RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Seats for Mathematics,PhysicsandfBilogy in a school are in the ratio 5:7:8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?
A.2:3:4
B.6:7:8
C.6:8:9
D.5:8:9
Answer: A.2:3:4
Explanation: Let the no.of seats Maths, physics and Biology be 5x, 7x and 8x
No.of increased seats are (140%5x), (150%7x) and (175%8x)
Required ration = (150%7x)= 7x:21x/2:2x = 2:3:4
ANSWER : A 2:3:4
Question: In 10 years,A will be 1.5 times as old as B was 10 years ago.If A is now 9 years older than B,the present age of B is :
A.17 Years
B.29 Years
C.39 Years
D.49 Years
Answer: A.17 Years
Explanation: Solution
Let B's present age = x years.Then,A's present age =(x +9) years.
âˆ´ (x + 9)+ 10 = 1.5 (x - 10) â‡” x + 19 = 1.5x- 15 â‡” 0.5x = 34. x=17Answer A
Question: The number of stamps that Kaye and Alberto had were in the ration of 6:4 respectively. After Kaye gave Alberto 5 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 8:6. As a result of the gift, Kaye had how many more stamps than Alberto ?
A.22
B.25
C.15
D.35
Answer: B.25
Explanation: K1 = 6x
A1 = 4x
K2 = 6x - 5
A2 = 4x + 5
K2/A2 = 8/6
(6x-5)/(4x+5) = 8/6
6*(6x-5) = 8*(4x+5)
36x - 30 = 32x + 40
4x = 70
x = 17.5
K2 = 6*17.5 -5 = 100
A2 = 4*17.5 + 5 =75
K2 - A2 = 100-75=25
Answer : B
Question: The area of a square is added to one of its sides, and the perimeter is then subtracted from this total, the result is 4. What is the length of one side?
A.5
B.4
C.3
D.2
Answer: B.4
Explanation: The equation is; side + Area - Perimeter = s + A - P = s + s^2 - 4s = s(1 + s - 4).
By plugging in the answers we can test the answers quickly; then, 4 is the only possible answer.
Answer: B
Question: The ratio of the present age of Sandy to that of Molly is 9:2. Eight years from now, the ratio of the ages of Sandy to Molly will be 5:2. What was Sandy's age 6 years ago?
A.18
B.21
C.24
D.27
Answer: B.21
Explanation: Let the present age of Sandy be 9x years and that of Molly be 2x years.
(9x + 8) / (2x + 8) = 5 / 2
8x = 24
x = 3
Six years ago, Sandy's age was 9(3) - 6 = 21
The answer is B.
Question: The ratio of the adjacent angles of a parallelogram is 5 : 10. Also, the ratio of the angles of quadrilateral is 5 : 6 : 7 : 12. What is the sum of the smaller angle of the parallelogram and the second largest angle of the quadrilateral?
A.168°
B.228°
C.144°
D.224°
Answer: C.144°
Explanation: The measures of the adjacent angles of a parallelogram add up to be 180°
Given
So, 5x + 10x = 180°
Or, 15x = 180°
Or, x = 12°
Hence the angles of the parallelogram are 60° and 120°
Further it is given
We know sum of all the four angles of a quadrilateral is 360°
So, 5y + 6y + 7y + 12 y = 360°
Or, 5y + 6y + 7y + 12 y = 360°
Or, 30y = 360°
Or, y = 12°
Hence the angles of the quadrilateral are 60° , 72, 84° and 144°
Will be 60° + 84° = 144°
Answer : C
Question: One fourth of a solution that was 10 percent wheat by weight was replaced by a second solution resulting in a solution that was 16 percent wheat by weight. The second solution was what percent wheat by weight ?
A.34%
B.24%
C.22%
D.18%
Answer: A.34%
Explanation: EQ can be written as ...
let sol be s... so (3/4)s*(.1)+(1/4)s*t=s*(.16).... we get t(% of wheat in 2nd sol)=34%=A
Question: How many different pairs of positive integers (a, b) satisfy the equation 1/a+1/b=34/41 ?
A.6
B.3
C.2
D.1
Answer: D.1
Explanation: There is no certain way to solve 2 unknown with 1 equation. The best way is to look at the question and retrospect the most efficient way. In this question, a and b are only positive integers. So that is a big relief. Now, we can start with putting a=1,2,.. and so on till the time we are confident about one of the options.
So, we start with
a=1, we get b as -ve. out
a=2, we get b as 6. Yes (Now (a,b) = (2,6). We can directly see that (a,b)=(6,2) will also satisfy. So we have 2 possible solutions)
a=3, we get b as 3. Yes (Now we have 3 possible solutions)
a=4, we get b as fraction. Out
a=5, we get b again as some fraction. Out
a=6 already taken.
We have A,B options left. C,D,E are out.
A is 6. To have 6 as the answer, we will need one more pair like2,6and one more solution where a=b.
When a=b, we have only 1 solution = 1. So, one more solution, where a=b is not possible.
So, answer will be D.
Question: In Mike's opinion, his weight is greater than 65kg but leas than 72 kg. His brother does not agree with Mike and he thinks that Mike's weight is greater than 60kg but less than 70kg. His mother's view is that his weight cannot be greater than 68 kg. If all of them are correct in their estimation, what is the average of different probable weights of Mike?
A.55 kg
B.55.5 kg
C.59.5 kg
D.66.5 kg
Answer: D.66.5 kg
Explanation: Let Mike's weight be X kg.
According to Mike, 65 < X < 72.
According to Mike's brother, 60 < X < 70.
According to Mike's mother, X < 68.
The values satisfying all the above conditions are 66 and 67.
Required average = (66 + 67) / 2 = 66.5 kg
D
Question: A contractor undertook a project to complete it in 20 days which needed 5 workers to work continuously for all the days estimated. But before the start of the work the client wanted to complete it earlier than the scheduled time, so the contractor calculated that he needed to increase 5 additional men every 2 days to complete the work in the time the client wanted it:
If the work was further increased by 50% but the contractor continues to increase the 5 workers o every 2 days then how many more days are required over the initial time specified by the client.
A.1 day
B.2 days
C.5 days
D.None of these
Answer: B.2 days
Explanation: Explanation:
Total work = 100+50 = 150man-days
In 8 days 100 man-days work has been completed. Now on 9th and 10th day there will be 25 workers. So in 2 days they wll complete additional 50 man- days work. Thus the work requires 2 more days
Answer: B
Question: If the integer q is rounded to the nearest hundred, the result represents a 66 2/3 % increase over the value obtained when q is rounded to the nearest ten. which of the following is a possible value of q?
A.64
B.67
C.99
D.133
Answer: A.64
Explanation: We have to check options 1 by 1.
64 rounded to nearest hundred = 100
64 rounded to nearest ten = 60
now difference = 40
the result represents a 66 2/3 % increase over the value obtained when x is rounded to the nearest ten.
therefore 40/60)*100 = 66 2/3 ==>this is the answer.
99 rounded to nearest ten = 100
133 rounded to nearest ten = 130
133 rounded to nearest hundred so q= 100=A
Question: Two men can complete a piece of work in four days. Two women can complete the same work in eight days. Four boys can complete the same work in five days. If four men, eight women and 20 boys work together in how many days can the work be completed?
A.1/2 day
B.2 1/2 days
C.1 1/2 days
D.3 1/2 days
Answer: A.1/2 day
Explanation: A
1/2 day
Two men take four days to complete the work four men would take (2 * 4)/4 = 2 days to complete it.
Similarly four women would take two days to complete it and 20 children would take one day to complete it.
All the three groups working togerther will complete 1/2 + 1/2 + 1/1 work in a day
= 2 times the unit work in a day.
They will take 1/2 a day to complete it working together.
Question: Angela has 13 pairs of matched socks. If she loses 7 individual socks, which of the following is NOT a possible number of matched pairs she has left?
A.8
B.9
C.10
D.11
Answer: C.10
Explanation: I think if Angela loses 7 individual socks,then she is bound to have lost minimum of 3 pairs and 1 individual sock,in this way she is left with only 9 pairs of socks (13-(3+1)).
Hence,10 cannot be the answer as maximum is 9.
Hence, option (C)
Question: A store sells a certain product at a fixed price per unit. At the product's current price, e units cost a total of exactly $300. If the price were lowered by $5 from its current value, then e + 2n units would cost exactly $300; if the price were raised by $5, then e – n units would cost exactly $300. What is the value of e?
A.10
B.15
C.20
D.25
Answer: C.20
Explanation: It got too complicated when I used algebra. Using plugging in, it was quite fast.
Price Quantity total value
p e pe = 300
p-5 e+2n (p-5)(e+2n) = 300
p+5 e-n (p+5)(e-n) = 300
Solving three equations for three unknowns. Tough!!
Plugging in, I always start with C. C was the answer here, so saved calculation!
Putting values in above equations:
Price Quantity total value
15 20 300
10 20+2n 300 -> 10(20 + 2n)=300 -> 200 +20n = 300 -> 20n = 100 -> n =5
20 15 300
So e = 20 satisfies all equations!!
Question: All of the students of Music High School are in the band, the orchestra, or both. 50 percent of the students are in only one group. There are 140 students in the band. If 20 percent of the students are in the band only, how many students are in the orchestra only?
A.60
B.70
C.50
D.80
Answer: A.60
Explanation: % of students in one group only = 50%
% of students in both groups = 100 - 50 = 50%
% of students in the band only = 20%
Number of students who are in band = 140
50% + 20% = 70% = 140 Students
Finding total students:
x = (140 x 100)/70
x = 200
Answer:A
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 50 years now, the son's age 10 years back was:
A.14 years
B.19 years
C.33 years
D.15 years
Answer: D.15 years
Explanation: Let the son's present age be x years. Then, (50 - x) = x
2x = 50
x = 25
Son's age 5 years back (25 - 10) = 15 years.
Answer: D
Question: A man saves a certain portion of his income during a year and spends the remaining portion on his personal expenses. Next year his income increases by 50% but his savings increase by 100%. If his total expenditure in 2 years is double his expenditure in 1st year, What %age of his income in the first year did he save?
A.40%
B.45%
C.50%
D.60%
Answer: C.50%
Explanation: 1st year Income= I
1st year savings= S
1st year Expense= E1
2nd year Income = 1.5I
2nd year savings= 2S (100% increase)
2nd Year expense= E2
E1+ E2= 2E1
E2=E1
That means Expenses are same during both years. With increase of 50% income the savings increased by 100%.
or S= .5I
or S= 50% of Income
C is the answer
Question: Consider below info to be a table:
AMOUNT OF BACTERIA
TIME - AMOUNT
1PM - 10gms
4PM - x gms
7PM - 10.0 gms
Data for a certain biology experiment are given in the table above. If the amount of bacteria present increased by the same factor during each of the two 3-hour periods shown, how many grams of bacteria were present at 4PM ?
A.12.0
B.12.1
C.10.0
D.12.3
Answer: C.10.0
Explanation: let say the factor is x, the at 7PM quantity = 10 (i.e. quantity @1PM)* x^2 =10.0 => x^2 =1.00 or x = 1.0 => @4PM quantity = 10x =10*1.0 =10.
Answer C
Question: The ratio 10:20 expressed as percent equals to
A.50 %
B.80 %
C.40 %
D.90 %
Answer: A.50 %
Explanation: Explanation:
Actually it means 10 is what percent of 20, which can be calculated as,
(10/20)*100 = 10 * 5 = 50
Answer: Option A
Question: Jonathan can type a 20 page document in 50 minutes, Susan can type it in 30 minutes, and Jack can type it in 24 minutes. Working together, how much time will it take them to type the same document?
A.5 minutes
B.11 minutes
C.15 minutes
D.18 minutes
Answer: B.11 minutes
Explanation: You may set up common equation like this:
job/A+job/B+job/C=job/x
Memorize this universal formula, you will need it definitely for GMAT.
and find x from this equation
In this specific case, the equation will look like this:
20/50+20/30+20/24=20/x
If you solve this equation, you get the same answer B (11)
Question: How many integers are between 3 and 86/7, inclusive?
A.8
B.9
C.10
D.11
Answer: C.10
Explanation: 86/7 = 12.xx
We are not concerned about the exact value of 86/7 as we just need the integers.
Since the values are small, we can write down the integers.
The different integers between 3 and 86/7 would be 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
Total number of integers = 10
Option C
If we need to find the number of integers between two numbers n and m, where m > n
The number of integers = m - n + 1
In the given question, the number of integers = 12 - 3 + 1 = 10
ANSWER:C
Question: A milkman purchases the milk at Rs. x per litre and sells it at Rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. What is the profit percentage?
A.166.69%
B.166.66%
C.166.76%
D.136.66%
Answer: B.166.66%
Explanation: Let the cost price of 1 litre pure milk be Re.1, then
\inline \begin{Bmatrix} 6 & litres(milk) & \rightarrow & CP=Rs.6\\ 2 & litres(water) & \rightarrow & CP=Rs.0 \end{Bmatrix}\rightarrow CP=Rs.6 only
and 8 litre mixture \rightarrow SP \rightarrow 8 x 2 = Rs.16
Profit %= %
Answer: B
Question: what is the unit digit in the product (3^68 x 6^59 x 7^71) ?
A.1
B.2
C.4
D.6
Answer: C.4
Explanation: Unit digit in 3^4=1=>Unit digit in (3^4)^16=1
therefore, Unit digit in 3^65=Unit digit in [(3^4)^16x3]=(1x3)=3
Unit digit in 6^59=6
Unit digit in 7^4=1=>Unit digit in (7^4)^17 is 1
Unit digit in 7^71=Unit digit in [(7^4)^17 x 7^3]=((1x3)=3
Therefore, Required digit=Unit digit in (3x6x3)=4
Answer is C
Question: Country C imposes a two-tiered tax on imported cars: the first tier imposes a tax of 10% of the car's price up to a certain price level. If the car's price is higher than the first tier's level, the tax on the portion of the price that exceeds this value is 8%. If Ron imported a $14,000 imported car and ended up paying $1440 in taxes, what is the first tier's price level?
A.$1600
B.$6000
C.$6050
D.$7050
Answer: A.$1600
Explanation: Let T be the tier price, P be total price = 14000
Per the given conditions:
0.10T + 0.08(P-T) = 1440 ----> T= 1600. A is the correct answer.
Question: 9 points are marked on a straight line and another 8 points are marked on a second straight line with no points in common. How many triangles can be constructed with vertices from among the above points?
A.540
B.105
C.196
D.21
Answer: A.540
Explanation: getting the answer 540 which is not in the choices, what is the source of the problem?
9C2* 8C1 + 8C2* 9C1 =540
A
Question: A pair of articles was bought for Rs. 37.40 at a discount of 15%. What must be the marked price of each of the articles ?
A.Rs15
B.Rs 20
C.Rs 22
D.Rs 25
Answer: C.Rs 22
Explanation: Solution: As question states that rate was of pair of articles, So rate of One article = 37.40/2 = Rs. 18.70 Let Marked price = Rs X then 85% of X = 18.70 => X = 1870/85 = 22
Answer: C
Question: Five persons - A, B, C, D and E are being compared in weight and height. The second heaviest person. D is the shortest. A is the 2nd tallest and shorter than E, The heaviest person is the third tallest person. There is only one person shorter than B, who is lighter than E and A respectively.
Who is the heaviest person?
A.A
B.B
C.C
D.D
Answer: C.C
Explanation: Explanation:
A is the second tallest person. There is only one person shorter than B. So, B is the fourth tallest person. D is the shortest and second heaviest.
Weight Height
1
2 D A
3
4
B
5
D
A is shorter than E. So, the third tallest person is C. Who is the heaviest person. B is lighter than E and A respectively. So, the final arrangement is as follows.
Weight Height
1. C E
2. D A
3. E C
4. A B
5. B D
C is heaviest person.
ANSWER IS C
Question: There are 600 military people in a division of the army. There is one Officer for every 29 soldiers in that division. Now the question is how many officers are in the division?
A.22
B.35
C.37
D.20
Answer: D.20
Explanation: D
20
29 soldiers + 1 officer makes a group of 30 people. Now number of such groups = 600/30 = 20.
Question: If the average (arithmetic mean) of a and b is 80, and the average of b and c is 180, what is the value of a − c?
A.−220
B.−200
C.100
D.135
Answer: B.−200
Explanation: a+b = 160
b+c = 360
a-c = -200.
IMO option B.
Question: An bus covers a certain distance at aspeed of 320 kmph in 5 hours. To cover the same distance in 1hr, it must travel at a speed of?
A.560 km/h
B.960 km/h
C.779 km/h
D.723 km/h
Answer: B.960 km/h
Explanation: Distance = (320 x 5) = 1600 km.
Speed = Distance/Time
Speed = 1600/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
Required speed = 1600 x 3/5 km/hr = 960 km/hr.
B
Question: A trader purchased two colour televisions for a total of Rs. 35000. He sold one colour television at 30% profit and the other 40% profit. Find the difference in the cost prices of the two televisions if he made an overall profit of 32%?
A.21000
B.21009
C.21029
D.21298
Answer: A.21000
Explanation: Let the cost prices of the colour television sold at 30% profit and 40% profit be Rs. x and Rs. (35000 - x) respectively.
Total selling price of televisions = x + 30/100 x + (35000 - x) + 40/100 (35000 - x)
=> 130/100 x + 140/100 (35000 - x)
= 35000 + 32/100 (35000)
x = 28000
35000 - x = 7000
Difference in the cost prices of televisions
= Rs.21000
Answer:A
Question: Which of the following number is divisible by 24 ?
A.3100000
B.3115832
C.3115800
D.3125832
Answer: D.3125832
Explanation: 31214 is not divisible by 3 and 8
=> 31214 is not divisible 24
61212 is not divisible by 8 though it is divisible by 3
=> 61212 is not divisible 24
512216 is not divisible by 3 though it is divisible by 8
=> 512216 is not divisible 24
3125832 is divisible by 3 and 8
=> 3125832 is divisible 24
D)
Question: Current age of Bruce and Tomy are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Tomy 's present age in years?
A.18 years
B.20 years
C.24 years
D.25 years
Answer: C.24 years
Explanation: Let the present ages of Bruce and Tomy be 5x years and 4x years respectively.
Then,	5x + 3	=	11
4x + 3	9
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x - 44x = 33 - 27
x = 6.
Anand's present age = 4x = 24 years.
C
Question: On Monday, a certain animal shelter housed 50 cats and dogs. By Friday, 1/5 of the cats and 1/4 of the dogs had been adopted; no new cats or dogs were brought to the shelter during this period. What is the greatest possible number of pets that could have been adopted from the animal shelter between Monday and Friday?
A.12
B.14
C.16
D.18
Answer: A.12
Explanation: To maximize the number of pets adopted, we should maximize the number of dogs adopted since 1/4 > 1/5.
The greatest multiple of 4 less than 50 is 40 (such that the remaining number is divisible by 5), so let's assume there were 40 dogs and 10 cats.
Then the maximum number of adopted pets is 1/4*(40) + 1/5*(10) = 10 + 2 = 12.
The answer is A.
Question: A student needed to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and x. He found the mean to be 12. What is the value of x?
A.12
B.5
C.7
D.9
Answer: C.7
Explanation: Explanation:
3+11+7+9+15+13+8+19+17+21+14+x/12 =12
⇒137+x12=12
⇒137+x=144
⇒x=144−137=7
Answer: Option C
Question: What is the ratio A of the surface area of a cube to the surface area of a rectangular solid identical to the cube in all ways except that its length has been doubled?
A.1/4
B.3/8
C.1/2
D.3/5
Answer: D.3/5
Explanation: One side surface area of a cube = x*x = x^2
Total 6 sides = 6x^2
As for the rectangular, Height (H) and Width (W) are same as Cube, x. Only Length = 2x.
L x H = 2x * x = 2x^2 ----> 4 sides = 2x^2 * 4 = 8x^2
W * H = x * x = x^2 ------> 2 sides = x^2 * 2 = 2x^2
Total 6 sides = 8x^2 + 2x^2 = 10x^2
Ratio of cube area to rectangular area A= 6x^2 / 10x^2 ----> 6/10 ----> 3/5 (D)
Question: In western Europe, q bicycles were sold in each of the years 1990 and 1993. The bicycle producers of Western Europe had a 42 percent share of this market in 1990 and a 33 percent share in 1993. Which of the following represents the decrease in the annual number of bicycles produced and sold in Western Europe from 1990 to 1993?
A.9% of (x/100)
B.14% of (x/100)
C.75% of (x/100)
D.9% of q
Answer: D.9% of q
Explanation: Moreover is't question actually asking the the difference between the {(Quantity Produced + Quantity Sold ) q in 1990 - (Quantity Produced + Quantity Sold ) in 1993}
Though the Quantity sold in both the years is same it actually boils down to (Quantity Produced in 1990 ) in (Quantity Produced in 1993)=D
Question: The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 8 years hence?
A.50
B.60
C.70
D.76
Answer: D.76
Explanation: A + B = 60, A = 2B
2B + B = 60 => B = 20 then A = 40.
5 years, their ages will be 48 and 28.
Sum of their ages = 48 + 28 = 76.
ANSWER:D
Question: Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 2244 sq. metres.
A.25.4
B.26.7
C.24.3
D.22.5
Answer: B.26.7
Explanation: Explanation:
Clearly, the cow will graze a circular field of area 2244 sq. metres and radius
equal to the length of the rope.
Let the length of the rope be R metres.
Then, Π(R)2= 2244 => R2 = (2244 X (7/22)) = 714=> R = 26.72
Length of the rope = 26.72 m.
Answer: Option B
Question: Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
A.4
B.7
C.9
D.13
Answer: A.4
Explanation: Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Answer is A
Question: difference between LCM and HCF of
following number 20 30 40?
A.140
B.130
C.100
D.110
Answer: D.110
Explanation: LCM of 20, 30, 40 is 120
HCF of 20, 30, 40 is 10
Difference is 120 - 10 = 110
ANSWER:D
Question: Carrey rented a car for Rs.20 plus Rs.0.25 per kilometer driven. Samuel rented a car for Rs.24 plus Rs.0.16 per kilometer driven. If each drove d km. and each was charged exactly the same amount for the rental, then d equals ?
A.44.4
B.44.8
C.1
D.19
Answer: A.44.4
Explanation: Explanation:
20 + 0.25 × d = 24 + 0.16d
Solving we get d = 44.4
Answer:A
Question: Three unbiased coins are tossed. What is the probability of getting 3 heads and 1 Tail?
A.3/4
B.1/4
C.3/8
D.1/2
Answer: D.1/2
Explanation: Let, H --> Head , T --> Tail
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting 3 heads
Then E = {HHH,HTH,THH,HHT}
P(E) = n(E)/n(S) =4/8 = 1/2
Answer is D
Question: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
A.9
B.9.6
C.10
D.10.8
Answer: D.10.8
Explanation: Explanation:
Relative speed = (60 + 40) km/hr =[ 100 x ( 5 / 18 ) ]m/sec = ( 250 /9 ) m/sec.
Distance covered in crossing each other = (140 + 160) m = 300 m.
Required time = [ 300 x ( 9/250 ) ] sec = ( 54/ 5 )sec = 10.8 sec. Answer: D
Question: An eccentric casino owner decides that his casino should only use chips in $5 and $9 denominations. Which of the following amount cannot be paid out using these chips?
A.$31
B.$37
C.$33
D.$24
Answer: A.$31
Explanation: Yes, the number of 5 or/and 9 dollar chips can be zero, however both being zero mean that the casino is paying out $0, which is not realistic.
Each option but A can be represented as the sum of a multiple of 5 and a multiple of 9:
A. $33 = 5*3 + 9*2
B. $37 = 5*2 + 9*3
C. $24 = 5*3 + 9*1
E. $15 = 5*3
Answer: A.
Question: The diameter of a garden roller is 1.4 m and it is 2 m long. How much area will it cover in 5 revolutions ? (use π = 22⁄7)
A.40 m2
B.44 m2
C.48 m2
D.36 m2
Answer: B.44 m2
Explanation: Required area covered in 5 revolutions
= 5 × 2πrh = 5 × 2 × 22⁄7 × 0.7 × 2 = 44 m2
Answer B
Question: A chemist mixes one liter of pure water with x liters of a 75% salt solution, and the resulting mixture is a 15% salt solution. What is the value of x?
A.1/4
B.1/3
C.1/2
D.1
Answer: A.1/4
Explanation: Concentration of salt in pure solution = 0
Concentration of salt in salt solution = 75%
Concentration of salt in the mixed solution = 15%
The pure solution and the salt solution is mixed in the ratio of --> (75 - 15)/(15 - 0) = 4/1
1/x = 4/1
x = 1/4
Answer: A