RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What amount does Kiran get if he invests Rs.6450 at 15% p.a. compound interest for two years, compounding done annually?
A.8400
B.8900
C.4560
D.8530
Answer: D.8530
Explanation: A= P{1 + R/100}n
=> 6450{1 + 15/100}2
= Rs.8530
Answer: D
Question: Find the number of square tiles to cover the floor of a room measuring 4 m * 9 m leaving 0.25 m space around the room. A side of square tile is given to be 25 cms?
A.125
B.879
C.476
D.255
Answer: C.476
Explanation: Explanation:
3 1/2 * 8 1/2 = 1/4 * 1/4 * x => x = 476
Answer : C
Question: The average weight of 10 persons increases by 3.2 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
A.76 kg
B.80 kg
C.85 kg
D.97 kg
Answer: D.97 kg
Explanation: Solution
Total weight increased	= (10 x 3.2)kg
= 32 kg.
Weight of new person	= (65 + 32)kg
= 97 kg.
Answer D
Question: What no. should be subtracted from x^3+4x^2−7x+12x^3+4x^2−7x+12, if it is to be perfectly divisible by x+3x+3?
A.40
B.42
C.44
D.48
Answer: B.42
Explanation: According to remainder theorem when dfracf(x)x+adfracf(x)x+a, then the remainder is f(−a)f(−a).
In this case, as x+3x+3 divides x3+4x2−7x+12–kx3+4x2−7x+12–k perfectly (kk being the number to be subtracted), the remainder is 0 when the value of xx is substituted by -3.
i.e., (−3)3+4(−3)2−7(−3)+12−k=0(−3)3+4(−3)2−7(−3)+12−k=0
or −27+36+21+12=k−27+36+21+12=k
or k=k= 42
B
Question: A rectangular paper, when folded into two congruent parts had a perimeter of 34 cm for each part folded along one set of sides and the same is 38 cm when folded along the other set of sides. What is the area of the paper?
A.140 cm2
B.240 cm2
C.560 cm2
D.160 cm2
Answer: A.140 cm2
Explanation: When folded along breadth, we have :
2(l⁄2 + b) = 34 or l + 2b = 34 ....(i)
When folded along length, we have :
2(l + b⁄2) = 38 or 2l + b = 38 ....(ii)
Solving (i) and (ii), we get :
l = 14 and b = 10.
∴ Area of the paper = (14 × 10) cm2 = 140 cm2
Answer A
Question: If tomorrow will be a Sunday, what day was the day before yesterday?
A.Monday
B.Tuesday
C.Wednesday
D.Thursday
Answer: D.Thursday
Explanation: Explanation:
Tomorrow will be a Sunday
=>Today is a Saturday
=> Yesterday was a Friday
=> The day before yesterday was Thursday
Answer: Option D
Question: What approximate value should come in place of the question mark (?) in each of the following equations ?
52.861 + 0.2563 + 8.1 + 57.35 + 0.0087 = ?
A.119
B.116
C.121
D.115
Answer: A.119
Explanation: Explanation :
52.8 + 3 + 8 + 57.4 + 0087 = 118.5 + 0.0087 = 119
Answer : Option A
Question: If 1/4 of the passengers on a ship are from North America, 1/8 are Europeans, 1/12 are from Africa, 1/6 are from Asia and the remaining 36 people are citizens of other continents, then how many passengers are on board the ship?
A.92
B.96
C.100
D.104
Answer: B.96
Explanation: 1/4 + 1/8 + 1/12 + 1/6 = (6+3+2+4)/24 = 15/24
Let x be the number of passengers on the ship.
36 = (9/24)x = 3x/8
x = 96
The answer is B.
Question: A and B can do a piece of work in 12 days and 16 days respectively. Both work for 3 days and then A goes away. Find how long will B take to complete the remaining work?
A.8 days
B.5 days
C.2 days
D.9 days
Answer: D.9 days
Explanation: 3/12 + (3 + x)/16 = 1
x = 9 days
Answer: D
Question: A book is bought for $60 and sold for $63. What is the profit in percentage?
A.3
B.5
C.7
D.9
Answer: B.5
Explanation: 63/60 = 1.05
The answer is B.
Question: In how many ways a hockey team of eleven can be elected from 16 players?
A.4368
B.4267
C.5368
D.4166
Answer: A.4368
Explanation: Solution
The required number of selections
= 3C1 × 4C1 × 2C1 (6C3 + 6C2 + 6C0) = 42 × 4!. Answer A
Question: Iron company has four empty trucks that will head out in the morning, all four to the same destination. The clerk has four different boxes to ship to that same destination. All four boxes could go on any one of the trucks, or the boxes could be split up into any groupings and given to the trucks in any combinations (ie. two to one truck, one to another, and one to another). In how many different ways could the boxes be put on the four trucks?
A. 16
B. 64
C. 256
D. 576
Answer: C. 256
Explanation: MAGOOSHOFFICIAL SOLUTION:
Iron company has four empty trucks that will head out in the morning, all four to the same destination.Where we put one box has absolutely no bearing on where we put any of the other boxes. The placement of the four boxes is completely independent of one another. For each box, we have four choices.
N = 4*4*4*4 = 16*16 = 256
Answer = (C)
Question: In an increasing sequence of 8 consecutive integers, the sum of the first 4 integers is 570. What is the sum of the last 4 integers in the sequence?
A.585
B.580
C.586
D.587
Answer: C.586
Explanation: Solution:
In solving this problem we must first remember that when we have 8 consecutive integers we can display them in terms of just 1 variable. Thus, we have the following:
Integer 1: x
Integer 2: x + 1
Integer 3: x + 2
Integer 4: x + 3
Integer 5: x + 4
Integer 6: x + 5
Integer 7: x + 6
Integer 8: x + 7
We are given that the sum of the first 4 integers is 570. This means that:
x + x+1 + x+2 + x+3 = 570
4x + 6 = 570
4x = 564
x = 141
The sum of the last 4 integers can be expressed and simplified as:
x+4 + x+5 + x+6+ x+7 = 4x + 22
Substituting 141 for x yields:
(4)(141) + 22 = 586
Answer: C
Question: How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 7?
A.4
B.5
C.6
D.7
Answer: C.6
Explanation: 6
Highest two digit number divisible by 7 is 63, so we count down the correct answers from there and see if they are feasible.
63 -yes
56 -yes
49 -no
42 - yes
35 - yes
28 - no
21 - yes
14- yes
Correct answer is C.
Question: Two circles with centres P and Q cut each other at two distinct points A and B. The circles have the same radii and neither P nor Q falls within the intersection of the circles. What is the smallest range that includes all possible values of the angle AQP in degrees?
A.Between 0 and 90
B.Between 0 and 30
C.Between 0 and 60
D.Between 0 and 75
Answer: C.Between 0 and 60
Explanation: Explanation :
It says P&Q falls outside the intersection area of the circle.
The maximum point where P&Q can be in the circle is represented by the 2 small dashes P1 and Q1, when they can be on the circumference of the other circle.
Suppose P & Q are on the circumference of the other circle. (Represented by P1 and Q1)
Then AP1 = r1 (Radius of 1st circle)
AQ1 = r2 (Radius of 2nd circle)
Also P1Q1 = r1 = r2 (As radius of both the circles are same)
So AP1 = AQ1 = P1Q1. Hence ∆AP1Q1 is equilateral, and ∠AQ1P1 = 600.
Suppose P1 and Q1 drift away from the circle, and are at the points P&Q represented in the diagram. Then the value is definitely less than 600.
If P and Q are collinear with A, then the angle is 0(0).
So, the maximum value is 600, and minimum 0(0)
Answer : C
Question: Divide $2000 among B,C in the ratio 4:16. How many $ that C get?
A.$1200
B.$1400
C.$1600
D.$1800
Answer: C.$1600
Explanation: Sum of ratio terms = 4+16 = 20
C = 2000*16/20 = $1600
Answer is C
Question: A container has 3L of pure wine. 1L from the container is taken out and 2L water is added.The process is repeated several times. After 19 such operations, qty of wine in mixture is
A.2/7 L
B.3/7 L
C.6/19L
D.7/23L
Answer: A.2/7 L
Explanation: First operation: 3L-1L=2=6/3L of wine left, total 4L;
#2: 6/3L-(6/3)/4=6/3-6/12=18/12=6/4L of wine left, total 5L;
#3: 6/4L-(6/4)/5=6/4-6/20=24/20=6/5L, total 6L;
#4: 6/5L-(6/5)/6=6/5-6/30=30/30=6/6L, total 7L;
....
At this point it's already possible to see the pattern: x=6/(n+2)
n=19 --> x=6/(19+2)=6/21=2/7L
Answer: A.
Question: If it would take one machine 6 minutes to fill a large production order and another machine 8 minutes to fill the same order, how many minutes would it take both machines working together, at their respective rates, to fill the order?
A.2 1/60
B.3 3/7
C.5 5/11
D.5 1/2
Answer: B.3 3/7
Explanation: Since , Machine 1-M1 take 6 mins to fill the order
The work done by M1 in a min = 1/6
Machine 2- M2 take 8 mins to fill the same order
and work done by M2 in a min = 1/8
Total work done by M1 and M2 in a min = 1/6 + 1/8 = 7/24
Time needed for M1 and M2 to complete the order = 24/7 = 3 3/7
Answer B
Question: Mona and Donald fly to Rome for the weekend. They take cash only in notes of $10 and notes of €10. Mona carries three times the amount of euros Donald carries. She also carries as many dollars as Donald carries. The number of €10 notes they take is double the number of $10 notes they take. If Donald carries a total of 45 notes (of either $10 or €10,) then what is the total number of notes (of either $10 or €10,) they take?
A.70
B.80
C.150
D.120
Answer: C.150
Explanation: .let e10 =x no. d10 =y no. donald is having x+y notes mona carries 3x+y again x =2y or donald x+y =45
or 3y =45 y =15 ;x =30 , total notes they carry = 4x+2y = 120+30 =150
C
Question: A frog can climb up a well at 3 ft per min but due to slipperiness of the well, frog slips down 2 ft before it starts climbing the next minute. If the depth of the well is 57 ft, how much time will the frog take to reach the top?
A.29
B.27
C.55
D.17
Answer: C.55
Explanation: Explanation:
As per given, in 1 min,frog climbs up 3 ft and slips down by 2 ft.
So the frog climbs only 1 ft in 1 min
So after 54 mins,it would have climbed 54ft.
At the end of 55 mins it climbs up 3 ft to make it 57 ft and come out of the well.
Once it had reached the destination,it will not slip.
So the frog will take only 55 minutes to climb up the well.
Answer: C
Question: If xy = 5 and x^2 + y^2 = 20, then x/y + y/x =
A.2 2/5
B.3 1/7
C.5 1/3
D.4
Answer: D.4
Explanation: x/y+y/x=(x^2+y^2)/xy =substitute given we get 20/5=4 answer D
Question: If 20 men can build a wall 66 metres long in 6 days, what length of a similar can be built by 86 men in 8 days?
A.49.5m
B.46 m
C.49 m
D.46.5m
Answer: C.49 m
Explanation: Let the required length be x metres
More men, More length built (Direct Proportion)
Less days, Less length built (Direct Proportion)
Men 20: 35
Days 6: 3 : : 56 : x
Therefore (20 x 6 x x)=(35 x 3 x 56)<=>x=(35 x 3 x 56)/120=49
Hence, the required length is 49 m.
Answer is C.
Question: The sides of a triangle are in the ratio 5: 12: 13 and its perimeter is 300 m, its area is?
A.150
B.882
C.277
D.261
Answer: A.150
Explanation: 5x + 12x + 13x = 300 => x = 10
a = 50, b = 120, c = 130
S = (50 + 120 + 130)/2 = 150
Answer: A
Question: If m : n = 3 : 4 and n : o = 8 : 9, then m : o is :
A.1 :3
B.3 :2
C.2 : 3
D.1 : 2
Answer: C.2 : 3
Explanation: m/n = m/n * n/o
=3/4 * 8/9
= 2/3.
So m : o = 2 : 3
ANSWER:C
Question: The average score of a cricketer for ten matches is 38.9 runs. If the average for first six matches is 42, then average for last four matches is
A.33.25
B.32.25
C.34.25
D.34.5
Answer: C.34.25
Explanation: Explanation:
=(38.9×10)−(42×6)/4
=(1216−750)4=34.25
Answer: Option C
Question: Fresh fruit contains 68% water and dry fruit contains 20% water.How much dry fruit can be obtained from 100 kg of fresh fruits ?
A.30 kg
B.40 kg
C.50 kg
D.60 kg
Answer: C.50 kg
Explanation: The fruit content in both the fresh fruit and dry fruit is the same.
given,fresh fruit has 68% water.so remaining 32%(100-68) is fruit content.weight of fresh fruits is 100kg
dry fruit has 20% water.so remaining 80% is fruit content.let weight if dry fruit be y kg.
fruit % in freshfruit = fruit% in dryfruit
32/100 * 100 = 80/100 * y
we get y = 40 kg
fruit pulp = 40 kg
so with water total amount = 40*100/80 = 50 kg
ANSWER:C
Question: Of the sixteen participants in a certain competition, half are male, and half of the males are younger than 18 years of age. If half of the female competitors are also younger than 18 years of age, into how many distinct groups of 4 competitors could the participants be divided if each group must contain two males under 18 years of age and 2 females over 18 years of age?
A.3
B.4
C.36
D.9
Answer: C.36
Explanation: M under 18 - 4
F above 18 - 4
How many distinct groups can be formed now: 4c2 * 4c2 = 36
Answer : C
Question: Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
A.4
B.7
C.9
D.13
Answer: A.4
Explanation: Solution
Required number
= H.C.F of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F of 48, 92 and 140
= 4.
Answer A
Question: The mean of 50 observations was 36. It was found later that an observation 45 was wrongly taken as 23. The corrected new mean is
A.35.24
B.36.14
C.36.24
D.36.44
Answer: D.36.44
Explanation: Solution
Correct sum = (36x50+45-23)
= 1822.
âˆ´ Correct mean = 1822 / 50
= 36.44.
Answer D
Question: If the product of the integers w, x, y and z is 68, and if 0< w < x < y < z, what is the value of w + z?
A.10
B.5
C.16
D.18
Answer: B.5
Explanation: 24= 1* 2* 3* 4
So w = 1, x = 2, y = 3, z = 4
w + z = 1+ 4= 5
Answer - B
Question: The ratio of the number of boys and girls in a school is 3:2 Out of these 10% the boys and 25% of girls are scholarship holders. % of students who are not scholarship holders.?
A.84%
B.86%
C.88%
D.82%
Answer: A.84%
Explanation: let the boys are 3x and girls are 2x
so,no.of boys not holding scholorship is 3x-(30x/100)=27x/10
and no.of girls not holding scholorship is 2x-(50x/100)=3x/2
the total is (27x/10)+(3x/2)=42x/10
% of students not scholorship holders are (42x/10)*100/5x=84%
ANSWER:A
Question: In the xy-plane, the line y = k is the perpendicular bisector of the line segment PQ and the line x = b is the perpendicular bisector of the line segment RQ. If the coordinates of the point R are (-b, -k), then what are the coordinates of the point P?
A.(-5b, -5k)
B.(-3b, -3k)
C.(2b, 2k)
D.(3b, 3k)
Answer: D.(3b, 3k)
Explanation: firstly the Question tells us that RQ and PQ are perpendicular at Q..
Now the coordinates of the point R are (-b, -k), so R is at a distance of 2b from line x and at dist of 2k from line Y..
as line X bisect RQ .... length of RQ =4b and coord (3b,-k)..
as line Y bisect PQ .... length of PQ =4k and coord (3b,3k).ans D
Question: If x and y are positive numbers and z = xy^2, a 50 percent increase in x and a 10 percent decrease in y would result in which of the following changes in z?
A.decrease of 4.5%
B.decrease of 14.5%
C.increase of 4.5%
D.increase of 21.5%
Answer: D.increase of 21.5%
Explanation: After the changes, z = 1.5x*(0.9y)^2 = (1.5*0.81)xy^2 = 1.215*z
The answer is D.
Question: Can you find the next letter in the series ?
S - T - I - L - N - T - F - Y - ?
A.A
B.B
C.C
D.D
Answer: C.C
Explanation: C
The answer is C.
These are letter of the question asked in reverse order.
Question: A rectangular field has a length 10 meters more than it is width. If the area of the field is 200, what is the length (in meters) of the rectangular field?
A.20
B.22
C.24
D.26
Answer: A.20
Explanation: area = l * w = (L) * (L-10) = 200
trial and error:
19*9 = 171 (too low)
20*10 = 200
The length is 20 meters.
The answer is A.
Question: If c > 1 and d = 2^(c −1), then 4^c =
A.16d^2
B.4d^2
C.d^2
D.d^2/4
Answer: B.4d^2
Explanation: If c > 1 and d = 2^(c −1), then 4^c
Given c>1, so let's assume c=2
d=2^(c-1) = 2^(2-1) = 2, so d=2
hence, 4^c = 4^2 = 16
only 1 ans. choice can satisfy this:
A) 16d^2 --> clearly > 16
B) 4d^2 --> 4*2^2 = 16(we can stop after this as there can be only 1 right answer)
C) d^2 --> clearly < 16
D) d^2/4 --> clearly < 16
E) d^2/16 --> clearly < 16
Ans. B) 4d^2
Question: Mike weighs twice as much as Mary. Mike's weight is 150% of Michelle's weight. Alan weighs 40% of Charlie's weight. Charlie weighs 180% of Mary's weight. Which of these 5 people weighs the highest?
A.Mary
B.Mike
C.Michelle
D.Alan
Answer: B.Mike
Explanation: Mary < Michelle < Mike
Alan < Charlie
Let x be Mary's weight.
Mike's weight is 2x and Charlie's weight is 1.8x.
The answer is B.
Question: One week a certain van rental lot had a total of 20 vans, all of which were on the lot Monday morning. If 50 percent of the vans that were rented out during the week were returned to the lot on or before Saturday morning of that week, and if there were at least 12 trucks on the lot that Saturday morning, what is the greatest number of different vans that could have been rented out during the week?
A. 16
B. 18
C. 20
D. 8
Answer: B. 18
Explanation: A) 16 vans rented means 4 were left and 8 were returned - 12 vans - good
Answer is (B)
Question: Roy is now 8 years older than Julia and half of that amount older than Kelly. If in 4 years, Roy will be twice as old as Julia, then in 4 years what would be Roy’s age multiplied by Kelly’s age?
A.172
B.180
C.192
D.200
Answer: C.192
Explanation: R = J+8 = K+4
R+4 = 2(J+4)
(J+8)+4 = 2J+8
J = 4
R = 12
K = 8
In 4 years (R+4)(K+4) = 16*12 = 192
The answer is C.
Question: how many words formed ACCIDENT without changing relative order of vowels??
A.360
B.370
C.380
D.390
Answer: A.360
Explanation: Vowels: AIE = 1, since order of vowels must not be changed, so 3! should not be multiplied.
Rest: CCDNT = here we have 5 terms, with 1 common term 'C'.
So according to me ans should be :
(5+1)!/2!
= 6!/2!
=360
ANSWER:A
Question: The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 10 cm. If the area of the trapezium is 250cm2 find the lengths of the parallel side
A.27, 23
B.25, 25
C.24, 26
D.23, 29
Answer: A.27, 23
Explanation: Explanation:
Let the two parallel sides of the trapezium be a cm and b cm.
Then, a-b = 4 ------ (1)
And, (1/2) x (a+b) x 10 = 475 =>(a+b) =((250 x 2)/10) => a + b = 50------- (2)
Solving 1 and 2, we get: a=27,b=23
So, the two parallel sides are 27 cm and 23 cm.
Answer: Option A
Question: A pump can fill a tank with water in 10 hours. Because of a leak, it took 20 hours to fill the tank. The leak can drain all the water in ?
A.20hr
B.10hr
C.30hr
D.14hr
Answer: A.20hr
Explanation: Work done by the leak in 1 hour = 1/10 - 1/20 = 1/20
Leak will empty the tank in 20 hours
Answer is A
Question: A and B have the same number of marbles when they start playing. After some time A gains 20 marbles and later he loses 2/3rds of what he had. Now B has 4 times as many marbles as A has. What are the initial number of marbles that each of them had?
A.80
B.90
C.100
D.110
Answer: C.100
Explanation: 100
ANSWER:C
Question: The pilot of a small aircraft with a 40-gallon fuel tank wants to fly to Cleveland, which is 480 miles away. The pilot recognizes that the current engine, which can fly only 6 miles per gallon, will not get him there. By how many miles per gallon must the aircraft’s fuel efficiency be improved to make the flight to Cleveland possible?
A.2
B.4
C.12
D.6
Answer: D.6
Explanation: Actual miles/gallon is = 480/40 = 12 miles/gallon.
Current engine miles/gallon is 6 miles/gallon.
Additional 6 miles/gallon is required to match the actual mileage.
IMO option D.
Question: How many positive integers G less than 10,000 are such that the product of their digits is 210?
A.24
B.30
C.48
D.54
Answer: D.54
Explanation: 210 is the answer when 2, 3, 5 and 7 are multiplied. 210 can also be arrive using 5,6 and 7 and 1, 5, 6 and 7.
So sum of arrangements of 2357, 567 and 1567. This translates to 4! +3! + 4!, this equals to 24 + 6 + 24 = 54, D is the answer.
Question: A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that atleast one bulb is good.
A.125/129
B.125/121
C.125/126
D.125/122
Answer: C.125/126
Explanation: Explanation:
Required probability = 1 - 1/126 = 125/126
Answer: C
Question: Find the value of x. (47% of 1442 - 36% of 1412) + 60 = x?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: A) 1
Question: Julie has $2000 saved in her bank account after this summer. She made money babysitting and delivering newspapers which she added to her previous savings. Julie babysat for 30 hours at $10/hr, she delivered papers for 40 hours at $7/hr. What % of her bank account was savings she had before this summer?
A.41 %
B.51 %
C.61 %
D.71 %
Answer: D.71 %
Explanation: Total amount in the bank account minus new earnings = 2000 - (10 x 30 + 7 x 40)
= 2000 - (580)
= 1420
Now, we need to calculate 1420 is what percent of 2000.
=> 1420/2000 * 100 = 71 %
D
Question: Rakesh's Mathematics test had 75 problems, 10 arithmetic, 30 algebra, 35 geometry problems. Although he answered 70% of arithmetic, 40% of arithmetic and 60% of geometry problems correctly, still he got less than 60% problems right. How many more questions he would have to answer more to get passed ?
A.5
B.6
C.7
D.8
Answer: A.5
Explanation: Explanation :
Number of questions attempted correctly = (70% of 10 + 40% of 30 + 60% of 35)
= 7 + 12 + 21 = 40.
Questions to be answered correctly for 60% = 60% of total quotations
= 60 % of 75 = 45.
He would have to answer 45 - 40 = 5
Answer : A
Question: The ratio E, by volume of soap to alcohol to water in a 76 litre solution is 2: 50: 100 . The solution is then altered by adding more soap, alcohol and water.After this alteration the ratio, by volume of soap to water in the solution doubles whereas the ratio, by volume of soap to water remains the same as before. What COULD BE the resulting volume.
A.79 litres
B.78 litres
C.77 litres
D.152 liters
Answer: C.77 litres
Explanation: I guess it should be
the ratio E, by volume ofsoaptowaterin the solutiondoubleswhereas the ratio, by volume ofalocoholtowaterremains thesameas before
2:50: 100 => 1 : 25 : 50. If we add all the parts, we get 76 liters
So we have 1 liters of Soap, 25 liters of Alcohol and 50 liters of Water.
Now as per the Question, Soap : Water doubles but alcohol to water remains the same.
So Soap becomes 2 liters, Alcohol remains 25 liters and Water remains at 50 liters.
Hence 77 liters - Option C)
Question: A loan has a variable interest rate that fluctuates between 6% and 8% of the base payment per month. If base payments remain at $400 each month and an additional monthly surcharge of 2% is added to the combined (base + interest), what would be the greatest possible payment due in any given month?
A.$435.32
B.$436.48
C.$438.16
D.$440.64
Answer: D.$440.64
Explanation: The maximum interest in one month is 8%*$400=$32.
The combined payment (base plus interest) is $400 + $32 = $432.
The greatest possible payment is: 1.02*$432=$440.64.
The answer is D.
Question: Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 54 sec. The length of each train is?
A.50
B.26
C.75
D.28
Answer: C.75
Explanation: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 - 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/54 = 25/9 => x = 75.
Answer: C
Question: John was thrice as old as Tom 6 yrs back. He will be 5/3 times as old as Tom 6 years hence. How old is Tom today?
A.8
B.10
C.12
D.14
Answer: C.12
Explanation: Sol. RMBflSk -6 = 3 (Ravi - 6) ...(j)
and Rupesh + 6 = | (Ravi + 6) ...(ii)
Solving both the equations we get,
Ravi = 12 years.
C
Question: Which one of the following is not a prime number?
A.21
B.34
C.67
D.91
Answer: D.91
Explanation: D
91 is divisible by 7. So, it is not a prime number.
Question: A honey bee flies for 10 seconds, from a daisy to a rose. It immediately continues to a poppy, flying for 6 additional seconds. The distance the bee passed, flying from the daisy to the rose is 6 meters longer than the distance it passed flying from the rose to the poppy. The bee flies to the poppy at 3 meters per second faster than her speed flying to the rose. The bee flies how many meters per second from the daisy to the rose?
A.3
B.5
C.6
D.8
Answer: A.3
Explanation: Let the speed be 's' and let the distance between rose and poppy be 'x'
The problem boils down to:
Rose to Poppy: s+3=x/6 ------- 1
Daisy to Rose: s=(x+6)/10------ 2
so from 1 we can re write x as x=6s+18
substitute the value of x in 2 gives us s=3 m/s
A
Question: There are 4 copies of 5 different pens. In how many ways can they be arranged on a shelf?
A.20!/4!
B.20!/5(4!)
C.20!/(4!)^5
D.20!
Answer: C.20!/(4!)^5
Explanation: There are 4 copies of 5 different pens.20!/((4!)^5)
Answer - C