RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Difference of two parallel sides of atrapezium is 4cm. perpendicular distance between them is10cm. If the area of the trapezium is 250cm^2. Find the lengths of the parallel side?
A.20 cm and 21 cm
B.25 cm and 23 cm
C.27 cm and 23 cm
D.30 cm and 34 cm
Answer: C.27 cm and 23 cm
Explanation: Let the two parallel sides of the trapezium be a cm and b cm.
Then, a-b = 4 ------ (1)
And, (1/2) x (a+b) x 10 = 475 =>(a+b) =((250 x 2)/10) => a + b = 50------- (2)
Solving 1 and 2, we get: a=27,b=23
So, the two parallel sides are 27 cm and 23 cm.
C
Question: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2490 ?
A.Rs. 820
B.Rs. 830
C.Rs. 840
D.Rs. 850
Answer: B.Rs. 830
Explanation: Explanation:
Let the total amount in the partnership be 'x'.
Then A's share = x/3
B's share = x/4
C's share = x/5
D's share = x - (x/3 + x/4 +x/5) = 13x/60
A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13
A's share in the profit of Rs. 2490 = 20 (2490/60) = Rs. 830.
ANSWER IS B
Question: Solve for x: 2x â€“ y = (3/4)x + 4.
A.(y + 6)/5
B.4(y + 4)/5
C.(y + 6)
D.4(y - 6)/5
Answer: B.4(y + 4)/5
Explanation: Solution:
2x â€“ y = (3/4)x + 4.
or, 2x - (3/4)x = y + 4.
or, (8x -3x)/4 = y + 4.
or, 5x/4 = y + 4.
or, 5x = 4(y + 4).
or, 5x = 4y + 16.
or, x = (4y + 16)/5.
Therefore, x = 4(y + 4)/5.
correct answer B
Question: A water supply company charges $3 for the first 500 liters of water plus $0.06 for each additional litter of water in a month. What would this company charge for a water consumption of 750 liters in a month ?
A.$15.60
B.$16.00
C.$18
D.$18.70
Answer: C.$18
Explanation: first 500 litres chages = $3
rest of the litres = 750 - (500) = 250
charge for the rest of the units = 250 *06 = 15
total charge = 3 + 15 = 18
Answer is C
Question: A woman is budgeting her 500 dollars over the next 50 days. After 10 days she paid off enough bills so that the remaining money will now be enough for the same period of 50 days as before. How much money did she spend?
A.100
B.200
C.150
D.50
Answer: A.100
Explanation: 500 ---- 50
500 ---- 40
x ---- 50
x*50 = 500*40
x = 400
500
-----
100
Answer = A
Question: 18 men shake hands with each other. Maximum no of handshakes without cyclic handshakes.
A.190
B.153
C.210
D.220
Answer: B.153
Explanation: 1st person will shake hand with 17 people
2nd person will shake hand with 16 people
3rd person will shake hand with 15 people
......
total no. of handshakes = 17+...+3+2+1 = 17*(17+1)/2 = 153
or, if there are n persons then no. of shakehands = nC2 = 18C2 = 153
ANSWER:B
Question: √(21)^2
A.7
B.14
C.49
D.21
Answer: D.21
Explanation: explanation
√(21)^2 =?
or, ? = 21
Answer D
Question: The difference between the squares of two consecutive odd integers is always divisible by:
A.3
B.6
C.7
D.8
Answer: D.8
Explanation: Let the two consecutive odd integers be (2x + 1) and (2x + 3)
Then, (2x + 3)2 - (2x + 1)2 = (2x + 3 + 2x + 1) (2x + 3 - 2x - 1) = (4x + 4)(2)
= 8 (x + 1), which is always divisible by 8
ANSWER:D
Question: A car crosses a 600 m long bridge in 5 minutes. Whatis the speed of car in km per hour?
A.7 km/hr
B.7.2 km/hr
C.7.5 km/hr
D.7.678 km/hr
Answer: B.7.2 km/hr
Explanation: Speed = 600 m/sec.
5 x 60
= 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
= 2 x 18 km/hr
5
= 7.2 km/hr
B
Question: By selling 32 orange in a dollar, a man loses 40%. How many orange must he sell in a dollar to gain 20% profit?
A.16
B.18
C.20
D.25
Answer: A.16
Explanation: x - expenses
0.6x after selling 32 oranges per 1$
want to get 1.2x
1.2x/0.6x=2, so should be 32/2=16 oranges
ANSWER:A
Question: From the set of numbers x, y, t, z, p, q and w, how many different combinations can we have without the t in them? Ex:. (x,y), (x), (w,z,y,x,p,q), etc and (x,y)=(y,x)
A.10
B.14
C.45
D.63
Answer: D.63
Explanation: Another way: Any letter (x, y, z, w, p, q) can be included or not. So, we have 2^6 combinations - 1 empty combination = 63 combinations
D
Question: The ratio of red, yellow, and green jelly beans in a jar is 1:3:4. If the number of jelly beans is increased by 60%, 20%, and 40% respectively, what will be the new ratio?
A.3:7:12
B.4:9:14
C.5:11:15
D.6:14:17
Answer: B.4:9:14
Explanation: The new ratio will be 1.6:3.6:5.6=16:36:56=4:9:14.
The answer is B.
Question: In the formula V = 1/(2r)^4, if r is halved, then V is multiplied by?
A.16
B.8
C.1
D.1/8
Answer: A.16
Explanation: Say r=2 => V1 = 1/256
when r=1; V2 = 1/16
V2 = 16*V1.
Answer : A
Question: From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first is a red card and the second is a king is?
A.1/26
B.1/25
C.1/19
D.1/11
Answer: A.1/26
Explanation: Let E1 be the event of drawing a red card.
Let E2 be the event of drawing a king .
P(E1 ∩ E2) = P(E1) . P(E2)
(As E1 and E2 are independent)
= 1/2 * 1/13 = 1/26
Answer:A
Question: While extinguishing a fire that has caught a mansion, the firefighter is standing on the middlemost rung of the ladder. In order to reach at a better position, he climbs 6 rungs but due to the devious flames, he has to climb down 10 rungs back. When the fire calms down a little, he climbs 18 rungs to reach the top rung.
How many rungs did the ladder have?
A.29
B.33
C.21
D.45
Answer: A.29
Explanation: A
29 rungs.
Since he is standing on the middle rung in the beginning,
Let the middle rung be x
He climbs 6 rungs first and then climbs down rungs and again climbs 18 rungs to reach the top.
Thus the position is now,
X+6-10+18 = x + 14.
This position is on the top rung.
Thus the ladder has 14 rungs above the middle rung and also it must be having 14 rungs down the middle point as well.
14+14+1 = 29.
Thus there are total 29 rungs in the ladder.
Question: The average weight of 8 person's increases by 6 kg when a new person comes in place of one of them weighing 45 kg. What is the weight of the new person?
A.90
B.93
C.56
D.80.5
Answer: B.93
Explanation: Total increase in weight =8 ×6= 48
If x is the weight of the new person, total increase in weight = x−45
=> 48 = x - 45
=> x =48+45 = 93
ANSWER:B
Question: There are 5 magazines and 4 fiction books. In how many ways can 4 magazines and 2 fiction can be arranged on a shelf?
A.21400
B.21500
C.21600
D.21700
Answer: C.21600
Explanation: 4 magazines can be selected out of 5 in 5C4 ways. 2 fiction can be selected out of4 in 4C2 ways. Number of ways of arranging magazines and fiction: = 5C4*4C2 =30 After selecting any 6 books (4 magazines and 2 fiction) in one of the 30 ways, they can be arranged on the shelf in 6!=720 ways. By the Counting Principle, the total number of arrangements =30*720= 21600
Answer C
Question: The sum of four consecutive odd numbers is equal to the sum of 3 consecutive even numbers. Given that the middle term of the even numbers is greater than 101 and lesser than 216, how many such sequences can be formed?
A.28
B.17
C.25
D.33
Answer: A.28
Explanation: Four consecutive odd numbers: k-2, k, k+2, k+4
Three consecutive even numbers: n-2, n, n+2
k-2+k+k+2+k+4=n-2+n+n+2
4k+4=3n
4(k+1)=3n
k+1=(3/4)n
k=(3/4)n-1
All n's that's divisible by 4 will have an integral k. So, we need to find out how many such n's are available within given range:
We know,
101<n<216
104<=n<=212
Count=(212-104)/4+1=108/4+1=27+1=28
Ans: 28.
Question: hree 6 faced dice are thrown together. The probability that all the three show the same number on them is ?
A.1/39
B.1/36
C.1/32
D.1/287
Answer: B.1/36
Explanation: It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36
Answer: B
Question: Tanya prepared 4 different letters to be sent to 4 different addresses. For each letter, she prepared an envelope with its correct address. If the 4 letters are to be put into the 4 envelopes at random, what is the probability that only 1 letter will be put into the envelope with its correct address?
A.1/24
B.1/8
C.1/4
D.1/3
Answer: D.1/3
Explanation: Total # of ways of choosing envelopes=4!=24.
Only one letter in the right envelope: 4(# of envelopes)*2(# of ways possible to arrange 3 letters incorrectly in the envelopes, when one is correct)
ABCD(envelopes)
ACDB(letters)
ADBC(letters)
(When A is in the right envelope other three have only 2 possible incorrect arrangements)
As we have 4 letters, total # of ways 4*2=8
P(C=1)=8/24=1/3
Answer:D
Question: A Fruit store sells four varieties of Mangoes. A,B,C & D. IF A Costs 20% less than B, and C costs 25% less than A,and D costs 40% less than C what percent of B's cost is D?
A.40%
B.38%
C.44%
D.36%
Answer: D.36%
Explanation: Soln:-
B=100
A 20% less than B = 80
C 25% less than A = 60
D 40% less than C = 36
D is what percent of B = D/B * 100
= 36/100 * 100 = 36%
ANSWER:D
Question: In what time will a bus 200 m long cross in the road, if its speed be 72 km/hr?
A.15
B.20
C.14
D.10
Answer: D.10
Explanation: Speed = 72 * 5/18 = 20 m/sec
Time taken = 200/20 = 10 sec.
Answer:D
Question: If c is a positive integer, which of the following could NOT be the square of c?
A.5532
B.9426
C.4966
D.6415
Answer: A.5532
Explanation: A number ending in 2 cannot be a perfect square.
5532 ends in a number 2, making that the correct answer
(A) 5532
Question: The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ Rs. 26.50 per metre is Rs. 5300, what is the length of the plot in metres?
A.238
B.200
C.287
D.117
Answer: B.200
Explanation: Let length of plot = L meters, then breadth = L - 20 meters
and perimeter = 2[L + L - 20] = [4L - 40] meters
[4L - 40] * 26.50 = 5300
[4L - 40] = 5300 / 26.50 = 200
4L = 240
L = 240/4= 60 meters.
Answer: B
Question: A shopkeeper has 280 kg of apples. He sells 40% of these at 20% profit and remaining 60% at 30% profit. Find his % profit on total.
A.24%
B.25%
C.26%
D.28%
Answer: C.26%
Explanation: Total number of apples = 280
Let the cost price be x
Selling price at 20% profit = 1.2x
Selling price at 30% profit = 1.3x
Profit % = ((SP - CP)/CP)*100
Profit % = ((2/5)*280*1.2x + (3/5)*280*1.3x - 280x)/280x * 100 = (1/5*(2.4 + 3.9) - 1)*100
= (6.3 - 5)*20 = 26%
Answer: C
Question: There are 35 students in a hostel. If the no. of students increases by 7, the expenses of the mess increase by Rs.42/day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess?
A.Rs. 30
B.Rs. 35
C.Rs. 42
D.Rs. 48
Answer: C.Rs. 42
Explanation: Suppose the average join the mess , total expenditure = 35x + 42
Now, the average expenditure = (35x + 42)/ (35 + 7) = x – 1
or, 35x + 42 = 42x – 42
or, x = 12
Thus the original expenditure of the mess = 35 x 12 = Rs. 42
C
Question: A big container is 50% full with water. If 20 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container in liters?
A.80
B.90
C.100
D.110
Answer: A.80
Explanation: 20 liters is 25% of the capacity C.
20 = 0.25C
C = 80 liters.
The answer is A.
Question: If (a – b) is 15 more than (c + d) and (a + b) is 3 less than (c – d), then (a – c) is:
A.6
B.2
C.3
D.4
Answer: A.6
Explanation: (a – b) – (c + d) = 15 and (c – d) – (a + b) = 3
=> (a – c) – (b + d) = 15 and (c – a) – (b + d) = 3
=> (b + d) = (a – c) – 15 and (b + d) = (c – a) – 3
=> (a – c) – 15 = (c – a) – 3 => 2(a – c) = 12 => (a – c) = 6
ANSWER:A
Question: The simple interest accrued on an amount of Rs.49500 at he end of three is Rs.17820. What would be the compound interest accured on the same amount at teh same rate in the same period? (Round off your answer to two decimal places)
A.20043.94
B.20043.948
C.20043.93
D.20043.92
Answer: A.20043.94
Explanation: Let the rate of interest be R% p.a.
(49500)(3)(R)/100 = 17820
495R = 5940
R = 12
CI on Rs.49500 at 12% p.a. for three years
= 49500{[1 + 12/100]3 - 1} = 69543.936 - 49500 = Rs.20043.94
when rounded off to two decimal places.
Answer:A
Question: In Arun's opinion, his weight is greater than 65 kg but leas than 72 kg. His brother does not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all of them are correct in their estimation, what is the average of diferent probable weights of Arun ?
A.66.9 kg
B.66.5 kg
C.66.6 kg
D.86.5 kg
Answer: B.66.5 kg
Explanation: Let Arun's weight be X kg.
According to Arun, 65 < X < 72.
According to Arun's brother, 60 < X < 70.
According to Arun's mother, X < 68.
The values satisfying all the above conditions are 66 and 67.
Required average = (66 + 67) / 2 = 66.5 kg
Answer:B
Question: In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 30 percent, but profits were 15 percent of revenues. The profits in 1999 were what percent of the profits in 1998?
A.80%
B.105%
C.120%
D.124.2%
Answer: B.105%
Explanation: 0,105R = x/100*0.1R
Answer B
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 23 years. The present age of the husband is
A.40
B.34
C.45
D.55
Answer: B.34
Explanation: Explanation:
Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) years = 90 years.
Sum of the present ages of wife and child = (23 * 2 + 5 * 2) years = 56 years.
Husband's present age = (90 - 56) years = 34 years
Option B
Question: If the price has fallen by 13% what percent of its consumption be: increased so that the expenditure may be the same as before?
A.11 1/8%
B.11 1/5%
C.14 82/87%
D.14 7/9%
Answer: C.14 82/87%
Explanation: 100 â€“ 13 = 87
87------13
100------? => 14 82/87%
Answer: C
Question: Find the probability that the number drawn is a multiple of 6 and 8.
A.3/50
B.2/25
C.1/50
D.1/25
Answer: D.1/25
Explanation: From 1 to 100 there are 4 numbers which are multiples of 6 and 8. (i.e, multiples of 24)
Therefore, required probability = 4 /100
= 1/25
ANSWER:D
Question: The average of first eight prime numbers:
A.5.6
B.11.2
C.9.625
D.6.3
Answer: C.9.625
Explanation: Explanation:
The first eight prime numbers is 2, 3, 5, 7, 11, 13, 17, 19
Average = 77/8 = 9.625
Answer: Option C
Question: A right triangle has sides of a, b, and 12, respectively, where a and b are both integers. What is the value of (a + b)?
A.144
B.146
C.148
D.150
Answer: A.144
Explanation: LET a= hypotenuse , b =base ,12 = perpendicular . therefore a^2 -b^2 =12^2 or (a+b)(a-b) = 144
a+b =144/a-b ' a-b cannot be zero ..therefore a+ b =144 where a-b is equal to 1
A
Question: Carol spends 1/4 of her savings on a stereo and 2/3 less than she spent on the stereo for a television. What fraction of her savings did she spend on the stereo and television?
A.1/4
B.2/7
C.5/12
D.1/2
Answer: A.1/4
Explanation: Total Savings = S
Amount spent on stereo = (1/4)S
Amount spent on television = (1-2/3)(1/4)S = (1/3)*(1/4)*S = (1/12)S
(Stereo + TV)/Total Savings = S(1/4 + 1/12)/S = 1/4
Answer: A
Question: A milkman sells his milk at CP but he mixes it with water and thereby gains 25%. What is the % of water in the mixture?
A.10%
B.15%
C.20%
D.30%
Answer: C.20%
Explanation: Here Gain= 25%
error = quantity of water he mixes in the milk =x
true value = true quantity of milk = T
So the formula becomes, 25=x(T−x)×100
⇒1=x(T−x)×4⇒T−x=4x⇒T=5x
Percentage of water in the mixture
=xT×100=x5x×100=15×100=20%
C
Question: A person want to give his money of $5400 to his 3 children A,B,C in the ratio 2:3:4. What is the B's share?
A.$2000
B.$1800
C.$2500
D.$1500
Answer: B.$1800
Explanation: B's share = 5400*3/9 = $1800
Answer is B
Question: Find the middle one when The sum of five consecutive even numbers is 75?
A.16
B.11
C.17
D.16
Answer: A.16
Explanation: Let the first number be n
Let the second number be n + 2
Let the third number be n + 4
Let the third number be n + 6
Let the third number be n + 8
n + n + 2 + n + 4 + n + 6 + n + 8= 75
Combine like terms:
5n + 20 = 75
5n = 75 - 20
5n = 55
5n = 55
n = 11
n + 2 = 13
n + 4 = 16
n + 6 = 17
n + 8 = 19
The middle number is 16
Answer: A
Question: There is food for 760 men for 22 days. How many more men should join after two days so that the same food may last for 10 days more?
A.220
B.760
C.990
D.880
Answer: B.760
Explanation: 760 ---- 22
760 ---- 20
x ----- 10
x*10 = 760*20
x = 1520
760
-------
760
Answer: B
Question: Tough and Tricky questions: Remainders.
1^1 + 2^2 + 3^3 + ... +8^8 is divided by 5. What is the remainder?
A.0
B.1
C.2
D.3
Answer: D.3
Explanation: a number is divisible by 5, if its last digit is divisible by 5
let's look into the sum of last digits of each term of the given expression
1^1=1
2^2=4
3^3=7
4^4=6
5^5=5
6^6=6
7^7=3
8^8=6
adding all these numbers we get 38 which gives a remainder of 3 when divided by 5. so answer must be 2.
bunuel, can you please confirm the answer of this question.
Yes, the OA is C. Clicked the wrong button when posting. Edited. Thank you.
D
Question: Rick deposited $600 to his bank account using $5 and $15 dollar bills only. If Rick came to the bank with 70 bills and left with 10 bills only, how many $15 dollar billsმ did he deposit?
A.5.
B.25.
C.30.
D.55.
Answer: C.30.
Explanation: 5x+15y=600 --1
x+y=60 ---2
multiply eq 2 with 5 and subtract from eq 1
5x+15y=600
5x+5y=300
10y= 300
y=30 and x = 30
therefore $15 bills = 30
Answer C
Question: A man goes from A to B at a speed of 15 kmph and comes back to A at a speed of 12 kmph. Find his average speed for the entire journey?
A.13.7 kmph
B.13.3 kmph
C.13.8 kmph
D.13.9 kmph
Answer: B.13.3 kmph
Explanation: Distance from A and B be 'd'
Average Speed = total distance/total time
Average Speed = (2d)/[(d/15) + (d/12]
= (2d)/[9d/60) => 13.3 kmph.
Answer:B
Question: There are 3 teams each with 4 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?
A.50
B.23
C.48
D.28
Answer: C.48
Explanation: There are altogether three arrangements, which are we can select two members each from team A and B, each from team A and C, and each from team B and C. For each arrangement, there are altogether 16 possibilities (4*4) since each team has 4 players. So there are a total of 48 possibilities (16*3). I hope this method is easier for you to understand.
Question: In a kilometer race, A beats B by 40 meters or 10 seconds. What time does A take to complete the race?
A.167 sec
B.190 sec
C.176 sec
D.240 sec
Answer: D.240 sec
Explanation: Time taken by B run 1000 meters
= (1000 * 10)/40 = 250 sec.
Time taken by A = 250 - 10
= 240 sec.
Answer:D
Question: A rope of which a calf is tied is increased from 12 m to 21 m, how much additional grassy ground shall it graze?
A.933.4
B.1219
C.1210
D.1212
Answer: A.933.4
Explanation: π (212 – 122) = 933.4
Answer:A
Question: Find out the C.I on Rs.4000 at 4% p.a. compound half-yearly for 1 1/2 years.
A.A)Rs.242.83
B.B)Rs.243.83
C.C)Rs.244.83
D.D)Rs.245.83
Answer: C.C)Rs.244.83
Explanation: A = 4000(51/50)3
= 4244.83
4000
-----------
244.83
ANSWER:C
Question: One night a certain hotel rented 1/2 of its rooms, including 2/3 of their air conditioned rooms. If 3/5 of its rooms were air conditioned, what percent of the rooms that were not rented were air conditioned?
A.25%
B.30%
C.35%
D.40%
Answer: D.40%
Explanation: The rooms which were not rented is 1/2
The AC rooms which were not rented is (1/3)*(3/5) = 1/5
The percentage of unrented rooms which were AC rooms is (1/5) / (1/2) = 2/5 = 40%
The answer is D.
Question: Find the time between 5 and 6 o'clock when the two hands of clock are 6 minutes spaces apart.
A.3 2/11 minutes past 5 o'clock
B.6 6/11 minutes past 5 o'clock
C.20 8/11 minutes past 5 o'clock
D.4 2/11 minutes past 5 o'clock
Answer: B.6 6/11 minutes past 5 o'clock
Explanation: minute hand should travel 19 mis or 31 mins to have gape of 6 mins...so in case of 19 mins (19 60/55) and in case of 31 mins (31*60/55) will be the ans...for above question c is ans...i.e 20 8/11
ANSWER:B
Question: An unbiased die is tossed. Find the probability of getting a multiple of 1
A.A)1/3
B.B)2/5
C.C)1/2
D.D)2/3
Answer: C.C)1/2
Explanation: Here S = {1,2,3,4,5,6}
E = event of getting a multiple of 2
E = {2,4,6}
P(E) = 3/6 = 1/2
Answer is C
Question: lexus car agency has 162 cars.he sold some cars at 9% profit and rest at 36% profit thus he gains 17% on the sale of all his cars.the no. of cars sold at 36% profit is?
A.36
B.37
C.48
D.39
Answer: C.48
Explanation: ratio of 36% profit cars to 9% profit cars = 8:19
so no. of cars sold at 36% profit = 162*8/27= 48 cars
ANSWER:C
Question: Guy drives 60 miles to attend a meeting. Halfway through, he increases his speed so that his average speed on the second half is 16 miles per hour faster than the average speed on the first half. His average speed for the entire trip is 30 miles per hour. Guy drives on average how many miles per hour during the first half of the way?
A.12
B.14
C.16
D.24
Answer: D.24
Explanation: Let x be the average speed for 1st half of the distance. Then the average speed for 2nd half of the distance will be x+16
avg speed= total distance/total time
30 = 60/{(30/x) + (30/(x+16))}
Solving we get
x^2-14x-240=0
x= -10 or 24
x cant be negative hence x= 24
ANSWER:D
Question: A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have?
A.50
B.78
C.267
D.29
Answer: A.50
Explanation: A+B+C = 500
A+C = 200
B+C = 350
--------------
A+B+2C = 550
A+B+C = 500
----------------
C = 50
Answer: A
Question: What is the greatest number of three digits which is divisible by 10, 20, 30 ?
A.960
B.970
C.980
D.990
Answer: A.960
Explanation: Greatest number of 3 digits = 999
LCM of 10,20,30 = 60
999 ÷ 60= 16, remainder = 39
Hence, greatest number of four digits which is divisible by 10,20,30
= 999 - 39 = 960
answer : A
Question: If 50% of 3/5 of a number is 36, then the number is?
A.120
B.100
C.75
D.90
Answer: A.120
Explanation: Let the number be x. Then 50% of 3/5 of x=36
50/100*3/5*x=36
x=(36*10/3)=120
Required number=120.
Correct Option: A
Question: $500 will become $1000 in 4 years find the rate of interest?
A.A)10%
B.B)20%
C.C)25%
D.D)30%
Answer: C.C)25%
Explanation: SI = simple interest = A-P = 1000-500 = $500
R = 100SI/PT = 100*500/500*4 =25%
Answer is C
Question: If a is positive and a4-62a2+1 = 0, find the value of a3+(1/a3)
A.424
B.648
C.392
D.488
Answer: D.488
Explanation: Explanation :
Given a4-62a2+1 = 0
Dividing by a2
a2-62+(1/a2) = 0 => a2+(1/a2) = 62
=> a2+(1/a2)+2 = 64 => (a+(1/a))2 = 64
Hence a+(1/a) = 8 or -8
Since a>0 so a+(1/a) = 8
Now (a+(1/a))3 = a3+(1/a3)+3(a+(1/a))
=> 512 = a3+(1/a3)+24
=> a3+(1/a3) = 488
Answer : D
Question: If (x^2 + 2x - 9)/2 ≤ x -4, then x could be represented by which of the following?
A.− 4 ≤ x ≤ − 3
B.− 4 ≤ x ≤ 3
C.-1 ≤ x ≤ 1
D.− 3 ≤ x ≤ 4
Answer: C.-1 ≤ x ≤ 1
Explanation: IMO C is correct answer
solving through eqautions
x^2 +2x-9<= 2x-8
(x+1)(x-1)<=0
Question: How long will it take a train travelling at 78kmph to pass an electric pole if the train is 110 meters in lenght?
A.2.07
B.3.07
C.5.07
D.4.07
Answer: C.5.07
Explanation: Sol.
Speed = [ 78x5/18] m/sec =21.7 m / sec.
Time taken = (110/21.7)sec =5.07 sec.
Answer C
Question: One fast typist type some matter in 5hrs and another slow typist type the same matter in 8hrs. If both do combine in how much time they will take to finish.
A.10 hr 4 mins
B.1 hr 4 mins
C.2 hr 4 mins
D.3 hr 4 mins
Answer: D.3 hr 4 mins
Explanation: Fast's 1 hr work = 1/5
slow's 1 hr work = 1/8
1/5 + 1/8 = 13/40
they ll finish in 40/13hrs= 3 1/13 ==> 3 hr 4 mins
ANSWER:D
Question: The ratio of three numbers is 5:3:4 and their sum is 108. The second number of the three numbers is?
A.24
B.27
C.29
D.32
Answer: B.27
Explanation: 5:3:4
Total parts = 12
12 parts --> 108
1 part ---->9
The second number of the three numbers is = 3
3 parts ----> 27
B
Question: A number consists of 3 digits whose sum is 10. The middle digit is equal to the sum of the other two and the number will be increased by 99 if its digits are reversed. The number is:
A.251
B.253
C.255
D.257
Answer: B.253
Explanation: Let the middle digit be x.
Then, 2x = 10 or x = 5. So, the number is either 253 or 352.
Since the number increases on reversing the digits, so the hundred's digits is smaller than the unit's digit.
Hence, required number = 253.
Option B
Question: From below option 22 is divisible by which one?
A.A)3
B.B)4
C.C)11
D.D)9
Answer: C.C)11
Explanation: 22/11 = 2
C