RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Five 6 faced dice are thrown together. The probability that all the three show the same number on them is?
A.1/32
B.1/1296
C.1/33
D.1/38
Answer: B.1/1296
Explanation: The three dice can fall in 6 * 6 * 6 * 6 * 6 = 7776 ways.
Hence the probability is 6/7776
= 1/1296
Answer: B
Question: Which is greatest in 16 ( 2/3) %, 2/5 and 0.17 ?
A.16 (2/3)
B.0.17
C.2/5
D.all are equal
Answer: B.0.17
Explanation: 16 (2/3)% =[ (50/3)* )1/100)]
= 1/6 = 0.166,
2/15 = 0.133.
Clearly,
0.17 is the greatest.
Answer is B.
Question: An article is bought for Rs.675 and sold for Rs.800, find the gain percent?
A.38%
B.28%
C.18%
D.22%
Answer: C.18%
Explanation: 675 ---- 125
100 ---- ? =>
=18%
Answer:C
Question: The product A of the first 10 prime numbers is closest to which of the following?
A.6.5 x 10^7
B.6.5 x 10^8
C.6.5 x 10^9
D.6.5 x 10^10
Answer: C.6.5 x 10^9
Explanation: The first 10 primes are: 2, 3, 5, 7, 11, 13, 17, 19, 23, and 29.
So, we need to find approximate value of 2*3*5*7*11*13*17*19*23*29.
# of different approximations are possible. For example:
2*5=10
3*17=~50 (actually more than 50);
7*13=~100 (actually less than 100);
11*19=~200 (actually more than 200)
23*29=667=A
2*3*5*7*11*13*17*19=~10*50*100*200*667=10^7*667=6.67*10^9.
Answer: C.
Question: If x and y are perfect squares, then which five of the following is not necessarily a perfect square?
A.x^2
B.xy
C.4x
D.x+y
Answer: A.x^2
Explanation: If x=y=1^2=1, then each option but A is a perfect square, therefore A is NOT necessarily a perfect square.
Answer: A.
Question: There are 7 non-collinear points. How many triangles can be drawn by joining these points?
A.12
B.27
C.35
D.28
Answer: C.35
Explanation: A triangle is formed by joining any three non-collinear points in pairs.
There are 7 non-collinear points
The number of triangles formed = 7C3
= 35
Answer: C
Question: A train is 435 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length
A.20 seconds
B.30 seconds
C.46 seconds
D.50 seconds
Answer: C.46 seconds
Explanation: Explanation:
Speed = 45 Km/hr = 45*(5/18) m/sec
= 25/2 m/sec
Total distance = 435+140 = 575 meter
Time = Distance/speed
=575∗2/25=46seconds
Option C
Question: The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:
A.0º
B.10º
C.5º
D.20º
Answer: B.10º
Explanation: Angle traced by hour hand in 13/3 hrs =(360/12 x 13/3)º = 130º. Angle traced by min. hand in 20 min. = (360/60	x 20)º = 120º. Required angle = (130 - 120)º = 10ºAnswer : B
Question: Speed of a boat in standing water is 8 kmph and the speed of the stream is 2 kmph. A man rows to place at a distance of 210 km and comes back to the starting point. The total time taken by him is:
A.48 hours
B.51 hours
C.36 hours
D.56 hours
Answer: D.56 hours
Explanation: Sol.
Speed upstream = 6 kmph; Speed downstream = 10 kmph.
∴ total time taken = [210/6 + 210/10] hours = 56 hours.
Answer D
Question: Jill invests $10000 in an account that pays an annual rate of 3.96%, compounding semi-annually. Approximately how much does she have in her account after two years?
A.$10079.44
B.$10815.83
C.$12652.61
D.$14232.14
Answer: B.$10815.83
Explanation: Solution: first of all, notice the magic word “approximately” — the test-writer is letting us know estimation is perfectly fine. Furthermore, the answer choices are nicely spread out, which will facilitate estimating.
OK, get ready for some fast & furious estimation. The interest rate 3.96% is an ugly number, so I’m going to approximate that as 4%. It compounds semiannually, so that means that there’s 2% every six months, and that happens four times in two years. Well, 2% of $10000 is $200. If you get $200, or a little more, on four occasions, that’s a little more than $800 in interest. We expect an answer slightly higher than $10800, so of course (B) is just right.
Notice, I estimated so that everything up until the last sum was single-digit math. Single-digit calculations are a good standard for which to strive when you are practicing estimation.
By the way, if you find the bank that will do answer (E), double your money in only two years, that’s terrific, but it probably is something wildly illegal, a Ponzi scheme or worse! In the real world, that just doesn’t happen. On word problems, especially in financial situations, you should always have your antenna up for what’s realistic or unrealistic.
answer (B)
Question: If n is an integer, which of the following CANNOT be a factor of 3n+4?
A.4
B.5
C.6
D.7
Answer: C.6
Explanation: 3n+4=3(n+1)+1 cannot be a multiple of 3, it's 1 more than multiple of 3: ... 4, 7, 10, 13, 16, ... Hence it cannot be a multiple of 2*3=6 as well.
Answer: C.
Question: The parameter of a square is equal to the perimeter of a rectangle of length 22 cm and breadth 16 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)
A.77.14 cm
B.47.14 cm
C.84.92 cm
D.29.85 cm
Answer: D.29.85 cm
Explanation: Let the side of the square be a cm.
Parameter of the rectangle = 2(22 + 16) = 76 cm Parameter of the square = 76 cm
i.e. 4a = 76
A = 19
Diameter of the semicircle = 19 cm
Circimference of the semicircle
= 1/2(∏)(19)
= 1/2(22/7)(19) = 418/14 = 29.85 cm to two decimal places
ANSWER:D
Question: n a contest, a bowl contains 10 keys, one of which will open a treasure chest and nine of which will not. If a contestant selects the key that opens the treasure chest, she wins the contents of that chest. If Anna is allowed to draw two keys, simultaneously and at random, from the bowl as the first contestant, what is the probability that she wins the prize?
A.1/10
B.. 1/9
C.1/5
D.19/90
Answer: C.1/5
Explanation: The total possibilities existing while withdrawing two keys are: 10C2 = 45
For Anna to win, 9 combinations exist assuming Key 1 to unlock the treasure E.g(1,2), (1,3)....(1,9)
P = 9/45 = 1/5
Option C
Question: Special codes are designated by either a 3-letter or a 4-letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different codes that can be designated with this system?
A.2(26)^4
B.26(26)^3
C.27(26)^3
D.26(26)^4
Answer: C.27(26)^3
Explanation: 26^3+26^4 = 26^3(1+26)=27*26^3
The answer is C.
Question: The manager of a produce market purchased a quantity of tomatoes for $0.80 per pound. Due to improper handling, 10 percent of the tomatoes, by weight, were ruined and discarded. At what price per pound should the manager sell the remaining tomatoes if she wishes to make a profit on the sale of the tomatoes equal to 12 percent of the cost of the tomatoes.
A.$0.94
B.$0.96
C.$0.99
D.$1.00
Answer: C.$0.99
Explanation: Assume the manager bought 100 tomatoes.
Cost Price = 80
Given: 10% are damaged --> Available tomatoes to sell = 90
90 * x - 80 = 0.12 * 80
90x - 80 = 9.6
90x = 89.6
x = 89.6/90 = 0.995
x is slightly under 0.9955 = 0.99
Answer: C
Question: A bag contains $510 in the form of 50 p, 25 p and 20 p coins in the ratio 2 : 3 : 4. Find the number of coins of each type.
A.200, 400, 500
B.300, 200, 600
C.800, 400, 600
D.400, 600, 800
Answer: D.400, 600, 800
Explanation: Let the number of 50 p, 25 p and 20 p coins be 2x, 3x and 4x.
Then 2x × 50/100 + 3x × 25/100 + 4x × 20/100 = 510
x/1 + 3x/4 + 4x/5 = 510
(20x + 15x + 16x)/20 = 510
⇒ 51x/20 = 510
x = (510 × 20)/51
x = 200
2x = 2 × 200 = 400
3x = 3 × 200 = 600
4x = 4 × 200 = 800.
Therefore, number of 50 p coins, 25 p coins and 20 p coins are 400, 600, 800 respectively.
Answer is D
Question: For all numbers a and b, the operationis defined by ab = (a + 2)(b – 3).
If 3x = –75, then x =
A. –15
B. –13
C. -14
D. -12
Answer: D. -12
Explanation: (3+2)(x-3)=-75..
x-3=-15..
x=-12
D
Question: Find the value of 1/(3+1/(3+1/(3-1/3)))
A.21/89
B.89/27
C.27/89
D.1/14
Answer: C.27/89
Explanation: 1/[3 + (1/(3+1/(3 - 1/3)))]
=> 1/[3 + 1/(3 + 1/(8/3))]
=> 1/[3 + 1/(3 + 3/8)]
=> 1/[3 + 8/27]
=> 1/(89/27)
=> 27/89
C
Question: If x, y, and z are consecutive odd integers, with x < y < z, then which of the following must be true?
I. y-x is even
II. (z-x)/y is an integer
III. xz is even
A.I only
B.II only
C.III only
D.I and II only
Answer: A.I only
Explanation: consecutive odds are:
2x+1, 2x+3, 2x+5
I. (2x+3)-(2x+1) = 2, so divisible by 2 and even - TRUE
II. ((2x+5)-(2x+1))/(2x+3)=4/(2x+3)=4/(odd number)= Not an integer - NOT TRUE
III. (2x+1)*(2x+5)=4x^2+10x+2x+5=4x^2+12x+5=(2x(x+6)+5)/2 is not integer, so NOT TRUE
ANSWER: A
Question: A man can swim in still water at 3 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
A.1.7
B.1.0
C.1.2
D.1.5
Answer: B.1.0
Explanation: M = 3
S = x
DS = 3 + x
US = 3 + x
3 + x = (3 - x)2
3 + x = 6 -2x
3x = 3
x = 1.0
Answer: B
Question: John buys 100 shares of par value Rs. 20 each, of a company, which pays an annual dividend of 12% at such a price that he gets 10% on his investment. Find the market value of a share.
A.2
B.24
C.5
D.6
Answer: B.24
Explanation: Face value of each share = Rs.20
Total dividend received by John = 100Ã—20Ã—12/100 = Rs.240
Let market value of 100 shares = Rs.x
xÃ—10/100=240
x = 2400
ie, Market value of 100 shares = Rs.2400
Hence, Market value of each share = Rs.24
Answer is B
Question: From theinteger n, if n*n*n is odd, then what is true from below options?
A.n is odd and n*n is even
B.n is odd
C.n*n is even
D.n is even
Answer: A.n is odd and n*n is even
Explanation: n is odd and n*n is even
Option A
Question: For the positive integers q, r, s, and t, the remainder when q is divided by r is 7 and the remainder when s is divided by t is 3. All of the following are possible values for the product rt EXCEPT
A.32
B.38
C.44
D.52
Answer: B.38
Explanation: For the positive integers q, r, s, and t, the remainder when q is divided by r is 7 and the remainder when s is divided by t is 3. All of the following are possible values for the product rt EXCEPT
A. 32
B. 38
C. 44
D. 52
E. 63
Important property:remainder cannot be greater than the divisor.
Therefore, since the remainder when q is divided by r is 7, then r>7;
Similarly, since the remainder when s is divided by t is 3, then t>3.
Now, all answers, except 38 can be represented as the product of two multiples one of which is greater than 7 and another is greater than 3:
32=8*4
44=11*4
52=13*4
63=9*7
However, 38=1*38 or 19*2, thus rt cannot equal to 38.
Answer: B.
Question: Of the 65 cars on a car lot, 45 have air-bag, 30 have power windows, and 12 have both air-bag and power windows. How many of the cars on the lot have neither air-bag nor power windows?
A. 8
B. 2
C. 10
D. 15
Answer: B. 2
Explanation: Total -Neither = All Air bag + All Power Windows - Both
or 65 - Neither = 45 + 30 -12 = 63.
=> Neither = 2, hence B.
Answer : B
Question: In how many ways Chief Minister and Minister be elected from a team of 12 members?
A.124
B.129
C.132
D.154
Answer: C.132
Explanation: To do this, if captain is elected first, then we have 12 ways of doing this.
For election of vice-captain, we have only 11 ways left, coz 1 way is already consumed. (Situations like this is called dependent situation. One selection depends upon other selection.)
So, the ans is 12*11 = 132 ways.
C
Question: In how many ways can a Chief Minister and a Vice Minister be elected from a team of 8 members?
A.32
B.40
C.48
D.56
Answer: D.56
Explanation: There are 8 choices for the Chief Minister.
Then there are 7 choices for the Vice Minister.
The total number of ways is 8*7 = 56.
The answer is D.
Question: If a boat goes 7 km upstream in 42 minutes and the speed of the stream is 5 kmph, then the speed of the boat in still water is :
A.3.5 km/hr
B.4.2 km/hr
C.5 km/hr
D.10.5 km/hr
Answer: A.3.5 km/hr
Explanation: Solution
Speed of stream = 1/2 (15-8) km/hr= 3.5kmph . Answer A
Question: In a certain game, a large bag is filled with blue, green, purple and red chips worth 1, 5, x and 11 points each, respectively. The purple chips are worth more than the green chips, but less than the red chips. A certain number of chips are then selected from the bag. If the product of the point values of the selected chips is 140800, how many purple chips were selected?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: 140800 = 1*5^2*8^3*11
The factors of 8 must come from the purple point value, so there are 3 purple chips.
The answer is C.
Question: Two numbers are less than a third number by 30% and 37%. How much percent is the second number is less than the first?
A.10%
B.15%
C.20%
D.25%
Answer: A.10%
Explanation: Let the third number be x
first number = 70% of x = 7x/10; second number = 63% of x = 63x/100;
Difference = 7x/10 - 63x/100 = 7x/100; Required percentage = 7x/100 * 10/7x * 100 = 10%
Answer is A
Question: Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.15of money?
A.1500
B.2999
C.2772
D.2987
Answer: A.1500
Explanation: P = 15(100/10)2 => P = 1500.Answer:A
Question: A single discount equivalent to the discount series of 20%, 10% and 8% is?
A.31.5
B.33.8
C.31.6
D.31.3
Answer: B.33.8
Explanation: 100*(80/100)*(90/100)*(92/100)
= 66.2
100 - 66.2 = 33.8
Answer:B
Question: B completes a work in 6 days. A alone can do it in 10 days. If both work together, the work can be completed in how many days?
A.3.33 days
B.4.33 days
C.5.33 days
D.6.33 days
Answer: A.3.33 days
Explanation: 1/5 + 1/10 = 3/10
10/3 = 3.33 days
ANSWER:A
Question: The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
A.276
B.299
C.322
D.345
Answer: C.322
Explanation: Clearly, the numbers are (23 x 13) and (23 x 14).
Larger number = (23 x 14) = 322. Answer: Option C
Question: Which of the following reaches the largest value over the range -1 <= R <= 1?
A.(R+3)^100
B.(R+3)/(R^100)
C.(R+1000)
D.97^97
Answer: B.(R+3)/(R^100)
Explanation: (R+3)/(R^100) can be equal any arbitrarily large number. Some of the other options are large, but they all have a definite maximum. (R+3)/(R^100) does not, so the correct answer is B.
Question: In how many ways can 3 postcards can be posted in 5 postboxes?
A.125
B.286
C.296
D.199
Answer: A.125
Explanation: Ans: First card can go into any of the five boxes, Second can go into any of the five boxes, Third can go into any of the five boxes = 5×5×5=1255×5×5=125
Answer:A
Question: Which of the following integers is a divisor of(15!+11)?
A.15
B.14
C.11
D.7
Answer: C.11
Explanation: When we say 15!, it just means 1*2*3*4*5*...*13*14*15
So you need to find the integer which is a divisor of
(1*2*3*4*5*...*13*14*15 + 11) = 11 (1*2*3*4*5*...10*12*13*14*15 + 1) We obtain this by taking 11 common.
Hence 11 is definitely a divisor of (15! + 11).
C
Question: Pipes A and B can fill a tank in 6 and 4 hours. Pipe C can empty it in 12 hours. If all pipes are opened together, then the tank will be filled in?
A.3hr
B.2hr
C.1hr
D.9/7hr
Answer: A.3hr
Explanation: Net part filled in 1 hour = 1/6 + 1/4 - 1/12 = 1/3
The tank will be full in 3 hr
Answer is A
Question: A number with an interesting property:
When I divide it by 2, the remainder is 1.
When I divide it by 3, the remainder is 2.
When I divide it by 4, the remainder is 3.
When I divide it by 5, the remainder is 4.
When I divide it by 6, the remainder is 5.
When I divide it by 7, the remainder is 6.
When I divide it by 8, the remainder is 7.
When I divide it by 9, the remainder is 8.
When I divide it by 10, the remainder is 9.
It's not a small number, but it's not really big, either.
When I looked for a smaller number with this property I couldn't find one.
Can you find it?
A.2588
B.2474
C.2254
D.2519
Answer: D.2519
Explanation: D
2519
The number has to end in 9.
Looked brute force for small numbers.
59 and 119 were promising, but no cigar.
Then looked for agreement among
39 + multiples of 40,
69 + multiples of 70 and
89 + multiples of 90
Smallest one was 2519.
Question: In a certain warehouse, 90 percent of the packages weigh less than 75 pounds, and a total of 48 packages weigh less than 25 pounds. If 80 percent of the packages weigh at least 25 pounds, how many of the packages weigh at least 25 pounds but less than 75 pounds?
A.8
B.64
C.168
D.102
Answer: C.168
Explanation: If 80% of the packages weigh at least 25 pounds
This means that 20% of the packages weigh LESS THAN 25 pounds
Let T = TOTAL number of packages
So, 20% of T = # of packages that weigh LESS THAN 25 pounds
48 packages weigh LESS THAN 25 pounds
GREAT. So, 20% of T = 48
Rewrite to get: 0.2T = 48
Solve:T = 240
90% of the packages weigh less than 75 pounds
So, 90% ofT= number of packages that weigh less than 75 pounds
90% of240=216, so216packages weigh less than 75 pounds
OF THOSE216packages that weigh less than 75 pounds,48packages weigh less than 25 pounds.
So, the number of packages that weight BETWEEN 25 and 75 pounds =216-48= 168 = C
Question: Paul and Jack are 2 mechanics who work 8 hours per day changing oil in cars at The Oil Spot. If Paul can change oil in 2 cars per hour, and Jack can change oil in 3 cars per hour. What is the least number of cars per work day the 2 men can finish?
A.50
B.40
C.35
D.10
Answer: B.40
Explanation: The proportion equation can be used. Let x = number cars and C = least number of cars per day the 2 men can finish (C = x/(8 hours), P = cars per hour Paul can change, and J = cars per hour Jack can change. Note: 8 hours = a work day
P + J = C
(2 cars/hour) + (3 cars/hour) = x/(8 hours)
Proportion: 2/1 + 3/1/ = x/300
x = 8(2 + 3) = 40. At least 40 cars per work day.
Answer is B
Question: If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, then the
average marks of all the students is
A.54.48
B.54.68
C.54.6
D.54.58
Answer: B.54.68
Explanation: Explanation:
(55×50)+(60×55)+(45×60)55+60+45
8750160=54.68
Answer: Option B
Question: The total of 324 of 20 paise and 25 paise make a sum of Rs. 70. The no of 20 paise coins is
A.238
B.277
C.220
D.200
Answer: C.220
Explanation: Explanation:
Let the number of 20 paise coins be x. Then the no of 25 paise coins = (324 - x).
0.20 * (x) + 0.25 (324 - x) = 70 => x = 220..
Answer: C) 220
Question: Find compound interest on Rs. 8000 at 15% per annum for 2 years 4 months, compounded annually.
A.Rs 309
B.Rs 319
C.Rs 3109
D.Rs 109
Answer: C.Rs 3109
Explanation: Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.
Amount = Rs'. [8000 X (1+¬(15/100))2 X (1+((1/3)*15)/100)]
=Rs. [8000 * (23/20) * (23/20) * (21/20)]
= Rs. 11109.	.
:. C.I. = Rs. (11109 - 8000) = Rs. 3109.
ANSWER C 3109
Question: A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
A.22
B.77
C.10
D.27
Answer: C.10
Explanation: Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters.
Answer: C
Question: Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 300 as interest at the end of the loan period, what was the rate of interest?
A.3.6
B.6
C.5
D.24
Answer: C.5
Explanation: Let rate = R% and time = R years.
Then, (1200 x R x R)/100 = 300
12R2 = 300
R2 = 25
R = 5.
Answer: Option C
Question: Tanks A and E are each in the shape of a right circular cylinder. The interior of tank A has a height of 10 meters and a circumference of 8 meters, and the interior of tank E has a height of 8 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank E?
A.75%
B.80%
C.100%
D.120%
Answer: B.80%
Explanation: B.
For A, r=8/2pi. Its capacity = (4pi)^2 * 10= 160pi
For E, r=10/pi. Its capacity = (5pi)^2 *8 = 200pi
A/E = 160pi/200pi = 0.8=B.
Question: 15 years hence, Rohan will be just four times as old as he was 15 years ago.How old is Rohan at present?
A.20
B.25
C.30
D.35
Answer: B.25
Explanation: Let the present age of Rohan be x years
Then, given: x + 15 = 4 (x - 15)
x = 25
ANSWER:B
Question: The average age of a group of 10 students was 20. The average age increased by 2 years when two new students joined the group. What is the average age of the two new students who joined the group?
A.22 years
B.30 years
C.44 years
D.32 years
Answer: D.32 years
Explanation: Answer
The average age of a group of 10 students is 20.
Therefore, the sum of the ages of all 10 of them = 10 * 20 = 200
When two new students join the group, the average age increases by 2. New average = 22.
Now, there are 12 students.
Therefore, the sum of the ages of all 12 of them = 12 * 22 = 264
Therefore, the sum of the ages of the two new students who joined = 264 - 200 = 64
And the average age of each of the two new students = 64/2 = 32 years.
Answer D
Question: If a car had traveled 30 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 90 km, at what speed did it travel?
A.35 kmh
B.45 kmh
C.60 kmh
D.75 kmh
Answer: C.60 kmh
Explanation: Time = Distance/Speed
Difference in time = 1/2 hrs
90/x - 90/(x + 30) = 1/2
Substitute the value of x from the options. --> x = 60 --> 90/60 - 90/90 = 3/2 - 1 = 1/2
Answer: C
Question: Find the smallest number which when divided by 11 and 13 leaves respective remainders of 4 and 6.
A.187
B.197
C.207
D.136
Answer: D.136
Explanation: Let 'N' is the smallest number which divided by 11 and 13 leaves respective remainders of 4 and 6.
Required number = (LCM of 11 and 13) - (common difference of divisors and remainders) = (143) - (7) = 136.
ANSWER:D
Question: The number of degrees that the hour hand of a clock moves through between noon and 2.30 in the afternoon of the same day is?
A.38
B.27
C.75
D.28
Answer: C.75
Explanation: Explanation:
The hour hand moves from pointing to 12 to pointing to half way between 2 and 3. The angle covered between each hour marking on the clock is 360/12 = 30. Since the hand has covered 2.5 of these divisions the angle moved through is 75.
Answer: C
Question: 3034 - (1002 / 200.4) = ?
A.2984
B.3029
C.2982
D.2981
Answer: B.3029
Explanation: 3034-5 = 3029
Answer : B
Question: After driving to a riverfront parking lot, Bob plans to run south along the river, turn around, and return to the parking lot, running north along the same path. After running 3.25 miles south, he decides to run for only 50 minutes more. If Bob runs at a constant rate of 8 minutes per mile, how many miles farther south can he run and still be able to return to the parking lot in 50 minutes?
A. 1.5
B. 2.25
C. 3.0
D. 3.25
Answer: A. 1.5
Explanation: For the first 3.25 miles, Bob takes 3.25x8=26minutes
Say he runs 'x' miles further south. So the total distance he covers is (3.25+2x+3.25) in (50+26) minutes
So we have 6.5+2x=76/8 => x=1.5
Answer A
Question: There is 60% increase in an amount in 6 years at S.I. What will be the C.I. of Rs. 12,000 after 3 years at the same rate?
A.Rs.3389
B.Rs.3923
C.Rs.3972
D.Rs.3928
Answer: C.Rs.3972
Explanation: Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R = (100 * 60)/(100 * 6) = 10% p.a.
Now, P = Rs. 12000, T = 3 years and R = 10% p.a.
C.I. = [12000 * {(1 + 10/100)3 - 1}]
= 12000 * 331/1000 =Rs.3972
Answer:C
Question: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement?
A.1898
B.9801
C.1987
D.1900
Answer: D.1900
Explanation: 2000 ---- 54
2000 ---- 39
x ----- 20
x*20 = 2000*39
x = 3900
2000
-------
1900
Answer:D
Question: Find the length of the wire required to go 15 times round a square field containing 69696 m2.
A.15840 m
B.16840 m
C.15820 m
D.15640 m
Answer: A.15840 m
Explanation: a2 = 69696 => a = 264
4a = 1056
1056 * 15 = 15840
ANSWER:A
Question: Ram get 450 marks in his exam which is 90% of total marks. What is the total marks?
A.475
B.600
C.550
D.500
Answer: D.500
Explanation: X * (90/100) = 450
X = 5 * 100
X = 500
Answer: D