RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What was the day on 15th august 1947 ?
A.Friday
B.Monday
C.Wednesday
D.Thursday
Answer: A.Friday
Explanation: 15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)
Odd days in 1600 years = 0
Odd days in 300 years = 1
46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day
Jan. Feb. Mar. Apr. May. Jun. Jul. Aug
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 1 ) = 213 days = (30 weeks + 3 days) = 3 odd days.
Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days.
Given day is Friday.
Answer is A.
Question: In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 0vers to reach the target of 282 runs?
A.6.25
B.6.5
C.6.75
D.7
Answer: A.6.25
Explanation: Sol.
Required run rate = 282 – (3.2 × 10 / 40)
= 240 / 40
= 6.25.
Answer A
Question: Monica planned her birthday party. She prepared 5 muffins for each of her guests and kept aside two additional muffins in case someone will want extra. After the party, it turned out that one of the guests didn't come but every one of the guests that did come ate six muffins and 6 muffins remained. How many guests did Monica plan on?
A.3.
B.4.
C.2.
D.6.
Answer: C.2.
Explanation: 5N +2 = 6 + 6(N-1)
Solving N= 2
Hence C
Question: The distance light travels in one year is approximately 5,880,000,000,000 miles. The distance light travels in 100 years is
A.A) 587 × 108 miles
B.B) 587 × 1010 miles
C.C) 587 × 10-10 miles
D.D) 588 × 1012 miles
Answer: D.D) 588 × 1012 miles
Explanation: The distance of the light travels in 100 years is:
5,880,000,000,000 × 100 miles.
= 588,000,000,000,000 miles.
= 588 × 1012 miles.
The answer is (D)
Question: what is the angle between the hands of a clock when time is 16:40?
A.625deg
B.420deg
C.145deg
D.150deg
Answer: B.420deg
Explanation: Angle between two hands =
40h - 11/2 m = 40*16 - 40*11/2 = 640 - 220 = 420deg
ANSWER:B
Question: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
A.175
B.185
C.165
D.155
Answer: A.175
Explanation: Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x x 3.20 = 432
3.20x = 432 - 384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175.
Answer is A.
Question: During the months May through October, Teddy the bear triples his weight, and during the months November through April, Teddy loses 100 pounds. If at the beginning of November 1973, Teddy's weight was m pounds, what was Teddy's weight in pounds by the end of April 1976?
A.9m−1300
B.9m−300
C.4m−1200
D.3m−300
Answer: A.9m−1300
Explanation: Nov ' 73 = m
April ' 74 = m - 100
Oct ' 74 = 3m - 300
April' 75 = 3m - 400
Oct' 75 = 9m - 1200
April'76 = 9m - 1300
Hence answer will be (A) 9m - 1300
Question: Stephanie wants to buy lipsticks. Each lipstick costs $20. How much will she pay if she decides to buy 5 lipsticks?
A.$500
B.$100
C.$20
D.$10
Answer: B.$100
Explanation: B. $100
Question: The distance between A&B is 600km. A person is traveling from A to B at 80km/hr started at 11AM and another person is traveling from B to A at 70km/hr and started at same time. Then at what time they meet together.?
A.A)2PM
B.B)4PM
C.C)1PM
D.D)3PM
Answer: D.D)3PM
Explanation: Let x hours be they will meet together
distance covered by 1st person+distance covered by 2nd person = 600km
70x+80x = 600
x= 4 hr
They will meet = 11AM +4hr = 3PM
Answer is D
Question: There are two concentric circles with radii 6 and 4. If the radius of the outer circle is increased by 50% and the radius of the inner circle decreased by 25%, by what percent does the area between the circles increase?
A.160
B.210
C.260
D.310
Answer: C.260
Explanation: The area of a circle is piR^2, where R is the radius.
The area of the big circle is 36pi.
The area of the small circle is 16pi.
The area A1 between the circles is 20pi.
When the big circle's radius increases, the new area is 81pi.
When the small circle's radius decreases, the new area is 9pi.
The area A2 between the circles is 72pi.
The ratio of A2/A1 is 72/20 = 3.6 which is an increase of 260%.
The answer is C.
Question: A basket has 5 apples and 4 oranges. Three fruits are picked at random. The probability that at least 2 apples are picked is?
A.25/42
B.25/421
C.35/42
D.25/82
Answer: A.25/42
Explanation: Total fruits = 9
Since there must be at least two apples,
(5C2 * 4C1)/9C3 + 5C3/9C3
= 25/42.
Answer: A
Question: Arun got 30% of the maximum marks in an examination and failed by 10 marks. However, Sujith who took the same examination got 40% of the total marks and got 15 marks more than the passing marks. What were the passing marks in the examination?
A.90
B.250
C.75
D.85
Answer: D.85
Explanation: Explanation :
Let x is the maximum marks of the examination
Marks that Arun got = 30 % of x = 30x/100
Given that Arun failed by 10 marks
⇒Minimum Pass Mark = (30x/100) + 10......(Equation 1)
Answer : Option D
Question: Two pipes A and B can fill a tank in 18 hours and 24 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?
A.20 hours
B.15 hours
C.10 hours
D.10 2/7 hours
Answer: D.10 2/7 hours
Explanation: Part filled by A in 1 hour = 1/18
Part filled by B in 1 hour = 1/24
Part filled by (A+B) in 1 hour = 1/18 + 1/24 = 7/72
Both the pipes together fill the tank in 72/7 = 10 2/7 hours
Answer is D
Question: The average of 1st 3 of 4 numbers is 16 and of the last 3 are 15. If the sum of the first and the last number is 13. What is the last numbers?
A.3
B.5
C.9
D.8
Answer: B.5
Explanation: A + B + C = 48
B + C + D = 45
A + D = 13
A – D = 3
A + D = 13
2D = 10
D = 5
Answer:B
Question: Tickets numbered from 1 to 20 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bearsa number which is a multiple of 3?
A.3/11
B.3/7
C.3/10
D.2/5
Answer: C.3/10
Explanation: Here, S = [1, 2, 3, 4, …., 19, 20]
Let E = event of getting a multiple of 3 = [3, 6, 9, 12, 15, 18]
P (E) = n (E) / n (S) = 6 / 20 = 3/10
C
Question: 9548 + 7314 = 8362 + (?)
A.8300
B.8400
C.8500
D.8700
Answer: C.8500
Explanation: 9548 16862 = 8362 + x
+ 7314 x = 16862 - 8362
----- = 8500
16862
-----
C)
Question: One millisecond is 0.001 of a second. The costs for a single run of a computer program are $1.04 for operating-system overhead, $0.023 per millisecond of computer time, and $4.35 for the mounting of a data tape. What is the total of these three costs for 1 run of a program that requires 1.5 seconds of computer time ?
A. $39.89
B. $48.87
C. $58.96
D. $65.57
Answer: A. $39.89
Explanation: Operating system overhead for 1 run = 1.04 $
Mounting of data tape = 4.35$
Cost per 1 millisecond of computer time = .023 $
Total cost of 1 run of a program that requires 1.5 seconds of computer time
= 1.04 + (.023*1500) + 4.35
=1.04 + 34.5 + 4.35
= 39.89$
Answer A
Question: Reema took a loan of Rs 1500 with simple interest for as many years as the rate of interest. If she paid Rs. 735 as interest at the end of the loan period, what was the rate of interest.
A.5%
B.6%
C.7%
D.8%
Answer: C.7%
Explanation: Explanation:
Let rate = R% then Time = R years.
=>1500∗R∗R /100=735
=>R2=49
=>R=7%
Option C
Question: The tax on a commodity is diminished by 30% but its consumption is increased by 20%. Find the decrease percent in the revenue derived from it?
A.18%
B.72%
C.32%
D.16%
Answer: D.16%
Explanation: 100 * 100 = 10000
70 * 120 = 8400
10000------- 1600
100 ------- ? = 16%
Answer:D
Question: If y exceeds x by 20%, then x is less than y by?
A.16 2/7%
B.16 2/8%
C.16 2/3%
D.16 2/9%
Answer: C.16 2/3%
Explanation: X=100	y=120
120------20
100-------? => 16 2/3%
Answer:C
Question: A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
A.2 mins
B.3 mins
C.9 mins
D.8 mins
Answer: B.3 mins
Explanation: D = 25 * 60 + 1500 = 3000 m
T = 3000/60 * 18/5 = 180 sec = 3 mins
Answer:B
Question: Scott's average (arithmetic mean) golf score on his first four rounds was 18.What score does he need on his fifth round to drop his average score by 2 points?
A.68
B.72
C.8
D.88
Answer: C.8
Explanation: Average score for first 4 rounds = 18
Average score after 5 rounds = 16
Score Scott needs on his 5th round to drop average score by 2 points = 18 - (2*5) = 8
Answer C
Question: In a hockey league there are 10 teams. Each team plays every other team once. If we can play 5 games every week, how many weeks long is one season?
A.8
B.9
C.18
D.20
Answer: B.9
Explanation: total matches = 10*9/2 = 45
so number of weeks = 45/5 = 9
ANSWER:B
Question: The jogging track in a sports complex is 627 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in?
A.4.56 min
B.5.28 min
C.5.08 min
D.9.28 min
Answer: A.4.56 min
Explanation: Clearly, the two will meet when they are 627 m apart.
To be (4.5 + 3.75) = 8.25 km apart, they take 1 hour.
To be 627 m apart, they take (100/825 * 627/1000) hrs = (627/8250 * 60) min = 4.56 min.
Answer: A
Question: A train passes a platform in 35 seconds. The same train passes a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, The length of the platform is
A.280 meter
B.240 meter
C.225 meter
D.200 meter
Answer: C.225 meter
Explanation: Explanation:
Speed of the train = 54 km/hr = (54×10)/35 m/s = 15 m/s
Length of the train = speed × time taken to cross the man = 15×20 = 300 m
Let the length of the platform = L
Time taken to cross the platform = (300+L)/15
=> (300+L)/15 = 35
=> 300+L = 15×35 = 525
=> L = 525-300 = 225 meter
Answer: Option C
Question: Having scored 99 runs in the 19th inning, a cricketer increases his average score by 4. What will be his average score after 19 innings?
A.28
B.27
C.26
D.22
Answer: B.27
Explanation: Explanation :
Let the average score of the first 18 innings be n
18n + 99 = 19(n+4)=> n = 23
So, Average score after 19th innings = x+4 =27.
Answer : B
Question: An investor deposited $5,000 to open a new savings account that earned 12 percent annual interest, compounded quarterly. If there were no other transactions in the account, what was the amount of money in the account 6 months after the account was opened?
A.$5300.50
B.$5304.50
C.$5405.50
D.$5604.50
Answer: B.$5304.50
Explanation: The amount in the account after 6 months is 1.03*1.03($5,000) = $5304.50.
The answer is B.
Question: Car A runs at the speed of 55 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 70 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B?
A.3 : 7
B.4 : 9
C.11 : 7
D.5 : 7
Answer: C.11 : 7
Explanation: Car A travels 55 × 8 = 440 km
Car B travels 70 × 4 = 280 km
The ratio is 440 : 280 = 44 : 28 = 11 : 7
The answer is C.
Question: Can anyhow help me with an easy solution for this
2, 7, 36, 4, 14, 225, 6, 21, ?
A.576
B.476
C.376
D.276
Answer: A.576
Explanation: 2, 7, 36, 4, 14, 225, 6, 21, ?
2+7=9 and 9-3=6 and 6^2=36
4+14=18 and 18-3=15 and 15^2=225
6+21=27 and 27-3=24 and 24^2=576
ANSWER:A
Question: Simple interest on a certain sum of money for 2 years at16% per annum is one fourth the compound interest on Rs. 4000 for 2 years at 8% per annum. The sum placed on simple interest is
A.Rs.4000
B.Rs.665.6
C.Rs.520
D.Rs.166.4
Answer: C.Rs.520
Explanation: Solution
C.I.	=Rs[4000x(1+8/100)Â²-4000]
Rs.(4000x108/100x108/100-4000)	= Rs.665.6.
Sum	=Rs. [166.4x100 /2x16]
= Rs.520.
Answer C
Question: Each week, Harry is paid x dollars per hour for the first 35 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ?
A.35
B.36
C.34
D.38
Answer: C.34
Explanation: James worked for 41 hours hence he earned 40*x+1*2x=42x dollars;
We know that Harry also earned the same 42x dollars, out of which he earned 35x dollars for thefirst 35 hoursplus 7x additional dollars. Since for each additional hour he gets 1.5x dollars then he worked for 7x/1.5x= 4 additional hours, so Harry worked for total of 30+4=34 hours.
Answer: C.
Question: A and B complete a work in 6 days. A alone can do it in 10 days. If both together can do the work in how many days?
A.7.75 days
B.2.75 days
C.5.75 days
D.3.75 days
Answer: D.3.75 days
Explanation: D
3.75 days
1/6 + 1/10 = 8/30 = 4/15
15/4 = 3.75 days
Question: Find the distance covered by a man walking for 30min at a speed of 10km/hr?
A.1km
B.3km
C.4km
D.5km
Answer: D.5km
Explanation: Distance = 10*20/60 = 5km
Answer is D
Question: How many possible integer values are there for x if |x - 3| < 6 ?
A.One
B.Two
C.Three
D.eleven
Answer: D.eleven
Explanation: Solution: |x-3| < 6
let x=a therefore we have |a-3| < 6 ==> read this as origin is at +3 and we have to move +6 to the right and -6 to the left
(the less than sign represents that the a must be within boundaries )
(3-6)----------3----------(3+6)
now, we have -3<a<9
but a =x ==> -3<x<9
Now question says Integer values (not rational ) therefore we have -2,-1,0,1,2,3,4,5,6,7,8
Hence 11 D
Question: ’A’ sold an article to ’B’ at a profit of 20%. ’B’ sold the same article to ’C’ at a loss of 25% and ’C’ sold the same article to ’D’ at a profit of 40%. If ’D’ paid Rs 252 for the article, then find how much did ’A’ pay for it?
A.Rs 175
B.Rs 200
C.Rs 180
D.Rs 210
Answer: B.Rs 200
Explanation: Let the article costs ‘X’ to A
Cost price of B = 1.2X
Cost price of C = 0.75(1.2X) = 0.9X
Cost price of D = 1.4(0.9X) = 1.26X = 252
Amount paid by A for the article = Rs 200
ANSWER:B
Question: A starts a business with a capital of Rs. 30,000. B joins in the business with Rs.12000 after some time. For how much period does B join, if the profits at the end of the year are divided in the ratio of 3 : 1?
A.5 months
B.6 months
C.7 months
D.10 months
Answer: D.10 months
Explanation: Explanation :
Let B joins for x months. Then
A:B = 30000*12 : x* 12000 = 3 : 1
=> 30*12 : 12x= 3 : 1
=> 30*12/ 12x = 3/1 = 3
=> 30*4 /12x = 1
=> 10/x = 1
=> x = 10. Answer : Option D
Question: If â€œ*â€ is called â€œ+â€, â€œ/â€ is called â€œ*â€, â€œ-â€ is called â€œ/â€, â€œ+â€ is called â€œ-â€. 240-80 / 60 - 40 * 10 = ?
A.14.5
B.13.5
C.12.5
D.17.5
Answer: A.14.5
Explanation: Explanation:
Given : 240-80 / 60 - 40 * 10 = ?
Substituting the coded symbols for mathematical operations, we get,
240 / 80 * 60 / 40 + 10 = ?
3*1.5+10 = 14.5
ANSWER : A
Question: The tax on a commodity is diminished by 30% but its consumption is increased by 15%. Find the decrease percent in the revenue derived from it?
A.20%
B.18%
C.15%
D.12%
Answer: A.20%
Explanation: 100 * 100 = 10000
70 * 115 = 8050
10000------- 1950
100 ------- ? = 20%
ANSWER:A
Question: A = {2, 3, 4, 5}
B = {4, 5, 6, 7, 8}
Two integers will be randomly selected from the sets above, one integer from set A and one integer from set B. What is the probability E that the sum of the two integers will equal 9 ?
A. 0.15
B. 0.20
C. 0.25
D. 0.30
Answer: B. 0.20
Explanation: Rearrange the first set:
A = {5,4,3,2}
B = {4,5,6,7, 8}
As you can see numbers in each column (the numbers of the same color) give the sum of 9. So there are 4 such pares possible, total # of pairs is 4*5=20. E=favorable/total=4/20=0.2.
Answer: B.
Or: we can select ANY number from set A (4/4=1) but in this case we must select its matching pair from set B (the number of the same color) and since there are only one matching pair of this particular number in B then the probability of this is 1/5. So, overall: E=1*1/5.
Answer: B.
Question: Two digits in John's age are the same as the digit in the Wilson's age, but in reverse order. In 21 years John will be twice as old as Wilson will be then. what is the difference in their current age ?
A.25
B.43
C.14
D.36
Answer: D.36
Explanation: John's age= 10x+y so Wilson's age= 10y+x..
after 21 years , 10x+y+21=2*(10y+x+21)....
so 21+19y=8x... check for odd values of y, y=1 satisfies the eqn with x=5... so ages are 51 and 15 and ans as found correctly by u is D..36
Question: The present worth of a certain bill due sometime hence is Rs.800 and the true discount is Rs.36.The banker’s discount is
A.Rs.34.38
B.Rs.38.98
C.Rs.37
D.Rs.37.62
Answer: D.Rs.37.62
Explanation: Solution
B.G	= [(T.D)² / P. W]
= Rs. (36 x 36 / 800)
= Rs.1.62
B.D
Given, T.D =36	= (T.D + B.G)
= Rs. (36 + 1.62)
= Rs.37.62.
Answer D
Question: Twenty women can do a work in sixteen days. Sixteen men can complete the same work in fifteen days. What is the ratio between the capacity of a man and a woman?
A.3 : 4
B.4 : 3
C.5 : 3
D.Data inadequate
Answer: B.4 : 3
Explanation: Explanation:
(20 x 16) women can complete the work in 1 day.
1 woman's 1 day's work =1/320
(16 x 15) men can complete the work in 1 day.
1 man's 1 day's work =	1/240
So, required ratio
=	1/240 =1/320
=1/3 : 1/4
= 4 : 3 (cross multiplied)
ANSWER IS B
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
A.18
B.74
C.15
D.44
Answer: D.44
Explanation: Explanation:
Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352 => T = 44.
Correct Option : D
Question: What is the smallest integer T greater than 1 that leaves a remainder of 1 when divided by any of the integers 6, 8, and 10?
A.21
B.41
C.T=121
D.241
Answer: C.T=121
Explanation: Or u can just use the answer choices here. Since the answers are already arranged in ascending order, the first number which gives remainder T as 1 for all three is the correct answer. In the given question, the first number which gives a remainder of 1 for 6,8 and 10 is 121.C
Question: What is the minimum percentage increase in the mean of set A {-4, -1, 0, 6, 9} if its two smallest elements are replaced with two different primes?
A. 25%
B. 50%
C. 75%
D. 100%
Answer: D. 100%
Explanation: Mean of A is (-4-1+0+6+9)/5=2;
In order the increase to be minimal we should replace two smallest elements of A, which are -4 and -1, with two smallest primes, which are 2 and 3. Hence our new set will be {2, 3, 0, 6, 9} --> new mean is (2+3+0+6+9)/5=4.
Percent increase=(4-2)/2*100=100%.
Answer: D.
Question: If [[x]] = x^2 + 2x + 4, what is the value of [[2]]?
A.3
B.9
C.12
D.19
Answer: C.12
Explanation: These functions questions might look intimidating, but they just test your knowledge about how well you can substitute values
[[x]] = x^2 + 2x + 4
[[2]] = 2^2 + 2*2 + 4 = 12. Option C
Question: If anangletis defined as 1 percent of 1 degree, then how many anglets are there in a fifth circle?
A.0.36
B.7200
C.360
D.3,600
Answer: B.7200
Explanation: 1 degree * 1/100 = 1 anglet
So 1 degree = 100 anglets
=> 72 degrees = 7200 anglets
Answer - B
Question: A motorboat can go at 21 kmph and still water. It takes 7 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 3 kmph?
A.65 km
B.85 km
C.55 km
D.72 km
Answer: D.72 km
Explanation: Let the distance between A and B be x km.
Total time = x/(21 + 3) + x/(21 - 3) = 7
=> x/24 + x/18 = 7 => (4x + 3x)/72 = 7 => x = 72 km.
ANSWER:D
Question: A given line L has an equation 3x+4y=5. Which of the following is the equation of line which is perpendicular to the above line?
A. 4x - 3y = 5
B. 3x + 4y = 10
C. 3x + 5y = 5
D. 3x + 5y = 3
Answer: A. 4x - 3y = 5
Explanation: For lines to be perpendicular ,
slope of line 1 * slope of line 2 = -1
(-3/4) * (x) = -1
x = (4/3)
where x is slope of line 2
Ans - A
Question: The cost price of a radio is Rs.1860 and it was sold for Rs.1340, find the loss %?
A.18%
B.12%
C.22%
D.27%
Answer: D.27%
Explanation: 1860 ---- 520
100 ---- ? => 27%
Answer:D
Question: A can do a piece of work in 24 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in ?
A.3 days
B.5 days
C.6 days
D.7 days
Answer: C.6 days
Explanation: B's 9 day's work = 9 x (1/12) = 3/4
Remaining work = (1 - 3/4) = 1/4
1/4 work is done by A in = 24 x (1/4) = 6 days.
answer : C
Question: A, B, C rent a pasture. A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing. If the rent of the pasture is Rs. 175, how much must C pay as his share of rent?
A.40
B.45
C.50
D.55
Answer: B.45
Explanation: A : B : C = (10 x 7) : (12 x 5) : (15 x 3) = 70 : 60 : 45 = 14 : 12 : 9.
C's rent = Rs.175 x 9/35 = Rs. 45.
answer :B
Question: If the wheel is 14 cm then the number of revolutions to cover a distance of 1056 cm is?
A.11
B.14
C.18
D.12
Answer: D.12
Explanation: 2 * 22/7 * 14 * x = 1056 => x = 12
Answer: D
Question: The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean score of 31. The mean score of remaining 55% is:
A.45
B.50
C.51.4 approx.
D.54.6 approx.
Answer: C.51.4 approx.
Explanation: Let the required means score be x. Then,
20 * 80 + 25 * 31 + 55 * x = 52 * 100
= 1600 + 775 + 55x = 5200
= 55x = 2825
= x = 565/11 = 51.4.
ANSWER:C
Question: Out of a total 85 children playing badminton or table tennis or both, total number of girls in the group is 70% of the total number of boys in the group. The number of boys playing only badminton is 50% of the number of boys and the total number of boys playing badminton is 60% of the total number of boys. The number of children playing only table tennis is 40% of the total number of children and a total of 12 children play badminton and table tennis both. What is the number of girls playing only badminton?
A.16
B.14
C.17
D.Data inadequate
Answer: B.14
Explanation: Let the number of boys= x
then x + 7x⁄10 = 85 or x = 50
No. of girls = 85 – 50 = 35
Answer B
Question: There are 35 students in a hostel. If the no. of students increases by 12, the expenses of the mess increase by Rs.42/day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess?
A.259.58
B.340.58
C.342.58
D.345.58
Answer: A.259.58
Explanation: Suppose the average join the mess , total expenditure = 35x + 42
Now, the average expenditure = (35x + 42)/ (35 + 12) = x – 1
or, 35x + 42 = 47x – 47
or, x = 7.42
Thus the original expenditure of the mess = 35 x 7.42 = Rs. 259.58
A
Question: A and B can do a work in 1 day, B and C in 2 days and C and A in 3 days. In how many days will the work be completed, if all three of them work together?
A.12/11
B.12/24
C.13/16
D.18/12
Answer: A.12/11
Explanation: One day work of A and B = 1/1
One day work of B and C = 1/2
One day work of C and A = 1/3
2(A + B + C) = 1/1+ 1/2 + 1/3
2(A + B + C) = 11/6
(A + B + C) = 11/12
Number of days required = 12/11 days.
Answer: A
Question: A man speaks truth 3 out of 4 times. He throws a die and reports it to be a 6.
What is the probability of it being a 6?
A.3/5
B.1/2
C.3/4
D.3/8
Answer: D.3/8
Explanation: Explanation :
There are two cases
1) He is telling truth that the die reports 6, its probability = 3/4*1/6 = 1/8
2) He is telling lie that the die reports 6, its probability = 1/4*5/6 = 5/24
So required probability = (1/8)/(1/8)+(5/24) = (1/8)/(1/3) = 3/8
Hencer (D) is the correct answer
Answer : D
Question: Which of the following is not the square of an integer?
A.455625
B.458623
C.227529
D.261121
Answer: B.458623
Explanation: The square of an integer (n^2) can have only the following units digit:
0, if the units digit of n is 0;
1, if the units digit of n is 1 or 9;
4, if the units digit of n is 2 or 8.
5, if the units digit of n is 5;
6, if the units digit of n is 6 or 4;
9, if the units digit of n is 3 or 7.
The square of an integer cannot have the units digit of 2, 3, 7, or 8.
The answer is B.