RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: here are 5 Rock songs, 6 karnatic songs and 3 Indi pop songs. How many different albums can be formed using the above albums should contain at least 1 Rock song and 1 karnatic song?
A.36254
B.45124
C.15624
D.45654
Answer: C.15624
Explanation: There are 2n ways of choosing ‘n’ objects. For e.g. if n = 3, then the three objects can be chosen in the following 23 ways - 3C0 ways of choosing none of the three, 3C1 ways of choosing one out of the three, 3C2 ways of choosing two out of the three and 3C3 ways of choosing all three.
In the given problem, there are 5 Rock songs. We can choose them in 25 ways. However, as the problem states that the case where you do not choose a Rock song does not exist (at least one rock song has to be selected), it can be done in 25 - 1 = 32 - 1 = 31 ways.
Similarly, the 6 Carnatic songs, choosing at least one, can be selected in 26 - 1 = 64 - 1 = 63 ways.
And the 3 Indi pop can be selected in 23 = 8 ways. Here the option of not selecting even one Indi Pop is allowed.
Therefore, the total number of combinations = 31 * 63 * 8 = 15624
Ans: C
Question: 3 people are sitting in a 4 seat row watching a football game. At halftime they all get up. When they return, they each randomly sit down on one of the 4 chairs. What is the likelihood that none of the 4 end up sitting in the same chair that they sat in during the first half?
A.1/2
B.9/24
C.15/24
D.18/24
Answer: A.1/2
Explanation: Originally seated A B C D
now when after they get up and when they sit back again .
1st- A has option to sit on 3 seats ( apart from his previous seat . thus he now sits on B's seat.)
2nd- Similarly B has option to sit on 3 seats ( because A has already occupied B's previous seat, thus B sits on a's seat.)
3rd- Now C has only 1 option to sit on D's seat . and similarly D also has one option to sit on C's seat.)
hence total favourable outcomes 3*1*1=3
and total possible outcomes =3!=6
probability of the favourable outcome=1/2. A
Question: Average of six numbers comes out to be 3.95. Average of two of the numbers is 3.4 while the average of other two is 3.85. Determine the average of the two numbers left.
A.4.7
B.4.8
C.4.3
D.4.6
Answer: D.4.6
Explanation: Explanation:
In the given question we have taken average of 6 numbers taken 2 at a time which makes 3 numbers.
=> 3.95 (Average of 1st and 2nd number)
=> 3.85 (Average of 3rd and 4th number)
=> 3.4 (Average of 5th and 6th number)
3.95 = (3.4 + 3.85 + x)/3
x = 4.6
ANSWER D
Question: The rate of a certain chemical reaction is directly proportional to the square of the concentration of chemical A present and inversely proportional to the concentration of chemical E present. If the concentration of chemical E is increased by 100 percent, which of the following is closest to the percent change in the concentration of chemical A required to keep the reaction rate unchanged?
A.100% decrease
B.50% decrease
C.40% decrease
D.40% increase
Answer: D.40% increase
Explanation: Let A and E be the concentratrations of the individual chemicals.
Rate of chemical reaction = A^2/E
Since new E is increased by 100%
Rate = A^2/(2E)
For the rate to be constant, new value of A should be square root(2)
So new value of A = 1.414A
That means A is increased by 41.4%
Nearest solution is D
Question: Simplify
25âˆ’[2âˆ’(6+2(7âˆ’8âˆ’5Â¯Â¯Â¯Â¯Â¯Â¯Â¯Â¯Â¯Â¯Â¯))]
A.37
B.25
C.28
D.30
Answer: A.37
Explanation: Explanation:
=25âˆ’[2âˆ’(6+2(7âˆ’8+5))]
(Please check due to overline, sign has been changed)
=25âˆ’[2âˆ’(6+2Ã—4))]
=25âˆ’[âˆ’12]=25+12=37
Option A
Question: To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present ?
A.10
B.35
C.25
D.45
Answer: A.10
Explanation: 2/5 of 25 = 10
ANSWER:A
Question: A four-character password consists of one letter of the alphabet and three different digits between 0 and 7, inclusive. The letter must appear as the second or third character of the password. How many different passwords are possible?
A.5,040
B.18,720
C.17,472
D.37,440
Answer: C.17,472
Explanation: 4 character password: DLDD
First digit can be chosen in 8 ways.
The letter can be chosen in 26 ways.
Next digit can be chosen in 7 ways.
Next digit can be chosen in 6 ways.
This gives us 8*26*7*6ways
Now, the letter can also be DDLD so there will be another 8*26*7*6 ways
Total = 8*26*7*6*2 = 17,472 ways C
Question: A single discount equivalent to the discount series of 20%, 10% and 5% is?
A.20
B.99
C.7878
D.656
Answer: A.20
Explanation: SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20% Answer: A
Question: If p/8 = r/2 and r = 0.75s, what is the ratio of p to r to s?
A.2 : 3 : 4
B.8 : 12 : 9
C.24 : 6 : 8
D.6 : 4 : 3
Answer: C.24 : 6 : 8
Explanation: p/8=r/2, r=0.75s, what is p:r:s?
we get p/r=8/2 and r/s=3/4, so
8/3*3/2 and 2/2*3/4
24/6 and 6/8
C
Question: A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 190 kilometers?
A.3.5 gallons
B.2.7 gallons
C.5.7 gallons
D.4.75 gallons
Answer: D.4.75 gallons
Explanation: Each 40 kilometers, 1 gallon is needed. We need to know how many 40 kilometers are there in 190 kilometers?
190 Ã· 40 = 4.75 Ã— 1 gallon = 4.75 gallons
correct answer is D) 4.75 gallons
Question: What sum of money put at C.I amounts in 2 years to Rs.8820 and in 3 years to Rs.9261?
A.8000
B.8077
C.2776
D.2976
Answer: A.8000
Explanation: 8820 ---- 441
100 ---- ? => 5%
x *105/100 * 105/100 = 8820
x*1.1025=8820
x=8820/1.1025 => 8000.Answer: A
Question: A basketball player succeeds with 80% of her free throws. If she has a set of three free throws, what is the probability that she succeeds at least once?
A.0.972
B.0.978
C.0.984
D.0.992
Answer: D.0.992
Explanation: P(missing all 3 free throws) = 0.2^3 = 0.008
P(succeeding at least once) = 1 - 0.008 = 0.992
The answer is D.
Question: A batsman scored 150runs which included 5 boundaries and 5 sixes. What percent of his total score did he make by running between the wickets.
A.40%
B.50%
C.60%
D.66.66%
Answer: D.66.66%
Explanation: Explanation:
Number of runs made by running = 150 - (5 x 4 + 5 x 6)
= 150 - (50)
= 100
Now, we need to calculate 100 is what percent of 150.
=> 100/150 * 100 = 66.66 %
Option D
Question: If shares of two persons in profits are Rs.400 and Rs.600 then ratio of their capitals is
A.3:4
B.2:3
C.4:3
D.1:3
Answer: B.2:3
Explanation: profit=time*capital
so 400:600=2:3
ANSWER:B
Question: If the cost of x metres of wire is d rupees, then what is the cost of y metres of wire at the same rate?
A.Rs.(yd/U)
B.Rs.(yI/x)
C.Rs.(Od/x)
D.Rs.(yd/x)
Answer: D.Rs.(yd/x)
Explanation: Cost of x metres = Rs. d.
Cost of 1 metre = Rs. d
x
Cost of y metres = Rs. d	. y = Rs. yd	.
x	x
View Answer Discuss in Forum
Answer:D
Question: An investor receives a total combined return of 7% on his two different investments. On his $10,000 investment he receives a return of 6%. What is the return on his $20,000 investment?
A.7.25%
B.7.5%
C.8%
D.8.5%
Answer: B.7.5%
Explanation: Total investment = $30000
on which he receives 7% = 2100
now,
on his $10000 he receives 6% = $600
remaining $1500
which is (1500/20000)*100 = 7.5
ANSWER:B
Question: A train 320 m in length crosses a telegraph post in 16 seconds. The speed of the train is?
A.22 kmph
B.77 kmph
C.54 kmph
D.72 kmph
Answer: D.72 kmph
Explanation: S = 320/16 * 18/5 = 72 kmph
Answer:D
Question: If 50 percent of X is 25 percent of Y, then what is the relation between X and Y?
A.X=Y
B.2X=Y
C.X=2Y
D.1
Answer: B.2X=Y
Explanation: 50/100(X) = 25/100(Y)
2X=Y..
Option B.
Question: In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100?
A.22
B.28
C.025
D.20
Answer: C.025
Explanation: A scores 60 while B score 40 and C scores 30.
The number of points that C scores when B scores 100 = (100 * 30)/40 = 25 * 3 = 75.
In a game of 100 points, B gives (100 - 75) = 25 points to C.
Answer: C
Question: A dozen bananas and 10 pounds of oranges are currently at the same price. If the price of a dozen bananas rises by 20 percent and the price of oranges rises by 4 %. How much more will it cost to buy a dozen bananas and 10 pounds of oranges.
A.24%
B.22%
C.23%
D.25%
Answer: A.24%
Explanation: Say currently both a dozen bananas and 10 pounds of oranges cost $100 (they are at the same price). So, to buy a dozen bananas and 10 pounds of oranges we need $200.
After the increase, the price of a dozen bananas will be $120 and the price of 10 pounds of oranges will be $104. So after the increase, to buy a dozen bananas and 10 pounds of oranges we'll need $224.
Increase = 24%.
Answer: A.
Question: What is the rate percent when the simple interest on Rs.4000 amount to Rs.640 in 2 Years?
A.8.2%
B.8%
C.8.5%
D.9%
Answer: B.8%
Explanation: Interest for 1 year = 640/2 = 320
Interest on Rs 4000 p/a = 320
interest rate = 320/4000*100 = 8%
Answer : B
Question: If x is divisible by 20, 14, and 70, which of the following must be the least multiple of x?
A.70
B.140
C.210
D.350
Answer: B.140
Explanation: We are looking for the LCM (which is not 0) of 20 = 2^2*5, 70 = 2*7*5, 14 = 2*7:
2^2 * 5 * 7 = 140
The answer is B.
Question: The longest side of a triangle is 3 times the shortest side and the third side is 2 cm shorter than the longest side. If the perimeter of the triangle is at least 61 cm,What is the minimum length of the shortest side?
A.8cm
B.9cm
C.10cm
D.11cm
Answer: B.9cm
Explanation: let the shortest measurement be x cm
then the largest side will be 3x cm
and the third side will be (3x-2)cm
now according to the problem
x+3x+3x-2 >=61
7x-2 >= 61
7x >= 63
therefore x>=9cm
ANSWER:B
Question: Let the function T(n) represent the product of the first n prime numbers, where n > 0. If x = T(n) + 1, which of the following must be true?
(i) x is always odd
(ii) x is always prime
(iii) x is never the square of an integer
A.ii only
B.iii only
C.i and ii only
D.i and iii only
Answer: D.i and iii only
Explanation: T(n) is always even, because the first prime is 2 and no matter what n is, 2 always will be a divisor of T(n). Thus, T(n) + 1 = even + 1 = odd. So, (i) is always true.
Now, use logic:
If (ii) is true (so if x is always prime), then (iii) must automatically be true: no prime is the square of an integer. So, the correct answer must be i only; i, ii, and iii only; or i and iii only. since onlyi and iii onlyis among the options, then it must be true.
Or, since (i) is always true, then from options the answer must be either C or D. C cannot be correct because if (ii) is true, then so must be (iii). Thus only D remains.
Answer: D.
Question: A rower can row upstream at 15 kph and downstream at 35 kph. What is the speed of the rower in still water?
A.22
B.23
C.24
D.25
Answer: D.25
Explanation: Let V be the rower's speed in still water.
Let S be the speed of the current in the stream
V-S = 15
V+S = 35
When we add the two equations, we get: 2V = 50
Then V = 25 kph.
The answer is D.
Question: A university cafeteria offers 5 flavors of pizza - pork,pepperoni, chicken, Hawaiian and vegetarian. If a customer has an option (but not the obligation) to add extra cheese, mushrooms or both to any kind of pizza, how many different pizza varieties are available ?
A.4
B.8
C.12
D.25
Answer: D.25
Explanation: 5 flavours * 5 choices = 5C1*5C1 = 5*5=25=D
Question: A man goes from A to B at a speed of 20 kmph and comes back to A at a speed of 30 kmph. Find his average speed for the entire journey?
A.24 kmph
B.22 kmph
C.23 kmph
D.21 kmph
Answer: A.24 kmph
Explanation: A
24 kmph
Distance from A and B be 'd'
Average Speed = total distance/total time
Average Speed = (2d)/[(d/20) + (d/30)]
= (2d)/[5d/60) => 24 kmph.
Question: A certain car can travel 40 kilometers on a liter of fuel. If the fuel tank’s contents decrease by 3.9 gallons over a period of 5.7 hours as the car moves at a constant speed, how fast is the car moving, in miles per hour? (1 gallon = 3.8 liters; 1 mile = 1.6 kilometers)
A.52
B.65
C.78
D.91
Answer: B.65
Explanation: Fuel used 3.9 gallons ;convert to liters--> 3.9 x 3.8 liters
Time = 5.7 hours
1 mile = 1.6 kilometers ;convert to miles--> 1km = 1/1.6 mile
Speed (km/hour)= D/T = 40 (km*) x 3.9 x 3.8 / 5.7
replace (km*) to miles ; multiply by 1/1.6 mile
Speed (miles/hour)= 40 x 3.9 x 3.8 / 5.7 x 1.6 = 78 miles/hour
Ans :C
PS :i felt the factors were easy to cancel out ,so didn't require much rounding off
= 40 x 3.9 x 3.8 / 5.7 x 1.6
= 65
B
Question: An area of a circularplace is 17 hectares. Find the cost of fencing it at the rate of Rs. 3 permeter approximately.
A.Rs. 4000
B.Rs. 4450
C.Rs. 4457
D.Rs. 4560
Answer: C.Rs. 4457
Explanation: Area = (17.56 x 10000) m2= 175600 m2.
ΠR2 = 175600 ⇔ (R)2 = (175600 x (7/22)) ⇔ R = 236.37 m.
Circumference = 2ΠR = (2 x (22/7) x 236.37) m =1485.78 m.
Cost of fencing = Rs. (1485.78 x 3) = Rs. 4457.
C
Question: A 12 month project had a total budget of $18,000. After five months, the project had spent $6,400. At this point, how much was the project under budget?
A.$1000
B.$1100
C.$1200
D.$1300
Answer: B.$1100
Explanation: Each month, the project should spend $18,000 / 12 = $1500.
In 5 months, the project should spend 5*$1500=$7500.
The project is under budget by $7500 - $6400 = $1100.
The answer is B.
Question: A work could be completed in 100days by x workers. However, due to the absence of 10workers, it was completed in 110days. The original no.of workers was:
A.90
B.100
C.110
D.134
Answer: C.110
Explanation: sax Letlheo g alnumberofworkers hex
x workers can do the wor - 100 days
(x — 10) workers can do the work in 110 days
4 100x 1u1x— 10)
1100 Q x 110
C
Question: Tough and Tricky questions: Exponents.
If a and b are positive integers and x = 24^a and y = 9^b, which of the following is a possible units digit of xy?
A.1
B.6
C.5
D.7
Answer: B.6
Explanation: Only Units digit of X and Y contribute to the Units digit of XY.
Finding all values ofXfor positive values ofa
When,
a=1; X=24
a=2; X=576
a=3; X=13824........ Units digit repeat in a cycle of 4,6,4,6......
Similarly, Finding all values ofYfor positive values ofb
When,
b=1; Y=9
b=2; Y= 81
b=3; Y= 729....... Units digit repeat in cycle of 9,1,9,1....
So, possible value of Units digit of XY can be found by considering all possibilities of Units digit of X and Y
When X=4 and Y=9: Units digit of XY = 6
When X=4 and Y=1: Units digit of XY = 4
When X=6 and Y=9: Units digit of XY = 4
When X=6 and Y=1: Units digit of XY = 6
Only two possibilities for Units digit of XY i.e. 4 and 6.
Only 6 is given in answer choices, therefore answer is B
Question: An inspector rejects 0.008% of the meters as defective. How many will be examine to project ?
A.2000
B.230
C.2700
D.25000
Answer: D.25000
Explanation: Let the number of meters to be examined be x.
Then, 0.008% of x =2
[(8/1000)*(1/100)*x] = 2
x = [(2*100*1000)/8] = 25000
Answer is D.
Question: In a school of 850 boys, 44% of Muslims, 32% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
A.A)125
B.B)119
C.C)153
D.D)721
Answer: B.B)119
Explanation: 44 + 32 + 10 = 86%
100 – 84 = 14%
850 * 14/100 = 119
Answer:B
Question: On the x-y coordinate plane there is a parabola, y=x(6-x). Which of the following points is in the region that is enclosed by this parabola and the x-axis?
I. (1, 1) II. (4, 4) III. (6, 6)
A.I only
B.II only
C.III only
D.I and II
Answer: D.I and II
Explanation: Since co-efficient of x^2 is negative, the parabola will be downward facing. So the parabola and the x axis will enclose some points where the y-values of the parabola are positive.
When x = 1, y = 5 lies on the parabola, so (1, 1) will be enclosed by the parabola and x axis.
When x = 4, y = 8 lies on the parabola, so (4, 4) will be enclosed by the parabola and x axis.
When x = 6, y = 0 lies on the parabola, so (6, 6) will not be enclosed by the parabola and x axis.
The answer is D.
Question: ♠n denotes the number obtained when n is rounded to the nearest tenth. For example ♠4.31 = 4.3
♠0.098 - ♠1.125 =
A.-1.1
B.1.04
C.-1.05
D.-1.0
Answer: A.-1.1
Explanation: ♠0.098 - ♠1.125 =
0.1 - 1.1 = -1.1
Answer : A
Question: A customer pays 20 dollars for a coffee maker after a discount of 20 dollars
What is the original price of the coffee maker?
A.50
B.40
C.70
D.60
Answer: B.40
Explanation: Let x be the original price.
x - 20 = 20
x - 20 + 20 = 20 + 20
x + 0 = 40
x = 40
Answer is B
Question: John makes $60 a week from his job. He earns a raise and now makes $90 a week. What is the % increase?
A.16%
B.50%
C.17%
D.17.61%
Answer: B.50%
Explanation: Increase = (30/60)*100 = (3/6)*100 = 50%.
B
Question: The function f is defined for all positive integers n by the following rule: f(n) is the product of the distinct prime factors of n. If f(n) < 30 and n is not prime, what is the greatest possible value of f(n)?
A.28
B.26
C.20
D.18
Answer: B.26
Explanation: Since we need the largest value of f (n), we will start with the largest option.
Option A: 28 = 2*2*7. This is not a product of distinct prime numbers. Hence incorrect
Option B: 26 = 2*13. This is a product of distinct prime numbers.
Rest all the options are smaller that 26.
Correct Option: B
Question: On dividing a certain number by 5, 7 and 8 successively, the remainders obtained are 2, 3 and 4 respectively. When the order of division is reversed and the number is successively divided by 8, 7 and 5, the respective remainders Q will be:[/b]
A.Q=3, 3, 2
B.Q=3, 4, 2
C.Q=5, 4, 3
D.Q=5, 5, 2
Answer: D.Q=5, 5, 2
Explanation: Let the original number be X. Then by the successive dividing we have followings :
X=5A+2
A=7B+3
B=8C+4.
So we have A=7*(8C+4)+3=7*8C+31, and X=5*(7*8C + 31)+2 = 5*7*8C + 157.
Now by dividing X by 8, 7, 5 successively we have followings :
X=8*(5*7C+19)+5
5*7C+19=7*(5C+2) + 5
5C+2=5C+2.
The remainders are, therefore, 5, 5, 2.
The answer is (D).
Question: One-fourth of a tank holds 135 litres of water. What part of the tank is full if it contains 180 litres of water?
A.1/2
B.1/3
C.1/5
D.1/6
Answer: B.1/3
Explanation: 135 litres = 1/4 of tank
180 litres = 1/4 x 180/135 = 1/3
Answer B.
Question: ?⁄50 = 60.5⁄?
A.55
B.1512.5
C.52.5
D.57.5
Answer: A.55
Explanation: ?⁄50 = 60.5⁄?
or,?2 = 50 × 60.5 or, ?2 = 3025
or, ? = √3025 = 55
Answer A
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is?
A.87 years
B.40 years
C.19 years
D.16 years
Answer: B.40 years
Explanation: Sum of the present ages of husband, wife and child
= (27 * 3 + 3 * 3) = 90 years.
Sum of the present age of wife and child
= (20 * 2 + 5 * 2) = 50 years.
Husband's present age
= (90 - 50) = 40 years.
Answer: B
Question: 15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men?
A.33
B.77
C.30
D.88
Answer: C.30
Explanation: 3W = 2M
15M ------ 21 * 8 hours
21 W ------ x * 6 hours
14 M ------ x * 6
15 * 21 * 8 = 14 * x * 6
x = 30
Answer: C
Question: The average of 35 students in a class is 18 years. The average age of 25 students is 16. What is the average age of remaining 10 students?
A.21 years
B.23 years
C.22 years
D.20 years
Answer: B.23 years
Explanation: Sum of the ages of 14 students
= (18 * 35) - (16 * 25) = 630 - 400 = 230
Required average = (230/10) = 23 years.
Answer:B
Question: What is the median from the below series 93, 88, 95, 88, 97, 87, and 98
A.80
B.82
C.92.14
D.98
Answer: C.92.14
Explanation: Ordering the data from least to greatest, we get:
87, 88, 88, 93, 95, 96, 98
The median quiz score was 92.14 (Four quiz scores were higher than 92.14 and four were lower.)
C
Question: What is the greatest 6-digit number when divided by 7 ,8 , 9, and 10 leaves a remainder of 5, 6, 7, and 8 respectively?
A.456788
B.678910
C.997479
D.997919
Answer: A.456788
Explanation: When you divide a positive integer by 10, the remainder will just be the units digit. We know the remainder is 8 when we divide by 10, so A is the only possible answer.
Question: A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed R of the train.
A.a) 45
B.b) 33
C.c) 48
D.d) 55
Answer: C.c) 48
Explanation: Let y be the balance distance to be covered and x be the former speed.
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late
so, y/(3x/4) - y/x = 35/60
4y/3x - y/x = 7/12
y/x(4/3-1)=7/12
y/x*1/3=7/12
y/x=7/4
4y-7x=0 ........ 1
Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late
so, (y-24)/(3x/4) - (y-24)/x = 25/60
4(y-24)/3x - (y-24)/x = 5/12
(y-24)/x (4/3-1) = 5/12
(y-24)/x *1/3 = 5/12
(y-24)*12 = 3x*5
(y-24)*4 = 5x
4y-5x = 96 ....... 2
eq2 - eq1
2x=96
x=48=R
Ans = C
Question: Find the average of all the numbers between 6 and 34 which are divisible by 5
A.18
B.20
C.24
D.30
Answer: B.20
Explanation: Exp. Multiples of 5 between 6 and 34 are 10,15,20,25,30
Average = (10+15+20+25+30)/5 =5(10+30)/2*5 = 40/2 =20
Answer:B
Question: In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at T mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]
A.{ (6T)^2 + (5000-5y)^2 }^1/2
B.{ (36x)^2 + (5000-7y)^2 }^1/2
C.{ (16x)^2 + (5000-7y)^2 }^1/2
D.{ (7x)^2 + (5200-7y)^2 }^1/2
Answer: A.{ (6T)^2 + (5000-5y)^2 }^1/2
Explanation: The chinese ship sailed for 5 months i.e. 5Y miles @Y miles/month, therefore distance from Egyptian port is 5000-5Y. Since A is the only option with this value ...therefore A is the answer
Question: After a storm deposits 120 billion gallons of water into the city reservoir, the reservoir is 80% full. If the original contents of the reservoir totaled 200 billion gallons, the reservoir was approximately what percentage full before the storm?
A.45%
B.48%
C.50%
D.58%
Answer: C.50%
Explanation: When the storm deposited 120 billion gallons, volume of water in the reservoir = 200 + 120 = 320 billion gallons
If this is only 80% of the capacity of the reservoir, the total capacity of the reservoir = 320/0.8 = 400 billion gallons
Therefore percentage of reservoir that was full before the storm = (200/400)*100 = 50%
Option C
Question: A mixture of 70 litres of milk and water contains 10% water. How many litres of water should be added to the mixture so that the mixture contains 12 1/2% water?
A.2
B.8
C.6
D.3
Answer: A.2
Explanation: A
2
Quantity of milk in the mixture = 90/100 (70) = 63 litres.
After adding water, milk would form 87 1/2% of the mixture.
Hence, if quantity of mixture after adding x liters of water, (87 1/2) / 100 x = 63 => x = 72
Hence 72 - 70 = 2 litres of water must be added.
Question: A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?
A.32 Yrs
B.36 Yrs
C.40 Yrs
D.48 Yrs
Answer: C.40 Yrs
Explanation: Explanation:
Let the mother's present age be x years.
Then, the person's present age = (2/5)*x years.
((2/5)*x)+8 = (1/2)(x+8)
2(2x + 40) = 5(x + 8)
x = 40.
Answer: C
Question: By selling 15 pens for a rupee a woman loses 25%. How many for a rupee should he sell in order to gain 25%?
A.12
B.14
C.45
D.10
Answer: D.10
Explanation: D
85% --- 15
125% --- ?
85/125 * 15 = 10
Question: By selling an article for 96, double profit is obtained than the profit that would have been obtained by selling it for 84. What is the cost price of the article?
A.72.0
B.75.0
C.70.00
D.68.00
Answer: A.72.0
Explanation: Let the cost price of the article be x.
Then,2(84 –x) = 96 – x
l68 – 2x= 96 – x \ x = 72
Answer A
Question: What is the area of square field whose side of length 13 m?
A.169
B.196
C.266
D.288
Answer: A.169
Explanation: 13 * 13 = 169 sq m
Answer: A