RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A vendor bought bananas at 6 for Rs.10 and sold them at Rs.4 for Rs.6 .Find his gain or loss percent .
A.13%
B.10%
C.47%
D.36%
Answer: B.10%
Explanation: Suppose , number of bananas bought = LCM of 6 and 4=12
CP=Rs.[(10/6)*12]=Rs.20 ; SP= Rs[(6/4)*12]=Rs.18
Loss%=[(2/20)*100]%=10%
Ans:B
Question: Which of the following has 35^70 as a factor?
A.70^70
B.30^40
C.40^70
D.60^60
Answer: A.70^70
Explanation: Here 35^70 = 5^70 * 7^70 Only Option A has both .
Smash A
Question: Three taps A,B and C can fill a tank in 10,20 and 30. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in?
A.6hour 20min
B.7hour 10min
C.7hour 30min
D.8hour 15min
Answer: C.7hour 30min
Explanation: A+B 1 hour work = 1/10 + 1/20 = 3/20
A+C 1 hour work = 1/12 + 1/30 = 7/60
Part filled in 2 hours = 3/20 + 7/60 = 4/15
Part filled in 6 hours = 3* 4/15 = 4/5
Remaining part = 1 - 4/5 = 1/5
Now it is the turn of A and B and 1/5 part is filled by A and B in 1hour 30min
Total time taken to fill the tank = 6+1.5 = 7hours 30min
Answer is C
Question: At what time between 5.30 and 6 will the hands of a clock beat right angles?
A.43 5⁄11 min. past 5
B.43 7⁄11 min. past 5
C.40 min. past 5
D.45 min. past 5
Answer: B.43 7⁄11 min. past 5
Explanation: At 5 o’clock, the hands are 25 min. spaces apart.
To be at right angles and that too between 5.30 and 6, the minute hand has to gain (25 + 15) = 40 min. spaces
55 min.spaces are gained in 60 min.
40 min. spaces are gained in (60⁄55 × 40) min = 43 7⁄11 min.
∴ Required time = 43 7⁄11 min. past 5
Answer B
Question: A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
A.11 liters
B.12 liters
C.10 liters
D.15 liters
Answer: C.10 liters
Explanation: Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters.
Answer:C
Question: Simplify: 45205 x 95
A.4520500
B.4294470
C.4294475
D.4068450
Answer: C.4294475
Explanation: 45205 x 95 = 45205 x (100 - 5)
= 4520500 - 226025
= 4294475
Answer is C
Question: The annual birth and death rate in a country per 1000 are 39.4 and 19.4 respectively . the number of years K in which the population would be doubled assuming there is no emigration or immigration is
A.20
B.K=25
C.30
D.K=35
Answer: D.K=35
Explanation: Suppose the population of the country in current year is 1000.
So annual increase is 1000 + 39.4 - 19.4=1020
Hence every year there is an increase of 2%.
2000=1000(1+ (2/100))^n
n=35 Answer is D.
Question: A began business with Rs.45000 and was joined afterwards by B with Rs.36000. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
A.1.5
B.6
C.7.5
D.8.5
Answer: C.7.5
Explanation: 45*12 : 36*x = 2: 1
x = 7.5
12 -7.5 = 4.5
Answer: C
Question: If 144/0.144 = 14.4/x, then the value of x is:
A.0.0414
B.0.144
C.0.0144
D.0.414
Answer: C.0.0144
Explanation: =144/0.144 = 14.4/x
=144 x 1000/144
=14.4/x
=x = 14.4/1000
= 0.0144
Answer is C.
Question: A man can row 12 Kmph in stil water and the river is running at 4 Kmph. If the man takes 2 hour to row to a place and back how far is the place?
A.3 Km
B.2.66 Km
C.10.66 Km
D.9 Km
Answer: C.10.66 Km
Explanation: Explanation:
Man's rate down stream = 12 + 4 = 16 kmph
Man's rate upstream = 12 - 4 = 8 kmph
Let the required distence be x Km
then, x/16 +x/8 = 2
3x = 32
x = 10.66 Km.
Answer: Option C
Question: x is what percent of y percent of z, in terms of x, y and z? k be the value expressed in terms of x,y and z.
A.xyz
B.1/xyz
C.100xyz
D.10^4*x/yz
Answer: D.10^4*x/yz
Explanation: Algebraically, y% of z is just (y/100)*z, or yz/100. So we want to answer the question: x is what percent of yz/100? Say x is equal to k% of yz/100; then we have:
x = (k/100)*(yz/100)
10,000x/yz = k
D
Question: The product Q of the first 10 prime numbers is closest to which of the following?
A.6.5 x 10^7
B.6.5 x 10^8
C.6.5 x 10^9
D.6.5 x 10^10
Answer: C.6.5 x 10^9
Explanation: The first 10 primes are: 2, 3, 5, 7, 11, 13, 17, 19, 23, and 29.
So, we need to find approximate value Q of 2*3*5*7*11*13*17*19*23*29.
# of different approximations are possible. For example:
2*5=10
3*17=~50 (actually more than 50);
7*13=~100 (actually less than 100);
11*19=~200 (actually more than 200)
23*29=667
2*3*5*7*11*13*17*19=~10*50*100*200*667=10^7*667=6.67*10^9.
Answer: C.
Question: A will was written such that an estate would be divided among three guys with the remainder donated to charity. One stipulation in the will is that no one from the guys can receive an amount within 30% of another's amount. If one of the guys received $20,000, what is the smallest possible range between the highest and lowest amounts (rounded to the nearest dollar) among the three guys?
A.$4096
B.$5904
C.$7892
D.$10052
Answer: D.$10052
Explanation: 1st - 20,000.
2nd - 0.7*20,000 = 14,000
3rd - 0.7*14,000 = 9,800
Range = 20,000 - 9800 = 10,200.
Answer: D.
Question: A company wants to spend equal amounts of money for the purchase of two types of computer printers costing $400 and $350 per unit, respectively. What is the fewest number of computer printers that the company can purchase?
A.11
B.13
C.15
D.17
Answer: C.15
Explanation: The smallest amount that the company can spend is the LCM of 400 and 350, which is 2800 for each, which is total 5600.
The number of 1st type of computers which costing $400 = 2800/400 = 7.
The number of 2nd type of computers which costing $350 = 2800/350 = 8.
Total = 7+8 = 15
Answer is C.
Question: A qualified worker digs a well in 5 hours. He invites 3 apprentices, both capable of working 3/4 as fast and 2 trainees both working 1/5 as fast as he. If the five-person team digs the same well, how much time does the team need to finish the job?
A.1:24
B.1:34
C.1:44
D.1:41
Answer: D.1:41
Explanation: and answer is correct as you have calculated : 100/56 hrs that is 1.62 hrs - 1 hr and 41 minutes, so 1:41, hence, D.
Question: A book is bought for $600 and sold for $624. What is the profit in percentage?
A.2
B.4
C.6
D.8
Answer: B.4
Explanation: 624/600 = 1.04
The answer is B.
Question: 10 men, working 5 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days ?
A.4 hours a day
B.5 hours a day
C.6 hours a day
D.7 hours a day
Answer: B.5 hours a day
Explanation: Explanation:
More Men, Less Hours {Indirect Proportion}
Less Days, More Hours {Indirect Proportion}
[men 15 10
days 12 18] ::5:x
=>xâˆ—15âˆ—12=10âˆ—18âˆ—6
=>x=10âˆ—18âˆ—5/ 15âˆ—12
=>x=5
Option B
Question: What is the sum of odd integers from 25 to 85
, inclusive?
A.1,705
B.1,500
C.1,240
D.1,120
Answer: A.1,705
Explanation: Number of odd integers = (85-25)/2 + 1
= 60/2 + 1
= 31
Sum of odd integers = (25+85)/2 * 31
= 1705
Answer A
Question: Peter invested an amount of Rs. 12,000 at the rate of 10% p.a simple interest and another amount at the rate of 20% p.a. simple interest. The total interest earned at the end of one year on the total amount invested became 14% p.a. Find the total amount invested?
A.20,000
B.72888
C.27899
D.27891
Answer: A.20,000
Explanation: Let the second amount be Rs. x. Then,
(12000 * 10 * 1)/100 + (x * 20 * 1)/100 = [(12000 + x) * 14 * 1] / 100
120000 + 20x = 16800 + 14x
x = 8000
Total investment = 12000 + 8000 = Rs. 20,000.
Answer:A
Question: The manager at a health foods store mixes a unique superfruit juice cocktail that costs $1399.45 per litre to make. The cocktail includes mixed fruit juice and açai berry juice, which cost $262.85 per litre and $3104.35 per litre, respectively. The manager has already opened 35 litres of the mixed fruit juice. How many litres of the açai berry juice does he need to add?
A.17 litres
B.23.3 litres
C.11 litres
D.07 litres
Answer: B.23.3 litres
Explanation: 262.85(35)+3,104.35x = 1,399.45(35 + x)
Solve the equation.
262.85(35)+3,104.35x = 1,399.45(35 + x)
9,199.75 + 3,104.35x = 48980.75 + 1,399.45x
9,199.75 + 1,704.9x = 48980.75
1,704.9x = 39,781
x ≈ 23.3
Answer is B.
Question: Rectangle ABCD is constructed in the coordinate plane parallel to the x- and y-axes. If the x- and y-coordinates of each of the points are integers which satisfy 4 ≤ x ≤ 11 and -5 ≤ y ≤ 5, how many possible ways are there to construct rectangle ABCD?
A.396
B.1260
C.1540
D.7920
Answer: C.1540
Explanation: As the rectangle is parallel to coordinate axes, the coordinates of the points of the rectangle would be
(X1, Y1), (X2, Y1), (X2, Y2), (X1,Y2)
given that X1, X2 lie between 4 and 11..ie., 8 possible numbers
Possible combinations for X1,X2 would be 8C2 = 28
Similarly, Possible combinations for Y1, Y2 would be 11C2 = 55
Possible ways of constructing rectangle is by selecting any of the combination of X1,X2 and Y1,Y2
= 28 * 55 = 1540
Ans. C
Question: The ratio of two quantities is 2 to 3. If each of the quantities is increased by 4, what is the ratio of these two new quantities?
A.5/5
B.It cannot be determined from the information given.
C.11/5
D.12/5
Answer: B.It cannot be determined from the information given.
Explanation: let the actual ratio be 2k/3k, increase numerator and denominator by 4=> 2k+4/3k+4
Until the value of k is unknown we can not determine the actual ratio.
OR
let the actual be 3/4. After increasing 4 => 7/8
let the actual be 6/8. After increasing 4 => 10/12
Therefore without actual quantities we cannot determine the actual ratio.
Answer : B
Question: There are 11 teams in a certain league and each team plays each of the other teams exactly once. What is the total number of games played?
A.35
B.45
C.55
D.65
Answer: C.55
Explanation: 11C2 = 55
The answer is C.
Question: In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 10 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?
A. 250
B. 625
C. 1,250
D. 2,500
Answer: A. 250
Explanation: total fish = x
percentage of second catch = (10/50)*100 = 20%
so, x * 20% = 50
x = 250 ans A.
Question: Find the greatest number of five digits which is exactly divisible by 12, 15 and 18?
A.A)13050
B.B)12960
C.C)10025
D.D)11080
Answer: B.B)12960
Explanation: The largest five digit numbers are
13050,12960,12080
13050 is not divisible by 12
12960 is divisible by 18, 12 and 15
ANSWER:B
Question: In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:
A.60 m
B.20m
C.43m
D.20m
Answer: D.20m
Explanation: To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.
While A covers 3 m, B covers 4 m.
While A covers 360 m, B covers 4	x 360	m	= 480 m.
3
Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
A wins by 20 m.
Answer:	D
Question: Average of first six multiples of 4 is
A.9
B.11
C.14
D.15
Answer: C.14
Explanation: Explanation:
Average=4(1+2+3+4+5+6) / 6=64 / 6=14
Option C
Question: A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit.
A.Rs.4500
B.Rs.5200
C.Rs.1800
D.Rs.3000
Answer: D.Rs.3000
Explanation: Explanation:
A:B:C = 5:6:4
Let the total profit = 100 - 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 - 160/3 = 140/3
A-(B+C) = 160/3 - 140/3 = 20/3
20/3 ---- 200
100 ---- ? => 3000
ANSWER IS D
Question: The average of first 80 non-zero positive numbers is:
A.22.25
B.31.25
C.35
D.40.5
Answer: D.40.5
Explanation: Explanation :
Sum of first n natural numbers = n (n + 1)/2
So, average of first n natural numbers =
n (n + 1)/2n = (n + 1)/2
Required average = (80 + 1)/2 = 81/2 = 40.5.
Answer : D
Question: The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is
A.152600m2
B.153500m2
C.153600m2
D.153800m2
Answer: C.153600m2
Explanation: Explanation:
Question seems to be typical, but trust me it is too easy to solve, before solving this, lets analyse how we can solve this.
We are having speed and time so we can calculate the distance or perimeter in this question.
Then by applying the formula of perimeter of rectangle we can get value of length and breadth, So finally can get the area. Lets solve it:
Perimeter = Distance travelled in 8 minutes,
=> Perimeter = 12000/60 * 8 = 1600 meter. [because Distance = Speed * Time]
As per question length is 3x and width is 2x
We know perimeter of rectangle is 2(L+B)
So, 2(3x+2x) = 1600
=> x = 160
So Length = 160*3 = 480 meter
and Width = 160*2 = 320 meter
Finally, Area = length * breadth
= 480 * 320 = 153600 Answer: Option C
Question: Four bells begin to ring together and they ring after an interval of 6,8,9 and 12 second respectively. How many times will they ring together in one hour, including the one at the start?
A.50
B.56
C.62
D.51
Answer: D.51
Explanation: LCM is 72. So they ring together in every 72 sec.
there are 3600 sec in 1 hr. so, 3600/72=50.
and 1 ring at the beginning. makes it 51.
ANSWER:D
Question: Find a number such that when 15 is subtracted from 7 times the number, the
Result is 10 more than twice the number.
A.1
B.4
C.5
D.0
Answer: C.5
Explanation: Let the number be x. Then, 7x - 15 = 2x + 10 => 5x = 25 =>x = 5.
Hence, the required number is 5.
Answer is C.
Question: Solve below question 3x - 5 = -20
A.-8
B.-9
C.-5
D.-4
Answer: C.-5
Explanation: 1. Subtract 1 from both sides: 3x - 5 + 5 = -20 + 5 2. Simplify both sides: 3x = -15 3. Divide both sides by 3: 4. Simplify both sides: x = -5 C
Question: A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 15 per metre of cloth. What is the cost price of one metre of cloth?
A.78
B.72
C.90
D.27
Answer: C.90
Explanation: SP of m of cloth
= 8925/85 = Rs. 105
CP of 1m of cloth
= SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 15
= Rs. 90.
Answer: C
Question: Lorna invests $4000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate?
A.$160
B.$1,600
C.$800
D.$4,400
Answer: C.$800
Explanation: We have that 'x' invested at 6%
We also have that 4000-x' invested at 11%
Now then 580/4000 is approx 10%
Therefore, -4x+4000-x=0
5x=4000
x=800 approximately. Probably higher
Only C matches
Question: There are 2 more women than there are men on a local co-ed softball team. If there are a total of 16 players on the team, what is the ratio of men to women?
A.10/16
B.6/16
C.4/16
D.7/9
Answer: D.7/9
Explanation: w = m+2
w+m = 16
m+2+m = 16
2m = 14
m = 7
w = 9
ratio:7:9
Ans: D
Question: What percent of 200 is 55?
A.0.25%
B.4%
C.25%
D.27.5%
Answer: D.27.5%
Explanation: 200*x /100 = 55
x = 27.5
Ans: D
Question: A number a is squared and then multiplied by negative 4. The result of this operation is equal to 4times the sum of FOURTH times a and 1. What is one possible value of a ?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: -4*a^2=4(4a+1)
a= -1 or -1
a=-1=B
ANSWER:A
Question: 8 men can do a piece of work in 12 days. 4 women can do it in 48 days and 10 children can do it in 24 days. In how many days can 10 men, 4 women and 10 children together complete the piece of work?
A.5 days
B.15 days
C.28 days
D.6 days
Answer: D.6 days
Explanation: Explanation:
1 man’s 1 day’s work = 1/8 × 12 = 1/96
10 men’s 1 day’s work = 1 × 10/96 = 5/48
1 woman’s 1 day’s work = 1/192
4 women’s 1 day’s work = 1/192 × 4 = 1/48
1 child’s 1 day’s work = 1/240
10 children’s 1 day’s work = 1/24
Therefore, (10 men + 4 women + 10 children)’s 1 day’s work = 5/48 + 1/48 + 1/24
= 8/48 =1/6
The required No. of days = 6 days
Answer: Option D
Question: The rate fo simple interest in two banks is in the ratio of 4 : 5 . Amith wants to deposit his total saving in these two banks in such a way that he should receive equal half yearly interest from both. He should deposits the saving in the banks in the ratio of:
A.2 : 5
B.5 : 4
C.5 : 3
D.4 : 5
Answer: B.5 : 4
Explanation: Let the savings be X and Y and the rates of simple interest be 4x and 5x respectively.
Then X +4x * 1/2 *1/100 = Y + 5x * 1/2 *1/100
or X/Y = 5/4
i.e. X : Y = 5 : 4
ANSWER:B
Question: The retail price of a washing machine is Rs.1265. If the manufacturer gains 10%, the wholesale dealer gains 15% and the retailer gains 25%, then the cost of the product is
A.Rs 800
B.Rs 900
C.Rs 700
D.Rs 600
Answer: A.Rs 800
Explanation: Suppose the cost = Rs X
Therefore, S.P. of the manufacturer = X + 10% of X = 11X/10
S.P. of the wholesale dealer = 11X/10 + 15% of 11X/10 = 11X/10 + 33X/200 = (253/200) X
S.P. of the retailer = 253/200 X + 25% of 253/200X = 253/200 X + 253/800 X = (1265/800) X
Given (1265/800) X = 1265 => X = Rs. 800
ANSWER:A
Question: Find the largest number which divides 62, 132 and 237 to leave the same remainder in each case.
A.35
B.25
C.15
D.45
Answer: A.35
Explanation: Required number = H.C.F. of (132 - 62), (237 - 132) and (237 - 62)
= H.C.F. of 70, 105 and 175 = 35.
Answer is A.
Question: There are 200 questions in a 3 hr examination. Among these questions there are 50 mathematics problems. It is suggested that twice as much time be spent on each maths problem as for each other question. How many minutes should be spent on mathematics problems
A.36
B.60
C.45
D.72
Answer: D.72
Explanation: Let x = minutes spent on a non-math problem
then 2x = minutes spent on a math problem
x(200-50) + 2x(50) = 180
x(150) + 2x(50) = 180
150x + 100x = 180
250x = 180
x = 0.72 minutes
Time to spend on math problems:
2x(50)=100x = 100(0.72) = 72 minutes ANSWER :D
Question: If the tens digit x and the units digit y of a positive integer n are reversed, the resulting integer is 9 less than n. What is y in terms of x ?
A. 20 - x
B. 9 - x
C. x + 9
D. x - 1
Answer: D. x - 1
Explanation: Original Digits=xy i.e. Number=10x+y
After reversing the digits:
Digits=yx i.e. Number=10y+x
10y+x is 9 less than 10x+y
10x+y-9=10y+x
10x-x-9=10y-y
9x-9=9y
x+1=y
OR
y=x-1
Ans:D
Question: The no. of gift pack bought by Dexter is 1 more than the price, in rupees, of each gift pack. The amount of Rs.380 which Dexter had, fell short of the required amount. What is theamount by which he might have fallen short.
A.30
B.40
C.45
D.48
Answer: B.40
Explanation: Let the price of gift pack be 'aa'
Then number of packs bought =a+1=a+1
Hence total cost is a(a+1)a(a+1)
It is given that 380<a(a+1)380<a(a+1)
If a=19a=19, the total cost =19×20=380=19×20=380
Dexter would not have fallen short, If:
a=20a=20, a(a+1)=420a(a+1)=420
So he would have fallen short by Rs 40.
This is the minimum amount by which he may have fallen short.
B)
Question: A train of 30 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
A.6
B.3.3
C.4
D.9
Answer: B.3.3
Explanation: D = 30 * 60 + 1500 = 3300 m
T = 3300/60 * 18/5 = 198 sec = 3.3 mins
Answer:B
Question: A person spent 1/5 of his salary last year on household and 1/4 of the remainder on clothes. What fraction of last year’s salary did the person have left after his household and clothes expenditures?
A.2/3
B.3/5
C.2/6
D.5/4
Answer: B.3/5
Explanation: The person spent 1/5 of his salary on household, so remaining is 4/5
1/4 of the remaining is spent is spent on clothes, 1/4*4/5 is 2/10
To make the denominator common, we use 10, so 1/5=2/10
Total amount spent=2/10+2/10=4/10 is the total amount spent on household and clothes
Remaining salary is 6/10 of the total salary reduced to 3/5
Answer is B
Question: I came across this problem in the GMATprep software and got it totally wrong!
A company consists of 6 senior and 4 junior staff officers. If a committee is created with 3 senior and 2 junior staff officers, how many possible committees are there?
A.12
B.44
C.56
D.120
Answer: D.120
Explanation: 6C3*4C2
=120=D
Question: In what ratio must rice at Rs 9.30 per Kg be mixed with rice at Rs 10.80 per Kg so that the mixture be worth Rs 10 per Kg?
A.5:7
B.8:7
C.7:3
D.3:8
Answer: B.8:7
Explanation: Cost of 1 kg of 1st kind=930 P
Cost of 1 kg of 2nd kind=1080 P
Mean Price=1000 P
Cost of 1 kg of 1st kind - Mean Price=1000-930= 70
Cost of 1 kg of 2nd kind- Mean Price=1080-1000=80
Required ratio = 80 : 70 = 8 : 7
Answer:B
Question: The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is
A.48
B.22
C.56
D.27
Answer: A.48
Explanation: Explanation:
Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.
Answer: Option A
Question: A dealer sells his goods 10% less at cost price uses 850gm weight for 1kg his gain or loss percentage is
A.21% Gain
B.21% Loss
C.17 11/17% Gain
D.17 11/17% Loss
Answer: C.17 11/17% Gain
Explanation: Explanation:
Cost price ---> 850
Selling price --->1000 - 100 = 900
= ( 900 ~ 850 )/850 * 100 = 150/850 * 100 = 17 11/17% Gain
Answer: Option C
Question: Find the circumference of radius 7 cm.
A.44
B.55
C.66
D.77
Answer: A.44
Explanation: Circumference of circle = 2πr
= 2 × 22/7 × 7
= 44 cm
ANSWER : A
Question: If a boat goes 7 km upstream in 42 minutes and the speed of the stream is 3 kmph, then the speed of the boat in still water is
A.12 kmph
B.13 kmph
C.14 kmph
D.15 kmph
Answer: B.13 kmph
Explanation: Explanation:
Rate upstream = (7/42)*60 kmh = 10 kmph.
Speed of stream = 3 kmph.
Let speed in sttil water is x km/hr
Then, speed upstream = (x —3) km/hr.
x-3 = 10 or x = 13 kmph
Option B
Question: Of the science books in a certain supply room, 50 are on botany, 60 are on zoology, 90 are on physics. 40 are on geology, and 110 are on chemistry. If science books are removed randomly from the supply room, how many must be removed to ensure that 80 of the books removed are on the same science?
A.81
B.159
C.309
D.285
Answer: C.309
Explanation: First, you can take all 50 Botany books, all 60 zoology books and all 40 geology books because you're sure to never pick 80 of them.
There are still 90 on physics and 110 on chemistry
The worst case could be that we pick 79 physics and 79 chemistry. So that the next book picked will necessary complete 80 books picked, either in physics or chemistry.
Minimum number of books picked to reach 80 in the same science should be : 50 + 60 + 40 + 79 +79 + 1 = 309
C
Question: Find the average of all the numbers between 6 and 34 which are divisible by 5.
A.18
B.20
C.24
D.30
Answer: B.20
Explanation: Solution
Average	= (10+15+20+25+30/5)
= 100 / 5
= 20.
Answer B
Question: How many 5 digit no. can b formed with digits 1, 2, 3,4,5,6 which r divisible by 4 and digits not repeated?
A.189
B.190
C.191
D.192
Answer: D.192
Explanation: for a no. to be divisible by 4, last two digit should be divisible by 4
last tw0 digit can be 12,16,24,32,36,52,56,64 (8 possibilities)
remaining 3 places can be filled in 4*3*2 ways for each
total 5 digit no. formed = 8*4*3*2 = 192
ANSWER:D
Question: In a school seats for Maths, Physics and Biology in a school are in the ratio 1:2:3. There is a proposal to increase these seats by 10%,20% and 30%. What will be the ratio of increased seats?
A.1:4:9
B.16:34:47
C.11:24:39
D.15:42:77
Answer: C.11:24:39
Explanation: Let the number of seats of M,P,B be x,2x,3x
Number of increased seats are 110% of x , 120% of 2x , 130% of 3x
x*110/100 , 2x*120/100 and 3x*130/100
i.e. 11x/10, 12x/5 and 39x/10
Required ratio = 11x:24x : 39x = 11:24:39
Answer is C
Question: In an election between the two candidates ,The candidates who gets 60% of votes polled is wined by 280 votes majority. What is the total number of votes polled?
A.1400
B.1500
C.1600
D.1700
Answer: A.1400
Explanation: Note : majority (20 %) = difference in votes polled to win (60 %) & defeated candidates (40 %)
20 % = 60 % - 40 %
20% -----> 280 (20×14 = 280 )
100% -----> 1400 (100×14 = 1400)
A