RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a series of six football matches between Germany and Argentina , the probability of Germany winning a match is 1/3 and the probability that the match ends in a draw is 1/4. If a win gets the team 2 points, a draw 1 point and a loss 0 Points, What is the probability that Germany will end up in 6 draws in the series?
A.24/576
B.125/864
C.1/25
D.1/4096
Answer: D.1/4096
Explanation: Since the probability of a draw is 1/4, then the probability of 6 draws in 6 matches is (1/4)^6=1/4096.
Answer: D.
Question: A train is 327 meter long is running at a speed of 40 km/hour. In what time will it pass a bridge of 122 meter length?
A.32.7
B.41
C.50.29
D.40.41
Answer: D.40.41
Explanation: Speed = 40 Km/hr = 40*(5/18) m/sec = 100/9 m/sec
Total distance = 327+122 = 449 meter
Time = Distance/speed
= 449 * (9/100) = 40.41 seconds.
Answer: D
Question: The value of a stock is X dollars. On Sunday the stock's value grew by half of its value, but on Monday its value dropped to a half of its new value. What is the stock's value at the end of Monday?
A.X.
B.X/2.
C.2X/3.
D.3X/4.
Answer: D.3X/4.
Explanation: Stock value= X
AT sunday end= x+.5X= 1.5 X
On monday the value drop to 1/2rd of its value on sunday
1.5x/2= .75x= 3X/4
D is the answer
Question: P alone can complete a piece of work in 10 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?
A.6 (1/4) days
B.30/4 days
C.7 (3/4) days
D.9/4 days
Answer: B.30/4 days
Explanation: Work done by P alone in one day = 1/10th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/10 of the total) = 1/30 of the total.
Work done by P and Q, working together in one day = 1/10 + 1/30 = 4/30 of the total
They would take 30/4 days to complete the work working together.
ANSWER:B
Question: A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes ?
A.50 meter
B.100 meter
C.110 meter
D.120 meter
Answer: B.100 meter
Explanation: Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr
Distance covered in 6 minutes =
1/60∗6=1/10=100meters
So distance between them after 6 minutes = 200 - 100
= 100 meters
Option B
Question: 1+3=2 2+3=10 3+3=30 4+3=68 5+3=??
A.110
B.120
C.130
D.140
Answer: C.130
Explanation: 1^3+3-2=2,
2^3+3-1=10,
3^3+3-0=30,
4^3+3+1=68,
5^3+3+2=130
ANSWER:C
Question: Find the average of all the numbers between 6 and 29 which are divisible by 5?
A.17
B.20
C.25
D.30
Answer: A.17
Explanation: Average = (10+15+20+25) 4 = 70/4 = 17
Answer is A
Question: If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 3:4 then find the largest number?
A.20
B.22
C.30
D.32
Answer: C.30
Explanation: Ratio is 2:3
2x + 10 : 3x + 10 = 3 : 4
4[2x + 10] = 3[3x + 10]
8x + 40 = 9x + 30
9x - 8x = 40 - 30
x = 10
Then largest number is = 3x
3x = 30
Ans = C
Question: What is the area of square field whose side of length 18 m?
A.225 sq m
B.186 sq m
C.586 sq m
D.324 sq m
Answer: D.324 sq m
Explanation: 18 * 18
= 324 sq m
Answer: D
Question: How many ways are there to split a group of 12 students into two groups of 6 students each? (The order of the groups does not matter)
A.180
B.262
C.384
D.462
Answer: D.462
Explanation: 12C6 = 924
If we consider these groups, each group will be counted twice.
The number of ways to choose 2 groups of 6 is 924/2 = 462
The answer is D.
Question: From the given equation find the value of x: x² − 3x + 2
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: (x − 1)(x − 2)
x = 1 or 2.
C
Question: A woman has 7 daughters and they each have a brother, how many children does she have?
A.7
B.8
C.9
D.5
Answer: B.8
Explanation: B
8
8 children, the sisters have just one brother!
Question: In a kilometer race, A beats B by 50 meters or 10 seconds. What time does A take to complete the race?
A.187 sec
B.190 sec
C.168 sec
D.197 sec
Answer: B.190 sec
Explanation: Time taken by B run 1000 meters
= (1000 * 10)/50 = 200 sec.
Time taken by A = 200 - 10
= 190 sec.
Answer: B
Question: A die is rolled twice. What is the probability of getting a sum equal to 9?
A.2/8
B.1/9
C.3/9
D.7/4
Answer: B.1/9
Explanation: Explanation :
Total number of outcomes possible when a die is rolled =6
Hence, total number of outcomes possible when a die is rolled twice, n(S)=6*6=36
E = Getting a sum of 9 when the two dice fall = {(3, 6), {4, 5}, {5, 4}, (6, 3)}
Hence, n(E) = 4
P(E) =n(E)/n(S)=4/36=1/9
B
Question: A and Bâ€™s salaries together amount to Rs. 2,000. A spends 95% of his salary and B spends 85% of his. If now their savings are the same, what is Aâ€™s salary?
A.Rs.500
B.Rs.750
C.Rs.1250
D.Rs.1500
Answer: D.Rs.1500
Explanation: Explanation:
(5/100) A = (15/100) B
A = 3B
A + B = 2000
4B = 2000 => B = 500
A = 1500
ANSWER IS D
Question: Ramu bought an old car for Rs. 35000. He spent Rs. 13000 on repairs and sold it for Rs. 64900. What is his profit percent?
A.A)14%
B.B)16%
C.C)18%
D.D)30.7%
Answer: D.D)30.7%
Explanation: Total CP = Rs. 35000 + Rs. 13000 = Rs. 48000 and SP = Rs. 64900
Profit(%) = (64900 - 48000)/55000 * 100 = 30.7%
ANSWER:D
Question: Bob bikes to school every day at a steady rate of b miles per hour. On a particular day, Bob had a flat tire exactly halfway to school. He immediately started walking to school at a steady pace of y miles per hour. He arrived at school exactly t hours after leaving his home. How many miles is it from the school to Bob's home?
A.(b + y) / t
B.2(b + t) / by
C.2byt / (b + y)
D.2(b + y + t) / by
Answer: C.2byt / (b + y)
Explanation: If we choose for d (distance): 10 miles, for b 10 and for y 5.
t would be 90 minutes or 1,5 hours.
If I try this for answer choice C it fits.
Question: There are between 100 and 110 marbles in a collection of cards. If they are counted out 3 at a time, there are 1 left over, but if they are counted out 4 at a time, there is 4 left over. How many marbles are in the collection?
A. 100
B. 103
C. 106
D. 108
Answer: A. 100
Explanation: Let number of cards = x
If the cards are counted 3 at a time , there are 2 left over-
x = 3p+1
x can take values 100 , 104 , 109
If the cards are counted 4 at a time , there is 1 left over
x= 4q+4
x can take values 100 , 108
Therefore , x = 100
Answer A
Question: Adding two non multiples of C always results in a multiple of C; which of the following must be the value of C ?
A.[A] two
B.[B] three
C.[C] five
D.[D] ten
Answer: A.[A] two
Explanation: NON- multiples of 2 would always be ODD and sum of two odd would be EVEN.
so irrespective of value of non-multiples, sum of two them would always be even and thus multiple of 2..
A
Question: A bag contains 5 red, 4 blue and 3 green balls. If 2 ballsare picked at random, what is the probability that both are red?
A.1/13
B.2/23
C.5/33
D.4/27
Answer: C.5/33
Explanation: P(Both are red),
=5C212C2=5C212C2
=10/66=5/33
C
Question: Johnny borrows $40,000 from Tony at 4% daily interest compounded daily. How much does Johnny owe Tony after 8 weeks?
A.40000*0.02^56
B.30000*1.12
C.40000*2.12
D.40000*1.04^56
Answer: D.40000*1.04^56
Explanation: A=A= P(1+r100)^n
So, A=40000(1+4/100)^7âˆ—8
So, A= 40000(1.04)^56
Hence answer will be (D)
Question: What least no. must be subtracted from 427398 so that remaining no.is divisible by 15?
A.344545629
B.723437481
C.354595321
D.964564944
Answer: B.723437481
Explanation: Explanation:
On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted
Option B
Question: Light glows for every 17 seconds . How many times did it between 1:57:58 and 3:20:47 am
A.291
B.292
C.293
D.384
Answer: C.293
Explanation: the diff in sec between 1:57:58 and 3:20:47 is 4969 sec, 4969/17 = 292.
so total 293 times light ll glow
ANSWER:C
Question: A rectangular field has a length 10 feet more than it is width. If the area of the field is 264, what are the dimensions of the rectangular field?
A.22
B.23
C.24
D.25
Answer: A.22
Explanation: Let x and y be the length and width of the field. The statement "a length 10 feet more than it is width" may be formulated by
x = 10 + y
The formula for the area is given by
A = x y
Substitute A and x in the above equation by 264 and 10 + y respectively to obtain
264 = (10 + y) y
Write the above equation in standard form as follows
y 2 + 10 y - 264 = 0
Solve the above equation for to obtain
y = 12 and y = - 22
Since y is the value of a width it must be positive. The dimensions of the field are given by
y = 12 and x = 10 + y = 22
As an exercise, check that the rectangular field has length 10 feet more than it is width and an area of 264.
Answer A
Question: The average of first three prime numbers greater than 5 is?
A.12.6
B.12.9
C.22.3
D.10.3
Answer: D.10.3
Explanation: 7 + 11+ 13 = 31/3 = 10.3
Answer: D
Question: What is the tens digit of 6^20?
A.1
B.3
C.5
D.7
Answer: D.7
Explanation: The tens digit of 6 in integer power starting from 2 (6^1 has no tens digit) repeats in a pattern of 5: {3, 1, 9, 7, 5}:
The tens digit of 6^2=36 is 3.
The tens digit of 6^3=216 is 1.
The tens digit of 6^4=...96 is 9.
The tens digit of 6^5=...76 is 7.
The tens digit of 6^6=...56 is 5.
The tens digit of 6^7=...36 is 3 again.
etc...
20 has the form 5n, so the tens digit of 6^20 is 7.
The answer is D.
Question: 96% of the population of a city is 23040. Find the total population of the city?
A.30000
B.28000
C.24000
D.25000
Answer: C.24000
Explanation: Population consider as x
x*(96/100) = 23040
x=240*100
==>24000
ANSWER C
Question: A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
A.220 km
B.224 km
C.230 km
D.232 km
Answer: B.224 km
Explanation: 0.5x/21 + 0.5x/24 = 10
--> x/21 + x/24 = 20
--> 15x = 168 x 20
--> x = (168 x 20)/15 = 224 km.
Answer : B.
Question: Different breeds of dogs get older at different rates in “dog years.” Livonian wolfhounds age 7 times as fast as humans, whereas Khazarian terriers age 3 times as fast and Akkadian retrievers age 4 times as fast. If Dan bought a newborn Akkadian on January 1, 2010, a newborn Khazarian 1 year later, and a newborn Livonian 1 year after that, in what year will the sum of the dog-year ages of the Akkadian and the Khazarian first be exceeded by twice the age of the Livonian in dog years, rounding all ages down to the nearest integer?
A.2013
B.2014
C.2015
D.2016
Answer: B.2014
Explanation: chart starting at 2011: A=4 ;2012= A=8 ,K=3
A+K=11
L=0.
Then I added 7 to a+k for each year and 14 to L for each year.
2013:AK=18 L=14
2014:AK= 25 L=28
thus, 2014 is the correct answer.
B
Question: My 5 sons are enrolled in an army's platoon of 80 men. The General is choosing randomly 2 men to a suicide mission. What is the probability of both of the selected men will be two of my sons?
A. 1/80
B. 2/80
C. 5/80
D. 1/316
Answer: D. 1/316
Explanation: My sons are 5 in a group of 80 men. Thus the probability of choosing 2 of my sons is: (5/80)(4/79) = 1/316. The correct answer is D.
Question: Ganet has to pay back her bank loan over 6 months following the below sequence.
$50, $55, $65, $80, $85, ?
How much will she pay back on the sixthmonth?
A.$155
B.$145
C.$95
D.$125
Answer: C.$95
Explanation: The sequence progresses +5, +10, +15 repeated; The amount to pay back on the 6th Month is $95
Ans C
Question: a man owns 1/3 of market reserch beauro buzness,and sells 3/5 of his shares for 2000rs,what is the value of buzness?
A.40000
B.60000
C.10000
D.25000
Answer: C.10000
Explanation: If value of business=x
Total sell (1x/3)(3/5)=2000
->x=10000
ANSWER:C
Question: Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 25 hours and 81 hours respectively. The ratio of their speeds is:
A.2 : 3
B.4 : 3
C.9 : 5
D.9 : 16
Answer: C.9 : 5
Explanation: Let us name the trains as A and B. Then,
(A's speed) : (B's speed) = âˆšb : âˆša = âˆš81 : âˆš25 = 9 : 5.
Answer C
Question: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
A.100
B.150
C.200
D.220
Answer: A.100
Explanation: Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Question: A garrison of 2000 men has provisions for 62 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement?
A.1977
B.1893
C.2700
D.1900
Answer: C.2700
Explanation: 2000 ---- 62
2000 ---- 47
x ----- 20
x*20 = 2000*47
x = 4700
2000
-------
2700
Answer: C
Question: When x and y are rounded to the nearest tenth, x is 0.3 and y is 0.6. The exact value of (x/y) must be between
A.5/12 and 7/12
B.6/11 and 6/13
C.5/13 and 7/11
D.3/7 and 7/12
Answer: C.5/13 and 7/11
Explanation: x rounded to nearest tenth is 0.3
i.e. x may vary from 0.25 to 0.34
0.25 < x < 0.34
y rounded to nearest tenth is 0.6
i.e. x may vary from 0.55 to 0.64
0.55 < y < 0.64
Min (x/y) = 0.25/0.64 = 25/64 = 25/65 (Approx) = 5/13 (Approx)
Max (x/y) = 0.34/0.55 = 34/55 = 35/55 (Approx) = 7/11 (Approx)
Answer: option C
Question: The perimeter of a square is equal to the perimeter of a rectangle of length 17 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)
A.23.57
B.23.54
C.23.5
D.24.35
Answer: D.24.35
Explanation: Let the side of the square be a cm.
Perimeter of the rectangle = 2(17 + 14) = 62 cm
Perimeter of the square = 62 cm
i.e. 4a = 62
A = 15.5
Diameter of the semicircle = 15.5 cm
Circumference of the semicircle
= 1/2(∏)(15.5)
= 1/2(22/7)(15.5) = 24.35 cm to two decimal places
Answer: D
Question: If r and s are positive integers and r-s=6, which of the following has the greatest value K?
A.2r
B.2s
C.r +s
D.2r-s
Answer: A.2r
Explanation: You can answer this question by using Number Properties and logic or by TESTing VALUES.
We're told that R and S are POSITIVE INTEGERS and that R-S = 6. We're asked which of the 5 answers has the GREATEST value.
IF....
R = 8
S = 2
Answer A: 2R = 2(8) = 16
Answer B: 2S = 2(2) = 4
Answer C: R+S = 8+2 = 10
Answer D: 2R-S = 2(8) - 2 = 14
Answer E: 2S-R = 2(2) - 8 = -4
Final Answer:
A
Question: Felix earned 30% more per month than Oscar. If Felix’s salary is decreased 10% and Oscar’s salary is increased by 10%, then Felix would be earning what percent more than Oscar?
A.10%
B.9.09%
C.7%
D.6.36%
Answer: D.6.36%
Explanation: the very first step requires taking some numbers for each..
ONE should be 100...
it is easy to take 70 and 100 here..
but the BASE is 100 here, so the salary can be 100 and 130..
100 increases 10% =110..
130 decreases 10%=117..
so the increase is 7..
again the BASE is 110, so answer 7/110 * 100= 6.36% D
without calculations,
answer cannot be equal to or greater than 7, as 7 is on 110..
so D is the only one left
ANSWER:D
Question: 1/5 of a number is equal to 5/8 of the second number. If 35 is added to the first number then it becomes 4 times of second number. What is the second number ?
A.125
B.70
C.40
D.25
Answer: C.40
Explanation: Answer
Let first and second numbers are p & q.
p/5 = 5q/8
∴ p/q = 25/8 ...(i)
p + 35 = 4q
or 25q/8 + 35= 4q
∴ q = 40
Correct Option: C
Question: A and B can do a work in 4 hours and 12 hours respectively. A starts the work at 6AM and they work alternately for one hour each. When will the work be completed?
A.3 days
B.6 days
C.7 days
D.2 days
Answer: B.6 days
Explanation: B
6 days
Work done by A and B in the first two hours, working alternately = First hour A + Second hour B = 1/4 + 1/12 = 1/3.
Total time required to complete the work = 2 * 3 = 6 days.
Question: The difference of the squares of two consecutive even integers is divisible by which of the following integers ?
A.3
B.4
C.6
D.7
Answer: B.4
Explanation: Let the two consecutive even integers be 2n and (2n + 2). Then,
(2n + 2)2 = (2n + 2 + 2n)(2n + 2 - 2n)
= 2(4n + 2)
= 4(2n + 1), which is divisible by 4.
ANSWER B
Question: Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability E that Jane will be on the same committee as Albert?
A. 12%
B. 20%
C. 33%
D. 40%
Answer: D. 40%
Explanation: Total number of ways to choose 3 member committee - 6C3=(6!/3!3!)=20
No. of ways Albert n Jane are in same committee:- (4C1 * 2)= 8
Probability E= (8/20) *100 =40%.
+1 for me.. :D
Question: Insert the missing number. 2, 7, 10, 22, 18, 37, 26, 52, 34,
A.42
B.52
C.77
D.62
Answer: C.77
Explanation: Explanation :
There are two series here
2, 10, 18, 26, 34 ... (Increase by 8)
7, 22, 37, 52 ... (Increase by 15)
Hence, next term is 52+15 = 77
Answer : Option C
Question: Rajiv can do a piece of work in 10 days , Venky in 12 days and Ravi in 15 days. They all start the work together, but Rajiv leaves after 2 days and Venky leaves 3 days before the work is completed. In how many days is the work completed ?
A.7
B.8
C.98
D.6
Answer: A.7
Explanation: Explanation: Let the work be 60 units. If venky leave 3 days before the work, Last 3 days must be worked by Ravi. So the remaining days of work be x days, total days to complete the work be x + 3 days.
Now Capacities of Rajiv is 60/10 = 6, Venky is 5, Ravi is 4.
(6 + 5 + 4) 2 + (5 + 4) (x – 3) + 4 x 3 = 60.
30 + 9x – 27 + 12 = 60
9x – 15 =30
9x = 45
x = 5
So total days to complete the work = 2 + 5 = 7 days.
Answer:A
Question: In a flower shop there were 4 flowers in each bouquet. If the seller has doubled the number of flowers in each bouquet then the new average of flowers in each bouque is
A.12
B.3
C.8
D.9
Answer: C.8
Explanation: Answer
Now required average
= old average x Multiplicand
= 4 x 2 = 8
Correct Option: C
Question: The 100-milliliter solution of sugar and water is 12% sugar. How much water (in milliliters) must be added to make a solution that is 8% sugar?
A.30
B.40
C.50
D.60
Answer: C.50
Explanation: In the original solution the amount of sugar is 0.12*100=12 ml.
Let the volume of the new solution be V.
0.08V=12 ml.
V=150 ml.
The amount of water we need to add is 150 - 100 = 50 ml.
The answer is C.
Question: How many Single-digit whole numbers yield a remainder of 1 when divided by 10 and also yield a remainder of 1 when divided by 6?
A.None
B.One
C.Two
D.Three
Answer: B.One
Explanation: The possible number N can be written as follow:
N = Multiple of LCM(6,10) + 1st such number
N = 30x + 1
Possible values = 1
Answer : B
Question: A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
A.10 liters
B.11 liters
C.18 liters
D.19 liters
Answer: A.10 liters
Explanation: Number of liters of water in 125 liters of the mixture = 20% of 150 = 1/5 of 150 = 30 liters
Let us Assume that another 'P' liters of water are added to the mixture to make water 25% of the new mixture. So, the total amount of water becomes (30 + P) and the total volume of the mixture becomes (150 + P)
Thus, (30 + P) = 25% of (150 + P)
Solving, we get P = 10 liters
Answer: A
Question: There are 4 prime numbers in ascending order. The multiplication of 1st 3 is 385 and that of last 3is 1001. what is the last no. is?
A.8
B.10
C.11
D.13
Answer: D.13
Explanation: abcbcd=3851001=>ad=513
abcbcd=3851001=>ad=513
So d = 13
D
Question: In an election between two candidates, 10% of votes are were declares invalid. First candidate got 7200 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:
A.9000
B.98000
C.40000
D.11000
Answer: C.40000
Explanation: 100 % - 10 % = 90 %
54%-36%=18%
18% ------> 7200 ( 18 × 400 = 7200)
100% -------> 40000 votes (100 × 400 = 40000)
C
Question: One side of a rectangular field is 16 m and one of its diagonal is 17 m. Find the area of the field.
A.100
B.120
C.91.2
D.180
Answer: C.91.2
Explanation: Solution
Other side = √(17)2 - (16)2
= √289 - 256
= √33
= 5.7 m.
∴ Area = (16 x 5.7)m2 = 91.2 m2.
Answer C
Question: Robert is travelling on his cycle and has calculated to reach the point A at 2 pm .if he travells at 10kmph;he will reach there at 12 noon if he travels at 15 kmph . at what speed he must travel to reach A at 1p.m
A.65km
B.85km
C.36km
D.12km
Answer: D.12km
Explanation: let the distance travelled be x km
Then x/10-x/15=2
3x-2x=60
x=60km
time taken to travel 60km at 10km/hr=(60/10)hrs=60hrs
so robert stared 6hrs before 2p.m ie 8 A.m
therefore the required speed =(60/5)kmph =12kmph
answer is (D)
Question: Which fraction should be added to:
1/(2 Ã— 3) + 1/(3 Ã— 4) + 1/(4 Ã— 5) + ....... + 1/(25 Ã— 26)
so that the result is equal to 1?
A.5/13
B.6/13
C.7/13
D.8/13
Answer: C.7/13
Explanation: The given expression
= 1/(2 Ã— 3) + 1/(3 Ã— 4) + 1/(4 Ã— 5) + ...... + 1/(25 Ã— 26)
= (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + .......... + (1/25 - 1/26)
= 1/2 - 1/26 = 12/26
Thus, the fraction we should add = 1 - 12/26 = 7/13
The answer is C.
Question: The total age of A and B is 14 years more than the total age of B and C. C is how many year younger than A
A.11
B.12
C.13
D.14
Answer: D.14
Explanation: Explanation:
Given that A+B = 14 + B + C
=> A ? C = 14 + B ? B = 14
=> C is younger than A by 14 years
Answer: Option D
Question: A furniture manufacturer has two machines, but only one can be used at a time. Machine P is utilized during the first shift and Machine B during the second shift, while both work half of the third shift. If Machine P can do the job in 12 days working two shifts and Machine B can do the job in 15 days working two shifts, how many days will it take to do the job with the current work schedule?
A.14
B.13
C.11
D.9
Answer: D.9
Explanation: machine P finish the job in 2*12 shifts = 24 shifts
machine B finish the job in 2*15 shifts = 30 shifts
Lets assume total work require 120 shifts
Therefore,
rate of P = 5 shifts/day
rate of B = 4 shifts/day
rate of (P+B) = 9 shifts/day
According to current schedule work complete in a day = 5+4+(9/2) =13.5 shifts/day
Therefore, Time required to finish 120 shifts = (120/13.5) = 8.88.. days ~ 9 days=D
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 24 minutes. The waste pipe can empty the full cistern in?
A.A)7
B.B)6
C.C)8
D.D)9
Answer: C.C)8
Explanation: 1/10 + 1/15 - 1/x = 1/24
x = 8
Answer:C
Question: Rates for having a manuscript typed at a certain typing service are $10 per page for the first time a page is typed and $5 per page each time a page is revised. If a certain manuscript has 100 pages, of which 20 were revised only once, 30 were revised twice, and the rest required no revisions, what was the total cost of having the manuscript typed?
A.$1200
B.$1500
C.$1400
D.$1250
Answer: C.$1400
Explanation: 50 pages typed 1x
20 pages typed 2x (original + one revision)
30 pages typed 3x (original + two revisions)
50(10)+20(10+5)+30(10+5+5)=500+300+600=1400
Answer - C
Question: A sum of Rs. 4000 amounts to Rs. 4600 in 5 years at a certain rate of simple interest. What would be the amount, if the rate of interest is increased by 3 %.
A.Rs. 5202
B.Rs. 5200
C.Rs. 5228
D.Rs. 5212
Answer: B.Rs. 5200
Explanation: Explanation:
Principal = Rs. 4000, Amount = Principal + SI = Rs. 4600
SI = Amount – Principal = 4600 – 4000 = Rs. 600
Given : Principal = Rs. 4000, Time = T = 5 years and SI = Rs. 600
SI =PRT/100
600 = 4000 *R * 5/100
600 = 200R
R = 3 % p.a.
Now the new interest rate is = 3% + 3% = 6 % p.a.
SI = PRT/ 100 = 4000 * 6 * 5/ 100 = Rs. 1200
Amount = Principal + SI
= 4000 + 1200
= 5200
ANSWER:B
Question: A man's speed with the current is 22 km/hr and the speed of the current is 5 km/hr. The man's speed against the current is
A.9
B.10
C.11
D.12
Answer: D.12
Explanation: Man's rate in still water = (22 - 5) km/hr = 17 km/hr.
Man's rate against the current = (17 - 5) km/hr = 12 km/hr.
Answer:D