RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: a, b are positive integers. The remainder of a to be divided by 8 is 5 and the remainder of b to be divided by 6 is 2.
Which is possible to be the remainder of a*b to be divided by 48
A.a) 10
B.b) 6
C.c) 8
D.d) 12
Answer: A.a) 10
Explanation: Two ways to do it...
a=8x+5..
b=6y+2..
1) convenient way..
Take x and y as 0, and you will get a*b as 5*2=10
Answer : A
Question: A and B complete a work in 8 days. A alone can do it in 14 days. If both together can do the work in how many days?
A.5 days
B.8 days
C.6 days
D.3.15 days
Answer: A.5 days
Explanation: 1/8 + 1/14 = 11/56
56/11 = 5 days
Answer: A
Question: Here the sum of the series is 4+8+12+16+….. =612. find how many terms are there in the series?
A.15
B.19
C.17
D.14
Answer: C.17
Explanation: Solution: This is an A.P. in which a=4, d=4 and Sn=612
Then, n/2[2a+(n-1)d]=612 => n/2[2*4+(n-1)*4]=612
=> 4n/2(n+1)=612
=> n(n+1)=306
=> n^2+n-306=0
=> n^2+18n-17n-306=0
=> n(n+18)-17(n+18)=0
=> (n+18)(n-17)=0
=> n=17.
Number of terms=17.
Answer C
Question: I have two 10 paise coins. If 4 If 4/5 of what I have is 8is 8/9 of what you have, how much do you have?
A.13
B.17
C.11
D.18
Answer: D.18
Explanation: D
18 paise.
Question: The amount of electrical current that flows through a wire is inversely proportional to the resistance in that wire. A wire originally carries 4 amperes of electrical current. Then the resistance is reduced to one-seventh of its original value. How many amperes of electrical current will flow through the wire?
A.4/7
B.7
C.14
D.28
Answer: D.28
Explanation: Given that, I∝1/R, I*R is a constant value.
I1*R1 = I2*R2
I1*R1 = I2*R1/7
I2 = 7*I1 = 28 amperes
The answer is D.
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 12, the how old is B?
A.10 years
B.4 years
C.6 years
D.15 years
Answer: B.4 years
Explanation: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 12
5x = 10
x = 2.
Hence, B's age = 2x = 4 years.
B)
Question: In how many different ways can the letters of the word "LEADING" be arranged in such a way that the vowels always come together.
A.W8
B.789
C.279
D.277
Answer: D.277
Explanation: Answer:D
Question: A car salesman earns a base salary of $800 per month plus a commission of $200 for each car he sells. If the car salesman earned $1600 in May, how many cars does he need to sell in June in order to double his May earnings?
A.10
B.11
C.12
D.13
Answer: C.12
Explanation: 800+200x=3200
x=12 cars.
The answer is C.
Question: A dishonest dealer professes to sell his goods at Cost Price but still gets 20% profit by using a false weight. What weight does he substitute for a kilogram?
A.833 1/0
B.833 1/3
C.833 1/21
D.833 1/2
Answer: B.833 1/3
Explanation: If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.
If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm ------ 100 gm
1000 gm ------ ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams.
Answer: B
Question: In an election between two candidates, 10% of votes are were declares invalid. First candidate got 9000 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:
A.9000
B.98000
C.50000
D.11000
Answer: C.50000
Explanation: 100 % - 10 % = 90 %
54%-36%=18%
18% ------> 9000 ( 18 × 500 = 9000)
100% -------> 50000 votes (100 × 500 = 50000)
C
Question: Reeya obtained 40, 60, 70, 80 and 80 out of 100 in different subjects, What will be the average
A.66
B.75
C.80
D.85
Answer: A.66
Explanation: Explanation:
(40+60+70+80+80 / 5)=66
Option A
Question: Convert 0.38 in to a vulgar fraction ?
A.18/50
B.16/50
C.17/50
D.19/50
Answer: D.19/50
Explanation: Answer
0.38 = 38/100 = 19/50
Correct Option: D
Question: A worker is paid x rupees for painting every 25 metres of a wall and y rupees for painting every extra metre. During one week, he painted 25 metres on Monday, 50 metres on Tuesday, 25 metres on Wednesday, 45 metres on Thursday and 25 metres on Friday. What is his average daily earning rupees for the five day week?
A.x + (8/5)y
B.(5x + 9y)/5
C.x + 9y
D.None of these
Answer: C.x + 9y
Explanation: Explanation :
On Monday, the payment = Rs x
On Tuesday, the payment = Rs (x + 25y)
On Wednesday, the payment = Rs x
On Thursday, the payment = Rs (x +20y)
On Friday, the payment = Rs x
Average daily earning during the five-day week = (5x + 45y)/5
= x + 9y
Answer : C
Question: A brick measures 20 cm * 10 cm * 7.5 cm how many bricks will be required for a wall 25 m * 2 m * 0.75 m?
A.24000
B.23000
C.22000
D.25000
Answer: D.25000
Explanation: 25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x
25 = 1/100 * x => x = 25000
ANSWER:D
Question: If there are 200 questions in a 3 hr examination. Among these questions are 20 type A problems, which requires twice as much as time be spent than the rest of the type B problems. How many minutes should be spent on type A problems?
A.72 min
B.62 min
C.70 min
D.32.72727 min
Answer: D.32.72727 min
Explanation: x=time for type B prolems
2x=time for type A problem
total time=3hrs=180min
180x+20*2x=180
x=180/220
x=0.818182
time taken for type A problem=20*2*0.818182=32.72727min
ANSWER:D
Question: A runs twice as fast as B and gives B a start of 42m.How long should the racecourse be so that A and B might reach in the same time?
A.75 m.
B.80 m.
C.84 m.
D.100 m.
Answer: C.84 m.
Explanation: ratio of speeds of a and b is 2:1
b is 42m away from a but we know that a covers 1 meter(2-1) more in every second than b
the time taken for a to cover 42m is 42/1=42m
so the total time taken by a and b to reach =2*42=84m
ANSWER:C
Question: The speed of a boat in still water in 22 km/hr and the rate of current is 5 km/hr. The distance travelled downstream in 24 minutes is:
A.10.6
B.10.2
C.10.8
D.10.4
Answer: C.10.8
Explanation: Speed downstream = (22 + 5) = 27 kmph
Time = 24 minutes =24/60 hour = 2/5 hour
Distance travelled = Time × speed =2/5×27 = 10.8 km
Answer is C.
Question: A car that has an original value of $52,500 depricates $10000 in the first year and there original cost per year. What is its value after 8 years?
A.$12100
B.$13100
C.$14100
D.$15100
Answer: B.$13100
Explanation: 1st year depreciation amount = 10000
next 7 year's depreciation amount = 7 * 8% original cost price
= 7*8/100 * 52500
=29400
Total depreciation amount = 39400
Value after 8 years = $13100
ANSWER:B
Question: If a computer program generates three-digit odd numbers using the numbers 9, 7, 0, 6, and 1, and the digits can be repeated, what is the probability that the number formed from the program is a multiple of three?
A.1/3
B.1/4
C.1/5
D.1/6
Answer: A.1/3
Explanation: A
Question: Last year the range of the annual sales of the 100 lamps at Company X was $30,000. If the annual sale of each of the 100 lamps this year is 10 percent greater than it was last year, what is the range of the annual sales of the 100 lamps this year?
A. $27,000
B. $30,000
C. $33,000
D. $36,000
Answer: C. $33,000
Explanation: let the lowest sale be x.
Therefore, highest sale is x +30000.
Now sale of each lamp is increased by 10%.
Therefore the sale will remain arranged in the same order as before.
or Lowest sale = 1.1x and Highest = 1.1 * (x+30000)
or Range = highest - lowest = 1.1 * (x+30000) - 1.1x
= 33000, Hence, C
Question: If the sum of two positive integers is 12 and the difference of their squares is 48, what is the product of the two integers?
A.32
B.119
C.128
D.135
Answer: A.32
Explanation: Let the 2 positive numbers x and y
x+ y = 12 -- 1
x^2 - y^2 = 48
=> (x+y)(x-y)=48 -- 2
Using equation 1 in 2 , we get
=> x-y = 4 -- 3
Solving equation 1 and 3 , we get
x= 8
y= 4
Product = 8*4 = 32
Answer A
Question: The output of a factory was increased by 15% to keep up with rising demand. To handle the holiday rush, this new output was increased by 20%. By approximately what percent would the output now have to be decreased in order to restore the original output?
A.20%
B.27%
C.30%
D.32%
Answer: B.27%
Explanation: The original output increases by 15% and then 20%.
Total % change = a + b + ab/100
Total % change = 15 + 20 + 15*20/100 = 38%
Now, you want to change it to 0, so,
0 = 38 + x + 38x/100
x = -38(100)/138 = 27% approximately
Answer is B
Question: In a certain archery competition, points were awarded as follows: the first place winner receives 11 points, the second place winner receives 7 points, the third place winner receives 5 points and the fourth place winner receives 2 points. No other points are awarded. John participated several times in the competition and finished first, second, third, or fourth each time. The product of all the points he received was 53900. How many times did he participate in the competition?
A.7
B.8
C.9
D.10
Answer: A.7
Explanation: 53900 = 2*2*5*5*7*7*11
John participated 7 times.
The answer is A.
Question: In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is
A.9 years
B.19 years
C.29 years
D.39 years
Answer: D.39 years
Explanation: Solution
Let B's present age	= x years.
Then, A's present age	‹=› (x + 9) years.
∴(x + 9) + 10 = 2 (x - 10)
‹=› x + 19 = 2x - 20
‹=› x = 39.
Answer D
Question: Let x and y be positive integers, and r and s be single-digit positive integers. If x/y = r.sss, where the bar below the s indicates that the decimal repeats infinitely, which of the following CANNOT be true?=
A. y = 1.2 × 10^a, where a is a positive integer.
B. y = 1.5 × 10^b, where b is a positive integer.
C. y = 1.8 × 10^c, where c is a positive integer.
D. y = 2.5 × 10^d, where d is a positive integer.
Answer: A. y = 1.2 × 10^a, where a is a positive integer.
Explanation: Concentrating only on the answer choices, only option D is not a multiple of 3. The rest of them are multiples of 3, thats a common trend in other answer choices. With this logic can we say that Option A is correct answer?
Question: A cycle is bought for Rs.900 and sold for Rs.1170, find the gain percent?
A.27%
B.20%
C.80%
D.30%
Answer: D.30%
Explanation: 900 ---- 270
100 ---- ? => 30%
Answer: D
Question: A person has three children with at least one boy. Find the probability of having at least two boys among the children.
A.3/4
B.1/3
C.2/3
D.1/4
Answer: A.3/4
Explanation: Explanation :
The event is occuring under the following situations:
Second is a boy and third is a girl OR
Second is a girl and third is a boy OR
Second is a boy and third is a boy
This will be represented by: (1/2) x (1/2) + (1/2) x (1/2) + (1/2) x (1/2) = 3/4
Answer : A
Question: P software has coding line 5% more than N, N software has coding line 4/20 more than M. M software has 80 lines of coding. find P lines.
A.101
B.107
C.108
D.109
Answer: A.101
Explanation: M s/w has 80 line of code
N s/w has = 80+80*4/20= 96 line of code
P s/w 5% more N' code 96+4.8=100.8
or
101 line of code
ANSWER:A
Question: Rs.8000 become Rs.9261 in a certain interval of time at the rate of 5% per annum of C.I. Find the time?
A.2 years
B.6 years
C.8 years
D.3 years
Answer: D.3 years
Explanation: 9261 = 8000(21/20)N
(21/20)3
= (21/20)N
=> N = 3
Answer:D
Question: From the set of numbers {p, t, u, v, w, x, y, z}, how many different combinations can we have without the t or the u in them? Ex:. (x,y), (x), (w,z,y,x), etc... and note that (x,y)=(y,x)
A.16
B.31
C.32
D.63
Answer: D.63
Explanation: Any letter (p, v, w, x, y, z) can be included or not.
Thus there are 2^6 combinations - 1 empty combination = 63 combinations
The answer is D.
Question: Which of the following is always true for any real number 'a' and 'b'?
A.|ab| = |a||b|
B.|a/b| = |a|/|b|
C.|-ab| < |a||b|
D.|ab| > |a/b|
Answer: A.|ab| = |a||b|
Explanation: This one is obvious if you know how absolute value works. One of the fundamental principles of absolute value is multiplicativeness, which holds that for absolute values, f(ab) = f(a) f(b). Thus the answer is A.
Question: The simple interest on a sum of money will be Rs.600 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year?
A.8981
B.3799
C.1200
D.2693
Answer: C.1200
Explanation: P --- 10 ---- 600
P --- 5 ----- 300
3P --- 5 ----- 900
------
=> 1200
Answer: C
Question: A field is 90 metre long and 50 metre broad. A 25 metre long, 20 metre broad and 4 metre deep tank dug in the field and the earth taken out is spread evenly over the remaining field. How much the level of field will rise?
A.0.5 metre
B.0.3 metre
C.0.8 metre
D.0.6 metre
Answer: A.0.5 metre
Explanation: Area of field = 90 x 50 = 4500 m2
Area of field dug out = 25 x 20 = 500 m2
Therefore, Area of remaining field = 4500 m2 - 500 m2 = 4000 m2
Volume of the earth dug out = 25 x 20 x 4 = 2000 m3
Therefore, Field will rise by 2000/4000 = 0.5 metre
Answer A
Question: A shopkeeper purchased 70 kg of potatoes for Rs.420 and sold the whole lot at the rate of Rs 6.50 per kg .What will be his gain percent?
A.8 1/9
B.8 1/1
C.8 1/3
D.8 1/7
Answer: C.8 1/3
Explanation: Explanation:
Price per 1 kg = 4207042070 = Rs.6.
Profit per 1 kg = Rs.6.5 – Rs.6 = Rs.0.5
Profit for 70 kg = 0.5 × 70 = Rs.35
Gain % = 3542035420 × 100= 8.33% = 8 1/3
Answer: C
Question: Perimeter of rhombus is equal to perimeter of circle. Longest distance between two points in rhombus is 80. Area of rhombus is 2400 cm^2. Find area of circle.
Options: 10000, 62500, 2500, one more I don't Remember.
A.3284.28678
B.3184.28678
C.3084.28678
D.4184.28678
Answer: B.3184.28678
Explanation: Let Diagonals of Rhombus are p,q and side is a .
Let Longest side is one of the p and q, let its p=80;
Area of a Rhombus is A =p*q/2
A=2400
2400=80 *q /2
4800=80q=> q=60
4a^2 =60^2 + 80^2
4a^2=10,000=> a=>50
Given: Perimeter of R = Perimeter of Circle
4a = 2*3.14* r=> r=31.84
Area of circle = 3.14* r^2 = 3184.28678
ANSWER:B
Question: The simple interest at y% for y years will be $y on a sum of
A.$ (1000)/x
B.$(100)x^2
C.$ x
D.$ (100)/y
Answer: D.$ (100)/y
Explanation: Principal =$(100*y)/(y*y)=$(100/y).
Answer is D
Question: The simple interest on a sum of money is 4/9 of the principal and the number of years is equal to the rate percent. Find the rate and the time?
A.6 2/3%
B.6 2/8%
C.6 7/3%
D.9 2/3%
Answer: A.6 2/3%
Explanation: 4/9 P = (P*R*R)/100
R = 20/3
= 6 2/3%
Answer:A
Question: If 20 men take 15 days to to complete a job, in how many days can 20 men finish that work?
A.15
B.16
C.17
D.18
Answer: A.15
Explanation: Ans. 15 days
Question: When a number is divided by 3 &then multiply by 12 the answer is 9 what is the no.?
A.4.5
B.5
C.2.25
D.5.7
Answer: C.2.25
Explanation: if $x$ is the number, x/3 * 12 = 9
=> 4x = 9
=> x = 2.25
C
Question: Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is:
A.17523
B.2788
C.1750
D.2787
Answer: C.1750
Explanation: Explanation:
C.I.= Rs.[4000*(1+10/100)^2-4000]
=Rs.840
sum=Rs.(420 * 100)/3*8=Rs.1750\
Answer: C) Rs,1750
Question: A certain research group plans to create computer models of x% of a list of 10,000 bacterial species known to inhabit the human body. After a budget cut, the group finds it must reduce this selection by (x − 5)%. In terms of x, how many species of bacteria will the group be able to model?
A.x*x – 5x
B.(x)(105 – x)
C.(100)(105 – x)
D.(100)(95 – x)
Answer: B.(x)(105 – x)
Explanation: Let's say that x = 10
So 10% of 10,000 = 1,000 types of bacteria
After the budget cuts, this 1,000 is reduced by (10-5)% = 5%
5% of 1,000 = 50
1,000 - 50 = 950
Plug x=10 into the answers and find 950.
Answer:B
Question: 5, -28, 2, -31....
A.1
B.3
C.2
D.4
Answer: A.1
Explanation: 5 - 33 = -28
-28 +30 = 2
2 - 33 =31
31 + 30 = 1
ANSWER:A
Question: A certain telephone company offers two plans, A and B. Under plan A, the company charges a total of $0.60 for the first 5 minutes of each call and $0.06 per minute thereafter. Under plan B, the company charges $0.08 per minute of each call. What is the duration of a call, in minutes, for which the company charges the same amount under plan A and under plan B?
A.2
B.9
C.15
D.21
Answer: C.15
Explanation: Let the duration, in minutes, for which the company charges the same under plan A and plan B be t minutes.
Then under plan A the cost would be $0.6+0.06(t-5) and under plan B the cost would be $0.08t. We want these amount to be equal: 0.6+0.06(t-5)=0.08t --> 60+6(t-5)=8t --> t=15.
Answer: C.
Question: Two trains one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 4 hours and 9 hours respectively. The ratio of their speeds is
A.3 : 2
B.4 : 3
C.4 : 7
D.8 : 5
Answer: A.3 : 2
Explanation: Sol.
Let us name the trains as A and B. Then,
(A's speed) : (B's speed) = √b : √a
= √9 : √4
= 3 : 2.
Answer A
Question: father is aged three times more than his son ronit. after 8 years, he would be two and half times if ronit's age. after further 8 years , how many times would he be of ronit's age?
A.2 times
B.2.5 times
C.3 times
D.3.8 times
Answer: A.2 times
Explanation: ronit's present age be x years . then, father's present age= (x+3x)years= 4x years
therefore (4x + 8) = 5/2 (x + 8)
8x + 16 = 5x + 40
3x = 24 , x= 8, ratio = (4x + 16)/(x + 16)= 48/24=2,
correct answer (A)
Question: What is the perimeter, in meters, of a rectangular garden 16 meters wide that has the same area as a rectangular playground 16 meters long and 12 meters wide?
A.48
B.56
C.60
D.56
Answer: D.56
Explanation: Say Length of garden is L meters.
Then (L*16) = 16 * 12 [Given area is same. Area= L * B]
Therefore L works out to 12 meters.
Perimeter of Garden = 2* (12+16) = 56 meter.
Answer is D
Question: For all positive integers m, [m]=3m when m is odd and [m]=(1/2)*m when m is even. What is [9]*[4] equivalent to?
A.[108]
B.[54]
C.[36]
D.[27]
Answer: A.[108]
Explanation: [9]*[4] = 27*2 = 54 = (1/2)(108) =[108]
The answer is A.
Question: What is the probability that a leap year has 53 Sundays and 52 Mondays?
A.1/9
B.1/8
C.1/3
D.1/7
Answer: D.1/7
Explanation: A leap year has 52 weeks and two days
Total number of cases = 7
Number of favourable cases = 1
i.e., {Saturday, Sunday}
Required Probability = 1/7
Answer:D
Question: Machine Z can produce x units in 3/4 of the time it takes machine N to produce x units. Machine N can produce x units in 2/3 the time it takes machine O to produce x units. If all three machines are working simultaneously, what fraction of the total output is produced by machine N?
A. 1/2
B. 1/3
C. 4/13
D. 8/29
Answer: C. 4/13
Explanation: Let the following be true:
Z makes x in time t
Then the following follows:
N makes x in 4t/3
O makes x in 3/2(4t/3) = 2t
M:N:O = 1:4/3:2=3:4:6
So N=4/(3+4+6)=4/13=C
Question: If cement, gravel and sand are to be mixed in 7:10:13 and 7 tons of cement is available how many tons of mixture can be produced assuming that sufficient gravel and sand is readily available.
A.35 7/8
B.30
C.34 2/7
D.34 5/7
Answer: B.30
Explanation: Cement:Gravel:Sand = 7:10:13 --> total of 7+10+13 = 30 parts.
If we use 7 tons of cement, then we'll get 7/7*30 = 30 tons of mixture.
Answer: B.
Question: If the cost price is 90% of the selling price, then what is the profit percent?
A.5%
B.11%
C.13%
D.21%
Answer: B.11%
Explanation: Let S.P. = $100
C.P. = $90
Profit = $10
Profit% = 10/90 * 100 = 25/6 = 11% approximately
Answer is B
Question: Which of the following is equal to 3.14 x 10^6) ?
A.3.14
B.3140000
C.31400
D.314
Answer: B.3140000
Explanation: = 3.14 x 10^6
= 3.14 x 1000000
= 3140000.
Answer is B.
Question: 9 men and 12 boys finish a job in 12 days, 12 men and 12 boys finish it in 10 days. 10 men and 10 boys shall finish it in how many days?
A.19 days
B.18 days
C.12 days
D.27 days
Answer: C.12 days
Explanation: 9M + 12B ----- 12 days
12M + 12B ------- 10 days
10M + 10B -------?
108M + 144B = 120M +120B
24B = 12M => 1M = 2B
18B + 12B = 30B ---- 12 days
20B + 10B = 30B -----? => 12 days
Answer: C
Question: A box contains 10 tablets of medicine A and 17 tablets of medicine B. What is the least number of tablets that should be taken from the box to ensure that at least two tablets of each kind are among the extracted.
A.12
B.15
C.17
D.19
Answer: D.19
Explanation: The worst case scenario will be if we remove all 17 tablets of medicine B first. The next 2 tablets we remove have to be of medicine A, so to guarantee that at least two tablets of each kind will be taken we should remove minimum of 17+2=19 tablets.
Answer:D.
Question: Which is better investment 11% stock at 143 or 9 Â¾% stock at 117
A.11 % stock at 143
B.9 3/4 stock at 117
C.both
D.cannot be compared
Answer: B.9 3/4 stock at 117
Explanation: Let the investment in each (143*117)
Income in first case = (11/143*143*117)=1287
Income in second case=((39/117*4)*143*117)=1394.25
Clearly, 9 Â¾% stock at 117
ANSWER B
Question: 96% of the population of a village is 23040. The total population of the village is?
A.26799
B.24000
C.26682
D.29973
Answer: B.24000
Explanation: X * (96/100) = 23040
X = 240 * 100
X = 24000
Answer: B
Question: Simplify:935421 x 625
A.594983125
B.584932715
C.584938125
D.584638125
Answer: D.584638125
Explanation: 935421 x 625 = 935421 x 54 = 935421 x (10/2)^ 4
935421 x 10^4/2^4=9354210000/16
= 584638125
Answer is D
Question: 1. Internet: $80, with no sales tax, plus $10 shipping fee
2. Store X: $90, a 10% discount, plus 10% tax on discounted price
3. Store Y: $90, no tax
4. Store Z: $90, a 10% sales tax, and $10 rebate after tax
Isaac can purchase a certain item in four different ways, as shown in the table. What is the lowest price for which he can purchase this item?
A.88.1
B.89.0
C.89.1
D.89.50
Answer: B.89.0
Explanation: 1. Internet: $80, with no sales tax, plus $10 shipping fee --> 80+10=90;
2. Store X: $90, a 10% discount, plus 10% tax on discounted price --> 90*0.9*1.1=89.1
3. Store Y: $90, no tax --> 90;
4. Store Z: $90, a 10% sales tax, and $10 rebate after tax --> 90*1.1-10=89.
So the lowest price is $89.
Answer: B.
Question: 3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 2 men and 3 women will do that task.
A.1/2
B.1/10
C.1/18
D.1/16
Answer: A.1/2
Explanation: 3 m + 8 w = 6 m + 2 w
3 m = 6 w
1 m = 2 w
Therefore 3 m + 8 w = 14 w
2 m + 3 w =7 w
Answer is 7/14 =1/2
Answer: A
Question: There are 10 cans in the refrigerator. 5 of them are red and 5 of them are blue. In how many ways we can remove 8 cans so that at least one red and at least one blue cans to remain the refrigerator.
A.410
B.490
C.493
D.455
Answer: A.410
Explanation: Answer: A.
Question: If W is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of W?
A.10
B.12
C.14
D.16
Answer: C.14
Explanation: W = 30!
8
W = 30 x 29 x 28 x 27 x 26 x 25 x 24 x 24 x 22 x 21 x 20 x 19 x 18 x 17 x 16 x 15 x 14 x 13 x 12 x 11 x 10 x 09 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
Out of these 30 , 27 , 24 , 21 , 18, 15 , 12 , 09 , 06 , 3 are factors of 3
3 x 10 , 3 x 3 x 3 , 3 x 8 , 3 x 3 x 2, 3 x 5 , 3 x 4 , 3 x 3 x 3 , 3 x 2 , 3
So we have a total of 14 three's ...
Therefore the maximum value of K can be 14 (C)
Question: What decimal fraction is 70 ml of a litre ?
A..7
B..07
C..05
D.0.07
Answer: B..07
Explanation: Answer
Required fraction = 70/1000
= 7/100
= .07
Correct Option: B
Question: There are 8 baskets numbered from 1 to 8 and filled with apples. 10 children are asked to pick apples one by one from each basket such that the number of apples picked by each child from each basket is equal to the number marked on the basket. If there were 1000 apples in total and the baskets were filled in such a way that none of the basket became empty in the process, how many apples were left in the end?
A.640
B.680
C.720
D.760
Answer: A.640
Explanation: Each child takes a total of 1+2+3+4+5+6+7+8 = 8*9/2 = 36 apples.
The total number of apples taken by 10 children is 10*36 = 360
The number of apples left in the end is 1000 - 360 = 640 apples.
The answer is A.
Question: If two numbers x, a perfect square and y, a perfect cube are added results a two digit number, whose digits if reversed, difference is 9, Find x and y ?
A.x=4,y=8
B.x=4,y=9
C.x=4,y=7
D.x=4,y=9
Answer: A.x=4,y=8
Explanation: 4+8=12
when reversed 21
21-12=9
x=4,y=8
ANSWER:A