RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In one hour, a boat goes 4 km/hr along the stream and 2 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
A.3 km/hr
B.4 km/hr
C.5 km/hr
D.6 km/hr
Answer: A.3 km/hr
Explanation: Upstream relative speed is u + v=4km/hr
Downstream speed is u-v = 2
Where u = speed of boat in still water and v is speed of stream
Then adding two equations u+v + u-v =4+2
2u=6
Finally, u=3.
ANSWER : A
Question: It is required to fix a pipe such that water flowing through it at a speed of 7 metres per minute fills a tank of capacity 220 cubic metres in 10 minutes. The inner radius of the pipe should be :
A.√2 m
B.2 m
C.1 m
D.1⁄√2 m
Answer: C.1 m
Explanation: Let inner radius of the pipe be r.
Then, 220 = 22⁄7 × r2 × 7 × 10
or r2=220/22×10=1
or r = √1=1 m
Answer C
Question: A = {2, 3, 5, 7, 15}
B = {2, 4, 6, 13}
Two integers will be randomly selected from sets A and B, one integer from set A and one from set B, and then multiplied together. How many different products can be obtained?
A.15
B.16
C.19
D.20
Answer: B.16
Explanation: Step 1: Find out the number of products you get.
5 distinct numbers in set A and 4 distinct in set B so number of products = 5*4 = 20
Step 2: Remove the products that appear more than once.
Notice that 5, 7, 11 and 13 are primes and none of their multiples are in either set. So ignore them. We just need to focus on 2 and 3 of set A and 2, 4 and 6 of set B.
2, 3
2, 4, 6
The only product repeated when you take a number from each set is 12. (3*4 and 2*6) Rest all are distinct.
Answer = 20 - 1 = 16
Note here that the second step will involve manual calculation since it will depend on the specific numbers you have in the two sets.
B
Question: I bought two books; for Rs.480. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss?
A.276
B.280
C.287
D.267
Answer: B.280
Explanation: x*(85/100)
= (480 - x)119/100
x = 280
Answer:B
Question: n what time will a railway train 60 m long moving at the rate of 36 kmph pass a telegraph post on its way?
A.2
B.7
C.8
D.6
Answer: D.6
Explanation: T = 60/36 * 18/5 = 6 sec
Answer: D
Question: If the product of the integers w, x, y and z is 840, and if 1 < w < x < y < z, what is the value of w + z?
A.10
B.11
C.16
D.18
Answer: B.11
Explanation: 840= 4* 5 * 6* 7
So w = 4, x = 5, y = 6, z = 7
w + z = 4+ 7= 11
Answer - B
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 44, the dividend is:
A.4884
B.5340
C.5342
D.5345
Answer: A.4884
Explanation: Divisor = (5 * 44) = 220
= 10 * Quotient = Divisor
=> Quotient = 220/10 = 22
Dividend = (Divisor * Quotient) + Remainder
Dividend = (220 * 22) + 44 = 4884.
A
Question: Bullock likes to keep a spare tyre in his car every time. On a certain day, he travels 1, 20,000 km and just to make the most of all the tyres, he changes the tyres between his journey such that each tyre runs the same distance.
What is the distance traveled by each tyre?
A.70,000
B.60,000
C.80,000
D.96,000
Answer: D.96,000
Explanation: The distance traveled by each tyre:
4/5 * 1, 20, 000km = 96,000 km. D
Question: If a person walks at 20 km/hr instead of 10 km/hr, he would have walked 40 km more. The actual distance traveled by him is?
A.40 km
B.76 km
C.18 km
D.16 km
Answer: A.40 km
Explanation: Let the actual distance traveled be x km. Then,
x/10 = (x + 40)/20
10x - 400 =>x = 40 km.
Answer: A
Question: If a man lost 10% by selling oranges at the rate of 10 a rupee at how many a rupee must he sell them to gain 50%?
A.6
B.8
C.7
D.4
Answer: A.6
Explanation: 90% ---- 10
150% ---- ?
90/150* 10 = 6
Answer: A
Question: Marge has 3 pumps for filling her swimming pool. When all 3 pumps work at their maximum rates, the swimming pool is filled in 56 minutes. Pump 1's maximum rate is twice the maximum rate of pump 2 and four times the maximum rate of pump 3. How long would it take Marge to fill the pool if she used only pump 2 at its maximum rate ?
A.3hrs, 16mins
B.6hrs, 32mins
C.7hrs, 12mins
D.13hrs, 4mins
Answer: A.3hrs, 16mins
Explanation: The rate of pump 1 = 4x job/minute.
The rate of pump 2 = 2x job/minute.
The rate of pump 3 = x job/minute.
Given that x+2x+4x=1/56 --> x=1/392 --> (time) = (reciprocal of rate) = 392 minutes x/2= 196 = 3 hrs 16 minutes.
Answer: A
Question: A watch which gains uniformly, is 6 min. slow at 8 o'clock in the morning Sunday and it is 6 min. 48 sec. fast at 8 p.m. on following Sunday. When was it correct?
A.20 min past 7 pm on Tuesday
B.20 min. past 7 p.m.on Wednesday
C.20 min. past 7 p.m. on Thursday
D.20 min. past 7 p.m. on Friday
Answer: B.20 min. past 7 p.m.on Wednesday
Explanation: Explanation :
Time from 8 a.m. on Sunday to 8 p.m. on following Sunday = 7 days 12 hours = 180 hours
The watch gains (5 + 29/5) min. or 54/5 min. in 180 hrs.
Now 54/5 min. are gained in 180 hrs.
5 min. are gained in (180 x 5/54 x 5) hrs = 83 hrs 20 min. = 3 days 11 hrs 20 min.
Watch is correct 3 days 11 hrs 20 min. after 8 a.m. of Sunday.
It will be correct at 20 min. past 7 p.m. on Wednesday.
Answer : B
Question: At a certain stage of a soccer tournament, the score ratio of teams A, B and C was 3:4:5. Eventually, the score ratio of A to B has doubled while the score ratio of A to C has halved. If the final score of team C was 40, what was the final score Q of team B?
A.1)8
B.2)10
C.3)20
D.4)40
Answer: A.1)8
Explanation: A to B = 3 : 4
So, on doubling we get 6 : 4
A to C = 3 : 5
So, on halving we get 1.5 : 5 or 3 : 10 or 6 : 20
So final ratio = 6 : 4 : 20.
If 20x = 40
4x = 8
Hence, answer is A
Question: What is the measure of the radius of the circle that circumscribes a triangle whose sides measure 9, 40 and 41?
A.6
B.4
C.24.5
D.20.5
Answer: D.20.5
Explanation: Explanatory Answer
9, 40 and 41 is Pythagorean triplet. So, the triangle is right angled.
Key property about right triangles
In a right angled triangle, the radius of the circle that circumscribes the triangle is half the hypotenuse.
In the given triangle, the hypotenuse = 41.
Therefore, the radius of the circle that circumscribes the triangle = 41/2 = 20.5 units.
Choice D
Question: A machine, working at a constant rate, manufactures 72 staplers in 28 minutes. How many staplers does it make in 1 hr 52 min?
A.268
B.262
C.300
D.288
Answer: D.288
Explanation: Change 1 hr 52 min to 112 min. For this, we need to set up a simple proportion of staplers per time 72/28= S/112.
The absolutely worst thing you could do at this point in the problem is to cross-multiply. That would be a supremely unstrategic move. We can cancel the common factor of 28 in the two denominators.
72/28*28 = S/112*28
72/1 = S/4
S = 4* 72
S = 288
The machine would be 288 staplers in 1 hr 52 min.
Answer:D
Question: Virat buys an old car for Rs. 50000 and spends Rs. 2000 on its repairs. If he sells the car for Rs. 62000, his gain percent is:
A.19.23%
B.11 (1/9) %
C.12.1 %
D.12%
Answer: A.19.23%
Explanation: Explanation:
C.P. = Rs. (50000 + 2000) = Rs. 52000
S.P. = Rs. 62000.
Gain% = ( (10000 / 52000) * 100 ) % = 19.23%
ANSWER A
Question: If a, r, and c are consecutive even integers and a < r < c, all of the following must be divisible by 4 EXCEPT
A.a + c
B.r + c
C.ac
D.(bc)/2
Answer: B.r + c
Explanation: I did get the correct answer within 80 seconds and it was not by luck either. I did not pick numbers but just used the concept stated by Ian.
The 3 numbers can be written as
a, (a + 2)(a + 4).
If 'a' is divisible by 4, then even 'c' or 'a + 4' is divisible by 4. However, is 'b' is divisible by 4, then both 'a' and 'a + 4' are still divisible by 2.
A - (a + c) = a + (a + 4) = 2a + 4 = 2(a + 2) = 2b. 2b will always be divisible by 4 even if 'b' is not divisible by 4. Reason: 'b' already has a prime factorization of at least a '2'. Hence '2b' has two 2s.
C - ac = a(a+4). If, as stated above, one of them is divisible by 4, then the product is divisible. If both of them are not divisible by 4, then the product is still divisible by 4 because of the presence of two 2s again in the prime factorization.
D - bc/2 = (a + 2)(a + 4)/2. Either b or c is divisible by 2. Hence, if we assume that b is divisible by 2 and not divisible by 4, then it leaves us just one possibility. Is c divisible by 4? It has to be because c is the next consecutive even integer.
E - abc/4 = a(a + 2)(a + 4)/4. One of these integers is divisible by 4 already. If we again assume 'b' to be that integer divisible by 4, then we are left with the question - Is a(a + 4) divisible by 4? This is the same as option C.
B - r + c = (a + 2) + (a + 4) = 2a + 6 = 2(a + 3). (a + 3) will never be divisible by 2 because it is an odd integer. Hence, 2(a + 3), although divisible by 2, will not be divisible by 4 because it has just one 2 in its prime factorization.
As a whole, whether you choose numbers (2, 46 being the easiest) or solve conceptually, the answer is still easily obtainable within 2 minutes.B
Question: An investor bought 200 shares of stock in ABCD company in 1990. By 1992, the investment was worth only 2/3 of its original value. By 1995, the 200 shares were worth only 2/5 of their value in 1990. By what percent did the value of the investment drop from 1992 to 1995?
A.16 2/3%
B.25%
C.40%
D.50%
Answer: C.40%
Explanation: Let price of each share in 1990 = X.
Total cost in 1990 = 200X
Now Price in 1992 = 2/3 * 200X = 400/3 * X
Now price in 1995 = 2/5 *200X= 80X
%Change in 1995 from 1992 = [(400/3* X -80X) / (400/3 *X) ] *100 = 40%
Answer C
Question: In a group of 6 boys&4 girls a Committee of 4 persons is to be formed. In how many different ways can it be done so that the committee has at least 1girl?
A.110
B.130
C.145
D.195
Answer: D.195
Explanation: The committee of 4 persons is to be so formed that it has at least 1 woman The different ways that we can choose to form such a committee are:
(i) lw. 3 m in t 6X5X4' x 6C3 = 4x — — 80 3X2X1
x 6c2 =42:: x 26:: = 90 (ii) 2w. 2 m in °C2 (iii) 3w. 1 m in 4C3 x 6C1 = 4 x 6 = 24 (iv) 4w in 6C4 = 1 Total no. of different ways in which a committee of 4 persons can be formed so that it has at least one woman. = 80 + 90 + 24 + 1 = 195
D
Question: What are the number of ways to select 3 men and 2 women such that one man and one woman are always selected?
A.26 ways
B.19 ways
C.30 ways
D.76 ways
Answer: C.30 ways
Explanation: The number of ways to select three men and two women such that one man and one woman are always selected = Number of ways selecting two men and one woman from men and five women
= ⁴C₂ * ⁵C₁ = (4 * 3)/(2 * 1) * 5
= 30 ways.
Answer: C
Question: A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:
A.49 m2
B.50 m2
C.53.5 m2
D.55 m2
Answer: A.49 m2
Explanation: Area of the wet surface	= [2(lb + bh + lh) - lb]
= 2(bh + lh) + lb
= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2
= 49 m2. Answer: Option A
Question: HCF of two numbers is 11 and the product of these numbers is 363, what is the the greater number?
A.28
B.31
C.33
D.35
Answer: C.33
Explanation: The numbers be 11a and 11b
11a × 11b = 363
ab = 3
co-primes with product 3 are (1, 3)
Hence the numbers with HCF 11 and product 363
= (11 × 1, 11 × 3)
= (11, 33)
Numbers are 11 and 33
The greater number = 33
Question: Sony and Johnny caught 25 fishes. Sony caught four times as many as Johnny. How many fishes did Johnny catch?
A.5
B.16
C.34
D.38
Answer: A.5
Explanation: s+j=25
s=4*j
j=5
ANSWER:A
Question: if a@b = a * b^(1/2) then 2@16 = ?
self made
A.2
B.6
C.3
D.8
Answer: D.8
Explanation: 2* (16)^1/2= 2*4= 8
D is the answer
Question: If integers ending in zero are excluded, what is the unit digit of the product of the even integers from 802 to 898, inclusive?
A.14
B.12
C.10
D.6
Answer: D.6
Explanation: 802 x 804 x 806 x 808 => unit digit 4
812 x 814 x 816 x 818 => unit digit 4
892 x 894 x 896 x 898 => unit digit 4
So we have 10 numbers ending by 4 to multiply.
Given that 4 x 4 = 16, we have 5 numbers ending by 6 to multiply
Given that 6 x 6 = 36, we have 3 numbers ending by 6 to multiply
So the unit digit is 6
Answer : D
Question: Three 6 faced dice are thrown together. The probability that no two dice show the same number on them is ?
A.5/8
B.5/9
C.5/2
D.5/1
Answer: B.5/9
Explanation: No two dice show same number would mean all the three faces should show different numbers. The first can fall in any one of the six ways. The second die can show a different number in five ways. The third should show a number that is different from the first and second. This can happen in four ways.
Thus 6 * 5 * 4 = 120 favourable cases.
The total cases are 6 * 6 * 6 = 216.
The probability = 120/216 = 5/9.
Answer: B
Question: It is given that 2^32 + 1 is exactly divisible by a certain number. Which one of the following is also divisible by the same number W?
A.a. 2^96 + 1
B.b. 2^16 - 1
C.c. 2^16 + 1
D.d. 7 * 2^33
Answer: A.a. 2^96 + 1
Explanation: a³ + b³ =(a+b)(a² -ab +b²)
Now, let (2^32 + 1) be (a+b)
a³ + b³ = (2^96 + 1)
Now, as mentioned in formula above,
a³ + b³ is always divisible by (a+b)
So any factor of W (a+b) is a factor of (a³ + b³)
Henca A
Question: There are 20 students with an average height of 105 cms in a class. Then 10 students with an average height of 120 cms join the class. What will be the average height of the class now?
A.110 cms
B.120 cms
C.100 cms
D.115 cms
Answer: A.110 cms
Explanation: 20 students average height is 105cms
sum of heights/ 20 =105cms
sum of heights of 20 students= 105*20= 2100
10 students of average height 120 added
so their, sum of 10 students height / 10 = 120
sum of heights of 10 students = 1200cms
By adding heights of 20 and 10 students , 1200+2100 = 3300
average of 30 students = 3300/30 = 110 cms
ANSWER:A
Question: In how many ways 7 boys and 7 girls can be seated in a row so that boys and girls are alternate?
A.50803200
B.50328000
C.50003280
D.50703200
Answer: A.50803200
Explanation: number of ways = 2*7!*7! = 50803200
Answer is A
Question: √{(1.5)(10^9)} is closest to which of the following?
A.5,000
B.20,000
C.40,000
D.100,000
Answer: C.40,000
Explanation: √{(1.5)(10^9)} = √{(15)(10^8)} = √(15)√(10^8) = (√15) * 10,000 which is almost 40,000.
The answer is C.
Question: The football association pays $2000 out of $8000 it owes to refrees. Then it pays $6000 out of the $12000 owes for the year to players.
How much did the ratio of payments made to monies owed increase?
A.A) 75%
B.B)100 %
C.C)1%
D.D) 50%
Answer: B.B)100 %
Explanation: Ratio in 1st case 2000:8000(1/4)
Ratio in second case 6000/12000 (2/4)
percentage increase is (difference/initial quantity)*100
(1/4)/(2/4 )* 100= 100%
Correct option is B
Question: 8 boys complete a work in 14 days . In how many days will 14 boys complete that work?
A.14 days
B.7 days
C.8 days
D.6 days
Answer: C.8 days
Explanation: Explanation:
1 boy 1 day work = 14 × 8,
14 boys complete the work in 14 × 8/14= 8 days
Answer: Option C
Question: The side of a square is increased by 20% then how much % does its area increases?
A.44.00 %
B.45.25 %
C.48.75 %
D.50.00 %
Answer: A.44.00 %
Explanation: a = 100 a2 = 10000
a = 120 a2 = 14400
----------------
10000 --------- 4400
100 -------? => 44.00 %
Answer:A
Question: A room of 5m 44cm long and 3m 74cm broad is to be paved with squre tiles. Find the least number of squre tiles required to cover the floor.
A.233
B.877
C.279
D.176
Answer: D.176
Explanation: Explanation:
area of the room = 544 * 374 sq cm
size of largest square tile = H.C.F of 544cm and 374cm= 34cm
area of 1 tile = 34*34 sq cm
no. of tiles required = (544*374) / (34 * 34) = 176
Answer: D) 176
Question: If the price of a commodity is decreased by 20% and its consumption is increased by 20%, what will be the increase or decrease in expenditure on the commodity?
A.4% increase
B.4% decrease
C.8% increase
D.8% decrease
Answer: B.4% decrease
Explanation: Solution: Let the initial expenditure on the commodity be Rs. 100.
Now, the price decreases by 20%,
Current Price = (100 - 20% of 100) = Rs. 80.
Same time due to decrement in price 20% consumption has been increased. So,
Current expenses on commodity = (80 + 20% of 80)= Rs. 96.
Here, the initial expenditure was Rs. 100 which became 96 at the end, it means there is 4% decrement in the expenditure of the commodity.
Mind Calculation Method:
100===20%↓(Decrement in Price)===>80===20%↑(Increment in Consumption)===>96.
Thus, there is a decrement of 4%.
Answer: Option B
Question: What is the present worth of Rs. 122 due in 2 years at 5% simple interest per annum?
A.Rs.154.32
B.Rs.121.42
C.Rs. 112
D.Rs.110.99
Answer: D.Rs.110.99
Explanation: Let the present worth be Rs. x. Then,
S.I. = (122 - x)
(x * 5 * 2) / 100 = (122 - x)
10x = 12200 - 100x
110x = 12200 => x = 110.99
ANSWER:D
Question: For any positive integer p, the sum of the first p positive integers equals p(p+1)/2 . If q and p are positive integers and q > p, what is the sum of all the integers between q and p, inclusive?
A. q(q+1)/2 + p(p+1)/2
B. q(q+1)/2 - p(p-1)/2
C. q(q+1)/2 - p(p+1)/2
D. q(q+1)/2 + p(p-1)/2
Answer: B. q(q+1)/2 - p(p-1)/2
Explanation: The sum of all the integers between q and p,inclusiveis the sum of the first q positive integersminusthe sum of the first p-1 positive integers.
The sum of the first q positive integers is q(q+1)/2;
The sum of the first p-1 positive integers is (p-1)p/2;
Therefore the answer is q(q+1)/2 - (p-1)p/2.
Answer: B.
Question: The average age of applicants for a new job is 31, with a standard deviation of 5. The hiring manager is only willing to accept applications whose age is within one standard deviation of the average age. What is the maximum number of different ages of the applicants?
A.11
B.14
C.15
D.18
Answer: A.11
Explanation: within one standard deviation of the average age means 31 +/- 7
26--31--36
number of dif.ages -26 27 28 29 30 31 32 33 34 35 36
total=11
A
Question: In how many different E ways can 4 ladies and 4 gentlemen be seated at a round table so that all ladies sit together?
A.70
B.288
C.576
D.10,080
Answer: C.576
Explanation: Treat the 4 ladies as one object, now you have 5 objects to arrange around a table (m1,m2,m3,m4,women). This can be done in (5-1)! ways
And there are 4! ways to arrange ladies among themselves
Answer E= (4!)^2 = 576 or C
Question: 0.999991+0.111119=?
A.1
B.1.0001
C.1.0021
D.1.11111
Answer: D.1.11111
Explanation: 0.999991 + 0.111119
= 0.999991 + 0.11111 + 0.00009
= (0.999991 + 0.00009) + 0.11111
= 1 + 0.11111
= 1.11111
D
Question: Which of the following inequalities is equivalent to –2 < y< 4 ?
A. | y– 2 | < 4
B. | y– 1 | < 3
C. | y+ 1 | < 3
D. | y+ 2 | < 4
Answer: B. | y– 1 | < 3
Explanation: First remove the mod
then set the expression to 0
then get a value of y
then add and subtract the value from the given number on the RHS
Lets try with an example (B) --------------> | y– 1 | < 3
First remove the mod -------------------> y-1
then set the expression to 0--------------> y-1=0
then get a value of y---------------------> y=1
then add and subtract the value from the given number on the RHS 1+3=4 and 1-3= -2
the range become -2 to 4 correct answer
Now try its with an incorrect option (C) | ----------> |y+ 1 | < 3
First remove the mod --------------------------> y+1
then set the expression to 0----------------------> y+1=0
then get a value of y------------------------------> y=-1
then add and subtract the value from the given number on the RHS -1+3=2 and -1-3= -4
the range become -4 to 2 Incorrect
THE CORRECT ANSWER IS B
Question: If Suresh distributes his pens in the ratio of 1/2 : 1/4 : 1/5 : 1/7 between his four friends A, B, C and D, then find the total number of pens Suresh should have?
A.153
B.150
C.100
D.125
Answer: A.153
Explanation: EXPLANATION:
Here, A : B : C : D = 1 / 2 : 1 / 4 : 1 / 5 : 1 / 7
1) L.C.M of 2, 4, 5, 7 is 140
2) Find the number of pens each friend received --------- (To find no. of pens each friend has, multiply the ratio with the L.C.M. calculated)
A = (1/2) x 140 = 70
B = (1/4) x 140 = 35
C = (1/5) x 140 = 28
D = (1/7) x 140 = 20
3) Total number of pens = (70 x + 35 x + 28 x + 20 x) = 153 x
Minimum number of pens (x) = 1
Therefore, total number of pens = 153 pens.
ANSWER IS A
Question: A tin of oil was 4/5 full. When 6 bottles of oil were taken out and four bottles of oil were poured into it, it was 3/4 full. how many bottles of oil can the tin contain?
A.10
B.40
C.46
D.36
Answer: B.40
Explanation: Suppose X bottles can fill the tin completely
Then Present oil = 4/5 X
after 6 bottles taken out it is 4/5 X - 6
after four bottles poured in it is 4/5 X - 6 + 4
now the oil level is 3/4X
so 4/5 X - 6+4 = 3/4X ===> 4/5 X - 3/4 X = 6-4
X/20=2
X=40
Therefore required no of bottles = 40
so 40 bottles of oil can fill the tin.
the answer is option B) 40.
Question: The total number of problems in the mathematics and algebra books is 28 more than the total number of problems in the algebra and geometry books. How much lesser is the number of problems in the geometry book as compared to the mathematics book?
A.30
B.18
C.28
D.25
Answer: C.28
Explanation: (Mathematics + Algebra) - (Algebra + Geometry) = 28
Mathematics - Geometry = 28
Answer: C
Question: With both inlets open, a water tank will be filled with water in 20 minutes. The first inlet alone would fill the tank in 2 hours. If in every minutes the second inlet admits 50 cubic meters of water than the first, what is the capacity of the tank ?
A.9,000
B.1,500
C.1,750
D.1,200
Answer: B.1,500
Explanation: The work Done by Inlet A and B together in 1 min = 1/20
The work Done by Inlet A (First Inlet) in 1 min = 1/120
The work Done by Inlet B (Second Inlet) in 1 min = (1/20)- (1/120) =1/24
DIfference of Work done by B and A = B - A = 50 Cubic meter
i.e. (1/24)- (1/120) = 50 Cubic meter
i.e. 1500 Cubic Meter
Answer: option B
Question: Amar takes as much time in running 18 meters as a car takes in covering 48 meters. What will be the distance covered by Amar during the time the car covers 1.3 km?
A.600 m
B.325 m
C.300 m
D.400 m
Answer: B.325 m
Explanation: B
325 m
Distance covered by Amar = 18/4.8 (1.3km) = 3/8(1300) = 325 m
Answer is B
Question: Two taps A and B can fill a tank in 5 hours and 20 hours respectively. If both the taps are open then due to a leakage, it took 30 minutes more to fill the tank. If the tank is full, how long will it take for the leakage alone to empty the tank ?
A.8 hrs
B.9 hrs
C.18 hrs
D.36 hrs
Answer: D.36 hrs
Explanation: 2 taps can fill in 4 hrs
With leak it will take 4 1/2 hrs
now leak can empty in 1/4-1/(4 (1/2))
1/4-8/9=1/36. so it an empty tank in 36 hrs
ANSWER:D
Question: A merchandise feedback online portal accords ‘ratings’ to a product by recording the percentage of customers who have reported their views as either ‘satisfied’ or ‘unsatisfied’ only. The portal rounds off the exact percentage value calculated to the closest integral value. If the percentage of unsatisfied customers as recorded by the portal is 57%, what is the LEAST possible number of people that could have reported their views as ‘satisfied’ ?
A.2
B.3
C.12
D.43
Answer: B.3
Explanation: 57% unsatisfied . So ~43% satisfied
But 100% should be an integer only and since the above percentages are approximations 100% should be as close as possible to an integer.
Now substitute value
[1] If 43% is 2 what is 100% -> 200/43 is not giving a number which is closest to an integer.
[2] If 43% is 3 what is 100% -> 300/43 [43*7=301] ...therefore closest possible to an integer. [It also satisfies the least possible and hence we need not check for other choices which are greater than 3]
Therefore Ans is B.
Question: There are 780 male and female participants in a meeting. Half the female participants and one-quarter of the male participants are Democrats. One-third of all the participants are Democrats. How many of the Democrats are female?
A.75
B.100
C.125
D.130
Answer: D.130
Explanation: female = x
Male = 780-x
x/2 + 780-x/4 = 1/3* (780)= 260
x= 260
x/2 = 130 is supposed to be the answer
M is missing something
Correct Option D
Question: Find the odd man out. 742, 743, 633, 581, 871, 990, 532
A.532
B.990
C.581
D.743
Answer: C.581
Explanation: Explanation :
In all numbers except 581, the difference of third and first digit is the middle digit. Answer : Option C