RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The daily wage is increased by 50% and a person now gets Rs 25 per day. What was his daily wage before the increase ?
A.Rs 20
B.Rs 16.6
C.Rs 18
D.Rs 19
Answer: B.Rs 16.6
Explanation: Let A be the daily wages before the increase,
A ( 1 + x/100) = 25 (Given)
Here, x = 50
Therefore, A( 1 + 50/100) = 25
A = (25 x 100) / (150) = Rs 16.6.
ANSWER:B
Question: If a card is drawn from a well shuffled pack of cards, the probability of drawing a spade or a king is?
A.4/15
B.4/19
C.4/11
D.4/13
Answer: D.4/13
Explanation: P(SᴜK) = P(S) + P(K) - P(S∩K), where S denotes spade and K denotes king.
P(SᴜK) = 13/52 + 4/52 - 1/52 = 4/13
Answer: D
Question: A, B and C can do a piece of work in 24, 30 and 40 days respectively. They start the work together but C leaves 4 days before the completion of the work. In how many days is the work done?
A.16 days
B.18 days
C.19 days
D.11 days
Answer: D.11 days
Explanation: x/24 + x/30 + x/40 = 1
x = 11 days
Answer:D
Question: In how many ways the word "SCALE" can be arranged?
A.220
B.240
C.120
D.None
Answer: C.120
Explanation: Explanation :
The required number of ways = 5!
= 120
Answer : C
Question: How many 3 digit numbers can be formed from the digits 2,3,5,6,7
and 9 which are divisible by 5 and none of the digits is repeated?
A.5
B.20
C.4
D.3
Answer: B.20
Explanation: Since each desired number is divisible by 5,
so we much have 5 at the unit place.
The hundreds place
can now be filled by any of the remaining 4 digits .
so, there4 ways of filling it.
Required number of numbers = (1 * 5 * 4)
= 20
ANSWER B
Question: A sum of money at simple interest amounts to Rs. 825 in 3 years and to Rs. 830 in 4 years. The sum is?
A.s. 738
B.s. 638
C.s. 650
D.s. 810
Answer: D.s. 810
Explanation: S.I. for 1 year = (830 - 825) = Rs. 5
S.I. for 3 years = 5 * 3 = Rs. 15
Principal = (825 - 15) = Rs. 810.
ANSWER:D
Question: The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero ?
A.0
B.9
C.2
D.7
Answer: A.0
Explanation: Average of 20 numbers = 0.
Sum of 20 numbers = (0 * 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (- a).
Answer: A
Question: If w>0.9, which of the following options can be the value of w?
A.0.9^2
B.√(0.9)
C.0.09
D.0.9
Answer: B.√(0.9)
Explanation: Lets take a few examples
When .2 is squared it gives .04
when .5 is squared it gives .25
When .9 is squared it gives .81
So raising a fraction to its power of 2 or 3 only reduces the value of the fraction
This is because
.2 = 2/10
.2^2= 4/100
.2^3=8/1000
Since the denominator gets an extra 0 each time u increase the power , it is going to drag the value down
But if you just think about the opposite case :
Then we can see , if squaring a fraction diminish its value, then taking the square root of it will again increase its value
that is √(0.04) will give you back 0.2
so √(0.04) > 0.04
so obviously diminishing the power will appreciate the value
So w √(0.9) > 0.9
Hence Correct Answer is (B)
Question: In a class there are 10 boys and 15 girls. In how many ways can a boy and a girl be selected?
A.288
B.150
C.277
D.266
Answer: B.150
Explanation: We can select one boy from 10 boys in 10 ways.
We select one girl from 15 girls in 15 ways
We select a boy and girl in 10 * 15 ways i.e.,
= 150 ways.
Answer: B
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 90 kmph and 72 kmph. In how much time will the trains cross each other?
A.70/9 sec
B.80/9 sec
C.40/9 sec
D.60/9 sec
Answer: B.80/9 sec
Explanation: B
Relative speed = (90 + 72)* 5/18 = 9 * 5 = 45 mps.
The time required = d/s = (100 + 100 + 200)/45
= 400/45 = 80/9 sec.
Question: How many seconds will a 650 meter long train moving with a speed of 63 km/hr take to cross a man walking with a speed of 3 km/hr in the direction of the train ?
A.48
B.36
C.26
D.39
Answer: D.39
Explanation: Explanation:
Here distance d = 650 mts
speed s = 63 - 3 = 60 kmph = 60 x 5/18 m/s
time t = = 39 sec.
Answer: D
Question: If ab represents a positive two-digit number, where a and b are one-digit integers, which of the following CAN be true?
A.a + b = 9
B.a - b = 9
C.b - a = 9
D.Both A and B
Answer: D.Both A and B
Explanation: The (tens place digit, a) cannot be zero, but the (ones place digit, b) can be zero.
A is possible
B is possible
C is NOT possible
Answer: D
Question: If a card is randomly drawn from a well shuffled pack of cards, what is the probability of drawing a club, or a red jack, or a red queen, or the ten of spades?
A.5/13
B.7/26
C.9/26
D.17/52
Answer: C.9/26
Explanation: There are 13 clubs and 2 red jacks and 2 red queens and 1 ten of spades.
P(club or red jack or red queen or ten of spades) = 18/52 = 9/26
The answer is C.
Question: The average age of the district level hockey team of eleven is 22 years.The average age gets increased by 1 year when the coach age is also included.what is the age of the coach ?
A.84 yrs
B.34 yrs
C.64 yrs
D.24 yrs
Answer: B.34 yrs
Explanation: Explanation:
Total age of players in team = 22 x 11 = 242
When coach is included, total members = 12, Avg age increases by one becomes 23
Total age when coach is included = 23x12 = 276
Age of coach = 276-242 = 34 yrs.
Answer: B
Question: A box contains 2 red, 3 black and 4 blue balls. 3 balls are randomly drawn from the box. What is the probability that the balls are of different colors?
A.23
B.25
C.24
D.26
Answer: C.24
Explanation: A box contains 2 red, 3 black and 4 blue balls. 3 balls are randomly drawn from the box. What is the probability that the balls are of different colors?First consider the probability of drawing a red ball at the first draw, a black at the second and a blue at the third. The first probability is 2/9, the second, conditional on the first is 3/8 and the third conditional on the other two is 4/7. The product is (2*3*4)/(9*8*7). It is easy to see that any other order is equally likely (the only difference is the order of the factors in the numerator). So adding 6 equally likely cases we obtain (6*2*3*4)/(9*8*7) = 2/7.
Combinations approach-
Let us assume that all balls are unique.
There are a total of 9 balls.
Total ways = 3 balls can be chosen in 9C3 ways = 9(6!3!) = 9*8*7/3*2*1 = 84
Favorable ways = 1 Red ball, 1 Black ball, and 1 Blue Ball = 2*3*4 = 24
Answer C
Question: John walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 11 minutes earlier. How far is the office from his house?
A.3 4/5 Km
B.3 1/5 Km
C.4 1/5 Km
D.5 1/5 Km
Answer: A.3 4/5 Km
Explanation: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 19/6
= 24/2 * 19/60
= 19/5 = 3 4/5 Km
A
Question: A man can swim in still water at 12 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
A.4
B.4.2
C.5.3
D.1.5
Answer: A.4
Explanation: M = 12
S = x
DS = 12 + x
US = 12 - x
12 + x = (12 - x)2
12 + x = 24 -2x
3x = 12
x = 4
Answer:A
Question: Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both B & G, with these two children immediately adjacent to here on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations are there for the children?
A.240
B.480
C.720
D.1440
Answer: A.240
Explanation: In order to sit together they become one entity that instead of having 7 students we have 4+ group of 3 = 4+1= 5 entities. In order to arrange 5 = 5! and the group of 3 can be arranged in 2 ways GAB or BAG hence total possible configurations 240
answer is A
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is?
A.3/8
B.3/2
C.3/3
D.3/5
Answer: B.3/2
Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y ==> 4 x = 6 y ==> x/y = 3/2.
Answer: B
Question: A plane flies 500 miles at a speed of r mph. If the plane flies at a speed of r + 250 miles per hour, it would fly the same distance in 1 hour less. What is the value of r?
A.250 mph
B.200 mph
C.205 mph
D.300 mph
Answer: A.250 mph
Explanation: Equation: 500/r = 500/(r+50) + 1
Plug options into the equation
A fits: 500/250 = 500/(250+250) + 1
Answer: A
Question: Oliver travelled for 15 hours. He covered the first half of the distance at 40 kmph and remaining half of the distance at 45 kmph. Find the distance travelled by Oliver?
A.280 km
B.634 km
C.760 km
D.720 km
Answer: D.720 km
Explanation: Let the distance travelled be x km.
Total time = (x/2)/40 + (x/2)/45 = 15 => x/80 + x/90
= 15 => (9x + 8x)/720 = 15 => x
= 720 km
Answer: D
Question: The element being searched for is not found in an array of 100 elements. What is the average number of comparisons needed in a sequential search to determine that the element is not there, if the elements are completely unordered?
A.25
B.50
C.75
D.100
Answer: D.100
Explanation: let us assume k be the element we need to search
then let array be n1,n2,n3..............n100
now to prove that the element searched is not there in the array we have to compare the element K with every element in the array.
So,totally we need 100 comparisons.
ANSWER:D
Question: If (A+B) = 11, (B+C) = 9 and (C+D) = 3, what is the value of (A+D)?
A.16.
B.8.
C.5.
D.2.
Answer: C.5.
Explanation: Given A+B = 11 => A = 11 - B --> Eq 1
B+C = 9
C+D = 3 => D = 3 - C --> Eq 2
Then Eqs 1 + 2 => A + D = 11 - B + 3 - C
=> 14 - (B+C)
=> 14 - 9 = 5.
Option C...
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
A.76 years
B.88 years
C.55 years
D.10 years
Answer: D.10 years
Explanation: Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B's age = 2x = 10 years.Answer:D
Question: John has on his shelf four books of poetry, four novels, and two reference works. Suppose from these ten books, we were to pick two books at random. What is the probability that we pick one novel and one poetry?
A.1/2
B.16/45
C.3/10
D.7/20
Answer: B.16/45
Explanation: When we are picking two books, one novel and one reference work, we could either pick a novel first and then a reference book or pick a reference book and then a novel. Therefore the answer is 4/10*4/9 + 4/10*4/9 = 16/45.
Answer: B.
Question: In how many years will a sum of money doubles itself at 5% per annum on simple interest?
A.27%
B.70%
C.29%
D.20%
Answer: D.20%
Explanation: P = (P*5*R)/100
R = 20%
Answer: D
Question: A department of ten people - six men and four women - needs to send a team of five to a conference. If they want to make sure that there are no more than three members of the team from any one gender, how many distinct groups are possible to send?
A.120
B.150
C.180
D.210
Answer: C.180
Explanation: They can make a team of 3 men and 2 women.
The number of ways to do this is 6C3*4C2=20*6 = 120
They can make a team of 2 men and 3 women.
The number of ways to do this is 6C2*4C3=15*4 = 60
The total number of distinct groups is 180.
The answer is C.
Question: A customer bought a product at the shop. However, the shopkeeper increased the price of the product by 15% so that the customer could not buy the required amount of the product. The customer managed to buy only 60% of the required amount. What is the difference in the amount of money that the customer paid for the second purchase compared to the first purchase?
A.27%
B.29%
C.31%
D.33%
Answer: C.31%
Explanation: Let x be the amount of money paid for the first purchase.
The second time, the customer paid 0.6(1.15x)=0.69x.
The difference is 31%.
The answer is C.
Question: A batsman scored 120 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
A.50%
B.40%
C.60%
D.70%
Answer: A.50%
Explanation: Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 120 - (60)
= 60
Now, we need to calculate 60 is what percent of 120.
=> 60/120 x 100 = 50 %
ANSWER:A
Question: The price of a jacket is reduced by 25%. During a special sale the price of the jacket is reduced another 10%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount?
A.32.5
B.35
C.48
D.65
Answer: C.48
Explanation: 1) Let the price of jacket initially be $100.
2) Then it is decreased by 25% , therefore bringing down the price to $75.
3) Again it is further discounted by 10%, therefore bringing down the price to $67.5.
4) Now 67.5 has to be added by X % in order to equal the original price.
67.5 + ( X% ) 67.5 = 100.
Solving this eq for X, we get X = 48.1
Answer is C.
Question: In a certain game of dice, the player’s score is determined as a sum of two throws of a single die. The player with the highest score wins the round. If more than one player has the highest score, the winnings of the round are divided equally among these players. If John plays this game against 22 other players, what is the probability of the minimum score that will guarantee John some monetary payoff?
A.41/50
B.1/221
C.1/216
D.1/36
Answer: D.1/36
Explanation: To guarantee that John will get some monetary payoff he must score the maximum score of 6+6=12, because if he gets even one less than that so 11, someone can get 12 and John will get nothing.
P(12)=1/6^2=1/36.
Answer: D.
Question: In a two-digit, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is:
A.24
B.26
C.32
D.42
Answer: A.24
Explanation: Let the ten's digit be x.
Then, unit's digit = x + 2.
Number = 10x + (x + 2) = 11x + 2.
Sum of digits = x + (x + 2) = 2x + 2.
(11x + 2)(2x + 2) = 144
22x2 + 26x - 140 = 0
11x2 + 13x - 70 = 0
(x - 2)(11x + 35) = 0
x = 2.
Hence, required number = 11x + 2 = 24.
answer :A
Question: Katie has 9 employees that she must assign to 3 different projects. If 3 employees are assigned to each project and no one is assigned to multiple projects, how many different combinations C of project assignments are possible?
A.252
B.1,680
C.2,340
D.362,880
Answer: B.1,680
Explanation: The ways to select three employees out of 9 for first project = 9C3
The ways to select three employees out of Remaining 6 for Second project = 6C3
Third Project already has the group of three to be assigned to it so need to select that
So total ways to assign 3 employees to each of 3 projects C= 9C3 * 6C3 * 1 = 1,680
Answer: Option B
Question: A bag contains 6 red, 5 blue and 2 green balls. If 2 ballsare picked at random, what is the probability that both are red?
A.3/21
B.1/31
C.5/26
D.2/25
Answer: C.5/26
Explanation: P(Both are red),
=6C213C2=6C213C2
=5/26
C
Question: Last year, Company X paid out a total of $1,050,000 in salaries to its 43 employees. If no employee earned a salary that is more than 20% greater than any other employee, what is the lowest possible salary that any one employee earned?
A. $20,428.01
B. $41,667
C. $42,000
D. $50,000
Answer: A. $20,428.01
Explanation: Employee 1 earned $x(say)
Employee 2 will not earn more than $1.2x
Therfore, to minimize the salary of any one employee, we need to maximize the salaries of the other 42 employees
(1.2x*42)+x=1,050,000
Solving for x=$20,428.01
Answer A
Question: If x, y, and z are consecutive positive odd integers, not necessarily in that order, which of the following must be true? I. xy> z^4 II. (x + z)^5 > y III. x+y>z^4
A.III only
B.I only
C.I,III only
D.II only
Answer: D.II only
Explanation: Lets suppose that a,b,c can take any one of following three value 1,5,7. Most important point is that the options MUST BE TRUE under any condition.
x+y>z^4
Not necessarily true as 1+5<2401
xz>y^4
Not necessarily true as 1.7<625
We don't need to check option as all the options except D can be discarded.
Thus Answer D
Question: When n liters of fuel was added to a tank that was already 2/3 full, the tank was filled to 8/9 of its capacity. In terms of n, what is the capacity of the tank, in liters?
A.10/9 n
B.4/3 n
C.9/2 n
D.9/4 n
Answer: C.9/2 n
Explanation: C is the answer.
To solve this problem, draw diagram or use algebra. I'm more comfortable with algebra.
Given
- tank was already 2/3 full.
- When n ltr added, it became 8/9
So 2/3 + n = 8/9
n = 8/9 - 6/9
n = 2/9
capacity of the tank is full fraction . i.e. 1 i.e. 9/9
so the question is 9/9 is how much times n
= 9/9 = 1 = xn
so x = 9/2
and total = 9/2n
Question: Bob invested one half of his savings in a bond that paid simple interest for 2 years and received $500 as interest. He invested the remaining in a bond that paid compound interest (compounded annually) for the same 2 years at the same rate of interest and received $600 as interest. What was the annual rate of interest?
A. 5%
B. 10%
C. 12%
D. 4%
Answer: D. 4%
Explanation: First divide $500/2years to get 250$/yr non-compounding interest.
Next, subtract from the total compound after 2 years to see the interest gained in the second year. This can be done because the same amount has been invested in both accounts and the interest gained for the first year will be the same. So, $600-$250= $350.
To find the difference in interest gained, $350-$250= $100 increase in interest after the first year through compounding.
From this information we can set up the equation $250 * X% =04% giving us answer choice D.
Question: A fill pipe can fill 1/5 of tank in 25 minutes in how many minutes, it can fill 4/5 of the cistern?
A.48min
B.80 min
C.100 min
D.50 min
Answer: C.100 min
Explanation: 1/5 of the cistern can fill in 25 min
4/5 of the tank can fill in = 25*5*4/5 = 100 min
Answer is C
Question: At a dinner party, 5 people are to be seated around a circular table. 2 seating arrangements are considered different only when the positions of the people are different relative to each other. what is the total number W of different possible seating arrangements for the group?
A.5
B.10
C.24
D.32
Answer: C.24
Explanation: Circular arrangements= (n-1)!
Hence (4!) = 24=W
Answer is C
Question: The sale price of an article including the sales tax is616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is :
A.500
B.515
C.550
D.600
Answer: A.500
Explanation: Sol.(a) Let the CP of the article be x
Then, SP = x × 1.12 × 1.1
Now, x × 1.12 × 1.1 = 616
=> x = 616⁄1.232 = 500 Answer A
Question: If both 5^2 and 3^3 are factors of n x (2^5) x (12^2) x (7^3) x (10), what is the smallest possible positive value of n?
A.15
B.45
C.75
D.125
Answer: A.15
Explanation: (2^5) x (12^2) x (7^3) x (10) has two appearances of 3 (in 12^2) and one appearance of 5 (in the 10).
Thus n must include at least 3 * 5 = 15
The answer is A.
Question: An amount of money is to be divided between P, Q and R in the ratio of 3:7:12. If the difference between the shares of P and Q is Rs.2400, what will be the difference between Q and R's share?
A.2211
B.3000
C.2772
D.1211
Answer: B.3000
Explanation: 4 --- 2000
5 --- ? => 3000
Answer: B
Question: If 2^4, 3^3, and 10^3 are factors of the product of 1,452 and w, where w is a positive integer, what is the smallest possible value of w?
A.198
B.288
C.360
D.396
Answer: C.360
Explanation: I will go with C (pending elements to match is 2^2*3^2*10^1 = 360
Question: An engineer designed a ball so that when it was dropped, it rose with each bounce exactly one-half as high as it had fallen. The engineer dropped the ball from a 16-meter platform and caught it after it had traveled 44 meters. How many times did the ball bounce?
A.5
B.6
C.7
D.3
Answer: D.3
Explanation: Going down = 16 m
Going Up = 8 --> Total = 24
Going down = 8 --> Total = 32
Going Up = 4 --> Total = 36
Going down = 4 --> Total = 40
Going up = 2 --> Total = 42
Going down = 2 --> Total = 44 (Caught)
No of bounce = 3 ..
Answer : D
Question: The proportion of copper and zinc in the brass is 13:7. How much zinc will there be in 100 kg of brass?
A.73
B.35
C.83
D.63
Answer: B.35
Explanation: Explanation:
7/20 * 100 = 35
Answer: Option B
Question: The ratio of cost price to the marked price of an article is 4 : 5. If the ratio of the
profit percentage on selling the article to the discount allow ed on it is 5 : 4, w hat is the
profit percentage?
A.10%
B.12%
C.12.5%
D.15%
Answer: C.12.5%
Explanation: CP:MP=4:5
so assume cp=400 and MP=500.
PROFIT%:DISCOUNT=5:4. so let 5x and 4x.
now from the problem
After giving discount on marked price still he has a profit too.
500 - (4x% of 500) = 400 + (5x% of 400)
500 - 2x = 400 + 2x
solving we get x=5/2
profit percentage = 5x = 5(5/2) = 12.5%
ANSWER:C
Question: A sum of money amounts to Rs.6690 after 3 years and to Rs.10,035 after 6 years on compound interest.find the sum.
A.4360
B.4460
C.4580
D.4690
Answer: B.4460
Explanation: Let the sum be Rs.P.thenP(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii)On dividing,we get (1+R/100)^3=10025/6690=3/2.Substituting this value in (i),we get:P*(3/2)=6690 or P=(6690*2/3)=4460Hence,the sum is rs.4460. Answer : B
Question: Sahil purchased a machine at Rs 9000, then got it repaired at Rs 5000, then gave its transportation charges Rs 1000. Then he sold it with 50% of profit. At what price he actually sold it.
A.Rs. 22500
B.Rs. 24500
C.Rs. 26500
D.Rs. 28500
Answer: A.Rs. 22500
Explanation: Explanation:
Question seems a bit tricky, but it is very simple.
Just calculate all Cost price, then get 150% of CP.
C.P. = 9000 + 5000 + 1000 = 15000
150% of 15000 = 150/100 * 15000 = 22500
Option A
Question: The lenght of a room is 5.5 m and width is 4 m. Find the cost of paving the floor by slabs at the rate of Rs. 800 per sq. metre.
A.Rs. 15,550
B.Rs. 15,600
C.Rs. 16,500
D.Rs. 17,600
Answer: D.Rs. 17,600
Explanation: Area of the floor = (5.5 × 4) m2 = 22 m2.
Cost of paving = Rs. (800 × 22) = Rs. 17600.
Answer: Option D
Question: A is half good a work man as B and together they finish a job in 18 days. In how many days working alone B finish the job?
A.27 days
B.21 days
C.17 days
D.18 days
Answer: A.27 days
Explanation: WC = 1:2
2x + x = 1/18 => x = 1/54
2x = 1/54 => 27 days
Answer:A
Question: Find the average of the series : 312, 162, 132, 142 and 122?
A.174
B.178
C.119
D.110
Answer: A.174
Explanation: Average = (312 + 162 + 132 + 142 + 122)/5
= 870/5
= 174
Answer: A
Question: The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.2.0 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
A.s.1014
B.s.1332
C.s.999
D.s.1085
Answer: B.s.1332
Explanation: a2 = 3136 => a = 56
56 * 4 * 3 = 672 – 6 = 666 * 2.0 = 1332
ANSWER:B
Question: How many bricks are needed to build a pillar of dimension .5x.5x25 m , if the dimension of the brick is 8x5x22 cm and the 15% of the total volume of the pillar is filled with concrete and steel.
A.3500
B.4100
C.4847
D.5310
Answer: D.5310
Explanation: Volume of the pillar that needed to be filled with bricks=.5x.5x25x0.85=5.31
Volume of the brick=0.08x0.05x0.25=.001
No. of bicks needed to build the pillar=5.31/0.001= 5310
Answer: D
Question: Ross has 80 shirts, 3/4 of the shirts are green and 1/10 is without buttons. Therefore Ross has between ___ and ___ shirts with buttons that are not green.
A.12 ; 20.
B.12 ; 19.
C.12 ; 18.
D.12 ; 17.
Answer: A.12 ; 20.
Explanation: Total shirts = 80
Green shirts = 3/4*80 = 60, Non green shirts = 20
Shirts without button = 1/10*80 = 8, shirts with button = 72
Required: Range of shirts with buttons that are not green.
Maximum non green shirts with buttons = number of non green shirts = 20
Minimum non green shirts with buttons (All without button shirts are non green) = Non green shirts - shirts without button = 20 - 8 = 12
Hence the range would be (12, 20)
Correct Option: A
Question: Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety of tea in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, what is the price of the third variety per kg ?
A.175.5
B.182.5
C.170.0
D.180.0
Answer: A.175.5
Explanation: Tea worth Rs. 126
ratio 1 : 1
average price
= (126+135)/2=130.5
Mean price = (x-153):22.50
=>x-153=22.50
x=175.5
ANSWER A