RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Mary decided to save a certain amount of her monthly salary each month and her salary was unchanged from month to month. If Mary's savings by the end of the year from these monthly savings were SIX times the amount she spent per month, what should be the fraction of her salary that she spent each month?
A.1/2
B.3/4
C.1/3
D.2/3
Answer: D.2/3
Explanation: Saving = S, Expenditure = E, Income = I
At the end of 12months; 12S=6E=6(I-S)
=> 18S = 6I => Savings = 1/3 I
Hence Expenditure = 1-(1/3) = 2/3
Answer (D)
Question: A can do a work in 16 days and B can do it in 8 days. In how many days A and B can do the work?
A.20 days
B.5 1/3 days
C.6 days
D.8 days
Answer: B.5 1/3 days
Explanation: Explanation:
A's 1day's work = 1/16
B's 1day's work = 1/8
They work together = 1/16 + 1/8 = 3/16 = 16/3 = 5 1/3days
Answer: Option B
Question: Nine persons went to a hotel for taking their meals 8 of them spent Rs.12 each on their meals and the ninth spent Rs.8 more than the average expenditure of all the nine.What was the total money spent by them?
A.Rs.118
B.Rs.117
C.Rs.116
D.Rs.115
Answer: B.Rs.117
Explanation: Let the average expenditure of all nine be Rs.x
Then 12*8+(x+8)=9x or 8x=104 or x=13.
Total money spent = 9x=Rs.(9*13)=Rs.117.
Option B
Question: Reeya obtained 55, 67, 76, 82 and 55 out of 100 in different subjects, What will be the average
A.70
B.75
C.67
D.85
Answer: C.67
Explanation: Explanation:
(55+67+76+82+55 / 5)=67
Option C
Question: A can do a piece of work in 15 days and B in 20 days. They began the work together but 5 days before the completion of the work, A leaves. The work was completed in?
A.11 3/5
B.11 3/0
C.11 3/3
D.11 3/7
Answer: D.11 3/7
Explanation: (x – 5)/15 + x/20 = 1
x = 11 3/7 days
Answer: D
Question: Cara took out a charge account at the General Store and agreed to pay 5% simple annual interest. If she charges $54 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments?
A.$55.70
B.$56.20
C.$56.70
D.$57.20
Answer: C.$56.70
Explanation: 1.05*$54=$56.70
The answer is C.
Question: A Martian bat flies at 60 yards per second from its nest to a dry lake. When it arrives there, it immediately continues at 45 yards per second to a nearby cave. If the distance between the lake and the cave is half the distance between the nest and the lake, what is the average speed, in yards per second, of the bat during the whole flight?
A.36
B.40
C.42
D.54
Answer: D.54
Explanation: Distance from nest to lake = d, Speed = 60, Time = d/60
Distance from lake to cave = d/2, Speed = 45, Time = d/90
Average speed = (d + d/2)/(d/60 + d/90) = (3/2)/(1/36) = 54
Answer: D
Question: 12.1212 + 17.0005 – 9.1102 = ?
A.200.01
B.20.011
C.20.0115.
D.20.1
Answer: C.20.0115.
Explanation: Solution
Given expression = (12.1212 + 17.0005) - 9.1102 = (29.1217 - 9.1102) = 20.0115. Answer C
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?
A.22 sec
B.27 sec
C.12 sec
D.19 sec
Answer: C.12 sec
Explanation: D = 250 m + 250 m = 500 m
RS = 80 + 70 = 150 * 5/18 = 125/3
T = 500 * 3/125 = 12 sec
Answer: C
Question: In a particular state, 60% of the counties received some rain on Monday, and 65% of the counties received some rain on Tuesday. No rain fell either day in 25% of the counties in the state. What percent of the counties received some rain on Monday and Tuesday?
A.12.5%
B.40%
C.50%
D.60%
Answer: C.50%
Explanation: 60 + 65 + 25 = 150%
The number is 50% above 100% because 50% of the counties were counted twice.
The answer is C.
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.380
B.384
C.356
D.324
Answer: B.384
Explanation: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.
Answer: Option B
Question: The sum of 9 hours 25 minutes and 4 hours 35 minutes is approximately what percent of a day?
A. 64%
B. 56%
C. 58%
D. 48%
Answer: C. 58%
Explanation: Since the question is asking for an approximate percentage
9:25+4:35 = 14 hours
% of day = 14*100/24 = 7*100/25 ~ 58%
Answer is C.
Question: 8, 24, 12, 36, 18, 54, (....)
A.27
B.68
C.108
D.72
Answer: A.27
Explanation: Explanation :
8 × 3 = 24
24 ÷ 2 = 12
12 × 3 = 36
36 ÷ 2 = 18
18 × 3 = 54
54 ÷ 2 = 27
Answer : Option A
Question: A train 108 m long is moving at a speed of 50 km/hr . It crosses a train 112 m long coming from opposite direction in 6 seconds. What is the speed of the second train?
A.81km/hr
B.80km/hr
C.82km/hr
D.85km/hr
Answer: C.82km/hr
Explanation: Total distance = 108+112 = 220 m
Time = 6s
Relative speed = distance/time = 220/6 m/s = 110/3 m/s
= (110/3) × (18/5) km/hr = 132 km/hr
=> 50 + speed of second train = 132 km/hr
=> Speed of second train = 132-50 = 82 km/hr
Answer is C.
Question: The marching band is made up of 140 musicians. The band wants to form a rectangular formation with A people in a row and B people in a column. If the number of people in a row is more than 4 and less than 35, how many different combinations of rectangular shapes are possible?
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: firstly factors of 140 = 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140
the question says each row will have musicians more than 4 and less than 35,
therefore, we should be interested in the factors between 4 and 35 (noninclusive)
5(in each row) * 28(number of columns) =140, similarly
7 * 20
10 * 14
14 * 10
20 * 7
28 * 5
total possibilities = 6
option D
Question: The average of 20, 40 and 150 is twice the average of 10, 30, and which of the following ?
A.1)10
B.2)30
C.3)65
D.4)90
Answer: C.3)65
Explanation: 20 40 150 = 150+60 = 210/3 = 70.
70/2 = 35
10 30 x = 40+x/3 should be smaller than 35
cross multiply 35*3-40 = 65
C
Question: A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
A.170
B.200
C.626
D.207
Answer: B.200
Explanation: The number of ways to select two men and three women = ⁵C₂ * ⁶C₃
= (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)
= 200
Answer:B
Question: If the perimeter of a rectangular garden is 600 m, its length when its breadth is 100 m is?
A.228
B.288
C.200
D.288
Answer: C.200
Explanation: 2(l + 100) = 600 => l = 200 m
Answer: C
Question: A fellow borrowed a certain sum of money at 4% per annum at simple interest and in 4 years the interest amounted to Rs.1260 less than the sum lent. What was the sum lent?
A.1050
B.1220
C.1500
D.1060
Answer: C.1500
Explanation: P - 1260 = (P*4*4)/100
P = 1500
Answer: C
Question: On the first day of her vacation, Louisa traveled 250 miles. On the second day, traveling at the same average speed, she traveled 350 miles. If the 250-mile trip took 3 hours less than the 350-mile trip, what was the average speed, in miles per hour?
A.31
B.33.33
C.35
D.37
Answer: B.33.33
Explanation: (time)*(rate) = (distance)-->(rate) = (distance)/(time)--> given:(rate) = 250/t = 350/(t+3)-->5/t = 7/(t+3)-->5t+15=7t ---->2t= 15 . t= 7.5 ---->(rate ) = 250/7.5 = 33.33
Answer: B
Question: A certain bakery baked a batch of 470 cookies one day. Of those, 320 contained nuts, 230 contained chocolate chips, and 85 contained neither nuts nor chocolate chips. What is the fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch?
A.166
B.293
C.413
D.438
Answer: B.293
Explanation: Cookies which have both nuts and chocolate chips = 165
Let fewest possible number of cookies with both chocolate chips and nuts that would need to be added to that
batch so that cookies with both nuts and chocolate chips represented more than 3/5 of all the cookies in the batch = x
(165+x)/(470+x) = 6/10
=>1650 + 10x = 2820 + 6x
=> 4x = 1170
=> x = 292.5
Therefore x = 293
Answer B
Question: An amount of money is to be divided between M, N and O in the ratio of 3:7:12. If the difference between the shares of M and N is Rs.2000, what will be the difference between N and O's share?
A.1266
B.3000
C.2866
D.2500
Answer: D.2500
Explanation: 7-3= 4= 2000
12-7 = 5 = 2000/4*5 = 2500
Answer : D
Question: The ratio of three numbers is 3:4:5 and the sum of their squares is 1250. The sum of the numbers is:
A.20
B.40
C.60
D.80
Answer: C.60
Explanation: Let the numbers be 3x, 4x and 5x
Then, 9x2+16x2+25x2=1250
50x2=1250
X=5
Sum of numbers= 3x+4x+5x=12x=60
ANSWER C
Question: The width of a rectangular hall is ½ of its length. If the area of the hall is 450 sq.m, what is the difference between its length and breadth?
A.8m
B.10m
C.12m
D.15m
Answer: D.15m
Explanation: Let the length of the hall be x m
Breadth of the hall = 1x/2 m
Area of the hall = Length * Breadth
450 = x * 1x/2
x² = 900
x =30
Difference between the length and breadth of the hall = x - 1x/2 = x/2
=30/2 = 15m
ANSWER:D
Question: What percent of the different arrangements of the letters of the word AGAHUS are those in which the vowels appear together?
A.30%
B.25%
C.20%
D.40%
Answer: C.20%
Explanation: let's determine the number of total possibilities in arranging the letters. There are six spaces, so the total number of arrangements is 6!, or 360.
Next, we need to figure out how to determine the number of ways that we can arrange the 3 vowels together - simply place them together (as in AAU) and call that a single place.
Next, we must determine the number of ways to arrange the now 4 units (i.e., AAU, B, C, S). Like above, there are 4 units and 4 places so the number of arrangements is 4!, or 24.
Finally, we need to account for the number of ways we can arrange AAU. We can either write out each unique iteration (AAU, AUA and UAA) or calculate as 3!/2! and get 3.
Putting this all together, we get the number of ways to arrange the letters so that the vowels are together is 4! x 3 ==> 72
the number of total arrangements of all the letters is 6! ==> 360
72/360 = 1/5, or 20% Correct answer is C
Question: An engineer designed a ball so that when it was dropped, it rose with each bounce exactly one-half as high as it had fallen. The engineer dropped the ball from a 16-meter platform and caught it after it had traveled 46.5 meters. How many times did the ball bounce?
A.5
B.6
C.7
D.8
Answer: A.5
Explanation: Going down = 16 m
Going Up = 8 --> Total = 24
Going down = 8 --> Total = 32
Going Up = 4 --> Total = 36
Going down = 4 --> Total = 40
Going up = 2 --> Total = 42
Going down = 2 --> Total = 44
Going up = 1 --> Total = 45
Going down = 1 --> Total = 46
Going up = 0.5 --> Total = 46.5 (Caught)
No of going downs = 5 ..
ANSWER:A
Question: A club wants to mix 15 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?
A.20
B.30
C.40
D.50
Answer: B.30
Explanation: Let number of pounds of 5$ candy to be used be w
6 = (15*8 + 5*w)/(15 +w)
=>90 + 6w = 120 + 5w
=> w = 30
Answer B
Question: A batsman of a cricket has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, thereby increasing his average by 6 runs. His new average is:
A.48 runs
B.52 runs
C.55 runs
D.60 runs
Answer: A.48 runs
Explanation: Explanation :
Let average for 10 innings be x. Then, (10x + 108)/11 = x + 6
11x + 66 = 10x + 108
x = 42
New average = (x + 6) = 48 runs.
Answer : A
Question: A man goes to shopkeeper and says that if u give me as much as i have ,i will spend Rs.10/- on ur shop. shopkeeper agrees and man moves to another shopkeeper ans asked same. at 3rd shop after all the transaction, he was left with no money. find the initial amount with the man
A.5.75
B.6.75
C.7.75
D.8.75
Answer: D.8.75
Explanation: man has Rs.x
he leaves-
1st shop wid Rs.(2x-10)
2nd shop wid Rs.[2(2x-10)-10]
3rd shop wid Rs.{2[2(2x-10)-10]-10}=0(since he has no money left)
so solving the eqn x=8.75
ANSWER:D
Question: If a person walks at 15 km/hr instead of 5 km/hr, he would have walked 20 km more. The actual distance traveled by him is?
A.50 km
B.76 km
C.18 km
D.10 km
Answer: D.10 km
Explanation: Let the actual distance traveled be x km. Then,
x/5 = (x + 20)/15
10x - 100 =>x = 10 km.
Answer: D
Question: The present age of a father is 3 years more than three times the age of his son. Five years hence, father's age will be 10 years more than twice the age of the son. Find the present age of the father.
A.33
B.38
C.27
D.40
Answer: C.27
Explanation: if the present age be x years.
father's will be (3x+3)years..
so, (3x+3+5)=2(x+3)+10
or, x=8
so the fathers present age =(3x+3)=(3*8+3)years =27 years..
ANSWER : OPTION C
Question: What percent of the month of April is 20 days?
A.75%
B.66,66%
C.60%
D.64,5%
Answer: B.66,66%
Explanation: Explanation :
Total days in the month of April = 30
Required percentage = (20/30) Ã— 100 = 66,66%
Answer : Option B
Question: 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.60 only. Menâ€™s wages are?
A.6Rs
B.7Rs
C.8Rs
D.4Rs
Answer: D.4Rs
Explanation: 5M = xW = 8B
5M + xW + 8B ----- 60 Rs.
5M + 5M + 5M ----- 60 Rs.
15M ------ 60 Rs. => 1M = 4Rs.
Answer:D
Question: Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
A.12,28
B.14,30
C.16,32
D.18,34
Answer: B.14,30
Explanation: Explanation:
Let the age of younger person is x,
Then elder person age is (x+16)
=> 3(x-6) = (x+16-6) [6 years before]
=> 3x-18 = x+10
=> x = 14.
So other person age is x + 16 = 30
Answer: Option B
Question: On simplification, 3500 – (1000 ÷ 20.50) is equal to :
A.3451.21
B.3029.0
C.2993.03
D.2984.36
Answer: A.3451.21
Explanation: Explanation:
Given exp. = 3500 - ((1000 ÷ 2050) * 100)
= 3451.21
ANSWER A
Question: An alloy weighing 16 ounces is 50% gold. How many ounces of pure gold must be added to create an alloy that is 80% gold?
A.24
B.18
C.9
D.27
Answer: A.24
Explanation: An alloy of 16oz which is 50% gold means there is 8 oz of gold. To get to an alloy that is 80% gold, let's use this expression: (8 + x)/(16 + x) = 0.8 with x representing the amount of pure gold that must be added to get to 80%. The expression we are using represents the new total weight of pure gold over the new total new weight of the alloy and this fraction should represent 80% or 0.8. you will see that 24 is the correct answer, as 32/40=0.8
Choose A
Question: Ben and King are partners in a business. Ben is a working partner and King is a sleeping partner in the business. Ben invested Rs.3500 and King invested Rs.7000. Ben receives 7% of the profit for managing the business the rest is divided in proportion of their capitals. Out of a total profit of Rs.9600, how much did Ben receive?
A.2648
B.3648
C.3548
D.4648
Answer: B.3648
Explanation: ratio of their investments Rs.3500:Rs.7000=1:2
7% of the profit for managing the business =7/100*9600=672
remaining profit=9600-672=8928
share profit in ratio of investment 8928/3 =2976
Ben ratio share=1*2976=2976
total money Ben collects=2976+672=3648
Answer: B
Question: Which of the following is the lowest positive integer that is divisible by the first 7 positive integer multiples of 3?
A.600
B.820
C.1040
D.1260
Answer: D.1260
Explanation: The number must be divisible by 3, 2*3, 3^2, 2^2*3, 5*3, 2*3^2, and 7*3.
The lowest such number is 2^2*3^2*5*7 = 1260.
The answer is D.
Question: The average age of three boys is 10 years and their ages are in proportion 2:4:4. What is the age in years of the youngest boy?
A.6
B.9
C.8
D.4
Answer: A.6
Explanation: 2x + 4x + 4x = 30
x =3
2x = 6
Answer: A
Question: Of the 200 employees in a certain company, 25 percent will be relocated to City X and the remaining 75 percent will be relocated to City Y. However, 30 percent of the employees prefer City Y and 70 percent prefer City X. What is the highest possible number of employees who will be relocated to the city they prefer?
A. 65
B. 110
C. 115
D. 130
Answer: B. 110
Explanation: 140 prefer X (Group 1);
60 prefer Y (Group 2).
City Y needs 150 people: letall 60 who prefer Y (entire Group 2) be relocated there, the rest 90 will be those who prefer X from Group 1;
City X needs 50 people: 140-90=50 from Group 1 will be relocated to X, which they prefer.
So, the highest possible number of employees who will be relocated to the city they prefer is 60+50=110.
Answer: B.
Question: How many zeros are the end of 380! ?
A.90
B.91
C.94
D.None
Answer: C.94
Explanation: 380! has 380/5+380/5^2+380/5^3=76+15+3=94 trailing zeros ( take only the quotient into account).
Answer: C.
Question: (0.0077)(3.6) / (0.04)(0.1)(0.007)=
A.0.099
B.0.0099
C.9.9
D.990
Answer: D.990
Explanation: (0.0077)(3.6) / (0.04)(0.1)(0.007)=0.0077 * 360/4 * (0.1)(0.007)
= 0.077*90/1 * 0.007 = 77*90/7 = 11*90
=990
Answer : D
Question: A factory that employs 1000 assembly line workers pays each of these workers $5 per hour for the first 40 hours worked during a week and 1½ times that rate for hours worked in excess of 40. What was the total payroll for the assembly-line workers for a week in which 30 percent of them worked 35 hours, 50 percent worked 40 hours, and the rest worked 50 hours?
A. $180,000
B. $185,000
C. $190,000
D. $207,500
Answer: D. $207,500
Explanation: 30% of 1000 = 300 worked for 20 hours
Payment @ 5/hr
Total Payment = 300*35*5 = 52500
50 % of 1000 = 500 worked for 40 hours
Payment @ 5/hr
Total payment = 500*40*5 = 100000
Remaining 200 worked for 50 Hours
Payment for first 40 Hours @ 5 /hr
Payment = 200*40*5 = 40000
Payment for next 10 hr @ 7.5/hr
Payment = 200 * 10 * 7.5 = 15000
Total Payment = 52500+100000 + 40000 +15000 = 207500
Hence , answer is D
Question: In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:
A.21 m
B.26 m
C.28m
D.29m
Answer: C.28m
Explanation: Explanation:
A : B = 100 : 75
B : C = 100 : 96.
A : C =A/BXB/C=100/75 X100/96=100:72
A beats C by (100 - 72) m = 28 m.
ANSWER IS C
Question: If the perimeter of a rectangular playground is 1200 m, its length when its breadth is 500 m is?
A.300
B.200
C.100
D.400
Answer: C.100
Explanation: 2(l + 500) = 1200 => l = 100 m Answer: C
Question: A tradesman by means of his false balance defrauds to the extent of 14%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
A.54.6%
B.29.96%
C.24.45%
D.24%
Answer: B.29.96%
Explanation: g% = 14 + 14 + (14*14)/100
= 29.96%
Answer: B
Question: Richard has to paint a mural with seven horizontal stripes. He only has enough paint for four blue stripes, four white stripes, four black stripes, and four yellow stripes. If his patron wants at most two different colors in the mural, how many different ways can he paint the wall?
A.420
B.350
C.700
D.2,520
Answer: A.420
Explanation: Number of ways to choose 2 colors among 4 - 4c2
Number of ways that the chosen colors can be painted for 7 horizontal stripes - 2 (either (4,3) or (3,4))
Now the order,
the number of ways in which a particular color among the 2 chosen colors can be painted for 4 stripes is - 7c4
[Note: We don't need to calculate the ways for the remaining 3 stripes as they are obvious and already counted under this]
Total number of combinations - 4c2 * 2* 7c4 = 420
A
Question: The C.I. on a certain sum for 2 years at 10% per annum is Rs. 525. The S.I. on the same sum for double the time at half the rate percent per annum is?
A.Rs.502
B.Rs.500
C.Rs.520
D.Rs.512
Answer: B.Rs.500
Explanation: Let the sum be Rs. P. Then,
[P(1 + 10/100)2 - p] = 525
P[(11/10)2 - 1] = 525
P = (525 * 100) / 21 = 2500
Sum = Rs. 2500
So, S.I. = (2500 * 5 * 4)/100
= Rs.500
Answer: B
Question: 1000 men have provisions for 18 days. If 400 more men join them, for how many days will the provisions last now?
A.12.9
B.12.8
C.12.6
D.12.2
Answer: B.12.8
Explanation: 1000*18 = 1400*x
x = 12.8
Answer: B
Question: A certain college's enrollment at the beginning of 1992 was 20 percent greater than it was at the beginning of 1991, and its enrollment at the beginning of 1993 was 25 percent greater than it was at the beginning of 1992. The college's enrollment at the beginning of 1993 was what percent greater than its enrollment at the beginning of 1991 ?
A.47.5%
B.44%
C.50%
D.35%
Answer: C.50%
Explanation: Suppose enrollment in 1991 was 100
Then enrollment in 1992 will be 120
And enrollment in 1993 will be 120*1.25=150
Increase in 1993 from 1991 = 150-100= 50
Answer : C
Question: A circular ground whose diameter is 35 metres, has a 1.4 metre-broad garden around it. What is the area of the garden in square metres?
A.160.16
B.6.16
C.122.66
D.Data inadequate
Answer: A.160.16
Explanation: Req. area = π[(17.5 + 1.4)2 – (17.5)2]
= 22⁄7 × (36.4 × 1.4)[since a2 - b2 = (a + b)(a - b)]
= 22 × 36.4 × 0.2 = 160.16 sq m
Answer A
Question: Last year a certain bond yielded 5 percent of its face value in interest. If that interest was approximately 4 percent of the bonds selling price of $8,000, what is the bonds face value?
A. $6,000
B. $6,750
C. $6,400
D. $7,500
Answer: C. $6,400
Explanation: Interest = 0.05*face value = 0.04*8,000 --> face value = 0.04*8,000/0.05 = 6,400.
Answer: C.
Question: If 100 microns = 1 decimeter, and 10,000 angstroms = 1 decimeter, how many angstroms equal 1 micron?
A.100
B.10
C.0.01
D.0.0001
Answer: A.100
Explanation: Given that 100 microns = 1 decimeter =10,000 angstroms
So, 1 micron = 10,000/100
=100
Answer : A
Question: The product of all the prime numbers less than 15 is closest to which of the following powers of 10 ?
A.10^9
B.10^8
C.10^5
D.10^6
Answer: C.10^5
Explanation: Product of Prime numbers less than 15 is 2*3*5*7*11*13
2*5=10 .
10*11*3*7*13 = 10*10*3*10*10 (approximately) ~ Product will be >10^4 <10^6 i.e. 10^5
C is the answer
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?
A.33/998
B.33/91
C.33/99
D.33/95
Answer: B.33/91
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is = ¹²C₄/¹⁵C₄ = (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12) =33/91.Answer: B
Question: If the sum of the first n positive integers is S, what is the sum of the first n negative even integers, in terms of S ?
A. S/2
B. S
C. 2S
D. 2S + 2
Answer: C. 2S
Explanation: Answer is C
Given sum of -1 -2 -3.....-n = S
sum of -2 , -4 , -6 ....-2n = 2[sum(-1 -2 -3....n) ] = 2S
Question: A solution contains 8 parts of water for every 7 parts of Lemonade syrup. How many parts of the solution should be removed and replaced with water so that the solution will now contain 10% lemonade syrup?
A.1.5
B.1.75
C.2.14
D.2.34
Answer: C.2.14
Explanation: Let the total solution is 150 L with 80 L water70 L syrup.
To make 10% syrup solution, the result solution must have 135 L syrup and 15 L syrup.
Therefore we are taking 55 L of syrup from initial solution and replacing with water.
using urinary method:
70 L syrup in 150 L solution
55 L syrup in 117.9 L solution
We started by multiplying 10
Now to get to the result we need to divide by 55 => amount of solution to be replaced with water = (117.9/55) = 2.14.
Correct option : C
Question: 12 men take 18 days to complete a job whereas 12 women in 18 days can complete 3â„5 of the same job. How many days will 10 men and 8 women together take to complete the same job?
A.6
B.13 1â„2
C.14 3/5
D.Data inadequate
Answer: C.14 3/5
Explanation: 12 M Ã— 18 = 12 W Ã— 18 Ã— 5/3
\ w = 3/5 M
10M + 8W = 10M + 8 Ã— 3â„5M = 14 4/5 M
\14 4/5 men can complete the same work
in 12Ã—18/14 4/5=14 3/5days
Answer C
Question: Yearly subscription to professional magazines cost a company $940.00. To Make a 35% cut in the magazine budget, how much less must be spent?
A.654
B.655
C.611
D.657
Answer: C.611
Explanation: total cost 940
940*35/100=329
so the cut in amount is 329
the less amount to be spend is 940-329=611
ANSWER:C