RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If f(a)=3a+6, what is the value of (f(2a)+f(a)) ?
A.2a-4
B.8a-7
C.9a+5
D.8a+12
Answer: D.8a+12
Explanation: f(a)=3a+6
f(2a)= 5a+6
(f(2a)+f(a)) = 5a+6+3a+6 = 8a+12
Answer is D
Question: Sum of 53 odd numbers is?
A.2709
B.2809
C.2909
D.3009
Answer: B.2809
Explanation: sum of 1st n odd no.s = 1+3+5+7+... = n^2
so, Sum of 1st 53 odd numbers = 53^2 = 2809
ANSWER:B
Question: Given that 2x + 11 > 5 and 5x - 13 < 7, all values of x must be between which of the following pairs of integers?
A.-4 and -1
B.-1 and 4
C.-4 and 1
D.-3 and 4
Answer: D.-3 and 4
Explanation: 2x + 11 > 5
i.e 2x >5-11
i.e. 2x > -6
i.e. x > -3
Also, 5x - 13 < 7
i.e. 5x <7+13
i.e 5x < 20
i.e x < 4
i.e. -3 < x < 4
Answer: Option D
Question: On dividing 136 by a number, the quotient is 9 and the remainder is 1. Find the divisor?
A.A)12
B.B)15
C.C)16
D.D)17
Answer: B.B)15
Explanation: d = (D-R)/Q
= (136 - 1)/9
= 135/9 = 15
B)
Question: The ratio of number of boys and girls in a school is 3:2. If there are 100 students in the school, find the number of girls in the school?
A.25
B.30
C.35
D.40
Answer: D.40
Explanation: Let the number of boys and girls be 3x and 2x
Total students = 100
Number of girls in the school = 2*100/5 = 40
Answer is D
Question: A train speeds past a pole in 15 seconds and a platform 150 meters long in 25 seconds. What is the length of the train (in meters)?
A.205
B.215
C.225
D.235
Answer: C.225
Explanation: Let the length of the train be x meters.
The speed of the train is x / 15.
Then, x + 150 = 25*(x / 15)
10x = 2250
x = 225 meters
The answer is C.
Question: -64x29+165=?
A.2436
B.2801
C.-2801
D.-1601
Answer: D.-1601
Explanation: Given exp.=-64x(30-1)+165
=-(64x30)+64+165
=-1830+229
=-1601
Answer is D
Question: Which of the following CANNOT be a product of two distinct positive integers r and s?
A.r
B.s
C.3s + 2r
D.s - r
Answer: D.s - r
Explanation: In these questions it is best to take an example as if something is true for all positive integers than it as to be true for the smallest and the easiest integers to work with
take r = 1 and s = 2 and work with the options
rs = 2
A) r take r =2, s = 1
B) s take r = 1 s = 2
C) 3s + 2r Seems tricky, lets see other options and then come back to it.
D) s - r take s = 1 and r = 2 --> s - r = -1 .. How the hell can product of two positive integers be negative ?? or less than each of them?
E) sr Always true
You don't even have to worry what C is !
ans D
Question: Three friends are buying a gift for a friend. Declan contributes 4 dollars more than 1/4 the cost of the gift, Ed contributes 6 dollar less than 1/3 the cost of the gift, and Frank contributes the remaining 22 dollars. What is the cost of the gift?
A.48
B.54
C.60
D.66
Answer: A.48
Explanation: Declan = D, Ed = E, Frank = F
t = total
D + E + F = t
(t/4 + 4) + (t/3 - 6) + 22 = t
t = 20 + (7t/12)
12t = 20(12) + 7t
5t = 5*4(12)
t = 48
The correct answer is A.
Question: In how many different number of ways 5 boys and 2 girls can sit on a shopa which can accommodate persons?
A.190
B.210
C.220
D.230
Answer: B.210
Explanation: Option 'B'
7p3 = 7 × 6 × 5 = 210
Question: Find the greatest number which leaves the same remainder when it divides 25, 57 and 105.
A.23
B.28
C.18
D.16
Answer: D.16
Explanation: Explanation:
105 - 57 = 48
57 - 25 = 32
105 - 25 = 80
The H.C.F of 32, 48 and 80 is 16.
Answer: D
Question: A small, rectangular park has a perimeter of 560 feet and a diagonal measurement of 600 feet. What is its area, in square feet?
A.172,800
B.19,600
C.20,000
D.20,400
Answer: A.172,800
Explanation: you can avoid a lot of work in this problem by recognizing that, with the info provided, the diagonal forms a triangle inside the rectangle with sides that have a 3:4:5 ratio.
diagonal = 200
2x + 2y = 560, or x + y = 280
a^2 + b^2 = c^2 for each the sides of the triangle
using the ratio 3:4:5 for sides, and knowing c = 600, you can deduce the following
a=360
b=480
360x480=172,800
A is the answer.
Question: If the remainder is 3 when positive integer n is divided by 18, what is the remainder when n is divided by 6?
A.3
B.1
C.2
D.3
Answer: A.3
Explanation: Assume x is quotient here,
n=18x+3 ----------(1)
and n=6x+ ?
We can also write first term as
n=(18x+6) = 6(3x+1) +3
ie 6(3x+1)+3 ie the first term is perfectly divisible by 6.
So,the remainder left is 3.
So,answer (A) is right choice.
Question: Health insurance Plan W requires the insured to pay $1000 or 50% of total cost, whichever is lower. Plan B requires the insured to pay the initial $300, but then pays 80% of the cost over $300. Which of the following is a cost level for which both insurance plans pay out the same amount?
A.$600
B.$1000
C.$3800
D.$5300
Answer: B.$1000
Explanation: 0.5 * 600 = 300 where W = B.
Question: We have boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If we dispose of one blue box for one additional red box, the total number of berries would increase by 30, and the difference between the total number of strawberries and the total number of blueberries would increase by 100. Each blue box contains how many blueberries?
A.35
B.40
C.45
D.50
Answer: A.35
Explanation: Let x be the number of blueberries in each blue box.
Then there are x+30 strawberries in each red box.
x+(x+30)=100
x = 35
The answer is A.
Question: If three numbers in the ratio 3 : 2: 5 be such that the sum of their squares is 1862, the middle number will be
A.10
B.14
C.18
D.22
Answer: B.14
Explanation: Explanation:
Let the numbers be 3x, 2x and 5x.
Then,
9x + 4x + 25x =1862
⇒ 38x = 1862
⇒ x = 49 ⇒ x = 7.
middle number = 2x = 14
Option B
Question: Rahul went to a shop and bought things worth Rs. 24, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
A.18.7
B.20
C.22
D.21.4
Answer: A.18.7
Explanation: Total cost of the items he purchased = Rs.24
Given that out of this Rs.24, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 6%
∴ (24−30/100−x)6/100 = 30/100
⇒ 6(24 −0.3 −x) = 30
⇒ (24 − 0.3 − x) = 5
⇒ x = 24 − 0.3 − 5 = 18.7
A
Question: In measuring the sides of a rectangle,one side is taken 5% in excess,and the other 4% in deficit.Find the error percent in the error percent in the area calculated from these measurements.
A.0.8%
B.0.2%
C.0.4%
D.0.9%
Answer: A.0.8%
Explanation: Let x and y be the sides of the rectangle.Then,correct area =xy.
calculated area =(105/100* x)*(96/100* y)=504/500*xy.
Error in measurement =504/500* xy)-xy=4/500*xy.
Error % =[4/500*xy*1/xy*100]%=4/5=0.8%.
Answer is A
Question: There 3 kinds of books in the library physics, chemistry and biology. Ratio of physics to chemistry is 3 to 2; ratio of chemistry to biology is 4 to 3, and the total of the books is more than 3000. Which one of following can be the total E of the book?
A.3003
B.3027
C.3024
D.3021
Answer: A.3003
Explanation: First, you have to find the common ratio for all 3 books. You have:
P:C:B
3:2 --> multiply by 2 (gives you row 3)
4:6
6:4:3
Hence:
P:C:B:T(Total)
6:4:3:13 ----> This means, the Total Number E must be a multiple of 13.
Answer A is correct since 299 is divisible by 13, hence is 2990 and so is 3003 (2990+13).
Question: From the given equation find the value of x: x² − 3x + 2
A.1
B.3
C.2
D.5
Answer: C.2
Explanation: (x − 1)(x − 2)
x = 1 or 2.
C
Question: Train E and F, 455 miles apart, are traveling toward each other at constant rates and in the same time zone. If train E left at 4 pm traveling at a speed of 60 miles per hour, and train F left at 5:45 pm and traveling at 45 miles per hour, then at what time would they pass each other?
A.9.03pm
B.9.05pm
C.9.07pm
D.9.08pm
Answer: B.9.05pm
Explanation: First, since E has a headstart then in that 1hr45min or 1.75hrs he travels 105 miles
Then remaining distance to be traveled will be 455 - 105 = 350 miles
Now, using relative rates (105)(t) = 350
This gives 10/3 hours
Now 5.45pm + 10/3 hours gives us 9.05pm
Hence answer is B
Question: An athlete runs 200 metres race in 24 seconds. His speed is
A.20 km / hr
B.24 km /hr
C.28.5 km / hr
D.30 km / hr
Answer: D.30 km / hr
Explanation: Sol.
Speed = 200 / 24 m/sec = 25 / 3 m/sec
= (25/3 x 18 / 5) km / hr = 30 km / hr.
Answer D
Question: While playing a certain dice game, Chris wins if the sum of the two dice is 10, at which point the game is over. If the game allows Chris three rolls in an attempt to win, what is the probability that Chris will win?
A.1/2
B.17/36
C.190/827
D.11/36
Answer: C.190/827
Explanation: Probability of winning game = 1- Probability of losing game
Probability of losing game = (Probability of not getting sum 7 in any of the three attempts)
Ways of getting sum 10 = (4,6)(5,5)(6,4)= 3 ways
Total ways of getting outcome on two dice =6*6=36
Probability of getting sum as 10 in any attempt =3/36=1/12
Probability of NOT getting sum as 10 in any attempt = 1-(1/12)= 11/12
Probability of losing game =(11/12)*(11/12)*(11/12)=637/827
I.e. Probability of wining game = 1-(637/827) = 190/827
Answer : Option C
Question: If the ratio of the change in the book's price to its new price is 1 : 5, What is the % price increase?
A.25%
B.50%
C.75%
D.90%
Answer: A.25%
Explanation: Solution:-
Given
ratio of change in book price/ new price = 1 /5
=>(new price−old price)/new price=1/5
=> old price/new price=4/5 ---- equation 1
% increase is always with respect in the initial or old price.
=> % increase = (( new price - old price)/old price)*100---equation 2
substituting 1 in 2 we have
% increase = ((new−(4/5)new)/((4/5)new))∗100
= 25%
ANSWER:A
Question: If 4x+y=34, 2x-y=20, for integers of x and y, y^2=?
A.2
B.4
C.0
D.10
Answer: B.4
Explanation: 4x+y = 34
2x-y = 20
6x = 54
x = 9
y = -2
y^2 = 4
Answer is B
Question: A sum of $1162 is divided among A,B and C. Such that 4 times A's share share is equal to 5 times B's share and 7 times C's share . What is the share of C?
A.$ 280
B.$ 180
C.$ 260
D.$ 140
Answer: A.$ 280
Explanation: 4 times of A's share =5 times of B's share=7 times of C's share=1
therefore , the ratio of their share =1/4:1/5:1/7
LCM of 4,5,7=140
therefore,A’s¼:1/5:1/7=35:28:20
the ratio now can be written as 35:28:20
therefore C's share=(20/83)*1162=20*14=$ 280
ANSWER : A 280
Question: The average of first 10 odd numbers is?
A.11
B.average=10
C.18
D.12
Answer: B.average=10
Explanation: Explanation:
Sum of 10 odd no. = 100
Average = 100/10 = 10
Answer:B
Question: The events A and B are independent. The probability that event A occurs is x and the probability that event B occurs is y. Which of the following is equal to the probability that exactly one of the events A and B occurs?
A.x − 2xy
B.y − xy
C.x + y − 2xy
D.x + y − xy
Answer: D.x + y − xy
Explanation: Probability of A occuring = x , Probability of A NOT occuring = 1-x
Probability of B occuring = y , Probability of B not occurring = 1-y
Probability of atleast of one of A and B occuring = 1-(1-x)(1-y) =x+y -xy
D
Question: What will be the cost of gardening 1 meter boundary around a rectangular plot having perimeter of 340 meters at the rate of Rs. 10 per square meter ?
A.22887
B.3440
C.2777
D.2689
Answer: B.3440
Explanation: In this question, we are having perimeter.
We know Perimeter = 2(l+b), right
So,
2(l+b) = 340
As we have to make 1 meter boundary around this, so
Area of boundary = ((l+2)+(b+2)-lb)
= 2(l+b)+4 = 340+4 = 344
So required cost will be = 344 * 10 = 3440
Answer: B
Question: A man buys s cycle for $1400 and sells it at a loss of 15%. What is the selling price of the cycle?
A.$950
B.$1006
C.$1190
D.$1245
Answer: C.$1190
Explanation: S.P. = 85% of the $1400 = 85/100 * 1400 = $1190
Answer is C
Question: Let the number which when multiplied by 15 is increased by 280.
A.14
B.20
C.26
D.28
Answer: B.20
Explanation: Solution
Let the number be x .
Then, 15x - x = 280
‹=›14x = 280
x ‹=› 20.
Answer B
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 700 grams per kg, what is his percent?
A.11
B.25
C.77
D.42
Answer: D.42
Explanation: 700 --- 300
100 --- ? => 42%
Answer:D
Question: The length of a rectangle is halved, while its breadth is tripled. Wa tis the % changein area?
A.34%
B.45%
C.50%
D.60%
Answer: C.50%
Explanation: Let original length = x and original breadth = y.
Original area = xy.
New length = x .
2
New breadth = 3y.
New area = x x 3y = 3 xy.
2 2
Increase % = 1 xy x 1 x 100 % = 50%.
2 xy
C
Question: The ratio of money with Ram and Gopal is 7 : 17 and that with Gopal and Krishan is 7: 17. If Ram has Rs. 490, Krishan has ?
A.Rs. 2890
B.Rs. 2330
C.Rs. 1190
D.Rs. 1620
Answer: A.Rs. 2890
Explanation: Ram : Gopal = 7 : 17 = 49 : 119
Gopal : Krishan = 7 : 17 = 119 : 289
Ram : Gopal : Krishan = 49 : 119 : 289
Ram : Krishan = 49 : 289
Thus, 49 : 289 = 490 : N
&there N = 289 x 490 / 49
= Rs. 2890
Answer :A
Question: A starts business with Rs.3500 and after 8 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is Bâ€™s contribution in the Capital ?
A.24887
B.20778
C.23788
D.15750
Answer: D.15750
Explanation: Explanation:
A invested Rs.3500 for 12 months.
Let B joined with investment x. And he invested for 12 - 8 = 4 months.
So there profit ratio = (3500 Ã— 12) : (4x) = 2 : 3
â‡’ x = 15750
Answer: D
Question: The integer E has a tens digit of 6 and a units digit of 7. The units digit of integer y is 8. The product of E and y has a tens digit of 8. Which of the following is a possible tens digit of integer y?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: Let E be 67 and y be a8. Then the product of E and y can be written as (60+7)*(10a+8)=600a + 480+70a+56=600a+536+70a. Since 600a dose not affect on the tens digit we can ignore 600a.
So tens digit should be the unit of 3+7a. That means 3+7a =8, 18, 28, 38, 48 or 58 (since 3+7a<=3+7*9=66) --->7a=5, 15, 25, 35, 45, 55. So the only possibility is a=5.
So the answer is (C).
Question: If Ram and gohul can do a job in 10 days and 15 days independently, How many days would they take to complete the same job working simultaneously?
A.10
B.5
C.8
D.6
Answer: D.6
Explanation: If total work is X.
Ram working rate=X/10 per day.
Working rate of gohul=X/15 per day.
Rate of work=(X/10)+(X+15)=30X/5X=6 days
The answer is option D
Question: A dishonest dealer professes to sell goods at the cost price but uses a false weight and gains 25%. Find his false weight age?
A.176
B.289
C.887
D.278
Answer: C.887
Explanation: 25 = E/(1000 - E) * 100
1000 - E = 4E
1000 = 5E => E = 200
1000 - 200 = 800
Answer:C
Question: 12, 36, ?, 324, 972
A.108
B.125
C.215
D.312
Answer: A.108
Explanation: Series pattern
Every next element = 3 x previous element
∴ Missing term = 3 x 36 = 108 Answer : A
Question: Two consultants can type up a report in 12.5 hours and edit it in 7.5 hours. If Mary needs 30 hours to type the report and Jim needs 12 hours to edit it alone, how many R hours will it take if Jim types the report and Mary edits it immediately after he is done?
A.41.4
B.34.1
C.13.4
D.12.4
Answer: A.41.4
Explanation: Break down the problem into two pieces: typing and editing.
Mary needs 30 hours to type the report--> Mary's typing rate = 1/30 (rate reciprocal of time)(point 1 in theory below);
Mary and Jim can type up a report in 12.5and --> 1/30+1/x=1/12.5=2/25 (where x is the time needed for Jim to type the report alone)(point 23 in theory below)--> x=150/7;
Jim needs 12 hours to edit the report--> Jim's editing rate = 1/12;
Mary and Jim can edit a report in 7.5and --> 1/y+1/12=1/7.5=2/15 (where y is the time needed for Mary to edit the report alone) --> y=20;
How many R hours will it take if Jim types the report and Mary edits it immediately after he is done--> x+y=150/7+20=~41.4
Answer: A.
Question: A man saves Rs 400 at the end of each year and lends the money at 5% compound interest. How
much will it become at the end of 3 years.
A.Rs 662
B.Rs 1232.01
C.Rs 1324.05
D.Rs 1662.05
Answer: C.Rs 1324.05
Explanation: Explanation:
=[400(21/20×21/20×21/20)+400(21/20×21/20)+400(21/20)]= 1324.05
Answer: C
Question: To apply for the position of photographer at a local magazine, a photographer needs to include three or four photos in an envelope accompanying the application. If the photographer has pre-selected six photos representative of her work, how many choices does she have to provide the photos for the magazine?
A.35
B.36
C.40
D.42
Answer: A.35
Explanation: 6C3 + 6C4 = 20 + 15 = 35
The answer is A.
Question: John bought 2 shares and sold them for $98 each. If he had a profit of 20% on the sale of one of the shares but a loss of 20% on the sale of the other share, then on the sale of both shares John had
A. a profit of $10
B. a profit of $8
C. a loss of $4
D. a loss of $10
Answer: C. a loss of $4
Explanation: $ Profit of the share sold at 20% profit =
120-98
20-?
$18 profit on the sale of 1 share.
$ Loss of the share sold at 20% loss=
80-98
20-?
$22 loss on the sale of 1 share.
18-22=Loss of $4
Answer: C
Question: If each participant of a chess tournament plays exactly one game with each of the remaining participants, then 253 games will be played during the tournament. What is the number of participants?
A.21
B.22
C.23
D.24
Answer: C.23
Explanation: Let n be the number of participants.
The number of games is nC2 = n*(n-1) / 2 = 253
n*(n-1) = 506 = 23*22 (trial and error)
The answer is C.
Question: A credit card number has 6 digits (between 1 to 9 inclusive). The first two digits are 12 in that order, the third digit is bigger than 6, the fourth digit is divisible by 2, and the fifth digit is 3 times the sixth. How many different credit card numbers are possible?
A.18
B.24
C.36
D.48
Answer: C.36
Explanation: The first two digits are fixed.
The third digit can be 7, 8, or 9 so there are 3 choices.
The fourth digit can be 2, 4, 6, or 8 so there are 4 choices.
The fifth digit depends entirely on the sixth digit.
The sixth digit can be 1, 2, or 3 so there are 3 choices.
The number of possibilities is 3*4*3 = 36
The answer is C.
Question: 1+ 1+ 1+ 2 × 1^2 + 2 × 1^1+ 2 × 1^4 + 2 × 1^5 + 2 × 1^6 + 2 × 1^7 =
A. 1^7
B. 1^8
C. 1^14
D. 1^28
Answer: B. 1^8
Explanation: We have the sum of 9 terms. Now, if all terms were equal to the largest term 2*1^7 we would have: sum=9*(2*1^7)=2*1^9=~1^10, so the actual sum is less than 1^10 and more than 1^7 (option A) as the last term is already more than that. So the answer is clearly B.
Answer: B.
Question: Tough and Tricky questions: Word Problems.
It takes Sarah 20 minutes to do one oil change, and it takes Alice 12 minutes. If Sarah and Alice both begin doing oil changes at exactly 9:00 a.m. without pausing, when is the first time at which they will finish changing the oil of a car simultaneously?
A.10:00 a.m.
B.10:42 a.m.
C.12:00 a.m.
D.1:00 p.m.
Answer: A.10:00 a.m.
Explanation: LCM of 1220
12 = 2 * 2 * 3
20 = 2 * 2 * 5
LCM = 2 * 2 * 3 * 5 = 60 = 1 hour
1000AM
A
Question: The length of the bridge, which a train 130 m long and traveling at 45 km/hr can cross in 30 sec is?
A.188
B.166
C.245
D.777
Answer: C.245
Explanation: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (130 + x)/30 = 25/2
x = 245 m.
Answer: C
Question: A firm has 4 senior partners and 6 junior partners. How many different groups of 3 partners can be formed in which at least one member of the group is a senior partner. (2 groups are considered different if at least one group member is different)
A.48
B.100
C.120
D.288
Answer: B.100
Explanation: Total no of groups of 3 members (including junior and senior) = 10C3
Total no of groups of 3 members (only juniors) = 6C3
Total no of groups of 3 members (at least 1 senior) = 10C3 - 6C3 = 120 - 20 =100
ans:B
Question: Three 6 faced dice are thrown together. The probability that all the three show the same number on them is -
A.1/216
B.1/36
C.5/9
D.5/12
Answer: B.1/36
Explanation: Answer: Option B
It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36
Question: 10 solid colored balls in a box, including 1 Green and 1 Yellow. If 3 of the balls in the box are chosen at random, without replacement, what is the probability that the 3 balls chosen will include the Green ball but not the yellow ball.
A.1/6
B.7/30
C.1/4
D.3/10
Answer: B.7/30
Explanation: But we ARE told that there is is only 1 green ball and only 1 yellow ball in the box, becausethere are 10 solid colored balls in a box,including 1 Green and 1 Yellowmeans exactly that. How else?
Would it make ANY sense if there were for example 2 green balls and we were told thatthere are 10 solid colored balls in a box,including 1 Green and 1 Yellow?
Hmm.. yeah, that does make sense. I'm a non-native English speaker so I tend to over-analyze simple things. In this case, since the wordonlywas missing i.e. there are 10 solid colored balls in a box, includingexactly/only1 Green and 1 Yellow . But yeah, in retrospect this is a Quant question not a Verbal SCThanks for the explanation answer is B
Question: A 1.5 by 2 rectangle is inscribed in circle. What is the circumference of the circle?
A.2.5π
B.3π
C.3.5π
D.4π
Answer: A.2.5π
Explanation: The diagonal of the rectangle will be the diameter of the circle.
and perimeter= 2*pi*r
Ans: A
Question: A man takes 5hr 45min in walking to certain place and riding back. He would have gained 2hrs by riding both ways. The time he would take to walk both ways is?
A.7 hr 45 min
B.7 hr 15 min
C.6 hr 45 min
D.6 hr 15 min
Answer: A.7 hr 45 min
Explanation: Let x be the speed of walked
Let y be the speed of ride
Let D be the distance
Then D/x + D/y = 23/4 hr -------------------(1)
D/y + D/y = 23/4 – 2 hr
D/y = 15/8 ----------------------------------(2)
substitute 2 in 1
D/x + 15/8 = 23/4
D/x = 23/4 -15/8 =46-15/8 =31/8
Time taken for walk one way is 31/8 hr
time taken to walk to and fro is 2*31/8 = 31/4 hr
=7 hr 45 min
Answer : A.
Question: A man covered a certain distance at some speed. If he had moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. What is the distance in km?
A.36
B.38
C.40
D.42
Answer: C.40
Explanation: Explanation:
speed=2v1v2/v1−v2
=2×3×23−2=12 km/H=hr
distance =vt1(1+v/v1)
=12×40/60(1+12/3)=40 km
ANSWER IS C
Question: A particular store purchased a stock of turtleneck sweaters and marked up its cost by 20%. During the New Year season, it further marked up its prices by 25% of the original retail price. In February, the store then offered a discount of 10%. What was its profit on the items sold in February?
A.27.5%
B.30%
C.35%
D.37.5%
Answer: C.35%
Explanation: Assume the total price = 100x
Price after 20% markup = 120x
Price after 25%further markup = 1.25*120x = 150x
Price after the discount = 0.9*150x = 135x
Hence total profit = 35%
Option C
Question: A and B walk around a circular track. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. If they start at 8 a.m. from the same point in opposite directions, how many times shall they cross each other before 9.30 a.m.?
A.9.39 am
B.9.80 am
C.9.30 am
D.9.32 am
Answer: C.9.30 am
Explanation: Relative speed = Speed of A + Speed of B (∴ they walk in opposite directions)
= 2 + 3 = 5 rounds per hour
=> They cross each other 5 times in 1 hour and 2 times in 1/2 hour
Time duration from 8 am to 9.30 am = 1.5 hour
Hence they cross each other 7 times before 9.30 am
Answer : C
Question: If q<0, which of the following must be true?
A.–100 < q < 100
B.q ≤ –1
C.q ≤ 1
D.q^2 ≥ 1/4
Answer: C.q ≤ 1
Explanation: q is a negative number.
A. –100 < q < 100q can be a negative number less than -100
B. q ≤ –1q can be a fraction, in which case it would be greater than -1
C. q ≤ 1must be true since 1 is positive and q is negative
D. q^2 ≥ 1/4not true if m is a negative fraction like -1/5
E. –100 < q < 0q can be a negative number less than -100=C
Question: How many days will there be from 26th January,1996 to 15th May,1996(both days included)?
A.102
B.103
C.111
D.120
Answer: C.111
Explanation: Explanation:
Number of days from 26-Jan-1996 to 15-May-1996 (both days included)
= 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May) = 111
Answer: Option C