RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A starts a business with a capital of Rs. 9,000. B joins in the business with Rs.18,000 after some time. For how much period does B join, if the profits at the end of the year are divided in the ratio of 3 : 1?
A.2 months
B.6 months
C.7 months
D.8 months
Answer: A.2 months
Explanation: Explanation :
Let B joins for x months. Then
A:B = 9000*12 : x* 18000 = 3 : 1
=> 9*12 : 18x= 3 : 1
=> 9*12/ 18x = 3/1 = 3
=> 9*4 /18x = 1
=> 2/x = 1
=> x = 2. Answer : Option A
Question: The sum of five consecutive odd numbers of set p is 435. What is the sum of five consecutive numbers of another set q. Whose largest number is 45 more than the largest number of set p?
A.530
B.six hundred seventy
C.730
D.770
Answer: B.six hundred seventy
Explanation: Let the five consecutive odd numbers of set p be 2n - 3, 2n - 1, 2n + 1, 2n + 3, 2n + 5.
Sum of these five numbers
= 2n - 3 + 2n - 1 + 2n + 1 + 2n + 3 + 2n + 5
= 10n + 5 = 435 => n = 43
Largest number of set p = 2(43) + 5 = 91
The largest number of set q = 91 + 45 = 136
=> The five numbers of set q are 132, 133, 134, 135, 136.
Sum of above numbers = 132 + 133 + 134 + 135 + 136 = 670.
ANSWER:B
Question: Length of a rectangular plot is 20 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
A.50 m
B.60 m
C.65 m
D.70 m
Answer: B.60 m
Explanation: Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m
B
Question: Find the one which does not belong to that group ?
A.23776
B.28287
C.84284
D.28278
Answer: C.84284
Explanation: Explanation:
42624, 37573, 74347 and 93339 are palindromes but not 84284.
Answer: C
Question: What is the sum of all remainders obtained when the first 100 natural numbers are divided by 8?
A.397
B.401
C.403
D.405
Answer: B.401
Explanation: A positive integer can give only the following 9 remainders when divided by 9: 1, 2, 3, 4, 5, 6, 7, 8, and 0.
1 divided by 9 gives the remainder of 1;
2 divided by 9 gives the remainder of 2;
...
8 divided by 9 gives the remainder of 8;
9 divided by 9 gives the remainder of 0.
We'll have 11 such blocks, since 99/9=11. The last will be:
91 divided by 9 gives the remainder of 1;
92 divided by 9 gives the remainder of 2;
...
98 divided by 9 gives the remainder of 8;
99 divided by 9 gives the remainder of 0.
The last number, 100, gives the remainder of 1 when divided by 9, thus the sum of all remainders will be:
11(1+2+3+4+5+6+7+8+0)+1=401.
Answer: B.
Question: A thief goes away with a SANTRO car at a speed of 35 kmph. The theft has been discovered after half an hour and the owner sets off in a bike at 100 kmph when will the owner over take the thief from the start?
A.12/3 hours
B.2/7 hours
C.7/13 hours
D.1/3 hours
Answer: C.7/13 hours
Explanation: -----------35--------------------|
100 35
D = 35
RS = 100 â€“ 35 = 65
T = 35/65 = 7/13 hours
ANSWER:C
Question: Three numbers are in the ratio 3:5:7. The largest number value is 42. Find difference between Smallest & largest number is?
A.20
B.22
C.24
D.26
Answer: C.24
Explanation: == 3:5:7
Total parts = 15
= The largest number value is 42
= The largest number is = 7
= Then 7 parts -----> 42 ( 7 * 6 = 42 )
= smallest number = 3 & Largest number = 7
= Difference between smallest number & largest number is = 7 - 3 = 4
= Then 4 parts -----> 24 (4 * 6 = 24)
C
Question: If X^y denotes x raised to the power y, then find last two digit of
1507^3381+1457^3757
A.64
B.65
C.66
D.75
Answer: A.64
Explanation: 1507^3381+1457^3757
=> 07^3381+57^3757
49^1690×7 + 49^1878 × 57
=> (100-51)^1690 ×7 + ( 100-51)^1878×57
=> 51^1690 × 7 + 51^1878×57
=> 07+57=64
ANSWER:A
Question: A car dealer purchased new cars at 80% of their list price and sold them for 90% of their list price. What is his percent gain?
A.11
B.12.5
C.15
D.16
Answer: B.12.5
Explanation: Cost = 80% of List Price = .8*LSale = 90% of List Price = .9*LGain Ratio = (Sale - Cost) / Cost = (.9*L - .8*L) / .8*L = .1*L / .8*L = .125Gain Percent = 100 * Gain Ratio = 100 * .125 = 12.5% = Answer B
Question: A goods train leaves a station at a certain time and at a fixed speed. After ^hours, an express train leaves the same station and moves in the same direction at a uniform speed of 90 kmph. This train catches up the goods train in 4 hours. Find the speed of the goods train.
A.24 kmph
B.36 kmph
C.56 kmph
D.32 kmph
Answer: B.36 kmph
Explanation: Let the speed of the goods train be x kmph.
Distance covered by goods train in 10 hours= Distance covered by express train in 4 hours
10x = 4 x 90 or x =36.
So, speed of goods train = 36kmph.
Ans: B
Question: Out of 10 persons working on a project, 6 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?
A.29/7
B.29/3
C.29/1
D.29/30
Answer: D.29/30
Explanation: P(at least one graduate) = 1 - P(no graduates)
= 1 - 4C₃/¹⁰C₃ = 1 - (4*3*2)/(10 * 9 * 8)
= 29/30
Answer: D
Question: How much time will it take for an amount of 1000 to yield 100 as interest at 5% per annum of simple interest?
A.3 years
B.4 years
C.2 years
D.5 years
Answer: C.2 years
Explanation: Time = (100 x 100)/(1000 x 5) years = 2 years.
answer C
Question: In the quiet town of "Nothintodo" there are 600 inhabitants, 400 are unemployed and 300 are somnambulists. If half of the somnambulists are unemployed, how many are employed and are not somnambulists?
A.50.
B.100
C.150
D.200
Answer: A.50.
Explanation: 400 are unemployed and 300 are somnambulists. So 200 are employed and 300 are Non-somnambulists.
Half of the somnambulists are unemployed = 150. So employed somnambulists = 300 -150 = 150.
Employed and not somnambulists = 200 - 150 = 50.
Hence the answer is A.
Question: There are two positive numbers in the ratio 2:7. If the larger number exceeds the smaller by 30, then find the larger number?
A.42
B.38
C.44
D.36
Answer: A.42
Explanation: Let the two positive numbers be 2x and 7x respectively.
7x - 2x = 30
5x = 30 => x = 6
=> Larger number = 7x = 42.
Answer: A
Question: Four of the five parts numbered (a), (b), (c), (d) and (e) are exactly equal. Which of the parts is not equal to the other four? The number of that part is the answer.
A.(a + b)(a – 2b)
B.a2 – b(a + 2b)
C.a2 + b2 – ab – 3b2
D.(a + b)(a – b) + ab
Answer: D.(a + b)(a – b) + ab
Explanation: Others equal a2 – ab – 2b2 whereas (d) equals a2 + ab – b2 .
Answer D
Question: In six successive games, a baseball team scored 2 runs once, 8 runs twice, and 12 runs three times.
What was the average (arithmetic mean) number of runs the team scored per game over the six-game period?
A.9
B.7
C.6
D.5
Answer: A.9
Explanation: 2 runs once (one game)
8 runs twice (two game)
12 runs three times (three games)
SO we have (2*1 + 8*2 + 12*3)/6 = 54/6 = 9.
ANS: A.
Question: If xy ≠ 0 and x^2y^2 − xy = 20, which of the following could be y in terms of x?
I. 5/x
II. -4/x
III. 3/x
A.I only
B.II only
C.I and II only
D.I and III
Answer: C.I and II only
Explanation: (x^2)(y^2) – xy - 20 = 0
(xy – 5)(xy + 4) = 0
xy – 5 = 0 or xy + 4 = 0
xy = 5 or xy = -4
Since we need y in terms of x, we can isolate y in both of our equations.
y = 5/x or y = -4/x
Answer: C
Question: A can run 2.7 km distance in 1 min 20 seconds, while B can run this distance in 1 min 30 sec. By how much distance can A beat B?
A.90 m
B.30 m
C.120 m
D.300 m
Answer: D.300 m
Explanation: A takes time 1.20 minutes=80sec
B takes time 1.30 minutes=90sec
diffrence= 90-80=10sec
now we are to find distance covered in 10 sec by B
90sec=30m
1sec=30m
10sec=10x30=300m
ANSWER:D
Question: 3x^2 - 13x + 12 =
A.(3x-4)(x-2)
B.(3x-4)(x+2)
C.(3x-4)(x-3)
D.(3x-2)(x+4)
Answer: C.(3x-4)(x-3)
Explanation: 3x^2 - 13x + 12
= 3x^2 - 9x - 4x + 12
= 3x (x - 3) - 4 (x-3)
= (3x-4) (x-3)
Option C
Question: The average temperature of the town in the first four days of a month was 58 degrees. The average for the second, third, fourth and fifth days was 60 degrees. If the temperatures of the first and fifth days were in the ratio 7 : 8, then what is the temperature on the fifth day ?
A.62 degrees
B.64 degrees
C.65 degrees
D.66 degrees
Answer: B.64 degrees
Explanation: Explanation:
Sum of temperatures on 1st, 2nd, 3rd and 4th days = (58 * 4) = 232 degrees ... (1)
Sum of temperatures on 2nd, 3rd, 4th and 5th days - (60 * 4) = 240 degrees ....(2)
Subtracting (1) From (2), we get :
Temp, on 5th day - Temp on 1st day = 8 degrees.
Let the temperatures on 1st and 5th days be 7x and 8x degrees respectively.
Then, 8x - 7x = 8 or x = 8. Answer: B
Temperature on the 5th day = 8x = 64 degrees.
Question: A company has a job to prepare certain number of cans and there are three machines A, B and C for this job. A can complete the job in 10 days, B can complete the job in 2 days and C can complete the job in 5 days. How many days the company will it take to complete the job if all the machines are used simultaneously?
A.4/3 days
B.5/4 days
C.4/5 days
D.20days
Answer: B.5/4 days
Explanation: Let the total number of cans to be prepared be 10.
The number of cans prepared by A in 1 day = 1.
The number of cans prepared by B in 1 day = 5.
The number of cans prepared by C in 1 day = 2.
Thus, the total number of cans that can be prepared by all the machines working simultaneously in a single day = 8.
Therefore, the number of days taken to complete the whole work = 10/8 = 5/4 days.
ANSWER:B
Question: Krishan and Nandan jointly started a business. Krishan invested three times as Nandan did and invested his money for double time as compared to Nandan. Nandan earned Rs. 4000. If the gain is proportional to the money invested and the time for which the money is invested then the total gain was?
A.28,008
B.28,006
C.28,005
D.28,000
Answer: D.28,000
Explanation: 3:1
2:1
------
6:1
1 ----- 4000
7 ----- ? => Rs.28,000.Answer:D
Question: Find the smallest number of five digits exactly divisible by 16,24,36 and 54.
A.10368
B.10638
C.10836
D.10863
Answer: A.10368
Explanation: Smallest number of five digits is 10000.
Required number must be divisible by L.C.M. of 16,24,36,54 i.e 432,
On dividing 10000 by 432,we get 64 as remainder.
Therefore, Required number = 10000 +( 432 – 64 ) = 10368.
Answer is A.
Question: Raj invested an amount of Rs.17400 for two years. Find the rate of compound interest that will fetch him an amount of Rs.1783.50 at the end of two years?
A.1/208
B.1/228
C.1/229
D.1/20
Answer: D.1/20
Explanation: Let the rate of interest be R% p.a.
17400[1 + R/100]2 = 17400 + 1783.50
[1 + R/100]2 = (17400 + 1783.50)/17400
= 1 + 1025/10000 = 1 + 41/400
= 441/400 = [21/20]2
[1 + R/100] = 21/20
R/100 = 1/20
Answer:D
Question: A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 610 m long?
A.22
B.89
C.85
D.278
Answer: C.85
Explanation: Speed = 240/24 = 10 m/sec.
Required time = (240 + 610)/10 = 85 sec.
Answer: C
Question: When 19 is divided by positive integer j, the remainder is 4. For how many values of j is this be true?
A.1
B.3
C.5
D.7
Answer: A.1
Explanation: When 19 is divided by j, the remainder is 4 i.e. 5 kiwis left over after grouping, so j must be greater than 5.
It also means that 15 is completely divisible by j.
Factors of 15 are 1, 3, 5, and 15.
Out of these, j can be 15.
Answer is (A).
Question: If n is the product of the integers from 1 to 9, inclusive, how many different prime factors greater than 1 does n have?
A.Four
B.Five
C.Six
D.Seven
Answer: A.Four
Explanation: n = 1*2*3*4*5*6*7*8*9
The prime factors of n are 2, 3, 5, and 7.
There are 4 prime factors.
The answer is A.
Question: In 1940, a correspondent proposed the following question:
A man's age at death was one twenty-ninth of the year of his birth. How old was he in 1900?
A.14
B.24
C.34
D.44
Answer: D.44
Explanation: He was 44 years old.
From the question you know the man died between 1900 and 1940. We also know his age at death (x) is one twenty-ninth of the year of his birth (29x). If you add his age at death to the year he was born you get the year he died (30x). Only one year between 1900 and 1940 is divisible by 30, 1920 (the year he died). The year he was born can now be found: 1920 * (29/30) = 1856. So in 1900 he was (1900 - 1856) = 44 years old.
Question: In two digit number, the digit in the unit’s place is four times the digit in ten's place and sum of the digits is equal to 10. What is the number?
A.14
B.18
C.20
D.28
Answer: D.28
Explanation: Sol.
Let the ten’s digits be x. Then, unit’s digit = 4x.
∴ x + 4x = 10 ⇔ 5x = 10 ⇔ x = 2.
So, ten’s digit = 2, unit’s digit = 8.
Hence, the required number is 28.
Answer D
Question: Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 34 kmph. Of how many minutes does the train stop per hour?
A.73
B.15
C.12
D.83
Answer: B.15
Explanation: Explanation:
T = 11/45 * 60 = 15
Answer: Option B
Question: The simple interest on a sum of money will be Rs.500 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year?
A.700
B.800
C.900
D.1000
Answer: D.1000
Explanation: P --- 10 ---- 500
P --- 5 ----- 250
3P --- 5 -----750
------
=> 1000
ANSWER:D
Question: By selling 50 meters of cloth. I gain the selling price of 15 meters. Find the gain percent?
A.72 6/7%
B.82 6/7%
C.22 6/7%
D.42 6/7%
Answer: D.42 6/7%
Explanation: Explanation:
SP = CP + g
50 SP = 50 CP + 15 SP
35 SP = 50 CP
35 --- 15 CP gain
100 --- ? => 42 6/7%
Answer: D
Question: A cyclist covers a distance of 750 m in 2 min 30 sec. What is the speed in km/hr of the cyclist?
A.28
B.18
C.20
D.22
Answer: B.18
Explanation: Speed = { 750 } m/sec =5 m/sec = { 5 * 18 } km/hr =18km/hr
Option B
Question: Calculate the percentage profit or loss if a trader bought the apples at 5 per rupee and sells 4 apples per rupee.
A.11 %
B.34 %
C.25 %
D.15 %
Answer: C.25 %
Explanation: Let he total number of oranges bought by the shopkeeper be 12.
If he buys 5 a rupee, his CP = 4
He selling at 4 a rupee, his SP = 5
Profit = SP - CP = 5 - 4 = 1
Profit Percent = 1/4 * 100 = 25 %
Answer: C
Question: In a class there are 20 boys and 23 girls. In how many ways can a boy and a girl be selected?
A.508
B.460
C.800
D.570
Answer: B.460
Explanation: We can select one boy from 20 boys in 20 ways.
We select one girl from 23 girls in 23 ways
We select a boy and girl in 20 * 23 ways i.e., = 460 ways.
Answer:B
Question: A man bought 40 shares of Rs. 80 at 5 discount, the rate of dividend being 12 1/2%The rate of interest obtained is
A.13.33%
B.15.5%
C.14%
D.14.25%
Answer: A.13.33%
Explanation: Explanation :
Face Value of a share = Rs.80
He bought each share at Rs.80 - Rs.5 = Rs.75
Number of shares = 40
Dividend = 12 1/2%=25/2%
Dividend per share = 80×25/2/100=Rs.10
Total dividend = (40 × 10)
ie, He got a dividend of (40 × 10) for an investment of Rs.(40 × 75)
Interest obtained = 40×10×100/40×75=13.33%
Answer : Option A
Question: A rectangular lawn of dimensions 100 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
A.s.3988
B.s.3900
C.s.4500
D.s.3922
Answer: C.s.4500
Explanation: Area = (l + b – d) d
(100 + 60 – 10)10 => 1500 m2
1500 * 3
= Rs.4500
Answer:C
Question: There are 8 men and 10 women and you need to form a committee of 5 men and 6 women. In how many ways can the committee be formed?
A.11660
B.11700
C.11760
D.11800
Answer: C.11760
Explanation: Explanation:
We need to select 5 men from 8 men and 6 women from 10 women
Number of ways to do this
= 8C5 × 10C6
= 8C3 × 10C4 [∵ nCr = nC(n-r)]
=
(
8
×
7
×
6
3
×
2
×
1
)
(
10
×
9
×
8
×
7
4
×
3
×
2
×
1
)
=
56
×
210
=11760
Option C
Question: A number is doubled and 9 is added. If the resultant is trebled, it becomes 63. What is that number?
A.3.5
B.6
C.8
D.7
Answer: B.6
Explanation: Let the number be x. Then,
3(2x + 9) = 63
2x = 12 => x = 6
ANSWER:B
Question: What will come in place of the x in the following Number series? 15, 60, X, 960, 3840
A.280
B.960
C.820
D.800
Answer: B.960
Explanation: (B)
15 x 4 = 60, 60 x 4 = 240, 240 x 4 = 960, 960 x 4 = 3840.
Question: A single letter is selected at random from the word 'CARE'. The probability that it is a vowel is..??
A.2/11
B.3/11
C.4/11
D.2/4
Answer: D.2/4
Explanation: total vowels = 2, total number of letters = 4
so probability = 2/4
ANSWER:D
Question: When the circumference and area of a circle are numerically equal, then the diameter is numerically equal to
A.area
B.circumference
C.4
D.2π
Answer: C.4
Explanation: According to question, circumference of circle = Area of circle
or πd = π(d⁄2)2 [where d = diameter]
∴ d = 4
Answer C
Question: The least number by which 72 must be multiplied in order to produce a multiple of 112, is:
A.6
B.12
C.14
D.18
Answer: C.14
Explanation: Required number is divisible by 72 as well as by 112, if it is divisible by their LCM, which is 1008.
Now, 1008 when divided by 72, gives quotient= 14.
Therefore, required number= 14.
ANSWER:C
Question: A rectangular lawn of dimensions 80 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m?
A.3902
B.3928
C.3929
D.3900
Answer: D.3900
Explanation: Area = (l + b – d) d
(80 + 60 – 10)10 => 1300 m2
1300 * 3 = Rs.3900
Answer:D
Question: John left home and drove at the rate of 45 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 55 mph to reach his destination. How many miles did John drive?
A.235 miles.
B.245 miles.
C.255 miles.
D.265 miles.
Answer: C.255 miles.
Explanation: The total distance D traveled by John is given by
D = 45 * 2 + 3 * 55 = 255 miles.
Answer C
Question: Aaron had $ 2100 left after spending 30 % of the money he took for shopping. How much money did he take along with him?
A.$3039
B.$3003
C.$3002
D.$3000
Answer: D.$3000
Explanation: Let the money he took for shopping be m.
Money he spent = 30 % of m
= 30/100 × m
= 3/10 m
Money left with him = m – 3/10 m = (10m – 3m)/10 = 7m/10
But money left with him = $ 2100
Therefore 7m/10 = $ 2100
m = $ 2100× 10/7
m = $ 21000/7
m = $ 3000
Therefore, the money he took for shopping is $ 3000
Answer:D
Question: Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
A.50
B.88
C.66
D.55
Answer: A.50
Explanation: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 - 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50.
Answer:A
Question: In an aquarium there is 14 purple fish, 8 orange fish,12 pink fish, 3 golden fish. How many fish are there in an aquarium?
A.27
B.37
C.17
D.47
Answer: B.37
Explanation: 14+8+12+3=37. Answer is B
Question: A trader marks his books 30% more than the cost price. If he allows 20% discount, then find his gain or loss percent?
A.4% Gain
B.12% loss
C.4% loss
D.No profit No loss
Answer: A.4% Gain
Explanation: Let CP of an book = 100
MP of an book = 130
Discount 20 % on 130 = 26
SP of the book = 130 - 26 = 104
Gain = 4%
Answer : A
Question: The difference between simple and compound interest on Rs. 1400 for one year at 10% per annum reckoned half-yearly is?
A.8.25
B.3.5
C.9.0
D.3.15
Answer: B.3.5
Explanation: S.I. = (1400 * 10 * 1)/100 = Rs. 140
C.I. = [1400 * (1 + 5/100)2 - 1400]
= Rs. 143.5 Difference = (143.5 - 140)
= Rs.3.50
Answer:B
Question: If xy > 0, 1/x + 1/y = 4, and 1/xy = 6, then (x+y)/2 = ?
A.1/25
B.1/6
C.1/5
D.1/3
Answer: D.1/3
Explanation: (1/X+1/Y)=4 canbe solved as {(x+y)/xy}=6. Substituting for 1/xy=6, we get
x+y=4/6
==> (x+y)/2= 4/(6*2)=1/3.
D
Question: If S is the sum of reciprocals of a list of consecutive integers from 55 to 64, inclusive, S is approximately equal to
A.0.16
B.0.2
C.0.3
D.0.4
Answer: A.0.16
Explanation: We need to find the approximate value of 1/55+1/56+1/57+1/58+1/59+1/60+1/61+1/62+1/63+1/64. Now, the sum of these 10 terms will be very close to 10 times 1/60, which is 0.016*10=0.16.
Answer: A.
Question: The percentage profit earned by selling an article for Rs. 1620 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit?
A.3000
B.1812.5
C.2000
D.5600
Answer: B.1812.5
Explanation: C.P. be Rs. x.
Then, (1620 - x)/x * 100 = (x - 1280)/x * 100
1620 - x = x - 1280
2x = 2900 => x = 1450
Required S.P. = 125 % of Rs. 1450 = 125/100 * 1450 = Rs. 1812.5.
ANSWER B
Question: Positive Integer A gives the remainder of 20 when divided by another positive Integer B. If A/B = 47.50, what is the value of B?
A.96
B.75
C.40
D.25
Answer: C.40
Explanation: .50 of B = Remainder
.50 of B = 20
B = (20 *100) / 50 = 40.
C
Question: A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
A.19
B.17
C.10
D.18
Answer: C.10
Explanation: Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters.Answer: C
Question: In a workshop there are 5 kinds of beds, 3 kinds of closets, 2 kinds of shelves and 7 kinds of chairs. In how many ways can a person decorate his room if he wants to buy in the workshop one shelf, one bed and one of the following: a chair or a closet?
A.A)168.
B.B)80.
C.C)100.
D.D)48.
Answer: C.C)100.
Explanation: ways to select one shelf = 2
ways to select one bed = 5
ways to select one of the following: a chair or a closet = 7+3 = 10
ways to select all of them together = 2*5*10 = 100
Answer : C
Question: There is a 20% chance Sandy will visit China this year, while there is a 60% chance that she will visit Malaysia this year. What is the probability that Sandy will visit either China or Malaysia this year, but NOT both?
A.40%
B.48%
C.56%
D.64%
Answer: C.56%
Explanation: P(China and not Malaysia) = 0.2*0.4 = 0.08
P(Malaysia and not China) = 0.6*0.8 = 0.48
Total probability = 0.08 + 0.48 = 0.56 = 56%
The answer is C.
Question: If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is:
A.9%
B.26%
C.50%
D.80%
Answer: C.50%
Explanation: C
C.P. of each pen be Re. 1.
Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.
Gain % = 4/8 * 100 = 50%
Question: In how many ways can a team of 4 persons be formed out of a total of 8 persons such that two particular persons should be included in each team?
A.15
B.20
C.18
D.22
Answer: A.15
Explanation: Two particular persons should be included in each team. Therefore we have to select remaining 4-2=2 persons from 8-2=6 persons.
Hence, required number of ways= 6C2 = 15
Answer is A
Question: Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full is?
A.2 hrs
B.6 hrs
C.7 hrs
D.8 hrs
Answer: C.7 hrs
Explanation: (A + B)'s 1 hour work = (1/12 + 1/15) = 3/20
(A + C)'s 1 hour work = (1/12 + 1/20) = 2/15
Part filled in 2 hrs = (3/20 + 2/15) = 17/60
Part filled in 6 hrs = 3 * 17/60 = 17/20
Remaining part = 1 - 17/20 = 3/20
Now, it is the turn of A and B and 3/20 part is filled by A and B in 1 hour.
Total time taken to fill the tank = (6 + 1) = 7 hrs.
Answer:C
Question: Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 25/49, what is the probability that the next one she draws will be pink?
A.1/49
B.2/7
C.3/7
D.16/49
Answer: B.2/7
Explanation: The probability of drawing a pink gumball both times is the same. The probability that she drew two blue gumballs = 25/49 = (5/7) * (5/7)
Therefore probability that the next one she draws is pink = 2/7
Option (B)
Question: If 3log(4*5^2) = x, find x
A.5
B.6
C.7
D.8
Answer: B.6
Explanation: 3(log2^2*5^2)=x
3log(5*2)^2=x
3*2log(5*2)=x
6log10=x
log10 base 10=1
so
6*1=x
x=6
ANSWER:B