RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Two persons A and B take a field on rent. A puts on it 21 horses for 3 months and 15 cows for 2 months; B puts 15 cows for 6months and 40 sheep for 7 1/2 months. If one day, 3 horses eat as much as 5 cows and 6 cows as much as 10 sheep, what part of the rent should A pay?
A.1/3
B.1/8
C.1/4
D.1/1
Answer: A.1/3
Explanation: 3h = 5c
6c = 10s
A = 21h*3 + 15c*2
= 63h + 30c
= 105c + 30c = 135c
B = 15c*6 + 40s*7 1/2
= 90c + 300s
= 90c + 180c = 270c
A:B = 135:270
27:52
A = 27/79 = 1/3
Answer: A
Question: In the coordinate plane, a circle centered on point (-3, -4) passes through point (-1, 1). What is the area of the circle?
A.9π
B.18π
C.29π
D.37π
Answer: C.29π
Explanation: r^2=(-3+1)^2+(-4-1)^2=4+25=29
Area of circle=πr^2=29π
Answer : C
Question: The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?
A.18%
B.17%
C.15%
D.11%
Answer: A.18%
Explanation: 1500 ---- 270
100 ---- ? => 18%
Answer: A
Question: If 6 (A's capital) = 8 (B's capital) = 10 (C's capital). Then the ratio of their capitals is?
A.20:15:16
B.20:15:15
C.20:15:12
D.20:15:14
Answer: C.20:15:12
Explanation: 6A = 8B = 10 C
A:B:C = 1/6:1/8:1/10
= 20:15:12
Answer: C
Question: Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 2 : 3?
A.50 kmph
B.60 kmph
C.40 kmph
D.70 kmph
Answer: A.50 kmph
Explanation: A
Let the distances between city A to B and B to C be 2x km and 3x km respectively.
Total time taken to cover from A to C
= (2x)/40 + (3x)/60 = (6x + 6x)/120 = 12x/120 = x/10 Average speed = (2x + 3x)/(x/10) = 50 kmph.
Question: There is a circle of radius 2. What is the perimeter of the biggest rectangle that can be cut out of this circle?
A.4âˆš8
B.4âˆš5
C.2âˆš6
D.16
Answer: A.4âˆš8
Explanation: The largest rectangle to be cut out of a circle would be a square, with a diagonal of 4 (Radius*2 2*2=4)
Using the Pythagorean theorem a^2+b^2=c^2; in a square this is 2a^2 because this is a right triangle/half of a square, so 2a^2=4^2
2a^2=16
a^2=8
a=âˆš8
Area of a square = side * 4 so perimeter= 4âˆš8
Answer is A
Question: Yearly subscription to professional magazines cost a company $940.00. To Make a 20% cut in the magazine budget, how much less must be spent?
A.654
B.752
C.656
D.657
Answer: B.752
Explanation: total cost 940
940*20/100=188
so the cut in amount is 188
the less amount to be spend is 940-188=752
ANSWER:B
Question: 24 * 22 = ? / 8
A.4224
B.2224
C.5374
D.2434
Answer: A.4224
Explanation: A
4224
?/8 = 24*22
? = 24 * 22 * 8
? = 4224
Question: The speed of a train is 90 kmph. What is the distance covered by it in 15 minutes?
A.15
B.66
C.22.5
D.52
Answer: C.22.5
Explanation: 90 * 15/60 = 22.5 kmph
Answer:C
Question: A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.08. For each additional day that the book is overdue, the total fine is either increased by $0.30 or doubled, whichever results in the lesser amount. What is the total for a book on the fourth day it is overdue?
A.$0.62
B.$0.70
C.$0.80
D.$0.90
Answer: A.$0.62
Explanation: 1st day fine - 0.08
2nd day fine - 0.08*2 = 0.16 (as doubling gives lower value)
3rd day fine - 0.16*2 = 0.32 (as doubling gives lower value)
4th day fine - 0.32 + 0.3 = 0.62 (as doubling gives higher value we add 0.3 this time)
Answer: A.
Question: A sock drawer contains 4 socks, each one a different solid color. The colors of the socks are green, blue, indigo, and violet. If a person reaches into the drawer and pulls out two socks, how many different color combinations are possible in the selected pair of socks?
A.12
B.15
C.6
D.36
Answer: C.6
Explanation: Since the order in which we select the socks does not matter we can use combinations.
We can select 2 socks from 4 socks in 4C2 ways.
4C2 = 6
Answer : C
Question: The marks obtained by Polly and Sandy are in the ratio 5:6 and those obtained by Sandy and Willy are in the ratio of 9:7. The marks obtained by Polly and Willy are in the ratio of...?
A.9:8
B.11:10
C.13:12
D.15:14
Answer: D.15:14
Explanation: Polly : Sandy = 5:6 = 15:18
Sandy : Willy = 9:7 = 18:14
Polly : Sandy : Willy = 15:18:14
Polly : Willy = 15:14
The answer is D.
Question: If a man lost 4% by selling oranges at the rate of 12 a rupee at how many a rupee must he sell them to gain 44%?
A.5
B.8
C.9
D.5
Answer: B.8
Explanation: 96% ---- 12
144% ---- ?
96/144 * 12 = 8
Answer: B
Question: During the first week of performances of a certain play, 5,400 tickets were sold, all at reduced price. During the remaining weeks of performances, 5 times as many tickets were sold at full price as were sold at reduced price. If the total number of tickets sold W was 25,200, how many of them were sold at full price?
A.21,000
B.19,800
C.16,500
D.15,800
Answer: C.16,500
Explanation: Given:
The question tells us about the number of tickets sold in the first week at reduced price = 5,400. It also tells us that during the remaining weeks, the number of tickets sold at full price was 5 times the no. of tickets sold at reduced price. The total tickets sold was 25,200, and we are asked to find the number of tickets that where sold at full price.
Approach:
The question asks us to find the number of ticket sold at full price. We know that the number of tickets sold at full price was 5 times the no. of tickets sold at reduced price in remaining weeks. Hence, assuming tickets sold at reduced price in remaining weeks to be x would give us the no. of tickets sold at full price to be 5x.
Tickets sold in first week + Tickets sold in remaining weeks = Total no. of tickets soldi.e.
Tickets sold in first week + Tickets sold at full price in remaining weeks + Tickets sold at reduced price in remaining weeks = Total no. of tickets sold
We know the no. of tickets sold during first week and the total no. of tickets sold. We will use this relation to get to our answer.
Working Out:
Tickets sold in first week + Tickets sold at full price in remaining weeks + Tickets sold at reduced price in remaining weeks = Total no. of tickets sold
Substituting values in the equation, we get
5,400 + 5x + x = 25,200
x= 3,300
Tickets sold at full price = 5x = 16,500
Answer: Option C
Question: In how many ways can 3 postcards can be posted in 5 postcards?
A.50
B.120
C.125
D.130
Answer: C.125
Explanation: First card can go into any of the five boxes, Second can go into any of the five boxes.
Third card also can go into any of the five boxes
Number of ways=5*5*5=125 ways
Answer:C
Question: Find a sum for 1st 5 prime no.'s?
A.23
B.28
C.30
D.32
Answer: B.28
Explanation: Required sum = (2 + 3 + 5 + 7 + 11) = 28
Note: 1 is not a prime number
Option B
Question: What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58?
A.3944
B.2882
C.2999
D.2667
Answer: A.3944
Explanation: Let the side of the square plot be a ft.
a2 = 289 => a = 17
Length of the fence = Perimeter of the plot = 4a = 68 ft.
Cost of building the fence = 68 * 58 = Rs. 3944.
Answer: A
Question: If 9975 kg of wheat is packed in 95 bags, how much wheat will each bag contain?
A.105
B.109
C.119
D.218
Answer: A.105
Explanation: Solution:
Since 95 bags contain wheat 9975 kg
Therefore, 1 bag contains wheat (9975 ÷ 95) kg
= 105 kg
ANSWER IS A
Question: An assembly line produces 30 cogs per hour until an initial order of 60 cogs is completed. The speed of the assembly line is then immediately increased so that it can produce 60 cogs per hour until another 60 cogs are produced. What is the overall average output, in cogs per hour, for the assembly line during this whole time?
A.40
B.44
C.48
D.52
Answer: A.40
Explanation: The time to produce the first 60 cogs is 60/30 = 2 hours.
The time to produce the next 60 cogs is 60/60 = 1 hour.
The average output is 120 cogs / 3 hours = 40 cogs per hour.
The answer is A.
Question: x is a set containing 8 different positive odd numbers. y is a set containing 7 different numbers, all of which are members of S. Which of the following statements CANNOT be true?
A.The range of y is even.
B.The mean of x is even.
C.The mean of y is even.
D.The range of x is equal to the range of y.
Answer: C.The mean of y is even.
Explanation: Given: x is a set containing 8 different positive odd numbers
Easily inferred: y is a set containing 7 differentoddnumbers
(A) The range of y is even. - Always even, since it is a difference of two odd numbers
(B) The mean of x is even. - can be. suppose 8 numbers consist of 4 pairs of (16n-1,16n+1) for different values of n. Adding these will give a multiple of 16, which when divided by 8 (to arrive at mean), will give an even number
(C) The mean of y is even. - Cannot be. Mean = (sum of 7 odd numbers)/7 = Odd number/odd number thus cannot be even.
(D) The range of x is equal to the range of y.
(E) The median of y is equal to the mean of y
Option C
Question: The H.C.F and L.C.M of two numbers are 84 and 21 respectively. If the ratio of the two numbers is 1 : 4 , then the larger of the two numbers is
A.32
B.37
C.84
D.29
Answer: C.84
Explanation: Explanation:
Let the numbers be x and 4x. Then, \inline \fn_jvn x\times 4x =84\times 21\: \: \Leftrightarrow \: \: x^{2}=\frac{84\times 21}{4} \: \: \Leftrightarrow \: \: x=21
Hence Larger Number = 4x = 84
Answer: C) 84
Question: A horse is tethered to one corner of a rectangular grassy field 36 m by 20 m with a rope 18 m long. Over how much area of the field can it graze?
A.154 cm2
B.308 m2
C.254 m2
D.260 m2
Answer: C.254 m2
Explanation: Area of the shaded portion
= 1⁄4 × π × (18)2 = 254 m2
Answer C
Question: Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 5 to 2 and the ratio of Indian to British stamps is 5 to 1, what is the ratio of US to British stamps?
A.10 : 5
B.15 : 2
C.20 : 2
D.25 : 2
Answer: D.25 : 2
Explanation: Explanation:
Indian stamps are common to both ratios. Multiply both ratios by factors such that the Indian stamps are represented by the same number.
US : Indian = 5 : 2, and Indian : British = 5 : 1. Multiply the first by 5, and the second by 2.
Hence the two ratios can be combined and US : British = 25 : 2
Now US : Indian = 25 : 10, and Indian : British = 10 : 2 Answer: D
Question: The average of six numbers is 3.95. The average of two of them is 3.3, while the average of the other two is 3.85. What is the average of the remaining two numbers?
A.4.5
B.4.6
C.4.7
D.4.8
Answer: C.4.7
Explanation: Sum of the remaining two numbers
= (3.95 × 6) – [(3.3 × 2) + (3.85 × 2)]
= 23.70 – (6.6 + 7.7)
= 23.70 – 14.3 = 9.40
∴ Required average = (9.4⁄2) = 4.7
Answer C
Question: For the positive numbers, n+3, n + 4, n + 6, n + 8, and n + 9, the mean is how much greater than the median?
A.0
B.1
C.n+l
D.n+2
Answer: A.0
Explanation: Let’s first calculate the mean (arithmetic average).
mean = sum/quantity
mean = (n + 3+n + 4 + n + 6 + n + 8 + n + 9)/5
mean = (5n + 30)/5
mean = n + 6
Next, we determine the median. The median is the middle value when the terms are ordered from least to greatest. The terms ordered from least to greatest are as follows:
n+3, n + 4, n + 6, n +8, n + 9
The median is n + 6
Finally we are asked how much greater the mean is than the median. To determine the difference we can subtract the smaller value (the median) from the larger value (the mean) and we get:
n + 6 – (n + 6) = n + 6 – n – 6 = 0
The answer is A
Question: The average of first six prime numbers which are odd is?
A.15.5
B.15.7
C.9.3
D.15.8
Answer: C.9.3
Explanation: Sum of first 6 prime no. which are odd = 56
Average = 56/6 = 9.3
Answer:C
Question: Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
A.12
B.13
C.16
D.10
Answer: D.10
Explanation: Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
Therefore 20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Answer: D
Question: A can do a piece of work in 4 days. B can do it in 5 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?
A.23 days
B.18 days
C.20 days
D.22 days
Answer: C.20 days
Explanation: C
20 days
C = 1/2 - 1/4 - 1/5 = 1/20 => 20 days
Question: A certain fruit stand sold apples for $0.70 each and bananas for $0.60 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase?
A.8
B.9
C.10
D.11
Answer: C.10
Explanation: Let's start with 1 apple for $0.70.
Let's subtract $0.70 from $6.30 until we get a multiple of $0.60.
$6.30, $5.60, $4.90, $4.20 = 7*$0.60
The customer purchased 7 bananas and 3 apples.
The answer is C.
Question: Sagar purchased 10 kg of rice at the rate of Rs. 15 per kg and 25 kg of rice at the rate Rs. 14 per kg. He mixed the two and sold the mixture. Approximately at what rate per kg should he sell the mixture to make 40 % profit in the transaction?
A.Rs. 20.00
B.Rs. 19.50
C.Rs. 15
D.Rs. 17.5
Answer: A.Rs. 20.00
Explanation: By 40% profit on cost price,
Selling price of mixture = 140/100 * 500
= Rs. 700
Therefore, selling price per kg of mixture = 700/35 = Rs. 20
ANSWER A
Question: The sum of two numbers is 16. The difference is 4. What are the two numbers?Let x be the first number. Ley y be the second number
x + y = 16
x - y = 4
A.10 and 6
B.10 and 5
C.10 and 4
D.10 and 3
Answer: A.10 and 6
Explanation: Solution
Let x be the first number. Ley y be the second number
x + y = 16
x - y = 4
Solve the system of equations by elimination
Adding the left sides and the right sides gives:
x + x + y + -y = 16 + 4
2x = 20
x = 10
Since x + y = 16, 10 + y = 16
10 + y = 16
10 - 10 + y = 16 - 10
y = 6
The numbers are 10 and 6
Answer A
Question: There are 28 balls which are red, blue or green. If 12 balls are green and the sum of red balls and green balls is less than 24, at most how many red balls are there?
A.10
B.12
C.11
D.13
Answer: C.11
Explanation: r+g+b=28
g=12
r + g < 24
=> r + 12 < 24
=> r < 12
=> at most 11 red balls
ANSWER:C
Question: At a certain restaurant, 30 percent of the servers reported their tips, while 40 percent of the servers who were tipped didn't report their tips. What percent of the servers were tipped?
A.30%
B.60%
C.50%
D.70%
Answer: C.50%
Explanation: Statement: 30% of Servers (S) Reported their Tips (RT). Of the servers who were tipped (T) 40% didn't report their tips (notRT). [Note: A Venn Diagram is useful to visualize the problem.]
Solution: Sample space is 100%.
S = 100%
RT/S = 30%
notRT/T = 40% => 100% - 40% => RT/T = 60%
T/S = (30)/(60)% = 50%
Answer: C
Question: The value of a machine depreciates at the rate of 10% per year. If its present is Rs.1,62,000 what will be its worth after 2 years ? What was the value of the machine 2 years ago ?
A.50000
B.100000
C.150000
D.200000
Answer: D.200000
Explanation: Value of the machine after 2 years
=Rs.[162000*(1-(10/100))^2] = Rs.[162000*(9/10)*(9/10)]
=Rs. 131220
Value of the machine 2 years ago
= Rs.[162000/(1-(10/100)^2)]=Rs.[162000*(10/9)*(10/9)]=Rs.200000
Answer is D.
Question: In the first 10 overs of a cricket game, the run rate was only 4.6. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
A.4.25
B.5.9
C.6.25
D.7
Answer: B.5.9
Explanation: Required run rate = 282 - (4.6x 10) =	236 236/40= 5.9
B)
Question: A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 98.01, the number of the member is the group is:
A.57
B.67
C.77
D.99
Answer: D.99
Explanation: Money collected = (98.01 x 100) paise = 9801 paise.
Number of members =Square root of 9801 = 99.
Answer: Option D
Question: A rower can row 5 km/h in still water. When the river is running at 2 km/h, it takes the rower 1 hour to row to Big Rock and back. How many kilometers is it to Big Rock?
A.1.5
B.1.8
C.2.1
D.2.4
Answer: C.2.1
Explanation: Let x be the distance to Big Rock.
time = x/3 + x/7 = 1
x = 21/10 = 2.1 km
The answer is C.
Question: A garrison of 3300 men has provisions for 32 days when supplied at the rate of 850 g per head. At the end of 7 days, a reinforcement arrives, and it is found that the provisions can last for 17 days more when supplied at the rate of 825 g per head. What is the strength of the reinforcement?
A.1700
B.1000
C.3000
D.2700
Answer: A.1700
Explanation: 825*17*x=850*25*3300
=> 5000
strength of reinforcement = (5000-1300)= 1700
final answer 1700.
ANSWER:A
Question: 4, 8, 16, 28, 44, ?
A.64
B.56
C.74
D.57
Answer: A.64
Explanation: The pattern is + 4, + 8, + 12, + 16, +20
Answer : A.
Question: Priya and her father differ in their ages by 31 years. After 8 years. if the sum of their ages will be 69, their present ages are
A.11, 42
B.12, 24
C.15, 42
D.16, 19
Answer: A.11, 42
Explanation: A
11, 42
Let the age of Priya = x years
Then, the age of her father = (x+ 31) years
ATQ,
(x+ 8) + (x+ 31 + 8) = 69
2x+ 47 = 69
2x= 69 – 47 = 22
x= 11
The age of Priya = 11 years
The age of her father = 11 + 31 = 42 years
Question: A reduction of 10% in the price of tea enables a dealer to purchase 25 kg more tea for Rs. 22500. What is the reduced price per kg of tea?
A.Rs. 70
B.Rs. 80
C.Rs. 90
D.Rs. 100
Answer: C.Rs. 90
Explanation: Solution: 1st Method:
Let the original price of tea be Rs. x/kg.
After reduction the price becomes = x -10% of x = 9x/10 per kg.
Now,
(22500/(9x/10))-22500/x = 25
Or, 22500[10/9x- 1/x] = 25
Or, 25*9x = 22500;
Or, x = (22500/2589) = Rs. 100.
Hence, new price = 90 per kg.
Thought process Method:
Let the original price be Rs. 100 per kg, he get tea = 22500/100 = 225 kg.
After reduction the price becomes = 90 per kg, he get tea = 22500/90 = 250 kg.
So, reduction price is Rs. 90 per kg as it enables him to buy 25 kg of more tea.
Answer: Option C
Question: Find (7x + 4y ) / (x-2y) if x/2y = 3/2 ?
A.24
B.25
C.26
D.27
Answer: B.25
Explanation: x/2y=3/2
=>x=6y/2=3y
=>(7x+4y)/(x-2y)=((7*(3y))+4y)/(3y-2y)
=>25y/y=25
ANSWER:B
Question: The rate of spin of a certain gyroscope doubled every 15 seconds from the moment a particular stopwatch started. If after a minute and a half the gyroscope reached a speed of 400 meters per second, what was the speed, in meters per second, when the stopwatch was started?
A.25/2
B.25/4
C.25/8
D.25/16
Answer: B.25/4
Explanation: Let x be the original speed when the stopwatch was started.
In 90 seconds, the speed doubled 6 times.
2^6 * x = 400
x = (2^4 * 25) / 2^6 = 25/4
The answer is B.
Question: A train covers a distance of 15 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
A.m
B.m
C.m
D.m
Answer: C.m
Explanation: Speed = (15/10 * 60) km/hr
= (90 * 5/18) m/sec = 25 m/sec.
Length of the train = 25 * 6
= 150 m.
Answer:C
Question: A man purchases the milk at Rs. x/litre and sells it at Rs. 2x/liter stillhe mixes 2liters waterwith every 6liters of pure milk. What is the profit %?
A.123%
B.134%
C.145%
D.166.66%
Answer: D.166.66%
Explanation: Let the cost price of 1 litre pure milk be Re.1, then
\inline{6litres(milk)→CP=Rs.62litres(water)→CP=Rs.0}{6litres(milk)→CP=Rs.62litres(water)→CP=Rs.0}\rightarrow CP=Rs.6 only
and 8 litre mixture \rightarrow SP \rightarrow 8 x 2 = Rs.16
Profit %= 166.66%
D
Question: In the xy-plane, line k passes through point (3,-2) and intersect perpendicularly with line n that passes through points (0,3) and (3,5). What is the equation of line k?
A.3x+2y-5=0
B.3x+2y+5=0
C.2x-3y-12=0
D.2x+3y=0
Answer: A.3x+2y-5=0
Explanation: If two lines intersect perpendicularly, we get -1 when we multiply two slopes together. The slope of a line n is (5-3)/(3-0)=2/3. Hence, the slope of a line k should be -3/2. Since it crosses (3,-2), if we calculate we get 3x+2y=5. Hence, the correct answer is A.
Question: A can build up a wall in 8 days while B can break it in 3 days. A has worked for 4 days and then B joined to work with A for another 2 days only. In how many days will A alone build up the remaining part of wall?
A.13 1⁄3 days
B.7 1⁄3 days
C.6 1⁄3 days
D.7 days
Answer: B.7 1⁄3 days
Explanation: A’s one day’s work = 1⁄8th work.
B’s one day’s work = 1⁄3rd work.
∴ A’s 4 day’s work = 4 × 1⁄8 = 1⁄2nd work
∴ In next two days, total wall = 1⁄2 + 2(1⁄8) - 2(1⁄3) = 1⁄12th wall
Remaining wall = 1 - 1⁄12 = 11⁄12th
Now, 1⁄8th wall is built up by A in one day.
∴ 11⁄12th wall is built up by A in 8 × 11⁄12 = 71⁄3 days.
Answer B
Question: The probability that A speaks truth is 7/9 and that of B speaking truth is 9/13. What is the probability that they agree in stating the same fact?
A.18/35
B.111/117
C.157/195
D.192/235
Answer: B.111/117
Explanation: If both agree stating the same fact, either both of them speak truth of both speak false.
Probability = 7/9 * 9/13 + 6/9 * 8/13
= 63/117 + 48/117 = 111/117
ANSWER:B
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
A.60
B.50
C.48
D.76
Answer: C.48
Explanation: Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 6/125 = 48 sec.
Answer: Option C
Question: Scott's average (arithmetic mean) golf score on his first four rounds was 58.What score does he need on his fifth round to drop his average score by 2 points?
A.48
B.72
C.78
D.88
Answer: A.48
Explanation: Average score for first 4 rounds = 58
Average score after 5 rounds = 56
Score Scott needs on his 5th round to drop average score by 2 points = 58 - (2*5) = 48
Answer A
Question: In what ratio must rice at Rs.7.10 be mixed with rice at Rs.9.20 so that the mixture may be worth
Rs.8 per Kg?
A.5 : 4
B.2 : 1
C.3 : 2
D.4 : 3
Answer: D.4 : 3
Explanation: Explanation :
By the rule of alligation, we have
CP of 1 kg Rice of 1st kind CP of 1 kg Rice of 2nd kind
7.1 9.2
Mean Price
8
9.2 - 8 = 1.2 8 - 7.1 = .9
Required ratio = 1.2 : .9 = 12 : 9 = 4 : 3
Answer : Option D
Question: A man buys Rs. 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:
A.12
B.13
C.14
D.15
Answer: D.15
Explanation: Dividend on Rs 20 = 9/100*20 = 9/5
is 12 income 100
9/5 is an income on Rs (100/12*9/5) = Rs 15
ANSWER D
Question: Taps A and B can fill a bucket in 10 minutes and 15 minutes respectively. If both are opened and A is closed after 3 minutes, how much further time would it take for B to fill the bucket?
A.7 min. 30 sec.
B.8min. 20 sec.
C.7min. 25 sec
D.7 min.35 sec.
Answer: A.7 min. 30 sec.
Explanation: Explanation:
Part filled in 3 minutes =
3∗(1/10+1/15)=3∗5/30=5/10
Remaining part =1−5/10=5/10
=>1/15:5/10=1:X
=>X=15/2
=>X=7.5mins.
So it will take further 7 mins 30 seconds to fill the bucket.
OptionA
Question: For what value of â€œkâ€ will the equation (2kx2 + 4kx +2)=0 have equal roots?
A.1
B.9/4
C.16/25
D.7/1
Answer: A.1
Explanation: for a 2nd degree equation ax2+bx_c=0 has equal roots the condition is b2-4ac =0
in the given equation
(4k)^2-4*2k*2=0
by solving this equation
we get k=0, k=1
ANSWER:A
Question: Which of the following numbers should not be included in the set?
331, 482, 551, 263, 386, 242, 111
A.263
B.386
C.242
D.111
Answer: B.386
Explanation: Solution
In each number except 386,the product of first and third digits is the middle one. Answer B
Question: How long does a train 110 m long traveling at 60 kmph takes to cross a bridge of 170 m in length?
A.16.8
B.17.8
C.15.9
D.13.2
Answer: A.16.8
Explanation: D = 110 + 170 = 280 m
S = 60 * 5/18 = 50/3
T = 280 * 3/50 = 16.8 sec
ANSWER A
Question: The average of first 11 prime numbers is?
A.14.55
B.11.11
C.12.11
D.13.11
Answer: A.14.55
Explanation: Sum of 11 prime no. = 160
Average = 160/11 = 14.55
ANSWER: A
Question: On flipping 3 coins together what is the outcomes for at least three TAILl?
A.1/7
B.3/8
C.1/8
D.4/13
Answer: C.1/8
Explanation: Sample space, S = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}
Favorable outcomes for at least two heads
= favorable outcomes for exactly two heads and favorable outcomes for more than two heads
= {TTT}
1/8
C