RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. Calculate the share of B in the profit.
A.Rs. 1900
B.Rs. 2660
C.Rs. 2800
D.Rs. 2840
Answer: B.Rs. 2660
Explanation: For managing, A received = 5% of Rs. 7400 = Rs. 370.
Balance = Rs. (7400 - 370) = Rs. 7030.
Ratio of their investments = (6500 x 6) : (8400 x 5) : (10000 x 3)
= 39000 : 42000 : 30000
= 13 : 14 : 10
B's share = Rs. (7030 x	14/37) = Rs. 2660.
Question: If x = (y)(y + 1) and y is a prime number less than 10, which of the following could not be the product of 2 consecutive integers?
A.a) 5x
B.b) 11x
C.c) 16x
D.d) 30x
Answer: C.c) 16x
Explanation: Given y is a prime number less than 11
possible values of y are 2 3 5 7
given, x=y*(y+1)
if y = 2 x=2*3=6
if y = 3 x=3*4=12
if y = 5 x=5*6=30
if y = 7 x=7*8=56
so possible values of x are 6,12,30,56
So from options
A. 5x can be (5*6)
B. 11x can be (11*12)
C. 16x can be (16*17)
D. 30x can be (30*31)
E. 57x can be (56*57)
So answer option C
Question: he average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?
A.22
B.28
C.15
D.199
Answer: C.15
Explanation: Total members in the group = 7
Average amount = Rs. 20
Total amount with them = 7 * 20 = Rs. 140
One number has Rs. 50. So, the amount with remaining 6 people = 140 - 50 = Rs. 90
The average amount with them = 90/6 = Rs. 15.Answer: C
Question: A statue is being carved by a sculptor. The original piece of marble weighed 140 kg. In the first week 60 percent is cut away. In the second week 40 percent of the remainder is cut away. In the third week the statue is completed when 30 percent of the remainder is cut away. What is the weight of the final statue?
A.24 kg
B.23 kg
C.28 kg
D.25 kg
Answer: A.24 kg
Explanation: A
24 kg
140 Ã— 0.4 Ã— 0.6 Ã— 0.7 = 24 kg.
Question: A library has an average of 510 visitors on sundays and 240 on other days . The avearge number of visitors per day in a month of 30 days beginning with a sunday is?
A.150
B.225
C.285
D.315
Answer: C.285
Explanation: Since the month begin with sunday, so there will be five sundays in the month
Required average = (510*5 + 240*25)/30 = 8550/30 = 285
Answer is C
Question: a number divided by 24 leaves remainder 56 what is the remainder when same number divided by 7
A.9
B.7
C.5
D.3
Answer: D.3
Explanation: add 24+56=80
now 80 divided by 7 so we get 3 as reaminder
ANSWER:D
Question: If three sides of the triangle are 8 , 15 and A respectively then the how many values can A ?
A.[A] 6
B.[B] 7
C.[C] 8
D.[D]9
Answer: D.[D]9
Explanation: Needed: How many Values can A take
Concept: Sum of any two sides of a triangle is greater then the third side.
Case 1: 8+5 > A => A<13
Case 2: 5+A > 8 => A >3
Case 3: 8+A > 5 => A > -3 (Always true since A is one side of a Triangle)
Finally, 3 < A < 13. So, we can have infinite number of sides between 3 and 13.
Answer = E
PS: If question said A can take only integer value, the A = 9. Answer choice D.
Question: Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is
A.1.967
B.1.963
C.2.388
D.3.388
Answer: A.1.967
Explanation: Explanation:
required area = (area of an equilateral triangle of side 7 cm)- (3 * area of sector with Ã = 60 degrees and r = 3.5cm)
\inline {\color{Black}(\frac{\sqrt{3}}{4}\times 7\times 7 )-(3\times \frac{22}{7}\times 3.5\times 3.5\times \frac{60}{360})} sq cm
=\inline {\color{Black}(\frac{\sqrt{3}}{4}\times 49 )-(11\times 0.5\times 3.5)} sq cm
= 1.967 sq cm
Answer: A) 1.967
Question: Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2:
3. What is the age of B at present
A.25
B.30
C.45
D.60
Answer: B.30
Explanation: Explanation:
Let their ages 10 years ago is x, 2x and 3x years.
10 + 2x + 10 + 3x + 10 = 90 hence x= 10
B�s present age = (2x + 10) =30 years
Answer: Option B
Question: The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 40% profit?
A.277
B.960
C.896
D.266
Answer: C.896
Explanation: Let C.P. = Rs. x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 14% of Rs. 640 = 140/100 * 640 = Rs. 896.
Answer: C
Question: The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?
A.18 cm
B.20 cm
C.22 cm
D.24 cm
Answer: A.18 cm
Explanation: 2(l + b)	=	5
b	1
2l + 2b = 5b
3b = 2l
b =	2	l
3
Then, Area = 216 cm2
l x b = 216
l x	2	l	= 216
3
l2 = 324
l = 18 cm.
A)
Question: A train 100 meters long completely crosses a 300 meters long bridge in 45 seconds. What is the speed of the train is?
A.32
B.55
C.6
D.78
Answer: A.32
Explanation: S = (100 + 300)/45 = 400/45 * 18/5
= 32
Answer: A
Question: Forks, Spoons, and Knives in drawer are in the ratio of 4: 4 : 3. If there are 16 Forks, the number of Knives in the drawer is:
A.8
B.4
C.12
D.16
Answer: C.12
Explanation: Explanation :
Let Forks = 4x, Spoons = 4x & Knives = 3x. Now, 4x = 16 hence x = 4.
Number of Knives = 3x = 12.
Answer : C
Question: The edge of three cubes of metal is 3 dm, 4 dm and 5 dm. They are melted and formed into a single cube. Find the edge of the new cube?
A.8
B.2
C.4
D.6
Answer: D.6
Explanation: 33 + 43 + 53
= a3
=> a = 6
Answer: D
Question: Bobby bought 2 shares, and which he sold for $124 each. If he had a profit of 40% on the sale of one of the shares but a loss of 17% on the sale of the other share, then on the sale of both shares Bobby had...
A.a profit of 10
B.a profit of 8
C.a loss of 8
D.a loss of 10
Answer: A.a profit of 10
Explanation: Cost of the first stock: 124/1.4=88.57, so profit from it 124-88.57=35.43
Cost of the second stock: 124/0.83=149.39, so loss from it 124-149.39=-25.39
Overall profit 35.43-25.39=10
Answer: A.
Question: Mona and Donald fly to Rome for the weekend. They take cash only in notes of $10 and notes of €10. Mona carries three times the amount of euros Donald carries. She also carries as many dollars as Donald carries. The number of €10 notes they take is double the number of $10 notes they take. If Donald carries a total of 42 notes (of either $10 or €10,) then what is the total number of notes (of either $10 or €10,) they take?
A.70
B.80
C.100
D.140
Answer: D.140
Explanation: let e10 =x no. d10 =y no. donald is having x+y notes mona carries 3x+y again x =2y or donald x+y =42
or 3y =42 y =14 ;x =28 , total notes they carry = 4x+2y = 112+28 =140
D
Question: A fair price shopkeeper takes 10% profit on his goods. He lost 30% goods during theft. His loss percent is:
A.23%
B.42%
C.32%
D.12%
Answer: A.23%
Explanation: Explanation:
Suppose he has 100 items. Let C.P. of each item be Re. 1.
Total cost = Rs. 100. Number of items left after theft = 70.
S.P. of each item = Rs. 1.10
Total sale = 1.10 * 70 = Rs. 77
Hence, loss % = 23/100 * 100 = 23%
Answer:A
Question: The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles?
A.1887
B.9977
C.4312
D.2976
Answer: C.4312
Explanation: Let the radii of the smaller and the larger circles be s m and l m respectively.
2∏s = 264 and 2∏l = 352
s = 264/2∏ and l = 352/2∏
Difference between the areas = ∏l2 - ∏s2
= ∏{1762/∏2 - 1322/∏2}
= 1762/∏ - 1322/∏
= (176 - 132)(176 + 132)/∏
= (44)(308)/(22/7) = (2)(308)(7) = 4312 sq m
Answer: C
Question: If 2|2 –s| = 5, what is the sum of all the possible values for s ?
A.1/2
B.2
C.5/2
D.4
Answer: D.4
Explanation: if s<2, then 2-s=5/2; s=-1/2
if s>2 , then s-2=5/2; s=9/2
9/2-1/2=8/2=4=D
Question: How many seconds will a train 100 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?
A.54 sec
B.65 sec
C.25 sec
D.45 sec
Answer: C.25 sec
Explanation: D = 100 + 150 = 250
S = 36 * 5/18 = 10 mps
T = 250/10 = 25 sec
Answer:C
Question: If x is a number such that x^2 + 4x - 5 = 0 and x^2 + x - 20 = 0, then x =
A.1
B.-4
C.4
D.-5
Answer: D.-5
Explanation: x^2 + 4x - 5 = (x+5)(x-1) = 0
Then x=-5 or x=1.
x^2 + x - 20 = (x-4)(x+5) = 0
Then x=4 or x=-5.
Thus x=-5.
The answer is D.
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?
A.2.91 km
B.2.88 km
C.2.78 km
D.2.98 km
Answer: B.2.88 km
Explanation: M = 6
S = 1.2
DS = 6 + 1.2 = 7.2
US = 6 - 1.2 = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
Answer: B
Question: In the Hillside summer camp there are 50 kids. 90% of the kids are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of kids in the camp. How many more boys must she bring to make that happen?
A.50.
B.45.
C.40.
D.30.
Answer: A.50.
Explanation: Given there are 50 kids , 90% of 50 = 45 boys and remaining 5 girls.
Now here 90% are Boys and 10% are Girls.
Now question is asking about how many boys do we need to add, to make the girls percentage to 5 or 5%..
If we add 50 to existing 45 then the count will be 95 and the girls number will be 5 as it.
Now boys are 95% and girls are 5%. ( out of 100 students = 95 boys + 5 girls ).
IMO option A is correct.
Question: A dealer purchased toys at 1/2 of their list price and sold them for 10% more than the list price. What is his percent gain?
A.10
B.50
C.110
D.120
Answer: D.120
Explanation: Cost = 1/2 List Price = .5*LSale = 1.10 List Price = 1.10*LGain Ratio = (Sale - Cost) / Cost = (1.10*L - .5*L) / .5*L = .6*L / .5*L = 1.20Gain Percent = 100 * Gain Ratio = 100 * 1.20 = 120% = Answer D
Question: A man sitting in a train which is travelling at 50 kmph observes that a goods train, travelling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.
A.62 kmph
B.58 kmph
C.52 kmph
D.50 kmph
Answer: A.62 kmph
Explanation: Relative speed = (280⁄9) m/sec = (280⁄9 × 18⁄5) kmph
= 112 kmph.
∴ Speed of goods train = (112 – 50) kmph = 62 kmph.
Answer A
Question: A merchant gains or loses, in a bargain, a certain sum. In a second bargain, he gains 550 dollars, and, in a third, loses 120. In the end he finds he has gained 300 dollars, by the three together. How much did he gain or lose bv the first ?
A.-130
B.120
C.130
D.-80
Answer: A.-130
Explanation: In this sum, as the profit and loss are opposite in their nature, they must be distinguished by contrary signs. If the profit is marked +, the loss must be -.
Let x = the sum required.
Then according to the statement x + 550 - 120 = 300
And x = -130.
Answer A
Question: There is rain all over the city at a rate of 7 centimeters per hour. If a person is waiting in his house for the rain to stop how long did he wait to go out. The rain water filled a bucket of 28 centimeters depth and 200 square meters area?
A.5 hours 14 minutes
B.6 hours
C.4 hours
D.8 hours
Answer: C.4 hours
Explanation: Answer is : C, 4 hours
The volume of the bucket is irrelevant and only height matters since rain fell all over the city.
Thus, it takes only 28 / 7 = 4 hours of rain to fill the bucket
Question: 16 men can complete a piece of work in 25 days. In how many days can 20 men complete that piece of work?
A.23
B.27
C.20
D.27
Answer: C.20
Explanation: 16 * 25 = 20 * x => x = 20 days
Answer:C
Question: in a soap company a soap is manufactured with 11 parts.for making one soap you will get 1 part as scrap.at the end of the day you have 251 such scraps.from that how many soaps can be manufactured?
A.24
B.25
C.26
D.27
Answer: B.25
Explanation: Using 251 scraps we make = 22 soaps. (i.e., 11*22 = 242)Remaining scraps = 9.
Again, 22 soaps produce = 22 scraps.
So, now we have 22+9=31 scraps remaining.
Using 31 scraps we make 2 soaps and 2scraps remaining.(i.e., 2*11 =22)
Again, that 2 soaps produce = 2 scraps. And already we have 9 scraps. Total 9+2 =11sscraps.
By using 11 scraps, we make 1 soap.
So, total = 22+2+1 = 25 soaps we produce.
ANSWER:B
Question: Sam purchased 20 dozens of toys at the rate of Rs. 375 per dozen. He sold each one of them at the rate of Rs. 33. What was his percentage profit?
A.3.5
B.4.5
C.5.6
D.6.5
Answer: C.5.6
Explanation: Solution
C.P of 1 toy	= Rs.(375/12)
= Rs.31.25
S.P of 1 toy	= Rs.33.
Therefore,Profit	= (1.75/31.25×100)%
=(28/5)%
=5.6%.
Answer C
Question: If the function f(x) is defined for all real numbers x as the maximum value of 2x + 2 and 12 + 3x, then for which one of the following values of x will f(x) actually equal 2x + 2 ?
A.–4
B.–8
C.–11
D.–13
Answer: C.–11
Explanation: Since f(x) defines maximum of 2x + 2 and 12 + 3x,
to find those x when 2x+2 has greater value,
2x + 2 > 12 + 3x
or x < -10
Only value that satisfy this is -11.
Answer is (C),
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
A.45 km/hr
B.50 km/hr
C.54 km/hr
D.55 km/hr
Answer: B.50 km/hr
Explanation: Speed of the train relative to man = 125/10	m/sec
= 25/2	m/sec.
2
= 25/2	x	18/5	km/hr
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 x = 50 km/hr.
Option B
Question: The average (arithmetic mean) of eight numbers is 48.1. If the sum of half of these numbers is 158.4, what is the average of the other half?
A.12.8
B.24.2
C.56.6
D.72.1
Answer: C.56.6
Explanation: arithmetic mean = sum / total numbers
sum = 48.1 * 8 = 384.8
sum of half of these numbers is 158.4. So, 4 numbers sum is 158.4. Rest 4 numbers sum = 384.8-158.4 = 226.4
Arithmetic mean of the 4 nos = 226.4/4 = 56.6
Hence, C is the answer.
Question: A man buys two articles for Rs.1980 each and he gains 10% on the first and loses 10% on the next. Find his total gain or loss percent?
A.9%loss
B.7%loss
C.8%loss
D.5%loss
Answer: A.9%loss
Explanation: (30*30)/100
= 9%loss
Answer: A
Question: How many possible ways can 2 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?
A. 3
B. 4
C. 5
D. 6
Answer: D. 6
Explanation: Any one girl can go with 3 boys.
2nd girl can go with remaining 2 boys
3*2 i.e 6 (D) is the answer
Question: 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning?
A.4400
B.3000
C.4200
D.5000
Answer: A.4400
Explanation: X * (95/100) * (85/100) = 3553
X = 4400
ANSWER A
Question: If a - b = 3, a^2 + b^2 = 29 ,find the value of ab.
A.10
B.12
C.15
D.18
Answer: A.10
Explanation: Explanation:
2ab = (a^2 + b^2) - (a - b)^2 = 29 - 9 = 20 => ab = 10..
Answer: A
Question: On a sum of money, the simple interest for 2 years is Rs. 660,while the compound interest is Rs.696.30,the rate of interest being the same in both the cases. The rate of interest is
A.23
B.11
C.378
D.36
Answer: B.11
Explanation: Explanation:
Difference in C.I and S.I for 2 years
= Rs(696.30-660)
=Rs. 36.30.
S.I for one years = Rs330.
S.I on Rs.330 for 1 year =Rs. 36.30
Rate
= (100x36.30/330x1)%
= 11%
Answer: B) 11%
Question: Walking at 6/7th of his usual speed, a man is 25 mins too late. His usual time is
A.7.5 hrs
B.1.5 hrs
C.2.5 hrs
D.1.67 hrs
Answer: C.2.5 hrs
Explanation: As the distance is same s*t=6/7s*(t+25)
solving this we get t=150 sec
150/60=2.5 hrs
ANSWER:C
Question: A shop purchased a pair of shoes for $150 and was selling it at a price that equaled the purchase price of the shoes plus a markup that was 25 percent of the selling price. After some time a shop owner decided to decrease the selling price by 20 percent. What was the shop's gross profit on this sale?
A.$0
B.$2
C.$10
D.$6
Answer: C.$10
Explanation: Sale Price(SP) = 150 + Markup(MP)
--> Mp = SP-150
and given MP=SP/4 ( 25% is 1/4th)
so SP/4= SP-150
3SP/4= 150
SP=200
Now a discount of 20% is given so NEW SP is .8 *200 =160
Profit=160-150 =$10
Answer is C
Question: What is the sum of all the odd numbers between 24 and 50, inclusive?
A.592
B.481
C.330
D.475
Answer: B.481
Explanation: To solve this problem, all you have to do is take every even number between 24 and 50 and add them together. So we have 25+27+29+31+33+35+37+39+41+43+45+47+49, which is 481.
Final Answer:
B
Question: A shipment of 8 TV sets contains 5 black and white sets and 3 color sets. If 2 TV sets are to be chosen at random from this shipment, what is the probability that at least 1 of the 2 sets chosen will be a black and white set?
A.1/7
B.1/4
C.5/14
D.25/28
Answer: D.25/28
Explanation: 3/8 * 2/7 = 6/56
1-(6/56) = 50/56 = 25/28
Answer D
Question: In a contest, a bowl contains 9 keys, one of which will open a treasure chest and eight of which will not. If a contestant selects the key that opens the treasure chest, she wins the contents of that chest. If Ram is allowed to draw two keys, simultaneously and at random, from the bowl as the first contestant, what is the probability that he wins the prize?
A.2/9
B.13/2
C.15/4
D.16/15
Answer: A.2/9
Explanation: The total possibilities existing while withdrawing two keys are: 9C2 = 36
For Ram to win, 8 combinations exist assuming Key 1 to unlock the treasure E.g(1,2), (1,3)....(1,8)
P = 8/36 = 2/9
Option A
Question: Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 5. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?
A.(4m+15)/[m(m-5)]
B.(8m-15)/[m(m-5)]
C.(10m-15)/[m(m-5)]
D.(4m-15)/[m(m-5)]
Answer: D.(4m-15)/[m(m-5)]
Explanation: Three of the sandwiches were evenly divided among the students
i.e. Amount of Sandwiches with each students = 3/m
Amount of 4th Sandwich with remaining (m-5) students = 1/(m-5)
The amount of Sandwich that carol ate = 3/m + 1/(m-5) = (3m-15+m)/[m(m-5)] = (4m-15)/[m(m-5)]
Answer: D
Question: The average of five numbers is 20. If one number is excluded, the average becomes 18. The excluded number is?
A.25
B.28
C.32
D.40
Answer: B.28
Explanation: Excluded number = 20*5-18*4 = 100-72 = 28
Answer is B
Question: A started a business with an investment of Rs. 70000 and after 6 months B joined him investing Rs. 120000. If the profit at the end of a year is Rs. 52000, then the share of B is?
A.Rs.24029
B.Rs.24000
C.Rs.24038
D.Rs.24082
Answer: B.Rs.24000
Explanation: Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6
Total profit = Rs. 52000
Share of B = 6/13 (52000) = Rs. 24000
Answer: B
Question: At the Widget factory, 20 percent of the employees are engineers and 50 percent are builders. If there are 57 other employees at the Widget factory, how many total employees work there?
A. 190
B. 180
C. 160
D. 200
Answer: A. 190
Explanation: Let the total number of employees in the factory be x
% of engineers = 20%
% of builders = 50%
% of other employees = 100% - 70% = 30%
But this number is given as 57
so 30% of x = 57
x = (57)(100/30) = 570/3 = 190
Therefore there a total of 190 employees in the Widget factory.
Correct answer - A
Question: A can do a piece of work in 80 days. He works at it for 10 days & then B alone
finishes the remaining work in 42 days. In how much time will A and B, working
together, finish the work?
A.30
B.120
C.150
D.41
Answer: A.30
Explanation: Work done by A in 10 days=10/80=1/8
Remaining work=(1-(1/8))=7/8
Now, work will be done by B in 42 days.
Whole work will be done by B in (42*8/7)=48 days
Therefore, A's one day's work=1/80
B’s one day's work=1/48
(A+B)'s one day's work=1/80+1/48=8/240=1/30
Hence, both will finish the work in 30 days.
ANSWER A
Question: What is the number of integers from 1 to 1000 (inclusive) that are divisible by neither 11 nor by 35?
A.884
B.890
C.892
D.910
Answer: A.884
Explanation: Number divisible by 11:-
1000/11= 90
numbers divisible by 35:-
1000/35= 28
Numbers divisible by both 11 and 35= 2
Total numbers divisible by both 11 and 28= 90+28-2= 116 (because we counted 2 in both 90 and 28)
Total numbers not divisible by 11 or 35= 1000-116= 884
Answer : A
Question: Of a set of 30 numbers, average of 1st 10 numbers is equal to average of last 20 numbers. The sum of last 20 numbers is?
A.2 x sum of 1st 60 numbers
B.2 x sum of 1st 10 numbers
C.2 x sum of 1st 30 numbers
D.2 x sum of 1st 20 numbers
Answer: B.2 x sum of 1st 10 numbers
Explanation: Let average of first 10 numbers is a. Then sum = 10a
Average of last 10 nmbers also a. Then their sum = 20a
From the options B correct
Answer:B
Question: The product of the squares of two positive integers is 100. How many pairs of positive integers satisfy this condition?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: Ans: C - 2 pairs
(xˆ2)(yˆ2) = 100 [square root both sides]
xy = 10
10 = 1x10, 10x1, 2x5, 5x2
Cancel the repeats
This leaves us with exactly 2 options.
Hence, C
Question: What is the sum of 60 consecutive integers from -30 inclusive, in a increasing order?
A.-29
B.29
C.-30
D.30
Answer: C.-30
Explanation: From -39 to -1 --> 30 nos.
zero --> 1 number
from +1 to +29 --> 29 nos.
When we add up nos. from -30 to +29 sum will be -30 for total 60 numbers.
C is the answer.
Question: A certain animal in the zoo has consumed 39 pounds of food in six days. If it continues to eat at the same rate, in how many more days will its total consumption be 156 pounds?
A.18
B.7
C.12
D.9
Answer: A.18
Explanation: Ans is A:
39 pounds --> 6 days
91 pounds --> x days
x = 156*6/39 = 24
the animal has already consumed food in 6 days so the the number of
days for it's total consumption be 156 pounds is 24-6 = 18
Question: Which of the following fractions can be written as the difference of reciprocals of two consecutive integers
A.1/20
B.7/30
C.1/45
D.13/56
Answer: A.1/20
Explanation: Difference of reciprocals means 1 has to be in the numerator;
So option BD can be ignored
For option A, BE, we require to search two consecutive numbers whose product is the denominator
20= 4 * 5 ......... Answer
Answer = A
Question: What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ?
A.196
B.630
C.680
D.780
Answer: B.630
Explanation: L.C.M. of 12, 18, 21 30 2 | 12 - 18 - 21 - 30
----------------------------
= 2 x 3 x 2 x 3 x 7 x 5 = 1260. 3 | 6 - 9 - 21 - 15
----------------------------
Required number = (1260 ÷ 2) | 2 - 3 - 7 - 5
= 630.
Answer: Option B
Question: The time in a clock is 20 minute past 2. Find the angle between the hands of the clock.
A.60 degrees
B.120 degrees
C.45 degrees
D.50 degrees
Answer: D.50 degrees
Explanation: Solution:
Time is 2:20. Position of the hands: Hour hand at 2 (nearly).
Minute hand at 4
Angle between 2 and 4 is 60 degrees [(360/12) * (4-2)]
Angle made by the hour hand in 20 minutes is 10 degrees, since it turns through ½ degrees in a minute.
Therefore, angle between the hands is 60 degrees - 10 degrees = 50 degrees
Answer D
Question: A pet groomer has 7 animals to groom for the day (2 cats and 5 dogs). If she randomly selects 4 animals to groom before lunch, what is the probability she will finish all the cats before lunch?
A.3/7
B.2/7
C.12/13
D.5/11
Answer: B.2/7
Explanation: Combination Probability Formula: nCr = n!/[r!(n-r)!]
Total possible, select 4 animals from 7 animals = 7C4 = 7!/[4!(7 - 4)!] = 35.
To finish all 2 cats there must be 2 dogs, select 2 dogs from 5 = 5C2 = 10.
And, select 2 cats from 2 = 2C2 = 1.
2 cats and 2 dogs = (1)(10) = 10
Probability = (number outcomes favorable)/(total number outcomes) = 10/735 = 2/7
Answer: B
Question: A river 5m deep and 19 m wide is flowing at the rate of 4 kmph the amount of water that runs into the sea per minute is?
A.4500
B.6333
C.6576
D.6345
Answer: B.6333
Explanation: (4000 * 5 * 19)/60
= 6333 M3
Answer:B
Question: What is the are of an equilateral triangle of side 10 cm?
A.25√3
B.20√3
C.15√3
D.30√3
Answer: A.25√3
Explanation: Area of an equilateral triangle = √3/4 S2
If S = 10, Area of triangle = √3/4 * 10 * 10
= 25√3 cm2;
Answer:A