RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Three balls are to be tossed in a row. How many different sequences are possible if red and blue always follow one-another in each toss ?
A.2
B.4
C.6
D.8
Answer: B.4
Explanation: Consider red and blue as one. But, in this arrangement they can be tossed in two different combinations.
Red first and Blue second or blue first and red second. Total we have (R and B) and third color = 2 arrangements to do. Total arrangements= 2*2= 4
B is the answer
Question: If 70% of an equal to 40% of b, then ratio between a and b is?
A.4: 7
B.4: 9
C.4: 2
D.4: 1
Answer: A.4: 7
Explanation: Explanation:
70 a = 40 b
a: b = 4: 7
Answer:A
Question: If 2/a + 3/a + 5/a is an integer, which of the following must also be an integer?
A.12/a
B.3/a
C.6/a
D.10/a
Answer: D.10/a
Explanation: 2/a + 3/a + 5/a
=10/a
Answer D
Question: Two partners investede Rs. 1250 and Rs. 850 respectively in a business. They distributed 60% of the profit equally and decide to distribute the remaining 40% as the ratio of their capitals. If one partner received Rs. 30 more than the other, find the total profit?
A.393.75
B.393.78
C.393.72
D.393.71
Answer: A.393.75
Explanation: Let the total profit be Rs.x
60% of the profit = \inline \frac{60}{100}\times x=Rs.\frac{3x}{5}
from this part of the profit each gets = Rs.\inline \frac{3x}{10}
40% of the profit = \inline \frac{40}{100}\times x=Rs.\frac{2x}{5}
Now, this amount of Rs.\inline \frac{2x}{5} has been divided in the ratio of capitals 1250 : 850 = 25 :17
\inline \therefore Share on first capital = \inline (\frac{2x}{5}\times \frac{25}{42})=Rs.\frac{5x}{21}
Share on second capital = \inline (\frac{2x}{5}\times \frac{17}{42})=Rs.\frac{17x}{105}
Total money received by 1st investor = \inline [\frac{3x}{10}+\frac{5x}{21}]= Rs.\frac{113x}{210}
Total money received by 2nd investor = \inline [\frac{113x}{210}+\frac{97x}{210}]=Rs.\frac{97x}{210}
\inline \therefore x = 393.75
Hence total profit = Rs. 393.75
Answer:A
Question: The difference between a number and its two-fifth is 510. What is 30% of that number?
A.158
B.200
C.255
D.400
Answer: C.255
Explanation: Let the number be x. Then,
x - 2/5 x = 510
x = (510 * 5)/3 = 850
10% of 850 = 255.
Answer:C
Question: By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?
A.28888
B.38000
C.28880
D.27752
Answer: B.38000
Explanation: CP + CP/8 = 45000
CP = 40000
SP = 40000*(95/100) = 38000
Answer: B
Question: The simple interest accrued on an amount of Rs.49500 at he end of three is Rs.17820. What would be the compound interest accured on the same amount at teh same rate in the same period? (Round off your answer to two decimal places?
A.Rs.20043.94
B.Rs.20043.99
C.Rs.20043.95
D.Rs.20043.98
Answer: A.Rs.20043.94
Explanation: Let the rate of interest be R% p.a.
(49500)(3)(R)/100 = 17820
495R = 5940
R = 12
CI on Rs.49500 at 12% p.a. for three years
= 49500{[1 + 12/100]3 - 1} = 69543.936 - 49500 = Rs.20043.94
when rounded off to two decimal places.
Answer:A
Question: How many zeros does 500! end with?
A.201
B.240
C.124
D.125
Answer: C.124
Explanation: According to above 500! has 500/5+500/25+500/125=100+20+4=124 trailing zeros.
Answer: C.
Question: If the sides of a triangle are 36 cm, 34 cm and 20 cm, what is its area?
A.320 cm2
B.360 cm2
C.340 cm2
D.310 cm2
Answer: C.340 cm2
Explanation: The triangle with sides 36 cm, 34 cm and 20 cm is right angled, where the hypotenuse is 36 cm.
Area of the triangle
= 1/2 * 34 * 20
= 340 cm2
Answer: C
Question: Sachin can cover a distance in 1hr 24 min by covering 2/3 of the distance at 4 kmph and the rest at 5 kmph. The total distance is?
A.8 km
B.7 km
C.5 km
D.6 km
Answer: D.6 km
Explanation: dist travelled at 4 kmph speed = 2/3
dist at 5 kmph speed = (1-2/3)d=(1/3)d
tot time = 1 hr 24 min =(64+24) min=84/60hr=>21/15 hr
time = dist/speed
21/15=2/3/4d+1/3/5d
d=6 km
ANSWER D
Question: The length of the bridge, which a train 170 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
A.388
B.267
C.205
D.288
Answer: C.205
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (170 + X)/30 = 25/2 ==> 2(170 + X) = 750 ==> X = 205 m.
Answer: C
Question: The membership of a committee consists of 3 English teachers, 4 Mathematics teachers, and 3 Social Studies teachers. If 2 committee members are to be selected at random to write the committee’s report, what is the probability that the two members selected will both be English teachers?
A.2/3
B.1/3
C.2/9
D.1/12
Answer: D.1/12
Explanation: Probability of first member an English teacher = 3/10
Probability of second member an English teacher = 2/10
Probability of both being english teacher = 3/9 x 2/8 =3/5(D)
Question: An object travels at fifteen feet per minute. How many feet does it travel in 24 minutes and 40 seconds?
A.220
B.156
C.370
D.420
Answer: C.370
Explanation: Convert speed from feet/minute into feet/seconds.
15 feet / mn = 15 feet / 60 sec
In 24 minutes 40 seconds, there are
24*60 + 40 = 1480 seconds
We now multiply speed by time to find distance
1480*15/60 = 370 feet
correct answer C
Question: What is the are of an equilateral triangle of side 16 cm?
A.64√3
B.64√5
C.64√9
D.64√2
Answer: A.64√3
Explanation: Area of an equilateral triangle = √3/4 S2
If S = 16, Area of triangle = √3/4 * 16 * 16
= 64√3 cm2;
Answer:A
Question: The least number of complete years in which a sum of money put out at 20% C.I. will be more than doubled is?
A.5
B.4
C.7
D.1
Answer: B.4
Explanation: P(1 + 20/100)n > 2P or (6/5)n > 2
Now, (6/5 * 6/5 * 6/5 * 6/5) > 2. So, n
= 4 years.
Answer:B
Question: Given that there are 11 cricket players per team, how many ways can you select 10 cricket players from 2 teams if no more than 7 players can be selected from each team?
A.108900
B.457845
C.145256
D.356586
Answer: A.108900
Explanation: Now from each group we have to select 5 persons only: 11C7 * 11C7= 330 * 330 = 108900
Total ways=108900 ways.
Answer A
Question: A, B and C can do a work in 8 days, 8 days and 12 days respectively. In how many days can all three of them working together, complete the work?
A.3
B.2 2/8
C.2 2/0
D.2 2/2
Answer: A.3
Explanation: Work done by all three of them in one day = 1/8 + 1/8 + 1/12 = 1/3
The number of days required = 3 days.
Answer:A
Question: A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
A.22 1/9
B.22 1/7
C.22 1/1
D.22 1/2
Answer: D.22 1/2
Explanation: 100 --- 10 DS = 10
? ---- 1
75 ---- 15 US = 5
? ----- 1 S = (10 - 5)/2
= 22 1/2 kmph.Answer:D
Question: If the average (arithmetic mean) of five consecutive negative integers is 4k – 1, what is the difference between the greatest and least of the five integers?
A.4K
B.4k^2 -4k
C.4-4k
D.4
Answer: D.4
Explanation: (n-2 + n - 1 + n + n + 1 + n + 2)/5 = 4k - 1
=> n = 20k - 5
Greatest = n + 2 = 20k - 5 + 2 = 20k - 3
Least = n - 2 = 20k - 5 - 2
=> Difference = 20k - 3 - (20k - 7)
= 4
Answer - D
Question: How long does a train 120 meters long running at the rate of 54 kmph take to cross a bridge 660 meters in length?
A.33
B.72
C.52
D.82
Answer: C.52
Explanation: Explanation:
T = (660 + 120)/54 * 18/5
T = 52
Answer: Option C
Question: There are a total of 10 students in Mr. Schmidt's gym class. Over the course of a badminton unit, each of the 10 students will compete exactly once against every other student in the class. How many total games of badminton will be played?
A.48
B.47
C.45
D.41
Answer: C.45
Explanation: there are 10 students , if each play with all other members .
then total games can be calculated as 9+8....+1 = 45.
alternate approach is to choose 2 distinct out of 10 = 10c2 = 45
Answer is C.
Question: In a race of 400 m, A can beat B by 40 m and C by 20 m. In how many meter race, C will beat B by 50m ?
A.1000m
B.1200m
C.800m
D.950m
Answer: D.950m
Explanation: Explanation:
A:B = 400 : 360
A:C = 400 : 380
=>B:C = 360:380 = 18:19
When C covers 380 m , B Covers 360 m
When C covers x m , B Covers
=> x - 50 m
18x/19 = x - 50
x = 950 m
Answer: D
Question: The population of a town increases 22% and 25% respectively in two consecutive years. After the growth the present population of the town is 1220. Then what is the population of the town 2 years ago?
A.A)600
B.B)700
C.C)800
D.D)900
Answer: C.C)800
Explanation: Explanation:
Formula: (After =100 denominator
Ago = 100 numerator)
1220 * 100/122 * 100/125 = 800
Answer: Option C
Question: If 30!/10! is written as the product of consecutive integers, the largest of which is 30, what is the smallest of the integers?
A.1
B.3
C.7
D.11
Answer: D.11
Explanation: 30!/10!=30∗29∗28...........11∗10!/10!
Smallest integer = 11
Answer = D
Question: How many 3-digit integers between 100 and 200 have a digit that is the average (arithmetic mean) of the other 2 digits?
A.1
B.7
C.9
D.11
Answer: D.11
Explanation: Since the number is between 100 and 200, the hundreds digit has to be 1.
And since the answer choices are small enough, it won't hurt just to write them out. 102, 111, 120, 123, 132, 135, 147, 153, 159, 174, 195.
Answer D
Question: A sells a bicycle to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays Rs. 225 for it, the cost price of the bicycle for A is
A.627
B.297
C.127
D.150
Answer: D.150
Explanation: Explanation:
125% of 120% of A = 225
125/100 * 120/100 * A = 225
A = 225 * 2/3 = 150.
Answer: D
Question: If x, y, and z are positive integers and x = 4y = 7z, then the least possible value of x - y - z is
A.33
B.17
C.49
D.16
Answer: B.17
Explanation: x - y - z = x - x/4 - x/7
= (28 - 7 - 4 )x/28 = 17x/28
17 is not divisible by 28(it's a prime #), so for least value, x = 28
Answer - B
Question: If 3 persons can do 3 times of a particular work in 3 days, then, 7 persons can do 7 times of that work in
?
A.3 days
B.7 days
C.9 days
D.11 days
Answer: A.3 days
Explanation: That is, 1 person can do one time of the work in 3 days.
Therefore, 7 persons can do 7 times work in the same 3 days itself.
Option 'A'
Question: Insert the missing number. 2, 7, 10, 22, 18, 37, 26
A.42
B.32
C.52
D.62
Answer: C.52
Explanation: There are two series here
2, 10, 18, 26, ... (Increase by 8)
7, 22, 37, ... (Increase by 15)
Hence, next term is 37+15 = 52
Answer is C.
Question: What is the total number of positive integers that are less than 800 and that have no positive factor in common with 800 other than 1?
A.200
B.320
C.480
D.500
Answer: B.320
Explanation: Since 800=2^5*5^2 then a number can not have 2 and/or 5 as a factor.
The odd numbers do not have 2 as a factor and there are 400 odd numbers from 1 to 800.
We then need to eliminate the 80 numbers that end with 5, that is 5, 15, 25,...,795.
There are a total of 400 - 80 = 320 such numbers between 1 and 800.
The answer is B.
Question: Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old as his son. Then the sum of the present ages of the son and the father is
A.54.
B.72
C.105
D.108
Answer: D.108
Explanation: Solution
Let the present ages of Father and Son be 2x years and x years respectively.
Then	(2x-18)=3(x-18)
2x-18=3x-54
x=54-18
x=36.
Required sum	= (2x+x)
=3x
=3x36
=108 years.
Answer D
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 900 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
A.140 sq.units
B.120 sq.units
C.187 sq.units
D.607 sq.units
Answer: B.120 sq.units
Explanation: Given that the area of the square = 900 sq.units
=> Side of square = √900 = 30 units
The radius of the circle = side of the square = 30 units
Length of the rectangle = 2/5 * 30 = 12 units
Given that breadth = 10 units
Area of the rectangle = lb = 12 * 10 = 120 sq.units
Answer: B
Question: Twenty-four men can complete a work in sixteen days. Thirty-two women can complete the same work in twenty-four days. Sixteen men and sixteen women started working and worked for twelve days. How many more men are to be added to complete the remaining work in 2 days?
A.48
B.24
C.36
D.16
Answer: B.24
Explanation: 24 men complete the work in 16 days
∴ 16 men complete (16⁄24 × 12⁄16) = 1⁄2 part of work in 12 days
32 women complete the work in 24 days
∴ 16 women complete 16⁄32 × 14⁄24) = 7⁄24 part of work in (12 + 2 ) = 14 days
So, the remaining part of the work which is done by sixteen men + sixteen women and the reqd additional no. of men in 2 days
= 1 - (1⁄2 + 7⁄24) = 1⁄2 - 7⁄24 = 5⁄24 (part)
Now, in 2 days 5⁄24 part of the work is done by
24 × 16⁄2 × 5⁄24 = 40 men
Hence, the reqd. additional no. of men
= 40 – 16 = 24 men.
Answer B
Question: In a shop, the cost of 4 shirts, 4 pairs of trousers and 2 hats is $560. The cost of 9 shirts, 9 pairs of trousers and 6 hats is $1,290. What is the total cost of 1 shirt, 1 pair of trousers and 1 hat?
A.$150
B.$545
C.$214
D.$332
Answer: A.$150
Explanation: Let x be the price of one shirt, y be the price of one pair of trousers and z be the price of one hat.
4x + 4y + 2z = 560 :
9x + 9y + 6z = 1,290
3x + 3y + 2z = 430 : divide all terms of equation C by 3
x + y = 130 : subtract equation D from equation B
3(x + y) + 2z = 430 : equation D with factored terms.
3*130 + 2z = 430
z = 20 : solve for z
x + y + z = 130 + 20 = $150
correct answer A
Question: If Ryan has 20% more notebook than justin.and Ryan have 18 notebook then Justin have how many notebooks?
A.16
B.14
C.12
D.15
Answer: D.15
Explanation: lets Justin have x notebook.
(18-x)*100/x=20
1800-100x=20x
120x=1800
x=1800/120
x=15
answer D
Question: In a recent survey at a local deli, it was observed that 3 out of 5 customers bought a bagel and 5 out of 7 customers bought a coffee. Some customers bought both. If 6 customers are selected, what are the chances that at least 1 customer bought a coffee and a bagel?
A.27/343
B.3/7
C.27/125
D.776/965
Answer: D.776/965
Explanation: Let us take 7*5=35 as the total number of customers. So 7*3=21 customers bought a bagel and 5*5=25 customers bought a coffee.
chances that at least 1 customer bought a coffee and a bagel = 1 - chances that no customer bought a coffee and a bagel
chances that no customer bought a coffee and a bagel= 24/35*23/34*22/33*21/32*20/31*19/30=189/965
chances that at least 1 customer bought a coffee and a bagel= 1 -189/965 = 776/965
Answer D.
Question: A can do a piece of work in 10 days, B in 15 days. They work for 5 days. The rest of work finished by C in 2 days. If they get Rs 1500 for the whole work, the daily wages of B and C are?
A.275
B.250
C.225
D.300
Answer: C.225
Explanation: Part of work done by A = 5/10 = 1/2
Part of work done by B = 1/3
Part of work done by C = (1- (1/2 + 1/3)) = 1/6
A’s share : B’s share : C’s share = 1/2 : 1/3 : 1/6 = 3 : 2 : 1.
A’s share = (3/6) x 1500 = 750
B’s share = (2/6) x 1500 = 500
C’s share = (1/6) x 1500 = 250
A’s daily wages = 750/5 = 150/-
B’s daily wages = 500/5 = 100/-
C’s daily wages = 250/2 = 125/-
Daily wages of B & C = 100 + 125 = 225/-
ANSWER:C
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either blue or yellow?
A.2/29
B.2/20
C.2/21
D.2/28
Answer: C.2/21
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. Probability that both marbles are blue = ³C₂/¹⁵C₂ = (3 * 2)/(15 * 14) = 1/35
Probability that both are yellow = ²C₂/¹⁵C₂
= (2 * 1)/(15 * 14) = 1/105
Probability that one blue and other is yellow
= (³C₁ * ²C₁)/¹⁵C₂ = (2 * 3 * 2)/(15 * 14)
= 2/35
Required probability = 1/35 + 1/105 + 2/35
= 3/35 + 1/105 = 1/35(3 + 1/3)
= 10/(3 * 35)
= 2/21
Answer:C
Question: A rectangular field is to be fenced on three sides leaving a side of 80 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required?
A.44ft
B.97ft
C.22ft
D.11ft
Answer: B.97ft
Explanation: Given that length and area, so we can find the breadth.
Length x Breadth = Area
80 x Breadth = 680
Breadth = 8.5 feet
Area to be fenced = 2B + L = 2 (8.5) + 80 = 97 feet
Answer: B) 97ft
Question: How many 8 ′ s are there in the given sequence which are not immediately preceded by 09 and not immediately followed by 90?
9 0 8 0 9 0 9 8 9 0 8 9 0 8 0 9 8 9 0 9 8 0 9 8 9 0 8 9 0
A.3
B.1
C.2
D.More than 3
Answer: A.3
Explanation: the given logic is executed 3 times for 8's occuring at 2nd eight,5th eight and 7th eight in the sequence.
ANSWER:A
Question: A product when sold with 10% rebate on the listed price gave a profit of Rs.70. What was its cost price?
A.Rs. 200
B.Rs. 250
C.Rs. 300
D.Cannot be determined
Answer: D.Cannot be determined
Explanation: Solution
Since the marked price is not given, so the cost price cannot be determined.
Answer D
Question: The average of first 10 natural numbers is?
A.5.7
B.5.5
C.5.6
D.5.4
Answer: B.5.5
Explanation: Sum of 10 natural no. = 110/2 = 55
Average = 55/10 = 5.5
Answer: B
Question: If 18 bindres bind 900 books in 10 days , How many binders will be required to bind 660 books in 12 days?
A.17
B.77
C.12
D.11
Answer: D.11
Explanation: Explanation:
Let the required no of binders be X.
Less books , Less binders (Direct Proportion)
More days, Less binders (Indirect proportion)
\inline \fn_jvn \left.\begin{matrix} Books\: 900:600\\ Days\: \: 12:10 \end{matrix}\right\}::18:x
\inline \fn_jvn \therefore \inline \fn_jvn (900\times 12\times x)=(600\times 10\times 18) \inline \fn_jvn \Leftrightarrow x= \inline \fn_jvn \frac{600\times 10\times 18}{900\times 12} = 11
Answer: D
Question: How many Books each of Volume 100 meter cube can be packed into a crate of volume 3000 meter cube?
A.50
B.cannot be determined
C.150
D.300
Answer: B.cannot be determined
Explanation: Gud question with a simple concept.
In geo if we want to insert one shape into another we need to know the dimensions of the two shapes.
In above with volume given , we can come up with different shapes, so we cant know the answer
For ex :3000 m3 can be 300*10 or 30*100 or just 3000*1 we don't know , so we cant calculate
Answer : B
Question: The average of 6 observations is 16. A new observation is included and the new average is decreased by 1. The seventh observation is?
A.1
B.3
C.9
D.6
Answer: C.9
Explanation: Let seventh observation = X.
Then, according to the question we have
=> (96 + X) / 7 = 15
=> X = 9
Hence, the seventh observation is 9.
ANSWER:C
Question: A zoo has an average of 510 visitors on Sundays and 480 on Saturday, 210 on other days and Wednesday is holiday. The average number of visitors in a month of 30 days starting with Saturday is
A.252
B.268
C.277
D.295
Answer: C.277
Explanation: Number of saturdays and sundays in that month is 5 and number of wednesdays in that month is 4.
Total number of visitors=(510x5)+(480x5)+((20-4)x210)=8310
Average visitor per day= 8310/30 = 277
Answer: C
Question: If the GCD of two numbers (not equal, both integers, greater than 1) is 2, then which of the following can be true?
A. They are prime.
B. They are consecutive.
C. They do not have a common prime factor.
D. They have a common factor other than 2.
A.Only A
B.Only B
C.Only C
D.Only D
Answer: D.Only D
Explanation: The GCD of two numbers (not equal, both integers, greater than 1) is 2 means that they don't share factors other than 1 and 2.
This also means that both numbers are even ( divisible by 2.)
A. They are not prime. 2 is the only even number that is prime, so one number can be prime but the other number cannot be.
B. They are not consecutive. With two consecutive numbers, one will be even and one will be odd.
C. They have a common prime factor. The question defines the numbers as having a GCD of 2, which is prime.
D. They have a common factor other than 2. Both numbers have common factors of 2 and 1. For example:
The factors of 4 are 1 and 2, the factors of 6 are 1, 2, and 3.
Therefore, (D) is the only correct answer.
Question: In Mrs. Susna's class, 1/4 of her students are getting an A, 1/2 are getting a B, 1/8 are getting a C, 1/12 are getting a D, and 1/24 are getting a F. What fraction of Mrs. Susna's class getting a passing grade of C or higher.
A.5/6
B.3/4
C.7/8
D.1/8
Answer: C.7/8
Explanation: If Mrs. Susna's class has 24 students, the number of students receiving As, Bs, or Cs, are 6, 12, and 3 respectively. That means 21/24 of her students are receiving passing grades or 7/8. (Answer:C)
Question: Find the probability that a number selected from numbers 1, 2, 3,...,45 is a prime number, when each of the given numbers is equally likely to be selected?
A.10/45
B.14/45
C.8/45
D.3/45
Answer: B.14/45
Explanation: Let X be the event of selecting a prime number.
X = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41,43}
n(X) = 14,
n(S) = 45
Hence, the required probability is 14/45.
ANSWER:B
Question: If log 27= 1.431, then the value of log 9 is:
A.0.934
B.0.945
C.0.954
D.0.958
Answer: C.0.954
Explanation: log 27 = 1.431 => log 33 = 1.431
=> 3 log 3= 1.431 => log 3 = 0.477
Therefore, log 9 = log 32 = 2 log 3 = (2*0.477) = 0.954
ANSWER:C
Question: If (2^16)(25^S) = 5(10^m) what is the value of m ?
A.7
B.8
C.15
D.16
Answer: D.16
Explanation: given
2^16 * 25^s = 5 * 10^2
=> 2^16 * 5^(2s) = 2^m * 5^(m+1)
Ans D
on comparing the power of 2 => m=16
Question: What least number must be subtracted from 42398 so that remaining no.is divisible by 15
A.3
B.5
C.6
D.8
Answer: D.8
Explanation: Explanation:
On dividing 42398 by 15 we get the remainder 8, so 8 should be subtracted
Option D
Question: A tourist purchased a total of $2,500 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
A.$1,430
B.$1,310
C.$1,290
D.$2,270
Answer: D.$2,270
Explanation: Let the number of $10 checks cashed beT
Let the number of $50 checks cashed beF
7 checks cashed;
T+F=7
Now; T can be F+1 OR T can be F-1
Let's check both conditions;
T=F+1
T+F=7
F+1+F=7
2F=6
F=3
T=4
Value cashed = 3*50+4*10=150+40=$190
Let's check the other condition as well;
T=F-1
T+F=7
F-1+F=7
2F=8
F=4
T=3
Value cashed = 4*50+3*10=200+30=$230
The more money he cashes, the less loss he incurs. Thus, we must consider the latter case.
Value cashed = $230
Value lost = 2500-230 = $2270
Ans:D
Question: A stock trader originally bought 300 shares of stock from a company at a total cost of m dollars. If each share was sold at 80% above the original cost per share of stock, then interns of m for how many dollars was each share sold?
A.a) 2m/300
B.b) 9m/1500
C.c) m/200
D.d) m/300 + 50
Answer: B.b) 9m/1500
Explanation: Let Cost of 300 shares be $ 3000
So, Cost of 1 shares be $ 10 =>m/300
Selling price per share = (100+80)/100 * m/300
Or, Selling price per share = 9/5 * m/300 => 9m/1500
Hence answer will be (B)
Question: Martha takes a road trip from point A to point B. She drives x percent of the distance at 60 miles per hour and the remainder at 30 miles per hour. If Martha's average speed for the entire trip is represented as a fraction in its reduced form, in terms of x, which of the following is the numerator?
A. 18,000
B. 300
C. 1,100
D. 3,000
Answer: A. 18,000
Explanation: total distance = d
total time taken = x/(100*60) + (100-x)/(100*30)
speed = distance / time
gives numerator = 18000
Answer : A
Question: If xy = 5 and x^2 + y^2 = 15, then x/y + y/x =
A.2 2/5
B.3
C.5 1/3
D.7
Answer: B.3
Explanation: x/y+y/x=(x^2+y^2)/xy =substitute given we get 15/5=3 answer B
Question: For a finite sequence of non zero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -5 ?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: Given sequence: {1, -3, 2, 5, -4, -6}
The questions basically asks: how manypairs of consecutive termsare there in the sequence such that the product of these consecutive terms is negative.
1*(-3)=-3=negative;
-3*2=-6=negative;
2*5=10=positive;
5*(-4)=-20=negative;
(-4)*(-6)=24=positive.
So there are 3 pairs of consecutive terms of the sequence for which the product is negative.
Answer: B.