 4 => -2<x<6: out
(B) | x – 1 | < 3 => –2 < x < 4: yeah
(C) | x + 1 | < 3 => -4<x<2: out
(D) | x + 2 | < 4 => -6<x<2: out
(E) None of the above: out
Ans: B
Question: The volumes of two cones are in the ratio 1 : 10 and the radii of the cones are in the ratio of 1 : 2. What is the length of the wire?
A.2 : 5
B.2 : 8
C.2 : 1
D.2 : 0
Answer: A.2 : 5
Explanation: The volume of the cone = (1/3)πr2h
Only radius (r) and height (h) are varying.
Hence, (1/3)π may be ignored.
V1/V2 = r12h1/r22h2 => 1/10 = (1)2h1/(2)2h2
=> h1/h2 = 2/5
i.e. h1 : h2 = 2 : 5
Answer: A
Question: 3,5,11,29,83,245,?
A.731
B.728
C.715
D.705
Answer: A.731
Explanation: We have to find the differences between the given numbers and then by applying
that number with 3 we can get the result
5-3=2
See here the result is 2,then multiply it with 3
11-5=6
29-11=18
83-29=54
245-83=162
731-245=486
ANSWER:A
Question: As part of a game, seven people each must secretly choose an integer between 1 and 7, inclusive. What is the approximate likelihood that all seven people will choose different numbers?
A.1%
B.12%
C.16%
D.20%
Answer: A.1%
Explanation: Ans:a)
1st person has option no's- (1,2,3,4,5,6,7) - there fore probability of getting a no =7c1/7c1 = 1
2nd person has option no's any six ,
he has to choose a no from six no's - there fore probability of getting a no = 6c1/7c1 = 6/7
3rd person has option no's any five,
he has to choose a no from five no's -there fore probability of getting a no = 5c1/7c1 =5/7
4th person has 4 options - there fore probability of getting a no= 4c1/7c1 =4/7
5th person has 3 options - there fore probability of getting a no= 3c1/7c1 = 3/7
6th person has 2 options - there fore probability of getting a no= 2c1/7c1 = 2/7
7th person has only one option - there fore probability of getting a no= 1c1/7c1 = 1/7
=1*6/7*5/7*4/7*3/7*2/7*1/7 = 1%
Question: When positive integer N is divided by positive integer P, the quotient is 20, with a remainder of 7. When N is divided by (P + 2), the quotient is 15 and the remainder is 2. What is the value of N?
A.107
B.331
C.511
D.691
Answer: A.107
Explanation: N/P=10 7/P= 20P+7
N/(P+2)=15 2/(P+2)=15P+30+2
solving these two equations
we get P=5 N= 107 answer is A.
Question: The New York Classical Group is designing the liner notes for an upcoming CD release. There are 10 soloists featured on the album, but the liner notes are only 5 pages long, and therefore only have room for 5 of the soloists. The soloists are fighting over which of them will appear in the liner notes, though not about which page they appear on. How many different combinations T of soloists can appear in the liner notes?
A.5!
B.10!/(5!5!)
C.10!/5!
D.10!
Answer: B.10!/(5!5!)
Explanation: Total Soloists to choose from = 10
Soloist Required = 5
Question : How many different combinations T of soloists can appear in the liner notes?
The language of the question clearly mentions that only the combinations need to be calculated
i.e. Arrangement of the Soloists does NOT matter(Refer theHighlightedpart of the question)
Method-1:
Total Ways to Choose 5 out of 10 soloists = 10C5 = 10! / (5!*5!)
Method-2:
No. of ways to select and arrange 5 soloist on 5 Page = 10*9*8*7*6
Since the arrangement of 5 selected Notes (which can happen in 5! ways) doesn't NOT matter,
Therefore total ways to pick 5 out of 10 soloists = 10*9*8*7*6 / 5! = 10*9*8*7*6 *5! / (5!*5!) = 10! / (5!*5!)
Answer: Option B
Question: The average of first 18 natural numbers is?
A.9.6
B.9.5
C.9.9
D.9.4
Answer: B.9.5
Explanation: Sum of 18 natural no. = 342/2 = 171
Average = 171/18 = 9.5
Answer:B
Question: In an effort to plan out expenses, the Roberts family is representing its annual budget as a circle graph. Each sector of the graph is proportional to the amount of the budget it represents. If “clothes and shoes” takes up 54° of the chart, how much of the Roberts’s $30,000 annual budget is dedicated to clothes and shoes?
A.$1,500
B.$3,000
C.$4,500
D.$5,000
Answer: C.$4,500
Explanation: Given for clothes and shoes” takes up 54° of the circular chart.
Then clothes and shoes = 54/360 * 30000.
=> 4500.
IMO option C is correct answer...
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8215 for a computer table, then what was the cost price of the computer table?
A.7297
B.6625
C.2871
D.6725
Answer: B.6625
Explanation: Explanation:
CP = SP * (100/(100 + profit%))
= 8215(100/124) = Rs. 6625.
Answer: B
Question: A rectangular table seats 2 people on each of two sides, with every person directly facing another person across the table. If four people choose their seats at random, what is probability that any two of them directly face other?
A.1/3
B.1/8
C.1/7
D.15/56
Answer: A.1/3
Explanation: A B
------------
| TABLE |
------------
C D
A to D are 4 people.
Prob to select any 1 person = 1
Prob to select the person opposite to the chosen person = 1/3
For ex. If we select A as the person than prob of choosing C is 1/3.
Hence, answer will be A.
Question: A train A leaves Mysore at 6 a.m. and reaches Bangalore at 10 a.m. Another train leaves B Bangalore at 8 a.m. and reaches Mysore at 11.30 a.m. At what time do the two trains cross each other ?
A.8.30 a.m.
B.8.45 a.m.
C.8.56 a.m.
D.9 a.m.
Answer: C.8.56 a.m.
Explanation: Explanation :
Solution: Let the distance between mysore and bangalore be x km and let the trains meet y hours after 8 a.m.
Clearly, A covers x km in 4 hours and B covers x km in 4.5 hrs = (7/2) hrs
.'. Speed of A = x/4 kmph, speed of B = 2x/7 kmph.
Distance covered by A in (y+2) hrs + distance covered by B in y hrs = x.
.'. x/4(y+2) + 2x/7 * y = x
=> (y+2)/4 + 2y/7 = 1
=> y = 14/15 hrs =14*60/15 = 56 min.
Hence, the trains meet at 8.56 a.m.
Answer : C
Question: The smallest number when increased by "2 " is exactly divisible by 12, 30, 48, 74 and 100 is:
A.14439
B.44398
C.44400
D.44402
Answer: B.44398
Explanation: LCM = 44400
44400 - 2 = 44398
ANSWER:B
Question: Find the greatest number of four digits which is perfectly divisible by 3 and when divided by 5, 7 and 9 leaves a remainder 3 in each case.
A.1128
B.1659
C.2687
D.1667
Answer: B.1659
Explanation: LCM of 3, 5, 7, 9 = 315. Greatest number of four digits which is divisible by 315 is 9765. The required number = 9765 + 3 = 9768. Ask doubt with Question Id: 1658 13) Find greatest number of four digits which when increased by 3568 is exactly divisible by 6, 8, 12, 20. a) 9992 b) 9785 c) 9840 d) None Explanation: Greatest number of 4 digits = 9999. 9999 + 3568 = 13567. LCM of 6, 8, 12 and 20 is 120.
∴ Required number of 4 digits = 9999 – 7 = 9992 i.e. 9992 is the number to which if 3568 is added, then it is exactly divisible by 6, 8, 12, 20. Ask doubt with Question Id: 1659
Answer:B
Question: In the exam the average was found to be p mark. After deducting typographical error the average marks of 85 student reduced from 75 to 50 . Due to this the average came down by 25 marks. What was the number of students who took the exam?
A.100
B.85
C.110
D.130
Answer: B.85
Explanation: Explanation :
Number of student = (75-50) * 85/25 = 85
Answer : B
Question: A coin has two sides. One side has the number 1 on it and the other side has the number 2 on it. If the coin is flipped three times what is the probability that the sum of the numbers on the landing side of the coin will be greater than 3?
A.3/8
B.1/16
C.7/8
D.1/2
Answer: C.7/8
Explanation: One approach to solve the problem is to list the different possibilities for a toss of coin three times. Because there are two outcomes and the coin is tossed three times, the table will have 2*2*2 or 8 rows.
Next add the resulting rows together to find the sum (the fourth column in the table below).
Toss 1 | Toss 2 | Toss 3 | Sum
1 ---------- 1 -------- 1 ------ 3
1 ---------- 1 -------- 2 ------ 4
1 ---------- 2 -------- 1 ------ 4
1 ---------- 2 -------- 2 ------ 5
2 ---------- 1 -------- 1 ------ 4
2 ---------- 1 -------- 2 ------ 5
2 ---------- 2 -------- 1 ------ 5
2 ---------- 2 -------- 2 ------ 6
From the table we see that there are 7 situations where the sum of the tosses will be greater than 3. And there are 8 possible combinations resulting in a probability of
7/8 or a probability of 7/8.
SO the correct answer is C.
Question: Three partners A, B, C in a business invested money such that 4(Aâ€™s capital) = 2(Bâ€™s capital) = 12(Câ€™s capital) then, The ratio of their capitals is
A.63 : 45 : 34
B.63 : 54 : 34
C.36 : 54 : 28
D.3 : 6 : 1
Answer: D.3 : 6 : 1
Explanation: Explanation:
Let 4(Aâ€™s capital) = 2(Bâ€™s capital) = 12(Câ€™s capital) = Rs.x
Then, Aâ€™s capital = Rs x/4, Bâ€™s capital = Rs. x/2 and Câ€™s capital = Rs. x/12
A : B : C = x/4 : x/2 : x/12
3 : 6 : 1
Answer: Option D
Question: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 230 per month. What is his monthly salary?
A.5000
B.5750
C.2878
D.2990
Answer: B.5750
Explanation: Income = Rs. 100
Expenditure = Rs. 80
Savings = Rs. 20
Present Expenditure 80*(20/100) = Rs. 96
Present Savings = 100 â€“ 96 =Rs. 4
100 ------ 4
? --------- 230 => 5750
Answer: B
Question: Find the average of the first 9 natural numbers?
A.8
B.5
C.10
D.11
Answer: B.5
Explanation: Average of the first 'n' natural numbers = (n + 1)/2
We get (9 + 1)/2 = 5
ANSWER:B
Question: If a and b are positive integers, which of the following cannot be an integer?
A.(2b)/(4a+1)
B.(2b)/(3a+1)
C.(2a+1)/(4b)
D.(2a+1)/(4b+1)
Answer: C.(2a+1)/(4b)
Explanation: I'd first look for an option which gives odd/even for any values of a and b, because odd/even is not an integer.
Option C fits: 2a+1/4b=even+odd/even=odd/even≠integer
To discard other A consider a=5 and b=1.
To discard other B consider a=2 and b=1.
To discard other D consider a=2 and b=1.
To discard other E consider a=3 and b=1.
Answer: C.
Question: Matt is touring a nation in which coins are issued in two amounts, 2¢ and 5¢, which are made of iron and copper, respectively. If Matt has ten iron coins and ten copper coins, how many different sums from 1¢ to 70¢ can he make with a combination of his coins?
A.66
B.67
C.68
D.69
Answer: A.66
Explanation: The total sum is 10*2 + 10*5 = 70¢. If you can make each sum from 1 to 70 (1¢, 2¢, 3¢, ..., 70¢), then the answer would be 70 (maximum possible).
Now, with 2¢ and 5¢ we cannot make 1¢ and 3¢. We also cannot make 69¢ and 67¢ (since total sum is 70¢ we cannot remove 1¢ or 3¢ to get 69¢ or 67¢).
So, out of 70 sums 4 are for sure not possible, so the answer must be 70 - 4 = 66 sums or less. Only A fits.
Answer: A.
Question: An empty wooden vessel weighs 12% of its total weight when filled with paint. If the weight of a partially filled vessel is one half that of a completely filled vessel, what fraction of the vessel is filled.
A.3/5
B.5/11
C.1/24
D.4/9
Answer: B.5/11
Explanation: An empty wooden vessel weighs 12% of its total weight when filled with paint:
Vessel = 0.12(Vessel + Paint);
12V = V + P (so the weight of completely filled vessel is 12V)
P = 11V (so the weight of the paint when the vessels is completely filled is 11V).
The weight of a partially filled vessel is one half that of a completely filled vessel:
V + P' = 1/2*12V;
P' = 5V (so the weight of the paint when the vessels is partially filled is 5V).
What fraction of the vessel is filled?
So, we need to find the ratio of the weight of the paint when the vessel iscompletely filledto the weight of the paint when the vessel ispartially filled:
P'/P = 5V/11V = 5/11.
Answer: B.
Question: A sum fetched a total simple interest of Rs. 750 at the rate of 6 p.c.p.a. in 5 years. What is the sum?
A.2600
B.2500
C.2900
D.2800
Answer: B.2500
Explanation: Sol.
Principal = Rs. [100 * 750 / 6 * 5] = Rs. [75000 / 30] = Rs. 2500.
Answer B
Question: A salesman sold twice as much pears in the afternoon than in the morning. If he sold $420 kilograms of pears that day, how many kilograms did he sell in the afternoon?
A.120
B.180
C.240
D.280
Answer: D.280
Explanation: 3x=420
x=140
Therefore, the salesman sold 140kg in the morning and 2⋅140=280 kg in the afternoon. So answer is D.
Question: If x = 5/8 and y = -1/2, what is the value of the expression -2x – y^2?
A.-3/2
B.-1
C.1
D.3/2
Answer: A.-3/2
Explanation: -2X- y^2
-2x5/8 - (1/2)^2
-5/4-1/4
-3/2
A correct