RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A rectangular lawn of dimensions 80 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
A.3909
B.3907
C.3905
D.3900
Answer: D.3900
Explanation: Area = (l + b – d) d
(80 + 60 – 10)10 => 1300 m2
1300 * 3 = Rs.3900
25. The length of a rectangl.Answer:D
Question: What is the perimeter of a square with area 4p^2/9 ?
A.8p/3
B.3p^2/4
C.3p
D.3p^2
Answer: A.8p/3
Explanation: Area of square, (side)^2 = (2p/3)^2
Therefore side of the square = 2p/3
Perimeter of square = 4*side = 4* (2p/3) = 8p/3
Answer is A.
Question: For what value(s) of n is the following equation satisfied: 2n-6-n = 5n+6-4n
A.a. -5
B.b. 0 only
C.c. 5/2 only
D.d. No value
Answer: D.d. No value
Explanation: 2n-6-n = 5n+6-4n
n - 6 = n + 6
-6 = 6, which is false.
So, no n satisfies given equation.
Answer: D.
Question: Ages of two persons differ by 4 years. If 3 years ago, the elder one was 3 times as old the younger one, find their present age
A.5,9
B.14,18
C.16,20
D.18,22
Answer: A.5,9
Explanation: Explanation:
Let the age of the younger person be x,
Then the elder person's age is (x+4)
=> 3(x-3) = (x+4-3) [3 years before]
=> 3x-9 = x+1
=> x = 5.
So the elder person's age is x + 4 = 9
Answer: Option A
Question: If the Average of 10 consecutive integers is 19.5 then the 10th integer is :-
A.15
B.20
C.23
D.24
Answer: D.24
Explanation: The average falls between the 5th and 6th integers,
integer 5 = 19, integer 6 = 20.
Counting up to the tenth integer
we get 24.
ANSWER:D
Question: Together, 15 type A machines and 7 type B machines can complete a certain job in 4 hours. Together 8 type B machines and 15 type C machines can complete the same job in 11 hours. How many W hours would it take one type A machine, one type B machine, and one type C machine working together to complete the job (assuming constant rates for each machine)?
A. 22 hours
B. 30 hours
C. 44 hours
D. 60 hours
Answer: C. 44 hours
Explanation: Say the rates of machines A, B and C are a, b, and c, respectively.
Together 15 type A machines and 7 type B machines can complete a certain job in 4 hours --> 15a + 7b = 1/4;
Together 8 type B machines and 15 type C machines can complete the same job in 11 hours --> 8b + 15c = 1/11.
Sum the above: 15a + 15b + 15c = 1/4 + 1/11 = 15/44 --> reduce by 15: a + b + c = 1/44 --> so, the combined rate of the three machines is 1/44 job/hour --> time is reciprocal of the rate, thus machines A, B and C can do the job W in 44 hours.
Answer: C.
Question: Evaluate: 40 - 12*3*2 = ?
A.62
B.52
C.32
D.12
Answer: C.32
Explanation: According to order of operations, 12?3?2 (division and multiplication) is done first from left to right
12**2 = 4* 2 = 8
Hence
40 - 12*3*2 = 40 - 8 = 32
correct answer C
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
A.140 sq.units
B.556 sq.units
C.155 sq.units
D.146 sq.units
Answer: A.140 sq.units
Explanation: Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10 = 140 sq.units
Answer:A
Question: The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned.
A.19828.89
B.19828.8
C.19828.37
D.19828.82
Answer: B.19828.8
Explanation: Let the sum be Rs.P
P{ [ 1 + 8/100]2 - 1 } = 2828.80
P(8/100)(2 + 8/100) = 2828.80 [a2 - b2
= (a - b) ( a + b)] P = 2828.80 / (0.08)(2.08)
= 1360/0.08 = 17000 Principal + Interest
= Rs.19828.80
Answer: B
Question: The average age of three boys is 12 years and their ages are in proportion 4:5:9. What is the age in years of the youngest boy?
A.6
B.9
C.8
D.4
Answer: C.8
Explanation: 4x + 5x + 9x = 36
x =2
4x = 8
Answer: C
Question: How many times in a day, the hands of a clock are straight?
A.22
B.24
C.44
D.48
Answer: C.44
Explanation: In 12 hours, the hands coincide or are in opposite direction 22 times.
In 24 hours, the hands coincide or are in opposite direction 44 times a day.
ANSWER:C
Question: The moon revolves around the earth at a speed of approximately 1.03 kilometers per second. This approximate speed is how many kilometers per hour?
A.60
B.61.2
C.62.5
D.3,708
Answer: D.3,708
Explanation: moon revolves around the earth at a speed of 1.02kilometers per second.
one hour equal to 60 minutes.
one minute equals to 60 seconds. so one hour equals to 3600seconds.
so one hour, speed= 1.03*3600=3708kilometers per hour.
Option D is correct
Question: The slant height of a cone is 12 cm and radius of the base is 4cm, find the curved surface of the cone.
A.48 pi cm2
B.30 pi cm2
C.35 pi cm2
D.40 pi cm2
Answer: A.48 pi cm2
Explanation: Ï€ * 12 * 4 = 48
ANSWER A
Question: A survey of employers found that during 1993 employment costs rose 3.5 percent, where employment costs consist of salary costs and fringe-benefit costs. If salary costs rose 3 percent and fringe-benefit costs rose 9.5 percent during 1993, then fringe-benefit costs represented what percent of employment costs at the beginning of 1993 ?
A. 16.5%
B. 8%
C. 35%
D. 55%
Answer: B. 8%
Explanation: The amount by which employment costs rose is equal to 0.035(salary costs + fringe benefit costs);
On the other hand the amount by which employment costs rose is equal to 0.03*salary costs + 0.095*fringe benefit costs;
So, 35(S+F) = 30S+95F --> S = F --> F/S = 1/12 --> F/(S+F) = 1/(1+12) = 1/13 = 0.08.
Answer: B.
Question: When positive integer N is divided by positive integer P, the quotient is 18, with a remainder of 7. When N is divided by (P + 2), the quotient is 15 and the remainder is 1. What is the value of N?
A.151
B.331
C.511
D.691
Answer: A.151
Explanation: Use the rule dividend = (integer quotient)*(divisor) + remainder to translate each sentence.
The first sentence becomes N = 18P + 7. The second equation becomes N = (P + 2)*15 + 1, which simplifies to N = 15P + 31. These are ordinary simultaneous equations Since they both equal N already, let’s set them equal and solve for P.
18P + 7 = 15P + 31
3P + 7 = 31
3P = 24
P = 8
Now that we know P = 8, we can just plug in. The product 15*8 is particularly easy to do, without a calculator, by using the “doubling and halving” trick. Double 15 to get 30, and take half of 8 to get 4 —- 15*8 = 30*4 = 120. So
N = 15(8) + 31 = 120 + 31 = 151
N = 151, answer = A.
Question: how many zeros are there in 50!
A.10
B.11
C.12
D.13
Answer: C.12
Explanation: To find the number of trailing zeroes in 50! factorial we must find the number of integral values in :
50/5 + 50/5^2 + 50/5^3 +.........
= 10+2+0+0....
=12
ANSWER:C
Question: There are two numbers. If 40% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?
A.8 : 25
B.25 : 8
C.8 : 5
D.5 : 8
Answer: D.5 : 8
Explanation: Let the two numbers be x and y.
40/100 * x + y = 5/4y
=> 2/5 x = 1/4 y => x/y = 5/8
ANSWER:D
Question: In 1995 a certain store had 1800 tools in stock that had been purchased for $30 each. If 1,000 of these tools were sold in 1995 for $50 each and the remaining 800 were sold in 1996 for $70 each, how many greater was the gross profit on the tools sold in 1996 than the gross profit on those sold in 1995?
A.$12,000
B.$6,000
C.$8,000
D.$32,000
Answer: A.$12,000
Explanation: The keyword here isGross Profit:
Gross Profit = (Selling Price - Original Price)*(# of Items Sold)
So lets figure out what the Gross Profit for 1995:
GP1995 = (50-30)*(1000) = 20000
And the Gross Profit for 1996:
GP1996 = (70-30)*(800) = 32000
So the difference would be:
32000-20000 = 12000
ANSWER: A 12000
Question: A ship sails out to a mark at the rate of 12 kmph. and sails back at the rate of 8 kmph. The average rate of sailing is ?
A.5 km/hr
B.9.6 km/hr
C.12.5 km/hr
D.25 km/hr
Answer: B.9.6 km/hr
Explanation: Answer
Average = ( 2uv / u +v ) km/hr
= ( 2 x 12 x 8 ) / (12 +8 ) km/hr.
= 9.6 km/hr.
Correct Option: B
Question: If x is the product of the positive integers from 1 to 8, inclusive, and if i, k, m, and p are positive integers such that x = 2^i * 3^k * 5^m * 7^p, then i + k + m + p =
A.4
B.7
C.8
D.11
Answer: D.11
Explanation: Given that x=8!=2^7∗3^2∗5∗7x. Hence, x=2^7∗3^2∗5^1∗7^1=2^i∗3^k∗5^m∗7p, since i, k, m, and p are positive integers, then we can equate the exponents, so we have that i=7, k=2, m=1, and p=1
Therefore, i+k+m+p=7+2+1+1=11
Answer: D.
Question: How many odd numbers between 10 and 800 are the squares of integers?
A.12
B.13
C.14
D.15
Answer: A.12
Explanation: The square of an odd number is an odd number:
10 < odd < 1,000
10 < odd^2 < 1,000
3.something < odd < 31.something (by taking the square root).
So, that odd number could be any odd number from 5 to 31, inclusive: 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, and 31.
12 numbers.
Answer: A.
Question: Two boats are heading towards each other at constant speeds of 5 miles/hr and 23 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ?
A.1/12
B.7/12
C.1/6
D.1/3
Answer: B.7/12
Explanation: The question asks: how far apart will they be 1 minute=1/60 hours before they collide?
Since the combined rate of the boats is 5+23=25 mph then 1/60 hours before they collide they'll be rate*time=distance --> 28*1/60=7/15 miles apart.
Answer: B.
Question: If 9 workers can build 9 cars in 9 days, then how many days would it take 7 workers to build 7 cars?
A.6
B.7
C.8
D.9
Answer: D.9
Explanation: 9 workers can build 1 car per day on average.
1 worker can build 1/9 of a car per day.
7 workers can build 7/9 car per day.
The time required to build 7 cars is 7 / (7/9) = 9 days
The answer is D.
Question: If the provisions last for 30 days for 3000 men then if after 10 men are included then the remaining provisions last for how many days?
A.29.9 days
B.39.9 days
C.19.9 days
D.49.9 days
Answer: A.29.9 days
Explanation: 3000 men use for 30 days. so for 1 person = 30/3000 days = 1/100 =0.01days
for 10 ppl,its 0.1. so for 3010 ppl,its 30 - 0.1 = 29.9 days
ANSWER:A
Question: Two brother X and Y appeared for an exam. The probability of selection of X is 1/7 and that of B is 2/9. Find the probability that both of them are selected.
A.2/69
B.2/60
C.2/63
D.2/29
Answer: C.2/63
Explanation: Explanation:
Let A be the event that X is selected and B is the event that Y is selected.
P(A) = 1/7, P(B) = 2/9.
Let C be the event that both are selected.
P(C) = P(A) × P(B) as A and B are independent events:
= (1/7) × (2/9) = 2/63
Answer: C) 2/63
Question: If the length, breadth and the height of a cuboid are in the ratio 6:5:4 and if the total surface area is 33300 cm2cm2, then the length , breadth and height in cms, are respectively.
A.90,85,60
B.85,75,60
C.90,75,70
D.90,75,60
Answer: D.90,75,60
Explanation: Explanation:
Let length = 6x, breadth = 5x and height =4x in cm
2(6x×5x+5x×4x+6x×4x)=33300
148x2=33300⇒x2=33300/148=225⇒x=15
Length = 90 cm, Breadth = 75 cm and Height = 60 cm
Correct Option: D
Question: 150 men consume 1050 kg of rice in 30 days. In how many days will 70 men consume 980 kg of rice?
A.62
B.60
C.65
D.73
Answer: B.60
Explanation: Explanation:
Rate of consumption of each man = 1050/(150 * 30) = 7/30 kg/day
Let us say 70 men take x days to consume 150 kg.
Quantity consumed by each item in x days = 7x/30 kg.
Quantity consumed by 70 men in x days = (7x/30)(70)kg
(7x/30)(70) = 980
x = (980 * 30)/490 => x = 60 days'
Answer: Option B
Question: Reeya obtained 65, 67, 76, 80 and 95 out of 100 in different subjects, What will be the average
A.76.6
B.75
C.80
D.85
Answer: A.76.6
Explanation: Explanation:
(65+67+76+80+95 / 5)=76.6
Option A
Question: How many positive integers less than 10,000 are there in which the sum of the digits equals 5?
A.31
B.51
C.56
D.62
Answer: C.56
Explanation: Basically, the question asks how many 4 digit numbers (including those in the form 0XXX, 00XX, and 000X) have digits which add up to 5. Think about the question this way: we know that there is a total of 5 to be spread among the 4 digits, we just have to determine the number of ways it can be spread.
Let X represent a sum of 1, and | represent a separator between two digits. As a result, we will have 5 X's (digits add up to the 5), and 3 |'s (3 digit separators).
So, for example:
XX|X|X|X = 2111
||XXX|XX = 0032
etc.
There are 8C3 ways to determine where to place the separators. Hence, the answer is 8C3 = 56.
ANSWER:C
Question: The bankerâ€™s discount of a certain sum of money is Rs. 42 and the true discount on the same sum for the same time is Rs. 36. The sum due is
A.252
B.280
C.360
D.450
Answer: A.252
Explanation: Sol.
Sum = B.D. * T.D. / B.D. - T.D. = Rs.[42 * 36 / 42 - 36] = Rs. [42 * 36 / 6] = Rs. 252
Answer A
Question: Kelly and Chris are moving into a new city. Both of them love books and thus packed several boxes with books. If Chris packed 60% of the total number of boxes, what was the ratio of the number of boxes Kelly packed to the number of boxes Chris packed?
A.4/3
B.2/3
C.1/3
D.3/4
Answer: B.2/3
Explanation: the ratio of the number of boxes Kelly packed to the number of boxes Chris packed = 40/60 = 2/3
ANSWER:B
Question: The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
A.298
B.270
C.245
D.267
Answer: C.245
Explanation: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x)
= 750 => x
= 245 m.
Answer:C
Question: The weights of three bags are in the ratio 4 : 5 : 6. If the sum of the weights of the heaviest and the lightest bag is 45 kg more than the weight of the third bag, what is the weight of the lightest bag?
A.45kg
B.38kg
C.66kg
D.36kg
Answer: D.36kg
Explanation: Let the weights of the three boys be 4k, 5k and 6k respectively.
4k + 6k = 5k + 45
=> 5k = 45 => k = 9
Therefore the weight of the lightest boy
= 4k = 4(9) = 36 kg.
ANSWER:D
Question: P and Q can do a work in 30 days. Q and R can do the same work in 24 days and R and P in 20 days. They started the work together, but Q and R left after 4 days. How many days more will P take to finish the work?
A.10
B.36
C.18
D.20
Answer: B.36
Explanation: Let work done by P in 1 day = p,
Work done by Q in 1 day = q,
Work done by R in 1 day = r
p + q = 1/30
q + r = 1/24
r + p = 1/20
Adding all the above, 2p + 2q + 2r = 1/30 + 1/24+ 1/20 = 15/120 = 1/8
=> p + q + r = 1/16
=> Work done by P,Q and R in 1 day = 1/16
Work done by P, Q and R in 4 days = 4 × (1/16) = 4/16 = 1/4
Remaining work = 1 = 1/4 = 3/4
Work done by P in 1 day = Work done by P,Q and R in 1 day - Work done by Q and R in 1 day
= 1/16 – 1/24 = 1/48
Number of days P needs to work to complete the remaining work = (3/4) / (1/48) = 36
Option B
Question: If a number between 0 and 1/2 is selected at random, which of the following will the number most likely be between
A.0 and 3/20
B.3/8 and 1/2
C.1/5 and 1/4
D.1/4 and 3/10
Answer: B.3/8 and 1/2
Explanation: B. 3/8 and 1/2
Definitely not. I am always happy to explain a given question or issue if I can. However, I sometime donot put my explanation if I am answering first because I want to put others first for their explanation.
Now you have excellent explanantion byscthakur. In fact the question is asking the likelyness of or high chances/probability of having a given number. Hope you already got it.B
Question: If A(k)=(k+2)^k, and k=0, what is the value of A(A(A(k)))/(18^15)?
A.1
B.18
C.16
D.6
Answer: B.18
Explanation: A(A(A(0)))=A(A(2))=A(16)=18^16
18^16/18^15 = 18
Thus, the answer is B.
Question: If one person completes a journey in 10 hrs. He travels 1st half of the journey at the rate of 21 km/hr and 2nd half at therate of 24 km/hr. Find the total journey in km.
A.210 km
B.216 km
C.224 km
D.230 km
Answer: C.224 km
Explanation: distance = speed x time
Let time taken to travel the first half = x hr
then time taken to travel the second half = (10 - x) hr
Distance covered in the the first half = 21x
Distance covered in the the second half = 24(10 - x)
But distance covered in the the first half = Distance covered in the the second half
=> 21x = 24(10 - x)
=> 21x = 240 - 24x
=> 45x = 240
=> 9x = 48
=> 3x = 16
⇒x=163Hence Distance covered in the the first half = 21x=21×163=7×16=112 kmTotal distance = 2×112=224 km
C
Question: 17+18=35. How many such 2 consecutive numbers are there less than 200 when added gives a sum which is divisible by 5?
A.80
B.40
C.50
D.60
Answer: B.40
Explanation: since 2+3=5 & 7+8=15
any combination with these no be will give u desirable result...
so total no in 100 will be 20 & that's why in 200,it will be 40
ANSWER:B
Question: When a commodity is sold for $34.80, there is a loss of 2%. what is the cost price of the commodity?
A.$46.40
B.$48
C.$42.60
D.$43.45
Answer: A.$46.40
Explanation: s.p. = $34.80
loss = 2%
c.p. = 100*34.80/75 = $46.40
correct option is A
Question: Two fractions 1/3 and 2/3 are given to you. Can you find a fraction that lies one third on the way between them?
A.10/15
B.13/19
C.11/32
D.12/27
Answer: D.12/27
Explanation: D
12/27
This is really simple if you know the concept. You just have to increase the fraction by multiplying with a number. In that way, you will increase the numerator and you will be able to find the required fraction. Here, we are multiplying the numerator and denominator of both the numbers with 9. Now if you simplify, the number will remain the same and thus dont think we changed the fraction.
1/3 * 9/9 = 9/27
2/3 * 9/9 = 18/27
Its easy to find the one third fraction on the way now i.e. 12/27.
Question: Three seventh of a number is 12 more than 40% of that number. What will be the 20% of that number?
A.A)148
B.B)210
C.C)42
D.D)248
Answer: C.C)42
Explanation: 3/7 x – 40/100 x = 12
x = 35 * 12
35 * 12 * 20/100 = 84/2 = 42
ANSWER:C
Question: The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 80/kg. how much did a kg of coffee cost in june ?
A.50
B.60
C.80
D.100
Answer: C.80
Explanation: Let the price of tea and coffee be x per kg in June.
Price of tea in July = 1.2x
Price of coffee in July = 0.8x .
In July the price of 1/2 kg (800gm) of tea and 1/2 kg (800gm) of coffee (equal quantities) = 80
1.2x(1/2) + 0.8x(1/2) = 80
=> x =80
Thus proved...option C.
Question: The L.C.M. of 2 numbers is 72. The numbers are in the ratio 2:3. Find their sum?
A.36
B.40
C.48
D.60
Answer: D.60
Explanation: Let the numbers be 2x and 3x
L.C.M. = 6x
6x = 72
x = 12
The numbers are = 24 and 36
Required sum = 24+36= 60
Answer is D
Question: The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.4180.What was his original salary?
A.2277
B.2999
C.4000
D.2651
Answer: C.4000
Explanation: X * (110/100) * (95/100) = 4180
X * (11/10) * (1/100) = 44
X = 4000
Answer: C
Question: A number, x is chosen at random from the set of positive integers less than 10. What is the probability that (8/x) > x?
A. 1/5
B. 2/8
C. 1/3
D. 2/3
Answer: B. 2/8
Explanation: Number x has to be chosen from numbers 1-9
(8/x) > x
=> 8 > x^2
=>x^2 - 8 < 0
x can have 2 values only 1 , 2
Therefore , probability = 2 / 8
Answer B
Question: 20 is added to a certain number, the sum is multiplied by 2, the product is divided by 2 and 2 is subtracted from the quotient. The remainder left is half of 88. What is the number?
A.21
B.20
C.26
D.30
Answer: C.26
Explanation: Let number is X.
When 20 added to it,
= (X+20)
2 multiplied to sum,
= 2 *(X +20)
Now,
= [{2 *(X +20)} /2]
And,
= [{2 *(X +20)} /2] - 2
According to question,
[{2 *(X +20)} /2] - 2 = half of 88
[(2X + 40) /2) = 44 +2
2X + 40 = 46 * 2
X + 20 = 46
X = 46 - 20
X = 26
So, required number is: 26.
ANSWER : C
Question: In a certificate by mistake a candidate gave his height as 25% more than actual height. In the interview panel, he clarified that his height was 5feet 5 nches. Find the % correction made by the candidate from his stated height to his actual height?
A.10
B.20
C.30
D.40
Answer: B.20
Explanation: His height was = 5 feet 5 inch = 5 + 60 = 65 inch. Required % correction =65*(1.25-1)* 100 = 20
B
Question: If 18 is 15 percent of 25 percent of a certain number, what is the number?
A.9
B.36
C.480
D.81
Answer: C.480
Explanation: Let the certain number be x.
=> (15/100)*(25/100)*x = 18;
=> x=480;
Ans is (C).
Question: Q and R are two-digit positive integers that have the same digits but in reverse order. If the positive difference between Q and R is less than 60, what is the greatest possible value of Q minus R?
A.52
B.54
C.55
D.56
Answer: B.54
Explanation: A two-digit integer "ab" can be expressed algebraically as 10a+b.
Q-R=(10a+b)-(10b+a)=9(a-b)<60.
The greatest multiple of 9 which is less than 60 is 54.
The answer is B.
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
A.5.77
B.5.79
C.5.76
D.5.75
Answer: C.5.76
Explanation: M = 6
S = 1.2
DS = 7.2
US = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
D = 2.88 * 2 = 5.76
Answer:C
Question: A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
A.3.46%
B.4.2%
C.4.5%
D.5%
Answer: A.3.46%
Explanation: Explanation :
Let the sum of Rs.725 is lent out at rate R% for 1 year
Then, at the end of 8 months, ad additional sum of 362.50 more is lent out at rate 2R% for remaining 4 months(1/3 year)
Total Simple Interest = 33.50
=>725×R×1/100+362.50×2R×1/3/100=33.50
=>725×R×1/100+362.50×2R/300=33.50
=>725R/100+725R300=33.50
=>725R(1/100+1/300)=33.50
=>725R(4/300)=33.50
=>725R×4=10050
=>725R=2512.5
=>145R=502.5
=>R=502.5/145
=3.46%
Answer : Option A
Question: If p^2 – 13p + 40 = d, and p is a positive integer between 1 and 10, inclusive, what is the probability that d < 0?
A.1/10
B.1/5
C.2/5
D.3/5
Answer: B.1/5
Explanation: p2 – 13p + 40 = d
so (p – 8)(p – 5) = d
For q to be negative, the expressions (p – 8) and (p – 5) must have opposite signs. Which integers on the number line will yield opposite signs for the expressions (p – 8) and (p – 5)? Those integers in the range 5 < p < 8 (notice 5 and 8 are not included because they would both yield a value of zero and zero is a nonnegative integer). That means that there are only two integer values for p, 6 and 7, that would yield a negative q. With a total of 10 possible p values, only 2 yield a negative q, so the probability is 2/10 or 1/5.
The correct answer is B.
Question: is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 42, then how old is B?
A.16
B.8
C.9
D.10
Answer: A.16
Explanation: Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 42
5x = 40 => x = 8
Hence, B's age = 2x = 16 years.
ANSWER:A
Question: There are 3 men, 8 women, they are standing in a row for a photoshoot, in how many ways they can be arranged if no 2 men can stand together.
A.9P3 * 8!
B.9P3 * 7!
C.9P3 * 6!
D.9P3 * 5!
Answer: A.9P3 * 8!
Explanation: There is restriction on the number of Men, so consideration of problem shall be done by fixing position of Women
_W_W_W_W_W_W_W_W_
In those blank spaces 3 Men can be arranged among 9 positions so that it satisfies the above condition.
No. of ways= 9P3 * 8!
ANSWER:A
Question: Find the missing in the series: 70, 58, 47, 37,___
A.28
B.287
C.2679
D.2767
Answer: A.28
Explanation: Answer:A
Question: Find the odd man out. 1, 8, 27, 64, 125, 196, 216, 343
A.64
B.196
C.216
D.1
Answer: B.196
Explanation: The pattern is 1^3, 2^3, 3^3, 4^3, 5^3, 6^3, 7^3.
196 is not a perfect cube
Answer is B