RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Double of Quarter of 6 percent written as a decimal is :
A.0.03
B.0.0005
C.0.25
D.0.005
Answer: A.0.03
Explanation: Explanation :
Solution: (2)*(1/4)*6% = 0.03
Answer : A
Question: If x and y are positive, which of the following must be greater that 1/sqrt(x + y)?
I. sqrt(x + y)/2x
II. [sqrt(x) + sqrt(y)]/(x + y)
III. [sqrt(x) - sqrt(y)]/(x + y)
A.None
B.I only
C.II only
D.I and II
Answer: C.II only
Explanation: solving i ) Y > X ( which could be true or false)
sloving ii) 2 Sqrt(xy) > 0 ( which is true-given x and y are positive)
solving iii) -2 Squrt(xy) > 0 ( which is false)
Therefore C should be the answer.
Question: In a triangle, one side is 6 Cm and another side is 4 Cm. which of the following can be the perimeter of the triangle?
A.18.
B.25.
C.30.
D.32.
Answer: A.18.
Explanation: Given : one side is 6 Cm and another side is 9 Cm. So the 3rd side will be > 3 and < 15. Thus the perimeter will be : 18 < perimeter < 30. Only option satisfying this condition is 18. Hence A.
Question: Ten cards numbered 1 to 10 are placed in a box, mixed up thoroughly and then one card is drawn
randomly. If it is known that the number on the drawn card is more than 3, what is the probability
that it is an even number?
A.3/7
B.4/7
C.6/7
D.7/11
Answer: B.4/7
Explanation: Let A be the event ‘the number on the card drawn is even’ and B be the
event ‘the number on the card drawn is greater than 3’. We have to find P(A|B).
Now, the sample space of the experiment is S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Then A = {2, 4, 6, 8, 10}, B = {4, 5, 6, 7, 8, 9, 10}
and A n B = {4, 6, 8, 10}
Also P(A) = 5/2, P(B) = 7/10 and P(A n B) = 4/10
Then P(A|B) = P(A n B)/P(B) = (4/10)/(7/10)	= 4/7
B)
Question: A small college reduced its faculty by approximately 13 percent to 195 professors. What was the original number of faculty members?
A.182
B.208
C.224
D.254
Answer: C.224
Explanation: f x is the original number of faculty members, then after 13% reduction in faculty members number is .87x
but we are given .87x = 195
x = 224
So the original number of faculty members is 224
Correct Answer - C
Question: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
A.1/2
B.2/5
C.8/5
D.9/20
Answer: D.9/20
Explanation: Explanation:
Here, S = {1, 2, 3, 4, ...., 19, 20}.
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
P(E) =	n(E)/n(S)	= 9/20.
ANSWER : D
Question: A certain factory employed 600 men and 400 women and the average wager was Rs. 25.50 per day, If a woman got Rs. 5 less than a man, then what are their daily wages ?
A.27.50,22.59
B.27.50,22.50
C.27.50,32.50
D.27.70,22.59
Answer: B.27.50,22.50
Explanation: Explanation:
Let the daily wage of a man be Rs. x.
Then, daily wage of a woman = Rs. (x - 5).
Now, 600x + 400 (x - 5) = 25.50 * (600 + 400) <=> 1000x = 27500 <=> x = 27.50.
Man's daily wages = Rs. 27.50; Woman's daily wages = (x - 5) = Rs. 22.50.
Answer: B) m:27.50 w:22.50
Question: Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 36 kmph. Of how many minutes does the train stop per hour?
A.73
B.83
C.12
D.83
Answer: C.12
Explanation: Explanation:
T = 9/45 * 60 = 12
Answer: Option C
Question: A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangule, whose length and breadth are in the ratio of 6 : 5. What is the area of the rectangle?
A.20
B.30
C.40
D.50
Answer: B.30
Explanation: The circumference of the circle is equal to the permeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=> x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm2
Answer: Option B
Question: After allowing a discount of 11.11%, a trader still makes a gain of 14.28%. At how many percentage above the cost price does he mark on his goods?
A.28.56%
B.35%
C.22.22%
D.None of these
Answer: A.28.56%
Explanation: Explanation :
Let Y be the Selling price.
So, x + (14.28x / 100) = y - (11.11y / 100).
Or y = 1.2856x
Or y = 128.56x/100
Or y = x + 28.56x/100
Hence, 28.56% above the cost price he marks his goods.
Answer : A
Question: A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 20%?
A.Rs.600
B.Rs.500
C.Rs.250
D.Rs.700
Answer: A.Rs.600
Explanation: Cost price = Rs.500
profit = 20% of 500 = Rs.100
Selling price = Cost price + Profit
= 500 + 100 = 600
ANSWER:A
Question: By selling 33 metres of cloth , one gains the selling price of 11 metres . Find the gain percent .
A.20
B.30
C.40
D.50
Answer: D.50
Explanation: Sol:
(SP of 33m)-(CP of 33m)=Gain=SP of 11m
SP of 22m = CP of 33m
Let CP of each metre be Re.1 , Then, CP of 22m= Rs.22,SP of 22m=Rs.33.
Gain%=[(11/22)*100]%=50%
option D
Question: Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is :
A.48
B.52
C.58
D.66
Answer: A.48
Explanation: Sol.
Relative sped = (60 + 90) km/hr
= [150 * 5/18] m/sec = [125 / 3] m/sec.
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = [2000 * 3/125] sec = 48 sec.
Answer A
Question: The length of the longest rod that can fit in a cubical room of 4 m side is?
A.7.256 m
B.6.928 m
C.8.524 m
D.10.256 m
Answer: B.6.928 m
Explanation: 4 root(3)= 6.928 m
ANSWER B
Question: A mixture contains alcohol and water in the ratio 4:3. If 5liters of water is added to the mixture, the ratio becomes 4:5. Find the quality of alcohol in the given mixture.
A.10
B.8
C.7.5
D.6
Answer: A.10
Explanation: Let the quantity of alcohol and water be 4x and 3x
4x/(3x+5) = 4/5
20x = 4(3x+5)
x=2.5
Quantity of alcohol = 4*2.5 = 10liters.
Answer is A
Question: Two persons A and B take a field on rent. A puts on it 21 horses for 3 months and 15 cows for 2 months; B puts 15 cows for 6months and 40 sheep for 7 1/2 months. If one day, 3 horses eat as much as 5 cows and 6 cows as much as 10 sheep, what part of the rent should A pay?
A.1/3
B.1/5
C.1/0
D.1/2
Answer: A.1/3
Explanation: 3h = 5c
6c = 10s
A = 21h*3 + 15c*2
= 63h + 30c
= 105c + 30c = 135c
B = 15c*6 + 40s*7 1/2
= 90c + 300s
= 90c + 180c = 270c
A:B = 135:270
27:52
A = 27/79 = 1/3
Answer: A
Question: Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
A.6/11
B.6/13
C.6/15
D.7/11
Answer: A.6/11
Explanation: Part filled by (A + B + C) in 3 minutes = 3 1	+	1	+	1 = 3 x	11 =	11	.
30	20	10	60	20
Part filled by C in 3 minutes =	3	.
10
Required ratio = 3/10	x	20/11 =	6/11	.
Answer A)
Question: If a fair die is rolled six times, what is the probability that a 3 occurs on at least one roll?
A.25/36
B.125/216
C.425/639
D.11/36
Answer: C.425/639
Explanation: Questions such as these that talk aboutat leastormaximumorminimumin probability questions should make sure realize that probability of any event (N) to occur = 1- P(Not N)
Thus, the probability of at least 1 roll = 1- Probability of NO 3s = 1- (5/6)(5/6)(5/6)(5/6)(5/6)(5/6) = 1-214/639 =425/639.
5/6 is the probability of NOT getting a 3 in any 1 roll with 5 allowed numbers (=1,2,4,5,6) out of a total of 6 possibilities.
C is thus the correct answer.
Question: What is the greatest positive integer n such that 3^n is a factor of 36^150?
A.100
B.200
C.300
D.600
Answer: C.300
Explanation: 36 = 3^2 * 2^2.
36^150 = 3^300 * 2^300
The answer is C.
Question: Annie has 100 cards numbered 1 through 100. If she deals nine cards to Alex, without replacing any of them, what is the probability that Alex will get five consecutive numbers?
A.95!/100!
B.9!/100!
C.(92! X 9!)/100!
D.(96! X 5!)/100!
Answer: C.(92! X 9!)/100!
Explanation: Alex to get 9 consecutive cards in ascending order, to have 9 consecutive at the end is good enough.
There are 92 consecutive numbers in 100: {1, 2, 3, 4, 5,6,7,8,9}, {2, 3, 4, 5, 6,7,8,9,10}, ..., {92,93,94,95,96, 97, 98, 99, 100};
Total ways to pick 9 cards out of 100 is {9!*92!}{100!}.
Answer: C.
Question: If -1<x<0, what is the median K of these six numbers listed below
1/x^3,1/x^2, 1/x,x, x^2,x^3
A.1/x
B.x^2
C.x^2(x+1)/2
D.K=x(x^2+1)/2
Answer: D.K=x(x^2+1)/2
Explanation: My approach: Put any value between -1 and 0. you will get the answer. lets say 0.5. so the list will be as follows:
-8,-2,-0.5,-0.125 and last two numbers will be positive so need to see that.
median will be between -0.5 and -0.125.
So, (x^3+x)/2 (D).
Question: I walk a certain distance and ride back taking a total time of 37 minutes. I could walk both ways in 55 minutes. How long would it take me to ride both ways?
A.21
B.25
C.15
D.19
Answer: D.19
Explanation: Let the distance be x km. Then,
(Time taken to walk x km) + (time taken to ride x km) =37 min.
(Time taken to walk 2x km ) + ( time taken to ride 2x km )= 74 min.
But, the time taken to walk 2x km = 55 min.
Time taken to ride 2x km = (74-55)min =19 min.
Answer is D.
Question: A boat can move upstream at 25 kmph and downstream at 35 kmph, then the speed of the current is?
A.5 kmph
B.7 kmph
C.8 kmph
D.9 kmph
Answer: A.5 kmph
Explanation: US = 25
DS = 35
M = (35 - 25)/2 = 5
Answer:A
Question: If the set S is composed of the following numbers {99, 100, 100, 105, 106, 113, 126}, which of the following is largest?
A.The average (arithmetic mean) of set S
B.The median of set S
C.The mode of set S
D.The range of set S
Answer: A.The average (arithmetic mean) of set S
Explanation: A) 99, 100, 100, 105, 106, 113, 126 = 749 and its mean is 749/7 = 107.
B) The list is of 7 numbers and median is 105.
C) Mode is number of repetition of a number in the list , here it is 100.
D) Range = Max value - min value = 126 -99 = 27.
E) SD = square root of (sum of ( mean of series - number)^2 ) / n =>< 100
IMO option A is correct answer..
Question: A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have?
A.50
B.70
C.100
D.150
Answer: A.50
Explanation: A+B+C = 500
A+C = 200
B+C = 350
A+B+2C = 550
A+B+C = 500
C =50
ANSWER A
Question: On a weekend, 8 friends went to the beach and evenly split the cost of their beach house. If the amount paid by each person was an integer, which of the following could not have been the cost of the beach house?
A.$200
B.$149
C.$184
D.$328
Answer: B.$149
Explanation: Each of the seven persons evenly splitting the cost is an integer amount, therefore check the divisibility by 8 for all answer choices.
200/8 = 25
149/8 = 18.63
184/8 = 23
328/8 = 41
216/8 = 27
B is not an integer amount.
Answer:B
Question: By how much is 3/5th of 875 greater than 2/3 of 333?
A.239
B.303
C.288
D.127
Answer: B.303
Explanation: Explanation:
3/5th of 875 is greater than 2/3rd of 333
= 3/5 * 875 - 2/3 * 333
= 525 - 222 = 303.
Answer: B
Question: John's mom gave john and his four friends a 1 liter jar of lemonade to share among themselves.
each friend gets a glass and each glass can hold 20 centiliters of lemonade .
How long will it take John to share the lemonade if filling one cup took 5 seconds ?
A.100 seconds
B.65 seconds
C.23 seconds
D.25 seconds
Answer: D.25 seconds
Explanation: It takes five seconds to fill one glass, to fill five glasses equally will take 25 seconds. The answer is D
Question: A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 300. How much did he have with him in the beginning?
A.s 200
B.s 750
C.s 300
D.s 450
Answer: B.s 750
Explanation: Suppose the amount in the beginning was Rs ’x’
Money spent on clothes = Rs 1x/3 Balance = Rs 2x/3
Money spent on food = 1/5 of 2x/3 = Rs 2x/15
Balance = 2x/3 - 2x/15 = Rs 8x/15
Money spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5
Therefore 2x/5 = 300 = 750
ANSWER:B
Question: John invested some money in 5% stock at 100.If David wants to invest in an equally good 10% stock ,he must purchase a stock worth of :
A.Rs. 250
B.Rs. 200
C.Rs. 220
D.Rs. 100
Answer: B.Rs. 200
Explanation: Solution
For an income of Rs. 5, investment = Rs. 100
For an income of Rs. 10, investment = Rs.(100/5x10) = Rs. 200
Answer B
Question: 1/3 of girls , 1/2 of boys go to canteen .What factor and total number of classmates go to canteen.
A.1/5
B.1/4
C.1/3
D.2/5
Answer: D.2/5
Explanation: let total girls be 3 ...
and total boys be 2 ...
so total girls going to canteen = 1
boys going to canteen = 1
total no. of classmates = 5(only suppose......to find out the factor of students going to canteen...)
factor of classmates going to canteen=2/5.
ANSWER:D
Question: The distance from City A to City B is 220 miles. While driving from City A to City B, Bob drives at a constant speed of 40 miles per hour. Alice leaves City A 30 minutes after Bob. What is the minimum constant speed in miles per hour that Alice must exceed in order to arrive in City B before Bob?
A.44
B.48
C.50
D.52
Answer: A.44
Explanation: The time it takes Bob to drive to City B is 220 / 40 = 5.5 hours.
Alice needs to take less than 5 hours for the trip.
Alice needs to exceed a constant speed of 220 / 5 = 44 miles per hour.
The answer is A.
Question: Of the goose eggs laid at a certain pond, 1/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
A.1000
B.1200
C.1400
D.1600
Answer: B.1200
Explanation: Let x be the number of eggs that were laid.
(2/5)(3/4)(1/3)x = 120
(6/60)x = 120
x = 1200
The answer is B.
Question: If log 64 = 1.8061, then the value of log 16 will be (approx)?
A.1.204
B.1.9874
C.1.3564
D.1.2547
Answer: A.1.204
Explanation: Log 64 = 1.8061
log4^3 = 1.8061
log4 = 0.6020
2log4=1.2040
log4^2=1.2040
log16=1.2040(approx)
ANSWER A
Question: If x=kc and y=kt,then y+2x =?
A.k(t-c)
B.k(c-t)
C.k(t+2c)
D.t(k-c)
Answer: C.k(t+2c)
Explanation: Just put in the given values of y and x
y +2x = kt +2 kc
Now take k common
y +2 x = k(t +2c)
You get (C) as your answer.
Question: A box contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the box, if at least one black ball is to be included in the draw?
A.64
B.23
C.32
D.45
Answer: A.64
Explanation: We may have(1 black and 2 non-black) or (2 black and 1 non-black) or (3 black).
Required number of ways	= (3C1 x 6C2) + (3C2 x 6C1) + (3C3)=>64
ANSWER A
Question: A and B began business with Rs.3000 and Rs.4000 after 8 months, A withdraws Rs.1000 and B advances Rs.1000 more. At the end of the year, their profits amounted to Rs.798 find the share of A.
A.240
B.388
C.379
D.304
Answer: D.304
Explanation: Explanation:
(3*8 + 2*4):(4*8 + 5*4)
8:13
8/21 * 798 = 304
Answer: D
Question: A shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net profit or loss that he makes?
A.7%
B.3%
C.9%
D.4%
Answer: D.4%
Explanation: SP of first article = 1000
Profit = 20%
CP = (SP)*[100/(100+P)] = 5000/6 = 2500/3
SP of second article = 1000
Loss = 20%
CP = (SP)*[100/(100-L)] = 5000/4 = 1250
Total SP = 2000
Total CP = 2500/3 + 1250 = 6250/3
CP is more than SP, he makes a loss.
Loss = CP-SP = (6250/3)- 2000 = 250/3
Loss Percent = [(250/3)/(6250/3)]*100
=0.04 * 100 = 4%
Answer: D
Question: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs 5000?
A.6000
B.6500
C.7000
D.6300
Answer: A.6000
Explanation: Explanation:
ratio of increase of wages=22:25
ratio of decrease of labourers=15:11
compound ratio of wages of labourers= 22*15:25*11=330:275
final bill = Rs 5000
for 275 ratio wages= Rs 5000
for 1 " " = 5000/275
for 330 " " = 5000/275*330 = Rs 6000
Answer : A
Question: Two clocks are set correctly at 1 0'clock in the afternoon. One keeps correct time. The other gains 5 seconds per minute. That evening, when
the fast clock shows 6:20, what does the correct clock show?
A.4.0
B.5.0
C.6.0
D.7.2
Answer: C.6.0
Explanation: Faster clock gains 5 seconds per minute or 5*60=300 seconds or 5minutes per hour.
Both clocks are set at 1:00
At 2:00
correct clock is at 2:00
faster clock is at 2:05:00 (1 hour + gained 5 minutes)
At 3:00 -
correct clock is at 3:00
faster clock is at 3:10:00 (2 hours + gained 10 minutes)
.
In 5 hours, faster clock would gain 20 minutes. It will show 6:20. At that point, the correct clock would show 6:00.
Answer is C
Question: There are two divisions A and B of a class, consisting of 36 and 44 students respectively. If the average weight of divisions A is 40 kg and that of division b is 35 kg. What is the average weight of the whole class?
A.37.0
B.37.75
C.37.5
D.37.25
Answer: D.37.25
Explanation: Total weight of students in division A = 36 × 40
Total weight of students in division B = 44 × 35
Total students = 36 + 44 = 80
Average weight of the whole class
=((36×40)+(44×35))/80
=((9×40)+(11×35))/20
=((9×8)+(11×7))/4
=(72+77)/4
=149/4
=37.25
Answer is D.
Question: A school’s annual budget for the purchase of student computers increased by 44% this year over last year. If the price of student computers increased by 20% this year, then the number of computers it can purchase this year is what percent greater than the number of computers it purchased last year?
A.20%
B.30%
C.22%
D.28%
Answer: A.20%
Explanation: Lats year: budget = $100, price = $1 --> the number of computers purchased = 100/1 = 100;
This year: budget = $144, price = $1.2 --> the number of computers purchased = 144/1.2 = 120.
Increase in the number of computers purchased = 120%.
Answer: A.
Question: A began a business with Rs. 85000. He was joined afterwards by B with Rs. 42,500. For how much perod does B join, if the profits at the end of the year are divided in the ratio of 3:1 ?
A.8
B.9
C.1
D.6
Answer: A.8
Explanation: Suppose B joined for x months.
Given profit is divided in the ratio 3:1. Then,
= 8 months.
Answer: A
Question: What should be the least number to be added to the 4499 number to make it divisible by 9?
A.1
B.17
C.18
D.77
Answer: A.1
Explanation: Answer : 1
Option : A
Question: If 20 men can build a wall 66 metres long in 12 days, what length of a similar can be built by 86 men in 8 days?
A.189.2 mtrs
B.378.4 mtrs
C.478.4 mtrs
D.488.4 mtrs
Answer: A.189.2 mtrs
Explanation: If 20 men can build a wall 66 metres long in 12 days,
length of a similar wall that can be built by 86 men in 8 days = (66*86*8)/(12*20) = 189.2 mtrs
ANSWER:A
Question: During a certain week, a seal ate 60% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?
A.32
B.40
C.96
D.64
Answer: C.96
Explanation: Total smelt = x.
Then, 0.6*80+0.3(x-80)=0.4*x --> x=240 --> 0.4*x=96.
Answer: C.
Question: How many words can be formed by using all letters of the word ‘DAUGHTER’ so that the vowels always come together?
A.3561
B.7845
C.5410
D.4320
Answer: D.4320
Explanation: Given word contains 8 different letters. When the vowels AUE are always together, we may suppose them to form an entity, treated as one letter.
Then, the letters to be arranged are DGNTR (AUE).
Then 6 letters to be arranged in 6p6 = 6! = 720 ways.
The vowels in the group (AUE) may be arranged in 3! = 6 ways.
Required number of words = (720x6) = 4320.
Ans: D
Question: The length and width of a rectangle are integer values. What is the area of the smallest such rectangle that can be inscribed in a circle whose radius is also an integer
A. 42
B. 24
C. 36
D. 48
Answer: A. 42
Explanation: If we consider all pythagorean triplets with integral values, we have the following results:-
(3,4,5),(6,8,10)........
The diameter of the circle is 5 in the 1st case and 10 in the 2nd.
But the question says that radius of the circle is also an integer hence the 1st triplet will be ruled out.
We are left with the 2nd triplet where radius of the circle=5,
Hence the sides of the rectangle are 6 and 8 making the area =42.
A
Question: During a trip, Francine traveled x percent of the total distance at an average speed of 20 miles per hour and the rest of the distance at an average speed of 80 miles per hour. In terms of x, what was Francineâ€™s average speed for the entire trip?
A.(180-x)/2
B.(x+60)/4
C.(300-x)/5
D.8,000/(100+3x)
Answer: D.8,000/(100+3x)
Explanation: D....
X% traveeled at 20 mph
100-X% traveeled at 80 mph
total timt taken = x/20 +(100-x)/80 = (100+3x)/80
Total distance = x+(100-x) = 100
Av speed = Tot Dis/Time Taken which is D
Question: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.75. How much was lent at 5%?
A.388
B.1500
C.277
D.500
Answer: B.1500
Explanation: (x*5*1)/100 + [(1500 - x)*6*1]/100 = 75
5x/100 + 90 – 6x/100 = 75
x/100 = 15
=> x = 1500.Answer: B
Question: The average age of the mother and her six children is 12 year which is reduced by 5 years if the age of the mother is excluded. how old is the mother ?
A.40 year
B.42 year
C.48 year
D.50 year
Answer: B.42 year
Explanation: Solution
age of the mother= ( 12 × 7 - 7 × 6 ) year = 42 year. Answer B
Question: The edge of a cube is 3a cm. Find its surface?
A.64a2 cm2
B.54a2 cm2
C.84a2 cm2
D.24a2 cm2
Answer: B.54a2 cm2
Explanation: 6a2 = 6 * 3a * 3a = 54a2
Answer:B
Question: Two pipes can fill the cistern in 10hr and 12 hr respectively, while the third empty it in 20hr.
If all pipes are opened simultaneously, then the cistern will be filled in
A.10.5
B.8
C.6
D.7.5
Answer: D.7.5
Explanation: First pipe fills cistern in 10 hours.
So, in 1 hour, pipe fills 1/10 of the cistern capacity
2nd pipe fills cistern in 12 hours.
So, in 1 hour, 2nd pipe fills 1/12 of the cistern capacity
3rd pipe empties cistern in 20 hours
So, in 1 hour, 3rd pipe empties 1/20 of the cistern capacity
Net volume added to cistern per hour = Volume filled by 1st pipe per hour + Volume filled by 2nd pipe per hour - Volume emptied by 3rd pipe per hour
= 1/10 + 1/12 - 1/20
=(6 + 5 - 3) / 60 = 8/60
=> Net volume added to cistern per hour = 2/15
So, Cistern will be fill in 15/2 hours = 7.5 hours
So, answer is D
Question: Rahul went to a shop and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
A.15
B.12.1
C.19.7
D.16.0
Answer: C.19.7
Explanation: Total cost of item he pirchased = 25
tot tax = 30 paise = 30/100
tax free = x
given tax rate = 6%
25-30/100 - x6/100 = 30/100
6(25-0.3-x) = 30
x=19.7
ANSWER C
Question: Buffalo gives 4 liter milk, cow gives (1/2) liter milk and goat gives 1/4 liter milk. you have to get 20 liter milk by 20 animals.what is the number of buffalos?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: Assume number of respective animals are x,y,z.
x+y+z=20---(1) as the total number of animal has to be 20
Amt of milk will be 4x+(1/2)y+(1/4)z=20---(2)
Solving equation 1 and 2 we get
15x+y=60 ----(3)
Since buffalo gives 4litre and total milk is 20, x < 5
But from eq 3, x cannot be more than 4;
Further if x=1 or 2; y>20... Not possible, since total animal is 20
Thus, x=3, y=15, z=2
Ans: 3 buffalos
ANSWER:C