RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Lagaan is levied on the 60 percent of the cultivated land. The revenue department collected total Rs. 3,84,000 through the lagaan from the village of Mettur. Mettur, a very rich farmer , paid only Rs.480 as lagaan. The percentage of total land of Mettur over the total taxable land of the village is:
A.0.20833
B.0.35424
C.0.10982
D.0.20933
Answer: A.0.20833
Explanation: Total land of Sukhiya = \inline \frac{480x}{0.6} = 800x
\therefore Cultivated land of village = 384000x
\therefore Required percentage = \inline \frac{800x}{384000}\times 100 = 0.20833
A
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions.
A.287 m
B.704 m
C.176 m
D.186 m
Answer: B.704 m
Explanation: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.
= 500 * 2 * 22/7 * 22.4
= 70400 cm
= 704 m
Answer:B
Question: A can do a job in 18 days and B can do it in 30 days. A and B working together will finish twice the amount of work in ------- days?
A.14 ½ days
B.16 ½ days
C.22 ½ days
D.11 ½ days
Answer: C.22 ½ days
Explanation: C
22 ½ days
1/18 + 1/30 = 8/90 = 4/45
45/4 = 11 ¼ *2 = 22 ½ days
Question: There is a 40 cm line marked at each centimeter and an insect is placed at every centimeter. 9 frogs are trained to jump a constant distance. The first one jumps 2 cm in every leap, the second one jumps 3 cm and so on until the 9th one jumps 10 cm in every leap and they eat any insect that is available at that spot. If all of them start from start line and finish the entire 40 cm, how many insects were still left after the race was over?
A.0
B.4
C.6
D.8
Answer: D.8
Explanation: Only the prime numbers greater than 10 and less than 40 were left.
That is 11, 13, 17, 19, 23, 29, 31, and 37.
The total is 8.
The answer is D.
Question: When Rahul was born, his father was 32 years older than his brother and his mother was 25 years older than his sister. If Rahul's brother is 6 years older than him and his mother is 3 years younger than his father, how old was Rahul's sister when he was born ?
A.7 years
B.10 years
C.14 years
D.19 years
Answer: B.10 years
Explanation: let rahuls age =x
x=0(born) den bro's age=6
father=32+bro=32+6=38(at the time rahul was born)
mother=father-3=35
mother= 25+ sis
=>35-25=sis
=> sis=10.
ANSWER:B
Question: A bag contains 3 red, 5 yellow and 7 green balls. 3 balls are drawn randomly. What is the probability that the balls drawn contain balls of different colours?
A.2/7
B.3/5
C.3/13
D.1/4
Answer: C.3/13
Explanation: Total number of balls = 3+5+7 = 15
n(S) = 15C3 = 455
n(E) = 3C1 * 5C1 * 7C1 = 105
Probability = 105/455 = 3/13
Answer is C
Question: A group of 6 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the probability that Bob and Lisa will each sit next to only one of the five other students from the group?
A.5.6%
B.6.7%
C.15.5%
D.20.4%
Answer: B.6.7%
Explanation: The question basically asks about the probability that Bob and Lisa sit at the ends.
The total # of sitting arrangements is 6!.
Desired arrangement is either BWXYZL or LWXYZB. Now, WXYZ can be arranged in 4! ways, therefore total # of favorable arrangements is 2*4!.
P=(favorable)/(total)=(2*4!)/6!=1/15.
Answer: B.
Question: A can complete a project in 10 days while B can complete same project in 30 days. If A and B start working together and A leaves the work 10 days before completion of project, then in how many days the project will be completed?
A.15
B.19
C.20
D.21
Answer: A.15
Explanation: A's 1day work=1/10;
B's 1day work=1/30;
(A+B) 1day work=(1/10+1/30)=2/15;
It is given that A leaves the work 10 days before completion of the project..
Thus,B alone does the remaining job in 10 days.
So,In 10 days ,B can do 1/3 w ..
Thus,(A+B) have worked (1-1/3)=2/3 w..
(A+B)can do 2/15 work in 1 day...
They did 2/3 w in 5 days.
Total days=(5+10) = 15
ANSWER:A
Question: The H.C.F. of two numbers is 12 and their L.C.M. is 600. If one of the number is 30, find the other?
A.100
B.240
C.120
D.200
Answer: B.240
Explanation: Other number = 12*600/30 = 240
Answer is B
Question: One train is traveling 45 kmph and other is at 10 meters a second. Ratio of the speed of the two trains is?
A.5:4
B.5:8
C.5:2
D.5:2
Answer: A.5:4
Explanation: :
45 * 5/18 = 10
25:20 => 5:4
Answer: A
Question: A motorcyclist goes from Bombay to Pune, a distance of 180 kms at an average of 20 kmph speed. Another man starts from Bombay by car 2 Â½ hours after the first, and reaches Pune Â½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
A.1:2
B.2:3
C.1:9
D.1:5
Answer: B.2:3
Explanation: T = 180/20 = 9 h
T = 9 - 3 = 6
Time Ratio = 9:6= 3:2
Speed Ratio = 2:3
Answer: B
Question: Harkamal purchased 8kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 45 per kg. How much amount did he pay to the shopkeeper?
A.A)1000
B.B)1055
C.C)965
D.D)1075
Answer: C.C)965
Explanation: Cost of 8 kg grapes = 70 × 8 = 560.
Cost of 9 kg of mangoes = 45 × 9 = 405.
Total cost he has to pay = 560 + 405 = 965.
C)
Question: Suppose the sales tax be reduced from 3 1/2% to 3 1/3%, then what difference does it make to a person who purchase an article with marked price of Rs. 7200 ?
A.Rs 12
B.Rs 16
C.Rs 10
D.Rs 14
Answer: A.Rs 12
Explanation: Explanation :
Solution: required difference = (3 1/2% of Rs. 7200) - (3 1/3% of 7200)
= (7/2 - 10/3)% of 7200 = 1/6 % of Rs. 7200
= Rs. ((1/6) * (1/100) *7200) = Rs. 12.
Answer : A
Question: Peter must choose a lab partner by picking a name out of a bag. If the bag has 9 male names and F female names, what is the least number of female names in the bag if the probability of choosing a male lab partner is less than 3 out of 7?
A.11
B.12
C.13
D.14
Answer: C.13
Explanation: Male Names in the bag = 9
Female Names in the bag = F
Probability of selecting a male name is = P = 9/(9+F)
The question asked is "what is the least number of female names in the bag if the probability of choosing a male lab partner is less than 3 out of 7?"
so, we need to find out the minimum value of F for which P<3/7
9/(9+F) < 3/7
Solving for F gives the equation;
F>12
Since the question asked is the minimum value F should be 13
( F should be an integer).
ANSWER:C
Question: 2)	An bus covers a certain distance at a speed of 240 kmph in 5 hours. To cover the samedistance in 1hr, it must travel at a speed of?
A.700 km/hr
B.720 km/hr
C.740 km/hr
D.780 km/hr
Answer: B.720 km/hr
Explanation: Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
Required speed = 1200 x 3 km/hr = 720 km/hr.
B
Question: Ada and Paul received their scores on three tests. On the first test, Ada's score was 10 points higher than Paul's score. On the second test, Ada's score was 2 points higher than Paul's score. If Paul's average (arithmetic mean) score on the three tests was 3 points higher than Ada's average score on the three tests, then Paul's score on the third test was how many points higher than Ada's score?
A.9
B.14
C.17
D.21
Answer: D.21
Explanation: My take is Option D (23)
I followed a simple approach (explained below):
Test 1: Ada's score = Paul's score + 10
Test 2: Ada's score = Paul's score + 4
Avg. of Paul's score = 3 points higher than Avg. of Ada's score
This implies that : Sum of Paul's score [3 Tests] = 9 points higher than Sum of Ada's score [3 Tests] (9 points higher since 3 points were given in terms of average of 3 scores)
So, Paul needs to score 23 points higher than Ada in Test 3, since Paul needs to compensate for the lower score in test 1 and Test 2 ( 21 = 10 + 2 + 9)
D
Question: Excluding stoppages, the speed of a bus is 50 kmph and including stoppages, it is 43 kmph. For how many minutes does the bus stop per hour?
A.70 min
B.16 min
C.20 min
D.8.4 min
Answer: D.8.4 min
Explanation: D
8.4 min
Due to stoppages, it covers 7 km less.
Time taken to cover 9 km = (7/50 x 60) min = 8.4 min
Question: At a tanning salon, customers are charged $10 for their first visit in a calendar month and $3 for each visit after that in the same calendar month. In the last calendar month, 100 customers visited the salon, of which 30 made a second visit, and 10 made a third visit. All other customers made only one visit. If those visits were the only source of revenue for the salon, what was the revenue for the last calendar month at the salon?
A.$1220
B.$1120
C.$1300
D.$1340
Answer: B.$1120
Explanation: I get B. This question seems too straightforward for 600+. Am I missing something?
100 first-time visits --> 100(10) = $1000
30 + 10 = 40 subsequent visits --> 40(3) = $120
Total revenue: 1000+ 120 = $1120
The answer is B.
Question: Maria's grandparents were celebrating their 50th anniversary. Each of the children contributed $100 and the grandchildren each contributed $80. Together, all 15 members the family collected a total of $1,300 dollars for the celebration. How many children did Maria's grandparents have.
A.3
B.5
C.8
D.9
Answer: B.5
Explanation: Let x = the number of children. That means the number of grandchildren = 15 - x.
The amount contributed by the children = 100x. The amount contributed by the grandchildren = 80(15 - x).
This means: 100x + 80(15 - x) = 1300
100x + 1200 - 80x = 1300
100x - 80x = 1300 - 1200
20x = 100
x = 5
Answer: B
Question: What is the speed required for a car to cover a distance of 600 km in 5 hours?
A.160 kmh
B.140 kmh
C.150 kmh
D.130 kmh
Answer: B.140 kmh
Explanation: Speed= Distance / Time
Speed = 600 / 5 = 140
Answer: B
Question: If the tens digit x and the units digit y of a positive integer n are reversed, the resulting integer is 54 more than n. What is y in terms of x ?
A.x-10
B.x-12
C.x+8
D.x+6
Answer: D.x+6
Explanation: Original Digits=xy i.e. Number=10x+y
After reversing the digits:
Digits=yx i.e. Number=10y+x
10y+x is 54 more than 10x+y
10x+y+54=10y+x
10x-x+54=10y-y
9x+54=9y
x+6=y
OR
y=x+6
Answer : D
Question: How many arrangements of four 0's (zeroes), two 1's and two 2's are there in which the first 1 occur before the first 2?
A.420
B.360
C.320
D.210
Answer: D.210
Explanation: Solution:
Total number of arrangements = [8! /(4! *2! *2!)]= 420.
Since, there are two 1's and two 0's, the number of arrangements in which the first 1 is before the first 2 is same as the number of arrangement in which the first 2 is before the first 1 and they are each equal to half the total number of arrangements = 210.
Answer: Option D
Question: If 12 men do a work in 80 days, in how many days will 16 men do it?
A.17 days
B.19 days
C.15 days
D.60 days
Answer: D.60 days
Explanation: 12 * 80 = 16 * x
x = 60 days
Answer: D
Question: Suppose you work for a manufacturing plant that pays you $12.50 an hour plus $0.16 for each widget you make. How many widgets must you produce in a 40 hour week to earn $700 (before payroll deductions)?
A.1220
B.1250
C.1280
D.1310
Answer: B.1250
Explanation: total pay = 40*$12.50 + $0.16*x = 700
x = 200 / 0.16 = 1250
The answer is B.
Question: Each of the following equations has at least one solution EXCEPT D. Is it true?
A.2* -a = (–2)*a
B.(–2)-a = –2-a
C.(–2)a = –2a
D.-2*a = -2-a
Answer: D.-2*a = -2-a
Explanation: If we put a = 1 then
A. -2
B. -3
C. -2
E. 2
For D -2 = -3 wrong. If we put 0 0=-2 wrong
Question: Four-ninths of a drink mix is dye and the rest is sugar. When the mix is added to water a gallon of drink is made that is 10% sugar. What percentage of the gallon is dye?
A. 6
B. 6.5
C. 7.5
D. 8
Answer: D. 8
Explanation: The proportion of Dye and sugar will remain constant.
Dye/Sugar = (4/9)/(5/9) = x/10
=> 4/5 = x/10 => x = 4*10/5 = 8
Answer is D
Question: The price of 24 apples is equal to that of 28 oranges. The price of 45 apples and 60 oranges together is Rs.1350. The total price of 30 apples and 40 oranges is
A.400
B.200
C.450
D.900
Answer: D.900
Explanation: Price of 45 apples and 60 oranges = Rs.1350
Price of 15 apples and 20 oranges = Rs.1350/3 = Rs.450 (∵ Divided LHS and RHS by 15)
Price of 30 apples and 40 oranges = Rs.450 × 2 = Rs.900 (∵ Multiplied LHS and RHS by 2)
Answer : Option D
Question: In how many years will a sum of money doubles itself at 5% per annum on simple interest?
A.20
B.25
C.15
D.10
Answer: A.20
Explanation: P = (P*5*R)/100
R = 20%
ANSWER A
Question: A jogger running at 9 kmph along side a railway track is 280 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
A.3.6 sec
B.40 sec
C.36 sec
D.72 sec
Answer: B.40 sec
Explanation: Speed of train relative to jogger
= (45 – 9) km/h = 36 km/h
= (36 × 5⁄18) m/sec = 10 m/sec
Distance to be covered = (280 + 120) m = 400 m.
∴ Time taken = (400⁄10) sec = 40 sec.
Answer B
Question: Which of the following is not a prime number ?
A.383
B.389
C.390
D.397
Answer: C.390
Explanation: Clearly, 390 is not a prime number.
Answer : C
Question: The amount of electrical current that flows through a wire is inversely proportional to the resistance in that wire. A wire originally carries 4 amperes of electrical current. Then the resistance is reduced to one-sixth of its original value. How many amperes of electrical current will flow through the wire?
A.2/3
B.4
C.16
D.24
Answer: D.24
Explanation: Given that, I∝1/R, I*R is a constant value.
I1*R1 = I2*R2
I1*R1 = I2*R1/6
I2 = 6*I1 = 24 amperes
The answer is D.
Question: If A:B = 1/2: 1/5 B:C = 1/2:1/5 then A:B:C?
A.12:24:36
B.1:2:3
C.25:10:4
D.14:12:16
Answer: C.25:10:4
Explanation: A:B = 1/2:1/5 = 5:2
B:C = 1/2:1/5 = 5:2
--------------------
A:B:C = 8:12
Answer: C
Question: A diagonal of a polygon is an segment between two non-adjacent vertices of the polygon. How many diagonals does a regular 30-sided polygon have?
A. 875
B. 405
C. 1425
D. 2025
Answer: B. 405
Explanation: There's a direct formula for this.
Number of diagonals in a regular polygon = [n*(n-3)] / 2, n = number of sides of the regular polygon.
Here, n = 30.
Plugging it in, we get 405 diagonals!
Answer (B).
Question: A can do half the work in one day where as B can do it full. B can also do half the work of C in one day. Ratio in their efficiency will be?
A.1:2:7
B.1:2:3
C.1:2:6
D.1:2:4
Answer: D.1:2:4
Explanation: WC of A: B = 1:2
B: C = 1:2
---------------------
A: B: C = 1:2:4
Answer: D
Question: From the top of a building, an object is thrown upward with an initial speed of 64 ft/sec. It touches the ground 5 seconds later. What is the height of the bulding
A.80 feet
B.70 feet
C.60 feet
D.50 feet
Answer: A.80 feet
Explanation: The formula for the height H of a projectile thrown upward is given by
H(t) = -(1 / 2) g t 2 + Vo t + Ho
g is a constant and equal to 32. The initial speed Vo is known and also when t = 5 seconds H = 0 (touches the ground). Ho is the initial height or height of the building. Hence we can write
0 = -(1 / 2) (32) (5) 2 + (64) (5) + Ho
Solve the above for Ho to find the height of the building
Ho = 80 feet
Answer A
Question: A shopkeeper forced to sell at cost price, uses a 700 grams weight for a kilogram. What is his gain percent?
A.10%
B.9%
C.11.11%
D.42.85 %
Answer: D.42.85 %
Explanation: Shopkeeper sells 700g instead of 1000g.
So, his gain = 1000 - 700 = 300g.
Thus, %Gain = (300 *100)/700 = 42.85%.
answer : OPTION D
Question: If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,879,277 minutes earlier? (Assume standard time in one location.)
A.6:22
B.6:24
C.6:27
D.6:30
Answer: D.6:30
Explanation: 6:27 minus 2,879,277 in any way must end with 0.
The only answer choice which ends with 0 is D.
The answer is D.
Question: The 15 homes in a new development are each to be sold for one of three different prices so that the developer receives an average (arithmetic mean) of $200,000 per home. If 4 of the homes are to be sold for $170,000 each and 5 are to be sold for $200,000 each, what will be the selling price of each of the remaining 20 homes?
A.$206,000
B.$210,000
C.$215,000
D.$220,000
Answer: A.$206,000
Explanation: IMO the answer has to be D.
5 houses are being sold for 200,000. 4 houses are being sold for $30,000 less, resulting in a loss of $120,000. To make the average selling price intact i.e. $200,000, the remaining 20 houses must be sold at such a profit that it compensates for the loss of 120,000. Hence 20x=120,000.
x=6,000.
The 20 houses are sold at $6,000 profit or at $206,000. (ANSWER A)
Question: Solve for x: 2x – y = (3/4)x + 6
A.(y + 6)/5
B.4(y + 6)/5
C.(y + 6)
D.4(y - 6)/5.
Answer: B.4(y + 6)/5
Explanation: 2x – y = (3/4)x + 6.
or, 2x - (3/4)x = y + 6.
or, (8x -3x)/4 = y + 6.
or, 5x/4 = y + 6.
or, 5x = 4(y + 6).
or, 5x = 4y + 24.
or, x = (4y + 24)/5.
Therefore, x = 4(y + 6)/5.
correct answer B
Question: The average age of the mother and her six children is 12 years which is reduced by 5 years if the age of the mother is excluded. How old is the mother
A.40
B.41
C.42
D.43
Answer: C.42
Explanation: Option C
Question: x, y, and z are all unique numbers. If x is chosen randomly from the set {6, 7, 8, 9, 10, 11} and y and z are chosen randomly from the set {20, 21, 22, 23}, what is the probability that x and y are prime and z is not?
A.1/5
B.3/20
C.2/15
D.1/12
Answer: D.1/12
Explanation: P(x is prime) = 1/3
P(y is prime) = 1/4
If y is prime, then z is not prime since y and z are unique.
Then the probability is 1/3*1/4 = 1/12
The answer is D.
Question: x, y, a, and b are positive integers. When x is divided by y, the remainder is 6. When a is divided by b, the remainder is 15. Which of the following is NOT a possible value for y + b?
A.24
B.21
C.20
D.17
Answer: B.21
Explanation: Important note: remainder is ALWAYS less than divisor, thus y>6 and b>15 --> y+b>21.
Answer: B.
Question: Which of the following integers does NOT have a divisor bigger than 1 that is the square of an integer?
A.95
B.125
C.54
D.16
Answer: A.95
Explanation: Prime Factorization
95=19*5. There are no perfect squares as factors.
125=5*5*5= 5^2*5. Includes the perfect square of 25.
54=3*3*3*2= 3^2*3*2. Includes the perfect square of 9.
16=2*2*2*2=2^2*2^2. Includes the perfect square of 4.
48=2*2*2*2*3=4^2*3. Includes the perfect square of 16.
All but 95 have a perfect square as a factor so the correct answer is A.
Question: The value of x + x(xx) when x = 3 is:
A.A)36
B.B)16
C.C)30
D.D)64
Answer: C.C)30
Explanation: x + x(xx)
Put the value of x = 2 in the above expression we get,
3 + 3(33)
= 3+ 3(3 × 3)
= 3 + 3(9)
= 3 + 27
= 30
C
Question: The average (arithmetic mean) of four distinct positive integers is 6. If the average of the smaller two of these four integers is 6, which of the following represents the maximum possible value of the largest integer?
A.12
B.6
C.3
D.2
Answer: A.12
Explanation: Let the distinct number be A,B,C, and D
Its given A > B > C > D
also A + B + C + D =24 and A + B = 6 means C + D = 18
Since the question ask for the largest possible number we should choose the least value for A and B,C. So D should be 12
Answer : A
Question: A train running at the speed of 30 km/hr crosses a pole in 24 seconds. What is the length of the train?
A.200 m
B.250 m
C.300 m
D.350 m
Answer: A.200 m
Explanation: Speed=(30 * 5/18) m/sec
= (25/3) m/sec Length of the train
= (Speed x Time)
= (25/3 * 24) m = 200 m.
Answer:A
Question: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.85. How much was lent at 5% ?
A.500
B.600
C.450
D.550
Answer: A.500
Explanation: Explanation:
Let the lent at 5% be 'A'
(A x 5 x 1)/100 + [(1500 - A)x 6 x 1]/100 = 85
5A/100 + 90 â€“ 6A/100 = 85
A/100 = 5
=> A = 500
ANSWER IS A
Question: P is 60% more efficient than Q. P can complete a work in 26 days. If P and Q work together, how many days will it take to complete the same work?
A.12
B.14
C.16
D.18
Answer: C.16
Explanation: The work done by P in 1 day = 1/26
Let work done by Q in 1 day = q
q × (160/100) = 1/26
q = 100/(26×160) = 10/(26×16)
The work done by P and Q in 1 day = 1/26 + 10/(26×16) = 26/(26×16)= 1/16
P and Q together can do the work in 16 days.
The answer is C.
Question: A man & his wife appear in an interview for 2 vacancies in the same post.The probability of husband's selection is (1/7) & probability of wife's selection is (1/5). what is the probability that only one of them is selected?
A.4/5
B.2/7
C.8/15
D.4/7
Answer: B.2/7
Explanation: (6/7)*(1/5)+(1/7)*(4/5) = (6/35)+(4/35)= 10/35 = 2/7
ANSWER:B
Question: Virginia, Adrienne, and Dennis have taught history for a combined total of 75 years. If Virginia has taught for 9 more years than Adrienne and for 9 fewer years than Dennis, for how many years has Dennis taught?
A. 23
B. 34
C. 35
D. 41
Answer: B. 34
Explanation: Let number of years taught by Virginia = V
number of years taught by Adrienne = A
number of years taught by Dennis = D
V+A+D = 75
V= A+9
=>A = V-9
V= D-9
=> A = (D-9)-9 = D-18
D-9 + D-18 + D = 96
=> 3D = 75+ 27 = 102
=> D = 34
Answer B
Question: What will be the difference between simple and compound interest @20% per annum on a sum of $500 after 2 years?
A.$10
B.$20
C.$25
D.$30
Answer: B.$20
Explanation: S.I. = 500*20*2/100 = $200
C.I. = 500 * (1 + 20/100)^2 - 500 = $220
Difference = 220-200 = $20
Answer is B
Question: One vessel contains a mixture of 5 parts pure wine and 3 parts soda, whereas the other vessel contains a mixture of 9 parts pure wine and 7 parts soda. Compare the strength of the wine.
A.35;36
B.7 : 8
C.7 : 4
D.10 : 9
Answer: D.10 : 9
Explanation: 5/8 : 9/16
LCM of 8,16 = 16
(5/8)*16 : (9/16)*16
10:9
Answer is D.
Question: five mobsters have arrived at the theater for the premiere of the film “Goodbuddies.” One of the mobsters, Frankie, is an informer, and he's afraid that another member of his crew, Joey, is on to him. Frankie, wanting to keep Joey in his sights, insists upon standing behind Joey in line at the concession stand, though not necessarily right behind him. How many ways can the six arrange themselves in line such that Frankie’s requirement is satisfied?
A.6
B.24
C.120
D.60
Answer: D.60
Explanation: Arrangement of 5=5!. In half of the cases Frankie will be behind Joey and in half of the cases Joey will be behind Frankie (as probability doesn't favor any of them). So, the needed arrangement is 5!/2=60.
Answer: D (60)
Question: Sales price is $60, gross profit is 140% of cost, what is the value of gross profit?
A.32
B.33
C.39
D.35
Answer: D.35
Explanation: Cost + Profit = Sales
Cost + (140/100)Cost = 60
Cost = 25
Profit = 60 - 25 = 35
Answer (D)
Question: Two brothers Ram and Ravi appeared for an exam. The probability of selection of Ram is 6/7 and that of Ravi is 1/5. Find the probability that both of them are selected.
A.2/35
B.2/3
C.6/35
D.5/7
Answer: C.6/35
Explanation: Let A be the event that Ram is selected and B is the event that Ravi is selected.
P(A) = 6/7
P(B) = 1/5
Let C be the event that both are selected.
P(C) = P(A) x P(B) as A and B are independent events:
= 6/7 x 1/5 = 6/35
ANSWER:C
Question: Find the length of the longest pole that can be placed in a room 12 m long, 8 m broad and 9 m high.
A.10 m
B.12 m
C.17 m
D.19 m
Answer: C.17 m
Explanation: Solution
Length of longest pole = Length of the diagonal of the room
=√(12)2 + 82 + 92
‹=›√289
= 17 m.
Answer C
Question: If the diagonal of a rectangle is 17 cm long and its perimeter is 46 cm, find the area of the rectangle.
A.127 cm^2
B.125 cm^2
C.120 cm^2
D.102 cm^2
Answer: C.120 cm^2
Explanation: Let length = x and breadth = y. Then,
2 (x + y) = 46 or x + y = 23 and x^2 + y^2 = (17)^2 = 289.
Now, (x + y)^2 = (23)^2 <=> (x^2 + y^2) + 2xy = 529 <=> 289 + 2xy = 529 =xy=120
Area = xy = 120 cm^2
Answer is C.
Question: Two pipes A and B can fill a tank in 30 and 40 minutes respectively. If both the pipes are used together, then how long it will take to fill the tank ?
A.16 1/7
B.17 1/7 mins.
C.15 1/7
D.14 1/7
Answer: B.17 1/7 mins.
Explanation: Explanation:
In this type of questions we first get the filling in 1 minute for both pipes then we will add them to get the result, as
Part filled by A in 1 min = 1/30
Part filled by B in 1 min = 1/40
Part filled by (A+B) in 1 min = 1/30 + 1/40
= 7/120
So both pipes can fill the tank in 17 1/7 mins.
Option B