RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The ratio of the arithmetic mean of two numbers to one of the numbers is 4:6. What is the ratio of the smaller number to the larger number?
A.1:5
B.1:4
C.1:3
D.1:2
Answer: C.1:3
Explanation: For two numbers, the arithmetic mean is the middle of the two numbers.
The ratio of the mean to the larger number is 4:6, thus the smaller number must have a ratio of 2.
The ratio of the smaller number to the larger number is 2:6 = 1:3.
The answer is C.
Question: The Simple Interest on Rs. 7300 from 11 May, 1987 to 10 September 1987 ( Both day Include ) at 5% per annum is :
A.120
B.123
C.125
D.128
Answer: B.123
Explanation: Time from 11 May to 10 September, 1987
=21+30+31+31+10 = 123 days
Time : 123 days = 123/365 year
S.I =(7300x123x5)/(365x100)=Rs.123
answer :B
Question: The average age of an adult class is 40years. 10new students with an avg age of 32years join the class. Therefore decreasing the average by 4year. Find what was theoriginal strength of class?
A.10
B.12
C.15
D.17
Answer: A.10
Explanation: Let original strength = y
Then , 40y + 10 x 32 = ( y + 10) x 36
â‡’ 40y + 320 = 36y + 360
â‡’ 4y = 40
âˆ´ y = 10
A
Question: The length of minute hand of a clock is 5.2 cm. What is the area covered by this in 10 minutes
A.15.27
B.14.15
C.17.27
D.18.27
Answer: B.14.15
Explanation: area of circle is pi*r^2
but in 10 minutes area covered is (10/60)*360=60 degree
so formula is pi*r^2*(angle/360)=3.14*(5.2^2)*(60/360)=14.15 cm^2
ANSWER:B
Question: A man can row upstream at 25 kmph and downstream at 35 kmph, and then find the speed of the man in still water?
A.22
B.37
C.30
D.27
Answer: C.30
Explanation: US = 25
DS = 35
M = (35 + 25)/2 = 30
Answer:C
Question: Sundar and Raju together can do a piece of work in 8 days. If Sundar alone can do the same work in 12 days, then Raju alone can do the same work in?
A.20 days
B.22 days
C.24 days
D.26 days
Answer: C.24 days
Explanation: Raju work = 1/8 - 1/2 = 1/24 => 24 days
ANSWER C
Question: Jamal had a bag of marbles. He had 12 yellow, 10 blue, 5 green and 1 black marbles. He decided to randomly select a ball from the bag. What is the proabilitly that he will draw a black marble?
A.10/28
B.1/28
C.12/28
D.28/1
Answer: B.1/28
Explanation: B
Question: Jake can dig a well in 16 days. Paul can dig the same well in 24 days. Jake, Paul and Hari together dig the well in 8 days. Hari alone can dig the well in
A.96 days
B.48 days
C.32 days
D.24 days
Answer: B.48 days
Explanation: jake 1 day work=1/16
paul 1 day work=1/24
j+p+h 1 ady work=1/8
1/16+1/24+1/x=1/8
1/x=1/48
x=48
so,Hari alone can dig the well in 48 days
ANSWER:B
Question: What is the 32nd word of "WAITING" in a dictionary?
A.AIWTNG
B.AGNTWI
C.AIGNWT
D.AGNTIWI
Answer: D.AGNTIWI
Explanation: Explanation :
Arranging the words of waiting in Alphabetical Order : A,G,I,I,N,T,W Start with A_ _ _ _ _ _ This can be arranged in 6!/2! ways=720/2=360 ways so can't be arranged starting with A alone as it is asking for 32nd word so it is out of range AG_ _ _ _ _then the remaining letters can be arranged in 5!/2! ways so,120/2=60 ways. Out of range as it has to be within 32 words. AGI_ _ _ _ Now the remaining letters can be arranged in 4! ways =24 AGN _ _ _ _ can be arranged in 4!/2! ways or 12 ways so,24+12 =36th word so out of range. So we should not consider all the words start with AGN now AGNI_ _ _can be arranged in 3! ways =6 ways so 24+6=30 within range Now only two word left so, arrange in alphabetical order. AGNTIIW - 31st word AGNTIWI - 32nd word
Answer : D
Question: A tradesman by means of his false balance defrauds to the extent of 32%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
A.74.5%
B.74.24%
C.84.6%
D.24.89%
Answer: B.74.24%
Explanation: g% = 32 + 32 + (32*32)/100
= 74.24%
Answer: B
Question: Four of the following five parts numbered (a), (b), (c), (d) and (e) in the following equation are exactly equal. Which of the parts is not equal to the other four? The number of that part is the answer.
A.xy2 – x2y + 2x2y2
B.xy2(1 – 2x) + x2y(2y – 1)
C.xy2(1 + x) – x2y(1 – y)
D.xy[y(1 + x) – x(1 – y)]
Answer: B.xy2(1 – 2x) + x2y(2y – 1)
Explanation: The other parts are equal to xy2 – x2y + 2x2y2.
Answer B
Question: The area of square ABCD above is 24. The shaded region is the intersection of the square and a circular region centered at C. What is the area of the shaded region?
A.18−9/4∗π
B.24−9/2∗π
C.19+9/4∗π
D.24−6∗π
Answer: D.24−6∗π
Explanation: =Square - Quarter circle
=24- pi*24/4
=24- pi*6
ANSWER:D
Question: If an integer n is to be chosen at random from the integers 1 to 92, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8?
A.1/4
B.3/8
C.1/2
D.29/46
Answer: D.29/46
Explanation: n(n+1)(n+2) will be divisible by 8 when n is a multiple of 2 or when (n+1) is a multiple of 8.
Thus when n is even, this whole expression will be divisible by 8.
from 1 to 96, there are 46 even integers.
Now when (n+1) is multiple by 8, we have 12 such values for (n+1)
probability that n(n+1)(n+2) will be divisible by 8
= (46 + 12)/92
= 58/96
= 29/46
Ans is D
Question: √[200√[200√[200……..∞]]] = ?
A.200
B.10
C.1
D.20
Answer: A.200
Explanation: Let √[200√[200√[200……..∞]]] = x ; Hence √200x = x
Squaring both sides 200x = x² Þ x (x – 200) = 0
Þ x = 0 or x – 200 = 0 i.e. x = 200
As x cannot be 0, x = 200.
ANSWER:A
Question: Donovan and Michael are racing around a circular 400-meter track. If Donovan runs each lap in 45 seconds and Michael runs each lap in 36 seconds, how many laps will Michael have to complete in order to pass Donovan, assuming they start at the same time?
A.8
B.7
C.6
D.5
Answer: D.5
Explanation: One way of approaching this question is by Relative speed method
1. Speed/ Rate of Donovan = Distance/ time => 400/45 =>80/9
2. Speed/ Rate of Michael = Distance/ time => 400/36 => 100/9
Relative Speed between them = 100/9 - 80/9 => 20/9 (We subtract the Rates if moving in the same direction and add the rates if moving in the opposite direction)
In order to pass Donovan-
Distance to be covered = 400, Relative Rate = 20/9
Total Time taken by Micheal to surpass Donovan = Distance / rate => 400*9/20 => 3600/10 => 180
No. of laps taken by Michael = Total time / Michael's rate => 180/36 => 5
Hence correct answer is 5 Laps.
D
Question: If x/(9p) is an even prime number, where x is a positive integer and p is a prime number, what is the least value of x?
A. 22
B. 33
C. 44
D. 66
Answer: C. 44
Explanation: x/(11p) = even prime number
x = even prime number * 11p
Least value of x = Lowest even prime number * 11 * Lowest value of p
= 2 * 11* 2 = 44
Answer C
Question: A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: Speed downstream = (13 + 4) km/hr = 17 km/hr.
Time taken to travel 68 km downstream =	68/17hrs = 4 hrs.
Answer: Option A
Question: Find the sum of prime numbers lying between 58 and 74?
A.198
B.201
C.252
D.331
Answer: D.331
Explanation: Solution
Required sum	= 59 + 61 + 67 + 71 + 73)
= 331.
Answer D
Question: 45 liters of mixture is created by mixing Liquid A and Liquid B in the ratio 3:2. How much more Liquid B must be added to make the ratio 9:11?
A.9 Litres
B.10 Litres
C.12 Litres
D.15 Lt
Answer: D.15 Lt
Explanation: In current ratio A = (3/5) * 45 = 27
B is 18
Suppose "b" amount of b is added
new ratio = 27/(b+18) = 9/11
=> b+18 = 33
=> b = 15
So, answer will be D
Question: During a recent track meet, Peter ran x meters of the 100 meter dash in 7 seconds; running at the same rate, how many seconds will it take Peter to run z meters of the 200 meter dash?
A.7x/z
B.7zx
C.7z/x
D.7/xz
Answer: C.7z/x
Explanation: Speed of Peter = x/7 meters per second
Time needed to run z meters = DISTANCE/SPEED = z / (x/7) =7z/x
Option C
The values 100m and 200m have no role to play here and are just given to confuse you.
Question: How many seconds will a train 250 meters long take to cross a platform 200 meters long if the speed of the train is 90 kmph?
A.18 sec
B.15 sec
C.21 sec
D.16 sec
Answer: A.18 sec
Explanation: D = 250+200 = 450
S = 90* 5/18 = 25 mps
T = 450/25 = 18 sec
A) 18 sec
Question: If n=10^100and n^n=10k what is the value of k?
A.200
B.10^100
C.10^102
D.100^100
Answer: C.10^102
Explanation: There is a simple logic to this question.
(a^m)^n = a^mn
So, (10^100)^(10^100) = 10^(100*(10^100))
= 10^((10^2)*(10^100))
= 10^(10^102)
and this equals 10^k
So, k = 10^102
ANSWER:C
Question: In a class of 140 students, 60% of them passed. By what percent is the number of students who passed more than the number of failed students?
A.80%
B.20%
C.40%
D.50%
Answer: D.50%
Explanation: Number of students passed = 60% of 140 = 60/100 * 140 = 84
Number of students failed = 140 - 84 = 56.
Required percentage = 28/56 * 100 = 50%.
ANSWER:D
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. How far is the place?
A.2.29
B.2.88
C.2.2
D.2.12
Answer: B.2.88
Explanation: M = 6
S = 1.2
DS = 6 + 1.2 = 7.2
US = 6 - 1.2 = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
Answer: B
Question: Approximately how many revolutions will be made by a car tire with a 15-inch diameter if the car travels 1⁄2 mile?
A.669
B.660
C.360
D.720
Answer: A.669
Explanation: Diameter of car tire = 15 inches
Radius of car tire = 7.5 inches = 7.5*2.54 cm = 19.05 cm
Circumference of the car tire = 2*pi * 19.05 = 2 *3.14 *19.05= 119.63 cm
Distance traveled by car = .5 mile = .5 *1.6 km = .8 km = 800 m = 8 * 10^4 cm
Number of revolutions =Distance traveled / Circumference of tire = 8 * 10^4 / 119.63 = 668.73
Since the answer choices are far apart we should use estimation in this question .
Ideally ,in the GMAT the conversion between units would be provided .
Answer A
Question: How many words with or without meaning, can be formed by using all the letters of the word, 'DELHI' using each letter exactly once?
A.720
B.24
C.None of these
D.120
Answer: D.120
Explanation: Explanation :
The word 'DELHI' has 5 letters and all these letters are different.
Total words (with or without meaning) formed by using all these
5 letters using each letter exactly once
= Number of arrangements of 5 letters taken all at a time
= 5P5 = 5! = 5 x 4 x 3 x 2 x 1 = 120. Answer : Option D
Question: If X,Y is 26%,30% smaller than Z then how much percentage is Y greater than X?
A.5 15/37 %
B.13%
C.13 1/2%
D.14%
Answer: A.5 15/37 %
Explanation: X = 74 %
Y = 70 %
Z = 100 %
X-Y/X × 100 = 4/76 × 100 = 5 15/37% greater than X
A)
Question: A can do 50% more work as B can do in the same time. B alone can do a piece of work in 20 hours. A, with help of B, can finish the same work in how many hours ?
A.12
B.8
C.13 1⁄3
D.51⁄2
Answer: B.8
Explanation: B alone can do a work in 20 hours.
∴ A alone can do 3⁄2 of the work in 20 hours.
i.e., A alone can do the same work in 40⁄3 hours
∴ (A + B)’s one hour’s work = 3⁄40 + 1⁄20 = 5⁄40 = 1⁄8
⇒ A and B together can finish the whole work in 8 hours.
Answer B
Question: When a number is divided by 31, the remainder is 29. When the same number is divided by 16, what will be the remainder?
A.11
B.13
C.15
D.Data inadequate
Answer: D.Data inadequate
Explanation: Number= (31 * Q)+ 29.
Given data is inadequate.
ANSWER:D
Question: Speed of a boat in standing water is 8 kmph and the speed of the stream is 6 kmph. A man rows to place at a distance of 210 km and comes back to the starting point. The total time taken by him is:
A.120 hours
B.240 hours
C.160 hours
D.480 hours
Answer: A.120 hours
Explanation: Sol.
Speed upstream = 2 kmph; Speed downstream = 14 kmph.
∴ total time taken = [210/2 + 210/2] hours = 120 hours.
Answer A
Question: SCORE INTERVAL----------------NUMBER OF SCORES
50-59-------------------------- 2
60-69--------------------------10
70-79--------------------------16
80-89--------------------------10
90-99--------------------------18
The table above shows the distribution of test scores for a group of management trainees. Which score interval contains the median of the 28 scores?
A.39
B.28th(50-79)
C.32
D.34
Answer: B.28th(50-79)
Explanation: Total scores= 2+10+16+10+18 =56, which is odd, therefore the median is the Floor(56/2)= 28th score. And the 37th score is in the 80-89 range, because 50-79 only reference 28 scores.
B
Question: Light glows for every 18 seconds . How many times did it between 1:57:58 and 3:20:47 am
A.281
B.277
C.283
D.384
Answer: B.277
Explanation: the diff in sec between 1:57:58 and 3:20:47 is 4969 sec, 4969/18 = 276.
so total 277 times light ll glow
ANSWER:B
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1344?
A.1200
B.2777
C.2889
D.27670
Answer: A.1200
Explanation: 1344 = P [1 + (5*12/5)/100]
P= 1200.Answer:A
Question: If the average marks of two sections of 40 and 45 students respectively is 75 and 60, then the average marks of all the students is:
A.53.33
B.67.05
C.75
D.None of these
Answer: B.67.05
Explanation: Explanation :
Required average = (40 x 75 + 45 x 60)/(40 + 45)
= (3000 + 2700)/85
= 5700/85
= 67.05
Answer : B
Question: A rectangular field has a length 10 meters more than it is width. If the area of the field is 231, what is the length (in meters) of the rectangular field?
A.21
B.23
C.25
D.27
Answer: A.21
Explanation: area = l * w = (L) * (L-10) = 231
trial and error:
20*10 = 200 (too low)
21*11 = 231
The length is 21 meters.
The answer is A.
Question: A manufacturing plant produces 2 products (hats and gloves). 25% of all products are colored red, the remaining products are colored blue. If the ratio of products made is 3:4, respectively, and the percentage of hats colored red is 55%, what percentage of gloves are colored blue?
A.87%
B.90.5%
C.97.5%
D.55.5%
Answer: C.97.5%
Explanation: Let H and G be number hats and gloves, and r and b represent red and blue, respectively.
H + G = total products.
H:G = 3:4
Hr/H = 55%
Gb/G = 100% - Gr/G = ?
[(3)(Hr/H) + (4)(Gr/G)]/(3 + 4) = 25%
[(3)(55%) + (4)(Gr/G)]/7 = 25%
Gb/G = 100% - 2.5% = 97.5%
Answer: C
Question: Let a, b, c, d and e be distinct integers such that (6-a)(6-b)(6-c)(6-d)(6-e) = 45. What is a+b+c+d+e?
A.5
B.17
C.25
D.27
Answer: C.25
Explanation: Since the prime factorization is 3*3*5
The constraint in the question is that they are distinct so the only possible way is 3,-3,5,1,-1
6-a = 3 => a=3
6-b = -3 => b=9
6-c = 5 => c=1
6-d = 1 => c=5
6-e = -1 => e = 7
Answer is C = 25
Question: In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?
A.2.5
B.2.6
C.2.9
D.2.1
Answer: A.2.5
Explanation: Speed = 144 * 5/18 = 40 m/sec
Time taken = 100/40 = 2.5 sec.
Answer: A
Question: Lisa plays a dice game in which she rolls two, fair, six-sided dice two times. If her second roll matches her first roll, she wins. What is the probability that she wins if her first roll was 10?
A.1/6
B.5/36
C.1/9
D.1/12
Answer: D.1/12
Explanation: There are 3 ways to roll a 10 with two six-sided dice: 4 and 6, 6 and 4, 5 and 5. You only count 5 and 5 once.
There are 6*6=36 ways to roll two six-sided dice. Thus the probability of rolling a 10 is 3/36 = 1/12.
D
Question: Car A leaves the airport at 9:00 am and travels at a constant rate of 30 km per hour. Car B leaves the airport at 9:30 am and travels in the same direction along the same highway at a constant rate of 35 km per hour. At what time will Car B be 20 km ahead of Car A?
A.4:00 pm
B.4:30 pm
C.5:00 pm
D.5:30 pm
Answer: B.4:30 pm
Explanation: At 9:30 am, Car A will be 15 km ahead of Car B.
Car B travels at a rate 5 km per hour faster than Car A.
Car B needs to travel 35 km more than Car A in order to be 20 km ahead.
This will take 35 km/5 km per hour=7 hours.
Car B will be 20 km ahead at 4:30 pm.
The answer is B.
Question: A single letter is drawn at random from the word."ASPIRATION", the probability that it is a vowel is?
A.1/2
B.1/3
C.1/4
D.1/5
Answer: A.1/2
Explanation: ASPIRATION
vowels= AIAIO= 5
total alphabets = 10
so the probability is 5/10 = 1/2
ANSWER:A
Question: If a 4-member subcommittee is to be formed from a certain 9-member committee, how many different such subcommittee are possible?
A.6
B.18
C.20
D.126
Answer: D.126
Explanation: Another way:
1st member can be selected in 9 ways
2nd can be selected in 8 ways
3rd can be selected in 7 ways
4th can be selected in 6 ways
So total ways : 3024
But to avoid the similar scenarios 3024/4!=126
D
Question: There are 408 boys and 264 girls in a school which are to be divided into equal sections of either boys or girls alone. Find the total number of sections thus formed.
A.28
B.32
C.35
D.30
Answer: A.28
Explanation: Explanation:
HCF (408, 264) = 24
The number of boys or girls that can be placed in a section = 24.
Thus the total number of sections is given by
408/24+264/24 =17+11 = 28
Answer: A
Question: A 5 litre jug contains 4 litres of a salt water solution that is 15 percent salt. If 1.5 litres of the solution spills out of the jug, and the jug is then filled to capacity with water,approximately what percent of the resulting solution in the jug is salt?
A.7.5%
B.8.5%
C.9.5%
D.10.5%
Answer: A.7.5%
Explanation: A 5 litre jug contains 4 litres of a salt water solution that is 15 percent salt. If 1.5 litres of the solution spills out of the jug,then 2.5 ltrs of solution with 15% salt is left in jug.
If solution is now increased to 5 ltrs, the volume is doubled, then salt percentage is halved to 7.5%.
ANSWER:A
Question: Diya finished 2/3 of a book. She calculated that she finished 70 more pages than she has yet to read. How long is her book?
A.A)210
B.B)150
C.C)130
D.D)90
Answer: A.A)210
Explanation: Let x be the total number of pages in the book, then she finished 2/3*x pages.
Then she has x−2/3*x=1/3*x pages left.
2/3*x−1/3*x=70
1/3*x=70
x=210
So the book is 210 pages long.
Answer is A.
Question: Four cups of water are to be poured into a 2-cup bottle and a 4-cup bottle. If each bottle is to be filled to the same fraction of its capacity, how many cups of water should be poured into the 4-cup bottle?
A. 2/3
B. 8/3
C. 5/2
D. 7/3
Answer: B. 8/3
Explanation: Let x be the # of cups going into the 4 cup bottle.
so.... x/4 = ((4-x)/2)
16 - 4x = 2x
16 = 6x
x = 8/3.
Answer : B
Question: Of the 5 numbers, whose average is 200, the first is one-fourth of the sum of the last 4. The first number is?
A.200
B.80
C.78.63
D.56.98
Answer: A.200
Explanation: Total of 5 numbers = 5 * 200 = 1000
Let total of last 4 numbers = x
1st number = x/4
x+ x/4 = 1000
5x = 4000 => x = 800
1st number = 800/ 4 = 200
Answer : A
Question: P takes twice as much time as Q or thrice as much time as R to finish a piece of work. They can finish the work in 2 days if work together. How much time will Q take to do the work alone?
A.4
B.5
C.6
D.7
Answer: C.6
Explanation: Explanation :
Let P takes x days to complete the work
Then Q takes x/2 days and R takes x/3 days to finish the work
Amount of work P does in 1 day = 1/x
Amount of work Q does in 1 day = 2/x
Amount of work R does in 1 day = 3/x
Amount of work P,Q and R do in 1 day = 1/x + 2/x + 3/x = 1/x (1 + 2 + 3) = 6/x
6/x = 2
=> x = 12
=> Q takes 12/2 days = 6 days to complete the work
Answer : Option C
Question: A boat has to travel upstream 20 km distance from point X of a river to point Y. The total time taken by boat in travelling from point X to Y and Y to X is 41 minutes 40 seconds. What is the speed of the boat?
A.66 km/hr
B.72 km/hr
C.48 km/hr
D.Data inadequate
Answer: D.Data inadequate
Explanation: Let x be the speed of the boat.
and y the speed of the current.
20/x−y+20/x+y=25/36
In this equation there are two variables, but only one equation, so, the value of ‘x’ cannot be determined.
Answer D
Question: In a partnership between A, B and C. A's capital is Rs.5000. If his share of a profit of Rs.800 is Rs.200 and C's share is Rs.130, what is B's capital?
A.11750
B.28882
C.27789
D.11750
Answer: D.11750
Explanation: 200 + 130 = 330
800 - 330 = 470
200 ---- 5000
470 ---- ? => 11750
Answer: D
Question: The average age of a group of 5 members is 20 years. Two years later, a new member joins the group. The average age of the group becomes 24 years. What is the age of the new member ?
A.20 years
B.21 years
C.22 years
D.34 years
Answer: D.34 years
Explanation: The average age of the 5 members is 20 years
=> The sum of the ages of the 5 members is 20*5 = 100 years
Once the new member joins, the average age becomes 24 years.
Let the age of the new member be x.
Then (110+x)/6 = 24
=> x = 34 years
Answer D
Question: If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 5:7 then find the largest number?
A.38
B.40
C.42
D.44
Answer: B.40
Explanation: 2:3
2x + 10 : 3x + 10 = 5 : 7
7[2x + 10] = 5[3x + 10]
14x + 70 = 15x + 50
15x - 14x = 70 - 50
x = 20
Then the first number is = 2
2x = 40
B
Question: how many such letters pairs are in word SERVANT having same no. of letters left between them in the word as they have in the series
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: 2 pairs.S-V,S-N
ANSWER:B
Question: A boat can travel with a speed of 16 km/hr in still water. If the rate of stream is 5 km/hr, then find the time taken by the boat to cover distance of 105 km downstream.
A.4 hours
B.5 hours
C.6 hours
D.7 hours
Answer: B.5 hours
Explanation: Explanation:
It is very important to check, if the boat speed given is in still water or with water or against water. Because if we neglect it we will not reach on right answer. I just mentioned here because mostly mistakes in this chapter are of this kind only.
Lets see the question now.
Speed downstream = (16 + 5) = 21 kmph
Time = distance/speed = 105/21 = 5 hours
Option B
Question: The compound interest accrued on an amount of Rs.44000 at the end of two years is Rs.1193.60. What would be the simple interest accrued on the same amount at the same rate in the same period?
A.Rs.10577
B.Rs.10528
C.Rs.10560
D.Rs.10512
Answer: C.Rs.10560
Explanation: Let the rate of interest be R% p.a.
4400{[1 + R/100]2 - 1} = 11193.60
[1 + R/100]2 = (44000 + 11193.60)/44000
[1 + R/100]2 = 1 + 2544/1000 = 1 + 159/625
[1 + R/100]2 = 784/625 = (28/25)2
1 + R/100 = 28/25
R/100 = 3/25
Therefore R = 12 SI on Rs.44000 at 12% p.a. for two years = 44000(2)(12)/100
=Rs.10560
Answer:C
Question: On 7th Nov, 2003 Friday falls. What day of the week was it on 7th Nov, 2002?
A.Tuesday
B.Wednesday
C.Thursday
D.Friday
Answer: C.Thursday
Explanation: Explanation:
7th Nov 2003 – 7th Nov 2002 = 52 weeks 1 day. So Nov 7th 2002 is behind one day = Thursday
Answer: C
Question: If x = 3 - t and y = 4t + 13, then for what value of t are x and y equal?
A.-1
B.-2
C.-(1/2)
D.-(1/4)
Answer: B.-2
Explanation: Explanation:
If x = y
=> 3 - t = 4t + 13
=> 5t = -10 => t = -2
Answer: Option B
Question: Each of the integers from 1 to 16 is written on the a seperate index card and placed in a box. If the cards are drawn from the box at random without replecement, how many cards must be drawn to ENSURE that the product of all the integers drawn is even?
A.9
B.12
C.11
D.10
Answer: A.9
Explanation: Out of the 16 integers: 8 are odd and 8 are even.
If we need to make sure that the product of all the integers withdrawn is even then we need to make sure that we have at least one even number. In the worst case:
1. we will end up picking odd numbers one by one, so we will pick all 8 odd numbers first
2. 9th number will be the first even number
So we need to withdraw at least 9 numbers to make sure that we get one even number and the product of all the integers picked is even.
So, answer will be 9. (A)
Question: Which of the following is the Highest Common Factor of 25, 40 and 20?
A.8
B.5
C.6
D.14
Answer: B.5
Explanation: COMMON FACTOR IS 5Ans is :B
Question: A and B began business with Rs.3000 and Rs.4000 after 8 months, A withdraws Rs.1000 and B advances Rs.1000 more. At the end of the year, their profits amounted to Rs.630 find the share of A?
A.240
B.209
C.279
D.270
Answer: A.240
Explanation: (3*8 + 2*4):(4*8 + 5*4)
8:13
8/21 * 630
= 240
Answer: A