RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A plant manager must assign 8 new workers to one of five shifts. She needs a first, second, and third shift, and two alternate shifts. Each of the shifts will receive 2 new workers. How many different ways can she assign the new workers?
A.243
B.336
C.350
D.486
Answer: B.336
Explanation: whatever : my take selecting team of 2 out of 8 to assign to the shifts = 8C2 = 28 ways.
now 2 out of 8 means total of 4 group possible.
so putting them in shifts = counting methode: first, second, third, alt , alt
= 4*3*2*1 = 24
here alt and alt are the same: so 24/2 = 12 ways.
total ways of selecting = (selecting 2 out of 8)*arranging those teams in shifts
= 28*12 = 336
Ans: B
Question: What percent of 250 is 45?
A.0.25%
B.18%
C.25%
D.40%
Answer: B.18%
Explanation: 250*x /100 = 45
x = 45*10/25
x = 18
Ans: B
Question: Six fencers participate in a fencing championship. Assuming all competitors have an equal chance of winning, how many possibilities are there with respect to how a first-place and second-place medal can be awarded?
A.20
B.24
C.25
D.30
Answer: D.30
Explanation: 6*5 = 30
The answer is D.
Question: If x is an integer and (x)(x^2)(x^3)(x^10) is positive, which of the following could be negative?
A.x^4
B.(x)(x^3)
C.(x)(x)
D.x + x^9
Answer: D.x + x^9
Explanation: A) X^4 - always positive (or 0).
B) X(X^3) = X^4 - Again always positive (or 0).
C) (x)(x) = X^2 - Again always positive (or 0).
D) x+x^9 - Could be -ve if x is -ve.
E) 3X^2 - again always positive (or 0)
Answer D.
Question: Charlene's annual bonus is calculated in the following manner: Charlene receives 20 percent of her first $11,000 in sales and 40 percent of her sales in excess of $11,000. If Charlene received a bonus of $7,300, what were her annual sales?
A.$ 10,000
B.$ 12,750
C.$ 24,000
D.$ 26,000
Answer: B.$ 12,750
Explanation: Let x be the total sales in $.
For the 1st 11,000 you get 20% ---> 0.2*11000 = 2200$
For the remaining (x-11000) $, you get 40% ---> 0.4*(x-11000)
Thus, 0.4*(x-11000) + 2200 = 7300 ----> x= 12,750 $
B is thus the correct answer.
Question: A security guard at a certain store is instructed to check the receipt of one out of every five customers as they are leaving the store. If, on the guard's shift,
customers leave the store, how many different samples of customers could have been selected to have their receipts checked?
A.20
B.10
C.59
D.90
Answer: B.10
Explanation: to choose the sample of 2 customers from 5. it can be done 5C2 possible ways.
So the answer is B. 10
Question: The revenue from sales items in 1996 increases by x percent, compared in 1995 and the revenue in 1997 decreases by x percent, compared in 1996. If the revenue from sales items in 1997 decreases by 4 percent, compared in 1995, what is the value of x?
A.10
B.15
C.20
D.30
Answer: C.20
Explanation: 1995 - let the value be z
1996 - x% increase - z(1+x/100)
1997 - x% decrease - z(1+x/100)(1-x/100)
from 95 to 97 decrease is 4%
hence, [z-{z(1+x/100)(1-x/100)}]/z = 4/100
solving x = 20%
C is the answer
Question: A motorcyclist goes from Bombay to Pune, a distance of 224 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
A.1:2
B.1:5
C.4:7
D.1:1
Answer: C.4:7
Explanation: T = 224/32 = 7 h
T = 7 - 3 = 4
Time Ratio = 7:4
Speed Ratio = 4:7
Answer: C
Question: Three grades of milk are 1 percent, 2 percent and 4 percent fat by volume. If x gallons of the 1 percent grade, y gallons of the 2 percent grade, and z gallons of the 3 percent grade are mixed to give x+y+z gallons of a 1.5 percent grade, what is x in terms of y and z?
A.y + 4z
B.(y +z) / 4
C.2y + 3z
D.3y + z
Answer: A.y + 4z
Explanation: Soln:
The resulting equation is
=> (.01x + .02y + .04z)/(x+y+z) = 1.5/100
=> x + 2y + 4z = 1.5x + 1.5y + 1.5z
taking x to one side and y and z to other side we get
=> x = y + 4z
Ans is a
Question: A total of 30 percent of the geese included in a certain migration study were male. If some of the geese migrated during the study and 30 percent of the migrating geese were male, what was the ratio of the migration rate for the male geese to the migration rate for the female geese? [Migration rate for geese of a certain sex = (number of geese of that sex migrating) / (total number of geese of that sex)]
A.1/4
B.7/12
C.2/3
D.1
Answer: D.1
Explanation: Let' take the Number of geese to be 100.
Male = 30. Female = 70.
Now the second part of the Q, Let's take the Number migrated to be 20.
So we have 20 geese that migrated and out of that 20% are male i.e 20/100 *30 = 6 Geese (Males)
And now we know out of the total 20 geese , 6 are male , then 14 have to be female.
Now the ratio part , Male Geese Ratios = 6/30 = 1/5. - A
Female Geese Ratios =14/70=1/5 - B
Cross Multiply Equations A and B and you get =1.
Ans D
Question: If 6th March, 2004 is sunday, what was the day of the week on 6th March, 2005?
A.monday
B.tuesday
C.friday
D.sunday
Answer: A.monday
Explanation: The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2004 is Sunday
6th March, 2005 is Monday.
Answer: A) Monday
Question: 3 no.'s A, B & C are in the ratio of 12:15:25. If sum of these no.'s is 312, find the ratio between the difference of B & A & the difference of C & B.
A.1 : 5
B.3 : 10
C.4 : 7
D.4 : 11
Answer: B.3 : 10
Explanation: We have, a = 12, b = 15, c = 25 and x = 312.
ax_ 12 X 312
a+b+c 12+15+25
— 72,
bx _ 15 X 312 B — — 90 a +b+c 12 + 15+ 25 cx 25 X 312 And, C =
a+b+c 12 + 15+ 25
...B-A=18 andC-B=60
- 150
Thus, their ratio = 18 : 60 or 3 : 10
B
Question: On a trip covering 450 km, a bicyclist travels the first 300 km at 20 km per hour and the remainder of the distance at 15 km per hour. What is the average speed, in km per hour, for the entire trip?
A.16.5
B.17.0
C.17.5
D.18.0
Answer: D.18.0
Explanation: time 1 = 300 / 20 = 15 hours
time 2 = 150 / 15 = 10 hours
total time = 25 hours
average speed = 450 / 25 = 18 km/hr
The answer is D.
Question: A speaks truth in 75% of cases and B in 80% of cases. In what percentage of cases are they likely to contradict each other, narrating the same incident
A.30%
B.35%
C.40%
D.45%
Answer: B.35%
Explanation: Explanation:
Let A = Event that A speaks the truth
B = Event that B speaks the truth
Then P(A) = 75/100 = 3/4
P(B) = 80/100 = 4/5
P(A-lie) = 1-3/4 = 1/4
P(B-lie) = 1-4/5 = 1/5
Now
A and B contradict each other =
[A lies and B true] or [B true and B lies]
= P(A).P(B-lie) + P(A-lie).P(B)
[Please note that we are adding at the place of OR]
= (3/5*1/5) + (1/4*4/5) = 7/20
= (7/20 * 100) % = 35%
Answer: Option B
Question: In a certain mathematical activity, we have five cards with five different prime numbers on them. We will distribute these five cards among three envelope: all could go in any envelope, or they could be broken up in any way among the envelopes. Then in each envelop, we find the product of all the cards in that envelope: that is the “number” of the envelope. An envelope containing no cards has the number 1. We then put the three envelope numbers in order, from lowest to highest, and that is our set. How many different T sets can be produced by this process?
A. 41
B. 89
C. 125
D. 243
Answer: A. 41
Explanation: Case 1: 1 used envelope => 1 way
Case 2: 2 used envelopes
- 4-1-0: Choose 4 from 5 cards: 5 ways
- 3-2-0: Choose 3 from 5 cards: 10 ways
Case 3: All envelopes used
- 3-1-1: Choose 3 from 5 andno need to choose 1 from 2: 10 ways
- 2-2-1: Choose 2 from 5 and choose 2 from 3, but two groups are the same => (10X3):2 = 15
Total T: 1+5+10+10+15=41 => Answer: A
Question: A set of football matches is to be organized in a "round-robin" fashion, i.e., every
participating team plays a match against every other team once and only once. If 10
matches are totally played, how many teams participated?
A.4
B.5
C.10
D.7
Answer: B.5
Explanation: 2 ways to solve this problem..
summation(x)=n(n-1)/2
n(n-1)/2=10;
n^2-n-20=0
Ans : 5
ANSWER:B
Question: Which one of the following numbers is exactly divisible by 11?
A.415624
B.415358
C.415647
D.425624
Answer: A.415624
Explanation: A
415624 is exactly divisible by 11.
Question: A woman has four blouses of different colors, three skirts of different colors, and two different pairs of shoes. She refuses to wear her pink blouse with her green skirt. How many different blouseskirt-shoe combinations could she wear?
A.8
B.12
C.22
D.17
Answer: C.22
Explanation: total ways = 4*3*2=24..
now its better to find the ways in which the pink blouse and green skirt are together and subtract from total to get the answer..
the ways in which the pink blouse and green skirt are together=1*1*2=2..
total ways =24-2=22..
ANSWER:C
Question: The area of a parallelogram is 128sq m and its altitude is twice the corresponding base. Then the length of the base is?
A.8
B.9
C.7
D.6
Answer: A.8
Explanation: 2x * x = 128
=> x= 8
Answer: A
Question: If the radius of a circle that centers at the origin is 5, how many W points on the circle have integer coordinates?
A. 4
B. 8
C. 12
D. 15
Answer: C. 12
Explanation: I understand this might not be required but I used the equation of a circle.
Since the origin is at 0, x^2+y^2=5^2.
X,Y could be +/- (0,5 or 5,0) - 4 possibilities.
X,Y could be +/- (3,4 or 4,3) - 8 possibilities.
Ans: W=C
Question: Raman mixed 27 kg of butter at Rs. 150 per kg with 36 kg butter at the rate of Rs. 125 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
A.129
B.287
C.190
D.188
Answer: C.190
Explanation: Explanation:
CP per kg of mixture = [27(150) + 36(125)]/(27 + 36) = Rs. 135.71
SP = CP[(100 + profit%)/100]
= 135.71 * [(100 + 40)/100] = Rs. 190.
Answer:C
Question: If 15 and 20 are the lengths of two sides of a triangular region, which of the following can be the length of the third side?
I. 10
II. 20
III. 40
A.I only
B.II only
C.I and II only
D.II and III only
Answer: C.I and II only
Explanation: The length of any side of a triangle must be larger than the positive difference of the other two sides, but smaller than the sum of the other two sides.
Let x be the length of the third side.
20-15 < x < 20+15
5 < x < 35
The answer is C.
Question: There are r red marbles, b blue marbles and w white marbles in a bag. Write the ratio of the number of blue marbles to the total number of marbles in terms of r, b and w.
A.r/ (r + b + w)
B.b/ (r + b + w)
C.w / (r + b + w)
D.r / (r + b )
Answer: A.r/ (r + b + w)
Explanation: Solution
The total number of marbles is
r + b + w
The total ratio of blue marbles to the total number of marbles is
r / (r + b + w)
ANSWER IS A
Question: If u, v, and w are three different positive integers whose sum is prime, which of the following statements could be true?
A.The average (arithmetic mean) of u, v, and w is prime.
B.Each of u + 3, v + 3, and w + 3 is prime.
C.Each of u + v, u + w, and v + w is prime.
D.Each of u, v, and w is prime.
Answer: D.Each of u, v, and w is prime.
Explanation: the question asks could be!!!!
this means that if at least one option works, it is the answer.
3, 7, 19 satisfies the condition, since 29 is a prime number. Since the question asks for a could be - we know automatically that D is the answer.
Question: The 106th term of the series a, b , b, c, c, c, d, d, d, d, e, e, e, e, e, .... is
A.h
B.k
C.l
D.o
Answer: D.o
Explanation: a is one time, b,2 times so on...
so 106=n(n+1)/2..
0r n(n+1)= 212 ... now 15*16=240...14*15<212 so n= 15. and 15th alphabet is O. ans D
Question: A person took some amount with some interest for 2 years, but increase the interest for 1%, he paid Rs.140/- extra, then how much amount he took?
A.s.5500/-
B.s.6000/-
C.s.4000/-
D.s.7000/-
Answer: D.s.7000/-
Explanation: Explanation:
2 years = Rs.140/-
year = 140/2
Rate of Interest = 1%
100/1% × 140/2 = Rs.7000/-
P = Rs.7000/-
Answer: Option D
Question: What is the ratio of 4/7 to the product 3*(7/3)?
A.4:49
B.1:3
C.3:21
D.1:7
Answer: A.4:49
Explanation: 4/7 / 21/3 = 4/49...
IMO option A.
Question: A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is:
A.2%
B.3%
C.5%
D.8%
Answer: C.5%
Explanation: C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.
S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.
Gain =(80/1600)x100 % = 5%
answer : C
Question: How many natural numbers are there between 23 and 100 which are exactly divisible by 6 ?
A.13
B.25
C.87
D.49
Answer: A.13
Explanation: Explanation:
Required numbers are 24, 30, 36, 42, ..., 96
This is an A.P. in which a = 24, d = 6 and l = 96
Let the number of terms in it be n.
Then tn = 96 a + (n - 1)d = 96
24 + (n - 1) x 6 = 96
(n - 1) x 6 = 72
(n - 1) = 12
n = 13
Required number of numbers = 13.
A)
Question: The present ratio of students to teachers at a certain school is 70 to 1. If the student enrollment were to increase by 50 students and the number of teachers were to increase by 5, the ratio of students to teachers would then be 25 to 1. What is the present number of teachers?
A.2
B.8
C.10
D.12
Answer: A.2
Explanation: We are given that the ratio of students to teacher is 70 to 1. We can rewrite this using variable multipliers.
students : teachers = 70x : x
We are next given that student enrollment increases by 50 and the number of teachers increases by 5. With this change the new ratio becomes 25 to 1. We can put all this into an equation:
Students/Teachers  25/1 = (70x + 50)/(x + 5)
If we cross multiply we have:
25(x + 5) =70x + 50
25x + 125 = 70x + 50
1.667 = x
x~2
Since x is the present number of teachers, currently there are 2 teachers.
Answer A.
Question: workers decided to raise Rs.3 lacs by equal contribution from each. Had they contributed Rs.50 eachextra, the contribution would have been Rs.3.60 lacs . How many workers were they?
A.220
B.230
C.1200
D.560
Answer: C.1200
Explanation: N * 50 = (360000 - 300000) = 60000
N = 60000 / 50
= 1200
C
Question: If |b| ≥ 1 and x= -| a| b, then which one of the following is necessarily true?
A.a -xb < 0
B.a -xb ≥ 0
C.a -xb > 0
D.a -xb ≤ 0
Answer: B.a -xb ≥ 0
Explanation: Explanation :
x = –|a| b
Now a – xb = a – (– |a| b) b
= a + |a| b2
∴ a – xb = a + ab2 … a 0 ≥ OR a – xb
= a - ab2 …a < 0
= a(1 + b2) = a(1 – b2).
Consider first case:
As a ≥ 0 and |b| ≥ 1, therefore (1 + b2) is positive.
∴ a (1 + b2) ≥ 0
∴ a – xb ≥ 0
Consider second case.
As a < 0 and |b| ≥ 1, therefore (1 – b2) ≤ 0
∴ a (1 – b2) ≥ 0 (Since –ve × -ve = +ve and 1 – b2 can be zero also), i.e. a – xb ≥ 0
Therefore, in both cases a – xb ≥ 0.
Answer : B
Question: Mr. loyd wants to fence his Square shaped land of 120Sqft each side.If a pole is laid every 12ft how many poles do he need?
A.20
B.30
C.40
D.50
Answer: C.40
Explanation: If each side is 120 feet..then total perimeter is 120*4=480
poles every 12 feet hence no of poles= 480/12=40
ANSWER:C
Question: In a zoo, the ratio of the number of cheetahs to the number of pandas is 1 : 3 and was the same five years ago. If the increase in the number of cheetahs in the zoo since then is 3, then what is the increase in the number of pandas?
A. 2
B. 3
C. 9
D. 10
Answer: C. 9
Explanation: One short cut to solve the problem is
c:p = 1:3
c increased to 4
=> 1:3 = 4:x
=> x = 12
=>p increased by 9
C is the answer
Question: A pilotless cargo carrier brings water, air and dry food to a space station. A third of the cargo's weight is water and the ratio, by weight, of air to dry food is 2:3. If the cargo contains 1,800 pounds of water, how many pounds of air does it contain?
A.1,200
B.1,300
C.1,440
D.3,000
Answer: C.1,440
Explanation: Let the capacity of the cargo be x
W + A + D = X
Given X/3 = W => X = 3*1800 = 5400
Now W+A+D = 5400
Now A+D = 5400 - 1800 => 3600
Given A/D = 2/3
Now air will 2/5*3600 =>1440.
ANSWER:C
Question: John found that the average of 15 numbers is 40. If 11 is added to each number then the mean of number is?
A.51
B.45
C.65
D.78
Answer: A.51
Explanation: (x+x1+...x14)/15 = 40
51
Option A
Question: Two identical machines have the ability to produce both nuts and bolts. However, it takes 1 second to produce a bolt but 2 seconds to produce a nut. What is the fastest the two machines, working together, can produce 1,800 nuts and 1,800 bolts?
A.1,250 seconds
B.1,500 seconds
C.1,750 seconds
D.2,700 seconds
Answer: D.2,700 seconds
Explanation: I used the Rate formula (R=\frac{1}{T})
Rate of 1st machine = Rate of making 1 bolt + Rate of making 1 nut = 1 + \frac{1}{2}
Rate of 1st machine = Rate of 2nd machine
After this I got lost.
Please can you help how to approach using algebra?
I wouldn't complicate:
1 machine needs 1,800*1 seconds to produce 1,800 bolts, so 2 need half of that, so 1,800/2 seconds.=900
1 machine needs 1,800*2 seconds to produce 1,800 nuts, so 2 need half of that, so 1,800*2/2 seconds.=1800
total =2700 sec
D
Question: Vanessa, Mike and Sarah have missed a total of 17 days of school this year. Vanessa and Mike have missed 14 days total, and Mike and Sarah have missed 12 days total. How many days of school did Vanessa miss alone?
A.9
B.4
C.5
D.2
Answer: C.5
Explanation: Vanessa + Mike + Sarah = 17
V+M=14
M+S=12 <<Use this formula & plug into the original formula, to get Vanessa's total
V + (M + S) = 17
V + 12 = 17
Subtract 12 from both sides
V = 5
Answer: C
Question: Suzie’s Discount Footwear sells all pairs of shoes for one price and all pairs of boots for another price. On Monday the store sold 22 pairs of shoes and 16 pairs of boots for $540. On Tuesday the store sold 8 pairs of shoes and 32 pairs of boots for $720. How much more do pairs of boots cost than pairs of shoes at Suzie’s Discount Footwear?
A.12
B.11
C.10
D.15
Answer: C.10
Explanation: Let X be pair of shoes and Y be pair of boots.
22x+16y = 540 ... eq1
8x +32y = 720....eq 2.
Now multiply eq 1 by 2 and sub eq 2.
44x = 1080
8x = 720.
36x = 360 => x = 10.
Sub x in eq 2.... we get 80 + 32y = 720... then we get 32y = 640 then y = 20
Differenece between X and Y is 10
Answer : C
Question: Molly's age in 18 years will be five times her age six years ago. What is Molly's present age?
A.8
B.9
C.10
D.12
Answer: D.12
Explanation: Let x be Molly's present age.
x + 18 = 5(x-6)
x = 12
The answer is D.
Question: What is the difference between the local value of 1 and 2 in the number 2124?
A.70
B.75
C.20
D.80
Answer: D.80
Explanation: Explanation:
100 â€“ 20 = 80
Answer: D
Question: The average age of 10 men increases by 2 years when two women are included in place of two men of ages 10 and 12 years. Find the average age of the women?
A.21
B.32
C.30
D.41
Answer: A.21
Explanation: 10 + 12+ 10 * 2
= 42/2
= 21
Answer:A
Question: Gambling with 4 dice, what is the probability of getting an even sum?
A.3/4
B.1/2
C.2/3
D.1/4
Answer: B.1/2
Explanation: Even sum can be obtained in following cases:
EEEE - one case. Each E can take 3 values (2, 4, or 6), so total for this case is 3^4;
OOOO - one case. Each O can take 3 values (1, 3, or 5), so total for this case is 3^4;
EEOO - 4!2!2!=64!2!2!=6 cases (EOEO, OOEE, ...). Each E can take 3 values (2, 4, or 6) and each O can also take 3 values (1, 3, or 5), so total for this case is 6*3^2*3^2=6*3^4
Total # of outcomes when throwing 4 dice is 6^4.
P=3^4+3^4+6∗3^4/6^4=1/2
Answer: B.
Question: How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.288
B.266
C.500
D.277
Answer: C.500
Explanation: Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
800+x = (65/3) * 60
800+x = 20 * 65 = 1300
x = 1300 - 800 = 500 meters
Answer: C
Question: Two trains of equal length, running with the speeds of 60 and 40 kmph, take 50 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions?
A.10 sec
B.11 sec
C.77 sec
D.99 sec
Answer: A.10 sec
Explanation: RS = 60 -40 = 20 * 5/18 = 100/18
T = 50
D = 50 * 100/18 = 2500/9
RS = 60 + 40 = 100 * 5/18
T = 2500/9 * 18/500 = 10 sec
Answer: A
Question: The ratio of 4 seconds to 8 hours
A.1:80
B.1:6000
C.1:600
D.1:7200
Answer: D.1:7200
Explanation: 1 hour =3600 sec
then 8 hours =8*3600=28800
so ,4:28800=1:7200
ANSWER:D
Question: At the end of the first quarter, the share price of a certain mutual fund was 25 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 55 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter?
A.24%
B.25%
C.30%
D.33%
Answer: A.24%
Explanation: Another method is to use the formula for 2 successive percentage changes:
Total = a + b + ab/100
55 = 25 + b + 25b/100
b = 24
Answer (A)
Question: 21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement.
A.3/19
B.3/31
C.9/42
D.4/49
Answer: C.9/42
Explanation: The probability that first toy shows the even number,
=1021=1021
Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.
Hence, probability that second toy shows the even number,
=920=920
Required probability,
=(1021)×(920)=(1021)×(920)
=9/42
C
Question: The ratio of cost price to the market price of an article is 4: 5. What is the profit percentage if the ratio of the profit percentage on selling the article to the discount allowed on it is 5: 4?
A.10%
B.12%
C.12.5%
D.15%
Answer: C.12.5%
Explanation: lets assume mp=100 and cp=80
p/d=5/4
therefore d= p*(4/5)
now cp + profit = mp- discount= sp
80+ p(80/100)=100-(p*(4/5)*(100/100))
solving for p we get p=12.5%
ANSWER:C
Question: A man can row with a speed of 15 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is?
A.78
B.66
C.20
D.26
Answer: C.20
Explanation: M = 15
S = 5
DS = 15 + 5
= 20
AnswerC
Question: A boat can move upstream at 25 kmph and downstream at 35 kmph, then the speed of the current is?
A.5
B.8
C.9
D.3
Answer: A.5
Explanation: US = 25
DS = 35
M = (35 - 25)/2 = 5
Answer:A
Question: A jogger is running at 9 kmph alongside a railway track in 240 meters ahead of the engine of a 120 meters long train . The train is running at 45 kmph in the same direction. how much time does it take for the train to pass the jogger?
A.46
B.36
C.18
D.22
Answer: B.36
Explanation: Explanation:
Distance to be covered = 240+ 120 = 360 m
Relative speed = 36 km/hr = 36×10/36 = 10 m/s
Time = distance/speed = 360/10 = 36 seconds
Answer: Option B
Question: A man swims downstream 30 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water?
A.3
B.8
C.9
D.4
Answer: B.8
Explanation: 30 --- 3 DS = 10
? ---- 1
18 ---- 3 US = 6
? ---- 1 M = ?
M = (10 + 6)/2 = 8
Answer: B
Question: 80 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
A.35
B.32
C.36
D.40
Answer: A.35
Explanation: x/7 = y/9 => x:y = 7:9
7/16 * 80 = 35
ANSWER:A
Question: Two pipes A and B can separately fill a tank in 2 minutes and 15 minutes respectively. Both the pipes are opened together but 4 minutes after the start the pipe A is turned off. How much time will it take to fill the tank?
A.22
B.10
C.28
D.27
Answer: B.10
Explanation: Explanation:
4/12 + x/15 = 1
x = 10
Answer:B
Question: A boat can travel with a speed of 24 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 56 km downstream
A.2 hours
B.4 hours
C.5 hours
D.6 hours
Answer: A.2 hours
Explanation: Explanation:
Speed of the boat in still water = 24 km/hr
speed of the stream = 4 km/hr
Speed downstream = (22+5) = 28 km/hr
Distance travelled downstream = 56 km
Time taken = distance/speed = 56/28 = 2 hours
Answer: Option A
Question: A, B, C together started a business. A invested Rs.1000 for 5 months B invested Rs.1500 for 6 months and C Rs.2000 for 3 months. If they get a total profit of Rs.3000. Find the share of A?
A.750
B.3000
C.2777
D.2999
Answer: A.750
Explanation: 2*5:3*6:4*3
10 : 18 : 12 => 5 : 9 : 6
5/20 * 3000 = 750
Answer:A