RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In September, John sold 2323 more soap than in February. In November, he sold 5 percent more than in September. John's November sales were what percent greater than his February sales?
A.10/3%
B.65%
C.214/3 %
D.75%
Answer: D.75%
Explanation: Let february sale= x
september sale= x+2/3x= 5x/3
November sale= 5x+3 + 5*5/100*3x
21/12x= 1.75 x
Hence November sale is 75% > February sale
D is the answer
Question: A man can row with a speed of 15 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is?
A.29
B.378
C.20
D.27
Answer: C.20
Explanation: M = 15
S = 5
DS = 15 + 5 = 20
Answer: C
Question: At a special sale, 9 tickets can be purchased for the price of 6 tickets. If 9 tickets are purchased at the sale, the amount saved will be What percent of the original price of the 9 tickets?
A.20%
B.33.3%
C.40%
D.60%
Answer: B.33.3%
Explanation: let the price of a ticket be Rs.100, so 6 tickets cost 600 & 9 tickets cost 900
9 tickets purchased at price of 6 tickets ie., for 600, so amount saved s Rs.300,
% of 9 tickets = (300 /900)*100 =33.3 %
ANSWER:B
Question: In a group containing 6 cows and 4 buffalos, 4 livestock are to be selected in such a way that at least 1 cow should always be present. How many way of doing that are possible?
A.209
B.277
C.297
D.161
Answer: A.209
Explanation: ANSWER:A
Question: If 47. 2506 = 4*A + 7/B + 2*C + 5/D + 6*E, then the value of 5*A + 3*B + 6*C + D + 3*E is :
A.153.6002
B.153.6008
C.153.6003
D.153.6001
Answer: C.153.6003
Explanation: Explanation:
4*A + 7/B + 2*C + 5/D + 6*E =47.2506
=> 4 * A + 7/B + 2 *C + 5/D + 6*E = 40 + 7 + 0.2 + 0.05 + 0.0006
Comparing the terms on both sides, we get :
4*A =40, 7/B = 7, 2*C = 0.2, 5/D = 0.05, 6*E = 0.0006
A = 10,
B = 1,
C = 0.1,
D = 100,
E = 0.0001.
5*A + 3*B + 6*C + D + 3*E =(5*10) + (3*1) + (6*0.1) +100 +(3*0.0001)
=50 + 3 + 0.6 + 100 + 0.003 = 153.6003.
Answer: C) 153.6003
Question: Alex takes a loan of $5,000 to buy a used truck at the rate of 2 % simple Interest.Calculate the annual interest to be paid for the loan amount.
A.100
B.150
C.720
D.200
Answer: A.100
Explanation: From the details given in the problem Principle = P = $5,000 and R = 2% or 0.02 expressed as a decimal.
As the annual Interest is to be calculated, the time period T =1.
Plugging these values in the simple Interest formula,
I = P x T x R
= 5,000 x 1 x 0.02
= 100.00
Annual Interest to be paid = $100
answer :A
Question: A can run a kilometer race in 4 1/2 min while B can run same race in 5 min. How many meters start can A give B in a kilometer race, so that the race mat end in a dead heat?
A.887 m
B.998 m
C.55 m
D.100 m
Answer: D.100 m
Explanation: A can give B (5 min - 4 1/2 min) = 30 sec start.
The distance covered by B in 5 min = 1000 m.
Distance covered in 30 sec = (1000 * 30)/300 = 100 m.
A can give B 100m start.
Answer:D
Question: A merchant marks goods up by 60% and then offers a discount on the marked price. The profit that the merchant makes after offering the discount is 20%. What % discount did the merchant offer?
A.20%
B.25%
C.30%
D.35%
Answer: B.25%
Explanation: Let P be the original price of the goods and let x be the rate after the markup.
(1.6P)*x = 1.2P
x = 1.2/1.6 = 0.75 which is a discount of 25%.
The answer is B.
Question: The cubic f(x) = x3 +bx2 +cx+d satisfies f(1) = 3, f(2) = 6, and f(4) = 12. Compute f(3).
A.6
B.7
C.8
D.9
Answer: B.7
Explanation: Note that f(x) - 3x = (x - 1)(x- 2)(x - 4), so f(x) = (x - 1)(x - 2)(x- 4) + 3x
and therefore f(3) = 2 *1 *(-1) + 9 = 7 .
correct answer B
Question: A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 54, what is the total amount?
A.234
B.116
C.117
D.118
Answer: A.234
Explanation: x:y:z = 100:45:50
20:9:10
9 --- 54
39 --- ? => 234
ANSWER:A
Question: The edge of a cube is 6a cm. Find its surface?
A.216a2
B.24a4
C.24a1
D.24a2
Answer: A.216a2
Explanation: 6a2 = 6 * 6a * 6a = 216a2
Answer:A
Question: 2, 7, 14, 23, ?, 47
A.31
B.28
C.34
D.33
Answer: C.34
Explanation: The given sequence is +5, +7, +9, ——
ie. 2+ 5 = 7, 7 + 7 = 14, 14 + 9 = 23
Missing Number = 23 + 11 = 34. ANSWER:C
Question: The average weight of a class of 24 students is 35 kg. If the weight of the teacher be included, the average rises by 400 g. The weight of the teacher is
A.45 kg
B.50 kg
C.53 kg
D.55 kg
Answer: A.45 kg
Explanation: Sol.
Weight of the teacher
= (35.4 × 25 – 35 × 24)kg
= 45 kg.
Answer A
Question: If a certain sample of data has a mean of 20.0 and a standard deviation of 2.0, which of the following values is more than 2.5 standard deviations from the mean?
A. 13.5
B. 12.0
C. 17.0
D. 23.5
Answer: B. 12.0
Explanation: The standard deviation is 2.0. 2.5 standard deviations, which is just 2.5 x 2.0 is 5.0. The only answer more than 6.0 away from the mean is B.
Question: a grazing land have length 200m and breadth 50m.there is grass 0.5kg/m2.
a cow graze 20kg grass daily.if cow graze for 20days.so after 20 days calculate the percentage of grass filled area.
A.90
B.92
C.95
D.85
Answer: B.92
Explanation: area of land=200*50=10000m2.
total grass grazed=400kg.
area grazed=400/0.5=800m2.
%of grass filled area=9200/10000*100=92%
answer B
Question: The product of three consecutive numbers is 120. Then the sum of the smallest two numbers is ?
A.9
B.15
C.20
D.38
Answer: A.9
Explanation: Product of three numbers = 120
120 = 2*2*5*6 = 4*5*6
So, the three numbers are 4,5 and 6.
And Sum of smallest of these two = 4 + 5 = 9.
ANSWER : OPTION A
Question: A money lender lent Rs. 800 at 3% per year and Rs. 1400 at 5% per year. The amount should be returned to him when the total interest comes to Rs. 350. Find the number of years.
A.3.5
B.3.72
C.4
D.4.25
Answer: B.3.72
Explanation: (800xtx3/100) + (1400xtx5/100) = 350 â†’ t =3.72 answer B
Question: If the sum of the 4th term and the 12th term of an arithmetic progression is 8, what is the sum of the first 15 terms of the progression?
A.60
B.120
C.160
D.240
Answer: A.60
Explanation: Let a = first term, d = common difference.
4th term = a+3d
12th term = a+11d
a+3d + a+11d = 8
2a + 14d = 8
a + 7d = 4.
Sum of the first 15 terms = 15/2 (2a + 14d) = 15 (a+7d) = 15 (4) = 60. Ans (A)
Question: If k is the sum of the digits of integer m, and m=12n, where n is an integer, which of the following must be true?
A.k is not divisible by 9
B.The sum of the digits of k is divisible by 3
C.m is a multiple of 2k
D.k is a multiple of 9
Answer: B.The sum of the digits of k is divisible by 3
Explanation: m= 12n i.e n =1,2,3 ,4 etc or -1,-2.-3 ,-4 then m =12,24,36,48 or -12 ,-24 ,-36 ,-48 then k 3,6 9,12 or -(1+2) , -(4+2) , -(3+6) ,-(4+8) .
ans B
Question: A certain roller coaster has 2 cars, and a passenger is equally likely to ride in any 1 of the 2 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 2 times, what is the probability that the passenger will ride in each of the 2 cars?
A.0
B.1/2
C.2/9
D.1/3
Answer: B.1/2
Explanation: If he is to ride 2 times and since he can choose any of the 2 cars each time, total number of ways is
= 2 * 2
= 4
Now the number of ways if he is to choose a different car each time is
= 2 * 1
= 2
So the probability is
= 2/4
= 1/2
Answer : B
Question: A train passes a bridge in 40 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
A.250
B.400
C.150
D.300
Answer: D.300
Explanation: Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/40 = 15 => x = 300 m.
Answer: D
Question: Six women can do a work in 10 days. Ten men can complete the same work in 4 days. What is the ratio between the capacity of a man and a woman?
A.1:2
B.2:1
C.2:3
D.3:2
Answer: D.3:2
Explanation: Explanation:
(6 Ã— 10) women can complete the work in 1 day.
âˆ´ 1 woman's 1 day's work = 1/60
(10 Ã— 4) men can complete the work in 1 day.
âˆ´ 1 man's 1 day's work = 1/40
so, required ratio =1/60 : 1/40= 3:2
Answer: D
Question: How many pounds of salt at 70 cents/lb must be mixed with 45 lbs of salt that costs 40 cents/lb so that a merchant will get 20% profit by selling the mixture at 48 cents/lb?
A.5
B.9
C.40
D.50
Answer: B.9
Explanation: Selling price is 48 cents/lb
For a 20% profit, cost price should be 40 cents/lb (CP*6/5 = 48)
Basically, you need to mix 40 cents/lb (Salt 1) with 70 cents/lb (Salt 2) to get a mixture costing 45 cents/lb (Salt Avg)
weight of Salt1/weight of Salt2 = (Salt2 - SaltAvg)/(SaltAvg - Salt1) = (70 - 45)/(45 - 40) = 5/1
We know that weight of salt 1 is 45 lbs. Weight of salt 2 must be 9 lbs.
Answer (B)
Question: A car covers a certain distance at a speed of 40 kmph in 5 hours. To cover the same distance in 2 hr, it must travel at a speed of?
A.100 km/hr
B.678 km/hr
C.782 km/hr
D.789 km/hr
Answer: A.100 km/hr
Explanation: Distance = (40 x 5) = 200 km
Speed = Distance/Time
Speed = 200/2 = 100 km/hr
Answer : A
Question: The product of two numbers is 266 and their difference is 5. What is the bigger number ?
A.67
B.26
C.26
D.19
Answer: D.19
Explanation: Explanation:
Let the two numbers be A and B, here A > B
AB = 266
B = 266/A -----------------(I)
Given,
A – B = 5 ----------- (II)
Substitute from (I) in (II), we get
A – 266/A = 5
A2 – 5A + 266 = 0
(A – 19)(A – 14) = 0
Therefore , A = 19 or A = 14
Hence, bigger number = A = 19
ANSWER: D
Question: If a trader sold two cars each at Rs. 325475 and gains 14% on the first and loses 14% on the second, then his profit or loss percent on the whole is?
A.1.44%
B.1.74%
C.1.84%
D.1.96%
Answer: D.1.96%
Explanation: SP of each car is Rs. 325475, he gains 14% on first car and losses 14% on second car.
In this case, there will be loss and percentage of loss is given by
= [(profit%)(loss%)]/100
= (14)(14)/100 % = 1.96%
Answer:D
Question: The average (arithmetic mean) weight of 5 friends is 150 pounds. If Joanne leaves the group and the new average of the group is 162 pounds. What is Joanne's weight?
A.60
B.78
C.102
D.105
Answer: C.102
Explanation: The average (arithmetic mean) weight of 5 friends is 150 pounds.
Let W be sum of weights of the four others. and J be Joanne's weight
(W + J)/5 = 150
When Joanne exits, the average is 162
W/4 = 162
W = 648
W + J = 750
J = 102
ANSWER:C
Question: Rob also compared the Empire State Building and the Petronas
Towers. What is the height difference between the two if the Empire
State Building is 443m tall and the Petronas Towers is 452m tall?
A.9
B.17
C.23
D.45
Answer: A.9
Explanation: 452-443=9.Answer is A.
Question: If $10 is invested at x percent simple annual interest for n years, which of the following represents the total amount of interest, in dollars, that will be earned by this investment in the n years?
A.10n(x/100)
B.10,000(x/100)^n
C.10,000n(x/100)
D.10,000(1+x/100)^n
Answer: A.10n(x/100)
Explanation: I think answer D is for compound interest (which i assumed)
and answer A is for simple interest because it is not compounding.
Question: 40 people are sitting around a circular table. Starting from 1 every 2nd person is killed. This process continues till only one person remains. How is the survivor? (Josephus riddle)
A.22
B.17
C.88
D.237
Answer: B.17
Explanation: Write the given number in Binary form: 101000
Shift the left digit to the right hand side: 010001
Convert this number into decimal and this could be the number of the survivor: 17
Sol 2: Write the given number as a sum of 2K + M where K should be maximum power less than the given number.
Survivor number is given by 2M + 1
this this case 40 < 25 + 8
So M =8, Survivor number = 2(8) + 1 = 17
Answer:B
Question: There are X girls in a class, and their average height is E inches. In the same class, there are Y boys with an average height of F inches. What is the average height of all the students in the class?
A.(X + Y)/(M + N)
B.(M + N)/(X + Y)
C.(XM + YN)/(M + N)
D.(XE + YF)/(X + Y)
Answer: D.(XE + YF)/(X + Y)
Explanation: Total height = XE+YF
No of students = X+Y
Avg = (XE+YF)/(X+Y)
Answer is D
Question: In a class of 25 students, 2 students did not borrow any books from the library, 10 students each borrowed 1 book, 8 students each borrowed 2 books, and the rest of the students each borrowed at least 3 books. If the average (arithmetic mean) number of books borrowed per student was 2, what is the maximum number of books that any single student could have borrowed ?
A.8
B.10
C.12
D.13
Answer: C.12
Explanation: The average number of books per student was 2means that total of 2*25=50 books were borrowed;
2+10+8=20 students borrowed total of 2*0+10*1+8*2=26 books;
So 50-26=24 books are left to distribute among 25-20=5 students, these 5 arethe rest who borrowed at least 3 books;
Tomaximizethe number of books one student from above 5 could have borrowed we shouldminimizethe number of books other 4 students from 5 could have borrowed. Minimum these 4 students could have borrowed is 4 books per student, so total number of books they could have borrowed is 4*3=12 books. So the 5th student could have borrowed is 24-12=12 books.
Answer: C.
Question: AB + CD = JJJ, where AB and CD are two-digit numbers and JJJ is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?
A. 1
B. 3
C. 7
D. 9
Answer: D. 9
Explanation: AB and CD are two digit integers, their sum can give us only one three digit integer of a kind of JJJ it's 111.
So, A=1. 1B+CD=111
Now, C can not be less than 9, because no to digit integer with first digit 1 (mean that it's<20) can be added to two digit integer less than 90 to have the sum 111 (if CD<90 meaning C<9 CD+1B<111) --> C=9
Answer: D.
Question: A single discount equivalent to the discount series of 20%, 15% and 5% is?
A.31.6
B.35.4
C.31.6
D.31.1
Answer: B.35.4
Explanation: 100*(80/100)*(85/100)*(95/100)
= 68.4
100 - 64.6 = 35.4
Answer: B
Question: 325.124 x 12.98 Ã· 3.001 + 21.21 = ?
A.1430.08
B.1420.06
C.781.189
D.656.112
Answer: A.1430.08
Explanation: Explanation:
? = 325.124 x 12.98 Ã· 3.001 + 21.21 = ?
â‰ˆ (325.124 x 13/3) + 21.21 â‰ˆ 1408.87 + 21.21 â‰ˆ 1430.080
Answer: Option A
Question: There is food for 760 men for 22 days. How many more men should join after two days so that the same food may last for 19 days more?
A.16
B.40
C.18
D.19
Answer: B.40
Explanation: 760 ---- 22
760 ---- 20
x ----- 19
x*19 = 760*20
x = 800
760
-------
40
Answer:B
Question: Suresh and Ramesh started a business investing Rs. 24,000 and Rs. 40,000 respectively. Out of total profit of Rs. 19,000, what is Suresh's share?
A.s. 7125
B.s. 8125
C.s. 9125
D.s. 9372
Answer: A.s. 7125
Explanation: Explanation:
Ratio of Suresh and Ramesh's share = 24,000 : 40,000 = 3 : 5
Suresh's share = Rs. (19000 x 3 / 8) = Rs. 7125
ANSWER: A
Question: The difference between simple interest and C.I. at the same rate for Rs.5000 for 2 years in Rs.72. The rate of interest is?
A.11
B.12
C.77
D.85
Answer: B.12
Explanation: 5000 = 72(100/R)2
5 R2 = 720 => R = 12.Answer:B
Question: If (t-8) is a factor of t^2-kt-43, then k=
A.16
B.12
C.2
D.3
Answer: D.3
Explanation: t^2-kt-48 = (t-8)(t+m) where m is any positive integer.
if 48/8 = 6, then we know as a matter of fact that:
m = +6
and thus k = 8-6 = 3
t^2-kt-m = (t-a)(t+m) where a>m
t^2+kt-m = (t-a)(t+m) where a<m
t^2-kt+m = (t-a)(t-m)
t^2+kt+m = (t+a)(t+m)
D
Question: Find the compound interest on Rs. 10000 at 12% rate of interest for 1 year, compounded half-yearly
A.Rs. 1036
B.Rs. 1236
C.Rs. 1186
D.Rs. 1206
Answer: B.Rs. 1236
Explanation: Amount with CI = 10000 [1+ (12/2 * 100)]2 = Rs. 11236
Therefore, CI = 11236 – 10000 = Rs. 1236 ANSWER :B
Question: In how many no. between 100 and 1000 exactly one of the digits is 3?
A. 648
B. 512
C. 252
D. 225
Answer: D. 225
Explanation: Another approach can be
total nos. between 100 and 1000 are 899
nos. in which all digits are 3 = 1
nos. in which digit 3 is in two places = 8 + 9 + 9 = 26 (for thousand , tens and once as different digit)
nos. in which no digit is 3 = 8*9*9 - 1 = 648 - 1 (for 100 not to be included)
required nos = 899 - 1 - 26 - 647 = 225
answer is D
Question: a manufacturing company has 15% cobalt ,25% led and 60% of copper. if 5kg of led is used in a mixture how much copper we need to use
A.12 kg
B.13 kg
C.22 kg
D.14 kg
Answer: A.12 kg
Explanation: 25%=5kg
100%=20kg
60% of 20 kg= 12kg
12 kg
ANSWER:A
Question: A boy has nine trousers and 15 shirts. In how many different ways can he select a trouser and a shirt?
A.88
B.98
C.106
D.135
Answer: D.135
Explanation: Explanation:
The boy can select one trouser in nine ways.
The boy can select one shirt in 15 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 15 = 135 ways
D)
Question: A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
A.5.2 km/hr.
B.8.2 km/hr.
C.7.2 km/hr.
D.3.2 km/hr.
Answer: C.7.2 km/hr.
Explanation: C
7.2 km/hr.
Speed=(600/5 * 60) m/sec
= 2 m/sec.
Converting m/sec to km/hr
=(2*18/5) km/hr
= 7.2 km/hr.
Question: The expression (3x-2)/(x+3) is equivalent to which of the following?
A.(5-2)/3
B.5 – (2/3)
C.3 – (11)/(x+3)
D.5 – (17)/(x+3)
Answer: C.3 – (11)/(x+3)
Explanation: Easiest way is to pick any number and put in (3x-2)/(x+3). Then check the options with the same number.
I took x=1 and got C as the answer.
Question: A completes 80% of a work in 20 days. Then B also joins and A and B together finish the remaining work in 3 days. How long does it need for B if he alone completes the work?
A.35 1/2
B.36 1/2
C.37 1/2
D.38 1/2
Answer: C.37 1/2
Explanation: Explanation:
Work done by A in 20 days = 80/100 = 8/10 = 4/5
Work done by A in 1 day = (4/5) / 20 = 4/100 = 1/25 --- (1)
Work done by A and B in 3 days = 20/100 = 1/5 (Because remaining 20% is done in 3 days by A and B)
Work done by A and B in 1 day = 1/15 ---(2)
Work done by B in 1 day = 1/15 â€“ 1/25 = 2/75
=> B can complete the work in 75/2 days = 37 (1/2) days
ANSWER IS C
Question: In a 100m race, Sam beats John by 4 seconds. On the contrary, if Sam allowed John to start 24m ahead of Sam, then Sam and John reach the finishing point at the same time. How long does Sam take to run the 100m race?
A.4 seconds
B.25 seconds
C.19 seconds
D.21 seconds
Answer: C.19 seconds
Explanation: Their difference is 4 second but this difference is 0 if john allows Sam to start the race from 24m ahead . that means Jhon was 24m away from finishing line when they started together . so He will cover 24 m in 4 seconds . so his speed =24/4=6 metre / second . so time taken =100/4=25 seconds . so Sam took = 19 seconds .
correct answer = C
Question: A sum of 13,400 amounts to 14,400 in 2 years at the rate of simple interest. What is the rate of interest?
A.2%
B.1%
C.6%
D.4%
Answer: D.4%
Explanation: D
4%
S.I. = (14400 - 13400) = 1000.
Rate = (100 x 1000)/(13400x2)% = 4%
Question: The rate of Interest on a sum of money is 5% p.a. for the first 3 years, 4% p.a. for the next 4 years, and 5% for the period beyond 7 years. If the S.I, Occured on the sum for the total period of 8 years is Rs. 540/-, the sum is
A.1,500
B.2,000
C.2,100
D.2,250
Answer: A.1,500
Explanation: Explanation:
I1 = (P x 3 x 5)/100 = 3P/20
I2 = (P x 4 x 4)/100 = 4P/25
I3 = (P x 1 x 5)/100 = P/20
3P/20 + 4P/25 + P/20 = 540
9P/25 = 540
P = 1500
Answer: Option A
Question: Find 60/42*4
A.14.7653
B.0.5897
C.3.6974
D.0.3571
Answer: D.0.3571
Explanation: Answer=60/42*4
=60/168=0.3571
Option D is correct
Question: A family consists of two grandparents, two parents and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of the family?
A.31 5/7
B.32
C.33
D.35
Answer: A.31 5/7
Explanation: Required average
= 67 x 2 + 35 x 2 + 6 x 3
2 + 2 + 3
= 134 + 70 + 18
7
=	222
7
= 31 5	years.
7
Option A
Question: When the smallest of 3 consecutive odd integers is added to four times the largest, it produces a result 732 more than 4times the middle integer. Find the numbers?
A.732
B.678
C.698
D.710
Answer: A.732
Explanation: x + 4 (x + 4) = 732 + 4 (x + 2)
Solve for x and find all three numbers
x + 4 x + 16 = 732 + 4 x + 8
x = 724
x + 2 = 726
x + 4 = 728
Check: the smallest is added to four times the largest
724 + 4 * 728 = 3636
four times the middle
4 * 726 = 2904
3636 is more than 2904 by
3636 - 2904 = 732
A
Question: A certain company retirement plan has arule of 70provision that allows an employee to retire when the employee's age plus years of employment with the company total at least 70. In what year could a female employee hired in 1989 on her 32nd birthday first be eligible to retire under this provision?
A.2008
B.2004
C.2005
D.2006
Answer: A.2008
Explanation: She must gain at least 70 points, now she has 32 and every year gives her two more points: one for age and one for additional year of employment, so 32 + 2*(# of years) = 70 --> (# of years) = 19 --> 1989+19=2008.
Answer: A.
Question: A and B complete a work in 10 days. A alone can do it in 14 days. If both together can do the work in how many days?
A.3.75 days
B.5.8 days
C.4.5 days
D.4.7 days
Answer: B.5.8 days
Explanation: 1/10 + 1/14 =6/35
35/6 = 5.8 days
Answer:B
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12300 after a year?
A.3630
B.3690
C.3630
D.3631
Answer: B.3690
Explanation: 6300:4200:10500
3:2:5
3/10 * 12300 = 3690
Answer: B
Question: At the start of an experiment, a certain population consisted of 3 animals. At the end of each month after the start of the experiment, the population size was double its size at the beginning of that month. Which of the following represents the population size at the end of 11 months?
A. 2^3
B. 3^2
C. 2(3^10)
D. 3(2^11)
Answer: D. 3(2^11)
Explanation: 3*2^n where n is the #of month --> 3*2^11 Answer (D)
Question: If n is the product of three consecutive integers, and n is divisible by 5, which of the following is not necessarily a divisor of n ?
A.210
B.220
C.230
D.240
Answer: A.210
Explanation: IF ONE NO. IS 5 THEN OTHER CONSEQUTIVE NO. ARE 3*4*5 =60 , 4*5*6=120 , 5*6*7 =210
210 WILL NO BE DIVISOR OF N
A
Question: If 280 people, constituting 5 percent of the population of a town, ride bicycles, and the others do not, then how many people in the town do not ride bicycles?
A.5930
B.5600
C.5320
D.5110
Answer: C.5320
Explanation: 5 % of X is 280
5/100 * X = 280
X = 280*100/5 = 5600
So C. 5320 is the correct Answer
No. of people Not Riding Bike = 5600 - 280 = 5320
answer is C
Question: In one hour, a boat goes 14 km/hr along the stream and 8 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
A.12 km/hr
B.11 km/hr
C.10 km/hr
D.8 km/hr
Answer: B.11 km/hr
Explanation: EXPLANATION
Let speed of the boat in still water = a and speed of the stream = b
Then
a + b = 14
a - b = 8
Adding these two equations, we get 2a = 22
=> a = 11
ie, speed of boat in still water = 11 km/hr
ANSWER IS B
Question: 50 square stone slabs of equal size were needed to cover a floor area of 72 sq.m. Find the length of each stone slab?
A.120cm
B.767cm
C.88cm
D.666cm
Answer: A.120cm
Explanation: Area of each slab
=72/50m2=1.44m2
Length of each slab √1.44=1.2m=120cm
Question: If one of the followings is the product of the two 3-digit integers 8K1 and 6L5 (K and L denote the tens digit of the respective integers), then that product must be
A. 478,823
B. 511,913
C. 531,875
D. 538,424
Answer: C. 531,875
Explanation: To know the unit digit you can multiply both digit number: 1 x 5 = 5
This eliminates A, B, D, and E, because the number must end with a 5
So the answer is C
Question: If a: b = 6:4, b: c =7: 8, find a: b: c?
A.24: 28: 32
B.42: 28: 36
C.42: 28: 38
D.42: 28: 32
Answer: D.42: 28: 32
Explanation: a: b = 6:4
b: c =7: 8
a: b: c = 42: 28: 32
Answer : D