RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Each of the integers from 1 to 15 is written on the a seperate index card and placed in a box. If the cards are drawn from the box at random without replecement, how many cards must be drawn to ENSURE that the product of all the integers drawn is even?
A.9
B.12
C.11
D.10
Answer: A.9
Explanation: Out of the 15 integers: 8 are odd and 7 are even.
If we need to make sure that the product of all the integers withdrawn is even then we need to make sure that we have at least one even number. In the worst case:
1. we will end up picking odd numbers one by one, so we will pick all 8 odd numbers first
2. 9th number will be the first even number
So we need to withdraw at least 9 numbers to make sure that we get one even number and the product of all the integers picked is even.
So, answer will be 9. (A)
Question: The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages.
A.16, 18, 36
B.16, 28, 36
C.8, 20, 28
D.20, 35, 45
Answer: B.16, 28, 36
Explanation: Answer: Option B
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x - 8) + (7x - 8) + (9x - 8) = 56
20x = 80 => x = 4
Their present ages are 16, 28 and 36 years respectively.
Question: The cash difference between the selling prices of an article at a profit of 4% and 6% is Rs. 3. The ratio of the two selling prices is?
A.52:56
B.52:53
C.52:28
D.52:19
Answer: B.52:53
Explanation: Let C.P. of the article be Rs. x.
Then, required ratio = 104% of x / 106% of x
= 104/106 = 52/53
=52:53
Answer: B
Question: A van takes 6 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
A.50 Kmph
B.60 Kmph
C.70 Kmph
D.80 Kmph
Answer: B.60 Kmph
Explanation: Time = 6
Distence = 540
3/2 of 6 hours = 6 * 3/2 = 9 Hours
Required speed = 540/9 = 60 Kmph
B
Question: Which of the following is the product of two integers whose sum is 15?
A. -42
B. -28
C. 12
D. 26
Answer: D. 26
Explanation: I solved this Question like this,
Let the two integers are x,y
x+y=15 (Given)
xy=? (Needed)
instead of solving this algebraically, Test the Answer choices
D. 26
Do the factorization : (1,26)----> There sum is not 15--eliminate
(2.13)---->There sum is 15 Bingo!!!!
So, my answer is D...
As the answer is in D, it took me very less time to answer the question. but i think this method is be simple and efficient.
Question: In the quiet town ofNothintodothere are 600 inhabitants, 200 are unemployed and 300 are somnambulists. If half of the somnambulists are unemployed, how many are employed and are not somnambulists?
A.50.
B.100.
C.150.
D.250.
Answer: D.250.
Explanation: Total = 600
unemployed=200
employed=600-200=400
som=300
unemployed som = 300/2=150
employed som = 150
employed that are not som = 400-150=250
Answer :D
Question: 617 x 617 + 583 x 583=?
A.720578
B.80578
C.80698
D.81268
Answer: A.720578
Explanation: =(617)^2 + (583)^2
=(600+17)^2 + (600-17)^2
=2[(600)^2+(17)^2]
=2[360000+289]
=2 x 360289 = 720578
Answer is A
Question: 5 men and 12 boys finish a piece of work in 4 days, 7 men and 6 boys do it in 5 days. The ratio between the efficiencies of a man and boy is?
A.1:2
B.2:1
C.2:3
D.6:5
Answer: D.6:5
Explanation: 7M + 6B ------- 5 days
20M + 48B = 35M + 30B
18B = 15M => 5M = 6B
M: B = 6:5
ANSWER D
Question: Both Robert and Alice leave from the same location at 7:00 a.m. driving in the same direction, but in separate cars. Robert drives 50 miles per hour while Alice drives 80 miles per hour. After 5 hours, Alice’s car stops. At what time will Robert’s car reach Alice’s car?
A.2 p.m.
B.3 p.m.
C.4 p.m.
D.8 p.m.
Answer: A.2 p.m.
Explanation: 7:00 am so 4 hours later is 11:00 am
In five hours, Robert will have driven 5*50 = 250 miles
In five hours, Alive will have driven 5*80 = 400 miles
So Robert needs 400-250 = 150 miles do catch Alice up.
So at 50 mph, he will need 3 hours
11:00 am + 3 hours = 2:00 pm
ANS : A
Question: In a game, a player can win by getting 3 consecutive tails in four throws of a coin. What is the probability of winning if the player gets a tail on the first throw?
A.1/4
B.3/4
C.1/2
D.3/8
Answer: A.1/4
Explanation: The only way to win is to get a tail on each of the next two throws.
P(two tails)=(1/2)^2=1/4
The answer is A.
Question: Two trains each of which is 100 m long moving in opposite direction to one another cross each other taking 8 seconds. If speed of one train is twice the speed of other
train find the speed of the faster train.
A.60 km/hr
B.76 km/hr
C.98 km/hr
D.9 km/hr
Answer: A.60 km/hr
Explanation: Explanation:
No explanation is available for this question!
ANSWER:A
Question: Into a room you store 38 black bottles and 4 green bottles, and you turn off the light. If you ask to someone look for 2 bottles without turn on the light, what is the probability of both the selected bottles will be green?
A. 1/574
B. 2/574
C. 1/287
D. 2/287
Answer: D. 2/287
Explanation: There are 4 green bottles in a group of 38 + 4 that is 42. Thus the probability of picking 2 green bottles is: (4/42)(3/41) = 2/287. The correct answer is D.
Question: What is the probability that Company G's advertisement will be one of the first two be shown during the first commercial break?
A. 1/ 225
B. 1 / 30
C. 1 /15
D. 2 / 15
Answer: D. 2 / 15
Explanation: G 1/15 + (14/15) * 1/14 = 2/15 D
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
A.7
B.8
C.9
D.10
Answer: D.10
Explanation: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
Answer: Option D
Question: A and B can finish a work in 16 days while A alone can do the same work in 24 days. In how many days B alone will complete the work?
A.24 days
B.48 days
C.22 days
D.77 days
Answer: B.48 days
Explanation: B = 1/16 – 1/24 = 1/48
=> 48 days
Answer:B
Question: A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs.When the smaller wheel has made 21 revolutions,then the number of revolutions made by the larger wheel is :
A.4
B.9
C.12
D.49
Answer: B.9
Explanation: Solution
Let the required number of revolutions made by larger wheel be x.
Then. More cogs, Less revolutions (Indirect Proporation)
∴ 14: 6 :: 21 : x ⇔ 14 × x = 6 × 21 ⇔ x = (6x21/14)=9. Answer B
Question: A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 75, the runs scored by B are?
A.10
B.18
C.20
D.25
Answer: B.18
Explanation: A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 75 = 18
ANSWER B
Question: If the Average of 10 consecutive integers is 21.5 then the 10th integer is :-
A.15
B.20
C.23
D.26
Answer: D.26
Explanation: The average falls between the 5th and 6th integers,
integer 5 = 21, integer 6 = 22.
Counting up to the tenth integer
we get 26.
ANSWER:D
Question: The current in a river is 3 mph. A boat can travel 21 mph in still water. How far up the river can the boat travel if the round trip is to take 10 hours?
A.69 miles
B.88 miles
C.96 miles
D.102.8 miles
Answer: D.102.8 miles
Explanation: Upstream Speed = 21-3=18mph
Downstream Speed = 21+3 = 24 mph
D/18 + D/24 = 10 hours
Solving for D we get D=102.8
Answer: D
Question: Solve below question 2x + 1 = -23
A.-8
B.-9
C.-12
D.-4
Answer: C.-12
Explanation: 1. Subtract 1 from both sides: 2x + 1 - 1 = -23 - 1 2. Simplify both sides: 2x = -24 3. Divide both sides by 2: 4. Simplify both sides: x = -12 C
Question: From January 1, 2015, to January 1, 2017, the number of people enrolled in health maintenance organizations increased by 11 percent. The enrollment on January 1, 2017, was 45 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 2015 ?
A.38
B.39
C.40
D.41
Answer: D.41
Explanation: Soln:-
11x=45 --> 10/9*x=45 --> x=45*9/10=1500/37=~41.
Answer: D.
Question: What is the probability that when a hand of 5 cards is drawn from a well shuffled deck of 52 cards,
it contains all Queens?
A.192/3790
B.192/379015
C.193
D.Cannot be determined
Answer: B.192/379015
Explanation: nCr = n!/(n-r)!r!
Total number of possible hands = 52C5
52C5 = 2274090
Number of hands with 4 Queens = 4C4 × 48C1
4C4 = 24
48C1 = 48
(other 1 card must be chosen from the rest 48 cards)
Hence P (a hand will have 4 Queens) = (4C4 × 48C1)/52C5 = 192/379015.
Option is B
Question: The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
A.7 : 3
B.7 : 4
C.7 : 5
D.7 : 65
Answer: A.7 : 3
Explanation: Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Answer:A
Question: The product of ages of Harshit and Haritika is 240. If Hritika would have been twice her age she will be 4 years elder to Harshit. What is Haritika's age now?
A.16 yrs
B.24 years
C.12 years
D.10 years
Answer: C.12 years
Explanation: x*y=240
2y=x+4
(2y-4)=x
2y^2-4y-240=0
y=12 years
ANSWER:C
Question: A bag consists of 20 marbles, of which 6 are blue, 9 are red, and the remainder are white. If Lisa is to select a marble from the bag at random, what is the probability that the marble will be red or white?
A.7/10
B.2/4
C.1/4
D.1/8
Answer: A.7/10
Explanation: bag consists of 20 marbles, of which 6 are blue, 9 are red
remainder are white. So, white = 20 - 6 - 9 = 5.
probability that the marble will be red or white = probability that the marble will be red + probability that the marble will be white
probability that the marble will be red or white = 9/20+5/20 = 14/20 = 7/10
Hence, answer will be A.
Question: The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
A.766 m
B.156 m
C.245 m
D.156 m
Answer: C.245 m
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time
= 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2
==> 2(130 + X) = 750 ==> X
= 245 m.
Answer: C
Question: On one side of a coin there is the number 0 and on the other side the number 1. What is the probability that the sum of three coin tosses will be 0 if a 1 is the value of the first coin flip?
A.0/8.
B.1/2.
C.1/5.
D.3/8.
Answer: A.0/8.
Explanation: Assume the coin is unbiased.
Possible sums from 3 tosses = 0,1,2,3
O and 3 are possible in only 1 case each. (0,0,0 or 1,1,1)
1 is possible in 3C1 = 3 cases. (1,0,0; 0,1,0 or 0,0,1) or
similarly, 2 is possible in 3C2=3 cases (1,0,1; 1,1,0; 0,1,1)
So answer will be 0/8. Option A.
Its impossible to get a total value of 0 if a 1 has been showed
Question: In a certain economy, C represents the total amount of consumption in millions of dollars, Y represents the total national income in millions of dollars, and the relationship between these two values is given by the equation C=90+9Y/11. If the total amount of consumption in the economy increases by 99 million dollars, what is the increase in the total national income, in millions of dollars?
A.11
B.22
C.99
D.121
Answer: D.121
Explanation: Just assume y=11 and C=99
Then C=198 and Y=132
So Y increases by 121
ANSWER:D
Question: The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 20 kg. What is the weight of the new person?
A.75
B.65
C.85
D.40
Answer: D.40
Explanation: Total increase in weight = 8 × 2.5 = 20
If x is the weight of the new person, total increase in weight = x−20
=> 20 = x - 20
=> x = 20 + 20= 40
Answer is D.
Question: How much interest can a person get on Rs. 8200 at 17.5% p.a. simple interest for a period of two years and six months?
A.3587.58
B.3587.52
C.3587.5
D.3587.59
Answer: C.3587.5
Explanation: I = (8200 * 2.5 * 17.5)/100 = (8200 * 5 * 35)/(100 * 2 * 2) = Rs. 3587.50.Answer: C
Question: A company wants to spend equal amounts of money for the purchase of two types of computer printers costing $350 and $200 per unit, respectively. What is the fewest number of computer printers that the company can purchase?
A.9
B.10
C.11
D.12
Answer: C.11
Explanation: The smallest amount that the company can spend is the LCM of 350 and 200, which is 1400 for each, which is total 2800.
The number of 1st type of computers which costing $350 = 1400/350 = 4.
The number of 2nd type of computers which costing $200 = 1400/200 = 7.
Total = 4+7 = 11
Answer is C.
Question: Which of the following equations is NOT equivalent to 4x^2 = a^2 - 9 ?
A. 4x^2 + 9 = a^2
B. 4x^2 - a^2 = -9
C. 4x^2= (a + 3)(a - 3)
D. 2x = a - 3
Answer: D. 2x = a - 3
Explanation: 4X^2 = a^2 - 9
The basic rule when dealing with equations is that you can do ANYTHING to both sides of an equation as long as you do it EQUALLY to BOTH sides. Everything gets a bit more complex when you're dealing with variables in the denominator of a fraction and/or inequalities, but neither of those subjects is a factor in this prompt.
Looking at Answer D, we have....
2X = a - 3
While you COULD take the square root of both sides of the original equation, it's important to note that the square root of a^2 - 9 is NOT (a-3).
a^2 - 9 can be factored into (a-3)(a+3), but neither of these parentheses is the square root of a^2 - 9.
You can see the proof when you square either of the two parentheses:
(a-3)^2 = a^2 - 6X + 9
(a+3)^2 = a^2 + 6x + 9
Thus, D is NOT equivalent to the prompt.
Question: The table shows the number of calls received by each of five operators during each of 5 one-hour periods. For which operator was the standard deviation of the numbers of calls received during these 5 periods the least?
A.Operator A: 3, 7, 7, 3, 4
B.Operator B: 4, 5, 5, 6, 5
C.Operator C: 8, 2, 5, 5, 6
D.Operator D: 6, 4, 4, 6, 6
Answer: A.Operator A: 3, 7, 7, 3, 4
Explanation: A
it has 2 numbers right at the average, A has none.
Question: 9.6 , 9.8 , 9.9 , 9.9 , 10.0 , 10.1 , 10.2 , 10.5
The mean and the standard deviation of the 8 numbers shown above is 10 and 0.255 respectively. What percent of the 8 numbers are within 1 standard deviation of the mean?
A.90%
B.75%
C.80%
D.85%
Answer: B.75%
Explanation: Within 1 standard deviation of the mean- means in the range {mean-1*sd; mean+1*sd} = {10-1*0.255; 10+0.255} = {9.745; 10.255}.
From the 8 listed numbers, 6 are within this range so 6/8=75%.
Answer: B.
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
A.10
B.5
C.8
D.6
Answer: A.10
Explanation: C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B's age = 2x = 10 years.
ANSWER A
Question: The population of a town is 1,76,400 . If it increases at the rate of 5% per year, what will be its population 2 years hence ? What was it 2 years ago ?
A.140000
B.180000
C.160000
D.200000
Answer: C.160000
Explanation: Population after 2 years = 176400*[1+(5/100)]^2
=[176400*(21/20)*(21/40)]
= 194481.
Population 2 years ago = 176400/[1+(5/100)]^2
=[716400*(20/21)*(20/21)]= 160000.
Answer is C.
Question: An aeroplane covers a certain distance at a speed of 150 kmph in 2 hours. To cover the same distance in 1 2/3 hours, it must travel at a speed of:
A.1300 kmph
B.160 kmph
C.180 kmph
D.1080 kmph
Answer: C.180 kmph
Explanation: Explanation: Distance = (150 x 2) = 300 km.
Speed = Distance/Time
Speed = 300/(5/3) km/hr. [We can write 1 2/3 hours as 5/3 hours]
Required speed = 300 x 3/5 km/hr = 180 km/hr.
Answer: Option C
Question: Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?
A.7
B.8
C.6
D.5
Answer: B.8
Explanation: Explanation:
1/10 + 1/15 = 1/6 * 4 = 2/3
1 - 2/3 = 1/3
1/10 + 1/15 - 1/x = 1/3
x = 8
Answer:B
Question: Find the cost of fencing around a circular field of diameter 32 m at the rate of Rs.2 a meter?
A.201
B.132
C.772
D.592
Answer: A.201
Explanation: 2 * 22/7 * 16 = 100.5
100.5 * 2 = Rs.201
Answer: A
Question: A computer wholesaler sells ten different computers and each is priced differently. If the wholesaler chooses three computers for display at a trade show, what is the probability (all things being equal) that the two most expensive computers will be among the three chosen for display?
A.15/56
B.3/28
C.1/28
D.1/15
Answer: D.1/15
Explanation: Since, two of the choices are prefixed, we are free to choose 1 from the rest of the 8 avilable. so 8C1 is the numerator.
Total no of ways we can choose 3 from 10 is 10c3, which is the denominator.
So, the probability: 8c1/10c3= 1/15 ans is D.
Question: On a Saturday night, each of the rooms at a certain motel was rented for either $50 or $60. If 10 of the rooms that were rented for $60 had instead been rented for $50, then the total rent the motel charged for that night would have been reduced by 25 percent. What was the total rent the motel actually charged for that night ?
A. $400
B. $800
C. $1,000
D. $1,600
Answer: A. $400
Explanation: Let total rent the motel charge for all rooms =x
If 10 rooms that were rented for 60 $ had instead been rented for 50 $,
then total difference in prices = 10 $ * 10 = 100 $
Total rent the motel charged would have been reduced by 25 %
.25x = 100
=> x= 400
Answer A
Question: In how many ways a committee consisting of 3 men and 2 women can be formed from 9 men and 3 women?
A.A)252
B.B)15
C.C)20
D.D)18
Answer: A.A)252
Explanation: Required number of ways = 9C3*3C2 = 84*3 = 252
Answer is A
Question: In a survey about potential presidential candidates A and B, 32% of the public like A and 50% like B. If the percentage of the public who like one candidate only is twice the percentage of the public who like both candidates, then what is the percentage of the public that like neither?
A.27.5 %
B.35.5 %
C.39.5 %
D.22%
Answer: C.39.5 %
Explanation: Let x be the percentage of people who like both.
Then the percentage of people who like only 1 but not both is 2x.
32% + 50% = 2x + 2(x) because the percentage who like both are counted twice.
Then x = 20.5% and 2x = 41%
100% = 20.5% + 41% + Neither
Neither = 39.5%
The answer is C.
Question: A dealer purchased an article at 3/4 of its list price and sold 50% more than the list price. Find his gain percent?
A.109%
B.160%
C.100%
D.600%
Answer: C.100%
Explanation: MP = 100
CP = 75
SP = 150
------
75 ---- 75
100 ---- ? => 100%
Answer:C
Question: For any positive number x, the function [x] denotes the greatest integer less than or equal to x. For example, [1] = 1, [1.567] = 1 and [1.999] = 1. If k is a positive integer such that k^2 is divisible by 45 and 80, what is the units digit of k^3/4000 ?
A.0
B.1
C.27
D.0
Answer: D.0
Explanation: K=[lCM of 80 and 45] * (any integer)
however minimum value of k is sq.rt of 3^2*4^2*5^2 = 60 * any integer
for value of k(60) * any integer unit value will be always zero .
D
Question: A shopkeeper sells 20% of his stock at 20% profit ans sells the remaining at a loss of 10%. He incurred an overall loss of Rs. 500. Find the total worth of the stock?
A.13500
B.12000
C.12500
D.15000
Answer: C.12500
Explanation: Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 6/5 = 6x/25
The SP of 80% of the stock = 4/5 * x * 0.9 = 24x/25
Total SP = 6x/25 + 18x/25 = 49x/50
Overall loss = x - 24x/50 = x/25
x/25 = 500 => x = 12500
Answer:C
Question: What annual payment will discharge a debt of Rs. 1060 due in 2 years at the rate of 5% compound interest?
A.993.2
B.551.25
C.570.07
D.543.33
Answer: C.570.07
Explanation: Explanation:
Let each installment be Rs. x. Then,
x/(1 + 5/100) + x/(1 + 5/100)2 = 1060
820x + 1060 * 441
x = 570.07
So, value of each installment = Rs. 570.07
Answer: Option C
Question: Two trains of length 210 m and 120 m are 160 m apart. They start moving towards each other on parallel tracks, at speeds 74 kmph and 92 kmph. After how much time will the trains meet?
A.35/10
B.31/10
C.31/10
D.36/10
Answer: A.35/10
Explanation: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (74 + 92)*5/18 = 46.1 mps.
The time required = d/s = 160/46.1= 35/10 sec.
Answer:A
Question: Ayush was born two years after his father's marriage. His mother is five years younger than his father but 20 years older than Ayush who is 15 years old. At what age did the father get married ?
A.20years
B.21years
C.22years
D.23years
Answer: D.23years
Explanation: Explanation:
Ayush's present age = 15 years.
His mother's present age = (15 + 20) years = 35 years.
Ayush's father's present age = (35 + 5) years = 40 years.
Ayush's father's age at the time of Ayush's birth = (40 - 15) years = 25 years.
Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.
Answer: D) 23 year
Question: The present worth of Rs. 242 due in 2 years at 10% per annum compound interest is:
A.Rs. 180
B.Rs. 240
C.Rs. 220
D.Rs. 200
Answer: D.Rs. 200
Explanation: Explanation:
Present worth of Rs. x due T years hence is given by
Present Worth (PW) = x/(1+R/100)^T
Present Worth (PW) = 242/(1+10/100)^2=242/(11/10)^2=Rs. 200
Answer : Option D
Question: A man can row a boat at 10 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?
A.30/83 hours
B.15/13 hours
C.15/4 hours
D.30/19 hours
Answer: C.15/4 hours
Explanation: Speed downstream = 10 + 6 = 16 kmph.
Time required to cover 60 km downstream
= d/s = 60/16
= 15/4 hours.
Answer:C
Question: A man jumps into a river from a overbridge ,at the same time a hat drops in the river which flows with the stream of the water. That man travels 10 minute upstream and returns back where he was asked to catch the hat. He catches hat at a distance of 1000 yard down at a second bridge . Find the speed of the river.
A.50
B.60
C.55
D.70
Answer: A.50
Explanation: Explanation :
Suppose x is the distance travelled by the man in 10 min upstream.
Then
=> x/(v-u) = 10 where v is man's speed and u is river speed)
Total time taken to swim by the man upstream and down stream is equal to the time taken by the
hat to travel 1000 yards with the speed of river :
=> 1000/u = 10 + (x+1000) / (u+v)
=> now substitute x = 10(v-u) and simplify
we will get,
=> 100v = 2uv
=> 2u = 100
=> u = 50 yards per minute
Hence (A) is the correct answer.
Answer : A
Question: The volumes of two cones are in the ratio 1 : 10 and the radii of the cones are in the ratio of 1 : 2. What is the length of the wire?
A.2:5
B.2:7
C.2:1
D.2:3
Answer: A.2:5
Explanation: The volume of the cone = (1/3)πr2h
Only radius (r) and height (h) are varying.
Hence, (1/3)π may be ignored.
V1/V2 = r12h1/r22h2 => 1/10 = (1)2h1/(2)2h2
=> h1/h2 = 2/5
i.e. h1 : h2 = 2:5
Answer:A
Question: How many three letter words are formed using the letters of the word TIME?
A.65
B.62
C.35
D.24
Answer: D.24
Explanation: The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is ⁴P₃ = 4 * 3 * 2 = 24.
Answer:D
Question: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?
A.1.9
B.1.5
C.2.8
D.3.0
Answer: B.1.5
Explanation: 72 --- 9 DS = 8
? ---- 1
45 ---- 9 US = 5
? ---- 1 S = ?
S = (8 - 5)/2 = 1.5
Answer: B
Question: Excluding stoppages, the speed of the bus is 54 kms /hr and with stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
A.9
B.10
C.11
D.12
Answer: B.10
Explanation: By including stoppages, bus will cover 9km less..(54km -45km = 9km)
Excluding stoppages, x = 54 kmph
Including stoppages, y = 45 kmph
Difference, z = 9km
Time taken to cover that 9km(bus stops per hour(60minutes))= z/x(60minutes)
= 9/54(60)
= 1/6(60)
= 10minutes.
ANSWER:B
Question: Of the five numbers in a sequence, the first term is 10,000, and each of the following terms is 70% of the previous term. What is the value range of the five numbers?
A.7,599
B.9,750
C.9,975
D.9,984
Answer: A.7,599
Explanation: 1st number= 10,000
2nd number = 70% of 10,000= 7000
3rd number= 70% of 7000= 4900
4th number = 70% of 4900= 3430
5th number= 70% of 3430= 2401
Range = 10,000-2401=7599
A is the answer