RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A coin has two sides. One side has the number 1 on it and the other side has the number 2 on it. If the coin is flipped three times what is the probability that the sum of the numbers on the landing side of the coin will be greater than 5?
A.3/8
B.1/16
C.1/8
D.1/2
Answer: C.1/8
Explanation: One approach to solve the problem is to list the different possibilities for a toss of coin three times. Because there are two outcomes and the coin is tossed three times, the table will have 2*2*2 or 8 rows.
Next add the resulting rows together to find the sum (the fourth column in the table below).
Toss 1 | Toss 2 | Toss 3 | Sum
1 ---------- 1 -------- 1 ------ 3
1 ---------- 1 -------- 2 ------ 4
1 ---------- 2 -------- 1 ------ 4
1 ---------- 2 -------- 2 ------ 5
2 ---------- 1 -------- 1 ------ 4
2 ---------- 1 -------- 2 ------ 5
2 ---------- 2 -------- 1 ------ 5
2 ---------- 2 -------- 2 ------ 6
From the table we see that there are 1 situations where the sum of the tosses will be greater than 5. And there are 8 possible combinations resulting in a probability of
1/8 or a probability of 1/8.
SO the correct answer is C.
Question: If x = –2, what is the value of 4x^3?
A.–32
B.–24
C.–8
D.8
Answer: A.–32
Explanation: 4x^3 = 4(−2)34(−2)3 = 4 * - 8 = -32.
Answer is -32
ANSWER:A
Question: Adam has s pairs of shoes, which is 1/2 as many as Katherine and twice as many as Julie. In terms of s, how many pairs of shoes do the three of them have combined?
A.7/2*s
B.11s
C.2s
D.5/2*s
Answer: A.7/2*s
Explanation: == s +2s + s/2 ==> 3s + 1/2 s = 7/2*s
Ans .A
Question: A table is bought for Rs.800/- and sold at Rs.600/- find gain or loss percentage
A.25% gain
B.20% loss
C.20% gain
D.25% loss
Answer: D.25% loss
Explanation: Formula = (Selling price ~ Cost price)/Cost price * 100
= (600 - 800)/800 = 25% loss
D
Question: The average of first 10 prime numbers is?
A.12.9
B.12.6
C.12.3
D.512.4
Answer: A.12.9
Explanation: Sum of 10 prime no. = 129
Average = 129/10 = 12.9
Answer: A
Question: The speed of a boat in still water is 12 kmph. What is the speed of the stream if the boat can cover 32 km downstream or 16 km upstream in the same time?
A.5 kmph
B.6 kmph
C.7 kmph
D.4 kmph
Answer: D.4 kmph
Explanation: X = the speed of the stream
(12 + X) / (12 - X) = 2/1
12+ X = 24 - 2X
3X = 12
X = 4 km/hour
If the speed of the stream is 4km/hour, then the 'downstream' speed of the boat is 12+4 = 16km/hour and the 'upstream' speed of the boat is 12-4 = 8km/hour. In that way, if the boat traveled for 2 hours, it would travel 2x8 = 16km downstream and 2x16 = 32km/hour upstream.
Answer : D
Question: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8748, its purchase price was :
A.12000
B.10000
C.15000
D.20000
Answer: A.12000
Explanation: Purchase = 8748/(1-10/100^3) = 12000
ANSWER A
Question: A man is 20 mins late to the office if he walks at 20 kmph, and 15 mins earlier if he walks at 30 kmph. How much time will he be early/late if he walks at 25 kmph?
A.early 1 min
B.early 2 min
C.late 1 min
D.late 2 min
Answer: A.early 1 min
Explanation: let distance be x,then
time1= x/20*60,
t2=x/30*60
difference b/w both time is 35min then
x/20-x/30=35 so x=35
now for 25kmph
35/25*60= 84 min
for 20kmph time=105 min
for 30kmph time= 70min
in 30 kmph he is early by 15 min then actual time is 85 min
so the anser is he is early by 1 min
ans=early 1 min
t=35/25*60
ANSWER:A
Question: Calculate the value of 8.14 x 10^3 ?
A.81400000
B.8140000
C.814000
D.8140
Answer: D.8140
Explanation: 8.14 x 10^6 = 8.14 x 1000 = 8140.
Answer = D
Question: The ratio of two numbers is 4 : 5 and their H.C.F. is 4. Their L.C.M. is
A.48
B.22
C.80
D.27
Answer: C.80
Explanation: Explanation:
Let the numbers be 4x and 5x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 16 and 20.
L.C.M. of 16 and 20 = 80.
Answer: Option C
Question: A certain debt will be paid in 52 installments from January 1 to December 31 of a certain year. Each of the first 12 payments is to be $410; each of the remaining payments is to be $65 more than each of the first 12 payments. What is the average (arithmetic mean) payment that will be made on the debt for the year?
A.443
B.450
C.460
D.468
Answer: C.460
Explanation: Total number of installments = 52
Payment per installment for the first 12 installments = 410
Payment per installment for the remaining 32 installments = 410+65=475
Average = (12*410 + 40*475)/52 = 460
Answer C
Question: One out of every 5000 computer chips is defective. If 2 out of every 30 defective chips have defective processors and there are 30 defective processors in the first batch, how many computer chips are there in the first batch?
A.450
B.900
C.90,000
D.2250,000
Answer: D.2250,000
Explanation: (D) Read the whole question to get the feel of what they are asking you to find. Then start with the smallest amount and work your way outwards. We are told that two out of every 30 defective chips have a defective processor. Let x be the total number of defective processors in the batch. Because we know 2 out of every 30 defective chips will have defective processors, and the total number of defective processors in the batch is 30, we can write out an equation: (2/30)x = 30. This can be simplified to (1/15)x = 30. Multiplying each side by 15, we arrive at x = 450. This tells us that there are 450 defective chips in the whole batch. Because we know that 1 out of every 1000 chips is defective, we can set up a proportion. If 1 out of every 5000 chips is defective, then 450 out of y chips would be defective, where y is the total number of chips in the batch. This can be set up as an equation as follows: 1/5000 = 450/y. Solve for y and you will get the total number of chips in the batch: 2250,000.
The answer is (D).
Question: If Solomon distributes his toys in the ratio of 1/4 : 1/6 : 1/10 : 1/9 between his four friends A, B, C and D, then find the total number of toys Solomon should have?
A.111.7
B.118.7
C.113.7
D.218.7
Answer: B.118.7
Explanation: Here, A : B : C : D = 1/4 : 1/6 : 1/10 : 1/9
1) L.C.M of 4 : 6 : 10 : 9 is 180
2) Find the number of pens each friend received --------- (To find no. of pens each friend has, multiply the ratio with the L.C.M. calculated)
A = (1/4) x 180 = 45
B = (1/6) x 180 = 30
C = (1/10) x 180 = 18
D = (1/7) x 180 = 25.7
3) Total number of toys = (45 x + 30 x + 18 x + 25.7 x) = 118.7 x
Minimum number of pens (x) = 1
Therefore, total number of pens = 118.7 pens.
Correct option :B
Question: Anil spends 40% of his income on rent, 30% of the remaining on medicines and 20% of the remaining on education. If he saves Rs. 840 every month, then find his monthly salary?
A.RS.3500
B.Rs.1500
C.Rs.4500
D.Rs.2500
Answer: D.Rs.2500
Explanation: Answer: Option D
Let's anil's salary be Rs. 100.
Money spent on Rent = 40% of 100 = Rs. 40.
Money spent on medical grounds = 30% of (100 - 40) = 3/10 * 60 = Rs. 18.
Money spent on education = 20% of (60 - 18) = 1/5 * 42 = Rs. 8.40
anil saves 100 - (40 + 18 + 8.40) i.e., Rs. 33.60
for 33.6 ---> 100 ; 840 ---> ?
Required salary = 840/33.6 * 100 = Rs. 2500
Question: When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/4 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?
A.1
B.2/5
C.1/2
D.2/3
Answer: A.1
Explanation: Say, the tree grows by x feet every year.
Then, 4 + 6x = (1+1/4)(4+4x)
or, x = 1
Answer A
Question: Ravi purchased a refrigerator and a mobile phone for Rs. 15000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 4 percent and the mobile phone at a profit of 10 percent. Overall he make a.
A.223
B.277
C.288
D.200
Answer: D.200
Explanation: Let the SP of the refrigerator and the mobile phone be Rs. r and Rs. m respectively.
r = 15000(1 - 4/100) = 15000 - 600
m = 8000(1 + 10/100) = 8000 + 800
Total SP - Total CP = r + m - (15000 + 8000) = -600 + 800 = Rs. 200
As this is positive, an overall profit of Rs. 200 was made.
Answer: D
Question: If y > 0, (1y)/20 + (3y)/10 is what percent of y?
A.35%
B.50%
C.60%
D.70%
Answer: A.35%
Explanation: can be reduced to y/20+3y/10 =7y/20=35%
A
Question: This topic is locked. If you want to discuss this question please re-post it in the respective forum.
Matt and Peter can do together a piece of work in 20 days. After they have worked together for 12 days Matt stops and Peter completes the remaining work in 14 days. In how many days Peter complete the work separately.
A.26 days
B.27 days
C.23 days
D.35 days
Answer: D.35 days
Explanation: Together they complete the job in 20 days means they complete 12/20 of the job after 12 days.
Peter completes the remaining (8/20) of the job in 14 days which means that the whole job(1) can be completed in X days.
<=> 8/20->14 <=> X=14/(8/20)=35Thus the answer is D.
Question: The average weight of 6 person's increases by 4.5 kg when a new person comes in place of one of them weighing 75 kg. What might be the weight of the new person?
A.160 kg
B.175 kg
C.180 kg
D.102 kg
Answer: D.102 kg
Explanation: Total weight increased = (6 x 4.5) kg = 27 kg.
Weight of new person = (75 + 27) kg = 102 kg
Option D
Question: If Aug 15th,2012 falls on Thursday then June 11th,2013 falls on which day ?
A.monday
B.saturday
C.friday
D.wednesday
Answer: D.wednesday
Explanation: First,we count the number of odd days for the left over days in the given period.
Here,given period is 15.8.2012 to 11.6.2013
Aug Sept Oct Nov Dec Jan Feb Mar Apr May Jun
16 30 31 30 31 31 28 31 30 31 11(left days)
2 + 2 + 3 + 2 + 3 + 3 + 0 + 3 + 2 + 3 + 4 (odd days) = 6 odd days
So,given day Thursday + 6 = Wednesday is the required result.
Answer: D) Wednesday
Question: -88 × 39 + 312 = ?
A.-3200
B.3120
C.-3120
D.3200
Answer: C.-3120
Explanation: -88 × 39 + 312 = -88 × (40-1) + 312
= -88 × 40 + 88 + 312
= -3520 + 88 + 312
= -3120
Answer is C
Question: Rob traveled a distance of 30 km, covering the first 10 km in x minutes, the next 10 km in y minutes and the last 10 km in z minutes. If he totally took 3y minutes to cover the whole distance, then which of the following cannot be true? Assume x , y and z are different.
A.z=3x
B.x=3z
C.y=2x
D.x=2y
Answer: D.x=2y
Explanation: Rob Travelled for x,y and for z min.
Total Time : x + y + z
Which is equal to : 3y
Equating both sides we get
x+y+z = 3y
=> x+z =2y ........ Eqn 1
Looking out at options
D Says x =2y
Using it in Eqn 1
2y + z = 2y
=> Z = 0 mins, Which I guess is not possible.
The Ans isD
Question: A certain cube floating in a bucket of water has between 75 and 85 percent of its volume below the surface of the water. If between 9 and 16 cubic centimeters of the cube's volume is above the surface of the water, then the length of a side of the cube is approximately
A.4
B.5
C.7
D.8
Answer: A.4
Explanation: If sides are 7, vol=7^3=343
75%= 257.25, 85%=291.55
so vol above water, between 85.75 and 51.45 -->too big
If side are 4, vol = 64
75%=48, 85%=54.4
vol above water between 16 and 9.6
So 4 should be the answer.
Check option C,
If sides are 5, vol = 125
75%= 93.75, .85%=106.25
vol above water between 18.75-31.25
(Sides are 4 cubic centimeters)
A
Question: An inspector rejects 0.08% of the meters as defective. How many will be examine to project ?
A.5500
B.7500
C.3500
D.2500
Answer: D.2500
Explanation: Let the number of meters to be examined be x.
Then, 0.08% of x =2
[(8/100)*(1/100)*x] = 2
x = [(2*100*100)/8] = 2500.
Answer is D.
Question: In how many ways can the letters of the word, ‘LANGUAGE’ be arranged in such a way that the vowels always come together?
A.600
B.700
C.720
D.750
Answer: C.720
Explanation: In the word ‘LANGUAGE’ we treat the vowels AUAE as one letter. Thus, we have LNGG (AUAE).
This we have 5 letters of which G occurs 2 times and the rest are different.
Number of ways arranging these letters= 5!/2! =5*4*3= 60
Now, 4 letters of which A occurs 2 times and the rest are different, can be arranged in 4!/2!
= 4*3=12.
Therefore, Required number of ways= 60*12= 720
ANSWER: C
Question: Out of 15 consecutive numbers, 2 are chosen at random. The probability that they are both odds or both primes is?
A.1/1
B.1/7
C.1/8
D.1/3
Answer: B.1/7
Explanation: A leap year has 52 weeks and two days
Total number of cases = 7
Number of favourable cases = 1
i.e., {Saturday, Sunday}
Required Probability = 1/7
Answer:B
Question: What is the difference between the compound interest on Rs.12000 at 20% p.a. for one year when compounded yearly and half yearly?
A.337
B.120
C.266
D.287
Answer: B.120
Explanation: When compounded annually, interest
= 12000[1 + 20/100]1 - 12000 = Rs.2400
When compounded semi-annually, interest
= 12000[1 + 10/100]2 - 12000 = Rs.2520
Required difference = 2520 - 2400 = Rs.120
Answer:B
Question: Compound interest earned on a sum for the second and the third years are Rs.2500 and Rs.2625 respectively. Find the rate of interest?
A.10% p.a.
B.5% p.a.
C.15% p.a.
D.12.5% p.a.
Answer: B.5% p.a.
Explanation: Rs.2625 - 2500 = Rs.125 is the interest on Rs.2500 for one year.
Rate of interest = (125/2500) * 100 = 5% p.a
ANSWER:B
Question: Jimmy has 18% more cookies than Janice. What percentage of cookies should Jimmy give to Janice so that both Jimmy and Janice have the same number of cookies?
A.7.6%
B.8.5%
C.9%
D.11%
Answer: A.7.6%
Explanation: An easy way to solve this question is by number plugging. Assume Janice has 100 cookies then Jimmy has 118 cookies. Now, for both Jimmy and Janice to have equal amounts of cookies we should give Janice 9 of Jimmy's cookies, which is 9/118=~7.6% of Jimmy's cookies.
Answer: A.
Question: The greatest common factor of 16 and the positive integer n is 4, and the greatest common factor of n and 45 is 3. Which of the following could be the greatest common factor of n and 60?
A.3
B.30
C.40
D.42
Answer: B.30
Explanation: Greatest common factor n and 16 is 4 = 2*2 * 2*2
Greatest common factor n and 45 is 3 = 3*3 *5
Greatest common factor n and 60 is = 2*3*5 =30
Answer: B.
Question: Rajan mixed 24 kg of butter at Rs. 200 per kg with 36 kg butter at the rate of Rs. 150 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction?
A.Rs.129
B.Rs.120
C.Rs.238
D.Rs.178
Answer: C.Rs.238
Explanation: CP per kg of mixture = [24*200) + 36*150)]/(24 + 36)
= Rs. 10200/60 =Rs. 170
SP = Rs.170 + 170*40/100
= Rs.170+68
= Rs.238
Answer:C
Question: How many 3 – digit number can be formed from the digit 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated?
A.5
B.10
C.15
D.20
Answer: D.20
Explanation: Solution
Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.
Tens place can be filled by any of the remaining 5 numbers.
So, there are 5 ways of filling the tens place.
The hundreds place can now be filled by any of the reaming 4 digits. so, there are 4 ways of filling it.
So, Required number of numbers = (1 × 5 × 4) = 20 . Answer D
Question: Last year the price per share of Stock X increased by k percent and the earnings per share of Stock X increased by m percent, where k is greater than m. By what percent did the ratio of price per share to earnings per share increase, in terms of k and m?
A.k/m %
B.(k-m) %
C.[100(k-m)]/(100+k) %
D.[100(k-m)]/(100+m) %
Answer: D.[100(k-m)]/(100+m) %
Explanation: If old price per share = X, old Earnings per share = Y
=> Old ratio = X/Y
New price per share = X(100+k)/100, new Earnings per share = Y(100+m)/100
=>New ratio = X(100+K)/[(100+m)(Y)]
Increase in the ratios after simplifying comes to [100(k-m)]/(100+m) %
ANSWER:D
Question: A car is running at a speed of 80kmph. What distance will it cover in 20sec?
A.100m
B.440m
C.180m
D.200m
Answer: B.440m
Explanation: Speed = 80kmph = 80*5/18 = 22 m/s
Distance covered in 20sec = 22*10 = 440m
Answer is B
Question: In what time will a train 120 m long cross an electric pole, it its speed be 121 km/hr?
A.2.5
B.2.7
C.2.9
D.3.6
Answer: D.3.6
Explanation: Speed = 121 * 5/18 = 33.6 m/sec
Time taken = 120/33.6
= 3.6 sec.
Answer: D
Question: Average of money that group of 4 friends pay for rent each month is $800.After one persons rent is increased by 20% the new mean is $870.What was original rent of friend whose rent is increased?
A.800
B.1400
C.1000
D.1100
Answer: B.1400
Explanation: 0.2X = 4(870-800)
0.2X = 280
X = 1400
Answer B
Question: Find the 25% of Rs. 800.
A.s. 50
B.s. 200
C.s. 100
D.s. 80
Answer: B.s. 200
Explanation: Explanation :
25% of 800
=> 25/100 *800 = Rs. 200
Answer : B
Question: Find out the square of a number which when doubled exceeds its quarter by 7 ?
A.16
B.25
C.19
D.26
Answer: A.16
Explanation: A
Let the number be p, then the square will be p^2
According to question:
2p = (p/4) + 7
=> 8p = p + 28
=> p = 4
p^2 = 4^2 = 16.
Question: In order to fence a square Manish fixed 48 poles. If the distance between two poles, is 6 metres then what will be the area of the square so formed?
A.Cannot be determined
B.2600 cm2
C.5184 cm2
D.3025 cm2
Answer: C.5184 cm2
Explanation: Let the side of the square be x m.
∴ Perimeter of the square = 48 × 6 = 4x ∴ x = 72 m
∴ Area = (72)2 = 5184 m2
Answer C
Question: A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 5:4. The ratio of economy cars to sport utility vehicles is 3:2. What is the ratio of luxury cars to sport utility vehicles?
A.9:8
B.8:9
C.6:5
D.2:3
Answer: C.6:5
Explanation: The ratio of economy to luxury cars is 5:4 --> E:L = 5:4 = 15:12.
The ratio of economy cars to sport utility vehicles is 3:2 --> E:S = 3:2 = 15:10.
Thus, L:S = 12:10 = 6:5.
Answer: C.
Question: A machine can finish a work in 15days and 2nd machine can finish the work in 30days. 2nd machine worked for 10days and left the job. In how many days, A alone can finish the remaining work?
A.5days
B.6days
C.10days
D.12days
Answer: C.10days
Explanation: 2nd machine 10days work = 1/30*10 = 1/3
Remaining work = 1 - 1/3 = 2/3
now 1/15 work is done by 1st machine in 1day
2/3 work is done by 1 machine in 15*2/3 = 10days.
Answer is C
Question: If each interior angle of a regular polygon is 144o, the it is
A.Octagon
B.Decagon
C.Dodecagon
D.Pentagon
Answer: C.Dodecagon
Explanation: Decagon, then each ext angle = 180-44=36 deg .
sum of all ext angles = 360 deg .
Then total ext angles = 360/36 =10 means 10 sides of polygon.
ANSWER:C
Question: The average age of a group of 5 members is 20 years. Two years later, a new member joins the group. The average age of the group becomes 21 years. What is the age of the new member ?
A.16 years
B.21 years
C.22 years
D.23 years
Answer: A.16 years
Explanation: The average age of the 5 members is 20 years
=> The sum of the ages of the 5 members is 20*5 = 100 years
Once the new member joins, the average age becomes 21 years.
Let the age of the new member be x.
Then (110+x)/6 = 21
=> x = 16 years
Answer A
Question: A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen?
A.1
B.2
C.4
D.3
Answer: D.3
Explanation: 40*(40/100) = 16 --- 64
? --- 12 => Rs.3
Answer: D
Question: If x is an integer, then x(x - 1)(x - k) must be evenly divisible by three when k is any of the following values except
A.-4
B.-8
C.-1
D.2
Answer: B.-8
Explanation: if we put k=-1 we get:
X(x-1)(X+1) rearrange:(x-1)X(X+1)
so it looks like a sequenc,
if we assume that X =2 and put number from the answer then we get:
(x – 1)x(x – k)
k=5 =1.2.-3
k=2 =1.2.0
k=-1 =1.2.3
k=-4 =1.2.6
but when we put
k=-8 =1.2.10 not satisfied
so,the answer is B
Question: The LCM of three numbers is four times their GCF. Which of the following must be true of the numbers?
I. At least o ne of the numbers is odd.
II. Two of the three numbers must be same.
III. At least one number is the same as GCF.
A.only
B.option II only
C.and III only
D.and II only
Answer: B.option II only
Explanation: Consider the following set: {2, 4, 8}.
GCF = 2.
LCM = 8 = 4*2.
The set discards options I and II. Only B fits.
Answer: B.
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
A.140
B.99
C.88
D.72
Answer: A.140
Explanation: Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10 = 140 sq.units
Answer: A
Question: Mr. loyd wants to fence his Square shaped land of 120Sqft each side.If a pole is laid every 10ft how many poles do he need?
A.20
B.30
C.48
D.50
Answer: C.48
Explanation: If each side is 120 feet..then total perimeter is 120*4=480
poles every 10 feet hence no of poles= 480/10=48
ANSWER:C
Question: A sum of money deposited at compound interest (compounded yearly) amounts to $4200 in 2 years and to $4494 in 3 years. What is the interest rate?
A.3%
B.5%
C.7%
D.9%
Answer: C.7%
Explanation: 4494 - 4200 = 294
294 / 4200 = 0.07 = 7%
The answer is C.
Question: The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 675 sq m, then what is the breadth of the rectangular plot?
A.11
B.15
C.18
D.101
Answer: B.15
Explanation: Let the breadth of the plot be b m.
Length of the plot = 3 b m
(3b)(b) = 675
3b2 = 675
b2 = 225 = 15 (b > 0)
b = 15 m.
Answer: B
Question: 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning?
A.4402
B.4418
C.4400
D.4418
Answer: C.4400
Explanation: X * (95/100) * (85/100) = 3553
X = 4400
Answer: C
Question: Two airplanes take off from one airfield at noon. One flies due east at 201 miles per hour while the other flies directly northeast at 283 miles per hour. Approximately how many miles apart are the airplanes at 2 p.m.?
A.166
B.332
C.400
D.402
Answer: D.402
Explanation: D
In two hours:
the plane flying East will be 402 miles away from airport.
the other plane will be 566 miles away from airport.
566/402 = ~1.4 = ~sqrt(2)
This means that planes formed a right isocheles triangle => sides of such triangles relate as 1:1:sqrt(2) => the planes are 402 miles apart. D
Question: A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 950gm. for a kg.His gain is …%.
A.5.26%
B.5.36%
C.4.26%
D.6.26%
Answer: A.5.26%
Explanation: His percentage gain is 100*50/950 as he is gaining 50 units for his purchase of 950 units.
so 5.26%.
ANSWER:A
Question: A man can swim in still water at 4 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
A.1.3
B.7.5
C.2.25
D.1.5
Answer: A.1.3
Explanation: M = 4
S = x
DS = 4 + x
US = 4 - x
4 + x = (4 - x)2
4 + x = 8 -2x
3x = 4
x = 1.3
ANSWER:A
Question: A train speeds past a pole in 15 seconds and a plaƞorm 100 meter long in 25 seconds. What is length
of the train ?
A.140 meter
B.145 meter
C.150 meter
D.155 meter
Answer: C.150 meter
Explanation: Explanation:
Let the length of the train is x meter and Speed of the train is y meter/second
Then x/y = 15 [because distance/speed = Ɵme]
=> y = 15/x
=>x+10025=x15x=150 meters
So length of the train is 150 meters
Answer: C