RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Find avrg speed if a man travels at speed of 24km/hr up and 36km/hr dawn at an altitude of 200m.
A.25.8
B.26.8
C.27.8
D.28.8
Answer: D.28.8
Explanation: avg speed=2*x*y/(x+y)
=2*24*36/(24+36)=28.8
ANSWER:D
Question: 34.97 + 240.016 + 23.98 = ?
A.298.966
B.298.694
C.289.496
D.289.469
Answer: A.298.966
Explanation: 34.97
240.016
+ 23.98
--------
298.966
Answer is A.
Question: If 42.36 = k(14 + m/50), where k and m are positive integers and m < 50, then what is the value of k + m ?
A.6
B.7
C.8
D.9
Answer: D.9
Explanation: 42.36 = 14K + Km/50...we can rewrite the number as follows:
42+ 0.36= 14K + Km/50........Since K is integer, then 42=14K..........K=3
0.36=Km/50......36/100=3m/50......m=6
k+m=3+6=9
Answer: D
Question: A jar is filled of liquid which is 3 parts water and 5 parts alcohol. How much of this mixture should be drawn out and replaced such that this mixture may contain half
water and half alcohol?
A.25%
B.20%
C.14.29%
D.33.33%
Answer: B.20%
Explanation: Explanation:
Let the jar initially contain 8 litres of mixture:3 litres water and 5 litres alcohol
Let x litres of this mixture is drawn out and is replaced by x litres of water.
Amount of water now in the solution: 3-(3/8)x+x.
Amount of alcohol now in the solution: 5-(5/8)x
Desired ratio: 1/1
=>3-(3/8)x+x=5-(5/8)x
x=8/5 litres
%x=((8/5)/8)*100=20%
ANSWER B
Question: A merchant purchased a jacket for $60 and then determined a selling price that equalled the purchase price of the jacket plus a markup that was 25 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant’s gross profit on this sale?
A.$0
B.$3
C.$4
D.$12
Answer: C.$4
Explanation: Markup = x
x = 0.25(60 + x)
=> 3x/4 = 15
=> x = 20
So SP = 80
But Actual SP = 0.8 * 80 = 64
So profit = $4
Answer - C
Question: A car traveled 75% of the way from town A to town B at an average speed of 50 miles per hour. The car travels at an average speed of S miles per hour for the remaining part of the trip. The average speed for the entire trip was 60 miles per hour. What is S ?
A.150
B.200
C.250
D.300
Answer: A.150
Explanation: Total distance = 100 miles (easier to work with %)
75% of the distance = 75 miles
25% of the distance = 25 miles
1st part of the trip → 75/50 = 1.5
2nd part of the trip → 25/S = t
Total trip → (75+25)/60 = 1.5 + t » 100/60 = 1.5 + t » 2.5 = 1.5 + t » t = 0.1667
Back to 2nd part of the trip formula: 25/S = 0.1667 » S = 150
Ans A
Question: What is the year next to 1990 which will have the same calendar as that of the year 1990?
A.1992
B.2001
C.1995
D.1996
Answer: B.2001
Explanation: Explanation:
For a year to have the same calendar with 1990 ,total odd days from 1990 should be 0.
Take the year 1992 from the given choices.
Total odd days in the period 1990-1991= 2 normal years
≡ 2 x 1 = 2 odd days
Take the year 1995 from the given choices.
Number of odd days in the period 1990-1994 = 4 normal years + 1 leap year
≡ 4 x 1 + 1 x 2 = 6 odd days
Take the year 1996 from the given choices.
Number of odd days in the period 1990-1995= 5 normal years + 1 leap year
≡ 5 x 1 + 1 x 2 = 7 odd days ≡ 0 odd days
(As we can reduce multiples of 7 from odd days which will not change anything)
Though number of odd days in the period 1990-1995 is 0, there is a catch here.
1990 is not a leap year whereas 1996 is a leap year.
Hence calendar for 1990 and 1996 will never be the same.
Take the year 2001 from the given choices.
Number of odd days in the period 1990-2000= 8 normal years + 3 leap years
≡ 8 x 1 + 3 x 2 = 14 odd days ≡ 0 odd days
Also, both 1990 and 2001 are normal years.
Hence 1990 will have the same calendar as that of 2001
Answer: Option B
Question: A meeting has to be conducted with 5 managers. Find the number of ways in which the managers be selected from among 9 managers, if 2 managers will not attend the meeting together?
A.35
B.91
C.120
D.126
Answer: B.91
Explanation: we can either choose all 5 people from 7 manager who have no problems or choose 4 from the 7 and 1 from the 2 managers who have a problem sitting together
so 7C5 + (7C4 * 2C1)
this is 21 + 70
91 ANS:B
Question: If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4030 , R will receive
A.600
B.780
C.800
D.900
Answer: B.780
Explanation: Explanation :
Let P's capital = p, Q's capital = q and R's capital = r
Then
4p = 6q = 10r
=> 2p = 3q = 5r
=>q = 2p/3
r = 2p/5
P : Q : R = p : 2p/3 : 2p/5
= 15 : 10 : 6
R's share = 4030 * (6/31) = 130*6 = 780. Answer : Option B
Question: How many positive integers will divide evenly into 370?
A.4
B.6
C.8
D.12
Answer: C.8
Explanation: The question is asking how many factors 370 has.
370 = 2*5*37
The number of factors is 2^3 = 8
The answer is C.
Question: A composer’s guild is planning its spring concert, and eleven pieces have been submitted for consideration. The director of the guild knows that they will only have time to present three of them. If the pieces can be played in any order, how many combinations of pieces are possible?
A.402
B.165
C.154
D.512
Answer: B.165
Explanation: Combination question..
11C3 = 165..
IMO option B is correct..
Question: The cash difference between the selling prices of an article at a profit of 8% and 6% is Rs 3. The ratio of two selling prices is
A.51:52
B.52:53
C.53:54
D.54:53
Answer: D.54:53
Explanation: Explanation:
Let the Cost price of article is Rs. x
Required ratio = (108% of x) / (106% of x)
=108/106
=54/53 = 54:53.
Answer: D
Question: A car travels from point A to point B. The average speed of the car is 60 km/hr and it travels the first half of the trip at a speed of 48 km/hr. What is the speed of the car in the second half of the trip?
A.72
B.75
C.80
D.84
Answer: C.80
Explanation: Let D be the distance and let V be the speed in the second half.
The total time = T1 + T2
D/60 = D/96 + (D/2) / V
8D/480 - 5D/480 = (D/2) / V
D/160 = D/2V and so V = 80 km/hr
The answer is C.
Question: A certain family has 3 sons: Richard is 6 years older than David, and David is 8 years older than Scott. If in 8 years, Richard will be twice as old as Scott, then how old was David 6 years ago?
A. 8
B. 10
C. 12
D. 14
Answer: A. 8
Explanation: Let's say
Age of Richard isR
Age of David isD
Age of Scott isS
Now
Richard is 6 years older than David,
i.e. R = D +6
David is 8 years older than Scott
i.e. D = S +8
If in 8 years, Richard will be twice as old as Scott
i.e. R+8 = 2x(S+8)
i.e. R+8 = 2S + 16
i.e. R = 2S+8
But R = D+6 = (S+8)+6 = S+14
therefore, 2S + 8 = S +14
i.e. S = 6
i.e. R = 20
i.e. D = 14
Now,
how old was David 6 years ago?
i.e. D-6 = 14-6 = 8 years
Answer: Option
A
Question: The length of a train and that of a platform are equal. If with a speed of 126 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
A.227
B.299
C.1050
D.750
Answer: C.1050
Explanation: Speed = [126 * 5/18] m/sec = 35 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 35 è x = 35 * 60 / 2 = 1050
Answer: C
Question: which of the following is a prime number ?
A.17
B.18
C.15
D.20
Answer: A.17
Explanation: Clearly, 17 is a prime number.
Option A
Question: A man takes 3 hours 45 minutes to row a boat 25 km downstream of a river and 2 hours 30 minutes to cover a distance of 15 km upstream. Find the speed of the current.
A.1 km/hr
B.2/3 km/hr
C.1/3 km/hr
D.4 km/hr
Answer: C.1/3 km/hr
Explanation: Explanation:
First of all, we know that
speed of current = 1/2(speed downstream - speed upstream) [important]
So we need to calculate speed downstream and speed upstream first.
Speed = Distance / Time [important]
Speed upstream =(25/3 3/4)km/hr
=20/3km/hr
Speed Downstream = (15/2 1/2)km/hr
=6km/hr
So speed of current = 1/2(20/3−6)
=1/3 km/hr
Option C
Question: An accurate clock shows 8 o'clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 2 o'clock in the afternoon?
A.144°
B.150°
C.168°
D.180°
Answer: D.180°
Explanation: Solution
Angle traced by hour hand in
5 hrs 10 min.	= (360/12 x 6)°
= 180°.
Answer D
Question: A person goes to his office at 1/3rd of the speed at which he returns from his office. If the avg speed during the whole trip is 12m/h. what is the speedof the person while he was going to his office?
A.8km/h
B.10km/h
C.12km/h
D.13km/h
Answer: A.8km/h
Explanation: u = k , v= 3k
\inline \therefore \frac{2uv}{u+v}\: \: \Rightarrow \frac{2\times k\times 3k}{(k+3k)}=12
\inline \Rightarrow 1.5k = 12
\inline \Rightarrow k=8km/h
A
Question: A marketing firm determined that, of 200 households surveyed, 80 used neither Brand R nor Brand B soap, 60 used only Brand R soap, and for every household that used both brands of soap, 3 used only Brand B soap. How many of the 200 households surveyed used both brands of soap?
A. 15
B. 20
C. 30
D. 40
Answer: D. 40
Explanation: SOLUTION FOR SOAP R AND SOAP B
(D) 40
Question: David and Rachel are getting married. The extended family wants to have its picture taken, but David's father is unwilling to stand next to Rachel's mother. How many options does the photographer have to arrange the 14 family members in a row for the picture?
A.12!
B.13×12!
C.12×13!
D.14!/2!
Answer: C.12×13!
Explanation: The number of ways to arrange 14 people is 14!
We need to subtract the arrangement when these two people are together.
Let's think of these two people as a single unit so there are 13 units.
The number of ways to arrange 13 units is 13!
We need to multiply this by 2 since these two people could switch places.
The total number of valid arrangements is 14! - 2*13! = 13!*(14-2) = 12x13!
The answer is C.
Question: What is the units digit of 33^2 * 17^3 * 39^2?
A.1
B.3
C.5
D.7
Answer: D.7
Explanation: The units digit of 33^2 is the units digit of 3*3 = 9 which is 9.
The units digit of 17^3 is the units digit of 7*7*7 = 343 which is 3.
The units digit of 39^2 is the units digit of 9*9 = 81 which is 1.
The units digit of 9*3*1 = 27 is 7.
The answer is D.
Question: A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg?
A.22
B.99
C.40
D.28
Answer: C.40
Explanation: 800*(25/100) = 200 ---- 5
? ---- 1 => Rs.40
Answer: C
Question: Saskia needs to catch the 3.15pm train in order to get to her Mixed Martial Arts fight on time. It is 2.55 pm and Saskia is 2 miles from the train station. Saskia can run at an average speed of 10 miles per hour. However Saskia is carrying a sack of bricks which slows her down by 20%. If she runs to the station how many minutes early or late will she be for the train?
A.10 minutes early
B.5 minutes early
C.0 minutes early
D.5 minutes late
Answer: B.5 minutes early
Explanation: Saskia can run at an average speed of 10 miles per hour however she is slowed down by 20% by the sack of bricks and so can only run at 8 miles per hour. (0.2 x 10 = 2; 10 - 2 = 8)
At a speed of 8 miles per hour, Saskia can run 2 miles in 15 minutes. (8 miles / 2 miles = 4; 60 minutes/4 = 15 minutes)
Saskia has 20 minutes until her train but can run the distance in 15 minutes therefore she will be 5 minutes early (20 - 15 = 5 minutes).
ANSWER: B
Question: The H.C.F of two numbers is 15 and their L.C.M is 3300. If one of the numbers is 225, then the other is?
A.200
B.210
C.220
D.230
Answer: C.220
Explanation: Other number = (15 * 3300)/225
= 220.
Answer: C
Question: The slant height of a cone is 12 cm and radius of the base is 4cm, find the curved surface of the cone?
A.26
B.28
C.48
D.26
Answer: C.48
Explanation: π * 12 * 4
= 48
Answer:C
Question: The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 4 years hence?
A.50
B.60
C.68
D.80
Answer: C.68
Explanation: A + B = 60, A = 2B
2B + B = 60 => B = 20 then A = 40.
5 years, their ages will be 44 and 24.
Sum of their ages = 44 + 24 = 68.
ANSWER:C
Question: What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58?
A.3944
B.2287
C.2977
D.2668
Answer: A.3944
Explanation: Let the side of the square plot be a ft.
a2 = 289 => a = 17
Length of the fence = Perimeter of the plot = 4a = 68 ft.
Cost of building the fence = 68 * 58 = Rs. 3944.
Answer:A
Question: B and C walk around a circular track. They start at 9 a.m from the same point in the opposite directions. B and C walk at a speed of 5 rounds per hour and 4 rounds per hour respectively. How many times shall they cross each other before 1 p.m
A.34
B.35
C.36
D.37
Answer: C.36
Explanation: Explanation:
Relative speed = (5+4) =9 rounds per hour
So, they cross each other 9 times in an hour hence, they cross 36 times before 1 p.m
Answer: Option C
Question: Sixteen men complete a work in 24 days while 48 children can do it in 16 days. Twelve men started the work, after 14 days 12 children joined them. In how Many days will all of them together complete the remaining work?
A.12
B.62
C.27
D.29
Answer: A.12
Explanation: Explanation:
Let man capacity = 2 units/day. Then total work = 16 × 2 × 24 = 768
Let the children capacity is k units/ days. So total work = 48 × k × 16
Equating above two equations we get k = 1. So children capacity = 1 unit / day.
Twelve men did 14 days of job. So they completed 12 × 2 ×14 = 336.
Remaining work = 768 - 336 = 432.
Now 12 children joined them. So per day capacity of entire team = 12 × 2 + 12 × 1 = 36.
So they complete the remaining work in 432/36 = 12 days.
Answer:A
Question: If a man walks to his office at ¾ of his usual rate, he reaches office 1/3 of an hour late than usual. What is his usual time to reach office?
A.1
B.4
C.5
D.6
Answer: A.1
Explanation: Speed Ratio = 1:3/4 = 4:3
Time Ratio = 3:4
1 -------- 1/3
3 --------- ? è 1 hour
Answer: A
Question: Rs.500 amounts to Rs.620 in 2 years at simple interest. If the interest is increased by 2%, it would amount to how much?
A.120
B.25
C.614
D.530
Answer: D.530
Explanation: (500*3*2)/100 = 30
500+ 30 = 530
Answer: D
Question: Yearly subscription to professional magazines cost a company $840.00. To Make a 30% cut in the magazine budget, how much less must be spent?
A.654
B.655
C.656
D.588
Answer: D.588
Explanation: total cost 840
840*30/100=252
so the cut in amount is 252
the less amount to be spend is 840-252=588
ANSWER:D
Question: What is the sum of the integers from -190 to 191 inclusive?
A.0
B.191
C.375
D.875
Answer: B.191
Explanation: sum/n= average.
sum=(average)(n)
average=a+b/2=190+191/2=0.5
number of items(n)=B-A+1=191-(-190)+1=195+191=382.
sum=average*n=0.5*382=191.
answer is B
Question: The number of ways in which six boys and six girls can be seated in a row for a photograph so that no two girls sit together is ?
A.6! * 7P6
B.2(6!)
C.6!)2
D.6! * 7
Answer: A.6! * 7P6
Explanation: We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.
Hence required number of ways
= 6! * 7P6
Answer:A:
Question: V is the volume of a cylinder; the radius of the cylinder is 3.5. The height of the cylinder is 650% more than the radius. Which of the following is true?
A.100 < V < 300
B.300 < V < 500
C.500 < V < 700
D.700 < V < 900
Answer: D.700 < V < 900
Explanation: As we see the answers are in form of range we can use approximation
Volume of cylinder is πr^2h
Given π= 22/7 and r = 3.5 so r^2 ~ 12 and h = 6.5 * 3.5 ~ 23
So 22/7 * 12 * 23 ~ 868
so answer should be
D. 700 < V < 900
Answer : D
Question: Rs 1000 is being charged at 50% per annum. what is the interest for 3rd year at compound interest?
A.3277
B.2667
C.1125
D.2867
Answer: C.1125
Explanation: Explanation:
Total amount for two years = \inline 1000(1.5)^2=2250
Now , interest for third year = \inline \frac{2250\times 50\times 1}{100}=1125
Answer: C) 1125
Question: The total weight of six nougat nuggets is 3 oz. What is the average (arithmetic mean) weight of one such nougat nugget?
A.0.18 oz.
B.0.5 oz.
C.1.8 oz.
D.5 oz.
Answer: B.0.5 oz.
Explanation: Average = Total/Number of items
= 3/6 = 0.5.
Hence, B
Question: From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first is a red card and the second is a king is?
A.1/26
B.1/24
C.1/20
D.1/21
Answer: A.1/26
Explanation: Let E1 be the event of drawing a red card.
Let E2 be the event of drawing a king .
P(E1 ∩ E2) = P(E1) . P(E2)
(As E1 and E2 are independent)
= 1/2 * 1/13 = 1/26
Answer:A
Question: A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 800. How many workers were part of the latter production run?
A.A)6
B.B)10
C.C)11
D.D)21
Answer: D.D)21
Explanation: The daily average production is given by 5n + 20- given
In the first k days, 500 units are produced
= (5n+20)K =500
k = 500/5n+20...................................1
5 workers were added = 5(n+5)+20 = 5n +45
cumulative is 1250 .. thus for the current period = 800 -500 = 300
(5n+45)K= 300
k = 300/5n+45........................................2
equate 1 and 2
500/5n+20 = 300 /5n+45
500(5n+45) = 300(5n+20)
2500n + 22500 = 1500n + 6000
1000n = -16500
n = 16
thus n+5 = 21
hence D
Question: If 0 < a < b and k = (2a + 4b)/b , which of the following must be true?
A.k < 2
B.k < 6
C.k < 9
D.k > 9
Answer: B.k < 6
Explanation: Here's another approach:
k = (2a + 4b)/b
= 2a/b + 4b/b
= 2(a/b) + 4
Since 0 < a < b, we know that a/b is less than 1, which means that 2(a/b) is some number less than 2.
So, we get k = (some number less than 2) + 4
From here, we can see that k must be less than 6
Answer: B
Question: find four consecutive numbers such that the sum of the first three numbers is twelve more than the fourth number ?
A.7,8,9,10
B.3,4,5,6
C.9,10,11,12
D.6,7,8,9
Answer: D.6,7,8,9
Explanation: Let
1st Integer = x
2nd Integer = x+1
3rd Integer = x+2
4th integer = x+3
=======================================
Given
x+x+1+x+2=(x+3)+12
3x+3=x+3+12
3x+3=x+15
3x=x+15-3
3x=x+12
3x-x=12
2x=12
x=12/2
x=6
========================================
1st Integer = x = 6
2nd Integer = x+1 = 6+1 = 7
3rd Integer = x+2 =6+2= 8
4th integer = x+3=6+3=9
Answer D
Question: By selling 16 pencils for a rupee a man loses 28%. How many for a rupee should he sell in order to gain 28%?
A.8
B.9
C.7
D.6
Answer: B.9
Explanation: 72% --- 16
128% --- ?
72/128 * 16 = 9
Answer: B
Question: A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 200. How much did he have with him in the beginning?
A.s 200
B.s 500
C.s 300
D.s 450
Answer: B.s 500
Explanation: Suppose the amount in the beginning was Rs ’x’
Money spent on clothes = Rs 1x/3 Balance = Rs 2x/3
Money spent on food = 1/5 of 2x/3 = Rs 2x/15
Balance = 2x/3 - 2x/15 = Rs 8x/15
Money spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5
Therefore 2x/5 = 200 = 500
ANSWER:B
Question: A certain junior class has 1000 students and a certain senior class has 800 students. Among these students, there are 40 siblings pairs each consisting of 1 junior and 1 senior. If 1 student is to be selected at random from each class, what is the probability that the 2 students selected will be a sibling pair?
A.3/40000
B.1/3600
C.1/20000
D.1/60
Answer: C.1/20000
Explanation: Let's see
Pick 40/1000 first
Then we can only pick 1 other pair from the 800
So total will be 40 / 800 *1000
Simplify and you get 1/20000
Answer is C
Question: A began a business with Rs. 85,000. He was joined afterwards by B with Ks. 42,500. For how much period does B join, if the profits at the end of the year are divided in the ratio of 8 : 1 ?
A.6 months
B.3 months
C.2 months
D.8 months
Answer: B.3 months
Explanation: Suppose B joined for x months . Then, ( 85000 * 12 )/(42500 * x) = 8. or x = (85000 * 12) / (42500 * 8) = 3.
So, B joined for 3 months.
Answer: B
Question: Dhoni weighs twice as much as Nameetha. Nameetha's weight is 55% of Bima's weight. Dravid weighs 35% of Leela's weight. Leela weighs 30% of Dhoni's weight. Who among these 5 persons weighs the least?
A.Dravid
B.Dhoni
C.Bima
D.Nameetha
Answer: A.Dravid
Explanation: if
Bima weight = x
we get
Nameetha's weight = 0.55x
Dhoni's weight = 1.1x
Leela's weight = 0.33x
and Dravid's weight = 0.1155x
Answer : A
Question: A money lender lent Rs. 1000 at 3% per year and Rs. 1400 at 5% per year. The amount should be returned to him when the total interest comes to Rs. 350. Find the number of years.
A.3.5
B.3.75
C.4
D.4.25
Answer: A.3.5
Explanation: (1000xtx3/100) + (1400xtx5/100) = 350 → t =3.5 answer A
Question: Find the length of the longest pole that can be placed in an indoor stadium 24 m long, 18 m wide and 16 m high
A.31
B.32
C.33
D.34
Answer: D.34
Explanation: sqrt(1156)=34
becoz max length is cuboid diagonal d=sqrt(L^2+B^2+H^2)
where L lenght
B breadth & H height
ANSWER:D
Question: During a given week A programmer spends 1/4 of his time preparing flow chart, 3/8 of his time coding and the rest of the time in debugging the programs. If he works 48 hours during the week , how many hours did he spend debugging the program.
A.15 hrs
B.16 hrs
C.18 hrs
D.19 hrs
Answer: C.18 hrs
Explanation: programmer takes 1/4*48=12 hrs a week to make flowchrt
same way.....18 hrs a week for codin...
so....for debugging=48-(12+18)=18 hrs
ANSWER:C
Question: Priya went to the stationers and bought things worth Rs. 200, out of which 50 paise went on sales tax on taxable purchases. If the tax rate was 2%. then what was the cost of the tax free items?
A.Rs. 175.50
B.Rs. 174.50
C.Rs. 174.00
D.Rs. 170.00
Answer: B.Rs. 174.50
Explanation: Solution
Let the amount of taxable purchases be Rs.x.
Then, 2% of x	= 50/100
x ‹=› (50/100×100/2)
= 25
Cost of tax free items	= Rs.[200 - (25 + 0.50)]
= Rs. 174.50
Answer B
Question: 8 friends are living in 8 different flats of an apartment. Each of them was allotted a parking spot to park their cars in the ground floor. But they used to park their cars randomly in any of the 8 parking spots. In how many ways can they park their cars so that exactly 6 people park their cars in the spots allotted to them?
A.20
B.28
C.36
D.44
Answer: B.28
Explanation: 8C6 = 28
The remaining 2 people in each case will be parked in each other's parking spots.
The answer is B.
Question: An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
A.16 2/6%
B.16 2/8%
C.16 3/3%
D.16 2/3%
Answer: D.16 2/3%
Explanation: 600 ---- 100
100 ---- ? => 16 2/3%
Answer: D
Question: Find the value of 72519 x 9999 = m?
A.709115678
B.723417481
C.710017481
D.725117481
Answer: D.725117481
Explanation: 72519 x 9999 = 72519 x (10000 - 1)
= 72519 x 10000 - 72519 x 1
= 725190000 - 72519
= 725117481
D
Question: Pipes A and B can fill a cistern in 8 and 24 minutes respectively. They are opened an alternate minutes. Find how many minutes, the cistern shall be full?
A.10
B.26
C.12
D.24
Answer: C.12
Explanation: 1/8 + 1/24 = 1/6
6 * 2 = 12
Answer: C
Question: Jerry travels 8 miles at an average speed of 40 miles per hour, stops for 12 minutes, and then travels another 20 miles at an average speed of 60 miles per hour. What is Jerry’s average speed, in miles per hour, for this trip?
A.42
B.42.5
C.44
D.50
Answer: A.42
Explanation: Total Time taken by jerry = (8/40)*60 Minutes + 12 Minutes + (20/60)*60 Minutes = 44 Minutes
Average Speed = Total Distance / Total Time = (8+20) miles / (44/60)Hours = 28*60 / 44 = 42 Miles per hour
Answer: option A
Question: In a class composed of x girls and y boys, What part of the class is composed of girls
A.y/(x + y)
B.x/xy
C.x/(x + y)
D.y/xy
Answer: C.x/(x + y)
Explanation: X/(X+Y).... ANSWER:C
Question: While playing a certain dice game, Chris wins if the sum of the two dice is 7, at which point the game is over. If the game allows Chris three rolls in an attempt to win, what is the probability that Chris will win?
A.1/2
B.17/36
C.91/216
D.11/36
Answer: C.91/216
Explanation: Total outcomes possible: 36
Total outcomes possible with sum 7: 6
Probability to win when rolled once = 6/36
Probability not to win when rolled once = 30/36 = 5/6
Probability to win in three attempts= 1- Probability will not to win in all three attempts
= 1- (5/6* 5/6*5/6)
= 91/216
Answer is C.