RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Joan took out a mortgage from hel local bank. Each monthly mortgage payment she makes must be triple the amount of the previous month's payment. If her first payment is $100, and the total amount she must pay back is $109300, how many months will it take Joan to pay back her mortgage?
A.7
B.8
C.10
D.11
Answer: A.7
Explanation: Joan starts off with 100 $ .. which is to be tripled every month
Her monthly payments look like this :
100 , 300 , 900 , 2700 ......... Upto 109300
This can be re written as :
100 x 1 , 100 x 3 , 100 x 9 , 100 x 27 ...... 100 x 1093
So we have 1 , 3 , 9 , 27 ..... 109300 in GP
We know that a =1 , and r = 3 ( its easy to figure it out by looking at the question , but regardless of it being mentioned in the question we can still compute the value of r using the formula Tn = a3^n-1 ...)
Therefore to find the Sum of n terms of a GP we use this formula :
Sn = a (1-r^n) / 1 -r
Using this and plugging in the information we get ...
1093 = 1 - 3^n / 1-3 ; 1-3^n / -2
Cross multiplying we get
1093 x -2 = 1- 3^n
- 2186 = 1 - 3^n
- 2187 = - 3 ^n
2187 = 3 ^n (negatives cancel out)
2187 can also be re written as 3 ^ 7
Therefore ; 3 ^7 = 3 ^n
Thus n = 7 (A)
Question: Mr. Karan borrowed a certain amount at 6% per annum simple interest for 9 years. After 9 years, he returned Rs. 8210/-. Find out the amount that he borrowed.
A.s. 5331
B.s. 5269
C.s. 5228
D.s. 5218
Answer: A.s. 5331
Explanation: Explanation:
Let us assume Mr. Karan borrowed amount is Rs. A. (the principal)
By formula of simple interest, S.I. = PRT / 100
Where P = The principal, R = Rate of interest as a %, T = Time in years
S.I. = (P * 6 * 9)/100 = 54 P/100
Amount = Principal + S.I.
8210 = P + (54P/100)
8210 = (100P + 54P)/100
8210 = 154P/100
P = (8210 * 100)/154 = Rs. 5331.169
ANSWER: A
Question: Mary has 1803 dollars with her. What is the amount that she should keep with her inorder to distribute the same among nine kids equally?
A.3
B.0
C.10
D.2
Answer: A.3
Explanation: The answer is 3. (1803-3=1800). 1800 is divisible by nine which gives an answer of 20.So,she will be distributing 20 each for the nine kids and the remaining 3 will be left with her. So the answer is A=3
Question: The average age of three boys is 15 years. If their ages are in ratio 3:5:7, the age of the youngest boy is
A.21 years
B.18 years
C.15 years
D.9 years
Answer: D.9 years
Explanation: Solution: Sum of ages of three boys = 45 years
Now, (3x+5x+7x) = 45
Or, 15x = 45
Or, x = 3
So, age of youngest boy = 3x = 3*3 = 9 years.
Answer: Option D
Question: A snail, climbing a 66 feet high wall, climbs up 4 feet on the first day but slides down 2 feet on the second. It climbs 4 feet on the third day and slides down again 2 feet on the fourth day. If this pattern continues, how many days will it take the snail to reach the top of the wall?
A.42
B.63
C.77
D.80
Answer: B.63
Explanation: total transaction in two days = 4-2 = 2 feet
in 62 days it will climb 62 feet
on the 63rd day , the snail will climb 4 feet , thus reaching the top
therefore , total no of days required =63
B
Question: A jar of 364 marbles is divided equally among a group of marble-players today. If 2 people joined the group in the future, each person would receive 1 marble less. How many people are there in the group today?
A.20
B.22
C.24
D.26
Answer: D.26
Explanation: 364 = 26*14 = 28*13
There are 26 people in the group today.
The answer is D.
Question: Mary replaced 20% of an 60% juice concentrate with water. Upon finding the resultant juice too sweet, she further replaced 30% of this solution with water, then fine tuned it by replacing 10% of that solution with water.
What is the final juice concentration Mary liked best?
A.25.5%
B.41.68%
C.30.24%
D.21%
Answer: C.30.24%
Explanation: The answer can be quickly calculated as: (60)(0.8)(0.7)(0.9)
How it works: By calculating how much juice is removed from an assumed 100 ml mixture, we can find out the final percentage.
In step 1, 20% of a 60% juice concentrate is replaced with water. With 100 ml of juice concentrate, this translates to removing 20% of juice, or rather keeping 80% of it. Hence, we multiply 60x0.8 = 48 ml.
In step 2, 30% of the solution is mixed with water. This translates to keeping 70% of the concentrate. Hence, 48x0.7 = 33.6 ml.
Finally in step 3, 10% of the solution is replaced with water. This means 90% of the concentrate remains. So, final amount of concentrate = 33.6x0.9 = 30.24 ml.
30.24 ml of concentrate in a 100 ml solution makes 30.24%
Answer: C
Question: A can contains a mixture of liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter M of liquid A was contained by the can initially?
A.10
B.20
C.21
D.25
Answer: C.21
Explanation: As A:B::7:5 ---> only option C is a multiple of 7 and hence it is a good place to start. Also A:B::7:5 means that , A = (712)*Total and B = (5/12)*Total
If A = 21 , B = 15 ---> remove 9 litres ---> you remove (7/12)*9 of A ---> A remaining = 21-(7/12)*9 = 63/4
Similarly, for B, you remove (5/12)*9 ---> B remaining = 15 - (5/12)*9 = 45/4 and then add 9 more litres of B ---> 9+45/4 = 81/4
Thus A/B (final ratio) = (45/4)/(81/4) = 7:9 , the same as the final ratio mentioned in the question.
Hence C is the correct answer.
A/B = 7/9 = (7x-(7/12)*9)/ (5x-(5/12)*9+9), where 7x and 5x are initial quantities of A and B respectively.
Thus, 7/9 = (7x-(7/12)*9)/ (5x-(5/12)*9+9) ---> giving you x=3. Thus A (original) M= 7*3 = 21.C
Question: A person want to give his money of $1000 to his 4 children A,B,C,D in the ratio 2:4:3:1. What is the A+D share?
A.$100
B.$200
C.$300
D.$500
Answer: C.$300
Explanation: A's share = 1000*2/10 = $200
D's share = 1000*1/10 = $100
A+D = $300
Answer is C
Question: [(13/2 ÷ 1/2 × 13/2)]/[(13/2 × 1/2 ÷ 13/2)] = ?
A.159
B.149
C.169
D.179
Answer: C.169
Explanation: Explanation:
[(13/2 ÷ 1/2 × 13/2)]/[(13/2 × 1/2 ÷ 13/2)]
= [13/2 × 2/1 × 13/2]/[13/2 × 1/2 × 2/13]
= 169/2 / 1/2 = 169/2 x 2/1 = 169
Answer: Option C
Question: An accurate clock shows 8 o'clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 12 o'clock noon?
A.180°
B.120°
C.160°
D.170°
Answer: B.120°
Explanation: The angle traced by the hour hand in 12 hours is 360°, which is 30° per hour.
In 4 hours, the angle traced by the hour hand is 4×30° = 120°
The answer is B.
Question: Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the same job. How long it take both A & B, working together but independently, to do the same job?
A.20/9
B.40/9
C.50/9
D.60/9
Answer: B.40/9
Explanation: one day work of A = 1/8
one day work of B = 1/10
so one day work of A and B together = 1/8 + 1/10 = 9/40
so total days required = 40/9
ANSWER:B
Question: A letter lock consists of five rings each marked with three different letters. The number of distinct unsuccessful attempts to open the lock is at the most?
A.277
B.269
C.242
D.177
Answer: C.242
Explanation: Since each ring consists of three different letters, the total number of attempts possible with the five rings is
= 3 * 3 * 3 * 3 * 3 = 216. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts = 243 - 1
= 242
Answer:C
Question: It takes 3 workers a total of 9 hours to build a giant machine with each worker working at the same rate. If 3 workers start to build the machine at 11:00 AM, and one extra worker per hour is added beginning at 2:00 PM, at what time will the machine be complete?
A.5:15
B.5:26
C.5:37
D.5:48
Answer: B.5:26
Explanation: 3 workers build 1/9 of a machine in one hour.
1 worker builds 1/27 of a machine in one hour.
In the first 3 hours, 3 workers build 3*(1/27)*3=9/27 of a machine
From 2:00 to 3:00, 4 workers build another 4/27. The total is 13/27.
From 3:00 to 4:00, 5 workers build another 5/27. The total is 18/27.
From 4:00 to 5:00, 6 workers build another 6/27. The total is 24/27.
To build another 3/27, 7 workers need (3/7)*60 minutes which is about 26 minutes.
The machine is complete at about 5:26.
The answer is B.
Question: Indu gave Bindu Rs.3750 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
A.s.6
B.s.2
C.s.5
D.s.3
Answer: A.s.6
Explanation: 3750 = D(100/4)2
D = 6
ANSWER:A
Question: Of the five numbers in a sequence, the first term is 10,000, and each of the following terms is 60% of the previous term. What is the value range of the five numbers?
A.8,704
B.9,750
C.9,975
D.9,984
Answer: A.8,704
Explanation: 1st number= 10,000
2nd number = 60% of 10,000= 6000
3rd number= 60% of 6000= 3600
4th number = 60% of 3600= 2160
5th number= 60% of 2160= 1296
Range = 10,000-1296= 8704
A is the answer
Question: A property decreases in value every year at the rate of 6 1/4% of its value at the beginning of the year its value at the end of 3 years was Rs.21093. Find its value at the beginning of the first year?
A.25600.24
B.25600.28
C.25600.243
D.25600.21
Answer: A.25600.24
Explanation: 6 1/4% = 1/16
x *15/16 * 15/16 * 15/16 = 21093
x = 25600.24
Answer: A
Question: 9. On level farmland, two runners leave at the same time from the intersection of two country roads. One runner jogs due north at a constant rate of 8 miles per hour while the second runner jogs due east at a constant rate that is 2 miles per hour slower than the first runner's rate. How far apart, to the nearest mile, will they be after 1/2 hour ?
A. 5
B. 7
C. 8
D. 12
Answer: A. 5
Explanation: If runner 1 is going north and runner 2 is going east they are like two sides of a 90 degree triangle.
Side 1 = 8 m/h --> 4 m in 1/2 hr
Side 2 = 6 m/h --> 3 m in 1/2 hr
to complete this right angle triangle
d^2 = 4^2 + 3^2
d^2 = 25
= 5
Answer option A
Question: Given a square of length 2m. Its corners are cut such that to represent a regular octagon. Find the length of side of octagon
A.2
B.3
C.4
D.5
Answer: A.2
Explanation: Let x is the side of the octagon and x + 2y is the side of the square.
In the given octagon, y2+y2=x2⇒2y2=x2⇒y=x2–√y2+y2=x2⇒2y2=x2⇒y=x2
But x2–√+x+x2–√=2x2+x+x2=2
⇒2–√x+x=2⇒2x+x=2
⇒x=22–√+1=22–√+1×2–√−12–√−1=2(2–√−1)⇒x=22+1=22+1×2−12−1=2(2−1)
Answer:A
Question: If the selling price is quintupled,the profit is hexatrupled,what is the percentage of profit??
A.50%
B.100%
C.150%
D.200%
Answer: B.100%
Explanation: we can make two equations from the given info..
let selling price be S and cost price be C..
so profit=P=S-C...
if S is doubled profit is tripled..
so 6P=5S-C..
or S=5P...
therefore C=P..
% of profit=P/P=100%
B
Question: A car traveled from San Diego to San Francisco at an average speed of 45 miles per hour. If the journey back took twice as long, what was the average speed of the trip?
A.30.
B.32.
C.36.
D.42.
Answer: A.30.
Explanation: Let the time taken be = x
One way distance = 45x
Total distance traveled = 2 * 45x = 90x
Total time taken = x + 2x = 3x
Average speed = 90x/3x = 30
Answer: A
Question: In how many no. between 100 and 1000 at least one of their digits is 7?
A.900
B.648
C.720
D.252
Answer: D.252
Explanation: Let's count the number of occurrences with only one 7:
(1) 7XX: 1 * 9 * 9 = 81
(2) X7X: 8 * 1 * 9 = 72
(3) XX7: 8 * 9 * 1 = 72
81 + 72 + 72 = 225
At this point we can already see that the answer must be D since the choice are very dispersed.
Anyways, let's count number of occurrences with two 7s:
(1) 77X: 1 * 1 * 9 = 9
(2) X77: 8 * 1 * 1 = 8
(3) 7X7: 1 * 9 * 1 = 9
9 + 8 + 9 = 26
Number 777 is missing. So the total becomes
225 + 26 + 1 = 252
D is the correct answer.
Question: The total number of students in Grades 1 and 2 is 30 more than the total number of students in grades 2 and 5. How much lesser is the number of students in Grade 5 as compared to Grade 1?
A.20
B.30
C.10
D.40
Answer: B.30
Explanation: (Grade 1 + Grade 2) - (Grade 2 + Grade 5) = 30
Grade 1 - Grade 5 = 30
Answer: B
Question: One card is drawn at random from a pack of 48 cards. What is the probability that the card drawn is a face card?
A.1/4
B.1/7
C.1/8
D.1/5
Answer: A.1/4
Explanation: Clearly, there are 52 cards, out of which there are 12 face cards.
P (getting a face card) =	12/48 = 1/4
A
Question: A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have?
A.50
B.45
C.20
D.73
Answer: A.50
Explanation: A+B+C = 500
A+C = 200
B+C = 350
--------------
A+B+2C = 550
A+B+C = 500
----------------
C = 50
Answer:A
Question: Kelly and Jody packed boxes with books. If Jody packed 20% of the total number of boxes, what was the ratio of the number of boxes Kelly packed to the number that Jody packed?
A.1 to 6
B.4 to 1
C.2 to 5
D.3 to 5
Answer: B.4 to 1
Explanation: Explanation:
If Jody packed 20% of the boxes then Kelly packed 80%. The ratio of the number of boxes Kelly packed to the number Jody packed is thus 80%/20%=4/1
Answer: Option B
Question: 8k8
+ k88
--------
1,6y6
If k and y represent non-zero digits within the integers above, what is y?
A.6
B.7
C.8
D.9
Answer: A.6
Explanation: 8k8
k88
--------
16y6
Trial and error or just plug-in method might be the shortest way to solve this problem. Though you can narrow down the possible values of k to just two: 7 and 8 --> 8**+7**=16** or 8**+8**=16** (k can not be less than 7 or 9, as the result won't be 16**). After that it's easy to get that k=7 and y=6.
Answer: A.
Question: A and B partner in a business. A contribute 1/4 of the capital for 15 months and B received 2/3 of the profit. For how long B's money was used?
A.5 months
B.10 months
C.8 months
D.12 months
Answer: B.10 months
Explanation: B received 2/3 of the profit.
Then A received remaining 1/3 of the profit.
=> A : B =1/3:2/3=1:2
Let the total capital =x
Then A's capital =x4
B's capital =x–x/4=3x/4
Assume B's money was used for b months
Then A:B =x/4×15:3x/4×b
⇒15x/4:3bx/4=1:2
⇒15:3b=1:2
⇒5:b=1:2
⇒5×2=1×b
⇒b=10
Answer is B.
Question: I. a2 - 2a - 8 = 0,
II. b2 = 9 to solve both the equations to find the values of a and b?
A.If a < b
B.If a ≤ b
C.If the relationship between a and b cannot be established
D.If a > b
Answer: C.If the relationship between a and b cannot be established
Explanation: Explanation:
I. (a - 4)(a + 2) = 0
=> a = 4, -2
II. b2 = 9
=> b = ± 3
-2 < 3, -2 > -3, 4 > 3, 4 > -3,
No relation can be established between a and b.
C)
Question: A, B and C can do a work in 7 days, 8 days and 12 days respectively. In how many days can all three of them working together, complete the work?
A.2 50/59
B.2 5/59
C.2 2/50
D.2 2/59
Answer: A.2 50/59
Explanation: Work done by all three of them in one day = 1/7 + 1/8 + 1/12 = 59/168
The number of days required = 168/59 = 2 50/59 days.
Answer:A
Question: Five bells commence tolling together and toll at intervals of 2, 4, 6, 8,10 seconds respectively. In 60 minutes, how many times do they toll together?
A.41
B.10
C.31
D.16
Answer: C.31
Explanation: L.C.M of 2,4,6,8,10 is 240. i.e after each 2 min they will toll together.So in 60 min they will toll 30 times.As they have initially tolled once,The answer will be 30+1=31.
ANSWER:C
Question: In a school with 5 classes, each class has 2 students less than the previous class. How many students are there in the largest class if the total number of students at school is 100?
A.24
B.25
C.26
D.27
Answer: A.24
Explanation: Let x be the number of students in the largest class.
Then x + (x-2) + (x-4) + (x-6) + (x-8) = 100
5x -20 = 100
5x = 120
x = 24
The answer is A.
Question: A wheel that has 6 cogs is meshed with a larger wheel of 7 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions made by the larger wheel is:
A.9
B.10
C.6
D.18
Answer: D.18
Explanation: Explanation :
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
7:6::21:x => 7 * x = 21 * 6
=> x = (21 * 6)/7
=> x = 18
Answer : D
Question: 0.009/x=0.1. find the value of X
A.0.0009
B.0.09
C.0.9
D.9
Answer: B.0.09
Explanation: x=0.009/0.1=0.09
ANSWER:B
Question: Two friends decide to get together; so they start riding bikes towards each other. They plan to meet halfway. Each is riding at 6 MPH. They live 36 miles apart. One of them has a pet carrier pigeon and it starts flying the instant the friends start traveling. The pigeon flies back and forth at 19 MPH between the 2 friends until the friends meet. How many miles does the pigeon travel?
A.54
B.57
C.60
D.36
Answer: B.57
Explanation: B
57
It takes 3 hours for the friends to meet; so the pigeon flies for 3 hours at 19 MPH = 57 miles
Question: On dividing a number by 56, we get 29 as remainder. On dividing the same number by 8, what will be the remainder ?
A.5
B.7
C.9
D.11
Answer: A.5
Explanation: Formula: (Divisor*Quotient) + Remainder = Dividend.
Soln:
(56*Q)+29 = D -------(1)
D%8 = R -------------(2)
From equation(2),
((56*Q)+29)%8 = R.
=> Assume Q = 1.
=> (56+29)%8 = R.
=> 85%8 = R
=> 5 = R.
A)
Question: Difference between two numbers is 5, six times of the smaller lacks by 6 from the four times of the greater. Find the numbers?
A.5
B.7
C.9
D.11
Answer: B.7
Explanation: Explanation:
x – y = 5
4x – 6y = 6
x = 12 y = 7
B)
Question: If YWVSQ is 25 - 23 - 21 - 19 - 17, Then MKIGW
A.13 - 11 - 9 - 7 - 9
B.13 - 11 - 9 - 7 - 6
C.13 - 11 - 9 - 7 - 11
D.13 - 11 - 9 - 7 - 3
Answer: C.13 - 11 - 9 - 7 - 11
Explanation: MKIGW = 13 - 11 - 9 - 7 - 11
Note: this is a dummy question. Dont answer these questions
Answer:C
Question: What is the value of (5!*4!*3!*2/ 6!*6!)-1/15?
A.5
B.12
C.20
D.0
Answer: D.0
Explanation: (5!*4!*3!*2/6!*6!)-1/15
(5!*4!*3!*2/5!*6*4!*5*6)-1/15
(3!*2/6*5*6)-1/15
1/15-1/15=0
answer D
Question: A worker's take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 6 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month?
A.1/6
B.1/5
C.1/4
D.1/3
Answer: D.1/3
Explanation: Let x be the fraction of her take-home pay that the worker saved.
Let P be the monthly pay.
12xP = 6(1-x)P
12xP = 6P - 6xP
18xP = 6P
x = 1/3
The answer is D.
Question: A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 1800 interest only for the period. The principal amount borrowed by him was:
A.s. 2,500
B.s. 1,000
C.s. 15,000
D.s. 5,000
Answer: D.s. 5,000
Explanation: Principal = Rs. (100 x 1800)/(12X3) = Rs. 5000. Answer: Option D
Question: Find the amount on Rs.5000 in 2 years, the rate of interest being 10% per first year and 12% for the second year?
A.3377
B.6160
C.5460
D.1976
Answer: B.6160
Explanation: 5000 * 110/100 * 112/100 => 6160
Answer: B
Question: What is the greatest value of n such that 18^n is a factor of 18! ?
A.1
B.2
C.3
D.4
Answer: D.4
Explanation: We know that 18 = 2 *3^2.
Hence, we need to find total number of 3s in 18! ( As out of 3 and 2 , we will have count of 3 least)
No. of 3s = 18/3 = 6/3 = 2.
Add the numbers in Bold, you will get total number of 3s = 8.
Hence, total number of 3^2 = 8/2 = 4.
Hence, answer is 4.
ANSWER:D
Question: In 1992 a total of 100 earthquakes occurred worldwide, some but not all of which occurred in Asia. If 10 of these earthquakes occurred in Asia, which of the following represents the ratio of the number of earthquakes that occurred in Asia to the number that did NOT occur in Asia?
A.1/5
B.1/9
C.1/2
D.1/3
Answer: B.1/9
Explanation: We're given a couple of facts to work with:
1) There were a total of 100 earthquakes
2) Of those earthquakes, 10 of them occurred in Asia
We're asked for the ratio of the number of earthquakes that occurred IN ASIA to the number of earthquakes that DID NOT occur in Asia.
Thus, there were 90 earthquakes that DID NOT occur in Asia....
The answer to the question is 10/90 = 1/9
Answer : B
Question: How many such 6's are there in the following number series which are followed by an even number and preceded by any odd number ? 3 6 4 5 7 6 3 5 4 3 6 4 5 6 4 1 6 3 9 6 3 4 5 6
A.three
B.one
C.two
D.four
Answer: A.three
Explanation: 3 6 4
3 6 4
5 6 4
so three times
ANSWER:A
Question: A train leaves Delhi at 11 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
A.360
B.288
C.600
D.888
Answer: A.360
Explanation: D = 30 * 3 = 90
RS = 40 – 30 = 10
T = 90/10 = 9
D = 40 * 9 = 360 km
Answer: A
Question: In a family 11 people eat only vegetarian, 6 people eat only non veg., 9 people eat both veg and non veg.. How many people eat veg in the family?
A.20
B.11
C.9
D.31
Answer: A.20
Explanation: Total people eat veg = only veg + both veg and non veg
Total= 11+9= 20
Answer = A
Question: 30 pens and 75 pencils were purchased for 450. If the average price of a pencil was 2.00, find the average price of a pen.
A.10
B.11
C.12
D.13
Answer: A.10
Explanation: Since average price of a pencil = 2
∴ Price of 75 pencils = 150
∴ Price of 30 pens = (450 – 150) = 300
∴ Average price of a pen = 360⁄60 = 10
Answer A
Question: A car covers a distance of 624 km in 4 hours. Find its speed?
A.104
B.277
C.156
D.269
Answer: C.156
Explanation: 624/4 = 156 kmph
Answer:C
Question: Shop Offered 32% offer for every Shirt, Smith bought a shirt at Rs. 650. and What was the shop's original selling Price?
A.955
B.550
C.600
D.700
Answer: A.955
Explanation: SP* (68/100) = 650
SP= 9.55 * 100 => CP = 955
Answer:A
Question: A Booster pump can be used for filling as well as for emptying a tank. The capacity of the tank is 2400 m3. The emptying capacity of the tank is 10 m3 per minute higher than its filling capacity and the pump needs 8 minutes lesser to empty the tank than it needs to fill it. What is the filling capacity of the pump?
A.18
B.50
C.34
D.69
Answer: B.50
Explanation: Let, the filling capacity of the pump be x m3/min
Then, emptying capacity of the pump=(x+10) m3/min.
So,2400/x – 2400/(x+10) = 8
on solving x=50.
ANSWER:B
Question: If 0.75 : x :: 5 : 8, then x is equal to:
A.120
B.12
C.1.2
D.0.12
Answer: C.1.2
Explanation: ((x) x 5) = (0.75 x 8)
= x = 6/5
= 1.20
Answer is C.
Question: If a student loses 5 kilograms, he will weigh twice as much as his sister. Together they now weigh 116 kilograms. What is the student's present weight in kilograms?
A.76
B.77
C.78
D.79
Answer: D.79
Explanation: Let x be the weight of the sister.
Then the student's weight is 2x+5.
x + (2x+5) = 116
3x = 111
x = 37 kg
Then the student's weight is 79 kg.
The answer is D.
Question: A trader mixes 80 kg of tea at 15 per kg with 20 kg of tea at cost price of 20 per kg. In order to earn a profit of 25%, what should be the sale price of the mixed tea?
A.23.75
B.22
C.20
D.19.20
Answer: C.20
Explanation: C.P. of mixture = 80×15+20×20/80+20=16
∴ S.P. = (100+25)/100×16=20
Answer C
Question: If x = 1 + √2, then what is the value of x4 - 4x3 + 4x2 + 5?
A.-1
B.0
C.6
D.2
Answer: C.6
Explanation: Answer
x = 1 + √2
∴ x4 - 4x3 + 4x2 + 5 = x2(x2 - 4x + 4) + 5
= x2(x - 2)2 + 5
= (1 + √2)2(1 + √2 - 2)2 + 5
=(√2 + 1)2 (√2 - 1)2 + 5
=[(√2)2 - (1)2]2 + 5
=(2 - 1)2 =1 + 5=6
Correct Option: C
Question: When I add 4 times my age 4 years from now to 5 times my age 5 years from now, I get 10 times my current age. How old will I be 3 years from now?
A.42 years
B.41 years
C.43 years
D.40 years
Answer: C.43 years
Explanation: Let x= current age 4(x+4)+5(x+5)=10x ;so x=R 41 years
Answer C
Question: If one-third of one-fourth of a number is 15, then three-tenth of that number is:
A. 35
A.23
B.87
C.26
D.54
Answer: D.54
Explanation: Explanation:
The number is 1/3 of 1/4 is =15 then 1/3 × 1/4 = 15
Number is 180 then 180 × 3/10 = 54
Answer: D
Question: Mangala completes a piece of work in 10 days, Raju completes the same work in 15 days. If both of them work together, then the number of days required to complete the work is?
A.5 days
B.6 days
C.7 days
D.8 days
Answer: B.6 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 Ã— 15/25 = 6 days.
B)