RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The ratio of the cost price and selling price is 4:5. The profit percent is?
A.20%
B.25%
C.30%
D.50%
Answer: B.25%
Explanation: Let the C.P. = $4x
Then S.P. = $5x
Then, Gain = 5x-4x = $x
Gain% = x/4x *100 = 25%
Answer is B
Question: Reema took a loan of Rs 1100 with simple interest for as many years as the rate of interest. If she paid Rs. 704 as interest at the end of the loan period, what was the rate of interest.
A.5%
B.6%
C.7%
D.8%
Answer: D.8%
Explanation: Explanation:
Let rate = R% then Time = R years.
=>1100∗R∗R /100=704
=>R2=64
=>R=8%
Option D
Question: Rs.1170 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share?
A.Rs.589
B.Rs.518
C.Rs.519
D.Rs.540
Answer: D.Rs.540
Explanation: A+B+C = 1170
4A = 3B = 2C = x
A:B:C = 1/4:1/3:1/2 = 3:4:6
6/13 * 1170 = Rs.540
Answer: D
Question: Mrs. Anderson divided $420 evenly among her children. Later, when Mrs. Anderson was away, Daniel, the eldest, took $5 from each of his brothers and sisters. Daniel ended up with $90. If Mrs. Anderson has more than 7 children, how many children does Mrs. Anderson have?
A.12
B.14
C.16
D.18
Answer: A.12
Explanation: Let no of children be x
Even share as per initial division = 420/x
Daniel took $5 from each of his brother & sisters = 5(x-1)
so, 420/x + 5(x-1) = 90
5x^2 -95x + 420 = 0
x^2 - 19x + 84 = 0
Solving for X, x = 12 or x =7
Since we are given that x > 7, so no of children = 12
Option A.
Question: If the sum of two integers is 6, then it must be true that
A.both integers are even
B.both integers are odd
C.both integers are positive
D.if one integer is negative, the other is positive
Answer: D.if one integer is negative, the other is positive
Explanation: We're asked to find a statement that MUST be true. So, if we can find a case where a statement is false, we can ELIMINATE that answer choice.
(A) both integers are even : it could be the case that the numbers are 1 and 5. ELIMINATE A
(B) both integers are odd : it could be the case that the numbers are 2 and 4. ELIMINATE B
(C) both integers are positive : it could be the case that the numbers are -1 and 7. ELIMINATE C
(D) if one integer is negative, the other is positive : Can't think of a counterexample so KEEP D for now
(E) if one integer is positive, the other is negative : it could be the case that the numbers are 1 and 5. ELIMINATE E
By the process of elimination, the correct answer is D
Question: A grocer has a sale of Rs. 5420, Rs. 5660, Rs. 6200, Rs. 6350 and Rs. 6500 for 5 consecutive months. Find the sale he should have in the sixth month, so that he gets an average sale of Rs. 6100?
A.Rs. 5870
B.Rs. 5991
C.Rs. 6470
D.Rs. 6850
Answer: C.Rs. 6470
Explanation: Explanation:
Total sale for 5 months = Rs. (5420 + 5660 + 6200 + 6350 + 6500) = Rs. 30,130
Therefore, required sale = Rs. [(6100 * 6) – 30,130] = Rs. (36600 – 30,130) = Rs. 6470
ANSWER C
Question: The probability that a visitor at the mall buys a pack of candy is 40%. If three visitors come to the mall today, what is the probability that exactly two will buy a pack of candy?
A..288
B..147
C..189
D..063
Answer: A..288
Explanation: One case is: candy - candy - no candy
The probability is 4/10*4/10*6/10 = 96/1000
There are 3 such cases, so we should multiply this probability by 3.
P(exactly 2 buy candy) = 96/1000 * 3 = 288/1000 = 0.288
The answer is A.
Question: A bus and a truck are available to cross a jungle. The speed of the truck is thrice that of the bus. The capacity of the truck is 50 persons and that of bus is 30 persons. The average occupancy of the bus is twice that of the truck. The tickets for the bus and the truck cost Re 1 and Re 1.50 respectively. What is the ratio of the average rupee collection of the truck to that of the bus in a day? Assume there is no wastage time between trips and the occupancy of the bus/truck is defined as the ratio of the actual number of persons boarding it and its capacity.
A.15:2
B.15:4
C.15:8
D.15:7
Answer: B.15:4
Explanation: Explanation :
Average Rupee collection = Speed × capacity × Occupancy × Ticket rate.
The ratio of average Rupee collection of truck to that of bus is :-
=>(3×50×1×1.5):(1×30×2×1)=15:4.
Answer : B
Question: The markup on a shirt is 50 percent of the cost. The markup is what percent of the selling price?
(markup = selling price - cost)
A. 18%
B. 20%
C. 33 1/3%
D. 45%
Answer: C. 33 1/3%
Explanation: MP = 0.5 CP
SP = CP + 0.5 CP = 1.5 CP
hence MP = 0.5/1.5 SP = 1/3 SP. Hence MP is 33.33 % of SP
Answer C
Question: If the day after tomorrow will be Sunday, when was Thursday?
A.Today
B.Tomorow
C.Yesterday
D.The day before yesterday
Answer: C.Yesterday
Explanation: Explanation:
Day after tomorrow will be Sunday
=>Tomorrow will be Saturday
=> Today is a Friday
=> Yesterday was a Thursday
Answer: Option C
Question: If â€˜PUNJABâ€™ is coded as â€˜GCEAABâ€™, then â€˜KERALAâ€™ is coded as
A.BEICCA
B.BIECAA
C.BEIACA
D.BIEACA
Answer: C.BEIACA
Explanation: M=13,1+3=4=D
A=1=A
SIMILARLY,
K=11=1+1=2=B
E=5=E
R=18=9=I
A=1=A
L=12=3=C
A=I=A
BEIACA
ANSWER:C
Question: The triplicate ratio of 2:4 is?
A.1:64
B.1:8
C.1:34
D.3:64
Answer: B.1:8
Explanation: 2^3: 4^3 = 8:64=1:8
ANSWER:B
Question: A certain set of numbers has an average (arithmetic mean) of 10 and a standard deviation of 2.5. If X, a number in the set, is within 2 standard deviations from the average, then which of the following CANNOT be the value of X?
A.2
B.5.5
C.6
D.10
Answer: A.2
Explanation: average (arithmetic mean) of 10 and a standard deviation of 2.5
Since, X, a number in the set, is within 2 standard deviations
i.e. X, a number in the set, between 10+2*2.5 and 10-2*2.5
i.e. X, a number in the set, between 15 and 5
Option A (2) is not within 2 SD therefore
Answer: Option A
Question: The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 3600 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
A.240
B.250
C.260
D.270
Answer: A.240
Explanation: Given that the area of the square = 3600 sq.units
=> Side of square = √3600 = 60 units
The radius of the circle = side of the square = 60 units
Length of the rectangle = 2/5 * 60 = 24 units
Given that breadth = 10 units
Area of the rectangle = lb = 24 * 10 = 240 sq.units
Answer: Option A
Question: The sum of two numbers is 33. Five times one number is equal to 6 times the other. The bigger of the two numbers is
A.10
B.18
C.15
D.22
Answer: B.18
Explanation: Sol.
Let the numbers be x and (33 - x).
Then, 5x = 6(33 - x)
⇔ 11x = 198⇔ x = 18.
So, the numbers are 18 and 15.
Answer B
Question: 4, 12, 48, 240, 1440, (...)
A.10080
B.12000
C.24000
D.14400
Answer: A.10080
Explanation: Go on multiplying the given numbers by 3, 4, 5, 6, 7
Answer is A
Question: The ratio between the radii of two spheres is 1:3. Find the ratio between their volumes?
A.1:27
B.27:1
C.3:1
D.1:3
Answer: A.1:27
Explanation: r1 : r2 = 1:3
r13 : r23 = 1:27
ANSWER A
Question: Set A = {2,3,4,5}
Set B = {4,5,6,7,8}
Two integers will be randomly selected from the sets above, one integer from Set A and one integer from Set B. What is the probability that the sum of the two integers will equal 9?
A.0.20
B.0.25
C.0.30
D.0.33
Answer: A.0.20
Explanation: Explanation :
Total numbers in n(S)=4×5=20.
=>n(E)=4. [(2,7), (3,6), (4,5), (5,4)].
The required probability :-
=>P(E)=n(E)/n(S).
=>4/20.
=>0.20.
Answer : A
Question: If 80% of 90 is greater than 70% of a number by 30, what is the number?
A.70
B.60
C.10
D.75
Answer: B.60
Explanation: Explanation:
80/100 * 90 - 70/100 * x = 30
72 - 70/100 * x = 30
72 - 30 = 70/100 *x
42 = 70/100 * x
42 * 100 / 70 = x
60 = x
Answer: Option B
Question: In practical applications, battery voltage:
A.22
B.66
C.76
D.126
Answer: B.66
Explanation: Explanation:
No answer description available for this questio
Answer: Option B
Question: A tin of oil was 4/5 full. when 6 bottles of oil were taken out and four bottles of oil were poured into it, it was ¾ full. how many bottles of oil can the tin contain?
A.20
B.10
C.40
D.50
Answer: C.40
Explanation: Suppose x bottles can fill the tin completely
Then 4/5x-3/4x=6-4
X/20=2
X=40
Therefore required no of bottles =40
Answer is C.
Question: A multiple choice test consists of 4 questions, and each question has 5 answer choices. In how many R ways can the test be completed if every question is unanswered?
A.24
B.120
C.625
D.720
Answer: C.625
Explanation: 5 choices for each of the 4 questions, thus total R of 5*5*5*5 = 5^4 = 625 ways to answer all of them.
Answer: C.
Question: x and y are positive integers. If xy + x is odd, then which of the following must be even?
.
A.x
B.y
C.x + y
D.xy − x
Answer: B.y
Explanation: Two possibilities:
(1) even + odd = odd
(2) odd + even= odd
In this case, x can not be even as it will make xy also even .
Therefore, (1) possibility present => y must be even.
Answer: B
Question: A sum amount to Rs.1344 in two years at simple interest. What will be the compound interest on the same sum at the same rate of interest for the same period?
A.10.75%
B.10.28%
C.10.25%
D.16.25%
Answer: C.10.25%
Explanation: 100
5 ---- I
5
0.25 --- II
-----------
10.25%.Answer:C
Question: X does a work in 10 days. Y does the same work in 15 days. In how many days they together will do the same work?
A.10
B.15
C.3
D.6
Answer: D.6
Explanation: X's 1day's work= 1/10
Y's 1 day's work=1/15
(X+Y)'s 1day's work= (1/10+1/15)=1/6
both together will finish the work in 6 days.
correct option is D
Question: Bob finishes the first half of an exam in one-thirds the time it takes him to finish the second half. If the whole exam takes him an hour, how many minutes does he spend on the first half of the exam?
A.20
B.24
C.27
D.30
Answer: D.30
Explanation: Many times, it is easiest to think of problems like this conceptually (as opposed to formulaically). Conceptually, if the first half of the exam takes 1/3's the time of the second half (3/3's), we can see that the hour the entire exam took to finish can be broken down into fifth's. (Another way to look at this problem is via ratio's - first half is 1:5 and the second half is 3:5). With each fifth of an hour being 15 minutes (60/4), the first half of the exam would have taken 30 minutes. Correct answer is D.
Question: In a store, the profit is 320% of the cost. If the cost increases by 25% but the SP remains constant, approximately what %of the sp is the profit?
A.50%
B.70%
C.80%
D.100%
Answer: B.70%
Explanation: Let C.P. = Rs. 100. Then, profit = Rs. 320, S.P. = Rs. 420
New C.P. = 125% of Rs. 100 = Rs. 125.
New S.P. = Rs. 420
Profit = 420 - 125 = Rs. 295
Required percentage = 295/420 * 100 = 1475/21 = 70%
B
Question: The ratio of ages of Aman, Bren, and Charlie are in the ratio 5:8:7 respectively. If 8 years ago, the sum of their ages was 76, what will be the age of Charlie 9 years from now?
A.44
B.52
C.57
D.65
Answer: A.44
Explanation: Let the present ages of Aman, Bren, and Charlie be 5x, 8x and 7x respectively.
5x-8 + 8x-8 + 7x-8 = 76
x = 5
Present age of Charlie = 7*5 = 35
Charlie's age 9 years hence = 35+9 = 44
Answer = A
Question: A shopkeeper sold an article for Rs 2591.36. Approximately what was his profit percent if the cost price of the article was Rs 2400
A.4%
B.5%
C.6%
D.8%
Answer: D.8%
Explanation: Explanation:
Gain % = (191.36*100/2400) = 7.97 % = 8% approx
Option D
Question: A team has to design a flag. The team has two yellow strips of cloth and five green strips of cloth that they must use as is to make the flag. How many different flags can the team design with the materials at hand?
A.21
B.121
C.240
D.720
Answer: A.21
Explanation: The # of permutations of total 2+5=7 strips where 2 are identical yellow and 5 are identical green is 7!/(2!*5!)=21 (note that they must use all the materials at hand, also I guess that the strips must be either only vertical or only horizontal).
Answer: A.
Question: How many numbers between 0 and 1670 have a prime tens digit and a prime units digit?
A.268
B.272
C.202
D.112
Answer: A.268
Explanation: There are 4 single digit prime numbers: 2, 3, 5 and 7. Hence, last two digits (tens and units) can take 4*4=16 different values: 22, 23, ..., 77.
So, in each hundred there are 16 such numbers. In 17 hundreds there will be 17*16=272 such numbers, but 4 out of them will be more than 1670, namely: 1672, 1673, 1675 and 1677. Which means that there are 272-4=268 numbers between 0 and 1670 which have a prime tens digit and a prime units digit.
Answer: A.
Question: If 'b' is a positive integer exactly divisible by 5 or 7 but not divisible by 11.What could possibly be the value of 'b' ?
A.55
B.35
C.77
D.110
Answer: B.35
Explanation: 55 and 77 are both divisible by 5 and 7 but also by 11. so they are not the right answer.
110 and 165 are both clearly not divisible by 7(not correct)
35 is both divisible by 5 and 7 but not by 11.
answer : (B) 35
Question: If x and y are non-zero integers, and 16x^4 – 4y^4 = 4x^2 + 2y^2, which of the following could be the value of x2 in terms of y?
A.2y^2
B.2y^2+3/4
C.2y^2+1/4
D.2y^2+1/2
Answer: C.2y^2+1/4
Explanation: 16x^4 – 4y^4 = 4x^2 + 2y^2
(4x^2 + 2y^2) (4x^2 - 2y^2) = 4x^2 + 2y^2
4x^2 - 2y^2 = 1
4x^2 = 2y^2+1
x^2 = 2y^2+1/4
Answer : C
Question: What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?
A.339
B.500
C.277
D.266
Answer: B.500
Explanation: 70 = (P*4*7/2)/100
P = 500
Answer:B
Question: The average of first five prime numbers greater than 20 is?
A.32.5
B.32.0
C.32.4
D.32.2
Answer: D.32.2
Explanation: 23 + 29 + 31 + 37 + 41 = 161/5
= 32.2
Answer: D
Question: How long does a train 130 m long running at the speed of 80 km/hr takes to cross a bridge 140 m length?
A.13.9 sec
B.12.3 sec
C.17.9 sec
D.61.9 sec
Answer: B.12.3 sec
Explanation: Speed = 80 * 5/18 = 22 m/sec
Total distance covered = 130 + 140 = 270 m.
Required time = 270/22 = 12.3 sec.
Answer:B
Question: A case of 12 rolls of paper towels sells for $9. The cost of one roll sold individually is $1.What is the percent E of savings per roll for the 12-roll package over the cost of 12 rolls purchased individually?
A.9%
B.11%
C.15%
D.25%
Answer: D.25%
Explanation: Cost of 12 paper towels individually = 1*12=12
Cost of a set of 12 paper towels = 9
Cost of one roll = 9/12 = 3/4 = 0.75
Savings per roll = 1-.75 = 0.25
% of savings is E= .25/ 1 *100 = 25% D is the answer.
Question: On a sum of money, the S.I. for 2 years is $600, while the C.I. is $609, the rate of interest being the same in both the cases. The rate of interest is?
A.2%
B.3%
C.4%
D.5%
Answer: B.3%
Explanation: Difference in C.I. and S.I for 2 years = $609 - $600 = $9
S.I for one year = $300
S.I. on $300 for 1 year = $9
Rate = (100 * 9)/(300) = 3%
The answer is B.
Question: Positive integers indicated by x and y satisfy 3 1/x * y 2/5 = 13 3/4, the fractions being in their lowest terms, then x = ? and y = ?
A.x = 4, y = 8
B.x = 4, y = 4
C.x = 2, y = 4
D.x = 8, y = 4
Answer: D.x = 8, y = 4
Explanation: 3 1/x * y 2/5 = 13¾
=> (3x + 1) / x + (5y + 1) / 2 += 55 / 4
only choice (4) i.e x = 8 and y = 4 satisfies the given equation.
3 (1/8) * 4 (2/5) = (25 / 8 ) * (22 / 5) = 55/4 = 13¾
ANSWER:D
Question: Paul purchased a house for Rs.46000 and a site for Rs.14000 respectively, if he sold the house for Rs.44000 and the site for Rs.20000, then find the resultant percentage of gain?
A.3.33%
B.4.44%
C.5.55%
D.6.66%
Answer: D.6.66%
Explanation: Sol.
Total CP = 60000 & total SP =64000 ⇒ gain = SP/CP = 64000/60000 = 1.0666 = 6.66%.
Answer D
Question: In an examination series, which consists of 5 exams, Arvind scored an average of 60 marks in
the first 3 exams and an average of 70 in the last 4 exams, what is the average score of
Arvind for the first and last two exams if his average scores of all the five exams are 65?
A.63.33
B.6
C.64
D.12
Answer: A.63.33
Explanation: let a,b,c,d,e be the five exams
(a+b+c+d+e)/5=65
a+b+c+d+e=325
first 3 exams avg is (a+b+c)/3=60
a+b+c=180
d+e=325-180=145
avg of last 4 exams is (b+c+d+e)/4=70
b+c+d+e=280
a=325-280=45
avg of first and last two exams are(a+d+e)/3=(45+145)/3=(190)/3=63.33
ANSWER:A
Question: A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg?
A.33
B.77
C.40
D.88
Answer: C.40
Explanation: 800*(25/100) = 200 ---- 5
? ---- 1 => Rs.40
Answer: C
Question: In how many ways can a committee of 7 people comprising at least 3 boys be formed using a group of 5 boys and 6 girls?
A.69
B.64
C.65
D.66
Answer: A.69
Explanation: There are 2 options: the selected groups have no girls or one girls.
-First case: 1 girl + 3 boys: 6C1 * 5C3 = 6*10 = 60
-Second case: 4 boys: 5C4 = 5
So there are 60 + 5 = 69 ways in total.
A
Question: A man can row with a speed of 10 kmph in still water. If the stream flows at 25 kmph, then the speed in downstream is?
A.10 kmph
B.35 kmph
C.20 kmph
D.22 kmph
Answer: B.35 kmph
Explanation: M = 10
S = 25
DS = 10 + 25 = 35
ANSWER:B
Question: A total of 3000 chocolates were distributed among 120 boys and girls such that each boy received 2 chocolates and each girl received 3 chocolates. Find the respective number of boys and girls?
A.32
B.60
C.27
D.29
Answer: B.60
Explanation: Let the number of boys be x.
Number of girls is 120 - x.
Total number of chocolates received by boys and girls = 2x + 3(120 - x) = 300
=> 360 - x = 300 => x = 60.
So, the number of boys or girls is 60.
Answer: B
Question: The time it took car P to travel 750 miles was 2 hours less than the time it took car R to travel the same distance. If car P’s average speed was 10 miles per hour greater than that of car R, what was car R’s average speed, in miles per hour?
A.40
B.56
C.60
D.70
Answer: B.56
Explanation: Let speed of car R be=x
Then speed of car P= x+10
A/Q,
(750/x)-(750/(x+10))=2
Solving for x=56 miles\hr.
B
Question: How many 2's are there between the terms 112 to 375?
A.156
B.157
C.158
D.159
Answer: A.156
Explanation: Let us calculate total 2's in the units place. (122, 132, 142 ... 192), (201, 212, 222, ... 292), (302, 312, ... 372) = 8 + 10 + 8 = 26
Total 2's in tenth's place, (120, 121, 122, ..., 129) + (220, 221, ..., 229) + (320, 321, ..., 329) = 30
Total 2's in hundred's place = (200, 201, ... 299) = 100.
Total 2's between 112 and 375 = 26 + 30 + 100 = 156
Answer:A
Question: If 12 men and 16 boys can do a piece of work in 5 days; 13 men and 24 boys can do it in 4 days, then the ratio of the daily work done by a man to that of a boy is?
A.2:1
B.2:98
C.2:2
D.2:9
Answer: A.2:1
Explanation: Let 1 man's 1 day work = x and 1 boy's 1 day work = y.
Then, 12x + 16y = 1/5 and 13x + 24y = 1/4
Solving these two equations, we get:
x = 1/100 and y = 1/200
Required ratio = x:y = 1/100 : 1/200 = 2:1.
Answer: A
Question: Plane leaves from Chelsea every 50 minutes from West Ham airport. Air hostess told Frank Lampard that the plane had left 25 minutes ago and the next plane for Chelsea will leave at 7:00 p.m.
At what time air hostess convey this information to Frank Lampard?
A.5:35 p.m
B.6:35 p.m
C.7:35 p.m
D.8:35 p.m
Answer: B.6:35 p.m
Explanation: Solution:
6:35 pm
Explanation:
Time of Frank Lampard last missed plane = 7:00 p.m - 50 min = 6:10 p.m
As this information has been given to Frank Lampard 15 minutes after the plane has already left, the air hostess gave the information at 6:10 p.m + 25 min = 6:35 p.m
Answer B
Question: A certain population of bacteria doubles every 10 minutes. If the number of bacteria in the population initially was 10^5, then what was the number in the population 1 hour later?
A.2(10^5)
B.6(10^5)
C.(2^6)(10^5)
D.(10^6)(10^5)
Answer: C.(2^6)(10^5)
Explanation: x bacteria would become 2x in 10 mins, which would become 4x in the next 10 (total 20 mins)...
So in 60 mins x becomes 2^6 times into x
Therefore Answer is C, (2^6)(10^5)
Question: How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 30 m long and 16 1/2 m board?
A.99
B.88
C.77
D.65
Answer: A.99
Explanation: 30 * 33/2 = 5/2 * 2 * x => x = 99
Answer: A
Question: Anil spends 40% of his income on rent, 30% of the remaining on medicines and 20% of the remaining on education. If he saves Rs. 840 every month, then find his monthly salary?
A.Rs. 1800
B.Rs. 2000
C.Rs. 2200
D.Rs. 2500
Answer: D.Rs. 2500
Explanation: Let's Anil's salary be Rs. 100.
Money spent on Rent = 40% of 100 = Rs. 40.
Money spent on medical grounds = 30% of (100 - 40) = 3/10 * 60 = Rs. 18.
Money spent on education = 20% of (60 - 18) = 1/5 * 42 = Rs. 8.40
Anil saves 100 - (40 + 18 + 8.40) i.e., Rs. 33.60
for 33.6 ---> 100 ; 840 ---> ?
Required salary = 840/33.6 * 100 = Rs. 2500
ANSWER:D
Question: The ratio of men to women in a class is 4 to 3. If 4 men drop out of the class and the ratio of men to women after the drop out is 10 to 9, then how many women are currently in the class?
A.14
B.16
C.18
D.20
Answer: C.18
Explanation: Equation on the basis of question
4x-4/3x=10/9
x=6
Original number of men = 4*6=24
Original Number of Women = 3*6=18 (Answer)
Current number of men = 24-4=20
Current number of women = 18
Ratio = 20/18= 10/9 ( Just to verify)
Ans C
Question: Working together, Tim and Tom can type 12 pages in one hour. If they would be able to type 14 pages in one hour if Tom increases his typing speed by 25%, what is the ratio of Tom's normal typing speed to that of Tim?
A.2/1
B.1/2
C.1/3
D.4/1
Answer: A.2/1
Explanation: Lets say Tim types x pages an hour and Tom types y pages an hour.
We know that x+y=12
Tom increase speed by 25% means he will type 1.25y pages an hour.
So we get x+1.25y=14
We need to know the ratio of Tom's speed to Tim's speed. This is going to be proportional to the number of pages each can type in an hour, hence (y/x).
Subtracting both : 0.25y=2 so y=8 ... so x=4
(y/x)=8/4 =2/1
Answer is (A)
Question: A person got Rs.52 more when he invested a certain sum at compound interest instead of simple interest for two years at 7% p.a. Find the sum?
A.10612
B.11234
C.10678
D.2667
Answer: A.10612
Explanation: P = (d * 1002) / R2
=> (52 * 100 * 100) / 7 * 7 = Rs.10612
Answer:A
Question: Find the average of first 4 multiples of 11?
A.10
B.12.6
C.27.5
D.31.3
Answer: C.27.5
Explanation: average = (11+22+33+44)/4 = 27.5
Answer is C
Question: From a square piece of a paper having each side equal to 10 cm, the largest possible circle is being cut out. The ratio of the area of the circle to the area of the original square is nearly :
A.4⁄5
B.3⁄5
C.5⁄6
D.6⁄7
Answer: A.4⁄5
Explanation: Area of the square = (10)2 = 100 cm2
Area of the circle = 22⁄7 × (5)2 = 22×25/7
Required ratio = 22×25/7×100=22/28=11/14
= 0.785 ≈ 0.8 = 4⁄5
Answer A
Question: A shop owner sells 50mtr of cloth and gains SP of 10 mtrs. Find the gain %?
A.25%
B.40%
C.50%
D.60%
Answer: A.25%
Explanation: Here, selling price of 10 m cloth is obtained as profit.
Profit of 10 m cloth = (S.P. of 50 m cloth) – (C.P. of 50 m cloth)
Selling price of 40 m cloth = Selling Price of 50 m of cloth
Let cost of each metre be Rs. 100.
Therefore, cost price of 40 m cloth = Rs. 4000 and S.P. of 40 m cloth = Rs. Rs. 5000
Profit% = 10/40 × 100 = 25%
Profit of 25% was made by the merchant.
A
Question: If |m+5|−5 = m, which of the following must be true?
A.m = 0
B.m = −10
C.m is a multiple of 5.
D.m ≥ −5
Answer: D.m ≥ −5
Explanation: Case 1 : |m+5| = 0, then m= -5
|-5+5|−5 = -5 --> true
Case 2; |m+5| < 0, then m< -5
|m+5|−5 = -m - 5 -5 = m , then m = -5 --> false
Case 3: Case 2; |m+5| > 0, then m> -5
|m+5|−5 = m+5 -5 = m , then m = m --> always true
Only case 1 and 3 satisfy the equation, so D is the answer.
Question: If 0 < m < 1 < n< 7, which of the following must be less than 1? I.m/n II. mn III. n - m
A.II,III only
B.I,III only
C.I only
D.III only
Answer: C.I only
Explanation: n > 1. So, option II, III is not possible.
So, Option I is correct.
Answer : C
Question: there are 6 elements and few are a ,b,c,d.find permutation and combination?
A.350,15
B.360,15
C.370,15
D.380,15
Answer: B.360,15
Explanation: 6p4 =3*4*5*6=360
6c4=15
ANSWER:B