RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The volume of a cube is 1000 cc. Find its surface.
A.900
B.700
C.600
D.500
Answer: C.600
Explanation: a3 = 1000 => a = 106a2 = 6 * 10 * 10 = 600Answer: C
Question: At Company K, 15 percent of the employees are secretaries and 60 percent are salespeople. If there are 35 other employees of Company K, how many employees does Company K have?
A. 140
B. 180
C. 190
D. 200
Answer: A. 140
Explanation: Let the total number of employees in the company be x
% of secretaries = 15%
% of salespeople = 60%
% of of employees other than secretaries and salespeople = 100 - 75 = 25%
But this number is given as 35
so 25% of x = 35
x = 140
Therefore there a total of 140 employees in the company K
Correct answer - A
Question: The average of 1st 3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 13. What is the last numbers?
A.5
B.7
C.8
D.9
Answer: A.5
Explanation: Explanation:
A + B + C = 48
B + C + D = 45
A + D = 13
A – D = 3
A + D = 13
2D = 10
D = 5
A)
Question: If a, b, and c are integers and a*b^2/c is a positive even integer, which of the following must be true?
I. c is even
II. ab > 0
III.ab is even
A.III only
B.II only
C.I and II
D.I and III
Answer: A.III only
Explanation: Two ways this can happen: 1- Even/ Even= Even or 2- Even/Odd= Even
So Ab MUST be even, with either A or B being even, Ab does not have to be positive, as B could be negative and once it is raised to 2 it becomes positive again, and of course, C could be Odd or Even as described above.
III only.letter A
Question: The area of a parallelogram is 72 sq m and its altitude is twice the corresponding base. Then the length of the base is?
A.6
B.16
C.8
D.36
Answer: A.6
Explanation: 2x * x = 72 => x
= 6
Answer:A
Question: A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 400. How much did he have with him in the beginning?
A.s 200
B.s 1000
C.s 300
D.s 450
Answer: B.s 1000
Explanation: Suppose the amount in the beginning was Rs ’x’
Money spent on clothes = Rs 1x/3 Balance = Rs 2x/3
Money spent on food = 1/5 of 2x/3 = Rs 2x/15
Balance = 2x/3 - 2x/15 = Rs 8x/15
Money spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5
Therefore 2x/5 = 400 = 1000
ANSWER:B
Question: If p is the product of the integers from 1 to 34, inclusive, what is the greatest integer k for which 3^k is a factor of p?
A.11
B.13
C.15
D.17
Answer: C.15
Explanation: 34! has 3, 6, 9,....30, 33 as factors, which are 11 multiples of 3.
We need to add 4 more to these 11 because of 9, 18, and 27.
The greatest integer of k is 15.
The answer is C.
Question: In Mr. Mehta's family, there are one grandfather, two fathers, two mothers, one father-in-law, one mother-in-law, one brother, two sisters, two sons, two daughters, etc. You have to give the minimal number of members
A.4
B.5
C.6
D.7
Answer: D.7
Explanation: one grandfather and his wife.
grandfather's first son and his wife.
grandfather's second son alone.
2 daughters from first son.
total minimal no =7.
ANSWER:D
Question: If P(A) = 5/7 and P (B) = 2/5, find P (A n B) if A and B are independent events.
A.7/25
B.3/25
C.8/25
D.2/7
Answer: D.2/7
Explanation: P (A n B) = P(A) . P(B)
P (A n B) = 5/7 . 2/5
P (A n B) = 2/7.
D
Question: A is three times as fast as B. If B alone can do a piece of work in 12 days, in what time can A and B together complete the work?
A.5
B.8
C.3
D.2
Answer: C.3
Explanation: A can do the work in 12/3 i.e., 4 days.
A and B's one day's work = 1/4 + 1/12 = (3+ 1)/12 = 1/3
So A and B together can do the work in 3 days.
Answer:C
Question: . A car covers a distance of 495 km in 5 hours. Find its speed?
A.99
B.100
C.102
D.288
Answer: A.99
Explanation: 495/5 = 99 kmph
Answer: A
Question: (753 x 753 + 247 x 247 - 753 x 247)/(753 x 753 x 753 + 247 x 247 x 247)=?
A.1 / 1000
B.1 / 506
C.253 / 500
D.253 / 1000
Answer: A.1 / 1000
Explanation: Given Exp. =(a^2 + b^2 - ab)/(a^3 + b^3)	= 1/(a + b) = 1/(753 + 247) =1/1000
Answer:A
Question: 1/2 is what percent of 1/3
A.150%
B.200%
C.250%
D.300%
Answer: A.150%
Explanation: Explanation:
1/2/1/3 * 100 = 1/2 * 3/1 * 100 = 150 %
Answer: Option A
Question: 4 friends want to buy a company from the $150 000 cost. However, they have only $20 000 to be put in the company. How much partner will they have to fetch in more and which will be the equal value for every partner (The value should not contain of decimals) ?
A.2
B.3
C.4
D.5
Answer: C.4
Explanation: 4 friends * $ 20 000 = $ 100 000 total
$150 000 - $ 100 000 = $ 50 000 / $ 20 000 = 2.5 partners (impossible and not equal)
1+5+0+0+0+0 = 6 (even) so the answer have to be even (2 partners, 4 partners, 6 partners)
$150 000/ (4 actuals partners + 2 new partners) = $25 000 but they can only afford $ 20 000. The option is reject
$150 000/ (4 actuals partners + 4 new partners) = $ 18 750
We don't need to go further because $18 750 is the close number to $20 000. Answer is C, 4 more partners
Correct option: C) 4 partners
Question: A man took a loan from a bank at the rate of 13% p.a. simple interest.After 3 years he had to pay Rs. 5400 interest only for the period.The principal amount borrowed by him was :
A.Rs. 12,000.15
B.Rs. 13846.15
C.Rs. 15,000.15
D.Rs. 20,000.15
Answer: B.Rs. 13846.15
Explanation: Solution
Principal = Rs.(100x5400/13x3)= Rs. 13846.15.
Answer B
Question: A peacock of flying speed 5 km/h is sitiing on a top of a wooden pole of height 10m. There is a hole in the pole downwards and a snake is approaching that hole which is 21m away from the snake.How much time it will take for the peacock to catch the snake before it enters the hole.
A.14.73 seconds
B.16.73 seconds
C.15.73 seconds
D.17.73 seconds
Answer: B.16.73 seconds
Explanation: Speed of the peacock = 5 km/h(given)
Distance of the pole = 10m(given)
Distance between the pole hole and snake = 21m(given)
Therefore, we have to first find the distance between the peacock and the snake.
This can be done by using Pythagora's Theorem,
Therefore, 21^2 + 10^2 = 23.26 metre(approx)
Speed of the peacock = 5 km/h or 1.39 metre/sec(approx)
Now, we know can find the time for peacock to catch the snake by,
Time = Distance/Speed
= 23.26/1.39
= 16.73 seconds(approx)
Therefore, the required time for peacock to catch the snake before it enters the hole of the pole is 16.73 seconds.
ANSWER:B
Question: One-quarter of one-seventh of a land is sold for Rs. 30,000. What is the value of an eight thirty-fifth of load?
A.Rs. 1,92,2300.
B.Rs. 1,92,2450.
C.Rs. 1,92,2400.
D.Rs. 1,92,2000.
Answer: D.Rs. 1,92,2000.
Explanation: One-quarter of one-seventh = 1/4 x 1/7
= 1/28
Now, 1/28 of a land costs = Rs. 30,000
Thus, 8/35 of the land will cost = 30,000 x 28 x 8/35
= Rs. 1,92,2000.
ANSWER:D
Question: A sells his goods 50% cheaper than B but 50% dearer than C. The cheapest is?
A.33.9
B.33.6
C.33.3
D.33.1
Answer: C.33.3
Explanation: Let B = 100
A = 50
C * (150/100) = 50
3C = 100
C = 33.3 then 'C' Cheapest
Answer: C
Question: From the below series find the remainder? 1201 × 1203 ×1205 × 1207 is divided by 6
A.3
B.4
C.6
D.7
Answer: A.3
Explanation: If you don't know the above rule, this problem is really calculation intensive.
But by applying the above rule, when 1201, 1201, 1203, 1204 divided by 6, leaves remainders 1, 3, 5, 1. The product of these remainders = 15.
When 15 is divided by 6, Remainder is 3
A
Question: An book was sold after a discount of 20% and there was a gain of 20%. If the profit made on it was $6 less than the discount offered on it, find its selling price?
A.$66
B.$38
C.$77
D.$72
Answer: D.$72
Explanation: D
$72
Let CP = $100x
SP = $120x
MP = 120x/80 * 100 = $150x
D = $150x - $120x = $30x
D - P = 30x - 20x = $6, 10x = $6
120x = 120/10 * 6 = $72
Question: Two same glasses are respectively 1/4th 1/5th full of milk. They are then filled with water and the contents mixed in a tumbler. The ratio of milk and water in the tumbler is?
A.3:7
B.9:31
C.7:21
D.9:25
Answer: B.9:31
Explanation: 1/4 : 3/4 = (1:3)5 = 5:15
1/5 : 4/5 = (1:4)4 = 4:16 = > 9:31
ANSWER B
Question: Twelve kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?
A. 6
B. 4.8
C. 2.5
D. 2
Answer: A. 6
Explanation: Twelve kilograms of oranges contained 98% of water. If the next day the concentration of water decreased by 2%, what was the new weight of the oranges, in kilograms?
(A) 6
(B) 4.8
(C) 2.5
(D) 2
(E) 1
If A is the answer, then the question means that the concentration of water the newt day became 96%.
Out of 12 kilograms 98%, or 11.76 kilograms was water and 0.24 kilograms was non-water.
The next day, after some water evaporated, oranges became 96% water and 4% of non-water, so the next day 0.24 kilograms of non-water composed 4% of oranges, which means that the new weight of the oranges was x*0.04=0.24 --> x=6 kilograms.
Answer: A.
Question: The greatest number of four digits which is divisible by 21, 25, 40 and 75 is:
A.9000
B.8400
C.9600
D.9800
Answer: B.8400
Explanation: Greatest number of 4-digits is 9999.
L.C.M. of 21, 25, 40 and 75 is 4200.
On dividing 9999 by 4200, the remainder is 1599.
Required number (9999 - 1599) = 8400.
Answer: Option B
Question: On a certain test, Bill scored 20 more points than John, but half as many points as Sue. If the sum of the scores of the three students was 220 points, how many points did Bill receive?
A.30
B.40
C.50
D.60
Answer: D.60
Explanation: consider john's points as x
so bill's points are x +20
So sue's points are 2x +40
total of all three students is 4x +60, but this total is given as 220
x = 40
so bill's points = 40 +20 = 60
correct answer option D
Question: In how many ways can a cricket eleven be chosen out of a batch
of 15 players.
A.1255
B.1355
C.1340
D.1365
Answer: D.1365
Explanation: Required number of ways
= 15C 11 = 15C (15-11)
= 15 C 4
15C4 = 15 * 14 * 13 * 12 / 4 * 3 * 2 *1
= 1365
ANSWER D
Question: Joe had an average of 95 on his first 5 tests. He had an average score of 90 on his first 6 tests. What did he score on the 6th test?
A.95
B.85
C.65
D.45
Answer: C.65
Explanation: The sum of Joe's first 5 tests is 95 * 5 and the sum of his first 6 tests is 90*6, so he received 90*6 - 95*5 on his 6th test. You can do the arithmetic and the correct answer is C.
Question: Rory and Roxy, both house cats, love to hunt and chase insects. Since Rory only has three paws, Roxy is able to catch approximately 2.5 times more insects than Rory in one day.
After 3 days of hunting, Roxy was able to catch 23 insects. Assuming that both cats had an equal amount of hunting time, how many total insects can the two of them catch after 18 days of hunting?
Please round to the nearest whole number.
A.143
B.193
C.111
D.194
Answer: B.193
Explanation: 18 (total days) is divisible by 3 (initial data given days) 6 times,
therefore we can easily find Roxy's total for the 18 day period is 23 x 6 = 138 insects
Taking Roxy's total, we can then find Rory's total by dividing 138 by 2.5 = 55.2 insects
To find the pair's total, we add 138 + 55.2 = 193.2
This number rounded to nearest whole number is 193, answer B.
You could also divide 23 by 2.5 to get 9.2, which would be Rory's total for the first 3 days.
You could then multiply again, (23x6) + (9.2x6) = 138 + 55.2 = 193.2
Question: An escalator moves towards the top level at the rate of 7 ft.sec and its length is 180 feet. If a person walks on the moving escalator at the rate of 2 feet per second towards the top level, how much time does he take to cover the entire length.
A.5sec
B.25sec
C.20sec
D.15sec
Answer: C.20sec
Explanation: Explanation :
Time taken to cover the entire length = tot.dist/resultant speed = 180/ (7+2) = 20sec
Answer : C
Question: In a cricket team, the average of eleven players is 28 years. Out of these, the average ages of three groups of three players each are 25 years, 28 years and 38 years respectively. If in these groups, the captain and the youngest player are not included, and the captain is eleven years older than the youngest player, what is the age of the captain ?
A.23 years
B.34 years
C.35 years
D.36 years
Answer: A.23 years
Explanation: Explanation :
Let the age of youngest player be x.
Then, age of the captain = (x + 11).
=> 3*25 + 3*28 + 3*38 + x + x + 11 = 11*28.
=> 75+84+114+2x+11=308
so 2x = 24
so x = 12.
Age of the captain = (x+11)
= 23 years.
Answer : A
Question: Bobby bought 2 shares, and which he sold for $96 each. If he had a profit of 20% on the sale of one of the shares but a loss of 20% on the sale of the other share, then on the sale of both shares Bobby had...
A.a profit of 10
B.a profit of 8
C.a loss of 8
D.a loss of 10
Answer: C.a loss of 8
Explanation: Cost of the first stock: 96/1.2=80, so profit from it 96-80=16
Cost of the second stock: 96/0.8=120, so loss from it 96-120=-24
Overall loss 16-24=-8
Answer: C.
Question: In a school of 850 boys, 44% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
A.176
B.179
C.153
D.167
Answer: C.153
Explanation: 44 + 28 + 10 = 82%
100 – 82 = 18%
850 * 18/100 = 153
Answer: C
Question: A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 3x km.
A.24 kmph
B.34 kmph
C.44 kmph
D.14 kmph
Answer: A.24 kmph
Explanation: A
24 kmph
Total time taken = x/40 + 2x/20 hours
= 5x/40 = x/8 hours
Average speed = 3x/(x/8) = 24 kmph
Question: Linda and Angela contract to paint a neighbor's house. Even though Linda
spends 10% more time painting the house than Angela, each receives a payment
of m dollars when the work is completed. If Angela decides to pay Linda n
dollars so that they would have received the same compensation per hour
worked, what is n in terms of m?
A.A)(1/21)m
B.B)(1/3)m
C.C)(1/4)m
D.D)(1/5)m
Answer: A.A)(1/21)m
Explanation: let angela work for 10hrs and get 1100 rs. (m =1050)
According to question, linda works 10% more time and gets the same amount. so let linda work 11hrs and get 1050 rs.
so they do a total of 10 +11 =21 hrs of work and get 2100 rs together . The question basically asks to equalise their payment. so a total of 2100 rs is received by them and they do 21 hrs work together. average rate will be 2100/21 = 100 rs per hr. so linda should get 11*100 =1100 rs. But she got only 1050. so angela should give 50 rs to linda. answer = 50/1050 =1/21
answer A
Question: What percent of 13 is 13 percent of 1?
A. 0.001
B. 0.01
C. 1
D. 10
Answer: C. 1
Explanation: 13 % of 1 = (13/100) * 1 = 13/100
To determine what percentage of 13 this is :
[13][/100*13] *100 = 1%
Ans : C
Question: Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 16/49 what is the probability that the next one she draws will be pink?
A.1/49
B.4/7
C.3/7
D.16/49
Answer: C.3/7
Explanation: The probability of drawing a pink gumball both times is the same. The probability that she drew two blue gumballs = 16/49 = (4/7) * (4/7)
Therefore probability that the next one she draws is pink = 3/7
Option (C)
Question: The bus that travels from St. Louis to Chicago and back comes to St. Louis every 5 hours while the bus that travels from St. Louis to Springfield and back comes to St. Louis every 4 hours. If at 2:00 o'clock both bused arrived at St. Louis, at what time will they meet in St. Louis again?
A.16:00.
B.18:00.
C.20:00.
D.22:00.
Answer: D.22:00.
Explanation: Time taken by bus to travel from St. Louis to Chicago and back comes to St. Louis = 5 hours
Time taken by bus to travel from St. Louis to Springfield and back comes to St. Louis = 4 hours
Time taken by both buses to meet again in St. Louis will be LCM of 5 and 4 = 20
If the buses start at 2:00 o'clock from St. Louis , they will meet again in St. Louis at 22:00 hours
Answer D
Question: In how many ways can a five-letter password be chosen, using the letters A, B, C, D, E, and/or F, such that at least one letter is repeated within the password?
A.420
B.576
C.900
D.936
Answer: B.576
Explanation: Total number of four letter passwords = 6*6*6*6= 1296 ------(1)
Total number of passwords in which no letter repeats = 6C5*5!= 6*120=720------(2)
therefore required value = (1)-(2)= 1296-720=576
B
Question: One-third of 1200 is what percent of 236 ?
A.169.49
B.30
C.120.32
D.125.32
Answer: A.169.49
Explanation: Answer
Let one-third of 1200 is N% of 236.
∵ 1200/3 = (N x 236)/100
∴ N = (400 x 100) / 236= 169.49
Correct Option: A
Question: A bank offers 5% C.I. calculated on half-yearly basis . A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is?
A.299
B.121
C.298
D.390
Answer: B.121
Explanation: Amount = [1600 * (1 + 5/(2 * 100)2 + 1600 * (1 + 5/(2 * 100)]
= [1600 * 41/40(41/40 + 1)
= [(1600 * 41 * 81)/(40 * 40)] = Rs. 3321.
C.I. = 3321 - 3200 = Rs. 121.
Answer:B
Question: A certain essay consists of 13 paragraphs. Each paragraph contains at least 120 words but not more than 125 words. Which of the following could be the total number of words in the essay?
A.1440
B.1540
C.1610
D.1740
Answer: C.1610
Explanation: lets consider minimum no of words ... 13 * 120 = 1560
Lets consider maximum no of words .... 13*125= 1625
answer should be one of these two values or should lie between these two values ...
only 1 option C - 1610
Question: The pages of a report are numbered consecutively from 1 to 8. If the sum of the page numbers up to and including page number x of the report is equal to six less than the sum of the page numbers following page number x, then x =
A.5
B.6
C.4
D.3
Answer: B.6
Explanation: sum of the first few numbers =1+2+3+4 +5 +6 =21
sum of the last few = 7 +8 =15 page no.6 answer .B
Question: A watch which gains uniformly is 2 minutes low at noon on Tuesday and is 4 min 48 sec fast at 2 p.m. on the following Tuesday. When was it correct ?
A.3 p.m. on Thursday.
B.2 p.m. on Thursday.
C.4 p.m. on Thursday.
D.2.10 p.m. on Thursday.
Answer: B.2 p.m. on Thursday.
Explanation: Time from 12 p.m. on Tuesday to 2 p.m. on the following Tuesday = 7 days 2 hours.
= 170 hours.
The watch gains = (2 + 4 x 4/5) min
= 34/5 min. in 170 hrs.
Now, 34/5 min are gained in 170 hrs.
Then, 2 min are gained in (170 x 5/34 x 2) hrs.
Watch is correct after 2 days 2 hrs after 12 p.m. on Tuesday, i.e., it will be correct at 2 p.m. on Thursday.
Answer B
Question: There are 2 sections A and B in a class, consisting of 36 and 24 students respectively. If the average weight of section A is 30kg and that of section B is 30kg, Find the average of the whole class?
A.30kg
B.37kg
C.42kg
D.55.12kg
Answer: A.30kg
Explanation: Total weight of 36+44 students = 36*30 + 24*30 = 1800
Average weight of the class is = 1800/60 = 30 kg
Answer is A
Question: A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
A.750 m
B.300 m
C.350 m
D.150 m
Answer: D.150 m
Explanation: Let the length of the train be x metres and its speed by y m/sec.
Then, x/y = 15 => y =x/15
Therefore	x + 100/25 =	x/15
=> 15(x + 100) = 25x
=> 15x + 1500 = 25x
=> 1500 = 10x
=> x = 150 m.
Answer: D
Question: What is the difference between the place values of two 2's in the numeral 58232
A.202
B.200
C.198
D.120
Answer: C.198
Explanation: Required difference = 200-2 = 198
Answer is C
Question: Excluding the stoppages, the speed of a bus is 48 km/hr and including the stoppages the speed of the bus is 24 km/hr. For how many minutes does the bus stop per hour?
A.30min
B.10 min
C.12 min
D.20 min
Answer: A.30min
Explanation: Speed of the bus without stoppage=48 km/hr
Speed of the bus with stoppage=24 km/hr
Difference in speed=24 km/hr
so,the time taken in the stoppages = time taken to cover 24 km=(24/48)hr = 1/2 hr =30 min
ANSWER:A
Question: A PERSON WENT TO A SHOP AND ASKED FOR CHANGE FOR 1.15 PAISE. BUT HE SAID THAT HE COULD NOT ONLY GIVE CHANGE FOR ONE RUPEE. BUT ALSO FOR 50P, 25P, 10P AND 5P. WHAT WERE THE COINS HE HAD
A.1.15
B.1.25
C.1.35
D.1.45
Answer: A.1.15
Explanation: 50p-1, 25p-2, 10p-1, 5p-1
thus total= 1.15
ANSWER:A
Question: Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
A.50
B.45
C.48
D.55
Answer: A.50
Explanation: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 - 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50.
Answer: Option A
Question: A cube has a volume of 216 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is?
A.24
B.1728
C.64
D.80
Answer: B.1728
Explanation: Volume = 216 = side^3
i.e. Side of Cube = 6
New Cube has dimensions 12, 12, and 12 as all sides are twice of teh side of first cube
Volume = 12*12*12 = 1728 square feet
Answer: option B
Question: The year next to 1991 having the same calendar as that of 1990 is –
A.1998
B.2001
C.2002
D.2003
Answer: C.2002
Explanation: We go on counting the odd days from 1991 onward still the sum is divisible by 7. The number of such days are 14 upto the year 2001. So, the calender for 1991 will be repeated in the year 2002.
Answer C
Question: What is the probability of rolling a total of 6 with a single roll of two fair six-sided dice, each with the distinct numbers 1 through 6 on each side?
A.1/12
B.5/36
C.2/7
D.1/3
Answer: B.5/36
Explanation: Totalsample spacefrom two fair six-sided dice is 36.
There are six possible ways to be 6 i.e. (1+5), (2+4), (3+3), (4+2), (5+1)
So, total probability is 5/36.
Answer is B.
Question: The population of a town is 8000. It decreases annually at the rate of 30% p.a. What will be its population after 2 years?
A.3920
B.5120
C.5200
D.5400
Answer: A.3920
Explanation: Formula :
( After =100 denominator
Ago = 100 numerator)
8000 Ã— 70/100 Ã— 70/100 = 3920
Answer : A
Question: How many even number in the range between 10 to 100 inclusive are not divisible by 3
A.15
B.30
C.31
D.33
Answer: C.31
Explanation: We have to find the number of terms that are divisible by 2 but not by 6( as the question asks for the even numbers only which are not divisible by 3)
For 2,
10,12,14...100
using AP formula, we can say 100 = 10 + (n-1) *2
or n=46.
For 6,
12,18,...96
using AP formula, we can say 96 = 12 + (n-1) *6
or n=15.
Hence, only divisible by 2 but not 3 = 46-15 = 31. hence, Answer C
Question: What is the total number of D integers between 100 and 200 that are divisible by 3?
A. 33
B. 32
C. 31
D. 30
Answer: A. 33
Explanation: yes there is a different way of arriving at that answer ....
u can also use airthmetic progression to get the answer
since the first term to be divisble by 3 is 102 ..take that as A .. the starting no
and since 198 is the last digit to be divisible by 3 take that as N ...
since the difference is 3 take that as D
no u have to find what term is 198 take that as nth term
the formula for that is N = A + (n-1) * d
198 = 102 +(n-1) * 3
from this u get n =33
Question: In a class of 32 students, 12 enrolled for both English and German. 22 enrolled for German. If the students of the class enrolled for at least one of the two subjects, then how many students enrolled for only English and not German?
A.30
B.10
C.18
D.28
Answer: B.10
Explanation: Total=English+German-Both+Neither --> 40=English+22-12+0 --> English=22 --> Only English=English-Both=22-12=10.
Answer: B.
Question: If n is a positive integer, then n(n+1)(n+2) is +ve and
A.divisible by 4 whenever n is even
B.divisible by 3 only when n is odd
C.odd whenever n is odd
D.even only when n is odd
Answer: A.divisible by 4 whenever n is even
Explanation: n*(n+1)*(n+2)= +ve even integer divisible by 4 ( e.g 3,4,&5)
A
Question: If a card is drawn from a well shuffled pack of cards, the probability of drawing a spade or a king is
A.19/52
B.17/52
C.5/13
D.4/13
Answer: D.4/13
Explanation: P(SᴜK) = P(S) + P(K) - P(S∩K), where S denotes spade and K denotes king.
P(SᴜK) = 13/52 + 4/52 - 1/52 = 4/13
ANSWER:D