RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The H.C.F. of two numbers is 12 and their difference is 12. The numbers are
A.66, 78
B.70, 82
C.94, 106
D.84, 96
Answer: D.84, 96
Explanation: Solution
Out of the given numbers, the two with H.C.F. 12 and difference 12 are 84 and 96
Answer D
Question: A positive number x is multiplied by 4, and this product is then divided by 3. If the positive square root of the result of these two operations equals x, what is the value of x ?
A. 9/4
B. 3/2
C. 4/3
D. 1/3
Answer: D. 1/3
Explanation: We need to produce an equation from the information given in the problem stem. We are first given that x is multiplied by 2 and then the product is divided by 3. This gives us:
2x/3
Next we are given that the positive square root of the result (which is 2x/3) is equal to x. This gives us
√(2x/3) = x
2x/3 = x^2
2x = 3x^2
3x^2 – 2x = 0
x(3x – 2) = 0
x = 0 or
3x – 2 = 0
3x = 2
x = 1/3
Because x is positive, x = 1/3. The answer is D.
Question: A(5, w^2) is the (x, y) coordinate of point located on the parabola Y = X^2 + 11. What is the value of w?
A.3.
B.4.
C.5.
D.6.
Answer: D.6.
Explanation: y=x^2 +11
w^2=5^2+11
w^2=36
W=6
Answer D
Question: If x,2x+2,3x+3 are the first three terms of a GP,then what is its fourth term?
A.-11.5
B.-12.5
C.-13.5
D.-14.5
Answer: C.-13.5
Explanation: (2x+2)/x= (3x+3)/(2x+2)
4x^2+8x+4 = 3x^2+3x
x^2+5x+4=0
x=-4
so series will be
-4,-6,-9,-13.5
ANSWER:C
Question: In a vessel, there are 10 litres of alcohol. An operation is defined as taking out five litres of what is present in the vessel and adding 10 litres of pure water to it. What is the ratio of alcohol to water after two operations?
A.1 : 0
B.1 : 5
C.1 : 1
D.1 : 2
Answer: B.1 : 5
Explanation: Final concentration = Initial concentration (1−replacement quantityfinal volume)(1−replacement quantityfinal volume)
Final concentration = =1×(1−1015)=13=1×(1−1015)=13
Final concentration = 13×(1−1020)=1613×(1−1020)=16
So ratio of alcohol : water = 1 : 5
Answer:B
Question: an article with cost price of 240 is sold at 20% profit. what is the selling price?
A.288
B.200
C.204
D.207
Answer: A.288
Explanation: sp=1.20*240=288
ANSWER:A
Question: (8^16)+(16^13)+(4^22) = ?
A.(4)*(2^29+1)
B.(6)*(2^48)
C.(9)*(2^49)
D.(28)*(2^53)
Answer: D.(28)*(2^53)
Explanation: I think you are assuming that (X^Y) + (X^Z) is = (X^Y+Z) which is not true, as it only applies to multiplication. Rather it would have to be (X^Y)(X^Z) = (X^YZ)
So when you simplify down to 2^48 + 2^52 + 2^48 you cannot just add exponents.
Here's how my brain works with this one,
Step 1: Recognize a common base.
(8^16) + (16^13) + (4^24) = ((2^2)^16) + ((2^4)^13) + ((2^2)^24) = (2^48) + (2^52) + (2^48)
Step 2: Recognize the factor and pull out of the equation.
= (2^48)(1 + (2^4) + 1)
= (2^48)(1 + 16 + 1)
= (2^48)(18)
Step 3: Recognize this is not an answer and adapt.
(2^48)(18) = (2^48)(2)(9) = (28)*(2^53)
Answer is D.
Question: A man sold 18 toys for Rs. 16800, gaining thereby the cost price of 3 toy find the cost price of a toy
A.Rs. 600
B.Rs. 800
C.Rs.500
D.Rs.900
Answer: B.Rs. 800
Explanation: Let the cost of one toy = X.
Then, cost of 18 toys = 18X.
Gain = 3X.
SP of 18 toys = Rs. 16800.
Gain = SP – CP
3X = 16800 – 18X
21X = 16800
X = Rs. 800.
ANSWER : OPTION B
Question: If A, B and C together can finish a piece of work in 2 days. A alone in 12 days and B in 18 days, then C alone can do it in?
A.5 days
B.4 days
C.3 days
D.2 days
Answer: C.3 days
Explanation: C = 1/2 - 1/12 – 1/18 = 1/3 => 3 days
ANSWER:C
Question: Six students - 3 boys and 3 girls - are to sit side by side for a makeup exam. How many ways could they arrange themselves given that no two boys and no two girls can sit next to one another?
A.A)12
B.B)36
C.C)72
D.D)240
Answer: C.C)72
Explanation: in order not to have two boys or two girls next to one another, we must make an alternate sitting arrangement. (B-G-B-G-B-G) or (G-B-G-B-G-B).
Total ways = 2C1*3!*3!
=2*6*6
=72
Ans - C
Question: A dishonest dealer professes to sell his goods at Cost Price but still gets 20% profit by using a false weight. What weight does he substitute for a kilogram?
A.833 1/3 grams
B.850 1/3 grams
C.825 1/3 grams
D.810 1/3 grams
Answer: A.833 1/3 grams
Explanation: A
833 1/3 grams
If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.
If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm ------ 100 gm
1000 gm ------ ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams.
Question: Pick the odd man out:
154, 235, 352, 460, 324
A.324
B.323
C.279
D.266
Answer: A.324
Explanation: Explanation:
Sum of the digit in each number, except 324 is 10.
ANSWER: A
Question: 23, 29, 31, 37, 41, 43, (...)
A.53
B.48
C.47
D.59
Answer: C.47
Explanation: All are prime numbers in their order, starting from 23
Hence, next number is 47
Answer is C.
Question: A man divides $8400 Among 5 Sons, 4 Daughters and 1 Nephews. If each daughter receives four times as much as each nephews and each son receives five times as much as each nephews, how much does each daughter receive?
A.A)$200
B.B)$1000
C.C)$800
D.D)$1200
Answer: C.C)$800
Explanation: Let the share of each nephews be $X.
Then, share of each daughter=$4X, share of each son= $5X.
So, 5*5X+4*4X+1*X=8400
25X+16X+X=8600
42X=8400, X=200.
Daughter receives four times of nephew so 4 * 200 = 800.
So Each Daughter receives $800. answer is option C) $800.
Question: The vertices of a rectangle in the standard (x,y) coordinate place are (0,0), (0,6), (10,0) and (10,6). If a line through (1,1) partitions the interior of this rectangle into 2 regions that have equal areas, what is the slope of this line?
A.1/2
B.1/3
C.1/4
D.1/5
Answer: A.1/2
Explanation: We should know that a rectangle can be divided into two equal areas by a straight line only when the straight line passes through the center of the rectangle.
The center of the rectangle is the point (5,3).
The slope of line passing through points (1,1) and (5,3) = (3-1)/(5-1) = 1/2
The answer is A.
Question: If x^6 + y^6 = 500, then the greatest possible value of x is between
A.0 and 3
B.3 and 6
C.6 and 9
D.9 and 12
Answer: A.0 and 3
Explanation: for the greatest possible value of x^6, we must minimize the value of y^6 i.e. lets say y^6 = 0
then we need to find a number x such that x^6 < 500. 2^6 = 64 and 3^6 = 729 so we can say that the maximum possible value of x can be a little less than 3 hence answer = between 0 and 3
hence A
Question: A cistern which could be filled in 9 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it?
A.90
B.25
C.40
D.23
Answer: A.90
Explanation: 1/9 - 1/x = 1/10
=> 90 hrs
ANSWER A
Question: A and B enter into partnership with capital as 7:9. At the end of 8 months, A withdraws. If they receive the profits in the ratio of 8:9 find how long B's capital was used?
A.8
B.9
C.4
D.7
Answer: D.7
Explanation: 7 * 8 : 9 * x = 8:9
=> x= 7
Answer: D
Question: Solve the given two equations and find the inequality of X and Y.(a) x^2-7x+12=0 and (b) y^2-12y+32=0
A.If x>y
B.If x>=y
C.If x<y
D.If x<=y
Answer: D.If x<=y
Explanation: Solution:-
X=3,4 and Y= 4,8
X<= Y
D
Question: A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.1100, what is the reduced price for kg?
A.s.40
B.s.46
C.s.55
D.s.41
Answer: C.s.55
Explanation: 800*(25/100) = 275 ---- 5
? ---- 1
=> Rs.55
Answer: C
Question: A rectangular field is to be fenced on three sides leaving a side of 30 feet uncovered. If the area of the field is 810 sq. feet, how many feet of fencing will be required?
A.34
B.40
C.68
D.84
Answer: D.84
Explanation: EXPLANATION
We have: l = 30 ft and lb = 810 sq. ft.
So, b = 27 ft.
Length of fencing = (l + 2b) = (30 + 54) ft = 84 ft.
Answer D
Question: A train 130 m long passes a man,running at 6 kmph in the direction opposite to that of the train,in 6 seconds.The speed of the train is
A.54 kmph
B.60 kmph
C.66 kmph
D.72 kmph
Answer: D.72 kmph
Explanation: speed of train relative to man: 130/6 * 18/5 km/hr
= 78 km/hr
let speed of train= x
therefore x+6 = 78
x= 78-6
x=72 km/hr
ANSWER:D
Question: The table below shows how many coaches work with each of the major sports teams at Kristensen School. Although no single coach works with all three teams, 3 coaches work with both the Track and Tennis teams, 2 coaches work with both the Track and Baseball teams, and 3 coach works with both the Tennis and Baseball teams. How many different coaches work with these three teams?
Sports No of coaches
Track 8
Tennis 5
Baseball 4
A.6
B.9
C.11
D.12
Answer: B.9
Explanation: X = 8 + 5 + 4 - (3 + 2 + 3) = 9
Answer is B
Question: The fuel indicator in a car shows 1/5th of the fuel tank as full. When 22 more liters of fuel are poured in to the tank, the indicator rests at the 3/4of the full mark. Find the capacity of the tank.
A.25 litres
B.35 litres
C.30 litres
D.40 litres
Answer: D.40 litres
Explanation: x/5 + 22 = 3x/4 => x = 40 litres
Answer: D
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 185220, then population in 1978 was?
A.120000
B.160000
C.187899
D.178968
Answer: B.160000
Explanation: X * (105/100) * (105/100) * (105/100) = 185220
X = 185220/1.157625
X = 160000
Answer:B
Question: A Sum of Rs.2600, is lent out in 2 parts SI at 10% for 5yrs is equal to SI on 2nd part at 9% rate for 6 yrs. find the ratio of parts.
A.21:23
B.27:25
C.23:27
D.23:24
Answer: B.27:25
Explanation: Solution :
Given SI1 = SI 2
P1 : P2 = 1/R1T1 : 1/R2T2
= 1/(10*5) : 1/(9:6)
27:25
B
Question: A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 360 m long platform?
A.37 min
B.55 min
C.48 min
D.67 min
Answer: C.48 min
Explanation: C
48 min
Let the length of the train be x m.
When a train crosses an electric pole, the distance covered is its own length.
So, x = 12 * 36 * 5 /18 m = 120 m.
Time taken to cross the platform = (120 +360)/ 36 * 5/18 = 48 min.
Question: How long will it take a sum of money invested at 6 % p.a. S.I. to increase its value by 60%?
A.11 years
B.12 years
C.10 years
D.15 years
Answer: C.10 years
Explanation: Sol.
Let the sum be x. Then, S.I. = 60% of x = 3x/5; Rate = 6%.
âˆ´ Time = [100 * 3x/5 * 1/x*6] = 10 years
Answer C
Question: In a simultaneous throw of 2 dice what is the probability of getting a total of 2?
A.1/4
B.1/36
C.2/11
D.3/13
Answer: B.1/36
Explanation: n(S) = 6*6 = 36
E = {(1,1)}
Probability = 1/36
Answer is B
Question: How many Three digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is replaced?
A.5
B.10
C.15
D.20
Answer: D.20
Explanation: Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.
Tens place can be filled by any of the remaining 5 numbers.
So, there are 5 ways of filling the tens place.
The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.
Therefore Required number of numbers = 1 x 5 x 4 = 20.
Answer D.
Question: If a - b = 3 and a2 + b2 = 29, find the value of ab.
A.10
B.12
C.15
D.18
Answer: A.10
Explanation: Explanation:
2ab = (a2 + b2) - (a - b)2
= 29 - 9 = 20
ab = 10.
Answer: A
Question: (X)+4671+6514-7687=19190. Calculate the value of X
A.15615
B.15692
C.15687
D.15112
Answer: B.15692
Explanation: x+4671+6514-7687=19190
=x+4671+6514=19190+7687
=x+11185=26877
=x=26877-11185
=15692
Answer is B
Question: If the complement of a certain angle is seven times the measure of that certain angle, then what is the measure of that certain angle?
A.45°
B.30°
C.11.25°
D.18°
Answer: C.11.25°
Explanation: The complement of angle A is the angle which, when added to angle A, gives 90 degrees. The two acute angles of a right triangle are complements, for example.
The original angle is x, so the complement is 7x, and together, these add up to 90 degrees.
x + 7x = 90
8x = 90
x = 11.25°
Answer = (C)
Question: A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 50 years now, the son's age 10 years back was?
A.12yr
B.15yr
C.14yr
D.10yr
Answer: B.15yr
Explanation: Let the son's present age be x years
Then, 50-x = x
x = 25
Son's age 10 years back = 25-10 = 15years
Answer is B
Question: A bag contains 2 yellow, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
A.1/2
B.10/21
C.9/11
D.7/11
Answer: B.10/21
Explanation: Total number of balls = 2 + 3 + 2 = 7
Let S be the sample space.
n(S) = Total number of ways of drawing 2 balls out of 7 = 7C2
Let E = Event of drawing 2 balls , none of them is blue.
n(E) = Number of ways of drawing 2 balls , none of them is blue
= Number of ways of drawing 2 balls from the total 5 (=7-2) balls = 5C2
(âˆµ There are two blue balls in the total 7 balls. Total number of non-blue balls = 7 - 2 = 5)
P(E) = n(E)/n(S)=5C2/7C2=(5Ã—4/2Ã—1)/(7Ã—6/2Ã—1)=5Ã—4/7Ã—6=10/21
Answer :B
Question: The volume of a cube is 1728 cc. Find its surface?
A.864
B.288
C.299
D.267
Answer: A.864
Explanation: a3 = 1728 => a = 12
6a2 = 6 * 12 * 12
= 864
Answer:A
Question: Deepak can read x pages in 10 minutes. At this rate, how long will it take him to read y pages?
A.(12/x)*y
B.(5/x)*y
C.(10/x)*y
D.(10x)*y
Answer: C.(10/x)*y
Explanation: x page in 10 mins
i.e. 1 page in 10/x mins
i.e. y pages in (10/x)*y
Answer: option C
Question: The speed of a railway engine is 84 Km per hour when no compartment is attached, and the reduction in speed is directly proportional to the square root of the number of compartments attached. If the speed of the train carried by this engine is 24 Km per hour when 9 compartments are attached, the maximum number of compartments that can be carried by the engine is:
A.19
B.18
C.16
D.17
Answer: D.17
Explanation: the reduction in speed is directly proportional to the square root of the number of compartments attached
Doesreductionmean amount subtracted? or percentage decrease? There are at least two interpretations, and the wording does not provide a clear interpretation between them.
Evidently what the question intends is the subtraction interpretation. What is subtracted from the speed is directly proportional to the square root of the number of compartments attached.
In other words, if S = speed, and N = number of compartments, then
S = 84 - k*sqrt(N)
wherekis a constant of the proportionality. In general, if A is directly proportional to B, we can write A = k*B and solve for k.
If N = 9, then S = 24
24 = 84 - k*sqrt(9) =84 - 3k
k = 20
Now, we need to know: what value of N makes S go to zero?
0 = 84 - 20*sqrt(N)
20*sqrt(N) = 84
sqrt(N) = 4.2
n = 4.2^2 >17
With 18 compartments, the train does not budge. Therefore, it would budge if there were one fewer cars. Thus, 17 is the maximum number of cars the engine can pull and still move.
D
Question: Two out of ten employees are capable of doing a certain task. Sixty percent of the five employees, including the two who are capable, are assigned to a project involving this task. what percentage of employees assigned to the project are not capable?
A.43.33%
B.66.66%
C.13.33%
D.38.33%
Answer: B.66.66%
Explanation: Given 60% of 10 employees including 2 who are capable of doing task.
60% of 10 employeees
= 60/100 * 10
= 6 employees
===> 2 employees who are capable of doing the task and four employee who is not capable.
percentage of employees assigned who are not capable
= 4/6 * 100
= 66.66%
ANSWER:B
Question: Eight women of eight different heights are to pose for a photo in two rows of four. Each woman in the second row must stand directly behind a shorter woman in the first row. In addition, all of the women in each row must be arranged in order of increasing height from left to right. Assuming that these restrictions are fully adhered to, in how many different ways can the women pose?
A.2
B.14
C.15
D.16
Answer: B.14
Explanation: Shortest (1) and highest (8) women are fixed:
XXX8
1XXX
2 and 7 have two options, so total 4 patterns:
1:
2xx8
1xx7
|2468| |2568|
|1357| |1347|
2.
2x78
1xxx
|2478| |2578| |2678|
|1356| |1346| |1345|
3.
xxx8
12x7
|4568| |3468| |3568|
|1237| |1257| |1247|
4.
xx78
12xx
|3478| |3678| |3578| |5678| |4578| |4678|
|1256| |1245| |1246| |1234| |1236| |1235|
14 options.
Answer: B.
Question: Can you find the smallest non fractional number such that
If the number gets divided by 7 , we get the remainder of 1;
If the number gets divided by 8 , we get the remainder of 2
If the number gets divided by 9 , we get the remainder of 3;
If the number gets divided by 10 , we get the remainder of 4.
A.1500
B.3210
C.2150
D.2518
Answer: D.2518
Explanation: D.2518
As we know LCM of the numbers 7 8 9 & 10 is 2520.
So if i divide 2520 by any of the four number , it gives remainder as 0.
Now to get reminder as desired, is should be 2 short of 2518. (3-1,4-2,5-3,6-4 )
Ans:option D
Question: In a race where 10 cars are running, the chance that car X will win is 1/7, that Y will win is 1/3 and that Z will win is 1/5. Assuming that a dead heat is impossible, find the chance that one of them will win.
A.1/140
B.1/180
C.71/105
D.21/113
Answer: C.71/105
Explanation: Required probability = P(X) + P(Y) + P(Z) (all the events are mutually exclusive).
= 1/7 + 1/3 + 1/5
= 71/105
ANSWER:C
Question: The area of a square field is 4802 m(power)2 the length of its diagonal is:
A.98m
B.102m
C.95m
D.105m
Answer: A.98m
Explanation: Let the diagonal be d metres,
Then 1/2 d(power)2 = 4802
d2 = 9604
d = √9604
d = 98 m
Answer is A.
Question: The sum of all the digits of the integers from 18 to 21 inclusive is 24 (1 + 8 + 1 + 9 + 2 + 0 + 2 + 1 = 24). What is the sum Q of all the digits of the integers from 0 to 99 inclusive?
A.450
B.810
C.900
D.1000
Answer: C.900
Explanation: We want the sum of the digits from 0 to 99, so I approximated:
0-9 ->45-> (9+0)*10/2
40-49 ->85(13+4)*10/2
90-99 ->135(18+9)*10/2
We can see at a glance that theweightgoes up as the numbers go up (meaning the difference between 85 and 45 is 40, while 135-85 is 50, this means that the second part of this sequence carries more weight for our result), so we know that the final answer has to be more than 850 (85*10) but close to it, and that's just Q=900:the answer is C.
Question: A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. Find the time required by the first pipe to fill the tank ?
A.10 hours
B.15 hours
C.17 hours
D.18 hours
Answer: B.15 hours
Explanation: Explanation:
Suppose, first pipe alone takes x hours to fill the tank .
Then, second and third pipes will take (x -5) and (x - 9) hours respectively to fill the tank.
As per question, we get
1/x+1/x−5=1/x−9
=>x−5+x/x(x−5)=1/x−9
=>(2x−5)(x−9)=x(x−5)
=>x2−18x+45=0
After solving this euation, we get
(x-15)(x+3) = 0,
As value can not be negative, so x = 15
Option B
Question: A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 49 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?
A.48pi/x
B.75x
C.34.2x
D.24x
Answer: C.34.2x
Explanation: C = (pi)d
C(small): (pi)*28
C(large): (pi)*49
Lets say the time horizon is 60 seconds, so during that time the smaller rim covers a distance of (pi)*28*60 = (pi)*(1680) inches
(pi)*(1680) = (pi)*(49)(x)
pi*(34.2) = pi*(x)
34.2=x
Answer: C. 34.2x
Question: If the number of boys in a class are 8 times the number of girls, which value can never be the total number of boys?
A.A - 16
B.B - 9
C.C - 10
D.D - 11
Answer: A.A - 16
Explanation: Let the number of girls = x and the number of boys = 8x Then, total number of students = x + 8x = 9x i.e., the total number of boys must be a multiple of 8 From the given choices, only 16 is multiple of 8. Answer is A.
Question: Three business people who wish to invest in a new company. Each person is willing to pay one third of the total investment. . After careful calculation, they realize that each of them would pay $ 7800 less if they could find two more equal investors. How much is the total investment in the new business.
A.a)	$ 58,500
B.b)	$ 54,000
C.c)	$ 21,000
D.d)	$ 5,400
Answer: A.a)	$ 58,500
Explanation: Initially each invest in x. Hence total investment is 3x.
Total investment is also 5(x-7800).
3x = 5(x-7800)
x= 5*7800/2 = 19500
3x = 58500 and the answer is A.
Question: Evaluate combination
16C2
A.120
B.1000
C.10
D.1
Answer: A.120
Explanation: Explanation:
nCn=1
nCr=n!/r!(n-r)!
16C2=16!/2!(16-2)!=120
Option A
Question: Find the largest number which divides 62,132,237 to leave the same reminder
A.30
B.32
C.35
D.45
Answer: C.35
Explanation: Explanation:
Trick is HCF of (237-132), (132-62), (237-62)
= HCF of (70,105,175) = 35
Option C
Question: A number of 47 marbles is to be divided and contain with boxes. If each box is to contain 3, 4, or 5 marbles, what is the largest possible number of boxes?
A.10
B.12
C.15
D.16
Answer: C.15
Explanation: To maximize # of boxes we should minimize marbles per box: 14*3+1*5=47 --> 14+1=15.
Answer: C.
Question: In the rectangular coordinate system, points (2, 0) and (– 2, 0) both lie on circle C. What is the maximum possible value of the radius of C ?
A.2
B.4
C.8
D.16
Answer: A.2
Explanation: The answer is A
It takes 3 distinct points to define a circle. Only 2 are given here.
The two points essentially identify a single chord of the circle C. Since no other information is provided, however, the radius of the circle can essentially be anything. All this information tell us is that the radius isgreater 2
Question: In an office, totally there are 6400 employees and 65% of the total employees are males. 25% of the males in the office are at-least 50 years old. Find the number of males aged below 50 years?
A.3127
B.3128
C.3120
D.3122
Answer: C.3120
Explanation: Number of male employees = 6400 * 65/100 = 4160
Required number of male employees who are less than 50 years old = 4160 * (100 - 25)%
= 4160 * 75/100 = 3120.
Answer: C
Question: A corporation seven times its annual bonus to 5 of its employees. What percent of the employees’ new bonus is the increase?
A.1.35%
B.85.71%
C.3.12%
D.4.78%
Answer: B.85.71%
Explanation: Let the annual bonus be X.
A corporation triples its annual bonus.
So new bonus = 7X.
Increase = 7X-X =6X
The increase is what percent of the employees’ new bonus
= (6X/7X)*100
= 85.71%
Hence B.
Question: A boatman can row 3 km against the stream in 20 minutes and return in 18 minutes. Find the rate of current ?
A.1/3 kmph
B.2/3 kmph
C.1/4 kmph
D.1/2 kmph
Answer: D.1/2 kmph
Explanation: Explanation:
Speed in upstream = Distance / Time = 3 x 60/20 = 9 km/hr.
Speed in downstream = 3 x 60/18 = 10 km/hr
Rate of current = (10-9)/2 = 1/2 km/hr.
ANSWER IS D
Question: The population of a town is 10000. It increases annually at the rate of 15% p.a. What will be its population after 2 years?
A.13300
B.13350
C.13225
D.13500
Answer: C.13225
Explanation: Formula :
( After =100 denominator
Ago = 100 numerator)
10000 Ã— 115/100 Ã— 115/100 = 13225
C
Question: Ifaequals the sum of the even integers from 2 to 100, inclusive, andbequals the sum of the odd integers from 1 to 99, inclusive, what is the value of a - b ?
A.1
B.50
C.19
D.20
Answer: B.50
Explanation: This is a solution from Beatthegmat:
even numbers:
(100-2)/2 + 1 = 50 even integers.
(100+2)/2 = 51 is the average of the even set.
sum = avg*(#of elements) = 51*50 = 2550 = a
odd numbers:
(99-1)/2 + 1 = 50 odd integers.
(99+1)/2 = 50 is the average of the odd set.
sum = avg*(#of elements) = 50*50 = 2500 = b
a-b = 2550 - 2500 = 50. (B)
Question: maximun number of identical pieces(of same size) of a cake by making only 3 cuts?
A.6
B.7
C.8
D.9
Answer: C.8
Explanation: since cake is a 3D object, it will have length,breadth, height...
first cut across length now we will get2 pieces
then cut across breadth we will get 4 parts in total now...
now cut across height, finally we will get 8 parts...
ANSWER:C