RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Let q represent the integer length of a side of a triangle. If r represents the number of distinct values for q such that we can create a triangle with lengths q, 9, and 12, what is the value of r?
A.5
B.17
C.18
D.22
Answer: B.17
Explanation: From the triangle inequality rule, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. So, the three inequalities are:
1. q + 9 > 12
2. 9 + 12 > q
3. q + 12 > 9
Equation 3 is true for any positive value of q.
From equation 1, q > 3
From equation 2, 21 > q
Then 21 > q > 3 so q can be any value from 4 to 20 inclusive.
The number of possible values is 17.
The answer is B.
Question: John makes $60 a week from his job. He earns a raise andnow makes $78 a week. What is the % increase?
A.16.12%
B.16.66%
C.30%
D.17.66%
Answer: C.30%
Explanation: Increase = (18/60)*100 = (3/10)*100 = 30%.
C
Question: Tom bought 2 shares and sold them for $60 each. If he had a profit of 25% on the sale of one of the shares but a loss of 40% on the sale of the other share, then on the sale of both shares Tom had
A. a profit of $50
B. a loss of $50
C. a profit of $60
D. a loss of $60
Answer: D. a loss of $60
Explanation: total CP = 6000/125 + 6000/60 = 80 + 100=180
SP=60*2=120
loss= Rs 60/-
Answer: D
Question: The cost price of a radio is Rs.1890 and it was sold for Rs.1500, find the loss %?
A.18
B.20
C.77
D.66
Answer: B.20
Explanation: 1890 ---- 390
100 ---- ? => 20%
Answer: B
Question: The unit's digit in the product 274 × 318 × 577 × 313 is
A.2
B.3
C.4
D.5
Answer: A.2
Explanation: Solution
Required digit	= Unit digit in(4×8×7×3).
= 2.
Answer A
Question: Pipes A and B can fill a tank in 7 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in
A.1 13/17 hours
B.2 8/11 hours
C.3 9/17 hours
D.4 8/19 hours
Answer: D.4 8/19 hours
Explanation: Solution
Net part filled in 1 hour	= (1/7 + 1/6 -1/12)
= 19/84.
Therefore, the tank will be full in 84/19 hrs.	â€¹=â€º 4 8/19 hrs.
Answer D
Question: Two squares are chosen at random on a chessboard. What is the probability that they have a side in common?
A.1/18
B.64/4032
C.63/64
D.1/9
Answer: A.1/18
Explanation: Explanation :
No of ways of selecting two squares from 64 squares on the chess board is 64C2.
Three cases arise:
case 1: when first square is any of the four corner ones
In this case second square can be chosen in 2 ways
no of ways of selecting two squares: 4*2 = 8
case2: when first square is any of the 24 squares on the side of the chess board other than the corner ones
the second square can be chosen in 3 ways
no of ways of selecting two squares: 24*3 = 72
case 3: the first square is any of the 36 remaining squares
the second square can be chosen in 4 ways
no of ways of selecting two squares: 36*4 = 144
Total no of ways of selecting two adjacent squares = 8 + 72 + 144 = 224
So required probability = 224/64C2 = 224/4032 = 1/18
Answer : A
Question: The length of a rectangular plot is 10mtr more than its width. The cost of fencing the plot along its perimeter at the rate of Rs. 6.5mtr is Rs.2210. The perimeter of the plot is?
A.126
B.156
C.340
D.321
Answer: C.340
Explanation: Sol. Let width = x, Length = (10+x)
Perimeter = 2(x+(10+x))
= 2(2x=10)
& 2(2x+10)*6.5 = 2210
X = 80
Required perimeter = 2(80+90) = 340
C
Question: The radius of the two circular fields is in the ratio 4: 10 the area of the second field is what percent greater than the area of the first?
A.72%
B.96%
C.94%
D.84%
Answer: D.84%
Explanation: r = 4 Ï€r2 = 16
r = 10 Ï€r2 = 100
100 Ï€ â€“ 84 Ï€
100 ---- ? =>84%.Answer:D
Question: If y = 35p, and p is prime, what is the greatest common factor of y and 42p, in terms of p?
A.p
B.2p
C.5p
D.7p
Answer: D.7p
Explanation: y = 35p = 5*7*p
42p = 2*3*7*p
The greatest common factor of 30p and 20p is the product of all the common prime factors, using the lower power of repeated factors. The greatest common factor is 7*p = 7p
The answer is D.
Question: A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed?
A.11
B.28
C.27
D.29
Answer: A.11
Explanation: Explanation:
One day's work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10
C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.
Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10
Remaining Work = 7/10, which was done by A,B and C in the initial number of days.
Number of days required for this initial work = 7 days.
Thus, the total numbers of days required = 4 + 7 = 11 days.
Answer: A) 11 days
Question: The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:
A.1008
B.1015
C.1022
D.1032
Answer: B.1015
Explanation: Explanation :
Required number = (L.C.M. of 12,16, 18, 21, 28) + 7
= 1008 + 7
= 1015
ANSWER IS B
Question: If every 2 out of 3 readymade shirts need alterations in the sleeves, and every 4 out of 5 need it in the body, how many alterations will be required for 60 shirts ?
A.88
B.123
C.133
D.143
Answer: C.133
Explanation: no.of Alteration required in 1 shirt is (2/3)+(4/5)+(3/4)=133/60
for 60 shirts it will 60*(133/60)=133
ANSWER:C
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
A.280
B.670
C.230
D.67
Answer: A.280
Explanation: A
x*(85/100) = (480 - x)119/100
x = 280
Question: A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
A.198 ways
B.128 ways
C.100 ways
D.108 ways
Answer: D.108 ways
Explanation: The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12 =108 ways
Answer:D
Question: A and B invest in a business in the ratio 3: 2. Assume that 5% of the total profit goes to charity. If A's share is Rs. 855, what is the total profit?
A.1200
B.1100
C.1500
D.1700
Answer: C.1500
Explanation: Assume that the total profit is x
Since 5% goes for charity, 95% of x will be divided between A and B in the ratio 3:2
Therefore, A's profit =(95x/100)×(3/5)
Given that A's share is Rs. 855. Therefore,
(95x/100)×(3/5)=855
⇒(95x/100)=855×5/3=285×5=1425
⇒x=(1425×100)/95=(285×100)/19=1500
Hence the total profit = 1500
Answer is C.
Question: In a dairy farm, 50 cows eat 50 bags of husk in 50 days. In how many days one cow will eat one bag of husk ?
A.34 days
B.40 days
C.46 days
D.50 days
Answer: D.50 days
Explanation: Explanation:
Less Cows, More days (Indirect Proportion)
Less bags, Less days (Direct Proportion)
[Cows1 50
Bags 50 1]::50:x
=>x∗50∗1=50∗1∗50
=>x=50
Option D
Question: Given that 2x + 13 > 5 and 5x - 13 < 7, all values of x must be between which of the following pairs of integers?
A.-4 and -1
B.-4 and 4
C.-4 and 1
D.-2 and 5
Answer: B.-4 and 4
Explanation: 2x + 13 > 5
i.e 2x >5-13
i.e. 2x > -8
i.e. x > -4
Also, 5x - 13 < 7
i.e. 5x <7+13
i.e 5x < 20
i.e x < 4
i.e. -4 < x < 4
Answer: Option B
Question: If (2/3)^n=(3/2)^3, what is the value of n?
A.-3
B.-2
C.-1
D.0
Answer: A.-3
Explanation: (2/3)^n = (3/2)^3
= (2/3)^-3
n = -3 (Answer = A)
Question: A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was?
A.Rs. 2000
B.Rs. 10,000
C.Rs. 15,000
D.Rs. 20,000
Answer: C.Rs. 15,000
Explanation: Principal =(100 x 5400)/(12 x 3) = Rs. 15000.
Answer: Option C
Question: Q. How many 8-digit even numbers less than 3,000,000 can be formed using the following digits: 1, 2, 2, 3, 5, 5, 6, 6?
A.180
B.240
C.210
D.270
Answer: D.270
Explanation: the number is less than 3000000 so we will have the digit on the left most side to be either 1 or 2
i.e your number can be 1 _ _ _ _ _ _ or 2 _ _ _ _ _ _
case 1 > 1 _ _ _ _ _ _ here the units digit can be either 2 or 6
when the units digit is 2 i.e 1 _ _ _ _ _ 2
number of ways this can be done would be 5! / 2! (as 5 is repeated twice) = 60
when the units digit is 6 i.e. 1 _ _ _ _ _ 6, number of ways would be 5!/(2! * 2!) {both 2 and 5 repeat twice} = 30
case 2 > 2 _ _ _ _ _ _ (here units digit may be 2 or 6)
number of ways this can be done would be 5! / (2!) for 2 =60
and 5! / 2! for 6 ... = 60
adding all of these ... gives the answer 270 ...
the explanation looks difficult but this technique helps if you are familiar with the concept of permutations when the numbers/alphabets repeat
D
Question: If the probability of Sita getting selected to a school is 20% and she applied to 3 schools. What is the probability that she will get selected in at least one school?
A.24/125
B.21/125
C.61/125
D.12/125
Answer: C.61/125
Explanation: The probability that she will be selected by at least one school equals to the sum of the probabilities of the following three events:
1. She is selected by only one school: P(SRR)=3!/2!∗1/5∗4/5∗4/5=48/125 (S stands for selected and R stands for rejected). We are multiplying by 3!/2! since SRR scenario can occur in several ways: SRR, RSR, RRS, (so 3!/2! is # of permutations of 3 letters SRR out of which 2 R's are identical);
2. She is selected by only two school: P(SSR)=3!/2!∗1/5∗1/5∗4/5=12/125, the same reason of multiplying by 3!/2!;
3. She is selected by all three school: P(SSS)=(15)^3=1125, we are not multiplying this time since SSS can occur only in one way.
So P=48/125+12/125+1/125=61/125
Answer: C
Question: Find the largest number of four digits which is exactly divisible by 27,18,12,15
A.9700
B.9710
C.9720
D.9520
Answer: C.9720
Explanation: Explanation:
LCM of 27-18-12-15 is 540.
After dividing 9999 by 540 we get 279 remainder.
So answer will be 9999-279 = 9720
Option C
Question: A can do a piece of work in 12 days. He worked for 15 days and then B completed the remaining work in 10 days. Both of them together will finish it in.
A.12 1/2 days
B.5 days
C.8.5 days
D.2 days
Answer: A.12 1/2 days
Explanation: Answer: Option A
15/25 + 10/x = 1 => x = 25
1/25 + 1/25 = 2/25
25/2 = 12 1/2 days
Question: A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?
A.13 1/0
B.13 1/3
C.13 1/2
D.13 1/1
Answer: B.13 1/3
Explanation: 5/30 + 20/x = 1
x = 24
1/30 + 1/24 = 3/40
40/3 = 13 1/3 days
Answer:B
Question: Thomas bought a pack of eleven computers for Rs. 500000 and sold it for Rs.550000. What is the % of profit he is making per computer?
A.10
B.14
C.19
D.21
Answer: A.10
Explanation: The cost of buying a single computer= Rs(500000/11)=Rs. 45454.5
The cost of selling a selling computer=Rs(550000/11)=Rs. 50000.0
Profit per computer=Rs.(50000-45454.5)=Rs. 4545.5
The % of profit in selling a single computer=(4545.5/45454.5)*100=10%
Answer:A
Question: Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years.
A.306.08
B.306.03
C.306.04
D.306.01
Answer: C.306.04
Explanation: Explanation:
A = 5000(51/50)3
= 5306.04
5000
-----------
306.04
Answer:C
Question: Convert 600 miles into meters?
A.784596
B.845796
C.965604
D.784596
Answer: C.965604
Explanation: 1 mile = 1609.34 meters
600mile = 600*1609.34 = 965604 meters
Answer is C
Question: Insert the missing number.
3, 7, 6, 5, 9, 3, 12, 1, 15, (....)
A.3
B.7
C.-1
D.8
Answer: C.-1
Explanation: Explanation:
There are two series, beginning respectively with 3 and 7. In one 3 is added and in another 2 is subtracted.
The next number is 1 - 2 = -1.
Answer: C) -1
Question: If BOMBAY is written as MYMYMY, how will TAMIL NADU be written in that code?
A.TIATIATIA
B.IATIATIAT
C.MNUMNUMNU
D.ALDALDALD
Answer: C.MNUMNUMNU
Explanation: Letters at multiples of 3 is repeated in the code.
So,
In the code BOMBAY, 3rd and 6th letter repeated for the code.
Like that, in the code TAMIL NADU, 3rd 6th and 9th letter must be repeated.
So, TAMILNADU = MNUMNUMNU
ANSWER:C
Question: What is the present worth of Rs. 132 due in 2 years at 5% simple interest per annum?
A.128
B.277
C.120
D.888
Answer: C.120
Explanation: Let the present worth be Rs. x. Then,
S.I. = (132 - x)
(x * 5 * 2) / 100 = (132 - x)
10x = 13200 - 100x
110x = 13200 => x = 120.
Answer: C
Question: A man can row downstream at the rate of 26 Kmph and upstream at 12 Kmph. Find the man’s rate in still water and rate of current?
A.8.5
B.8.0
C.9.5
D.7.0
Answer: D.7.0
Explanation: Rate of still water = 1/2 (down stream + upstream)
= 1/2 (26 + 12) = 19 Kmph
rate of current = 1/2 (down stream - upstream)
= 1/2 (26 - 12)
= 1/2 (14)
= 7 kmph
Answer is D.
Question: A car is running at a speed of 120kmph. What distance will it cover in 12sec?
A.396m
B.267m
C.180m
D.200m
Answer: A.396m
Explanation: Speed = 120kmph = 120*5/18 = 33 m/s
Distance covered in 12sec = 33*12 = 396m
Answer is A
Question: The average of 11 results is 48, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
A.21
B.56
C.78
D.25
Answer: C.78
Explanation: 1 to 11 = 11 * 48 = 528
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 â€“ 528 = 78
Answer:C
Question: A trader mixes 25 kg of rice at Rs. 20 per kg with 25 kg of rice of other variety at Rs. 30 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:
A.No profit, no loss
B.5%
C.8%
D.20%
Answer: D.20%
Explanation: C.P. of 50 kg rice = Rs. (25 x 20 + 25 x 30) = Rs. (500 + 750) = Rs. 1250
S.P. of 50 kg rice = Rs. (50 x 30) = Rs. 1500
Gain =250/1250x100% = 20%.
Answer: Option D
Question: RAM and GOPAL invested in a business. They earned some profit which they divided in the ratio of 1:2. If RAM invested Rs.25, 000, the amount invested by GOPAL is:
A.Rs. 65,000
B.Rs. 50,000
C.Rs. 80,000
D.Rs. 90,000
Answer: B.Rs. 50,000
Explanation: Invested by Gopal = 25000/1*2 = 50000
ANSWER : B
Question: A company has 15 managers and 75 associates. The 15 managers have an average salary of $90,000. The 75 associates have an average salary of $30,000. What is the average salary for the company?
A.$35,000
B.$40,000
C.$55,000
D.$65,000
Answer: B.$40,000
Explanation: Another method is to get ratios
Say 30000=a and
We know the # of people are in 1:5 ratio
Average=(3a*1+a*5)/6= 8a/6=40000
Answer is B. $40,000
Question: Alice’s take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 2 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month?
A.1/7
B.1/6
C.1/5
D.1/4
Answer: A.1/7
Explanation: Suppose the portion of her salary that she saved is X
and the remaining portion is Y
X+Y= total take home salary
given, 12X = 2Y
or 6X = Y
Total take-home salary= X+ 6X= 7X
hence, she saved 1/7-th portion of her take home salary
A
Question: In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 30 liters and they are all empty, how much money total will it cost to fuel all cars?
A.320$
B.255$
C.420$
D.450$
Answer: B.255$
Explanation: Total Cost = ( 1.75*12 ) + ( 0.65 * 12 * 30 ) = 21 + 234 => 255
Hence answer will be (B)
Question: A cycle is bought for Rs.1120 and sold for Rs.1200, find the gain percent?
A.7%
B.2%
C.6%
D.1%
Answer: A.7%
Explanation: Explanation:
1120---- 80
100 ---- ? => 7%
Answer: A
Question: A man in train notice that he can count 51 telephone posts in 1 minute. If they are known to be 80 meters apart,then at what speed is the train traveling?
A.100km/hr
B.110km/hr
C.240km/hr
D.150km/hr
Answer: C.240km/hr
Explanation: Number of gaps between 51 telephone posts = 50
Distance traveled in 1 minute = 50*80 = 4000m = 4km
Speed = 60*4=240km/hr
Answer is C
Question: A number is doubled and 9 is added. If the resultant is trebled, it becomes 75. What is that number?
A.3.5
B.6
C.8
D.9
Answer: C.8
Explanation: by option
8*2=16(number is doubled)
add 9(16+9=25)
if 25 trebled it becomes 75
ANSWER:C
Question: A car covers a distance of 720 km in10 hrs. What is its speed in mps.
A.40 m/s
B.25 m/s
C.20 m/s
D.15 m/s
Answer: C.20 m/s
Explanation: Explanation:
Distance = Speed x Time
Speed = (720/10) = 72 kmph
Spees in mps = 72 x 5/18 = 4 x 5 = 20 mps.
Answer: Option C
Question: The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
A.8, 20, 28
B.16, 28, 36
C.20, 35, 45
D.20, 45, 55
Answer: B.16, 28, 36
Explanation: Explanation:
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
⇒ 20x = 80
⇒ x = 4.
⇒ Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Answer: B
Question: If x, y, and z are all factors of 35, which of the following must be true?
A.The product xyz > 35
B.Either x = y, y = z, or x = z
C.x – y – z = even
D.The product xyz is odd
Answer: D.The product xyz is odd
Explanation: All the factors of 35 are odd numbers.
The product of odd numbers is odd.
The answer is D.
Question: The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, find out the value of x
A.13
B.14
C.15
D.16
Answer: D.16
Explanation: Explanation:
Let the Cost Price of one article = Rs. 1
CP of x articles = Rs. x
CP of 20 articles = 20
Selling price of x articles = 20
Profit = 25% [Given]
⇒(SP−CP /CP)=25/ 100=1/4
⇒(20−x)/x=1/4
⇒80−4x=x
⇒5x=80
Option D
⇒x=805=16
Question: What is the maximum number of pieces of birthday cake of size 3” by 3” that can be cut from a cake 21” by 21”?
A.5
B.7
C.49
D.20
Answer: C.49
Explanation: The prompt is essentially asking for the maximum number of 3x3 squares that can be cut from a larger 21 by 21 square. Since each 'row' and each 'column' of the larger square can be sub-divided into 7 'pieces' each, we have (7)(7) = 49 total smaller squares (at maximum).
C
Question: If an item that originally sold for r dollars was marked up by p percent and then discounted by q percent, which of the following expressions represents the final price of the item?
A.(10,000r + 100r(p – q) – pqr)/10,000
B.(10,000r + 100r(q – p) – pqr)/10,000
C.(100r(p – q) – pqr)/10000
D.(100r(q – p) – pqr)/10000
Answer: A.(10,000r + 100r(p – q) – pqr)/10,000
Explanation: Assume r=100, p=10, q=10. So final price is 99. Now put these value each option. Only option A will give right answer.
Question: The product of n consecutive positive integers is always divisible by?
A.n^2 -1
B.(n+1)!
C.2n +1
D.n!
Answer: D.n!
Explanation: Plug in some vlues and check -
Product of first 2 number is 2*1
Product of first 3 number is 3*2*1
Product of first 4 number is 4*3*2*1
Product of first 5 number is 5*4*3*2*1
So, The product of first n natural numbers is always divisible by n! , answer will be (D)
Question: A bag marked at $240 is sold for $120. The rate of discount is?
A.10%
B.25%
C.20%
D.50%
Answer: D.50%
Explanation: Rate of discount = 120/240 * 100 = 50%
Answer is D
Question: What is the sum of odd integers from 20 to 80, inclusive?
A.1,550
B.1,500
C.1,240
D.1,120
Answer: A.1,550
Explanation: Number of odd integers = (80-20)/2 + 1
= 60/2 + 1
= 31
Sum of odd integers = (20+80)/2 * 31
= 50 * 31
= 1550
Answer A
Question: A box contains 2 white, 3 black and 5 red balls. In how many ways can three balls be drawn from the box if at least one black ball is to be included in the draw?
A.85
B.66
C.27
D.19
Answer: A.85
Explanation: Explanation:
Total balls in a box = 2W + 3B + 5R = 10 balls.
Therefore total number of ways of drawing 3 balls from 10 balls is 10C3 = 120 ways ........(1)
This includes all types of color combinations of white, black and red.
Now total balls in a box of white and red color = 2W + 5R = 7 balls.
Therefore total number of ways of drawing 3 balls from 7 balls is 7C3 = 35 ways ........(2)
This includes all types of color combinations of white and red only.
Therefore from (1) and (2), we get the total number of ways of drawing 3 balls, which includes at least one black ball = 120 – 35 = 85 ways.
ANSWER: A
Question: Adam, Bryan, Chris, and David are all basketball players. An unknown habit of Adam's is to score 7 more than half as many points as Bryan. Bryan is their star player and will always score at least 50 points plus Chris' score. Chris is a consistent player in that he will score twice as many points as David. Write a general equation that shows the total score of these four players in a game in terms of David, D
A.82 +6D
B.82 +4D
C.82 +8D
D.8D
Answer: A.82 +6D
Explanation: A = B/2+7
B = 50+C
C = 2D
D = D
Now compile new equations
A+B+C+D = (B/2+7) +(50+C) +(2D) +(D)
= (B/2+7) +(50+C) +3D, look back at original equations
=(B/2+7) +(50+2D) +3D
=(B/2+7) +50+5D
= (50+2D)/2+7 +50 +5D
= 25 +D +7+50+5D
=82 +6D
Answer: A
Question: A mixture of 70 lts. Of wine and water contains 10% of water. How much water must be added to make 37% of the resulting mixture?
A.30
B.31
C.32
D.33
Answer: A.30
Explanation: Its given that currently water is 10% of the mixture.
=> (10/100)(70) = 7lts
lets say x litres of water is added.
=> 7+x = (37/100)(70+x)
=> x = 30 liters
ANSWER:A
Question: During a sale, the price of a pair of shoes is marked down 14% from the regular price. After the sale ends, the price goes back to the original price. What is the percent of increase to the nearest percent from the sale price back to the regular price for the shoes?
A.9%
B.10%
C.11%
D.16%
Answer: D.16%
Explanation: Assume the price = 100
Price during sale = 86
Price after sale = 100
Percent increase = 14/86*100 = 16% approx.
Correct Option: D
Question: A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.85 less, he could have gained 25%. What is the cost price?
A.372
B.375
C.278
D.425
Answer: D.425
Explanation: CP1 = 100 SP1 = 120
CP2 = 80 SP2 = 80 * (125/100) = 100
20 ----- 100
85 ----- ? => 425
Answer:D
Question: A car covers a distance of 600 km in 6 hours. Find its speed?
A.104
B.100
C.266
D.288
Answer: B.100
Explanation: 600/6 = 100 kmph
Answer:B
Question: The function f is defined for all the positive integers n by the following rule: f(a) is the number of positive integers each of which is less than a and has no positive factor in common with a other than 1 . if p is a prime number then f(p)?
A.p-1
B.p-2
C.(p+1)/2
D.(p-1)/2
Answer: A.p-1
Explanation: The moment you put a prime number in the function f(a), notice that all the numbers lesser than a have no divisor clashing with divisor of a since a is prime!!.
For instance f(7)= {6, 5, 4, 3, 2, 1}
Thus for f(p) number of integers falling under this set will be p-1
Answer :- A
Question: All of the students of the Music High School are in the band, the orchestra, or both. 80 percent of the students are in only one group. There are 98 students in the band. If 50 percent of the students are in the band only, how many students are in the orchestra only?
A.36
B.39
C.42
D.45
Answer: C.42
Explanation: 50% of students are in the band only, so 30% of students are in the orchestra only.
Since 20% of students are in both, then 70% of students are in the band which is 98 students.
The number of students in the orchestra is (30/70)*98 = 42.
The answer is C.
Question: In a group of 80 children and 17 youngsters, each child got sweets that are 15% of the total number of children and each youngster got sweets that are 25% of the total number of children. How many sweets were there?
A.1140
B.1160
C.1180
D.1300
Answer: D.1300
Explanation: Number of sweets each child got = 15% of 80 = 15/100 * 80 = 12.
Number of sweets 80 children got = 80 * 12 = 960.
Number of sweets each youngster got = 25% of 80 = 25/100 * 80 = 20.
Number of sweets 17 youngsters got = 17 * 20 = 340.
Total number of sweets = 960 + 340 = 1300.
D)
Question: A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 10km?
A.3
B.5
C.8
D.9
Answer: B.5
Explanation: M = 4
S = 2
US = 4 - 2 = 2
D = 10
T = 10/2 = 5
Answer:B