RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in?
A.3 9/97 hrs
B.3 9/77 hrs
C.3 9/17 hrs
D.3 9/27 hrs
Answer: C.3 9/17 hrs
Explanation: Net part filled in 1 hour = 1/5 + 1/6 - 1/12
= 17/60
The tank will be full in 60/17 hrs, i.e., 3 9/17 hrs.
Answer:C
Question: In what time will a train 250 metres long cross an electric pole, if its speed be 162 km/hr?
A.4 sec
B.5 sec
C.5.55 sec
D.6.55sec
Answer: C.5.55 sec
Explanation: Solution
Speed	= (162 x 5 /18) m/sec
= 45 m / sec
Time taken	= (250 /45) sec
= 5.55 sec.
Answer C
Question: At an elementary school, 70% of the faculty members are women and 40% of the faculty members are married. If 1⁄3 of the men are single, what fraction of the men are married?
A.1/2
B.1/3
C.2/3
D.3/5
Answer: C.2/3
Explanation: --------------------M------W--------Total
Marrried----------20-----20---------40
Not married-----10-----50---------60
Total-------------30-----70--------100
need married man/total man, so 20/30=2/3
C
Question: A manâ€™s current age is (2/5) of the age of his father. After 10 years, he will be (1/2) of the age of his father. What is the age of father at now?
A.40
B.45
C.38
D.50
Answer: D.50
Explanation: Let, fatherâ€™s current age is A years.
Then, Manâ€™s current age =[ (2/5)A ]years.
Therefore, [ (2/5)A + 10 ]= (1/2)(A + 10)
2(2A + 50) = 5(A + 10)
A = 50
D
Question: When 52416 is divided by 312, the quotient is 168. what will be the quotient when 52.416 is divided by 0.12510168?
A.5
B.6
C.10
D.3
Answer: C.10
Explanation: for the 1st no. there are 2 digits after decimal
for the 2nd no. there are 9 digits after decimal
total no. of decimals = 11
req. no. of digits=(n-1)=(11-1)=10
ANSWER :C
Question: If (a-b) is 6 more than (c+d) and (a+b) is 3 less than (c-d), then (a-c)
A.0.5
B.1
C.1.5
D.2
Answer: C.1.5
Explanation: (a-b)-(c-d)=6 and (c-d)-(a+b)=3
(a-c)-(b+d)=6 and (c-a)-(b+d)=3
(b+d)= (a-c)-6 and (b+d)=3-(c-a)
2(a-c)=3
(a-c)=1.5
ANSWER C 1.5
Question: James took a 3-hour bike ride. In the second hour he traveled 30 miles, which was 20 percent farther than he traveled the first hour. If he traveled 25 percent farther in the third hour than he did in the second hour, how many miles did jose travel during the entire ride?
A.54.0
B.54.9
C.92.5
D.57.0
Answer: C.92.5
Explanation: Let the distance travelled in the first hour be x. Thus, 1.2x = 30 , x = 25. Now, the distance travelled in the 3rd hour = 30+1/4âˆ—30= 37.5 The only option ending with a 0.5 in the decimal place is C.
ANSWER:C
Question: If 3 people can do 3 times of a particular work in 3 days, then how many days would it take 6 people to do 6 times of that particular work?
A.1
B.2
C.3
D.6
Answer: C.3
Explanation: 3 people can do the work one time in one day.
1 person can do 1/3 of the work in one day.
6 people can do 6/3 of the work in one day.
6 people can do 6 times the work in 3 days.
The answer is C.
Question: Mary is traveling from one end of a forest to the other. In order to find her way back, she is leaving morsels of bread in the following pattern: 2 morsels of wheat, 3 morsels of white, and 1 morsel of waffle. The pattern repeats after she leaves the morsel of waffle. If Mary drops 2,000 morsels of bread, what are the last 3 morsels of bread that she drops?
A.waffle − wheat − wheat
B.wheat − wheat − white
C.white − waffle − wheat
D.white − white − white
Answer: A.waffle − wheat − wheat
Explanation: In a single round Mary drops 6 morsels.
Remainder (2000/6) = 2
Final action = 2 drops of Wheat --> Options B, C, D and E can be eliminated
Answer: A
Question: Average of five numbers is 30 . If one number is excluded the average becomes 26. The excluded number is
A.35
B.45
C.55
D.46
Answer: D.46
Explanation: Explanation:
Number is (5*30) - (4*26) = 150-104 = 46
Answer: Option D
Question: Ron scored 344 marks out of 400 marks and his elder brother Ben scored 582 marks out of 600 marks. Who scored percentage is better?
A.2333
B.2778
C.1000
D.2776
Answer: C.1000
Explanation: An alloy contains 26 % of copper. What quantity of alloy is required to get 260 g of copper?
Solution:
Let the quantity of alloy required = m g
Then 26 % of m =260 g
⇒ 26/100 × m = 260 g
⇒ m = (260 × 100)/26 g
⇒ m = 26000/26 g
⇒ m = 1000 g
Answer:C
Question: The seats in an Engineering college for Computer science, electronics and civil are in the ratio of 5 : 7 :
8. There is a proportion to increase these seats by 40%, 50% and 75% respectively. What will be the
ratio of increased seats ?
A.2 : 3 : 4
B.6 : 7 : 8
C.6 : 8 : 9
D.none of these
Answer: A.2 : 3 : 4
Explanation: Expl : Originally, let the number of seats for Computer science, electronics and civil
are 5x : 7x : 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x)
7x : 21x/2 : 14x = 14x : 21x : 28x = 2 : 3 : 4.
Answer: A
Question: What is the perimeter of a rectangular field whose diagonal is 10m and length is 3m ?
A.12 m
B.5 m
C.10 m
D.8 m
Answer: D.8 m
Explanation: Sol:
Breadth of the rectangular plot is=10^2-3^2=1m
Therefore,
Perimeter of the rectangular plot= 2(3+1)=8m
D) 8m
Question: The average of a set of five distinct integers is 400. If each number is less than 2,000, and the median of the set is the greatest possible value, what is the sum of the two smallest numbers?
A.-4,494
B.-3,994
C.-3,494
D.-3,194
Answer: B.-3,994
Explanation: Sum of the set = 400*5=2000 Each number is less than 2000 and median of the set is the greatest possible value.
Therefore last 3 numbers can be 1999,1998 and 1997. Their sum=5994.
Therefore sum of two smallest numbers= 2000-5994= -3994
Answer=B
Question: A can complete a journey in 1 hours. He travels first half of the journey at the rate of 21km/hr and second half at the rate of 24km/hr. Find the total journey in km?
A.120km
B.150km
C.200km
D.224km
Answer: D.224km
Explanation: Let the total distance be xkm
x/2/21 + x/2/24 = 10
x/21 + x/24 = 20
15x = 168*20
x = 224km
Answer is D
Question: The average age of an adult class is 40years. 15new students with an avg age of 32years join the class. Therefore decreasing the average by 4year. Find what was theoriginal strength of class?
A.8
B.12
C.15
D.17
Answer: C.15
Explanation: Let original strength = y
Then , 40y + 15 x 32 = ( y + 15) x 36
â‡’ 40y + 480 = 36y + 540
â‡’ 4y = 60
âˆ´ y = 15
C
Question: the cyclist going at a constant rate of 18 miles per hour is passed by a motor-cyclist traveling in the same direction along the same path at 48 miles per hour. the motor-cyclist stops to wait for the cyclist 15 minutes after passing cyclist, while the cyclist continues to travel at constant rate, how many minutes must the motor-cyclist wait until the cyclist catches up?
A.25
B.30
C.35
D.40
Answer: A.25
Explanation: For the 15 minutes the motor-cyclist continues to overtake the cyclist, she is going at 30 miles per hour faster than the cyclist.
Once the motor-cyclist stops, the cyclist is going at 18 miles per hour while the motor-cyclist is at rest
So the amount of time the cyclist will take to cover the distance between them is going to be in the ratio of the relative speeds. 30/18 * 15 or 25 minutes
Answer is (A)
Question: A man can row with a speed of 15 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is?
A.10 kmph
B.5 kmph
C.20 kmph
D.22 kmph
Answer: C.20 kmph
Explanation: M = 15
S = 5
DS = 15 + 5 = 20
ANSWER:C
Question: If a – 8 = b, then determine the value of | a - b| - | b - a|.
A.16
B.0
C.4
D.2
Answer: B.0
Explanation: Sol.(b) | a - b| = |8| = 8
=> | b - a| = |-8| = 8
=> | a - b| - | b - a| = 8 - 8 = 0.
Answer B
Question: A motorcycle importer is planning on increasing the price of a certain model by $1000. At this new price 7 fewer motorcycles will be sold per month, but the total revenues will increase by $26,000 to $594,000. What is the number of motorcycles the manufacturer will sell at this new price?
A.62
B.63
C.64
D.65
Answer: C.64
Explanation: I will make an equation in x and then make educated guesses. Here's how:
Assuming x motorcycles were sold every month initially.
(568000/x + 1000)(x-7) = 594000
(568/x + 1)(x-7) = 594
Now 568 = 8*71
Assuming x = 71 (We have all integers so it is obvious that 568/x should be an integer.
We get 9*66 = 594 (matches)
So he will sell 71 - 7 = 64 bikes this month
Answer (C)
Question: What no. should be subtracted from x^3+4x^2−7x+12x^3+4x^2−7x+12, if it is to be perfectly divisible by x+3x+3?
A.30
B.42
C.45
D.49
Answer: B.42
Explanation: According to remainder theorem when dfracf(x)x+adfracf(x)x+a, then the remainder is f(−a)f(−a).
In this case, as x+3x+3 divides x3+4x2−7x+12–kx3+4x2−7x+12–k perfectly (kk being the number to be subtracted), the remainder is 0 when the value of xx is substituted by -3.
i.e., (−3)3+4(−3)2−7(−3)+12−k=0(−3)3+4(−3)2−7(−3)+12−k=0
or −27+36+21+12=k−27+36+21+12=k
or k=k= 42
B
Question: Three rugs have a combined area of 200 square meters. By overlapping the rugs to cover floor area of 138 square meters, the area that is covered by exactly two layers of rug is 24 square meters. What is the area that is covered with three layers of rug ?
A.18 square meters
B.19 square meters
C.24 square meters
D.28 square meters
Answer: B.19 square meters
Explanation: Total = Rug1 + Rug2 + Rug3 - {overlap of exactly 2 rugs} - 2*{overlap of exactly 3 rugs}
138 = 200 - 24 - 2*{overlap of exactly 2 rugs} --> {overlap of exactly 3 rugs} = 19.
Answer: B.
Question: Two employees X and Y are paid a total of Rs. 590 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
A.s.268
B.s.288
C.s.298
D.s.300
Answer: A.s.268
Explanation: Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 590
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 590
⇒ y[12/10 + 1] = 590
⇒ 22y/10 = 590
⇒ 22y = 5900
⇒ y = 5900/22 = 500/2 = Rs.268
A)
Question: The sequence a1, a2, a3, a4. a5 is such that an = a n-1 +5 for 2≤ n ≤ 5. If a5 = 39 what is the value of a1 ?
A.1
B.6
C.19
D.16
Answer: C.19
Explanation: Here, each value of an is the previous value plus 5
Since the numbers are less, the fastest way to solve this problem is to successively subtract 5 from a5 till you reach a1
a5 = 39
a4 = 34
a3 = 29
a2 = 24
a1 = 19 <<<< Ans C
Question: What is the probability that Company Q's advertisement will be one of the first two be shown during the first commercial break?
A. 1/ 225
B. 1 / 30
C. 1 /15
D. 2 / 15
Answer: D. 2 / 15
Explanation: Q 1/15 + (14/15) * 1/14 = 2/15 D
Question: In a jar there are balls in different colors: blue, red, green and yellow.
The probability of drawing a blue ball is 1/8.
The probability of drawing a red ball is 2/5.
The probability of drawing a green ball is 7/10.
If a jar cannot contain more than 50 balls, how many yellow balls are in the Jar?
A.12
B.15
C.23
D.7
Answer: D.7
Explanation: answer of 1st
just add the given probabilities p(blue)+p(red)+p(green) i.e
1/8+2/5+ 3/10=5+16+12/40
now we know p(blue)+p(red)+p(green)+p(yellow)=1
33/40+p(yellow)=1
p(yellow)=33/40
i.e why yellow balls are 7.
D
Question: In a box, there are 10 blue, 12 white and 10 yellow bulbs. One bulb is picked up randomly. What is the probability that it is neither white nor blue?
A.3/16
B.5/16
C.8/32
D.2/32
Answer: B.5/16
Explanation: Total number of bulbs = (10 + 12 + 10) = 32.
Let E = event that the bulb drawn is neither white nor blue = event that the bulb drawn is yellow.
Therefore, P(E)=10/32= 5/32
ANSWER:B
Question: How many different 6-letter sequences are there that consist of 2A, 7B's and 3C's ?
A.6
B.60
C.120
D.360
Answer: C.120
Explanation: How many different 6-letter sequences are there that consist of 2 A, 7B's, and 3 C's?
(A) 6
(B) 60
(C) 120
(D) 360
(E) 720 (ANS C)
Question: 100 liters of a mixture contains milk and water in the ratio 7:3. If 10 liters of this mixture be replaced by 10 liters of milk, the ratio of milk to water in the new mixture would be?
A.7:8
B.8:3
C.3:8
D.8:7
Answer: B.8:3
Explanation: Quantity of milk in 100 liters if mix = 100*7/10 =70 liters
Quantity of milk in 110 liters of new mix = 80+10 = 80liters
Quantity of water in it = 110-80 = 30 liters
Ratio of milk and water in new mix = 80:30 = 8:3
Answer is B
Question: What is the sum of all digits for the number 10^29 - 41?
A.257
B.242
C.231
D.202
Answer: A.257
Explanation: 10^29 is a 30-digit number: 1 followed by 29 zeros.
10^29 - 41 is a 29-digit number: 27 9's and 59 at the end.
The sum of the digits is 27*9+5+9=257.
The answer is A.
Question: The ratio of Red Balls to Blue Balls is 3:7. 70% of the Red balls and 30% of the Blue balls are tennis balls. How many of the balls are tennis balls?
A.44%
B.40%
C.45%
D.42%
Answer: D.42%
Explanation: let total no of Balls 100, Red Ball 30 and Blue Ball 70, so tennis ball for Red and Blue Ball respectively 30* 70/100=21 and 70* 30/100=21
so total 42 tennis balls out of 100 balls..so required % is 42%
ANSWER:D
Question: 20% loss on the selling price is what percent loss on the cost price?
A.27/7%
B.47/11%
C.50/3%
D.63/8%
Answer: C.50/3%
Explanation: Let S.P. = $100
Then, loss = $20
C.P. = 100+20 = $120
Loss% = 20/120 * 100 = 50/3%
Answer is C
Question: When the number 9y30012 is exactly divisible by 11, what is the smallest whole number that can replace y?
A.1
B.2
C.5
D.6
Answer: B.2
Explanation: The given number =9y30012
Sum of the odd places =2+0+3+9=14
Sum of the even places = 1+0+y
(Sum of the odd places)- (Sum of even places) = Number (exactly divisible by 11)
14-(1+y) = divisible by 11
13 � y = divisible by 11.
Y must be 2, to make given number divisible by 11.
B
Question: If 6 persons can do 6 times of a particular work in 6 days, then, 7 persons can do 7 times of that work in
?
A.3 days
B.7 days
C.6 days
D.11 days
Answer: C.6 days
Explanation: That is, 1 person can do one time of the work in 6 days.
Therefore, 7 persons can do 7 times work in the same 6 days itself.
Option 'C'
Question: A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
A.22 1/2
B.22 18/2
C.28 1/2
D.22 1/5
Answer: A.22 1/2
Explanation: 100 --- 10 DS = 10
? ---- 1
75 ---- 15 US = 5
? ----- 1 S = (10 - 5)/2
= 22 1/2 kmph.Answer: A
Question: Of the three- digit integers greater than 700, how many have two digits W that are equal to each other and the remaining digit different from the other two?
A.90
B.82
C.80
D.45
Answer: C.80
Explanation: three-digit integers greater than 700: 701 to 999, inclusive.
possible values for hundreds-digit--> 7,8,9
possible values for tens-digit and ones-digit --> 0, 1,2,3,4,5,6,7,8,9
when hundreds-digit and tens-digit are the same: (3x1x10)-3=27 ---> we minus three to exclude 777, 888 and 999
when hundreds-digit and ones-digit are the same: (3x10x1)-3=27 ---> we minus three to exclude 777, 888 and 999
when tens-digit and hundreds-digit are the same:[(3x10x1)-3]-1=26 ---> we minus three to exclude 777, 888 and 999; we minus one to exclude 700
W=27+27+26 = 80
Answer: C
Question: A can do a piece of work in 12 days. When he had worked for 2 days B joins him. If the complete work was finished in 8 days. In how many days B alone can finish the work?
A.2 days
B.25days
C.9 days
D.18 days
Answer: D.18 days
Explanation: Explanation:
8/12 + 6/x = 1
X = 18 days
Answer: D
Question: The length of the longest tape in cm which can be used to measure exactly, the length 10m; 3m 85cm; and 11m 50cm is:
A.5
B.35
C.34
D.36
Answer: A.5
Explanation: The three lengths in cm are 1000, 385 & 1150.
HCF of 700, 385 & 1295 is 5.
Hence, the answer is 5 cm.
ANSWER:A
Question: If y exceeds x by 35%, then x is less than y by?
A.16 2/9%
B.25 5/27%
C.16 2/3%
D.12 2/3%
Answer: B.25 5/27%
Explanation: X=100	y=135
135------35
100-------? => 25 5/27%
Answer:B
Question: The value of a 10.5% stock, in which an income of Rs.756 is derived by investing Rs.9000, brokerage being% is :
A.Rs. 113.5
B.Rs. 120
C.Rs. 124.75
D.Rs. 137.5
Answer: C.Rs. 124.75
Explanation: For an income of Rs.756, investment = Rs.9000
For an income of Rs., investment = = Rs.125
For a Rs.100 stock, investment = Rs.125.
Market value of Rs. 100 stock = = Rs. 124.75
C
Question: There are 2 sections A and B in a class, consisting of 16 and 14 students respectively. If the average weight of section A is 20kg and that of section B is 25kg, Find the average of the whole class?
A.33.5kg
B.37.25kg
C.42.45kg
D.55.12kg
Answer: A.33.5kg
Explanation: Total weight of 36+44 students = 16*20 + 14*25 = 670
Average weight of the class is = 670/20 = 33.5 kg
Answer is A
Question: A jar full of whiskey contains 40% alcohol. A part of this whisky is replaced by another containing 19%
alcohols and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is
A.43
B.34
C.32
D.23
Answer: D.23
Explanation: Explanation :
Concentration of alcohol in 1st Jar = 40%
Concentration of alcohol in 2nd Jar = 19%
After the mixing, Concentration of alcohol in the mixture = 26%
By the rule of alligation,
Concentration of alcohol in 1st Jar Concentration of alcohol in 2nd Jar
40% 19%
Mean
26%
7 :14
Hence ratio of 1st and 2nd quantities = 7 : 14 = 1 : 2
Answer : Option D
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?
A.2.89
B.2.88
C.2.85
D.2.84
Answer: B.2.88
Explanation: M = 6
S = 1.2
DS = 6 + 1.2 = 7.2
US = 6 - 1.2 = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
Answer:B
Question: By selling an umbrella for Rs. 300, a shop keeper gains 20%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
A.5%
B.2%
C.8%
D.3%
Answer: C.8%
Explanation: Marked price = Rs. 300
C.P. = 100/120 * 300 = Rs. 250
Sale price = 90% of Rs. 300 = Rs. 270
Required gain % = 20/250 * 100 =8%.
Answer: C
Question: If the sum of one-third and one-half of a number exceeds two-third of a number by 5, the number is
A.30
B.32
C.36
D.40
Answer: A.30
Explanation: Explanation:
Let the number be x. Then,
x/3 + x/2 = 2x/3 + 5
= 5x/6 - 2x/3 = 5
= x/6 = 5
= x = 30
Answer: Option A
Question: What least number mustbe subtracted from 427398 so that remaining no.is divisible by 15
A.3
B.4
C.6
D.7
Answer: A.3
Explanation: Explanation:
On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted
Answer: Option A
Question: The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
A.10 a.m
B.10.30 a.m
C.11 a.m
D.11.30 a.m
Answer: C.11 a.m
Explanation: Explanation:
Suppose they meet x hrs after 8 a.m
then,
[Distance moved by first in x hrs] + [Distance moved by second in (x - 1) hrs] = 330.
Therefore, 60x + 75(x - 1) = 330.
=> x = 3.
So,they meet at (8 + 3) i.e, 11a.m.
Answer: C
Question: How should we mix two rice packets to get one 1kg packet priced at Rs 8 when the prices of 1 kg packets of the two types are Rs 7.1 and Rs 9.2.
A.4:3
B.4:7
C.4:9
D.4:2
Answer: A.4:3
Explanation: Explanation:
No explanation is available for this question!
ANSWER: A
Question: If DON is coded as 18 and MASS is coded as 29 Then KING is coded as
A.21
B.20
C.19
D.17
Answer: D.17
Explanation: KING = 11+9+14+7=41 i.e (4*4)+(1*1)=17
MASS = 13+1+19+19=52 i.e (5*5)+(2*2)=29
DON = 4+14+15=33 i.e(3*3)+(3*3)=18
ANSWER:D
Question: A reduction of 30% in the price of oil enables a house wife to obtain 9kgs more for Rs.900, what is the reduced price for kg?
A.72
B.27
C.40
D.30
Answer: D.30
Explanation: 900*(30/100) = 270 ---- 9
? ---- 1 => Rs.30
Answer:D
Question: A company bought for its 7 offices 2 computers of brand N and 4 computers of brand M. In how many ways could computers be distributed among the offices if each office can have only 1 computer.
A.196
B.105
C.256
D.292
Answer: B.105
Explanation: This problem has to do withcombinations. Here's the general idea: if you have a set of n elements, and you are going to choose r of them (r < n), then the number of combinations of size r one could choose from this total set of n is:
# of combinations = nCr = (n!)/[(r!)((n-r)!)]
where n! is the factorial symbol, which means the product of every integer from n down to 1. BTW, nCr is readn choose r.
In this problem, let's consider first the three computers of brand M. How many ways can three computer be distributed to seven offices?
# of combinations = 7C4 = 35
There are 35 different ways to distribute three computers to 7 offices. (The massive amount of cancelling that occurred there is very much typical of what happens in the nCr formula.)
One we have distributed those three M computers, we have to distribute 2 N computers to the remaining four offices. How many ways can two computer be distributed to four offices?
# of combinations = 3C2 = 3
For each of the 35 configurations of distributing the M computers, we have 3 ways of distributing the N computers to the remaining offices. Thus, the total number of configurations is 35*3 = 105. Answer choice =B
Question: At a party, there were five times as many girls as boys and three times as many adults as children. Which of the following could NOT be the number of people at the party?
A.258
B.259
C.216
D.120
Answer: A.258
Explanation: Five times as many girls as boys --> F = 5M.
Three times as many adults as children --> (F + M) = 3C.
The number of people at the party = F + M + C = 3C + C = 4C.
The number of people at the party must be a multiple of 4. The only answer choice which is NOT a multiple of 4 is A.
Answer: A.
Question: The price of rice falls by 20%. How much rice can be bought now with the money that was sufficient to buy 10 kg of rice previously?
A.5 kg
B.12,5 kg
C.25 kg
D.30 kg
Answer: B.12,5 kg
Explanation: Solution: Let Rs. 100 be spend on rice initially for 10 kg.
As the price falls by 20%, new price for 10 kg rice,
= (100 -20% of 100) = 80
New price of rice = 80/10 = Rs. 8 per kg.
Rice can bought now at = 100/8 = 12,5 kg.
Answer: Option B
Question: What proximate value should come in place of the question mark (?) in the following question?
8.595 Ã— 1084 + 2568.34 â€“ 1708.34 = ?
A.6,000
B.12,000
C.10,000
D.10148
Answer: D.10148
Explanation: ? â‰ˆ 8.6 Ã— 1080 + 2560 â€“ 1700 â‰ˆ 9288 + 860 â‰ˆ 10148
Answer D
Question: A financier claims to be lending money at simple interest, But he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes.
A.9.25%
B.10%
C.10.25%
D.9%
Answer: C.10.25%
Explanation: Explanation :
Let the sum is 100.
As financier includes interest every six months , then we will calculate SI for 6 months, then again for six months as below:
SI for first Six Months = (100*10*1)/(100*2) = Rs. 5
Important: now sum will become 100+5 = 105
SI for last Six Months = (105*10*1)/(100*2) = Rs. 5.25
So amount at the end of year will be (100+5+5.25)
= 110.25
Effective rate = 110.25 - 100 = 10.25
Answer : C
Question: What percent of 120 are 90?
A.33
B.66
C.75
D.44
Answer: C.75
Explanation: (?% /100) * 120 = 90
? = 75%
Answer: C
Question: for doing any work A take 50% more time than B.if both together finish the work in 18 days,then B alone in how much days finish the work?
A.35 days
B.30 days
C.40 days
D.45 days
Answer: B.30 days
Explanation: let B take x days in finishing work
then,A take=150x/100 days=3x/2 days
so,1/x+2/3x=1/18,5/3x=1/18,3x=90,x=30
hence,whole work B finish in 30 days
answer B
Question: A shopkeeper has 100 kg of apples. He sells 50% of these at 25% profit and remaining 50% at 30% profit. Find his % profit on total.
A.27.5%
B.25.6%
C.31.5%
D.35.9%
Answer: A.27.5%
Explanation: Total number of apples = 100
Let the cost price be x
Selling price at 25% profit = 1.25x
Selling price at 30% profit = 1.3x
Profit % = ((SP - CP)/CP)*100
Profit % = ((1/2)*100*1.25x + (1/2)*100*1.3x - 100x)/100x * 100 = (255-200)/2
= 27.5%
Answer is A