RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What will be the HCF of ( 2 x 3 x 7 x 9 ), ( 2 x 3 x 9 x 11 ) and ( 2 x 3 x 4 x 5 )?
A.2 x 3 x 7
B.2 x 3 x 9
C.2 x 3
D.2 x 7 x 9 x 11
Answer: C.2 x 3
Explanation: Answer
Given factors
2 x 3 x 7 x 9; 2 x 3 x 9 x 11; 2 x 3 x 4 x 5
∴ Required HCF = Product of common prime factors having least powers = 2 x 3
Correct Option: C
Question: 70% of the employees in a multinational corporation have VCD players, 75 percent have microwave ovens, 80 percent have ACs and 85 percent have washing machines. At least what percentage of employees has all four gadgets?
A.15%
B.5%
C.10%
D.20%
Answer: C.10%
Explanation: Given a population where A% has a certain characteristic X and B% has another characteristic Y (assuming both aren't exclusive), then you get the minimum overlap by assuming that the entire population that doesn't have X has characteristic Y, therefore the minimum portion of the population that has both characteristics is:
B-(100-A) %
So given A=70 for employees with VCD players and B=75 for employees with microwave ovens, at least:
75-(100-70)=45% have both. Then take the output and repeat with the other appliances.
A=45 for employees with both VCD players and microwaves, B=80 for ACs
80-(100-45)=25%
A=25 for employees with VCD players, microwaves and ACs, B=85 for washing machines
85-(100-25)=10%
Answer C
Question: Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 663 and for 36kgs of Apples is 726 then the cost of first 10 kgs of Apples is
A.100
B.150
C.200
D.350
Answer: C.200
Explanation: Ans: By framing equations we get
30L+3Q=663
30L+6Q=726
Eliminate Q by multiplying the first equation by 2 and subtracting second equation from the first
Then we get L = 20
Cost of 10 kgs of apples = 10 x 20 = 200
Answer:C
Question: A Train requires 10 seconds to pass a pole while it requires 35 seconds to cross a stationary train which is 500 mtrs long. Find the speed of the train.
A.68 kmph
B.70 kmph
C.72 kmph
D.60 kmph
Answer: C.72 kmph
Explanation: In 10s the train crosses the pole and in 35 sec the train crosses one more stationary train
In 25 sec the train travels a distance of 500 mtrs
Speed = 500/25 = 20 m/s = 20 (3600/1000) = 20 * 18/5 = 72 kmph
Answer: C
Question: The balance of a trader weighs 10% less than it should. Still the trader marks up his goods to get an overall profit of 30%. What is the mark up on the cost price?
A.40%
B.8%
C.25%
D.17%
Answer: D.17%
Explanation: The most natural way to deal with 'weights' questions is by assuming values.
Say the trader's balance shows 100 gms. It is actually 90 gms because it weighs 10% less. Say, the cost price is $90 ($1/gm). Since he gets a profit of 30%, the selling price must be 90+(30/100)*90 = $117
Since the cost price is actually supposed to be $100 (for 100 gms) and the selling price is $117, the mark up is simply 17%.
Ans : D
Question: Arabica coffee costs $0.4 per ounce while Robusta coffee costs $0.3 per ounce. If the blend of Arabica and Robusta costs $0.37 per ounce, what is the share of Arabica in this blend?
A.20%
B.24%
C.70%
D.33%
Answer: C.70%
Explanation: a= amount of arabica coffee
1-a = amount of robusta coffee. because if you subtract a from the 1 ounce, the remaining amount is robusta
therefore:
.4a + .3(1-a) = .37
.4a + .3 - .3a = .37
a= .7
therefore: .7/1 ounce = 70%. Therefore, the answer should be C
Question: A can do half the work in one day where as B can do it full. B can also do half the work of C in one day. Ratio in their efficiency will be?
A.1:2:8
B.1:2:1
C.1:2:2
D.1:2:4
Answer: D.1:2:4
Explanation: WC of A: B = 1:2
B: C = 1:2
---------------------
A: B: C = 1:2:4
Answer:D
Question: Vijay bought 160 shirts at the rate of Rs. 255 per shirt. The transport expenditure was Rs. 1400. He paid an octroi at the rate of Rs. 1.75 per shirt and labour charges were Rs. 320. What should be the selling price of one shirt, if he wants a profit of 20%?
A.Rs. 321
B.Rs. 270
C.Rs. 277.5
D.Rs. 285
Answer: A.Rs. 321
Explanation: Total CP per shirt = 255 + 1400/160 + 1.75 + 320/160 = Rs. 267.5
SP = CP[(100 + profit%)/100]
= 267.5 * [(100 + 20)/100] = Rs. 321.
ANSWER:A
Question: Four staff members at a certain company worked on a project. The amounts of time that the four staff members worked on the project were in the ratio 2 to 3 to 5 to 6. If one of the four staff members worked on the project for 240 hours, which of the following CANNOT be the total number of hours that the four staff members worked on the project?
A.1280
B.960
C.768
D.1920
Answer: B.960
Explanation: Four members worked in ration 2:3:5:6, hence as everyone mentioned, individual work could be taken as 2x, 3x,5x, and 6x. Also this gives us total work as 16x.
But we are told that one of these individual works is 30hrs. hence, possible scenarios, if
(1)2x =240 => 16x = 1920 (2) 3x =240 => 16x = 1280 (3) 5x =240 => 16x = 768 (4) 6x =240 => 16x = 640
Hence Answer is B 960 which can not be any of these.
Question: The difference between the local value and face value of 7 in the numeral 657903 is:
A.0
B.7896
C.6993
D.903
Answer: C.6993
Explanation: (Local value)-(Face value)= (7000-7)
=6993.
ANSWER:C
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a loss of 25% and then I found each book was sold at the same price. Find the cost of the book sold at a lower loss?
A.A)657
B.B)280
C.C)225
D.D)289
Answer: C.C)225
Explanation: x*(85/100)
= (480 - x)75/100
x = 225
Answer:C
Question: Which of the following has the most number of divisors?
A.344
B.377
C.176
D.888
Answer: C.176
Explanation: Explanation:
99 = 1 x 3 x 3 x 11
101 = 1 x 101
176 = 1 x 2 x 2 x 2 x 2 x 11
182 = 1 x 2 x 7 x 13
So, divisors of 99 are 1, 3, 9, 11, 33, .99
Divisors of 101 are 1 and 101
Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176
Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.
Hence, 176 has the most number of divisors.
Answer: C) 176
Question: The cash difference between the selling prices of an article at a profit of 2% and 6% is Rs 3. The ratio of two selling prices is
A.51:53
B.52:53
C.53:54
D.54:55
Answer: A.51:53
Explanation: Explanation:
Let the Cost price of article is Rs. x
Required ratio = (102% of x) / (106% of x)
=102/106
=51/53 = 51:53.
Answer: A
Question: A jar contains 4 black and 3 white balls. If you pick two balls at the same time, what's the probability that one ball is black and one is white?
A.2/7
B.5/7
C.4/7
D.3/7
Answer: C.4/7
Explanation: P(1st black, 2nd white) = 4/7*3/6 = 4/14;
P(1st white, 2nd black) = 3/7*4/6 = 4/14.
P = 4/14 + 4/14 = 4/7.
Answer: C.
Question: If s and t are positive integers such that s/t = 64.14, which of the following could be the remainder when s is divided by t ?
A.9
B.16
C.18
D.21
Answer: D.21
Explanation: 0.14 = 7/50
The remainder must be divisible by 7.
The answer is D.
Question: A foreign language club at Washington Middle School consists of n students, 2/5 of whom are boys. All of the students in the club study exactly one foreign language. 1/3 of the girls in the club study Spanish and 4/5 of the remaining girls study French. If the rest of the girls in the club study German, how many girls in the club, in terms of n, study German?
A.2n/5
B.n/3
C.2n/25
D.2n/15
Answer: C.2n/25
Explanation: 2/5 of the students are boys, thus 3/5 of the students are girls.
1/3 of the girls in the club study Spanish and 4/5 of the remaining girls study French.
Thus 1/5 of 2/3 = 2/15 of the girls study German.
Since girls comprise 3/5 of the students, then 3/5*2/15 = 2/25 are girls who study German.
The answer is C.
Question: Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 12 inches by 15 inches and Jordan's rectangle is 9 inches long, how wide is Jordan's rectangle, in inches?
A.17
B.18
C.19
D.20
Answer: D.20
Explanation: Area of first rectangle is 12*15=180 hence area of second would be 9x=180x
x=20
answer is D
Question: A is twice as good as workman as B and together they finish a piece of work in 18 days. In how many
days will B alone finish the work.
A.27 days
B.54 days
C.56 days
D.68 days
Answer: B.54 days
Explanation: Explanation:
As per question, A do twice the work as done by B.
So A:B = 2:1
Also (A+B) one day work = 1/18
To get days in which B will finish the work, lets calculate work done by B in 1 day =
=(118
∗
13)=154
[Please note we multiplied by 1/3 as per B share and total of raƟo is 1/3]
So B will finish the work in 54 days
Answer: B
Question: Points A, B, C, and D, in that order, lie on a line. If AB = 2 cm, AC = 5 cm, and BD = 9 cm, what is CD, in centimeters?
A. 1
B. 2
C. 3
D. 6
Answer: D. 6
Explanation: Putting a value to each point, lets use the following:
A - 0
B - 2 (AB = 2)
C - 5 (AC = 5)
D - 11 (BD = 9)
CD is 11-5 = 6.
Ans D
Question: The sum of ages of 5 children born at the intervals of 3 years each is 60 years. What is the age of the youngest child?
A.3 years
B.4 years
C.6 years
D.7 years
Answer: C.6 years
Explanation: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 60
5x = 30
x = 6.
Age of the youngest child = x = 6 years.
C)
Question: If 20% of a number, then 120% of that number will be?
A.20
B.120
C.360
D.720
Answer: D.720
Explanation: Let the number x. Then,
20% of x = 120
x = (120 * 100)/20 = 600
120% of x = (120/100 * 600) = 720.
ANSWER:D
Question: Income and expenditure of a person are in the ratio 5 : 3. If the income of the person is Rs. 10000, then find his savings?
A.Rs.4000
B.Rs.3603
C.Rs.3639
D.Rs.3632
Answer: A.Rs.4000
Explanation: Let the income and the expenditure of the person be Rs. 5x and Rs. 3x respectively.
Income, 5x = 10000 => x = 2000
Savings = Income - expenditure = 5x - 3x =2x
So, savings = Rs.2*2000 = Rs. 4000
Answer:A
Question: Sanjay invested an amount of ` 16,000 for two years on compound interest and received an amount of ` 17,640 on maturity. What is the rate of interest per annum?
A.4%
B.5%
C.8%
D.9%
Answer: B.5%
Explanation: The extra money for two years is 1,640. This can be broken up as 800 + (800 + 40). Since 40 = 5% of 800 and 800 = 5% of 16000
So, r = 5%.
Answer: B
Question: A shipping clerk has five boxes of different but unknown weights each weighing less than 100 kg. The clerk weighs the boxes in pairs. The weights obtained are 110, 112, 113, 114, 115, 116, 117, 118, 120 and 121 kg. What is the weight, in kg, of the heaviest box ?
A.60
B.61
C.64
D.Can't be determined
Answer: B.61
Explanation: Explanation :
Two boxes are selected at at time and weighed together. Thus, the selection order does not matter and selecting box 1 and then box 2 is the same as selecting box 2 and then box 1. So this is a combination problem.
2 boxes can be selected from 5 boxes in 5C2 ways, i.e. 10 ways. The given list of weighings is 10 in number. So we can assume that all the possible combinations of boxes have been weighed. Lets assume that all boxes are lined as per increasing weights and named as b1, b2, b3, b4, b5. From the given list (Arranges in increasing order of weights) ,
what we have is b1 + b2 = 110, as b1 is the lightest and b2 is the next lightest box heavier than b1. So the sum of these two should be the minimum value in the list.
The second lightest sum of weights, the second value in the list, will be the sum of the b1 + b3 = 112.
Similarly, the maximum value in the list should be the sum of weights of b4 and b5, giving b4 + b5 = 121.
The second last heaviest will be b3 + b5 = 120.
Adding the 4 equations, we get, 2 b1 + 2 b3 + 2 b5 + b2 + b4 = 463 - Equation 1.
Sum of all the weights in the given list is 1160. This sum is the sum of each of the cases b1+b2, b1+b3, b1+b4, b1+b5, b2+b3, b2+b4, b2+b5, b3+b4, b3+b5, b4+b5. Thus sum of all this will be 4(b1 + b2 + b3 + b4 + b5) = 1160. Thus, b1 + b2 + b3 + b4 + b5 = 290 - Equation 2.
Subtracting equation 2 from equation 1, we get, b1 + b3 + b5 = 173.
We know that b1 + b3 = 112, So b5 = 173 - 112 = 61 = Desired answer.
Answer : B
Question: Tina’s cat weighs 3.2 kilograms. Her dog weighs 4 times as much as her cat. How much does her dog weigh in kilograms?
A.A)10.4kg
B.B)38kg
C.C)12.8kg
D.D)48kg
Answer: C.C)12.8kg
Explanation: 3.2*4=12.8kg.Answer is C.
Question: Anintegratedteam consists of 2 members from the engineering team and 2 members from the design team. If the engineering team has 6 members and the design team has 3 members, how manyintegratedteam formations are possible?
A. 36
B. 45
C. 76
D. 90
Answer: B. 45
Explanation: 2 out of 6 times 2 out of 3 => 6*5/2*1 * 3*2/2*1 = 45
B
Question: Which of the following values of x satisfies the inequality 2x2 – 3x + 1 > 0?
A.-1 < x < -1⁄2
B.1⁄2 < x < 1
C.x > 1 or x < 1⁄2
D.-1⁄2 < x < 1
Answer: C.x > 1 or x < 1⁄2
Explanation: 2x2 – 3x + 1 = 0.
or (2x – 1)(x – 1) = 0
Hence, α = 1⁄2 and β = 1
Now, the given inequality is 2x2 – 3x + 1 > 0,
Hence, sign scheme will be as follows:
--------|---------------------|----------------
+ve 1⁄2 –ve 1 +ve
∴ x > 1 or x < 1⁄2
[Note:If the inequality were 2x2 – 3x + 1 < 0; the answer will be 1⁄2 < x < 1]
Answer C
Question: There are 4 more women than men on Centerville's board of education. If there are 8 members on the board, how many are women?
A. 3
B. 4
C. 6
D. 7
Answer: C. 6
Explanation: Given: M=W-4 so, W+(W-4)=8 --> W=6.
Answer: C.
Question: 96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part?
A.66
B.77
C.42
D.88
Answer: C.42
Explanation: x/7 = y/9 => x:y = 7:9
7/16 * 96 = 42.Answer: C
Question: Two men start together to walk a certain distance, one at 4 kmph and another at 3 kmph.The former arrives half an hour before the latter. Find the distance.
A.6 km
B.7 km
C.8 km
D.9 km
Answer: A.6 km
Explanation: Let the distance be x km. Then,
x/3 - x/4 =1/2
(4x - 3x)/12 = 1/2
x = 6 km
ANSWER:A
Question: Find compound interest on Rs. 8000 at 15% per annum for 2 years 4 months, compounded annually
A.3109
B.3115
C.3250
D.3500
Answer: A.3109
Explanation: Time = 2 yrs 4 mos = 2(4/12) yrs = 2(1/3) yrs.
Amount = Rs. [8000 X (1+(15/100))^2 X (1+((1/3)*15)/100)]
= Rs. 11109.
:. C.I. = Rs. (11109 - 8000) = Rs. 3109.
ANSWER A
Question: Given that there are 11 cricket players per team, how many ways can you select 10 cricket players from 2 teams if no more than 1 players can be selected from each team?
A.150
B.200
C.121
D.140
Answer: C.121
Explanation: Now from each group we have to select 5 persons only: 11C1 * 11C1= 11 * 11 = 121
Total ways=313444 ways.
Answer C
Question: The average amount with a group of seven numbers is Rs. 30. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?
A.Rs. 25.6
B.Rs. 26.6
C.Rs. 16.6
D.Rs. 26
Answer: B.Rs. 26.6
Explanation: Total members in the group = 7
Average amount = Rs. 30
Total amount with them = 7 * 30 = Rs. 210
One number has Rs. 50. So, the amount with remaining 6 people = 210 - 50 = Rs. 160
The average amount with them = 160/6 = Rs. 26.6
ANSWER:B
Question: Which of the following is closest to 1/5+1/55+1/555
A.1/4.54
B.1/3.5
C.1/2.5
D.1/3.6
Answer: A.1/4.54
Explanation: 1/5+1/55+1/555=0.2+0.018+0.0018=0.2198=1/4.54
Answer is A
Question: Find the ones digit of 73^330
A.3
B.5
C.6
D.7
Answer: B.5
Explanation: Cyclicity of 3 is 3,9,7,1after 4 multiplication again the cycle repeats.
So divide 330 by 4 and we get 87 as quotient and 2 as remainder. So cycle will run for 87 times and then 2 times more. So pick up the 2nd item from the cycle.
Hence Answer B.
Question: I came across this problem in the GMATprep software and got it totally wrong!
A company consists of 6 senior and 4 junior staff officers. If a committee is created with 4 senior and 1 junior staff officers, how many possible committees are there?
A.12
B.44
C.56
D.60
Answer: D.60
Explanation: 6C4*4C1
=60=D
Question: A worker earns $20 on the first day and spends $15 on the second day. The worker earns $20 on the third day and spends $15 on the fourth day. If this pattern continues, on which day will the worker first reach a net total of $80?
A.24
B.25
C.27
D.30
Answer: B.25
Explanation: Every two days, the net total is $5.
After 24 days, the worker will have $60.
On day 25, the worker will receive $20 for a net total of $80.
The answer is B.
Question: Three pipes, A, B, & C are attached to a tank. A & B can fill it in 20 & 30 minutes respectively while C can empty it in 20 minutes. If A, B & C are kept open successively for 1 minute each, how soon will the tank be filled?
A.2 hours
B.4 hours
C.1 hour 30 min
D.5 hours
Answer: C.1 hour 30 min
Explanation: in three minute 1/20+1/30-1/20=2/60 = 1/30 part is filled
3 min--------1/30 parts
x min--------- 1 part(full)
x=90 min =1 hour 30 min
ANSWER:C
Question: In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case?
A.273
B.528
C.539
D.538
Answer: B.528
Explanation: Assume X soldiers join the fort. 1200 soldiers have provision for 1200(days for which provisions last them)(rate of consumption of each soldier)
= 1200(30)(3) kg
Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) kg
As the same provisions are available
=> 1200(30)(3) = (1200 + x)(25)(2.5)
x = [1200(30)(3)]/[(25)(2.5)] - 1200
x = 528
Answer: Option B
Question: Total of ages of A,B and C at present is 90 years. If ratio of this ages is 2 : 3 : 4 what will be the age of C after 2 years?
A.45 years
B.42 years
C.40 years
D.37 years
Answer: B.42 years
Explanation: 2+3+4=9
4*(90/9)=40yrs
after 2yrs=42
ANSWER:B
Question: If $30,000 interest is invested in 10 percent simple annual interest for 2 years, which of the following represents the total amount of interest, in dollars, that will be earned by this investment in the 2 years?
A.$6000
B.$4000
C.$5000
D.$3000
Answer: A.$6000
Explanation: 30000*10/100*2 = $6000
Answer : A
Question: Teas worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs 156 per Kg , the price of the third variety per Kg will be?
A.Rs. 147.50
B.Rs. 785.50
C.Rs. 178.50
D.Rs. 258.50
Answer: C.Rs. 178.50
Explanation: Explanation :
Since first and second varieties are mixed in equal proportions.
So, their average price =Rs. (126+135)/2.
=>Rs. 130.50.
So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. x per kg in the ratio 2 : 2, i.e., 1 : 1.
We have to find x.
By the rule of alligation, we have:
Cost of 1 kg Cost of 1 kg
of 1st kind of 2nd kind
(Rs. 130.50) (Rs. x)
\ /
Mean Price
(Rs. 156)
/ \
xâˆ’156 22.50
=>xâˆ’(156/22.50)=1.
=>xâˆ’156=22.50.
=>x= 178.50 Rs.
Answer : C
Question: What is the % change in the area of a rectangle when its length increases by 35% and its width decreases by 35%?
A.0%
B.20% increase
C.20% decrease
D.12% decrease
Answer: D.12% decrease
Explanation: (135/10)*(65/10) = 8775/100~88 of original area
0.88 is a 12% decrease from 100/100 ->D
Question: A jar contains 7 marbles consisting of an equal number of red, green, and blue marbles. Three marbles are removed from the jar and discarded. What is the probability that only two colors will remain in the jar after the Three marbles have been removed?
A.1/45
B.3/35
C.1/81
D.1/35
Answer: B.3/35
Explanation: Jar contains {4-red, 4-green, 4-blue} marbles. We are asked to find the probability that after removing 3 marbles only 2 colours remain in the jar, i.e., the probability of removing EITHER red, OR green, OR blue.
Sample space = 7C3 = 35.
Probability of choosing 3 red = 3C3/7C3 = 1/35.
Probability of choosing 3 green = 3C3/7C3 = 1/35.
Probability of choosing 3 blue = 3C3/7C3 = 1/35.
Required probability = 1+1+1/495 = 3/35 Ans (B).
Question: In your bucket you have 6.35 $, and you want to travel to the next state by train and its ticket costs 1.35 $. How many times can you use this train between the two stations?
Suppose that the cost of ticket is the same in both ways!
A.4
B.5
C.6
D.7
Answer: A.4
Explanation: As the ticket costs 1.35 $ for one way, so the two-way trip costs 2.7$, and the two tow-way trips cost 5.4$.
So if you have 6.35$, you are able to go and return just two times according to your money in your bucket.
So the correct choice is A
Question: a wall clock rings after every 1 hr and a wrist watch beep after every 25 min.they voice together at 12 a.m,time taken to voice again simultaneously?
A.4 a.m
B.5 a.m
C.6 a.m
D.7 a.m
Answer: B.5 a.m
Explanation: 1 hr = 60 minutes
So, L.C.M. of 60 and 25 is = 300
300 minutes = 5 hr
So after 5 hr that is at 5 a.m both will voice again simultaneously.
ANSWER:B
Question: For integers U and V, when U is divided by V, the remainder is even. Which of the following must be true?
A.U is odd
B.At least one of U and V is odd
C.The sum U + V is odd
D.U and V share no common factors other than 1
Answer: B.At least one of U and V is odd
Explanation: At least one of U and V is odd
B
Question: Lisa's grade was 75th percentile of the 40 grades for her class. Of the 50 grades from another class, 8 were higher than Lisa's, and the rest were lower. If no other grade was the same as Lisa's grade, then Lisa's grade was what percentile of the grades of the two classes of two classes combined?
A.62nd
B.74th
C.80th
D.87th
Answer: C.80th
Explanation: 62nd/74th/80th/87th/92nd
Correct option: C
Question: The sum of the squares of three numbers is 225, while the sum of their products taken two at a time is 200. Their sum is:
A.10
B.30
C.40
D.25
Answer: D.25
Explanation: x^+y^2+z^2=225
xy+yz+zx=200
as we know.. (x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx)
so (x+y+z)^2=225+(2*200)
(x+y+z)^2=625
so x+y+z=25
ANSWER:D
Question: In a shop, the marked price of an article is worked out in such a way that it generates a profit of 33133313. What should be the discount percent allowed on the marked price during a sale, so that the final profit made is 20%?
A.13 1/3
B.12 1/2
C.10%
D.8 1/2
Answer: C.10%
Explanation: soln:-
lets consider the cost price of an article as $60 (take a number whose 33.33% can be calculated easily)
so marked price = 1.3333*60 = 80
profit to be earned = 20%
final selling price = 1.2*60 = 72
therefore discount to be given = 8/80 = 10%
answer - C
Question: If x^2 +2x = 15, then one possible value of x – 4 =
A.-8
B.-5
C.-3
D.-1
Answer: D.-1
Explanation: x^2 +2x = 15
i.e. x^2 +2x - 15 = 0
i.e. x^2 +5x -3x - 15 = 0
i.e. (x+5)(x-3) = 0
i.e. x =-5 or 3
i.e. x-4 = -5-4 or 3-4
i.e. x-4 = - 9 or -1
Answer: Option D
Question: A sum of Rs.1460 is divided into 14 students so that each boy gets Rs.120 while each girl gets Rs.100. Find the number of boys and number of girls
A.8B, 5G
B.5B, 8G
C.3B, 9G
D.9B, 4G
Answer: C.3B, 9G
Explanation: 120B+100G=1460-----i
B+G=12-------ii
from i
100B+20B+100G=1460
100(B+G)+20B=1460
100(14)+20B=1460
By simplifing we get
B=3;G=9
ANSWER:C
Question: The probability of Sam passing the exam is 1/4. The probability of Sam passing the exam and Michael passing the driving test is 1/6. What is the probability of Michael passing his driving test?
A.1/24
B.1/2
C.1/3
D.2/3
Answer: D.2/3
Explanation: let p(s) and p(m) denote probability of sam passing the exam and michael passing the driving test respectively
as per the question
p(s)=1/4 and
p(s) * p(m)=1/6
therefore,
p(m)=(1/6)*4=2/3
Answer:D
Question: The average age of a husband and his wife was 23 years at the time of their marriage. After five years they have a one year old child. The average age of the family now is
A.19 years
B.23 years
C.28.5 years
D.29.3 years
Answer: A.19 years
Explanation: Solution
Sum of the present ages on husband, wife and child	=(23x2+5x2)+1
= 57 years
Required average
= (57/3)
= 19 years.
Answer A
Question: If 6 men can reap 60 acres of land in 10 days, how many acres of land can 12 men reap in 20 days?
A.120
B.360
C.240
D.182
Answer: C.240
Explanation: 6 men 60 acres 10 days
12 men ? 20 days
60 * 12/6 * 20/10
60 * 2* 2
60 * 4 = 240
Answer:C