RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Cara and Dan drive at constant speeds toward each other on a highway. Cara drives at a constant speed of 32 km per hour. At a certain time they pass by each other, and then keep driving away from each other, maintaining their constant speeds. If Cara is 110 km away from Dan at 7 am, and also 110 km away from Dan at 11 am, then how fast is Dan driving (in kilometers per hour)?
A.20
B.23
C.26
D.29
Answer: B.23
Explanation: Cara and Dan complete 220 km / 4 hours = 55 km/hour
Dan's speed is 55-32=23 km/hour
The answer is B.
Question: Of the 3,600 employees of Company X, 16/25 are clerical. If the clerical staff were to be reduced by 1/4, what percent of the total number of the remaining employees would then be clerical?
A.57%
B.22.2%
C.20%
D.12.5%
Answer: A.57%
Explanation: Let's see, the way I did it was
16/25 are clerical out of 3600 so 2304 are clerical
2304 reduced by 1/4 is 2304*1/4
so it reduced 576 people , so there is 1728 clerical people left
but since 576 people left, it also reduced from the total of 3600 so there are 3024 people total
since 1728 clerical left / 3024 people total
you get (A) 57%
Question: What is the probability of getting at least one six in a single throw of three unbiased dice ?
A.31/216
B.91/216
C.125/216
D.81/216
Answer: B.91/216
Explanation: Explanation :
Three cases arise:
Case 1: When only one dice shows up a six
This dice can be any of the 1st, 2nd or 3rd dice. Find the probability for these three independent events and add them up to get the total probability
Probability that only 1st dice shows up a six: (probability that first dice shows up a 6) and (probability that second dice shows up other than 6) and (probability that third dice shows up other than 6)
=(1/6)*(5/6)*(5/6)
=25/216
similarly probability that 2nd dice shows up a six: (5/6)*(1/6)*(5/6) = 25/216
And, probability that 3rd dice shows up a six: (5/6)*(5/6)*(1/6) = 25/216
So probability that only one dice shows up a six: (25/216)+(25/216) +(25/216) = 75/216
Case 2:When two dice show up a six
Total number of ways of selecting a pair of dice that show up a six from a set of 3 dice are: 3C2=3
Find the probability of getting six on a pair of dice and multiply it by total number of such possible pairs
Probability of getting a six on a pair of dice = (1/6)*(1/6)*(5/6) = 5/216
So, total probability = 3*(5/216) = 15/216
Case 3: When all dice show up a six
In this case total probability is just (1/6)*(1/6)*(1/6) = 1/216
So total probability of getting at least one six = (75/216) + (15/216) + (1/216) = 91/216
Answer : B
Question: 30 is subtracted from 40% of a number, the result is 50. Find the number?
A.200
B.997
C.266
D.288
Answer: A.200
Explanation: (40/100) * X – 30 = 50
4X = 800
X = 200
Answer:A
Question: A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that atleast one bulb is good.
A.125/127
B.127/125
C.125/126
D.126/125
Answer: C.125/126
Explanation: Required probability = 1 - 1/126 = 125/126
Answer: C
Question: A retailer bought a machine at a wholesale price of $99 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price of the machine?
A.81
B.100
C.120
D.132
Answer: D.132
Explanation: My solution: Wholesale Price= 99
Retail Price, be = x
He provides 10 % discount on Retail price= x-10 x/100
This Retail price = 20 % profit on Wholesale price
x-10 x/100 = 99+ 1/5(99)
x=132;
ANSWER:D
Question: Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 540 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)
A.8/3
B.3/8
C.8/5
D.12/5
Answer: D.12/5
Explanation: Distance traveled by Eddy = 540 km
Time taken by Eddy = 3 hours
Average speed of Eddy = 540/3 = 180 km/hour
Distance traveled by Freddy = 300 km
Time taken by Freddy = 4 hours
Average speed of Freddy = 300/4 = 75 km/hour
Ratio of average speed of Eddy to Freddy = 180/75 = 12/5
Answer D
Question: A group of 10 representatives is to be selected out of 16 seniors and 10 juniors. In how many different ways can the group be selected, if it should have 5 seniors and 5 juniors?
A.16C₅ * 10
B.16C₇ * 10
C.16C11 * ¹⁰C₅
D.12 * ¹⁰C₅
Answer: C.16C11 * ¹⁰C₅
Explanation: Here, five seniors out of 16 seniors can be selected in 16C₅ ways. Also, five juniors out of ten juniors can be selected ¹⁰C₅ ways. Hence the total number of different ways of selection = 16C₅ * ¹⁰C₅ = 16C11 * ¹⁰C₅
since 16C₅ = 16C11
ANSWER:C
Question: A, B and C enter into a partnership. They invest Rs. 40,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. IN what ratio will the profit be shared at the end of 3 years?
A.3:4:6
B.3:4:7
C.3:4:0
D.3:4:2
Answer: B.3:4:7
Explanation: A:B:C = (40000 * 36) : (80000 * 12 + 40000 * 24) : (120000 * 24 + 40000 * 12)
= 144:192:336 = 3:4:7.
Answer: B
Question: The difference between the place value and the face value of 6 in the numerical 856973 is
A.973
B.6973
C.5994
D.9554
Answer: C.5994
Explanation: =(place value of 6)-(Face value of 6)
=(6000-6)
=5994
Answer is C
Question: In how many ways can Ann, Bob, Chuck, Don and Ed be seated in a row such that Ann and Bob are not seated next to each other?
A.24
B.48
C.56
D.72 ways
Answer: D.72 ways
Explanation: These 5 people can be arranged in 5! ways. These are the total number of ways you get.
Now, when we tie 2 people together, we have only 4 entities to arrange. We can do this in 4! ways. But in each of these entities, the two people can sit in two different ways (AB and BA). So number of ways in which these two people sit together is 4!*2!.
Now, the ways in which these two people will not be together will be 5!- 4!*2! = 4!(5 - 2) = 72
ANSWER:D
Question: The difference of two numbers is 11 and one-fifth of their sum is 9. Find the numbers.
A.28 and 17
B.27 and 18
C.25 and 15
D.27 and 15
Answer: A.28 and 17
Explanation: Let the number be x and y. Then,
x – y = 11 ----(i) and 1/5 (x + y) = 9 => x + y = 45 ----(ii)
Adding (i) and (ii), we get: 2x = 56 or x = 28. Putting x = 28 in (i), we get: y = 17.
Hence, the numbers are 28 and 17.
Answer is A.
Question: Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 year?
A.306.06
B.306.02
C.306.04
D.306.09
Answer: C.306.04
Explanation: A = 5000(51/50)3
= 5306.04
5000
-----------
306.04
Answer: C
Question: The angles of a triangle are in the ratio 1 : 2 :3 . Find the measurement of the 3angles of triangle.
A.100°
B.110°
C.60°
D.180°
Answer: C.60°
Explanation: If the ratio of the three angles is 1:2:3, then the measures of these angles can be written as x, 2x and 3x. Also the sum of the three interior angles of a triangle is equal to 180°. Hence
x + 2x + 3x = 180
Solve for x
6x = 180
x = 30
The measures of the three angles are
x = 30°
2x = 2 × 30 = 60°
3x = 3 × 30 = 90°
C
Question: A circle is circumscribed around a quadrilateral, and the quadrilateral is ABCD, What is the value of arc BDA when angle A is 35 degrees?
A.210
B.240
C.270
D.290
Answer: D.290
Explanation: An inscribed angle is an angle in a circle composed of two chords with a common endpoint, that is, an angle with its vertex on the circle. In this problem, all four lettered angles are inscribed angles.
An inscribed angle necessarily opens to intersect an arc (the technical word is to subtend an arc). The Inscribed Angle Theorem said that the measure of an inscribed angle is always half the measure of the arc it intersects, or subtends.
angle A = 35 degrees
Thus,
arc BCD = 70 degrees
A whole circle has 360 degrees of arc, so arc BDA should be the rest of the circle.
arc BDA = 360 - 70 = 290 degrees
Answer =(D)
Question: A real estate agent received a 6% commission on the selling price of a house. If his commission was $8,880, what was the selling price of the house?
A.$148,000
B.$167,000
C.$156,000
D.$175,000
Answer: A.$148,000
Explanation: 6% x = 8,880 : x = selling price of house.
x = $148,000 : solve for x.
correct answer A
Question: A walks at 30 kmph and 30 hours after his start, B cycles after him at 48 kmph. How far from the start does B catch up with A?
A.1200km
B.1500km
C.2000km
D.2400km
Answer: D.2400km
Explanation: Suppose after x km from the start B catches up with A. Then, the difference in the time taken by A to cover x km and that taken by B to cover x km is 30 hours.
x/30 - x/48 = 30
x = 2400 km
Answer is D
Question: What is the value of x^2yz − xyz^2, if x = -1, y = 1, and z = 3?
A. 20
B. 24
C. 30
D. 12
Answer: D. 12
Explanation: 1*1*3 -(- 1*1*9)
=3+9 = 12
Ans: D
Question: 3 friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order In 7 rounds. A, B, C, AB, BC, AC, ABC. Final round measure is 170kg then find the average weight of all the 7 rounds?
A.97.1 kgs
B.88.5 kgs
C.86.5 kgs
D.67.5 kgs
Answer: A.97.1 kgs
Explanation: Average weight = [(a + b + c + (a+b) + (b+c) + (c+a)+(a+b+c)] / 7 = 4 (a+b+c) /7 = 4 x 170/7 = 97.1kgs
Answer:A
Question: A vessel contains a mixture of two milk M and N is the ratio 7 : 5. When 9 ltr of mixture are drawn off and the vessel is filled with B, the ratio of Mand N becomes 7 : 9. How many ltrof liquid M was contained by the can initially?
A.20ltr
B.21ltr
C.23ltr
D.24ltr
Answer: B.21ltr
Explanation: Suppose the can initially contains 7x and 5x of mixtures A and B respectively.
Quantity of M in mixture left = 7x -	7	x 9 ltr= 7x -	21 ltr.
12	4
Quantity of N in mixture left = 5x -	5	x 9 ltr = 5x -	15 ltr.
12	4
7x -	21
4
=	7
5x -	15 + 9
4
9
28x - 21	=	7
20x + 21	9
252x - 189 = 140x + 147
112x = 336
x = 3.
So, the can contained 21ltr of M
B
Question: Tom and Beth each drove from Smallville to Crown City by different routes. Tom drove an an average speed of 40 miles per hour and completed the trip in 30 minutes. Beth's route was 5 miles longer, and it took her 20 minutes more than Tom to complete the trip. How many miles per hour was Beth's average speed on this trip?
A. 24
B. 30
C. 48
D. 54
Answer: B. 30
Explanation: Speed = Distance/Time
Distance for Tom = Speed * Time = 40 * 1/2 = 20 miles
Distance for Beth = Distance for Tom +5 = 20+5 = 25 miles
Time taken by Beth = Time taken by Tom + (1/3 hour) = 1/2+1/3 = 5/6
Speed of Beth = D/T = 25/(5/6) = 25*6/5 = 30 miles per hour
Hence, B is the answer.
Question: A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of man is
A.12 kg
B.60 kg
C.72 kg
D.96 kg
Answer: B.60 kg
Explanation: Solution
Volume of water displaced	= (3 x 2 x 0.01)m3
= 0.06m3.
Mass of man	=Volume of water displaced ×Density of water
= (0.06×1000) kg
= 60 kg.
Answer B
Question: The ration between the present ages of P and Q is 1:2. If Q is 8 years older than P, what will be the ratio of the ages of P and Q after 8 years?
A.1:2
B.1:3
C.2:3
D.5:7
Answer: C.2:3
Explanation: Let P's and Q's age be x and 2x
2x-x = 8
x = 8
Required ratio = (x+8):(2x+8) = 16:24 = 2:3
Answer is C
Question: The sum of three numbers is 98. If the ratio between first and second be 2 : 3 and that between second and third be 5 : 8, then the second number is?
A.30
B.20
C.58
D.48
Answer: A.30
Explanation: Let the numbers be X, Y and Z. Then,
X + Y + Z = 98, X/Y = 2/3 and Y/Z = 5/8
Therefore, X = 2Y/3 and Z = 8Y/5. So, 2Y/3 + Y + 8Y/5 = 98.
49Y/15 = 98
Y = 30.
ANSWER:A
Question: The cost to rent a small bus for a trip is x dollars, which is to be shared equally among the people taking the trip. If 10 people take the trip rather than 30, how many more dollars, in terms of x, will it cost per person?
A. x/6
B. x/12
C. x/15
D. 3x/40
Answer: C. x/15
Explanation: Just plugging in values
X= 300
Cost per person if we consider 10 = 30
Cost per person if we consider 30 = 10
Difference between costs is 20 dollars.
Plugging in the value of x into the answer choices, let's see which one yields a result of 20. And that is C.
Question: In a series of three football matches between Germany and Argentina , the probability of Germany winning a match is 1/3 and the probability that the match ends in a draw is 1/4. If a win gets the team 2 points, a draw 1 point and a loss 0 Points, What is the probability that Germany will end up in 3 draws in the series?
A.24/576
B.125/864
C.1/25
D.1/64
Answer: D.1/64
Explanation: Since the probability of a draw is 1/4, then the probability of 3 draws in 3 matches is (1/4)^3=1/64.
Answer: D.
Question: A sales executive receives an annual bonus if he meets a certain target. This year, the salesman has so far sold 1/4 of last year's quota. If this year's quota is reduced by 20 percent from last year, how much target percentage of this year's target does he still need to complete to get bonus?
A.15/25
B.4/20
C.3/4
D.15/20
Answer: A.15/25
Explanation: We have 1/5 and 20% which is 1/5. Let's pick some smart numbers.
Assume last year's quota to be 25.
This year's quota = 20% reduction from 25 = 20
Sold so far = 1/5 * 25 = 5
Remaining = 20-5 = 15
Required = 15/25
Answer (A).
Question: The product of two numbers is 9375 and the quotient, when the larger one is divided by the smaller, is 15. The sum of the numbers is :
A.334
B.378
C.377
D.400
Answer: D.400
Explanation: Explanation:
Let the numbers be x and y.
Then, xy = 9375 and x/y = 15.
=>
=> y = 25
=> x = 15y = 15 x 25 = 375.
Sum of the numbers = 375 + 25 = 400.
Answer: D) 400
Question: In a deck of cards there are 52 cards numbered from 1 to 13. There are 4 cards of each number in the deck. If you insert 12 more cards with the number 10 on them and you shuffle the deck really good, what is the probability to pull out a card with a number 10 on it?
A.1/4.
B.4/17.
C.5/29
D.4/13
Answer: A.1/4.
Explanation: P(10) = (4+12) / (52+12)
= 16/64
= 1/4.
Answer:A
Question: Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 12 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
A.477
B.396
C.279
D.276
Answer: B.396
Explanation: 1h ----- 5
? ------ 60
12 h
RS = 12 + 21 = 33
T = 12
D = 33 * 12 = 396.Answer: B
Question: Look at this series: 0.6, 0.3, ____, 0.075, 0.0375, ... What number should fill the blank?
A.0.015
B.1.15
C.0.15
D.0.25
Answer: C.0.15
Explanation: This is a simple multiplication series. Each number is multiple by 1/2.
Answer: C
Question: A tap can fill a tank in 6 hours. After half the tank is filled, two more similar taps are opened. What is the total time taken to fill the tank completely?
A.1 hr 20 min
B.2 hr
C.3 hr
D.4 hr
Answer: D.4 hr
Explanation: Explanation:
1 tap can fill the tank in 6 hours.
Therefore
1 tap can fill half tank in 3 hours.
3 taps can fill the tank in 6/3 hour = 2 hours.
Therefore
3 taps can fill half tank in 2/2 hour =60 minutes = 1hour.
Total time taken=4 hours
Answer: Option D
Question: Find out the C.I on Rs.2000 at 4% p.a. compound half-yearly for 1 1/2 years.
A.A)Rs.420.20
B.B)Rs.319.06
C.C)Rs.306.04
D.D)Rs.294.75
Answer: C.C)Rs.306.04
Explanation: A = 2000(51/50)3
= 2122.41
2000
-----------
122.41
ANSWER:C
Question: Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 31 kmph. Of how many minutes does the train stop per hour?
A.18.6
B.27
C.12
D.121
Answer: A.18.6
Explanation: Explanation:
T = 14/45 * 60 = 18.6
Answer: Option A
Question: A small beaker is 1/2 filled with salt water. Another beaker, which has five times the capacity of the small beaker, is 1/3 filled with fresh water. After dumping all of the salt water from the small beaker into the large beaker, to what fraction of its capacity will the large beaker be filled?
A.7/10
B.11/20
C.13/30
D.17/30
Answer: C.13/30
Explanation: 1/2 of the small beaker is 1/10 of the large beaker.
1/10 + 1/3 = 13/30
The answer is C.
Question: A man walks at a speed of 4 km/hr and runs at a speed of 7 km/hr. How much time will the man require to cover a distance of 10 1/2 km, if he completes half of the distance, i.e., (5 1/4) km on foot and the other half by running?
A.2 4/2 hours
B.2 hours
C.2 1/6 hours
D.2 1/1 hours
Answer: B.2 hours
Explanation: Required time
= (5 1/4)/4 + (5 1/4)/7
= 2 hours.
Answer:B
Question: Given that E and F are events such that P(E) = 0.16, P(F) = 0.4 and P(E n F) = 0.4,
find P (E|F) and P(F|E)
A.1/4
B.1/5
C.1/7
D.2/5
Answer: A.1/4
Explanation: Here, E and F are events
P(E|F) = P(EnF)/P(F) = 0.4/0.4 = 1
P(F|E) = P(EnF)/P(E) = 0.4/0.16 = 1/4.
A
Question: A group of 6 members to be made from 8 boys and 6 girls. How many ways of forming group provided that there will be exactly 3 boys?
A.1110
B.1120
C.1130
D.1140
Answer: B.1120
Explanation: 3 boys out of 8 boys & 3 girls out of 6 girls bcz total 6 member of a group where exactly 3 boys.
8C3*6C3= 8!/(5!3!) * 6!/(3!3!)= 56*20=1120
ANSWER:B
Question: A certain no. when divided by 80 leaves a remainder 25, what is the remainder if the same no.be divided by 15?
A.2
B.4
C.7
D.8
Answer: C.7
Explanation: Explanation:
80 + 25 = 105/15 = 7(Remainder)
C
Question: Seats for Maths, Physics and Biology are in the ratio of 9 : 7 : 8 respectively. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the respective ratio of increased seats?
A.18 : 15 : 20
B.6 : 7 : 8
C.6 : 8 : 9
D.Cannot be determined
Answer: A.18 : 15 : 20
Explanation: Reqd ratio 9 Ã— 140â„100 : 7 Ã— 150â„100 : 8 Ã— 175â„100
= 9 Ã— 140 : 7 Ã— 150 : 8 Ã— 175 = 18 : 15 : 20
Answer A
Question: An urn contains 5 black and 3 white balls. Two balls are drawn from the urn one after the other
without replacement. What is the probability that both drawn balls are black?
A.1/5
B.3/7
C.2/5
D.5/14
Answer: D.5/14
Explanation: Let E and F denote respectively the events that first and second ball drawn
are black. We have to find P(E n F) or P (EF).
Now P(E) = P (black ball in first draw) = 5/8
Also given that the first ball drawn is black, i.e., event E has occurred, now there are 4 black balls and three white balls left in the urn. Therefore, the probability that the second ball drawn is black, given that the ball in the first draw is black, is nothing but the conditional probability of F given that E has occurred.
That is P(F|E) = 4/7
By multiplication rule of probability, we have
P (E n F) = P(E) P(F|E)
= 5/8 × 4/7 = 5/14
D
Question: A wolf eats 5 Kg of meat in 2 days. A baby tiger eats 3 Kg of meat in 4 days. How much meat can the two combined eat in three days?
A.10.5
B.9.75
C.8.25
D.7.15
Answer: B.9.75
Explanation: 3/2*5+3/4*3=9.75 kg
B
Question: In how many ways can a team of 5 be chosen out of a batch of 8 players?
A.45
B.56
C.32
D.50
Answer: B.56
Explanation: required number of ways = 8C5 = 56
Answer is B
Question: The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?
A.432
B.277
C.269
D.2656
Answer: A.432
Explanation: 2(3x + x) = 96
l = 36 b = 12
lb = 36 * 12 = 432
Answer: A
Question: The scoring system in a certain football competition goes as follows: 3 points for victory, 1 point for a draw, and 0 points for defeat. Each team plays 20 matches. If a team scored 12 points after 5 games, what is the least number of the remaining matches it has to win to reach the 40-point mark by the end of the tournament?
A.6
B.7
C.8
D.9
Answer: B.7
Explanation: To get 40 points as end of season we need another 28 points or more from remaining 15 matches:
Option A= 6*3+9*1=27
Option B=7*3 + 8*1=29
hence option B-7
Question: A letter lock consists of three rings each marked with thirteen different letters. The number of distinct unsuccessful attempts to open the lock is at the most ?
A.1773
B.2196
C.2153
D.1683
Answer: B.2196
Explanation: Since each ring consists of thirteen different letters, the total number of attempts possible with the three rings is
= 13*13*13 = 2197. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts
= 2197 - 1
= 2196.
Answer: B
Question: Which number is the odd one out ?
9654 4832 5945 7642 7963 8216 3669
A.3669
B.9654
C.5945
D.7963
Answer: A.3669
Explanation: The product of first two digits in a number equals the last two digits, except in 3669. Hence, it is the odd one.
The answer is 3669.
ANSWER:A
Question: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
A.20
B.80
C.100
D.200
Answer: C.100
Explanation: Explanation:
Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Answer: C
Question: The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?
A.Rs.4538
B.Rs.4518
C.Rs.4518
D.Rs.4530
Answer: D.Rs.4530
Explanation: Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5 = Rs.4530
Answer: D
Question: Uncle Bruce is baking chocolate chip cookies. He has 40 ounces of dough (with no chocolate) and 20 ounces of chocolate. How much chocolate is left over if he uses all the dough but only wants the cookies to consist of 25% chocolate?
A.8.5
B.9.5
C.10.5
D.6.7
Answer: D.6.7
Explanation: First, you must find the total weight of the mixture given that 80% of it will be dough.
75%*Total = 40 => (75/100)Total=40 => Total=4000/75=> Total=53.33oz,
From there, you must find 25% of the total 53.33 oz of the mixture.
25%*Total => (25/100)(53.33)= 13.33 oz choclate used,
Not forgetting that the question asks how much chocolate is left over we must subtract the chocolate used from the initial chocolate. 20-13.3 = 6.7 oz chocolate left over.
Answer : D
Question: A straight fence is to be constructed from posts 6 inches wide and separated by lengths of chain 7 feet long. If a certain fence begins and ends with a post, which of the following could not be the length of the fence in feet? (12 inches = 1 foot)
A.18
B.23
C.38
D.53
Answer: A.18
Explanation: There is one post for each length of chain, plus one final post at the end.
The length of the fence in feet is 7.5x + 0.5, where each is the number of chain lengths.
The length of the fence is an integer when x = 1,3,5,7,...
The length of the fence could be 8, 23, 38, 53, 68,...
The answer is A.
Question: y = 248 - 198x
Which of the following values of x gives the greatest value of y in the equation above?
A. 200
B. 100
C. 0.5
D. -5
Answer: D. -5
Explanation: Clearly, the negative value of x will result in maximum value of y.
Don't even look at the rest of the answer choices as only one negative value is being present.
Answer is D
Question: A number when divided by 45, gives 30 as quotient and 0 as remainder. What will be the remainder when dividing the same number by 15
A.A)0
B.B)3
C.C)4
D.D)6
Answer: A.A)0
Explanation: Explanation:
P ÷ 45 = 30
=> P = 30 * 45 = 1350
P / 15 = 1350 / 15 = 90, remainder = 0
Answer: Option A
Question: Car Dealership X, the total profit from sales increased by 8 percent over the previous years, while the number of cars sold decreased by 8 percent over the previous years. Approximately what was the average percent increase in profit per car over the previous year.
A.17.39%
B.20%
C.22%
D.23%
Answer: A.17.39%
Explanation: Let Profit be x and cars sold be y
Originally Profit/Car = x/y
Now it is 1.08x / 0.92 y = 108/92 (x/y)
Increase in profit per car = ((16/92) (x/y)) / (x/y) * 100 = 17.39%
Answer = A
Question: A sum of money is put out at compound interest for 2 years at 20%. It would fetch Rs.964 more if the interest were payable half-yearly, then it were pay able yearly. Find the sum.
A.22200
B.31897
C.38799
D.40000
Answer: D.40000
Explanation: P(11/10)^4 - P(6/5)^2 = 964
P = 40000
Answer: D