RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: How many integers Q are prime numbers in the range 200 < Q < 220?
A. 1
B. 2
C. 3
D. 4
Answer: A. 1
Explanation: My friend, every single odd number greater than can be written either as 4Q+1 or as 4Q+3. If you divide any odd number by 4, you will get a remainder of either 1 or 3. That's not a rule unique to prime numbers at all.
The 6Q+1 or 6Q-1 rule is basically every odd number that is not divisible by three, so it narrows the search a little.
Here's how I thought about the problem. First, eliminate all the even numbers and the odd multiples of 5 in that range. That leaves us with:
{201, 203, 207, 209, 211, 213, 217, 219}
Eliminate the four multiples of 3. Notice that 21 is a multiple of 3, so 210 is also a multiple of 3. If we add or subtract 3 or 9, we get more multiples of three. When we eliminate those, we are left with.
{203, 209, 211, 217}
Now, notice that a cool thing about this range is that 210 is also a multiple 7 (again, because 21 is a multiple of 7). This means that
210 - 7 = 203
210 + 7 = 217
Those two numbers are also multiples of 7, so eliminate them from the list. Now, we are left with
{209, 211}.
We've already checked all the prime numbers less than 10, so we know that neither of these numbers is divisible by anything less than 10. We have to check 11 now. We know that 22 is a multiple of 11, so 220 is also a multiple of 11. This means that
220 - 11 = 209
is also a multiple of 11. We can eliminate this from the list also.
That leaves us with just 211. There's no zero option in the question, so this must be a prime number.
Answer = (A)
Question: If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is:
A.80%
B.90%
C.50%
D.40%
Answer: C.50%
Explanation: Explanation:
Let C.P. of each pen be Re. 1.
Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.
Gain % = 4/8 * 100 = 50%
Answer:C
Question: A trader sold an article at a loss of 5% but when he increased the selling price by Rs.65 he gained 3.33% on the cost price. If he sells the same article at Rs. 936, what is the profit percentage?
A.23
B.22
C.20
D.28
Answer: C.20
Explanation: Explanation:
103.33 CP- 0.95 CP = 65
inline \Rightarrow CP = Rs. 780
profit (%) = \inline \frac{936-780}{780}\times 100 = 20%
Answer: C) 20%
Question: Machine A produces pencils at a constant rate of 9000 pencils per hour, and machine B produces pencils at a constant rate of 7000 pencils per hour. If the two machines to gather must produce 100,000 pencils and if each machine can operate for at most 8 hours, what is the least amount of time W, in hours, that machine B must operate?
A.4
B.4 2/3
C.5 1/3
D.6
Answer: A.4
Explanation: Machine A produces pencils at a constant rate of 9,000 pencils per hour, and machine B produces pencils at a constant rate of 7,000 pencils per hour. If the two machines together must produce 100,000 pencils and if each machine can operate for at most 8 hours, what is the least amount of time W, in hours, that machine B must operate?
a) 4
b) 4 and 2/3
c) 5 and 1/3
d) 6
e) 6 and 1/4
To minimize the time that machine B must operate we must maximize the time machine A can operate, so make it operate 8 hours. In 8 hours machine A will produce 8*9,000=72,000 pencils, so 100,000-72,000=28,000 pencils are left to produce, which can be produced by machine B in 28,000/7,000=4 hours.
Answer: A.
Question: A clock loses 5 min for every hour and another gains 5 min for every hour. If they are set correct at 10 am on Monday then when will they be 12 hrs apart ?
A.10 am on Thursday
B.10 am on Friday
C.10 am on Saturday
D.None of the above
Answer: A.10 am on Thursday
Explanation: Explanation :
For every hour watch A loses 5 min and watch B gains 5 min.
So for every hour they will differ by 10 min.
For 12 hrs (720 min) difference between them the time required = 720 / 10 = 72 hrs
So they will be 12 hrs apart after 3 days i.e., at 10 am on Thursday.
Answer : A
Question: Find the number of shares that can be bought for Rs.8200 if the market value is Rs.25 each with brokerage being 2.5%.
A.237
B.320
C.177
D.166
Answer: B.320
Explanation: Explanation:
Cost of each share = (25 + 2.5% of 25) = Rs.25.625
Therefore, number of shares = 8200/25.625 = 320
ANSWER:B
Question: The bankerâ€™s gain on a sum due 3 years hence at 12% per annum is Rs. 90. The bankerâ€™s discount is
A.Rs.340
B.Rs.840
C.Rs.1020
D.Rs.760
Answer: A.Rs.340
Explanation: Solution
T.D	=(B.G x 100 / R x T)
= Rs.(90x100/12 x 3)
= Rs.250.
B.D
=Rs(250+ 90)
= Rs.340.
Answer A
Question: What is the value of 18^2 + 19^2 + 20^2 + 21^2 + 22^2 ?
A.2010
B.2012
C.2016
D.2028
Answer: A.2010
Explanation: This is what I did, all the nos are close to 20, and squared, so 20^2 plus there are 5 numbers, so (20)^2 x 5 =2000,
now squaring the last digits of each no individually comes up to (4+1+0+1+4) = 10.
when you add the 2 up it gives you a (2000+10) =2010,
Answer is A
Question: If the price of 23 toys is 276, then what will the price of 12 toys ?
A.144
B.148
C.156
D.186
Answer: A.144
Explanation: Explanation:
Less toys, Less Price (Direct Proportion)
So, let the price be Rs. x
then,
23:12::276:x=>x=276∗12 /23
=>x=144
So price of 12 toys will be Rs. 144
Option A
Question: If a man buys 60 lollipops for $150 and sold them for $2 dollars each determine his loss.
A.$ 28
B.$ 35
C.$ 52
D.$ 30
Answer: D.$ 30
Explanation: Cost of 60 lollipops = $150
Sold each lollipop for $2
So he sold 20 lollipops for $(60 × 2) = $120
Loss = $(150 – 120) = $30
Therefore, loss = $ 30.
Answer:D
Question: Let f(x,y) be defined as the remainder when (x–y)! is divided by x. If x=50, what is the maximum value of y for which f(x,y)=0?
A.35
B.36
C.40
D.42
Answer: C.40
Explanation: The question is finding y such that (50-y)! is a multiple of 50. That means we need to have 2*5^2 in (50-y)!
10! is the smallest factorial number with 2*5^2 as a factor.
50-y = 10
y = 40
The answer is C.
Question: The speed of a car is 90 km in the first hour and 60 km in the second hour. What is the average speed of the car?
A.76 kmph
B.75 kmph
C.87 kmph
D.56 kmph
Answer: B.75 kmph
Explanation: S = (90 + 60)/2
= 75 kmph
Answer: B
Question: Two trains, each 100 meters long, moving in opposite directions, completely pass each other in 12 seconds. If one train is moving twice as fast the other, then what is the speed of the faster train (in km/hr)?
A.36 km/hr
B.40 km/hr
C.44 km/hr
D.48 km/hr
Answer: B.40 km/hr
Explanation: Let the speed of the slower train be x m/s
Then, the speed of the faster train is 2x m/s
The relative speed is 3x m/s
(100 + 100)/12 = 3x
x = 50/9
So, the speed of the faster train is 100/9 = 100/9 * 18/5 = 40 km/hr
The answer is B.
Question: In a school of 700 students, 45% wear blue shirts, 23% wear red shirts, 15% wear green shirts, and the remaining students wear other colors. How many students wear other colors (not blue, not red, not green)?
A.109
B.119
C.129
D.139
Answer: B.119
Explanation: 45 + 23 + 15 = 83%
100 – 83 = 17%
700 * 17/100 = 119
The answer is B.
Question: How many multiples of 7 are there between 21 and 343, inclusive ?
A.48
B.47
C.46
D.45
Answer: B.47
Explanation: 7 * 3 = 21
7 * 49 = 343
Total multiples = (49-3) + 1 = 47
Include 21 and 343 = 47
Answer is B
Question: Rs. 7800 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/2:1/3:1/4?
A.1878
B.1878
C.1999
D.1800
Answer: D.1800
Explanation: 1/2:1/3:1/4
= 6:4:3
3/13*7800
= 1800
Answer: D
Question: Two numbers are in the ratio 1:2, if 7 is added to both, their ratio changes to 3:5. The greatest number is
A.28
B.30
C.32
D.36
Answer: A.28
Explanation: Let the numbers be x and 2x
Then, (x+7)/(2x+7)=3/5
X=14
There fore answer is 28
ANSWER A
Question: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.85. How much was lent at 5% ?
A.500
B.287
C.288
D.122
Answer: A.500
Explanation: Let the lent at 5% be 'A'
(A x 5 x 1)/100 + [(1500 - A)x 6 x 1]/100 = 85
5A/100 + 90 – 6A/100 = 85
A/100 = 5
=> A = 500
Answer: A
Question: X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
A.11
B.10
C.99
D.87
Answer: B.10
Explanation: Work done by X in 4 days = (1/20 * 4) = 1/5
Remaining work = (1 - 1/5) = 4/5
(X + Y)'s 1 day work = (1/20 + 1/12) = 2/15
Now, 2/15 work is done by X and Y in 1 day.
So, 4/5 work will be done by X and Y in (15/2 * 4/5) = 6 days.
Hence, total time taken = (6 + 4) = 10 days.
Answer:B
Question: If 3 workers collect 48 kg of cotton in 4 days, how many kg of cotton will 9 workers collect in 2 days?
A.12 kg
B.88 kg
C.72 kg
D.99 kg
Answer: C.72 kg
Explanation: (3 * 4)/48 = (9 * 2)/ x
x = 72 kg
Answer: C
Question: Ravi can do a piece of work in 30 days while Prakash can do it in 40 days. In how many days will they finish it together?
A.17 1/7 days
B.27 1/7 days
C.23 2/7 days
D.16 4/11 days
Answer: A.17 1/7 days
Explanation: 1/30 + 1/40 = 7/120
120/7 = 17 1/7 days
ANSWER:A
Question: The volume of the sphere Q is (37/64)% less than the volume of sphere P and the volume of sphere R is (19/27)% less than that of sphere Q. By what is the surface area of sphere R less than the surface area of sphere P?
A.77.77%
B.75%
C.67.5%
D.87.5%
Answer: B.75%
Explanation: Explanation :
Let the volume of sphere P be 64 parts.
Therefore volume of sphere Q
=>64−(37/64)% of 64.
=>64−37=27 parts.
The volume of R is:-
=>27−(19/27)×27.
=>27−19=8 parts.
Volume ratio:
=>P:Q:R=64:27:8.
Radius ratio:
=>P:Q:R=4:3:2.
The surface area will be 16:9:5.
Surface area of R is less than the surface area of sphere P.
=>16k−4k=12k.
Now,
=>(12k/16k)×100.
=>75%.
Hence, the surface area of sphere R is less than the surface area of sphere P by 75%.
Answer : B
Question: Eight years ago, Ajay's age was 4/3 times that of Vijay. Eight years hence, Ajay's age will be 6/5 times that of Vijay. What is the present age of Ajay?
A.33
B.40
C.99
D.77
Answer: B.40
Explanation: Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively.
A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8)
3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8
V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8
=> 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8
=> 10 - 20/3 = 10/12 A - 9/12 A
=> 10/3 = A/12 => A = 40.
Answer: B:
Question: A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 10 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold?
A.4800
B.1200
C.1680
D.1100
Answer: B.1200
Explanation: 1/x - 1/20 = -1/24
x = 120
120 * 10 = 1200
Answer:B
Question: Jose completes a piece of work in 10 days, Raju completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is
A.5 days
B.6 days
C.8 days
D.10 days
Answer: C.8 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 × 40/50 = 8 days.
C)
Question: The equation of line m is y = 4/3*x - 100. What is the smallest possible distance in the xy-plane from the point with coordinates (0, 0) to any point on line m?
A.48
B.50
C.60
D.75
Answer: C.60
Explanation: This can be solve in two steps and without any complex calculation.
Given : equation of line m as y=(4/3)x -100. So the line intercept the axes at (0,-100) and (75,0).
This can be considered a right angle triangle with right angle at (0,0) . So Base=100 , Height=75 and Hypotenuse =125 (By Pythagoras triplet)
So a perpendicular from the (0,0) to hypotenuse will be the answer.
Area of triangle= 0.5*100*75=0.5*125* x
=> x=60;
SO answer is 60=C
Question: A retail appliance store priced a video recorder at 20 percent above the wholesale cost of $200. If a store employee applied the 15 percent employee discount to the retail price to buy the recorder, how much did the employee pay for the recorder?
A. $204
B. $216
C. $220
D. $230
Answer: A. $204
Explanation: Wholesale cost of video recorder = 200 $
Video recorder was priced at 20 percent above 200 = 240 $
% discount given by store employee = 15
Emlpoyee paid = .85 * 240 = 204 $
Answer A
Question: The average salary/head of allthe workers in a workshop is Rs.850, if the average salary/head of 7technician is Rs.1000 and the average salary/head of the rest is Rs.780, the total no. of workers in the work-shop is ?
A.18
B.20
C.22
D.24
Answer: C.22
Explanation: Let the total number of workers be y.
So sum of salary for all workers = sum of salary of 7 technician + sum of salary for other y -7 workers.
7 x 1000 + 780(y -7) = 850 y
⇒ 7000 + 780y - 5460 = 850y
⇒ 70y = 1540
∴ y = 22
So total number of workers = 22
C
Question: The average of 1st 3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 11. What is the last numbers?
A.2
B.4
C.6
D.5
Answer: B.4
Explanation: A + B + C = 48
B + C + D = 45
A + D = 11
A – D = 3
A + D = 11
2D = 8
D = 4
ANSWER B
Question: A certain student has received the following test grades: 94%, 83%, 71%, 82%, and 88%. If the highest test grade is increased by 5 percentage points, which of the following statements best describes the change in the mean and the median of the test grades?
A. The mean and the median will remain unchanged.
B. The mean will remain unchanged but the median will increase.
C. The mean will increase but the median will remain unchanged.
D. The mean and the median will increase by the same amount.
Answer: C. The mean will increase but the median will remain unchanged.
Explanation: Old set = {71, 82, 83, 88, 94}.
New set = {71, 82, 83, 88, 99} --> the median (middle term) will remain the same and the mean will increase.
Answer: C.
Question: How many different 5 digit numbers can be formed from the number 28579 by re-arranging its digits so that the odd digits occupy even position
A.12
B.5
C.7
D.3
Answer: A.12
Explanation: There are 3 odd numbers which have to be placed at 3 even places =3!=6 ways
There are 2 even numbers which have to be placed at 2 odd places. So 2! = 2 ways
so total number of ways of arranging all these numbers are 6 * 2 = 12 ways
Answer:A
Question: By selling 32 plums in a dollar, a man loses 40%. How many plums must he sell in a dollar to gain 20% profit?
A.16
B.18
C.20
D.25
Answer: A.16
Explanation: This is a question that is much easier than it first appears. If you work with the percents directly, you can solve it very quickly. If the man sells 32 plums for a dollar, he loses 40%. That means he is at 60% of his cost (100% - 40% = 60%). We are trying to figure out how many plums he has to sell in order to make a 20% profit, or be at 120% (100% + 20% = 120%). 120% is double 60%, meaning that we simply cut the number of plums in half to double our returns (from 60% to 120%), yielding 32/2 = 16 plums, or answer choice A.
Question: A boy wants to go abroad by boat and return by flight. He has a choice of 6 different boat to go and 5 flight to return. In how many ways, can the boy perform his journey?
A.20
B.25
C.30
D.40
Answer: C.30
Explanation: Ans.(C)
Sol. Number of choices to go by ship = 6 Number of choices to return by airline = 5 From, fundamental principle, total number of ways of performing the journey = 6 x 5 = 30 ways
Question: There are 24 stations between Ernakulam and Chennai. How many second class tickets have to be printed, so that a passenger can travel from one station to any other station?
A.800
B.820
C.650
D.870
Answer: C.650
Explanation: The total number of stations= 26
From 26 Stations we have to choose any two stations and the direction of travel (Ernakulam to Chennai is different from Chennai to Ernakulam) in 26P2 ways.
26P2= 26*25= 650
ANSWER:C
Question: Four of the five parts numbered (a),(b),(c),(d) and (e) in the following equation are exactly equal. Which of the parts is not equal to the other four? The number of that part is the answer.
A.(a – b)2 + 4ab
B.a(a + b) + b(a + b)
C.(a2 – b2) + 2b(b + a)
D.(a – b)b + (a + b)2b
Answer: D.(a – b)b + (a + b)2b
Explanation: The other parts are equal to (a + b)2.
Answer D
Question: What is the area of a rectangle whose length is twice its width and whose perimeter is equal to that of a square whose area is 1?
A.1/9 sq units.
B.4/9 sq units.
C.8/9 sq units.
D.7/9 sq units.
Answer: C.8/9 sq units.
Explanation: Area will be 2/3 *4/3 = 8/9 sq units.
ANSWER:C
Question: John tossed a fair coin 6 times. What is the probability that the coin landed heads up exactly twice?
A.0.094
B.0.15
C.0.194
D.0.25
Answer: A.0.094
Explanation: The probability is exactly same as the cion landed tail up once. That is 6*(1/2)^6 = 6/64 =0.094.
The answer is, therefore, (A).
Question: If -3x > 6, which of the following must be true?
A.x < -3
B.x < -2
C.x > 3
D.x > -2
Answer: B.x < -2
Explanation: -3x > 6
=> -x > 2
=> x < - 2
Answer B
Question: Lucy deposited $62500 in an investment fund that provided 12 percent annual return compounded quarterly. If she made no other transactions with the fund, in how much time, in months, did her investment earn a total interest of $5100?
A.0.5
B.12
C.3
D.18
Answer: D.18
Explanation: A = P + I = 62500 + 5100 = 67600
67600 = 62500(1 + 12/4*100)^(4t)
(676/625) = (103/100)^(4t)
t =1 1/2 yrs = 18 months
Answer: D
Question: The residents of Town X participated in a survey to determine the number of hours per week each resident spent watching television. The distribution of the results of the survey had a mean of 21 hours and a standard deviation of 8 hours. The number of hours that Pat, a resident of Town X, watched television last week was between 1 and 2 standard deviations below the mean. Which of the following could be the number of hours that Pat watched television last week?
A.30
B.20
C.11
D.14
Answer: C.11
Explanation: Given: mean=21 and SD=8
The number of hours that Pat watched television was between 1 and 2 standard deviations below the mean: 1 SD below the mean ismean-1*SD=13 and 2 SD below the mean ismean-2*SD=5, so the number of hours that Pat watched television was between 5 and 13 hours.
Answer: C
Question: If the capacity of a cylindrical tank is 1848 m3 and the diameter of its base is 14 m, then find the depth of the tank.
A.10
B.11
C.12
D.13
Answer: C.12
Explanation: Let the depth of the tank be h meters. Then,
∏ x 72 x h = 1848  h = (1848 x (7/22) x (1/49) = 12 m
Answer is C
Question: The equation q = 2y2 + 5y - 17, describes a parabola in the xy coordinate plane. If line l, with slope of 3, intersects the parabola in the upper-left quadrant at q = -5, the equation for l is
A.+ y + 15 = 0
B.- 3x - 11 = 0
C.+ y - 16.5 = 0
D.- y - 7 = 0
Answer: C.+ y - 16.5 = 0
Explanation: Is optionC: -3q + y -6.5= 0=C
Question: Subtract. Simplify your answer and write it as a proper fraction or as a whole or mixed number.
4/5 - 1/5=
A.1/5
B.2/5
C.3/5
D.4/5
Answer: C.3/5
Explanation: Here's how to subtract 1/5 from 4/5:
4/5−	1/5
Since our denominators match, we can subtract the numerators.
4 − 1 = 3
So the answer is:
3/5
answer :C
Question: What are the last two digits of 63*35*37*82*71*41?
A.10
B.30
C.40
D.70
Answer: D.70
Explanation: First, multiplied 82 and 35, since 2 and 5 will give a 0 in the end. Got last 2 digits 70.
no need to multiply 70 by 41 and 71, since they wont change the last 2 digits (try if you want to, but effective multiplication in case of 41 and 71 is only with 1).
Now, 70 * 3(of 63) gives : last 2 digits as 10.
lastly, 10 * 7(of 37) gives : last 2 digits 70.
ANSWER:D
Question: What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58?
A.Rs.3944
B.Rs.3948
C.Rs.3988
D.Rs.3949
Answer: A.Rs.3944
Explanation: Let the side of the square plot be a ft.
a2 = 289 => a = 17
Length of the fence = Perimeter of the plot = 4a = 68 ft.
Cost of building the fence = 68 * 58 = Rs.3944.
Answer: A
Question: From a group of 4 boys and 4 girls, 4 children are to be randomly selected. What is the probability that 2 boys and 2 girls will be selected?
A.12/29
B.14/31
C.16/33
D.18/35
Answer: D.18/35
Explanation: The total number of ways to choose 4 children from 8 is 8C4 = 70
The number of ways to choose 2 boys and 2 girls is 4C2*4C2 = 6*6 = 36
P(2 boys and 2 girls) = 36/70 = 18/35
The answer is D.
Question: From a group of 16 astronauts that includes 7 people with previous experience in space flight, a 3-person crew is to be selected so that exactly 1 person in the crew has previous experience in space flight. How many different crews of this type are possible?
A.270
B.252
C.272
D.292
Answer: B.252
Explanation: number of astronauts with previous experience = 7
Remaining =9
we need to pick exactly one from the first group
and 2 from the second group
(7C1)*(9C2)
=7*36= 252
Answer : B
Question: A does half as much work as Band C does half as much work as A and B together. If C alone can finish the work in 80 days, then together ,all will finish the work in :
A.13 1/3 days
B.16 days
C.15 days
D.20 days
Answer: B.16 days
Explanation: C alone can finish the work in 80 days.
(A + B)can do it in 20 days
(A + B)s 1 days wok = 1/20.
As 1 days work : Bs 1 days Work = 1/2 : 1 = 1:2.
Aâ€™s 1 dayâ€™s work = (1/20) * (1/3) = (1/60). [Divide 1/20 in the raio 1:2] Bs 1 days work = (1/20) * (2/3) = 1/30
(A+B+c)S 1 dayâ€™s work = (1/60) + (1/30) + (1/80) = 1/16
All the three together will finish it in 16 days.
ANSWER:B
Question: Ramu mixed 40% kerosene solution to 25% kerosene solution hence obtaining 30% kerosene solution. In what ratio were the both solutions mixed?
A.2:9
B.2:2
C.2:1
D.2:8
Answer: C.2:1
Explanation: QUESTION : A can contains a mixture of two liquids X and Y in the ratio 7:5 when 9 liters of mixture are drawn off and the can is filled with Y, the ratio of X and Y becomes 7:9. How many liters of liquid A were contained by the can initially?
12 Litres
21 litres
13 litres
22 litres
ANSWER :C
Question: When p is divided by 9, the remainder is 3. All of the following are possible values of p, except for which of the following?
A.12
B.30
C.48
D.56
Answer: D.56
Explanation: Four of these numbers can be expressed in the form of 9x+3, where x can be 0,1,2,3,4....
However, 56 = 9(6) + 2
The answer is D.
Question: In an examination a pupil's average marks were 63 per paper. If he had obtained 26 more marks for his Geography paper and 2 more marks for his History paper, his average per paper would have been 65. How many papers were there in the examination?
A.8
B.9
C.10
D.14
Answer: D.14
Explanation: Let the number of papers be x. Then,
63x + 26 + 2 = 65x
= 2x = 28
= x = 14.
ANSWER:D
Question: Factor: 4x4y3 â€“ 64y3
A.A) 4y3(x2 + 4)(x + 2)(x -2)
B.B) 2y3(x2 + 4)(x + 2)(x -2)
C.C) 3y3(x2 + 4)(x + 2)(x -3)
D.D) 3y3(x2 + 4)(x + 3)(x -2)
Answer: A.A) 4y3(x2 + 4)(x + 2)(x -2)
Explanation: 4x4y3â€“ 64y3.
= 4y3(x4 â€“ 16).
= 4y3[(x2)2 - 42].
= 4y3(x2 + 4)(x2 - 4).
= 4y3(x2 + 4)(x2 - 22).
= 4y3(x2 + 4)(x + 2)(x -2).
Answer: (A) 4y3(x2 + 4)(x + 2)(x -2)
Question: WINK, Inc. follows a certain procedure that requires two tasks to be finished independently in order for a job to be done. On any given day, there is a 2/3 probability that task 1 will be completed on time, and a 3/5 probability that task 2 will be completed on time. On a certain day, what is the probability that task 1 will be completed on time, but task 2 will not?
A.4/15
B.3/40
C.13/40
D.7/20
Answer: A.4/15
Explanation: P(1 and not 2)=2/3*(1-3/5)=4/15.
Answer: A.
Question: A little girl is numbering her collection of butterflies by placing single-digit stickers under each specimen. If the girl has 330 butterflies, how many stickers does she need? (The numbers are consecutive and the number of the first butterfly is 1).
A.882
B.901
C.1,001
D.1,003
Answer: A.882
Explanation: For the first 9 butterflies we need 9 stickers.
For the next 90 we need 2 stickers each or 180 stickers.
For the next 900 butterflies we need 3 stickers each.
The first 99 butterflies correspond to 189 stickers.
Subtract 99 from the total number of butterflies (330).
This leaves 231 butterflies that use 3 stickers each. So, multiply 231 by 3 to get 693.
Add 693 to 189 stickers to get 882 stickers.
Answer: A