RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: An investment E gained an interest payment of $250 each month when the annual interest rate was 8%, how much more should we invest annually if we want to gain 12% more per month with a new annual interest rate of 7.5% ?
A.$9,360
B.$9,100
C.$8,250
D.$7,300
Answer: D.$7,300
Explanation: Answer is D : 7,300
An investment E gained an interest payment of $250 each month when the annual interest rate was 8%,Interest per annum with 8% interest rate is = 250* 12 = Principal * Interest Rate(8/100)
This gives Principal as 37,500$
For an revised interest of 12% more and new interest rate of 7.5% , ie. 250* 12 * 1.12 = Principal * Interest Rate (7.5/100)
This gives the new Principal as 44,800.
The question is how much more should we invest, so 44,800 - 37,500 = 7,300.D
Question: A is a working partner and B is a sleeping partner in a business. A puts in 50,000 and B 60,000. A gets 12.5% of the profit for managing the business, and the rest is divided in proportion to their capitals. Find the share of A in profit of 8800.
A.3500
B.4600
C.5400
D.4800
Answer: B.4600
Explanation: The amount A gets for managing
= 12.5% of Rs. 8800 = 1100
Remaining profit = 8800 – 1100 = 7700
This is to be divided in the ratio 5 : 6.
Share of A = 5/11 of 7700 = 3500
⇒ Total share of A = 3500 + 1100 = 4600.
Answer B
Question: If it takes 12 identical printing presses exactly 5 hours to print 12,000 newspapers, how long would it take 6 of these presses to print 8,000 newspapers?
A.6 hrs 40 mins
B.6 hrs 50 mins
C.6 hrs 30 mins
D.5 hrs 40 mins
Answer: A.6 hrs 40 mins
Explanation: 12 presses - 12,000 newspapers - 5 hours ;
6 presses - 6,000 newspapers - 5 hours ; (300 mins)
6 presses - 8,000 newspapers - 300/6000*8000 = 400 mins = 6 hrs 40 mins
Answer : A
Question: The volumes of two cones are in the ratio 1 : 20 and the radii of the cones are in the ratio of 1 : 2. What is the ratio of their heights?
A.A)2:5
B.B)2:7
C.C)1:5
D.D)2:1
Answer: C.C)1:5
Explanation: The volume of the cone = (1/3)πr2h
Only radius (r) and height (h) are varying.
Hence, (1/3)π may be ignored.
V1/V2 = r12h1/r22h2 => 1/20 = (1)2h1/(2)2h2
=> h1/h2 = 1/5
i.e. h1 : h2 = 1 : 5
Answer: C
Question: A man swims downstream 30 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water?
A.7
B.8
C.9
D.4
Answer: B.8
Explanation: 30 --- 3 DS = 10
? ---- 1
18 ---- 3 US = 6
? ---- 1 M = ?
M = (10 + 6)/2
= 8
Answer: B
Question: A certain junior class has 100 students and a certain senior class has 80 students. Among these students, there are 6 siblings pairs each consisting of 1 junior and 1 senior. If 1 student is to be selected at random from each class, what is the probability that the 2 students selected will be a sibling pair?
A.3/40000
B.1/3600
C.9/2000
D.3/4000
Answer: D.3/4000
Explanation: Let's see
Pick 6/100 first
Then we can only pick 1 other pair from the 800
So total will be 6 / 80 *100
Simplify and you get 3/4000
Answer is D
Question: A train sets off at 2 p.m. at the speed of 50 kmph. Another train starts at 3:30 p.m. in the same direction at the rate of 75 kmph. At what time the trains will meet?
A.6.37 p.m
B.6.20 p.m
C.6.30 p.m
D.6.38 p.m
Answer: C.6.30 p.m
Explanation: D = 50 * 1 Â½ = 75 km
RS = 75 â€“ 50 = 25
T = 75/25 = 3 h
3.30 + 3 h = 6.30 p.m.
Answer: C
Question: In a recent election, Geoff received 0.5 percent of the 6,000 votes cast. To win the election, a candidate needed to receive more than x% of the vote. If Geoff needed exactly 3,000 more votes to win the election, what is the value of x ?
A. 50
B. 50.5
C. 56
D. 60
Answer: B. 50.5
Explanation: Word problems are tricky in somehow more than other problem because you have the additional step to translate.
Breaking the problem: Geoff how many votes he receives ?? 30 votes
he needs 3571 more votes so : 30+3000= 3030
Now what's the problem wants ?? a x %........3030 is what % of total votes 6000........translating: 3030= x/100 * 6000 ---
x= 50.5 %..........B
Question: In a class of 32 students, 2 students did not borrow any books from the library, 12 students each borrowed 1 book, 10 students each borrowed 2 books, and the rest borrowed at least 3 books. If the average number of books per student was 2, what is the maximum number of books any single student could have borrowed?
A.3
B.5
C.8
D.11
Answer: D.11
Explanation: Total # of students = 32
Avg # of books per student = 2
Total # of books = 32*2 = 64
# of student borrowed at least 3 books = 32-2-12-10 = 8
# of books borrowed by above 8 students = 60-(12*1)+(10*2) = 32
Considering that 7 out of above 8 students borrowed only 3 books, # of books borrowed = 7*3 = 21
So maximum # of books borrowed by any single student = 32 -21 =11
option D
Question: A and B invest in a business in the ratio 3 : 2. If 5% of the total profit goes to charity and A's share is Rs. 855, the total profit is:
A.Rs. 1425
B.Rs. 1500
C.Rs. 1537.50
D.Rs. 1576
Answer: B.Rs. 1500
Explanation: Explanation:
Let the total profit be Rs. 100.
After paying to charity, A's share = Rs.(95 X 3/5)=Rs. 57
If A's share is Rs. 57, total profit = Rs. 100.
If A's share Rs. 855, total profit =(100/57 X 855)=1500.
ANSWER IS B
Question: When tossed, a certain six-sided die has an equal probability of landing on any of the six sides. If the die is tossed 2 times, what is the probability that it will land on the same side each time?
A.1/2
B.1/6
C.1/12
D.1/36
Answer: B.1/6
Explanation: On the first toss, the die will land on one of the sides.
On the second toss, the probability of landing on the same side is 1/6.
P(same side both times)=1/6.
The answer is B.
Question: Eight years ago, Rhea was half of Rick in age. If the ratio of their present ages is 3:4, what is the total of their present ages?
A.25 years
B.28 years
C.32 years
D.26 years
Answer: B.28 years
Explanation: let rhea age be x
rick age be y
given
x-8=1/2(y-8)......a
also given
x/y=(3/4)
=>x=3/4(y).......b
by solving a and b
we get y=16
x=12
then x+y=12+16=28
ANSWER:B
Question: You are standing in one of the biggest palaces in the world "Hofburg Palace, Vienna". In palace five commando are staying. Each commando has allotted five big rooms and each room contains five huge Tigers.
Each huge tiger has five small tigers.
We all know a tiger has 4 legs.
So how many legs are there in the palace ?
A.3012
B.3011
C.3010
D.3013
Answer: A.3012
Explanation: Solution:
3012
Explanation:
A)
Five Commando alloted 5 room each, Number of rooms = 5 * 5 = 25
Number of huge Tiger = 25 * 5 = 125
Number of small Tigers = 125 * 5 = 625
Total tigers = 625 + 125 = 750
Number of legs of tigers = 750 * 4 = 3000 ..............................(1)
B)
There are 5 soldiers =>
Number of legs of soldiers = 5*2 = 10 .......................(2)
C)
Your leg = 2 ............(3)
Summing all , 3000 + 10 + 2 = 3012
Answer A
Question: John's age is 86 years. If he is 4 more than twice the age of his son, find the age of his son.
A.20 years
B.22 years
C.40 years
D.50 years
Answer: C.40 years
Explanation: Let Mike's son age be x.
4 + 2 x = 84
x = 40
Hence Mike's son age is 40 years
Answer : C
Question: The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of numbers is:
A.28
B.30
C.40
D.50
Answer: C.40
Explanation: Let the numbers be 2x and 3x.
Then, their L.C.M = 6x. So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
ANSWER:C
Question: Veena ranks 73rd from the top in a class of 182. What is her rank from the bottom if 22 students have failed the examination?
A.88
B.108
C.110
D.90
Answer: A.88
Explanation: total student=182
failed=22
paasd student=182-22=160
from bottom her rank is=160-73+1=88
ANSWER:A
Question: How many 3-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed?
A.690
B.720
C.740
D.760
Answer: B.720
Explanation: The word 'LOGARITHMS' has 10 different letters.
Hence, the number of 3-letter words(with or without meaning) formed by using these letters
= 10P3
=
10
×
9
×
8
=
720
Option B
Question: If a man lost 4% by selling oranges at the rate of 16 a rupee at how many a rupee must he sell them to gain 28%?
A.12
B.13
C.14
D.15
Answer: A.12
Explanation: 96% ---- 16
128% ---- ?
96/128 * 16 = 12
Answer: A
Question: Stock / Number of shares
V ------------ 68
W ---------- 112
X ------------ 56
Y ------------ 94
Z ------------ 45
The table shows the number of shares of each of the 5 stocks owned by Mr Sami. If Mr. Sami was to sell 20 shares of Stock X and buy 22 shares of stock Y, what would be the increase in the range of the numbers of shares of the 5 stocks owned by Mr. Sami?
A.4
B.6
C.9
D.13
Answer: D.13
Explanation: Based on the original number of shares, the range would be: 112 - 45 = 67
However, the prompt tells us that two of the values in the table are going to change. After the changes, the values will be:
V 68
W 112
X 36
Y 116
Z 45
Now the range is 116 - 36 = 80
The INCREASE in the range requires us to compare thenewrange to theoldrange: 80 - 67 = 13
D
Question: A boy is travelling from his home to school at 3 km/hr and reached 7 min late. Next day he traveled at 12 km/hr and reached 8 min early. Distance between home and school?
A.1km
B.3km
C.4km
D.5km
Answer: A.1km
Explanation: Let the distance be x
T1 = x/3 hr
T2 = x/12hr
Difference in time = 7+8 = 15 =1/4hr
x/3-x/12 = 1/4
x/4 = 1/4
x = 1 km
Answer is A
Question: The average of five results is 46 and that of the first four is 45. The fifth result is?
A.18
B.50
C.27
D.23
Answer: B.50
Explanation: 5 * 46 – 4 * 45
= 50
Answer:B
Question: For covering 88km a wheel revolve 1000 times.what is the radius of wheel?
A.14 m
B.24 m
C.28 m
D.40 m
Answer: C.28 m
Explanation: distance travel in 1 round=88000/1000m=88 m
perimeter=88 m,2πr=88,2R=[88*7/22]=28 m
hence, diameter=28 m
answer C
Question: A chair is bought for Rs.600/- and sold at a loss of 10% find its selling price
A.Rs.540/-
B.Rs.550/-
C.Rs.560/-
D.Rs.590/-
Answer: A.Rs.540/-
Explanation: 100 % ------> 600 (100 * 6 = 600)
90 % ------> 540 (90 * 6 = 540)
Selling price = Rs.540/-
A)
Question: A florist has 2 azaleas, 4 buttercups, and 5 petunias. The florist puts two flowers together at random in a bouquet. However, the customer calls and says that she does not want two of the same flower. What is the probability that the florist does not have to change the bouquet?
A.43/55
B.38/55
C.17/55
D.8/11
Answer: B.38/55
Explanation: The probability that two of the same flowers were chosen:
P(AA) = 2/11 * 1/10 = 2/110
P(BB) = 4/11 * 3/10 = 12/110
P(PP) = 5/11 * 4/10 = 20/110
The sum of these probabilities is 17/55
P(two flowers are different) = 1 - 17/55 = 38/55
The answer is B.
Question: The H.C.F. of two numbers is 38 and the other two factors of their L.C.M. are 12 and 10. The larger of the two numbers is:
A.678
B.456
C.234
D.476
Answer: B.456
Explanation: :	Explanation:
Clearly, the numbers are (38 x 12) and (38 x 10).
{\color{Blue} \therefore } Larger number = (38 x 12) = 456.
Answer: B)456
Question: In one alloy there is 12% chromium while in another alloy it is 8%. 10 kg of the first alloy was melted together with 30 kg of the second one to form a third alloy. Find the percentage of chromium in the new alloy.
A.9.4%
B.9.6%
C.9%
D.9.8%
Answer: C.9%
Explanation: The amount of chromium in the new 10+30=40 kg alloy is 0.12*10+0.08*30=3.6 kg, so the percentage is 3.6/40*100=9%.
Answer: C
Question: The length of a side of a hexagon is 7 inches. What is the perimeter?
A.48
B.42
C.44
D.45
Answer: B.42
Explanation: Hexagon. It means 6 equal sides.
p = 6(7) = 42 inches
Answer B
Question: How much is 80% of 40 is greater than 4/5 of 25?
A.17
B.19
C.11
D.12
Answer: D.12
Explanation: (80/100) * 40 – (4/5) * 25
32 - 20 = 12
Answer: D
Question: A chemical lab is scheduled to go through two air ventilation systems, a basic system and a more advanced system that takes forty minutes and 3 hours respectively to fully ventilate the room. If both ventilation systems were to operate at the same time with their respective constant rates, how many hours would it take to fully ventilate the chemical lab?
A.4/9
B.2/3
C.7/12
D.6/11
Answer: D.6/11
Explanation: The rate of the basic system is 1 room/ (2/3 of an hour) = 3/2 rooms per hour
The rate of the advanced system is 1/3 of a room per hour
The combined rate is 11/6 rooms per hour.
The time to ventilate one room is 6/11 of an hour.
The answer is D.
Question: A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.75 less, he could have gained 25%. What is the cost price?
A.228
B.375
C.219
D.111
Answer: B.375
Explanation: Explanation:
CP1 = 100 SP1 = 120
CP2 = 80 SP2 = 80 * (125/100) = 100
20 ----- 100
75 ----- ? => 375
Answer:B
Question: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 110 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
A. 280
B. 400
C. 540
D. 550
Answer: D. 550
Explanation: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month:
2/3*3/4 = 1/2 survived the first month.
Of the geese that survived the first month, 3/5 did not survive the first year:
(1-3/5)*1/2 = 1/5 survived the first year.
110 geese survived the first year:
1/5*(total) = 110 --> (total) = 550.
Answer: D.
Question: To mail a package, the rate is 20 cents for the first pound and 5 cents for each additional pound. Two packages weighing 4 pounds and 6 pounds, respectively can be mailed seperately or combined as one package. Which method is cheaper and how much money is saved?
A.Separately, with a saving of 10 cents
B.Combined, with a saving of 25 cents
C.Combined, with a saving of 20 cents
D.Combined, with a saving of 15 cents
Answer: D.Combined, with a saving of 15 cents
Explanation: 4 pounds cost = 20+3*5 = 35
6 pounds cost = 20+5*5 = 45
Total = 80
10 pounds cost = 20+ 9*5 =65 dif. 80-65=15
Answer : D
Question: is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
A.7
B.8
C.9
D.10
Answer: D.10
Explanation: Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B's age = 2x = 10 years.
ANSWER:D
Question: {-10, -6, -5, -4, -2.5, -1, 0, 2.5, 4, 6, 7, 10}
A number is to be selected at random from the set above. What is the probability that the number selected will be a solution of the equation (x+5)(x+10)(2x-5) = 0?
A.1/12
B.1/6
C.1/4
D.1/3
Answer: C.1/4
Explanation: Roots of the equation (x-5)(x+10)(2x-5)=0 are x=-5,x=-10andx=5/2=2.5. So, three solutions present in our set of 12 distinct numbers, therefore P=3/12=1/4.
Answer: C.
Question: -16 -8 4 24 12 -6 -40
A.-20
B.-10
C.-2
D.8
Answer: A.-20
Explanation: take triplet combination
-16/2=-8
-8/-2=4
24/2=12
12/-2=-6
-40/2=-20
ANSWER:A
Question: For any positive integer Y, the sum of the first Y positive integers equals Y(Y+1)/2 . If X and Y are positive integers and X > Y, what is the sum of all the integers between X and Y, inclusive?
A. X(X+1)/2 + Y(Y+1)/2
B. X(X+1)/2 - Y(Y-1)/2
C. X(X+1)/2 - Y(Y+1)/2
D. X(X+1)/2 + Y(Y-1)/2
Answer: B. X(X+1)/2 - Y(Y-1)/2
Explanation: The sum of all the integers between X and Y,inclusiveis the sum of the first X positive integersminusthe sum of the first Y-1 positive integers.
The sum of the first X positive integers is X(X+1)/2;
The sum of the first Y-1 positive integers is (Y-1)Y/2;
Therefore the answer is X(X+1)/2 - (Y-1)Y/2.
Answer: B.
Question: Rectangular tile each of size 60cm by 56cm must be laid horizontally on a rectangular floor of size 560cm by 240cm,such that the tiles do not overlap and they are placed with edges jutting against each other on all edges. A tile can be placed in any orientation so long as its edges are parallel to the edges of floor. No tile should overshoot any edge of the floor. The maximum number of tiles that can be accommodated on the floor is:
A.50
B.54
C.47
D.40
Answer: D.40
Explanation: Area of tile = 60*56 = 3360
Area of floor = 560*240 = 134400
No of tiles = 134400/3360 = 40
So, the no of tile = 40
ANSWER:D
Question: The length of a rectangular landscape is 4times its breadth. There is a playground in it whose area is 1200 square mtr & which is 1/3rd of the total landscape. What is the length of the landscape?
A.100
B.110
C.120
D.130
Answer: C.120
Explanation: Sol. x * 4x = 3 * 1200
x = 30
Length = 4 * 30 = 120
C
Question: Let f(x) = x^2 + bx + c. If f(1) = 0 and f(-8) = 0, then f(x) crosses the y-axis at what y-coordinate?
A.-8
B.-1
C.0
D.1
Answer: A.-8
Explanation: When x = 1 and when x = -8, the expression f(x) = x² + bx + c equals 0.
Then f(x) = (x-1)(x+8)
f(0) = -8
The answer is A.
Question: A man can swim in still water at 1.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
A.1.7
B.0.5
C.1.1
D.1.5
Answer: B.0.5
Explanation: M = 1.5
S = x
DS = 1.5 + x
US = 1.5 + x
1.5 + x = (1.5 - x)2
1.5 + x = 3 -2x
3x = 1.5
x = 0.5
Answer:B
Question: In the xy-coordinate system, what is the slope of the line that goes through point (2, 4) and is equidistant from the two points P = (9, 3) and Q = (5, 9)?
A.0.1
B.0.2
C.0.3
D.0.4
Answer: D.0.4
Explanation: First, get the middle coordinate between (9,3) and (5,9).
x = 9 + (5-9)/2 = 7
y = 3 + (9-3)/2 = 6
Second, get the slope of (7,6) and (2,4). m = 6-4 / 7-2 = 2/5 = 0.4
Answer: D
Question: A can do a half of certain work in 70 days and B one third of the same in 35 days. They together will do the whole work in?
A.1/65
B.1/62
C.1/63
D.1/60
Answer: D.1/60
Explanation: A = 140 days
B = 105 days
1/140 + 1/105 = 7/420 = 1/60
=>60 days
Answer: D
Question: 45 men can complete a work in 16days. Six days after they started working, 30 more men joined them. How many days will they now take to complete the remaining work?
A.6
B.10
C.15
D.7
Answer: A.6
Explanation: 45*16 men can complete the work in 1 day
1 man's 1 day work = 1/720
45 men 6days work = 6*1/16 = 3/8
remaining work = 1-3/8 = 5/8
75 men's 1 day's work = 75/720 = 5/48
5/8 work is done by them in 48/5 * 5/8 = 6days
Answer is A
Question: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
A.28
B.68
C.25
D.23
Answer: B.68
Explanation: Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X - 48 = 180
1000/x - 48 * 5/18 = 180
50 = 9X - 120
X = 68 Kmph
Answer: B
Question: A large box contains 17 small boxes and each small box contains 26 chocolate bars. How many chocolate bars are in the large box?
A.A)442
B.B)490
C.C)380
D.D)450
Answer: A.A)442
Explanation: the only thing you have to do is a simple multiply
we have:
17*26
=442
correct answer is:
A) 442
Question: The ages of Raju and Biju are in the ratio 3:1. Fifteen years hence, the ratio will be 2:1. Their present ages are:
A.30yrs, 10yrs
B.45 yrs, 15yrs
C.21 yrs, 7 yrs
D.60yrs, 20yrs
Answer: B.45 yrs, 15yrs
Explanation: Let the ages of raju and Biju is 3x and x years respectively.
Then, (3x +15)/ (x+15) = 2/1;
-> 2x + 30 = 3x + 15 -> x = 15
So Raju’s age = 3*15 = 45 and Biju’s age = 15 years
ANSWER:B
Question: The sum of money will be thrice itself in 15 years and simple interest find rate of interest?
A.A)12.33%
B.B)13.33%
C.C)14.33%
D.D)15.33%
Answer: B.B)13.33%
Explanation: T = 15 years
P= principle amount = x
A = total amount = 3x
SI = simple interest = A-P = 3x-x = 2x
R = 100SI/PT = 100.2x/15x =13.33%
Answer is B
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
A.657
B.280
C.438
D.289
Answer: B.280
Explanation: x*(85/100)
= (480 - x)119/100
x = 280
Answer:B
Question: A certain junior class has 1000 students and a certain senior class has 600 students. Among these students, there are 60 siblings pairs each consisting of 1 junior and 1 senior. If 1 student is to be selected at random from each class, what is the probability that the 2 students selected will be a sibling pair?
A.3/40000
B.1/1000
C.9/2000
D.1/60
Answer: B.1/1000
Explanation: Let's see
Pick 60/1000 first
Then we can only pick 1 other pair from the 800
So total will be 60 / 600 *1000
Simplify and you get 1/10000
Answer is B
Question: A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: S = 600/40 = 15 mps
S = 3600/15 = 240 sec = 4 min
Answer: A
Question: A, B, C subscribe Rs. 50,000 for a business, A Subscribes Rs. 4000 more than B and B Rs. 5000 more thanC. Out of a total profit of Rs. 35,000, A receives :
A.14700
B.14703
C.37798
D.13777
Answer: A.14700
Explanation: Explanation:
Let C = x. Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.
So, x + x + 5000 + x + 9000 = 50000 <=> 3x = 36000 <=>
x = 12000.
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
A's share = Rs. (35000 * 21/50 ) = Rs. 14,700.
Answer: A) 14700
Question: One hour after Matthew started waking from w to y, a distance of 45km, Johnny started walking along the same road from y to w. Matthew's walking rate was 3 km per hour and Johnny's was 4km per hour, how many km had Johnny walked when they met?
A.24
B.23
C.22
D.21
Answer: A.24
Explanation: Just an alternative method...
After the first hour the distance w is 42 km (45-3). Now the problem can be treated as if bothof them started at the same time. Since the speeds are in the ratio 3 : 4, the distances will also be in the same ratio. Splitting 42 in that ratio we get 18 : 24. So answer is 24.
Hence A.
Question: If Bill can buy 3 pairs of jeans and 2 shirts for $69 or 2 pairs of jeans and 3 shirts for $71, how much does one shirt cost?
A.$10
B.$12
C.$13.20
D.$15
Answer: D.$15
Explanation: 3J + 2S = 69
2J + 3S = 71
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5J + 5S = 140 ----(divide by 5)---> J + S = 28
3J + 2S = J + 2(J + S) = J + 56 = 69 ---> J = 13
3*13 + 2S = 69
39 + 2S = 69
2S = 30
S = 15
Answer: D
Question: A baseball team won 50 percent of the first 80 games it played. How many of the remaining 82 games will the team have to win in order to have won exactly 50 percent of all the games it played?
A.36
B.41
C.50
D.55
Answer: B.41
Explanation: Games won out of first 80 questions = (50/100)*80 = 40
Total Games = 80+82 = 162
Games to be won = (50/100)*162 = 81
Remaining games to be won = 81-40 = 41
Answer: Option B
Question: If l and g are distinct prime numbers less than 10, which of the following cannot be the product of l and g?
A.6
B.9
C.10
D.14
Answer: B.9
Explanation: If l and g are distinct prime numbers less than 10, prime numbers less than 10 are 2, 3, 5, 7
all except 9 is product of any two numbers picked from above set.
Ans: B
Question: Susan is traveling from one end of a forest to the other. In order to find her way back, she is leaving morsels of bread in the following pattern: 2 morsels of wheat, 3 morsels of white, and 1 morsel of bap. The pattern repeats after she leaves the morsel of rye. If Susan drops 2,000 morsels of bread, what are the last 3 morsels of bread that she drops?
A.wheat − wheat − white
B.bap − wheat − wheat
C.white − bap − wheat
D.white − white − white
Answer: B.bap − wheat − wheat
Explanation: In a single round Susan drops 6 morsels.
Remainder (2000/6) = 2
Final action = 2 drops of Wheat --> Options A, C, D and E can be eliminated
Answer: B
Question: The ration of the father’s age to his son’s age is 7:3.The product of their ages is 756.The ratio of their ages after 6 years will be :
A.5:2
B.2:1
C.11:7
D.13:9
Answer: B.2:1
Explanation: Solution
Let the present ages of the father and son be 7x and 3x years respectively.
Then,7x 3x =756 ⇔ 21x2=756 ⇔ x2=36 ⇔ x=6.
∴ Required ratio =(7x +6) :(3x +6)=48:24=2:1. Answer B