RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A, B and C can do a piece of work in 6,8 and 12 days respectively. In how many days would all of them complete the same job working together?
A.2 3/4 days.
B.2 2/3 days.
C.2 3/2 days.
D.3 1/2 days.
Answer: B.2 2/3 days.
Explanation: Explanation:
In this type of questions we first get the finishing of work in 1 day for A,B,C then we will add them to get the result, as:
Part finished by A in 1 day= 1/6
Part finished by B in 1 day = 1/8
Part finished by C in 1 day =1/12
Part finished by (A+B+C) in 1 day = 9/24
= 9/24 Remaining work =1-9/20=11/20. Number days to finish the work by A+B+C =2 2/3 days.
Option B
Question: The food in a camp lasts for 10 men for 20 days. If 30 more men join, how many days will the food last?
A.8 days
B.4 days
C.5 days
D.10 days
Answer: C.5 days
Explanation: one man can consume the same food in 10*20 = 200 days.
30 more men join, the total number of men = 40
The number of days the food will last = 200/40 = 5 days.
Answer:C
Question: A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 456. What is the sum of the last 8 of the even integers?
A.580
B.584
C.588
D.592
Answer: B.584
Explanation: The sum of the first 8 numbers is: x + (x+2) +...+ (x+14) = 456
The sum of the next 8 numbers is: (x+16) + (x+2+16) +...+ (x+14+16) =
456 + 8(16) = 456 + 128 = 584
The answer is B.
Question: The perimeter of one square is 48 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?
A.13√6
B.13√2
C.13√0
D.13√2
Answer: B.13√2
Explanation: 4a = 48 4a = 20
a = 12 a = 5
a2 = 144 a2 = 25
Combined area = a2 = 169 => a = 13
d = 13√2 Answer:B
Question: In a recent election, Ms. Robinson received 8000 voters cast by independent voters, that is, voters not registered with a specific political party. She also received 40 percent of the votes cast by those voters registered with a political party. IF N is the total number of votes cast in the election and 40 percent of the votes cast were cast by independent voters, which of the following represents the number of votes that Mrs. Robbins received?
A. 0.06N+3200
B. 0.1N+7200
C. 0.24N+8000
D. 0.1N+8000
Answer: C. 0.24N+8000
Explanation: 40% of N are independent voters, hence 60% of N are not independent voters. From this group she received 40% votes so, 0.4*0.6*N plus 8,000 votes from independents: total=0.4*0.6*N+8,000=0.24*N+8,000.
Answer: C.
Question: David invested certain amount in three different schemes. A, B and C with the rate of interest 10% p.a., 12% p.a. and 15% p.a. respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in scheme C was 150% of the amount invested in scheme A and 240% of the amount invested in scheme B, what was the amount invested in scheme B?
A.Rs. 5000
B.Rs. 6500
C.Rs. 8000
D.Cannot be determined
Answer: A.Rs. 5000
Explanation: Let x, y and z be the amount invested in schemes A, B and C respectively. Then,
(x * 10 * 1)/100 + (y * 12 * 1)/100 + (z * 15 * 1)/100 = 3200
10x + 12y + 15z = 320000
Now, z = 240% of y = 12/5 y
And, z = 150% of x = 3/2 x
x = 2/3 z = ( 2/3 * 12/5) y = 8/5 y
16y + 12y + 36y = 320000
y = 5000
Sum invested in scheme B = Rs. 5000
ANSWER:A
Question: In a partnership between A, B and C. A's capital is Rs.5000. If his share of a profit of Rs.800 is Rs.200 and C's share is Rs.130, what is B's capital?
A.11719
B.11710
C.11712
D.11750
Answer: D.11750
Explanation: 200 + 130 = 330
800 - 330 = 470
200 ---- 5000
470 ---- ? => 11750
Answer:D
Question: There are 16 balls in a jar: 8 red, 6 blue and 2 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?
A.1/12
B.1/4
C.7/8
D.2/3
Answer: C.7/8
Explanation: Blue + Red =14
Total number of balls is 8+6+2=16
So the answer is 14/16=7/8
Answer C
Question: By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 40%?
A.228
B.384
C.267
D.288
Answer: B.384
Explanation: SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 40% = 40% of 640 = Rs.256
SP = CP - Loss = 640 - 256 = Rs.384
Answer: B
Question: If x, y, and z are positive integers, and 4x = 5y = 8z, then the least possible value of x + y + z is
A.15
B.23
C.37
D.42
Answer: B.23
Explanation: Take LCM of 4,5 and 8 = 40
Now 4x = 40 => x =10
5y = 40 => y = 8
8z = 40 => z =5
10+8+5 = 23.
Option B.
Question: 1. The simple interest on a sum of money is Rs. 50. What is the sum?
I. The interest rate is 10% p.a.
II. The sum earned simple interest in 10 years
A.I alone sufficient while II alone not sufficient to answer
B.II alone sufficient while I alone not sufficient to answer
C.Either I or II alone sufficient to answer
D.Both I and II are necessary to answer
Answer: D.Both I and II are necessary to answer
Explanation: Explanation:
Given : S.I. = Rs. 50.
I gives, R = 10% p.a.
II gives, T = 10 years.
Sum = (100 x S.I)/(t x r ) = Rs.(100 x 50)/(10 x 10) = Rs.50
ANSWER IS D
Question: (6)6.5 × (36)4.5 ÷ (216)4.5 = (6)?
A.1
B.2
C.4
D.6
Answer: B.2
Explanation: Explanation :
(6)6.5 × (36)4.5 ÷ (216)4.5
= (6)6.5 × [(6)2]4.5 ÷ [(6)3]4.5
= (6)6.5 × (6)9 ÷ (6)13.5
= (6)(6.5 + 9 - 13.5)
= (6)2
Answer : Option B
Question: A train 200 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?
A.5 sec
B.9 sec
C.12 sec
D.15 sec
Answer: C.12 sec
Explanation: Speed of the train relative to man = (68 - 8) kmph
= (60* 5/18) m/sec = (50/3)m/sec
Time taken by the train to cross the man
= Time taken by It to cover 200 m at 50/3 m / sec
= 200 *3/ 50 sec = 12sec
Answer : C
Question: What inequality represents the condition 1<x<7?
A.|x|<3
B.|x+5|<4
C.|x-1|<9
D.|-4+x|<3
Answer: D.|-4+x|<3
Explanation: 1<x<7 represents segment with
length: 7-1 = 6
center: (7+1)/2 = 4
For any |x-a|<b a is a center and b is a half of length. So, |x-4|<6/2 represents our inequality (answer D)
Question: Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed?
A.502
B.512
C.523
D.521
Answer: B.512
Explanation: Let n be the total number of children.
More children, less notebooks(Indirect proportion)
If the number children = n, number of books each child will get = n/8
If the number children = n/2, number of books each child will get = 16
Hence we can write as
children n:n/2}::16:n/8
⇒n×n/8=n/2×16
⇒n8=16/2=8
⇒n=8×8=64
Then, total number of notebooks those were distributed = n×n/8=(64×64)/8=64×8=512
Answer is B.
Question: Vijay sells a cupboard at 16% below cost price. Had he got Rs.1200 more, he would have made a profit of 16%. What is the cost price of the cupboard?
A.3750
B.3600
C.7400
D.7500
Answer: A.3750
Explanation: Explanation:
Cost price = 1200/(0.16 + 0.16) = 1200/0.32
= Rs.3750
ANSWER A
Question: The total marks obtained by a student in Physics, Chemistry and Mathematics is 150 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics?
A.75
B.28
C.279
D.271
Answer: A.75
Explanation: Let the marks obtained by the student in Physics, Chemistry and Mathematics be P, C and M respectively.
P + C + M = 150 + P
C + M = 150
Average mark obtained by the student in Chemistry and Mathematics
= (C + M)/2 = 150/2 = 75.
Answer:A
Question: A sum of money doubles itself in 7 years. In how many years it becomes four fold?
A.35 years
B.28 years
C.14 years
D.21 years
Answer: D.21 years
Explanation: Double in seven years.
So 4 times will be in = 7 × (4 − 1) = 21 years.
Answer:D.
Question: A car drove from Town A to Town B without stopping. The car traveled the first 50 miles of its journey at an average speed of 25 miles per hour. What was the car’s average speed, in miles per hour, for the remaining 110 miles if the car’s average speed for the entire trip was 40 miles per hour?
A.28
B.48
C.50
D.55
Answer: D.55
Explanation: KAPLANOFFICIAL SOLUTION:
To solve this problem, you must remember that average speed means total distance divided by total time over an entire journey. This should not be confused with the average of the speeds. The total distance in this problem is 160 miles, but we will need to express the total time in a more complex way.
For the first 50 miles, the car traveled at 25 miles per hour. Therefore, we can say that the time this took was 50/25, because distance divided by rate equals time.
For the last 110 miles, we are trying to solve for the rate, so we can call this speed R. Thus, the time for the final 110 miles is 110/R.
If we put all of this together, knowing that the average speed over the entire journey is 40 miles per hour, we get the equation 160/(50/25 + 110/R) = 40. We can now solve for R and reach our answer.
160/(50/25 + 110/R) = 40
R = 55
55 is choice (D) and that’s our correct answer.
Question: For each 6-month period during a light bulb's life span, the odds of it not burning out from over-use are half what they were in the previous 6-month period. If the odds of a light bulb burning out during the first 6-month period following its purchase are 1/8, what are the odds of it burning out during the period from 6months to 1 year following its purchase?
A.5/27
B.2/9
C.1/2
D.4/9
Answer: C.1/2
Explanation: P(of not burning out in a six mnth period)=1/2 of P(of not burning out in prev 6 mnth period)
P(of burning out in 1st 6 mnth)= 1/8
--->P( of not burning out in 1st 6 mnth)=1-1/8=7/8
---->P(of not burning out in a six mnth period)=1/2 *7/8=4/9
--->P(of burning out in a six mnth period)=1-4/9=4/7
now
P( of burning out in 2nd six mnth period)=P( of not burning out in 1st six mnth)*P(of burning out in a six mnth)
=7/8 *4/7 =1/2
Ans C
Question: A person can row at 10 kmph in still water. If the velocity of the current is 2 kmph and it takes him 20 hour to row to a place and come back, how far is the place?
A.24km
B.30km
C.96km
D.12km
Answer: C.96km
Explanation: Speed of down stream = 10+2 = 12kmph
speed of upstream = 10-2 = 8kmph
Let the required distance be xkm
x/12 + x/8 = 20
2x+3x = 480
x = 96 km
Answer is C
Question: A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have?
A.50
B.99
C.88
D.77
Answer: A.50
Explanation: A+B+C = 500
A+C = 200
B+C = 350
--------------
A+B+2C = 550
A+B+C = 500
----------------
C = 50
Answer: A
Question: Sachin was twice as old as Ajay 10 years back. How old is Ajay today if Sachin will be 40 years old 10 years hence
A.76 years
B.88 years
C.97 years
D.20 years
Answer: D.20 years
Explanation: Sachin's age today = 30 years.
Sachin's age 10 years back = 20 years.
Ajay's age 10 years back = 10 years.
Ajay's age today =20 years
Answer: D
Question: A man buys a cycle for Rs. 1400 and sells it at a loss of 15%. What is the selling price of the cycle?
A.Rs. 1090
B.Rs. 1160
C.Rs. 1190
D.Rs. 1202
Answer: C.Rs. 1190
Explanation: S.P. = 85% of Rs. 1400 = Rs.85/100x 1400	= Rs. 1190
ANSWER :C
Question: A person walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 10 minutes earlier. How far is the office from his house?
A.4 1/5 Km
B.4 1/7 Km
C.3 3/5 Km
D.3 1/7 Km
Answer: C.3 3/5 Km
Explanation: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 18/6
= 24/2 * 18/60
= 9 * 2/5
= 18/5 = 3 3/5 Km
C)
Question: Two brothers take the same route to school on their bicycles, one gets to school in 25 minutes and the second one gets to school in 36 minutes. The ratio of their speeds is
A.4 : 5
B.1 : 2
C.6 : 7
D.5 : 6
Answer: D.5 : 6
Explanation: Solution
Let us name the brothers
as A and B.	= (A'S speed) : (B's speed)
=âˆšb : âˆša
= âˆš25 : âˆš36
= 5 : 6
Answer D
Question: A number whose fifth part increased by 5 is equal to its fourth part diminished by 5, is
A.160
B.180
C.200
D.220
Answer: C.200
Explanation: x/5 + 5 = x/4 - 5
=> x/5 - x/4 = 10
x/20 = 10
=> x = 200
Answer: C.
Question: In how many different ways can the letters of the word 'RUMOUR' be arranged?
A.180
B.90
C.30
D.720
Answer: A.180
Explanation: The word 'RUMOUR' contains 6 letters, namely 2R, 2U, 1M and 1U.
Required number of ways =6!/(2!)(2!)(1!)(1!)=180.
Answer is A
Question: Find the number of ways of arranging the letters of the word "MATERIAL" such that all the vowels in the word are to come together?
A.1840 ways
B.1440 ways
C.1490 ways
D.1447 ways
Answer: B.1440 ways
Explanation: In the word, "MATERIAL" there are three vowels A, I, E.
If all the vowels are together, the arrangement is MTRL'AAEI'.
Consider AAEI as one unit. The arrangement is as follows.
M T R L A A E I
The above 5 items can be arranged in 5! ways and AAEI can be arranged among themselves in 4!/2! ways.
Number of required ways of arranging the above letters = 5! * 4!/2!
= (120 * 24)/2 = 1440 ways.
Answer: B
Question: A train is 460 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
A.76 seconds
B.18 seconds
C.40 seconds
D.48 seconds
Answer: D.48 seconds
Explanation: Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 460+140 = 600 meter
Time = Distance/speed
= 600 * (2/25)
= 48 seconds
Answer: D
Question: Find the distance covered by a man walking for 30min at a speed of 5km/hr?
A.1km
B.3km
C.4km
D.2.5 km
Answer: D.2.5 km
Explanation: Distance = 5*30/60 =2.5 km
Answer is D
Question: 90% of the population of a village is 45000. The total population of the village is?
A.26799
B.24000
C.50000
D.29973
Answer: C.50000
Explanation: X * (90/100) = 45000
X = 500 * 100
X = 50000
Answer: C
Question: A and B start a business with Rs.6000 and Rs.8000 respectively. Hoe should they share their profits at the end of one year?
A.3:8
B.3:4
C.3:0
D.3:2
Answer: B.3:4
Explanation: They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B
=6000 : 8000 => 3:4
Answer: B
Question: If f(x2 – 1) = x4 – 7x2 + k1 and f(x3 – 2) = x6 – 9x3 + k2 then the value of (k2 – k1) is _____
A.6
B.7
C.8
D.9
Answer: C.8
Explanation: Explanatory Answer
Given Data
f(x2 – 1) = x4 – 7x2 + k1
f(x3 – 2) = x6 – 9x3 + k2
Approach and Solution
When x2 = 1, f(x2 – 1) = f(1 - 1) = f(0) =(1)2 - 7(1) + k1
f(0) = - 6 + k1 ..........(1)
Essentially, we have replaced all x2 with 1.
When x3 = 2,f(x3 – 2) = f(2 - 2) = f(0) =(2)2 - 9(2) + k2
f(0) = - 14 + k2 ..........(2)
Essentially, we have replaced all x3 with 2.
Equating f(0) in equations (1) and (2)
(-6 + k1) = (-14 + k2)
or k2 - k1 = 8
The correct answer is Choice C.
Question: There are 9 books on a shelf that consist of 2 paperback books and 7 hardback books. If 4 books are selected at random without replacement, how many different combinations are there which include at least one paperback book?
A.85
B.91
C.97
D.103
Answer: B.91
Explanation: The total number of ways to select 4 books is 9C4 = 126
The number of ways which do not include any paperbacks is 7C4 = 35
The number of combinations with at least one paperback is 126-35 = 91
The answer is B.
Question: The probability is 1/2 that a certain coin turns up heads on any given toss. If the coin is tossed three times, what is the probability that the coin turns up tails on at least one of the tosses?
A.7/8
B.5/8
C.3/8
D.3/4
Answer: A.7/8
Explanation: P(3 heads)= 1/2*1/2*1/2=1/8.
P(at least one tail)=1-1/8=7/8.
The answer is A.
Question: Look at this series: 3, 4, 7, 8, 11, 12, ... What number should come next?
A.11
B.14
C.15
D.17
Answer: C.15
Explanation: C
15
This alternating addition series begins with 3; then 1 is added to give 4; then 3 is added to give 7; then 1 is added, and so on.
Question: The average weight of 16 pupils in a class is 50.25 kg and that of the remaining 8 pupils is 45.15 kg. Find the average weights of all the pupils in the class.
A.A)48.55
B.B)49
C.C)51
D.D)61
Answer: A.A)48.55
Explanation: Required average
= (50.25 x 16 + 45.15 x 8)/(16 + 8)
= (804 + 361.20)/24
= 1165.20/24
= 48.55kg
Answer is A
Question: The speed of a boat in still water is 60kmph and the speed of the current is 10kmph. Find the speed downstream and upstream?
A.40, 68 kmph
B.70, 50 kmph
C.90, 60 kmph
D.40, 60 kmph
Answer: B.70, 50 kmph
Explanation: Speed downstream = 60 + 10 = 70 kmph
Speed upstream = 60 - 10 = 50 kmph
Answer: B
Question: The total of the ages of Amar, Akbar and Anthony is 80 years. What was the total of their ages three years ago ?
A.71 years
B.72 years
C.74 years
D.77 years
Answer: A.71 years
Explanation: Explanation:
Required sum = (80 - 3 x 3) years = (80 - 9) years = 71 years.
Answer IS A
Question: From a pack of 52 cards, 1 card is drawn at random. Find the probability of a face card drawn.
A.4/13
B.1/52
C.1/4
D.1/3
Answer: A.4/13
Explanation: Explanation:
Total number of cases = 52
Total face cards = 16 [favourable cases]
So probability = 16/52 = 4/13
Answer: Option A
Question: In a partnership, A inverts 1/12 of the capital for 1/12 of the time, B invests 1/6 of the Capital for 1/6 of the time and C, the rest of the capital for the whole time. Out of a profit of Rs 113000/-, B’s share is :
A.Rs. 40000/-
B.Rs. 4000/-
C.Rs. 14000/-
D.Rs. 24000/-
Answer: B.Rs. 4000/-
Explanation: Explanation:
Let the total capital be Rs x and the total time be y months. Then,
A invests Rs x/12 for x/12 months;
B invests Rs x/6 for x/6 months;
C invests Rs [x – (x/12 + x/16)] => Rs.[x – (x+12)/12]
Rs. [(12x – 3x)/12]
Rs. [9x/12]
Rs. [3x/4] for y months
Then A : B : C = [x/12 * y/12] : [x/6 * y/6] : [3x/4 * y/1]
= xy/144 : xy/36 : 3xy/4
LCM = 144, 36, 4 = 144
A : B : C = 1 : 4 : 108
B’s Share = Rs(113000 * 4/113) = Rs. 4000/-
Answer: Option B
Question: Two roads XY and YZ of 15 metres and 20 metres length respectively are perpendicular to each other. What is the distance between X & Z by the shortest route?
A.35 metres
B.30 metres
C.24 metres
D.25 metres
Answer: D.25 metres
Explanation: XYZ is a right-angled triangle
XZ =√15(2)+20(2)=√=625=25m
Answer D
Question: The sum of two numbers is 25 and their difference is 15. Find their product.
A.104
B.100
C.114
D.325
Answer: B.100
Explanation: Sol.
Let the numbers be x and y.
Then, x + y = 25
x - y = 15
2x = 40 => x = 20
so, y = 5
xy = 20* 5 = 100
Answer B
Question: For any positive integer n, n>1, thelengthof n is the number of positive primes (not necessary distinct) whose product is n. For ex, the length of 50 is 5, since 50=2x5x5. What is the greatest possible length of a positive integer less than 1000.
A.10
B.9
C.8
D.7
Answer: D.7
Explanation: you are missing something in your post:
For any positive integer n , n > 1, thelengthof n is the number of positive primes (not distinct) whose product is n. For example, the length of 50 is 3 since 50 = (2)(5)(5)
the lenght of 1000 = (2)(5)(2)(5)(2)(5) = 6
but we need n < 1000
using 2 as the base = (2)(2)(2)(2)(2)(2)(2)(2)(2) = 7 the length of 512.
the answer is (D)
Question: A is the average (arithmetic mean) of the first 7 positive multiples of 4 and B is the median of the first 3 positive multiples of positive integer n. If the value of A^2 – B^2 is zero, what is the value of n?
A.2
B.4
C.6
D.8
Answer: D.8
Explanation: If A^2 - B^2 = 0, then let's assume that A = B.
A must equal the 4th positive multiple of 4, thus A = 16, which also equals B.
B is the second positive multiple of n, thus n = 16/2 = 8.
The answer is D.
Question: If 7 spiders make 7 webs in 7 days, then 1 spider will make 1 web in how many days?
A.8
B.6
C.7
D.5
Answer: C.7
Explanation: Explanation:
Let the required number days be x.
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)
{\color{Blue} therefore } 1 x 7 x x = 7 x 1 x 7
=> x= 7
Answer: C
Question: In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?
A.16%
B.25%
C.32%
D.40%
Answer: B.25%
Explanation: let population be 100
total employed people = 64% of the population = 64
employed males = 48 % of the population = 48
employed females = 16% of the population = 16
employed females % in terms of employed people = (16/64) * 100 = 25%
Answer is B.
Question: Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is ?
A.40 meter
B.45 meter
C.50 meter
D.55 meter
Answer: C.50 meter
Explanation: Explanation:
Let the length of each train is x meter
Distance will be x+x = 2x
Relative Speed = 46-36 = 10 km/hr
= 10*(5/18) = 25/9 m/sec
Distance = Speed*Time
2x=25/9∗36
2x=100
=>x=50
So length of both the trains are 50 meters
Option C
Question: The cost of five chairs and three tables is Rs.3110. Cost of one chair is Rs.210 less than cost one table. What is the cost of two tables and two chairs?
A.Rs.1660/-
B.Rs.1860/-
C.Rs.2600/-
D.Cannot be determined
Answer: A.Rs.1660/-
Explanation: Explanation:
Let ‘x’ be the cost of one chair
Then cost of 1 table = x + 210
Given 5x + 3(x+210) = Rs.3110
8x = 3110 – 630 = 2480
Cost of one chair (x) = 2480/8 = 310
Cost of one table = 310 + 210 = rs.520
:. Cost of 2 tables + 2 chairs = 2x520 + 2x310 = Rs.1660
Answer: Option A
Question: A man is 22 years older than his son. In two years, his age will be twice the age of his son. The
present age of his son is
A.20 years
B.21 years
C.22 years
D.24 years
Answer: A.20 years
Explanation: Explanation:
Let the son's present age be x years. Then, man's present age = (x + 22) years
=> (x + 22) + 2 = 2(x + 2)
=> x + 24 = 2x + 4
So, x = 20
Answer: Option A
Question: X, Y and Z enter into partnership. X invests some money at the beginning, Y invests double the amount after 6 months, and Z invests thrice the amount after 8 months. If the annual gain be Rs.6000. X's share is?
A.2500
B.2000
C.2100
D.2200
Answer: B.2000
Explanation: x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 6000 = 2000
Answer: B
Question: One hour after Yolanda started walking from X to Y, a distance of 60 miles, Bob started walking along the same road from Y to X. If Yolandaâs walking rate was 5 miles per hour and Bobâs was 6 miles per hour, how many miles had Bob walked when they met?
A.40
B.25
C.28
D.30
Answer: D.30
Explanation: Let t be the number of hours that Bob had walked when he met Yolanda. Then, when they met, Bob had walked 4t miles and Yolanda had walked 5(t + 1) miles. These distances must sum to 60 miles, so 6t + 5(t + 1) = 60, which may be solved for t as follows
6t + 5(t + 1) = 60
6t + 5t + 5 = 60
11t = 55
T = 5 (hours)
Therefore, Bob had walked 6t = 6(5) = 30 miles when they met. The best answer is D.
Question: 1 men takes 37$ to Eat a pizza in restaurant such that it have discount multiple of 4 if u eat more pizza . discount increase by multiple of 4 every pizza u eat. for 1 pizza 0% off. for 2 pizza % off for 3 pizza 8% off. pizza without discount is 10$. How much that man eats the pizza.
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: Solution: B. For 1 pizza 10$. For 2 pizza 10$ +9.6$(4% off)=19.6, For 3 pizza 19.6+9.2(8% off)=28.8, For 4 pizza 28.8+8.8(12% off)=37.6. so he have 37 so he cant eat 4th pizza.
Question: 150 is increased by 40%. Find the final number.
A.200
B.210
C.180
D.190
Answer: B.210
Explanation: Final number = Initial number + 40%(original number) = 150 + 40%(150) = 150 + 60 = 210.
Answer B
Question: The probability of rain showers in Barcelona on any given day is 0.7. What is the probability that it will rain on exactly one out of three straight days in Barcelona?
A.0.189
B.0.072
C.0.432
D.0.72
Answer: A.0.189
Explanation: IMO This is just for first day! It can rain on 2nd day or 3 rd day (and not rain on other days) in 3 consecutive days!
Hence,
0.7*0.3*0.3 + 0.3*0.7*0.3 + 0.3*0.3*0.7 = 0.189
Option - A
Question: Two trains leave the same train station at 6:00 am and 6:45 am and they travel at 100 kph and 125 kph respectively. How many kilometers from the train station will the two trains be together?
A.300
B.325
C.350
D.375
Answer: D.375
Explanation: At 6:45, the first train is 75 km ahead.
The second train gains 25 km each hour.
The time it takes the second train to catch the first train is 75 / 25 = 3 hours.
In this time, the second train travels 3*125=375 km.
The answer is D.