RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: How many multiples of 5 are there between 5 to 85?
A.15
B.18
C.17
D.none of these
Answer: A.15
Explanation: Explanation :
As you know, multiples of 5 are integers having 0 or 5 in the digit to the extreme right (i.e. the units place).
So the numbers are 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80.
Answer : A
Question: Divide 71 into 2 parts such that 1 part exceeds the other by 8. What are the 2 no.'s in that part?
A.26
B.30
C.31
D.34
Answer: C.31
Explanation: Let $let n$ be the smaller and 71 - n be the larger number. Now, since the larger number exceeds the smaller number by 7, we can form the equation
larger number – smaller number = 7
which is equivalent to
Simplifying, we have 71 - 2n = 7. This gives us 2n = 78 which implies that the larger number is . The smaller is 71-39=31.
C
Question: A can do a work in 15 days and B in 20 days. If they work on it together for 5 days, then the fraction of the work that is left is
A.8/17
B.7/15
C.3/15
D.5/12
Answer: D.5/12
Explanation: Person ( A ) ( B ) ( A+B )
Time - ( 15 ) ( 20 ) (-)
Rate - ( 20 ) ( 15 ) ( 35 )
Work -(300) (300) (300)
therefore A+B requires (300/35) days to complete entire work
For 1st 5 days they work 35 * 5 = 175
Remaining work is 300 - 175 = 125
Remaining fraction of work is = 125/300 = 5/12
Answer D
Question: What is the value of 3x^2 − 1.8x + 0.8 for x = 0.6?
A.−0.3
B.0.8
C.0.3
D.1.08
Answer: B.0.8
Explanation: 3x^2-1.8x+0.8 for x=0.6
=3(0.6*0.6)-3*0.6*(0.6)+0.8
=0+0.8
=0.8
ANSWER:B
Question: The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is ?
A.7 kmph
B.6 kmph
C.4 kmph
D.3 kmph
Answer: B.6 kmph
Explanation: Explanation:
Speed of the stream = 1
Motor boat speed in still water be = x kmph
Down Stream = x + 1 kmph
Up Stream = x - 1 kmph
[35/(x + 1)] + [35/(x - 1)] = 12
x = 6 kmph
Answer: B
Question: In how many ways can 5 letters be posted in 3 post boxes, if any number of letters can be posted in all of the three post boxes?
A.5 C 3
B.5 P 3
C.5(3)
D.3(5)
Answer: D.3(5)
Explanation: Explanatory Answer
Sampling with replacement
The first letter can be posted in any of the 3 post boxes. Therefore, we have 3 possibilities.
Similarly, the second, the third, the fourth and the fifth letter can each be posted in any of the 3 post boxes.
Each of the 5 letters has 3 possibilities because we can post any number of letters in all of the boxes.
Therefore, the total number of ways the 5 letters can be posted in 3 boxes is 3 * 3 * 3 * 3 * 3 = 3(5)
Choice D
Question: -84x29+365=?
A.2436
B.2801
C.-2801
D.-2071
Answer: D.-2071
Explanation: Given exp.=-84x(30-1)+365
=-(84x30)+84+365
=-2520+449
=-2071
Answer is D
Question: In a certain mathematical activity, we start with seven cards, each with a different prime number written on it. These seven cards are randomly put into three boxes in the following way: one box must get four cards, one must get two, and one gets only one. Then, for each box, we find the product of all the cards in the box, and that’s the “number” of the box. Then, we put those three numbers in order, from lowest to highest, and that is our set. How many different sets R can be created from this process?
A. 35
B. 105
C. 210
D. 420
Answer: B. 105
Explanation: R=7C4 * 3C2 = 105 Answer B.
7C4 ways to choose 4 numbers for Box 1
3C2 ways to choose 2 numbers for Box2
1 way for Box 3 .
every combination will give a different product and can be arranged least to highest only in one way .B
Question: 48 gallon solution of salt and water is 10% salt. How many gallons of water must be added to the solution in order to decrease the salt to 8% of the volume?
A.8
B.12
C.13
D.14
Answer: B.12
Explanation: Amount of salt = 4.8
Assume x gallons of water are added.
4.8 / 48 + x = 8/100
480 = 8x + 384
8x = 96
x = 12
Correct Option: B
Question: Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
A.15
B.15.7
C.19.7
D.19.2
Answer: C.19.7
Explanation: Let the amount taxable purchases be Rs. x.
Then, 6% of x =30/100
x =(	(30/100)x(100/6) )= 5.
Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70
ANSWER C
Question: If a and b are positive real numbers, and a^3 + b^3 = 20, then the greatest possible value of a is between:
A.0 and 3
B.3 and 4
C.4 and 5
D.5 and 7
Answer: A.0 and 3
Explanation: If a > 3, then a^3 + b^3 > 20.
The answer is A.
Question: In how many ways can 5 letters be posted in 3 post boxes, if any number of letters can be posted in all of the three post boxes?
A.3
B.9
C.35
D.25
Answer: C.35
Explanation: The first letter can be posted in any of the 3 post boxes. Therefore, we have 3 possibilities.
Similarly, the second, the third, the fourth and the fifth letter can each be posted in any of the 3 post boxes.
Each of the 5 letters has 3 possibilities because we can post any number of letters in all of the boxes.
Therefore, the total number of ways the 5 letters can be posted in 3 boxes is
3 * 3 * 3 * 3 * 3 = 35
Option C
Question: In a class, there are 21 boys who are over 160 cm tall. If these constitute three-fourths of the boys and the total number of boys is two-thirds of the total number of students in the class, what is the number of girls in the class ?
A.8
B.14
C.18
D.24
Answer: B.14
Explanation: Explanation:
Let the number of boys be x. Then, (3/4)x = 21 or x = 21 x(4/3) = 28.
If total number of students is y, then (2/3) y = 28 or y = 28 x (3/2) = 42.
Therefore Number of girls in the class = (42 - 28) = 14.
Answer: B
Question: On a wedding catering service, An experienced chef can prepare a service for a wedding in 6 hours while an novice chef would finish the preparations in 7 hours.
If the catering service employs the same number of novice and experienced chefs, then how many chefs would it take to prepare a wedding service in 1 hour and 36 minutes?
A.2
B.3
C.4
D.6
Answer: C.4
Explanation: Experienced chefs work = 1 wedding/6 hours
Novice chefs work = 1 wedding/7 hours
Since we don't know the number of experienced or novice chefs but know that there is an equal number each, let the number of chefs for each group equalx
1hr and 36mins = 8/5 an hour
x/6 + x/7 = 1 wedding / (8/5)
x/6 + x/7 = 5/8
x=2
So there are 2 novice chefs and 2 experienced chefs. In total there are 4. The answer is C.
Question: If (x+3)^2/(2x+15)=3, then the difference between the two possible values of x is:
A.8
B.10
C.12
D.14
Answer: C.12
Explanation: (x+3)^2/(2x+15)=3
(x+3)^2=3(2x+15)
x^2+6x+9=6x+45
x^2-36=0
(x-6)(x+6)=0
x=6 or x=-6
The answer is C.
Question: In how many ways a committee consisting of 5 men and 6 women can be formed from 8 men and 10 women?
A.266
B.86400
C.11760
D.5040
Answer: C.11760
Explanation: Here, 5 men out of 8 men and 6 women out of 10 women can be chosen in
8C5 × 10C6 ways, i.e., 11760 ways.
Answer C
Question: Excluding stoppages, the speed of a train is 55 kmph and including stoppages it is 30 kmph. Of how many minutes does the train stop per hour?
A.82
B.27
C.12
D.82
Answer: B.27
Explanation: Explanation:
T = 25/55 * 60 = 27
Answer: Option B
Question: Find the remainder when 32^33^34 is divided by 11
A.22
B.10
C.99
D.76
Answer: B.10
Explanation: So 32103210 gives remainder 1.
Now we have to write 32^33^34 in this format. So we have to find the remainder 33^34 when divided by 10. The remainder is nothig but unit digit of the number. Click here to learn this concept
33^34 gives unit digit of 9.
So 33^34 = 10 K + 9
323334=32(10K+9)=(3210)K.329323334=32(10K+9)=(3210)K.329
Now this expression when divided by 11 leaves a remainder of 329329 which inturn is equal to (−1)9=−1=10
Answer:B
Question: In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C is
A.33
B.10
C.88
D.37
Answer: B.10
Explanation: 10 points
Answer: B
Question: Johnson has a corporate proposal. The probability that vice-president Adams will approve the proposal is 0.6. The probability that vice-president Baker will approve the proposal is 0.5. The probability that vice-president Corfu will approve the proposal is 0.4. The approvals of the three VPs are entirely independent of one another.
Suppose the Johnson must get VP Adam’s approval, as well as the approval of at least one of the other VPs, Baker or Corfu, to win funding. What is the probability that Johnson’s proposal is funded?
A.0.49
B.0.42
C.0.45
D.0.48
Answer: B.0.42
Explanation: probability of adams approval = 0.6
baker approval =0.5
corfu approval=0.4
proabability of approval is must adam approval and atleast one approval
= adam approval*baker approval*corfu approval(approval of both remaining)+adam approval*baker approval*corfu not approval(atleast one remaining approval)+
adam approval*baker not approval*coffu approval( atleast one remaining approval
= 0.6*0.5*0.4+0.6*0.5*0.6+0.6*0.5*0.4
=0.12+0.18+0.12
=0.42
B
Question: What is the place value of 3 in the numeral 2734?
A.45
B.30
C.43
D.56
Answer: B.30
Explanation: Option 'B'
3 * 10 = 30
Question: A alone can complete a work in 16 days and B alone can do in 12 days. Starting with A, they work on alternate days. The total work will be completed in
A.13 1/4
B.13 1/2
C.13 3/4
D.13 4/4
Answer: C.13 3/4
Explanation: Explanation:
A's 1 day work = 1/16
B's 1 day work = 1/12
As they are working on alternate day's
So their 2 days work = (1/16)+(1/12)
= 7/48
[here is a small technique, Total work done will be 1, right, then multiply numerator till denominator, as 7*6 = 42, 7*7 = 49, as 7*7 is more than 48, so we will consider 7*6, means 6 pairs ]
Work done in 6 pairs = 6*(7/48) = 7/8
Remaining work = 1-7/8 = 1/8
On 13th day it will A turn,
then remaining work = (1/8)-(1/16) = 1/16
On 14th day it is B turn,
1/12 work done by B in 1 day
1/16 work will be done in (12*1/16) = 3/4 day
So total days =
13 3/4
Option C
Question: Find the average of all prime numbers between 30 and 50
A.15
B.42
C.45
D.34
Answer: B.42
Explanation: Prime numbers between 30 and 50 are 37, 41, 43, 47
Required average = (37+ 41+ 43+ 47)/4 = 168/4 = 42
Answer is B
Question: For 6-digit integer 46x,y12, when x and y are drawn at random from {3,5,8}, what is the probability Q that the integer drawn is divisible by 8?
* A solution will be posted in two days.
A.1/6
B.1/3
C.1/2
D.2/3
Answer: D.2/3
Explanation: In general, the remainder divided by integer n is the same as the remainder that up to tens of n is divided by 8.
Thus, in order for 46,x,y12 to be divided by 8, y12 should be divided by 8.
Amongst 3,5,8, 3 and 5 can be divided by 8.
Therefore, Q=two out of three can be divided and the answer is D.
Question: A certain roller coaster has 4 cars, and a passenger is equally likely to ride in any 1 of the 4 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 4 times, what is the probability that the passenger will ride in each of the 4 cars?
A.0
B.1/9
C.2/9
D.3/32
Answer: D.3/32
Explanation: If he is to ride 4 times and since he can choose any of the 4 cars each time, total number of ways is
= 4 * 4 * 4 * 4
= 256
Now the number of ways if he is to choose a different car each time is
= 4* 3 * 2 * 1
= 24
So the probability is
= 24/256 =6/64=3/32
= 3/32
Answer : D
Question: A shopkeeper buys mangoes at the rate of 4 a rupee and sells them at 3 a rupee. Find his net profit or loss percent?
A.33 1/6
B.33 1/0
C.33 1/3
D.33 1/5
Answer: C.33 1/3
Explanation: The total number of mangoes bought by the shopkeeper be 12.
If he buys 4 a rupee, his CP = 3
He selling at 3 a rupee, his SP = 4
Profit = SP - CP = 4 - 3 = 1
Profit Percent = 1/3 * 100 = 33 1/3 %.Answer:C
Question: In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1200 employees, then the no. of female employees who are computer literate ?
A.504
B.674
C.672
D.960
Answer: A.504
Explanation: Solution: Total employees,
= 1200
Female employees, 60% of 1200.
= (60 *1200) /100 = 720.
Then male employees,
= 480
50 % of male are computer literate,
= 240 male computer literate.
62 % of total employees are computer literate,
= (62 *1200) /100 = 744 computer literate.
Thus, Female computer literate = 744 - 240
= 504.
Answer: Option A
Question: 10 liters are drawn from a cask full of wine and is then filled with water. This operation is performed one more time . The ratio of the quantity of wine now left in cask to that of the water is 4:5. How much wine did the cask hold originally?
A.10
B.20
C.30
D.45
Answer: C.30
Explanation: Let the quantity of wine in the cask originally be x liters
quantity of wine left in cask after 2 operations = x(1 - 10/x)^2 liters
x(1 - 10/x)^2 /x = 4/9
(1-10/x)^2 = (2/3)^2
x = 30
Answer is C
Question: What is the units digit of (493) (915) (381) (756) (28)
A.0
B.1
C.4
D.5
Answer: B.1
Explanation: Just multiply the digits in the units place for each term and you will get the answer. It should be 0. you got a 5 as a unit digit and an even number term. so the multiplication of this will definitely yield a 0. Answer has to be 0.
I also tried it using the calculator and the answer is 1.
IMO B.
Question: Look at this series: 25000,5000,1000, ... What number should come next?
A.17
B.10
C.15
D.200
Answer: D.200
Explanation: 200
This is a simple division series. Each number is divided by 5.
ANSWER D
Question: How much time will a train of length 380 m moving at a speed of 72 kmph take to cross another train of length 540 m, moving at 36 kmph in the same direction?
A.50
B.99
C.88
D.92
Answer: D.92
Explanation: The distance to be covered = Sum of their lengths = 380 + 540 = 920 m.
Relative speed = 72 -36 = 36 kmph = 36 * 5/18 = 10 mps.
Time required = d/s = 920/10 = 92 sec.
Answer:D
Question: A work could be completed in 100days by x workers. However, due to the absence of 10workers, it was completed in 110days. The original no.of workers was:
A.90
B.100
C.110
D.130
Answer: C.110
Explanation: sax Letlheo g alnumberofworkers hex
x workers can do the wor - 100 days
(x — 10) workers can do the work in 110 days
4 100x 1u1x— 10)
1100 Q x 110
C
Question: An engineer designed a ball so that when it was dropped, it rose with each bounce exactly one-half as high as it had fallen. The engineer dropped the ball from a 16-meter platform and caught it after it had traveled 45 meters. How many times did the ball bounce?
A.5
B.4
C.7
D.8
Answer: B.4
Explanation: Going down = 16 m
Going Up = 8 --> Total = 24
Going down = 8 --> Total = 32
Going Up = 4 --> Total = 36
Going down = 4 --> Total = 40
Going up = 2 --> Total = 42
Going down = 2 --> Total = 44
Going up = 1 --> Total = 45 (Caught)
No of bounce = 4
Answer : B
Question: Statement : Until our country achieves economic equality, political freedom and democracy would be meaningless.
Conclusions :
I. Political freedom and democracy go hand in hand.
II. Economic equality leads to real political freedom and democracy.
A. I only
B. II only
C. I and II only
D. I and III only
Answer: B. II only
Explanation: Explanation:
Nothing about first conclusion is stated in statement.
Only II conclusion follows.
(B) II only
Question: What is the value of 28^2 + 29^2 + 30^2 + 31^2 + 32^2 ?
A.4298
B.4508
C.4510
D.4528
Answer: C.4510
Explanation: This is what I did, all the nos are close to 30, and squared, so 30^2 plus there are 5 numbers, so (30)^2 x 5 =4500,
now squaring the last digits of each no individually comes up to (4+1+0+1+4) = 10.
when you add the 2 up it gives you a (4500+10) =4510,
Answer is C.
Question: If three numbers are added in pairs, the sums equal 10, 19 and 21. Find the numbers
A.6, 4, 15
B.7, 8, 6
C.5, 15, 45
D.12, 8, 13
Answer: A.6, 4, 15
Explanation: Let the numbers be x, y and z. Then,
x+ y = 10 ...(i) y + z = 19 ...(ii) x + z = 21 …(iii)
Adding (i) ,(ii) and (iii), we get: 2(x + y + z ) = 50 or (x + y + z) = 25.
Thus, x= (25 - 19) = 6; y = (25 - 21) = 4; z = (25 - 10) = 15.
Hence, the required numbers are 6, 4 and 15.
Answer A)6, 4, 15
Question: If d=1/(2^3*5^6) is expressed as a terminating decimal, how many nonzero digits will d have?
A.One
B.Two
C.Three
D.Seven
Answer: A.One
Explanation: Another way to do it is :
We know x^a*y^a=(X*Y)^a
given = 1/(2^3*5^6)
= Multiply and divide by 2^3
=2^3/(2^3*2^3*5^6)
=2^3/10^6
=> non zero digits are 8 => Ans A
Question: Three cows work to fill a tub at at different rate. Hose A and B, working together, can fill the tub in 3/5 of an hour. Hoses A and C can fill it in 1/2 an hour. Houses B and C can fill it in 2 hours. How long does it take all 3 cows, working together, to fill the tub?
A.3/10
B.2/5
C.6/11
D.1
Answer: C.6/11
Explanation: We have ,in 1 hourwhen two hose working together can fill the tub as follow:
1/a + 1/b = 1/3/5 of the work
1/a + 1/c = 1/1/2 of the work
1/b + 1/c = 1/2 of the work
=>Get total both sides we got : 2(1/a +1/b +1/c) = 10+30+15/30 of the work
or 1/a +1/b +1/c = 55/30=11/6 of the work
Calculate total amount of time taken when three hoses work together 11/6 = 6/11
C
Question: How many of the positive factors of 24 , 16 and how many common factors are there in numbers?
A.1
B.2
C.3
D.4
Answer: D.4
Explanation: factors of 24 - 1, 2, 3, 4, 8, 12 and 24
factors of 16 - 1 , 2, 4, 8 and 16
Comparing both, we have three common factors of 45,16-4
Answer D
Question: If {x} is the product of all even integers from 1 to x inclusive, what is the greatest prime factor of {22} + {20}?
A.23
B.20
C.11
D.5
Answer: A.23
Explanation: Soln:
{22} + {20} = 22*{20} +{20} = 23*{20}
ANSWER:A
Question: The total car population in a Mumbai is 2,94,00 out of which 1,50,00 are made by Honda. Out of every 100 Honda cars, 98 are red in color, but only 53% of the total car population is red. Find the % of non-Honda cars that are red
A.5%
B.6%
C.6.125%
D.7.12%
Answer: C.6.125%
Explanation: Total Car.29.10 i.e., Honda +non Honda = 29400 Given: Whim. tractor .150W
Now,5346 of 2..00 = Honda +Red Non-Honda 29400 .:4 =15582 Thus...El Mall... 1.0 Now Honda 15582 flow, Non-. Honda =15582 - 15.582-14700=8B2 96 non-Honda =1=1.100 = 6.125%
C
Question: Jack and Christina are standing 150 feet apart on a level surface. Their dog, Lindy, is standing next to Christina. At the same time, they all begin moving toward each other. Jack walks in a straight line toward Christina at a constant speed of 7 feet per second and Christina walks in a straight line toward Jack at a constant speed of 8 feet per second. Lindy runs at a constant speed of 10 feet per second from Christina to Jack, back to Christina, back to Jack, and so forth. What is the total distance, in feet, that Lindy has traveled when the three meet at one place?
A.40
B.60
C.80
D.100
Answer: D.100
Explanation: The relative speed of Jack and Christina is 7 + 8 = 15 feet per second.
The distance between them is 210 feet, hence they will meet in (time) = (distance)/(relative speed) = 150/15 = 10 seconds.
For all this time Lindy was running back and forth, so it covered (distance) = (speed)*(time) = 10*10 = 100 feet.
Answer: D.
Question: A money lender finds that due to a fall in the annual rate of interest from 8% to 7 3/4 % his yearly income diminishes by Rs. 61.50, his capital is?
A.24,602
B.28,888
C.24,600
D.24,628
Answer: C.24,600
Explanation: Let the capital be Rs. x. Then,
(x * 8 * 1)/100 - (x * 31/4 * 1/100) = 61.50
32x - 31x = 6150 * 4
x = 24,600.
Answer: C
Question: A glass was filled with 12 ounces of water, and 0.03 ounce of the water evaporated each day during a 22-day period. What percent of the original amount of water evaporated during this period?
A.5.002%
B.5.5%
C.0.5%
D.5%
Answer: B.5.5%
Explanation: In 22 days 22*0.03=0.66 ounces of water evaporated, which is 0.66/12âˆ—100=5.5 of the original amount of water.
Answer: B.
Question: A, B, and C working alone can finish constructing a house in 4, 8, and 12 hours respectively. A starts alone and works for 1 hour. He is then joined by B and they work together for 1 hour. Finally C joins them and they all work together to finish the work. If they start working at 9 am, at what time will they finish?
A.11:12 am
B.11:32 am
C.11:49 am
D.12:07 pm
Answer: C.11:49 am
Explanation: A completes 1/4 of the job each hour.
B completes 1/8 of the work each hour.
C completes 1/12 of the work each hour.
A completes 1/4 of the work in the first hour.
Working together, A and B complete another 3/8 for a total of 5/8.
Working together, A, B, and C can complete 11/24 of the work each hour.
To complete 3/8, the time required is (3/8) / (11/24) = 9/11 hours.
The work will be completed at 11:00 plus 9*60/11 minutes which is about 11:49 am.
The answer is C.
Question: 331, 482, 551, 263, 383, 242, 111
A.263
B.383
C.242
D.111
Answer: B.383
Explanation: Solution
In each number except 383,the product of first and third digits is the middle one. Answer B
Question: An alloy of zinc and copper contains the metals in the ratio 5 : 3. The quantity of zinc to be added to 6 kg of the alloy so that the ratio of the metal may be 3 : 1 is:
A.2
B.9
C.8
D.7
Answer: C.8
Explanation: Explanation:
In sixteen kg of alloy 10 kg of zinc and 6 kg copper is present
To make the ratio 3:1 we must add 8 kg of zinc to make it 18 kg of zinc and 6 kg copper
So answer is 8.
Answer: C
Question: I. a3 - 988 = 740,
II. b2 - 72 = 72 to solve both the equations to find the values of a and b?
A.a > b
B.a ≥ b
C.a < b
D.a ≤ b
Answer: B.a ≥ b
Explanation: a3 = 1728 => a = 12
b2 = 144 => b = ± 12
a ≥ b
ANSWER:B
Question: If 3a – 3b – 2c = 32 and √3a-√(2b+2c)=4, what is the value of a + b + c?
A.3
B.9
C.10
D.12
Answer: C.10
Explanation: when we look at the two equations, we can relize some similarity, so lets work on it..
3a – 2b – 2c = 32 can be written as √3a^2-√(2b+2c)^2=32
{√3a-√(2b+2c)}{√3a+√(2b+2c)}=32..
or 4*√3a+√(2b+2c)=32..
or √3a+√(2b+2c)=8..
now lets work on these two equations
1)√3a-√(2b+2c)=4..
2)√3a+√(2b+2c)=8..
A) add the two eq..
√3a+√(2b+2c)+√3a-√(2b+2c)=12..
2√3a=12..
or √3a=6..
3a=36..
a=12.
B) subtract 1 from 2..
√3a+√(2b+2c)-√3a+√(2b+2c)=4..
2√(2b+2c)=4..
√(2b+2c)=2..
2b+2c=4..
or b+c=2..
from A and B a+b+c=12+2=14..
C
Question: The price of an item is discounted 10 percent on day 1 of a sale. On day 2, the item is discounted another 10 percent, and on day 3, it is discounted an additional 5 percent. The price of the item on day 3 is what percentage of the sale price on day 1?
A.28%
B.40%
C.85.5%
D.70%
Answer: C.85.5%
Explanation: original price = 100
day 1 discount = 10%,price = 100-10 =90
day 2 discount = 10%,price = 90-9=81
day 3 discount = 5%,price = 81-4.05= 76.95
which is 76.95/90 *100 of the sale price on day 1= ~8
Answer C
Question: The average monthly income of P and Q is Rs. 6050. The average monthly income of Q and R is Rs. 7050 and the average monthly income of P and R is Rs. 8000. The monthly income of P+Q+R is:
A.41100
B.42000
C.21100
D.42200
Answer: C.21100
Explanation: Explanation:
Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (6050 x 2) = 12100 .... (i)
Q + R = (7050 x 2) = 14100 .... (ii)
P + R = (8000 x 2) = 16000 .... (iii)
Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 42200 or P + Q + R = 21100 .... (iv)
(P+Q+R)'s monthly income = Rs. 21100.
Answer: C
Question: $600 will become $720 in 4 years find the rate of interest?
A.10%
B.15%
C.5%
D.7%
Answer: C.5%
Explanation: SI = simple interest = A-P = 720-600 = $120
R = 100SI/PT = 100*120/600*4 =5%
Answer is C
Question: Hardy and Andy start a two-length swimming race at the same moment but from opposite ends of the pool. They swim in lanes at uniform speeds, but Hardy is faster than Andy. They 1st pass at a point 18.5m from the deep end and having completed one length each 1 is allowed to rest on the edge for exactly 50 sec. After setting off on the return length, the swimmers pass for the 2nd time just 10.5m from the shallow end. How long is the pool?
A.65
B.25
C.35
D.45
Answer: D.45
Explanation: let x=length of pool
at first meeting, combined distance=x
at second meeting, combined distance=3x
if andy swims 18.5 m of x, then he will swim 3*18.5=55.5 m of 3x
andy's total distance to second meeting=x+10.5 m
x+10.5=55.5 m
x=45 m
D