RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A sum of Rs.4600 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
A.Rs.2990
B.Rs.3120
C.Rs.3320
D.Rs.2760
Answer: A.Rs.2990
Explanation: Let A be the amount received at the end of the three years.
A = 4600[1 + 10/100][1 + 20/100][1 + 25/100]
A = (4600 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.7590
So the interest = 7590 - 4600 = Rs.2990
ANSWER:A
Question: Henry eats X scones in X percent of the time it takes Rachel to eat Y scones. If Rachel eats four scones in ten minutes, then the number of minutes it takes Henry to eat 20 scones must be equal to which of the following?
A.Y/2
B.20/Y
C.100Y/(15X)
D.XY/250
Answer: A.Y/2
Explanation: Rachel eats 4 scones/10 minutes = 2/5 scones per minute
The time for Rachel to eat 1 scone is 5/2 minutes.
The time for Rachel to eat Y scones is 5Y/2 minutes.
The time for Henry to eat X scones is 5YX/200 minutes.
The time for Henry to eat 1 scone is 5Y/200 minutes.
The time for Henry to eat 20 scones is 100Y/200 = Y/2 minutes.
The answer is A.
Question: Jill works as a waitress at the local diner where she earns an hourly wage of $4.00 per hour and a standard tip rate of 15% of the cost of the orders she serves. If she worked one 8-hour shifts this week and averaged $40 in orders per hour, how much did Jill earn this week?
A.280
B.300
C.80
D.350
Answer: C.80
Explanation: Jill earns 4 dollars/hour and the hourly tip is (3/20)*40.
Jill thus earns 4*8+8*2*3 per day(or 4(8)+6(8)=10(8)=80).
Jill has worked for 1 days -> 80*1=80.
This matches answer choice C.
Question: Annie has 3 times the number of stamps that Doris does and Jane has 7 stamps more than Doris does. If Annie, Doris, and Jane each increase their number of stamps by 4, which of the following must be true after each person increases her number of stamps?
Annie has more stamps than Jane.
Jane has 3 more stamps than Doris.
The sum of the numbers of stamps that Annie and Doris have is a multiple of 4.
A.None
B.IIIonly
C.and III only
D.and III only
Answer: B.IIIonly
Explanation: Given that:
A=3D;
J=D+7;
After increase:
Alice: A=3D+4;
Jane: J=D+11;
Doris: D+4.
Analyze each option:
Alice has more stamps than Jane.
3D+4>D+11 --> D>7/3=3.5. Thus this statement will be true if D is more than or equal to 4. Since we don't know that, then this statement is not always true.
Jane has 3 more stamps than Doris.
D+11=(D+4)+3. This is not true for ANY value of D.
The sum of the numbers of stamps that Alice and Doris have is a multiple of 4.
The sum of the numbers of stamps that Alice and Doris have is (3D+4)+(D+4)=4D+8=4(D+2). So, this sum is a multiple of 4 for ANY value of D, which smeans that this statement is always true.
Answer: B (III only).
Question: Two equal triangles constitute rhombus A. If the diagonals of rhombus are 15cm and 20cm long. What is the area of each triangle?
A.300
B.150
C.75
D.40
Answer: C.75
Explanation: Area of rhombus =0.5 x 15 x 20
=150 cmÂ²
Area of triangle= 150/2=75 cmÂ²
Answer: C
Question: If Ryan and Smith car ratio is 5:8. Ryan bought 6 new car and Smith bought 2 new car. Now,Smith has 18 car.what is their car ratio now?
A.5:4
B.3:2
C.8:9
D.6:5
Answer: C.8:9
Explanation: current no. of Smith car=8x+2=18,8x=16,x=2.
current car ratio= 10+6/18=16/18=8:9.
answer C
Question: Rs.1170 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share?
A.Rs.528
B.Rs.542
C.Rs.528
D.Rs.540
Answer: D.Rs.540
Explanation: A+B+C = 1170
4A = 3B = 2C = x
A:B:C = 1/4:1/3:1/2 = 3:4:6
6/13 * 1170 = Rs.540
Answer: D
Question: The banker's discount on Rs.1550 due a certain time hence is Rs.155. Find the true discount and the banker's gain.
A.14
B.15
C.18
D.21
Answer: A.14
Explanation: Solution
Sum	=B.D x T.D/ B.D - T.D
= B.D x T.D/ B.G
T.D / B. G	=Sum / B.D
= 1550 / 155
= 10 / 1
If B.D is Rs. 11,T.D= Rs.10.
If B.D is Rs.155,
T.D	= Rs.(10 / 11 x 155)
= Rs.140.
And, B.G	= Rs(155 - 140)
= Rs.14.
Answer A
Question: What number should replace the question mark? 2, 16, 4, 14, 6, 12, ---?
A.8
B.10
C.12
D.14
Answer: A.8
Explanation: Answer: A
2, 16, 4, 14, 6, 12, 8?
There are two alternate sequences: +2 and -2.
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 4 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
A.40
B.44
C.48
D.22
Answer: D.22
Explanation: Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 4)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 4 = 4/9(T - 4)
10T = 396 - 176 => T = 22.
ANSWER:D
Question: Which of the following can be a perimeter e of a triangle inscribed in a circle of radius 1?
I. 0.001
II. 0.010
III. 0.100
A.I only
B.III only
C.II and III only
D.I, II, and III
Answer: D.I, II, and III
Explanation: Yes,the length of any side of a triangle must be larger than the positive difference of the other two sides, but smaller than the sum of the other two sides.
But how do you use the above property to solve the question?
The lower limit of the perimeter of an inscribed triangle in a circle of ANY radius is 0: e>0.
Answer is D.
Question: By selling 100 pencil, a trader gains the cost of 30 Pencil. Find his gain percentage?
A.26 1/3%
B.51 1/3%
C.30%
D.53 1/3%
Answer: C.30%
Explanation: C
30%
Let the CP of each pencil be Rs. 1.
CP of 100 pens = Rs. 100
Profit = Cost of 30 pencil = Rs. 30
Profit% = 30/100 * 100 =30%
Question: If $ 5,000 is invested in an account that earns 6% interest compounded semi-annually, then the interest earned after one year would be how much greater than if the $ 5,000 had been invested at 8% simple yearly interest?
A.$ 6
B.$ 8
C.$ 12
D.$ 16
Answer: A.$ 6
Explanation: ANS A
Solution
Amount (CI) = P+(1+r/n)^nt = 5000+(1+0.06/2)^2= 5406
Amount (SI) = P+PTR/100 = 5000+(5000*1*8/100)=5400
Difference = 5406-5400=6 $
A
Question: An error 12% in excess is made while measuring the side of a square. Now What is the percentage of error in the calculated area of the square?
A.6.64%
B.16.64%
C.15.64%
D.25.44%
Answer: D.25.44%
Explanation: Percentage error in calculated area
=(12+12+(12Ã—12)/100)%=25.44%
ANSWER:D
Question: ZYXW’ as coded as ‘ABCD’ then ‘STUV’ is coded as
A.YU
B.YY
C.U
D.H
Answer: D.H
Explanation: Here each letter is coded with its opposite letter. i.e. Z – A, Y – B, X – C, W – D. Similarly, S – H, T – G, U – F, V – E.
Answer:D
Question: There are 15 members in a family. it takes 180 days for a women to complete the work, however man completes in 120 days. They take 17days to complete the work if men work on alternate days and women work every third day. if all of them started together on the 1st day, then how many women are there in the family
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: Let the number of men be m and so the number of women = 15-m
Out of 17 days, men and women work together on 1,4,7,10,13,16th days (Total of 6 days) from the start.
Men work on alternate days, that is 1,3,5,7,9,11,13,15,17th days (Total of 9 days).
Let the total work be 360 units (LCM of 180 and 120).
1 man does 360/120 = 3 units per day
1 woman does 360/180 = 2 units per day
Based on above facts,
Total work by men + women in these 17 days = 360 units
m*9*3 + (15-m)*6*2 = 360,
27m + 180 -12m = 360, Solving m=12.
Num of men = 12 and number of women = 15-12 = 3
ANSWER:C
Question: Mr. Smitherly leaves Cedar Rapids at 8:00 a.m. and drives north on the highway at an average speed of 50 km per hour. Mr. Dinkle leaves Cedar Rapids at 9:00 a.m. and drives north on the same highway at an average speed of 70 km per hour. Mr. Dinkle will
A.overtake Mr. Smitherly at 9:30 a.m.
B.overtake Mr. Smitherly at 10:30 a.m.
C.overtake Mr. Smitherly at 11:30 a.m.
D.be 30 miles behind at 9:35 a.m.
Answer: C.overtake Mr. Smitherly at 11:30 a.m.
Explanation: After one hour, Mr. Smitherly is ahead by 50 km.
Mr. Dinkle gains on Mr. Smitherly 20 km each hour.
2.5 hours after 9:00 a.m., Mr. Dinkle will catch Mr. Smitherly.
The answer is C.
Question: In how much time would the simple interest on a certain sum be 0.125 times the principal at 10% per annum?
A.1 1/4
B.1 1/6
C.1 1/5
D.1 1/3
Answer: A.1 1/4
Explanation: Let sum = x. Then, S.I. = 0.125x = 1/8 x, R = 10%
Time = (100 * x) / (x * 8 * 10) = 5/4 = 1 1/4 years.
Answer:A
Question: In a cinema hall for the matinee show which started at 2.30 pm and ended at 5.30 pm the vehicle parking lot had only three wheelers (auto rickshaws) and four wheelers. Today the wheels of the vehicles parked was counted and found to be 240. What could be the number of three wheelers parked therein?
A.41
B.43
C.42
D.45
Answer: D.45
Explanation: 3X+4y=240
by substitute through options 48 is correct
ANSWER:D
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 sec. What is the length of the fast train?
A.27 7/5
B.27 7/3
C.27 7/2
D.27 7/9
Answer: D.27 7/9
Explanation: Relative speed = (40 - 20) = 20 km/hr.
= 20 * 5/ 18 = 50/9 m/sec.
Length of faster train = 50/9 * 5 = 250/9
= 27 7/9 m.
Answer: D
Question: A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
A.2.5 min
B.3 min
C.3.2 min
D.3.5 min
Answer: B.3 min
Explanation: Total distance = (7/2 + 1/4) miles
= 15/4 miles
time taken = 15/4*75 hrs
=1/20 hrs = 3 min
ANSWER B
Question: A merchant marks his goods up in such a way that the profit made on selling 30 articles is equal to the cost price of 20 articles. What is the E % profit made by the merchant?
A.66.67 %
B.50 %
C.200 %
D.100 %
Answer: A.66.67 %
Explanation: C.P of 1 article= $30(say)
C.P of 20 articles=30*20=$600
Now, C.P of 20 articles=Profit on 30 articles
Therefore, profit on 1 article=$600/30=$20
Profit E%=(20/30)*100=66.67%
Answer A
Question: In an exam Ashley secured 332 marks. If she secured 83 % makes, find the maximum marks
A.133
B.376
C.377
D.400
Answer: D.400
Explanation: Let the maximum marks be m.
Ashley’s marks = 83% of m
Ashley secured 332 marks
Therefore, 83% of m = 332
⇒ 83/100 × m = 332
⇒ m = (332 × 100)/83
⇒ m =33200/83
⇒ m = 400
Therefore, Ashley got 332 marks out of 400 marks.
Answer:D
Question: How many seconds will a 900 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.23 sec
B.30 sec
C.49 sec
D.54 sec
Answer: D.54 sec
Explanation: Speed of train relative to man = 63 - 3
= 60 km/hr.
= 60 * 5/18
= 50/3 m/sec.
Time taken to pass the man = 900 * 3/50
= 54 sec.
Answer:D
Question: The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
A.238
B.3769
C.750
D.789
Answer: D.789
Explanation: Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 25 è x = 25 * 60 / 2 = 750
Answer: D
Question: If the arithmetic mean of seventy five numbers is calculated, it is 35. If each number is increased by 5, then mean of new numbers is
A.30
B.35
C.40
D.50
Answer: C.40
Explanation: Sol.
A.M. of 75 numbers = 35.
Sum of 75 numbers = (75 x 35) = 2625.
Total increase = (75x5) = 375.
Increased sum = (2625 + 375) = 3000.
Increased average = 3000 / 75 = 40.
Answer C
Question: Some of the 50% solution of acid was removed and this was replaced with an equal amount of 30% solution of acid. As a result, a 40% solution of acid was obtained. What fraction of the original solution was replaced?
A.1/2
B.1/3
C.2/3
D.1/4
Answer: A.1/2
Explanation: Let x be the fraction of the original solution that was replaced.
0.5*(1-x)+0.3(x)=0.4
0.2x=0.1
x=1/2
The answer is A.
Question: In how many ways can 4 apples (identical) be distributed among 3 children? (Some children may get no apples.)
A.20
B.25
C.30
D.15
Answer: D.15
Explanation: Generalised form for n = number of identical objects, and r = number of children is n+r-1Cr-1.
n=4 r= 3
6C2 =15
Answer : D
Question: A factory produces 7500 toys per week. If the workers at this factory work 5 days a week and if these workers make the same number of toys everyday, how many toys are produced each day?
A.4436 toys
B.5487 toys
C.6113 toys
D.1875 toys
Answer: D.1875 toys
Explanation: To find the number of toys produced every day, we divide the total number of toys produced in one week (of 5 days) by 5.
7500 /4 = 1875 toys
correct answer D
Question: A student has to secure 30% marks to get through. If he gets 80 marks and fails by 70 marks, find the maximum marks set for the examination.
A.500
B.1000
C.1200
D.1500
Answer: A.500
Explanation: Here, x = 30 , y = 80 and z = 70
Therefore, Maximum marks = [100( y + z )] / x.
= [100( 80 + 70 )]/30
= 500.
ANSWER:A
Question: In a certain village, 20 litres of water are required per household per month. At this rate, if there are 10 households in the village, how long (in months) will 2000 litres of water last?
A.5
B.2
C.10
D.1
Answer: C.10
Explanation: I find it much easier to understand with real numbers, so choose (almost) any numbers to replace m,n and p:
In a certain village,m 20 litres of water are required per household per month. At this rate, if there aren 10 households in the village, how long (in months) willp2000litres of water last?
Water required is 20*10=200 (m*n)
Water available is 2000 (p)
It will last 10 months (p/m*n)
Ans : C
Question: In how many ways a committee, consisting of 4 men and 2 women can be formed from 6men and 4 women?
A.120
B.60
C.90
D.150
Answer: C.90
Explanation: Required number of ways = 6C4 * 4C2
= (6*5/2*1)*(4*3/2*1)
= 90
Answer is C
Question: Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
A.Rs.250
B.Rs.300
C.Rs.350
D.Rs.400
Answer: A.Rs.250
Explanation: Let the amount paid to X per week = x
and the amount paid to Y per week = y
Then x + y = 550
But x = 120% of y = 120y/100 = 12y/10
∴12y/10 + y = 550
⇒ y[12/10 + 1] = 550
⇒ 22y/10 = 550
⇒ 22y = 5500
⇒ y = 5500/22 = 500/2 = Rs.250
A)
Question: John decides to attend a basketball game with six friends. If the party of seven sits together in seven consecutive seats, and John must NOT sit in between two of his friends, how many ways can the seven friends be arranged?
A.1220
B.1000
C.540
D.1440
Answer: D.1440
Explanation: John have to sit at either of the ends.
If John sits on the left most corner, then other 6 friends can be arranged in 6! = 720
John can also sit on the other end, then another 6! ways we can arrange.
So total number of ways = 720+720 = 1440
Answer : D
Question: In how many ways can the letters of the word 'APPLE' be arranged ?
A.90
B.180
C.120
D.60
Answer: D.60
Explanation: The word 'APPLE' contains 5 letters, 1A, 2P, 1L.and 1E.
∴ Required number of ways = 5!/(1!)(2!)(1!)(1!) = 60.
Answer is D
Question: In the faculty of Reverse-Engineering, 230 second year students study numeric methods, 423 second year students study automatic control of airborne vehicles and 134 second year students study them both. How many students are there in the faculty if the second year students are approximately 80% of the total?
A.515.
B.545.
C.618.
D.649.
Answer: D.649.
Explanation: Answer is D :649
Solution : Total number of students studying both are 423 + 230 - 134 = 519 (Subtracting the 134 since they were included in the both the other numbers already).
So 80% of total is 519, so 100% is approx. 649.
Question: If the selling price of a mat is five times the discount offered and if the percentage of discount is equal to the percentage profit, find the ratio of the discount offered to the cost price.
A.11: 30
B.1 : 5
C.1 : 6
D.7 : 30
Answer: D.7 : 30
Explanation: Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.
M.P. = (6/5) S.P.
Since the percentage discount = Percentage profit,
[ { (6/5) S.P. - S.P. } / ((6/5 ) S.P) ] x100 = (S.P - C.P) / C.P x 100
Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.P
M.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.P
Therefore, Ratio of discount to C.P
= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]
= 7/30
Therefore the ratio is 7 : 30
ANSWER:D
Question: If 9 men do a work in 80 days, in how many days will 20 men do it?
A.18 days
B.36 days
C.42 days
D.48 days
Answer: B.36 days
Explanation: 9 * 80 = 20 * x
x = 36 days
ANSWER:B
Question: A tyre has two punctures. The first puncture along would have made the tyre flat in 9 minutes and the second alone would have done it in 6 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat?
A.1 1⁄2 minutes
B.3 1⁄2 minutes
C.3 3⁄5 minutes
D.4 1⁄4 minutes
Answer: C.3 3⁄5 minutes
Explanation: 1 minute’s work of both the punctures = (1⁄9 + 1⁄6) = 5⁄18
So, both the punctures will make the tyre flat in 18⁄5 = 33⁄5 min.
Answer C
Question: A man can row downstream at 18 kmph and upstream at 10 kmph. Find the speed of the man in still water and the speed of stream respectively?
A.6
B.8
C.3
D.4
Answer: D.4
Explanation: Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.
Given x + y = 18 --- (1)
and x - y = 10 --- (2)
From (1) & (2) 2x = 28 => x = 14, y = 4.
Answer:D
Question: A train which has 440 m long, is running 45 kmph. In what time will it cross a person moving at 9 kmph in same direction ?
A.56 sec
B.44 sec
C.36 sec
D.29 sec.
Answer: B.44 sec
Explanation: Time taken to cross a moving person = length of train/ relative speed
Time taken = 440/((45-9) (5/18)
= 440/ 36*(5/18)
= 440/10
= 44 sec
ANSWER:B
Question: Find the curved surface area, if the radius of a cone is 35 m and slant height is 30 m?
A.1100
B.2200
C.3300
D.4400
Answer: C.3300
Explanation: Cone curved surface area = Ï€rl
22/7 Ã— 35 Ã— 30 = 110 Ã— 30 = 3300 m(power2)
Answer is C.
Question: The difference between C.I. and S.I. on an amount of $10,000 for 2 years is $36. What is the rate of interest per annum?
A.5%
B.6%
C.7%
D.8%
Answer: B.6%
Explanation: $36 is the interest on the first year of interest.
Let x be the interest rate.
The interest after the first year is 10000*x.
The interest on the first year's interest is 10000*x*x
10000*x^2 = 36
x = 0.06
The answer is B.
Question: Speed of a boat in standing water is 9 kmph and the speed of the stream is 1. 5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is
A.16 hours
B.18 hours
C.20 hours
D.24 hours
Answer: D.24 hours
Explanation: upstream = 9kmph-1.5kmph = 7.5kmph
Downstream = 9kmph+1.5kmph = 10.5kmph
total time taken = 105/7.5 + 105/10.5 =24 hrs
ANSWER:D
Question: On a certain road 14% of the motorists exceed the posted speed limit and receive speeding tickets, but 20% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit?
A.10.5%
B.12.5%
C.17.5%
D.22%
Answer: C.17.5%
Explanation: Answer is C.
This question is in the OG and thus well explained by ets.
those who exceed : X
so X = 14%+0,2X
id est X = 17,5%
Question: Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R?
A.767
B.500
C.287
D.111
Answer: B.500
Explanation: Explanation:
Let the amounts to be received by P, Q and R be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r
Adding 'p' both sides, 3p = p + q + r = 1200
=> p = Rs.400
q = 1/3 (p + r) => 3q = p + r
Adding 'q' both sides, 4q = p + q + r = 1200
=> q = Rs.300
r = 1200 - (p + q) => r = Rs.500.
Answer: B
Question: If 8 men or 12 women can do a piece of work in 25 days, in how many days can the same work be done by 6 men and 11 women?
A.10 days
B.11 days
C.13 days
D.15 days
Answer: D.15 days
Explanation: 8men = 12women (i.e 2men = 3women)
12women 1 day work= 1/25
soln:
6men(9women)+ 11women=20women=?
1 women 1 day work =12*25= 1/300
so, 20 women work= 20/300=1/15
ans: 15 days
ANSWER:D
Question: A motor boat takes 12 hours to go downstream and it takes 24 hours to return the same distance. what is the time taken by boat in still water?
A.26 h
B.16 h
C.86 h
D.96 h
Answer: B.16 h
Explanation: Explanation:
If t1 and t2 are the upstream and down stream times. Then time taken in still water is given by
\inline \frac{2\times t1\times t2}{t1+t2}=\frac{2\times 12\times 24}{36}=16h
Answer: B
Question: A man buys Rs. 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is?
A.14
B.15
C.61
D.17
Answer: B.15
Explanation: Dividend on Rs. 20 = Rs. (9/100)x 20 = Rs.9/5.
Rs. 12 is an income on Rs. 100.
Rs.9/5 is an income on Rs.[ (100/12) x (9/5)] = Rs. 15?
Answer: B
Question: A and B invest money in the ratio 2:3 and they has loss of Rs.7000 at the end of year. what is the share of loss of B?
A.Rs.4200
B.Rs.3200
C.Rs.1200
D.Rs.200
Answer: A.Rs.4200
Explanation: et ratio of A and B be 2x & 3x
so net loss = 2x+3x= 7000
x=1400
A=2x=2(1400)=2800
B= 3x=3(1400)=4200
so, B= 4200
ANSWER:A
Question: A bullet train leaves Kyoto for Tokyo traveling 240 miles per hour at 12 noon. Ten minutes later, a train leaves Tokyo for Kyoto traveling 160 miles per hour. If Tokyo and Kyoto are 340 miles apart, at what time will the trains pass each other?
A.12:40pm
B.12:49pm
C.12:55pm
D.1:00pm
Answer: C.12:55pm
Explanation: Train A: going from K to T
Train B: going from T to K
First I calculated how far Train A will have travelled by the time Train B starts at 12:10:
10 minutes at 240 mph
1/6*240=40miles
They have 340-40=300 miles to travel to meet each other.
I found the combined rate of the two trains
Rate(A) + Rate(B) = 400mph
Divide Distance/Rate to find total time each will travel:
300/400>>> 45 Minutes to meet
12:10+45 minutes = 12:55 or Answer C
Question: A chemist mixes one liter of pure water with x liters of a 30% salt solution, and the resulting mixture is a 15% salt solution. What is the value of x?
A.1/4
B.1/3
C.1/2
D.1
Answer: D.1
Explanation: Concentration of salt in pure solution = 0
Concentration of salt in salt solution = 30%
Concentration of salt in the mixed solution = 15%
The pure solution and the salt solution is mixed in the ratio of --> (30 - 15)/(15 - 0) = 1/1
1/x = 1/1
x = 1
Answer: D
Question: In five football games thus far this season, Barry has run for 98, 107, 85, 89, and 91 yards. At a minimum, how many yards N will he need to gain this Sunday if he wants to keep his season average above 100 yards?
A.101
B.116
C.130
D.N=131
Answer: D.N=131
Explanation: Sorry the answer N=131 is D.
Question: The probability of obtaining an even prime number on each die, when a pair of dice is rolled out?
A.2/13
B.1/15
C.1/36
D.1/25
Answer: C.1/36
Explanation: The probability of getting an even prime (2) for a pair of dice is only once.
That is 1 on each die.
probability of getting 1 on a die is 1/6.
probability of getting 1 on 2 dice is 1/6 × 1/6 = 1/36
C
Question: A bag contains 6 red, 5 blue and 2 green balls. If 2 ballsare picked at random, what is the probability that both are red?
A.2/13
B.1/15
C.5/26
D.3/25
Answer: C.5/26
Explanation: P(Both are red),
=6C213C2=6C213C2
=5/26
C
Question: If the simple interest on a sum of money at 5% per annum for 3 years is Rs.1200, find the compound interest on the same sum for the same period at the same rate.
A.1251
B.1261
C.1271
D.1281
Answer: B.1261
Explanation: Solution
Clearly, Rate	= 5% p.a.
Time	= 3 years
S.I	=Rs.1200.
So,Principal	=Rs.(100 x 1200/3x5)
=Rs.8000.
Amount	=Rs.[8000 x (1+5/100)³]
=Rs(8000x21/20x21/20x21/20)
= Rs.9261
C.I	=Rs.(9261-8000)
=Rs.1261.
Answer B