RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: 2^46655 mod 9 = ?
A.4
B.5
C.6
D.7
Answer: B.5
Explanation: By remainder theorem
Remainder={[(2^3)^1551*2^2]/9}
=[{(-1)^1551*4}/9]
=5
ANSWER:B
Question: A man engaged a servant on the condition that he would pay him Rs.1000 and a uniform after one year service. He served only for 9 months and received uniform and Rs.550, find the price of the uniform?
A.s.80
B.s.85
C.s.90
D.s.800
Answer: D.s.800
Explanation: 9/12 = 3/4 * 1000 = 750
550
-------------
200
1/4 -------- 200
1 --------- ? => Rs.800
ANSWER:D
Question: Find the number of terms in an arithmetic progression with the first term 2 and the last term being 62, given that common difference is 2.
A.31
B.40
C.22
D.27
Answer: A.31
Explanation: The n th term = a +(n-1) *d
62 = 2 +(n- 1) *2,
62 – 2 = (n-1) *2,
n = 60/2 +1 = 31.
ANSWER:A
Question: A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is?
A.17
B.27
C.15
D.19
Answer: C.15
Explanation: Suppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x - 5) and (x - 9) hours respectively to fill the tank.
1/x + 1/(x - 5) = 1/(x - 9)
(2x - 5)(x - 9) = x(x - 5)
x2 - 18x + 45 = 0
(x- 15)(x - 3) = 0 => x = 15
Answer: C
Question: If 8 ∙ 2x = 5(y+8), then when y = -8, x =
A.-4
B.-3
C.0
D.4
Answer: C.0
Explanation: Solution:
8 ∙ 2x = 5(y+8).
or, 8 ∙ 2x = 5(-8+8).
or, 2x = 50.
or, 2x = 1 [anything to the power 0 is 1 then, 50 = 1].
Taking log on both sides,
log 2x = log 1.
or, x log 2 = 0 [since log 1 = 0].
or, x = 0/log 2 [dividing log 2 on both sides].
Therefore, x = 0.
Answer: C
Question: To fill an art exhibit, the girls in an art course are assigned to create one piece of artwork each in the following distribution: 1/3 are sculptures, 1/8 are oil paintings, 1/2 are watercolors, and the remaining 10 pieces are mosaics. How many girls are in the art class?
A.80
B.120
C.240
D.320
Answer: C.240
Explanation: Let the total number of girls in the art class = s
Distribution of artwork is as
1/3 are sculptures
1/8 are oil paintings
1/2 are watercolors, and the remaining 10 pieces are mosaics
(1/3)s +(1/8)s +(1/2)s + 10 = s
Since remaining 10 pieces are mosaics , (1/24)s = 10
s = 240
Answer C
Question: Out of 200 donors, ¼ are men and remaining are women. Each male donor donates Rs.3000 per year and each female donor donates ½ of that amount. What is the total yearly collection through donations?
A.Rs.1, 50,000
B.Rs.3, 75,000
C.Rs.1, 40,300
D.Rs.2, 25,000
Answer: B.Rs.3, 75,000
Explanation: Number of men donors= 200*1/4 =50
Number of women donors=200-50=150
1 man donor donates = Rs.3000
Therefore, 50 men donor donates = 3000* 50= Rs.1,50,000
1 woman donor donates= 3000*1/2 = Rs.1500
Therefore, 150 women donor donates = 1500* 150= Rs.2,25,000
Hence total amount collected = 1,50,000+ 2,25,000
= Rs.3,75,000
ANSWER:B
Question: The principal that amounts to Rs. 4903 in 3 years at 6 1/4 % per annum C.I. compounded annually, is?
A.s. 3096
B.s. 4076
C.s. 4085
D.s. 4096
Answer: B.s. 4076
Explanation: Principal = [4913 / (1 + 25/(4 * 100))3]
= 4903 * 16/17 * 16/17 * 16/17 = Rs. 4076.
ANSWER:B
Question: Two pens and three pencils cost 86. Four pens and a pencil cost 112. What is the difference between the cost of a pen and that of a pencil?
A.25
B.13
C.19
D.Cannot be determined
Answer: B.13
Explanation: Let the cost of a pen and a pencil be ‘x’ and ‘y’ respectively. We have to find (x – y).
From the question,
2x + 3y = 86 ..... (i)
4x + y = 112 ......(ii)
Subtracting (i) from (ii), we get
2x – 2y = 26 or, x – y = 13
Answer B
Question: Three friends had dinner at a restaurant. When the bill was received, Akshitha paid 2/5 as much as Veena paid and Veena paid 1/2 as much as Lasya paid. What fraction of the bill did Veena pay ?
A.3/19
B.3/12
C.5/17
D.3/10
Answer: C.5/17
Explanation: Let Veena paid x,
so Akshitha paid 2x/5 , and Lasya paid 2x,
So total bill paid is given by
x+(2x/5) +2x = 1, we get
i.e. x = 5/17
Answer: C
Question: In the first week of the Year, Jancy saved $1. In each of the next 51 weeks, she saved $1 more than she had saved in the previous week. What was the total amount that Jancy saved during the 52 weeks?
A.$1,326
B.$1,352
C.$1,378
D.$2,652
Answer: C.$1,378
Explanation: In the first week of the Year, Jancy saved $1.If you don't recall the formula, there is one method:
1 + 2 + 3 + 4 + 5 ........ + 26 + 27 + ............ + 48 + 50 + 51 + 52
Sum of 1stlast digit = 1 + 52 = 53
Sum of 2nd2nd last digit = 2 + 51 = 53
Sum of 3rd3rd last digit = 3 + 50 = 53
.
.
.
.
This is repeated 26 times
So, 26 * 53 = 1378
Answer = C
Question: If 8 ministers are to be seated at a round table conference, then how many different ways can they be seated?
A.24
B.60
C.5040
D.720
Answer: C.5040
Explanation: Simple formula:
There are (n - 1)! ways to arrange n distinct objects in a circle.
so its (8-1)! = 7! = 5040=C
Question: Simplify: (4 – 5) – (13 – 18 + 2).
A.-1
B.–2
C.1
D.2
Answer: D.2
Explanation: Solution:
(4 – 5) – (13 – 18 + 2).
= -1-(13+2-18).
= -1-(15-18).
= -1-(-3).
= -1+3.
= 2.
Answer: (D)
Question: Find the smallest number of 6 digits which is exactly divisible by 111
A.100011
B.111111
C.101111
D.1011111
Answer: A.100011
Explanation: Smallest number of 6 digits is 100000.
On dividing 100000 by 111, we get 100 as remainder.
Number to be added = (111 - 100) - 11.
Hence, required number = 100011
ANSWER A 100011
Question: Eric, Nick and Archi make contributions to the Society Of Nature Protection in the ratio of 5:3:2.5. If altogether they contribute 4452 Nis, how much more money does Nick contribute than Archi?
A.128 Nis
B.212 Nis
C.234 Nis
D.245 Nis
Answer: B.212 Nis
Explanation: E:N:A 5:3:2.5
so total = 5x + 3x + 2.5 x = 10.5 x = 4452
so x = 424
Nick Contribution is 0.5 more than Archi so 0.5 x =0.5 * 424 = 212
So B. 212 Nis is the correct answer
Question: If c = 9/25, w = 15/32, and m + w + c = 1, which of the following gives the values of m, w, and c in increasing order?
A.c, m, w
B.c, w, m
C.m, w, c
D.m, c, w
Answer: D.m, c, w
Explanation: Answer D - m, c, w
c ~ 1/3
w ~ 1/2
and m+w+c = 1 hence m ~ 1/6
Hence increasing order would be m -> c -> w
Aswer D
Question: The average salary of the employees in a office is Rs.120/month.The avg salary of officers is Rs.450 and of non officers is Rs 110. If the no.of officers is 15,then find the No of nonofficers in the office.
A.400
B.420
C.430
D.495
Answer: D.495
Explanation: Let no. of non- officers be x
15 * 450 + x * 110 = (x + 15) 120
x = 495
D
Question: Valentine day 14 Feb. 2005 was celebrated by Anand and shilpa on Monday. They were very happy. What day of the week would come on 14 Feb. 2013?
A.monday
B.tuesday
C.sunday
D.wednesday
Answer: D.wednesday
Explanation: feb 14 2005 - monday
feb 14 2006 - tuesday
feb 14 2007 - wednesday
feb 14 2008 - thursday
feb 14 2009 - saturday [since 2008 is leap year , 2 days ll go forward]
feb 14 2010 - sunday
feb 14 2011 - monday
feb 14 2012 - tuesday
feb 14 2013 - wednesday
ANSWER:D
Question: Let B represent a set of four distinct prime numbers. If the sum of the numbers in B is even and x is a member of B, then what is the least possible value that x can be?
A.1
B.2
C.3
D.5
Answer: C.3
Explanation: We are told that B is a set of four distinct prime numbers, and the sum of the numbers in B is even. Since the question involves odds, evens and the smallest possible prime, you should immediately think of 2, the smallest prime number and the only even prime number.
If 2 were a member of the set, then we would have one even number and three odd numbers. Since such sum would always be odd, 2 cannot be a member of the set. Thus, all the members of B must be odd to yield an even sum.
Since all the members of the set must be odd prime numbers, the answer is the smallest odd prime number, which is 3.
The correct answer is choice (C).
Note:1 is not a prime number.
Question: A dealer purchased an article at 3/4 of its list price and sold 50% more than the list price. Find his gain percent?
A.108%
B.300%
C.100%
D.180%
Answer: C.100%
Explanation: MP = 100
CP = 75
SP = 150
------
75 ---- 75
100 ---- ? => 100%
Answer: C
Question: During the first week of performances of a certain play, 5,400 tickets were sold, all at reduced price. During the remaining weeks of performances, 5 times as many tickets were sold at full price as were sold at reduced price. If the total number of tickets R sold was 25,200, how many of them were sold at full price?
A.21,000
B.19,800
C.16,500
D.15,800
Answer: C.16,500
Explanation: Given:
The question tells us about the number of tickets sold in the first week at reduced price = 5,400. It also tells us that during the remaining weeks, the number of tickets sold at full price was 5 times the no. of tickets sold at reduced price. The total tickets sold was 25,200, and we are asked to find the number of tickets that where sold at full price.
Approach:
The question asks us to find the number of ticket sold at full price. We know that the number of tickets sold at full price was 5 times the no. of tickets sold at reduced price in remaining weeks. Hence, assuming tickets sold at reduced price in remaining weeks to be x would give us the no. of tickets sold at full price to be 5x.
Tickets sold in first week + Tickets sold in remaining weeks = Total no. of tickets soldi.e.
Tickets sold in first week + Tickets sold at full price in remaining weeks + Tickets sold at reduced price in remaining weeks = Total no. of tickets sold
We know the no. of tickets sold during first week and the total no. of tickets sold. We will use this relation to get to our answer.
Working Out:
Tickets sold in first week + Tickets sold at full price in remaining weeks + Tickets sold at reduced price in remaining weeks = Total no. of tickets sold
Substituting values in the equation, we get
5,400 + 5x + x = 25,200
x= 3,300
Tickets sold at full price = 5x = 16,500
Answer: Option C
Question: 40 percent of the ducks included in a certain side effects study were male. If some of the ducks had side effects during the study and 20 percent of the ducks who had side effects were male, what was the ratio of the side effect rate for the male ducks to the side effect rate for the female ducks?
A.1/4
B.9/14
C.2/3
D.3/8
Answer: D.3/8
Explanation: Say total male = 40
Total female =60
Required ratio =( .2/40)/ (.8/60) = 3/8 D is the answer
Question: What do you get if you add 3 to 989 five times?
A.902
B.990
C.678
D.992
Answer: D.992
Explanation: D
992 , 992 , 992 , 992 , 992
Question: On the number line, if x is halfway between -11 and 5, and if y is halfway between -3 and 7, what number is halfway between x and y?
A.-1.5
B.-0.5
C.0.5
D.1.5
Answer: B.-0.5
Explanation: x= -3 and y = 2.
The answer is B.
Question: In 1 hour, a boat goes 5 km along the stream and 9 km against the stream. The speed of the boat in still water (in km/hr) is :
A.3 km/hr.
B.2 km/hr.
C.7 km/hr.
D.8 km/hr.
Answer: C.7 km/hr.
Explanation: Speed in still water = 1/2(9 + 5) km/hr
= 7 km/hr. ANSWER :C
Question: Three 6 faced dice are thrown together. The probability that all the three show the same number on them is
A.1/37
B.1/36
C.1/32
D.1/31
Answer: B.1/36
Explanation: It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36
Answer: B
Question: Dan can do a job alone in 15 hours. Annie, working alone, can do the same job in just 10 hours. If Dan works alone for 6 hours and then stops, how many hours will it take Annie, working alone, to complete the job?
A.2
B.4
C.6
D.8
Answer: C.6
Explanation: Dan can complete 1/15 of the job per hour.
In 6 hours, Dan completes 6(1/15) = 2/5 of the job.
Annie can complete 1/10 of the job per hour.
To complete the job, Annie will take 3/5 / 1/10 = 6 hours.
The answer is C.
Question: The remainder when 1!+2!+3!...+50! divided by 4! will be
A.21
B.9
C.77
D.927
Answer: B.9
Explanation: The remainder when the terms greater than 4! are divided by 4! becomes 0 so we need to consider the terms upto 3!.
So remainder will be whatever is obtained by dividing 1!+2!+3! with 4!.
So remainder is obtained by dividing (1+2+6)= 9 with 4! ( 33)
So remainder is 9.
Answer:B
Question: If the two-digit integers A and B are positive and have the same digits, but in reverse order, which of the following could be the sum of A and B?
A.65
B.66
C.67
D.68
Answer: B.66
Explanation: A two-digit number "cd" can be expressed algebraically as 10c+d.
The sum of A + B = (10c+d)+(10d+c)=11(c+d).
The only answer that is a multiple of 11 is 66.
The answer is B.
Question: A trader marked the selling price of an article at 11% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of :
A.10 %
B.10.5 %
C.9.9%
D.12.5 %
Answer: C.9.9%
Explanation: Sol.
Let C.P. = Rs. 100. Then, Marked Price = Rs. 110, S.P. = Rs. 99.
∴ Discount % = [11/111 * 100] % = 9.9%
Answer C
Question: When Jack picks olives for two hours at three times his regular speed, he picks 11 pounds of olives more than Mac working for five hours at 80% of his regular speed. Therefore, if Mac picks olives for one hour at double his regular speeds, and Jack picks olives for four hours at 75% of his regular speed, then
A.Jack picks double the amount of olives Mac picks
B.Mac picks 10 pounds more than Jack
C.Jack picks 10 pounds more than Mac
D.Mac picks 5 more pounds than Jack
Answer: D.Mac picks 5 more pounds than Jack
Explanation: Let's say Jack's regular speed is J olives/hr and Mac's regular speed is M olives/hr
Given:
2*3J = 10 + 5*(4/5)M
3J = 5 + 2M
Question:if Mac picks olives for one hour at double his regular speeds, and Jack picks olives for four hours at 75% of his regular speed
Mac picks 2M and Jack picks 4*(3/4)J = 3J
They are asking you for the relation between 3J and 2M. You already know 3J = 5 + 2M
So Mac picks 5 pounds more olives than Jack.
D
Question: Find the ones digit of 73^320
A.3
B.5
C.6
D.7
Answer: D.7
Explanation: Cyclicity of 3 is 3,9,7,1after 4 multiplication again the cycle repeats.
So divide 320 by 4 and we get 87 as quotient and 2 as remainder. So cycle will run for 87 times and then 2 times more. So pick up the 2nd item from the cycle.
Hence Answer D.
Question: Mary has a monthly salary of $1200. She spends $280 per month on food. What percent of her monthly salary does she spend on food?
A.20
B.21
C.22
D.23
Answer: D.23
Explanation: The part of her salary that is spent on food is $280 out of her monthly salary of $1200
percent = part / whole = 280 / 1200 = 0.23 (rounded to 2 decimal places)
Multiply and divide 0.23 by 100 to convert in percent
percent = 0.23 * 100 / 100 = 23 / 100 = 23%
Option D is correct.
Question: Ratio between Rahul and Deepak is 5:2, After 6 Years Rahul age will be 26 years. What is Deepak present age.
A.14
B.15
C.8
D.22
Answer: C.8
Explanation: Explanation:
Present age is 5x and 2x,
=> 5x + 6 = 26 => x = 4
So Deepak age is = 2(4) = 8
Option C
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
A.Rs.28
B.Rs.280
C.Rs.140
D.Rs.70
Answer: B.Rs.280
Explanation: x*(85/100) = (480 - x)119/100
x = 280
ANSWER:B
Question: What is the sum of the local values of the digits 2, 3, 4, 5 in the number 2345?
A.2345
B.4500
C.5000
D.6000
Answer: A.2345
Explanation: 2000 + 300 + 40 + 5 = 2345
ANSWER A
Question: What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
A.814
B.800
C.100
D.200
Answer: A.814
Explanation: Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
Required number of tiles = (1517 x 902)/41 x 41 = 814.
Answer:A
Question: In a group of 44 students, each student is registered for at least one of three classes – History, Math and English. Twenty students are registered for History, twenty students are registered for Math, and thirty students are registered for English. If only three students are registered for all three classes, how many students are registered for exactly two classes?
A.13
B.10
C.20
D.8
Answer: C.20
Explanation: Each student is registered forat least one of three classesmeans thatthere are no students who are registered for none of the classes.
Total = {people in group A} + {people in group B} + {people in group C} - {people in exactly 2 groups} - 2*{people in exactly 3 groups} + {people in none of the groups}:
44 = 20 + 20+ 30- {people in exactly 2 groups} - 2*3 + 0-->{people in exactly 2 groups}=20
Answer: C
Question: Can you find the missing number in the sequence given below?
11 16 21 12 17 ? 13 18 23 14 19 24
A.20
B.21
C.22
D.23
Answer: C.22
Explanation: Solution:
22
Explanation :
The sequence is given in the puzzle is :
11 16 21 12 17 ? 13 18 23 14 19 24
Let's break the given series as below:
11 16 21
12 17 22
13 18 23
14 19 24
Now read the number from left hand side from top to bottom as :
So the number that will replace '?' is 22.
Answer C
Question: There are 6 people from different countries namely Germany, Italy, Britain, Spain, Poland and France. They are sitting around a table. Polish sits next to British. German sits next to Italian, or British or both. Italian does not sit next to the Frenchman. Spanish sits immediately after British. Who sits on the either side of the German?
A.British and Italian
B.Polish and British
C.British and French
D.Italian and French
Answer: D.Italian and French
Explanation: according to question
the arrangement would be
FGISBP
So the answer is : option (d)
ANSWER:D
Question: Let us say that a table tennis tournament was going on with knock out terms which means the one who loses the match is out of the tournament. 91 players took part in that tournament. How many matches were played?
A.90 matches
B.95 matches
C.99 matches
D.85 matches
Answer: A.90 matches
Explanation: A 90 matches. The number of matches will always sum up to one less than the number of players in a knock out tournament. You may calculate it in any manner. Thus 90 matches were played.
Question: In a hockey championship, there are 153 matches played. Every two team played one match with each other. The number of teams participating in the championship is:
A.16
B.17
C.18
D.19
Answer: C.18
Explanation: Solution:
Let there were x teams participating in the games, then total number of matches,
nC2 = 153.
On solving we get,
=> n =−17 and n =18.
It cannot be negative so,
n = 18 is the answer.
Answer: Option C
Question: Students at a school were on average 180 cm tall. The average female height was 170 cm, and the average male height was 188 cms. What was the ratio of men to women?
A. 5:2
B. 5:1
C. 4:3
D. 5:4
Answer: D. 5:4
Explanation: We're given a few facts to work with:
1) The average height of the females is 170cm
2) The average height of the males is 188cm
3) The average of the GROUP is 180cm
We're asked for the RATIO of men to women.
W = number of Women
M = number of Men
(170W + 188M)/(W+M) = 180
170W + 188M = 180W + 180M
8M = 10W
4M = 5W
M/W = 5/4
The ratio of men to women is 5 tổ 4.
D
Question: If the price of gold increases by 50%, find by how much the quantity of ornaments must be reduced, so that the expenditure may remain the same as before?
A.331/8%
B.331/3%
C.631/3%
D.332/3%
Answer: B.331/3%
Explanation: 100
150
------
150-------50
100-------? => 331/3%
Answer:B
Question: The number of bacteria in a petri dish increased by 50 percent every 1 hour. If there were 108 million bacteria in the dish at 2: 00 p.m., at what time were there 32 million bacteria in the dish?
A.10: 00 a.m.
B.11: 00 a.m.
C.12: 00 p.m.
D.01: 00 p.m.
Answer: B.11: 00 a.m.
Explanation: Given:
he number of bacteria in a petri dish increased by 50 percent every 1 hour
There were 108 million bacteria in the dish at 2: 00 p.m
Since the bacteria is increasing by 50% every 1 hour, this means that the number is multiplied by 1.5 every 1 hour.
Required: At what time were there 32 million bacteria in the dish?
Assume that there were n intervals of 1 hour between 32 million and 108 million.
32 * (1.5)^n = 108
(3/2)^n = 108/32 = 27/8 = (3/2)^3
Hence n = 3 intervals.
Each interval was of 1 hour. Therefore, the number of hours = 3
Subtracting 3 hours from 2 PM, we get 11 AM as the answer.
Option B
Question: During the break of a football match, the coach will make 3 substitutions. If the team consists of 15 players among which there are 2 forwards, what is the probability that none of the forwards will be substituted?
A. 21/55
B. 18/44
C. 12/65
D. 28/44
Answer: C. 12/65
Explanation: Required probability = no. of favorable outcome/ total no. of outcomes
out of 15 players any 3 can be selected in 15C3 ways
after removing 2 forwards any 3 players can be selected from the remaining 9 players in 9C3 ways
thus required probability = 9C3/15C3 =12/65
Question: Nitin ranks 15th in a class of 47 students. What is rank from the last ?
A.33
B.38
C.32
D.28
Answer: A.33
Explanation: Explanation:
Number students behind the nitin in rank = (47 - 15) = 32
Nitin is 33rd from the last
Answer: A) 33
Question: There are three bags.The first bag has two blue rocks. The second bag has two red rocks. The third bag has a blue and a red rock. All bags are labeled but all labels are wrong.You are allowed to open one bag, pick one rock at random, see its color and put it back into the bag, without seeing the color of the other rock.
How many such operations are necessary to correctly label the bags ?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: Just One!
example
If u get Blue rock with label as "blue+red" => this is red as all labels are wrong.
In this way u can logically solve this puzzle.
Answer A
Question: In a village of 2,500 people, 800 people are over 70 years old and 850 people are female. It is known that 40 percent of the females are younger than 70 years old. If no one in the village is 70 years old, what is the probability that a person chosen at random is either a male or younger than 70 years old?
A.221/250
B.199/250
C.33/50
D.8/25
Answer: B.199/250
Explanation: To solve this we would need to know the number of people who are less than 70 years old, the number of males, and the number of males who are less than 70 years old.
Overlapping sets: quantity of A or B = A + B - (A∩B) = quantity of A + quantity of B - (intersection of A and B)
Number of males = 2500-850 = 1650
Number of people below 70 years old = 2500-800 = 1700
Number of males below 70 years old = 1700-(850*0.4) = 1360
Total number of people who are male OR below 70 = 1650 + 1700 - 1360 = 1990
Probability of male or below 70 = 1990/2500 = 199/250
Answer: B
Question: In a garden there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is
A.20 m
B.22 m
C.24 m
D.26 m
Answer: C.24 m
Explanation: Each row contains 12 plants.
There are 11 gapes between the two corner trees (11 x 2) metres and 1 metre on each side is left.
Therefore Length = (22 + 2) m = 24 m.
ANSWER:C
Question: A restaurant meal cost $30 and there was no tax. If the tip was more than 15 percent but less than 25 percent of the cost of the meal, then the total amount paid must have been between
A. $40 and $42
B. $39 and $41
C. $38 and $40
D. $34 and $39
Answer: D. $34 and $39
Explanation: Hence it will be between 30 * (1+15/100) and 30 * (1+25/100).
i.e b/w 34.5 and 37.5. Hence the answer D (b/w 34 and 39).
Question: Pam had $23. Then she saved $11 from her allowance and spent $6 on a comic book and $8 on a puzzle. How much money does Pam have left?
A.$33
B.$20
C.$25
D.$60
Answer: B.$20
Explanation: Step 1: Find the total amount of money saved.
$23 + $11 = $34
Step 2: Find the total cost of the comic book and the puzzle.
$6 + $8 = $14
Step 3: Find the amount of money left.
$34 – $14 = $20
Pam has $20 left.
Answer is B.