RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Two men Amar and Bhavan have the ratio of their monthly incomes as 6:5. The ratio of their monthly expenditures is 3:2. If Bhavan saves one-fourth of his income, find the ratio of their monthly savings?
A.3:19
B.3:10
C.3:12
D.3:11
Answer: B.3:10
Explanation: Let the monthly incomes of Amar and Bhavan be 6x and 5x respectively.
Let the monthly expenditures of Amar and Bhavan be 3y and 2y respectively.
Savings of Bhavan every month = 1/4 (5x)
=(his income) - (his expenditure) = 5x - 2y
=> 5x = 20x - 8y => y = 15x/8
Ratio of savings of Amar and Bhavan
= 6x - 3y : 1/4 (5x) = 6x - 3(15x/8) : 5x/4
= 3x/8 : 5x/4 => 3:10
Answer:B
Question: Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is -.
A.5/12
B.4/13
C.5/17
D.3/12
Answer: A.5/12
Explanation: Using question number 11 and 12, we get the probability as
1 - (1/36 + 5/9) = 5/12
ANSWER A
Question: 16* 16 * 16 * 16 * 16 = 4^ ?
A.8
B.6
C.10
D.4
Answer: C.10
Explanation: 4^2 * 4^2 * 4^2 * 4^2 * 4^2 = 4^(2 +2+2+2+2) = 4^10
Answer : 10
Option : C
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 52, the dividend is:
A.6832
B.6814
C.6816
D.6812
Answer: D.6812
Explanation: Divisor = (5 * 52) = 260
= 10 * Quotient = Divisor
=> Quotient = 260/10 = 26
Dividend = (Divisor * Quotient) + Remainder
Dividend = (260 * 26) + 52 = 6812.
D
Question: There are 20 poles with a constant distance between each pole. A car takes 25 second to reach the 12th pole. How much will it take to reach the last pole.
A.43.1543
B.43.1818
C.43.45128
D.43.41288
Answer: B.43.1818
Explanation: Assuming the car starts at the first pole.
To reach the 12th pole, the car need to travel 11 poles (the first pole doesn't count, as the car is already there).
11 poles 25 seconds
1 pole (25/11) seconds
To reach the last (20th) pole, the car needs to travel 19 poles.
19 pole 19 x (25/11) seconds
= 43.1818 seconds
Answer:B
Question: For an employee to qualify for early retirement at a certain company, the sum of the employee’s age and years of service must be at least 65, If Sue was K years old when she was hired by the company, what is the minimum age at which she could possibly qualify for early retirement.
A.K+35
B.2K+35
C.(70+K)/2
D.(65+K)/2
Answer: D.(65+K)/2
Explanation: Say Sue was hired when she was already 65 years old (k=65), then she could retire right away, at the age of 65. Now, plug k=65 in the answer choices and see which yields 65. Only C fits.
Answer: D.
Question: 2 no's are respectively 40% & 60% more than 3rdnumber. Find the ration of two numbers ?
A.3 : 4
B.4 : 5
C.7 : 8
D.8 : 9
Answer: C.7 : 8
Explanation: Step 1: Let the third number is A
Then first number is 140% of A = 140 x A / 100 = 7A / 5 and second number is 160% of B = 160 x B / 100 = 8B /5.
Step 2: now ratio of first and second number is 7A / 5 : 8B / 5 = 35A : 40B = 7 : 8.
C
Question: An alloy of copper and aluminum has 40% copper. An alloy of Copper and Zinc has Copper and Zinc in the ratio 2:7. These two alloys are mixed in such a way that in the overall alloy, there is more aluminum than Zinc, and copper constitutes x% of this alloy. What is the range of values x can take?
A.30% ≤ x ≤ 40%
B.32.5% ≤ x ≤ 40%
C.32.5% ≤ x ≤ 42%
D.33.33% ≤ x ≤ 40%
Answer: A.30% ≤ x ≤ 40%
Explanation: The maximum aluminium you can have is when you mix copper and aluminium alloy (say alloy A) with infinitesimally small amount of copper and zinc alloy (alloy B). In that case, you will have almost 40% of copper in the mix (because alloy A has 40% of copper). So x% < 40%.
Minimum case:
60% of alloy A > (7/9) of alloy B
A/B > 35/27
If the two alloys are mixed in this ratio, the copper concentration will be:
Using weighted average:
Cavg = (2/5 * 35 + 2/9 * 27)/(35 + 27)
Cavg = (14 + 6)/62= 20/62 = 32.26% (rounded to 2 decimal places)
So x% > 32.26%
Answer: 32.26 < x < 40
ANSWER:A
Question: 10 men can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 men and 10 children take to complete the work?
A.4
B.7
C.3
D.5
Answer: B.7
Explanation: 1 man's 1 day's work = 1
70
1 child's 1 day's work = 1
140
(5 men + 10 children)'s day's work = 5 + 10 = 1 + 1 = 1
70 140 14 14 7
5 men and 10 children will complete the work in 7 days.
Correct Answer is B
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?
A.20/6 hours
B.27/2 hours
C.30 hours
D.30/13 hours
Answer: D.30/13 hours
Explanation: Speed downstream = 20 + 6 = 26 kmph.
Time required to cover 60 km downstream = d/s = 60/26 = 30/13 hours
ANSWER:D
Question: Kamal started a business with Rs.25000 and after 4 months, Kiran joined him with Rs.60000. Kamal received Rs.58000 including 10% of profit as commission for managing the business. What amount did Kiran receive?
A.75000
B.70000
C.72000
D.78000
Answer: C.72000
Explanation: Explanation :
Ratio of the profits = 25000*12 : 60000*8
= 25*12 : 60*8 = 5*3 : 12:2 = 5 : 4*2
= 5:8
Let the total profit = x.
Then Kamal received 10x/100 = x/10 as commission for managing the business
Remaining profit = x- x/10 = 9x/10 which is shared in the ration 5:8
Kamal's share = x/10 + (9x/10) * (5/13) = 58000
=> x + 9x(5/13) = 580000
=> x(1 + 45/13) = 580000
=> x ( 58/13) = 580000
=> x ( 1/13) = 10000
=> x = 130000
Kiran's share = 130000 - 58000 = 72000. Answer : Option C
Question: How many arrangements of the letters of the word BEGIN can be made, without changing the place of the vowels in the word?
A.6 ways
B.7 ways
C.9 ways
D.11 ways
Answer: A.6 ways
Explanation: E,I fixed. Consonants can be arrangements in 3P3 = 3! = 6 ways
A)
Question: In a division sum, the quotient is 120, the divisor 456 and the remainder 333, find the dividend?
A.55287
B.29887
C.27768
D.55053
Answer: D.55053
Explanation: Explanation:
120 * 456 + 333 = 55053
Answer: D
Question: 4 dice are thrown simultaneously on the board. Find the probability show the same face.
A.2/213
B.3/115
C.1/216
D.4/221
Answer: C.1/216
Explanation: The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:
=6×6×6×6=64=6×6×6×6=64
n(S)=64n(S)=64
Let XX be the event that all dice show the same face.
X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}
n(X)=6n(X)=6
Hence required probability,
=n(X)n(S)=664=n(X)n(S)=664
=1/216
C
Question: On a sum of money, the S.I. for 2 years is Rs. 660, while the C.I. is Rs. 696.30, the rate of interest being the same in both the cases. The rate of interest is?
A.23
B.28
C.12
D.11
Answer: D.11
Explanation: Explanation:
Difference in C.I. and S.I for 2 years = (696.30 - 660) = Rs. 36.30.
S.I for one year = Rs. 330.
S.I. on Rs. 330 for 1 year = Rs. 36.30
Rate = (100 * 36.30)/(330 * 1) = 11%
Answer: D
Question: There are 24 students in a seventh grade class. They decided to plant birches and roses at the school's backyard. While each girl planted 3 roses, every three boys planted 1 birch. By the end of the day they planted 24 plants. How many birches and roses were planted?
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: Let x be the number of roses. Then the number of birches is 24−x, and the number of boys is 3×(24−x). If each girl planted 3 roses, there are x3 girls in the class.
We know that there are 24 students in the class. Therefore x3+3(24−x)=24
x+9(24−x)=3⋅24
x+216−9x=72
216−72=8x
1448=x
x=18
So, students planted 18 roses and 24 - x = 24 - 18 = 6 birches.
So answer is D.
Question: Raj drives slowly along the perimeter of a rectangular park at 24 kmph and completes one full round in 4 min. If the ratio of length to bredth of the park is 3 : 2, what are the dimansions?
A.100 m x 109 m
B.100 m x 102 m
C.100 m x 120 m
D.100 m x 100 m
Answer: D.100 m x 100 m
Explanation: 24 kmph = 24×100060=40024×100060=400 m / min
In 4 minutes he covered 4 x 400 = 1600 m
This is equal to the perimeter 2 ( l + b) = 1600
But l : b = 3:2
Let l = 3k, b = 2k
Substituting, we get 2 ( 3k + 2k ) = 1600 => k = 180
So dimensions are 480 x 320
Answer:D
Question: How much interest will $10,000 earn in 3 months at an annual rate of 6%?
A.$250
B.$150
C.$450
D.$550
Answer: B.$150
Explanation: Soln:-
6 months = 1/4 of year;
6% = 6/100=3/50;
$10,000(principal)*3/50(interest rate)*1/4(time)=$150.
ANSWER:B
Question: A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 950gm. for a kg. His gain is …%.
A.5.3 %
B.8.2%
C.4.3%
D.8.3%
Answer: A.5.3 %
Explanation: He sells 950 grams of pulses and gains 50 grams.
If he sells 100 grams of pulses then he will gain (50 / 950) *100 = 5.26
4. A software engineer has the capability of thinking 100 lines of code in five minutes and can type 100 lines of code in 10 minutes. He takes a break for five minutes after every ten minutes. How many lines of codes will he complete typing after an hour?
Answer:A
Question: The average price of three items of furniture is Rs. 15000. If their prices are in the ratio 3:5:7, the price of the cheapest item is :
A.2348
B.3888
C.3988
D.9000
Answer: D.9000
Explanation: Explanation:
Let their prices be 3x, 5x and 7x.
Then, 3x + 5x + 7x = (15000 * 3) or x = 3000.
Cost of cheapest item = 3x = Rs. 9000.
Answer: D) 9000
Question: The respective ratio between the angles of a quadrilateral is 1 : 2 : 3 : 4. What is the sum of the twice the smallest angle and half the largest angle together?
A.22
B.77
C.62
D.22
Answer: B.77
Explanation: Answer:B
Question: Last year’s receipts from the sale of greeting cards during the week before Mother’s Day totaled $234 million, which represented 6 percent of total greeting card sales for the year. Total greeting card sales for the year totaled how many million dollars?
A.17,010
B.2,100
C.3,900
D.1,701
Answer: C.3,900
Explanation: 6% ---- 234 millions
for 100% => ( 234 * 100% )/6% = 3900.
Option C.
Question: List I: 4, 8, 12, 16 List II: x,4, 8, 12, 16
A.5
B.4
C.3
D.10
Answer: D.10
Explanation: List I has even number of terms, thus its median is the average of two middle terms (when arranged in ascending/descending order), so median=(8+12)/2=10
List II has odd number of terms, thus its median is the middle term (when arranged in ascending/descending order). As no other number in the list equal to 10, then x=10.
Answer: D
Question: When a shop keeper sold 2/3 of an item, he got the cost price of the whole lot. What is the percentage of his profit?
A.33 1/8%
B.66 2/3%
C.25%
D.50%
Answer: D.50%
Explanation: Explanation:
If 2/3 of the cost of item amount to CP
Then the ½ of the cost of item amounts to gain
:. Profit percentage = 1 x 100/2 = 50%.
Answer: Option D
Question: John bought 9.25m of cloth for $416.25. Find the cost price per metre.
A.46
B.47
C.45
D.56
Answer: C.45
Explanation: Cloth bought by John = 9.25 m
Cost of 9.25 m = $416.25
Cost per metre = 416.25 ÷ 9.25
The cost of the cloth per metre = $ 45
Answers: C
Question: A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 3% of bananas were rotten. Find the percentage of fruits in good condition?
A.92.5%
B.89.8%
C.85.2%
D.96.8%
Answer: B.89.8%
Explanation: Total number of fruits shopkeeper bought = 600 + 400 = 1000
Number of rotten oranges = 15% of 600
= 15/100 × 600
= 9000/100
= 90
Number of rotten bananas = 3% of 400
= 12
Therefore, total number of rotten fruits = 90 + 12 = 102
Therefore Number of fruits in good condition = 1000 - 102= 898
Therefore Percentage of fruits in good condition = (898/1000 × 100)%
= (89800/1000)%
= 89.8%
Answer:B
Question: The number of circles that can be drawn out of 10 points of which 7 are collinear is
A.130
B.85
C.45
D.Cannot be determined
Answer: B.85
Explanation: Solution
For drawing a circle we need 3 non collinear points.This can be done in:
3C3 + 3C2 × 7C1 + 3C1 × 7C2 = 1 + 21 + 63 = 85.
Answer B
Question: A 25 cm wide path is to be made around a circular garden having a diameter of 4 meters. Approximate area of the path is square meters is
A.3.34
B.2
C.4.5
D.5.5
Answer: A.3.34
Explanation: Area of the path = Area of the outer circle - Area of the inner circle = ∏{4/2 + 25/100}2 - ∏[4/2]2
= ∏[2.252 - 22] = ∏(0.25)(4.25) { (a2 - b2 = (a - b)(a + b) }
= (3.14)(1/4)(17/4) = 53.38/16 = 3.34 sq m
ANSWER:A
Question: Evan ran a mile in 10 minutes Monday morning, and he ran the same mile in 8 minutes on Tuesday morning. On average, how many minutes did he take to run the mile over both days?
A.9
B.18
C.2
D.80
Answer: A.9
Explanation: (10 + 8)/2 = 9
The correct answer is A
Question: A double decked bus can accomodate 90 passengers,40 in the upper deck and 50 in the lower deck.In how many ways can the passengers be accomodated if 15 refuse to be in the upper deck while 10 others refuse to be in the lower deck?
A.1. 85!50!60!/40!45!
B.2. 65!/30!35!
C.3. 110!/50!60!
D.4. 110!50!60!/40!45!
Answer: B.2. 65!/30!35!
Explanation: 90 passengers,40 in the upper deck and 50 in the lower deck.
25 passengers have issues as 15 refuse to be in the upper deck while 10 others refuse to be in the lower deck
So those 15 will be put in lower deck and 10 will be in upper deck
So from the rest 65 passengers(90-25), we need to find 30 people to put into upper deck and the rest go to lower deck
So the ways are: C(65,30) = 65!/30!35! . Answer B
Question: What is the sum of the multiples of 4 between 53 and 145 inclusive?
A.2000
B.2200
C.2300
D.2450
Answer: C.2300
Explanation: the fastest way in an AP is to find the average and multiply with total integers..
between 53 and 145, the smallest multiple of 4 is 56 and largest =144..
average=(56+144)/2=100..
total numbers = (144-56)/4 + 1= 22+1=23..
sum=23*100=2300
ans C
Question: Let g(x) be a function such that g(x + 1) + g(x - 1) = g(x) for every real x. Then for what value of p is the relation g(x + p) = g(x) necessarily true for every real x?
A.7
B.2
C.6
D.87
Answer: A.7
Explanation: g(x + 1) + g(x - 1) = g(x)
g(x + 2) + g(x) = g(x + 1)
Adding these two equations we get
⇒⇒ g(x + 2) + g(x - 1) = 0
⇒⇒ g(x + 3) + g(x) = 0 (By substituting x = x+1)
⇒⇒ g(x + 4) + g(x + 1) = 0 (By substituting x = x+1)
⇒⇒ g(x + 5) + g(x + 2) = 0 (By substituting x = x+1)
⇒⇒ g(x + 6) + g(x + 3) = 0 (By substituting x = x+1)
⇒⇒ g(x + 6) - g(x) = 0 ( g(x+3) + g(x) = 0 ⇒⇒ g(x+3) = - g(x))
⇒⇒ g(x + 6) = g(x)
So for p = 6 the function is periodic.
Answer:A
Question: Ravi's 4days average income is 1025.68. But in a form he should write his average income as the greatest positive even integer less than or equal to his 4days average income. what is the difference between his real average and form filling average?
A.2
B.4.3
C.1.68
D.1.5
Answer: C.1.68
Explanation: Since Ravi's 4days average income for form filling is defined as the greatest positive even integer less than or equal to his avg income, then avg income for form filling =1024 (the greatest positive even integer less than or equal to 1025.68 is 1024).
Hence the difference = 1025.68 - 1024 = 1.68
Answer: C.
Question: 60% of a number is added to 120, the result is the same number. Find the number?
A.300
B.200
C.400
D.500
Answer: A.300
Explanation: (60/100) * X + 120 = X
2X = 600
X = 300
ANSWER:A
Question: Set S has a mean of 10 and a standard deviation of 1.5. We are going to add two additional numbers to Set S. Which pair of numbers would decrease the standard deviation the most?
A.{2, 10}
B.{10, 18}
C.{7, 13}
D.{9, 11}
Answer: D.{9, 11}
Explanation: Starting list has mean = 10 and standard deviation of 1.5.
(A) {2, 10} — these two don’t have a mean of 10, so adding them will change the mean; further, one number is “far away”, which will wildly decrease the mean, increasing the deviations from the mean of almost every number on the list, and therefore increasing the standard deviation. WRONG
B. {10, 18} — these two don’t have a mean of 10, so adding them will change the mean; further, one number is “far away”, which will wildly increase the mean, increasing the deviations from the mean of almost every number on the list, and therefore increasing the standard deviation. BTW, (A) & (B) are essentially the same change — add the mean and add one number eight units from the mean. WRONG
C. {7, 13} — centered on 10, so this will not change the mean. Both of these are a distance of 3 units from the mean, and this is larger than the standard deviation, so it increases the size of the typical deviation from the mean. WRONG
D. {9, 11} — centered on 10, so this will not change the mean. Both of these are a distance of 1 units from the mean, and this is less than the standard deviation, so it decreases the size of the typical deviation from the mean. RIGHT
E. {16, 16} — these are two values far away from everything else, so this will wildly increase the standard deviation. WRONG
Answer = D
Question: How many odd factors does 460 have?
A. 3
B. 4
C. 5
D. 6
Answer: B. 4
Explanation: Start with the prime factorization: 460 = 2*5*23
For odd factors, we put aside the factor of two, and look at the other prime factors.
set of exponents = {1, 1}
plus 1 to each = {2, 2}
product = 2*2 = 4
Therefore, there are 4 odd factors of 460.
Answer: B.
Question: A is thrice as good as B in work. A is able to finish a job in 60 days less than B. They can finish the work in - days if they work together.
A.18 days
B.22 ½ days
C.24 days
D.26 days
Answer: B.22 ½ days
Explanation: If A completes a work in 1 day, B completes the same work in 3 days
Hence, if the difference is 2 days, B can complete the work in 3 days
=> if the difference is 60 days, B can complete the work in 90 days
=> Amount of work B can do in 1 day= 1/90
Amount of work A can do in 1 day = 3 × (1/90) = 1/30
Amount of work A and B can together do in 1 day = 1/90 + 1/30 = 4/90 = 2/45
=> A and B together can do the work in 45/2 days = 22 ½ days
Answer : B
Question: The remainder obtained when a prime number greater than 5 is divided by 5 is
A.a) 1 or 2
B.b) 1 or 5
C.c) 3 or 5
D.d) 4 or 5
Answer: A.a) 1 or 2
Explanation: The easiest way to answer this question is probably to pick numbers. Use the next two prime numbers greater than 6, i.e. 7 and 11:
7/5 = 1 + remainder of 2
11 / 5 = 2 + remainder of 1
This is already sufficient to see that answer choice a) is correct.
A
Question: If x, y, and z are consecutive positive odd integers, not necessarily in that order, which of the following must be true? I. xy> z^4 II. (x + z)^4 > y III. x+y>z^4
A.II only
B.I only
C.III only
D.I,II only
Answer: A.II only
Explanation: Lets suppose that a,b,c can take any one of following three value 1,5,7. Most important point is that the options MUST BE TRUE under any condition.
x+y>z^4
Not necessarily true as 1+5<2401
xz>y^4
Not necessarily true as 1.7<625
We don't need to check option as all the options except A can be discarded.
Thus Answer A
Question: A sum is sufficient to pay either George age for 15 days or marks wage to 10dayshow long together?
A.4
B.5
C.6
D.7
Answer: C.6
Explanation: George one day work is (1/15)
Marks one day work is (1/10)
G+M=(1/15)+(1/10)=(1/6)
6 is the answer
ANSWER:C
Question: The average age of seven persons sitting in a row facing east is 28 years. If the average age of the first three persons is 21 years and the average age of the last three persons is 34 years, then find the age of the person sitting in the middle of the row?
A.31 years
B.78 years
C.27 years
D.11 years
Answer: B.78 years
Explanation: Total age seven persons = (28 * 7)years
Total age of the first three persons and the last three persons are (21 * 3) years and (34 * 3) years respectively.
Age of the person sitting in the middle of the row
= 28 * 7 - 21 * 3 - 34 * 3 = 196 - 63 - 102
= 31 years.
Answer: B
Question: The average (arithmetic mean) of the integers from 200 to 400, inclusive, is how much greater than the average of the integers from 100 to 200, inclusive?
A. 150
B. 175
C. 200
D. 225
Answer: A. 150
Explanation: For an AP the mean or average of series is average of first and last term.
So, average of numbers between 200 to 400, inclusive = (200+400)/2 = 300
average of numbers between 100 to 200, inclusive = (100+200)/2 = 150
difference = 300 - 150 = 150
Answer is A
Question: Six computers, each working at the same constant rate, together can process a certain amount of data in 12 days. How many additional computers, each working at the same constant rate, will be needed to process the same amount of data in 6 days?
A.3
B.5
C.6
D.9
Answer: C.6
Explanation: Explanation: If six computers require 12 days to process the data, thats
a total of 72 computer-days the product of 6 and 12. If you change the number
of computers or the number of days, 72 will have to remain the product, whether
that means 72 days of one computer or one day with 72 computers.
In 6 days, the number of computers is:
6c = 72
c = 12
12 computers is 6 more than the 6 that it took to do the job in 12 days, so
the correct choice is (C).
Question: If x and y are positive integers, which of the following CANNOT be the greatest common divisor of 5x and 20y?
A.5
B.5(x-y)
C.20x
D.20y
Answer: C.20x
Explanation: We are looking for a choice that CANNOT be the greatest common divisor of 5x and 20y ...which means 5x and 20y when divided by the answer choice the quotient should not be a integer.
lets check
a. 5 5x/5 = x and 20y/5 = 4y both are integers so eliminate
b. 5(x-y) when x = 2 and y = 1 it could be be the greatest common divisor ..so eliminate
c. 20x when x = 1 its 20 and 20 cannot be the greatest common divisor of 5x and 20y ...
or 5x/20x = 1/4 which is not a integer.
C
Question: If two distinct positive divisors of 128 are randomly selected, what is the probability that their sum will be less than 32?
A.2/5
B.3/7
C.5/14
D.11/28
Answer: C.5/14
Explanation: The positive divisors are 1, 2, 4, 8, 16, 32, 64, 128.
If any of the first five are chosen, the sum will be less than 32.
P(sum is less than 32) = 5/8 * 4/7 = 5/14
The answer is C.
Question: The average of 50 numbers is 38. If two numbers 45 and 55 are discarded, the average of the remaining set of numbers is
A.38.5
B.37.5
C.37.0
D.36.5
Answer: B.37.5
Explanation: Average of the remaining set of numbers
[50 x 38 - (45 + 55)] / (50 - 2)
= (1900 - 100) / 48
= 37.5
ANSWER:B
Question: A man bought 40 shares of Rs. 60 at 5 discount, the rate of dividend being 1212%The rate of interest obtained is
A.13.64%
B.15.5%
C.14%
D.14.25%
Answer: A.13.64%
Explanation: Explanation :
Face Value of a share = Rs.60
He bought each share at Rs.60 - Rs.5 = Rs.55
Number of shares = 40
Dividend = 12 1/2%=25/2%
Dividend per share = 60×25/2×100=Rs.7.5
Total dividend = (40 × 7.5)
ie, He got a dividend of (40 × 7.5) for an investment of Rs.(40 × 55)
Interest obtained = 40×7.5×100/40×55=13.64%
Answer : Option A
Question: If 42.30 = k(14 + m/50), where k and m are positive integers and m < 50, then what is the value of k + m ?
A.6
B.7
C.8
D.9
Answer: C.8
Explanation: 42.30 = 14K + Km/50...we can rewrite the number as follows:
42+ 0.30= 14K + Km/50........Since K is integer, then 42=14K..........K=3
0.30=Km/50......40/100=3m/50......m=5
k+m=3+5=8
Answer: C
Question: There are 3 teams each with 5 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?
A.50
B.23
C.75
D.28
Answer: C.75
Explanation: There are altogether three arrangements, which are we can select two members each from team A and B, each from team A and C, and each from team B and C. For each arrangement, there are altogether 25 possibilities (5*5) since each team has 5 players. So there are a total of 75 possibilities (25*3).
ANSWER:C
Question: If Jenee earns a raise of between 5% and 10%, non-inclusive, by what fraction could her salary have increased?
A.1/4
B.1/5
C.1/10
D.3/50
Answer: D.3/50
Explanation: Perhaps it is also easy to just translate the % into fractions:
6%: 6/100 = 3/50
7%: 7/100
8%: 8/100 = 4/50 =2/25
9%: 9/100
Only 3/50 exists in the answer choices, so ANS D
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:
A.10
B.18
C.36
D.72
Answer: A.10
Explanation: Let the speed of the train is x
Realtive speed between the trains =2x
time =12
distance=240
2x=240/12
2x=20
x=10 km/hr ANSWER:A