RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The ratio between the present ages of A and B is 7:3 respectively. The ratio between A's age 4 years ago and B's age 4 years hence is 1:1. What is the ratio between A's age 4 years hence and B's age 4 years ago?
A.3:4
B.3:0
C.9:1
D.9:2
Answer: C.9:1
Explanation: Let the present ages of A and B be 7x and 3x years respectively.
Then, (7x - 4)/(3x + 4) = 1/1
4x = 8 => x = 2
Required ratio = (5x + 4):(3x - 4) = 18:2 = 9:1.Answer: C
Question: If 47.5% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class?
A.110
B.330
C.550
D.462
Answer: D.462
Explanation: Students enrolled in biology are 47.5% and therefore not enrolled are 52.5%. so of 880 is 880*.525 = 462
Answer is D 462
Question: Anil started a business with Rs.5000 and Rajesh joined afterwards with Rs.10,000. If profit at the end of the year is divided equally, then when did Rajesh join him?
A.6 months afterwards
B.8 months afterwards
C.9 months afterwards
D.5 months afterwards
Answer: A.6 months afterwards
Explanation: 5000*12=10000*(12-x)
x=6
ANSWER:A
Question: Two consultants can type up a report in 12.5 hours and edit it in 7.5 hours. If Mary needs 30 hours to type the report and Jim needs 12 hours to edit it alone, how many T hours will it take if Jim types the report and Mary edits it immediately after he is done?
A.41.4
B.34.1
C.13.4
D.12.4
Answer: A.41.4
Explanation: Break down the problem into two pieces: typing and editing.
Mary needs 30 hours to type the report--> Mary's typing rate = 1/30 (rate reciprocal of time)(point 1 in theory below);
Mary and Jim can type up a report in 12.5and --> 1/30+1/x=1/12.5=2/25 (where x is the time needed for Jim to type the report alone)(point 23 in theory below)--> x=150/7;
Jim needs 12 hours to edit the report--> Jim's editing rate = 1/12;
Mary and Jim can edit a report in 7.5and --> 1/y+1/12=1/7.5=2/15 (where y is the time needed for Mary to edit the report alone) --> y=20;
How many T hours will it take if Jim types the report and Mary edits it immediately after he is done--> x+y=150/7+20=~41.4
Answer: A.
Question: The difference of 2 digit number & the number obtained by interchanging the digits is 36. What is the difference the sum and the number if the ratio between the digits of the number is 1:2 ?
A.5
B.8
C.10
D.14
Answer: B.8
Explanation: Let the number be xy.
Given xy – yx = 36.
This means the number is greater is than the number got on reversing the digits.
This shows that the ten’s digit x > unit digit y.
Also given ratio between digits is 1 : 2 => x = 2y
(10x + y) – (10y +x) = 36 => x – y = 4 => 2y – y =4.
Hence, (x + y) – (x – y) = 3y – y = 2y = 8
B
Question: At Ram's firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a $1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?
A.700
B.1000
C.1300
D.1600
Answer: C.1300
Explanation: At Ram's firm's annual revenue grows twice as fast as its costs.First solve for how much revenue is increasing each year:
R2008= R2007*(1+x)
R2009= R2007*(1+x)^2=1.44*R2007
(1+x)^2 = 1.44
1+x=1.2
x=0.2 aka revenue increases 20% each year and cost increases 10% annually
Next solve for R2007and C2007:
R2007= C2007- 1000
1.2*R2007- 1.1*C2007= 0
1.2*[C2007- 1000] - 1.1*C2007= 0
0.1*C2007= 1,200
C2007= 12,000
R2007= 11,000
Finally find 2009 profits:
Profit2009= 1.44*11,000 - 1.21*12,000
Profit2009= 15,840 - 14,520
Profit2009= 1320
Answer: C
Question: A boat moves upstream at the rate of 1 km in 30 minutes and down stream 1 km in 12 minutes. Then the speed of the current is :
A.1.5 kmph
B.2 kmph
C.3 kmph
D.2.5 kmph
Answer: A.1.5 kmph
Explanation: Rate upstream = (1/30 *60) = 2 kmph
Rate down stream = 1/12 * 60 = 5 kmph
Rate of the current = ½ (5-2) = 1.5 kmph
ANSWER:A
Question: It rained as much as on Wednesday as on all the other days of the week combined. If the average rainfall for the whole week was 3.5 cms, How much did it rain on Wednesday?
A.10.9
B.10.5
C.12.25
D.10.1
Answer: C.12.25
Explanation: Explanation:
Let the rainfall on wednesday = 6x.
âˆ´ Rainfall on the remaining days = 6x
Given,
(6x + 6x )/7 = 3.5
â‡’12x = 24.5
â‡’6x = 12.25
Answer: C
Question: Two trains are moving in the same direction at 72 kmph and 36 kmph. The faster train crosses a man in the slower train in 27 seconds. Find the length of the faster train?
A.270
B.288
C.266
D.299
Answer: A.270
Explanation: Relative speed = (72 - 36) * 5/18 = 2 * 5 = 10 mps.
Distance covered in 27 sec = 27 * 10 = 270 m.
The length of the faster train = 270 m.
Answer: A
Question: How many positive integers less than 22 can be expressed as the sum of a positive multiple of 2 and a positive multiple of 3?
A.14
B.17
C.12
D.11
Answer: B.17
Explanation: The number = 2a + 3b < 20
When a = 1, b = 1, 2, 3, 4, 5, 6 -> 2a = 2; 3b = 3, 6, 9, 12, 15, 18 -> the number = 5, 8, 11, 14, 17, 20 --> 6 numbers
when a =2, b = 1,2,3,4,5, 6 -> ....--> 6 numbers
when a =3, b = 1,2,3,4, 5 --> ....--> 5 numbers
Total number is already 17. Look at the answer there is no number greater than 17 --> we dont need to try any more
Answer must be B
Question: a school has 11 maths 8 physics and 5 chemistry teachers each teacher can teach 3 subjects max what is he minimum number of teachers required
A.2
B.4
C.6
D.8
Answer: D.8
Explanation: Total subjects = 11+8+5=24
Max subjects by 1 teacher = 3
So, min of teachers required = 24/3 = 8
ANSWER:D
Question: Harish can paint a wall in just 3 hours. However it takes 6 hours for Ganpat to complete the same job of painting the wall.
How long would it take for both of them to paint the wall , if both work together ?
A.3 Hours
B.1 Hours
C.3.20 Hours
D.2 Hours
Answer: D.2 Hours
Explanation: D
Two hours.
Harish who could paint the wall in 3 hours could paint 2/3 of the wall in just two hours. Ganpat who paint the wall in 6 hours could paint 1/3 of the wall in two hours.
2/3 + 1/3 = 1.
Question: If 2 is one solution of the equation x^2 + 3x + k = 10, where k is a constant, what is the other solution?
A. -7
B. -4
C. -5
D. 1
Answer: C. -5
Explanation: The phrase “2 is one solution of the equation” means that one value of x is 2. Thus, we first must plug 2 for x into the given equation to determine the value of k. So we have
2^2 + (3)(2) + k = 10
4 + 6 + k = 10
10 + k = 10
k =0
Next we plug 0 into the given equation for k and then solve for x.
x^2 + 3x = 10
x^2 + 3x – 10 = 0
(x+5)(x-2) = 0
x = -5 or x = 2
Thus, -5 is the other solution. Answer C.
Question: Suzie’s Discount Footwear sells all pairs of shoes for one price and all pairs of boots for another price. On Monday the store sold 22 pairs of shoes and 16 pairs of boots for $650. On Tuesday the store sold 8 pairs of shoes and 32 pairs of boots for $760. How much more do pairs of boots cost than pairs of shoes at Suzie’s Discount Footwear?
A.$2.50
B.$5.00
C.$5.50
D.$7.50
Answer: B.$5.00
Explanation: Let X be pair of shoes and Y be pair of boots.
22x+16y = 650 ... eq1
8x +32y = 760....eq 2.
Now multiply eq 1 by 2 and sub eq 2.
44x = 1300
8x = 760.
36x = 540 => x = 15.
Sub x in eq 2.... we get 120 + 32y = 760... then we get 32y = 640 then y = 20
Difference between X and Y is 5.
Answer: option B is correct answer.
Question: A triangle has a perimeter 16. The two shorter sides have integer lengths equal to x and x + 1. Which of the following could be the length of the other side?
A.2
B.4
C.6
D.7
Answer: C.6
Explanation: The SHORTER sides have integral lengths equal to x and x + 1
Let the longest side be 'a'
So, a + x + (x +1) = 16
a + 2x = 15.......eqn (1)
We know that the sum of the lengths of the shorter sides has to be more than the length of the longer one. i.e 2x+1> a
a =6
C
Question: If a·b·c·d=360, where a, b, c and d are positive integers, and a<b<c<d, which of the following could be the value of d−a?
A.9
B.10
C.11
D.13
Answer: B.10
Explanation: prime factorize : 360 = 2*3*5*12
Hence a = 2 and d = 12 .
Hence answer is 12 - 2 = 10
Answer B
Question: The maximum number of students among them 1008 pens and 928 pencils can be distributed in such a way that each student get the same number of pens and same number of pencils?
A.16
B.18
C.36
D.19
Answer: A.16
Explanation: number of pens = 1008
number of pencils = 928
Required number of students = H.C.F. of 1008 and 928 = 16
Answer is A
Question: Every student in a room is either a junior or a senior. There is at least one junior and at least one senior in the room. If 1/2 of the juniors is equal to 2/3 of the seniors, what fraction of the students in the room are juniors?
A.4/7
B.1/3
C.5/3
D.12/7
Answer: A.4/7
Explanation: Let total number of juniors= J
total number of seniors =S
(1/2) J = (2/3) S
=> S = 3/4 J
Total number of students = J+S = (7/4) J
Fraction of the students in the room are juniors = J/(J+S) = J/[(7/4) J]
=4/7
Answer A
Question: Rani bought more apples than oranges. She sells apples at ₹23 apiece and makes 15% profit. She sells oranges at ₹10 apiece and makes 25% profit. If she gets ₹653 after selling all the apples and oranges, find her profit percentage.
A.16.8%
B.17.4%
C.17.9%
D.18.5%
Answer: B.17.4%
Explanation: Given: Selling price of an Apple = 23 --> Cost price = 23/1.15 = 20
Selling price of an orange = 10 --> Cost price = 10/1.25 = 8
A > O
23*(A) + 10*(O) = 653
653 - 23*(A) has to be divisible by 10 --> Units digit has to be 0
Values of A can be 1, 11, 21, 31, .... --> 1 cannot be the value
Between 11 and 21, If A = 11, O = 30 --> Not possible
If A = 21, O = 17 --> Possible
Cost price = 20*21 + 8*17 = 420 + 136 = 556
Profit = 653 - 556 = 97
Profit% = (97/556)*100 = 17.4%
Answer: B
Question: The C.P of 10 pens is equal to the S.P of 12 pens. Find his gain % or loss%?
A.16 2/7%
B.16 6/3%
C.16 2/3%
D.16 1/3%
Answer: C.16 2/3%
Explanation: 10 CP = 12 SP
12 --- 2 CP loss
100 --- ? => 16 2/3%
Answer: C
Question: Jen has a jar of jam, and she ate 1/3 of the jam for lunch. If Jen ate 1/7 of the remaining jam for dinner, what fraction of the jam was left after dinner?
A.2/7
B.3/7
C.4/7
D.9/14
Answer: C.4/7
Explanation: Let x be the amount of jam at the beginning.
After lunch, the remaining jam was (2/3)x.
After dinner, the remaining jam was (6/7)(2/3)x = (4/7)x.
The answer is C.
Question: At what price must an article costing Rs.47.50 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price?
A.62.5
B.62.6
C.62.1
D.62.7
Answer: A.62.5
Explanation: CP = 47.50
SP = 47.50*(125/100) = 59.375
MP*(95/100) = 59.375
MP = 62.5
Answer: A
Question: Two whole numbers whose sum is 40 cannot be in the ratio
A.4:10
B.2:3
C.1:3
D.2:4
Answer: D.2:4
Explanation: D) 2:4
Question: The integers from 1 to 1851 are entered sequentially in 12 columns (numbered 1 to 12); i.e. Row 1 contains the numbers 1 to 12, Row 2 contains the next 12 numbers and so on. If the number 1369 occurs in row p and column q, then the value of p + q is
A.114
B.115
C.116
D.117
Answer: C.116
Explanation: 1369=114*12+1
1368=114*12 mean 1368 occurs in 114 row and 12 column.
so 1369 occur in 115 row and 1st column.as elements are entered sequentially.
so p=115 q=1.p+q=116
ANSWER:C
Question: For any integer p, *p is equal to the product of all the integers between 1 and p, inclusive. How many prime numbers are there between *6 + 3 and *6 + 6, inclusive?
A. One
B. None
C. Two
D. Three
Answer: B. None
Explanation: Generally *p or p! will be divisible by ALL numbers from 1 to p. Therefore, *6 would be divisible by all numbers from 1 to 6.
=> *6+3 would give me a number which is a multiple of 3 and therefore divisible (since *6 is divisible by 3)
In fact adding anyprimenumber between 1 to 6 to *6 will definitely be divisible.
So the answer is none (A)!
Supposing if the question had asked for prime numbers between *6 + 3 and *6 + 11 then the answer would be 1. For *6 +3 and *6+ 13, it is 2 and so on...
B
Question: At 5% per annum simple interest, Rahul borrowed Rs. 500. What amount will he pay to clear the debt after 4 years
A.750
B.700
C.650
D.600
Answer: D.600
Explanation: Explanation:
We need to calculate the total amount to be paid by him after 4 years, So it will be Principal + simple interest.
So,
=>500+500∗5∗4 /100=>Rs.600
Option D
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?
A.3:7
B.3:6
C.3:1
D.3:2
Answer: C.3:1
Explanation: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 42/3 = 14 kmph.Answer:C
Question: How many different 6-letter sequences are there that consist of 1A, 20B's and 15C's ?
A.6
B.60
C.120
D.360
Answer: D.360
Explanation: How many different 6-letter sequences are there that consist of 1 A, 20B's, and 15 C's?
(A) 6
(B) 60
(C) 120
(D) 360
(E) 720 (ANS D)
Question: A volume of 10976 l water is in a container of sphere. How many hemisphere of volume 4l each will be required to transfer all the water into the small hemispheres?
A.2812
B.8231
C.2734
D.2744
Answer: D.2744
Explanation: a volume of 4l can be kept in 1 hemisphere
therefore, a volume of 10976l can be kept in (10976/4) hemispheres
ans.2744
ANSWER:D
Question: 576, 529, 484, 441, 400, ?
A.324
B.361
C.289
D.256
Answer: B.361
Explanation: Explanation :
The pattern is 24^2, 23^2, 22^2, 21^2, 20^2, ...
So next number is 19^2 = 361
Answer : Option B
Question: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?
A.9:1
B.9:8
C.9:0
D.9:5
Answer: A.9:1
Explanation: Explanation:
Milk = 3/5 * 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10 = 8 liters.
Amount of water removed = 2 liters.
Answer: Option A
Question: In how many ways can 5 Indians and 5 Englishmen be seated along a circle so that they are alternate?
A.6!8!
B.4!5!
C.3!9!
D.8!5!
Answer: B.4!5!
Explanation: 5 Indians can be seated along a circle in 4! ways
Now there are 5 places for 5 Englishmen
5 Englishmen can be seated in 5! ways
Required number = 4!5!
Answer is B
Question: The sum of the first 50 positive even integers is 2,000. What is the sum of the odd integers from 101 to 200, inclusive?
A. 5,050
B. 7,500
C. 8,050
D. 15,000
Answer: C. 8,050
Explanation: 101+103+.......199
If we remove 100 from each of these it will be sum of 1st 100 odd numbers.
so 101+103+.......199 = 50 * 100 + (1+3+5+7+......)
sum of 1st 100 natural numbers = (100 * 101) / 2 = 5050
Sum of 1st 50 positive even integers = 2000
sum of 1st 100 odd numbers = 5050 - 2000 = 3050
so 101+103+.......199 = 50 * 100 + (1+3+5+7+......) = 5000 + 3050 =8050
C is the answer.
Question: The tax on a commodity is diminished by 20% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it?
A.20%
B.18%
C.15%
D.12%
Answer: D.12%
Explanation: Answer: Option D
100 * 100 = 10000
80 * 110 = 8800
10000------- 1200
100 ------- ? = 12%
Question: Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and they are sold fetching the profit 40% and 20% respectively. If the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4/3 and 5/3 times respectively, then the mixture will fetch the profit of
A.18%
B.20%
C.21%
D.33%
Answer: D.33%
Explanation: Answer: D.
Question: What is the total number of integers between 100 and 500(exclusive) that are divisible by 5?
A.51
B.63
C.79
D.66
Answer: C.79
Explanation: 105, 110, 115, ..., 490,495
This is an equally spaced list; you can use the formula:
n = (largest - smallest) / ('space') + 1 = (495 - 105) / (5) + 1 = 78 + 1 = 79
Answer is C
Question: Rs.770 were divided among A,B,C in such a way that A had Rs.40 more than B and C had Rs 30 more than A . How much was Bâ€™s share?
A.Rs.260
B.Rs.270
C.Rs.280
D.Rs.290
Answer: D.Rs.290
Explanation: Let B gets Rs x. Then We can say A gets Rs (x + 40 ) and C gets Rs ( x + 70) .
x + 40 + x + x + 70 = 770
3x = 660
x = 220 .
Bâ€™s share = Rs ( 220 + 70 ) = Rs.290
D
Question: A student gets 60% in one subject, 70% in the other. To get an overall of 70% how much should get in third subject.
A.75%
B.80%
C.45%
D.55%
Answer: B.80%
Explanation: Let the 3rd subject % = x
60+70+x = 3*70
130+x =210
x = 210-130 = 80
Answer :B
Question: In how many ways can the letters L, I, M, I, T, S be arranged so that the two I's are not next to each other?
A.36
B.48
C.240
D.296
Answer: C.240
Explanation: 1 L
2 I
1 M
1 T
1 S
Number of ways these letters can be arranged = 6!/2! (2! to account 2 same Is) = 360
Consider 2 Is as 1 entity and thus the number of arrangements for (II)LMTS = 5! = 120
Total allowed cases = 360-120 =240
C is the correct answer.
Question: A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
A.3.46%
B.3.96%
C.3.49%
D.4.46%
Answer: A.3.46%
Explanation: Explanation:
Let the original rate be R%. Then, new rate = (2R)%.
Note: Here, original rate is for 1 year(s); the new rate is for only 4 months i.e.1/3 year(s).
(2175 + 725) R = 33.50 x 100 x 3
(2175 + 725) R = 10050
(2900)R = 10050
Original rate = 3.46%
Answer: A) 3.46%
Question: Solve the given two equations and find the inequality of X and Y. (a) x^2 = 729 and (b) Y= (729)^(1/2)
A.If x>y
B.If x>=y
C.If x<y
D.If x<=y
Answer: D.If x<=y
Explanation: Solution:-
X=+27, -27 and Y= +27
Comparing we get X<=Y
D
Question: A box contains 25 mangoes out of which 5 are spoilt. If five mangoes are chosen at random, find the probability that A number is selected at random from first fifty natural numbers. What is the chance that it is a multiple of either 7 or 9?
A.17/25
B.1/25
C.6/25
D.7/25
Answer: C.6/25
Explanation: The probability that the number is a multiple of 7 is 7/50. (Since 7*7= 49).
Similarly the probability that the number is a multiple of 9 is 5/50. {Since 9*5 =
45).
Neither 7 nor 9 has common multiple from 1 to 50. Hence these events are mutually exclusive events. Therefore chance that the selected number is a multiple of 7 or 9 is (7+5)/50 = 6/25.
ANSWER:C
Question: 7 members have to be selected from 12 men and 3 women ,Such that no two women can come together .In how many ways we can select them ?
A.12c6*3c1 + 12c7
B.12c6*3c1 + 2c7
C.1c6*3c1 + 12c7
D.11c6*3c1 + 12c7
Answer: A.12c6*3c1 + 12c7
Explanation: since no two women can come together,therfore women can be selected in 3c1 ways ...and men will be chosen in 12c6 so to complete the 7 group members...
=12c6*3c1
and only selection of men also possible = 12c7
so final ans : 12c6*3c1 + 12c7
ANSWER:A
Question: In a class, the average age of 30 boys is 13 years and the average of 20 girls is 12 years. what is the average age of the whole class?
A.12 Years
B.12.6 Years
C.13.6 Years
D.14 Years
Answer: B.12.6 Years
Explanation: Total age of 50 students
(30X 13+20 X 12) = 630
Average = 630/50 = 12.6 Years \
B
Question: In what time will a railway train 60 m long moving at the rate of 36 kmph pass a telegraph post on its way?
A.6 sec
B.9 sec
C.7 sec
D.11 sec
Answer: A.6 sec
Explanation: Explanation:
T = 60/36 * 18/5 = 6 sec
A)
Question: Lucy bought a 1-year,10000 certificate of deposit that paid interest at an annual rate of 8 percent compunded semiannually. What was the total amount of interest paid on this certificate at maturity ?
.
A.10464
B.864
C.816
D.800
Answer: D.800
Explanation: Solution:
It says, 8 percent per annum per compounded semi annually.
Therefore r = 8/2 = 4% .
So, P = 10000
r = 4
n = 2
Net Amount A = 10816, I = 800.
ANSWER:D
Question: The 8 spokes of a custom circular bicycle wheel radiate from the central axle of the wheel and are arranged such that the sectors formed by adjacent spokes all have different central angles, which constitute an arithmetic series of numbers (that is, the difference between any angle and the next largest angle is constant). If the largest sector so formed has a central angle of 40°, what fraction of the wheel’s area is represented by the smallest sector?
A.5/36
B.1/36
C.1/18
D.1/12
Answer: A.5/36
Explanation: Its an AP question .... it is given clearly in the question .
Let the smallest angle be a
and the circle has 8 sectors and hence 8 angle with a common difference d
hence all the angles can be written in AP form with Cd as d ,
a, a+d, a+2d, a+3d ,a+4d, a+5d, a+6d ,a+7d,
given that a+7d = 40 --------1
also
a + a+d + a+2d + a+3d +
a+4d + a+5d + a+6d + a+7d = 360 ( as sum of all the angle is 360)
which is 8a + 28d = 360 --------2
solving 1 and 2
we get a=50
We are almost done ,
now the question ask what fraction of the wheel’s area is represented by the smallest sector ?
(50/360)( pie r*r)/ (pie r*r) = 50/360= 5/36
A ans ....
Question: In a company of 12 employees, 5 employees earn $36,000, 4 employees earn $45,000, and the 3 highest-paid employees earn the same amount. If the average annual salary for the 12 employees is $47,500, what is the annual salary for each of the highest-paid employees?
A.$60,000
B.$65,000
C.$70,000
D.$75,000
Answer: C.$70,000
Explanation: 5*36,000+4*45,000+3x=12*47,500
3x=570,000-180,000-180,000
3x=210,000
x=70,000
The answer is C.
Question: If an article is sold at 20% profit instead of 14% profit, then the profit would be Rs. 180 more. What is the cost price?
A.Rs.1000
B.Rs. 2000
C.Rs. 3000
D.Rs. 4000
Answer: C.Rs. 3000
Explanation: Explanation:
Let the cost price of an article be Rs. x.
(20% of x) - (14% of x) = 180
20x/100 - 14x/100 = 105 => 6x = 180 * 100
=> x = 3000
Cost price = Rs. 3000
Answer:C
Question: Pipe P can fill a tank in 16 minutes and pipe Q cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe Q be closed, so that the tank is filled in 30 minutes?
A.21
B.20
C.25
D.22
Answer: A.21
Explanation: 30/16-X/24==>1
X/24=30/16-1==14/16
X=14/16*24 = 21
ANSWER A
Question: At a certain restaurant, the ratio of the number of cooks to the number of waiters is 3 to 10. When 12 more waiters are hired, the ratio of the number of cooks to the number of waiters changes to 3 to 14. How many cooks does the restaurant have?
A.4
B.6
C.9
D.12
Answer: C.9
Explanation: Originally there were 3k cooks and 10k waiters.
14k = 10k+12
k=3
There are 9 cooks.
The answer is C.
Question: A gambler bought $3,000 worth of chips at a casino in denominations of $20 and $100. That evening, the gambler lost 16 chips, and then cashed in the remainder. If the number of $20 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back?
A.$2,040
B.$2,120
C.$1,960
D.$1,920
Answer: B.$2,120
Explanation: In order to maximize the amount of money that the gambler kept, we should maximize # of $20 chips lost and minimize # of $100 chips lost, which means that # of $20 chips lost must be 2 more than # of $100 chips lost.
So, if # of $20 chips lost is x then # of $100 chips lost should be x-2. Now, given that total # of chips lost is 16: x+x-2=16 --> x=9: 9 $20 chips were lost and 9-2=7 $100 chips were lost.
Total worth of chips lost is 9*20+7*100=$880, so the gambler kept $3,000-$880=$2,120.
Answer: B.