RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: How many odd integers between 200 and 600 are there such that their tens digit is even?
A.20
B.25
C.100
D.150
Answer: C.100
Explanation: The hundreds digit can take 4 values: 2, 3, 4 and 5;
The tens digit can take 5 values: 0, 2, 4, 6 and 8;
The units digit can take 5 values: 1, 3, 5, 7 and 9;
Total: 4*5*5=100.
Answer: C
Question: In what time will Rs.4000 lent at 3% per annum on simple interest earn as much interest as Rs.5000 will earn in 5 years at 4% per annum on simple interest?
A.8 1/3
B.8 1/6
C.8 1/2
D.8 1/9
Answer: A.8 1/3
Explanation: (4000*3*R)/100
= (5000*5*4)/100
R = 8 1/3
Answer: A
Question: If the area of a circle is 49pi square feet, find its circumference.
A.14 pi feet
B.28 pi feet
C.38 pi feet
D.48 pi feet
Answer: A.14 pi feet
Explanation: The area is given by pi *r* r. Hence
pi * r *r = 49 pi
r * r = 49; hence r = 49 feet
The circumference is given by
2 * pi * r = 2 * pi * 7 = 14 pi feet
correct answer A
Question: In a set of three numbers,the difference between the largest and the second largest numbers is added to the smallest number.The average of the largest,second largest and the new number formed exceeds the average of the original three numbers by 5.The largest number exceeds the second largest number by how much ?
A.5
B.10
C.15
D.30
Answer: C.15
Explanation: Let the numbers in increasing order be A<B<C...
since the new number(N) increase the average of new set of numbers by 5 after replacing the smallest number,A,
the new number,N, exceeds the smallest,A, by 3*5=15 or N=15+A..(1)
and what is the new number,N,---- C-B (diff in the largest and second largest)+A...(2)...
from (1) & (2) C-B=15...
Answer:-C
Question: A train running at the speed of 60 km/hr crosses a pole in 12 seconds. What is the length of the train?
A.187 m
B.278 m
C.876 m
D.200 m
Answer: D.200 m
Explanation: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train
= (Speed x Time)
= (50/3 * 12) m
= 200 m.
Answer: D
Question: J is 25% less than P and 20% less than T. T is q% less than P. What is the value of q?
A.93.5
B.90
C.6.75
D.6.25
Answer: D.6.25
Explanation: Usually We can solve every question of this type by choosing appropriate value of the Variable and deriving the value of other related variables.
Let, P = 400
then J = (75/100)*400 = 300
also J = (80/100)*T
i.e. T = 300*100/80 = 375
and T = [1-(q/100)]*P
i.e. 100-q = 100*T/P = 100*375/400 = 93.75
i.e. q = 6.25
Answer: Option D
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8587 for a computer table, then what was the cost price of the computer table?
A.7297
B.2977
C.2871
D.6925
Answer: D.6925
Explanation: Explanation:
CP = SP * (100/(100 + profit%))
= 8587(100/124) = Rs. 6925.
Answer: D
Question: let S is a set of all natural numbers less than 120 such that HCF of any element in S and 120 is 1. Find the sum of all elements in S?
A.1584
B.7640
C.5640
D.7240
Answer: A.1584
Explanation: S is a set of all natural numbers less than 120 such that HCF of any element in S and 120 is 1.
Such numbers are,
S = {1, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113}
Sum of S = 1584.
ANSWER:A
Question: If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is?
A.Rs.8082
B.Rs.7800
C.Rs.8100
D.Rs.8112
Answer: D.Rs.8112
Explanation: Explanation:
A = 7500(26/25)2 = 8112
ANSWER IS D
Question: Calculate 12351 ÷ ? = 69
A.179
B.119
C.129
D.173
Answer: A.179
Explanation: Answer
Let 12351 ÷ ? = 69
Then X = 12351/69 = 179.
Option: A
Question: find remainder when (10^3+9^3)^1000 divided by 12^3
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: (10^3+9^3)^1000 / 12^3
= 1729^1000 / 1728
=> (1728*1+1)^1000 / 1728
=> 1^1000 / 1728
=> rem = 1
ANSWER:B
Question: How many seconds will a train 120 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?
A.17 sec
B.21 sec
C.25 sec
D.27 sec
Answer: D.27 sec
Explanation: D = 120 + 150 = 270
S = 36 * 5/18 = 10 mps
T = 270/10 = 27 sec
Question: Evaluate: 6602.5 + 660.25 + 66.025 + 6.6025 + 0.66025
A.6819.59775
B.7336.03775
C.6918.59775
D.6198.59775
Answer: B.7336.03775
Explanation: 6602.5
660.25
66.025
6.6025
+ 0.66025
---------------
7336.03775
Answer is B.
Question: Find the cost of fencing around a circular field of diameter 16 m at the rate of Rs.3 a meter?
A.150.84
B.160.6
C.150.45
D.160.99
Answer: A.150.84
Explanation: 2 * 22/7 * 8 = 50.28
50.28 * 3= Rs.150.84
Answer: A
Question: The difference between simple interest and compound interest on Rs.1400 for one year at 20% per annum reckoned half-yearly is:
A.$185.63
B.$852.36
C.$875.5
D.$989.9
Answer: D.$989.9
Explanation: S.I= [(1400*20*1)/100]= $280.
C.I=[1400*(1+(5/100)^2)-1400]=$1269.8.
Difference=(1269.8-280) =$989.8
Answer(D)
Question: Sambhu buys rice at Rs. 10/kg and puts a price tag on it so as to earn a profit of 20%. However, his faulty balance shows 1000 gm when it is actually 800 gm. What is his actual gain percentage ?
A.20%
B.30%
C.50%
D.40%
Answer: C.50%
Explanation: 1kg rice =Rs. 10 => 800gm actual cost =Rs. 8.
But he wants to earn a profit of 20% => 1kg = Rs.12.
Moreover his faulty balance shows 800 gm = 1000gm (1 kg)
=> He sells 800 gm for Rs.12
Therefore the actual profit earned by him is (12-8)/8 * 100 =50%
ANSWER:C
Question: In Town P, 60 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town P are females?
A.20%
B.25%
C.30%
D.35%
Answer: A.20%
Explanation: The percent of the population who are employed females is 60-48 = 12%
The percent of employed people who are female is 12% / 60% = 20%.
The answer is A.
Question: Four contestants representing four different countries advance to the finals of a fencing championship. Assuming all competitors have an equal chance of winning, how many possibilities are there with respect to how a first-place and second-place medal can be awarded?
A.6
B.7
C.12
D.16
Answer: C.12
Explanation: Number of ways First-place medal can be awarded to four contestants = 4
Number of ways Second-place medal can be awarded to contestants after awarding First-place medal =3
Therefore number of possibilities = 4 *3 =12
Answer: C
Question: A boatman goes 2 km against the current of the stream in 2 hour and goes 1 km along the current in 20 minutes. How long will it take to go 5 km in stationary water?
A.2 hr 30 min
B.2 hr
C.4 hr
D.1 hr 15 min
Answer: A.2 hr 30 min
Explanation: Explanation :
Speed upstream = 2/2 = 1 km/hr
Speed downstream = 1/((20/60)) = 3 km/hr
Speed in still water = 1/2(3+1) = 2 km/hr
Time taken to travel 5 km in still water = 5/2 = 2(1/2) hours = 2 hour 30 minutes. Answer : Option A
Question: If S is the sum of the reciprocals of the consecutive integers from 91 to 100, inclusive, which of the following is less than S?
I. 1/11
II. 1/10
III. 1/10
A.II only
B.I only
C.III only
D.II and III only
Answer: A.II only
Explanation: Since we summarize the reciprocals from 100 to 91, we can say also that we add ten numbers who are all (with one exception 1/100) greater than 1/100, so that the sum must be greater than 1/10.
On the other side we can say that we add the reciprocals from 91 to 100, so that the sum has to be less than the sum of ten times 1/91.
We can conclude that the sum has to be less than 1/9 but more than 1/10. That leaves us A a as the only possible answer.
Question: If a, b, and c are consecutive integers such that a < b < c and a is an even prime number, which of the following is true?
I. a + b + c > a^3
II. a × b × c < a^3
III. 4b < bc
A.I only
B.II only
C.III only
D.II and III
Answer: A.I only
Explanation: Only 'A' is possible solution. If a is even prime number i.e 2, b is 3 and c is 4
Putting the values in the answers only 'A' seems valid.
Question: If the product of the integers from 1 to n is divisible by 210, what is the least possible value of n?
A.7
B.14
C.21
D.28
Answer: A.7
Explanation: 210 = 2 x 3 x 5 x 7
N must include at least up to the number 7.
The answer is A.
Question: The probability that A speaks truth is 5/9 and that of B speaking truth is 7/11. What is the probability that they agree in stating the same fact?
A.68/95
B.12/85
C.59/99
D.33/39
Answer: C.59/99
Explanation: If both agree stating the same fact, either both of them speak truth of both speak false.
Probability = 5/9 * 7/11 + 4/9 * 6/11
= 35/99 + 24/99 = 59/99
ANSWER:C
Question: A car driver travels from the plains to the hill station, which are 200 km apart at an average speed of 40 km / hr. In the return trip, he covers the same distance at an average speed of 20 km / hr. The average speed of the car over the entire distance of 400 km / hr.
A.22 km/hr
B.28.56 km/hr
C.26.67 km/hr
D.30 km/hr
Answer: C.26.67 km/hr
Explanation: Sol.
Average speed = (2×40×20 / 40 + 60) km/hr
= (80/3)km/hr
= 26.67 km/hr.
Answer C
Question: If the selling price of 8 articles is same as the cost price of 10 articles. Find the gain or loss percentage?
A.25%
B.45%
C.35%
D.65%
Answer: A.25%
Explanation: Let the C.P of each article be Re 1. Then,
S.P of 8 articles = C.P of 10 articles = Rs. 10
Now, C.P of 8 articles = Rs. 8, S.p of 8 articles = Rs 10
Gain = Rs ( 10 - 8 ) = Rs 2.
Gain% = ( 2/8 × 100 ) % = 25%
Answer : A
Question: Find the value of x when the average of 3x,(5x+6),(7x-4) is 51?
A.5
B.10
C.15
D.12
Answer: B.10
Explanation: Average = (3x+5x+6+7x-4)/3 = (15x+3)/3 = 5x+1
5x+1 = 51
x = 50/5 = 10
Answer is B
Question: The average speed of a train running at a speed of 30 km/hr during the first 100 kilometres, at 40 km/hr during the second 100 kilometres and at 50 km/hr during the last 100 kilometres is nearly?
A.38.5 km/hr
B.38.3 km/hr
C.40.0 km/hr
D.39.2 km/hr
Answer: B.38.3 km/hr
Explanation: Time taken to cover first 100 kilometres = 100/3 = 3(1/3) hours
Time taken to cover second 100 kilometres =100/40 = 2(1/2) hours
Time take to cover last 100 kilometres = 100/2 = 2 hours
Total distance covered = 300 km.
Total time taken = 47/6 hours
Thus, average speed = 300/(47/6) = 38.3 km/hr.
ANSWER:B
Question: The age of man is three times the sum of the ages of his two sons.Five years hence,his age will be double of the sum of the ages of his sons.The father's present age is :
A.50 years
B.46 years
C.20 years
D.45 years
Answer: D.45 years
Explanation: Let the sum of present ages of the two sons be x years.
then father's present age =3x years.
(3x+5)=2(x+10)
3x+5=2x+20
x=15.
Hence, father's present age =45 years.
Answer is D
Question: y w v t r p n
Next letter in the series
A.L
B.M
C.N
D.O
Answer: A.L
Explanation: y--w(y-2)
v--t(v-2)
r--p(r-2)
n--l(n-2)
so ans is l
ANSWER:A
Question: On a certain number line, conditions are x<Y<z<U<v. xyzuv>0 Which of the following must be true?
I xy>0
II zu>0
III uv>0
A.I only
B.II only
C.I and II
D.III only
Answer: C.I and II
Explanation: Suppose, for the product to be greater than 0, we can two variables as -ve or four variables can be -ve.
We are given : I xy>0 II yz>0 III uv>0
case 1: x and y can be negative/positive and if they are... we get greater than 0.
case 2: we have zu , then z and u both can be negative/positive and if they are... we get greater than 0.
C
Question: (0.96)(power 3) - (0.1)(power 3)/ (0.96)(power 2) + 0.096 + (0.1)(power 2) is:
A.0.68
B.0.086
C.0.86
D.0.068
Answer: C.0.86
Explanation: Given expression
= (0.96) (power 3) - (0.1)(power 3) / (0.96)(power 2) + (0.96 x 0.1) + (0.1)(power 2)
= a (power 3) - b(power 3) / a(power 2) + ab + b(power 2)
= (a - b)
= (0.96 - 0.1)
= 0.86
Answer is C.
Question: Peta has six times as many dimes as quarters in her piggy bank. She has 21 coins in her piggy bank totaling $2.55
How many of each type of coin does she have?
A.4q & 20d
B.5q & 15d
C.3q & 18d
D.6q & 16d
Answer: C.3q & 18d
Explanation: Let x be the number of quarters. Let 6x be the number of dimes
Since one quarter equals 25 cents, x quarters equals x × 25 cents or 25x cents
Since one dime equals 10 cents, 6x dimes equals 6x × 10 cents or 60x cents
Since one 1 dollar equals 100 cents, 2.55 dollars equals 2.55 × 100 = 255 cents
Putting it all together, 25x cents + 60x cents = 255 cents
85x cents = 255 cents
85x cents / 85 cents = 255 cents / 85 cents
x = 3
6x = 6 × 3 = 18
Therefore Peta has 3 quarters and 18 dimes
correct answer is C)3q & 18d
Question: The average age of M boys is ‘b’ years and of ‘n’ girls ‘c’ years. The average age of all together is?
A.(mb – nc)/ (m + n) years
B.(mb + nc)/ (m - n) years
C.(mb + nc)/ (m + n) years
D.(mb – nc)/ (m - n) years
Answer: C.(mb + nc)/ (m + n) years
Explanation: (mb + nc) / (m+ n)
Answer:C
Question: The average mark of the students of a class in a particular exam is 65. If 5 students whose average mark in that exam is 20 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam.
A.14
B.25
C.35
D.45
Answer: A.14
Explanation: Let the number of students who wrote the exam be x.
Total marks of students = 75 x.
Total marks of (x - 5) students = 90(x - 5)
65x - (5 * 20) = 90(x - 5)
350 = 25x => x = 14
ANSWER:A
Question: The function f is defined for all positive integers m by the following rule. f(m) is the number of positive integers each of which is less than m and has no positive factor in common with m other than 1. If q is any prime, number then f(q)=
A.q-2
B.q-1
C.(q+1)/2
D.(q-1)/2
Answer: B.q-1
Explanation: If not the wording the question wouldn't be as tough as it is now. The GMAT often hides some simple concept in complicated way of delivering it.
This question for instance basically asks: how many positive integers are less than given prime number q which have no common factor with q except 1.
Well as q is a prime, all positive numbers less than q have no common factors with q (except common factor 1). So there would be q-1 such numbers (as we are looking number of integers less than q).
For example: if q=8 how many numbers are less than 8 having no common factors with 8: 1, 2, 3, 4, 5, 6, 7 --> 8-1=7.
Answer: B.
Question: The average age of father and his two sons is 27 years. The difference in age between the two sons is 4 years and five years ago the average age of the two sons was 12 years. What is the present age of the father?
A.34years
B.47years
C.64years
D.27years
Answer: B.47years
Explanation: The average age of father and his two sons is 27 years.
The total age of father and his two sons is 81 years.
five years ago the average age of the two sons was 12 years.
Now the average age of the two sons is 17 years.
Now the total age of the two sons is 34 years.
age of father = 81-34 =47 years
ANSWER:B
Question: A table is bought for Rs.940/- and sold at Rs.1040/- find the loss percentage
A.10% Loss
B.10% Gain
C.20% Loss
D.20% Gain
Answer: B.10% Gain
Explanation: Formula = (Selling price ~ Cost price)/Cost price * 100
= (1040 ~ 940)/940 = 10% gain
B
Question: A salesperson receives a base salary of $1000 per month and a commission of 7.5% of the selling price of each item sold above the first 50 item. If this month she sold 370 items for $150 each, what will her monthly salary be?
A.$1,500
B.$4,600
C.$2,100
D.$2,500
Answer: B.$4,600
Explanation: Ans : 1000+ 7.5 % * 150 * (370-50) = $ 4600
ANSWER:B
Question: In how many different ways can change be provided for a one dollar bill using pennies (1 cent), nickels (5 cents), dimes (10 cents), and quarters (25 cents), if at least one of each type of coin must be included?
A.39
B.42
C.60
D.65
Answer: C.60
Explanation: I. Case I = Four Quarters = this is impossible, because if we already have a dollar in quarters, then we cannot have any other coins. We can't have all four coins represented if we have four quarters.
Case I does not allow any ways.
II. Case II = Three Quarters (75 cents)
This allows for one dime. Two dimes would bring us up to $0.95, and we wouldn't have room for both pennies and nickels.
Subcase 1 = 3 Q, 1 D (85 cents)
1) one nickel (N) and 10 pennies (P)
2) 2 N and 5 P
Case II allows for a total of two ways.
III. Case III = Two Quarters (50 cents)
This allows for 1-4 dimes.
Subcase 1 = 2 Q, 4 D (90 cents)
(1 way) we could have 1 nickel
Subcase 2 = 2 Q, 3 D (80 cents)
(3 ways) we could have 1-3 nickels
Subcase 3 = 2 Q, 2 D (70 cents)
(5 ways) we could have 1-5 nickels
Subcase 4 = 2 Q, 1 D (60 cents)
(7 ways) we could have 1-7 nickels
Case III allows for a total of 16 ways
IV. Case IV = One Quarter (25 cents)
This allows for 1-6 dimes
Subcase 1 = 1 Q, 6 D (85 cents)
(2 ways) we could have 1-2 nickels
Subcase 2 = 1 Q, 5 D (75 cents)
(4 ways) we could have 1-4 nickels
Subcase 3 = 1 Q, 4 D (65 cents)
(6 ways) we could have 1-6 nickels
Subcase 4 = 1 Q, 3 D (55 cents)
(8 ways) we could have 1-8 nickels
Subcase 5 = 1 Q, 2 D (45 cents)
(10 ways) we could have 1-10 nickels
Subcase 6 = 1 Q, 1 D (35 cents)
(12 ways) we could have 1-12 nickels
Case IV allows for a total of 42 ways.
There's no other case, because we have to have at least one quarter and one dime. The total over the cases equals
Total = 0 + 2 + 16 + 42 =60 ways.
OA =(C)
Question: A library has an average of 510 visitors on Sunday and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is?
A.187
B.279
C.280
D.285
Answer: D.285
Explanation: Since the month begins with a Sunday, so there will be five Sundays in the month.
Required average
= [(510 * 5) + (240 * 25)]/30 = 8550/30 = 285.
Answer:D
Question: In aquarium A there are 2 yellow fish and 2 green ones, in aquarium B there are 3 yellow fish and 4 green ones. An aquarium is chosen at random, what is the probability of picking up a green fish out of aquarium A?
A.1/2.
B.3/5.
C.1/4.
D.1/3.
Answer: C.1/4.
Explanation: Probability of picking up one aquarium out of two= 1/2
probability of picking 1 green fish from aquarium A= 2/4=1/2
Hence the desired probability= 1/2*1/2= 1/4
C is the answer
Question: 4,7,15,31,35,19,11,?
A.5
B.6
C.7
D.8
Answer: D.8
Explanation: Find the diff between each digits:
7-4=3
15-7=8
31-15=16
35-31=4
19-35=-16
11-19=-8
i.e. it shows a series 3,8,16,4,-16,-8,-3
that means next digit would be 8.
ANSWER:D
Question: What will be the cost of gardening 1 meter boundary around a rectangular plot having perimeter of 340 meters at the rate of Rs. 10 per square meter ?
A.Rs. 3430
B.Rs. 3440
C.Rs. 3450
D.Rs. 3460
Answer: B.Rs. 3440
Explanation: Explanation:
In this question, we are having perimeter.
We know Perimeter = 2(l+b), right
So,
2(l+b) = 340
As we have to make 1 meter boundary around this, so
Area of boundary = ((l+2)+(b+2)-lb)
= 2(l+b)+4 = 340+4 = 344
So required cost will be = 344 * 10 = 3440
Answer: Option B
Question: TOM traveled the entire 80 miles trip. If he did the first 30 miles of at a constant rate 30 miles per hour and the remaining trip of at a constant rate 50 miles per hour, what is the his average speed, in miles per hour?
A.55 mph
B.50 mph
C.40 mph
D.60 mph
Answer: C.40 mph
Explanation: avg speed = total distance/ total time = (d1+d2)/(t1+t2) = (30+50) / ((30/30)+(50/50)) = 80/2=40mph
C
Question: Find the odd man out.10, 25, 45, 50, 66, 70, 80
A.45
B.50
C.66
D.70
Answer: C.66
Explanation: Each of the numbers except 66 is multiple of 5.
ANSWER :C
Question: The cost of the paint is rs.36.50 per kg. if 1kg of paint covers 16sq.ft, how much will it cost to paint outside of a cube having 8 feet each side
A.Rs.962
B.Rs.672
C.Rs.546
D.Rs.876
Answer: D.Rs.876
Explanation: Explanation:
surface area of a cube= 6 x 82 = 384sq.ft
quantity of paint required=(384/16)=24kg
cost of painting= 36.5 x 24 = Rs.876
Answer: D
Question: In a division sum, the remainder is 5 and the divisor is 3 times the quotient and is obtained by adding 3 to the thrice of the remainder. The dividend is:
A.72
B.76
C.100
D.113
Answer: D.113
Explanation: Diver = (5*3)+3 = 18
3* Quotient = 18
Quotient = 6
Dividend = (Divisor * Quotient) + Remainder
Dividend = (18* 6) + 5 = 113
D
Question: Let Tn be the number of all possible triangles formed by joining vertices of an n-sided regular polygon. If Tn+1−Tn=10Tn+1−Tn=10, then the value of n is
A.5
B.6
C.7
D.8
Answer: A.5
Explanation: We are given that Tn+1−Tn=C3n+1−C3n=10 --> C3n+1−C3n=(n+1)!/3!(n−2)!−n!3!(n−3)!=10 --> (n−1)n(n+1)/6−(n−2)(n−1)n/6=10 (n−1)n=20 --> n=5n=5.
Answer: A.
Or: one additional point gives 10 more triangles, so when we add one point there are 10 different pairs of points which make triangles with that additional point --> C2n=10--> (n−1)n=20 --> n=5
Answer: A.
Question: A firm has 4 senior partners and 6 junior partners. How many different groups W of 3 partners can be formed in which at least one member of the group is a senior partner. (2 groups are considered different if at least one group member is different)
A.48
B.100
C.120
D.288
Answer: B.100
Explanation: What seems to work as well, though its tougher to come up with this solution:
(10*9*8) * 2/3 + (10*9*4)*1/3 = 600. Divided by all possible permutations (=3!) yields 100.
Explanation: For the first spot you have 10 possible canditates, for the 2nd 9. For the 3rd spot you need to differentiate if a senior partner has been picked for one of the first 2 spots or not. If yes, then you can pick one of the 8 remaining guys, so 10*9*8. If no senior partner has been picked yet, you need 10*9*4.
Now you need to weight the 2 cases with the corresponding probabilities: probability of no senior partner being picked in the first 2 draws = 6/10*5/9=1/3, so you weight 10*9*4 with 1/3. For the complementary case (senior partner was picked in the first 2 draws) you just take the complementary prob (1-1/3)= 2/3 and weight 10*9*8 with it.
Now you just need to divide the answer (600) by the number of different positions (=3!) and get W=600/6=100.B
Question: If the value of a piece of land decreases by 10% while the new tax rate on the land represent 110% of the original tax rate, what is the effect on the taxes?
A.a - taxes increase by 10%
B.b- taxes increase by 1%
C.c- there is no change in taxes
D.d- taxes decrease by 1%
Answer: D.d- taxes decrease by 1%
Explanation: Cansider the value of land = 100, Original tax rate 10%, hence tax value = 100*10% = 10.
Decreased value of land = 90, New tax rate = 110% of 10 = 11%, hence tax value = 90*11% = 9.9
10-9.9 = decrease by 1%.
Answer D.
Question: The sum of all the integers k such that –21 < k < 24 is
A.0
B.-2
C.-25
D.-39
Answer: D.-39
Explanation: -20------------------0-----------------23
values upto+23 cancels outwe are left with only -20-19 sum of which is - 39. hence option D.
D
Question: In a recent survey at a local deli, it was observed that 3 out of 5 customers bought a bagel and 5 out of 7 customers bought a coffee. Some customers bought both. If 4 customers are selected, what are the chances that at least 1 customer bought a coffee and a bagel?
A.27/343
B.3/7
C.27/125
D.271/340
Answer: D.271/340
Explanation: Let us take 7*5=35 as the total number of customers. So 7*3=21 customers bought a bagel and 5*5=25 customers bought a coffee.
chances that at least 1 customer bought a coffee and a bagel = 1 - chances that no customer bought a coffee and a bagel
chances that no customer bought a coffee and a bagel= 24/35*23/34*22/33*21/32=69/340
chances that at least 1 customer bought a coffee and a bagel= 1 - 69/340 = 271/340
D
Question: The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ?
A.Rs.6003
B.Rs.6029
C.Rs.1288
D.Rs.6108
Answer: A.Rs.6003
Explanation: Explanation:
Manager's monthly salary Rs. (1600 * 21 - 1500 * 20) = Rs.6003.
Answer: A
Question: If the selling price of 100 articles is equal to the cost price of 40 articles, then the loss or gain percent is:
A.25%
B.40%
C.60%
D.65%
Answer: C.60%
Explanation: Let C.P. of each article be Re. 1.
Then, C.P. of 100 articles = Rs. 100;
S.P. of 100 articles = Rs. 40.
Loss % = 60/100 * 100 = 60%
ANSWER:C
Question: At 15:00 there were 20 students in the computer lab. At 15:03 and every three minutes after that, 3 students entered the lab. If at 15:10 and every ten minutes after that 9 students left the lab, how many students were in the computer lab at 15:44 ?
A.7
B.14
C.25
D.27
Answer: C.25
Explanation: Initial no of students + 3 * (1 + No of possible 3 minute intervals between 15:03 and 15:44) -
8 *(1 + No of possible 10 minute intervals between 15:10 and 15:44)
20 + 3*14 -8 * 4 = 25
C