RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If a quarter kg of onions costs 60 paise, how many paise will 100 gm cost?
A.24 paise
B.65 paise
C.56 paise
D.87 paise
Answer: A.24 paise
Explanation: Explanation:
Let the required cost be x paise.
Less weight, Less cost (Direct proportion)
250 : 100 : : 60 : x
250 * x = (100 * 60)
x = (100 * 60) / 250
x = 24
ANSWER: A
Question: In assembling a Bluetooth device, a factory uses one of two kinds of modules. One module costs $10 and the other one, that is cheaper, costs $6. The factory holds a $80 worth stock of 12 modules. How many of the modules in the stock are of the cheaper kind?
A.20
B.25
C.10
D.30
Answer: C.10
Explanation: So the number of $6 modules must be 10 so that the leftover 2 modules are of $10 which will give a total value $80. 10*6+2*10 = 60+20=80
Answer : C
Question: If x/y = 9/8, Then (8x + 7y) / (8x â€“ 7y) = ?
A.8
B.7
C.10
D.9
Answer: A.8
Explanation: Answer
Dividing numerator as well as denominator by y, we get
Given Exp. = (8x + 7y) / (8x â€“ 7y) = (8x/y + 7) / (8x/y â€“ 7)
Since x/y = 9/8
this implies that
=[(8*9)/8 +7]/[(8*9)/8 -7)]
= (9+ 7) / (9 - 7)
= 8
Option: A
Question: There are 6 periods in each working day of a school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period?
A.1023
B.6000
C.1980
D.1800
Answer: D.1800
Explanation: 5 subjects can be arranged in 6 periods in 6P5 ways.
Any of the 5 subjects can be organized in the remaining period (5C1 ways).
Two subjects are alike in each of the arrangement. So we need to divide by 2! to avoid overcounting.
Total number of arrangements
= 6P5× 5C1 /2!=1800
ANSWER D 1800
Question: A patient was given four pills which he is required to take one after every thirty-five minutes.
How long can the pills run for him?
A.1 hour and 30 minutes
B.1 hour and 20 minutes
C.1 hour and 45 minutes
D.1 hour and 15 minutes
Answer: C.1 hour and 45 minutes
Explanation: He took the first pill at the zero minute.
He took the second pill after 20 minutes = 0+35=35
He took the third pill after 20 minutes = 35+35=70
He took the fourth pill after 20 minutes = 70+35=105
Then it will last for 105 minutes or an hour and 45 minutes.
Answer C
Question: In a kilometer race, A beats B by 80 meters or 8 seconds. What time does A take to complete the race?
A.77 sec
B.92 sec
C.67 sec
D.16 sec
Answer: B.92 sec
Explanation: Time taken by B run 1000 meters = (1000 * 8)/80 = 100 sec.
Time taken by A = 100 - 8 = 92 sec.Answer: B
Question: At what price must an article costing Rs.47.50 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price?
A.62.5
B.62.9
C.52.1
D.62.6
Answer: A.62.5
Explanation: CP = 47.50
SP = 47.50*(125/100) = 59.375
MP*(95/100) = 59.375
MP = 62.5
Answer: A
Question: The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 36. What is the difference between the two digits of that number?
A.Difference is 3
B.Difference is 4
C.Difference is 9
D.Cannot be determined
Answer: B.Difference is 4
Explanation: EXPLANATION
Let the ten’s digit be x and unit’s digit be y.
Then, (10x + y) – (10y + x) = 36
9(x – y) = 36
x – y = 4.
Answer B
Question: The sum of two numbers is 22. Five times one number is equal to 6 times the other. The bigger of the two numbers is
A.10
B.11
C.12
D.16
Answer: C.12
Explanation: Solution
Let the number be x and (22-x)
‹=› 11x = 132
‹=›x = 12
So,the numbers are 12&10.
Answer C
Question: Jackson invested $500,000, dividing it all unequally between Account P and Account Q. At the end of the year, it turned out that Account P had earned 12% interest and Account Q had earned 25% interest. If Jackson earned a total of $60,000 in interest between the two accounts, which of the following is approximately the amount he put in account P?
A.$115,384
B.$120,000
C.$121,072
D.$124,129
Answer: C.$121,072
Explanation: x be the amount invested in account P
0.12*x +(500000-x)*0.25=60,000
15000/.13=x
x=1500000/13=11...=$121,072
hence answer is C
Question: Find the principle on a certain sum of money at 5% per annum for 5 years if the amount being Rs.1120?
A.896
B.1067
C.1977
D.1056
Answer: A.896
Explanation: 1120 = P [1 + (5*5)/100]
P= 896
Answer: A
Question: An engagement team consists of a project manager, team leader, and four consultants. There are 5 candidates for the position of project manager, 8 candidates for the position of team leader, and 7 candidates for the 4 consultant slots. If 2 out of 7 consultants refuse to be on the same team, how many different teams are possible?
A.850
B.900
C.980
D.1000
Answer: D.1000
Explanation: Answer= Total number combinations - Total number of combinations with constraints
Total number of combinations = 5C1*8C1*7C4= 1400
Total number of combinations with constraints = 5C1*8C1*5C2=400
Answer=1400-400=1000
ANSWER: D
Question: From a group of 3 signers and 3 comedians, a show organizer might select two singers and two comedians to appear one after another in the show, how many different ways an organizer can arrange the performers in the show.
A.221
B.216
C.312
D.62
Answer: B.216
Explanation: Ways to select 2 Singers out of 3 = 3C2 = 3
Ways to select 2 Comedians out of 3 = 3C2 = 3
Ways to rearrange 4 performers = !4 = 24
Total combinations = 3*3*24=216.
ANS:B
Question: How many different arrangements of A, B, C, D, and E are possible where B and D is not adjacent to E?
A.96
B.72
C.32
D.30
Answer: B.72
Explanation: So you have A,B,C,D,E
five possible ways to arrange it = 5! = 120
A,B,C,(DE) = 4! = 24 x 2 = 48
120 -48 =72 possible ways
B
Question: The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).?
A.178.27 cm
B.178.29 cm
C.978.29 cm
D.178.89 cm
Answer: B.178.29 cm
Explanation: Calculated average height of 35 boys = 180 cm.
Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm - 166 cm + 106 cm
= 180 * 35 cm - 166 cm + 106 cm/35 = 180 cm - 60 /35 cm
= 180 cm - 1.71 cm = 178.29 cm.
Answer: B
Question: An error 3% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:
A.6.05
B.6.09
C.6.03
D.6.02
Answer: B.6.09
Explanation: Explanation:
100 cm is read as 103 cm.
A1 =(100 × 100)cm2 = 10000
and A2= (103 × 103)cm2= 10609
(A2 - A1) = 10609-10000 = 609
=> 609/10000*100 =6.09
Answer : B
Question: The probability of a team winning a match given Matt is playing the match is 0.70. The probability of the team winning a match given Matt is not playing the match is 0.5. The probability of Matt playing any match is 0.9.
If it is known that the team has won the last match, what is the probability that Matt played the match?
A.A)0.8321
B.B)0.7
C.C)0.8571
D.D)0.926
Answer: D.D)0.926
Explanation: Out of 100 matches:
Matt is plays in 90 and not plays in 10.
Out of 90 matches Matt plays in, team wins 0.70*90 = 63.
Out of 10 matches Matt does not play in, team wins 0.5*10 = 5.
So, out of 100 matches 63 + 5 = 68 are won.
It is known that the team has won the last match. Out of 68 matches won, Matt is in 63: 63/68 = 0.926...
Answer: D.
Question: A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:
A.22
B.73
C.99
D.42
Answer: D.42
Explanation: Explanation:
Just go in reverse order.
Check the options with th subtracting 18 from each option for getting reverse number.
42 – 18 = 24 (which is in reverse).
So answer is 42.
Answer D
Question: An equilateral triangle of sides 3 inch each is given. How many equilateral triangles of side 1 inch can be formed from it?
A.8
B.9
C.10
D.11
Answer: B.9
Explanation: volume of equilateral triangle = 1/2*bh (b base, h height)
volume of 3 inch Eq tri =1/2*3*20598 = 1/2*1*.866*N(volume of 1 inch eq tri and N is no of 1 inch triangles9
so ans is 9 ANSWER:B
Question: While working alone at their respective constant rates, server P uploads 480 files in 4 hours and server Y uploads 480 files in 8 hours. If all files uploaded by these servers are the same size, how long would it take the two servers, working at the same time and at their respective constant rates, to process a total of 480 files?
A. 2 hr
B. 2hr 20 min
C. 2hr 40 min
D. 5 hr 40 min
Answer: C. 2hr 40 min
Explanation: Server P processes 480/4 files per hour = 120 per hour
Server Y processes 180/8 files per hour = 60 per hour
Total files processed per hour when P and Y work together = 120+60 per hour = 180 files per hour
480/180 = 2 2/3 hours=C
Question: In a flower shop there were 10 flowers in each bouquet. If the seller has doubled the number of flowers in each bouquet then the new average of flowers in each bouque is
A.12
B.20
C.18
D.19
Answer: B.20
Explanation: Answer
Now required average
= old average x Multiplicand
= 10 x 2 = 20
Correct Option: B
Question: In certain year in Country C, x sets of twins and y sets of triplets were born. If there were z total babies born in Country C in this year, and x and y were both greater than 0, which of the following represents the fraction W of all babies born who were NOT part of a set of twins or triplets?
A.z - 2x - 3y
B.(2x+3y)/z
C.(x+y)/z
D.1 - (2x+3y)/z
Answer: D.1 - (2x+3y)/z
Explanation: X set of twins implies 2x babies of twin category.
Y set of triplets means 3y babies of triplet category.
Let K be the babies other than twin or triplet category.
Total babies = z = 2x+3y+k.
or K=Z-(2x+3y)
=> Fraction of babies other than twin or triplet categories = K/Z = Z-(2x+3y)/Z.
W= 1- (2x+3y)/Z. Hence answer is D.
Question: Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years?
A.306.78
B.306.79
C.306.04
D.306.18
Answer: C.306.04
Explanation: A = 5000(51/50)3
= 5306.04
5000
-----------
306.04
Answer: C
Question: A sum of $500 amounts to 600 in 2 years at simple interest. If the interest rate is increased by 10% it would amount to how much ?
A.$500
B.$700
C.$800
D.$600
Answer: B.$700
Explanation: S.I = 600-500 = 100
P = $500
T = 2 years
R = 100*100 / 500*2 = 10%
New rate = 10+10 =20%
New S.I. = 500*20*2/100 = $200
New amount = 500+200 = $700
Answer is B
Question: Find the principle on a certain sum of money at 5% per annum for 3 1/5 years if the amount being Rs.870?
A.Rs.700
B.Rs.780
C.Rs.750
D.Rs.1000
Answer: C.Rs.750
Explanation: Explanation:
870 = P [1 + (5*16/5)/100]
P= 750
Answer: Option C
Question: The least among the following is:
A.0.2
B.1 ÷ 0.2
C.0.2 (power 2)
D.22/7
Answer: C.0.2 (power 2)
Explanation: 1 ÷ 0.2 = 1/0.2 =10/2= 5;
22/7 = 3.14;
(0.2)(power 2) = 0.04;
0.04 < 1 < 3.14 <5.
Since 0.04 is the least, so (0.2)2 is the least.
Answer is C.
Question: A boat running downstream covers a distance of 24 km in 3 hours while for covering the same distance upstream,it takes 4 hours.What is the speed of the boat in still water ?
A.4 km/hr
B.6 km/hr
C.8 km/hr
D.7 km/hr
Answer: D.7 km/hr
Explanation: Solution
Rate downstream =(24/3) kmph = 8 kmph, Rate upstream =(24/4) = 6 kmph.
∴ Speed in still water =1/2(8+6) kmph = 7 kmph.
Answer D
Question: Arnold and Danny are two twin brothers that are celebrating their birthday. The product of their ages today is smaller by 9 from the product of their ages a year from today. What is their age today?
A.2.
B.4.
C.5.
D.7
Answer: B.4.
Explanation: ad = (a+1) (d+1) -9
0= a+d-8
a+d = 8
a=d (as they are twin brothers)
a=d=4
B is the answer
Question: A company conducted a survey about its two brands, A and B. x percent of respondents liked product A, (x – 20) percent liked product B, 23 percent liked both products, and 23 percent liked neither product. What is the minimum number F of people surveyed by the company?
A.46
B.80
C.F=90
D.F=100
Answer: D.F=100
Explanation: 100 = x + x - 20 + 23 - 23
x = 60,
So, Product A = 60%, Product B = 40%, Both = 23%, Neither = 23%
23% of the total no. of people should be an integer. So, A,BC are out.
60% of D and 40% of D are both integers. So, D satisfies all conditions.
So, answer is D.
Question: The product of all prime numbers less than or equal to nine are?
A.210
B.125
C.15
D.55
Answer: A.210
Explanation: A)
Question: 7386038 is divisible by
A.3
B.4
C.9
D.11
Answer: D.11
Explanation: Explanation:
The given number is 7386038.
The sum of the digits at even places is = 3+ 6+ 3=12.
The sum of the digits at odd places is = 7+ 8+ 0+ 8 = 23.
The difference is given by 23-12 = 11
Answer: D
Question: Two, trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:
A.2:3
B.4:3
C.7:3
D.9:3
Answer: B.4:3
Explanation: Let us name the trains as A and B. Then,
(A's speed) : (B's speed) = b : a = 16 : 9 = 4 : 3.
Question: A town in California fines residents who do not pay their property taxes on time. All residents must pay their taxes before July 1st for that calendar year or face the following fine structure: For the first month the taxes are overdue (that would be any payment made on July 1st through July 31st), the total fine is 3% of the original tax bill; for each additional month that the taxes are overdue, the total fine is increased by $600 or doubled, whichever results in the lesser amount. What is the total fine for a resident of that town who originally owed $20,000 in property taxes, but did not pay until October 15th?
A.$1,400
B.$1,800
C.$2,400
D.$21,400
Answer: C.$2,400
Explanation: Original amount = 20,000
Fine for July = 20,000 * 3% = 600
Fine for August = lesser of the 2 , 600+600= 1200 or 600*2=1200 . Pick 1200
Fine for September = 1200+600=1800 or 1200*2 = 2400. Pick 1800
Fine for October = 1800+600=2400 or 1800*2 = 3600. Pick 2400.
The wording of the question should be have been clearer as total fines should be = 2400+1800+1200+400 = 5800 and NOT 2400.
2400 is the fine ONLY for the month of October!
C
Question: The difference between compound interest and simple interest on a certain amount of money at 5% per annum for 2 years is 20. Find the sum :
A.4500
B.7500
C.5000
D.8000
Answer: D.8000
Explanation: Sol.(d) Let the sum be 100.
Therefore, SI = 100×5×2100=10100×5×2100=10
and CI = 100(1+5100)2−100100(1+5100)2−100
∴ =100×21×2120×20−100=414=100×21×2120×20−100=414
Difference of CI and SI = 41⁄4 - 10 = 1⁄4
If the difference is 1⁄4 , the sum = 100
=> If the difference is 20, the sum
= 400 × 20 = 8000 Answer D
Question: Difference between the length &breadth of a rectangle is 20 m. If its perimeter is 206 m, then its area is?
A.2400 m^2
B.2500 m^2
C.2400 m^2
D.2560 m^2
Answer: C.2400 m^2
Explanation: Solving the two equations, we get: l = 60 and b = 40.
Area = (l x b) = (60 x 40) m2 = 2400 m^2
C
Question: The sum of ages of 4 girls born at the intervals of 3 years each is 50 years. What is the age of the youngest girl?
A.years
B.years
C.years
D.years
Answer: A.years
Explanation: Let the ages of children be x, (x + 3), (x + 6), (x + 9) years.
Then, x + (x + 3) + (x + 6) + (x + 9) = 50
4x = 32
x = 8.
Age of the youngest child = x = 4 years.
A)
Question: The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?
A.1
B.3
C.4
D.2
Answer: D.2
Explanation: Let the sides of the rectangle be l and b respectively.
From the given data,
(l2 + b2) = (1 + 108 1/3 %)lb
=> l2 + b2 = (1 + 325/3 * 1/100)lb
= (1 + 13/12)lb
= 25/12 lb
=> (l2 + b2)/lb = 25/12
12(l2 + b2) = 25lb
Adding 24lb on both sides
12l2 + 12b2 + 24lb = 49lb
12(l2 + b2 + 2lb) = 49lb
but 2(l + b) = 28 => l + b = 14
12(l + b)2 = 49lb
=> 12(14)2 = 49lb
=> lb = 48
Since l + b = 14, l = 8 and b = 6
l - b = 8 - 6 = 2m.
Answer: Option D
Question: In one day, Juan sends Keith three times as many messages as he sends Laurence, and Laurence sends Missy 5 times as many messages as he receives from Juan. If Missy received 25 messages from Laurence, how many messages does Keith receive from Juan?
A.3
B.12
C.15
D.18
Answer: C.15
Explanation: Juan --> Laurence = x messages;
Juan --> Keith = 3x messages (Juan sends Keith three times as many messages as he sends Laurence);
Laurence --> Missy = 5x =25 (Laurence sends Missy 5 times as many messages as he receives from Juan).
5x =25 --> x = 5 --> 3x = 15.
Answer: C.
Question: 6 women can do 75 unit of work in 8 days by working 5hr/day in how many days 4 women do 30 units of work by working 8hr/day
A.3
B.4
C.5
D.6
Answer: A.3
Explanation: (6x8x5)/75=(Ax4x8)/30
A=3
ANSWER:A
Question: In country Z, 10% of the people do not have a university diploma but have the job of their choice, and 25% of the people who do not have the job of their choice have a university diploma. If 20% of the people have the job of their choice, what percent of the people have a university diploma?
A.30%
B.45%
C.55%
D.65%
Answer: A.30%
Explanation: Setting up a matrix is how I solve this one.
Diploma No Diploma Totals
Job of Choice w/Diploma
Job of Choice w/o Diploma = 10%
Job of Choice Total = 20%
Not Job of Choice with Diploma =.25X
Not Job of Choice w/o Diploma= .75X
Total Not Job of Choice = X
Total with Diploma
Total without Diploma
Total citizen = 100
If 20% of people have their job of choice, then 80% of people do NOT have their job of choice. 25% of 80% = 20%. We can also see that 10% of the people have their job of choice and a diploma (20%-10%=10%). 10% + 20% = 30%. Therefore 30% of the people in Country Z have a diploma.
Ans A
Question: The average height of 6 people is 67 inches. When Robert's height is included, the average increases by 2 inches. How tall is Robert in inches?
A.81
B.72
C.69
D.84
Answer: A.81
Explanation: Total height of 6 people = 6*67 = 402
Total height of 7 people = 7*69 = 483
Robert's height = 483-402 = 81 inches
Answer is A
Question: A card game called “high-low” divides a deck of 52 playing cards into 2 types, “high” cards and “low” cards. There are an equal number of “high” cards and “low” cards in the deck and “high” cards are worth 2 points, while “low” cards are worth 1 point. If you draw cards one at a time, how many ways can you draw “high” and “low” cards to earn 7 points if you must draw exactly 5 “low” cards?
A.6
B.2
C.3
D.4
Answer: A.6
Explanation: Great question Ravih. This is a permutations problem (order matters) with repeating elements. Given thatlowcards are worth 1 pt andhigh cards2 pts, and you must draw 3 low cards, we know that you must also draw 1 high card. The formula for permutations problems with repeating elements isN!/A!B!...where N represents the number of elements in the group and A, B, etc. represent the number of times that repeating elements are repeated. Here there are 4 elements and thelowcard is repeated 3 times. As a result, the formula is:
6!/5! which represents (6*5*4*3*2*1)/(5*4*3*2*1) which simplifies to just 6, giving you answer A.
Question: Lewis must answer 7 out of 10 questions on an examination. If at least 3 of the first 5 questions must be answered, how many possible combinations of 7 questions are available to lewis?
A.110
B.100
C.90
D.120
Answer: A.110
Explanation: as there is ONLY one possiblity of choosing 7 out of 10, while choosing less than 3 in first five
choose 2 in first 5 and all 5 from later half..
ways = 5C2 = 10..
total ways = 10C3 = 120
ans = 120-10 = 110
A
Question: A boat can move upstream at 25 kmph and downstream at 35 kmph, then the speed of the current is?
A.5
B.4
C.3
D.26
Answer: A.5
Explanation: US = 25
DS = 35
M = (35 - 25)/2 = 5
Answer: A
Question: An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
A.16 2/8%
B.16 1/3%
C.96 2/3%
D.16 2/3%
Answer: D.16 2/3%
Explanation: 600 ---- 100
100 ---- ? => 16 2/3%
Answer: D
Question: A total of 30 percent of the geese included in a certain migration study were male. If some of the geese migrated during the study and 20 percent of the migrating geese were male, what was the ratio of the migration rate for the male geese to the migration rate for the female geese? [Migration rate for geese of a certain sex = (number of geese of that sex migrating) / (total number of geese of that sex)]
A.1/4
B.7/12
C.2/3
D.7/8
Answer: B.7/12
Explanation: Let there be g geese, of which 0.3g are male and 0.7g are female
Lets say m geese migrated, 0.2m are male and 0.8m are female
Migration Rate Male = 0.2m / 0.3g = (2/3)*(m/g)
Migration Rate Female = 0.8m / 0.7g = (8/7)*(m/g)
Ratio of migration rates = (2/3) / (8/7) = 7/12
Answer is (B)
Question: In a certain game, a player begins with a bag containing tiles numbered 3 through 10, each of which has an equal probability of being selected. The player draws one tile. If the tile is even, the player stops. If not, the player draws another tile without replacing the first. If this second tile is even, the player stops. If not, the player draws a third tile—without replacing either of the first two tiles—and then stops. What is the probability that at the conclusion of the game, the sum of the tiles that the player has drawn is odd?
A.5/18
B.13/36
C.3/8
D.5/8
Answer: A.5/18
Explanation: player begins with containing tiles 1 to 10 and have equal probability of selecting means
Proabability of selecting one number =1/10. here 5 even numbers and 5 odd numbers are there.
Next , player draws one title , if number is even player stops or otherwise title is odd without replacement
player draws second title.
If second title is even , player stops or title is odd without replacement player draws third title.
in third title , without replacement of first and second title, player draws and stops it.
the sum of tilte probability is odd. here two conditions are possible.
1st condition is
1st title is odd+ 2nd title is even stops= probability of selecting one title is 1/10*5c1.
Here are we are not selecting 1st condition as even stops because sum of tile is odd.
Here 5 odd numbers are there we can select 1out of 5 odd numbers.
without replacement of fist we select second tilte is even. is 5/10*5c1/9c1.
here we are selecting one number out of remaining 9 numbers. so probability is 5/18.
we are selecting 1 even number out of 5.
2nd condition is 1stodd without replacement,2nd odd without replacement and 3rd one also odd to get odd as sum of title.
Then probability is 5/10*4/9*3/8=1/12.
Finally sum of probability of two conditions is 5/18+1/12
=5/18.
so option A is correct.
Question: At a certain amateur bands rock show the ratio of freaks to nerds to geeks is 1:2:3. If these are the only types of people in the crowd, and each person in the crowd has the same chance of yelling rock on!, what are the chances that the next person who yellsrock on!will be a nerds?
A.1
B.1/2
C.1/4
D.1/3
Answer: D.1/3
Explanation: Another approach is to assign some nice values for the number of freaks, nerds and geeks.
Given: the ratio of freaks to nerds to geeks is 1:2:3
So, let's say there is: 1 freak, 2 nerds and 3 geeks for a TOTAL of 6 people.
P(next person who yells rock on!is a nerds) = (# of nerds in the crowd)/(TOTAL # of people in the crowd)
=2/6
= 1/3
Answer:
D