RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: There is one highland where planes get fuel. A plan can cover the half of the world with full tank. A plane can transfer fuel from one plane to the other in the air. How many planes are required to make one plane cover the entire world once. Starting point of the travel is the Highland and coming back to the same Highland. All the other planes giving fuels to this Plane should also come back to the same highland and they don't have to cover the entire world.
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: Divide the world as 6 parts.
To cover 1/6 th of the distance 1/3 rd of fuel is required.
1 plane, B, can start in same direction of target flight say A.
It can travel 1/6 th of the distance and give 1/3rd of fuel to A and return home with 1/3rd fuel. Now A can cover 4/6th world with that full tank.
Let C and D start from home at opposite direction.
Let C cover 1/6th dist and give 1/3rd fuel to D. Now D travels 1/3 rd more distance and meets A and gives 1/3rd fuel. Both are now 1/6th distance away from home. Let E take fuel and bring one plane home and F take fuel and bring home A. Now excluding A.. 5 supporting planes are required.
ANSWER:D
Question: Given a square of 10cm each side with the four semi circles inside as shown in the above
diagram, find the area of the shaded portion
A.54
B.55
C.56
D.57
Answer: D.57
Explanation: area quadra circle- area of triangle
area of triangle =1/8(area of square)
required area=((pie*5*5/4)-(10*10/8))*8=57
ANSWER:D
Question: A pump can be operated both for filling a tank and for emptying it. The capacity of the tank is 2400 m3. The emptying capacity of the pump is 10m3 per minute higher than its filling capacity. Consequently, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump.
A.45 m3/min
B.40 m3/min
C.50 m3/min
D.55 m3/min
Answer: C.50 m3/min
Explanation: 2400/x - 2400/x+10=8,solving this we get x,
=50m3/min
Answer: C
Question: The total circumference of two circles is 64. If the first circle has a circumference that is exactly twice the circumference of the second circle, then what is the approximate sum of their two radii?
A.5.7
B.6.0
C.6.7
D.10.2
Answer: D.10.2
Explanation: Let r= Radius of smaller circle. Let R = Radius of larger circle
Therefore:
2πr + 2πR = 64
where 2r = R
Thus:
2πr + 4πr = 64
6πr = 64
r = approx 3.4
πR + 2Rπ = 64
3πR = 64
R = approx 6.8
r + R = approx 10.2
Answer D
Question: The events A and B are independent. The probability that event A occurs is u and the probability that event B occurs is v. Which of the following is equal to the probability that exactly one of the events A and B occurs?
A.u − 2uv
B.v − uv
C.u + v − 2uv
D.u + v − uv
Answer: D.u + v − uv
Explanation: Probability of A occuring = u , Probability of A NOT occuring = 1-u
Probability of B occuring = v , Probability of B not occurring = 1-v
Probability of atleast of one of A and B occuring = 1-(1-u)(1-v) =u+v -uv
D
Question: If two numbers x, a perfect square and y, a perfect cube are added results a two digit number, whose digits if reversed, difference is 18, Find x and y ?
A.x=4,y=8
B.x=4,y=9
C.x=4,y=7
D.x=4,y=64
Answer: D.x=4,y=64
Explanation: 4+64=68
when reversed 86
86-68=18
x=4,y=64
ANSWER:D
Question: In a college, the ratio of the number of boys to girls is 8 : 5. If there are 160 girls, the total number of students in the college is
A.100
B.250
C.260
D.416
Answer: D.416
Explanation: Sol.
Let the number of boys and girls be 8x and 5x respectively.
Then, 5x = 160 ⇔ x = 32.
∴ Total number of students = 13x = (13 x 32) = 416.
Answer D
Question: The calendar of the year 2032 can be used again in the year?
A.2060
B.2050
C.2040
D.2033
Answer: A.2060
Explanation: Explanation:
Given year 2032 when divided by 4, leaves a remainder 0.
NOTE: When remainder is 0, 28 is added to the given year to get the result.
So, 2032 + 28 = 2060
Answer: A
Question: A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
A.4 months
B.6 months
C.7 months
D.9 months
Answer: C.7 months
Explanation: 45*12 : 54*x = 2: 1
x = 5
12 -5 = 7
ANSWER:C
Question: A will states that the estate would be divided among six sons with the remainder donated to charity. One stipulation in the will is that no one among the sons can receive an amount within 12% of another's amount. If one of the beneficiaries received $30,000, what is the smallest possible range between the highest and lowest amounts (rounded to the nearest dollar) among the six sons?
A.$4096
B.$14043
C.$7892
D.$17736
Answer: B.$14043
Explanation: 1st - 30,000.
2nd - 0.88*30,000 = 26,400
3rd - 0.88*26,400 = 23,232
4th - 0.88*23,232 = 20,444.16
5th - 0.88*20,444.16 = ~17,990.86
6th - 0.88*17,990.86 = ~15,831.96
Range = 30,000 - 15,831 = 14,168
Answer: B.
Question: Every student in a room is either a junior or a senior. There is at least one junior and at least one senior in the room. If 4/5 of the juniors is equal to 1/2 of the seniors, what fraction of the students in the room are juniors?
A.13/20
B.11/3
C.5/13
D.12/17
Answer: C.5/13
Explanation: Let total number of juniors= J
total number of seniors =S
(4/5) J = (1/2) S
=> S = 8/5 J
Total number of students = J+S = (13/5) J
Fraction of the students in the room are juniors = J/(J+S) = J/[(13/5) J]
=5/13
Answer C
Question: 5x + y = 19 , and x + 3y = 1. Find the value of 3x + 2y
A.20
B.18
C.11
D.10
Answer: D.10
Explanation: Add these two equations
6x + 4y = 20
Divide by 2 ( to Get 3x + 2y)
Answer will be D. 10
Question: A card is drawn from a pack of 52 cards. The probability of getting a queen of spade or an ace of club is:
A.1/13
B.1/26
C.2/13
D.1/52
Answer: B.1/26
Explanation: Explanation :
Total outcomes = 52
Favourable outcomes (getting a queen of spade or an ace of club) = 2
Probability = 2/52 = 1/26.
Answer : B
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
A.45 km/hr
B.50 km/hr
C.54 km/hr
D.55 km/hr
Answer: B.50 km/hr
Explanation: Speed of the train relative to man =	125	m/sec
10
=	25	m/sec.
2
=	25	x	18	km/hr
2	5
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 x = 50 km/hr.
ANSWER:B
Question: There is a train and car. The ratio between the speed of a train & a car is 16:15 respectively. Also, a bus covered a distance of 320 km in 5 hours. The speed of the bus is 4/5th of the speed of the train. How many kilometers will the car cover in 7 hours?
A.375
B.425
C.475
D.525
Answer: D.525
Explanation: The speed of the bus is 320/5 = 64 km/hr
The speed of the train is (64*5)/4 = 80 km/hr
The speed of the car is 80/16 * 15 = 75 km/hr
The distance covered by the car in 7 hours is 75 × 7 = 525 km
The answer is D.
Question: In a 5 digit ID number, what is the probability of exactly 4 digits are the digit 2?
A.0.81
B.1
C.11/22500
D.0.0081
Answer: C.11/22500
Explanation: Total number of 5 digit numbers = 9 * 10 * 10 * 10 * 10 = 90,000
No. of ways of arranging 4 digits as 2 = 5C4=5.
Arrangements are as follows. Here X can be any digit other than 2
1) 2222X = no. of ways = 9
2) 2X222 = no. of ways = 9
3) 22X22 = no. of ways = 9
4) X2222 = no. of ways = 8
5) 222X2 = no. of ways = 9
Probability = (9+9+9+9+8)/90000
=11/22500
Ans - C
Question: There are 10 boxes numbered from 1 to 10. Either a red ball or a green ball will be placed in each box in such a way that at least 1 box contains a green ball and the boxes containing green balls are consecutively numbered. How many different ways can this be done?
A.46
B.49
C.52
D.55
Answer: D.55
Explanation: 1 green ball: 10 ways
2 green balls: 9 ways
3 green balls: 8 ways
4 green balls: 7 ways
5 green balls: 6 ways
6 green balls: 5 ways
7 green balls: 4 ways
8 green balls: 3 ways
9 green balls: 2 ways
10 green balls: 1 way
The total number of ways is 10*11/2=55
The answer is D.
Question: If A = x% of y and B = y% of x, then which of the following is true?
A.None of these
B.A is smaller than B.
C.Relationship between A and B
D.If x is smaller than y, then cannot be determined. A is greater than B.
Answer: A.None of these
Explanation: Explanation :
A = (x/100)y = xy/100.................(Equation 1)
B = (y/100)x = yx/100.................(Equation 2)
From these equations, it is clear that A = B
Answer : Option A
Question: Mary charges $8.50 per hour to clean a house. If she works 27 hours, how much
does she earn in one week?
A.$619.50
B.$122.50
C.$229.50
D.$429.50
Answer: C.$229.50
Explanation: Multiply 27 hours x $8.50 =
Answer: $229.50
correct answer C
Question: For 1rs 4p interest
wat will be for 2000rs?
A.45Rs
B.80Rs
C.40Rs
D.30Rs
Answer: B.80Rs
Explanation: For 1rs , 4p interest
for 2000rs, x
x= 2000/1 * 4p ==> 8000 paise
To express in rs, 8000/100 = 80rs
ANSWER:B
Question: Find the total number of divisors of 1728(including 1 and 1728)
A.28
B.29
C.30
D.31
Answer: A.28
Explanation: 1728=2^6*3^3
no. of divisors = (6+1)*(3+1)=28
ANSWER:A
Question: A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?
A.10 min.
B.40 min.
C.30 min.
D.20 min.
Answer: C.30 min.
Explanation: Part filled by (A + B) in 1 minute =1/60+1/40=1/24	.
Suppose the tank is filled in x minutes.
Then,	x /2	(1/24+ 1/40)= 1
x/2 x 1/15=1
x/30=1
x = 30 min.
Answer is C
Question: If the simple interest on a certain amount in at 4% rate 5 years amounted to Rs.2240 less than the principal. What was the principal?
A.1500
B.2500
C.2507
D.2800
Answer: D.2800
Explanation: P - 2240 = (P*5*4)/100
P = 2800
Answer: D
Question: Five years ago, the average age of A, B, C and D was 45 years. With E Joining them now, the average of all the five is 50 years. The age of E is?
A.50
B.47
C.48
D.49
Answer: A.50
Explanation: Solution
5 years ago average age of A,B,C,D = 45 years
=> 5 years ago total age of A, B, C, D = 45 x 4 = 180 years
=> Total present age of A, B, C, D = 180 + 5x4 = 200 years
If E's present age is x years = 200+x/5= 50
x=50 years. Answer A
Question: A school currently maintains a fixed number of students per class. If the ratio of students per class were to be increased by 1, 10 fewer classes would be run for a total of 120 students. What is the current ratio E of students per class?
A.E=3
B.4
C.6
D.8
Answer: A.E=3
Explanation: Another way to look at the problem...
Since the total is 120, RATIO * CLASSES = R*C = 120.....(i)
we are looking where ratio increases by 1 and # of classes decreases by 10 = (R+1)(C-10) = RC+C-10R-10=120....(ii)
(ii)-(i)....
C=10R+10 = 10(R+1).......
so # of classes has to be multiple of 10
AS RC=120.... 10(R+1)*R = 120...................R(R+1) = 12..
so 12 is a multiple of consecutive numbers ONLY 3 *4 fits in..... and R=3
A
Question: A man, a woman and a boy can together complete a piece of work in 3 days. If a man alone can do it in 6 days and a women alone in 18 days, how long will a boy take to complete the work?
A.6days
B.8days
C.9days
D.7days
Answer: C.9days
Explanation: Explanation:
(1 Man + 1 woman + 1 boy)’s 1day’s work = 1/3
1 man’s 1 day work = 1/6
1womans 1 day’s work = 1/18
(1 Man + 1 woman) ‘s 1 day’s work = 1/6 + 1/18 = 2/9
Therefore, 1 boys 1 day’s work = 1/3 – 2/9 = 3-2/9 = 1/9
Therefore, the boy alone can finish the work in 9 days.
Answer: Option C
Question: If n is an integer and 5^n > 50,000,000, what is the least possible value of n?
A.12
B.8
C.9
D.10
Answer: A.12
Explanation: When you seperate the 50000000 into factors of 5 and 2 you get - > 10^7 x 5^1 = 5^8 x 2^7
2 to the ^ 7 = 128 so its 128 x 5^8
that means 5^8 x 5^x must be greater
5^x > 128
5^1=5
5^2=25
5^4= 625
- > so x must be at least 4
5^(8+4)= 5^12
A
Question: If a coin is tossed twice, what is the probability that the coin lands on tails on both tosses?
A.1/6
B.1/3
C.1/4
D.1/2
Answer: C.1/4
Explanation: P(2 tails) = 1/2*1/2=1/4
The answer is C.
Question: The price of a certain painting increased by 20% during the first year and decreased by 15% during the second year. The price of the painting at the end of the 2-year period was what percent of the original price?
A.102%
B.105%
C.120%
D.135%
Answer: A.102%
Explanation: Assume that price is 100
Price at the end of yr 1: 100+ 20 = 120
Price at the end of year 2 = 120 - 120*0.15 = 120*0.85 = 102
Hence required answer = (102/100)*100% = 102%
Answer is A.
Question: Two trains start at same time from two stations and proceed towards each other at the rate of 20 km/hr and 25 km/hr respectively. When they meet, it is found that one train has traveled 55 km more than the other. What is the distance between the two stations?
A.540 km
B.495 km
C.276 km
D.178 km
Answer: B.495 km
Explanation: Explanation:
Let us assume that trains meet after 'x' hours
Distance = speed * Time
Distance traveled by two trains = 20x km and 25x km resp.
As one train travels 55 km more than the other,
25x â€“ 20x = 55
5x = 55
x = 11hours
As the two trains are moving towards each other, relative speed = 20 + 25 = 45 km/hr
Therefore, total distance = 45*11 = 495 km.
ANSWER: B
Question: A student took 6 courses last year and received an average (arithmetic mean) grade of 100 points. The year before, the student took 5 courses and received an average grade of 80 points. To the nearest tenth of a point, what was the student’s average grade for the entire two-year period?
A.79
B.89
C.95
D.90.91
Answer: D.90.91
Explanation: Let the 6 courses that were taken last year be A1 , A2, A3 , A4 , A5 , A6
A1+A2+A3+A4+A5+A6 = 100*6 = 600
The year before , the 5 courses be B1, B2 , B3 , B4 , B5
B1+B2+B3+B4+B5 = 80*5 = 400
Student's average = (600+400)/11 = 90.91
Answer D
Question: A single refined oil can contains 20% impurities. After double – refining it contains 4% impurities. How much of double- refined oil can be obtained from 30 litres of single refined oil?
A.24.0 litres
B.24.8 litres
C.25.0 litres
D.25.5 litres
Answer: C.25.0 litres
Explanation: Exp. On double- refining impurity decreases from 20% to 4%., but the
amount of pure oil in both cases remains constant,
i.e, 96% of double refined oil = 80% of single refined oil.
Let x be the quantity of double-refined oil
Then 96*x/100 = 80*30/100, x = 30*80 /96 = 25
Answer:C
Question: In 2005, 20 percent of the math department’s 45 students were female, and in 2007, 40 percent of the math department’s 705 students were female. What was the percent increase from 2005 to 2007 in the number of female students in the department?
A.85%
B.130%
C.211.1%
D.220%
Answer: C.211.1%
Explanation: Female students in 2005 = 20% of 45 = 9
Female students in 2007 = 40% of 70 = 28
Percentage increase = [(28 - 9)/9] *100 % = 211.1%
Correct Option: C
Question: From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first card is a red and the second card is black is?
A.1/4
B.1/52
C.1/26
D.1/13
Answer: A.1/4
Explanation: Probability of a queen = 4/52 = 1/2
Probability of a red card = 26/52 = 1/2
Probability of both = P1*P2 = 1/(2*2) = 1/4
Answer is A.
Question: A certain sum amounts to Rs.1725 in 3 years and Rs.1875 in 5 years. Find the rate % per annum?
A.4%
B.5%
C.2%
D.9%
Answer: B.5%
Explanation: 3 --- 1725
5 --- 1875
--------------
2 --- 150
N = 1 I = 75 R = ?
P = 1725 - 225 = 1500
75 = (1500*1*R)/100
R =5%
Answer:B
Question: If 0 < a < b and k = (2a + b)/b , which of the following must be true?
A.k < 3
B.k < 7
C.k < 9
D.k > 9
Answer: A.k < 3
Explanation: Please follow posting guidelines (link in my signature) especially writing the correct topic title. Also do mention the source of the question if you select the tag:Source-Other Please Specify.
As for your question, it is very simple and straightforward with number plug in.
Assume a=1 and b=2 as a<b, you get k = (2+2)/2 = 2. This eliminates all but option A , making it the correct answer.
Question: Platinum is 19 times as heavy as bronze and silver is 9 times as heavy as bronze. In what ratio these two metals be mixed so that the alloy is 15 times as heavy as bronze is
A.2:1
B.3:2
C.1:2
D.2:3
Answer: B.3:2
Explanation: Let the proportion of weight of platinum in the mixture = x
then the proportion of weight of silver in the mixture = 1 - x
According to the question
19 X x + 9 (1 - x) = 15 X 1
19x + 9 - 9x = 15
10x = 15 - 9 = 6
x = 6/10 = 3/5
Therefore the proportion of weight of platinum in the mixture = x = 3/5
and the proportion of weight of silver in the mixture = 1 - x = 1 - 3/5 = 2/5
The required ratio of platinum : silver = 3/5 : 2/5
= 3 : 2
ANSWER:B
Question: Chauncy, an English bulldog, received 1200 votes in the Mr. Bulldog USA competition, giving him approximately 30 percent of the vote. Approximately what percent of the remaining votes would he have needed to receive in order to win 70 percent of the total votes?
A.56.14%
B.57.14%
C.58.14%
D.59.14%
Answer: B.57.14%
Explanation: let the total vote is x.then 30% of x=(30/100)*x=1200,
or,x=(1200*100)/30;
or,x=4000;
now, 30% of votes already given...so other 70% of x votes=(70/100) *4000=2800 votes. now other needed votes=(70-30)%=40% votes. so 40% votes of x=(40/100)*4000=1600; now he have needed only % of votes=(100*1600)/2800=160000/2800;=57.14285714%
ANSWER:B
Question: Calculate the number of bricks, each measuring 25 cm * 15 cm * 8 cm required to construct a wall of dimensions 10 m * 4 m * 5 m when 10% of its volume is occupied by mortar?
A.33277
B.6888
C.6000
D.2777
Answer: C.6000
Explanation: 10 * 4/100 * 5 * 90/100 = 25/100 * 15/100 * 8/100 * x
10 * 20 * 90 = 15 * 2 * x => x = 6000
Answer: C
Question: The sum of three numbers is 98. If the ratio of the first to second is 2 : 3 and that of the second to the third is 5 : 8, then the second number is
A.33
B.28
C.30
D.88
Answer: C.30
Explanation: Explanation:
Let the three parts be A, B, C. Then,
A : B = 2 : 3 and B : C = 5 : 8 ==
A : B : C = 2 : 3 : = 10 : 15 : 24
B = = 30
Answer: C) 30
Question: Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
A.11 a.m.
B.10 a.m.
C.12 a.m.
D.9 a.m.
Answer: B.10 a.m.
Explanation: Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
Therefore 20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Answer: Option B
Question: 80 ? 860 1550 2440 3530
A.370
B.840
C.750
D.860
Answer: A.370
Explanation: 10^2 - 20 = 80
20^2 - 30 = 370
30^2 - 40 = 860
40^2 - 50 = 1550
50^2 - 60 = 2440
60^2 - 70 = 3530.
ANSWER:A
Question: Tom can hit a target 3times in 6 shots, Karan can hit the target 2 times in 6shots & Ashwini can hit 4 times in 4 shots.What is the probability that at least 2 shots hit the target ?
A.1/2
B.2/5
C.2/3
D.2/7
Answer: C.2/3
Explanation: Ashwini hits the target definitely, hence required probability that atleast 2 shots hit the target is given by
Karan hits tha target and Raja not hit the target.
or
Karan does not hit the target and Raja hits the target.
or.
Karan hits the target and Raja hits the target
= 2/6 x 3/6 + 4/6 x 3/6 + 2/6 x 3/6
= 24/36 = 2/3
C
Question: Tough and Tricky questions: Absolute Values.
If |a| = 1/2 and |b| = 2/3, which of the following CANNOT be the result of a + b?
A.7/6
B.-1/6
C.1/6
D.2/6
Answer: D.2/6
Explanation: |a| = 1/2
Absolute value of 'a' can have two values = 1/2 and -(1/2)
|b| = 2/3
Absolute value of 'b' can have two values = 2/3 and -(2/3)
Now different combinations of a + b are as follows:
a + b = (1/2) + (2/3) = 7/6
- a - b = -(1/2) - (2/3) = -7/6
a - b = (1/2) - (2/3) = -(1/6)
-a + b = -(1/2) + (2/3) = 1/6
Cross verifying with the given options, left over option is D.
Question: The sale price watches listed for Rs.4500 after successive discount is 10% and 20% is?
A.3240
B.3420
C.4320
D.4230
Answer: A.3240
Explanation: 4500*(90/100)*(80/100)
= 342
Answer: A
Question: A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?
A.20 years
B.21 years
C.22 years
D.23 years
Answer: C.22 years
Explanation: Let present age of the son =x years
Then, present age the man =(x+24) years
Given that, in 2 years, man's age will be twice the age of his son
=(x+24)+2=2(x+2)
=x=22
Answer: Option C
Question: A train 385 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
A.15
B.61
C.21
D.14
Answer: C.21
Explanation: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [385 * 3/55] sec = 21 sec
Answer: C
Question: Two pipes A and B can fill a tank in 20 and 30 minutes respectively. If both the pipes are used together, then how long will it take to fill the tank?
A.12 minutes
B.18 minutes
C.10 minutes
D.15 minutes
Answer: A.12 minutes
Explanation: Part filled by A in 1 min. = 1/20
Part filled by B in 1 min. = 1/30
part filled by (A + B) in 1 min. = 1/20 + 1/30 = 1/12.
Both the pipes can fill the tank in 12 minutes.
Answer:A
Question: A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.287 m
B.350 m
C.187 m
D.197 m
Answer: B.350 m
Explanation: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x
= 350 m.
Answer: B
Question: A tradesman by means of his false balance defrauds to the extent of 20%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
A.20%
B.45%
C.44%
D.48%
Answer: C.44%
Explanation: g% = 20 + 20 + (20*20)/100
= 44%
ANSWER:C
Question: A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.227
B.350
C.771
D.176
Answer: B.350
Explanation: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.
Answer: B
Question: 10% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 6514, how much was it in the beginning?
A.8545
B.8770
C.8515
D.7999
Answer: C.8515
Explanation: X * (90/100) * (85/100) = 6514
X = 8515
Answer: C
Question: Shekhar started a business investing Rs.25,000 in 1999.In 2000,he invested an additional amount of Rs.10,000 and Rajeev joined him with an amount of Rs.35,000.In 2001,Shekhar invested another additional amount of Rs.10,000 and Jatin joined them with an amount of Rs.35,000.What will be Rajeev’s share in the profit of Rs.1,50,000 earned at the end of 3 years from the start of the business in 1999 ?
A.Rs.45,000
B.Rs.50,000
C.Rs.70,000
D.Rs.75,000
Answer: B.Rs.50,000
Explanation: Solution
Shekhar : Rajeev : Jatin
= (25000x12+35000x12+45000x12) :(35000x24) : (35000x12)
= 1260000 : 840000 : 420000 = 3 : 2 : 1.
∴ Rajeev’s share = Rs.(15000x2/6) = Rs. 50,000. Answer B
Question: If a > x > y > z on the number line, y is halfway between x and z, and x is halfway between w and z, then (y - x)/(y - a) =
A.1/4
B.1/3
C.1/2
D.3/4
Answer: B.1/3
Explanation: Let y-z=t ---> since y is halfway between x and z and x>y we have x-y=t. Moreover x-z=(x-y)+(y-z)=2t. Similarly since x is halfway between w and z, we have a-x=2t. So y-x=-t, y-a=-3t. ---> (y - x)/(y - a) = 1/3.
The answer is (B).
Question: If 5 machines can produce 20 units in 10 hours, how long would it take 10 to produce 60 units?
A.9
B.10
C.15
D.25
Answer: C.15
Explanation: 5 machines would produce 60 units in 30 hours. Increasing the amount of machines by 2 would mean dividing 30 hours by 2.
30/2 = 15
Answer : C