RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The sector of a circle has radius of 21 cm and central angle 150o. Find its perimeter?
A.91.5
B.91.4
C.97
D.91.3
Answer: C.97
Explanation: Perimeter of the sector = length of the arc + 2(radius)
= (150/360 * 2 * 22/7 * 21) + 2(21)
= 55 + 42 = 97 cm
Answer:C
Question: The no. of gift pack bought by Dexter is 1 more than the price, in rupees, of each gift pack. The amount of Rs.380 which Dexter had, fell short of the required amount. What is theamount by which he might have fallen short.
A.20
B.40 rs
C.50
D.60
Answer: B.40 rs
Explanation: Let the price of gift pack be 'aa'
Then number of packs bought =a+1=a+1
Hence total cost is a(a+1)a(a+1)
It is given that 380<a(a+1)380<a(a+1)
If a=19a=19, the total cost =19×20=380=19×20=380
Dexter would not have fallen short, If:
a=20a=20, a(a+1)=420a(a+1)=420
So he would have fallen short by Rs 40.
This is the minimum amount by which he may have fallen short.
B
Question: A man bought a horse and a carriage for Rs. 3000. He sold the horse at a gain of 20% and the carriage at a loss of 10%, thereby gaining 2% on the whole. Find the cost of the horse.
A.2200
B.1800
C.1200
D.1000
Answer: C.1200
Explanation: Let the C.P of the horse be Rs. X, Then, C.P of the carriage = Rs.(3000- x).
20% of x - 10% of ( 3000-x ) =2% of 3000 = 60,
x/5 - ( 3000-x )/10 = 60, 3x - 3000 = 600, 3x =3600, x = 1200.
Hence, C.P of the horse = Rs. 1200
ANSWER:C
Question: A is twice as good a workman as B and they took 10 days together to do the work B alone can do it in.
A.17 days
B.12 days
C.30 days
D.25 days
Answer: C.30 days
Explanation: WC = 2:1
2x + x = 1/10
x = 1/30 => 30 days
ANSWER:C
Question: Amit, Raju and Ram agree to pay their total electricity bill in the proportion 3 : 4 : 5. Amit pays first day's bill of Rs. 50, Raju pays second day's bill of Rs. 55 and Ram pays third day's bill of Rs. 75. How much amount should Amit pay to settle the accounts?
A.Rs. 15.25
B.Rs. 17
C.Rs. 12
D.Rs. 5
Answer: D.Rs. 5
Explanation: EXPLANATION:
Total bill paid by Amit, Raju and Ram = ( 50 + 55 +75 ) = Rs. 180
Let amount paid by Amit, Raju and Ram be Rs. 3x, 4x and 5x respectively.
Therefore, (3x + 4x + 5x ) = 180
12x = 180
x = 15
Therefore, amount paid by,
Amit = Rs. 45
Raju = Rs. 60
Ram = Rs. 75
But actually as given in the question, Amit pays Rs. 50, Raju pays Rs. 55 and Ram pays Rs. 80. Hence, Amit pays Rs. 5 less than the actual amount to be paid. Hence he needs to pay Rs. 5 to Raju settle the amount.
ANSWER IS D
Question: The average weight of a class of 24 students is 35 kg. If the weight of the teacher be included, the average rises by 400 g. The weight of the teacher is
A.45 kg
B.55 kg
C.75 kg
D.15 kg
Answer: A.45 kg
Explanation: Weight of the teacher = (35.4 x 25 - 35 x 24) kg
= 45 kg.
Answer: A
Question: In covering a distance of 90 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:
A.5 km/h
B.8 km/h
C.10 km/h
D.15 km/h
Answer: D.15 km/h
Explanation: Let A's speed be X km/hr.
Then, 90/x - 90/2x = 3
45/x = 3
x = 15 km/hr.
Answer : D
Question: Find the total number of prime factors in the expression (4)^11 x (7)^3 x (11)^2
A.26
B.22
C.25
D.27
Answer: D.27
Explanation: (4)^11x (7)^3 x (11)^2
= (2 x 2)^11 x (7)^3 x (11)^2
= 2^11 x 2^11 x7^3x 11^2
= 2^22 x 7^3 x11^2
Total number of prime factors = (22 +3+ 2) = 27.
Answer is D.
Question: The price of precious stone is directly proportional to square of its weight. what will be the loss incurred if a stone weighing 28gm and costing 28,000 breaks into two pieces whose weights are in the ratio 15:13?
A.13958.58
B.13928.58
C.14000
D.13562.42
Answer: B.13928.58
Explanation: Explanation :
Let price = p,weight = w.
p=k w^2 ---------eq(1) [here k is a constant taken]
As it is given dat price is directly proportional to weight
given w = 28,p = 28000
So from eq(1),k=1000/28
Now the broken pieces are 15gm nd 13gm
By putting the values of w and k in eq(1) we get
p1=8035.71(for w=15)
p2=6035.71(for w=13)
Total cost for broken pieces = (8035.71+6035.71) = 14071.42
So the loss=(28000-14071.42)
=13928.58
Answer : B
Question: If taxi fares were $1.00 for the first 1/5 mile and $0.30 for each 1/5 mile there after, then the taxi fare for a 3-mile ride was
A.$1.56
B.$2.40
C.$3.80
D.$5.20
Answer: D.$5.20
Explanation: In 3 miles , initial 1/5 mile charge is $1
rest of the distance = 3 - (1/5) = 14/5
rest of the distance charge = 14(0.3) = $4.2 (as the charge is 0.3 for every 1/5 mile)
=> total charge for 3 miles = 1+4.2 =5.2
Answer is D.
Question: The average expenditure of a labourer for 5 months was 85 and he fell into debt. In the next 4 months by reducing his monthly expenses to 60 he not only cleared off his debt but also saved 30. His monthly income is
A.69.5
B.71.2
C.60.4
D.62.1
Answer: A.69.5
Explanation: Income of 6 months = (5 × 85) – debt
= 425 – debt
Income of the man for next 4 months
= 4 × 60 + debt + 30
= 270 + debt
∴ Income of 10 months = 695
Average monthly income = 695 ÷ 10 = 69.5
Answer A
Question: Tom divided $360 among his six children for them to use for Christmas gifts. His daughter Kate
added $20 to her portion, then used the money to buy 16 gifts that each cost the same amount.
What was the price of each of Kate’s gifts?
A.$5
B.$10
C.$15
D.$20
Answer: A.$5
Explanation: $360 ÷ 6 = $60 for each child
$60 + $20 = $80 Kate’s money
$80 ÷ 16 = $5 cost of each gift
correct answer A
Question: A, B and C shared the profit in a business in the ratio 5 : 7 : 8. They had partnered for 14 months, 2 months and 7 months respectively. What was the ratio of their investments?
A.10:12:14
B.12:24:28
C.20:22:12
D.5:49:16
Answer: D.5:49:16
Explanation: Explanation :
Ratio in which A,B and C shared the profit = 5 : 7 : 8
Assume that the ratio of their investment = a:b:c
Then 14a : 2b : 7c = 5 : 7 : 8
Good to go, we got the equation. Now it's a matter of time to find a, b and c
14a/2b = 5/7
=> 98a = 10b
=> b = 98a/10 = 49a/5 ---(1)
14a/7c =5/8
=> 2a/c =5/8
=> 16a = 5c
=> c = 16a/5 ---(2)
a : b : c = a : 49a/5 : 16a/5 = 1 : 49/20 : 16/5 = 5 : 49 : 16. Answer : Option D
Question: If a point (x,y) is randomly selected within the square shown in the figure above, (the vertices are on 1,1 1,-1, -1,1 -1,-1) what are
the R odds that x^2+y^2>1?
A.1. pi/4
B.2. R=pi/16
C.3. R=1-pi/4
D.4. 1-pi/16
Answer: C.3. R=1-pi/4
Explanation: area of the square will be 4, and the area of circle with center (0,0) and radius 1 will be pi.
then succesful outcomes = 4 - pi (the area where x2+y2 will be greater than 1)
total outcomes = 4
therefore probability = (4-pi)/4
C
Question: X divided by Y equals 7.28 what is a possible remainder?
A.20
B.21
C.5
D.6
Answer: B.21
Explanation: With the decimal being 28/100, the simplest form is 7/25. If the divisor is a multiple of 25, the remainder must be a multiple of 7. The only number that is so is 21. Answer B.
Question: A car going at 10 miles per hour set out on an 80-mile trip at 9:00 A.M. Exactly 10 minutes later, a second car left from the same place and followed the same route. How fast, in miles per hour, was the second car going if it caught up with the first car at 10:30 A.M.?
A. 45
B. 20
C. 53
D. 55
Answer: B. 20
Explanation: Let Car A = car that starts at 9 AM
Car B = car that starts at 9:10 AM
Time for which car A travels at speed of 10 m per hour = 1.5 hours
Distance travelled by Car A = 10 *1.5 =15 miles
Since Car B catches up Car A at 10:30 , time = 80 mins = 4/3 hour
Speed of Car B = 15/(4/3) = 20 miles per hour
Answer B
Question: Speed of a boat in standing water is 14 kmph and the speed of the stream is 1.2 kmph. A man rows to a place at a distance of 4664 km and comes back to the starting point. The total time taken by him is:
A.784 hours
B.794 hours
C.780 hours
D.684 hours
Answer: A.784 hours
Explanation: Speed downstream = (12 + 1.2) = 13.2 kmph
Speed upstream = (12 - 1.2) = 10.8 kmph
Total time taken=4664/13.2+4664/10.8 = 353 + 431 = 784 hours
ANSWER:A
Question: If the average marks of three batches of 70, 60 and 45 students respectively is 50, 55 and 60, then the average marks of all the students is
A.53.33
B.54.28
C.55
D.57
Answer: B.54.28
Explanation: Sol.
Required average = [70x50 + 60x55 + 45x60 / 70 + 60 + 45]
= [3500 + 3300 + 2700 / 175]
= 9500 / 175 = 54.28.
Answer B
Question: You have 10 users plugged into a hub running 10Mbps half-duplex. There is a server connected to the switch running 10Mbps half-duplex as well. How much bandwidth does each host have to the server?
A.22
B.377
C.26
D.10
Answer: D.10
Explanation: Explanation:
Each device has 10 Mbps	to the server.
Answer: Option D
Question: 70% of the employees in a multinational corporation have VCD players, 83 percent have microwave ovens, 80 percent have ACs and 85 percent have washing machines. At least what percentage of employees has all four gadgets?
A.(a) 15%
B.(b) 5%
C.(c) 10%
D.(d) 18%
Answer: D.(d) 18%
Explanation: so 30% employees don't have VCD devices.
17% employees don't have MO
20% employees don't have ACs
15% employees don't have WM
Summ of employees that don't have some device = 30%+17%+20%+15% = 82% < 100%
So definitely at least 18% employees have 4 devices.
ans: D
Question: A train speeds past a pole in 15 sec and a platform 100 m long in 25 sec, its length is?
A.171
B.150
C.278
D.266
Answer: B.150
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 100)/25 = x/15 => x
= 150 m.
Answer:B
Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
A.10.9 sec
B.14.8 sec
C.10.6 sec
D.10.8 sec
Answer: D.10.8 sec
Explanation: Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5
= 10.8 sec.
Answer: D
Question: Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.
A.1 : 3
B.2 : 3
C.3 : 4
D.4 : 5
Answer: B.2 : 3
Explanation: Explanation:
By the rule of alligation:
Required ratio = 60 : 90 = 2 : 3.
ANSWER IS B
Question: 6x − 18 = 6y
5y + 5x = 15
Which of the following is the number of solutions to the system of equations shown above?
A.More than three
B.Exactly three
C.Exactly two
D.Exactly one
Answer: D.Exactly one
Explanation: 6x − 12 = 6y
=> 6x - 6y = 18
=> x- y =3 -- 1
5y + 5x = 15
=>x + y = 3 -- 2
From equation 1 and 2 , we get
2x = 6
=> x=3
y=0
Therefore , the given system will have Exactly one solution
D
Question: A and B can do a work in 8 days, B and C can do the same work in 12 days. A,B and C together can finish it in 6 days. A and C together will do it in how many days?
A.7
B.6
C.5
D.8
Answer: D.8
Explanation: Let the total units of work be 48.
Units of work completed by A and B in one day = 6.
Units of work completed by B and C in one day = 4
Units of work completed by A, B, and C in one day = 8.
From the above information we get the work completed by A and C in one day is 6 units.
Therefore, the number of days taken by A and C to complete the whole work = 48/6 = 8 days.
ANSWER:D
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is?
A.125
B.150
C.200
D.250
Answer: A.125
Explanation: 3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 1/2 = Rs.125
ANSWER A
Question: A jar contains only three types of objects: red, blue, and silver paper clips. The probability of selecting a red paper clip is 1/10, and the probability of selecting a blue paper clip is 1/2. What is the probability of selecting a silver paper clip?
A. 5/13
B. 1/2
C. 4/10
D. 3/4
Answer: C. 4/10
Explanation: Prob of Red = 1/10
Prob of Blue = 1/2
Prob of Silver = ?
P(Silver) = 1 - P(Red) - P(Blue) ==> 1-1/10-1/2 = 4/10
Ans: C
Question: A jar has 250 marbles. 46 are blue, 56 are red, 75 are green, 25 are yellow, and the remainder, purple.
What percent of the marbles are purple?
A.76%
B.24%
C.30%
D.16%
Answer: B.24%
Explanation: Total number of blue, red, green, and yellow marbles: 46 + 56 + 75 + 25 = 190
Percentage of marbles other than purple: 190/250 = 76%
Percenage of purple marbles: 1-.76=.24=24%
Answer is B
Question: All of the citizens of a country have a three-character or four-character national identification code that is created using the 26 letters of the alphabet and the 10 digits from 0 to 9. What is the maximum number of citizens who can be designated with these codes?
A.36^7
B.37(36^3)
C.35(36^4)
D.35(36^3)
Answer: B.37(36^3)
Explanation: The number of possible 3-digit codes is 36^3.
The number of possible 4-digit codes is 36^4.
The total sum is 36^3 + 36^4 = 36^3(1+36) = 37(36^3)
The answer is B.
Question: Find the simple interest on Rs. 64,000 at 16 2/3% per annum for 9 months.
A.s.8500
B.s.8000
C.s.7500
D.s.7000
Answer: B.s.8000
Explanation: P = Rs.64000,R = 50/3% p.a and T = 9/12 years = 3/4years.
S.I. = (P*R*T)/100 = Rs.(64,000*(50/3)*(3/4)*(1/100))
= Rs.8000
Answer is B.
Question: A man two flats for $675958 each. On one he gains 15% while on the other he loses 15%. How much does he gain or lose in the whole transaction?
A.2%
B.2.25%
C.3.12%
D.4.65%
Answer: B.2.25%
Explanation: In such a case there is always a loss
Loss% = (15/10)^2 = 9/4 = 2.25%
Answer is B
Question: The nth term in a certain sequence is defined for positive integer n as 1+(−1)(n(n+1)/2)^2. What is the total of the first 64 terms of this sequence?
A.−164
B.0
C.16
D.32
Answer: D.32
Explanation: sequence goes like this 0 , 1, 0 , 1, 0 ...... 1(64th term)
sum of 64 terms = 32
ANSWER:D
Question: For which of the following functions is f(w) = f(−w) for all values of w ?
A.f(x) = x^3 + 3
B.f(x) = −x
C.f(x) = 2x + 3
D.f(w) = −w^2 + 2
Answer: D.f(w) = −w^2 + 2
Explanation: f(w) = f(−w)
The above is a property of an even function .
f(w) = f^(n)
f(w) = f(−w) will hold when n is an even integer .
The only case when w is even is option D
Answer D
Question: Given that a is the average (arithmetic mean) of the first eight positive multiples of six and b is the median of the first twelve positive multiples of six, what is the ratio of a to b?
A.3:4
B.10:13
C.5:6
D.9:13
Answer: D.9:13
Explanation: The first nine positive multiples of six are {6, 12, 18, 24,30, 36, 42, 48}
The first twelve positive multiples of six are {6, 12, 18, 24, 30,36,42, 48, 54, 60, 66, 72}
Both sets are evenly spaced, thus their median=mean:
a=(24+30)/2=27 and b=(36+42)/2=39 --> a/b=27/39=9/13.
Answer: D.
Question: Grace packed 5 pairs of shoes, 3 pairs of pants, 8 shirts, and 3 jackets for her business trip. If an outfit consists of one of each item of clothing except shirts, of which she will wear 2, how many different outfits C can does Grace have available during her trip?
A. 2,520
B. 1,260
C. 620
D. 360
Answer: B. 1,260
Explanation: The idea is to multiply the number of possibilities for each item of clothing with the different items. For the shirts you essentially choose 2 out of 8 so you should use the combination forumla (don't know how to use math symbols here).
This gives you C=5 x 3 x 28 x 3 = 1'260. Hence, solution B is correct.
Question: Line D passes through point (-2,5), and the product of its x-intercept and y-intercept is positive. Which of the following points could be on line D?
A.(5,10)
B.(-3,2)
C.(-1,7)
D.(-1,2)
Answer: D.(-1,2)
Explanation: The slope of the line is -ve, the only point that makes the slope -ve is D.
(5 - 2)/(-2 + 1) = 3/-1
Answer - D
Question: Find the average (arithmetic mean) of x and y if the average of x, y, and 5 is 20 more than the average of x, y, 5, and 15.
A.110
B.120
C.130
D.140
Answer: D.140
Explanation: consider the statement 50 is 20 more than 30: 50 = 30+20
similarly
the average of x, y, and 5 = (the average of x, y, 5, and 15) + 20
(x+y+5)/3 = (x+y+5+15)/4 + 20
(x+y+5)/3 = (x+y+20)/4 + 20
(x+y+5)/3 = (x+y+20)/4 + 80/4
(x+y+5)/3 = (x+y+20+80)/4
(x+y+5)/3 = (x+y+100)/4
cross multiply
4(x+y+5) = 3(x+y+100)
4x+4y+20 = 3x+3y+300
4x-3x +4y-3y = 300 - 20
x + y = 280
so
(x+y)/2 = 280/2
(x+y)/2 = 140
i.e the average of x and y is 140
D
Question: The number 97215*6 is completely divisible by 11. What is the smallest whole number in place of * ?
A.3
B.4
C.1
D.2
Answer: A.3
Explanation: From the above given "Divisibility by 11 rule", it is clear that
if 97215*6 is divisible by 11, then (9 + 2 + 5 + 6) - (7 + 1 + *) is divisible by 11
=> 22 - (8 + *) is divisible by 11
=> (14 - *) is divisible by 11
The smallest whole number which can be substituted in the place of * to satisfy the
above equation is 3 such that 14 - 3 = 11 and 11 is divisible by 11.
Answer is A
Question: The sale price at which a store sells an article is 25% more than its cost price. If the sale price is an integer, which of the following cannot be the cost price?
A.$20
B.$37
C.$48
D.$60
Answer: B.$37
Explanation: Sale Price = (5/4)*(Cost Price)
If the sale price is an integer, then the cost price must be divisible by 4.
The answer is B.
Question: In how many ways can a committee consisting of three men and four women be formed from a group of six men and seven women?
A.⁶C₄ ⁷C₃
B.⁶C₃ ⁷C₅
C.⁶C₃⁷C₄
D.⁷C₅ ⁶C₄
Answer: C.⁶C₃⁷C₄
Explanation: The group contain six men and seven women
Three men can be selected from six men in ⁶C₃ ways.
Four women can be selected from seven women in ⁷C₄ ways.
Total number of ways = (⁷C₄)(⁶C₃).
ANSWER:C
Question: There are 5 physics books and 1 chemistry book on shelf P and 4 physics books on shelf Q. One book is moved from shelf P to shelf Q. A student picks up a book from shelf Q. What is the probability that the chemistry book is taken by the student?
A.1/40
B.1/35
C.1/30
D.1/25
Answer: C.1/30
Explanation: P(a chemistry book is moved to shelf Q) = 1/6
P(a chemistry book is then chosen from shelf Q) = 1/5
P(the student takes a chemistry book) = 1/6 * 1/5 = 1/30
The answer is C.
Question: A man gets a simple interest of Rs.600 on a certain principal at the rate of 5% p.a in two years. Find the compound interest the man will get on twice the principal in two years at the same rate?
A.s.1000
B.s.1056
C.s.1150
D.s.1230
Answer: D.s.1230
Explanation: Let the principal be Rs.P
S.I at 5% p.a in 2 years on Rs.P = Rs.600
(P)(2)(5)/100 = 600
P = 6000
C.I on Rs.2P i.e., Rs.12000 at 5% p.a in two years
=12000{ [1 + 5/100]^2 - 1}
= 12000(41/ 400)
= Rs.1230
Answer:D
Question: A rower can row upstream at 20 kph and downstream at 34 kph. What is the speed of the rower in still water?
A.26
B.27
C.28
D.29
Answer: B.27
Explanation: Let V be the rower's speed in still water.
Let S be the speed of the current in the stream
V-S = 20
V+S = 34
When we add the two equations, we get: 2V = 54
Then V = 27 kph.
The answer is B.
Question: The diagonals of a rhombus are 15 cm and 20 cm. Find its area?
A.277
B.266
C.150
D.288
Answer: C.150
Explanation: 1/2 * 15 * 20 = 150
Answer: C
Question: 8+88+888+.....+8888........8888. There are 21 “8” digits in the last term of the series.
Find the last three digits of the sum.
A.384
B.584
C.784
D.968
Answer: D.968
Explanation: 21*8=168 carry 16
20*8=160+16=176 carry 17
19*8=152+17=169
the value is 968
ANSWER:D
Question: Find 12 ×× 19
A.238
B.228
C.208
D.277
Answer: B.228
Explanation: Mentally imagine this number as (10 + 2 ) ×× 19 = 190 + 38 = 228.
Answer:B
Question: The average age of a class of 19 students is 20 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher?
A.39
B.41
C.40
D.42
Answer: C.40
Explanation: Total age of all students =19Ã—20
Total age of all students + Age of the teacher =20Ã—21
Age of the teacher
=20Ã—21âˆ’20Ã—19=20(21âˆ’19)=20Ã—2=40
Answer is C.
Question: The distance between a sports store and a recreation center is approximately 3.34 x 10^5 inches. Which of the following is closest to the distance between the sports store and a recreation center, in kilometers? (1 kilometer is approximately 3.9 x 10^4 inches.)
A.9.33
B.8.98
C.8.56
D.9.21
Answer: C.8.56
Explanation: We know that 1 kilometer = 3.9x10^4 inches. Therefore, we now have a ratio of (1 kilometer/3.9x10^4 inches).
We also know that the distance between the sports store and a recreation center is approximately 3.34x10^5 inches. To convert inches to kilometers, we need to multiply 3.34x10^5 inches by the ratio we just found out.
kilometers = 3.34x10^5 inches x (1 kilometer/3.9x10^4 inches) [note: "inches" cancel out, leaving us with just km]
km = 3.34x10^5/3.9x10^4 km
km = 8.56 km
Therefore, we can see that the closest answer is C.
Question: If 25% of a class averages 80% on a test, 50% of the class averages 65% on the test, and the remainder of the class averages 90% on the test, what is the overall class average?
A.60%
B.65%
C.70%
D.75%
Answer: D.75%
Explanation: This question is a Weighted Average question with a series of dependent variables.
The remaining portion of the class represents 100% - 25% - 50% = 25% of the class
Converting the portions of the class population to decimal weights, we find:
Class Average = 0.25x80 + 0.50x65 + 0.25x90 = 75
The class average is 75%
Final Answer
D) 75%
Question: Two numbers x and y are such that the sum of 3% of x and 4% of y is one-third of the sum of 2% of of x and 8% of y. Find the ratio of x : y.
A.3:8
B.6:7
C.4:7
D.2:5
Answer: C.4:7
Explanation: Explanation :
Solution: 3% of x+ 4% of y=1/3(2% of x+8% of y)
3x/100 + 4y/100 = 2x/300 + 8y/300
(3x+4y)3 = 2x+8y
7x = 4y
x/y = 4/7
Answer : C
Question: How many five digit numbers can be formed using digits 0,1,2,3,4,5, Which are divisible by 7, without any of the digits repeating?
A.96
B.98
C.100
D.81
Answer: A.96
Explanation: 0,1,2,3,4,5
One digit will have to remain out for all 5 digit numbers;
if 0 is out; Leftover digits will be 1,2,3,4,5 = Sum(1,2,3,4,5)=15.Ignore
if 1 is out; Leftover digits will be 0,2,3,4,5 = Sum(0,2,3,4,5)=14. divisible by 7)
if 3 is out; Leftover digits will be 0,1,2,4,5 = Sum(0,1,2,4,5)=12. Ignore
if 4 is out; Leftover digits will be 0,1,2,3,5 = Sum(0,1,2,3,5)=11. Ignore
if 5 is out; Leftover digits will be 0,1,2,3,4 = Sum(0,1,2,3,4)=10. Ignore
Total count of numbers divisible by 7 = 4*4! = 96
A
Question: 20 people going to one temple. (some time waste data) They want Rs. 20. For men-Rs.3, women-Rs.2, children-50 paisa. How much money spends for men, children and women?
A.3,7,10
B.4,7,10
C.5,7,10
D.6,7,10
Answer: A.3,7,10
Explanation: M=1 => 1*3= 3
W=5 => 5*2= 10
C=14 => 14*.5= 7
1+5+14= 20 & 3+10+7=20
ANSWER:A
Question: A land owner needs to fence his semicircular land leaving an opening of length of 3m for access. The radius of the semicircular plot is 7m. How long would be the fence in meters?
A.22
B.33
C.36
D.44
Answer: B.33
Explanation: Perimeter of the semicircle= Ï€xD/2 + D
= Ï€x7 + 14
=22+14 = 36m
Length of the fence= 36-3=33m
Answer: B
Question: A man has Rs. 560 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
A.45
B.60
C.75
D.105
Answer: D.105
Explanation: Let number of notes of each denomination be x.
Then x + 5x + 10x = 560
16x = 560
x = 35.
Hence, total number of notes = 3x = 105.
Answer = D
Question: What is the smallest of six consecutive odd integers whose average (arithmetic mean) is x + 2?
A.x - 5
B.x - 3
C.x - 1
D.x
Answer: B.x - 3
Explanation: Assume the integers to be
n - 5, n - 3, n- 1, n+1, n + 3, n + 5
AM = 6n/6 = n
Given n = x + 2
Therefore, smallest term = n - 5 = x + 2 - 5 = x - 3
Correct Option: B
Question: The grade point average of one third of the classroom is 60; the grade point average of the rest is 66. What is the grade point average of the whole class?
A.55
B.56
C.64
D.65
Answer: C.64
Explanation: Let n=total students in class
total points for 1/3 class=60n/3=20n
total points for 2/3 class=66*2n/3=44n
total points for whole class=20n+44n=64n
64n total class points/n total students=64 grade point average for total class
Answer : C
Question: If half of 5 were 3, that would one-third of 10 be
A.2
B.4
C.6
D.8
Answer: B.4
Explanation: Explanation:
Half of 5 is 2.5. But given as 3. So take 1/2 of 5x = 3 ⇒ x = 6/5
Now 1/3 (10x) = 1/3 × 10 × 6/5 = 4.
Answer: B
Question: An article is bought for Rs.675 and sold for Rs.900, find the gain percent?
A.33 1/7%
B.33 2/3%
C.33 1/3%
D.37 1/3%
Answer: C.33 1/3%
Explanation: 675 ---- 225
100 ---- ? =>
=33 1/3%
Answer:C