RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Ram borrowed some money at the rate of 6% p.a. for the first three years, 8% p.a.for the next six years and 10% p.a.for the period beyond nine years If the total interest paid by him at the end of 12 years is 19200, how much money did he borrow?
A.18,000
B.10,000
C.25,000
D.20,000
Answer: D.20,000
Explanation: Let the sum be x. Then,
(x×3×6/100)+(x×6×8/100)+(x×3×10/100)=19200
⇒ 18x + 48x + 30x = (19200 × 100)
⇒ 96x = 1920000
⇒ x = 20000.
Answer D
Question: The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
A.200 m
B.225 m
C.245 m
D.250 m
Answer: C.245 m
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.
ANSWER:C
Question: A box contains 4 black, 3 red and 6 green marbles. 3 marbles are drawn from the box at random. What is the probability that both the marbles are of the same color?
A.24/286
B.25/709
C.25/286
D.24/268
Answer: C.25/286
Explanation: Explanation:
Total marbles in a box = 4 black + 3 red + 6 green marbles = 13 marbles
3 marbles are drawn from 13 marbles at random. Therefore,
n(S) = 13C3= 286 ways
Let A be the event that 2 marbles drawn at random are of the same color. Number of cases favorable to the event A is
n(A) = 4C3 + 3C3+ 6C3 = 4 +1 + 20 = 25
Therefore, by definition of probability of event A,
P(A) = n(A)/n(S) = 25/286
ANSWER:C
Question: The average score of a cricketer for five matches is 45 runs. If the average for first three matches is 30, then average for last two matches is
A.33.25
B.32.25
C.67.5
D.60.5
Answer: C.67.5
Explanation: Explanation:
=(45×5)−(30×3)/2
=(225 −90)4=67.5
Answer: Option C
Question: By selling 16 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
A.28
B.25
C.24
D.23
Answer: C.24
Explanation: 80% --- 16
120% --- ?
80/120 * 16 = 24
Answer:C
Question: A man performs 1/2 of the total journey by rail, 1/3 by bus and the remaining 5km on foot. His total journey is
A.16km
B.10km
C.12km
D.30km
Answer: D.30km
Explanation: Explanation:
Let the journey be x km
Then, 1x/2 + 1x/3 +5 =x
5x +30 =6x
X = 30km
Answer: Option D
Question: In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 17 to the thrice of the remainder. The dividend is
A.74
B.146
C.86
D.92
Answer: B.146
Explanation: Divisor = (6 * 3) + 17 = 35
5 * Quotient = 35
Quotient = 7.
Dividend = (Divisor * Quotient) + Remainder
Dividend = (20 * 7) + 6 = 146.
B)
Question: Calculate how many ways a woman who has 5 bags and 4 books can put the books in her bag?
A.625
B.635
C.615
D.325
Answer: A.625
Explanation: First paper can be put in 5 ways, similarly second, third, and forth books also can be put in 5 ways.
So total number of ways = 5 x 5 x 5 x 5 = 625
A
Question: Solve below question 2x + 1 = -17
A.-8
B.-9
C.9
D.8
Answer: B.-9
Explanation: 1. Subtract 1 from both sides:
2x + 1 - 1 = -17 - 1
2. Simplify both sides:
2x = -18
3. Divide both sides by 2:
4. Simplify both sides:
x = -9
B
Question: The area of an isosceles trapezoid with sides of length 5 and bases of length 8 and 14 is?
A.22
B.32
C.44
D.55
Answer: C.44
Explanation: we can divide the trapezoid into two triangles and a rectangle
sides of triangle , t1 --> h1 =5 , b1 =3 , s1= root(25-9) = 4 = s2 of triangle t2
area of triangle = (1/2)*4*3=6
side of the rectangle = 8*4=32
total area of the trapezoid= 32+6+6=44
ANSWER:C
Question: A man can row with a speed of 15 kmph in still water. If the stream flows at 1 kmph, then the speed in downstream is?
A.10 kmph
B.5 kmph
C.20 kmph
D.16 kmph
Answer: D.16 kmph
Explanation: M = 15
S = 1
DS = 15 + 1 = 16
ANSWER:D
Question: Given two fair dice, what is the probability E that the sum of their numbers is 4 if exactly one die shows a 3?
A.a) 2/11
B.b) 1/18
C.c) 3/11
D.d) 2/39
Answer: A.a) 2/11
Explanation: If exactly one die shows 3, there are 10 such combinations (given that we have 2 fair dice).
1:3, 2:3, 4:3, 5:3, 6:3,
3:1, 3:2, 3:4, 3:5, 3:6
The sum of numbers would be 4 for two events: 1:3, 3:1.
E=2/11 would be the answer if 'at least one of the die shows a 3'.A
Question: If a and b are odd integers which of the following must be an even integer?
A.a/b
B.ab
C.(ab)^2
D.ab + b
Answer: D.ab + b
Explanation: Certainly (D)
ab+b=b(a+1)
Sine both a & b are ODD , we can say ( a + 1 ) is EVEN as ODD + 1 = EVEN
Hence there is no doubt that the OA must be (D)
ANSWER:D
Question: if the price of a book is first decreased by 20% and then increased by 20%, then the net change in the price will be :
A.10
B.388
C.4
D.29
Answer: C.4
Explanation: Explanation:
Let the original price be Rs. 100.
Decreased by 20% = 80
Then increased 20% on Rs 80 = 80 + 16 = 96
Net change in price = 100 - 96 = 4
Answer : C
Question: The ratio of three numbers is 6:7:5 and their sum is 108. The second number of the three numbers is?
A.12
B.42
C.30
D.36
Answer: B.42
Explanation: Explanation:
6:7:5
Total parts = 18
18 parts --> 108
1 part ---->6
The second number of the three numbers is = 7
7 parts ----> 42
Answer: Option B
Question: If x and y are both odd prime numbers and x < y, how many distinct positive R integer factors does 2xy have?
A.3
B.4
C.6
D.8
Answer: D.8
Explanation: Since 2xy prime R factors are x^1*y^1*2^1, its total number or factors must be (1+1)(1+1)(1+1)=2^3=8. Thus, I think D would be the correct answer.
Question: Three students appear at an examination of Mathematics. The probability of their success are 1/3, 1/4, 2/5 respectively. Find the probability of success of at least two.
A.1/4
B.2/5
C.3/4
D.3/5
Answer: A.1/4
Explanation: The probability of success of at least two students will involve the following possibilities.
The first two students are successful, the last two students are successful, the first and third students are successful and all the three students are successful.
Therefore, the required probability = 1/3 x 1/4 x 3/5 + 1/4 x 2/5 x 2/3 + 1/3 x 2/5 x 3/4 + 1/3 x 1/4 x 2/5 = 1/4
ANSWER:A
Question: Which of the following is closer to (24!+23!)/(24!-23!)?
A.49
B.36
C.25
D.1
Answer: D.1
Explanation: Notice that 24! = (24)(23!), so we can factor out 23! from top and bottom.
(24!+23!)/(24!-23!)=[23!(24+1)]/[23!(24-1)]
= (24+1)/(23-1)
= 25/23
≈ 1
Answer: D
Question: Molly can do a task in 15 days while Sandy can do the task in 30 days. How many days will it take to complete the task if both work together?
A.8
B.10
C.11
D.12
Answer: B.10
Explanation: Each day, Molly can do 1/15 of the task.
Each day, Sandy can do 1/30 of the task.
Each day, they can do 1/15 + 1/30 = 1/10 of the task.
The task will be completed in 10 days.
The answer is B.
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.288
B.668
C.240
D.299
Answer: C.240
Explanation: Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m.
Answer:C
Question: A store reduced the price of all items in the store by 15% on the first day and by another 10% on the second day. The price of items on the second day was what percent of the price before the first reduction took place?
A.76.5
B.80.9
C.81.0
D.81.1
Answer: A.76.5
Explanation: consider price of the all items as $100
after a initial reduction of 15% price becomes = 0.85 *100 = $ 85
after the final reduction of 10% price becomes = 0.9* 85 = $ 76.5
price of all items on second day is 76.5% of price on first day
correct answer option A
Question: What is his percentage profit made by Osborn if he purchased 30 dozen watches at Rs. 50 per dozen. He sold 12 dozens at 12% profit and the remaining 18 dozens with 17% profit?
A.12.6%
B.13.6%
C.16.6%
D.15.6%
Answer: D.15.6%
Explanation: Explanation :
C.P of 30 dozen = Rs.(50 x 30) = Rs.1500
C.P of 12 dozen = Rs. (50 x12) = Rs. 600.
C.P of 18 dozen =Rs. (50 x18) = Rs. 900
profit on 12 dozen at 12% = 12/100*600 = 72
profit on 18 remaining dozen at 18% = 18/100*900 = 162
total profit = 72 + 162 = 234
% profit = ?/100*1500 = 234
= 15.6%
Answer : D
Question: A box contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the box, if at least one black ball is to be included in the draw?
A.54
B.58
C.62
D.64
Answer: D.64
Explanation: We may have(1 black and 2 non-black) or (2 black and 1 non-black) or (3 black).
Required number of ways	= (3C1 x 6C2) + (3C2 x 6C1) + (3C3)
= 3 x	6 x 5 + 3 x 2	x 6 + 1
2 x 1	2 x 1
= (45 + 18 + 1)
= 64
Answer: D.
Question: A sock drawer contains five socks, each one a different solid color. The colors of the socks are red, orange, yellow, indigo, and violet. If a person reaches into the drawer and pulls out two socks, how many different color combinations are possible in the selected pair of socks?
A.10
B.15
C.21
D.36
Answer: A.10
Explanation: Since here order of socks is not important then we'll have 5C2 i.e. 10 combinations.
Answer : A
Question: A number consists of two digits whose sum is 11. If 27 is added to the number, then the digits change their places. What is the number ?
A.47
B.65
C.83
D.92
Answer: A.47
Explanation: If number is xy , then x +y =11
and
10x+y +27 = 10y+x
solving these eqns, we get
x=4 and y =7
so number is 47.
ANSWER:A
Question: 8 x 5.4 - 0.6 x 10/1.2 = ?
A.30
B.45
C.50
D.31
Answer: D.31
Explanation: Given Expression
= (43.2 - 6)/1.2
= 37.2/1.2
= 31
Answer is D.
Question: A circular well with a diameter of 2 meters, is dug to a depth of 14 meters. What is the volume of the earth dug out.
A.40m3
B.42m3
C.44m3
D.46m3
Answer: C.44m3
Explanation: Explanation:
Volume=πr2h
Volume=((22/7)∗1∗1∗14)m3
=44m3
ANSWER IS C
Question: A walks at 10 kmph and 6 hours after his start, B cycles after him at 20 kmph. How far from the start does B catch up with A?
A.100km
B.150km
C.50km
D.120km
Answer: D.120km
Explanation: Suppose after x km from the start B catches up with A. Then, the difference in the time taken by A to cover x km and that taken by B to cover x km is 6 hours.
x/10 - x/20 = 6
x = 120 km
Answer is D
Question: The radius of a semi circle is 6.3 cm then its perimeter is?
A.35.4 cm
B.32.4 cm
C.32 cm
D.30 cm
Answer: B.32.4 cm
Explanation: Explanation:
36/7 r = 6.3 = 32.4
ANSWER IS B
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres?
A.16 seconds
B.76 seconds
C.26 seconds
D.12 seconds
Answer: D.12 seconds
Explanation: Speed of the boat downstream = 15 + 3
= 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m
= 60/5
= 12 seconds.
Answer: D
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 8 sec. What is the length of the fast train?
A.44 7/6 m
B.44 4/9 m
C.44 7/2 m
D.44 7/9 m
Answer: B.44 4/9 m
Explanation: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 8 = 400/9 = 44 4/9 m.Answer:B
Question: (4.5 x 3.7 + 4.5 x 6.3)/(1.5 x 8.4 - 1.5 x 7.4) = ?
A.30
B.30.05
C.32
D.34
Answer: A.30
Explanation: Explanation:
(4.5 x 3.7 + 4.5 x 6.3)/(1.5 x 8.4 - 1.5 x 7.4)
= 4.5 x (3.7 + 6.3)/1.5 x (8.4 - 7.4)
= 4.5 x 10/1.5 x 1 = 30
Answer: Option A
Question: In a 4 person race, medals are awarded to the fastest 3 runners. The first-place runner receives a gold medal, the second-place runner receives a silver medal, and the third-place runner receives a bronze medal. In the event of a tie, the tied runners receive the same color medal. (For example, if there is a two-way tie for first-place, the top two runners receive gold medals, the next-fastest runner receives a silver medal, and no bronze medal is awarded). Assuming that exactly three medals are awarded, and that the three medal winners stand together with their medals to form a victory circle, how many C different victory circles are possible?
A.24
B.52
C.96
D.144
Answer: B.52
Explanation: Possible scenarios are:
1. Gold/Silver/Bronze/No medal (no ties) - 4!=24;
2. Gold/Gold/Silver/No medal - 4!/2!=12;
3. Gold/Silver/Silver/No medal - 4!/2!=12;
4. Gold/Gold/Gold/No medal - 4!/3!=4.
Total: 24+12+12+4=52
Answer: B.
Question: A train crosses a platform of 130 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
A.A)150m
B.B)170m
C.C)230m
D.D)158m
Answer: C.C)230m
Explanation: Length of the train be ‘X’
X + 130/15 = X + 250/20
4X + 520 = 3X + 750
X = 230m
Answer: C
Question: Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Tharak's age. After further 6 years, how many times would he be of Tharak's age?
A.1.52 times
B.1.83 times
C.2.83 times
D.0.83 times
Answer: B.1.83 times
Explanation: Assume that Tharak's present age =x.
Then, father's present age =3x+x=4x
After 8 years, father's age=2 1/2 times of Tharak' age
⇒(4x+8)=2 1/2(x+8)
⇒4x+8=5/2(x+8)
⇒8x+16=5x+40
⇒3x=40−16=24
⇒x=24/3=8
After further 6 years,
Sunil's age =x+6+6=8+6+6=20
Father's age =4x+6+6=4×8+6+6=44
Father's age/Sunil's age
=44/24
=1.83
ANSWER:B
Question: If a * b * c =(√(a + 2)(b + 3)) / (c + 1), find the value of 6 * 15 * 11.
A.8
B.5
C.1
D.3
Answer: C.1
Explanation: 6 * 15 * 11 = (√(6 + 2)(15 + 3) )/ (11 + 1)
= (√8 * 18) / 12
= (√144) / 12
= 12 / 124 = 1.
Answer is C
Question: A number when divided by a certain divisor left remainder 255, when twice the number was divided by the same divisor, the remainder was 112. Find the divisor?
A.370
B.365
C.398
D.456
Answer: C.398
Explanation: Easy solution:
N= Dq1+255
2N = 2Dq1 + 51 0- (1)
2N = Dq2 + 112 - (2)
As (1) = (2) = 2N
D*(q2-2q1) = 398
D * Some integer = 398
Checking all options only (C) syncs with it.
Answer C
Question: In covering a distance of 24 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:
A.4 kmph
B.6 kmph
C.6.25 kmph
D.7.5 kmph
Answer: A.4 kmph
Explanation: Let Abhay's speed be x km/hr.
Then,	24/X	-	24/2X	= 3
6x = 24
x = 4 km/hr. Answer: Option A
Question: A batsman in his 17th innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17thinnings?
A.39
B.12
C.11
D.37
Answer: D.37
Explanation: Explanation:
16x + 85 = 17(x + 3)
x = 34 + 3 = 37
Answer: Option D
Question: What is the unit’s digit of 7^5
A.1
B.3
C.5
D.7
Answer: D.7
Explanation: 7^1=7
7^2=49
7^3=343
7^4=1(last digit)
7^5=7(last digit) and the cycle repeats after every 4 powers
Therefore, last digit of 7^5=7
Answer D
Question: 20 people attend a party. 7 men are single and the rest are there with their wives. There are no children in the party. In all 10 women are present. Then the number of married men at the party is ?
A.5
B.3
C.7
D.8
Answer: B.3
Explanation: Total people = number of men + number of women
20 = 7 + number of married men + 10
number of married men = 20-10-7 = 3 men
ANSWER:B
Question: By weight, liquid X makes up 0.8 percent of solution A and 1.8 percent of solution B. If 300 grams of solution A are mixed with 700 grams of solution B, then liquid X accounts for what percent of the weight of the resulting solution?
A.1.5%
B.1.9%
C.10%
D.15%
Answer: A.1.5%
Explanation: I think there is a typo in question.
It should have been "By weight Liquid 'X ' makes up..... "
Weight of Liquid X = 0.8 % of Weight of A + 1.8% of Weight of B
When 300gms of A and 700gms of B is mixed :
Weight of Liquid X = (0.8 * 300)/100 + (1.8* 700)/100 = 15gms
% of Liquid X in resultant mixture = (15/1000) *100 = 1.5%
Answer : 1.5% ANSWER:A
Question: Simplify: (10-5)-(-3+14-2)+(7-5)
A.-1
B.–2
C.1
D.2
Answer: B.–2
Explanation: Solution:
(10-5)-(-3+14-2)+(7-5)
=5-(9)+2
=5-9+2
=-4+2
-2
Answer: (B)
Question: Tom is chasing Jerry. In the same interval of time Tom jumps 8 times while Jerry jumps 6 times. But the distance covered by Tom in 7 Jumps is equal to the distance covered by Jerry in 5 Jumps. The ratio of speed of Tom and Jerry is:
A.48 :35
B.28 :15
C.24 :20
D.20 :21
Answer: D.20 :21
Explanation: Solution:
Given;
7 jumps of Tom = 5 jumps of Jerry.
Or, Tom / Jerry = 5/7;
Let Jerry's 1 leap = 7 meter and Tom's 1 leap = 5 meter.
Then, ratio of speed of Tom and Jerry = 8*5/6*7 = 40/42 = 20 :21.
Answer: Option D
Question: A man saves Rs. 200 at the end of each year and lends the money at 5% compound interest. How much will it become at the end of 3 years?
A.662.07
B.662.0
C.662.02
D.362.02
Answer: C.662.02
Explanation: Amount = [200(1 + 5/100)3 + 200(1 + 5/100)2 + 200(1 + 5/100)]
= [200 * 21/20(21/20 * 21/20 + 21/20 + 1)] = Rs. 662.02
Answer:C
Question: A large box contains 19 small boxes and each small box contains 25 chocolate bars. How many chocolate bars are in the large box?
A.475
B.350
C.450
D.550
Answer: A.475
Explanation: The number of chocolate bars is equal to
19 * 25 = 475
correct answer A
Question: Out of 10 persons working on a project, 4 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?
A.5/9
B.5/4
C.5/1
D.5/6
Answer: D.5/6
Explanation: P(at least one graduate) = 1 - P(no graduates)
(6 * 5 * 4)/(10 * 9 * 8) = 5/6
Answer: D
Question: A, B, K start from the same place and travel in the same direction at speeds of 30 km/hr, 40 km/hr, 50 km/hr respectively. B starts two hours after A. If B and K overtake A at the same instant, how many hours after A did K start?
A.2.4
B.3.2
C.4.0
D.4.8
Answer: B.3.2
Explanation: In 2 hours, A travels 60 km.
B can catch A at a rate of 10 km/hr, so B catches A 6 hours after B starts.
So A and B both travel a distance of 240 km.
C needs 4.8 hours to travel 240 km, so C leaves 3.2 hours after A.
The answer is B.
Question: Mr.Govind invested an amount of Rs.13900 divided in two different schemes S1 and S2 at the simple interst rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in two years was Rs.3508, what was the amount invested in Scheme S2?
A.Rs.6400
B.Rs.6500
C.Rs.7200
D.Rs.7500
Answer: A.Rs.6400
Explanation: Let the sum invested in Scheme S1 be Rs.x and that in Scheme S2 be Rs.(13900-x).
Then, (x*14*2)/100 + ((13900-x)*11*2)/100 = 3508;
28x-22x= 3350800-(13900*22);
6x = 45000; x= 7500
So sum invested in Scheme S2 = Rs. (13900-7500) = Rs.6400
ANSWER:A
Question: If x + (1/x) = 5, what is the value of E=x^2 + (1/x)^2?
A.E=21
B.E=22
C.E=23
D.24
Answer: C.E=23
Explanation: Squaring on both sides,
x^2 + (1/x)^2 + 2(x)(1/x) = 5^2
x^2 + (1/x)^2 = 23
Answer: C
Question: The sum of three from the four numbers A, B , C , D are 3957 , 4012 , 4370 and 4374 What is the largest of the numbers A , B , C and D?
A.1614
B.1200
C.1560
D.1198
Answer: A.1614
Explanation: 3*(A+B+C+D)=3957+4012+4370+4374
A+B+C+D=5571
5571-(Least sum of 3 numbers)=Largest number
5571-3957=1614
so Largest number is 1614
ANSWER:A
Question: John has to secure 60% marks to clear his exam of class 5th.
He got 10 marks and failed by 50 marks.
What is the maximum marks ?
A.110
B.105
C.100
D.95
Answer: C.100
Explanation: C
100
To pass the exam ravish needs 10 + 50 = 60 marks.
=> (60/60) *100 = 100
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 48 kmph, find the speed of the stream?
A.77
B.88
C.14
D.16
Answer: D.16
Explanation: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 48/3 = 16 kmph.
Answer:D
Question: There are seven thieves. They stole diamonds from a diamond merchant and ran away. While running, night sets in and they decide to rest in the jungle.
When everybody was sleeping, two of them woke up and decided to divide the diamonds equally among themselves. But when they divided the diamonds equally, one diamond is left.
So they woke up the 3rd thief and tried to divide the diamonds equally again but still one diamond was left. Then they woke up the 4th thief to divide the diamonds equally again, and again one diamond was left. This happened with the 5th and 6th thief – one diamond was still left.
Finally, they woke up the 7th thief and this time the diamonds were divided equally.
How many diamonds did they steal in total?
A.1101
B.1141
C.1120
D.1130
Answer: B.1141
Explanation: We need a number that is a multiple of 7 that will give a remainder of 1 when divided by 2, 3, 4, 5, and 6. The least common multiple of these numbers is 60. So, we need a multiple of 7 that is 1 greater than a multiple of 60.
Answer B
Question: Find the odd man out
36, 315, 612, 810, 966, 1362
A.966
B.612
C.315
D.36
Answer: C.315
Explanation: 315is divisible by 3 which is odd number where as all others are even numbers divisible by 3.
ANSWER:C
Question: The price of raw materials has gone up by 15%, labour cost has also increased from 25% of the cost of raw material to 30% of the cost of raw material. By how much percentage should there be reduction in the usage of raw materials so as to keep the cost same?
A.28%
B.17%
C.27%
D.24%
Answer: B.17%
Explanation: Solution: Let the initial cost of raw material be 100. So, initial labour cost was 25 and net cost was 125.
Now,
15% increment in raw materials cost and labour cost has gone up to 30% from 25 %.
Raw material cost = 115. And
Labour cost = (115 *30) = 34.5
So, New net cost,
= 115 + 34.5 = 149.5
%reduction = 24.5/149.5 = 17%(approx.)
Answer: Option B
Question: If 40% of 3/5 of a number is 36, then the number is?
A.80
B.150
C.75
D.90
Answer: B.150
Explanation: Let the number be x. Then 40% of 3/5 of x=36
40/100*3/5*x=36
x=(36*50/12)=150
Required number=150.
Correct Option: B
Question: A train 90 m long running at 56 kmph crosses a platform in 18 sec. What is the length of the platform?
A.190
B.200
C.180
D.881
Answer: A.190
Explanation: D = 56 * 5/18 = 25 = 280 – 90 = 190
Answer: A
Question: In a factory, there are 40% technicians and 60% non-technicians. If the 60% of the technicians and 40% of non-technicians are permanent employees, then the percentage of workers who are temporary is?
A.52%
B.58%
C.82%
D.32%
Answer: A.52%
Explanation: Total = 100
T= 40 NT= 60
40*(60/100)=24 60*(40/100)=24
24 + 24 = 48 => 100 - 48 = 52%
Answer: A
Question: The ratio of the amount of the oil bill for the month of February to the amount of the oil bill for the month of January was 5:4. If the oil bill for February had been $30 more, the corresponding ratio would have been 3:2. How much was the oil bill for January?
A.$60
B.$80
C.$100
D.$120
Answer: D.$120
Explanation: 5:4 = 15:12 and 3:2 = 18:12.
An increase in $30 increases the ratio by 3:12.
Therefore an increase in $10 increases the ratio by 1:12.
Therefore, January's bill was 12($10) = $120.
The answer is D.
Question: An amount of money is to be divided between P, Q and R in the ratio of 3:7:12. If the difference between the shares of P and Q is Rs.3200, what will be the difference between Q and R's share?
A.2788
B.4000
C.7282
D.2782
Answer: B.4000
Explanation: 4 --- 3200
5 --- ? => 4000
Answer:B
Question: Data sufficiency question.
A.37
B.277
C.299
D.26
Answer: B.277
Explanation: Statement 1 has three solutions,(8, 0), (5, 1), (2, 2) but we cannot say precisely about the relationship
Statement 2 has three solutions, (8, 0), (5, 1), (2, 2) but we cannot say about the relationship.
So data insufficient.
Answer:B
Question: Today Joelle opened an interest-bearing savings account and deposited $5,000. If the annual interest rate is 4 percent compounded interest, and she neither deposits nor withdraws money for exactly 2 years, how much money will she have in the account?
A.$5200
B.$5408
C.$5208
D.$5608
Answer: B.$5408
Explanation: Interest for 1st year = 5000*4/100 = 200
Interest for 2nd year = 5200 *4/100 = 208
Total =5000+200+208 = 5408
Answer : B
Question: A boat can row 18 kmph in still water.It takes twice as long to row up as to row down the river.Find the rate of stream.
A.6 km/hr
B.7 km/hr
C.8km/hr
D.5 km/hr
Answer: A.6 km/hr
Explanation: still water-18kmph
It takes twice as long to row up as to row down the river.
then let upstream=2x and downstream=x
now buy the formulae
18=0.5(x+2X)----->x=12
so stream=0.5*(24-12)=6kmph
ANSWER:A