RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A sum of Rs.4800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
A.Rs.2520
B.Rs.3120
C.Rs.3320
D.Rs.2760
Answer: B.Rs.3120
Explanation: Let A be the amount received at the end of the three years.
A = 4800[1 + 10/100][1 + 20/100][1 + 25/100]
A = (4800 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.7920
So the interest = 7920 - 4800 = Rs.3120
ANSWER:B
Question: In an NGO the daily average wages of 20 illiterate employees is decreased from Rs.25 to Rs.10, thus the average salary of all the literate and illiterate employees is decreased Rs.10 per day. The No. of educated employees working in the NGO is ?
A.11
B.82
C.10
D.28
Answer: C.10
Explanation: Explanation:
Total employees = \inline \frac{(25-10)\times 20}{10}=30
Hence number of educated employees = 30-20 = 10
Answer: C
Question: Find the fraction which has the same ratio to 2/13 that 5/34 has to 7/48?
A.240/1576
B.240/1542
C.240/1547
D.240/1528
Answer: C.240/1547
Explanation: P : 2/13 = 5/34 : 7/48
As the product of the means is equal to the product of the extremes.
P*7/48 = 2/13 * 5/34
P*7/48 = 10/442
P = 480/3094 => P = 240/1547
Answer: C
Question: If the average of q, b, c, 14 and 15 is 12. What is the average value of q, b, c and 29
A.12
B.13
C.14
D.15
Answer: D.15
Explanation: q+b+c+14+15 = 12*5 = 60
=>q+b+c = 60-29 = 31
q+b+c+29 = 31+29= 60
Average = 60/4 = 15
Answer D
Question: Amit and Ian paint a wall in alternating shifts. First Amit paints alone, then Ian paints alone, then Amit paints alone, etc. During each of his shifts, Amit paints 1/2 of the remaining unpainted area of the wall, while Ian paints 1/3 of the remaining unpainted area of the wall during each of his shifts. If Amit goes first, what fraction of the wall's area will remain unpainted after Amit has completed his 5th shift?
A.1/27
B.1/54
C.1/81
D.1/162
Answer: D.1/162
Explanation: Fraction of area unpainted after FIRST shift of Amit = 1-(1/2) = 1/2
Fraction of area unpainted after FIRST shift of Ian = (1/2)-(1/3)(1/2) = (2/3)(1/2)
Fraction of area unpainted after SECOND shift of Amit = (1/2)(2/3)(1/2)
Fraction of area unpainted after SECOND shift of Ian = (2/3)(1/2)(2/3)(1/2)
Fraction of area unpainted after THIRD shift of Amit = (1/2)(2/3)(1/2)(2/3)(1/2)
Fraction of area unpainted after THIRD shift of Ian = (2/3)(1/2)(2/3)(1/2)(2/3)(1/2)
Fraction of area unpainted after FORTH shift of Amit = (1/2)(2/3)(1/2)(2/3)(1/2)(2/3)(1/2)
Fraction of area unpainted after FORTH shift of Ian = (2/3)(1/2)(2/3)(1/2)(2/3)(1/2)(2/3)(1/2)
Fraction of area unpainted after FIFTH shift of Amit = (1/2)(2/3)(1/2)(2/3)(1/2)(2/3)(1/2)(2/3)(1/2)=1/162
Answer: option D
Question: Average of first five multiples of 2 is
A.9
B.6
C.13
D.15
Answer: B.6
Explanation: Explanation:
Average=2(1+2+3+4+5)5=6
Answer: Option B
Question: The difference of 2 digit number & the number obtained by interchanging the digits is 36. What is the difference the sum and the number if the ratio between the digits of the number is 1:2 ?
A.6
B.8
C.9
D.10
Answer: B.8
Explanation: Let the number be xy.
Given xy – yx = 36.
This means the number is greater is than the number got on reversing the digits.
This shows that the ten’s digit x > unit digit y.
Also given ratio between digits is 1 : 2 => x = 2y
(10x + y) – (10y +x) = 36 => x – y = 4 => 2y – y =4.
Hence, (x + y) – (x – y) = 3y – y = 2y = 8
B
Question: The length of the bridge, which a train 130 m long and traveling at 45 km/hr can cross in 30 sec is?
A.227
B.268
C.245
D.299
Answer: C.245
Explanation: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (130 + x)/30 = 25/2
x = 245 m.
Answer:C:
Question: A bag contains 15 purple jellybeans, 10 green jellybeans, and 10 yellow jellybeans; these jellybeans are the only items in the bag. If a person picks a jellybean at random out of the bag, what is the probability that the jellybean will be green?
A.15%
B.29%
C.25%
D.30%
Answer: B.29%
Explanation: Probability of green beans = 10 / (15 + 10 + 10) = 10/35 = 29%
Answer is B
Question: What amount does Kiran get if he invests Rs. 18000 at 15% p.a. simple interest for four years?
A.Rs. 24800
B.Rs. 28400
C.Rs. 24400
D.Rs. 28800
Answer: D.Rs. 28800
Explanation: Explanation:
Simple interest = (18000 * 4 * 15)/100 = Rs. 10800
Amount = P + I = 18000 + 10800 = Rs. 28800
ANSWER IS D
Question: For the symbol, m”n=n^2−m for all values of m and n. What is the value of 3”3?
A.6
B.3
C.2
D.1
Answer: A.6
Explanation: 3”3= 9 - 3=6
Answer: A
Question: In a garment industry, 12 men working 9 hours per day complete a piece of work in 10 days. To complete the same work in 12 days, working 15 hours a day, the number of men required is:
A.4
B.5
C.6
D.7
Answer: D.7
Explanation: Explanation :
Let the required number of men be x.
Less days, More men (Indirect Proportion)
More working hrs per day, Less men (Indirect Proportion)
Days 8 : 10
Working Hrs 15 : 9 :: 12 : x
=> 12 x 15 x x = 10 x 8 x 12
=> x = 10 x 9 x 12 / (12 x 15)
=> x = 7
Answer : D
Question: Half of 1 percent written as decimal is
A.5
B.0.5
C.0.05
D.0.005
Answer: D.0.005
Explanation: Explanation:
It will be 1/2(1%) = 1/2(1/100) = 1/200 = 0.005
Option D
Question: If 20 typists can type 40 letters in 20 minutes, then how many letters will 30 typists working at the same rate complete in 1 hour?
A.63
B.72
C.144
D.180
Answer: D.180
Explanation: 20 typists can type 40 letters, so 30 typists can type = 40*30/20
40*30/20 letters can be typed in 20 mins. In 60 mins typist can type= 40*30*60/20*20= 180
D is the answer
Question: In a game of 60 points; A can give B 10 points and C 15 points. Then how many points B can give C in a game of 40 ?
A.can give C 1 points
B.can give C 4 points
C.can give C 2 points
D.can give C 6 points
Answer: B.can give C 4 points
Explanation: A: B = 60 : 50, A : C = 60 : 45.
B/C = ( B/ A * A/C) = (50 / 60 * 60 / 45) = 10/9 = 40 /36
Therefore ,In a game of 40, B can give C 4 points.
Answer is B.
Question: How many two letter words are formed using the letters of the word RAM?
A.22
B.6
C.8
D.10
Answer: B.6
Explanation: Explanation:
The number of letters in the given word is three.
The number of two letter words that can be formed using these four letters is Ã¢Â´PÃ¢â€šÆ’ = 3 * 2 = 6.
Answer: B
Question: Count each 7 which is not immediately preceded by 5 but is immediately followed by either 2 or 3.
How many such 7's are there ?
5 7 2 6 5 7 3 8 3 7 3 2 5 7 2 7 3 4 8 2 6 7 8
A.2
B.4
C.3
D.5
Answer: A.2
Explanation: Answer: A . 2
Question: What is the 8th digit to the right of the decimal point in the decimal expansion of 1/37?
A. 0
B. 2
C. 4
D. 7
Answer: B. 2
Explanation: 1/37=0.027027... So, we have a repeating cycle of 027. Every third digit (2nd, 4th, 6th, ...) to the right of the decimal point is alternating by 2,0,7, thus 8th digit to the right of the decimal point is 2.
Answer: B.
Question: In a series of consecutive odd numbers, 27 is the seventh smallest number and 25 is the tenth largest number. What is the range of the series?
A. 32
B. 30
C. 29
D.28
Answer: D.28
Explanation: Imp:All are consecutive odd numbers.
27 is the 8th smallest ,there are 6 numbers smaller then 27 ,smallest number :27-12=15
25 is the 10th largest ,so there are 9 numbers larger then 25, largest number:25+18=43
Range:43-15=28
Ans : D
Question: Insert the missing number.
2, 4, 12, 48, 240, (....)
A.3388
B.1440
C.398
D.278
Answer: B.1440
Explanation: Explanation:
Go on multiplying the given numbers by 2, 3, 4, 5, 6.
So, the correct next number is 1440.
Answer: B) 1440
Question: Bongani and Jane are friends. Bongani takes Jane's physics test paper and will not tell her what her mark is. He knows that Jane hates maths so he decides to tease her. Bongani says: “I have 2 marks more than you do and the sum of both our marks is equal to 14. What are our marks?”
A.j=6,b=8
B.j=3,b=5
C.j=8,b=2
D.j=1,b=3
Answer: A.j=6,b=8
Explanation: We have two unknown quantities, Bongani's mark and Jane's mark. Let Bongani's mark be b and Jane's mark be j.
Set up a system of equations
Bongani has 2 more marks than Jane.
b=j+2............(1)
Both marks add up to 14.
b+j=14............(2)
Use equation (1) to express b in terms of j
b=j+2
Substitute into equation (2)
b+j=14
(j+2)+j=14
Rearrange and solve for j
2j=14−2
=12
∴j=6
Substitute the value for j back into equation (1) and solve for b
b=j+2
=6+2
=8
Bongani got 8 for his test and Jane got 6.
Answer is A.
Question: Shannon and Maxine work in the same building and leave work at the same time. Shannon lives due north of work and Maxine lives due south. The distance between Maxine's house and Shannon's house is 60 miles. If they both drive home at the rate 2R miles per hour, Maxine arrives home 40 minutes after Shannon. If Maxine rider her bike home at the rate of R per hour and Shannon still drives at a rate of 2R miles per hour, Shannon arrives home 2 hours before Maxine. How far does maxine live from work?
A.20
B.34
C.38
D.40
Answer: D.40
Explanation: We have that X/24 - (60-X)/2R = 40
Also X/R - (60-X)/2R = 120
So we get that 2x - 60 = 80R
3x - 60 = 240R
Get rid of R
120 = 3x
x = 40
Hence answer is D
Question: Machines X and Y produce bottles at their respective constant rates. Machine X produces k bottles in 6 hours and machine Y produces k bottles in 12 hours. How many hours does it take machines X and Y , working simultaneously , to produce 12k bottles?
A. 8
B. 12
C. 15
D. 48
Answer: D. 48
Explanation: x rate = k/6
y rate = k/12
k/6 + k/12 = 12k / T
solving T = 48
Answer D
Question: Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 200 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 4 of the days were hot, then what was the price of 1 cup on a hot day?
A.$ 1.56
B.$ 1.88
C.$ 2.25
D.$ 2.50
Answer: A.$ 1.56
Explanation: 6 regular days --> sales = 6*32*x = 192x;
4 hot days --> sales = 4*32*(1.25x) = 160x;
Total sales = 192x+160x = 352x.
Total cost = 10*32*0.75 = 240.
Profit = 352x - 240 = 200 --> x=1.25.
1.25x=~1.56.
Answer: A.
Question: Find the no.of ways of arranging the boy and 8 guests at a circular table so that the boy always sits in a particular seat?
A.2!
B.8!
C.9!
D.10!
Answer: B.8!
Explanation: Ans.(B)
Sol. Total number of persons = 9 Host can sit in a particular seat in one way. Now, remaining positions are defined relative to the host. Hence, the remaining can sit in 8 places in 8P8 = 8! Ways ... The number of required arrangements = 8! x 1= 8! = 8! ways
Question: A basketball player practices 2 hours a day Monday through Friday. How many hours must he practice Saturday and Sunday combined if he wants to practice an average (arithmetic mean) of 3 hours a day for the seven day week?
A.8
B.9
C.10
D.11
Answer: D.11
Explanation: Total number of hours practiced Mon through Fri: 5*2 = 10
Total number of hours that will be practiced in a 7 day week considering 3 hours a day average: 7*3 = 21
thus 21-10 = 11 hours still need to be practiced (on Sat and Sun combined)
D
Question: Two numbers N and 24 have LCM = 48 and GCF = 8. Find N.
A.16
B.56
C.76
D.87
Answer: A.16
Explanation: The product of two integers is equal to the product of their LCM and GCF. Hence.
24* N = 48 * 8
N = 48*8 / 24 = 16 correct answer A
Question: Which of the options is a two-digit number, which has a unit's digit that exceeds its ten's digit by 3 and the product of the given number and the sum of its digits is equal to 175.
A.25
B.36
C.47
D.52
Answer: A.25
Explanation: Using the elimination method the option that fits this description is 25
5-2 = 3 (unit's digit that exceeds its ten's digit by 3)
25*7 = 175 (the product of the given number and the sum of its digits is equal to 175)
answer :A
Question: If a man walks at the rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at the rate of 6 kmph, he reaches the station 5 minutes before the arrival of the train. Find the distance covered by him to reach the station.
A.6 km
B.8 km
C.5 km
D.3 km
Answer: B.8 km
Explanation: Let the required distance be x km
Difference in the time taken at two speeds=1 min =1/2 hr
Hence x/5-x/6=1/5<=>6x-5x=6
x=6
Hence, the required distance is 6 km
Ans: B
Question: Huey's Hip Pizza sells two sizes of square pizzas: a small pizza that measures 12 inches on a side and costs $10, and a large pizza that measures 18 inches on a side and costs $20. If two friends go to Huey's with $30 apiece, how many more square inches of pizza can they buy if they pool their money than if they each purchase pizza alone?
A.5 square inches
B.36 square inches
C.15 square inches
D.25 square inches
Answer: B.36 square inches
Explanation: In the first case each can buy one pizza of $10 and one pizza of $20.
In square inches that would be (12*12=144) for the small pizza and (18*18=324) for the large pizza. In total sq inches that would be (144+324)*2= 936 sq inches.
In the second case if they pool their money together they can buy 3 large pizzas. In terms of square inches that would be 3*324= 972 sq inches.
Hence, the difference is 36 square inches more (972-936).
The correct answer is B
Question: A water tank is two-third full. Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes. If both the pipes are open, how long will it take to empty or fill the tank completely?
A.6 min. to empty
B.6 min. to full
C.10 min. to empty
D.9 min. to full
Answer: C.10 min. to empty
Explanation: Clearly, pipe B is faster than pipe A and so, the tank will be emptied.
Part to be emptied = 2/3
Part emptied by (A + B) in 1 minute = (1/6 - 1/10) = 1/15
1/15 : 2/3 :: 1 : x
x = (2/3 * 1 * 15) = 10 min.
So, the tank will be emptied in 10 min.
ANSWER:C
Question: What is the sum of all 3 digit positive integers that can be formed using the digits 1, 3, and 7, if the digits are allowed to repeat within a number?
A.8,434
B.9,656
C.10,989
D.11,323
Answer: C.10,989
Explanation: The number of these 3-digit numbers is 3*3*3 = 27
Each digit 1, 3, and 7 will appear in the ones, tens, and hundreds place 9 times each.
The sum equals 9(111) + 9(333) + 9(777) = 10,989
The answer is C.
Question: When 30 per cent of a number is added to another number the second number increases to its 140 per cent. What is the ratio between the first and the second number?
A.3 : 4
B.4 : 3
C.3 : 2
D.Data inadequate
Answer: B.4 : 3
Explanation: Let the first and the second numbers be x and y respect then
y + 30% of x = 140% of y
or, y + 0.3x = 1.4y
or, 0.3x = 0.4y
∴ x : y = 0.4 : 0.3 = 4 : 3
Answer B
Question: Given f(x) = 3x – 5, for what value of x does 2*[f(x)] – 1 = f(3x – 6)
A.0
B.4
C.6
D.7
Answer: B.4
Explanation: explanations
We have the function f(x) = 3x – 5, and we want to some sophisticated algebra with it. Let’s look at the two sides of the prompt equation separately. The left side says: 2*[f(x)] – 1 —- this is saying: take f(x), which is equal to its equation, and multiply that by 2 and then subtract 1.
2*[f(x)] – 1 = 2*(3x – 5) – 1 = 6x – 10 – 1 = 6x – 11
The right side says f(3x – 6) — this means, take the algebraic expression (3x – 6) and plug it into the function, as discussed above in the section “How a mathematician things about a function.” This algebraic expression, (3x – 6), must take the place of x on both sides of the function equation.
f(3x – 6)= 3*[3x – 6] – 5 = 9x – 18 – 5 = 9x – 23
Now, set those two equal and solve for x:
9x – 23 = 6x – 11
9x = 6x – 11 + 23
9x = 6x + 12
9x – 6x = 12
3x = 12
x = 4
Answer = B
Question: How many minutes does it take John to type z words if he types at the rate of x words per minute?
A.x/y
B.z/x
C.xy
D.60x/y
Answer: B.z/x
Explanation: time*rate=job --> time*x=z --> time=z/x.
Answer: B.
Question: 3,7,12,18,25,..............6th terms
A.43
B.53
C.63
D.33
Answer: D.33
Explanation: 3+4=7
7+5=12
12+6=18
18+7=25
25+8=33
ANSWER:D
Question: In how many ways 8 different tickets T can be distributed between Jane and Bill if each is to receive any even number of tickets and all 8 tickets to be distributed.
A.From 2 to 6 inclusive.
B.From 98 to 102 inclusive.
C.From 122 to 126 inclusive.
D.From 128 to 132 inclusive.
Answer: D.From 128 to 132 inclusive.
Explanation: Possibilities
J 8 6 4 2 0
B 0 2 4 6 8
# of ways 8C8 8C6 8C4 8C2 8C0
T=1+28+70+28+1 = 128 Answer is D.
Question: Company A has 13 employees, 8 of whom belong to the union. If 4 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?
A.56
B.231
C.336
D.350
Answer: D.350
Explanation: Looks easy: -- 8C4*4C1 + 8C5 --350 (D).
Question: A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 844 in 4 years. The sum is:
A.s. 650
B.s. 690
C.s. 698
D.s. 728
Answer: D.s. 728
Explanation: S.I. for 1 year = Rs. (844 - 815) = Rs. 29.
S.I. for 3 years = Rs.(29 x 3) = Rs. 87.
Principal = Rs. (815 - 87) = Rs. 728.
Answer: Option D
Question: The Italian size of a suit jacket is N centimeters, where N is the linear distance between the armpits when the jacket is laid on a flat surface. The American size of a suit jacket is P inches, where P is twice the linear distance between the armpits when the jacket is laid on a flat surface. If, for a particular jacket, N = P + 12, which of the following is closest to the value of N? (One inch is approximately 2.54 centimeters.)
A.36
B.47
C.58
D.55
Answer: D.55
Explanation: Since one inch is approximately 2.54 centimeters, then N centimeters is N/2.54 inches.
Next, since the American size (P inches) is twice the Italian size (N/2.54 inches), then P=2*N/2.54.
As given that N = P + 12, then N=2*N/2.54+12 --> N=~55.
Answer: D.
Question: John draws a card from a pack of cards. What is the probability that the card drawn is a card of black suit?
A.1/2
B.1/4
C.1/3
D.1/13
Answer: A.1/2
Explanation: Tot no of cards n(S) = 52
Tot no of black cards = 26
=>26/52=1/2
ANSWER A
Question: A father is now three times as old as his son. Six years back, he was four times as old as his son. The age of the son (in years) is
A.A)12
B.B)15
C.C)19
D.D)20
Answer: C.C)19
Explanation: Explanation:
Let son's age be x years. Then, father's age = (3x) years.
Six years ago, father's age = (3x -6 ) years and son's age = (x - 6) years.
So, 3x - 6 = 4 (x - 6)=> 3x - 5 = 4x - 24=> x = 19.
Answer: C
Question: In Arun's opinion, his weight is greater than 65 kg but less than 72 kg. His brother doest not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?
A.67 kg.
B.68 kg.
C.69 kg.
D.Data inadequate
Answer: A.67 kg.
Explanation: Explanation:
Let Arun's weight by X kg.
According to Arun, 65 < X < 72
According to Arun's brother, 60 < X < 70.
According to Arun's mother, X <= 68
The values satisfying all the above conditions are 66, 67 and 68.
req average = (66 + 67 + 68) / 3 = 67 kg
Answer: A
Question: 7^1+7^2+7^3+...........+7^2015 find out how many numbers present which unit place contain 3 ?
A.504
B.505
C.506
D.507
Answer: A.504
Explanation: 7^3,7^7,7^11,7^15,7^19.........7^2015 contains last digit=3.
Now,we see
3,7,11,15....2015 are in AP
tn=a+(n-1)d
2015=3+(n-1)4
2015=3+4n-4
4n=2016
n=504
ANSWER:A
Question: Each of the cucumbers in 100 pounds of cucumbers is composed of 99% water, by weight. After some of the water evaporates, the cucumbers are now 93% water by weight. What is the new weight of the cucumbers, in pounds?
A.2
B.15
C.92
D.96
Answer: B.15
Explanation: Out of 100 pounds 99% or 99 pounds is water and 1 pound is non-water. After somewaterevaporates the cucumbers become 93% water and 7% of non-water, so now 1 pound of non-water composes 7% of cucucmbers, which means that the new weight of cucumbers is 1/0.07=15 pounds.
Answer: B.
Question: If each digit in the set of A = {1,2,3,4,5,6,7,8,9} is exactly used once, in how many ways can the digits be arranged such that the 2 and 5 are not adjacent?
A.9! - 8!
B.8!
C.9!
D.7*8!
Answer: D.7*8!
Explanation: The answer should be the (total arrangements) - (arrangements when 2 and 5 are adjacent).
The number of ways to arrange 9 units is 9!
If we think of 2 and 5 as one single unit, the number of arrangements is 8!
Note that 2 and 5 can have two arrangements, so we multiply by 2 to get 2*8!
The total number of valid arrangements is 9! - 2*8! = 9*8! - 2*8! = 7*8!
The answer is D.
Question: The 8 spokes of a custom circular bicycle wheel radiate from the central axle of the wheel and are arranged such that the sectors formed by adjacent spokes all have different central angles, which constitute an arithmetic series of numbers (that is, the difference between any angle and the next largest angle is constant). If the largest sector has a central angle of 76.5°, what fraction of the wheel’s area is represented by the smallest sector?
A.3/80
B.2/35
C.2/25
D.1/20
Answer: A.3/80
Explanation: The largest angle is 76.5.
Let d be the difference between any two angles in the progression.
The sum of all the angles will be:
76.5 + (76.5-d) + (76.5-2d) + ... + (76.5-7d) = 612 - 28d
The sum of all the central angles in a circle = 360
612 - 28d = 360
d = 252/28 = 9
The smallest sector is (76.5-7d) = 76.5-7*9 = 13.5
13.5/360 = 27/720 = 3/80
The answer is A.
Question: The volumes of three containers are in the ratio 4 : 5 : 6. If the sum of the volumes of the largest and the smallest container is is 20litres more than the weight of the third container, what is the volume of the smallest container?
A.11litres
B.19litres
C.15litres
D.16litres
Answer: D.16litres
Explanation: Let the volumes of the three containers be 4k, 5k and 6k respectively.
4k + 6k = 5k + 20
=> 5k = 20 => k = 4
Therefore the weight of the lightest boy
= 4k = 4(4) = 16 litres.
ANSWER:D
Question: A merchant sells an item at a 20% discount, but still makes a gross profit of 20 percent of the cost. What percent of the cost would the gross profit on the item have been if it had been sold without the discount?
A.20%
B.40%
C.50%
D.60%
Answer: C.50%
Explanation: Soln:-
original SP = X
Cost =C
current selling price = .8x ( 20% discount)
.8x = 1.2C (20% profit)
x= 1.2/.8 *C
x= 3/2 C
Original selling price is 1.5C which is 50% profit
ANSWER:C
Question: In the list 1, 2, 3, 4, 5, 5, 5, 5, 7, 11, 21, what fraction of the data is less than the mode?
A.2/9
B.1/3
C.2/5
D.4/11
Answer: D.4/11
Explanation: Mode: The mode of any set is the term which has the highest frequency (Occurrence)
Highest frequent term in the set is 5 (with frequency 4) hence
Mode = 5
four terms (1, 2, 3, 4) out of a total of 11 terms are less than mode of the set.
Fraction of set that are less than Mode of set = 4/11
Answer: Option D
Question: If 4 less than x is 4 greater than y, then a number z that is 5 greater than x reduced by y is equal to
A.4
B.13
C.14
D.y + 9
Answer: B.13
Explanation: 13 it is....nice one....
B
Question: A train of length 240 m crosses a bridge of length 150m in 20 seconds. What is the speed of train?
A.33
B.27
C.25
D.70.2
Answer: D.70.2
Explanation: Sol : (length of train+ length of bridge) = speed of train x Time
(240+150) = 20 x Speed
Speed = 390/20= 19.5 m/s =70.2 km/h
ANSWER=D
Question: At Annie's party, there were five times as many females as males. There were three times as many adults as children. Which of the following could NOT be the number of people at the party?
A.384
B.258
C.216
D.120
Answer: B.258
Explanation: we have to work on the info and understand what that info takes us to...
1) there were five times as many females as males At Annie's party..
this means F=5M.. so total number=6M..
2) There were three times as many adults as children..
A=3C...
or total = 4C..
so the total is 4C or 6M..
since C and M have to be positive integers, we can say for sure that Total is a multiple of 4 and 6..
or Total is multiple of LCM of 4,6..
LCM of 4,6= 12..
lets see which number is not multiple of 12..
A. 384...12*32
B. 258... no
C. 216....12*18
D. 120....12*10
E. 72......12*6..
so B is our answer..