RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 3025., the number of the member is the group is:
A.55
B.67
C.77
D.87
Answer: A.55
Explanation: Money collected = (30.25 x 100) paise = 3025 paise.
Number of members =Square root of 3025 = 55.
Answer: Option A
Question: What ratio must a shopkeeper mix Peas and Soybean of Rs.16 and Rs. 25/kg, As to obtain a mixture of Rs.21?
A.10 : 7
B.9 : 8
C.4 : 5
D.13 : 11
Answer: C.4 : 5
Explanation: Correct option: (C)
Use rule of alligation, to determine the ratio
The required ratio of Soybean and Peas = 4 : 5
Question: Dick and Jane each saved $2,000 in 1989. In 1990 Dick saved 10 percent more than in 1989, and together he and Jane saved a total of $4,000. Approximately what percent less did Jane save in 1990 than in 1989?
A.10%
B.20%
C.25%
D.30%
Answer: A.10%
Explanation: 1990
Dick saved = $ 2200
Jane saved = $ 1800 (jane saved $200 less than she did the prior year)
Jane saved approximately $200/2000$ (10%) less in 1990
Answer: A
Question: A train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the train?
A.300 m
B.270 m
C.200 m
D.250 m
Answer: B.270 m
Explanation: speed = 72*5/18 = 20 m/sec
t = 26 sec
length => x
x+250 = 520
x= 270
ANSWER B
Question: X can lay railway track between two station in 16; Y can do the same work in 20 days,both are working together for 2 days after Y left the job then how many days X requires to complete the remaining work ? Total number of days taken to complete the whole work?
A.7 Days and 9 days
B.5.89 Days and 7.89 days
C.8.26 Days and 10.26 days
D.7.75 Days and 9.75 days
Answer: D.7.75 Days and 9.75 days
Explanation: First take LCM of (16,20) = 160; Total work = 160; X's one day work = 160/16 =10; Y's one day work =160/20 = 8; One day work of both X+Y= 10+8 = 18; Total work completed in 2 days = 18*2=36; remaining work is = 160 - 36 =124; remaining work completed by X in = 124/16= 7.75 days.Total number of days taken to complete the whole work = 2+7.75 = 9.75 days.
Answer =D
Question: By selling an article at Rs.600, a profit of 25% is made. Find its cost price?
A.228
B.200
C.279
D.480
Answer: D.480
Explanation: SP = 600
CP = (SP)*[100/(100+P)]
= 600 * [100/(100+25)]
= 600 * [100/125] = Rs.480.Answer:D
Question: If two sides of a triangle have lengths 4 and 7, which of the following could be the perimeter of the triangle?
I. 9
II. 15
III. 19
A.None
B.I only
C.II only
D.II and III only
Answer: D.II and III only
Explanation: Let x be the length of the third side.
7-4 < x < 7+4
3 < x < 11
14 < perimeter < 22
The answer is D.
Question: A can run a kilometer race in 4 1/2 min while B can run same race in 5 min. How many meters start can A give B in a kilometer race, so that the race mat end in a dead heat?
A.188m
B.278m
C.887m
D.100m
Answer: D.100m
Explanation: A can give B (5 min - 4 1/2 min) = 30 sec start.
The distance covered by B in 5 min = 1000 m.
Distance covered in 30 sec = (1000 * 30)/300 = 100 m.
A can give B 100m start.
Answer: D
Question: Two trains start simultaneously from opposite ends of a 140-km route and travel toward each other on parallel tracks. Train X, traveling at a constant rate, completes the 140-km trip in 4 hours. Train Y, travelling at a constant rate, completes the 140-km trip in 3 hours. How many kilometers had Train X traveled when it met Train Y?
A.60
B.64
C.68
D.72
Answer: A.60
Explanation: If the two trains cover a total distance D, then Train X travels (3/7)*D while Train Y travels (4/7)*D. If the trains travel 140 km to the meeting point, then Train X travels (3/7)*140 = 60 km.
The answer is A.
Question: The area of a circle is subtracted from its diameter, and the circumference is then added to this total, the result is 0. What is the radius of the circle?
A.2*pi
B.pi
C.1
D.2
Answer: D.2
Explanation: The equation is; diameter - Area + Circumference = d - A + C = d - pi * r^2 + 2 * pi * r = 2r - pi * r(r + 2).
By plugging in the answers we can test the answers quickly; then, 2 is the only possible answer.
Answer: D
Question: Bullock likes to keep a spare tyre in his car every time. On a certain day, he travels 1, 30,000 km and just to make the most of all the tyres, he changes the tyres between his journey such that each tyre runs the same distance.
What is the distance traveled by each tyre?
A.104,000
B.60,000
C.80,000
D.90,000
Answer: A.104,000
Explanation: The distance traveled by each tyre:
4/5 * 1, 30, 000km = 104,000 km. A
Question: In a group of ducks and cows, the total number of legs are 34 more than twice the no. of heads. Find the total no.of buffaloes.
A.11
B.12
C.14
D.17
Answer: D.17
Explanation: Let the number of buffaloes be x and the number of ducks be y
=> 4x + 2y = 2 (x + y) + 34
=> 2x = 34 => x = 17
D
Question: The positive number x is q percent greater than the positive number b, which is p percent less than x itself. If a is increased by p percent, and the result is then decreased by q percent to produce a positive number c, which of the following could be true?
I. c > x
II. c = x
III. c < x
A.I only
B.II only
C.III only
D.I and II only
Answer: C.III only
Explanation: Let q = 10% then p = 100/11 %
let b = 100 then x = 110
after increasing x by p and decreasing by q we get c= 108
therefore c<x
C it is answer
Question: A certain company had a total annual expenditure of 2.55∗10^7 on employee salaries last year. If the company employed 425 people, what was the average employee salary?
A.$60,000
B.$25,000
C.$35,000
D.$40,000
Answer: A.$60,000
Explanation: Given: Total annual expenditure of 2.55∗10^7 on employee salaries
Total employees = 425
Observe that 425*6 = 2550
Therefore try to bring the numerator in terms of 2550
Average salary = (2550*10^4) /425 = 6*10^4 = 60,000
Option A
Question: In a class of students, the ratio of girls to boys is 1:2. If 3 more girls joined the class, the ratio would be 3:4. How many students are in the class?
A.16
B.18
C.20
D.22
Answer: B.18
Explanation: Let x be the number of students in the class.
(1/3)*x=(3/7)(x+3)-3
7x=9x+27-63
2x=36
x=18
The answer is B.
Question: A fair coin is tossed 3 times. What is the probability of getting at least 2 heads?
A.3/4
B.3/2
C.1/4
D.1/2
Answer: D.1/2
Explanation: Let's find the probability of 2 heads , 3 heads
P(HHH)=((1/2)^3=1/8.
P(HHT)=(3!/2!)*(1/2)^3=3/8
Total Probablity = 1/8 + 3/8
=1/2
Answer(D)
Question: Which one of the following is the sum of the numbers 1, 3, 5, 7, 9â€¦. up to nth number?
A.N2 + 1
B.N2 - 1
C.N(N + 1)/2
D.N2
Answer: D.N2
Explanation: Explanation:
N2
Answer: D
Question: A car costs a dealer Rs.50,000.Dealer raised price by Rs.10,000 and then deducted 4% of new price.
What is the profit/loss %?
A.14
B.15
C.15.2%
D.16
Answer: C.15.2%
Explanation: Ans: Let P be the percentage of price raised=(10000/500000) * 100 =20%
Discount %=4%
profit %=(20-4- 20*4/100 ) =15.2%
Answer C
Question: If 'c' is a positive integer exactly divisible by 6 or 5 but not divisible by 12.What could possibly be the value of 'c' ?
A.30
B.60
C.120
D.24
Answer: A.30
Explanation: 60 and 120 are both divisible by 6 and 5 but also by 12. so they are not the right answer.
24 and 72 are both clearly not divisible by 5(not correct)
30 is both divisible by 6 and 5 but not by 12.
answer : (A) 30
Question: What number continues the sequence?
25, 50, 27, 46, 31, 38, 39, ?
A.11
B.33
C.52
D.22
Answer: D.22
Explanation: D
22
There are two alternate sequences, the first increases by 2, 4, 8 etc and the second decreases by 4, 8, 16 etc.
Question: Victor gets 92 % marks in examinations. If these are 368 marks, find the maximum marks.
A.334
B.500
C.400
D.288
Answer: C.400
Explanation: Let the maximum marks be m
Then 92 % of m = 368
⇒ 92/100 × m = 368
⇒ m = (368 × 100)/92
⇒ m = 36800/92
⇒ m = 400
Therefore, maximum marks in the examinations are 400.
Answer : C
Question: If n is a prime number greater than 3, what is the remainder when n^2 is divided by 12 ?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: There are several algebraic ways to solve this question, but the easiest way is as follows: since we cannot have two correct answers just pick a prime greater than 3, square it and see what would be the remainder upon division of it by 12.
n=5 --> n^2=25 --> remainder upon division 25 by 12 is 1.
Answer: B
Question: If a quality control check is made inspecting a sample of 2 light bulbs from a box of 10 lighbulbs, how many different samples can be chosen?
A.6
B.24
C.45
D.66
Answer: C.45
Explanation: Try using the formula for combinations:
n!/r!(n-r)!
10!/2!(10-2)!
10!/2!*8!
10*9/2*1
=45
C
Question: A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 20 sec respectively. What is the speed of the train?
A.27.8 km/hr
B.22.9 km/hr
C.26.6 km/hr
D.79.2 km/hr
Answer: D.79.2 km/hr
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/20 = y
y = 22
Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.
Answer: D
Question: A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 10 per metre of cloth. What is the cost price of one metre of cloth?
A.95
B.28
C.90
D.26
Answer: A.95
Explanation: Explanation:
SP of 1m of cloth = 8925/85 = Rs. 105
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 10 = Rs. 95.
Answer: A
Question: A fort had provision of food for 150 men for 45 days. After 20 days, 40 men left the fort. The number of days for which the remaining food will last, is:
A.29	1/5
B.37	1/4
C.42
D.34
Answer: D.34
Explanation: we have food for 150 men for 45 days.
After 20 days food left for 150 men for 25 days.
so
150 : 25
now we have 110 men and x days
110 : 150 :: 25 : x
x = (150*25)/110 = 34 days.
ANSWER:D
Question: Set A {3,3,3,4,5,5,5} has a standard deviation of 1. What will the standard deviation be if every number in the set is multiplied by 7?
A.A)1
B.B)2
C.C)4
D.D)7
Answer: D.D)7
Explanation: Points to remember -
1. If oneAdd/Subtractthe same amont from every term in a set, SD doesn't change.
2. If oneMultiply/Divideevery term by the same number in a set, SD changes by same number.
Hence the answer to the above question is D
Question: A certain machine produces 650 units of product P per hour. Working continuously at this constant rate, this machine will produce how many units of product P in 7 days?
A.7,000
B.24,000
C.40,000
D.109,200
Answer: D.109,200
Explanation: Since 7 days consist of 24*7 hours the total hours of a week is 168 hours.
Since every hour the machine produces 650 units of product P the total product during 168 hours is 650*168= 109,200
Correct Option : D
Question: What is the place value of 5 in the numeral 5259
A.2500
B.3400
C.3500
D.5000
Answer: D.5000
Explanation: Option 'D'
5 * 1000 = 5000
Question: If Re.1 amounts to Rs.9 over a period of 20 years. What is the rate of simple interest?
A.49%
B.90%
C.60%
D.40%
Answer: D.40%
Explanation: 8 = (1*20*R)/100
R = 40%
Answer:D
Question: A cistern 6 m long and 4 m wide contains water up to a breadth of 1 m 25 cm. Find the total area of the wet surface.
A.42 m sqaure
B.49 m sqaure
C.52 m sqaure
D.64 m sqaure
Answer: B.49 m sqaure
Explanation: Explanation:
Area of the wet surface =
2[lb+bh+hl] - lb = 2 [bh+hl] + lb
= 2[(4*1.25+6*1.25)]+6*4 = 49 m square
Option B
Question: When positive integer p is divided by positive integer x, the remainder is 5 and when positive integer q is divided by positive integer y, the remainder is 8. Which of the following is a possible value for x + y?
I.16
II. 15
III. 14
A.I and II only
B.II only
C.III only
D.II and III only
Answer: A.I and II only
Explanation: p/x -- remainder is 5 => x is anything greater than 5. Minimum value of x could be 6.
q/y -- remainder is 8 => y is anything greater than 8. Minimum value of y could be 9.
Hence, the minimum value of x+y = 15. So, I and II are correct.
ANSWER:A
Question: The average age of a group of 16 students was 20. The average age increased by 2 years when two new students joined the group. What is the average age of the two new students who joined the group?
A.22 years
B.30 years
C.38 years
D.32 years
Answer: C.38 years
Explanation: Answer
The average age of a group of 16 students is 20.
Therefore, the sum of the ages of all 16 of them = 16 * 20 = 320
When two new students join the group, the average age increases by 2. New average = 22.
Now, there are 18 students.
Therefore, the sum of the ages of all 18 of them = 18 * 22 = 396
Therefore, the sum of the ages of the two new students who joined = 396 - 320 = 76
And the average age of each of the two new students = 76/2 = 38 years.
Answer C
Question: Which of the following is NOT prime?
A.1,556,551
B.2,442,113
C.3,893,257
D.3,999,991
Answer: D.3,999,991
Explanation: 3,999,991 = 4,000,000 - 9 = (2000)^2 - 3^2
So this number is a product of two numbers other than 1 and itself. This means it is not prime. This must be the answer.
Let's take a look at (E) too.
9,999,991 = 10,000,000 - 9
Here the difference is that 10,000,000 is not a perfect square. It has odd number of 0s. So this would be a prime number.
Answer (D)
Question: There are 100 students in a college class of which 36 are boys studying Tamil & 13 girls not studying Tamil. If there are 55 girls in all, then the probability that a boy picked up at random is not studying Tamil, is
A.1/5
B.2
C.3
D.4
Answer: A.1/5
Explanation: There are 55 girls and 45 boys in the college. Out of 45 boys, 36 are studying Tamil and 9 are not studying Tamil. The probability that a boy picked up at random is not studying Tamil= 9/45 = 1/5
A
Question: There are some chickens and some chicken field. If we sell 75 chickens Then the feed will last 20 days longer.If we buy 100 chickens more, then the feed will get over before 15 days.What is the present number of chickens?
A.100
B.200
C.300
D.400
Answer: C.300
Explanation: let x=number of chicken,y=no of days,z= each day chicken's feed....so total feed=xyz then eqn 1 will be xyz=(x-75)(y+20)z.....
and eqn 2 will be xyz=(x+100)(y-15)z if we solve this two eqn we get x=300
ANSWER:C
Question: The ratio of efficiency of A is to C is 5:3.The ratio of no.of days taken by B is to C is 2:3.A takes 6 days less than C,when A and C completes the work individually.B and C left the work after 2 days.the no of days taken by A to finish the remaining work?
A.4.5
B.5
C.6
D.7
Answer: C.6
Explanation: A : B : C
Efficiency 10 : 9 : 6
No of days 9x : 10x : 15x
given=> 15x-9x = 6
hence, x = 1
Number of days taken by A = 9 and daily work done=10
Number of days taken by B= 10 and daily work done=9 (total work =90)
Number of days taken by C = 15 and daily work done=6
work done by B and C in initial 2 days =30
rest work =60
Number of days required by A to finish = 60/10=6 days
ANSWER:C
Question: When tossing two coins once, what is the probability of heads on both the coins?
A.3/4
B.2/4
C.1/3
D.1/4
Answer: D.1/4
Explanation: Since two coins are tossed, sample space = 4
Getting heads on both the coins=1
p(E) = 1/4 = 1/4
ANSWER:D
Question: The number of years of service of the eight employees in a production department are 15, 10, 9, 17, 6, 5, 14 and 16. What is the range in the number of years of service of the eight employees?
A.10
B.11
C.12
D.13
Answer: C.12
Explanation: = 17-5
= 12
Answer C
Question: L.C.M of two numbers is 192 and there H.C.F is 16. If one of them is 48. Find the other
A.32
B.64
C.48
D.68
Answer: B.64
Explanation: Explanation:
Product of two numbers = product of their L.C.M and H.C.F
48 x a = 192 x 16
a = (192 x 16)/48 = 64
Answer: Option B
Question: A Cistern is filled by pipe A in 8 hrs and the full Cistern can be leaked out by an exhaust pipe B in 12 hrs. If both the pipes are opened in what time the Cistern is full?
A.12 hrs
B.24 hrs
C.16 hrs
D.32 hrs
Answer: B.24 hrs
Explanation: Explanation :
Pipe A can fill 1⁄8 of the cistern in 1 hour.
Pipe B can empty 1⁄12 of the cistern in 1 hour
Both Pipe A and B together can effectively fill 1⁄8-1⁄12= 1⁄24 of the cistern in 1 hour
i.e, the cistern will be full in 24 hrs. Answer : Option B
Question: Among the employees of a certain company, 52 percent of the employees are male and 48 percent are female. In this company 60 percent of the male employees are married and 50 percent of the female employees are married. If one employee in the company is randomly selected, approximately what is the probability that he or she is NOT married?
A. 0.4
B. 0.3
C. 0.5
D. 0.6
Answer: A. 0.4
Explanation: Much faster: draw 4 quadrants
______________Male (52%)_____Female (48%)
Married :__________60%____________40%
Not Married:_______30%____________50%
Therefore: the probability of picking one random person Not Married (he or she) is: 0,52 x 0,30 + 0,50 x 0,50 = 0,15 + 0,25 (approx.)
Solution: approx. 0,4 (answer A)
Question: There are 50 employees in the office of ABC Company. Of these, 22 have taken an accounting course, 15 have taken a course in finance and 14 have taken a marketing course. Nine of the employees have taken exactly two of the courses and 3 employee has taken all three of the courses. How many of the 50 employees have taken none of the courses?
A.9
B.8
C.14
D.10
Answer: C.14
Explanation: 50 Employees. Counting every different attendand to the courses we have:
Accounting: 22
Finance: 15
Marketing: 14
Which would add up to 51 different attendands, which is not possible.
Now 9 have taken exactly 2 courses, which means that there are 9 less different attendands. Say that 9 of the Finance attentands also attended Accounting.
51-9= 42
3 Person has taken all three courses. As above, we subtract him from the number of different attendands. Since this time the person took all three courses, we have to substract him two times.
42-6= 36.
Answer : C
Question: Define r* by the equation r* = π-r. Then ((−π)*)* =
A. −2π
B. -1
C. −π
D. 2π
Answer: C. −π
Explanation: for r* f(f(−π)) = f(π − (−π)) = f(π + π) = f(2π) = π − 2π = −π=C
Question: In how many ways the word "DARKEST" can be arranged?
A.5040
B.4506
C.3450
D.8900
Answer: A.5040
Explanation: Explanation :
The required number of ways = 7!
= 5040
Answer : A
Question: A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: DS = 6
US = 4
S = ?
S = (6 - 4)/2 = 1 kmph Answer: A
Question: A chartered bank offers a five-year Escalator Guaranteed Investment Certificate.In successive years it pays annual interest rates of 4%, 4.5%, 5%, 5.5%, and 6%, respectively, compounded at the end of each year. The bank also offers regular five-year GICs paying a fixed rate of 5% compounded annually. Calculate and compare the maturity values of $1000 invested in each type of GIC. (Note that 5% is the average of the five successive one-year rates paid on the Escalator GIC.)
A.1276.28
B.1276.22
C.1276.29
D.1276.21
Answer: A.1276.28
Explanation: Explanation:
FV = $1000(1.04)(1.045)(1.05)(1.055)(1.06) = $1276.14
the maturity value of the regular GIC is
FV = $= $1276.28
Answer: A) 1276.28
Question: Each side of a certain parallelogram has length 5. If the area of the parallelogram is 20. Which of the following is the measure of one of its angles?
A.30
B.45
C.53.13
D.90
Answer: C.53.13
Explanation: area of a parallelogram = b*h
b*h=20
h=20/5=4
sin theta =opp/hyp= 4/5
theta = sin inv of 4/5=53.13 deg
C
Question: Find the Value of X :log(x+1) + (log(x-1) = log8
A.5
B.3
C.6
D.9
Answer: B.3
Explanation: Explanation:
log(x+1)(x-1) = log8
log(x^2-1) = log8
x^2-1 = 8
x^2 = 9
x = {-3, 3}
Testing for extraneous solutions eliminates -3 leaving you with:
x = 3
Answer B
Question: The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child ?
A.4 years
B.8 years
C.10 years
D.12 years
Answer: A.4 years
Explanation: Solution
Let the ages of the children be x,(x+3),(x+6),(x+9) and (x+12) years.
Then,	x+(x+3)+(x+6)+(x+9)+(x+12)=50
5x=20
x=4.
Age of the youngest child	=4 years.
Answer A
Question: If the time is currently 1:30 pm, what time will it be in exactly 643 hours?
A.5:30 am
B.6:30 am
C.7:30 am
D.8:30 am
Answer: D.8:30 am
Explanation: 643 = 26(24) + 19/24
The time will be 19 hours later than 1:30 pm which is 8:30 am.
The answer is D.
Question: The ratio of the cost price and selling price is 2:3. The profit percent is?
A.20%
B.25%
C.50%
D.75%
Answer: C.50%
Explanation: Let the C.P. = $2x
Then S.P. = $3x
Then, Gain = 3x-2x = $x
Gain% = x/2x *100 = 50%
Answer is C
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when No boy gets more than one prize?
A.12
B.15
C.18
D.24
Answer: D.24
Explanation: Sol. In this case, repetitions are not allowed. So, the first prize can be given in 4 ways. The second in 3 ways and the third in 2 ways. But fundamental principle, (4 x 3 x 2) ways = 24 ways
4: Or 4p = — 4:- 4X3X2X1- 24 ways
D
Question: A boy traveled from the village to the post-office at the rate of 12.5 kmph and walked back at the rate of 2 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village.
A.5 km
B.7 km
C.9 km
D.10 km
Answer: D.10 km
Explanation: Explanation :
Solution: Average speed = 2xy/(x+y) km/hr
= (2*12.5*2)/(12.5+2) km/hr
= 50/14.5 km/hr.
Total distance = (50/14.5 * 29/5) km.
= 20 km.
Required distance = 20/2 = 10 km.
Answer : D
Question: The first flight out of Phoenix airport had a late departure. If the next three flights departed on-time, how many subsequent flights need to depart from Phoenix on-time, for the airport's on-time departure rate to be higher than 40%?
I will see what is the quickest way to solve it then I will provide the explanation
A.6
B.2
C.9
D.10
Answer: B.2
Explanation: The following approach might be the easiest one and less error prone.
We need on-time departure rate to be higher than 4/10, so it should be at least 5/11, which means that 5 out of 11 flights must depart on time. Since for now 3 out of 4 flights departed on time then 5-3=2 subsequent flights need to depart on-time.
Answer: B.
Question: There are 5 pairs of socks and 2 socks are worn from that such that the pair of socks worn are not of the same pair. what is the number of pair that can be formed.
A.19
B.20
C.30
D.32
Answer: B.20
Explanation: First of all you should remember that there is a difference in left and right sock.
now no. of way to select any of the sock = 5
and for second = 4
so total methods = 5*4 = 20
ANSWER:B
Question: Due to construction, the speed limit along an 4-mile section of highway is reduced from 55 miles per hour to 35 miles per hour. Approximately how many minutes more will it take to travel along this section of highway at the new speed limit than it would have taken at the old speed limit ?
A.A) 3.12
B.B) 8
C.C) 2.49
D.D) 15
Answer: C.C) 2.49
Explanation: Old time in minutes to cross 4 miles stretch = 4*60/55 = 4*12/11 = 4.36
New time in minutes to cross 4 miles stretch = 4*60/35 = 4*12/7 = 6.85
Time difference = 2.49
Ans:C
Question: A batsman in his 20th innings makes a score of 90, and thereby increases his average by 2. What is his average after the 20th innings? He had never been ’not out’.
A.52
B.37
C.39
D.43
Answer: A.52
Explanation: Average score before 20th innings
= 90 - 2 × 20= 50
Average score after 20th innings
=> 50 + 2 = 52
ANSWER:A
Question: The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?
A.6m
B.5m
C.2m
D.8m
Answer: D.8m
Explanation: Let the sides of the rectangle be l and b respectively.
From the given data,
(√l2 + b2) = (1 + 108 1/3 %)lb
=> l2 + b2 = (1 + 325/3 * 1/100)lb
= (1 + 13/12)lb
= 25/12 lb
=> (l2 + b2)/lb = 25/12
12(l2 + b2) = 25lb
Adding 24lb on both sides
12l2 + 12b2 + 24lb = 49lb
12(l2 + b2 + 2lb) = 49lb
but 2(l + b) = 28 => l + b = 14
12(l + b)2 = 49lb
=> 12(14)2 = 49lb
=> lb = 48
Since l + b = 14, l = 8 and b = 6
l - b = 8 - 6
= 2m.
Answer:D
Question: The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is?
A.8.09%
B.6.07%
C.1.09%
D.6.09%
Answer: D.6.09%
Explanation: Explanation:
Amount of Rs. 100 for 1 year when compounded half-yearly = [100 * (1 + 3/100)2] = Rs. 106.09 Effective rate = (106.09 - 100) = 6.09%
Answer: D