RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Oranges are bought at 7 for Rs.3. At what rate per hundred must they be sold to gain 33%?
A.57
B.58
C.59
D.54
Answer: A.57
Explanation: 7 oranges bought for rs 3
1 orange cost =3/7
therefore for 100 oranges =100*(3/7)
gain =33%
300/7+(33/100)*300/7=rate per hundred he want to sell
ans :57
ANSWER:A
Question: The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 10%. if in july , a mixture containing equal quantities of tea and coffee costs 50/kg. how much did a kg of coffee cost in june ?
A.45
B.40
C.35
D.47.61
Answer: D.47.61
Explanation: Let the price of tea and coffee be x per kg in June.
Price of tea in July = 1.2x
Price of coffee in July = 0.9x .
In July the price of 1/2 kg (500gm) of tea and 1/2 kg (500gm) of coffee (equal quantities) = 50
1.2x(1/2) + 0.9x(1/2) = 50
=> x =47.61
D
Question: The average of 12 result is 55. Average of the first 6 of them is 42 and that of the last 6 is 48. Find the 8th result?
A.35
B.564
C.526
D.48
Answer: B.564
Explanation: Sum of all the 12 results = 12 * 55 = 660
Sum of the first 6 of them = 6 * 42 = 252
Sum of the last 6 of them = 6 * 48 = 288
So, the 8th number = 600 + 252 - 288= 564.
B
Question: After replacing an old member by a new member, it was found that the average age of five members of a club is the same as it was 3 years ago. What is the difference between the ages of the replaced and the new member ?
A.12
B.13
C.14
D.15
Answer: D.15
Explanation: Explanation:
i) Let the ages of the five members at present be a, b, c, d & e years.
And the age of the new member be f years.
ii) So the new average of five members' age = (a + b + c + d + f)/5 ------- (1)
iii) Their corresponding ages 3 years ago = (a-3), (b-3), (c-3), (d-3) & (e-3) years
So their average age 3 years ago = (a + b + c + d + e - 15)/5 = x ----- (2)
==> a + b + c + d + e = 5x + 15
==> a + b + c + d = 5x + 15 - e ------ (3)
iv) Substituting this value of a + b + c + d = 5x + 15 - e in (1) above,
The new average is: (5x + 15 - e + f)/5
Equating this to the average age of x years, 3 yrs, ago as in (2) above,
(5x + 15 - e + f)/5 = x
==> (5x + 15 - e + f) = 5x
Solving e - f = 15 years.
Thus the difference of ages between replaced and new member = 15 years. Answer: D
Question: If x = a!, which of these following values of a is the least possible value (in this list) for which the last 8 digits of the integer x will all be zero?
A.21
B.29
C.37
D.41
Answer: C.37
Explanation: 2*5 will give one 0 at the end. We need 2^8*5^8 to get 8 zeroes at the end.
There are many 2's, so we need to find the first 8 appearances of 5.
These multiples of 5 are: 5, 10, 15, 20, 5*5, 30, 35...which gives us 8.
To have at least 8 zeroes at the end, a => 35.
The answer is C.
Question: Sreedhar and Sravan together can do a work in 25 days. With the help of Pavan, they completed the work in 8 days and earned Rs. 225. What is the share of Sravan, if Sreedhar alone can do the work in 75 days?
A.$42
B.$46
C.$48
D.$49
Answer: C.$48
Explanation: C
$48
Sravan's one day's work = 1/25 - 1/75 = 2/75
Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75
Sravan completed 16/75th of total work.
So, his share is 16/75 * 225 = $48.
Question: If logx y =100 and log2 x =10, then the values of y is
A.2(10)
B.2 (100)
C.2 (1000)
D.2 (10000)
Answer: D.2 (10000)
Explanation: Solution
log2 x	= 10
x= 210
logx y	= 100
y= x100
=(210)100
y‹=›2(1000)
Answer D
Question: P can lay railway track between two stations in 16 days. Q can do the same job in 12 days. With the help of R, they completes the job in 4 days. How much days does it take for R alone to complete the work?
A.9 days
B.9 (3/5) days
C.11 1/5 days
D.13 days
Answer: B.9 (3/5) days
Explanation: Amount of work P can do in 1 day = 1/16
Amount of work Q can do in 1 day = 1/12
Amount of work P, Q and R can together do in 1 day = 1/4
Amount of work R can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48
=> Hence R can do the job on 48/5 days = 9 (3/5) days
B)
Question: In how many ways can a committee consisting of 4 men and 5 women be formed from a group of 7 men and 7 women?
A.7C4 7C5
B.4C7 5C7
C.7C5 9C4
D.9C4 7C5
Answer: A.7C4 7C5
Explanation: Group consisting of 7 men and 7 women
4 men can be selected from 7 men in 7C4 ways
5 women can be selected from 7 women in 7C5 ways
Therefore, Total number of ways= 7C4 7C5
ANSWER:A
Question: Each week, Harry is paid x dollars per hour for the first 24 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ?
A.35
B.36
C.37
D.38
Answer: B.36
Explanation: 42x=24x+1.5x(H-24)
==> 42=24+1.5(H-24)
==> H-24 = 18/1.5=12=> H = 36
Answer is B
Question: At Jefferson Elementary School, the number of teachers and students (kindergarten through sixth grade) totals 510. The ratio of students to teachers is 16 to 1. Kindergarten students make up 1/8 of the student population and fifth and sixth graders account for 1/3 of the remainder. Students in first and second grades account for 1/4 of all the students. If there are an equal number of students in the third and fourth grades, then the number of students in third grade is how many greater or fewer than the number of students in kindergarten?
A.8 greater
B.17 fewer
C.28 fewer
D.36 fewer
Answer: A.8 greater
Explanation: Soln>> from the given ratio of 16:1 u can derive that ter are 480 students
KG= 1/8* 480 =60
5th and 6th graders = 1/3 * 384= 128 (1/3 of remainder)
1st and 2nd grade = 1/4 * 480 =120 ( 1/4 of all students)
equal number of students in 3rd and 4th => 480 - 344= 136 and 136/2=68 each since equal number
(344 is the sum of remaining students)
thus 60-68 =-8>>> therfore answer is 8 greater
A
Question: To produce an annual income of Rs. 800 from a 8% stock at 90, What is the amount of stock needed?
A.10000
B.11000
C.12000
D.13000
Answer: A.10000
Explanation: Since face value is not given, take it as Rs.100.
As it is an 8% stock, income (dividend) per stock = Rs.8
ie, For an income of Rs.8,amount of stock needed = Rs.100
For an income of Rs.800, amount of stock needed = 100×800/8=10000
Answer is A.
Question: In Arun’s opinion, his weight is greater than 65 kg but less than 72 kg. His brother doest not agree with Arun and he thinks that Arun’s weight is greater than 60 kg but less than 70 kg. His mother’s view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun?
A.66 kg
B.67 kg
C.68 kg
D.69 kg
Answer: B.67 kg
Explanation: Explanation:
Let Arun’s weight by X kg.
According to Arun, 65 < X < 72
According to Arun’s brother, 60 < X < 70.
According to Arun’s mother, X <= 68
The values satisfying all the above conditions are 66, 67 and 68.
Required average = [66+67+68/3]=[201/3]=67kg
Answer B
Question: The difference in compound interest earned on a deposit (compounded annually) in year 1 and year 2 is $ 40. Had the interest rate been three times its present value, the difference would have been how much?
A.40/3
B.40
C.120
D.360
Answer: D.360
Explanation: CASE 1:
Deposit = $x;
Rate of increase = r.
Interest yearned in 1 year = xr. Deposit in 1 year = x + xr.
Interest yearned in 2 year = (x + xr)r.
The difference = (x + xr)r - xr = xr^2 = 40.
CASE 2:
Deposit = $x;
Rate of increase = 3r.
Interest yearned in 1 year = x(3r). Deposit in 1 year = x + 3xr.
Interest yearned in 2 year = (x + 3xr)3r.
The difference = (x + 3xr)3r - 3xr = 9xr^2. Since from CASE 1 we know that xr^2 = 40, then 9xr^2 = 9*40 = 360.
Answer: D
Question: Carrie likes to buy t-shirts at the local clothing store. They cost $9.95 each. One day, she bought 20 t-shirts. How much money did she spend?
A.$150
B.$248.75
C.$199
D.$171.6
Answer: C.$199
Explanation: $9.95*20=$199. Answer is C.
Question: A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 2 hour to row to a place and come back, how far is the place?
A.2.4 km
B.4.8 km
C.3.4 km
D.4.4 km
Answer: B.4.8 km
Explanation: Explanation:
Speed in still water = 5 kmph
Speed of the current = 1 kmph
Speed downstream = (5+1) = 6 kmph
Speed upstream = (5-1) = 4 kmph
Let the required distance be x km
Total time taken = 2 hour
â‡’ x/6+x/4=2
â‡’2x+3x=24
â‡’5x=24
â‡’x=4.8 km
Answer: Option B
Question: A van takes 5 hours to cover a distance of 600 km. What speed in kph should the van maintain to cover the same distance in 3/2 of the previous time?
A.80
B.84
C.88
D.92
Answer: A.80
Explanation: (3/2)*5 = 7.5 hours
600 / 7.5 = 80 kph
The answer is A.
Question: The sum of the ages of 5 children born at the intervals of 3 year each is 50 year. what is the age of the eldest child ?
A.16 year
B.8 year
C.10 year
D.None of these
Answer: A.16 year
Explanation: Solution
let the ages of the children be x,(x + 3),(x + 6),(x + 9) and (x + 12) year.
then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50 â‡” 5 x = 20 â‡” x= 4.
âˆ´ Age of the eldest child = x+12 = 4 +12 =16 years. Answer A
Question: A batsman makes a score of 110 runs in the 11th inning and thus increases his average by 5. Find his average after 11th inning.
A.40
B.50
C.60
D.45
Answer: C.60
Explanation: Let the average after 11th inning = x
Then, average after 10th inning = x-5
10(x-5)+110 = 11x
x = 110-50 = 60
Answer is C
Question: In how many different ways can the letters of the word 'CORPORATION' be arranged so that the vowels always come together?
A.47200
B.48000
C.42000
D.50400
Answer: D.50400
Explanation: Explanation:
The word 'CORPORATION' has 11 letters. It has the vowels 'O','O','A','I','O' in it and these 5 vowels should always come together. Hence these 5 vowels can be grouped and considered as a single letter. that is, CRPRTN(OOAIO).
Hence we can assume total letters as 7. But in these 7 letters, 'R' occurs 2 times and rest of the letters are different.
Number of ways to arrange these letters
=7!2!=7Ã—6Ã—5Ã—4Ã—3Ã—2Ã—12Ã—1=2520=7!2!=7Ã—6Ã—5Ã—4Ã—3Ã—2Ã—12Ã—1=2520
In the 5 vowels (OOAIO), 'O' occurs 3 and rest of the vowels are different.
Number of ways to arrange these vowels among themselves =5!3!=5Ã—4Ã—3Ã—2Ã—13Ã—2Ã—1=20=5!3!=5Ã—4Ã—3Ã—2Ã—13Ã—2Ã—1=20
Hence, required number of ways
=2520Ã—20=50400=2520Ã—20=50400
ANSWER IS D
Question: In a factory, there are 80% technicians and 20% non-technicians. If the 80% of the technicians and 20% of non-technicians are permanent employees, then the percentage of workers who are temporary is?
A.62%
B.68%
C.52%
D.22%
Answer: B.68%
Explanation: Total = 100
T= 80 NT= 20
80*(20/100)=24 80*(20/100)=24
16 + 16 = 32 => 100 - 32 = 68%
Answer:B
Question: One-third of Rahul's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,80,000 as total savings, how much has he saved in Public Provident Fund?
A.81000
B.85000
C.75000
D.72000
Answer: D.72000
Explanation: Let savings in National Savings Certificate = x
and savings in Public Provident Fund = (180000 - x)
1/3x=1/2(180000−x)
⇒2x=3(180000−x)
⇒2x=540000−3x
⇒5x=540000
⇒x=540000/5=108000
Savings in Public Provident Fund = (180000 - 108000) = 72000
Answer is D.
Question: The average of six numbers is x and the average of three of these is y. If the average of the remaining three is z, then
A.None of these
B.x = y + z
C.2x = y + z
D.x = 2y + 2z
Answer: C.2x = y + z
Explanation: Explanation:
Average of 6 numbers = x
=> Sum of 6 numbers = 6x
Average of the 3 numbers = y
=> Sum of these 3 numbers = 3y
Average of the remaining 3 numbers = z
=> Sum of the remaining 3 numbers = 3z
Now we know that 6x = 3y + 3z
=> 2x = y + z
Answer: Option C
Question: In how many ways 2 students can be chosen from the class of 20 students?
A.190
B.180
C.240
D.390
Answer: A.190
Explanation: Solution: Number of ways = 20C2 = 20!/(2! 18!)
= 20*19/2
= 190.
Answer: Option A
Question: 1939392 * 625
A.1212120010
B.1212120000
C.1212120011
D.1212121010
Answer: B.1212120000
Explanation: Explanation:
Trick: when multiplying with
5n
5n
then put n zeros to the right of multiplicand and divide the number with
2n
2n
So using this we can solve this question in much less
time.
1939392×5(4)=1939392000016=1212120000
Option B
Question: In how many different number of ways 4 man and 3 woman can sit on a bench such that girls always sit together.
A.700
B.720
C.730
D.750
Answer: B.720
Explanation: Option 'B'
Question: Two employees X and Y are paid a total of Rs. 440 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
A.s.150
B.s.200
C.s.250
D.s.350
Answer: B.s.200
Explanation: Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 440
But x = 120% of y = 120y/100 = 12y/10
âˆ´12y/10 + y = 440
â‡’ y[12/10 + 1] = 440
â‡’ 22y/10 = 440
â‡’ 22y = 4400
â‡’ y = 4400/22 = 400/2 = Rs.200
B)
Question: Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case
A.4
B.7
C.9
D.13
Answer: A.4
Explanation: Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
ANSWER IS A
Question: 10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?
A.6
B.5
C.7
D.8
Answer: C.7
Explanation: 1 women's 1 day work = 1/70
1 child's 1 day work = 1/140
(5 women + 10 children)'s 1 day work
= (5/10 + 10/140) = (1/14 + 1/14) = 1/7
5 women and 10 children will complete the work in 7 days.
Answer:C
Question: If in a certain sequence of consecutive multiples of 50, the median is 625, and the greatest term is 850, how many terms that are smaller than 625 are there in the sequence?
A.5
B.7
C.8
D.12
Answer: A.5
Explanation: Since the median is 625 we know there must be a even number of integers because 50 is not a multiple of 625.
So the list around 625 must go. 600 (625) 650 700 750 800 850
Since we know there are 5 numbers greater than 625 then there must be 5 numbers less then 625.
A
Question: 23,8,34,81,33,...
A.24
B.25
C.26
D.27
Answer: D.27
Explanation: 23 : 2^3=8
34 : 3^4=81
33 : 3^3=27
ANSWER:D
Question: If 2ab - 3c = 2a(b - c), which of the following must be true?
A. a=3/2 and c=0
B. a=1/2 and b=2
C. b=1 and c=0
D. a=1 or b=0
Answer: A. a=3/2 and c=0
Explanation: 2ab-3c = 2a (b-c)
2ab - 3c = 2ab - 2ac
3c= 2ac
2ac-3c = 0
c(2a-3) = 0
Either c = 0; or a = 3/2
A is the answer
Question: Anita has 360 apples. There are 60 students are studying in her class. She would like to give each student the same amount of apples, how much should she give to each student?
A.12
B.6
C.9
D.15
Answer: B.6
Explanation: 360/60 = 6
The answer is B.
Question: Find the length of the wire required to go 11 times round a square field containing 27889 m2.
A.7348
B.3388
C.2667
D.8766
Answer: A.7348
Explanation: a2 = 27889 => a = 167
4a = 668
668 * 11 = 7348
Answer: A
Question: Mary received a 20% raise each month for three consecutive months. What was her salary after the three raises if her starting salary was $1,000 per month?
A.$1,348
B.$1,500
C.$1,631
D.$1,728
Answer: D.$1,728
Explanation: 1000 * 1.2 * 1.2 * 1.2 = 1000 * 1.728 = 1728
Answer: D
Question: Five drainage pipes, each draining water from a pool at the same constant rate, together can drain a certain pool in 8 days. How many additional pipes, each draining water at the same constant rate, will be needed to drain the pool in 4 days?
A. 5
B. 9
C. 10
D. 12
Answer: A. 5
Explanation: This is an inverse proportional problem......
5 pipes in 8 days; So for 4 days, it will be = 8 x 5 / 4 = 10
So, 10-5 = 5
Answer A
Question: A can do a work in 9 days and B can do the same work in 18 days. If they work together, in how many days will they complete the work?
A.6 days
B.7 days
C.5 days
D.3 days
Answer: A.6 days
Explanation: One day's work of A and B = 1/9 + 1/8 = (2+1)/18 = 1/6 So, the time taken to complete the work is 6 days.
Answer:A
Question: A can contains a mixture of liquids A and B is the ratio 7:5. When 15 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter of liquid A was contained by the can initially?
A.30
B.35
C.40
D.45
Answer: B.35
Explanation: Ci*Vi = Cf*Vf
(7/12)*(V1 - 15) = (7/16)*V1
(V1 - 15)/V1 = 3/4
15 accounts for the difference of 1 on ratio scale so Initial volume = V1 = 4*15 = 60 litres.
7/12 of the initial mixture was liquid A so liquid A was (7/12)*60 = 35 litres.
Answer : B
Question: The compound interest on Rs. 20,000 at 8% per annum is Rs. 3,328. What is the period (in year)?
A.1 year
B.4 years
C.3 years
D.2 years
Answer: D.2 years
Explanation: Explanation:
Let the period be n years.
Amount after n years = Rs.20000 + Rs.3328 = Rs. 23328
P(1+R/100)T=23328
20000(1 + 8/100)n = 23328
20000(108/100)n = 23328
(108/100)n = 23328/20000 = 11664/10000 = (108/100)2
n = 2 years
Answer: Option D
Question: The ratio of three numbers is 5:3:4 and their sum is 108. The second number of the three numbers is?
A.23
B.27
C.30
D.32
Answer: B.27
Explanation: 5:3:4
Total parts = 12
12 parts --> 108
1 part ---->9
The second number of the three numbers is = 3
3 parts ----> 27
B)
Question: How many 7s are there in the following series which are not immediately following by 3 but immediately preceded by 8?
8 9 8 7 6 2 2 6 3 2 6 9 7 3 2 8 7 2 7 7 8 7 3 7 7 9 4
A.Nil
B.One
C.Two
D.Three
Answer: C.Two
Explanation: 876 and 872
ANSWER:C
Question: Find the principal which yields a simple interest of Rs. 20 and compound interest of Rs. 30 in two years, at the same percent rate per annum?
A.s. 20
B.s. 48
C.s. 42
D.s. 20
Answer: A.s. 20
Explanation: Explanation:
SI in 2 years = Rs. 20, SI in 1 year = Rs. 10
CI in 2 years = Rs. 30
% rate per annum = [(CI – SI) / (SI in 1 year)] *100
= [(30 – 20) / 20] * 100
= 50 % p.a.
Let the principal be Rs. X
Time = T = 2 years
% rate = 50% p.a.
SI = (PRT/100)
20 = (X*50*2) / 100
X = Rs. 20
ANSWER: A
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?
A.26 sec
B.28 sec
C.12 sec
D.77 sec
Answer: C.12 sec
Explanation: D = 250 m + 250 m = 500 m
RS = 80 + 70 = 150 * 5/18 = 125/3
T = 500 * 3/125 = 12 sec
Answer: C
Question: If the function Q is defined by the formula Q = 5w/(4m(z^2)), by what factor will Q be multiplied if w is quadrupled, m is doubled, and z is tripled?
A.1/9
B.2/9
C.4/9
D.3/9
Answer: B.2/9
Explanation: We just need to find the factor thats all,
w -> quadrupled -> 4w
m-> doubled -> 2m
z-> tripled -> 3Z
Hence, Z^2 = 9Z^2
W is in numerator, and m*z in denominator.
Hence,
Additional factor being introduced = 4/2*9
=4/18 = 2/9 = B
Question: (74 + 75 + 76 + 77 + ..... + 149 + 150) = ?
A.8624
B.8634
C.8654
D.8644
Answer: A.8624
Explanation: Explanation:
Sum of first n natural numbers
= (1 + 2 + 3 + ..... + n) = n(n+1)/2
(74 + 75 + 76 + .....+ 150)
=(1 + 2 + .... + 73 + 74 + 75 + .....+ 150) - (1 + 2 + .... + 73)
=(1/2 x 150 x 151) - (1/2 x 73 x 74)
= 11325 - 2701 = 8624
Answer: Option A
Question: Vijay bought 160 shirts at the rate of Rs. 245 per shirt. The transport expenditure was Rs. 1400. He paid an octroi at the rate of Rs. 1.75 per shirt and labour charges were Rs. 320. What should be the selling price of one shirt, if he wants a profit of 20%?
A.Rs. 258
B.Rs. 270
C.Rs. 277.5
D.Rs. 309
Answer: D.Rs. 309
Explanation: Total CP per shirt = 245 + 1400/160 + 1.75 + 320/160 = Rs. 257.5
SP = CP[(100 + profit%)/100]
= 257.5 * [(100 + 20)/100] = Rs. 309.
ANSWER:D
Question: Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours. C is closed A and B can fill the remaining par in 7 hours. The number of hours taken by C alone to fill the tank is?
A.76
B.55
C.14
D.33
Answer: C.14
Explanation: Part filled in 2 hours = 2/6 = 1/3.
Remaining part = 1 - 1/3 = 2/3
(A + B)'s 1 hour work = 2/21
C's 1 hour work = [(A + B + C)'s 1 hour work - (A + B)'s 1 hour work]
= (1/6 - 2/21) = 1/14
C alone can fill the tank in 14 hours.Answer:C
Question: The volume of a wall, 5 times as high as it is broad and 8 times as long as it is high, is 12.8 cu. meters. Find the breadth of the wall.
A.40
B.29
C.28
D.27
Answer: A.40
Explanation: Explanation:
Let the breadth of the wall be x metres.
Then, Height = 5x metres and Length = 40x metres.
x * 5x * 40x = 12.8
=>\inline \fn_jvn x^3=\frac{12.8}{200}=\frac{128}{2000}=\frac{64}{1000}
=>\inline \fn_jvn x=\frac{4}{10}m
=>\inline \fn_jvn x=\frac{4}{10}\times 100=40cm
Answer: A) 40cm
Question: What is the remainder when 5990990900032 is divided by 32 ?
A.16
B.8
C.0
D.2
Answer: C.0
Explanation: Though i was unaware of the divisibility test for 32 but i guessed the pattern!!
divisibility rule for 4- last two digits must be divisible by 4
divisibility rule for 8- last three digits must be divisible by 8
similarly, divisibility rule for 32 - last five digits must be divisible by 32
Hence, Ans C
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 800 grams per kg, what is his percent?
A.25%
B.25%
C.29%
D.55%
Answer: B.25%
Explanation: 800 --- 200
100 --- ? => 25%
Answer: B
Question: Tim came second in Math. When his mother asked him how much he had scored, he answered that he got the sum of the first 9 even numbers. His mother immediately worked out the answer. How much had he scored in Math?
A.80
B.90
C.30
D.70
Answer: B.90
Explanation: B
90
Sum = (n x n) + n
Hence, 9 x 9 = 81 + 9 = 90
Question: A, B and C start a business, each investing Rs. 30,000/-. After 4 months A withdrew Rs. 10,000/-, B Rs. 6,000/- and C invested Rs 8000/- more. At the end of the year, a total profit of Rs. 69,000/-was recorded. What is the share of B?
A.Rs. 25000/-
B.Rs. 21,600/-
C.Rs. 21,000/-
D.Rs. 21,200/-
Answer: C.Rs. 21,000/-
Explanation: Explanation:
A : B : C = (30000 * 4 + 10000 * 8) : (30000 * 4 + 6000 * 8) : (30000 * 4 + 8000 * 8)
(120000 + 80000) : (120000 + 48000) : (120000 + 64000)
= 200000 : 168000 : 184000
A : B : C = 25 : 21 : 23
B’s Share = Rs. (69000 * 21/69) = 1000 * 21 = Rs. 21,000/-
Answer: Option C
Question: If the cost price of 72 articles is equal to the selling price of 60 articles, then what is the percent profit?
A.10%
B.15%
C.20%
D.25%
Answer: C.20%
Explanation: Let x be the cost price of one article.
Let y be the selling price of one article.
60y = 72x
y = 1.2x
The answer is C.
Question: In 1999, there are 28 days in February and there are 365 days in the year. In 2000, there are 29 days in February and there are 366 days in the year. If the date March 20, 1999 is a Wednesday, then which one of the following would the date March 20, 2000 be?
A.Friday
B.Tuesday
C.Monday
D.Sunday
Answer: A.Friday
Explanation: From the information given, March 20, 2000 is 366 days after March 20, 1999.
366 days = 52 weeks and 2 more days. Therefore if March 20, 1999 is a Wednesday, then March 20, 2000 is Wednesday + 2 days = Friday
Answer: A
Question: The list price of an article is Rs.69. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?
A.9.33%
B.9.44%
C.9.45%
D.9.56%
Answer: D.9.56%
Explanation: 69*(90/100)*((100-x)/100) = 56.16
x = 9.56%
ANSWER:D
Question: The ratio of the volumes of two cubes is 729 : 2197. What is the ratio of their total surface areas?
A.81 : 169
B.81 : 122
C.81 : 124
D.81 : 126
Answer: A.81 : 169
Explanation: Ratio of the sides = 3√729 : 3√2197 = 9 : 13
Ratio of surface areas = 9^2 : 13^2 = 81 : 169
Answer: Option A
Question: Country X taxes each of its citizens an amount equal to 14 percent of the first $40,000 of income, plus 20 percent of all income in excess of $40,000. If a citizen of Country X is taxed a total of $8,000, what is her income?
A.$40,000
B.$52,000
C.$64,000
D.$66,667
Answer: B.$52,000
Explanation: Equation is correct, so math must be a problem.
0.14*40,000+0.2*(x-40,000)=8,000 --> 5,600+0.2x-8,000=8,000 --> 0.2x=10,400 --> x=52,000.
Answer: B.