RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A man has some hens and cows. If the number of heads be 42 and the number of feet equals 124, then the number of hens will be
A.22
B.24
C.26
D.20
Answer: A.22
Explanation: Explanation :
Let number of hens = h and number of cows = c
number of heads = 42
=> h + c = 42 ---(Equation 1)
number of feet = 124
=> 2h + 4c = 124
=> h + 2c = 62 ---(Equation 2)
(Equation 2) - (Equation 1) gives
2c - c = 62 - 42
=> c = 20
Substituting the value of c in Equation 1, we get
h + 22 = 42
=> h = 42 - 20 = 22
i.e., number of hens = 22
Answer : A
Question: How much more would Rs.20000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly?
A.482
B.197
C.267
D.216
Answer: A.482
Explanation: 20000(11/10)4 - 20000(6/5)2
= 482
Answer:A
Question: The first three terms of an infinite sequence are 2, 7, and 22. After the first term, each consecutive term can be obtained by multiplying the previous term by 3 and then adding 1. What is the sum of the tens digit and the units digit of the 15th term in the sequence?
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: Following the rule of Infinite sequence we obtain the terms of the sequence as mentioned below
02,07,22,67, 202, 607, 1822, 5467...
Observe the last two digits of the sequence which have the cyclicity of4and the last two digits repeat in the order {02, 07, 22, 67}
Also 15th Term =4*3 +3
i.e. 15th Terms will have same Last two digits as 3rd term of the sequence = 22
i.e. Sum of lat two digits of 15th Term = 2+2 = 4
A
Question: 1000 men have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now?
A.12.9
B.12.5
C.12.6
D.12.2
Answer: C.12.6
Explanation: 1000*15 = 1200*x
x = 12.5
Answer: C
Question: A sock drawer contains four socks, each one a different solid color. The colors of the socks are red, orange, indigo, and violet. If a person reaches into the drawer and pulls out two socks, how many different color combinations are possible in the selected pair of socks?
A.12
B.15
C.6
D.36
Answer: C.6
Explanation: Since here order of socks is not important then we'll have 4C2 i.e. 6 combinations.
Answer : C
Question: A cylindrical can has a radius of 4 centimeters and a height of 18 centimeters. What is the area, in square centimeters, of a rectangular label that completely covers the curved surface of the can without over-lapping?
A.16 pi
B.64 pi
C.96 pi
D.144 pi
Answer: D.144 pi
Explanation: They are asking the lateral surface area of the cylinder.
the Lateral surface area = 2* pi * r *h
= 2*pi*4*18=144 pi
Answer is D.
Question: Robert's salary was increased by 50% and subsequently decreased by 10%. how much percentage does he gain?
A.15%
B.20%
C.10%
D.25%
Answer: A.15%
Explanation: let original salary be $100
increased salary = 10% of (150% of $100) = (10/100)*(150/100)*100 = $15
increase = 15%
correct option is A
Question: Find the average of all prime numbers between 40 and 80.
A.59.4
B.56
C.39.8
D.44.9
Answer: A.59.4
Explanation: Sol.
There are five prime numbers between 40 and 80.
They are 41, 43, 47, 53, 59, 61, 67, 71, 73, 79
âˆ´ Required average = [41+ 43+ 47+ 53+ 59+ 61+67+ 71+73+ 79 / 10] = 594/ 10 = 59.4
Answer A
Question: One fourth of a solution that was 13% salt by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent salt by weight?
A.25%
B.34%
C.22%
D.18%
Answer: A.25%
Explanation: consider total solution to be 100 liters and in this case you'll have: 75*0.13+25*x=100*0.16 --> x=0.25.
Answer: A.
Question: Find the smallest number of five digits exactly divisible by 24,48,64 and 88.
A.11952
B.11852
C.11752
D.11652
Answer: A.11952
Explanation: Smallest number of five digits is 10000.
Required number must be divisible by L.C.M. of 24,48,64,88 i.e 2012,
On dividing 10000 by 2012,we get 60 as remainder.
Therefore, Required number = 10000 +( 2012 â€“ 60 ) = 11952.
Answer is A.
Question: A student travels from his house to school at 10 km/hr and reaches school 2 hours late. The next day he travels 18 km/hr and reaches school 1 hour early. What is the distance between his house and the school?
A.65.0
B.67.5
C.70.0
D.72.5
Answer: B.67.5
Explanation: Let x be the distance from his house to the school.
x/10 = x/18 + 3
9x = 5x + 270
4x = 270
x = 67.5 km
The answer is B.
Question: Dan’s car gets 32 miles per gallon. If gas costs $4/gallon, then how many miles can Dan’s car go on $38 of gas?
A.212
B.256
C.304
D.372
Answer: C.304
Explanation: 38/4 = 9.5 gallons
9.5*32 = 304 miles
The answer is C.
Question: Arjun sold an ipod for Rs 17,940 with a discount of 8% and gained 19.6%. If no discount is allowed, then what will be his gain per cent?
A.30%
B.26.4%
C.24.8%
D.25.8%
Answer: A.30%
Explanation: S.P = Rs 17,940
Discount = 8%
Market price = (17940 x 100)/ (100 - 8)
Rs 19,500
Gain = 19.6%
C.P = 17940 x 100/100 + 19.6 = Rs 15,000
If no discount is allowed on the Market price then S.P = Rs 19,500
Therefore, Gain % = (4500/15000 ) x 100 = 30 %
ANSWER:A
Question: How many seconds will a 600 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.20
B.30
C.36
D.50
Answer: C.36
Explanation: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 600 * 3/50 = 36 sec.
Answer: Option C
Question: If X,Y is 25%,35% smaller than Z then how much percentage is Y greater than X?
A.13 1/2%
B.13 1/4%
C.13 1/3%
D.12 1/2%
Answer: C.13 1/3%
Explanation: Explanation:
X = 75 %
Y = 65 %
Z = 100 %
X-Y/X * 100 = 10/75 * 100 = 13 1/3 % greater than X
Answer: Option C
Question: A bike traveled 127 miles in 5 hours 11 minutes. What was the average speed of the bike in miles per hour?
A.24.50 miles / hour
B.25.6 miles / hour
C.25.9 miles / hour
D.29.1 miles / hour
Answer: A.24.50 miles / hour
Explanation: We first convert the time of 5 hours 11 minutes in minutes
5 hours 11 minutes = 5* 60 + 11 =311 minutes
Average speed S is given by distance / time. Hence
S = 127 miles / 311 minutes = 0.408 mile / minute
= 24.50 miles / hour
correct answer A
Question: If m,s,and t are positive real numbers such that m(s+t) = 152, s(t+m) =162 , and t(m+s) = 170, then mst is
A.a) 672
B.b) 688
C.c) 704
D.d) 720
Answer: D.d) 720
Explanation: ms+mt = 152 --------------------------------------1)
st+sm = 162---------------------------------------2)
mt+ts = 170---------------------------------------3)
Re-writing equation 3 as follows:
mt+ts = 162 + 8
mt+ts = st+sm + 8
mt = sm + 8 ............... (4)
Adding (1)(4)
2mt = 160
mt = 80
mst has to be multiple of 80, only 720 fits in
Answer = D
Question: Bert left the house with N dollars. He spent 1/4 of this at the hardware store, then $9 at the dry cleaners, and then half of what was left at the grocery store. When he got home, he had $15 left in his pocket. What was the value of N?
A.$36
B.$44
C.$52
D.$60
Answer: C.$52
Explanation: started to test answer C
if he had 52, then he spent 13 at hardware store
now he was left with 39$
he spent 9 dollars on cleaning, thus he remained with 30$
he then spent 1/2 of 30, or 15, and was left with 15.
hence, the only option that can be right is C.
Question: 6+2=42
4+9=48
8+2=72
3+7=27
1+4=??
Solve it?
A.9
B.3
C.42
D.4
Answer: D.4
Explanation: x+y=x[y+(x-1)]=x^2+xy-x
6+2=6[2+(6-1)]=36+12-6=42
4+9=4[9+(4-1)]=16+36-4=48
8+2=8[2+(8-1)]=64+16-8=72
3+7=3[7+(3-1)]=9+21-3=27
1+4=1[4+(4-1)]=1+4-1=4
Answer :D
Question: 4/6 of the population of the country of Venezia lives in Montague Province, while the rest lives in Capulet Province. In the upcoming election, 80% of Montague residents support Romeo, while 70% of Capulet residents support Juliet; each resident of Venezia supports exactly one of these two candidates. Rounded if necessary to the nearest percent, the probability that a Juliet supporter chosen at random resides in Capulet is
A.28%
B.41%
C.45%
D.64%
Answer: D.64%
Explanation: Total population = 60 (assume).
4/6*60=40 people from Montague.
2/6*60=20 people from Capulet.
0.2*40=8 people from Montague support Juliet.
0.7*20=14 people from Capulet support Juliet.
The probability that a Juliet supporter chosen at random resides in Capulet is 14/(8+14)=~64.
Answer: D
Question: find value for x from below equation? x + 1 = 2
A.-5
B.1
C.4
D.3
Answer: B.1
Explanation: 1. Subtract 1 from both sides:
x + 1 - 1 = 2 - 1
2. Simplify both sides:
x = 1
B
Question: Randy can rebuild an automobile engine in b hours. Alvin can rebuild the same engine in a hours. If Randy and Alvin work together at their respective rates to rebuild the engine, which of the following represents the portion of the job that Alvin will have to complete?
A.ab/(a+b)
B.(b)/(a+b)
C.b/(b-a)
D.a/(a+b)
Answer: B.(b)/(a+b)
Explanation: Randy can do the job in a hrs, Alvin can do the job in b hrs.
When they work together, you need to find the fraction of work that Randy doesn't need to do i.e. the fraction that will be done by Alvin.
Ratio of Randy's speed:Alvin's speed = b:a (since time taken by them is in the ratio a:b)
So Alvin does b/(a+b) of the work
Answer (B).
Question: A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that exactly three bulbs are good?
A.20/68
B.20/63
C.20/29
D.20/20
Answer: B.20/63
Explanation: Required probability
= (⁵C₃ . ⁴C₁)/⁹C₄
= (10 * 4)/126 = 20/63
Answer:B
Question: 8900 ÷ 6 ÷ 4 = ?
A.349
B.541.75
C.224.37
D.370.833
Answer: D.370.833
Explanation: Explanation:
Given Exp. 8900 * 1/6 * 1/4
= 370.833
ANSWER: D
Question: On retirement, a person gets 1.53 lakhs of his provident fund which he invests in a scheme at 20% p.a. His monthly income from this scheme will be
A.2,450
B.2,500
C.2,550
D.2,600
Answer: B.2,500
Explanation: Let S.I. = x
= 1.53×10(5)×20/100
= 2,500
Answer B
Question: Three runners Q, B and C run a race, with runner A finishing 12m ahead of runner B and 18m ahead of runner C, while runner B finishes 8m ahead of runner C. Each runner travels entire distance at a constant speed. What was the length of the race?
A.36m
B.48m
C.60m
D.72m
Answer: B.48m
Explanation: Let distance of race be x mtrs. Then when Q finishes x m , B has run (x- 12)mtrs and C has run x-18 mtrs. so at this point B is 6 m ahead of C. Now to finish race b needs to run another 12 m, so he runs another 12 m. when B finishes race he is 8 m ahead of C. so last 12 m B has run, C has run 10 m.
as speeds are constant, we have equation,
x-12/ x-18 = 12/10 > x = 48.
Answer B
Question: In racing over a given distance d at uniform speed, A can beat B by 10 meters, B can beat C by 4 meters, and A can beat C by 12 meters. What is the distance d in meters?
A.16
B.20
C.30
D.40
Answer: B.20
Explanation: When A is at the finish line, B is 10 meters back, and C is 12 meters back.
When B runs another 10 meters to the finish line, C is 4 meters back.
So B gains 2 meters every 10 meters covered.
To gain a final difference of 4 meters, B runs a total of 20 meters.
The answer is B.
Question: If a=2/3b , b=2/3c, and c=2/3d what part of d is b/
A.8/27
B.4/9
C.2/3
D.7/8
Answer: B.4/9
Explanation: now put c=2/3d in b=2/3c
so b=2/3*2/3d
b=4/9d
ANSWER:B
Question: I. j; k; m; n; p
II. j - 10; m; m; m; p + 15
III. j + 2; k + 1; m; n - 1; p - 2
If j, k, m, n, and p are consecutive positive integers such that j < k < m < n < p, the data sets I, II, and III above are ordered from greatest standard deviation D to least standard deviation in which of the following?
A. I, III, II
B. II, I, III
C. II, III, I
D. III, I, II
Answer: B. II, I, III
Explanation: Range of 1st Set = (p-j)
Range of 2nd Set = P+15 - j +10 = (p-j) +25
Range of 3rd Set = P -2 - j - 2 = (p-j) - 4
R2 > R1 > R3 ==> SD2 > SD1 > SD3
Since,D= Higher the Range -> More Dispersion in the Set -> More Standard Deviation.B
Question: The ages of 2 persons differ by 32 years. If 9 years ago the elder one be 5 times as old as the younger one, find the present age of elder person.
A.30
B.42.5
C.45
D.49
Answer: D.49
Explanation: age of the younger person = x
age of the elder person = x+32
5(x-9) = x+32-9
x= 17
age of elder person =17+32=49
Answer is D
Question: Albert and Bob are painting rooms at constant, but different rates. Albert takes 1 hour longer than Bob to paint n rooms. Working side by side, they can paint a total of 3n/7 rooms in 4/3 hours. How many hours would it take Albert to paint 3n rooms by himself?
A.7
B.21
C.11
D.D.13
Answer: B.21
Explanation: rate of bob to paint n rooms is n/T(bob)
rate of Albert to paint n rooms is n/T(albert).
albert paints the room 1 hour slower than bob, so T (albert) = T(bob) -1
Together they paint the 3n/5 rooms in 4/3 hours. Rate is equal to work over time
Therefore
n/x + n/x-1 = (3n/5)/(4/3) =
n/x + n/x-1 = 9n/20. Fastest way for me is to think how would make the denominator 20. 4*5 = 20 and it fits x and x-1 or you can solve the quadratic
4n/20 + 5n/20 = 9n/20. Therefore you know it takes Albert 5 hours to paint n room, since Albert's rate is n/5.
7*3 = 3n
21 = 3n.
Answer is B
Question: In a certain supermarket, a triangular display of cans is arranged in 10 rows, numbered 1 through 10 from top to bottom. Each successively numbered row contains 3 more cans than the row immediately above it. If there are fewer than 150 cans in the entire display, how many cans are in the seventh row?
A.13
B.15
C.17
D.19
Answer: D.19
Explanation: Let x be the number of cans in row 1.
The total number of cans is x + (x+3) + ... + (x+27) =
10x + 3(1+2+...+9) =
10x + 3(9)(10)/2 =
10x + 135
Since the total is less than 150, x must equal 1.
The number of cans in the 7th row is 1 + 3(6) = 19
The answer is D.
Question: Average of 13 results is 65. If the average of first six results is 61 and average of last six results is 59 Then find the seventh result?
A.118
B.120
C.125
D.130
Answer: C.125
Explanation: 125
Option 'C'
Question: Four bells ring at an interval of 4, 8, 6, 10 minutes. If they toll together at 2:00 A.M, when will they toll together again?
A.4 am
B.5 am
C.6 am
D.7 am
Answer: A.4 am
Explanation: l.c.m of 4,8,6,10 is 120 min i.e 2 hours
so ans is 2 am + 2=4 am
ANSWER:A
Question: The no. of gift pack bought by Dexter is 1 more than the price, in rupees, of each gift pack. The amount of Rs.380 which Dexter had, fell short of the required amount. What is theamount by which he might have fallen short.
A.38
B.40
C.45
D.48
Answer: B.40
Explanation: Let the price of gift pack be 'aa'
Then number of packs bought =a+1=a+1
Hence total cost is a(a+1)a(a+1)
It is given that 380<a(a+1)380<a(a+1)
If a=19a=19, the total cost =19×20=380=19×20=380
Dexter would not have fallen short, If:
a=20a=20, a(a+1)=420a(a+1)=420
So he would have fallen short by Rs 40.
This is the minimum amount by which he may have fallen short.
B)
Question: A reduction of 20% in the price of salt enables a lady to obtain 4 kgs more for Rs.100, find the original price per kg?
A.6.16
B.6.21
C.6.25
D.2.4
Answer: C.6.25
Explanation: 100*(20/100) = 20 --- 4
? --- 1 => Rs.5
100 --- 80
? --- 5 => Rs.6.25
Answer: C
Question: A rectangular window is twice as long as it is wide. If its perimeter is 12 feet, then what are its dimensions in feet?
A.2 by 4
B.5/3 by 10/3
C.2.5 by 5
D.3 by 6
Answer: A.2 by 4
Explanation: Let x be the width of the window. Then the length is 2x.
x+2x+x+2x = 12
6x = 12
x = 2
The width is 2 and the length is 4.
The answer is A.
Question: 99^n is such a number begin with 8, least value of n?
A.11
B.10
C.9
D.8
Answer: A.11
Explanation: 99^1=9801
99^2=971299
99^3=96157601
like this......
take only first two digit for n=1 99
n=2 98
n=3 97
n=4 96
......................................................
n=10 90
n=11 89
so for n=11 number start with 8
ANSWER:A
Question: If u clothes can be purchased for v dollars, how many clothes can be purchased for z dollars?
A.u/z
B.z/uv
C.uv/z
D.uz/v
Answer: D.uz/v
Explanation: Ans = D
Question: The area of a triangle is with base 4m and height 5m?
A.65 m2
B.10 m2
C.70 m2
D.90 m2
Answer: B.10 m2
Explanation: 1/2 * 4 * 5
= 10 m2
Answer:B
Question: The sale price shirts listed for Rs.400 after successive discount is 10% and 5% is?
A.280
B.290
C.342
D.250
Answer: C.342
Explanation: 400*(90/100)*(95/100) = 342
C
Question: Two pipes can fill a cistern in 14 and 16 hours respectively. The pipes are opened simultaneously and it is found that due to leakage in the bottom, 32 minutes extra are taken for the cistern to be filled up. If the cistern is full, in what time would the leak empty it ?
A.110 hours
B.112 hours
C.115 hours
D.100 hours
Answer: B.112 hours
Explanation: Cistern filled by both pipes in one hour
= 1⁄14 + 1⁄16 = 15⁄112th
∴ Both pipes filled the cistern in 112⁄15 hrs.
Now, due to leakage both pipes filled the cistern in
112⁄15 + 32⁄60 = 8 hrs.
∴ due to leakage, filled part in one hour 1⁄8
∴ part of cistern emptied, due to leakage in one hour
= 15⁄112 - 1⁄8 = 1⁄112th
∴ in 112 hr, the leakage would empty the cistern.
Answer B
Question: In how many ways can Ram choose a vowel and a constant from the letters of the word ALLAHABAD?
A.4
B.6
C.9
D.5
Answer: A.4
Explanation: Solution
In the letters of the word ALLAHABAD there is only 1 vowel available for selection (A). Note that the fact that A is available 4 times has no impact on this fact.
Also, there are 4 consonants available – viz. L, H, Band D. Thus, the number of ways of selecting a vowel and a consonant would be 1 × 4C1 = 4.
Answer A
Question: The ratio of the areas of a square and rhombus whose base is same is:
A.1:2
B.2:1
C.1:1
D.3:1
Answer: C.1:1
Explanation: SOLUTION :
The square and the rhombus are equal in area if they have a common base.
ANSWER IS C
Question: A sporting good store sells one type of baseball bat and one type of baseball. The cost for 2 bats and 4 balls is $200. The cost for 1 bat and 6 balls is $220, as well. If someone were to buy an equal number of bats and balls, at most how many bats can he purchase if he has a budget of $210 for the purchase?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: IMO it should be C that is 3
reason:
formed an equation... bat = b ball = c
2b+4c=200
1b+6c=220
solving both we get b that is bat = 40 and c that is ball = 30
new equation 210 to be divided in equal
3b+3c=210
3*40 + 3*30 = 210
120 + 90 = 210
Question: If the perimeter of square region W and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3 then the ratio of the area of R to the area of W
A.25:16
B.24:25
C.5:6
D.4:5
Answer: B.24:25
Explanation: We know Perimeter of a square (Pw) = 4*side
Perimeter of a rectangle (Pr) = 2(length+breath)
Let us assume 40 to be the perimeter of the square (since we know each side of a square is equal and the perimeter is divisible by 4, also take in to account the length and breadth of the rectangle is in the ration 2k:3k = 5k; we can assume such a number)
Therefore,
Pw = Pr = 40
Area of the square = 100 sq. units
We know 2(length+breadth) = 40
i.e. length + breadth = 20 (or 5k = 20 given that l:b (or b:l) = 2:3)
Therefore length = 8, breath = 12
Area of the rectangle = 8*12 = 96 sq. units
Question asked = Area of the rectangle : Area of the square = 96:100 ==> 24:25=B
Question: If x and y are numbers such that (x+4)(y-4)=0, what is the smallest possible value of x^2 + y^2
A.0
B.9
C.12
D.16
Answer: D.16
Explanation: From (x+4)(y-4)=0 it follows that either x=-4 or y=4. Thus either x^2=16 or y^2=16.
Now, if x^2=16, then the least value of y^2 is 0, so the least value of x^2 + y^2 = 16 + 0 = 16.
Similarly if y^2=16, then the least value of x^2 is 0, so the least value of x^2 + y^2 = 0 + 16 = 16.
Answer: D.
Question: 24 people are there, they are shaking hands together, how many hand shakes possible, if they are in pair of cyclic sequence.
A.24
B.23
C.44
D.45
Answer: A.24
Explanation: n for cyclic hand shake and n-1 for linear handshake.
so here no of hand shake is 24.
ANSWER:A
Question: In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?
A.30
B.20
C.40
D.57
Answer: A.30
Explanation: A
30
There is a meal for 200 children.
150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children 120 men.
50 children = (120/200)x 50 = 30 men.
Question: In a 6 digit ID number, what is the probability of exactly four digits are the digit 0?
A.9/2000
B.81/20000
C.12/36001
D.81/16000
Answer: B.81/20000
Explanation: Total number of 6 digit numbers = 9*10*10*10*10*10 = 9,00,000
No. of ways of arranging 4 digits as 0 = 5C4=5.
Arrangements are as follows. Here X can be any digit other than 0
1) XX000X ==> no. of ways - 729
2) XXX000 ==> no. of ways - 729
3) X0XX00 ==> no. of ways - 729
4) XX00X0 ==> no. of ways - 729
5) X00XX0 ==> no. of ways - 729
Probability = (729*5)/90000
=81/20000
Ans - B
Question: A, B, C, D, E, F are the only six families in Indira Nagar. A, B, C, D, E and F has 7, 8, 10, 13, 6, and 10 member in their families respectively. If 1 member from all the six families left their respective families to accommodate themselves in the hostel of IIM Lucknow, then the average number of member now in each family of Indira nagar is
A.8
B.9
C.10
D.13
Answer: A.8
Explanation: Answer
Required average
= (( 7 - 1 ) + ( 8 - 1 ) + ( 10 - 1 ) + ( 13 - 1 ) + (6 - 1) +( 10 - 1 ) )/ 6
= ( 7 + 8 +10 + 13 + 6 + 10 ) / 6 - ( 6 x 1 ) / 6
=9 - 1 = 8
Correct Option: A
Question: Two taps can fill a tank in 12 and 18 minutes respectively. Both are kept open for 2 minutes and the first is turned off. In how many minutes more will the tank be filled ?
A.15 min.
B.20 min.
C.11 min.
D.13 min.
Answer: D.13 min.
Explanation: Part filled by first tap in one min = 1⁄12th
Part filled by second tap in one min = 1⁄18th
Now, 2[1⁄12 + 1⁄18] + unfilled part = 1
⇒ unfilled part = 13⁄18th
∵ 1⁄18th part of tank is filled by second tap in 1 min.
∴ 13⁄18th part of tank is filled by second tap in 1 min.
= 18 × 13⁄18 min = 13 min.
Answer D
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is?
A.176 m
B.198 m
C.197 m
D.150 m
Answer: D.150 m
Explanation: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15
=> y = x/15
x + 100 / 25
= x / 15
x = 150 m.
Answer:D
Question: The quantities S and T are positive and are related by the equation S=K/T, where k is a constant. If the value of S increases by 40 percent, then the value of T decreases by what percent?
A.25%
B.33 ¹/₃%
C.50%
D.66 ²/₃%
Answer: B.33 ¹/₃%
Explanation: We can assign numbers:
lets say S = 2, K = 6 (constant) and T = 3 (so that S=K/T)
Now increasing S by 40% gives S=3, K remains constant, so T = 2 (6/2=3)
decrease in T= 1, percent decrease in T = (1/3)*100 = 33.33%
Answer B
Question: If 10 litres of an oil of Rs.55 per litres be mixed with 5 litres of another oil of Rs.66 per litre then what is the rate of mixed oil per litre?
A.Rs.49.17
B.Rs.51.03
C.Rs.58.66
D.Rs.55.33
Answer: C.Rs.58.66
Explanation: 55*10 = 550
66*5 = 330
880/15 = 58.66
ANSWER:C
Question: There is a sequence An for a positive integer n such that when An-2 is divided by An-1 the remainder is An. If A3=6, A4=0, which of the following can be the value of A1?
A.48
B.50
C.52
D.56
Answer: A.48
Explanation: When A1/A2, Remainder = A3 = 6 --> A1 = xA2 + 6
When A2/A3, Remainder = A4 = 0 --> A2 = yA3
A1 = xyA3 + 6 = kA3 + 6 = 6(k + 1) --> A1 must be a multiple of 6
Only option A is a multiple of 6
Answer: A
Question: In a colony of 70 residents, the ratio of the number of men and women is 5: 2. Among the women, the ratio of the educated to the uneducated is 1 : 4. If the ratio of the number of educated to uneducated persons is 8 : 27, then find the ratio of the number of educated to uneducated men in the colony?
A.A)1:5
B.B)1:1
C.C)1:8
D.D)1:9
Answer: A.A)1:5
Explanation: Number of men in the colony = 5/7 * 70 = 50.
Number of women in the colony = 2/7 * 70 = 20.
Number educated women in the colony = 1/5 * 30 = 6.
Number of uneducated women in the colony = 4/5 * 50 = 24.
Number of educated persons in the colony = 8 /35 * 70 = 16.
As 6 females are educated, remaining 10 educated persons must be men.
Number of uneducated men in the colony = 50 - 10 = 40.
Number of educated men and uneducated men are in the ratio 10 : 40 i.e., 1:4.
Answer:A