RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: One decade ago, X was half of Y in age. If the proportion of their current ages is 3:4, what will be the overall of their current ages?
A.35 years
B.44 years
C.76 years
D.55 years
Answer: A.35 years
Explanation: A
35 years
Let the ages of X and Y 1 decade ago be A and 2A years correspondingly.
Then, [ (A +10)/2A+10) ] = (3/4)
4 (A – 10) = 3(2A – 10)
2A = 10
A = 5
Therefore,
Sum of theircurrent ages = (A + 10) + (2A + 10) = (3A + 20)
= 35 years.
Question: Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $200, what were her original savings?
A.$500
B.$600
C.$700
D.$800
Answer: D.$800
Explanation: If Linda spent 3/4 of her savings on furnitute, the rest
4 / 4 - 3 / 4 = 1 / 4 on a TV
But the TV cost her $200. So 1 / 4 of her savings is $200. So her original savings are 4 times $200 = $800
correct answer D
Question: Two water pumps, working simultaneously at their respective constant rates, took exactly 6 hours to fill a swimming pool. If the constant rate of one pump was 1.5 times the constant rate of the other, how many hours would it have taken the faster pump to fill the pool if it had worked alone at its constant rate?
A.7
B.8
C.9
D.10
Answer: D.10
Explanation: Let the rate of the slow pump be x. Then the rate of the fast pump is 1.5x.
(x+1.5x)*6 = 2.5x*6 = 15x, which is the capacity of the whole pool.
Working alone:
1.5x*Time = 15x
Time = 15/1.5 = 10 hours
The answer is D.
Question: Find large number from below question The difference of two numbers is 250. On dividing the larger number by the smaller, we get 5 as quotient and the 14 as remainder
A.120
B.135
C.140
D.309
Answer: D.309
Explanation: Let the smaller number be x. Then larger number = (x + 250).
x + 250= 5x + 14
4x = 236
x = 59
Large number = 59+250 = 309
D
Question: Entry fee in an exhibition is $1. Later this was reduced by 25% which increased the sale by 20%. The percentage increase in the number of visitors is?
A.20%
B.40%
C.50%
D.60%
Answer: D.60%
Explanation: Let the total original sale be $100
Then original number of visitors = 100
New number of visitors = 120/0.75 = 160
Increase % = 60%
Answer is D
Question: A train 400 m long can cross an electric pole in 20 sec and then find the speed of the train?
A.17 Kmph
B.26 Kmph
C.72 Kmph
D.66 Kmph
Answer: C.72 Kmph
Explanation: Length = Speed * time
Speed = L/T
S = 400/20
S = 20 M/Sec
Speed= 20*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 72 Kmph
Answer:C
Question: Kate and Danny each have $10. Together, they flip a fair coin 5 times. Every time the coin lands on heads, Kate gives Danny $1. Every time the coin lands on tails, Danny gives Kate $1. After the five coin flips, what is the probability R that Kate has more than $10 but less than $15?
A.5/16
B.1/2
C.R=12/30
D.R=15/32
Answer: D.R=15/32
Explanation: For 21 heads Kate will end up with < $10 and we want her to win. Therefore, only possibilities are 3 or 4 heads.
I made an educated guess and it worked fine.
Ans- 'D'
MGMAT's anagram helped here as well.
HHHHT = 5!/4!*1! = 5
HHHTT = 5!/3!*2! = 10
Total acceptable cases = 15
Total cases = 32
P = 15/32.D
Question: An escalator moves towards the top level at the rate of 8 ft.sec and its length is 160 feet. If a person walks on the moving escalator at the rate of 2 feet per second towards the top level, how much time does he take to cover the entire length.
A.14 sec
B.10 sec
C.16 sec
D.8 sec
Answer: C.16 sec
Explanation: Time taken to cover the entire length = tot.dist/resultant speed
= 160/ (8+2)
= 16sec
ANSWER:C
Question: The G.C.D. of 1.08, 0.36 and 0.9 is:
A.0.03
B.0.9
C.0.18
D.0.108
Answer: C.0.18
Explanation: Given numbers are 1.08, 0.36 and 0.90. H.C.F. of 108, 36 and 90 is 18,
H.C.F. of given numbers = 0.18.
Answer: Option C
Question: If r and s are positive integers, and r^2 + r/s is an odd integer, which of the following cannot be even?
A.3r + 2s
B.(r-1)(s+2)
C.r^(s+1) + s^r
D.r^3 +3
Answer: D.r^3 +3
Explanation: Given: r and s are positive integers, and r2r2 + r/s is an odd integer
What are some "nice" values that make this true?
How about r = 2 and s = 2. We get: 2222 + 2/2 = 4 + 1 = 5, which IS an odd integer
Great, now let's plug r = 2 and s = 2 into each answer choice.
A. 3(2) + 2(2) = 10, which is even. so ELIMINATE A
B. (2 - 1)(2 + 2) = 4, which is even. so ELIMINATE B
C. 2^(2+1) + 2^2 = 12, which is even. so ELIMINATE C
D. 23+323+3 = 11, which is odd. so KEEP D for now
E. 24+424+4 = 20, which is even. so ELIMINATE E
By the process of elimination, the answer must be D
Question: 117 + 1.017 + 0.117 + 1.0017 = ?
A.109.3657
B.119.7563
C.119.1357
D.119.5637
Answer: C.119.1357
Explanation: 117
1.017
0.117
+ 1.0017
--------
119.1357
---------
Answer is C.
Question: A person bought an article and sold it at a loss of 10%. If he had bought it for 20% less and sold it for $75 less, he could have gained 25%. What is the cost price?
A.220
B.274
C.250
D.280
Answer: C.250
Explanation: C
250
$250
CP1 = 100 SP1 = 90
CP2 = 80 SP2 = 80 * (140/100) = 112
22 ----- 100
55 ----- ? => $250
Question: A cement mixture is composed of 3 elements. By weight, 1/4 of the mixture is sand, 2/5 of the mixture is water, and the remaining 14 pounds of the mixture is gravel. What is the weight of the entire mixture in pounds?
A.9
B.14
C.28
D.40
Answer: D.40
Explanation: Let the total weight be x.
Sand content= (1/4)x
Water content= (2/5)x
Gravel=x-(1/4)x-(2/5)x=(7/20)x=14
x=40
Then answer will be D=40
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1120?
A.1000
B.1991
C.2888
D.1777
Answer: A.1000
Explanation: 1120 = P [1 + (5*12/5)/100]
P= 1000
Answer:A
Question: The areas of the two spheres are in the ratio 1: 4. The ratio of their volume is?
A.1 : 4
B.1 : 9
C.1 : 8
D.1 : 3
Answer: C.1 : 8
Explanation: 4πr12 : 4πr22 = 1 : 4
r1 : r2 = 1 : 2
4/3 πr13 : 4/3 πr23
r13 : r23 = 1 : 8
Answer: C
Question: Cost is expressed by the formula tb^4. If b is doubled, the new cost R is what percent of the original cost?
A.R=200
B.R=600
C.R=800
D.R=1600
Answer: D.R=1600
Explanation: Original Cost C1=t1*b1^4
New Cost C2= t2*b2^4....only b is doubled so t2=t1 and b2=2b1
C2=t2*(2b1)^4
=16(t1*b1^4)
=16C1
16 times C1=>1600% of C1
Ans D=1600
Question: In what ratio must a grocer mix two varieties of pulses costing Rs.15 and Rs.20 per kg respectively so as to get a mixture worth Rs.16.50 per Kg?
A.3 : 7
B.5 : 7
C.7 : 3
D.7 : 5
Answer: C.7 : 3
Explanation: Solution
Required ratio = 3.50 : 1.50 = 35 : 15 = 7 : 3.
Answer C
Question: A thief goes away with a SANTRO car at a speed of 40 kmph. The theft has been discovered after half an hour and the owner sets off in a bike at 50 kmph when will the owner over take the thief from the start?
A.2 hours
B.7 hours
C.5 hours
D.9 hours
Answer: A.2 hours
Explanation: |-----------20--------------------|
50 40
D = 20
RS = 50 – 40 = 10
T = 20/10 = 2 hours
Answer: A
Question: A man walks at a rate of 10 mph. After every ten miles, he rests for 6 minutes. How much time does he take to walk 40 miles?
A. 258
B. 318
C. 322
D. 324
Answer: A. 258
Explanation: To cover 40 miles the man needs (time) = (distance)/(rate) = 40/10 = 4 hours = 240 minutes. He will also rest 3 times (after 10, 20, and 30 miles), so total resting time = 3*6 = 18 minutes.
Total time = 240 + 18 = 258 minutes.
Answer: A.
Question: What is the difference between the CI on Rs. 5000 for 1 years at 4% per annum CI yearly and half yearly?
A.Rs. 2.04
B.Rs. 3
C.Rs. 4.50
D.Rs. 5
Answer: A.Rs. 2.04
Explanation: C.I. when interest
compounded yearly
= Rs. 5000 x 1 + 4 x 1 + x 4
100 100
= Rs. 5000 x 26 x 51
25 50
= Rs. 5304.
C.I. when interest is
compounded half-yearly
= Rs. 5000 x 1 + 2 3
100
= Rs. 5000 x 51 x 51 x 51
50 50 50
= Rs. 5306.04
Difference = Rs. (5306.04 - 5304) = Rs. 2.04
A
Question: Of the female students at Barkely University, 1/6 are on the honor roll. Of the male students, 2/5 are on the honor roll. If 3/5 of the students are female, what is ratio of male to female students on honor roll?
A.8/5
B.3/15
C.23/30
D.43/60
Answer: A.8/5
Explanation: let the total students be 100
given 3/5 of the students are females = 60
then males = 2/5 = 40
1/6 of the females are on honor roll = 10
males on the honor roll = 2/5= 16
ratio of M:F students on honor roll = 16/10 = 8/5
A
Question: A and B can do a piece of work in 3 days, B and C in 4 days, C and A in 6 days. How long will C take to do it?
A.33 days
B.27 days
C.24 days
D.18 days
Answer: C.24 days
Explanation: 2c = 1/4 + 1/6 – 1/3 = 1/12
c = 1/24 => 24 days
Answer: C
Question: If 4 men can colour 48 m long cloth in 2 days, then 5 men can colour 36 m long cloth in
A.1.2 day
B.2.0 days
C.3 days
D.4.2 days
Answer: A.1.2 day
Explanation: The length of cloth painted by one man in one day = 48 / 4 × 2 = 6 m
No. of days required to paint 36 m cloth by 6 men = 36/ 6 × 5 = 1.2 day.
A
Question: If s=1 and (s-b)/c = 1 which of the following is NOT a possible value of b?
A.-2
B.-1
C.0
D.1
Answer: D.1
Explanation: Equation is:
(s-b)/c = 1 where s = 1
so plug in 1 for s and look at it again
(1-b)/c = 1
now C can be anything we want, so if b = -2 we can plug it in and make it work
(1-(-2))/c = 1
3/c = 1
c = 3 and it works
HOWEVER, if we have a 0 in the numerator there isn't a number on earth that makes 0/C = 1
(1-1)/c = 1
0/c = 1
there aren't any matches for C to make this true
B cannot be 1.
Answer is D
Question: A certain factory employed 600 men and 400 women and the average wager was Rs. 25.50 per day, If a woman got Rs. 5 less than a man, then what are their daily wages ?
A.m:25.50 w:27.50
B.m:27.50 w:22.50
C.m:26.50 w:27.50
D.m: 24.50 w:26.50
Answer: B.m:27.50 w:22.50
Explanation: Explanation:
Let the daily wage of a man be Rs. x.
Then, daily wage of a woman = Rs. (x - 5).
Now, 600x + 400 (x - 5) = 25.50 * (600 + 400) <=> 1000x = 27500 <=> x = 27.50.
Man's daily wages = Rs. 27.50; Woman's daily wages = (x - 5) = Rs. 22.50. Answer: B
Question: Find the greatest number which divides 83, 125 and 209 leaving the same remainder in each case.
A.19
B.17
C.42
D.23
Answer: C.42
Explanation: The greatest number which divides three dividends p, q and r leaving the same remainder in each case is given by H.C.F(any two of (q - p), (r - p) and (r - q)).
For the given problem, p = 83, q = 125 and r = 209.
Hence the greatest number which divides these three leaving the same remainder in each case is H.C.F(any two of (125 - 83, 209 - 83, 209 - 125) = 42.
ANSWER:C
Question: A student multiplied a number by 3/5 instead of 5/3. What is the percentage error.
A.64%
B.65%
C.66%
D.67%
Answer: A.64%
Explanation: Explanation:
Let the number be x,
then,
5/3−3/5=16/15x
Error% =
(16/15x∗3/5∗100)
Answer: Option A
Question: 9 men or 6 women can do a piece of work in 20 days. In how many days will 12 men and 8 women do the same work?
A.12/9 days
B.15/2 days
C.82/8 days
D.22/76 days
Answer: B.15/2 days
Explanation: 9M = 6W ---- 20 days
12M + 8W -----?
8W + 8 W = 16W ---?
6W ---- 20 16 -----?
6 * 20 = 16 * x => x = 15/2 days
Answer:B
Question: The average of temperatures at noontime from Monday to Friday is 60; the lowest one is 50, what is the possible maximum range of the temperatures?
A.50
B.25
C.40
D.45
Answer: A.50
Explanation: Average=60, Sum of temperatures=60*5=300
As the min temperature is 50, max would be 300-4*50=100 --> The range=100(max)-50(min)=50
Answer: A
Question: Two friends A and B apply for a job in the same company. The chances of A getting selected is 2/5 and that of B is 4/7. What is the probability that both of them get selected?
A.8/35
B.34/35
C.27/35
D.21/32
Answer: A.8/35
Explanation: Solution:
P(A) = 2/5
P(B) = 4/7
E = {A and B both get selected}
P(E) = P(A)*P(B)
= 2/5 * 4/7
= 8/35
ANSWER IS A
Question: A certain no. when divided by 50 leaves a remainder 25, what is the remainder if the same no.be divided by 15?
A.2
B.4
C.5
D.8
Answer: C.5
Explanation: Explanation:
50 + 25 = 75/15 = 5 (Remainder)
C
Question: Pandiyan buys an old scooter for Rs. 6000 and spends Rs. 600 on its repairs. If he sells the scooter for Rs. 7200, his gain percent is :
A.20%
B.12%
C.9.09%
D.5%
Answer: C.9.09%
Explanation: Explanation :
Solution: C.P. =Rs. (6000+600) =Rs. 6600; S.P. = Rs. 7200.
Gain% = 7200-6600/6600*100 = 9.09%
Answer : C
Question: Two tains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:
A.12
B.24
C.36
D.48
Answer: C.36
Explanation: Sol.
Let the speed of each train be x m/sec.
Then, relative speed of the two trains = 2x m/sec.
So, 2x = (120 + 120)/12 ⇔ 2x = 20 ⇔ x = 10.
∴ Speed of each train = 10 m/sec = [10 * 18/5] km/hr = 36 km/hr.
Answer C
Question: If a certain sample of data has a mean of 25.0 and a standard deviation of 3.0, which of the following values is more than 2.5 standard deviations from the mean?
A.12.0
B.13.5
C.17.0
D.23.5
Answer: C.17.0
Explanation: Value ismore than 2.5SDfrom the mean means that the distance between the mean and the value must be more than 2.5*SD=7.5. So the value must be either less than 25-7.5=17.5.5or more than 25+7.5=32.5.
Answer: C.
Question: The number 0.650 is how much greater than 1/8 ?
A.½
B.21/40
C.1/50
D.1/500
Answer: B.21/40
Explanation: let x be the difference
then
.65-1/8=x
65/100-1/8=x
x=21/40
ans B
Question: Which of the following multipliers will cause a number to be increased by 29.7%?
A.1.297
B.12.97
C.129.7
D.1297
Answer: D.1297
Explanation: Solution
Let the number be 100 and required multiplier be y.
Then, 100y = 129.7
y = 129.7 / 100
= 1.297
Answer D
Question: How many diagonals does a polygon with 17 sides have, if one of its vertices does not connect to any diagonal?
A.102
B.104
C.110
D.90
Answer: B.104
Explanation: If I calculate it using the formulae, #diagonals = n (n-3)/2Each vertex sends of n-3 diagonals
n= 17-1 then 16*(16-3)/2 = 104
Correct Option:	B
Question: If two numbers are in the ratio 2:3. If 5 is added to both of the numbers then the ratio becomes 3:4 then find the smallest number?
A.A)10
B.B)20
C.C)25
D.D)30
Answer: A.A)10
Explanation: 2:3
2x + 10 : 3x + 10 = 3 : 4
4[2x + 5] = 3[3x + 5]
8x + 20 = 9x + 15
9x - 8x = 20 - 15
x = 5
Then smallest number is = 2
2x = 10
Correct Option A
Question: √(14)^2
A.7
B.14
C.49
D.21
Answer: B.14
Explanation: explanation
√(14)^2 =?
or, ? = 14
Answer B
Question: 12 men work 8 hours per day to complete the work in 10 days. To complete the same work in 8 days, working 15 hours a day, the number of men required?
A.8 days
B.9 days
C.11 days
D.13 days
Answer: A.8 days
Explanation: That is, 1 work done = 12 × 8 × 10
Then, 12 8 × 10 = ? × 15 × 8
? (i.e. No. of men required) = 12 × 8 × 10/15× 10 = 8 days.
A)
Question: The sale price sarees listed for Rs.400 after successive discount is 15% and 5% is?
A.297
B.879
C.323
D.762
Answer: C.323
Explanation: 400*(85/100)*(95/100)
= 323
Answer: C
Question: Nitin borrowed some money at the rate of 6% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years. If the total interest paid by him at the end of eleven years is Rs. 9180, how much money did he borrow?
A.9000
B.80288
C.2668
D.2600
Answer: A.9000
Explanation: Let the sum be Rs. x. Then,
[(x * 6 * 3)/100] + [(x * 9 * 5)/100] + [(x * 13 * 3)/100] = 9180
18x + 45x + 39x = (9180 * 100)
102x = 918000 => x = 9000.
Answer:A
Question: If a trader sold two cars each at Rs. 325475 and gains 12% on the first and loses 12% on the second, then his profit or loss percent on the whole is?
A.1.44
B.1.42
C.1.49
D.1.42
Answer: A.1.44
Explanation: SP of each car is Rs. 325475, he gains 12% on first car and losses 12% on second car.
In this case, there will be loss and percentage of loss is given by = [(profit%)(loss%)]/100 = (12)(12)/100 % = 1.44%
Answer:A
Question: The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 2 years hence?
A.58
B.59
C.64
D.70
Answer: C.64
Explanation: Explanation:
A + B = 60, A = 2B
2B + B = 60 => B = 20 then A = 40.
2 years, their ages will be 42 and 22.
Sum of their ages = 42 + 22 = 64.
C)
Question: A, B and C can do a work in 6, 9 and 12 days respectively doing the work together and get a payment of Rs.1800. What is B’s share?
A.Rs.245.8
B.Rs.653.8
C.Rs.300
D.Rs.400
Answer: B.Rs.653.8
Explanation: WC = 1/6:1/9:1/12 => 6:4:3
4/13 * 1800 = 653.8
ANSWER:B
Question: A large kennel has a gate for dogs to enter and a gate for dogs to exit. The kennel can be filled with dogs who use the entrance in 5 hours. The exit gate can be used to empty the kennel in 15 hours. If it is desired that the kennel should be filled, from empty, exactly 6 hours after the entrance gate is opened at 9:30am, then at what time should the exit gate be opened ?
A.10:00am
B.10:45am
C.12:00pm
D.12:30pm
Answer: D.12:30pm
Explanation: In 6 hours the entrance gate can accept the amount of dogs equal to 6*1/5 = 6/5 of the kennel. So, 1/5 more than necessary, which should be compensated by the exit gate. To ride the kennel 1/5 of the dogs the exit gate needs 15/5 = 3 hours.
Therefore, the exit gate should be opened at 9:30am + 6 hours - 3 hours = 12:30pm.
Answer: D.
Question: On a trip, a cyclist averaged 8 miles per hour for the first 16 miles and 10 miles per hour for the remaining 16 miles. If the cyclist returned immediately via the same route and took a total of 6.8 hours for the round trip, what was the average speed (in miles per hour) for the return trip?
A.9
B.10
C.11
D.12
Answer: B.10
Explanation: The time to go 32 miles was 16/8+16/10=2+1.6=3.6 hours.
The average speed for the return trip was 32 miles/3.2 hours= 10 mph.
The answer is B.
Question: What is the minimum value of z for which z^2 + z - 3/14 > 0 is not true?
A. -5/7
B. -3/7
C. -1/7
D. 1/7
Answer: B. -3/7
Explanation: I think B -3/7 is the best ans...
Question: Goldenrod and No Hope are in a horse race with 7 contestants. How many different arrangements of finishes are there if No Hope always finishes before Goldenrod and if all of the horses finish the race?
A.5040
B.2520
C.1200
D.240
Answer: B.2520
Explanation: All 7 horses can finish the race in 7! way (assuming no tie).
If no tie is possible between No Hope and Goldenrod, then in half of these cases No Hope will be before Goldenrod and in half of these cases after (not necessarily right before or right after). How else? So, there are 7!/2=2520 different arrangements of finishes where No Hope always finishes before Goldenrod.
Answer: B.
Question: A person walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 8 minutes earlier. How far is the office from his house?
A.3 1/5 Km
B.2 1/5 Km
C.4 1/5 Km
D.5 1/5 Km
Answer: A.3 1/5 Km
Explanation: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 16/6
= 24/2 * 16/60
= 8 * 2/5
= 16/5 = 3 1/5 Km
Answer: Option 'A'
Question: In an increasing sequence of 6 consecutive integers, the sum of the first 4 integers is 570. What is the sum of the last 2 integers in the sequence?
A. 291
B. 290
C. 274
D. 270
Answer: A. 291
Explanation: Solution:
In solving this problem we must first remember that when we have 6 consecutive integers we can display them in terms of just 1 variable. Thus, we have the following:
Integer 1: x
Integer 2: x + 1
Integer 3: x + 2
Integer 4: x + 3
Integer 5: x + 4
Integer 6: x + 5
We are given that the sum of the first 4 integers is 570. This means that:
x + x+1 + x+2 + x+3 = 570
4x + 6 = 570
4x = 564
x = 141
The sum of the last 2 integers can be expressed and simplified as:
x+4 + x+5 = 2x + 9
Substituting 141 for x yields:
(2)(141) + 9 = 291
Answer: A
Question: Sandy can do a job in 15 days and Molly can do the same job in 30 days. If they work together, in how many days will they complete the job?
A.8
B.9
C.10
D.11
Answer: C.10
Explanation: Sandy can do 1/15 of the job each day.
Molly can do 1/30 of the job each day.
The combined rate is 1/15 + 1/30 = 1/10 of the job each day.
The job will take 10 days.
The answer is C.
Question: How many 5 letter combinations can be made from the letters of the word VERMONT if the first letter has to be a vowel and the last letter has to be a consonant, and repetition is allowed?
A.3441
B.3433
C.3333
D.3430
Answer: D.3430
Explanation: Vowel: E O
Consonants: V R M N T
First letter can be filled in 2 Ways ( As the question states that first letter has to be a vowel)
Fifth letter can be filled in 5 Ways ( As the question states that the last letter has to be a consonant)
Second letter can be filled in 7 Ways
Third letter can be filled in 7 Ways
Fourth letter can be filled in 7 Ways
So, Total number of ways = 2 Ways x 7 Ways x 7 ways x 7 ways x 5 ways = 3430
Answer D
Question: 5, 9, 17, 29, 45, ?
A.49
B.87
C.60
D.65
Answer: D.65
Explanation: D
65
The pattern is + 4, + 8, + 12, + 16, ....
Question: The present ages of A,B & C are in proportions 4:7:9. 8 years ago, the sum of their ages was 56. What are their present ages?
A.10,20 and 36
B.16,22 and 36
C.16,28 and 36
D.14,18 and 36
Answer: C.16,28 and 36
Explanation: Let present age of A,B and C be 4x,7x and 9x respectively.
(4x−8)+(7x−8)+(9x−8)=56⇒20x=80⇒x=4
Hence present age of A, B and C are
4×4, 7×4 and 9×4 respectively.
i.e., 16,28 and 36 respectively.
C
Question: A train 300m long takes 10 sec to cross a man walking at 5kmph in a direction opposite to that of the train. Find the speed of the train?
A.A)175kmph
B.B)113kmph
C.C)162kmph
D.D)145kmph
Answer: B.B)113kmph
Explanation: Let the speed of the train be x kmph
Speed of the train relative to man = x+5 = (x+5)*5/18 m/sec
300/[(x+5)*5/18] = 10
10(x+5) = 60*18
x = 175kmph
Answer is B
Question: A train 250 m long passed a pole in 10 sec. How long will it take to pass a platform 1250 m long?
A.60 sec
B.90 sec
C.120 sec
D.150 sec
Answer: A.60 sec
Explanation: Speed = 250/10 = 25 m/sec.
Required time = (250 + 1250)/25 = 60 sec
Answer:A
Question: Two horses begin running on an oval course at the same time. One runs each lap in 4 minutes; the other takes 16 minutes to run each lap. How Many minutes after the start will the faster horse have a one lap lead?
A.36
B.12
C.16/3
D.4
Answer: C.16/3
Explanation: The rate of the faster horse is 1/4 lap/minute;
The rate of the slower horse is 1/16 lap/minute;
Their relative rate is 1/4-1/16=3/16 lap/minute;
The faster horse to gain one full lap will need time=distance/rate=1/(3/16)=16/3 minutes.
Answer: C
Question: Two tailors x and y are paid a total of $100 per week by their employer. If x is paid 150% of the sum paid to y. How much is y paid per week?
A.28.6
B.15.9
C.36.3
D.45.5
Answer: A.28.6
Explanation: Let the sum paid to y per week be $z
then, z+150% of z = 100
z+(150/100)z = 100
z = 28.6
Answer is A
Question: 1100 boys and 700 girls are examined in a test; 45% of the boys and 30% of the girls pass. The percentage of the total who failed is ?
A.A)63.3%
B.B)60.8%
C.C)81.2%
D.D)75.4%
Answer: B.B)60.8%
Explanation: Total number of students = 1100+700 = 1800
Number of students passed = (45% of 1100+30% of 700) = 495+210 = 705
number of failures = 1095*100/1800 = 60.8%
Answer is B
Question: z, b, and c are positive integers. If z, b, and c are assembled into the six-digit number zbczbc, which one of the following must be a factor of zbczbc?
A. 16
B. 13
C. 5
D. 3
Answer: B. 13
Explanation: Plug in some values and check -
zbczbc = 123123
Not divisible by 16 and 5
let zbczbc = 125125
Not divisible by 3
Only option (B) and (E) is left in both the cases...
Check once more to marke (B) as correct answer
let zbczbc = 135135
Again divisible by 13
So, mark answer as (B) 13
Question: A company recently conducted a survey and found that 25,000 of its customers live in rural areas. If the number of customers who live in urban areas is 120 percent greater than the number of customers who live in rural areas, how many customers live in urban areas?
A.50,000
B.55,000
C.60,000
D.65,000
Answer: B.55,000
Explanation: The number of customers in urban areas is 25,000+1.2*25,000=55,000.
The answer is B.
Question: The lenght of a room is 5.5 m and width is 4 m. Find the cost of paving the floor by slabs at the rate of Rs. 900 per sq. metre.
A.s. 19,800
B.s. 15,600
C.s. 16,500
D.s. 17,600
Answer: A.s. 19,800
Explanation: Area of the floor = (5.5 Ã— 4) m2 = 22 m2.
Cost of paving = Rs. (900 Ã— 22) = Rs. 19800
Answer: Option A