RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In how many ways the letters of the word RAIMBON be arranged?
A.4540
B.4740
C.5040
D.6432
Answer: C.5040
Explanation: Total ways of arranging the letters = 7! = 5040 ways.
C)
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 80 ps per meter is?
A.287
B.369
C.125
D.200
Answer: D.200
Explanation: 3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 0.80
= Rs.200
Answer:D
Question: The cost price of 13 articles is equal to the selling price of 11 articles. Find the profit percent?
A.78 2/11%
B.18 2/11%
C.88 2/11%
D.58 2/11%
Answer: B.18 2/11%
Explanation: Explanation:
13 CP = 11 SP
11 --- 2 CP
100 --- ? =>18 2/11%
Answer:B
Question: The ages of Charlie and Vaibhav are in the proportion of 3 : 5. After 9 years, the proportion of their ages will be 3 : 4. Then the current age of Vaibhav is:
A.15 years
B.16 years
C.135 years
D.21 years
Answer: A.15 years
Explanation: A
15 years
Charlie’s age = 3A and
Vaibhav’s age = 5A
{ (3A + 9)/(5A + 9) }=3/4
=> 4 (3A + 9) = 3 (5A + 9)
=> A = 3
Therefore, Vaibhav’s age = 15 years.
Question: A tank is 25 m long, 12 m wide and 6 m deep. What is the cost of plastering its walls and bottom at the rate of 75 paise per sq.m?
A.558
B.502
C.516
D.612
Answer: A.558
Explanation: TOTAL SURFACE S = 2LW + 2LH + 2WH
=(25 * 12) + (2 * 25 * 6 ) + ( 2 * 12 * 6 )
= 300 + 300 + 144
=744 M2
THEREFORE COST OF PLASTERING = 744 * 75 = 5800 PAISE = 558
ANSWER A
Question: Look at this series: 14, 28, 20, 40, 32, 64, ... What number should come next?
A.56
B.44
C.26
D.48
Answer: A.56
Explanation: A
56
This is an alternating multiplication and subtracting series: First, multiply by 2 and then subtract 8.
Question: If a is a digit in the number (a5,608 + 584)/88 = an integer, what is the value of a?
A.2
B.1
C.3
D.7
Answer: B.1
Explanation: (a5,608 + 584)/88 = a6,192/88
Factors of 88 = (8)(11)
Divisible by 8: if the last 3 digits of the number are divisible by 8.
192/8 = 24 => So, we want divisible by 11.
Divisibe by 11: subtract the last digit from the number, over and over again, as necessary. If the remaining number is divisible by 11, the original number is divisible by 11.
a619-2 => a61-7 => a5-4 => a1 => 11/11.
So a = 1.
Answer: B
Question: Determine the equation for the line parallel to r ≡ x + 2y − 2= 0 that passes through the point A = (1, 3).
A.x + 2y = 0
B.2y − 7= 0
C.x + 2y − 7= 0
D.x − 7= 0
Answer: C.x + 2y − 7= 0
Explanation: the equation for the line parallel to r ≡ x + 2y − 2= 0 is
x + 2y + K= 0
1 + 2• 3 + k = 0
k = −7
x + 2y − 7= 0
ANSWER C x + 2y − 7= 0
Question: In the sequence S, each term after the first is twice the previous term. If the first term of sequence S is 3, what is the sum of the 14th term in sequence S?
A.3(2^13)
B.9(2^15)
C.21(2^14)
D.9(2^14)
Answer: A.3(2^13)
Explanation: The terms in the sequence can be shown as
a(n) = 2* a(n-1)
So, the sequence will look like: 3, 2*3, (2^2) *3,...
And the nth term will be given as 2^(n-1) *3
Therefore, a(14) = (2^13)*3,
Answer : A
Question: David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross ?
A.19
B.28
C.30
D.37
Answer: C.30
Explanation: Explanation:
Suppose their paths cross after x minutes.
Then, 11 + 57x = 51 - 63x 120x = 40
x =	1/3
Number of floors covered by David in (1/3) min. = (1/3x 57	)=19.
So, their paths cross at (11 +19) i.e., 30th floor.
ANSWER IS C
Question: If 15 men can build a wall of forty two metres long in 5 days, what length of a similar wall can be built by 25 men in 4 days
A.48 metres
B.56 metres
C.60 metres
D.62 metres
Answer: B.56 metres
Explanation: Explanation :
Solution: Let the required length be x metres.
More men, more length built (Direct proportion)
Less days, less length built (Direct proportion)
men 15 : 25
days 5 : 4
.'.(15*5*x) = (25*4*42)
x = 56 metres.
Answer : B
Question: A company makes a profit equal to 25% of its sales. The profit is shared equally among the 4 owners of the company. If the company generates sales of $5,000,000, how much money does each one of the owners get?
A.$ 112,500
B.$ 212,500
C.$ 312,500
D.$ 412,500
Answer: C.$ 312,500
Explanation: The profit made on sales of $5,000,000 is given by
25% * $5,000,000 = $ 1,250,000
The profit made by each one of the 4 owners is given by
$ 1,250,000 / 4 = $ 312,500
correct answer C
Question: Bag contain 10 back and 20 white balls, One ball is drawn at random. What is the probability that ball is white
A.1
B.2/3
C.1/3
D.4/3
Answer: B.2/3
Explanation: Explanation:
Total cases = 10 + 20 = 30
Favourable cases = 20
So probability = 20/30 = 2/3
Answer: Option B
Question: If k^3 is divisible by 60, what is the least possible value of integer k?
A.12
B.30
C.60
D.90
Answer: B.30
Explanation: 60 = 2^2*3*5
Therefore k must include at least 2 * 3 * 5 = 30.
The answer is B.
Question: Denominator of a number is 4 less than the numerator. If 6 is added to the numerator, it becomes 3 times the denominator. Find the denominator.
A.1
B.3
C.5
D.7
Answer: C.5
Explanation: Let the Numerator be X and Denominator be Y. Then
=>X=Y+4 and 6+X=3*Y
=>6+Y+4=3*Y
=>2Y=10=>Y=5
Option C
Question: If 0.2 of a number is equal to 0.08 of another number, the ratio of the numbers is :
A.2 :3
B.3 :4
C.2 : 5
D.20 : 3
Answer: C.2 : 5
Explanation: 0.2A = 0.08B
-> A/B = 0.08/0.20 = 8/20 = 2/5
:. A : B = 2 : 5
ANSWER:C
Question: A cloth merchant has announced 25% rebate in prices. If one needs to have a rebate of Rs.40, then how many shirts, cash costing Rs.32, he should purchase ?
A.6
B.5
C.10
D.7
Answer: B.5
Explanation: Explanation:
Suppose the number of shirts = x.
Then, rebate = [25/100×32x]=8x
8x=40 or x = 5.
Correct Option : B
Question: A ranch has both horses and ponies. Exactly 5/6 of the ponies have horseshoes, and exactly 2/3 of the ponies with horseshoes are from Iceland. If there are 4 more horses than ponies, what is the minimum possible combined number of horses and ponies on the ranch?
A.18
B.21
C.38
D.40
Answer: D.40
Explanation: 5/6*P have horseshoes, so P is a multiple of 6.
2/3*5/6*P = 5/9*P are Icelandic ponies with horseshoes, so P is a multiple of 9.
The minimum value of P is 18. Then H = P+4 = 22.
The minimum number of horses and ponies is 40.
The answer is D.
Question: Henry sold an item for Rs.7200/- and incurred a loss of 20%. At what price should he have sold the item to have gained a profit of 20%?
A.10600
B.10800
C.11000
D.11200
Answer: B.10800
Explanation: Explanation:
20% loss means SP = 80% of CP
:. CP = Rs.7200x100/80 = Rs.9000.
The SP for a gain of 20% = 9000+20% of 9000 = 9000+1800 =Rs10800.
Answer: Option B
Question: If y = 30p, and p is prime, what is the greatest common factor of y and 10p, in terms of p?
A.10p
B.2p
C.5p
D.7p
Answer: A.10p
Explanation: Y=30p
other number is 10p
then GCF(30p,10P)=10P; A is the correct answer
Question: 10% people of a village in Sri Lanka died by bombardment, 20% of the remainder left the village on account of fear. If now the population is reduced to 3168, how much was it in the beginning?
A.A)3800
B.B)4200
C.C)4400
D.D)4500
Answer: C.C)4400
Explanation: X * (90/100) * (80/100) = 3168
X = 4400
ANSWER:C
Question: A dealer originally bought 90 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?
A.q/60
B.3q/2
C.145q
D.q/90
Answer: A.q/60
Explanation: The cost of each battery was q/90.
Each battery was sold for 1.5q/90 = 3q/180 = q/60.
The answer is A.
Question: The first term in a sequence is 1 and the second term is 10. From the third term on each term is the average (arithmetic mean) of all preceding terms. What is the 29th term in the sequence?
A.3.5
B.5.5
C.10
D.10.5
Answer: B.5.5
Explanation: The third term is 5.5 since this is the average of 1 and 10.
Then the next terms will all be 5.5 since the average stays at 5.5
The answer is B.
Question: Billy makes $124 more than Kimberly in a week. Wynona makes 3 times as much as Billy and Kimberly put together in a week, which totals $2,436. How much would Billy, Kimberly, and Wynona make together in a month?
A.$12,992
B.$9,744
C.$29,232
D.$11,232
Answer: A.$12,992
Explanation: b-k=124
3(b+k)=2,436 or b+k=812
Solving the 2 equations you get B=$468 and K=$344
So 4(468+344+2436)=$12,992
Correct Answer: A
Question: The perimeter of one square is 48 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?
A.13√4
B.13√2
C.23√2
D.12√4
Answer: B.13√2
Explanation: 4a = 48 4a = 20
a = 12 a = 5
a2 = 144 a2 = 25
Combined area = a2 = 169 => a = 13
d = 13√2
Answer: B
Question: The average age of A and B is 50 years. If C were to replace A, the average would be 50 and if C were to replace B, the average would be 40. What are the age of A, B and C?
A.100,100, 80
B.50, 50, 40
C.40, 60, 40
D.50, 60, 40
Answer: C.40, 60, 40
Explanation: Given A + B = 100â€¦(i)
C + B = 100â€¦ (ii)
A + C = 80â€¦(iii)
(i) + (ii) + (iii) â‡’ A + B + C = 140â€¦(iv)
from (i) and (iv), we get
C = 40years
âˆ´ B = 60 years and A = 40 years
Answer C
Question: If 50 apprentices can finish a job in 4 hours, and 30 journeymen can finish the same job in 7 hours, how much of the job should be completed by 10 apprentices and 15 journeymen in one hour?
A.17/140
B.29/180
C.26/143
D.1/5
Answer: A.17/140
Explanation: 50 apprentices can finish the job in 4 hours,thus:
10 apprentices can finish the job in 4*5 = 20 hours;
In 1 hour 10 apprentices can finish 1/20 of the job.
30 journeymen can finish the same job in 4,5 hours,thus:
15 journeymen can finish the job in 7*2 = 14 hours;
In 1 hour 15 journeymen can finish 1/14 of the job.
Therefore, in 1 hour 10 apprentices and 15 journeymen can finish 1/20+1/14=17/140 of the job.
Answer: A
Question: If x^4 > x^5 > x^3, which of the following could be the value of x?
A.-3
B.-2
C.-2/3
D.2/3
Answer: C.-2/3
Explanation: Let's break this question down into two parts. I: x4>x5x4>x5 and II: x5>x3x5>x3
Consider Part I:
x4>x5x4>x5
For this to be true, either xx is negative or it is a fraction less than 1
Consider Part II:
x5>x3x5>x3
If xx is negative, then for this to be true, xx has to be greater than -1.
If xx is a fraction less than 1, then for this part to be true, xx must also be negative.
In either case, xx can be represented by the inequality 0>x>−10>x>−1.
The only option that satisfies this condition is C (-2/3)
ANSWER:C
Question: A die is thrown three times. Events X and Y are defined as below:
X : 4 on the third throw
Y : 6 on the first and 5 on the second throw
What is the probability of X given that Y has already occurred.
A.1/7
B.1 by 6
C.2/3
D.2/5
Answer: B.1 by 6
Explanation: The sample space has 216 outcomes.
Now X =
(1,1,4) (1,2,4) ... (1,6,4) (2,1,4) (2,2,4) ... (2,6,4)
(3,1,4) (3,2,4) ... (3,6,4) (4,1,4) (4,2,4) ...(4,6,4)
(5,1,4) (5,2,4) ... (5,6,4) (6,1,4) (6,2,4) ...(6,5,4) (6,6,4)
Y = {(6,5,1), (6,5,2), (6,5,3), (6,5,4), (6,5,5), (6,5,6)}
and X n Y = {(6,5,4)}.
Now P(Y) = 6/216
and P (X n Y) = 1/216
Then P(X|Y) = (1/216)/(6/216) = 1/6.
B)
Question: What is the sum of all the numbers between 1 and 16, inclusive?
A.190
B.200
C.185
D.166
Answer: A.190
Explanation: All you have to do is add 1+2+3+4...+14+15+16, which is 190.
Final Answer:
A
Question: If the median of a list of numbers is m, the first quartile of the list is the median of the numbers in the list that are less than m. What is the first quartile of the list of numbers 42, 24, 30, 34, 26, 36, 33 and 35 ?
A.33
B.28
C.27
D.24
Answer: B.28
Explanation: It is given that a quartile is the middle number of all numbers less than median..
so lets arrange the number in ascending order- 42, 24, 30, 34, 26, 36, 33 and 35
24, 26, 30, 33, 34, 35, 36, 42...
numbers less than median are 24, 26, 30, 33..
the median of these numbers = center of 26 and 30 = 28
B
Question: If Re.250 amounts to Rs.400 over a period of 5 years. What is the rate of simple interest?
A.11%
B.12%
C.13%
D.10%
Answer: B.12%
Explanation: 150 = (250*5*R)/100
R = 12%
Answer:B
Question: For the given equation x9+5x8−x3+7x+2=0,x9+5x8−x3+7x+2=0, how many maximum real roots are possible?
A.3
B.7
C.4
D.0
Answer: C.4
Explanation: f(x) = x9+5x8−x3+7x+2=0x9+5x8−x3+7x+2=0
In f(x), there are 2 changes of sign. So, there are two positive roots.
f(-x) = - x9+5x8−x3+7x+2=0x9+5x8−x3+7x+2=0
In f(-x), there are 3 changes of sign. So, there are three negative roots.
So, in all there are 5 real roots possible (2 positive and 3 negative) and as degree of the given equation is 9, there are total 9 roots. So, remaining 4 roots will be imaginary.
Answer:C
Question: The diagonals of two squares are in the ratio of 2 : 5. Find the ratio of their areas.
A.5:25
B.4:25
C.3:15
D.7:15
Answer: B.4:25
Explanation: Let the diagonals of the squares be 2x and 5x respectively.
Ratio of their areas = (1/2)*(2x) 2:(1/2)*(5x) 2
= 4x2: 25x2
= 4 : 25.
ANSWER B 4:25
Question: In how many ways R can the crew of a ten oared boat be arranged ,when of the ten persons available, 2 of whom can row only on the bow side and 3 of whom can row only on the stroke side?
A.1. 10!/(2! * 3!)
B.2. 10!/(8! * 7!)
C.3. 5!/(3! * 2!)
D.4. (5!)^3/(3! * 2!)
Answer: D.4. (5!)^3/(3! * 2!)
Explanation: Ans is D.
Going by the assumtion that both the Bow side and Stroke side will have 5 person each.
Five(3+2) of them had allready been selected(according to their preference), so from the remaining 5 we have to select 2 for the stroke side or 3 for the bow side.
and the 5 crew of each side can be arranged in 5! ways.R
Hence answer is 5C3 * 5! * 5!= (5!)^3/ 3!2!.D
Question: Envelopes can be purchased for $1.50 per pack of 100, $1.00 per pack of 50, or $0.03 each. What is the greatest number of envelopes that can be purchased for $8.40?
A.426
B.430
C.443
D.530
Answer: D.530
Explanation: I think first we should see in what group envelopes value less, so that we can buy as many as we can with a specific amount of money:
-the 100 pack costs 1.5$, meaning 0.015$ per envelope
-the 50 pack costs 1$, meaning 0.02$ per envelope
-the single envelope costs 0.03$ per envelope
Thus, we have to buy as many 100 packs as we can, then as meny of 50 packs as we can and the remaining envelopes are single ones.
Having 8.4$, we can buy as many as 5 packs of 100 (5 x 1.5$ = 7.5$). We then have 0.9 $ left. so we buy 30 individual envelopes. If we add up the numbers, we get 500+30=530 envelopes. Answer D
Question: A wholesaler wishes to sell 100 pounds of mixed nuts at $1.50 a pound. She mixes peanuts worth $1.50 a pound with cashews worth $4.00 a pound. How many pounds of cashews must she use?
A.40
B.45
C.50
D.55
Answer: A.40
Explanation: From the question stem we know that we need a mixture of 100 pounds of peanuts and cashews. If we represent peanuts as x and cashews as y, we get x + y = 100. Since the wholesaler wants to sell the mixture of 100 pounds @ $2.50, we can write this as: $1.5 * (x + y) = $1.5x + $4y
From the equation x + y = 100, we can rewrite y as y = 100 - x and substitute this into our equation to get:
$2.5 * (x + 100 - x) = $1.5x + $4(100 - x)
If you solve for x, you will get x = 60, and therefore y = 40. So the wholesaler must use 40 pounds of cashews.
You can substitute into the original equation to see that: $250 = $1.5(60) + $4(40)
Answer is A.
Question: A can finish a piece of work in 4 days. B can do it in 8 days. They work together for two days and then A goes away. In how many days will B finish the work?
A.4
B.5
C.6
D.2
Answer: D.2
Explanation: 2/4 + (2 + x)/8 = 1 => x = 2 days
Answer: D
Question: If each term in the sum a1+a2+a3+...+an either 2 or 22 and the sum equals 100, which of the following could be equal to n?
A.38
B.39
C.40
D.41
Answer: C.40
Explanation: Min value of 'n' can be 10 i.e 4*22+6*12 => 22+22+22+22+2+2+2+2+2+2 = 100
Since we don't have 10 in the options proceed further, (10-1)+22/2 => 20 digits, which is again not in the options
(20-1) + 22/2 = 30 digits ( not in options)
(30-1) + 22/2 = 40 digits
ANSWER:C
Question: Two trains start from the same station at the same time and travel in opposite directions. One
train travels at an average rate of 40 mph, the other at 65 mph. In how many hours will they be
315 miles apart?
A.1 hour
B.2 hours
C.3 hours
D.4 hours
Answer: C.3 hours
Explanation: First we’ll make the d=rt chart. But we won’t fill in the d.
d = r x t
Train 1 40 x
Train 2 65 x
The reason we have an x in the time column is because they left at the same time and will be 315
at the same time. In other words, their times are equal.
Now, the big question. Are there distances equal? Since they do not meet the criteria in a TYPE
A problem, the answer is no. That means the sum of the distances must be equal to a number.
D1 + D2 = #
40x + 65 = 315
105x = 315
x = 3 It will take three hours.
correct answer C
Question: The average of first ten prime numbers:
A.5.6
B.11.2
C.12.9
D.6.3
Answer: C.12.9
Explanation: Explanation:
The first ten prime numbers is 2, 3, 5, 7, 11, 13, 17, 19, 23, 29
Average = 129/10 = 12.9
Answer: Option C
Question: One out of every 500 light bulbs are defected. If 2 out of every 10 defected light bulbs have a broken glass and there are 12 broken glass light bulbs in the shipment, how many light bulbs total are there in the shipment?
A.2,000
B.5,000
C.10,000
D.30,000
Answer: D.30,000
Explanation: out of 500 only 1 bulb is defective.So for 10 defective bulbs, we must have 5000 bulbs
Now out of these 10 bulbs, 2 bulbs, have broken glass
i.e 2 broken glass out of 5000 bulbs
12 broken glass will be from 30000 bulbs
Answer is D
Question: The local carpenter made a beautiful table for my father. He told him that the type of wood which he used costs G dollars per kg, and that the table only weight F kilograms. If the carpenter worked for D hours on the table and makes E dollars per hour, how much profit will my father make when he sells the table for V dollars?
A.V-GF-DE
B.V+GE-DF
C.V-(GF-DE)
D.G(V-DE)+F
Answer: A.V-GF-DE
Explanation: The wood will cost= GF dollars
The carpenter will be payed an amount= DE dollars
Hence, the cost price= GF+DE dollars
The selling price= V dollars
And the profit= V-(GF+DE)
The answer is A
Question: In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is?
A.1 hr
B.7 hr
C.9 hr
D.4 hr
Answer: A.1 hr
Explanation: Let the duration of the flight be x hours. Then,
600/x - 600/(x + 1/2) = 200
x(2x + 1) = 3 2x2 + x - 3 = 0
(2x + 3)(x - 1) = 0
x = 1 hr.
Answer: A
Question: In a rectangular axis system, what is the area of a parallelogram with the coordinates: (4,4), (7,4), (5,9), (8,9) ?
A.21.
B.28.
C.5.
D.49.
Answer: C.5.
Explanation: Delta x will give us the dimension of one side of the parallelogram = 5-4= 1 unit
Delta y will give us the dimension of the other side of parallelogram = 9-4=5 unit
Area of parallelogram = 1*5 = 5
ANSWER IS C
Question: For a certain set, the value range of its members is 84.4. A new set is created from the members of the old set as follows: 12 is subtracted from a member of the old set, and the result is divided by 4. The resulting value is a member of the new set. If this operation is done for each member of the old set, what is the range of values of the members of the new set?
A.18.1
B.21.1
C.36.5
D.42.2
Answer: B.21.1
Explanation: Let x and z be the smallest and largest of the original set, respectively.
z - x = 84.4
The smallest and largest members of the new set will be (x-12) / 4 and (z-12) / 4.
Then the range is (z-12) / 4 - (x-12) / 4 = (z-x) / 4 = 84.4 / 4 = 21.1
The answer is B.
Question: A discount of 10 percent on an order of goods followed by a discount of 30 percent amounts to
A.the same as one 45 percent discount
B.the same as one 40 percent discount
C.the same as one 37 percent discount
D.the same as one 30 percent discount
Answer: C.the same as one 37 percent discount
Explanation: 0.9*0.7*x=0.63x from initial value, meaning 0.37 or 37% discount
C
Question: The interest on a certain deposit at 4.5% p.a. is Rs. 202.50 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a.?
A.Rs. 20.25
B.Rs. 22.50
C.Rs. 25
D.Rs. 42.75
Answer: B.Rs. 22.50
Explanation: Solution
S.I. = Rs. 202.50, R = 4.5% ,T = 1 year.
principal = Rs. (100x202.50/4.5x1)= Rs. 4500.
Now,P = Rs. 4500,R = 5% ,T = 1 year.
S.I. = Rs.(4500x5x1/1000 = Rs. 225.
∴ Difference in interest = Rs. (225 - 202.50)= Rs. 22.50.
Answer B
Question: If an amount of Rs 42,900 is distributed equally
amongst 22 persons, how much amount would each
person get?
A.Rs 1950
B.Rs 2000
C.Rs 745
D.Rs 765
Answer: A.Rs 1950
Explanation: Required amount =42900/22 = Rs 1950
Answer A
Question: When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 15% water?
A.1.2 kg
B.1.5 kg
C.1.7 kg
D.1.9 kg
Answer: C.1.7 kg
Explanation: Explanation :
Flower-nectar contains 50% of non-water part.
In honey this non-water part constitutes 85% (100-15).
Therefore 0.5 X Amount of flower-nectar = 0.85 X Amount of honey = 0.85 X 1 kg
Therefore amount of flower-nectar needed =
(0.85/0.51)kg=1.7 kgs
Answer : C
Question: A particular library has 300 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 65 percent of books that were loaned out are returned and there are 244 books in the special collection at that time, how many books of the special collection were loaned out during that month?
A.120
B.140
C.160
D.180
Answer: C.160
Explanation: The total number of books is 300.
Let x be the number of books which were loaned out.
65% of books that were loaned out are returned.
35% of books that were loaned out are NOT returned.
Now, there are 244 books, thus the number of un-returned books is 300-244 = 56 books.
0.35x = 56
x = 160
The answer is C.
Question: When N is divided by T, the quotient is S and the remainder is B. Which of the following expressions is equal to N?
A.ST
B.S + V
C.ST + B
D.T(S+V)
Answer: C.ST + B
Explanation: Using the rule dividend = Quotient * divisor + remainder =>ST + B C is correct
Question: Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran share in the profit?
A.Rs 9500
B.Rs 10,000
C.Rs 10,500
D.Rs 11,000
Answer: C.Rs 10,500
Explanation: Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.
Simran's share = Rs.24500 x	3/7	= Rs. 10,500.
ANSWER :C
Question: what is next no. 11 23 47 83 131 191 263 347 443???
A.171
B.181
C.191
D.551
Answer: D.551
Explanation: 11+12*1=23
23+12*2=47
47+12*3=83
83+12*4=131
131+12*5=191
191+ 12*6=263
263+12*7=347
347+12*8=443
443+12*9=551
ANSWER:D
Question: After 10% of the inhabitants of a village disappeared, a panic set in during which 25% of the remaining inhabitants left the village. At that time, the population was reduced to 5130. What was the number of original inhabitants?
A.7300
B.7600
C.7900
D.8200
Answer: B.7600
Explanation: Let the total number of original inhabitants be x.
(75/100) * (90/100) * x = 5130
(27/40) * x = 5130
x = 5130 * 40 / 27 = 7600
The answer is B.
Question: A 400 meter long train crosses a platform in 45 seconds while it crosses a signal pole in 30 seconds. What is the length of the platform?
A.200
B.400
C.350
D.1800
Answer: A.200
Explanation: Speed = [400 / 30] m/sec = 40/3 m/sec.
Let the length of the platform be x meters.
Then, x + 400 / 45= 40/3
3(x + 400) = 1800 è x = 200 m. Answer: A