RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Find a two digit number, given that the sum of the digits is 12 and the difference of the digits is 6.?
A.41
B.46
C.42
D.46
Answer: A.41
Explanation: Using elimination method find which of the options fit the description of the number
... from the option only 41 meets this description
sum of digits---4+1 = 5
difference of digits ---4-1 = 3
Answer A.
Question: Rs. 9800 are invested partly in 9% stock at 75 and 10% stock at 80 to have equal amount of incomes. The investment in 9% stock is:
A.5000
B.4500
C.5400
D.5600
Answer: A.5000
Explanation: Let the investment 9% stock rs x
then investment in 10% stock = rs(9800-x)
9/75 xx = 10/80 *(9800-x)
3x/25 = 9800 - x
x=5000
ANSWER A
Question: If y = 2 + 2K and y≠0y≠0, then 3/y + 2/y + 2/y + 1/y = ?
A.1/(8+8k)
B.4/(1+k)
C.1/(8+k)
D.4/(8+k)
Answer: B.4/(1+k)
Explanation: 3/Y + 2/Y + 2/Y + 1/Y
= 8/Y
= 8/(2 + 2K)
= 4/(1 + K)
ANSWER:B
Question: A family pays $850 per year for an insurance plan that pays 80 percent of the first $1,000 in expenses and 100 percent of all medical expenses thereafter. In any given year, the total amount paid by the family will equal the amount paid by the plan when the family's medical expenses total.
A.$1,000
B.$1,250
C.$1,400
D.$1,800
Answer: B.$1,250
Explanation: Upfront payment for insurance plan = 850$
Family needs to pay 20 % of first 1000 $ in expense = 200$
Total amount paid by family when medical expenses are equal to or greater than 1000 $ = 850 + 200 = 1050 $
Total amount paid by insurance plan for first 1000 $ = 850 $
Total amount paid by family will equal amount paid by plan when medical expense = 1250 $
(Since insurance plan will pay 100% of amount that exceeds 1050$ )
Answer B
Question: The square root of (7 + 3âˆš5) (7 - 3âˆš5) is
A.âˆš5
B.2
C.4
D.3âˆš5
Answer: B.2
Explanation: Explanation:
âˆš(7 + 3âˆš5)(7 - 3âˆš5)	=	âˆš(7)2 - (3âˆš5)2 = âˆš49 - 45 = âˆš4 = 2.
ANSWER IS B
Question: The diagonals of a rhombus are 12 cm and 20 cm. Find its area?
A.329
B.288
C.120
D.238
Answer: C.120
Explanation: 1/2 * 12 * 20 = 120
Answer: C
Question: If X = the product of six distinct prime numbers, how many factors does X have besides 1 and itself?
A.50
B.56
C.62
D.68
Answer: C.62
Explanation: Since X has 6 distinct prime factors, X has a total of 2^6 = 64 factors.
Besides 1 and itself, X has 62 factors.
The answer is C.
Question: 180 college students were asked in a survey if they preferred Windows or Mac brand computers. 50 Students claimed that they preferred Mac to Windows brand computers. One third as many of the students who preferred Mac to Windows, equally preferred both brands. 60 of the students had no preference. How many of the students in the survey preferred Windows to Mac brand computers?
A.25
B.70
C.50
D.60
Answer: B.70
Explanation: 180 = 50(Mac) + x(Window) + 60(both) => x=70
ANSWER:B
Question: Two integers x and y are chosen without replacement out of the set {1, 2, 3,......, 10}. Then the probability that x^y is a single digit number.
A.11/90
B.13/90
C.17/90
D.19/90
Answer: D.19/90
Explanation: it can take 9 values when x=1..
it can take another 8 values when y=1..
when x=2, y=3 as other values already considered..
when x=3, y=2 as other values already considered.. total-19 values so prob=19/90
ANSWER:D
Question: There are 3 black cards, 2 white cards, and 7 green cards, in a box. What is the least number of cards that you have to pull out to make sure that you will have a matching pair?
A.8
B.4
C.5
D.12
Answer: B.4
Explanation: Since there are 3 colors, if you take 3 cards, you could still have 1 card per color and not have a match.
Therefore, upon taking the 4th card, you will definitely have a match since the 4th card will form at least a pair with the 1st 3
So 3+1 = 4
Answer is B
Question: A distributor sells a product through an online store, which take a commission of 20% of the price set by the distributor. The distributor obtains the product from a producer at the price of $18 per item. What is the price that the buyer observers online if the distributor wants to maintain a 20% profit on the cost of the item?
A.$25
B.$26
C.$27
D.$28
Answer: C.$27
Explanation: Let x be the price that buyers see online.
The distributor wants to receive 1.2(original price) which should be 80% of x.
1.2(18) = 0.8x
x = 1.2(18) / 0.8 = 1.5(18) = $27
The answer is C.
Question: If a - b = 3 and a^2 + b^2 = 29, find the value of ab.
A.5
B.10
C.12
D.14
Answer: B.10
Explanation: 2ab = (a^2 + b^2) - (a - b)^2
= 29 - 9 = 20
ab = 10.
B)
Question: An automotive test consisted of driving a car the same distance three separate times, first at an average rate of 50 miles per hour, then 60 miles per hour, then 80 miles per hour. If the test took 30 hours to complete, how many miles was the car driven during the entire test?
A.1500
B.1830
C.1645
D.1562
Answer: B.1830
Explanation: let x be the distance..
so time taken by three cars is x/50,x/60,x/80... total time taken= x/50+x/60+x/80=x*59/1200 =30(given)
x=610... total =3x=1830
Answer is B
Question: The ratio of the money with Rita and Sita is 7:15 and that with Sita and Kavita is 7:16. If Rita has $490, how much money does Kavita have?
A.$1500
B.$1800
C.$2000
D.$2400
Answer: D.$2400
Explanation: Rita : Sita : Kavita
7 : 15
7 : 16
49 : 105 : 240
The ratio of money with Rita, Sita and Kavita is 49:105:240
We see that 49 = $490
Then 240 = $ 2400
Answer is D
Question: In August,a cricket team that played 120 matches won 22% of the games it played.After a continuous winning streak,this team raised its average to 52%.How many matches did the team win to attain this average?
A.40
B.52
C.68
D.75
Answer: D.75
Explanation: let the no of matches played more=x
so,
(120+x)*52/100=26.4+x
by solving we get x=75
ANSWER:D
Question: What is the least number that should be added to 1055, so the sum of the number is divisible by 23?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: (1055 / 23) gives a remainder 20 so we need to add 3.
The answer is C.
Question: If (5 - x)/(5 + x) = x, what is the value of x^2 + 6x - 5?
A.-6
B.-4
C.-2
D.0
Answer: D.0
Explanation: (5-x) = x*(5+x)
(5-x) = 5x+x^2
0 = x^2+6x-5
The answer is D.
Question: If x and a are integers and (15^x + 15^(x+1))/4^a = 15^a what is the value of x?
A.2
B.3
C.4
D.5
Answer: A.2
Explanation: \frac{15^x( 1+ 15)}{4^a} = 15^a
(15^x . 4^2 ) / 4^a = 15^a. 4^0
15^x . 4^(2-a) = 15^a. 4^0
Equating the powers, x = a; 2-a = 0; So x = a = 2=A
Question: If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is ?
A.1/4
B.1/2
C.1/8
D.1/6
Answer: B.1/2
Explanation: The number of exhaustive outcomes is 36.
Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2
P(E) = 1 - 1/2 = 1/2.
Answer: B
Question: Pointing to a girl in the photograph, Amar said, "Her mother's brother is the only son of my mother's father." How is the girl's mother related to Amar ?
A.Mother
B.Sister
C.Aunt
D.Grandmother
Answer: C.Aunt
Explanation: Explanation:
Only son of Amar's mother's father — Amar's maternal uncle.
So, the girl's maternal uncle is Arnar's maternal uncle. Thus, the girl's mother is Amar's aunt.
Answer: C
Question: Roy was suffering from severe headaches. He went to see his doctor and the doctor gave him five tablets asking him to take one tablet every 15 minutes.
How much time will it take Roy to consume all the five tablets?
A.60 min
B.50 min
C.70 min
D.65 min
Answer: A.60 min
Explanation: A
60 min
Roy will be able to consume all the five tablets in an hour.
Tablet 1 will be taken in 0 min.
Tablet 2 will be taken in 15 min.
Tablet 3 will be taken in 30 min.
Tablet 4 will be taken in 45 min.
Tablet 5 will be taken in 60 min.
Question: In a shop, 40% socks are white and rest are black. 60% socks are made of cotton and rest are made of wool. 25% white socks are made of cotton and 20 of the black socks are made of wool. How many black socks C are made of cotton?
A.100
B.80
C.60
D.50
Answer: A.100
Explanation: I'll prefer to solve this with plug n play method.
As we know, White Cotton socks are only 25% and Total Cotton socks is 60% - Hence Black Cotton socks C has to be [highlight]HIGH[/highlight]number. Thats why we've to pick high number... say 100 or 80.
100 fits perfectly after relevant calculations. Hence answer A.
Question: The speed of a boat in still water is 80kmph and the speed of the current is 30kmph. Find the speed downstream and upstream?
A.76,28 kmph
B.110,30 kmph
C.29,25 kmph
D.26,10 kmph
Answer: B.110,30 kmph
Explanation: Speed downstream = 80 + 30
= 110 kmph
Speed upstream = 80 - 30
= 50 kmph
Answer: B
Question: On flipping 3 coins together what is the outcomes for at least two heads?
A.{HHH, HHT, HTH, THH}
B.{HHT, HHT, HTH, THH}
C.{TTH, HHT, HTH, THH}
D.{TTT, HHT, HTH, THH}
Answer: A.{HHH, HHT, HTH, THH}
Explanation: Sample space, S = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}
Favorable outcomes for at least two heads
= favorable outcomes for exactly two heads and favorable outcomes for more than two heads
= {HHH, HHT, HTH, THH}
A
Question: If the price of gold increases by 50%, find by how much the quantity of ornaments must be reduced, so that the expenditure may remain the same as before?
A.331/8%
B.331/3%
C.381/3%
D.231/3%
Answer: B.331/3%
Explanation: 100
150
------
150-------50
100-------? => 331/3%
Answer: B
Question: Rs. 730 were divided among Punith, Michael, Suresh in such a way that if Punith gets Rs. 3, then Michael gets Rs. 4 and if Michael gets Rs. 3.50 then Suresh gets Rs. 3. The share of Michael exceeds that of Suresh by
A.Rs 30
B.Rs 40
C.Rs 70
D.Rs 210
Answer: B.Rs 40
Explanation: Explanation :
Let A = Punith, B = Michael, C = Suresh.
A:B = 3:4 and B:C = 7/2:3 = (8/7)*(7/2)*(8/7)*3 = 4:(24/7)
A : B : C = 3 :4: 24/7 = 21 : 28 : 24.
Bs share = Rs. [730 *(28/73)]= Rs. 280.
Cs share = Rs. [730 * (24/73)] = Rs. 240.
Difference of their shares = 40
Answer : B
Question: A clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 11 AM, what will be the time at the end of 10 days?
A.11:54:40 AM
B.11:56:24 AM
C.12:16:40 PM
D.11:54:24 AM
Answer: D.11:54:24 AM
Explanation: Clock loses: 1 minute in 3 hours = 8 minutes in 24 hours = 32 minutes in 4 days.
Clock gains: 1% in the subsequent 6 days = 1% in 6*24*60 minutes = 86.40 minute in 6 days;
Net gain in 10 days = 86.40 - 32 = 54.4 minutes.
11AM + 54.4 minutes = 11:54 and 4/10th of a minute or 24 seconds.
Answer: D.
Question: P is three times as old as Q. In 10 years, P will be twice as old as Q. How old was P three years ago?
A.27
B.30
C.33
D.36
Answer: A.27
Explanation: P = 3Q so Q = P/3
P+10 = 2(Q+10) = 2(P/3+10)
P/3 = 10
P = 30
Three years ago, P was 27.
The answer is A.
Question: A trader bought a car at 20% discount on its original price. He sold it at a 40% increase on the price he bought it. What percent of profit did he make on the original price?
A.17%
B.72%
C.12%
D.82%
Answer: C.12%
Explanation: Original price = 100
CP = 80
S = 80*(140/100) = 112
100 - 112 = 12%
Answer:C
Question: The true discount on a bill of Rs. 2260 is Rs. 360. What is the banker's discount?
A.Rs. 428
B.Rs. 422
C.Rs. 412
D.Rs. 442
Answer: A.Rs. 428
Explanation: Explanation :
F = Rs. 2260
TD = Rs. 360
PW = F - TD = 2260 - 360 = Rs. 1900
True Discount is the Simple Interest on the present value for unexpired time
=>Simple Interest on Rs. 1900 for unexpired time = Rs. 360
Banker's Discount is the Simple Interest on the face value of the bill for unexpired time
= Simple Interest on Rs. 2260 for unexpired time
=360/1900 × 2260 = 0.19 × 2260 = Rs. 428 Answer : Option A
Question: If n = 20! + 19, then n is divisible by which of the following?
I. 15
II. 17
III. 19
A.I only
B.II only
C.III only
D.I and II
Answer: C.III only
Explanation: 19 divides 20! so 19 also divides 20! + 19.
15 and 17 divide 20! so they do not divide 20! + 19.
The answer is C.
Question: A can fill the tank in 28hrs
B can fill the tank in 14 hrs
and C takes 7hrs.
If all three pipes are opened simultaneously ,how long it will take to fill the tank?
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: Solution:time taken=(28*14*7*)/(28*14 + 14*7 + 28*7)
To solve this quicker find out LCM(28,14,7)
we get 28
Time taken =28/(28/28 + 28/14 + 28/7)
=28/(1+2+4)
=28/7
=4
Answer A
Question: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
A.100
B.110
C.112
D.115
Answer: A.100
Explanation: Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Question: Three friends (Amar, Mohan and Sham) started partnership business by investing Rs. 1,00,000, Rs. 1,40,000 and Rs. 1,60,000 respectively. After eight months, Ramesh joins them with his capital of Rs. 50,000. If, at the end of the year, a profit of Rs. 30,500 was made, what would be the difference between the shares of Sham and Mohan?
A.1464
B.1462
C.2679
D.2776
Answer: A.1464
Explanation: Explanation:
Amar invests Rs. 1,00,000 for 12 months : Mohan invests Rs. 1,40,000 for 12 months : Sham invests Rs.1,60,000 for 12 months : Ramesh invests Rs. 50,000 for 4 months
Amar : Mohan : Sham : Ramesh = 30 : 42 : 48 : 5
Sham's share = (48/125) * 30,500 = 11712
Mohan's share = (42/125) * 30,500 = 10248
Difference between shares of Sham's and Mohan's = 1464
ANSWER: A
Question: the total age of A and B is 12 year more than the total age of B and C. C is how many years younger than A ?
A.12
B.24
C.data inadequate
D.None of these
Answer: A.12
Explanation: Solution
(A + B ) - (B + C) = 12 ⇔ A - C = 12. Answer A
Question: Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 110 mangoes.
A.367
B.380
C.400
D.406
Answer: A.367
Explanation: Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 120 mangoes.
Method 1:
Let price per mango = x. Let number of mangoes be n. Then, nx = 360.
Now price = 0.9x; number of mangoes = n + 12. Total amount = 0.9x*(n+12) = 360.
nx = 0.9nx + 10.8x => 0.1nx = 10.8x => n = 108 => x = 360/108 = 3.33
Original price of 110 mangoes = 110*3.33 = 367.
Answer A
Question: 5+3+2 = 151022
9+2+4 = 183652
8+6+3 = 482466
5+4+5 = 202541
THEN ;
7+2+5 = ?
A.253547
B.143681
C.143547
D.147614
Answer: C.143547
Explanation: C
143547
Question: In a mayoral election, Candidate X received 1/4 more votes than candidate Y, and Candidate Y received 1/6 fewer votes than Z. If Z received 24,000 votes how many votes did candidate X received?
A.18000
B.22000
C.24000
D.25000
Answer: D.25000
Explanation: Z=24 --> Y received 1/4 fewer votes than Z --> Y=Z-1/6*Z=20;
X received 1/4 more votes than Y --> X=Y+1/4*Y=25.
Answer: D.
Question: The average (arithmetic mean) of 20, 40, and 60 is 5 more than the average of 10, 70, and what number?
A.15
B.25
C.35
D.45
Answer: B.25
Explanation: a1 = 120/3 = 40
a2 = a1 -5 = 35
sum of second list = 35*3 = 105
therefore the number = 105 -80 = 25
ANSWER:B
Question: There are, in a certain league, 8 teams, and each team face another team for a total of 12 times. How many games are played in the season?
A.150
B.121
C.144
D.180
Answer: C.144
Explanation: By using the formula, t[n(n - 1) / 2], where t = no. of games between two teams and n = total no. of teams, we get: 144
Option C.
Question: Six years ago I was three times as old as my brother, and now I am twice as old my brother. Find my brother's age.
A.8 years
B.24 years
C.12 years
D.16 years
Answer: B.24 years
Explanation: Let brother's age = x
And my age = 2x
6 years ago:
Brother age = x-6
My age = 2x-6
I was 3 time his age then,
2x-6 = 3(x-6)
2x-6 = 3x-18
3x-2x = 18-6
x = 12
Brother's age = 12years
My age now = 2x
= 2(12)
= 24years
ANSWER:B
Question: A and B can do a piece of work in 3 days, B and C in 4 days, C and A in 5 days. How long will C take to do it?
A.120/7 days
B.110/11 days
C.100/9 days
D.90/13 days
Answer: A.120/7 days
Explanation: 2c = 1/4 + 1/5 – 1/3 = 7/60
c = 7/120 => 120/7 days
The answer is A.
Question: The simple interest accrued on an amount of Rs.49500 at he end of three is Rs.17820. What would be the compound interest accured on the same amount at teh same rate in the same period? (Round off your answer to two decimal places)?
A.Rs.20043.94
B.Rs.20043.97
C.Rs.20043.99
D.Rs.20043.90
Answer: A.Rs.20043.94
Explanation: Let the rate of interest be R% p.a.
(49500)(3)(R)/100 = 17820
495R = 5940
R = 12
CI on Rs.49500 at 12% p.a. for three years
= 49500{[1 + 12/100]3 - 1} = 69543.936 - 49500 = Rs.20043.94
when rounded off to two decimal places.
Answer:A
Question: To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present ?
A.62.5
B.65
C.61
D.64
Answer: A.62.5
Explanation: Let the capacity of 1 bucket = x.
Then, the capacity of tank = 25x.
New capacity of bucket = 2/5 x
Therefore, Required number of buckets = (25x)/(2x/5)
= (25x) x 5/2x
= 125/2
= 62.5
Answer is A.
Question: A man borrowed Rs. 800 at 10% per annum simple interest and immediately lent the whole sum at 10% per annum compound interest. What does he gain at the end of 2 years ?
A.Rs. 6
B.Rs. 8
C.Rs. 10
D.Rs. 12
Answer: B.Rs. 8
Explanation: S.I FOR RS.800 FR 2 YEARS IS RS.160, WHEREAS AMOUNT IS 168 RS. HENCE GAIN IS 168-160=8
ANSWER:B
Question: For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 90 units raises the average to 52 units per day, what is the value of n ?
A.30
B.19
C.10
D.9
Answer: B.19
Explanation: (average production for n days) * n = (total production for n days) --> 50n=(total production for n days);
(total production for n days) + 90 = (average production for n+1 days) * (n+1) --> 50n + 90 = 52 * (n+1) --> n=19.
Or as 40 extra units increased the average for n+1 days by 2 units per day then 40/(n+1)=2 --> n=19.
Answer:B.
Question: A dishonest dealer professes to sell his goods at Cost Price but still gets 20% profit by using a false weight. What weight does he substitute for a kilogram?
A.855 1/2 grams
B.833 1/3 grams
C.833 1/2 grams
D.875 2/7 grams
Answer: B.833 1/3 grams
Explanation: If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.
If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm ------ 100 gm
1000 gm ------ ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams.
ANSWER:B
Question: A starts a business with a capital of Rs. 5,000. B joins in the business with Rs.2000 after some time. For how much period does B join, if the profits at the end of the year are divided in the ratio of 3 : 1?
A.5 months
B.6 months
C.7 months
D.10 months
Answer: D.10 months
Explanation: Explanation :
Let B joins for x months. Then
A:B = 5000*12 : x* 2000 = 3 : 1
=> 5*12 : 2x= 3 : 1
=> 5*12/ 2x = 3/1 = 3
=> 5*4 /2x = 1
=> 10/x = 1
=> x = 10. Answer : Option D
Question: A is half good a work man as B and together they finish a job in 14 days. In how many days working alone B finish the job?
A.23
B.22
C.21
D.36
Answer: C.21
Explanation: C
21
WC = 1:2
2x + x = 1/14 => x = 1/42
2x = 1/21 => 21 days
Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
A.10.9
B.10.7
C.10.3
D.10.8
Answer: D.10.8
Explanation: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5 = 10.8 sec.
'Answer: D
Question: There has been successive increases of 20% and then 10% in the price of gas from the previous month. By what percentage should a driver reduce gas consumption so that the expenditure does not change?
A.16%
B.20%
C.24%
D.28%
Answer: C.24%
Explanation: Let P be the original price per unit of gas.
Let x be the original gas consumption.
Let y be the reduced gas consumption.
y*1.1*1.2*P = x*P
y = x / (1.1*1.2) which is about 0.76x which is a decrease of about 24%.
The answer is C.
Question: The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 17 terms of the arithmetic progression?
A.300
B.120
C.150
D.170
Answer: D.170
Explanation: n th term of A.P. is given by a+(n-1)d
4 th term = a+3d
12 th term = a+11d
Given a+3d+a+11d=20 --> 2a+14d=20 --> a+7d = 10
Sum of n term of A.P = n/2[2a+(n-1)d]
subsitiuing n = 17 ...we get 17/2[ 2a + 14d] = 17 [a+7d] = 17*10 = 170...
Answer is D...
Question: What is the least number which when divided by 6, 7, 9 and 18 leaves remainder 4 in each care?
A.130
B.140
C.136
D.156
Answer: A.130
Explanation: Explanation:
LCM of 6, 7, 9 and 18 is 126
Required number = 126 + 4 = 130
Answer: Option A
Question: If x, y, and z are consecutive positive integers greater than 1, not necessarily in that order, then which of the following is (are) true?
I. x > z
II. 2(x+ y) > 2z
III. yz > xz
IV. xy > y + z
A. I only
B. II only
C. II and III only
D. II and IV only
Answer: B. II only
Explanation: we do not know the values or the relative values but that the three are consecutive..
so the max difference in any two number is 2 and min 1..
lets see the choices..
I. x > z...
we do not know the values or the relative values... need not be true..
II. 2(x+ y) > 2z or x+ y > z
we take the worst case that z is teh largest and x and y are lowest possible..... so 2+3>4.. 5>4.. always true
III. yz > xz
we do not know the values or the relative values between x and y..need not be true
IV. xy > y + z
xy-y>z or y(x-1)>z...
again lets take the worst scenario..
we take the worst case that z is the largest and x and y are lowest possible..... so (2-1)3>4.. 3>4.. not true
only ii is true
ans B
Question: If Rs 1050 is divided into three parts, proportional to (1 / 3) : (3 / 4) : ( 4 / 6), then what is the first part?
A.500
B.300
C.200
D.100
Answer: C.200
Explanation: EXPLANATION:
Given:
1050 =	1/3	:	3/4	:	4/6
1) L.C.M. of 3, 4 and 6 is 12
Therefore, multiply numerator and denominator of (1/3) with 4, to obtain denominator 12. Similarly multiply (3/4) with 3 and (4/6) with 2
4/12	:	9/12	:	8/12 = 4 : 9 : 8
2) If a number a is divided in three ratios x : y : z,
First Part:	ax/(x + y + z) ------- (a is the number divided)
Therefore,
First Part:	(1050 x 4) /(4 + 9 + 8)=200
ANSWER IS C
Question: A charity collected $1,499 from donors during the last month. If each donor gave at least $20, what is the greatest possible number of donors the charity could have?
A.77
B.78
C.79
D.74
Answer: D.74
Explanation: Min fund = 20
Total = 1499
The closest multiple of 20 to 1499 is : 73
Which implies 73 people gave 20 and 1 person gave 39
Ans. D
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.299
B.200
C.240
D.111
Answer: C.240
Explanation: Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 36 = 15
x + 300 = 540
x = 240 m. Answer:C
Question: Find the invalid no.from the following series 3, 7, 15, 27, 63, 127, 255
A.3
B.15
C.27
D.127
Answer: C.27
Explanation: Go on multiplying the number by 2 and adding 1 to it to get the next number.So, 27 is wrong.
C
Question: If the number 52,1n6, where n represents the tens digit, is a multiple of 3, then the value of n could be which of the following?
A.6
B.5
C.3
D.4
Answer: D.4
Explanation: The sum of the digits 5 + 2 + 1 + n + 6 must be a multiple of 3
14 + n must be a multiple of 3
substituting the numbers n must = 4
Answer D