RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Five machines at a certain factory operate at the same constant rate. If four of these machines, operating simultaneously, take 20 hours to fill a certain production order, how many fewer hours does it take all five machines, operating simultaneously, to fill the same production order?
A. 4
B. 5
C. 6
D. 16
Answer: A. 4
Explanation: Total work = 4*20 machine hrs
Time taken = 4* 20 /5 => 16 hours...
Thus all five machines, operating simultaneously will take ( 20 - 16 ) 4 hours..
Answer will be (A) 4
Question: Four years ago, the average age of a family of 4 members was 21 years.A baby having been born,the average age of the family is the same today.The present age of the baby?
A.5 years
B.7 years
C.2 years
D.3 years
Answer: A.5 years
Explanation: Total age of the 4 members, 4 years ago = (21*4)= 84 years.
Total age of the 4 members now =( 84+ 4*4) years =100 years.
Total age of the 5 members now = (21*5) = 105 years.
Age of the baby is = 105- 100= 5 years
Answer :A
Question: How many 1/10s are there in 37 1/2?
A.375
B.475
C.500
D.670
Answer: A.375
Explanation: Required number = (75/2)/(1/10)
= (75/2 x 10/1)
= 375.
ANSWER:A
Question: a light flashes every 5seconds, how many times will it flash in ? of an hour?
A.720
B.600
C.650
D.700
Answer: A.720
Explanation: 1flash=5sec
for 1 min=12flashes
so for 1 hour=12*60=720 flashes.
ANSWER:A
Question: RADIO X sells cheap radios for commercial use by buying surplus supplies. A surplus bag of 100 diodes costs $2.00. A surplus bag of diodes, on average, has 10% faulty diodes (the faulty diodes are thrown away, and the remaining diodes are used in production). It takes 5 diodes to make 1 circuit board. If it takes 3 circuit boards to make a radio, how much money is needed to buy diodes to make x number of radios, in dollars?
A.x/3
B.3x
C.2x/3
D.x
Answer: A.x/3
Explanation: Initial cost for 1 bag of diodes = $2, but ONLY 100(1 - 0.1) = 90 are used. So the cost for 90 diodes = $2. The number of diodes for making a radio is (3 circuit boards)(5 diodes) = 15 diodes. So, the cost for diodes to make a radio is $2(15/90) = $1/3.
$x/3 =cost of diodes to make x number of radios.
Answer is A
Question: A Positive number which when added to 999 given a sum which is greater than when it is multiplied by 999. Which of the following could be the value of the positive integer?
A.5
B.3
C.1
D.2
Answer: C.1
Explanation: Explanation:
Let the positive integer = x
Then, 999 + x > 999x
By trial and error, when x = 1,
1000 > 999
So, the required positive integer is 1,
1000 > 999
So, the required positive integer is 1.
Answer: Option C
Question: X starts a business with Rs.77000. Y joins in the business after 5 months with Rs.42000. What will be the ratio in which they should share the profit at the end of the year?
A.21:23
B.23:45
C.22:7
D.25:29
Answer: C.22:7
Explanation: Explanation :
Ratio in which they should share the profit
= Ratio of the investments multiplied by the time period
= 77000 * 12: 42000 * 7
= 77 * 12: 42 * 7
= 11*2: 7
= 22:7.
Answer : Option C
Question: A person standing on a railway platform noticed that a train took 21 seconds to completely pass through the platform which was 84 m long and it took 9 seconds in passing him. The speed of the train was
A.25.2 km/hr
B.32.4 km/hr
C.50.4 km/hr
D.75.6 km/hr.
Answer: A.25.2 km/hr
Explanation: Explanation:
Let the train’s length be L m.
L/9=(L+84)/21
21 L = 9L +756
12L= 756
L=63 m
Speed = 63 /9 = 7 m/s = 7 x 18/5 = 25.2 Km/hr.
Answer A
Question: By travelling at 40 kmph, a person reaches his destination on time. He covered two-third the total distance in one-third of the total time. What speed should he maintain for the remaining distance to reach his destination on time?
A.20 kmph
B.30 kmph
C.87 kmph
D.99 kmph
Answer: A.20 kmph
Explanation: Let the time taken to reach the destination be 3x hours. Total distance
= 40 * 3x = 120x km
He covered 2/3 * 120x = 80x km in 1/3 * 3x
= x hours So, the remaining 40x km, he has to cover in 2x hours. Required speed
= 40x/2x = 20 kmph.
Answer:A
Question: When the no.7y86038 is exactly divisible by 11, then the smallest whole no.in place of y?
A.9
B.10
C.11
D.13
Answer: C.11
Explanation: The given number =7y86038
Sum of the odd places =8+0+8+7=23
Sum of the even places = 3+6+y
(Sum of the odd places)- (Sum of even places) = Number (exactly divisible by 11)
23-(9+y) = divisible by 11
14 � y = divisible by 11.
Y must be 3, to make given number divisible by 11.
C
Question: A certain city with a population of 108,000 is to be divided into 11 voting districts , and no district is to have a population that is more than 10 percent greater than the population of any other district What is the minimum possible population that the least populated district could have ?
A.a) 10,700
B.b) 10,800
C.c) 9,000
D.d) 11,000
Answer: C.c) 9,000
Explanation: Let x = number of people in smallest district
x*1.1 = number of people in largest district
x will be minimised when the number of people in largest district is maximised
10*x*1.1 = 11x = total number of people in other districts
So we have 11x + x = 108k
x = 9,000
Answer : C
Question: A can do a piece of work in 10 days. He works at it for 4 days and then B finishes it in 9 days. In how many days can A and B together finish the work?
A.6
B.7
C.9
D.5
Answer: A.6
Explanation: 4/10 + 9/x = 1 => x = 15
1/10 + 1/15 = 1/6 => 6 days
Answer: A
Question: Set A: 3, r, 8, 10
Set B: 4, g, 9, 11
The terms of each set above are given in ascending order. If the median of Set A is equal to the median of Set B, what is the value of g – r?
A.-2
B.-1
C.0
D.1
Answer: B.-1
Explanation: So we have even no. of elements in the Set
So median is the average of Middle two numbers
(r+8)/2= (g+9)/2
g - r= -1
Answer B
Question: A train travelled from station P to Q in 8 hours and came back from station Q to P is 6 hours. What would be the ratio of the speed of the train while traveling from station P to Q to that from station Q to P?
A.3 : 9
B.3 : 7
C.3 : 8
D.3 : 4
Answer: D.3 : 4
Explanation: Since S # 1/t
S1 : S2 = 1/t1 : 1/t2 = 1/8 : 1/6 = 3 : 4
Answer:D
Question: John was thrice as old as Tom 6 yrs back. He will be 5/3 times as old as Tom 6 years hence. How old is Tom today?
A.6
B.9
C.12
D.18
Answer: C.12
Explanation: Sol. RMBflSk -6 = 3 (Ravi - 6) ...(j)
and Rupesh + 6 = | (Ravi + 6) ...(ii)
Solving both the equations we get,
Ravi = 12 years.
C
Question: What is the sum of all consecutive integers from 10 to 100, inclusive?
A.4550
B.4950
C.5005
D.5500
Answer: C.5005
Explanation: SUM= n/2(Starting number+ Ending number)
n: total numbers between the starting no. and ending no.
n= 100-10+1= 91
SUM= (91/2)*(10+100)
= 91*55
=5005
Hence, answer C
Question: Average age of 7 members of a family is 29 years. If present age of the youngest member is 5 year, find average age of the remaining members at the time of birth of the youngest member.
A.28
B.37
C.29
D.237
Answer: A.28
Explanation: Average age (present) of 7 members = 29 years
5 years ago, average age of 7 members was 29 - 5 = 24 years.
Since, the youngest member was not born 5 years ago.
Therefore, Average age of remaining 6 members is increased by 246246 = 4 years.
Therefore, 5 years ago, average age of 6 members was 24 + 4 = 28 years.
Answer:A
Question: What is the probability of finding exactly 33 multiples of 3 when 100 consecutive
natural nos are selected?
A.1/3
B.2/3
C.1
D.2
Answer: B.2/3
Explanation: out of 3x,3x+1,3x+2 as starting numbers,
Only case when starting no. is 3x we'll get 34 multiples of 3.
ANSWER:B
Question: What is the probability that a three digit number is divisible by 7?
A.1/7
B.127/900
C.32/225
D.129/900
Answer: C.32/225
Explanation: Total 3 digit integers which are divisible by 7 :
(994-105)/7+1 = 128
The total number of 3 digit integers = (999-100)+1 = 900
The required probability : 128/900 = 32/225
answer:C.
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 46, the dividend is:
A.5324
B.5334
C.5336
D.5356
Answer: C.5336
Explanation: Divisor = (5 * 46) = 230
= 10 * Quotient = Divisor
=> Quotient = 230/10 = 23
Dividend = (Divisor * Quotient) + Remainder
Dividend = (230 * 23) + 46 = 5336.
C
Question: If one of the roots of the quadratic equation x2 + mx + 24 = 0 is 1.5, then what is the value of m?
A.-22.5
B.16
C.-10.5
D.-17.5
Answer: D.-17.5
Explanation: Explanatory Answer
We know that the product of the roots of a quadratic equation ax2 + bx + c = 0 is
In the given equation, x2 + mx + 24 = 0, the product of the roots = = 24.
The question states that one of the roots of this equation = 1.5.
If x1 and x2 are the roots of the given quadratic equation and let x1 = 1.5.
Therefore, x2 == 16.
In the given equation, m is the co-efficient of the x term.
We know that the sum of the roots of the quadratic equation ax2 + bx + c = 0 is = -m
Sum of the roots = 16 + 1. 5 = 17 = -17.5.
Therefore, the value of m = -17.5
Answer D
Question: When toys are grouped into 12 and 18, always 3 toys remain ungrouped. What is the minimum number of toys to be added so that when they are grouped into 7, no toys will remain ungrouped ?
A.0
B.1
C.2
D.3
Answer: D.3
Explanation: T= 12a+3 = 18b + 3
2a=3b --> min (a,b) = (3,2)
So minimum number of toys --> 12*3+3 = 39
When toys are grouped into 7, 4 will remain ungrouped so in order to make another group of 7 toys -->
7-4 = 3 toys at least to be added.
ANSWER: D
Question: The expenditure of a businessman increase consistently by 10% per year. If his present expenditure is Rs. 20000 then what will his expenditure be after 2 years ?
A.24500
B.24400
C.24300
D.24200
Answer: D.24200
Explanation: Explanation :
Expenditure = 20000 x 1.1 x 1.1 = 24200
Answer : Option D
Question: In a 500 m race,the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m.Then,A wins by
A.60 m
B.40 m
C.20 m
D.10 m
Answer: C.20 m
Explanation: Solution
To reach the winning post A will have to cover a distance of ( 500 -140)m, i.e,360m.
While A covers 3 m, B covers 4 m.
While A covers 360 m, B covers (4/3 x 360)m =480m
Thus,when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
∴ A wins by 20 m.
Answer C
Question: Two pipes A and B can separately fill a cistern in 45 minutes and 60 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 40 minutes. In how much time, the third pipe alone can empty the cistern?
A.90 min
B.100 min
C.72 min
D.75 min
Answer: C.72 min
Explanation: 1/40-(1/45+1/60)=-1/72
third pipe can empty in 72 minutes
ANSWER:C
Question: Which of the following CANNOT be the median W of the four consecutive positive integers w, x, y, and z, where w < x < y < z ?
A.(w+x)/2 - 1
B.(w+z)/2
C.(x+y)/2
D.(y+z)/2 -1
Answer: A.(w+x)/2 - 1
Explanation: Using the properties of consecutive positive integers we could right away eliminate B,C and E.
(B) - The average of first and last terms is the median
(C) - For even number of integers, the median is the average of middle terms
(E) - The average is equal to median if the integers are consecutive
Remaining answer choices are A and D.
For A, the average of first two consecutive numbers (w,x) will definitely be less than x making it impossible to be a median W.
Answer (A)
Question: The time it took car P to travel 600 miles was 2 hours less than the time it took car R to travel the same distance. If car P’s average speed was 10 miles per hour greater than that of car R, what was car R’s average speed, in miles per hour?
A.40
B.50
C.60
D.70
Answer: B.50
Explanation: Let speed of car R be=x
Then speed of car P= x+10
A/Q,
(600/x)-(600/(x+10))=2
Solving for x=50 miles\hr
ANSWER:B
Question: Carrie likes to buy t-shirts at the local clothing store. They cost $8.75 each. One day, she bought 18 t-shirts. How much money did she spend?
A.$150
B.$70
C.$200
D.$171.6
Answer: B.$70
Explanation: $8.75*18=$70. Answer is B.
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is?
A.Rs.122
B.Rs.129
C.Rs.125
D.Rs.120
Answer: C.Rs.125
Explanation: 3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 1/2 = Rs.125
Answer:C
Question: The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum.
A.Rs.17277
B.Rs.17000
C.Rs.17287
D.Rs.172827
Answer: B.Rs.17000
Explanation: Explanation:
The simple interest for the first year is 10200/2 is Rs.5100 and compound interest for first year also is Rs.5100. The compound interest for second year on Rs.5100 for one year
So rate of the interest = (100 * 1530)/ (5100 * 1) = 30% p.a.
So P = (100 * 10200)/ (30 * 2) = Rs.17000
Answer: B
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
A.1 years
B.20 years
C.10 years
D.15 years
Answer: C.10 years
Explanation: Explanation:
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
Answer: C
Question: There are 40 students in a certain geometry class. If two thirds of the students are boys and three fourths of the boys are under six feet tall, how many boys in the class are under six feet tall?
A.6
B.12
C.20
D.24
Answer: C.20
Explanation: 40*2/3 *3/4= 20
Answer: C
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 900 grams per kg, what is his percent?
A.28%
B.25%
C.11.11%
D.28%
Answer: C.11.11%
Explanation: 900 --- 100
100 --- ? => 11.11%
Answer: C
Question: A grocer is storing soap boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 6 inches by 6 inches, then what is the maximum number of soap boxes that can be placed in each carton?
A.210
B.252
C.250
D.300
Answer: C.250
Explanation: however the process of dividing the volume of box by the volume of a soap seems flawed but it does work in this case due to the numbers
Dimensions of the box =25*42*60
Dimensions of the soap = 6*6*7
placing the 7 inch side along 42 inch side we get 6 soaps in a line and in a similar way 5 along 25 and 6 along 60
we get = 5x5x10 = 250
so the question is why this particular arrangement, in order to maximize number of soaps we need to minimize the space wasted and this is the only config where we dont waste any space so we can expect the maximum number
the answer is (C)
Question: If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (3x - 4y) is odd
II. xy^2 is an even negative integer
III. (y^2 - x) is an odd negative integer
A.(3X-4Y) IS ODD TRUE
B.II only
C.I and II
D.I and III
Answer: A.(3X-4Y) IS ODD TRUE
Explanation: If x is an odd negative integer and y is an even integer, which of the following statements must be true?
I. (3x - 4y) is odd
3x - is always negative and odd
2y - can be 0, when y=0, or always even integer (positivie or negative)
odd integer +/- even integer = always odd
I statement is always true
II. xy^2 is an even negative integer
y can be 0 => xy^2 = 0 (non-negative even) => II statement is not true
III. (y^2 - x) is an odd negative integer
y can be 0 => -x will be positive => III statement is not true
basing on above, only I statement will always be true
answer is A
Question: A train speeds past a pole in 15 sec and a platform 100 m long in 25 sec, its length is?
A.100
B.150
C.140
D.130
Answer: B.150
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 100)/25 = x/15 => x = 150 m.
Answer: Option B
Question: Two trains are moving at 50 kmph and 70 kmph in opposite directions. Their lengths are 150 m and 100 m respectively. The time they will take to pass each other completely is?
A.7 1/2 sec
B.2 sec
C.3 sec
D.5 sec
Answer: A.7 1/2 sec
Explanation: 70 + 50 = 120 * 5/18 = 100/3 mps
D = 150 + 100 = 250 m
T = 250 * 3/100 = 15/2 = 7 Â½ sec
ANSWER A
Question: The jogging track in a sports complex is 900 m in circumference. Sunil and Sachin start from the same point and walk in opposite directions at 5.4 km/hr and 3.6km/hr respectively. They will meet for the first time in?
A.2.98 min
B.5.7 min
C.6.0 min
D.6.3 min
Answer: C.6.0 min
Explanation: Clearly, the two will meet when they are 900m apart.
To be (5.4+ 3.6) = 9.0 km apart, they take 1 hour.
To be 900 m apart, they take
= (900/9000 * 60) min
= 6.00 min.
Answer: C
Question: A trainer is standing in one corner of a square ground of side 25m. His voice can be heard upto 140m. Find the area of the ground in which his voice can be heard?
A.12300
B.14500
C.15400
D.16700
Answer: C.15400
Explanation: Area covered by goat = Pi*r^2/4 ( here we divide by 4 because the trainer is standing in a corner of the ground and only in 1/4 part , the voice can be heard)
where r= 14 m = length reaching the voice
So area = (22/7)*140*140/4 = 15400 sq m
answer :C
Question: Pipe A can fill a tank in 6 hours. Due to a leak at the bottom, it takes 9 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank?
A.17
B.16
C.18
D.77
Answer: C.18
Explanation: Explanation:
Let the leak can empty the full tank in x hours 1/6 - 1/x = 1/9
=> 1/x = 1/6 - 1/9 = (3 - 2)/18 = 1/18
=> x = 18.
Answer: C
Question: What is the difference between the compound interests on Rs. 5000 for 11â„2 years at 4% per annum compounded yearly and half-yearly?
A.2.04
B.4.8
C.3.06
D.8.3
Answer: A.2.04
Explanation: compunded yearly
= 5000*(1+4/100)*(1+1/2*4/100)
=5304
compound interest for 1 1/2 years when interest=>(5304-5000)
=>P(1+(R/2)/100)^2T = 5000(1+(4/2)/100)2*3/2 = 5000(1+2/100)^3
=5000(102/100)^3 = 5306.04
1 1/2 Years half yearly = (5306.04 - 5000)=> 2.04
ANSWER A
Question: A water tank is four-fifth full.Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes.If both the pipes are open,how long will it take to empty or fill the tank completely?
A.12 min.to empty
B.9 min.to empty
C.5 min.to empty
D.4 min.to empty
Answer: A.12 min.to empty
Explanation: Explanation:
Clearly,pipe B is faster than pipe A and so,the tank will be emptied.
part to be emptied = 4/5
part emptied by (A+B) in 1 minute=(1/6-1/10)=1/15
so, the tank will be emptied in 12 min
Answer: A
Question: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement?
A.1977
B.1893
C.1979
D.1900
Answer: D.1900
Explanation: 2000 ---- 54
2000 ---- 39
x ----- 20
x*20 = 2000*39
x = 3900
2000
-------
1900
Answer: D
Question: If 2^k = 4, then 2^(2K+2) =
A.29
B.45
C.81
D.64
Answer: D.64
Explanation: 2^k=4
2^2k=4^2
2^2k=16
2^(2k+2)
=2^2k*2^2
=16*4
=64
Answer: D
Question: The true discount on Rs.2562 due 4 months hence is Rs.122.The rate % is?
A.12%
B.13 (1/3)%
C.15%
D.14%
Answer: A.12%
Explanation: Explanation:
P.W = Rs.( 2562 - 122) = Rs.2440
S.I on Rs.2440 for 4 months is Rs.122
Rate = [100X 122/2440X1/3 ] % = 15%
Answer: A
Question: Find the compound interest on $1200 for 5 years at 20% p.a. if CI is component yearly?
A.$120
B.$150
C.$1786
D.$250
Answer: C.$1786
Explanation: A = P(1 + R/100)^T
= 1200(1 + 20/100)^5
=$2986
CI = $1786
Answer is C
Question: An article is bought for Rs.675 and sold for Rs.700, find the gain percent?
A.2%
B.3%
C.4%
D.5%
Answer: C.4%
Explanation: 675 ---- 25
100 ---- ? =>
=4%
Answer:C
Question: 0, 180, 12, 50, 100, 200, ?, 3, 50, 4, 25, 2, 6, 30, 3
A.150
B.175
C.225
D.250
Answer: A.150
Explanation: 90, 180, 12, 50, 100, 200, ?, 3, 50, 4, 25, 2, 6, 30, 3
I think 1st term will be 90
two series
90, 180, 12, 50, 100, 200, ?,
and 3, 50, 4, 25, 2, 6, 30, 3
3*50=150
50*4=200
4*25=100
25*2=100
2*6=12
6*30=180
30*3=90
so ans is 150
ANSWER:A
Question: At a particular graduation party with 220 guests, 70% of the guests brought gifts, and 40% of the female guests brought gifts. If 12 males did not bring gifts to the party, how many females did bring gifts?
A.18
B.36
C.42
D.68
Answer: B.36
Explanation: the correct method
total = 220..
70% of 220= 154 got gifts..
66 did not get gift, out of which 12 are males, so remaining 60-12=54 are females..
But 40% females brought gift, so 60% did not get it..
so 60% = 54, 100%= 54*100/60= 90..
ans 40% of 90 =36
B
Question: A car traveled 480 miles per tankful of gasoline on the highway and 336 miles per tankful of gasoline in the city. If the car traveled 6 fewer miles per gallon in the city than on the highway, how many miles per gallon did the car travel in the city?
A.14
B.16
C.21
D.22
Answer: A.14
Explanation: Let the speed in highway be h mpg and in city be c mpg.
h = c+6
h miles are covered in 1 gallon
462 miles will be covered in 462/h.
Similarly c miles are covered in 1 gallon
336 miles will be covered in 336/c.
Both should be same (as car's fuel capacity does not change with speed)
=> 336/c = 480/h
=> 336/c = 480/(c+6)
=> 336c+336*6=480c
=>c=336*6/144 =14
Answer A.
Question: Ramesh has solved 108 questions in an examination. If he
got only ‘0’ marks, then how many questions were wrong
when one mark is given for each one correct answer and 1/3
mark is subtracted on each wrong answer.
A.78
B.79
C.80
D.81
Answer: D.81
Explanation: If Ramesh attempts 'x' questions correct and 'y' questions wrong, then
x + y=108 ---(i) &
x - (1/3)y=0 ---(ii)
On solving x=27, y=81
ANSWER:D
Question: Sara bought both German chocolate and Swiss chocolate for some cakes she was baking. The Swiss chocolate cost $2.5 per pound, and German chocolate cost $1.5 per pound. if the total the she spent on chocolate was $30 and both types of chocolate were purchased in whole number of pounds, how many total pounds of chocolate she purchased?
A.7
B.18
C.10
D.12
Answer: B.18
Explanation: If there were all the expensive ones 2.5....
There would be 30/2.5 or 12 of them but since 1.5$ ones are also there, answer has to be >12....
If all were 1.5$ ones, there will be 30/1.5 or 20...
So ONLY 18 is left
Ans B..
Question: A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.340
B.350
C.360
D.370
Answer: B.350
Explanation: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.
Answer: Option B
Question: In a river flowing at 2 km/hr, a boat travels 72 km upstream and then returns downstream to the starting point. If its speed in still water be 6 km/hr, find the total journey time.
A.10 hours
B.12 hours
C.14 hours
D.27 hours
Answer: D.27 hours
Explanation: Explanation :
speed of the boat = 6 km/hr
Speed downstream = (6+2) = 8 km/hr
Speed upstream = (6-2) = 4 km/hr
Distance travelled downstream = Distance travelled upstream = 72 km
Total time taken = Time taken downstream + Time taken upstream
= (72/8) + (72/4) = 27 hr. Answer : Option D
Question: Each week a restaurant serving Mexican food uses the same volume of chili paste, which comes in either 25-ounce cans or 15-ounce cans of chili paste. If the restaurant must order 30 more of the smaller cans than the larger cans to fulfill its weekly needs, then how manysmallercans are required to fulfill its weekly needs?
A.60
B.70
C.75
D.100
Answer: C.75
Explanation: let x be the number of 25 ounce cans. Therefore (x+30) is the number of 15 ounce cans.
Total volume is same, therefore
25x=15(x+30)
10x=450
x=45
Therefore, number of 15 ounce cans=45+30=75
Ans - C
Question: If x^2 + y^2 = 2xy, then (x+y)^2 =
A.x^2
B.3x^2
C.4xy
D.2y^2
Answer: C.4xy
Explanation: Its B
x^2 +y^2 = 2xy
Add 2xy on both sides we get
x^2 +y^2+2xy = 2xy+2xy
(x+y)^2=4xy
Correct Option : C
Question: A company D has 30 percent of the employees are secretaries and 20 percent are salespeople. If there are 60 other employees of Company D, how many employees does Company D have?
A.120
B.162
C.180
D.152
Answer: A.120
Explanation: Let the total number of employees in the company be x
% of secretaries = 30%
% of salespeople = 20%
% of of employees other than secretaries and salespeople = 100 - 50 = 50%
But this number is given as 60
so 50% of x = 60
x = 120
Therefore there a total of 120 employees in the company D
Correct answer - A