RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The first three terms of a proportion are 3, 9 and 12. The fourth term is?
A.6
B.36
C.5
D.25
Answer: B.36
Explanation: Explanation:
(9*12)/3 = 36
ANSWER B
Question: Find the middle one when The sum of five consecutive even numbers is 65?
A.9
B.13
C.15
D.17
Answer: B.13
Explanation: Let the first number be n
Let the second number be n + 2
Let the third number be n + 4
Let the third number be n + 6
Let the third number be n + 8
n + n + 2 + n + 4 + n + 6 + n + 8= 65
Combine like terms:
5n + 20 = 65
5n = 65 - 20
5n = 45
5n = 45
n = 9
n + 2 = 11
n + 4 = 13
n + 6 = 15
n + 8 = 17
The middle number is 13
Answer: B
Question: A, B and C enter into a partnership. They invest Rs. 70,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. In what ratio will the profit be shared at the end of 3 years?
A.21 : 32 : 4
B.21 : 26 : 4
C.21: 12 : 1
D.21: 16 : 28
Answer: D.21: 16 : 28
Explanation: Sol.
A : B : C = (40000 * 36) : (80000 * 12 + 40000 * 24)
: (120000 * 24 + 40000 * 12) =252 : 192 : 336 = 21: 16 : 28
Answer D
Question: Three fill pipes A, B and C can fill separately a cistern in 3, 4 and 6 minutes respectively. A was opened first. After 1 minute, B was opened and after 2 minutes from the start of A, C was also opened. Find the time when the cistern will be full ?
A.2 1⁄9 min.
B.4 1⁄2 min.
C.3 3⁄4 min.
D.3 min.
Answer: A.2 1⁄9 min.
Explanation: Let cistern will be full in x min. Then,
part filled by A in x min + part filled by B in (x – 1) min + part filled by C in (x – 2)min = 1
⇒ x/3+x−1/4+x−2/6=1
⇒ 9x = 19 ⇒ x = 19⁄9 = 21⁄9 min.
Answer A
Question: The forth proportional to 20,8,15 is?
A.15
B.6
C.18
D.20
Answer: B.6
Explanation: Let the fourth proportional to 20,8,15 be x
then 20:8::15:x
20x = 8*15
x = 6
Answer is B
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.228
B.240
C.188
D.266
Answer: B.240
Explanation: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m.
Answer: B
Question: Marge has 3 pumps for filling her swimming pool. When all 3 pumps work at their maximum rates, the swimming pool is filled in 60 minutes. Pump 1's maximum rate is twice the maximum rate of pump 2 and four times the maximum rate of pump 3. How long would it take Marge to fill the pool if she used only pump 3 at its maximum rate ?
A.2hrs, 48mins
B.7hrs,
C.7hrs, 12mins
D.13hrs, 4mins
Answer: B.7hrs,
Explanation: The rate of pump 1 = 4x job/minute.
The rate of pump 2 = 2x job/minute.
The rate of pump 3 = x job/minute.
Given that x+2x+4x=1/60 --> x=1/420--> (time) = (reciprocal of rate) = 392 minutes = 7 hours
Answer: B.
Question: A machine puts c caps on bottles in m minutes. How many R hours will it take to put caps on b bottles?
A.60bm/c
B.R=bm/60c
C.bc/60m
D.60b/cm
Answer: B.R=bm/60c
Explanation: The machine puts c caps in m minutes or c caps in m/60 hours.
Rate = c/m/60 = 60c/m.
To put b caps the machine will take:-
Time = Work/Rate
T = b/60c/m = bm/60c
Answer is B.
Question: At the beginning of a year ,the owner of a jewel shop raised the price of all the jewels in his shop by x% and lowered them by x%. The price of one jewel after this up and down cycle reduced by Rs.100.The owner carried out the same procedure after a month.After this second up-down cycle,the price of that jewel was Rs.2304.Find the original price of that jewel(in Rs.)
A.2500
B.550
C.2600
D.2650
Answer: A.2500
Explanation: Solution: Let the original price = y,
After first change, It becomes,
y * (1+(x/100))
After second change, It becomes
y *(1+(x/100))(1-(x/100)) = y(1-(x/100)^2 )
Thus,
x2*y = 106 ------- (1)
x2 = 106/y
Now,
y(1-(106/10000y))2 = 2304(similar to above)
y(1-100/y)2 = 2304
y = 2500.
Answer: Option A
Question: Mirun travels the first 3 hours of her journey at 20 mph speed and the remaining 2 hours at 40 mph speed. What is the average speed of Mirun 's travel in mph?
A.26mph
B.27mph
C.22mph
D.28mph
Answer: D.28mph
Explanation: Explanation :
Average speed=Total Distance/Time.
Total distance travelled by Mirun = Distance covered in the first 3 hours + Distance covered in the next 2 hours.
Distance covered in the first 3 hours = 3Ã—20=60 miles
Distance covered in the next 2 hours= 2Ã—40=80 miles
Therefore, total distance travelled = 60+80=140 miles.
The total time taken = 3+2=5hours.
Hence, the average speed =140/5= 28mph.
Answer : D
Question: Three fifth of the roads from A to B are at least 5 miles long, and 5/6 of the roads from B to C are at least 5 miles long. If you randomly pick a road from A to B and then randomly pick a road from B to C, what is the probability that at least one of the roads you pick is at least 5 miles long?
A.1/6
B.1/4
C.2/3
D.3/4
Answer: C.2/3
Explanation: So please:
Find the probability of the event thatnoneof the roads you pick will be at least 5 miles long and subtract from 1 to get the probability thatat least oneof the roads you pick will be at least 5 miles long: P=1-2/5*5/6=2/3.
Answer: C.
Question: Each side of a rectangle is increased by 100% .By what percentage does the area increase?
A.300%
B.400%
C.500%
D.200%
Answer: A.300%
Explanation: original area=a*b where a and b are sides
after increase in side increase in area will be=(((2a*2b)-(a*b))*100)/(a*b)=300%
ANSWER:A
Question: If the number of boys in a class are 8 times the number of girls, which value can never be the total number of students?
A.27
B.45
C.81
D.42
Answer: D.42
Explanation: Explanation :
Let the number of girls = x and the number of boys = 8x
Then, total number of students = x + 8x = 9x
i.e., the total number of students must be a multiple of 9
From the given choices, 42 cannot be a multiple of 9.
Hence, 42 cannot be the total number of students.
Answer : D
Question: The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?
A.18%
B.28%
C.34%
D.39%
Answer: A.18%
Explanation: 1500 ---- 270
100 ---- ? => 18%
Answer: A
Question: If four coins are tossed, the probability of getting two heads and two tails is
A.3/8
B.3/5
C.3/9
D.3/1
Answer: A.3/8
Explanation: Since four coins are tossed, sample space = 24
Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = 6/24 = 3/8
Answer:A
Question: In how many different ways can 5 boys and 2 girls sit on a bench such that the girls always sit together?
A.360
B.720
C.1440
D.1800
Answer: C.1440
Explanation: We can think of the girls as one unit.
The number of ways to arrange 6 units in order is 6!
The girls can have different arrangements, so we multiply this by 2!
The number of ways to sit is 6!*2!=1440
The answer is C.
Question: In how many different ways can the letters of the word ‘CAN’ be arranged?
A.6
B.12
C.8
D.2
Answer: A.6
Explanation: A
6
The word SMART has 3 distinct letters.
Number of arrangements = 3!
= 3 × 2 × 1 = 6
Question: How long does a truck of 200 m long traveling at 60 kmph takes to cross a bridge of 180 m in length?
A.36.7
B.26.8
C.22.8
D.21.1
Answer: C.22.8
Explanation: D = 200 + 180 = 380 m
S = 60 * 5/18 = 50/3
T = 380 * 3/50 = 22.8 sec
Answer:C
Question: The principal that amounts to Rs. 4913 in 3 years at 6 1/4 % per annum C.I. compounded annually, is?
A.2368
B.2768
C.1121
D.4096
Answer: D.4096
Explanation: Explanation:
Principal = [4913 / (1 + 25/(4 * 100))3]
= 4913 * 16/17 * 16/17 * 16/17 = Rs. 4096.
Answer:D
Question: A person can row at 10 kmph in still water. If the velocity of the current is 2 kmph and it takes him 25 hour to row to a place and come back, how far is the place?
A.24km
B.30km
C.48km
D.120km
Answer: D.120km
Explanation: Speed of down stream = 10+2 = 12kmph
speed of upstream = 10-2 = 8kmph
Let the required distance be xkm
x/12 + x/8 = 25
2x+3x = 600
x = 120 km
Answer is D
Question: In the rectangular coordinate system, what is the area of triangle CDE with points
C=(3,3)
D=(4,1)
E=(0,8)
A.0.75
B.1
C.0.5
D.0.25
Answer: C.0.5
Explanation: Use the formula of the distance formula
square root (x2-x1)^2+(y2-y1)^2
Do this for each of the sides and then the value is given as C.
Question: A basket has 5 apples and 4 oranges. Three fruits are picked at random. The probability that at least 2 apples are picked is?
A.25/42
B.25/47
C.25/48
D.25/21
Answer: A.25/42
Explanation: Total fruits = 9
Since there must be at least two apples,
(⁵C₂ * ⁴C₁)/⁹C₃ + ⁵C₃/⁹C₃ = 25/42
Answer:A
Question: Two-third of two-fifth of three-fourth of a number is 36. What is the square root of four-fifth of that number?
A.9
B.12
C.14
D.16
Answer: B.12
Explanation: Explanation:
We have, 2/3 * 2/5 * 3/4 * X = 36
X = 180
Now, 4/5 * X ===> 4/5 * 180 = 144
√144 = 12
ANSWER: B
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 8 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
A.s.7248
B.s.4518
C.s.4518
D.s.4530
Answer: A.s.7248
Explanation: Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5 = Rs.7248
Answer: A
Question: The first doughnut is priced at $1 and then if you purchase additional doughnuts as dozens then the price is $6/dozen. What is the total number of doughnuts purchased if you paid $21?
A.33
B.35
C.37
D.39
Answer: D.39
Explanation: $21 = 3 * $6 + $3
The number of doughnuts is 3*12 + 3 = 39
The answer is D.
Question: If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is?
A.Rs.544
B.Rs. 8112
C.Rs.820
D.Rs.639
Answer: B.Rs. 8112
Explanation: Explanation:
Explanation:
A = 7500(26/25)2 =Rs. 8112
Answer:B
Question: If k > 0, x + 2k = y, and y + 5k = z, what is the ratio between z - x and y - x ?
A.3 to 1
B.3 to 2
C.4 to 3
D.7 to 2
Answer: D.7 to 2
Explanation: y-x = 2k
z-y = 5k
Let's add the two equations together:
z-x = 7k
The ratio of z-x to y-x is 7:2.
The answer is D.
Question: Nine men went to a hotel. Eight of them spent Rs.3 each over their meals and the ninth spent Rs.2 more than the average expenditure of all the nine. Determine the total money spent by them?
A.29.25
B.29.28
C.39.25
D.29.21
Answer: A.29.25
Explanation: Average of 9 = x
9x = 8 * 3 + x * 2 x = 3.25
Total = 9 * 3.25 = 29.25.A
Question: Two pipes P and Q can fill a tank in 15 min and 20 min respectively. Both the pipes are opened together but after 4 min, pipe P is turned off. What is the total time required to fill the tank?
A.10 min
B.12 min
C.14 min 40 sec
D.15 min 30 sec
Answer: C.14 min 40 sec
Explanation: filled in 4 min = 4(1/15 + 1/20) = 7/15
part = 1-7/15==>8/15
filled by Q in 1 min = 1/20
x=8/15*1*20==> 10 2/3 min==>10 min 40 sec
so tank will be full in (4 min +10 min 40 sec) = 14min 40 sec
ANSWER C
Question: If f(2, 3) = 17 and f(2, 4) = 24, what is the value of f(2, 5)?
A.107
B.127
C.147
D.33
Answer: D.33
Explanation: Solution:
The function f(a, b) = a3 + b2
f(2, 3) therefore is = 17 and
f(2, 4) = 24
Therefore, f(2, 5) = 33
Answer D
Question: A boat covers a certain distance downstream in I hour, while it comes back in 1½ hours. If the speed of the stream be 3 kmph. what is the speed of the boat in still Water?
A.12kmph
B.13kmph
C.15kmph
D.16kmph
Answer: C.15kmph
Explanation: Solution
Let the speed of the boat in still water be x kmph. Then,
Speed downsteram	= (x + 3) kmph.
Speed upsteram	= (x - 3) kmph.
= (x+3)x1
= (x - 3)x3/2 kmph.
= 2x+6 = 3x-9
x= 15 kmph.
Answer C
Question: How many integers k greater than 100 and less than 600 are there such that if the hundreds and the unit digits of k are reversed, the resulting integer is k + 99?
A.40
B.60
C.70
D.80
Answer: A.40
Explanation: Not sure if this is the shortest.. But this is how I did this
There are 8 sets of integers with hundreds and units digits exchanged that satisfies k + 99.
1. 102 | 201 (satisfies k+99, where k = 102)
2. 203 | 302 (satisfies k+99, where k = 203)
3. ...
4. 405 | 504
Each set has 10 such numbers.
1. 102 | 201 (still k+99 holds good)
2. 112 | 211
3. 122 | 221
4. 132 | 231
5. ...
6. ...
7. ...
8. ...
9. 182 | 281
10. 192 | 291
Therefore, 4 sets with 10 such number in each set will give 4 x 10 = 40 integers.
A
Question: In a container there are two solutions; solution A and solution B in the ratio of 3 : 4. If 8 litres of solution A is added, the ratio becomes 11:12. What is the total quantity in the container after adding the extra 8 litres ?
A.96 liters
B.104 liters
C.94 liters
D.92 liters
Answer: D.92 liters
Explanation: Let Solution A : Solution B be = 3x : 4x.
(Solution A / Solution B) = (3x + 8) / 4x = 11 / 12 =11 / 12
36x + 96 = 44x => 8x = 96 => x = 12.
Solution A + Solution B = 3x + 8 + 4x = 32 + 8 + 48 = 92 liters
Option D
Question: The simple interest on a sum of money will be Rs.600 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year?
A.1277
B.2977
C.1200
D.2769
Answer: C.1200
Explanation: P --- 10 ---- 600
P --- 5 ----- 300
3P --- 5 ----- 900
------
=> 1200
Answer: C
Question: How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction?
A.50 sec
B.16 sec
C.31 sec
D.26 sec
Answer: A.50 sec
Explanation: The distance to be covered = Sum of their lengths = 200 + 300
= 500 m.
Relative speed = 72 -36 = 36 kmph = 36 * 5/18
=10 mps.
Time required = d/s = 500/10
=50 sec.
Answer:A
Question: Jill has 35 gallons of water stored in quart, half-gallon, and one gallon jars. She has equal numbers of each size jar holding the liquid. What is the total number of water filled jars?
A.3
B.60
C.9
D.12
Answer: B.60
Explanation: Let the number of each size of jar = wthen 1/4w + 1/2w + w = 35 1 3/4w = 35w=20The total number of jars = 3w =60Answer: B
Question: The digital sum of a number is the sum of its digits. For how many of the positive integers 24-90 inclusive is the digital sum a multiple of 7?
A.10
B.8
C.14
D.16
Answer: A.10
Explanation: is there other way than just listing?
25
34
43
52
59
61
68
70
77
86
10 ways..
A
Question: In a camp, there is a meal for 80 men or 200 children. If 135 children have taken the meal, how many men will be catered to with remaining meal?
A.41
B.35
C.26
D.48
Answer: C.26
Explanation: C
26
There is a meal for 200 children.
135 children have taken the meal.
Remaining meal is to be catered to 65 children.
Now, 200 children 80 men.
65 children = (80 /200)x 65= 26 men.
Question: Two trains are moving in the same direction at 72 kmph and 36 kmph. The faster train crosses a man in the slower train in 18 seconds. Find the length of the faster train?
A.270
B.277
C.187
D.180
Answer: D.180
Explanation: Relative speed = (72 - 36) * 5/18 = 2 * 5 = 10 mps.
Distance covered in 18 sec = 18 * 10 = 180 m.
The length of the faster train = 180 m.
Answer: D
Question: 2+2+ 2^2 + 2^3 + 2^4 + 2^5 + 2^6 + 2^7 + 2^8 =
A. 2^9
B. 2^10
C. 2^12
D. 2^16
Answer: A. 2^9
Explanation: Let's see that: 2 + 2 is 2^2, then: 2^2 + 2^2 becomes 2 x 2^2 that is 2^3. You follow with the next: 2^3 + 2^3 is equal to 2 x 2^3 that is 2^4. Then is assumed right before 2^8: 2^8 x 2^8 becomes 2 x 2^8 that is 2^9. Option A, 2^9.
Question: In a friendship gang Andrew has 8 gang, in how many ways can he invite one or more of the gang to his house?
A.243
B.255
C.256
D.287
Answer: B.255
Explanation: Andrew can select one or more than one of his 8 gang.
=> Required number of ways = 28 – 1= 255.
B
Question: Find the value of (√1.21)/(√0.81) + (√1.00)/(√0.49) is
A.2.65
B.145/63
C.155/63
D.125/63
Answer: A.2.65
Explanation: (√1.21)/(√0.81) + (√1.00)/(√0.49)
11/9 + 10/7 => 2.65
Answer is A
Question: A car travels at a speed of 60 miles per hour. How far will it travel in 5 hours?
A.425 miles
B.625 miles
C.300 miles
D.225 miles
Answer: C.300 miles
Explanation: During each hour, the car travels 65 miles. For 5 hours it will travel
60 + 60 + 60 + 60 + 60 = 5 *65 = 300 miles correct answer C
Question: The calendar for the year 2007 will be the same for the year
A.2017
B.2018
C.2014
D.2016
Answer: B.2018
Explanation: Explanation :
For a year to have the same calendar with 2007 ,the total odd days from 2007 should be 0.
Year	2007	2008	2009	2010	2011	2012
Odd Days	1	2	1	1	1	2
Year	2013	2014	2015	2016	2017
Odd Year	1	1	1	2	1
Take the year 2014 given in the choice.
Total odd days in the period 2007-2013 = 5 normal years + 2 leap year
= 5 x 1 + 2 x 2 = 9 odd days
= 2 odd day (As we can reduce multiples of 7 from odd days which will not change anything)
Take the year 2016 given in the choice.
Number of odd days in the period 2007-2015 = 7 normal years + 2 leap year
= 7 x 1 + 2 x 2 = 11 odd days
= 4 odd days
(Even if the odd days were 0, calendar of 2007 will not be same as the calendar of 2016 because 2007 is not a leap year whereas 2016 is a leap year. In fact, you can straight away ignore this choice due to this fact without even bothering to check the odd days)
Take the year 2017 given in the choice.
Number of odd days in the period 2007-2016 = 7 normal years + 3 leap year
= 7 x 1 + 3 x 2 = 13 odd days
= 6 odd days
Take the year 2018 given in the choice.
Number of odd days in the period 2007-2017 = 8 normal years + 3 leap year
= 8 x 1 + 3 x 2 = 14 odd days
= 0 odd day (As we can reduce multiples of 7 from odd days which will not change anything)
Also, both 2007 and 2018 are not leap years.
Since total odd days in the period 2007-2017 = 0 and both 2007 and 2018 are of same type, 2018 will have the same calendar as that of 2007. Answer : Option B
Question: The rate of increase of the price of sugar is observed to be two percent more than the inflation rate expressed in percentage. The price of sugar, on January 1, 1994, is Rs. 18 per kg. The inflation rate for the years 1994 and 1995 are expected to be 6% each. The expected price of sugar on January 1, 1996 would be
A.20.99
B.21.9
C.25.4
D.20.19
Answer: A.20.99
Explanation: Explanation :
Increase in the price of sugar = (6+2)= 8%
Hence, price of the sugar on Jan 1, 1996
=> (18 * 108 * 108)/( 100 * 100 ) = Rs 20.99.
Answer : A
Question: If [P] denotes the least integer greater than or equal to P and [P] = 0, which of the following statements must be true?
A.P = 0
B.-1 < P <= 0
C.0 < P <= 1
D.-1 <= P < 0
Answer: B.-1 < P <= 0
Explanation: The answer for this is 0 < = P < = 1
However it is not available in the options. The match to the above is-1 < P <= 0
Answer = B
Question: A man can row 24 kmph in still water. It takes him thrice as long to row up as to row down the river. Find the rate of the stream?
A.6
B.12
C.18
D.15
Answer: B.12
Explanation: Let man's rate upsteam be X kmph
Then his rate of downstream = 3X kmph
Rate still water = 1/2 (3X + X) = 2X
2X = 24
X = 12
Rate of upstream = 12
Rate of downstream = 36
Rate of stream 1/2 ( 36 - 12) = 12 kmph
Answer is B.
Question: Two trains are moving in the same direction at 72 kmph and 36 kmph. The faster train crosses a girl sitting at window seat in the slower train in 32 seconds. Find the length of the faster train ?
A.170 m
B.100 m
C.270 m
D.320 m
Answer: D.320 m
Explanation: Explanation:
Relative speed = (72 - 36) x 5/18 = 2 x 5 = 10 mps.
Distance covered in 32 sec = 32 x 10 = 320 m.
The length of the faster train = 320 m.
ANSWER IS D
Question: If a man can cover 10 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?
A.288
B.162
C.145
D.135
Answer: D.135
Explanation: 10 m/s = 10 * 18/5 kmph
3 hours 45 minutes = 3 3/4 hours = 15/4 hours
Distance = speed * time = 10 * 18/5 * 15/4 km = 135 km.
Answer: D
Question: A certain fraction is equivalent to 2/5. If the numerator of the fraction is increased by 4 and the denominator is doubled, the new fraction is equivalent to 1/3. What is the difference of the numerator and denominator of the original fraction?
A. 49
B. 9
C. 28
D. 26
Answer: B. 9
Explanation: x/y = 2/5 -> 1
(x+4)/2y = 1/3 -> 2
Divide 1 by 2 :
=> 2x/(x+4) = 6/5
=> 5x = 3x + 12
=> x = 6
=> y = 5/2 * 6 = 15
so x - y = 9
The answer is B
Question: A five-digit number divisible by 3 is to be formed using numerical 0, 1, 2, 3, 4 and 5 without repetition. The total number R of ways this can be done is:
A.122
B.210
C.216
D.217
Answer: C.216
Explanation: We should determine which 5 digits from given 6, would form the 5 digit number divisible by 3.
We have six digits: 0, 1, 2, 3, 4, 5. Their sum=15.
For a number to be divisible by 3 the sum of the digits must be divisible by 3. As the sum of the six given numbers is 15 (divisible by 3) only 5 digits good to form our 5 digit number would be 15-0={1, 2, 3, 4, 5} and 15-3={0, 1, 2, 4, 5}. Meaning that no other 5 from given six will total the number divisible by 3.
Second step:
We have two set of numbers:
1, 2, 3, 4, 5 and 0, 1, 2, 4, 5. How many 5 digit numbers can be formed using these two sets:
1, 2, 3, 4, 5 --> 5! as any combination of these digits would give us 5 digit number divisible by 3. 5!=120.
0, 1, 2, 4, 5 --> here we can not use 0 as the first digit, otherwise number won't be any more 5 digit and become 4 digit. So, desired # would be total combinations 5!, minus combinations with 0 as the first digit (combination of 4) 4! --> 5!-4!=4!(5-1)=4!*4=96
120+96=216=R
Answer: C.
Question: Two employees A and B are paid a total of Rs. 550 per week by their employer. If A is paid 120 percent of the sum paid to B, how much is B paid per week?
A.Rs.130
B.Rs.140
C.Rs.150
D.Rs.250
Answer: D.Rs.250
Explanation: Let the amount paid to A per week = x
and the amount paid to B per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
D)
Question: wo passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
A.227
B.444
C.277
D.298
Answer: B.444
Explanation: 1h ----- 5
? ------ 60
12 h
RS = 16 + 21 = 37
T = 12
D = 37 * 12 = 444
Answer: B
Question: Five years ago, the average age of A, B, C and D was 45 years. With E Joining them now, the average of all the five is 49 years. The age of E is?
A.45
B.47
C.48
D.49
Answer: A.45
Explanation: Solution
5 years ago average age of A,B,C,D = 45 years
=> 5 years ago total age of A, B, C, D = 45 x 4 = 180 years
=> Total present age of A, B, C, D = 180 + 5x4 = 200 years
If E's present age is x years = 200+x/5= 49
x=45 years. Answer A
Question: When the positive integer k is divided by the positive integer n , the remainder is 11. If k/n = 61.2 , what is the value of n?
A.9
B.20
C.65
D.70
Answer: C.65
Explanation: Here's an approach that's based on Number Properties and a bit ofbrute forcemath:
We're told that K and N are both INTEGERS.
Since K/N = 61.2, we can say that K = 61.2(N)
N has tomultiply outthe .2 so that K becomes an INTEGER. With the answers that we have to work with, N has to be a multiple of 5. Eliminate A and E.
With the remaining answers, we can TEST THE ANSWERS and find the one that fits the rest of the info (K/N = 81.2 and K/N has a remainder of 11)
Answer B: If N = 20, then K = 1624; 1624/20 has a remainder of 4 NOT A MATCH
Answer C: If N = 55, then K = 4466; 4466/55 has a remainder of 11 MATCH.
Final Answer:
C
Question: The surface area of a sphere is 4πR^2, where R is the radius of the sphere. If the surface area of sphere A is eight times as large as the surface area of sphere B, then the radius of sphere A is how many times the radius of sphere B?
A.2
B.2√2
C.4
D.2π
Answer: B.2√2
Explanation: R1 : Radius of sphere A
R2 : Radius of sphere B
As per question,4πR1^2=8∗4πR2^2
or R12=8∗R2^2
or R1 = 2√2R2. Hence, B
Question: A sum of Rs. 2717 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
A.1642
B.1672
C.1632
D.2789
Answer: B.1672
Explanation: (x*8*3)/100 = ((2717 - x)*3*5)/100
24x/100 = 40755/100 - 15x/100
39x = 40755 => x = 1045
Second sum = 2717 – 1045
=1672
Answer:B