RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Evaluate combination
15C5
A.10000
B.3003
C.10
D.1
Answer: B.3003
Explanation: Explanation:
nCn=1
nCr=n!/r!(n-r)!
15C5=15!/5!(15-5)!=3003
Option B
Question: At what rate percent of simple interest will a sum of money double itself in 33 years?
A.6.54 %
B.4.54 %
C.8 .2 %
D.3.03 %
Answer: D.3.03 %
Explanation: Let sum = x. Then, S.I. = x.
Rate = (100 * S.I.) / (P * T) = (100 * x) / (x * 33)
= 100/33 = 3.03 %
ANSWER:D
Question: When a train travels at a speed of 70kmph,it reaches the destination on time.when the same train travels at a speed of 50kmph,it reaches its destination 15min late.what is the length of journey?
A.37.5km
B.50.5km
C.60km
D.85.5km
Answer: A.37.5km
Explanation: Let x be the time reached with the speed 70km/h
50km/h ----> x+15
Distance is equal so
70(km/h)× xhr = 50(km/h) × (x+15) hr
So
70 x = 50x + 750
So the would be in km
And x = 37.5
ANSWER:A
Question: John makes $60 a week from his job. He earns a raise andnow makes $72 a week. What is the % increase?
A.20%
B.16.66%
C.16.56%
D.17.66%
Answer: A.20%
Explanation: Increase = (12/60)*100 = (1/5)*100 = 20%.
A
Question: At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but,not together?
A.(5 + 5/11 )min past7
B.(5 + 5/11 )min past6
C.(5 + 5/11 )min past2
D.(5 + 5/11 )min past1
Answer: A.(5 + 5/11 )min past7
Explanation: When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.
At 7 o'clock, they are 25 min. spaces apart.
Minute hand will have to gain only 5 min. spaces.
55 min. spaces are gained in 60 min.
5 min spaces are gained in min = min
so, Required time = min past 7
Answer: A
Question: There are 42 people in a certain community who belong to the local golf club, tennis club or both clubs. If twice as many people belong to the tennis club as belong to the golf club, what could be the number of people who belong to both clubs?
A.1) 4
B.2) 7
C.3) 12
D.4) 21
Answer: C.3) 12
Explanation: x -> Golf Club
2x -> Tennis Club
y -> both
x+2x-y = 42
3x - y =42
multiples of 3 greater than 42
45
48
51
54-12=42
IMO (C)
Question: A fruit seller had some oranges. He sells 40% oranges and still has 300 oranges. How many oranges he had originally?
A.420
B.700
C.220
D.500
Answer: D.500
Explanation: Explanation :
He sells 40% of oranges and still there are 300 oranges remaining
=> 60% of oranges = 300
⇒ (60 × Total Oranges)/100 = 300
⇒ Total Oranges/100 = 5
⇒ Total Oranges = 5 × 100 = 500
Answer : Option D
Question: In May Mrs Lee's earnings were 50 percent of the Lee family's total income. In June Mrs Lee earned 20 percent more than in May. If the rest of the family's income was the same both months, then, in June, Mrs Lee's earnings were approximately what percent of the Lee family's total income ?
A.55
B.56
C.34
D.78
Answer: A.55
Explanation: Lets say the Family Income is 100
In May, lee earned 50Family income is 50
In june, Lee earned 20% more than May, so it is (50+20*50/100 = 60)
Family Income is same 50
In June Lee's Income percent is 60*100/110 ~ 55
Ans is A
Question: A dishonest dealer professes to sell goods at the cost price but uses a false weight and gains 25%. Find his false weight age?
A.2288
B.277
C.800
D.2878
Answer: C.800
Explanation: 25 = E/(1000 - E) * 100
1000 - E = 4E
1000 = 5E => E = 200
1000 - 200 = 800.Answer: C
Question: If a : b = 5 : 9 and b : c = 4: 7, find a : b : c
A.63:36:20
B.36:20:63
C.20:63:36
D.20:36:63
Answer: D.20:36:63
Explanation: a:b=5:9 and b:c=4:7= (4X9/4): (7x9/4) = 9:63/4
a:b:c = 5:9:63/4 =20:36:63.
Answer is D.
Question: The ratio of the ages of Anil and his son at present is 7 : 3. Six years hence, the ratio of the ages of the Anil's wife and the son will be 2 : 1. Find the ratio of the present ages of Anil and his wife?
A.3:2
B.4:1
C.3:2
D.Cannot be determined
Answer: D.Cannot be determined
Explanation: Answer: Option D
Explanation:
Let the present ages of Anil and his son be 7x and 3x years respectively.
Let the present age of the son's mother be m years.
(m + 6) / (3x + 6) = 2/1
m + 6 = 6x + 12 => m = 6x + 6
Ratio of the present ages of Anil and the son's mother = 7x / (6x + 6).
This cannot be found uniquely.
Answer:D
Question: There are 50 girls in a dance group in a private school. 30% of them dance hip hop and 80% dance ballet. How many of them dance both hip hop or ballet?
A.5
B.10
C.15
D.20
Answer: A.5
Explanation: The total number of girls in the class is n = 50.
The number of girls dancing hop hop is 30% of it, thus
n (A)=30/100×50=30/2=15.
The number of girls dancing ballet is 80%, thus
n (B)=80/100×50=80/2=40.
In order to calculate the number of girls dancing both hip hop and ballet we can use the following equation:
n (AnB)=n (A)+n (B) -n =15+40-50=5.
So, 5 girls in this dance class dance both hip hop and ballet.
ANSWER: A
Question: If 40% of a number is 24, then the number is
A.number is 60
B.number is 70
C.number is 90
D.number is 80
Answer: A.number is 60
Explanation: Solution:
Let "a" be the number we seek. We get
40% × a = 24
2 × 40% × a = 2 × 24 = 48
80% × a = 48
10% × a = 48 : 8 = 6
100% × a = 6 × 10 = 60
a = 60
Answer A
Question: A worker makes a toy in every 3h. If he works for 150h, then how many toys will he make ?
A.40
B.54
C.45
D.50
Answer: D.50
Explanation: No. of toys = 150/3 = 50
Answer : D
Question: Before January, the price of a dress was D and the price of a matching pair of shoes was H. In January, the price of the dress increased by 40% and the price of the shoes increased by 50%. In March, Roberta bought both items with a 30% discount. If D = 2H, which of the following represents the amount that Roberta paid?
A.D + 40
B.D + H – 1
C.D + 2H
D.3.01H
Answer: D.3.01H
Explanation: before Discount price was: 1.4D+1.5H
After Discount: 1.4D +1.5H-.42D-.45H
substitute D=2H
final value: 3.01H
Ans Is D :
Question: Jar A has 6% more marbles than Jar B . What percent of marbles from Jar A need to be moved into Jar B so that both jars have equal marbles?
A.2.8%
B.3.0%
C.3.2%
D.3.4%
Answer: A.2.8%
Explanation: An easy way to solve this question is by number plugging. Assume there are 100 marbles in Jar B then in Jar A there will be 106 marbles. Now, for both jars to have equal marbles we should move 3 marbles from A to B, which is 3/106=~2.8% of A.
Answer: A.
Question: Rs. 9800 are invested partly in 9% stock at 75 and 10% stock at 80 to have equal amount of incomes. The investment in 9% stock is:
A.Rs 4000
B.Rs 3000
C.Rs 5000
D.Rs 4500
Answer: C.Rs 5000
Explanation: investment 9% ==>x
investment in 10% stock = (9800-x)
9/75xx=10/80x(9800-x)
3x/25=9800-x/8
24x=9800x25-25x
49x=9800 x 25
x=5000
ANSWER C
Question: The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
A.178
B.169
C.245
D.178
Answer: C.245
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30
= 25/2 ==> 2(130 + X) = 750 ==> X
= 245 m.
Answer: C
Question: What should come in place of the question mark (?) in the following equation?
5978 + 6134 + 7014 = ?
A.19226
B.16226
C.19216
D.19126
Answer: D.19126
Explanation: ? = 5978 + 6134 + 7014 = 19126
Answer D
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 30 minutes. The waste pipe can empty the full cistern in?
A.8 min
B.7.5 min
C.5 min
D.9 min
Answer: B.7.5 min
Explanation: 1/10 + 1/15 - 1/x
= 1/30
x = 7.5
Answer: B
Question: A certain company employs 7 senior officers and 4 junior officers. If a committee is to be created, that is made up of 3 senior officers and 1 junior officer, how many different committee are possible?
A.8
B.24
C.58
D.140
Answer: D.140
Explanation: Number of ways to select 3 senior officers from 7 of them = 7C3 = 35 ways
Next we can determine the number of ways to select 1 junior officer.
number of ways to select 1 junior officer from 4 of them = 4C1 = 4 ways
Thus the number of ways to select 3 senior officers and 1 junior officer is 35 x 4 = 140 ways.
Answer: D
Question: Ajay can walk 10km in 1 hour. In how many hours he can walk 50km?
A.5hrs
B.10hrs
C.15hrs
D.20hrs
Answer: A.5hrs
Explanation: 1 hour he walk 10km
he walk 50km in = 50/10 * 1 = 5hours
Answer is A
Question: The radius of a semi circle is 6.5 cm then its perimeter is?
A.32.7
B.32.4
C.33.4
D.32.8
Answer: C.33.4
Explanation: 36/7 r = 6.5 = 33.4
Answer:C
Question: The average of 6 no.'s is 3.95. The average of 2 of them is 3.6, while the average of the other 2 is 3.85. What is the average of the remaining 2 no's?
A.4.2
B.4.4
C.4.6
D.5.6
Answer: B.4.4
Explanation: Sum of the remaining two numbers = (3.95 * 6) - [(3.6 * 2) + (3.85 * 2)]
= 8.8.
Required average = (8.8 / 2) = 4.4.
B
Question: 657.987 - ? + 56.84 = 324.943
A.A)899.015
B.B)752.804
C.C)389.884
D.D)629.906
Answer: C.C)389.884
Explanation: Explanation:
389.884
Answer: Option C
Question: The G.C.D. of 1.08, 0.36 and 0.7 is:
A.0.02
B.0.9
C.0.18
D.0.108
Answer: A.0.02
Explanation: Given numbers are 1.08, 0.36 and 0.70. H.C.F. of 108, 36 and 70 is 18,
H.C.F. of given numbers = 0.02.
Answer: Option A
Question: Find the odd man out. 2, 5, 10, 17, 26, 38, 50, 65
A.50
B.38
C.26
D.65
Answer: B.38
Explanation: Explanation :
The pattern is (1×1)+1 , (2×2)+1 , (3×3)+1 , (4×4)+1 , (5×5)+1 , (6×6)+1 , (7×7)+1 , (8×8)+1
Hence, in place of 38, the right number was (6×6)+1 = 37
Answer : Option B
Question: There are two taps, which are used to fill the tank and one tap to empty the tank. First tap fill the tank in 10 min., while the second takes quarter of an hour to fill the tank if both are operated independently.Third tap is capable of emptying the tank in seven and a half minutes. If all the taps are opened simultaneously how long (if ever) will it take for the tank to get filled completely?
A.10 minutes
B.20 minutes
C.30 minutes
D.40 minutes
Answer: C.30 minutes
Explanation: Pipe A fills the tank in 10 min
Pipe B fills the tank in 15 min
Pipe C empties the tank in 15/2 min
If all the three opened simultaneously then in 1 min
1/10 + 1/15 - 2/15 of the tank will be filled
that means 1/30 th of the tank will be filled in 1 min
So it will take 30 minutes to fill the tank completely if all three pipes opened
ANSWER:C
Question: How many numbers between 100 and 714 are divisible by 2, 3, and 7 together?
A.112
B.77
C.267
D.15
Answer: D.15
Explanation: Explanation:
As the division is by 2, 3, 7 together, the numbers are to be divisible by: 2*3*7 = 42
The limits are 100 and 714
The first number divisible is 42*3 = 126
To find out the last number divisible by 42 within 714:
714/42 = 17
Hence, 42*14 = 714 is the last number divisible by 42 within 714
Hence, total numbers divisible by 2, 3, 7 together are (17 â€“ 2) = 15
ANSWER: D
Question: The population of Linterhast was 3,600 people in 1990 and 4,800 people in 1993. If the population growth rate per thousand is constant, then what will be the population in 1996?
A.6000
B.6400
C.7200
D.8000
Answer: B.6400
Explanation: This is a set rate problem. If the population grew by 1,200 people in the past three years, then it grew by 33 percent:
4800−3600/3600=1200/3600=1/3≈33
Therefore in the next three years the population will grow at the same rate of 33% because the growth rate has been constant.
4,800+1/3∗4,800=4,800+1,600=6,400
Another approach is to backsolve by comparing the ratio of each answer to 4,800. For example, the ratio of 7,200 to 4,800 is not the same as the ratio of 4,800 to 3,600.
Answer: B
Question: A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
A.100
B.110
C.120
D.121
Answer: C.120
Explanation: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 6 = 120 m.
Answer: Option C
Question: An investment yields an interest payment of $231 each month. If the simple annual interest rate is 9%, what is the amount of the investment?
A.$28,300
B.$30,800
C.$31,300
D.$32,500
Answer: B.$30,800
Explanation: Let the principal amount = P
Simple annual interest = 9%
Simple monthly interest = (9/12) = (3/4)%
(3/4)*(P/100) = 230
=>P = (231 *4 * 10^2 )/3
= 77*4*10^2
= 308 * 10^2=30800
Answer B
Question: A case contains C cartons. Each carton contains B boxes, and each box contains 200 paper clips. How many paper clips are contained in 2 cases?
A.200BC
B.200B/C
C.400BC
D.400B/C
Answer: C.400BC
Explanation: 2 cases * C cartons/case * B boxes/carton * 200 clips/box = 400BC paper clips
The answer is C.
Question: Which of the following data sets has the second largest standard deviation?
A. {1, 2, 3, 4, 5}
B. {2, 3, 3, 3, 4}
C. {2, 2, 2, 4, 5}
D. {0, 2, 3, 4, 6}
Answer: D. {0, 2, 3, 4, 6}
Explanation: since we are asked to compare 'standard deviation', we should look out for similarity between all the sets..
The SIMILARITY is - the SUM of all sets is equal =15..
and hence average = 15/5 = 3...
Now we have 5 different sets which have AVG as 3, so we will look for the spread of the other elements of set around the AVERAGE..
clearly E has a range of 7-(-1) or 8, and has the highest standard deviation..
Next is D, which has a range of 6-0 or 6..
ans D
Question: If the number of boys in a class are 8 times the number of girls, which value can never be the total number of students?
A.42
B.45
C.41
D.40
Answer: A.42
Explanation: Let the number of girls = x and the number of boys = 8x
Then, total number of students = x + 8x = 9x
i.e., the total number of students must be a multiple of 9
From the given choices, 42 cannot be a multiple of 9.
Hence, 42 cannot be the total number of students.
Answer is A.
Question: A carpenter makes 5 bunk beds every day. A military school needs to organize a place to sleep for 143 soldiers. If there are 5 carpenters working on the job, how many whole days in advance should they receive the order and start working in order to finish the right number of beds assuming that each bunk- bed is used by two soldiers?
A.3.
B.4.
C.5.
D.6.
Answer: C.5.
Explanation: I believe it is C because if 1C makes 3 beds in 1 day then:
1C's rate = 3/1
So 5c's = 3/1 * 5 = 15/1 = 15 beds in a day.
Since we have 173 soldiers who need beds and bunk beds come in pairs, 72 is the least amount of beds needed.
Time = Amount / Rate
Time = 72 / (15/1) = 72/15, simplifying we get 72/15 = 24/5 = 4.9
So, in order for the carpenters to be able to finish they need 5 whole days. At first I made the mistake of thinking how many whole days it took them to finish (as in ignore the partial day) but the prompt clarifiesdays in advance, meaning how many days would they need to finish so even if they finish early, theyusedthat day.
C
Question: A dishonest dealer professes to sell his goods at Cost Price but still gets 20% profit by using a false weight. What weight does he substitute for a kilogram?
A.833 1/7 grams
B.833 1/3 grams
C.833 8/3 grams
D.933 1/3 grams
Answer: B.833 1/3 grams
Explanation: If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.
If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm ------ 100 gm
1000 gm ------ ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams.
Answer:B
Question: The average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 44 with him, what was the average amount with the group before his joining the group?
A.s.16
B.s.14
C.s.15
D.s.22
Answer: A.s.16
Explanation: Total members in the group = 7
Average amount = Rs. 20
Total amount with them = 7 * 20 = Rs. 140
One number has Rs. 44. So, the amount with remaining 6 people = 140 - 44 = Rs. 96
The average amount with them = 96/6 = Rs.16.
Answer:A
Question: Solution for 1.35+.123+.321
A.2.91
B.1.794
C.1.338
D.1.986
Answer: B.1.794
Explanation: 1.35+.123+.321=0
0=0-1.35-0.123-0.321
0=-1.794
answer :B
Question: By selling 24 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
A.16
B.7
C.6
D.4
Answer: A.16
Explanation: 80% --- 24
120% --- ?
80/120 * 24
= 16
Answer:A
Question: Solution X is 40% chemical A and 60% chemical B by volume. Solution Y is 50% chemical A and 50% chemical B by volume. If a mixture of X and Y is 47% chemical A, what percent of the mixture is Solution X?
A.15%
B.20%
C.25%
D.30%
Answer: D.30%
Explanation: The volume of the mixture be X+Y.
0.4X +0.5Y=0.47(X+Y)
X=3Y/7
X/(X+Y)=(3Y/7) / (10Y/7)=3/10=30%.
The answer is D.
Question: The closest approximation of Q=(69.28 × 0.004)/0.03 is
A.0.092
B.0.92
C.9.2
D.92
Answer: C.9.2
Explanation: Q=(69.28 × 0.004)/0.03
1. 0.004 = 4 × 10^(-3)
2. 0.03 = 3 × 10^(-2)
3. (a × b)/c = a × (b/c)
4. 0.004/0.03 = 4 × 10^(-3)/ (3 × 10^(-2)) = 4 × 10^( -3 - (-2))/3 = 4 × 10^(-1) / 3 = (4/3) × 10^(-1) = 1.333 × 10^(-1)
Therefore,
(69.28 × 0.004)/0.03 = 69.28 × (0.004/0.03) = 69.28 × 1.33 × 10^(-1) = 69.28 × 1.33/10 = 6.928*1.33
Now,
7 × 2 = 14
7 × 1 = 7
or better:
6.9 × 1 = 6.9
6.9 × 2 = 13.8
hence,
6.9 <6.928 × 1.33 < 13.8
9.2 is the only answer that satisfies this condition.C
Question: 1,2,2,4,8,32,?(mult)
A.2816
B.1816
C.2812
D.2817
Answer: A.2816
Explanation: Each number is the product of the previous two numbers, ie 8*32 = 2816.
Answer :A
Question: The elevator in an eleven-story office building travels at the rate of one floor per 1/4 minute, which allows time for picking up and discharging passengers. At the main floor and at the top floor, the operator stops for 1 minute. How many complete trips will an operator make during a 5-hour period?
A.88
B.56
C.45
D.42
Answer: D.42
Explanation: Complete trip = 10 floors up and 10 floors down = 20 floors = 20*1/4 = 5 minutes plus 2 minutes = 7 minutes.
5 hour = 300 minutes.
In 300 minutes operator can make 300/7=42 trips.
Answer: D.
Question: man is 28 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
A.14years
B.26 years
C.17 years
D.18 years
Answer: B.26 years
Explanation: Let the son's present age be x years. Then, man's present age = (x + 20) years.
(x + 28) + 2 = 2(x + 2)
x + 30 = 2x + 4
x = 26.
answer :B
Question: Crew A can build a complete car in 20 minutes and Crew B can build a complete car in 25 minutes. If both crews work independently and start at the same time, what is the shortest amount of time R it could take for 10 cars to be complete?
A.111 1/9 minutes
B.115 2/5 minutes
C.116 minutes
D.120 minutes
Answer: D.120 minutes
Explanation: A builds 4 cars in 80 min
B builds 4 cars in 100 min
So A builds another car in another 20 min (i.e total 5 cars)
B builds another car in another 25 minutes (i.e, total 5 cars)
However, A can build another car in next 20 min (i.e total 6 cars)
So total time R= 125 min by B, which is > 120 min by A
B - 4 cars, A - 6 cars
Answer = D
Question: The length of the bridge, which a train 130 m long and traveling at 45 km/hr can cross in 30 sec is?
A.235
B.240
C.245
D.250
Answer: C.245
Explanation: Speed = 45 * 5/18 = 25/2 m/sec.
Time = 30 sec
Let the length of bridge be x meters.
Then, (130 + x)/30 = 25/2
x = 245 m.
Answer: Option C
Question: R campers fished for 5 hours. If m of the campers caught 2 fish apiece and the rest caught a combined total of n fish, how many fish did the R campers catch per hour?
A.2m + n(R-m)
B.(2m + n(R-m))/3
C.(2m + n(m-R))/3
D.(2m + n)/5
Answer: D.(2m + n)/5
Explanation: m of the campers caught 2 fish apiece in 5 hours --> total fish caught by m campers = 2m;
The rest caught a combined total of n fish.
Total fish caught in 5 hours = 2m+n --> per hour (2m+n)/5.
Answer: D.
Question: if the angles of an n sided polygon are in A.P and a>=20 and d>=20 then wat is the maximum possible value of n?
A.12
B.14
C.21
D.25
Answer: B.14
Explanation: Sum of Interior angles of a polygon = (n-2) × 180° where n = number of sides
There will be n angles which are in A.P. Therefore,
Since we need to find maximum value of n, put minimum value for a and d.i.e., take a=20 and d=20
Then sum of the angles
=n/2[2×20+(n−1)20]
Therefore,
10n(n+1)=(n−2)180
n=14.52
Since number of sides must be a positive integer, maximum value of n = 14
ANSWER:B
Question: By how much is three-fifth of 350 greater than four-seventh of 210 ?
A.90
B.100
C.110
D.120
Answer: A.90
Explanation: Explanation:
3/5 of 350 - 4/7 of 210 = 210 - 120 = 90.
Answer: A
Question: If the number 517*324 is completely divisible by 3, then the smallest whole number in the place of * will be:
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = (22 + x), which must be divisible by 3.
x = 2.
Answer B) 2.
Question: A present value of a machine is $900. Its value depletiation rate is 25% per annum then find the machine value before 2 years?
A.$1500
B.$1200
C.$1600
D.$1000
Answer: C.$1600
Explanation: P= $900
R = 25%
T = 2 years
Machine value before 2 years = P/[(1-R/100)^T]
=900*4/3 * 4/3
=$1600
Answer is C
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 30, the dividend is:
A.A)5322
B.B)5330
C.C)2280
D.D)5340
Answer: C.C)2280
Explanation: Divisor = (5 * 30) = 150
= 10 * Quotient = Divisor
=> Quotient = 150/10 = 15
Dividend = (Divisor * Quotient) + Remainder
Dividend = (150 * 15) + 30 = 2280.
C
Question: The length of the bridge, which a train 200 metres long and travelling at 60 km/hr can cross in 30 seconds, is?
A.720
B.470
C.270
D.370 m.
Answer: D.370 m.
Explanation: Speed = [60 X 5/18] m/sec = [50/3] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30
= 50/3 => (130 + x)/30
= 370=> x
= 370 m.
Answer:D
Question: 4000 was divided into two parts such a way that when first part was invested at 3% and the second at 5%, the whole annual interest from both the investments is Rs.144, how much was put at 3%?
A.3299
B.2690
C.2800
D.2692
Answer: C.2800
Explanation: (x*3*1)/100 + [(4000 - x)*5*1]/100 = 144
3x/100 + 200 – 5x/100 = 144
2x/100 = 56 è x = 2800.Answer: C
Question: There are 30 students in a certain geometry class. If two thirds of the students are boys and three fourths of the boys are under six feet tall, how many boys in the class are under six feet tall?
A.6
B.12
C.15
D.24
Answer: C.15
Explanation: 30*2/3 *3/4= 15
Answer: C
Question: 96% of the population of a village is 23040. The total population of the village is?
A.16800
B.1689
C.6795
D.24000
Answer: D.24000
Explanation: Explanation:
X * (96/100) = 23040
X = 240 * 100
X = 24000
Answer: D
Question: Value of
(256)5/4
A.1012
B.1024
C.1048
D.525
Answer: B.1024
Explanation: Explanation:
=(256)5/4=(44)5/4=4(5)=1024
Option B
Question: A car traveled 281 miles in 4 hours 41 minutes. What was the average speed of the car in miles per hour?
A.100 miles / hour
B.90 miles / hour
C.70 miles / hour
D.60 miles / hour
Answer: D.60 miles / hour
Explanation: We first convert the time of 4 hours 41 minutes in minutes
4 hours 41 minutes = 4 ? 60 + 41 = 281 minutes
Average speed S is given by distance / time. Hence
S = 281 miles / 281 minutes = 1 mile / minute
= 60 miles / hour
correct answer D
Question: The average score in an examination of 10 students of a class is 60. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark was 50 and the maximum mark was 100. It is also known that none of the students failed. If each of the top five scorers had distinct integral scores, the maximum possible score of the topper is
A.90
B.99
C.92
D.94
Answer: B.99
Explanation: The average score in an examination of 10 students of a class is 60 --> the total score = 10*60 = 600;
The 5 smallest scores have an average of 55 --> the total score of the 5 smallest scores = 275.
From above, the total score of the 5 largest scores = 600 - 275 = 325.
Say the 5 largest scores are a, b, c, d, and e (where a<b<c<d<e, since each of the top five scorers had distinct scores). We want to maximize e. To maximize e, we need to minimize a, b, c, and d. The least value of a, is 55 (The least score of the top 5 , a, should be equal to the highest of the bottom 5 and to minimize the highest of the bottom 5, all scores from the bottom 5 should be equal). In this case the least values of b, c, and d are 56, 57, and 58 respectively:
a + b + c + d + e = 55 + 56 +57 + 58 + e = 325;
e = 99.
Answer: B.