RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Solve the following quadratic equation by factoring.
u2+15u=-50
A.-5,-10
B.5,10
C.4,3
D.-4,3
Answer: A.-5,-10
Explanation: u+5=0=>u=-5
u+10=0=>u=-10
ANSWER A
Question: A certain sum earns simple interest of Rs. 800 in 2 years at a certain rate of interest. If the same sum earns compound interest of Rs.900in the same period of 2 years, What must be the rate of interest?
A.25%
B.10%
C.15%
D.20%
Answer: A.25%
Explanation: Explanation:
Given: 800 = (P * R * 2) / 100
S.I. For 1 year = Rs. 400
Thus, (900 – 800) = S.I. on Rs. 400 for 1 year
100 = (400 * R * 1) / 100
R = 25% p.a.
ANSWER: A
Question: In a consumer survey, 66% of those surveyed liked at least one of three products: 1, 2, and 3. 35% of those asked liked product 1, 30% liked product 2, and 20% liked product 3. If 8% of the people in the survey liked all three of the products, what percentage of the survey participants liked more than one of the three products?
A.9
B.10
C.11
D.12
Answer: C.11
Explanation: 35 + 30 + 20 = 85
This number includes some people counted twice and some people counted three times.
85 - 66 = 19, and this number represents people counted twice or three times.
8% of the people are counted two extra times.
The percentage of people counted one extra time is 19 - 8(2) = 3.
The percentage of people who liked more than one product is 8% + 3% = 11%.
The answer is C.
Question: Which of the following is true about 0<|x|-2x<5?
A.-1<x<0
B.0<x<1
C.1<x<2
D.2<x<3
Answer: A.-1<x<0
Explanation: when can be |x|-2x be greater than 0..
NEVER when x is positive..
ONLY A is left..
you can also substitute any value within the given range to check for answer
Example - put x as -0.5 for A. -1<x<0..
so |x|-2x = |-0.5|- 2*(-0.5) = 0.5+1 = 1.5 and it satisfies 0<|x|-4x<5
A
Question: Two numbers when divided by a divisor leave remainders of 208 and 332 respectively. The remainder obtained when the sum of the numbers is divided by the same divisor is 68. Find the divisor.
A.335
B.365
C.387
D.472
Answer: D.472
Explanation: Let x be the divisor.
N1 = xa + 208
N2 = xb + 332
N1 + N2 = x(a+b) + 540 = xc + 68
x(c-a-b) = 472 but we know that x > 332, thus (c-a-b) must equal 1.
The answer is D.
Question: When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 12-inch boxes. If the university pays $0.40 for every box, and if the university needs 2.4 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes?
A.$200
B.$275
C.$510
D.$1,250
Answer: A.$200
Explanation: The volume of each box is 20*20*12 = 4800 cubic inches.
Number of boxes = 2,400,000/4800 = 500 boxes
Total cost = 500×$0.4=$200
The answer is A.
Question: A rectangular grass field is 75 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.3 per sq m?
A.1350
B.1357
C.2025
D.2052
Answer: C.2025
Explanation: Area = (l + b +2d) 2d
= (75 + 55 +2.5 * 2) 2*2.5 => 675
675 * 3 = Rs.2025
Answer:C
Question: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money J did Bob receive?
A.20
B.22
C.24
D.26
Answer: B.22
Explanation: Notice that we need not consider Ann's portion in the solution. We can just let K = the money REMAINING after Ann has received her portion and go from there.
Our equation will use the fact that, once we remove Bob's portion, we have $32 for Chloe.
So, we getK - Bob's $ = 32
Bob received 4 dollars plus one-third of what remained
Once Bob receives $4, the amount remaining is K-4 dollars. So, Bob gets a 1/3 of that as well.
1/3 of K-4 is (K-4)/3
So ALTOGETHER, Bob receives4 + (K-4)/3
So, our equation becomes:K -[4 + (K-4)/3 ]= 32
Simplify to get: K - 4 - (K-4)/3 = 32
Multiply both sides by 3 to get: 3K - 12 - K + 4 = 96
Simplify: 2K - 8 = 96
Solve: K = 52
Plug this K-value intoK - Bob's $ = 32to get: 52 - Bob's $ = 32
So, Bob's $ J= 20
Answer:
B
Question: A horse is tied to one corner of a square playground of side 20m by a rope 3.5m long. Find the area it can move in that playground?
A.9.625
B.10.5
C.11.125
D.12.5
Answer: A.9.625
Explanation: Area covered by horse = Pi*r^2/4 ( here we divide by 4 because rope is tied at the corner of the playground and only 1/4 part , the horse can move in that playground.)
where r= 3.5 m = length of rope
So area = (22/7)*3.5*3.5/4 = 9.625 sq m
answer :A
Question: By mixing two qualities of pulses in the ratio 2: 3 and selling the mixture at the rate of Rs 22 per kilogram, a shopkeeper makes a profit of 10 %. If the cost of the smaller quantity be Rs 14 per kg, the cost per kg of the larger quantity is:
A.Rs 23
B.Rs 25
C.Rs 24
D.None of these
Answer: C.Rs 24
Explanation: Explanation:
Cost Price of 5 kg = Rs.(14*2 + x*3) = (28 + 3x).
Sell price of 5 kg = Rs. (22x5) = Rs. 110.
[{110 - (28 + 3x)}/(28 + 3x) ]* 100 =10
[82-3x/28 + 3x]= 1 / 10
820 - 30x = 28 +3x
33x = 792
x = 24
Answer: C
Question: If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
A.120 cm2
B.176 cm2
C.112 cm2
D.166 cm2
Answer: A.120 cm2
Explanation: The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle
= 1/2 * 24 * 10
= 120 cm2
Answer:A
Question: A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
A.288
B.277
C.284
D.108
Answer: D.108
Explanation: The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12
= 108 ways.
Answer: D
Question: In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?
A.2.5 sec
B.2.8 sec
C.8.5 sec
D.2.7 sec
Answer: A.2.5 sec
Explanation: Speed = 144 * 5/18 = 40 m/sec
Time taken = 100/40 = 2.5 sec.
Answer:A
Question: If the average of 365, 409, 187, 420, 451, and x is 314, then what is x?
A.190
B.52
C.232
D.114
Answer: B.52
Explanation: x = 52 because:
(365+409+187+420+451+x)/6=314
(365+409+187+420+451+x)/6*6=314*6
(365+409+187+420+451+x)=1884
(365+409+187+420+451+x)-1832=1884-1832
x=52
Therefore, the answer is B, 52.
Question: The duplicate ratio of 3:4 is?
A.9:19
B.9:11
C.9:16
D.9:109
Answer: C.9:16
Explanation: 32: 42 = 9:16
Answer: C
Question: What is the least possible product of 4 different integers, each of which has a value between –3 and 10, inclusive?
A.–5040
B.–3600
C.–2160
D.–600
Answer: C.–2160
Explanation: Maximize the total product with a -ve sign
so -3 * 10 * 9 * 8 = 720 * -3 = -2160
Answer is C.
Question: P is a prime number. If 6p is between 15 and 95, which of the following can be a value of 7p + 2?
A.15
B.79
C.121
D.65
Answer: D.65
Explanation: We see that the format we are looking for is 7p + 2.
When you subtract 2 from option A, you get 13 - not a multiple of 7. Ignore.
When you subtract 2 from option B, you get 77. It is a multiple of 7. Let's check it. p = 11 which is prime. Good. 6p = 66 which is between 15 and 95. Very good.
ANSWER:D
Question: Shekhar started a business investing Rs.25,000 in 1999.In 2000,he invested an additional amount of Rs.10,000 and Rajeev joined him with an amount of Rs.35,000.In 2001,Shekhar invested another additional amount of Rs.10,000 and Jatin joined them with an amount of Rs.35,000.What will be Rajeev’s share in the profit of Rs.2,70,000 earned at the end of 3 years from the start of the business in 1999 ?
A.Rs.45,000
B.Rs.50,000
C.Rs.90,000
D.Rs.75,000
Answer: C.Rs.90,000
Explanation: Solution
Shekhar : Rajeev : Jatin
= (25000x12+35000x12+45000x12) :(35000x24) : (35000x12)
= 1260000 : 840000 : 420000 = 3 : 2 : 1.
∴ Rajeev’s share = Rs.(27000x2/6) = Rs. 90,000. Answer C
Question: Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 15% profit?
A.14.49
B.16.33
C.16.35
D.16.3
Answer: A.14.49
Explanation: C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630.
S.P. of 50 kg wheat = 115% of Rs. 630 = 115/100 * 630 = Rs. 724.5
S.P. per kg = 724.5/50 = 14.49
A
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
A.3/9
B.3/2
C.3/1
D.3/7
Answer: B.3/2
Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train
= 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23
==> 27 x + 17 y = 23 x + 23 y ==> 4 x
= 6 y ==> x/y = 3/2.
Answer:B
Question: (5)1.25 × (12)0.25 × (60)0.75 = ?
A.420
B.260
C.200
D.300
Answer: D.300
Explanation: Explanation :
(5)1.25 × (12)0.25 × (60)0.75
=(5)1.25 × (12)0.25 × (12 × 5)0.75
= (5)1.25 × (12)0.25 × (12)0.75 × (5)0.75
= (5)(1.25 + 0.75) × (12)(0.25 + 0.75)
= (5)2 × (12)1
= 25 × 12
= 300
Answer : Option D
Question: The probability of picking 2 red balls one after another without replacement from a bag containing only red and white balls is 14/33. What will be the probability of picking 2 white balls one after another w/o replacement from that bag, given that it can hold at the most 20 balls?
A.1/33
B.3/33
C.5/33
D.9/33
Answer: B.3/33
Explanation: Probability of picking 2 red balls = 14/33
(R/R+W)*(R-1)/(R+W-1) = 14/33 = (2*7)/(3*11) = (2/3)*(7/11) --> Once the value is reduced to this level, it should be easy to find out the number of red balls.
1) Considering the above expression, both numerator and denominator must be consecutive.
2) Lets multiply both numerator and denominator with the same integer so that the value remains unaffected.
3) We can't multiply 7/11 as we need a consecutive term in both numerator and denominator. So lets multiply (2/3) to make the numerator and denominator consecutive.
(2/3)*(2/2) = 4/6 --> 4*7/6*11 --> Numerator and denominator not consecutive
(2/3)*(3/3) = 6/9 --> 6*7/9*11 --> Only numerator is consecutive
(2/3)*(4/4) = 8/12 --> 8*7/12*11 --> Numerator and denominator are consecutive here
Number of red balls, R = 8.
Total number of balls, R + W = 12 (This value is < 20, satisfying the condition)
Number of white balls, W = 12 - 8 = 4
Probability of picking 2 white balls w/o replacement = (W/R+W)*(W-1)/(R+W-1) = (4/12)*(3/11) = 3/33
Answer: B
Question: Find the rank of the word GOOGLE if all the words which can be formed by permuting letters of this word without repitition are arranged in dictionary in alphabetical order???
A.86
B.67
C.88
D.89
Answer: C.88
Explanation: EGGLOO arranging in alphabetiaccal order
E - - - - - 5!/(2!*2!)=30
GE- - - - 4!/2!=12 30+12=42
GG- - - - 4!/2!=12 42+12=54
GL- - - - 4!/2!=12 54+12=66
GOE - - - 3!=6 66+6=72
GOG- - - 3!=6 72+6=78
GOL- - - 3!=6 78+6=84
GOOE- - 2!=2 84+2=86
GOOGE - 1!=1 86+1=87
GOOGLE 1!=1 87+1=88
So, 88 th no, is GOOGLE
ANSWER:C
Question: The surface of a cube is 54sq cm. Find its volume?
A.8cc
B.27cc
C.2cc
D.4cc
Answer: B.27cc
Explanation: 6a2 = 54 = 6*9
a = 3 => a3 = 27cc
Answer: B
Question: A firm has 3 senior partners and 5 junior partners. How many different groups of 3 partners can be formed in which at least one member of the group is a senior partner? (Note that two groups are considered different if at least one group member is different.)
A.42
B.46
C.50
D.54
Answer: B.46
Explanation: The number of ways to form a group of 3 is 8C3 = 56
The number of groups with no senior partner is 5C3 = 10
The number of groups with at least one senior partner is 56-10 = 46
The answer is B.
Question: Fresh grapes contain 75% by weight while dried grapes contain 25% water by weight. What is the weight of dry grapes available from 200 kg of fresh grapes?
A.40.00 kg
B.45.50 kg
C.66.67 kg
D.80.56 kg
Answer: C.66.67 kg
Explanation: From the question we know: 200kg * 75% = 150kg of water in the fresh grapes
200kg - 150kg of water = 50kg of non-water mass
We are looking for the weight of the dry grapes (X).
Since the question tells us that 25% of the weight of the dry graps is water and we know that 50kg is non-water mass we can set up the following equation:
X = 1/4(X) + 50kg
3/4(X) = 50kg
X = 66.67 kg
Answer- C
Question: A woman has five blouses of different colors, three skirts of different colors, and two different pairs of shoes. She refuses to wear her pink blouse with her green skirt. How many different blouseskirt-shoe combinations could she wear?
A.8
B.12
C.28
D.17
Answer: C.28
Explanation: total ways = 5*3*2=30..
now its better to find the ways in which the pink blouse and green skirt are together and subtract from total to get the answer..
the ways in which the pink blouse and green skirt are together=1*1*2=2..
total ways =30-2=28..
ANSWER:C
Question: The value of 0.1 x 0.1 x 0.1 + 0.02 x 0.02 x 0.02/ 0.2 x 0.2 x 0.2 + 0.04 x 0.04 x 0.04	is:
A.0.125
B.0.135
C.0.145
D.0.155
Answer: A.0.125
Explanation: Given expression
=(0.1)(power 3) + (0.02)(power 3) /2(power 3) [(0.1)(power 3) + (0.02)(power 3)]
=1/8
= 0.125
Answer is A
Question: A man standing at a point P is watching the top of a tower, which makes an angle of elevation of 30° with the man’s eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes 60°. What is the distance between the base of the tower and the point P?
A.4 units
B.8 units
C.12 units
D.Data inadequate
Answer: D.Data inadequate
Explanation: Explanation:
One of AB, AD and CD must have been given.So, the data is inadequate.
Answer: D
Question: The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 10 terms of the arithmetic progression?
A.300
B.100
C.150
D.170
Answer: B.100
Explanation: n th term of A.P. is given by a+(n-1)d
4 th term = a+3d
12 th term = a+11d
Given a+3d+a+11d=20 --> 2a+14d=20 --> a+7d = 10
Sum of n term of A.P = n/2[2a+(n-1)d]
subsitiuing n = 10 ...we get 10/2[ 2a + 14d] = 10 [a+7d] = 10*10 = 100...
Answer is B...
Question: In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, the divident is
A.4236
B.4306
C.4336
D.5336
Answer: D.5336
Explanation: Solution
Divisor	= (5×46)
= 230.
Also. 10×Q	= 230
‹=› Q=23.
And, R= 46.
Dividend	= (230×23+46)
= 5336.
Answer D
Question: A line that passes through (–1, –4) and (3, k) has a slope = k. What is the value of k?
A.3/4
B.1
C.4/3
D.2
Answer: C.4/3
Explanation: This is a considerably more difficult one, which will involve some algebra. Let’s say that the “first” point is (–1, –4) and the “second,” (3, k). The rise = k + 4, which involves a variable. The run = 3 – (–1) = 4. There the slope is (k + 4)/4, and we can set this equal to k and solve for k.
{{k + 4}/4} = k
k + 4 = 4k
4 = 3k
k = 4/3
Answer = C
Question: If the function f(x) is defined for all real numbers x as the maximum value of 4x + 4 and 12 + 3x, then for which one of the following values of x will f(x) actually equal 4x + 4 ?
A.4
B.5
C.6
D.7
Answer: D.7
Explanation: Since f(x) defines maximum of 4x + 4 and 12 + 3x,
to find those x when 4x+4 has greater value,
4x + 4 > 12 + 3x
or x < 8
Only value that satisfy this is 7.
Answer is (D),
Question: A train 250 m long is running at a speed of 58 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?
A.5 sec
B.9 sec
C.12 sec
D.18 sec
Answer: D.18 sec
Explanation: Answer : D.
Speed of the train relative to man = (58 - 8) kmph
= (50* 5/18) m/sec = (125/9)m/sec
Time taken by the train to cross the man
= Time taken by It to cover 250 m at 125/9 m / sec = 250 *9/ 125 sec = 18sec
Question: A is a working and B is sleeping partners in a business. A puts in Rs. 5000 and B puts in Rs.6000. A receives % of the profit for managing the business and the rest is divided in proportion to their capital. What does each get out of a profit of Rs. 880?
A.770
B.266
C.297
D.260
Answer: A.770
Explanation: Total profit = Rs. 880
A's share for managing the business i.e
\inline 12\frac{1}{2} % = \inline \frac{25\times 880}{200}=Rs.110
Remaining profit of A and B as per their capital = 880 - 110 = Rs. 770
Ratio of amounts = 5000 : 6000 = 5 : 6
Sum of ratios = 5 + 6 = 11
A's share = \inline 770\times \frac{5}{11}= Rs.350
A's total share = 350 + 110 = Rs. 460
B's share = \inline 770\times \frac{6}{11}=Rs.420
Answer:A
Question: Ten cards numbered 1 to 10 are placed in a box, mixed up thoroughly and then one card is drawn
randomly. If it is known that the number on the drawn card is more than 3, what is the probability
that it is an even number?
A.1/3
B.1/5
C.4/7
D.3/5
Answer: C.4/7
Explanation: Let A be the event ‘the number on the card drawn is even’ and B be the
event ‘the number on the card drawn is greater than 3’. We have to find P(A|B).
Now, the sample space of the experiment is S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Then A = {2, 4, 6, 8, 10}, B = {4, 5, 6, 7, 8, 9, 10}
and A n B = {4, 6, 8, 10}
Also P(A) = 5/2, P(B) = 7/10 and P(A n B) = 4/10
Then P(A|B) = P(A n B)/P(B) = (4/10)/(7/10)	= 4/7
C)
Question: A contract is to be completed in 56 days if 104 persons work, each working at 8 hours a day. After 30 days, 2/5 of the work is completed. How many additional persons should be deployed so that the work will be completed in the scheduled time, each person’s now working 9 hours a day.
A.160
B.150
C.24
D.56
Answer: D.56
Explanation: Explanation:
Persons worked = 104
Number of hours each person worked per day = 8
Number of days they worked = 30
Work completed =25
Remaining days = 56 - 30 = 26
Remaining Work to be completed =1−2/5=3/5
Let the total number of persons who do the remaining work =x
Number of hours each person needs to be work per day = 9
More days, less persons (indirect proportion)
More hours, less persons (indirect proportion)
More work, more persons (direct proportion)
Hence we can write as
(days)30:26
(hours)8:9
(work)35:25 }::x:104
⇒30×8×35×104 =26×9×2/5 × x
⇒x=30×8×3/5×104/26×9×2/5
=30×8×3×104/26×9×2
=30×8×104/26×3×2
=30×8×4/3×2
=5×8×4=160
Number of additional persons required = 160 - 104 = 56
Answer: Option D
Question: A Ball is dropped from 8 m height.it rebounds to half the height when it hits the ground. What is the distance travelled by the ball before it hits the ground?
A.20m
B.21m
C.22m
D.24m
Answer: D.24m
Explanation: distance travelled by the ball before coming to rest = 8+4+4+2+2+1+1+(1/2)+(1/2)+(1/4)+(1/4)+...upto infinity
=8+2*[4+2+1+(1/2)+(1/4)+...]
=8+2*[4/(1-1/2)]
=8+2*8
=24 m
ANSWER:D
Question: If at least 150 dollar is to be divided equally among 12 beneficiaries, how much more the donor needs to add to his dollar balance in order to meet the equal distribution criteria.
A.5
B.6
C.7
D.8
Answer: B.6
Explanation: The donor when left with 150 dollar can either distribute either 12 dollar (12x12=144) or 13 dollar (13x12=156) meeting criteria of equal distribution. As the donor has to distribute at least 150 dollar, he or she needs to add 6 dollar more to the balance. Answer: B
Question: A car started running at a speed of 30 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey.
A.390 km
B.340 km
C.380 km
D.360 km
Answer: A.390 km
Explanation: A
390 km
The total distance covered by the car in the first 10 hours = 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44 + 46 + 48 = sum of 10 terms in AP whose first term is 30 and last term is 48 = 10/2 [30 + 48] = 390 km
Question: A basket has 5 apples and 4 oranges. Three fruits are picked at random. The probability that at least 2 apples are picked is?
A.25/42
B.25/47
C.25/17
D.25/19
Answer: A.25/42
Explanation: Total fruits = 9
Since there must be at least two apples,
(⁵C₂ * ⁴C₁)/⁹C₃ + ⁵C₃/⁹C₃
= 25/42.
Answer: A
Question: If two projectiles are launched at the same moment from 1386 km apart and travel directly towards each other at 445 km per hour and 545 km per hour respectively, how many minutes will it take for them to meet?
A.80
B.82
C.84
D.86
Answer: C.84
Explanation: The projectiles travel a total of 990 km per hour.
The time to meet is 1386/990=1.4 hours = 84 minutes
The answer is C.
Question: Two trains are running at 40km/hr and 20km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
A. 23 m
B. 23 2/9 m
C. 27 7/9 m
D. 29 m
Answer: C. 27 7/9 m
Explanation: SOLUTION:
Relative speed =(40-20)km/hr=(20*5/18)m/sec=(50/9)m/sec.
Therefore length of faster train = ((50/9)*5)m=250/9 m = 27 7/9 m.
Answer: C
Question: Ravi and sunil are partners in a business. Ravi invests Rs.9,000 for 8 months and Sunil invested Rs.12000 for 9 months then after one year ratio of their profits will be
A.1:3
B.2:3
C.3:2
D.3:1
Answer: B.2:3
Explanation: =(9000*8):(15000*8)
=72000:108000
=2:3
ANSWER:B
Question: Rs. 120 are divided among A, B, C such that A's share is Rs. 20 more than B's and Rs. 20 less than C's. What is B's share
A.Rs 10
B.Rs 20
C.Rs 24
D.Rs 28
Answer: B.Rs 20
Explanation: Explanation:
Let C = x. Then A = (x—20) and B = (x—40).
x + x - 20 + x - 40 = 120 Or x=60.
A:B:C = 40:20:60 = 2:1 :3.
B's share = Rs. 120*(1/6) = Rs. 20
Option B
Question: You are having 31kg of rice. You are provided with a 1kg stone for weighing. In how many weights the 31kg of rice can be weighed. ?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: in 1st weight 1kg stone and 1 kg rice.. rice weighed = 1kg.
2nd weighing 2kg of (stone +rice) and 2 kg of rice.. rice weighed = 3kg.
3rd weighing 4kg of (stone +rice) and 4 kg of rice.. rice weighed = 7kg.
4th weighing 8kg of (stone +rice) and 8 kg of rice.. rice weighed = 15kg.
5th weighing 16kg of (stone +rice) and 16 kg of rice.. rice weighed = 31kg.
Therefore 5 weights
ANSWER:C
Question: Find the wrong number below mentioned series
7,30,80,250,550
A.7
B.30
C.80
D.250
Answer: A.7
Explanation: 7 is the only prime number or odd number in the series.
ANSWER:A
Question: If the equation x^2−x=k has at least one solution, which of the following must be true?
A.k ≥-1/4
B.k < −9
C.k = 9
D.k ≤ 9
Answer: A.k ≥-1/4
Explanation: x^2−x=k
=> x^2−x - k = 0
For a quadratic equation to have at least one solution, its discriminant (b^2-4ac) should be non-negative.
b^2-4ac ≥0
=> 1- 4*1*(-k) ≥0
=>1 + 4k ≥0
=> k ≥ -14
Answer A
Question: The product of all the prime numbers less than 14 is closest to which of the following powers of 10 ?
A.10^5
B.10^8
C.10^7
D.10^6
Answer: A.10^5
Explanation: Product of Prime numbers less than 14 is 2*3*5*7*11*13
2*5=10 .
10*11*3*7*13 = 10*10*3*10*10 (approximately) ~ Product will be >10^4 <10^6 i.e. 10^5
A is the answer
Question: In a box of 9 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective?
A.5/12
B.1/15
C.2/13
D.2/15
Answer: A.5/12
Explanation: First, there are 7C3 ways you can select 3 good pencils from 4 good ones.
Second, there are 9C3 ways you select 3 pencils from 6 ones in the box.
Then, the probability that neither pen will be defective is: 7C3/9C3=35/84 = 5/12
Answer is A
Question: 12,31,68,129,220,?
A.129
B.220
C.387
D.347
Answer: D.347
Explanation: 2*2*2 + 4 = 12
3*3*3 +4 = 31
4*4*4 + 4 = 68
5*5*5 + 4 = 129
6*6*6 + 4 = 220
7 *7 *7 + 4 = 347
ANSWER : D
Question: The fourth proportional to 5, 8, 15 is:
A.18
B.24
C.19
D.20
Answer: B.24
Explanation: Let the fourth proportional to 5, 8, 15 be x.
Then, 5 : 8 : 15 : x
5x = (8 x 15)
x =	(8 x 15)/5
x=120/5 =24
Answer: Option B
Question: Given the equation a^2 +a^(-3)=4.125, which of the following options is the correct value of a?
A.2
B.1
C.0
D.3
Answer: A.2
Explanation: Plugging in the various option into the equation to find out which is correct:
a^2 +a^(-3)= 4.125
2^2 +2^(-3) = 4.125 Ans. A
Question: A train 500 m long can cross an electric pole in 20 sec and then find the speed of the train?
A.90
B.67
C.28
D.26
Answer: A.90
Explanation: Length = Speed * time
Speed = L/T
S = 500/20
S = 25 M/Sec
Speed= 25*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 90 Kmph
Answer:A