RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Mukesh borrowed a sum of Rs. 10000 at simple interest from a bank. After two years he takes Rs. 12000 more as loan and discharge all the debt at the end of next 3 years depositing Rs. 27160 to the bank. What is the rate of interest per annum?
A.5%
B.6%
C.8%
D.10%
Answer: B.6%
Explanation: si=27160-(principal amount)=27160-22000=5160.
now,(10000*5*R/100) + (12000*3*R/100)=5160.
500R+360R=5160.....Rate=6%.
ANSWER:B
Question: The speeds of three asteroids were compared. Asteroids X-13 and Y-14 were observed for identical durations, while asteroid Z-15 was observed for 2 seconds longer. During its period of observation, asteroid Y-14 traveled three times the distance X-13 traveled, and therefore Y-14 was found to be faster than X-13 by 4000 kilometers per second. Asteroid Z-15 had an identical speed as that of X-13, but because Z-15 was observed for a longer period, it traveled five times the distance X-13 traveled during X-13's inspection. Asteroid X-13 traveled how many kilometers during its observation?
A.500
B.1,600/3
C.1,000
D.1,500
Answer: C.1,000
Explanation: ST+2S = 5ST
T+2 = 5T
2=4T
t= 1/2
We are looking for distance (d=s*t) so we need to solve for speed now that we have time.
Speed y14 - speed x13
Speed = d/t
3d/t - d/t = 4000 (remember, t is the same because both asteroids were observed for the same amount of time)
2d = 4000
2 = 2000
d=s*t
d=2000*(1/2)
d=1000
ANSWER: C
Question: Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 8 as quotient and the 15 as remainder
A.1235
B.1557.9
C.1378
D.1635
Answer: B.1557.9
Explanation: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 8x + 15
7x = 1350
x = 192.9
Large number = 192.9+1365 = 1557.9
B
Question: Four staff members at a certain company worked on a project. The amounts of time that the four staff members worked on the project were in the ratio 2 to 3 to 5 to 6. If one of the four staff members worked on the project for 15 hours, which of the following CANNOT be the total number of hours that the four staff members worked on the project?
A.120
B.80
C.48
D.192
Answer: D.192
Explanation: Four members worked in ration 2:3:5:6, hence as everyone mentioned, individual work could be taken as 2x, 3x,5x, and 6x. Also this gives us total work as 16x.
But we are told that one of these individual works is 15hrs. hence, possible scenarios, if
(1)2x =15 => 16x = 120 (2) 3x =15 => 16x = 80 (3) 5x =15 => 16x = 48 (4) 6x =15 => 16x = 40
Hence Answer is D 192 which can not be any of these.
Question: Anil and suresh started a business with Rs.50,000 and 40,000 respectively. After 6 months Rakesh joined them with capital of Rs.60,000 They got a profit of Rs.6000, then profit of Rakesh is
A.Rs.1500
B.Rs.3000
C.Rs.2000
D.Rs.1000
Answer: A.Rs.1500
Explanation: Ratio of investments of Anil, Suresh & Rakesh=(50000*12) : (40000*12) : (60000*6)=5 : 4 : 3
Profit of Rakesh in Rs. 6000 = 3*6000/(5+4+3) =1500
ANSWER:A
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 100 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
A.28 sec
B.16 sec
C.34 sec
D.18 sec
Answer: C.34 sec
Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 100 = 340 m.
Time taken = 340/10 = 34 sec.
Answer:C
Question: The percentage increase in the area of a rectangle, if each of its sides is increased by 20%
A.33
B.37
C.44
D.99
Answer: C.44
Explanation: Explanation:
Let original length = x metres and original breadth = y metres.
Original area = xy
Increased length = and Increased breadth =
New area =
The difference between the Original area and New area is:
Increase % == 44%]
Answer: C) 44%
Question: A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that exactly three bulbs are good.
A.20/61
B.20/63
C.20/62
D.20/87
Answer: B.20/63
Explanation: Required probability
= (⁵C₃ . ⁴C₁)/⁹C₄ = (10 * 4)/126
= 20/63
Answer: B
Question: The telephone company wants to add an area code composed of 2 letters to every phone number. In order to do so, the company chose a special sign language containing 224 different signs. If the company used 222 of the signs fully and two remained unused, how many additional area codes can be created if the company uses all 224 signs?
A.246
B.248
C.892
D.15,128
Answer: C.892
Explanation: # of 2-letter codes possible from 224 different signs = 224*224.
# of 2-letter codes possible from 222 different signs = 222*222.
The difference= 224^2 - 222^2 = (224 - 222)(224 + 222) = 892.
Answer: C.
Question: How many different positive integers exist between 10^4 and 10^5, the sum of whose digits is equal to 2?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: 10001
10010
10100
11000
20000
TOTAL NO. =5
C
Question: Molly's age in 18 years will be six times her age seven years ago. What is Molly's present age?
A.8
B.9
C.10
D.12
Answer: D.12
Explanation: Let x be Molly's present age.
x + 18 = 6(x-7)
x = 12
The answer is D.
Question: Two goods trains each 125 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
A.40
B.12
C.48
D.51
Answer: B.12
Explanation: Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 125 + 125 = 250 m.
Required time = 250 * 6/125 = 12 sec.
Answer: Option B
Question: How many integers between 7000 and 8000 that have distinct digits and increase from left to right ?
A.30
B.48
C.60
D.20
Answer: D.20
Explanation: Since the numbers must be distinct and increasing from left to right,
The only arrangements we could come-up with are:
745_ --> 4
746_ --> 3
747_ --> 2
748_ --> 1
756_ --> 3
757_ --> 2
758_ --> 1
767_ --> 2
768_ --> 1
778_ --> 1
Number of integers =20
D
Question: Some of the 50% solution of acid was removed and this was replaced with an equal amount of 14% solution of acid. As a result, a 23% solution of acid was obtained. What fraction of the original solution was replaced?
A.1/2
B.1/3
C.2/3
D.3/4
Answer: D.3/4
Explanation: Let x be the fraction of the original solution that was replaced.
0.5*(1-x)+0.14(x)=0.23
0.36x=0.27
x=3/4
The answer is D.
Question: What will be the output of the following code statements?
Integer a = 12, b = 45, c = 6 print (a × b / c) – c
A.65
B.84
C.29
D.26
Answer: B.84
Explanation: Explanation:
Apply BODMAS rule
12 × 45 = 540/6-6 =90 –6 =84
Answer:B
Question: This topic is locked. If you want to discuss this question please re-post it in the respective forum.
The sum of the first 51 positive even integers is 2550. What is the sum of the even integers from 100 to 200 inclusive?
A.5,100
B.7,650
C.10,100
D.15,500
Answer: B.7,650
Explanation: even numbers from 100 to 200=100/2+1=51
Sum= (200+100)x51/2=7650
So B is the ans.
Question: In the list 3, 3, 4, 5, 5, 5, 5, 7, 11, 21, what fraction of the data is less than the mode?
A.2/9
B.3/10
C.2/5
D.2/3
Answer: B.3/10
Explanation: Mode: The mode of any set is the term which has the highest frequency (Occurrence)
Highest frequent term in the set is 5 (with frequency 4) hence
Mode = 5
three terms (3, 3, 4) out of a total of 10 terms are less than mode of the set.
Fraction of set that are less than Mode of set = 3/10
Answer: Option B
Question: On a game show, there are three tables. Each table has three boxes (one Zonk!, one cash prize, and one Grand Prize). The contestant can choose one box from each table for a total of three boxes. If any of the boxes are a Zonk!, the contestant loses everything. What is the probability of getting NO Zonk! from any of the three boxes chosen?
A.1/5
B.1/3
C.8/27
D.1/27
Answer: C.8/27
Explanation: NO Zonk!:
1st box = No Zonk! = 2/3
2nd box = NO Zonk! = 2/3
3rd box = No Zonk! = 2/3
(2/3)(2/3)(2/3) = 8/27
8/27 is the probability of NO Zonk!, so...
Answer: C
Question: How many total number of ways in which b distinct objects can be put into two different boxes is
A.n2
B.2n
C.2b
D.3n
Answer: C.2b
Explanation: Let the two boxes be B1 and B2. There are two choices for each of the b objects. So, the total number of ways is
2 × 2 ×.....× 2 (b times ) = 2b
Answer C
Question: What is the next number in the sequence : 13,17,25,32,37,47,58,71__?
A.78
B.79
C.71
D.76
Answer: B.79
Explanation: next no. = previous + (sum of digits)
13 + (1+3) = 17
17 + (1+7) = 25
25 + (2+5) = 32
32 + (3+2) = 37
37 + (3+7) = 47
47 + (4+7) = 58
58 +(5+8) = 71
71 + (7+1) = 79
ANSWER:B
Question: Simplify: (4 – 6) – (12+17+3)-(3+5)
A.-10
B.-42
C.-44
D.-41
Answer: D.-41
Explanation: Solution:
(4-6)-(12+17+3)-(3+5)
=(-1)-32-8
=-1-32-8
=-33-8
-41
Answer: (D)
Question: An error 2% in excess is made while measuring the side ofa square. The % of error in the calculated area of the square is?
A.4.00%
B.4.04%
C.4.25%
D.4.30%
Answer: B.4.04%
Explanation: 100 cm is read as 102 cm.
A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.
(A2 - A1) = [(102)2 - (100)2]
= (102 + 100) x (102 - 100)
= 404 cm2.
Percentage error = 404 x 100 % = 4.04%
100 x 100
B
Question: If (x+3)^2/(3x+29)=2, then the difference between the two possible values of x is:
A.8
B.10
C.12
D.14
Answer: D.14
Explanation: (x+3)^2/(3x+29)=2
(x+3)^2=2(3x+29)
x^2+6x+9=6x+58
x^2-49=0
(x-7)(x+7)=0
x=7 or x=-7
The answer is D.
Question: What time will be taken by an amount of Rs. 900 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
A.7
B.8
C.9
D.2
Answer: D.2
Explanation: Explanation:
P= Rs 900
Rate = 4.5*
SI= Rs 81
=> SI= Time*P*rate
calculating for rate,
=> Time= SI/rate*P
= 81/4.5%*900
=> 2 years
Thus, it will take 2 years to yield Rs 81.
ANSWER: D
Question: A rectangular table seats 6 people on each of two sides, with every person directly facing another person across the table. If 12 people choose their seats at random, what is probability that person P directly faces person Q?
A.1/13
B.1/12
C.1/11
D.1/10
Answer: C.1/11
Explanation: Person P will be seated somewhere at the table.
Each of the other 11 people has an equal chance of sitting opposite person P.
The probability that person Q sits across is 1/11.
The answer is C.
Question: If |x - 5| = 23 what is the sum of all the values of x.
A.46
B.10
C.56
D.-46
Answer: B.10
Explanation: There will be two cases
x-5 = 23 and x-5 = -23
Solve for x => x=23+5=> x=28 or x= -23 + 5 => x= -18
The sum of both values will be 28 + -18 = 10
Answer is B
Question: n is an integer chosen at random from the set
{5, 7, 9, 11 }
p is chosen at random from the set
{2, 6, 10, 14, 18}
What is the probability that n + p = 7 ?
A.0.1
B.0.2
C.0.25
D.0.05
Answer: D.0.05
Explanation: Set N: there is 4 ways to chose a number
Set P: there is 5 ways to chose a number
so total outcome is 4*5 = 20 which is represent 20 pairs of number
now we have 1 pairs can give us 7 which are (5,2) .
1/20 = 0.05
Answer D
Question: The letters of the word 'SERITI' are written in all possible orders and these words are written in alphabetical order. Then what is the rank of the word 'SERITI'
A.- 238
B.- 245
C.- 307
D.- 315
Answer: A.- 238
Explanation: Total Number of Words = 6!/2! = 360 [(number of characters)/(repeating group )!]
After S, we have T and E.
Number of words starting with T = 5!/2! = 60
Number of words starting with U = 5!/2! = 60
So any word starting with S will have rank < 360 - 60(for Us) - 60(for Ts) = 240
Only option A < 240, so Answer is A.
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either blue or yellow?
A.2/29
B.2/20
C.2/21
D.2/22
Answer: C.2/21
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. Probability that both marbles are blue = ³C₂/¹⁵C₂ = (3 * 2)/(15 * 14) = 1/35
Probability that both are yellow = ²C₂/¹⁵C₂ = (2 * 1)/(15 * 14) = 1/105
Probability that one blue and other is yellow = (³C₁ * ²C₁)/¹⁵C₂ = (2 * 3 * 2)/(15 * 14) = 2/35
Required probability = 1/35 + 1/105 + 2/35
= 3/35 + 1/105 = 1/35(3 + 1/3)
= 10/(3 * 35) = 2/21
Answer: C
Question: What is the smallest number which, when increased by 9, is divisible by 8, 11, and 24?
A.237
B.246
C.255
D.264
Answer: C.255
Explanation: LCM(8,11,24)=24x11=264
So the least divisible number is 264, and the number we are looking for is 264-9=255.
The answer is C.
Question: Dora walked 3 kilometers. She walked first 1.5 kilometers in 20 meter per sec and the rest 1.5 kilometers in 60 meter per sec. what is the average speed?
A.28m/s
B.30m/s
C.32m/s
D.34m/s
Answer: B.30m/s
Explanation: Since the distance traveled is same, we can apply direct formula= 2XS1XS2/(S1+S2)
2X20X60/80= 30. 'B' is the answer.
Question: There is a train and car. The ratio between the speed of a train & a car is 24:19 respectively. Also, a bus covered a distance of 320 km in 5 hours. The speed of the bus is 2/3rd of the speed of the train. How many kilometers will the car cover in 4 hours?
A.276
B.290
C.304
D.318
Answer: C.304
Explanation: The speed of the bus is 320/5 = 64 km/hr
The speed of the train is (64*3)/2 = 96 km/hr
The speed of the car is 96/24 * 19 = 76 km/hr
The distance covered by the car in 4 hours is 76 × 4 = 304 km
The answer is C.
Question: What is the are of an equilateral triangle of side 16 cm?
A.64√5
B.64√9
C.44√3
D.64√3
Answer: D.64√3
Explanation: Area of an equilateral triangle = √3/4 S2
If S = 16, Area of triangle = √3/4 * 16 * 16 = 64√3 cm2;
Answer: D
Question: The edge of three cubes of metal is 3 dm, 4 dm and 5 dm. They are melted and formed into a single cube. Find the edge of the new cube?
A.15
B.7
C.9
D.6
Answer: D.6
Explanation: 33 + 43 + 53 = a3 => a
= 6
Answer:D
Question: An engine moves at the speed of 30 kmph without any coaches attached to it.Speed of the train reduces at the rate that varies directly as the square root of the number of coaches attached.When 9 coaches are attached speed decreases to 18 kmph. What will be the speed of train when 16 coaches are attached.
A.14
B.16
C.18
D.20
Answer: A.14
Explanation: 1.
No. of coaches =9
sqr root=3
speed decreases by 12
12=k*3
k=4
No. of coaches=16
swr root=4
decrease=4*4=16
New speed=30-16=14
A
Question: A husband and wife can complete a certain task in 1 and 2 hours respectively. Their children, Rae and Herman, can complete the same task in 4 and 5 hours, respectively. What is the ratio of the couple's time working together to complete the task to the children's time working together to complete the task?
A.a)15:46
B.b)3:10
C.c)12:23
D.d)5:18
Answer: B.b)3:10
Explanation: couples one hour work=1/1+1/2=3/2
so total time=2/3..
now, kids one hour work=1/4+1/5=9/20
so total time=20/9..
ratio=2/3:20/9=3/10
ans B
Question: Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.140. How much was lent at 5%?
A.2288
B.27669
C.1766
D.1000
Answer: D.1000
Explanation: (x*5*1)/100 + [(2500 - x)*6*1]/100 = 140
X = 1000
Answer: D
Question: Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at speed of 25 kmph. At what time will they meet?
A.9 a.m.
B.10 a.m.
C.10.30 a.m.
D.11 a.m.
Answer: B.10 a.m.
Explanation: Sol.
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20 x km.
Distance covered by B in (x-1) hours = 25(x-1) km.
∴ 20x + 25(x-1) = 110
⇔ 45x = 135
⇔ x = 3.
So, they meet at 10 a.m.
Answer B
Question: When positive integer A is divided by positive integer B, the result is 5.15. Which of the following could be the reminder when A is divided by B?
A. 2
B. 8
C. 7
D. 3
Answer: D. 3
Explanation: the remainder will be obtained from the decimal part when A is divided by B i.e. 0.15
0.15 = 15/100 = 3/20 so possible remainders are 3,6,12,9,15. Only option D-3 satisfies this
Ans - D
Question: In how many ways 8 different tickets W can be distributed between Jane and Bill if each is to receive any even number of tickets and all 8 tickets to be distributed.
A.From 2 to 6 inclusive.
B.From 98 to 102 inclusive.
C.From 122 to 126 inclusive.
D.From 128 to 132 inclusive.
Answer: D.From 128 to 132 inclusive.
Explanation: Possibilities
J 8 6 4 2 0
B 0 2 4 6 8
# of ways 8C8 8C6 8C4 8C2 8C0
W=1+28+70+28+1 = 128 Answer is D.
Question: How many pieces of 0.35 meteres can be cut from a rod 12.5 meteres long
A.30
B.40
C.35
D.60
Answer: C.35
Explanation: Explanation:
We need so simple divide 42.5/0.85,
=(1250/35) = 35
Option C
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
A.3/7
B.3/2.
C.3/88
D.3/8.
Answer: B.3/2.
Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y ==> 4 x = 6 y ==> x/y = 3/2.
Answer: B
Question: If 35 + 125 = 17.88, then what will be the value of 80 + 65 ?
A.13.41
B.20.46
C.21.66
D.22.35
Answer: D.22.35
Explanation: 35 + 125 = 17.88
35 + 25 x 5 = 17.88
35 + 55 = 17.88
85 = 17.88
5 = 2.235
80 + 65 = 16 x 5 + 65
= 45 + 65
= 105 = (10 x 2.235) = 22.35
Answer: Option D
Question: A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 5 metres apart, how many poles will be needed?
A.55
B.56
C.57
D.58
Answer: B.56
Explanation: Solution
Perimeter of the plot	= 2 ( 90 + 50 )
= 280 m.
Number of poles	= (280 / 5)
= 56 m.
Answer B
Question: If abc ≠2 and the sum of the reciprocals of a, b, and c equals the reciprocal of the product of a, b, and c, then a =
A.(1 + bc)/(b + c)
B.(1 – bc)/(b + c)
C.(1 + b + c)/(bc)
D.(1 – b – c)/(bc)
Answer: A.(1 + bc)/(b + c)
Explanation: Answer is A though it took me around 4 minutes to get that.
Question: If (5^7)(9^4)=3(15^x), what is the value of x?
A. 7
B. 9
C. 11
D. 13
Answer: A. 7
Explanation: (5^7)(9^4)=3(15^x)
=> 5^7 * 3^8 = 3 * 3^x * 5^x
=> 5^7 * 3^8 = 3^(x+1) * 5^x
Value of x = 7
Answer A
Question: How many words, with or without meaning, can be formed using all letters of the word EQUATION using each letter exactly once?
A.38,320
B.39,320
C.40,320
D.38,400
Answer: C.40,320
Explanation: The Word EQUATION has exactly 8 letters which are all different.
Therefore the number of words that can be formed = Number of permutations of 8 letters taken all at a time.
= P (8, 8) = 8!
= 8 × 7 x 6 × 5 x 4 x 3 x 2 × 1
= 40,320
ANSWER:C
Question: 325 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees
A.13
B.12
C.14
D.16
Answer: A.13
Explanation: 26 trees have 25 gaps between them,
Required distance (325/25) = 13
A
Question: A boy runs 200 metres in 24 seconds. What is his speed ?
A.20 km/hr
B.24 km/hr
C.28.5 km/hr
D.30 km/hr
Answer: D.30 km/hr
Explanation: 200/24 * 18/5 = 30 km/hr
Answer: D
Question: What is the sum R of all 3 digit numbers that leave a remainder of '2' when divided by 3?
A.897
B.164,850
C.164,749
D.149,700
Answer: B.164,850
Explanation: The series is => 101+...998
Number of terms => 300
sum => 300/2 * [101+998]
hence sum R=> 164850 i.e. option B
Question: David walks to a viewpoint and returns to the starting point by his car and thus takes a total time of 2 hours 20 minutes. He would have gained 1 hour by driving both ways. How long would it have taken for him to walk both ways.
A.4 h
B.3 h
C.5 h
D.3 h 20 min
Answer: D.3 h 20 min
Explanation: 1.Walking to to a viewpoint+Driving back=2 hours 20 minutes
2.Driving to a viewpoint+Driving back=2 hours 20 minutes - 1 hours=1 hours 20 minutes, thereforeone way driving=1 hours 20 minutes/2 = 40 minutes.
3. From 1.one way driving=2 hours 20 minutes-40 minutes=1 hour 40 minutes.
4.Walking to to a viewpoint+Walking back=1 hours 40 minutes+1 hours 40 minutes=3 hours 20 minutes.
Answer: D
Question: A basket has 5 apples and 4 oranges. Three fruits are picked at random. The probability that at least 2 apples are picked is
A.25/42
B.25/48
C.25/45
D.25/47
Answer: A.25/42
Explanation: Total fruits = 9
Since there must be at least two apples,
(5C2 * 4C1)/9C3 + 5C3/9C3 = 25/42.
Answer:A
Question: If anitha rows 65 km upstream and 105 km down steam taking 13 hours each, then the speed of the stream
A.8.4 kmph
B.5.5 kmph
C.6 kmph
D.8 kmph
Answer: D.8 kmph
Explanation: Speed upstream = 65/13 = 5 kmph
Speed down stream = 105/5 = 21 kmph
Speed of stream = ½ (21-5) = 8 kmph
ANSWER:D
Question: Of the 20 participants in a certain competition, half are male, and half of the males are younger than 18 years of age. If half of the female competitors are also younger than 18 years of age, into how many distinct groups of 4 competitors could the participants be divided if each group must contain two males under 18 years of age and 2 females over 18 years of age?
A.3
B.4
C.6
D.100
Answer: D.100
Explanation: M under 18 - 5
F above 18 - 5
How many distinct groups can be formed now: 5c2 * 5c2 = 100
Answer : D
Question: A cycle is bought for Rs.930 and sold for Rs.1210, find the gain percent?
A.70%
B.30%
C.40%
D.50%
Answer: B.30%
Explanation: Explanation:
930---- 280
100 ---- ? => 30%
Answer: B
Question: A shopkeeper sells his goods at cost price but uses a faulty meter that weighs 900 grams. Find the profit percent.
A.12.11
B.11.11
C.13.11
D.14.11
Answer: B.11.11
Explanation: Explanation:
(100 + g) / (100 + x) = True measure / Faulty measure
x = 0
true measure = 1000
faulty measure = 900
100 + g / 100 + 0 = 1000 / 900
100+g = 10/9*100
g = 11.11
ANSWER: B
Question: How many leading zeros (zeros after the decimal point but before the first nonzero digit of a number) are in 1/5!?
A.1
B.2
C.5
D.6
Answer: B.2
Explanation: 5! =120
1/1000 < 1/120 < 1/100
0.0001 < 1/120 < 0.001
So 1/120 has 2 leading zeros
Answer: B
Question: 0.35 represents what percent of 0.05?
A.0.05%
B.0.5%
C.5%
D.700%
Answer: D.700%
Explanation: One more method
0.35 represents what percent of 0.05?
Adjusting the decimal
35 represents what percent of 5?
Divide by 5
7 represents what percent of 1?
Answer = 7*100 = 700% = D
Question: If 13 = 13w/(1-w) ,then (5w)2 =
A.1/4
B.5
C.1
D.2
Answer: B.5
Explanation: 13-13w=13w
26w=13
w=1/2
5w=5/2
5w*2=5/2*2=5
ANSWER:B
Question: John, Vikram and Keerthana started a Pizza shop with capitals of Rs. 2000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of John is Rs. 500. The difference between the profit shares of Vikram and Keerthana is?
A.480
B.600
C.500
D.280
Answer: C.500
Explanation: Ratio of investments of John, Vikram and Keerthana is 2000 : 10000 : 12000 = 1 : 5 : 6
And also given that, profit share of John is Rs. 500
=> 1 part out of 12 parts is Rs. 500
Now, required difference is 6 - 5 = 1 part
Required difference = 1/1 (500) = Rs. 500.Answer: C
Question: A and B finish the job in 15 days.while A,B and C can finish it in 6 days . C alone will finish the job in
A.10 days
B.30 days
C.60 days
D.70 days
Answer: A.10 days
Explanation: Explanation:
6 = (15 * x)/(15 + x)
90+6x=15x
9x=90
X=10
Answer: Option A
Question: If taxi fares were $1.00 for the first 1/5 mile and $0.25 for each 1/5 mile there after, then the taxi fare for a 3-mile ride was
A.$1.56
B.$2.40
C.$3.80
D.$4.50
Answer: D.$4.50
Explanation: In 3 miles , initial 1/5 mile charge is $1
rest of the distance = 3 - (1/5) = 14/5
rest of the distance charge = 14(0.25) = $3.5 (as the charge is 0.25 for every 1/5 mile)
=> total charge for 3 miles = 1+3.5 = 4.5
Answer is D.