RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: At the end of year X, automobile installment credit accounted for 20% of all outstanding consumer installment credit. At that time automobile finance companies extended $57 billion of credit, or 1/3 of the automobile installment credit. How many billion dollars of consumer installment credit was outstanding at that time?
A.171
B.855
C.870
D.788
Answer: B.855
Explanation: System of Equations
a = (20/100) c
(1/3) a = 57 --> a = 171
Substitution
171 = (20100) c
c = (100/20) 171
- Calculate 171/20 * 100
The Correct answer B. The answer is 855.
Question: A man can row with a speed of 20 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is?
A.27
B.27
C.20
D.25
Answer: D.25
Explanation: M = 20
S = 5
DS = 20 + 5 = 25
Answer:D
Question: A positive number x is multiplied by 7, and this product is then divided by 3. If the positive square root of the result of these two operations equals x, what is the value of x ?
A. 7/3
B. 3/2
C. 4/3
D. 2/3
Answer: A. 7/3
Explanation: sq rt(7x/3) = x
=> 7x/3 = x^2
=> x = 7/3
Ans - A
Question: One fast typist type some matter in 3 hrs and another slow typist type the same matter in 5hrs. If both do combine in how much time they will take to finish.
A.1 hr 5 mins
B.1 hr 10 mins
C.1 hr 12 mins
D.3 hr 10 mins
Answer: C.1 hr 12 mins
Explanation: Fast's 1 hr work = 1/3
slow's 1 hr work = 1/5
1/3 + 1/5 = 8/15
they ll finish in 15/8hrs= 1 7/8 ==> 1 hr 12 mins
ANSWER:C
Question: A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
A.3 hrs 45 min
B.3 hrs 15 min
C.4 hrs
D.4 hrs 15 min
Answer: A.3 hrs 45 min
Explanation: time taken by one tap in hr = (4*1/6)=2/3
remaining part = (1-1/2)=1/2
x=3/4 hrs => 3hrs 45 min
ANSWER A
Question: Having received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.40 at the candy store. What is John’s weekly allowance?
A.$1.50
B.$2.00
C.$2.50
D.$3.00
Answer: A.$1.50
Explanation: x = 3x/5 + 1/3*2x/5 + 40
4x/15 = 40
x = 150 = $1.50
The answer is A.
Question: 10x + 2y = -4
4x + y = 1
In the system of equations above, what is the value of x?
A.-5
B.-3
C.-1
D.1
Answer: B.-3
Explanation: 10x + 2y = -4 can be written as 5x + y = -2
Let's subtract the second equation from this equation.
x = -3
The answer is B.
Question: If p and r are positive integers such that p > r > 1, what is the remainder when 92p × 5p+r + 11r × 6pr is divided by 10?
A.A.0
B.B.1
C.C.3
D.D.4
Answer: B.B.1
Explanation: 92p × 5p+r + 11r × 6pr--1=B
Question: There are 750 male and female participants in a meeting. Half the female participants and one-quarterof the male participants are Democrats. One-third of all the participants are Democrats. How many of the Democrats are female?
A.75
B.100
C.125
D.175
Answer: C.125
Explanation: Let m be the number of male participants and f be the number of female articipants in the meeting. Thetotal number of participants is given as 750.
Hence, we have m+f= 750
Now, we have that half the female participants and one-quarter of the male participants are Democrats.
Let d equal the number of the Democrats.
Then we have the equation f/2 + m/4 =d
Now, we have that one-third of the total participants are Democrats. Hence, we have the equation
d = 750/3 = 250
Solving the three equations yields the solution
f = 250,m= 500, and d= 250.
The number of female democratic participants equals half the female participants equals
250/2 = 125.
ANSWER:C
Question: If a - b = 3 and a2 + b2 = 29, find the value of ab.
A.10
B.12
C.13
D.14
Answer: A.10
Explanation: 2ab = (a2 + b2) - (a - b)2
= 29 - 9 = 20
ab = 10.
A
Question: The average weight of three boys M, N and P is 54 1/3 kg, while the Average weight of three boys N, Q and R is 53 kg. What is the average weight of M, N, P, Q and R?
A.52.4 kg
B.53.2 kg
C.53.8 kg
D.Data Inadequate
Answer: D.Data Inadequate
Explanation: Explanation :
Total weight of (M + N + P) = 54 1/3 x 3 kg = 163 kg.
Total weight of (N + Q + R) = (53 x 3) kg = 159 kg.
Adding both, we : M + 2N + P + Q + R = (163 + 159) kg = 322 kg.
So, to find the average weight of M, N, P, Q and R, we ought to know Ns weight, which is not given. So, the data is inadequate.
Answer : D
Question: City A and City B are 140 miles apart. Train C departs City A, heading towards City B, at 4:00 and travels at 40 miles per hour. Train D departs City B, heading towards City A, at 4:40 and travels at 20 miles per hour. The trains travel on parallel tracks. At what time do the two trains meet?
A.5:00
B.5:30
C.6:40
D.6:30
Answer: C.6:40
Explanation: Train C has traveled 20 mi in the half hour before Train D has started its journey.
140-20=120
40+20 =60 mph
120 mi/ 60 mph = 2 hrs
4:40pm + 2 hrs = 6:40pm
Answer:
C. 6:40
Question: If a2 - b2 = 8 and a*b = 2, find a4 + b4.
A.62
B.72
C.82
D.92
Answer: B.72
Explanation: a2 - b2 = 8 : given
a4 + b4 - 2a2b2 = 82 : square both sides and expand.
a*b = 2 : given
a2b2 = 22 : square both sides.
a4 + b4 - 2(4) = 82 : substitute
a4 + b4 = 72
correct answer B
Question: 3 OUT OF 1500 PARTS OF EARTH IS SULPHUR. WHAT IS THE PERCENTAGE OF SULPHUR IN EARTH
A.1/5
B.2/9
C.1/45
D.2/45
Answer: A.1/5
Explanation: REQUIRED PERCENTAGE=(3/1500*100)%=1/5%
CORRECT OPTIONS: A
Question: A train 200 m long can cross an electric pole in 5 sec and then find the speed of the train?
A.114
B.124
C.134
D.144
Answer: D.144
Explanation: Length = Speed * time
Speed = L/T
S = 200/5
S = 40 M/Sec
Speed= 40*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 144 Kmph
Answer:D
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
A.170 m
B.177 m
C.278 m
D.150 m
Answer: D.150 m
Explanation: Speed=(60 * 5/18) m/sec
= (50/3) m/sec Length of the train
= (Speed x Time) = (50/3 * 9) m
= 150 m.
Answer:D
Question: In 1 hour, a boat goes 10 km along the stream and 12 km against the stream. The speed of the boat in still water (in km/hr) is :
A.3 km/hr.
B.2 km/hr.
C.11 km/hr.
D.8 km/hr.
Answer: C.11 km/hr.
Explanation: Speed in still water = 1/2(10 + 12) km/hr
= 11 km/hr. ANSWER :C
Question: Three people are playing cards. What is the probability that a card drawn from a pack of 52 cards will be a diamond or a king?
A.1/3
B.2/11
C.4/13
D.5/13
Answer: C.4/13
Explanation: Here, n(S) = 52
There are 13 cards of diamond (including one king) and there are 3 more kings.
Let E = event of getting a diamond or a king.
Then, n(E) = (13 + 3) = 16
P (E) = 16 / 52 = 4/13
C
Question: If a computer program generates three-digit odd numbers using the numbers 9, 7, 0, 8, and 1, and the digits can be repeated, what is the probability that the number formed from the program is a multiple of three?
A.1/3
B.1/4
C.1/5
D.1/6
Answer: A.1/3
Explanation: A
Question: There are 42 distinct numbers in set M, there are 28 distinct numbers in set N, and there are 12 distinct numbers that are in both sets M and N. Set H is the set containing the elements that are in at least one of sets M and N. How many elements are in set H?
A.39
B.40
C.51
D.58
Answer: D.58
Explanation: {Total} = {M} + {N} - {Both}
{Total} = 42 + 28 - 12 = 58.
Answer: D.
Question: If a and b are positive integers and (2^a)^b = 2^5, what is the value of 2^a*2^b?
A.8
B.64
C.16
D.32
Answer: B.64
Explanation: 2^ab =2^5 therefore ab=5 either a=1or5 or b=5 or 1
therefore 2^a* 2^b = 2^(a+b)= 2^6 =64
B
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?
A.120000
B.298991
C.299992
D.188611
Answer: A.120000
Explanation: X * (105/100) * (105/100) * (105/100) = 138915
X = 138915/1.157625
X = 120000
Answer: A
Question: What percent is 6 gm of 1 kg?
A.1.5 %
B.0.5 %
C.0.6 %
D.3.5 %
Answer: C.0.6 %
Explanation: 1 kg = 1000 gm
6/1000 × 100 = 600/1000
=3/5 = 0.6 %
C)
Question: What is the average of first 21 multiples of 5 ?
A.A)70
B.B)77
C.C)55
D.D)81
Answer: C.C)55
Explanation: Required average = 7(1+2+....+21) / 21
(5/21)X ( (21x22) / 2 ) (because sum of first 21 natural numbers)
= 55
C
Question: Jamshid can paint a fence in 50 percent less time than Taimour can when each works alone. When they work together, they can paint the fence in 6 hours. How long would it take Taimour to paint the fence alone?
A.6 hours
B.8 hours
C.18 hours
D.24 hours
Answer: C.18 hours
Explanation: I believe the answer is C. Please see below for explanation.
if Jamshid can paint a dence in 50 percent less time then Taimour we can infer the following rate J = 2T
if working together they can do the job in 8 hours we can infer 1 = 2T+T * 6 => 1/18
Working alone Taimour can do the job in 1 = 1/18* hours => 18
Answer C
Question: A is faster than B. A and B each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then, A's speed is equal to?
A.12 km/hr
B.3 km/hr
C.17km/hr
D.16km/hr
Answer: B.3 km/hr
Explanation: Let A's speed = x km/hr. Then, B's speed = (7 - x) km/ hr.
So, 24/x + 24/(7 - x) = 14
x2 - 98x + 168 = 0
(x - 3)(x - 4) = 0 => x = 3 or 4.
Since, A is faster than B, so A's speed = 4 km/hr and B's speed
= 3 km/hr.
Answer:B
Question: Each of the 11 letters A, H, I, M, O, T, U, V, W, X and Z appears same when looked at in a mirror. They are called symmetric letters. Other letters in the alphabet are asymmetric letters. How many two letter computer passwords can be formed (no repetition allowed) with at least one symmetric letter?
A.2,145
B.6,435
C.12,100
D.2420
Answer: D.2420
Explanation: Since we are given atleast one symmetric letter in the three letter word we can take the following cases
1. All two
2. One symmetry and other two non
4. All the two letters can be arranged in 2 ways
( 11c2+ 11c1 * 15c2) *2
( 11*10/ 2 + 11 * 15 * 14 / 2 ) * 2
2420
IMO option D is the correct answer..
OA please...will correct if I missed anything..D
Question: A, B and C rents a pasture for Rs.870. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should C pay?
A.270
B.988
C.773
D.562
Answer: A.270
Explanation: 12*8 :16*9 = 18*6
8: 12: 9
9/29 * 870 = 270
Answer: A
Question: If Rs.3250 be divided among Ram, Shyam and Mohan in the ratio of 1/2:1/3:1/4 then the share of each are?
A.750
B.387
C.237
D.198
Answer: A.750
Explanation: Explanation:
1/2:1/3:1/4 = 6:4:3
Ram = 6/13 * 3250 = 1500
Shyam = 4/13 * 3250 = 1000
Mohan = 3/13 * 3250 = 750
Answer: A
Question: Average of five numbers is -10, and the sum of three of the numbers is 16, wat is the average of the other 2 numbers?
A.-33
B.34
C.-45
D.-56
Answer: A.-33
Explanation: Let the five numbers be a, b, c, d, e. Then their average is (a+b+c+d+e5)=10.(a+b+c+d+e5)=10.
Now three of the numbers have a sum of 16, say, a+b+c=16a+b+c=16.
So substitute 16 for a+b+ca+b+c in the average above: (16+d+e5)=10.(16+d+e5)=10.
Solving this equation for d+ed+e gives d+e=−66d+e=−66.
Finally, dividing by 2 (to form the average) gives (d+e2)=−33.(d+e2)=−33.
Hence, the answer is A: -33
Question: A child must place 5 different toys in 4 different bins. If any of the toys can go in any of the bins, in how many ways can the child place the toys into the bins?
A.6^6
B.6^4
C.4^5
D.4^4
Answer: C.4^5
Explanation: there are 4 different bins and each of the toy can go to any of these bins..
so answer 4âˆ—4âˆ—4âˆ—4âˆ—4=4^5
ANSWER:C
Question: 0.1+(0.1)^2+(0.1)^3=
A.0.1
B.0.111
C.0.1211
D.0.2341
Answer: B.0.111
Explanation: Explanation:
0.1+(0.1)^2+(0.1)^3=0.1+0.01+0.001=0.111
Answer: Option B
Question: 3 boys and 7 girls can complete John work in 10 days . But 4 boys and 6 girls need 8 days to complete the same work . In how many days will 10 girls complete the same work?
A.30 days
B.35 days
C.40 days
D.50 days
Answer: C.40 days
Explanation: Work done by 4 boys and 6 girls in 1 day = 1/8
Work done by 3 boys and 7 girls in 1 day = 1/10
Let 1 man does m work in 1 day and 1 woman does w work in 1 day. The above equations can be written as
4m + 6w = 1/8 ---(1)
3m + 7w = 1/10 ---(2)
Solving equation (1) and (2) , we get m=11/400 and w=1/400
Amount of work 10 girls can do in John day = 10 × (1/400) = 1/40
Ie, 10 girls can complete the work in 40 days
C
Question: If u, v, and w are consecutive integers such that u > v > w and the sum of u, v, and w is a multiple of 10, which of the following could be the value of u?
A.0
B.1
C.9
D.10
Answer: B.1
Explanation: We're given a very specific set of restrictions in this prompt:
1) U, V and W are CONSECUTIVE INTEGERS
2) U> V > W
3) U+V+W = a multiple of 10
We're asked which of the 5 answer COULD be the value of U given these restrictions. Rather than staring at the screen or doing layered math, we canbrute forcethe answers until we find one that fits these restrictions..
Answer A: U = 0
In this case, the numbers would be 0, -1, and -2. The sum = -3 which is NOT a multiple of 10. Eliminate A.
Answer B: U = 1
In this case, the numbers would be 1, 0, and -1. The sum = 0 which IS a multiple of 10. B IS the answer.
Final Answer:
B
Question: If x^2 + y^2 = 50, then the greatest possible value of y is between
A.2 and 3
B.4 and 5
C.5 and 6
D.7 and 8
Answer: D.7 and 8
Explanation: for the greatest possible value of y^2, we must minimize the value of x^2 i.e. lets say x^2 = 0
then we need to find a number y such that y^2 < 50. 7^2 = 49 and 8^2 = 64 so we can say that the maximum possible value of y can be a little more than 7 hence answer = between 7 and 8
hence D
Question: Oak trees line both sides of a street for a length of 5/8 of a kilometer. If there is 16 meters of space between the trees, and each tree is 1 meter wide, how many trees are there along the street?
A.a)	22
B.b)	23
C.c)	38
D.d)	44
Answer: C.c)	38
Explanation: There is a gap of 16 m between every 2 trees , each tree is 1 m wide.
5/8 of 1 km = 625 m
Lets assume that x trees are planted So equation is
x*1 +(x-1)*16 = 625
Solve for x and we get x = 38, answer is C
Question: One-sixth of the students at a nursery school are 5 years old or older. If 15 students have not yet reached their fourth birthday, and a total of 30 students are not between 4 years old and 5 years old, how many children are in the nursery school?
A.50
B.55
C.60
D.65
Answer: C.60
Explanation: x/6 students are > 5 yrs
15 students are < 4 yrs
x/6+15 = 25
x/6 = 10
x = 60
Answer: C
Question: In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with the remaining meal ?
A.38 men
B.32 men
C.34 men
D.30 men
Answer: D.30 men
Explanation: Explanation:
There is meal for 200 children. 150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children = 120 men
So, 50 Children = 120/200 * 50 = 30 men
Option D
Question: Some of 15%-intensity red paint is replaced with 25% solution of red paint such that the new paint intensity is 30%. What fraction of the original paint was replaced?
A.1/5
B.1/3
C.1/2
D.3/2
Answer: D.3/2
Explanation: Let total paint = 1
Let amount replaced = x
15 (1-x) + 25x = 30
x = 3/2
ANSWER:D
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 75 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
A.48
B.30
C.26
D.23
Answer: B.30
Explanation: Relative speed = 45 + 75 = 120 km/hr.
120 * 5/18 = 100/3 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 3/100 = 30 sec.
Answer:B
Question: On a certain number line, conditions are x<y<z<u<v and xyzuv>0. Which of the following must be true?
I xy>0 II zu>0 III zu>0
A.I only
B.I & II only
C.III only
D.II only
Answer: B.I & II only
Explanation: Givenx<y<z<u<v and xyzuv>0.
Suppose, for the product to be greater than 0, we can two variables as -ve or four variables can be -ve.
We are given : I xy>0 II yz>0 III uv>0
case 1: x and y can be negative/positive and if they are... we get greater than 0.
case 2: we have zu , then z and u both can be negative/positive and if they are... we get greater than 0.
case 2: we have uv , then z and u both can be negative/positive and if they are... we get greater than 0.
if zu both negative , then de both have to negative in order to get greater than 0. In order to xyzuv>0 , zuv can't be negative else we get -ve value, then we need to have either x or y as negative then ab can't be greater than 0.
so cde have to be positive.
xy > 0 , yz > 0 obviouly v will be positive , since we have information uv> 0 . ( Here we have relationship between cd and uv , where u is common).
Option B.
Question: 5^5 is equal to which of the following?
A.3,125
B.8,752
C.9,660
D.5,662
Answer: A.3,125
Explanation: A is the correct answer. We do not really need to calculate it. The last digit for 5^5 will be 5. Hence A is the correct answer
Question: Running at constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?
A.648
B.1800
C.2700
D.10800
Answer: B.1800
Explanation: If 6 machines can produce 270 bottles in one minute, 10 machines can produce 270*10/6 bottles in the same time. In 4 minutes, they would produce 4*270*10/6=1800
ANSWER:B
Question: If the positive integer y is divisible by 2, 4, and 8, then which of the following must y be divisible by?
I. 8
II. 31
III. 45
A.III only
B.I only
C.I and II only
D.II and III only
Answer: B.I only
Explanation: Answer = B
LCM of 2, 4, 8 = 8
Answer = 8
Answer: B
Question: The volumes of two cubes are in the ratio 27: 125, what shall be the ratio of their surface areas?
A.9 : 25
B.6:25
C.3:5
D.11:25
Answer: A.9 : 25
Explanation: Explanation:
a13 : a23 = 27 : 125
a1 : a2 = 3 : 5
6 a12 : 6 a22
a12 : a22 = 9 : 25
A)
Question: Phil’s only source of income comes from his job as a question writer. In this capacity, Phil earns a flat salary of $200 per week plus a fee of $9 for every question that he writes. Every year, Phil takes exactly two weeks of unpaid vacation to visit his uncle, a monk in Tibet, and get inspired for the next year. If a regular year consists of 52 weeks and the number of questions that Phil wrote in each of the past 5 years was an odd number greater than 20, which of the following could be Phil’s median annual income over the past 5 years?
A.$22,474
B.$25,673
C.$27,318
D.$28,495
Answer: D.$28,495
Explanation: Okay u just need less than one min to answer this question. any odd number greater than 20 means that that last digit must be 1,3,5,7, or 9. 9$ per week for every question. So (odd)(odd) will give odd digit. A and C out. (50 weeks) (200) = 10,000. subtract this amount from option B, D and E and u will find that only option D is divisible by 9 (once 10,000 is subtracted from 28495) so its the right choice..D..
Question: What is the lowest possible common multiple H of 2 distinct integers, each greater than 329?
A.330·331
B.330^2
C.33·331
D.660
Answer: D.660
Explanation: Lowest possible common multiple H of 2 distinct integers will have to be multiple of the number greater than 329...which 330..
so one number will be 330...another one will be 660..
Ans is D.
Question: A shopkeeper sold an article at $1170 and gained a 20% profit. What was the cost price?
A.$950
B.$975
C.$1000
D.$1025
Answer: B.$975
Explanation: Let x be the cost price.
1.2x = 1170
x = 1170/1.2 = 975
The answer is B.
Question: At present the ratio between the ages of Arun and Deepak is 5:7. After 6years, Arun's age will be 36 years. What is the age of Deepak at present?
A.35years
B.25years
C.42years
D.39years
Answer: C.42years
Explanation: Let the present ages of Arun and Deepak be 5x years and 7x years respectively
5x+6 = 36
5x = 30
x = 6
Deepak's age = 7x = 42years
Answer is C
Question: Joan took out a mortgage from hel local bank. Each monthly mortgage payment she makes must be triple the amount of the previous month's payment. If her first payment is $100, and the total amount she must pay back is $2952400, how many months will it take Joan to pay back her mortgage?
A.6
B.8
C.10
D.11
Answer: C.10
Explanation: Joan starts off with 100 $ .. which is to be tripled every month
Her monthly payments look like this :
100 , 300 , 900 , 2700 ......... Upto 2952400
This can be re written as :
100 x 1 , 100 x 3 , 100 x 9 , 100 x 27 ...... 100 x 29524
So we have 1 , 3 , 9 , 27 ..... 2652400 in GP
We know that a =1 , and r = 3 ( its easy to figure it out by looking at the question , but regardless of it being mentioned in the question we can still compute the value of r using the formula Tn = a3^n-1 ...)
Therefore to find the Sum of n terms of a GP we use this formula :
Sn = a (1-r^n) / 1 -r
Using this and plugging in the information we get ...
29524 = 1 - 3^n / 1-3 ; 1-3^n / -2
Cross multiplying we get
29524 x -2 = 1- 3^n
- 59048 = 1 - 3^n
- 59049 = - 3 ^n
59049 = 3 ^n (negatives cancel out)
59049 can also be re written as 3 ^ 10
Therefore ; 3 ^10 = 3 ^n
Thus n = 10 (C)
Question: At a contest with 2,500 participants, 1/2 of the people are aged 10 to 12. Next year, the number of people aged 10 to 12 will increase by 1/5. After this change, what percentage of the total 2,500 people will the 10- to 12-year-olds represent?
A.55%
B.60%
C.50%
D.45%
Answer: B.60%
Explanation: I just wanted to mention a couple of things here:
* this is a pure ratio question; the number 2,500 is completely irrelevant, and you can ignore it if you like. When we increase something by 1/5, we are multiplying it by 1 + 1/5 = 6/5, so the answer here must be (1/2)*(6/5) = 3/5 = 60 %.
Answer : B
Question: What leat value must be assigned to * so that the number 63576*2 is divisible by 8?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: Solution
The given number is divisible by 8, if the number 6x2 is divisible by 8.
Clearly, the least value of x is 3.
Answer C
Question: A grocer purchased a quantity of bananas at 3 pounds for $0.50 and sold the entire quantity at 4 pounds for $1.00. How many pounds did the grocer purchase if the profit from selling the bananas was $8.00?
A. 40
B. 60
C. 96
D. 120
Answer: C. 96
Explanation: Cost price of 1 pound of bananas = 0.5/3 = 1/6
Selling price of 1 pound of bananas = 1/4
Profit per pound = (1/4 - 1/6) = (1/12)
Total profit is given as 8
(1/12)*x = 8
x = 96
Answer: C
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8339 for a computer table, then what was the cost price of the computer table?
A.Rs.6289
B.Rs.6298
C.Rs.6290
D.Rs.6725
Answer: D.Rs.6725
Explanation: CP = SP * (100/(100 + profit%))
= 8339(100/124) = Rs.6725.
Answer: D
Question: In given series 1, 8, 27, 64, 124, 216, 343 only one number is incorrect. Find out that wrong number
A.120
B.126
C.127
D.124
Answer: D.124
Explanation: The numbers are 1^3=1
2^3=8
3^3=27
4^3=64
5^3=125
etc. So, 124 is wrong
ANSWER:D
Question: In the coordinate plane, points (x, 1) and (7, y) are on line k. If line k passes through the origin and has slope 1/7, then x - y =
A.6
B.7
C.5
D.8
Answer: A.6
Explanation: Line k passes through the origin and has slope 1/7 means that its equation is y=1/7*x.
Thus: (x, 1)=(7, 1) and (7, y) = (7,1) --> x-y=7-1=6.
Answer: A
Question: If the 30th january 2003 was thursday, what was the day day on 2nd march, 2003?
A.sunday
B.thursday
C.tuesday
D.saturday
Answer: A.sunday
Explanation: Explanation:
30th january, 2003 was thursday.
So, 6th, 13th, 20th, 27th february were all thursdays.
thus 2nd march, 2003 was 3 days after thursday, i.e. , sunday
Answer: A) sunday
Question: When all the students in a school are made to stand in rows of 54, 30 such rows are formed. If the students are made to stand in rows of 45, how many such rows will be formed ?
A.12
B.36
C.38
D.28
Answer: B.36
Explanation: Total number of students = 54 x 30
When arranged in rows of 45, number of rows formed are,
= 36.
Answer: B
Question: A train 250 m long, running with a speed of 50 km/hr will pass a tree in?
A.18sec
B.20sec
C.25sec
D.30sec
Answer: A.18sec
Explanation: Speed = 50 * 5/18 = 125/9 m/sec
Time taken = 250 *9/125 = 18 sec
Answer:A