RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A, B and C can do a work in 60, 30 and 45 days respectively. If they work together, in how many days will they complete the work?
A.12 4/5 days
B.13 4/5 days
C.13 1/5 days
D.13 2/5 days
Answer: B.13 4/5 days
Explanation: One days's work of A, B and C = 1/60 + 1/30 + 1/45
= (3+6+4)/180 =13/180
A, B and C together can do the work in 13 4/5 days.
ANSWER:B
Question: If x/4 + 24/x = 5, what are the values of 3x - 4?
A.8 And 9
B.20 and 32
C.17 and 19
D.12 and 29
Answer: B.20 and 32
Explanation: I got the same thing B is the answer 20 or 32
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?
A.19 sec
B.22 sec
C.12 sec
D.42 sec
Answer: C.12 sec
Explanation: Explanation:
D = 250 m + 250 m = 500 m
RS = 80 + 70 = 150 * 5/18 = 125/3
T = 500 * 3/125 = 12 sec
Answer: Option C
Question: Evaluate: |5 - 8(3 - 12)| - |5 - 11| = ?
A.40
B.50
C.60
D.71
Answer: D.71
Explanation: According to order of operations, inner brackets first. Hence
|5 - 8(3 - 12)| - |5 - 11| = |5 - 8*(-9)| - |5 - 11|
According to order of operations, multiplication within absolute value signs (which may be considered as brackets when it comes to order of operations) next. Hence
= |5 + 72| - |5 - 11|
= |77| - |-6|
= 77 - 6 = 71
correct answer D)71
Question: Find the 25% of Rs. 200.
A.Rs. 50
B.Rs. 70
C.Rs. 100
D.Rs. 80
Answer: A.Rs. 50
Explanation: Explanation :
25% of 200
=> 25/100 *200 = Rs. 50
Answer : A
Question: The elementary school has 19 fourth graders, 23 fifth graders, and 29 six graders. Fourth graders have 30 minutes of homework per night, fifth graders have 40 minutes of homework per night, and six graders have 60 minutes of homework per night. How many minutes per night does the average student with homework have?
A.about 30 minutes
B.about 40 minutes
C.about 45 minutes
D.about 50 minutes
Answer: C.about 45 minutes
Explanation: Explanation:
19 23 29
30 40 60
570 + 920 + 1740 = 3230/71 = about 45 minutes
C
Question: One fast typist type some matter in 5hrs and another slow typist type the same matter in 6hrs. If both do combine in how much time they will take to finish.
A.2 hr 44 mins
B.11 hr 40 mins
C.2hr 14 mins
D.3 hr 44 mins
Answer: A.2 hr 44 mins
Explanation: Fast's 1 hr work = 1/5
slow's 1 hr work = 1/6
1/5 + 1/6 = 11/30
they ll finish in 30/11hrs= 2 8/11 ==> 2 hr 44 mins
ANSWER:A
Question: if 105 is represented as 253 in base 6,how is 253 represented in base 6?
A.1100
B.1101
C.1111
D.1011
Answer: B.1101
Explanation: (105)base6=253
then (253)base6=1101
because 253%6=1 and 253/6=42
then 42%6=0 and 42/6=7
then7%6=1 and 7/6 = 1
and then 1%6=1 and 1/6=0
we see remainder part in reverse order that is 1101
so ans is 1101
ANSWER:B
Question: The speed of a car is 80 km in the first hour and 60 km in the second hour. What is the average speed of the car?
A.76 kmph
B.70 kmph
C.87 kmph
D.56 kmph
Answer: B.70 kmph
Explanation: S = (80 + 60)/2
= 70 kmph
Answer: B
Question: At present, the ratio between the ages of Arun and Deepak is 4:3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present?
A.20
B.15
C.25
D.18
Answer: B.15
Explanation: Let the present ages of Arun and Deepak be 4x and 3x years respectively.
Then, 4x + 6 = 26 => x = 5
Deepak's age = 3x = 15 years.
ANSWER B
Question: If the area of a square with sides of length 5 centimeters is equal to the area of a rectangle with a width of 4 centimeters, what is the length of the rectangle, in centimeters?
A.4
B.8
C.12
D.7
Answer: D.7
Explanation: Let length of rectangle = L
5^2 = L*4
=> L = 25/4 = 7
Answer D
Question: Two numbers are less than third number by 25% and 37% respectively. How much percent is the second number less than by the first
A.6%
B.8%
C.9%
D.11%
Answer: A.6%
Explanation: Let the third number is x.
then first number = (100-25)% of x
= 75% of x = 75x/100
Second number is (63x/100)
Difference = 75x/100 - 63x/100 = 3x/25
So required percentage is, difference is what percent of first number
(3x/25 * 100/75x * 100 )% = 6% ANSWER :A
Question: What is the sum of all possible solutions to |x + 3|^2 + |x + 3| = 20 ?
A.-1
B.6
C.7
D.12
Answer: C.7
Explanation: Denote |x + 3| as y: y^2 + y = 20 --> y = -5 or y = 4. Discard the first solution since y = |x + 3|, so it's an absolute value and thus cannot be negative.
y = |x + 3| = 4 --> x = 7 . The sum = 7.
Answer: C.
Question: Given a two-digit number, the unit's digit exceeds its ten's digit by 5 and the product of the given number and the sum of its digits is equal to 90, which of the options is the number?
A.27
B.16
C.38
D.61
Answer: A.27
Explanation: Using the elimination method the option that fits this description is 27
7-2 = 5 (unit's digit that exceeds its ten's digit by 3)
27*9 = 243 (the product of the given number and the sum of its digits is equal to 175)
answer :A
Question: Find the value of (2 − 1/3) (1 − 1/4)(1 − 1/5)……… (1 − 1/99)(1 − 1/100)
A.1/20
B.1/18
C.1/21
D.3/5
Answer: A.1/20
Explanation: (2 − 1/3) (1 − 1/4)(1 − 1/5)..... (1 − 1/99)(1 − 1/100)
5/3 × 3/4 × 4/5 × ....... 98/99 × 99/100 = 5/100 = 1/20
A)
Question: In how many B ways can the wordGMATbe arranged so that no such arrangement has A as the first letter?
A.6
B.12
C.18
D.24
Answer: C.18
Explanation: Number of ways of arranging the word GMAT = 4! = 24
Number of ways of arranging the word GMAT so that A is always in the first = 3! = 6
Number of ways of arranging GMAT so that A is not in the beginning B= 24 - 6 = 18
Answer: C
Question: Raj invests a part of Rs. 12,000 in 12% stock at Rs. 120 and the remainder in 15% stock at Rs. 125. If his total dividend per annum is Rs. 1360, how much does he invest in 12% stock at Rs. 120?
A.3000
B.4000
C.5000
D.5500
Answer: B.4000
Explanation: investment in 12% stock be X
Then investment 15% stock = (12000-x)
12/120*x+15/125*(12000-x) = 1360
x=4000
ANSWER B
Question: At what price must an article costing Rs.47.50 be marked in order that after deducting 10% from the list price. It may be sold at a profit of 25% on the cost price?
A.65.9
B.62.3
C.62.7
D.62.2
Answer: A.65.9
Explanation: CP = 47.50
SP = 47.50*(125/100)
= 59.375
MP*(90/100)
= 59.375
MP = 65.9
Answer:A
Question: A palindrome is a number that reads the same forward and backward, such as 242. How many odd seven-digit numbers are palindromes?
A.40
B.400
C.500
D.5,000
Answer: D.5,000
Explanation: 7th digit 1,3,5,7,9
6th digit 0 through 9
5th digit 0 through 9
4th digit 0 through 9
i.e 10*10*10*5 = 5000 numbers
first and second digit and third digit is going to be same as 4th and 5th and 6th. so it would still be 5000 numbers.
Answer is D.
Question: If a certain sample of data has a mean of 33.0 and a standard deviation of 2.0, which of the following pairs contain two values that are each at least 2.5 standard deviations from the mean?
A.(26.0; 39.5)
B.(32.5; 34.0)
C.(30.0; 36.5)
D.(31.5; 38.5)
Answer: A.(26.0; 39.5)
Explanation: The standard deviation is 2, so 2.5 standard deviations would be (2.5)(2) = 5.
The values between 28 and 38 are within 2.5 standard deviations from the mean.
The answer is A.
Question: If the number 97215 * 6 is completely divisible by 11, then the smallest whole number in place of * will be:
A.3
B.2
C.1
D.5
Answer: A.3
Explanation: Answer: Option A
Given number = 97215x6
(6 + 5 + 2 + 9) - (x + 1 + 7) = (14 - x), which must be divisible by 11.
x = 3
Question: A fort of 2000 soldiers has provisions for 50 days. After 10 days some of them left and the food was now enough for the same period of 50 days as before. How many of them left?
A.400
B.992
C.878
D.665
Answer: A.400
Explanation: 2000 ---- 50
2000 ---- 40
x ----- 50
x*50 = 2000*40
x=1600
2000
-------
400
Answer:A
Question: 5n + 2 > 12 and 7n - 19 < 44; n must be between which numbers?
A.1 and 8
B.2 and 6
C.2 and 9
D.2 and 7
Answer: C.2 and 9
Explanation: 5n+2 > 12
5n > 10
n > 2
7n-19 < 44
7n < 63
n < 9
So n must be between 2 and 9
2 < n < 9
correct answer C
Question: A and B complete a work in 8 days. A alone can do it in 16 days. If both together can do the work in how many days?
A.3.75 days
B.3.78 days
C.5.3 days
D.3.15 days
Answer: C.5.3 days
Explanation: 1/8 + 1/16 = 3/16
16/3 = 5.3 days
Answer: C
Question: 40 = a + 3b
5 = |–a|
If a and b are both integers, What is the only possible value that b can take?
A.14
B.15
C.13
D.12
Answer: B.15
Explanation: First understand the meaning of 5 = |-a|
1) when we write |-x| this means the same as |x|.
2) Mod is very easy concept if you solve mod question by considering as a distance. when a mod is written as |x-(a)| = b, this means the distance from point 'a' (both side left and right of 'a' on number line) is b (This is same as given case). |x-(a)| < b means the distance is between the two extreme distance(left and right side of 'a' on number line, considering the max distance is 'b' from 'a’. |x-(a)| > b means the distance is greater than the distance of 'b'..i.e the value of a could be anywhere more than 'b'.
Now come to the question. First its given|-a| = 5 ==> |a| = 5 ===> |a-0| = 5 ==> the distance from zero is equal to 5. So the point will be -5 or 5, as distance from 0 to (-5) is 5 and distance from 0 to 5 is 5. Thus, the value of a will be either 5 or -5.
Now, lets move to equation a + 3b = 40 ==> b = (40 - a)/3. According to question, b is an integer, hence to make b integer (40 - a) must be divisible by 3. Now remove the value which can’t make (40-a) divisible by 3 from the possible values of a (i.e. 5, -5). It will remain with -5 which makes the value of b = (40 - (-5))/3 = 45/3 ==> b = 15...hence answer is B.
Question: Of the total amount that Jill spent on a shopping trip, excluding taxes, she spent 45 percent on clothing, 45 percent on food, and 10 percent on other items. If Jill paid a 5 percent tax on the clothing, no tax on the food, and an 10 percent tax on all other items, then the total tax that she paid was what percent of the total amount that she spent, excluding taxes?
A.3.5
B.3.35
C.3.45
D.3.25
Answer: D.3.25
Explanation: Assume she has $200 to spend.
TAX
Clothing = 45% = $90= $4.5
Food = 45% = $ 90 = $0.00
Items = 10% = $ 20 = $ 2.00
Total tax = $6.50
% of total amount = 6.5/200 * 100 = 3.25%
Answer D
Question: A and B are two partially filled buckets of water. If 4 liters are transferred from A to B, then A would contain one-third of the amount of water in B. Alternatively, if 5 liters are transferred from B to A, B would contain one-half of the amount of water in A. Bucket A contains how many liters of water?
A.47/5
B.13
C.17
D.21
Answer: A.47/5
Explanation: Let A contains A, B contains B liters
so, (A-4)/(B+4)= 1/3.......(1)
again, (B-5)/(A+5)= 1/2..........(2)
from (1)(2) we find A= 47/5
ans: (A)
Question: A bag contains 6 red, 2 green balls. 3 balls are drawn randomly. What is the probability that balls drawn contain exactly two green balls?
A.1/7
B.2/9
C.3/11
D.3/28
Answer: D.3/28
Explanation: Total number of balls = 6+2 = 8
n(S) = 8C3 = 8*7*6 / 3*2 = 56
n(E) = 2C2* 6C1 = 6
Probability = 6/56 = 3/28
Answer is D
Question: How many 4 digit numbers can be formed with the digits 0, 1, 2, 3, 4, 5, 6 and 5?
A.a. 220
B.b. 249
C.c. 432
D.d. 216
Answer: A.a. 220
Explanation: Taking Question with it's same language as given
To make number divisible by 5, the unit digit should be either 0 or 5 only
Case 1: If unit digit is fixed as zero
With two6s The choice to fill the remaining three digits = 3C2 x 5 = 15
With all remaining 3 digits different, The choice to fill the remaining three digits = 6 x 5 x 4= 120
Total Such cases = 120+15 = 135
Case 2: If unit digit is fixed as Five
With two6s and one0The choice to fill the remaining three digits = 2 [6605 or 6065]
With two6s and without0The choice to fill the remaining three digits = 3C2 x 4 = 12
With all remaining 3 digits different, and one0The choice to fill the remaining three digits = 2 (ways to place zero) x 5 x 4= 40
With all remaining 3 digits different, and without0The choice to fill the remaining three digits = 3 x 5 x 4= 60
Total Such cases = 2+12+40+60 = 114
Total numbers = 135+114 = 220
ANSWER OPTION A
Question: 12.5 * 6.2 * 8.8 = ?
A.352
B.435
C.224
D.682
Answer: D.682
Explanation: D
682
? = 12.5 * 6.2 * 8.8 = 682
Question: A pipe takes a hours to fill the tank. But because of a leakage it took 6 times of its original time. Find the time taken by the leakage to empty the tank
A.50 min
B.60 min
C.72 min
D.80 min
Answer: C.72 min
Explanation: pipe a can do a work 60 min.
lets leakage time is x;
then
1/60 -1/x=1/360
x=72 min
ANSWER:C
Question: Rs.8000 become Rs.10720 in a certain interval of time at the rate of 5% per annum of C.I. Find the time?
A.6 YEARS
B.7
C.5
D.3
Answer: A.6 YEARS
Explanation: Explanation:
10720 = 8000(21/20)N
(21/20)6 = (21/20)N => N = 6
Answer: Option A
Question: A train traveling at 72 kmph crosses a platform in 31 seconds and a man standing on the platform in 18 seconds. What is the length of the platform in meters?
A.240 meters
B.260 meters
C.420 meters
D.600 meters
Answer: B.260 meters
Explanation: Speed of train = 72 * (5/18) = 20 m/s
Lets consider the man as a stationery point on the platform.
Crossing the point gives us the length of the train.
Lt = 20 * 18 = 360 m.
Crossing the platform gives us the length of trainlength of platform.
L(t+p) = 20 * 31 = 620 m.
So, length of platform = 620 - 360 = 260 m
IMO, Answer
B
Question: Kiran travels from A to B by car and returns from B to A by cycle in 7 hours. If he travels both ways by car he saves 3 hours. What is the time taken to cover both ways by cycle?
A.11 hours
B.10 hours
C.15 hours
D.17 hours
Answer: B.10 hours
Explanation: B
10 hours
Let the time taken to cover from A to B in car and cycle be x hours and y hours respectively.
x + y = 7 --- (1) ; 2x = 4 --- (2)
solving both the equations, we get y = 5
So, time taken to cover both ways by cycle = 2y hours = 10 hours.
Question: Let A be the event that a randomly selected two digit number is divisible by 3 and let B be the event that a randomly selected two digit number is divisible by 10. What is P(A and B)?
A.1/30
B.1/15
C.1/5
D.1/3
Answer: A.1/30
Explanation: P(A and B) = 1/3*1/10 = 1/30
The answer is A.
Question: The price of food in the area where the Sims family lives is scheduled to increase by 50% next year. Since the Sims family cannot afford an increase in their food bill, how much will they have to reduce consumption to keep their cost the same?
A.17%
B.25.6%
C.none%
D.33.3%
Answer: D.33.3%
Explanation: Solution: Let the current food expense be represented by Rs. 100.
The cost of food rises 50%. So, to buy same amount of food, they need to increase their expense,
= (100 + 50% of 100) = Rs. 150.
But, they want to keep food expense the same, so they have to cut Rs. by 50 to keep it to Rs. =100.
The % decrease in consumption is,
(50/150)*100 = 33.3%.
Mental Calculation Method;
100-----50%↑---→150------X%↓---→100.
Here, X = (50/125)*100 = 33.3%.
Answer: Option D
Question: Two trains of equal lengths take 10 sec and 12 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
A.11
B.12
C.10.9
D.14
Answer: C.10.9
Explanation: Speed of the first train = 120/10 = 12 m/sec.
Speed of the second train = 120/12 = 10 m/sec.
Relative speed = 12 + 10 = 22 m/sec.
Required time = (120 + 120)/22 = 10.9 sec.
Answer: Option C
Question: Which is equal to 11?
A.1.1
B.-11
C.11/11
D.11/1
Answer: D.11/1
Explanation: 11/1 is equal to 11.
Answer: D
Question: A water tank, having the shape of a rectangular prism of base 100 square centimeters, is being filled at the rate of 1 liter per minute. Find the rate at which the height of the water in the water tank increases. Express your answer in centimeters per minute.
A.30 cm
B.10 cm
C.50 cm
D.90 cm
Answer: B.10 cm
Explanation: The volume of a rectangular prism is given by
area of base ? height
The rate at which the tank is being filled is 1 liter per minute which we need to convert
1 liter = 1 dm3
But 1 dm = 10 cm. Hence
1 liter = (10 cm)3 = 1000 cm3
The height h of the water is related to the volume by
volume = area of base *h
In one minute the volume increases by 1 liter or 1000 cm3 and the height increases by
h = volume / area of base = 1000 cm3 / 100 cm2 = 10 cm
correct answer B
Question: A train 200 m long is running with a speed of 68 kmph. In what time will it pass a man who is running at 8 kmph in the same direction in which the train is going?
A.6 sec.
B.7 sec.
C.9 sec.
D.12 sec.
Answer: D.12 sec.
Explanation: Solution
Speed of the train relative to man	=( 68 - 8 )
= 60 Kmph
= 60 x 5 / 18
=50/3 m/sec.
Time taken by it to cover 200 m at (50 /3)m/sec
= (200 x 3/50)sec
= 12 sec.
Answer D
Question: How many possible ways can 2 girls (Rebecca, Kate, Ashley) go on a date with 2 boys (Peter, Kyle, Sam)?
A. 2
B. 4
C. 5
D. 6
Answer: A. 2
Explanation: Any one girl can go with 2 boys.
and 2rd girl can go with remaining 1 boy
2! i.e 2 (A) is the answer
Question: a man buys m no. of pens for rs. n each and sells n no. of pens for rs. m each. then what is the profit he have earned?
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: c.p. of 1 pen=Rs n (given each)
so c.p. of m pens=rs mn
s.p. of 1 pen =rs m
so s.p. of n pens=rs mn
so profit =s.p.-c.p.=0(zero)
ANSWER:A
Question: With an average speed of 40 km/hr a car reaches its destination on time. If it goes with an average speed of 35 km/h, it is late by 15 minutes. The total journey is?
A.30 km
B.40 km
C.70 km
D.80 km
Answer: C.70 km
Explanation: Let the total journey be X km.
X/35 - X/40 = 15/60
Solving for X, we get X = 70
Therefore, total journey = 70 km.
ANSWER:C
Question: If (t-8) is a factor of t^2-kt-45, then k=
A.16
B.12
C.2
D.6
Answer: B.12
Explanation: t^2-kt-48 = (t-8)(t+m) where m is any positive integer.
if 48/8 = 6, then we know as a matter of fact that:
m = +6
and thus k = 8-6 = 12
t^2-kt-m = (t-a)(t+m) where a>m
t^2+kt-m = (t-a)(t+m) where a<m
t^2-kt+m = (t-a)(t-m)
t^2+kt+m = (t+a)(t+m)
B
Question: The perimeter of a semi circle is 144 cm then the radius is?
A.22
B.28
C.97
D.26
Answer: B.28
Explanation: 36/7 r = 144 => r
= 28
Answer:B
Question: Arun, Akash, Amir and Aswanth go for a picnic. When Arun stands on a weighing machine, Akash also climbs on, and the weight shown was 132 kg. When Akash stands, Amir also climbs on, and the machine shows 130 kg. Similarly the weight of Amir and Aswanth is found as 102 kg and that of Akash and Aswanth is 116 kg. What is Aswanth’s weight?
A.58kg
B.78 kg
C.44 kg
D.48 kg
Answer: C.44 kg
Explanation: arun+akash=132-----eq1
akash+amir=130------eq2
amir+aswanth=102------eq3
akash+aswanth=116-------eq4
solving eq 2 and 4
we get amir-aswanth=14-------eq5
now solving eq 3 and 5
we get aswanth=44
ANSWER:C
Question: The ratio between the speeds of two trains is 5: 6. If the second train runs 300 kms in 5 hours, then the speed of the first train is ?
A.60 km/hr
B.50 km/hr
C.55 km/hr
D.65 km/hr
Answer: B.50 km/hr
Explanation: Explanation:
Let the speeds of two trains be 5X and 6X km/hr.
6/X=300/5=>X=10 Km/hr
So speed of first train is 10*5 = 50 km/hr
Option B
Question: A and B can do a piece of work in 21 and 24 days respectively. They started the work together and after some days A leaves the work and B completes the remaining work in 9 days. After how many days did A leave?
A.5 days
B.6 days
C.7 days
D.8 days
Answer: C.7 days
Explanation: In 9 days B completes 9/24 i.e., 3/8th of the work.
Hence 1 - 3/8 = 5/8th of the work is completed by A and B together.
i.e., x (1/21 + 1/24) = 5/8 => x = 7 days.
ANSWER:C
Question: The workforce of Company X is 60% female. The company hired 20 additional male workers, and as a result, the percent of female workers dropped to 50%.How many employees did the company have after hiring the additional male workers?
A.145
B.188
C.189
D.190
Answer: A.145
Explanation: let x be the total worker then 0.6x =female worker and 0.4x is male worker then 20 male worker added
06x/(0.4x +20) = 50/100 or 60x = 50*( 0.4x+100) = 20x+ 5000 or 40x = 5000 , x = 500/4= 125
total worker = 125 +20= 145
A
Question: D is the set of all the multiples of 3 between 20 and 100. E is the set of all the factors of 400. Set D and Set E have how many numbers in common?
A.0
B.1
C.3
D.5
Answer: A.0
Explanation: D is a set of multiples of 3.
400 is NOT a multiple of 3, hence none of its factors is a multiple of 3.
Therefore, those two sets won't have any overlap.
Answer: A.
Question: judith is practicing her dance steps along with her friends. In a particular sequence, all of them form a row. At that point, judithis standing on the 5th position from either end of the row.
Can you find out how many girls are practicing together?
A.4
B.9
C.7
D.6
Answer: B.9
Explanation: As judith is 5th from either end of the row, it means that 4 girls are on one of her sides and 4 are present on the other.
4 + 4 + 1(judith herself) = 9.
Hence,9 girls are practicing the dance together.
correct answer is B)9
Question: What is the value of 3x^2 − 1.8x + 0.4 for x = 0.6?
A.−0.3
B.0
C.0.4
D.1.08
Answer: C.0.4
Explanation: 3x^2-1.8x+0.4 for x=0.6
=3(0.6*0.6)-3*0.6*(0.6)+0.4
=0+0.4
=0.4
ANSWER:C
Question: The contents of a certain box consist of 24 mangos and 30 kiwis. How many kiwis must be added to the box so that exactly 30% of the pieces of fruit in the box will be mangos?
A.24
B.26
C.30
D.46
Answer: B.26
Explanation: mango = (mango + kiwi + x)*0.3
24 = (30 + 24 + x)*0.3
x = 26.
Answer: B.
Question: A computer program generates a sequence of numbers a1, a2, a3, ... such that a1=1, a2=2, and ak=a(k-2)*4-1 for 2 < k < n for n=10. Find a6.
A.19
B.27
C.31
D.36
Answer: B.27
Explanation: a1=1
a2=2
a3=1*4-1=3
a4=2*4-1=7
a5=3*4-1=11
a6=7*4-1=27
27
Question: In an examination, there were 2,000 candidates, out of which 900 candidates were girls and rest were Boys. If 38% of the boys and 32% of the girls passed, then the total percentage of failed candidates is?
A.35.67%
B.64.75%
C.68.57%
D.69.57%
Answer: B.64.75%
Explanation: Girls = 900, Boys = 1100
Passed = ( 38% of 1100 ) + ( 32% of 900)
= 418 + 288 = 706
Failed = 2000 - 706 = 1294
Failed % = [(1294/2000) x 100]%
= 64.7%.
ANSWER:B
Question: If 45% of z is 60% of y and y is 75% of x, what percent of x is z?
A.200
B.160
C.100
D.65
Answer: C.100
Explanation: (45/100)z = (60/100)y
and y = (75/100)x i.e. y = (3/4)x
i.e. (45/100)z = (60/100)*(3/4)x
i.e. z = (60*3)x/(45*4)
i.e. z = (1)x = (100/100)x
i.e. z is 100% of x
Answer: Option C
Question: If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is :
A.Rs.8082
B.Rs.7800
C.Rs.8100
D.Rs.8112
Answer: D.Rs.8112
Explanation: Explanation:
Amount = Rs. [7500(1+4/100)2]= Rs. [7500×26/25×26/25]=Rs.8112.
Correct Option: D
Question: If S is the sum of reciprocals of a list of consecutive integers from 25 to 34, inclusive, S is approximately equal to
A.0.1
B.0.2
C.0.33
D.0.4
Answer: C.0.33
Explanation: We need to find the approximate value of 1/25+1/26+1/27+1/28+1/29+1/30+1/31+1/32+1/33+1/34. Now, the sum of these 10 terms will be very close to 10 times 1/30, which is 0.033*10=0.33.
Answer: C.
Question: sue has 3 apples. Billy has 5 apples. If billy steals all of sues apples and eats 1 how many does he have left?
A.2
B.5
C.6
D.7
Answer: D.7
Explanation: 7 D
Question: If x+|x|+y=7 and x+|y|-y=5 what is x+y=?
A.1
B.-1
C.3
D.5
Answer: D.5
Explanation: If x<0 and y<0, then we'll have x-x+y=7 and x-y-y=6. From the first equation y=7, so we can discard this case since y is not less than 0.
If x>=0 and y<0, then we'll have x+x+y=7 and x-y-y=6. Solving gives x=4>0 and y=-1<0 --> x+y=3. Since in PS questions only one answer choice can be correct, then the answer is C (so, we can stop here and not even consider other two cases).
Answer: C.
Adding both eqn we get 2x +IxI+IyI = 13
Now considering X <0 and y>0
2x-x +y = 13
we get x+y =5
Hence answer should be D