RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A number consists of 3 digits whose sum is 10. The middle digit is equal to the sum of the other two and the number will be increased by 99 if its digits are reversed. The number is:
A.250
B.330
C.352
D.253
Answer: D.253
Explanation: Let the middle digit be x.
Then, 2x = 10 or x = 5. So, the number is either 253 or 352.
Since the number increases on reversing the digits, so the hundred's digits is smaller than the unit's digit.
Hence, required number = 253.
ANSWER D
Question: When n is divided by 24, the remainder is 5. What is the remainder when 4n is divided by 8?
A.3
B.5
C.4
D.6
Answer: C.4
Explanation: Let n=5 (leaves a remainder of 5 when divided by 24)
4n = 4(5) =20, which leaves a remainder of 4 when divided by 8.
Answer C
Question: If a(a - 2) = 2 and b(b - 2) = 2, where a ≠ b, then a + b =
A. −1
B. −2
C. 4
D. 46
Answer: A. −1
Explanation: i.e. if a = -1 then b = 2
or if a = 2 then b = -1
But in each case a+b = -1+2 = -1
Answer: option A
Question: Find the value of x in 8.5 – { 5 ½ – [7 ½ + 2.8]/x}*4.25/(0.2)^2 = 306
A.3.2
B.3.4
C.3.5
D.4.1
Answer: C.3.5
Explanation: 8.5-{5.5-(7.5+(2.8/x))}*(4.25/0.04) = 306
 8.5-{5.5-{(7.5x+2.8)/x)}*(425/4) = 306
 8.5-{(5.5x-7.5x-2.8)/x}*(425/4) = 306
 8.5-{(-2x-2.8)/x}*106.25 = 306
 8.5-{(-212.5x-297.5)/x} = 306
 (306-221)x = 297.5  x =(297.5/85) = 3.5.
ANSWER C 3.5
Question: Two persons A and B take a field on rent. A puts on it 21 horses for 3 months and 15 cows for 2 months; B puts 15 cows for 6months and 40 sheep for 7 1/2 months. If one day, 3 horses eat as much as 5 cows and 6 cows as much as 10 sheep, what part of the rent should A pay?
A.27:52
B.27:58
C.27:57
D.57:52
Answer: A.27:52
Explanation: 3h = 5c
6c = 10s
A = 21h*3 + 15c*2
= 63h + 30c
= 105c + 30c = 135c
B = 15c*6 + 40s*7 1/2
= 90c + 300s
= 90c + 180c = 270c
A:B = 135:270
27:52
Answer:A
Question: If m^(-1) = -1/7 then m^(-2) is equal to
A.-9
B.-3
C.-1/9
D.1/49
Answer: D.1/49
Explanation: You made a mistake here.
You're right till
m^-2 = 1/m^2 and m^-1 = 1/m^1 = 1/m
given m^-1 = -(1/7) so, 1/m = -(1/7) solving this, m = -7
Now, m^-2 = 1/m^2 = 1/(-7)^2 = 1/49 ANS D
Question: Martin buys a pencil and a notebook for 80 cents. At the same store, Gloria buys a notebook and an eraser for $1.05 cents, and Zachary buys a pencil and an eraser for 65 cents. How many cents would it cost to buy three pencils, three notebooks, and three erasers? (Assume that there is no volume discount.)
A.300
B.325
C.350
D.375
Answer: D.375
Explanation: pencil + notebook = 80
notebook + eraser = 105
pencil + eraser = 65
Let's add all three equations.
2 pencils + 2 notebooks + 2 erasers = 250 cents
The cost to buy 3 of each would be (3/2)(250) = 375
The answer is D.
Question: Visitors to show were charged Rs.15 each on the first day. Rs.7.50 on the second day, Rs.2.50 on the third day and total attendance on the three days were in ratio 2:5:13 respectively. The average charge per person for the whole show is?
A.2
B.9
C.5
D.8
Answer: C.5
Explanation: 2: 5: 13
2x 5x 13x
15 7.5 2.5
30x + 37.5x + 32.5x = 100x/20x
Average = 5
Answer: C
Question: At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.60000?
A.19860
B.3277
C.2688
D.2998
Answer: A.19860
Explanation: A = 60000(11/10)3
= 79860
= 60000
----------
19860
Answer:A
Question: Three 6 faced dice are thrown together. The probability that all the three show the same number on them is?
A.1/38
B.1/36
C.1/28
D.1/29
Answer: B.1/36
Explanation: It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216
=1/36
Answer:B
Question: There are 6 working days in a regular week and for each day, the working hours are 10. A man earns Rs. 2.10 per hour for regular work and Rs. 4.20 per hour for overtime. If he earns Rs.525 in 4 weeks, how many hours did he work?
A.245
B.285
C.275
D.255
Answer: A.245
Explanation: Regular working hours in 4 weeks = (4 × 6 × 10) = 240 hours
Amount earned by working in these regular working hours
= 240 × 2.10 = Rs.504
Additional amount he earned = 525 - 504 = Rs.21
Hours he worked overtime = 21/4.2 = 210/42 = 5 hours
Total hours he worked = 240 + 5 = 245 hours
ANSWER:A
Question: A boy has 12 trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
A.120ways
B.149ways
C.144ways
D.130ways
Answer: C.144ways
Explanation: The boy can select one trouser in 12 ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 12 * 12
= 144 ways.
Answer: C
Question: A car driver travels from the plains to the hill station, which are 200 km apart at an average speed of 25km/hr. in return trip, he covers the same distance at an average speed of 20km/hr. the average speed of the car over the entire distance of 400 km is
A.8.95km/hr
B.22.2km/hr
C.27.8km/hr
D.37.9km/hr
Answer: B.22.2km/hr
Explanation: average speed = (2*25*20)/25+20 km/hr
=22.22 km/hr
Answer (B)
Question: A and B complete a job in 6 days. A alone can do the job in 9 days. If B works alone, how many days will it take to complete the job?
A.12
B.15
C.18
D.21
Answer: C.18
Explanation: The rate of A and B is 1/6
A's rate is 1/9
B's rate is 1/6 - 1/9 = 1/18
B can complete the job in 18 days.
The answer is C.
Question: A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that atleast one bulb is good?
A.125/128
B.125/120
C.125/126
D.125/125
Answer: C.125/126
Explanation: Required probability = 1 - 1/126
= 125/126
Answer: C
Question: If x = 2, then what is the value of 8x √x3 – x2
A.32
B.34
C.88
D.37
Answer: A.32
Explanation: Explanation:
Given: x = 2
8 * 2 √23 – 22
16√8-4
16√4
16 * 2 = 32
ANSWER:A
Question: The volume of a cube is 1728 cc. Find its surface?
A.864
B.209
C.278
D.276
Answer: A.864
Explanation: a3 = 1728 => a = 12
6a2 = 6 * 12 * 12 = 864
Answer:A
Question: Ram is working on a set of Data Sufficiency problems for his December GMAT: a geometry problem, an algebra problem, and a data interpretation problem. He has determined that statement 1 of the geometry problem is insufficient on its own, that both statement 1 and 2 of the algebra problem are insufficient on their own, and that statement 2 of the data interpretation problem is insufficient on its own. If the probabilities are expressed as percents R, approximately how much greater is the probability that all three answers are “C” after Ram figures out that statement 1 of the data interpretation problem is also insufficient on its own?
A.R=2.3%
B.R=2.8%
C.R=3.3%
D.5.6%
Answer: B.R=2.8%
Explanation: Step 1: Figure out what we need to know.We have two probabilities that we need to figure out: the one before Raj figures out that statement 1 of the data interpretation problem is also insufficient, and the one after. The answer is the difference between them, in the form of a percent.
Step 2: The first probability.
If statement 1 of the geometry problem is insufficient, then the only valid answer choices are B, C, and E; the probability that it is C is 1/3.
If both statements of the algebra problem are insufficient on their own, then the only remaining valid answers are C and E; the probability that it is C is 1/2
If statement 2 of the data interpretation problem is insufficient, then the remaining answers are A, C, and E, and the probability that C is correct is 1/3.
The probability of all three occurring is the product of the probability fractions: (1/3)*(1/2)*(1/3) = 1/18.
Step 3: The second probability.
Only the third problem has changed; if Raj now knows that statement 1 is also insufficient, the valid answer choices are only C and E, leaving a 1/2 probability that the answer is C.
The probability of all three occurring is still the product of those fractions, but this time they are (1/3)*(1/2)*(1/2) = 1/12.
Step 4: The answer.Note that here, as will sometimes happen on the GMAT, values that you compute “along the way” appear as wrong answer choices. This problem calls for the difference between our two numbers, (1/12)-(1/18) = 1/36, which is a 2.77777% chance, rounded to 2.8% —the correct answer is Choice B.
Question: The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 13 runs. Find his average in all the 30 matches?
A.31
B.66
C.88
D.99
Answer: A.31
Explanation: Total score of the batsman in 20 matches = 800.
Total score of the batsman in the next 10 matches = 130.
Total score of the batsman in the 30 matches = 930.
Average score of the batsman = 930/30 = 31.Answer:A
Question: Suppose in 1960, the consumer price index was 70 while in 2015 it is 280. What monthly salary in 2015 would have the same purchasing power as a monthly salary of 800 dollars in 1960?
A.2100
B.3200
C.2030
D.3000
Answer: B.3200
Explanation: Solution:
Let x be the monthly salary in 2015.
x/800 =280/70
x × 70 = 280 × 800
70x = 224000
70/70 x= 224000/70
x = 3200
Answer B
Question: At Daifu university, 40% of all students are members of both a chess club and a swim team. If 20% of members of the swim team are not members of the chess club, what percentage of all Daifu students are members of the swim team?
A.20%
B.30%
C.40%
D.50%
Answer: D.50%
Explanation: Assume there are total of 100 students. 40 students are members of both clubs. We are told that: "20% of members of the swim team are not members of the chess club", thus if S is a # of members of the swim team then 0.2S is # of members of ONLY the swim teem:
40+0.2S=S --> S=50.
Answer: D.
Question: Each of the 11 letters A, H, I, M, O, T, U, V, W, X and Z appears same when looked at in a mirror. They are called symmetric letters. Other letters in the alphabet are asymmetric letters. How many three letter computer passwords can be formed (no repetition allowed) with at least one symmetric letter?
A.2,145
B.6,435
C.12,100
D.12,870
Answer: D.12,870
Explanation: Total 3 letter passwords = 26 * 25 * 24 = 15600
Total letters = 26 = symmetrical letters (11) + asymmetrical letters (x) => x = 15
Total no. of 3 letters passwords using asymmetrical letters = 15 * 14 * 13 = 2730 (no repetition allowed)
Hence, no. of 3 letter passwords using atleast one symmetrical letter = 15600 - 2730 = 12870 ---> Option D
Question: 1,000^2 + 1,001^2 +1,002^2 + 1,003^2 + 1,004^2 + 1,005^2+ 1,006^2 =
A.6,030,053
B.6,030,054
C.6,030,055
D.6,042,091
Answer: D.6,042,091
Explanation: Interesting problem.
I think key is to notice that all the given answer choices differs in last two digits. Therefore, our entire focus should be to figure out how the given terms contribute to last two digits of total.
1000^2 -> 00
1001^1 -> 01
.
.
.
1006^2 -> 36
Total -> *91
Answer D.
Question: The center of a circle is (5, -1). (5, 7) is outside the circle, and (1, -1) is inside the circle. If the radius, r, is an
integer, how many possible values are there for r?
A. 3
B. 2
C. 6
D. 12
Answer: C. 6
Explanation: r must be greater than 4 and smaller than 8, hence r=5,6 or 7.
Answer C
Question: Nil and Ethan are brothers. They left their home
at the same time and drove to the same beach.
Nil drove at a speed of 50 miles per hour. Ethan
drove at a speed of 20 miles per hour. Nil
arrived at the beach 0.5 hour earlier than Ethan.
What is the distance between their home and the
beach?
A.60 miles
B.50 miles
C.40 miles
D.30 miles
Answer: B.50 miles
Explanation: Every hour, Nil gets ahead of Ethan 50 - 20 =
30 miles. When Nil arrived at the beach, Ethan
is only 20 × 0.5 = 10 miles behind. That tells us
they only drove 1 hour when Nil arrived at the
beach.
The distance between their home and the beach
is
Nil’s speed × Nil’s time
= 50 × 1 = 50 miles.
correct answer B
Question: Ram and Krishna start from A and B respectively at the same time and travel towards each other at constant speeds along the same route. Ram meets Krishna at point C on the road which is 900m away from starting point A and 600m away from point B. The time taken by Ram to reach point B is 20minutes. Find the constant speed of Krishna.
A.50 m/m
B.60 m/m
C.40 m/m
D.53.5 m/m
Answer: A.50 m/m
Explanation: total distance from A to B-
A - C = 900m, B - C = 600m;
therefore A-B = 1500m;
Vr=1500/20=75 m/m;
t-time taken by Ram for AB meet,
t=900/75=12 minutes = Time taken by Krishna for AB meet.
therefore,
Vk=600/12=50m/m.
option A
Question: A table is bought for Rs.940/- and sold at Rs.820/- find the loss percentage
A.12% Loss
B.10% Gain
C.20% Loss
D.20% Gain
Answer: A.12% Loss
Explanation: Formula = (Selling price ~ Cost price)/Cost price * 100
= (820 ~ 940)/940 = 12% Loss
A
Question: Rahul can finish one-fifth of hhis homework in one hour.Neha can finish three-seventh of her homework in one hout thirty minutes and riya can finish three fourth of her homework in three hours thirty minutes.If all of them start their homework at 12:00pm and can go to play as soon as they all finish their homework,when can they start to play,if they take a break at 3:30pm for thirty minutes?
A.5.00pm
B.BY 5:30 pm
C.4.40pm
D.6.30pm
Answer: B.BY 5:30 pm
Explanation: Let the work be 1
Then Rahul do 1/5 work in 60min
So Rahul do 1 work in 300 min
Then Neha do 3/7 work in 90min
So Neha do 1 work in 210min
Then Riya do 3/4 work in 210min
So Riya do 1 work in 280 min
By 300min i.e 5hr all will complete their work so
12-1,1-2,2-3,3-3:30, 4-4:30 ,4:30-5:30
By 5:30 they all go to play
ANSWER:B
Question: Pipe A can fill a tank in 6 hours. Due to a leak at the bottom, it takes 9 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank?
A.11
B.15
C.18
D.77
Answer: C.18
Explanation: Let the leak can empty the full tank in x hours 1/6 - 1/x = 1/9
=> 1/x = 1/6 - 1/9 = (3 - 2)/18 = 1/18
=> x = 18.
Answer: C
Question: An engagement team consists of a project manager, two team leaders, and four consultants. There are 2 candidates for the position of project manager, 3 candidates for the position of team leader, and 7 candidates for the 4 consultant slots. If 2 out of 7 consultants refuse to be on the same team, how many different teams are possible?
A.25
B.35
C.150
D.210
Answer: C.150
Explanation: Answer= Total number combinations - Total number of combinations with constraints
Total number of combinations = 2C1*3C2*7C4= 210
Total number of combinations with constraints = 2C1*3C2*5C2=60
Answer=210-60=150
ANSWER:C
Question: 112 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
A.66
B.26
C.49
D.27
Answer: C.49
Explanation: x/7 = y/9 => x:y = 7:9
7/16 * 112 = 49
Answer: C
Question: An employee’s annual salary was increased 50%. If her old annual salary equals $80,000 , what was the new salary?
A.$128,000
B.$120,000
C.$110,000
D.$139,000
Answer: B.$120,000
Explanation: Old annual salary = $80,000
Salary increase = 50%.
Original salary = $80,000 *50/100
= $40,000
new salary = $80,000+$40,000
=$120,000
Hence B.
Question: Tom read a book containing 560 pages by reading the same number of pages each day. If he would have finished the book 5 days earlier by reading 16 pages a day more, how many days did Tom spend reading the book?
A.19
B.18
C.9.12
D.20
Answer: C.9.12
Explanation: Actually u can set up 2 equation
P--stands for the pages
D--stands for the days
1) P*D=560(we want to find the Days, soP=560/D)
2) (P+16)(D-5)=560 => PD-5P+16D-80=560
as the 1) stated u can put 1) into 2)
=> 560-5P+16D-80=560 => 16D-5P=80
put the bold one into it => 16D-5(560/D)=80
the we get the final equation 16D^2-2800=80D (divide 16)
=> D^2-5D-175=0
(D-15)(D+10)=0 so D=9.12days Ans: C
Question: If A:B = 1/2: 1/3 B:C = 1/2:1/3 then A:B:C?
A.9:6:7
B.9:6:2
C.9:6:8
D.9:6:4
Answer: D.9:6:4
Explanation: A:B = 1/2:1/3 = 3:2
B:C = 1/2:1/3 = 3:2
--------------------
A:B:C = 9:6:4
Answer: D
Question: Using all the letters of the word "THURSDAY", how many different words can be formed?
A.8!
B.1
C.7
D.6
Answer: A.8!
Explanation: Total number of letters = 8
Using these letters the number of 8 letters words formed is 8P8 = 4.
Answer: A
Question: The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?
A.21:22
B.17:18
C.8:9
D.9:8
Answer: A.21:22
Explanation: Originally, let the number of boys and girls in the college be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
= (120/100) 7x and (110/100) 8x
= 42x/5 and 44x/5
Therefore, The required ratio = (42x/5):(44x/5)
= 21 : 22
Answer is A.
Question: There are three departments having students 64,58,24 .In an exam they have to be seated in rooms such that each room has equal number of students and each room has students of one type only (No mixing of departments). Find the minimum number of rooms required?
A.73
B.74
C.75
D.76
Answer: A.73
Explanation: WE NEED TO TAKE GCD WHICH IS 2
THUS ALL THE ROOMS WILL HAVE 2 STUDENTS OF THE SAME DEPT
1) 64/2 = 32
2) 58/2 = 29
3) 24/2 = 12
TOTAL NO. OF MIN ROOMS REQD = 32+12+29 = 73
ANSWER:A
Question: A girl sold a book at a profit of 7%. Did she sold it for Rs.7.50 more, 22% would have been gained. Find the CP?
A.20%
B.30%
C.50%
D.60%
Answer: C.50%
Explanation: 50%
C
Question: If the probability that Green Bay wins the Super Bowl is 1/12 and the probability that Milwaukee wins the World Series is 1/20, what is the approximate probability that either Green Bay wins the Super Bowl or Milwaukee wins the World Series?
A.1/240
B.1/12
C.1/8
D.1/7
Answer: C.1/8
Explanation: P(AorB)=P(A)+P(B)−P(AandB)P(AorB)=P(A)+P(B)−P(AandB)
P(AandB)=P(A)∗P(B)P(AandB)=P(A)∗P(B)
1/12 + 1/20 - (1/12 * 1/20)
= 5/60 + 3/60 - 1/120
= 8/60 - 1/120
= 16/120 - 1/120
= 15/120
= 1/8
The correct answer is C.
Question: A man is 28 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is
A.26 years
B.18 years
C.20 years
D.22 years
Answer: A.26 years
Explanation: Solution
Let the son's present age be x years .Then, man's present age	= (x+28)years.
Then	â€¹=â€º(x+28)+2= 2(x+2)
â€¹=â€ºx+30=2x+4
x= 26.
Answer A
Question: Pipe A can fill a tank in 16 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes?
A.21
B.55
C.66
D.77
Answer: A.21
Explanation: Let the pipe B be closed after x minutes.
30/16 - x/24 = 1 => x/24 = 30/16 - 1 = 14/16
=> x = 14/16 * 24 = 21.
Answer:A
Question: In a consumer survey, 65% of those surveyed liked at least one of three products: 1, 2, and 3. 40% of those asked liked product 1, 35% liked product 2, and 15% liked product 3. If 7% of the people in the survey liked all three of the products, what percentage of the survey participants liked more than one of the three products?
A.12
B.14
C.16
D.18
Answer: D.18
Explanation: 40 + 35 + 15 = 90
This number includes some people counted twice and some people counted three times.
90 - 65 = 25, and this number represents people counted twice or three times.
7% of the people are counted two extra times.
The percentage of people counted one extra time is 25 - 7(2) = 11.
The percentage of people who liked more than one product is 7% + 11% = 18%.
The answer is D.
Question: A man can row upstream at 10 kmph and downstream at 20 kmph, and then find the speed of the man in still water?
A.11
B.77
C.25
D.88
Answer: C.25
Explanation: US = 20
DS = 30
M = (30 + 20)/2 = 25
Answer:C
Question: A vessel of capacity 90 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution?
A.72
B.72.9
C.73
D.74
Answer: B.72.9
Explanation: Let the initial quantity of milk in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T - y)/T]n * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(90 - 9)/90]2 (90) = 72.9 litres.
ANSWER:B
Question: In a forest 150 deer were caught, tagged with electronic markers, then released. A week later, 50 deer were captured in the same forest. Of these 50 deer, it was found that 20 had been tagged with the electronic markers. If the percentage of tagged deer in the second sample approximates the percentage of tagged deer in the forest, and if no deer had either left or entered the forest over the preceding week, what is the approximate number of deer in the forest?
A.150
B.6,000
C.1,250
D.1,500
Answer: B.6,000
Explanation: The percentage of tagged deer in the second sample = 20/50*100=40%.
So, 150 tagged deers comprise 10% of total # of deers --> total # of deers = 150*40 = 6,000.
Answer: B
Question: What is the sum of all even numbers from 1 to 801?
A.160400
B.281228
C.281199
D.122850
Answer: A.160400
Explanation: Explanation:
800/2 = 400
400 * 401 = 160400
Answer: A
Question: A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold?
A.480
B.500
C.300
D.550
Answer: A.480
Explanation: 1/x - 1/20 = -1/24
x = 120
120 * 4 = 480
ANSWER A
Question: Of the diplomats attending a summit conference, 25 speak French, 32 do not speak Russian, and 20% of the diplomats speak neither French nor Russian. If 10% of the diplomats speak both languages, then how many diplomats attended the conference?
A.72
B.70
C.108
D.120
Answer: B.70
Explanation: {Total} = {French} + {Russian} - {Both} + {Neither}
{Total} = 25 + ({Total} - 32) - (0.1*{Total}) + 0.2*{Total}
Solving gives {Total} = 70.
Answer: B.
Question: In a hostel there were 100 students. To accommodate some more students the average budget is decreased by rupees 10. But total expenditure increased by Rs.400. If the total expenditure of the hostel now 5400, find the number of student joined?
A.30
B.20
C.35
D.32
Answer: D.32
Explanation: Let average is x
100x + 400 = 5400
x = 50
let the number of student joined is y
(100+y)*(50-10)=5400
y = 35
Answer:D
Question: Which one of the given numbers is completely divisible by 45?
A.202860
B.165642
C.112330
D.112332
Answer: A.202860
Explanation: To be divisible by 45 number has to be divisible by both 9 and 5.
If number ends with zero or five then it'll be divisible by 5.
For 9, add all the digits and if addition of all the digits is divisible by 9 then number'll be divisible by 9.
So, 202860 => 2+0+2+8+6+0= 18 which is divisible of 9. Last digit is 0, means divisible by 5.
So, 202860
ANSWER:A
Question: lexus car agency has 243 cars.he sold some cars at 9% profit and rest at 36% profit thus he gains 17% on the sale of all his cars.the no. of cars sold at 36% profit is?
A.36
B.37
C.72
D.39
Answer: C.72
Explanation: ratio of 36% profit cars to 9% profit cars = 8:19
so no. of cars sold at 36% profit = 243*8/27= 72 cars
ANSWER:C
Question: How many zeros does 65! end with?
A.20
B.15
C.25
D.30
Answer: B.15
Explanation: According to above 65! has 65/5+65/25=13+2=15 trailing zeros.
Answer: B.
Question: What is the units digit of (3^16)(4^13)?
A.2
B.4
C.6
D.7
Answer: B.4
Explanation: -> The ones place of (~3)^n repeats after 4 times like 39713.
The ones place of (~4)^n repeats after 2 times like 464.
Then, 3^16=3^4*4=3^0=1.,
4^13=4^2*6+1=4^1=~4
which is (3^16)(4^13) (3^0)(~4)=(~1)(~4)=~4. Therefore, the answer is B.
Question: A sum of money becomes 7/6 of itself in 5 years at a certain rate of simple interest. The rate per annum is?
A.20/7
B.20/3
C.23/6
D.10/3
Answer: D.10/3
Explanation: Let sum = x. Then, amount = 7x/6
S.I. = 7x/6 - x = x/6; Time = 5 years.
Rate = (100 * x) / (x * 6 * 5) = 10/3 %.
Answer:D
Question: A train 150 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?
A.2 Sec
B.6 Sec
C.8 Sec
D.9 Sec
Answer: D.9 Sec
Explanation: D
9 Sec
Speed of the train relative to man = (68 - 8) kmph
= (60* 5/18) m/sec = (50/3)m/sec
Time taken by the train to cross the man
= Time taken by It to cover 150 m at 50/3 m / sec = 150 *3/ 50 sec = 9sec