RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The average of first 10 even numbers is?
A.17
B.199
C.16
D.11
Answer: D.11
Explanation: Sum of 10 even numbers = 10 * 11 = 110
Average = 110/10 = 11
Answer:D
Question: Look at this series: 23, 22, 24, 23, 25, 24, ... What number should come next?
A.20
B.26
C.28
D.21
Answer: B.26
Explanation: In this simple alternating subtraction and addition series; 1 is subtracted, then 2 is added, and so on.
23-1 = 22
22+2 = 24
24-1 = 23
23+2 = 25
25-1 = 24
24+2 = 26
Answer is B
Question: A can do a piece of work in 4 hours; B and C together can do it in 3 hours, which A and B together can do it in 2 hours. How long will C alone take to do it?
A.12hours
B.10hours
C.6hours
D.8hours
Answer: A.12hours
Explanation: A's 1 hour work = 1/4;
(B + C)'s 1 hour work = 1/3;
(A + B)'s 1 hour work = 1/2
(A + B + C)'s 1 hour work = (1/4 + 1/3) = 7/12
C's 1 hour work = (7/12 - 1/2) = 1/12
C alone will take 12 hours to do the work.
Answer:A
Question: If the sum of three consecutive positive odd integers is A, then the sum of the next three consecutive odd integers in terms of A is:
A.A+3
B.A+9
C.A+18
D.2A + 3
Answer: C.A+18
Explanation: In Case of Consecutive Integers or Integers in Arithmetic Progression Mean = Median
I.e. Median = A/3 = Mean = Second Integer
First Integer = A/3 - 2
Second Integer = A/3
Third Integer = A/3 + 2
i.e.
Fourth Integer = A/3 + 4
Fifth Integer = A/3 + 6
Sixth Integer = A/3 + 8
Now Mean of next 3 Integers = Median = A/3 + 6
i.e. Sum of Next 3 integers = (A/3 + 6)*3 = A+18
Answer: option C
Question: The average of 35 numbers is 25. If each number is multiplied by 5, find the new average?
A.125
B.777
C.255
D.199
Answer: A.125
Explanation: Sum of the 35 numbers = 35 * 25 = 875
If each number is multiplied by 5, the sum also gets multiplied by 5 and the average also gets multiplied by 5.
Thus, the new average = 25 * 5 = 125.Answer: A
Question: In an intercollegiate competition that lasted for 3 days, 175 students took part on day 1, 210 on day 2 and 150 on day 3. If 80 took part on day 1 and day 2 and 70 took part on day 2 and day 3 and 20 took part on all three days, how many students took part only on day 1?
A.25
B.45
C.55
D.70
Answer: B.45
Explanation: Day 1&2 = 80; Only Day 1&2 (80-20) = 60,
Day 2&3 = 70; Only Day 2&3 (70-20) = 50,
Only Day 1 = 175 - (60+50+20) = 45
Answer:B
Question: Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
A.Rs.200
B.Rs.220
C.Rs.250
D.Rs.300
Answer: C.Rs.250
Explanation: Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
C
Question: The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 16000, then find the annual income of A?
A.Rs. 537600
B.Rs. 180000
C.Rs. 201600
D.Rs. 504000
Answer: A.Rs. 537600
Explanation: B's monthly income = 16000 * 112/100 = Rs. 17920
B's monthly income = 2 parts ----> Rs. 17920
A's monthly income = 5 parts = 5/2 * 17920 = Rs. 44800
A's annual income = Rs. 44800 * 12 = Rs. 537600
ANSWER:A
Question: Two stations A and B are 110 km apart on a straight line. One train starts from A at 4 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
A.15 a.m
B.10 a.m
C.7 a.m
D.02 a.m
Answer: C.7 a.m
Explanation: Suppose they meet x hours after 4 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
Therefore 20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 7 a.m.
Answer:C
Question: A dishonest dealer professes to sell his goods at Cost Price but still gets 25% profit by using a false weight. What weight does he substitute for a kilogram?
A.800 1/7 grams
B.800 grams
C.800 8/3 grams
D.883 1/3 grams
Answer: B.800 grams
Explanation: If the cost price is Rs.100, then to get a profit of 25%, the selling price should be Rs.125.
If 125kg are to be sold, and the dealer gives only 100kg, to get a profit of 25%.
How many grams he has to give instead of one kilogram(1000 gm).
125 gm ------ 100 gm
1000 gm ------ ?
(1000 * 100)/125 =800 grams.
Answer:B
Question: A man's speed with the current is 21 km/hr and the speed of the current is 4.3 km/hr. The man's speed against the current is
A.9.2
B.10.3
C.11.5
D.12.4
Answer: D.12.4
Explanation: Man's rate in still water = (21 - 4.3) km/hr = 16.7 km/hr.
Man's rate against the current = (16.7 - 4.3) km/hr = 12.4 km/hr.
Answer:D
Question: The sum of two numbers is 21 and the sum of their squares is 527. Find the product of the numbers.
A.48
B.41
C.46
D.43
Answer: D.43
Explanation: Let a and b be the two numbers(a+b)^2=a^2+2ab+b^2Given (a+b)=21 a^2+b^2=527So, 21^2=527+2ab2ab=527-4412ab=86ab=43Ans D
Question: If a, b, and c are consecutive positive integers and a > b > c, which of the following must be true?
I. c - a = 2
II. abc is an odd integer.
III. (a + b + c)/3 is an integer.
A. I only
B. II only
C. I and III only
D. II and III only
Answer: C. I and III only
Explanation: Since a, b, and c are consecutive positive integers and a < b < c, then c = a + 2, from which it follows that c - a = 2. So, I is true.
Next, out of 3 consecutive integers at least 1 must be even, thus abc=even. II is false.
Finally, since b = a + 1, and c = a + 2, then (a + b + c)/3 = (a + a + 1 + a + 2)/3 = a + 1 = integer. III is true as well.
Answer: C.
Question: If a tire rotates at 400 revolutions per minute when the car is traveling 96km/h, what is the circumference of the tire?
A.7 meters
B.9 meters
C.4 meters
D.5 meters
Answer: C.4 meters
Explanation: 400 rev / minute = 400 * 60 rev / 60 minutes
= 24,000 rev / hour
24,000 * C = 96,000 m : C is the circumference
C = 4 meters
correct answer C
Question: Approximately what percent of the employees with 5 or more years of employment are NOT taking either workshop?
A.86%
B.64%
C.50%
D.14%
Answer: B.64%
Explanation: Total = n(A) + n(B) - Both + None
None = Total - n(A) - n(B) + Both
Calculate "none" for each case
None(5+ yrs Line) = 200 - 50 - 40 + 30 = 140
None(5+ yrs Staff) = 160 - 40 - 50 + 20 = 90
Employees not taking either workshop/Total number of employees = (140 + 90)/(200 + 160) = 230/360 = About 64%
ANSWER:B
Question: A and B undertake to do a piece of work for $600. A alone can do it in 6days while B alone can do it in 8days. With the help of C, they finish it in 3days. Find the share of A?
A.$100
B.$150
C.$300
D.$250
Answer: C.$300
Explanation: C's 1day work = (1/3)-(1/6 + 1/8) = 1/24
A:B:C= 1/6 : 1/8: 1/24 = 4:3:1
A's share = 600*4/8 = $300
Answer is C
Question: The true discount on a bill due 9 months hence at 16% per annum is Rs. 171.The amount of the bill is
A.Rs. 1386
B.Rs. 1764
C.Rs. 1425
D.Rs. 2268
Answer: C.Rs. 1425
Explanation: Solution
32.5
Let P.W. be Rs. x.Then,S.I. on Rs.x at 16% for 9 months =Rs.171.
∴ x 16 x9/ 12x 1/100}= 171 or x = 1425.
∴ P.W. = Rs. 1425.
Answer C
Question: If the two-digit integers P and N are positive and have the same digits, but in reverse order, which of the following CANNOT be the sum of P and N?
A.181
B.165
C.121
D.99
Answer: A.181
Explanation: Since the question asks for the answer that CANNOT be the sum of P and N, and the answers are numbers, we can use a combination of TESTing VALUES and TESTing THE ANSWERS to eliminate the possible values and find the answer to the question.
We're told that P and N are two-digit positive integers and have the SAME DIGITS but in REVERSE ORDER. We're asked which of the 5 answers CANNOT be the SUM of P and N.
Let's start with the 'easiest' answer first:
44. Can we get to 44 in the manner described?
Yes, if the numbers are 13 and 31.....13+31 = 44. Eliminate Answer E
Now let's work through the rest of the list....
Can we get to 99 in the manner described?
Yes, there are several ways to do it. For example, if the numbers are 18 and 81.....18+81 = 99. Eliminate Answer D
Can we get to 121 in the manner described?
Yes, there are several ways to do it. For example, if the numbers are 38 and 83.....38+83 = 121. Eliminate Answer C
Can we get to 165 in the manner described?
Yes, there are a couple of ways to do it. For example, if the numbers are 78 and 87.....78+87 = 165. Eliminate Answer B
There's only one answer left....
A
Question: If f(a)=a^2, what is the value of (f(a+b)−f(b))/b ?
A.2a+a^2
B.b
C.2a
D.2a + b
Answer: A.2a+a^2
Explanation: start with f(a+b) before start calculations: f(a+b)=(a+b)^2= a^2+2ab+b^2
a^2+2ab+b^2 - b^2/b = (simplify a^2)
2ab+a^2/b = (cancel b's)
= 2a+a^2
Ans : A
Question: A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:
A.120 meter
B.300 meter
C.100 meter
D.200 meter
Answer: C.100 meter
Explanation: when B runs 25 m, A runs 22.5 m
=> When B runs 1000 metre, A runs 22.5/25 x 1000 = 900m.
=> When B runs 1 kilometre, A runs 900 m
Hence, in a kilometre race, B beats A by
ANSWER:C
(1 kilometre - 900 metre) = (1000 metre - 900 metre) = 100 metre
Question: The sum of the present ages of two persons A and B is 54. If the age of A is twice that of B, find the sum of their ages 5 years hence?
A.50
B.64
C.70
D.80
Answer: B.64
Explanation: A + B = 54, A = 2B
2B + B = 54 => B = 18 then A = 36.
5 years, their ages will be 41 and 23.
Sum of their ages = 41 + 23 = 64.
ANSWER:B
Question: A and B walk around a circular track. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. If they start at 8 a.m. from the same point in opposite directions, how many times shall they cross each other before 9.30 a.m.?
A.5
B.6
C.7
D.8
Answer: C.7
Explanation: Explanation:
Relative speed = Speed of A + Speed of B (∴ they walk in opposite directions)
=2+3=5 rounds per hour
Therefore, they cross each other 5 times in 1 hour and 2 times in 12 hour
Time duration from 8 a.m. to 9.30 a.m. =1.5 hour
Hence they cross each other 7 times before 9.30 a.m.
ANSWER IS C
Question: Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $10 more than 1/4 of the fine and Peter paid $10 less than 1/3 of the fine, leaving pay $25 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?
A.$120
B.$125
C.$130
D.$135
Answer: B.$125
Explanation: Call the fine F. Joe paid (1/4)F + 4 and Peter paid (1/3)F – 4, leaving (1/2)F – 5 left. If we add those three up, they should add up to F.
F = [(1/4)F + 10] + [(1/3)F – 10] + [(1/2)F – 25]
F = (1/4)F + (1/3)F + (1/2)F – 25
Multiply all terms by 12 to clear the fractions.
12F = 3F + 4F + 6F – 300
12F = 13 F – 300
–F = – 300
F = 300
Well, if the fine cost $300, then Sam paid the part not covered by Joe or Peter. Half the fine is $150, and Sam paid $25 less than this: $125
Answer = B
Question: Mary built a model ship. She spent 10 hours constructing the ship and 5 hours painting it, for what fraction of the total time did she spend painting the ship?
A.1/3
B.1/5
C.1/4
D.2/3
Answer: A.1/3
Explanation: We don't need to get into calculations for solving this question. We can use the concept of weighted averages.
The average time for the entire project is 15 hours; so, she spent a lesser duration of time painting the ship than constructing it.
5---(5---5)
This shows that you can divide the entire project into 3 equal parts. Thus, 1/3 of the journey was spent painting.
Answer: A
Question: A and B participate in a seven-person footrace on the basketball court during All-Star Weekend. If all seven contestants finish (including Charles Barkley) and there are no ties, how many different arrangements of finishes are there in which A defeats B ?
A. 5040
B. 2520
C. 720
D. 120
Answer: B. 2520
Explanation: PRINCETON REVIEW OFFICIAL SOLUTION:
A beats B? Carmelo beats B? No one said anything about specific results, especially not on a question that includes so many people.
Many questions on the GMAT can be overwhelming in appearance so first thing…Relax. This question looks nasty, but it’s pretty straightforward, requiring two things: the basic first calculation and then some additional work to solve the problem. It would be extremely painful to try to calculate this whole question in one fell swoop. So don’t.
Calculate out all possibilities first to get your bearings. That is, how many different arrangements, period? Since the order of arrangement again matters, this is another permutation. And since we’re placing all seven runners, this calculation is…
7 x 6 x 5 x 4 x 3 x 2 x 1, cash and prizes worth 5040 arrangements.
Now, what to do? Again, some nice deep breathing to control your nerves – relax and think. These 5040 arrangements are a comprehensive list; every possible seven-person order of finish has been counted. So, we have accounted for every time A beats B AND every time LeBron beats Carmelo. Doesn’t it make sense that, for every time Carmelo beats LeBron, there is exactly one other instance in which LeBron beats Carmelo? Or more simply, doesn’t it make sense that, if these 5040 represents everything, that Carmelo beats LeBron exactly 50% of the time and vice versa?
The thought takes time. You need to have the presence to recognize that grinding your way in, around, and through this question could take roughly forever. Stepping back and recognizing that this is simply a 50/50 proposition and applying that thought to the 5040 you cranked out gives you 2520. The answer is B.
Question: Half of 3 percent written as decimal is
A.5
B.0.5
C.0.05
D.0.015
Answer: D.0.015
Explanation: Explanation:
It will be 1/2(3%) = 1/2(3/100) = 3/200 = 0.015
Answer: Option D
Question: Jane and Thomas are among the 6 people from which a committee of 3 people is to be selected. How many different possible committees of 3 people can be selected from these 6 people if at least one of either Jane or Thomas is to be selected?
A.12
B.14
C.16
D.18
Answer: C.16
Explanation: The total number of ways to choose 3 people from 6 is 6C3 = 20.
The number of committees without Jane or Thomas is 4C3 = 4.
There are 20-4 = 16 possible committees which include Jane and/or Thomas.
The answer is C.
Question: In a class of 37 students 26 play football and play 20 long tennis, if 17 play above, many play neither?
A.6
B.8
C.10
D.12
Answer: B.8
Explanation: 26 + 20 - 17 = 29
37 - 29 = 8 play neither
Answer is B
Question: P can do a work in the same time in which Q and R together can do it. If P and Q work together, the work can be completed in 10 days. R alone needs 35 days to complete the same work. then Q alone can do it in
A.20
B.22
C.25
D.28
Answer: D.28
Explanation: Work done by P and Q in 1 day = 1/10
Work done by R in 1 day = 1/35
Work done by P, Q and R in 1 day = 1/10 + 1/35 =9/70
But Work done by P in 1 day = Work done by Q and R in 1 day . Hence the above equation can be written as Work done by P in 1 day Ã— 2 = 9/70
=> Work done by P in 1 day = 9/140
=> Work done by Q and R in 1 day = 9/140
Hence work done by Q in 1 day = 9/140â€“ 1/35 = 1/28
So Q alone can do the work in 28 days
Answer is D.
Question: 6 + 12 + 18 + 5 x 6^2 + 5 x 6^3 + 5 x 6^4 + 5 x 6^5 + 5 x 6^6 =
A. 6^7
B. 6^10
C. 6^12
D. 6^16
Answer: A. 6^7
Explanation: Let's see that 6 + 12 + 18 is 36 or 6^2, then: 6^2 + 5 x 6^2 becomes 6 x 6^2 that is 6^3. So we follow with the next element: 6^3 + 5 x 6^3 is equal to 6 x 6^3 that is 6^4. Then is assumed right before 5 x 6^6: 6^6 + 5 x 6^6 becomes 6 x 6^6 that is 6^7. Thus, the correct answer is the option A, 6^7.
Question: A car takes 6 hours to cover a distance of 180 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
A.50 Kmph
B.20 Kmph
C.65 Kmph
D.70 Kmph
Answer: B.20 Kmph
Explanation: Time = 6
Distence = 180
3/2 of 6 hours = 6 * 3/2 = 9 Hours
Required speed = 180/9 = 60 Kmph
B)
Question: How many positive integers less than 70 have a reminder 01 when divided by 3?
A.13
B.24
C.35
D.16
Answer: B.24
Explanation: 1 also gives the remainder of 1 when divided by 3. So, there are total of 24 numbers.
Answer: B.
Question: A plane flies 720 km with the wind and 630 km against the wind in the same length of time. If the speed of the wind is 15 km/h, what is the speed of the plane in still air?
A.205 km/h
B.215 km/h
C.225 km/h
D.235 km/h
Answer: C.225 km/h
Explanation: The speed of the plane in still air = x km/h
The speed of the wind is 15 km/h
Speed with the wind = (x + 15) km/h
Speed against the wind = (x â€“ 15) km/h
Time = Distance/ Speed
720 / (x+15) = 630 / (x-15)
720(x-15) = 630(x+15)
72x - 1080 = 63x + 945
9x = 2025
x = 225
Therefore, the speed of the plane in still air is 225 km/h.
The answer is C.
Question: Amar takes as much time in running 18 meters as a car takes in covering 48 meters. What will be the distance covered by Amar during the time the car covers 1.6 km?
A.328
B.288
C.2800
D.600
Answer: D.600
Explanation: Distance covered by Amar = 18/4.8 (1.6km)
= 3/8(1600)
= 600 m
Answer:D
Question: The sum of the digits of a two digit number is 7. When the digits are reversed then the number is decreased by 9. Then find the number
A.43
B.34
C.44
D.35
Answer: B.34
Explanation: Let the original no be 10x+y
Sum of the digits x+y=7
When the digits are reversed then it is 10y+x
Since it is decreased by 9 it is written as (10y+x)-(10x+y)=9 solving this we get y=4
Substitute in x+y=7 we get x=3
so the number is 34 correct ans is B
Question: Craig had 200 apples. He lost 20 apples and sold 43 apples. A customer returned one apple. How many apples did he have left?
A.137
B.138
C.135
D.140
Answer: B.138
Explanation: For lost, use negative. For gain, use positive.
200+-20+-43+1
correct answer is B)138
Question: The value of x is to be randomly selected from the integers from 1 to 8, inclusive, and then substituted into the equation y = x^2 - 4x + 3. What is the probability that the value of y will be negative?
A.1/4
B.1/8
C.1/2
D.3/8
Answer: B.1/8
Explanation: y will only be negative for x=2.
(We can check the values from 1 to 8 to be certain.)
P(y is negative) = 1/8
The answer is B.
Question: A man buy a book in Rs50 & sale it Rs70. What is the rate of profit ???
A.10%
B.40%
C.30%
D.25%
Answer: B.40%
Explanation: cp=50
sp=70
profit=70-50=20
%=20/50*100=40%
ANSWER:B
Question: John starts his journey from A to B and Tom starts his journey from B to A at the same time.After passing each other they complete their journeys in 3 1/3 and 4 4/5 hours respectively.Find the speed of Tom if John traveled at 12 miles/hr.
A.a) 8.33 m/hr
B.b) 9 m/hr
C.c) 10 m/hr
D.d) 20 m/hr
Answer: C.c) 10 m/hr
Explanation: Your calculations look perfect, but I think they answer a different question from the one the question designer intended. I don't find the wording of this question to be good at all, but I'm pretty sure what they mean is this: from the point in time at which John and Tom meet, it takes a *further* 3 1/3 hours for John to complete his journey, and a *further* 4 4/5 hours for Tom to complete his journey. So if it takes them t hours to meet, John will end up traveling for a total of t + 10/3 hours, and Tom a total of t + 24/5 hours. That's a more difficult problem than the one you solved. I don't have time to write up a solution at the moment, but I can later if that would be helpful.
C)
Question: find the number, difference between number and its 3/5 is 50.
A.120
B.123
C.124
D.125
Answer: D.125
Explanation: Explanation:
Let the number = x,
Then, x-(3/5)x = 50,
=> (2/5)x = 50 => 2x = 50*5,
=> x = 125
Answer: Option D
Question: A four digit number is such that the product of all of its digits is 126. The sum of all the digits is equal to the 2 digit number formed by using thousands digit and tens digit (Thousand digit in tens place & ten digit in units place) which in turn is equal to 19. Then difference of units and thousand place of the number is, given that this difference is positive.
A.1692
B.1792
C.1795
D.1892
Answer: B.1792
Explanation: the number is 1792.
Let the number be represented as 1000x+100y+10z+t
acc to ques,
xyzt=126
x + y + z + t = 10x + z = 19
so, number in thousands and tens place are 1 and 9 respectively.
the remaining factor is 14 which is 7*2
So the number is 1792.
ANSWER:B
Question: In a group of hats consisting of only blue hats, green hats, and purple hats, the ratio of blue hats to green hats to purple hats is 7:4:12. If there are a total of 115 hats in this group, how many of these hats are not blue?
A.28
B.42
C.48
D.80
Answer: D.80
Explanation: Since the hats Blue, Green and Purple are in ratio of 7:4:12...The total no. of balls will be
7x+4x+12x=115 or 23x=115...here 7x,4x and 12x represent hats of each type
23x=115 so x=5...Blue hats =7*5=35...Not blue will be 115-35=80.
Ans D
Question: In country Z, 10% of the people do not have a university diploma but have the job of their choice, and 15% of the people who do not have the job of their choice have a university diploma. If 40% of the people have the job of their choice, what percent of the people have a university diploma?
A.39%
B.45%
C.55%
D.65%
Answer: A.39%
Explanation: Setting up a matrix is how I solve this one.
Diploma No Diploma Totals
Job of Choice w/Diploma
Job of Choice w/o Diploma = 10%
Job of Choice Total = 40%
Not Job of Choice with Diploma =.15X
Not Job of Choice w/o Diploma= .85X
Total Not Job of Choice = X
Total with Diploma
Total without Diploma
Total citizen = 100
If 40% of people have their job of choice, then 60% of people do NOT have their job of choice. 15% of 60% = 9%. We can also see that 30% of the people have their job of choice and a diploma (40%-10%=30%). 30% + 9% = 39%. Therefore 39% of the people in Country Z have a diploma.
Ans A
Question: if a person has to divide equally $13011 among all his 12 people then how much minimum should he keep with himself so that he divides equally among all 12 people in whole numbers?
A.$1
B.$2
C.$3
D.$4
Answer: C.$3
Explanation: He would need to keep $ 3 to himself so he can give $ 1084 to all 12 people so option C is correct one
Question: if 50% of (x-y) = 40% of (x+y) then what percent of x is y?
A.2.5%
B.11%
C.5%
D.15%
Answer: B.11%
Explanation: 50% of (x-y)=40% of(x+y)
(50/100)(x-y)=(40/100)(x+y)
5(x-y)=4(x+y)
x=9y
x=9y
therefore required percentage
=((y/x) X 100)% = ((y/9y) X 100) =11%
Answer is B.
Question: After replacing an old member by a new member, it was found that the average age of eight members of a club is the same as it was two years ago.What is the difference between the ages of the replaced and the new member?
A.2 years
B.4 years
C.8 years
D.16 years
Answer: D.16 years
Explanation: Explanation :
Age decreased = (8 x 2) years
16 years
So, required difference =16 years.
Answer : D
Question: Nine coins are tossed simultaneously. In how many of the outcomes will the first coin turn up a head?
A.2^8
B.2^10
C.3 * 2^8
D.3 * 2^9
Answer: A.2^8
Explanation: Fix the first coin as H. The remaining8 coins have 2^8 outcomes.
Ans:A
Question: In how many W ways can the letters of the word JUPITER be arranged in a row so that the vowels appear in alphabetic order?
A. 736
B. 768
C. 792
D. 840
Answer: D. 840
Explanation: three letters can be arranged in 3! ways.
only one combination EIU is required.
7 letters can be arranged in 7! ways.
thus W=7!/ 3! * 1 = 840.
D
Question: A 600 meter long train crosses a signal post in 30 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?
A.4 min
B.2 min
C.8 min
D.3 min
Answer: D.3 min
Explanation: S = 600/30 = 20 mps
S = 3600/20 = 180 sec = 4 min
Answer: D
Question: A student writes a computer program that generates a sequence of numbers a1, a2, a3, ... such that a1=a2=1 and ak=a(k-1)*4+1 for 2<k<n. If n=15, find a5.
A.85
B.87
C.89
D.93
Answer: A.85
Explanation: a1=1
a2=1
a3=1*4+1=5
a4=5*4+1=21
a5=21*4+1=84+1=85
85
Question: The original price of a car was $30,000. Because the car owner thought he could get more money for the car, he set a new price by increasing the original price of the car by 10%. After a week, the car had not sold, so the owner discounted the new price by 10%, and the car was finally sold. What price was the car sold for?
A.$29,660
B.$29,680
C.$29,700
D.$29,720
Answer: C.$29,700
Explanation: The car was sold for (0.9)(1.1)($30,000)=$29,700.
The answer is C.