RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Cost of 2 bats and 3 balls is Rs.1300. The cost of 3 bats and 2 balls is Rs.1200. The cost of each balls is more than that of each bat by?
A.50
B.100
C.110
D.120
Answer: B.100
Explanation: 2Bats + 3Ball = 1300 --- (1)
3Bats + 3Ball = 1200 --- (2)
Subtracting 2nd from 1st, we get
-Bats + Ball = 100 => Ball - Bats = 100
B
Question: If 11 and 13 are prime numbers, which of the following CANNOT be the sum of a and b?
A.24
B.48
C.72
D.47
Answer: D.47
Explanation: ans =D
Question: A and B started a partnership business investing some amount in the ratio of 3 : 5. C joined then after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A, B and C?
A.3 : 5 : 2
B.3 : 5 : 5
C.6 : 10 : 5
D.8 : 12 : 4
Answer: C.6 : 10 : 5
Explanation: Explanation:
Let the initial investments of A and B be 3x and 5x.
A : B : C = (3x x 12) : (5x x 12) : (5x x 6) = 36 : 60 : 30 = 6 : 10 : 5.
Answer is C
Question: A shop keeper had some books. He sells 40% books and still has 420 books. Originally, he had
A.588 books
B.600 books
C.620 books
D.700 books
Answer: D.700 books
Explanation: Explanation :
Suppose originally he had x books.
Then,(100-40)% of x = 420.
=>60/100x = 420
=>x = (420 100 / 60
=>x=700.
Answer : D
Question: There were totally 100 men.81 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married?
A.11
B.12
C.13
D.14
Answer: A.11
Explanation: 100-(100-81)-(100-75)-(100-85)-(100-70)= 100-19-25-15-30=100-89=11
ANSWER:A
Question: A = {2, 3, 5, 7, 11}
B = {2, 4, 6, 17}
Two integers will be randomly selected from sets A and B, one integer from set A and one from set B, and then multiplied together. How many different products can be obtained?
A.15
B.16
C.19
D.20
Answer: D.20
Explanation: Step 1: Find out the number of products you get.
5 distinct numbers in set A and 4 distinct in set B so number of products = 5*4 = 20
Step 2: Remove the products that appear more than once.
Notice that 5, 7, 11 and 13 are primes and none of their multiples are in either set. So ignore them. We just need to focus on 2 and 3 of set A and 2, 4 and 6 of set B.
2, 3
2, 4, 6
The only product repeated when you take a number from each set is 12. (3*4 and 2*6) Rest all are distinct.
Answer = 20 - 1 = 20
Note here that the second step will involve manual calculation since it will depend on the specific numbers you have in the two sets.
D
Question: A 270m long train running at the speed of 120kmph crosses another train running in opposite direction at the speed of 80kmph in 9 second. What is the length of the other train?
A.150m
B.230m
C.290m
D.310m
Answer: B.230m
Explanation: Relative speed = 120+80 = 200*5/18 = 500/9 m/s
Let the length of the other train be x meters
x+270/9 = 500/9
x = 230m
Answer is B
Question: A sum of 15,600 amounts to 21,200 in 5 years at the rate of simple interest. What is the rate of interest?
A.2%
B.1%
C.7%
D.5%
Answer: C.7%
Explanation: C
7%
S.I. = (21200 - 15600) = 5600.
Rate = (100 x 5600)/(15600x5)% = 7%
Question: 10 books are placed at random in a shelf. The probability that a pair of books will always be together is
A.1/9
B.1/7
C.1/5
D.1/6
Answer: C.1/5
Explanation: 10 books can be rearranged in 10! ways consider the two books taken as a pair then number of favourable ways of getting these two books together is 9! 2!
Required probability = 1/5
Answer: C
Question: (540 + ?) × 3/5 - 120 = 483
A.A)465
B.B)450
C.C)540
D.D)20
Answer: A.A)465
Explanation: Explanation:
=> (540 + ?) × 3/5 - 120 = 483
=> (540 + ?) × 3/5 = 483 + 120
=> (540 + ?) × 3/5 = 603
=> ? = 603 × 5/3 - 540 = 1005 - 540 = 465
Answer: Option A
Question: Lilly has 10 fish and Rosy has 14 fish. In total, how many fish do they have in all?
A.21
B.22
C.23
D.24
Answer: D.24
Explanation: 10+14=24
The answer is D.
Question: What quantity of water should be added to reduce 20 liters of 80% acidic liquid to 20% acidic liquid?
A.30liters
B.50liters
C.60liters
D.70liters
Answer: C.60liters
Explanation: Acid in 20 liters = 80% of 20 = 16 liters
Suppose x liters of water be added.
Then 16 liters of acid in 20+x liters of diluted solution
20% of 20+x = 16
20+x = 80
x = 60liters
Answer is C
Question: Ashis's height is 25% more than Babji, by how much percent Babji's height is less than Ashis.
A.30%
B.25%
C.75%
D.20%
Answer: D.20%
Explanation: Explanation :
Solution: Babji is less than Ashis by (25/(100+25) * 100)% = 20%
Answer : D
Question: A bullet train 140 m long is running at 60 kmph. In how much time will it pass a platform 210 m long?
A.34 Seconds
B.22 Seconds
C.21 Seconds
D.24 Seconds
Answer: C.21 Seconds
Explanation: Distance travelled = 140 + 210m = 350m
Speed = 60 * 5/8 = 50/3m
Time = 350 * 3/50 = 21 Seconds
ANSWER C
Question: Incomes of two companies A and B are in the ratio of 5 : 8. Had the income of company A been more by 35 lakh, the ratio of their incomes would have been 5 : 4. What is the income of company B?
A.80 lakh
B.56 lakh
C.40 lakh
D.60 lakh
Answer: B.56 lakh
Explanation: Let the incomes of two companies A and B be 5x and 8x respectively.
From the question,
5x+35/8x=5/4 ⇒ 20x + 140 = 40x
∴ x = 7
∴ Income of company B = 8x = 56 lakh
Answer B
Question: Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
A.Rs.250
B.Rs.300
C.Rs.320
D.Rs.340
Answer: A.Rs.250
Explanation: Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
A
Question: If N is the least positive integer that is divisible by every integer from 3 to 10 inclusive, then N/7 is =
A. 360
B. 720
C. 2520
D. 3960
Answer: A. 360
Explanation: The integer should be divisible by: 3, 4, 5, 6, 7, 8, 9 and 10, that is 3, 2^2, 5, 2*3, 7, 2^3, 3^2, 2*5. The least common multiple of these integers is the product of 7, 5, 3^2 and 2^3. Then, N/7 is (7 * 5 * 3^2 * 2^3)/7 = 5*9*8 = 360.
Answer: A.
Question: If A got 70 marks and B got 60 marks, then what percent of A's mark is B's mark?
A.A)60%
B.B)85.7%
C.C)65%
D.D)75%
Answer: B.B)85.7%
Explanation: A's marks = 70 ; B's marks = 60.
Let x% of A = B => x/100 *70 = 60
=> x = (60 * 100)/80 = 85.7
B's marks is 85.7% of A's marks.
ANSWER:B
Question: How many seconds will a 500 meter long train moving with a speed of 63 km/hr, take to cross a man walking with a speed of 3 km/hr in the direction of the train ?
A.42
B.50
C.30
D.28
Answer: C.30
Explanation: Explanation:
Distance = 500m
Speed = 63 -3 km/hr = 60 km/hr = 600/36 m/s = 50/3 m/s
Time taken = distance/speed = 500/(50/3) = 30 s
Answer: Option C
Question: Kid have 8 black balls and 8 white balls. He is trying to arrange a ball in a row then in how many ways can he arrange these balls in a row so that balls of different colors alternate?
A.3×(4!)^2
B.1×(9!)^3
C.2×(8!)^2
D.2×(8!)
Answer: C.2×(8!)^2
Explanation: 8 black balls can be arranged in 8! ways ...(A)
Now we need to arrange white balls such that white balls and black balls are positioned alternatively. i.e., we can arrange 8 white balls either in the 8 positions marked as A,B,C,D,E,F,G,H or in the 8 positions marked as B,C,D,E,F,G,H,I as shown below.
8 white balls can be arranged in the 8 positions marked as A,B,C,D,E,F,G,H in 8! ways.
8 white balls can be arranged in the 8 positions marked as B,C,D,E,F,G,H,I in 8! ways.
8 white balls can be arranged in the 8 positions marked as A,B,C,D,E,F,G,H or in the 8 positions marked as B,C,D,E,F,G,H,I in 8!+8!=2×8! ways ...(B)
From (A) and (B),
required number of ways =8!×2×8!=2×(8!)^2
C
Question: If √x = x, then which of the following must be true?
A.x is positive
B.x=1
C.x^2>x
D.x is non-negative
Answer: D.x is non-negative
Explanation: Square both the sides we get
x = x^2
x^2 - x= 0
x(x-1)=0
either x=0 or x=1
So, answer will be D
Question: Andrew started saving at the beginning of the year and had saved $240 by the end of the year. He continued to save and by the end of 2 years had saved a total of $600. Which of the following is closest to the percent increase in the amount Andrew saved during the second year compared to the amount he saved during the first year?
A.11%
B.25%
C.44%
D.50%
Answer: D.50%
Explanation: Percent increase in the amount Andrew saved during the second year compared to the amount he saved during the first year.
Percentage Change = ( Change in value / Original value ) * 100
Percentage Change = [ (Saving in 2nd year - Saving in 1st year ) / Saving in 1st year ] * 100
Saving in 2nd year + Saving in 1st year = 600
Saving in 2nd year + 240 = 600
Saving in 2nd year = 600 - 240 = 360
Change in Value = 360 - 240 = 120
Original Value = 240
Percentage Increase = (120 / 240 ) * 100
= (1/2 ) * 100 = 50 % ..... Answer D......
Question: The total age of A and B is 12 years more than the total age of B and C. C is how many year younger than A
A.11
B.12
C.13
D.14
Answer: B.12
Explanation: Explanation:
Given that A+B = 12 + B + C
=> A – C = 12 + B – B = 12
=> C is younger than A by 12 years
Answer: Option B
Question: In an effort to plan out expenses, the Roberts family is representing its annual budget as a circle graph. Each sector of the graph is proportional to the amount of the budget it represents. If “clothes and shoes” takes up 54° of the chart, how much of the Roberts’s $20,000 annual budget is dedicated to clothes and shoes?
A.$1,500
B.$3,000
C.$4,500
D.$5,000
Answer: B.$3,000
Explanation: Given for clothes and shoes” takes up 54° of the circular chart.
Then clothes and shoes = 54/360 * 20000.
=> 3000.
Answer:option B is correct answer...
Question: In an automobile market of spare parts dealers and workshops, average earning of a spare parts dealer per day is $520 and the average earning of a workshop is $700. Considering there are 40 shops in market and number of spare parts dealer shops exceeds the workshops by 4. What is the average earning of this market consisting of only spare parts dealers and workshops.
A.535
B.562
C.594
D.601
Answer: D.601
Explanation: Let the number of workshops be x
number of s.p.d=x+4
x+x+4=40 = 2x=36 = x=18
workshops are 18 in number and spd are 22 in number
Average earning of the market= ((520x22)+(700x18))/40
=(11440+12600)/40
=24040/40
=601
Answer: D
Question: If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same sum at the rate and for the same time?
A.51.25
B.51.29
C.51.22
D.51.38
Answer: A.51.25
Explanation: Sum = (50 * 100) / (2 * 5) = Rs. 500
Amount = [500 * (1 + 5/100)2] = Rs. 551.25
C.I. = (551.25 - 500)
= Rs.51.25.
Answer: a
Question: Each cell of a certain kind of bacteria produces two more cells. The life span of each cell is 10 minutes and each cell multiples only once in its life time, when it is exactly one minute old. If a new cell is placed in an empty box at time t = 0, then how many live cells will be there in the box just after t = 20 minutes?
A.2048 × 1023
B.1024 × 1023 cells
C.(1024)²
D.1023 × 1025
Answer: B.1024 × 1023 cells
Explanation: see total cells created after
1min be 2^1
2min be 2^2
3 min be 2^3.......
thus after 20 min 2^20 will be created
now after 10 min 1 cell will die (2^0)
after 11 min 2 cells die (2^1)
similarly after 20 min 2^10 cells die
thus total cells remained=(2^20)-(1024)
or (1024)^2-1024
or1024*(1024-1)
i.e, 1024*1023
ANSWER:B
Question: A certain automobile company’s best-selling model is the Speedster. The Speedster, like all of their other models, comes in coupe and convertible styles. 2/3 of the current inventory is Speedsters, of which 4/5 are convertibles. If there are 60 vehicles that are not Speedsters, how many Speedster convertibles are there?
A.36
B.96
C.100
D.76
Answer: B.96
Explanation: Total Vehicle = 2/3 of speedster + 1/3 of others.
Speedster convertibles = 2/3 total vehicle * 4 /5
Given : 1/3 constitutes 60 Vehicles. hence 2/3 constitutes 120
Speedster convertibls = 120 * 4/5 = 96
B
Question: The difference between the place values of two sevens in the numeral 69758472 is
A.0
B.100
C.6993
D.699930
Answer: D.699930
Explanation: Required difference = (700000 - 70) = 699930
Answer: Option D
Question: Average expenditure of a person for the first 3 days of a week is Rs. 310 and for the next 4 days is Rs. 420. Average expenditure of the man for the whole week is:
A.350
B.370
C.390
D.430
Answer: A.350
Explanation: Explanation:
Assumed mean = Rs. 310
Total excess than assumed mean = 4 × (Rs. 420 - Rs. 350) = Rs. 280
Therefore, Increase in average expenditure = Rs. 280/7 = Rs. 40
Therefore, Average expenditure for 7 days = Rs. 310 + Rs. 40 = Rs. 350
Correct Option: A
Question: Tom planted vegetables in a rectangular garden that was 25 feet long and 15 feet wide. He used
1/3 of the area for corn and 1/5 of it for peas. How many square feet are left for other vegetables?
A.175 sq. ft.
B.176 sq. ft.
C.177 sq. ft.
D.178 sq. ft.
Answer: A.175 sq. ft.
Explanation: area of garden is 25 x 15 = 375 sq. ft.
1/3 x 375 = 125 sq. ft. for corn
1/5 x 375 = 75 sq. ft. for peas
125 + 75 = 200 sq. ft. used
375 - 200 = 175 sq. ft. left over
correct answer A
Question: If a certain coin is flipped, the probability that the coin will land heads is 1/2. If the coin is flipped 5 times, what is the probability that it will land heads up on the first flip but not on the last 4 flips?
A.1/4
B.1/8
C.1/16
D.1/32
Answer: D.1/32
Explanation: P(HTTTT) = 1/2*1/2*1/2*1/2*1/2 = 1/32
The answer is D.
Question: Aman started a business investing Rs. 70,000. Rakhi joined him after six months with an amount of Rs. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business ?
A.12 : 15 :19
B.12 : 15 :29
C.12 : 15 :11
D.12 : 15 :16
Answer: D.12 : 15 :16
Explanation: Aman : Rakhi : Sagar = (70000 x 36) : (105000 x 30) : (140000 x 24)
= 12 : 15 : 16.
Answer: D
Question: Bank account A contains exactly x dollars, an amount that will decrease by 10% each month for the next two months. Bank account B contains exactly y dollars, an amount that will increase by 20% each month for the next two months. If A and B contain the same amount at the end of two months, what is the ratio of x√x to y√y?
A.4 : 3
B.3 : 2
C.16 : 9
D.2 : 1
Answer: A.4 : 3
Explanation: Explanation:
Account A has amount after 2 months = 0.9*0.9*x = 0.81*x
Account B has amount after 2 months = 1.2*1.2*y = 1.44*y
0.81*x=1.44*y --> √(x/y)=√(1.44/0.81) = 12/9 = 4/3.
Ans A
Question: What is the units digit of 18! + 1 ?
A.1
B.3
C.5
D.7
Answer: A.1
Explanation: Any number above 4!, such as 5!, 6!, etc... are always multiples of 10, so their units digit is 0.
The units digit of 18! + 1 is 1.
The answer is A.
Question: A 14 meter long wire is cut into two pieces. If the longer piece is then used to form a perimeter of a square, what is the probability that the area of the square will be more than 4 if the original wire was cut at an arbitrary point?
A.5/14
B.3/14
C.8/21
D.6/7
Answer: D.6/7
Explanation: A square with an area of 4 has a perimeter of 8.
For the area to be >4, the longer piece must be >8.
The wire must be cut within 6 meters from either end.
The probability of this is 12/14 = 6/7.
The answer is D.
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.50 km and 1.25 km respectively. The time taken by the slower train to cross the faster train in seconds is?
A.12
B.77
C.66
D.99
Answer: C.66
Explanation: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.50 + 1.25 = 2.75 km = 2750 m.
Required time = 2750 * 3/125 = 66 sec.
Answer: C
Question: What is the speed required for a bike to cover a distance of 720 km in 12 hours?
A.50 kmh
B.40 kmh
C.100 kmh
D.60 kmh
Answer: D.60 kmh
Explanation: Speed= Distance / Time
Speed = 720 / 12 = 60
Answer: D
Question: If a positive integer n is divisible by both 2 and 5, then n must also be divisible by which of the following?
I. 10
II. 7
III. 40
A.None
B.I only
C.II only
D.I and II
Answer: B.I only
Explanation: A multiple of 2 and 5 is also a multiple of 10, but not necessarily a multiple of 7 or 40.
The answer is B.
Question: The list price of an article is Rs.70. A customer pays Rs.61.11 for it. He was given two successive discounts, one of them being 10%. The other discount is?
A.8%
B.7%
C.10%
D.3%
Answer: D.3%
Explanation: Explanation:
70*(90/100)*((100-x)/100) = 61.11
x = 3%
D
Question: Which of the following triples of numbers have the same standard deviation as the numbers p, q, and r?
I. p-2, q-2, r-2
II. 0, p-q, r-q
III. p-4, q+5, r-1
A.I only
B.II only
C.I and III only
D.II and I only
Answer: D.II and I only
Explanation: If we add or subtract a constant to each term in a set the standard deviation will not change.
Set {p-2, q-2, r-2} is obtained by subtracting 2 from each term of {p, q, r}
Set {0, p-q, r-q} is obtained by subtracting s from each term of {p, q, r}
Set {p-4, q+5, r-1} is totally different from {p, q, r}.
Thus the answer is I and II only.
Answer:D.
Question: 5.40 can be expressed in terms of percentage as
A.5.04%
B.50.4%
C.209%
D.540%
Answer: D.540%
Explanation: Explanation:
While calculation in terms of percentage we need to multiply by 100, so
5.40 * 100 = 540
Answer: Option D
Question: What is the rate percent when the simple interest on Rs.780 amount to Rs.130 in 4 Years?
A.4.16
B.5.16
C.6.16
D.7.16
Answer: A.4.16
Explanation: 130 = (780*4*R)/100
R = 4.16%
Answer: A
Question: Find the fourth proportion to 2,3,6
A.18
B.12
C.9
D.3
Answer: C.9
Explanation: Explanation:
2:3 :: 6:x
=> 2/3 = 6/x
=> x = 18/2
=> x = 9
Option C
Question: Sekar started a business investing Rs.25,000 in 1999. In 2000, he invested an additional amount of Rs.10,000 and Rajeev joined him with an amount of Rs.35,000. In 2001, Sekar invested another additional amount of Rs.10,000 and Jatin joined them with an amount of Rs.35,000. What will be Rajeev's share in the profit of Rs.2,10,000 earned at the end of 3 years from the start of the business in 1999?
A.Rs.45,000
B.Rs.50,000
C.Rs.70,000
D.Rs.75,000
Answer: C.Rs.70,000
Explanation: Solution
Sekar:Rajeev:Jatin=	(25000×12+35000×12+45000×12):(35000×24) : (35000×12)
= 1260000 : 840000 : 420000
= 3 : 2 : 1.
Rajeev's share	=Rs.(210000×2/6)
= Rs.70000.
Answer C
Question: If 15 machine can finish a job in 36 days, then how many more machines would be needed to finish the job in one -fourth less time?
A.a. 5
B.b. 8
C.c. 10
D.d. 12
Answer: A.a. 5
Explanation: You might think of this in a management context - we can use the principle of 'person-hours' to solve any problem where we have identical workers. So, using simpler numbers, suppose you know that 6 identical employees, working simultaneously, would finish a job in 5 hours. Then that job requires 6*5 = 30 total hours of person-work. If instead you wanted the job done in 3 hours, you'd assign 30/3 = 10 employees to do the job, because you want to get a total of 30 hours of work from the employees.
We can solve this problem identically. If 15 machines (identical ones, I assume) work simultaneously for 36 days, they will do a total of 15*36 machine-days of work. So the job requires 15*36 days of machine work in total. We instead want the job done in 1/4 less time, so in 27 days. So we'll need 15*36/27 = 20 machines, or 5 additional machines.
A
Question: A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 200 kilometers?
A.4.5
B.5
C.6.5
D.7.5
Answer: B.5
Explanation: Each 40 kilometers, 1 gallon is needed. We need to know how many 40 kilometers are there in 180 kilometers?
200 ÷ 40 = 5 × 1 gallon = 5 gallons
correct answer B
Question: A series of number is given: 5, 6, 12, 5, 7, 13, 5,__14, 5, 9, 15.. What number fills the blank?
A.6
B.5
C.9
D.8
Answer: D.8
Explanation: Looking at the series we can see 1 is added to 6, then to 7, then to 8 and so on...
The answer is option D (8)
Question: A, B and C start a business each investing 2,000. After 6 months A withdrew 1000, B withdrew 1000 and C invests 1000 more. At the end of the year, a total profit of 6600 was recorded. Find the share of B.
A.20,000
B.21,200
C.1,800
D.20,500
Answer: C.1,800
Explanation: Ratio of the capitals of A, B and C
= 2000 Ã— 6 + 1000 Ã— 6 : 2000 Ã— 6 + 1000 Ã— 6 : 2000 Ã— 6 + 3000 Ã— 6
= 18000 : 18000 : 30000 = 18 : 18 : 30
Bâ€™s share = (6600 Ã— 18â„66) = 1800
Answer C
Question: A worker is paid x rupees for painting every 5 metres of a wall and y rupees for painting every extra metre. During one week, he painted 5 metres on Monday, 6 metres on Tuesday, 7 metres on Wednesday, 8 metres on Thursday and 9 metres on Friday. What is his average daily earning rupees for the five day week?
A.x + 2y
B.(5x + 9y)/5
C.10x + (8/5)y
D.None of these
Answer: A.x + 2y
Explanation: Explanation :
On Monday, the payment = Rs x
On Tuesday, the payment = Rs (x + y)
On Wednesday, the payment = Rs (x + 2y)
On Thursday, the payment = Rs (x + 3y)
On Friday, the payment = Rs (x + 4y)
Average daily earning during the five-day week = (5x + 10y)/5
= x + 2y
Answer : A
Question: If x is a positive, single-digit integer such that 2/3*x, 2x, x, and x + 2, and 3x – 2 form a non-ordered list of consecutive integers, which of the following could be the median of that list?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: The big hints are thatx is a 1-digit integerAND (2/3)x, 2x, x, and x + 2, and 3x – 2 are ALLintegers
For (2/3)x to be an integer, x MUST BE A MULTIPLE OF 3. So, x can equal 3, 6, or 9.
Now let's plug each possible value of x into the terms and see which one yields a list ofconsecutive integers
When x =3, we get the following terms: (2/3)(3), 2(3),3,3+ 2, and 3(3) – 2.
When we evaluate these terms we get: 4, 6, 3, 5 and 7
Rearrange to get: 2, 4, 5, 6, 7. So, when x = 3, we getconsecutive integers.
In this case, the MEDIAN = 5
Since 5 is among the answer choices, we need not test the other 2 values of x (i.e., x = 6 and x = 9)
Answer:
C
Question: The average age of father and his two sons is 38 Years. Five years ago, the average age of the two sons was 16 Years. If the difference between the ages of the two sons is four years, what is the present age of the father?
A.45
B.46
C.72
D.48
Answer: C.72
Explanation: The total present age of father and two sons is 3x38 = 114 yrs
The total present age of sons is (16+5) X 2 = 42Years
so, present age of father is 114 â€“ 42 = 72 yrs
Answer C
Question: Sushil got thrice as many marks in English as in Science. His total marks in English, Science and Maths are 162. If the ratio of his marks in English and Maths is 3:5, find his marks in Science?
A.18
B.77
C.66
D.55
Answer: A.18
Explanation: S:E = 1:3
E:M = 3:5
------------
S:E:M = 3:9:15
3/27 * 162 = 18
Answer:A
Question: Three persons A, B and C divide a certain amount of money such that A's share is Rs.4 less than half of the total amount. B's share is Rs.8 more than half of what is left and finally C takes the which is Rs.14. Find the total amount they initially had with them?
A.Rs.68
B.Rs.85
C.Rs.80
D.Rs.56
Answer: C.Rs.80
Explanation: Let the total amount be Rs.P
Let shares of A and B be Rs.X and Rs.Y respectively.
Given, C's share was Rs.14.
X + Y + 14 = P --- (1)
From the given data, X = P/2 - 4 --- (2)
Remaining amount = P - (P/2 - 4) = P/2 + 4
Y = 1/2(P/2 + 4) + 8
=> P/4 + 10 --- (3)
From (1), (2) and (3)
P/2 - 4 + P/4 + 10 + 14 = P
=> 3P/4 + 20 = P
=> P - 3P/4 = 20
=> P/4 = 20 => P = Rs.80
Answer: C
Question: 40 is subtracted from 60% of a number, the result is 50. Find the number?
A.150
B.388
C.278
D.277
Answer: A.150
Explanation: (60/100) * X – 40 = 50
6X = 900
X = 150
Answer: A
Question: In what ratio must rice of Rs.32per kg be mixed with rice of Rs.42 per kg so that cost of mixture is Rs.20 per kg?
A.13:6
B.13:5
C.11:6
D.11:5
Answer: C.11:6
Explanation: (20-42)/(32-20)=22/12=11:6
ANSWER:C