RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: If four machines working at the same rate can do 3/4 of a job in 30 minutes, how many minutes would it take two machines working at the same rate to do 3/5 of the job?
A.48
B.60
C.75
D.80
Answer: A.48
Explanation: using the std formula
m1d1h1/w1=m2d2h2/w2
substituting the values we have
4*1/2*4/3=2*5/3*x (converted 30 min into hours =1/2)
8/3=10/3*x
x=4/5 hour
so 48 minutes
ANSWER:A
Question: Pipe A can fill a tank in 32 minutes. Pipe B can fill the same tank 4 times faster than pipe A. If both the pipes are connected to the tank so that they fill the tank simultaneously, how long will it take for the empty tank to overflow?
A.16/3 minutes
B.32/7 minutes
C.192/7 minutes
D.224/7 minutes
Answer: A.16/3 minutes
Explanation: Pipe A can fill a tank in 32 minutes --> the rate of A = 1/32 tank/minute;
Pipe B can fill the same tank 4 times fasterthan pipe A --> the rate of B = 1/32 + 4/32 = 5/32 tank/minute.
Their combined rate = 1/32 + 5/32 = 3/16 tank/minute;
Therefore, A and B can fill the tank in 16/3 minutes.
Answer: A.
Question: Each person who attended a company meeting was either a stockholder in the company, an employee of the company, or both. If 57 percent of those who attended the meeting were stockholders and 51 percent were employees, what percent were stockholders who were not employees?
A.47
B.49
C.51
D.53
Answer: B.49
Explanation: 57+51=108 so 8% were both stockholders and employees.
The percent who were stockholders but not employees is 57-8=49%
The answer is B.
Question: A Bus is running at 9/10 of its own speed reached a place in 22 hours. How much time could be saved if the bus would run at its own speed ?
A.8.2 hrs
B.6.2 hrs
C.2.2 hrs
D.1.2 hrs
Answer: C.2.2 hrs
Explanation: Explanation:
Let the original Speed be "s" kmph
And the usual time be "t" hrs
Given that if the bus is running at 9s/10 kmph the time is 22 hrs
=> [9s/10] x 22 = t x s
=> 99/5 = t
=> t = 19.8 hrs
Answer: C
Question: If -1 ≤ a ≤ 2 and 1 ≤ b ≤ 3, then least possible value of (2a – 3b) is:
A.-11
B.-3
C.-4
D.-5
Answer: A.-11
Explanation: -1 ≤ a; so a = -1
b ≤ 3; so b = 3
Now, 2a – 3b = -2 - 9 = -11
Therefore, the least value is -11
ANSWER:A
Question: The average age of a group of 5 members is 20 years. Two years later, a new member joins the group. The average age of the group becomes 23 years. What is the age of the new member ?
A.20 years
B.21 years
C.28 years
D.23 years
Answer: C.28 years
Explanation: The average age of a group of 5 members is 20 years --> the sum of the ages is 5*20=100;
Two years laterthe sum of the ages of these 5 members would be 100+5*2=110;
Now, say the age of the new member is x years, so the sum of the ages of a new 6 member group is 110+x. Since given that the average age of this group of 6 members is 23 years then: 23*6=110+x --> x=28.
Answer: C.
Question: The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. Find the length of the rectangle?
A.10 cm
B.40 cm
C.20 cm
D.30 cm
Answer: B.40 cm
Explanation: Let the breadth of the given rectangle be x then length is 2x.
thus area of the given rect is \fn_jvn {\color{Black} 2x^{2}}
after dec 5cm from length and inc 5cm breadth , new lenght becomes 2x-5 and breadth is x+5.thus new area =(2x-5)(x+5)=\fn_jvn {\color{Black} 2x^{2}+5x-25}
since new area is 75 units greater than original area thus
\fn_jvn {\color{Black}2x^{2}+75= 2x^{2}+5x-25}
5x=75+25
5x=100
therefore x=20
hence length of the rectangle is 40 cm.
Answer: B
Question: For any even integer P, 300 multiplied by P is square of an integer. What is the least value of P?
A.3
B.4
C.10
D.12
Answer: A.3
Explanation: p∗3∗10^2=s^2
So, s=√p∗3∗10^2
So, if p = 3 we get a perfect square number !!
Hence answer will be (A) 3
Question: 3^13 + 3^13 + 3^13 =
A.3^11
B.3^13
C.3^14
D.9^15
Answer: C.3^14
Explanation: Since we have 3^13 added together 3 times, we can factor out a 3 and we get 3(3^13) which is equal to 3^14.
The answer is C.
Question: Bil and Jill work at a hospital with 4 other workers. For an internal review, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that Bil and Jill will both be chosen?
A.A)1/3
B.B)1/4
C.C)1/15
D.D)3/8
Answer: C.C)1/15
Explanation: Total number of people = 6
Probability of selecting Bil first and then Jill is 1/6∗1/5=1/30
Probability of selecting Jill first and then Bil is 1/6∗1/5=1/30
Therefore probability of selecting Bil and Jill for the review is 1/30+1/30=1/15
Answer is C
Question: 10 friends went to a hotel and decided to pay the bill amount equally. But 9 of them could pay Rs. 50 each as a result 10th has to pay Rs. 180 extra than his share. Find the amount paid by him.
A.130
B.140
C.110
D.120
Answer: D.120
Explanation: Explanation:
Average amount paid by 9 persons = Rs. 50
Increase in average due to Rs. 50 paid extra by the 10th men = Rs. 180/9= Rs. 20
Therefore, Average expenditure of 10 friends = Rs. 50 + Rs. 20 = Rs. 70
Therefore, Amount paid by the 10th men = Rs. 70 + Rs. 50 = Rs. 120
Correct Option: D
Question: Four people each roll a die once. Find the probability that at least two people will roll the same number?
A.3/18
B.13/18
C.14/18
D.15/18
Answer: B.13/18
Explanation: atleast 2 means
1-p(no one has same number)
p(no person has same number)=6*5*4*3/6^4=10/36
reqd probability=1-10/36
=26/36=13/18
ANSWER:B
Question: The average of first 20 natural numbers is?
A.5.6
B.10.5
C.10.1
D.5.8
Answer: B.10.5
Explanation: Sum of 20 natural no.
= 420/2 = 210
Average = 210/20
= 10.5
Answer:B
Question: What approximate value should come in place of question mark (?) in the following equation
287.532 + 1894.029 – 857.48 = 743.095 + ?
A.870
B.790
C.580
D.770
Answer: C.580
Explanation: ? = 285 + 1895 – 855 – 745 or, ? = 580
Answer C
Question: A train 260 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
A.40 sec
B.50 sec
C.32 sec
D.49 sec
Answer: C.32 sec
Explanation: Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 260 + 140 = 400 m
Required time = 400 * 2/25 = 32 sec
Answer:C
Question: Last year, for every 100 million vehicles that traveled on a certain highway, 40 vehicles were involved in accidents. If 2 billion vehicles traveled on the highway last year, how many of those vehicles were involved in accidents? (1 billion = 1,000,000,000)
A.800
B.900
C.100
D.1000
Answer: A.800
Explanation: To solve we will set up a proportion. We know that “100 million vehicles is to 40 accidents as 2 billion vehicles is to x accidents”. To express everything in terms of “millions”, we can use 2,000 million rather than 2 billion. Creating a proportion we have:
100/40 = 2,000/x
Cross multiplying gives us:
100x = 2,000 * 40
x = 20 * 40 = 800
Answer : A
Question: A coach must choose five starters from a team of 12 players. How many different ways can the coach choose the starters ?
A.237
B.729
C.277
D.166
Answer: B.729
Explanation: Choose 5 starters from a team of 12 players. Order is not important.
12C_{5}}= 729
Answer: B
Question: For which of the following functions is f(d) = f(−d) for all values of d ?
A.f(x) = x^3 + 3
B.f(x) = −x
C.f(x) = 2x + 3
D.f(d) = −d^2 + 2
Answer: D.f(d) = −d^2 + 2
Explanation: f(d) = f(−d)
The above is a property of an even function .
f(d) = f^(n)
f(d) = f(−d) will hold when n is an even integer .
The only case when d is even is option D
Answer D
Question: Find Nikhil's present age, if
I. Five years ago, Nikhil's age was double that of his daughter's age at that time.
II. Present ages of Nikhil and his daughter are in the ratio of 11:6 respectively
III. Five years hence, the respective ratio of Nikhil's age and his daughter age will become 12:7
A.Any two of the three
B.8
C.7
D.6
Answer: A.Any two of the three
Explanation: Explanation:
1) Present ages of Nikhil and his daughter will be 11x and 6x years respectively.
2) 5 years ago, Nikhil's age = 2 * His daughter's age
3) 5 years hence, Nikhil's age / daughter's age = 12/7
Clearly, any two of the above will give Nikhil's present age
Therefore, correct answer is (d).
ANSWER: A
Question: 4 male and 6 female can cultivate a field in 8 days, 7 male and 3 female can cultivate a field in 10 days. then how many days will take to cultivate a field if 10 female works?
A.120/19
B.130/19
C.140/19
D.120/18
Answer: A.120/19
Explanation: 4 male+6female in 8 days=> 32 male+48 female in 1day
7male+ 3 female in 10 days =>70 male+30 female in 1 day
.:32 male+48 female=70 male+30 female
18 female=38 male
1 female= 38/18 male=19/9 male
now,4 male+6 female=4 male+6*(19/9)=50/3 male=150/9 male
we have to find for 10 female workers= 10*(19/9)=190/9 male
more men ,fewer days wud be req to finish work
male days
150/9 8
190/9 x
so, x/8=(150/9)/(190/9)
x=120/19
ANSWER:A
Question: if x:y = 2:3, then find the value of
(7x+3y):(2x+y)
A.23:7
B.15:5
C.16:5
D.17:5
Answer: A.23:7
Explanation: Explanation:
let x = 2k and y = 3k, so
=7(2k)+3(3k)/ 2(2k)+1(3k)
=23k/7k
=23:7
Option A
Question: There are 50 boys in a class. Their average weight is 45 kg. When one boy leaves the class, the average reduces by 100 g. Find the weight of the boy who left the class.
A.40.9 kg
B.42.9 kg
C.49.9 kg
D.39.9 kg
Answer: C.49.9 kg
Explanation: Here one boy is excluded and final average of the group decreases.
∴ change in average is (–)ve = – 0.1 kg.
Using the formula
Sum of the quantities excluded
=(Changein no.ofquantities×Origina lAverage)+(ChangeinAverage×Final no.ofquantities)
⇒ weight of the boy who left = (1 × 45) – (– 0.1 × 49)
= 49.9 kg
Answer C
Question: After a storm deposits 120 billion gallons of water into the city reservoir, the reservoir is 50% full. If the original contents of the reservoir totaled 280 billion gallons, the reservoir was approximately what percentage full before the storm?
A.45%
B.48%
C.54%
D.58%
Answer: C.54%
Explanation: When the storm deposited 115 billion gallons, volume of water in the reservoir = 280 + 120 = 400 billion gallons
If this is only 80% of the capacity of the reservoir, the total capacity of the reservoir = 400/0.5 = 800 billion gallons
Therefore percentage of reservoir that was full before the storm = (280/800)*100 = 35%
Option C
Question: A envelop weight 8.5 gm,if 880 of these envelop are sent with an advertisement mail. How much wieght?
A.6.6kg
B.6.8kg
C.7.48kg
D.6.9kg
Answer: C.7.48kg
Explanation: 880*8.5
7480.0gm
7.48kg
ANSWER:C
Question: How many integers from 0 to 50 inclusive have a remainder of 3 when divided by 6?
A.5
B.6
C.7
D.8
Answer: D.8
Explanation: The numbers should be of the form 6c+3.
The minimum is 3 when c=0.
The maximum is 45 when c=7.
There are 8 such numbers.
The answer is D.
Question: A department of nine people - four men and five women - needs to send a team of five to a conference. If they want to make sure that there are no more than three members of the team from any one gender, how many distinct groups are possible to send?
A.100
B.120
C.150
D.180
Answer: A.100
Explanation: They can make a team of 3 men and 2 women.
The number of ways to do this is 4C3*5C2=4*10 = 40
They can make a team of 2 men and 3 women.
The number of ways to do this is 4C2*5C3=6*10 = 60
The total number of distinct groups is 100.
The answer is A.
Question: A number when successively divided by 5, 3, 2 gives remainder 0, 2, 1 respectively in that order. What will be the remainder when the same number is divided successively by 2, 3, 5 in that order
A.22
B.87
C.26
D.25
Answer: D.25
Explanation: use this simple technique.[ (1 x 3) + 2] = 5
[(5 x 5) + 0] = 25
Answer:D
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
A.13.9 sec
B.12.1 sec
C.17.9 sec
D.61.9 sec
Answer: B.12.1 sec
Explanation: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.
Answer:B
Question: The cost price of 13 articles is equal to the selling price of 11 articles. Find the profit percent?
A.18 2/19%
B.18 2/11%
C.18 2/41%
D.18 4/11%
Answer: B.18 2/11%
Explanation: 13 CP = 11 SP
11 --- 2 CP
100 --- ? =>18 2/11%
Answer: B
Question: If a hostal has eleven romos and two of those romos has view to the lake and others has view to the camp. What is the probability that you get a room with view to the lake?
A.2/8
B.2/11
C.1
D.none
Answer: B.2/11
Explanation: the total number of rooms is 11
and the number of romos with view to the lake is 2
then, in one chance the probability to pick a room with view to the lake is
2/11
Answer B
Question: There were r red balls and y yellow balls in a bag. Three red balls and four yellow ones were added to the bag. What is the probability that a yellow ball and then a red ball will be selected if Jerry pulls out two balls at random, and puts the first ball back before pulling the second ball?
A.(y+4)/(y+r+7)*(r+3)/(y+r+7)
B.(y+3)/(y+r+7) + (r+4)/(y+r+6)
C.(y+3)/(y+r+7)*(r+4)/(y+r+6)
D.(y+3)/(y+r+7)*(r+3)/(y+r+7)
Answer: A.(y+4)/(y+r+7)*(r+3)/(y+r+7)
Explanation: Currently we have r red and y yellow balls.
After adding new balls, we have
red = r + 3
Yellow = y + 4.
Total = r + y + 7
Now question says we are taking one ball first putting it back and then taking another ball. So, it means both the times, the number of ways of selecting one ball will be Total C 1 or (r+y+7)C1
So, Probability of selecting 1st as yellow and then 2nd as red = [(y+4)C1 / (r+y+7)C1] * [(r +3)C1 / (r+y+7)C1]
Answer : option A.
Question: The area of a triangle is with base 4.5m and height 6m?
A.11 m2
B.10 m2
C.13.5 m2
D.19 m2
Answer: C.13.5 m2
Explanation: 1/2 * 4.5 * 6
= 13.5 m2
Answer: C
Question: Anthony and Michael sit on the six member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent R of all the possible subcommittees that include Michael also include Anthony?
A. 20%
B. 30%
C. 40%
D. 50%
Answer: C. 40%
Explanation: The answer is C. Let's look at a committee where Mike belongs (he's person # 1) on that committee. When we choose person #2, there is a 1/5 probability that it's going to be Anthony (then it doesn't matter who the third person is), and 4/5 probability that it's going to be someone else (then person #3 is going to be Anthony with probability 1/4). Total probability R= 1/5+4/5*1/4 = 2/5.C
Question: What is the scope including 1/31+1/32+1/33+......+1/40?
A.1/6~1/5
B.1/5~1/4
C.1/4~1/3
D.1/3~1/2
Answer: C.1/4~1/3
Explanation: For Maximum value : It should be less than 1/31 + 1/31 +1/31... 10 times = 10/31 ~ 1/3
For Minimum Value : It should be greater than 1/40+ 1/40+ 1/40 .. 10 times = 10/40 = 1/4.
Thus, the answer should lie between 1/4 and 1/3. Correct ans : C.
Question: If x and y are positive integers, and 4x^2=3y, then which of the following must be a multiple of 8?
I. x^2
II. y^2
III. xy
A.I only
B.II only
C.III only
D.I and II only
Answer: C.III only
Explanation: 4x^2 = 3y
since x,y are positive integers, x^2 = x*x is divisible by 3 -> x is divisible by 3 and y is divisible by x^2
-> x^2 and y is divisible by 9 -> y^2 is divisible by 9
(1),(2), and (3) must be true
Answer is C
Question: Bert and Rebecca were looking at the price of a condominium. The price of the condominium was 110% more than Bert had in savings, and separately, the same price was also 20% more than Rebecca had in savings. What is the ratio of what Bert has in savings to what Rebecca has in savings.
A.1:5
B.1:4
C.2:3
D.4:7
Answer: D.4:7
Explanation: Suppose bert had 100 so price becomes 210 , this 210 = 1.2 times R's saving .. so R's saving becomes 175
So required ratio is 100:175=4:7
ANSWER:D
Question: If '×' means '+', '+' means '÷', '–' means '×' and '÷' means '–', then 6 × 4 – 5 + 2 ÷ 1 = ?
A.11
B.14
C.15
D.17
Answer: C.15
Explanation: C
6 + 4 × 5 ÷ 2 – 1
= 6 + 4 × 5/2 – 1
= 15
Question: In how many years does a sum of Rs. 5000 yield a simple interest of Rs. 16500 at 15% p.a.?
A.22 years
B.17 years
C.97 years
D.16 years
Answer: A.22 years
Explanation: T = (100 * 16500)/(15 * 5000)
= 22 years
Answer: A
Question: On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 160 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school?
A.600
B.320
C.500
D.520
Answer: B.320
Explanation: Let the number of children in the school be x. Since each child gets 2 bananas, total number of bananas = 2x.
2x/(x - 160) = 2 + 2(extra)
=> 2x - 320 = x => x = 320.
ANSWER:B
Question: On a sum of money, the S.I. for 2 years is $600, while the C.I. is $630, the rate of interest being the same in both the cases. The rate of interest is?
A.8%
B.10%
C.12%
D.14%
Answer: B.10%
Explanation: Difference in C.I. and S.I for 2 years = $630 - $600 = $30
S.I for one year = $300
S.I. on $300 for 1 year = $30
Rate = (100 * 30)/(300) = 10%
The answer is B.
Question: kamal finish a work in 15 days.vimal is 50% more efficient than kamal.then how much time vimal take to finish the work?
A.10 days
B.21/2 days
C.12 days
D.14 days
Answer: A.10 days
Explanation: work of kamal in 1 days=1/15
work of vimal in 1 days=1/15*150%=[1/15*150/100]=1/10
hence,vimal take 10 days to finish the work
answer A
Question: When Rahul was born, his father was 35 years older than his brother and his mother was 27 years older than his sister. If Rahul's brother is 6 years older than him and his mother is 3 years younger than his father, how old was Rahul's sister when he was born ?
A.10 years
B.11 years
C.9 years
D.8 years
Answer: B.11 years
Explanation: When Rahul was born, his brother's age = 6 years; his father's age = (6 + 35) years = 41 years,
his mother's age = (41 - 3) years = 38 years;
his sister's age = (38 - 27) years = 11 years.
Answer: Option B
Question: A certain protective additive increases from 45 days to 60 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive?
A.25%
B.33 1/3%
C.50%
D.66 2/3%
Answer: B.33 1/3%
Explanation: General formula for percent increase or decrease, (percent change):
percent=Change/Original∗100
So, the time between maintenance checks increased by 60−45/45∗100=33 1/3
Answer: B.
Question: If the wheel is 14 cm then the number of revolutions to cover a distance of 1056 cm is?
A.14
B.86
C.16
D.12
Answer: D.12
Explanation: 2 * 22/7 * 14 * x = 1056 => x
= 12
Answer:D
Question: The mean of 25 values was 190. It was detected on rechecking that one value 165 was wrongly copied as 130 for the computation of the mean. Find the correct mean.
A.151
B.149
C.152
D.191.4
Answer: D.191.4
Explanation: Corrected mean = 190×25−130+165/25
= 4750+35/25
=4785/25=191.4
Answer D
Question: A project manager needs to select a group of 3 people from a total of 3 men and 3 women. How many possible group combinations exist such that no group has all men or all women?
A.18
B.24
C.74
D.82
Answer: A.18
Explanation: Since the order in which the group is selected does not matter, we are dealing with a combinations problem (and not a permutations problem).
The formula for combinations is:
N!/((N-K)!K!)
Where N = the total number of elements from which we will select, 6 people in this case.
Where K = the total number of elements to select, 3 people in this case.
The total number of combinations is therefore:
6!/((6-3)!3!) = 20
However, two of these combinations are not valid since they have all members of one gender.
The correct answer is 20-2 = 18. Ans A
Question: A part-time employee whose hourly wage was increased by 20 percent decided to reduce the number of hours worked per week so that the employee's total weekly income would remain unchanged. By what percent should the number of hours worked be reduced?
A.11
B.15
C.16.66
D.17
Answer: C.16.66
Explanation: Let original hourly wage be x and let the no of hours worked be y
Total wage will be =x*y
After the increment the wage will be=1.2 x
Now we need to find number of hours worked so that
x*y=1.2x*z i.e z= 1/1.2 y
%decrease = (y-1/1.2y)/y *100=16.66
Thus my answer is C.
Question: If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same sum at the rate and for the same time?
A.Rs. 51.25
B.Rs. 51.22
C.Rs. 51.219
D.Rs. 51.18
Answer: A.Rs. 51.25
Explanation: Explanation:
Sum = (50 * 100) / (2 * 5) = Rs. 500
Amount = [500 * (1 + 5/100)2] = Rs. 551.25
C.I. = (551.25 - 500) = Rs. 51.25.
Answer:A
Question: In a mixture of milk and water, the proportion of milk by weight was 80%. If, in a 180 gm mixture, 36 gms of pure milk is added, what would be the percentage of milk in the mixture formed?
A.80
B.83.33
C.85
D.90
Answer: B.83.33
Explanation: Percentage of milk in the mixture formed = [80/100 (180) + 36] / (180 + 36) * 100% = (144 + 36)/216 * 100% = 5/6 * 100% = 83.33%.
ANSWER B
Question: A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.340. How much does C have?
A.50
B.40
C.267
D.29
Answer: B.40
Explanation: A+B+C = 500
A+C = 200
B+C = 340
--------------
A+B+2C = 540
A+B+C = 500
----------------
C = 40
Answer: B
Question: How many pieces of 85 cm length can be cut from a rod of 38.25 meters long?
A.25
B.35
C.45
D.55
Answer: C.45
Explanation: Number of pieces = 3825/85 = 45
The answer is C.
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
A.12
B.27
C.36
D.28
Answer: C.36
Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10
= 36 sec.
Answer: C
Question: What is 3 2/3 - 2 1/4 divided by 6/7 - 2/5 ?
A.17/36
B.36/17
C.17/64
D.15/4
Answer: C.17/64
Explanation: 3 2/3 - 2 1/4 = 11/3 - 9/4 = (44 - 27)/12 = 17/12
6/7 - 2/5 = (30-14)/35 = 16/35
So 17/12/16/3 = 17/12 * 3/16 = 17/64
Answer - C
Question: A discount cloth store normally sells all merchandise at a discount of 10 percent to 25 percent off the suggested retail price. If, during a special sale, an additional 30 percent were to be deducted from the discount price, what would be the lowest possible price of an item costing $1000 before any discount?
A.$180.00
B.$545.60
C.$750.00
D.$525.00
Answer: D.$525.00
Explanation: Original price : 1000 $
Max first discount = -25%
Thus : 1000âˆ—(1âˆ’25/100)=750
Second discount on the discounted price = -30%
Thus : 750âˆ—(1âˆ’30/100)=525
Answer D
Question: The population of a city increases at the rate of 4% p.a. but there is an additional annual increase of 1% in the population due to some job seekers. The percentage increase in the population after 2 years is?
A.10.29%
B.10.22%
C.10.25%
D.12.25%
Answer: C.10.25%
Explanation: 100
5 ---- I
5
0.25 --- II
-----------
10.25%
Answer:C
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 36 kmph and 72 kmph. After how much time will the trains meet?
A.10/3 sec
B.20/7 sec
C.33/7 sec
D.21/7 sec
Answer: A.10/3 sec
Explanation: They are moving in opposite directions, relative speed is equal to the sum of their speeds.
Relative speed = (36 + 72)*5/18 = 6*5 = 30 mps.
The time required = d/s = 100/30 = 10/3 sec.
Answer : A