RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides?
A.3
B.7
C.8
D.6
Answer: A.3
Explanation: S = (1 + 2 + 3)/2
= 3
Answer:A
Question: The sum of the two numbers is 16 and their product is 35. What is the sum of the reciprocals of these numbers?
A.16/35
B.1/35
C.35/8
D.7/32
Answer: A.16/35
Explanation: Let the numbers be a and b. Then, a+b=16 and ab =35.
a+b/ab=16/35; (1/b+1/a)=16/35
Sum of reciprocals of given numbers=16/35.
Correct Option: A
Question: Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is?
A.33
B.76
C.85
D.22
Answer: C.85
Explanation: Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F of 551 and 1073 = 29;
First number = 551/29 = 19
Third number = 1073/29 = 37.
Required sum = 19 + 29 + 37 = 85.
Answer:C
Question: In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 110?
A.35
B.77
C.25
D.18
Answer: A.35
Explanation: A scores 60 while B score 40 and C scores 30.
The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.
In a game of 100 points, B gives (110 - 75) = 35 points to C.
Answer:A
Question: If the price of 23 balls is 276, then what will the price of 12 balls?
A.144
B.148
C.156
D.186
Answer: A.144
Explanation: Explanation :
Less balls, Less Price (Direct Proportion)
So, let the price be Rs. x
then,
23:12::276:x
=>x=276*12/23
=>x=144
So price of 12 balls will be Rs. 144
Answer : A
Question: As a treat for her two children, a mother runs to the freezer in which she has three cherry ice pops, three orange ice pops, and four lemon ice pops. She chooses two at random to bring outside to the children, but realizes as she runs out the door that she cannot bring them different flavors without one being jealous of the other and getting even more upset. What is the probability that she has to return to the freezer to make sure that they each receive the same flavor?
A.2/5
B.3/7
C.7/12
D.11/15
Answer: D.11/15
Explanation: P(2 cherry) = 3/10 * 2/9 = 6/90
P(2 orange) = 3/10 * 2/9 = 6/90
P(2 lemon) = 4/10 * 3/9 = 12/90
P(2 of the same flavor) = 24/90
P(2 different flavors) = 1 - 24/90 = 66/90 = 11/15
The answer is D.
Question: which one is odd?
4377
3954
9862
8454
9831
A.4377
B.3954
C.9862
D.8454
Answer: C.9862
Explanation: Correct Answer : C
sum of digit of all other number is 21, but sum of digit of 9862 is 25
Question: In a box of 8 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective?
A.1/12
B.5/14
C.2/13
D.2/15
Answer: B.5/14
Explanation: First, there are 6C3 ways you can select 3 good pencils from 4 good ones.
Second, there are 8C3 ways you select 3 pencils from 6 ones in the box.
Then, the probability that neither pen will be defective is: 6C3/8C3=20/56 = 5/14
Answer is B
Question: There are 408 boys and 192 girls in a school which are to be divided into equal sections of either boys or girls alone. Find the total number of sections thus formed.
A.25
B.32
C.35
D.30
Answer: A.25
Explanation: Explanation:
HCF (408, 192) = 24
The number of boys or girls that can be placed in a section = 24.
Thus the total number of sections is given by
408/24+192/24 =17+8 = 25
Answer: A
Question: A tourist purchased a total of $1,400 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
A.$1,430
B.$1,310
C.$1,290
D.$1,170
Answer: D.$1,170
Explanation: since total cashed checks = 7 ans $10 check cashed = one less or more than $50 checks
Therefore either $10 checks = 3 and $50 checks = 4 OR $10 checks = 4 and $50 checks = 3
using this information 1st option gives us the maximum cashed value therefore if we negate this value from total value we will get minimum value of which checks have lost
Therfore 1400 - 230 = 1170 hence answer is D
Question: A recipe requires 2 1/2 (mixed number) cups of flour 2 3/4 (mixed number) cups of sugar and 1 1/3 (mixed number) cups of milk to make one cake. Victor has 15 cups if flour, 16 cups of sugar and 8 cups of milk. What is the greatest number of cakes William can make using this recipe?
A.5
B.6
C.7
D.8
Answer: A.5
Explanation: Less work up front: Go through each item and see what the greatest number of cakes you can make with each. The lowest of these will be the right answer.
Flour: 15 cups, we need 2.5 cups each. Just keep going up the line to see how many cakes we can make: That means I can make 2 cakes with 5 cups, so 6 cakes overall with 15 cups. I've already got the answer narrowed to either A or B.
Sugar: 16 cups, we need 2.75 cups each. Same principle. I can make 2 cups with 5.5 cups, so to make 6 cakes I'd need 16.5 cups. I don't have that much sugar, so we're limited to 5 cakes. No need to even do milk because we're already at 5. Sugar will be the limiting factor.
answer is A
Question: In an intercollegiate competition that lasted for 3 days, 150 students took part on day 1, 110 on day 2 and 140 on day 3. If 75 took part on day 1 and day 2 and 25 took part on day 2 and day 3 and 15 took part on all three days, how many students took part only on day 2?
A.50
B.35
C.45
D.25
Answer: D.25
Explanation: Day 1&2 = 75; Only Day 1&2 (75 -15) = 60,
Day 2&3 = 25; Only Day 2&3 (25 -15) = 10,
Only Day 2 = 110 - (60+10+15) = 25
Answer:D
Question: From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first is a red card and the second is a king is?
A.1/26
B.1/27
C.1/87
D.1/67
Answer: A.1/26
Explanation: Let E1 be the event of drawing a red card.
Let E2 be the event of drawing a king .
P(E1 ∩ E2) = P(E1) . P(E2)
(As E1 and E2 are independent)
= 1/2 * 1/13 = 1/26
Answer:A
Question: The Average of six numbers is 8. The average of the first two is 11 and the average of the last three is 4. What is the middle number?
A.A)15
B.B)8
C.C)6
D.D)14
Answer: D.D)14
Explanation: The total of six numbers = 6X8 = 48
The total of first 2 and last 3 numbers is = 2 X 11+3 X 4 = 34
So, the middle number is (48 - 34 ) = 14
D
Question: If 5^23 * 4^12 = 2 * 10^n, what is the value of n?
A.11
B.21
C.22
D.23
Answer: D.23
Explanation: My attempt:
5^(23) * 4^(12) = 2*10^p
5^(23) * 2 ^ (24) = 2 * (2*5)^p
5^(23) * 2 ^ (24) = 2 * 2^(p) * 5^(p)
5^(23) * 2 ^ (24) = 2^(p+1) * 5^(p)
=> (p+1) = 24
=> p = 23
Answer: 23 (D)
Question: Ravi purchased a refrigerator and a mobile phone for Rs. 15000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 5 percent and the mobile phone at a profit of 10 percent. Overall he make a.
A.50
B.288
C.27
D.200
Answer: A.50
Explanation: Let the SP of the refrigerator and the mobile phone be Rs. r and Rs. m respectively.
r = 15000(1 - 5/100) = 15000 - 750
m = 8000(1 + 10/100) = 8000 + 800
Total SP - Total CP = r + m - (15000 + 8000) = -750 + 800 = Rs. 50
As this is positive, an overall profit of Rs. 50 was made.Answer:A
Question: A began business with 45,000 and was later joined by B with 54,000. When did B join if the profit at the end of the year were divided in the ratio 2 : 1?
A.5 months after
B.10 months after
C.7 months after
D.12 months after
Answer: C.7 months after
Explanation: Let B join after ‘x’ month of the start of the business.
⇒ (45,000 × 12) : 54,000 × (12 – x) = 2 : 1
∴ (45,000 × 12) × 1 = 54,000 × (12 – x) × 2
⇒ x = 7
Answer C
Question: A military commander has to choose 6 soldiers out of a company of 9 for guarding the headquarters. How many different group combinations of 6 does he have to choose from?
A.84
B.15
C.16
D.27
Answer: A.84
Explanation: A military commander has to choose 6 soldiers out of a company of 9.
different group combinations of 6
He can do this in 9C6 ways
9*8*7*6*5*4/6*5*4*3*2*1= 84 ways
ANSWER:A
Question: Of all the students in a certain dormitory, 1/2 are first-year students and the rest are second-year students. If 4/5 of the first-year students have not declared a major and if the fraction of second-year students who have declared a major is 1/3 times the fraction of first-year students who have declared a major, what fraction of all the students in the dormitory are second-year students who have not declared a major?
A.7/15
B.1/5
C.4/15
D.1/3
Answer: A.7/15
Explanation: tot students=x
1st year student=x/2----> non majaor=4/5(x/2)-----> maj=1/5(x/2)
2nd year student=x/2---->maj=1/3(1/5(x/2))=1/30(x)--->non major=x/2-1/30(x)=7/15(x)
hence 7/15
A
Question: 45 workers work 8 hours to dig a hole 30 meters deep. How many extra workers should be hired to dig another hole 55 meters deep by working for 6 hours?
A.50
B.55
C.60
D.65
Answer: D.65
Explanation: 45 workers * 8 hours / 30 meters = x * 6 / 55
x = 110 total workers
110 - 45 = 65 new workers
The answer is D.
Question: The product of all the prime numbers less than 22 is closest to which of the following powers of 10?
A.a) 10^9
B.b) 10^7
C.c) 10^8
D.d) 10^6
Answer: B.b) 10^7
Explanation: Group these numbers so as to get product close to a multiple of 10, so they can be rewritten as (2*5)(3*7)(11*19)(13*17) or 10*21*209*221
Now take out power of 10 from each number and rewrite
10*10*100*100*(1*2.1*2.09*2.21) or 10^6*(1*2.1*2.09*2.21)
=9.69*10^6=10^7
B
Question: If r = ||s – 3| – 2|, for how many values of s is r = 7?
A.4
B.5
C.2
D.1
Answer: C.2
Explanation: r = ||s – 3| – 2| can be 4 only and only when s-3= +/-9. so there are 2 values of s
Answer : C
Question: What is the place value of 1 in the numeral 1259
A.A)1000
B.B)2800
C.C)2900
D.D)2980
Answer: A.A)1000
Explanation: 1 * 1000 = 1000
A
Question: A grocer buys apples for 81¢ per pound. If 10% of the apples goes bad and he still wants to make a 20% profit over his purchase price, what should be the sales price?
A.100¢
B.108¢
C.110¢
D.95¢
Answer: B.108¢
Explanation: for making calculation simple let us consider he buys 10pounds @ 81/pound=810¢ in total .
10% apples lost...means 9 pounds left.
further he wants 20% profit on 810 ¢
means he wants to earn 972¢
sales price should be 972/9=¢ 108
Ans B
Question: Ram professes to sell his goods at the cost price but he made use of 975 grms instead of a kg, what is the gain percent?
A.3 22/39%
B.4 22/39%
C.2 22/39%
D.7 22/39%
Answer: C.2 22/39%
Explanation: 975 --- 25
25 --- ? =>
25/975 *100
= 2 22/39%
Answer: C
Question: If the probability that Stock A will increase in value during the next month is 0.54, and the probability that Stock B will increase in value during the next month is 0.68. What is the greatest value for the probability that neither of these two events will occur?
A.
B.
C.
D.
E.
A.0.22
B.0.32
C.0.37
D.0.46
Answer: B.0.32
Explanation: This would be a different question if we knew the probabilities were independent --- that is, any increase in Stock A would tell you nothing about whether or not Stock B increased, and vice versa. If the question guaranteed that, then probability P(not A *and* not B) = P(not A)*P(not B) = (1 - 0.54)*(1 - 0.68) = (0.46)*(0.32) = 0.1472 We can't do that here, because the question does not specify that A and B are independent, but I share that because that's also a common type of question on the GMAT.
The best way to think about this particular question is this. Visualize a big circle: that's the space of everything that could happen with these two stocks next year, what statisticians call the "sample space." That represents 100%. The "B space", the area of that space where Stock B increases is 68% of that space, so only 32% is outside the "B space". We don't know the relationship of Stock A & Stock B, but we'd like to know where to put Stock A on the diagram to maximize the area that's outside of both the "A space" and the "B space." Well, with just the "B space" in the big circle, already 68% is taken up, and only 32% is free. If any of the "A space" is outside of the "B space", then it will eat up some of that free 32%. The only way to maximize that free space, to keep all 32% free, would be to put the entirety of "A space" inside "B space", that is, overlapping with "B space." That would be the real world situation in which Stock A rises *only if* Stock B rises: Stock B could go up without Stock A going up, but the the only way that Stock A can go up is if Stock B goes up too. That configuration would leave the maximum amount, 32%, in the region that overlaps with neither "A space" or "B space". Thus, the greatest value for the probability that neither of these two events will occur is 32%, or 0.32. Answer choice = B.
Question: A tradesman fixed his selling price of goods at 30% above the cost price. He sells half the stock at this price, one-quarter of his stock at a discount of 15% on the original selling price and rest at a discount of 30% on the original selling price. Find the gain percentage altogether?
A.14.875%
B.15.375%
C.15.575%
D.16.375%
Answer: B.15.375%
Explanation: Solution: Let CP = 100; then, marked price=130;
Now,
revenue = [(1/2)*130+(1/4)*0.85*130+(1/4)*0.7*130]
= 65+27.65+22.5 = 115.4;
% profit = 15.4*100/100 = 15.4%.
Answer: Option B
Question: An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
A.18 2/3%
B.16 7/3%
C.16 2/8%
D.16 2/3%
Answer: D.16 2/3%
Explanation: 600 ---- 100
100 ---- ? => 16 2/3%
Answer:D
Question: 5 liters of a 20 percent solution of alcohol in water are mixed with 3 liters of a 12 percent alcohol in water solution. What is the percentage of alcohol in the new solution?
A.16.7%
B.17.0%
C.17.3%
D.17.6%
Answer: B.17.0%
Explanation: The total amount of alcohol is 0.2(5) + 0.12(3) = 1.36 liters.
The percentage is 1.36 / 8 = 136 / 800 = 17 / 100 which is 17%
The answer is B.
Question: The length, breadth and height of a room are in the ratio 12 : 4 : 4. If the breadth and height are halved while the length is doubled, then the total area of the four walls of the room will
A.(a) remain the same
B.(b) decrease by 13.64%
C.(c) decrease by 15%
D.(d) decrease by 18.75%
Answer: D.(d) decrease by 18.75%
Explanation: Length (L) = 12
Breadth (B) = 4
Height (H) = 4
Total Area of Walls = 2(BH + LH) = 2*(4*4 + 12*4) = 2*(16+48) = 128
Then, Finally
Length (L) = 2*12 = 24
Breadth (B) = 4/2 = 2
Height (H) = 4/2 = 2
Total Area of Walls = 2(BH + LH) = 2*(2*2 + 24*2) = 2*(4+48) = 104
% change in Area of four walls = (Final Area-Initial Area)*100 /Initial Area
i.e. % change in Area of four walls = (104-128)*100 /128=- 18.75% (Decrease)
Answer: Option D
Question: A certain number of men complete a piece of work in 60 days. If there were 8 men more, the work could be finished in 10 days less. How many men were originally there?
A.30
B.32
C.36
D.40
Answer: D.40
Explanation: Originally 1et there be x men.
More men, Less days
(x + 8) : x ∷ 60:50
So, x + 8 / x = 60/50 or x = 40.
ANSWER:D
Question: How many 2's are there between the terms 112 to 375?
A.A)156
B.B)157
C.C)158
D.D)159
Answer: A.A)156
Explanation: Let us calculate total 2's in the units place. (122, 132, 142 ... 192), (201, 212, 222, ... 292), (302, 312, ... 372) = 8 + 10 + 8 = 26
Total 2's in tenth's place, (120, 121, 122, ..., 129) + (220, 221, ..., 229) + (320, 321, ..., 329) = 30
Total 2's in hundred's place = (200, 201, ... 299) = 100.
Total 2's between 112 and 375 = 26 + 30 + 100 = 156
Answer:A
Question: What is greatest positive integer n such that 2^n is a factor of 12^11?
A.a)10
B.b)12
C.c)22
D.d)20
Answer: C.c)22
Explanation: The given number is 12^11
=(2*2*3)^11
=(2^22)*(3^11)
So the greatest possible value for n such that 2^n can be factor of given number is 22.
Answer C
Question: Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?
A.9269
B.9261
C.9262
D.9231
Answer: B.9261
Explanation: A = 8000(21/20)3 = 9261
Answer:B
Question: How many liters of water must be evaporated from 50 liters of a 1-percent sugar solution to get a 10-percent solution?
A.35
B.40
C.42
D.45
Answer: D.45
Explanation: 1% of a 50 liter solution is 0.5L which is 10% of the solution at the end.
The solution at the end must be 5 L.
We need to evaporate 45 liters.
The answer is D.
Question: A fair coin is tossed 13 times. What is the probability of getting more heads than tails in 13 tosses?
A.1/2
B.63/128
C.4/7
D.61/256
Answer: A.1/2
Explanation: On each toss, the probability of getting a head is 1/2 and the probability of getting a tail is 1/2.
There is no way to get the same number of heads and tails on an odd number of tosses.
There will either be more heads or more tails.
Then there must be more heads on half of the possible outcomes and more tails on half of the possible outcomes.
P(more heads) = 1/2
The answer is A.
Question: N is a positive integer. When N + 1 is divided by 6, the remainder is 4. What is the remainder when N is divided by 2?
A.6
B.5
C.1
D.3
Answer: C.1
Explanation: N+1 = 6a+4
i.e. N+1 = 10, 16, 22, 28, ... etc.
i.e. N = 9, 15, 21, 27, ... etc.
When N is divided by 2 Remainder is always 1
Answer: C
Question: The radius of a circular wheel is 1.75 m, how many revolutions will it make in traveling 1 km?
A.100
B.277
C.288
D.267
Answer: A.100
Explanation: 2 * 22/7 * 1.75 * x = 11000
x = 1000
Answer: A
Question: A man bought 20 shares of Rs. 50 at 5 discount, the rate of dividend being 13. The rate of interest obtained is:
A.12	1/2	%
B.13 1/2%
C.15%
D.16 2/3%
Answer: C.15%
Explanation: Explanation:
Investment = Rs. [20 x (50 - 5)] = Rs. 900.
Face value = Rs. (50 x 20) = Rs. 1000.
Dividend = Rs.27/2 * 1000/100 =Rs. 135.
Interest obtained =(135/900 *100)%= 15%
ANSWER IS C
Question: In the coordinate plane, points (x, 1) and (4, y) are on line k. If line k passes through the origin and has slope 1/4, then x + y =
A.1
B.2
C.4
D.5
Answer: D.5
Explanation: Line k passes through the origin and has slope 1/4 means that its equation is y=1/4*x.
Thus: (x, 1)=(4, 1) and (4, y) = (4,1) --> x+y=4+1=5.
Answer: D
Question: If 76 is divided into four parts proportional to 7, 5, 3, 4, then the smallest part is:
A.12
B.15
C.16
D.19
Answer: A.12
Explanation: Explanation:
Given ratio = 7 : 5 : 3 : 4, Sum of ratio terms = 19.
Smallest part =(76 x 3/19) = 12
Answer: A
Question: If 1/(m – 2) = 1/(m + 2) + 1/(m – 1), which of the following is a possible value of m?
A.0
B.-1
C.-2
D.1
Answer: A.0
Explanation: Multiply by (m-2)*(m+2)*(m-1) throughout to get:
(m+2)*(m-1) = (m-2)*(m-1) + (m+2)(m-2)
Of the given options, only m=0 satisfies this.
Answer : A
Question: The sum of squares of three numbers is 764 and sum of their products taken two at a time is 500. What is their sum?
A.48
B.42
C.52
D.32
Answer: B.42
Explanation: Description :
Let the numbers be x,y,z.
=> x2+y2+z2=764
=> 2(xy+yz+xz)=2*500=1000
=> (x+y+z)2=(x2+y2+z2)+2(xy+yz+xz)=1764
=> (x+y+z)=sqrt(1764)=42
Answer B
Question: A, B and C enter into a partnership by investing $7000, $11000 and $18000 respectively. At the end of 8 months, B receives $880 as his share. Find the share of A.
A.$320
B.$440
C.$560
D.$670
Answer: C.$560
Explanation: The ratio of capital of A, B and C = 7000 : 11000 : 18000 = 7 : 11 : 18
A's share = (7/11)*880 = $560
The answer is C.
Question: A man rows 750 m in 675 seconds against the stream and returns in 7 and half minutes. His rowing speed in still water is
A.4 kmph
B.5 kmph
C.6 kmph
D.7 kmph
Answer: B.5 kmph
Explanation: Explanation:
Rate upstream = (750/675) = 10/9 m/sec
Rate downstream (750/450) m/sec = 5/3 m/sec
Rate in still water = (1/2)*[(10/9) + (5/3)] m/sec.
= 25/18 m/sec
= (25/18)*(18/5) kmph
= 5 kmph
Option B
Question: The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 16%, then the cost price of the article is:
A.500
B.334
C.531
D.664
Answer: C.531
Explanation: 110% of S.P. = 616
S.P. = (616 * 100)/110 = Rs. 560
C.P = (110 * 560)/116 = Rs. 531
Answer: Option C
Question: Find the value of e from (14)^2 x 5^3 Ã· 568 = e.
A.13.1
B.43.1
C.40.1
D.23.1
Answer: B.43.1
Explanation: Given Exp. =(14)^2 x 5^3 Ã· 568 = e
= 196 x 125 Ã· 568
43.1
B
Question: Evaluate:58- 12*3*2 =?
A.42
B.50
C.62
D.72
Answer: B.50
Explanation: According to order of operations, 12?3?2 (division and multiplication) is done first from left to right
12**2 = 4* 2 = 8
Hence
58- 12*3*2 = 58- 8 = 50
correct answer B
Question: A spike is hammered into a train rail. You are standing at the other end of the rail. You hear the sound of the hammer strike both through the air and through the rail itself. These sounds arrive at your point six seconds apart. You know that sound travels through air at 1100 feet per second and through steel at 16,500 feet per second. How far away is that spike?
A.7070.25 ft
B.7080.25
C.6070.25
D.8070.25
Answer: A.7070.25 ft
Explanation: d = 1100(t + 6 ), d = 16500t, so 1100(t + 6) = 16500t
1100t + 6600 = 16500t, 1100t - 1100t + 6600 = 16500t-1100t, 6600 = 15400t
6600/15400 = 15400t/15400, 0.4285 = t, 1100(.4285 + 6) = 7071.35, 16500(.4285) = 7070.25
ANSWER:A
Question: How many positive factors of 42 are not factors of 56?
A.1
B.2
C.3
D.4
Answer: D.4
Explanation: 42=2*3*7.
So, total number of factors for 42 = 2*2*2 = 8
factors for 42 = 1,2,3,6,7,14,21 and 42
56=2*2*2*7
So, total number of factors for 56 = 4*2 = 8
factors of 56 = 1,2,4,7,8,14,28 and 56.
Factors same in 42 and 56 are 1,2,7 and 14.
Hence, answer will be D.
Question: The total of 334 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is
A.250
B.277
C.278
D.200
Answer: A.250
Explanation: Explanation:
Let the number of 20 paise coins be x. Then the no of 25 paise coins = (334 - x).
0.20 * (x) + 0.25 (334 - x) = 71 => x = 250..
Answer: A) 250
Question: The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:
A.3
B.13
C.23
D.33
Answer: C.23
Explanation: L.C.M of 5, 6, 4 and 3 = 60.
On dividing 2496 by 60, the remainder is 37. Number to be added = 60 - 37 = 23.
ANSWER:C
Question: The average (arithmetic mean) of four different positive integers is 15. If the first of these integers in 3 times the second integer and the second integer is 2 less than the third integer, what is the least possible value of the fourth integer?
A.8
B.4
C.3
D.2
Answer: A.8
Explanation: Let the second integer be x and the fourth be a.
Then [3x + x + (x+2) + a]/4 =15
=> 5x + 2 + a = 60
=> 5x + a = 58
=> a = 58 - 5x
From the above equation we can see that a is minimum when x is maximum, provided both are positive
The maximum value that x can take in the above equation while still keeping a positive is x=10
This gives us a= 58 - 50 =8
Therefore the minimum value that the fourth integer can have is 8. Option A.
Question: What is the maximum number of pieces of birthday cake of size 2” by 2” that can be cut from a cake 20” by 20”?
A.5
B.100
C.16
D.20
Answer: B.100
Explanation: The prompt is essentially asking for the maximum number of 2 x 2 squares that can be cut from a larger 20 by 20 square. Since each 'row' and each 'column' of the larger square can be sub-divided into 10 'pieces' each, we have (10)(10) = 100 total smaller squares (at maximum).
B
Question: How many litres of pure salt are there in 12 litres of a 25% solution?
A.1.14 litres
B.1.41 litres
C.2.56 litres
D.3 litres
Answer: D.3 litres
Explanation: Explanation :
Quantity of pure salt = 25% of 12 litres
= (25/10012)litres
= 3 litres
Answer : D
Question: A fair price shopkeeper takes 10% profit on his goods. He lost 20% goods during theft. His loss percent is:
A.10%
B.45%
C.12%
D.17%
Answer: C.12%
Explanation: C
Suppose he has 100 items. Let C.P. of each item be Re. 1.
Total cost = Rs. 100. Number of items left after theft = 80.
S.P. of each item = Rs. 1.10
Total sale = 1.10 * 80 = Rs. 88
Hence, loss % = 12/100 * 100 = 12%
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
A.298 m
B.277 m
C.245 m
D.256 m
Answer: C.245 m
Explanation: Speed = [45 X 5/18] m/sec
= [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30
= 25/2 => 2(130 + x) = 750 => x
= 245 m.
Answer: C