RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 50 as remainder. Find the no. is?
A.220060
B.145778
C.220050
D.220800
Answer: C.220050
Explanation: (555 + 445) * 2 * 110 + 50 = 220000 + 50 = 220050
C
Question: The difference between the simple interest received from two different sources on Rs.1500 for 3 years is Rs.13.50. The difference between their rates of interest is
A.0.1%
B.0.2%
C.0.3%
D.0.4%
Answer: D.0.4%
Explanation: (1500xR1x3)/100-(100xR2x3)/100 =13.50
4500(R1-R2)=1350
R1-R2 = 1350/4500=0.3%
answer : D
Question: If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (4x - 2y) is odd
II. xy^2 is an even negative integer
III. (y^2 - x) is an odd negative integer
A.I only
B.I,II,III NOT TRUE
C.I and II
D.I and III
Answer: B.I,II,III NOT TRUE
Explanation: If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (3x - 2y) is odd
4x - is always negative and EVEN
2y - can be 0, when y=0, or always even integer (positivie or negative)
odd integer +/- even integer = always EVEN
I statement is always true
II. xy^2 is an even negative integer
y can be 0 => xy^2 = 0 (non-negative even) => II statement is not true
III. (y^2 - x) is an odd negative integer
y can be 0 => -x will be positive => III statement is not true
basing on above, only I statement will always be true
answer is B
Question: ake can dig a well in 16 days. Paul can dig the same well in 24 days. Jake, Paul and Hari together dig the well in 8 days. Hari alone can dig the well in
A.48
B.39
C.37
D.27
Answer: A.48
Explanation: Simple one. Let the total work to be done is 48 meters. Now Jake can dig 3 mts, Paul can dig 2 mts a day. Now all of them combined dug in 8 days so per day they dug 48/8 = 6 mts. So Of these 8 mts, Hari capacity is 1 mt.
So he takes 48 /1 = 48 days to complete the digging job.
Answer:A
Question: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl, and then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 10, what is the probability that one of the two cards drawn is numbered 4?
A.1/2
B.1/3
C.2/3
D.1/4
Answer: C.2/3
Explanation: There are 3 ways to get a total sum of 10.
2 of these ways include the number 4.
The probability that one of the cards is a 4 is 2/3
The answer is C.
Question: There are 10 points on a circle. A hexagon can be formed by linking 4 of the 10 points. How many such hexagons are possible?
A.60
B.120
C.200
D.210
Answer: D.210
Explanation: 4 points can be selected out of 10 points in 10C4 ways
=10 !/6!*4!=210
Ans D
Question: John draws a card from a pack of cards. What is the probability that the card drawn is a card of black suit?
A.3/78
B.4/8
C.6/5
D.1/2
Answer: D.1/2
Explanation: Explanation :
Total number of cards, n(S) = 52
Total number of black cards, n(E) = 26
P(E) =n(E)/n(S)=26/52=1/2
Answer: D
Question: A cyclist rides a bicycle 8 km at an average speed of 10 km/hr and again travels 10 km at an average speed of 8 km/hr. What is the average speed for the entire trip?
A.9.28
B.8.48
C.8.78
D.8.98
Answer: C.8.78
Explanation: distance = 18 km
time = 8/10 + 10/8 = (64 + 100) / 80 = 164 / 80 = 41 / 20 hours
average speed = (18 * 20) / 41 = 8.78 km/h
The answer is C.
Question: Question:	A sporting good store sells one type of baseball bat and one type of baseball. The cost for 2 bats and 4 balls is $180. The cost for 1 bat and 6 balls is $170, as well. If someone were to buy an equal number of bats and balls, at most how many bats can he purchase if he has a budget of $210 for the purchase?
Options:
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: IMO it should be C that is C
reason:
formed an equation... bat = b ball = c
2b+4c=180
1b+6c=170
solving both we get b that is bat = 50 and c that is ball = 20
new equation 210 to be divided in equal
3b+3c=210
3*50 + 3*20 = 210
150+60= 210
Question: The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
A.28
B.24
C.15
D.30
Answer: D.30
Explanation: Let the three parts be A, B, C. Then,
A : B = 2 : 3 and B : C = 5 : 8
= (5 x (3/5)):(8 x (3/5))
= 3 : 24/5
A : B : C = 2 : 3 : 24/5
= 10 : 15 : 24
B = (98 x 15/49)= 30.
Answer is D.
Question: Alfred buys an old scooter for $4700 and spends $1000 on its repairs. If he sells the scooter for $5800, his gain percent is?
A.5.45%
B.6.23%
C.1.75%
D.8.12%
Answer: C.1.75%
Explanation: C.P. = 4700+1000 = $5700
S.P. = $5800
Gain = 5800-5700 = $100
Gain% = 100/5700 * 100 = 1.75%
Answer is C
Question: Fresh grapes contain 80% water by weight and raisins obtained by drying fresh grapes contain 25% water by weight. How many kgs of fresh grapes are needed to get 40 kgs of raisins?
A.150 kgs
B.64kgs
C.72 kgs
D.65 kgs
Answer: A.150 kgs
Explanation: The weight of non-water in 40 kg of dried grapes (which is 100-25=75% of whole weight) will be the same as the weight of non-water in x kg of fresh grapes (which is 100-80=20% of whole weight), so
40*0.75 = x*0.2
--> x = 150.
Answer: A.
Question: If a, b, c, d, e and f are integers and (ab + cdef) < 0, then what is the maximum number E of integers that can be negative?
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: Minimuum should be 1
Maximum should be 4:
1 out of a or b to make the multiplication negative
3 out of c, d, e or f to make the multiplication negative.
Negative+Negative<0
Answer:C
maximum will be 5..
you dont require both the multiplicatin to be negative for entire equation to be negative...
any one a or b can be negative to make ab negative and it can still be more(away from 0) than the multiplication of 4 other -ve numbers...
actually by writing minimum required as 1 out of 6,you are actually meaning 5 out of 6 also possible as you will see E=5 or 1 will give you same equation..
ans D
Question: 7 teams compete in a track competition. If there are 14 events in the competition, no event ends in a tie, and no team wins more than 3 events, what is the minimum possible number of teams that won at least one event?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: 3(max wins) x 4 = 12 (4 teams win three events)
One team wins the other 2 events.
The answer is C.
Question: A man swims downstream 72 km and upstream 45 km taking 10 hours each time; what is the speed of the current?
A.1.55
B.1.85
C.1.65
D.1.35
Answer: D.1.35
Explanation: 72 --- 10 DS = 7.2
? ---- 1
45 ---- 10 US = 4.5
? ---- 1 S = ?
S = (7.2 - 4.5)/2 = 1.35
Answer:D
Question: A father is now three times as old as his son. Eight years back, he was four times as old as his son. The age of the son (in years) is
A.12
B.24
C.18
D.27
Answer: B.24
Explanation: If father's age is F and son's age is S, then
F=3S
and
F-8 = 4*(S-8)
3S-5 =4S-32
S=24
F=72 years
ANSWER:B
Question: In a group of 100 people, 90 have an age of more 30 years, and the others have an age of less than 20 years. If a person is selected at random from this group, what is the probability the person's age is less than 20?
A.0.1
B.0.55
C.0.65
D.0.75
Answer: A.0.1
Explanation: Number of people whose age is less than 20 is given by
100 - 90 = 10
Probability P that a person selected at random from the group is less than 20 is given by
10 / 100 = 0.1
correct answer A
Question: A certain auto manufacturer sold 8% fewer vehicles in 2007 than in 2006. If the manufacturer sold 2.1 million vehicles in 2006, how many vehicles, to the nearest 10,000, did the manufacturer sell in 2007?
A.63,000
B.1,930,000
C.2,030,000
D.2,040,000
Answer: B.1,930,000
Explanation: Let's assume in 2006 the manufacturer sold X.
In 2007 he sold X-8/100(X)
If sales in 2006,X= 2.1 million find X-8/100(X)
(2.1 x 10^6)-8/100(2.1 x 10^6)
2100000-168000=1,932,000-----> 1,930,000(approx)
ANSWER:B
Question: In a 100 member association consisting of men and women, exactly 10% of men and exactly 20 % women are homeowners. What is the maximum number of members who are homeowners?
A.29
B.27
C.25
D.23
Answer: A.29
Explanation: Solution simple
Out of 100 10% are male i.e 10 and 20% are female i.e 20 , so total homeowner is 30.
Now min number homeowner is 10 and max is 30 so question ask us to find maximum and 29 has maximum value among all option.
So ans is 29.
Ans: A
Question: 12 men work 8 hours per day to complete the work in 10 days. To complete the same work in 4 days, working 15 hours a day, the number of men required?
A.15days
B.12days
C.16days
D.18days
Answer: C.16days
Explanation: That is, 1 work done = 12 × 8 × 10
Then, 12 8 × 10 = ? × 15 × 6
? (i.e. No. of men required) = 12 × 8 × 10/15× 6 = 16 days
C)
Question: A sum fetched a total simple interest of Rs. 1000 at the rate of 10 p.c.p.a. in 4 years. What is the sum?
A.2500
B.2800
C.3500
D.1900
Answer: A.2500
Explanation: Sol.
Principal = Rs. [100 * 1000 / 10 * 4] = Rs. [100000 / 40] = Rs. 2500.
Answer A
Question: David and Rachel are getting married. The extended family wants to have its picture taken, but David's father is unwilling to stand next to Rachel's mother. How many options does the photographer have to arrange the 6 family members in a row for the picture?
A.9!
B.9×8!
C.4x5!
D.10!/2!
Answer: C.4x5!
Explanation: In how many ways David's father and Rachel's mother can stand together? Consider them as one unit: {F, M}. So, we'd have 9 units {F, M}, 1, 2, 3, 4, which can be arranged in 9! ways. David's father and Rachel's mother within their unit can be arranged in 2! ways. Therefore, David's father and Rachel's mother can stand together in 5!*2! ways.
Total - Restriction =
= 6! - 5!*2! =
= 5!(6- 2!) =
= 4*5!.
Answer: C.
Question: There are 6 gentlemen and 5 ladies to dine at a round table. In how many ways can they seat themselves so that no two ladies are seated together.
A.85400
B.36400
C.86400
D.65600
Answer: C.86400
Explanation: 6 men can be arranged around a table in (6-1)!=5! ways.
Now, if we place each woman between the men then no two women will be together. There are 6 available slots between the men, thus 6C5=6 is the number of ways we can choose 5 slots out of 6 for the women.
Next, these 5 women can be arranged in 5! ways, hence the total number of ways is 5!*6*5!=86,400.
Answer: C.
Question: The greatest common factor of 16 and the positive integer n is 4, and the greatest common factor of n and 45 is 3. Which of the following could be the greatest common factor of n and 420?
A.15
B.48
C.64
D.84
Answer: D.84
Explanation: n includes the factors 2^2 (but not 2^3) and 3 (but not 3^2 or 5)
420 = 4*3*5*7
The GCF could be 12 or 84.
The answer is D.
Question: What approximate value should come in place of the question mark (?) in the following equation?
1.542 × 2408.69 + 8134.632 = ?
A.14600
B.11800
C.12030
D.16400
Answer: B.11800
Explanation: Explanation 3700 + 8100 = 11800
Answer B
Question: Carol spends 1/4 of her savings on a stereo and 1/3 less than she spent on the stereo for a television. What fraction of her savings did she spend on the stereo and television?
A.1/4
B.2/7
C.5/12
D.1/2
Answer: C.5/12
Explanation: Total Savings = S
Amount spent on stereo = (1/4)S
Amount spent on television = (1-1/3)(1/4)S = (2/3)*(1/4)*S = (1/6)S
(Stereo + TV)/Total Savings = S(1/4 + 1/6)/S = 5/12
Answer: C
Question: If a copier makes 3 copies every 4 seconds, then continues at this rate, how many minutes will it take to make 9,000 copies?
A.60
B.100
C.120
D.200
Answer: D.200
Explanation: Let x = seconds to make 9000 copies.
We get: 3/4 = 9000/x
Cross multiply to get: 3x = (4)(9000)
Simplify: 3x = 36,000
Solve: x = 12,000 SECONDS
There are 60 seconds in a minute.
12,000/60 = 200
So, it takes 200 MINUTES to make 9000 copies
Answer: D
Question: A man can row 30 km downstream and 20 km upstream in 4 hours. He can row 45 km downstream and 40 km upstream in 7 hours. Find the speed of man in still water?
A.92.5 kmph
B.17.5 kmph
C.15.5 kmph
D.12.5 kmph
Answer: D.12.5 kmph
Explanation: Let the speed of the man in still water be a kmph and let the speed of the stream be b kmph.
Now 30/(a + b) + 20/(a - b) = 4 and 45/(a + b) + 40/(a - b) = 7
Solving the equation, the speed of man in still water is 12.5 kmph.
Answer: D
Question: Ten cards numbered 1 to 10 are placed in a box, mixed up thoroughly and then one card is drawn
randomly. If it is known that the number on the drawn card is more than 3, what is the probability
that it is an even number?
A.1/3
B.1/5
C.4/7
D.7/4
Answer: C.4/7
Explanation: Let A be the event ‘the number on the card drawn is even’ and B be the
event ‘the number on the card drawn is greater than 3’. We have to find P(A|B).
Now, the sample space of the experiment is S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Then A = {2, 4, 6, 8, 10}, B = {4, 5, 6, 7, 8, 9, 10}
and A n B = {4, 6, 8, 10}
Also P(A) = 5/2, P(B) = 7/10 and P(A n B) = 4/10
Then P(A|B) = P(A n B)/P(B) = (4/10)/(7/10) = 4/7
C
Question: How many different arrangements of letters are possible if three letters are chosen from the letters A through E and the letters E and A must be among the letters selected?
A.72
B.64
C.36
D.18
Answer: D.18
Explanation: Since A and E must be among 3 letters then the third letter must be out of B, C and D. 3C1 = 3 ways to choose which one it'll be. Now, 3 different letters (A, E and the third one) can be arranged in 3!=6 ways, so the final answer is 3*6=18.
Answer: D.
Question: Indu gave Bindu Rs.4375 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
A.1
B.2
C.7
D.4
Answer: C.7
Explanation: 4375 = D(100/4)2
D = 7
Answer:C
Question: A meeting has to be conducted with 4 managers. Find the number of ways in which the managers may be selected from among 7 managers, if there are 2 managers who refuse to attend the meeting together.
A.18
B.21
C.25
D.30
Answer: C.25
Explanation: The total number of ways to choose 4 managers is 7C4 = 35
We need to subtract the number of groups which include the two managers, which is 5C2 = 10.
35 - 10 = 25
The answer is C.
Question: In how many different ways can the letters of the word ORGANISE be arranged in such a way that all the vowels always come together and all the consonants always come together?
A.576
B.1152
C.2880
D.1440
Answer: B.1152
Explanation: The word ORGANISE has 4 vowels and 4 consonants.
Now, both groups (vowels and consonants) can be treated as two letters. This can be arranged in 2! ways.
Now, the 4 letters of each group can be arranged.in 4! ways.
So, total possible ways of arrangement
= 2! × 4! × 4!
= 2 × 24 × 24 = 1152.
Answer B
Question: In a certain school, 20% of the students are below 8 yrs of age. The number of students above 8 yrs of age is (2/3) of the number of students of 8 years age which is 96. What is the total number of students in the school?
A.237
B.200
C.267
D.176
Answer: B.200
Explanation: Explanation:
Let total students be x.
⇒ 0.2x + 2323 × 96 + 96 = x
⇒ x = 200
Answer: B
Question: Which of the following is closer to (22!+21!)/(22!-21!)?
A.49
B.36
C.1
D.16
Answer: C.1
Explanation: Notice that 22! = (22)(21!), so we can factor out 21! from top and bottom.
(22!+21!)/(22!-21!)=[21!(22+1)]/[21!(22-1)]
= (22+1)/(21-1)
= 23/21
≈ 1
Answer: C
Question: If 3 strawberry vines produce 30 fruit and 20 strawberry vines produce 200 fruit, how many fruit do 50 strawberry vines produce?
A.5
B.50
C.500
D.5000
Answer: C.500
Explanation: 3 x ? = 30
20 x ? = 200
50 x ? = ?
3 x 10 = 30
20 x 10 = 200
Therefore, each strawberry vine makes 10 fruits.
50 x 10 = 500
answer: c
Question: A credit card number has 6 digits (between 1 to 9 inclusive). The first two digits are 12 in that order, the third digit is bigger than 6, the fourth digit is divisible by 3, and the fifth digit is 4 times the sixth. How many different credit card numbers are possible?
A.12
B.15
C.18
D.24
Answer: C.18
Explanation: The first two digits are fixed.
The third digit can be 7, 8, or 9 so there are 3 choices.
The fourth digit can be 3, 6, or 9 so there are 3 choices.
The fifth digit depends entirely on the sixth digit.
The sixth digit can be 1 or 2 so there are 2 choices.
The number of possibilities is 3*3*2 = 18
The answer is C.
Question: The breath of a rectangle is three- seventh of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the length is 10 units?
A.310 sq.units
B.110 sq.units
C.210 sq.units
D.105 sq.units
Answer: C.210 sq.units
Explanation: Given that the area of the square = 4900 sq.units
=> Side of square = √4900 = 70units
The radius of the circle = side of the square = 49 units breath of the rectangle = 3/7 * 49 = 21units
Given that length = 10 units
Area of the rectangle = lb = 21 * 10 = 210 sq.units
Answer:C
Question: Each of the integers from 0 to 9, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 12?
A.8
B.4
C.5
D.6
Answer: A.8
Explanation: i'm not sure i got the question right, if it is what i think it is, then 8 should be the right answer
0,1,2,3,4,5, will not have 2 slip sum of 10, add another (either 6,7,8 or 9) and we'll have a pair with sum 12
Ans:8
Question: Out of the fractions 4/7, 5/13, 6/11, 3/5 and 2/3 which is the second smallest fraction ?
A.4/7
B.5/13
C.6/11
D.3/5
Answer: C.6/11
Explanation: Answer
4/7 = 0.57,
5/13 = 0.38,
6/11 = 0.54,
3/5 = 0.6 and
2/3 = 0.67
Clearly, the second smallest fraction is 6/11
Correct Option: C
Question: Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.140. How much was lent at 5%?
A.2978
B.2681
C.2689
D.1000
Answer: D.1000
Explanation: (x*5*1)/100 + [(2500 - x)*6*1]/100
= 140
X = 1000
Answer: D
Question: The difference between a number and its two-fifth is 510. What is 10% of that number?
A.12.75
B.85
C.204
D.224
Answer: B.85
Explanation: Let the number be x. Then,
x - 2/5 x = 510
x = (510 * 5)/3 = 850
10% of 850 = 85.
ANSWER:B
Question: A train of 40 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
A.6
B.3
C.4
D.3.9
Answer: D.3.9
Explanation: D = 40 * 60 + 1500 = 3900 m
T = 3900/60 * 18/5 = 234 sec = 3.9 mins
Answer:D
Question: Two mixtures A and B contain milk and water in the ratios 2:5 and 5:4 respectively. How many gallons of A must be mixed with 90 gallons of B so that the resultant mixture contains 40% milk?
A.144
B.122.5
C.105.1
D.72
Answer: B.122.5
Explanation: Mixture A: 2:5 ratio of Milk:Water
Mixture B: 5:4 ratio of Milk:water
90 gallons mixture B with a ratio of 5:4 = 50 gallons of milk and 40 gallons of water 90/(5+4) = 10. 10*5 = 50 and 10*4 = 40.
(50+(2/7x))/(90+x) = .40
50+(2/7x)=.4(90+x)
50+(2/7x)=(2/5x)+36
50+(10/35x)=(14/35x) +36
4/35x=14
4x=14*35
4x=490
x=122.5 gallons
ANSWER:B
Question: 0.1 decates ago, Vijaya was quadrice as old as her daughter Simran. 0.6 decades hence, Vijaya’s age will beat her daughter’s age by 0.9 decades. The proportion of the current ages of Vijaya and Simran is : [ 0.1 Decates =1 Year; quadrice = 4 times]
A.8:1
B.10:2
C.11:4
D.13:4
Answer: D.13:4
Explanation: Explanation:
Let, Ages of Vijaya and Simran – 1 year ago was 4A and A years correspondingly.
Then, [(4A + 1) + 6] – [(A + 1) + 6] = 9
3A = 9 A = 3
Needed Ratio = (4A + 1) : (A + 1) = 13 : 4.. Answer: D
Question: The total car population in a Mumbai is 2,94,00 out of which 1,50,00 are made by Honda. Out of every 100 Honda cars, 98 are red in color, but only 53% of the total car population is red. Find the % of non-Honda cars that are red
A.5.456%
B.6.124%
C.6.125%
D.7.256%
Answer: C.6.125%
Explanation: Total Car.29.10 i.e., Honda +non Honda = 29400 Given: Whim. tractor .150W
Now,5346 of 2..00 = Honda +Red Non-Honda 29400 .:4 =15582 Thus...El Mall... 1.0 Now Honda 15582 flow, Non-. Honda =15582 - 15.582-14700=8B2 96 non-Honda =1=1.100 = 6.125%
C
Question: Points M(9,4) and N(5,8) lie on the xy - plane. What is the midpoint of line segment MN?
A.(7,6)
B.(0,5)
C.(0, (136^(1/2))/2)
D.(3/2,0)
Answer: A.(7,6)
Explanation: The midpoint of a segment is exactly halfway between its endpoints and it's location can be found using the Midpoint Theorem, which states:
• The x-coordinate of the midpoint is the average of the x-coordinates of the two endpoints.
• Likewise, the y-coordinate is the average of the y-coordinates of the endpoints.
So, x=(9+5)/2=7 and y=(4+8)/2=6 --> coordinates of the midpoint are (7, 6).
Answer: A.
Question: A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
A.2:6
B.2:6
C.2:3
D.2:4
Answer: C.2:3
Explanation: Let the principal be P and rate of interest be R%.
Required ratio = [(P * R * 6)/100] / [(P * R * 9)/100]
= 6PR/9PR = 6/9
= 2:3
Answer: C
Question: The ratio between a two-digit number and the sum of the digits of that
number is 4 : 1.If the digit in the unit's place is 3 more than the digit in the ten’s place, what is the number?
A.47
B.36
C.58
D.25
Answer: B.36
Explanation: Let the ten's digit be x. Then, unit's digit = (x + 3).
Sum of the digits = x + (x + 3) = 2x + 3. Number = l0x + (x + 3) = llx + 3.
11x+3 / 2x + 3 = 4 / 1 => 11x + 3 = 4 (2x + 3) => 3x = 9 => x = 3.
Hence, required number = 11x + 3 = 36.
Answer is B.
Question: The ratio of number of ladies to gents at a party was 1 : 2, but when 2 ladies and 2 gents left, the ratio became 1 : 3. How many people were originally present at the party?
A.6
B.9
C.12
D.10
Answer: C.12
Explanation: Let number of ladies = x
then, number of gents = 2x
Now, x−2/2x−2=1/3⇒ 3x - 6 = 2x - 2
⇒ x = 4
∴ Total number of people originally present = 4 + 8 = 12
Answer C
Question: 15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men?
A.16
B.30
C.86
D.27
Answer: C.86
Explanation: 3W = 2M
15M ------ 21 * 8 hours
21 W ------ x * 6 hours
14 M ------ x * 6
15 * 21 * 8 = 14 * x * 6
x = 30
Answer: C
Question: A student traveled 30 percent of the distance of the trip alone, continued another 20 miles with a friend, and then finished the last half of the trip alone. How many miles long was the trip?
A.240
B.200
C.160
D.100
Answer: D.100
Explanation: Let x be the total length of the trip.
0.3x + 20 miles + 0.5x = x
20 miles = 0.2x
x = 100 miles
The answer is D.
Question: A and B enter into a partnership with respective capitals of Rs. 20,000 and Rs. 40,000. At the end of the year, the total profit is Rs. 27,000. If A receives Rs. 15,000 as both his salary and profit, then what is his salary?
A.Rs. 2000
B.Rs. 4000
C.Rs. 6000
D.Rs. 3000
Answer: C.Rs. 6000
Explanation: Explanation:
A's capital : B 's capital
20000 : 40000 = 1 : 2
Since, the time period is fixed, the profit is distributed in the ratio of capital 1 : 2
Profit of A = (1/3) * 27,000 = Rs. 9,000
Salary of A = Rs. (15000 – 9000) = Rs. 6000
ANSWER: C
Question: If the ratio of the sum of the first 6 terms of a G.P. to the sum of the first 3 terms of the G.P. is 217, what is the common ratio of the G.P?
A.3
B.1/3
C.2
D.6
Answer: D.6
Explanation: 217=(a1+a2+a3+a4+a5+a6)/(a1+a2+a3)
Factorize the same terms
217=1+(a4+a5+a6)/(a1+a2+a3)
Write every term with respect to r
a1=a1
a2=a1*r^1
a3=a1*r^2
.........
217=1+(a1(r^3+r^4+r^5))/(a1(1+r^1+r^2))
216=(r^3 (1+r^1+r^2))/((1+r^1+r^2))
216=r^3
r=6
D
Question: Find the sum of all 3 digit natural numbers, which are divisible by 8
A.61376
B.54411
C.612314
D.64170
Answer: A.61376
Explanation: The three digit natural numbers divisible by 8 are
104, 112, 120, …. 992.
Let Sndenote their sum. That is, Sn = 104 112 120 128 , 992 g + + + + + .
Now, the sequence 104, 112, 120, g, 992 forms an A.P.
a=104, d=8, l=992
n=l-a/d
n=112
S112=n/2(a+l)=61376
ANSWER A 61376
Question: If x=3y=4z, what is z+y, in terms of x?
A.3x/5
B.4x/9
C.11x/13
D.7x/12
Answer: D.7x/12
Explanation: x=3y=4z
x/4 = z
and y = x/3
z+y = x/4 + x/3 = 7x/12
Answer is D