RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A fruit-salad mixture consists of apples, peaches, and grapes in the ratio 12:8:7, respectively, by weight. If 54 pounds of the mixture is prepared, the mixture includes how many more pounds of apples than grapes?
A.15
B.10
C.9
D.6
Answer: B.10
Explanation: We can first set up our ratio using variable multipliers. We are given that a fruit-salad mixture consists of apples, peaches, and grapes, in the ratio of 6:5:2, respectively, by weight. Thus, we can say:
apples : peaches : grapes = 12x : 8x : 7x
We are given that 54 pounds of the mixture is prepared so we can set up the following question and determine a value for x:
12x + 8x + 7x = 54
27x = 54
x = 2
Now we can determine the number of pounds of apples and of grapes.
pounds of grapes = (7)(2) = 14
pounds of apples = (12)(2) = 24
Thus we know that there are 24-14 = 10 more pounds of apples than grapes.
Answer is B.
Question: In what time will a railway train 30 m long moving at the rate of 36 kmph pass a telegraph post on its way?
A.5 sec
B.4 sec
C.3 sec
D.6 sec
Answer: C.3 sec
Explanation: T = 30/36 * 18/5 = 3 sec
Answer: C
Question: Angelina walked 600 meters from her home to the grocery at a constant speed. She then walked 480 meters to the gym at double the speed. She spent 40 seconds less on her way from the grocery to the gym than on her way from home to the grocery. What was Angelina's speed, in meters per second, from the grocery to the gym?
A.2
B.3
C.4
D.9
Answer: D.9
Explanation: let the speed be X...
so time taken from home to grocery= 600/x..
the speed to gym = 2x..
so time taken = 480/2x=240/x..
its given 600/x-240/x=40..
360/x=40..
x=9m/secs..
so grocery to gym=2*9=18m/s...
D
Question: An alchemist discovered that the formula expressing the correct proportions needed to turn ordinary metal into gold is G = 3/2M + 15, where G is the number of gold bars and M is the number of metal bars. If a metal bar weighs twice as much as a gold bar, how many metal bars will yield an equal weight of gold?
A.10
B.15
C.22.5
D.30
Answer: D.30
Explanation: Plug in the answer choices!
A --- 30/2 + 15 = 30 --- wrong
B --- 45/2 + 15 = not an integer --- wrong
C --- 22.5(3/2) + 15 = not an integer --- wrong
D --- 90/2+15 = 60 --- CORRECT
ANSWER:D
Question: It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
A.(296 + 1)
B.(216 + 1)
C.(216 - 1)
D.(217 - 1)
Answer: A.(296 + 1)
Explanation: Let 232 = x. Then, (232 + 1) = (x + 1).
Let (x + 1) be completely divisible by the natural number N. Then,
(296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
Option A
Question: If ‘DELHI’ is coded as ‘FGNJK’, then ‘PUNE’ is coded as
A.RWPG
B.TGFR
C.UHTG
D.WEDS
Answer: A.RWPG
Explanation: D= 4 = 4+2 = 6 = F
E = 5 = 5+2= 7= G
SIMILARLY,
P = 16 = 16+2 = 18 =R
U = 21 = 21+2 =23 =W
N = 14 = 14+2 =16 = P
E = 5 = 5+2 = 7 = G
SO ANS IS
RWPG
Question: David and Lewis leave Chennai for Hyderabad simultaneously at 8 P.M in the night driving in two cars at speeds of 50 mph and 70 mph respectively. As soon as Lewis reaches Hyderabad he returns back to Chennai along the same route and meets David on the way back. If the distance between the two cities is 350 miles, how far from Chennai did David and Lewis meet?
A.250 miles
B.240 miles
C.230 miles
D.235 miles
Answer: A.250 miles
Explanation: Time taken by Lewis to reach Hyderabad = 350/70 = 5 hours
In 5 hours, David travels 50*5 = 250 miles
So distance at which they meet should be greater than 250 miles.
Only A satisfies.
Answer is A.
Question: How many Q ways can you group 3 people from 4 sets of twins if no two people from the same set of twins can be chosen?
A.3
B.16
C.28
D.32
Answer: D.32
Explanation: Ways to select 3 people from 8 people (4 twins x 2) = 8C3 = 56
Ways to select 1 twin + 1 people = 4C1*6C1 = 24
Ways to select a group 3 people from 4 sets of twins if no two people from the same set of twins can be chosen Q= 56 - 24 = 32
Ans: D
Question: A salesman sold twice as much pears in the afternoon than in the morning. If he sold $450 kilograms of pears that day, how many kilograms did he sell in the afternoon?
A.120
B.180
C.300
D.280
Answer: C.300
Explanation: 3x=450
x=150
Therefore, the salesman sold 150kg in the morning and 2⋅150=300 kg in the afternoon. So answer is C.
Question: A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that exactly three bulbs are good.
A. 20/31
A.80/63
B.20/63
C.20/93
D.20/03
Answer: B.20/63
Explanation: Explanation:
Required probability = (⁵C₃ . ⁴C₁)/⁹C₄ = (10 * 4)/126 = 20/63
Answer: Option B
Question: In a certain supermarket, a triangular display of cans is arranged in 9 rows, numbered 1 through 9 from top to bottom. Each successively numbered row contains 3 more cans than the row immediately above it. If there are fewer than 120 cans in the entire display, how many cans are in the seventh row?
A.13
B.15
C.17
D.19
Answer: D.19
Explanation: Let x be the number of cans in row 1.
The total number of cans is x + (x+3) + ... + (x+24) =
9x + 3(1+2+...+8) =
9x + 3(8)(9)/2 =
9x + 108
Since the total is less than 120, x must equal 1.
The number of cans in the 7th row is 1 + 3(6) = 19
The answer is D.
Question: By travelling at 40 kmph, a person reaches his destination on time. He covered two-third the total distance in one-third of the total time. What speed should he maintain for the remaining distance to reach his destination on time?
A.20 kmph
B.17 kmph
C.15 kmph
D.14 kmph
Answer: A.20 kmph
Explanation: Let the time taken to reach the destination be 3x hours. Total distance
= 40 * 3x = 120x km
He covered 2/3 * 120x
= 80x km in 1/3 * 3x
= x hours So, the remaining 40x km, he has to cover in 2x hours. Required speed
= 40x/2x = 20 kmph.
Answer:A
Question: If a and b are the two values of t that satisfy
the equation t^2 â€“ 12t + 20 = 0, with a > b, what is the value of a â€“ b?
A.2
B.4
C.6
D.8
Answer: D.8
Explanation: Factor the left side of the equation:
t^2 â€“ 12t + 20 = 0
(t â€“ 2)(t â€“ 10) = 0
t = 2, t = 10
Thus, a = 10 and b = 2. So a â€“ b = 10 â€“ 2 = 8.
The answer is D.
Question: Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1120?
A.1000
B.2877
C.2769
D.2776
Answer: A.1000
Explanation: 1120 = P [1 + (5*12/5)/100]
P= 1000
Answer:A
Question: If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 3 years the amount to be paid is?
A.3377
B.2688
C.2688
D.8436
Answer: D.8436
Explanation: A = 7500(26/25)^3 = 8436
Answer: D
Question: Which is the odd number out?
9421, 7532, 9854, 8612, 6531, 8541
A.8612
B.8626
C.2579
D.6642
Answer: A.8612
Explanation: C
8612.
All the other numbers have their digits in descending order.
Question: Which of the following can be a perimeter q of a triangle inscribed in a circle of radius 1?
I. 0.001
II. 0.010
III. 0.100
A.I only
B.III only
C.II and III only
D.I, II, and III
Answer: D.I, II, and III
Explanation: Yes,the length of any side of a triangle must be larger than the positive difference of the other two sides, but smaller than the sum of the other two sides.
But how do you use the above property to solve the question?
The lower limit of the perimeter of an inscribed triangle in a circle of ANY radius is 0: q>0.
Answer is D.
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
A.22
B.50
C.888
D.277
Answer: B.50
Explanation: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 => x = 50 km/hr.
Answer: B
Question: The total age of A and B is 13 years more than the total age of B and C. C is how many year younger than A
A.A)11
B.B)12
C.C)13
D.D)14
Answer: C.C)13
Explanation: Explanation:
Given that A+B = 13 + B + C
=> A – C = 13 + B – B = 13
=> C is younger than A by 13 years
Answer: Option C
Question: Niki covers a distance in 45 min , if she drives at a speed of 60 km/h on an average. Find the speed at which she must drive at to reduce the time of the journey by 50%.
A.101.02 kmph
B.121.62 kmph
C.100.62 kmph
D.111.00 kmph
Answer: B.121.62 kmph
Explanation: Given Speed = 60 Kmph.
It means Niki covered 60 km in 60 min (1 hour). So, in 45 min he will cover 45 km.
50% time reduced = 45 - 50% of 45 = 22.5 min.
Thus, Niki needs to cover 45 km in 22.5 min (0.37hour).
Speed * Time = Distance.
Speed * 0.37 = 45
Speed = 121.62 kmph.
ANSWER : OPTION B
Question: What is the difference between the place values of two fives in the numeral 7589452
A.499950
B.411150
C.500050
D.500000
Answer: A.499950
Explanation: Required difference = 500000-50 = 499950
Answer is A
Question: At the wholesale store you can buy an 8-pack of hot dogs for $1.75, a 20-pack for $3.05, and a 250-pack for $22.95. What is the greatest number of hot dogs you can buy at this store with $250?
A. 1,108
B. 2,100
C. 2,108
D. 2,628
Answer: D. 2,628
Explanation: To maximize number of hot dogs with 250$
Total number of hot dogs bought in 250-pack = 22.95*10 =229.5$
Amount remaining = 250 - 229.5 = 20.5$
Total number of hot dogs bought in 20-pack = 3.05*6 =18.3$
Amount remaining = 20.5 - 18.3 = 2.2$
Total number of hot dogs bought in 8-pack = 1.55*1 =1.55$
Amount remaining = 2.2 - 1.75 = 0.45$
This amount is too less to buy any 8- pack .
Greatest number of hot dogs one can buy with 250 $ = 250*10+20*6+8*1 = 2628
Answer D
Question: An accurate clock shows 8 o'clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 2 o'clock in the afternoon?
A.144
B.150
C.168
D.180
Answer: D.180
Explanation: Explanation :
Angle traced by hour hand in
5 hrs 10 min. = (360/12 x 6)
= 180.
Answer : D
Question: A and B can do a piece of work in 12 days and 16 days respectively. Both work for 3 days and then A goes away. Find how long will B take to complete the remaining work?
A.6 days
B.7 days
C.4 days
D.9 days
Answer: D.9 days
Explanation: 3/12 + (3 + x)/16 = 1
x = 9 days
Answer: D
Question: If cement, gravel and sand are to be mixed in 7:10:13 and 5 tons of cement is available how many tons of mixture can be produced assuming that sufficient gravel and sand is readily available.
A.35 7/8
B.36
C.34 2/7
D.21 3/7
Answer: D.21 3/7
Explanation: Cement:Gravel:Sand = 7:10:13 --> total of 7+10+13 = 30 parts.
If we use 8 tons of cement, then we'll get 5/7*30 =21 3/7 tons of mixture.
Answer: D.
Question: The avg weight of A,B & C is 84 kg. If D joins the group, the avg weight of the group becomes 80 kg.If another man E who weights is 6 kg more than D Replaces A, Then the avgof B,C,D&E becomes 79 kg. What is the weight of A?
A.45
B.65
C.75
D.78
Answer: D.78
Explanation: A + B + C = 3 *84 = 252
A + B + C + D = 4 * 80 = 320 ---- (i)
So, D = 68& E = 68 + 6 = 74
B + C + D +E = 79 * 4 = 316 --- (ii)
From Eq. (i) & (ii)
A-E = 320 – 316 = 4
A = E +4 = 74 + 4 = 78
D
Question: A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
A.1/5
B.2/5
C.3/5
D.4/5
Answer: A.1/5
Explanation: Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture = (3 -(3x/8)+ x)litres
Quantity of syrup in new mixture = (5 - 5x/8) litres
Therefore, (3 - (3x/8)	+ x)	= 5 -	5x/8)
= 5x + 24 = 40 - 5x
= 10x = 16
= x = 8/5
So, part of the mixture replaced = (8/5 x 1/8)= 1/5
Answer is A.
Question: The average of thirteen numbers is 9. The average of first six numbers is 5 and the average of last six numbers is 7. What is the middle number?
A.47
B.45
C.25
D.37
Answer: B.45
Explanation: The total of thirteen numbers = 13X9 = 117
The total of first 6 and last 6 numbers is = 6 X 5+6 X 7 = 72
So, the middle number is (117 - 72 ) = 45
B
Question: [(5/2 ÷ 1/2 × 5/2)]/[(5/2 × 1/2 ÷ 5/2)] = ?
A.25
B.20
C.18
D.16
Answer: A.25
Explanation: Explanation:
[(5/2 ÷ 1/2 × 5/2)]/[(5/2 × 1/2 ÷ 5/2)]
= [5/2 × 2/1 × 5/2]/[5/2 × 1/2 × 2/5]
= 25/2 / 1/2 = 25/2 x 2/1 = 25
Answer: Option A
Question: A man spent 1/5 of his loan amount on house construction and 1/4 of the remaining on his office renovation. How much fraction of the loan amount is he left with after spending on house and office renovation?
A.3/5
B.2/6
C.5/4
D.1/5
Answer: A.3/5
Explanation: The man spent 1/5 his loan amount on house construction, remaining amount is 4/5
He spent 1/4 of the remaining amount for office renovation, 1/4*4/5=4/20
Total loan amount spent on house and office renovation =1/5+4/20
To get a common denominator we use 20, so 1/5 is 4/20
4/20+4/20=8/20 is the total amount spent on house construction and office renovation.
remaining 12/20 is left with the man, 3/5
Answer is A
Question: If a and b are different values and a – b = 6(√a - √b), then in terms of b, a equals:
A.√b
B.b
C.b - 12√b + 36
D.b + 2√b + 1
Answer: C.b - 12√b + 36
Explanation: (√a)^2 - (√b)^2 = 6(√a - √b) -----> ( √a + √b) ( √a - √b) = 6(√a - √b) -------> √a + √b = 6, so
√a = 6 - √b, square both sides and solve. Answer is C.
Question: Kramer can pack X boxes of cigarettes per minute. If there are Y boxes of cigarettes in one case, how many cases can Kramer pack in 6 hours?
A.60X/Y.
B.360X/Y.
C.60Y/X.
D.120Y/X.
Answer: B.360X/Y.
Explanation: Kramer can pack X boxes per min.
Therefore in 6 hrs(360mins)he can pack 360X boxes.
If there are Y boxes in one case then then the total number of cases packed by Kramer = 360X/Y
(ANSWER B)
Question: The positive numbers w, x, y, and z are such that x is 30 percent greater than y, y is 20 percent greater than z, and w is 20 percent less than x. What percent greater than z is w ?
A.15.2%
B.16.0%
C.20.0%
D.23.2%
Answer: C.20.0%
Explanation: My strategy is same as theDobermanbut instead take z=100, which makes life a bit easy. As:
z=100
y=120 (20% greater than z)
z=144(20% greater than y)
Now calculate w 20% less than z = 144*80/100= 115.2
Now by just looking, relation between w and z:
w-z/z*100 = 20 - Answer
C
Question: After three successive equal percentage rise in the salary the sum of 100 rupees turned into 140 rupees and 49 paise. Find the percentage rise in the salary.
A.12%
B.22%
C.66%
D.82%
Answer: A.12%
Explanation: Solution:
We solve it through options. Choosing options for trial depends on mental thought.
100 ==12% up ==>112 ==12% up ==>125.44 ==12% Up ==> 140.49
So, answer is 12%.
Answer: Option A
Question: A and B put in Rs.300 and Rs.400 respectively into a business. A reinvests into the business his share of the first year's profit of Rs.210 where as B does not. In what ratio should they divide the second year's profit?
A.39:40
B.39:45
C.39:40
D.39:41
Answer: A.39:40
Explanation: 3: 4
A = 3/7*210 = 90
390: 400
39:40
Answer: A
Question: If x > 5 and y < -5, then which of the following must be true ?
A.x/y > 1
B.x/y < -1
C.x/y < 0
D.x + y > 0
Answer: A.x/y > 1
Explanation: Pick x=3, y = -3
A) x/y > 1 - Incorrect as x/y = -1
B) x/y < -1 - Incorrect as x/y = -1
C) x/y < 0 -Correct. It will hold for all values x > 2 and y < -2 as x/y = -1 < 0
D) x + y > 0 - Incorrect. x + y = 0
E) xy > 0 - Incorrect. XY = -9 which is less than zero.
A should be the answer.
Question: When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 15-inch boxes. If the university pays $0.70 for every box, and if the university needs 3.06 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes?
A.$255
B.$357
C.$510
D.$1,250
Answer: B.$357
Explanation: Total no. Of boxes = 3060000/(20×20×15) = 510
Total cost = 510×$0.7=$357
Answer B
Question: If 10 men can reap 80 hectares in 24 days , then how many hectares can 36 men reap in 30 days?
A.127
B.237
C.360
D.450
Answer: C.360
Explanation: Explanation:
Let the required no of hectares be x. Then
Men --- Hectares---Days
10---------80---------24
36---------x---------30
More men, More hectares (Direct proportion)
More days, More hectares (Direct proportion)
x=36/10*30/24*80
x= 360
Answer: C
Question: 8, 27, 64, 100, 125, 216, 343
A.40
B.100
C.290
D.102
Answer: B.100
Explanation: The pattern is 23, 33, 43, 53, 63, 73. But, 100 is not a perfect cube.
Question: The rate of increase of the price of sugar is observed to be two percent more than the inflation rate expressed in percentage. The price of sugar, on January 1, 1994, is Rs. 24 per kg. The inflation rate for the years 1994 and 1995 are expected to be 20% each. The expected price of sugar on January 1, 1996 would be
A.23.6
B.36.45
C.35.72
D.24.6
Answer: C.35.72
Explanation: Explanation :
Increase in the price of sugar = (20+2)= 22%
Hence, price of the sugar on Jan 1, 1996
=> (24 * 122 * 122)/( 100 * 100 ) = Rs 35.72.
Answer : C
Question: A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his average after 17th match
A.36
B.37
C.38
D.39
Answer: D.39
Explanation: Explanation:
Let the average after 17th match is x
then the average before 17th match is x-3
so 16(x-3) + 87 = 17x
=> x = 87 - 48 = 39
Answer: Option D
Question: f(1)=1,where f(x+y)=f(x)+f(y)+8xy-2.then f(7)=?
A.162
B.163
C.164
D.165
Answer: B.163
Explanation: f(1)=1
f(2)= f(1+1)= 1+1+8-2= 8
f(3) = f(2+1)= 8+1+ (8*2*1)-2 = 23
f(6)= f(3+3)= 23+23+ (8*3*3)-2= 116
f(7) = f(6+1)= 116+1+(8*6*1)-2= 163
thus ans is 163
ANSWER:B
Question: A solution contains 8 parts of water for every 7 parts of Lemonade syrup. How many parts of the solution should be removed and replaced with water so that the solution will now contain 35% lemonade syrup?
A.1.5
B.1.75
C.2.14
D.2.34
Answer: C.2.14
Explanation: Let the total solution is 150 L with 80 L water70 L syrup.
To make 35% syrup solution, the result solution must have 97.5 L syrup and 52.5 L syrup.
Therefore we are taking 17.5 L of syrup from initial solution and replacing with water.
using urinary method:
70 L syrup in 150 L solution
17.5 L syrup in 37.5 L solution
We started by multiplying 10
Now to get to the result we need to divide by 17.5 => amount of solution to be replaced with water (37.5/17.5)=2.14.
Correct option : C
Question: If Ajay completes a certain work in 8 days and Vijay can complete the same work in 24 days, find the time in which the work will be completed if both Ajay and Vijay work together.
A.6 days
B.9 days
C.2 days
D.7 days
Answer: A.6 days
Explanation: Explanation:
On working together Ajay and Vijay can complete the work in (8*24)/(8 + 24)
= 192/32
= 6 days
ANSWER: A
Question: A password of a computer used five digits where they are from 0 and 9. What is the probability that the password solely consists of prime numbers and zero?
A.1/32
B.1/16
C.1/8
D.2/5
Answer: A.1/32
Explanation: We have five digits can be used for password -0,2,3,5,7.
Assuming that the numbers can be repeated any number of times in the password, probability of selecting any one of them is 5/10 (out of 10 digits from 0-9)
So, 5/10 * 5/10 * 5/10 * 5/10 * 5/10 =1/32 (A)
Question: A pupil's marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half. The number of pupils in the class is
A.38
B.40
C.28
D.12
Answer: B.40
Explanation: Explanation:
Let there be x pupils in the class.
Total increase in marks = (x * 1/2) = x/2.
x/2 = (83 - 63) => x/2 = 20 => x = 40.
Answer: B
Question: A shopkeeper buys mangoes at the rate of 4 a rupee and sells them at 3 a rupee. Find his net profit or loss percent?
A.33 1/4 %
B.33 9/3 %
C.33 1/3 %
D.33 1/5 %
Answer: C.33 1/3 %
Explanation: The total number of mangoes bought by the shopkeeper be 12.
If he buys 4 a rupee, his CP = 3
He selling at 3 a rupee, his SP = 4
Profit = SP - CP = 4 - 3 = 1
Profit Percent = 1/3 * 100 = 33 1/3 %
Answer:C
Question: A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?
A.3630
B.3617
C.3187
D.7288
Answer: A.3630
Explanation: 6300:4200:10500
3:2:5
3/10 * 12100 = 3630
Answer: A
Question: On my sister's birthday, she was 154 cm in height, having grown 10% since the year before. How tall was she the previous year?
A.150 cm
B.140 cm
C.142 cm
D.148 cm
Answer: B.140 cm
Explanation: Let the previous year's height be x.
1.1x = 154
x = 140
The answer is B.
Question: Triangle STV has sides ST = TV = 10, and SV = 12. What is the area?
A.36
B.40
C.44
D.48
Answer: D.48
Explanation: Let the base B of the triangle be SV = 12. Then we need to find the height H.
H^2 = 100^2 - 6^2 = 64 and then H = 8.
The area is (1/2)*B*H = 6*8 = 48
The answer is D.
Question: A 240 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
A.260
B.250
C.240
D.230
Answer: A.260
Explanation: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 240)/9 = 500/9 => x = 260.
Answer: Option A
Question: I. a3 - 212 = 131,
II. b2 - 72 = -23 to solve both the equations to find the values of a and b?
A.a > b
B.a ≥ b
C.a < b
D.a ≤ b
Answer: B.a ≥ b
Explanation: a3 = 343 => a = 7
b2 = 49 => b = ± 7
a ≥ b
ANSWER:B
Question: Jennifer had $60 to spend on herself. She spent 1/5 of the money on a sandwich, 1/6 for a ticket
to a museum, and 1/2 of it on a book. How much money does Jennifer have left over?
A.$8
B.$14
C.$5
D.$15
Answer: A.$8
Explanation: 1/5 x $60 = $12 for sandwich
1/6 x $60 = $10 for museum
1/2 x $60 = $30 for book
$12 + $10 + $30 = $52 spent
$60 - $52 = $8 left over
correct answer A
Question: Two varieties of wheat - A and B costing Rs. 9 per kg and Rs. 15 per kg were mixed in the ratio 3 : 7. If 5 kg of the mixture is sold at 25% profit, find the profit made?
A.16.9
B.16.59
C.16.53
D.16.5
Answer: D.16.5
Explanation: Explanation:
Let the quantities of A and B mixed be 3x kg and 7x kg.
Cost of 3x kg of A = 9(3x) = Rs. 27x
Cost of 7x kg of B = 15(7x) = Rs. 105x
Cost of 10x kg of the mixture = 27x + 105x = Rs. 132x
Cost of 5 kg of the mixture = 132x/10x (5) = Rs. 66
Profit made in selling 5 kg of the mixture = 25/100 (cost of 5 kg of the mixture) = 25/100 * 66 = Rs. 16.50
Answer: Option D
Question: By the how much is two-fifth of 100 greater than three -fifths of 25?
A.25
B.3
C.5
D.30
Answer: A.25
Explanation: Reqd no. = 2â„5 Ã— 200 - 3â„5 Ã— 25
= 40 - 15 = 25
Answer A
Question: If |x|/|4| > 1, which of the following must be true?
A.x>4
B.x<4
C.x=4
D.x!=4
Answer: D.x!=4
Explanation: Notice that if x = 4, then |x| / |4| = |4| / |4| = 1, so |x| / |4| is NOT more than 1, it's equal to 1. Thus if x = 4, the given inequality does NOT hold true.
As for the other options.
D. x ≠ 4 --> we know that x < -4 or x >4. Thus x cannot be 4. Thus this option is true.
ANSWER: D x!=4
Question: A company that ships boxes to a total of 12 distribution centers uses color coding to identify each center. If either a single color or a pair of two different colors is chosen to represent each center and if each center is uniquely represented by that choice of one or two colors, what is the minimum number of colors needed for the coding? (assume that the order of colors in a pair does not matter)
A.4
B.5
C.6
D.12
Answer: B.5
Explanation: Let # of colors needed be nn, then it must be true that n+C2n≥12n+Cn2 - # of ways to choose the pair of different colors from nn colors when order doesn't matter) --> n+n(n−1)/2≥12 --> 2n+n(n−1)≥24 --> n is an integer (it represents # of colors) n≥5--> nmin=5
Answer: B.
Question: Which greatest possible length can be used to measure exactly 12 meter 15 cm, 10 meter 15 cm and 10 meter 65 cm
A.45cm
B.25cm
C.4cm
D.5cm
Answer: D.5cm
Explanation: Explanation:
Convert first all terms into cm.
i.e. 1215 cm, 1015cm, 1065cm.
Now whenever we need to calculate this type of question, we need to find the HCF. HCF of above terms is 5.
Option D