RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The first three terms of an infinite sequence are 2, 7, and 22. After the first term, each consecutive term can be obtained by multiplying the previous term by 3 and then adding 1. What is the sum of the tens digit and the units digit of the 22nd term in the sequence?
A.4
B.7
C.6
D.8
Answer: B.7
Explanation: Following the rule of Infinite sequence we obtain the terms of the sequence as mentioned below
02,07,22,67, 202, 607, 1822, 5467...
Observe the last two digits of the sequence which have the cyclicity of 4 and the last two digits repeat in the order {02, 07, 22, 67}
Also 22th Term =4*5 +2
i.e. 35th Terms will have same Last two digits as 2 nd term of the sequence = 07
i.e. Sum of lat two digits of 2ndth Term = 0+7 = 7
B
Question: Two trains start from stations A and B spaced 50 kms apart at the same time and speed. As the trains start, a bird flies from one train towards the other and on reaching the second train, it flies back to the first train. This is repeated till the trains collide. If the speed of the trains is 25 km/h and that of the bird is 100 km/h. How much did the bird travel till the collision.
A.100
B.288
C.127
D.27
Answer: A.100
Explanation: ince the trains is travelling at 25 kmph, at each other, the relative speed is 50 kmph.
Speed = 50 kmph
Distance = 50 km
Time to collision = distance / speed = 1 hr
Speed of bird = 100 kmph
Time flying = 1 hr (the bird is flying till the trains collide)
Distance travelled = speed × time = 100 km
Answer:A
Question: S1 = 6 S2 = 9 ... Sn = 3n + 4 For the sequence above, in which any term n is defined as 3n + 4, what is the value of n for the first term in the sequence to exceed 50?
A.14
B.12
C.13
D.16
Answer: D.16
Explanation: term 16 = 3*16+4 = 52
Answer : D
Question: The distance between Delhi and Mathura is 215 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet?
A.10.50 a.m.
B.00.20 p.m.
C.10.30 a.m.
D.11.40 a.m.
Answer: B.00.20 p.m.
Explanation: D = 215 â€“ 20 = 195
RS = 20 + 25 = 45
T = 195/45 = 4 1/3 hours
8 a.m. + 4 hrs 20 min = 00.20 p.m.
ANSWER:B
Question: A, B and C can do a work in 9 days, 8 days and 12 days respectively. In how many days can all three of them working together, complete the work?
A.3 3/23
B.3 3/28
C.2 2/0
D.2 2/2
Answer: A.3 3/23
Explanation: Work done by all three of them in one day = 1/9 + 1/8 + 1/12 = 23/72.
The number of days required = 72/23 = 3 3/23 days.
Answer:A
Question: If an integer "k" is divisible by 2,5 and 13.what is the next largest number that is divisible by all the three given numbers?
A.k+13
B.k+130
C.2k
D.2k+13
Answer: B.k+130
Explanation: LCM of 2,5,13 is 130
so k=130
2k also the correct answer,but we need to find next largest number
therefore ans is k+130
ANSWER:B
Question: If the number of boys in a class are 8 times the number of girls. If the number of people in the class are 45, how many girls are in the class?
A.A - 5
B.B - 6
C.C - 7
D.D - 8
Answer: A.A - 5
Explanation: Let the number of girls = x and the number of boys = 8x Then, total number of students = x + 8x = 9x = 45Hence, x = 45/9 = 5 i.e., the total number of girls in the class are 5. Answer is A.
Question: Eric throws 2 dice,and his score is the sum of the values shown.Sandra throws one dice and her score is the square of the value shown. what is the probabilty that Sandras score will be strictly higher than Erics score??
A.117/216
B.127/126
C.137/126
D.147/126
Answer: C.137/126
Explanation: sandra score can be like 1,4,9,16,25,36
eric score less then 1-->0
eric score less then 4=(1,1),(1,2)(2,1)-->3
eric score less then 9 are (1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(4,1)(4,2)(4,3)(4,4)(5,1)(5,2)(5,3)(6,1)(6,2)-->26
eric score will always be less then 16--->36
eric score will always be less then 25--->36
eric score will always be less then 36--->36
total favorable outcomes=3+26+36+36+36=137
total possible outcomes=216(36*6)
probability=137/216
ANSWER:C
Question: Two spies agreed to meet at a gas station between noon and 1pm, but they have both forgotten
the arranged time. Each arrives at a random time between noon and 1pm and stays for 6
minutes unless the other is there before the 6 minutes are up. Assuming all random times are
equally likely, what is the probability that they will meet within the hour (noon to 1pm)?
A.0.12
B.0.15
C.0.17
D.0.19
Answer: D.0.19
Explanation: The probability that they do not meet is represented by the total of the areas of the
two outer triangles in the figure below, which is 0.81. So the probability of a meeting is 1 -
0.81 =0 .19.
correct answer D
Question: Raja's club with a total membership of 30 has formed 3 committees, M, S and R which have 8,12, and 5 members respectively. If no member of committee M is on either of the other 2 committees, what is the greatest possible number of members in the club who are on none of the committees.
A.5
B.7
C.8
D.10
Answer: D.10
Explanation: Raja's club with a total membership of 30 has formed 3 committees Given no member of committee M is on either of the other 2 committees -- hence (M n R) and (M n S) and (M n R n S) is zero.
Hence only M is 8. Now we need to consider only S, (S n R) and R.
(M U R U S) = M + R + S - (M n R) - (M n S) - (R n S) + (M n R n S) + Neither.
30 = 8 + (12 - x) + (5 - x) + 0 + 0 + x + 0 + Neither.
22 = (12-x) + (5-x) + x + Neither.
Now the max value of x could be 5 and the min value of x could be 0.
When x is 5 (max), Neither is 10.
When x is 0 (min), Neither is 5. We need maximum no of people who do not belong to any group. Hence max value of neither is 10.
Answer 10 (D).
Question: The sum of the present ages of a father and his son is 50 years. five years ago, father's age was five times the age of the son. After 5 years, son's age will be:
A.16
B.16.2
C.16.1
D.16.66
Answer: D.16.66
Explanation: Let the present ages of son and father be x and (50 -x) years respectively.
Then, (50 - x) - 5 = 5(x - 5)
45 - x = 5x - 25
6x = 70
x = 70/6= 11.66 years
Son's age after 6 years = (x+ 5) = 16.66 years.
answer :D
Question: A committee of two people is to be chosen from 4 married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?
A.16
B.24
C.26
D.30
Answer: B.24
Explanation: One of the approaches:
Each couple can send only onerepresentativeto the committee. Let's see in how many ways we can choose 2 couples (as there should be 2 members) out of 4 to send only onerepresentativesto the committee: 4C2=6.
But each of these 2 couples can send two persons (husband or wife): 2*2=2^2=4.
Total # of ways: 4C2*2^2=24.
Answer: B.
Question: There are 2 sections A and B in a class, consisting of 36 and 44 students respectively. If the average weight of section A is 40kg and that of section B is 35kg, Find the average of the whole class?
A.35.29kg
B.37.25kg
C.42.45kg
D.55.12kg
Answer: B.37.25kg
Explanation: Total weight of 36+44 students = 36*44 + 44*35 = 2980
Average weight of the class is = 2980/80 = 37.25 kg
Answer is B
Question: Of 25 applicants for a job, 14 had at least 4 years' experience, 18 had degrees, and 3 had less than 4 years' experience and did not have a degree. How many of the applicants had at least 4 years' experience and a degree?
A. 14
B. 10
C. 9
D. 7
Answer: B. 10
Explanation: set A : people with more than 4 years exp
set B : people with degree
AUB = total - (less than 4 exp and no degree)
AUB = 25-3=22
AUB = A + B - AiB
AiB = 18+14-22
=10
Answer B
Question: Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 5x boxes?
A.3 minutes
B.4 minutes
C.5 minutes
D.10 minutes
Answer: D.10 minutes
Explanation: Rate = Work / Time
Given Rate of Machine A = X / 10 min
Machine B Produces 2x boxes in 5 min hence , Machine B produces 4x boxes in 10 min .
Rate of Machine B = 4x / 10
we need tofind the combined time that machines A and B, working simultaneouslytakeat their respective constant rates
let's first find the combined Rate of Machine A and B
Rate of Machine A = X / 10 min + Rate of Machine B = 4x / 10 = 5X/10
Now combine Time = combine work needs to be done / Combine Rate = 5x/5x * 10 = 10 Min
Ans: D
Question: In a business school case competition, the top three teams receive cash prizes of $1000, $ 2000, and $ 3000. while remaining teams are not ranked and do not receive any prizes, there are 6 participating teams, named A, B, C, D, E, F. If team A wins one of the prizes, team B wins also one of the prizes. How many outcomes of the competition are possible ?
A.18
B.28
C.36
D.84
Answer: D.84
Explanation: if team A wins one of the prizes, team B wins also one of the prizes". Consider following cases:
A wins one of the prizes, then B must also win one of the prizes, and in this case we can have 4 triplets: {ABC}, {ABD}, {ABE}, {ABF}. Each triplet can be arranged in 3!=6 ways. Hence in the case when A wins one of the prizes 4*6=24 arrangements are possible.
A does NOT win one of the prizes, then three winners must be from other 5 teams. 3 winners out of 5 (B, C, D, E, F) teams can be chosen in C35=10C53=10 ways and each case (for example {CDE}) can be arranged in 3!=6 ways, hence in the case when A does NOT win one of the prizes 10*6=60 arrangements are possible.
Total = 24+60 = 84.
Answer: D.
Question: A mixture of 20 kg of spirit and water contains 10% water. How much water must be added to this mixture to raise the percentage of water to 25%
A.4 kg
B.5 kg
C.8 kg
D.30 kg
Answer: A.4 kg
Explanation: Water in the given mixture = 10*20/100 =2 kg,
And spirit = (20-2) = 18 kg
Let x kg of water added, Then, x+2/20+x *100 ==25
4x+8 =20+x, or x =4 kg
ANSWER:A
Question: In a kickball competition of 9 teams, how many possible matches can each team play with each other?
A.9
B.16
C.24
D.36
Answer: D.36
Explanation: Each team can play with each other in 9C2 ways
9C2 = 9*8 / 1*2 = 36
Option D
Question: Working alone, Mary can pave a driveway in 4 hours and Hillary can pave the same driveway in 3 hours. When they work together, Mary thrives on teamwork so her rate increases by 33.33%, but Hillary becomes distracted and her rate decreases by 50%. If they both work together, how many hours will it take to pave the driveway?
A.2 hours
B.4 hours
C.5 hours
D.6 hours
Answer: A.2 hours
Explanation: Initial working rates:
Mary = 1/4 per hour
Hillary = 1/3 per hour
Rate when working together:
Mary = 1/4 + (1/3*1/4) = 1/3 per hour
Hillary = 1/3 - (1/2*1/3) = 1/6 per hour
Together they work 1/3 + 1/6= 1/2 per hour
So they will need 2 hours to complete the driveway. The correct answer is A.
Question: A and B can do a piece of work in 12 days and 16 days respectively. Both work for 3 days and then A goes away. Find how long will B take to complete the remaining work?
A.6
B.7
C.5
D.9
Answer: D.9
Explanation: 3/12 + (3 + x)/16 = 1
x = 9 days
Answer: D
Question: The edge of a cube is 9a cm. Find its surface?
A.153a2 cm2
B.143a2 cm2
C.233a2 cm2
D.243a2 cm2
Answer: D.243a2 cm2
Explanation: 6a2 = 6 * 9a * 9a = 243a2
Answer:D
Question: On Thursday, Kramer purchases exactly 3 new shirts, 2 new sweaters, and 4 new hats, On the following day and each subsequent day thereafter, Kramer wears one of his new shirts together with one of his new sweaters and one of his new hats. Kramer avoids wearing the exact same combination of shirt, sweater, and hat for as long as possible. On which day is this no longer possible?
A.Monday
B.Wednesday
C.Thursday
D.Friday
Answer: A.Monday
Explanation: Shirt combinations = 3!/1*(3-1)! = 3*2*1/1*2*1 = 3
Sweater combinations = 2!/1*(2-1)! = 2*1/1*1 = 2
Hat combinations = 4!/1!*(4-1)! = 4*3*2*1/1*3*2*1 = 4
Total Combinations = Shirt Combos*Sweater Combos*Hat Combos
3*2*4=24 combinations
24 / 7 (days of the week) = remainder of 3
Purchased on Thursday, 3rd day is Sunday. Next day, which he won't have a new combination for, is Monday. (A)
Question: A small company reduced its faculty by approximately 13 percent to 181 employees. What was the original number of employees?
A.A)182
B.B)208
C.C)220
D.D)224
Answer: B.B)208
Explanation: If x is the original number of employees, then after 13% reduction in employees number is .87x
but we are given .87x = 181
x = 208
So the original number of employees is 208
Correct Answer - B
Question: The sale price sarees listed for Rs.500 after successive discount is 10% and 5% is?
A.427.5
B.879
C.342
D.762
Answer: A.427.5
Explanation: 500*(90/100)*(95/100)
= 427.5
Answer: A
Question: John sold 100 shares of stock for $96 per share. For half his shares, this represented a 20% profit; for the other half, this represented a 20% loss. What was the net gain or net loss on this sale of stock?
A.No loss or gain
B.Gain of $400
C.Loss of $400
D.Gain of $800
Answer: C.Loss of $400
Explanation: Cost of the profitable stock: x=96/1.2=80, so profit from it 96-80=16. Total profit 50*16=800
Cost of the non-profitable stock: y=96/0.8=120, so loss from it 96-120=-24. Total loss 50*(-24)=-1200
Total loss: 800+(-1200)=-400.
Answer: C.
Question: Suppose son name is 120,his brother name is 150 and his mother name is 180.find out his father's name???
A.190
B.210
C.230
D.240
Answer: C.230
Explanation: since difference between all name is =30
so father's name will be 180+30=210.
ANSWER:C
Question: If A lends Rs.2500 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?
A. Rs.107.50
A.112.5
B.122.5
C.132.5
D.114.5
Answer: A.112.5
Explanation: (2500*1.5*3)/100 => 112.50
ANSWER:A
Question: Two integers are in the ratio of 1 to 4. If 6 is added to the smaller number, the ratio becomes 1 to 3. Find the larger integer.
A.4
B.24
C.30
D.72
Answer: D.72
Explanation: One option is to set up the equations and solve:
If the ratio of two integers x and y is 1 to 4, then 4x=y, where x is the smaller integer.
If adding 6 to the smaller integer makes the ratio 1 to 3, then 3(x+6)=y.
Substituting y=4x into the second equation yields 3x+18=4x.
So, x=18 (smaller integer) and, y=4x=72 (larger integer) so D is the correct answer.
Another option is to TEST the answer choices.
A) the larger number is 4
Given: the two integers are in the ratio of 1 to 4
So, the smaller number must be 1
If 6 is added to the smaller number, the ratio becomes 1 to 3
If we add 6 to the smaller number (1), we get 7.
So, the new ratio is 7 to 4.
No good. We want a resulting ratio of 1 to 3
ELIMINATE A
B) the larger number is 24
Given: the two integers are in the ratio of 1 to 4
So, the smaller number must be 6
If 6 is added to the smaller number, the ratio becomes 1 to 3
If we add 6 to the smaller number (6), we get 12
So, the new ratio is 12 to 24 which is 1 to 2.
No good. We want a resulting ratio of 1 to 3
ELIMINATE B
C) the larger number is 30
Given: the two integers are in the ratio of 1 to 4
So, the smaller number must be 7.5 (which is not an integer)
Since both numbers are integers, the larger number cannot be 30.
ELIMINATE C
D) the larger number is 72
Given: the two integers are in the ratio of 1 to 4
So, the smaller number must be 18
If 6 is added to the smaller number, the ratio becomes 1 to 3
If we add 6 to the smaller number (18), we get 24
So, the new ratio is 24 to 72. This is the same as the ratio of 1 to 3
Therefore (D) is correct
E) the larger number is 80
Given: the two integers are in the ratio of 1 to 4
So, the smaller number must be 20
If 6 is added to the smaller number, the ratio becomes 1 to 3
If we add 6 to the smaller number (20), we get 26
So, the new ratio is 26 to 80 which is 13 to 40.
No good. We want a resulting ratio of 1 to 3
ELIMINATE E
Therefore D is the only correct choice.
Question: The daily hotel rates for five hotels John was considering were $60, $125, $80, $70 and $x. If the median price was $5 lower than the average (arithmetic mean) price, which of the following could be $x?
A.$80
B.$85
C.$90
D.$95
Answer: C.$90
Explanation: Look at the options available
Value of x seems to $80 < = $x < = $100
A. $80
B. $85
C. $90
D. $95
E. $100
So position of $x is fourth
$60 , $70 , $80 , $x , $125
Median = $80
Median price was $5 lower than the average, so average = $85
$60 + $70 + $80 + x + $125 = $425
$x = $90 = Answer = C
Question: A 440-liter solution of Kola is made from 88% water, 8% concentrated Kola and the rest is made from sugar. If 3.2 liters of sugar, 10 liter of water and 6.8 liters of concentrated Kola were added to the solution, what percent of the solution is made from sugar?
A.4.52%.
B.7.5%.
C.9.2%.
D.10.5%.
Answer: A.4.52%.
Explanation: Denominator:
440+10+3.2+6.8=460
Numerator:
440(1-.88-.08)+3.2
440(0.04)+3.2
17.6+3.2
20.8
Ratio:
20.8/460=0.045
Answer: A
Question: For every positive integer n, form the number n / s(n), where s(n) is the sum of the digits of n in base 10. What is the minimum value of n/s(n) for 10 <= n <= 99.
A.1.2
B.3.45
C.1.9
D.2
Answer: C.1.9
Explanation: possibility to sum of digits 10
i.e
(1.9),(2,8),(3,7),(4,6),(5,5)
we get s/s()n are 1.9,2.8,3.7,4.6,5.5
so the minimum possibility of s/s(n)=19/10=1.9
ANSWER:C
Question: In one hour,a boat goes 11 km along the stream and 5 km against the stream.The speed of the boat in still water is :
A.3
B.5
C.8
D.9
Answer: C.8
Explanation: Solution
Speed in still water =1/2(11+5) kmph = 8 kmph.Answer C
Question: The cost price of a radio is Rs.1680 and it was sold for Rs.1450, find the loss %?
A.18
B.13
C.15
D.18
Answer: B.13
Explanation: 1680 ---- 230
100 ---- ? => 13%
Answer: B
Question: Out of 15 students in a class, 10 are wearing blue shirts, 2 are wearing green shirts, and 3 are wearing red shirts. Four students are to be selected at random. What is the probability that at least one is wearing a green shirt?
A.10/21
B.20/31
C.30/41
D.40/51
Answer: A.10/21
Explanation: Total possible ways to choose 4 students out of 15 = 15C4 = 1365
The number of ways to choose 4 students with no green shirts = 13C4 = 715
P(no green shirts) = 715/1365 = 11/21
P(at least 1 green shirt) = 1 - 11/21 = 10/21
The answer is A.
Question: On a sum of money, the S.I. for 2 years is $600, while the C.I. is $612, the rate of interest being the same in both the cases. The rate of interest is?
A.3%
B.4%
C.5%
D.6%
Answer: B.4%
Explanation: Difference in C.I. and S.I for 2 years = $612 - $600 = $12
S.I for one year = $300
S.I. on $300 for 1 year = $12
Rate = (100 * 12)/(300) = 4%
The answer is B.
Question: âˆš1.5625 = ?
A.1.05
B.1.25
C.1.45
D.1.55
Answer: B.1.25
Explanation: Explanation:
1|1.5625( 1.25
|1
|-------
22| 56
| 44
|-------
245| 1225
| 1225
|-------
| X
|-------
1.5625 = 1.25.
ANSWER IS B
Question: The sum of three consecutive integers is 312. What is the sum of the next three consecutive integers?
A.315
B.321
C.330
D.415
Answer: B.321
Explanation: a+(a+1)+(a+2)=3a+3=312
(a+3)+(a+4)+(a+5)=(3a+3)+9=312+9=321
Answer: B.
Question: Three hundred gallons of fuel are purchased at $0.90 per gallon. The fuel is consumed at a rate of $0.50 worth of fuel per hour. At this rate, how many hours are required to consume the 300 gallons of fuel?
A.510
B.520
C.530
D.540
Answer: D.540
Explanation: The fuel is consumed at this rate: $0.50/$0.90 = 5/9 gallons per hour.
The time it takes to consume 300 gallons is: 300 / (5/9) = 540 hours.
The answer is D.
Question: The least common multiple of positive integer d and 3-digit integer n is 690. If n is not divisible by 3 and d is not divisible by 2, what is the value of n?
A.115
B.230
C.460
D.575
Answer: B.230
Explanation: The LCM of n and d is 690 = 2*3*5*23.
d is not divisible by 2, thus 2 goes to n
n is not divisible by 3, thus 3 goes to d.
From above:
n must be divisible by 2 and not divisible by 3: n = 2*... In order n to be a 3-digit number it must take all other primes too: n = 2*5*23 = 230.
Answer: B.
Question: Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
A.18 a.m
B.10 a.m
C.167 a.m
D.18 a.m
Answer: B.10 a.m
Explanation: Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
Therefore 20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Answer:B
Question: A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man's rate is?
A.1 kmph
B.3 kmph
C.8 kmph
D.7 kmph
Answer: A.1 kmph
Explanation: DS = 6
US = 4
S = ?
S = (6 - 4)/2 = 1 kmph
Answer: A
Question: A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 20 sec respectively. What is the speed of the train?
A.79.7
B.79.8
C.76.2
D.79.2
Answer: D.79.2
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/20 = y
y = 22
Speed = 22 m/sec = 22 * 18/5
= 79.2 km/hr.
Answer:D
Question: Three faces of a fair die are Yellow, two faces red and two blue.The die is tossed three
times. The probability that the colours, yellow, red and blue appear in the first, second and
third tosses respectively is
A.1/36
B.1/18
C.1/32
D.1/37
Answer: B.1/18
Explanation: Probability of getting yellow color = P(Y) = 3/6 = 1/2
Probability of getting red color = P(R) = 2/6 = 1/3
Probability of getting blue color = P(B) = 2/6=1/3
So, the probability that the colors yellow, red and blue appear in first, second and third toss respectively= P(Y ∩ R ∩ B) = P(Y) x P(R) x P(B) = 1/2 x 1/3 x 1/3 = 1/18
ANSWER:B
Question: If the tens digit x and the units digit y of a positive integer n are reversed, the resulting integer is 81 more than n. What is y in terms of x ?
A. 10 - x
B. 9 - x
C. x + 9
D. x - 1
Answer: C. x + 9
Explanation: Original Digits=xy i.e. Number=10x+y
After reversing the digits:
Digits=yx i.e. Number=10y+x
10y+x is 9 more than 10x+y
10x+y+81=10y+x
10x-x+81=10y-y
9x+81=9y
x+9=y
OR
y=x+9
Ans:C
Question: A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:
A.No profit, no loss
B.5%
C.8%
D.10%
Answer: B.5%
Explanation: C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.
S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680
Gain = (80/1600 * 100)% = 5%
Answer = B
Question: how many such letters pairs r in word FRONTIER having same no. of letters left between them in the word as they have in the series
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: the no of letters between the specific two letters when we write in the alphabetical order should be same as the number of letters between those two letters in the given word
two are possible
1)letters 'o' and 'n'
2)'n' and 'r'......( middle letters are o,p,q i.e 3 letters in alphabetical order & in the given word t,i,e i.e 3 letters)
so 2 such pairs are possible
ANSWER:B
Question: convert 100 miles into inches?
A.6336000
B.6542000
C.5462300
D.6213000
Answer: A.6336000
Explanation: 1 feet = 12 inches
1 mile = 5280 feet
100 mile = 5280*12*100 = 6336000
Ans: A
Question: curie bakes 5 cookies for 5 friends. 2 of the friend arrive early and eat 3 cookies each. How many cookies are left over if the other friends all have the same number of cookies?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: curie made 5*5 cookies = 25 cookies. 2 friends eat 3 cookies, leaving 9 remaining for 2 friends.
9 is not divisible by 2. The 2 friends ate a cumulative number of cookies less than 9 that must be divisible by 2, because the number is the same.
The nearest multiple of 2 is 8.
9-8=1
A is the correct answer
Question: Albert invested amount of 12000 in a fixed deposit for 2 years at compound interest rate of 5 % per annum. How much Albert will get on the maturity of the fixed deposit
A.Rs. 8510
B.Rs. 8620
C.Rs. 8730
D.Rs. 13230
Answer: D.Rs. 13230
Explanation: Explanation:
=>(12000×(1+5/100)2)
=>12000×21/20×21/20
=>13230
Option D