RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a division sum, the divisor is 12 times the quotient and 6 times the remainder. If the remainder is 24, what is the divident?
A.1738
B.1752
C.1846
D.1648
Answer: B.1752
Explanation: Solution: Dividend= [Divisor*quotient]+Remainder ----> (1).
Given divisor=6*24=144. 12*quotient=144 => quotient=144/12= 12.
substitute these values in the (1) then we get 1752 as dividend.
Answer B
Question: In how many different number of ways 5 men and 2 girls can sit on a shopa which can accommodate persons?
A.180
B.200
C.210
D.220
Answer: C.210
Explanation: 7p3 = 7 × 6 × 5 = 210
C)
Question: Three pounds of 05 grass seed contain 5 percent herbicide. A different type of grass seed, 20, which contains 20 percent herbicide, will be mixed with three pounds of 05 grass seed. How much grass seed of type 20 should be added to the three pounds of 05 grass seed so that the mixture contains 15 percent herbicide?
A.3
B.3.75
C.4.5
D.6
Answer: D.6
Explanation: 05 grass seed contains 5% herbicide and its amount is 3 pound
20 grass seed contains 20% herbicide and its amount is x
when these two types of grass seeds are mixed, their average becomes 15%
thus we have
3(5)+x(20)/(x+3) = 15
15+20x=15x +45
5x=30
or x=6
ANSWER:D
Question: Machine–X produces 50% of the total output and Machine-Y produces 75% of the total output. An average of 16 units out of a thousand goods manufactured by Machine-X and 3 unit of 500 units produced by Machine-X prove to be defective. What is the probability that a unit chosen at random from the total daily output of the factory is defective?
A.0.01
B.0.02
C.0.04
D.0.06
Answer: A.0.01
Explanation: Suppose machine X produce 1000 units
total defective = 16
Machine Y then produces=1500 units
total defective=9
probability=25/2500
=0.01
Answer : A
Question: One side of a rectangular field is 15 m and one of its diagonals is 17 m. Find the area of the field.
A.120
B.147
C.251
D.451
Answer: A.120
Explanation: Other side = ((17) 2- (15)2)(1/2) = (289- 225)(1/2) = (64)(1/2) = 8 m.
Area = (15 x 8) m2 = 120 m2.
Ans: A
Question: 6 points are marked on a straight line and another 8 points are marked on a second straight line with no points in common. How many triangles can be constructed with vertices from among the above points?
A.91
B.105
C.288
D.21
Answer: C.288
Explanation: getting the answer 288 which is not in the choices, what is the source of the problem?
6C2* 8C1 + 8C2* 6C1 = 288
C
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12400 after a year?
A.3630
B.9232
C.3720
D.3720
Answer: C.3720
Explanation: 6300:4200:10500
3:2:5
3/10 * 12400 = 3720
Answer: C
Question: From the word 'CARRIAGE', how many independent words can be made with-out changing the order of the letters and using each letter only once ?
A.5
B.8
C.3
D.2
Answer: C.3
Explanation: Explanation:
The words formed are
CAR, AGE and RIAGE
Answer: C) 3
Question: The value of a machine depreciates at 23% per annum. If its present value is $1,50,000, at what price should it be sold after two years such that a profit of $24,000 is made?
A.$252935
B.$432935
C.$122935
D.$112935
Answer: D.$112935
Explanation: The value of the machine after two years = 0.77 * 0.77 * 1,50,000 = $88,935
SP such that a profit of $24,000 is made = 88,935 + 24,000 = $1,12,935
D
Question: What is the remainder when 9^1 + 9^2 + 9^3 +...+ 9^9 is divided by 9?
A.2
B.3
C.0
D.5
Answer: C.0
Explanation: Notice that in the brackets we have the sum of 9 odd multiples of 9, which yields remainder of 0 upon division by 9.
Answer : C
Question: A river 2m deep and 45 m wide is flowing at the rate of 3 kmph the amount of water that runs into the sea per minute is?
A.4500
B.2678
C.2689
D.2761
Answer: A.4500
Explanation: (3000 * 2 * 5)/60
= 4500 M3
Answer:A
Question: A number is doubled and 9 is added. If the resultant is trebled, it becomes 75. What is that number ?
A.2
B.4
C.5
D.8
Answer: D.8
Explanation: Explanation:
Let the number be v. Then, 3 (2x + 9) = 75.
2x + 9 = 25
=> 2x = 16
=> x = 8
Answer: D) 8
Question: Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In what ratio should these be mixed to get an alloy 17 times as heavy as water?
A.1:2
B.3:2
C.4:1
D.5:2
Answer: C.4:1
Explanation: G = 19W
C = 9W
Let 1gm of gold mixed with x gm of copper to get 1+x gm of the alloy
1gm gold + x gm copper = x+1 gm of alloy
19W+9Wx = x+1 * 17W
19+9x = 17(x+1)
x = 1/4
Ratio of gold with copper = 1:1/4 = 4:1
Answer is C
Question: In what time will the simple interest be 2/5 of the principal at 8 per cent per annum?
A.8 years
B.7 years
C.6 years
D.5 years
Answer: C.6 years
Explanation: Explanation:
Let sum = x.
Then, Amount =2/5 x ,R=8% pa
Here, S.I = 2/5 of sum
Time =( 100 X 2x/x X 5 X 8) = 5 Years
Answer: C
Question: A student needed to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and x. He found the mean to be 12. What is the value of x?
A.7
B.8
C.9
D.6
Answer: A.7
Explanation: (3+11+7+9+15+13+8+19+17+21+14+x)/12 =12
⇒(137+x)/12=12
⇒137+x=144
⇒x=144−137=7
Answer is A.
Question: The Pinedale bus line travels at an average speed of 60 km/h, and has stops every 5 minutes along its route. Yahya wants to go from his house to the Pinedale Mall, which is 9 stops away. How far away, in kilometers, is Pinedale Mall away from Yahya's house?
A.20 km
B.30 km
C.45 km
D.50 km
Answer: C.45 km
Explanation: Number of stops in an hour: 60/5 = 12
Distance between stops: 60/12 = 5 km
Distance between Yahya's house and Pinedale Mall: 5 x 9 = 45 km
IMO, correct answer is "C."
Question: In a certain alphabet, 20 letters contain a dot and a straight line. 36 letters contain a straight line but do not contain a dot. If that alphabet has 60 letters, all of which contain either a dot or a straight line or both, how many letters contain a dot but do not contain a straight line?
A.4
B.3
C.14
D.20
Answer: A.4
Explanation: We are told that all of the letters contain either a dot or a straight line or both, which implies that there are no letters without a dot and a line (no line/no dot box = 0).
First we find the total # of letters with lines: 20 +36 = 56;
Next, we find the total # of letters without line: 60 - 56 = 4;
Finally, we find the # of letters that contain a dot but do not contain a straight line: 4 - 0 = 4.
Question: Choose the missing terms out of the given alternatives.
JE, LH, OL, SQ, ?
A.XW
B.DT
C.WV
D.WX
Answer: A.XW
Explanation: A
XW
The first letter moves 2, 3, 4 ... steps forward. The second letter moves 3, 4, 5 ... steps forward
Question: A bag contains 40 black balls and 50 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
A.2/5
B.5/7
C.1/2
D.1/4
Answer: B.5/7
Explanation: Total number of balls = 40+50 = 70
no. of white balls = 50
probability of drawing a white ball = 50/70 = 5/7
Answer is B
Question: The owner of a furniture shop charges his customer 20% more than the cost price. If a customer paid Rs. 3600 for a computer table, then what was the cost price of the computer table?
A.2299
B.2699
C.3000
D.6725
Answer: C.3000
Explanation: CP = SP * (100/(100 + profit%))
= 3600(100/120) = Rs. 3000
Answer:C
Question: It takes John 5 minutes to walk to the car park and 45 to drive to work. At what time should he get out of the house in order to get to work at 9:00 a.m.?
A.7:30
B.7
C.6:30
D.6
Answer: A.7:30
Explanation: The time it takes John to get to work: time to walk to car park + time to drive
25 + 45 = 70 minutes = 1 hour and 10 minutes
John needs to get out of the house 1 hour and 10 minutes before 9:00 am at
9:00 - 1:10 = 7:30 a.m.
A
Question: A man purchased a grinder for Rs. 420 and sold it at a profit of 10%. The selling price is:
A.Rs. 462
B.Rs. 812
C.Rs. 684
D.None of these
Answer: A.Rs. 462
Explanation: s.p.=110/100 × 420=462
Answer: A
Question: A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
A.320 m
B.350 m
C.650 m
D.None of these
Answer: B.350 m
Explanation: Solution
Speed	= (300 / 18) m/sec
= (50 / 3) m/sec.
Length of the platform be x metres.
Then	= x + 300 /39
= 50 / 3 m/sec
= 3 (x + 300) =1950 .
= 350 m
Answer B
Question: A person covered one-fourth of the total distance at 26 kmph and remaining distance at 24 kmph. What is the average speed for the total distance?
A.91 (1/3) kmph
B.21 (1/3) kmph
C.81 (1/3) kmph
D.21 (1/7) kmph
Answer: B.21 (1/3) kmph
Explanation: Let the total distance be x km
total time taken
= (x/4)/16 + (3x/4)/24
= x/64 + x/32 = 3x/64
Average speed = x/(3x/64)
= 64/3kmph = 21 (1/3)kmph.
Answer:B
Question: How many odd integers from 1 to 100 (both inclusive) have odd number of factors?
A.13
B.14
C.5
D.6
Answer: C.5
Explanation: Integers having odd number of factors will be perfect squares. Odd numbers will have odd perfect squares. Thus, the possible values for the perfect squares are :
1,9,25,49,81 and the corresponding integers are 1,3,5,7,9 (more than 4). Thus C is the correct answer .
Question: At the faculty of Aerospace Engineering, 302 students study Random-processing methods, 232 students study Scramjet rocket engines and 112 students study them both. If every student in the faculty has to study one of the two subjects, how many students are there in the faculty of Aerospace Engineering?
A.444
B.432
C.346
D.422
Answer: D.422
Explanation: 302 + 232 - 112 (since 112 is counted twice )= 422
D is the answer
Question: 20 beavers, working together in a constant pace, can build a dam in 18 hours. How many hours will it take 12 beavers that work at the same pace, to build the same dam?
A.22.
B.24.
C.30.
D.36
Answer: C.30.
Explanation: Total Work = 20*18= 360 Beaver hours
12 Beaver * x =360 Beaver hours
x=360/12=30
ANSWER:C
Question: An Office used three types of envelopes: small,medium and large. They used 80 small envelopes. The no.of Medium envelopes used was 5 times, the no.of small envelopes plus 5/20 of the number of envelopes. The no.of.large envelopes was equals to the no.of small envelopes plus 5/20 of the no.of medium envelope. Altogether, How many envelope did they use?
A.950
B.960
C.972
D.970
Answer: B.960
Explanation: Let the total no. of envelopes be x
No. of small envelopes = 80
No. of medium envelopes =5*80+5/20*x = 400+5/20*x
No. of large envelopes = 80 +5/20(400+5/20*x) = 180+25/400*x
Sum of small, medium and large envelopes = x
80 + 400+5/20*x + 180+25/400*x = x
660 + 5/16*x = x
11/16*x = 660
x = 960
ANSWER:B
Question: Simplify: 1005-1000+10
A.900
B.926
C.1001
D.905
Answer: D.905
Explanation: 1005-1000+10
=1005-(1000/10)
=1005-100
=905.
Answer is D
Question: One ball will drop from a certain height. The height it will reach after rebounding from the floor is 50 percent of the previous height. The total travel is 250cm when it touches the floor on third time. What is the value of the original height?
A.80cm
B.90cm
C.100cm
D.120cm
Answer: C.100cm
Explanation: when Ball comes down, Then i have indicated the distance covered in green
when Ball goes up, Then i have indicated the distance covered in red
Distance travelled uptil the ball touches the floor 3rd time:h+0.5h+0.5 h+0.5*0.5 h+0.5*0.5 h
h + 2 * 0.5 * h + 2 * 0.25 * h = h (1+2*0.5+2* 0.25) = h (1+1+0.5) = 250
2.5 h = 250
h = 100.
C is the answer.
Question: A drum has a combination of 2 liquids X and Y in the proportion 7:5 when 9 L of combination are taken out and the Drum is filled with Y, the proportion of X and Y becomes 7:9. Then how many litres of liquids X was obtained by the Drum initially?
A.21 litres
B.22 litres
C.23 litres
D.24 litres
Answer: A.21 litres
Explanation: Explanation :
=> If the Drum has 7a and 5a litres of combinations X and Y correspondingly. Amount of Combination taken out is 9 litres
Some of X in Combination left = [ 7a - (7/12)*9] litres
= [ 7a - (21/4) ] litres
Some of Y in combination left = [ 5a - (5/12)*9 ] litres
= [ 5a - (15/4) ] litres
=> Since the combination is in the ratio 7:9,
{ [7a - (21/4)] / [ 5a - (15/4) ]+9 } = (7/9) => [ (28a - 21) / (20a + 21) ] = (7/9)
=>252a – 189 = 140a + 147
=> 112a = 336
=> a = 3
Some of liquid X, has in the Drum initially is (7*3) = 21 litres
Answer : A
Question: The average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
A.76 kg
B.80 kg
C.85 kg
D.90 kg
Answer: C.85 kg
Explanation: Solution
Total weight increased	= (8 x 2.5)kg
= 20 kg.
Weight of new person	= (65 + 20)kg
= 85 kg.
Answer C
Question: A soccer store typically sells replica jerseys at a discount of 30 percent to 70 percent off list price. During the annual summer sale, everything in the store is an additional 20 percent off the original list price. If a replica jersey's list price is $80, approximately what percent of the list price is the lowest possible sale price?
A.20
B.25
C.30
D.40
Answer: D.40
Explanation: Let the list price be 2x
for min sale price, the first discount given should be 70%, 2x becomes x here
now, during summer sale additional 20% off is given ie sale price becomes 0.8x
it is given lise price is $80
=> 2x = 80
=> x = 40
and 0.8x = 32
so lowest sale price is 32, which is 40% of 80
hence, D is the answer
Question: 21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement.
A.2/31
B.4/35
C.9/42
D.8/41
Answer: C.9/42
Explanation: The probability that first toy shows the even number,
=1021=1021
Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.
Hence, probability that second toy shows the even number,
=920=920
Required probability,
=(1021)×(920)=(1021)×(920)
=9/42
C
Question: In a local school district, the high school and middle school each received r dollars toward funding for the student arts program. The high school enrolled 400 students and the middle school enrolled 200 students. Later, the middle school transferred s dollars to the high school so that they would have received the same funding per student. Which of the following is equivalent to s?
A.r/2
B.r/3
C.r/4
D.r/5
Answer: B.r/3
Explanation: Total per head = 2r/600
After s transfer both schools have total for head.
So at High School it will be:
r+s = (400)* (2r/600) = 8r/6=4r/3
i.e. s = 4r/3 - r/1 =4r-3r/3=r/3
Answer : B
Question: What is the perimeter of a square with area p^2/16 ?
A.3p/4
B.3p^2/4
C.p
D.3p^2
Answer: C.p
Explanation: Area of square, (side)^2 = (p/4)^2
Therefore side of the square = p/4
Perimeter of square = 4*side = 4* (p/4) = p
Answer is C.
Question: A spirit and water solution is sold in a market. The cost per liter of the solution is directly proportional to the part (fraction) of spirit (by volume) the solution has. A solution of 1 liter of spirit and 1 liter of water costs 50 cents. How many cents does a solution of 1 liter of spirit and 3 liters of water cost?
A.13
B.33
C.56
D.50
Answer: D.50
Explanation: C. 50 cents
Yes, ensure that you understand the relation thoroughly!
Cost per liter = K * Fraction of Spirit
50 cents is the cost of 2 liters of solution (1 part water, 1 part spirit). So cost per liter is 25 cents. Fraction of spirit is 1/2.
25 = K * (1/2)
K = 50
Cost per liter = 50 * (1/4) (1 part spirit, 3 parts water)
Cost for 4 liters = 50 * (1/4) * 4 = 50 cents
D. 50 cents
Question: The difference between the simple interest received from two different sources on Rs. 1000 for 3 years is Rs. 13.50. The difference between their rates of interest is?
A.A)2.4%
B.B)2.6%
C.C)0.3%
D.D)0.25%
Answer: D.D)0.25%
Explanation: (1000 * R1 * 3)/100 - (1000 * R2 * 3)/100 = 13.50 4000(R1 - R2) = 1350
R1 - R2 = 0.25%
Answer:D
Question: Find the compound interest on $1200 for 6 years at 20% p.a. if CI is component yearly?
A.$120
B.$150
C.$2383
D.$250
Answer: C.$2383
Explanation: A = P(1 + R/100)^T
= 1200(1 + 20/100)^6
=$3583
CI = $2383
Answer is C
Question: A bank offers 5% C.I. calculated on half-yearly basis . A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is?
A.Rs.181
B.Rs.121
C.Rs.126
D.Rs.128
Answer: B.Rs.121
Explanation: Amount = [1600 * (1 + 5/(2 * 100)2 + 1600 * (1 + 5/(2 * 100)]
= [1600 * 41/40(41/40 + 1)
= [(1600 * 41 * 81)/(40 * 40)] = Rs. 3321.
C.I. = 3321 - 3200 = Rs. 121.
Answer: B
Question: What is the value of the following expression?
(1/ (2^2 – 1)) + (1/ (4^2 – 1)) + (1/ (6^2 – 1)) + .... + (1/ (24^2 – 1))
A.a. 9/19
B.b. 10/19
C.c. 12/25
D.d. 11/21
Answer: C.c. 12/25
Explanation: it can be written into
1/3+1/15+ 1/35.....1/575
i.e
1/3+1/2*(1/3-1/5)+1/2*(1/5-1/7).... til last term - 1/2*(1/25)
all terms from 1/5 .. to second last term get cancelled
left with
1/3+1/6-1/50=1/2-1/50=24/50=12/25 C
Question: If y ≠ 3 and 2m/y is a prime integer greater than 2, which of the following must be true?
I. m = y
II. y = 1
III. m and y are prime integers.
A. None
B. I only
C. II only
D. III only
Answer: A. None
Explanation: Note that we are asked which of the following MUST be true, not COULD be true. For such kind of questions if you can prove that a statement is NOT true for one particular set of numbers, it will mean that this statement is not always true and hence not a correct answer.
So we should try to make the listed statements not true for some m and y (which satisfy y≠3 and 2m/y=prime>2).
I. m = y --> not necessarily true: m=3 and y=2 (2m/y=3=prime>2);
II. y=1 --> not necessarily true: m=3 and y=2 (2m/y=3=prime>2);
III. m and y are prime integers --> not necessarily true: m=10 and y=4 (2m/y=5=prime>2).
Answer: A.
Question: The sum of two numbers is 75 and their difference is 20. Find the difference of their squares.
A.3000
B.2700
C.1500
D.1254
Answer: C.1500
Explanation: If the sum of two numbers is x and their difference is y, then the difference of their squares is xy.
Here x= 75 and y = 20
75 × 20 = 1500
Question: The value for G=(0.889 × 55)/9.97 to the nearest tenth is
A.0.5
B.4.63
C.4.9
D.7.7
Answer: C.4.9
Explanation: if we read the Q, we can easily home on to the answer,,
the numerator is clearly between 40 and 50..
denomiator is close to 10..
so G=(0.889 × 55)/9.97 is between 4 and 5..
It may tempt us to solve it since ther are two values between 4 and 5..
but the catch is innearest tenth
4.63 can be called nearest to hundreth and no tenth, so can be eliminated..
4.9 is our answer...
C
Question: Two quarts containing 6⁄7 water and 1/7 formula are mixed with three quarts containing 7⁄10 water and 2⁄10 formula. Approximately what percent of the combined five-quart mixture is water?
A.74%
B.76%
C.73%
D.72%
Answer: B.76%
Explanation: 6/7 of 2 quarts = 12/7 quarts of water
7/10 of 3 quarts = 21/10 quarts of water
12/7 = 1.714
21/10 = 2.100
Total water = 1.714 + 2.100= 3.814
Total quarts = 5
3.814/5 = 76.28% approx. 76%
Answer : B
Question: The price of a book is increased from $300 to $360. What is the % of increase in its price?
A.10%
B.20%
C.35%
D.40%
Answer: B.20%
Explanation: Explanation: Change in the price = Rs 360 – Rs 300
= Rs 60
Percentage of increase = Change in the price Initial Price
* 100.
Percentage increase in price =( 60 300
) *100 = 20%
B
Question: Linda and Angela contract to paint a neighbor's house. Even though Linda
spends 75% more time painting the house than Angela, each receives a payment
of m dollars when the work is completed. If Angela decides to pay Linda n
dollars so that they would have received the same compensation per hour
worked, what is n in terms of m?
A.A)(1/2)m
B.B)(1/3)m
C.C)(9/33)m
D.D)(1/5)m
Answer: C.C)(9/33)m
Explanation: let angela work for 12 hrs and get 1650 rs. (m =1650)
According to question, linda works 75% more time and gets the same amount. so let linda work 21 hrs and get 1650 rs.
so they do a total of 21 +12 =33 hrs of work and get 3300 rs together . The question basically asks to equalise their payment. so a total of 3300 rs is received by them and they do 10 hrs work together. average rate will be 3300/33 = 100 rs per hr. so linda should get 21*100 =2100 rs. But she got only 1650. so angela should give 450 rs to linda. answer = 450/1650 =9/33
answer C
Question: The speed of a car is 65 km in the first hour and 45 km in the second hour. What is the average speed of the car?
A.72 kmph
B.55 kmph
C.50 kmph
D.80 kmph
Answer: B.55 kmph
Explanation: S = (65 + 45)/2
= 55 kmph
ANSWER:B
Question: A train is running at a uniform speed of 80 kmph. It passes a railway platform in 15 seconds. If the length of the platform is 130 m,then the length of the train is
A.160 m
B.203.33 m
C.140.5 m
D.150.5 m
Answer: B.203.33 m
Explanation: Let the length of train be X m.
We know that Speed = Distance / Time.
Thus, (X + 130)/15 = 80 x 5/18
or, (X + 130)/15 = 400/18
or, (X + 130) = 1000/3
or X= 1000/3 - 130
X = 203.33
ANSWER:B
Question: Sophika can buy watches at a price of P dollars per watch, which she marks up by a certain percentage before selling. If she makes a total profit of X by selling Y watches, then in terms of P and X and Y, what is the percent of the markup from her buy price to her sell price?
A.(YP)/100X
B.100X/(YP)
C.(YP)+100X
D.(YP)-100X
Answer: B.100X/(YP)
Explanation: Algebraic Solution:If she makes a total profit of X for Y watches, then that must be a profit of X/Y for each watch. That must be the markup above cost on each watch, the amount of the increase. Well, percent increase = (amount of increase)/(starting amount) x 100% = (X/Y)/P *100 = 100X/(YP)
Answer : B
Question: Fence X is twice as long as fence Y, and fence Y is 2 feet shorter than fence Z. If 2 feet were added to each fence, which of the following must be true?
I) X is twice as long as Y.
II) Y is 2 feet shorter than Z.
III) X is longer than Z.
A.I only
B.II only
C.II and III
D.I and II
Answer: C.II and III
Explanation: If X= 6
Y= 3
Z= 5
Then, after adding 3 feet to each:
X= 8
Y=5
Z=7
And the answer would be C, which is wrong.
Question: A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
A.14 Years
B.18 Years
C.20 Years
D.22 Years
Answer: D.22 Years
Explanation: Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
ANSWER D
Question: A motorist travels to a place 150 km away at an average speed of 50 km/hr and returns at 30 km/hr. His average speed for the whole journey in km/hr is ?
A.37.9
B.37.53
C.37.5
D.37.1
Answer: C.37.5
Explanation: Explanation:
Average speed = (2xy) /(x + y) km/hr
= (2 * 50 * 30) / (50 + 30) km/hr.
37.5 km/hr.
Answer: C
Question: A, B and C enter into a partnership. They invest Rs. 40,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. IN what ratio will the profit be shared at the end of 3 years?
A.3:4:9
B.3:4:7
C.3:4:2
D.3:4:4
Answer: B.3:4:7
Explanation: A:B:C = (40000 * 36) : (80000 * 12 + 40000 * 24) : (120000 * 24 + 40000 * 12)
= 144:192:336 = 3:4:7
Answer: B
Question: Two different primes may be said to “rhyme” around an integer if they are the same distance from the integer on the number line. For instance, 3 and 7 rhyme around 5. What integer between 1 and 20, inclusive, has the greatest number of distinct rhyming primes around it?
A.12
B.15
C.17
D.18
Answer: D.18
Explanation: Let's test each option:
A. 12 --> 2*12=24 --> 24=5+19=7+17=11+13: 6 rhyming primes (start from the least prime and see whether we can get the sum of 24 by adding another prime more than 12 to it);
B. 15 --> 2*15=30 --> 30=7+23=11+19=13+17: 6 rhyming primes;
C. 17 --> 2*15=30 --> 34=7+23=11+19=13+17: 6 rhyming primes;
D. 18 --> 2*18=36 --> 36=5+31=7+29=13+23=17+19: 8 rhyming primes;
E. 20 --> 2*20=40 --> 40=3+37=11+29=17+23: 6 rhyming primes.
Answer: D.
Question: A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
A.20%
B.30%
C.40%
D.50%
Answer: B.30%
Explanation: Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = (0.59x)/2x	x 100	%	= 30% (approx.)
B)
Question: A and B together can do a work in 6 days. If A alone can do it in 15 days. In how many days can B alone do it?
A.10
B.99
C.77
D.65
Answer: A.10
Explanation: 1/6 – 1/15 = 1/10 => 10
Answer: A