RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Tap 'A' can fill the tank completely in 6 hrs while tap 'B' can empty it by 12 hrs. By mistake, the person forgot to close the tap 'B', As a result, both the taps, remained open. After 3 hrs, the person realized the mistake and immediately closed the tap 'B'. In how much time now onwards, would the tank be full?
A.2.5 hours
B.4.5 hours
C.5.5 hours
D.1.5 hour
Answer: B.4.5 hours
Explanation: Explanation :
Tap A can fill the tank completely in 6 hours
=> In 1 hour, Tap A can fill 1⁄6 of the tank
Tap B can empty the tank completely in 12 hours
=> In 1 hour, Tap B can empty 1⁄12 of the tank
i.e., In one hour, Tank A and B together can effectively fill 1⁄6 - 1⁄12 = 1⁄12 of the tank
=> In 3 hours, Tank A and B can effectively fill 1⁄12 × 3 = 1⁄4 of the tank.
Time taken to fill the remaining 1−(1/4) = 3/4 of the tank = (3/4)/(1/6) = 4.5 hours. Answer : Option B
Question: The probability that B can shoot a target 3 out of 3 times is 0.25. What is the probability that the target will be missed by B immediately after such two shots?
A.0.25
B.0.5
C.0.4
D.0.75
Answer: D.0.75
Explanation: Suppose there are total 'x' shots.
B shoots 3 out of 3 times. means out of x shots (x>3)
therefore, 3/x = 0.25 (given)
the target will be missed by B immediately after such two shots : this means he can shot just twice ...the third shot cannot happen which means he missed (x-3) shots.
thus, the probabilty of missing just after 2 shots is (x-3)/x.
(x-3)/x = 1 - 3/x
= 1 - 0.25
= 0.75
Answer : D
Question: Of two numbers, 4 times the smaller one is less then 3 times the 1arger one by 5. If the sum of the numbers is larger than 6 times their difference by 6, find the two numbers.
A.59 and 43
B.55 and 44
C.58 and 43
D.59 and 42
Answer: A.59 and 43
Explanation: Let the numbers be x and y, such that x > y
Then, 3x - 4y = 5 ...(i) and (x + y) - 6 (x - y) = 6 => -5x + 7y = 6 …(ii)
Solving (i) and (ii), we get: x = 59 and y = 43.
Hence, the required numbers are 59 and 43.
Answer is A.
Question: If the height of a cone is increased by 140% then its volume is increased by?
A.100
B.140
C.998
D.729
Answer: B.140
Explanation: 140%
Answer:B
Question: How many times do the hands of a clock coincide in a day?
A.20
B.21
C.22
D.23
Answer: C.22
Explanation: The hands of a clock coincide 11 times in every 12 hours (Since between 11 and 1, they coincide only once, i.e., at 12 o'clock).
AM
12:00
1:05
2:11
3:16
4:22
5:27
6:33
7:38
8:44
9:49
10:55
PM
12:00
1:05
2:11
3:16
4:22
5:27
6:33
7:38
8:44
9:49
10:55
The hands overlap about every 65 minutes, not every 60 minutes.
The hands coincide 22 times in a day.
Answer: Option C
Question: The distance between Delhi and Mathura is 125 kms. A starts from Delhi with a speed of 25 kmph at 9 a.m. for Mathura and B starts from Mathura with a speed of 35 kmph at 10 a.m. from Delhi. When will they meet?
A.11 1/2
B.77 2/3
C.16 3/4
D.10
Answer: A.11 1/2
Explanation: D = 125 – 25 = 100
RS = 35 + 25 = 60
T = 100/60 = 1.6 hours
10 a.m. + 1.6 = 11 1/2a.m..Answer: A
Question: A recipe requires 2 1/2 (mixed number) cups of flour 2 3/4 (mixed number) cups of sugar and 1 1/3 (mixed number) cups of milk to make one cake. Victor has 15 cups if flour, 16 cups of sugar and 8 cups of milk. What is the greatest number of cakes john can make using this recipe?
A.5
B.6
C.7
D.8
Answer: A.5
Explanation: Less work up front: Go through each item and see what the greatest number of cakes you can make with each. The lowest of these will be the right answer.
Flour: 15 cups, we need 2.5 cups each. Just keep going up the line to see how many cakes we can make: That means I can make 2 cakes with 5 cups, so 6 cakes overall with 15 cups. I've already got the answer narrowed to either A or B.
Sugar: 16 cups, we need 2.75 cups each. Same principle. I can make 2 cups with 5.5 cups, so to make 6 cakes I'd need 16.5 cups. I don't have that much sugar, so we're limited to 5 cakes. No need to even do milk because we're already at 5. Sugar will be the limiting factor.
answer is A
Question: Find the 10th term of an arithmetic progression whose first term is 8 and the common difference is 2.
A.45
B.26
C.44
D.40
Answer: B.26
Explanation: n th term of A.P = a +(n-1) *d
= 8+(10-1)*2 , = 8 + 18 = 26.
ANSWER:B
Question: Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 2 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is?
A.13:9
B.12:2
C.19:3
D.19:5
Answer: D.19:5
Explanation: Quantity of alcohol in vessel P = 62.5/100 * 2 = 5/4 litres
Quantity of alcohol in vessel Q = 87.5/100 * 4 = 7/2 litres
Quantity of alcohol in the mixture formed = 5/4 + 7/2 = 19/4 = 4.75 litres
As 6 litres of mixture is formed, ratio of alcohol and water in the mixture formed = 4.75 : 1.25 = 19 : 5.
Answer:D
Question: A container holds 4 quarts of alcohol and 4 quarts of water. How many quarts of water must be added to the container to create a mixture that is 3 parts alcohol to 5 parts water by volume?
A.4/3
B.5/3
C.7/3
D.8/3
Answer: D.8/3
Explanation: Let the number of quarts that should be added to get the required ratio = x
So total quarts of water = (x + 4)
But the original number of quarts of alcohol remains the same, so we have :
4/(x+4) = 3/5
Cross-multiply:
Now we have 20 = 3x + 12
=> 3x = 20 -12
=> x = 8/3
Answer - D
Question: Nona is one-third as old as her mother. Five years ago, she was only one-fifth of the age of her mother. How old is Nona now?
A.11.5
B.12.5
C.13.5
D.14.5
Answer: B.12.5
Explanation: mother age be x
nona age bcomes 1/3(x)
1/3(x)-5=1/5(x)
by solving we get,
x=37.5
and nona is 12.5
ANSWER:B
Question: A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
A.20
B.21
C.22
D.23
Answer: A.20
Explanation: Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
Answer:A
Question: If Dale works at full efficiency he needs a break of 1 day after every 2 days of work and he completes a job in a total of 20 days. If he works at reduced efficiency, he can work without break and finish that same job in 20 days. Dale's output at reduced efficiency is what fraction of his output at full efficiency?
A.7/3
B.5/2
C.6/5
D.1/5
Answer: A.7/3
Explanation: We're told that there are 2 ways for Dale to complete a job:
1) Full Efficiency: 2 days of work followed by 1 dayofffor a total of 20 days.
2) Reduced Efficiency: 20 straight days with no days off.
Working at Full Efficiency creates the following pattern:
2 days on, 1 day OFF, 2 days on, 1 day OFF, 2 days on, 1 day OFF, 2 days on = 2+1+2+1+2+1+2+1+2+1+2+1+2= 20 days
Totals: 14 days on, 6 days off
Reduced Efficiency means that Dale will do 14 days of work in 20 days, thus those Reduceddaysare 14/6=7/3 of Full Efficiency.
Answer : A
Question: The length of a train and that of a platform are equal. If with a speed of 126 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
A.757
B.758
C.1050
D.750
Answer: C.1050
Explanation: Speed = [126 * 5/18] m/sec = 35 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 35 è x = 35 * 60 / 2
=1050
Answer:C
Question: At a certain conference, 32% of the attendees registered at least two weeks in advance and paid their conference fee in full. If 50% of the attendees who paid their conference fee in full did not register at least two weeks in advance, what percent of conference attendees registered at least two weeks in advance?
A. 18.0%
B. 62.0%
C. 79.2%
D. 64.0%
Answer: D. 64.0%
Explanation: Refer to the table in the attachment:
Let x= No. of members who have paid in Full
50 % members paid in full and did not register in advance = 0.5x
32 % registerd in advance and paid in full.
So if total No. of members = 100, then 32 members paid Full and registered in advance.
Hence total members who paid full amount = 0.5x + 32 =x
0.5x =32
Hence x = 64
i.e. 64 out of 100 or 64 %
Ans. D
Question: In a bag there are coins of 50 paisa, 25 paisa and one rupee in the proportion 5:6:2. If there are in all Rs.32, the number of 25 paisa coins is?
A.30
B.31
C.32
D.34
Answer: C.32
Explanation: 5x 6x 2x
50 25 100
250x + 150x + 200x = 3200
600x = 3200
x = 5.33 => 6x = 32
ANSWER:C
Question: In the xy-plane, a line has slope 4 and x-intercept 3. What is the y-intercept of the line?
A.-12
B.-3
C.0
D.3
Answer: A.-12
Explanation: Let the line be represented by a general equation y=mx+b, where m = slope (4) and b=y intercept. We are also given the value of x-intercept 3.
Theory : y intercept represents the point on the line where the x=0, and x intercept represents the point on the line where the y=0.
Putting these values in the equation : 0 = 4*3 + b => b = -12. Hence A.
Question: The average (arithmetic mean) of six numbers is 8. If 3 is subtracted from each of four of the numbers, what is the new average?
A.6
B.2
C.3
D.4
Answer: A.6
Explanation: Sum of 6 numbers = 6*8 =48
If 3 is subtracted from each of four of the numbers , we subtract 3*4=12 from the total sum
Sum of 6 number after subtracting 3 from each of four of the numbers = 48 - 12 = 36
New average = 36/6 = 6
Answer A
Question: The average of first five multiples of 5 is?
A.6
B.8
C.9
D.15
Answer: D.15
Explanation: Average = 5(1 + 2 + 3 + 4 + 5)/5
= 75/5
= 15.
Answer:D
Question: Two numbers are in the ratio of 5:7. If 20 is subtracted from each number, they are in the ratio of 5:9. What are the two numbers?
A.35, 49
B.40, 56
C.45, 63
D.50, 70
Answer: B.40, 56
Explanation: (5x-20):(7x-20) = 5y:9y
5x - 20 = 5y
7x - 20 = 9y
140-100 = 45y - 35y
40 = 10y
y = 4
5x-20 = 20
x = 8
The two numbers are 5x and 7x which are 40 and 56.
The answer is B.
Question: For positive integers q and r, which of the following can be written as r^2?
A.q^2-12
B.q^2-11
C.q^2-10
D.q^2-9
Answer: D.q^2-9
Explanation: Plug values: if q=5, then 5^2-9=4
The question asks which of the following CAN be written as r^2. If q=16, then q^2-9 CAN be written as 2^2.
Answer: D
Question: What is the area of a square field whose diagonal of length 20 m?
A.238
B.379
C.200
D.328
Answer: C.200
Explanation: d2/2 = (20 * 20)/2
= 200
Answer:C
Question: sue has 3 apples. Billy has 12 apples. If billy steals all of sues apples and eats 4 how many does he have left?
A.11
B.10
C.7
D.9
Answer: A.11
Explanation: 11 A
Question: Calculate how many days it will take for 7 boys to wash a 35 m long wall if 5 boys can wash a 25 m long wall in 4 days,
A.6 days
B.3 days
C.4 days
D.2 days
Answer: C.4 days
Explanation: The length of wall painted by one boy in one day = 25 / 5 * 1/4 = 1.25 m
No. of days required to paint 50 m cloth by 8 boys = 35/ 7 *1/ 1.25 = 4 days.
C
Question: What are the last two digits of (301*402*503*604*646*547*448*349)^2
A.96
B.76
C.56
D.36
Answer: B.76
Explanation: ((301*402*503*604*646)*(547*448*349))^2
If you observe above digits, last digit are: 1,2,3,4,6,7,8,9; 5 is missing; so I have rearranged them so that multiplication will be easy for me as initial 4 digits have last two digits as 01,02,03,04,46 and final three as 47*48*49.
Solving for only last two digits and multiplying them we get:( (06*04*46)(56*49))^2 = (44*44)^2=36^2=76
Hence answer is B
Question: If the simple interest on a sum of money at twelve percent per annum for two years is Rs.3800, compound interest on the same sum for the same period at the same rate of interest is
A.Rs.4028
B.Rs.4100
C.Rs.4128
D.Rs.4228
Answer: A.Rs.4028
Explanation: S I for 2 years = 3800 ie for one year =1900
The compound interest for Rs.1900 for the second year = 1900*12/100 =228
The CI for two years 3800+228 = 4028
ANSWER:A
Question: A reduction of 20% in the price of salt enables a lady to obtain 10kgs more for Rs.600, find the original price per kg?
A.s.11
B.s.14
C.s.15
D.s.21
Answer: C.s.15
Explanation: 100*(20/100) = 20 --- 10
? --- 1 => Rs.2
600 --- 80
? --- 2 => Rs.15
Answer:C
Question: In how many years Rs 200 will produce the same interest at 10% as Rs. 400 produce in 5 years at 12%
A.16
B.13
C.12
D.14
Answer: C.12
Explanation: Explanation:
Clue:
Firstly we need to calculate the SI with prinical 400,Time 5 years and Rate 12%, it will be Rs. 240
Then we can get the Time as
Time = (100*240)/(200*10) = 12
Option C
Question: What is the remainder when 10^49 + 2 is divided by 11?
A.1
B.2
C.3
D.5
Answer: A.1
Explanation: With exponent-based problems and huge numbers, it's often helpful to try to establish a pattern using small numbers. On this problem, while 1049+2 is a massive number that you'd never want to try to perform calculations with, you can start by using smaller numbers to get a feel for what it would look like:
10^2+2=102, which when divided by 11 produces a remainder of 3 (as 9 * 11 = 99, leaving 3 left over)
10^3+2=1002, which when divided by 11 produces a remainder of 1 (as 9 * 110 = 990, and when you add one more 11 to that you get to 1001, leaving one left)
10^4+2=10002, which when divided by 11 produces a remainder of 3 (as you can get to 9999 as a multiple of 11, which would leave 3 left over)
10^5+2=100002, which when divided by 11 produces a remainder of 1 (as you can get to 99990 and then add 11 more, bringing you to 100001 leaving one left over).
By this point, you should see that the pattern will repeat, meaning that when 10 has an even exponent the remainder is 3 and when it has an odd exponent the remainder is 1. Therefore, since 10 has an odd exponent in the problem, the remainder will be 1.
answer is A
Question: Ram sold two bicycles, each for Rs.990. If he made 10% profit on the first and 10% loss on the second, what is the total cost of both bicycles?
A.2000
B.2388
C.2798
D.2666
Answer: A.2000
Explanation: (10*10)/100 = 1%loss
100 --- 99
? --- 1980 => Rs.2000
Answer:A
Question: Which of the following is closest to (-5/6)^199？
A.-1
B.-1/2
C.0
D.1
Answer: C.0
Explanation: (-5/6)^4 = 625/1296 which is already less than 1/2.
For larger exponents, the expression will get closer and closer to zero.
The answer is C.
Question: In a group of 4 boys and 6 girls, four children are to be selected. In how many different ways can they be selected such that at least one girl is included?
A.185
B.197
C.209
D.221
Answer: C.209
Explanation: The total number of ways to choose 4 children is 10C4 = 210
The number of ways to choose only boys is 4C4 = 1
The number of groups which include at least one girl is 209.
The answer is C.
Question: A can finish a piece of work in 5 days. B can do it in 10 days. They work together for two days and then A goes away. In how many days will B finish the work?
A.4
B.5
C.6
D.76
Answer: A.4
Explanation: 2/5 + (2 + x)/10 = 1 => x = 4 days
\Answer: A
Question: A person travels equal distances with speeds of 3 km/hr, 4 km/hr and 5 km/hr and takes a total time of 45 minutes. The total distance is?
A.1 km
B.2.87 km
C.3 km
D.4 km
Answer: B.2.87 km
Explanation: B
3 km
Let the total distance be 3x km.
Then, x/3 + x/4 + x/5 = 45/60
47x/60 = 45/60 => x = 0.95.
Total distance = 3 * 0.95 = 2.87 km.
Question: If the range of the set of numbers {150, 90, 125, 110, 170, 155, x, 100, 140} is 90, which of the following could be x?
A.80
B.95
C.110
D.125
Answer: A.80
Explanation: The range of the other 8 numbers is 170-90 = 80, so x must be either the smallest number or the largest number in the set.
Then x = 170-90 = 80 or x = 90+90 = 180
The answer is A.
Question: If 1535/1038 = a+1/[b+1/{c+(d+ 1/e)}]. Find a*b*c*d*e?
A.165/2
B.175/2
C.178/3
D.187 by 2
Answer: D.187 by 2
Explanation: by expanding 1535/1038 make form like a+1/[b+1/{c+(d+1/e)}
=1+(497/1038) now a=1
=1+{1/(1038/497)}
=1+{1/(2+42/497)}
=1+{1/(2+1/(497/42)} now b= 2 similarly expand
c=11 d= 1 e=34/8
finally a*b*b*c*d*e
1*2*11*1*34/8
187/2
ANSWER:D
Question: In order to complete a reading assignment on time, Terry planned to read 80 pages per day. However, she read only 40 pages per day at first, leaving 1000 pages to be read during the last 6 days before the assignment was to be completed. How many days in all did Terry have to complete the assignment on time?
A.18
B.19
C.17
D.16
Answer: B.19
Explanation: D=80*X - according to the plan, assignment to be completed on time reading 80 pages per day for next X days. But, Terry's plans changed so she read as follow:
40 pages for first Y days and 1000 pages for last 6 days, we get these equations:
40*Y+1000=80*X
X-Y=6 --------->>X planned number of days, Y - actually used reading 40 pages per day and 6 leftover days used to complete a lump 1000 pages
From above we find that X=Y+6 and 40Y+1000=80Y+480 or 40Y=520 --->>>>> Y=13, hence X=19
Answer : B
Question: What is the sum of the prime factors of 121 and the prime factors of 7434
A.27
B.67
C.57
D.37
Answer: D.37
Explanation: The prime factors of 7434are 3*3*2*7
The prime factors of 121 are 11*11
3+3+2+7+11+11 = 37. D is the correct answer
Question: 15% people of a village in Sri Lanka died by bombardment, 25% of the remainder left the village on account of fear. If now the population is reduced to 4555, how much was it in the beginning?
A.7400
B.7145
C.7200
D.7323
Answer: B.7145
Explanation: X * (85/100) * (75/100) = 4555
X = 7145
Answer: B
Question: A goods train runs at a speed of 72 kmph and crosses a 250 m long platform in 26 seconds.What is the length of the goods train?
A.230 m
B.240 m
C.260 m
D.270 m
Answer: D.270 m
Explanation: s=250+x/t
72*5/18=250+x/26
x=270
ANSWER:D
Question: Find the odd man out
1,5,14,30,50,55,91.
A.5
B.50
C.55
D.91
Answer: B.50
Explanation: 50 is the odd man.. diff between sucessive no.s is a perfect square
ANSWER:B
Question: The edge of three cubes of metal is 3 dm, 4 dm and 5 dm. They are melted and formed into a single cube. Find the edge of the new cube?
A.6
B.8
C.10
D.12
Answer: A.6
Explanation: Explanation:
33 + 43 + 53 = a3 => a = 6
A)
Question: A sum of money invested at C.I. amounts to Rs. 800 in 3 years to Rs. 870 in 4 years. The rate of interest per annum is?
A.2 1/2 %
B.8 3/4%
C.5%
D.6 2/3 %
Answer: B.8 3/4%
Explanation: S.I. on Rs. 800 for 1 year = (870 - 800) = Rs. 70 Rate = (100 * 70)/(800 * 1) = 8 3/4%
ANSWER:B
Question: A waitress's income consists of her salary and tips.During one week ,her tips were 2/4 of her salary.What fraction of her income for the week came from tips?
A.1/9
B.1/6
C.1/3
D.4/9
Answer: C.1/3
Explanation: Her tips were 2/4 of her salary.
Let's say her salary =$4
This mean her tips = (2/4)($4) =$2
So, her TOTAL INCOME =$4+$2=$6
What fraction of her income for the week came from tips
$2/$6= 1/3
= C
Question: A father tells his son, "I was of your present age when you were born". If the father is 36 now, how old was the boy five years back ?
A.13
B.15
C.17
D.20
Answer: A.13
Explanation: F is fathers age and B is Boys age
F-B=B, F=2B
2B=36, B=18
Boys age 5 years back would be 13
ANSWER:A
Question: 34.94 + 240.016 + 23.98 = ?
A.298.936
B.298.694
C.289.496
D.289.469
Answer: A.298.936
Explanation: 34.94
240.016
+ 23.98
--------
298.936
Answer is A.
Question: The C.P of 10 pens is equal to the S.P of 12 pens. Find his gain % or loss%?
A.16 2/9%
B.16 4/3%
C.16 2/3%
D.16 3/3%
Answer: C.16 2/3%
Explanation: 10 CP = 12 SP
12 --- 2 CP loss
100 --- ? => 16 2/3%
Answer: C
Question: An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq m?
A.Rs.4082.67
B.Rs.4082.99
C.Rs.4082.29
D.Rs.4082.40
Answer: D.Rs.4082.40
Explanation: Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 * 7) = 315 (13 - 0.04) = 4095 - 12.6
= Rs.4082.40
Answer:D
Question: How many different subsets of the set {10, 12, 17, 24} are there that contain an odd number of elements?
A. 3
B. 8
C. 6
D. 10
Answer: B. 8
Explanation: Answer = B = 8
{10}
{12}
{17}
{24}
{10, 12, 17}
{12, 17, 24}
{10, 17, 24}
{10, 12, 24}
Question: A car travels from B at a speed of 20 km/hr. The bus travel starts from A at a time of 6 A.M. There is a bus for every half an hour interval. The car starts at 12 noon. Each bus travels at a speed of 25 km/hr. Distance between A and B is 100 km. During its journey ,The number of buses that the car encounter is ?
A.15
B.16
C.17
D.18
Answer: C.17
Explanation: Total journey = 100 km.
The bus travel starts from A at a time of 6 A.M. and each bus travels at a speed of 25 km/hr so time required for the bus to complete the journey = 4 hrs.
so the bus starts at 8:30 will meet with the car moving in opposite direction definitely.
Car travels from B at a speed of 20 km/hr so time of arrival of car at A is 5 P.M., it means the last bus which will meet with the car is that starts at 4:30 P.M.
so total bus ranges from 8:30 P.M. to 4:30 P.M. = 17
ANSWER:C
Question: On Saturday morning, John will begin a camping vacation and he will return home at the end of the first day on which it rains. If on the first three days of the vacation the probability of rain on each day is 0.7, what is the probability that Malachi will return home at the end of the day on the following Monday?
A.0.063
B.0.125
C.0.128
D.0.512
Answer: A.0.063
Explanation: Re-phrasing the question:
What is the probability of: Saturday: No rain, Sunday: No rain, Monday: Rain
Probability of rain = 0.7
Therefore, probability of no rain = 0.3
0.3*0.3*0.7 = 0.063
Hence A
Question: If 14 lions can kill 14 deers in 14 minutes how long will it take 100 lions to kill 100 deers?
A.1 minutes
B.14 minute
C.100 minutes
D.10000 minutes
Answer: B.14 minute
Explanation: we can try the logic of time and work,our work is to kill the deers so 14(lions)*14(min)/14(deers)=100(lions)*x(min)/100(deers)hence answer is x=14
ANSWER:B
Question: The remainder obtained by the division of two numbers by a common divisor are 33 and 47 respectively. However when the sum of these two numbers is divided by the same divisor, the remainder obtained is only 30. What is the divisor?
A.20
B.30
C.40
D.50
Answer: D.50
Explanation: Remainders are 33 & 47. So directly rule out the possibility of the divisor being 20, 30 & 40
Option A, B, C ruled out
Consider option D - 50
50+33 = 83 & 50+47 = 97
83+97 = 180
180/50 gives remainder = 30
Answer = D
Question: jess bakes 5 biscuits for 5 friends. 3 of the friend arrive early and eat 3 biscuits each. How many biscuits are left over if the other friends all have the same number of biscuits?
A.7
B.1
C.0
D.3
Answer: C.0
Explanation: jess made 5*5 biscuits = 25 biscuits. 3 friends eat 3 biscuits, leaving 16 remaining for 2 friends.
16 divisible by 2.
C is the correct answer
Question: In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?
A.37
B.28
C.30
D.19
Answer: C.30
Explanation: Explanation:
There is a meal for 200 children. 150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children = 120 men.
50 children = {\color{Blue} \left ( \frac{120}{200} \right )\times 50} =30men
Answer: C
Question: A dragon has 100 heads. A soldier can cut off 15, 17, 20 or 5 heads, respectively with one blow of his sword. In each of these cases, 24, 2, 14, 17 new heads grow on its shoulders. If all heads are cut off, the dragon dies. Can the dragon ever die?
A.61
B.3
C.5
D.6
Answer: B.3
Explanation: Here the difference in the cutoff heads and newly grown heads is 3. 100 is not divisible by 3. The dragon never die.
Answer:B
Question: Find the next number in the series
1, 6, 13, 22, 33, ......
A.44
B.45
C.46
D.47
Answer: C.46
Explanation: 1+5=6
6+7=13
13+9=22
22+11=33
33+13=46
ANSWER:C
Question: Which of the following is between 1/9 and 5/21?
A.2/13
B.3/8
C.1/2
D.5/8
Answer: A.2/13
Explanation: I see this as a POE (Process of Elimination) and Ballparking (Estimation) question. Not sure if this is the most efficient, but it worked:
1) I estimate 1/9 to be ~1/10 + (approximately slightly greater than 3/4)
2) I estimate 5/21 to be ~1/5+ (approximately slightly greater than 1/5)
3) So now I'm looking for an answer choice that is .1 < x < .2
Answer A - 2/13 ~ ..15 which is greater than .1 and less than .2