RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A and B started business in partnership investing Rs. 20,000 and Rs. 15,000 respectively. After six months, C joined them with Rs. 20,000. What will be B's share in the total profit of Rs. 25,000 earned at the end of 2 years from the starting of the business?
A.7500
B.4366
C.2877
D.2768
Answer: A.7500
Explanation: A:B:C = (20000 * 24) : (15000 * 24) : (20000 * 18) = 4:3:3
B's share = 25000 * 3/10
= Rs. 7500.
Answer: A
Question: The area of a square field is 28808 sq m. How long will a lady take to cross the field diagonally at the rate of 7.2 km/hr?
A.2.5 min
B.3 min
C.2 min
D.4 min
Answer: C.2 min
Explanation: Area of a square field = 28808 sq m
Let the side of square = a
a^2 = 28808
=> a = 169.73
Diagonal = (2)^(1/2) * a
= 1.414 * 169.73
=240
Speed of lady = 7.2 km / hour
= 7200 m / hour
= 120 m / min
Time taken by lady to cross the field diagonally = 240/120 = 2 min
Answer C
Question: A rectangular table seats 7 people on each of two sides, with every person directly facing another person across the table. If 14 people choose their seats at random, what is probability that person P directly faces person Q?
A.1/10
B.1/11
C.1/12
D.1/13
Answer: D.1/13
Explanation: Person P will be seated somewhere at the table.
Each of the other 13 people has an equal chance of sitting opposite person P.
The probability that person Q sits across is 1/13.
The answer is D.
Question: A man & his wife appear in an interview for 2vacancies in the same post. The probability of husband's selection is 1/7 & the probability of wife's selection is 1/5. What is the probability that only 1 of them is selected ?
A.1/3
B.2/3
C.2/7
D.3/11
Answer: C.2/7
Explanation: Let A = Event that the husband is selected and
B = Event that the wife is selected.
Then, P (A) = 1/7
and P(B) = 1/5
∴P(A¯) = (1 - 17/5) = 6/7
and
= (1 - 1/5) = 4/5
Required probability = P [(A and not B) or (B and not A)]
= P[(A and B¯) or (B and A¯)]
= P(A and B¯) + P(B and A¯)
= P(A).P(B¯) + P(B).P(A¯)
= (1/7* 4/5) + (1/5* 6/7)
= 10/35
= 2/7
C
Question: If a, t, and c are consecutive even integers and a < t < c, all of the following must be divisible by 4 EXCEPT
A.a + c
B.t + c
C.ac
D.(bc)/2
Answer: B.t + c
Explanation: I did get the correct answer within 80 seconds and it was not by luck either. I did not pick numbers but just used the concept stated by Ian.
The 3 numbers can be written as
a, (a + 2)(a + 4).
If 'a' is divisible by 4, then even 'c' or 'a + 4' is divisible by 4. However, is 'b' is divisible by 4, then both 'a' and 'a + 4' are still divisible by 2.
A - (a + c) = a + (a + 4) = 2a + 4 = 2(a + 2) = 2b. 2b will always be divisible by 4 even if 'b' is not divisible by 4. Reason: 'b' already has a prime factorization of at least a '2'. Hence '2b' has two 2s.
C - ac = a(a+4). If, as stated above, one of them is divisible by 4, then the product is divisible. If both of them are not divisible by 4, then the product is still divisible by 4 because of the presence of two 2s again in the prime factorization.
D - bc/2 = (a + 2)(a + 4)/2. Either b or c is divisible by 2. Hence, if we assume that b is divisible by 2 and not divisible by 4, then it leaves us just one possibility. Is c divisible by 4? It has to be because c is the next consecutive even integer.
E - atc/4 = a(a + 2)(a + 4)/4. One of these integers is divisible by 4 already. If we again assume 'b' to be that integer divisible by 4, then we are left with the question - Is a(a + 4) divisible by 4? This is the same as option C.
B - b + c = (a + 2) + (a + 4) = 2a + 6 = 2(a + 3). (a + 3) will never be divisible by 2 because it is an odd integer. Hence, 2(a + 3), although divisible by 2, will not be divisible by 4 because it has just one 2 in its prime factorization.
As a whole, whether you choose numbers (2, 46 being the easiest) or solve conceptually, the answer is still easily obtainable within 2 minutes.B
Question: The difference between a two digit number and the number obtained by interchanging the positions of its digit is 36. What is the difference between the two digits of that number?
A.3
B.4
C.9
D.8
Answer: B.4
Explanation: Let the ten’s digit be x
Unit’s digit be y
Then (10x+y)-(10y+x)=36
9(x-y)=36
x-y=4
Option B
Question: How many positive numbers not greater than 4300 can be formed using the digits 0,1,2,3,4 where repeatation is allowed?
A.576 numbers
B.575
C.620
D.640
Answer: A.576 numbers
Explanation: 1 digit = 5
2 digits = 4* 5 = 20
3 digits = 4*5*5= 100
Now,4 digit number till 4000 can have digits 1,2,3 in thousands place ( total choices = 3 )
0,1,2,3,4 in hundreds ,tens and ones place
I.e 3*5*5*5 = 375
Now From 4000 to 4299 = 1*3*5*5 =75
Total = 5+20+100+375+75+1 =576 (1 for 4300)
ANSWER:A
Question: A train crosses a platform of 200 m in 20 sec, same train crosses another platform of length 350 m in 25 sec. then find the length of the train?
A.150m
B.180m
C.400m
D.250m
Answer: C.400m
Explanation: Length of the train be ‘X’
X + 200/20 = X + 350/25
5X + 1000 = 4X + 1400
X = 400m
Answer:C
Question: The ratio of three numbers is 5:3:4 and their sum is 108. The second number of the three numbers is?
A.13
B.16
C.27
D.29
Answer: C.27
Explanation: 5:3:4
Total parts = 12
12 parts --> 108
1 part ---->9
The second number of the three numbers is = 3
3 parts ----> 27
C)
Question: A and B starts a business with Rs.8000 each, and after 4 months, B withdraws half of his capital . How should they share the profits at the end of the 16 months?
A.18:11
B.16:11
C.18:19
D.18:121
Answer: B.16:11
Explanation: A invests Rs.8000 for 16 months, but B invests Rs.8000 for the first 4 months and then withdraws Rs.4000. So, the investment of B for remaining 14 months is Rs.4000 only.
A : B
8000*16 : (8000*4) + (4000*14)
128000 : 88000
A:B = 16:11.Answer:B
Question: Worker A takes 10 hours to do a job. Worker B takes 12 hours to do the same job. How long it take both A & B, working together but independently, to do the same job?
A.40 days
B.40/9 days
C.60/11 days
D.30/9 days
Answer: C.60/11 days
Explanation: A's one hour work = 1/10.
B's one hour work = 1/12.
(A+B)'s one hour work = 1/10+1/12 = 11/60.
Both A & B can finish the work in 60/11 days
C
Question: The simple form of the ratio 4/2:2/5 is?
A.10:6
B.5:1
C.15:3
D.25:3
Answer: B.5:1
Explanation: 4/2 : 2/5 = 20:4 = 5:1
ANSWER:B
Question: What is the smallest no. which must be added to 8261955 so as to obtain a sum which is divisible by 11?
A.1
B.2
C.4
D.6
Answer: B.2
Explanation: For divisibility by 11, the difference of sums of digits at even and odd places must be either zero or divisible by 11.
For 8261955, Difference =(8+6+9+5) -(2+1+5)=28-8=20.
The units digit is at odd place. So we add 2 to the number
=> 8261955 +2 = 8261957
Now , (8+6+9+7) -(2+1+5)=30-8=22 => 22 is a multiple of 11 and hence 8261957 is also divisible by 11
B
Question: A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 700 m long?
A.94sec
B.90sec
C.85sec
D.80sec
Answer: A.94sec
Explanation: Speed = 240/24 = 10 m/sec.
Required time = (240 + 700)/10 = 94 sec.
Answer:A
Question: There are 5 cars to be displayed in 5 parking spaces with all the cars facing the same direction. Of the 5 cars, 3 are red, 1 is blue and 1 is yellow. If the cars are identical except for color, how many different display arrangements of the 5 cars are possible?
A.20
B.25
C.40
D.60
Answer: C.40
Explanation: I think the above logic is correct except one thing:
# of arrangements is 5!3!=205!3!=20.
But a car can be arranged facing TWO directions (within one particular parking space), so we should multiply 20 by 2, 20∗2=4020∗2=40
Answer: C.
Question: Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ?
A.17/26
B.17/29
C.17/24
D.17/20
Answer: D.17/20
Explanation: n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 - 1/20 = 17/20
Answer: D
Question: What is the banker's discount if the true discount on a bill of Rs.540 is Rs.90 ?
A.Rs. 108
B.Rs. 120
C.Rs. 102
D.Rs. 106
Answer: A.Rs. 108
Explanation: Explanation :
Present Worth, PW = F - TD = 540 - 90 = Rs. 450
Simple Interest on the Present Worth = True Discount
Hence Simple Interest on 450 = 90 ------(Equation 1)
Simple Interest on the face value = Bankers Discount
=> Simple Interest on 540 = Bankers Discount
From Equation 1, Simple Interest on 450 = 90
Hence, Simple Interest on 540 = 90/450×540=540/5 = Rs. 108
=> Bankers Discount = Rs. 108 Answer : Option A
Question: In one year, the population, of a village increased by 10% and in the next year, it decreased by 10%. If at the end of 2nd year, the population was 7920, what was it in the beginning?
A.3337
B.8000
C.2788
D.2999
Answer: B.8000
Explanation: x*110/100 * 90/100 = 7920
X*0.99=7920
X=7920/0.99
=> 8000
Answer: B
Question: During a trip, Francine traveled x percent of the total distance at an average speed of 40 miles per hour and the rest of the distance at an average speed of 80 miles per hour. In terms of x, what was Francine's average speed for the entire trip?
A.(180-x)/2
B.4800/x+60
C.(300-x)/5
D.600/(115-x)
Answer: B.4800/x+60
Explanation: total distance =100 ;total time = T
t1 = x/40 t2 = 100-x /80
T =t1+t2 = x/30 + 100-x/80 = (80x + 3000- 30x)/2400
= (50x+3000)/2400
= x +60 / 48
av speed = 100*48/x+60 = 4800/x+60
B
Question: The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years
A.7:8
B.7:9
C.3:8
D.5:8
Answer: A.7:8
Explanation: Explanation:
Let P age and Q age is 6x years and 7x years.
Then 7x - 6x = 4 <=> x = 4
So required ratio will be (6x+4): (7x+4) => 28:32 => 7:8
Answer: Option A
Question: Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
A.3 9 /17 hours
B.1 13 /17 hours
C.2 8 /11 hours
D.4 1 /2 hours
Answer: A.3 9 /17 hours
Explanation: Explanation:
Solution 1
Pipes A and B can fill the tank in 5 and 6 hours respectively. Therefore,
part filled by pipe A in 1 hour =1/5
part filled by pipe B in 1 hour =1/6
Pipe C can empty the tank in 12 hours. Therefore,
part emptied by pipe C in 1 hour =1/12
Net part filled by Pipes A,B,C together in 1 hour =1/5 +1/6+1/12 =17/60
i.e., the tank can be filled in 60/17=3 9/17 hours.
ANSWER IS A
Question: Simple interest on a certain sum is 9.8 over 20 of the sum. Find the rate per cent and time, if both are equal.
A.7% and 7 years
B.6% and 6 years
C.10% and 10 years
D.12 % and 12 years
Answer: A.7% and 7 years
Explanation: 9.8â„20 P = PÃ—RÃ—R/100
â‡’ R2 = 980â„20=49 â‡’ R = 7%
Also, time = 7 years
Answer A
Question: An businessman earns an income of Re 2 on the first day of his business. On every subsequent day, he earns an income which is just double of that made on the previous day. On the 20th day of business, he earns an income of:
A.21
B.22
C.36
D.20
Answer: C.36
Explanation: 2nd day he earns = 2(2 – 2)
3rd day he earns = 2(3 – 2)
On 20th day he earns 2(20 -2) = 36 rupees
ANSWER:C
Question: Walking 6/7th of his usual speed, a man is 12 minutes too late. The usual time taken by him to cover that distance is :
A.1 hr 20 min
B.1 hr 10 min
C.1 hr 11 min
D.1 hr 12 min
Answer: D.1 hr 12 min
Explanation: Sol.
New speed = 6/7 of usual speed.
New time = 7/6 of usual time
∴ [7/6 of usual time] - (usual time) = 1/5 hr.
⇒ 1/6 of usual time = 1/5 hr ⇒ usual time = 6/5 hr = 1 hr 12 min.
Answer D
Question: What is the least integer that is a sum of four different prime numbers each greater than 10?
A.60
B.62
C.64
D.66
Answer: A.60
Explanation: The sum of the four smallest primes greater than 10 is 11+13+17+19=60.
The answer is A.
Question: If you divide 7^93 by 5, which remainder do you get?
A.0
B.1
C.2
D.3
Answer: C.2
Explanation: The units digit of 7^1 is 7.
The units digit of 7^2 is 9.
The units digit of 7^3 is 3.
The units digit of 7^4 is 1.
The units digit of 7^5 is 7.
etc...
The units digit of 7^n repeats in blocks of 4: {7, 9, 3, 1}
The remainder of 93/4 is 1.
So the units digit of 7^93 is 7.
The remainder of 7^93 / 5 is 2.
The answer is C.
Question: The number of roots common between the two equations x3+3x2+4x+5=0x3+3x2+4x+5=0 and x3+2x2+7x+3=0x3+2x2+7x+3=0 is
A.22
B.27
C.13
D.88
Answer: C.13
Explanation: Here f(x) = x3+3x2+4x+5=0x3+3x2+4x+5=0 and g(x) = x3+2x2+7x+3=0x3+2x2+7x+3=0
To find the common roots we have to solve the equation f(x) - g(x) = 0
i.e. (x3+3x2+4x+5)(x3+3x2+4x+5) - (x3+2x2+7x+3)=0(x3+2x2+7x+3)=0
x2−3x+2=0x2−3x+2=0
x = 2, x = 1
These are the points of intersection f(x) and g(x). Whether these points are also the common root will have to be checked by putting these vales in f(x) = 0 and g(x) = 0.
For x = 2;
f(2) = g(2) = 43 ≠≠ 0. Hence 2 is not a common root but only a point of intersection.
For x = 1;
f(1) = g(1) = 13 ≠≠ 0. Again 1 is not a common root but a point of intersection. Hence, we find that the two equations do not have any common root between them.
Answer:C
Question: If a quality control check is made inspecting a sample of 2 light bulbs from a box of 8 lighbulbs, how many different samples can be chosen?
A.6
B.28
C.36
D.66
Answer: B.28
Explanation: Try using the formula for combinations:
n!/r!(n-r)!
8!/2!(8-2)!
8!/2!*6!
8*7/2*1
=28
B
Question: A boy want to make a cuboid of dimension 5m, 6m, 7m from small cubes of .04 m3. Later he realized he can make same cuboid by making it hollow. Then it takes some cubes less. What is the no. of these cubes?
A.2150
B.2250
C.2350
D.2850
Answer: B.2250
Explanation: volume of cuboid=5*6*7=210m3
volume of inner cuboid=(5-1)*(6-1)*(7-1)=120m3
therefore,volume of hollow cuboid=210-120=90 m3
no of cubes required=90/.04=2250 cubes
ANSWER:B
Question: If X,Y is 20%,25% greater than Z then how much percentage is X smaller than Y?
A.2
B.4
C.6
D.7
Answer: B.4
Explanation: X=120%
Y=125%
Z=100%
X-Y/Y*100 = 5/125*100
==>4%
ANSWER B
Question: A data set with a mean of 60 has a standard deviation of 8.7. Which of the following is the smallest number that falls within one standard deviation of the mean?
A.51
B.56
C.59
D.63.5
Answer: A.51
Explanation: One standard deviation of the mean is from{mean}-{deviation}=60-8.7=51.3 to{mean}+{deviation}=60+8.7=68.7. The smallest number within this range from the options is 51.
Answer: A.
Hope this helps.
Question: Anne traveled from City A to City B in 4 hours, and her speed was between 20 miles per hour and 40 miles per hour. John traveled from City A to City B along the same route in 2 hours, and his speed was between 45 miles per hour and 60 miles per hour. Which of the following could be the distance, in miles, from City A to City B?
A.95
B.115
C.125
D.160
Answer: B.115
Explanation: In four hours Anne must travel 4 times her speed
so Anne's possible distances =
4(20 -40) or 80-160 miles
in two hours John travels 2 times his speed or
2(45-60) or 90-120 miles
the statement is only true if both distances are possible,
so you can tell its between or equal to
90-120
B is the answer.
Question: At the time of marriage, a man was 6 years elder to his wife. 14 years after their marriage, his age is 8/7 times the age of his wife. What was wife's age at the time of marriage ? Choose one answer.
A.36 years
B.30 years
C.28 years
D.14 years
Answer: C.28 years
Explanation: let wifes age= x
husband age = x+6
now after 14 years of mrg x+14 wifes age
x+6+14 husbands age
8/7(x+14)=x+6+14
after solving x=28
ANSWER:C
Question: g(a) is defined as the product of all even integers k such that 0 < k ≤ x. For example, g(14) = 2 × 4 × 6 × 8 × 10 × 12 × 14. If g(y) is divisible by 4^11, what is the smallest possible value for a?
A. 22
B. 24
C. 28
D. 32
Answer: B. 24
Explanation: g(a)=4^11=2^22. So we have to find a product with atleast 22 2's in it.
in option 1 22 the total no of 2's = [22/2] + [22/4] +[22/8] +[22/16] = 11+5+2+1 = 19
in option 2 24 the total no of 2's = [24/2] + [24/4] +[24/8] +[24/16] = 12+6+3+1 = 22 . Hence B
Question: A merchant has 1000 kg of sugar part of which he sells at 8% profit and the rest at 18% profit. He
gains 14% on the whole. The Quantity sold at 18% profit is
A.300
B.400
C.600
D.500
Answer: C.600
Explanation: Explanation :
By the rule of alligation,we have
Profit% by selling 1st part Profit% by selling 2nd part
8 18
Net % profit
14
18-14=4 14-8=6
=> Quantity of part1 : Quantity of part2 = 4 : 6 = 2 : 3
Total quantity is given as 1000Kg
So Quantity of part2 (Quantity sold at 18% profit) = 1000×35=600Kg
Answer : Option C
Question: A train 960 m long passed a pole in 24 sec. How long will it take to pass a platform 800 m long?
A.40
B.44
C.48
D.52
Answer: B.44
Explanation: Speed = 960/24
= 40 m/sec.
Required time
= (960 + 800)/40
= 44 sec.
Answer:B
Question: All the students of class are told to sit in circle shape. Here the boy at the 6 th position is exactly opposite to 16 th boy. Total number of boys in the class?
A.10
B.15
C.20
D.25
Answer: C.20
Explanation: As half the circle shape consist of 16-6=10 boys,
So total number of boys in full circle=2*10=20
ANSWER:C
Question: The speed of a boat in upstream is 75 kmph and the speed of the boat downstream is 115 kmph. Find the speed of the boat in still water and the speed of the stream?
A.20 kmph
B.76 kmph
C.12 kmph
D.97 kmph
Answer: A.20 kmph
Explanation: Speed of the boat in still water
= (75+115)/2
= 90 kmph. Speed of the stream
= (115-75)/2
= 20 kmph.
Answer:A
Question: Data sufficiency question:
There are six people. Each cast one vote in favor of other five. Who won the elections?
i) 4 older cast their vote in favor of the oldest candidate
ii) 2 younger cast their vote to the second oldest
A.287
B.27
C.199
D.17
Answer: D.17
Explanation: xplanation:
Total possible votes are 6. Of which 4 votes went to the oldest person. So he must have won the election. Statement 1 is sufficient.
Answer:D
Question: A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
A.187
B.200
C.827
D.289
Answer: B.200
Explanation: The number of ways to select two men and three women
= ⁵C₂ * ⁶C₃
= (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)
= 200
Answer:B
Question: For a particular American football game, the probability of a team's quarterback throwing a completed pass on each throw is 3/10. What is the least number of times that the quarterback should throw the ball that will increase the probability of getting a completed pass at least once to more than 50%.
A.10
B.5
C.2
D.3
Answer: C.2
Explanation: Rule of Subtraction: P(A) = 1 - P(A')
Rule of Multiplication: P(A ∩ B) = P(A) P(B)
The probability that the quarterback throws a completed pass at least once in 2 throws is 1- (7/10)^2 = 1 - 49/100 = 51/100 > 50%
Answer: C
Question: If x and y are multiples of 2 then which are all the multiples of 2
1) x*y
2) x^y
3) x+y
4) x-y
5) x/y
A.1,3
B.1,2,4,5
C.1,2,5
D.1,2,3,4
Answer: D.1,2,3,4
Explanation: x*y,x^y,x+y, x-Y are even numbers
ANSWER:D
Question: what is the sum of the first 30 odd natural numbers
A.300
B.400
C.900
D.600
Answer: C.900
Explanation: sum of first n odd natural nuber is = n^2
so sum of the first 30 odd natural numbers=(30)^2=900
ans 900
ANSWER:C
Question: How many times digit 10 is used while writing numbers from 100 to 1000?
A.100
B.90
C.85
D.110
Answer: B.90
Explanation: in 100 to 300 there are 20 ten's
in 300 to 500 there are 20 ten's
in 500 to 700 there are 20 ten's
in 700 t0 900 there are 20 ten's
in 900 to 1000 there are 10 ten's
so total is 90 ten's
CORRECT OPTION :B
Question: Workers at a campaign office have 3000 fliers to send out. If they send out 1/5 of them in the morning and 1/4 of the remaining ones out during the afternoon, how many are left for the next day?
A.1800
B.800
C.1100
D.1200
Answer: A.1800
Explanation: (1/5)*3000 = 600
Remaining = 3000-600 = 2400
(1/4) of remaining = (1/4)*2400 = 600
Remaining now = 2400-600 = 1800
Answer: Option A
Question: Arun went for a movie nine days ago. He goes to watch movies only on Thursdays. What day of the week is today?
A.Wednesday
B.Saturday
C.Friday
D.Sunday
Answer: B.Saturday
Explanation: Explanation:
Clearly it can be understood from the question that 9 days ago was a Thursday
Number of odd days in 9 days = 2 (As 9-7 = 2, reduced perfect multiple of 7 from total days)
Hence today = (Thursday + 2 odd days) = Saturday
Answer: Option B
Question: By selling 12 toffees for a rupee, a man loses 20%. How many for a rupee should be sell to get a gain of 20%?
A.7
B.8
C.9
D.6
Answer: B.8
Explanation: Let S.P. of 12 toffees be Rs. x.
Then, 80:1 = 120:x or x = 120/180 = 3/2
For Rs. 3/2, toffees sold = 12.
For Re. 1, toffees sold = 12 * 2/3 = 8
Answer: B
Question: When working alone, painter W can paint a room in 2 hours, and working alone, painter X can paint the same room in f hours. When the two painters work together and independently, they can paint the room in 3/4 of an hour. What is the value of f?
A.3/4
B.1[1/5]
C.1[2/5]
D.1[3/4]
Answer: B.1[1/5]
Explanation: Rate*Time=Work
Let Painter W's rate be W and Painter X's rate be X
R*T = Work
W * 2 = 1 (If the work done is same throughout the question then the work done can be taken as 1) => W = 1/2
X * f = 1 => X = 1/f
When they both work together then their rates get added up
Combined Rate = (W+X)
R*T = Work
(W+X) * 3/4 = 1
=> W+X = 4/3
=> 1/2 + 1/f = 4/3
=> 1/f = (8-3)/6 = 5/6
=> f = 6/5 = 1[1/5]
Answer B
Question: If 2 tables and 3 chairs cost Rs, 3500 and 3 tables and 2 chairs cost Rs. 4000, then how much does a table cost ?
A.2377
B.1000
C.2778
D.766
Answer: B.1000
Explanation: Let the cost of a table and that of a chair be Rs. x and Rs, y respectively.
Then, 2x + 3y = 3500 ...(i)
and 3x + 2y = 4000 .....(ii)
solving (i) and (ii) we get x = 1000, y = 500
Answer: B) 1000
Question: A type A machine can complete a job in 5 hours and a type B machine can complete the job in 7 hours. How many hours will it take 2 type A machines and 3 type B machines working together and independently to complete the job?
A.1/5
B.29/35
C.5/6
D.35/29
Answer: D.35/29
Explanation: A needs 5 hours to complete the job
2A need 5/2 hours to complete the job,
similarly 3B need 7/3 hours to complete the job
Lets consider 2A and 3B as single entity (X, Y)
so
1/X + 1/Y = 1/Z Z is the time to complete the job if working together.
1/(2/5) + 1/(7/3) =1/Z
2/5 + 3/7 =1/Z
29/35 = 1/Z
Z = 35/29
so if 2A and 3 B working together, they would need 35/29 hours to complete the job.
ANSWER:D
Question: A boat ma goes 2km against the current of the stream in 1 hr and goes 1 km along the current in 10 min. how long will it take to go 5 km in stationary water
A.40 min
B.1hr
C.1hr 15 min
D.1hr 30 min
Answer: C.1hr 15 min
Explanation: rate down stream=(1/10*60)km/hr=6km/hr
rate up stream=2km/hr
speed still water =1/2(6+2)=4km/hr
required time =(5/4)=1 1/4=1hr 15 min
Answer(C)
Question: A bowl was filled with 10 ounces of water, and 0.012 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period?
A.0.004%
B.0.04%
C.0.40%
D.6%
Answer: D.6%
Explanation: Total amount of water evaporated each day during a 50-day period = .012 * 50
=.012 * 100/2
= 1.2/2
= .6
percent of the original amount of water evaporated during this period = (.6/10) * 100%
= 6 %
Answer D
Question: By selling 12 toffees for a rupee, a man loses 20%. How many for a rupee should be sell to get a gain of 20%?
A.5
B.8
C.10
D.15
Answer: B.8
Explanation: Explanation:
Let S.P. of 12 toffees be Rs. x.
Then, 80:1 = 120:x or x = 120/180 = 3/2
For Rs. 3/2, toffees sold = 12.
For Re. 1, toffees sold = 12 * 2/3 = 8
ANSWER IS B
Question: A trader bought a car at 20% discount on its original price. He sold it at a 40% increase on the price he bought it. What percent of profit did he make on the original price?
A.12%
B.19%
C.15%
D.14%
Answer: A.12%
Explanation: Original price = 100
CP = 80
S = 80*(140/100) = 112
100 - 112 = 12%
Answer:A
Question: A man can row his boat with the stream at 22 km/h and against the stream in 10 km/h. The man's rate is?
A.1 kmph
B.6 kmph
C.7 kmph
D.4 kmph
Answer: B.6 kmph
Explanation: Explanation:
DS = 22
US = 10
S = ?
S = (22 - 10)/2 =6 kmph
Answer: B