RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a garden, there are 10 rows and 15 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is
A.20 m
B.30 m
C.24 m
D.26 m
Answer: B.30 m
Explanation: Explanation:
Each row contains 15 plants.
There are 14 gapes between the two corner trees (14 x 2) metres and 1 metre on each side is left.
Therefore Length = (28 + 2) m = 30 m.
Answer: B
Question: If x and y are integers and x + y = 5, which of the following must be true?
A.x and y are consecutive integers.
B.If x < 0, then y > 0.
C.If x > 0, then y < 0.
D.Both x and y are even.
Answer: B.If x < 0, then y > 0.
Explanation: Notice that the question asks which of the following MUST be true, not COULD be true.
Given: x + y = 5
A. x and y are consecutive integers: not necessarily true, for example x=1 and y=4;
B. If x < 0, then y > 0: if x is negative then y must be positive in order x+y to be positive, so this statement must be true;
C. If x > 0, then y < 0: not necessarily true, for example x=1 and y=4;
D. Both x and y are even: never true, as the sum of two even numbers is even and can not equal to odd number 5;
E. Both x and y are less than 5: not necessarily true, for example x=6 and y=-1;
Answer: B.
Question: Sam is training for the marathon. He drove 12 miles from his home to the Grey Hills Park and then ran 5 miles to Red Rock, retraced his path back for 2 miles, and then ran 3 miles to Rock Creek. If he is then n miles from home, what is the range of possible values for n?
A.1 ≤ n ≤23
B.3 ≤ n ≤21
C.6 ≤ n ≤18
D.5 ≤ n ≤19
Answer: C.6 ≤ n ≤18
Explanation: ANSWER: C To find the maximum and minimum range for his distance from home, assume that he traveled either directly toward his home or directly away from his home. The range then is between 12+5-2+3=18 for the maximum, and 12-5+2-3=6 for the minimum, so C is the answer
Question: 8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of the water is 16 : 65. How much wine the cask hold originally ?
A.18 litres of wine
B.24 litres of wine
C.32 litres
D.42 litres
Answer: B.24 litres of wine
Explanation: Solution
Let the quantity of the wine in the cask originally be x litres
then, quantity of wine left in cask after 4 operations
= [x(1- 8/x)4] litres.
Therefore x(1- 8/x)4 / x = 16/81 =› (1- 8/x)4 = (2/3)2
=› (x - 8 / x) = 2/3 =› 3x - 24 = 2x =› x = 24.
Answer B
Question: The sides of a cube are in the ratio 1:2 the ratio of their volume is?
A.1:6
B.1:4
C.1:0
D.1:2
Answer: B.1:4
Explanation: 1:4
Answer:B
Question: It takes a boat 3 hours to travel down a river from point A to point B, and 5 hours to travel up the river from B to A. How long would it take the same boat to go from A to B in still water?
A.1h 15m
B.6h 35m
C.3h 45m
D.2h 49m
Answer: C.3h 45m
Explanation: Let: S be the speed of the boat in still water, r be the rate of the water current and d the distance between A and B.
d = 3(S + r) : boat traveling down river
d = 5(S - r) : boat traveling up river
3(S + r) = 5(S - r)
r = S / 4 : solve above equation for r
d = 3(S + S/4) : substitute r by S/4 in equation B
d / S = 3.75 hours = 3 hours and 45 minutes.
correct answer is :C) 3h 45m
Question: If the mean of numbers 28, x, 42, 78 and 104 is 62, then what is the mean of 128, 255, 280, 511, 1023 and x?
A.395
B.375.8
C.355
D.415
Answer: B.375.8
Explanation: The mean of numbers 28, x, 42, 78 and 104 is 62: 28+x+42+78+104=62*5 --> x=58;
So, the mean of 128, 255, 511, 1023 and x is (128+255+280+511+1023+58)/6=375.8.
Answer: B.
Question: What is the equation of a circle of radius 4 units centered at (3, 2)?
A.x^2 + y^2 + 6x – 4y = 23
B.x^2 + y^2 - 6x + 4y = 23
C.x^2 + y^2 - 6x – 4y = 3
D.x^2 + y^2 - 6x – 4y = - 23
Answer: C.x^2 + y^2 - 6x – 4y = 3
Explanation: the equation of a circle with center at (a,b) and radius R is (X-a)^2+(Y-b)^2=R^2
=> answer = (X-3)^2+(Y-2)^2=4^2
solving,,we get the equation in answer choice C
Question: If green means red, red means yellow, yellow means blue, blue means orange and orange means green, what is the colour of leaf ?
A.Red
B.Green
C.Yellow
D.Orange
Answer: D.Orange
Explanation: Explanation:
The colour of leaf is 'green' and as given 'orange' means 'green'.
so, the colour of leaf is 'red'.
Answer: D
Question: A committee of 4 persons is to be formed from 3 company secretaries, 4 economists and 1 chartered accountant. What is the probability that each of the three professions is represented in the committee?
A.1/28
B.12/14
C.1/14
D.4/28
Answer: B.12/14
Explanation: 3/8*4/7*1/6*4! = 3/14. We are multiplying by 4! because we can choose secretary,economist, and accountant is several way:
Answer: B.
Question: How many positive integers less than 500 can be formed using the numbers 1, 2, 3 and 5 for the digits?
A.48
B.52
C.66
D.68
Answer: D.68
Explanation: Notice that we can find the number of 2 and 3 digit numbers by just assuming the first digit can also be zero:
0 1 1
1 2 2
2 3 3
3 5 5
Number of possibilities = 4*4*4 = 64.
Then, just add up the number of 1 digits numbers = 4, so total is 64+4 = 68.
Answer: D
Question: In a mixed college 160 students are there in one class. Out of this 160 students 3/4 students are girls. How many boys are there ?
A.40
B.60
C.80
D.120
Answer: A.40
Explanation: Total Number of Students :160
Total Girls : 160*3/4 =120
Total Boys : 160-120 = 40
Answer is A
Question: What is the sum of odd integers from 35 to 95, inclusive?
A.2,015
B.1,500
C.1,240
D.1,120
Answer: A.2,015
Explanation: Number of odd integers = (95-35)/2 + 1
= 60/2 + 1
= 31
Sum of odd integers = (35+95)/2 * 31
=2015
Answer A
Question: A boat can move upstream at 25 kmph and downstream at 37 kmph, then the speed of the current is?
A.5
B.6
C.7
D.54
Answer: B.6
Explanation: US = 25
DS = 37
M = (37 - 25)/2 = 6.Answer:B
Question: The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 7000, brokerage being 1/4%, is:
A.96.97
B.114
C.114.75
D.124
Answer: A.96.97
Explanation: Face Value = Rs. 7000.
Dividend = 10.5%.
Annual Income = Rs. 756.
Brokerage per Rs. 100 = Rs. 0.25.
Dividend is always paid on the face value of a share.
Face Value * Dividend / (Market Value + Brokerage per Rs. 100) = Annual income.
= 7000 * 10.5 / 756 = Market Value of Rs. 100 stock + Brokerage per Rs. 100.
= Market Value of Rs. 100 stock + Brokerage per Rs. 100 = Rs. 97.22.
= Market Value of Rs. 100 stock = Rs. 97.22 - Re. 0.25.
= Market Value of Rs. 100 stock = Rs. 96.97
answer : A
Question: Peter got a weekly raise of $680. If he gets paid every other week, write an integer describing how the raise will affect his paycheck.
A.860
B.806
C.608
D.680
Answer: D.680
Explanation: Let the 1st paycheck be x (integer).
Peter got a weekly raise of $ 680.
So after completing the 1st week she will get $ (x+680).
Similarly after completing the 2nd week he will get $ (x + 680) + $ 680.
= $ (x + 680 + 680)
= $ (x + 1360)
So in this way end of every week her salary will increase by (D)$ 680.
Question: What is the normal price of an article sold at $126 after two successive discounts of 10% and 20%?
A.$155
B.$165
C.$175
D.$185
Answer: C.$175
Explanation: 0.8*0.9*cost price = $126
cost price = $175
The answer is C.
Question: If x and y are integers such that x > y, which of the following CANNOT be a positive integer?
I. y(y – x)
II. y(x – y)
III. (x - y)/(y - x)
A.I only
B.II only
C.III only
D.I and II only
Answer: C.III only
Explanation: lets see the three equations..
I. y(y – x)
if both x and y are negative number, y will be -ive and y-x, as numeric value of y will be more than x,will also be -ive... so out
II. y(x – y)
if both x and y are +ive number, y will be +ive and x-y will also be positive... so out
III. (x - y)/(y - x)
either one of the numerator and denominator will be -ive and the other +ive..
so will always be -ive
we need not see any further after checking for II as all choices except C are eliminated..
ANSWER:C
Question: A and B started business in partnership investing Rs. 20,000 and Rs. 15,000 respectively. After six months, C joined them with Rs. 20,000. What will be B's share in the total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business?
A.Rs.7500
B.Rs.7509
C.Rs.7508
D.Rs.7597
Answer: A.Rs.7500
Explanation: A:B:C = (20000 * 24) : (15000 * 24) : (20000 * 18) = 4:3:3
B's share = 25000 * 3/10 = Rs.7500.
Answer: A
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when No boy gets more than one prize?
A.12
B.14
C.17
D.24
Answer: D.24
Explanation: Sol. In this case, repetitions are not allowed. So, the first prize can be given in 4 ways. The second in 3 ways and the third in 2 ways. But fundamental principle, (4 x 3 x 2) ways = 24 ways
4: Or 4p = — 4:- 4X3X2X1- 24 ways
D
Question: The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?
A.2277
B.2667
C.3600
D.2766
Answer: C.3600
Explanation: P = 144(100/5)2 => P = 3600
Answer: C
Question: Six students - 3 boys and 3 girls - are to sit side by side for a makeup exam. How many ways could they arrange themselves given that no two boys and no two girls can sit next to one another?
A.12
B.36
C.72
D.240
Answer: C.72
Explanation: in order not to have two boys or two girls next to one another, we must make an alternate sitting arrangement. (B-G-B-G-B-G) or (G-B-G-B-G-B).
Total ways = 2C1*3!*3!
=2*6*6
=72
Ans - C
Question: Mohit sold an article for Rs. 18000. Had he offered a discount of 19% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
A.13500
B.27767
C.16688
D.26678
Answer: A.13500
Explanation: Let the CP be Rs. x.
Had he offered 19% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x = Rs. 1.08x = 18000 - 19/100(18000) = Rs. 14580
=> 1.08x = 14580
=> x = 13500
\Answer: A
Question: A reduction of 25% in the price of apples would enable a man to obtain 36 more for Rs.25, what is reduced price per dozen?
A.2
B.3
C.6
D.7
Answer: A.2
Explanation: A
25*(25/100) = 6 --- 36
? --- 12 => Rs.2
Question: The average speed of a car decreased by 3 miles per hour every successive 8-minutes interval. If the car traveled 4.4 miles in the sixth 8-minute interval, what was the average speed of the car, in miles per hour, in the first 8 minute interval?
A.35
B.40
C.48
D.51
Answer: C.48
Explanation: (4.4 miles / 8 minutes)*60 minutes/hour = 33 mph
Let x be the original speed.
x - 5(3) = 33
x = 48 mph
The answer is C.
Question: Find the value of x in 3(x-8)=24
A.8
B.12
C.16
D.20
Answer: C.16
Explanation: 3(x-8)=24
Dividing both sides with 3 gives x-8=8
Adding both sides with 8 gives x=16
Answer: C
Question: Gopi gives Rs. 90 plus one turban as salary to his servant for one year. The servant leaves after 9 months and receives Rs. 65 and the turban. Find the price of the turban.
A.27
B.36
C.29
D.10
Answer: D.10
Explanation: Let the price of turban be x.
Thus, for one year the salary = (90 + x)
For 9 months he should earn 3434 (90 + x).
Now he gets one turban and Rs. 65.
Thus, 3434 (90 + x) = 65 + x or 270 + 3x = 260 + 4x or x = 10
Answer:D
Question: Three numbers are in the ratio 1 : 2 : 3 and their H.C.F. is 12. The numbers are :
A.4, 8, 12
B.5, 10, 15
C.10, 20, 30
D.12, 24, 36
Answer: D.12, 24, 36
Explanation: Explanation:
Let the required numbers be x, 2x and 3x.
Then, their H.C.F = x. So, x = 12.
The numbers are 12, 24 and 36.
ANSWER IS D
Question: The cost per unit of electricity during a 4 year period is as follows: Year 1, $3 per unit; Year 2, $4 per unit; Year 3, $5 per unit; Year 4, $6 per unit. If a factory spent equal dollars on electricity each year, what was the average cost of a unit of electricity during the 4 year period?
A.$4.31
B.$4.51
C.$4.21
D.$5.21
Answer: C.$4.21
Explanation: Let money spent each year = $60
Units bought first year = 20
Units bought second year = 15
Units bought third year = 12
Units bought fourth year = 10
Total number of units = 57
Total money spent = 60*4 = 240
Average = 240/57 = 4.21
Answer : C
Question: If P is a prime number greater than 3, find the remainder when P^2 + 14 is divided by 12.
A.6
B.1
C.3
D.8
Answer: C.3
Explanation: Every prime number greater than 3 can be written 6N+1 or 6N-1.
If P = 6N+1, then P^2 + 14 = 36N^2 + 12N + 1 + 14 = 36N^2 + 12N + 12 + 3
If P = 6N-1, then P^2 + 14 = 36N^2 - 12N + 1 + 14 = 36N^2 - 12N + 12 + 3
When divided by 12, it must leave a remainder of 3.
The answer is C.
Question: Find the odd man out. 2,4,7,10,16
A.11
B.9
C.10
D.6
Answer: A.11
Explanation: Explanation :
2+2=4
4+3=7
7+4=11
11+5=16
Hence, it is clear that 11 should have come instead of 10
Answer : Option A
Question: 30 pens and 75 pencils were purchased for 510. If the average price of a pencil was 2.00, find the average price of a pen.
A.10
B.11
C.12
D.cannot be determined
Answer: C.12
Explanation: Since average price of a pencil = 2
∴ Price of 75 pencils = 150
∴ Price of 30 pens = (510 – 150) = 360
∴ Average price of a pen = 360⁄60 = 12
Answer C
Question: The area of a square is 4096 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square?
A.5 : 16
B.5 : 17
C.5 : 11
D.5 : 19
Answer: A.5 : 16
Explanation: Let the length and the breadth of the rectangle be l cm and b cm respectively. Let the side of the square be a cm.
a2 = 4096 = 212
a = (212)1/2 = 26 = 64
L = 2a and b = a - 24
b : l = a - 24 : 2a = 40 : 128 = 5 : 16
Answer: A
Question: A person is traveling at 45km/hr and reached his destiny in 5hr find the distance?
A.A)100km
B.B225km
C.C)135km
D.D)80km
Answer: B.B225km
Explanation: speed = 45km/hr
time = 5hr
distance = 45*5 = 225km
Answer is B
Question: what is next no. 11 23 47 83 131 191 263 ???
A.171
B.347
C.191
D.201
Answer: B.347
Explanation: 11+12*1=23
23+12*2=47
47+12*3=83
83+12*4=131
131+12*5=191
191+ 12*6=263
263+12*7=347
ANSWER:B
Question: Two brothers were expected to return here on the same day. Rajat returned 3 days earlier but Rohit returned 4 days later. If Rajat returned on Monday, what was the expected day when both the brothers were to return home and when did Rohit Return?
A.Wednesday, Sunday
B.Tuesday, Monday
C.Thursday, Monday
D.Monday, Friday
Answer: C.Thursday, Monday
Explanation: Rajat returned on Monday -i.e. 3 days earlier
so actual day to return home is Thursday.
Rohit returned after days so Monday
ANSWER:C
Question: A 70 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?
A.35
B.20
C.47
D.36
Answer: B.20
Explanation: 1: 2/5 = 5: 2
2/7 * 70 =20
Answer:B
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?
A.1,20,000
B.1,10,000
C.1,00,000
D.90,000
Answer: A.1,20,000
Explanation: X * (105/100) * (105/100) * (105/100) = 138915
X = 138915/1.157625
X = 120000
ANSWER:A
Question: In a petting zoo, there are 50 hens, there are 40 goats, and 10 llamas with some humans. If the total number of feet are 210 more than the number of heads in the zoo, the number of humans is
A.1
B.5
C.10
D.15
Answer: C.10
Explanation: Explanation: Let number of humans be x. Then, Total number of feet = 2 x 50 + 4 x 40 + 4 x 10 + 2x = 2x + 300 Total number of heads = 50 + 40 + 10 + x= 100 + x. Therefore (2x + 300) = (100 + x) + 210 or x = 10. Answer: C
Question: A train 520 m long can cross an electric pole in 20 sec and then find the speed of the train?
A.88 Kmph
B.94 Kmph
C.72 Kmph
D.16 Kmph
Answer: B.94 Kmph
Explanation: Length = Speed * time
Speed = L/T
S = 520/20
S = 26 M/Sec
Speed= 26*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 94 Kmph
Answer: B
Question: A batsman in his 17th innings makes a score of 85, and thereby increases his average by 3. What is his average after the 17th innings? He had never been ’not out’.
A.47
B.37
C.39
D.43
Answer: B.37
Explanation: Average score before 17th innings
= 85 - 3 × 17= 34
Average score after 17th innings
=> 34 + 3 = 37
ANSWER:B
Question: What is the units digit of 17^83 × 13^82 × 11^83?
A.4
B.5
C.6
D.7
Answer: B.5
Explanation: To find : the units digit of 17^83 × 13^82 × 11^87
Let's reduce the clutter and simplify the product
(7^83) (3^82) (1^87)
7 has a cyclicity of 4 : the last digit of any positive power of 7 repeats itself after every 4th power
so 7^5 has the same last digit as 7^1, 7^9, 7^13
Thus , 7^83 has the same last digit as 7^3, 7^7, 7^11 i.e.3
3 has a cyclicity of 4 : exactly the same routine as above
Thus , 3^82 has the same last digit as 3^2, 3^6, 3^10 i.e.9
Any power of 1 will result in1as the last digit
So, product of our last digits = 3 x 9 x 1 = 27....last digit is 5
Correct Option : B
Question: You collect coins. Suppose you start out with 11. Since you're nice, you give Sharon 2 coins. Since you're nice, you give Steven 4 coins. How many coins do you have at the end?
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: Solution
Start with 11 coins.
Sharon takes 2 coins from you: 11 - 2 = 9 coins.
Steven takes 4 coins from you: 9 - 4 = 5 coins.
So you have 5 at the end.
Correct answer : D
Question: Today is Monday. After 61 days, it will be
A.Sunday
B.Saturday
C.Monday
D.Thursday
Answer: B.Saturday
Explanation: 61 days = 8 weeks 5 days = 5 odd days
Hence if today is Monday, After 61 days, it will be = (Monday + 5 odd days)
= Saturday
Answer is B
Question: Jonathan can type a 10 page document in 40 minutes, Susan can type it in 30 minutes, and Jack can type it in 24 minutes. Working together, how much time will it take them to type the same document?
A.5 minutes
B.10 minutes
C.15 minutes
D.18 minutes
Answer: B.10 minutes
Explanation: You may set up common equation like this:
job/A+job/B+job/C=job/x
Memorize this universal formula, you will need it definitely for GMAT.
and find x from this equation
In this specific case, the equation will look like this:
10/40+10/30+10/24=10/x
If you solve this equation, you get the same answer B (10)
Question: How many different three-digit multiples of 5 can be composed of digits 2, 7, 4, and 5 if none of the digits is repeated?
A.3
B.6
C.10
D.12
Answer: B.6
Explanation: = 3c2 x 2 = 6
can you explain your method. i solved it differently
XYZ, where Z must be 5. therefore 1 variation of digit in Z.
Y can be any of the 3 possible choices.
X can be any of the 2 possible choices.
2+3+1= 6
B
Question: How much more would Rs.20000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly?
A.482
B.337
C.277
D.288
Answer: A.482
Explanation: 20000(11/10)4 - 20000(6/5)2 = 482
Answer: A
Question: The banker's gain of a certain sum due 2 years hence at 10% per annum is Rs. 24. The present worth is:
A.Rs.608
B.Rs.6076
C.Rs.600
D.Rs.602
Answer: C.Rs.600
Explanation: T.D. = B.G. x 100 = Rs. 24 x 100 = Rs. 120.
Rate x Time	10 x 2
P.W. =	100 x T.D.	= Rs. 100 x 120 = Rs. 600.
Rate x Time	10 x 2
Answer:C
Question: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
A.160
B.175
C.180
D.195
Answer: B.175
Explanation: EXPLANATION
Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x x 3.20 = 432
3.20x = 432 – 384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175.
Answer B
Question: if x - y = -10,2x + 3y = 15what is the value of y?
A.8
B.6
C.7
D.6.5
Answer: C.7
Explanation: solution
Rearranged I--> y = x + 10
Substituted into II---> 2x + 3(x + 10) = 15
we get x = -3
Solve for Y: 2(-3) + 3(y) = 15
y = 7
Answer is C
Question: What percent is 3% of 5%?
A.60%
B.50%
C.75%
D.45%
Answer: A.60%
Explanation: Required percentage = 3%/5% * 100 = 3/5 * 100 = 60%
Answer is A
Question: A train covers a certain distance at a speed of 240kmph in 5 hours. To cover the same distance in 1 2/3 hours, it must travel at a speed of
A.720km/hr
B.620km/hr
C.650km/hr
D.750km/hr
Answer: A.720km/hr
Explanation: Explanation:
Distance = 240×5 = 1200km
Required speed = (1200× 3/5) = 720km/hr
Answer: Option A
Question: Mohan purchased 15 kgs of rice at the rate of Rs.20 per kg and 8 kgs of pulses at the rate of Rs.20 per kg. Whaat is the total amount that he paid to the shopkeeper?
A.A)Rs.598
B.B)Rs.594
C.C)Rs.460
D.D)Rs.595
Answer: C.C)Rs.460
Explanation: Explanation:
Price of 15 kgs of rice at Rs.20/kg = 15x20 = Rs.300
Price of 8 kgs of pulses at Rs.20/kg = 8x20 = Rs.160
Therefore, Total amount = Rs.300+Rs.160 = Rs.460
Answer: Option C
Question: Two men can complete a piece of work in four days. Two women can complete the same work in eight days. Four boys can complete the same work in five days. If four men, eight women and 20 boys work together in how many days can the work be completed?
A.1/2 day
B.1/7 day
C.3/2 day
D.1/4 day
Answer: A.1/2 day
Explanation: Two men take four days to complete the work four men would take (2 * 4)/4 = 2 days to complete it.
Similarly four women would take two days to complete it and 20 children would take one day to complete it.
All the three groups working togerther will complete 1/2 + 1/2 + 1/1 work in a day
= 2 times the unit work in a day.
They will take 1/2 a day to complete it working together.
Answer:A
Question: A car ferry can hold up to 60 tons of cargo. What is the greatest number of vehicles that the ferry can carry if half the vehicles are cars with an average (arithmetic mean) weight of 0.75 tons and half of the vehicles are trucks with an average (arithmetic mean) weight of 4 tons?
A.12
B.16
C.20
D.24
Answer: D.24
Explanation: The weight of one car and one truck is 4.75 tons.
60/4.75 = 12 plus a remainder
The ferry could carry 12 cars and 12 trucks for a total of 24 vehicles.
The answer is D.
Question: There are n cities. What is the number of airlines that connected 7 different cities (airline from city A to city B is different with airline from city B to city A)?
A.n(n-1)
B.n(n+1)
C.n(n-1)/2
D.n(n-6)
Answer: D.n(n-6)
Explanation: First of all, the possible number of airlines is n. Then, the possible number of airlines departing from one city to another becomes (n-6). Hence, the answer is n(n-6), which makes A an answer choice.
D
Question: Of the p students at a certain college, x are studying French and y are studying German. If w are studying both French and German, which of the following expresses the number of students at the college not studying either French or German ?
A. p + w- x- y
B. p - w- x- y
C. p- w - x + y
D. w + x + y- z
Answer: A. p + w- x- y
Explanation: {Total} = {French} + {German} - {Both} + {Neither}
p = x + y - w + {Neither}
{Neither} = p + w - x - y.
Answer: A.
Question: Ravi and Kavi start a business by investing â‚¹ 4000 and â‚¹ 72000, respectively. Find the ratio of their profits at the end of year.
A.2 : 28
B.5 : 28
C.7 : 18
D.1 : 18
Answer: D.1 : 18
Explanation: Ratio of profit = Ratio of investments
= 4000 : 72000 = 1 : 18
Answer : D
Question: Shruti purchased several number of three articles P, Q and R in the proportion 3 : 2 : 3. If the unit costs of the articles P, Q and R are 200, Rs. 90 and Rs. 60 respectively, how many articles of Q must have been purchased in the total purchases of Rs. 4800?
A.8
B.10
C.12
D.14
Answer: B.10
Explanation: Explanation:
Let the number of articles of types P, Q and R be 3a, 2a and 3a respectively.
Thus, we get,
(200 x 3a) + (90 x 2a) + (60 x 3a) = 4800
960a = 4800
a = 5
Hence, the number of articles of type “Q” = 2x5 = 10
ANSWER B
Question: Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 588 as interest at the end of the loan period, what was the rate of interest?
A.7
B.6
C.18
D.24
Answer: A.7
Explanation: Let rate = R% and time = R years.
Then, (1200 x R x R)/100 = 588
12R2 = 588
R2 = 49
R = 7.
Answer: Option A