RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Keats Library purchases a number of new books, all in the category of biography, and the library does not acquire any other books. With the addition of the new biographies, the biography collection of the library amounts to 32% of the total number of books in the library. If prior to the purchase, only 20% of the books in Keats Library were biographies, by what percent has the number of biographies in the library increased?
A.60%
B.72%
C.88%
D.95%
Answer: C.88%
Explanation: Let x be the number of new biographies added to the library.
Let b be the original number of biographies, so the original number of books was 5b.
0.32(5b+x) = b+x
0.6b = 0.68x
x = 0.88b
The answer is C.
Question: Which of the following is the best approximation for y?
1/2−1/3+1/6−1/10+1/12−1/14+1/16
A.0.1
B.0.31
C.0.35
D.0.4
Answer: B.0.31
Explanation: 1/2 - 1/3 +1/6-1/10+1/12-1/14+1/16
=> 1/2 [1+1/3-1/5+1/6-1/7+1/8] - 1/3
=> 0.5 [ 1+0.33-0.2+0.167-0.142+0.125] - 0.33
=> 0.31
Option B
Question: The students of a particular class were given two tests for evaluation. Twenty Five percent of the class cleared both the tests and forty five percent of the students were able to clear the first test.
You have to calculate the percentage of those students who passed the first test and were also able to pass the second test. How will you do it?
A.48%
B.55%
C.60%
D.71%
Answer: C.60%
Explanation: C
60%
In all such cases where you have to find out the probability of anything with an already given situation, you have to use the formula for conditional probability.
In this case, you have to find out the probability that the second test was passed by a student given that he passed the first test already.
Therefore, P(Second/First) = P (First and Second)/ P (First)
= 0.25/0.42
=0.60
=60 %
Question: How many different possible arrangements can be obtained from the letters G, M, A, T, I, I, and T, such that there is at least one character between both I's?
A.360
B.720
C.900
D.1800
Answer: C.900
Explanation: A= all possible permutations = 7!/2!2!
B= permutations with II together = 6!/2!
A-B = 900
ANSWER:C
Question: Caleb spends $70.50 on 50 hamburgers for the marching band. If single burgers cost $1.00 each and double burgers cost $1.50 each, how many double burgers did he buy?
A.5
B.10
C.20
D.41
Answer: D.41
Explanation: Solution -
Lets say, Single hamburgersxand Double hamburgersy
Given that,
x+y=50 and 1x+1.5y=70.50. By solving the equations y=41. ANS D.
Question: A tourist purchased a total of $1,700 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
A.$1,430
B.$1,310
C.$1,290
D.$1,470
Answer: D.$1,470
Explanation: since total cashed checks = 7 ans $10 check cashed = one less or more than $50 checks
Therefore either $10 checks = 3 and $50 checks = 4 OR $10 checks = 4 and $50 checks = 3
using this information 1st option gives us the maximum cashed value therefore if we negate this value from total value we will get minimum value of which checks have lost
Therfore 1700 - 230 = 1470 hence answer is D
Question: The least number which when divided by 2,3, 4 and 6 leaves a remainder 3, but when divided by 9 leaves no remainder, is
A.17
B.27
C.25
D.33
Answer: B.27
Explanation: Explanation:
L.C.M of 2, 3, 4, 6= 12
therefore Required Number is of the form 12k+3.
Least value of k for which (12k+3) is divisible by 9 is k = 2
therefore Required Number = (12 x 2+3)=27. Answer: B
Question: A customer bought a product at the shop. However, the shopkeeper increased the price of the product by 20% so that the customer could not buy the required amount of the product. The customer managed to buy only 70% of the required amount. What is the difference in the amount of money that the customer paid for the second purchase compared to the first purchase?
A.16%
B.18%
C.20%
D.22%
Answer: A.16%
Explanation: Let x be the amount of money paid for the first purchase.
The second time, the customer paid 0.7(1.2x)=0.84x.
The difference is 16%.
The answer is A.
Question: If (A-B-C+D = 12) and (A+B-C-D = 6), what is the value of (B-D)^2?
A.4.
B.9.
C.12.
D.16.
Answer: B.9.
Explanation: EQ1: A - B - C + D = 12
EQ2: A + B - C - D = 6
(1) Subtract EQ1 from EQ2
A - B - C + D = 12
- A +B - C - D = 6
------------------------
-2B + 2D = 6
(2) Simplify
-B + D = 3
B - D = -3
(B-D)^2 = (-3)^2 = 9
My answer: B
Question: Of the families in City X in 2001, 25 percent owned a personal computer. The number of families in City X owning a computer in 2008 was 15 percent greater than it was in 2001, and the total number of families in City X was 6 percent greater in 2008 than it was in 2001. what percent of the families in City X owned a personal computer in 2008?
A.27.12%
B.23.12%
C.25.55%
D.31.22%
Answer: A.27.12%
Explanation: Say a 100 families existed in 1994 then the number of families owning a computer in 1994 - 25
Number of families owning computer in 1998 = 25 * 115/100 = 28.75
Number of families in 1998 = 106
The percentage = 28.75/106 * 100 = 27.12%.
ANSWER:A
Question: A rectangular cube has a volume of 9 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is?
Choices
A.24
B.48
C.81
D.72
Answer: D.72
Explanation: Lets say the sides of the rectangular cube are x, y and z. Problem states volume is 9.
i.e,
x*y*z = 9 .
If every side is increased twice as before. then new volume is
2x*2y*2z = 9*(x*y*z) = 8*9 = 72.
Answer is D
Question: John throws a coin until a series of seven consecutive heads or three consecutive tails appears. What is the probability that the game will end after the eighth throw?
A.1/128
B.2/16
C.3/16
D.7/16
Answer: A.1/128
Explanation: Let's consider the routes that would lead to ending the game on the fourth toss. In order to be a win at that point, tosses #2#3#4 would all have to be the same, either H or T, and in order for the game NOT to end on the third toss, the first toss would have to be different from the other four. Thus, the only two possible sequences are
H-T-T-T--T-T-T-T ----> P = (1/2)^8 = 1/256
T-H-H-H-H-H-H-H ----> P = (1/2)^8 = 1/256
Either one of these would satisfy the condition, so we could have one or the other. OR means add in probability.
1/256 + 1/256 = 2/256 = 1/128
Answer(A).
Question: Bhajan Singh purchased 120 reams of paper at Rs 80 per ream. He spent Rs 280 on transportation, paid octroi at the rate of 40 paise per ream and paid Rs 72 to the coolie. If he wants to have a gain of 8 %, what must be the selling price per ream?
A.90
B.89
C.87.48
D.86
Answer: A.90
Explanation: Explanation:
Total investment = Rs. (120 * 80 + 280 + (40/100) * 120 + 72).
= Rs. (9600 + 280+48 + 72) = Rs, 10000.
Sell price of 120 reams = 108% of Rs. 10000 = Rs. 10800.
Sell Price per ream = Rs. [10800/120] = Rs. 90. Answer: A
Question: Seed mixture X is 40% ryegrass and 60% bluegrass by weight; seed mixture Y is 25% ryegrass and 75% fescue. If a mixture of X and Y contains 34% ryegrass, what percent of the weight of the mixture is from mixture X?
A.25%
B.40%
C.50%
D.60%
Answer: D.60%
Explanation: 34% is 9%-points above 25% and 6%-points below 40%.
Thus the ratio of mixture Y to mixture X is 2:3.
The percent of mixture X is 3/5 = 60%.
The answer is D.
Question: The H.C.F of two numbers is 11 and their L.C.M is 7700. If one of the numbers is 275 , then the other is
A.344
B.387
C.308
D.299
Answer: C.308
Explanation: Explanation:
other number = \inline \fn_jvn \left ( \frac{11\times 7700}{275} \right ) = 308
Answer: C) 308
Question: Find the greatest number, which will divide 260, 281 and 303, leaving 7, 5 and 4 as remainders respectively.
A.23
B.24
C.25
D.26
Answer: A.23
Explanation: Ans: We have to find the HCF of (260 - 7, 281 - 5, 303 - 4) = HCF (253, 276, 299) = 23
Answer A
Question: Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years.
A.893.09
B.392.98
C.306.04
D.830.48
Answer: C.306.04
Explanation: A = 5000(51/50)3
= 5306.04
5000
-----------
306.04
Answer:C
Question: In a certain brick wall, each row of bricks above the bottom row contains one less brick than the row just below it. If there are 6 rows in all and a total of 135 bricks in the wall, how many bricks does the bottom row contain ?
A.21
B.20
C.22
D.19
Answer: B.20
Explanation: The bottom row has x bricks
x+x-1+x-2+x-3+x-4+x-5 = 135
6x-15=135
6x=120
x= 20
Answer:B
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 57 kmph, find the speed of the stream?
A.19
B.88
C.14
D.12
Answer: A.19
Explanation: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 57/3 = 19 kmph.
Answer:A
Question: A total of 115 homes within Verde county were damaged during a terrible storm. The county had an emergency fund of $509,862.50 to be disbursed among households that incurred damage. The funds were distributed so that two story homes received $6,219.70 whereas one story homes received $3109.85. What was the number of damaged one story homes?
A.75
B.80
C.95
D.100
Answer: A.75
Explanation: Let x = two story homes
115 - x = one story homes
6219.70x + 3109.85(115 - x) = 590862.50
6219.70x + 357623.75 - 3109.85x = 590862.50
3109.85x = 233238.75
x = 75
Answer: A
Question: How many arrangements can be made out of the letters of the word 'ENGINEERING'?
A.277200
B.92400
C.69300
D.23100
Answer: A.277200
Explanation: The word 'ENGINEERING' contains 11 letters, namely 3E, 3N, 2G, 2I and 1R.
Required number of arrangements =11!/(3!)(3!)(2!)(2!)(1!)=277200
Answer is A
Question: If x, y, and z are consecutive positive integers greater than 1, not necessarily in that order, then which of the following is (are) true?
I. x > z
II. 5x+ 5y >5z
III. yz > xz
IV. xy > y + z
A. I only
B. II only
C. II and III only
D. II and IV only
Answer: B. II only
Explanation: we do not know the values or the relative values but that the three are consecutive..
so the max difference in any two number is 2 and min 1..
lets see the choices..
I. x > z...
we do not know the values or the relative values... need not be true..
II. 5x+ 5y >5z or x+ y > z
we take the worst case that z is teh largest and x and y are lowest possible..... so 2+3>4.. 5>4.. always true
III. yz > xz
we do not know the values or the relative values between x and y..need not be true
IV. xy > y + z
xy-y>z or y(x-1)>z...
again lets take the worst scenario..
we take the worst case that z is the largest and x and y are lowest possible..... so (2-1)3>4.. 3>4.. not true
only ii is true
ans B
Question: On a map the distance between two mountains is 310 inches. The actual distance between the mountains is 136 km. Ram is camped at a location that on the map is 34 inch from the base of the mountain. How many km is he from the base of the mountain?
A.14.83
B.14.81
C.14.91
D.14.82
Answer: C.14.91
Explanation: Explanation:
Since 310 inch = 136 km
So 1 inch = 136/310 km
So 34 inch = (136 Ã— 34)/ 310 = 14.91 km
Answer: C
Question: If the fraction 9/6 is equivalent to 6/a, then a is
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: Solution:
If the fractions are equivalent, then 9 × a = 36
a = 36 ÷ 9 = 4
Answer A
Question: The sum of four consecutive even numbers is 52, Find the third number ?
A.14
B.10
C.12
D.16
Answer: A.14
Explanation: Let the first number be n
Let the second number be n + 2
Let the third number be n + 4
Let the third number be n + 6
n + n + 2 + n + 4 + n + 6 = 52
Combine like terms:
4n + 12 = 52
4n + 12 = 52
4n = 52 - 12
4n = 40
n = 10
n + 2 = 12
n + 4 = 14
n + 6 = 16
The third number is 14
Answer: A
Question: An insect leaps 48 centimeters in 1.2 seconds. What is its speed?
A.0.4 meters per second
B.4 meters per second
C.40 meters per second
D.4 centimeters per second
Answer: A.0.4 meters per second
Explanation: 48 / 1.2 = 40 cm/s = 0.4 m/s
The answer is A.
Question: A man sells two articles for Rs.3600 each and he gains 40% on the first and loses 40% on the next. Find his total gain or loss?
A.16% loss
B.400
C.4000
D.324
Answer: A.16% loss
Explanation: (40*40)/100 = 16%loss
ANSWER:A
Question: If x and y are integers and x divided by y is 22.15, then which of the following integers is a possible value for the remainder when x is divided by y? I. 15 II. 5 III. 3
A.II,III only
B.I,III only
C.I,II only
D.I only
Answer: B.I,III only
Explanation: x=22.15y from which x = 22y + 15y/100 or x = 22y + 3y/20.
Since x and y are integers, 3y/20 must also be an integer. 3 is not divisible by 20, then y must be divisible by 20, and therefore, y/20 is an integer and 3y/20 is an integer which is a multiple of 3. From the given answers, only 15 and 3 are divisible by 3.
Answer B
Question: Solution for 4.75+.303+.432
A.2.91
B.5.911
C.5.485
D.5.986
Answer: C.5.485
Explanation: 4.75+.303+.432=0
0=0-4.75-0.303-0.432
0=-5.485
answer :C
Question: The price of an item is discounted 6 percent on day 1 of a sale. On day 2, the item is discounted another 6 percent, and on day 3, it is discounted an additional 10 percent. The price of the item on day 3 is what percentage of the sale price on day 1?
A.82.3%
B.84.6%
C.85.6%
D.89.6%
Answer: B.84.6%
Explanation: Let initial price be 100
Price in day 1 after 6% discount = 94
Price in day 2 after 6% discount = 88.36
Price in day 3 after 10% discount = 79.52
So, Price in day 3 as percentage of the sale price on day 1 will be = 79.52//94*100 => 84.6%
Answer will definitely be (B)
Question: In a recent head-to-head run-off election, 12,000 absentee ballets were cast. 1/2 of the absentee ballets were thrown out and 1/2 of the remaining absentee ballets were cast for Candidate A. How many absentee votes did Candidate B receive?
A.2,000
B.3,000
C.6,000
D.8,000
Answer: B.3,000
Explanation: 1/2 * 1/2 (total absentee votes) = 1/4 (total votes)=1/4*12000=3000
Answer is B
Question: A person covered one-fourth of the total distance at 22 kmph and remaining distance at 24 kmph. What is the average speed for the total distance?
A.21 (7/8)kmph
B.23 (7/15)kmph
C.23 (7/3)kmph
D.27 (1/13)kmph
Answer: B.23 (7/15)kmph
Explanation: Let the total distance be x km
total time taken = (x/4)/22 + (3x/4)/24 = x/88 + x/32 = 15x/352
Average speed = x/(15x/352) = 352/15kmph
= 23 (7/15)kmph.
Answer:B
Question: In what time will a train 120 m long cross an electric pole, it its speed be 160 km/hr?
A.2.5 sec
B.2.9 sec
C.2.7 sec
D.8.7 sec
Answer: C.2.7 sec
Explanation: Speed = 160 * 5/18 = 44 m/sec
Time taken = 120/44 = 2.7 sec.
Answer: C
Question: A person travels equal distances with speeds of 50km/hr,100km/hr and 120km/hr and takes a total time of 23 minutes. The total distance is?
A.15km
B.30km
C.45km
D.50km
Answer: B.30km
Explanation: Let the total distance be 3x km
x/50 + x/100 + x/120 = 23/60
23x/600 = 23/60
23x = 230
x = 10km
Total distance = 3x = 30km
Answer is B
Question: The price of a book is increased from $300 to $360. What is the % of increase in its price?
A.10%
B.20%
C.40%
D.50%
Answer: B.20%
Explanation: Explanation: Change in the price = Rs 360 – Rs 300
= Rs 60
Percentage of increase = Change in the price Initial Price
* 100.
Percentage increase in price =( 60 300
) *100 = 20%
B
Question: A rabbit on a controlled diet is fed daily 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If the rabbit`s diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?
A.100
B.140
C.150
D.160
Answer: B.140
Explanation: Let there be X and Y gm of food.
0.10 X + 0.15 Y = 38
or 10 X + 15 Y = 3800 -----(1)
X + Y = 300 ---------(2)
1) + 2) Eliminating Y, we get
X = 140 gm
ANSWER:B
Question: 50 % of 2 is equal to
A.0.2
B.1.0
C.0.6
D.0.7
Answer: B.1.0
Explanation: 50 % of 2 = (50 / 100) * 2 = 1.0
Answer: Option B
Question: The time a passenger train takes to cross another freight train is twice when the passenger train crosses the freight train running in opposite directions. What is the ratio of their speeds?
A.1:3
B.3:1
C.1:4
D.4:1
Answer: B.3:1
Explanation: let speed of freight train=x and speed of passenger train=y, and sum of their length =s so time=s/(x-y),when both are in same direction and time=s/(x+y) when oppsite direction.from question,s/(x-y)=2.s/(x+y) so solving this we get, x/y=3/1.
so x:y=3:1
ANSWER:B
Question: A person took some amount with some interest for 3 years, but increase the interest for 1%, he paid Rs.240/- extra, then how much amount he took?
A.Rs.8000/-
B.Rs.6000/-
C.Rs.4000/-
D.Rs.7000/-
Answer: A.Rs.8000/-
Explanation: Explanation:3 years = Rs.240/-year = 240/3Rate of Interest = 1%100/1% × 240/3 = Rs.8000/-P = Rs.8000/- Answer: Option A
Question: The present worth of a sum due sometime hence is Rs.576 and the banker’s gain is Rs.16.The true discount is
A.Rs.36
B.Rs.72
C.Rs.48
D.Rs.96
Answer: D.Rs.96
Explanation: Solution
T.D	= √P.W xB.G
= √576 x 16
= 96.
Answer D
Question: In a certain school, 25% of students are below 8 years of age. The number of students above 8 years of age is 2/3 of the number of students of 8 years of age which is 36. What is the total number of students in the school?
A.72
B.80
C.120
D.150
Answer: B.80
Explanation: Explanation: Let the number of students be x.
Then, Number of students above 8 years of age = (100 - 25)% of x = 75% of x.
75% of x = 36 + 2/3 of 36
75/100x = 60
x = 80.
Answer: Option B
Question: If 1+2+3+...+n=n (n+1), then
3 (1+3+5+....+99)=?
A.7000
B.7250
C.7500
D.7750
Answer: C.7500
Explanation: Explanation :
To solve this use the formula of AP,
Sn= (n/2)(a+l) ................(1)
To find n, use
=> Tn= a+(n-1)d
=> 99=1+(n-1)2
=> n=50
Use value of n in (1)
then,
Sn = (50/2)(1+99) = 2500
Ans:- 3(Sn) = 7500
Answer : C
Question: ASvennumber is defined as a five-digit number which goes according to the following rules: the leftmost digit is even, any digit to the right of an even digit must be an odd digit, and any digit to the right of an odd digit can only be one of the digits 1 or 7. How many different 4-digit numbers areSvennumbers?
A.20
B.80
C.160
D.220
Answer: A.20
Explanation: ASvennumber is defined as a five-digit number which goes according to the following rules: the leftmost digit is even, any digit to the right of an even digit must be an odd digit, and any digit to the right of an odd digit can only be one of the digits 1 or 7. How many different 5-digit numbers areSvennumbers?
4/9*5/10*2/10*2/10*2/10=160/9000
A. 20
Question: Rajan and Rakesh started a business and invested Rs. 20,000 and Rs. 25,000 respectively. After 4 months Rakesh left and Mukesh joined by investing Rs. 15,000. At the end of the year there was a profit of Rs. 4,600. What is the share of Mukesh?
A.900
B.100
C.1100
D.1200
Answer: D.1200
Explanation: Ratio of share of Rajan, Rakesh nd Mukesh => 20000:25000:15000
=>4:5:3
=>4*12 : 5*4 : 3*8 [Since Rakesh left after 4 months nd Mukesh joined after 4 months...]
=> 12:5:6
Share of Rajan => 4600*12/23 = 2400
Share of Rakesh => 4600*5/23 = 1000
Share of Mukesh => 4600*6/23 = 1200
ANSWER:D
Question: A single discount equivalent to the discount series of 20%, 10% and 5% is?
A.31.9
B.31.7
C.31.6
D.31.54
Answer: C.31.6
Explanation: 100*(80/100)*(90/100)*(95/100) = 68.4
100 - 68.4 = 31.6
Answer:C
Question: Find the compound interest on $ 16,000 at 20% per annum for 9 months, compounded quarterly
A.2532
B.2552
C.2524
D.2522
Answer: D.2522
Explanation: Principal = $ 16000; Time = 9 months =3 quarters;
Rate = 20% per annum = 5% per quarter.
Amount = $ [16000 x (1+(5/100))^3] = $ 18522.
CI. = $ (18522 - 16000) = $ 2522.
Answer D.
Question: Robert is traveling on his cycle and has calculated to reach point A at 2 p.m. if he travels at 10 km/hr; he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 p.m.?
A.109
B.12
C.99
D.81
Answer: B.12
Explanation: Let the distance traveled be x km.
Then, x/10 - x/15 = 2
3x - 2x = 60 => x = 60 km.
Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.
So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.
Required speed = 60/5 = 12 kmph.
Answer: B
Question: Mrs. Rodger got a weekly raise of $145. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.
A.$ 231
B.$ 545
C.$ 145
D.$ 643
Answer: C.$ 145
Explanation: Let the 1st paycheck be x (integer).
Mrs. Rodger got a weekly raise of $ 145.
So after completing the 1st week she will get $ (x+145).
Similarly after completing the 2nd week she will get $ (x + 145) + $ 145.
= $ (x + 145 + 145)
= $ (x + 290)
So in this way end of every week her salary will increase by $ 145.
correct answer C
Question: A, B, C are three consecutive positive integers (A>B>C). What is the value of the expression 2A +B - 2C?
A.6A+7.
B.A+3.
C.5A-1.
D.6A-5.
Answer: B.A+3.
Explanation: B = A-1
C= A-2
Putting these values in 2A +B -2C we get A +3
B is the answer
Question: 50, 47, 45, 42, 40, 37, 35, ?
A.33
B.32
C.31
D.30
Answer: B.32
Explanation: This is an alternating number subtraction series. The pattern is -3, -2, -3, -2, ....
The answer is B.
Question: ramesh,ram,kareem and Mohan collected coins of different countries. they collected 100 together. none collected less than 10.each collected an even number. each collected a different number. based on these, we can say that the number of coins collected by the boy who collected the most could not have exceeded
A.54
B.64
C.58
D.60
Answer: B.64
Explanation: as other three must have collected atleast 10+12+14=36 coins
the number of coins collected by the boy who collected the most could not have exceeded
100-36=64
ANSWER:B
Question: 64 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
A.13.25
B.28
C.30
D.13.2
Answer: B.28
Explanation: x/7 = y/9 => x:y = 7:9
7/16 * 64 = 28
ANSWER:B
Question: A woman is 18 years older than her son. In 3 years, her age will be twice the age of her son. The present age of her son is
A.18
B.17
C.15
D.16
Answer: C.15
Explanation: Explanation:
Let the son's present age be x years. Then, woman's present age = (x + 18) years
=> (x + 18) + 3 = 2(x + 3)
=> x + 21 = 2x + 6
So, x = 15. Answer: C
Question: The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is?
A.22
B.67
C.40
D.88
Answer: C.40
Explanation: Let the numbers be 2x and 3x.
Then, their L.C.M = 6x. So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
Answer:C
Question: What is the Positive integer that can be Added by 595 to make it a perfect square?
A.2*3*6
B.3*2*5
C.5*3*3
D.2*3
Answer: B.3*2*5
Explanation: 596 is added to a number that gives a perfect square
Nearest perfect square is 625.
so,625-596=30
30=2*3*5
Option B is answer
Question: Two airplanes take off from one airfield at noon. One flies due east at 203 miles per hour while the other flies directly northeast at 283 miles per hour. Approximately how many miles apart are the airplanes at 2 p.m.?
A.166
B.332
C.406
D.483
Answer: C.406
Explanation: C
In two hours:
the plane flying East will be 406 miles away from airport.
the other plane will be 566 miles away from airport.
566/406= ~1.4 = ~sqrt(2)
This means that planes formed a right isocheles triangle => sides of such triangles relate as 1:1:sqrt(2) => the planes are 406 miles apart.C
Question: A train 110 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
A.5
B.6
C.7
D.9
Answer: B.6
Explanation: Speed of train relative to man = 60 + 6 = 66 km/hr.
= 66 * 5/18 = 55/3 m/sec.
Time taken to pass the men = 110 * 3/55 = 6 sec.Answer: B
Question: If the numerator of a fraction is increased by 20% and its denominator is diminished by 25% value of the fraction is 2/15. Find the original fraction.
A.1/12
B.1/8
C.1/6
D.1/4
Answer: A.1/12
Explanation: X * (120/100)
---------------- = 2/15
Y * (75/100)
X/Y = 1/12
ANSWER:A