RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A dishonest person wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing 33 $ per litre so as to make a profit of 60% on cost when he sells the resulting milk and water mixture for 36$. In what ratio should he mix the water and milk?
A.7:15
B.7:10
C.7:8
D.7:4
Answer: A.7:15
Explanation: First of all, let's consider 1 liter of the stuff he is going to sell --- naive customers think it's pure milk, but we know it's some milk-water mixture. He is going to sell this liter of milk-water for $36.
This $36 should be a 60% increase over cost. Here, we need to think about percentage increases as multipliers.
Using multipliers
(cost)*1.60 = $36
cost = 36/1.6 = $22.5
If he wants a 60% increase over cost on the sale of one liter of his milk-water, the cost has to be $22.5
Well, a liter of milk costs $33, so if he is going to use just $30 of milk in his mixture, that's 22.5/33 = 15/22 of a liter. If milk is 15/22 of the liter, then water is 7/22 of the liter, and the ratio of water to milk is 7:15. Answer choice(A)
Question: The ratio between the number of sheep and the number of horses at the Stewart farm is 2 to 7, If each horse is fed 230 ounces of horse food per day and the farm needs a total 12,880 ounces of horse food per day, what is the number of sheep in the farm?
A.18
B.16
C.32
D.56
Answer: B.16
Explanation: Let the number of sheeps and horses be 4x and 7x.
Now total number of horses = total consumption of horse food/consumption per horse = 12880/230 = 56, which is equal to 7x. => x = 8
Sheeps = 2x = 2*8 = 16. Hence B
Question: In a group of 90 people, 55 have visited Iceland and 33 have visited Norway. If 51 people have visited both Iceland and Norway, how many people have visited neither country?
A.50
B.51
C.52
D.53
Answer: D.53
Explanation: This is an example of a standard Overlapping Sets question. It has no 'twists' to it, so you'll likely find using the Overlapping Sets Formula to be a fairly easy approach. If you're not familiar with it, then here is the Formula:
90= 55 + 33 - 51 + (# in Neither Group)
=53
The prompt gives you all of the numbers you need to get to the correct answer. Just plug in and solve.
D
Question: What is the smallest positive integer x such that 280-x is the cube of a positive integer
A.5
B.64
C.62
D.60
Answer: B.64
Explanation: Given 280-x is a perfect cube
so we will take 216= 6*6*6
280-x = 216
x =280-216 = 64
correct option is B
Question: If a farmer sells 15 of his chickens, his stock of feed will last for 4 more days than planned, but if he buys 10 more chickens, he will run out of feed 6 days earlier than planned. If no chickens are sold or bought, the farmer will be exactly on schedule. How many chickens does the farmer have?
A.20
B.50
C.40
D.30
Answer: D.30
Explanation: Let x = total feed required for the planned period
n= number of chicken
t = total time of the planned feed
x = nt
1) x = (n-15) * (t+4)
2) x = (n+10) * (t-6)
equating 1&2
(n-15) * (t+4) = (n+10) * (t-6) or nt+4n-15t-60 =nt-6n+10t-60
10n = 25t
n =5/2 *t or t = 2n/5
x= n *2n/5
substituting this value in 1
n * 2n/5 = (n-15) * (2n/5+4)
2n = 60
n =30
D
Question: If p + | p | = 0, which of the following must be true?
A.p > 0
B.p≥0
C.p < 0
D.p≤0
Answer: D.p≤0
Explanation: Manipulate the equations:
p + | p | = 0
|p| = -p
-p > 0 OR -p = 0
This means p could be 0 or p is less than 0.
D. p≤0
E. p=0
Answer: D
Question: A positive whole number has factors of 5 and 10. The number MUST be divisible by:
I. 10
II. 30
III. 60
A.I
B.II
C.I & II
D.III
Answer: D.III
Explanation: 10 , 30 is not divisible by 60.But 60 is divisible by 5,10,30,60.
So answer is III
Answer : D
Question: One-third of Rahul's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,25,000 as total savings, how much has he saved in Public Provident Fund ?
A.80000
B.60000
C.50000
D.75000
Answer: C.50000
Explanation: Let savings in N.S.C and P.P.F. be Rs. x and Rs. (125000 - x) respectively. Then,
=1/3 x = 1/2 (125000 - x)
=x/3 + x/2 = 62500
=5x/6 = 62500
=x = 62500 x 6 /5	= 75000
Savings in Public Provident Fund = Rs. (125000 - 75000) = Rs. 50000
Answer is C.
Question: Of 70 players on a football team, 31 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total?
A.57
B.59
C.63
D.71
Answer: A.57
Explanation: Total = 70
Thrower = 31
Rest = 70 - 31 = 39
Left Handed = 39/3 = 13
Right handed = 26
If all Thrower are right handed then total right handed is 31 + 26 = 57
so A. 57 is the right answer
Question: There are 2 vessels A & B containing 25 liters each of pure milk and pure water respectively. 5 liters of milk from A is taken and poured into B , then 6 liters of mixture from B is taken and poured in A. What is ratio of water A and B respectively.
A.1:3
B.1:4
C.1:5
D.1:6
Answer: B.1:4
Explanation: At first
A cotain Milk = 25 Water = 0
B cotain Milk = 00 Water = 25
5 litres of milk taken from A and poured in B then
A cotain Milk = 20 Water = 0
B cotain Milk = 5 Water = 25
6 litres(1 lit Milk & 5 lit Water) of mixture from B and poured in A.
So, Finally
A cotain Milk = 21 Water = 5
B cotain Milk = 4 Water = 20
Ratio of water in A & B is 5:20 = 1:4
ANSWER:B
Question: A certain number of men can finish a piece of work in 10 days. However, if there were 10 less men it will take 10 days more for the work to be finished. How many men were there originally?
A.10 men
B.30 men
C.40 men
D.20 men
Answer: D.20 men
Explanation: Let x be the number of men originally
Thus, 10x=(10+10)(x-10)
10x=20(x-10)
x=2(x-10)
x = 20
ANSWER:D
Question: A letter lock consists of two rings each marked with four different letters. The number of distinct unsuccessful attempts to open the lock is at the most ?
A.17
B.19
C.15
D.168
Answer: C.15
Explanation: Since each ring consists of four different letters, the total number of attempts possible with the two rings is
= 4*4 = 16. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts
= 16 - 1
= 15.
Answer: C
Question: how many prime no. are there from 0 to 50?
A.14
B.15
C.16
D.17
Answer: B.15
Explanation: we calculate it manually.we know the definition of prime no.prime no. should only have two distinctâ€‹ natural no. divisor 1 and itself.
note:1 is not a prime no.
2,3,5,7,11,13,17,19,23,29,31,37,41,43,47
total no.=15
answer B
Question: Boston is 4 hr ahead of Frankfurt and 2 hr behind India. X leaves Frankfurt at 6 p.m. on Friday and reaches Boston the next day. After waiting there for 2 hr, he leaves exactly at noon and reaches India at 1 a.m. On his return journey, he takes the same route as before, but halts at Boston for 1hr less than his previous halt there. He then proceeds to Frankfurt.
What is X's average speed for the entire journey (to and fro)?
A.176 mph
B.180 mph
C.165 mph
D.Data insufficient
Answer: B.180 mph
Explanation: Explanation :
X reaches Boston at 10 AM. At the same moment, time in Frankfurt is 6 AM. Hence, the journey time was 12 hours.
X reaches India at 1 AM. At the same moment, time in Boston is 11 PM. Hence, the journey time was 11 hours.
Waiting time = 2 hours.
So, total time = 12 + 2 + 11 = 25 hours.
Avg speed = 180 mph .
Answer : B
Question: If P's height is 40% less than that of Q, how much percent Q's height is more than that of P?
A.75.56%
B.66.66%
C.70.05%
D.80%
Answer: B.66.66%
Explanation: Excess of Q's height over P =(40/(100-40))*100
= => 66.66%
ANSWER B
Question: Car A runs at the speed of 35 km/hr & reaches its destination in 10hr. Car B runs at the speed of 25 km/h & reaches its destination in 6h. What is the respective ratio of distances covered by Car A & Car B?
A.7 : 3
B.5 : 7
C.9 : 7
D.3 : 5
Answer: A.7 : 3
Explanation: Sol. Distance travelled by Car A = 36 × 10 = 350 km
Distance travelled by Car B = 25 × 6 = 150 km
Ratio = 350/150 = 7 : 3
A
Question: If a certain sample of data has a mean of 10.0 and a standard deviation of 2.0, which of the following pairs contain two values that are each at least 2.5 standard deviations from the mean?
A.(5.0; 16.5)
B.(8.5; 21.0)
C.(14.0; 26.5)
D.(16.5; 26.0)
Answer: A.(5.0; 16.5)
Explanation: 2.5 standard deviation equals to 2.5*2=5;
2.5 standard deviations from the mean, so5 points, from the mean is the range from {mean-5} to {mean+5}, so from 5 to 15:
The correct answer choice must cover all this range: only answer choice A does this.
Answer:A.
Question: A sum of money is distributed among w,x,y,z in the proportion of 4:2:5:3. If y gets $500 more than z, what is the x's share?
A.$4000
B.$500
C.$2500
D.$2800
Answer: B.$500
Explanation: Let the shares of w,x,y,z are 4a,2a,5a,3a
5a-3a = 500
2a = 500,a=250
x's share = 2a = $500
Answer is B
Question: In a group of 80 children and 30 youngsters, each child got sweets that are 15% of the total number of children and each youngster got sweets that are 25% of the total number of children. How many sweets were there?
A.1140
B.1160
C.1180
D.1560
Answer: D.1560
Explanation: Number of sweets each child got = 15% of 80 = 15/100 * 80 = 12.
Number of sweets 80 children got = 80 * 12 = 960.
Number of sweets each youngster got = 25% of 80 = 25/100 * 80 = 20.
Number of sweets 10 youngsters got = 30 * 20 = 600.
Total number of sweets = 960 + 200 = 1560.
D)
Question: How many diagonals does a 63-sided convex polygon have?
A.1890
B.1953
C.3780
D.3843
Answer: A.1890
Explanation: A 63-sided convex polygon has 63 vertices.
If we examine a single vertex, we can see that we can connect it with 60 other vertices to create a diagonal. NOTE: there are 60 options because we can't connect the vertex to ITSELF, and we can't connect it to its ADJACENT vertices, since this would not create a diagonal.
If each of the 63 vertices can be connected with 60 vertices to create a diagonal then...
...the total number of diagonals = (63)(60) = 3780
HOWEVER, before we select answer choice C, we must recognize that we have counted every diagonal TWICE.
For example, we might connect vertex A with vertex F and count that as 1 diagonal, and at the same time we connect vertex F with vertex A and count that as 1 diagonal. Of course these diagonals are the SAME.
To account for counting each diagonal twice, we must divide 3780 by 2 to get: 1890
ANSWER:A
Question: Which of the following is(are) true for a@b=b@a?
I. a@b=b+ba
II. a@b=(a+b)(a-b)
III. a@b=(a/b)+(b/a)
A.only Ⅰ
B.only Ⅱ
C.only Ⅲ
D.only ⅠⅢ
Answer: A.only Ⅰ
Explanation: -> If I. a@b=ab+ba, a@b=ab+ba=ba+ab=b@a (X).
If II. a@b=(a+b)(a-b), a@b=(a+b)(a-b)≠(b+a)/(b-a)=b@a (O).
If III.a@b=(a/b)+(b/a), a@b=(a/b)+(b/a)=(b/a)+(a/b)=b@a (O).
Thus, ⅠⅢ are the answers. Therefore, A is the answer.
Question: ♠n denotes the number obtained when n is rounded to the nearest tenth. For example ♠4.31 = 4.3
♠0.089 - ♠2.135 =
A.1.05
B.1.04
C.-1.05
D.-2
Answer: D.-2
Explanation: ♠0.089 - ♠2.135 =
0.1 - 2.1 = -2
Answer : D
Question: The simplified value of 1.2 + (1.2)2 + (1.2)3 is:
A.4.248
B.4.368
C.3.248
D.3.368
Answer: B.4.368
Explanation: The expression is in geometric progression with a common ratio of 1.2. Formula to sum a geometric sequence is a(1-r^n)/1-r where a=r=1.2.Solving it we get the ans as 4.368
ANSWER:B
Question: A person jogged 10 times along the perimeter of a rectangular field at the rate of 12 kilometers per hour for 30 minutes. If field has a length that is twice its width, find the area of the field in square meters.
A.70,000 square meters
B.60,000 square meters
C.50,000 square meters
D.20,000 square meters
Answer: D.20,000 square meters
Explanation: Let us first find the distance d jogged
distance = rate* time = (12 km / hr) ? 30 minutes
= (12 km/hr) * 0.5 hr = 6 km
The distance of 6 km corresponds to 10 perimeters and therefore 1 perimeter is equal to
6 km / 10 = 0.6 km = 0.6 * 1000 meters = 600 meters
Let L and W be the length and width of the field. The length is twice the width. Hence
L = 2 W
The perimeter is 600 meters and is given by
2 (L + W) = 600
Substitute L by 2 W
2 (2 W + W) = 600
Simplify and solve for W
4 W + 2 W = 600
6 W = 600
W = 100
Find L
L = 2 W = 200
Find the area A of the rectangle
A = L * W = 200 * 100 = 20,000 square meters
correct answer D
Question: How many times are the hands of a clock at right angles in a day?
A.22
B.44
C.55
D.888
Answer: B.44
Explanation: In 12 hours, they are at right angles 22 times.
==> In 24 hours, they are at right angles 44 times.
Answer: Option 'B'
Question: A car gets 20 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 190 kilometers?
A.3.5 gallons
B.9.5 gallons
C.8.7 gallons
D.4.5 gallons
Answer: B.9.5 gallons
Explanation: Each 40 kilometers, 1 gallon is needed. We need to know how many 40 kilometers are there in 180 kilometers?
180 Ã· 40 = 9.5 Ã— 1 gallon = 9.5 gallons
correct answer is B) 9.5 gallons
Question: Two trains are moving in opposite directions with speed of 60 km/hr and 90 km/hr respectively. Their lengths are 1.10 km and 0.9 km respectively. the slower train cross the faster train in --- seconds
A.56
B.48
C.47
D.26
Answer: B.48
Explanation: Explanation:
Relative speed = 60+90 = 150 km/hr (Since both trains are moving in opposite directions)
Total distance = 1.1+.9 = 2km
Time = 2/150 hr = 1//75 hr = 3600/75 seconds = 1200/25 = 240/5 = 48 seconds
Answer: Option B
Question: How many of the following numbers are divisible by 132 ?
264, 396, 462, 792, 968, 2178, 5184, 6336
A.3
B.4
C.6
D.7
Answer: B.4
Explanation: 132 = 4 x 3 x 11
So, if the number divisible by all the three number 4, 3 and 11, then the number is divisible by 132 also.
264 11,3,4 (/)
396 11,3,4 (/)
462 11,3 (X)
792 11,3,4 (/)
968 11,4 (X)
2178 11,3 (X)
5184 3,4 (X)
6336 11,3,4 (/)
Therefore the following numbers are divisible by 132 : 264, 396, 792 and 6336.
Required number of number = 4.
B)
Question: If x and y are unique prime integers, which of the following must be even?
A.x−y
B.x−2y
C.2x−2y
D.2x−y
Answer: C.2x−2y
Explanation: Any number multiplied by 2 has to be an even number
Answer C
Question: A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
A.1:2
B.1:6
C.1:9
D.1:3
Answer: A.1:2
Explanation: T = 192/32 = 6 h
T = 6 - 3 = 3
Time Ratio = 6:3 = 2:1
Speed Ratio = 1:2.Answer: A
Question: What is the % change in the area of a rectangle when its length increases by 60% and its width decreases by 60%?
A.0%
B.20% increase
C.36% decrease
D.1% decrease
Answer: C.36% decrease
Explanation: (16/10)*(4/10) = 64/100 of original area
64/100 is a 36% decrease from 100/100 ->C
Question: Which of the following could be the sides of an obtuse angled triangle? all values are in degree only
I. 51, 29, 100
II. 10,110, 60
III. 20, 30, 50
A.I and III only
B.II only
C.I and II only
D.I
Answer: C.I and II only
Explanation: obtuse angled triangle means one angle more than 90 deg and total 180 deg.. I and II only
HENCE, (C)
Question: When positive integer N is divided by positive integer J, the remainder is 14. If N/J = 213.28, what is value of J?
A.30
B.35
C.40
D.50
Answer: D.50
Explanation: When a number is divided by another number, we can represent it as : Dividend = Quotient * Divisor + Remainder
So, Dividend/Divisor = Quotient + Remainder/Divisor
Given that N/J = 213.28
Here 213 is the quotient.
Given that Remainder = 14
So, 213.28 = 213 + 14/J
So, J = 50
Question: Rs.160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins?
A.120
B.125
C.115
D.110
Answer: A.120
Explanation: 4x 5x 6x
100 50 25
400x + 350x + 150x = 16000
x = 20
6x = 120
ANSWER A
Question: 5 men and 12 boys finish a piece of work in 4 days, 7 men and 6 boys do it in 5 days. The ratio between the efficiencies of a man and boy is?
A.1:5
B.6:5
C.4:5
D.9:5
Answer: B.6:5
Explanation: B
6:5
5M + 12B ----- 4 days
7M + 6B ------- 5 days
20M + 48B = 35M + 30B
18B = 15M => 5M = 6B
M: B = 6:5
Question: Ramu and Shamu invested in a shop. The profits were divided in the ratio of 4 : 4 respectively. If Ramu invested Rs. 35,500, the amount invested by Shamu is:
A.35000
B.40000
C.45000
D.35500
Answer: D.35500
Explanation: Suppose Shamu invested Rs. y. Then, 35500/y =4/4 or y = [35500 x 4 / 4] = 35500.
Answer D
Question: The principal that amounts to Rs. 4913 in 3 years at 6 1/4 % per annum C.I. compounded annually, is?
A.Rs. 3096
B.Rs. 4076
C.Rs. 4085
D.Rs. 4096
Answer: D.Rs. 4096
Explanation: Explanation:
Principal = [4913 / (1 + 25/(4 * 100))3]
= 4913 * 16/17 * 16/17 * 16/17 = Rs. 4096.
ANSWER IS D
Question: If Nancy's income is Rs 17000, calculate his savings given that his income and expenditure are in the ratio 5:3.?
A.Rs.3800
B.Rs.1800
C.Rs.6800
D.Rs.7800
Answer: C.Rs.6800
Explanation: Let the income and the expenditure of the person be Rs.5x and Rs.3x respectively.
Income, 5x = 17000 => x = 3400
Savings = Income - expenditure = 5x - 3x =2x
So, savings = Rs.6800
Answer: C
Question: Kate wanted to buy 2kgs of apples. The vendor kept the 2kg weight on the right side and weighed 4 apples for that. She doubted on the correctness of the balance and placed 2 kg weight on the left side and she could weight 14 apples for 2 kgs. If the balance was correct how many apples she would have got?
A.6
B.9
C.8
D.4
Answer: B.9
Explanation: As she got less apples when the weight put on the right side, the left pan has more weight say w kgs.
Now w + 4a = 2
and w+ 2 = 14a
Solving we get a = 2/9 Kgs.
So she gets, 2/(2/9) = 9 apples
Answer:B
Question: How many seconds will a 900 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.22
B.54
C.99
D.77
Answer: B.54
Explanation: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 900 * 3/50 = 54 sec.
Answer: B
Question: The ratio between the present ages of P and Q is 5:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years?
A.A)3:4
B.B)8:9
C.C)4:3
D.inadequate
Answer: B.B)8:9
Explanation: Let P's age and Q's age be 5x and 7x years respectively.
Then, 7x - 5x = 4 => x = 2
Required ratio = (6x + 4) : (7x + 4)
16 : 18= 8:9
ANSWER:B
Question: If a rectangle length and width are both doubled,by what percent is the rectangle area increase?
A.100
B.150
C.300
D.200
Answer: C.300
Explanation: let length and width are l and b
so area = lb
now after doubling both we will get area = 2l*2b = 4lb
so % increase = 400-100 =300
ANSWER:C
Question: Traders A and B buy two goods for Rs. 1000 and Rs. 2000 respectively. Trader A marks his goods up by x%, while trader B marks his goods up by 2x% and offers a discount of x%. If both make the same non-zero profit, find x.
A.25%
B.12.5%
C.37.5%
D.40%
Answer: A.25%
Explanation: DETAILED SOLUTION
SP of trader A = 1000 (1 + x).
Profit of trader A = 1000 (1 + x) – 1000.
MP of trader B = 2000 (1 + 2x).
SP of trader B = 2000 (1 + 2x) (1 – x).
Profit of trader B = 2000(1 + 2x) (1 – x) – 2000.
Both make the same profit => 1000(1 + x) – 1000 = 2000(1 + 2x) (1 – x) – 2000
1000x = 2000 – 4000x2 + 4000x – 2000x – 2000
4000x2 -1000x = 0
1000x (4x – 1) = 0
=> x = 25%.
Answer choice (A)
Question: The ratio of the present age of Viju to that of Aju is 7:2. Four years from now, the ratio of the ages of Viju to Aju will be 5:2. What was Viju age 2 years ago ? (RBI Assistant 2015)
A.24
B.19
C.12
D.15
Answer: B.19
Explanation: Let the present age of Viju be 7x years and that of Aju be 2x years.
Then, 4 years from now
7x + 4 / 2x + 4 = 5 / 2
or 4x = 12
or x = 3
Viju present age = 7 * 3 = 21 years
Viju age 2 years ago = 21 - 2 = 19 years
answer :B
Question: Speed of boat in water is 12km/hr. and the speed of the stream is 3km/hr. Find the time taken by the boat to go upstream a distance of 45km.
A.3
B.4
C.5 hrs.
D.6
Answer: C.5 hrs.
Explanation: US =speed of the boat - speed of the stream 12-3 =9km/hr. Time taken to cover 45km =45/9 = 5hrs. Answer : C
Question: An error 6% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:
A.12.36
B.8.36
C.9.36
D.10.36
Answer: A.12.36
Explanation: Explanation:
100 cm is read as 106 cm.
A1 =(100 × 100)cm2 = 10000
and A2= (106 × 106)cm2= 11236
(A2 - A1) = 11236-10000 = 1236
=> 1236/10000*100 =12.36
Answer : A
Question: A pharmaceutical company uses 900 gm in place of 1 kg to sell the drug. Find the actual % profit or loss, when the company sells the product on 10% gain on cost price?
A.20
B.25
C.30
D.35
Answer: B.25
Explanation: Selling price of 900gm = 100+10 = $110
Profit = 110-90 = $20
% of profit = 20*100/80 =25 %
Answer is B
Question: A certain cricket team played seven games and scored an average of 180 runs per game. If, in the team’s first five games, it scored 175, 169, 181, 190, and 173 points, what was the average (arithmetic mean) number of points scored over the last two games?
A.165
B.181
C.182
D.186
Answer: D.186
Explanation: Avg runs for total of 7 games = 50
So A+B+C+D+E+F+G/7=180
and A+B+C+D+E+F+G = 1260
Given A+B+C+D+E = 888
So F+G = 372
So average (arithmetic mean) number of runs scored over the last two games is 372/2 = 186
Correct answer is D) 186
Question: A train 280 m long, running with a speed of 72 km / hr will pass a tree in
A.14 sec
B.15 sec
C.16 sec
D.20 sec
Answer: A.14 sec
Explanation: Sol.
Speed = (72 x 5/18) m/sec.
= 20 m / sec.
Time taken = (280 x 1/20) sec = 14 sec
Answer A
Question: At what rate of compound interest per annum will a sum of Rs.1200 become Rs.1348.32 in 2 years?
A.6%
B.6.5%
C.7%
D.7.5%
Answer: A.6%
Explanation: Let the rate be R% p.a. (1+ R )2 = 1348.32. Then, 1200* (1+ (R/100))2 = 1348.32
(1+R/100)2 = 134832/120000 = 11236/10000 :. (1 + R/100) 2 = (106/100)2
1 + R/100 = 106/100. So R = 6%
ANSWER:A
Question: The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
A.80 kg
B.85 kg
C.90 kg
D.100 kg
Answer: B.85 kg
Explanation: Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (65 + 20) kg = 85 kg.
B)
Question: In what time will a railway train 70 m long moving at the rate of 36 kmph pass a telegraph post on its way?
A.5 sec
B.4 sec
C.3 sec
D.7 sec
Answer: D.7 sec
Explanation: T = 70/36 * 18/5 = 7 sec
Answer: D
Question: In a box of 6 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective?
A.1/2
B.1/5
C.2/3
D.2/5
Answer: B.1/5
Explanation: First, there are 4C3 ways you can select 3 good pencils from 4 good ones.
Second, there are 6C3 ways you select 3 pencils from 6 ones in the box.
Then, the probability that neither pen will be defective is: 4C3/6C3=4/20 = 1/5
Answer is B
Question: In a pet shop there are 120 eyes and 172 legs. How many birds are included in these?
A.33
B.34
C.35
D.36
Answer: B.34
Explanation: Let there are x birds and y puppies.
Each bird and puppy has 2 eyes. Each bird has 2 legs and each puppy has 4 legs.
Then 2x+2y = 120 => x+y = 60 (i)
2x+4y = 172 => x+2y = 86 (ii)
Solving (i) and (ii) we get
y = 26 & x = 34
So birds are 34
ANSWER:B
Question: On dividing 109 by a number, the quotient is 9 and the remainder is 1. Find the divisor?
A.10
B.12
C.14
D.16
Answer: B.12
Explanation: d = (D-R)/Q
= (109 - 1)/9
= 108/9 = 12
B)
Question: The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 4 years hence?
A.22
B.77
C.70
D.68
Answer: D.68
Explanation: A + B = 60, A = 2B
2B + B = 60 => B = 20 then A = 40.
4 years, their ages will be 44 and 24.
Sum of their ages = 44 + 24 = 68.
Answer: D
Question: If circles x and y have the same area and circle x has a circumference of 18π, half of the radius of circle y is:
A.16
B.4.5
C.4
D.2
Answer: B.4.5
Explanation: x be radius of circle x
y be radius of circle y
given:
pi*x^2 = pi*y^2
also,
2*pi*x = 18*pi
x = 9
thus y =9
y/2 = 4.5
Ans: B
Question: . In digging a pond 18 m * 8 m * 6 m the volumes of the soil extracted will be?
A.889
B.1000
C.864
D.989
Answer: C.864
Explanation: 20 * 10 * 5 = 864
Answer: C