RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The surface area of a cube is 486 Cm3. Find its volume
A.729
B.739
C.759
D.749
Answer: A.729
Explanation: Let each edge of the cube be a Cm.
Then 6 a(power)2 = 486 => a(power)2 = 81 = 9(power)2 => a = 9
Volume = a(power)3 = 9(power)3 Cm(power)3 => 729 Cm(power)3
Answer is A.
Question: Including Cara and Dan, there are six members on the board of directors for a company. If the board is to be split up into a four-person subcommittee, what fraction of all the possible subcommittees that include Cara, also include Dan?
A.3/5
B.4/5
C.3/10
D.7/10
Answer: A.3/5
Explanation: The number of possible subcommittees with Cara is 5C3=10.
The number of possible subcommittees with Cara and Dan is 4C2=6.
The fraction of Cara's subcommittees which include Dan is 6/10=3/5.
The answer is A.
Question: Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.
A.2:7
B.2:3
C.2:0
D.2:1
Answer: B.2:3
Explanation: Explanation:
By the rule of alligation:
Cost of 1 kg rice of 1st kind Cost of 1 kg rice of 2nd kind
{\color{Blue} \therefore } Required ratio = 60 : 90 = 2 : 3
Answer: B) 2:3
Question: A girl goes to her office for work which is 50 miles. She goes to her office few distance by bicycle and remaining by train. The speed of bicycle is 15 mph and that of train is twice of bicycle. If she spend 20 min. more on bicycle, then total time taken by her from going to office from her home?
A.1 hr 20 min
B.2 hr 20 min
C.2 hr 30 min
D.2 hr 40 min
Answer: B.2 hr 20 min
Explanation: Let time travelled in train is x min then in cycle (x+20) min.
(30/60)x + (15/60)(x + 20) = 50 or x = 60
Total time taken 60 + (60 + 20) = 2 hr 20 min
ANSWER:B
Question: A man can row upstream at 8km/hr and down stream at 11km/hr find mans rate in still water ?
A.9.5km/hr
B.4.5km/hr
C.6.5km/hr
D.3.5km/hr
Answer: A.9.5km/hr
Explanation: :	given upstream(u) =8km/hr
down stream (v)= 11km/hr rate in still water =1/2(u+v)=1/2(8+11)=9.5km/hr Answer is (A):9.5
Question: There are 30 socks in a drawer. 60% of the socks are red and the rest are blue. What is the minimum number of socks that must be taken from the drawer without looking in order to be certain that atleast two blue socks have been chosen?
A.23
B.37
C.97
D.20
Answer: D.20
Explanation: Explanation:
Number of red socks = 30 × 60% = 18
If you draw out 18 socks there's a possibility that all of them are red
If you draw out 19 socks one of them has to be a blue one
And if u draw 20 socks then definitely 2 of them are blue socks
So the answer is 20.
Answer:D
Question: John want to buy a $100 Trouser at the store, but he think it’s too expensive. Finally, it goes on sale for $10. What is the percent decrease?
A.90%
B.30%
C.40%
D.70%
Answer: A.90%
Explanation: The is always the difference between our starting and ending points. In this case, it’s 100 – 10 = 90. The “original” is our starting point; in this case, it’s 100. (90/100)*100 = (0.9)*100 = 90%.
A
Question: If two drawers of socks contains five different colored socks in each drawer, and a sock is randomly selected from each drawer, what is the probability of getting a pair of the same colored socks?
A.2/5
B.1/5
C.1/6
D.1/2
Answer: B.1/5
Explanation: A pair of matching socks.
First solve for NO matching socks:
1st drawer = any color = 5/5
2nd drawer = not a match to the first = 4/5
(5/5)(4/5) =
(1)(4/5) =
20/25
4/5 is the probability of NO matching socks, so...
1 - 4/5 = 1/5 = the probability of getting at least one matching pair of socks.
Answer: B
Question: what is the angle between the hands of a clock when time is 8:20?
A.65deg
B.75deg
C.50deg
D.15deg
Answer: C.50deg
Explanation: Angle between two hands =
20h - 11/2 m = 20*8 - 20*11/2 = 160 - 110 = 50deg
ANSWER:C
Question: The lettersmove four steps backward to obtain the letters of the next term
?, SIY, OEU, KAQ, GWM, CSI
A.AAH
B.AHU
C.WMC
D.RTR
Answer: C.WMC
Explanation: C
WMC
The lettersmove four steps backward to obtain the letters of the next term
Question: Priya covers journey from kavali to nellore by car at average speed of 70 Km/hr. She returns back by scooty with an average speed of 70 Km/hr. Find her average speed during the whole journey?
A.60Km/hr
B.70Km/hr
C.80Km/hr
D.90Km/hr
Answer: B.70Km/hr
Explanation: Explanation:
Average speed = 2 xy/x+y
= 2*70*70/140
= 70 Km/hr
Answer: Option B
Question: By selling an umbrella for Rs. 300, a shop keeper gains 15%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?
A.6.5%
B.2%
C.5.88%
D.3%
Answer: C.5.88%
Explanation: Marked price = Rs. 300
C.P. = 100/115 * 300 = Rs. 255
Sale price = 90% of Rs. 300 = Rs. 270
Required gain % = 15/255 * 100 =5.88%.
Answer: C
Question: 3 candidates in an election & received 1136, 7636 and 11628 votes respectively. What % of the total votes did the winning candidategot in that election?
A.50%
B.52%
C.57%
D.60%
Answer: C.57%
Explanation: Total number of votes polled = (1136 + 7636 + 11628) = 20400
So, Required percentage = 11628/20400 * 100 = 57%
C
Question: Two trains 200 m and 150 m long are running on parallel rails at the rate of 40 kmph and 45 kmph respectively. In how much time will they cross each other, if they are running in the same direction?
A.72 sec
B.132 sec
C.192 sec
D.252 sec
Answer: D.252 sec
Explanation: Solution
Relative Speed	= (45 - 40 ) Kmph
= 5 kmph
=(5 x 5 / 18)m/sec
= (25 / 18 ) m/sec
Time taken	= (350 x 18 / 25) sec
= 252 sec.
Answer D
Question: At what rate percent on simple interest will Rs.750 amount to Rs.900 in 5 years?
A.8
B.7
C.4
D.3
Answer: C.4
Explanation: 150 = (750*5*R)/100
R = 4%
Answer: C
Question: 10 men, working 3 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days ?
A.3 hours a day
B.5 hours a day
C.6 hours a day
D.7 hours a day
Answer: A.3 hours a day
Explanation: Explanation:
More Men, Less Hours {Indirect Proportion}
Less Days, More Hours {Indirect Proportion}
[men 15 10
days 12 18] ::3:x
=>xâˆ—15âˆ—12=10âˆ—18âˆ—3
=>x=10âˆ—18âˆ—3/ 15âˆ—12
=>x=3
Option A
Question: Find the smallest number of four digits exactly divisible by 4,5,7 and 8.
A.1150
B.1160
C.1140
D.1152
Answer: B.1160
Explanation: Smallest number of four digits is 1000.
Required number must be divisible by L.C.M. of 4,5,7,8 i.e 280,
On dividing 1000 by 280,we get 120 as remainder.
Therefore, Required number = 1000 +( 280 â€“ 120 ) = 1160.
Answer is B.
Question: Two persons start at the same point, walk in opposite directions with 6 km/hr and 7 km/hr respectively.
What is the distance separated after 3 and half hrs?
A.45.5 km
B.27.250 km
C.28.250 km
D.29.250 km
Answer: A.45.5 km
Explanation: As the two persons are moving in the opposite direction, so they will be separateed in 1 hour = 6 + 7 = 13 km.
They will be separated in 2.5 hours = 13 * 3.5 = 45.5 km
ANSWER:A
Question: 3889 + 12.952 – ? = 3854.002
A.47.095
B.47.752
C.47.932
D.47.95
Answer: D.47.95
Explanation: EXPLANATION
Let 3889 + 12.952 – x = 3854.002.
Then x = (3889 + 12.952) – 3854.002
= 3901.952 – 3854.002
= 47.95.
Answer D
Question: Three cards are drawn successively, without replacement from a pack of 52 well shuffled cards.
What is the probability that first two cards are queens and the third card drawn is an ace?
A.2/5525
B.3/5525
C.2/5525
D.2/5526
Answer: A.2/5525
Explanation: Let Q denote the event that the card drawn is queen and A be the event that
the card drawn is an ace. Clearly, we have to find P (QQA)
Now P(Q) = 4/52
Also, P (Q|Q) is the probability of second queen with the condition that one queen has
already been drawn. Now there are three queen in (52 - 1) = 51 cards.
Therefore P(Q|Q) = 3/51
P(A|QQ) is the probability of third drawn card to be an ace, with the condition
that two queens have already been drawn. Now there are four aces in left 50 cards.
Therefore P(A|QQ) = 4/50
By multiplication law of probability, we have
P(QQA) = P(Q) P(Q|Q) P(A|QQ)
= 4/52 × 3/51 × 4/50
= 2/5525.
A)
Question: An woman swims downstream 45 km and upstream 25 km taking 5 hours each time; what is the speed of the current?
A.2
B.1
C.3
D.4
Answer: A.2
Explanation: 45 --- 5 DS = 9
? ---- 1
25---- 5 US = 5
? ---- 1 S = ?
S = (9 - 5)/2 = 2
Answer: A
Question: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
A.11 Kmph
B.68 Kmph
C.88 Kmph
D.19 Kmph
Answer: B.68 Kmph
Explanation: Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X - 48 = 180
1000/x - 48 * 5/18 = 180
50 = 9X - 120
X = 68 Kmph
Answer: B
Question: A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 400 m long?
A.176 Sec
B.190 Sec
C.178 Sec
D.160 Sec
Answer: D.160 Sec
Explanation: L = S*T
S= 1200/120
S= 10 m/Sec.
Total length (D)= 1600 m
T = D/S
T = 1600/10
T = 160 Sec
Answer:D
Question: The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8500. If his salary for the month of May is Rs.6500, find his salary for the month of January?
A.299
B.2889
C.4500
D.2728
Answer: C.4500
Explanation: Sum of the salaries of the person for the months of January, February, March and April = 4 * 8000 = 32000 ----(1)
Sum of the salaries of the person for the months of February, March, April and May = 4 * 8500 = 34000 ----(2)
(2)-(1) i.e. May - Jan = 2000
Salary of May is Rs.6500
Salary of January = Rs.4500
Answer: C
Question: One computer can upload 100 megabytes worth of data in 5 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 40 seconds. How long would it take for the second computer, working on its own, to upload 100 megabytes of data?
A. 6
B. 8
C. 9
D. 11
Answer: B. 8
Explanation: Since the first computer can upload 100 megabytes worth of data in 5 seconds then in 5*8=40 seconds it can upload 8*100=800 megabytes worth of data, hence the second computer in 40 seconds uploads 1300-800=500 megabytes worth of data. The second computer can upload 100 megabytes of data in 8 seconds.
Answer: B.
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?
A.65 kmph
B.88 kmph
C.14 kmph
D.66 kmph
Answer: C.14 kmph
Explanation: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 42/3 = 14 kmph..Answer: C
Question: The ratio of the present ages of two Friends is 2 : 3 and six years back, the ratio was 1 : 3. What will be the ratio of their ages after 4 years ?
A.1:4
B.3:4
C.1:2
D.3:1
Answer: B.3:4
Explanation: let the ages be 2x,3x
6yrs back,so
2x-6/3x-6=1/3
x=4
after 4 yrs
2x+4,3x+4
2(4)+4,3(4)+4
12:16
3:4
ANSWER:B
Question: The price of a furniture is Rs. 3,25,000. It was insured to 85% of its price. The furniture was damaged completely in an incident and the insurance company paid 90% of the insurance. What was the difference between the price of the furniture and the amount received ?
A.Rs 36,583
B.Rs 67,375
C.Rs 76,375
D.Rs 76,735
Answer: C.Rs 76,375
Explanation: Explanation :
Amount paid to furniture owner = 90% of 85% of Rs. 3,25,000.
= Rs. (90/100 85/100 325000)
= Rs. 2,48,625.
Required difference = Rs. (325000 - 248625)
= Rs. 76,375.
Answer : C
Question: For which of the following functions f is f(c) = f(1-c) for all c?
A.f (c) = 1 - c
B.f (c) = 1 - c^2
C.f (c) = c^2 - (1 - c)^2
D.f (c) = c^2*(1 - c)^2
Answer: D.f (c) = c^2*(1 - c)^2
Explanation: I remember seeing this problem in a GMATprep test. I think choice D should be F(c)=(c^2) (1-c)^2. If that is true then substituting (1-c) for will give us the same function back and the answer choice is D, where the function is multiplicative
Question: The diagonal of a square is twice the side of equilateral triangle then the ratio of Area of the Triangle to the Area of Square is?
A.3√9
B.3√8
C.3√7
D.3√5
Answer: B.3√8
Explanation: Let the side of equilateral triangle = 1 unit.
We know that area of an equilateral triangle = 3–√4a234a2
As side = 1 unit area of the equilateral triangle = 3–√434
Now Diagonal of the square = 2 (side of the equilateral triangle) = 2
We know that area of the square = 12D212D2 where D = diagonal
So area of the square = 12(22)=212(22)=2
Ratio of the areas of equilateral triangle and square = 3–√434 : 2 ⇒⇒ 3√8
Answer:B
Question: Find the greatest number which, while dividing 19, 83 and 67, gives a remainder of 3 in each case?
A.16
B.17
C.18
D.19
Answer: A.16
Explanation: Subtract the remainder 3 from each of the given numbers: (19-3)=16, (67-3)=64 and (83-3)=80. Now, find the HCF of the results 16, 64 and 80, we get 16. Thus, the greatest number is 16
ANSWER:A
Question: If two dice are thrown together, the probability of getting prime number on both dice is
A.5/9
B.1/9
C.2/9
D.4/9
Answer: C.2/9
Explanation: The number of exhaustive outcomes is 36.
Let E be the event of getting a prime number on both the dice.
P(E) = 8/36 = 2/9.
C)
Question: If r and s are positive integers and r-s=6, which of the following has the greatest value M?
A.2r
B.2s
C.r +s
D.2r-s
Answer: A.2r
Explanation: You can answer this question by using Number Properties and logic or by TESTing VALUES.
We're told that R and S are POSITIVE INTEGERS and that R-S = 6. We're asked which of the 5 answers has the GREATEST value.
IF....
R = 8
S = 2
Answer A: 2R = 2(8) = 16
Answer B: 2S = 2(2) = 4
Answer C: R+S = 8+2 = 10
Answer D: 2R-S = 2(8) - 2 = 14
Answer E: 2S-R = 2(2) - 8 = -4
Final Answer:
A
Question: There are 10 members from that a total of 6 men & 4 ladies a committee of 3 is to be formed. If Mrs. A is not willing to join the committee in which Mr. B is a member, whereas Mr.B is willing to join the committee only if Mrs C is included, how many such committee are possible?
A.87
B.89
C.90
D.91
Answer: D.91
Explanation: We first count the number of committee in which
(i). Mr. Y is a member
(ii). the ones in which he is not
case (i): As Mr. Y agrees to be in committee only where Mrs. Z is a member.
Now we are left with (6-1) men and (4-2) ladies (Mrs. X is not willing to join).
We can choose 1 more in5+\inline {\color{Blue} 2C_{1}}=7 ways.
case (ii): If Mr. Y is not a member then we left with (6+4-1) people.
we can select 3 from 9 in \inline {\color{Blue} 9C_{3}}=84 ways.
Thus, total number of ways is 7+84= 91 ways.
D
Question: A and B work at a hospital with 4 other workers. For an internal review, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that A and B will both be chosen?
A.A)1/3
B.B)1/4
C.C)1/15
D.D)3/8
Answer: C.C)1/15
Explanation: Total number of people = 6
Probability of selecting A first and then B is 1/6∗1/5=1/30
Probability of selecting B first and then A is 1/6∗1/5=1/30
Therefore probability of selecting A and B for the review is 1/30+1/30=1/15
Answer is C
Question: If x and y are positive odd integers, then which of the following must also be an odd integer?
I. x^(y+2)
II. x(y+2)
III. (y+1)^(x-1) + 1
A.I only
B.II only
C.All options are applicable
D.III only
Answer: C.All options are applicable
Explanation: let x= 5, y= 3
I. 5^5 = > Odd
II. 5*5 = > Odd
III. 4^4 +1 = > Odd
Answer : C
Question: A certain sum earns simple interest of Rs. 800 in 2 years at a certain rate of interest. If the same sum earns compound interest of Rs. 845 in the same period of 2 years, What must be the rate of interest?
A.10% p.a.
B.90% p.a.
C.30% p.a.
D.19% p.a.
Answer: A.10% p.a.
Explanation: Explanation:
Given: 800 = (P * R * 2) / 100
S.I. For 1 year = Rs. 400
Thus, (840 – 800) = S.I. on Rs. 400 for 1 year
40 = (400 * R * 1) / 100
R = 10% p.a.
ANSWER: A
Question: Steve traveled the first 2 hours of his journey at 60 mph and the remaining 3 hours of his journey at 80 mph. What is his average speed for the entire journey?
A.60 mph
B.72 mph
C.53.33 mph
D.64 mph
Answer: B.72 mph
Explanation: Distance traveled in 2 hours = 2 * 60 = 120 m
Distance traveled in 3 hours = 3 * 80 = 240m
Total distance covered = 240 + 120 = 360m
Total time = 2 + 3 =5 h
Hence avg speed = total distance covered / total time taken
= 360/5 = 72mph
Answer: B
Question: There are 16 stations between Mumbai and Chennai. How many second class tickets have to be printed, so that a passenger can travel from any station to any other station?
A.316
B.306
C.326
D.336
Answer: B.306
Explanation: The total number of stations = 18
From 18 stations we have to choose any two stations and the direction of travel (i.e., Mumbai to Chennai is different from Chennai to Mumbai) in 18P2 ways.
18P2= 18 * 17 = 306
ANSWER: B
Question: How many seconds will a train 100 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?
A.22 sec
B.27 sec
C.25 sec
D.24 sec
Answer: C.25 sec
Explanation: Explanation:
D = 100 + 150 = 250
S = 36 * 5/18 = 10 mps
T = 250/10 = 25 sec
Answer: Option C
Question: Without any stoppages a person travels a certain distance at an average speed of 40 km/hr and with stoppages he covers the same distance at an average of 20 km/hr. How many minutes per hour does he stop?
A.15
B.20
C.30
D.45
Answer: C.30
Explanation: speed = 40km and with stoppages it covers only 20 kmso to travel 20 km at original speed i.e. 20 = 40*t, so t = 1/2 hour = 30minutes Answer : C
Question: What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 6?
A.82,650
B.64,850
C.64,749
D.49,700
Answer: A.82,650
Explanation: Find the number , Upon Sum of 3 Digits of a number Gives a Reminder 2 when it is Divided by 6
Seeing the Options After Dividing an Finding the Reminder of 2
My Answer was A
Question: David can divide his herd into 5 equal parts and also to 6 equal parts, but not to 9 equal parts. What could be the number of cows David has in his herd?
A.180
B.120
C.155
D.336
Answer: B.120
Explanation: On first look D, C,E are not divisible either by 5 or 6 - ruled out.
A,B divisible by both 5,6, but 180 is divisible by 9.
Answer : B
Question: Rajeev' age after 15 years will be 5 times his age 5 years back . What is the present age of Rajeev ?
A.8 years
B.10 years
C.12 years
D.14 years
Answer: B.10 years
Explanation: Explanation :
Dol. Let Rajeev's presen age be xx years , Then
Rajeev's ae after 15 years = (x+15)(x+15)years
Rajeev's age 5 years back = (xâˆ’5)(x-5) years
âˆ´âˆ´ x+15=5(xâˆ’5)x+15=5(x-5)
â‡” x+15=5xâˆ’25â‡” x+15=5x-25
â‡” 4x=40â‡” 4x=40
â‡” x=10â‡” x=10
Hence , Rajeev's present age = 10 years.
ANSWER IS B
Question: After decreasing 24% in the price of an article costs Rs.1216. Find the actual cost of an article?
A.1667
B.6789
C.1200
D.1600
Answer: D.1600
Explanation: CP* (76/100)
= 1216
CP= 16 * 100 => CP
= 1600
Answer: D
Question: A sphere is inscribed in a cube with an edge of 10. What is the shortest possible distance from one of the vertices of the cube to the surface of the sphere?
A.10(√3-1)
B.5
C.10(√2-1)
D.5(√3-1)
Answer: D.5(√3-1)
Explanation: As sphere is inscribed in cube then
=>the edge of the cube equals to the diameter of a sphere --> Diameter=10
Diagonal of a cube equals to Diagonal=square_root(10^2+10^2+10^2)=10√3.
half of Diagonal-Diameter is gap between the vertex of a cube and the surface of the sphere = (10√3-10)/2
=5(√3-1)
ANSWER:D
Question: In how many ways can a committee consisting of three boys and four girls be formed from a group of six boys and seven girls?
A.⁶C₄ ⁷C₃
B.(⁷C₄)(⁶C₃)
C.⁶C₃ ⁷C₅
D.⁷C₅ ⁶C₄
Answer: B.(⁷C₄)(⁶C₃)
Explanation: The group contain six boys and seven girls
Three boys can be selected from six boys in ⁶C₃ ways.
Four girls can be selected from seven girls in ⁷C₄ ways.
Total number of ways = (⁷C₄)(⁶C₃)
B
Question: A canteen requires 13 dozen bananas per day. How
many bananas will it require for 9 weeks?
A.728
B.9828
C.1404
D.9882
Answer: D.9882
Explanation: Requirement of bananas for 1 day in the canteen
= 13 dozens
∴ Requirement of bananas for 9 weeks i.e. 63 days
= 63 × 13 dozens
= 63 × 13 × 12 = 9828.
Answer D
Question: A couple decides to have 3 children. If they succeed in having 4 children and each child is equally likely to be a boy or a girl, What is the probability that they will have exactly 2 girls and 1 boy?
A.1
B.2
C.3
D.5/8
Answer: D.5/8
Explanation: Sample space = 2^3 = 8.
Favourable events = {bgg}, {bgb}, {bbb}, {ggg}, {gbg}
Probability = 5/8 = 5/8.
Ans (D).
Question: Ramu bought an old car for Rs. 42000. He spent Rs. 10000 on repairs and sold it for Rs. 64900. What is his profit percent?
A.17%
B.19%
C.24.8%
D.14%
Answer: C.24.8%
Explanation: Total CP = Rs. 42000 + Rs. 10000
= Rs. 52000 and SP
= Rs. 64900
Profit(%) = (64900 - 52000)/52000 * 100
= 24.8%
Answer: C
Question: 01-Jan-2007 was Monday. What day of the week lies on 01-Jan-2008?
A.Wednesday
B.Sunday
C.Friday
D.Tuesday
Answer: D.Tuesday
Explanation: Explanation:
Given that January 1, 2007 was Monday.
Odd days in 2007 = 1 (we have taken the complete year 2007 because we need to find out the odd days from 01-Jan-2007 to 31-Dec-2007, that is the whole year 2007)
Hence January 1, 2008 = (Monday + 1 Odd day) = Tuesday
Answer: Option D
Question: The ratio between the number of sheep and the number of horses at the Stewar farm is 7 to 7. If each of horse is fed 230 ounces of horse food per day and the farm needs a total 12880 ounces of horse food per day. what is number sheep in the form??
A.18
B.28
C.32
D.56
Answer: D.56
Explanation: et no of sheep and horses are 7k and 7k
no of horses= 12880/230=56
now 7K=56 and k=8
no of sheep=(7*8) =56
ANSWER:D
Question: 2,500 has how many positive divisors?
A.10
B.12
C.15
D.20
Answer: C.15
Explanation: By factorization, we can write 2500 as 2500=2^2*5^4.
The number of factors is (2+1)(4+1) = 15
The answer is C.
Question: On dividing a number by 357, we get 40 as remainder.On dividing the same number by 17, what will be the remainder ?
A.6
B.5
C.8
D.7
Answer: A.6
Explanation: Let x be the number and y be the quotient.Then,
x=357*y+40
=(17*21*y)+(17*2)+6
=17*(21y+2)+6.
Required number =6.
Answer is A
Question: Five years ago the average of the ages of A and B was 40 years and now the average of the ages of B and C is 48 years. What will be the age of the B ten years hence?
A.16 years
B.15 years
C.56 years
D.Data inadequate
Answer: D.Data inadequate
Explanation: Let the present ages of A, B and C be a, b and c respectively.
Given, [(a - 5) + (b - 5)] / 2 = 40 => a + b = 90 --- (1)
(b + c)/2 = 48 => b + c = 96 --- (2)
From (1) and (2), we cannot find b.
Answer:D
Question: the square of two digit number(ab) divided by half of itself resultant added by 18 then divided by 2 then we get reverse of original number(ba). how many combination of ab exist
A.9
B.8
C.7
D.6
Answer: A.9
Explanation: (((10a+b)^2)/(10a+b/2)+18)/2=10b+a.
Simplify the above equation.
The final equation will be a-b=-1
There will be 8 combinations of a &b which will satisfy this equation.
i.e.
a=1,b=2
a=2,b=3
a=3,b=4
a=4,b=5
a=5,b=6
a=6,b=7
a=7,b=8
a=8,b=9
ANSWER:A
Question: If p and q are integers, such that p < 1 < q, and s is a nonnegative integer, which of the following must be true?
A.p^2 < q^2
B.p + q = 0
C.sp < sq
D.sp ≠ sq
Answer: A.p^2 < q^2
Explanation: We're told that P < 0 < Q and that S is a NON-NEGATIVE INTEGER. We're asked which of the following MUST be true.
P = -2
Q = 1
S = 0
Answer A: P^2 < Q^2.... 4 < 5 is TRUE
Answer B: P+Q=0... -2+1 = -1 NOT TRUE
Answer C: SP < SQ... 0 < 0 NOT TRUE
Answer D: SP ≠ SQ... 0 = 0 NOT TRUE
Answer E: P/Q < S... -2/1 < 0 not TRUE
A
Question: An meeting has 6 employees; there are 5 female employees and 1 male employee. In how many ways can a 3-person committee be created if the committee must include the male employee?
A.10
B.12
C.15
D.24
Answer: A.10
Explanation: An meeting has 6 employees;for male 1C1 = 1 ........ A
foe female = 5C2 = 10.........B
total = 10*1
= 10 - answer=A