RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Solve x2 – 7x = 0
A.0,7
B.1,7
C.2,7
D.3,7
Answer: A.0,7
Explanation: This quadratic factors easily: Copyright © Elizabeth Stapel 2002-2011 All Rights Reserved
x2 – 7x = 0
x(x – 7) = 0
x = 0 or x – 7 = 0
x = 0 or x = 7
The solution is x = 0, 7
ANSWER A 0,7
Question: How many 3-letter words with or without meaning, can be formed out of the letters of the word, 'LOGAR', if repetition of letters is not allowed?
A.690
B.60
C.740
D.760
Answer: B.60
Explanation: The word 'LOGAR' has 5 different letters.
Hence, the number of 3-letter words(with or without meaning) formed by using these letters
= 5P3
=
5
×
4
×
3
=
60
Option B
Question: A train running at the speed of 56 km/hr crosses a pole in 9 sec. What is the length of the train?
A.140 m
B.786 m
C.566 m
D.546 m
Answer: A.140 m
Explanation: Speed = 56 * 5/18 = 140/9 m/sec
Length of the train = speed * time = 140/9 * 9
= 140 m
Answer: A
Question: If w and t are positive integers, wt + w + t cannot be
A.5
B.6
C.7
D.8
Answer: B.6
Explanation: Let wt + t + w = x
Add 1 on both sides:
wt + t + w + 1 = x + 1
t(w + 1) + w + 1 = x + 1
(w + 1)(t + 1) = x + 1
Minimum value of (w + 1) = 2
Minimum value of (t + 1) = 2
Hence x + 1 cannot be prime
Substitute x from the given options: 6 + 1 = 7 --> prime --> wt + t + s cannot be 6
Answer: B
Question: A mobile battery in 1 hour charges to 20 percent.How much time (in minute) will it require more to charge to 30 percent.
A.145
B.90
C.175
D.160
Answer: B.90
Explanation: 1 hr =20 percent.Thus 15 min=5 percent .Now to charge 30 percent 90 min.Answer:B
Question: If the average (arithmetic mean) of 18 consecutive odd integers is 414, then the least of these integers is
A.a) 497
B.b) 518
C.c) 519
D.d) 521
Answer: A.a) 497
Explanation: A very helpful rule to know in arithmetic is the rule that in evenly spaced sets, average = median. Because the average will equal the median in these sets, then we quickly know that the median of this set of consecutive odd integer numbers is 414.
There are 18 numbers in the set, and in a set with an even number of terms the median is just the average of the two most median terms (here the 9th and 10th numbers in the set). This means that numbers 9 and 10 in this set are 413 and 415. Because we know that number 9 is 413, we know that the smallest number is 8 odd numbers below this, which means that it is 8*2 = 16 below this (every odd number is every other number). Therefore 413-16 = 397, answer choice A
Question: A car started running at a speed of 38 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey.
A.47 km
B.76 km
C.25 km
D.15 km
Answer: A.47 km
Explanation: A
47 km
The total distance covered by the car in the first 10 hours = 38 + 40 + 42 + 44 + 46 + 48 + 50 + 52 + 54 + 56= sum of 10 terms in AP whose first term is 30 and last term is 56 = 10/2 [38 + 56] = 470 km.
Question: H.C.F. of 513, 1134 and 1215 is
A.27
B.21
C.76
D.42
Answer: A.27
Explanation: H.C.F. of 513, 1134 and 1215 = 3 × 3 × 3 = 27
Answer: Option A
Question: On Saturday morning, Malachi will begin a camping vacation and he will return home at the end of the first day on which it rains. If on the first three days of the vacation the probability of rain on each day is 0.3, what is the probability that Malachi will return home at the end of the day on the following Monday?
A.0.008
B.0.147
C.0.488
D.0.512
Answer: B.0.147
Explanation: Re-phrasing the question:
What is the probability of: Saturday: No rain, Sunday: No rain, Monday: Rain
Probablity of rain = 0.3
Therefore, probability of no rain = 0.7
0.7*0.7*0.3 = 0.147
Hence B
Question: If 10 men can make 200 tables working for 15 days at the rate of 8 hr per day, how many tables can 5 men make working for 10 days at the rate of 6 hr a day?A
A.150
B.50
C.250
D.100
Answer: B.50
Explanation: formula
men* days * workinghour / work
so m1*d1*t1/ w1 = m2*d2*t2 / w2
= 50
ANSWER:B
Question: A and B together can do a work in6 days. If A alone can do it in 42 days. In how many days can B alone do it?
A.11
B.7
C.8
D.20
Answer: B.7
Explanation: B
7
1/6 â€“ 1/42 = 1/7 => 7
Question: A technician makes a round-trip to and from a certain service center by the same route. If the technician completes the drive to the center and then completes 80 percent of the drive from the center, what percent of the round-trip has the technician completed?
A.5%
B.75%
C.25%
D.40%
Answer: B.75%
Explanation: The complete round trip consists of driving to the service center and then back home again.
So, once the technician drives to the service center he/she has already competed 50% of the entire trip.
Since the technician completes a portion of the trip back home,the correct answer must be greater than 50%
Only one answer choice works.
Answer:
B
Question: A shop sells chocolates at re.1 each. U can exchange 3 wrappers for 1 chocolate. If u have Rs.100, how many chocolates can you totally get?
A.147
B.148
C.149
D.145
Answer: C.149
Explanation: for 100 rupees we will get 100 chocolates
then for 3 wrappers we will get 1 chocolate so 100/3==33 chocolates and we left with one more wraper the 33+1=34 ...34/3=11...one more wrapper so 12/3=4 ..4/3=1 and one more wrapper so finally...100+33+11+4+1=149
ANSWER:C
Question: A trader bought a car at 20% discount on its original price. He sold it at a 50% increase on the price he bought it. What percent of profit did he make on the original price?
A.A)10%
B.B)12%
C.C)14%
D.D)20%
Answer: D.D)20%
Explanation: Original price = 100
CP = 80
S = 80*(150/100) = 120
100 - 120 = 20%
D)
Question: If rupee one produces rupees nine over a period of 25 years, find the rate of simple interest?
A.22 1/7 %
B.36 %
C.22 1/8 %
D.22 1/2 %
Answer: B.36 %
Explanation: 9 = (1*25*R)/100
R = 36 %
Answer:B
Question: Sripad has scored average of 64 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ?
A.79
B.28
C.76
D.27
Answer: C.76
Explanation: Assuming Sripad has scored the least marks in subject other than science,
Then the marks he could secure in other two are 58 each.
Since the average mark of all the 3 subject is 64.
i.e (58+58+x)/3 = 64
116 + x = 192
x = 76 marks.
Therefore, the maximum marks he can score in maths is 76.
Answer: C
Question: Roses can be purchased individually for $7.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?
A. 156
B. 162
C. 316
D. 324
Answer: C. 316
Explanation: Buy as many $50 deals as possible. We can by 650/50=13 two dozen roses, thus total of 13*24 = 312 roses.
We are left with 680 - 650 = $30. We can buy 30/7.3 = ~4 roses for that amount.
Total = 312 + 4 = 316.
Answer: C.
Question: The average age of a class of 42 students is 16 yrs. if the teacher's age is also included, the average increases by one year. Find the age of the teacher
A.45 Years
B.46 Years
C.59 Years
D.52 Years
Answer: C.59 Years
Explanation: Total age of students is 42X16 = 672 Years Total age inclusive of teacher = 43X (16+1) = 731 So, Teacher's age is 731-672= 59 Yrs There is a shortcut for these type of problems Teacher's age is 16+(43X1) = 59 Years Answer : C
Question: Suganya and Suriya are partners in a business. Suganya invests Rs. 35,000 for 8 months and Suriya invests Rs.42,000 for 10 months. Out of a profit of Rs.30,570. Suganya's share is
A.Rs.9471
B.Rs.12,628
C.Rs.18,040
D.Rs.12,228
Answer: D.Rs.12,228
Explanation: Solution
Ratio of their shares	=(35000Ã—8):(42000Ã—10)
= 2 : 3.
Suganya's share	= Rs.(31570 Ã—2/5)
= Rs.12228.
Answer D
Question: A train covers a distance in 50 min, if it runs at a speed of 48kmph on an average. The speed at which the train must run to reduce the time of journey to 40min will be.
A.60 km/h
B.55 km/h
C.40 km/h
D.70 km/h
Answer: A.60 km/h
Explanation: Time=50/60 hr=5/6hr
Speed=48mph
distance=S*T=48*5/6=40km
time=40/60hr=2/3hr
New speed = 40* 3/2 kmph= 60kmph
Answer : A.
Question: A train 650 m long is running at a speed of 117 km/hr. In what time will it pass a bridge 325 m long?
A.30
B.35
C.40
D.45
Answer: A.30
Explanation: Speed = 117 * 5/18 = 65/2 m/sec
Total distance covered = 650 + 325 = 975 m
Required time = 975 * 2/65 = 30 sec
Answer: A
Question: Find the value of ( 0.75 * 0.75 * 0.75 - 0.001 ) / ( 0.75 * 0.75 - 0.075 + 0.01)
A.0.845
B.1.908
C.2.312
D.0.001
Answer: A.0.845
Explanation: (0.75*0.75*0.75-0.001)=0.75^3 -0.1^3
0.75*0.75-0.075+0.01=0.75^2-0.1^2
a^3-b^3=(a+b)(a^2-ab+b^2)
so after cancellation remainning term is (a+b) i.e 0.75+0.1=0.85
nearly to 0.845
ANSWER:A
Question: The average age of seven persons sitting in a row facing east is 28 years. If the average age of the first three persons is 25 years and the average age of the last three persons is 34 years, then find the age of the person sitting in the middle of the row?
A.9 years
B.29 years
C.18 years
D.19 years
Answer: D.19 years
Explanation: Total age seven persons = (28 * 7)years
Total age of the first three persons and the last three persons are (25 * 3) years and (34 * 3) years respectively.
Age of the person sitting in the middle of the row = 28 * 7 - 25 * 3 - 34 * 3 = 196 - 75 - 102 = 19 years.
ANSWER:D
Question: A train speeds past a pole in 25 seconds and a platform 150 m long in 30 seconds. Its length is?
A.23
B.22
C.21
D.30
Answer: D.30
Explanation: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 25 => y = x/25
(x + 150) / 30 = x / 25
x = 30 m.
Answer:D
Question: Two trains are moving in opposite directions with speed of 150 km/hr and 90 km/hr respectively. Their lengths are 1.10 km and 0.9 km respectively. the slower train cross the faster train in --- seconds
A.56
B.48
C.47
D.30
Answer: D.30
Explanation: Explanation:
Relative speed = 150+90 = 240 km/hr (Since both trains are moving in opposite directions)
Total distance = 1.1+.9 = 2km
Time = 2/240 hr = 1/120 hr = 3600/120 seconds = 30 seconds
Answer: Option D
Question: LCM of 2/7,3/14 and 5/3is
A.45
B.35
C.30
D.25
Answer: C.30
Explanation: Explanation:
LCM of numerators /HCF of denominators= LCM of 2, 3, 5/HCFof7,14,3 = 30/1=30
Correct Option: C
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.13000 after a year?
A.3630
B.3900
C.8828
D.2387
Answer: B.3900
Explanation: 6300:4200:10500
3:2:5
3/10 * 13000 = 3900
Answer: B
Question: An error 1% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:
A.2.01
B.30.1
C.3.01
D.25.01
Answer: A.2.01
Explanation: Explanation:
100 cm is read as 101 cm.
A1 =(100 × 100)cm2 = 10000
and A2= (101 × 101)cm2= 10609
(A2 - A1) = 10201-10000 = 201
=> 201/10000*100 =2.01
Answer : A
Question: If the cost price is 81% of selling price then what is the profit percentage.
A.22.45
B.23.45
C.32.45
D.23.54
Answer: B.23.45
Explanation: selling price=Rs100 : then cost price=Rs 81:profit =Rs 19.
Profit={(19/81)*100}%=23.45%
Answer is B.
Question: On a certain day, Tim invested $500 at 10 percent annual interest, compounded annually, and Lana invested 800 at 5 percent annual interest, compounded annually.The total amount of interest earned by Tim’s investment in the first 2 years was how much greater than the total amount of interest earned by Lana’s investment in the first 2 years?
A.$5
B.$15
C.$23
D.$100
Answer: C.$23
Explanation: Compounded annually means that the interest is applied once per year. One can have 10% annual interest compounded monthly - in this case 10%/12 would be applied each month, or 10% annual interest compounded daily etc.
With respect to the problem at hand, at the end of two years, Tim would have
500(1.10)^2 = 500(1.21) = 605
and Lana would have
800(1.05)^2 = 800(1.1025) = 882
Thus, Tim earned 105 dollars, while Lana earned 82 dollars
The difference is $23 and the answer is C.
Question: John completes a piece of work in 320 days, Rose completes the same work in 480 days. If both of them work together, then the number of days required to complete the work is?
A.190
B.192
C.194
D.196
Answer: B.192
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 320 × 480/800 = 192 days
Answer is B
Question: Out of seven models, all of different heights, five models will be chosen to pose for a photograph. If the five models are to stand in a line from shortest to tallest, and the fourth-tallest and sixth-tallest models cannot be adjacent, how many different arrangements of five models are possible?
A.6
B.11
C.17
D.72
Answer: C.17
Explanation: Total no. of ways "5 models can be selected from 7" = 7C5 = 21.
Fourth tallest and Sixth tallest can never stand adjacent to each other. Also, all selected models will be lined up from shortest to tallest.
Hence, we have to pull out the no. of ways 4 & 6 stand adjacent to each other from the above total, i.e = 21.
The following will be the way in which 4 & 6 stand close to each other.
1 2 3 4 6
1 2 4 6 7
1 3 4 6 7
2 3 4 6 7
So, the answer will be 21-4 = 17 ways.
ANS:C
Question: Two pipes A and B can separately fill a tank in 10 and 15 minutes respectively. A third pipe C can drain off 45 liters of water per minute. If all the pipes are opened, the tank can be filled in 15 minutes. What is the capacity of the tank?
A.450
B.540
C.542
D.829
Answer: A.450
Explanation: 1/10 + 1/15 - 1/x = 1/15
x = 10
10 * 45 = 450
Answer: A
Question: A rectangular table seats 3 people on each of two sides, with every person directly facing another person across the table. If 6 people choose their seats at random, what is probability that person P directly faces person Q?
A.1/5
B.1/8
C.2/7
D.5/6
Answer: A.1/5
Explanation: Person P will be seated somewhere at the table.
Each of the other 5 people has an equal chance of sitting opposite person P.
The probability that person Q sits across is 1/5.
The answer is A.
Question: In what ratio should water and wine be mixed so that after selling the mixture at the cost price a profit of 33.33% is made?
A.1:4
B.1:3
C.2:3
D.3:4
Answer: B.1:3
Explanation: Explanation:
33.33% profit means there is one part water and 3 part is pure wine. so the required ratio of water and wine in the mixture is 1:3. Answer: B
Question: Of 30 applicants for a job, 11 had at least 4 years' experience, 18 had degrees, and 3 had less than 4 years' experience and did not have a degree.How many of the applicants had at least 4 years' experience and a degree?
A.14
B.13
C.8
D.7
Answer: C.8
Explanation: C. 8
30 - 3 = 27
27 - 11 - 18 = -8
Then 8 are in the intersection between 4 years experience and degree.
Answer C
Question: How many multiples of 2 are there between 10 and 100(both are inclusive)?
A.2
B.7
C.6
D.46
Answer: D.46
Explanation: the answer is (100-10)/2+1=46
Answer is D
Question: If the average (arithmetic mean) of 8 consecutive odd integers is 414, then the least of these integers is
A.a) 407
B.b) 518
C.c) 519
D.d) 521
Answer: A.a) 407
Explanation: A very helpful rule to know in arithmetic is the rule that in evenly spaced sets, average = median. Because the average will equal the median in these sets, then we quickly know that the median of this set of consecutive odd integer numbers is 414.
There are 8 numbers in the set, and in a set with an even number of terms the median is just the average of the two most median terms (here the 4th and 5th numbers in the set). This means that numbers 4 and 5 in this set are 413 and 415. Because we know that number 4 is 413, we know that the smallest number is 3 odd numbers below this, which means that it is 3*2 = 6 below this (every odd number is every other number). Therefore 413-6 = 407, answer choice A
Question: If N = 2^0.15 and N^b = 32, b must equal
A.3/80
B.3/5
C.4
D.100/3
Answer: D.100/3
Explanation: 15/100 = 3/20
N = 2 ^ 3/20
N^b = 2^5
(2^3/20)^b = 2^5
b = 100/3
Answer: D
Question: The slant height of a cone is 12 cm and radius of the base is 4cm, find the curved surface of the cone?
A.87
B.26
C.48
D.37
Answer: C.48
Explanation: π * 12 * 4
= 48
Answer:C
Question: Of the 20 members of a kitchen crew, 17 can use the meat-cutting machine, 18 can use the bread-slicing machine, and 15 can use both machines. If one member is chosen at random, what is the probability that the member chosen will be someone who cannot use either machine?
A.0
B.1/10
C.1/7
D.1/4
Answer: A.0
Explanation: You know how to solve for Total number of people who can use at least one machine:
Total = n(A) + n(B) - n(A and B)
Total people who can use at least one machine = 17 + 18 - 15 = 20
So all 20 people know how to use at least one machine. Hence, if you pick anyone, the probability is 0 that he wouldn't know how to use any machine.
Answer A
Question: A CAR HAS RUNS 10000 MILES USING 5 TYRES INTERCHANGABLY TO HAVE A EQUAL WORNOUT BY ALL TYRES HOW MANY MILES EACH TYRE SHOULD HAVE RUN?
A.7000 miles.
B.8000 miles.
C.9000 miles.
D.6000 miles.
Answer: B.8000 miles.
Explanation: Total distance traveled by all the tires is 4*10000= 40000 miles.(since only 4 tires can be active at a time.
To make an equal run, Distance traveled by each tire is 40000/5 = 8000 miles.
ANSWER:B
Question: A train covers a distance at a speed of 240kmph in 5 hours. To cover the same distance in 5/3 hours, it must travel at a speed of?
A.516
B.840
C.560
D.720
Answer: D.720
Explanation: Distance = 240*5 = 1200km
Required speed = 1200*3/5 = 720 km/hr
Answer is D
Question: Calculate how many ways a woman who has 4 bags and 5 books can put the books in her bag?
A.1034
B.1025
C.1024
D.1025
Answer: C.1024
Explanation: First book can be put in 4 ways, similarly second, third ,forth and fifth books also can be put in 4 ways.
So total number of ways = 4 x 4 x 4 x 4 x 4 = 1024
C
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
A.5.74 km
B.5.78 km
C.5.76 km
D.5.79 km
Answer: C.5.76 km
Explanation: M = 6
S = 1.2
DS = 7.2
US = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
D = 2.88 * 2 = 5.76
Answer:C
Question: What is the CP of Rs 100 stock at 5 discount, with 1/5% brokerage?
A.99.6
B.95.2
C.97.5
D.98.25
Answer: B.95.2
Explanation: Explanation:
Use the formula,
CP= 100 â€“ discount + brokerage%
CP= 100-5+1/5
95.2
Thus the CP is Rs 95.2.
ANSWER B
Question: The weights of one liter vegetable ghee packet of two brands ‘A’ and ‘B’ are 900 gm and 750 gm respectively. If they are mixed in the ratio of 3 : 2 by volumes to form a mixture of 4 liters, what is the weight (in kg) of the mixture?
A.3.84
B.1.75
C.3.36
D.2.72
Answer: C.3.36
Explanation: Here's how I did it. My notes from reading the problem were:
1L A = 900 gm
1L B = 850 gm
We are mixing five parts (3 parts A plus 2 parts B, 5 parts total) to get 4L, so 5x = 4 ---> x = 4/5. Eachpartis 4/5 of a liter.
So if we have 3 parts A, we have 900*3*(4/5) = 2160
If we have 2 parts B, we have 750*2*(4/5) = 1200
2160 + 1200 = 3360
Solving for units gives us 3.36
So the answer is C
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
A.16 km/hr
B.56 km/hr
C.43 km/hr
D.50 km/hr
Answer: D.50 km/hr
Explanation: Speed of the train relative to man
= (125/10) m/sec
= (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45
==> x
= 50 km/hr.
Answer:D
Question: If 5^k + 5^k = (5^9)^(5^9) - 5^k, then k = ?
A. 5^11 - 1
B. 11/2
C. 242
D. 3^10
Answer: A. 5^11 - 1
Explanation: 5^k + 5^k = (5^9)^5^9 - 5^k
5*(5^k) = 5 ^ (25 * 5^9 ) = 5^(5^2 * 5^9) = 5^(5^11)
5^k+1 = 5^(5^11)
So k+1 = 5^11
So k = 5^11 -1
Answer is A
Question: The cash realised on selling a 14% stock is Rs.107.25, brokerage being 1/4% is?
A.366
B.107
C.102
D.192
Answer: B.107
Explanation: Cash realised= Rs. (107.25 - 0.25)
= Rs. 107.
Answer: B
Question: An employer pays Rs.20 for each day a worker works and for fests Rs.3 for each day is ideal at the end of sixty days a worker gets Rs.280 . for how many days did the worker remain ideal?
A.40
B.30
C.70
D.20
Answer: A.40
Explanation: Suppose a worker remained ideal for x days then he worked for 60-x days
20*(60-x)-3x=280
1200-23x=280
23x=920
x=40
Answer is A.
Question: A car covers a distance of 624 km in 6 Â½ hours. Find its speed?
A.104
B.140
C.200
D.150
Answer: A.104
Explanation: 624/6 = 104 kmph
ANSWER A
Question: The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person
A.15
B.20
C.25
D.30
Answer: D.30
Explanation: Explanation:
Let's take the present age of the elder person = x
and the present age of the younger person = x – 16
(x – 6) = 3 (x-16-6)
=> x – 6 = 3x – 66
=> 2x = 60
=> x = 60/2 = 30
Answer: Option D
Question: Working alone at its constant rate, machine K took 3 hours to produce 1/8 of the units produced last Friday. Then machine M started working and the two machines, working simultaneously at their respective constant rates, took 6 hours to produce the rest of the units produced last Friday. How many hours would it have taken machine M, working alone at its constant rate, to produce all of the units produced last Friday?
A.9.6
B.12.4
C.16.2
D.18.3
Answer: A.9.6
Explanation: Machine K works at a rate of 1/24 of the units per hour.
The rate of K + M together is 7/8 * 1/6 = 7/48 of the units per hour.
The rate of machine M is 7/48 - 2/48 = 5/48.
It would have taken machine M a total time of 9.6 hours.
The answer is A.
Question: The number 219 can be written as sum of the squares of 3 different positive integers. What is the sum of these 3 different integers?
A.20
B.21
C.19
D.17
Answer: B.21
Explanation: sum of the squares of 3 different positive integers = 219
13^2 + 7^2 + 1^2 = 219
now,
sum of these 3 different integers = 13 + 7 + 1 = 21
Ans - B
Question: Griffin has a bag of marbles that contains 7 black marbles and 5 red marbles. If he removes 3 marbles at random without replacing any of the marbles, what is the probability that all 3 marbles selected will be black?
A.4/15
B.5/22
C.6/35
D.7/44
Answer: D.7/44
Explanation: P(3 black marbles) = 7/12*6/11*5/10 = 7/44
The answer is D.
Question: A train 100 m long is running at the speed of 30 km / hr. Find the time taken by it to pass a man standing near the railway line in seconds
A.5 sec
B.6 sec
C.7 sec
D.8 sec
Answer: B.6 sec
Explanation: Explanation:
Speed of the train = (60 x 5/18m / sec = 50/3 m/ sec.
Distance moved in passing the standing man = 100 m.
Required time taken = 100/(50/3) = (100 ×(3/50)) sec =6 sec
Answer: Option B
Question: A gardener grows cabbages in her garden that is in the shape of a square. Each cabbage takes 1 square feet of area in her garden. This year, she has increased her output by 181 cabbages as compared to last year. The shape of the area used for growing the cabbages has remained a square in both these years. How many cabbages did she produce this year?
A.6564
B.7372
C.8281
D.9331
Answer: C.8281
Explanation: Let the side for growing cabbages this year be X ft. Thus the area is X^2.
Let the side for growing cabbages last year be Y ft. Thus, the area was Y^2.
The area would have increased by 181 sq ft as each cabbage takes 1 sq ft space.
X^2 - Y^2 = 181
(X + Y)(X - Y) = 181
181 is a prime number and thus it will be (91+90)*(91-90).
Thus X = 91 and Y = 90
X^2 = 91^2 = 8281
The answer is C.
Question: Given that 2x + 15 > 5 and 5x - 13 < 7, all values of x must be between which of the following pairs of integers?
A.-4 and -1
B.-5 and 4
C.-4 and 1
D.-2 and 5
Answer: B.-5 and 4
Explanation: 2x + 15 > 5
i.e 2x >5-15
i.e. 2x > -10
i.e. x > -5
Also, 5x - 13 < 7
i.e. 5x <7+13
i.e 5x < 20
i.e x < 4
i.e. -5 < x < 4
Answer: Option B
Question: Difference between the length &breadth of a rectangle is 15 m. If its perimeter is 90 m, then its area is??
A.2000 m^2
B.2340 m^2
C.450 m^2
D.2556 m^2
Answer: C.450 m^2
Explanation: We have: (l - b) = 15 and 2(l + b) = 90 or (l + b) = 45
so 2 l = 60 = > l = 30 & b = 15
Area = 30 * 15 = 450 m^2
Answer : C