RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A train 108 m long is moving at a speed of 50 km/hr . It crosses a train 112 m long coming from opposite direction in 6 seconds. What is the speed of the second train?
A.82 kmph
B.76 kmph
C.44 kmph
D.58 kmph
Answer: A.82 kmph
Explanation: Explanation:
Total distance = 108+112 = 220 m
Time = 6s
Relative speed = distance/time = 220/6 m/s = 110/3 m/s
= (110/3) × (18/5) km/hr = 132 km/hr
=> 50 + speed of second train = 132 km/hr
=> Speed of second train = 132-50 = 82 km/hr
Answer: Option A
Question: The average of 35 students in a class is 15 years. The average age of 25 students is 13. What is the average age of remaining 10 students?
A.17 years
B.18 years
C.19 years
D.20 years
Answer: D.20 years
Explanation: Sum of the ages of 14 students
= (15 * 35) - (13 * 25) = 525 - 325 = 200
Required average = (200/10) = 20 years.
Answer:D
Question: A train 400 m long can cross an electric pole in 40 sec and then find the speed of the train?
A.36 Kmph
B.40 Kmph
C.42 Kmph
D.45 Kmph
Answer: A.36 Kmph
Explanation: Length = Speed * time
Speed = L/T
S = 400/40
S = 10 M/Sec
Speed= 10*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 36 Kmph
ANSWER:A
Question: A person crosses a 600 meter long street in 5 minutes. What is the speed in Km/hr
A.6.2 km/hr
B.7.2 km/hr
C.8.2 km/hr
D.9.2 km/hr
Answer: B.7.2 km/hr
Explanation: ExplanaƟon:
Two things to give aƩenƟon on this quesƟon.
First Ɵme is in minutes, we need to change it to seconds to get speed in m/sec, then we need to get the
final answer in km/hr.
So lets solve this.
Speed=DistanceTimeDistance=650meterTime=5
minutes=300secSpeed=600300=2m/sec=>2
∗
185km/hr=7.2km/hr
Answer:B
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
A.11 years
B.10 years
C.18 years
D.189 years
Answer: B.10 years
Explanation: Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B's age = 2x = 10 years.
Answer: B
Question: Two persons start running simultaneously around a circular track of length 440 m from the same point at speeds of 14 kmph and 24 kmph. When will they meet for the first time any where on the track if they
are moving in the opposite direction ?
A.144
B.36
C.124
D.42
Answer: D.42
Explanation: Time taken to meet the first time = length of track/relative speed
= 440/ (14 +24) (5/18)
= 400/38 *(18/5) = 42 sec.
Answer : D
Question: Pipe A can fill a tank in 10 hours, pipe B in 5 hours and pipe C in 5 hours. If all the pipes are open, in how many hours will the tank be filled?
A.2 hours
B.3 hours
C.4 hours
D.5 hours
Answer: A.2 hours
Explanation: Part filled by A + B + C in 1 hour = 1/10 + 1/5 + 1/5= 1/2
All the three pipes together will fill the tank in 2 hours.
Answer:A
Question: In a hockey team of 11 members, the captain's age is 26 years old and the goalkeeper is 3 years older If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
A.23 years
B.24 years
C.25 years
D.27 years
Answer: A.23 years
Explanation: Explanation :
Let the average age of the whole team be x years.
11x - (26 + 29) = 9(x - 1)
11x - 9x = 46
2x = 46
x = 23
So, average age of the team is 23 years.
Answer : A
Question: Let y = 2m + x^2 and m = 5x + 3. If m^2 =64, then which of the following can be a value of 2y + 3m?
A.68
B.58
C.78
D.88
Answer: B.58
Explanation: m^2 = 64 => m=8
8= 5x+3 => x=1
y= 2*8+1^2 = 17
2y+3m = 2*17+3*8 = 58
Answer : B
Question: Four packages have an average weight of 12.5 pounds. What is the minimum possible weight of the heaviest package in pounds if the median is 10 pounds?
A.20
B.19
C.18
D.17
Answer: A.20
Explanation: Let us denote the weights of the packages in pounds by a, b, c, d naming from the lightest one to the heaviest one. The median is 10 pounds. Therefore (b + c) / 2 = 10.
b + c = 20
The average is 12.5 pounds. Therefore (a + b + c + d) / 4 = 12.5.
a + (b + c) + d = 50
a + 20 + d = 50
a + d = 30
The weight a must be no greater than 10, since 10 is the median. Therefore the minimum possible weight of the heaviest package is 30 – 10 = 20 pounds (all the other packages would weigh 10 pounds in this case).
Answer: A
Question: If xerox paper costs 5 cents a sheet and a buyer gets 10% discount on all xerox paper one buys after the first 2000 papers and 20% discount after first 10000 papers, how much will it cost to buy 20000 sheets of xerox paper?
A.$1250
B.$1060
C.$1350
D.$900
Answer: D.$900
Explanation: 30 sec approach - solve it using approximation
20000 sheet at full price, 5 cent = 1000
20000 sheet at max discount price, 4 cent = 800
Your ans got to be between these two.
Ans D it is.
Question: A is thrice as good as B in work. A is able to finish a job in 60 days less than B. They can finish the work in - days if they work together.
A.5 6/2
B.3/15
C.8/7
D.22 1/2
Answer: D.22 1/2
Explanation: Explanation :
If A completes a work in 1 day, B completes the same work in 3 days
Hence, if the difference is 2 days, B can complete the work in 3 days
=> if the difference is 60 days, B can complete the work in 90 days
=> Amount of work B can do in 1 day= 1/90
Amount of work A can do in 1 day = 3 × (1/90) = 1/30
Amount of work A and B can together do in 1 day = 1/90 + 1/30 = 4/90 = 2/45
=> A and B together can do the work in 45/2 days = 22 ½ days
ANSWER:D
Question: The sum of first 45 natural numbers is
A.1035
B.1280
C.2070
D.2140
Answer: A.1035
Explanation: Solution
We know that(1+2+3+.....+45)	= n(n+1)/2
Therefore (1+2+3+....+45)	=(45×46 / 2)
= 1035.
Answer A
Question: The ratio of the length and the width of a rectangle is 4 : 3 and the area of the rectangle is 5292 sq cm. What is the ratio of the width and the area of the rectangle?
A.1:72
B.1:76
C.1:80
D.1:84
Answer: D.1:84
Explanation: Let the length and the width be 4x and 3x respectively.
Area = (4x)(3x) = 5292
12x^2 = 5292
x^2 = 441
x = 21
The ratio of the width and the area is 3x : 12x^2 = 1 : 4x = 1 : 84
The answer is D.
Question: SI on a certain sum of money for 3 yrs at 8 percent /annum is 1/2 the CI on Rs.4000 for 2 yrs at 10 percent/ annum. The sum placed on SI is?
A.Rs. 1700
B.Rs. 1720
C.Rs. 1750
D.Rs. 1850
Answer: C.Rs. 1750
Explanation: C.I.
= Rs. 4000 x 1 + 10 2 - 4000
100
= Rs. 4000 x 11 x 11 - 4000
10 10
= Rs. 840.
Sum = Rs. 420 x 100 = Rs. 1750.
3 x 8
C
Question: P is 30% more efficient than Q. P can complete a work in 23 days. If P and Q work together, how much time will it take to complete the same work?
A.9
B.11
C.13
D.15
Answer: C.13
Explanation: Explanation :
Work done by P in 1 day = 1/23
Let work done by Q in 1 day = q
q × (130/100) = 1/23
=> q = 100/(23×130) = 10/(23×13)
Work done by P and Q in 1 day = 1/23 + 10/(23×13) = 23/(23×13)= 1/13
=> P and Q together can do the work in 13 days
Answer : Option C
Question: (4300531)-?=2535618
A.1865113
B.1775123
C.1764913
D.1675123
Answer: C.1764913
Explanation: Let 4300531-x=2535618
then x=4300531-2535618
=1764913
Answer is C
Question: A shopkeeper purchased an article at 20% discount on list price, he marked up his article in such a way that after selling the article at 20% discount, he gained 20% on SP. what % is SP of the list price?
A.94
B.95
C.96
D.97
Answer: C.96
Explanation: Let L.P = 100 ==> C.P = 80. He gains 20% on S.P ==> S.P = 96.
ANSWER:C
Question: What sum of money put at C.I amounts in 2 years to Rs.8820 and in 3 years to Rs.9261?
A.8000
B.2881
C.2664
D.2667
Answer: A.8000
Explanation: 8820 ---- 441
100 ---- ? => 5%
x *105/100 * 105/100 = 8820
x*1.1025=8820
x=8820/1.1025 => 8000.Answer: A
Question: The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 42 degrees. Find the temperature on Friday?
A.34
B.55
C.66
D.81
Answer: A.34
Explanation: M + Tu + W + Th = 4 * 48 = 192
Tu + W + Th + F = 4 * 46 = 184
M = 42
Tu + W + Th = 192 -42 = 150
F = 184 – 150 = 34.Answer: A
Question: Sound is said to travel in air at about 1100 feet per second. A man hears the axe striking the tree, 11/5 seconds after he sees it strike the tree. How far is the man from the wood chopper ?
A.2420 ft
B.2524 ft
C.2600 ft
D.2740 ft
Answer: A.2420 ft
Explanation: Explanation :
Distance = [1100 * 11/5] feet
= 2420 feet.
Answer : A
Question: Line P has a positive slope and a positive y-intercept. Line Q also has a positive slope and a positive y-intercept. The two slopes and the two y-intercepts are four different numbers, none equal. Lines P & Q have a single intersection point — what is the full set of possible quadrants in which the intersection point could be?
A.I only
B.I & III only
C.I & II only
D.I & II & III onl
Answer: D.I & II & III onl
Explanation: If you forget quadrants, take a look at this post. This is a tricky one, because you have to be careful to think about all cases. The first important point to realize is: any line with both a positive slope and a positive y-intercept goes through quadrants I & II & III, but never quadrant IV. Neither of these lines is ever in Quadrant IV, so they can’t intersect there. As it turns out, for different values of the slope, they can intersect in any of the other three quadrants.
Therefore, the answer = (D)
Question: The angle between the minute hand and the hour hand of a clock when the time is 4.20° is
A.0°
B.5°
C.10°
D.20°
Answer: C.10°
Explanation: Sol.
Angle traced by hour hand in 13/3 hrs = (360/12 x 13/3)° = 130°
Angle traced by min. hand in 20 min. = (360/60 x 20)° = 120°
∴ Required angle = (130 - 120)° = 10°
Answer C
Question: Two spherical balls lie on the ground touching. If one of the balls has a radius of 4 cm, and the point of contact is 6 cm above the ground, what is the radius of the other ball?
A.10 cm
B.12 cm
C.14 cm
D.16 cm
Answer: C.14 cm
Explanation: similar triangle properties..
2/r+4 = 4/r-4
giving r = 14.
Answer: C
Question: 4 weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 14 weavers in 14 days?
A.40
B.45
C.49
D.53
Answer: C.49
Explanation: 1 weaver can weave 1 mat in 4 days.
14 weavers can weave 14 mats in 4 days.
14 weavers can weave 49 mats in 14 days.
The answer is C.
Question: The chance of rain on any given day in Tel-Aviv is 50%. What is the probability A that it rained in Tel-Aviv on exactly 4 out of 6 randomly chosen days?
A.15/64
B.30/64
C.1/2
D.1/4
Answer: A.15/64
Explanation: chances of rain on exactly 4 days and not rain on 2 days = (1/2)^4* (1/2)^2 = 1/64
Chosing 4 days out of 6 = 6!/(4!*2!) = 15
chances of rain on exactly 4 days out of 6 days A= 15/64
Ans A it is.
Question: If X is invested in a bank at a rate of simple interest of y% p.a. for two years, then the interest earned is 400. if X is invested at y% p.a., for two years when the interest is compounded annually, the interest is 410. What is the value of X?
A.8000
B.6000
C.5000
D.4000
Answer: D.4000
Explanation: Simple way to solve this question is to use options.
From SI, we know that X*y=20,000.
Now, put the value of X = 4000, we will have y = 5%
To calculate CI,
Now, we know 1st year Amount= 4000+5% of 4000= 4200.
2nd year, Amount = 4200 + 5% of 4200 = 4410.
We can see after 2 years Interest = 4410-4000= 410. hence, it satisfies the question. Hence D is the correct answer
Question: Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour?
A.60 min
B.18 min
C.37 min
D.20 min
Answer: D.20 min
Explanation: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages.
Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr.
stoppage time = 20/60 hrs = 20 min.
Answer:D
Question: What is the product of all the numbers in the dial of a telephone ?
A.0
B.53231
C.12312445
D.451231
Answer: A.0
Explanation: Answer : A
Since one of the numbers on the dial of a telephone is zero, so the product of all the numbers on it is 0.
Question: A certain family has 3 sons: Richard is 6 years older than David, and David is 8 years older than Scott. If in 8 years, Richard will be twice as old as Scott, then how old was David 4 years ago?
A.8
B.10
C.12
D.14
Answer: B.10
Explanation: Let's say
Age of Richard is "R"
Age of David is "D"
Age of Scott is "S"
Now
Richard is 6 years older than David,
i.e. R = D +6
David is 8 years older than Scott
i.e. D = S +8
If in 8 years, Richard will be twice as old as Scott
i.e. R+8 = 2x(S+8)
i.e. R+8 = 2S + 16
i.e. R = 2S+8
But R = D+6 = (S+8)+6 = S+14
therefore, 2S + 8 = S +14
i.e. S = 6
i.e. R = 20
i.e. D = 14
Now,
how old was David 4 years ago?
i.e. D-4 = 14-4 = 10 years
ANSWER:B
Question: A man walks at a speed of 2 km/hr and runs at a speed of 7 km/hr. How much time will the man require to cover a distance of 10 1/2 km, if he completes half of the distance, i.e., (5 1/4) km on foot and the other half by running?
A.4 5/2 hours.
B.2 5/2 hours.
C.3 5/2 hours.
D.5 5/2 hours.
Answer: C.3 5/2 hours.
Explanation: Required time = (5 1/4)/2 + (5 1/4)/7 = 3 5/2 hours.
ANSWER:C
Question: A train is 560 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
A.56 seconds
B.18 seconds
C.40 seconds
D.19 seconds
Answer: A.56 seconds
Explanation: Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec
Total distance = 560+140 = 700 meter
Time = Distance/speed
= 700 * (2/25)
= 56 seconds
Answer: A
Question: I. j; k; m; n; p
II. j - 10; m; m; m; p + 15
III. j + 2; k + 1; m; n - 1; p - 2
If j, k, m, n, and p are consecutive positive integers such that j < k < m < n < p, the data sets I, II, and III above are ordered from greatest standard deviation C to least standard deviation in which of the following?
A. I, III, II
B. II, I, III
C. II, III, I
D. III, I, II
Answer: B. II, I, III
Explanation: Range of 1st Set = (p-j)
Range of 2nd Set = P+15 - j +10 = (p-j) +25
Range of 3rd Set = P -2 - j - 2 = (p-j) - 4
R2 > R1 > R3 ==> SD2 > SD1 > SD3
Since, C=Higher the Range -> More Dispersion in the Set -> More Standard Deviation.B
Question: Find the middle one when The sum of three consecutive even numbers is 36?
A.10
B.12
C.15
D.16
Answer: B.12
Explanation: 3 consecutive numbers can be a - 1, a, a + 1
So sum of numbers = 3a = 36.
Hence a = 12.
B
Question: Evaluate: 22 + sqrt(- 4 + 6*4*3)=?
A.4
B.14
C.24
D.34
Answer: C.24
Explanation: According to order of operations, inner brackets first where 6?4?3 is first calculated since it has a multiplication and a division.
6*4*3 = 24*3 = 8
Hence
22 + sqrt(- 4 + 6*4*3) = 22 + sqrt(- 4 + 8)
= 22+ sqrt(4) = 22 + 2 = 24
correct answer C
Question: Carolyn bought 17 gumballs, Lew bought 12 gumballs, and Carey bought X gumballs. The average (arithmetic mean) number of gumballs the three bought is between 19 and 25, inclusive. What is the difference between the greatest number and the smallest number of gumballs Carey could have bought?
A.18
B.20
C.22
D.24
Answer: A.18
Explanation: Smallest gumballs = (19-17) + (19-12) +19= 28
Largest gumballs = (25-17) + (25-12) +25= 46
Difference = 46 - 28 = 18
A
Question: The mean of 50 observations was 36. It was found later that an observation 46 was wrongly taken as 23. The corrected new mean is
A.35.24
B.36.16
C.36.24
D.36.46
Answer: D.36.46
Explanation: Solution
Correct sum = (36x50+46-23)
= 1823.
âˆ´ Correct mean = 1823 / 50
= 36.46.
Answer D
Question: Danny can divide his herd into 5 equal parts and also to 6 equal parts, but not to 9 equal parts. What could be the number of cows Danny has in his herd?
A.120
B.155
C.180
D.336
Answer: A.120
Explanation: Danny can divide his herd into 5 equal parts and also to 6 equal parts =>
No of cows = Multiple of 5 and 6 = Multiple of 30.
Only option A and C qualify.
Now 2nd condition : but not to 9 equal parts :
So it should not be a multiple of 9.
ANSWER:A
Question: There are two concentric circles with radii 10 and 6. If the radius of the outer circle is increased by 20% and the radius of the inner circle decreased by 50%, by what percent does the area between the circles increase?
A.11
B.111
C.211
D.311
Answer: B.111
Explanation: The area of a circle is piR^2, where R is the radius.
The area of the big circle is 100pi.
The area of the small circle is 36pi.
The area A1 between the circles is 64pi.
When the big circle's radius increases, the new area is 144pi.
When the small circle's radius decreases, the new area is 9pi.
The area A2 between the circles is 135pi.
The ratio of A2/A1 is 135/64 = 2.11 which is an increase of 111%.
The answer is B.
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
A.199
B.87
C.120
D.150
Answer: D.150
Explanation: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train = (Speed x Time) = (50/3 * 9) m = 150 m.Answer:D
Question: A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
A.7 liters
B.15 liters
C.10 liters
D.9 liters
Answer: C.10 liters
Explanation: Explanation:
Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters.
ANSWER IS C
Question: A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in?
A.17 hr
B.19 hr
C.10 hr
D.14 hr
Answer: D.14 hr
Explanation: Work done by the tank in 1 hour
= (1/2 - 1/3)
= 1/14 Leak will empty the tank in 14 hrs.
Answer:D
Question: Different breeds of dogs get older at different rates in “dog years.” Livonian wolfhounds age 7 times as fast as humans, whereas Khazarian terriers age 5 times as fast and Akkadian retrievers age 4 times as fast. If Dan bought a newborn Akkadian on January 1, 2002, a newborn Khazarian 1 year later, and a newborn Livonian 1 year after that, in what year will the sum of the dog-year ages of the Akkadian and the Khazarian first be exceeded by twice the age of the Livonian in dog years, rounding all ages down to the nearest integer?
A.2013
B.2014
C.2015
D.2007
Answer: D.2007
Explanation: I'm going with C:
I made a chart starting at 2004:
A+K=13
L=0.
Then I added 9 to a+k for each year and 14 to L for each year.
2005:AK=22 L=14
2006:AK=31 L=28
2007:AK=40 L=42
thus, 2007 is the correct answer. => D
Question: Anil spends 40% of his income on rent, 30% of the remaining on medicines and 20% of the remaining on education. If he saves Rs. 840 every month, then find his monthly salary?
A.Rs. 2000
B.Rs. 2500
C.Rs. 2700
D.Rs. 3000
Answer: B.Rs. 2500
Explanation: Let's Anil's salary be Rs. 100.
Money spent on Rent = 40% of 100 = Rs. 40.
Money spent on medical grounds = 30% of (100 - 40) = 3/10 * 60 = Rs. 18.
Money spent on education = 20% of (60 - 18) = 1/5 * 42 = Rs. 8.40
Anil saves 100 - (40 + 18 + 8.40) i.e., Rs. 33.60
for 33.6 ---> 100 ; 840 ---> ?
Required salary = 840/33.6 * 100 = Rs. 2500
B)
Question: Two trains of equal lengths take 15 sec and 20 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
A.16 sec
B.12 sec
C.17 sec
D.21 sec
Answer: C.17 sec
Explanation: Speed of the first train = 120/15 = 8 m/sec.
Speed of the second train = 120/20 = 6 m/sec.
Relative speed = 8 + 6 = 14 m/sec.
Required time = (120 + 120)/14 = 17 sec.
Answer: C
Question: A shopkeeper sells 400 metres of cloth for Rs. 18000 at a loss of Rs.5 per metre. Find his cost price for one metre of cloth?
A.Rs.59
B.Rs.58
C.Rs.09
D.Rs.50
Answer: D.Rs.50
Explanation: SP per metre = 18000/400
= Rs. 45 Loss per metre
= Rs. 5 CP per metre = 45 + 5
= Rs.50
Answer: D
Question: 20 men can do a work in 40 days. When should 20 men leave the work so that the entire work is completed in 40 days after they leave the work?
A.0 days
B.10 days
C.20 days
D.30 days
Answer: A.0 days
Explanation: Total work to be done = 20 * 40 = 800
Let 20 men leave the work after 'P' days, so that the remaining work is completed in 40 days after they leave the work.
40P + (20 * 40) = 800
40P = 0 => P = 0 days
ANSWER:A
Question: A train is 288 meter long is running at a speed of 29 km/hour. In what time will it pass a bridge of 101 meter length?
A.48.29
B.50
C.26.8
D.45.29
Answer: A.48.29
Explanation: Speed = 29 Km/hr = 29*(5/18) m/sec = 145/18 m/sec
Total distance = 288+101 = 389 meter
Time = Distance/speed
= 389 * (18/145) = 48.29 seconds.
Answer: A
Question: If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,880,715 minutes earlier? (Assume standard time in one location.)
A.6:22
B.6:24
C.6:27
D.6:30
Answer: A.6:22
Explanation: 6:27minus 2,880,715in any way must end with 2, the only answer choice which ends with 2 is A.
Answer: A.
Question: If 3 cats can kill 3 rats in 3 minutes, how long will it take 100 cats to kill 100 rats?
A.1 minutes
B.2 minutes
C.3 minutes
D.4 minutes
Answer: C.3 minutes
Explanation: It will take 3 minutes for 100 cats to kill 100 rats.
1 cat can kill 1 rat in 3 minutes, so 100 cats can kill 100 rats in 3 minutes
Answer C
Question: If y exceeds x by 25%, then x is less than y by?
A.28%
B.21%
C.20%
D.30%
Answer: C.20%
Explanation: X=100	y=125
125--------25
100--------? => 20%
Answer:C
Question: Difference of 2 parallel sides ofa trapezium is 4cm. perpendicular distance between them is 10cm. If the area of the trapezium is 250cm^2. Find the lengths of the parallel side?
A.20,25
B.21,25
C.27,23
D.28,25
Answer: C.27,23
Explanation: Let the two parallel sides of the trapezium be a cm and b cm.
Then, a-b = 4 ------ (1)
And, (1/2) x (a+b) x 10 = 475 =>(a+b) =((250 x 2)/10) => a + b = 50------- (2)
Solving 1 and 2, we get: a=27,b=23
So, the two parallel sides are 27 cm and 23 cm.
C
Question: If the cost price of 50 articles is equal to the selling price of 40 articles, then the gain or loss percent is?
A.33%
B.29%
C.25%
D.55%
Answer: C.25%
Explanation: C
25%
Given that, cost price of 50 article is equal to selling price of 40 articles.
Let cost price of one article = Rs. 1
Selling price of 40 articles = Rs. 50
But Cost price of 40 articles = Rs. 40
Therefore, the trader made profit.\Percentage of profit = 10/40 * 100 = 25%
Question: In a straight highway 2 cars starts from the same point in opposite directions each travels for 8 Kms and take left turn then travel for 6 Kms what is the distance between them now.
A.16
B.20
C.25
D.10
Answer: B.20
Explanation: use pythagoras theorem
c^2=a^2+b^2
=8^2+6^2 =64+36
c^2=100
c=10
the distance between A and B is (10+10)=20
ANSWER:B
Question: The distance between two towns is 380 km. At the same moment, a passenger car and a truck start moving towards each other from different towns. They meet 4 hours later. If the car drives 5 km/hr faster than the truck, what are their speeds?
A.33
B.45
C.37
D.36
Answer: B.45
Explanation: The main idea used in this kind of problems is that the distance equals speed multiplied by time S=V⋅tS=V⋅t
V (km/hr)	t (hr)	S (km)
Car	x + 5	4	4(x +5)
Truck	X	4	4x
4(x+5)+4x=3804(x+5)+4x=380
4x+4x=380−204x+4x=380−20
8x=3608x=360
x=3608x=3608
x=45x=45
Therefore the truck's speed is 45 km/hr, and the car's speed is 50 km/hr.
Answer:B
Question: A train 125 m long passes a man, running at 4 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
A.49 km/hr
B.50 km/hr
C.45 km/hr
D.65 km/hr
Answer: A.49 km/hr
Explanation: Speed of the train relative to man
= (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr
= 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed
= (x - 4) km/hr. x - 4 = 45 ==> x = 49 km/hr.
Answer: A
Question: An article sold at a profit of 20% if both the cost price and selling price would be Rs.20/- the profit
would be 10% more. What is the cost price of that article?
A.40
B.50
C.60
D.70
Answer: C.60
Explanation: if both cost price and selling price would be Rs.20 less.
let c.p-x and s.p-1.2x
1.2x-20 = 1.3(x-20)
x = 60
ANSWER:C