RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The area of a square garden is Q square feet and the perimeter is P feet. If Q=P+32, what is the perimeter of the garden in feet?
A.32
B.36
C.40
D.44
Answer: A.32
Explanation: Let x be the length of one side of the square garden.
x^2 = 4x + 32
x^2 - 4x - 32 = 0
(x-8)(x+4) = 0
x = 8, -4
P = 4(8) = 32
The answer is A.
Question: A rectangular field has to be fenced on three sides leaving a side of
20
20 feet uncovered. If the area of the field is
680
680 sq. feet, how many feet of fencing will be required?
A.95
B.92
C.88
D.82
Answer: C.88
Explanation: Area of the field=680 sq. feet.
Length of the adjacent sides are 20 feet and 680/20=34feet.
Required length of the fencing=20+34+34=88 feet
ANSWER:C
Question: Let f(x) = x^2 + bx + c. If f(1) = 0 and f(-5) = 0, then f(x) crosses the y-axis at what y-coordinate?
A.-5
B.-1
C.0
D.1
Answer: A.-5
Explanation: When x = 1 and when x = -5, the expression f(x) = x² + bx + c equals 0.
Then f(x) = (x-1)(x+5)
f(0) = -5
The answer is A.
Question: If the time is currently 1:30pm, what time will it be in exactly 649 hours?
A.12:30am
B.1:30am
C.12:30pm
D.2:30pm
Answer: D.2:30pm
Explanation: Every 24 hours will bring us to the same 1:30pm. 648 is divisible by 24 (27*24=648), so if it were 648 hours we would have 1:30pm, but since it's 648 hours then it will be 1 hour more, so 2:30pm.
Answer: D.
Question: Replace the ? mark with an appropriate approximate value in the following equation’?
7 1/2 of 265.6+15% of 2564= ? - 620.5
A.2297.1
B.2997.1
C.2557.1
D.2937.1
Answer: B.2997.1
Explanation: 7 1/2 of 265.6+15% of 2564= ? - 620.5
15/2 of 265.6+15% of 2564= ? - 620.5
1992+384.6= ? - 620.5
1992+384.6 +620.5= ?
≈ 2997.1
Answer B
Question: How many numbers from 2 to 11 are exactly divisible by 2?
A.A)2
B.B)3
C.C)5
D.D)7
Answer: C.C)5
Explanation: 2/2 = 1 and11/2 = 5
5 - 1 = 4
4 + 1 = 5 Numbers.
Answer : C
Question: What two-digit number is less than the sum of the square of its digits by 12 and exceeds their doubled product by 5?
A. 95
B. 99
C. 26
D. 73
Answer: B. 99
Explanation: Let the digits be x and y. The number would be 10x + y.
We are given that 2xy + 5 = 10x +y = x^2 y^2 -12
Thus 2xy +5 = x^2 + y^2 - 12
x^2 + y^2 -2xy = 16
(x-y)^2 = 16
(x-y) = 4 or -4
Substituting the values of (x-y) in the equation 2xy +5 = 10x + y
x comes out to be 1 or 9... thus the two numbers can be 15 or 99
Thus the answer is B
Question: Susan weighs 20 pounds more than Anna does, and together they weigh a total of 160 pounds. Which of the following represents Anna’s weight in pounds?
A.55
B.50
C.70
D.65
Answer: C.70
Explanation: Total weight = 160
Anna's weight = 160-20 /2 = 70
Answer : C
Question: Daniel went to a shop and bought things worth Rs. 25, out of which 30 Paise went on sales tax on taxable purchases. If the tax rate was 10%, then what was the cost of the tax free items?
A.A)19.7
B.B)20
C.C)21.3
D.D)21.7
Answer: D.D)21.7
Explanation: Total cost of the items he purchased = Rs.25
Given that out of this Rs.25, 30 Paise is given as tax
=> Total tax incurred = 30 Paise = Rs.30/100
Let the cost of the tax free items = x
Given that tax rate = 10%
∴ (25−30/100−x)10/100 = 30/100
⇒ 10(25 −0.3 −x) = 30
⇒ (25 − 0.3 − x) = 3
⇒ x = 25 − 0.3 − 3
= 21.7
D
Question: A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg?
A.22
B.80
C.40
D.77
Answer: C.40
Explanation: 800*(25/100) = 200 ---- 5
? ---- 1 => Rs.40
Answer: C
Question: In a class, the average age of 25 boys is 10 years and the average of 18 girls is 10 years. what is the average age of the whole class?
A.10 Years
B.12.6 Years
C.13 Years
D.13.5 Years
Answer: A.10 Years
Explanation: Total age of 43 students
(25X 10+18 X 10) = 430
Average = 430/43 = 10 Years
A)
Question: Event E is defined to be rolling an even number on a 6-sided die and Event F is defined to be rolling a 1, 2 or 3. Calculate the probability of rolling a die such that events E and F occur simultaneously on a single roll of the die.
A.1/2
B.1/6
C.0
D.5/6
Answer: B.1/6
Explanation: Determine if E and F are independent.
P(E|F) = the probability of event E occurring given that event F has already occurred
P(E|F) ≠ P(E) as P(E) is changed if it is given that F occurs.
Consequently, P(E∩F) ≠ P(E)P(F) since the events are not independent. As a result, P(E∩F) ≠ 1/4 = P(E)P(F)
We must use the more complex formula for finding the intersection of E and F:
P(E∩F) = P(F)P(E|F)
P(F) = the probability of event F occurring
The probability of rolling a 1, 2, or 3 is 3/6 = 1/2
P(E|F) = the probability of event E occurring given that event F has already occurred
If event F already occurred, we are limited to the numbers 1, 2, or 3. Within this range of 3 possible numbers, only one number--namely, 2--is an even number. Therefore, P(E|F) = 1/3
P(E∩F) = P(F)P(E|F) = (1/2) * (1/3) = 1/6
Answer B
Question: How many words can be formed by using all letters of the word “FAR”
A.12
B.24
C.8
D.6
Answer: D.6
Explanation: The word FAR contains 3 different letters.
Required number of words = 3p3 = 3! = (3x2x1) = 6.
Answer D.
Question: In a class, except 18 all are above 50 years.15 are below 50 years of age. How many people are there
A.30
B.33
C.36
D.can not be determined.
Answer: D.can not be determined.
Explanation: As per given statements,
15 are below 50 years of age.
except 18 all are above 50 years. means 3 are of 50 years of age.
there is no information about no of students above 50 years of age.
so total no can not be determined. ANSWER:D
Question: The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 144° of the circle, what percentage of MegaTek employees are in manufacturing?
A.20%
B.25%
C.30%
D.40%
Answer: D.40%
Explanation: ANSWER: D 144° divided by 360° equals 0.4, therefore the sector is equal to 40% of the total
Question: Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 9?
A.2
B.3
C.1
D.6
Answer: D.6
Explanation: You should consider the worst case scenario: if you pick numbers 0, 1, 2, 3 and 4 then no two numbers out of these 5 add up to 9.
Now, the next, 6th number whatever it'll be (5,6,7,8 or 9) will guarantee that two number WILL add up to 9. So, 6 slips must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 9
Answer: D
Question: Out of 9 persons, 8 persons spent Rs. 30 each for their meals. The ninth one spent Rs. 20 more than the average expenditure of all the nine. The total money spent by all of them was
A.Rs. 292.50
B.Rs. 292.77
C.Rs. 292.21
D.Rs. 292.19
Answer: A.Rs. 292.50
Explanation: Explanation:
Let the average expenditure be Rs. x Then,
Total money spent = 9x = Rs. (9 x 32.5O) = Rs 292. 50
Answer: A
Question: If a - b = 3 and a(power 2) + b(power 2) = 27, find the value of ab.
A.5
B.9
C.4
D.10
Answer: B.9
Explanation: 2ab = (a(power 2) + b(power 2) - (a - b)(power 2)
= 27 - 9 = 18
ab = 9.
Answer is B.
Question: Ron begins reading a book at 4: 30 p.m. and reads at a steady pace of 30 pages per hour. Michelle begins reading a copy of the same book at 7: 30 p.m. If Michelle started 5 pages behind the page that Ron started on and reads at an average pace of 50 pages per hour, at what time would Ron and Michelle be reading the same page?
A.7: 00 p.m.
B.7: 30 p.m.
C.7: 45 p.m.
D.10: 00 p.m.
Answer: D.10: 00 p.m.
Explanation: M gains 50-30=20 pages per hour on R
at 7:30pm R has read 45 pages and M is 45+5=50 pages behind him
time=50/20=2.5 hours
they are on the same page at 10:00pm
D
Question: A dice is numbered from 1 to 6 in different ways.
If 1 is adjacent to 2, 4 and 6, then which of the following statements is necessarily true?
A.3 is adjacent to 8
B.3 is adjacent to 2
C.3 is adjacent to 5
D.3 is adjacent to 1
Answer: C.3 is adjacent to 5
Explanation: Explanation:
If 1 is adjacent to 2, 4 and 6 then either 3 or 5 lies opposite to 1. So, the numbers 3 and 5 cannot lie opposite to each other. Hence, 3 is adjacent to 5 (necessarily).
Answer: C
Question: If y is the smallest positive integer such that 1,260 multiplied by y is the square of an integer, then y must be
A.23
B.51
C.38
D.35
Answer: D.35
Explanation: 1260= 2*2*3*3*7*5, so we need one 7 and one 5 to make it a square of a number. so 7*5= 35
Ans: D
Question: If 5400 mn = k^4, where m, n, and k are positive integers, what is the least possible value of m + n?
A.11
B.18
C.20
D.25
Answer: D.25
Explanation: k^4=5400∗mn
k^4=3^3.2^3.5^2.mn
In order to make RHS a perfect power of 4, we require it to be multiplied by 3, 2 & 5^2
mn=3.2.5^2
mn = 150 = 10 * 15 (Least possible)
Answer = 10 + 15 = 25
ANSWER:D
Question: 20 men or 25 women can finish a work in 25 days. How many days 38 men and 15 women will take to finish this job?
A.12days
B.10days
C.5days
D.6days
Answer: B.10days
Explanation: 20 men = 25 women
Therefore, 1 women = 20/25 men = 4/5 men
15 women = 4/5 *15 men = 12 men
i.e. 38 men + 15 women = 38 men + 12 men = 50men
1 work done by men = 20*25
20 *25 = 50 * ?
number of days = 20 *25/50 = 10days.
B
Question: What is the leastvalue of x. So that 23x57 is divisible by 3?
A.2
B.5
C.1
D.6
Answer: C.1
Explanation: The sum of the digits of the number is divisible by 3, then the number is divisible by3.
2 + 3 + x + 5 + 7 = 17 + x
Least value of x may be 1
Therefore 17 + 1 = 18 is divisible by 3.
C
Question: Which of the following is equivalent to the pair of inequalities x + 4 > 10 and x - 2 <= 5 ?
A. 2 < x < 16
B. 2 <= x < 4
C.(D) 6 < x <= 7
D.(C) 2 < x <= 8
Answer: C.(D) 6 < x <= 7
Explanation: Solution:
Let’s isolate x in both inequalities, starting with x + 4 > 10.
x + 4 > 10
x > 6
Next we isolate x in the inequality x – 2 5.
x – 2 <= 5
x <= 7
Bringing these two inequalities together we know:
6 < x <= 7
The answer is C.
Question: If log3(2), log3(2x - 5), log3(2x - 7/2) are in arithmetic progression, then the value of x is equal to
A.5
B.4
C.2
D.3
Answer: D.3
Explanation: Explanation :
Using log a – log b = log(a/b) ,
=> 2/(y-5) = (y-5) / (y-3.5), where y = 2x.
Solving we get, y= 4 or 8 i.e x = 2 or 3.
It can't be 2 as log of negative number is not deifned.
Answer : D
Question: The cross-section of a lake is a trapezium in shape. If the lake is 20m wide at the top and 5m wide at the bottom and the area of cross-section is 600 sq m, the depth of lake is?
A.48 m
B.68 m
C.46 m
D.84 m
Answer: A.48 m
Explanation: 1/2 * d (20+5) = 600
d = 48
ANSWER:A
Question: Two boys starts from the same place walking at the rate of 5 kmph and 5.5 kmph respectively in the same direction. What time will they take to be 8.5 km apart?
A.17 hr
B.14 hr
C.12 hr
D.19hr
Answer: A.17 hr
Explanation: Relative speed = 5.5 - 5 = 0.5 kmph (because they walk in the same direction)
distance = 8.5 km
time = distance/speed=8.5/0.5=17 hr
Answer is A
Question: There are 30 girls in hostel whose average age is decreased by 2 months, when one girl 18 yrs is replaced by a new boy.Find the age of new girl.
A.1 year
B.1 year 2 months
C.2 years 5 months
D.5 years
Answer: D.5 years
Explanation: Total decrease =30 * 2 = 60 month
= 5 years
D
Question: A thief is noticed by a policeman from a distance of 275 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes ?
A.50 meter
B.100 meter
C.175 meter
D.120 meter
Answer: C.175 meter
Explanation: Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr
Distance covered in 6 minutes =
1/60∗6=1/10=100meters
So distance between them after 6 minutes = 275 - 100
= 175 meters
Option C
Question: Ravi, Ram and Raj together started a business in partnership. The ratio of their capitals is 4:5:9.If their annual profit be Rs. 30600/-. What will be Raj’s share in this profit?
A.Rs. 8500/-
B.Rs. 6800/-
C.Rs. 15030/-
D.Rs. 15,300/-
Answer: D.Rs. 15,300/-
Explanation: Explanation:
Ravi : Ram : Raj = 4 : 5 : 9
Raj’s share = Rs(30600 * 9/18)
= Rs(30600 * 1/2) = 15300/-
Ram’s share = (30600 * 5/18) = 1700 * 5 = 8500/-
Ravi’s share = 6800/-
Answer: Option D
Question: A man saves Rs. 200 at the end of each year and lends the money at 5% compound interest. How much will it become at the end of 3 years?
A.Rs.662.09
B.Rs.662.18
C.Rs.662.02
D.Rs.662.01
Answer: C.Rs.662.02
Explanation: Amount = [200(1 + 5/100)3 + 200(1 + 5/100)2 + 200(1 + 5/100)]
= [200 * 21/20(21/20 * 21/20 + 21/20 + 1)]
= Rs.662.02
Answer: C
Question: Of the three numbers, the first is twice as second and three times the third. The average of the three numbers is 44, and the three numbers in order are?
A.116,58,36
B.98,49,33
C.72,36,24
D.108,54,36
Answer: C.72,36,24
Explanation: Explanation :
Solution: Let A =x,
B =x/2, C = x/3.
=x + x/2 + x/3 / 3 = 44
By solving we will get x = 72.
Hence A= 72
B= 72/2= 36
C= 72/3 = 24
Answer : C
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
A.22 kmph
B.40 kmph
C.78 kmph
D.15 kmph
Answer: B.40 kmph
Explanation: Speed downstream = 60 + 20 = 80 kmph
Speed upstream = 60 - 20
= 40 kmph
Answer:B
Question: Linda bought 3 notebooks at $1.20 each; a box of pencils at $1.50 and a box of pens at $1.70. How much did Linda spend?
A.$3.80
B.$6.80
C.$7.80
D.$10.80
Answer: B.$6.80
Explanation: Linda spent
1.20*3 = $3.60 on notebooks
The total amount of money that Linda spent is equal to
3.60 + 1.50 + 1.70 = $6.80
correct answer B
Question: Rs.8000 become Rs.9261 in a certain interval of time at the rate of 5% per annum of C.I. Find the time?
A.4 years
B.6 years
C.2 years
D.3 years
Answer: D.3 years
Explanation: 9261 = 8000(21/20)N
(21/20)3 = (21/20)N => N = 3
ANSWER:D
Question: Lexy walks 5 miles from point A to point K in one hour, then bicycles back to point A along the same route at 15 miles per hour. Ben makes the same round trip, but does so at half of Lexy’s average speed. How many minutes does Ben spend on his round trip?
A.40
B.80
C.120
D.160
Answer: D.160
Explanation: Lexy walks 5 miles from point A to point K in one hour, then bicycles back to point A along the same route at 15 miles per hour. Ben makes the same round trip, but does so at half of Lexy’s average speed. How many minutes does Ben spend on his round trip?
Average speed = total distance/total time
We know the total distance is 5+5 (going from A to K then from K to A)
Time = distance/speed
Time = 5/15
Time = 1/3 hour
Average speed = (10)/(1hr + 1/3hr)
Average speed (lexi) = 10 / 1.33
Therefore, if Ben's average speed is 1/2 of lexi's then his speed = 10/2.66.
This means it took him 2.66 hours to cover the same 10 miles Lexi did. 2.66 hours = roughly 160 minutes.
Answer: D). 160
Question: Find the odd man out. 856, 743, 633, 853, 871, 990, 532
A.532
B.990
C.528
D.633
Answer: C.528
Explanation: Explanation :
In all numbers except 742, the difference of third and first digit is the middle digit. Answer : Option C
Question: After an ice began to melt out from the freezer, in the first hour lost 3/4, in the second hour lost 3/4 of its remaining. If after two hours, the volume is 0.3 cubic inches, what is the original volume of the cubic ice, in cubic inches?
A.2.5
B.3.0
C.4.8
D.6.5
Answer: C.4.8
Explanation: Let initial volume of ice be = x
Ice Remaining after 1 hour = x - 0.75x = 0.25x
Ice Remaining after 2 hour = (1/4)x - (3/4 * 1/4 * x) = (1/16)x
(1/16)x = 0.3
x = 4.8
Alternate solution: Try to backsolve.
Initial volume = 4.8
After one hour --> (1/4)4.8 = 1.2
After two hours --> (1/4)1.2 = 0.3
Answer: C
Question: a rabbit is tied to one end of an equilateral triangle of side 5 m with a rope length of 8 m.The rabbit is not allowed to travel inside the triangle then find the maximum area covered by the rabbit?
A.(96/9)*pi
B.(480/9)*pi
C.(240/9)*pi
D.(100/9)*pi
Answer: B.(480/9)*pi
Explanation: The rabbit can graze upto 64*pi area if the triangle is not there.but the constraint here is,it should not enter the triangle so it must avoid grazing the sector of the circle which covers the triangular area also.each angle in the equilateral triangle is 60 degrees.so the area of the sector formed by 60 degrees and of radius 8m is (pi*8*8*60)/360
therefore maximum total area covered by the rabbit is given by=area of circle-area of sector
=(pi*8*8)-(pi*8*8*60)/360
=(480/9)*pi
ANSWER:B
Question: A train passes a station platform in 38 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.248 m
B.240 m
C.270 m
D.765 m
Answer: C.270 m
Explanation: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/38 = 15 ==> x + 300 = 570 ==> x
= 270 m.
Answer: C
Question: In how many different number of ways 5 men and 2 women can sit on a shop which can accommodate persons?
A.180
B.190
C.200
D.210
Answer: D.210
Explanation: 7p3 = 7 × 6 × 5 = 210
Option 'D'
Question: After decreasing 24% in the price of an article costs Rs.820. Find the actual cost of an article?
A.1400
B.1079
C.1200
D.1023
Answer: B.1079
Explanation: CP* (76/100) = 820
CP= 10.78 * 100 => CP = 1079
ANSWER:B
Question: If x and y are positive integers, and y=x^2+8, the greatest common divisor of a and b CANNOT be
A.9
B.1
C.2
D.4
Answer: A.9
Explanation: If x is 1, 2, 4, or 8, then GCD of x and y is 1, 2, 4, and 8 respectively. So, by POE the answer must be A.
Still: if x is a multiple of 9, then y is 8 greater than a multiple of 9, so not a multiple of 9, so both of them cannot be divisive by 9.
Answer: A.
Question: The average age of three boys is 5 years and their ages are in proportion 3:5:7. What is the age in years of the youngest boy?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: 3x + 5x + 7x = 15
x =1
3x = 3
ANSWER:C
Question: Of the 100 athletes at a soccer club, 40 play defense and 62 play midfield. If at least 20 of the athletes play neither midfield nor defense, the number of athletes that play both midfield and defense could be any number between
A.10 to 20
B.10 to 40
C.22 to 40
D.30 to 70
Answer: C.22 to 40
Explanation: First of all notice that since only 40 athletes play defense, then the number of athletes that play both midfield and defense cannot possibly be greater than 40.Eliminate D and E.
{Total} = {defense} + {midfield} - {both} + {neither}
100 = 40 + 62 - {both} + {neither}
{both} = {neither} + 2.
Since the least value of {neither} is given to be 20, then the least value of {both} is 20+2=22.Eliminate A and B.
Answer: C.
Question: The ratio of 2 numbers is 3:4 and their H.C.F. is 4. Their L.C.M. is ?
A.20
B.24
C.48
D.36
Answer: C.48
Explanation: Let the numbers be 3x and 4x
Their H.C.F. = 4
so the numbers are 3*4 , 4*4 = 12,16
L.C.M. =48
Answer is C
Question: The volume of a cube is 1331 cc. Find its surface.
A.864
B.726
C.255
D.287
Answer: B.726
Explanation: a3 = 1331 => a = 11
6a2 = 6 * 11 * 11 = 726
Answer:B
Question: The sum of two numbers is 96, and one of them is 12 more than the other. What are the two numbers?
A.36-48
B.50-34
C.60-24
D.42-54
Answer: D.42-54
Explanation: In this problem, we are asked to find two numbers. Therefore, we must let x be one of them. Let x, then, be the first number.
We are told that the other number is 12 more, x + 12.
The problem states that their sum is 96:
word problem = 96
The line over x + 12 is a grouping symbol called a vinculum. It saves us writing parentheses.
We have:
2x = 96 âˆ’ 12
= 84.
x = 84/2
= 42.
This is the first number. Therefore the other number is
x + 12 = 42 + 12 = 54.
The sum of 42 + 54 is 96.
D
Question: At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.20000?
A.Rs.6620
B.Rs.6500
C.Rs.6800
D.Rs.6400
Answer: A.Rs.6620
Explanation: A = 20000(11/10)3
= 26620
= 20000
----------
6620
ANSWER:A
Question: The population of a town increased from 1,75,000 to 2,62,500 in a decade. What is the average percent increase of population per year?
A.4%
B.6%
C.5%
D.50%
Answer: C.5%
Explanation: Explanation :
Increase in the population in 10 years = 2,62,500 - 1,75,000 = 87500
% ncrease in the population in 10 years = (87500/175000) × 100 = 8750/175 = 50%
Average % increase of population per year = 50%/10 = 5%
Answer : Option C
Question: The distance between Delhi and Mathura is 140 kms. A starts from Delhi with a speed of 24 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 46 kmph at 8 a.m. from Delhi. When will they meet?
A.11
B.23 3/4
C.16 1/2
D.9 1/2
Answer: D.9 1/2
Explanation: D = 140 – 24 = 116
RS = 46 + 24 = 70
T = 116/70 = 1.6 hours
8 a.m. + 1.6 = 9 1/2 a.m..Answer: D
Question: Five booksâ€ Math, Physics, Chemistry, Biology and Commerceâ€ are going to place on each other. The math book & biology book should not be together, and the others can placed in any order. How many possible configurations are there for the books?
A.110
B.112
C.48
D.60
Answer: B.112
Explanation: the total no. of configuration for placing books are permutation of five item
5p5=5!=120
now the no. of ways in which math and biology will come together is 4Ã—2=8.
so by subtracting 8 to total no. of configuration give us the value in which math and biology book will not come together.
120-8=112.
answer B
Question: A train traveled at an average speed of 100 km/hr, stopping for 3 minutes after every 75 km. How
long did it take to reach its desƟnaƟon 600 km from the starting point
A.6 hours 24 mins
B.6 hours 21 mins
C.6 hours 18 mins
D.6 hours 15 mins
Answer: B.6 hours 21 mins
Explanation: Explanation:
Time taken to cover 600 km = 6 hours [because train speed is 100 km/hr]
Number of stops =
begin{aligned}
frac{600}{75} - 1 = 7 \
text{Total Ɵme on stops =}7*3 = 21 mins
end{aligned}
Total Ɵme taken by train = 6 hours 21 mins
Answer: B
Question: If 8 ∙ 2x = 5(y+8), then when y = -8, x =
A.8
B.2
C.6
D.0
Answer: D.0
Explanation: 8 ∙ 2x = 5(y+8).
or, 8 ∙ 2x = 5(-8+8).
or, 2x = 50.
or, 2x = 1 [anything to the power 0 is 1 then, 50 = 1].
Taking log on both sides,
log 2x = log 1.
or, x log 2 = 0 [since log 1 = 0].
or, x = 0/log 2 [dividing log 2 on both sides].
Therefore, x = 0.
Answer:D
Question: In a 1000 m race, A beats B by 200 meters or 25 seconds. Find the speed of B?
A.8 m/s
B.9 m/s
C.5 m/s
D.3 m/s
Answer: A.8 m/s
Explanation: Since A beats B by 200 m or 25 seconds, i
t implies that B covers 200 m in 25 seconds.
Hence speed of B = 200/25
= 8 m/s.
Answer:A
Question: 5354 x 51 = ?
A.273054
B.273243
C.273247
D.273250
Answer: A.273054
Explanation: 5354 x 51	= 5354 x (50 + 1)
= 5354 x 50 + 5354 x 1
= 267700 + 5354
= 273054
A
Question: In a certain warehouse, 40 percent of the packages weigh less than 75 pounds, and a total of 48 packages weigh less than 25 pounds. If 80 percent of the packages weigh at least 25 pounds, how many of the packages weigh at least 25 pounds but less than 75 pounds?
A.8
B.64
C.48
D.102
Answer: C.48
Explanation: If 80% of the packages weigh at least 25 pounds
This means that 20% of the packages weigh LESS THAN 25 pounds
Let T = TOTAL number of packages
So, 20% of T = # of packages that weigh LESS THAN 25 pounds
48 packages weigh LESS THAN 25 pounds
GREAT. So, 20% of T = 48
Rewrite to get: 0.2T = 48
Solve:T = 240
40% of the packages weigh less than 75 pounds
So, 40% ofT= number of packages that weigh less than 75 pounds
40% of240=96, so96packages weigh less than 75 pounds
OF THOSE96packages that weigh less than 75 pounds,48packages weigh less than 25 pounds.
So, the number of packages that weight BETWEEN 25 and 75 pounds =96-48= 48 = C
Question: In a flower shop there were 6 flowers in each bouquet. If the seller has doubled the number of flowers in each bouquet then the new average of flowers in each bouque is
A.12
B.3
C.8
D.9
Answer: A.12
Explanation: Answer
Now required average
= old average x Multiplicand
= 6 x 2 = 12
Correct Option: A