RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Two men started running simultaneously around a circular track of length 19200 m from the same point at speeds of 120 km/hr and 200 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions?
A.214
B.215
C.216
D.217
Answer: C.216
Explanation: Time taken to meet for the first time anywhere on the track
= length of the track / relative speed
= 19200 / (120 + 200)5/18 = 19200* 18 / 320 * 5 = 216 seconds.
Answer:C
Question: There are 35 students in a hostel. If the no. of students increases by 7, the expenses of the mess increase by Rs.42/day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess?
A.Rs. 34
B.Rs. 39
C.Rs. 42
D.Rs. 49
Answer: C.Rs. 42
Explanation: Suppose the average join the mess , total expenditure = 35x + 42
Now, the average expenditure = (35x + 42)/ (35 + 7) = x – 1
or, 35x + 42 = 42x – 42
or, x = 12
Thus the original expenditure of the mess = 35 x 12 = Rs. 42
C
Question: There were two candidates in an election. Winner candidate received 62% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate?
A.228
B.744
C.255
D.199
Answer: B.744
Explanation: W = 62% L = 38%
62% - 38% = 24%
24% -------- 288
62% -------- ? => 744
Answer:B
Question: The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
A.1
B.2
C.8
D.7
Answer: C.8
Explanation: S = 4
M = x
DS = x + 4
US = x - 4
6/(x + 4) + 6/(x - 4) = 2
x = 8
Answer: C
Question: The sum of the digits of a two digit number is 9 less than the number. Which of the following digits is at units place of the number?
A.1
B.2
C.3
D.Data inadequate
Answer: D.Data inadequate
Explanation: Sol.
Let the ten's digit be x and unit's digit be y.
Then, (10x + y) - (x + y) = 9 or x = 1.
From the data, we cannot find y, the units digit.
So, the data is inadequate.
Answer D
Question: Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
Year	Item of Expenditure
Salary	Fuel and Transport	Bonus	Interest on Loans	Taxes
1998	288	98	3.00	23.4	83
1999	342	112	2.52	32.5	108
2000	324	101	3.84	41.6	74
2001	336	133	3.68	36.4	88
2002	420	142	3.96	49.4	98
The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?
A.0.5%
B.1%
C.1.25%
D.3%
Answer: B.1%
Explanation: Required percentage
=	[	(3.00 + 2.52 + 3.84 + 3.68 + 3.96)	x 100	]	%
(288 + 342 + 324 + 336 + 420)
=	[	17	x 100	]	%
1710
~= 1%.
B)
Question: The cost to rent a small bus for a trip is x dollars, which is to be shared equally among the people taking the trip. If 2 people take the trip rather than 8, how many more dollars, in terms of x, will it cost per person?
A. x/6
B. x/16
C. x/40
D. 3x/8
Answer: D. 3x/8
Explanation: Just plugging in values
X= 16
Cost per person if we consider 2 = 8
Cost per person if we consider 8 = 2
Difference between costs is 6 dollars.
Plugging in the value of x into the answer choices, let's see which one yields a result of 6. And that is D.
Question: John & Mary go for an interview for 2 vacancies. The probability for the selection of John is 1/3 & whereas the probability forthe selection of Mary is 1/5. What is the probabilitynone of them are selected?
A.2/11
B.3/14
C.8/15
D.7/13
Answer: C.8/15
Explanation: Let A = the event that John is selected and B = the event that Dani is selected.
Given that P(A) = 1/3 and P(B) = 1/5
We know that A¯ is the event that A does not occur and B¯ is the event that B does not occur
Probability that none of them are selected
=P(A¯∩B¯)(∵ Reference : Algebra of Events)
=P(A¯).P(B¯) (∵ Here A and B are Independent Events and refer theorem on independent events)
=[ 1 - P(A) ][ 1 - P(B)]
=(1−13)(1−15)
=23×45=8/15
C
Question: In a can, there is a mixture of milk and water in the ratio 1 : 5. If it is filled with an additional 2 litres of milk the can would be full and ratio of milk and water would become 3 : 5. Find the capacity of the can?
A.40
B.44
C.48
D.8
Answer: D.8
Explanation: Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 1/6 (T - 2)
After adding milk, quantity of milk in the mixture = 3/8 T.
3T/8 - 2 = 1/6=(T - 2)
10T = 96 - 16 => T = 8
Answer:D
Question: Six family members are seated around their circular dinner table. If only arrangements that are considered distinct are those where family members are seated in different locations relative to each other, and Michael and Bobby insist on sitting next to one another, then how many distinct arrangements around the table are possible?
A.48
B.56
C.64
D.72
Answer: A.48
Explanation: Let's consider Michael and Bobby as one unit.
There are 5! possible arrangements of 5 units.
Around a table, there would be repetitions of each arrangement, so we divide by 5.
Then there are 4! arrangements around a circular table.
For each arrangement, Michael and Bobby can switch places, so we multiply by 2.
The number of arrangements is 4!*2 = 48.
The answer is A.
Question: A reduction of 25% in the price of salt enables a lady to obtain 10kgs more for Rs.800, find the original price per kg?
A.25.67
B.26.67
C.27.2
D.26.98
Answer: B.26.67
Explanation: Answer:	800*(25/100) = 200 --- 10
? --- 1 => Rs.20
800 --- 600
? --- 20 => Rs.26.67.Answer: B
Question: What is the thousandths digit in the decimal equivalent of 64/5000?
A.2
B.1
C.3
D.5
Answer: A.2
Explanation: 64/5000 = 64 /(5*10^3)
= (64/5) *10^-3
=12.8 * 10^-3
=.0128
Thousandths digit = 2
Answer A
Question: On a baseball team, 5 players including Alice want to play 1st base, 2nd base, or 3rd base. Before every game, the coach chooses a name randomly from a bag and this person plays 1st base. Then the coach chooses the next name randomly and this person plays 2nd base. The coach then chooses a third name randomly and this person plays 3rd base. What is the probability that Alice plays 1st, 2nd, or 3rd base?
A.2/5
B.3/5
C.3/10
D.7/10
Answer: B.3/5
Explanation: The total number of ways to choose three players is 5C3=10.
Excluding Alice, the number of ways to choose three players is 4C3=4.
P(Alice is not chosen)=4/10=2/5.
P(Alice is chosen)=1 - 2/5 = 3/5.
The answer is B.
Question: in a house there are two rooms in a cube form with surface area 150 and 96 respectively. then what is the ratio between their volumes?
A.125:64
B.64:125
C.5:4
D.4:5
Answer: A.125:64
Explanation: 6a12:a22=150:96
a12:a22=25:16
a1:a2=5:4
then volume a13:a23=:125:64
the answer is A
Question: If A's height is 40% less than that of B, how much percent B's height is more than that of A?
A.66.66%
B.66.68%
C.66.766%
D.86.66%
Answer: A.66.66%
Explanation: Excess of B's height over A's = [(40/(100 - 40)] x 100%
= 66.66%
Answer: A) 66.66%
Question: A, B and C enter into a partnership. They invest Rs. 40,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. IN what ratio will the profit be shared at the end of 3 years?
A.3:4:4
B.3:4:7
C.3:4:3
D.3:4:9
Answer: B.3:4:7
Explanation: A:B:C = (40000 * 36) : (80000 * 12 + 40000 * 24) : (120000 * 24 + 40000 * 12)
= 144:192:336
= 3:4:7
Answer: B
Question: The product of two successive numbers is 2652. Which is the smaller of the two numbers?
A.51
B.68
C.57
D.55
Answer: A.51
Explanation: A
51
From the given alternatives,
51 × 52 = 2652
∴ Smaller number = 51
Question: An electronics store purchased a CD player at a wholesale price of 60$ and then sold it at a 40 percent discount off the original retail price. If the store made a 25 percent profit on the whole price of the CD player, what was the stores profit as a percent of the original retail price?
A.10%
B.12%
C.15%
D.18%
Answer: B.12%
Explanation: Store makes 25% on WP so Store sold CD for $75 ($60*.25+$60). The question tells us that the store sold the CD 40% off its ORP so 75=.6(ORP)=125. From here we just need to answer the specific question of what percent of the ORP was the stores profit..hence 15=x/100(125)=12%;ANSWER:B
Question: The ratio of a to b to c is 2 to 3 to 4, and a, b, c are positive integers. If the average (arithmetic mean) of the three numbers is 45, what is the value of a?
A.21
B.25
C.28
D.30
Answer: D.30
Explanation: Let a=2k, b=3k, and c=4k.
a+b+c = 2k+3k+4k = 9k
Since the average is 45:
9k/3 = 45
3k = 45
k=15
Then a=30.
The answer is D.
Question: A and B invests Rs.10000 each, A investing for 8 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.25000, find their shares?
A.15005
B.15009
C.15004
D.15000
Answer: D.15000
Explanation: The ratio of their profits A:B = 8:12 = 2:3
Share of A in the total profit = 2/5 * 25000
= Rs.10000 Share of A in the total profit = 3/5 * 25000
= Rs.15000
Answer:D
Question: From the below series find the remainder? 1201 × 1203 ×1205 × 1207 is divided by 6.
A.3
B.5
C.7
D.8
Answer: A.3
Explanation: If you don't know the above rule, this problem is really calculation intensive.
But by applying the above rule, when 1201, 1201, 1203, 1204 divided by 6, leaves remainders 1, 3, 5, 1. The product of these remainders = 15.
When 15 is divided by 6, Remainder is 3
A
Question: The average age of 35 students in a class is 16 years. The average age of 21 students is 14. What is the average age of remaining 19students?
A.14 years
B.17 years
C.19 years
D.21 years
Answer: A.14 years
Explanation: Solution
Sum of the ages of 14 students	= (16 x 35) - (14 x 21)
= 560 - 294.
= 266.
∴ Required average	= 266 / 19
= 14 years.
Answer A
Question: In 15 year’s time the combined age of my four brothers will be 107. What will it be in the six year’s time?
A.61
B.78
C.71
D.68
Answer: C.71
Explanation: C
71
Combined age in 15 years = 107.
4 × 15 = 60,
Therefore combined age now is 107– 60 = 47.
In 6 years time, therefore, combined age will be 47 + 24(4 x 6) = 71.
Question: If x#y is defined to equal x^2/y for all x and y, then (-1#2)#-3 =
A.1/12
B.1/3
C.1/2
D.-1/12
Answer: D.-1/12
Explanation: (-1)^2 / 2 = 1/2
(-1/2)^2 /- 3 =- 1/12
so D is my answer
Question: Worker A takes 8 hours to do a job. Worker B takes 10 hours to do a job. How long should it take both
A and B, working together to do same job
A.49
B.249
C.349
D.449
Answer: D.449
Explanation: Explanation:
In this type of questions, first we need to calculate 1 hours work, then their collective work as
A's 1 hour work is 1/8
B's 1 hour work is 1/10
(A+B)'s 1 hour work = 1/8 + 1/10
= 9/40
So both will finish the work in 40/9 hours
=
449
Answer: D
Question: If A lends Rs.1200 to B at 10% per annum and B lends the same sum to C at 18% per annum then the gain of B in a period of 2 years is?
A.190
B.188
C.192
D.145
Answer: C.192
Explanation: (1200*8*2)/100
=> 192
Answer: C
Question: If Sharon's weekly salary increased by 15 percent, she would earn $575per week. If instead, her weekly salary were to decreased by 12 percent, how much would she earn per week?
A.Rs.540
B.Rs.580
C.Rs.560
D.Rs.620
Answer: C.Rs.560
Explanation: Soln:-
(575/115)112=560
In this case long division does not take much time.
(23/5)=4.6
4.6*112=Rs.560
ANSWER:C
Question: Seed mixture X is 40% ryegrass and 60% bluegrass by weight; seed mixture Y is 25% ryegrass and 75% fescue. If a mixture of X and Y contains 30% ryegrass, what percent of the weight of the mixture is X?
A.10%
B.33.33%
C.40%
D.50%
Answer: B.33.33%
Explanation: x - wt of Mix X added
y - wt of Mix Y added
0.4x + 0.25y = 0.3(x+y)
0.1x = 0.05y
x/y = 5/10 = 1/2
y/x = 2
(y+x)/x = 3
=> x/(y+x) * 100 = 100/3 = 33.33%
ANSWER:B
Question: The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is :
A.22
B.21
C.88
D.37
Answer: B.21
Explanation: Explanation:
Lot the total number of workers be v Then,
8OOOv = (12000 * 7) + 6000 (v - 7) <=> 2000v = 42000 <=> v = 21
Answer: B) 21
Question: In an election between two candidates, 75% of the voters cast thier thier votes, out of which 2% of the votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the total number of votes enrolled in that election.
A.15000
B.17000
C.16800
D.16600
Answer: C.16800
Explanation: Let the number of votes enrolled be x. Then ,
Number of votes cast =75% of x. Valid votes = 98% of (75% of x).
75% of (98% of (75%of x)) =9261.
[(75/100)*(98/100)*(75/100)*x] =9261.
X = [(9261*100*100*100)/(75*98*75)] =16800.
Answer is C.
Question: In a shipment of televisions, 1/50 of the televisions are defective. What is the ratio of defective to nondefective televisions?
A.1/50
B.2/50
C.1/49
D.2/49
Answer: C.1/49
Explanation: If 1/50 then
1 - 1/50 = 49 / 50 are not defective
So if x is the total number of TV sets, then (1/50)x are defective and (49/5)x are not defective. Hence the ratio of defective to non defective is given by
x(1 / 50) / x(49 / 50) = (1/50)(50/49) = 1/49
correct answer C
Question: What percent is 5 gm of 1 kg?
A.0.5 %
B.1%
C.1.5%
D.2%
Answer: A.0.5 %
Explanation: 1 kg = 1000 gm
5/1000 × 100 = 500/1000
=1/2 = 0.5 %
A)
Question: The following operations are defined for real numbers.
a # b = a + b, if a and b both are positive else a # b = 1.
a ∇ b = ( a x b)a+b if a x b is positive else a ∇ b = 1.
(2 # 1 ) / (1 ∇ 2) =
A.1/8
B.1
C.3/8
D.3
Answer: C.3/8
Explanation: Explanation :
Here, a and b both are positive numbers.
Hence, the required value is (2 + 1) / 23 i.e 3 / 8.
Answer : C
Question: From a group of 21 astronauts that includes 12 people with previous experience in space flight, a 3-person crew is to be selected so that exactly 1 person in the crew has previous experience in space flight. How many different crews of this type are possible?
A.432
B.594
C.864
D.1330
Answer: A.432
Explanation: C112∗C29=12∗36=432, where C112 is ways to select 1 astronaut with previous experience out of 12 and C29 is ways to select 2 astronauts without experience out of 9 remaining astronauts (21-12=9).
Answer: A.
Question: If x=3, which of the following is(are) true? I. x^2=2x II x/3 = 1 III |x|=-x
A.I only
B.III only
C.II only
D.I,II only
Answer: C.II only
Explanation: 3/3 =1
Answer : C
Question: If the fifth day of a month is two days earlier than Sunday, What day will it be on the tenth day of the month?
A.Saturday
B.Monday
C.Sunday
D.Wednesday
Answer: D.Wednesday
Explanation: Explanation:
Given that fifth day of a month is two days earlier than Sunday
=> Fifth day is Friday
=> 12th is Friday
=> 10th is Wednesday
Answer: Option D
Question: In a group of cows and chickens, the number of legs was 10 more than twice the number of heads. The number of cows was:
A.5
B.7
C.10
D.12
Answer: A.5
Explanation: Let the number of cows be x and their legs be 4x.
Let the number of chicken be y and their legs be 2x.
Total number of legs = 4x + 2y.
Total number of heads = x + y.
The number of legs was 10 more than twice the number of heads.
Therefore, 2 × (x + y) + 10 = 4x + 2y.
or, 2x + 2y + 10 = 4x + 2y.
or, 2x + 10 = 4x [subtracting 2y from both sides].
or, 10 = 4x – 2x [subtracting 2x from both sides].
or, 10 = 2x.
or, x = 5 [dividing by 2 on both sides].
Therefore, the number of cows = 5.
Correct Answer:A)5
Question: A and B enter into partnership with capitals in the ratio 4 : 3. At the end of 10 months A withdraws,and the profits now are divided in the ratio of 5 : 6. Find how long B remained in the business?
A.9 months
B.8 months
C.16 months
D.7 months
Answer: C.16 months
Explanation: Initially A’s investment = 4x and B’s investment = 3x
Let B remain in the business for ‘n’ months.
⇒ 4x × 10 : 3x × n = 5 : 6
∴ 4x × 10 × 6 = 3x × n × 5
⇒ n = 16
Answer C
Question: What is the diagonal of a square field whose perimeter is 64m?
A.15 m
B.16√2m
C.20 m
D.25 m
Answer: B.16√2m
Explanation: Sol:
Let the side of the square be xm.
Therefore,
4x=64
x=16
Diagonal of the square is= √2*(16)^2=16√2
Answer: B
Question: find value for x from below equation? x + 1 = 5
A.-5
B.-4
C.4
D.3
Answer: C.4
Explanation: 1. Subtract 1 from both sides:
x + 1 - 1 = 5 - 1
2. Simplify both sides:
x = 4
C
Question: A box contains 20 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective is
A.4/19
B.7/19
C.12/19
D.21/95
Answer: B.7/19
Explanation: Solution
P( None is defective)
= 16C2 / 20C2
= (16x15/2x1 ×2x1/20x19)
= 12/19.
P( at least one is defective)
= (1- 12/19)
= 7/19.
Answer B
Question: Find the L.C.M of the fractions 2/7 , 5/14, and 4/21
A.1 1/7
B.3 4/7
C.2 4/7
D.2 6/7
Answer: D.2 6/7
Explanation: Explanation:
L.C.M = L.C.M of numerator/ H.CF of denominator
L.C.M = L.C.M of 2,5,4 / H.C.F of 7, 14, 21,
L.C.M = 20/7,
L.C.M = 2 6/7
Answer: Option D
Question: 10% of the inhabitants of village having died of cholera.,a panic set in , during which 25% of the remaining inhabitants left the village. The population is then reduced to 4050. Find the number of original inhabitants.
A.5000
B.6000
C.56000
D.6500
Answer: B.6000
Explanation: Let the total number of orginal inhabitants be x.
((75/100))*(90/100)*x)=4050  (27/40)*x=4050
x=((4050*40)/27)=6000.
ANSWER B
Question: A candidate appearing for an examination has to secure 55% marks to pass paper I. But he secured only 45 marks and failed by 25 marks. What is the maximum mark for paper I?
A.127
B.120
C.130
D.140
Answer: A.127
Explanation: he secured 45 marks nd fail by 25 marks so
total marks for pass the examinatn=70
let toal marks x
x*55/100=70
x=127
ANSWER:A
Question: A can do a piece of work in 15 days. When he had worked for 2 days B joins him. If the complete work was finished in 8 days. In how many days B alone can finish the work?
A.11 6/7days
B.12 6/7days
C.13 6/7days
D.14 6/7days
Answer: B.12 6/7days
Explanation: 8/15 + 6/x = 1
X = 12 6/7days
ANSWER:B
Question: What is the area of the square with the following coordinates: (x, y), (20, 20), (20, 8), (x, 8)?
A.81
B.144
C.196
D.225
Answer: B.144
Explanation: To find the area of a square, knowing the length of one side is sufficient.
From the coordinates given, we can see that one side equals 12.
The area is 12*12 = 144.
The answer is B.
Question: Rs. 2780 are invested partly in 4% stock at 75 and 5% stock at 80 to have equal amount of incomes. The investment in 5% stock is:
A.1200
B.1500
C.1280
D.1300
Answer: C.1280
Explanation: Investment Rs 2780
stock - 4% 75 5% at 80%
req 5% stock is -- 1280
ANSWER C
Question: If 17,777 – n is divisible by 11, and 0 < n < 11, what is n?
A.1
B.3
C.5
D.7
Answer: A.1
Explanation: 17,777 / 11 = 1616 with a remainder of 1.
We need to subtract the remainder to get a multiple of 11.
The answer is A.
Question: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?
A.9.1
B.9.0
C.9.3
D.9.2
Answer: A.9.1
Explanation: Explanation:
Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 - 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Answer: Option A
Question: Find the greatest number that will divide 48, 210 and 136 leaving 4, 12 and 4 as remainders respectively
A.19
B.17
C.13
D.22
Answer: D.22
Explanation: Explanation:
Answer will be HCF of (48-4, 210-12, 136-4)
HCF of (44, 198, 132) = 22
Option D
Question: Health insurance Plan P requires the insured person to pay $600 but then the insurance pays 70% of the cost over $600. Plan Q requires the insured to pay the initial $400, but then pays 60% of the cost over $400. Which of the following is a cost level for which both insurance plans pay out the same amount?
A.$1200
B.$1400
C.$1600
D.$1800
Answer: D.$1800
Explanation: 0.7(x-600)=0.6(x-400)
0.1x=420-240
x=1800
The answer is D.
Question: 9548 + 7314 = 4362 + (?)
A.8300
B.8400
C.12500
D.8700
Answer: C.12500
Explanation: 9548 16862 = 4362 + x
+ 7314 x = 16862 - 4362
----- = 12500
16862
-----
C)
Question: Tom started a new grocery store business. During his first month he bought groceries for $650$650 and sold them for $800$800, while in the second month he bought with $800$800 and sold for $1200$1200. We need to know if Tom made more profit or not and profit or loss percentage
A.50 % loss
B.50% Profit
C.40 % loss
D.60 % Profit
Answer: B.50% Profit
Explanation: Solution:
We cannot directly tell from these numbers if Tom's profit is increasing or not since his spending and gain are different amounts each month. In order to solve this problem we need to refer all the values to a fixed base value which is 100. Let us express the percent of his profit with respect to his expenditure for the first month:
(800 - 650) ÷ 650 ⋅ 100 = 23.08%
This means that, if Tom spent $100, he would have made a profit of 23.08 in the first month.
Now, let us apply the same for the second month:
(1200 - 800) ÷ 800 ⋅ 100 = 50%
So, for the second month, if Tom spent $100$100 he would have made a profit of $50$50(because $100⋅50%=$100⋅50÷100=$50$100⋅50%=$100⋅50÷100=$50). Now it is clear that Tom's profits are increasing.
Answer B
Question: Sarah's grade was 50th percentile of the 20 grades for her class. Of the 30 grades from another class, 10 were higher than Sarah's, and the rest were lower. If no other grade was the same as Sarah's grade, then Sarah's grade was what percentile of the grades of the two classes of two classes combined?
A.52nd
B.56th
C.60th
D.70th
Answer: C.60th
Explanation: 52nd/56th/60th/70th/82nd
Correct option: C
Question: eleven family members: 5 grandchildren (3 brothers and 2 sisters) and their 6 grandparents are to be seated around a circular table. How many different seating arrangements are possible so that 2 sisters are seated between any two of the three brothers?
A.120
B.60480
C.1440
D.2880
Answer: B.60480
Explanation: Answer: B.
Question: In a car wheel, four spokes cover 40 degree. Then for the entire car,how many spokes are there?
A.120
B.144
C.158
D.200
Answer: B.144
Explanation: given, 4 spokes cover 40degrees,
so for 360 degrees.---->360*4/40=36..
so, for entire car, 4*36=144
ANSWER:B
Question: A pipe can empty 2/3rd of a cistern in 10mins. In 8 mins, what part of the cistern will be empty?
A.2/3
B.3/7
C.8/15
D.3/8
Answer: C.8/15
Explanation: 2/3 ---- 10
? ----- 8 ==> 8/15
C
Question: In an election between the two candidates, the candidates who gets 70% of votes polled is winned by 200 vote’s majority. What is the total number of votes polled?
A.750
B.500
C.800
D.850
Answer: B.500
Explanation: Explanation:
Note: majority (40 %) = difference in votes polled to win (70 %) & defeated candidates (30 %)
40 % = 70 % - 30 %
40% -----> 200 (40*5 = 200)
100% -----> 500 (100*5 = 500)
Answer: Option B
Question: (112 x 5^4) = ?
A.60000
B.70000
C.80000
D.64000
Answer: B.70000
Explanation: (112 x 5^4) = 112 x (10/2)^4 =112 x 10^4 / 2^4 =	1120000 /6 = 70000
ANSWER:B