RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If -4 < x < 8 and -6 < y < 3, which of the following specifies all the possible values of xy?
A.-42 < xy < 21
B.-42 < xy < 24
C.-48 < xy < 24
D.-24 < xy < 21
Answer: C.-48 < xy < 24
Explanation: The least value of xy is a bit more than 8*(-6)=-48 and the largest value of xy is a bit less than (-4)*(-6)=24.
Therefore -48 < xy < 24.
Answer: C.
Question: On Friday, Kramer purchases exactly 3 new shirts, 2 new sweaters, and 4 new hats, On the following day and each subsequent day thereafter, Kramer wears one of his new shirts together with one of his new sweaters and one of his new hats. Kramer avoids wearing the exact same combination of shirt, sweater, and hat for as long as possible. On which day is this no longer possible?
A.Tuesday
B.Wednesday
C.Thursday
D.Friday
Answer: A.Tuesday
Explanation: Shirt combinations = 3!/1*(3-1)! = 3*2*1/1*2*1 = 3
Sweater combinations = 2!/1*(2-1)! = 2*1/1*1 = 2
Hat combinations = 4!/1!*(4-1)! = 4*3*2*1/1*3*2*1 = 4
Total Combinations = Shirt Combos*Sweater Combos*Hat Combos
3*2*4=24 combinations
24 / 7 (days of the week) = remainder of 3
Purchased on Friday, 3rd day is Monday. Next day, which he won't have a new combination for, is Tuesday. (A)
Question: In the x-y plane, the area of the region bounded by the graph of |x+y| + |x-y| = 6 is
A.8
B.12
C.81
D.20
Answer: C.81
Explanation: I've never seen such kind of question in GMAT before.
OK there can be 4 cases:
|x+y| + |x-y| = 4
A. x+y+x-y = 6 --> x=3
B. x+y-x+y = 6 --> y=3
C. -x-y +x-y= 6 --> y=-3
D. -x-y-x+y=6 --> x=-3
The area bounded by 4 graphs x=3, x=-3, y=3, y=-3 will be square with the side of 4 so the area will be 9*9=81.
Answer: C
Question: A basket has 5 apples and 4 oranges. Three fruits are picked at random. The probability that at least 2 apples are picked is
A.25/42
B.25/44
C.25/409
D.25/45
Answer: A.25/42
Explanation: Total fruits = 9
Since there must be at least two apples,
(5C2 * 4C1)/8C1 +2C2/2C2 = 25/42.
Answer:A
Question: On a certain test, Bill scored 20 more points than John, but half as many points as Sue. If the sum of the scores of the three students was 160 points, how many points did Bill receive?
A.30
B.45
C.50
D.80
Answer: B.45
Explanation: consider john's points as x
so bill's points are x +20
So sue's points are 2x +40
total of all three students is 4x +60, but this total is given as 160
x = 25
so bill's points = 25 +20 = 45
correct answer option B
Question: A basket has 4 apples and 6 oranges. Three fruits are picked at random. What is the probability that at least 2 apples are picked?
A.1/2
B.1/3
C.1/4
D.2/5
Answer: B.1/3
Explanation: The total possible choices are 10C3 = 120
The ways to choose 3 apples: 4C3 = 4
The ways to choose 2 apples: 4C2 * 6C1 = 36
P(at least 2 apples) = 40/120 = 1/3
The answer is B.
Question: A polling company reports that there is a 50% chance that a certain candidate will win the next election. If the candidate wins, there is a 60% chance that she will sign Bill X and no other bills. If she decides not to sign Bill X, she will sign either Bill Y or Bill Z, chosen randomly. What is the chance that the candidate will sign Bill Z?
A.11
B.10
C.6
D.4
Answer: B.10
Explanation: 50% - Candidate Elected
100%-60% = 40% - Candidate doesnotsigh Bill X
50% - Candidate randomly chooses between two bills.
These are multiplicative:
50% x 40% x 50%
0.5 x 0.4 x 0.5 = 0.10 = 10%
Answer (B)
Question: In a park there are two ponds with both brown ducks and green ducks. In the smaller pond there are 30 ducks and in the larger pond there are 50 ducks. If 20% of the ducks in the smaller pond are green and 12% of the ducks in the larger pond are green, then what percentage of ducks are green?
A.13%
B.14%
C.15%
D.16%
Answer: C.15%
Explanation: Number of ducks in small pond = 30
green ducks in small pond = 20 % of 30 = 6 ducks
Number of ducks in large pond = 50
green ducks in large pond = 12 % of 50 = 6 ducks
Total number of ducks = 30 + 50 = 80
total number of green ducks = 6 + 6 = 12 ducks
percentage of green ducks = 12/80 * 100 = 15%
Answer: C
Question: If 6 men and 8 women can do a piece of work in 10 days while 26 men and 48 women can do the same in 2 days, the time taken by 15 men and 20 women in doing the same type of work will be?
A.5
B.4
C.6
D.7
Answer: B.4
Explanation: Let 1 man's 1 day's work = x and 1 women's 1 day's work = y.
Then, 6x + 8y = 1 and 26x + 48y = 1 .
10 2
Solving these two equations, we get : x = 1 and y = 1 .
100 200
(15 men + 20 women)'s 1 day's work = 15 + 20 = 1 .
100 200 4
15 men and 20 women can do the work in 4 days.
Hence Answer will be B
Question: X = 101102103104105106107......146147148149150 (From numbers 101-150). Find out the remainder when this number is divided by 9.
A.2
B.4
C.5
D.6
Answer: A.2
Explanation: Sol:
The divisibility rule for 9 is sum of the digits is to be divisible by 9. So
We calculate separately, sum of the digits in hundreds place, tenths place, and units place.
Sum of the digits in hundreds place: 1 x 50 = 50
Sum of the digits in tenths place : 0 x 9 + 1 x 10 + 2 x 10 + 3 x 10 + 4 x 10 + 5 x 1 = 105
Sum of the digits in units place : (1 + 2 + 3 + ...+ 9) x 5 = 225
So total = 380
So remainder = 380 / 9 = 2
Answer:A
Question: Ifaequals the sum of the even integers from 2 to 80, inclusive, andbequals the sum of the odd integers from 1 to 79, inclusive, what is the value of a - b ?
A.1
B.10
C.19
D.40
Answer: D.40
Explanation: This is a solution from Beatthegmat:
even numbers:
(80-2)/2 + 1 = 40 even integers.
(80+2)/2 = 41 is the average of the even set.
sum = avg*(#of elements) = 41*40 = 1640 = a
odd numbers:
(79-1)/2 + 1 = 40 odd integers.
(79+1)/2 = 40 is the average of the odd set.
sum = avg*(#of elements) = 40*40 = 1600 = b
a-b = 1640 - 1600 = 40. Answer : D
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
A.10 kmph
B.67 kmph
C.22 kmph
D.88 kmph
Answer: A.10 kmph
Explanation: Speed of the boat in still water
= (60+80)/2
= 70 kmph. Speed of the stream
= (80-60)/2
= 10 kmph.
Answer:A
Question: If x is an odd integer, which of the following is an odd integer?
A.2x+2
B.x^2
C.2x+4x
D.1+2x+x^2
Answer: B.x^2
Explanation: Plug in an odd integer; in this case 3
(2*3)+2 = 8 Even
3^2 = 9 Odd
(2*3)+(4*3) = 6 + 12 = 18 Even
1+(2*3)+3^2 = 1+ 6 + 9 = 16 Even
(3*3)-1 = 9 - 1 = 8 Even
Answer: B
Question: The length of a rectangular plot is 10mtr more than its width. The cost of fencing the plot along its perimeter at the rate of Rs. 6.5mtr is Rs.1170. The perimeter of the plot is?
A.126
B.156
C.180
D.321
Answer: C.180
Explanation: Sol. Let width = x, Length = (10+x)
Perimeter = 2(x+(10+x))
= 2(2x=10)
& 2(2x+10)*6.5 = 1170
X = 40
Required perimeter = 2(40+50) = 180
C
Question: The ratio of two quantities is 3 to 7. If the first quantity is increased by 6, how much should the second quantity be increased to maintain the same ratio?
A.6
B.7
C.14
D.28
Answer: C.14
Explanation: 3:7 means 3x:7x...
The ratio is maintained when each of the Xs are the same...
3(1) + 6 equals 3(3)
7(3) equals 7(1) +14
ANSWER:C
Question: A Prototype fuel-efficient car (P-Car) is estimated to get 90% more miles per gallon of gasoline
than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type
of gasoline that costs 60% more per gallon than does the gasoline used by a T-Car. If the two
cars are driven the same distance, what percent less than the money spent on gasoline for the
T-Car is the money spent on gasoline for the P-Car?
A.15.78%
B.33 1/3 %
C.50%
D.60%
Answer: A.15.78%
Explanation: Assumption
Miles/Gallon
T = 100
P = 190 ( 90% more)
$/gallon
T = 100
P = 160 (60% more)
Miles
100 for both
Cost = (Miles X $/ Gallon)/ M/gallon
T = 100
P = 84.21
Hence 100 - 84.21 =15.78%
Ans A
Question: How long does a train 110 m long running at the speed of 90 km/hr takes to cross a bridge 132 m length?
A.12.9 sec
B.9.68 sec
C.17.9 sec
D.16.8 sec
Answer: B.9.68 sec
Explanation: Speed = 90 * 5/18 = 25 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/25 = 9.68 sec.
Answer: B
Question: In a partnership, A invests 1⁄6 of the capital for 1⁄6 of the time, B invests 1⁄3 of the capital for 1⁄3 of the time and C, the rest of the capital for whole time. Find A’s share of the total profit of 2,300
A.100
B.200
C.300
D.400
Answer: A.100
Explanation: Remaining capital = 1 - (1⁄6 + 1⁄3) = 1⁄2
Ratio of their profit
= 1⁄6 × [1⁄6 × 12] : 1⁄3 × [1⁄3 × 12] : 1⁄2 × 12
= 1⁄3 : 4⁄3 : 6 = 1 : 4 : 18
∴ A's share = 1 /1+4+18×2300 = 100
Answer A
Question: Two different solutions of alcohol with respective proportions of alcohol to water of 3:1 and 2:3 were combined. What is the concentration of alcohol in the new solution if the first solution was 4 times the amount of the second solution?
A.62
B.65
C.68
D.70
Answer: C.68
Explanation: SOL:
Lets assume that 40L of sol1 was mixed with 10L of sol2.
Alcohol in Sol1: 40*3/4 = 30L
Alcohol in Sol2: 10*2/5 = 4L
Total Alcohol in the mixed solution of 50L = 30 + 4 = 34L
Alcohol concentration in the new sol: (34/50)*100 = 68%
ANSWER:C
Question: A can do a piece of work in 7 days of 9 hours each and B can do it in 6 days of 7 hours each. How long will they take to do it, working together 8 hours a day?
A.2 days
B.5 days
C.7 days
D.3 days
Answer: D.3 days
Explanation: Sol. A can complete the work in (7 x 9) = 63 hours.
B can complete the work in (6 x 7) = 42 hours.
A’s 1 hour's work = (1/63) and B's 1 hour's work =(1/42)
(A + B)'s 1 hour's work =(1/63)+(1/42)=(5/126)
Both will finish the work in (126/5) hrs.
Number of days. of (42/5) hrs each =(126 x 5)/(5 x 42)=3 days
Ans: D
Question: What distance will be covered by a bus moving at 72 kmph in 30 seconds?
A.278
B.600
C.772
D.551
Answer: B.600
Explanation: 72 kmph = 72 * 5/18 = 20 mps
D = Speed * time = 20 * 30 = 600 m.
Answer: B
Question: Two pipes A and B can separately fill a tank in 2 minutes and 15 minutes respectively. Both the pipes are opened together but 4 minutes after the start the pipe A is turned off. How much time will it take to fill the tank?
A.28
B.10
C.28
D.27
Answer: B.10
Explanation: 4/12 + x/15 = 1
x = 10
Answer:B
Question: Tom left a job paying $75,000 per year to accept a sales job paying $45,000 per year plus 15 percent commission. If each of his sales is for $750, what is the least number of sales he must make per year if he is not to lose money because of the change?
A.40
B.200
C.266
D.267
Answer: D.267
Explanation: In order not to lose money because of the change Tom's total commission must beat least$75,000-$45,000=$30,000, so total sales must beat least$30,000/0.15=$200,000. Which means that he must makeat least$200,000/750=800/3=266.6 sales, so 267 sales.
Answer: D.
Question: Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 16/36, what is the probability that the next one she draws will be pink?
A.1/49
B.4/7
C.3/7
D.1/3
Answer: D.1/3
Explanation: The probability of drawing a pink gumball both times is the same. The probability that she drew two blue gumballs = 16/36 = (2/3) * (2/3)
Therefore probability that the next one she draws is pink = 1/3
Option (D)
Question: Find the area of circle whose radius is 5m?
A.113.1
B.154
C.288
D.280
Answer: A.113.1
Explanation: 22/7 * 5 * 5
= 113.1
Answer:A
Question: SCORE INTERVAL----------------NUMBER OF SCORES
50-59-------------------------- 2
60-69--------------------------10
70-79--------------------------16
80-89--------------------------3.
90-99--------------------------8
The table above shows the distribution of test scores for a group of management trainees. Which score interval contains the median of the 39 scores?
A.22th
B.23th
C.20th( 70-79)
D.25th
Answer: D.25th
Explanation: Total scores= 2+10+16+3+8 = 39, which is odd, therefore the median is the Floor(39/2)+1 = 20 th score. And the 20th score is in the 70-79 range, because 50-69 only reference 12 scores.
D
Question: To fill a tank, 42 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifths of its present ?
A.102
B.103
C.104
D.105
Answer: D.105
Explanation: Let the capacity of 1 bucket = x.
Then, the capacity of tank = 42x.
New capacity of bucket = 2/5 x
Therefore, Required number of buckets = (42x)/(2x/5)
= (42x) x 5/2x
= 210/2
= 105
Answer is D.
Question: If s is a positive integer, and if the units' digit of s^2 is 4 and the units' digit of (s + 1)^2 is 1, what is the units' digit of (s + 2)^2 ?
A.	0
B.	2
C.	4
D.	6
Answer: A.	0
Explanation: A for me.
_1² = _1
_2² = _4
_3² = _9
_4² = _6
_5² = _5
_6² = _6
_7² = _9
_8² = _4
_9² = _1
_0² = _0
On the list, the only number that squared has the units digit = 4 preceding a number that squared has the units digit = 1 is the _8.
So, s = _8, that has square 4. The next square is 1 andnext nextsquare is 0.
Question: What is the dividend. divisor 16, the quotient is 9 and the remainder is 5?
A.A)130
B.B)134
C.C)149
D.D)158
Answer: C.C)149
Explanation: D = d * Q + R
D = 16 * 9 + 5
D = 144 + 5
D = 149
Answer C
Question: Of the science books in a certain supply room, 50 are on botany, 60 are on zoology, 90 are on physics. 50 are on geology, and 110 are on chemistry. If science books are removed randomly from the supply room, how many must be removed to ensure that 80 of the books removed are on the same science?
A.81
B.319
C.166
D.285
Answer: B.319
Explanation: First, you can take all 50 Botany books, all 60 zoology books and all 50 geology books because you're sure to never pick 80 of them.
There are still 90 on physics and 110 on chemistry
The worst case could be that we pick 79 physics and 79 chemistry. So that the next book picked will necessary complete 80 books picked, either in physics or chemistry.
Minimum number of books picked to reach 80 in the same science should be : 50 + 60 + 50 + 79 +79 + 1 = 319
B
Question: A single discount equivalent to the discount series of 12%, 10% and 5% is?
A.31.67
B.31.9
C.24.67
D.24.76
Answer: D.24.76
Explanation: 100*(88/100)*(90/100)*(95/100) = 75.24
100 - 75.24 = 24.76
Answer: D
Question: In how many different number of ways 3 boys and 2 girls can sit on a bench?
A.700
B.710
C.120
D.720
Answer: C.120
Explanation: npn = n!
5p5 = 5 Ã— 4 Ã— 3 Ã— 2 Ã— 1 = 120
C
Question: A fill pipe can fill 1/2 of cistern in 25 minutes. In how many minutes, it can fill 1/2 of the cistern?
A.10 min
B.15 min
C.20 min
D.25 min
Answer: D.25 min
Explanation: Required time = 25*2*1/2 = 25 minutes
Answer is D
Question: A photography dealer ordered 72 Model X cameras to be sold for $250 each, which represents a 20 percent markup over the dealer’s initial cost for each camera. Of the cameras ordered, 6 were never sold and were returned to the manufacturer for a refund of 50 percent of the dealer's initial cost. What was the dealer's approximate profit or loss as a percent of the dealer’s initial cost for the 72 cameras?
A.7% loss
B.13% loss
C.7% profit
D.14% profit
Answer: D.14% profit
Explanation: Total cost 72*($250/1.2)=60*250;
# of cameras sold is 72-6=66 total revenue is 66*250;
# of cameras returned is 6 total refund 6*(250/1.2)*0.5;
So, total income 66*250+ 6*(250/1.2)*0.5
The dealer's approximate profit is (66*250+ 6*(250/1.2)*0.5-60*250)/(60*250)*100=14%
Answer: D.
Question: Four bells commence tolling together and toll at intervals of 2, 4, 6, 8 seconds respectively. In 18 minutes, how many times do they toll together ?
A.43
B.44
C.45
D.46
Answer: C.45
Explanation: LCM of 2, 4, 6, 8 is 24.
So, after each 24 seconds, they would toll together.
Hence, in 18 minutes, they would toll 18*60 seconds / 24 seconds = 45 times
But then the question says they commence tolling together. So, they basically also toll at thebeginning(0second).
So, total tolls together = 45+1 = 46
Answer C
Question: 16 business executives and 7 chairmen meet at a conference. If each business executive shakes the hand of every other business executive and every chairman once, and each chairman shakes the hand of each of the business executives but not the other chairmen, how many handshakes would take place?
A.144
B.131
C.232
D.90
Answer: C.232
Explanation: there are 16 business exec and in each handshake 2 business execs are involved.
hence 16C2=120
Also, each of 16 exec will shake hand with every 7 other chairmen for total of 112 handshake.
total=120+112=232
ANS: C
Question: WHAT WILL BE THE VALUE OF
log e(e(e....)^1/2)^1/2)^1/2).....log base is e?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: e(e(e....)^1/2)^1/2)^1/2 = e ^ (1/2 + 1/4 + 1/8 +....)
it is in G.P(Geometric progression) then sum to infinite terms = (a)/(1-r)
(1/2 + 1/4 + 1/8 +....) = (1/2)/(1-1/2) = 1
so e ^ 1
log(e^1) base e = 1
ANSWER:B
Question: The average age of 40 students is 8 years. If the age of teacher is also included , then their average age increases by half a year. What is the age of the teacher?
A.45 years
B.48.5 years
C.28.5 years
D.26.5 years
Answer: C.28.5 years
Explanation: Exp. Total age of 40 students = 40*8 = 320
Let the age of the the teacher be x, Then (320+x)/41 = 8+1/2 =8 ½.
320+x =17/2*41 =697/2 = 348.5, x =348.5-320 = 28.5
Answer: C
Question: A, B and C have Rs.300 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have?
A.A)250
B.B)249
C.C)248
D.D)247
Answer: A.A)250
Explanation: A+B+C = 300
A+C = 200
B+C = 350
--------------
A+B+2C = 550
A+B+C = 300
----------------
C = 250
Answer:A
Question: Of the 200 stamps in a collection, 90 are foreign and 50 are more than 10 years old. If 20 stamps are both foreign and more than 10 years old, how many stamps are neither foreign nor more than 10 years old?
A.30
B.80
C.100
D.130
Answer: B.80
Explanation: 20 stamps are both foreign and more than 10 years old.
70 stamps are foreign only.
30 stamps are 10 years old only.
The number of remaining stamps is 200 - (20+70+30) = 80
The answer is B.
Question: If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4960 , R will receive
A.600
B.700
C.800
D.960
Answer: D.960
Explanation: Explanation :
Let P's capital = p, Q's capital = q and R's capital = r
Then
4p = 6q = 10r
=> 2p = 3q = 5r
=>q = 2p/3
r = 2p/5
P : Q : R = p : 2p/3 : 2p/5
= 15 : 10 : 6
R's share = 4960 * (6/31) = 160*6 = 960. Answer : Option D
Question: A and B can together finish a work in 10days. They worked together for 5days and then B left. After another 5days, A finished the remaining work. In how many days A alone can finish the job?
A.10
B.15
C.20
D.5
Answer: A.10
Explanation: A+B 5days work = 5*1/10 = 1/2
Remaining work = 1-1/2 = 1/2
1/2 work is done by A in 5days
whole work will be done by A in 5*2 = 10days
Answer is A
Question: Four hundred students at College Q study a foreign language. Of these, 190 of those students study French, and 260 study Spanish. If at least 105 students who study a foreign language at College Q study neither French nor Spanish, then the number of students who study Spanish but not French could be any number from
A.10 to 40
B.40 to 100
C.60 to 100
D.60 to 105
Answer: D.60 to 105
Explanation: 190 students study French
210 students do not study French
260 students study Spanish
140 students do not study Spanish
105 students study neither French nor Spanish
210-140=70
210-105=90
D. 60 to 105
Question: 40% of x is greater than 1/3rd of x by 110.what is x?
A.1100
B.2100
C.1300
D.1650
Answer: D.1650
Explanation: 4x/10-x/3=110
1x/15=110
x=1650
ANSWER:D
Question: Evaluate :log3 27
A.3
B.4
C.5
D.6
Answer: A.3
Explanation: Solution
log3 27	= n
=3n
=27
=33
n‹=›3.
Answer A
Question: The average weight of 4 person's increases by 1.5 kg when a new person comes in place of one of them weighing 95 kg. What might be the weight of the new person?
A.101 kg
B.103.4 kg
C.105 kg
D.Data inadequate
Answer: A.101 kg
Explanation: Total weight increased = (4 x 1.5) kg = 6 kg.
Weight of new person = (95 + 6) kg = 101 kg.
Answer: Option A
Question: Anne has pouches of grain that she wants to divide between the different areas of the petting zoo. Unfortunately, Anne's pouches of grain don't divide evenly. It turns out that in order for the pouches of grain to divide evenly, Anne will have to purchase two additional pouches of grain, and not visit two of the petting zoo areas. Which of the following can describe the initial number of grain pouches, and the initial number of areas in the petting zoo (in the order areas of the petting zoo; pouches of grain)?
A.20; 5.
B.16; 5.
C.12; 4
D.30; 4
Answer: B.16; 5.
Explanation: Option B) Initially 16 petting zoo areas, then decreased to 14 petting zoo areas; and Initially 5 pouches of grain, then icreased to 7 pouces of grain fits the requirement.
14 / 7 = 2 pouches of grain per petting zoo area
Question: A group of tourists wants to visit at least three of the four cities A, B, C, and D. How many travel itineraries can they make? All cities are connected to one another and please note that visiting the same cities in a different order counts as a different itinerary.
A.24
B.36
C.48
D.60
Answer: C.48
Explanation: The number of ways to choose three cities is 4C3=4.
The number of itineraries for each group of 3 cities is 3!.
So the number of itineraries to three cities is 4*3!=24.
The number of ways to choose four cities is 4C4=1.
The number of itineraries for the group of 4 cities is 4!.
So the number of itineraries to four cities is 4!=24.
The total number of itineraries is 24+24=48.
The answer is C.
Question: 2/3rd of the boys and 3/4th of the girls of a school participate in a function. If the no.of participating students is 550, out of which 150 are girls, what is the total no.of students in the school?
A.620
B.780
C.800
D.880
Answer: C.800
Explanation: Let total number of boys be x and total number of girls be y. y=400=>x = 600and^= I50=>y = 200 Now, x + y = 800
C
Question: The owner of a furniture shop charges his customer 20% more than the cost price. If a customer paid Rs. 3000 for a computer table, then what was the cost price of the computer table?
A.2500
B.2772
C.1991
D.6725
Answer: A.2500
Explanation: CP = SP * (100/(100 + profit%))
= 3000(100/120) = Rs. 2500.
Answer: A
Question: Mangoes, Oranges and Apples in a fruit shop are in the ratio of 10: 2 : 3. If there are 120 Mangoes, the number of Apples in the shop is:.
A.36
B.42
C.72
D.400
Answer: A.36
Explanation: Explanation :
Let Mangoes = 10x, Oranges = 2x & Apples = 3x. Now, 10x = 120 hence x = 12.
Number of Apples = 3x = 36.
Answer : A
Question: The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person?
A.11
B.19
C.12
D.17
Answer: C.12
Explanation: Initial average age of the 10 persons be P.
Age of the new person Q.
Sum of the ages of the initial 10 persons = 10P
New average = (P-3) 10(P-3) = 10P - 42 + Q => Q
= 12
Answer: C
Question: There are 3 classes having 20, 24 and 30 students respectively having average marks in
an examination as 20,25 and 30 respectively. The three classes are represented by A, B and C and you have the following information about the three classes.
a. In class A highest score is 22 and lowest score is 18
b. In class B highest score is 31 and lowest score is 23
c. In class C highest score is 33 and lowest score is 26.
A.can't be determined in both cases
B.definite decrease in both cases
C.definite increase in both cases
D.will remain constant in both cases
Answer: A.can't be determined in both cases
Explanation: Ans: B
Explanation:
Class A average is 20. And their range is 18 to 22
Class B average is 25. And their range is 23 to 31
Class A average is 30. And their range is 26 to 33
If 5 students transferred from A to B, A's average cannot be determined but B's average comes down as the highest score of A is less than lowest score of B.
If 5 students transferred from B to C, C's average cannot be determined the B's range fo marks and C's range of marks are overlapping.
Answer:A