RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What is the median from the below series 90, 92, 93, 88, 95, 88, 97, 87, and 98
A.76
B.79
C.92
D.94
Answer: C.92
Explanation: Ordering the data from least to greatest, we get:
87, 88, 88, 90, 92, 93, 95, 96, 98
The median quiz score was 92. (Four quiz scores were higher than 92 and four were lower.)
C
Question: A rectangle having length 140 cm and width 40 cm. If the length of the rectangle is increased by thirty percent then how much percent the breadth should be decreased so as to maintain the same area.
A.17.64%
B.33.33%
C.40%
D.75%
Answer: A.17.64%
Explanation: Explanation :
Solution: (30/(140+30) * 100)% = 17.64%
Answer : A
Question: A number increased by 30% gives 650. The number is?
A.200
B.300
C.400
D.500
Answer: D.500
Explanation: Formula = TOTAL=100% ,INCREASE = "+" DECREASE= "-"
A number means = 100 %
That same number increased by 30 % = 130 %
130 % -------> 650 (130 Ã— 5 = 650)
100 % -------> 400 (100 Ã— 5 = 500)
Option 'D'
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 sec. What is the length of the fast train?
A.23 m
B.23 2/9 m
C.27 m
D.27 7/9 m
Answer: D.27 7/9 m
Explanation: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5 = 250/9 = 27 7/9 m.
ANSWER:D
Question: There are two inlets and one outlet to a cistern. One of the inlets takes 5/2hours to fill up the cistern and the other inlet takes twice as much time to fill up the same cistern. Both of the inlets are turned on at 9:00 AM with the cistern completely empty, and at 10:30AM, the outlet is turned on and it takes 1 more hour to fill the cistern completely. How much time does the outlet working alone takes to empty the cistern when the cistern is full?
A.2 hours
B.2.5 hours
C.3 hours
D.3.5 hours
Answer: A.2 hours
Explanation: The combined inflow rate of the two inlets is 2/5 + 1/5 = 3/5 cistern/hour. Thus, working together, it takes 5/3 hours (time is reciprocal of rate) to fill the cistern.
From 9:00 AM to 10:30 AM, so in 1.5=3/2 hours, the inlet pipes will fill (time)*(rate) = 3/2*3/5 = 9/10 th of the cistern .
Then the outlet is turned on and the remaining 1/10 th of the cistern is filled in 1 hour.
Letting x to be the rate of the outlet, we would have: 3/5 - x = 1/10 --> x = 1/2 cistern/hour, which means that it takes 2 hours the outlet working alone to empty the cistern.
Answer: A.
Question: What is the next number: 3, 27, 627, __
A.8847
B.9837
C.11,497
D.15,627
Answer: D.15,627
Explanation: 5^0 + 2 = 3
5^2 + 2 = 27
5^4 + 2 = 627
5^6 + 2 = 15,627
The answer is D.
Question: There are 6561 balls out of them 1 is heavy.Find the min. no. of times the balls have to be
weighed for finding out the haevy ball.
A.7
B.8
C.9
D.10
Answer: B.8
Explanation: 1))6561/3=2187->2187,2187,2187
2)2187/3=729->729,729,729
3)729/3=243->243,243,243
4)243/3=81->81,81,81
5)81/3=27->27,27,27
6)27/3=9->9,9,9
7)9/3=3->3,3,3
8)3/3=1->1,1,1
8 times required
ANSWER:B
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
A.1/455
B.1/458
C.1/457
D.1/454
Answer: A.1/455
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue
= ³C₃/¹⁵C₃
= (1 * 3 * 2 * 1)/(15 * 14 * 13)
= 1/455
Answer: A
Question: One train is travelling 45 kmph and other is at 10 meters a second. Ratio of the speed of the two trains is?
A.3:3
B.5:7
C.5:4
D.7:2
Answer: C.5:4
Explanation: C
5:4
45 * 5/18 = 10
25:20 => 5:4
Question: A person walking 5/6 of his usual rate is 40 minutes late. What is
his usual time?
A.3 hrs 20 min
B.4 hrs 20 min
C.5 hrs 20 min
D.6 hrs 20 min
Answer: A.3 hrs 20 min
Explanation: Let t be the usual time. If the usual rate is 1 unit, then the unusual rate is 5/6.
Balance by the distance,
1*t = (5/6)(t+40)
6t = 5(t+40)
Solve for t,
t = 200 minutes = 3 hrs 20 min
ANSWER:A
Question: The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?
A.12 cm
B.14 cm
C.18 cm
D.20 cm
Answer: C.18 cm
Explanation: 2(l+b)/b=5/1
2l+2b=5b
3b=2l
b=2/3l
Then, Area = 216 cm2
lx b=216
lx 2/3l=216
l2=324
l=18 cm
ANSWER:C
Question: 217 * 217 + 183 * 183
A.70578
B.82578
C.80578
D.80568
Answer: C.80578
Explanation: Explanation:
1/2×2(a2+b2)=1/2×[(a+b)2+(a−b)2]
=1/2×[(217+183)2+(217−183)2]=80578
Option C
Question: Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?
A.4
B.10
C.15
D.16
Answer: D.16
Explanation: Explanation:
L.C.M. of 2, 4, 6, 8, 10, 12 is 120.
So, the bells will toll together after every 120 seconds(2 minutes).
In 30 minutes, they will toll together	30/2+ 1 = 16 times.
ANSWER IS D
Question: Q is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years. What is definitely the difference between R and Q's age?
A.16
B.17
C.13
D.50
Answer: D.50
Explanation: R - Q = R - T
Q = T.
Also R + T = 50; R + Q
= 50
So, (R - Q) cannot be determined.
Answer: D
Question: What is the lowest possible common multiple of 2 distinct integers, each greater than 130?
A.131
B.131*132
C.131*131
D.262
Answer: D.262
Explanation: The least common multiple of two numbers greater than 130 is 2(131) = 262, where the two distinct integers are 131 and 262.
The answer is D.
Question: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
A.35
B.36 2/3
C.37 1/2
D.40
Answer: D.40
Explanation: Explanation:
Let distance = x km and usual rate = y kmph.
Then,	x/y-x/y + 3=40/60 =>2y(y + 3) = 9x ....(i)
And, x/y -2-x/y =40/60 =>y(y - 2) = 3x ....(ii)
On dividing (i) by (ii), we get: x = 40.
ANSWER IS D
Question: The average of seven numbers is 15. The average of first three numbers is 14 and the average of last three numbers is 19. What is the middle number?
A.6
B.29
C.31
D.34
Answer: A.6
Explanation: The total of seven numbers = 7X15 = 105
The total of first 3 and last 3 numbers is = 3 X 14+3 X 19 = 99
So, the middle number is (105 - 99 ) = 6
A
Question: A fast food company plans to build 5 new restaurants. If there are 14 sites that satisfy the company's criteria for location of new restaurant, in how many different ways can company select the 5 sites needed for the new restaurant if the order of selection doesn't matter.
A.1001
B.2002
C.495
D.1532
Answer: B.2002
Explanation: The number of ways of choosing 5 sites out of 14 are counted by = 14C5 ways = 2002
Answer: Option B
Question: The ratio of the cost price and the selling price is 4:5. The profit percent is:
A.33
B.77
C.25
D.66
Answer: C.25
Explanation: Let C.P. = Rs. 4x. Then, S.P. = Rs. 5x
Gain = (5x - 4x) = Rs. x
Gain % = (x * 100)/ 4x = 25%.
Answer: C
Question: In a certain game of dice, the player’s score is determined as a sum of two throws of a single die. The player with the highest score wins the round. If more than one player has the highest score, the winnings of the round are divided equally among these players. If Jim plays this game against 21 other players, what is the probability of the minimum score that will guarantee Jim some monetary payoff?
A.41/50
B.1/221
C.1/216
D.1/36
Answer: D.1/36
Explanation: Toguaranteethat Jim will get some monetary payoff he must score the maximum score of 6+6=12, because if he gets even one less than that so 11, someone can get 12 and Jim will get nothing.
P(12)=1/6^2=1/36.
Answer: D
Question: A sum of Rs 468.75 was lent out at simple interest and at the end of 1 year and 8 months, the total amount of Rs 500 is received. find the rate of interest?
A.3%
B.4%
C.5%
D.6%
Answer: B.4%
Explanation: Here P=468.75 which is the principle.
Amount=Rs 500
Amount =SI+P
500=[468.75*(20/12)*R]/100 + 468.75
31.25=156.25*5R/100
R=4%
ANSWER:B
Question: A was born when B was 1 year and 3 months old. C was born when A was 2 years 1 month old. What is the age of B when C is 4 years and 6 months old?
A.4 yr 10 month
B.6 yr 10 month
C.7 yr 11 month
D.7 yr 10 month
Answer: D.7 yr 10 month
Explanation: When C is 4yr 6 month i.e. 54 months old
A is 79 month old..
B is 15 month older than A
When A is 79 months old then,
B is 94 months old i.e. 7yr 10 month
ANSWER:D
Question: Y and Z started a business investing Rs. 10,000 and Rs. 15,000 respectively. Out of a total profit of Rs. 5,000, Z’s share is :
A.3000
B.3300
C.3600
D.3900
Answer: A.3000
Explanation: Ratio of their shares = 10000 : 15000 = 2 : 3.
Z’s share = Rs. 5000 * 3/5
= Rs. 3000
ANSWER:A
Question: Machine A can process 6000 envelopes in 3 hours. Machines B and C working together but independently can process the same number of envelopes in 2.5 hours. If Machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take Machine B to process 7000 envelopes.
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: You can either take the amount of work done as the same as Karishma has done or take the work done by each in the same time. I will do the latter
1. Work done in 1 hr by A is 2000 envelopes
2. Work done in 1 hr by A and C is 3000 envelopes
3. So work done in 1 hr by C is 1000 envelopes
4. Work done in 1 hr by B and C is 2400 envelopes
5. So work done in 1 hr by B is 1400 envelopes
6. So to process 7000 envelopes B will take 7000/1400 hrs = 5 hrs
So the answer is choice D
Question: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is?
A.6
B.8
C.1
D.5
Answer: A.6
Explanation: S = 1
M = x
DS = x + 1
US = x - 1
35/(x + 1) + 35/(x - 1) = 12
x = 6
Answer:A
Question: If Yury has been writing programming code for 12 hours at a rate of 5 lines of code per 20 seconds, how many lines of code has he written?
A.126(10^2)
B.126(10^3)
C.12.6(10^5)
D.108(10^2)
Answer: D.108(10^2)
Explanation: 5 LINES IN 20 SECONDS
SO FOR 1 MINUTE ( 5 X 3 = 15 LINES )
I HOUR = 60 MINUTES
15 X 60 = 900 LINES IN AN HOUR
12 HOURS = 900 X 12 = 108(10^2)
ANSWER D
Question: There are 36 students in a certain geometry class. If two thirds of the students are boys and three fourths of the boys are under six feet tall, how many boys in the class are under six feet tall?
A.6
B.12
C.18
D.24
Answer: C.18
Explanation: Total Students = 36
Two thirds of the students are boys = 2/3*36 = 24
Three fourths of the boys are under six feet tall = 3/4*24 = 18 ...
Therefore Number of boys in the class under six feet tall = 18 ... Answer C....
Alternatively... Number of boys in the class under six feet tall = 3/4 of 2/3 of Total Students = 3/4*2/3*36 = 18...
Answer C
Question: A magician has five animals in his magic hat: 3 doves and 2 rabbits. If he pulls two animals out of the hat at random, what is the chance X that he will have a matched pair?
A.X=2/5
B.X=3/5
C.X=1/5
D.1/2
Answer: A.X=2/5
Explanation: P(both doves) + P(both rabbits) = p(matched pair)
(3/5)*(2/4) + (2/5)*(1/4) = 2/5
Hi How did you get the probability 2/4 and 1/4???
You have 3 doves and 2 rabbits i.e. a total of 5 animals.
The probability that you pick a dove on your first pick is 3/5 (since there are 3 doves)
The probability that you pick a dove on your second pick too is 2/4 (because now only 2 doves are left after we picked a dove in the first pick. ALso only 4 animals are left to choose from)
Similarly,
The probability that you pick a rabbit on your first pick is 2/5 (since there are 2 rabbits)
The probability that you pick a rabbit on your second pick too is 1/4 (because now only 1 rabbit is left after we picked a rabbit in the first pick. Also only 4 animals are left to choose from)
Probability of picking a matched pair = 3/5 * 2/4 + 2/5 * 1/4 = 2/5
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 40 kmph respectively. In what time will they cross each other completely?
A.15 sec
B.19 sec
C.12 sec
D.10 sec
Answer: A.15 sec
Explanation: Explanation:
D = 250 m + 250 m = 500 m
RS = 80 + 40 = 120 * 5/18 = 100/3
T = 500 * 3/100 = 15 sec
Answer: Option A
Question: In shop contains 500 articles each of a cost of $10. He sold them at a price of $15. If the shop keeper has a order of 200 articles, how much profit he will get?
A.A)200
B.B)2000
C.C)1500
D.D)1000
Answer: D.D)1000
Explanation: Total money after selling articles = 200*15 = 3000
cost price = 200*10 = 2000
profit = 1000
correct option is D
Question: A bag contains 12 red marbles. If someone were to remove 2 marbles from the bag, one at a time, and replace the first marble after it was removed, the probability that neither marble would be red is 36/49. How many marbles are in the bag?
A.24
B.48
C.84
D.72
Answer: C.84
Explanation: ok let me see if i can explain what went on in the previous post
lets say i have x marbles in the bag in total --> out of them 12 are red
so the probability of pulling a non-red marble is (x -12) / x
now the marble is placed back in the bag and we have x marbles again, of which again 12 are red. so the probability of pulling a non-red marble out is (x-12) / x
probability theorm states that if the probability of event A occuring is m and the probability of event B occuring is n then the probability of both A and B occuring is m*n
so therefore the probability of 2 non-red marbles getting pulled out is [(x-12)/x ] * [(x-12)/x]
this is given as 36/49
-->(x-12)^2= 36/49
x^2
square rooting u have x-12/x = 6/7 or 7x-6x =84 or x =84
C
Question: What is the smallest positive perfect square that is divisible by 9, 15, and 25?
A.100
B.225
C.900
D.1,600
Answer: B.225
Explanation: The number needs to be divisible by 3^2, 3*5, and 5^2.
The smallest such perfect square is 3^2*5^2 = 225
The answer is B.
Question: 10 play kabadi, 25 play kho kho only, 5 play both gmaes. Then how many in total?
A.30
B.35
C.38
D.40
Answer: B.35
Explanation: 10 play kabadi =>n(A)=10,
5 play both gmaes.=> n(AnB)=5
25 play kho kho only,=>n(B)=n(B only)+n(AnB)=25+5=30
Total => n(AUB)= n(A)+n(B)-n(AnB)
= 10+30-5
= 35
ANSWER:B
Question: A train speeds past a pole in 15 sec and a platform 100 m long in 25 sec, its length is?
A.100
B.150
C.160
D.170
Answer: B.150
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 100)/25 = x/15 => x = 150 m.
Answer: Option B
Question: The area of a parallelogram is 98sq m and its altitude is twice the corresponding base. Then the length of the base is?
A.8
B.9
C.7
D.62
Answer: C.7
Explanation: 2x * x = 98 => x= 7
Answer: C
Question: A certain amount earns simple interest of Rs. 1750 after 6 years. Had the interest been 2% more, how much more interest would it have earned?
A.Rs. 350
B.Rs. 35
C.Rs. 245
D.Cannot be determined
Answer: D.Cannot be determined
Explanation: We need to know the S.I., principal and time to find the rate. Since the principal is not given, so data is inadequate.
ANSWER:D
Question: Twenty percent of Country Y's yearly exports come from fruit exports. One-fourth of all fruit exports from Country Y are orange exports. If country Y generates $20 million from its orange exports, how much money does it generate from its yearly total of exports?
A.$21.25m
B.$25.5m
C.$106.25m
D.$400m
Answer: D.$400m
Explanation: 20/100*1/4*(total) = 20
1/20*(total) = 20
(total) = 20*20 = 400
Answer: D.
Question: The average of runs of a cricket player of 10 innings was 34. How many runs must he make in his next innings so as to increase his average of runs by 4 ?
A.78
B.79
C.85
D.87
Answer: A.78
Explanation: Explanation:
Average = total runs / no.of innings = 34
So, total = Average x no.of innings = 34 x 10 = 340.
Now increase in avg = 4runs. So, new avg = 34+4 = 38runs
Total runs = new avg x new no. of innings = 38 x 11 = 418
Runs made in the 11th inning = 418 - 340 = 78 Answer: A
Question: In one can of mixed nuts, 60% is peanuts. In another can of mixed nuts that is one-half the size of the first one, 40% is peanuts. If both cans are emptied into the same bowl, what percentage of the mixed nuts in the bowl is peanuts?
A.16 2/3%
B.20%
C.25%
D.53 1/3%
Answer: D.53 1/3%
Explanation: Can 1: size 1; 60% nuts
Can 2: size 0.5 and 40% nuts
(1x0.6+0.5x0.4)/1.5=53.33
D
Question: The difference between compound interest and simple interest on a sum for two years at 8% per annum, where the interest is compounded annually is Rs.16. if the interest were compounded half yearly , the difference in two interests would be nearly
A.24.64
B.24.69
C.24.62
D.24.6
Answer: A.24.64
Explanation: Explanation:
For 1st year S.I =C.I.
Thus, Rs.16 is the S.I. on S.I. for 1 year, which at 8% is thus Rs.200
i.e S.I on the principal for 1 year is Rs.200
Principle = = Rs.2500
Amount for 2 years, compounded half-yearly
C.I = Rs.424.64
Also,
Hence, [(C.I) - (S.I)] = Rs. (424.64 - 400) = Rs.24.64
Answer:A
Question: If the quantity 8^2+ 8^4 + 8^6 is written as (a + b)(a – b), in which both a and b are integers, which of the following could be the value of b?
A.51
B.64
C.49
D.29
Answer: B.64
Explanation: (a+b)(a-b) = a^2 - b^2
8^2+ 8^4 + 8^6 = 8^2 (1+8^2+8^4)
if the above expression is solved even then every term of the expression will remain a multiple of 8^2 which is out of parenthesis
hence, b must be a multiple of 8^2 i.e. 64
Answer: option B
Question: The prime sum of an integer n greater than 1 is the sum of all the prime factors of n, including repetitions. For example , the prime sum of 12 is 7, since 12 = 2 x 2 x 3 and 2 +2 + 3 = 7. For which of the following integers is the prime sum greater than 30 ?
A.440
B.512
C.550
D.620
Answer: D.620
Explanation: Large numbers are made in two ways:
Either by taking small prime numbers and raising them to higher powers or taking large prime numbers in the first place.
31*2 = 62 (large prime number)
2^6 = 64 (many small prime numbers)
To get a sum as large as 30 or more, you would need some large prime numbers. So options such as 512, 700 and 750 which have small prime numbers as factors should be ignored first. 440 also splits into 11, 4( which is 2*2), 2, 5 - relatively small prime numbers.
You are left with 620 which is 31*2*2*5 (sum greater than 30)
Answer (D)
Question: A, B and C enter into a partnership investing Rs 35000, Rs 45000 and Rs 55000 resp. The respective share of A,B and C in an annual profit of Rs 40500 are.
A.Rs. 11500, Rs. 13500, Rs. 16500
B.Rs. 10500, Rs. 12500, Rs. 16500
C.Rs. 10500, Rs. 13500, Rs. 15500
D.Rs. 10500, Rs. 13500, Rs. 16500
Answer: D.Rs. 10500, Rs. 13500, Rs. 16500
Explanation: Explanation:
A:B:C = 35000:45000:55000
= 7:9:11
Now we are having the ratio.
to get the share, first make total of above ratio.
then get each share.
A's Share=40500∗7/27=Rs.10500
B's Share=40500∗927=Rs.13500
B's Share=40500∗1127=Rs.16500
Option D
Question: Employees of a certain company are each to receive a unique 5-digit identification code consisting of the digits 0, 1, 2, 3, and 4 such that no digit is used more than once in any given code. In valid codes, the second digit in the code is exactly twice the first digit. How many valid codes are there?
A.10
B.12
C.14
D.16
Answer: B.12
Explanation: There are 3! ways to make codes starting with 12.
There are 3! ways to make codes starting with 24.
The number of codes is 2*3! = 12.
The answer is B.
Question: x^2 + rx + 72 = 0 has two distinct integer roots; how many values are possible for r?
A.3
B.6
C.8
D.12
Answer: D.12
Explanation: For a quadratic equation ax^2+rx+c=0, we know that -r/a is sum of roots and c/a is product of roots.
The quadratic equation here is x^2 + rx + 72 = 0, where product of roots is 72.
If we find all the factors of 72, we have the answer.
By prime factorization, we get 72= 2^3*3^2.
We know that total factors are (3+1)*(2+1) = 12 (Reason: with 2^n, we have n+1 possibilities. n^0 to n^n. so n+1)=D
Question: If the remainder is 10 when the integer n is divided by 18, what is the remainder when 2n is divided by 9?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: n = 18k+10
2n = 2(18k+10) = 4k*9 + 20 = 4k*9 + 2*9 + 2 = 9j + 2
The answer is C.
Question: Find the compound ratio of (1:2), (1:3) and (3:5) is
A.1:10
B.2:3
C.3:4
D.4:5
Answer: A.1:10
Explanation: Required ratio = 1/2 * 1/3 * 3/5 = 1/10 = 1:10
Answer is A
Question: Four of the following five parts numbered (a), (b), (c), (d) and (e) are exactly equal. The number of the part which is not equal to the other four parts is your answer.
A.85 ÷ 17 × 110
B.45 × 6 + 75 × 4
C.175 ÷ 25 × 75 + 5(2)
D.36 × 4 + 21(2) – 7 × 5
Answer: B.45 × 6 + 75 × 4
Explanation: Except it, others are equal to 550.
Answer B
Question: A small, rectangular park has a perimeter of 560 feet and a diagonal measurement of 100 feet. What is its area, in square feet?
A.4,800
B.19,600
C.20,000
D.20,400
Answer: A.4,800
Explanation: you can avoid a lot of work in this problem by recognizing that, with the info provided, the diagonal forms a triangle inside the rectangle with sides that have a 3:4:5 ratio.
diagonal = 200
2x + 2y = 560, or x + y = 280
a^2 + b^2 = c^2 for each the sides of the triangle
using the ratio 3:4:5 for sides, and knowing c = 100, you can deduce the following
a=60
b=80
60x80=4,800
A is the answer.
Question: A security guard at a certain store is instructed to check the receipt of one out of every five customers as they are leaving the store. If, on the guard's shift, 10 customers leave the store, how many different samples of customers could have been selected to have their receipts checked?
A.20
B.45
C.59
D.90
Answer: B.45
Explanation: If the guard is instructed to select 1 of every 5 receipts and the question is asking how many different sets of customers could be selected out of 10 then the guard will select 2 of the 10 customers to review.
10C2 = 45.
ANS:B
Question: The average weight of 6 students decreases by 3 kg when one of them weighing 80 kg is replaced by a new student. The weight of the student is
A.62 kg
B.60 kg
C.70 kg
D.72 kg
Answer: A.62 kg
Explanation: Explanation :
Let the weight of student be x kg.
Given, Difference in average weight = 3 kg
=> (80-x)/6 = 3
=> x = 62
Answer : A
Question: A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 45, what is the total amount?
A.166
B.105
C.175
D.177
Answer: C.175
Explanation: x:y:z = 100:45:30
20:9:6
9 --- 45
35 --- ? => 175
Answer: C
Question: How many 6 digit even numbers can be formed from digits 1, 2, 3, 4, 5, 6, and 7 so that the digit should not repeat and the second last digit is even?
A.6480
B.320
C.2160
D.720
Answer: D.720
Explanation: 5x4x3x2x2x3= 720
last digit can be 2 or 4 or 6 ie 3ways since the no is even
and second last digit 2 ways bcz no cannot be repeated similarly remaining 5,4,3,2 ways
multipling all we get 720
ANSWER:D
Question: The price of a T.V. set worth Rs. 70000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be?
A.22678
B.26699
C.69000
D.19000
Answer: C.69000
Explanation: Money paid in cash = Rs. 1000
Balance payment = (70000 - 1000) = Rs. 69000
Answer: C
Question: One year ago, the ratio of Sooraj's and Vimal's age was 6:7 respectively. Four years hence, this ratio would become 7:8. How old is Vimal?
A.35
B.36
C.37
D.38
Answer: B.36
Explanation: 1 year ago
Age of Sooraj and Vimal, 6x and 7x respectively.
After 4 years ratio would become 7:8
(6x+5):(7x+5)=7:8
8(6x+5)=7(7x+5)
48x+40=49x+35
x=5 Vimal's present age
=7x+1=7×5+1=36
answer :B
Question: Solve for X, log10X + log√10 X + log3√100 X = 27.
A.1
B.106
C.104
D.10
Answer: B.106
Explanation: Changing the base to 10, we get
log√10 X = log10X / log10√10 = 2log10X
log3√X = log10X / log103√100 = 3log10X / 2.
Thus, log10X + 2log10X + 3/2 log10X = 27
=> 9/2 log10X = 27
=> log10X = 6
ANSWER:B