RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: There are some pigeons and hares in a zoo. If heads are counted, there are 250. If legs are counted, there are 580. The number of hares in the zoo is?
A.40
B.50
C.60
D.70
Answer: A.40
Explanation: 250*2 = 500
580
-----
80
1----2
?----80 = 40
ANSWER:A
Question: The average age of 30 students in a class is 14 years. If the age of teacher is also included, the average becomes 15 years, find the age of the teacher.
A.43
B.44
C.45
D.47
Answer: C.45
Explanation: Explanation:
If teacher's age is 14 years, there is no change in the average. But teacher has contributed 1 year to all the students along with maintaining his age at 15.
Age of teacher = Average age of all + Total increase in age
= 15 + (1 x 30 ) = 45 years
Answer:C
Question: A man can row 7.2 kmph in still water and he finds that it takes him twice as long to row up as to row down the river. Find the rate of stream.
A.2.4 km/hr
B.12.5 km/hr
C.1 2.6 km/hr
D.22.5 km/hr
Answer: A.2.4 km/hr
Explanation: Given that, time taken to travel upstream = 2 × time taken to travel downstream
When distance is constant, speed is inversely proportional to the time
Hence, 2 × speed upstream = speed downstream
Let speed upstream = x
Then speed downstream = 2x
we have, 1/2(x+2x) = speed in still water
⇒1/2(3x)=7.2
3x = 14.4
x = 4.8
i.e., speed upstream = 4.8 km/hr
Rate of stream = 1/2(2x−x)=x/2=4.8/2=2.4 km/hr
Answer is A
Question: Two pipes A and B can fill a cistern in 75/2 minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the B is turned off after:
A.5 min.
B.9 min.
C.10 min.
D.15 min
Answer: B.9 min.
Explanation: If B is closed after x mins, then
30*2/75 + x/45 = 1
x/45 = 1 - 4/5 = 1/5
x= 45/5 = 9 mins
ANSWER:B
Question: During the months May through October, Teddy the bear sextuples his weight, and during the months November through April, Teddy loses 100 pounds. If at the beginning of November 1973, Teddy's weight was m pounds, what was Teddy's weight in pounds by the end of April 1976?
A.36m - 1300
B.36m - 1200
C.6m - 1300
D.6m - 1200
Answer: A.36m - 1300
Explanation: Nov ' 73 = m
April ' 74 = m - 100
Oct ' 74 = 6m - 300
April' 75 = 6m - 400
Oct' 75 = 36m - 1200
April'76 = 36m - 1300
Hence answer will be (A) 36m - 1300
Question: A person goes to his office at 1/3rd of the speed at which he returns from his office. If the avg speed during the whole trip is 24m/h. what is the speedof the person while he was going to his office?
A.8km/h
B.10km/h
C.12km/h
D.16km/h
Answer: D.16km/h
Explanation: u = k , v= 3k
\inline \therefore \frac{2uv}{u+v}\: \: \Rightarrow \frac{2\times k\times 3k}{(k+3k)}=24
\inline \Rightarrow 1.5k = 24
\inline \Rightarrow k=16km/h
D
Question: A car travels uphill at 30 km/hr and downhill at 80 km/hr. It goes 100 km uphill and 50 km downhill. Find the average speed of the car?
A.38kmph
B.33kmph
C.34kmph
D.35kmph
Answer: A.38kmph
Explanation: avg speed=total distance/total time.
total distance traveled=100+50=150km;
time taken for uphill journey=100/30=10/3;
time taken for down hill journey=50/80=5/8;
avg speed=150/(10/3+5/8)=38kmph
ANSWER:A
Question: The number of arrangements that can be made with the letters of the word WORDS so that the vowels occupy the even places?
A.14
B.32
C.777
D.24
Answer: D.24
Explanation: The word MEADOWS has 7 letters of which 3 are vowels.
-V-V-V-
As the vowels have to occupy even places, they can be arranged in the 1 even places in 1! i.e., 1 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways.
Hence the total ways are 24 * 1 = 24.
Answer:D
Question: There are 50 students in a class. If 14% are absent on a particular day, find the number of students present in the class.
A.43
B.36
C.28
D.129
Answer: A.43
Explanation: Number of students absent on a particular day = 14 % of 50
i.e., 14/100 × 50 = 7
Therefore, the number of students present = 50 - 7 = 43 students.
Answer:A
Question: A train running at the speed of 27 km/hr crosses a post in 20 seconds. What is the length of the train?
A.200
B.150
C.300
D.175
Answer: B.150
Explanation: Speed=(27x5/18)=7.5 m/sec.
Length of the train=(Speed x Time).
Length of the train=7.5 x20	m = 150 m.
Answer: B
Question: The inverse ratio of 3: 2: 1 is?
A.2:3:7
B.2:3:9
C.2:3:2
D.2:3:6
Answer: D.2:3:6
Explanation: 1/3: 1/2: 1/1 = 2:3:6
Answer:D
Question: Luke travelled 12 2/3 miles in 1 hours and 40 minutes. What was his average rate of speed in miles per hour?
A.7
B.7 3/5
C.8 1/5
D.9
Answer: B.7 3/5
Explanation: D = 12(2/3) = 38/3
T = 1(2/3) = 5/3
S = D/T = 7 3/5
Answer = B
Question: If x = 7 and y = −2, what is the value of (x − 2y)^y?
A.−100
B.0.001
C.0.25
D.4
Answer: B.0.001
Explanation: Quickly we can spot that answer is neither integer nor negative. Eliminate A, DE
by inversing and squaring 0.001
Answer: B
Question: The sum of 4 hours 45 minutes and 5 hours 55 minutes is approximately what percent of a day?
A.32%
B.36%
C.40%
D.44%
Answer: D.44%
Explanation: Since the question is asking for an approximate percentage
4:45+5:55 ~ 11 hours
% of day = 11*100/24 ~ 11*100/25= 44%
Answer is D.
Question: A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is:
A.8.5 km/hr
B.10 km/hr
C.12.5 km/hr
D.9 km/hr
Answer: B.10 km/hr
Explanation: Explanation:
Man's speed with the current = 15 km/hr
=> speed of the man + speed of the current = 15 km/hr
speed of the current is 2.5 km/hr
Hence, speed of the man = 15 - 2.5 = 12.5 km/hr
man's speed against the current = speed of the man - speed of the current
= 12.5 - 2.5 = 10 km/hr
ANSWER IS B
Question: 90 students represent x percent of the boys at Jones Elementary School. If the boys at Jones Elementary make up 20% of the total school population of x students, what is x?
A.125
B.150
C.212
D.250
Answer: C.212
Explanation: 90=x/100*20/100*x=>x^2 = 9*10000/2 = > x =212
C
Question: If z + | z | = 0, which of the following must be true?
A.z > 0
B.z≥0
C.z< 0
D.z≤0
Answer: D.z≤0
Explanation: Manipulate the equations:
z + | z | = 0
|z| = -y
-z > 0 OR -z = 0
This means z could be 0 or z is less than 0.
D. z≤0
E. z=0
Answer: D
Question: If 20% of s = t, then t% of 20 is the same as
A.10% of s
B.4% of s
C.20% of s
D.None
Answer: B.4% of s
Explanation: Explanation :
20% of s = t
=> t = 20/100s
Then,
t% of 20 = (t/100)*20=((20/100)*s)*20/100
=(2020s)/(100100) =4s/100 = 4% of s
Answer : B
Question: What is the minimum value of z for which z^2 + z - 3/6 > 0 is not true?
A. -5/2
B. -3/2
C. -1
D. 1/4
Answer: C. -1
Explanation: I think C -1 is the best ans...
Question: One side if a square is doubled. If the parameter is now 12x. What was the length of one of the sides before it was doubled?
A.12x/4
B.12x/2
C.6x/2
D.12x/6
Answer: B.12x/2
Explanation: If the parameter is now 12x, the each side is 12x/4. To get the original each side is divided by 2. One side is represented by 1 since it's a square. 1/2 is 0.5, which when times by 4 is 2. Thus the answer is 12x/2. Answer option B.
Question: A lady builds 10cm length, 13cm width, and 5cm height box using 5cubic cm cubes. What is the minimum number of cubes required to build the box?
A.107
B.108
C.130
D.150
Answer: C.130
Explanation: Number of cubes required = Volume of box/Volume of cube
= 10*13*5/5
=130 cubes
ANSWER:C
Question: Find the smallest number of 6 digits which is exactly divisible by 111?
A.12000
B.15550
C.100011
D.158993
Answer: B.15550
Explanation: Smallest number of 6 digits is 100000.
On dividing 100000 by 111, we get 100 as remainder.
Number to be added = (111 - 100) - 11.
Hence, required number = 100011
Answer B
Question: If m is a positive integer and m^2 is divisible by 24, then the largest positive integer that must divide m is?
A. 3
B. 6
C. 8
D. 12
Answer: C. 8
Explanation: M^2 is divisible by 48 so M^2 must be multiple of 48.
If the value of M is Multiples of 8 then it will satisfy the condition. If we If M is 12 or 24 or 36 then it ans is C but if M = 48 then answer should be 16.
Is the question right? Or am i missing some thing?
C
Question: a person travels from his house to office from 11:10am to 11:50 am and covers a distence of 13.4km. find the average speed of the person.
A.20.1km/h
B.20.5km/h
C.21.1km/h
D.22.1km/h
Answer: A.20.1km/h
Explanation: time=11:50-11:10=40min=2/3hour
distance=13.4km
speed=13.4*3/2=20.1km/h
ANSWER:A
Question: 3/x + 3x = 3(x-9)
A.-9
B.-1/6
C.-1/9
D.1/9
Answer: B.-1/6
Explanation: We can solve - expand the right side, multiply by x on both sides and then subtract away the 3x^2 terms:
(3/X) + 3x = 3(x-9)
(3/x) + 3x = 3x - 18
3 + 3x^2 = 3x^2 - 18x
3 = -18x
-1/6 = x
and to confirm, you can plug that answer back into the original equation to see that it makes the left and right sides equal.
B
Question: A bowl of fruit contains 14 apples and 21 oranges. How many oranges must be removed so that 70% of the pieces of fruit in the bowl will be apples?
A. 3
B. 15
C. 14
D. 17
Answer: B. 15
Explanation: Number of apples = 14
number of oranges = 23
let number of oranges that must be removed so that 70% of pieces of fruit in bowl will be apples = x
Total number of fruits after x oranges are removed = 14+(21-x) = 35-x
14/(35-x) = 7/10
=>20 = 35-x
=>x= 15
Answer B
Question: A train 210 meters long is running with a speed of 54 kmph. The time taken by it to cross a tunnel 120 meters long is?
A.29
B.22
C.48
D.99
Answer: B.22
Explanation: D = 210 + 120 = 330
S = 54 * 5/18 = 15 mps
T = 330/15 = 22 sec
Answer: B
Question: At the store opening, Larry's Grocery had 50 Lemons and 60 Oranges. By closing, the store at 20 Lemons and 40 Oranges left. By approximately what percent did the ratio of Lemons to Orange decrease from opening to closing.
A.50.0%
B.40.0%
C.30.0%
D.20.0%
Answer: B.40.0%
Explanation: Opening: Lemons/Oranges = 50/60 =100/120
Closing: Lemons/Oranges = 20/40 =60/120
ASIDE: It's useful to write both ratios with the same denominator. This allows us to IGNORE the denominator and focus solely on the numerators.
So, our ratio went from 100/120 to 60/120
Ignoring the denominators, we went from 100 to 60
The percent change = 100(difference in values)/(original value)
= (100)(100-60)/100
= (100)(40)/100)
= 40
Answer: B
Question: .
On dividing a number by 357, we get 40 as remainder. On dividing the same number 17, what will be the remainder ?
A.6
B.3
C.5
D.8
Answer: A.6
Explanation: Let x be the number and y be the quotient. Then,
x = 357 x y + 40
= (17 x 21 x y) + (17 x 2) + 6
= 17 x (21y + 2) + 6)
Required remainder = 6.
Answer: Option A
Question: A number x is 7 times another number y. The percentage that y is less than x is
A.12.5%
B.85.7%
C.80%
D.11%
Answer: B.85.7%
Explanation: Say y=1 and x=7.
Then y=1 is less than x=7 by (7-1)/7*100=6/7*100=85.7%.
Answer: B.
Question: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is
A.100
B.110
C.120
D.140
Answer: A.100
Explanation: Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Question: Two varieties of wheat - A and B costing Rs. 9 per kg and Rs. 15 per kg were mixed in the ratio 3 : 7. If 5 kg of the mixture is sold at 25% profit, find the profit made?
A.1.2
B.3.78
C.16.5
D.5.84
Answer: C.16.5
Explanation: Explanation:
Let the quantities of A and B mixed be 3x kg and 7x kg.
Cost of 3x kg of A = 9(3x) = Rs. 27x
Cost of 7x kg of B = 15(7x) = Rs. 105x
Cost of 10x kg of the mixture = 27x + 105x = Rs. 132x
Cost of 5 kg of the mixture = 132x/10x (5) = Rs. 66
Profit made in selling 5 kg of the mixture = 25/100 (cost of 5 kg of the mixture) = 25/100 * 66 = Rs. 16.50
Correct Option : C
Question: From a group of 7 men and 6 women, 4 persons are to be selected to form a committee so that at most 2 men are there in the committee. In how many ways can it be done?
A.480
B.520
C.760
D.470
Answer: D.470
Explanation: Total Men = 7
Total Women = 6
Persons in committee = 4
No. of ways to select at most 2 men = 6C4 + 7C1 * 6C3 + 7C2*6C2
= 470
Ans -D
Question: 14, 35, 56, 91, 126
In the sequence above, each term is related with the others. Which of the following could not be a term in the sequence?
A.407
B.259
C.322
D.686
Answer: A.407
Explanation: Simplifying the question into easier words we just need to find which of the numbers is not divisible by 7
clearly the answer is 407 because if we divide 407 by 4 we get a remainder of 1
Correct answer - A
Question: Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. Find out his new time compared with the old time.
A.twice as much
B.three times as much
C.the same
D.half as much
Answer: A.twice as much
Explanation: Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.
We know that
Speed = Distance/Time.
Or, Time = Distance/Speed.
So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.
And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.
= 100/x hr.
So we can clearly see that his new time compared with the old time was: twice as much.
Answer is A.
Question: The age of Ritu's mother is 6 times that of Ritu's age. After 6 years it will be 3 times that of Ritu's age. what is Ritu's mother present age?
A.24 years
B.26 years
C.28 years
D.10 years
Answer: A.24 years
Explanation: Let present age of Ritu=x
then, present age of ritu's mother=6x
A/c
after 6 years
=>6x+6=3(6+x)
x=4
so, Ritu mother present age is 24 years
ANSWER:A
Question: Every letter in the alphabet has a number value that is equal to its place in the alphabet. Thus, the letter A has a value of 1, the letter B has a value of 2, the letter C has a value of 3, etc... The number value of a word is obtained by adding up the value of the letters in the word and then multiplying that sum by the length of the word. What is the number value of the word "RAT"?
A.108
B.111
C.114
D.117
Answer: D.117
Explanation: "RAT" = (18+1+20)*3=117.
The answer is D.
Question: For any non-zero a and b that satisfy |ab| = -ab and |a| = a, a^2+b^2+2|ab| =?
A.ab-4
B.(a+b)^2
C.(a-b)^2
D.a^2-|ab+ab^2|
Answer: C.(a-b)^2
Explanation: Given: |ab| = -ab and |a| = a
Question: a^2+b^2+2|ab| =?
**** Looking at |ab| = -ab tells us that a and b are either positive or negative
**** Looking at |a| = a tells us that a must be positive
**** Combine two observations: a is positive, b is negative
so a^2+b^2+2|ab| = a^2+b^2-2ab.
as we know : (a-b)^2= a^2+b^2-2ab.
hence option c is correct.
Question: A train speeds past a pole in 15 seconds and a platform 100 meter long in 25 seconds. What is length of the train ?
A.140 meter
B.145 meter
C.150 meter
D.155 meter
Answer: C.150 meter
Explanation: Explanation:
Let the length of the train is x meter and Speed of the train is y meter/second
Then x/y = 15 [because distance/speed = time]
=> y = 15/x
=>x+100/25=x/15
x=150 meters
So length of the train is 150 meters
Option C
Question: The ratio of the length and the breadth of a rectangle is 4 : 3 and the area of the rectangle is 6912 sq cm. Find the ratio of the breadth and the area of the rectangle?
A.1: 96.
B.1: 99
C.1: 94
D.1: 93
Answer: A.1: 96.
Explanation: Explanation:
Let the length and the breadth of the rectangle be 4x cm and 3x respectively.
(4x)(3x) = 6912
12x2 = 6912
x2 = 576 = 4 * 144 = 22 * 122 (x > 0)
=> x = 2 * 12 = 24
Ratio of the breadth and the areas = 3x : 12x2 = 1 : 4x = 1: 96.
Answer: Option A
Question: A sequence of positive and negative numbers contain q numbers. If the sequence begins with a negative number and q is an odd number how many positive numbers are in it.
A.q/(2+1)
B.(q+1)/2
C.(q-1)/2
D.q/(2-1)
Answer: C.(q-1)/2
Explanation: Lets put values for x, say q=7 since it's odd
and first number is neg so sequence will be {neg,pos,neg,pos,neg,pos,pos} we can see that it has 3 positive terms
so putting q=7 in the options,
option C = (q-1)/2 => 7-1/2 = 3 , the number of positive integers
So, C is the answer
Question: There are 8 executives, including the CEO and CFO, that are asked to form a small team of 5 members. However, the CEO and CFO may not both be assigned to the team. Given this constraint, how many ways are there to form the team?
A.34
B.35
C.36
D.37
Answer: C.36
Explanation: The total number of ways to form a team of 5 is 8C5=56.
We need to subtract the number of teams that have both the CEO and the CFO.
The number of teams with both the CEO and CFO is 6C3=20.
The number of ways to form an acceptable team is 56-20=36.
The answer is C.
Question: A car covers a distance of 720 km in 6 ½ hours. Find its speed?
A.104 kmph
B.187 kmph
C.120 kmph
D.175 kmph
Answer: C.120 kmph
Explanation: 720/6
= 120 kmph
Answer: C
Question: A man can swim in still water at 6 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
A.2
B.1.4
C.1.1
D.1.5
Answer: A.2
Explanation: M = 6
S = x
6 + x = (4.5 - x)2
6 + x = 12 -2x
3x = 6
x = 2
Answer:A
Question: A sprinter starts running on a circular path of radius r metres. Her average speed (in metres/minute) is πr during the first 30 seconds, πr/2 during next one minute, πr/4 during next 2 minutes, πr/8 during next 4 minutes, and so on. What is the ratio of the time taken for the nth round to that for the previous round?
A.4
B.8
C.16
D.32
Answer: C.16
Explanation: Explanation :
There is more than 1 way to approach the solution; however, I will detail the easiest way to go about it here.
We want to find the ratio of time taken for nth round : time taken for (n-1)th round
It will be same as finding the ratio of time taken for 2nd round : Time taken for 1st round.
1 round = Circumference of the circle = 2πr
1st round :
Speed = πr for 30 seconds. So, total distance travelled = πr/2.
Speed = πr/2 for 1 minute. So, total distance travelled = πr/2.
Speed = πr/4 for 2 minutes. So, total distance travelled = πr/2.
Speed = πr/8 for 4 minutes. So, total distance travelled = πr/2.
So, for a distance of 2πr, time taken is 7.5 minutes.
2nd round:
Speed = πr/16 for 8 minutes. So, total distance travelled = πr/2.
Speed = πr/32 for 16 minutes. So, total distance travelled = πr/2.
Speed = πr/64 for 32 minutes. So, total distance travelled = πr/2.
Speed = πr/128 for 64 minutes. So, total distance travelled = πr/2.
So, for a distance of 2πr, time taken is 120 minutes.
Ratio is 120:7.5 = 16:1.
Answer : C
Question: Anand and Deepak started a business investing Rs. 4,500 and Rs. 6,000 respectively. Out of a total profit of Rs. 420. Deepak's share is?
A.s. 280
B.s. 310
C.s. 240
D.s. 840
Answer: C.s. 240
Explanation: Ratio of their shares = 4500 : 6000 = 3 : 4
Deepak's share = Rs. (420 * 4/7) = Rs. 240 ANSWER "C
Question: Evaluate : (2.39)(power 2) - (1.61) (power 2) / 2.39 - 1.61
A.4
B.6
C.8
D.2
Answer: A.4
Explanation: Given Expression = a(power 2) - b(power 2) / a-b
= (a + b)(a - b) / (a-b)
= (a + b) = (2.39 + 1.61) = 4.
Answer is A.
Question: The average of first 16 even numbers is?
A.10
B.11
C.17
D.13
Answer: C.17
Explanation: Sum of 16 even numbers = 16 * 17 = 272
Average = 272/16 = 17
ANSWER:C
Question: A basket contains 9 marbles. 4 are red and 5 are blue marbles If two marbles are drawn at random what is the probability that at least one ball is red.
A.19/18
B.17/18
C.11/18
D.13/18
Answer: D.13/18
Explanation: Total probability=9C2=36
4C2 +4C1*5C1=6+20=26
therefore the probability that at least one of the red ball will be selected= 26/36=13/18
answer is D
Question: The average age of 38 students in a group is 14 years. When teacherâ€™s age is included to it, the average increases by one. What is the teacherâ€™s age in years?
A.31
B.36
C.53
D.58
Answer: C.53
Explanation: Sol.
Age of the teacher = ( 39 Ã— 15 â€“ 38 Ã— 14 ) years = 53 years.
Answer C
Question: How many three digit numbers N are divisible by 78 or 91?
A.17
B.19
C.20
D.21
Answer: B.19
Explanation: The answer will be 19.
Explanation:
78= 2*3*13 now multiples of 78, 156 ....780, now 1000-780 = 220 only two more muktiples of 78 can exists. So total number of 3 digit Multiples of 78 are 9+2=11
91= 13*7--Total number of three digit multiples --9
No remember we have a common multiples as well N-- 13*7*6=91*6=546
So total number of multiples--11+9 -1 =19.
Hence Answer is 19.B
Question: In three annual examinations, of which the aggregate marks of each was 500, a student secured
average marks 45% and 55% in the first and the second yearly examinations respectively. To secure 50% average total marks, it is necessary for him in third yearly examination to secure marks :
A.300
B.250
C.400
D.450
Answer: B.250
Explanation: total marks:1500 for three exams
50% of 1500=750
first exam marks=45% of 500=225
second exam marks=55% of 500=275
let X be the third exam marks
225 + 275 + X =750
X=250
ANSWER:B
Question: The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?
A.18%
B.16%
C.17%
D.78%
Answer: A.18%
Explanation: 1500 ---- 270
100 ---- ? => 18%
Answer:A
Question: Two circular signs are to be painted. If the diameter of the larger sign is six times that of the smaller sign, how many times more paint is needed to paint the larger sign? (We can assume that a given amount of paint covers the same area on both signs.)
A.6
B.12
C.24
D.36
Answer: D.36
Explanation: Let R be the radius of the smaller sign.
Then the diameter of the smaller sign is 2R, the diameter of the larger sign is 12R, and the radius of the larger sign is 6R.
The area A of the smaller sign is A = piR^2.
The area of the larger sign is pi(6R)^2=36piR^2=36A.
Since the area is 36 times larger, we need 36 times more paint for the larger sign.
The answer is D.
Question: A cube of edge 5cm is immersed completely in a rectangular vessel containing water. If the dimensions of the base of vessel are 10cm * 5cm , find the rise in water level?
A.2.5cm
B.3.6cm
C.5cm
D.6.43cm
Answer: A.2.5cm
Explanation: Increase in volume = volume of the cube = 5*5*5 cm^3
Rise in water level = volume / area = 5*5*5/10*5 = 2.5cm
Answer is A
Question: A baker filled with a measuring cup with 1/4 cup water. He poured 1/2 of the water into the batter, and then spilled 1/8 of the water on the floor. How much water will the baker needed to add what is left in the cup to have 50% more than what he started with?
A.1/8 cup
B.3/8 cup
C.1/4 cup
D.1/2 cup
Answer: B.3/8 cup
Explanation: B
1/4 is the original water in cup .half in batter.So left is 1/8 out which 1/8 is spilled out.So again left with 0.
so 50% more than what he started was = 1/4+1/2*(1/4)=3/8
Amount of water needed to add = 3/8 - 0=3/8
B
Question: If two positive numbers are in the ratio 1/8 : 1/5, then by what percent is the second number more than the first?
A.67%.
B.70%.
C.60%.
D.68%.
Answer: C.60%.
Explanation: Given ratio = 1/8 : 1/5 = 5 : 8
Let first number be 5x and the second number be 8x.
The second number is more than first number by 3x.
Required percentage = 3x/5x * 100 = 60%.
Answer: C
Question: A shopkeeper sold 8articles at the cost price of 10 articles. Then find the profit% or lost%
A.10%
B.25%
C.20%
D.30%
Answer: B.25%
Explanation: here 8 articles selling price = 10 articles cost price
so the difference = 10-8 = 2
% of profit = 2*100/8 = 25%
correct option is B
Question: Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest?
A.65% p.a
B.88% p.a
C.20% p.a
D.66% p.a
Answer: C.20% p.a
Explanation: Rs.1440 - 1200 = Rs.240 is the interest on Rs.1200 for one year.
Rate of interest = (100 * 240) / (100 * 1) = 20% p.a
Answer: C
Question: A certain rectangular window is (1/3) times as long as it is wide. If its perimeter is 28 feet, what are its dimensions in terms of length by width?
A.12 by 2
B.11 by 3
C.10.5 by 3.5
D.10 by 4
Answer: C.10.5 by 3.5
Explanation: 2x+2y=28
x+y=14
x+(1/3)x=14
4x=14*3
x=10.5
Answer C
Question: In how many years Rs 100 will produce the same interest at 5% as Rs. 200 produce in 2 years at 10%
A.8
B.10
C.9
D.12
Answer: A.8
Explanation: Explanation:
Clue:
Firstly we need to calculate the SI with prinical 200,Time 2 years and Rate 10%, it will be Rs. 40
Then we can get the Time as
Time = (100*40)/(100*5) = 8
Option A