RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: One pipe can fill a pool three times faster than a second pipe. When both pipes are opened, they fill the pool in seven hours. How long would it take to fill the pool if only the faster pipe is used?
A.3.6 hr
B.4.7 hr
C.5.1 hr
D.9.3 hr
Answer: D.9.3 hr
Explanation: fast pipe + slow pipe = together
One pipe fills the pool three times faster than the other pipe so,
hourly fill rates:
1/x + 1/3x = 1/7
Let x = number of hours it would take the fast pipe to fill the pool thus,
x=9.3 hours
Answer: D
Question: Of a certain group of 100 people, 40 graduated from High School M, 65 graduated from College Y, and 30 live in City Z. What is the greatest possible number of people in this group who did not graduate from High School M, did not graduate from College Y, and do not live in City Z ?
A. 5
B. 15
C. 35
D. 65
Answer: C. 35
Explanation: 1. m+y+z+my+yz+mz+myz+ none=100. Fornoneto be maximum others have to be minimum
2. We know the underlined portions sum to 65 and that is the minimum value of others
3. Maximumnone= 100-65=35=C
Question: After spending Rs. 5000 on rent, Rs. 1500 on milk, Rs. 4500 on groceries, Rs.2500 On childrens education Rs. 2000 on petrol and Rs. 5650 on miscellaneous expenses, Mr. Kishore saved 10% of his monthly salary. How much did he save in Rs. ?
A.2160
B.2350
C.2000
D.2300
Answer: B.2350
Explanation: Explanation :
Total Exp = 5000+1500+4500+2500+2000+5650 = 21150
Exp in % = 100-10 = 90%, 21150 = 90%
Saving = 10 % = 21150 X 10/90 = Rs. 2350
Answer : B
Question: 1,1,3,2,1,5,3,4,10,4,2,?
A.10
B.11
C.12
D.13
Answer: A.10
Explanation: 1+1+1=3
2+1+2=5
3+4+3=10
4+2+4=10
ANSWER:A
Question: Dave has no fashion sense, and will wear any combination of garments regardless of whether someone thinks they “match.” Every day Dave chooses an outfit consisting of one of each of the following garments: jacket, tie, shirt, pants, boxers, right sock, left sock, right shoe, left shoe. If Dave has more than one of each of the listed garments, and can make 7200 different outfits, then for how many garments does Dave have exactly five choices?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: 7200 = 72*100 = 72*5^2*2^2
Dave has exactly 5 choices for two garments.
The answer is C.
Question: What is the least common multiple of 12, 18, and 24?
A.72
B.120
C.240
D.360
Answer: A.72
Explanation: Let us first write the numbers in the form of prime factors:
12 = 2^2 * 3^1
18 = 2^1 * 3^2
24 = 2 * 17^1
The LCM would be the largest powers of the prime numbers from all these three numbers.
Hence LCM = 72
Option A
Question: The division of a whole number N by 13 gives a quotient of 15 and a remainder of 2. Find N.
A.797
B.197
C.597
D.997
Answer: B.197
Explanation: According to the division process of whole numbers, N can be written, using multiplication, as follows
N = quotient *divisor + remainder = 15* 13 + 2 = 197 correc answer B
Question: How many positive factors of 42 are not factors of 56?
A.1
B.2
C.3
D.four
Answer: D.four
Explanation: 42=2*3*7.
So, total number of factors for 42 = 2*2 *2 = 8
factors for 42 = 1,2,3,6,7,14,21 and 42
56=2*2*2*7
So, total number of factors for 56 = 4*2 = 8
factors of 56 = 1,2,4,7,8,14,28 and 56.
Factors same in 42 and 56 are 1,2,7 and 14.
Hence, answer will be D.
Question: A dog takes 5 leaps for every 8 leaps of a hare. If one leap of the dog is equal to 5 leaps of the hare, the ratio of the speed of the dog to that of the hare is :
A.25 : 10
B.25 : 8
C.25 : 9
D.8 : 25
Answer: B.25 : 8
Explanation: Explanation:
Dog : Hare = (5*5) leaps of hare : 8 leaps of hare = 25 : 8
Answer: B
Question: If integer k is equal to the sum of all even multiples of 15 between 390 and 615, what is the greatest prime factor of k?
A.5
B.7
C.8
D.13
Answer: C.8
Explanation: if we break down what the stem is asking what is the sum of all mult of 30 between 390 and 600.
using arithmetic progression to find n : 600 = 390 + (n - 1) 30
210+ 30 = 30n
240 = 3n => n = 8
the sum would be: 8* mean
mean = [600 + 390] / 2 = 495
8*495
C
Question: If 6 men and 2 boys working together, can do four times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time?
A.3:2
B.2:2
C.3:4
D.1:2
Answer: B.2:2
Explanation: B
2:2
6M + 2B = 4(1M + 1B)
6M + 2B = 4M + 4B
2M = 2B
The required ratio of work done by a man and a boy = 2:2
Question: How long does a train 150 m long traveling at 50 kmph takes to cross a bridge of 250m in length?
A.28.8 sec
B.16.8 sec
C.15.2 sec
D.25.4 sec
Answer: A.28.8 sec
Explanation: D = 150 + 250 = 400 m
S = 50 * 5/18 = 125/9
T = 400 * 125/9 = 28.8 sec
ANSWER:A
Question: In a city, the streets are aligned in a grid, where the east-west roads are called 1st Rd, 2nd Rd, 3rd Rd, etc, increasing in number as one moves northward. The north-south roads are called 1st Ave, 2nd Ave, 3rd Ave, etc, increasing in number as one moves eastward. If Bill needs to walk from the corner of 2nd Rd and 3rd Ave to the corner of 7th Rd and 8th Ave in the shortest possible time, how many different routes could he take?
A.156
B.180
C.225
D.252
Answer: D.252
Explanation: Bills needs to walk 5 blocks north and 5 blocks east.
One possible solution is NNNNNEEEEE.
There are 10C5 = 252 possible solutions.
The answer is D.
Question: How many integers are divisible by 5 between 10! and 10! + 20 inclusive?
A.5
B.7
C.8
D.9
Answer: A.5
Explanation: A - 7
10! is divisible by 5
There are 4 numbers between 10! and 10!+20 that are divisible by 5.
Hence 5
Question: Students at a school were on average 180 cm tall. The average female height was 170 cm, and the average male height was 184 cms. What was the ratio F of men to women?
A. 5:2
B. 5:1
C. 4:3
D. 4:1
Answer: A. 5:2
Explanation: (A)F= 184 x 5 + 170 x 2 = 1260.A
Question: 40 percent of the ducks included in a certain side effects study were male. If some of the ducks had side effects during the study and 35 percent of the ducks who had side effects were male, what was the ratio of the side effect rate for the male ducks to the side effect rate for the female ducks?
A.1/4
B.21/26
C.2/3
D.7/8
Answer: B.21/26
Explanation: Say total male = 40
Total female =60
Required ratio =( .35/40)/ (.65/60) = 21/26 B is the answer
Question: The average of first 17 even numbers is?
A.10
B.11
C.18
D.20
Answer: C.18
Explanation: Sum of 17 even numbers = 17 * 18 = 306
Average = 306/17 = 18
ANSWER:C
Question: Which of the following equivalent to (1/216)^2?
A.(0.01)^3
B.(0.02)^3
C.(0.03)^3
D.(0.04)^3
Answer: B.(0.02)^3
Explanation: (1/36)^2 = (1/6^3)^2 = (1/6)^6 = (1/36)^3 = (0.02)^3
Answer: Option B
Question: On the coordinate plane , points P and U are defined by the coordinates (-1,0) and (3,3), respectively, and are connected to form a chord of a circle which also lies on the plane. If the area of the circle is (25/4) π , what are the coordinates of the center of the circle ?
A. (1.5,1)
B. (2,-5)
C. (0,0)
D. (1,1.5)
Answer: D. (1,1.5)
Explanation: Although it took me 3 mins to solve this question using all those equations, later I thought this question can be solved easily using options.
One property to keep in mind - A line passing through the centre of the circle bisects the chord (or passes from the mid point of the chord).
Now mid point of chord here is (-1+3)/2, (3+0)/2 i.e. (1,1.5) now luckily we have this in our Ans. choice. so definitely this is the ans. It also indictaes that PU is the diameter of the circle.
There can be a case when PU is not a diameter but in that case also the y-coordinate will remain same as it is the midpoint of the chord and we are moving up in the st. line to locate the centre of the circle.
If ans choices are all distinct (y cordinates) ONLY CHECK FOR Y CORDINATE and mark the ans=D
Question: Cheese, bologna, and peanut butter sandwiches were made for a picnic in a ratio of 5 to 7 to 8. If a total of 180 sandwiches were made, how many bologna sandwiches
were made?
A.63
B.30
C.38
D.42
Answer: A.63
Explanation: For deciding such task we should calculate all parts 5 + 7 + 8 = 20 parts
and we should calculate how many sandwiches holds 1 part:
180 / 20 = 9 sandwiches in one part
For bologna we have 7 parts so:
7 * 9= 63
Answer is A
Question: Rs.160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins?
A.100
B.150
C.120
D.130
Answer: C.120
Explanation: 4x 5x 6x
100 50 25
400x + 350x + 150x = 16000
x = 20
6x = 120
ANSWER C
Question: If one length of a square is tripled, and the original parameter is 4y. What is the new length of one of the sides?
A.12y/3
B.2y/2
C.6y/3
D.12y/4
Answer: D.12y/4
Explanation: If the original parameter is 4y, each length of the square is 4y/4. If the parameter is tripled, then each length becomes 3(4y)/4. This is 12y/4. Answer option D.
Question: The number 94 can be written as the sum of the squares of 4 different positive integers in two ways. Of the following, which can be the sum of these 4 integers?
A.9
B.14
C.15
D.18
Answer: B.14
Explanation: The only possible sum for 4 different squares of an integer with total sum number is 95 are :
48 + 36 + 9 + 1 = 95 which are the square from numbers :8, 6, 3, 1 (total sum number is 16)
or
80 + 9 + 4 + 1 = 95 which are the square from numbers : 9, 3, 2, 1 (total sum number is 14)
hence the answer is (B)
Question: A man spends Rs. 1800 per month on an average for the first three months, Rs 1550 for next four months and Rs. 1800 per month for the last five months and saves Rs . 5200 a year. What is his average monthly income?
A.2050
B.2150
C.2250
D.2350
Answer: B.2150
Explanation: Explanation:
Total expenditure for the first 3 months = 3 Ã— 1800 = 5400
Total expenditure for 4 months = 4 Ã— 1550 = 6200
Total expenditure for 5 months = 5 Ã— 1800 = 9000
Total expenditure and saving (which is income for one year)
= 5400 + 6200 + 9000 + 5200 = Rs. 25800
So, Average monthly income = 25800/12 = Rs. 2150
Answer B
Question: If log 27 = 1.434, then the value of log 9 is:
A.0.934
B.0.945
C.0.956
D.0.958
Answer: C.0.956
Explanation: log 27 = 1.434
log (33 ) = 1.434
3 log 3 = 1.434
log 3 = 0.478
log 9 = log(32 ) = 2 log 3 = (2 x 0.478) = 0.956.
Answer: Option C
Question: If a fair coin is flipped three times in a row, what is the probability that there will be at least one head and one tail?
A.3/4
B.11/12
C.15/16
D.31/32
Answer: A.3/4
Explanation: The number of possible outcomes is 2^3 = 8
There is one way to get no heads and one way to get no tails.
Thus there are 6 outcomes with at least one head and one tail.
P(at least one head and one tail) = 6/8 = 3/4
The answer is A.
Question: A boat travels 72 km downstream in 8 hours and 84 km upstream in 12 hours. Find the speed of the boat in still water and the speed of the water current ?
A.6 and 1 kmph
B.8 and 2 kmph
C.8 and 1 kmph
D.9 and 1 kmph
Answer: C.8 and 1 kmph
Explanation: Explanation:
Downstream speed = 72km/8hrs = 9 kmph
upstream speed = 84km/12hrs = 7 kmph
speed of boat = avg of downstream and upstream speeds
speed of boat = (9+7)/2kmph = 8 kmph.
current speed = half of the difference of downstream and upstream speeds
currend speed = (9-7)/2kmph = 1 kmph
Answer: C
Question: If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?
A.22 1/8 %
B.22 9/2 %
C.22 1/7 %
D.22 1/2 %
Answer: D.22 1/2 %
Explanation: 9 = (1*40*R)/100
R = 22 1/2 %
Answer:D
Question: The height of the wall is 6 times its width and lenght of the wall is 7 times its height .if the volume of the wall be 16128 cu.m.its width is
A.4m
B.5m
C.6m
D.7m
Answer: A.4m
Explanation: Explanation:
Let width = x
Then, height=6x and length=42x
42x × 6x × x = 16128
x = 4
Answer: A
Question: The value of a machine is Rs 6,250. It decreases by 20% during the first , 40% during the second year and 30% during the third year. What will be the value of the machine after 3 years?
A.Rs 2,100
B.Rs 2,200
C.Rs 2,152
D.Rs 2,252
Answer: A.Rs 2,100
Explanation: Here A = 6250, x = - 20, y = - 40 and z = - 30
Therefore value of the machine after 3 years
= A ( 1 + x/100) ( 1 + y/100) ( 1 + z/100)
= 6250 ( 1 - 20/100) ( 1 - 40/100) ( 1 - 30/100)
= (6250 x 80 x 60 x 70) / (100 x 100 x 100)
= Rs 2,100
ANSWER:A
Question: Solve the equation for x : 6x - 27 + 3x = 4 + 9 - x
A.4
B.5
C.7
D.9
Answer: A.4
Explanation: A
4
9 x + x = 13 + 27
10 x = 40 => x = 4
Question: In a fraction, if 1 is added to both the numerator at the denominator, the fraction becomes 1/2. If numerator is subtracted from the denominator, the fraction becomes 3/4. Find the fraction.
A.3/7
B.4/7
C.5/7
D.6/7
Answer: A.3/7
Explanation: Let fraction be a/b, where a and b are integers.
"If 1 is added to both the numerator and denominator, the fraction becomes 1/2"
(a+1)/(b+1) = 1/2
2(a+1) = b+1
2a + 2 = b + 1
2a - b = -1
"If numerator is subtracted from the denominator, the fraction becomes 3/4"
a/(b-a) = 3/4
4a = 3(b-a)
4a = 3b - 3a
4a + 3a - 3b = 0
7a - 3b = 0
Now we just need to solve system of linear equations:
2a - b = -1 . . . [1]
7a - 3b = 0 . . . [2]
From [1], we get:
b = 2a + 1
Substituting in this value of b into [2], we get
7a - 3(2a+1) = 0
7a - 6a - 3 = 0
a - 3 = 0
a = 3
b = 2(3)+1
b = 7
So original fraction is a/b = 3/7
ANSWER:A
Question: Given f(x) = 3x – 5, for what value of x does 2*[f(x)] – 10 = f(x – 2) ?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: 2(3x-5)-10 = 3(x-2) - 5
3x = 9
x = 3
The answer is C.
Question: Can you get total of 720 by using six zeros 0,0,0,0,0,0 and any maths operators.
A.650
B.550
C.700
D.720
Answer: D.720
Explanation: D
720
(0!+0!+0!+0!+0!+0!)!
=(1+1+1+1+1+1)!
=(5)!
=6! is 6*5*4*3*2*1=720
Question: A four-digit code can consist of the digits 0 ~ 9 except that it does not contain the digits 1, 2, and 4 at all. If repeated digits are allowed, what is the probability that it has at least one even digit?
A.145/401
B.845/901
C.1145/1401
D.2145/2401
Answer: D.2145/2401
Explanation: P(no even digits) = 4/7*4/7*4/7*4/7 = 256/2401
P(at least one even digit) = 1 - 256/2401 = 2145/2401
The answer is D.
Question: A certain car traveled twice as many miles from Town A to Town B as it did from Town B to Town C. From Town A to Town B, the car averaged 10 miles per gallon, and from Town B to Town C, the car averaged 12 miles per gallon. What is the average miles per gallon that the car achieved on its trip from Town A through Town B to Town C?
A.11.5
B.9.5
C.13.5
D.10.6
Answer: D.10.6
Explanation: step 1) took LCM of 10 and 12.. came as 30. just multiplied by 10...(to make easy calculation)
step 2) 300 distance between B to C... do 300/12 hence 25 gallons used
step 3) twice distance.. hence 300*2= 600... do as above.. 600/10= 60 gallons used
step 4) total gallons.. 25+60=85 gallons
step ) total miles= 300+600= 900 miles
hence.. average of whole journey = 900/85 which comes to 10.6
Answer : D
Question: An average age of A, B and C is 45. If the averageage of A and B be 40 and that of B and C be 43, then the weight of B is
A.25
B.29
C.31
D.35
Answer: C.31
Explanation: Let A, B, C represent their respective age's. Then, we have:
A + B + C = (45 x 3) = 135 .... (i)
A + B = (40 x 2) = 80 .... (ii)
B + C = (43 x 2) = 86 ....(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)
Subtracting (i) from (iv), we get : B = 31.
B's age= 31
C
Question: Annie has 100 cards numbered 1 through 100. If she deals seven cards to Alex, without replacing any of them, what is the probability that Alex will get five consecutive numbers?
A.95!/100!
B.(94! X 7!)/100!
C.(95! X 5!)/100!
D.(96! X 5!)/100!
Answer: B.(94! X 7!)/100!
Explanation: Alex to get 7 consecutive cards in ascending order, to have 7 consecutive at the end is good enough.
There are 94 consecutive numbers in 100: {1, 2, 3, 4, 5, 6, 7}, {2, 3, 4, 5, 6, 7, 8}, ..., {94, 95, 96, 97, 98, 99, 100};
Total ways to pick 7 cards out of 100 is {7!*94!}{100!}.
Answer: B.
Question: A bar over a sequence of digits in a decimal indicates that the sequence repeats indefinitely. What is the value of (10^4 -10^2)(0.0018)?
A.16.82
B.19.82
C.17.82
D.20
Answer: C.17.82
Explanation: You get 10^2 (100-1) (.0018)
we know 18/10000 = .0018
10^2 (99) * (18/10000)
10^2 = 100 and 100^2 = 10000
Cancel out the 100 with the 10^2
Left with 99(18/100).
0.99*18 = 17.82
Answer : C
Question: Find the option to replace the question mark in the series below
5 ? 15 75 525 4725
A.2
B.6
C.7
D.5
Answer: D.5
Explanation: ol: 5 x 1 = 5
5 x 3 = 15
15 x 5 = 75
75 x 7 = 525
525 x 9 = 4725
So ? = 5
Answer:D
Question: A shop sells bicycles and tricycles. In total there are 10 cycles (cycles include both bicycles and tricycles) and 21 wheels. Determine how many of each there are, if a bicycle has two wheels and a tricycle has three wheels.
A.b=9,t=1
B.b=7,t=3
C.b=6,t=2
D.b=2,t=5
Answer: A.b=9,t=1
Explanation: Let b be the number of bicycles and let t be the number of tricycles.
Set up the equations
b+t=10............(1)
2b+3t=21............(2)
Rearrange equation (1) and substitute into equation (2)
2b+30-3b=21
-b=-9
b=9
Calculate the number of tricycles t
t=10−b
=10−9
=1
There are 1 tricycles and 9 bicycles.
Answer is A.
Question: Which of the following are roots of an equation (x^-2)+(3x^-1)-10=0
A.1/5 and -1/2
B.-1/5 and 1/2
C.1/5 and 1/2
D.-1/5 and -1/2
Answer: B.-1/5 and 1/2
Explanation: Given: (x^-2) + (3x^-1) - 10 = 0
Rewrite as: 1/(x²) + 3/x - 10 = 0
Remove fractions by multiplying both sides by x² to get: 1 + 3x - 10x² = 0
Rearrange to get: 10x² - 3x - 1 = 0
Factor to get: (5x + 1)(2x - 1) = 0
So, EITHER 5x + 1 OR 2x - 1 = 0
If 5x + 1 = 0, then x = -1/5
If 2x - 1 = 0, then x = 1/2
So, the roots (solutions) are -1/5 and 1/2
The answer is B.
Question: S and T are two-digit positive integers that have the same digits but in reverse order. If the positive difference between S and T is less than 50, what is the greatest possible value of S minus T?
A.40
B.42
C.44
D.45
Answer: D.45
Explanation: A two-digit integer "ab" can be expressed algebraically as 10a+b.
S-T=(10a+b)-(10b+a)=9(a-b)<50.
The greatest multiple of 9 which is less than 50 is 45.
The answer is D.
Question: Rose is two years older than Bruce who is twice as old as Chris. If the total of the ages of Rose, B and Chris be 27, the how old is Bruce ?
A.8 years
B.10 years
C.12 years
D.13 years
Answer: B.10 years
Explanation: Let Chris's age be x years. Then, Bruce's age = 2x years.Rose's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, Bruce's age = 2x = 10 years.
B
Question: The true discount on a bill due 9 months hence at 16% per annum is Rs. 180.The amount of the bill is
A.Rs. 1386
B.Rs. 1764
C.Rs. 1500
D.Rs. 2268
Answer: C.Rs. 1500
Explanation: Solution
32.5
Let P.W. be Rs. x.Then,S.I. on Rs.x at 16% for 9 months =Rs.180.
∴ x 16 x9/ 12x 1/100}= 180 or x = 1500.
∴ P.W. = Rs. 1500.
Answer C
Question: A store raised the price of an item by exactly 25 percent. Which of the following could NOT be the resulting price of the item?
A.130
B.250
C.375
D.500
Answer: A.130
Explanation: If it raised the value by 25% then the resulting price is 1.25 times the original price. So the final answer has to be a multiple of 1.25. Check the answers.
130 - No
250 - Yes
375 - Yes
500 - Yes
62.50 - Yes
Answer : A
Question: How many shots of 1cm radius can be prepared from a sphere of 7cm radius?
A.343
B.388
C.327
D.88
Answer: A.343
Explanation: 4/3 Ï€ * 7 * 7 * 7 = 4/3 Ï€ * 1 * 1 * 1 * x
x =343
Answer: A
Question: Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 % fescue. If a mixture of X and Y contains 30% ryegrass, what percent of the weight of the mixture is X?
A.10%
B.33 1/3%
C.40%
D.50%
Answer: B.33 1/3%
Explanation: Assuming the weight of the mixture to be 100g**, then the weight of ryegrass in the mixture would be 30g.
Also, assume the weight mixture X used in the mixture is Xg, then the weight of mixture Y used in the mixture would be (100-X)g.
So we can now equate the parts of the ryegrass in the mixture as:
0.4X + 0.25(100-X) = 30
0.4X + 25 - 0.25X = 30
0.15X = 5
X = 5/0.15 = 500/15 = 100/3
So the weight of mixture X as a percentage of the weight of the mixture
= (weight of X/weight of mixture) * 100%
= (100/3)/100 * 100%
= 33%
ANSWER:B
Question: In 1970 there were 8,902 women stockbrokers in the United States. By 1978 the number had increased to 19,947. Approximately what was the percent increase?
A.45%
B.125%
C.145%
D.150%
Answer: B.125%
Explanation: We can use approximation to get the answer quickly.
Like,
19,947 is approx 20000
8902 is approx 8900
So, Total increase = 20000 - 8900 = 11100
Hence, % increase = 11100 / 8900 = approx. 11/9 = 1.22 = approx. 1.25
So, Choice is B.
Question: The area of a square is equal to five times the area of a rectangle of dimensions 125 cm * 64 cm. What is the perimeter of the square?
A.700
B.800
C.900
D.600
Answer: B.800
Explanation: Area of the square = s * s = 5(125 * 64)=> s = 25 * 8 = 200 cm
Perimeter of the square = 4 * 200 = 800 cm.
Answer: Option B
Question: The expression (11.98 x 11.98 + 11.98 x x + 0.02 x 0.02) will be a perfect square for x equal to:
A.0.02
B.0.2
C.0.04
D.0.4
Answer: C.0.04
Explanation: EXPLANATION
Given expression = (11.98)2 + (0.02)2 + 11.98 x x.
For the given expression to be a perfect square, we must have
11.98 x x = 2 x 11.98 x 0.02 or x = 0.04
Answer C
Question: In digging a grave 200 m * 100 m * 3 m the volumes of the dirt to be extracted will be?
A.600 cu.m
B.12000 cu.m
C.6000 cu.m
D.60000 cu.m
Answer: D.60000 cu.m
Explanation: 200 * 100 * 3 = 60000
ANSWER:D
Question: Sreenivas sells a table to Shiva at 10% profit and Shiva sells it to Mahesh at 10% loss. At what price did Sreenivas purchase the table if Mahesh paid Rs. 2178?
A.2887
B.2665
C.2200
D.2665
Answer: C.2200
Explanation: Let the cost price of table for Sreenivas be Rs. x and given that, cost price of table for Mahesh = Rs. 2178.
=> (90%) of (110%) of x = Rs. 2178.
=> (90/100)(110/100)x = 2178
=> x = (2178 * 100)/(9 * 11)
=> x = Rs. 2200
Answer:C
Question: A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 20 hrs and a machine of type S does the same job in 60 hours. If the company used the same number of each type of machine to do the job in 3 hours, how many machines of type R were used?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: Type R completes 1/20 of the job each hour.
Type S completes 1/60 of the job each hour.
Together R and S complete 1/20 +1/60 = 1/15 of the job each hour.
Let n be the number of each type of machine.
3*n*(1/15) = 1 job completed
n = 5
The answer is C.
Question: The ages of X and Y are in the proportion of 6:5 and total of their ages is 44 years. The proportion of their ages after 8 years will be
A.3:6
B.6:3
C.8:7
D.9:5
Answer: C.8:7
Explanation: Explanation:
Let current ages of X and Y correspondingly, is 6A & 5A
Given: 6A + 5A = 44
=> A = 4
Proportion of ages after 0.8 decades will be
6A + 8 : 5A + 8 32:28 (or) 8:7 . Answer: C
Question: The sum of the present ages of A, B, C is 33 years. Three years ago their ages were in the ratio 1:2:3. What is the present age of A?
A.5
B.7
C.9
D.11
Answer: B.7
Explanation: Three years ago:
a:b:c = 1:2:3
Let a = 1x, b = 2x, and c = 3x.
Today:
(x+3) + (2x+3) + (3x+3) = 33
x = 4
So the present age of A is x+3 = 7
The answer is B.
Question: A shop owner has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 years. How much sale must she have in the 6th year so that she gets an average sale of Rs. 6500?
A.5000
B.5500
C.4991
D.5600
Answer: C.4991
Explanation: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991
C
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 7 years ago was 20 years. The present age of the husband is:
A.20 years
B.30 years
C.60 years
D.36 years
Answer: D.36 years
Explanation: D
36 years
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 7 x 2) years = 54 years.
Husband's present age = (90 - 54) years = 36 years.