RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a recent election, James received 2.1 percent of the 2,000 votes cast. To win the election, a candidate needed to receive more than 46 percent of the vote. How many additional votes would James have needed to win the election?
A.901
B.879
C.990
D.991
Answer: B.879
Explanation: James = (2.1/100)*2000 = 42
Votes to win = (46/100)*Total Votes +1 = (46/100)*2000 +1 = 921
Remaining Voted needed to win election = 921 - 42 = 879
Answer: option B
Question: Paul's income is 40% less than Rex's income, Quentin's income is 20% less than Paul's income, and Sam's income is 40% less than Paul's income. If Rex gave 60% of his income to Paul and 40% of his income to Quentin, Quentin's new income would be what fraction of Paul's new income?
A.	11/12
B.	13/17
C.	22/30
D.	12/19
Answer: C.	22/30
Explanation: MAKE R = 10
P = 0.6R = 6
Q = 0.8P = 4.8
S= 0.6P = 3.6
FOR THAT WE GET P = 12
AND Q 8.8
SO 8.8/12 = = 2.2/ 3
Ans:C
Question: Find the least number which when divided by 37 and 7 leaves a remainder of 2 in each case.
A.259
B.261
C.263
D.265
Answer: B.261
Explanation: The least number which when divided by different divisors leaving the same remainder in each case
= LCM(different divisors) + remainder left in each case.
Hence the required least number
= LCM(37, 7) + 2 = 261.
ANSWER:B
Question: The circus sells two kinds of tickets: lower seats for $30 and upper seats for $20. On a certain night, the circus sells 80 tickets and gets $2100 in revenue from the sales. How many tickets for lower seats did they sell?
A.40
B.45
C.50
D.55
Answer: C.50
Explanation: Let L be the number of lower seat tickets.
Let U be the number of upper seat tickets.
L + U = 80 and U = 80-L.
30L+20U=2100.
30L+20(80-L)=2100
10L+1600=2100.
10L=500.
L=50.
The answer is C.
Question: The length of the room is 3m and width is 3m. Find the cost of paving the floor by slabs at the rate of Rs.300 per sq meter?
A.1800
B.1500
C.1700
D.1600
Answer: A.1800
Explanation: l=3m w=3m
area of the floor = 3 x 3 = 9 sq m
cost of paving = 200 x 9 = Rs. 1800
Answer: A
Question: If a farmer wants to plough a farm field on time, he must plough 90 hectares a day. For technical reasons he ploughed only 85 hectares a day, hence he had to plough 2 more days than he planned and he still has 40 hectares left. What is the area of the farm field and how many days the farmer planned to work initially?
A.1600
B.2490
C.3780
D.4235
Answer: C.3780
Explanation: Let x be the number of days in the initial plan. Therefore, the whole field is 90â‹…x hectares. The farmer had to work for x+2 days, and he ploughed 85(x+2) hectares, leaving 40 hectares unploughed. Then we have the equation:
90x=85(x+2)+40
5x=210
x=42
So the farmer planned to have the work done in 6 days, and the area of the farm field is 90(42)=3780 hectares
correct answer C
Question: If A got 80 marks and B got 40 marks, then what percent of A's mark is B's mark?
A.A)60%
B.B)80%
C.C)50%
D.D)75%
Answer: C.C)50%
Explanation: A's marks = 80 ; B's marks = 40.
Let x% of A = B => x/100 * 80 = 40
=> x = (40 * 100)/80 = 50
B's marks is 50% of A's marks.
ANSWER:C
Question: The numbers of pizza slices that are sold in Joey's Pizza are only in quantities of 4 and 6 slices per customer. How many slices cannot be bought?
A.42.
B.38.
C.54.
D.33.
Answer: D.33.
Explanation: Answer:	Let X pizzas of 4 slices and Y pizzas of 6 slices.
4X + 6Y.
Lets check options wise.
A. 42 => 4(3) + 6(5)
B. 38 => 4(5) + 6(3)
C. 33 = 3(4) + 6(7)
D. 54 => we can't write anything with 4 and 6 series..Lets try 4(5) + 6(2) = 32 , 4(4) + 6(3) = 34 , nothing works out.
E. 18 => 4(3) + 6(1)
Answer: correct option is D
Question: A person takes 5 hrs 45 min in walking to a place and riding back. He would have gained 1 hour by riding both ways. The time he would take to walk both ways is?
A.5 hours 45 min
B.5 hours 55 min
C.6 hours 45 min
D.7 hours 45 min
Answer: C.6 hours 45 min
Explanation: ----------------------------------------------------------------
Solution 1
----------------------------------------------------------------
Given that time taken for riding both ways will be 1 hours lesser than
the time needed for waking one way and riding back
From this, we can understand that
time needed for riding one way = time needed for waking one way - 1 hours
Given that time taken in walking one way and riding back = 5 hours 45 min
Hence The time he would take to walk both ways = 5 hours 45 min + 1 hours = 6 hours 45 min
C
Question: if p is a positive integer greater than 8, which of the following must be divisible by 4?
A. p(p-1)(p+2)(p+3)
B. p(p-1)(p+3)(p+4)
C. p(p-3)(p+2)(p+4)
D. p(p-3)(p+2)(p+3)
Answer: D. p(p-3)(p+2)(p+3)
Explanation: D.
For any integer p, D is the only answer choice which will always be divisible by 4.
A product of 4 consecutive integers will always be divisible by 4. Since, none of the answer choices are a product of 4 consecutive integers, we have to ensure at least one of the integers is always a multiple of 4. The best way to do that is to ensure the answer choice isp* [(p-1)OR(p+3)] * [(p-2)OR(p+2)] * [(p-3)OR(p+1)]. (answer D)
Question: Sum of the numbers from 1 to 25 is
A.210
B.325
C.320
D.105
Answer: B.325
Explanation: Explanation: Sum of first n natural numbers = 1 + 2 + 3 + ..... n = n(n+1)/2
Substitute n = 25.
So S20=25Ã—26/2=325
Correct Option: B
Question: Set S consists of integers {2,3,4,5}. If two numbers are chosen from set S at random, what is the probability that the product of 2 numbers is more than 10?
A.1/2
B.1/4
C.2/5
D.3/7
Answer: A.1/2
Explanation: Number of ways you can choose 2 from 4 = 4C2 = 6
E = event of getting the 2 numbers product is more than 10 = (3,4),(3,5),(4,5) = 3
probability = 3/6 = 1/2
Answer is A
Question: A boat sails 15 km of a river towards upstream in 5 hours. How long will it take to cover the same distance downstream, if the speed of current is one-fourth the speed of the boat in still water:
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: Explanation:
Upstream speed = B-S
Downstream speed = B+s
B-S = 15/5 = 3 km/h
Again B= 4S
Therefore B-S = 3= 3S
=> S = 1 and B= 4 km/h
Therefore B+S = 5km/h
Therefore, Time during downstream = 15/5 = 3h
Answer: B) 3h
Question: Express of the following as a fraction:
44%
A.11/25
B.13/25
C.11/25
D.17/25
Answer: A.11/25
Explanation: 44% = 44/100= 11/25.
Answer is A.
Question: What is the probability of getting a sum 9 from two throws of a dice?
A.1/9
B.1
C.2/9
D.2
Answer: A.1/9
Explanation: In two throws of a dice, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
P(E) = n(E)/n(S) = 4/36	= 1/9
Hence answer is A
Question: How many multiples of 4 are there between 12 and 92, inclusive?
A.21
B.22
C.23
D.24
Answer: A.21
Explanation: The multiples of 4 are from 4*3 up to 4*23.
23-3+1 = 21.
The answer is A.
Question: A train passes a station platform in 45 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
A.177 m
B.375 m
C.240 m
D.187 m
Answer: B.375 m
Explanation: Speed = [54 * 5/18] m/sec = 15 m/sec.
Length of the train = (15 * 20) m = 300 m.
Let the length of the platform be x meters.
Then, x + 300 / 45 = 15
x + 300 = 675
x = 375 m.
Answer: B
Question: A mailman puts .05% of letters in the wrong mailbox. How many deliveries must he make to misdeliver 2 items?
A.4000
B.400
C.40
D.40000
Answer: A.4000
Explanation: Let the number of total deliveries be x
Then, .05% of x=2
(5/100)*(1/100)*x=2
x=4000
Answer is A
Question: The probability of a lottery ticket being a prized ticket is 0.2. When 4 tickets are purchased, the probability of winning a prize on atleast one ticket is?
A.0.5908
B.0.5904
C.0.5901
D.0.5916
Answer: B.0.5904
Explanation: P(winning prize atleast on one ticket)
= 1 - P("Losing on all tickets")
= 1 - (0.8)4 = (1 + (0.8)2)(1 - (0.8)2)
= (1.64)(0.36) = 0.5904
Answer:B
Question: What is the place value of 4 in the numeral 57468?
A.400
B.40
C.4000
D.4
Answer: A.400
Explanation: place value of 4 = 4 * 100 = 400
Answer is A
Question: How many different subset of the set {I, II, III, IV, V, VI, VII, VIII, IX) do not contain V.
A.273
B.282
C.285
D.283
Answer: D.283
Explanation: This is a combination solution
Since we have 8 different Roman Numerals other than the V we can take any Roman numeral from the set of 8 to make a subset.
8C1 +8C2 + 8C3 + 8C4 + 8C5 + 8C6 + 8C7 + 8 C8 = 282
Plus the one set that is null that is the Set having no element in it which is 8C0 =1
= 282 + 1 = 16
D = 283
Question: In a forest 160 deer were caught, tagged with electronic markers, then released. A week later, 50 deer were captured in the same forest. Of these 50 deer, it was found that 5 had been tagged with the electronic markers. If the percentage of tagged deer in the second sample approximates the percentage of tagged deer in the forest, and if no deer had either left or entered the forest over the preceding week, what is the approximate number of deer in the forest?
A.150
B.750
C.1,250
D.1,600
Answer: D.1,600
Explanation: The percentage of tagged deer in the second sample = 5/50*100=10%.
So, 160 tagged deers comprise 10% of total # of deers --> total # of deers = 160*10 = 1,600.
Answer: D.
Question: If each term in the sum T=a1+a2+a3+...+an either 2 or 22 and the sum equals 100, which of the following could be equal to n?
A.38
B.39
C.40
D.41
Answer: C.40
Explanation: Min value of 'n' can be 10 i.e 4*22+6*12=T => 22+22+22+22+2+2+2+2+2+2 = 100
Since we don't have 10 in the options proceed further, (10-1)+22/2 => 20 digits, which is again not in the options
(20-1) + 22/2 = 30 digits ( not in options)
(30-1) + 22/2 = 40 digits
Hence C.
Question: When x + p is divided by p - 2, the quotient is n and there is no remainder. Which of the following must be the value of x?
A.n(p +1)
B.n(p − 1)
C.p(n + 1) + 2n
D.p(n - 1) + 2n
Answer: D.p(n - 1) + 2n
Explanation: Given in question (x+p)/p-2= n
=> x+p= n(p-2)
=>x= np+2n-p
or x= np-p+2n
Now we are good to check the options
x= p(n-1) + 2n
Answer D
Question: Indu gave Bindu Rs.2500 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
A.1
B.2
C.3
D.4
Answer: D.4
Explanation: 2500 = D(100/4)2
D = 4
Answer: D
Question: What was the day of the week on, 16th July, 1776?
A.Tuesday
B.Wednesday
C.Monday
D.Saturday
Answer: A.Tuesday
Explanation: 16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)
Counting of odd days :
1600 years have 0 odd day.
100 years have 5 odd days.
75 years = (18 leap years + 57 ordinary years) = [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days.
1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day.
Jan Feb Mar Apr May Jun Jul
31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days)
Total number of odd days = (0 + 2) = 2.
Required day was 'Tuesday'.
Answer:A
Question: A horse is tethered to one corner of a rectangular grassy field 45 m by 25 m with a rope 22 m long. Over how much area of the field can it graze?
A.354 cm2
B.380 m2
C.350 m2
D.407 m2
Answer: B.380 m2
Explanation: Area of the shaded portion
= 1⁄4 × π × (22)2 = 380 m2
Answer B
Question: A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
A.20 hrs
B.25 hrs
C.35 hrs
D.Cannot be determined
Answer: C.35 hrs
Explanation: Suppose pipe A alone takes x hours to fill the tank.
Then, pipes B and C will take x/2 and x/4 hours respectively to fill the tank.
1/x + 2/x + 4/x = 1/5
7/x = 1/5 => x = 35 hrs.
ANSWER:C
Question: If 0 < a < b < c < 1 , which of the following are positive?
I.	b-c
II.	a-b
III.	c-a
A.I only
B.II only
C.III only
D.I and II
Answer: C.III only
Explanation: We could solve this easily using examples.
I is false since b<c and both are positive
II is false since b<c and both are positive
III is true since c>a and both are positive
So, the answer is C.
Question: Evaluate combination
100C97=100!/(97)!(3)!
A.161700
B.151700
C.141700
D.131700
Answer: A.161700
Explanation: Explanation:
nCr=n!/(r)!(n−r)!
100C97=100!/(97)!(3)!
=100∗99∗98∗97!/(97)!(3)!
=100∗99∗98/3∗2∗1
=100∗99∗98/3∗2∗1=161700
Option A
Question: Find the area of trapezium whose parallel sides are 26 cm and 18 cm long, and the distance between them is 15 cm.
A.227
B.299
C.330
D.161
Answer: C.330
Explanation: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (26 + 18) * (15)
= 330 cm2
Answer: C
Question: Two persons start running simultaneously around a circular track of length 300 m from the same point at speeds of 15 km/hr and 25 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions?
A.16 seconds
B.18 seconds
C.19 seconds
D.27 seconds
Answer: D.27 seconds
Explanation: Time taken to meet for the first time anywhere on the track
= length of the track / relative speed
= 300 / (15 + 25)5/18 = 300* 18 / 40 * 5
= 27 seconds.
Answer:D
Question: If the manufacturer gains 10 %, the wholesale dealer 15 % and the retailer 25 %, then find the cost of production of a table if the retail price was Rs 1265
A.Rs. 750
B.Rs. 800
C.Rs. 850
D.Rs. 900
Answer: B.Rs. 800
Explanation: Explanation:
Let the cost of Production = Rs. P
Then, as per question,
=>(125/100∗115/100∗110/100∗P)=1265
=>253/160P=1265
=>P=800
Option B
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres?
A.12
B.16
C.17
D.19
Answer: A.12
Explanation: Speed of the boat downstream = 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m = 60/5 = 12 seconds.
Answer: A
Question: A meeting has to be conducted with 5 managers.Find the number of ways in which the managers may be selected from among 8 managers,if 2 managers will not attend the meeting together.
A.1.35
B.2.91
C.3.12
D.4.36
Answer: D.4.36
Explanation: 8 managers, but two of them cannot attend the meeting together.
We can split it into two cases.
1. Meeting without these two managers in it. That would mean selecting 5, from the remaining 6 which is 6C5 = 6
2. Meeting with one of the two managers. select 1 manager from two, and then select 4 from the remaining 6, which is 2C1 X 6C4 = 15.
So, answer is 30 + 6 = 36.
Answer : D
Question: If 0.25 of a number is equal to 0.05 of another number, the ratio of the numbers is :
A.2 : 5
B.3 : 4
C.1 : 5
D.20 : 5
Answer: C.1 : 5
Explanation: 0.25A = 0.05B
-> A/B = 0.05/0.25 = 5/25 = 1/5
:. A : B = 1 : 5
ANSWER:C
Question: The average weight of A,B,C is 45 Kg. The avgwgt of A & B be 40Kg & that of B,C be 43Kg. Find the wgt of B.
A.23
B.43
C.21
D.31
Answer: D.31
Explanation: Sol. Let A,B,c represent their individual wgts.
Then,
A+B+C=(45*3)Kg=135Kg
A+B=(40*2)Kg=80Kg & B+C=(43*2)Kg=86Kg
B=(A+B)+(B+C)-(A+B+C)
=(80+86-135)Kg
=31Kg.
ANSWER D
Question: A family made a down payment of $20
and borrowed the balance on a set of
encyclopedias that cost $120. The
balance with interest was paid in 7
monthly payments of $15.2 each and a
final payment of $7. The amount of
interest paid was what percent of the
amount borrowed?
A. 6%
B. 12%
C. 13.4%
D. 16%
Answer: C. 13.4%
Explanation: interest paid = 15.2*7+7 - 100 = 13.4
% off the balance = (13.4/100) * 100 = 13.4 %
Answer is C.
Question: If x^2 = 161, which of the following is closest to a potential value of x?
A.-127
B.-11
C.12
D.13
Answer: D.13
Explanation: Here the thing we must not forget is that X^even has two potential solutions
=> x =+- √161 => +- 13 (approx)
this value is closer to 13
Hence D is correct.
Question: What least number should be subtracted from 1398 so that the remainder when divided by 7, 9, and 11 will leave in each case the same remainder 5 ?
A.6
B.7
C.8
D.10
Answer: B.7
Explanation: The LCM of 7, 9, and 11 is 693. The next multiple is 2*693 = 1386.
1386 + {remainder} = 1386 + 5 = 1391, which is 7 less than 1398.
Answer: B.
Question: If 90% of A =30% of B and B=x% of A, then the value of x is?
A.800
B.300
C.700
D.400
Answer: B.300
Explanation: 0.9 A= 0.3 B
so b=3A means 300% of A
ANSWER:B
Question: During the first two weeks of May, the total rainfall in Springdale was 35 inches. If the rainfall during the second week was 1.5 times the rainfall during the first week, what was the rainfall in inches during the second week of May?
A.12
B.15
C.18
D.21
Answer: D.21
Explanation: Let x be the rainfall in the first week. Then 1.5x was the rainfall in the second week.
2.5x = 35
x = 14
The rainfall during the second week was 1.5 * 14 = 21 inches
The answer is D.
Question: If 5 machines can produce 20 units in 10 hours, how long would it take 25 to produce 100 units?
A.5
B.9
C.6
D.10
Answer: D.10
Explanation: 5 machines would produce 100 units in 50 hours. Increasing the amount of machines by 5 would mean dividing 50 hours by 5.
50/5 = 10
Answer : D
Question: A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work?
A.22
B.88
C.27
D.14
Answer: D.14
Explanation: Let A worked for x days.
x/21 + 4/28 = 1 => x/21 = 6/7 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.
Answer: D
Question: Four milkmen rented a pasture. A grazed 24 cows for 3 months; B 10 for 5 months; C 35 cows for 4 months and D 21 cows for 3 months. If A's share of rent is Rs. 1440, find the total rent of the field.
A.6500
B.3550
C.4250
D.2250
Answer: A.6500
Explanation: Ratio of shares of A, B, C, D = (24 x 3) : (10 x 5) : (35 x 4) : (21 x 3) = 72 : 50 : 140 : 63.
Let total rent be Rs. x. Then, A’s share = Rs. (72x)/325
(72x)/325=1440 = x=(1440 x 325)/72 = 6500
Hence, total rent of the field is Rs. 6500.
Answer is A.
Question: A can do a job in 8 days and B can do it in 20 days. A and B working together will finish twice the amount of work in ------- days?
A.21 ½ days
B.11 3/7 days
C.23 ½ days
D.12 ½ days
Answer: B.11 3/7 days
Explanation: Explanation:
1/8 + 1/20 = 7/40
40/7 = 40/7 *2 = 11 3/7 days
Answer: B
Question: A man purchases 8 pens for Rs.9 and sells 9 pens for Rs.8, how much profit or loss does he make?
A.11
B.99
C.28
D.20
Answer: D.20
Explanation: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages.
Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr.
stoppage time = 20/60 hrs = 20 min.
Answer:D
Question: The price of 3 tables and 4 chairs is Rs. 3300. With the same money one can buy 2 tables and 10 chairs. If one wants to buy 1 table and 1 chair, how much does he need to pay?
A.Rs.940
B.Rs.1050
C.Rs.1040
D.Rs.950
Answer: B.Rs.1050
Explanation: Explanation :
Let price of a table = t
and price of a chair = c
3t + 4c = 3300 ---(Equation 1)
2t + 10c = 3300
=> t + 5c = 1650 ---(Equation 2)
(Equation 2) × 3 => 3t + 15c = 4950 ---(Equation 3)
(Equation 3) - (Equation 1) => 11c = 1650
=> c = 150
Substituting the value of c in equation 1, we get
3t + (4 × 150) = 3300
=> 3t = 3300 – 600 = 2700
=>t = 2700/3 = 900
Cost of 1 table and 1 chair = c + t = 150 + 900 = 1050
Answer : B
Question: All the stocks on the over-the-counter market are designated by either a 6 letter or 5 letter codes that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be designated with these codes?
A.2(26^5)
B.26(26^4)
C.27(26^6)
D.26(26^5)
Answer: C.27(26^6)
Explanation: with 4 letters: 26^6
with 5 letters: 26^5
26^6 + 26^5 = 27*(26^5)
C
Question: On dividing 109 by a number, the quotient is 9 and the remainder is 1. Find the divisor.
A.12
B.14
C.16
D.18
Answer: A.12
Explanation: d = (D-R)/Q
= (109 - 1)/9
= 108/9 = 12
A)
Question: m and n are the x and y coordinates, respectively, of a point in the coordinate plane. If the points (m, n) and (m + p, n + 21) both lie on the line defined by the equation x = (y/7) - (2/5), what is the value of p?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: x = (y/7) - (2/5), and so y = 7x + 14/5. The slope is 7.
(n+21-n) / (m+p-m) = 7
p = 3
The answer is C.
Question: Length of a rectangular plot is 20 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
A.45 m
B.60 m
C.56 m
D.67 m
Answer: B.60 m
Explanation: Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m
B
Question: A student was asked to find 4/5 of a number. But the student divided the number by 4/5, thus the student got 36 more than the correct answer. Find the number.
A.60
B.70
C.80
D.90
Answer: C.80
Explanation: Let the number be x.
(5/4) * x = (4/5)*x + 36
25x = 16x + 720
9x = 720
x = 80
The answer is C.
Question: Every year an amount increases by 1/6th of itself. How much will it be after two years if its present value is Rs.64000?
A.87111
B.81007
C.81008
D.81066
Answer: A.87111
Explanation: 64000* 7/6 * 7/6 = 87111
Answer:A
Question: Find the missing number: ? - 1936248 = 1635773
A.3572021
B.3572012
C.3770221
D.3570221
Answer: B.3572012
Explanation: Let x - 1936248=1635773.
Then, x = 1635773 + 1936248
=3572021.
Answer is B.
Question: The perimeter of one square is 40 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?
A.11.2√2
B.13√2
C.23√2
D.12√4
Answer: A.11.2√2
Explanation: 4a = 40 4a = 20
a = 10 a = 5
a2 = 100 a2 = 25
Combined area = a2 = 125 => a = 11.2
d = 11.2√2
Answer: A
Question: If john makes a contribution to a charity fund at school, the average contribution size will increase by 50% reaching $75 per person. If there were 2 other contributions made before john's, what is the size of his donation?
A.$125
B.$150
C.$200
D.$250
Answer: A.$125
Explanation: Cavg = average contribution before John
Cavg*1.5 = 75, therefore the average cont is $50 before John.
If he needs to increase the average contribution by $25, he must put in $25 for each of the 2 people.
so $50.
But, he also has to put in the average for himself (the threeth person), so add $75.
So $125 is your answer.
Answer A
Question: P sells an article to Q at 10 % profit. Q sells it to R at 25 % profit. If R pays Rs. 250 for it, What did P pay for it ?
A.Rs. 181.81
B.Rs. 181.88
C.Rs. 181.82
D.Rs. 181.89
Answer: A.Rs. 181.81
Explanation: Explanation:
Selling price of P = Cost price of Q
Selling Price of Q = Cost price of R = Rs. 250 ….. Given
Q sold it to R with 25 % profit.
Cost price of Q = 100/125 * 250/1 = Rs. 200 = Selling price of P.
P sold it to Q with 10 % profit.
Cost price of P = 100 / 110 * 200 / 1 = Rs. 181.81
ANSWER: A
Question: If 4 women can color 48 m long cloth in 2 days, then 6 women can color 36 m long cloth in
A.2 days
B.3 days
C.1 day
D.4 days
Answer: C.1 day
Explanation: The length of cloth painted by one woman in one day = 48 / 4 × 2 = 6 m
No. of days required to paint 36 m cloth by 6 women = 36/ 6 × 6 = 1 day.
C
Question: Ann and Bob drive separately to a meeting. Ann's average driving speed is greater than Bob's avergae driving speed by one-third of Bob's average driving speed, and Ann drives twice as many miles as Bob. What is the ratio W of the number of hours Ann spends driving to the meeting to the number of hours Bob spends driving to the meeting?
A.8:3
B.3:2
C.4:3
D.2:3
Answer: B.3:2
Explanation: Say the rate of Bob is 3mph and he covers 6 miles then he needs 6/3=2 hours to do that.
Now, in this case the rate of Ann would be 3+3*1/3=4mph and the distance she covers would be 6*2=12 miles, so she needs 12/4=3 hours for that.
The ratio W of Ann's time to Bob's time is 3:2.
Answer: B.
Question: 3x^2-6x+3 = 0
Find the above equation find the value of x
A.0
B.1
C.2
D.4
Answer: B.1
Explanation: a = 3, b = -6, c = 3
x1,2 = (6 ± √( (-6)2 - 4×3×3)) / (2×3) = (6 ± √(36-36)) / 6 = (6 ± 0) / 6
x1 = x2 = 1
B
Question: If x#y is defined to equal x^2/y for all x and y, then (-1#2)#2 =
A.4/3
B.1/3
C.1/12
D.1/8
Answer: D.1/8
Explanation: (-1)^2 / 2 = 1/2
(1/2)^2 / 2 = 1/8
so D is my answer