RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: 8 years ago, the age of Anand was one-third the age of Bala at that time. The present age of Bala is 12 years more than the present age of Anand. Find the present age of Anand?
A.12
B.13
C.14
D.15
Answer: C.14
Explanation: Let the present ages of Anand and Bala be 'a' and 'b' respectively.
a - 8 = 1/3 (b - 8) --- (1)
b = a + 12
Substituting b = a + 12 in first equation,
a - 8 = 1/3 (a + 4) => 3a - 24 = a + 4
=> 2a = 28=> a = 14.
ANSWER:C
Question: Sam, Suresh and Sanket run a race of 1400 meters. Sam runs twice as fast as Suresh while Suresh runs thrice as fast as Sanket. If Sanket finishes the race by clocking 15 minutes, how far was Suresh from the finish line when Sam must have finished the race?
A.450 m
B.680 m
C.700 m
D.900 m
Answer: C.700 m
Explanation: Explanation:
When Sanket finishes the race in 15 minutes, Suresh & Sam would finish the same race in 5 minutes and 2.5 minutes respectively. Thus, when Sam reaches the ”finish” mark, Suresh must be “half-way” through i.e. 700 meters behind the “finish” line when “Sam” must have finished the race
ANSWER C
Question: A man loses 1/3rd of his money, then wins Rs. 10 loses 1/3rd of what he has and wins Rs. 20 and finds that he has exactly what be had at the beginning. What was the amount he originally bad ?
A.25
B.36
C.10
D.48
Answer: D.48
Explanation: let x be that amount
so accordind to question , eqn will be like:
(((x-x/3)+10)-(((x-x/3)+10)/3))+20=x
=> ((2x/3+10)-((2x/3+10)/3))+20=x
=>3x-4x/3=80
=>x=48
ANSWER:D
Question: A is twice as good a work man as B and together they finish the work in 14 days. In how many days A alone can finish the work?
A.33
B.77
C.265
D.21
Answer: D.21
Explanation: WC = 2:1
2x + x = 1/14 => x = 1/42
2x = 1/21
A can do the work in 21 days.
Answer: D
Question: A train travels 210 km in 3 hours and 270 km in 4 hours.find the average speed of train.
A.80 kmph
B.69 kmph
C.70 kmph
D.90 kmph
Answer: B.69 kmph
Explanation: As we know that Speed = Distance / Time
for average speed = Total Distance / Total Time Taken
Thus, Total Distance = 210 + 270 = 480 km
Thus, Total Speed = 7hrs
or,Average Speed = 480/7
or, 69kmph.
ANSWER:B
Question: A(n+1)=1+(1/A(n)) and A(1)=1. What is the value of A(9)?
A.53/32
B.55/34
C.57/36
D.59/38
Answer: B.55/34
Explanation: A(n+1)=1+(1/A(n))
A(1) = 1
A(2) = 2
A(3) = 3/2
A(4) = 5/3
A(5) = 8/5
A(6) = 13/8
A(7) = 21/13
A(8) = 34/21
A(9) = 55/34
The answer is B.
Question: A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
A.502 m
B.298 m
C.500 m
D.189 m
Answer: C.500 m
Explanation: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60 = 65/3
x = 500 m.
Answer:C
Question: Each term of a certain sequence is 3 less than the previous term. The first term of this sequence is 15. If the sum of the first n terms of the sequence is n, what is the value of positive integer n?
A.1
B.11
C.15
D.19
Answer: B.11
Explanation: We know that it is a decreasing sequence i.e. the terms keep decreasing till 0 and then negative terms start.
What does this imply?If the sum of the first n terms of the sequence is n
Since number of terms will definitely be positive, we are looking for a positive sum.
10 + 7 + 4 + 1 -2 -5 -7 -10 .... and so on
Note that the first 7 terms are positive and all others negative. Every negative term has greater absolute value than the corresponding positive terms i.e. -2 absolute value is greater than 1 absolute value, -5 absolute value is greater than 4 absolute value, and so on...
Since we have 7 positive terms, we must have less than 7 negative terms to get the sum as positive. If we have 6 negative terms, we will have a total of 13 terms. Of the given options, only 13 is possible and hence it must be the answer.
Answer (B)
Question: . The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet?
A.10 a.m
B.10.30 a.m
C.11 a.m
D.11.30 a.m
Answer: C.11 a.m
Explanation: Suppose they meet x hrs after 8 a.m. Then,
(Distance moved by first in x hrs) + [Distance moved by second in (x - 1) hrs] = 330
60x + 75(x - 1) = 330 => x = 3
So, they meet at (8 + 3) i.e., 11 a.m.
ANSWER:C
Question: In how many ways can you seat 5 people on a bench if one of them does not want to sit on the middle seat or at either end?
A.40
B.44
C.48
D.52
Answer: C.48
Explanation: One person can choose 2 possible chairs to sit. The remaining 4 people can sit in 4! ways.
The number of arrangements is 2*4! = 48.
The answer is C.
Question: Of 30 applicants for a job, 16 had at least 4 years' experience, 21 had degrees, and 5 had less than 4 years' experience and did not have a degree. How many of the applicants had at least 4 years' experience and a degree?
A. 12
B. 10
C. 9
D. 7
Answer: A. 12
Explanation: set A : people with more than 4 years exp
set B : people with degree
AUB = total - (less than 4 exp and no degree)
AUB = 30-5=25
AUB = A + B - AiB
AiB = 21+16-25
=12
Answer A
Question: Six balls of different colors are to be placed in three different boxes such that any box contains at least 1 ball . What is the maximum number of different ways in which this can be done?
A.60
B.90
C.210
D.150
Answer: C.210
Explanation: Since the balls are all of different colors, let's permute them and then decide how many balls we put in each box.
For example, arrange in a row the balls, then decide: two balls go into the first box, next two in the second box, and the last ball goes to the third box.
Since in each box there must be at least one ball, we have the possibilities of (2,2,1), (2,1,2), (1,2,2) OR (3,1,1), (1,3,1), (1,1,3) balls in the three boxes.
For the 2,2,1 type arrangements, we have [5!/(2!2!1!)]*3 = 90 possibilities. Inside a box, it doesn't matter the order of the balls.
For the 3,1,1 type arrangements, we have [5!/(3!1!1!)]*3 = 60 possibilities.
Total of 120 + 90 = 210 possibilities.
Answer C.
Question: Subtract the absolute value from the local value of 4 in 564823
A.196
B.1996
C.2996
D.3996
Answer: D.3996
Explanation: Explanation:
Place value = Local value
Face value = Absolute value
The place value of 4 in 564823 is 4 x 1000 = 4000
The face value of 4 in 564823 is nothing but 4.
=> 4000 - 4 = 3,996
Answer: Option D
Question: P cando a work in 15 days and Q cando the same work in 20 days. If they can work together for 4 days, what is the fraction of work left?
A.3/5
B.4/5
C.8/15
D.7/11
Answer: C.8/15
Explanation: Amount of work P can do in 1 day = 1/15
Amount of work Q can do in 1 day = 1/20
Amount of work P and Q can do in 1 day = 1/15 + 1/20 = 7/60
Amount of work P and Q can together do in 4 days = 4 × (7/60) = 7/15
Fraction of work left = 1 – 7/15= 8/15
C
Question: In each series, look for the degree and direction of change between the numbers. In other words, do the numbers increase or decrease, and by how much
Look at this series: 21, 9, 21, 11, 21, 13, 21, ... What number should come next?
A.14
B.15
C.16
D.17
Answer: B.15
Explanation: B
15
In this alternating repetition series, the random number 21 is interpolated every other number into an otherwise simple addition series that increases by 2, beginning with the number 9.
Question: A butler stole wine from a butt of sherry which contained
40% of spirit and he replaced,what he had stolen by wine
containing only 16% spirit. The butt was then of 24%
strength only. How much of the butt did he steal?
A.1/3
B.2/3
C.1/4
D.1/8
Answer: B.2/3
Explanation: Wine containing 40%spirit Wine containing 16% spirit
Wine containing 24% spirit
8 16
They must be mixed in the ratio of =1:2.
Thus 1/3 of the butt of sherry was left
hence the butler drew out 2/3 of the butt.
ANSWER B
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
A.27
B.50
C.98
D.77
Answer: B.50
Explanation: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45 ==> x = 50 km/hr.Answer: B
Question: In the first hour of a two-hour trip, a car traveled d kilometers, and in the second hour of the trip, the car traveled a quarter that distance. What is the average rate at which the car traveled during the trip, in kilometers per hour?
A. d
B. 1/3*d
C. 1/2*d
D.5/8*d
Answer: D.5/8*d
Explanation: Solution:
Lets look at the information given in the question...
Total time travelled = 2 hrs
Distance travelled first hour = d
Distance travelled second hour = d/4
The question is asking for the avg speed at which the car travels for 2 hrs
We know that avg speed = total distance/total time
Lets place the information given in the question to the formula above = (d+d/4)/2
= 5/8*d
We find that option D is the answer as it gives the same expression as found in our calculation above. Answer option D.
Question: How many integers from 10 to 180, inclusive, are divisible by 3 but not divisible by 7?
A.45
B.49
C.50
D.52
Answer: B.49
Explanation: We should find # of integers divisible by 3 but not by 3*7=21.
# of multiples of 21 in the range from 10 to 180, inclusive is (168-21)/21+1=8;
57-8=49.
Answer: B.
Question: Five kids were walking down the street. At a shop, they saw three brands of chocolates viz. Cadbury, Nestle and Ferrero being displayed. The shopkeeper has three chocolates which are of three different flavors of each brand. The kids bought all the chocolates available and decided to play a game. The chocolates will be distributed only to the winners of that game. Also they have decided that any winner cannot have all three brands of chocolates as his prize. Find the number of ways in which the chocolates can be distributed when there are four winners of the game and the best of them gets at least 4 chocolates?
A.12312
B.22536
C.4320
D.11268
Answer: B.22536
Explanation: Since, one child cannot have more than two brands of chocolates, therefore, one child can get a maximum of six chocolates.
When there are four winners, the winners can have the chocolates in the following possible way
Case I
One of them gets six chocolates and the other three get one each.
The one who gets six chocolates can be selected in 4C1 ways and he will get any two brands out of three in 3C2 ways.
The three chocolates of the same brand will be distributed among the other three in 3! ways.
Hence, the total number of ways = 4 × 3 × 6 = 72
Case II
One of them gets 5 chocolates, one of them gets 2 chocolates and the other two get 1 each.
Kid with 5 chocolates:
The one who gets five chocolates can be selected in 4C1 ways and he will get any two brands out of three in 3C2 ways.
After choosing the two brands (say AB), he can get all three chocolates of one brand in 2 ways (i.e. either A or B). The other two chocolates can be chosen from the second brand in 3 ways. Thus, there are 4 × 3 × 2 × 3 = 36 ways
Kid with 2 chocolates:
This person can be chosen in 3 ways. Now, he can either get two chocolates from the same brand or from two different brands.
Thus, there are 6 × 3 = 18 ways
Kids with 1 chocolate each
The remaining chocolates can be distributed between the two remaining winners in 2 ways.
Therefore, total number of ways = 36 × 18 × 2 = 1296 ways.
Case III
Similarly for four chocolates the following combinations are possible:
a) 4 3 1 1
The number of ways = 4 × 3 × [{6 × 3(1 + ( 6 + 3))} + {1 × 9 × 3 (1 + 6)}] × 2 = 8856
b) 4 2 2 1
The number of ways = 4 × 3 × [{6 × 3(2 × 6 × 3 + (3 + 9))} + {9 × (9 + 9)}] = 12312
Since, the best of them can’t have less than 4 chocolates the above are the only cases applicable.
Hence, the total number of ways = 72 + 1296 + (8856 + 12312) = 22536.
Option B
Question: On dividing 122 by a number, the quotient is 6 and the remainder is 2. Find the divisor?
A.14
B.16
C.18
D.20
Answer: D.20
Explanation: d = (D-R)/Q
= (122 - 2)/6
= 122/6 = 20
D)
Question: A farmer needs 2400 ounces of corn to feed his pigs. How many pounds should he buy?
A. 120
B. 130
C. 140
D. 150
Answer: D. 150
Explanation: 1 pound = 16 ounces.
2400 ounces / 16 = 150 pounds.
Answer: D.
Question: How many minutes does it take John to type z words if he types at the rate of y words per minute?
A.z/y
B.y/x
C.xy
D.60x/y
Answer: A.z/y
Explanation: time*rate=job --> time*y=z --> time=z/y.
Answer: A.
Question: Nine men went to a hotel. Eight of them spent Rs.3 each over their meals and the ninth spent Rs.2 more than the average expenditure of all the nine. Determine the total money spent by them?
A.Rs.29.25
B.Rs.39.25
C.Rs.29.29
D.Rs.23.25
Answer: A.Rs.29.25
Explanation: Average of 9 = x
9x = 8 * 3 + x * 2 x = 3.25
Total = 9 * 3.25 = 29.25
Answer:A
Question: Two pipes A and B can fill a cistern in 20 and 30 minutes respectively, and a third pipe C can empty it in 40 minutes. How long will it take to fill the cistern if all the three are opened at the same time?
A.17 1/7
B.17 1/9
C.17 8/7
D.17 8/8
Answer: C.17 8/7
Explanation: 1/20 + 1/30 - 1/40
= 7/120
120/7
= 17 1/7
Answer:C
Question: How long does a train 100 m long travelling at 60 kmph takes to cross a bridge of 80 m in length?
A.15.8 sec
B.14.9 sec
C.12.4 sec
D.10.8 sec
Answer: D.10.8 sec
Explanation: D
16.8 sec
D = 100 + 80 = 180 m
S = 60 * 5/18 = 50/3
T = 180 * 3/50 = 10.8 sec
Question: Take number 1000 and then add 20 to it. Now add 1000 one more time. Now add 30. Now add 1000 one more time. Now add 40. Now add 1000 one more time. Now add 10. What is the total?
A.4100
B.3590
C.2800
D.3700
Answer: A.4100
Explanation: A
4100
Question: Water boils at 212°F or 100°C and melts at 32°F or 0°C . If the temperature of the particular day is 35°C , it is equal to
A.50°F
B.76°F
C.95°F
D.110°F
Answer: C.95°F
Explanation: Let F and C denotes the temparature in Fahrenheit anid Celcsius respectively.
Then, (F - 32) /(212 - 32) = (C - 0)/(100 - 0), if c = 35, then F = 95.
C
Question: Three consecutive traffic signals each show either red or green. How many different arrangements of the three signals are possible? (Note: “Red-redgreen” is different from “green-red-red.”)
A.10
B.9
C.8
D.7
Answer: C.8
Explanation: The best way to do this Q would be to find the ways separately for each type of arrangements..
all three of same colour= 1*2(for green and red)= 2..
two of one colour and third different colour= 3!/2!=3..
total= 1*2+3*2=8
ANSWER:C
Question: A boat can travel with a speed of 24 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 84 km downstream
A.3 hours
B.4 hours
C.5 hours
D.6 hours
Answer: A.3 hours
Explanation: Explanation:
Speed of the boat in still water = 24 km/hr
speed of the stream = 4 km/hr
Speed downstream = (22+5) = 28 km/hr
Distance travelled downstream = 84 km
Time taken = distance/speed = 84/28 = 3 hours
Answer: Option A
Question: The average of first six prime numbers greater than 65 is?
A.55
B.77
C.56
D.67
Answer: B.77
Explanation: 67 + 71 + 73 + 79 + 83 + 89 = 462/6 = 77
Answer: B
Question: The length of the bridge, which a train 150 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
A.766 m
B.156 m
C.245 m
D.225 m
Answer: D.225 m
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time
= 30 sec. Let the length of bridge be x meters. Then, (150 + X)/30 = 25/2
==> 2(150 + X) = 750 ==> X
= 225 m.
Answer: D
Question: A can do a piece of work in 12 days and B alone can do it in 14 days. How much time will both take to finish the work ?
A.A)3.2222
B.B)5
C.C)6.46
D.D)8.3333
Answer: C.C)6.46
Explanation: This question can be solved by different methods. We need to conserve time in exams so solving this problem using equations is the good idea.
Time taken to finish the job = XY / (X + Y)
= 12 x 14 / (12 + 14)
= 150 / 25
= 6.46 days
Answer: C
Question: The mean salary in ICM ltd. was Rs 1500, and the standard deviation was Rs 400. A year later each employee got a Rs 100 raise. After another year each employee's salary was increased by 20%. The standard deviation of the current salary is?
A.Rs 400
B.Rs 480
C.Rs 600
D.Rs 700
Answer: B.Rs 480
Explanation: Mean salary was Rs 1500
Standard deviation = Rs 400
After 1 year all the employees got a uniform rise of Rs 100.
So, there will be no change in standard deviation.
After another year, every employee's salary was increased by 20%.
So, standard deviation will be increased by 20%.
Standard deviation=400×
120
100
= Rs 480
Answer B
Question: Find the sum lend at C.I. at 5 p.c per annum will amount to Rs.240 in 2 years?
A.217
B.287
C.400
D.288
Answer: A.217
Explanation: Explanation:
240 = P(21/20)2
P = 217
Answer:A
Question: If k is a non-negative integer and 15^k is a divisor of 823,435 then 5^k - k^5 =
A.0
B.1
C.35
D.120
Answer: B.1
Explanation: 8+2+3+4+3+5 = 25, so this number is not divisible by 3 and thus not divisible by 15.
Therefore, k=0
5^k - k^5 =1-0=1
The answer is B.
Question: A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?
A.111.12
B.111.13
C.111.22
D.111.0
Answer: A.111.12
Explanation: A runs 1000 m while B runs 900 m and C runs 800 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 800)/900 = 8000/9
= 888.88 m.
B can give C = 1000 - 888.88
=111.12m.
Answer:A
Question: The perimeter of an equilateral triangle is 60. If one of the sides of the equilateral triangle is the side of an isosceles triangle of perimeter 65, then how long is the base of isosceles triangle?
A.10
B.15
C.20
D.25
Answer: D.25
Explanation: The base of the isosceles triangle is 65-20-20= 25 units
The answer is D.
Question: A train is moving at a speed of 132 km/hr. If the length of the train is 200 meters, how long will it take to cross a railway platform 295 meters long
A.6 ½ sec
B.7 ½ sec
C.8 sec
D.13 ½ sec
Answer: D.13 ½ sec
Explanation: Explanation:
Speed of train = 132 ×(5/18) m/sec = 110/3 m/sec.
Distance covered in passing the platform = (200 + 295) m = 495 m.
Time taken =495 ×(3/110) sec =27/2 sec = 13 ½ sec
Answer: Option D
Question: A car traveling at a certain constant speed takes 2 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 225 kilometers per hour. At what speed, in kilometers per hour, is the car traveling?
A.220
B.200
C.210
D.225
Answer: B.200
Explanation: B
225 * T = 1 km => T = 1/225 km/h
V*(T+2/3600) = 1
V (1/225 + 2/3600) = 1 => V = 200 km/h
Question: Q is not equal to zero and k = (Q x n - s)/2.What is n?
A.(2 x k + s)/Q
B.(2 x s x k)/Q
C.(2 x k - s)/Q
D.(2 x k + s x Q)/Q
Answer: A.(2 x k + s)/Q
Explanation: k=(Q*n-s)/2
=> (2k+s)/Q = n
ANSWER:A
Question: What is the measure of the radius of the circle inscribed in a triangle whose sides measure 8, 15 and 19 units?
A.2.8 units
B.6 units
C.3 units
D.5 units
Answer: A.2.8 units
Explanation: Sides are 8, 15 and 19...thus it is right angle triangle Since 19^2 = 8^2 + 15^2
therefore, area = 1/2 * 15 * 8 = 60
We have to find in-radius
Therefore, area of triangle = S*r ....where S=semi-perimeter and r= in-radius
Now S=semi-perimeter = 19+15+8 /2 = 21
Thus , 60 =21*r
and hence r=in-radius= 2.8
Option A
Question: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.84. How much was lent at 5%?
A.228
B.299
C.266
D.600
Answer: D.600
Explanation: (x*5*1)/100 + [(1500 - x)*6*1]/100 = 84
5x/100 + 90 â€“ 6x/100 = 84
x/100 = 6
=> x = 600
Answer:D
Question: A woman complete a journey in 10 hours. She travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
A.334 km.
B.216 km.
C.314 km.
D.224 km.
Answer: D.224 km.
Explanation: D
224 km.
0.5x/21 + 0.5x/24 = 10
--> x/21 + x/24 = 20
--> 15x = 168 x 20
--> x = (168 x 20)/15 = 224 km.
Question: An employer has 8 applicants for a programming position and 4 applicants for a manager position. If the employer must hire 3 programmers and 2 managers, what is the total number of ways the employer can make the selection?
A.a) 1,490
B.b) 132
C.c) 336
D.d) 60
Answer: C.c) 336
Explanation: 8C3 * 4C2 = 336. Answer C.
Question: The calendar of the year 2060 can be used again in the year?
A.2081
B.2083
C.2088
D.1971
Answer: C.2088
Explanation: Explanation:
Given year 2060 when divided by 4, leaves a remainder 0.
NOTE: When remainder is 0, 28 is added to the given year to get the result.
So, 2060 + 28 = 2088
Answer: C
Question: To be considered for “movie of the year,” a film must appear in at least 1/4 of the top-10-movies lists submitted by the Cinematic Academy’s 775 members. What is the smallest number of top-10 lists a film can appear on and still be considered for “movie of the year”?
A.191
B.194
C.193
D.212
Answer: B.194
Explanation: Total movies submitted are 775.
As per question we need to take 1/4 of 775 to be considered for top 10 movies = 193.75
approximate the value we 194.
IMO option B is the correct answer...
Question: A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
A.288 m
B.256 m
C.500 m
D.278 m
Answer: C.500 m
Explanation: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (800 + x)/60
= 65/3
x = 500 m.
Answer:C
Question: The cost of a Personal computer was $2,000 in 1990. In 2000, the price had decreased to $500. What was the percent decrease in the cost of the Personal computer?
A.25%
B.-30%
C.-75%
D.40%
Answer: C.-75%
Explanation: Decrease = 2000-500 = 1500
% decrease = 1500*100/2000 = -75%
Answer: option C
Question: A man rows his boat 105 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
A.5 kmph
B.7 kmph
C.12 kmph
D.8 kmph
Answer: C.12 kmph
Explanation: Speed downstream = d/t = 105/(2 1/2) = 42 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (42 - 18)/2 = 12 kmph
Answer:C
Question: The first train leaves the station at 6:00 am with a speed of 60 km/hr. The second train leaves at 7:15 am, in the same direction from the same station, with a speed of 75 km/hr. What time will the second train catch the first train?
A.11:15 am
B.11:45 am
C.12:15 pm
D.12:45 pm
Answer: C.12:15 pm
Explanation: In seventy-five minutes, the first train travels 75 km.
The second train catches the first train with a relative speed of 15 km/h.
The second train will catch the first train in 5 hours.
The second train will catch the first train at 12:15 pm.
The answer is C.
Question: How many such letter-pairs are there in the word SERVANT having the same no. of letters left between them in the word as they have in the series?
A.2
B.3
C.4
D.5
Answer: A.2
Explanation: 1 pair is S & V
1 pair is N &S
total 2 pair
ANSWER: A
Question: At 1:00 pm, there were 10.0 grams of bacteria. The bacteria increased to x grams at 4:00 pm, and 22.5 grams at 7:00 pm. If the amount of bacteria present increased by the same fraction during each of the 3-hour periods, how many grams of bacteria were present at 4:00 pm?
A.14.4
B.14.7
C.15.0
D.15.3
Answer: C.15.0
Explanation: Let x be the factor by which the bacteria increases every three hours.
At 4:00 pm, the amount of bacteria was 10x and at 7:00 pm it was 10x^2.
10x^2 = 22.5
x^2=2.25
x=1.5
At 4:00 pm, the amount of bacteria was 10(1.5)=15 grams.
The answer is C.
Question: In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 27 to the thrice of the remainder. The dividend is
A.74
B.78
C.186
D.92
Answer: C.186
Explanation: Divisor = (6 * 3) + 27 = 45
5 * Quotient = 45
Quotient = 9.
Dividend = (Divisor * Quotient) + Remainder
Dividend = (20 * 9) + 6 = 186.
C)
Question: A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.300
B.350
C.360
D.370
Answer: B.350
Explanation: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.
Answer: Option B