RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Two mixtures of A and B have A and B in the ratio 3:2 and 3:4. In what proportion should these two mixtures be mixed to get a new mixture in which the ration of A to B is 5:4?
A.6:1
B.5:4
C.20:7
D.10:9
Answer: C.20:7
Explanation: I got C but with a different, yet slightly longer approach, which I constantly use for proportion problems such as this one. Usually, this approach is very efficient when used with slightly difficult questions, but this problem is quite hard so I had to slightly tweak it. I will show you how I usually use the approach and later show you how to use it with this specific problem.
Example.
1 Liter of Solution A contains 45% alcohol, while 1 Liter of Solution B contains 20% alcohol. In what ratio must the two solutions be used to get a solution with 30% alcohol
Solution:
1.	45/100*[A/(A+B)]+20/100*[B/(A+B)] = 30/100
2.	Multiply 100 to both sides to arrive at 45A/(A+B) + 20B/(A+B) = 30
3.	Multiply (A+B) to both sides to arrive at 45A + 20B = 30A + 30B
4.	Distribute to arrive at 15A = 10B
5.	Thus the ratio is A/B = 10/15 = 2/3
Now using this same approach, we tackle Gopu106’s question. It is important to first think of X in the mixture as the alcohol in the problem above; hence, a mixture of X and Y in the ratio of 3:2 translates to X is 3/5 of the solution. Applying this concept to all three equations, we write:
1.	3/5*[A/(A+B)]+3/7*[B/(A+B)] = 5/9
2.	Now here is the tweak that must be made to continue with this approach. You must find the common denominator for all three numbers and organize the fractions accordingly. By finding the common denominator of 5,7,9 (or 315) we re-write the equations as follows
3.	189/315*[A/(A+B)]+135/315*[B/(A+B)] = 175/315
4.	Multiply 315 to both sides to arrive at 189A/(A+B) + 135B/(A+B) = 175
5.	Multiply (A+B) to both sides to arrive at 189A + 135B = 175A + 175B
6.	Distribute to arrive at 14A = 40B
7.	Thus the ratio is A/B = 40/14 = 20/7 or answer C
Question: Cream costs twice as much as skim milk. A certain brand of milk is 2/5 cream and 3/5 skim milk. What fraction of the cost of this brand is due to the cream?
A.2/7
B.3/7
C.4/7
D.3/5
Answer: C.4/7
Explanation: Let x be the cost of the skim milk in the mixture.
The cost of the cream is (2/3)*x*2 = 4x/3.
The total cost is x+4x/3 = 7x/3 and the fraction due to the cream is (4x/3) / (7x/3) = 4/7
The answer is C.
Question: An art gallery has only paintings and sculptures. Currently, 1/3 of the pieces of art are displayed, and 1/6 of the pieces on display are sculptures. If 1/3 of the pieces not on display are paintings, and 1000 sculptures are not on display, how many pieces of art does the gallery have?
A.360
B.2250
C.540
D.640
Answer: B.2250
Explanation: Too many words and redundant info there.
(i) 1/3 of the pieces of art are displayed, hence2/3 of the pieces of art are NOT displayed.
(ii) 1/6 of the pieces on display are sculptures, hence 5/6 of the pieces on display are paintings.
(iii) 1/3 of the pieces NOT on display are paintings, hence2/3 of the pieces NOT on display are sculptures.
1000 sculptures are not on display, so according to (iii) 2/3*{not on display} = 1000 --> {not on display} = 1500.
According to (i) 2/3*{total} = 1500 --> {total} = 2250.
Answer: B.
Question: A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then, (a + b) = ?
A.10
B.11
C.23
D.43
Answer: A.10
Explanation: A
10
4 a 3 |
9 8 4 } ==> a + 8 = b ==> b - a = 8
13 b 7 |
Also, 13 b7 is divisible by 11 (7 + 3) - (b + 1) = (9 - b)
(9 - b) = 0
b = 9
(b = 9 and a = 1) (a + b) = 10.
Question: Riya covers journey from kavali to nellore by car at average speed of 50 Km/hr. She returns back by scooty with an average speed of 50 Km/hr. Find her average speed during the whole journey?
A.30Km/hr
B.50Km/hr
C.80Km/hr
D.90Km/hr
Answer: B.50Km/hr
Explanation: Explanation:
Average speed = 2 xy/x+y
= 2*50*50/100
= 50 Km/hr
Answer: Option B
Question: The average age of a group of 5 members is 20 years. Two years later, a new member joins the group. The average age of the group becomes 22.5 years. What is the age of the new member ?
A.20 years
B.21 years
C.22 years
D.25 years
Answer: D.25 years
Explanation: The average age of the 5 members is 20 years
=> The sum of the ages of the 5 members is 20*5 = 100 years
Once the new member joins, the average age becomes 22.5 years.
Let the age of the new member be x.
Then (110+x)/6 = 22.5
=> x = 25 years
Answer D
Question: Water consists of hydrogen and oxygen, and the approximate ratio, by mass, of hydrogen to oxygen is 2:16. Approximately how many grams of oxygen are there in 117 grams of water?
A. 16
B. 104
C. 112
D. 128
Answer: B. 104
Explanation: Since the ratio, by mass, of hydrogen to oxygen is 2:16, then oxygen is 16/(2+16)=8/9 of mass of water.
Therefore there are 117*8/9=104 grams of oxygen in 117 grams of water.
Answer: B.
Question: Chunilal invests 65% in machinery 20% in raw material ands till has 1,305 cash with him. Find his total investment.
A.6,500
B.7,225
C.8,500
D.7,395
Answer: D.7,395
Explanation: Let he had originally x.
Then 65% of x + 20 % of x + 1305 = x
0.65x + 0.2x + 1305 = x
⇒ 0.15 x = 1305 ⇒ x = 8700
∴ His total investment = 65% of 8700 + 20% of 8700
= 85% of 700 = 7395
Answer D
Question: The largest 4 digit number exactly divisible by 44 is?
A.9988
B.9939
C.9944
D.9954
Answer: A.9988
Explanation: Largest 4-digit number = 9999
44) 9999 (227
9988
Largest number : 9988
Answer : A
Question: What is the remainder when the number 14^2 * 15^8 is divided by 5?
A.0
B.1
C.2
D.4
Answer: A.0
Explanation: 14^2 has units digit 6
15^8 has units digit 5
Thus 14^2*15^8 has units digit 0 and will be divisible by 5. The remainder will be zero
Answer: (A)
Question: Find compound interest on $ 10000 at 15% per annum for 2 years 4 months, compounded annually.
A.3886.25
B.3286.25
C.3186.25
D.3386.25
Answer: A.3886.25
Explanation: Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.
Amount = $ [10000 X (1+­(15/100))2 X (1+((1/3)*15)/100)]
=$ [10000 * (23/20) * (23/20) * (21/20)]
= $ 13886.25	.
:. C.I. = Rs. (13886.25 -10000) = $ 3886.25
Answer A.
Question: The lenght of a room is 5.5 m and width is 4 m. Find the cost of paving the floor by slabs at the rate of Rs. 750 per sq. metre.
A.s. 15,550
B.s. 15,600
C.s. 16,500
D.s. 17,600
Answer: C.s. 16,500
Explanation: Area of the floor = (5.5 Ã— 4) m2 = 22 m2.
Cost of paving = Rs. (750 Ã— 22) = Rs. 16500
.
Answer: Option C
Question: How long does a train 100 m long running at the speed of 65 km/hr takes to cross a bridge 145 m length?
A.13.6 sec
B.12.1 sec
C.17.9 sec
D.61.9 sec
Answer: A.13.6 sec
Explanation: Speed = 65 * 5/18 = 18 m/sec
Total distance covered = 100 + 145 = 245 m.
Required time = 245/18 = 13.6 sec.
Answer:A
Question: The slant height of a cone is 12 cm and radius of the base is 4cm, find the curved surface of the cone.
A.49 π cm2
B.40 π cm2
C.48 π cm2
D.43 π cm2
Answer: C.48 π cm2
Explanation: Explanation:
π * 12 * 4 = 48
Answer: Option C
Question: If P(A) = 4/5 and P (B) = 2/5, find P (A n B) if A and B are independent events.
A.7/25
B.3/25
C.8/25
D.2/13
Answer: C.8/25
Explanation: P (A n B) = P(A) . P(B)
P (A n B) = 4/5 . 2/5
P (A n B) = 8/25.
C
Question: Sum of three nos is 98. The ratio between 1 and 2 is 2:3. The ratio between 2 and 3 is 5:8 .
Find the second no?
A.10
B.20
C.30
D.40
Answer: C.30
Explanation: x+y+z=98
x/y=2/3
x=2y/3
and
y/z=5/8
z=8y/5 subtitute this is x and z
2y/3+y+8y/5=98
y=30
ANSWER:C
Question: Kaushalya can do a work in 20 days, while kaikeyi can do the same work in 25 days. They started the work jointly.Few days later Sumitra also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.700. What is the Share of Sumitra?
A.Rs.130
B.Rs.185
C.Rs.70
D.can't be determined
Answer: C.Rs.70
Explanation: Explanation:
Efficiency of kaushalya = 5%
Efficiency of kaikeyi = 4%
Thus, in 10 days working together they will complete only 90% of the work.
[(5 + 4) × 10] =90
Hence, the remaining work will surely done by sumitra, which is 10%.
Thus, sumitra will get 10% of Rs. 700, which is Rs.70
Answer: C
Question: Three unbiased coins are tossed. What is the probability of getting 2 Heads and 2 Tail?
A.5/8
B.1/4
C.3/8
D.7/8
Answer: A.5/8
Explanation: Let, H --> Head , T --> Tail
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting 3 heads
Then E = {THH,HTH,HHT,THT,TTH}
P(E) = n(E)/n(S) =5/8
Answer is A
Question: A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is?
A.10
B.12
C.15
D.13
Answer: C.15
Explanation: Suppose, first pipe alone takes x hours to fill the tank. Then, second and third pipes will take (x - 5) and (x - 9) hours respectively to fill the tank.
1/x + 1/(x - 5) = 1/(x - 9)
(2x - 5)(x - 9) = x(x - 5)
x2 - 18x + 45 = 0
(x- 15)(x - 3) = 0 => x = 15
ANSWER C
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 23 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.877 m
B.195 m
C.167 m
D.887 m
Answer: B.195 m
Explanation: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train
= (15 x 23)m = 345 m. Let the length of the platform be x meters. Then, (x + 345)/36 = 15
==> x + 345 = 540 ==> x
= 195 m.
Answer: B
Question: A man purchased a watch for Rs.400 and sold it at a gain of 20% of the selling price. The selling price of the watch is:
A.232
B.480
C.178
D.277
Answer: B.480
Explanation: Explanation:
Cost price = 400
Gain% = 20%
Gain = 400 × 2010020100 = 80
Cost price = 400 + 80 = 480
Answer: B
Question: A train passes a station platform in 40 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.180 m
B.240 m
C.260 m
D.300 m
Answer: D.300 m
Explanation: Speed = 54 x 5/18 = 15 m/s
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, (x + 300)/40 = 15
--> x + 300 = 600
x = 300m.
Answer : D.
Question: A family consists of two grandparents, two parents and four grandchildren. The average age of the grandparents is 70 years, that of the parents is 40 years and that of the grandchildren is 6 years. What is the average age of family?
A.8/4years
B.B)31
C.C)30
D.D)33
Answer: A.8/4years
Explanation: Required average
= (70 x 2 + 40 x 2 + 6 x 4 )/(2 + 2 + 4)
= (140 + 80 + 24)/8
= 244/8
= 30 8/4years.
Answer is A
Question: Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
A.12 sec
B.24 sec
C.48 sec
D.60 sec
Answer: B.24 sec
Explanation: Explanation:
Relative speed =	= (45 + 30) km/hr
=75 x	5/18 m/sec
=125/6 m/sec
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
Required time =500 x	6/125 = 24 sec.
ANSWER IS B
Question: A chair is bought for Rs.400/- and sold at Rs.500/- find gain or loss percentage
A.15% loss
B.20% gain
C.25% gain
D.30% gain
Answer: C.25% gain
Explanation: Formula = (Selling price ~ Cost price)/Cost price * 100
= (500 - 400)/400 = 25% gain
C
Question: A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
A.289
B.278
C.211
D.450
Answer: D.450
Explanation: 10 * 150 = 1500
3 * 100 + 5 * 150 = 1050
1500 – 1050
= 450
Answer:D
Question: If √(3 + ³√x) = 2, then x is equal to :
A.1
B.2
C.4
D.8
Answer: A.1
Explanation: On squaring both sides, we get:
3 + ³√x = 4 or ³√x = 1.
Cubing both sides, we get x = (1 x 1 x 1) = 1
ANSWER:A
Question: A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
A.60 birds
B.72 birds
C.30 birds
D.80 birds
Answer: C.30 birds
Explanation: Let the total number of shots be x. Then,
Shots fired by A =(5/8)x
Shots fired by B =(3/8)x
Killing shots by A =(1/3)of	(5/8)x=(5/24)x
Shots missed by B =(1/2) of (3/8)x	=(3/16)x
3x/16= 27 or x =(27 x 16)/3= 144.
Birds killed by A =(5x/24)	=(5/24*144)= 30.
Answer is C.
Question: When y is divided by 288, the remainder is 45. What is the remainder when the same y is divided by 24?
A.20
B.21
C.23
D.25
Answer: B.21
Explanation: y = 288*a + 45 = (24*12)*a + 24 + 21
The answer is B.
Question: Which of the following is not a prime number ?
A.502
B.503
C.509
D.521
Answer: A.502
Explanation: Clearly, 502 is not a prime number.
Answer : A
Question: Best friends Sprite and Icey have are playing a game of marbles. They invite 10 of their friends to play with them. There are 36 marbles in the bag. If all 12 people are playing, how many marbles does each person get?
A.3
B.4
C.5
D.6
Answer: A.3
Explanation: Answer= A
36 / 12 = 3
Answer= A
Question: Of the families in City X in 1904, 50 percent owned a personal computer. The number of families in City X owning a computer in 1908 was 30 percent greater than it was in 1904, and the total number of families in City X was 5 percent greater in 1908 than it was in 1904. what percent of the families in City X owned a personal computer in 1908?
A.61.90%
B.52.20%
C.56.20%
D.70.45%
Answer: A.61.90%
Explanation: Say a 100 families existed in 1904 then the number of families owning a computer in 1904 - 50
Number of families owning computer in 1908 = 50 * 130/100 = 65
Number of families in 1908 = 105
The percentage = 65/105 * 100 = 61.90%.
Option: A
Question: A father was twelve times as old as his son twenty years back. Now he is twice as old as his son. What are their present ages?
A.Father 44 and Son 22
B.Father 35 and Son 23
C.Father 38 and Son 44
D.Father 55 and Son 22
Answer: A.Father 44 and Son 22
Explanation: Let present age of the Son = X.
Present age of the father = 2X.
Now according to question,
2X -20 = 12*(X-20)
2X - 20 = 12X -240
10X = 220
X = 22
Present age son = 22 years,
Present age father = 2*22 = 44.
ANSWER : OPTION A
Question: John found that the average of 15 no.'s is 40. If 10 is added to each number then the mean of number is?
A.50
B.55
C.65
D.72
Answer: A.50
Explanation: (x+x1+...x14)/15 = 40
50
Option A
Question: Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
A.12
B.25
C.50
D.10
Answer: D.10
Explanation: Explanation:
Due to stoppages, it covers 9 km less.
time taken to cover 9 km=(9/54*60)min=10 min
Answer D
Question: During the break of a football match, the coach will make 3 substitutions. If the team consists of 12 players among which there are 2 forwards, what is the probability that none of the forwards will be substituted?
A. 21/55
B. 18/44
C. 28/55
D. 28/44
Answer: A. 21/55
Explanation: Required probability = no. of favorable outcome/ total no. of outcomes
out of 12 players any 3 can be selected in 12C3 ways
after removing 2 forwards any 3 players can be selected from the remaining 9 players in 9C3 ways
thus required probability = 9C3/12C3 =21/55=A
Question: 529 is a perfect square. When x is added to the square root of 529, the result is also a perfect square. What is x?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: 529 is 23*23
here
A 23+1 = 24
B 23+2 = 25
C 23+3 = 26
D 23+4 = 27
E 23+5= 28
so, B is the only addition that gives a perfect square. so x=3
then the answer is B
Question: Braun invested a certain sum of money at 8% p.a. simple interest for 'n' years. At the end of 'n' years, Braun got back 3 times his original investment. What is the value of n?
A.50 years
B.25 years
C.12 years 6 months
D.37 years 6 months
Answer: B.25 years
Explanation: Explanatory Answer
Let us say Braun invested $100.
Then, at the end of 'n' years he would have got back $300.
Therefore, the Simple Interest earned =300 - 100 = $200.
We know that Simple Interest = (Principal * number of years * rate of interest) / 100
Substituting the values in the above equation we get 200 = (100 * n * 8) / 100
Or 8n = 200
Or n = 25 years.
correct choice is (B)
Question: Which of the following can be a perimeter r of a triangle inscribed in a circle of radius 1?
I. 0.001
II. 0.010
III. 0.100
A.I only
B.III only
C.II and III only
D.I, II, and III
Answer: D.I, II, and III
Explanation: Yes,the length of any side of a triangle must be larger than the positive difference of the other two sides, but smaller than the sum of the other two sides.
But how do you use the above property to solve the question?
The lower limit of the perimeter of an inscribed triangle in a circle of ANY radius is 0: r>0.
Answer is D.
Question: In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?
A.2.5
B.2.9
C.2.4
D.2.8
Answer: A.2.5
Explanation: Speed = 144 * 5/18 = 40 m/sec
Time taken = 100/40
= 2.5 sec.
Answer:A:
Question: A tradesman by means of his false balance defrauds to the extent of 60%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
A.156%
B.147%
C.134%
D.146%
Answer: A.156%
Explanation: g% = 60 + 60 + (60*60)/100
= 156%
Answer: A
Question: What will come in place of the x in the following Number series? 73205, 6655, 605, 55, x
A.56675
B.73205
C.86543
D.98765
Answer: B.73205
Explanation: (B)
5 x 11 = 55, 55 x 11 = 605, 605 x 11 = 6655, 6655 x 11 = 73205
Question: If 120/x is an integer and 108/x is an integer, which of the following must be true?
I. 9/x is an integer
II. 12/x is an integer
III. 36/x is an integer
A.I only
B.III only
C.I and II only
D.II and III only
Answer: A.I only
Explanation: I think, here we should use the greatest common factor.
The greatest common factor for 144 and 108 is 36.
So 36/x is an integer.
For the rest of the answers, if x is 36 then 9/x and 12/x leads to fractions.
Ans is A.
Question: Let N be the greatest number that divides 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: HCF of (4665-1305) , ( 6905-4665) , (6905-1305)
= HCF of 3360 ,2240,5600
= 1120
sum of digits = 4
ANSWER:A
Question: A and B have less than 6 diamonds each.What is the probability that the sum of diamonds they have is more than 3 but less than 7?
A.3/5
B.9/25
C.4/9
D.2/3
Answer: C.4/9
Explanation: A has 0, 1, 2, 3, 4, or 5 diamonds;
B has 0, 1, 2, 3, 4, or 5 diamonds.
More than 3 but less than 7 = 4, 5, or 6.
4:
{A, B}
{4, 0}
{3, 1}
{2, 2}
{1, 3}
{0, 4}
5:
{A, B}
{5, 0}
{4, 1}
{3, 2}
{2, 3}
{1, 4}
{0, 5}
6:
{A, B}
{5, 1}
{4, 2}
{3, 3}
{2, 4}
{1, 5}
Favorable = 5 + 6 + 5 = 16.
Total = 6*6 = 36
Probability = 16/36 = 4/9.
Answer: C.
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 1.9 km respectively. The time taken by the slower train to cross the faster train in seconds is?
A.99
B.72
C.48
D.96
Answer: B.72
Explanation: Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 1.9 = 3 km = 3000 m.
Required time = 3000 * 3/125 = 72 sec.
Answer:B
Question: What amount does Kiran get if he invests Rs.8000 at 10% p.a. compound interest for two years, compounding done annually?
A.Rs.19828.89
B.Rs.19828.80
C.Rs.19878.80
D.Rs.19825.80
Answer: B.Rs.19828.80
Explanation: Let the sum be Rs.P
P{ [ 1 + 8/100]2 - 1 } = 2828.80
P(8/100)(2 + 8/100) = 2828.80 [a2 - b2 = (a - b) ( a + b)] P
= 2828.80 / (0.08)(2.08) = 1360/0.08 = 17000 Principal + Interest
= Rs.19828.80
Answer:B
Question: What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 55?
A.3944
B.3740
C.7290
D.6928
Answer: B.3740
Explanation: Explanation:
Let the side of the square plot be a ft.
a2 = 289 => a = 17
Length of the fence = Perimeter of the plot = 4a = 68 ft.
Cost of building the fence = 68 * 55 = Rs. 3740.
Answer: Option B
Question: if length of a rectangle is equal to side of a square and breadth of rectangle is half of length.if area of square is 36 sq.m.calculate the area of rectangle?
A.18
B.20
C.27
D.32
Answer: A.18
Explanation: side of square=√36=6 m.
length=6 m and breadth=3 m
area of rectangle=6*3=18 sq.m
answer A
Question: A tea expert claims that he can easily find out whether milk or tea leaves were added first to water just by tasting the cup of tea. In order to check this claims 16 cups of tea are prepared, 8 in one way and 8 in other. Find the different possible ways of presenting these 16 cups to the expert.
A.12520
B.12870
C.13000
D.13400
Answer: B.12870
Explanation: Solution:
Since, there are 8 cups of each kind, prepared with milk or tea leaves added first, are identical hence, total number of different people ways of presenting the cups to the expert is,
[16!/(8!x8!)]= 12870
Answer: Option B
Question: Statement: Unemployment allowance should be given to all unemployed Indian youth above 18 yrs of age. Assumptions: 1) There are unemployed youth in India who needs monetary support. 2) The government has sufficient funds to provide allowance to all unemployed youth.
A.Only assumption I is implicit
B.Only assumption II is implicit
C.Either I or II is implicit
D.Neither I nor II is implicit
Answer: A.Only assumption I is implicit
Explanation: I directly follows from the statement and so is implicit. Also, the statement is a suggestion and does not tell about a government policy or its position of funds. So, II is not implicit.
A
Question: A fruit seller sells mangoes at the rate of Rs.6 per kg and thereby loses 15%. At what price per kg, he should have sold them to make a profit of 5%
A.Rs 7.41
B.Rs 9.81
C.Rs 10.41
D.Rs 11.81
Answer: A.Rs 7.41
Explanation: Explanation:
85 : 6 = 105 : x
x= (6×105/85)
= Rs 7.41
Option A
Question: Sandy gets 3 marks for each correct sum and loses 2 marks for each incorrect sum. Sandy attempts 30 sums and obtains 45 marks. How many sums did Sandy get correct?
A.18
B.21
C.24
D.27
Answer: B.21
Explanation: Let x be the correct sums and (30-x) be the incorrect sums.
3x - 2(30-x) = 45
5x = 105
x = 21
The answer is B.
Question: What ratio must a shopkeepermix Peas and Soybean of Rs.16 and Rs. 25/kg, As to obtain a mixture of Rs.22?
A.10 : 7
B.9 : 8
C.1 : 2
D.13 : 11
Answer: C.1 : 2
Explanation: Correct option: (C)
Use rule of alligation, to determine the ratio
The required ratio of Soybean and Peas = 3 : 6 = 1 :2
Question: Jolene entered an 18-month investment contract that guarantees to pay 2 percent interest at the end of 4 months, another 3 percent interest at the end of 12 months, and 4 percent interest at the end of the 18 month contract. If each interest payment is reinvested in the contract, and Jolene invested $10,000 initially, what will be the total amount of interest paid during the 18-month contract?
A.$506.00
B.$726.24
C.$900.00
D.$920.24
Answer: D.$920.24
Explanation: If interest were not compounded in every six months (so if interest were not earned on interest) then we would have (2+3+4)=9% simple interest earned on $10,000, which is $900. So, you can rule out A, B and C right away.
Interest earned after the first time interval: $10,000*2%=$200;
Interest earned after the second time interval: ($10,000+$200)*3%=$300+$6=$306;
Interest earned after the third time interval: ($10,000+$200+$306)*4%=$400+$8+(~$12)=~$420;
Total: 200+306+(~420)=~$920.24
Answer: D.
Question: (3+√3+√5)^2-(√3+√5)^2=?
A.9+6√3+6√5
B.1+2√3+3√5
C.1-√3+√5
D.1+√3-√5
Answer: A.9+6√3+6√5
Explanation: (3+√3+√5)^2-(√3+√5)^2
(3+√3)^2 + 5 +2 (3+√3) (√5) - ( 3 +5 + 2√3√5)
9+ 3+ 6√3 +5 +6 √5 + 2 √15 - 3-5 -2√15
9+6√3+6√5
A is the answer