RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Steve traveled the first 2 hours of his journey at 40 mph and the last 3 hours of his journey at 90 mph. What is his average speed of travel for the entire journey?
A.60 mph
B.56.67 mph
C.53.33 mph
D.70 mph
Answer: D.70 mph
Explanation: Answer
Average speed of travel = Total distance travelled/Total time taken
Total distance traveled by Steve = Distance covered in the first 2 hours + distance covered in the next 3 hours.
Distance covered in the first 2 hours = speed * time = 40 * 2 = 80 miles.
Distance covered in the next 3 hours = speed * time = 90 * 3 = 270 miles.
Therefore, total distance covered = 80 + 270 = 350 miles.
Total time taken = 2 + 3 = 5 hours.
Hence, average speed = Total distance travelled/Total time taken=350/5 = 70 miles per hour.
Choice D
Question: Three people (1 couple and 1 single) are seated at random in a row of 8 chairs. What is the probability that the couple does not sit together?
A.2/3
B.2/5
C.3/8
D.3/4
Answer: D.3/4
Explanation: The total number of arrangements of 3 people is 8*7*6 = 336
Let's think of the couple as a single unit.
The number of arrangements when the couple sits together is 7*6*2 = 84.
Note that we multiply by 2 because the couple can switch places with each other.
The number of ways the couple won't sit together is 336 - 84 = 252
P(couple won't sit together) = 252/336 = 3/4
The answer is D.
Question: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
A.100
B.110
C.120
D.130
Answer: A.100
Explanation: Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Question: A student was asked to find 4/5 of a number. But the student divided the number by 4/5, thus the student got 18 more than the correct answer. Find the number.
A.30
B.35
C.40
D.45
Answer: C.40
Explanation: Let the number be x.
(5/4) * x = (4/5)*x + 18
25x = 16x + 360
9x = 360
x = 40
The answer is C.
Question: Rohit walked 25 m towards south. Then he turned to his left and walked 20 m. He then turned to his left and walked 25 m. He again turned to his right and walked 15 m. At what distance is he from the starting point and in which direction?
A.35 m East
B.35 m North
C.30 m West
D.45 m East
Answer: A.35 m East
Explanation: ! 20 !--->15
! !
!--->!
20+15=35
ANSWER:A
Question: If the selling price is hexatrupled, the profit is septupled, what is the percentage of profit??
A.50%
B.100%
C.150%
D.200%
Answer: B.100%
Explanation: we can make two equations from the given info..
let selling price be S and cost price be C..
so profit=P=S-C...
if S is doubled profit is tripled..
so 7P=6S-C..
or S=6P...
therefore C=P..
% of profit=P/P=100%
B
Question: What is the total number of P integers between 100 and 200 that are divisible by 3?
A. 33
B. 32
C. 31
D. 30
Answer: A. 33
Explanation: yes there is a different way of arriving at that answer ....
u can also use airthmetic progression to get the answer
since the first term to be divisble by 3 is 102 ..take that as A .. the starting no
and since 198 is the last digit to be divisible by 3 take that as N ...
since the difference is 3 take that as D
no u have to find what term is 198 take that as nth term
the formula for that is N = A + (n-1) * d
198 = 102 +(n-1) * 3
from this u get n =33
Question: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
A.20
B.80
C.100
D.200
Answer: C.100
Explanation: Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10
x - y = 20 .... (i)
and x + 20 = 2(y - 20)
x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
ANSWER:C
Question: Which one of the following numbers is the greatest positive integer x such that 4^x is a factor of 64^5?
A.5
B.8
C.10
D.15
Answer: D.15
Explanation: 64 = 4*4*4= 4^3
64^5 =(4^3)^5
=4^15
we have to find the greatest positive integer value for x
when x=15, it divides exactly once and that is the least positive integer value of the quotient
therefore, the correct option is D
Question: The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is:
A.15 cm
B.25 cm
C.35 cm
D.42 cm
Answer: C.35 cm
Explanation: Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm.
Answer: Option C
Question: In a friendship gang Kala has 11 gang, in how many ways can he invite one or more of the gang to his house?
A.1244
B.2047
C.3698
D.5789
Answer: B.2047
Explanation: Kala can select one or more than one of his 8 gang.
=> Required number of ways = 2^11 – 1= 2047.
B
Question: A train moves past a house and a river bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train ?
A.79.2 km/hr
B.60.5 km/hr
C.65 km/hr
D.62.5 km/hr
Answer: A.79.2 km/hr
Explanation: length of the train be p metres and its speed - q m/sec.
p/q = 8 => p = 8q
p+264/20 = q
8q+264 = 20q
q = 22
speed = 22 m/s = (22*18/5) = 79.2 km/hr
ANSWER A
Question: The last day of a century cannot be
A.Monday
B.Wednesday
C.Tuesday
D.Friday
Answer: C.Tuesday
Explanation: Explanation :
We know that number of odd days in 100 years = 5
Hence last day of the first century is Friday
Number of odd days in 200 years = 5 x 2 = 10 = 3 (As we can reduce multiples of 7
from odd days which will not change anything)
Hence last day of the 2nd century is Wednesday
Number of odd days in 300 years = 5 x 3 = 15 = 1 (As we can reduce multiples of 7
from odd days which will not change anything)
Hence last day of the 3rd century is Monday
We know that umber of odd days in 400 years = 0. (? 5 x 4 + 1 = 21 = 0)
Hence last day of the 4th century is Sunday
Now this cycle will be repeated.
Hence last day of a century will not be Tuesday or Thursday or Saturday
Answer : Option C
Question: What is the product of all positive factors of 21?
A.39
B.324
C.441
D.451
Answer: C.441
Explanation: Positive factors of 21 are 1, 3, 7, 21.
Positive factors of 21 is: 21*7*3 =441
Answer: C
Question: A, B and C rents a pasture for Rs.870. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should B pay?
A.360
B.227
C.268
D.198
Answer: A.360
Explanation: 12*8 :16*9 = 18*6
8: 12: 9
12/29 * 870 = 360
Answer:A
Question: The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 867 sq m, then what is the breadth of the rectangular plot?
A.16
B.17
C.18
D.19
Answer: B.17
Explanation: Let the breadth of the plot be b m.
Length of the plot = 3 b m
(3b)(b) = 867
3b2 = 867
b2 = 289 = 172 (b > 0)
b = 17 m.
Answer: Option B
Question: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
A.175
B.195
C.180
D.160
Answer: A.175
Explanation: Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x * 3.20 = 432
3.20x = 432 - 384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175.
Answer is A.
Question: A shipment of 220 smartphones contains 84 that are defective. If a customer buys two smartphones at random from the shipment, what is the approximate probability that both phones are defective?
A.1/250
B.1/84
C.11/76
D.1/9
Answer: C.11/76
Explanation: Probability of chosing one defective phone from a lot of 220 which ontains 84 defective phones is = (84/220)
Probability of chosing one defective phone from a lot of 219(we already picked one) which ontains 83(we already picked one) defective phones is = (83/219)
Combined probability of series of events = product of the probabilities = (84/220)*(83/219)
84/220 is close to (21/55) and (83/219)= (36/95)
so answer is (21/55)*(36/95) = (11/76)
So, answer will be C
Question: A man sells a horse for Rs.800 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?
A.277
B.277
C.261
D.860
Answer: D.860
Explanation: CP = SP + 1CP = SP - g
800 + x = 980 - 2x
3x = 180 => x = 60
CP = 800 + 60 = 860
Answer: D
Question: In a certain town, the ratio of NY Yankees fans to NY Mets fans is 3:2, and the ratio of NY Mets fans to Boston Red Sox fans is 4:5. If there are 330 baseball fans in the town, each of whom is a fan of exactly one of those three teams, how many NY Mets fans are there in this town?
A.72
B.88
C.95
D.120
Answer: B.88
Explanation: The ratio of Yankees:Mets:Red Sox = 6:4:5
The Mets fans are 4/15 of the population.
(4/15)*330 = 88
The answer is B.
Question: pqrs is a rectangle having area 50. rx=1/4sr.what is the area of pqxs?
A.41.75
B.42.75
C.43.75
D.44.75
Answer: B.42.75
Explanation: given pqrs is a rectangle and x located on sr whivh is having length rx=1/4sr.
from this we get right angle traingle qrx.
area of qrx=1/2*l/4*b=lb/8= 50/8 =6.25.
therefore area of pqxs= 50-6.25 = 42.75
ANSWER:B
Question: A runs 1 2⁄3 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
A.200 m
B.250 m
C.450 m
D.350 m
Answer: A.200 m
Explanation: Speed of A : Speed of B = 5⁄3 : 1 = 5 : 3
i.e., In a race of 5 m, A runs 5 m and B runs 3 m
i.e., A gains 2 m over B in a race of 5 m
=> A gains 80 m over B in a race of 52×80 = 200 m
Hence, winning point should be 200 m away from the starting point.
ANSWER:A
Question: Johnny bought six peanut butter cans at an average price (arithmetic mean) of 35¢. If Johnny returned two cans to the retailer, and the average price of the remaining cans was 31¢, then what is the average price, in cents, of the two returned peanut butter cans?
A.5.5
B.43
C.47.5
D.66
Answer: B.43
Explanation: Total price of six cans = 6*35 = 210
Total price of 4 cans = 4*31 = 124
Total rice of two cans = 210 - 124 = 86
Average price of two cans = 86/2 = 43 c
Another way to do it is this:
Assume that the four leftover cans were of 31c each. The avg was 35c initially because the two cans were 35c each and were providing another 4c of cost to other 4 cans.
So cost of the two cans = 2*35 + 4*4 = 86
Avg cost of the two cans = 86/2 = 43c
Answer (B)
Question: A rope of which a calf is tied is increased from 5m to 9 m, how much additional grassy ground shall it graze?
A.1218
B.180
C.176
D.200
Answer: C.176
Explanation: π (92 – 52) = 176
Answer: C
Question: (7 + 7 + 7 ÷ 7) / (5 + 5 + 5 ÷ 5) = ?
A.1
B.1 / 5
C.15 / 11
D.3 / 11
Answer: C.15 / 11
Explanation: Answer
Given expression = (7 + 7 + 7 ÷ 7) / (5 + 5 + 5 ÷ 5)
= (14 + 1) / (10 + 1)
=15 / 11
Option: C
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train.
A.150
B.776
C.555
D.257
Answer: A.150
Explanation: Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train(Distance) = Speed * Time
=50/3∗9=150meter
Answer: A
Question: In a certain province in France there are 15 cities. If a single road segment connects only two cities, how many road segments are required in order to connect the cities so that each city is connected to all other cities with a single road segment?
A.30
B.105
C.330
D.14!
Answer: B.105
Explanation: 1 city needs 14 roads to connect directly to the rest => 15 city needs 15*14 roads.
One road is counted twice => the number of road needed is 15*14/2 = 105
Answer B
Question: The value of (8x10^7)(8x10^8) is closest to which of the following?
A.10^17
B.10^14
C.10^18
D.10^19
Answer: A.10^17
Explanation: multiplying these we get,
64 x 10^7 x 10^8
= 6.4 x 10^16
which is closer to 10^17
Answer: A
Question: If the number65947*8 is completely divisible by 8, then the smallest whole number in place of * will be?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: The number 7x8 must be divisible by 8.
x=2 as 728 is divisible by 8.
Correct Option : B
Question: A sum of money place at compound interest doubles itself in 7 years. In how many years will it amount to eight times itself?
A.21
B.25
C.31
D.35
Answer: A.21
Explanation: 100 ---- 200 ---- 7
400 ---- 7
800 ---- 7
------
21 years
Answer: A
Question: A dealer purchased an article at 3/4 of its list price and sold 50% more than the list price. Find his gain percent?
A.180%
B.189%
C.100%
D.109%
Answer: C.100%
Explanation: MP = 100
CP = 75
SP = 150
------
75 ---- 75
100 ---- ? => 100%
Answer: C
Question: The division of a whole number N by 13 gives a quotient of 15 and a remainder of 2. Find N.
A.195
B.196
C.197
D.198
Answer: C.197
Explanation: According to the division process of whole numbers, N can be written, using multiplication, as follows
N = quotient × divisor + remainder = 15 × 13 + 2 = 197
correct answer is C)197
Question: A train running at the speed of 36 km/hr crosses a pole in 9 seconds. Find the length of the train?
A.150 meter
B.299 meter
C.666 meter
D.90 meter
Answer: D.90 meter
Explanation: Speed = 36*(5/18) m/sec = 10 m/sec
Length of Train (Distance) = Speed * Time
(10) * 9
= 90 meter
Answer: D
Question: Which of the following best approximates the value of q if 6^44+3^11=6^q ?
A.55
B.50
C.45
D.44
Answer: D.44
Explanation: We have: 6^44+3^11=6^q
==> because 3^11 > 0 --> 6^q MUST be equal or greater than 6^44 ==>q MUST be equal or greater than 44
==> Option E is out immediately.
Divide both sides by 6^q and q >= 44
We have:
6^(44-q) + 3^11/6^q = 1
Because q >= 44 ==>3^11/6^q = 0.0000xyz, that is very small,we can ignore it.
Thus, 6^(44-q) must be approximately 1
==> 44-q = 0 ==> q is approximately 44
D is the answer.
Question: A worker is paid x rupees for painting every 10 metres of a wall and y rupees for painting every extra metre. During one week, he painted 10 metres on Monday, 13 metres on Tuesday, 12 metres on Wednesday, 11 metres on Thursday and 12 metres on Friday. What is his average daily earning rupees for the five day week?
A.x + (8/5)y
B.(5x + 9y)/5
C.10x + (8/5)y
D.None of these
Answer: A.x + (8/5)y
Explanation: Explanation :
On Monday, the payment = Rs x
On Tuesday, the payment = Rs (x + 3y)
On Wednesday, the payment = Rs (x + 2y)
On Thursday, the payment = Rs (x + y)
On Friday, the payment = Rs (x + 2y)
Average daily earning during the five-day week = (5x + 8y)/5
= x + (8/5)y
Answer : A
Question: A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
A.298 m
B.188 m
C.120 m
D.178 m
Answer: C.120 m
Explanation: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec
= 20 m/sec.
Length of the train = 20 * 6
= 120 m.
Answer:C
Question: A distributor sells a product through an online store, which take a commission of 20% of the price set by the distributor. The distributor obtains the product from a producer at the price of $20 per item. What is the price that the buyer observers online if the distributor wants to maintain a 20% profit on the cost of the item?
A.$30
B.$31
C.$32
D.$33
Answer: A.$30
Explanation: Let x be the price that buyers see online.
The distributor wants to receive 1.2(original price) which should be 80% of x.
1.2(20) = 0.8x
x = 1.2(20) / 0.8 = 1.5(20) = $30
The answer is A.
Question: In a Basket there are 10 apples. Jack wants only 5 apples to eat. How many Possible Combinations that he have?
A.60
B.720
C.84
D.100
Answer: C.84
Explanation: Jack Wants only 5 apples. so the combination comes under 10C5.
10C5= 10!/(10-5)!*5!=10!/5!*5!
10!=10*9*8*7*6*5!
5!=5*4*3*2*1
10C5=10*9*8*7*6/5*4*3*2=84
There are 84 possible ways to choose apples in a basket
Question: A town consists of only one street in the form of a circle. The town authorities give out four licenses for a particular kind of business. The inhabitants of the town live in equal density along the circle and will always go to the closest business for what they need. Business A gets to choose a location first, then business B, then C, and finally D. Each business desires to carve out as much business for themselves as possible but each knows the others all have the same motive. Assume that if a business is indifferent between locating in two different sections of the circle it will choose a section at random. Also assume that the business that goes last will choose a location in the middle of the largest (or one of the largest) sections. Where should business B choose relative to the location of A?
A.more then 1/3
B.barely less then 1/3
C.less then 2/3
D.more then 2/3
Answer: B.barely less then 1/3
Explanation: The answer is just barely less then 1/3 of the circumference of the circle away from A.
This is only a quick overview of the solution, the details are left up to you. Let the circumference of the circle be 1 and that A chooses a location at point 0. Business D will choose a location in the middle of the largest section.
Business C will also choose the midpoint of the larger of the two gaps between the first two businesses.
If business B chooses a point before 1/3 then C will choose a point halfway between B and 1. Business D will choose randomly between the halfway point between A and C or B and C. If x is the location of business B then the area which B will carve out of the circle will be either (1+3x)/8 if D goes between B and C or (1+x)/4 if D goes between A and C. The average of these is (3+5x)/16. The same logic applies if B chooses a point after 2/3.
If business B chooses a point after 1/3 (but before 1/2) then C will choose a point halfway between A and B going the long way and D will choose the halfway point between A and B the short way. This will leave B exactly a 1/4 share of the business. The same logic applies if A chooses a point between 1/2 and just before 2/3.
If B should choose a location at exactly 1/3 then C would choose at 2/3 and D would be indifferent between 1/6, 1/2, and 5/6. B would have a 2/3 chance of having 1/4 of the business share and 1/3 chance of having 1/3, the average being 5/18 =~ 0.27778 .
Thus B should try to maximize (3+5x)/16 without choosing x equal or greater to 1/3. The optimal choice of location would be just a hair short of 1/3 (or just a hair after 2/3). At this point B will have a 50/50 chance at having either 1/4 or 1/3 of the market share for an average of 7/24=~ 0.29166667 of the market share.
correct answer B
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 sec. What is the length of the fast train?
A.27 7/7 m
B.27 8/9 m
C.29 7/9 m
D.27 7/9 m
Answer: D.27 7/9 m
Explanation: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5
= 250/9
= 27 7/9 m.
Answer:D:
Question: If 3 people can do 3 times of a particular work in 3 days, then how many days would it take 4 people to do 4 times of that particular work?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: 3 people can do the work one time in one day.
1 person can do 1/3 of the work in one day.
4 people can do 4/3 of the work in one day.
4 people can do 4 times the work in 3 days.
The answer is C.
Question: There are 12 stamps from which two stamps will be selected. We have five stamps which are the same as five of the stamps which could be selected. What is the probability that the two stamps selected will be different from the stamps that we have?
A.3/14
B.5/19
C.7/22
D.9/23
Answer: C.7/22
Explanation: P(first stamp is different) = 7/12
P(second stamp is different) = 6/11
P(both stamps are different) = 7/12*6/11 = 7/22
The answer is C.
Question: Certain sum becomes 3 times it self at compound interest in 10 years. In how many years it becomes 9 times?
A.24
B.20
C.22
D.28
Answer: B.20
Explanation: P(1 + R/100)(power10) = 3P
=> P(1 + R/100)(power10) = 3
Let P(1 + R/100)(power n) = 9P
=> (1 + R/100)(power n) = 9
=> 3(power 2) = [(1 + R/100)(power10)](power2)
=> (1 + R/100)(power n) => (1 + R/100)(power 20)
=> n = 20 Years.
Answer is B.
Question: 5 years ago Kate was 5 times as old as her Son. 5 years hence her age will be 8 less than three times the corresponding age of her Son. Find the age of kate?
A.33
B.34
C.35
D.36
Answer: C.35
Explanation: let x be the mother's age and y be the son's age
x-5=5(y-5)
x+5=3(y+5)-8
by solving this we get x=35
ANSWER:C
Question: The last day of a century cannot be
A.Monday
B.Wednesday
C.Tuesday
D.Friday
Answer: C.Tuesday
Explanation: Answer: C) Tuesday
Question: What is the ratio between perimeters of two squares one having 3 times the diagonal then the other?
A.32.5
B.32.4
C.32.9
D.32.3
Answer: B.32.4
Explanation: 36/7 r = 6.3
= 32.4
Answer:B
Question: If x is the interest on y and y is the interest on z, the rate and time is the same on both the cases. What is the relation between x, y and z?
A.Y2 = XY
B.Y2 = XZ
C.Y2 = XZ
D.X2 = XZ
Answer: C.Y2 = XZ
Explanation: X = (Y*NR)/100 Y = (Z*NR)/100
X/Y = NR/100 Y/Z = NR/100
X/Y = Y/Z
Y2 = XZ
Answer: C:
Question: A gas station sold 50 000 liters of petrol at $1.50 per liter, 40 000 liters of diesel at $2.20 per liter and 100 000 liters of bio diesel at $1.10 per liter. what % of its total revenue is from bio diesel?
A.45.3%
B.40.3%
C.41.3%
D.42.3%
Answer: B.40.3%
Explanation: Correct Answer:B
The company's total revenue from petrol=50000*$1.50=$75000
The company's total revenue from diesel=40000*$2.20=$88000
The company's total revenue from bio diesel =100000*$1.10=$110000
The combined total of all sales=$273000
Therefore % of bio diesel sales=110000/273000*100= 40.3%
Question: How many multiples of 7 are there between 10 and 100 (both are inclusive)?
A.11
B.13
C.15
D.17
Answer: B.13
Explanation: 7 multiples are 14,21,28,---------,98
It should be mentioned whether 10 and 100 are inclusive.
the answer is (98-14)/7+1=13
Answer is B
Question: if a men rows at the rate of 5 kmph in still water and his rate against the current is 3.5 kmph, then the man’s rate along the current is :
A.4.25 kmhr
B.6 kmph
C.6.5 kmph
D.8.5 kmph
Answer: C.6.5 kmph
Explanation: Solution
Let the rate along the current be x kmph.
Then,1/2(x +3.5)= 5 or x= 6.5 kmph. Answer C
Question: between 100 to 200 how many no are divisible by both 3 and 2 and 100,200 are inclusive?
A.77
B.78
C.79
D.80
Answer: C.79
Explanation: Prime numbers are 21
So 100-21=79
ANSWER:C
Question: Suppose that another fresh fruit contains 40% water and dry fruit contains 25% water. How much dry fruit can be obtained from 100kg of fresh fruit?
A.A)32kg
B.B)40kg
C.C)80kg
D.D)85kg
Answer: C.C)80kg
Explanation: Quantity of pulp in 100kg of fresh fruits = (100-40)% of 100kg = 60kg
Let the quantity of dry fruit obtained be x kg
then, (100-25)% of x = 60
(75/100)*x = 60
x = 80
correct option is C
Question: How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.25 sec
B.40 sec
C.30 sec
D.60 sec
Answer: C.30 sec
Explanation: Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
800+x = (65/3) * 60
800+x = 20 * 65 = 1300
x = 1300 - 800 = 500 meters
ANSWER C
Question: Cheese, bologna, and peanut butter sandwiches were made for a picnic in a ratio of 5 to 7 to 8. If a total of 360 sandwiches were made, how many Cheese sandwiches
were made?
A.15
B.30
C.90
D.42
Answer: C.90
Explanation: For deciding such task we should calculate all parts 5 + 7 + 8 = 20 parts
and we should calculate how many sandwiches holds 1 part:
360 / 20 = 18 sandwiches in one part
For cheese we have 5 parts so:
5 * 18 = 90
Answer is C
Question: If |20x-10| = 130, then find the product of the values of x?
A.-45
B.50
C.-42
D.35
Answer: C.-42
Explanation: |20x-10| = 130
20x-10 = 130 or 20x-10 = -130
20x = 140 or 20x = -120
x = 7 or x = -6
product = -6*7 = -42
Answer is C
Question: One side of a rectangular field is 4 m and its length along diagonal is 5 m. What is the area of the field?
A.3
B.4
C.6
D.8
Answer: A.3
Explanation: M = 4
S = 2
US = 4 - 2 = 2
D = 6
T = 6/2 = 3
Answer: A