RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: There are 280 female managers in a certain company. Find the total number of female employees in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers.
A.600
B.650
C.700
D.750
Answer: C.700
Explanation: as per question stem 2/5M (Portion of Men employees who are managers) + 280 (Portion of Female employees who are managers) = 2/5T (Portion of Total number of employees who are managers), thus we get that 2/5M+280= 2/5T, or 2/5(T-M)=280, from here we get that T-M=700, that would be total number of female employees and the answer (C)
Question: If 7a - 3b = 10b + 40 = -12b - 2a, what is the value of 9a + 9b?
A.-5
B.-3
C.0
D.3
Answer: C.0
Explanation: (i) 7a - 13b = 40
(ii) 2a + 22b = -40
Adding (i) and (ii):
9a + 9b = 0
The answer is C.
Question: A bag contains 6 black and 4 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
A.3/4
B.2/5
C.1/7
D.1/8
Answer: B.2/5
Explanation: Let number of balls = (6 + 4) = 10.
Number of white balls = 4.
P (drawing a white ball) =4/10=2/5.
Option B.
Question: Given f(x) = 3x – 5, for what value of x does 2*[f(x)] + 5 = f(3x – 6)
A.0
B.4
C.6
D.7
Answer: C.6
Explanation: Answer = C = 6
f(x) = 3x – 5
2*[f(x)] + 5 = f(3x – 6)
2(3x-5) + 5 = 3 (3x-6) - 5
6x - 5 = 9x - 23
x = 6
Question: Ashok secured average of 76 marks in 6 subjects. If the average of marks in 5 subjects is 74, how many marks did he secure in the 6th subject?
A.66
B.74
C.78
D.86
Answer: D.86
Explanation: Explanation:
Number of subjects = 6
Average of marks in 6 subjects = 76
Therefore total marks in 6 subjects = 76 * 6 = 456
Now, No. of subjects = 5
Total marks in 5 subjects = 74 * 5 = 370
Therefore marks in 6th subject = 456 – 370 = 86
ANSWER D
Question: Which one of the following is a prime number?
A.45
B.90
C.81
D.29
Answer: D.29
Explanation: 73 is divisible by 1 and itself So, it is a prime number.
D
Question: The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.00 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
A.s.666
B.s.1140
C.s.999
D.s.1085
Answer: A.s.666
Explanation: a2 = 3136 => a = 56
56 * 4 * 3 = 672 – 6 = 666 * 1.0 = 666
ANSWER:A
Question: In a given set of S = {1,2,3,4,5,6,7,8} what is the median of the set S?
A.4
B.4.5
C.5
D.3.5
Answer: B.4.5
Explanation: median = 4+5 / 2 = 9/2 = 4.5
Answer is B
Question: A dishonest dealer marks up the price of his goods by 20% and gives a discount of 10% to the customer. Besides, he also cheats both his supplier and his buyer by 100 grams while buying or selling 1 kilogram. Find the percentage profit earned by the shopkeeper?
A.20%
B.25%
C.32%
D.46.66%
Answer: C.32%
Explanation: Solution: While buying,
He buys 1100 gram instead of 1000gram.
Suppose he bought 1100 grams for Rs. 1000.
While selling,
He sells only 900 grams when he takes the money for 1 kg.
Now, according to the problem,
he sells at a 8% profit (20% markup, 10% discount).
Hence, his selling price is Rs. 1080 for 900 grams.
Now,
1100grams for Rs. 1000
Hence, 1188 grams for Rs. 1080
Selling: 900 grams for Rs. 1080.
Hence, % profit = 288/900 = 32%.
(using goods left by goods sold formula)
Answer: Option C
Question: The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
A.276
B.299
C.322
D.345
Answer: C.322
Explanation: EXPLANATION
Clearly, the numbers are (23 x 13) and (23 x 14).
Larger number = (23 x 14) = 322.
Answer C
Question: If the area of circle is 616 sq cm then its circumference?
A.22
B.88
C.77
D.51
Answer: B.88
Explanation: 22/7 r2 = 616 => r = 14
2 * 22/7 * 14 = 88
Answer: B
Question: The H.C.F of two numbers is 8. Which of the following can never be their L.C.M?
A.55
B.44
C.66
D.60
Answer: D.60
Explanation: H.C.F of two numbers divides their L.C.M exactly. Clearly, 8 is not a factor of 60.
Answer:D
Question: The ratio of the radius of two circles is 1: 4, and then the ratio of their areas is?
A.1: 16
B.1: 6
C.1: 9
D.1: 3
Answer: A.1: 16
Explanation: r1: r2 = 1: 4
Πr12: Πr22
r12: r22 = 1: 16
Answer:A
Question: Two stations P and Q are 110 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet?
A.10.30 am
B.10 am
C.9 am
D.11 am
Answer: A.10.30 am
Explanation: Assume both trains meet after x hours after 7 am
Distance covered by train starting from P in x hours = 20x km
Distance covered by train starting from Q in (x-1) hours = 25(x-1)
Total distance = 110
=> 20x + 25(x-1) = 110
=> 45x = 135
=> x= 3
Means, they meet after 3 hours after 7 am, ie, they meet at 10 am
ANSWER:A
Question: A bag contains 7 red, 2 green balls. 3 balls are drawn randomly. What is the probability that balls drawn contain exactly two green balls?
A.1/7
B.2/9
C.1/12
D.4/17
Answer: C.1/12
Explanation: Total number of balls = 7+2 = 9
n(S) = 9C3 = 9*8*7 / 3*2 = 84
n(E) = 2C2* 7C1 = 7
Probability = 7/84 = 1/12
Answer is C
Question: One-third of Rahul’s savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 50,000 as total savings, how much has he saved in Public Provident Fund ?
A.Rs. 20,000
B.Rs. 30,000
C.Rs. 60,000
D.Rs. 90,000
Answer: A.Rs. 20,000
Explanation: EXPLANATION
Let savings in N.S.C and P.P.F. be Rs. x and Rs. (50000 – x) respectively. Then,
1/3x=1/2(50000-x)
=> x/3 + x/2 = 25000
=> 5x/6 = 25000
=> x= 25000 x 6 /5= 30000
Savings in Public Provident Fund = Rs. (50000 – 30000) = Rs. 20000
Answer A
Question: What is the units digit of the expression 13^27 +1?
A.1
B.3
C.4
D.8
Answer: D.8
Explanation: Power of 3 follows repetition pattern of = 3, 9, 7, 1, 3, 9, 7, 1 ....
Repetition after 4 powers = (3, 9, 7, 1)
13^27 = 27th Power = 24+3
24/4 = 6 (6 repetitions) + 3 = "7"
7+1=8
Answer D
Question: Two bullet train s 140 m and 170 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
A.15.8 sec.
B.12.8 sec.
C.11.16 sec.
D.10.8 sec.
Answer: C.11.16 sec.
Explanation: Relative speed = (60 + 40) km/hr = 100x5/18 = 250/9 m/ sec.
Distance covered in crossing each other = (140 + 170) m = 310 m.
Required time = 310x9/250 = 11.16 sec.
ANSWER C
Question: The equation f= 2y2 + 5y - 17, describes a parabola in the xy coordinate plane. If line l, with slope of 3, intersects the parabola in the upper-left quadrant at f = -5, the equation for l is
A.+ y + 15 = 0
B.- 3x - 11 = 0
C.+ y - 16.5 = 0
D.- y - 7 = 0
Answer: C.+ y - 16.5 = 0
Explanation: Is optionC: -3f + y -6.5= 0=C
Question: If the price of 357 apples is Rs.1517.25, what will be the approximate price of 49 dozens of such apples
A.Rs. 2500
B.Rs. 2300
C.Rs. 2200
D.Rs. 1400
Answer: A.Rs. 2500
Explanation: Let the required price be x
More apples, More price(direct proportion)
Hence we can write as
apples357:(49×12)}::1517.25:x
⇒357x = (49 × 12) × 1517.25
⇒x = (49 × 12 × 1517.25)/357 = (7 × 12 × 1517.25)/51
= (7 × 4 × 1517.25)/17 = 7 × 4 × 89.25 ≈ 2500. Answer A
Question: The product S of the first 10 prime numbers is closest to which of the following?
A.6.5 x 10^7
B.6.5 x 10^8
C.6.5 x 10^9
D.6.5 x 10^10
Answer: C.6.5 x 10^9
Explanation: The first 10 primes are: 2, 3, 5, 7, 11, 13, 17, 19, 23, and 29.
So, we need to find approximate value of 2*3*5*7*11*13*17*19*23*29.
# of different approximations are possible. For example:
2*5=10
3*17=~50 (actually more than 50);
7*13=~100 (actually less than 100);
11*19=~200 (actually more than 200)
23*29=667=S
2*3*5*7*11*13*17*19=~10*50*100*200*667=10^7*667=6.67*10^9.
Answer: C.
Question: A type of extra-large SUV averages 12.2 miles per gallon (mpg) on the highway, but only 7.6 mpg in the city. What is the maximum distance, in miles, that this SUV could be driven on 24 gallons of gasoline?
A.190
B.284.6
C.300
D.292
Answer: D.292
Explanation: so 12.2 * 24 = 292..
IMO option D is correct answer..
Question: There are two positive numbers in the ratio 4:8. If the larger number exceeds the smaller by 16, then find the smaller number?
A.25
B.20
C.77
D.88
Answer: B.20
Explanation: Let the two positive numbers be 5x and 8x respectively.
8x - 4x = 16
4x = 16 => x = 4
=> Smaller number = 5x = 20.
Answer: B
Question: The parameter of a square is equal to the perimeter of a rectangle of length 18 cm and breadth 10 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)?
A.22.51
B.22.0
C.22.15
D.22.17
Answer: B.22.0
Explanation: Let the side of the square be a cm.
Parameter of the rectangle = 2(18 + 10) = 56 cm Parameter of the square = 56 cm
i.e. 4a = 56
a = 14
Diameter of the semicircle = 15 cm
Circimference of the semicircle
= 1/2(âˆ)(14)
= 1/2(22/7)(14) = 308/14 = 22 cm to two decimal places
Answer: B
Question: How many liters of oil at Rs.40 per liter should be mixed with 240 liters of a second variety of oil at Rs.60 per liter so as to get a mixture whose cost is Rs.52 per liter?
A.120
B.150
C.160
D.180
Answer: C.160
Explanation: 8:12 = 2:3
If 240 lrs of the 2nd variety taken then the 1st variety should be taken as 160 lr
ANSWER C
Question: A bag contains 3 red, 3 green and 4 white balls. Three balls are picked up one by one without replacement. What is the probability that there will be at least one red ball?
A.5/8
B.7/12
C.11/16
D.17/24
Answer: D.17/24
Explanation: P(no red balls) = 7/10*6/9*5/8 = 7/24
P(at least one red ball) = 1 - 7/24 = 17/24
The answer is D.
Question: How many integers from 0 to 44, inclusive, have a remainder of 1 when divided by 3 ?
A.13
B.16
C.17
D.18
Answer: A.13
Explanation: Explanation:
1 also gives 1 remainder when divided by 3, another number is 4, then 7 and so on.
Hence we have an arithmetic progression: 1, 4, 7, 10,..... 43, which are in the form 3n+1.
Now we have to find out number of terms.
tn=a+(n-1)d, where tn is the nth term of an AP, a is the first term and d is the common difference.
so, 43 = 1+(n-1)3
or, (n-1)3 = 42
or, n-1 = 12
or, n = 13
A
Question: Divide 50 into two parts so that sum of the reciprocal is 1/12 ?
A.10,20
B.20,20
C.30,20
D.40,20
Answer: C.30,20
Explanation: let two no be x,y
x+y=50 ....eq(1)
1/x+1/y=1/12...eq(2)
x+y/xy=1/12(using eq(1))
xy=600
now, (x-y)^2=(x+y)^2 -4xy
using above
x-y=10.....eq(3)
solving eq(1) & eq(2)
x=30 & y=20
ANSWER:C
Question: emblem is coded as 216;
crude is coded as 125
Crickets will be ?
A.243
B.644
C.512
D.380
Answer: C.512
Explanation: coding follows (no. of letters)^3
emblem = 216 = 6^3
crude = 125 = 5^3
Crickets = 8^3 =512
ANSWER:C
Question: If the price of gold increases by 50%, find by how much the quantity of ornaments must be reduced, so that the expenditure may remain the same as before?
A.331/8%
B.331/3%
C.381/3%
D.351/3%
Answer: B.331/3%
Explanation: 100
150
------
150-------50
100-------? => 331/3%
Answer: B
Question: When a student Joe, weighing 42 kg, joins a group of students whose average weight is 30 kg, the average weight goes up by 1 kg. Subsequently, if two students, excluding Joe, leave the group the average weight comes back to 30 kg. What is the difference between the average weight of the two students who left and the weight of Joe?
A.5.5 kg
B.6 kg
C.30 kg
D.36.5 kg
Answer: B.6 kg
Explanation: After two persons leave the group the average remains the same. That means the weight of the two persons = 42+30 = 72
So, the average the two persons = 36
That gives the answer 42-36 = 6
Answer B
Question: A can do a piece of work in 10 days. He works at it for 4 days and then B finishes it in 9 days. In how many days can A and B together finish the work?
A.6 days
B.7 days
C.8 days
D.5 days
Answer: A.6 days
Explanation: 4/10 + 9/x = 1 => x = 15
1/10 + 1/15 = 1/6 => 6 days
\Answer:A
Question: A can do a piece of work in 40 days; B can do the same in 30 days. A started alone but left the work after 10 days, then B worked at it for 10 days. C finished the remaining work in 10 days. C alone can do the whole work in?
A.24
B.66
C.88
D.92
Answer: A.24
Explanation: 10/40 + 10/30 + 10/x = 1
x = 24 days
Answer:A
Question: What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 4 Years?
A.5
B.6
C.7
D.1
Answer: A.5
Explanation: 160 = (180*4*R)/100
R = 5%
Answer: A
Question: The average score of a cricketer for ten matches is 38.9 runs. If the average for the first six matches is 42, then find the average for the last four matches.
A.33.25
B.33.5
C.34.25
D.35
Answer: C.34.25
Explanation: Solution:
Total sum of last 4 matches,
= (10 * 38.9) – (6 * 42)
= 389 – 252 = 137.
Average = 137 /4 = 34.25
Answer: Option C
Question: How many multiples of 8 are there between 100 and 200 (both are inclusive)?
A.27
B.4
C.6
D.13.5
Answer: D.13.5
Explanation: the answer is (200-100)/8+1=13.5
Answer is D
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 90 km/hr, what is the length of the platform?
A.338
B.240
C.287
D.400
Answer: D.400
Explanation: Speed = (90 * 5/18) m/sec = 25 m/sec. Length of the train = (25 x 20)m = 500 m. Let the length of the platform be x meters. Then, (x + 500)/36 = 25 ==> x + 500 = 900 ==> x = 400 m.
Answer: D
Question: The S.I. on a certain sum of money for 3 years at 8% per annum is half the C.I. on Rs. 4000 for 2 years at 10% per annum. The sum placed on S.I. is?
A.Rs. 1550
B.Rs. 1650
C.Rs. 1750
D.Rs. 2000
Answer: C.Rs. 1750
Explanation: Explanation:
C.I. = [4000 * (1 + 10/100)2 - 4000]
= (4000 * 11/10 * 11/10 - 4000) = Rs. 840.
Sum = (420 * 100)/(3 * 8) = Rs. 1750
ANSWER IS C
Question: Two horses begin running on an oval course at the same time. One runs each lap in 9 minutes; the other takes 15 minutes to run each lap. How Many minutes after the start will the faster horse have a one lap lead?
A.36
B.12
C.9
D.45/2
Answer: D.45/2
Explanation: The rate of the faster horse is 1/9 lap/minute;
The rate of the slower horse is 1/15 lap/minute;
Their relative rate is 1/9-1/15=2/45 lap/minute;
The faster horse to gain one full lap will need time=distance/rate=1/(2/45)=45/2 minutes.
Answer: D.
Question: In ten years, David will be four times as old as Aaron. Twenty years ago, David was twice as old as Ellen. If David is eleven years older than Ellen, how old is Aaron?
A.1–5
B.3–5
C.11–15
D.16–20
Answer: B.3–5
Explanation: Let David's present age be 'd', Aaron's present age be 'a' and Ellen's present age be 'e'
In ten years, David will be four times as old as Aaron --> d+10 = 4(a+10)
Twenty years ago, David was twice as old as Ellen --> d-20 = 2(e-20)
David is seven years older than Ellen --> d = e + 11
e+11-20 = 2e-40
e-9 = 2e-40
e = 31
d = 42
52 = 4a + 40
a = 3
Answer: B
Question: A student worked for 20 days. For each of the amounts shown in the first row of the table, the second row gives the number of days that the student earned that amount. What is the amount of money that the student earned per day for the 16th day?
Amounts earned per day : $96 $84 $80 $70 $48
Number of days : 4 7 4 3 2
A.(1) $96
B.(2) $84
C.(3) $80
D.(4) $70
Answer: B.(2) $84
Explanation: 4+7+4+3+2 = 20
The series is as follows. Arrange the terms in increasing order of amounts earned and cumulatively add up the number of days of each amount.
1st to 2nd term = 48 (2 days)
3rd to 5th term = 70 (3 days)
6th to 9th term = 80 (4 days)
10th to 16th term = 84 (7 days)
Pick B
Question: Two equally sized jugs full of water are each emptied into two separate unequally sized empty jugs, X and Y. Now, jug X is 1/4 full, while jug Y is 2/3 full. If water is poured from jug X into jug Y until jug Y is filled, what fraction of jug X then contains water?
A.0
B.1/15
C.2/15
D.1/8
Answer: D.1/8
Explanation: Suppose the water in each jug is L liters
CX x (1/4) = L
CX = 4L liters
CX is capacity of X
CY x (2/3) = L
CY = 3L/2 liters
CY is capacity of Y
Now, Y is 3L/2 - L empty = L/2 empty
So, we can put only L/2 water in jug Y from Jug X
Jug X's remaining water = L - L/2 = L/2
Fraction of X which contains water = water / CX
= (L/2)/ 4L
= 1/8
Answer will be D
Question: Ten coins are tossed simultaneously. In how many of the outcomes will the first coin turn up a head?
A.2^7
B.2^10
C.3 * 2^8
D.2^9
Answer: D.2^9
Explanation: Fix the third coin as H. The remaining 9 coins have 2^9 outcomes.
Ans:D
Question: Bill and Jane play a simple game involving two fair dice, each of which has six sides numbered from 1 to 6 (with an equal chance of landing on any side). Bill rolls the dice and his score is the total of the two dice. Jane then rolls the dice and her score is the total of her two dice. If Jane’s score is higher than Bill’s, she wins the game. What is the probability the Jane will win the game?
A.15/36
B.175/432
C.575/1296
D.583/1296
Answer: C.575/1296
Explanation: There are three possible outcomes in the game:
1. B Wins
2. J Wins
3. Draw
So, 1=P(J)+P(B)+P(Draw)1=P(J)+P(B)+P(Draw)
The probability of B winning or J winning the game is same.
so, 1=2∗P(J)+P(Draw)1=2∗P(J)+P(Draw)
So, we need to calculate the probability of a draw.
A draw can happen when both will have the same sum.
The possible sums are - 2,3,4,5,6,7,8,9,10,11,12
Prob. of each sum is -
2 - 1,1 - 1/36
3 - 1 2, 2 1 - 2/36
4 - 1 3, 2 2, 3 1 - 3/36
5 - 1 4, 2 3, 3 2, 41 - 4/36
6 - 1 5, 2 4, 3 3, 4 2, 5 1 - 5/36
7 - 1 6, 2 5, 3 4, 4 3, 5 2, 61 - 6/36
8 - 2 6, 3 5, 4 4, 5 3, 6 2, - 5/36
9 - 3 6, 4 5, 5 4, 63 - 4/36
10 - 4 6, 5 5, 6 4 - 3/36
11 - 5 6, 6 5 - 2/36
12 - 6 6 - 1/36
Now, since both have to get the same sum, the probability will be same for both and the combined probability will be the square of the probabilities
i.e. 2 - (1/36)^2
3 - (2/36)^2
etc.
Squaring the probabilities and adding them will give 146/1296
So, P(D) = 146/1296
1 = 2*P(J) + P(D)
2*P(J) = 1150/1296
P(J) = 575 / 1296
Ans. C
Question: A veterinarian surveys 26 of his patrons. He discovers that 14 have dogs, 10 have cats, and 5 have fish. Four have dogs and cats, 3 have dogs and fish, and one has a cat and fish. If no one has all three kinds of pets, how many patrons have none of these pets?
A.5
B.6
C.8
D.None of these
Answer: A.5
Explanation: 7 + 4 + 0 + 3 + 1 + 5 + 1 + x = 26
21 + x = 26
x = 5 patrons have none of these animals
A)
Question: Two trains of equal are running on parallel lines in the same direction at 18 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
A.25
B.26
C.27
D.28
Answer: A.25
Explanation: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 - 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/18 = 25/9 => x = 25.
Answer: A
Question: Jamshid can paint a fence in 50 percent less time than Taimour can when each works alone. When they work together, they can paint the fence in 7 hours. How long would it take Taimour to paint the fence alone?
A.6 hours
B.8 hours
C.14 hours
D.21 hours
Answer: D.21 hours
Explanation: I believe the answer is D. Please see below for explanation.
if Jamshid can paint a dence in 50 percent less time then Taimour we can infer the following rate J = 2T
if working together they can do the job in 8 hours we can infer 1 = 2T+T * 7 => 1/21
Working alone Taimour can do the job in 1 = 1/21 * hours => 21
Answer D
Question: A bat is bought for Rs.800 and sold at a gain of 20% find its selling price
A.Rs.920/-
B.Rs.950/-
C.Rs.860/-
D.Rs.960/-
Answer: D.Rs.960/-
Explanation: Explanation:
100 % ------> 800 (100 * 8 = 800)
120 % ------> 960 (120 * 8 = 960)
Selling price = Rs. 960/-
Answer: Option D
Question: A boy goes to his school from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming. The distance between his house and school is?
A.7 km
B.3 km
C.6 km
D.9 km
Answer: C.6 km
Explanation: Average speed = (2 * 3 * 2) / (3 + 2)
= 12/5 km/hr.
Distance traveled = 12/5 * 5 = 12 km.
Distance between house and school
= 12/2
= 6 km.
Answer: C
Question: If the mode of Set F is equal to the median of Set F, Set F could be
A.[0, 1, 2, 2, 3, 4, 5, 6]
B.[2, 2, 5, 7, 9]
C.[x, x+1, x+2, x+2, x+3, x+3]
D.[10, 102, 105, 105]
Answer: C.[x, x+1, x+2, x+2, x+3, x+3]
Explanation: Correct Answer: (C)
Set F could be The mode is the most common number; the median is the middle number when the numbers are arranged from least to greatest. Any number plus an integer value is greater than the original number, so x + 1 is greater than x, x + 2 is greater than x + 1, etc., so set (C) is arranged from least to greatest. Its median is the average of (x+2) and (x+2), which must be (x+2). (x+2) is also the most common number, so the mode of set C is equal to the median of set C.
Question: Three numbers are in the ratio 3:4:5 and their L.C.M. is 2400. Their H.C.F is?
A.20
B.30
C.40
D.50
Answer: C.40
Explanation: Let the numbers be 3x,4x and 5x
their L.C.M. = 60x
60x = 2400
x = 40
The numbers are 3*40 , 4*40 , 5*40
Hence required H.C.F. = 40
Answer is C
Question: Which of the following is the sum of all the even numbers between 1 and 97, inclusive?
A.2550
B.2450
C.2600
D.2449
Answer: D.2449
Explanation: This question can be solved withbunching.
We're asked for the SUM of all of the EVEN integers from 1 to 99, so we really want the sum of 4, 6, 8.....96.
If you take the next smallest and next biggest numbers, you have...
4+96 = 100
This pattern will continue on, so we're going to have a bunch of 100s, BUT we have to be careful to make sure that we don't miss a number if it'sin the middleand doesn't get paired up. Since we know that the sum of each pair is 100, we can 'jump ahead' to find the last few pairs...
44+56 = 100
46+54 = 100
48+52 = 100
There IS a middle number: 50; this number does NOT get paired up.
Since 48 is the 24th even integer, we know there are twenty-four 100s + one 50. 2400+50-1 = 2449
Final Answer:
D
Question: An article is bought for Rs.900 and sold for Rs.1000, find the gain percent?
A.11 2/5%
B.11 2/9%
C.11 1/9%
D.11 2/3%
Answer: C.11 1/9%
Explanation: 900 ---- 100
100 ---- ? => 11 1/9%
Answer: C
Question: In May, Xiang sold 15 used cars. For these 15 cars, the range of the selling price was $15,000 and the lowest selling price was $4,500. In June, Xiang sold 10 used cars. For these 10 cars, the range of the selling prices was $16,500 and the lowest selling price was $5,100. What was the range of the selling prices of the 25 used cars sold by Xiang in May and June?
A.1. $15,600
B.2. $15,750
C.3. $17,100
D.4. $18,100
Answer: C.3. $17,100
Explanation: Edited the question as there was a typo.
Range = Highest Value - Lowest Value.
Range in May was 15,000 and the lowest price in May was 4,500, thus the highest price in May was 15,000+4,500=19,500.
Range in June was 16,500 and the lowest price in June was 5,100, thus the highest price in June was 16,500+5,100=21,600.
Lowest price of a car in May-June was 4,500 (May) and the highest price of a car in May-June was 21,600, thus the range for May-June is 21,600-4,500=17,100.
Answer: C.
Question: A tour group of 25 people paid a total of $945 for entrance to a museum. If this price included a 5% sales tax, and all the tickets cost the same amount, what was the face value of each ticket price without the sales tax?
Choices
A.$22
B.$23.94
C.$36
D.$25.20
Answer: C.$36
Explanation: Soln:-
945/25=x+0.05x
945/25=1.05x
x=36
ANSWER:C
Question: A parking garage rents parking spaces for $10 per week or $40 per month. How much does a person save in a year by renting by the month rather than by the week?
A. $140
B. $160
C. $220
D. $40
Answer: D. $40
Explanation: 10$ per week!
An year has 52 weeks.
Annual charges per year = 52* 10 = 520$
30$ per month!
An year has 12 months.
Annual charges per year = 12 * 40 = 480$
520 - 480 = 40
Ans D
Question: A squirrel runs up a cylindrical post , in a perfect spiral path making one circuit for each rise of 4 feet . How many feet does the squirrel travels if the post is 12 feet tall and 3 feet in circumference?
A.9 feet
B.12 feet
C.13 feet
D.15 feet
Answer: A.9 feet
Explanation: total circuit=12/4=3
total feet squirrel travels=3*3=9 feet
ANSWER:A