RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: We bought a total of 80 books at the store. Math books cost $4 and history books cost $5. The total price was $368. How many math books did we buy?
A.28
B.32
C.36
D.40
Answer: B.32
Explanation: M + H = 80
H = 80 - M
4M + 5H = 368
4M + 5*(80 - M) = 368
M = 32
The answer is B.
Question: A train 90 meters long completely crosses a 270-meter long bridge in 30 seconds. What is the speed of the train in km/h?
A.34.2 km/h
B.37.2 km/h
C.40.2 km/h
D.43.2 km/h
Answer: D.43.2 km/h
Explanation: speed = distance / time = (90 + 270)/30 = 360/30 (m/s) * 3600/1000 = 43.2 km/h
The answer is D.
Question: The county-mandated guidelines at a certain community college specify that for the introductory English class, the professor may choose one of three specified novels, and choose two from a list of 5 specified plays. Thus, the reading list for this introductory class is guaranteed to have one novel and two plays. How many different reading lists could a professor create within these parameters?
A.15
B.30
C.90
D.150
Answer: B.30
Explanation: There are three possibilities for the novel. With the plays, we are taken a combination of 2 from a set of 5 right n = 5, r = 2, n – r = 3
# of combinations = 5!/2!3! = (5)(4)(3)(2)(1)/(2)(1)(3)(2)(1) = (5)(4)/2 = 10
If the plays are P, Q, R, S, and T, then the 10 sets of two are PQ, PR, PS, PT, QR, QS, QT, RS, RT, & ST.
Any of the three novels can be grouped with any of the 10 possible pairs of plays, for a total of 30 possible reading lists.
Answer: B.
Question: Triangle ATriangle B are similar triangles with areas 2023 units square and 1792 units square respectively. The ratio of there corresponding height would be
A.9:10
B.17:16
C.23:27
D.13:17
Answer: B.17:16
Explanation: Let x be the height of triangle A and y be the height of triangle of B.
since triangles are similar, ratio of area of A and B is in the ratio of x^2/y^2
Therefore, (x^2/y^2)=2023/1792
(x^2/y^2)=(17*17*7)/(16*16*7)
(x^2/y^2)=17^2/16^2
x/y=17/16
Ans=B
You need to take a hint from given options to find factors of 2013 and 2527.
Question: 7 letters have to be put into their 7 respective envelopes. If the letters are inserted randomly into the envelopes, what is the probability that all the letters go into their respective envelopes?
A.1/30
B.1/720
C.1/5040
D.1/240
Answer: C.1/5040
Explanation: A-B-C-D-E (envelopes)
a-b-c-d-e (letters)
7 letters (a, b, c, d, and e) can be assigned to 7 envelopes (arranged) in 7! ways, out of which only one will be correct, thus the probability is 1/7! = 1/5040.
Answer: C.
Question: If an article is sold at 18% profit instead of 11% profit, then the profit would be $63 more. What is the cost price?
A.$600
B.$900
C.$1200
D.$1500
Answer: B.$900
Explanation: 7% * cost price = $63
1% * cost price = $63 / 7 = $9
The cost price is $900.
The answer is B.
Question: 36 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work?
A.12
B.18
C.22
D.24
Answer: D.24
Explanation: Let the required number of days be x.
Less men, More days (Indirect Proportion)
27 : 36 :: 18 : x 27 * x = 36 * 18
x =	(36 * 18)/27
x = 24.
Answer is D.
Question: What is the present age of Kim, given that the ratio between her age and her sisters age 7 years ago was 4:3, and her sister is presently 31 years old.
A.23
B.19
C.22
D.21
Answer: D.21
Explanation: Let the present ages of Kim's sister and Kim be 4x years and 3x years respectively
4x+7 = 35
4x = 28
x = 7
Kim's age = 3x = 21 years
Answer is D
Question: What is the smallest positive perfect square that is divisible by 4, 9, and 18?
A.36
B.81
C.144
D.625
Answer: A.36
Explanation: The number needs to be divisible by 2^2, 3^2, and 2*3^2.
The smallest such perfect square is 2^2*3^2 = 36
The answer is A.
Question: In a cinema hall for the matinee show which started at 2.30 pm and ended at 5.30 pm the vehicle parking lot had only three wheelers (auto rickshaws) and four wheelers. Today the wheels of the vehicles parked was counted and found to be 240. What could be the number of three wheelers parked therein ?
A.48
B.37
C.26
D.98
Answer: A.48
Explanation: Explanation:
3X + 4y = 240
by substitute through options 48 is correct
Answer: A
Question: A dishonest milk man tops up his bucket which is only 4/5 th full of milk with water. He again removes 5 liters of this mixture from the bucket and adds an equal quantity of water. If milk is now 60% of the mixture, what is the capacity of the bucket ?
A.15 lit
B.20 lit
C.22.5 lit
D.25 lit
Answer: B.20 lit
Explanation: Solution:
Let x be the capacity of the bucket.then, initial mixture has 80% milk.
then after 5 lt replaced with water---->(80/100)∗(x−5)=(60/100)∗x(80/100)∗(x−5)=(60/100)∗x
x=20 lt.
Ans:- B.
Question: How many ounces of a 60% salt solution must be added to 40 ounces of a 20 percent salt solution so that the resulting mixture is 40% salt?
A.16.67
B.40
C.50
D.60.33
Answer: B.40
Explanation: let x=ounces of 60% salt solution to be added
.2*40+.6x=.4(40+x)
x=40
Amswer B
Question: A and B start a business jointly. A invests Rs. 16,000 for 8 months and B remains in the business for 4 months, Out of total profit, B claims - of the profit. How much money was contributed by B ?
A.12822
B.12800
C.12819
D.12129
Answer: B.12800
Explanation: Let the total profit be Rs. x. Then, B = 2x/7 and A = (x - 2x /7) = 5x / 7.
So, A : B = 5x/7 : 2x/7 = 5 : 2.
Let B s capital be Rs. y. Then, (16000 * 8) / ( y * 4) = 5/2 <=> (16000 * 8 * 2) / (5 * 4) = 12800..
Answer: B
Question: Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 7 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her?
A.8 mph
B.5.25 mph
C.3.5 mph
D.4 mph
Answer: D.4 mph
Explanation: (1 mph +7 mph)/2 = 4 mph
Correct option is: D
Question: A photography dealer ordered 60 Model X cameras to be sold for $250 each, which represents a 10 percent markup over the dealer’s initial cost for each camera. Of the cameras ordered, 6 were never sold and were returned to the manufacturer for a refund of 50 percent of the dealer's initial cost. What was the dealer's approximate profit or loss as a percent of the dealer’s initial cost for the 60 cameras?
A.7% loss
B.13% loss
C.5% profit
D.13% profit
Answer: C.5% profit
Explanation: Total cost 60*($250/1.1)=54.54*250;
# of cameras sold is 60-5=55 total revenue is 55*250;
# of cameras returned is 6 total refund 6*(250/1.1)*0.5;
So, total income 55*250+ 6*(250/1.1)*0.5
The dealer's approximate profit is (55*250+ 6*(250/1.1)*0.5-54.54*250)/(54.54*250)*100=5%
Answer: C.
Question: The banker's discount on Rs. 1600 at 15% per annum is the same as true discount on Rs. 1680 for the same time and at the same rate. The time is:
A.7
B.4
C.5
D.3
Answer: B.4
Explanation: S.I. on Rs. 1600 = T.D. on Rs. 1680.
Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is on Rs. 1600 at 15%.
Time = 100 x 80	year	=	1	year = 4 months.
1600 x 15	3
Answer:B
Question: In an election between two candidates, one got 55% of the total valid votes. 20% of the votes were invalid. If the total number of votes was 7500, what was the number of valid votes that the other candidate got?
A.2800
B.2700
C.2100
D.2500
Answer: B.2700
Explanation: Total no of votes = 7500
20 % invalid
=>80% valid
tot valid votes = 7500*80/100
=>valid for 2nd candidate got
7500*80/100*45/100
=2700
ANSWER B
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 72 kmph and 90 kmph. In how much time will the trains cross each other?
A.80/8
B.80/9
C.80/5
D.80/3
Answer: B.80/9
Explanation: Relative speed = (72 + 90)* 5/18 = 9* 5 = 45 mps.
The time required = d/s = (100 + 100 + 200)/45
= 400/45 = 80/9 sec.
Answer: B
Question: The probabilities of solving a question by 3students A, B & C are 1/2,1/3 &1/4, respectively. The probability that the problem will be solved is?
A.3/4
B.3/5
C.4/7
D.4/9
Answer: B.3/5
Explanation: Sol. First, we find the probability of not solving the problem x PTO x = (1 — D x - D x - D
1 2 3 1 =iXiX71=4;
1 3 Required probability 3/4
B
Question: 42573y is exactly divisible by 72, then what is the minimum value of y?
A.3
B.4
C.6
D.8
Answer: C.6
Explanation: 72 = 9 x8, where 9 and 8 are co-prime.
The minimum value of x for which 73x for which 73x is divisible by 8 is, x = 6.
Sum of digits in 425736 = (4 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 9.
Required value of y is 6
C
Question: For a certain exam,a score of 58 was 2 standard deviations below mean and a score of 98 was 3 standard deviations above mean.What was the mean score R for the exam?
A.74
B.76
C.78
D.80
Answer: A.74
Explanation: A score of 58 was 2 standard deviations below the mean --> 58 = Mean - 2d
A score of 98 was 3 standard deviations above the mean --> 98 = Mean + 3d
Solving above for Mean R= 74.
Answer: A.
Question: 5 years ago, Paula was 3 times as old as Karl. In 6 years, Paula will be twice as old as Karl. What is the sum of their ages now?
A.42
B.46
C.50
D.54
Answer: D.54
Explanation: P-5 = 3(K-5) and so P = 3K-10
P+6 = 2(K+6)
(3K-10)+6 = 2K+12
K = 16
P = 38
P+K = 54
The answer is D.
Question: A five-person team is to be formed from a pool of 6 East All Stars and 6 West All Stars. What is the probability that the team will contain at least 2 East All Stars?
A.29/33
B.81/169
C.57/120
D.47/144
Answer: A.29/33
Explanation: Teams can be formed as 2E-3W , 3E-2W , 4E-W and 5E
Possible ways to make a team 2E-3W = 6c2 * 6c3 = 300
Possible ways to make a team 3E-2W = 6c3 * 6c2 = 300
Possible ways to make a team 4E-W = 6c4 * 6c1 = 90
Possible ways to make a team 5E = 6c5 = 6
Number of ways to select a team of 5 out of 12 people = 12c5
=12!/(7!*5!)
= 792
Probability that the team will contain at least 2 East All Stars
= (300+300+90+6) / 792
=696/792
= 29/33
Answer A
Alternatively we can also calculate the number of possible ways to make a team of 5W and E-4W .
Possible ways to make a team 5W = 6c5 = 6
Possible ways to make a team E-4W = 6c1 * 6c4 = 90
Probability that the team will contain at least 2 East All Stars = 1 - (96/792)
= 29/33
Question: A rectangular park is 110 m long and 65 m wide.in this park there is 2.5m wide path all four side.on this path on the rate of 7.20 per sq. m what will be cost of spreading sand?
A.6120
B.7350
C.6250
D.8285
Answer: A.6120
Explanation: Area of park=110*65=7150sq.m
Area of park without path=[(110-2.5*2)×(65-2.5*2)]sq.m
(105*60) sq.m=6300 sq.m
Area of path=(7150-6300)=850 sq.m
Cost of spreading sand=[850×720/100]=6120
Answer A
Question: 9 men went to a hotel. Eight of them spent Rs.3 each over their meals and the ninth spent Rs.2 more than the average expenditure of all the nine. Determine the total money spent by them?
A.29.25
B.30
C.31.2
D.34
Answer: A.29.25
Explanation: Average of 9 = x
9x = 8 * 3 + x * 2 x = 3.25
Total = 9 * 3.25 = 29.25
A
Question: There are 6 distinct letters of the English alphabet and 4 distinct digits. all possible 6 character apha-numero codes are generated using any 4 letters of the alphabet and any 2 available digits. If in any given code, the characters are all distinct, then what is the maximum number of such codes that can be generated?
A.4320
B.64800
C.8800
D.22000
Answer: B.64800
Explanation: From the six letters, we need four distinct letters
# of combinations = 6C4 = 15
From the four numerals, we need 2 distinct digits
4C2 = 6
Once we have our unique four letter and our unique 2 digits, we can put them in any order: each new order would be a different code. The number of orders would be
6! = 720
Total number of codes equals = 15*6*720
Without a calculator, first do 15*6 = 90. Then, 90 = 100 - 10, so
720*90 = 720*(100 - 10) = 72000 - 7200 = 64800
Answer = (B)
Question: A certain electric-company plan offers customers reduced rates for electricity used between 8 p.m. and 8 a.m. weekdays and 24 hours a day Saturdays and Sundays. Under this plan, the reduced rates Z apply to what fraction of a week?
A. 1/2
B. 5/8
C. 9/14
D. 16/21
Answer: C. 9/14
Explanation: Number of hours between 8 PM to 8 AM = 12
Number of hours with reduced rates = (12*5)+(24*2)
Hours with reduced rates Z/Total number of hours in a week = (12*5)+(24*2)/(24*7) = 108/(24*7) = 9/14
Answer: C
Question: Zinc and copper are melted together in the ratio 9 : 11. What is the weight of melted mixture, if 27 kg of zinc has been consumed in it?
A.58 kg
B.60 kg
C.64 kg
D.70 kg
Answer: B.60 kg
Explanation: Sol.
For 9 kg Zinc, mixture melted = (9+11) kg.
For 27 kg Zinc, mixture, melted = [20/9 x 27] kg
= 60 kg.
Answer B
Question: A certain party consists of four different group of people 30 students, 35 politicians, 20 actors and 27 leaders. On a particular function day, the total cost spent on party members was Rs.9000. It was found that 6 students spent as much as 7 politicians, 15 politicians spent as much as 12 actors and 10 actors spent as much as 9 leaders. How much did students spent?
A.2191
B.2200
C.2291
D.2391
Answer: C.2291
Explanation: Let S be the amount spent for all students
Let P be the amount spent for all politicians
Let A be the amount spent for all actors and
Let L be the amount spent for all leaders.
given that 6 students spent as much as 7 politicians
i.e Amount spent per student x 6 = Amount spent per politician x 7
Or (Total amount spent on students / Total Students) x 6 = (Total amount spent on politicians / Total politicians)x 7
Or., (S/30)x 6 = (P/35)x7
=> S/5 = P/5
=> S = P ..... eqn 1
15 politicians spent as much as 12 actors :
Therefore, (P/35)x15 = (A/20)x12
=> 3P/7 = 3A/5
=> 5P = 7P
=> 5S = 7A (since S = P)
=> A = 5S/7 ........eqn2
and 10 actors spent as much as 9 leaders :
Therefore, (A/20)x10 = (L/27)x9
=> 3A = 2L
=> A = 2L/3
=> 5S/7 = 2L/3 (since A=5S/7)
=> L = 15S/14 ......eqn3
the total amount spent for the party is Rs.9000
i.e., S+P+A+L = 9000
from eqn1, eqn2, eqn3 we have
S + S + 5S/7 + 15S/14 = 9000
53S/14 = 9000
s=9000*14 / 53
s=2290.90 ~ 2291
Hence the answer is Rs.2291
ANSWER:C
Question: Anna and Carol buy CDs and tapes at a music store that sells each of its CDs for a certain price and each of its tapes for a certain price. Anna spends twice as much as Carol spends, buying three times as many CDs and the same number of tapes. If Carol spends $70.00 on four CDs and five tapes, how much does one tape cost?
A.$5.00
B.$6.25
C.$7.00
D.$25.00
Answer: C.$7.00
Explanation: CD => C
Type => T
Carol: 4C+5T=70
Anna: 12C+5T=140
12C-4C=70
8C=70
C=8.75
4C+5T=70
35+5T=70
5T=35
T=7
Answer is C
Question: Anne, Markov, Peter line up at a ticket window. In how many ways can they arrange themselves so that Peter is first in line from the window?
A.a 24
B.b 12
C.c 9
D.d 2
Answer: D.d 2
Explanation: D
Peter's position is fixed. Now we need to arrange all others around Peter.
There are 2x1= 2 ways to arrange two people.
Question: When a merchant imported a certain item, he paid a 9 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that the merchant paid was $76.50, what was the total value of the item?
A.$1,250
B.$1,450
C.$1,650
D.$1,850
Answer: D.$1,850
Explanation: Let x be the value in excess of $1,000.
0.09x = 76.5
x = $850
The total value was $850 + $1,000 = $1,850.
The answer is D.
Question: In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes?
A.430
B.436
C.477
D.439
Answer: A.430
Explanation: Let the total number of valid votes be x.
70% of x = 70/100 * x = 7x/10
Number of votes secured by the other candidate = x - 7x/100 = 3x/10
Given, 7x/10 - 3x/10 = 172 => 4x/10 = 172
=> 4x = 1720 => x = 430.
Answer:A
Question: The greatest common divisor of (b-2)!,(b+1)!, and (b+4)! is 5040. what is the value of b?
A.8
B.10
C.12
D.9
Answer: D.9
Explanation: GCD of (b-2)!,(b+1)!, and (b+4)! is 5040. Find x.
Best way to find n is substitute each of the answer and find out the correct one.
Only option D gave the correct answer.
Option D: 9 and find GCD or 7!, 10! and 13!. 7! itself is 5040 and 7! which is contained in the other two factorials. This satisfies the condition, hence answer is 9.
Answer is D.
Question: By walking at 3/4th of his usual speed, a man reaches office 18 minutes later than usual. What is his usual time?
A.43min
B.54min
C.65min
D.60min
Answer: B.54min
Explanation: let T be the usual time.
time spent=4T/3
therefore, 4T/3=T+18
4T=3T+54...therefor T=54min
ANSWER:B
Question: A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train ?
A.230
B.777
C.267
D.288
Answer: A.230
Explanation: Explanation:
Relative speed = (120 + 80) km/hr
==
Let the length of the other train be x metres.
Then,
x + 270 = 500
x = 230.
Answer: A) 230 m
Question: If each participant of a chess tournament plays exactly one game with each of the remaining participants, then 153 games will be played during the tournament. Find the number of participants.
A.15
B.16
C.17
D.18
Answer: D.18
Explanation: If the number of participants is 3 (say A, B, C) the number of games played will be 2 (A plays against B and C) + 1 (B plays against C) = 3
Using the same logic, if the number of participants is n, the number of games played will be (n-1) + (n - 2) + (n - 3) + ... 3 + 2 + 1
Given that this sum = 153 = 1 + 2 + 3 + ... ( n - 1)
Sum of first m positive integers is given by m(m+1)/2. So sum of first (n-1) positive integers is (n-1)*n/2
153 = (n-1)*n/2
(n-1)*n = 306
17*18 = 306 (We know that 15^2 = 225 so the two consecutive numbers must be greater than 15. Also, 20^2 = 400 so the two numbers must be less than 20. The pair of numbers in between 15 and 20 whose product ends with 6 is 17 and 18)
So n = 18
Answer (D)
Question: A cab driver 5days income was $30, $50, $60, $65 , $70. Then his average income is?
A.A)$55
B.B)$42
C.C)$65
D.D)$48
Answer: A.A)$55
Explanation: avg = sum of observations/number of observations
avg income=(30+50+60+65+70)/5 = 55
Answer is A
Question: A wheel rotates 15 times every minute and moves 35 cm during each rotation. How many metres does the wheel move in one hour?
A.6 metre
B.12 metre
C.120 metre
D.315 metre
Answer: D.315 metre
Explanation: Number of times wheel moves in 1 hour = 15 * 60 = 900
:. Distance moves = (900 *35) cms = 31500 cms
In metres = 315 metre
ANSWER:D
Question: A clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 8 AM, what will be the time at the end of 10 days?
A.08:54:40 AM
B.08:56:24 AM
C.08:16:40 PM
D.08:54:24 AM
Answer: D.08:54:24 AM
Explanation: Loses 8 minutes each day.
so total loss = 4×8 = 32min
subsequent 6 days = 6×24×60 minutes
1% gain = ( 6×24×60)/100 = 86.4 minutes
so, total gain = 86.4 - 32 = 54.4 min = 54 + 0.4 min = 54 minutes + 0.4 × 60 seconds = 54min + 24seconds
10 days later the clock should be 54 min and 24seconds fast.
so time , 09:54:24 am (Answer D)
Question: Judges will select 6 finalists from the 7 contestants entered in a singing competition. The judges will then rank the contestants and award prizes to the 3 highest ranked contestants: a blue ribbon for first place, a red ribbon for second place, and a yellow ribbon for third place. How many different arrangements of prize-winners are possible?
A.140
B.21
C.210
D.420
Answer: A.140
Explanation: First Select 5 from 7 contestants and then select top 3 from those 5 =
7C6*6C3 = 7 * 20 = 140
ANS:A
Question: What will come in place of the x in the following Number series? 68, 36, 20, 12, 8, x
A.6
B.4
C.2
D.1
Answer: A.6
Explanation: 6868 / 2 + 2 = 3636 / 2 + 2 = 2020 / 2 + 2 = 1212 / 2 + 2 = 88 / 2 + 2 = 6 A
Question: Today is Thursday. The day after 54 days will be?
A.Monday
B.Tuesday
C.Saturday
D.Sunday
Answer: B.Tuesday
Explanation: Explanation:
54 days = 7 weeks 3 days = 5 odd days
Hence if today is Thursday, After 54 days, it will be = (Thursday + 5 odd days)
= Tuesday
Answer: Option B
Question: Amit and Ananthu can do a work in 15 days and 90 days respectively. Amit started the work and left after 3 days. Ananthu took over and completed the work. In how many days was the total work completed?
A.68 days
B.70 days
C.73 days
D.75 days
Answer: D.75 days
Explanation: Amit’s one day’s work= 1/15
Amit’s 3 day’s work = 1/15 *3 = 1/5
Work left= 1-1/5 = 4/5
Ananthu’s one day’s work= 1/90
Ananthu can do work in = 4/5 *90 = 72 days
So total days = 72+3 = 75 days
ANSWER:D
Question: The ratio of three numbers is 4:2:5 and their sum is 121. The second number of the three numbers is?
A.22
B.26
C.27
D.29
Answer: A.22
Explanation: 4:2:5
Total parts = 11
11 parts --> 121
1 part ---->11
The second number of the three numbers is = 2 * 11= 22
Answer : A
Question: The product of the squares of two positive integers is 81. How many pairs of positive integers satisfy this condition?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: Ans: C - 2 pairs
(xˆ2)(yˆ2) = 81 [square root both sides]
xy = 9
9 = 1x9, 9x1, 3x3
Cancel the repeats
This leaves us with exactly 2 options.
Hence, C
Question: What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58?
A.17
B.18
C.19
D.14
Answer: A.17
Explanation: Let the side of the square plot be a ft.
a2 = 289 => a = 17
Length of the fence = Perimeter of the plot = 4a = 68 ft.
Cost of building the fence = 68 * 58 = Rs. 3944.
Answer: Option A
Question: 2 hours after train A leaves Lucknow a train B leaves the same stationtraveling in the same direction at an average speed of 36 km/hr. After traveling 6 hrsthe train B overtakes the train A. What is the average speed of the train A?
A.22.5 km/hr
B.16 km/hr
C.27 km/hr
D.18 km/hr
Answer: C.27 km/hr
Explanation: Explanation :
Total distance covered by B=36*6=216kmTotal time taken by A to cover same distance=2+6=8 hrsaverage speed of A=216/8=27 km/hr
Answer : C
Question: The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit?
A.2000
B.2887
C.2797
D.1172
Answer: A.2000
Explanation: Explanation:
Let C.P. be Rs. x.
Then, (1920 - x)/x * 100 = (x - 1280)/x * 100
1920 - x = x - 1280
2x = 3200 => x = 1600
Required S.P. = 125 % of Rs. 1600 = 125/100 * 1600 = Rs. 2000.
Answer:A
Question: Thabo owns exactly 160 books, and each book is either paperback fiction, paperback nonfiction, or hardcover nonfiction. If he owns 20 more paperback nonfiction books than hardcover nonfiction books, and twice as many paperback fiction books as paperback nonfiction books, how many hardcover books nonfiction books does Thabo own?
A.10
B.25
C.35
D.46
Answer: B.25
Explanation: I think we can use double-matrix method and solve using only one variable.
Our goal is to find the number of hardcover nonfiction books. Let that number be x. We are given that all 140 books are either paperback fiction, paperback nonfiction, or hardcover nonfiction. This implies that number of hardcover fiction books is 0.
Double-matrix: P = paperback; H = hardcover; F = fiction; NF = nonfiction
P H Total
F 2x+40 0
NF x+20 x
Total 3x+60 x 160
3x + 60 + x = 160
x = 25
Answer (B.)
Question: In a manufacturing plant, it takes 36 machines 4 hours of continuous work to fill 8 standard orders. At this rate, how many hours of continuous work by 72 machines are required to fill 24 standard orders?
A.3
B.6
C.8
D.9
Answer: B.6
Explanation: the choices give away the answer..
36 machines take 4 hours to fill 8 standard orders..
in next eq we aredoubling the machines from 36 to 72, but thework is not doubling(only 1 1/2 times), = 4*48/72*24/8 = 6
Ans B
Question: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most?
A.176
B.178
C.215
D.197
Answer: C.215
Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is
= 6 * 6 * 6 = 216. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts
= 216 - 1 = 215.
Answer: C