RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: 5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3443, how much was it in the beginning?
A.4264
B.2776
C.4400
D.2871
Answer: A.4264
Explanation: X * (95/100) * (85/100) = 3443
X = 4264
Answer:A
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
A.177 m
B.166 m
C.776 m
D.150 m
Answer: D.150 m
Explanation: Speed=(60 * 5/18) m/sec
= (50/3) m/sec Length of the train
= (Speed x Time)
= (50/3 * 9) m = 150 m.
Answer:D
Question: If r = 2^4 * 5^2 * 7 and s = 2 * 3^2 * 5, which of the following is equal to the greatest common divisor of r and s?
A.2 * 5
B.2^2 * 5
C.2^3 * 5^2
D.2*3*5*7
Answer: A.2 * 5
Explanation: GCD = product of prime factors raised to the least power = 2 * 5
The answer is A.
Question: A company produces 72000 bottles of water everyday. If a case can hold 10 bottles of water .How many cases are required by the company to hold its one day production
A.2000
B.4500
C.5000
D.7200
Answer: D.7200
Explanation: Number of bottles that can be held in a case =10
Number of cases required to hold 72000 bottles = 72000/10=7200 cases.
So the answer is D =7200
Question: For any integer n greater than 1, [n denotes the product of all the integers from 1 to n, inclusive. How many prime numbers are there between [6 + 2 and [6 + 6, inclusive?
A.None
B.One
C.Two
D.Three
Answer: A.None
Explanation: Given that [n denotes the product of all the integers from 1 to n, inclusive so, [6+2=6!+2 and [6+6=6!+6.
Now, notice that we can factor out 2 our of 6!+2 so it cannot be a prime number, we can factor out 3 our of 6!+3 so it cannot be a prime number, we can factor out 4 our of 6!+4 so it cannot be a prime number, ... The same way for all numbers between 6*+2=6!+2 and 6*+6=6!+6, inclusive. Which means that there are no primes in this range.
Answer: A
Question: The present worth of a bill due sometime hence is Rs. 1100 and the true discount on the bill is Rs.110.Find the banker's discount and the banker’s gain?
A.Rs.111
B.Rs.120
C.Rs.121
D.Rs.125
Answer: C.Rs.121
Explanation: Solution
T.D	=	√P.W x B.G
B.G	= (T.D)² / P.W
= Rs(110x110/1100)
= Rs.11.
B.D	= (T.D + B.G)
= Rs(110+11)
= Rs.121.
Answer C
Question: The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum.
A.Rs.18000
B.Rs.17000
C.Rs.18500
D.Rs.17500
Answer: B.Rs.17000
Explanation: The simple interest for the first year is 10200/2 is Rs.5100 and compound interest for first year also is Rs.5100. The compound interest for second year on Rs.5100 for one year
So rate of the interest = (100 * 1530)/ (5100 * 1) = 30% p.a.
So P = (100 * 10200)/ (30 * 2) = Rs.17000
ANSWER:B
Question: The marks obtained by Polly and Sandy are in the ratio 4:5 and those obtained by Sandy and Willy are in the ratio of 5:2. The marks obtained by Polly and Willy are in the ratio of...?
A.2:1
B.3:2
C.4:3
D.5:4
Answer: A.2:1
Explanation: Polly : Sandy = 4:5
Sandy : Willy = 5:2
Polly : Sandy : Willy = 4:5:2
Polly : Willy = 4:2 = 2:1
The answer is A.
Question: A bus trip of 550 miles would have taken 1 hour less if the average speed V for the trip had been greater by 5 miles per hour. What was the average speed V, in miles per hour, for the trip?
A.40
B.45
C.50
D.55
Answer: C.50
Explanation: The time is the distance/speed. The time difference is 1 hour.
550/V - 550/(V+5) = 1
550(V+5) - 550V = (V)(V+5)
2750 = (V)(V+5)
50*55 = (V)(V+5)
V = 50 mph
The answer is C.
Question: If q is an integer greater than 6, which of the following must be divisible by 3?
A.Q(Q+1)(Q-4)
B.N(N+2)(N-1)
C.N(N+3)(N-5)
D.N(N+4)(N-2)
Answer: A.Q(Q+1)(Q-4)
Explanation: Now take Q = 3k , Q = 3k+1 Q = 3k+2..put in all the choices. If by putting all the values of Q we get it is divisible by 3, then it is correct answer choice.
A is correct. It will hardy take 10 sec per choice as we have to consider only 3k+1 and 3k+2.
Question: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
A.122.9 m
B.127.5 m.
C.122.2 m
D.222.9 m
Answer: B.127.5 m.
Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.
When B runs 900 m, distance that C runs = (900 * 700)/800
= 6300/8
= 787.5 m.
In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C.
In a race of 600 m, the number of meters by which A beats C = (600 * 212.5)/1000
= 127.5 m.
Answer:B
Question: How many integers are between 7 and 120/9, inclusive?
A.5
B.6
C.7
D.9
Answer: C.7
Explanation: 120/9 = 13.xx
We are not concerned about the exact value of 120/9 as we just need the integers.
The different integers between 7 and 120/9 would be 7, 8, 9, 10, 11, 12,13
Total number of integers = 7
Option C
Question: The salary of a worker is first increased by 15% and afterwards reduced by 15%. What is the net change in the worker's salary?
A.5.25% increase
B.5.25% decrease
C.2.25% increase
D.2.25% decrease
Answer: D.2.25% decrease
Explanation: Let x be the original salary.
The final salary is 0.85(1.15x) = 0.9775x
The answer is D.
Question: In x-y plane, there is a right triangle ABC (∠B=90o). If the length of AC is 25 and the slope of line segment AC is 4/3, what is the length of AB?
A.12
B.18
C.20
D.28
Answer: C.20
Explanation: Slope = Change in Vertical Direction/Change in Horizontal Direction = 4/3
Change in Vertical Direction = 4x = AB
Change in Horizontal Direction = 3x = BC
AB^2 + BC^2 = 25^2
16x^2 + 9x^2 = 625
25x^2 = 625
x^2 = 25
x = 5
Therefore AB = 5*4 = 20
Answer: C
Question: An express traveled at an average speed of 120 km/hr, stopping for 3 min after every 90 kn. How long did it take to reach its destination 600 km from the starting point?
A.5 hrs 21 min
B.4 hrs 21 min
C.6 hrs 41 min
D.5 hrs 15 min
Answer: D.5 hrs 15 min
Explanation: D
6 hrs 21 min
Time taken to cover 600 km = 600/120 = 5 hrs.
Number of stoppages = 600/90 - 1 = 5
Total time of stoppages = 3 * 5 = 15 min
Hence, total time taken = 5 hrs 15 min.
Question: The set X = {10,11,12,13}. The set Y = {2,3,4,5}. We will randomly choose one element x from set X and one element y from set Y. What is the probability that x / y will be an integer?
A.9/16
B.7/16
C.5/16
D.5/8
Answer: C.5/16
Explanation: The total number of x and y pairs is 4*4=16.
There are five pairs such that x / y is an integer.
The probability that x / y is an integer is 5/16.
The answer is C.
Question: A passenger sitting near the window in a train moving at 45 km/h, noticed that it took 3 sec. for the oncoming train to pass by. What was the speed of the oncoming train if the length of the oncoming train was 75 metres?
A.a)50km/h
B.b)52km/h
C.c)45km/h
D.d)60km/h
Answer: C.c)45km/h
Explanation: im getting A
3 secs to pass a 75 mts train , therefore speed = 25 meters/sec
to convert m/s to km/hrs multiply by 3.6
25*3.6 = 90
so its 90-45 = 45 .
C
Question: How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
A.3.5 years
B.4 years
C.4.5 years
D.5 years
Answer: B.4 years
Explanation: Time = (100 x 81)/(450 x 4.5) = 4 years.
Answer: Option B
Question: Find last two digits of the following expression (201*202*203*204*246*247*248*249)^2
A.33Q76
B.76
C.20
D.27
Answer: B.76
Explanation: To find the last two digits of a product take the last two digits in each number and multiply. 01*02*03......48*49 (use onscreen calculator)
this gives 76. So 762762 = 576 So last two digits are 76
Answer:B
Question: A work can be finished in 16 days by 30 women. The same work can be finished in 10 days by sixteen men. The ratio between the capacity of a man and a woman is
A.3:1
B.4:3
C.2:3
D.2:1
Answer: A.3:1
Explanation: Work done by 30 women in 1 day = 1/16
Work done by 1 woman in 1 day = 1/(16×30)
Work done by 16 men in 1 day = 1/10
Work done by 1 man in 1 day = 1/(10×16)
Ratio of the capacity of a man and woman =1/(10×16) : 1/(16×30) = 1/10 : 1/30
= 1/1 :1/3 = 3:1
Option A
Question: If a, b, c and d are positive integers and a/b < c/d, which of the following must be true?
I. (a+c)/(b+d) < c/d
II. (a+c)/(b+d) < a/b
III. (a+c)/(b+d) = a/b +c/d
A.None
B.I only
C.II only
D.I and II
Answer: B.I only
Explanation: If a, b, c and d are positive integers and a/b < c/d, which of the following must be true?
Since the numbers are positive we can safely cross-multiply. So, we are given that ad<bcad<bc.
I. a+cb+d<cda+cb+d<cd = ad+cd<bc+cd
ad+cd<bc+cd= cdcd cancels out: ad<bc. This is given to be true.
II. a+cb+d<aba+cb+d<ab = ab+bc<ab+adab+bc<ab+ad= ab
ab cancels out: bc<ad bc<ad. Opposite what is given, thus this option is not true.
III. a+cb+d=ab+cda+cb+d=ab+cd. From I we already know that a+cb+d<cda+cb+d<cd, thus when we add a positive value (abab) to (cdcd)we make the right hand side even bigger.Thus a+cb+d=ab+cda+cb+d=ab+cd cannot be true.
Answer: B.
Question: For a road work, a contractor was given a deadline to complete the work in 25 days. Hence, he employed a certain number of workers to accomplish the job. But from the very first day 9 workers were absent and the remaining workers could finish the work in 40 days. What number of workers did the contractor hired in the beginning?
A.20
B.30
C.24
D.16
Answer: C.24
Explanation: Explanation :
Let the number of workers initially hired be x.
Hence, x workers can complete the work in 25 days and (x-9) workers can complete the work in 40 days.
Now, the number of men and the amount of work are in direct proportion and number of men and number of days in indirect proportion.
x*25 = (x 9)*40
25x = 40x 360
15x = 360
x = 24
Answer : C
Question: It rained on exactly 7 of the days during Jane's summer holiday trip. On
each day that it rained, it rained either in the morning or the afternoon
but not both. There were exactly 5 afternoons when it did not rain and
exactly 6 mornings when it did not rain. How many days did the trip
last?
A.7
B.8
C.9
D.10
Answer: C.9
Explanation: Let M be the number of days it rained in the morning; A - the number of
days it rained in the afternoon; and let N be the number of days when it did not rain.
We have M + A = 7 (days when it rained); M + N = 5 (afternoons when it did not
rain); and A + N = 6 (mornings when it did not rain). Adding the equations we get
2(M + A + N) = 18, M + A + N = 9.
correct answer C
Question: The simple form of the ratio 2/3:2/5 is?
A.5:6
B.5:1
C.5:7
D.5:3
Answer: D.5:3
Explanation: 2/3 : 2/5 = 10:6
=5:3
Answer:D
Question: A box contains 4 red chips and 5 blue chips. If two chips are selected at random without replacement, what is the probability that the chips are different colors?
A.1/2
B.5/9
C.7/12
D.2/3
Answer: B.5/9
Explanation: Total selection ways: 9C2=9!/5!4!=36
Selecting one blue chip out of two: 5C1=5!/4!1!=5
Selecting one red chip out of four: 4C1=4!/1!3!=4
Thus, (5C1*4C1)/9C2=(5*4)/36=20/36=5/9=B
Question: Walking at 8KMPH From Point R to Point railway station, mike will miss the train by 5 minutes. If he walks at 10KMPH he will reach the station by 5 minutes early.What is the distance between Point R to Railway station?
A.A)9KM
B.B)6.66KM
C.C)7.25KM
D.D)12.40KM
Answer: B.B)6.66KM
Explanation: Since time differences given are in minutes so let's convert speed in Km per minute
8 kmph = 8/60 km per minute = (2/15) km per minute
10 kmph = 10/60 km per minute = (1/6) km per minute
Let, Time of train to depart from station = t minutes
Distance between Point R and Railway Station = Speed*Time = (2/15)*(t+5)
Distance between Point R and Railway Station = Speed*Time = (1/6)*(t-5)
i.e. (2/15)*(t+5) = (1/6)*(t-5)
i.e. 12t+60 = 15t - 75
i.e. 3t = 135
i.e. t = 45 minutes
i.e. Distance = (1/6)*(t-5) = (1/6)*(45-5) = 40/6 = 20/3 Km = 6.66 Km
Answer: Option B
Question: A shop sells bicycles and tricycles. In total there are 10 cycles (cycles include both bicycles and tricycles) and 23 wheels. Determine how many of each there are, if a bicycle has two wheels and a tricycle has three wheels.
A.b=7,t=3
B.b=5,t=3
C.b=8,t=2
D.b=2,t=5
Answer: A.b=7,t=3
Explanation: Let b be the number of bicycles and let t be the number of tricycles.
Set up the equations
b+t=10............(1)
2b+3t=23............(2)
Let b be the number of bicycles and let t be the number of tricycles.
Set up the equations
b+t=8............(1)
2b+3t=19............(2)
Rearrange equation (1) and substitute into equation (2)
2b+30-3b=23
-b=-7
b=7
Calculate the number of tricycles t
t=10−b
=10−7
=3
There are 3 tricycles and 7 bicycles.
Answer is A.
Question: 12 buckets of water fill a tank when the capacity of each tank is 13.5 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 9 litres?
A.8
B.15
C.16
D.18
Answer: D.18
Explanation: Solution
Capacity of the tank	= (12×13.5) litres
= 162 litres.
Capacity of each bucket	= 9 litres.
Number of buckets needed	= (162/9)
‹=› 18.
Answer D
Question: On average, the boys in the class have 20 pencils and the girls have 38 pencils. If the overall class average is 30 pencils, what is the ratio of boys to girls in the class?
A.1/2
B.2/3
C.3/4
D.4/5
Answer: D.4/5
Explanation: (38G + 20B) / (G+B) = 30
38G + 20B = 30(G+B)
8G=10B
B/G = 4/5
The answer is D.
Question: What is the ratio of 12 minute to 1 hour ?
A.1/4
B.3/4
C.1/5
D.2/2
Answer: C.1/5
Explanation: C
1/5
Question: Tough and Tricky questions: Work/Rate Problems.
If it takes 70 workers 3 hours to disassemble the exhibition rides at a small amusement park, how many hours would it take 20 workers to do this same job?
A.40/3
B.10.5
C.7
D.7/3
Answer: B.10.5
Explanation: 70 Workers = 3 hours then,
1 Worker = 3*70 Hours
20 Workers = (3*70) /(20) = 10.5 Answer. B
Question: Monica planned her birthday party. She prepared 5 muffins for each of her guests and kept aside two additional muffins in case someone will want extra. After the party, it turned out that one of the guests didn't come but every one of the guests that did come ate six muffins and 7 muffins remained. How many guests did Monica plan on?
A.3.
B.4.
C.1.
D.6.
Answer: C.1.
Explanation: 5N +2 = 7 + 6(N-1)
Solving N= 1
Hence C
Question: A and B enter into a partnership with respective capitals of Rs. 20,000 and Rs. 40,000. At the end of the year, the total profit is Rs. 39,000. If A receives Rs. 15,000 as both his salary and profit, then what is his salary?
A.Rs. 2000
B.Rs. 4000
C.Rs. 3500
D.Rs. 3000
Answer: A.Rs. 2000
Explanation: Explanation:
A's capital : B 's capital
20000 : 40000 = 1 : 2
Since, the time period is fixed, the profit is distributed in the ratio of capital 1 : 2
Profit of A = (1/3) * 39,000 = Rs. 13,000
Salary of A = Rs. (15000 – 13000) = Rs. 2000
ANSWER: A
Question: Jack and Jill work at a hospital with 4 other workers. For an internal review, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen?
A.1/3
B.1/4
C.1/15
D.3/8
Answer: C.1/15
Explanation: Total number of ways to choose 2 out of 6 workers= 6!/2!4!= 15
Number of ways to choose both jack and jill= 1
probability= 1/15
C should be the answer
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
A.5.77 km
B.5.98 km
C.5.76 km
D.5.96 km
Answer: C.5.76 km
Explanation: Explanation:
M = 6
S = 1.2
DS = 7.2
US = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
D = 2.88 * 2 = 5.76
Answer: Option C
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
A.120
B.121.1
C.13
D.156
Answer: B.121.1
Explanation: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.
Answer: Option B
Question: The sum of ages of 5 children born 2 years different each is 50 yrs. What is the age of the Elder child?
A.8
B.14
C.16
D.17
Answer: B.14
Explanation: Let the ages of children be x, (x + 2), (x + 4), (x + 6) and (x + 8) years.
Then, x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 50
5x = 30
x = 6
x+8= 6+8= 14
Answer : B
Question: If x and y are prime numbers, which of the following CANNOT be ( x + Y )?
A.5
B.23
C.13
D.16
Answer: B.23
Explanation: All answer choices but B are odd. In order odd number to be the sum of two prime numbers one must be even, so 2, and another odd.
Now, 23=2+21. Since 21 is not a prime then 23 cannot be written as the sum of two prime numbers.
Answer: B
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
A.22
B.66
C.48
D.77
Answer: C.48
Explanation: Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 6/125 = 48 sec.
Answer:C
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 50, the dividend is:
A.A)5322
B.B)5330
C.C)6300
D.D)5340
Answer: C.C)6300
Explanation: Divisor = (5 * 50) = 250
= 10 * Quotient = Divisor
=> Quotient = 250/10 = 25
Dividend = (Divisor * Quotient) + Remainder
Dividend = (250 * 25) + 50 = 6300.
C
Question: Which of the following is equal to (x+1)!/x!
A.x-1
B.1+(1/x)
C.x+1
D.1
Answer: C.x+1
Explanation: (x + 1)! = (x + 1) * x!
(x + 1)!/x! = x + 1
Answer: C
Question: In how many different number of ways 4 boys and 2 girls can sit on a bench?
A.700
B.710
C.720
D.800
Answer: C.720
Explanation: npn = n!
6p6 = 6 × 5 × 4 × 3 × 2 × 1 = 720
C)
Question: Charlie's lawn service fills up all their gas cans every Friday at Zeb's store. They have to get enough gas for 10 lawn mowers and 10 weed-eaters. The weed-eaters use 5 liters of gas each. The mowers us 60% more than the weedeaters.
Zeb charges .75 cents service per item. Fuel is .40 cents per liter. How much will it cost to fill all mowers and weed-eaters?
A.$77
B.$60
C.$67
D.$62
Answer: C.$67
Explanation: Lots of calculations.
.75*20 + 10*.40*5+ 5*(8/5)*10*.40
Answer=$67
The correct option is C
Question: A tin of oil was 4/5full.when 6 bottles of oil were taken out and four bottles of oil were poured into it, it was ¾ full. how many bottles of oil can the tin contain?
A.40
B.30
C.20
D.50
Answer: A.40
Explanation: Suppose x bottles can fill the tin completely
Then4/5x-3/4x=6-4
X/20=2
X=40
Therefore required no of bottles =40
Answer is A.
Question: A goods train runs at a speed of 72 kmph and crosses a 270 m long platform in 26 seconds.What is the length of the goods train?
A.230 m
B.250 m
C.260 m
D.270 m
Answer: B.250 m
Explanation: s=270+x/t
72*5/18=270+x/26
x=250
ANSWER:B
Question: The cost price of 20 books is the same as the selling price of ’X’ books. If the profit is 25%, then the value of X is ?
A.25
B.18
C.16
D.15
Answer: C.16
Explanation: let S.P. of X books = Rs 100 = C.P. of 20 books
Therefore, C.P. of one book = Rs 5
Profit = 25 %
Therefore, S.P of one book = 6.25
S.P of X articles = 6.25 X
6.25 X = 100 => X = 16
ANSWER:C
Question: he average of 10 numbers is zero. Of them, at the most, how many may be greater than zero?
A.0
B.1
C.10
D.9
Answer: D.9
Explanation: Average of 10 numbers = 0.
Sum of 10 numbers (0 x 10) = 0.
It is quite possible that 9 of these numbers may be positive and if their sum is a the 10th number is (-a).
Answer: Option D
Question: Divide Rs. 1500 among A, B and C so that A receives 1/3 as much as B and C together and B receives 2/3 as A and C together. A's share is?
A.378
B.277
C.375
D.287
Answer: C.375
Explanation: A+B+C = 1500
A = 1/3(B+C); B = 2/3(A+C)
A/(B+C) = 1/3
A = 1/4 * 1500 => 375
Answer: C
Question: Martin has a business washing cars. Last year he washed 20 cars a
week. This year, he wants to increase his business to 1,200 cars a year.
How many cars will he have to wash each month on average?
A.200 cars
B.500 cars
C.300 cars
D.100 cars
Answer: D.100 cars
Explanation: The last year part is extra information. 1200÷12 (months in a year)= 100
He will have to wash 100 cars each month.
correct answer D
Question: A train speeds past a pole in 23 seconds and a platform 125 m long in 33 seconds. Its length is?
A.275
B.287.5
C.288
D.233.5
Answer: B.287.5
Explanation: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 23 => y = x/23
x + 125 / 33 = x / 23
x = 287.5 m.
Answer:B
Question: A vending machine randomly dispenses four different types of fruit candy. There are twice as many apple candies as orange candies, twice as many strawberry candies as grape candies, and twice as many apple candies as strawberry candies. If each candy cost $0.2, and there are exactly 90 candies, what is the minimum amount of money required to guarantee that you would buy at least three of each type of candy?
A.$16.60
B.$20.75
C.$22.50
D.$42.75
Answer: A.$16.60
Explanation: Let number of Apple , Orange , strawberry and grape candies be A, O ,S and G respectively .
A= 2O
S= 2G
A= 2S
A= 4G
A+O+S+G = 90
=>A + A/2 + A/2 +A/4 = 90
=> 9A/4 = 90
=> A = 40
O = 20
S = 20
G = 10
Cost of each candy = .2 $
Mininum amount of money required to guarantee that you would buy at least three of each type of candy
We can buy 40 Apple candies , 20 orange candies , 20 strawberry candies and 3 grape candies to ensure atleast 3 of each type of candies .
Total = 83 candies
Amount required = 83 * .2 = 16.60 $
Answer A
Question: What is the remainder when 14,451 × 15,654 × 16,783 is divided by 5?
A.1
B.3
C.2
D.4
Answer: C.2
Explanation: Only the unit's digit of the product will decide the remainder when divided by 5.
Hence, 1*4*3= will give units digit as 2
So, whatever be the number, if it ends in 2, the remainder after dividing with 5 will be 2.
Option C
Question: In a group of 120 people, 90 have an age of more 30 years, and the others have an age of less than 20 years. If a person is selected at random from this group, what is the probability the person's age is less than 20?
A.60/ 120
B.15 / 120
C.30 / 120
D.80 / 120
Answer: C.30 / 120
Explanation: Number of people whose age is less than 20 is given by
120 - 90 = 30
Probability P that a person selected at random from the group is less than 20 is gieven by
30 / 120 = 0.25
correct answer C
Question: Find the one which does not belong to that group?
A.16
B.36
C.77
D.64
Answer: C.77
Explanation: Explanation:
16, 36, 64 and 4 are perfect squares but not 77.
Answer:C
Question: If one positive integer is greater than another positive integer by 4, and the difference of their cubes is 316, what is their sum?
A.6
B.8
C.10
D.12
Answer: C.10
Explanation: 1^3 = 1
2^3 = 8
3^3 = 27
4^3 = 64
5^3 = 125
6^3 = 216
7^3 = 343
The two numbers are 3 and 7.
The answer is C.
Question: A car X takes 3 hours more than a bus Y in covering 40 km. If the car triples its speed it takes 1 hour less than bus. What is the speed of the car?
A.6 km/hr
B.6.25 km/hr
C.6.67 km/hr
D.7 km/hr
Answer: C.6.67 km/hr
Explanation: Explanation :
Let the car's speed be x km/hr.
=> 40/x-40/(3x)=4
=> 80/3x=4
=> 12x=80
=> x=6.67 km/hr
Answer : C
Question: A can finish a piece of work in 4 days. B can do it in 12 days. They work together for two days and then A goes away. In how many days will B finish the work?
A.6 days
B.5 days
C.7 days
D.4 days
Answer: A.6 days
Explanation: 2/4 + (2 + x)/12= 1 => x =6 days
Answer: A
Question: A local bank that has 9 branches uses a two-digit code to represent each of its branches. The same integer can be used for both digits of a code, and a pair of two-digit numbers that are the reverse of each other (such as 17 and 71) are considered as two separate codes. What is the fewest number of different integers required for the 9 codes?
A.9 codes 3 integers
B.4
C.5
D.6
Answer: A.9 codes 3 integers
Explanation: Pick any two integer.
Integers: 12
Code: 11, 12, 21, 22 = 4 Codes
Add one more integer: 3
13, 31, 33, 23, 32 = 5 Codes
Total = 9 Codes.. Answer: A
Question: If the number 481 * 673 is completely divisible by 9, then the smallest whole number in place of * will be
A.7
B.9
C.12
D.14
Answer: A.7
Explanation: Sum of digits = (4 + 8 + 1 + x + 6 + 7 + 3) = (29 + x), which must be divisible by 9.
x = 7.
A)
Question: If the number 5 * 2 is divisible by 6, then * = ?
A.8
B.6
C.2
D.1
Answer: C.2
Explanation: C
2
6 = 3 x 2. Clearly, 5 * 2 is divisible by 2. Replace * by x.
Then, (5 + x + 2) must be divisible by 3. So, x = 2.