RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If 2 cards are selected at random from the deck of 52 cards then What is the probability of one of the selected cards will be King and other will be 10?
A deck of cards has a total of 52 cards, consisting of 4 suits; (spades(Black), hearts(Red), diamond(Red)s, and clubs(Black)); and 13 cards including 1 king, 1 queen and 1 jack in each suit
A.8/2652
B.18/2652
C.1/2652
D.12/2652
Answer: B.18/2652
Explanation: 2 possible cases:
King - 10 or 10 -King (4 kings and 4 10).
Either way,
the total probability = 2( King -10) = 2 (4/52 * 4/51) = 18/2652. B is the correct answer.
Question: sale of Rs 6835, Rs. 9927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6700 ?
A.4966
B.6191
C.2877
D.2676
Answer: B.6191
Explanation: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6700 x 6) - 34009]
= Rs. (40200 - 34009)
= Rs. 6191
Answer: B
Question: In one can of mixed nuts, 10% is peanuts. In another can of mixed nuts that is one-half the size of the first one, 40% is peanuts. If both cans are emptied into the same bowl, what percentage of the mixed nuts in the bowl is peanuts?
A.16 2/3%
B.20%
C.25%
D.33 1/3%
Answer: D.33 1/3%
Explanation: Can 1: size 1; 10% nuts
Can 2: size 0.5 and 40% nuts
(1x0.1+0.5x0.4)/1.5=33.33
D
Question: There is a lot of speculation that the economy of a country depends on how fast people spend their money in addition to how much they save. Auggie was very curious to test this theory.
Auggie spent all of his money in 5 stores. In each store, he spent Rs.4 more than one-half of what he had when he went in. How many rupees did Auggie have when he entered the first store?
A.248
B.120
C.252
D.250
Answer: A.248
Explanation: Amount left = 0.5x−4
For fifth store this is zero. So x = 8. That means he entered fifth store with 8.
Now for fourth store, amount left = 8 so 0.5x−4=8⇒ x = 24
For third store, amount left = 24 so 12x−4=24⇒ x = 56
For Second store, amount left = 56 so 0.5x−4=56⇒ x = 120
For first store, amount left = 120 so 0.5x−4=120⇒ x = 248
So he entered first store with 248.
ANSWER:A
Question: A farmer is having a total of 20 fruits (apples or oranges). He made two type packets with these fruits. All the fruits are in either apple packets of orange packets. Apple Packets contain 3 apples each and Orange packets contain 2 oranges each.
If |apple packets| < 4
Then How many packets of apples the farmer can have. When number of apple and orange packets are both positive integers above zero.
A.2
B.3
C.4
D.7
Answer: A.2
Explanation: Let us start by understand the meaning of 4 > |Number of Apples|
1) when we write |-x| this means the same as |x|.
2) Mod is very easy concept if you solve mod question by considering as a distance. when a mod is written as |x-(a)| = b, this means the distance from point 'a' (both side left and right of 'a' on number line) is b. |x-(a)| < b means the distance is between the two extreme distance(left and right side of 'a' on number line, considering the max distance is 'b' from 'a' - as per this scenario.....hence the value of 'a' must be between these two extremes. |x-(a)| > b means the distance is greater than the distance of 'b'..i.e the value of a could be anywhere more than 'b'.
Now come to the question. Let number of apple packets be ‘a’ and number of oranges packets be ‘b’. First its given |a| < 4 ==> |a-0| < 4 ==> the distance from zero is less than 4. So the point ‘a’ will be -3,-2,-1,0,1,2,3 as distance from 0 to these values is less than 4. Number of apple packets is above zero so possible values of ‘a’ left are 1,2,3.
As per the given information there are total of 20 fruits and they are in packets (3 per packet for apples and 2 per packets for oranges) so we can write it as follows:
3a + 2b = 20 ==> b = 10 – (3*a)/2. If b is an integer then ‘a’ must be divisible by 2. If we take only those values of ‘a’ that are divisible by 2 then we are left with 2 only. So there are two packets of apples. If there are two packets of apples then b = 10 – (3*2)/2 ==> b = 7. So we have 7 packets of oranges and 2 packets of apples. So A is the answer. 7 packets (2 orange each) and 2 packets of apples (3 apples each) make 20 fruits in total.
Question: A class average mark in an exam is 70. The average of students who scored below 60 is 50. The average of students who scored 60 or more is 75. If the total number of students in this class is 20, how many students scored below 60?
A.20
B.10
C.60
D.50
Answer: A.20
Explanation: Let n the number of students who scored below 60 and N the number of students who scored 60 or more. Xi the grades below 60 and Yi the grades 60 or above.
[sum(Xi) + sum(Yi)] / 20 = 70 : class average
sum(Xi) / n = 50 : average for less that 60
sum(Yi) / N = 75 : average for 60 or more
50n + 75N = 1400 : combine the above equations
n + N = 20 : total number of students
n = 4 and N = 16 : solve the above system
correct answer A
Question: A grocer stacked oranges in a pile. The bottom layer was rectangular with 4 rows of 5 oranges each. In the second layer from the bottom, each orange rested on 4 oranges from the bottom layer, and in the third layer, each orange rested on 4 oranges from the second layer. Which of the following is the maximum number of oranges that could have been in the third layer?
A. 6
B. 4
C. 3
D. 2
Answer: A. 6
Explanation: Bottom Layer = 5 x 4 = 20
IInd Layer = (5-1) x (4-1) = 12
IIIrd Layer = (4-1) x (3-1) = 6
Answer = 6 = A
Question: A person walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 8 minutes earlier. How far is the office from his house?
A.3 1/5 Km
B.4 Km
C.4 1/5 Km
D.3 2/5 Km
Answer: A.3 1/5 Km
Explanation: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 16/6
= 24/2 * 16/60
= 8 * 2/5
= 16/5 = 3 1/5 Km
A
Question: A train sets off at 2 p.m. at the speed of 70 kmph. Another train starts at 3:30 p.m. in the same direction at the rate of 85 kmph. At what time the trains will meet?
A.10.36
B.10.39
C.10.3
D.10.34
Answer: C.10.3
Explanation: D = 70 * 1 ½ = 105 km
RS = 85 – 70 = 15
T = 105/15 = 7 h
3.30 + 7 h = 10.30 p.m.
Answer:C
Question: An entry in an unshaded square is obtained by adding the entries connected to it from the row above (11 is one such number). Write the value of n ?
A.10
B.11
C.12
D.9
Answer: A.10
Explanation: see the values row wise
5 6 n 7
11 6+n 7+n
11+6+n 6+n+7+n
60
hence 11+6+n+6+n+7+n =60
n= 10
ANSWER:A
Question: The population of a town is 10000. It increases annually at the rate of 40% p.a. What will be its population after 2 years?
A.14000
B.14400
C.19600
D.14600
Answer: C.19600
Explanation: Formula :
10000 × 140/100 × 140/100 = 19600
Answer : C
Question: Length of a rectangular plot is 20mtr more than its breadth. If the cost of fencing theplot at 26.50 per meter is Rs.5300, what is the length of the plot in mtr?
A.40 m
B.60 m
C.70 m
D.77 m
Answer: B.60 m
Explanation: Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m
B
Question: How much interest will $10,000 earn in 9 months at an annual rate of 4%?
A.$300
B.$350
C.$450
D.$550
Answer: A.$300
Explanation: Soln:-
9 months = 3/4 of year;
4% = 4/100=1/25;
$10,000(principal)*1/25(interest rate)*3/4(time)=$300.
ANSWER:A
Question: A small table has a length of 12 inches and a breadth of b inches. Cubes are placed on the surface of the table so as to cover the entire surface. The maximum side of such cubes is found to be 4 inches. Also, a few such tables are arranged to form a square. The minimum length of side possible for such a square is 40 inches. Find b.
A.8
B.6
C.24
D.32
Answer: B.6
Explanation: From the info that the maximum sides of the cubes is 4, we know that the GCF of 12 (=2^2*3) andbis 4 (=2^2), sob=2^x, where x>=2.
From the second premise, we know that the LCM of 12 (2^2*3) andbis 40 (2^3*5), sob=2^3 or 2^3*5 (8 or 40).
Combining 2 premises shows the answer is B(6).
Question: The edge of a cube is 5a cm. Find its surface?
A.150a2 cm2
B.170a2 cm2
C.125a2 cm2
D.175a2 cm2
Answer: A.150a2 cm2
Explanation: 6a2 = 6 * 5a * 5a = 150a2
Answer:A
Question: Of the 65 cars on a car lot, 45 have power steering, 25 have power windows, and 17 have both power steering and power windows. How many of the cars on the lot have neither power steering nor power windows?
A. 2
B. 8
C. 12
D. 15
Answer: C. 12
Explanation: Total -Neither = All power steering + All Power Windows - Both
or 65 - Neither = 45 + 25 -17 = 53.
=> Neither = 12, hence C.
Answer : C
Question: If x, y, and z are negative integers and 3x - 3y = -3z, then which of the following statements must be true?
I.	x > y>z
II.	x > y
III. x = z
A.I and II
B.I only
C.II only
D.III only
Answer: C.II only
Explanation: 3x-3y=-3z
x-y=-z
Since z<0; -z>0
x-y>0
x>y
II correct.
We can't say much about z though;
x=-5; y=-100; z=-95
I and III incorrect.
Ans:C
Question: To create paint with a certain shade of gray, one must combine 2.116 liters of black paint with every one liter of white paint. Approximately how many liters of white paint must be combined with 350 liters of black paint to create the certain shade of gray?
A.165.4
B.176.4
C.347.1
D.694.4
Answer: A.165.4
Explanation: Since the ratio of Black to White is 2.016 to 1 this implies that Amount of Black is going to be more than (approximately double) the amount of White. This implies Option C, D and E can not be correct.
Now between A and B:
Black:White = 2.116:1 Since the ratio is more than double, the amount of White Paint should be less than half of Black Paint. B is more than half so can not be the answer, A fits the criteria hence should be the correct answer. No calculation needed whatsoever.
Question: Statements: The old order changed yielding place to new.
Assumption:
1) Change is the law of nature.
2) Discard old ideas because they are old.
A.Only conclusion I follows
B.Only conclusion II follows
C.Either I or II follows
D.Neither I nor II follows
Answer: A.Only conclusion I follows
Explanation: Clearly, I directly follows from the given statement. Also, it is mentioned that old ideas are replaced by new ones, as thinking changes with the progressing time. So, II does not follow.
A
Question: A man is 24 years older than his son.In two years, his age will be twice the age of his son.The present age of the son is :
A.22
B.25
C.45
D.32
Answer: A.22
Explanation: Let the son's present age be x years. Then, man's present age =(x+24) years.
(x+24)+2=2(x+2)
x+26=2x+4
x=22.
Answer is A
Question: The numbers in which of the following pairs do NOT have a pair of distinct prime divisors in common?
A.10 and 20
B.12 and 18
C.30 and 16
D.21 and 63
Answer: C.30 and 16
Explanation: 16 has only the prime 2 (16=2^4) in its prime factorization, so it can not have a PAIR of distinct prime divisors in common with ANY of the numbers.
The answer is C.
Question: In how many R ways can 4 white and 3 black chess pieces be arranged in a row such that they occupy alternate places? Assume that the pieces are distinct.
A.288
B.R=144
C.R=12
D.R=48
Answer: B.R=144
Explanation: 4 white chess pieces can be arranged in 4! ways and 4 black pieces can be arranged in 3 ! ways.
W_ W_W_W
Number of ways = 4!*3! = 24 * 6 = 144
Answer B
Question: If 25% of x is 20 less than 15% of 1500, then x is?
A.872
B.820
C.837
D.840
Answer: B.820
Explanation: 25% of x = x/4 ; 15% of 1500
= 15/100 * 1500 = 225
Given that, x/4 = 225 - 20
=> x/4 = 205 => x = 820.
Answer:B
Question: Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest?
A.29%p.a
B.28%p.a
C.20%p.a
D.24%p.a
Answer: C.20%p.a
Explanation: Rs.1440 - 1200
= Rs.240 is the interest on Rs.1200 for one year.
Rate of interest
= (100 * 240) / (100 * 1) = 20%p.a
Answer:C
Question: Which of the following functions does not intersect with E = 3x^2 + 2x + 1
A.E = 3x^2 + 3x + 1
B.E = 2x^2 + 3x + 1
C.E = 3x^2 + 2x + 3
D.E = 4x^2 + 2x - 3
Answer: C.E = 3x^2 + 2x + 3
Explanation: Let’s find the actual intersecting point of given function and each choice E.
A. 3x^2 + 2x + 1 = 3x^2 + 3x + 1 --> x=0
B. 3x^2 + 2x + 1 = 2x^2 + 3x + 1 --> x^2 – x =0 --> x=0 or 1
C. 3x^2 + 2x + 1 = 3x^2 + 2x + 3 --> 1=3(X) --> they don’t have any intersect.
D. 3x^2 + 2x + 1 = 4x^2 + 2x - 3 --> x^2 –4=0 --> x= 2 or -2
E. 3x^2 + 2x + 1 = x^2 + 2x + 3 --> 2x^2 –2 =0 --> x= 1 or –1.
So only choice (C) has no intersecting point. The answer is (C).
Question: Look at this series: 53, 53, 40, 40, 27, 27, ... What number should come next?
A.12
B.14
C.27
D.53
Answer: B.14
Explanation: In this series, each number is repeated, then 13 is subtracted to arrive at the next number.
Answer: B
Question: A fast food truck spends one third of its monthly budget for truck rent and half of the rest for food and beverages. What percentage of the budget does the fast food truck spend for food and beverages?
A.23.5%
B.32.5%
C.33.33%
D.30%
Answer: C.33.33%
Explanation: Spend on rent = 1/3
Spend on food and beverage= 1/2 of remaining = 1/2*2/3= 2/6=1/3
So 1/3= 33.33%
C is the answer
Question: In a apartment, 30% of the people speak English, 20% speak Hindi and 12% speak both. If a people is selected at random, what is the probability that he has speak English or Hindi?
A.1/30
B.2/30
C.19/50
D.12/90
Answer: C.19/50
Explanation: P (E) = 30 / 100 , P (H) = 20 / 100 and P (E âˆ© H) = 12 / 100 =
P (E or H) = P (E U H)
= P (E) + P (H) - P (E âˆ© H)
= (30 / 100) + (20/100 - (12 / 100) = 38/100 = 19/50
C
Question: Difference of two numbers is 1760. If 7.5% of the number is 12.5% of the other number , find the number ?
A.2640, 1000
B.3660, 4400
C.3000, 4160
D.2490, 4150
Answer: B.3660, 4400
Explanation: Let the numbers be x and y. Then, 7.5 % of x =12.5% of y
X = 125*y/75 = 5*y/3.
Now, x-y =1760
5*y/3 –y =1760
2*y/3= 1760
y =[ (1760*3)/2] =2640.
One number = 2640, Second number =5*y/3 =4400.
Answer B.
Question: A student multiplied a number by 3/5 instead of 5/3.
What is the percentage error in the calculation?
A.34%
B.44%
C.54%
D.64%
Answer: D.64%
Explanation: Let the number be x
Then error = 5/3x - 3/5x = 16/15x
Error%= (16x/15 x 3/5x x 100)% = 64%
Answer: Option D
Question: If it is assumed that 60 percent of those who receive a questionnaire by mail will respond and 222 responses are needed, what is the minimum number of questionnaires that should be mailed?
A.280
B.370
C.460
D.550
Answer: B.370
Explanation: Let x be the minimum number of questionnaires to be mailed.
0.6x = 222
x = 370
The answer is B.
Question: 34 is related to 12 in the same way as 59 is related to
A.45
B.66
C.77
D.88
Answer: A.45
Explanation: Explanation:
The second number is the product of the digits of the first.
Answer: A) 45
Question: Evaluate 28% of 450 + 45% of 260
A.232
B.243
C.252
D.262
Answer: B.243
Explanation: Explanation:
= (28/100) * 450 + (45/100) * 260
= 126 + 117 = 243
Answer: Option B
Question: Find the principal which yields a simple interest of Rs. 20 and compound interest of Rs. 25 in two years, at the same percent rate per annum?
A.s. 40
B.s. 48
C.s. 49
D.s. 20
Answer: A.s. 40
Explanation: Explanation:
SI in 2 years = Rs. 20, SI in 1 year = Rs. 10
CI in 2 years = Rs. 25
% rate per annum = [(CI – SI) / (SI in 1 year)] *100
= [(25 – 20) / 20] * 100
= 25 % p.a.
Let the principal be Rs. X
Time = T = 2 years
% rate = 25% p.a.
SI = (PRT/100)
20 = (X*25*2) / 100
X = Rs. 40
ANSWER: A
Question: What is the largest 4 digit number exactly divisible by 88?
A.9999
B.9944
C.9988
D.9900
Answer: B.9944
Explanation: Largest 4 digit number = 9999
9999 ÷ 88 = 113, remainder = 55
Hence largest 4 digit number exactly divisible by 88 = 9999 - 55 = 9944
Answer is B
Question: Two cyclists are running on a circular track of 500m.They start from the same point A at the same time.If they meet for the first time at a point 300 m from A, which of the following could be the possible ratio of their speeds?
A.1:3
B.2:3
C.3:2
D.5:7
Answer: C.3:2
Explanation: well, the key aspect of this question is the distance mentioned, when they met for the first time, which is 300m away from the starting point. This distance between their first meeting can be less than 500 in only two circumstance.
1) if both are travelling in the same direction and one of them has been given a head start say by few meters.
2) or if both are travelling in the opposite direction.
now since they start their journey at the same time. hence option 1 is ruled out. hence they must be running in the opposite direction. hence answer should be 3:2
Why?? here is a solution
As here time is constant, therefore, distance traveled will be directly proportional to the the respective velocities/speed of the two runners.(d1/d2=v1/v2)
now one of them has covered 300m, therefore other must have covered 200m, therefore ratio of their speeds/velocities will be 3:2
C
Question: There are 4 more women than there are men on a local co-ed softball team. If there are a total of 18 players on the team, what is the ratio of men to women?
A.10/16
B.6/16
C.7/11
D.6/10
Answer: C.7/11
Explanation: w = m+4
w+m = 18
m+4+m = 18
2m = 14
m = 7
w = 11
ratio:7:11
Ans: C
Question: What value should come in place of question mark (?) in the following equations ?
64% of 1775 + 36% of 550 = ? % of 6670
A.20
B.24
C.30
D.40
Answer: A.20
Explanation: Explanation :
64x1775/100 + 36x550/100 = ?x6670/100
∴ ? = 1136 + 198/6670 x 100 = 20%
Answer : Option A
Question: Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 20 percent alcohol by volume?
A.200
B.300
C.400
D.500
Answer: A.200
Explanation: 20% is an equal distance between 10% and 30%.
Thus there should be equal parts of both solutions.
We should add 200 ml of solution Y.
The answer is A.
Question: If each term in the sum a1+a2+a3+.....+an is either 7 or 77 and the sum equals 329, which of the following could be equal to n?
A.37
B.38
C.39
D.41
Answer: A.37
Explanation: Since, there is no 47 in the answer choices (329/7 = 47), we know there is at least one 77.
329 - 77 = 252
252/7 = 36
36+1 = 37.
If 37 wasn't there, I would have subtracted 77 from 252 and continued in a similar way.
Ans. A
Question: If N is the product of all positive integers less than 31, than what is the greatest integer k for which N/18^k is an integer?
A.3
B.6
C.7
D.14
Answer: C.7
Explanation: Basically the question is asking us what is the highest power of 18 that can give us a number that is a factor of 31!
So remember 18 after prime factorization is (3^2)(2). Now there are going to be less factors of 3 in 31!, than factors of 2.
Therefore, let's find how many factors of 3 in 31! We can use this quick method
31/3^1 = 10
31/3^2= 3
31/3^3=1
Sum = 14
Just ignore the remainders.
So we have that 3^14 must be the least. Now don't forget that 18 is 3^2k so k must be ONLY 7, because 2k will give us the 14.
Hence answer is (C)
Question: The average weight of 16 students in a class is 50.25 kg and that of the remaining 8 students is 45.15 kg. Find the average weights of all the students in the class.
A.A)48.55
B.B)49
C.C)51
D.D)61
Answer: A.A)48.55
Explanation: Required average
= (50.25 x 16 + 45.15 x 8)/(16 + 8)
= (804 + 361.20)/24
= 1165.20/24
= 48.55kg
Answer is A
Question: A cylinder of radius R and height H is reshaped. Which of the following changes results in the cylinder of greatest volume?
A.a 20% decrease in H and a 50% increase in R.
B.a 500% increase in H and a 50% decrease in R.
C.a 300% increase in H and a 30% decrease in R
D.a 70% decrease in H and a 100% increase in R
Answer: C.a 300% increase in H and a 30% decrease in R
Explanation: Volume of a cylinder = Pi. R^2.H
Check for options as per given Q.
A. (1.5)^2 * (0.8) = 2.25 * 0.8 = 1.8 (Since 20% decrease in H and a 50% increase in R.)
B. (0.5)^2 * (6) = 0.25 * 6 = 1.5 (Since 500% increase in H and a 50% decrease in R)
C. (0.7)^2 * (4) = 0.49 * 4 = 1.96 (Since 300% increase in H and a 30% decrease in R )
D. (2)^2 * (0.3) = 4 * 0.3 = 1.2 (Since 70% decrease in H and a 100% increase in R. )
E. (0.9)^2 * (2) = 0.81 * 2 = 1.62 (Since 100% increase in H and a 10% decrease in R. )
Maximum value is 1.96
Option C
Question: A bucket full of nuts was discovered by the crow living in the basement. The crow eats a sixth of the total number of nuts in 4 hours. How many hours i total will it take the crow to finish a quarter of the nuts?
A.6
B.8
C.10
D.12
Answer: A.6
Explanation: In one hour, the crow eats 1/24 of the nuts.
(1/4) / (1/24) = 6 hours
The answer is A.
Question: A computer program produces a sequence a1, a2, a3, ... such that a1=a2=1 and ak=a(k-1)*3-1 for 2 < k < n for some n. If n=9, what is a6?
A.35
B.37
C.39
D.41
Answer: D.41
Explanation: a1=1
a2=1
a3=1*3-1=2
a4=2*3-1=5
a5=5*3-1=14
a6=14*3-1=42-1=41
41
Question: Every letter in the alphabet has a number value that is equal to its place in the alphabet. Thus, the letter A has a value of 1, the letter B has a value of 2, the letter C has a value of 3, etc... The number value of a word is obtained by adding up the value of the letters in the word and then multiplying that sum by the length of the word. What is the number value of the word "DOG"?
A.72
B.75
C.78
D.81
Answer: C.78
Explanation: "DOG" = (4+15+7)*3=78.
The answer is C.
Question: All of the students of Music High School are in the band, the orchestra, or both. 60 percent of the students are in only one group. There are 106 students in the band. If 10 percent of the students are in the band only, how many students are in the orchestra only?
A.120
B.110
C.116
D.106
Answer: D.106
Explanation: % of students in one group only = 60%
% of students in both groups = 100 - 60 = 40%
% of students in the band only = 10%
Number of students who are in band = 106
40% + 10% = 50% = 106 Students
Finding total students:
x = (106 x 100)/50
x = 212
Students in orchestra only = 212 - 106 = 106
Answer:D
Question: There are 500 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of managers to 98%?
A.150
B.200
C.250
D.350
Answer: C.250
Explanation: There are 495 managers and 5 others. The 5 others would compose 2% of the total number of people if there were 250 people in the room. Thus 250 managers must leave.
The answer is C.
Question: A shirt goes on sale for 60% of its original price. One week later, the sale price is marked down 10%. The final price is what percent of the original price?
A.72%
B.70%
C.52%
D.50%
Answer: C.52%
Explanation: Just assume original price is 100.
Sale price = 60
Then it is marked down by 10% = 60-6=52.
Hence it is 52% od the original price. Hence answer is C.
Question: The third proportional to 1 and 5 is?
A.8
B.27
C.24
D.25
Answer: D.25
Explanation: (5*5)/1 = 25
Answer:D
Question: A man covers a certain distance Q in a train. If the train moved 4km/hr faster, it would take 30 min less. If it moved 2km/hr slower, it would take 20 mins more. Find the distance?
A.200 km
B.50 km
C.20 km
D.60 km
Answer: D.60 km
Explanation: Not really. When you solve the 2 equation above, you get,
6T-4/3 = 5R/6 from simplifying equation 1
4T-2=R/2 from simplifying equation 2
You can now multiply equation 2 by 5 to get
5(4T-2=R/2 ) = 20T-10=5R/2 and then subtract this new equation from equation 1 to get T=3, followed by R=20 to give you distance Q = R*T=20*3=60 km.D
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 40 ps per meter is?
A.287
B.369
C.100
D.279
Answer: C.100
Explanation: 3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 0.40
= Rs.100
Answer:C
Question: Dana borrows 5000 pounds annually for her college education. If Dana gives her parents 4% of that amount back each month, how much will she still owe her parents after four years of college?
A.9800
B.10000
C.10200
D.10400
Answer: C.10200
Explanation: dana borrows 5000 and returns 4% per month.
so returns 200 per month. and 2400 per year.
so dana owes 5000-2400=2600 per year.
after 4 years she will owe 10400.
Ans (C)