RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder?
A.1108
B.1683
C.2007
D.3363
Answer: B.1683
Explanation: LCM of 5, 6, 7 and 8 = 840
Hence the number can be written in the form (840k + 3) which is divisible by 9.
If k = 1, number = (840 × 1) + 3 = 843 which is not divisible by 9.
If k = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9.
Hence 1683 is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.
ANSWER:B
Question: A library has an average of 400 books on Sundays and 240 on other days. The average number of books per day in a month of 30 days beginning with a Sunday is?
A.50
B.55.5
C.65
D.75.5
Answer: D.75.5
Explanation: Since the month begins with a Sunday, to there will be five Sundays in the month.
Required average
= (400 x 5 + 240 x 25)/30
=	8550
30
= 75.5
D
Question: complete the numerical series with the correct number
5+3+4=152032
9+2+9=188197
8+6+7=485698
5+4+4=202036
9+5+2= ?
A.451858
B.454586
C.454585
D.454386
Answer: A.451858
Explanation: 9+5+2=451858
Answer : A
Question: Chandu started a business investing Rs. 70,000. Firoz joined him after 6 months with an amount of Rs. 1,05,000 and Pavan joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Chandu, Firoz and Pavan respectively, 3 years after Chandu started the business ?
A.12:15:16
B.13:16:21
C.16:15:12
D.10:14:19
Answer: A.12:15:16
Explanation: Explanation :
Chandu : Firoz : Pavan = (70000*36) : (105000*30) : (140000*24)
= 12 : 15 : 16
Answer : A
Question: A card game called “high-low” divides a deck of 52 playing cards into 2 types, “high” cards and “low” cards. There are an equal number of “high” cards and “low” cards in the deck and “high” cards are worth 2 points, while “low” cards are worth 1 point. If you draw cards one at a time, how many ways can you draw “high” and “low” cards to earn 4 points if you must draw exactly 2 “low” cards?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: Great question Ravih. This is a permutations problem (order matters) with repeating elements. Given thatlowcards are worth 1 pt andhigh cards2 pts, and you must draw 3 low cards, we know that you must also draw 1 high card. The formula for permutations problems with repeating elements isN!/A!B!...where N represents the number of elements in the group and A, B, etc. represent the number of times that repeating elements are repeated. Here there are 4 elements and thelowcard is repeated 3 times. As a result, the formula is:
3!/2! which represents (3*2*1)/(2*1) which simplifies to just 4, giving you answer C.
Question: six friends met for lunch at an expensive restaurant, and everyone decided to contribute equally to the total bill of $420. If one of the friends had a coupon for 20% off the total bill, and if each friend still contributed equally after the coupon was applied to the bill, how much did each friend pay?
A.$90
B.$70
C.$56
D.$37
Answer: C.$56
Explanation: 420 * 0,20 = 84
420 - 84 = 336
336 /6 = 56
Answer C
Question: The average of six number is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. what is the average of the remaining two number ?
A.4.5
B.4.6
C.4.7
D.4.8
Answer: B.4.6
Explanation: solution:
Sum of the remaining two numbers = (3.95 × 6) - [(3.4 × 2) + (3.85 ×2)]
=23.70 -(6.8 + 7.7) = 23.70 - 14.5 = 9.20.
∴ Required average =9.2/2 = 4.6 Answer B
Question: An art gallery owner is hanging paintings for a new show. Of the six paintings she has to choose from, she can only hang three on the main wall of the gallery. Assuming that she hangs as many as possible on that wall, in how many ways can she arrange the paintings?
A.18
B.30
C.64
D.120
Answer: D.120
Explanation: Arrangement means permutations questions..
6P3 = 6!/3! = 120
.
ANS option D is correct answer..
Question: Find the invalid no.from the following series 13, 18, 25, 30, 37, 40
A.13
B.18
C.40
D.25
Answer: C.40
Explanation: The differences between two successive terms from the beginning are 7, 5, 7, 5, 7, 5. So, 40 is wrong.
C
Question: A computer can perform y calculations in s seconds. How many minutes will it take the computer to perform k calculations?
A.60ks/y
B.ks/y
C.ks/60y
D.60y/ks
Answer: C.ks/60y
Explanation: As 'thick' as this question might look, it's actually a fairly straight-forward Rate question and can be solved by TESTing VALUES.
We're told that a computer can perform y calculations in S seconds.
Let's TEST....
y = 2
S = 3
2 calculations every 3 seconds =
40 calculations every 1 minute
We're asked how many MINUTES it will take to perform K calculations.
Since we already know that the computer can perform 40 calculations in 1 minute, let's TEST...
K = 80
So we're looking for an answer that = 2 when y = 2, S = 3 and K = 80
Answer A: 60KS/y = 60(80)(3)/2 = 7200 This is NOT a match
Answer B: KS/y = (80)(3)/2 = 120 This is NOT a match
Answer C: KS/60y = (80)(3)/(60)(2) = 2 This IS a match
Answer D: 60y/KS = 60(2)/(80)(3) = 1/2 This is NOT a match
Answer E: K/60yS = 80/(60)(2)(3) = a fraction. This is NOT a match
C
Question: 9000 + 16 2/3 % of ? = 10500
A.2387
B.2888
C.9000
D.2837
Answer: C.9000
Explanation: Explanation:
9000 + 16 2/3 % of ? = 10500 => 9000 + 50/3 % of ? = 10500
50/(3 * 100) of ? = 1500 => ? = 1500 * 6
? = 9000
Answer: C
Question: In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/6 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented?
A.50
B.70
C.10
D.105
Answer: C.10
Explanation: Rented = 4/7*490 = 280.
Rented two-bedroom = 6/7*280 = 240;
Rented one-bedroom = 1/7*280 = 40 (or 280-240=40).
Rented one-bedroom units are 1/5 of all one-bedroom: 1/6*{All one bedroom} = 40 --> {All one-bedroom} = 240.
{All two-bedroom} = 490 - 240 = 250.
Two-bedroom not rented = 250 - 240 = 10.
Answer: C.
Question: If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?
A.22 1/7 %
B.22 3/2 %
C.22 1/8 %
D.22 1/2 %
Answer: D.22 1/2 %
Explanation: 9 = (1*40*R)/100
R = 22 1/2 %
Answer:D
Question: What will come in place of the x in the following Number series? 6, 12, 21, x , 48
A.33
B.38
C.45
D.49
Answer: A.33
Explanation: (A)
The pattern is + 6, + 9, + 12, +15 ………..
So the missing term is = 21 + 12 = 33
Question: For what values of k will the pair of equations 4(3x + 4y) = 48 and kx + 12y = 30 does not have a unique solution?
A.12
B.9
C.3
D.7.5
Answer: B.9
Explanation: we have 2 equations
1. 4(3x + 4y) = 48 --> 3x + 4y = 12 -- > 9x + 12y = 36
2. kx + 12y = 30
substract 1-2, we get (9-K)x = 6
i.e. x = 6/(9-k)
then, by looking at options, we get some value of x except for B. When we put k=9, x becomes 6/0 and hence answer is B
Question: If it takes a tub 3 minutes to drain 6/7 of its content, how much more time will it take for the tub to be empty?
A.30 seconds
B.1 minute, 12 seconds
C.1 minute, 50 seconds
D.2 minutes, 14 seconds
Answer: A.30 seconds
Explanation: If 6/7 of tub's content is drained 1/7 th of tub still needs to be drained.
If it takes 3 minutes to drain 6/7 th of tub it takes 3*(7/6) minutes to drain the entire tub and 3*(7/6)*(1/7) min to drain 1/7 th of the tub which is 6/5 minutes or 0.5 minutes or 30 seconds
So answer is A
Question: If a man lost 4% by selling oranges at the rate of 12 a rupee at how many a rupee must he sell them to gain 44%?
A.6
B.8
C.6
D.5
Answer: B.8
Explanation: 96% ---- 12
144% ---- ?
96/144 * 12 = 8
Answer:B
Question: In how many ways can the letters of word "EDUCATION" be arranged such that NO two vowels appear together?
A.9!
B.5!*4!
C.5!*5!
D.5!*4!*2!
Answer: B.5!*4!
Explanation: No 2 vowels together = the only arrangement possible will be V C V C V C V C V (with V=vowel, C=consonant). This is true as we have 5 vowels and 4 consonants and any other combination will force us to pair 2 vowels together.
Thus, the number of arrangements possible : 5 *4 *4 *3 *3 *2 *2*1 = 5!*4! ----> B is the correct answer.
Question: A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
A.22 1/9 kmph
B.27 1/2 kmph
C.42 1/2 kmph
D.22 1/2 kmph
Answer: D.22 1/2 kmph
Explanation: 100 --- 10 DS = 10
? ---- 1
75 ---- 15 US = 5
? ----- 1 S = (10 - 5)/2
= 22 ½ kmph
Answer: D
Question: In a primary school, 10% of students are below 11 years of age. The number of students above 11 years of age is 3/4 of the number of students of 11 years of age which is 36. What is the total number of students in the school?
A.72
B.80
C.70
D.150
Answer: C.70
Explanation: Explanation :
Let the number of students be x.
Then, Number of students above 11 years of age = (100 - 10)% of x = 90% of x.
90% of x = 36 + 3/4 of 36
90x/100 = 63
x = 70.
Answer : C
Question: Sandy is younger than Molly by 10 years. If their ages are in the respective ratio of 7:9, how old is Molly?
A.27
B.36
C.45
D.54
Answer: C.45
Explanation: S = M - 10
S / M = 7/9
9S = 7M
9(M-10) = 7M
M = 45
The answer is C.
Question: How many distinct ponts do the hour and minute hands of a clock meet on its dual between 6AM and 6PM of certain day.
A.14 times
B.13 times
C.12 times
D.11 times
Answer: D.11 times
Explanation: in 12 hours min. & hr. hand meet 11 times at different times
ANSWER:D
Question: A pipe can fill a cistern in 20 minutes whereas the cistern when fill can be emptied by a leak in 28 minutes. When both pipes are opened, find when the cistern will be full?
A.17 minutes
B.87 minutes
C.70 minutes
D.27 minutes
Answer: C.70 minutes
Explanation: 1/20 - 1/28 = 1/70
70 minutes
Answer:C
Question: A train 400 m long is running at a speed of 54 km/hr. If it crosses a tunnel in 2 minutes. Then what is the length of tunnel?
A.1200 m
B.1400 m
C.1600 m
D.1800 m
Answer: B.1400 m
Explanation: Speed of train in m/sec = (speed of train in km/hr) x 5/18
∴ speed of train in m/sec = 54 x 5/18 = 15 m/sec
Time taken to cross the tunnel = 2 minutes = 120 sec
Therefore, Total length covered by train in crossing the tunnel = Speed of train x Time taken to cross the tunnel
= 15 m/sec x 120 sec = 1800 m
Total length covered by train in crossing the tunnel = Length of train + Length of tunnel
Given, Length of train =400m and
Calculated above, Length covered by train in crossing the tunnel = 1800 m
Therefore, Length of tunnel = 1800m- 400m = 1400m
CORRECT ANSWER : Option: B
Question: (935421 x 625) = ?
A.542622125
B.584632125
C.544638125
D.584638125
Answer: D.584638125
Explanation: Explanation :
935421 × 625 = 935421 × 54 = 935421 × (10/2)4 = (935421 × 10000)/16 = 584638125. Answer : Option D
Question: What is the probability of getting a sum 9 from two throws of a dice?
A.1/6
B.1/8
C.1/9
D.1/12
Answer: C.1/9
Explanation: In two throws of a dice, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
P(E) =n(E)/n(S)=4/36=1/9.
Answer:C
Question: Pointing a photograph X said to his friend Y, "She is the only daughter of the father of my mother." How X is related to the person of photograph?
A.Daughter
B.Son
C.Nephew
D.Cannot be decided
Answer: C.Nephew
Explanation: since the lady is daughter of his grandfather ...so she must be sister of his mother....that means he is the nephew.
ANSWER:C
Question: Sandy had $231 left after spending 30% of the money she took for shopping. How much money did Sandy take along with her?
A.$270
B.$290
C.$310
D.$330
Answer: D.$330
Explanation: Let the money Sandy took for shopping be x.
0.7x = 231
x = 330
The answer is D.
Question: In the first 5 overs of a cricket game, the run rate was only 2.1. What should be the rate in the remaining 30 overs to reach the target of 200 runs?
A.6.25
B.6.28
C.6.31
D.6.19
Answer: C.6.31
Explanation: Required run rate
= [200 - (2.1 * 5)]/30
= 189.50/30
= 6.31
Answer:C
Question: By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?
A.38029
B.38000
C.38098
D.38028
Answer: B.38000
Explanation: CP + CP/8 = 45000
CP = 40000
SP = 40000*(95/100) = 38000
Answer: B
Question: A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 6 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
A.17.5
B.7.4
C.7.9
D.12.0
Answer: D.12.0
Explanation: Net part filled in 1 hour = (1/4 - 1/6) = 1/12
The cistern will be filled in 12/1 hrs i.e., 12 hrs.Answer: D
Question: Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 11.67and for 36kgs of Apples is 12.48 then the cost of first 10 kgs of Apples is
A.3.69
B.3.66
C.3.6
D.3.62
Answer: D.3.62
Explanation: Ans: By framing equations we get
30L+3Q=11.67
30L+6Q=12.48
Eliminate Q by multiplying the first equation by 2 and subtracting second equation from the first
Then we get L = 0.362
Cost of 10 kgs of apples = 0.362 x 10 = 3.62
Answer:D
Question: The sum of the present ages of father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
A.12 years
B.11 years
C.10years
D.20 years
Answer: D.20 years
Explanation: Answer: Option D
Let the present ages of son and father be x and (60 - x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
6x = 84 => x = 14
Son's age after 6 years = (x + 6) = 20 years.
Question: What is the remainder when 43*49 is divided by 8?
A. 1
B. 3
C. 4
D. 5
Answer: B. 3
Explanation: we can make use of the rule :
Remainder of { (a * b)/n}} = Remainder of (a/n) * Remainder of (b/n)
Here
Remainder of { 43 * 49)/8}} = Remainder of (43/8) * Remainder of (49/8) = 3 * 1 = 3
Answer :B
Question: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is?
A.12
B.77
C.26
D.29
Answer: A.12
Explanation: S = 1
M = x
DS = x + 1
US = x - 1
35/(x + 1) + 35/(x - 1) = 12
x = 6.Answer: A
Question: Mark is playing poker at a casino. Mark starts playing with 110 chips, 20% of which are $100 chips and 80% of which are $20 chips. For his first bet, Mark places chips, 10% of which are $100 chips, in the center of the table. If 70% of Mark's remaining chips are $20 chips, how much money did Mark bet?
A.$1,960
B.$1,740
C.$1,540
D.$3,080
Answer: C.$1,540
Explanation: Total chips 110
20% of $100 chips = 22 chips * $100 = $2,200
80% of $20 chips = 88 chips * $20 = $1,760
If x is the number of chips bet and y is the amount of chips remaining:
x + y = 110
y = 110 - x ~ (1)
[First round bet] + [Second round bet] = $2,200 + $1,760
[0.1x * $100 + 0.9x * $20] + [0.3y * $100 + 0.7y * $20] = $3,960
10x + 18x + 30y + 14y = 3960
28x + 44y = 3960 ~ (2)
Substitute (1) into (2) to solve for x:
28x + 44(110 - x) = 3960
28x + 4840 - 44x = 3960
16x = 880
x = 55
Substituting x:
[First round bet] = [0.1x * $100 + 0.9x * $20] = 0.1(55)($100)+0.9(55)($20) = $550 + $990 = $1,540
Answer is C
Question: How many zeroes are there at the end of the number N, if N = 70! + 140! ?
A.8
B.12
C.16
D.20
Answer: C.16
Explanation: The number of zeroes at the end of 70! will be less than the number of zeroes at the end of 140!
Hence it is sufficient to calculate the number of zeroes at the end of 70!
The number of zeroes = [70/5] + [70/25] + [70/125] = 14 + 2 + 0 = 16
The answer is C.
Question: The area of a circular field is 17.56 hectares. Find the cost of fencing it at the rate of Rs. 7 per metre approximately
A.4457
B.10400
C.4235
D.4547
Answer: B.10400
Explanation: Explanation:
Area = (17.56 x 10000) m2= 175600 m2.
ΠR2 = 175600 ⇔ (R)2 = (175600 x (7/22)) ⇔ R = 236.37 m.
Circumference = 2ΠR = (2 x (22/7) x 236.37) m =1485.78 m.
Cost of fencing = Rs. (1485.78 x 7) = Rs. 10400.
Answer: Option B
Question: If the sum of two numbers is 12 and the sum of their squares is 124, then the product of the numbers is
A.10
B.44
C.80
D.88
Answer: A.10
Explanation: Sol.
Let the numbers be x and y.
Then, (x+y) = 12 and x2 + y2 = 124.
Now, 2xy = (x+y)2 - (x2 + y2)
= (12)2 - 124 = 144 - 124 = 20
xy = 10.
Answer A
Question: The average expenditure of a labourer for 6 months was 70 and he fell into debt. In the next 4 months by reducing his monthly expenses to 60 he not only cleared off his debt but also saved 30. His monthly income i
A.69
B.72
C.75
D.78
Answer: A.69
Explanation: Income of 6 months = (6 × 70) – debt
= 420 – debt
Income of the man for next 4 months
= 4 × 60 + debt + 30
= 270 + debt
∴ Income of 10 months = 690
Average monthly income = 690 ÷ 10 = 69
Answer A
Question: In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?
A.5/21
B.5/22
C.5/29
D.5/27
Answer: A.5/21
Explanation: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)
As remaining person can be any one among three couples left.
Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅
= (10 * 6)/252
= 5/21
Answer: A
Question: Laya finished 2/3 of a book. She calculated that she finished 50 more pages than she has yet to read. How long is her book?
A.A)150
B.B)180
C.C)130
D.D)90
Answer: A.A)150
Explanation: Let x be the total number of pages in the book, then she finished 2/3*x pages.
Then she has x−2/3*x=1/3*x pages left.
2/3*x−1/3*x=50
1/3*x=50
x=150
So the book is 150 pages long.
Answer is A.
Question: A dealer purchases 15 articles for Rs. 25 and sells 12 articles for Rs. 30. Find the profit percentage?
A.59
B.50
C.56
D.51
Answer: B.50
Explanation: L.C.M of 15 and 12 = 60
CP of 60 articles = Rs. 100 (25 * 4)
SP of 60 articles = Rs. 150 (30 * 5)
Profit percentage = (150 - 100)/100 * 100 = 50%.AnswerB
Question: Simplify 1235 * 9999
A.145628
B.122265
C.428589
D.864597
Answer: B.122265
Explanation: Explanation:
Although it is a simple question, but the trick is to save time in solving this.
Rather than multiplying it we can do as follows:
1235 * (100 - 1) = 123500 - 1235= 122265
Answer: Option B
Question: Car A runs at the speed of 50 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 70 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B?
A.3 : 7
B.4 : 9
C.10 : 7
D.5 : 7
Answer: C.10 : 7
Explanation: Car A travels 50 × 8 = 400 km
Car B travels 70 × 4 = 280 km
The ratio is 400 : 280 = 40 : 28 = 10 : 7
The answer is C.
Question: In a box, there are 6 red, 3 blue and 56 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?
A.2/3
B.8/21
C.6/14
D.9/22
Answer: C.6/14
Explanation: Explanation:
Total number of balls = (6 + 3 + 5) = 14
Let E = event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.
Therefore, n(E) = 6.
P(E) = 6/14.
Answer: Option C
Question: The length and width of a rectangle are integer values. What is the area of the smallest such rectangle that can be inscribed in a circle whose radius is also an integer
A. 12
B. 45
C. 36
D. 48
Answer: B. 45
Explanation: If we consider all pythagorean triplets with integral values, we have the following results:-
(3,4,5),(6,8,10)........
The diameter of the circle is 5 in the 1st case and 10 in the 2nd.
But the question says that radius of the circle is also an integer hence the 1st triplet will be ruled out.
We are left with the 2nd triplet where radius of the circle=5,
Hence the sides of the rectangle are 6 and 8 making the area =45.
B
Question: one year before the age of pramila was four times than her daughter swati.after 6 years the age of pramila will be 24 year greater than the age of swati.then calculate the ratio of ages of pramila and swati?
A.5:3
B.16:3
C.11:3
D.11:5
Answer: C.11:3
Explanation: let 1 year before age of swati=x years and age of pramila =4x years
swati present age=(x+1) and pramila present age=(4x+1)
after 6 year age of swati=(x+7),age of pramila=(4x+7)
so,4x+7-(x+7)=24,3x=24,x=8.
ratio=(4x+7):(x+1)=33:9=11:3
answer C
Question: Abhay’s age after six years will be three-seventh of his fathers age. Ten years ago the ratio of their ages was 1 : 5. What is Abhay’s father's age at present?
A.52 years
B.48 years
C.50 years
D.54 years
Answer: C.50 years
Explanation: Let the ages of Abhay and his father 10 years ago be x and 5x years respectively. Then,
Abhay's age after 6 years = (x + 10) + 6 = (x + 16) years.
Father's age after 6 years = (5x + 10) + 6 = (5x + 16) years.
(x + 16) = 3 (5x + 16)
__
7
7(x + 16) = 3 (5x + 16)
7x + 112 = 15x + 48
8x = 64
x = 8.
hence, Abhay's father's present age = (5x + 10) = 50 years.
Answer is C.
Question: A 300-metre-long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
A.320 metres
B.650 metres
C.350 metres
D.Data inadequate
Answer: C.350 metres
Explanation: When a train crosses a platform, it crosses a distance equal to the sum of the length of the platform and that of the train. But when a train crosses a signal pole, it crosses the distance equal to its length only.
Here, time taken by the train to cross a signal pole = 18 seconds
Hence, speed of the train = 300⁄18 m/sec
The train takes 21 = (39 – 18) seconds extra in order to cross the platform.
Hence, length of platform = 21×300/18=350m
Answer C
Question: If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 5:7 then find the largest number?
A.20
B.25
C.40
D.44
Answer: C.40
Explanation: 2:3
2x + 10 : 3x + 10 = 5 : 7
7[2x + 10] = 5[3x + 10]
14x + 70 = 15x + 50
15x - 14x = 70 - 50
x = 20
Then the first number is = 2
2x = 40
Short cut method:
a:b = 2:3
c:d = 5:7
1.Cross multiplication with both ratios
a * d ~ b * c = 2 * 7 ~ 3 * 5 = 14 ~ 15 = 1
2. If 10 is added both the number means 10 * 5 = 50 and 10 * 7 = 70,
Then 50 ~ 70 = 20
===> 1 -----> 20
===> 2 -----> 40 (Answer is = 40)
C
Question: A man buys 25 shares in company which pays 9 % dividend. The
money invested is such that it gives 10 % on investment. At what price did he buy the shares?
A.25
B.22.5
C.23
D.24
Answer: B.22.5
Explanation: Suppose he buys each share for $ x.
Then, [25*(9/100)] = [x*(10/100)] or x = $ 22.50.
Cost of each share = $ 22.50.
Answer B.
Question: In a survey conducted to find out the readership of three Newspapers A,B and C, it was found that the number of newspaper A is at least 20 and at most 40. The number of people who read newspaper B is at least 50 and at most 70. The number of people who read newspaper C is at least 70 and at most 83. It was also found that 6 people read all three newspapers. Find the minimum number of people who read both A and B but not C.
A.A)1
B.B)2
C.C)3
D.D)0
Answer: B.B)2
Explanation: I wish I could draw a diagram to show you but by giving you number A and B, it might help a little.
A and B and C is 6 - that means A and B is at least 6. This seems trivial given the value intervals of A and B but definitely helps to think through how to minimize A and B but not C
A and B but not C = |A|-|B| - 6
So i would pick A=30 and B =50 to minimize the value to a 2. (ANS B)
Question: In how many ways 8 different tickets can be distributed between Jane and Bill if each is to receive any even number of tickets and all 8 tickets to be distributed.
A.From 2 to 6 inclusive.
B.From 98 to 102 inclusive.
C.From 122 to 126 inclusive.
D.From 128 to 132 inclusive
Answer: D.From 128 to 132 inclusive
Explanation: Possibilities
J 8 6 4 2 0
B 0 2 4 6 8
# of ways 8C8 8C6 8C4 8C2 8C0
1+28+70+28+1 = 128 Answer is D.
Question: At a dinner party 2 people are to be seated around a circular table. Two sitting arrangements are considered different only when the positions of the people are different relative to each other.What is the total number of possible sitting arrangements or the group?
A.1
B.10
C.24
D.32
Answer: A.1
Explanation: Hi there,
You can treat this as an ordering question except thatfor a circular arrangement you need to divide by the number of spaces.So in this case:
2!/2=1
If you spin the circle to right, that doesn't count as a new arrangement. Dividing by the number of spaces takes that into consideration.
Happy Studies,
HG.
A