RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If the sides of a triangle are 26 cm, 24 cm and 12 cm, what is its area?
A.120 cm2
B.112 cm2
C.144 cm2
D.666 cm2
Answer: C.144 cm2
Explanation: The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.
Area of the triangle = 1/2 * 24 * 12 = 144 cm2
Answer: C
Question: Which one of the following numbers is a solution of the equation
(x(2sq)-2)(x(2sq) + 6)(x(third3)-8) = 0?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: One checks each of the ve given possible answers. Since 2-3third- - 8 = 0, the answer
is 2.
correct answer B
Question: Rs. 850 becomes Rs. 956 in 3 years at a certain rate of simple interest.If the rate of interest is increased by 4% ,What amount will Rs. 850 become in 3 years ?
A.Rs. 1020.80
B.Rs. 1025
C.Rs. 1058
D.Data inadequate
Answer: C.Rs. 1058
Explanation: Solution
S.I. = Rs.(956-850 )=Rs.106
Rate = (100x106/850x3) = 212/51%
New rate = (212/51 +4)% = 416/51%
New S.I. = Rs.(850 x416/51x3/100) Rs. 208.
∴ New amount = Rs.(850+208)= Rs. 1058.
Answer C
Question: Instead of multiplying a number by 2, the number is divided by 10. What is the percentage of error obtained ?
A.94%
B.92%
C.95%
D.93%
Answer: C.95%
Explanation: let the number be x
the right number is 2x
the wrong number is x/10
error is(2x-x/10)=19x/10
percentage of error is((19x/10)/2x)*100=95%
ANSWER:C
Question: Eight years ago, P was half of Q's age. If the ratio of their present ages is 3:4 what will be the total of their present ages?
A.33
B.67
C.28
D.31
Answer: C.28
Explanation: Let present age of P and Q be 3x3x and 4x4x respectively.
Eight years ago, P was half of Q's age
â‡’(3xâˆ’8)=1/2(4xâˆ’8)
â‡’6xâˆ’16=4xâˆ’8
â‡’2x=8
â‡’x=4
Total of their present ages
=3x+4x=7x=7Ã—4=28
C
Question: Albert invested amount of 4000 in a fixed deposit for 2 years at compound interest rate of 5 % per annum. How much Albert will get on the maturity of the fixed deposit
A.Rs. 8510
B.Rs. 8620
C.Rs. 4410
D.Rs. 8820
Answer: C.Rs. 4410
Explanation: Explanation:
=>(4000×(1+5/100)2)
=>4000×21/20×21/20
=>4410
Option C
Question: Total dinning bill for 6 people was $211.00.If they add 15% tip and divided the bill evenly ,approximate.What was each persons find share
A.$30.14
B.40.44
C.34.66
D.32.29
Answer: B.40.44
Explanation: 211*15=3165/100=31.65
211+31.65=242.65
242.65/6=40.44
ANSWER:B
Question: If x is a positive even number, then each of the following is even odd EXCEPT
A.(x + 3)(x + 5)
B.x^2 +4
C.x^2 + 6x + 9
D.3x^2 + 4
Answer: B.x^2 +4
Explanation: Since it is given tht x is even number, so any integer multiplied with x will also be even..
so, we should concentrate only on other terms..
lets see the choices..
A. (x + 3)(x + 5)
We have two terms with x and each is added with a odd number..
each bracket becomes odd and Odd*Odd=Odd
B. x^2 + 5
here we are adding an Odd number to even.. so E + O=O
C. x^2 + 6x + 9
here we are again adding an Odd number to even.. so E +E + O=O
D. 3x^2 + 4
here we are adding an Even number to even.. so E + E=E..
so tjis is our answer
E. 5(x + 3)
again O*O=O
B
Question: Barbata invests $2400 in the National Bank at 5%. How much additional money must she invest at 10% so that the total annual income will be equal to 6% of her entire investment?
A.120
B.600
C.1000
D.360
Answer: B.600
Explanation: Let the additional invested amount for 10% interest be x;
Equation will be;
2400+0.05*2400+x+0.10x = 2400+x+0.06(2400+x)
0.05*2400+0.10x = 0.06x+0.06*2400
0.04x = 2400(0.06-0.05)
x = 2400*0.01/0.04 = 600
Ans:B
Question: The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. What is the length of the rectangle?
A.20cm
B.40cm
C.30cm
D.60cm
Answer: B.40cm
Explanation: Let breadth =x cm
Then, length =2x cm
Area =x×2x=2x2 sq.cm.
New length =(2x−5) cm
New breadth =(x+5) cm
New area =(2x−5)(x+5) sq.cm.
Given that, new area = initial area +75 sq.cm.
⇒(2x−5)(x+5)=2x2+75⇒2x2+10x−5x−25=2x2+75⇒5x−25=75⇒5x=75+25=100⇒x=1005=20 cm
Length =2x=2×20=40cm
Answer is B.
Question: 54 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day?
A.A)57
B.B)77
C.C)66
D.D)55
Answer: C.C)66
Explanation: (54 * 8)/30
= (x * 6)/50
=> x =120
120 – 54
= 66
Answer:C
Question: How many bricks, each measuring 25 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm?
A.3488
B.37799
C.6400
D.2777
Answer: C.6400
Explanation: Explanation:
Number of bricks \frac{800\times 600\times 22.5}{25\times 11.25\times 6} = 6400
Answer: C) 6400
Question: Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.
A.335 cm2
B.885 cm2
C.285 cm2
D.825 cm2
Answer: C.285 cm2
Explanation: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (20 + 18) * (15)
= 285 cm2
Answer: C
Question: Four car rental agencies A, B, C and D rented a plot for parking their cars during the night. A parked 15 cars for 12 days, B parked 12 cars for 20 days, C parked 18 cars for 18 days and D parked 16 cars for 15 days. If A paid Rs. 1125 as rent for parking his cars, what is the total rent paid by all the four agencies?
A.3388
B.2678
C.2977
D.6150
Answer: D.6150
Explanation: The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15
= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60
Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.
The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k
It is given that A paid Rs. 1125
45k = 1125 => k = 25
246k = 246(25) = Rs. 6150
Thus the total rent paid by all the four agencies is Rs. 6150.
\Answer: D
Question: If the cost price of 12 items is equal to the selling price of 16 items, the loss percent is
A.20%
B.25%
C.30%
D.35%
Answer: B.25%
Explanation: Explanation:
Let the Cost Price of 1 item = Re. 1
Cost Price of 16 items = 16
Selling Price of 16 items = 12
Loss = 16 - 12 = Rs 4
Loss % = (4/16)* 100 = 25%
Option B
Question: Avinash covers a distance of 8km in 50 minutes. If he covers 3km distance in 2/5th of time then, What speed should he maintain to cover the remaining distance in the remaining time?
A.15 Kmph
B.17 Kmph
C.21 Kmph
D.23 Kmph
Answer: A.15 Kmph
Explanation: Total distance = 8 Km
Total time = 50 Km
Time taken to cover the distence of 3 Km = 50*2/5 = 20 min = 1/3 hours
Remaining distance = 8 - 3 = 5 Km
Required speed = 5/1/3 = 15 Kmph
Option 'A'
Question: Carl is facing very difficult financial times and can only pay the interest on a $10,000 loan he has taken. The bank charges him a quarterly compound rate of 5%. What is the approximate interest he pays annually?
A.$1200
B.$2000
C.$2150
D.$2500
Answer: C.$2150
Explanation: since the options did not make sense with 5% annual rate of interest, it is apparent that the intent was a 5% quarterly rate. So the bank charges 5% every quarter and compounds it in the next quarter. Had it been a simple quarterly rate, we would have just found 4 * 5% of 10,000 = $2000 as our answer.
But since, the interest is compounded, it will be a bit more than $2000. Option (C) looks correct.
ANSWER:C
Question: The population of a town is 45000; 5/9th of them are males and the rest females 40% of the males are married. What is the percentage of married females?
A.28%
B.50%
C.32%
D.34%
Answer: B.50%
Explanation: Male = 45,000* 5/9 = 25,000
Female = 45,000* 4/9 = 20,000
Married Male = 25,000* 40/100 = 10,000
Married Female = 10,000
20,000 ------------ 10,000
100 ------------- ? => 50%
Answer:B
Question: If a no. when divided by 44, gives 432 as quotient and 0 as remainder. What will be the remainder when dividing thesame no. by 31
A.2
B.4
C.5
D.6
Answer: C.5
Explanation: P ÷ 44 = 432
=> P = 432 * 44 = 19008
P / 31 = 19008 / 31 = 613, remainder = 5
C
Question: Two pipes A and B can fill a cistern in 12 and 15 minutes respectively. Both are opened together but after 4 minutes A is turned off. After how much more time will the cistern be filled?
A.6
B.8 1/1
C.8 1/4
D.8 1/2
Answer: A.6
Explanation: 4/12 + (4 + x)/15 = 1
x = 6
Answer: A
Question: If √a+√b=a+b means then (√a+√b)^2=?
A.a^2+b^2
B.a^2+b^2+2*a*b
C.a+b
D.√a^2+√b^2
Answer: B.a^2+b^2+2*a*b
Explanation: Option B is answer.
√a+√b=a+b then (√a+√b)^2=(a+b)^2=a^2+b^2+2*a*b.
Question: At a particular graduation party with 300 guests, 70% of the guests brought gifts, and 40% of the female guests brought gifts. If 36 males did not bring gifts to the party, how many females did bring gifts?
A.18
B.36
C.42
D.68
Answer: B.36
Explanation: the correct method
total = 300..
70% of 300 = 210 got gifts..
90 did not get gift, out of which 48 are males, so remaining 90-36=54 are females..
But 40% females brought gift, so 60% did not get it..
so 60% = 54, 100%= 54*100/60= 90..
ans 40% of 90 =36
B
Question: A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
A.18 sec
B.16 sec
C.76 sec
D.15 sec
Answer: B.16 sec
Explanation: Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 280 * 2/35 = 16 sec
Answer:B
Question: If a particular is never chosen, in how many ways can a cricketbe chosen out of 15 players?
A.200
B.230
C.364
D.354
Answer: C.364
Explanation: A particular players is never chosen, it means that 11 players are selected out of 14 players.
=> Required number of ways = 14C11
= 14!/11!x3! = 364
C
Question: Calculate the circumference of a circular field whose radius is 2 centimeters.
A.2
B.4
C.6
D.8
Answer: B.4
Explanation: Circumference C is given by
C = 2Ï€r = 2Ï€*2 = 4 Ï€ cm
correct answer B
Question: Two trains, each 100 m long are moving in opposite directions. They cross each other in 8 seconds. If one is moving twice as fast the other, the speed of the faster train is
A.75 km/hr
B.60 km/hr
C.35 km/hr
D.70 km/hr
Answer: B.60 km/hr
Explanation: Total distance covered = 100+100 = 200 m
Time = 8 s
let speed of slower train is v . Then the speed of the faster train is 2v
(Since one is moving twice as fast the other)
Relative speed = v + 2v = 3v
3v = 200/8 m/s = 25 m/s
=> v = 25/3 m/s
Speed of the faster train = 2v = 50/3 m/s = (50/3)×(36/10) km/hr
= 5×36/3 = 5×12
= 60 km/hr
ANSWER:B
Question: A car crosses a 600 m long bridge in 5 minutes. Whatis the speed of car in km per hour?
A.1 m/sec
B.7.2 km/hr
C.3 m/sec
D.4 m/sec
Answer: B.7.2 km/hr
Explanation: Speed = 600 m/sec.
5 x 60
= 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
= 2 x 18 km/hr
5
= 7.2 km/hr
B
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
A.82.1 sec.
B.12.1 sec
C.19.1 sec.
D.17.1 sec.
Answer: B.12.1 sec
Explanation: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.
Answer: B
Question: When the positive integer x is divided by 9,the remainder is 5.What is the remainder when 4x is divided by 9?
A.0
B.1
C.2
D.4
Answer: C.2
Explanation: i tried plugging in numbers
x = 9q+5
x = 14
4x = 56
4x/9 = 9*6+2
remainder is 2.
Answer is C
Question: In how many ways can 16 different gifts be divided among four children such that each child receives exactly four gifts?
A.16^4
B.(4!)^4
C.16!/(4!)^4
D.16!/4!
Answer: C.16!/(4!)^4
Explanation: Total 16 different Gifts, and 4 children.
Thus any one child gets 16C4 gifts,
then the other child gets 12C4 gifts(16 total - 4 already given),
then the third one gets 8C4 gifts,
and the last child gets 4C4 gifts.
Since order in which each child gets the gift is not imp, thus, ans :
16C4 * 12C4 * 8C4 * 4C4 = 16! / (4!)^4
Ans : C.
Question: Consider below info to be a table:
AMOUNT OF BACTERIA
TIME - AMOUNT
1PM - 10gms
4PM - x gms
7PM - 19.6 gms
Data for a certain biology experiment are given in the table above. If the amount of bacteria present increased by the same factor during each of the two 3-hour periods shown, how many grams of bacteria were present at 4PM ?
A.12.0
B.13.0
C.12.2
D.12.3
Answer: B.13.0
Explanation: let say the factor is x, the at 7PM quantity = 10 (i.e. quantity @1PM)* x^2 =19.6 => x^2 =1.96 or x = 1.3 => @4PM quantity = 10x =10*1.3 =13.
Answer B
Question: The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
A.288
B.200
C.999
D.277
Answer: C.999
Explanation: a2 = 3136 => a = 56
56 * 4 * 3 = 672 – 6 = 666 * 1.5 = 999
Answer:C
Question: Find the numbers which are in the ratio 3:2:2 such that the sum of the first and the second added to the difference of the third and the second is 20?
A.12,8,8
B.4,4,22
C.9,3,32
D.9,6,12
Answer: A.12,8,8
Explanation: Let the numbers be a, b and c.
a:b:c = 3:2:2
Given, (a + b) + (c - b) = 20
=> a + c = 20
=> 3x + 2x = 20 => x =4
a, b, c are 3x, 2x, 2x
a, b, c are 12, 8, 8.
Answer:A
Question: There is a church tower 150 feet tall and another catholic tower at a distance of 350 feet from it which is 200 feet tall. There is one each bird sitting on top of both the towers. They fly at a constant speed and time to reach a grain in b/w the towers at the same time. At what distance from the church is the grain?
A.170 meters
B.160 meters
C.150 meters
D.140 meters
Answer: C.150 meters
Explanation: If x ft is the distance of grain from 200 ft tall tower, then
150^2 +(350-x)^2= 200^2 + x^2
then
x= 150 meters
ANSWER:C
Question: How many 3-digit numbers are completely divisible 6 ?
A.149
B.150
C.151
D.166
Answer: B.150
Explanation: Explanation:
3-digit number divisible by 6 are: 102, 108, 114,... , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
a + (n - 1)d = 996
102 + (n - 1) x 6 = 996
6 x (n - 1) = 894
(n - 1) = 149
n = 150
Number of terms = 150.
ANSWER IS B
Question: In each series, look for the degree and direction of change between the numbers. In other words, do the numbers increase or decrease, and by how much
Look at this series: 2, 1, (1/2), (1/4), ... What number should come next?
A.1/8
B.1/4
C.2/5
D.2/7
Answer: A.1/8
Explanation: A
1/8
This is a simple division series; each number is one-half of the previous number. In other terms to say, the number is divided by 2 successively to get the next result.
4/2 = 2
2/2 = 1
1/2 = 1/2
(1/2)/2 = 1/4
(1/4)/2 = 1/8 and so on.
Question: The ratio of two numbers is 1:3 and the sum of their cubes is 945. The difference of number is?
A.5.23
B.1.23
C.3.93
D.3.23
Answer: D.3.23
Explanation: 1x 3x
1x cube + 27x cube = 945
28x cube = 945
x cube = 33.75 => x = 3.23
ANSWER:D
Question: An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
A.16 2/9%
B.16 3/3%
C.16 2/2%
D.13 2/3%
Answer: D.13 2/3%
Explanation: 600 ---- 100
100 ---- ? => 16 2/3%
Answer: D
Question: If ‘DELHI’ is coded as ‘EFMIJ’, then ‘PUNE’ is coded as
A.QVOF
B.TGFR
C.RFDE
D.QVOO
Answer: A.QVOF
Explanation: D= 4 = 4+1 = 5 = E
E = 5 =5+1 =6 = F
SIMILARLY,
P = 16 = 16+1 = 17 = Q
U = 21 = 21+1 = 22 = V
N = 14 = 14+1 = 15 = O
E = 4 = 4 +1 = 5 = F
SO ANS IS
QVOF
Question: A man buys Rs. 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:
A.12
B.15
C.18
D.20
Answer: B.15
Explanation: Explanation:
Dividend on Rs. 20 = Rs. (9/100) x 20 = Rs.9/5.
Rs. 12 is an income on Rs. 100.
Rs.9/5 is an income on Rs.[ (100/12) x (9/5)] = Rs. 15.
Answer: B
Question: In a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:
A.75 cu. m
B.750 cu. m
C.7500 cu. m
D.75000 cu. m
Answer: B.750 cu. m
Explanation: 1 hectare = 10000 sq mtr
The volume of water that falls on 1.5 hectares of ground = 0.05*1.5*10000 = 75*10 cu, mtr = 750 cub mtr .
ANSWER:B
Question: The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is:
A.6.06%
B.6.07%
C.6.08%
D.6.09%
Answer: D.6.09%
Explanation: Explanation:
Amount of Rs. 100 for 1 year = Rs.[100 x (1 + 3/100)2]=Rs. 106.09
when compounded half-yearly
Effective rate = (106.09 - 100)% = 6.09%
ANSWER IS D
Question: For how many integers pair (x,y) satisfies the result
(1/x)+((1/y)=1/19
A.a)22
B.b) 6
C.c) 10
D.d) 16
Answer: A.a)22
Explanation: It seems that the accepted answer is wrong, according to WolframAlpha. The answer should be 32, which isn't even listed as a selectable answer.
A
Question: 53, 53, 40, 40, 27, 27, ?
A.14
B.12
C.16
D.18
Answer: A.14
Explanation: First, each number is repeated, then 13 is subtracted to arrive at the next number.
Answer : A.
Question: If a: b :: 3 : 7, then what is (5a+6b): (a-4b)?
A.57:11
B.-57:11
C.11 : 10
D.-57 : 25
Answer: D.-57 : 25
Explanation: a/b= 3/7
Dividing numerator & denominator of ' (5a+6b)/(a-2b) 'by b,
[5(a/b)+6]/[(a/b)-4]= [5*(3/7)+6]/[(3/7)-4]= -57/25
ANSWER:D
Question: The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).
A.178.27
B.178.29
C.178.21
D.178.19
Answer: B.178.29
Explanation: Calculated average height of 35 boys = 180 cm.
Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm - 166 cm + 106 cm
= 180 * 35 cm - 166 cm + 106 cm/35 = 180 cm - 60 /35 cm
= 180 cm - 1.71 cm = 178.29 cm.Answer:B
Question: If it takes a hrs for x to repair 1 machine and b hrs for y to repair 1 machine then how many hrs will they take to repair 750 machines if they work together?
A.750 × ab/(a+b)
B.750 (a+b)/ab
C.750 ab
D.750/(a+b)
Answer: A.750 × ab/(a+b)
Explanation: Explanation:
x repair machine in a hrs he work 1/a for 1 hr
y repairs machine in b hrs he works 1/b for 1 hr
(x+y) work per 1 hr = 1/a+1/b= (a+b)/ab
time = ab/(a+b)
for 750 machines time = 750 × ab/(a+b)
Answer: Option A
Question: In a box of 11 pens, a total of 3 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?
A.5/11
B.16/33
C.28/55
D.38/77
Answer: C.28/55
Explanation: # defective pens = 3
# good pens = 8
Probability of the 1st pen being good = 8/11
Probability of the 2nd pen being good = 7/10
Total probability = 8/11 * 7/10 = 28/55
The answer is C.
Question: After allowing a discount of 15% on the marked price, the selling price is Rs. 6800 for an article. If it was sold at marked price, there would have been a profit of 60%. The cost price of the article is?
A.2338
B.2298
C.5000
D.2871
Answer: C.5000
Explanation: Explanation:
Given SP = Rs. 6800
Marked price = [SP(100)]/(100 - d%) = (6800 * 100)/(100 - 15) = Rs. 8000
If SP = Rs. 8000, profit = 60%
CP = [SP(100)]/(100 + 60) = (8000 * 100)/160 = Rs. 5000
Answer:C
Question: A tradesman by means of his false balance defrauds to the extent of 30%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
A.60%
B.70%
C.69%
D.71%
Answer: C.69%
Explanation: g% = 30 + 30 + (30*30)/100
= 69%
ANSWER:C
Question: If A earns 99/3% more than B,how much percent does B earn less then A ?
A.42%
B.14%
C.25%
D.15%
Answer: C.25%
Explanation: Required Percentage = [((100/3)*100)/[100+(100/3)]]%
=[(100/400)*100]%=25%
Answer is C.
Question: The sum of the present ages of a son and his father is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, what will be son's age?
A.100
B.40
C.80
D.20
Answer: D.20
Explanation: Let the present age of the son =x
Then, present age of the father =(60−x)
Six years ago father's age was 5 times the age of the son
(60-X)-6=5(X-6)
84=6X
X=84/6=14
Son's age after 6 years
=X+6=14+6=20
answer is D.
Question: From the word 'HEARTLESS', how many independent words can be made with-out changing the order of the letters and using each letter only once ?
A.5
B.8
C.3
D.2
Answer: A.5
Explanation: Explanation:
The words formed are
HE, ART, LESS, HEART and EAR
Answer: A) 5
Question: By the how much is two-fifth of 150 greater than three -fifths of 25?
A.15
B.3
C.45
D.30
Answer: C.45
Explanation: Reqd no. = 2â„5 Ã— 150 - 3â„5 Ã— 25
= 60 - 15 = 45
Answer C
Question: A gardener wants to plant trees in his garden in such a way that the number of trees in each row should be the same. If there are 4 rows or 5 rows or 6 rows, then no tree will be left. Find the least number of trees required
A.22
B.60
C.28
D.76
Answer: B.60
Explanation: Explanation:
The least number of trees that are required = LCM(4, 5, 6) = 60.
Answer: B
Question: During the second quarter of 1984, a total of 3,976,000 domestic cars were sold. If this was 32% greater than the number sold during the first quarter of 1984, how many were sold during the first quarter ?
A.714,240
B.2,261,760
C.2,400,000
D.3,012,121
Answer: D.3,012,121
Explanation: Let number of cars sold in 1st quarter = x
Number of cars sold in 2nd quarter = 32% greater than the number sold during the first quarter = (1 + 32/100)x = 1.32 x
1.32 x = 3,976,000
=> x = 3,012,121
So, answer will be D
Question: What is the difference between the place value and face value of 3 in the numeral 1375?
A.287
B.290
C.297
D.390
Answer: C.297
Explanation: place value of 3 = 3 * 100 = 300
face value of 3 = 3
300 - 3 = 297
C
Question: A certain sum of money doubles itself in 12 years in how much many years will it trible itself at the same rate?
A.20 years
B.76 years
C.24 years
D.44 years
Answer: C.24 years
Explanation: 100 ---- 100 --- 12
100 --- 12
--------------------
300 ---- 24 years
Answer: C
Question: Jerry, an electrician, worked 6 months out of the year. What percent
of the year did he work? (round answer to the nearest hundredth)
What percent 12 is 6? 12 months = 1 year
A.58.33%
B.68.33%
C.78.33%
D.50.00%
Answer: D.50.00%
Explanation: 1. Multiply the opposites
6 x 100 = 600
100=6/12
50% (rounded to hundredth)
correct answer D
Question: A textile manufacturing firm employees 70 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 70 looms is Rs 5,00,000 and the monthly manufacturing expenses is Rs 1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs 75000. If one loom breaks down and remains idle for one month, the decrease in profit is:
A.13000
B.7000
C.10000
D.5000
Answer: D.5000
Explanation: Explanation :
Profit = 5,00,000âˆ’(1,50,000+75,000) =Rs. 2,75,000.
Since, such loom contributes equally to sales and manufacturing expenses.
But the monthly charges are fixed at Rs 75,000.
If one loan breaks down sales and expenses will decrease.
New profit :-
=>500000Ã—(69/70)âˆ’150000Ã—(69/70)âˆ’75000.
=>Rs 2,70,000.
Decrease in profit
=>2,75,000âˆ’2,70,000
=>Rs. 5,000.
Answer : D
Question: Jeya invested an amount of Rs. 9,500 at the rate of 13% p.a simple interest and another amount at the rate of 15% p.a. simple interest. The total interest earned at the end of one year on the total amount invested became 14% p.a. Find the total amount invested?
A.15550
B.18450
C.13450
D.14450
Answer: D.14450
Explanation: Let the second amount be Rs. x. Then,
(9500 * 13 * 1)/100 + (x * 15 * 1)/100 = [(12000 + x) * 14 * 1] / 100
12350+ 15x= 16800 + 14x
x = 4450
Total investment = 10000 + 4450 = Rs. 14450 .Answer: D
Question: In a classroom, 12 students brought apples and 8 students brought bananas. If exactly 10 students brought only one of the two types of fruits, how many students brought both types of fruits?
A.5
B.6
C.7
D.12
Answer: A.5
Explanation: Say x students brought both fruits.
(12 - x) + (8 - x) = 10 --> x = 5.
Answer: A.
Question: Helen went to the stationers and bought things worth Euro 45, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
A.Euro 15
B.Euro 15.7
C.Euro 19.7
D.Euro 39.7
Answer: D.Euro 39.7
Explanation: Explanation: Let the amount taxable purchases be Euro x.
Then, 6% of x = 30/100
x = (30/100 x 100/6) = 5.
Cost of tax free items = Euro [45 - (5 + 0.30)] = Euro 39.70
Answer: Option D