RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A, Band C enter into a partnership by investing in the ratio of 3 : 2: 4. After 1 year, B invests another Rs. 2,70,000 and C, at the end of 2 years, also invests Rs.2,70,000. At the end of three years, profits are shared in the ratio of 3 : 4 : 5. Find initial investment of each.
A.360000;180000;270000
B.270000;180000;360000
C.180000;360000;270000
D.270000;360000;270000
Answer: B.270000;180000;360000
Explanation: Let the initial investments of A, Band C be Rs. 3x, Rs. 2x and Rs. 4x respectively. Then,
(3x x 36) : [(2x x 12) + (2x + 270000) x 24] : [(4x x 24) + (4x +270000) x 12]=3:4:5
1O8x : (72x + 6480000) : (144x + 3240000) = 3 : 4 : 5
108x /(72x+6480000)=3/4  432x = 216x + 19440000
=216x = 19440000
=x=90000
Hence, A’s initial investment = 3x = Rs. 2,70,000;
B's initial investment = 2x = Rs. 1,80,000;
C's initial investment = 4x = Rs. 3,60,000.
Answer is B.
Question: The average of a couple was 28Yrs when they were married 15Yrs ago.The avg age of
the couple and a child, who was born during the interval, is 31Yrs now. How old is the
child now ?
A.2 Yrs
B.7 Yrs
C.3 Yrs
D.1 Yrs
Answer: B.7 Yrs
Explanation: (a+b-15-15)/2=28;
a+b=86;
a+b+c/3=31;
solving both c=7
ANSWER:B
Question: Rahim went to a shop and bought things worth Rs. 35, out of which 50 Paise went on sales tax on taxable purchases. If the tax rate was 5%, then what was the cost of the tax free items?
A.18.5
B.21.5
C.24.5
D.23.5
Answer: C.24.5
Explanation: Total cost of the items he purchased = Rs.35
Given that out of this Rs.35, 50 Paise is given as tax
=> Total tax incurred = 50 Paise = Rs.50/100
Let the cost of the tax free items = x
Given that tax rate = 5%
∴ (35−50/100−x)5/100 = 50/100
⇒ 5(35 −0.5−x) = 50
⇒ (35 − 0.5 − x) = 10
⇒ x = 35 − 0.5 − 10= 24.5
C)
Question: In a games hour 4 different types of players came to the ground? cricket 10, hokey 12, football 16, softball 13. How many players are present in the ground?
A.70
B.52
C.51
D.49
Answer: C.51
Explanation: total number of players= 10+12+16+13= 51
Answer is C
Question: If 36 men can do a piece of work in 25 hours, in how many hours will 12 men
do it ?
A.65 hours
B.75 hours
C.30 hours
D.62 hours
Answer: B.75 hours
Explanation: Let the required number of hours be x. Then,
Less men, More hours	(Indirect Proportion)
12 : 36 : : 25 : x	(12 x x) = (36 x 25)	(36 x 25)/12 = 75
Hence, 15 men can do it in 60 hours.
Answer is B.
Question: A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
A.230
B.88
C.77
D.26
Answer: A.230
Explanation: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x = 230.
Answer: A
Question: Divide $1000 among A,B in the ratio 1:4. How many $ that B get?
A.$500
B.$800
C.$1000
D.$200
Answer: B.$800
Explanation: Sum of ratio terms = 1+4 = 5
A = 1000*4/5 = $800
Answer is B
Question: John is building a rectangular fence around a garden. The length will be 5 feet shorter than its width. If the total area of the garden is 176 square feet, what is the length of the diagonal (in feet)?
A.Between 18 and 19
B.Between 19 and 20
C.Between 20 and 21
D.Between 21 and 22
Answer: B.Between 19 and 20
Explanation: To solve this, we first need to set up an equation for the area of the garden. If x is the width, then we have
x(x - 5) = 176. By putting the equation in standard form, we get x^2-5x-176=0. By using the quadratic formula, we get roots of -11 and 16. We know that x is the width, and x-5 is the length, so by using the roots, we get 16 as the width (x), and 11 as the length (x-5).
Once we have this, we can use the Pythagorean Theorem to solve for the diagonal. Plugging in the length and width, we will get d^2=16^2+11^2
=256+121
=377
The square root of 377 is less than 20, since 20^2 = 400. Going down a number, we can compute 19^2 = 361 < 377. Therefore, the length of the diagonal must be between 19 and 20.
The correct answer is B.
Question: There is a single elimination lacrosse tournament, meaning when one player loses, they are out of the tournament. There are 10 teams in the tournament, how many games are played?
A.10
B.5
C.2
D.9
Answer: D.9
Explanation: D
The number of games always adds up to one less than the number of teams in a single elimination tournament. You may calculate it any way. Therefore, 9 games were played.
Question: x, a, z, and b are single digit positive integers. x = ¼ a. z = ¼ b.2*( (10a + b) – (10x + z) )could NOT equal
A.66
B.72
C.48
D.126
Answer: C.48
Explanation: 1) firstly we are not given that all are different integers..
2) since each is a positive single digit integer and x=a/4... a can take only 4 and 8 as value, and x can take 1 and 2..
3) same as 2) for b and z.
so in 2*((10a + b) – (10x + z)) ..
10a+b can be
44,48,84,88..
10x+z can be
11,12,21,22..
lets see teh choices
ans C
Question: The average of 5 numbers is 6.8. If one of the numbers is multiplied by a factor of 2, the average of the numbers increases to 9.2. What number is multiplied by 2?
A. 12.0
B. 30.0
C. 30.9
D. 40.0
Answer: A. 12.0
Explanation: The average of 5 numbers is 6.8
The sum of 5 numbers will be 6.8 x 5 = 34
The average of 5 number after one of the number is multiplied by 2 is 9.2
The sum of the numbers will now be 9.2 x 5 = 46
So the sum has increased by 46-34 = 12
Let the number multiplied by 2 be n
Then,
2n = n+12
or n = 12
Answer:- A
Question: A certain rectangular crate measures 8 feet by 12 feet by 14 feet. A cylindrical gas tank is to be made for shipment in the crate and will stand upright when the crate is placed on one of its six faces. What should the radius of the tank be if it is to be of the largest possible volume?
A.6
B.5
C.6
D.8
Answer: A.6
Explanation: Ans is "B".
For max volume of cylinder (pi*r^2*h) we need to max out r^2*h. We don't know what the dimensions of the crate refer to. So to maximize the above eqn, radius may be of 9,10,12 one of the base area( 8x12, 14x12 or 8 x14) r is maximum for base 14x12 and 12 can be maximum value so r = 10/2 =6
A
Question: Which is the least number, which, when divided by 12 and 16, leave the same remainder, but is exactly divisible by 11?
A.55
B.27
C.29
D.12
Answer: A.55
Explanation: Explanation:
No explanation is available for this question!
ANSWER: A
Question: In an examination, 300 students appeared. Out of these students; 28 % got first division, 54 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed.
A.33
B.37
C.54
D.99
Answer: C.54
Explanation: The number of students with first division = 28 % of 300 = 28/100 × 300 = 8400/100 = 84
And, the number of students with second division = 54 % of 300
= 54/100 × 300
=16200/100
= 162
Therefore, the number of students who just passed = 300 – (84 + 162) = 54
Answer:C
Question: If Z = 52 and ACT = 48, then BAT will be equal to
A.33
B.88
C.77
D.46
Answer: D.46
Explanation: Explanation:
In the given code, A = 2, B = 4, C = 6,.... , Z = 52.
So, ACT = 2 + 6 + 40 = 48 and
BAT = 4 + 2 + 40 = 46
Answer: D) 46
Question: What is the lowest positive integer that is divisible by 1 through 3, inclusive?
A.12
B.6
C.8
D.18
Answer: B.6
Explanation: The integer should be divisible by: 1, 2, and 3. The least common multiple of these integers is LCM=1*2*3=6
Answer: B
Question: A train 240 m in length crosses a telegraph post in 16 seconds. The speed of the train is?
A.22
B.21
C.54
D.28
Answer: C.54
Explanation: S = 240/16 * 18/5 = 54 kmph.Answer:C
Question: On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price Q per glass on the second day?
A. $015
B. $0.20
C. $0.30
D. $0.40
Answer: D. $0.40
Explanation: On the first day 1 unit of orange juice and 1 unit of water was used to make 2 units of orangeade;
On the second day 1 unit of orange juice and 2 units of water was used to make 3 units of orangeade;
So, the ratio of the amount of orangeade made on the first day to the amount of orangeade made on the second day is 2 to 3. Naturally the ratio of the # of glasses of orangeade made on the first day to the # of glasses of orangeade made on the second day is 2 to 3.
We are told thatthe revenue from selling the orangeade was the same for both daysso the revenue from 2 glasses on the first day equals to the revenue from 3 glasses on the second day.
Say the price of the glass of the orangeade on the second day was $x then 2*0.6=3*x --> x=$0.4.
Answer: D.
Question: A librarian has a set of eight books, including four different books about Abraham Lincoln. The librarian wants to put the eight books on a shelf with the four Lincoln books next to each other, somewhere on the shelf among the other four books. How many different arrangements of the eight books are possible?
A.(8!)/(4!)
B.(4!)(4!)
C.(4!)(5!)
D.(4!)(8!)
Answer: C.(4!)(5!)
Explanation: You can club the four Lincoln books as one, which leaves us with four other books plus this one to think about. So, these five items can be arranged in 5! ways, and since the four books can be moved around among themselves with each combination giving us a new overall combination, we have an additional 4! ways. Therefore, the answer would be 5!*4!, which is C.
Question: The sequence of numbers a1, a2, a3, ..., an is defined by an = 1/n - 1/(n+2) for each integer n >= 1. What is the sum of the first 50 terms of this sequence?
A.(1+1/2) – (1/51 +1/ 52)
B.(1/51 +1/ 52)
C.(1+1/2) +(1/51 +1/ 52)
D.(1+1/2) – 1/51
Answer: A.(1+1/2) – (1/51 +1/ 52)
Explanation: The answer would most certainly be[A]. But the question needs a slight modification.n>=1, since the answer does consider a1 under the sum.
The sequence is :
a1 = 1-1/3
a2 = 1/2 - 1/4
a3 = 1/3 - 1/5....
We can observe that the third term in the sequence cancels the negative term in the first. A similar approach can be seen on all the terms and we would be left with 1 + 1/2 from a1 and a2 along with -1/52 and -1/51 from a50 and a49 term which could not be cancelled.
Hence the sum = (1+1/2) – (1/51 +1/ 52)
Answer : A
Question: ((7^1/2)^2)
A.49^1/2
B.49^1/4
C.7^1/2
D.7^1/4
Answer: A.49^1/2
Explanation: ((7^1/2)^2)
=7^(1/2*2)
=7^1
=7
=49^1/2
ANSWER:A
Question: All the stocks on the over-the-counter market are designated by either a 3 letter or 4 letter codes that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be designated with these codes?
A.2(26^5)
B.26(26^4)
C.27(26^3)
D.26(26^5)
Answer: C.27(26^3)
Explanation: with 3 letters: 26^3
with 4 letters: 26^4
26^3 + 26^4 = 27*(26^3)
C
Question: A courier charges for packages to a certain destination are 65 cents for the first 250 grams and 10 cents for each additional 100 grams or part thereof. What could be the weight in grams of a package for which the charge is $2.05?
A.980
B.1130
C.1440
D.1610
Answer: D.1610
Explanation: The charge is 65 cents for the first 250 grams.
This leaves a charge of $2.05 - $0.65 = $1.40
The charge for the next 1300 grams is $1.30 which leaves a charge of $0.10
The weight is somewhere between 1550 and 1650.
The answer is D.
Question: If 1/2 of the air in a tank is removed with each stroke of a vacuum pump, what fraction of the original amount of air has been removed after 3 strokes ?
A.15/16
B.7/8
C.1/4
D.1/8
Answer: B.7/8
Explanation: Left After 1st stroke = 1/2
Left After 2nd stroke = 1/2 * 1/2 = 1/4
Left After 3rd stroke = 1/2 * 1/4 = 1/8
So removed = 1- 1/8 = 7/8=B
Question: 30 men can do a work in 40 days. When should 14 men leave the work so that the entire work is completed in 40 days after they leave the work?
A.87 days
B.16 days
C.55 days
D.44 days
Answer: B.16 days
Explanation: Total work to be done = 30 * 40 = 1200
Let 14 men leave the work after 'P' days, so that the remaining work is completed in 40 days after they leave the work.
40P + (14 * 40) = 1200
40P = 640 => P = 16 days
Answer:B
Question: In the coordinate plane, Line A has a slope of -1 and an x-intercept of 1. Line B has a slope of 4 and a y-intercept of -4. If the two lines intersect at the point (a,b), what is the sum a+b?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: The equation of Line A is y = -x + 1
The equation of Line B is y = 4x - 4
4x - 4 = -x + 1
x = 1
y = 0
The point of intersection is (1,0) and then a+b = 1.
The answer is B.
Question: A doctor prescribed 24 cubic centimeters of a certain drug to a patient whose body weight was 120 pounds. If the typical dosage is 2 cubic centimeters per 15 pounds of the body weight, by what percent was the prescribed dosage greater than the typical dosage?
A.8%
B.9%
C.50%
D.12.5%
Answer: D.12.5%
Explanation: Typical dosage per 15 pound of the body weight = 2 c.c
Typical dosage per 120 pound of the body weight = 2 *(120/15)
= 2 * 8
= 16 c.c
Dosage prescribed by doctor for 120 pound patient = 24 c.c
% prescribed dosage greater than the typical dosage = (24-16/16) *100%
=(8/16) *100%
= 50%
Answer D
Question: Car A runs at the speed of 65km/hr & reaches its destination in 8hr. Car B runs at the speed of 70 km/h & reaches its destination in 4h. What is the respective ratio of distances covered by Car A & Car B?
A.10 : 4
B.10 : 7
C.13 : 7
D.14 : 6
Answer: C.13 : 7
Explanation: Sol. Distance travelled by Car A = 65 × 8 = 520 km
Distance travelled by Car B = 70 × 4 = 280 km
Ratio = 520/280 = 13 : 7
C
Question: 3 gentlemen and 3 gentlewomen are candidates for 2vacancies. A voter has to vote for 2candidates. In how many ways can one cast his vote?
A.12
B.14
C.15
D.17
Answer: C.15
Explanation: There are 6 candidates and a voter has to vote for any two of them.
So, the required number of ways is,
= 6C2 = 6!/2!*4!
= 15.
C
Question: If p^2 – 8p + 15 = q, and p is a positive integer between 1 and 10, inclusive, what is the probability that q < 0?
A.1/10
B.1/5
C.2/5
D.3/5
Answer: A.1/10
Explanation: (p-5)(p-3) = q
p = 4 for this to be true, so
1/10
Ans :A
Question: A company assigns product codes consisting of all the letters in the alphabet.How many product codes are possible if the company uses at most 5 letters in its codes, and all letters can be repeated in any one code?
A.A.15600
B.B.1622654
C.C.12356630
D.D.24515230
Answer: C.C.12356630
Explanation: The no of ways in which the company can make codes of 1 letter : 26
# for 2 letters : 26*26 = 676
# for 3 letters : 26 * 26*26 =17576
# for 4 letters : 26 * 26*26*26 =456976
# for 5 letters : 26 * 26*26*26*26 =11881376
The total : By adding all of them , 26+676+17576+456976+11881376=12356630
C
Question: The food in a camp lasts for 40 men for 40 days. If ten more men join, how many days will the food last?
A.40 days
B.20 days
C.32 days
D.50 days
Answer: C.32 days
Explanation: one man can consume the same food in 40*40 = 1600 days.
10 more men join, the total number of men = 50
The number of days the food will last = 1600/50 = 32 days.
ANSWER:C
Question: How many positive integers less than 100 have a reminder 5 when divided by 7?
A.11
B.12
C.13
D.14
Answer: D.14
Explanation: take the multiples of 7 and add 5
0X7+5=5 ....13X7+5=96
there are 14 numbers
answer D
Question: If w and y are both odd prime numbers and w < y, how many distinct positive integer factors does 2wy have?
A.3
B.4
C.6
D.8
Answer: D.8
Explanation: Since 2wy prime factors are w^1*y^1*2^1, its total number or factors must be (1+1)(1+1)(1+1)=2^3=8. Thus, I think D would be the correct answer.D
Question: A crew can row a certain course up the stream in 84 minutes; they can row the same course down stream in 8 minutes less than they can row it in still water. How long would they take to row down with the stream
A.45 or 23 minutes
B.63 or 12 minutes
C.76 minutes
D.19 minutes
Answer: C.76 minutes
Explanation: A method has been discussed here to nullify the calculations though.
All I can input here is,
speed of a crew in still water = 1/2 ( speed upstream + speed downstream)
approximating this for time,
t = 1/2(84+ (t-8))
giving t = 76
C.
Question: In an engineering class that contained 150 students, the final exam consisted of 2 questions. Three fifths of the students answered the first question correctly. If four fifths of the remainder answered the second question correctly, how many students answered both questions incorrectly?
A.4
B.6
C.10
D.12
Answer: D.12
Explanation: 1st Question : Three fifths of the students answered the first question correctly - so 3/5âˆ—150=90
2nd Question : four fifths of the remainder answered the second question correctly so 4/5âˆ—(150âˆ’90)=4/5âˆ—60=48
total students who answered at least one Q correct =90+48=138
so students who answered BOTH incorrectly = 150âˆ’138=12
ANSWER:D
Question: A train 500 m long, running with a speed of 180 km/hr will pass a tree in?
A.17 sec
B.16 sec
C.18 sec
D.10 sec
Answer: D.10 sec
Explanation: Speed = 180 * 5/18
= 50 m/sec
Time taken = 500 * 1/50
= 10 sec
Answer: D
Question: When tossed, a certain coin has equal probability of landing on either side. If the coin is tossed 4 times, what is the probability that it will land twice on heads and twice tails?
A.1/8
B.1/4
C.1/16
D.1/32
Answer: C.1/16
Explanation: Must be twice on heads and twice on tails
1/2*1/2*1/2*1/2 = 1/16
Answer: C
Question: Two numbers are in ratio P:Q. when 1 is added to both the numerator and the denominator, the ratio gets changed to R/S. again, when 1 is added to both the numerator and denominator, it becomes 1/2. Find the sum of P and Q.
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: Solution: If we go through normal method, It will be quite cumbersome,so,
We will solve this question through options.
Taking option a: It has P+Q = 3. The possible value of P/Q is 1/2 or 2/1.
Using 1/2, we see that on adding 2 in both the numerator and denominator we get 3/4 (not required value.
Similarly we check for 2/1, this will also not give the required value.
OPTION b:
We have 1/3 possible ratio.
Then, we get the final value as 3/5 (not = to 1/2)
Hence, rejected.
Here we have 1/4 or 2/3.
Checking for 1/4 we get 3/6 = 1/2. Hence, the option is correct.
Option c:
Question: An alloy is to contain copper and zinc in the ratio 9:4. The zinc required to be melted with 24kg of copper is?
A.12kg
B.8.3kg
C.10.7kg
D.15.5kg
Answer: C.10.7kg
Explanation: Let the required quantity of copper be x kg
9:4::24:x
9x = 4*24
x = 10 2/3 kg = 32/3 = 10.7kg
Answer is C
Question: The speed of a car is 90 km in the first hour and 55 km in the second hour. What is the average speed of the car?
A.72.5 kmph
B.75 kmph
C.87 kmph
D.56 kmph
Answer: A.72.5 kmph
Explanation: S = (90 + 55)/2
= 72.5 kmph
Answer: A
Question: Find the sum 3/10 + 5/100 + 8/1000 in decimal form ?
A.0.853
B.0.358
C.3.58
D.8.35
Answer: B.0.358
Explanation: Answer
3/10 + 5/100 + 8/1000
= 0.3 + 0.05 + 0.008
= 0.358
Correct Option: B
Question: Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
A.2 years
B.4 years
C.5 years
D.6 years
Answer: D.6 years
Explanation: Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
Required difference = (42 - 36) years = 6 years.
answer :D
Question: What is the Units digit of (5!*4! - 3!*5!)/120
A.7
B.8
C.9
D.4
Answer: B.8
Explanation: (5!*4! - 3!*5!)/9
=5!(4! - 3!)/120
=120 (24-6)/120
=18
Units digit of the above product will be equal to 8
Answer B
Question: One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.
A.28 %
B.25 %
C.30 %
D.27%
Answer: D.27%
Explanation: Let the percentage of benzene =X
(30 - X)/(X- 25) = 6/4 = 3/2
=> 5X = 135 or
X = 27 so,
required percentage of benzene = 27 %
ANSWER:D
Question: Find avrg speed if a man travels at speed of 15km/hr up and 28km/hr dawn at an altitude of 230m.
A.25.8
B.19.5
C.18.0
D.12.2
Answer: B.19.5
Explanation: avg speed=2*x*y/(x+y)
=2*15*28/(15+28)=19.5
ANSWER:B
Question: If a farmer is splitting her crop of apples between her nine customers, how many would be left if she evenly divided the 541 apples?
A.1
B.3
C.5
D.6
Answer: A.1
Explanation: If a number is divisible by 9, the sum of its digits must be a multiple of 9.
Here,5+4+1=10. This means 1 apple will remain after the rest are divided among the nine customers.
A
Question: A sum of money becomes triple itself in 4 years at simple interest. How many years will it become six times at the same rate?
A.11 years
B.10 years
C.12 years
D.14 years
Answer: B.10 years
Explanation: 100 ---- 200 ---- 4
200 ---- 4
100 ---- 2
------------------
600 ---- 10 years
ANSWER:B
Question: If a company allocates 10 percent of its budget to advertising, 10 percent to capital improvements, and 5 percent to salaries, what fraction of its budget remains for other allocations?
A.1/4
B.2/4
C.3/4
D.1/5
Answer: C.3/4
Explanation: 100%-(10%+10%+5%)=75% remains for other allocations --> 75% = 75/100 = 3/4.
Answer: C.
Question: If the average of 10 digits is 80 and the average of 6 of them is 58, calculate the average of the remaining 4 numbers?
A.119
B.117
C.116
D.113
Answer: D.113
Explanation: Explanation:
Total of the 10 digits - 10*80 = 800
Total of the 6 digits - 6*58 = 348
Total of the remaining 4 digits - 800-348 = 452
average of the remaining 4 numbers = 452/4 = 113
ANSWER: D
Question: Find the C.I. on a sum of Rs.1600 for 9 months at 20% per annum, interest being compounded quarterly?
A.3388
B.2778
C.2522
D.2988
Answer: C.2522
Explanation: A = 1600(21/20)3 = 2522
Answer:C
Question: A company seeks to hire a sales manager, a shipping clerk, and a receptionist. The company has narrowed its candidate search and plans to interview all remaining candidates including 7 persons for the position of sales manager, 6 persons for the position of shipping clerk, and 10 persons for the position of receptionist. How many different hirings of these three people are possible?
A.7 + 6 + 10
B.7 × 6 × 10
C.21 × 20 × 19
D.7! + 6! + 10!
Answer: B.7 × 6 × 10
Explanation: 1 sales manager can be selected out of 7 in 7 ways
1 clerk can be selected out of 6 in 6 ways
1 receptionist can be selected out of 10 in 10 ways
total no. of ways these 3 can be selected = 7 *6 * 10
Ans. B) 7 × 6 × 10
Question: John had $100 to buy drinks and sandwiches for his birhtday party. He bought 5 small boxes of drinks at $4 each box and 8 boxes of sandwiches at $6 each box. How much money was left after the shopping?
A.$32
B.$33
C.$34
D.$35
Answer: A.$32
Explanation: Money spent on drinks
5 * 4 = $20
Money spent on sandwiches
8 * 6 = $48
Total money spent
20 + 48 = $68
Money left after shopping
100 - 68 = $32
correct answer A
Question: If 20% of a = b, then b% of 20 is the same as :
A.4% of a
B.8% of a
C.12% of a
D.9% of a
Answer: A.4% of a
Explanation: 20% of a = b
b% of 20 = = = = 4% of a.
Answer: a
Question: Find the length of the wire required to go 15 times round a square field containing 69696 m2?
A.15840
B.19879
C.27997
D.15842
Answer: A.15840
Explanation: a2 = 69696 => a = 264
4a = 1056
1056 * 15
=15840
Answer:A