RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Indu gave Bindu Rs.5000 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
A.8
B.2
C.9
D.5
Answer: A.8
Explanation: 5000
= D(100/4)2
D = 8
Answer: A
Question: The average weight of 25 boys sitting in a class had some value. A new boy added to them whose weight was 46 kg only. Due to his arrival, the average weight of all the boys decreased by 5 kg. Find the average weight of first 25 boys?
A.150
B.152
C.176
D.180
Answer: C.176
Explanation: 25x + 46 = 26(x – 5)
x = 176
C
Question: Find the number of bricks, each measuring 24 cm x 12 cm x 8 cm, required to construct a wall 24 m long, 8m high and 60 cm thick, if 10% of the wall is filled with mortar?
A.35000
B.45000
C.55000
D.65000
Answer: B.45000
Explanation: Explanation:
Volume of the wall = (2400 x 800 x 60) cm3
Volume of bricks = 90% of the volume of the wall
= [(90/100) x 2400 x 800 x 60] cm3
Volume of 1 brick = (24 x 12 x 8) cm3
Number of bricks = [(90/100) x (2400 x 800 x 60) ]/ (24 x 12 x 8) = 45000
Answer: B
Question: Excluding stoppages, the speed of a bus is 84 kmph and including stoppages, it is 70 kmph. For how many minutes does the bus stop per hour?
A.12 min
B.10 min
C.15 min
D.14 min
Answer: B.10 min
Explanation: Due to stoppages, it covers 14 km less.
Time taken to cover 14 km = (14/84 x 60) min = 10 min
Answer : B
Question: An express traveled at an average speed of 80 km/hr, stopping for 3 min after every 45 kn. How long did it take to reach its destination 480 km from the starting point?
A.5 hrs 21 min
B.4 hrs 21 min
C.6 hrs 41 min
D.6 hrs 27 min
Answer: D.6 hrs 27 min
Explanation: D
6 hrs 27 min
Time taken to cover 480 km = 480/80 = 6 hrs.
Number of stoppages = 480/45 - 1 = 9
Total time of stoppages = 3 * 9 = 27 min
Hence, total time taken = 6 hrs 27 min.
Question: What would be the compound interest on Rs.7700/- at 15 ¼% per year for 2 years compounded annually
A.2527.57
B.2257.57
C.2572.57
D.2752.57
Answer: A.2527.57
Explanation: Principal = Rs. 7700/-
time = 2 years
rate = 15 ¼%
Amount = P(1+R/100)n
= 7700 × (1 + 61/(4 × 100)2)
= 7700 × [(1 + 61/400)2]
= 7700 × [(461/400)2)]
= 7700 × 461/400 × 461/400
= 7700 × 1.1525 × 1.1525
= 7700 × 1.32825625
= 10227.573125
C.I = 10227.573125 - 7700 = 2527.57/-
Answer is A.
Question: Two letters from the word BARKHINT are selected at random. What is the probability that at least one of the selected letters is a consonant?
A.30/28
B.40/28
C.25/28
D.27/28
Answer: D.27/28
Explanation: There are 6 consonants and 2 vowels in BARKHINT .
probability that at least one of the selected letters is a consonant = 1 - (Probability of both vowels)
Probability of both vowels = 2C2/8C2 = 1/28
So,Answer is 1 - 1/28 = 27/28
Answer : D
Question: James purchased n items from a catalog for $12 each. Postage and handling charges consisted of $5 for the first item and $2 for each additional item. Which of the following gives the total dollar amount for Kim’s purchase, including postage and handling, in terms of n ?
A.13n + 3
B.13n + 4
C.13n + 2
D.13n + 6
Answer: A.13n + 3
Explanation: its A
n items for $12 each
total price $12n
postage and handling of $5 for 1st item and $2 for the rest
total postage and handling = $ [5+ (n-2)]
= $ n+3
total cost
12n+n+3 = 13n+3
Question: A bag contains 26 purple jellybeans, 15 green jellybeans, and 9 yellow jellybeans; these jellybeans are the only items in the bag. If a person picks a jellybean at random out of the bag, what is the probability that the jellybean will be green?
A.15%
B.20%
C.25%
D.30%
Answer: D.30%
Explanation: Probability of green beans = 15 / (26 + 15 + 9) = 3/10 = 30%
Answer is D
Question: If x is a positive integer, then the least value of x for which x! is divisible by 100 is?
Can someone please explain intuitively what the question is asking?
A.5
B.9
C.10
D.15
Answer: C.10
Explanation: In order x! to be divisible by 1,00, it should have at least 2 trailing zeros. A trailing 0 in factorial of a number is produced by 2 and 5 in it: 2*5 = 10. So, we need 10 to be in x! at least in power of 2.
5! = 120 has 1 trailing zeros.
10! will have 2 trailing zeros.
Answer: C.
Question: A can run a kilometer race in 4 1/2 min while B can run same race in 5 min. How many meters start can A give B in a kilometer race, so that the race mat end in a dead heat?
A.200 m
B.876 m
C.868 m
D.100 m
Answer: D.100 m
Explanation: A can give B (5 min - 4 1/2 min) = 30 sec start.
The distance covered by B in 5 min = 1000 m.
Distance covered in 30 sec = (1000 * 30)/300 = 100 m.
A can give B 100m start.
Answer:D
Question: If 2/3rd of the contents of a container evaporated on the 1st day. And 1/4th of the remaining evaporated on the second day. What part of the contents of the container is left at the end of the second day?
A.1/4
B.1/12
C.1/18
D.1/6
Answer: D.1/6
Explanation: After first day, 1/3 of the contents remain.
After second day,
(1/3) - (1/4(2/3)) = (1/3) - (1/6) = 1/6 of the contents remain
ANSWER:D
Question: A sum fetched a total simple interest of 4052.25 at the rate of 9 %.p.a. in 5 years. What is the sum?
A.9005
B.8925
C.2345
D.6474
Answer: A.9005
Explanation: Principal = (100 x 4052.25)/(9 x 5)
= 405225/45
= 9005.
ANSWER A
Question: Every day a certain bank calculates its average daily deposit for that calendar month up to and including that day. If on a randomly chosen day in June the sum of all deposits up to and including that day is a prime integer greater than 100, what is the probability that the average daily deposit up to and including that day contains fewer than 5 decimal places?
(A)
(B)
(C)
(D)
(E)
A.1/10
B.2/15
C.4/15
D.3/10
Answer: D.3/10
Explanation: average=p/d has less than 5 decimal places? Where p=prime>100 and d is the chosen day.
If the chosen day, d, is NOT of a type 2^n5^m (where n and m are nonnegative integers) then average=p/d will not be a terminating decimal and thus will have more than 5 decimal places.
How many such days are there of a type 2n5m: 1, 2, 4, 5, 8, 10, 16, 20, 25 (1=2^0∗5^0, 2=2^2, 4=2^2, 5, 8=2^3, 10=2∗5, 16=2^4, 20=22∗5, 2^5=52), total of 9 such days (1st of June, 4th of June, ...).
Now, does p divided by any of these d′s have fewer than 5 decimal places? Yes, as p/d∗10,000=integer for any such d (10,000 is divisible by all these numbers: 1, 2, 4, 5, 8, 10, 16, 20, 25).
So, there are 9 such days out of 30 in June: P=9/30=3/10 .
Answer: D.
Question: (3 x 10^4) + (2 x 10^3) + (4 x 10^2) =
A.302400
B.32400
C.30240
D.3240
Answer: B.32400
Explanation: When you multiply a number by 10 you just add a zero
=> 3 x 10^4 => add 4 zeros => 3 x 10^4 = 30000
=>2 x 10^3 = 2000
=> 4 x 10^2 = 400
=>3 x 10^4 + 2 x 10^3 + 4 x 10^2 = 30000 + 2000 + 400 = 32400
=> answer is B ( 32400)
Question: The ratio of the cost price and the selling price is 4:5. The profit percent is:
A.22%
B.31%
C.25%
D.30%
Answer: C.25%
Explanation: C
25%
Let C.P. = $ 4x. Then, S.P. = $ 5x
Gain = (5x - 4x) = $ x
Gain % = (x * 100)/ 4x = 25%.
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 6 years ago was 20 years. The present age of the husband is:
A.20 years
B.30 years
C.60 years
D.38 years
Answer: D.38 years
Explanation: D
38 years
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 6 x 2) years = 52 years.
Husband's present age = (90 - 52) years = 38 years.
Question: A and B together finish a wor in 20 days.They worked together for 15 days and then B left. Afer another 10 days,A finished the remaining work. In how many days A alone can finish the job?
A.30
B.40
C.50
D.60
Answer: B.40
Explanation: Explanation:
(A+B)'s 15 days work = (1/20 × 15) = ¾
Remaining work = (1 - ¾) = ¼
Now, ¼ work is done by A in 10 days.
Whole work will bedone by A in (10 × 4 = 40) days.
Answer: B
Question: In a camp,there is a meal for 140 men or 200 children.If 150 children have taken the meal,how many men will be catered to with the remaining meal ?
A.35
B.30
C.40
D.50
Answer: A.35
Explanation: Solution
There is a meal for 200 children. 150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children = 140 men
50 children =( 140/200x50)men= 35 men. Answer A
Question: The average of 65 numbers is 40. If two numbers, 40 and 60 are discarded, then the average of the remaining numbers is nearly
A.28.32
B.39
C.38.78
D.39.68
Answer: D.39.68
Explanation: Explanation :
Total sum of 63 numbers = (65 * 40) - (40+60) = 2600 - 100 = 2500
Average = 2457/63 = 39.68
Answer : D
Question: Tough and Tricky questions: Statistics.
Set X consists of prime numbers {3, 11, 7, K, 17, 19}. If integer W represents the product of all elements in set X and if 11W is an even number, what is the range of set X?
A. 14
B. 16
C. 17
D. 20
Answer: C. 17
Explanation: Since 11W = Even therefore W has to beEVENsince 11 is a odd integer (Even * Odd = Even)
Similarly, W is the product of all integers in set X But all integers in Set X are odd except the unknown K and since X contains only prime numbers, K has to equal to 2... ( 2 is the only even prime number and the product of all prime numbers in set X has to be Even, Even * Odd = Even)
Since you know value of K you can calculate the range = Largest integer in the set minus Smallest integer in the set = 19-2 =17
Answer is C
Question: If D is the least common multiple of 90,196, and 300, which of the following is NOT a factor of D?
A.600
B.700
C.900
D.2,100
Answer: A.600
Explanation: IF D is the least common multiple of 90,196 and 300, which of the following is NOT a factor of D?
A- 600
B- 700
C- 900
D- 2100
E- 4900
90 = 2 * 3 * 3 * 5
196 = 2 * 2 * 7 * 7
300 = 2 * 2 * 3 * 5 * 5
LCM = 2 * 2 * 3 * 3 * 5 * 5 * 7 * 7
(TWO 2, TWO 3, TWO 5, TWO 7)
600 = 2 * 2 * 2 * 3 * 5 * 5
700 = 2 * 2 * 5 * 5 * 7
900 = 2 * 2 * 3 * 3 * 5 * 5
2100 = 2 * 2 * 3 * 5 * 5 * 7
4900 = 2 * 2 * 5 * 5 * 7 * 7=A
Question: A train 330 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
A.18 sec
B.15 sec
C.4 sec
D.16 sec
Answer: A.18 sec
Explanation: Speed of train relative to man
= (60 + 6) km/hr
= 66 km/hr
[66 * 5/18] m/sec
= [55/3] m/sec.
Time taken to pass the man
= [330 * 3/55] sec
= 18 sec
Answer:A
Question: The cost of 20 kgs. of sugar is Rs.400. What is the cost of 12.5 kgs. of sugar?
A.Rs.200
B.Rs.150
C.Rs.250
D.Rs.125
Answer: C.Rs.250
Explanation: Explanation:
The cost of .153 kgs. of sugar = 400x 12.5/20 = Rs.250
Answer: Option C
Question: If a(a - 4) = 5 and b(b -4) = 5, where a ≠ b, then a + b =
A.−48
B.−4
C.4
D.9
Answer: C.4
Explanation: i.e. if a = -1 then b =5
or if a = 5 then b = -1
But in each case a+b = -1+5 = 4
Answer: option C
Question: A disease has infected an ant colony that consists ofworkersandsoldiers: 30% of the soldiers and 14% of theworkerswere infected. If that colony is inhabited by 7000 ants, out of which 1660 are infected, how manyworkersinhabit the colony?
A.1500
B.2500
C.2750
D.3000
Answer: C.2750
Explanation: From two question we get wo equations:
(1) 0,3s + 0,14w = 1660
(2) s + w = 7000
From (2) we get w=7000-s
In (1) 0,3s + 980-0,14s= 1660
0,16s=680
68000:16= 4250 =s
In (2) 4250 + w = 7000
w= 2750 C
Question: What is the unit digit in 7^105
A.7
B.0
C.2
D.3
Answer: A.7
Explanation: Explanation:
Unit digit in 7^105 = Unit digit in [ (7^4)26 x 7 ]
But, unit digit in (7^4)26 = 1
Unit digit in 7105 = (1 x 7) = 7
A
Question: How many factors does 34^2 have?
A.2
B.8
C.20
D.25
Answer: C.20
Explanation: 36^2 = 6*6*6*6 = 2^4*3^4
Total factors = (4+1)*(4+1) = 5*4 = 20
Answer C.
Question: If f(f(n)) + f(n) = 2n+3, f(0) = 1 then f(2013) = ?
A.2014
B.2088
C.270
D.1881
Answer: A.2014
Explanation: f (f(0)) + f(0) = 2(0) + 3 ⇒⇒ f(1) = 3-1 = 2, f(1) = 2
f(f(1)) + f(1) = 2(1) + 3 ⇒⇒ f(2) = 5-2 = 3, f(2) = 3
f(f(2)) + f(2) = 2(2) + 3 ⇒⇒ f(3) = 7-3 = 4, f(3) = 4
..............
f(2013) = 2014
Ans: A
Question: An equity analyst needs to select 4 stocks for the upcoming year and rank these securities in terms of their investment potential. If the analyst has narrowed down the list of potential stocks to 5, in how many ways can she choose and rank her top 4 picks?
A.210
B.350
C.110
D.120
Answer: D.120
Explanation: Number of ways of ch0osing 4 stocks = 5C4
Number of ways of ranking the chosen stocks = 4!
Hence total ways of chosing and ranking = 5C4 * 4! = 120
Correct Option: D
Question: The first half of a 600-mile trip was travelled in x hours and the second half in y hours. Which of the following is equal	to the average speed, in miles per hour, for the entire trip?
A.300/(x + y)
B.600/(x + y)
C.150/x + 150/y
D.300/x + 300/y
Answer: B.600/(x + y)
Explanation: Time taken to cover first half i.e 300 miles of a 600 mile trip = x
time taken to cover the second half i.e 300 miles of a 600 mile trip = y
Total time taken = x+y
Average speed for the entire trip =total distance /total time
=600/(x+y)
Answer B
Question: A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 12 minutes. How long will it take to go 5 km in stationary water?
A.40 minutes
B.1 hour
C.1 hour 25 min
D.1 hour 30 min
Answer: C.1 hour 25 min
Explanation: speed (upstream) =2/1 = 2 kmhr
speed (downstream)=1/(12/60)= 5 kmhr
speed in still water = 1/2 (2+5) = 3.5 kmhr
time taken in stationary = 5/3.5 = 1 hrs 25 min
ANSWER:C
Question: Three students appear at an examination of Mathematics. The probability of their success are 1/3, 1/4, 1/5 respectively. Find the probability of success of at least two.
A.1/6
B.2/5
C.3/4
D.3/5
Answer: A.1/6
Explanation: The probability of success of at least two students will involve the following possibilities.
The first two students are successful, the last two students are successful, the first and third students are successful and all the three students are successful.
Therefore, the required probability = 1/3 x 1/4 x 4/5 + 1/4 x 1/5 x 2/3 + 1/3 x 1/5 x 3/4 + 1/3 x 1/4 x 1/5 = 10/60 = 1/6
ANSWER:A
Question: In how many ways can a group of 7 men and 5 women be made out of a total of 10 men and 7 women?
A.2200
B.2520
C.2689
D.2540
Answer: B.2520
Explanation: We need to select 7 men from 10 men and 5 women from 7 women. Number of ways to do this= 10C7 × 7C5=2520B)
Question: A certain barrel, which is a right circular cylinder, is filled to capacity with 40 gallons of oil. The first barrel is poured into a second barrel, also a right circular cylinder, which is empty. The second barrel is twice as tall as the first barrel and has twice the diameter of the first barrel. If all of the oil in the first barrel is poured into the second barrel, how much empty capacity, in gallons, is left in the second barrel?
A.There is no empty capacity
B.100 gallons
C.280 gallons
D.700 gallons
Answer: C.280 gallons
Explanation: Radius of first cylinder=r, diameter=2r, height=h
Radius of second cylinder=2r, diameter=2d and height=2h
Volume of first cylinder=pie (r^2)*h=40
Volume of second cylinder=pie(2r^2)2h
Put the value of pie (r^2)*h=40 in the second cylinder,volume= pie (r^2)*4*2=40*8=320 gallons
Empty capacity=280 gallons
Answer C
Question: A can give B 100 meters start and C 300 meters start in a kilometer race. How much start can B give C in a kilometer race?
A.110.22 meters
B.111.22 meters
C.222.22 meters
D.333.22 meters
Answer: C.222.22 meters
Explanation: Explanation:
A runs 1000 meters while B runs 900 meters and C runs 700 meters.
Therefore, B runs 900 meters while C runs 700 meters.
So, the number of meters that C runs when B runs 1000 meters = (1000 x 700)/900 = 777.77 meters
Thus, B can give C (1000 - 777.77) = 222.22 meters start
Answer: C
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 25 hours respectively. The ratio of their speeds is?
A.4:5
B.5:3
C.4:4
D.4:8
Answer: B.5:3
Explanation: Let us name the trains A and B.
Then, (A's speed) : (B's speed)
= √b : √a = √25 : √9
= 5:3
Answer: B
Question: A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that exactly three bulbs are good?
A.20/68
B.20/63
C.20/62
D.20/61
Answer: B.20/63
Explanation: Required probability = (⁵C₃ . ⁴C₁)/⁹C₄ = (10 * 4)/126
= 20/63
Answer:B
Question: The cost of the paint is rs.40.00 per kg. if 1kg of paint covers 20sq.ft, how much will it cost to paint outside of a cube having 10 feet each side
A.Rs.1200
B.Rs.672
C.Rs.546
D.Rs.876
Answer: A.Rs.1200
Explanation: Explanation:
surface area of a cube= 6 x 10^2 = 600s q.ft
quantity of paint required=(600/20)=30 kg
cost of painting= 40 x 30 = Rs.1200
Answer: A
Question: When tossed, a certain six-sided die has an equal probability of landing on any of the six sides. If the die is tossed 3 times, what is the probability that it will land on the same side each time?
A.1/6
B.1/12
C.1/36
D.1/72
Answer: C.1/36
Explanation: On the first toss, the die will land on one of the sides.
On the second toss, the probability of landing on the same side is 1/6.
On the third toss, the probability of landing on the same side is 1/6.
P(same side three times)=1/6*1/6=1/36.
The answer is C.
Question: A cube of edge 16cm is immersed completely in a rectangular vessel containing water. If the dimensions of the base of vessel are 20cm * 15cm , find the rise in water level?
A.6cm
B.8.25cm
C.13.65cm
D.15.12cm
Answer: C.13.65cm
Explanation: Increase in volume = volume of the cube = 16*16*16 cm^3
Rise in water level = volume / area = 16*16*16/20*15 = 13.65cm
Answer is C
Question: Walking at 8KMPH From Point Q to Point railway station, mike will miss the train by 5 minutes. If he walks at 10KMPH he will reach the station by 5 minutes early.What is the distance between Point Q to Railway station?
A.A)9KM
B.B)6.66KM
C.C)7.25KM
D.D)12.40KM
Answer: B.B)6.66KM
Explanation: Since time differences given are in minutes so let's convert speed in Km per minute
8 kmph = 8/60 km per minute = (2/15) km per minute
10 kmph = 10/60 km per minute = (1/6) km per minute
Let, Time of train to depart from station = t minutes
Distance between Point Q and Railway Station = Speed*Time = (2/15)*(t+5)
Distance between Point Q and Railway Station = Speed*Time = (1/6)*(t-5)
i.e. (2/15)*(t+5) = (1/6)*(t-5)
i.e. 12t+60 = 15t - 75
i.e. 3t = 135
i.e. t = 45 minutes
i.e. Distance = (1/6)*(t-5) = (1/6)*(45-5) = 40/6 = 20/3 Km = 6.66 Km
Answer: Option B
Question: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
A.1/2
B.1/2
C.8/15
D.9/20
Answer: D.9/20
Explanation: Explanation :
Here, S = {1, 2, 3, 4, ...., 19, 20}.
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
P(E) = n(E)/n(S) = 9/20
Answer : D
Question: A box contains nine bulbs out of which 3 are defective. If four bulbs are chosen at random, find the probability that atleast one bulb is good.
A.125/167
B.125/186
C.83/84
D.125/186
Answer: C.83/84
Explanation: Required probability
= 1 - 1/84
= 83/84
Answer: C
Question: If you roll a fair-sided die twice, what is the probability of getting a (3,3 ) double?
A.1/2!
B.1/4!
C.1/3!
D.1/5!
Answer: C.1/3!
Explanation: total no. in two dice (1,1) ,(2,2) .....(6,)
Total number of events= 6*6
Total events of getting same pair(3, 3) = 6
Probability= 6/6*6= 1/6=1/3!
C
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions
A.700
B.704
C.704
D.706
Answer: B.704
Explanation: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4 = 70400 cm = 704 m
Answer: Option B
Question: Howmany three digits odd numbers can be formed using the digits 4,5,6,7,8,9 (repetition of digits not allowed)
A.60
B.75
C.65
D.55
Answer: A.60
Explanation: There are 3 ways of filling the unit place of the number. The remaining ten's and 100's place canbe filled in 5ways and
4 ways respectively. Required number of numbers =3x5x4=60. Ans: A
Question: If the quantity 6^2+ 6^4 + 6^6 is written as (a + b)(a – b), in which both a and b are integers, which of the following could be the value of b?
A.52
B.15
C.36
D.22
Answer: C.36
Explanation: (a+b)(a-b) = a^2 - b^2
6^2+ 6^4 + 6^6 = 6^2 (1+6^2+6^4)
if the above expression is solved even then every term of the expression will remain a multiple of 6^2 which is out of parenthesis
hence, b must be a multiple of 6^2 i.e. 36
Answer: option C
Question: What does RBI regulate through Open Market Operation Transactions?
A.Flow of Foreign Direct Investment
B.What does RBI regulate through Open Market Operation Transactions?
C.Borrowing powers of the banks
D.Liquidity in economy
Answer: D.Liquidity in economy
Explanation: Explanation:
Outright purchase and Repurchase agreement are the two traditional type of OMO's used by RBI.
ANSWER: D
Question: Which of the following correctly lists the data sets in order of least to greatest standard deviation?
I. 12, 13, 15, 12, 14, 14
II. 32, 32, 32, 32, 32, 32
III. 37, 48, 59, 40, 41, 42
A.I, II, III
B.I, III, II
C.II, I, III
D.II, III, I
Answer: C.II, I, III
Explanation: (D) To answer a question such as this, you DO NOT need to know how to calculate standard deviation. You simply need to understand how to compare standard deviations of different sets. The more spread out the numbers are, the greater the standard deviation will be. Even one or two numbers that are much larger or smaller than the others will cause the standard deviation to rise drastically.
correct order from least to greatest standard deviation is II, I. III
C
Question: A train 210 metres long is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2 km per hour in :
A.28 sec
B.32 sec
C.36 sec
D.38 sec
Answer: A.28 sec
Explanation: Relative speed = (25+2) km/hr = 27 km/hr
= (27×5/18) m/sec = 15/2 m/sec.
Time taken by the train to pass the man =(210×2/15) sec=28 sec
ANSWER :A
Question: Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 2 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is?
A.16 : 5
B.14 : 5
C.16 : 7
D.19 : 5
Answer: D.19 : 5
Explanation: Explanation:
Quantity of alcohol in vessel P = 62.5/100 * 2 = 5/4 litres
Quantity of alcohol in vessel Q = 87.5/100 * 4 = 7/2 litres
Quantity of alcohol in the mixture formed = 5/4 + 7/2 = 19/4 = 4.75 litres
As 6 litres of mixture is formed, ratio of alcohol and water in the mixture formed = 4.75 : 1.25 = 19 : 5
Answer: Option D
Question: A pipe can fill a cistern in 7 minutes whereas the cistern when fill can be emptied by a leak in 14 minutes. When both pipes are opened, find when the cistern will be full?
A.17
B.16
C.70
D.14
Answer: D.14
Explanation: 1/7 - 1/14 = 1/14
14 minutes
Answer: D
Question: Due to an increase in 30% in the price of eggs, 3 eggs less are available for Rs. 7.80. Find the present rate of eggs per dozen.
A.Rs. 9.36
B.Rs. 10.36
C.Rs. 11.36
D.Rs. 12.36
Answer: A.Rs. 9.36
Explanation: Explanation:
Let the original price per egg be Rs x
Then increased price will be,
(130/100)x
=>7.80/x- 7.80/ 130/100x =3
=>x=0.6
Actual price was Rs 0.6,
Present price per dozen will be
Rs.(12*130/100*0.6)=Rs.9.36
(130100x)=>7.80xâˆ’7.80130100x=3=>7.80xâˆ’780130x=3=>390x=234=>x=0.6Actual price was Rs 0.6Present price per dozen will beRs.(12âˆ—130100âˆ—0.6)=Rs.9.36
ANSWER IS A
Question: If the average (arithmetic mean) of three consecutive integers is 21, then the product of the greatest and least integer is
A.443
B.442
C.440
D.444
Answer: C.440
Explanation: n = smallest number
n+2 = largest number
(n + n + 2)/2 = 21
=> (2n+2)/2 = 21
=> n + 1 = 21
=> n = 20
So Product of n and n+2 = (20)(22)
= 440
Answer - C
Question: In expressing a length 81.469 km as nearly as possible with three significant digits, find the percentage error?
A.0.075%
B.0.156%
C.0.034%
D.0.038%
Answer: D.0.038%
Explanation: Error = 81.5-81.469 = 0.031
Required percentage = (0.031/81.469)*100 = 0.038%
Answer is D