RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: There are 5 locks and 5 keys and each of the 5 keys matches each of the 5 locks. What is the minimum and the maximum trial numbers of attempts F needed to confirm that each of the 5 keys matches each of the 5 locks?
A.5,15
B.4,15
C.5,10
D.4,10
Answer: D.4,10
Explanation: Assume you have locks 1-5 and keys A-E.
Minimum: assume you are lucky to find the correct key/combo on the first try. So, 1 -> A, 2 -> B, 3 ->C, and 4 -> D, then 5 must match with E. Therefore, you only need to try 4 combos at a minimum.
Maximum: assume that it takes as many guesses as possible. So, with the first key you try A, B, C, and D with no success, therefore E must be the match (so 4 attempts). For key 2 you no longer have E available so you try A, B, and C, with no success, therefore D must be the match (3 attempts). And so on for key 3 (2 attempts) and key 4 (1 attempt). Key 5 matches with the remaining lock for a total of F= 4 + 3 + 2 + 1 = 10 attempts.D
Question: Each of three investments has a 20% of becoming worthless within a year of purchase, independently of what happens to the other two investments. If Simone invests an equal sum K in each of these three investments on January 1, the approximate chance that by the end of the year, she loses no more than 1/3 of her original investment is
A.90%
B.80%
C.70%
D.60%
Answer: A.90%
Explanation: The problem asks for the approximate chance that no more than 1/3 of the original investment is lost. We can apply the “1 – x” technique: what’s the chance that more than 1/3 of the original investment is lost? There are two outcomes we have to separately measure:
(a) All 3 investments become worthless.
(b) 2 of the 3 investments become worthless, while 1 doesn’t.
Outcome (a): The probability is (0.2)(0.2)(0.2) = 0.008, or a little less than 1%.
Outcome (b): Call the investments X, Y, and Z. The probability that X retains value, while Y and Z become worthless, is (0.8)(0.2)(0.2) = 0.032. Now, we have to do the same thing for the specific scenarios in which Y retains value (while X and Z don’t) and in which Z retains value (while X and Y don’t). Each of those scenarios results in the same math: 0.032. Thus, we can simply multiply 0.032 by 3 to get 0.096, or a little less than 10%.
The sum of these two probabilities is 0.008 + 0.096 = 0.104, or a little more than 10%. Finally, subtracting from 100% and rounding, we find that the probability we were looking for is approximately 90%.
The correct answer is A.
This problem illustrates the power of diversification in financial investments. All else being equal, it’s less risky to hold a third of your money in three uncorrelated (independent) but otherwise equivalent investments than to put all your eggs in one of the baskets. That said, be wary of historical correlations! Housing price changes in different US cities were not so correlated—and then they became highly correlated during the recent housing crisis (they all fell together), fatally undermining spreadsheet models that assumed that these price changes were independent.
Question: A man is walking at the rate of 6 km/hr crosses a bridge in 15 minutes. The length of the bridge is
A.1000 meters
B.1050 meters
C.1200 meters
D.1500 meters
Answer: D.1500 meters
Explanation: Explanation:
We need to get the answer in meters. So we will first of change distance from km/hour to meter/sec by multiplying it with 5/18 and also change 15 minutes to seconds by multiplying it with 60.
Speed=6âˆ—5/18=5/3m/sec
Time=15âˆ—60seconds=900seconds
Distance=Timeâˆ—Speed/Distance=5/3âˆ—900=1500meter
Option D
Question: if a three-digit number is selected at random from the integers 100 to 999, inclusive, what is the probability that the first digit and the last digit of the integer will both be exactly two less than the middle digit?
A.1:900
B.7:900
C.1:1,000
D.1:100
Answer: B.7:900
Explanation: There are 900 numbers between 100 and 999 (inclusive).
Numbers of the form ABA are: 131, 242,353,464,575,686,797 = total 7
Thus the probability asked = 7/900
B is the correct answer.
Question: Anil purchased 30 kg of wheat at the rate of Rs. 22 per kg and 20 kg of wheat at the rate of Rs. 24 per kg. He mixed the two. Approximately at what rate per kg should he sell the mixture to make 25% profit?
A.Rs. 25
B.Rs. 28.5
C.Rs. 30
D.Rs. 32.5
Answer: B.Rs. 28.5
Explanation: Explanation:
Total quantity of mixture = 30 + 20 = 50 kg.
By earning a profit of 25% on the total cost, the selling price of the mixture is
125/100 * (660 + 480 = 1140) = Rs. 1425
Selling price per kg = Total selling price / Total of mixture
= 1425 / 50
= Rs. 28.5
ANSWER B
Question: A pipe can empty 2/3rd of a cistern in 12mins. In 5 mins, what part of the cistern will be empty?
A.2/3
B.5/18
C.4/9
D.3/8
Answer: B.5/18
Explanation: 2/3 ---- 12
? ----- 5 ==> 5/18
B
Question: The radius of the two circular fields is in the ratio 3: 5 the area of the first field is what percent less than the area of the second?
A.69%
B.79%
C.60%
D.64%
Answer: D.64%
Explanation: r = 3 πr2 = 9
r = 5 πr2 = 25
25 π – 16 π
100 ---- ? => 64%
Answer: D
Question: If a < b < c , which of the following must be true?
(I) a < b^2
(II) b − a > c
(III) a^2 < b^2 < c^2
A.II only
B.I only
C.None
D.III only
Answer: C.None
Explanation: (I) a < b^2. Not necessarily true fractions: try a=1/3 and b=1/2.
(II) b − a < c. Not necessarily true: try a=-1/2, b=-1/3, and c=-1/4.
(III) a^2 < b^2 < c^2. Not necessarily true: try a=-1, b=0, and c=1.
None of the options must be true.
Answer: C.
Question: According to a survey, at least 50% of people like apples, at least 75% like bananas and at least 80% like cherries. What is the minimum percentage of people who like all three?
A.5%
B.10%
C.15%
D.20%
Answer: A.5%
Explanation: To minimize the percentage who like all three, let's maximize the percentage who like 2 out of 3.
80% like cherries and 20% don't like cherries.
Let's combine this with the people who like bananas.
20% don't like cherries but do like bananas.
55% like cherries and bananas.
25% like cherries but not bananas.
Now let's distribute the people who like apples.
20% like bananas and apples, but not cherries.
25% like cherries and apples, but not bananas.
5% like all three.
50% like cherries and bananas, but not apples.
The answer is A.
Question: A pen factory stores its toys in either a big box or a small box. The big box can store 27 pens while the small box can store 18 pens. If the factory is to store 112 newly manufactured pens, what is the least number of pens that will be left unboxed?
A.6
B.2
C.4
D.3
Answer: C.4
Explanation: Total pens to be stored 112
The big box can store 27
small box can store 18
storing 112 pens in big box 112/27 =4 r 4
least number of pens that will be left unboxed=4
Answer: C
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.278
B.240
C.88
D.21
Answer: B.240
Explanation: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x meters. Then, (x + 300)/36 = 15 ==> x + 300 = 540 ==> x = 240 m Answer:B
Question: The vertices of a rectangle in the standard (x,y) coordinate place are (0,0), (0,6), (12,0) and (12,6). If a line through (1,1) partitions the interior of this rectangle into 2 regions that have equal areas, what is the slope of this line?
A.1/2
B.2/3
C.1/4
D.2/5
Answer: D.2/5
Explanation: We should know that a rectangle can be divided into two equal areas by a straight line only when the straight line passes through the center of the rectangle.
The center of the rectangle is the point (6,3).
The slope of line passing through points (1,1) and (6,3) = (3-1)/(6-1) = 2/5
The answer is D.
Question: A envelop weight 8.5 gm,if 800 of these envelop are sent with an advertisement mail. How much wieght?
A.6.6kg
B.6.8kg
C.6.7kg
D.6.9kg
Answer: B.6.8kg
Explanation: 800*8.5
6800.0gm
6.8kg
ANSWER:B
Question: If XY denotes X is raised to the power Y, Find the last two digits of 19413843+ 19614181
A.12
B.22
C.42
D.82
Answer: D.82
Explanation: 1941^3843
unit digit= 1^3=1
10th digit=4*3=12=2 means last two digit =21
and 1961^4181
unit digit=1
10th digit=6*1=6 mean last two digit= 61
hence,
21+61= 82
ANSWER:D
Question: Ravi can do a piece of work in 20 days while Prakash can do it in 40 days. In how many days will they finish it together?
A.13 1/3 days
B.15 1/3 days
C.17 1/3 days
D.17 7/3 days
Answer: A.13 1/3 days
Explanation: 1/20 + 1/40 =3/40
40/3
= 13 1/13 days
Answer: A
Question: In a camp, there is a meal for 180 men or 200 children. If 150 children have taken the meal, how many men will be catered to with the remaining meal ?
A.38 men
B.32 men
C.34 men
D.45 men
Answer: D.45 men
Explanation: Explanation:
There is meal for 200 children. 150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children = 180 men
So, 50 Children = 180/200 * 50 = 45 men
Answer: D
Question: A set of numbers has the property that for any number t in the set, t + 2 is in the set. If -1 is in the set, which of the following must also be in the set?
I. 1
II. -3
III. 5
A.I only
B.II only
C.I and III only
D.II and III only
Answer: C.I and III only
Explanation: The question is which of the following must be in the set, not could be in the set.
If -1 is in the set so must be -1+2=1, as 1 is in the set so must be 1+2=3, as 3 is in the set so must be 3+2=5 and so on. So basically knowing that -1 is in the set we can say that ALL odd numbers more than -1 are also in the set.
Answer: C.
Question: In a particular course, only two grades are given all semester: the midterm exam, which counts for 25% of the semester grade, and the final exam, which counts for the remainder. Lindsey's semester grade was 88%. If the highest possible score on either exam is 100%, what is the lowest possible score B that Lindsey could have received on her midterm exam?
A.52%
B.64%
C.72%
D.76%
Answer: A.52%
Explanation: If the midterm counts for 25% of the total grade, then the final exam must count for the remaining 75%, meaning that in this weighted average problem the final is weighted 3 times as much as the midterm. Using the weighted average mapping strategy, then, and maximizing her final exam score so that you minimize her midterm score, you have:
100-------------88----------------------------x
And you know that the ratio is 3:1. Since the final exam score of 100 is weighted heavier, then the difference of 12 between 100 and 88 is the1part of the ratio, meaning that 3(12) is the 3 portion. That equals 36, so the midterm score (x) is 36 less than the weighted average of 88. 88 - 36 = 52, sothe correct answer is 52%.
Question: Two trains T1 and T2 start simultaneously from two stations X and Y respectively towards each other. If
they are 40 km apart both 3 and 6 hours after start, then find the distance between the two stations.
A.120km
B.150km
C.220km
D.180km
Answer: A.120km
Explanation: In first 3 hours T1 travels R km and T2 travels S km.
After 6 hours they traveled R+S+40+ 40
2(R+S ) = R+S +80
R+S = 180
Hence distance between XY is R+S+ 40 = 40 +80 =120
Answer : A
Question: The measures of the 2 acute angles of a triangle are in the ratio of 2:7. What are the measures of the 2 angles?
A.50°
B.70°
C.80°
D.90°
Answer: B.70°
Explanation: If the ratio of the two angles is 2:7, then the measures of two angles can be written as 2x and 7x. Also the two acute angles of a triangle is equal to 90°. Hence
2x + 7x = 90
9x = 90
x = 10
Measures of the two acute angles are
2x = 2 × 10 = 20°
7x = 7 × 10 = 70°
B
Question: A cycle is bought for Rs.900 and sold for Rs.1080, find the gain percent?
A.10
B.16
C.20
D.22
Answer: C.20
Explanation: C
20%
900 ---- 180
100 ---- ? => 20%
Question: In a kilometer race, A beats B by 50 meters or 5 seconds. What time does A take to complete the race?
A.199 sec
B.190 sec
C.726 sec
D.90 sec
Answer: D.90 sec
Explanation: Time taken by B run 1000 meters
= (1000 * 5)/50 = 100 sec.
Time taken by A = 100 - 10
= 90 sec.
Answer: D
Question: In what ratio must tea at Rs.62 per Kg be mixed with tea at Rs.72 per Kg so that the mixture must be worth Rs.64.50 per Kg?
A.3 : 1
B.3 : 2
C.4 : 3
D.5 : 3
Answer: A.3 : 1
Explanation: Required ratio = 750 : 250 = 3 : 1
Answer A
Question: The perimeter of a semi circle is 180 cm then the radius is?
A.22
B.28
C.35
D.37
Answer: C.35
Explanation: 36/7 r = 180
=> r
= 35
Answer: C
Question: A train 250 m long running at 72 kmph crosses a platform in 20 sec. What is the length of the platform?
A.150m
B.200m
C.250m
D.270m
Answer: A.150m
Explanation: D = 72 * 5/18 = 20 = 400 â€“ 250 = 150m
ANSWER:A
Question: In current of a stream runs at 2 km/hr. A motor boat goes 30 km upstream and back again to the starting point in 20 hours. The speed of the moter boat in still water is:
A.5 km/hr
B.8 km/hr
C.2 km/hr
D.4 km/hr
Answer: D.4 km/hr
Explanation: Explanation:
Let the speed ofboat in still water be x km/hr.
Speed down stream = (x + 2) km/hr
Speed up stream = (x - 2) km/hr
30/(x+2) + 30/(x-2) = 20 hours
(30x-60+30x+60)/(x2-4) = 20
60x = 20x2 - 80
3x = x2 - 4
x2-3x-4=0
x2-4x+x-4=0
x(x-4)+1(x-4)=0
x=4, x=-1
Speed of moter boat is 4 km/hr
Answer: Option D
Question: A fair coin is tossed 15 times. What is the probability of getting more heads than tails in 15 tosses?
A.1/2
B.63/128
C.4/7
D.61/256
Answer: A.1/2
Explanation: On each toss, the probability of getting a head is 1/2 and the probability of getting a tail is 1/2.
There is no way to get the same number of heads and tails on an odd number of tosses.
There will either be more heads or more tails.
Then there must be more heads on half of the possible outcomes and more tails on half of the possible outcomes.
P(more heads) = 1/2
The answer is A.
Question: A total of 3000 chocolates were distributed among 120 boys and girls such that each boy received 2 chocolates and each girl received 3 chocolates. Find the respective number of boys and girls?
A.22
B.60
C.77
D.26
Answer: B.60
Explanation: Let the number of boys be x.
Number of girls is 120 - x.
Total number of chocolates received by boys and girls = 2x + 3(120 - x) = 300
=> 360 - x = 300 => x = 60.
So, the number of boys or girls is 60.
Answer: B
Question: From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:
A.149 m
B.156 m
C.173 m
D.200 m
Answer: C.173 m
Explanation: Solution
Let AB be the tower.
Then, <APB =30° and AB= 100 m
AB/AP= tan30°
= 1 / √3
AB = (AB x √3)= 100√3 m.
= (100 x 1.73) m = 173 m.
Answer C
Question: In a shower, 8 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:
A.75 cu. m
B.1200 cu. m
C.7500 cu. m
D.75000 cu. m
Answer: B.1200 cu. m
Explanation: 1 hectare = 10000 sq mtr
The volume of water that falls on 1.5 hectares of ground = 0.08*1.5*10000 = 1200 cub mtr .
ANSWER:B
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively . If they cross each other in 23 seconds, what is the ratio of their speeds?
A.3/2
B.1/2
C.4/3
D.3/4
Answer: A.3/2
Explanation: Let the speed of the trains be x and y respectively
length of train1 = 27x
length of train2 = 17y
Relative speed= x+ y
Time taken to cross each other = 23 s
=> (27x + 17 y)/(x+y) = 23
=> (27x + 17 y)/ = 23(x+y)
=> 4x = 6y
=> x/y = 6/4 = 3/2
Answer is A.
Question: Let the polynomials be:
P1(x)=3x2−7x+8,
P2(x)=−5x2−4x+2,
P1(x)+P2(x)=
A.2x2 + 11x - 7
B.-2x2 - 11x + 10
C.-2x2 - 11x + 6
D.2x2 - 9x + 7
Answer: B.-2x2 - 11x + 10
Explanation: Solution:
P1(x)+P2(x)=(3x2−7x+8)+(−5x2−4x+2)=P1(x)+P2(x)=(3x2−7x+8)+(−5x2−4x+2)=
3x2−7x+8−5x2−4x+2=3x2−7x+8−5x2−4x+2=
−2x2−11x+10
Answer B
Question: Two trains of lengths 150m and 180m respectively are running in opposite directions with a speed of 30 km/hr and 24 km/hr respectively. How much time will they take to cross each ther?
A.21 secs.
B.23 secs.
C.24 secs.
D.22 secs.
Answer: D.22 secs.
Explanation: Relative speed = (30+24) km/hr =15m/s. Time taken by the trains to cross each other =sum of lengths of two trains /Relative speed. (150+180)/15sec. =330/15 = sec22s. Answer : D
Question: 3x^2-6x+3 = 0
Find the above equation find the value of x
A.0
B.X=1
C.2
D.4
Answer: B.X=1
Explanation: a = 3, b = -6, c = 3
x1,2 = (6 ± √ ( (-6)2 - 4×3×3)) / (2×3) = (6 ± √(36-36)) / 6 = (6 ± 0) / 6
x1 = x2 = 1
B
Question: Sarah's seafood restaurant gets a delivery of fresh seafood every day, 6 days per week, and her delivery company charges her dollars per delivery plus cents per item delivered. If lst week Sarah's seafood restaurant had an average of x items per day delivered, then which of the following is the total cost, in dollars, of last week's deliveries ?
A.6cdx/100
B.d + 6cx/100
C.6d + xc/100
D.6d + 6xc/100
Answer: D.6d + 6xc/100
Explanation: Answer will be D. Straightforward question.
Question: A three digit non-zero number 'abc' in base 5, when converted to base 7, becomes 'cba'. Which of the following is necessarily true?
A.a must be 2
B.c must be 2
C.b must be 0
D.None
Answer: C.b must be 0
Explanation: Sol:
Given (abc)5=(cba)7(abc)5=(cba)7
or 25a + 5b + c = 49c + 7b + a
or 24a = 2b + 48c
or 12a = b + 24c
as abc is a 3 digit number in base 5, the possible values for a, b and c are 0, 1, 2, 3, 4 only
The possible solutions of the above equation are:
(a, b, c) = (2, 0, 1) and (4, 0, 2) only
a can take value = 2 or 4
b can take value = 0 only
c can take value = 1 or 2 only.
So correct option c.
Answer C
Question: A photo-mat shop charges $0.6 for the first photo inside a film, and 40% cents less for each additional photo. How many photos can we develop with $36 if each film contains 36 photos?
A.2 films and 26 photos
B.5 films and 6 photos
C.5 films and 14 photos
D.6 films and 4 photos
Answer: A.2 films and 26 photos
Explanation: 1st photo = 0.60
Subsequent = 0.60*0.6=0.36
Price of 1 full film=0.6+0.36*35=13.2
Price of 4 full film = 13.2*2=26.4
36-26.4=9.6
9.6=0.6+0.36x
x=25
36--->2 full films and 1+25=26 photos
Answer: A
Question: In how many ways can a four-letter password be chosen, using the letters A, B, C, D, and/or E, such that at least one letter is repeated within the password?
A.505
B.864
C.900
D.936
Answer: A.505
Explanation: Total number of four letter passwords = 5*5*5*5= 625 ------(1)
Total number of passwords in which no letter repeats = 5C4*4!= 5*24=120------(2)
therefore required value = (1)-(2)= 625-120=505
A
Question: The two lines y = x and x = -5 intersect on the coordinate plane. If z represents the area of the figure formed by the intersecting lines and the x-axis, what is the side length of a cube whose surface area is equal to 6z?
A.16
B.5/√2
C.8
D.2√2
Answer: B.5/√2
Explanation: 800score Official Solution:
The first step to solving this problem is to actually graph the two lines. The lines intersect at the point (-5, -5) and form a right triangle whose base length and height are both equal to 4. As you know, the area of a triangle is equal to one half the product of its base length and height: A = (1/2)bh = (1/2)(4 × 4) = 25/2; so z = 25/2.
The next step requires us to find the length of a side of a cube that has a face area equal to 25/2. As you know the 6 faces of a cube are squares. So, we can reduce the problem to finding the length of the side of a square that has an area of 25/2. Since the area of a square is equal to s², where s is the length of one of its side, we can write and solve the equation s² = 25/2. Clearly s = √25/2 = 5/√2 , oranswer choice (B).
Question: During a certain two-week period, 80 percent of the movies rented from a video store were comedies, and of the remaining movies rented, there were 4 times as many dramas as action movies. If no other movies were rented during that two-week period and there were A action movies rented, then how many comedies, in terms of A, were rented during that two-week period?
A.5 A
B.15 A
C.20 A
D.1/25 A
Answer: C.20 A
Explanation: Movies: 80 % comedies. 20 % remaining genre.
Now in this 20 %, there are only 2 categories. Action movies and Drama Movies.
If Action = x; Drama movies = 4x. Total 5x.
5x = 20; x = 4
Action movies: 4 %
Drama movies: 16 %
we can say that out of 100z,:
comedies: 80z
action: 4z
drama: 16 z
Now action movies wereA
This means:
A = 4z.
z = (A/4)
Comedies: 80z = 80 * (A/4)
20 A
C is the answer.
Question: What percent of selling price would be 34% of cost price if gross profit is 26% of the selling price?
A.17.16
B.74.0
C.25.16
D.88.4
Answer: C.25.16
Explanation: Let the selling price of the article be 100.
∴ Profit = 26
∴ Cost price of the article = 100 – 26 = 74
∴ Reqd.% = 34×74/100=25.16%
Answer C
Question: Two horses begin running on an oval course at the same time. One runs each lap in 9 minutes; the other takes 12 minutes to run each lap. How Many minutes after the start will the faster horse have a one lap lead?
A.36
B.12
C.9
D.4
Answer: A.36
Explanation: The rate of the faster horse is 1/9 lap/minute;
The rate of the slower horse is 1/12 lap/minute;
Their relative rate is 1/9-1/12=1/36 lap/minute;
The faster horse to gain one full lap will need time=distance/rate=1/(1/36)=36 minutes.
Answer: A.
Question: What is 2 2/3 - 1 1/4 divided by 1/2 - 1/4 ?
A.17/36
B.36/17
C.17/6
D.17/3
Answer: D.17/3
Explanation: 2 2/3 - 1 1/4 = 8/3 - 5/4 = (32 - 15 )/12 = 17/12
1/2 - 1/4 = (2-1)/4 = 1/4
So 17/12/1/4 = 17/12 *4 = 17/3
Answer - D
Question: A car travelling with 5/7 of its actual speed covers 42km in 1hr 40 min 48 sec find the actual speedof the car?
A.52km/hr
B.25km/min
C.35km/hr
D.125km/hr
Answer: C.35km/hr
Explanation: Time taken=1hr 40 min 48sec
=1hr 404/5 min=1 51/75hrs =126/75hrs.
let the actual speed be xkm/hr.
then x 5/7*126/75=42
x=(42*7*75/5*126)=35km/hr
Answer(C)
Question: At what rate percent on simple interest will Rs.750 amount to Rs.900 in 5 years?
A.4
B.5
C.2
D.1
Answer: A.4
Explanation: 150 = (750*5*R)/100
R = 4%
ANSWER A
Question: 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3294, how much was it in the beginning?
A.2988
B.2776
C.4079
D.2871
Answer: C.4079
Explanation: X * (95/100) * (85/100) = 3294
X = 4079
Answer:C
Question: The total of the ages of Jai, Prajan and Sarath is 93 years. Ten years ago, the ratio of their ages was 2 : 3 : 4. What is the present age of Sarath?
A.24 years
B.32 years
C.38 years
D.42 years
Answer: C.38 years
Explanation: Sol.
Let the ages of Jai, Prajan and Sarath 10 years ago be 2x, 3x and 4x years respectively.
Then, (2x + 10) + (3x + 10) + (4x + 10) = 93
⇔ 9x = 63
⇔ x = 7.
∴ Sarath's present age = (4x +10) = 38 years.
Answer C
Question: After 38 liters of petrol were poured into the tank, it was still 5% empty. How much petrol must be poured into the tank in order to fill it?
A.7 liters
B.9 liters
C.4 liters
D.2 liters
Answer: D.2 liters
Explanation: 95% ----------- 38
5% ------------ ? => 2 liters
Answer:D
Question: In how many different number of ways 4 men and 2 women can sit on a shopa which can accommodate persons?
A.25
B.30
C.45
D.20
Answer: B.30
Explanation: 6p2 = 6 x 5 = 30
B)
Question: A data set with a mean of 60 has a standard deviation of 3.5. Which of the following is the smallest number that falls within one standard deviation of the mean?.
A.58
B.59
C.64
D.68
Answer: B.59
Explanation: [(59-60)^2]^1/2 = 1
So 59 satisfies that criteria
answer is B
Question: Find the cost of fencing around a circular field of diameter 28 m at the rate of Rs.1.50 a meter?
A.281
B.132
C.882
D.279
Answer: B.132
Explanation: 2 * 22/7 * 14 = 88
88 * 1 1/2
= Rs.132
Answer: B
Question: An insect leaps 42 centimeters in 1.2 seconds. What is its speed?
A.3.5 meters per second
B.0.35 meters per second
C.5 centimeters per second
D.0.5 meters per second
Answer: B.0.35 meters per second
Explanation: 42 / 1.2 = 35 cm/s = 0.35 m/s
The answer is B.
Question: Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
A.250
B.300
C.350
D.400
Answer: A.250
Explanation: Explanation :
Here's the solution :
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
=> z + (120/100) * z = 550
=> (11 / 5) * z = 550
=> z = 550 * 5 / 11
=> z = 250
Hence (A) is the correct answer.
Answer : A