RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a certain city, 60% of the registered voters are democrats and the rest are republicans.In a mayoral race, if 70% of the registered voters who are democrats and 20% of the registered voters who are republicans are expected to vote for candidate A,What % of the registered voters are expected to vote for candidate A?
A.a) 50%
B.b) 53%
C.c) 54%
D.d) 55%
Answer: D.d) 55%
Explanation: Let total voters = 100
so D= 60, vote for the mayor 60*75%=45 (60*3/4)
R= 40, vote for the mayor 40*20%= (40*1/5)
45+8=53
53/100*100=55%
D
Question: In how many minimum number of complete years, the interest on 212.50 P at 3% per annum will be in exact number of rupees?
A.6
B.8
C.9
D.7
Answer: B.8
Explanation: Interest for one year = 212.50 × 3⁄100 × 1 = 51⁄8
Thus in 8 years, the interest is 51.
Answer B
Question: The annual budget of a certain college is to be shown on a circle graph. If the size of each sector of the graph is to be proportional to the amount of the budget it represents, how many degrees of the circle should be used to represent an item that is 35 percent of the budget?
A. 126 °
B. 15 °
C. 54 °
D. 90 °
Answer: A. 126 °
Explanation: 100 percent = 360 degrees
35 percent = 360*35/100 = 126 degrees
Answer is A.
Question: 300 first-time customers of a fashion store were surveyed for their shopping experience right after leaving the store. 60% of the customers in the survey had purchased clothes for less than $100. 40% of the customers in the survey reported they were overall satisfied with their purchase. 65% of the customers that had purchased clothes for less than $100 reported they were overall satisfied with their purchase. What percent of the customers surveyed purchased clothes for at least $100 and reported that they were NOT overall satisfied with their purchase?
A.1
B.25
C.35
D.45
Answer: A.1
Explanation: Out of 300 - 180 purchased for less than 100$120 for more
Out of 300 - 120 responded as satisfied and 180 responded disatisfied
Out of 180 ( Purchased less than 100$) - 65% = 117 responded as satisfied, So remaining Satisfied are 120 - 117 = 3
so 3 is what percentage of 300 - 1%
So the answer should be A
Question: A car started running at a speed of 29 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey.
A.41 km
B.76 km
C.25 km
D.15 km
Answer: A.41 km
Explanation: A
41 km
The total distance covered by the car in the first 10 hours = 32 + 34 + 36 + 38 + 40 + 42 + 44 + 46 + 48 + 50 = sum of 10 terms in AP whose first term is 32 and last term is 50 = 10/2 [32 + 50] = 410 km.
Question: Three bottles contain equal mixtures of spirit and water in the ratio 6 : 1, 5 : 2 and 3 : 1 respectively. If all the solutions are mixed together, the ratio of spirit to water in the final mixture will be
A.64 : 65
B.65 : 64
C.19 : 65
D.65 : 19
Answer: D.65 : 19
Explanation: Given that all bottles contain equal amount of mixture say V.
So in the first vessel -> water : spirit =1/7 : 6/7
In the second bottle -> 2/7 : 5/7
In the third bottle -> l/4:3/4.
Hence, the final ratio is=((6/7) + (5/7) + (3/4)) / ((1/7) + (2/7) + (1/4))
= 65/19
ANSWER:D
Question: When a student Joe, weighing 43 kg, joins a group of students whose average weight is 30 kg, the average weight goes up by 1 kg. Subsequently, if two students, excluding Joe, leave the group the average weight comes back to 30 kg. What is the difference between the average weight of the two students who left and the weight of Joe?
A.5.5 kg
B.11 kg
C.30 kg
D.6.5 kg
Answer: D.6.5 kg
Explanation: After two persons leave the group the average remains the same. That means the weight of the two persons = 43+30 = 73
So, the average the two persons = 36.5
That gives the answer 43-36.5 = 6.5
Answer D
Question: What is the remainder when 7777* 8888 * 101010 is divided by 33
A.110
B.220
C.330
D.440
Answer: B.220
Explanation: 7777/33==> Remainder=22
8888/33==> Remainder=11
101010/33==> Remainder=30
=22*11*30=7260/33==> Remainder=220
Answer:B
Question: In a class of 78 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course?
A.23
B.12
C.24
D.27
Answer: C.24
Explanation: You could solve this by drawing a Venn diagram. A simpler way is to realize that you can subtract the number of students taking both languages from the numbers taking French to find the number taking only French. Likewise find those taking only German. Then we have:Total = only French + only German + both + neither
78 = (41-9) + (22-9) + 9 + neither.
Not enrolled students = 24
Answer: C
Question: 10 books are placed at random in a shelf. The probability that a pair of books will always be together is
A.1/9
B.1/7
C.1/5
D.1/1
Answer: C.1/5
Explanation: 10 books can be rearranged in 10! ways consider the two books taken as a pair then number of favourable ways of getting these two books together is 9! 2!
Required probability = 1/5
Answer: C
Question: If difference between compound interest and simple interest on a sum at 10% P.a. for 2 years is Rs.61 then sum is
A.s.6100
B.s.5100
C.s.5800
D.s.6000
Answer: A.s.6100
Explanation: p(r/100)^2=C.I-S.I
P(10/100)^2=61
6100
ANSWER:A
Question: In 1985 a company sold a brand of shoes to retailers for a fixed price per pair. In 1986 the number of pairs of the shoes that the company sold to retailers decreased by 20 percent, while the price per pair increased by 20 percent. If the company’s revenue from the sale of the shoes in 1986 was $3.0 million, what was the approximate revenue from the sale of the shoes in 1985 ?
A. $2.4 million
B. $2.9 million
C. $3.0 million
D. $3.1 million
Answer: D. $3.1 million
Explanation: Let the number of pairs of shoes sold in 1985 = N
let price per pair of shoe sold in 1985 = P
In 1986,number of pairs of shoes sold decreased by 20 % = .8N
Price per pair increased by 20% = 1.2P
Company's revenue from sale of shoes in 1986 = 3 million$
=> .8N * 1.2 P = 3
=>.96 NP = 3
=> NP = 3/.96 = 3.125 million $
Answer D
Question: When positive integer N is divided by positive integer J, the remainder is 14. If N/J = 134.07, what is value of J?
A.22
B.56
C.78
D.200
Answer: D.200
Explanation: 1) We know that
decimal part of decimal quotient ={remainder/divisor}
So 0.07, the decimal part of the decimal quotient, must equal the remainder, 14, divided by the divisor J.
0.07 = 14/J
0.07*J = 14
J = 14/0.07 = 1400/7 = 200
So J =200, answer = D.
Question: At what rate percent per annum will the simple interest on a sum of money be 3/5 of the amount in 10 years?
A.6%
B.7%
C.9%
D.3%
Answer: A.6%
Explanation: Let sum = x. Then, S.I. = 2x/5, Time
= 10 years.
Rate = (100 * 3x) / (x * 5 * 10)
= 6%
Answer: A
Question: The speed of a car is 90 km in the first hour and 60 km in the second hour. What is the average speed of the car?
A.228
B.75
C.299
D.267
Answer: B.75
Explanation: S = (90 + 60)/2 = 75 kmph
Answer: B
Question: When 0.232323..... is converted into a fraction, then the result is
A.23/99
B.24/99
C.25/99
D.22/99
Answer: A.23/99
Explanation: 0.232323... = 0.23
=	23/99
Answer is A.
Question: The function f is defined by subtracting 25 from the square of a number and the function v is defined as the square root of one-half of a number. If v(f(x))=10, then which of the following is a possible value of x?
A.-15
B.-5
C.0
D.5
Answer: A.-15
Explanation: f(x) = x^2-25
v(x) = sqrt(x/2) not sqrt(x)/2, because the question clearly says its square root of (half of the number).
v(f(x)) = 10
v(x^2-25) =10
sqrt((x^2-25)/2) = 10
=> (x^2-25)/2 = 100
=>x^2 = 225
=> x = 15 or -15
Answer is A.
Question: John took a bus from home to market, that travels at 50 kmph. While walking back at 5 kmph,
halfway through, he suddenly realized he was getting late and he cycled back the remaining distance in 35 kmph. Find the average speed.
A.8.5 kmph
B.16.0 kmph
C.22.5 kmph
D.18.6 kmph
Answer: D.18.6 kmph
Explanation: Let the distance be 2x(one way)
Time taken by bus = 2x/50, by walking =x/5, by cycling = x/35 hours
:. Average speed = Total Distance/Total time
= 5x / x/25 + x/5 + x/35
= 5 *60 / 2.4+12+1.7
= 18.6
ANSWER:D
Question: Priya covers journey from kavali to nellore by car at average speed of 80 Km/hr. She returns back by scooty with an average speed of 40 Km/hr. Find her average speed during the whole journey?
A.50Km/hr
B.53.33Km/hr
C.60Km/hr
D.66Km/hr
Answer: B.53.33Km/hr
Explanation: Explanation:
Average speed = 2 xy/x+y
= 2*80*40/120
= 53.33 Km/hr
Answer: Option B
Question: There are two sets A and B. The range of set A is 7, and the range of set B is 13. If the two sets are combined and get a new set W, which cannot be the range of the set W?
A.8
B.B.11
C.C.14
D.D.17
Answer: B.B.11
Explanation: Let Set A has 1,8 as elements
B has 1,14 as elements.. So Range for Combined set W becomes 14-1=13
For range to be 14,
A = 1,8
B= 2,15 (Range=14)
For range to be 17
A=1,8
B= 5,18
For range to be 21:
A=1,8
B= 9 ,22
So we are left with A and B.
Now consider A has elements A= -1,-8 and Thus Range =-1-(-8) =7
So for Range of combined set to be 11, B needs to have largest elementxso that x- (-8)=11 or x=3...But if x=3, the largest element in Combined Set then smallest element in the combined set will be 3-y=13 or y=-10....And the range of combined set 3-(-10)=13...
Consider Option A
A=-1,-8
B= y,x where y and x are smallest and largest element in Set B
Elements of Combined Set: -8,-1,y and x
Now x-(-8)=8 or x=0, then x-y=13 or y=-13...
Range of Combined Set: 0-(-13)= 13...
I don't see how range can be 8 or 11...Can you please post the source and explanation for the OA in spoiler...=B
Question: How many of the following numbers are divisible by 3 but not by 9 ?
2133, 2343, 3474, 4131, 5286, 5340, 6336, 7347, 8115, 9276
A.5
B.6
C.7
D.None of these
Answer: B.6
Explanation: Explanation: Marking (/) those which are are divisible by 3 by not by 9 and the others by (X), by taking the sum of digits, we get:s
2133 9 (X)
2343 12 (/)
3474 18 (X)
4131 9 (X)
5286 21 (/)
5340 12 (/)
6336 18 (X)
7347 21 (/)
8115 15 (/)
9276 24 (/)
Required number of numbers = 6.
Answer: Option B
Question: A can do a job in 10 days and B can do it in 30 days. A and B working together will finish twice the amount of work in ------- days?
A.21 ½ days
B.22 ½ days
C.23 ½ days
D.15 days
Answer: D.15 days
Explanation: Explanation:
1/10 + 1/30 = 4/30 = 2/15
15/2 = 15/2 *2 = 15 days
Answer: D
Question: Five years ago the average of the ages of A and B was 40 years and now the average of the ages of B and C is 48 years. What will be the age of the B ten years hence?
A.66
B.77
C.66
D.96
Answer: D.96
Explanation: Let the present ages of A, B and C be a, b and c respectively.
Given, [(a - 5) + (b - 5)] / 2 = 40 => a + b = 90 --- (1)
(b + c)/2 = 48 => b + c = 96 --- (2)
From (1) and (2), we cannot find b.
Answer: D
Question: Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is
A.4 : 5
B.5 : 4
C.3 : 2
D.4 :7
Answer: A.4 : 5
Explanation: Let the third number be x.
Then, first number = 120% of x = 120x = 6x
100 5
Second number = 150% of x = 150x = 3x
100 2
Ratio of first two numbers = 6x : 3x = 12x : 15x = 4 : 5.
5 2
A
Question: Find the average of all the numbers between 11 and 36 which are divisible by 5.
A.25
B.77
C.20
D.28
Answer: A.25
Explanation: Explanation:
Average = (15 + 20 + 25 + 30 + 35) / 5 = 125/5 = 25
ANSWER: A
Question: How many positive integers less than 100 have a remainder of 4 when divided by 13?
A.6
B.7
C.4
D.9
Answer: C.4
Explanation: We have to include 4 also.As 13*0 + 4 =2
If somebody says to divide 4 by 13 ,we will be telling we have 0 quotient and remainder as 4.
Answer is C
Question: If x and y are integers and |x - y| = 10, what is the minimum possible value of xy?
A.-9
B.-18
C.-24
D.-25
Answer: D.-25
Explanation: Sometimes the answer choices to a given question provide a big 'hint' as to how you can go about solving it. This prompt can also be solved without any complex math ideas - you just need to do a bit of 'brute force' math and you'll have the answer relatively quickly.
We're told that X and Y are INTEGERS and |X - Y| = 10. We're asked for the MINIMUM possible value of (X)(Y).
Since all of the answer choices are NEGATIVE, this tells us that ONE of the two variables MUST be negative (and the other must be positive), so we should restrict our work to those options.
IF...
X = 9, Y = -1, then XY = -9
X = 8, Y = -2, then XY = -16
X = 7, Y = -3, then XY = -21
X = 6, Y = -4, then XY = -24
X = 5, Y = -5, then XY = -25
X = 4, Y = -6, then XY = -24
X = 3, Y = -7, then XY = -21
From this, we can conclude the XY will start to get bigger as X continues to decrease down to 1, so there's no need to do any additional work.
Final Answer:
D
Question: At the end of three years what will be the compound interest at the rate of 10% p.a. on an amount of Rs.20000?
A.Rs.6620
B.Rs.1258
C.Rs.3556
D.Rs.974
Answer: A.Rs.6620
Explanation: A = 20000(11/10)3
= 26620
26620-20000=Rs.6620
Answer:A
Question: In triangle XYZ, side XY, which runs perpendicular to side YZ, measures 24 inches in length. If the longest side of the the triangle is 26 inches, what is the area, in square inches, of triangle XYZ?
A. 100
B. 120
C. 140
D. 150
Answer: B. 120
Explanation: Okay we know we have a right triangle with hypotenuse 26.
Using Pythagoras theory I think: 24^2 + x^2 = 26^2
so 576 + x^2 = 676 ---> x^2 = 100 ---> x= 10
Areal of triangle = base* height / 2 so 24*10/2 = 120
So answer choice B
Question: What is the least number which when divided by 6, 9, 12 and 18 leaves remainder 4 in each care?
A.30
B.40
C.36
D.56
Answer: B.40
Explanation: Explanation:
LCM of 6, 9, 12 and 18 is 36
Required number = 36 + 4 = 40
Answer: Option B
Question: A boy wants to go abroad by boat and return by flight. He has a choice of 7 different boat to go and 5 flight to return. In how many ways, can the boy perform his journey?
A.20
B.25
C.30
D.35
Answer: D.35
Explanation: Ans.(D)
Sol. Number of choices to go by ship = 7 Number of choices to return by airline = 5 From, fundamental principle, total number of ways of performing the journey = 7 x 5 = 35 ways
Question: In a batch of 125 students, there are 12 books related with different subjects to be distributed. If the total number of books bought during the time of distribution were 1511, how many extra books will be lying with the distributor?
A.10
B.11
C.2
D.5
Answer: B.11
Explanation: 125x12=1500 is the total number of books required to be distributed. As the number of books actually bought during the time of distribution 1511, 11 extra books were purchased. Answer: B
Question: A company pays project contractors a rate of a dollars for the first hour and b dollars for each additional hour after the first, where a > b.
In a given month, a contractor worked on two different projects that lasted 4 and 6 hours, respectively. The company has the option to pay for each project individually or for all the projects at the end of the month. Which arrangement would be cheaper for the company and how much would the company save?
A.Per month, with savings of $(3a + 3b)
B.Per month, with savings of $(3a - 3b)
C.The two options would cost an equal amount.
D.Per project, with savings of $(3a + 3b)
Answer: B.Per month, with savings of $(3a - 3b)
Explanation: Per Project, company will pay as follows:
For 4 hours work = a+3b
For 6 hours work = a+5b
Total = 2a+8b
Per Month, company will pay for 10 hours work = a+9b
Total per contract - total per month
4a+6b - (a+9b)
3a-3b
Since a>b Amount 4a+6b(per contract amount) > a+9b (per project amount) by 3a-3b.
Hence per month payment will be cheaper by 3a-3b .
OA B
Question: In Prasanna's opinion, his weight is greater than 65 kg but less than 72 kg. His brother does not agree with Prasanna and he thinks that Prasanna's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all of them are correct in their estimation, what is the average of different probable weights of Prasanna?
A.67 kg
B.68 kg
C.66.5 kg
D.69 kg
Answer: C.66.5 kg
Explanation: Sol.
Let Prasanna's weight be X kg.
According to Prasanna, 65 < X < 72.
According to Prasanna's brother, 60 < X < 70.
According to Prasanna's mother, X < 68.
The value satisfying all the above conditions are 66 and 67.
∴ Required average = [ 66 + 67 / 2 ] = [133 / 2] = 66.5 kg.
Answer C
Question: In a mixture of 45 litres, the ratio of acid to base is 4 : 1. How much base must be added to make the mixture ratio 3 :2?
A.72 lts
B.24 lts
C.15 lts
D.1.5 lts
Answer: C.15 lts
Explanation: Base = 9 litres
Acid = 9 lts
To make the ratio of acid : base as
3 : 2,
15 litres of base must be added.
ANSWER:C
Question: A plot is sold for Rs. 18,700 with a loss of 15%. At what price it should be sold to get profit of 15%.
A.Rs 25300
B.Rs 22300
C.Rs 24300
D.Rs 21300
Answer: A.Rs 25300
Explanation: Explanation:
This type of question can be easily and quickly solved as following:
Let at Rs x it can earn 15% pr0fit
85:18700 = 115:x [as, loss = 100 -15, Profit = 100 +15]
x = (18700*115)/85
= Rs.25300
Option A
Question: Six friends are planning to attend a concert. If another friend also goes with them, they will get a group discount on their tickets. If the new total price of the tickets with the group discount is the same as the original total price of the tickets without the group discount, how much is the discount?
A.11%
B.14%
C.20%
D.22%
Answer: B.14%
Explanation: Let x be the original price of one ticket.
The total original cost is 6x.
The new cost is 7y, where y is the discounted price of one ticket.
6x = 7y
y = 6x/7 which is about 0.86x which is a discount of about 14%.
The answer is B.
Question: Two pipes A and B can fill a tank in 20 and 30 minutes respectively. If both the pipes are used together, then how long will it take to fill the tank?
A.12 min
B.15 min
C.25 min
D.50 min
Answer: A.12 min
Explanation: Part filled by A in 1 min. = 1/20
Part filled by B in 1 min. = 1/30
part filled by (A + B) in 1 min. = 1/20 + 1/30 = 1/12.
Both the pipes can fill the tank in 12 minutes.
ANSWER:A
Question: A retailer bought a hat at wholesale and marked it up 60% to its initial price of $24. By how many more dollars does he need to increase the price to achieve a 100% markup?
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: Let x be the wholesale price.
Then 1.6x= 24 and x = 24/1.6 = 15.
To achieve a 100% markup, the price needs to be $30.
The retailer needs to increase the price by $6 more.
The answer is D.
Question: Compare the rates of two trains, one travelling at 45 km/hr and other is at 10m/s?
A.5:4
B.3:2
C.1:5
D.2:7
Answer: A.5:4
Explanation: speed of the 1st train = 45km/hr
speed of the 2nd train = 10m/s = 10*18/5 = 36km/hr
ratio of the speeds of the train = 45:36 = 5:4
Answer is A
Question: If P, x, y, and z are positive integers and (x)×(y)×(z)=P^2, which of the following could be the values of x, y, and z?
A.3, 16, 25
B.9, 25, 24
C.2, 49, 32
D.2, 9, 16
Answer: C.2, 49, 32
Explanation: This is one of those questions where using the given options is fastest way to get the solution. We need to find a set where 3 numbers can be paired into 2 pairs of some numbers because we need a product which is a square number.
C fits the bill. 2*49*32 = 2*7*7*8*4 = 7*7*8*8
Ans C
Question: A train is running between Patna to Howrah.Seven people enter the train somewhere between Patna and Howrah.It is given that nine stops are there between patna and howrah.In how many ways can the tickets be purchased if no restriction is there with respect to the number of tickets at any station?(2 people donot buy the same ticket)
A.45c7 ways
B.45c6 ways
C.44c7 ways
D.46c7 ways
Answer: A.45c7 ways
Explanation: P _ _ _ _ _ _ _ _ _ H
P 1 2 3 4 5 6 7 8 9 H
If those people enter in the 1st station, the no. of ways they can buy tickets: 9 ways
If those people enter in the 2nd station, the no. of ways they can buy tickets: 8 ways
.
.
If those people enter in the 9th station, the no. of ways they can buy tickets: 1 way
Now total no. of ways to buy tickets are: 9+8+7+6+5+4+3+2+1=45
So, the tickets can be purchased by 7 people is 45c7 ways
ANSWER:A
Question: How many positive integers between 5 and 5000(both are inclusive) are there such that they are multiples of 5?
A.1500
B.1000
C.999
D.1001
Answer: B.1000
Explanation: Multiples of 5 = 5,10,15-----,5000
Number of multiples of 5 => 5000-5/5+1= 1000
Answer is B
Question: Fifty percent of the members of a swim club have passed the lifesaving test. Among the members who have not passed the test, 12 have taken the preparatory course and 30 have not taken the course. How many members are there in the swim club?
A. 60
B. 80
C. 84
D. 120
Answer: C. 84
Explanation: 50% of the members have passed the test, thus 50% have not passed the test.
We also know that 30+12=42 members have not passed the test, thus 0.5*Total=42 --> Total=84.
Answer: C.
Question: f n = 3^2 - 2^2, which of the following is NOT a factor of n?
A.5
B.10
C.4
D.15
Answer: C.4
Explanation: 9-4 =5 is prime no. any number not multiply with five is not a factor
C
Question: If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 150% of j ?
A.0.35
B.466
C.35
D.350
Answer: B.466
Explanation: IMO answer should be 350...
consider j=10, then k=50, l=150 and m=350....
20% of 350, comes out to be 70....
150% of 10 is 15....
(70*100)/15=466.66....
Ans : B
Question: Which of the following equations has a root in common with x^2−4x+3=0 ?
A.x^2-4x-4=0
B.x^2-2x+1=0
C.x^2-x-1=0
D.x^2-10x-1=0
Answer: B.x^2-2x+1=0
Explanation: If we carefully look at the given equation we can arrange it in the following manner:
(x-1)(x-3) = 0
so the two roots are 1 and 3.
Now put 1 and 3 in given equations. The equation in which one of them gives value 0, that will be our answer.
(A) putting 1: we get -7; Putting 3 we get -7. Reject this option.
(B) putting 1: we get 0. This is the equation.
We are lucky. No need to check other options.
B is the answer.
Question: 2 cyclist begin training at same time A complete each lap in 4 sec B in 6 minutes how many minutes after start will both cyclist pass at exactly same spot when they begin to cycle
A.160 seconds
B.260 seconds
C.360 seconds
D.460 seconds
Answer: C.360 seconds
Explanation: 6 minutes= 360 sec
lcm of 4, 360 is 360
so they meet after 360 seconds
ANSWER:C
Question: The sum of four consecutive odd numbers is equal to the sum of 3 consecutive even numbers. Given that the middle term of the even numbers is greater than 101 and lesser than 208, how many such sequences can be formed?
A.26
B.17
C.25
D.33
Answer: A.26
Explanation: Four consecutive odd numbers: k-2, k, k+2, k+4
Three consecutive even numbers: n-2, n, n+2
k-2+k+k+2+k+4=n-2+n+n+2
4k+4=3n
4(k+1)=3n
k+1=(3/4)n
k=(3/4)n-1
All n's that's divisible by 4 will have an integral k. So, we need to find out how many such n's are available within given range:
We know,
101<n<208
104<=n<=204
Count=(204-104)/4+1=100/4+1=25+1=26
Ans: 26.
Question: Lagaan is levied on the 60 percent of the cultivated land. The revenue department collected total Rs. 3,74,000 through the lagaan from the village of Mutter. Mutter, a very rich farmer , paid only Rs.480 as lagaan. The percentage of total land of Mutter over the total taxable land of the village is:
A.0.20833
B.0.14544
C.0.25632
D.0.2139
Answer: D.0.2139
Explanation: Total land of Sukhiya = \inline \frac{480x}{0.6} = 800x
\therefore Cultivated land of village = 374000x
\therefore Required percentage = \inline \frac{800x}{374000}\times 100 = 0.21390
D
Question: A person can walk at a constant rate of 8mph and can bike at a rate of 16mph. If he wants to travel 80 miles in 8 hours using bike and walking at their constant rates, how much distance would he require to walk?
A.20
B.30
C.48
D.60
Answer: C.48
Explanation: Total distance = 80
Distance = Speed * Time
Walking speed = s1 = 8
Walking time = t1
Bike speed = s2 = 16
Time traveled in bike = t2
d1 + d2 = 80
s1t1 + s2t2 = 80
8*t1 + 16*t2 = 80
t1 + 2*t2 = 10 ----- (1)
Given: t1 + t2 = 8 ----- (2)
(1) - (2) --> t2 = 2 and t1 = 8 - 2 = 6
Walking distance = s1*t1 = 8*6 = 48
Answer: C