RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 5766 sq m, the cost of fencing it at 50 ps per meter is?
A.287
B.1287
C.125
D.155
Answer: D.155
Explanation: 3x * 2x = 5766 => x = 31
2(93 + 62) = 310 m
310 * 1/2 = Rs.155
Answer: D
Question: If toaster X costs 10 percent more than toaster Y costs, which of the following COULD be true?
I. Toaster Y costs $10 less than toaster X costs
II. Toaster X costs $20 more than toaster Y costs
III. Toaster Y costs 10 percent less than toaster X costs
A.I only
B.I and II only
C.I and III only
D.II and III only
Answer: B.I and II only
Explanation: 1. In case p=100 , Toaster X = 110
Toaster Y = 100
1 could be true .
2. In case p=200 ,
Toaster X = 220
Toaster Y = 200
2 could be true .
3. Never true .
Toaster Y will be (1/11)x100 percent lesser i.e 9.09 percent
Answer B.
Question: Two trains are running in opposite directions with the same speed. If the length of each train is 420 m and they cross each other in 12 sec, then the speed of each train is?
A.11
B.26
C.126
D.99
Answer: C.126
Explanation: Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (420 + 420)/12 => x = 35
Speed of each train = 10 m/sec.
= 35 * 18/5 =126 km/hr.
Answer: C
Question: Six high school boys gather at the gym for a modified game of basketball involving three teams. Three teams of 2 people each will be created. How many ways are there to create these 3 teams?
A.15
B.30
C.42
D.90
Answer: A.15
Explanation: To put it in a different way:
Say 6 boys are a,b,c,d,e,f and we need to form 3 teams say t1,t2,t3
With a : a,b a,c a,d a,e a,f --->5
With b : b,c b,d b,e b,f --->4
With c : c,d c,e c,f --->3
With d : d,e d,f --->2
With e : e,f --->1
With f : --- --->0
Hence Total is 5+4+3+2+1+0 = 15.
ANSWER:A
Question: A number when divided by a divisor leaves a remainder of 24.
When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor?
A.13
B.59
C.35
D.37
Answer: D.37
Explanation: Let the original number be 'a'
Let the divisor be 'd'
Let the quotient of the division of aa by dd be 'x'
Therefore, we can write the relation as a/d=xa/d=x and the remainder is 24.
i.e., a=dx+24
When twice the original number is divided by d,2a is divided by d.
We know that a=dx+24. Therefore, 2a=2dx+48
The problem states that (2dx+48)/dleaves a remainder of 11.
2dx is perfectly divisible by dd and will therefore, not leave a remainder.
The remainder of 11 was obtained by dividing 48 by d.
When 48 is divided by 37, the remainder that one will obtain is 11.
Hence, the divisor is 37.
Option (D)
Question: The average age of 20 men in the class is 15.6 years. Five new men join and the new average becomes 15.56 years. What was the average age of five new men?
A.15.5
B.15.4
C.15.25
D.15.3
Answer: B.15.4
Explanation: Total age of 20 men = 15.6 x 20 = 312
Now, total age of 25 men = 389.
Total age of five men added later = 389 - 312 = 77.
Hence, the total average of five men = 77/5 = 15.4
ANSWER:B
Question: Tough and Tricky questions: Exponents.
If a and b are positive integers and x = 16^a and y = 9^b, which of the following is a possible units digit of xy?
A.1
B.6
C.5
D.7
Answer: B.6
Explanation: Only Units digit of X and Y contribute to the Units digit of XY.
Finding all values ofXfor positive values ofa
When,
a=1; X=16
a=2; X=256
a=3; X=4096........ Units digit repeat in a cycle of 6,6,6,6......
Similarly, Finding all values ofYfor positive values ofb
When,
b=1; Y=9
b=2; Y= 81
b=3; Y= 729....... Units digit repeat in cycle of 9,1,9,1....
So, possible value of Units digit of XY can be found by considering all possibilities of Units digit of X and Y
When X=6 and Y=9: Units digit of XY = 4
When X=6 and Y=1: Units digit of XY = 6
When X=6 and Y=9: Units digit of XY = 4
When X=6 and Y=1: Units digit of XY = 6
Only two possibilities for Units digit of XY i.e. 4 and 6.
Only 6 is given in answer choices, therefore answer is B
Question: The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
A.101
B.107
C.111
D.185
Answer: C.111
Explanation: Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Answer: Option C
Question: A man takes 3 hours 45 minutes to row a boat 20 km downstream of a river and 2 hours 30 minutes to cover a distance of 3 km upstream. Find the speed of the current.
A.1 km/hr
B.2 km/hr
C.3 km/hr
D.4 km/hr
Answer: B.2 km/hr
Explanation: Explanation:
First of all, we know that
speed of current = 1/2(speed downstream - speed upstream) [important]
So we need to calculate speed downstream and speed upstream first.
Speed = Distance / Time [important]
Speed upstream =(20/3 3/4)km/hr
=16/3km/hr
Speed Downstream = (3/2 1/2)km/hr
=6/5km/hr
So speed of current = 1/2(16/3−6/5)
=2km/hr
Option B
Question: A sells a bicycle to B at a profit of 60% and B sells it to C at a loss of 40%. Find the resultant profit or loss.
A.-4%
B.5%
C.-5%
D.6%
Answer: A.-4%
Explanation: The resultant profit or loss = 60 - 40 - (60*40)/100 = -4%
loss = 4%
Answer is A
Question: For integers a and b, 16a = 32^b. Which of the following correctly expresses a in terms of b?
A.a = 2^b
B.a = 4^b
C.a = 2^(5b − 4)
D.a = 4^(5b − 4)
Answer: C.a = 2^(5b − 4)
Explanation: I tried this one with an example, although I am not quite sure if this is correct. I would appreciate if there would be a common rule for this.
I tried it out with b = 2 and only c correctly expresses the following:
16a = 32^b b = 2
16a = 1024
a = 64
choice c --> a = 2^6 = 64
However, this is a quite time consuming process. Is there something faster?
Answer C
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?
A.3630
B.2979
C.2789
D.2662
Answer: A.3630
Explanation: 6300:4200:10500
3:2:5
3/10 * 12100
= 3630
Answer:A
Question: A man has Rs. 412 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
A.45
B.60
C.77.25
D.90
Answer: C.77.25
Explanation: Let number of notes of each denomination be x.
Then x + 5x + 10x = 412
16x = 412
x = 25.75.
Hence, total number of notes = 3x = 77.25.
Answer = C
Question: The average (arithmetic mean) of 8 numbers is Z, and one of the numbers is 14. If 14 is replaced with 28, then what is the new average (arithmetic mean) in terms of Z?
A.Z + 1/2
B.Z + 7/4
C.Z + 2
D.Z + 4
Answer: B.Z + 7/4
Explanation: (8z−14+28)/8
Or, (8z+14)/8
Or, (4z+7)/4
Or, z+7/4
So, correct answer will be (B) z+7/4
Question: Find the odd man out. 1050, 510, 242, 107, 46, 16, 3
A.107
B.106
C.510
D.1050
Answer: A.107
Explanation: Explanation :
1050
(1050 - 30)/2 = 510
(510 - 26)/2 = 242
(242 - 22)/2 = 110
(110 - 18)/2 = 46
(46- 14)/2 = 16
(16- 10)/2 = 3
Hence, 110 should have come in place of 107. Answer : Option A
Question: A plane flying north at 500 kmph passes over a city at 12 noon. A plane flying east at the same attitude passes over the same city at 12.30 pm. The plane is flying east at 400 kmph. To the nearest hundred km, how far apart are the two planes at 2 pm?
A.600 km
B.1000 km
C.1100 km
D.1200 km
Answer: D.1200 km
Explanation: The plane flying north would have traveled for 2 hours at 2 PM.
It travels at 500 kmph.
Hence, the plane flying north would have covered 1000 kms from the city at 2 PM.
The plane flying east would have traveled for 1.5 hours at 2 PM.
It travels at 400 kmph.
Hence, the plane flying east would have covered 1.5*400 = 600 kms from the city at 2 PM.
The two planes are flying at right angles to each other.
The shortest distance between the two planes is the length of the hypotenuse of the right triangle whose legs are the distances covered by the two planes.
Hence, distance = 1000square + 200 square = 1166 km
The nearest 100 km distance between the two planes = 1200 kms.
Answer D
Question: John started driving on a highway at a constant speed of R miles per hour at 13:00. Then, 2 hours later, Tom started driving on the same highway at a constant speed of 2R miles per hour at 15:00. If both drivers maintained their speed, how many miles had John driven on the highway when Tom caught up with John?
A.2R
B.3R
C.4R
D.5R
Answer: C.4R
Explanation: In 2 hours, John drove 2R miles.
Tom can catch John at a rate of 2R - R = R miles per hour.
The time it takes Tom to catch John is 2R / R = 2 hours.
In 2 hours, John can drive another 2R miles for a total of 4R miles.
The answer is C.
Question: If n=5p where p is a prime number greater than 1, how many different positive even divisors does n have, including n?
A.1
B.2
C.32
D.4
Answer: B.2
Explanation: N = 5P and that P is a prime number greater than 1. Let's TEST P = 2; so N = 10
The question now asks how many DIFFERENT positive EVEN divisors does 10 have, including 10?
10:
1,10
5,2
How many of these divisors are EVEN? 2, 10…..2 even divisors.
ANSWER:B
Question: Before January, the price of a dress was D and the price of a matching pair of shoes was H. In January, the price of the dress increased by 40% and the price of the shoes increased by 50%. In March, Roberta bought both items with a 30% discount. If D = 5H, which of the following represents the amount that Roberta paid?
A.D + 40
B.D + H – 1
C.D + 2H
D.5.95H
Answer: D.5.95H
Explanation: Before Discount price was: 1.4D+1.5H
After Discount: 1.4D +1.5H-.42D-.45H
substitute D=5H
final value: 5.95H
Ans Is D : 5.95H
Question: In march Mrs Bil's earnings were 80 percent of the Bil family's total income. In april Mrs Bil earned 10 percent more than in May. If the rest of the family's income was the same both months, then, in June, Mrs Bil's earnings were approximately what percent of the Bil family's total income ?
A.83
B.56
C.34
D.12
Answer: A.83
Explanation: Lets say the Family Income is 100
In May, lee earned 80Family income is 20
In june, Lee earned 20% more than May, so it is (80+20*80/100 = 96)
Family Income is same 20
In June Lee's Income percent is 96*100/116 ~ 83
Ans is A
Question: A started a business with Rs. 18000. After 4 months B joins with Rs. 24000. After 2 more months C joins with Rs. 30000. At the end of 10 months C received Rs. 1850 as his share. Find the total profit.
A.Rs. 7955
B.Rs. 7030
C.Rs. 8510
D.Rs. 6845
Answer: D.Rs. 6845
Explanation: Explanation:
Ratio of capitals of A, B and C
= (18000 × 10) : (24000 × 6) : (30000 × 4)
= 15 : 12 : 10
Let the total profit be Rs. x.
C's share = Rs. 10x/37
=> 10x/37 = 1850
=> x (1850 × 37)/10 = 6845
Hence, the total profit = Rs. 6845
Answer: Option D
Question: A beggar on the street can make one cigarette out of every 6 cigarette butts he finds. After one whole day of searching and checking public ashtrays the beggar finds a total of 72 cigarette butts. How many cigarettes can he make and smoke from the butts he found?
A.4
B.10
C.14
D.16
Answer: C.14
Explanation: If the begger can make a whole cigarette from 6 butts then he can make 12 cigarettes from the 72 he found. Once he smokes those, he then will have another 12 butts, which gives him enough to make another 2 cigarettes 12+2=14. A total of 14.
Question: What is the dividend. divisor 17, the quotient is 9 and the remainder is 5?
A.130
B.134
C.148
D.158
Answer: D.158
Explanation: D = d * Q + R
D = 17 * 9 + 5
D = 153 + 5
D = 158
Question: Bruce and Anne can clean their house in 4 hours working together at their respective constant rates. If Anne’s speed were doubled, they could clean their house in 3 hours working at their respective rates. How many W hours does it currently take Anne to clean the house on her own?
A.6
B.7
C.8
D.12
Answer: D.12
Explanation: Lets suppose Anne and Bruce take A and B hrs working separately
So in 1 hour they can together finish 1/A + 1/B portion of the work which equals 1/4 (As the work is completed in 4 hours)
After anne doubles her rate of work the portion completed by the both is 1/A +2/B which is W equal to 1/3 (As the work is completed in W=3 hours)
Solving these 2 equations we can find B as 12
So, D
Question: Find (7x + 4y ) / (x-2y) if x/2y = 5/2 ?
A.13
B.25
C.26
D.27
Answer: A.13
Explanation: x/2y=3/2
=>x=10y/2=5y
=>(7x+4y)/(x-2y)=((7*(5y))+4y)/(5y-2y)
=>39y/3y=13
ANSWER:A
Question: If a committee of 3 people is to be selected from among 5 married couples so that the committee does not include two people who are married to each other, how many B such committees are possible?
A.B=20
B.40
C.50
D.B=80
Answer: D.B=80
Explanation: Each couple can send only onerepresentativeto the committee. Let's see in how many ways we can choose 3 couples (as there should be 3 members) each to send onerepresentativeto the committee: 5C3=10.
But these 3 chosen couples can send two persons (either husband or wife): 2*2*2=2^3=8.
Total # of ways: 5C3*2^3=80.
Answer: D.
Question: There are two concentric circles such that the area of the outer circle is four times the area of the inner circle. Let A, B and C be three distinct points on the perimeter of the outer circle such that AB and AC are tangents to the inner circle. If the area of the outer circle is 12 square centimetres then the area (in square centimetres) of the triangle ABC would be
A.π√​12
B.9/π
C.9√3/π square centimetres
D.6√3/π
Answer: C.9√3/π square centimetres
Explanation: Explanation :
Outer circle:
Since πR² = 12, R = √(12/π) = 2√(3/π).
Inner circle:
Since the area is 1/4 the area of the outer circle, πr² = 3 and r = √(3/π).
AO is the Radius of the outer circle and OD is the radius of the inner circle.
A line tangent to a circle and a radius drawn to the point of tangency form a right angle.
Thus, ∆AOD is a right triangle.
Hypotenuse AO is twice the length of leg OD.
A right triangle whose hypotenuse is twice the length of a leg is a 30-60-90 triangle.
Thus, ∆AOD is a 30-60-90 triangle.
In a 30-60-90 triangle, the sides are proportioned x : x√3 : 2x.
Thus, AD = √3 * √(3/π) * = 3/√π.
Using the same reasoning for ∆OCD, we can deduce that CD = 3/√π.
Thus, AC = 2 * 3/√π = 6/√π.
The formula for the area of an equilateral triangle = (s²√3)/4.
Since AC = 6/√π, the area of ∆ABC = (6/√π)² * √3/4 = 36/π * √3/4 = (9√3)/π.
Answer : C
Question: A policeman noticed a criminal from a distance of 180 km. The criminal starts running and the policeman chases him. The criminal and the policeman run at the rate of 8 km and 9 km per hour respectively. What is the distance between them after 5 minutes ?
A.96.7 m
B.120 m
C.130 m
D.150 m
Answer: A.96.7 m
Explanation: Explanation :
Solution: Relative speed = (9 - 8) = 1 km/hr.
Distance covered in 3 minutes = (1 * 5/60) km = 1/12 km = 83.3 m.
.'. Distance between the criminal and policeman = (180 - 83.3) m = 96.7 m.
Answer : A
Question: Raffle tickets numbered consecutively from 101 through 450 are placed in a box. What is the probability that a ticket selected at random will have a number with a hundreds digit of 2 ?
A.2/5
B.2/7
C.10/35
D.99/250
Answer: C.10/35
Explanation: SOLUTION
The number of integers from 101 to 450, inclusive is 250, out of which 100 (from 200 to 299) will have a hundreds digit of 2. Thus the probability is 100/350
Answer: C
Question: Mr. Wayne bungee jumps from the top of a building straight to the ground at a constant speed. 3 seconds after he starts plummeting he passes the 20th floor. 15 seconds after he starts plummeting he passes the 5th floor. Each floor is 3.6 meters high. What is Mr. Wayne's speed in meters per second?
A.3
B.3.75
C.4.5
D.4.25
Answer: C.4.5
Explanation: IMO: C
15 Floors * 3.6 Meter/Floor = 54 Meters
Time= 12 sec
Rate * 12 = 54
Rate= 54/12
=4.5
Answer C
Question: The speed of a boat in still water is 50kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
A.40, 68 kmph
B.40, 30 kmph
C.70, 30 kmph
D.40, 60 kmph
Answer: C.70, 30 kmph
Explanation: Speed downstream = 50 + 20 = 70 kmph
Speed upstream = 50 - 20 = 30 kmph
Answer: C
Question: A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
A.76 kmph
B.6 kmph
C.14 kmph
D.8 kmph
Answer: D.8 kmph
Explanation: Speed downstream = d/t = 85/(2 1/2)
= 34 kmph
Speed upstream = d/t = 45/(2 1/2)
= 18 kmph
The speed of the stream = (34 - 18)/2
= 8 kmph
Answer:D
Question: A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.389 m
B.350 m
C.289 m
D.299 m
Answer: B.350 m
Explanation: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.
Answer:B
Question: A, B and C enter into a partnership. They invest Rs. 40,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. In what ratio will the profit be shared at the end of 3 years ?
A.8:7:4
B.1:3:5
C.3:4:7
D.4:5:9
Answer: C.3:4:7
Explanation: Explanation:
A:B:C =(40000Ã—36) :(80000Ã—12+40000Ã—24) :(120000Ã—24+40000Ã—12)
=144:192:336=144:192:336 =3:4:7.
ANSWER IS C
Question: If a committee of 3 people is to be selected from among 5 married couples so that the committee does not include two people who are married to each other, how many such committees are possible?
A.
B.
C.
D.
E.
A.20
B.40
C.50
D.80
Answer: D.80
Explanation: Each couple can send only one "representative" to the committee. Let's see in how many ways we can choose 3 couples (as there should be 3 members) each to send one "representative" to the committee: 5C3=10.
But these 3 chosen couples can send two persons (either husband or wife): 2*2*2=2^3=8.
Total # of ways: 5C3*2^3=80.
Answer: D.
Question: Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 26 years. What is Deepak present age.
A.14
B.15
C.20
D.22
Answer: B.15
Explanation: Explanation:
Present age is 4x and 3x,
=> 4x + 6 = 26 => x = 5
So Deepak age is = 3(5) = 15
Answer: Option B
Question: The average weight of four boys A, B, C, and D is 75 kg. The fifth boy E is included and the average weight decreases by 4 kg. A is replaced by F. The weight of F is 6 kg more than E. Average weight decreases because of the replacement of A and now the average weight is 72 kg. Find the weight of A.
A.57 kg
B.54 kg
C.56 kg
D.60 kg
Answer: C.56 kg
Explanation: Sum of the weight of A, B, C and D = 75 × 4 = 300 kg
and average weight of A, B, C, D and E = 71 kg
sum of the weight of A, B, C, D and E
= 71 × 5 = 355 kg
weight of E = 355 – 300 = 55 kg
weight of F = 55 + 6 = 61 kg
Now, average weight of F, B, C, D and E = 72 kg
Sum of the weight of F, B, C, D and E = 72 × 5 = 360 kg
B + C + D = 360 – 55 – 61 = 244 kg.
Weight of A = 300 – 244 = 56 kg.
ANSWER:C
Question: A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 60 kmph. When and at what distance from Mumbai do the two trains meet?
A.187
B.279
C.120
D.278
Answer: C.120
Explanation: When the second train leaves Mumbai the first train covers 40 * 1 = 40 km
So, the distance between first train and second train is 40 km at 10.00am
Time taken by the trains to meet
= Distance / relative speed = 40 / (60 -40) = 2 hours
So, the two trains meet at 12 a.m. The two trains meet 2 * 60 = 120 km away from Mumbai.
Answer:C
Question: On a man's tombstone, it is said that one sixth of his life was spent in childhood and one twelfth as a teenager. One seventh of his life passed between the time he became an adult and the time he married; five years later, his son was born. Alas, the son died four years before he did. He lived to be twice as old as his son did. How old did the man live to be?
A.82
B.83
C.84
D.85
Answer: C.84
Explanation: Let the age of man is x so that of son = x/2 (given)
now according to the given condition
(x/6) + (x/12) + (x/7) + 5 + (x/2) + 4 = x
or x = 84
ANSWER:C
Question: If the annual interest on a principal is 16%, how many years before the amount is double?
A.6.25
B.20
C.17.2
D.15.2
Answer: A.6.25
Explanation: P = (P*16*R)/100
R = 6.25
Answer: A
Question: The area of Circle O is added to its diameter. If twice the circumference of Circle O is then subtracted from this total, the result is 8. What is the diameter of Circle O?
A.4/π
B.4
C.8
D.10
Answer: C.8
Explanation: area+diameter-2*circumference=8
pi*r^2+2r=8+2*2pi*r
isolate r and get r(pi*r+2)=8+4pi*r
r=(8+4pi*r)/(pi*r+2) =>4(pi*r+2)/(pi*r+2)
r=4
Diameter = 2r = 8
C
Question: What is the dividend. divisor 18, the quotient is 9 and the remainder is 4
A.A)166
B.B)148
C.C)150
D.D)153
Answer: A.A)166
Explanation: D = d * Q + R
D = 18 * 9 + 4
D = 166
Answer : A
Question: A reduction of 20% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg?
A.30
B.31
C.32
D.33
Answer: C.32
Explanation: 800*(20/100) = 160 ---- 5
? ---- 1 => Rs.32
Answer: C
Question: A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?
A.18
B.19
C.21
D.26
Answer: C.21
Explanation: Suppose the can initially contains 7x and 5x of mixtures A and B respectively.
Quantity of A in mixture left = 7x -	7	x 9 litres = 7x -	21 litres.
12	4
Quantity of B in mixture left = 5x -	5	x 9 litres = 5x -	15 litres.
12	4
7x -	21
4
=	7
5x -	15 + 9
4
9
28x - 21	=	7
20x + 21	9
252x - 189 = 140x + 147
112x = 336
x = 3.
So, the can contained 21 litres of A.
Option C
Question: In a mixture of 45 litres the ratio of milk to water is 4:1. Additional 18 litres of water is added to the mixture. Find the ratio of milk to water in the resulting mixture.
A.2/1
B.4/3
C.2/3
D.3/4
Answer: B.4/3
Explanation: Given that Milk/Water=4x/x and 4x+x=45 --> x=9.
Thus Milk=4x=36 liters and Water=x=9 liters.
New ratio = 36/(9+18) = 36/27 = 4/3.
Answer: B.
Question: Without any stoppages a person travels a certain distance at an average speed of 40 km/hr and with stoppages he covers the same distance at an average of 20 km/hr. How many minutes per hour does he stop?
A.15 minute
B.20 minutes
C.30 minutes
D.45 minutes
Answer: C.30 minutes
Explanation: Explanation :
In one hour the distance covered at actual speed = 40km and with stoppages it covers only 20 km
so to travel 20 km at original speed i.e. 20 = 40*t, so t = 1/2 hour = 30
minutes
Answer – C
Question: Divide Rs. 720 among A, B and C so that A receives 1/3 as much as B and C together and B receives 2/3 as A and C together. A's share is?
A.s.800
B.s.400
C.s.600
D.s.180
Answer: D.s.180
Explanation: A+B+C = 720
A = 1/3(B+C); B = 2/3(A+C)
A/(B+C) = 1/3
A = 1/4 * 720 => 180
ANSWER:D
Question: The average mark of a class of thirty two students is 75. If three students whose marks are 28 and 34 are removed , then find the approximate average mark of the remaining students of the class.
A.71
B.74
C.78
D.70
Answer: C.78
Explanation: Exp. Total mark of 32 students = 75*32 = 2400,
Total mark after the removal of 2 students = 2400 –(28+34)
= 2400 – 62 = 2338
Approximate average mark = 2338/(32-2) = 2338/30 = 78
Answer: C
Question: The function f(x) = x + 4 is given. Solve the equation:
[3.f(x - 2)]/f(0) + 4 = f(2x + 1)
A.0.2
B.0.3
C.0.4
D.0.5
Answer: C.0.4
Explanation: Solution:
We calculate f(0), f(x -2), f(2x +1), namely f(0) = 0 + 4 = 4;
f(x - 2) = x - 2 + 4 = x + 2;
f(2x + 1) = 2x + 1 + 4 = 2x + 5 The equation gets this look
[3(x + 2)]/4 + 4 = 2x + 5 <=>
3(x + 2) +16 = 4(2x + 5) <=>
3x + 6 +16 = 8x + 20 <=>
22 - 20 = 8x - 3x <=>
2 = 5x <=> x = 0.4
Answer C
Question: In a game of billiards, A can give B 20 points in 60 and he can give C 40 points in 60. How many points can B give C in a game of 100?
A.18
B.27
C.50
D.21
Answer: C.50
Explanation: A scores 80 while B score 40 and C scores 20.
The number of points that C scores when B scores 100 = (100 * 20)/40 = 50.
In a game of 100 points, B gives (100 - 50) = 50 points to C.
Answer: C