RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The salary of a person was reduced by 15%. By what percent should his reduced salary be raised so as to bring it at par with his original salary?
A.10%
B.17.6%
C.13.7%
D.15.1%
Answer: B.17.6%
Explanation: Let the original salary be $100
New salary = $85
Increase on 85=15
Increase on 100 = 15/85* 100 = 17.6%
Answer is B
Question: Two numbers are such that the ratio between them is 3:5 but if each is increased by 10, the ratio between them becomes 5 : 7, the numbers are
A.3, 5
B.7, 9
C.13, 22
D.15, 25
Answer: D.15, 25
Explanation: Explanation:
Let the numbers be 3a and 5a
Then 3a+10/5a+10=5/7
⇒7(3a+10)=5(5a+10)⇒a=5
The numbers are 15 & 25
Correct Option: D
Question: A parallelogram has sides 12 cm and 9 cm. If the distance between its shorter sides is 8 cm, find the distance between its longer side.
A.2
B.4
C.6
D.8
Answer: C.6
Explanation: Adjacent sides of parallelogram = 2 cm and 9 cm
Distance between shorter sides = 8 cm
Area of parallelogram = b × h
= 9 × 8 cm²
= 72 cm²
Again, area of parallelogram = b × h
72 = 12 × h
h = 72/12
h = 6 cm
Therefore, the distance between its longer side = 6 cm.
ANSWER-OPTION C
Question: A person buys an article at Rs.550. At what price should he sell the article so as to make a profit of 30%?
A.600
B.715
C.772
D.662
Answer: B.715
Explanation: Cost price = Rs.550
profit = 30% of 550 = Rs.165
Selling price = Cost price + Profit
= 550 + 165 = 715
Answer: B
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:
A.12 years
B.14 years
C.15 years
D.20 years
Answer: B.14 years
Explanation: Let the son's present age be x years. Then, (38 - x) = x
2x = 38.
x = 19.
Son's age 5 years back (19 - 5) = 14 years.
ANSWER B
Question: In a group of cows and chickens, the number of legs was 18 more than twice the number of heads. The number of cows was:
A.5
B.7
C.9
D.12
Answer: C.9
Explanation: Let the number of cows be x and their legs be 4x.
Let the number of chicken be y and their legs be 2x.
Total number of legs = 4x + 2y.
Total number of heads = x + y.
The number of legs was 18 more than twice the number of heads.
Therefore, 2 × (x + y) + 18 = 4x + 2y.
or, 2x + 2y + 18 = 4x + 2y.
or, 2x + 18 = 4x [subtracting 2y from both sides].
or, 18 = 4x – 2x [subtracting 2x from both sides].
or, 18 = 2x.
or, x = 9 [dividing by 2 on both sides].
Therefore, the number of cows = 9.
Correct Answer:C)9
Question: If the L.C.M of two numbers is 750 and their product is 18750, find the H.C.F of the numbers.
A.50
B.30
C.125
D.25
Answer: D.25
Explanation: H.C.F = (Product of the numbers) / (Their L.C.M) = 18750/750 = 25.
ANSWER:D
Question: 3 men and 7 women can complete a work in 10 days . But 4 men and 6 women need 8 days to complete the same work . In how many days will 10 women complete the same work?
A.40
B.45
C.50
D.35
Answer: A.40
Explanation: Work done by 4 men and 6 women in 1 day = 1/8
Work done by 3 men and 7 women in 1 day = 1/10
Let 1 man does m work in 1 day and 1 woman does w work in 1 day. The above equations can be written as
4m + 6w = 1/8 ---(1)
3m + 7w = 1/10 ---(2)
Solving equation (1) and (2) , we get m=11/400 and w=1/400
Amount of work 10 women can do in a day = 10 × (1/400) = 1/40
Ie, 10 women can complete the work in 40 days
Answer is A.
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.180 m
B.240 m
C.260 m
D.280 m
Answer: B.240 m
Explanation: Speed = 54 x 5/18 = 15 m/s
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, (x + 300)/36 = 15
--> x + 300 = 540
x = 240m.
Answer : B.
Question: Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is ?
A.5/ 19
B.5/ 12
C.5/ 27
D.5/ 18
Answer: B.5/ 12
Explanation: Using question number 11 and 12, we get the probability as
1 - (1/36 + 5/9)
=5/ 12
Answer: B
Question: Private Benjamin is a member of a squad of 10 soldiers, which must volunteer 4 of its members for latrine duty. If the members of the latrine patrol are chosen randomly, what is the probability W that private Benjamin will be chosen for latrine duty?
A.1/10
B.1/5
C.2/5
D.3/5
Answer: C.2/5
Explanation: Easier way : Desired probability = 1- 'excluded' probability
In this case, Excluded probability = probability of Benjamin not being a part of the 4 volunteers. We can choose 4 out of 9 remaining soldiers in 9C4 ways. total ways possible = 10C4.
Thus excluded probability = 9C4/10C4 = 3/5
Thus, the desired probability W= 1- 3/5 = 2/5. Thus C is the correct answer.
Question: Donovan took a math test and got 35 correct and 10 incorrect answers.
What was the percentage of correct answers? (Round to the nearest
hundredth)
A.57.78%
B.67.78%
C.77.78%
D.47.78%
Answer: C.77.78%
Explanation: 35 correct answers+10 incorrect answers=45 total answers
Multiple the opposites
100 x 35 = 3500
77.777/3500
77.78% (rounded to hundredth)
correct answer C
Question: If the product of two positive integers is 144, which of the following could be the LCM and HCF of the two numbers?
I. LCM : 24; HCF : 6
II. LCM : 18; HCF : 8
III. LCM : 16; HCF : 9
A.I only
B.II and III only
C.I and II only
D.I and III only
Answer: A.I only
Explanation: We need to keep two things in mind here:
1. Product of two numbers = LCM*HCF
2. LCM should be a multiple of HCF
Only Statement I follows these two rules.
Correct Option A
Question: Ramu rides his bike at an average speed of 45 km/hr and reaches his desitination in four hours. Somu covers the same distance in six hours. If Ramu covered his journey at an average speed which was 9 km/hr less and Somu covered his journey at an average speed which was 10 km/hr more, then the difference in their times taken to reach the destination would be (in minutes).
A.23 minutes
B.30 minutes
C.87 minutes
D.16 minutes
Answer: B.30 minutes
Explanation: Distance travelled by Ramu = 45 * 4 = 180 km
Somu travelled the same distance in 6 hours.
His speed = 180/6 = 30 km/hr
Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 30 + 10 = 40km/hr.
Therefore travel time of Ramu and Somu would be 5 hours and 4.5 hours respectively. Hence difference in the time taken = 0.5 hours = 30 minutes.
Answer: B
Question: A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 52 years now, the son's age five years back was?
A.16 years
B.14 years
C.18 years
D.21 years
Answer: D.21 years
Explanation: Let the son's present age be x years.
Then, (52 - x) = x
2x = 52 => x = 26
Son's age 5 years back = (26 - 5)
= 21 years.
Answer: D
Question: A car takes 6 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
A.50 Kmph
B.60 Kmph
C.65 Kmph
D.70 Kmph
Answer: B.60 Kmph
Explanation: Time = 6
Distence = 540
3/2 of 6 hours = 6 * 3/2 = 9 Hours
Required speed = 540/9 = 60 Kmph
B)
Question: A train 300m long takes 9 sec to cross a man walking at 3kmph in a direction opposite to that of the train. Find the speed of the train?
A.100kmph
B.90kmph
C.120kmph
D.117kmph
Answer: D.117kmph
Explanation: Let the speed of the train be x kmph
Speed of the train relative to man = x+3 = (x+3)*5/18 m/sec
300/[(x+3)*5/18] = 9
9(x+3) = 1080
x = 117kmph
Answer is D
Question: If a^x = b^y, then
A.log a/b= x/y
B.log a/ log b = x/y
C.log a/ log b = y/x
D.log b/a = x/y
Answer: C.log a/ log b = y/x
Explanation: a^x = b^y => log a^x = log b^y => x log a = y log b
=> log a/ log b = y/x
ANSWER:C
Question: On dividing 23 by a number, the quotient is 7 and the remainder is 2. Find the divisor.
A.1
B.2
C.3
D.6
Answer: C.3
Explanation: d = (D-R)/Q
= (23 - 2)/7
= 21/7 = 3
C
Question: Nitin borrowed some money at the rate of 6% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years. If the total interest paid by him at the end of eleven years is Rs. 8160, how much money did he borrow?
A.8000
B.9289
C.2689
D.2769
Answer: A.8000
Explanation: Let the sum be Rs. x. Then,
[(x * 6 * 3)/100] + [(x * 9 * 5)/100] + [(x * 13 * 3)/100] = 8160
18x + 45x + 39x = (8160 * 100)
102x = 816000 => x = 8000.
Answer:A
Question: What least number should be subtracted from 13600 such that the remainder is divisible by 87 ?
A.27
B.29
C.28
D.30
Answer: C.28
Explanation: 13600 ÷ 87 = 156, remainder = 28
Hence 28 is the least number which can be subtracted from 13600 such that the remainder
is divisible by 87
Answer is C
Question: You collect baseball cards. Suppose you start out with 16. Since you're nice, you give John 4 baseball cards. How many baseball cards do you have at the end?
A.11
B.12
C.13
D.14
Answer: B.12
Explanation: Solution
Start with 16 baseball cards.
John takes 4 baseball cards from you: 16 - 4 = 12 baseball cards.
So you have 12 at the end.
Correct answer : B
Question: If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is?
A.3377
B.2688
C.2688
D.8112
Answer: D.8112
Explanation: A = 7500(26/25)2 = 8112
Answer: D
Question: If x and y are integers and 3^(x-4) = 3^(y-2), what is y in terms of x?
A.x - 6
B.x - 5
C.x - 2
D.x + 2
Answer: C.x - 2
Explanation: Answer: A
3^(x-4) = 3^(y-2)
Since the base is the same, I isolated the equations and solved for y.
x-4 = y-2
y=x-2
Ans : C
Question: From a group of 5men and 4 women, 3 persons are to be selected to form a committee so that at least 2 men are there are on the committee. In how many ways can it be done?
A.20
B.50
C.65
D.86
Answer: B.50
Explanation: We have (2men and 1 woman) or (3men only)
Therefore, Required number of ways= (5C2*4C1) + (5C3)
= (5*4)/(2*1) * 4 + 5C2
= 10*4 + 10
= 40 +10
=50
ANSWER:B
Question: A man walking at a rate of 10km/hr crosses a bridge in 24 minutes. The length of the bridge is?
A.1521
B.1492
C.1667
D.4000
Answer: D.4000
Explanation: Speed = 10*5/18 = 50/18 m/sec
Distance covered in 24 minutes = 50/18 * 24 *60 = 4000 m
Answer is D
Question: 40 is subtracted from 60% of a number, the result is 50. Find the number?
A.150
B.887
C.769
D.266
Answer: A.150
Explanation: (60/100) * X – 40 = 50
6X = 900
X = 150
Answer: A
Question: If Sharon's weekly salary increased by 16 percent, she would earn $406 per week. If instead, her weekly salary were to increase by 20 percent, how much would she earn per week?
A. $420
B. $382
C. $385
D. $392
Answer: A. $420
Explanation: (406/116)120 =420
In this case long division does not take much time.
(406/116)=3.5
35*12=420(350+70)
Answer A
Question: 2 pipes function simultaneously the reservoir will be filled in 12 hrs. One pipe fills reservoir 10 hrs faster thanthe other. How many hours does the faster pipe take to fill the reservoir?
A.12
B.20
C.24
D.26
Answer: B.20
Explanation: 1/x + 1/(x + 10) = 1/12
x = 20
B
Question: A bike covers a certain distance at the speed of 56km/h in 5 hrs. If the bike was to cover the same distance in approximately 7 hrs, at what approximate speed should the bike travel?
A.39 km/h
B.35 km/h
C.55 km/h
D.40 km/h
Answer: D.40 km/h
Explanation: Ans.(D)
Sol. Total distance = 56 × 5 = 280 km
Now speed = 280/7 = 40 km/h
Question: A hall is 15 m long and 12 m broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume of the hall is:
A.3348
B.3898
C.1200
D.2881
Answer: C.1200
Explanation: Answer: C) 1200
Question: Anand and Deepak started a business investing Rs. 22,500 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Deepak's share is?
A.8428
B.8199
C.8400
D.8419
Answer: C.8400
Explanation: Ratio of their shares = 22500 : 35000 = 9:14
Deepak's share = 13800 * 14/23
= Rs. 8400.
Answer:C
Question: A cube of side one meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?
A.1278
B.1728
C.1000
D.8732
Answer: C.1000
Explanation: Along one edge, the number of small cubes that can be cut
= 100/10 = 10
Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut
= 10 * 10 * 10
= 1000
Answer:C
Question: A rectangular lawn of dimensions 80 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
A.2987
B.2768
C.2775
D.3900
Answer: D.3900
Explanation: Area = (l + b – d) d
(80 + 60 – 10)10 => 1300 m2
1300 * 3 = Rs.3900
Answer:D
Question: Find the value of x from the below equation: x^2−7x+10=0
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: Here we need to find out a and b such that a + b = -7 and ab = +10
a = -5 and b = -2 satisfies the above condition.
Hence
x^2−7x+10=(x−5)(x−2)
x2−7x+10=(x−5)(x−2)
x^2−7x+10
=0
⇒(x−5)(x−2)
=0
x2−7x+10=0⇒(x−5)(x−2)=0
Step 3: Equate each factor to 0 and solve the equations
(x−5)(x−2)
=0
⇒(x−5)
=0or (x−2)=0
⇒x= 5 or 2
B
Question: A football player just signed a new contract in which he will earn a 10% raise in base pay from the previous year. Last year, he did not earn a performance bonus; but this year, he will have the chance to earn a performance bonus of up to $20,000. If his new salary is effectively an 11% raise after earning the top performance bonus, what is his new salary?
A.2,120,000
B.2,170,000
C.2,210,000
D.2,220,000
Answer: D.2,220,000
Explanation: let x = the old salary
(1+.10)*x + 20,000 = (1+.11)*x
1.1x + 20,000 = 1.11x
20,000 = .01x
2,000,000 = x
the new salary is thus (1+.11)*2,000,000 = 1.11*2,000,000 = 2,220,000
D
Question: On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 50 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?
A.30%
B.40%
C.50%
D.60%
Answer: B.40%
Explanation: Let T be the total number of passengers.
Let x be the number of people with round trip tickets.
0.2T had round trip tickets and took their cars.
0.5x had round trip tickets and took their cars.
0.5x = 0.2T
x = 0.4T
The answer is B.
Question: In how many ways can the letters of wordSOLUTIONbe arranged such that all the Consonants always appear together?
A.9!
B.5!*4!
C.5!*5!
D.5!*4!*2!
Answer: B.5!*4!
Explanation: Let the arrangment be: _ _ _ _ _ _ _ _ _ _ (8 letters, 4 vowels O, U, I, O and 4 consonant S, L, T, N)
For all consonants together, consider them as 1 group {S, L, T, N} O U I O --> this gives us 5! arrangements with {} group considered as 1 . Now {} group can in itself be arranged in 4! ways
Thus total arrangements with all consonants together = 5!*4! --> B is the correct answer.
Question: Out of first 50 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is -.
A.1/2
B.16/19
C.4/5
D.61/50
Answer: D.61/50
Explanation: n(S) = 50
n(Even no) = 25 = n(E)
n(Prime no) = 15 = n(P)
P(EᴜP) = 25/50 + 15/50 - 1/50 = 61/50
ANSWER:D
Question: When 15 is divided by integer u, the remainder is 4. For how many values of u is this be true?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: When 15 is divided by u, the remainder is 4 i.e. 4 mangoes left over after grouping, so u must be greater than 4.
It also means that 11 is completely divisible by u.
Factors of 11 are 1 and 11.
Out of these, u could be 11.
Answer (A)
Question: in a rectangle 8 vertical and 4 horizontal lines are drawn find the number of rectangle formed ?
A.654
B.664
C.674
D.684
Answer: C.674
Explanation: 8 vertical lines plus the 2 lines of the existing rectangle(as its mentioned in the question "in a rectangle") accordingly 4 plus 2 horizontal lines.
therefore
10C2*6C2= 675 and if its asked for the new rectangle formed than
675-1=674 (excluding the existing rectangle)
ANSWER:C
Question: Two bullet trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each bullet train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
A.13 sec.
B.15 sec.
C.12 sec.
D.17 sec.
Answer: C.12 sec.
Explanation: C
12 sec.
Speed of the first bullet train = 120/10 m/sec = 12 m/sec.
Speed of the second bullet train = 120/15 m/sec = 8 m/sec.
Relative speed = (12 + 8) = 20 m/sec.
Required time = (120 + 120)/20 sec = 12 sec.
Question: Which of the following is divisible by the first thousand positive even integer multiples of 101?
(i) 55650000
(ii) 234177623000
(iii)11111111111110000000000000000000000000
A.None
B.i only
C.ii only
D.iii only
Answer: A.None
Explanation: The digits of (iii) add to 13, so (iii) is not divisible by 3, so is not divisible by 3*101, and hence not divisible by the first thousand positive even integer multiples.
A positive integer x is divisible by the first thousand integer multiples of 101 if and only if it is divisible by their least common multiple. There are at least 12 primes greater than 10 but less than 1000 so to be divisible by the first thousand integer multiples of 101 x must be at least 10^12. Consquently, neither (i) not (ii) is divisible by the first thousand integer multiples of 101.
Answer A
Question: A can do a piece of work in 12 days and B can do a piece of work in 18 days how many days will the work be completed if both of them work together?
A.15
B.7.2
C.7.7
D.7.4
Answer: B.7.2
Explanation: A's 1 day work=1/12,B's 1 day work =1/18;
(A+B) 1 day work=1/12+1/18=5/36;
they can finish the work in=36/5=7.2
ANSWER:B
Question: Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
A.50
B.99
C.88
D.71
Answer: A.50
Explanation: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 - 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50.
Answer:A
Question: Rs. 6000 is lent out in two parts. One part is lent at 7% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?
A.5:1
B.5:5
C.5:8
D.5:4
Answer: A.5:1
Explanation: Let the amount lent at 7% be Rs. x
Amount lent at 10% is Rs. (6000 - x)
Total interest for one year on the two sums lent
= 7/100 x + 10/100 (6000 - x) = 600 - 3x/100
=> 600 - 3/100 x = 450 => x = 5000
Amount lent at 10% = 1000
Required ratio = 5000 : 1000 = 5:1
Answer:A
Question: If BELT is coded as 27 and JUMPED is coded as 54, then CHAIRS is coded as
A.10
B.21
C.40
D.92
Answer: C.40
Explanation: BELT= 2+5+12+20=39 i.e 3*9=27
JUMPED= 10+21+13+16+5+4=69 i.e 6*9=54
CHAIRS= 3+8+1+9+18+19 =58 5*8=40
ANSWER:C
Question: The width of a rectangular hall is ½ of its length. If the area of the hall is 800 sq.m, what is the difference between its length and breadth?
A.8m
B.10m
C.12m
D.20m
Answer: D.20m
Explanation: Let the length of the hall be x m
Breadth of the hall = 1x/2 m
Area of the hall = Length * Breadth
800 = x * 1x/2
x² = 1600
x =40
Difference between the length and breadth of the hall = x - 1x/2 = x/2
=40/2 = 20m
ANSWER:D
Question: 60% of a number is added to 150, the result is the same number. Find the number?
A.375
B.277
C.266
D.99
Answer: A.375
Explanation: :
(60/100) * X + 150 = X
2X = 750
X = 375
Answer: A
Question: Tough and Tricky questions: Distance/Rate.
On a reconnaissance mission, a state-of-the-art nuclear powered submarine traveled 600 miles to reposition itself in the proximity of an aircraft carrier. This journey would have taken 2 hour less if the submarine had traveled 10 miles per hour faster. What was the average speed, in miles per hour, for the actual journey?
A.20
B.40
C.60
D.50
Answer: D.50
Explanation: Say, if speed is 50, 600/50 = 12 hrs and 600/60 = 10 hrs (a reduction of 2 hr -> Correct answer)
Answer (D)
Question: After 57 liters of petrol were poured into the tank, it was still 5% empty. How much petrol must be poured into the tank in order to fill it?
A.7 liters
B.4 liters
C.3 liters
D.2 liters
Answer: C.3 liters
Explanation: 95% ----------- 57
5% ------------ ?
=> 3 liters
Answer: C
Question: A sum of money becomes Rs. 2200 after three years and Rs. 4400 after six years on compound interest. The sum is
A.Rs. 1400
B.Rs. 1100
C.Rs. 1000
D.Rs. 1200
Answer: B.Rs. 1100
Explanation: Explanation:
Let the sum be P and rate of interest be R% per annum.
Amount after 3 years = 2200
P(1 + R/100)T = 2200
P(1 + R/100)3 = 2200 --- ( 1)
Amount after 6 years = 4400
P(1+R/100)T = 4400
P(1 + R/100)6 = 4400 --- (2)
(2) ÷ (1) => [P(1+R/100)6]/[P(1+R/100)3] = 4400/2200 = 2
=> (1+R/100)3 = 2 (Substituting this value in equation 1)
=> P × 2 = 2200
P = 22002 = 1100
Answer: Option B
Question: The greater of two numbers is twice the less, and the sum of the numbers is 96. What are the numbers?
A.64
B.68
C.70
D.79
Answer: A.64
Explanation: Let x = the less number
2x = the greater number
The sum of the numbers is 96
x+2x=96
3x=96
x=32
2x=64
Option A
Question: The value of (2.75)3 - (2.00)3 - (0.75)3 is
A.12.375
B.6
C.9
D.8
Answer: A.12.375
Explanation: Explanation:
(2.75)3 - (2.00)3 - (0.75)3
a^3 + b^3 + c^3 = (a + b + c)(a^3 + b^3 + c^3 - ab - bc - ca)
If a + b + c = 0 then a^3 + b^3 + c^3 = 3abc
Hence 2.75 - 2.00 - 0.75 = 0
So, (2.75)3 - (2.00)3 - (0.75)3
= 3 * 2.75 * 2 * 0.75 = 3 * 1.5 * 2.75
= 4.5 * 2.75=12.375
A
Question: If a copier makes 10 copies every 5 seconds, then continues at this rate, how many minutes will it take to make 10,000 copies?
A.82.33
B.81.33
C.84.33
D.83.33
Answer: D.83.33
Explanation: 10 copies 5 seconds
10000 copies = (10000*5)/10 seconds
= 5000/60 minutes
= 83.33 minutes
Answer : D
Question: A cow leaps 8 leaps for every 3 leaps of a bull, but 6 leaps of the bull are equal to 4 leaps of the cow. What is the ratio of the speed of the cow to that of the bull?
A.4:1
B.1:1
C.3:2
D.4:5
Answer: A.4:1
Explanation: Given;
6 bull = 4 cow;
Or, bull/cow = 4/6;
Let cow's 1 leap = 6 meter and bulls 1 leap = 4 meter.
Then, ratio of speed of cow and bull = 6*8/4*3 = 4:1.''Answer: 4:1
Question: A certain automobile company’s best-selling model is the Speedster. The Speedster, like all of their other models, comes in coupe and convertible styles. 2/3 of the current inventory is Speedsters, of which 4/5 are convertibles. If there are 40 vehicles that are not Speedsters, how many Speedster convertibles are there?
A.30
B.64
C.60
D.70
Answer: B.64
Explanation: Total Vehicle = 2/3 of speedster + 1/3 of others.
Speedster convertibles = 2/3 total vehicle * 4 /5
Given : 1/3 constitutes 40 Vehicles. hence 2/3 constitutes 80
Speedster convertibls = 80 * 4/5 = 64
B
Question: A jar contains 8 marbles consisting of an equal number of red, green, and blue marbles. Four marbles are removed from the jar and discarded. What is the probability that only two colors will remain in the jar after the four marbles have been removed?
A.1/495
B.1/165
C.3/70
D.1/35
Answer: C.3/70
Explanation: Jar contains {4-red, 4-green, 4-blue} marbles. We are asked to find the probability that after removing 4 marbles only 2 colours remain in the jar, i.e., the probability of removing EITHER red, OR green, OR blue.
Sample space = 8C4 = 495.
Probability of choosing 4 red = 4C4/8C4 = 1/70.
Probability of choosing 4 green = 4C4/8C4 = 1/70.
Probability of choosing 4 blue = 4C4/8C4 = 1/70.
Required probability = 1+1+1/70 = 3/70 Ans (C).
Question: Jill invests $10000 in an account that pays an annual rate of 3.96%, compounding semi-annually. Approximately how much E does she have in her account after two years?
A.$10079.44
B.E=$10815.83
C.$12652.61
D.$14232.14
Answer: B.E=$10815.83
Explanation: PS. I guess one can use simple interest to solve cause the answer choices are quite spread between you can easily arrive at something near 8%
Hence B the answer
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. In how much time will the trains cross each other?
A.89/7 sec
B.80/7 sec
C.80/8 sec
D.89/7 sec
Answer: B.80/7 sec
Explanation: Relative speed = (54 + 72)* 5/18 = 7 * 5 = 35 mps.
The time required = d/s = (100 + 100 + 200)/35
= 400/35 = 80/7 sec.
Answer:B