RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Simple interest on a sum at 9% per annum for 2 years is Rs.200. The C.I. on the same sum for the same period is?
A.201.1
B.201.5
C.200.4
D.109.1
Answer: A.201.1
Explanation: SI = 100 + 100
CI = 100 + 100 + 1.1 = 201.1
Answer: A
Question: A walks at 30 kmph and 30 hours after his start, B cycles after him at 55 kmph. How far from the start does B catch up with A?
A.1200km
B.1980km
C.2000km
D.2500km
Answer: B.1980km
Explanation: Suppose after x km from the start B catches up with A. Then, the difference in the time taken by A to cover x km and that taken by B to cover x km is 30 hours.
x/30 - x/55 = 30
x = 1980 km
Answer is B
Question: A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is:
A.8.5 km/hr
B.10 km/hr
C.12.5 km/hr
D.9 km/hr
Answer: B.10 km/hr
Explanation: Man's speed with the current = 15 km/hr
=> speed of the man + speed of the current = 15 km/hr
speed of the current is 2.5 km/hr
Hence, speed of the man = 15 - 2.5 = 12.5 km/hr
man's speed against the current = speed of the man - speed of the current
= 12.5 - 2.5 = 10 km/hr
ANSWER:B
Question: Jack and Jill are marathon runners. Jack can finish a marathon (42 km) in 6 hours and Jill can run a marathon in 4.2 hours.What is the ratio of their average running speed? (Jack: Jill)
A.7/10
B.15/14
C.4/5
D.5/4
Answer: A.7/10
Explanation: Average Speed of Jack =Distance/ Time
= 42 /6= 7
Average Speed of Jill = 42/(4.2) = 10
Ratio of Average speed of Jack to Jill = 7/10
Answer A
Question: If x=y=2z and xyz=256 then what is the value of x?
A.12
B.8
C.16
D.6
Answer: B.8
Explanation: Given that x=y=z.
so,x=y,
x=2z,
y=2z.
given xyz=256
=>(2z)*(2z)*z=256
=>4z^3=256
=>z=4
then x=2z
=2(4)
=8
ANSWER:B
Question: Harkamal purchased 8kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 50 per kg. How much amount did he pay to the shopkeeper?
A.A)1000
B.B)1010
C.C)1065
D.D)1075
Answer: B.B)1010
Explanation: Cost of 8 kg grapes = 70 × 8 = 560.
Cost of 9 kg of mangoes = 50 × 9 = 450.
Total cost he has to pay = 560 + 450 = 1010.
B)
Question: Find the odd man out. 1,4,9,16,20
A.8
B.10
C.25
D.6
Answer: C.25
Explanation: Explanation :
1^2=1
2^2=4
3^2=9
4^2=16
5^2=25
Hence, it is clear that 25 should have come instead of 20
Answer : Option C
Question: Havid has d books, which is 3 times as many as Jeff and 1/2 as many as Paula. How many books do the three of them have altogether, in terms of d?
A. 5/6*d
B. 7/3*d
C. 10/3*d
D. 7/2*d
Answer: C. 10/3*d
Explanation: Havid has d books;
Jeff has d/3 books;
Paula has 2d books;
Total = d+d/3+2d=10d/3.
Answer: C.
Question: Mike needs 30% to pass. If he scored 212 marks and falls short by 25 marks, what was the maximum marks he could have got?
A.343
B.677
C.790
D.867
Answer: C.790
Explanation: If Mike had scored 25 marks more, he could have scored 30%
Therefore, Mike required 212 + 25 = 237 marks
Let the maximum marks be m.
Then 30 % of m = 237
(30/100) × m = 237
m = (237 × 100)/30
m = 23700/30
m = 790
Answer:C
Question: Bag A contains red, white and blue marbles such that the red to white marble ratio is 1:3 and the white to blue marble ratio is 2:3. Bag B contains red and white marbles in the ratio of 1:4. Together, the two bags contain 24 white marbles. How many red marbles could be in bag A?
A.1
B.3
C.4
D.6
Answer: C.4
Explanation: 6 is the answer.
Bag A-
R:W:B = 2:6:9
Let W in bag A be 6K
Bab B -
R:W = 1:4
Let W in bag B be 4P
W = 24 = 6K+4P
=> K =2, P=3
Total Red's in bag A will be 2K = 4
C
Question: The timing of a college is from 12 p.m to 4.20 p.m. Five lectures are held in the given duration and a break of 5 minutes after each lecture is given to the students. Find the duration of each lecture.
A.52 minutes
B.45 minutes
C.30 minutes
D.48 minutes
Answer: D.48 minutes
Explanation: Explanation:
Total time a student spends in college = 4 hours 20 minutes = 260 minutes
As there are 5 lectures, the number of breaks between lectures is 4. Total time of the break = 20 minutes
Hence, the duration of each lecture is = (260 – 20)/5
= 48 minutes
ANSWER D
Question: On dividing 12401 by a certain number, we get 76 as quotient and 13 as remainder. What is the divisor?
A.163
B.785
C.852
D.456
Answer: A.163
Explanation: Divisor *quotient+remainder=dividend
divisor=(dividend)-(remainder)/quotient
(12401-13)/76=163
Answer(A)
Question: Three people each took 5 tests. If the ranges of their scores in the 5 practice tests were 15, 25 and 30, what is the minimum possible range in scores of the three test-takers?
A.25
B.30
C.35
D.15
Answer: A.25
Explanation: I simply looked at the 3 different possible scores for each individual test: 15,30,25
We have to find the minimum range:
30-15=15
30-25=5
25-15=10
The find the minimum range, you have to make the set of the 5 scores as small as possible.
Which means that 4 of the 5 scores of each individual person is zero.
5*5 = 25.
Answer:A
Question: There are 30 people in a party. If everyone is to shake hands with one another, how many hand shakes are possible?
A.435
B.367
C.361
D.297
Answer: A.435
Explanation: Explanation:
Total number of persons = n = 30
Shakehands involve only 2 persons = r = 2
Number of shakehands = nCr = 30C2
30C2 = (30 * 29) /(2 * 1) = 435
nCr = (n!) / r! (n – r)!
= 30! / 2! 28!
= 435
ANSWER:A
Question: A pump can fill a tank with a water in 2 hours. Because of a leak, it took 2 and 4/5 hours to fill the tank. The leak can drain all the water of the full tank in how many hours?
A.4
B.5
C.6
D.7
Answer: D.7
Explanation: The rate of the pump + leak = 5/14
1/2 - leak's rate = 5/14
leak's rate = 1/2 - 5/14 = 1/7
The leak will empty the tank in 7 hours.
The answer is D.
Question: P alone can complete a piece of work in 6 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?
A.491/2)
B.4(1/2)
C.4(1/8)
D.7(1/2)
Answer: D.7(1/2)
Explanation: Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9 of the total
They would take 9/2 days = 4 (1/2) days to complete the work working together.
Answer:D
Question: A cyclist traveled for two days. On the second day the cyclist traveled 6 hours longer and at an average speed 10 mile per hour slower than she traveled on the first day. If during the two days she traveled a total of 280 miles and spent a total of 12 hours traveling, what was her average speed on the second day?
A.5 mph
B.10 mph
C.20 mph
D.30 mph
Answer: A.5 mph
Explanation: SOLUTION:
D = 280 Mi
T = 12 hrs
Đây 1 time = T1
Dây 2 time = T2
T2 - T1 = 4 hrs ----- (I)
T1 + T2 = 12 hrs ----- (II)
Adding I and II, T2 = 8 hrs and T1 = 4 hrs
Dày 1 Rate = R1
Dây 2 Rate = R2
R1 - R2 = 10 mph
í.ẹ. R1 = 10 + R2
280 = 8R2 + 4R1
í.ẹ. 280 = 8R2 + 4 (10 + R2)
í.ẹ. R2 = 20 mph
ANSWER: A
Question: If the two-digit integers A and B are positive and have the same digits, but in reverse order, which of the following could be the sum of A and B?
A.77
B.78
C.79
D.80
Answer: A.77
Explanation: A two-digit number "cd" can be expressed algebraically as 10c+d.
The sum of A + B = (10c+d)+(10d+c)=11(c+d).
The only answer that is a multiple of 11 is 77.
The answer is A.
Question: The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is 6250 and the average monthly income of P and R is Rs. 5250. The monthly income of P is?
A.A)Rs.4078
B.B)Rs.4000
C.C)Rs.4050
D.D)Rs.4027
Answer: C.C)Rs.4050
Explanation: Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 * 2) = 10100 --- (i)
Q + R = (6250 * 2) = 12500 --- (ii)
P + R = (5200 * 2) = 10500 --- (iii)
Adding (i), (ii) and (iii), we get:
2(P + Q + R) = 33100 = P + Q + R = 16550 --- (iv)
Subtracting (ii) from (iv), we get, P = 4050.
P's monthly income = Rs.4050.
Answer: C
Question: A teacher can divide her class into groups into groups of 5,13 and 17. What is the smallest possible strength of the class?
A.1387
B.1768
C.1105
D.1286
Answer: C.1105
Explanation: Explanation:
For smallest possible class strength, we consider LCM of the given numbers. So LCM (5, 13, 17) = 1105
Answer: C
Question: If the cost of 6 erasers and 4 sharpeners is Rs.21/-. What will be the cost of 24 erasers and 16 sharpeners?
A.Rs.62/-
B.Rs.84/-
C.Rs.64/-
D.Rs.88/-
Answer: B.Rs.84/-
Explanation: Explanation:
6 erasers + 4 sharpeners = Rs.21.
Multiply by 4
We get,
24 erasers + 16 sharpeners = Rs.21x4 = Rs.84/-.
Answer: Option B
Question: The contents of two vessels containing copper and tin in the ratio 1:2 and 2:5 are mixed in the ratio 1:4. The resulting mixture will have copper and tin in the ratio?
A.15:32
B.21:28
C.31:74
D.33:37
Answer: C.31:74
Explanation: The ratio of copper and tin the new vessel= (1/3*1/5 + 2/7*4/5) : (2/3*1/5 + 5/7*4/5)
= 31/105 : 74/105 = 31:74
Answer is C
Question: What will come in place of the question mark (?) in the following question?
112.36 + 225.05 + ? = 815.30
A.477.79
B.477.8
C.477.81
D.477.89
Answer: D.477.89
Explanation: Explanation:
815.30 - ( 112.36 + 225.05) = ?
= 477.89
ANSWER:D
Question: A wooden box of dimensions 8 m x 7 m x 6 m is to carry rectangularboxes of dimensions 4 cm x 7 cm x 6 cm. The maximum number ofboxes that can be carried in the wooden box, is
A.9800000
B.1000000
C.7500000
D.2000000
Answer: D.2000000
Explanation: Explanation: Number = (800*700*600)/8*7*6 = 2000000 Answer: D
Question: Two unbiased coins are tossed. What is the probability of getting at most one head?
A.1/2
B.1/4
C.2/3
D.3/4
Answer: D.3/4
Explanation: S = {HH, HT, TH, TT}
E = event of getting at most one head
E = {TT, HT, TH}
P(E) = 3/4
Answer is D
Question: Natasha climbs up a hill, and descends along the same way she went up. It takes her 4 hours to reach the top and 2 hours to come back down. If her average speed along the whole journey is 3 kilometers per hour, what was her average speed (in kilometers per hour) while climbing to the top?
A.1.75
B.2.25
C.2.5
D.2.75
Answer: B.2.25
Explanation: Let the distance to the top be x, so the total distance traveled by Natasha is 2x.
The total time is 4 + 2 = 6 hours
The average speed = total distance/total time taken = 2x/6 = x/3
The average speed of the complete journey is 3 km/hour
x/3 = 3
x = 9 km
The average speed while climbing = distance/time = 9/4 = 2.25 km/h
The answer is B.
Question: What is the unit’s digit of 213 *212*347*468*778 ?
A.5
B.6
C.7
D.8
Answer: D.8
Explanation: 3 × 2 = 6
6 × 7 = 42
2 × 8 = 16
6 × 8 = 48
So at units place 8 is present
thus ans is 8
ANSWER:D
Question: The product D of the first 10 prime numbers is closest to which of the following?
A.6.5 x 10^7
B.6.5 x 10^8
C.6.5 x 10^9
D.6.5 x 10^10
Answer: C.6.5 x 10^9
Explanation: The first 10 primes are: 2, 3, 5, 7, 11, 13, 17, 19, 23, and 29.
So, we need to find approximate value of 2*3*5*7*11*13*17*19*23*29.
# of different approximations are possible. For example:
2*5=10
3*17=~50 (actually more than 50);
7*13=~100 (actually less than 100);
11*19=~200 (actually more than 200)
23*29=667=D
2*3*5*7*11*13*17*19=~10*50*100*200*667=10^7*667=6.67*10^9.
Answer: C.
Question: On a sum of money ,the simple interest for 2 years is Rs. 660,while the compound interest is Rs. 696.30,the rate of interest being the same in both the cases.The rate of interest is :
A.10%
B.10.5%
C.12%
D.None of these
Answer: D.None of these
Explanation: Solution
Difference in C.I. and S.I. for 2 years = Rs.(696.30 - 660)= Rs. 36.30.
S.I. for one year = Rs. 330.
∴ S.I. on Rs. 330 for 1 year = Rs. 36.30.
∴ Rate (100x36.30/330x1)% = 11%. Answer D
Question: The duplicate ratio of 3:4 is?
A.9:15
B.9:10
C.9:16
D.9:13
Answer: C.9:16
Explanation: 32: 42 = 9:16
Answer: C
Question: A number consists of two digits whose sum is 11. If 27 is added to the number, then the digits change their places. What is the number ?
A.47
B.65
C.83
D.92
Answer: A.47
Explanation: Explanation:
Let the ten's digit be x. Then, unit's digit = (11 - x).
So, number = 10x + (11 - x) = 9x + 11.
Therefore (9x + 11) + 27 = 10 (11 - x) + x 9x + 38 = 110 - 9x 18x = 72 x = 4.
Thus, ten's digit = 4 and unit's digit = 7.
Hence, required number = 47.
Answer: Option A
Question: What is the smallest prime number with two sevens in it?
A.77
B.177
C.277
D.377
Answer: C.277
Explanation: The smallest positive integers with two sevens are 77, 177, 277, . . . . The first
integer with two sevens that does not end with two sevens is 707.
77 = 7 11, and 177 is divisible by 3 because the sum of its digits is. So now you just need to
check that 277 is prime. There is no particular shortcut to see this – test divisibility by 2, 3, 5,
7, 11, and 13.
correct answer C
Question: If neha is 10
Both Sonali and priyanka is 15
Both sadaf and tanu is 10.
how much is prinka by the same system ?
A.8
B.11
C.10
D.15
Answer: C.10
Explanation: C
prinka is 10, in a system that awards five for each vowel.
Question: If X boxes of grape juice cost 200 cents, how much will Y boxes cost in dollars?
A.Y*3/x
B.Y*4/x
C.Y*2/x
D.Y*6/x
Answer: C.Y*2/x
Explanation: X boxes of grape juice cost 200 cents or 2 dollars.
cost of grape juice = 2/x
Cost of Y grape juices = Y*2/x
Hence Answer : C
Question: √3 percent of 3√3 =
A.5.2
B.1.0
C.0.1
D.2.0
Answer: C.0.1
Explanation: The other solutions are great, but here's one more approach.
First, we scan the answer choices to see that they are quite spread apart. This means we can also use someAPPROXIMATION
All test-takers must memorize the following approximations:
√2 ≈ 1.4
√3 ≈ 1.7
So, √3 percent of 3√3 ≈ 1.7 percent of (3)(1.7)
≈ (1.7/100)(5.1)
≈ 8.67/100
≈ 0.08
Check the answer choices to see that C is the only answer that's close.
Answer: C
Question: On average, activated yeast cells divide once every 120 minutes; that is, each individual cell divides into two individual cells over that time span. Given that a certain yeast colony consisted of 310,000 cells two hours ago, approximately how many cells will be populating the colony ten hours from now?
A.77,500
B.1,860,000
C.12,480,000
D.19,840,000
Answer: D.19,840,000
Explanation: 310,000 × 2 × 2×2×2×2×2 = 310,000 × 64 = D
Question: Two trains of equal are running on parallel lines in the same direction at 50 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
A.70 m
B.72 m
C.80 m
D.82 m
Answer: A.70 m
Explanation: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 50 - 36 = 14 km/hr.
= 14 * 5/18 =35/9 m/sec.
2x/36 =35/9 => x = 70.
ANSWER:A
Question: The greatest ratio out of 2:1, 5:8, 3:2, 8:9 and 8:5 is?
A.2:1
B.3:2
C.5:8
D.8:5
Answer: A.2:1
Explanation: 2/1=2
5/8=0.625
3/2=1.5
8/9=0.888
8/5=1.6
ANSWER:A
Question: How many numbers from 10 to 40 are exactly divisible by 3?
A.13
B.15
C.16
D.10
Answer: D.10
Explanation: 12, 15, 18, 21, 24, 27, 30, 33, 36, 39.
10 Numbers.
10/3 = 3 and 40/3 = 13 ==> 13 - 3 = 10. Therefore 10 digits
D)
Question: Each of the following equations Q has at least one solution EXCEPT
A.Q=–2^n = (–2)^-n
B.Q=2^-n = (–2)^n
C.2^n = (–2)^-n
D.(–2)^n = –2^n
Answer: A.Q=–2^n = (–2)^-n
Explanation: While it is possible to reason out which of these choices must not work, we may not have time or the confidence to do so. However, this problem has variable in its answer choice, and relatively simple math. Therefore, an easy alternative is picking numbers.
Since we're dealing with exponents, we want to keep things as easy as possible. Hence, we'll start with the easiest exponent possible: n = 1. A, B, and C are not solved (x^-n = 1/(x^n), so we're comparing integers to fractions), but choices D and E both end up valid, eliminating them from contention.
In the process of doing this, however, we've uncovered a major clue to our next step: A, B, and C, all compared integers to fractions, and the only integer equal to it's reciprocal is 1, which is equal to 1/1. This, in turn, tells us the we need to pick n = 0. Remember, for all non-zero x, x^0 = 1.
If we plug n = 0 into choices B and C, we end up with 1 = 1 both times. Choice A, however, results in the false 1 = -1. Thus, we conclude that the first choice has no valid solutions, and is therefore the correct answer.
Question: A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m , then the altitude of the triangle is
A.10√2 m
B.100 m
C.100√2 m
D.200 m
Answer: D.200 m
Explanation: Solution
Let the altitude of the triangle be hïand base of each be b.
Then , (½ ×b× h1) where h2 = 100 m.
= h1 = 2h2
= ( 2 x 100) m
= 200 m.
Answer D
Question: The length and breadth of the floor of the room are 20 feet and 10 feet respectively. Square tiles of 2 feet length of different colours are to be laid on the floor. Black tiles are laid in the first row on all sides. If white tiles are laid in the one-third of the remaining and blue tiles in the rest, how many blue tiles will be there?
A.16
B.24
C.32
D.48
Answer: A.16
Explanation: Area left after laying black tiles
= [(20 – 4) × (10 – 4)] sq. ft. = 96 sq. ft.
Area under white tiles = (1⁄3 × 96) sq. ft = 32 sq. ft.
Area under blue tiles = (96 – 32) sq. ft = 64 sq. ft.
Number of blue tiles = 64/2×2=16.
Answer A
Question: If 20 men can build a wall 66 metres long in 8 days, what length of a similar can be built by 86 men in 8 days?
A.283.8 mtrs
B.378.4 mtrs
C.478.4 mtrs
D.488.4 mtrs
Answer: A.283.8 mtrs
Explanation: If 20 men can build a wall 66 metres long in 8 days,
length of a similar wall that can be built by 86 men in 8 days = (66*86*8)/(8*20) = 283.8 mtrs
ANSWER:A
Question: How many multiples of 6 are there between 30 and 140, 30 and 140 inclusive ?
A.18
B.16
C.17
D.19
Answer: D.19
Explanation: 6 multiples are ...30,36,42,48,54,60,66,72,78,84,90,96,102,108,114,120,126,132,138,...
,...,
the answer is =19
Answer is D
Question: How many 5 digit ( digit = 0 - 9 ) zip codes can exist in which at least one digit is repeated ?
A.39760
B.49760
C.59760
D.69760
Answer: D.69760
Explanation: Zip codes with 5 digits (all five digits can be repeated): 10^5=100,000
Zip codes with no digit being repeated: 10*9*8*7*6=30,240
Zip codes with at least one digit being repeated: 100,000-30,240=69,760
= 69760
ANS:D
Question: Express of the following as a fraction:
56%
A.14/25
B.13/25
C.11/25
D.17/25
Answer: A.14/25
Explanation: 56% = 56/100= 14/25.
Answer is A.
Question: What will come in place of the x in the following Number series? 11, 14, 19, 22, 27, 30, x
A.23
B.26
C.41
D.35
Answer: D.35
Explanation: (D)
The pattern is + 3, + 5, + 3, + 5, …………
So the missing term is = 30 + 5 = 35.
Question: Two trains each 210m in length each, are running on two parallel lines in opposite directions. If one goes at the speed of 90km/h while the other travels at 85km/h. how long will it take for them to pass each other completely.
A.3 sec
B.2.6 sec
C.3.6 sec
D.8.6 sec
Answer: D.8.6 sec
Explanation: Explanation:
D = 210 m +210 m = 420 m
RS = 90 + 85 = 175 * 5/18 = 243/5
T = 420 * 5/243 = 8.6 sec
Answer: Option D
Question: A can do in 6 day and B can do in 8 and C can do in 12 days but b left after working for 6 days for how many no of day A and C shluld work ?
A.2 days
B.1 day
C.3 days
D.4 days
Answer: B.1 day
Explanation: B for one day work is 1/8
he worked for 6 days, so 6*1/8=3/4 work will be completed.
remaining work is 1-3/4=1/4
A and C can complete the work in 4 days
but there is only 1/4 work that is to be completed, so A and C can complete 1/4 work in 1 day..
ANSWER:B
Question: Mahesh can do a piece of work in 60days. He works at it for 20days and then Rajesh finished it in 30days. How long will Y take to complete the work?
A.45
B.25
C.37
D.41
Answer: A.45
Explanation: Work done by Mahesh in 60days = 20*1/60 = 1/3
Remaining work = 1 - 1/3 = 2/3
2/3 work is done by Rajesh in 30days
Whole work will be done by Rajesh is 30*3/2 = 45days
Answer is A
Question: Anne bought doughnuts for a class breakfast party. She bought 12 chocolate doughnuts, 6 coconut doughnuts, and 8 jam-filled doughnuts. How many doughnuts did Anne buy in all?
A.25
B.26
C.39
D.21
Answer: B.26
Explanation: Add the numbers of doughnuts.
12 + 6 + 8 =26.
Answer is B.
Question: In the Johnsons' monthly budget, the dollar amounts allocated to household expenses, food, and miscellaneous items are in the ratio 5:3:1, respectively. If the total amount allocated to these three categories is $1,800, what is the amount allocated to food?
A. $900
B. $720
C. $600
D. $450
Answer: C. $600
Explanation: To solve this question, it will be best to first express the given ratio using variable multipliers. Thus, we have:
Household Expenses : Food : Miscellaneous = 5x : 3x : x
Since we are told that the TOTAL amount allocated to these categories is $1,800 we can set up the equation:
5x + 3x + x = 1,800
9x = 1,800
x = 200
Thus, the total amount allocated to food is 3 x 200 = $600.
Answer C.
Question: If 20 men can build a wall 66 metres long in 6 days, what length of a similar can be built by 86 men in 8 days?
A.278.4 mtrs
B.378.4 mtrs
C.478.4 mtrs
D.488.4 mtrs
Answer: B.378.4 mtrs
Explanation: If 20 men can build a wall 66 metres long in 6 days,
length of a similar wall that can be built by 86 men in 8 days = (66*86*8)/(6*20) = 11*172/5 = 1892/5 mtrs = 378.4 mtrs
ANSWER:B
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
A.22
B.44
C.276
D.29
Answer: B.44
Explanation: Explanation:
Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352 => T = 44.
Answer:B
Question: The ratio of the number of ladies to gents at a party was 1:2 but when 2 ladies and 2 gents left, the ratio became 1:3. How many people were at the party originally?
A.12
B.6
C.15
D.8
Answer: A.12
Explanation: x, 2x
(x-2):(2x-2) = 1:3
3x-6 = 2x-2
x = 4
x+2x = 3x
=> 3*4 = 12
ANSWER A
Question: Suppose 10 monkeys take 20 minutes to eat 10 bananas. How many monkeys would it take to eat 80 bananas in 80 minutes?
A.9
B.10
C.11
D.20
Answer: D.20
Explanation: One monkey takes 20 min to eat 1 banana , so in 80 mins 1 monkey will eat 4 bananas , so for 80 bananas in 80 min we need 80/4 =20 monkeys
ANSWER:D
Question: 10 men do a work in 10days. How many men are needed to finish the work in 2days?
A.50
B.20
C.30
D.10
Answer: A.50
Explanation: men required to finish the work in 2days = 10*10/2 = 50
Answer is A
Question: A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's age is?
A.25 years
B.65 years
C.45 years
D.75 years
Answer: C.45 years
Explanation: Let x and y be the ten's and unit's digits respectively of the numeral denoting the woman's age.
Then, woman's age = (10X + y) years; husband's age = (10y + x) years.
Therefore (10y + x)- (10X + y) = (1/11) (10y + x + 10x + y)
(9y-9x) = (1/11)(11y + 11x) = (x + y) 10x = 8y x = (4/5)y
Clearly, y should be a single-digit multiple of 5, which is 5.
So, x = 4, y = 5.
Hence, woman's age = 10x + y = 45 years.
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Answer:C
Question: A certain telephone number has seven digits. If the telephone number has the digit zero exactly 3 times, and the number 1 is not used at all, what is the probability that the phone number contains one or more prime digits.
A.1/24
B.1/16
C.1/2
D.15/16
Answer: D.15/16
Explanation: First step of getting rid of 3 digits of containing zeros is right: we are left with 4 digit number each of which can be one of 8 digit (2,3,4,5,6,7,8,9 as 0 is already used in first three and 1 is not used).
Next step:
total number of combinations possible 8^,
combinations with NO PRIME 4^4,
P(no prime)=4^4/8^4=1/2^4
P(p>=1)=1-1/2^4=15/16
Answer D.
Question: Look at this series: 2, 6, 18, 54, ... What number should come next?
A.108
B.148
C.162
D.216
Answer: C.162
Explanation: Explanation: This is a simple multiplication series. Each number is 3 times more than the previous number.
Answer: Option C