RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A car travells the first 1/3 of certain distance with a speed of 7km/hr the next 1/2 distance witha a speed of 12 km/hr, and the last 1/4 distance with a speed of 16 km/hr. the average speed of the carfor the whole journey is?
A.9.53km/hr
B.56.89km/hr
C.8.96km/hr
D.7.96km/hr
Answer: A.9.53km/hr
Explanation: Let the whole distance travelled be x km
and the average speed of the car for he whole journey be y km/hr
then (x/3)/7+(x/2)/12+(x/4)/16=x/y
x/21+x/24+x/64=x/y
y=9.53km/hr
Answer(A)
Question: Mr. Suresh is on tour and he has 360 for his expenses. If he exceeds his tour by 4 days he must cut down daily expenses by 3. The number of days of Mr. Suresh’s tour programme is :
A.20 days
B.24 days
C.40 days
D.42 days
Answer: A.20 days
Explanation: Let Suresh undertakes a tour of x days.
Then, expenses for each day = 360⁄x
now, 360/x+4=360/x−3
or 360(1/x−1/x+4)=33
or x2 + 4x - 480 = 0 or x = – 24 or x = 20
Since, x ≠ -24 we have x = 20
Answer A
Question: Lindsay can paint 1/x of a certain room in 40 minutes. What fraction of the same room can Joseph paint in 40 minutes if the two of them can paint the room in an hour, working together at their respective rates?
A.2/3x
B.3x/(x – 3)
C.(2x – 3) / 3x
D.1/ (x – 3)
Answer: C.(2x – 3) / 3x
Explanation: Lindsey and Joseph together can paint the room in 1 hour
in 40 mins they can paint 2/3 part of the room.
Lindsay alone paints 1/x part of the room in 40 mins
Take Joseph paints 1/y parts in 40 mins
1/x + 1/y = 2/3
1/y = 2/3 - 1/x = (2x-3)/3x ANs C
Question: If a stationery store owner buys 50% more identically-priced calendars than she usually purchases, she will be given a 20% discount off the standard price. Her total cost would then be 120 times the dollar value of the standard price of one calendar. How many calendars does she usually purchase?
A.40
B.80
C.100
D.120
Answer: C.100
Explanation: Let the Price is x per item
and the final number of items she bought is y items
So to buy y items , the cost will be .8x (80% of original price , since there is a 20% discount on it)
120*x = y*0.8*x
Solving we get y =150
now to get the discount she bought 50% more than what she usually buys
So the number of items she usually buys is 50% less than 150
i.e. original number of items she usually buys is = 150*(100/150) = 100
Hence Answer is (C)
Question: A woman has three blouses of different colors, five skirts of different colors, and two different pairs of shoes. She refuses to wear her pink blouse with her green skirt. How many different blouseskirt-shoe combinations could she wear?
A.8
B.12
C.28
D.17
Answer: C.28
Explanation: total ways = 3*5*2=30..
now its better to find the ways in which the pink blouse and green skirt are together and subtract from total to get the answer..
the ways in which the pink blouse and green skirt are together=1*1*2=2..
total ways =30-2=28..
ANSWER:C
Question: A combustion reaction forms carbon dioxide. A carbon dioxide molecule contains one carbon and two oxygen atoms. If, over a period of 12 minutes, a combustion reaction creates 12,000 molecules of carbon dioxide then approximately how many more atoms of oxygen than carbon are created on average per minute?
A.20
B.60
C.600
D.1,000
Answer: D.1,000
Explanation: Solution:
12,000 carbon dioxide molecules are created over a period of 12 minutes. Therefore 12,000/12 = 1,000 carbon dioxide molecules are created on average per minute
Each carbon dioxide molecule contains one carbon atom and two oxygen atoms. So 1,000 carbon dioxide molecules contain 1 × 1,000 = 1,000 carbon atoms and 2 × 1,000 = 2,000 oxygen atoms. The difference is 2,000 – 1,000 = 1,000.
The correct answer is D.
Question: In a dice game, a player wins if he rolls the same number on his second roll as he rolls on his first. If Jason rolls a total of 4 on the first roll, what is the probability that he wins on his next roll? In this game, each roll is made with 2, fair, six-sided dice.
A.1/6
B.1/9
C.1/12
D.1/15
Answer: C.1/12
Explanation: There are 3 ways to roll a 4: 1 and 3, 3 and 1, and 2 and 2.
There are 6*6=36 ways to roll two dice.
Thus the probability of rolling a 4 is 3/36 = 1/12
C
Question: A group consists of 4 men, 6 women and 4 children. In how many ways can 2 men , 3 women and 1 child selected from the given group?
A.400
B.480
C.287
D.278
Answer: B.480
Explanation: Explanation:
Two men, three women and one child can be selected in â´Câ‚‚ * â¶Câ‚ƒ * âµCâ‚ ways
= (4 * 3)/(2 * 1) * (6 * 5 * 4)/(3 * 2) * 4
= 480 ways.
Answer:B
Question: A positive number when decreased by 4 is equal to 21 times the reciprocal of the number. The number is:
A.2
B.5
C.9
D.7
Answer: D.7
Explanation: Let the number be x
x-4=21/x
x^2 - 4x -21=0
(x-7)(x+3)=0
x=7
correct answer D
Question: If P(A) = 1/5 and P (B) = 2/5, find P (A n B) if A and B are independent events.
A.7/25
B.3/25
C.8/25
D.2/25
Answer: D.2/25
Explanation: P (A n B) = P(A) . P(B)
P (A n B) = 1/5 . 2/5
P (A n B) = 2/25.
D
Question: A man invested Rs. 4455 in Rs. 10 shares quoted at Rs. 8.25. If the rate of dividend be 12%, his annual income is:
A.233
B.648
C.366
D.266
Answer: B.648
Explanation: Explanation:
Number of shares = = 540.
Face value = Rs. (540 x 10) = Rs. 5400.
Annual income = = Rs. 648.
Answer: B) 648
Question: The greatest common factor of two positive integers is P. The least common multiple of these two integers is Y. If one of the integers is Z, what is the other?
A.PY⁄Z
B.XZ + YZ
C.X⁄Z + Y
D.X + Y⁄Z
Answer: A.PY⁄Z
Explanation: Say other integer is W
Formula
GCF(WZ)*LCM(WZ) = W*Z
P*Y = W*Z
So W= PY/Z
Answer A
Question: The average of four consecutive even numbers is 27. Find the largest of these numbers.
A.28
B.30
C.32
D.34
Answer: B.30
Explanation: Given:
Consider the consecutive even numbers as : x, (x + 2), (x + 4) and (x+ 6)
Average =	Sum of Quantities/Number of Quantities
=	[x + (x + 2) + (x + 4) + (x + 6)] /4=	(4x + 12) /4	= 27
Simplifying we get, x = 24
Therefore,
Largest number = (x + 6) = (24 + 6) = 30
Smallest number = 24
ANSWER IS B
Question: A man can row upstream at 25 kmph and downstream at 35 kmph, and then find the speed of the man in still water?
A.86
B.67
C.30
D.15
Answer: C.30
Explanation: US = 25
DS = 35
M = (35 + 25)/2
= 30
Answer: C
Question: The length and breadth of a rectangle is increased by 10% and 25% respectively. What is the increase in the area?
A.37.2%
B.37.5%
C.57.5%
D.37.4%
Answer: B.37.5%
Explanation: 100 * 100 = 10000
110 * 125 = 13750
-----------
3750
10000 ------ 3750
100 ------- ? => 37.5%
27. The side of a rhombus is 2
Answer: B
Question: Find the least number which when divided by 26, 36 and 46 leaves the remainders 12, 22 and 32 respectively.
A.10570
B.10750
C.17050
D.10075
Answer: B.10750
Explanation: Explanation:
The difference between any divisor and the corresponding remainder is 14,
L.C.M of 26,36,46 -14
= 10764-14
= 10750
Answer: Option B
Question: When 6 fair coins are tossed simultaneously, in how many outcomes will the first and the last coin turn up heads?
A.1
B.3
C.16
D.31
Answer: C.16
Explanation: Total outcome is 2^6 = 64
Favourable cases = H_ _ _ _ H
The second, third, fourth and fifth places can be occupied by either H or T
There are 2^4 =16 ways that can be done.
Hence, the correct option is C
Question: Six years ago Ram was P times as old as Shyam was. If Ram is now 17 years old, how old is Shyam now in terms of P ?
A.11/P + 6
B.P/11 +6
C.17 - P/6
D.17/P
Answer: A.11/P + 6
Explanation: let's call Shyam's age six years ago is x
so six years ago Ram was: 17-6 = 11 years old
and six years ago Ram was P times as old as Shyam was
=> 11/x = P
=> x = 11/P
=> Now Shyam's age will be : x+6 = 11/P+6
=> the answer is A
Question: The present age of a father is 3 years more than three times the age of his son.Three years hence,father as age will be 12 years more than twice the age of the son.Find the present age of the father.
A.88
B.39
C.33
D.44
Answer: B.39
Explanation: Explanation:
Let the present age be 'x' years. Then father's present age is 3x+3 years. Three years hence (3x+3)+3=2(x+3)+12 x=12 Hence father's present age = 3x+3 =[ (3 x 12) + 3] = 39 years.
Answer: B
Question: If x is the interest on y and y is the interest on z, the rate and time is the same on both the cases. What is the relation between x, y and z?
A.9810
B.1002
C.2799
D.1000
Answer: D.1000
Explanation: (x*5*1)/100 + [(2500 - x)*6*1]/100
= 140
X = 1000
Answer:D
Question: A rower can row upstream at 7 km/hr and downstream at 14 km/hr. What is the rower's rate in still water?
A.9.5 km/hr
B.10.0 km/hr
C.10.5 km/hr
D.11.0 km/hr
Answer: C.10.5 km/hr
Explanation: The rate in still water is 1/2 * (14 + 7) = 10.5 km/hr
The answer is C.
Question: How many even number in the range between 10 to 160 inclusive are not divisible by 3
A.15
B.30
C.51
D.63
Answer: C.51
Explanation: We have to find the number of terms that are divisible by 2 but not by 6( as the question asks for the even numbers only which are not divisible by 3)
For 2,
10,12,14...160
using AP formula, we can say 160 = 10 + (n-1) *2
or n=76.
For 6,
12,18,...156
using AP formula, we can say 156 = 12 + (n-1) *6
or n=25.
Hence, only divisible by 2 but not 3 =76-25 = 51. hence, Answer C
Question: Edward's home have 3 taps,One tap, working alone at its maximum constant rate, can fill a certain sink in 270 seconds.A second tap working alone at its maximum constant rate, can fill a certain sink in 274 seconds. A third tap, working alone at its maximum constant rate, can fill the same sink in 276 seconds. If all taps work together at their respective maximum constant rates, the time it will take to fill the sink is closest to
A.91 seconds
B.102 seconds
C.177 seconds
D.200 seconds
Answer: A.91 seconds
Explanation: Tap 1 : 270 secs
Tap 2 : 274 secs
Tap 3:276 secs
Considering the average of these 3 taps : 273.33 secs.
So 1 tap can fill the tank in 273.33 secs, so 3 taps can fill the tank in 273.33/3 = 91.11 secs.
Closest answer is A.
Question: The average age of a family of 6 members is 26 years.If the age of the youngest member is 10 years,what was the average age of the family at the birth of the youngest member?
A.15
B.18
C.16
D.12
Answer: C.16
Explanation: Present age of total members = 6 X 26 = 156
10 yrs back their ages were = 6 x 10 = 60
Ages at the birth of youngest member = 156 - 60 = 96
Therefore, avg age at the birth of youngest member = 96/6 = 16.
ANSWER:C
Question: What amount does Kiran get if he invests Rs. 16000 at 15% p.a. simple interest for four years?
A.29893
B.27773
C.25600
D.28800
Answer: C.25600
Explanation: Simple interest = (16000 * 4 * 15)/100 = Rs. 9600
Amount = P + I = 16000 + 9600 = Rs. 25600
Answer: C
Question: The average of five numbers id 27. If one number is excluded, the average becomes 25. What is the excluded number?
A.30
B.40
C.32.5
D.35
Answer: D.35
Explanation: Explanation:
Sum of 5 numbers = 5 × 27
Sum of 4 numbers after excluding one number = 4 × 25
Excluded number
= 5 × 27 - 4 × 25
= 135 - 100 = 35
Answer: Option D
Question: A rectangular mat has an area of 120 sq.metres and perimeter of 46 m. The length of its diagonal is:
A.19m
B.17m
C.15m
D.16m
Answer: B.17m
Explanation: rectangular area = l × b = 120 and perimeter = 2(l+b) = 46
l+b = 23
(l-b)power2 - 4lb = (23)power2 - 4 × 120 = (529-480) = 49 = l-b = 7
l+b = 23, l-b = 7, we get l = 15, b = 8
Diagonal = √152+82
√225+64 => √289 = 17m
Answer is B.
Question: If x and y are different integers and x^2 = xy, which of the following must be true ?
I. x = y
II. y = 0
III. x = 0
A.I only
B.II only
C.III only
D.I and III only
Answer: C.III only
Explanation: Answer choice A is correct.
The question gives you x^2=xy
you can simplify that as x^2-xy=0
x(x-y)=0 the solution will be either x=0 or x=y, since x and y are different integers x cannot equal y, that leaves you x=0 to be the only answer.
Answer C
Question: If (2 to the x) - (2 to the (x-2)) = 3 (2 to the 10), what is the value of x?
A.9
B.11
C.13
D.12
Answer: D.12
Explanation: (2 to the power x) - (2 to the power (x-2)) = 3 (2 to the power 10)
2^x - 2^(x-2) = 3. 2^10
Hence x = 12.
Answer is D
Question: The price of an item is discounted 10 percent on day 1 of a sale. On day 2, the item is discounted another 10 percent, and on day 3, it is discounted an additional 25 percent. The price of the item on day 3 is what percentage of the sale price on day 1?
A.28%
B.67.5%
C.64.8%
D.70%
Answer: B.67.5%
Explanation: original price = 100
day 1 discount = 10%,price = 100-10 =90
day 2 discount = 10%,price = 90-9=81
day 3 discount = 25%,price = 81-20.25= 60.75
which is 60.75/90 *100 of the sale price on day 1= ~67.5%
Answer B
Question: A can do a work in 6 days. B can do the same work in 8 days. Both A&B together will finish the work and they got $1000 from that work. Find their shares?
A.600,400
B.600,800
C.300,700
D.800,200
Answer: B.600,800
Explanation: Ratio of their works A:B = 6:8
Ratio of their wages A:B = 3:4
A's share = (3/5)1000 = 600
B's share = (4/5)1000 = 800
correct option is B
Question: John read the quarter of the time that Tom read. Tom read only two-fifth of the time that Sasha read. Sasha read twice as long as Mike. If Mike read 5 hours, how long did John read?
A.1 hour
B.2 hour
C.3 hour
D.4 hour
Answer: A.1 hour
Explanation: Mike read 5 hours. Sasha read twice as long as Mike. Hence Sasha read:
2 ? 5 = 10 hours
Tom read two-fifths of the time that Sasha read. Hence Tom read:
(2 / 5) ? 10 = 4 hours
John read the quarter of the time that Tom read. Hence John read:
(1 / 4) ? 4 = 1 hour
correct answer A
Question: A circular ground whose diameter is 34 metres, has a 2 metre-broad garden around it. What is the area of the garden in square metres?
A.226.3
B.226.2
C.228.2
D.227
Answer: A.226.3
Explanation: Req. area = Ï€[(19)2 â€“ (17)2]
= 22â„7 Ã— (36 Ã— 2)[since a2 - b2 = (a + b)(a - b)]
= (22 Ã— 36Ã— 2)/7 = 226.3sq m
Answer A
Question: What is the least number of square tiles required to pave the floor of a room 15 m 17 cm long and 9m 2 cm broad?
A.724
B.804
C.814
D.844
Answer: C.814
Explanation: Solution
Length of largest tile = H.C.F. of 1517cm & 902cm = 41cm.
Area of each tile = (41 x 41)cm2
∴ Required number of tiles	= [1517x902/41x41]
= 814.
Answer C
Question: In May Mrs Lee's earnings were 30 percent of the Lee family's total income. In June Mrs Lee earned 20 percent more than in May. If the rest of the family's income was the same both months, then, in June, Mrs Lee's earnings were approximately what percent of the Lee family's total income ?
A.34
B.67
C.85
D.25
Answer: A.34
Explanation: Lets say the Family Income is 100
In May, lee earned 30Family income is 70
In june, Lee earned 20% more than May, so it is (30+20*30/100 = 36)
Family Income is same 70
In June Lee's Income percent is 36*100/106 ~ 34
Ans is A
Question: The average speed of a car is 1 4/5 times the avg speed of a bike. A tractor covers 575km in 25hrs. How much distance will the car cover in 4hrs if the speed of the bike is twice speed of the tractor?
A.400 km
B.500 km
C.331.2 km
D.550 km
Answer: C.331.2 km
Explanation: Sol. Average speed of a tractor = 23 km / h
The speed of a bus in an hour = 23 × 2 = 46 km
The speed of a car in an hour = 9/5 * 46 = 82.8 km
So, the distance covered by car in 4 h is
82.8 × 4 = 331.2 km
Ans.(C)
Question: The distance between stations A and B is 148 km. An express train left station A towards station B with the speed of 80 km/hr. At the same time, a freight train left station B towards station A with the speed of 36 km/hr. They met at station C at 12 pm, and by that time the express train stopped at at intermediate station for 10 min and the freight train stopped for 5 min. Find:
a) The distance between stations C and B.
b) The time when the freight train left station B.
A.12.17
B.10.35
C.29.28
D.12.32
Answer: B.10.35
Explanation: a) Let x be the distance between stations B and C. Then the distance from station C to station A is (148−x)(148−x) km. By the time of the meeting at station C, the express train travelled for 148−x80+1060148−x80+1060 hours and the freight train travelled for x36+560x36+560 hours. The trains left at the same time, so: 148−x80+16=x36+112148−x80+16=x36+112. The common denominator for 6, 12, 36, 80 is 720. Then
9(148−x)+120=20x+609(148−x)+120=20x+60
1332−9x+120=20x+601332−9x+120=20x+60
29x=139229x=1392
x=48x=48. Therefore the distance between stations B and C is 48 km.
b) By the time of the meeting at station C the freight train rode for 4836+5604836+560 hours, i.e. 11 hour and 2525 min.
Therefore it left station B at 12−(1+2560)=10+356012−(1+2560)=10+3560 hours, i.e. at 10:35 am.
Answer:B
Question: Find the compound interest and the amount on Rs.8000 at 5% per annum for 3 years when C.I is reckoned yearly?
A.Rs.1261
B.Rs.1440
C.Rs.1185
D.Rs.1346
Answer: A.Rs.1261
Explanation: A = 8000(21/20)3
= 9261
= 8000
---------
1261
ANSWER:A
Question: Riya and Priya set on a journey. Riya moves eastward at a speed of 21kmph and Priya moves westward at a speed of 22 kmph.How far will be priya from Riya after 60 minutes
A.43kms
B.45kms
C.50kms
D.30kms
Answer: A.43kms
Explanation: total eastward distance= 21kmph*1hr=21 km
total westward distance= 22kmph*1hr=22 km
total distn betn them= 21+22=43km
ans 43km
ANSWER:A
Question: What percent of 5 letter combinations that can be made from the letters of the word DERMONT and in which each letter can be used only once are the combinations in which the first letter is a vowel and the last letter is a consonant?
A.23.8%
B.24%
C.25%
D.30.2%
Answer: A.23.8%
Explanation: a) no of combinations when all 5 letters are different = 7*6*5*4*3
b) no of combinations when first letter is vowel and last is consonant = 2c1*5c1*5*4*3
b/a = 5/21= 0.238
A
Question: Each of three investments has a 20% of becoming worthless within a year of purchase, independently of what happens to the other two investments. If Simone invests an equal sum J in each of these three investments on January 1, the approximate chance that by the end of the year, she loses no more than 1/3 of her original investment is
A.90%
B.80%
C.70%
D.60%
Answer: A.90%
Explanation: The problem asks for the approximate chance that no more than 1/3 of the original investment is lost. We can apply the “1 – x” technique: what’s the chance that more than 1/3 of the original investment is lost? There are two outcomes we have to separately measure:
(a) All 3 investments become worthless.
(b) 2 of the 3 investments become worthless, while 1 doesn’t.
Outcome (a): The probability is (0.2)(0.2)(0.2) = 0.008, or a little less than 1%.
Outcome (b): Call the investments X, Y, and Z. The probability that X retains value, while Y and Z become worthless, is (0.8)(0.2)(0.2) = 0.032. Now, we have to do the same thing for the specific scenarios in which Y retains value (while X and Z don’t) and in which Z retains value (while X and Y don’t). Each of those scenarios results in the same math: 0.032. Thus, we can simply multiply 0.032 by 3 to get 0.096, or a little less than 10%.
The sum of these two probabilities is 0.008 + 0.096 = 0.104, or a little more than 10%. Finally, subtracting from 100% and rounding, we find that the probability we were looking for is approximately 90%.
The correct answer is A.
This problem illustrates the power of diversification in financial investments. All else being equal, it’s less risky to hold a third of your money in three uncorrelated (independent) but otherwise equivalent investments than to put all your eggs in one of the baskets. That said, be wary of historical correlations! Housing price changes in different US cities were not so correlated—and then they became highly correlated during the recent housing crisis (they all fell together), fatally undermining spreadsheet models that assumed that these price changes were independent.
Question: A rectangular lawn of dimensions 70 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
A.A)3600
B.B)930
C.C)9309
D.D)3900
Answer: A.A)3600
Explanation: Explanation:
Area = (l + b – d) d
(70 + 60 – 10)10 => 1200 m2
1200 * 3 = Rs.3600
Answer: Option A
Question: The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?
A.432 sq m
B.356 sq m
C.452 sq m
D.428 sq m
Answer: A.432 sq m
Explanation: 2(3x + x) = 96
l = 36 b = 12
lb = 36 * 12 = 432
ANSWER:A
Question: A Man can row upstream at 65kmph and downward stream at 47 kmph. Find Man's rate of the current
A.87km/hr
B.20km/hr
C.9km/hr
D.2.8km/hr
Answer: C.9km/hr
Explanation: Rate of the current=1/2(65-47)km/hr
=9km/hr
correct option is :C
Question: If 5x = 7y and xy ≠ 0, what is the ratio of 1/5*x to 1/6*y ?
A. 25/6
B. 42/25
C. 6/5
D. 5/6
Answer: B. 42/25
Explanation: 5x = 7y => x/y = 7/5
1/5*x to 1/6*y = x/y * 6/5 = (7/5)*(6/5)=42/25
Ans: B
Question: 3/[(1/0.03) + (1/0.37)] = ?
A.0.004
B.0.08333
C.2.775
D.3.6036
Answer: B.0.08333
Explanation: Approximate.
1/.03 = 100/3 = 33
1/.37 = 100/37 = 3
Denominator becomes 33 + 3 = 36
3/36 = .08 something
Answer (B)
Question: What amount does Kiran get if he invests Rs. 18000 at 15% p.a. simple interest for four years?
A.228777
B.26788
C.26088
D.28800
Answer: D.28800
Explanation: Simple interest = (18000 * 4 * 15)/100 = Rs. 10800
Amount = P + I = 18000 + 10800 = Rs. 28800
Answer: D
Question: Two-third of two-fifth of three-fourth of a number is 36. What is the square root of four-fifth of that number?
A.9
B.12
C.14
D.16
Answer: B.12
Explanation: Explanation:
We have, 2/3 * 2/5 * 3/4 * X = 36
X = 180
Now, 4/5 * X ===> 4/5 * 180 = 144
√144 = 12
ANSWER B
Question: How many halves are there in two-fourth?
A.8
B.1
C.32
D.7
Answer: B.1
Explanation: divide 2/4 by 1/2
=2/4÷1/2
=2/4*2/1
=4/4
=1.
Answer is B.
Question: If 213 × 16 = 3408, then 1.6 × 213.0 is equal to :
A.0.3408
B.3.408
C.34.08
D.340.8
Answer: D.340.8
Explanation: Solution
1.6 × 21.3 = (16/10x 213)= (16x 213/10) = 3408/10 = 340.8. Answer D
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 42 years now, the son's age five years back was:
A.14
B.16
C.19
D.22
Answer: B.16
Explanation: Let the son's present age be x years. Then, (42 - x) = x
2x = 42.
x = 21.
Son's age 5 years back (21 - 5) = 16 years.
answer :B
Question: How many cuboids of length 6 m, width 4 m and height 3 m can be farmed from a cuboid of 18 m length, 15 m width and 2 m height.
A.2.6
B.5.8
C.6.2
D.7.5
Answer: D.7.5
Explanation: (18 Ã— 15 Ã— 2)/(6 Ã— 4Ã— 3) = 7.5
Answer is D.
Question: Find the least number of complete years in which a sum of money put out at 50% compound interest will be more than double of itself?
A.2
B.3
C.4
D.5
Answer: A.2
Explanation: 2 years
Answer: A
Question: If C:D = 2:5 and D:F = 4:7 then C:D:F is
A.8:20:35
B.6:20:35
C.8:20:33
D.8:22:35
Answer: A.8:20:35
Explanation: Solution:
C/D = 2/5;
D/F = 4/7;
C:D:F = 2*4:5*4:5*7 = 8:20:35.
Answer: Option A
Question: When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.45, what is the value of y?
A.96
B.75
C.48
D.20
Answer: D.20
Explanation: Guys, one more simple funda.
5/2= 2.5
now .5 x2 =1 is the remainder
25/4 = 6.25
now .25x4=1 is the remainder
32/5=6.4
now.4x5 = 2 is the remainder
given x/y = 96.45 and remainder is 9
So .45 X y = 9
hence y= 20
Ans D
Question: John has 6 friends who want to ride in his new car that can accommodate only 3 people at a time (John plus 2 passengers). How many different combinations of 2 passengers can be formed from John's 6 friends?
A.3
B.8
C.10
D.15
Answer: D.15
Explanation: 6C2 = 15
The answer is D.
Question: A Train requires 5 seconds to pass a pole while it requires 25 seconds to cross a stationary train which is 360 mtrs long. Find the speed of the train.
A.66.8 kmph
B.65.8 kmph
C.54.8 kmph
D.64.8 kmph
Answer: D.64.8 kmph
Explanation: In 5s the train crosses the pole and in 25 sec the train crosses one more stationary train
In 20 sec the train travels a distance of 360 mtrs
Speed = 360/20 = 18 m/s = 18 (3600/1000) = 18 * 18/5 = 64.8 kmph
Answer: D
Question: 20% of a number is more than 20% of 650 by 190. Find the number?
A.288
B.278
C.800
D.1600
Answer: D.1600
Explanation: (20/100) * X â€“ (20/100) * 650 = 190
1/5 X = 320
X = 1600
Answer:D