RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: John deposited $10,000 to open a new savings account that earned 4 percent annual interest, compounded quarterly. If there were no other transactions in the account, what was the amount of money in John’s account 6 months after the account was opened?
A.$10,100
B.$10,101
C.$10,200
D.$10,201
Answer: D.$10,201
Explanation: Approach #1:
4 percent annual interest compounded quarterly --> 1% in 3 moths.
For the first 3 moths interest was 1% of $10,000, so $100;
For the next 3 moths interest was 1% of $10,000, plus 1% earned on previous interest of $100, so $100+$1=$101;
Total interest for 6 months was $100+$101=$201, hence balance after 6 months was $10,000+ $201=$10,201.
Answer: D.
Approach #2:
If the interest were compounded every 6 moths instead of every 3 months (quarterly) then in 6 months the interest would be 4%/2=2% of $10,000, so $200. Now, since the interest is compounded quarterly then there would be interest earned on interest (very small amount) thus the actual interest should be a little bit more than $200, only answer choice D fits.
Answer: D.
Question: How many 4 digit numbers are there, if it is known that the first digit is odd, the second is odd, the third is prime, the fourth (units digit) is divisible by 3, and the digit 1 can be used only once?
A.20
B.150
C.384
D.300
Answer: C.384
Explanation: 4 options for the first digit: 1, 3, 5, 7, 9;
5 options for the second digit: 1, 3, 5, 7, 9;
4 options for the third digit: 2, 3, 5, 7;
4 options for the fourth digit: 0, 3, 6, 9.
Four digit # possible without the restriction (about the digit 2): 5*5*4*4=400
Numbers with one 1-s, 1X1X 1*1*4*4=16.
Thus there are 400-16=384 such numbers.
Answer: C.
Question: Anil bought a T.V with 20% discount on the labeled price . Had he bought it with 25% discount, he would have saved Rs. 500. At what price did he buy the T.V?
A.Rs. 16000
B.Rs. 12000
C.Rs. 10000
D.Rs. 5000
Answer: C.Rs. 10000
Explanation: Let the labelled price be Rs. X,
S.P = 80/100*X =4X/5
New S.P = 75/100*X = 3X/4
4X/5 –3X/4 500, X = 10000
ANSWER:C
Question: I remember during the school days , the teacher asked the class "can you tell me the sum of the first 50 odd numbers ?".
I ran quickly to the teacher and told her "the answer is 2500". The teacher replied "lucky guess".
She then asked me "can you tell me the sum of first 75 odd numbers ?".
I wait for approx 10 seconds and replied with the correct answer.
How can i answer so quickly and whats the correct answer ?
A.5624
B.5625
C.5626
D.5627
Answer: B.5625
Explanation: Solution:
5625
n^1
75 * 75 = 5625 (sum of first 75 odd numbers).
50 * 50 = 2500 (sum of first 50 odd numbers).
Answer B
Question: A train of length 250 m crosses a bridge of length 180m in 20 seconds. What is the speed of train?
A.33
B.77.4
C.25
D.22
Answer: B.77.4
Explanation: Sol : (length of train+ length of bridge) = speed of train x Time
(250+180) = 20 x Speed
Speed = 430/20= 21.5 m/s =77.4 km/h
ANSWER=B
Question: The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 13 runs. Find his average in all the 30 matches?
A.31
B.67
C.88
D.69
Answer: A.31
Explanation: Total score of the batsman in 20 matches = 800.
Total score of the batsman in the next 10 matches = 130.
Total score of the batsman in the 30 matches = 930.
Average score of the batsman = 930/30 = 31.
Answer:A
Question: if an article with marked price of rs.400 is sold at successive discount of 10%,25% and 15%,what is the price the customer has to pay?
A.360
B.300
C.230
D.270
Answer: C.230
Explanation: discount=0.9*.75*.85=.57
so .57*400=230
ANSWER:C
Question: The ratio of the present ages of Ram and Rahim is 3 : 2. The ratio of the present ages of Rahim and Aman is 5 : 2. What is the ratio of the present ages of Ram and Aman?
A.4 : 15
B.15 : 4
C.9 : 5
D.Cannot be determined
Answer: B.15 : 4
Explanation: ram/rahim=3/2;
rahim/aman=5/2;
rahim=5aman/2;
ram/(5aman/2)=3/2;
ram=(3/2)*5aman/2;
ram/aman = (3/2)*5/2;
ram/aman = 15/4
ANSWER:B
Question: In a class of 25 students in an examination in maths 3 students scored 95 marks each, 3 get zero each and the average of the rest was 45. What is the average of the whole class?
A.47
B.45.6
C.44
D.48
Answer: B.45.6
Explanation: Explanation:
Total marks obtained by a class of 25 students
= 3*95 + 3*0 + 19 * 45 =1140
Average marks of whole class = 1140/25 =45.6
Answer: Option B
Question: Three (rather lazy) men A, B and C working together can do a work in 5 days. They start the work together and A works for 1 day and takes rest on the second day, B works for 2 days and takes rest on the next two days and C works for 2 days and takes rest on the next three days. In how many days will the work be completed ? (A, B, C work at the same rate)
A.7 days
B.8 days
C.9 days
D.10 days
Answer: D.10 days
Explanation: Total work is 3*5 = 15 units.
A does 1 day of work every 2 days.
B does 2 days of work every 4 days.
C does 2 days of work every 5 days.
Test the options.
In 7 days:
A will do 1*3 + 1 = 4 units (3 complete cycles and 1 day of work).
B will do 2*1+ 2= 4 units (1 complete cycle, 2 days of work, and 1 day of rest).
C will do 2*1 + 2 =4 units (1 complete cycle and 2 days of work).
Total = 4 + 4 + 4 = 12 units.
In 8 days:
A will do 1*4 = 4 units (4 complete cycles).
B will do 2*2= 4 units (2 complete cycles).
C will do 2*1 + 2 =4 units (1 complete cycle, 2 days of work, and 1 day of rest).
Total = 4 + 4 + 4 = 12 units.
In 9 days:
A will do 1*4 + 1 = 5 units (4 complete cycles and 1 day of work).
B will do 2*2+ 1 = 4 units (2 complete cycles and 1 day of work).
C will do 2*1 + 2 = 4 units (1 complete cycle, 2 days of work, and two days of rest).
Total = 5 + 5 + 4 = 14 units.
In 10 days:
A will do 1*5 = 5 units (5 complete cycles).
B will do 2*2+ 2= 6 units (2 complete cycle and 2 days of work).
C will do 2*2 =4 units (2 complete cycles).
Total = 5 + 6 + 4 = 15 units.
Therefore, the answer is D.
Question: Shipment --- No. of Defective Chips/shipment --- Total Chips in shipment
S1 ---------------------- 2 ------------------------------------------ 5,000
S2 ---------------------- 5 ------------------- ---------------------- 12,000
S3 ---------------------- 6 ------------------------------------------ 18,000
S4 ---------------------- 4 ------------------------------------------ 16,000
A computer chip manufacturer expects the ratio of the number of defective chips to the total number of chips in all future shipments to equal the corresponding ratio for shipments S1, S2, S3, and S4 combined, as shown in the table above. What’s the expected number of defective chips in a shipment of 66,000 chips?
A.14
B.20
C.22
D.24
Answer: C.22
Explanation: for a total of 51000 chips (adding S1,S2,S3,S4) total number of defective chips is 17 ((adding defective chips of S1,S2,S3,S4) so ratio is 17/51000 or 1 every 3000 chips.
Keeping this ratio constant for 60000 chips number of defective chips will be (1/3000) * 66000 = 22
C
Question: At 3:40, the hour hand and the minute hand of a clock form an angle of
A.160°
B.180°
C.130°
D.110°
Answer: C.130°
Explanation: Angle between hands of a clock
When the minute hand is behind the hour hand, the angle between the two hands at M minutes past H 'o clock
=30(H−M/5)+M/2 degree
When the minute hand is ahead of the hour hand, the angle between the two hands at M minutes past H 'o clock
=30(M/5−H)−M/2 degree
Here H = 3, M = 40 and minute hand is ahead of the hour hand.
Hence the angle
=30(M/5−H)−M/2
=30(40/5−3)−40/2
=30(8−3)−20
=30×5−20 =130°
Answer is C.
Question: If a - b = 10 and a2 + b2 = 210, find the value of ab.
A.68
B.42
C.55
D.18
Answer: C.55
Explanation: 2ab = (a2 + b2) - (a - b)2
= 210 - 100 = 110
ab = 55.
Answer: C
Question: A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
A.5 mins
B.1 mins
C.8 mins
D.3 mins
Answer: D.3 mins
Explanation: D
3 mins
D = 25 * 60 + 1500 = 3000 m
T = 3000/60 * 18/5 = 180 sec = 3 mins
Question: The length of a rectangular landscape is 4times its breadth. There is a playground in it whose area is 1200 square mtr & which is 1/3rd of the total landscape. What is the length of the landscape?
A.80
B.100
C.120
D.130
Answer: C.120
Explanation: Sol. x * 4x = 3 * 1200
x = 30
Length = 4 * 30 = 120
C
Question: The divisor is 25 times the quotient and 5 times the remainder, if the quotient is 16, the dividend is
A.6400
B.6480
C.400
D.480
Answer: B.6480
Explanation: Let the divisor be X
Given, Quotient = X/25
Remainder = X/5
X/25 = 16 ==> X = 25 * 16
Dividend = Divisor x Quotient + Remainder
= X * X/25 + X/5 = X/5(X/5 + 1)
= (16 * 25)/5 * (16 * 25/5 + 1)
= 80(80 + 1) = 81 * 80 = 6480
Answer B.
Question: A company, Chauncy Co., has an annual travel budget of $56,000. The accounting department estimates that transportation expenses will increase 5 percent in the coming year, and nontransportation travel expenses will increase by 15 percent in the coming year. Last year, Chauncy Co. spent $19,500 on transportation-related expenses, and $35,000 on nontransportation travel expenses. If the annual travel budget does not increase this year, and if the accounting department’s estimates are correct, how far over the annual travel budget will expenses be this year?
A.Expenses will not go over the budget.
B.$500
C.$4,725
D.$5,725
Answer: C.$4,725
Explanation: annual travel budget of $56,000
Let, Transportation expenses = T = 19500
and Non-Transportation expenses = N=35000
i.e. Increased Transportation expenses = 1.05T = 20475
and Increased Non-Transportation expenses = 1.15N = 40250
Total Expense = 20475+40250 = 60725
Expense over Budget = Budget - expense = 56000-60725 = 4725
Answer: Option C
Question: For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 200?
A.48
B.49
C.50
D.51
Answer: C.50
Explanation: From first constraint
4n+7 > 1
4n> -6
n > -(3/2)
n> -1.5 (n = -1, 0, 1 ,2 3........ upto infinity)
From second constraint
4n+7 < 200
4n< 193
n < 48. 25
n = (-infinity, .......-3, -2, -1, 0, 1, 2, .........upto 48)
Combining the two
-1.5 < n<48.25
n = 1 to 48 (48 integers)
and n = -1 and 0
so 50 integers.
C is the answer
Question: 23, 27, 36, 52,...
A.40
B.24
C.77
D.36
Answer: C.77
Explanation: Explanation :
23
23+2^2=27
23+3^2=36
23+4^2=52
23+5^2=77
ANSWER:C
Question: What is the rate percent when the simple interest on Rs.1600 amount to Rs.200 in 4 Years?
A.4%
B.3.125%
C.5%
D.6%
Answer: B.3.125%
Explanation: Interest for 1 year = 200/4 = 50
Interest on Rs 1600 p/a = 50
interest rate = 50/1600*100 = 3.125%
Answer : B
Question: The length of the bridge, which a train 130 metres long and travelling at 54 km/hr can cross in 30 seconds, is:
A.200 m
B.225 m
C.320 m
D.250 m
Answer: C.320 m
Explanation: Speed = [54 X 5/18] m/sec = [15/1] m/sec
Time = 30 sec
Let the length of bridge be x metres.
Then, (130 + x)/30 = 15 => (130 + x) = 450 => x = 450-130 = 320m
ANSWER:C
Question: If S is the sum of the reciprocals of the consecutive integers from 91 to 100, inclusive, which of the following is less than S?
I. 1/8
II. 1/10
III. 1/9
A.None
B.I only
C.III only
D.II only
Answer: D.II only
Explanation: Since we summarize the reciprocals from 100 to 91, we can say also that we add ten numbers who are all (with one exception 1/100) greater than 1/100, so that the sum must be greater than 1/10.
On the other side we can say that we add the reciprocals from 91 to 100, so that the sum has to be less than the sum of ten times 1/91.
We can conclude that the sum has to be less than 1/9 but more than 1/10. That leaves us D as the only possible answer.
Question: Factor (x + 4)3 - 9x - 36 =
A.(x - 4)(x + 1)(x + 7)
B.(x + 6)(x + 2)(x + 9)
C.(x + 4)(x + 1)(x + 5)
D.(x + 4)(x + 1)(x + 7)
Answer: D.(x + 4)(x + 1)(x + 7)
Explanation: (x + 4)3 - 9x - 36=
(x + 4)3 - 9(x + 4)=
(x + 4)[(x + 4)2 - 9]=
(x + 4)(x + 4 - 3)(x + 4 + 3)=
(x + 4)(x + 1)(x + 7
Answer D
Question: How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per
Kg so that there may be a gain of 10 % by selling the mixture at Rs. 9.24 per Kg ?
A.60 Kg
B.63 kg
C.58 Kg
D.56 Kg
Answer: B.63 kg
Explanation: Explanation :
Selling Price(SP) of 1 Kg mixture= Rs. 9.24
Profit = 10%
Cost Price(CP) of 1 Kg mixture= 100(100+Profit%)×SP=100(100+10)×9.24=100110×9.24=92.411=Rs.8.4
By the rule of alligation, we have
CP of 1 kg sugar of 1st kind CP of 1 kg sugar of 2nd kind
Rs. 9 Rs. 7
Mean Price
Rs.8.4
8.4 - 7 = 1.4 9 - 8.4 = .6
ie, to get a cost price of 8.4, the sugars of kind1 and kind2 should be mixed in the
ratio 1.4 : .6 = 14 : 6 = 7 : 3
Let x Kg of kind1 sugar is mixed with 27 kg of kind2 sugar
then x : 27 = 7 : 3
⇒x27=73⇒x=27×73=63
Answer : Option B
Question: In a throw of a coin find the probability of getting a tail?
A.1/2
B.1/3
C.1/4
D.2/5
Answer: A.1/2
Explanation: S = {H,T}
E = {T}
P(E) = 1/2
Answer is A
Question: How many positive integers less than 160 are there such that they are multiples of 13 or multiples of 12 but not both?
A.18
B.19
C.20
D.23
Answer: D.23
Explanation: for 13: 13...160=13*12
for 12: 12...156=12*13
but there is one integer 13*12. so
N=(12-1)+(13-1)=23
D
Question: A cycle is bought for Rs.900 and sold for Rs.1080, find the gain percent?
A.16 2/3%
B.20%
C.18%
D.25%
Answer: B.20%
Explanation: Explanation:
900 ---- 180
100 ---- ? => 20%
ANSWER IS B
Question: A certain list consists of 21 different numbers. If n is in the list and n is 6 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?
A.1/20
B.3/13
C.1/5
D.4/21
Answer: B.3/13
Explanation: series : a1, a2....a20,n
sum of a1+a2+...+a20 = 20*x (x = average)
so, n = 6*x
Hence, a1+a2+..+a20+n = 26x
So, the fraction asked = 6x/26x = 3/13
Answer B
Question: In a competitive examination batch A 7% candidates got selected from the total appeared candidates. Batch B also had an equal number of candidates appeared and 10% candidates got selected with 15 more candidates got selected than batch A. what was the number of candidates appeared from each batch?
A.100
B.360
C.500
D.240
Answer: C.500
Explanation: Explanation :
Solution: Let the number of candidates appeared from each batch be x.
then, 10% of x - 7% of x =15.
=>3% of x =15
=>3x/100 =15 => x =15*100/3 = 500
Answer : C
Question: One hundred gallons of fuel are purchased at $0.70 per gallon. The fuel is consumed at a rate of $0.40 worth of fuel per hour. At this rate, how many hours are required to consume the 100 gallons of fuel?
A.150
B.175
C.200
D.225
Answer: B.175
Explanation: The fuel is consumed at this rate: $0.40/$0.70 = 4/7 gallons per hour.
The time it takes to consume 100 gallons is: 100 / (4/7) = 175 hours.
The answer is B.
Question: A man rows his boat 80 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
A.6
B.8
C.5
D.7
Answer: D.7
Explanation: Speed downstream = d/t = 80/(2 1/2) = 32 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (32 - 18)/2
= 7 kmph
Answer: D
Question: 20 men went to a restaurant. Ninteen of them paid Rs.70 each and the twentieth man paid Rs.90.25 more than the average of all the 20 men. What is the total bill ?
A.1495
B.1121
C.1298
D.1102
Answer: A.1495
Explanation: Let the average bill paid by twenty members = 'x'
But 19 men paid each = Rs. 70
20th man paid Rs. 90.25 more than the avg bill of 20 = x + 90.25
20x = 19(70) + x + 90.25
19x = 1330 + 90.25
19x = 1420.25
x = 1420.25/19 = Rs. 74.75
But the total bill = 20 x 74.75 = Rs. 1495
Answer: A
Question: The average age of a husband and his wife was 23 years at the time of their marriage.After five years they have a one year old child.The average age of the family now is
A.19 years
B.23 years
C.28.5 years
D.29.3 years
Answer: A.19 years
Explanation: (h+w)/2 = 23 --> h+w = 46
after five years
H+W + C = 46+10+1 = 57
average age of family = 57/3 = 19
ANSWER:A
Question: A man traveled a total distance of 1800 km. He traveled one-third of the whole trip by plane and the distance traveled by train is one-half of the distance traveled by bus. If he traveled by train, plane and bus, how many kilometers did he travel by bus?
A.700
B.800
C.900
D.1000
Answer: B.800
Explanation: total distance traveled = 1800 km.
distance traveled by plane = 600 km.
distance traveled by bus = x
distance traveled by train = x/2
x + x/2 + 600 = 1800
3x/2 = 1200
x = 800 km
The answer is B.
Question: The ages of two friends is in the ratio of 6:5.If the sum of their ages is 66. Then after how many years will the ratio become 7:6?
A.5
B.6
C.8
D.9
Answer: B.6
Explanation: the ratio of ages is 6:5 or we can say 6x and 5x
so , 6x+5x=66 (sum)
x=6
the ages are 6*6=36 and 6*5=30
let the years after which ratio will become 7:6 be y
36+y/30+y=7/6
the value of y will be 6
ANSWER:B
Question: For integers U and V, when U is divided by V, the remainder is Zero. Which of the following must be true?
A.U and V share no common factors other than 1
B.UV is odd.
C.At least one of U and V is odd
D.The sum U + V is odd
Answer: C.At least one of U and V is odd
Explanation: At least one of U and V is odd
C
Question: Two alloys A and B are composed of two basic elements. The ratios of the compositions of the two basic elements in the two alloys are 5 : 3 and 5 : 1, respectively. A new alloy X is formed by mixing the two alloys A and B in the ratio 4 : 3. What is the ratio of the composition of the two basic elements in alloy X ?
A.1 : 1
B.2 : 3
C.5 : 2
D.4 : 3
Answer: C.5 : 2
Explanation: Mixture A has a total of 5 + 3 = 8 parts. If in the final mixture this represents 4 parts, then the total number of parts in mixture B should be (8/4)*3 = 6.
So, we should take of mixture B a quantity with 5 and 1 parts, respectively.
This will give us in the final mixture (5 + 5) : (3 + 1), which means 10:4, or 5:2.
Answer C.
Question: In a certain experiment, the data collected is the number of organisms per sample, and this data follows a normal distribution. If the sample of data has a mean of 60 and a standard deviation of 10, which of the following is exactly 1.75 standard deviations more than the mean?
A.a) 48
B.b) 60
C.c) 72
D.d) 77.5
Answer: D.d) 77.5
Explanation: Standard Deviation is a relatively rare category in the Quant section, although you're like to be tested on it 1 time on Test Day. You'll never be asked to calculate SD though, so you really just need to learn the basic 'concepts' behind it.
Here, we're told two things about a group of numbers:
1) The average of the group is 60
2) The standard deviation of the group is 10
If you go 1 SDupfrom the average, you hit.....60+10 = 70
If you go 1 SDdownfrom the average, you hit.....60-10 = 50
If you go 2 SDsupfrom the average, you hit.....60+2(10) = 80
If you go 2 SDsdownfrom the average, you hit.....60-2(10) = 40
Etc.
Here, we're asked for the number that is EXACTLY 1.75 SDs above the mean....
1.75 SDsupwould be.....60 + 1.75(10) = 77.5
D
Question: The number of female students in a college in the previous year was 450. If in the current year the number of male students in the college doubled over that of the previous year but the proportion of male students halved, then what is the number of female students in the college in the current year?
A.1500
B.1800
C.2100
D.2400
Answer: B.1800
Explanation: Let x be the number of male students last year. The number of male students this year is 2x.
Let y be the number of female students this year.
x/450 = 2(2x/y)
y = 1800
The answer is B.
Question: If a man crosses a 500 m long street in 5 minutes. What is his speed?
A.6 km/hr
B.7.1 km/hr
C.7.2 km/hr
D.8 km/hr
Answer: A.6 km/hr
Explanation: distance = 500 meter
time = 5 minutes = 5 x 60 seconds = 300 seconds
Speed = distance/time=500/300=1.67m/s=1.67×18/5 km/hr=6 km/hr
A
Question: A train is 360 meter long is running at a speed of 60 km/hour. In what time will it pass a bridge of 140 meter length?
A.27 seconds
B.29 seconds
C.40 seconds
D.30 seconds
Answer: D.30 seconds
Explanation: Speed = 60 Km/hr = 60*(5/18) m/sec = 50/3 m/sec
Total distance = 360+140 = 500 meter
Time = Distance/speed
= 500 * (3/50) = 30 seconds
Answer:D
Question: How many three digit numbers can be formed in which if one digit is 3 then it must be follwed by 7 and repetetion of digits is not allowed
A.12
B.13
C.14
D.15
Answer: D.15
Explanation: if 7 is to be followed by 3 , then the numbers will be either 37_ or _37.
for 37_ ,we have 370,371,372,374,375,376,378,379.
and for _37,we have 137,237,437,537,637,837,937.
therefore i think the answer is 15
ANSWER:D
Question: a person travels from his house to office from 11:10 am to 12:10 am and covers a distence of 1km. find the average speed of the person.
A.20.1km/h
B.20.5km/h
C.1km/h
D.22.1km/h
Answer: C.1km/h
Explanation: time=12:10-11:10= 1hour
distance= 1km
speed=1*1= 1km/h
ANSWER:C
Question: A man purchases two watches at 560. He sells one at 15% profit and other at 10% loss. Then he neither gains nor lose. Find the cost price of each watch.
A.224, 300
B.200, 300
C.224, 336
D.200, 336
Answer: C.224, 336
Explanation: Here, in whole transaction, there is neither gains nor loss, therefore,
Amount of gain in one watch = Amount of loss in other watch
⇒ 0.15 × CP1 = 0.10 × CP2
⇒ CP1/CP2=0.10/0.15=23
Also CP1 + CP2 = 560
∴ CP1 = 2/2+3×560=224
and CP2 = 560 – 224 = 336
Answer C
Question: What is the slope of a line perpendicular to 2y = -6x - 10?
A.3
B.-3
C.-1
D.1/3
Answer: D.1/3
Explanation: For lines to be perpendicular ,
slope of line 1 * slope of line 2 = -1
(-6/3) * (x) = -1
x = (1/3)
where x is slope of line 2
Ans - D
Question: A certain sum of money at simple interest amounted Rs.1023 in 12 years at 4% per annum, find the sum?
A.338
B.689
C.691
D.646
Answer: C.691
Explanation: 1023 = P [1 + (12*4)/100]
P = 691
Answer:C
Question: Raja spends 35% of his monthly income on household items, 20% of his monthly income on buying cloths, 5% of his monthly income on medicines and saves the remaining amount which is Rs. 15000. Find his monthly income.
A.Rs. 40000
B.Rs. 36000
C.Rs. 37500
D.Rs. 45000
Answer: C.Rs. 37500
Explanation: Savings 40% - 15000
Expenditure 60 % - 22500
Total - 37500
Answer : C
Question: The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?
A.16 cm
B.18 cm
C.20 cm
D.22 cm
Answer: B.18 cm
Explanation: 2(l + b)	=	5
b	1
2l + 2b = 5b
3b = 2l
b =	2	l
3
Then, Area = 216 cm2
l x b = 216
l x	2	l	= 216
3
l2 = 324
l = 18 cm.
B
Question: A train is running at a speed of 40 km/hr and it crosses a post in 18 seconds. What is the length of the train?
A.150 m
B.180 m
C.200 m
D.240 m
Answer: C.200 m
Explanation: Speed =40 km/hr =40×(5/18)=(100/9) m/s Length of the train = (Speed x Time)
=(100/9*18) m
=200 m
Answer: C
Question: What approximate value should come in place of the question mark (?) in the following equation?40.75 Ã— 10.77 â€“ 18.75 Ã— 11.15 = (47 + ?) Ã— 4
A.10.454
B.11.454
C.12.454
D.14.454
Answer: A.10.454
Explanation: Solve using approximation
Answer A
Question: If any amount is distributed among A ,B and C so that the part of A is doubled that of the part of B and part of b is 2 time the part of C .Find the ratio among their parts.
A.1:2:4
B.4:2:1
C.8:4:1
D.2:4:1
Answer: B.4:2:1
Explanation: By the assumptions as mentioned we have A=2B and B=2C. So A=2(2C) and we get A=4C. We have, therefore, A:B:C = 4C:2C:C. By cancelling the ratio with C we have 8:4:1. The answer is, therefore, B.
Question: Find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 748.
A.121 ,123 , 125 ,127
B.120 ,122 , 125 ,128
C.120 ,121 , 122 ,123
D.123 ,125 , 127 ,129
Answer: A.121 ,123 , 125 ,127
Explanation: Let x, x + 2, x + 4 and x + 6 be the four integers. The sum of the first two
x + (x + 2)
twice the sum of the last two is written as
2 ((x + 4) + (x + 6)) = 4 x + 20
sum of the first two added to twice the sum of the last two is equal to 748 is written as
x + (x + 2) + 4 x + 20 = 748
Solve for x and find all four numbers
x = 121 , x + 2 = 123 , x + 4 = 125 , x + 6 = 127
Answer A