RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: 4539,1513,378.25,75.65,12.60 ?
A.1.2
B.6.87
C.1.8
D.4.68
Answer: C.1.8
Explanation: Explanation :
Terms are continuously divided by 3 ,4, 5,6 and so on
4539
4539 Ã· 3 = 1513
1513 Ã· 4 = 378.25
378.25 Ã· 5 =75.65
75.65 Ã· 6= 12.60
12.60Ã·7=1.80
Answer : Option C
Question: A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year?
A.2277
B.28886
C.5550
D.2678
Answer: C.5550
Explanation: Total production of salt by the company in that year
= 5000 + 5100 + 5200 + .... + 6100 = 66600.
Average monthly production of salt for that year
= 66600/12 = 5550
Answer: C
Question: A square has a side 5 centimeters shorter than the side of a second square. The area of the larger square is four times the area of the smaller square. Find the side of each square
A.5
B.6
C.7
D.8
Answer: A.5
Explanation: Let x be the side of the smaller square and y be the side of the larger square. The statement "A square has a side 5 centimeters shorter than the side of a second square" may be formulated by
x = y - 5
The area of the smaller square is equal to x 2 = (y - 5) 2 and the area of the larger square is equal to y 2
The statement "the area of the larger square is four times the area of the smaller square" may be formulated by
y 2 = 4 (y - 5) 2
Write the above equation so that the right side is equal to 0
y 2 - 4 (y - 5) 2 = 0
The left side is made up of the difference of two squares and can be easily factored as follows
[ y - 2 (y - 5) ] [ y + 2 (y - 5) ] = 0
Solve for y to find
y = 10 and y = 10 / 3.
We now use the equation x = y - 5 to find x
y = 10 and x = 5
For the second solution y = 10 / 3, x is negative and cannot be accepted as the length of the side of a square must be positive.
Answer A
Question: . A cycle is bought for Rs.900 and sold for Rs.1080, find the gain percent?
A.16 2/3%
B.20%
C.18%
D.25%
Answer: B.20%
Explanation: 900 ---- 180
100 ---- ? => 20%
ANSWER:B
Question: In a 80 meters race A beats B by 56 m or 7 seconds. A's time over the course is:
A.3 seconds
B.12 seconds
C.10 seconds
D.18 seconds
Answer: A.3 seconds
Explanation: B runs 56 m in 7 sec.
=> B runs 80 m in 7/56*80 = 10 seconds
Since A beats B by 7 seconds, A runs 80 m in (10-7) = 3 seconds
Hence, A's time over the course = 3 seconds
ANSWER:A
Question: A man invests Rs.5000 for 3 years at 5% p.a. compound interest reckoned yearly. Income tax at the rate of 20% on the interest earned is deducted at the end of each year. Find the amount at the end of the third year
A).	B)
C) D)
A.Rs. 5624.32
B.Rs.5423
C.Rs.5634
D.Rs.5976
Answer: A.Rs. 5624.32
Explanation: 5% is the rate of interest. 20% of the interest amount is paid as tax.
i.e 80% of the interest amount stays back.
if we compute the rate of interest as 80% of 5% = 4% p.a., we will get the same value.
The interest accrued for 3 years in compound interest = 3 x simple interest on principal + 3 x interest on simple interest + 1 x interest on interest on interest.
= 3 x (200) + 3 x (8) + 1 x 0.32 =600 + 24 + 0.32 = 624.32
The amount at the end of 3 years = 5000 + 624.32 = 5624.32 Answer: A
Question: A boat can move upstream at 25 kmph and downstream at 35 kmph, then the speed of the current is?
A.5
B.8
C.7
D.4
Answer: A.5
Explanation: US = 25
DS = 35
M = (35 - 25)/2 = 5
Answer:A
Question: An empty pool being filled with water at a constant rate takes 6hours to fill to 3/5 of its capacity.how much more time will it take to finish filling the pool?
A.5hr 30min
B.5hr 20min
C.4hr 48min
D.3 hr 12min
Answer: D.3 hr 12min
Explanation: As pool is filled to 3/5 of its capacity then 2/5 of its capacity is left to fill.
To fill 3/5 of the pool took 8 hours --> to fill 2/5 of the pool will take 8/(3/5)*2/5=16/3 hours = 5 hours 20 minutes (because if t is the time needed to fill the pool then t*3/5=8 --> t=8*5/3 hours --> to fill 2/5 of the pool 8*5/3*2/5=16/3 hours will be needed).
Or plug values: take the capacity of the pool to be 5 liters --> 3/5 of the pool or 3 liters is filled in 8 hours, which gives the rate of 3/8 liters per hour --> remaining 2 liters will require: time = job/rate = 2/(3/8) = 16/3 hours =3 hours 12 minutes.
Answer: D.
Question: How many meters are there in 660 centimeters?
A.6.6 meters
B.660 meters
C.600 meters
D.6.5 meters
Answer: A.6.6 meters
Explanation: Solution:
1 meter = 100 centimeters
Just divide 660 by 100
660 Ã· 100 = 6.6, so there are 6.6 meters in 660 centimeters
Option A
Question: Consider a Number 3.1n2
n represent the hundredths digit in the number shown above. If the number is rounded to the nearest hundredth, which of the following could be the tenths digit in the rounded number?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: In this ques we are given the thousandth digit as 2, so the hundreth digit can take any value from 0-9. For the hundreth digit i considered 2 set of values (i) 0, 1, 2, 3 and (ii) 4, 5, 6, 7, 8, 9. Given that the thousandth digit is 2, the hundreth digit has to go up by 0, and correspondingly, the tenth digit should remain same.i.e 0-9.say 1
A
Question: If x and y are integers and x=50y + 39, which of the following must be odd?
A.xy
B.x + y
C.3X-1
D.X+2Y
Answer: D.X+2Y
Explanation: x = 50y + 69, since y is integer, 50y will always be even hence 50y + 69 will be odd hence x = odd
you don't know whether Y is even or odd, so you need to try.
A: odd * even = even ; odd*odd= odd ->not true
B: odd + odd = even ; odd+even = odd -> not true
D: odd + 2*odd = odd ; odd + 2*even = odd -> TRUE, stop here.
C: EVEN ...E - EVEN
Answer D
Question: In the Bombay Stock Exchange there are 45% female employees and thus the number of male employees is exceeded by 72. Hence the total no. of employees in the BSE is:
A.540
B.720
C.800
D.550
Answer: B.720
Explanation: Solution: Female employees = 45%
Male employees = 55%
Difference = 55 - 45 = 10%
→ 10% = 72
→ 1% = 72 /10
→ 100 = 7.2 * 100 = 720.
Answer: Option B
Question: Find the simple interest on the Rs. 2000 at 25/4% per annum for the period from 4th Feb 2005 to 18th April 2005
A.Rs 25
B.Rs 30
C.Rs 35
D.Rs 40
Answer: A.Rs 25
Explanation: Explanation:
One thing which is tricky in this question is to calculate the number of days.
Always remember that the day on which money is deposited is not counted while the day on which money is withdrawn is counted.
So lets calculate the number of days now,
Time = (24+31+18) days = 73/365 years = 1/5 years
P = 2000
R = 25/4%
S.I. = =2000×25 /4×5×100=25
Option A
Question: A man is 18 years older than his son. In eight years, his age will be twice the age of his son. The present age of this son is
A.5 years
B.10 years
C.15 years
D.20 years
Answer: B.10 years
Explanation: Explanation:
Let's Son age is x, then Father age is x+18.
=> 2(x+8) = (x+18+8)
=> 2x+16 = x+26
=> x = 10 years
Answer: Option B
Question: Calculate 73196 ÷ ? = 631
A.101
B.116
C.119
D.116
Answer: D.116
Explanation: Answer
Let 62976/X = 631
Then X = 62976/631 =116
Option: D
Question: The angles of a triangle are in the ratio 2: 6 : 4. Find the measurement of the 3 angles of triangle.
A.90°
B.60°
C.20°
D.30°
Answer: B.60°
Explanation: If the ratio of the three angles is 2:6:4, then the measures of these angles can be written as 2x, 6x and 4x. Also the sum of the three interior angles of a triangle is equal to 180°. Hence
2x + 6x + 4x = 180
Solve for x
12x = 180
x =15
The measures of the three angles are
2x =2 x15=30°
6x = 6 × 15= 90°
4x = 4 × 15 = 60°
B
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions?
A.708 m
B.704 m
C.774 m
D.714 m
Answer: B.704 m
Explanation: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm
= 704 m
Answer:B
Question: In Town X, 64 percent of the population are employed, and 44 percent of the population are employed males. What percent of the employed people in Town X are females?
A.16%
B.55%
C.29%
D.40%
Answer: C.29%
Explanation: answer b
male-employed - 64%
female-employed-20%
Total employed 64%
means total unemployed = 36%
therefore d and e are not correct because female unemployed has to be less than 36%
female-unemployed = 32% male unemployed = 4%
48% + 4% = 52%
16% + 32% = 48%
plug in a and b in place of 32% and the sum is not 100%
20/64 =29 C
Question: An investment of $100 was made in a certain account and earned interest that was compounded annually. The annual interest rate was fixed for the duration of the investment, and after 12 years the $100 increased to $400 by earning interest. In how many years after the initial investment was made the $1000 have increased to $8000 by earning interest at that rate?
A.16
B.20
C.18
D.24
Answer: C.18
Explanation: In 12 years the investment quadrupled (from $100 to $400).
Thus, at the same rate compounded annually, it would need additional 12/2=6 years to double (from $400 to $800).
Therefore, 12+6=18 years are needed $100 to increase to $800.
Answer: C.
Question: A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long?
A.26
B.89
C.76
D.27
Answer: B.89
Explanation: Speed = 240/24 = 10 m/sec.
Required time = (240 + 650)/10
= 89 sec.
Answer:B
Question: How many 3-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHM', if repetition of letters is not allowed?
A.690
B.504
C.740
D.760
Answer: B.504
Explanation: The word 'LOGARITHM' has 9 different letters.
Hence, the number of 3-letter words(with or without meaning) formed by using these letters
= 9P3
=
9
×
8
×
7
=
504
Option B
Question: 10, 14, 26, 42, 70, ?
A.86
B.98
C.114
D.126
Answer: C.114
Explanation: Each term of the series, except the first two terms, is 2 more than the sum of the preceding two terms.
Answer : C.
Question: A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 60%?
A.800
B.882
C.772
D.652
Answer: A.800
Explanation: Cost price = Rs.500
profit = 60% of 500 = Rs.300
Selling price = Cost price + Profit
= 500 + 300 = 800
Answer:A
Question: A trader cheats both his supplier and customer by using faulty weights. When he buys from the supplier, he takes 10% more than the indicated weight. When he sells to his customer, he gives the customer a weight such that 30% of that is added to the weight, the weight claimed by the trader is obtained. If he charges the cost price of the weight that he claims, find his profit percentage.
A.20%
B.43%
C.99.33%
D.75.109%
Answer: B.43%
Explanation: Anyways, one can infer that he 'steals' 10% from suppliers and then charges 30% extra to customers
So basically 1.1 * 1.3 = 1.43
Given that 1 is start point, we get 43% more
Hence answer is B
Question: The sale price sarees listed for Rs.400 after successive discount is 10% and 5% is?
A.39
B.37
C.342
D.288
Answer: C.342
Explanation: 400*(90/100)*(95/100) = 342
Answer: C
Question: A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.
A.200, 360,162
B.200, 460,160
C.200, 360,160
D.200, 360,138
Answer: C.200, 360,160
Explanation: Explanation:
let ratio be x.
Hence no. of coins be 5x ,9x , 4x respectively
Now given total amount = Rs.206
=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206
we get x = 40
=> No. of 50p coins = 200
=> No. of 25p coins = 360
=> No. of 10p coins = 160
Answer: C)
Question: If (A-B-C+D = 18) and (A+B-C-D = 4), what is the value of (B-D)^2?
A.49.
B.8.
C.12.
D.16.
Answer: A.49.
Explanation: EQ1: A - B - C + D = 18
EQ2: A + B - C - D = 4
(1) Subtract EQ1 from EQ2
A - B - C + D = 18
- A +B - C - D = 4
------------------------
-2B + 2D = 14
(2) Simplify
-B + D = 7
B - D = -7
(B-D)^2 = (-7)^2 = 49
My answer: A
Question: A vendor sells 60 percent of the apples he had and throws away 40 percent of the remainder. The next day, the vendor sells 50 percent of the remaining apples and throws away the rest. In total, what percent of his apples does the vendor throw away?
A.24
B.26
C.28
D.30
Answer: C.28
Explanation: Let x be the original number of apples.
On day one, the vendor throws away (0.4)(0.4)x=0.16x.
The remaining apples are (0.6)(0.4)x = 0.24x.
On day two, the vendor throws away (0.5)(0.24)x=0.12x.
The vendor throws away a total of 0.16x + 0.12x = 0.28x.
The vendor throws away 28 percent of the apples.
The answer is C.
Question: A bookshop had science and art books in the ratio of 2:5. By the end of the week, 20% of both type of books were sold and 2240 books were unsold. How many science books were there at the starting?
A.700
B.750
C.780
D.800
Answer: D.800
Explanation: science books sold = 2x × 0.2 = 0.4x
science books unsold = 2x – 0.4x = 1.6x
art books sold = 5x × 0.2 = x
art books unsold = 5x – x = 4x
total books unsold = 1.6x + 4x = 5.6x
5.6x = 2240
x = 400
2x science = 800
D
Question: A perfect cube is an integer whose cube root is an integer. For example, 27, 64 and 125 are perfect cubes. If p and q are perfect cubes, which of the following will not necessarily be a perfect cube?
A.8p
B.pq
C.pq + 27
D.-p
Answer: C.pq + 27
Explanation: A. since p is a perfect cube and 8 is a perfect cube, 8p will be a perfect cube. reject.
B. since p is a perfect cube and q is a perfect cube, pq will be a perfect cube. reject.
C. Hold.
D. since p is a perfect cube, -p will also be a perfect cube. reject.
E. (p-q)^6, is a perfect cube, so reject.
By elimination C is the answer.
Check say p = 1, q=8, then 8+27 = 35 --> not a perfect cube.
ANSWER:C
Question: find value for x from given equation? x + 1 = -3
A.1
B.-4
C.-3
D.-5
Answer: B.-4
Explanation: 1. Subtract 1 from both sides:
x + 1 - 1 = -3 - 1
2. Simplify both sides:
x = -4
B
Question: If n is a positive integer, which of the following is a possible value of |71 - 5n| ?
A.7
B.5
C.19
D.15
Answer: C.19
Explanation: When 71>5n, then |71- 5n| = 71- 5n = (70-5n) + 1 = {multiple of 5} + 1
When 71<=5n, then |71 - 5n| = -(71- 5n) = (5n-70) - 1 = {multiple of 5} - 1
So, the correct answer must be 1 greater or 1 less than a multiple of 5. Only C fits.
Answer: C
Question: SI on a certain sum of money for 3 yrs at 8 percent /annum is 1/2 the CI on Rs.4000 for 2 yrs at 10 percent/ annum. The sum placed on SI is?
A.Rs. 1600
B.Rs. 1650
C.Rs. 1750
D.Rs. 1800
Answer: C.Rs. 1750
Explanation: C.I.
= Rs. 4000 x 1 +	10 2	- 4000
100
= Rs. 4000 x	11	x	11	- 4000
10	10
= Rs. 840.
Sum = Rs. 420 x 100 = Rs. 1750.
3 x 8
C
Question: The sum of two numbers is 40 and their product is 300. What will be the sum of their reciprocals?
A.1/40
B.8/75
C.75/4
D.2/15
Answer: D.2/15
Explanation: (1/a)+(1/b)=(a+b)/ab=40/300=2/15
ANSWER:D
Question: The length of a rectangle is four times its width. If the area is 100 m2 what is the length of the rectangle?
A.50 m
B.40 m
C.80 m
D.20 m
Answer: D.20 m
Explanation: Let L be the length and W be the width of the rectangle. Hence
L = 4 W
We now use the area to write
100 = L ? W
Substitute L by 4 W in the equation above
100 = 4 W ? W = 4 W2
Solve for W and find L
4 W2 = 100
W2 = 25 , W = 5 and L = 4 W = 20 m
correct answer D
Question: There are 15 boys and 10 girls in a class. If three students are selected at random, in how many ways that 1 girl or 2 boys are selected ?
A.100
B.105
C.115
D.120
Answer: C.115
Explanation: n(s) = sample space = 25C3 = 2300
E = event that 1 girl and 2 boys are selected
n(E) = we have to select 2 boys from 15 or 1 girl from 10
= 15C2 + 10C1
= 115
Ans - C
Question: A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 400. Find the total worth of the stock?
A.30000
B.66000
C.53000
D.20000
Answer: D.20000
Explanation: D
20000
Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x - 49x/50 = x/50
x/50 = 400 => x = 20000
Question: In a plastic company, 14 men working 8 hrs per day complete a piece of work in 12 days. To complete the same work in 6 days, working 14 hours a day, the number of men required is :
A.16
B.8
C.12
D.20
Answer: A.16
Explanation: Explanation :
Solution: Let the required number of men be x.
Less days, more men (Indirect proportion)
more working hrs per day, less men (Indirect proportion)
days 6 : 12
} : : 14 :x
working hrs 14 : 8
.'. 6*14*x = 12*8*14 \
=> x =16.
Answer : A
Question: Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of the tickets sold, 30% were sold at half price and the remaining tickets were sold at the full price of $2. What was the total revenue from ticket sales?
A.$16,830
B.$17,820
C.$18,000
D.$19,800
Answer: A.$16,830
Explanation: 10000 seats --> Full Price : Half Price = 7000 : 3000
Price when all seats are filled = 14000 + 3000 = 17000
100 seats are unsold --> Loss due to unfilled seats = 30 + 2*70 = 170
Revenue = 17000 - 170 = 16830
Answer: A
Question: In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100?
A.18
B.27
C.25
D.21
Answer: C.25
Explanation: A scores 60 while B score 40 and C scores 30.
The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.
In a game of 100 points, B gives (100 - 75) = 25 points to C.
Answer: C
Question: A person distributed 20% of his income to his 3 children each. He deposited 25% of his income to his wife's account. He donated 5% of remaining amount to an orphan house.Finally he has $40000. Find his total income?
A.A)452000
B.B)562000
C.C)800000
D.D)400000
Answer: D.D)400000
Explanation: 3 children got = 3*20% = 60%
wife got = 25%
orphan house = 5%
total = 60+25+5 = 90%
remaining = 100-90 = 10%
10% = 40000
100% = 40000*100/10 = $400000
Answer is D
Question: A part of certain sum of money is invested at 9% per annum and the rest at 12% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
A.4:2
B.4:8
C.4:3
D.4:0
Answer: C.4:3
Explanation: 12:9
= 4:3
Answer: C
Question: In what time will a railway train 50 m long moving at the rate of 36 kmph pass a telegraph post on its way?
A.5 sec
B.4 sec
C.3 sec
D.6 sec
Answer: A.5 sec
Explanation: T = 50/36 * 18/5 = 5 sec
Answer: A
Question: The average of 11 results is 44, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
A.122
B.156
C.118
D.125
Answer: A.122
Explanation: 1 to 11 = 11 * 44 = 484
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 â€“ 484 = 122
Answer:A
Question: In a school 50% of the students are younger than 10, 1/20 are 10 years old and 1/10 are older than 10 but younger than 12, the remaining 70 students are 12 years or older. How many students are 10 years old?
A.10 students
B.20 students
C.30 students
D.40 students
Answer: A.10 students
Explanation: Let us write the fraction for each group of students
Group A: younger than 10: 50% = 50/100 = 1/2
Group B: 10 years old: 1/20
Group C: older that 10 but younger than 12: 1/10
Group D: 12 years or older: 70 students
The fraction for group A, B and C together is given by
1 / 2 + 1 / 20 + 1 / 10 = 10 / 20 + 1 / 20 + 2 / 20 , common denominator
= 13 / 20 , add numerators
The fraction for group D is given by
20 / 20 - 13 / 20 = 7 / 20 and corresponds to 70 students
If X is the total number of students, then
7 / 20 of X = 70
or (7 / 20) ? X = 70
Solve for X
X = 70 ? (20 / 7) = 200
Students who are 10 years old have a fraction of 1 / 20 of the total X and their number is equal to
(1 / 20) of 200 = 10 students
correct answer A
Question: Pointing to an old man, Kailash said, "His son is my son's uncle." How is the old man related to Kailash ?
A.Brother
B.Uncle
C.Father
D.Grandfather
Answer: C.Father
Explanation: Explanation:
Kailash's son's uncle — Kailash's brother. So. the old man's son is Kailash's brother
i.e., the old man is Kailash's father.
Answer: C
Question: On what dates of April,2001 did Wednesday fall ?
A.1st,8th,15th,22nd,29th
B.2nd,9th,16th,23rd,30th
C.3rd,10th,17th,24th
D.4th,11th,18th,25th
Answer: D.4th,11th,18th,25th
Explanation: Solution
We shall find the day on 1st April,2001.
1st April,2001 =(2000 years + Period from 1.1.2001 to 1.4.2001)
Odd days in 1600 years =0
Odd days in 400 years =0
Jan. Feb. March April
(31 + 28 + 31 + 1) =91 days =0 odd days. Answer D
Question: In a simultaneous throw of 2 dice what is the probability of getting a total of 6?
A.1/4
B.5/36
C.2/11
D.3/13
Answer: B.5/36
Explanation: n(S) = 6*6 = 36
E = {(1,5),(2,4),(3,3),(4,2),(5,1)}
Probability = 5/36
Answer is B
Question: The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?
A.12 cm
B.14 cm
C.18 cm
D.20 cm
Answer: C.18 cm
Explanation: 2(l + b) = 5
b 1
2l + 2b = 5b
3b = 2l
b = 2 l
3
Then, Area = 216 cm2
l x b = 216
l x 2 l = 216
3
l2 = 324
l = 18 cm.
C
Question: Find the least number of candidates in an examination so that the percentage of successful candidates should be 76.8%:
A.105
B.115
C.125
D.135
Answer: C.125
Explanation: suppose no. of total candidates are 'y' and successful are 'x'.
(x/y)*(100)=76.8 or x/y=0.768
or y=x/0.768
here we need minimum value of y, which is obtained by minimum value of x.
if put x=768 then y=1000
now we will try decrease value of x than we will find less value of y. so factorized 768 by 2 further.
if put x=384 then y=500
if put x=192 then y=250
if put x=96 then y=125(answer)
if put x=48 then y=62.5(not integer)
so ans is 125
ANSWER:C
Question: If the difference between the length and breadth of a rectangle is 23 m and its perimeter is 166 m, what is its area?
A.1590
B.2535
C.2530
D.2515
Answer: A.1590
Explanation: length = breadth +23. Therefore,
4× breadth +2×23=166 m
⇒ breadth =30 m
length =30+23=53 m
Area =53×30=1590 m2
Answer is A.
Question: A glass was filled with 10 ounces of water, and 0.02 ounce of the water evaporated each day during a 30-day period. What percent of the original amount of water evaporated during this period?
A.0.006%
B.0.06%
C.6%
D.2%
Answer: C.6%
Explanation: In 30 days 30*0.02=0.6 ounces of water evaporated, which is 0.6/10âˆ—100=6 of the original amount of water.
Answer: C.
Question: Two bullet train s 140 m and 180 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
A.15.8 sec.
B.11.52 sec.
C.11.8 sec.
D.10.8 sec.
Answer: B.11.52 sec.
Explanation: Relative speed = (60 + 40) km/hr = 100x5/18 = 250/9 m/ sec.
Distance covered in crossing each other = (140 + 180) m = 320 m.
Required time = 320x9/250 = 11.52 sec.
ANSWER B
Question: M, N and O are inner angles in a triangle. If M= N+ O, what can't be the size of N?
A.90 DEGREES
B.60 DEGREES
C.960 DEGREES
D.960 DEGREES
Answer: A.90 DEGREES
Explanation: Given M= N+ O, and M, N and O are inner angles in a triangle. Thus M+ N+ O= 180
N+ O + N+ O= 180 => 2(N+ O) = 180 => N+ O= 90. Thus beta will be less than 90.
Hence the answer is A.
Question: Mohan purchased 16 kgs of rice at the rate of Rs.26 per kg and 8 kgs of pulses at the rate of Rs.26 per kg. Whaat is the total amount that he paid to the shopkeeper?
A.A)Rs.598
B.B)Rs.625
C.C)Rs.596
D.D)Rs.595
Answer: B.B)Rs.625
Explanation: Explanation:
Price of 16 kgs of rice at Rs.26/kg = 16x26 = Rs.416
Price of 8 kgs of pulses at Rs.26/kg = 8x26 = Rs.208
Therefore, Total amount = Rs.416+Rs.208 = Rs.624.
Answer: Option B
Question: Raj writes a number. He sees that the number of two digits exceeds four times the sum of its digits by 3. If the number is increased by 18, the results is the same as the number formed by reversing the digits. Find the next immediate prime greater than the number.
A.22
B.37
C.88
D.27
Answer: B.37
Explanation: Let the number be xy = 10x + y
10x + y = 4(x+y) + 3 ⇒⇒ 2x - y -1 -------(1)
Also 10x + y +18 = 10y +x , 9(y-x) = 18, y-x = 2 -------(2)
Solving we get x = 3, y = 5
The number is 35. So next immediate prime is 37
Answer:B
Question: Q' = 3Q - 3, what is the value of (5')' ?
A. 96
B. 108
C. 120
D. 132
Answer: D. 132
Explanation: (5')'=(3*5-3)'=12'=12*12-12=132
Answer D