RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Some pen bought something at loss for Rs 60.He then sold it the price of 81 and his profit was 20% of the loss.At what price did he buy the object
A.77.5
B.76.5
C.75.5
D.74.5
Answer: A.77.5
Explanation: lets Assume loss be Rs x on Rs 60
Cost Price = 60+x
He then sold it the price of 81 and his profit was 20% of the loss
60+x + 20%x = 81
Solving this x will be 17.5
Cost Price = 60 + x = 60 + 17.5 = 77.5
ANSWER:A
Question: Exactly 3/7 of the people in the room are under the age of 21, and exactly 5/8 of the people in the room are over the age of 65. If the total number of the people in the room is greater than 50 and less than 100, how many people in the room are under the age of 21?
A.24
B.35
C.39
D.60
Answer: A.24
Explanation: The total number of the people in the room must be a multiple of both 7 and 8 (in order 3/7 and 5/8 of the number to be an integer), thus the total number of the people must be a multiple of LCM of 7 and 8, which is 56.
Since, the total number of the people in the room is greater than 50 and less than 100, then there are 56 people in the room.
Therefore there are 3/7*56=24 people in the room under the age of 21.
Answer: A.
Question: A telephone number contains 10 digit, including a 3-digit area code. Bob remembers the area code and the next 5 digits of the number. He also remembers that the remaining digits are not 0, 1, 6, or 7. If Bob tries to find the number by guessing the remaining digits at random, the probability that he will be able to find the correct number in at most 2 attempts is closest to which of the following?
A.1/6
B.1/9
C.1/18
D.1/24
Answer: C.1/18
Explanation: There are 6*6 = 36 possibilities.
Bob has 2 chances so the probability is 2/36 = 1/18.
The answer is C.
Question: If in a kindergarten class, there are five children 3 feet 4 inches tall (indicated by notation 3'4"), two children 4'3" tall and thirteen children 2'9" tall, which of the following is the median height of the children?
A.2'9"
B.2'6"
C.3'3"
D.3'4"
Answer: A.2'9"
Explanation: Total number of children in class = 20
so median must be between 10th and 11th child when they are arranged in ascending order.
When arranged in ascending order 5th and 6th child will have the height of 3'4"
so required median height = (2'9"+2'9")/2 = 2'6"
Ans:Option A
Question: A reduction of 20% in the price of salt enables a lady to obtain 10kgs more for Rs.100, find the original price per kg?
A.2 3/2
B.2 2/3
C.2.5
D.3
Answer: C.2.5
Explanation: 100*(20/100) = 20 --- 10
? --- 1 => Rs.2
100 --- 80
? --- 2 => Rs.2.5
Answer: C
Question: Change 1/8 = 8-1 to logarithmic notation.
A.log(8)8
B.log7
C.log(5)8
D.log 5
Answer: A.log(8)8
Explanation: Solution:
1/8 = 8-1 = log88
Answer is A
Question: Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old his son. Then the sum of the present ages of the son and the father is:
A.54
B.72
C.105
D.108
Answer: D.108
Explanation: Let the present ages of the father and son be 2x and x years respectively.
Then, (2x - 18) = 3(x - 18) => x = 36
Required sum = (2x + x) = 108 years.
ANSWER:D
Question: One lady has 2 children, one of her child is boy, what is the probability of having both are boys
A.1/2
B.1/3
C.1/4
D.1/5
Answer: A.1/2
Explanation: n(S)=one of her child is boy out of 2 children=BB,BG=2
n(E)=both are boys=BB=1
so p=n(E)/n(s)=1/2
ANSWER:A
Question: If the product 48^64 × 9x2 is divisible by 12, then what is the value of x?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: 4864 × 9a2 is divisible by 12
=> 4864 × 9a2 is divisible by 3
and 4864 × 9a2 is divisible by 4
4864 is divisible by 4 because number formed by the last two digits is 64 which is divisible by 4. Hence 4864 × 9a2 will also be divisible by 4
4864 is not divisible by 3 (because 4 + 8 + 6 + 4 = 22 which is not divisible by 3). Hence 9a2 must be divisible by 3 because 48^64 × 9x2 is divisible by 3
=> 9 + x + 2 is divisible by 3
=> 11 + a is divisible by 3
Hence a can be 1 or 4 or 7 such that 11 + a is divisible by 3
So, from the given choices, 1 is the answer.
A
Question: Sterling Silver is 92.5% pure silver. How many grams of Sterling Silver must be mixed to a 90% Silver alloy to obtain a 500g of a 91% Silver alloy?
A.200
B.300
C.400
D.500
Answer: A.200
Explanation: Let x and y be the weights, in grams, of sterling silver and of the 90% alloy to make the 500 grams at 91%. Hence
x + y =500
The number of grams of pure silver in x plus the number of grams of pure silver in y is equal to the number of grams of pure silver in the 500 grams. The pure silver is given in percentage forms. Hence
92.5% x + 90% y = 91% 500
Substitute y by 500 - x in the last equation to write
92.5% x + 90% (500 - x) = 91% 500
Simplify and solve
92.5 x + 45000 - 90 x = 45500
x = 200 grams.
200 grams of Sterling Silver is needed to make the 91% alloy.
Answer A
Question: Walking with 4/5 of my usual speed, I miss the bus by 6 minutes. What is my usual time?
A.16 min
B.26 min
C.34 min
D.24 min
Answer: D.24 min
Explanation: Speed Ratio = 1:4/5 = 5:4Time Ratio
= 4:5 1 -------- 6 4 --------- ? è 24
Answer: D
Question: A 300 m long train crosses a platform in 33 sec while it crosses a signal pole in 18 sec. What is the length of the platform?
A.286 m
B.250 m
C.277 m
D.278 m
Answer: B.250 m
Explanation: Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/33 = 50/3
=> x = 250 m.
Answer:B
Question: A 240 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
A.230
B.260
C.267
D.256
Answer: B.260
Explanation: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 240)/9 = 500/9 => x = 260.
Answer: B
Question: If an article is sold at 19% profit instead of 12% profit, then the profit would be Rs. 105 more. What is the cost price?
A.2278
B.388
C.1500
D.2776
Answer: C.1500
Explanation: Let the cost price of an article be Rs. x.
(19% of x) - (12% of x) = 105
19x/100 - 12x/100 = 105 => 7x = 105 * 100
=> x = 1500
Cost price = Rs. 1500
Answer:C
Question: If 8 men do a work in 80 days, in how many days will 20 men do it?
A.18 days
B.32 days
C.42 days
D.48 days
Answer: B.32 days
Explanation: 8 * 80 = 20 * x
x = 32 days
ANSWER:B
Question: The angle between the minute hand and the hour hand of a clock when the time is 12.30, is
A.35°
B.65°
C.45°
D.195°
Answer: D.195°
Explanation: Angle between hands of a clock
When the minute hand is behind the hour hand, the angle between the two hands at M minutes past H 'o clock
=30(H−M/5)+M/2 degree
When the minute hand is ahead of the hour hand, the angle between the two hands at M minutes past H 'o clock
=30(M/5−H)−M/2 degree
Here H = 12, M = 30 and minute hand is behind the hour hand.
Hence the angle
=30(H−M/5)+M/2
=30(12−30/5)+30/2
=30(12−6)+15
=30×6+15 =195°
Answer is D.
Question: A credit card number has 6 digits (between 1 to 9). The first two digits are 12 in that order, the third digit is bigger than 5, the forth is divisible by 3 and the fifth digit is 3 times the sixth. How many different credit card numbers exist?
A.27
B.72
C.36
D.112
Answer: C.36
Explanation: {1}{2}{greater than 5}{divisible by 3}{3x}{x}:
The third digit can take 4 values:6, 7, 8, or 9.
The fourth digit can take 3 values: 3, 6, or 9.
The fifth and sixth digits can take 3 values: 31, 62, or 93.
Total = 4*3*3 = 36.
Answer: C.
Question: The taxi charges in a city comprise of a fixed charge, together with the charge of the distance covered. For a journey of 16 km, the charges paid are Rs. 156 and for a journey of 24 km, the charges paid are Rs. 204. What will a person have to pay for travelling a distance of 30 km?
A.Rs. 236
B.Rs. 240
C.Rs. 248
D.Rs. 252
Answer: B.Rs. 240
Explanation: For a journey of 16 km, the charges paid are Rs. 156 and for a journey of 24 km, the charges paid are Rs. 204.
Additional charges for 8 kms = 204-156 = 48 Rs
additional charge/km= 48/8 = Rs 6
additional charge for 6 kms = 6*6 = Rs 36.
total charges for 30 kms = 204 +36 = Rs 240
ANSWER:B
Question: A boatman goes 3 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
A.40 minutes
B.1 hour 7 min
C.1 hour 15 min
D.1 hour 30 min
Answer: B.1 hour 7 min
Explanation: speed (upstream) =3/1 = 3 kmhr
speed (downstream)=1/(10/60)= 6 kmhr
speed in still water = 1/2 (3+6) = 4.5 kmhr
time taken in stationary = 5/4.5 = 1 hrs 7 min
ANSWER:B
Question: In a mens hostel, there were 95 students. To accommodate 30 more students the average is decreased by rupees 5. But total expenditure increased by Rs.500. Find the total expenditure of the hostel now ?
A.Rs.4680
B.Rs.4287
C.Rs.4129
D.Rs.4112
Answer: A.Rs.4680
Explanation: Explanation:
Let the expenditure on the 95 students be 'x'
Then,
95x + 500 = 120(x â€“ 5)
95x + 500 = 120x - 600
120x - 95x = 1100
25x = 1100
=> x = 44
Therefore, total expenditure of the hostel becomes
95 x 44 + 500 = 4680.
Answer: A
Question: For the set {2, 2, 3, 3, 4, 4, 5, 5,7,7 x}, which of the following values of x will most increase the standard deviation?
A.1
B.2
C.3
D.(-3.2)^2
Answer: D.(-3.2)^2
Explanation: Standard Deviation Step 1, as pointed out by others, is to find out the mean = 4.2
Step 2, For each number: subtract the Mean and square the result =
(1-4.2)^2=(-3.2)^2
(2-4.2)^2=(-2.2)^2
(3-4.2)^2 =(-1.2)^2
(4-4.2)^2=(.2)^2
(5-4.2)^2=(.8)^2
Clearly (1-3.5)^2=(-3.2)^2 will give you the greatest value among all the other options.
Hence D
Question: The population of a town is 186800. If it increase at the rate of 7% per annum. What will be its population for 2years hence?
A.200000
B.215600
C.194582
D.213867
Answer: D.213867
Explanation: population after 2years = 186800*(1+ 7/100)^2 = 213867
Answer is D
Question: 0,2,6,12,20, ____
A.25
B.28
C.30
D.26
Answer: C.30
Explanation: 0,2,6,12,20, .....
1*1-1=0
2*2-2=2
3*3-3=6
4*4-4=12
5*5-5=20
So 6*6-6=30
ANSWER:C
Question: In the city of San Durango, 60 people own cats, dogs, or rabbits. If 30 people owned cats, 40 owned dogs, 14 owned rabbits, and 12 owned exactly two of the three types of pet, how many people owned all three?
A.2
B.4
C.6
D.12
Answer: C.6
Explanation: You are considering a case when cat dogs and rabbit are not exactly equal to 12 .
The solution shall be 60=30+40+14-12-2x
and hence x shall be 6.
Answer C
Question: If the area of a square with sides of length 3 centimeters is equal to the area of a rectangle with a width of 4 centimeters, what is the length of the rectangle, in centimeters?
A.4
B.8
C.12
D.3
Answer: D.3
Explanation: Let length of rectangle = L
3^2 = L*4
=> L = 9/4 = 3
Answer D
Question: In a hostel there were 100 students. To accommodate 20 more students the average is decreased by rupees 5. But total expenditure increased by Rs.400. Find the total expenditure of the hostel now?
A.5429
B.2897
C.5400
D.2689
Answer: C.5400
Explanation: 100x + 400 = 12(x – 5)
x = 50
100 * 50 + 400 = 5400
Answer:C
Question: The digital sum of a number is the sum of its digits. For how many of the positive integers 24-80 inclusive is the digital sum a multiple of 7?
A.7
B.9
C.14
D.16
Answer: B.9
Explanation: is there other way than just listing?
25
34
43
52
59
61
68
70
77
9 ways..
B
Question: The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
A.8 years
B.16 years
C.4 years
D.18 years
Answer: C.4 years
Explanation: Let the age of first child be x years.
since all the children got birth in interval of 3 years so the age of 2nd,3rd,4th and 5th child would be x-3 , (x-3)-3 ,((x-3)-3)-3 ,(((x-3)-3)-3)-3 respectively,
also the sum of ages of all children is 50,
= x+(x-3)+(x-6)+(x-9)+(x-12)=50
=5x-30=50
=5x=80
=x=16
so the age of youngest child would be 16-12 = 4 years. ANSWER : C
Question: Jamboree and GMAT Club Contest Starts
QUESTION #20:
How many words (with or without meaning) can be formed using all the letters of the word “SELFIE” so that the two E’s are not together?
A. 660
B. 600
C. 500
D. 300
Answer: B. 600
Explanation: The question is asking the total number of arrangements possible with the letters of the word “SELFIE” where two E’s are not together.
Arrangements when two E’s are not together = Total arrangements - Arrangements when two E’s are together
In total there are 6 letters but two are identical. so we can arrange in 6! ways. but we divide for those objects that are identical. so divide by 2!. Hence,
Total arrangements = 6!/2!
Now two E's are coupled together. Consider this couple (EE) as one letter. apart from this there are 4 more letters. so we can arrange these 5 different objects in 5! ways.
Two E's can arrange themselves in 2! ways, but we divide for those objects that are identical. so divide by 2!. so arrangement for E's would be 2!/2!.
Hence, Arrangements when two E’s are together = 5! * (2!/2!)
Arrangements when two E’s are not together = 6!/2! - 5! = 5! * ( 6/2 -1 ) = 120 * 2 = 240.
Option B is correct!
Question: Which of the following lines has x-intercept and y-intercept that are integers W?
A.y=3x+1
B.y=√x+1
C.y=-2/x
D.y=x^2-1
Answer: D.y=x^2-1
Explanation: Values that satisfy y=x^2-1 are (x,y)=(-1,0),(1,0),(0,-1). Hence, they are all integers W and the correct answer is D.
Question: In X game of billiards, X can give Y 20 points in 60 and he can give Z 30 points in 60. How many points can Y give Z in X game of 80?
A.30
B.20
C.25
D.40
Answer: B.20
Explanation: X scores 60 while Y score 40 and Z scores 30.
The number of points that Z scores when Y scores 80 = (80 * 30)/40 = 60.
In X game of 100 points, Y gives (80 - 60) = 20 points to C.
B
Question: Two dice are rolled. What is the probability the sum will be greater than 8?
A.2/9.
B.1/12.
C.5/36.
D.7/36.
Answer: A.2/9.
Explanation: Combinations possible: (6,6) , (5,6) , (6,5) , (4,6), (6,4) , (5,5) , (5,4), (4,5) = 8
Total combinations possible: 6*6=36
Answer = 8/36 = 2/9 Option A.
Question: The length and breadth of a room are 8 m and 6 m respectively. A cat runs along all the four walls and finally along a diagonal order to catch a rat. How much total distance is covered by the cat?
A.22
B.88
C.38
D.99
Answer: C.38
Explanation: Answer: C) 38
Question: A bag of potatoes weighs 12 lbs divided by half of its weight. How much does the bag of potatoes weight?
A.20 lb
B.18 lb
C.12 lb
D.15 lb
Answer: C.12 lb
Explanation: Sol.
12÷1 = 12.
Answer : C
Question: The difference between simple and compound interests annually on a particular sum of money for 2 years at 4% per annum is Rs. 1. What is the sum?
A.600
B.625
C.650
D.675
Answer: B.625
Explanation: sum consider as x
CI = (x(1+4/100)^2-x) = 676/625x-x
=>51/625x
SI = x*4*2/100 = 2x/25
51x/625 - 2x/25 = 1
x= 625
ANSWER B
Question: If the length of a certain rectangle is decreased by 4 cm and the width is increased by 3 cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle.
A.33
B.38
C.77
D.50
Answer: D.50
Explanation: Explanation:
Let x and y be the length and breadth of the rectangle respectively.
Then, x - 4 = y + 3 or x - y = 7 ----(i)
Area of the rectangle =xy; Area of the square = (x - 4) (y + 3)
(x - 4) (y + 3) =xy <=> 3x - 4y = 12 ----(ii)
Solving (i) and (ii), we get x = 16 and y = 9.
Perimeter of the rectangle = 2 (x + y) = [2 (16 + 9)] cm = 50 cm.
Answer: D) 50
Question: What day of the week was 1 January 1901
A.Monday
B.Tuesday
C.Saturday
D.Friday
Answer: B.Tuesday
Explanation: Explanation :
1 Jan 1901 = (1900 years + 1-Jan-1901)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfect multiple of 400)
Number of odd days in the period 1601-1900
= Number of odd days in 300 years
= 5 x 3 = 15 = 1
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
1-Jan-1901 = 1 odd day
Total number of odd days = (0 + 1 + 1) = 2
2 odd days = Tuesday
Hence 1 January 1901 is Tuesday.
Answer : Option B
Question: Car A runs at the speed of 50km/hr & reaches its destination in 8hr. Car B runs at the speed of 25 km/h & reaches its destination in 4h. What is the respective ratio of distances covered by Car A & Car B?
A.4 : 1
B.11 : 8
C.13 : 7
D.15 : 7
Answer: A.4 : 1
Explanation: Sol. Distance travelled by Car A = 50 × 8 = 400 km
Distance travelled by Car B = 25 × 4 =100 km
Ratio = 400/100 = 4 : 1
Answer : A
Question: If x and y are positive integers such that (3x + 7y) is a multiple of 11, then which of the following will be divisible by 11 ?
A.9
B.11
C.17
D.21
Answer: B.11
Explanation: By hit and trial, we put x = 5 and y = 1 so that (3x + 7y) = (3 x 5 + 7 x 1) = 22, which is divisible by 11.
(4x + 6y) = ( 4 x 5 + 6 x 1) = 26, which is not divisible by 11;
(x + y + 4 ) = (5 + 1 + 4) = 10, which is not divisible by 11;
(9x + 4y) = (9 x 5 + 4 x 1) = 49, which is not divisible by 11;
(4x - 9y) = (4 x 5 - 9 x 1) = 11, which is divisible by 11.
Option B
Question: A cycle is bought for Rs.900 and sold for Rs.1350, find the gain percent?
A.27%
B.20%
C.50%
D.30%
Answer: C.50%
Explanation: 900 ---- 450
100 ---- ? => 50%
Answer: C
Question: What is the maximum number of pieces that a circular pizza can be cut into with 5 linear cuts?
A.10
B.14
C.15
D.16
Answer: D.16
Explanation: 1 cut makes 2 pieces
a second cut can make 4 pieces
a third cut can make 7 pieces by cutting through 3 of the pieces
a fourth cut can make 11 pieces by cutting through 4 of the pieces
a fifth cut can make 16 pieces by cutting through 5 of the pieces
D
Question: A meeting has to be conducted with 5 managers. Find the number of ways in which the managers be selected from among 8 managers, if 2 managers will not attend the meeting together?
A.40
B.36
C.42
D.45
Answer: B.36
Explanation: we can either choose all 5 people from 6 manager who have no problems or choose 4 from the 6 and 1 from the 2 managers who have a problem sitting together
so 6C5 + (6C4 * 2C1)
this is 6 + 30=36
Answer : B
Question: If x = y^2, and x and y are positive integers, which of the following numbers could be the value of x?
A.9,343
B.10,982
C.11,881
D.12,988
Answer: C.11,881
Explanation: The square of an integer can have a units digit of 0, 1, 4, 5, 6, or 9.
The answer is C.
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
A.112
B.50
C.77
D.14
Answer: B.50
Explanation: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr
= 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45 ==> x
= 50 km/hr.
Answer: B
Question: A teacher has 16 students, then she gets 7 more students. Now how many students does she have?
A.A)9
B.B)15
C.C)15
D.D)23
Answer: D.D)23
Explanation: 16+7=23. Answer is D
Question: Ravi can do a piece of work in 50 days while Prakash can do it in 75 days. In how many days will they finish it together?
A.30 days
B.35 days
C.25 days
D.27 days
Answer: A.30 days
Explanation: 1/50 + 1/75 = 5/150
30/1 = 30 days
ANSWER:A
Question: Kiran travels from A to B by car and returns from B to A by cycle in 7 hours. If he travels both ways by car he saves 3 hours. What is the time taken to cover both ways by cycle?
A.10 hours
B.16 hours
C.19 hours
D.15 hours
Answer: A.10 hours
Explanation: Let the time taken to cover from A to B in car and cycle be x hours and y hours respectively.
x + y = 7 --- (1) ; 2x = 4 --- (2)
solving both the equations, we get y = 5
So, time taken to cover both ways by cycle = 2y hours
=10 hours.
Answer: A
Question: George and Mark can paint 720 boxes in 20 days. Mark and Harry in 24 days and Harry and George in 15 days. George works for 4 days, Mark for 8 days and Harry for 8 days. The total number of boxes painted by them is
A.28
B.H
C.27
D.29
Answer: B.H
Explanation: Answer:B
Question: If x = a/(a – 1) and 1/(a – 1), then:
A.x is equal to y
B.x is equal to y only if a < 1
C.x is greater than y
D.x is greater than y only if a < 1
Answer: A.x is equal to y
Explanation: x = a/(a – 1) = 1 + 1/(a – 1) = 1 + y.
Therefore, x > y
ANSWER:A
Question: In August,a cricket team that played 120 matches won 20% of the games it played.After a continuous winning streak,this team raised its average to 52%.How many matches did the team win to attain this average?
A.40
B.52
C.68
D.80
Answer: D.80
Explanation: let the no of matches played more=x
so,
(120+x)*52/100=24+x
by solving we get x=80
ANSWER:D
Question: An article was sold after a discount of 20% and therewas a gain of 20%. If the profit madeon it was Rs.6 less thanthe discount offered on it, find its SP?
A.Rs. 70
B.Rs. 71
C.Rs. 72
D.Rs. 90
Answer: C.Rs. 72
Explanation: Let CP = Rs. 100x
SP = Rs. 120x
MP = 120x/80 * 100 = Rs. 150x
D = Rs. 150x - Rs. 120x = Rs. 30x
D - P = 30x - 20x = Rs. 6, 10x = Rs. 6
120x = 120/10 * 6 = Rs. 72
C
Question: If (4.2)x = (0.42)y = 100, then (1/x) - (1/y) =
A.1
B.2
C.1/2
D.1/4
Answer: C.1/2
Explanation: (4.2)x = 100
=> (42)x = 102+x
=> 42 = 10(2/x+1) ---------- (i)
[42/100]y = 100 => 42y = 102+2y
=> 42 = 102/y+2-------- (ii)
From (i) and (ii), 2/x - 2/y = 1
=>1/x - 1/y = 1/2.
ANSWER:C
Question: In each of the following questions a number series is given with one term missing. Choose the correct alternative that will continue the same pattern and fill in the blank spaces.
2, 7, 14, 23, 34, ?
A.31
B.47
C.36
D.31
Answer: B.47
Explanation: B
47
The given sequence is +5, +7, +9, ——
ie. 2+ 5 = 7, 7 + 7 = 14, 14 + 9 = 23
Question: Find the no.of ways of arranging 5 men and 5 ladies at a circular table so that no two ladies sit together ?
A.4!x4!
B.5!x5!
C.4!x5!
D.10!x10!
Answer: C.4!x5!
Explanation: The no. of ways of 5 men may be arranged in 4! ways. The ladies can arranged in themselves in 5! ways. The required no. of ways of arranging them is 4!x5! . Ans:(C)
Question: A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
A.7 kmph
B.6 kmph
C.5 kmph
D.8 kmph
Answer: D.8 kmph
Explanation: Speed downstream = d/t = 85/(2 1/2)
= 34 kmph
Speed upstream = d/t = 45/(2 1/2)
= 18 kmph
The speed of the stream = (34 - 18)/2
= 8 kmph
Answer: D
Question: How many words with or without meaning, can be formed by using all the letters of the word, â€˜WORKâ€™, using each letter exactly once?
A.700
B.24
C.32
D.48
Answer: B.24
Explanation: The word â€˜WORKâ€™ contains 4 different letters.
Therefore, Required number of words= Number of arrangement of 4 letters, taken all at a time
=4P4
= 4!
= 4*3*2*1
= 24
ANSWER:B
Question: If A invested 5 times of B and at the end of the year they got a profit of Rs.36,000 in their business then share. of B in the profit was (in Rs.)
A.5000
B.4000
C.3000
D.6000
Answer: D.6000
Explanation: A:B=5:1
so b=1/6 *36000
=6000
ANSWER:D
Question: By selling 12 toffees for a dollar, a man loses 20%. How many for a dollar should be sell to get a gain of 20%?
A.8
B.5
C.9
D.4
Answer: A.8
Explanation: A
8
Let S.P. of 12 toffees be $x.
Then, 80:1 = 120:x or x = 120/180 = 3/2
For $3/2, toffees sold = 12.
For Re. 1, toffees sold = 12 * 2/3 = 8
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 50, the dividend is:
A.5330
B.6300
C.5343
D.5345
Answer: B.6300
Explanation: Divisor = (5 * 50) = 250
= 10 * Quotient = Divisor
=> Quotient = 250/10 = 25
Dividend = (Divisor * Quotient) + Remainder
Dividend = (250 * 25) + 50 = 6300.
B
Question: From a Group of 8 People, Including Sachin and Rahul, 3 people are to be selected at random to work on a certain project. What is the probability that 3 people selected will include Sachin but not Rahul
A.5/56
B.9/56
C.15/56
D.21/56
Answer: C.15/56
Explanation: Number of ways of selecting 3 people out of 8 people = 8C3
In the three members Sachin will always be there in the team. At this step we have vacancy for 2 more members and 7 members are available. Lina cannot be there in the team. So 2 members have to be selected and the number of available members = 7 - Rahul = 6
Number of ways to form a 3 member team that includes Sachin and excludes Rahul = 6C2
Probability = 6C2/8C3 = 15/56
Answer: C