RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Winson will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him or her. How many such arrangements of the 6 people are possible?
A.5
B.6
C.9
D.24
Answer: A.5
Explanation: Winson will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing is standing in front of someone in the second row.person with max height is in the second row, person with min height is in the first row. We need to select 1 person in the middle of each row... In the middle of the first row we can put only 2, 3 or 4. In the middle of the second row we can put only 3, 4, 5. If we select {3 in the sec. row, 2 in the first}, {4,2}, {5,2}, {4,3}, {5,3}, {5,4}. So, there are 0*1 + 1*1 + 2*1 + 1*1 + 1*1 + 0*1 = 5 cases...A
Question: Two employees A and B are paid a total of Rs. 550 per week by their employer. If A is paid 150 percent of the sum paid to B, how much is B paid per week?
A.130
B.140
C.150
D.220
Answer: D.220
Explanation: Let the amount paid to A per week = x
and the amount paid to B per week = y
Then x + y = 550
But x = 150% of y = 150y/100 = 15y/10
∴15y/10 + y = 550
⇒ y[15/10 + 1] = 550
⇒ 25y/10 = 550
⇒ 25y = 5500
⇒ y = 5500/25 =Rs.220
D)
Question: A military garrison in a wild frontier has 600 men who have provisions to last 22 weeks. At the end of 6 weeks they are joined by another 300 men. How long will the provisions last?
A.13 1/3
B.12 1/3
C.10 2/3
D.12 1/2
Answer: C.10 2/3
Explanation: Total provisions=600*22*7=92400
Provisions used for in 6 weeks=6*7*600=25200
remaining provisions=67200
remaining provisions need to be split between 900(600+300) people.
Number of provisions per person= 67200/900
we need to find the answer in terms of weeks=(67200/900)/7=10 2/3
Answer:C
Question: I sold a book at a profit of 10%. Had I sold it for $110 more, 15% would have been gained. Find the cost price?
A.$2000
B.$2200
C.$3000
D.$3120
Answer: B.$2200
Explanation: 115% of cost - 110% of cost = $110
5% of cost = $110
cost = 110*100/5 = $2200
Answer is B
Question: eleven books,consisting of 5 engineering books , 4 maths books,2 physics books are arranged in a shelf at random .what is the probability that books of each kind are all together?
A.0.001443
B.0.002443
C.0.003443
D.0.004443
Answer: A.0.001443
Explanation: 3 lots can be arranged in 5!x3!x4!x2!
total arrangements possible= 11!
hence probability of the same=(5!x3!x4!x2!)/11!=0.001443
ANSWER:A
Question: If x > 6 and y < -6, then which of the following must be true ?
A.x/y > 1
B.x/y < -1
C.x/y < 0
D.x + y > 0
Answer: D.x + y > 0
Explanation: Pick x=3, y = -3
A) x/y > 1 - Incorrect as x/y = -1
B) x/y < -1 - Incorrect as x/y = -1
C) x/y < 0 -Correct. It will hold for all values x > 2 and y < -2 as x/y = -1 < 0
D) x + y > 0 - Incorrect. x + y = 0
E) xy > 0 - Incorrect. XY = -9 which is less than zero.
D should be the answer.
Question: If the probability of rain on any given day in City X is 50%, what is probability that it rains on exactly 3 days in a 4 day period?
A.1/2
B.1/4
C.1/8
D.1/16
Answer: B.1/4
Explanation: One possible way is rain-rain-rain-no rain.
The probability of this is 1/2*1/2*1/2*1/2 = 1/16
The number of possible ways is 4C3 = 4, so we multiply this by 4.
P(rain on exactly 3 days) = 4*1/16 = 4/16 = 1/4
The answer is B.
Question: An escalator moves towards the top level at the rate of 11 ft.sec and its length is 140 feet. If a person walks on the moving escalator at the rate of 3 feet per second towards the top level, how much time does he take to cover the entire length.
A.14 sec
B.10 sec
C.12 sec
D.8 sec
Answer: B.10 sec
Explanation: Time taken to cover the entire length = tot.dist/resultant speed
= 140/ (11+3)
= 10sec
ANSWER:B
Question: A seller has 1000 kg of rice part of which he sells at 8% profit and the rest at 18% profit. He gains 14%. The quantity sold at 18% profit is?
A.350 kg
B.360 kg
C.400 kg
D.600 kg
Answer: D.600 kg
Explanation: By rule of alligation,
Profit% by selling 1st part Profit% by selling 2nd part
8 18
Net % profit
14
18-14=4 14-8=6
=> Quantity of part1 : Quantity of part2 = 4 : 6 = 2 : 3
Total quantity is given as 1000 kg. So quantity of part2 (quantity sold at 18% profit)
=1000×35
= 600 kg
D
Question: A bullet train passes a station platform in 36 seconds and a man standing on the platform in 24 seconds. If the speed of the bullet train is 54 km/hr, what is the length of the platform?
A.240 m
B.180 m
C.260 m
D.224 m
Answer: B.180 m
Explanation: A
180 M
Speed = 54 x 5/18 = 15 m/s
Length of the bullet train = (15 x 24)m = 360 m.
Let the length of the platform be x metres.
Then, (x + 360)/36 = 15
--> x + 360 = 540
x = 180m. B
Question: A and B tanks are there. 1/8th of the tank B is filled in 22Hrs. What is time to fill the full tank
A.175
B.176
C.177
D.178
Answer: B.176
Explanation: 1/8th = 22 hrs
therefore entire tank is 8 x 22.
176hrs
Full tank ll be filled in 176 hrs
ANSWER:B
Question: Jerry is mixing up a salad dressing. Regardless of the number of servings, the recipe requires that 5/8 of the finished dressing mix be olive oil, 1/4 mint , and the remainder an even mixture of salt, pepper and sugar. If Jerry accidentally doubles the mint and forgets the sugar altogether, what proportion of the botched dressing will be olive oil?
A.15/29
B.5/8
C.5/16
D.1/2
Answer: A.15/29
Explanation: Olive oil = 5/8 = 15/24 --> 15 parts out of 24;
mint = 1/4 = 6/24 --> 6 parts out of 24;
Salt + pepper + sugar = 1-(15/24+6/24)= 3/24, so each = 1/24 --> 1 part out of 24 each;
If mint = 12 (instead of 6) and sugar = 0 (instead of 1) then total = 15+12+1+1+0 = 29 parts out of which 15 parts are olive oil --> proportion = 15/29.
Answer: A.
Question: A = {2, 3, 4, 5}
B = {4, 5, 6, 7, 8}
Two integers will be randomly selected from the sets above, one integer from set A and one integer from set B. What is the probability that the sum of the two integers will equal 9 ?
A.0.15
B.0.2
C.0.25
D.0.3
Answer: B.0.2
Explanation: The total number of pairs possible is 4*5=20. Out of these 20 pairs only 4 sum up to 9: (2, 7); (3, 6), (4, 5) and (5, 4). The probability thus is 4/20=0.2.
Answer: B.
Question: If CRY is coded as MRYC then how will GET be coded?
A.MTEG
B.MGET
C.MEGT
D.METG
Answer: D.METG
Explanation: The letters of word (1)(2)(3) is written by prefixing M and ordering letters
(2)(3)(1)
So GET= METG
ANSWER:D
Question: In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100?
A.22
B.17
C.25
D.27
Answer: C.25
Explanation: A scores 60 while B score 40 and C scores 30.
The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.
In a game of 100 points, B gives (100 - 75) = 25 points to C.Answer: C
Question: A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
A.65 liters
B.88 liters
C.10 liters
D.45 liters
Answer: C.10 liters
Explanation: Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters. Answer: C
Question: A number whose one-fourth part is increased by 5 is equal to the third part diminished by 5.
A.100
B.80
C.120
D.60
Answer: C.120
Explanation: Explanation:
Let the number be x. Then,
x/4 + 5 = x/3 - 5 => x/4 - x/3 = -10
=> 3x - 4x = -120
=> x = 120
Answer: Option C
Question: When m is divided by 9, the remainder is 2. When m is divided by 13, the remainder is 5. If 1 < m < 300, what is the greatest possible value of m?
A.160
B.180
C.200
D.220
Answer: C.200
Explanation: 13*9 = 117
Let's start with 5, and keep adding 13 until we find a number with the form 9k+2.
5, 18, 31, 44, 57, 70, 83 = 9*9+2
The next possible number is 83 + 117 = 200
The next possible number would be greater than 300.
The answer is C.
Question: What should come in place of the question mark(?) in each of the following questions ?
6% of 350+ (?)% of 200 = 75% of 40
A.5
B.4.5
C.5.5
D.7
Answer: B.4.5
Explanation: Explanation :
let x% of 220 = 75% of 40 - 60% of 350 = 9 or x=9x100/220 = 45/11 = 4.09
Answer : Option B
Question: In Jessica's opinion, her weight is greater than 65 kg but less than 72 kg. Her brother doest not agree with Jessica and he thinks that Jessica's weight is greater than 60 kg but less than 70 kg. Her mother's view is that her weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Jessica?
A.67 kg.
B.68 kg.
C.69 kg.
D.Data inadequate
Answer: A.67 kg.
Explanation: Explanation: Let Jessica's weight by X kg.
According to Jessica, 65 < X < 72
According to Jessica's brother, 60 < X < 70.
According to Jessica's mohter, X <= 68
The values satisfying all the above conditions are 66, 67 and 68.
Required average= (66+67+68 /3) = (201 /3) = 67kg
Answer: Option A
Question: List D consists of 12 consecutive integers. If -4 is the least integer in list D, what is the range of positive integers in list D?
A.5
B.6
C.7
D.11
Answer: B.6
Explanation: Since -4 is the least integer in list D, then 7 is the largest integer in that list. Thus the range of the positive integers in the list is 7-1=6.
Answer: B.
Question: Find the best average of the first 10 multiples of 7....
A.30.5
B.38.5
C.40
D.43.5
Answer: B.38.5
Explanation: the exp is - 7(1+2+3+4+5+6+7+8+9+10)/10 =>
7(10(10+1)/10*2 =>
7(110)/10*2 = 38.5
ANSWER B
Question: What is 35% of 4/13 of 845?
A.58
B.69
C.80
D.91
Answer: C.80
Explanation: This problem can be solved easily if we just use approximation: 35% is a little over 1/3, while 4/13 is a little less than 4/12, which is 1/3. Thus, the answer is about 1/3 of 1/3 of 845, or 1/9 of 845. Since the first 1/3 is a slight underestimate and the second 1/3 is a slight overestimate, the errors will partially cancel each other out. Our estimate will be relatively accurate.
The number 845 is a bit more than 810, so (1/9)*845 will be a bit more than 90.
Keeping track not only of your current estimate, but also of the degree to which you have overestimated or underestimated , can help you pinpoint the correct answer more confidently.
The closest answer is 91, so this is the answer to choose.
The answer is C.
Question: Which of these expressions has the greatest value?
A.1856721/1856725
B.1288542/1288743
C.1354321/1314325
D.1608521/1608526
Answer: C.1354321/1314325
Explanation: Using elimination method on options
1354321/1314325 = 1.03043082951...
ANSWER:C
Question: For each 6-month period during a light bulb's life span, the odds of it not burning out from over-use are half what they were in the previous 6-month period. If the odds of a light bulb burning out during the first 6-month period following its purchase are 2/7, what are the odds of it burning out during the period from 6months to 1 year following its purchase?
A.5/27
B.2/9
C.1/2
D.4/9
Answer: C.1/2
Explanation: P(of not burning out in a six mnth period)=1/2 of P(of not burning out in prev 6 mnth period)
P(of burning out in 1st 6 mnth)= 2/7
--->P( of not burning out in 1st 6 mnth)=1-2/7=5/7
---->P(of not burning out in a six mnth period)=1/2 *5/7=1/3
--->P(of burning out in a six mnth period)=1-1/3=2/3
now
P( of burning out in 2nd six mnth period)=P( of not burning out in 1st six mnth)*P(of burning out in a six mnth)
=5/7 * 2/3=1/2
Ans C
Question: What day of the week does May 28 2006 fall on
A.Saturday
B.Monday
C.Sunday
D.Thursday
Answer: C.Sunday
Explanation: Explanation :
28th May 2006 = (2005 years + period from 1-Jan-2006 to 28-May-2006)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Number of odd days in the period 2001-2005
= 4 normal years + 1 leap year
= 4 x 1 + 1 x 2 = 6
Days from 1-Jan-2006 to 28-May-2006 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 28(may)
= 148
148 days = 21 weeks + 1 day = 1 odd day
Total number of odd days = (0 + 6 + 1) = 7 odd days = 0 odd day
0 odd day = Sunday
Hence May 28 2006 is Sunday
Answer : Option C
Question: If $2000 was invested at an annual interest rate of 5.6% compounded annually, which of the following represents the amount the investment was worth after 3 years?
A.2000 (1.056)(3)
B.2000 (1.056)^3
C.2000 (1+3(0.056))
D.2000 (1+(0.056)^3)
Answer: B.2000 (1.056)^3
Explanation: the formula is CI=P(1+r/100)^t
in this case i think B is the ans
Question: The heights of three individuals are in the ratio 4 : 5 : 6. If the sum of the heights of the heaviest and the lightest boy is 150cm more than the height of the third boy, what is the weight of the lightest boy?
A.120cm
B.150cm
C.160cm
D.190cm
Answer: A.120cm
Explanation: Let the heights of the three boys be 4k, 5k and 6k respectively.
4k + 6k = 5k + 150
=> 5k = 150=> k = 30
Therefore the height of the lightest boy
= 4k = 4(30) = 120 cm.
ANSWER:A
Question: The sum of number of boys and girls in a school is 400. If the number of boys is x, then the number of girls becomes x% of the total number of students. The number of boys is?
A.50
B.40
C.60
D.80
Answer: D.80
Explanation: We have x+x% of 400 = 400
x + x/100 * 400 = 400
5 * x = 400
x = 80
Answer is D
Question: Given the two equations 5r + s = 26 and r + 5s = 10, by how much does r exceed s?
A.3
B.4
C.5
D.6
Answer: B.4
Explanation: Solve by Simultaneous Equations.
My Answer is B.
r=5
s=1
Question: The average speed of a car is 1 4/5 times the avg speed of a bike. A tractor covers 575km in 23hrs. How much distance will the car cover in 4hrs if the speed of the bike is twice speed of the tractor?
A.300 km
B.320 km
C.360 km
D.430 km
Answer: C.360 km
Explanation: Sol. Average speed of a tractor = 25 km / h
The speed of a bus in an hour = 25 × 2 = 50 km
The speed of a car in an hour = 9/5 * 50 = 90 km
So, the distance covered by car in 4 h is
90 × 4 = 360 km
Ans.(C)
Question: 15% of a certain number is subtracted from 299, the result is the same number. What is the number?
A.199
B.260
C.365
D.175
Answer: B.260
Explanation: 299 - (15/100) * X = X
299 - .15*X = X
299 = 1.15 * X
X = 260
Answer: B
Question: Set S consists of integers {1,2,3,4}. If two numbers are chosen from set S at random, what is the probability that the sum of 2 numbers is more than 6?
A.1/3
B.P(E)=1/6
C.2/3
D.2/5
Answer: B.P(E)=1/6
Explanation: Number of ways you can choose 2 from 4 = 4C2 = 6
E = event of getting the 2 numbers is more than 6 = (3,4) = 1
probability = 1/6
Answer is B
Question: Three hoses work to fill a tub at at different rate. Hose P and B, working together, can fill the tub in 6/5 of an hour. Hoses P and C can fill it in 3/2 an hour. Houses B and C can fill it in 2 hours. How long does it take all 3 hoses, working together, to fill the tub?
Edited for accurate solution
A.3/10
B.2/5
C.1/2
D.1
Answer: D.1
Explanation: Convert the given time to rate and you will be able to add it up.
Total Rate of P and B = Rate of P + Rate of B = 1/(6/5) = 5/6
Total Rate of P and C = Rate of P + Rate of C = 1/(3/2) = 2/3
Total Rate of B and C = Rate of B + Rate of C = 1/2
Adding all three,
2(Rate of P + Rate of B + Rate of C) = 5/6 + 2/3 + 1/2 = 2
Rate of P + Rate of B + Rate of C = 1 tub/hour
Time taken by all three together to fill up the tub is 1 hour=D
Question: In a rectangular coordinate system, points O (2,0), P (2,8), and Q (8,0) represent the sites of three proposed housing developments. If a fire station can be built at any point in the coordinate system, at which point would it be equidistant from all three developments?
A.(3,5)
B.(4,3)
C.(5,4)
D.(4,4)
Answer: C.(5,4)
Explanation: All points equidistant from O and Q lie on the line x = 5, so the fire station should lie on this line.
All points equidistant from O and P lie on the line y = 4, so the fire station should lie on this line.
These two intersect at (5,4) and that will be the point equidistant from all 3 points.
The answer is C.
Question: The population of a town is 10000. It increases annually at the rate of 10% p.a. What will be its population after 2 years?
A.12300
B.12350
C.12100
D.12500
Answer: C.12100
Explanation: Formula :
( After =100 denominator
Ago = 100 numerator)
10000 Ã— 110/100 Ã— 110/100 = 12100
C
Question: The HCF and LCM of two numbers m and n are respectively 6 and 210. If m + n = 72, then 1/m + 1/n is equal to
A.1/35
B.3/35
C.5/37
D.2/35
Answer: D.2/35
Explanation: Answer
We have, m x n = 6 x 210 = 1260
∴ 1/m + 1/n = (m + n)/mn = 72/1260 = 4/70 = 2/35
Correct Option: D
Question: The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides?
A.3
B.6
C.4
D.9
Answer: A.3
Explanation: S = (1 + 2 + 3)/2
= 3
Answer:A
Question: When a random experiment is conducted, the probability that event A occurs is 1/4. If the random experiment is conducted 4 independent times, what is the probability that event A occurs exactly twice?
A.14/65
B.27/128
C.33/140
D.37/165
Answer: B.27/128
Explanation: One case is: 1/4*1/4*3/4*3/4=9/256
The total number of possible cases is 4C2 = 6
P(event A occurs exactly twice) = 6*(9/256) = 27/128
The answer is B.
Question: A man whose speed is 5.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
A.7
B.5.1
C.6
D.9
Answer: B.5.1
Explanation: M = 5.5
S = 1.5
DS = 7
US = 4
AS = (2 * 7 * 4) /11 = 5.1
Answer:B
Question: A coin is tossed 6 times. What is the probability of getting exactly 5 heads?
A.3/8
B.3/16
C.5/16
D.3/32
Answer: D.3/32
Explanation: The number of possible outcomes is 2^6 = 64
There are 6 ways to get exactly 5 heads.
P(exactly 5 heads) = 6/64 = 3/32
The answer is D.
Question: If a + b = x and a - b = y , then 3ab =
can someone explain!
A.(3x^2 - 3y^2)/4
B.(3y^2 - 3x^2)/4
C.3x+3y/2
D.3x - 3y/2
Answer: A.(3x^2 - 3y^2)/4
Explanation: plugging numbers is quite fast in this case:
Let
a=1
b=2
Then; x= 1+2=> 3 and Y= 1-2=> -1
Question asks 3ab=.........
As our number 3ab= 3*1*2=6
now plug the value of x and y in the answer choices. Option A gives 6 and that is the number we need.
Hence: Ans is A.
Question: Set A contains all the even numbers between 32 and 80 inclusive. Set B contains all the even numbers between 62 and 110 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A?
A.450
B.550
C.650
D.750
Answer: D.750
Explanation: Each term in set B is 30 more than the corresponding term in set A.
The difference of the sums = 25 * 30 = 750.
The answer is D.
Question: When Q is divided by 9, the remainder is 4. All of the following are possible values of Q, except for which of the following?
A.13
B.31
C.49
D.57
Answer: D.57
Explanation: The number can be expressed in the form of 9x+4 where x can 0,1,2,3,4....
by evaluating the answer choices carefully we can clearly observe that 57 is the only number which can't be expressed Q in the form of 9x+4
In other words we can also say that the (answer - 4) will not be divisible by 9.57 is the number which doesn't follow this condition
Correct Answer - D
Question: The price of 80 apples is equal to that of 120 oranges. The price of 60 apples and 75 oranges together is Rs.1320. The total price of 25 apples and 40 oranges is
A.680
B.620
C.720
D.480
Answer: B.620
Explanation: Let the price of one apple = a and price of one orange = b
The price of 80 apples is equal to that of 120 oranges
80a = 120b
=> 2a = 3b ==> b=2a/3 ------------(1)
price of 60 apples and 75 oranges together is Rs.1320
=>60a + 75b = 1320
=> 4a + 5b = 88 ==> 4a + 5(2a/3) = 88 -------(from equation 1)
=> 12a + 10a = 88 × 3
=> 6a + 5a = 44 × 3
=> 11a = 44 × 3
=> a = 4 × 3 = 12
b = 2a/3
b = 2*12/3
b = 8
Total price of 25 apples and 40 oranges
= 25a + 40b = (25 × 12) + (40 × 8) = 300 + 320 = 620
Ans - B
Question: In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is
Rs. 30 in all, how many 5 p coins are there?
A.150
B.130
C.120
D.110
Answer: A.150
Explanation: Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values = Rs. (25X/100 + 10X2X/100 + 5X3X/100) = RS 60X/100
60X/100 = 30 X =30 X 10/60 = 50
Hence, the number of 5 p coins = (3 x 50) = 150.
ANSWER A 150
Question: Sally has $100 in pennies. She wants to stack her pennies into three large piles and five small piles. The large piles are all the same size, and the small piles are all the same size. Additionally, Sally wants all of the small piles put together to equal one of the large piles. How many pennies does Sally put in one of the small piles?
A.2500 pennies
B.500 pennies
C.250 pennies
D.100 pennies
Answer: B.500 pennies
Explanation: B. Each large pile gets 1/4 of the total pennies. Each small pile gets 1/5 of the remaining 1/4 of the total pennies. So each small pile gets 1/20 of the total pennies. $100 is 10,000 pennies. 1/20 of 10,000 is 500, so the correct answer is B: 500 pennies.
Question: If 32.5% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class?
A.110
B.330
C.550
D.594
Answer: D.594
Explanation: Students enrolled in biology are 32.5% and therefore not enrolled are 67.5%. so of 880 is 880*.675 = 594
Answer is D 594
Question: The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 45, what is the possible maximum range of the temperatures?
A.20
B.25
C.40
D.45
Answer: B.25
Explanation: Average=50, Sum of temperatures=50*5=250
As the min temperature is 45, max would be 250-4*45=70 --> The range=70(max)-45(min)=25
Answer: B.
Question: A and B entered into a partnership investing Rs. 13,000 and Rs. 12,000 respectively.After 3 months, A withdrew Rs. 5000 while B invested Rs. 5000 more, After 3 more months, C joins the business with a capital of Rs. 21,000, The share of B exceeds that of C, out of a total profit of Rs. 26,400 after one year by?
A.8340
B.3600
C.2787
D.1287
Answer: B.3600
Explanation: A : B : C = (16000 * 3 + 11000 * 9) : (12000 * 3 + 17000 * 9) : (21000 * 6)
= 147 : 189 : 126
= 7 : 9 ; 6.
Difference of B and C's shares = Rs. ( 26400 * 9/22 - 26400 * 6/22 )
= Rs. 3600.
Answer: B
Question: A certain sum is invested at simple interest at 15% p.a. for two years instead of investing at 12% p.a. for the same time period. Therefore the interest received is more by Rs. 900. Find the sum?
A.s. 7000
B.s. 9000
C.s. 15000
D.s. 17000
Answer: C.s. 15000
Explanation: Let the sum be Rs. x.
(x * 15 * 2)/100 - (x * 12 * 2)/100 = 900
=> 30x/100 - 24x/100 =900
=> 6x/100 = 900
=> x = 15000.
ANSWER:C
Question: If an integer n is divisible by3, 5, 12. what is the next larger integer divisible by all these numbers
A.n+3
B.n+5
C.n+12
D.n+60
Answer: D.n+60
Explanation: If n is divisible by 3, 5 and 12 it must a multiple of the lcm of 3, 5 and 12 which is 60.
n=60k
n + 60 is also divisible by 60 since
n + 60 = 60 k + 60 = 60(k + 1)
The answer is D.
Question: If it is 6:12 in the evening on a certain day, what time in the morning was it exactly 1,440,711 minutes earlier? (Assume standard time in one location.)
A.6:12
B.6:15
C.6:18
D.6:21
Answer: D.6:21
Explanation: 6:12 minus 1,440,711 must end with 1, the only answer choice which ends with 1 is D.
Answer: D.
Question: x^2-y^2= 16 and 2. xy=4 so find out x+y=? tell that both statement are required to find out the value of x+Y
A.6
B.7
C.8
D.9
Answer: C.8
Explanation: x^2-y^2= 16 = 25-9 =5^2-3^2
=> (x+y)*(x-y)=(5+3)*(5-3)
=> (x+y)=(5+3)=8
ANSWER:C
Question: A number increased by 20% gives 480. The number is
A.250
B.400
C.450
D.500
Answer: B.400
Explanation: Formula = TOTAL=100% ,INCRESE = "+" DECREASE= "-"
A number means = 100 %
That same number increased by 20 % = 120 %
120 % -------> 480 (120 × 4 = 480)
100 % -------> 400 (100 × 4 = 400)
B)