RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: There are seven thieves. They stole diamonds from a diamond merchant and ran away. While running, night sets in and they decide to rest in the jungle.
When everybody was sleeping, two of them woke up and decided to divide the diamonds equally among themselves. But when they divided the diamonds equally, one diamond is left.
So they woke up the 3rd thief and tried to divide the diamonds equally again but still one diamond was left. Then they woke up the 4th thief to divide the diamonds equally again, and again one diamond was left. This happened with the 5th and 6th thief – one diamond was still left.
Finally, they woke up the 7th thief and this time the diamonds were divided equally.
How many diamonds did they steal in total?
A.300
B.301
C.302
D.303
Answer: B.301
Explanation: They stole 301 diamonds in total.
We need a number that is a multiple of 7 that will give a remainder of 1 when divided by 2, 3, 4, 5, and 6. The least common multiple of these numbers is 60. So, we need a multiple of 7 that is 1 greater than a multiple of 60.
60 + 1 = 61, not a multiple of 7
60 x 2 + 1 = 121, not a multiple of 7
60 x 3 + 1 = 181, not a multiple of 7
60 x 4 + 1 = 241, not a multiple of 7
60 x 5 + 1 = 301, a multiple of 7
Answer B
Question: How many seconds will a 500 m long train take to cros a man walking with a speed of 3 kmph in the direction of the moving train if the speed of the train is 63 kmph
A.25
B.30
C.40
D.45
Answer: B.30
Explanation: time=distance(here length of the train)/relative speed (63-3)
thus time=500/60*5/18=500*18/ 60*5
=30 seconds
ANSWER:B
Question: If there are Six periods in each working day of a school, In how many ways can one arrange 5 subjects such that each subject is allowed at least one period?
A.2388
B.3600
C.2791
D.1817
Answer: B.3600
Explanation: To arrange 6 periods with 5 subjects, then one subject can be arranged in two slots.
5 Subjects can be arranged in 6 periods in 6P56P5 ways and now we have 1 period which we can fill with any of the 5 subjects in 5 ways. so 6P5×5=6P5×5=3600
Alternate method:
Assume the subjects are X1, X2, A, B , C, D,. Here X is the subject which repeats. So arranging 6 objects in 6 places will be equal to 6! = 720 (here no need to divide this number with 2! as even though the subject is same, but not identical)
But this repeated subect can be any of the five. So total arrangements are 720 x 5 = 3600
Answer:	B
Question: If 5√5 x 5^3 + 5^-3/2 = 5 ^(a + 2), then the value of a is:
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: 5^1x5^1/2x5^3+5^-3/2 = 5^(a+2)
5^3/2x5^3+5^-3/2
5^9/2+5^-3/2
5^6/2
5^3 = 5^(a+2)
now, 3 = a+2
a=1
ANSWER:B
Question: The diagonals of a rhombus are 10 cm and 12 cm. Find its area?
A.158
B.60
C.150
D.123
Answer: B.60
Explanation: 1/2 * 10 * 12 = 60
Answer:B
Question: A and B start a business with investments of Rs.5000 and Rs.4500 respectively.After 4 months,A takes out half of his capital.After two more months,B takes out one-third of his capital while C joins them with a capital of Rs.7000.At the end of a year,they earn a profit of Rs.5080.Find the share of each member in the profit.
A.A - Rs.1400,B - Rs.1900,C - Rs.1780
B.A - Rs.1600,B - Rs.1800,C - Rs.1680
C.A - Rs.1800,B - Rs.1500,C - Rs.1780
D.A - Rs.1680,B - Rs.1600,C - Rs.1800
Answer: B.A - Rs.1600,B - Rs.1800,C - Rs.1680
Explanation: Solution
A : B : C =(5000x4+2500x8) : (4500x6+3000x6): (7000x6)
= 40000 : 42000 : 45000 = 4 : 42 : 45.
A’s share = Rs. (5080x40/127) = Rs. 1600.
B’s share = Rs. (5080x45/127) = Rs. 1800.
C’s share = Rs. (5080x42/127) = Rs. 1680. Answer B
Question: What is the least number should be added to 1100, so the sum of the number is completely divisible by 23?
A.1
B.2
C.5
D.4
Answer: D.4
Explanation: (1100 / 23) gives remainder 19
19 + 4 = 23, So we need to add 4
Answer : D
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
A.22
B.50
C.99
D.288
Answer: B.50
Explanation: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45 ==> x = 50 km/hr.Answer: B
Question: If d<0, which of the following represents a positive number?
A.d|d|
B.|d|d
C.|d|/d
D.-d|d|
Answer: D.-d|d|
Explanation: Answer : D
Question: A circular mat with diameter 18 inches is placed on a square tabletop, each of whose sides is 24 inches long. Which of the following is closest to the fraction of the tabletop covered by the mat?
A.5/12
B.3/5
C.1/2
D.3/8
Answer: D.3/8
Explanation: SO we are looking for the area of the cloth over the area of the table
Area of the Cloth = (pi)(r)^2 which is about (3)(9)(9)
Area of the Table = (24)(24)
So the quick way to estimate is looking at the fraction like this: (3/24)(81/24)
I hope this is easy to follow, so with some simplification i get (1/8)(3) = (3/8) Answer is D
Question: A relay has a series of 5 circuits in a line. The even-numbered circuits are control circuits; the odd are buffer circuits. If both a control circuit and the buffer circuit immediately following it both fail in that order, then the relay fails. The probability of circuit one failing is 3/8; circuit two, 7/8; circuit three, 3/10; circuit four, 3/4; and circuit five, 2/5 .What is the probability that the relay fails?
A.9/80
B.3/10
C.387/800
D.35/80
Answer: C.387/800
Explanation: The first circuit doesn't matter.
Prob(relay fails) = 1 - Prob(relay succeeds)
Prob(2+3 work) = 1 - 21/80 = 59/80
Prob(4+5 work) = 1 - 3/10 = 7/10
Prob(relay fails) = 1 - Prob(2+3 work AND 4+5 work) = 1 - (59/80)(7/10) = 1 - 413/800 = 387/800
C
Question: If A, B and C together can finish a piece of work in 4 days. A alone in 12 days and B in 24 days, then C alone can do it in?
A.1
B.7
C.8
D.9
Answer: C.8
Explanation: C = 1/4 - 1/12 – 1/24 = 1/8 => 8 days'
Answer: C
Question: If the price of an article went up by 20%, then by what percent should it be brought down to bring it back to its original price?
A.16 2/3%
B.16 2/6%
C.16 8/3%
D.17 2/3%
Answer: A.16 2/3%
Explanation: Let the price of the article be Rs. 100.
20% of 100 = 20.
New price = 100 + 20 = Rs. 120
Required percentage = (120 - 100)/120 * 100
= 20/120 * 100 = 50/3 = 16 2/3%.
Answer:A
Question: Both Robert and Alice leave from the same location at 6:00 a.m. driving in the same direction, but in separate cars. Robert drives 30 miles per hour while Alice drives 40 miles per hour. After 6 hours, Alice’s car stops. At what time will Robert’s car reach Alice’s car?
A.2 p.m.
B.3 p.m.
C.4 p.m.
D.8 p.m.
Answer: A.2 p.m.
Explanation: 6:00 am so 6 hours later is 12:00 pm
In six hours, Robert will have driven 6*30 = 180 miles
In six hours, Alive will have driven 6*40 = 240 miles
So Robert needs 240-180 = 60 miles do catch Alice up.
So at 30 mph, he will need 2 hours
12:00 pm + 2 hours = 2:00 pm
ANS : A
Question: a merchant sold an article at a loss of 12%,. if the selling price had been increased by $50 the merchant would have made a profit of 8%. what is the cost price of the article?
A.$550
B.$500
C.$510
D.$565
Answer: B.$500
Explanation: Let C.P. be $x
Then 108% of x - 88% of x = 100
20% of x = 100
x/5 = 100
x = 500
Answer is B
Question: Last year 26 members of a certain club traveled to England, 26 members traveled to France, and 32 members traveled to Italy. Last year 12 members of the club traveled to both England and France, 6 members traveled to both England and Italy, and 0 members traveled to both France and Italy. How many members of the club traveled to at least one of these three countries last year?
A.52
B.67
C.71
D.66
Answer: D.66
Explanation: n(E or F or I) = n(E) + n(F) + n(I) - n(E and F) - n(F and I) - n(I and E) +n(E and F and I)
n(E or F or I) = 26 + 26 + 32 - 12 - 0 - 6 + 0
Why is the number of people who traveled to E and F and I 0? Because no one traveled to both England and France. So obviously, no one would have traveled to England, France and Italy.
n(E or F or I) = 66
Answer (D)
Question: A glass was filled with 25 ounces of water, and 0.04 ounce of the water evaporated each day during a 10-day period. What percent of the original amount of water evaporated during this period?
A.0.004%
B.0.04%
C.0.4%
D.1.6%
Answer: D.1.6%
Explanation: In 10 days 10*0.04=0.4 ounces of water evaporated, which is 0.4/25âˆ—100=1.6 of the original amount of water.
Answer: D.
Question: How long does a train 110 m long running at the speed of 36 km/hr takes to cross a bridge 132 m length?
A.12.9 sec
B.12.1 sec
C.24.2 sec
D.16.8 sec
Answer: C.24.2 sec
Explanation: Speed = 36 * 5/18 = 10 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/10 = 24.2 sec.
Answer: C
Question: The wheel of a motorcycle 70cm in diameter makes 40 revolutions in every 10sec.What is the speed of motorcycle n km/hr?
A.31.65
B.31.68
C.31.62
D.31.61
Answer: B.31.68
Explanation: Explanation:
In this type of question, we will first calculate the distance covered in given time.
Distance covered will be : Number of revolutions x Circumference
So we will be having distance and time, from which we can calculate the speed.
Radius of wheel = 70 / 2 = 35 cm
Distance covered in 40 revolutions will be = 88 m
Distance covered in 1 sec =
Answer: B) 31.68kmph
Question: On dividing 15968 by a certain number, the quotient is 89 and the remainder is 37. Find the divisor.
A.179
B.189
C.199
D.169
Answer: A.179
Explanation: Divisor = Dividend - Remainder / Quotient
= 15968-37 / 89
= 179.
Answer is A.
Question: A garrison of 500 persons had provisions for 27 days. After 3 days a reinforcement of 300 persons arrived. For how many more days will the remaining food last now?
A.12 days
B.16 days
C.14 days
D.15 days
Answer: D.15 days
Explanation: Explanation :
Given that fort had provision for 500 persons for 27 days
Hence, after 3 days, the remaining food is sufficient for 500 persons for 24 days
Remaining persons after 3 days = 500 + 300 = 800
Assume that after 10 days,the remaining food is sufficient for 800 persons for x days
More men, Less days (Indirect Proportion)
⇒Men500:800}::x:24
⇒500 × 24 = 800x
⇒ 5 × 24 = 8x
⇒ x = 5 × 3 = 15. Answer : Option D
Question: A business executive and his client are charging their dinner tab on the executive's expense account.The company will only allow them to spend a total of 75$ for the meal.Assuming that they will pay 7% in sales tax for the meal and leave a 15% tip,what is the most their food can cost?
A.69.55$
B.50.63$
C.60.95$
D.52.15$
Answer: C.60.95$
Explanation: let x is the cost of the food
1.07x is the gross bill after including sales tax
1.15* 1.07x=75
x=60.95
Hence, the correct option is C
Question: A highway is to be divided into 3 lanes. For this purpose, two yellow stripes are painted so that stripes divide the highway into 3 lanes. If 2 gallons of paint cover an area of 3P square feet of highway, how many gallons of paint are needed to paint two stripes x inches wide on a stretch of highway m miles long? (1 mile = 5280 feet and 1 feet = 12 inches)
A.440P/mx
B.880mx/P
C.880mx/3P
D.1760mx/3P
Answer: D.1760mx/3P
Explanation: 1 square foot needs 2/3P gallons of paint.
The width of each stripe is x/12 feet.
The length of each stripe is 5280m feet.
The area of each stripe is (5280m)(x/12) = 440mx square feet.
For two stripes, the total area is 880mx square feet.
The number of gallons needed is (880mx)*(2/3P) = 1760mx/3P gallons.
The answer is D.
Question: A train 330 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
A.5
B.6
C.7
D.18
Answer: D.18
Explanation: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [330 * 3/55] sec
= 18 sec
Answer: D
Question: What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?
A.288
B.500
C.299
D.2766
Answer: B.500
Explanation: 70 = (P*4*7/2)/100
P = 500.Answer: B
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
A.1/455
B.1/487
C.1/429
D.1/876
Answer: A.1/455
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue
= 3C3/15C3
= (1 * 3 * 2 * 1)/(15 * 14 * 13)
= 1/455
Answer:A
Question: r=4^(n+2), then in terms of r, 9^n=
A.r^2/81
B.r^2/9
C.r^2/256
D.r/3
Answer: C.r^2/256
Explanation: Questions in terms of variables can be easily solved by plugging in some values: Say n = 0
r = 4^2 = 16
and you need the value of 16^n which is 16^0 = 1
So when you put r = 16 in the options, you should get 1. Only option (A) satisfies.
Answer (C)
Question: Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is:
A.30%
B.100/3%
C.35%
D.44%
Answer: D.44%
Explanation: Explanation :
C.P. of 6 articles = Rs. 5
=> C.P. of 1 article = Rs. 5/6
S.P. of 5 articles = Rs. 6
=> S.P. of 1 article = Rs. 6/5
Profit earned per article = 6/5 - 5/6 = 11/30
% Profit = 11/30∗6/5∗100% = 44%
Answer : D
Question: Three coins are tossed. What is the probability of getting at most two tails?
A.2
B.6/7
C.7/8
D.25
Answer: C.7/8
Explanation: Explanation :
Total number of outcomes possible when a coin is tossed = 2
Hence, total number of outcomes possible when 3 coins are tossed, n(S) = 2 × 2 × 2 = 8
E = event of getting at most two Tails = {TTH, THT, HTT, THH, HTH, HHT, HHH}
Hence, p(E)=n(E)/n(S)=7/8
C
Question: At present, the ratio between the ages of Arun and Deepak is 4:3. After 6 years, Arun's age will be 38 years. What is the age of Deepak at present?
A.77 years
B.15 years
C.66 years
D.24 years
Answer: D.24 years
Explanation: Let the present ages of Arun and Deepak be 4x and 3x years respectively.
Then, 4x + 6 = 38 => x = 8
Deepak's age = 3x = 24 years.
Answer: D
Question: Two trains running in opposite directions cross a man standing on the platform in 20 seconds and 18 seconds respectively and they cross each other in 19 seconds. The ratio of their speeds is:
A.1 : 1
B.3 : 2
C.3 : 8
D.3 : 25
Answer: A.1 : 1
Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 20 x meters, and length of the second train = 18 y meters. (20 x + 15 y) / (x + y) = 19
==> 20 x + 18 y = 19 x + 19 y ==> x = y ==> x/y = 1/1
Answer: Option A
Question: Find the value of 72519 x 9999 = m?
A.34545481
B.45461743
C.24117456
D.725117481
Answer: D.725117481
Explanation: 72519 x 9999 = 72519 x (10000 - 1)
= 72519 x 10000 - 72519 x 1
= 725190000 - 72519
= 725117481
D
Question: A man invested Rs. 14,400 in Rs. 100 shares of a company at 20 % premium . If the company declares 5% dividend at the end of the year , then how much does he get ?
A.500
B.600
C.650
D.700
Answer: B.600
Explanation: No of shares = 14400/120 = 120
Face value = 100*120 = 12000
Annual income = 5/100*12000 = 600
ANSWER B
Question: A trader sells 75 meters of cloth for Rs. 4950 at the profit of Rs. 15 per metre of cloth. What is the cost price of one metre of cloth?
A.51
B.88
C.90
D.42
Answer: A.51
Explanation: SP of 1m of cloth = 4950/75 = Rs. 66
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 66 - Rs. 15 = Rs. 51
Answer:A
Question: Molly is rolling a number cube with faces numbered 1 to 6 repeatedly. When she receives a 2, she will stop rolling the cube. What is the probability that Molly will roll the die less than 2 times before stopping?
A.11/180
B.1/6
C.25/216
D.91/216
Answer: B.1/6
Explanation: The probability that Molly will roll the die less than 4 times before stopping is the sum of the following:
The probability that Molly will roll the die once: P=1/6 (she gets 2 on the first roll);
P = 1/6
Answer: B
Question: There are 11 boys and 10 girls in a class. If three students are selected at random, in how many ways that 3 girl & 2 boys are selected ?
A.6600
B.1300
C.6780
D.1976
Answer: A.6600
Explanation: E = event that 3 girl and 2 boys are selected
n(E) = we have to select 2 boys from 11 and 3 girl from 10
= 11C2 * 10C3
= 6600
Ans - A
Question: If the population of a certain country increases at the rate of 1 person every 60 seconds, by how many persons does the population increase in 2 Hours?
A.120
B.80
C.100
D.150
Answer: A.120
Explanation: Answer = 1 * 120(2 hour = 120 minutes)= 120
Answer = A
Question: Reena and Shaloo are partners in a business, Reena invests Rs, 35,000 for 8 months and Shaloo invests Rs. 42,000 for 10 months, out of a profit of Rs. 31,570, Reena's share is ?
A.12628
B.12228
C.22812
D.12727
Answer: A.12628
Explanation: Ratio of their shares = (35000 * 8) : (42000 * 10) = 2 : 3.
Reena's share Rs. 31570 * (2 / 5) = Rs. 12628
Answer: A
Question: A four-character password consists of one letter of the alphabet and three different digits between 1 and 9, inclusive. The letter must appear as the second or third character of the password. How many different passwords are possible?
A.5,040
B.18,720
C.26,208
D.37,440
Answer: C.26,208
Explanation: 4 character password: DLDD
First digit can be chosen in 9 ways.
The letter can be chosen in 26 ways.
Next digit can be chosen in 8 ways.
Next digit can be chosen in 7 ways.
This gives us 9*26*8*7ways
Now, the letter can also be DDLD so there will be another 9*26*8*7 ways
Total = 9*26*8*7*2 = 26,208 ways C
Question: Factor | Percent of Respondents |
User-friendly | 56% |
Fast response time | 48% |
Bargain prices | 42% |
The table gives three factors to be considered when choosing an Internet service provider and the percent of the 1,100 respondents to a survey who cited that factor as important. If 30 percent of the respondents cited both “user-friendly” and “fast response time,” what is the maximum possible number of respondents who cited “bargain prices,” but neither “user-friendly” nor “fast response time?”
A.286
B.336
C.360
D.384
Answer: A.286
Explanation: The way I looked at is is as follows:
UserFriendly(UF) + FastResponse (FR) = 30%
UF leftover = 56 - 30 = 26%
FR leftover = 48 - 30 = 18%
Sum these = 74% (ie. 74% were either UF+FR, UF, FR)
26% leftover is the maximum number for Bargain Price
26/100 * 1100 = 26 * 11 = 286 (A).
Question: A type of extra-large SUV averages 12.2 miles per gallon (mpg) on the highway, but only 7.6 mpg in the city. What is the maximum distance, in miles, that this SUV could be driven on 25 gallons of gasoline?
A.190
B.284.6
C.300
D.305
Answer: D.305
Explanation: To maximize the distance that SUV could be driven on 25 gallons of gasoline , we need consider only highway driving .
Max distance = 25 * 12.2 = 305
Answer D
Question: Square RSTU shown above is rotated in a plane about its center in a clockwise direction the minimum number of degrees necessary for T to be in the position where R is now shown. The number of degrees through which RSTU is rotated is
A. 135 degree
B. 180 degree
C. 225 degree
D. 270 degree
Answer: B. 180 degree
Explanation: From the options, I am assuming the positioning of R and T relative to each other to be as shown. To replace R by T, focus on OT. Say, you rotate OT clockwise (and with it the entire square) and bring it in place of OR. How many degrees did you go? You covered 2 right angles i.e. 180 degrees.
Answer : B
Question: A man swims downstream 35 km and upstream 20 km taking 5 hours each time, what is the speed of the man in still water?
A.6.5
B.5.5
C.5.2
D.4.6
Answer: B.5.5
Explanation: 35 --- 5 DS = 7
? ---- 1
20 ---- 5 US = 4
? ---- 1 M = ?
M = (7+ 4)/2 = 5.5
Answer: B
Question: The ratio of number of students studying Arts, Commerce and Science in a College is 3 : 7 :8. What is the new ratio of the number of students studying Arts, Commerce and Science respectively if there is an increase of 20%, 40% and 25% in the number of students studying Arts, Commerce and Science?
A.18 : 35 : 50
B.18 : 49 : 50
C.4 : 8 : 5
D.32 : 35 : 25
Answer: B.18 : 49 : 50
Explanation: Suppose the number of students studying Arts, Commerce and Science be 3x, 7x and 8x respectively.
When their numbers are increased by 20%, 40% and 25% respectively the new ratio becomes
3x × 120% : 7x × 140% :
8x × 125% = 36 : 98 : 100
= 18 : 49 : 50
Answer B
Question: For an integer x greater than 1, x* denotes the product of all the integers from 1 to x inclusive. How many prime numbers are there between 7*+2 and 7*+7, inclusive ?
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: Given that x* denotes the product of all the integers from 1 to n, inclusive so, 7* + 2 = 7! + 2 and 7* + 7 = 7! + 7.
Now, notice that we can factor out 2 our of 7! + 2 so it cannot be a prime number, we can factor out 3 our of 7! + 3 so it cannot be a prime number, we can factor out 4 our of 7! + 4 so it cannot be a prime number, ... The same way for all numbers between 7! + 2 and 7! +7, inclusive. Which means that there are no primes in this range.
Answer: A.
Question: If (m-8) is a factor of m^2-sm-24, then s=
A.3
B.5
C.6
D.11
Answer: B.5
Explanation: (m-8)(m-a)=m^2-sm-24
A=-3
s=8+a=5=D=B
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions?
A.187 m
B.704 m
C.179 m
D.127 m
Answer: B.704 m
Explanation: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4
= 70400 cm
= 704 m
Answer:B
Question: By selling 150 mangoes, a fruit-seller gains the selling price of 30 mangoes. Find the gain percent?
A.28%
B.25%
C.95%
D.75%
Answer: B.25%
Explanation: SP = CP + g
150 SP = 150 CP + 30 SP
120 SP = 150 CP
120 --- 30 CP
100 --- ? => 25%
Answer:B
Question: A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
A.1/13
B.2/13
C.1/26
D.2/26
Answer: C.1/26
Explanation: Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
P(E) =	n(E)/n(S)	=2/52=1/26
Option C
Question: A sales staff is composed of a sales manager and two sales people, all of whom earn commission as a percentage of sales. Each sales person earns 5% commission on sales. In a given week, the sales staff earned a total of $1,500 in commissions on $5,000 worth of sales. What commission rate did the sales manager earn during that week?
A.20%
B.30%
C.35%
D.40%
Answer: A.20%
Explanation: A for me.
Let managers comminsion rate be M.
m*5000+ 2*0.05*5000=1500
5000*m=1000
m=20/100=20%
Question: A certain lab experiments with white and brown mice only. In one experiment, 2/5 of the mice are brown. If there are 12 white mice in the experiment, how many mice in total are in the experiment?
A.20
B.12
C.15
D.18
Answer: A.20
Explanation: Let total number of mice = M
Number of brown mice = 2/5M
Number of white mice = 3/5 M = 12
=> M = 20
Answer A
Question: The greatest number of four digits which is divisible by 15, 25, 40 and 75 is:
A.9000
B.9400
C.9600
D.9800
Answer: C.9600
Explanation: EXPLANATION
Greatest number of 4-digits is 9999.
L.C.M. of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399.
Required number (9999 – 399) = 9600.
Answer C
Question: What will come in place of the x in the following Number series? 46080, 3840, 384, x
A.48
B.3
C.4
D.5
Answer: A.48
Explanation: 46080 /12 = 3840
3840 /10 = 384
384 /8 = 48
A
Question: An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
A.16 4/3%
B.100/3%
C.16%
D.16 2/3%
Answer: D.16 2/3%
Explanation: Explanation:
600 ---- 100
100 ---- ? => 16 2/3%
ANSWER IS D
Question: Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 3 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is?
A.887 gallons
B.176 gallons
C.120 gallons
D.289 gallons
Answer: C.120 gallons
Explanation: Work done by the waste pipe in 1 minute
= 1/15 - (1/20 + 1/24) = - 1/40
Volume of 1/40 part
= 3 gallons
Volume of whole = 3 * 40
= 120 gallons.
Answer:C
Question: The food in a camp lasts for 20 men for 50 days. If twenty more men join, how many days will the food last?
A.22 days
B.25 days
C.28 days
D.16 days
Answer: B.25 days
Explanation: one man can consume the same food in 20*50 = 1000 days.
20 more men join, the total number of men = 40
The number of days the food will last = 1000/40 = 25 days.
Answer:B