RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: There is an increase of 30% in the production of milk chocolates in Amul Dairy in one month. If now it is 9,100 milk chocolates per month, what was it one month ago?
A.10,000 chocolates
B.9000 chocolates
C.8000 chocolates
D.7000 chocolates
Answer: D.7000 chocolates
Explanation: Let one month ago, production be x chocolates.
Then, 130 % of x = 9100
⇒ x = 9100×100/130=7000 chocolates
Answer D
Question: Which of the following cannot be the range of a set consisting of 5 odd multiples of 13?
A.52
B.100
C.104
D.208
Answer: B.100
Explanation: Solution: sequence of 13 lets say sequence is 13n, 13(n+1), 13(n+2), 13(n+3), 13(n+4)
so range is 13n+52-13n = 52
if we put the different values of n we will get different but the range will be multiple of 52
and only 100 is not multiple of 52
Answer : B
Question: A and B started a business with an investment of Rs.26000 and Rs.28000. After two months C joined in the business with an investment of Rs.32000, what is share of C in the half year profit of Rs.9040 ?
A.Rs.3360
B.Rs.3120
C.Rs.2940
D.Rs.2560
Answer: D.Rs.2560
Explanation: Investment x Time.
A = 26000 x 6 = 156000.
B = 28000 x 6 = 168000.
C = 32000 x 4 = 128000.
Ratio of shares A : B : C = 39 : 42 : 32 = [ Total 113 units ]
Share of C in the profit = 9040 × 32 / 113 = 2560
Option D
Question: A shopkeeper has 280 kg of apples. He sells 40% of these at 10% profit and remaining 60% at 30% profit. Find his % profit on total.
A.22%
B.25%
C.26%
D.28%
Answer: A.22%
Explanation: If the total quantity was 100
Then 40X 10% + 60 X30%= 22
This profit will remain same for any total quantity unless the % of products remains the same. Hence 'A' is the answer
Question: The probability that A speaks truth is 3/5 and that of B speaking truth is 4/7. What is the probability that they agree in stating the same fact?
A.18/35
B.18/39
C.18/128
D.18/30
Answer: A.18/35
Explanation: Explanation:
If both agree stating the same fact, either both of them speak truth of both speak false.
Probability = 3/5 * 4/7 + 2/5 * 3/7
= 12/35 + 6/35 = 18/35
Answer:A
Question: In a kilometer race, A beats B by 50 meters or 10 seconds. What time does A take to complete the race?
A.277 sec
B.190 sec
C.667 sec
D.167 sec
Answer: B.190 sec
Explanation: Time taken by B run 1000 meters = (1000 * 10)/50 = 200 sec.
Time taken by A = 200 - 10 = 190 sec.Answer: B
Question: In a race of length L metres, Johnson beats Lewis by P metres and Greene by Q metres, By how many metres does Lewis beat Greene in the same race ? (P<Q)
A.L(L-Q) / L-P
B.L(Q-P) / L-P
C.L-Q
D.P-Q
Answer: B.L(Q-P) / L-P
Explanation: As the time is constant, the ratio of distances will be the same as the ratio of speeds.
If Sj,Sl,Sg are the speeds of Johnson, Lewis, and Greene respectively, then
Sj/Sl = L/(L-P)
and Sj/Sg = L/(L-Q)
=> Sg/Sl = (L-Q)/(L-P)
Therefore the speeds of Lewis and Greene are in the ratio (L-P)/(L-Q)
When Lewis finishes the race, the time run by him and Greene are same
=> The ratio of the speeds of Lewis and Greene will be the same as the ratio of distances run by them.
=> Distance run by Greene when Lewis finishes the race = (L-Q)/(L-P) * L
=> Lewis beats Greene by L - L*(L-Q)/(L-P) = L [ 1 - (L-Q)/(L-P)] = L (Q-P) / (L-P)
Option (B) is therefore correct.
Question: The age of father 5 years ago was four times the age of his son. Five years hence, father's age will be twice that of his son. The ratio of their present ages is:
A.5 : 4
B.7 : 4
C.5 : 2
D.5 : 3
Answer: C.5 : 2
Explanation: Let the ages of father and son 5 years ago be 4x and x years respectively.
Then, (4x + 5) + 5= 2[(x + 5) + 5]
4x + 10 = 2x + 20
x = 5.
Required ratio = (4x + 5) : (x + 5) = 25: 10= 5 : 2.
Answer: Option C
Question: The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares
A.22 cm
B.24 cm
C.26 cm
D.28 cm
Answer: B.24 cm
Explanation: Explanation:
We know perimeter of square = 4(side)
So Side of first square = 40/4 = 10 cm
Side of second square = 32/4 = 8 cm
Area of third Square = 10*10 - 8*8
= 36 cm
So side of third square = 6 [because area of square = side*side]
Perimeter = 4*Side = 4*6 = 24 cm
Option B
Question: If the price of a certain bond on May 1st was 3/4 the price of the bond on June 1st and the price of the bond on July 1st was 50% greater than the price of the bond on May 1st. then the price of the bond on June 1st st was what percent of the average (arithmetic mean) price of the bond on May 1st and July 1st?
A.50%
B.114.28%
C.120%
D.133 1/3%
Answer: B.114.28%
Explanation: The price on June 1st = 12 (assume);
The price on May 1st = 3/4*12 = 9;
The price on July 1st = 8*1.5 = 12.
The average price of the bond on May 1st and July 1st = (9+12)/2 = 10.5.
The price of the bond on June 1st (12) is 24/21 times (114.28%) the average price of the bond on May 1st and July 1st.
Answer: B.
Question: The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.2.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
A.s.1014
B.s.1140
C.s.999
D.s.1665
Answer: D.s.1665
Explanation: a2 = 3136 => a = 56
56 * 4 * 3 = 672 – 6 = 666 * 2.5 = 1665
ANSWER:D
Question: Two trains are traveling on a collision course. If train A is traveling at a speed of 350 mph and train B is traveling 28% slower, how much time will it take the trains to collide if the initial distance between the two is 1806 miles?
A.Two hours and 30 minutes.
B.One hour and 10 minutes.
C.Two hours and 25 minutes.
D.Three hours and 0 minutes.
Answer: D.Three hours and 0 minutes.
Explanation: Answer is D. Three hours and 0 minutes.
Since they are racing towards each other, the speed is accumulative, ie. 350 mph + 350*0.72 = 602 (0.72 because the second train is 28% slower)
So time before collision is total distance / total speed = 1806/602 = 3 hours and 00 mins
Question: How long will a man take to go, walking at 4 km per hour, twice round a circular garden of 70 m radius
A.11
B.28
C.26
D.18
Answer: B.28
Explanation: Answer:B
Question: In each of the following questions a number series is given with one term missing. Choose the correct alternative that will continue the same pattern and fill in the blank spaces.
2, ?, 14, 23, 34, 47
A.31
B.7
C.36
D.31
Answer: B.7
Explanation: B
7
The given sequence is +5, +7, +9, ——
ie. 2+ 5 = 7, 7 + 7 = 14, 14 + 9 = 23
Question: The average of first ten prime numbers which are odd is?
A.15.2
B.15.7
C.15.4
D.15.8
Answer: D.15.8
Explanation: Sum of first 10 prime no. which are odd = 158
Average = 158/10
= 15.8
Answer:D
Question: 10 men, working 6 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days ?
A.2hours a day
B.7hours a day
C.6hours a day
D.3hours a day
Answer: C.6hours a day
Explanation: Explanation:
More Men, Less Hours {Indirect Proportion}
Less Days, More Hours {Indirect Proportion}
\inline {\color{Blue} \begin{bmatrix} Men &15 & 10\\ Days &12 & 18 \end{bmatrix}::6:x}
=> x * 15 * 12 = 10 * 18 * 6
=> x = (10 *18 *6)/(12*15)
=>x = 6
Answer: C
Question: By selling a house for Rs.72000, it was found that 1/5 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?
A.38020
B.57000
C.38028
D.38019
Answer: B.57000
Explanation: CP + CP/5 = 72000
CP = 60000
SP = 60000*(95/100)
=57000
Answer: B
Question: How many negative numbers are there in an alternating sequence of positive and negative numbers, if the sequence contains b numbers, where b is an odd number greater than 12. The first number of the sequence is a negative number.
A.(b-1)/2
B.(b+1)/2
C.b/2
D.b/(2-1)
Answer: B.(b+1)/2
Explanation: Lets put values for b, say b=13 since it's odd and it is grater than 12,
and first number is neg so sequence will be {neg,pos,neg,pos,neg,pos,neg,pos,neg,pos,neg,pos,neg} we can see that it has 7 positive terms
so putting bx=13 in the options,
option B = (b+1)/2 => (13+1)/2 = 7 , the number of positive integers
So, B is the answer
Question: The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq.cm. Find its height?
A.3 cm
B.6 cm
C.7 cm
D.9 cm
Answer: B.6 cm
Explanation: Solution
Let the height of the parallelogram be x cm.Then base
= (2x) cm
=2x² = 72
x²=36
x = 6.
Answer B
Question: How many ways can 10 friends be arranged around a circular dinner table?
A.6!
B.7!
C.8!
D.9!
Answer: D.9!
Explanation: The number of ways to order 10 people is 10!
However, around a circular table, each pattern would be repeated 10 times.
So the number of ways to seat 10 friends around a circular table is 9!
The answer is D.
Question: Replace X with the appropriate number in
1 , 3 , 5 , 7 , 8 , 9 , 10 , X
A.2
B.11
C.4
D.6
Answer: B.11
Explanation: B
list of consecutive numbers that has an 'e' in the spelling
Question: What will come in place of the x in the following Number series? 2, 7, 32, 157, 782, x
A.3707
B.3790
C.3910
D.3907
Answer: D.3907
Explanation: 22 x 5 - 3 = 77 x 5 - 3 = 3232 x 5 - 3 = 157157 x 5 - 3 = 782782 x 5 - 3 = 3907D
Question: In given series 582, 605, 588, 611, 634, 617, 600 only one number is incorrect. Find out that wrong number
A.615
B.634
C.600
D.620
Answer: B.634
Explanation: 582+23=605
605-17=588
588+23=611
611-17=594....so 634 is wrong.
594+23=617
617-17=600
ANSWER:B
Question: Find the value for x from below equation: x/3=-4?
A.-12
B.1
C.-2
D.-3
Answer: A.-12
Explanation: 1. Multiply both sides by 3:
x*3/3= -4/3
. Simplify both sides:
x = -12
A
Question: A college has classes from 10:00 AM until 1:40 PM. In this duration, there are five periods. If 5 minutes are provided between each period to leave one class and enter the next class, how many minutes long is each period?
A.38 min
B.41 min
C.40 min
D.42 min
Answer: C.40 min
Explanation: The total time is 220 minutes.
There are four breaks of five minutes between the classes for a total of 20 minutes.
The total class time is 200 minutes.
200 / 5 classes = 40 minutes per class
The answer is C.
Question: Rajan and Rakesh started a business and invested Rs. 20,000 and Rs. 25,000 respectively. After 4 months Rakesh left and Mukesh joined by investing Rs. 15,000. At the end of the year there was a profit of Rs. 4,600. What is the share of Rakesh ?
A.1000
B.1100
C.1125
D.1200
Answer: A.1000
Explanation: Ratio of share of Rajan, Rakesh nd Mukesh => 20000:25000:15000
=>4:5:3
=>4*12 : 5*4 : 3*8 [Since Rakesh left after 4 months nd Mukesh joined after 4 months...]
=> 12:5:6
Share of Rajan => 4600*12/23 = 2400
Share of Rakesh => 4600*5/23 = 1000
ANSWER:A
Question: A man swims downstream 76 km and upstream 48 km taking 4 hours each time; what is the speed of the current?
A.3 kmph
B.1.5 kmph
C.3.5 kmph
D.6.5 kmph
Answer: C.3.5 kmph
Explanation: Explanation:
76 --- 4 DS = 19
? ---- 1
48 ---- 4 US = 12
? ---- 1 S = ?
S = (19 - 12)/2 = 3.5
Answer: Option C
Question: How many multiples of 8 are less than 7600, and also multiples of 19?
A.104
B.100
C.50
D.89
Answer: C.50
Explanation: LCM of 8 & 19 = 152
Tried dividing 7600 by 152
Got quotient 50'So C is answer
Question: The value of log2(log5625) is
A.2
B.5
C.10
D.15
Answer: A.2
Explanation: Solution
Let log5625	= x.
Then, 5x	= 625
= 54
‹=› x=4.
Let log2( log5625)	= y.
Then, log 24= y
‹=› 2y= 4
y;2.
Answer A
Question: Solve x2 â€“ 3x â€“ 4 = 0.
A.1,4
B.-1,4
C.2,3
D.2,4
Answer: B.-1,4
Explanation: This one factors easily:
x2 â€“ 3x â€“ 4 = 0
(x + 1)(x â€“ 4) = 0
x + 1 = 0 or x â€“ 4 = 0
x = â€“1 or x = 4
The solution is x = â€“1, 4
ANSWER B
Question: What is the product of all the prime factors of 25?
A.25
B.30
C.35
D.40
Answer: A.25
Explanation: 25 , factors are 5,1. Now again prime Number is Only 5 , this time we would have 5*5=25
Answer : A
Question: Jackie has two solutions that are 2 percent sulfuric acid and 12 percent sulfuric acid by volume, respectively. If these solutions are mixed in appropriate quantities to produce 60 liters of a solution that is 5 percent sulfuric acid, approximately how many liters of the 12 percent solution will be required?
A.18
B.20
C.24
D.36
Answer: A.18
Explanation: let a=amount of 2% acid and b= amount of 12% acid.
Now, The equation translates to,
0.02a + .12b = .05(a+b)
but a+b= 60
therefore .02a + .12b = .05(60)
=> 2a + 12b = 300
but b=60-a
therefore
2a+ 12(60-a) = 300
=> 10a = 420
hence a = 42., B = 60-42 =18
Answer :A
Question: There are 6 people and 3 chairs. In how many different ways people can occupy the chairs?
A.90
B.120
C.150
D.100
Answer: B.120
Explanation: number of ways =6*5*4 = 120
Answer is B
Question: If (-12x)^(4x) = 12x^(15 - x) and x is an integer, what is the value of x ?
A.5
B.4
C.3
D.2
Answer: C.3
Explanation: Since x is an integer, (-12x)^(4x) is always positive.
So, 12x^4x = 12x^(15 - x)
4x = 15 - x
5x = 15
x = 3
Answer: C
Question: There are 100 wine glasses. I offered my servant to 3 paise for every broken glass to be delivered safely and forfeit 9 paisa for every glass broken at the end of day. He recieved Rs.2.40 .how many glass did he break.
a. 20 b. 73 c. 5 d. 8
A.22
B.281
C.29
D.28
Answer: B.281
Explanation: Answer:B
Question: In a single throw of a die, what is probability of getting a number greater than 4?
A.2/3
B.4/3
C.1/3
D.5/7
Answer: C.1/3
Explanation: E= {5,6}
n(E)=2
P(S)=n(E)/n(S)
=2/6
=1/3
Ans: C
Question: 4, 12, 48, 240, 1440, (...)
A.7620
B.6200
C.10020
D.10080
Answer: D.10080
Explanation: Go on multiplying the given numbers by 3, 4, 5, 6, 7
4 x 3 =12; 12 x 4 = 48 .....1440 x 7 = 10080
Answer is D.
Question: A glass was filled with 15 ounces of water, and 0.05 ounce of the water evaporated each day during a 15-day period. What percent of the original amount of water evaporated during this period?
A.0.005%
B.0.05%
C.0.5%
D.5%
Answer: D.5%
Explanation: In 15 days 15*0.05=0.75 ounces of water evaporated, which is 0.75/15âˆ—100=5 of the original amount of water.
Answer: D.
Question: A rectangular block 6cm by 12cm by 15cm is cut into an exact number of equal cubes. Find the least possible number of cubes?
A.20
B.25
C.40
D.50
Answer: C.40
Explanation: Volume of the block = 6*12*15 = 1080 cm^3
Side of the largest cube = H.C.F of 6,12,15 = 3cm
Volume of the cube = 3*3*3 = 27 cm^3
Number of cubes = 1080/27 = 40
Answer is C
Question: If log 0.317 = 0.3332 and log 0.318 = 0.3364, then find log 0.319
A.0.3396
B.0.3496
C.0.3596
D.0.3696
Answer: A.0.3396
Explanation: log.318-log.317=.0032
log.318+log.oo1=log.319
.3364+.0032=.3396
ANSWER:A
Question: In a class of 120 students numbered 1 to 120, all even numbered students opt for Physics, whose numbers are divisible by 5 opt for Chemistry and those whose numbers are divisible by 7 opt for Math. How many opt for none of the three subjects?
A.19
B.41
C.21
D.26
Answer: B.41
Explanation: Explanatory Answer
We need to find out the number of students who took at least one of the three subjects and subtract that number from the overall 120 to get the number of students who did not opt for any of the three subjects.
Number of students who took at least one of the three subjects can be found by finding out A U B U C, where A is the set of those who took Physics, B the set of those who took Chemistry and C the set of those who opted for Math.
Now, AUBUC = A + B + C - (A n B + B n C + C n A) + (A n B n C)
A is the set of those who opted for Physics = 120/2 = 60 students
B is the set of those who opted for Chemistry = 120/5 = 24
C is the set of those who opted for Math = 120/7 = 17.
The 10th, 20th, 30th…… numbered students would have opted for both Physics and Chemistry.
Therefore, A n B = 120/10 = 12
The 14th, 28th, 42nd…. Numbered students would have opted for Physics and Math.
Therefore, C n A = 120/14 = 8
The 35th, 70th …. Numbered students would have opted for Chemistry and Math.
Therefore, A n B = 120/35 = 3
And the 70th numbered student would have opted for all three subjects.
Therefore, AUBUC = 60 + 24 + 17 - (12 + 8 + 3) + 1 = 79.
Number of students who opted for none of the three subjects = 120 - 79 = 41.
Answer B
Question: Find the area of a triangle whose sides are 41 cm, 28 cm, 15 cm. Also, find the length of the altitude corresponding to the largest side of the triangle.
A.4.1 cm
B.5.1 cm
C.6.1 cm
D.7.1 cm
Answer: C.6.1 cm
Explanation: Semi-perimeter of the triangle = (a + b + c)/2
= (41 + 28 + 15)/2
= 84/2
= 42 cm
Therefore, area of the triangle = √(s(s - a) (s - b) (s - c))
= √(42 (42 - 41) (42 - 28) (42 - 15)) cm²
= √(42 × 1 × 27 × 14) cm²
= √(3 × 3 × 3 × 3 × 2 × 2 × 7 × 7) cm²
= 3 × 3 × 2 × 7 cm²
= 126 cm²
Now, area of triangle = 1/2 × b × h
Therefore, h = 2A/b
= (2 × 126)/41
= 252/41
= 6.1 cm
ANSWER : OPTION C
Question: What is the greatest prime factor of 4^6 - 1?
A.13
B.17
C.19
D.23
Answer: A.13
Explanation: 4^6-1 = (4^3-1)(4^3+1) = 63*65 = 7*9*5*13
The answer is A.
Question: The H.C.F. of two numbers is 10 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
A.100
B.120
C.180
D.140
Answer: D.140
Explanation: Clearly, the numbers are (10 x 13) and (10 x 14).
Larger number = (10 x 14) = 140. Answer: Option D
Question: 7% of the total quantity of rice is lost in grinding when a country has to import 6 million tonnes, but when only 7 3/4% is lost, it can import 3 million tonnes. Find the quantity of rice grown in the country.
A.200
B.300
C.400
D.450
Answer: C.400
Explanation: Let x be the total grown quantity of wheat. According to the question
(7%of x)+ 64 31 %of x)+3 7x 31x => 100+ 6 = 400 + 3 1200 x = — 400 million tonnes rice grown
C
Question: Rahul went to a shop and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
A.Rs. 15
B.Rs. 17
C.Rs. 19.7
D.Rs. 21
Answer: C.Rs. 19.7
Explanation: Total cost of the items he purchased = Rs.25
Total tax incurred = 30 paise = Rs.
30
100
30100
Let the cost of the tax free items
=
x
=x
Given that tax rate = 6%
∴
(
25
−
30
100
−
x
)
6
100
=
30
100
⇒
6
(
25
−
0.3
−
x
)
=
30
⇒
(
25
−
0.3
−
x
)
=
5
⇒
x
=
25
−
0.3
−
5
=
19.7
Option C
Question: A Train requires 8 seconds to pass a pole while it requires 18 seconds to cross a stationary train which is 400 mtrs long. Find the speed of the train.
A.144 kmph
B.124 kmph
C.134 kmph
D.150 kmph
Answer: A.144 kmph
Explanation: In 8s the train crosses the pole and in 18 sec the train crosses one more stationary train
In 10 sec the train travels a distance of 400 mtrs
Speed = 400/10 = 40 m/s = 40 (3600/1000) = 40 * 18/5 = 144 kmph
Answer: A
Question: Which of the following points falls outside of the region defined by 2y≤4x−12?
A.(5, 1)
B.(3, -8)
C.(2, 0)
D.(1, -2)
Answer: C.(2, 0)
Explanation: Equation given is 2y<=4x-12
Simplifying this; y<=2x-6
Plug in the values provided in the options,
A. 1<=4
B. -8<=0
C. 0<=-2
D.-2<=-2
E. -14<=-12
Option C is the answer.
Question: Day after tomorrow is my birthday. On the same day next week falls 'Holi'. Today is Monday. What will be the day after 'Holi'?
A.Wednesday
B.Thursday
C.Friday
D.Saturday
Answer: B.Thursday
Explanation: next week is WEDNESDAY
BUT THEY ASKED
What will be the day after 'Holi'?
SO THURSDAY
ANSWER:B
Question: Three candidates contested in an election and received 5136, 7636, 11628 votes respectively. What is the percentage of the total votes did the winning candidate get?
A.45%
B.48%
C.57%
D.51%
Answer: B.48%
Explanation: Total number of votes polled = 5136+7636+11628 = 24400
Required percentage = 11628*100/24400 = 48%
Answer is B
Question: A Father told his son, " I was as old as you are at present, at the time of your birth," if the father is 38 years old now, then what was the son age five years back?
A.14 years
B.19 years
C.38 years
D.33 years
Answer: A.14 years
Explanation: Let the present age of the son be x years, then
x = 38 - x
x = 19 years.
Five years back, son’s age = x - 5 = 19 - 5 = 14 years
ANSWER:A
Question: The H.C.F. of two numbers is 30 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
A.276
B.299
C.420
D.345
Answer: C.420
Explanation: Clearly, the numbers are (30 x 13) and (30 x 14).
Larger number = (30 x 14) = 420. Answer: Option C
Question: Denise is trying to open a safe whose combination she does not know. IF the safe has 4000 possible combinations,and she can try 150 different possibilities,what is the probability that she does not pick the one correct combination.
A.0.9625
B.159/160
C.157/160
D.3/160
Answer: A.0.9625
Explanation: If Denise does not pick the correct combination in first 150 try, then the correct combination is one of remaining 3850. So Probability = 3850/4000 = 0.9625
answer is A
Question: A man misses a bus by 40 minutes if he travels at 30 kmph. If he travels at 40 kmph, then also he misses the bus by 10 minutes. What is the minimum speed required to catch the bus on time?
A.49 kmph
B.45 kmph
C.95 kmph
D.75 kmph
Answer: B.45 kmph
Explanation: Let the distance to be travelled to catch the bus be x km
x/30 - x/40 = 30/60 => (4x - 3x)/120 = 1/2 => x = 60 km
By traavelling 30 kmph time taken = 60/30 = 2 hours
By taking 2 hours, he is late by 40 min. So, he has to cover 60 km in at most speed
= 60/(4/3) = 45 kmph.
Answer: B
Question: (935421 x 625) = ?
A.584638125
B.584638150
C.584638180
D.584638220
Answer: A.584638125
Explanation: 935421 x 625 = 935421 x 54 = 935421 x 10 4
2
=	935421 x 104	=	9354210000
24	16
= 584638125
A)
Question: How long will a boy take to run round a square field of side 50 meters, if he runs at the rate of 9km/hr?
A.80sec
B.45sec
C.1min
D.32sec
Answer: A.80sec
Explanation: Speed = 9 km/hr = 9*5/18 = 5/2 m/sec
Distance = 50*4 = 200m
Time taken = 200*2/5 = 80sec
Answer is A
Question: How many three letter words are formed using the letters of the word POLICE?
A.22
B.120
C.140
D.24
Answer: B.120
Explanation: Explanation:
The number of letters in the given word is six.
The number of three letter words that can be formed using these four letters is Ã¢Â´PÃ¢â€šÆ’ = 6*5*4 = 120.
Answer: B
Question: A shop owner professes to sell his articles at certain cost price but he uses false weights with which he cheats by 10% while buying and by 10% while selling. What is his percentage profit?
A.10.22%
B.20.22%
C.21.22%
D.22.22%
Answer: D.22.22%
Explanation: The owner buys 100 kg but actually gets 110kg;
The owner sells 100 kg but actually gives 90kg;
Profit: (110-90)/90*100=~22.22%
Answer: D.
Question: In a certain game, each player scores either 2 points or 5 points. If n players score 2 points and m players score 5 points, and the total number of points scored is 50, what is the least possible positive R difference between n and m?
A.1
B.3
C.5
D.7
Answer: B.3
Explanation: We have equation 2n + 5m = 50
We have factor 2 in first number and we have factor 5 in second number.
LCM(2, 5) = 10
So we can try some numbers and we should start from 5 because it will be less list than for 2
2 * 5 = 10 and n should be equal 20
4 * 5 = 20 and n should be equal 15
6 * 5 = 30 and n should be equal 10
8 * 5 = 40 and n should be equal 5
10 * 5 = 50 and n should be equal 0
third variant give us the mininal difference
n - m = 10 - 6 = 4
And there is some mistake in my way of thinking because we don't have such answer )
If we change the task and will seek for difference between m and n
than minimal result R will be 8 - 5 = 3
And answer B
Question: The cost of setting up a magazine is Rs. 2800. The cost of paper and ink etc is Rs. 80 per 100 copies and printing cost is Rs. 160 per 100 copies. In last month 2000 copies were printed but only 1500 copies could be sold at Rs. 5 each. Total 25% profit on the sale price was realized. There is one more resource of income from magazine which is advertising. What sum of money obtained from the advertising in magazine?
A.Rs. 1750
B.Rs. 2350
C.Rs. 1150
D.Rs. 1975
Answer: D.Rs. 1975
Explanation: Solution: Set up cost = Rs. 2800
Paper etc = Rs. 1600
Printing cost = Rs. 3200
Total cost = Rs. 7600
Total sale price = 1500*5 = 7500
Let amount obtained from advertising be x then,
(7500+x)-7600 = 25 % of 7500
x = 1975.
Answer: Option D
Question: The arithmetic mean of a data set is 46 and the standard deviation of the set is 4. Which of the following contains the interval two standard deviations from the mean of the set?
A.38 to 55
B.38 to 54
C.48 to 54
D.80 to 54
Answer: B.38 to 54
Explanation: Arithmetic Mean = 46
SD = 4 (One Interval )
Two SD intervals means 38__42__46 __50__54
answer B