RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The average age of 20 students of a class is 20 years. Out of these, the average age of 9 students is 11 years and that of the other 10 students is 24 years. The age of the 20th student is?
A.65
B.61
C.59
D.63
Answer: B.61
Explanation: Age of the 20th student = 20*20 - (9*11+10*24) = 400-339 = 61 years
Answer is B
Question: A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
A.45
B.500/11
C.600/11
D.55
Answer: B.500/11
Explanation: Explanation :
Number of runs made by running,
=>110−(3×4+8×6).
=>110−(60).
=>50.
Hence, the required percentage is:-
=>(50/100×100).
=>500/11.
Answer : B
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.276 m
B.279 m
C.240 m
D.207 m
Answer: C.240 m
Explanation: Speed = [54 * 5/18] m/sec
= 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x =240 m.
Answer: C
Question: A sells a bicycle to B at a profit of 80% and B sells it to C at a loss of 40%. Find the resultant profit or loss.
A.-4%
B.5%
C.-5%
D.8%
Answer: D.8%
Explanation: The resultant profit or loss = 80 - 40 - (80*40)/100 = 8%
Profit = 8%
Answer is D
Question: Which number need to add to 8679921 to get a number exactly divisible by 330?
A.69
B.62
C.61
D.63
Answer: A.69
Explanation: 8679921 / 330 = 26302 and reminder = 261.
330-261 = 69
So, the next number divisible by 339 is 69 places in front of 8679921
Which means 69 + 8679921 =8679990
69 should be added to 8679921
A
Question: If Rs. 762 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is?
A.A)426
B.B)526
C.C)207
D.D)199
Answer: D.D)199
Explanation: Given ratio
= 1/2:2/3:3/4 = 6:8:9
1st part = 762 * 6/23
= Rs. 199.
Answer:D
Question: The total car population in a Mumbai is 90,000 out of which 50,000 are made by Honda. Out of every 100 Honda cars, 90 are red in color, but only 60% of the total car population is red. Find the % of non-Honda cars that are red
A.12.5%
B.19.5%
C.22.5%
D.21.5%
Answer: C.22.5%
Explanation: Total Honda brand red cars = 90/100 *50000 = 45000
Total red cars = 60/100*90000 = 54000
No. of Non-Honda cars = 90000-50000 = 40000
No. of Non-Honda red cars = 54000 - 45000 = 9000
% of Non-Honda red cars = 9000/40000*100 = 22.5%
Answer : C
Question: If a committee of 3 people is to be selected from among 5 married couples so that the committee does not include two people who are married to each other, how many such committees are possible?
A.20
B.40
C.50
D.80
Answer: D.80
Explanation: total people=10.. ways to select 3 out of them=10c3=120...
it includes comb including couple..
ways in which couple are included =8c1*5=40..
so ans reqd 120-40=80...
ANS:D
Question: 97 students take part in a test and the median score is 85. Which of the following descriptions must be correct?
I. . At most 49 students’ score are equal to or more than 85..
II. At least 49 students’ score are equal to or more than 85.
III. At least 49 students’ score are less than 85.
A.I
B.II
C.III
D.III
Answer: B.II
Explanation: If we order the scores increasingly, then on the 49th place we have the score of 85. There must be 48 scores (those on the right of the 85 score) greater or equal to 85. So, I is necessarily correct.
The scores on the left of the 49th place, all have to be equal or less than 85. Since we can have the extreme case of all the scores 85, neither II, nor III is correct. The question asks for descriptions thatmustbe correct.
Answer B.
Question: What is the probability of drawing a queen from a deck of 52 cards?
A.4/13
B.1/13
C.4
D.1
Answer: B.1/13
Explanation: Total number of cards,n(s)=52
Total number of queen cards,n(e)=4
p(e)=n(e)/n(s)=4/52=1/13
Option B is answer
Question: Find the 2nd least number of four digits which is exactly divisible by 12, 15 and 18?
A.A)1080
B.B)6480
C.C)3240
D.D)9720
Answer: C.C)3240
Explanation: The largest five digit numbers are
1080,1240,3240,6480,9720
1080 is divisible by 12,15, and 18 -----(1st least no)
1240 is not divisible by 18, 12 and 15
3240 is divisible by 12,15, and 18 -----(2nd least no)
ANSWER:C
Question: If the numerator of a fraction W is tripled, and the denominator of a fraction is doubled, the resulting fraction will reflect an increase of what percent?
A.16 1⁄6%
B.25%
C.33 1⁄3%
D.50%
Answer: D.50%
Explanation: This question can be dealt with conceptually or by TESTing VALUES.
We're told that the numerator of a fraction W is tripled and the denominator of that same fraction is doubled. We're asked for the resulting increase, in percentage terms, of that fraction.
Let's TEST 2/1
If we triple the numerator and double the denominator, we end up with....
(2x3)/(1x2) = 6/2 = 3
Since we're increasing 2 to 3, we're increasing that fraction by (3-2)/2 = 1/2 of itself = 50%
D
Question: The first half of a 400-mile trip was travelled in x hours and the second half in y hours. Which of the following is equal to the average speed, in miles per hour, for the entire trip?
A.200/(x + y)
B.400/(x + y)
C.50/x + 50/y
D.200/x + 200/y
Answer: B.400/(x + y)
Explanation: Time taken to cover first half i.e 200 miles of a 400 mile trip = x
time taken to cover the second half i.e 200 miles of a 400 mile trip = y
Total time taken = x+y
Average speed for the entire trip =total distance /total time
=400/(x+y)
Answer B
Question: Which of the following will come in place of the question mark (?) in the following letter series?
BXF, DVI, FTL, HRO,?
A.JPL
B.KPL
C.JOL
D.JOK
Answer: A.JPL
Explanation: firstword B then D so theres a diff of 1 word ,so after F then H then J...then second word of BXF is X then -1 word so V ,then with J it will be P ...so ans is JPL...
ANSWER:A
Question: Pakistan, India and Srilanka are engaged in a missile war, such that they fire one after the other, in a sequence, the sequence selected by draw of lots. The rules of war are such that the 3 countries keep on shooting at each other until they hit with the missile. This goes on until there is one last country left unhit, and then the war ends. The chances that Pakistan hits its target is 100%, Srilanka hits the target is 80% and India hits the target is 50%.
Who has the highest chance of winning the war?
A.India
B.Pakistan
C.Srilanka
D.None of these
Answer: D.None of these
Explanation: Solution:
India has the highest chances of winning the war (47/90)
Missile Firing order:
Chances of Remaining Unhit - Pakistan:
Chances of Remaining Unhit - Srilanka:
Chances of Remaining Unhit - India
Pakistan - Srilanka - India
1/2 0 1/2
Pakistan - India - Srilanka
1/2 0 1/2
India - Pakistan - Srilanka
1/10 16/45 49/90
Srilanka- Pakistan - India
1/2 0 1/2
Srilanka - India - Pakistan
1/10 16/45 49/90
India - Srilanka - Pakistan
1/10 16/45 49/90
Total chances of being unhit (sum of the probabilities divided by 6):
27/90 16/90 47/90
Answer D
Question: A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average(arithmetic mean) of the other 20 numbers in the list, then n is what fraction W of the sum of the 21 numbers in the list?
A. 1/20
B. 1/6
C. 1/5
D. 4/21
Answer: B. 1/6
Explanation: This is how I used to calculate which I think works pretty well:
if you let the average of the 20 other numbers equal a, can you write this equation for sum of the list (S)
n + 20a = S
the question tells us that
n = 4a
plug this back into the first equation and you get that the sum is 24a
4a + 20a = 24a
therefore fraction W of n to the total would be
4a/24a or 1/6
answer B
Question: In how many ways can seven friends be seated in a row having 35 seats, such that no two friends occupy adjacent seats?
A.29P7
B.29C7
C.28P7
D.28C7
Answer: A.29P7
Explanation: Solution:
First let us consider the 28 unoccupied seats.
They create 29 slots- one on the left of each seat and one on the right of the last one.
We can place the 7 friends in any of these 29 slots i.e. 29P7 ways.
Answer A
Question: A fraction becomes 2/3 when 1 is added to both, its numerator and denominator.
And ,it becomes 1/2 when 1 is subtracted from both the numerator and denominator. Find the fraction.
A.1/2
B.3/4
C.2/3
D.3/5
Answer: D.3/5
Explanation: Let the required fraction be x/y. Then,
x+1 / y+1 = 2 / 3 => 3x – 2y = - 1 …(i) and x – 1 / y – 1 = 1 / 2
	2x – y = 1 …(ii)
Solving (i) and (ii), we get : x = 3 , y = 5
therefore, Required fraction= 3 / 5.
Answer is D.
Question: Given that there are 5 basketball players per team, how many ways can you select 3 basketball players from 3 teams if no more than one player can be selected from each team?
A. 25
B. 30
C. 60
D. 75
Answer: A. 25
Explanation: 3 teams can be selected from 3 teams in 3C3 ways = 1 ways
as the condition is that the 2 players should be from different teams
one player can be chosen from 1st team in 5 ways
similarly another player can be chosen from 2nd team in 5 ways
Total number of ways to choose the player = 5 * 5 * 1 = 25 ways
Correct Answer - A
Question: At what time will the train reach city X from city Y?
I.The train crosses another train of equal length of 200 metres and running in opposite directions in 15 seconds.
II.The train leaves city Y and 7.15 a.m. for city X situated at a distance of 558 km.
III.The 200 metres long train crosses a signal pole in 10 seconds.
A.I only
B.II only
C.III only
D.II and III only
Answer: D.II and III only
Explanation: Explanation:
From the statement I, we get length of the train is 200 metres (Redundant info while comparing with Statement III).
The rest of the info given in this statement cannot be used for calculating the speed of the train,
because the two trains might run at different speed.
III gives, speed =200/1o m/sec = 20 m/sec = {20 x 18/5} km/hr = 72 km/hr.
II gives, time taken =(558/72) hrs = 31/4 hrs = 7 3/4 hrs = 7 hrs 45 min.
So, the train will reach city X at 3 p.m.
.’. Hence II and III only gives the answer.
Answer D
Question: How to additions fast. For example we have to do a simple addition like 234 + 563+ 985 + 349.
A.2131
B.7399
C.2997
D.2769
Answer: A.2131
Explanation: Instead of doing like this we first add all the digits in the hundred's place. 2 + 5 + 9 + 3 = 19. Put 2 zero's to the right hand side so we get 1900.
Now add the digits in the tenth's place. 3 + 6 + 8 + 4 = 21. Put 1 zero to the right hand side so we get 210.
Now add the digits in the units place 4 + 3 + 5 + 9 = 21.
Now 1900 + 210 + 21 = 2131
Answer:A
Question: Of the 11 members of a football team in school, 9 are trained to play the offensive position, 6 can play defensive position, and 4 can play both position. If one member is chosen at random, what is the probability that the member chosen will be someone who play either position ?
A.a) 3/11
B.b) 4/11
C.c) 0
D.d) 6/11
Answer: C.c) 0
Explanation: You know how to solve for Total number of people who can play at one position:
Total = n(A) + n(B) - n(A and B)
Total people who can play at least one position = 9+6-4=11
So all 11 people know how to play at least one position. Hence, if you pick anyone, the probability is 0 that he wouldn't know how to play any position
Answer (C)
Question: Josh spends a total of $6.00 buying N items in the convenience store. If each of the items is either a 5 cents single bubblegum, or a 50 cents bubblegum pack, then N may be which of the following?
A.99
B.111
C.101
D.109
Answer: B.111
Explanation: Let x be 0.05$ single bubblegum and y be the total 0.5$ packs ---> 0.05x+0.5y=6.00 ---> x+10y=120 ...(1)
Also, x+y=N ...(2)
Solving 1 and 2 , we get, N = 120-9y ---> only value satisfied is when y = 1---> N = 120-9=111. B is the correct answer. Other options are not equal to multiples of 9 removed from 120.
Question: Define a* by the equation a* = π-x. Then ((−π)*)* =
A. −2π
B. -1
C. −π
D. 2π
Answer: C. −π
Explanation: for a* f(f(−π)) = f(π − (−π)) = f(π + π) = f(2π) = π − 2π = −π=C
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
A.1/45
B.1/29
C.1/455
D.2/275
Answer: C.1/455
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue = Â³Câ‚ƒ/Â¹âµCâ‚ƒ = (1 * 3 * 2 * 1)/(15 * 14 * 13) = 1/455
Answer: C
Question: At 3:40, the hour hand and the minute hand of a clock form an angle of:
A.130
B.125
C.140
D.154
Answer: A.130
Explanation: Angle traced by hour hand in 12 hrs. = 360Â°.
abgle traced it in 11/3 hrs = (360/12 * 11/3) = 110
angle traced by min hand in 60 min = 360
angle traced by it in 40 min = (360/60*40) = 240
req (240-110)=130d
Question: If there are 30 red and blue marbles in a jar, and the ratio of red to blue marbles is 2:3, what is the probability that, drawing twice, you will select two red marbles if you return the marbles after each draw?
A.1/25
B.2/25
C.3/25
D.4/25
Answer: D.4/25
Explanation: 0 red and blue marbles in a jar, and the ratio of red to blue marbles is 2:3
So, 5x=30 ---> x=6
Red marbles = 2*x = 2*6 = 12
Blue marbles = 3*x = 3*6 = 18
Prob to select a red marble = 12/30 = 2/5
Prob to select 2 red marbles with replacement = 2/5*2*5 = 4/25
Hence, answer will be D.
Question: A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 3:5. The ratio of economy cars to sport utility vehicles is 4:3. What is the ratio of luxury cars to sport utility vehicles?
A.9:8
B.8:9
C.3:2
D.20:9
Answer: D.20:9
Explanation: The ratio of economy to luxury cars is 3:5 --> E:L = 3:5 = 12:20.
The ratio of economy cars to sport utility vehicles is 4:3 --> E:S = 4:3 = 12:9.
Thus, L:S = 20:9.
Answer: D.
Question: The ratio of kamla and nisha is 6:5 and the sum of their ages is 44.what will be the ratio of their ages after 8 years.
A.5:6
B.7:8
C.8:7
D.12:11
Answer: C.8:7
Explanation: Answer:	let age of kamla is 6x and age of nisha is 5x.
then,6x+5x=44,11x=44,x=4
after 8 year the ratio of their ages=6x+8/5x+8=8:7
answer C
Question: The ratio of two quantities is 7 to 12. If each of the quantities is divided by 3, what is the ratio of these 2 new quantities?
A.3.5:6
B.14:24
C.7:12
D.2.3:4
Answer: C.7:12
Explanation: If both sides of a ratio are divided by the same number there is no change in the ratio.
5:6 means 7x:12x...
The ratio starts as 7/(1): 12/(1). So when you diveide by three it becomes 7/(3): 12/(3)..
So if the Xs are equal the ratio does not change..
ANSWER:C
Question: There are six cards in which it has two king cards. all cards are turned down and two cards are opened what is the possibility to get two kings.
A.1/15
B.2/15
C.3/15
D.4/15
Answer: A.1/15
Explanation: P0SSIBLITY TO GET TWO KINGS IS 2C2/6C2=1/15
ANSWER:A
Question: A fruit seller sells mangoes at the rate of Rs.8 per kg and thereby loses 20%. At what price per kg, he should have sold them to make a profit of 5%
A.Rs 8.5
B.Rs 9.5
C.Rs 10.5
D.Rs 11.5
Answer: C.Rs 10.5
Explanation: Explanation:
80 : 8 = 105 : x
x= (8×105/80)
= Rs 10.5
Option C
Question: A, B and C enter into a partnership. A invests 3 times as much as B invests and 2/3 of what C invests. At the end of the year, the profit earned is Rs. 44000. What is the share of C?
A.Rs. 12000
B.Rs. 13375
C.Rs. 11750
D.Rs. 11625
Answer: A.Rs. 12000
Explanation: Explanation:
Let the investment of C be Rs. x.
The inverstment of B = Rs.(2x/3)
The inverstment of A = Rs. (3 × (2/3)x) = Rs. (2x)
Ratio of capitals of A, B and C = 2x : 2x/3 : x = 6 : 2 : 3
C's share = Rs. [(3/11) × 44000] = Rs. 12000
Answer: Option A
Question: At exactly what time past 8:00 will the minute and hour hands of an accurate working clock be precisely perpendicular to each other for the first time?
A.20 13/21 minutes past 7:00
B.21 9/11 minutes past 8:00
C.21 3/23 minutes past 7:00
D.21 9/11 minutes past 7:00
Answer: B.21 9/11 minutes past 8:00
Explanation: 5.5 is the angle between minute n hour, this is what I was taught...so shouldn't it be solve by dividing 90 with 5.5?
That would have been the case if your initial difference between the hour and the minute hand was = 0 degrees or in other words, both minute and hour hands were at the same location. But as per the question, you are asked for time AFTER 8:00. At 8:00, the angle between the hour and the minute hand is 210 degrees. you need to take this into account as well.
So in order for the difference to decrease to 90 degrees, the minute hand must eat away this difference of 210-90 = 120 degree at the rate of 5.5 degrees per minute ---> 120/5.5 = 21 9/11 minutes.
Thus, B is the correct answer.
Question: Two pipes A and B can separately fill a cistern in 60 min and 75 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 min. In how much time, the third pipe alone can empty the cistern?
A.90 min
B.100 min
C.110 min
D.120 min
Answer: B.100 min
Explanation: Work done by the third pipe in 1 min = 1/50 - (1/60 + 1/75) = - 1/100.
[-ve sign means emptying]
The third pipe alone can empty the cistern in 100 min.
ANSWER:B
Question: Can you please walk me through how to best approach this problem? Thanks
If #p# = ap^3+ bp – 1 where a and b are constants, and #-3# = 2, what is the value of #3#?
A.-4
B.0
C.-2
D.-3
Answer: A.-4
Explanation: #p# = ap^3 + bp - 1
#-3# = 2
putting p = -3 in above equation
-27a -(3b +1) = 2 or
#-5# = (27a+3b+1) = -2
therefore 27a+3b = -3 .....(1
now putting p = 3
#3# = 27 a+3b - 1
using equation 1(27a+3b = -3)
#3# = -3-1 = -4
hence A
Question: Jenny can divide her sweets equally to 5 people and also to 6 people equally but not to 12 people. What could be the number?
A.120
B.134
C.127
D.30
Answer: D.30
Explanation: Option (B) and (C) are ruled out as they are not divisilble by 5 and 6.
120 is both divisible by 5 and 6 but also by 12, so it wrong.
650 is divisible by 5 but not by 6.
hence,
(D) is the answer, as it is both divisible by 5 or 6 but not by 12
Question: If n=t^3 , when n and t are positive integers and 8, 9, 10 are each factors of n, which of the following must be a factor of n?
A.16
B.175
C.225
D.275
Answer: C.225
Explanation: n = 8p,n = 9q and n = 10r.Thus,n^3=t^6=2^4∗3^2∗5∗[k is some positive integers]
Thus, for t to be a positive integer, k must atleast have the value = 2^2∗3^4∗5^5
Thus,n=t3=2^3∗3^2∗5^2∗y[y is a positive integer]
225 is definitely a factor of n.
ANSWER:C
Question: If 5 machines can produce 20 units in 10 hours, how long would it take 20 machines to produce 160 units?
A.50 hours
B.40 hours
C.20 hours
D.12 hours
Answer: C.20 hours
Explanation: Here, we're told that 5 machines can produce 20 units in 10 hours....
That means that EACH machine WORKS for 10 hours apiece. Since there are 5 machines (and we're meant to assume that each machine does the same amount of work), then the 5 machines equally created the 20 units.
20 units/5 machines = 4 units are made by each machine every 10 hours
Now that we know how long it takes each machine to make 4 units, we can break THIS down further if we choose to...
10 hours/4 units = 2.5 hours per unit when 1 machine is working.
The prompt asks us how long would it take 20 machines to produce 160 units.
If 20 machines each work for 2.5 hours, then we'll have 20 units. Since 160 units is '8 times' 20, we need '8 times' more TIME.
(2.5 hours)(8 times) = 20 hours
Final Answer:
[Reveal]Spoiler:
C
Question: How many numbers up to 100 and 300 are divisible by 11?
A.18 2/98
B.18 9/11
C.18 2/19
D.18 2/11
Answer: D.18 2/11
Explanation: Explanation:
(300 â€“ 100)/11 = 200/11 = 18 2/11
18 Numbers
Answer: D
Question: How many positive integers less than 28 are prime numbers, odd multiples of 5, or the sum of a positive multiple of 2 and a positive multiple of 4?
A.27
B.25
C.24
D.22
Answer: D.22
Explanation: 9 prime numbers less than 28: {2, 3, 5, 7, 11, 13, 17, 19, 23}
3 odd multiples of 5: {5, 15, 25}
11 numbers which are the sum of a positive multiple of 2 and a positive multiple of 4: {6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26}
Notice, that 5 is in two sets, thus total # of integers satisfying the given conditions is 9+3+11-1=22.
Answer: D.
Question: The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of?
A.6:8
B.6:1
C.6:5
D.6:2
Answer: C.6:5
Explanation: 4:5
3:2
-------
12:15:10
12:10
6:5
Answer: C
Question: If 2^y = 4^(5x + 3) and 3^(x - 7) = 9^y, what is the value of x + y ?
A.-10
B.-5
C.-4
D.3
Answer: B.-5
Explanation: 2^y = 4^(5x + 3)
2^y=2^2(5x+3)
y=10x+6 ........... 1
3^(x - 7) = 9^y
3^(x-7)=3^2y
x-7=2y ............. 2
put value of y=10x+6 in eq 2
x-7=2(10x+6)
x-7=20x+12
19x=-19
x=-1
therefore, y= -10+6
y=-4
x+y= -1-4= -5
Answer: B
Question: A number when divided by 779 gives a remainder 47. By dividing the same number by 19, what would be the remainder?
A.9
B.8
C.7
D.6
Answer: A.9
Explanation: Number = ( 779 x a) + 47, where "a" is the quotient
= (19 x 41 x a) + (19 x 2) + 9
= 19 x (41a + 2) + 9
= 19 x (New quotient) + 9
\inline \fn_jvn \therefore Required remainder = 9
Answer:A
Question: A alone finish a work in 12 days,where B finish same work in 15 days and C alone finish in 20 days.all three start work together but after 2 days A leave the work and B leave the work before 2 days of finishing the work.then in how many days work finished?
A.8
B.45/6
C.6
D.58/7
Answer: D.58/7
Explanation: work of A in 1 day=1/12,work of B in 1 day=1/15 and work of C in 1 day=1/20
(A+B+C) Work in 2 days=2(1/12+1/15+1/20)=2×12/60=2/5
work of C in 2 days=1/10
remaining work=1-(2/5+1/10)=1-1/2=1/2
this work done by both B and C together
(B+C) work in 1 days=7/60
1/2 work done by (B+C)=[1*60/7*1/2]=30/7 days
total time taken to finish the work=[2+2+30/7]=58/7 days
Answer D
Question: A plane flies 420 miles with the wind and 350 miles against the wind in the same length of time. If the speed of the wind is 23 mph, what is the speed of the plain in still air?
A.253 mph.
B.378 mph.
C.565 mph.
D.431 mph.
Answer: A.253 mph.
Explanation: The speed of the plane in still air = x miles/hour
The speed of the wind is 23 mph
Speed with the wind = (x + 23) mph
Speed against the wind = (x – 23) mph
Time = Distance/ Speed
According to the problem,
420/(x + 23) = 350/(x – 23)
420(x – 23) = 350(x + 23)
420x – 9660 = 350x + 805
420x – 350x = 8050 + 9660
70x = 17710
x = 17710/70
x = 253
Therefore, the speed of the plane in still air = 253 mph.
correct answer A
Question: Two trains of length 200 m and 100 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 18 kmph and 36 kmph. After how much time will the trains meet?
A.27/7 sec
B.20/3 sec
C.33/7 sec
D.21/7 sec
Answer: B.20/3 sec
Explanation: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (18 + 36)*5/18 = 3*5 = 15 mps.
The time required = d/s = 100/15 = 20/3 sec.
Answer : B
Question: A trader marks his books 20% more than the cost price. If he allows 30% discount, then find his gain or loss percent?
A.2% profit
B.2% loss
C.16% loss
D.No profit No loss
Answer: C.16% loss
Explanation: Let CP of an book = 100
MP of an book = 120
Discount 30 % on 120 = 36
SP of the book = 120 - 36 = 84
loss = 16%
Answer : C
Question: P and Q invested in a shop. The profits were divided in the ratio of 2 : 4 respectively. If P invested Rs. 500000, the amount invested by Q is:
A.5000000
B.4000000
C.1000000
D.6000000
Answer: C.1000000
Explanation: Suppose Q invested Rs. y. Then, 500000/y = 2/4 or y = [500000 x 4 / 2] = 1000000.
Answer C
Question: The distance light travels in one year is approximately 5,840,000,000,000 miles. The distance light travels in 100 years is
A.A) 587 × 108 miles
B.B) 587 × 1010 miles
C.C) 587 × 10-10 miles
D.D) 584 × 1012 miles
Answer: D.D) 584 × 1012 miles
Explanation: The distance of the light travels in 100 years is:
5,840,000,000,000 × 100 miles.
= 584,000,000,000,000 miles.
= 584 × 1012 miles.
The answer is (D)