RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If a(a - 7) = 8 and b(b -7) = 8, where a ≠ b, then a + b =
A.−48
B.−2
C.2
D.7
Answer: D.7
Explanation: i.e. if a = -1 then b = 8
or if a = 8 then b = -1
But in each case a+b = -1+8 = 7
Answer: option D
Question: If the simple interest on a sum of a money for 1 years at 4% per annum is rs 70 what is the compound interest on the sum of the same rate and same time
A.$856.38
B.$752.36
C.$523.98
D.$1822.8
Answer: D.$1822.8
Explanation: sum= 70*100/1*4=1750
amount=$(1750(1+4/100)^2)
=1700*26/25*26/25
=$1892.8
C.I=Rs.(1892.8-70)=$.1822.8
Answer (D)
Question: A candidate got 35% of the votes polled and he lost to his rival by 2250 votes. How many votes were cast?
A.7500
B.3388
C.2665
D.2888
Answer: A.7500
Explanation: 35%-----------L
65%-----------W
------------------
30%----------2250
100%---------? => 7500
Answer: A
Question: In how many ways the word "CALORIES" can be arranged?
A.40322
B.40320
C.45340
D.None
Answer: B.40320
Explanation: Explanation :
The required number of ways = 8!
= 40320
Answer : B
Question: (0.15)(power 3) - (0.1)(power 3)/ (0.15)(power 2) + 0.015 + (0.1)(power 2) is:
A.0.68
B.0.08
C.0.05
D.0.06
Answer: C.0.05
Explanation: Given expression
= (0.15) (power 3) - (0.1)(power 3) / (0.15)(power 2) + (0.15 x 0.1) + (0.1)(power 2)
= a (power 3) - b(power 3) / a(power 2) + ab + b(power 2)
= (a - b)
= (0.15 - 0.1)
= 0.05
Answer is C.
Question: In a certain pond, 55 fish were caught, tagged, and returned to the pond. A few days later, 55 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what`s the approximate number of fish in the pond?
A.400
B.625
C.1250
D.1528
Answer: D.1528
Explanation: The percent of tagged fish in the second catch is 2/55*100 = 3.64%.
We are told that 3.64% approximates the percent of tagged fish in the pond. Since there are 55 tagged fish, then we have 0.036x = 55 --> x = 1,528.
Answer: D.
Question: A businessman earns $27800 in December, thus decreasing his average annual (January to December) earnings by $1200. His average annual earnings would be
A.$29000
B.$33500
C.$40200
D.$41000
Answer: D.$41000
Explanation: (x - 27,800)/11 - x/12 = 1,200
x = 492,000
x/12 = 41,000
Answer: D.
Question: A courtyard is 18 meter long and 12 meter board is to be paved with bricks of dimensions 15 cm by 13 cm. The total number of bricks required is :
A.16000
B.18078
C.11076
D.11456
Answer: C.11076
Explanation: Explanation:
Number of bricks =Courtyard area /1 brick area
=(1800Ã—1200 /15Ã—13)=11076
Option C
Question: If a person walks at 25 km/hr instead of 10 km/hr, he would have walked 31 km more. The actual distance traveled by him is?
A.30
B.25
C.20.67
D.12.33
Answer: C.20.67
Explanation: Let the actual distance traveled is 'x' km
Then by given conditions, we have
x/10 = (x+31)/25
25x = 10x + 310
x = 20.67 km
Ans- C
Question: A buffet consists of 5 main dishes and 4 side dishes. If a plate is created with 2 main dishes and 2 side dishes, in how many ways can the plates be formed?
A.36
B.60
C.66
D.180
Answer: B.60
Explanation: Choose 2 main dishes from 5 main dishes and 2 side dishes from 3 side dishes:
2C5 * 2C4 = 10*6 = 60
Ans: B
Question: 46080, 3840, 384, 48, 8, 2, ?
A.0.5
B.1
C.1.5
D.2
Answer: B.1
Explanation: 46080 ÷ 12 = 3840
3840 ÷ 10 = 384
384 ÷ 8 = 48
48 ÷ 6 = 8
8 ÷ 4 = 2
2 ÷ 2 = 1
Answer is B.
Question: A hat company ships its hats, individually wrapped, in 8-inch by 10-inch by 12-inch boxes. Each hat is valued at $7.00. If the company’s latest order required a truck with at least 288,000 cubic inches of storage space in which to ship the hats in their boxes, what was the minimum value of the order?
A.$960
B.$1,350
C.$1,725
D.$2,100
Answer: D.$2,100
Explanation: Total Volume is 288000
Given LBH = 8*10*12.
the number of hats inside it = 288000/10 * 8 * 12 = 300.
price of each hat is 7.5 $ then total value is 300 * 7.0 = 2100.
IMO option D is correct answer..
Question: Kailash loses 20% of his pocket money. After spending 25% of the remainder he has Rs 480 left. What was his pocket money?
A.Rs 600
B.Rs 800
C.Rs 900
D.Rs 1000
Answer: B.Rs 800
Explanation: Let A be the pocket money,
A ( 1 + x/100) ( 1 + y/100) = 480 (Given)
Here x = - 20, y = - 25
Therefore,
A( 1 - 20/100) ( 1 - 25/100) = 480
A = (480 x 100 x 100) / (80 x 75) = Rs 800
ANSWER:B
Question: Two persons starting from the same place walk at a rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5km apart, if they walk in the same direction?
A.17 hrs
B.22 hrs
C.25 hrs
D.12 hrs
Answer: A.17 hrs
Explanation: The relative speed of the boys = 5.5kmph – 5kmph
= 0.5 kmph
Distance between them is 8.5 km
Time= 8.5km / 0.5 kmph = 17 hrs
Answer : A.
Question: In a pair of fractions, fraction A is twice the fraction B and the product of two fractions is 2/25. What is the value of fraction A?
A.1/5
B.1/25
C.2/5
D.3/5
Answer: C.2/5
Explanation: Explanation:
A = 2B => B = 1/2 A, so, AB = 2/25
1/2 A2 = 2/25
A2 = 4/25
A = 2/5
ANSWER IS C
Question: The measures of the 2 acute angles of a triangle are in the ratio of 3 : 6. What arethe measures of the 2 angles?
A.20°
B.70°
C.60°
D.120°
Answer: C.60°
Explanation: If the ratio of the two angles is 3:6, then the measures of two angles can be written as 3x and 6x. Also the two acute angles of a triangle is equal to 90°. Hence
3x + 6x = 90
9x = 90
x = 10
Measures of the two acute angles are
3x = 3 × 10 = 30°
6x = 6 × 10 = 60°
C
Question: A tradesman by means of his false balance defrauds to the extent of 20%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
A.37
B.27
C.44
D.26
Answer: C.44
Explanation: Explanation:
g% = 20 + 20 + (20*20)/100
= 44%
Answer: C
Question: 49 Ã— 49 Ã— 49 Ã— 49 x 49 Ã— 49 Ã— 49 Ã— 49= 7?
A.4
B.7
C.8
D.16
Answer: D.16
Explanation: 49 Ã— 49 Ã— 49 Ã— 49 x 49 Ã— 49 Ã— 49 Ã— 49 = 7?
or, 7(2) Ã— 7(2) Ã— 7(2) Ã— 7(2) x 7(2) Ã— 7(2) Ã— 7(2) Ã— 7(2)= 7^?
or 7(16) = 7? or, ? =16
Answer D
Question: 5/9= 25/45 . which method did you use to determine whether this proportion is true or false?
A.true
B.neutral
C.false
D.not sure
Answer: A.true
Explanation: 5/9= 25/45. cross multiplication: 5 * 45= 225, 25 * 9 = 225,
we see that 225 are not equal to 225. so there is proportion. corrcet answer: (A)
Question: The sum of the number of boys and girls in a school is 150. if the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is ?
A.60
B.38
C.26
D.29
Answer: A.60
Explanation: Explanation:
We have : x + x% of 150 = 150
Answer: A) 60
Question: A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 86.49, the number of the member is the group is:
A.93
B.67
C.77
D.87
Answer: A.93
Explanation: Money collected =(86.49 x 100) paise = 8649 paise
numbers of members = 8649 squareroot = 93
Answer A
Question: Which of the following is two more than the square of an odd integer?
A.14,173
B.14,361
C.14,643
D.14,737
Answer: C.14,643
Explanation: one of the given options should be a square if 2 is subtracted from it.
the options would be
(A) 14,171
(B) 14,359
(C) 14,641
(D) 14,735
(E) 14,979
We can solve this question with many approaches. Here are the 2 easiest methods.
Method 1:-
If a square has odd unit's digit, then it's ten's digit will always be even.
Only 14,641 satisfies this condition.
Method 2:-
If you know about palindromic numbers,
then you can clearly see that 14,641 is a palindromic square.
Answer:- C
Question: E and F have a data plan which gives them 200 GB every month. If E uses 7 GB every 9 days and F uses 5 GB every 4 days, how many GB will be unused after a 30 day month? Answer in fractions.
A.365/6
B.73/6
C.35/6
D.835/6
Answer: D.835/6
Explanation: Number of GB that E uses every day: 7/9
Number of GB that F uses every day: 5/4
Number of GB that E and F use every day: 7/9+5/4=73/36
Number of GB that E and F use in 30 days: 30x(73/36)=365/6
Number of GB remaining: 200-365/6=835/6
Answer is D
Question: John has taken four (4) tests that have an average of 83. In order to bring his course grade up to a ‘B’, he will need to have a final average of 87. What will he need to average on his final two tests to achieve this grade?
A.87
B.90
C.92
D.95
Answer: D.95
Explanation: Traditional Method:
Total scored till now 83*4=332
Total score to avg 87 in 6 tests = 87*6=522
Total to be scored on 2 tests = 522-332=190
Avg on 2 tests = 190/2 = 95
Answer: D
Question: Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 60 white marbles. How many red marbles could be in bag A?
A.1
B.3
C.4
D.12
Answer: D.12
Explanation: 6 is the answer.
Bag A-
R:W:B = 2:6:9
Let W in bag A be 6K
Bab B -
R:W = 1:4
Let W in bag B be 4k
W = 60 = 6K+4k
=> k =6
Total Red's in bag A will be 2K = 12
D
Question: Sam purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?
A.5.2%
B.5.4%
C.5.6%
D.6%
Answer: C.5.6%
Explanation: Cost Price of 1 toy = Rs. 375 = Rs. 31.25
12
Selling Price of 1 toy = Rs. 33
So, Gain = Rs. (33 - 31.25) = Rs. 1.75
Profit % = 1.75	x 100	%	=	28	% = 5.6%
C)
Question: Sachi invested amount of 8000 in a fixed deposit for 2 years at compound interest rate of 5 % per annum. How much Sachi will get on the maturity of the fixed deposit.
A.8000
B.8500
C.8820
D.8870
Answer: C.8820
Explanation: CI = (800*(1+5/100)^2
==> 8820
ANSWER C
Question: At a particular graduation party with 300 guests, 70% of the guests brought gifts, and 40% of the female guests brought gifts. If 15 males did not bring gifts to the party, how many females did bring gifts?
A.18
B.28
C.50
D.68
Answer: C.50
Explanation: the correct method
total = 300..
70% of 300 = 210 got gifts..
90 did not get gift, out of which 15 are males, so remaining 90-15=75 are females..
But 40% females brought gift, so 60% did not get it..
so 60% = 75, 100%= 75*100/60=125..
ans 40% of 125 =50
C
Question: If a is the sum of b and c, then which one of the following must equal b – c?
A.a+2c
B.a+c
C.a-c
D.a-2c
Answer: D.a-2c
Explanation: Given a= b+c if you subtracts both side with -2c
a-2c = b-c
Answer : D
Question: Husband has prepared for a candle light dinner on the honeymoon for his wife. While they were having the dinner, a strong breeze flew through the open window and four candles out of ten were extinguished. After that, the husband closed the window.
How many candles were left in the end?
A.2
B.3
C.4
D.5
Answer: C.4
Explanation: Solution:
Four
As the window was closed it is obvious that the six candles that were not extinguished were lit till they melted away entirely. Thus only four candles that were extinguished remain at the end.
Answer C
Question: Mr. Jones is the Chairman of a committee. In how many ways can a committee of 5 be chosen from 10 people given that Mr. Jones must be one of them?
A.126
B.252
C.459
D.3024
Answer: A.126
Explanation: Total Ways of choosing the committee = Total Ways of choosing 4 out of 9 candidates leaving Mr.Jones as one of the selected candidate in advance
Total Ways of choosing 4 out of 9 candidates = 9C4 = 9!/(5!*4!) = 126
Answer: option A
Question: There are cats got together and decided to kill the mice of 999975. Each cat kills equal number of mice and each cat kills more number of mice than cats there were. Then what are the number of cats?
A.941,1009
B.991,1001
C.995,1005
D.791,1009
Answer: C.995,1005
Explanation: 999975 can be written as 1000000 â€“ 25
= 10002 â€“ 52 ie of the form a2-b2=(a+b)(a-b)
=(1000+5)*(1000-5)
= (1005)*(995)
Given that number of cats is less than number if mice.
So number of cats is 995 and number of mice were 1005
Answer C
Question: The average of six numbers is 3.95. The average of two of them is 3.2, while the average of the other two is 3.85. What is the average of the remaining two numbers?
A.4.5
B.4.6
C.4.7
D.4.8
Answer: D.4.8
Explanation: Sum of the remaining two numbers
= (3.95 × 6) – [(3.2 × 2) + (3.85 × 2)]
= 23.70 – (6.4 + 7.7)
= 23.70 – 14.1 = 9.60
∴ Required average = (9.6⁄2) = 4.8
Answer D
Question: How many shots of 1cm radius can be prepared from a sphere of 3cm radius?
A.33
B.77
C.27
D.88
Answer: C.27
Explanation: 4/3 π * 3 * 3 * 3 = 4/3 π * 1 * 1 * 1 * x
x = 27
Answer: C
Question: A club wants to mix 30 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?
A.30
B.40
C.50
D.60
Answer: D.60
Explanation: Let number of pounds of 5$ candy to be used be w
6 = (30*8 + 5*w)/(30 +w)
=>180 + 6w = 240 + 5w
=> w = 60
Answer D
Question: How many even multiples of 25 are there between 249 and 501?
A.5
B.6
C.9
D.10
Answer: B.6
Explanation: 250 = 10*25
500 = 20*25
The even multiples are 25 multiplied by 10, 12, 14, 16, 18, and 20 for a total of 6.
The answer is B.
Question: How many two letter words are formed using the letters of the word RAM?
A.8
B.1
C.6
D.4
Answer: C.6
Explanation: The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is 3P2
= 3 * 2 = 6.
Answer: C
Question: Jim is able to sell a hand-carved statue for $550 which was a 35% profit over his cost. How much did the statue originally cost him?
A.$407.41
B.$412.40
C.$455.40
D.$474.90
Answer: A.$407.41
Explanation: 550 = 1.35*X
X = 550/1.35 = 407.407407...
which rounds to $407.41, which is (A).
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.37
B.240
C.288
D.267
Answer: B.240
Explanation: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.Answer: B
Question: Anand and Deepak started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Deepak’s share is :
A.Rs. 5400
B.Rs.7200
C.Rs. 8400
D.Rs. 9600
Answer: C.Rs. 8400
Explanation: Ratio of their shares = 22500 : 35000 = 9 : 14.
Deepak’s share = Rs. 13800 * 14/23
= Rs. 8400
ANSWER:C
Question: A man walking at a rate of 10km/hr crosses a bridge in 3 minutes. The length of the bridge is?
A.500
B.650
C.250
D.111
Answer: A.500
Explanation: Speed = 10*5/18 = 50/18 m/sec
Distance covered in 5 minutes = 50/18 * 5 *60 = 500 m
Answer is A
Question: A BAG CONTAINS 6 WHITE AND 4 BLACK BALLS .2 BALLS ARE DRAWN AT RANDOM. FIND THE PROBABILITY THAT THEY ARE OF SAME COLOUR.
A.7/15
B.4/8
C.15/7
D.6/7
Answer: A.7/15
Explanation: LET S BE THE SAMPLE SPACE
THEN N(S)=NO OF WAYS OF DRAWING 2 BALLS OUT OF (6+4)=10C2=(10*9)/(2*1)=45
LET E=EVENT OF GETTING BOTH BALLS OF SAME COLOUR
THEN N(E)=NO OF WAYS(2 BALLS OUT OF SIX) OR(2 BALLS OUT OF 4)
=(6C2+4C2)=(6*5)/(2*1)+(4*3)/(2*1)=15+6=21
P(E)=N(E)/N(S)=21/45=7/15
Ans: A
Question: A team bought a total of 355 balls. If each player on the team bought at least 16 balls, then what is the greatest possible number of players on the team?
A.21
B.22
C.23
D.24
Answer: B.22
Explanation: 355/16=22 plus remainder.
The answer is B.
Question: A, B, and C were to be paid in proportion to the part of work they did while working on the same piece of work. A and B individually can finish the piece of work in 12 days and 10 days respectively. They worked together for five days and then C completed the remaining work all alone. If $720 was the net sum to be paid for the entire work, what was the average daily wage of B?
A.$144
B.$90
C.$72
D.$54
Answer: C.$72
Explanation: The correct answer is C.
Question: John takes 18 hours to complete a certain job, while Bill takes only 6 hours to complete the same job. If Steve is faster than John but slower than Bill at completing the same job, then which of the following could be the time it takes the three men together, working at their constant, individual rates, to complete the job?
A.2 hours, 10 minutes
B.2 hours, 30 minutes
C.3 hours, 10 minutes
D.3 hours, 45 minutes
Answer: C.3 hours, 10 minutes
Explanation: The rate of John plus Bill is 1/18 + 1/6 = 4/18 of the job completed per hour.
If Steve worked at the same rate as John, the rate would be 4/18 + 1/18 = 5/18
The slowest possible time would be 18/5 hours = 3 hours, 36 minutes.
If Steve worked at the same rate as Bill, the rate would be 4/18 + 1/6 = 7/18
The fastest possible time would be 18/7 hours = 2 hours + 4/7 hours.
The actual time is somewhere between these two extreme points.
The answer is C.
Question: If the speed of Y meters per minute is equivalent to the speed of X kilometers per hour, what is X in terms of Y? (1 kilometer=1000 meters)
A.15y/18
B.6y/5
C.18y/5
D.6y/100
Answer: D.6y/100
Explanation: If the speed of Y meters per second is equivalent to the speed of X kilometers per hour, what is X in terms of Y? (1 kilometer=1000 meters)
We need to find an equation with y in the answer...
convert all measurements so they are alike (i.e. convert km to m, minutes to hours, etc)
Speed = y/t
y meters/second
(60) x meters/hour
Speed = x/t
x KM/hour
Speed = x(1000m)/hour
x(1000meters)/hour = (60) x meters/hour
x(1000)/1hour = y(60) / 1 hour
x(1000) = y(60)
x = 0.06y
Answer: D. 6y/100
Question: A string of 15 light bulbs is wired in such a way that if any individual light bulb fails, the entire string fails. If for each individual light bulb the probability of failing during time period T is 0.06, what is the probability that the string of light bulbs will fail during the time period T?
A.1 - (0.94)^15
B.(0.06)^15
C.1 - (0.06)^15
D.(0.94)^15
Answer: A.1 - (0.94)^15
Explanation: The string of light bulbs will fail if at least one light bulb fails. So, let's find the probability of the opposite event and subtract that value from 1.
The opposite event is when none of the 15 light bulbs fails, since the probability of each light bulb not to fail is 1-0.06=0.94 the probability that none of the 15 light bulbs fails is 0.94^15.
Hence, the probability that at least one light bulb fails is 1-0.94^15.
Answer: A.
Now, you should have spotted that your reasoning was not right because of one simple thing, consider the case when we have 100 light bulbs instead of 15, then according to your logic the probability that the string of light bulbs will fail would be 100*0.06=6, which is not possible since the probability of an event cannot be more than 1 (100%).
Question: A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 20 sec respectively. What is the speed of the train?
A.28.9 km/hr
B.89.9 km/hr
C.28.9 km/hr
D.79.2 km/hr
Answer: D.79.2 km/hr
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/20 = y
y = 22
Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.
Answer:D
Question: Andrew purchased 7kg of grapes at the rate of 68 per kg and 9 kg of mangoes at the rate of 48 per kg. How much amount did he pay to the shopkeeper?
A.1000
B.908
C.930
D.1075
Answer: B.908
Explanation: Cost of 7 kg grapes = 68 × 7 = 476.
Cost of 9 kg of mangoes = 48 × 9 = 432.
Total cost he has to pay = 476 + 432 = 908
B
Question: If f(x) = -*5 (x^4 - 1)/(x^2), what is f(1/x) in terms of f(x)?
A.f(x)
B.-f(x)
C.1/f(x)
D.5f(x)
Answer: D.5f(x)
Explanation: -5*f(1/x) =-5* ((1/x)^4 - 1) / ((1/x)^2)
= -5*((1/x^4) - 1) / (1/x^2)
= -5*((1-x^4)/(x^4)) / (1/x^2)
= -5* (1-x^4)/(x^2)
= -5* ( (x^4) -1) / (x^2)
= 5f(x)
Answer is D.
Question: The cost of fencing a square field @ Rs. 20 per metre is Rs.10.080.How much will it cost to lay a three meter wide pavement along the fencing inside the field @ Rs. 50 per sq m
A.73828
B.73829
C.73811
D.73800
Answer: D.73800
Explanation: perimeter = total cost / cost per m = 10080 /20 = 504m
side of the square = 504/4 = 126m
breadth of the pavement = 3m
side of inner square = 126 - 6 = 120m
area of the pavement = (126 x126) - (120 x 120) = 246 x 6 sq m
cost of pavement = 246*6*50 = Rs. 73800
Answer: D
Question: In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 50 questions and secures 130 marks, the no of questions he attempts correctly is :
A.A)36
B.B)38
C.C)90
D.D)88
Answer: A.A)36
Explanation: Let the number of correct answers be X.
Number of incorrect answers = (60 – X).
4x – (50 – x) = 130
=> 5x = 180
=> x = 36
Answer:A
Question: How many cones of radius 4 m, height 2 m can be formed from a cylinder of 12 m radius, 10 m height:
A.135
B.125
C.145
D.115
Answer: A.135
Explanation: (Cylinder volume)/(Cone volume)
(πr(power2)h)/(1/3 πr(power2)h)
= (π × 12 × 12 × 10)/(1/3 π × 4 × 4 × 2) = 135
Answer is A.
Question: A sum at simple interests at 13 ½ % per annum amounts to Rs.2502.50 after 4 years find the sum.
A.Rs.1645.
B.Rs.1675.
C.Rs.1625.
D.Rs.1635.
Answer: C.Rs.1625.
Explanation: Let sum be Rs. x then , S.I.=Rs.(x*(27/2) *4*(1/100) ) = Rs.27x/50
amount = (Rs. x+(27x/50)) = Rs.77x/50
77x/50 = 2502.50  x = (2502.50 * 50)/77 = 1625
Hence , sum = Rs.1625.
Answer is C.
Question: Frank is 14 years younger then John. In 5 years John will be twice as old as Frank. How old will Frank be in four years?
A.8
B.10
C.13
D.14
Answer: C.13
Explanation: Frank is 15 years younger then John --> F+14=J;
In 5 years John will be twice as old as Frank (in 5 year John will be J+5 years old and Frank will be F+5 years old) --> J+5=2*(F+5) --> (F+14)+5=2*(F+5) --> F=9;
In 4 years Frank will be 9+4=13 years old.
Answer: C.
Question: A 250 m long train is running at a speed of 55 Km/hr. It crossed a platform of length 520 m in ?
A.41.1 sec
B.20.2 sec
C.31.8 sec
D.50.4 sec
Answer: D.50.4 sec
Explanation: Speed = 55 Km/hr
(to convert km/hr in to M/s)
= 55 x 5/18 M/s
Distance = 250 m + 520 m ( If questions is about train crossing a post you need to consider only the length of Train, )
= 770 m
Time = Distance / Speed
= 770 x 18 / (5 x 55)
= 50.4 sec
Ans is :D
Question: The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
A.5:2
B.7:3
C.9:2
D.10:4
Answer: B.7:3
Explanation: Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10):(x + 10) = 70:30 = 7:3.
Answer: Option B
Question: In Arun’s opinion, his weight is greater than 65 kg but less than 72 kg. His brother doest not agree with Arun and he thinks that Arun’s weight is greater than 60 kg but less than 70 kg. His mother’s view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?
A.67 kg.
B.68 kg.
C.69 kg.
D.Data inadequate
Answer: A.67 kg.
Explanation: EXPLANATION
Let Arun’s weight by X kg.
According to Arun, 65 < X < 72
According to Arun’s brother, 60 < X < 70.
According to Arun’s mother, X <= 68
The values satisfying all the above conditions are 66, 67 and 68.
Required Average =( 66 + 67 + 68 /3 )= (201/3) = 67 kg
Answer A
Question: A crate of apples contains 1 bruised apple for every 30 apples in the crate. Two out of every 4 bruised apples are considered not fit to sell, and every apple that is not fit to sell is bruised. If there are 12 apples not fit to sell in the crate, how many apples are there in the crate?
A.720
B.360
C.480
D.600
Answer: A.720
Explanation: as given 2 out of every 4 bruised apple is not fit to sell
or, 50% of the bruised apples are not fit to sell.
as per the question 12 are not fit to sell
or,
0.0.5x=12
x=1200/50=24
thus total number of bruised apples =24
total number of apples =30*24=720
Answer:A
Question: A library has an average of 510 visitors on Sundays and 240 on other day. The average number of visitors in a month of 5 days starting with sunday is
A.1215
B.1314
C.2900
D.1710
Answer: D.1710
Explanation: Explanation:
As the month begin with sunday, so there will be five sundays in the month. So result will be:
=(510×5+240×25/30)=(8550/5)=1710
Answer: Option D