RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The area of a square is equal to five times the area of a rectangle of dimensions 125 cm * 64 cm. What is the perimeter of the square?
A.876 cm
B.800 cm
C.167 cm
D.765 cm
Answer: B.800 cm
Explanation: Area of the square = s * s = 5(125 * 64)
=> s = 25 * 8 = 200 cm
Perimeter of the square = 4 * 200
= 800 cm.
Answer:B
Question: By selling 200 apples, a fruit-seller gains the selling price of 50 apples. Find the gain percent?
A.33.33%
B.35%
C.27.75%
D.35.75%
Answer: A.33.33%
Explanation: SP = CP + g
200 SP = 200 CP + 50 SP
150 SP = 200 CP
150 --- 50 CP
100 --- ? => 33.33%
Answer: A
Question: If C is the temperature in degrees Celsins and F is the temperature in degrees Fahrenheit, then the relationship between temperatures on the two scales is expressed by the equation 9C=5(F-32). In a weekly range of temperature recorded at a certain weather station differed by 25 degrees on the Fahrenheit scale, by how many degrees did the temperature extremes differ on the Celsius scale?
A.a) 65/9
B.b) 13
C.c) 25
D.d) 45
Answer: B.b) 13
Explanation: The relationship is 9/5 - 32, so approximately half of difference in Celsius (the -32 part won't be used in this case). Just looking at the answer choices you can pick B which is the only number near half of 25. The other answer choices are too far apart so no need to calculate.
Question: Pipe A can fill a tank in 10 hours, pipe B in 20 hours, and pipe C in 60 hours. If all the pipes are open, in how many hours will the tank be filled?
A.6
B.7
C.8
D.9
Answer: A.6
Explanation: The part filled by A + B + C in 1 hour is 1/10 + 1/20 + 1/60 = 1/6
All the three pipes together will fill the tank in 6 hours.
The answer is A.
Question: The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is
A.33
B.40
C.38
D.27
Answer: B.40
Explanation: Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Answer: B) 40
Question: A boat running downstream covers a distance of 20 km in 2 hours while for covering the same distance upstream, it takes 5 hours. What is the speed of the boat in still water?
A.6
B.7
C.8
D.9
Answer: B.7
Explanation: Explanation:
Rate downstream = (20/2) kmph = 10 kmph;
Rate upstream = (20/5) kmph = 4 kmph
Speed in still water = 1/2 (10 + 4) kmph = 7 kmph
ANSWER: B
Question: A man sells a car to his friend at 12% loss. If the friend sells it for Rs.54000 and gains 20%, the original C.P.of the car was :
A.Rs.21136.36
B.Rs.31136.36
C.Rs.51136.36
D.Rs.61136.36
Answer: C.Rs.51136.36
Explanation: Explanation:
S.P = Rs.54,000. Gain earned = 20%
C.P = Rs.[100/120Ã—54000]
=Rs. 45000
This is the price the first person sold to the second at at loss of 12%.
Now S.P = Rs.45000 and loss = 12%
C.P. Rs.[100/88Ã—45000]= Rs.51136.36
Correct Option : C
Question: In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 5500, the number of valid votes that the other candidate got, was:
A.2800
B.1980
C.2900
D.2200
Answer: B.1980
Explanation: B
Number of valid votes = 80% of 5500 = 4400.
Valid votes polled by other candidate = 45% of 4400
= (45/100 x 4400) = 1980.
Question: How many meters are there in 330 centimeters?
A.550 meters
B.3.3 meters
C.100 meters
D.3.5 meters
Answer: B.3.3 meters
Explanation: Solution:
1 meter = 100 centimeters
Just divide 330 by 100
330 Ã· 100 = 3.3, so there are 3.3 meters in 330 centimeters
Option B
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
A.40
B.44
C.47
D.83
Answer: B.44
Explanation: Explanation:
Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352 => T = 44.
Answer: Option B
Question: The sum of the mean, the median, and the range of the set {1,2,3} equals which one of the following values?
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: Here Mean => 1+2+3/3 => 2
median => 2
and range => 3-1 => 2
hence sum => 2+2+2 => 6
Answer: D
Question: The speed of light is approximately 1,86 * 10^4 miles per second. This approximate speed is how many miles per hour?
A. 1,11 * 10^7
B. 6,70 * 10^7
C. 1,11 * 10^8
D. 1,86 * 10^8
Answer: B. 6,70 * 10^7
Explanation: The easiest way to answer this question is by POE, it does not require any calculation (answered in 30seconds). In one hour there are 3600 seconds, therefore speed in miles/hour will be.
(1.86*10^4)*3600 = (1.86*10^4)*(3.6*10^3) = some number*10^7...
The key is realizing that thesome numberhas to be bigger thatn 1.86 (because 1.86*3.6), and the only answer that fits that is B
Question: A train 280 m long is running at a speed of 54 km/hr. In what time will it pass a bridge 200 m long?
A.32 sec
B.42 sec
C.45 sec
D.18 sec
Answer: A.32 sec
Explanation: total length= 280+200=480
speed=54km/h=(54*5)/18= 15/1m/s
time=(480*1)/15=32 sec.
ANSWER:A
Question: If 4/(a - 5) = 5/(a + 5), then a = ?
A.40
B.45
C.35
D.55
Answer: B.45
Explanation: Multiply all terms of the given equation by (a - 5)(a + 5), simplify and solve
(a - 5)(a + 5)[ 4/(a - 5) ] = (a - 5)(a + 5) [5/(a + 5) ]
4 (a + 5) = 5 (a - 5)
a =45
correct answer B
Question: In August,a cricket team that played 120 matches won 26% of the games it played.After a continuous winning streak,this team raised its average to 52%.How many matches did the team win to attain this average?
A.40
B.52
C.65
D.80
Answer: C.65
Explanation: let the no of matches played more=x
so,
(120+x)*52/100=31.2+x
by solving we get x=65
ANSWER:C
Question: A person can walk at a constant rate of 8mph and can bike at a rate of 16mph. If he wants to travel 72 miles in 8 hours using bike and walking at their constant rates, how much distance would he require to walk?
A.20
B.30
C.48
D.56
Answer: D.56
Explanation: Total distance = 72
Distance = Speed * Time
Walking speed = s1 = 8
Walking time = t1
Bike speed = s2 = 16
Time traveled in bike = t2
d1 + d2 = 72
s1t1 + s2t2 = 72
8*t1 + 16*t2 = 72
t1 + 2*t2 = 9 ----- (1)
Given: t1 + t2 = 8 ----- (2)
(1) - (2) --> t2 = 1 and t1 = 8 - 1 = 7
Walking distance = s1*t1 = 8*7 = 56
Answer: D
Question: If it is possible to from a word with the first, fourth, seventh and eleventh letters in the word 'SPHERVLVODS' write the second letter of thet word. Otherwise, X is the answer.?
A.D
B.E
C.S
D.P
Answer: B.E
Explanation: The first, fourth, seventh and eleventh letters of the word 'SPHERVLVODS'
The word formed is LESS
The second letter is E.
ANSWER B
Question: What is the units' digit of the following expression (11)^5*(1)^3*(21)^5?
A.0
B.1
C.3
D.5
Answer: B.1
Explanation: We do not have to do any calculations or find units digit of remaining numbers...
all three terms - 11,1,21 - are ODD and since the PRODUCT contains 1, the units digit of the product will remain 1
B
Question: The sum of three consecutive odd natural numbers, each divisible by 3 is 87. What is the largest among them?
A.21
B.24
C.27
D.32
Answer: D.32
Explanation: Let the 3 consecutive odd numbers each divisible by 3 be X, X+3, X+6
Given, X + X+3 + X+6 =87
3X = 78
X = 26
The numbers are 26, 29, 32
Therefore the largest number is 32
Answer D.
Question: The current ofa stream runs at the rate of 2 km/hour. A motor boat goes 10 km upstream & back again to the starting point in 55 min. Find the speed of the motor boat in still water?
A.20 km/hr
B.22 km/hr
C.28 km/hr
D.30 km/hr
Answer: B.22 km/hr
Explanation: Let the speed of the boat in still water =x km/hr
Speed of the current = 2 km/hr
Then, speed downstream =(x+2) km/hr
speed upstream =(x−2) km/hr
Total time taken to travel 10 km upstream and back = 55 minutes =5560 hour = 1112 hour
⇒10x−2+10x+2=1112 120(x+2)+120(x−2)=11(x2−4) 240x=11x2−44 11x2−240x−44=0 11x2−242x+2x−44=0 11x(x−22)+2(x−22)=0 (x−22)(11x+2)=0 x=22 or −211
Since x cannot be negative, x = 22
i.e., speed of the boat in still water = 22 km/hr
B
Question: Which of the following is the median number of goals scored per student?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: Total number of students = 8+2+5= 15
so median must be the middle term out of the 15 terms i.e., 8th term when arranged in ascending order
arranging in ascending order we have {1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 3, 3, 3, 3, 3}
median number of goals scored per student = 1
ANSWER:B
Question: A bag contains 25p coins, 50p coins and 1 rupee coins whose values are in the ratio of 8:4:2. The total values of coins are 840. Then find the total number of coins
A.220
B.240
C.260
D.280
Answer: D.280
Explanation: Value is given in the ratio 8:4:2.
(8x/0.25) + (4x/0.5) + (2x/1) = 840.
X = 20. Total amount = 14*20 = 280
Answer:D
Question: In his pocket, a boy has 3 red marbles, 4 blue marbles, and 5 green marbles. How many will he have to take out of his pocket to ensure that he has taken out at least one of each color?
A.7
B.8
C.9
D.10
Answer: D.10
Explanation: The worst case scenario would be that he has taken 4 blue and 5 green, a total of 9 marbles, and still doesn't have 3 distinct colors. But the next draw will surely be red as only the red marbles are left in his pocket.
The answer is D.
Question: A man invests a certain sum of money at 6% per annum simple interest and another sum at 7% per annum simple interest. His income from interest after 2 years was Rs. 354. One-forth of the first sum is equal to one-fifth of the second sum. The total sum invested was :
A.Rs.3100
B.Rs.2700
C.Rs.2200
D.Rs.1800
Answer: B.Rs.2700
Explanation: Explanation :
Let the man invests Rs.x at 6% and Rs.y at 7%
Simple Interest on Rs.x at 6% for 2 years + Simple Interest on Rs.y at 7% for 2 years = Rs.354
x × 6 ×2 /100+y×7×2/100=354
x × 6 × 2+y×7×2=354×100
x × 6+y × 7=177×100
6x+7y=17700⋯(1)
One-forth of the first sum is equal to one-fifth of the second sum
=>x/4=y/5
=>x=4y/5⋯(2)
Solving (1) and (2),
6x+7y=17700
6(4y/5)+7y=17700
24y+35y=17700×5
59y=17700×
y=300×5=1500
x=4y/5
=4×1500/5
=4×300
=1200
total sum invested = x + y = 1500 + 1200 = 2700
Answer : Option B
Question: If 1/(x+2)+1/(x-2)=1/(x+2), what is the value of x?
A.-1
B.2
C.1
D.-2
Answer: D.-2
Explanation: If we solve the question, we get x=-2.
Option: D
Question: A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late . Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late. What is the speed Q of the train.
A.a) 45
B.b) 33
C.c) 48
D.d) 55
Answer: C.c) 48
Explanation: Let y be the balance distance to be covered and x be the former speed.
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late
so, y/(3x/4) - y/x = 35/60
4y/3x - y/x = 7/12
y/x(4/3-1)=7/12
y/x*1/3=7/12
y/x=7/4
4y-7x=0 ........ 1
Had the accident occurred 24 km farther, it would have reached the destination only 25 minutes late
so, (y-24)/(3x/4) - (y-24)/x = 25/60
4(y-24)/3x - (y-24)/x = 5/12
(y-24)/x (4/3-1) = 5/12
(y-24)/x *1/3 = 5/12
(y-24)*12 = 3x*5
(y-24)*4 = 5x
4y-5x = 96 ....... 2
eq2 - eq1
2x=96
x=48=Q
Ans = C
Question: If a survey shows that 40 citizens out of a sample of 200 support a particular Senate bill, what percent of the sample does not support the bill?
A.56%
B.64%
C.80%
D.82%
Answer: C.80%
Explanation: Those who support = 40.
% of those who don't support it is (200-40)/ 200 = 80%
Answer C
Question: Evaluate: 2344 - 12*3*2 =?
A.2337
B.1227
C.3327
D.5457
Answer: A.2337
Explanation: According to order of operations, 12?3?2 (division and multiplication) is done first from left to right
12**2 = 4* 2 = 8
Hence
2344 - 12*3*2 = 2344 - 8 = 2337
correct answer A
Question: Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present
A.25
B.30
C.45
D.60
Answer: B.30
Explanation: Explanation:
Let their ages 10 years ago is x, 2x and 3x years.
10 + 2x + 10 + 3x + 10 = 90 hence x= 10
B’s present age = (2x + 10) =30 years
Option B
Question: A paint crew gets a rush order to paint 80 houses in a new development. They paint the first y houses at a rate of x houses per week. Realizing that they'll be late at this rate, they bring in some more painters and paint the rest of the houses at the rate of 1.25x houses per week. The total time W it takes them to paint all the houses under this scenario is what fraction of the time it would have taken if they had painted all the houses at their original rate of x houses per week?
A. 0.8(80 – y)
B. 0.8 + 0.0025y
C. 80/y – 1.25
D. 80/1.25y
Answer: B. 0.8 + 0.0025y
Explanation: This may be a case of bad numberpicking but it worked for me.
80 houses. Let's say that y=40 houses are painted at the rate x=10 houses per week <=> 1/10 week per house. 40*1/10 = 4 houses per week will be painted at this rate.
80-y = 80-40 = 40 houses are to be painted at the faster rate. X*1,25=12,5 houses per week <=> 1/12,5 weeks per house * 40 houses = 40/12,5 = 80/25 = 320/100 = 3,2 weeks.
Which means finishing all houses at normal rate W=> 2*4 = 8 weeks. Faster rate = 4+3,2 = 7,2 weeks.
7,2/8 = 9/10 = 0,9. Insert y=40 in equations and it is clear that only (B) gives us 0,9.
Question: Set M contains number that satisfy the condition that, if integer x is in the set then x + 2 will also be in the set M. If -4 is one value in the set, which of the following values must also be present in the set M?
I) -6
II) -2
III) 2
A.I only
B.II only
C.I and II only
D.II and III only
Answer: D.II and III only
Explanation: Since -4 is in the set, then the set must also include -2, 0, 2, 4, etc...
Depending on whether -4 is the starting element in the set or not, we can have -6...or not.
The answer is D.
Question: What is the HCF of 2/3, 4/12 and 6/5
A.7/45
B.2/45
C.4/15
D.1/30
Answer: D.1/30
Explanation: Explanation:
HCF of Fractions = HCF of Numerators/LCM of Denominators
= (HCF of 2, 4, 6)/(LCM of 3, 12, 5) = 2/60 = 1/30
Answer: Option D
Question: From (1, 2, 3, 4, 5, 6), one number is picked out and replaced and one number is picked out again. If the sum of the 2 numbers is 3, what is the probability that the 2 numbers included the number 1?
A.1/5
B.2/5
C.1
D.3/5
Answer: C.1
Explanation: We know that the sum of two numbers picked was 3. So, there could be the following cases:
(1, 2);
(2, 1);
Total of 2 cases out of which 2 have 1, thus the probability is 2/2=1.
Ans C
Question: Each family in a locality has atmost two adults, and no family has fewer than 3 children. Considering all the families together, there are more adults than boys, more boys than girls and more girls than families. Then the minimum possible number of families in the locality is
A.4
B.5
C.2
D.3
Answer: D.3
Explanation: Explanation :
As per the question, we need to satisfy three
conditions namely:
1. Adults (A) > Boys (B)
2. Boys (B) > Girls (G)
3. Girls (G) > Families (F)
Clearly, if the number of families is 2, maximum number of adults can only be 4. Now, for the second condition to be satisfied, every family should have atleast two boys and one girl each.
This will result in non-compliance with the first condition because adults will be equal to boys. If we consider the same conditions for 3 families, then all three conditions will be satisfied.
Answer : D
Question: A runs twice as fast as B and gives B a start of 50m.How long should the racecourse be so that A and B might reach in the same time?
A.75 m.
B.80 m.
C.150 m.
D.100 m.
Answer: D.100 m.
Explanation: ratio of speeds of a and b is 2:1
b is 50m away from a but we know that a covers 1 meter(2-1) more in every second than b
the time taken for a to cover 50m is 50/1=50m
so the total time taken by a and b to reach =2*50=100m
ANSWER:D
Question: An inspector rejects 0.08% of the meters as defective, How many meters he examine to reject 2 meteres
A.1300
B.1400
C.2400
D.2500
Answer: D.2500
Explanation: It means that 0.08% of x = 2
(8100×100 ×x)=2
x=2×100×1008
x=2500
ANSWER :D
Question: At 3:00 pm, a car has driven 10 miles east. It will continue to drive east at 0.8 minutes per mile and then turn around and drive at 0.8 minutes per mile back to its original starting point. How far can it drive before turning around in order to arrive back to its original starting point by 3:40 pm?
A.a) 10
B.b) 11
C.c) 12
D.d) 20
Answer: D.d) 20
Explanation: 0.8 minutes --> 1 mile
1 minute --> 1/0.8 = 10/8 = 1.25 miles/minute
Distance covered in 40 minutes = 1.25 * 40 = 12.5 * 4 = 50 miles
Distance covered in the current direction = Distance covered from the opposite direction (since car returns back to starting point)
Let x be the miles driven before turning
10 + x = 50 - x
2x = 40
x = 20
Answer: D
Question: The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 60/kg. how much did a kg of coffee cost in june ?
A.50
B.60
C.80
D.100
Answer: B.60
Explanation: Let the price of tea and coffee be x per kg in June.
Price of tea in July = 1.2x
Price of coffee in July = 0.8x .
In July the price of 1/2 kg (600gm) of tea and 1/2 kg (600gm) of coffee (equal quantities) = 60
1.2x(1/2) + 0.8x(1/2) = 60
=> x =60
Thus proved...option B.
Question: A women buys an article and sells it at a profit of 20%. If she had bought it at 20% less and sold it for $75 less, she could have gained 25%. What is the cost price?
A.392
B.424
C.375
D.273
Answer: C.375
Explanation: C
375
CP1 = 100 SP1 = 120
CP2 = 80 SP2 = 80 * (125/100) = 100
20 ----- 100
75 ----- ? => 375
Question: If two resistors, A(R1) and B(R2) stand in parallel with each other in electrical wire, the total resistor appears as R1R2/(R1+R2). If three resistors, A(R1), B(R2), and C(2R2) stand in parallel in electrical wire, what is the ratio W of the resistors’ sum of A and C to the resistors’ sum of A and B?
A.2(R1+R2):(R1+2R2)
B.(R1+R2):(R1+2R2)
C.(2R1+R2):(R1+2R2)
D.2(R1+R2):(2R1+R2)
Answer: A.2(R1+R2):(R1+2R2)
Explanation: two resistors A (r1) and B (r2).
total or sum of two resistors appear as
r1r2/r1+r2. It is looks like inversion of sum of rates.
1/r1+1/r2= r1+r2/r1r2.
same way sum of A(r1) and c(2r2)=1/r1+1/2r2
=2r2+r1/r12r2.
inversion rate = r12r2/2r2+r1.
ratio W of sum of a and c/sum of a and b=2r2r1/2r2+r1*r1+r2/r1r2
=2(r1+r2)/2r2+r1.A
Question: A and B start from Opladen and Cologne respectively at the same time and travel towards each other at constant speeds along the same route. After meeting at a point between Opladen and Cologne, A and B proceed to their destinations of Cologne and Opladen respectively. A reaches Cologne 40 minutes after the two meet and B reaches Opladen 50 minutes after their meeting. How long did A take to cover the distance between Opladen and Cologne?
A.1 hour
B.1 hour 20 minutes
C.2 hours 30 minutes
D.1 hour 40 minutes
Answer: B.1 hour 20 minutes
Explanation: v1 and V2 are speeds.
v1.t /50 = v2
v2.t/40 = v1
v1/v2 = 5/4
which train A would 50. 4/5 mins to cover the same distance
40 + 40 = 80 mins (ANS B)
Question: A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
A.5 mins
B.3 mins
C.7 mins
D.9 mins
Answer: B.3 mins
Explanation: D = 25 * 60 + 1500 = 3000 m
T = 3000/60 * 18/5 = 180 sec = 3 mins
Answer: B
Question: The area of a circular field is 17.56 hectares. Find the cost of fencing it at the rate of Rs. 4 per metre approximately
A.4457
B.4567
C.5943
D.4547
Answer: C.5943
Explanation: Explanation:
Area = (17.56 x 10000) m2= 175600 m2.
ΠR2 = 175600 ⇔ (R)2 = (175600 x (7/22)) ⇔ R = 236.37 m.
Circumference = 2ΠR = (2 x (22/7) x 236.37) m =1485.78 m.
Cost of fencing = Rs. (1485.78 x 4) = Rs. 5943.
Answer: Option C
Question: If n is a natural number, then (6n2 + 6n) is always divisible by:
A.Both 6 and 12
B.6 only
C.12 only
D.None of these
Answer: A.Both 6 and 12
Explanation: Explanation :
6n2 + 6n = 6n(n + 1)
Hence 6n2 + 6n is always divisible by 6 and 12 (∵ remember that n(n + 1) is always even) Answer : Option A
Question: A train 150 m long is running at a speed of 62 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?
A.5 sec
B.10 sec
C.12 sec
D.18 sec
Answer: B.10 sec
Explanation: Answer : B.
Speed of the train relative to man = (62 - 8) kmph
= (54* 5/18) m/sec = 15m/sec
Time taken by the train to cross the man
= Time taken by It to cover 150 m at 15 m / sec = 150 *1/ 15 sec = 10sec
Question: There are how many hours between x minutes past 12 noon and 8:10 p.m. of the same day, where x < 60?
A. (490-x)/60
B. (480-x)/60
C. (470-x)/60
D. 60 (60 – x + 7)
Answer: A. (490-x)/60
Explanation: Let's just say that X is equal to 10 so we will have that the number of hours will be 8, this is our target value. Now plug 10 in the answer choices to see which gives 8.
A is correct here.
Question: P is three times as fast as Q and working together, they can complete a work in 12 days. In how many days can Q alone complete the work?
A.16
B.88
C.29
D.14
Answer: A.16
Explanation: P = 3Q
P + Q = 3Q + Q = 4Q
These 4Q people can do the work in 12 days, which means Q can do the work in 48 days.
Hence, P can do the work in 16 days. Answer: A
Question: If a motorist had driven 1 hour longer on a certain day and at an average rate of 5 miles per hour faster, he would have covered 60 more miles than he actually did. How many more miles would he have covered than he actually did if he had driven 2 hours longer and at an average rate of 10 miles per hour faster on that day?
A. 100
B. 120
C. 140
D. 150
Answer: B. 120
Explanation: Case 1:
let rate = R, Time = T, and Distance =D
so D=RT
Case 2:
(D+60)=(R+5)(T+1)
Case 3:
(D+X)=(R+10)(T+2)
X=120
Ans B
Question: A BISCUIT manufacturer produces 300 units of a certain model each month at a cost to the manufacturer of £30 per unit and all of the produced units are sold each month. What is the minimum selling price per unit that will ensure that the monthly profit (revenue from sales minus production costs) on the sales of these units will be at least £30,000?
A.110
B.330
C.220
D.440
Answer: B.330
Explanation: 300(x-30)≥30,000
x-30≥300
x≥330
Answer: Option B
Question: 210 college students were asked in a survey if they preferred Windows or Mac brand computers. 60 Students claimed that they preferred Mac to Windows brand computers. One third as many of the students who preferred Mac to Windows, equally preferred both brands. 90 of the students had no preference. How many of the students in the survey preferred Windows to Mac brand computers?
A.25
B.40
C.50
D.60
Answer: B.40
Explanation: 120 = 60(Mac) + x(Window) + 20(both) => x=40
ANSWER:B
Question: Magnabulk Corp sells boxes holding d magnets each. The boxes are shipped in crates, each holding b boxes. What is the price charged per magnet, if Magnabulk charges m dollars for each crate?
A.100bd/m
B.100m/(bd)
C.bd/(100m)
D.m/(bd)
Answer: D.m/(bd)
Explanation: crate has = bd magnates
C crate cost = m dollars = 100 m cents
each magnate cost for each crate = m / bd
Ans; D
Question: The overall age of X and Y is 12 year greater than the overall age of Y and Z. Z is how many decades younger that X?
A.11
B.15
C.12
D.17
Answer: C.12
Explanation: C
12
(X + Y) – (Y + Z) = 12
X – Z = 12
Question: In the formula V = (4r)^2, if r is halved, then V is multiplied by
A.64
B.8
C.1/4
D.1/8
Answer: C.1/4
Explanation: Say r=2 => V1 = 16
when r=1; V2 = 4
V2 = 1/4*V1.
Answer : C
Question: Find √? /11= 4 ?
A.76
B.1936
C.1304
D.1296
Answer: B.1936
Explanation: Answer
Let √N/11= 4
Then √N = 11 x 4 = 44
∴ N = 44 x 44= 1936.
Correct Option: B