RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: P, Q and R have Rs.8000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R?
A.Rs.3200
B.Rs.3600
C.Rs.2400
D.Rs.4000
Answer: A.Rs.3200
Explanation: Let the amount with R be Rs.r
r = 2/3 (total amount with P and Q)
r = 2/3(8000 - r) => 3r = 16000 - 2r
=> 5r = 16000 => r = 3200.
ANSWER:A
Question: Which of the following numbers is prime?
A.2^16+1
B.2^31+3^31
C.4^66+7^66
D.5^82−2^82
Answer: A.2^16+1
Explanation: Let's check which of the options is NOT a prime:
A. 2^16 + 1 --> the units digit of 2 in positive integer power repeats in blocks of four {2, 4, 8, 6}. Hence, the units digit of 2^16 is 6 and the units digit of 2^16 + 1 is 7 --> 2^16 + 1 CAN be a prime.
B. 2^31 + 3^31 --> the units digit of 2^31 is 8 and the units digit of 3^31 is 7 (the units digit of 3 in positive integer power repeats in blocks of four {3, 9, 7, 1}). Hence, the units digit of 2^31 + 3^31 is 5 (8+7). Thus 2^31 + 3^31 is divisible by 5. Not a prime.
C. 4^66 + 7^66 --> the units digit of 4^66 is 6 (the units digit of 4 in positive integer power repeats in blocks of two {4, 6}) and the units digit of 7^66 is 9 (the units digit of 7 in positive integer power repeats in blocks of four {7, 9, 3, 1}). Hence, the units digit of 4^66 + 7^66 is 5 (6+9). Thus 4^66 + 7^66 is divisible by 5. Not a prime.
D. 5^82 - 2^82 --> we can factor this as (5^41 - 2^41)(5^41 + 2^41). Not a prime.
E. 5^2881+ 7^2881 --> 5^2881 + 7^2881 = odd + odd = even. Not a prime.
Only option A can be prime.
Answer: A.
Question: In how many different ways can the letters of the word BOOKLET be arranged such that B and T always come together?
A.360
B.720
C.480
D.5040
Answer: B.720
Explanation: Treat B and T as a single letter. Then the remaining letters (5 + 1 = 6) can be arranged in 6! ways. Since, O is repeated twice, we have to divide by 2 and the B and T letters can be arranged in 2! ways.
Total no. of ways = 6!×2!/2=720
Answer B
Question: In an examination, 34% of total students failed in Hindi, 44% failed in English and 22% in both. The percentage of these who passed in both the subjects is :
A.23
B.37
C.28
D.44
Answer: D.44
Explanation: Explanation:
Formula n(aâˆªb) = n(a) + n(b) âˆ’ n(aâˆ©b)
Fail in Hindi or English = 34 + 44 â€“ 22 = 56
Therefore students who passed = 100 â€“ 56 = 44.
Answer: D
Question: The radius of a cylinder is 10 m, height 12 m. The volume of the cylinder is:
A.2200
B.5500
C.3300
D.3771.4
Answer: D.3771.4
Explanation: Cylinder volume = Ï€r(power2)h
= 22/7 Ã— 10 Ã— 10 Ã— 12
= 3771.4 m(power3)
Answer is D.
Question: A boat has a speed of 14kmph in standing water. The stream has a speed of 1.2kmph. What time does the boat take to go to a distance of 4864 km and come back? (hours)
A.700
B.378
C.2696
D.1207
Answer: A.700
Explanation: Explanation:
A boat travels at the speed of 14 km/hr in still water.
=> Speed of stream = 1.2 kmph
=> Speed of boat downstream becomes 14 + 1.2 = 15.2 kmph
=> Speed of boat upstream becomes 14 - 1.2 = 12.8 kmph
Total time taken in the journey = Journey downstream + Journey upstream
Therefore, 4864(1/12.8 + 1/15.2) = 700 hours
ANSWER: A
Question: If n is a prime number greater than 7, what is the remainder when n^2 is divided by 12 ?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: There are several algebraic ways to solve this question, but the easiest way is as follows:since we cannot have two correct answers just pick a prime greater than 7, square it and see what would be the remainder upon division of it by 12.
n=11 --> n^2=121 --> remainder upon division 121 by 12 is 1.
Answer: B.
Question: 700 + 6 × 4 = ?
A.820
B.202
C.420
D.724
Answer: D.724
Explanation: 700 + 6 × 4 = ?
or, ? = 700 + 24 = 724
Answer D
Question: A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old id the mother at present?
A.32 years
B.36 years
C.40 years
D.48 years
Answer: C.40 years
Explanation: Let the mother's present age be x years. Then, the person's present age = 2/5 x years.
(2/5 x + 8) = 1/2 (x + 8)
2(2x + 40) = 5(x + 8) => x = 40
ANSWER:C
Question: 5 letters have to be put in 5 different envelopes numbered 1 through 5 such that each of the letters go into only 1 envelope.The letter is said to be put in correct position if for example letter 1 goes into envelope 1.Now what is the probability that all letters be put into wrong envelopes?
A.1/3
B.2/3
C.11/120
D.11/30
Answer: D.11/30
Explanation: This Q is based on derangement, a permutation in which all elements are in the wrong position.
Number of derangements = n!(12!−13!+14!+...+((−1)n)n!)n!(12!−13!+14!+...+((−1)n)n!).. Of Course it can be derived but thats not required..
Since there are 5 letters and 5 envelopes:-
Derangements=5!(12!−13!+14!−15!)Derangements=5!(12!−13!+14!−15!)
=> 120(1/2−1/6+1/24−1/120)=60−20+5−1=44.120(1/2−1/6+1/24−1/120)=60−20+5−1=44.
Total possible ways = 5! = 120.
therefore required prob, P=44/120=11/30.
ans D
Question: A and B walk around a circular track. They start at 9 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 11:00 a.m.?
A.8
B.7
C.6
D.15
Answer: D.15
Explanation: Sol.
Relative speed = (2 + 3) = 5 rounds per hour.
So, they cross each other 5 times in an hour.
Hence, they cross each other 15 times before 11:00 a.m.
Answer D
Question: In track last week, the boys ran 20 laps. The girls ran 10 more
laps. Each lap is a 1/10th of a mile. How many miles did the girls run?
A.1 mile
B.3 miles
C.5 miles
D.7 miles
Answer: B.3 miles
Explanation: The girls ran 20 + 10 = 30 laps. 30 x 1/10 = 30/10, which reduces to 3.
The girls ran 3 miles
correct answer B
Question: Which of the following is a prime number
A.9
B.2
C.4
D.8
Answer: B.2
Explanation: Explanation:
A prime number is a natural number greater than 1 which has no positive divisors other than 1 or itself.
So from above options 2 is that number
Option B
Question: In covering a distance of 30 km, Amla takes 2 hours more than Peter. If Amla doubles his speed, then he would take 1 hour less than Peter. Amla’s speed is :
A.7 kmph
B.6.5 kmph
C.5.5 kmph
D.5 kmph
Answer: D.5 kmph
Explanation: Sol.
Let Peter’s speed be x km/hr.
Then, 30/x - 30/2x = 3
⇔ 6x = 30
⇔ x = 5 km/hr
Answer D
Question: If n=4p where p is a prime number greater than 2, how many different positive even divisors does n have, including n?
A.two
B.three
C.four
D.six
Answer: C.four
Explanation: We're told that N = 4P and that P is a prime number greater than 2. Let's TEST P = 3; so N = 12
The question now asks how many DIFFERENT positive EVEN divisors does 12 have, including 12?
12:
1,12
2,6
3,4
How many of these divisors are EVEN? 2, 4, 6, 12 …..4 even divisors.
ANSWER:C
Question: When n is divided by 11, the remainder is 6. When n is divided by 19, the quotient is equal to Z, and the remainder is equal to 6. Z must be divisible by which of the following numbers?
A.11
B.12
C.13
D.14
Answer: A.11
Explanation: N = 11 q + 6
N = 19 z + 6
Equating
11 Q + 6 = 19z+6
19z=11q
19z/11 = q
since q is an integer Z must be divisible by 19.
Hence A
Question: A beggar on the street can make one cigarette out of every 6 cigarette butts he finds. After one whole day of searching and checking public ashtrays,the beggar finds a total of 72 cigarette butts. How many cigarettes can he make and smoke from the butts he found?
A.4
B.14
C.34
D.27
Answer: B.14
Explanation: If the begger can make a whole cigarette from 6 butts then he can make 12 cigarettes from the 72 he found. Once he smokes those, he then will have another 12 butts, which gives him enough to make another 2 cigarettes. A total of 14.
correct answer is B)14
Question: If pqr = 0 , rst = 1 , and spr = 0, which of the following must be zero?
A.P
B.Q
C.R
D.S
Answer: A.P
Explanation: rst = 1 which means neither r / s/ t is 0
r x pq = 0 , we know r is not 0 from above hence either p or q must be 0.
s x p x r = 0, we know from first expression that r an p are not 0 hence p =0.
option A
Question: In the rectangular coordinate system, if the line x = 8y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p?
A.1/2
B.1/3
C.1/4
D.1/5
Answer: C.1/4
Explanation: x = 8y+5, and thus y = x/8 - 5/8
The slope is 1/8.
The slope of a line through points (m,n) and (m + 2,n + p) is (n+p-n)/(m+2-m) = p/2
p/2 = 1/8 and thus p = 1/4
The answer is C.
Question: A dealer marks his goods 20% above cost price. He then allows some discount on it and makes a profit of 8%. The rate of discount is :
A.8%
B.11%
C.21%
D.10%
Answer: D.10%
Explanation: Let C.P.=Rs.100
Marked price = Rs.120, S.P. = Rs.108
Discount = [12120×100][12120×100]% = 10%
Ans is : D
Question: In a bag there are 10 black balls and 25 blue balls and 15 white balls. A ball is drawn at random. What is the probability of getting a white ball?
A.2/5
B.3/10
C.4/10
D.5/10
Answer: B.3/10
Explanation: total balls = 10+25+15=50
probability of getting a white ball= 15/50 = 3/10 . correct option is B
Question: Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 6 : 3?
A.16
B.45
C.277
D.92
Answer: B.45
Explanation: Let the distances between city A to B and B to C be 6x km and 3x km respectively.
Total time taken to cover from A to C
= (6x)/40 + (3x)/60 = (18x + 6x)/120 = 24x/120 = x/5 Average speed = (6x + 3x)/(x/5) = 45 kmph.
Answer:B
Question: An article is bought for Rs.675 and sold for Rs.900, find the gain percent?
A.30 1/3%
B.33 1/3%
C.23 1/3%
D.35 1/3%
Answer: B.33 1/3%
Explanation: B
33 1/3%
675 ---- 225
100 ---- ? => 33 1/3%
Question: A train running at the speed of 60 km/hr crosses a pole in 18 seconds. Find the length of the train?
A.150 meter
B.170 meter
C.156 meter
D.300 meter
Answer: D.300 meter
Explanation: Speed = 60*(5/18) m/sec
= 50/3 m/sec
Length of Train (Distance)
= Speed * Time
(50/3) * 18
= 300 meter
Answer:D
Question: Walking at 40% of his usual speed a man takes 24 minutes more to cover a distance. What is his usual time to cover this distance?
A.16
B.36
C.42
D.48
Answer: A.16
Explanation: speed is inversly proprtional to time
walking at 40% of speed meand 2/5s takes 5/2t.
It takes 24 minutes extra to cover the distance. then
5/2t=t+24
5t=2t+48
3t=48
t=16.
Option A is correct
Question: If x^4 + y^4 = 85, then the greatest possible value of x is between:
A.0 to 2
B.2 to 4
C.4 to 6
D.6 to 8
Answer: B.2 to 4
Explanation: The answers to this question provide a great 'hint' as to how to go about solving it; since they're all essentially 'ranges', you can use them to figure out which solution contains the maximum value of X.
We're told that X^4 + Y^4 = 100. To maximize the value of X, we need to minimize the value of Y^4. The smallest that Y^4 could be is 0 (when Y = 0), so we'll have....
X^4 = 100
Looking at the answers, it makes sense to see what 3^4 equals....
3^4 = 81
Since that is BELOW 85, and 6^4 will clearly be MORE than 85, we have the correct answer.
Final Answer:
B
Question: If goods be purchased for Rs.840 and one-fourth be sold at a loss of 20% at what gain percent should the remainder be sold so as to gain 20% on the whole transaction?
A.33 1/7%
B.33 6/3%
C.33 1/3%
D.39 1/3%
Answer: C.33 1/3%
Explanation: 1/4 CP = 210 SP = 21*(80/100) = 168
SP = 840*(120/100) = 1008
1008 - 168 = 840
3/4 SP = 630
Gain = 210
630 --- 210
100 --- ? => 33 1/3%
Answer:C
Question: Two water pumps, working simultaneously at their respective constant rates, took exactly 9 hours to fill a swimming pool. If the constant rate of one pump was 1.5 times the constant rate of the other, how many hours would it have taken the faster pump to fill the pool if it had worked alone at its constant rate?
A.12
B.14
C.15
D.16
Answer: C.15
Explanation: Let the rate of the slow pump be x. Then the rate of the fast pump is 1.5x.
(x+1.5x) = 2.5x = 1/9 of the capacity of the whole pool per hour.
The rate of the fast pump is (1.5/2.5)*1/9 = 1/15 of the whole pool per hour.
The time it takes the faster pump to fill the pool would be 15 hours.
The answer is C.
Question: A sum of Rs. 125000 amounts to Rs. 14500 in 4 years at the rate of simple interest. What is the rate of interest?
A.3%
B.4%
C.5%
D.6%
Answer: B.4%
Explanation: S.I. = (14500 - 12500) = Rs. 2000\
Rate = (100 * 2000) / (12500 * 4) = 4%
ANSWER:B
Question: The largest 4 digit number exactly divisible by 77 is?
A.9935
B.9933
C.9944
D.9954
Answer: B.9933
Explanation: Largest 4-digit number = 9999
77) 9999 (129
9933
Answer : B
Question: Q=√[2√63 + 2/(8+3√7)] =
A.8 + 3√7
B.4 + 3√7
C.8
D.4
Answer: D.4
Explanation: In these type of question u multiply the nominator and denominator with conjugate...Conjugate of 8 +3sqrt(7) is 8 -3sqrt(7)
sqrt[2sqrt(63) + 2 { 8 - 3sqrt(7)}/{64 - 63}]
Q=sqrt[2sqrt(63) +16 - 2sqrt(63)] =4
Answer is 4.=D
Question: A library has an average of 140 visitors on Sundays and 80 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is :
A.90
B.100
C.105
D.110
Answer: A.90
Explanation: Explanation:
Since the month begins with a Sunday, so there will be five Sundays in the month,
Required average = (140 * 5 + 80 * 25) / 30 = 2700/30 = 90
Answer: A) 90
Question: If 4a = 16b and 5b = 13c, Find a:b:c?
A.52:13:5
B.13:7:52
C.7:13:52
D.7:13:54
Answer: A.52:13:5
Explanation: Explanation:
(4a = 16b ==> a/b = 16/4)
and (5b = 13c ==> b/c = 13/5)
==> a:b = 16:4 and b:c = 13:5
a:b:c =52:13:5
Answer: Option A
Question: 50 persons like apple. 7 like orange and mango dislike apple. 10 like mango and apple and dislike orange. 4 like all. How many people like apple?
A.47
B.46
C.54
D.57
Answer: D.57
Explanation: orange+mango-apple=7
mango+apple-orange=10
apple=50
orange+mango+apple=4
50+10+4-7=57 like apple
ANSWER:D
Question: If the sales tax be reduced from 4 (1/2) % to 3 (1/2) %, then what difference does it make to a person who purchases a bag with marked price of Rs. 10500?
A.Rs. 105
B.Rs. 150
C.Rs. 146
D.Rs. 135
Answer: A.Rs. 105
Explanation: Explanation:
Required difference = (4 (1/2) of Rs. 10500) - (3 (1/2) of Rs. 10500)
= (9/2– 7/2) % of Rs. 10500
= (1) x (1/100) x 10500
= Rs. 105
ANSWER A
Question: The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?
A.26
B.56
C.22
D.29
Answer: B.56
Explanation: 1 to 11 = 11 * 50 = 550
1 to 6 = 6 * 49 = 294
6 to 11 = 6 * 52 = 312
6th = 294 + 312 – 550
= 56
Answer:B
Question: A relay has a series of 5 circuits in a line. The even-numbered circuits are control circuits; the odd are buffer circuits. If both a control circuit and the buffer circuit immediately following it both fail in that order, then the relay fails. The probability of circuit one failing is 3/8; circuit two, 5/8; circuit three, 3/10; circuit four, 3/4; and circuit five, 2/5 .What is the probability that the relay fails?
A.9/80
B.3/10
C.303/800
D.69/160
Answer: D.69/160
Explanation: The first circuit doesn't matter.
Prob(relay fails) = 1 - Prob(relay succeeds)
Prob(2+3 work) = 1 - 3/16 = 13/16
Prob(4+5 work) = 1 - 3/10 = 7/10
Prob(relay fails) = 1 - Prob(2+3 work AND 4+5 work) = 1 - (13/16)(7/10) = 1 -91/160 = 69/160
D
Question: Which one of the following numbers is divisible by 11?
A.4823718
B.8423718
C.8432718
D.4832718
Answer: D.4832718
Explanation: Explanation:
4832718 = (4+3+7+8) – (8+2+1) = 11
So, the given number is divisible by 11
Answer:D
Question: In an electric circuit, three resistors with resistances r1, r2 and r3 are connected in parallel. In this case, if R is the combined resistance of these three resistors, then the reciprocal of R is equal to the sum of the reciprocals of r1, r2 and r3. What is R in terms of r1, r2 and r3?
A.(r1 + r2 + r3)
B.r1r2r3
C.1/(x + y)
D.r1r2r3/(r1 + r2 + r3)
Answer: D.r1r2r3/(r1 + r2 + r3)
Explanation: The wording is a bit confusing, though basically we are told that 1/R = 1/r1 + 1/r2 + 1/r3, from which it follows that r=r1r2r3/(r1 + r2 + r3).
Answer: D.
Question: In a hostel there were 100 students. To accommodate 15 more students the average is decreased by rupees 5. But total expenditure increased by Rs.400. Find the total expenditure of the hostel now?
A.A)Rs.6900
B.B)Rs.5480
C.C)Rs.5400
D.D)Rs.5900
Answer: A.A)Rs.6900
Explanation: 100x + 400
= 115(x – 5)
x = 65
100 * 65 + 400
= 6900
Answer:A
Question: The sum of the 1st and 3rd of 3consecutive odd integers is 131 less than three times the second integer. Find the three integers?
A.121
B.133
C.145
D.150
Answer: B.133
Explanation: Let x, x + 2 and x + 4 be three integers. The sum of the first x and third x + 4 is given by
x + (x + 4)
131 less than three times the second 3(x + 2) is given by
3(x + 2) - 131
"The sum of the first and third is 131 less than three times the second" gives
x + (x + 4) = 3(x + 2) - 131
Solve for x and find all three numbers
x = 129 , x + 2 = 131 , x + 4 = 133
As an exercise, check that the sum of the first and third is 131 less than three times
B
Question: Some of the people in Town F are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town F, three times as many people are tall as are tall in Town F, three times as many people are both as are both in Town F, but no one is neither. If the total number of people in Town F is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town F who are neither left-handed nor tall?
A. 23
B. 39
C. 72
D. 143
Answer: D. 143
Explanation: Yes, correct answer is indeed D.
{F}={Left} + {Tall} - {Both} + {Neither};
{Y} = 3*{Left} + 3*{Tall} - 3*{Both};
Since the total number of people in Town F is four times greater than the total number of people in Town Y, then:
{Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});
{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town F who are neither left-handed nor tall must be a multiple of 11.
Only answer choice D, is a multiple of 11: 143=11*13.
Answer: D.
Question: What are the number of ways to select 3 men and 2 women such that one man and one woman are always selected?
A.12
B.10
C.30
D.99
Answer: C.30
Explanation: The number of ways to select three men and two women such that one man and one woman are always selected = Number of ways selecting two men and one woman from men and five women
= ⁴C₂ * ⁵C₁ = (4 * 3)/(2 * 1) * 5
= 30 ways.
Answer:C
Question: If n is the product of three consecutive integers, and n is divisible by 4, which of the following is not necessarily a divisor of n ?
A.26
B.24
C.28
D.30
Answer: B.24
Explanation: IF ONE NO. IS 4 THEN OTHER CONSEQUTIVE NO. ARE 2*3*4 =24 , 3*4*5=60 , 4*5*6 =120
24 IS NOT A DIVISOR OF N
B
Question: The output of a factory is increased by 10% to keep up with rising demand. To handle the holiday rush, this new output is increased by 10%. By approximately what percent would the output of the factory now have to be decreased in order to restore the original output?
A.17%
B.24%
C.30%
D.32%
Answer: A.17%
Explanation: take it as original output =100.
to meet demand increase by 10%, then output=110.
to meet holiday demand , new output increase by 10% then output equals 121
To restore new holidy demand output to original 100.
final -initial/final*100
=21/121*100=8/33*100=17% approxiamately.
option A is correct.
Question: If 34 men completed 2/5th of a work in 8 days working 9 hours a day. How many more man should be engaged to finish the rest of the work in 6 days working 9 hours a day?
A.89
B.98
C.102
D.142
Answer: C.102
Explanation: From the above formula i.e (m1*t1/w1) = (m2*t2/w2)
so, (34*8*9/(2/5)) = (x*6*9/(3/5))
so, x = 136 men
number of men to be added to finish the work = 136-34 = 102 men
Answer : C.
Question: A circular box kept around a circular place. If the difference between the circumference of the outer circle and the inner circle is 44m, find the width of the box?
A.4 m
B.5 m
C.6 m
D.7 m
Answer: D.7 m
Explanation: Let radius of the outer circle be R and radius of the inner circle be r.
Circumference of the outer circle =
Circumference of the inner circle =
But,
or, R - r =
Thus, width of the road = 7 m
D
Question: Three persons invested Rs.9000 in a joint business. The second person invested Rs.1000 more than the first and the third Rs.1000 more than second. After two years, they gained Rs.5400. How much third person will get?
A.2400
B.2878
C.2699
D.2662
Answer: A.2400
Explanation: First persons investment = x
Second persons investment = x + 1000
Third persons investments = x + 2000
x + x + 1000 + x + 2000 = 9000
3x = 6000
x = 2000
Ratio = 2000 : 3000 : 4000
2:3:4
4/9 * 54000 = 2400
Answer: A
Question: What is the sum of odd integers from 35 to 85, inclusive?
A.1,560
B.1,500
C.1,240
D.1,120
Answer: A.1,560
Explanation: Number of odd integers = (85-35)/2 + 1
= 50/2 + 1
= 26
Sum of odd integers = (35+85)/2 * 26
= 60 * 26
= 1560
Answer A
Question: After successive discounts of 20%, 10% and 5% a certain good is sold for Rs. 6800. Find the actual price of the good.
A.s. 6000
B.s. 9000
C.s. 10800
D.s. 9942
Answer: D.s. 9942
Explanation: Let actual price was 100.
After three successive discount this will become,
100 ==20% discount => 80 ==10% discount => 72 ==5% discount = 68.4
Now Compare,
68.4 = 6800
1 = 6800/68.4
100 = (6800*100)/68.4 = Rs. 9942.
Answer: Option D
Question: From his monthly salary a man spends 10% of his salary for house rent, 20% on food, 25% for all other expenses and saves Rs 2520 per month. His monthly salary is?
A.Rs 4000
B.Rs 4200
C.Rs 5600
D.Rs 5880
Answer: C.Rs 5600
Explanation: Explanation: Total salary = 100%
His spending are on house rent 10%, on food 20% and for other expenses 25%.
Total expenditure = 10 % + 20% + 25% = 55%
His savings are => Income – Expenses
=> 100% - 55% => 45% = Rs 2520
Hi salary is 1005 => 2520 45
x 100
= Rs 5600
C
Question: Let A = {3, 5, 7}, B = {2, 3, 4, 6}.Find A ∩ B
A.{12}
B.{5}
C.{1}
D.{3}
Answer: D.{3}
Explanation: A = {3, 5, 7}
B = {2, 3, 4, 6}
correct answer :A ∩ B = {3}
D
Question: If 3 women can color 180 m long cloth in 2 days, then 5 women can color 300 m long cloth in?
A.2 days
B.3 days
C.5 days
D.1 day
Answer: A.2 days
Explanation: The length of cloth painted by one woman in one day = 180/ 3× 2 = 30 m
No. of days required to paint 300 m cloth by 5 women = 300/ 5 × 30 = 2 days
Answer : A
Question: At what rate of interest is an amount doubled in two years, when compounded annually?
A.41.8%
B.41.4%
C.81.4%
D.48.4%
Answer: B.41.4%
Explanation: Let the rate of interest be r. The amount gets doubled in two years => P(1 + r/100)2 = 2p => 1 + r/100 = √2 => r/100 = √2 - 1 = 0.414 => r = 100(0.414) = 41.4%.Answer:B
Question: The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned?
A.19828.88
B.19828.8
C.19828.87
D.19828.84
Answer: B.19828.8
Explanation: Let the sum be Rs.P
P{ [ 1 + 8/100]2 - 1 } = 2828.80
P(8/100)(2 + 8/100) = 2828.80 [a2 - b2 = (a - b) ( a + b)] P = 2828.80 / (0.08)(2.08) = 1360/0.08 = 17000 Principal + Interest = Rs.19828.80
Answer:B
Question: A crate of mangoes contains one bruised mango for every thirty mango in the crate. If three out of every four bruised mango are considerably unsaleble and there are 12 unsaleable mangoes in the crate then how msny mango are there in the crate?
A.100 mangoes
B.110 mangoes
C.120 mangoes
D.130 mangoes
Answer: C.120 mangoes
Explanation: 120 mangoes
ANSWER:C
Question: How many positive integers less than 50 have a reminder 01 when divided by 5?
A.10
B.14
C.15
D.16
Answer: A.10
Explanation: 1 also gives the remainder of 1 when divided by 5. So, there are total of 10 numbers.
Answer: A.
Question: A flagstaff 17.5 m high casts a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be?
A.10 m
B.12.5 m
C.12m
D.13 m
Answer: B.12.5 m
Explanation: Let the height of the building x metres.
Less lengthy shadow, Less in the height (Direct Proportion)
40.25 : 28.75 :: 17.5 : x 40.25 x x = 28.75 x 17.5
x =	28.75 x 17.5/40.25
x = 12.5
Answer:B