RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A certain city with a population of 84,000 is to be divided into 11 voting districts , and no district is to have a population that is more than 10 percent greater than the population of any other district What is the minimum possible population that the least populated district could have ?
A.a) 10,700
B.b) 10,800
C.c) 7,000
D.d) 11,000
Answer: C.c) 7,000
Explanation: Let x = number of people in smallest district
x*1.1 = number of people in largest district
x will be minimised when the number of people in largest district is maximised
10*x*1.1 = 11x = total number of people in other districts
So we have 11x + x = 84k
x = 7,000
Answer : C
Question: A lady gives a dinner party to 5 guests to be selected from nine friends. The number of ways of forming the party of 5, given that two of the friends will not attend the party together is
A.56
B.126
C.91
D.94
Answer: C.91
Explanation: Number of ways of selecting 5 guests from nine friends = 9C5
Out of these, 7C3 ways are those in which two of the friends occur together [3 more persons to be selected out of remaining 7]
∴ Number of ways, in which two of the friends will not attend the party together = 9C5 – 7C3 = 91.
Answer C
Question: The number of boxes in a warehouse can be divided evenly into 6 equal shipments by boat or 27 equal shipments by truck. What is the smallest number of boxes that could be in the warehouse?
A.27
B.33
C.54
D.81
Answer: C.54
Explanation: Explanations
1) This tells us that the number of boxes is evenly divisible by both 6 and 27; in other words, it’s a common multiple of 6 and 27. The question says: what’s the smallest value it could have? In other words, what’s the LCM of 6 and 27? (This question is one example of a real-world set-up where the question is actually asking for the LCM.)
Step (a): 6 = 2*3 27 = 3*3*3
Step (b): 6 = 2*3 27 = 3*3*3 GCF = 3
Step (c): 6 = 3*2 27 = 3*9
Step (d) LCM = 3*2*9 = 54
Thus, 54 is the LCM of 6 and 27.
Answer: C.
Question: A bag contains 3 red, 6 yellow and 8 green balls. 3 balls are drawn randomly. What is the probability that the balls drawn contain balls of different colours?
A.2/7
B.3/5
C.3/11
D.18/85
Answer: D.18/85
Explanation: Total number of balls = 3+6+8 = 17
n(S) = 17C3 = 680
n(E) = 3C1 * 6C1 * 8C1 = 144
Probability = 144/680 = 18/85
Answer is D
Question: What is the factorial of 5?
A.1
B.60
C.120
D.130
Answer: C.120
Explanation: C
120
120 (5 X 4 X 3 X 2 X 1).
Question: Bill made a profit of 10% by selling a product. If he had purchased that product for 10% less and sold it at a profit of 30%, he would have received $63 more. What was his original selling price?
A.$850
B.$990
C.$1050
D.$1180
Answer: B.$990
Explanation: Let P be the original purchase price of the product.
Bill originally sold the product for 1.1*P.
In the second scenario, the purchase price is 0.9*P.
A 30% profit means the selling price would be 1.3*0.9*P = 1.17*P
Thus, according to the information in the question, 1.17P - 1.1P = 63
0.07 = 63
P = 900
The original selling price was 900*1.1 = 990.
The correct answer is B.
Question: The workforce of Company X is 60% female. The company hired 28 additional male workers, and as a result, the percent of female workers dropped to 55%.How many employees did the company have after hiring the additional male workers?
A.160
B.220
C.336
D.360
Answer: C.336
Explanation: Let's xx be total quantity of employees
0.6x=females before adding men
0.55(x+28)=females after adding men
as quantity of women doesn't change we can make an equation:
0.6x=0.55(x+28)
0.05x=15.4
x=308 - this is quantity of employees before adding 28 men
So after adding it will be 336
Answer is C
Question: Bruce and Bhishma are running on a circular track of length 600m. Speed of Bruce is 30 m/s and that of Bhishma is 20 m/s .They start fro the same point at the same time in the same direction. When will they meet again for the first time?
A.30 sec
B.40 sec
C.50 sec
D.60 sec
Answer: D.60 sec
Explanation: Actually Arjun has to make a lead of 600 m, because when Arjun will be 600m ahead of Bhishma, they will be together again as a person when completes the total length it starts retracing he same path and thus Arjun and Bhishma can be together again.
Since , they make a difference of 10 m in 1 second. so, he will create 600m difference in 60 second.
D
Question: x is the smallest integer greater than 1000 that is not prime and that has only one factor in common with 30!. What is x?
A.1009
B.1021
C.1147
D.1273
Answer: C.1147
Explanation: Next, x and 30! have only one factor in common means that this factor must be 1 (any two integers have 1 as a common factor). Thus no other factor of 30! is a factor of x. So, the least prime of x can be 31 (30! has all primes less than 30).
x cannot be 31*31 = 961 because it's less than 1,000.
The next prime is 37: 31*37 = 1147 > 1,000.
Answer: C
Question: A, B and C enter into a partnership by investing $11000, $15000 and $23000 respectively. At the end of 8 months, B receives $1540 as his share. Find the share of A.
A.$811
B.$922
C.$1033
D.$1144
Answer: D.$1144
Explanation: The ratio of capital of A, B and C = 11000 : 15000 : 23000 = 11 : 15 : 23
A's share = (11/15)*1560 = $1144
The answer is D.
Question: A number when divided by a divisor leaves a remainder of 24.
When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor?
A.34
B.35
C.37
D.38
Answer: C.37
Explanation: Let the original number be 'a'
Let the divisor be 'd'
Let the quotient of the division of aa by dd be 'x'
Therefore, we can write the relation as a/d = x and the remainder is 24.
i.e., a=dx+24 When twice the original number is divided by d, 2a is divided by d.
We know that a=dx+24. Therefore, 2a = 2dx + 48
The problem states that (2dx+48)/d leaves a remainder of 11.
2dx2dx is perfectly divisible by d and will therefore, not leave a remainder.
The remainder of 11 was obtained by dividing 48 by d.
When 48 is divided by 37, the remainder that one will obtain is 11.
Hence, the divisor is 37.
C
Question: What is the area of a square field whose diagonal of length 30 m?
A.300 sq m
B.250 sq m
C.200 sq m
D.400 sq m
Answer: A.300 sq m
Explanation: d2/2 = (30 * 30)/2 = 300
ANSWER:A
Question: A,B,C invested the capitals in a business. If the investment of A, B, C are Rs. 40,000, Rs.50,000, Rs.10000 respectively and the profit got by B is Rs.7500, find the profit of others.
A.6000, 1500
B.5000, 2500
C.6500, 1000
D.5500, 2000
Answer: A.6000, 1500
Explanation: A==40,000
B==50,000
C==10,000
so, ration are 4:5:1
5x = 7500 ie) x=1500
A's profit=4x =6000
C's profit =x=1500
ANSWER:A
Question: The average score in an examination of 10 students of a class is 60. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark was 40 and the maximum mark was 100. It is also known that none of the students failed. If each of the top five scorers had distinct integral scores, the maximum possible score of the topper is ?
A.87
B.95
C.99
D.100
Answer: C.99
Explanation: The average score in an examination of 10 students of a class is 60 --> the total score = 10*60 = 600;
The 5 smallest scores have an average of 55 --> the total score of the 5 smallest scores = 275.
From above, the total score of the 5 largest scores = 600 - 275 = 325.
Say the 5 largest scores are a, b, c, d, and e (where a<b<c<d<e, since each of the top five scorers had distinct scores). We want to maximize e. To maximize e, we need to minimize a, b, c, and d. The least value of a, is 55 (The least score of the top 5 , a, should be equal to the highest of the bottom 5 and to minimize the highest of the bottom 5, all scores from the bottom 5 should be equal). In this case the least values of b, c, and d are 56, 57, and 58 respectively:
a + b + c + d + e = 55 + 56 +57 + 58 + e = 325;
e = 99.
Answer: C.
Question: The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is?
A.1200
B.1500
C.1700
D.1349
Answer: D.1349
Explanation: LCM = 1400
1400 - 6 = 1394
ANSWER D
Question: If a - b = 3 and a(power 2) + b(power 2) = 21, find the value of ab.
A.5
B.8
C.4
D.6
Answer: D.6
Explanation: 2ab = (a(power 2) + b(power 2) - (a - b)(power 2)
= 21 - 9 = 12
ab = 6.
Answer is D.
Question: A lady builds 9cm length, 12cm width, and 3cm height box using 3cubic cm cubes. What is the minimum number of cubes required to build the box?
A.107
B.108
C.109
D.110
Answer: B.108
Explanation: Number of cubes required = Volume of box/Volume of cube
= 9*12*3/3
=108 cubes
ANSWER:B
Question: Five years ago the average of the ages of A and B was 40 years and now the average of the ages of B and C is 47 years. What will be the age of the B ten years hence?
A.22
B.77
C.94
D.96
Answer: C.94
Explanation: Let the present ages of A, B and C be a, b and c respectively.
Given, [(a - 5) + (b - 5)] / 2 = 40 => a + b = 90 --- (1)
(b + c)/2 = 47 => b + c = 94 --- (2)
From (1) and (2), we cannot find b.
Answer: C
Question: One out of every 300 light bulbs are defected. If 2 out of every 10 defected light bulbs have a broken glass and there are 20 broken glass light bulbs in the shipment, how many light bulbs total are there in the shipment?
A.2,000
B.30000
C.10,000
D.50,000
Answer: B.30000
Explanation: 20 broken glasses indicates that 10*10= 100 defected bulbs are present.
100 defected bulbs indicates that 100*300= 30,000 light bulbs are present.
B is the answer
Question: If the sales tax reduced from 3 1/2 % to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 7800 ?
A.11
B.13
C.14
D.18
Answer: B.13
Explanation: Required difference = [3 ½ % of Rs.7800] – [3 1/3 % of Rs.7800]
= [(7/20-(10/3)]% of Rs.7800 =1/6 % of Rs.7800
= Rs. [(1/6)8(1/100)*7800] = Rs. 13.
Answer is B.
Question: If f(a)=2a+8, what is the value of (f(2a)+f(a)) ?
A.6a+16
B.8a-7
C.6a+18
D.6a+12
Answer: A.6a+16
Explanation: f(a)=2a+8
f(2a)= 4a+8
(f(2a)+f(a)) = 4a+8+2a+8 = 6a+16
Answer is A
Question: A cistern 10 m long and 6 m wide contains water up to a breadth of 1 m 35 cm. Find the total area of the wet surface.
A.100 m sqaure
B.103 m sqaure
C.152 m sqaure
D.164 m sqaure
Answer: B.103 m sqaure
Explanation: Explanation:
Area of the wet surface =
2[lb+bh+hl] - lb = 2 [bh+hl] + lb
= 2[(6*1.35+10*1.35)]+10*6 = 103 m square
Option B
Question: A boat having a length 3 m and breadth 3 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:
A.100 kg
B.120 kg
C.89 Kg
D.90 Kg
Answer: D.90 Kg
Explanation: Volume of water displaced	= (3 x 3 x 0.01) m3
= 0.09 m3.
Mass of man = Volume of water displaced x Density of water
= (0.09 x 1000) kg
= 90 kg.
Answer: D
Question: Tom and John traveled in the same direction along the equal route at their constant speed rates of 15 km per hour and 10 km per hour, respectively. After 15 minutes Tom passed John, Tom reaches a certain Gas station, how many Q minutes it takes John to reach the station?
A.5 min
B.6 min
C.7 and 1/2 min
D.8 min
Answer: C.7 and 1/2 min
Explanation: Since the question states “after 15 minutes”, we can say Tom traveled 15/4km for 15 minutes as he can travel 15km per hour. Hence, using the same logic, we can say John traveled 10/4km as he travels 10km per hour. So, John has to travel (15/4)-(10/4)km=5/4km more. Since John’s speed is 10km/hour, which means 1km/6minutes. As he has to travel 5/4km more, it is going to take him 6(5/4) minutes. Hence,Q= 6(5/4)=15/2 minutes. The correct answer is C.
Question: The diameter of the driving wheel of a bus is 120 m. How many revolution, per minute must the wheel make in order to keep a speed of 60 kmph approximately
A.245
B.257
C.262
D.265
Answer: D.265
Explanation: Explanation:
Distance to be covered in 1 min. = (60 X 1000)/(60) m = 1000 m.
Circumference of the wheel = (2 x (22/7) x 0.60) m = 3.77 m.
Number of revolutions per min. =(1000/3.77) = 265
Answer: Option D
Question: How many different positive integers exist between 10^6 and 10^7, the sum of whose digits is equal to 2?
A.5
B.6
C.7
D.8
Answer: C.7
Explanation: Total cases => 1000000=> 6 cases for 1 being present at any of the 6 zero
and last case 2000000
hence & cases
ANSWER:C
Question: A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?
A.11 hours
B.16 hours
C.12 hours
D.13 hours
Answer: C.12 hours
Explanation: A's 1 hour's work =1/4;
(B + C)'s 1 hour's work = 1/3;
(A + C)'s 1 hour's work = 1/2.
(A + B + C)'s 1 hour's work = ( 1/4 + 1/3 )	= 7/12.
B's 1 hour's work = ( 7/12 - 1/2 ) = 1/12.
Therefore B alone will take 12 hours to do the work.
CORRECT OPTION : "C"
Question: What is the average of 12, 13, 14, 51, 52, 53, 1,11.5, 1,1.20, and 11.25?
A. 21.06
B. 23
C. 26
D.23.69
Answer: A. 21.06
Explanation: Add 12, 13, 14, 51, 52, 53, 1,11.5, 1,12, and 11.25
Grouping numbers together may quicken the addition
sum = 231.75
231.75/11 =21.06
A
Question: Today is Thursday. The day after 51 days will be?
A.Monday
B.Tuesday
C.Saturday
D.Sunday
Answer: C.Saturday
Explanation: Explanation:
51 days = 7 weeks 2 days = 2 odd days
Hence if today is Thursday, After 51 days, it will be = (Thursday + 2 odd days)
= Saturday
Answer: Option C
Question: A man saves a certain portion of his income during a year and spends the remaining portion on his personal expenses. Next year his income increases by 20% but his savings increase by 100%. If his total expenditure in 2 years is double his expenditure in 1st year, What %age of his income in the first year did he save?
A.15%
B.18%
C.20%
D.25%
Answer: C.20%
Explanation: 1st year Income= I
1st year savings= S
1st year Expense= E1
2nd year Income = 1.2I
2nd year savings= 2S (100% increase)
2nd Year expense= E2
E1+ E2= 2E1
E2=E1
That means Expenses are same during both years. With increase of 20% income the savings increased by 100%.
or S= .2I
or S= 20% of Income
C is the answer
Question: If x2*square* – x – 2 > 0, which of the following is the
solution set for x?
A.x > –1
B.x > 2
C.–1 < x < 2
D.x < –1 or x > 2
Answer: D.x < –1 or x > 2
Explanation: Begin by treating the inequality x2 – x – 2 > 0 as if it were an equation. Factor to find the zeros:
x2 – x – 2 = 0
(x + 1)(x – 2) = 0
x = –1 and x = 2
The graph of this function is a parabola that crosses the x-axis at –1 and 2. This graph is
concave up because the coefficient of the x2 term (that is, a) is positive. The parabola dips
below the x-axis when –1 < x < 2, so these values do not satisfy the equation. Therefore, the
correct answer is D. (If you doubt this answer, note that when x = 0, x2 – x – 2 = –2,
which is less than 0. So 0 is not in the solution set.)
correct answer D) x < –1 or x > 2
Question: In the rectangular coordinate system, points (8, 0) and (– 8, 0) both lie on circle C. What is the maximum possible value of the radius of C ?
A.2
B.4
C.8
D.16
Answer: C.8
Explanation: The answer is C
It takes 3 distinct points to define a circle. Only 2 are given here.
The two points essentially identify a single chord of the circle C. Since no other information is provided, however, the radius of the circle can essentially be anything. All this information tell us is that the radius isgreater 8 C
Question: some 6th std students each bought a pencil paying a total of 143rs.some of the 26 fifth std students each bought a pencil and they paid a total of 165rs.how many more fifth std students than sixth std students bought a pencil
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: common factor between 165 and 143 is 11. (11*15=165, 11*13=143). so each pencil costs 11rs. and there was (13-11)=2 students more in fifth std than sith std
ANSWER:B
Question: The LCM and HCF of two numbers are 1000 and 100 respectively. Find the larger of the two numbers if their sum is 1100.
A.1000
B.10
C.567
D.57
Answer: A.1000
Explanation: There are 2 approaches in solving this.
Methode 1.
HCF * LCM = The Actual Number.
1000* 100= 100000
So the answer which we are looking for has to be a factor of 100000.
So among the options shortlist the answers by eliminating those numbers which is not divisible by 100000. and then take the highest number as the answer as the question asks abt the highest number.
answer is A
Question: If n = 2p, where p is a prime number greater than 2, how many different positive even divisors does n have, including n ?
A. Two
B. Three
C. Four
D. Six
Answer: A. Two
Explanation: If n = 2p, where p is a prime number greater than 2, how many different positive even divisors does n have, including n ?
(A) Two
(B) Three
(C) Four
(D) Six
(E) Eight
Since we cannot have two correct answers just pick a prime greater than 2, and see how many different positiveevendivisors will 2p have.
p = 3 --> 2p = 6--> 6 has 2 even divisors: 2, 6
Answer: A.
Question: How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.25
B.30
C.40
D.45
Answer: B.30
Explanation: Relative speed of the train=63-3=60kmph=60*5/18=50/3 m/sec
t=500*3/50=30sec
ANSWER:B
Question: A hostel had provisions for 250 men for 32 days. If 50 men left the hostel, how long will the food last at the same rate?
A.30
B.40
C.50
D.60
Answer: B.40
Explanation: A hostel had provisions for 250 men for 32 days
If 50 men leaves the hostel, remaining men = 250 - 50 = 200
We need to find out how long the food will last for these 200 men.
Let the required number of days = x days
More men, Less days (Indirect Proportion)
(men) 250 : 200 :: x : 32
250×32=200x
5×32=4x
x=5×8=40
ANSWER B
Question: The population of a city is 160,000. If it increases at the rate of 6% per annum, then what will be its population 2 years hence?
A.268942
B.186935
C.179776
D.167425
Answer: C.179776
Explanation: Explanation:
Population after n years = P [1 + (R/100)]2
Population after 2 years = 160000 * [1 + 6/100]2 = (160000 x 53/50 x 53/50) = 179776
ANSWER: C
Question: Consider a lady took a loan from a bank at the rate of 12% p.a. simple interest. After 3 years she had to pay Rs. 9900 interest only for the period. The principal amount borrowed by her was
A.Rs. 2000
B.Rs. 27500
C.Rs. 15000
D.Rs. 20000
Answer: B.Rs. 27500
Explanation: Explanation :
Principal = Rs. (100×9900 / 12×3)
=> Rs. 27500.
Answer : B
Question: Jupiter travels around the Sun at an approximate speed of 7.8 miles per second. This speed is how many kilometers per hour? (1 km = 0.6 miles)
A.40,500
B.42,600
C.44,700
D.46,800
Answer: D.46,800
Explanation: The speed is 7.8 miles/s. Then 7.8/0.6 = 13 km/s
13*3600 = 46,800 kph
The answer is D.
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 852 grams per kg, what is his percent?
A.22%
B.25%
C.17.37%
D.99%
Answer: C.17.37%
Explanation: 852 --- 148
100 --- ? => 17.37%
Answer: C
Question: In a question on division with zero remainder, a candidate took 12 as divisor instead of 21. The quotient obtained by him was 35. The correct quotient is:
A.20
B.30
C.32
D.34
Answer: A.20
Explanation: Number = (35 * 12) = 420
Correct quotient = 420/21 = 20
A)
Question: A certain kind of necklace is made from 9 yellow, 6 blue, and 3 silver beads. What is the maximum number of these necklaces that can be made from 63 beads of each color ?
A.7
B.6
C.5
D.4
Answer: A.7
Explanation: Atleast 9 yellow breads are needed to make a necklace, so irrespective of the combinations of blue and silver beads, the number of necklaces that can be formed will be
63/9 =7
Answer:- A
Question: The number of positive integers valued pairs (x, y) satisfying 4x -17y = 1 and x <= 1000 (x is less than or equal to 1000) is
A.59
B.57
C.55
D.58
Answer: A.59
Explanation: We are asked to find integer solutions for x,y.
There is no need to apply Euclidian algorithm here, we can get particular solutions simply by plugging in some values.
As y reaches 3 we get:
y’ = 3 and x’ = 13. We need only to solve for x.
General solution for x will be:
x = x’ + bn = 13 + 17n
Hence lower limit for n is n ≥ 0.
Now we’ll find upper limit using given restriction x ≤ 1000. Plugging in general solution we’ll get:
13 + 17n ≤ 1000
17n ≤ 987
n ≤ 58
And our list of possible values of n has following representation:
0, 1,2, 3, ….. , 58
Total number of elements is 59.
ANSWER:A
Question: A man's speed with the current is 20 kmph and speed of the current is 3 kmph. The Man's speed against the current will be
A.11 kmph
B.12 kmph
C.14 kmph
D.17 kmph
Answer: C.14 kmph
Explanation: Explanation:
If you solved this question yourself, then trust me you have a all very clear with the basics of this chapter.
If not then lets solve this together.
Speed with current is 20,
speed of the man + It is speed of the current
Speed in still water = 20 - 3 = 17
Now speed against the current will be
speed of the man - speed of the current
= 17 - 3 = 14 kmph
Option C
Question: Fifteen runners from four different countries are competing in a tournament. Each country holds a qualifying heat to determine who its fastest runner is. These four runners then run a final race for first, second, and third place. If no country has more than one more runner than any other country, how many arrangements of prize winners are there?
A.24
B.384
C.455
D.1248
Answer: D.1248
Explanation: 1. We have runners by countries: 4 4 4 3
2. We choose 3 countries for all 3 "wining" places. 4 possibility: 4 4 4 and 3 times 4 4 3
3. Now we can choose any person from each country and take into account different positions (3!)
So, we get: (4*4*4)*3! + 3*(4*4*3)*3! = 3!*4*4*(4+3*3) = 1248 (D)
Question: A train of length 250 metres takes 45 seconds to cross a tunnel of length 350metres. What is the speed of the train in km/hr?
A.10 km/hr.
B.240 km/hr.
C.30 km/hr.
D.24 km/hr.
Answer: D.24 km/hr.
Explanation: Sol.
Speed = [250 + 350/ 45] m/sec = [600 / 45 * 18/5] km/hr = 24 km/hr.
Answer D
Question: 10 books are placed at random in a shelf. The probability that a pair of books will always be together is
A.1/6
B.1/9
C.1/5
D.1/6
Answer: C.1/5
Explanation: 10 books can be rearranged in 10! ways consider the two books taken as a pair then number of favourable ways of getting these two books together is 9! 2!
Required probability = 1/5
Answer: C
Question: Two trains 140 m and 180 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
A.11.52 sec
B.10.1 sec
C.10.6 sec
D.10.8 sec
Answer: A.11.52 sec
Explanation: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other
= 140 + 180 = 320 m.
Required time = 320 * 9/250
= 11.52 sec.
Answer:A
Question: One woman and one man can build a wall together in half an hour, but the woman would need the help of two girls in order to complete the same job in the same amount of time. If one man and one girl worked together, it would take them two hours to build the wall. Assuming that rates for men, women and girls remain constant, how many hours would it take one woman, one man, and one girl, working together, to build the wall?
A.5/7
B.1
C.10/7
D.6/13
Answer: D.6/13
Explanation: Solution:Let work done by man, women and girl per hour be m,w,g respectively.
Then, m+w = 2/1-->(1) , w + 2g = 2/1-->(2) and m + g =1/2-->(3).
No. of hours it would take forone woman, one man, and one girl, working together, to build the wall,n = 1/m+w+g
From (1) and (2), m=2g and from (3) g=1/6,m=1/3 and w=5/3.
So, n = 1/(13/6) = 6/13
Option, D
Question: Add: + 47 and -27
A.-30
B.+30
C.0
D.27
Answer: B.+30
Explanation: The absolute values of +47 and -27 are 47 and 27 respectively; and their difference = 47 – 27 = 30.
(+47) + (-27) = +30
ANSWER :B
Question: If the population of a certain country increases at the rate of one person every 25 seconds, by how many persons does the population increase in 1 hour?
A.100
B.120
C.144
D.180
Answer: C.144
Explanation: Answer = 2.4 * 60 = 144
Answer is C