RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The average weight of 5 students decreases by 12 kg when one of them weighing 72 kg is replaced by a new student. The weight of the student is
A.12 kg
B.10 kg
C.20 kg
D.72 kg
Answer: A.12 kg
Explanation: Explanation :
Let the weight of student be x kg.
Given, Difference in average weight = 12 kg
=> (72-x)/5 = 12
=> x = 12
Answer : A
Question: A container has a capacity of 20 gallons and is full of spirit. 4 gallons of spirit is drawn out and the container is again filled with water. This process is repeated 4 times. Find how much spirit is left in the resulting mixture finally?
A.8(257/525) gallons
B.8(346/625) gallons
C.8.192 gallons
D.8.25 gallons
Answer: C.8.192 gallons
Explanation: There is a direct formula to calculate such repetition:
Left QTY / Orig QTY = ( (Orig QTY - Rep QTY) / Orig QTY )^n
where n is number of times mixing done:
Left QTY / 20 = (20 -4)^4 / 20^4
Left QTY = 20 (16/20)^4
Left QTY = 20 ( 4/5 )^4
Left QTY = 8.192
Answer is C
Question: Find the cost of fencing around a circular field of diameter 28 m at the rate of Rs.1.50 a meter?
A.289
B.132
C.279
D.277
Answer: B.132
Explanation: 2 * 22/7 * 14 = 88
88 * 1 1/2
= Rs.132
Answer: B
Question: If the price of an article decreases by 111/9 % and the sale of the article increases by 12 ½ %, what is the net effect on revenue?
A.1% loss
B.1% gain
C.No loss or no gain
D.Cannot be determined
Answer: C.No loss or no gain
Explanation: M. F 1 = 100-100/9/100 =800/900 = 8/9
M. F 2 = 100+25/2/100 =225/200 =9/8
Total M. F =8/9*9/8 = 1
Overall % change = ( M. F – 1 ) * 100 = ( 1 – 1 ) * 100 = 0
ANSWER:C
Question: A train 280 m long, running with a speed of 63 km / hr will pass a tree in
A.12 sec
B.15 sec
C.16 sec
D.20 sec
Answer: C.16 sec
Explanation: Sol.
Speed = (63 x 5/18) m/sec.
= 35 /2 m / sec.
Time taken = (280 x 2/35) sec = 16 sec
Answer C
Question: A salesman travels a distance of 50 km in 2 hours and 30 minutes. How much faster in kilometer per hour, on an average, must he travel to make such trip in 5/6 hour less time?
A.10km/hr
B.15km/hr
C.20km/hr
D.30km/hr
Answer: A.10km/hr
Explanation: Time required = 2 hrs 30 min - 50 min = 1 hr 40 min = 1 2/3 hrs
Required speed = 50*3/5 = 30km/hr
Original speed = 50*2/5 = 20 km/hr
Difference = 30-20 = 10 km/hr
Answer is A
Question: John tossed a fair coin 2 times. What is the probability that the coin landed heads up exactly twice?
A.0.5
B.0.55
C.0.6
D.0.65
Answer: A.0.5
Explanation: The probability is exactly same as the cion landed tail up once. That is 2*(1/2)^2 = 2/4 =0.5.
The answer is, therefore, (A).
Question: 0.002 x 0.5 = ?
A.0.0001
B.0.001
C.0.01
D.0.1
Answer: B.0.001
Explanation: 2 x 5 = 10.
Sum of decimal places = 4
0.002 x 0.5 = 0.001
Answer: Option B
Question: Andy completes a piece of work in 10 days, Raju completes the same work in 40 days. If both of them work together, then the number of days required to complete the work is
A.6 days
B.8 days
C.9 days
D.10 days
Answer: B.8 days
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 10 × 40/50 = 8 days.
B
Question: The price of commodity X increases by 40 paise every year, while the price of commodityY increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?
A.2010
B.2011
C.2012
D.2013
Answer: B.2011
Explanation: EXPLANATION
Suppose commodity X will cost 40 paise more than Y after z years.
Then, (4.20 + 0.40z) – (6.30 + 0.15z) = 0.40
0.25z = 0.40 + 2.10
x =2.50/ 0.25 =250/25 =10
X will cost 40 paise more than Y 10 years after 2001 i.e., 2011.
Answer B
Question: Let's find out how sharp your mind is. Let's see if you can find the missing numbers in the series:
192, 021, 222, 324, 252, 627, 2__, 9__?
A.281 and 930.
B.282 and 930.
C.283 and 930.
D.None
Answer: B.282 and 930.
Explanation: Solution:
If you look closely, you will find a sequence in every alternating number.
192, 222 and 252 form one series where 30 is added each time.
021, 324 and 627 form one series where 303 is added each time.
Thus the next two numbers will be 282 and 930.
Answer B
Question: A watch was sold at a loss of 21%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
A.560
B.882
C.799
D.778
Answer: A.560
Explanation: 79%
104%
--------
25% ---- 140
100% ---- ? => Rs.560
Answer: A
Question: The radius of a cylinder is 8 m, height 13 m. The volume of the cylinder is:
A.2200
B.2614.9
C.3300
D.1100
Answer: B.2614.9
Explanation: Cylinder volume = Ï€r(power2)h
= 22/7 Ã— 8 Ã— 8 Ã— 13
= 2614.9 m(power3)
Answer is B.
Question: A started a business with an investment of Rs. 70000 and after 6 months B joined him investing Rs. 120000. If the profit at the end of a year is Rs. 26000, then the share of B is?
A.A)14500
B.B)14000
C.C)12000
D.D)13007
Answer: C.C)12000
Explanation: Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6
Total profit = Rs. 26000
Share of B = 6/13 (26000)
= Rs. 12000
Answer:C
Question: If a+b+c=13, a2+b2+c2=69, then find ab+bc+ca
A.50
B.60
C.69
D.75
Answer: A.50
Explanation: (a+b+c)2= a2+b2+c2+2(ab+bc+ca)
2(ab+bc+ca)= (a+b+c)2- a2+b2+c2
=169-69
=100
ab+bc+ca=50
ANSWER A 50
Question: M = {-6, -5, -4, -3, -2}
T = {-2, -1, 0, 1, 2, 3, 4, 5}
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative?
A.5/8
B.1/3
C.2/5
D.1/2
Answer: A.5/8
Explanation: Answer A.
Total # of outcomes: 5*8= 40
# of outcomes where Product is -ve : (-6,1) ,(-6,2), (-6,3)... Hence, total: 25
Probability: 25/40 = 5/8
Question: Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 108 as interest at the end of the loan period, what was the rate of interest?
A.3.6
B.3
C.18
D.24
Answer: B.3
Explanation: Let rate = R% and time = R years.
Then, (1200 x R x R)/100 = 108
12R2 = 108
R2 =9
R = 3.
Answer: Option B
Question: A sum of money is to be distributed among A, B, C, D in the proportion of 5:2:4:3. If C gets Rs. 1000 more than D, what is B's share?
A.2778
B.2679
C.2000
D.2699
Answer: C.2000
Explanation: Let the shares of A, B, C and D be 5x, 2x, 4x and 3x Rs. respectively.
Then, 4x - 3x = 1000 => x = 1000.
B's share = Rs. 2x = 2 * 1000 = Rs.2000.
Answer:C
Question: When I acquired my Mercedes-Benz car in Germany, the first thing I had to do was to get a license plate. The plate I got had a peculiar number on it. It consisted of 5 different numbers and by mistake when I fixed it upside down the number could be still read, but the value had increased by 78633.
A.10966
B.10968
C.10967
D.10966
Answer: B.10968
Explanation: 5 differ numbers can be read upside down same are 0 , 1 , 6 , 8 , 9
try with these no.s
number is 10968.
10968
78633
-------
89601
--------
ANSWER:B
Question: Ram has two dies which has a nos 2,3,4,6 when he throws the two dies together find the no of possibility so that the some of the two dies should be even...???
A.4/8
B.5/8
C.6/8
D.7/8
Answer: B.5/8
Explanation: total possible combinations=(2,2)(2,4)(2,6)(4,2)(4,4)(4,6)(3,3)(6,2)(6,4)(6,6)=10
so probability=10/16=5/8
ANSWER:B
Question: When positive integer N is divided by positive integer J, the remainder is 16. If N/J = 127.05, what is value of J?
A.300
B.320
C.370
D.400
Answer: B.320
Explanation: When a number is divided by another number, we can represent it as : Dividend = Quotient * Divisor + Remainder
So, Dividend/Divisor = Quotient + Remainder/Divisor
Given that N/J = 127.05
Here 127 is the quotient.
Given that Remainder = 16
So, 127.05 = 127 + 16/J
So, J = 320
Answer: B
Question: When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 15-inch boxes. If the university pays $1.20 for every box, and if the university needs 3.06 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes?
A.$255
B.$275
C.$510
D.$612
Answer: D.$612
Explanation: Total no. Of boxes = 3060000/(20×20×15) = 510
Total cost = 510×$1.20=$612
Answer D
Question: Which of the following describes all values of x for which 9–x^2 >= 0?
A. x >= 1
B. x <= –1
C. -3 <= x <= 3
D. x <= –1 or x >= 1
Answer: C. -3 <= x <= 3
Explanation: 9 - x^2 >=0
means x^2 - 9 <=0
=> (x-3)(x+3) <= 0
=> -3 <= x <= 3
Answer - C
Question: How many integers between 324,700 and 458,600 have a 2 in the tens digit and a 1 in the units digit?
A.1339
B.2300
C.4200
D.1340
Answer: A.1339
Explanation: There is one number in hundred with 2 in th tens digit and 1 in the units digit: 21, 121, 221, 321, ...
The difference between 324,700 and 458,600 is 458,600-324,700=133,900 - one number per each hundred gives 133,900/100=1,339 numbers.
Answer: 1,339 A
Question: In business, A and C invested amounts in the ratio 4:2, whereas the ratio between amounts invested by A and B was 4:1, If Rs 20,000 was their profit, how much amount did A receive.
A.13333
B.26758
C.45896
D.14639
Answer: A.13333
Explanation: Explanation:
A:B = 4:1 = 4:1
=> A:C = 4:2 = 4:2
=> A:B:C = 4:1:2
A share = (4/6)*20000
= 13333
Option A
Question: The arithmetic mean and standard deviation of a certain normal distribution are 14.5 and 1.7, respectively. What value is exactly 2 standard deviations less than the mean?
A.10.5
B.11
C.11.1
D.12
Answer: C.11.1
Explanation: Mean = 14.5
Two standard deviations is 1.7 + 1.7 = 3.4
There could be two calues for this.
Mean + two standard deviations = 17.9
Mean - Two standard deviations = 11.1
Answer choice has 11.1 and so C is the answer.
Question: What number comes next?
482, 693, 754, 826, 937, ?
A.113
B.231
C.245
D.548
Answer: D.548
Explanation: D
548
The numbers 48269375 are being repeated in the same sequence.
Question: There is a certain relation between two given words on one side of : : and one word is given on another side of : : while another word is to be found from the given alternatives, having the same relation with this word as the given pair has.
A.Chauffeur
B.Steering
C.Mechanic
D.Brake
Answer: A.Chauffeur
Explanation: Explanation:
Horse is driven by a jockey .
Similarly,car is driven by a chauffeur
Answer: A)
Question: Anil spends 40% of his income on rent, 30% of the remaining on medicines and 20% of the remaining on education. If he saves Rs. 840 every month, then find his monthly salary?
A.2882
B.2672
C.2288
D.2500
Answer: D.2500
Explanation: Let's Anil's salary be Rs. 100.
Money spent on Rent = 40% of 100 = Rs. 40.
Money spent on medical grounds = 30% of (100 - 40) = 3/10 * 60 = Rs. 18.
Money spent on education = 20% of (60 - 18) = 1/5 * 42 = Rs. 8.40
Anil saves 100 - (40 + 18 + 8.40) i.e., Rs. 33.60
for 33.6 ---> 100 ; 840 ---> ?
Required salary = 840/33.6 * 100 = Rs. 2500
Answer: D
Question: 15 men take 21 days of 8 hrs. each to do a piece of work. How many days of 3 hrs. each would it take for 21 women if 3 women do as much work as 2 men?
A.60
B.20
C.19
D.29
Answer: A.60
Explanation: Let 1Man does 1unit/hr of work
15M in 21 days of 8hrs will do (15*21*8) units
3W = 2M
1W=(2/3)units/hr
21W with 3hrs a day will take (15*21*8)/(21*3*(2/3)) days
=> 60 Days
ANSWER:A
Question: Shopkeeper rise price by 31% and gives successive discount of 10% and 15%. What is overall % gain or loss?
A.0.215%
B.1.215%
C.3.215%
D.6.215%
Answer: A.0.215%
Explanation: Let d initial price be 100
31 % rise
now price = 131/100*100 = 131
10% discount
Then price = 131 * 90/100 = 117.9
15 % discount
Then price = 117.9 * 85/100 = 100.215
So Gain = 100.215 - 100 = 0.215
Gain % = Gain * 100 /CP
==> 0.215 * 100 /100 = 0.215%
ANSWER:A
Question: Jane covered a distance of 330 miles between city A and city B taking a total of 5 hours. If part of the distance was covered at 60 miles per hour speed and the balance at 80 miles per hour speed, how many hours did she travel at 60 miles per hour?
A.2 hours 30 minutes
B.3 hours
C.2 hours
D.1 hour 45 minutes
Answer: A.2 hours 30 minutes
Explanation: Answer
Let Jane travel 'x' at 60 miles per hour.
As the total time taken to cover 340 miles is 5 hours, Jane would have traveled (5 - x) hours at 80 miles per hour.
Distance covered at 60 miles per hour = Speed * time = 60 * x = 60x miles.
Distance covered at 80 miles per hour = Speed * time = 80 (5 - x) = 400 - 80x miles.
Total distance covered = Distance covered at 60 miles per hour + Distance covered at 80 miles per hour.
Therefore, total distance = 60x + 400 - 80x.
Total distance travelled = 340 miles.
Therefore, 330 = 60x + 400 - 80x
20x = 50 or x = 2 hours 30 minutes.
Choice A
Question: 1^2 – 2^2 + 3^2 – 4^2 + 5^2 – 6^2 + 7^2 – 8^2 + 9^2 – 10^2=?
A.-21
B.-53
C.-35
D.-55
Answer: D.-55
Explanation: 1-4+9-16+25-36+49-64+81-100= -55
ANSWER:D
Question: Find 4 + 7 + 10 + 13 + 16 + . . . up to 20 terms
A.650
B.640
C.630
D.620
Answer: A.650
Explanation: a = 4
d = 7 – 4 = 3
Sum of first 20 terms, S20
ANSWER IS A
Question: A man invested Rs. 26000 in 5% stock at 104. He sold the stock when the price rose to Rs. 120 and invested the sale proceeds in 6% stock. By doing this his income increased by Rs. 2500. At what price did he purchase the second stock?
A.125
B.40
C.48
D.35
Answer: C.48
Explanation: Assuming that face value of the first stock = Rs.100 as it is not given in the question
Since it is a 5% stock, we can take the dividend per stock = Rs.5
Market Value of the first stock = Rs.104
Investment on the first stock = Rs.26000
Number of stocks purchases = 26000/104 = 250
His total income from all these stocks = Rs.250 × 5 = Rs.1250
He sells each of this stock at Rs.120
ie, amount he earns = Rs.120 × 250 = Rs.30000
He invest this Rs.30000 in 6% stock (here also face value is not given and hence take it as Rs.100)
His new income = Rs.(1250 + 2500) = Rs.3750
ie, By Rs.30000 of investment , he earns an income of Rs.3750
To get an income of Rs.6, investment needed = 30000×6/3750=Rs.48
This is the market value of the second stock
Answer is C.
Question: 55
a6
+ 2b
____
96
If a and b represent positive single digits in the correctly worked computation above, what is the value of a + 2b ?
A.2
B.7
C.9
D.11
Answer: D.11
Explanation: Adding the digits in unit's place , 5+ 6 + b = 16 (Since a and b are positive single digits )
=> b = 5
Now adding the digits in ten's place , 5+a + 2 + 1= 9 (1 has been carried over from unit's place addition)
=> a= 1
a+2b = 1+2*5
=11
Answer D
Question: A can do a piece of work in 4 hours; B and C together can do it in 3 hours, which A and C together can do it in 2 hours. How long will B alone take to do it?
A.11
B.77
C.12
D.99
Answer: C.12
Explanation: A's 1 hour work = 1/4;
(B + C)'s 1 hour work = 1/3;
(A + C)'s 1 hour work = 1/2
(A + B + C)'s 1 hour work = (1/4 + 1/3) = 7/12
B's 1 hour work = (7/12 + 1/2) = 1/12
B alone will take 12 hours to do the work.
Answer: C
Question: Company KW is being sold, and both Company A and Company B were considering the purchase. The price of Company KW is 50% more than Company A has in assets, and this same price is also 100% more than Company B has in assets. If Companies A and B were to merge and combine their assets, the price of Company KW would be approximately what percent of these combined assets?
A.66%
B.75%
C.86%
D.116%
Answer: C.86%
Explanation: Let the price of Company A's assets be 100
Price of assets of KW is 50% more than company A's assets which is 150
Price of assets of KW is 100% more than company B's assets which means price of Company B's assets is half the price of KW = 75
A+B = 175
KW = 150
KW/(A+B)*100 = 150/175*100 = 85.7% or 86%
ANSWER:C
Question: A certain boxer has agreed to pay his opponent a fee of 4% of his total purse for every pound over the specified weight limit he weighs in. If the boxer pays his opponent a fee of $26,250 after weighing in seven pounds over the specified limit, what was the boxer's purse?
A.$65,625
B.$105,000
C.$150,000
D.$93,750
Answer: D.$93,750
Explanation: .04*7 = .28
26250/.28 = $93,750
Answer: D
Question: In a class of 38 students 26 play football and play 20 long tennis, if 17 play above, many play neither?
A.6
B.8
C.9
D.12
Answer: C.9
Explanation: 26 + 20 - 17 = 29
38 - 29 = 9 play neither
Answer is C
Question: The ratio of money with Ram and Gopal is 7 : 17 and that with Gopal and Krishan is 7: 17. If Ram has Rs. 686, Krishan has ?
A.s. 2890
B.s. 4046
C.s. 1190
D.s. 1620
Answer: B.s. 4046
Explanation: Ram : Gopal = 7 : 17 = 49 : 119
Gopal : Krishan = 7 : 17 = 119 : 289
Ram : Gopal : Krishan = 49 : 119 : 289
Ram : Krishan = 49 : 289
Thus, 49 : 289 = 686 : N
&there N = 289 x 686 / 49
= Rs. 4046
Answer :B
Question: The list price of an article is Rs.65. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?
A.2%
B.4%
C.6%
D.9%
Answer: B.4%
Explanation: 65*(90/100)*((100-x)/100) = 56.16
x = 4%
Answer:B
Question: A salesperson received a commission of 3 percent of the sale price for each of the first 100 machines that she sold and 4 percent of the sale price for each machine that she sold after the first 100. If the sale price of each machine was $10,000 and the salesperson received a $32,000 commission, how many machines did she sell?
A. 90
B. 110
C. 105
D. 115
Answer: B. 110
Explanation: First 100 machines = 3% commission = 0.03*100*10000 = 30000
Commission from sale of next machines = 34000 - 30000 = 4000
So 10 more machines..
Total = 110 machines
IMO B..
Question: An alloy weighing 60 ounces is 20 percent copper. How many ounces of copper must be added to create an alloy that is 60 percent copper?
A.40
B.50
C.60
D.70
Answer: C.60
Explanation: An alloy of 60oz which is 20% copper means there is 12 oz of gold. To get to an alloy that is 60% copper, let's use this expression: (12 + x)/(60 + x) = 0.60 with x representing the amount of pure copper that must be added to get to 60%. The expression we are using represents the new total weight of pure copper over the new total weight of the alloy and this fraction should represent 60% or 0.6. you will see that 60 is the correct answer, as 72/120=0.6
Choose C
Question: Foodmart customers regularly buy at least one of the following products: milk, chicken, or apples. 60% of shoppers buy milk, 50% buy chicken, and 45% buy apples. If 10% of the customers buy all 3 products, what percentage of Foodmart customers purchase exactly 2 of the products listed above?
A.5%
B.10%
C.15%
D.35%
Answer: D.35%
Explanation: The formula is
n(AUBUC) = n(A)+n(B)+n(C)-B+A-N
where B is both (it will sum of (AB), (BC), (CA)).
and A is All
and N is neither
so plugging in we get
100 = 60+50+45+10-B-0
B = 65.
exactly two = 65 - 3(10) = 35
subtracting 10% three times as this value is including in all the (AB), (BC), (CA).
Answer D
Question: A number when divided by 296 leaves 75 as remainder. When the same number is divided by 37, the remainder will be:
A.1
B.2
C.8
D.11
Answer: A.1
Explanation: Let x = 296q + 75
= (37 x 8q + 37 x 2) + 1
= 37 (8q + 2) + 1
Thus, when the number is divided by 37, the remainder is 1.
Answer :A
Question: Two cars start from the opposite places of a main road, 105 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point?
A.65
B.38
C.20
D.28
Answer: C.20
Explanation: Answer: C) 20 km
Question: If N = 2^0.25 and N^b = 8, b must equal
A.3/80
B.3/5
C.12
D.5/3
Answer: C.12
Explanation: 25/100 = 1/4
N = 2 ^ 1/4
N^b = 2^3
(2^1/4)^b = 2^3
b =12
Answer: C
Question: If $400 is deposited into a savings account at an annual interest rate of 3% that compounds monthly, what is the value of the investment after 8 years?
A.574.65
B.514.23
C.508.35
D.536.87
Answer: C.508.35
Explanation: Using CI Formula:
A=P(1+r/n)^n*t
A=400(1+3/2)^2*8
A=508.35.
Option: C
Question: The wheel of a motorcycle, 70 cm in diameter makes 40 revolutions in every 10 seconds. What is the speed of the motorcycle in km/hr
A.30.68 km/hr
B.31.68 km/hr
C.32.68 km/hr
D.33.68 km/hr
Answer: B.31.68 km/hr
Explanation: Explanation:
In this type of question, we will first calculate the distance covered in given time.
Distance covered will be, Number of revolutions * Circumference
So we will be having distance and time, from which we can calculate the speed. So let solve.
Radius of wheel = 70/2 = 35 cm
Distance covered in 40 revolutions will be
40 * Circumference =40 * 2*\pi*r =40∗2∗22/7∗35=8800cm
=8800/100m=88m
Distance covered in 1 sec =88/10=8.8m
Speed=8.8m/s=8.8∗18/5=31.68km/hr
Option B
Question: Yesterday's closing prices of 2,420 different stocks listed on a certain stock exchange were all different from today's closing prices. The number of stocks that closed at a higher price today than yesterday was 20 percent greater than the number that closed at a lower price. How many of the stocks closed at a higher price today than yesterday?
A.484
B.726
C.1,100
D.1,320
Answer: D.1,320
Explanation: Lets consider the below -
The number of stocks that closed at a higher price = H
The number of stocks that closed at a lower price = L
We understand from first statement -> H+L = 2420 ----(1)
We understand from second statement -> H = (120/100)L => H = 1.2L ----(2)
Solve eq (1) & (2) to get H = 1320.
D is answer.
Question: 10 is 6% of a, and 6 is 10% of b. c equals b/a. What is the value of c?
A.3/10
B.6/17
C.9/25
D.10/33
Answer: C.9/25
Explanation: 6a/100 = 10
a = 500/3
b/10 = 6
b = 60
c = b/a = 60*3/ 500 = 9/25
The answer is C.
Question: At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but,not together?
A.(5 + 5/11 )min past 5
B.(5 + 5/11 )min past 7
C.(5 + 5/11 )min past -0
D.(5 + 7/11 )min past 7
Answer: B.(5 + 5/11 )min past 7
Explanation: Explanation:
When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.
At 7 o'clock, they are 25 min. spaces apart.
Minute hand will have to gain only 5 min. spaces.
55 min. spaces are gained in 60 min.
5 min spaces are gained in min = min
so, Required time = min past 7
Answer: B)
Question: Valentine day 14 Feb. 2005 was celebrated by Anand and shilpa on Tuesday. They were very happy. What day of the week would come on 14 Feb. 2010?
A.monday
B.tuesday
C.sunday
D.wednesday
Answer: A.monday
Explanation: feb 14 2005 - tuesday
feb 14 2006 - wednesday
feb 14 2007 - thursday
feb 14 2008 - friday
feb 14 2009 - sunday[since 2008 is leap year , 2 days ll go forward]
feb 14 2010 - monday
ANSWER:A
Question: A certain characteristic in a large population has a distribution that is symmetric about the mean m. 84 percent of the distribution lies within one standard deviation d of the mean. If the shelf’s average life is 9.2 years and the standard deviation is 3.5 years, what percent of the distribution has more than 12.7 years as a shelf’s average life?
A.18%
B.19%
C.20%
D.21%
Answer: D.21%
Explanation: Average = 9.2
SD = 3.5
9.2 - 3.5 < 84% of distribution < 9.2 + 3.5
5.7 < 84% of distribution < 12.7
42% is outside this range.
Given: Distribution is symmetric. So 21% of distribution is less than 5.7 and the other 21% of distribution is greater than 5.7.
Answer: D
Question: If 20 men can build a wall 66 meters long in 6 days, what length of a similar can be built by 86 men in 8 days?
A.49
B.39
C.29
D.19
Answer: A.49
Explanation: Let the required length be x meters
More men, More length built (Direct Proportion)
Less days, Less length built (Direct Proportion)
Men 20: 35
Days 6: 3 : : 56 : x
Therefore (20 x 6 x x)=(35 x 3 x 56)= x=(35 x 3 x 56)/120=49
Hence, the required length is 49 m.
Answer is A.