RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A company has a job to prepare certain number of cans and there are three machines A, B and C for this job. A can complete the job in 2 days, B can complete the job in 5 days and C can complete the job in 7 days. How many days the company will it take to complete the job if all the machines are used simultaneously?
A.71/59 days
B.70/59 days
C.3 days
D.12days
Answer: B.70/59 days
Explanation: Let the total number of cans to be prepared be 70.
The number of cans prepared by A in 1 day = 35.
The number of cans prepared by B in 1 day = 14.
The number of cans prepared by C in 1 day = 10.
Thus, the total number of cans that can be prepared by all the machines working simultaneously in a single day = 59.
Therefore, the number of days taken to complete the whole work = 70/59 days.
ANSWER:B
Question: An error 4% in excess is made while measuring the side of a square. What is the percentage of error in the calculated area of the square?
A.4.05%
B.4.02%
C.8.16%
D.3%
Answer: C.8.16%
Explanation: Percentage error in calculated area
=(4+4+(4Ã—4)/100)%
=8.16%
ANSWER:C
Question: The average of five numbers is 60. If one number is excluded, the average becomes 65. The excluded number is?
A.40
B.6
C.58
D.35
Answer: A.40
Explanation: Excluded number
= (60 * 5) - (65 * 4)
= 300 - 260 = 40
Answer:A
Question: Anil invested a sum of money at a certain rate of simple interest for a period of five years. Had he invested the sum for a period of eight years for the same rate, the total intrest earned by him would have been sixty percent more than the earlier interest amount. Find the rate of interest p.a.
A.5352
B.5355
C.2789
D.2689
Answer: B.5355
Explanation: Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3450.3.6/100
= Rs.824.85
27P = 62100
= 82485
P = (82485 + 62100)/27 = 3055 + 2300
= Rs.5355
Answer: B
Question: What is the 100th digit of (3!*5! + 4!*3!)/2?
A.4
B.3
C.2
D.7
Answer: A.4
Explanation: (3!*5! + 4!*3!)/2
=3!(5! + 4!)/2
=6 (120+24)/2
=432
100th digit of the above product will be equal to 4
Answer A
Question: From a nine-member dance group, five will be chosen at random to volunteer at a youth dance event. If Kori and Jason are two of the nine members, what is the probability that both will be chosen to volunteer?
A.a) 1/21
B.b) 35/2
C.c) 4/21
D.d) 2/7
Answer: B.b) 35/2
Explanation: Total number of ways to choose 5 out of 9 = 9C5 = 144.
Number of ways to choose 2 (any but Kori and Jason) out of 7 (excluding Kori and Jason) = 7C2 = 2520.
P = favorable/total = 2520/144 = 35/2.
Answer: B.
Question: A began business with Rs.45000 and was joined afterwards by B with Rs.5400. When did B join if the profits at the end of the year were divided in the ratio of 2:1?
A.6
B.9
C.7
D.5
Answer: C.7
Explanation: 45*12 : 54*x = 2: 1
x = 5
12 -5 = 7
Answer: C
Question: W is an even integer greater than 300,000 and smaller than 1,000,000. How many numbers can W be?
A.300,000
B.349,999
C.350,000
D.399,999
Answer: B.349,999
Explanation: W 1,000,000-300,000=700,000 integers
700,000/2= 350,000 even integers.
350,000+1 inclusive. But since 1,000,000 and 300,000 are not included.
350,001-2=349,999
B
Question: If the letters of the word PLACE are arranged taken all at a time, find how many do not start with AE
A.110
B.114
C.118
D.120
Answer: B.114
Explanation: Total no'of arrangements 5P5 = 5! = 120
no'of arrangements start with AE = 1 × 6 = 6
no'of arrangements which do not start with AE = 120 - 6 = 114.
B)
Question: At a recent small town election for mayor a total of 967 votes were cast for the four candidates, the winner exceeding his opponents by 53, 79 and 105 votes, respectively. How many votes were cast for the candidate in fourth place?
A.134
B.178
C.196
D.166
Answer: C.196
Explanation: The number of votes the winning candidate received was
967 + 53 + 79 + 105	/4= 301.
The fourth place received 301 – 105 = 196.
C
Question: Find the value of x from the below equation? : x^2+5x+4 = 0
A.1
B.-3
C.3
D.2
Answer: B.-3
Explanation: a = 1, b = 5, c = 4
x1,2 = (-5 Â± âˆš(5^2 - 4Ã—1Ã—4)) / (2Ã—1) = (-5 Â± âˆš(25-16)) / 2 = (-5 Â± 3) / 2
x1 = (-5 + 3)/2 = -2/2 = -1
x2 = (-5 - 1)/2 = -6/2 = -3
B
Question: In a sequence of 39 numbers, each term, except for the first one, is 7 less than the previous term. If the greatest term in the sequence is 281, what is the smallest term in the sequence?
A.2
B.-2
C.0
D.18
Answer: D.18
Explanation: Which term is the greatest? The first or the last? It is given to you that every term is 7 less than the previous term. Hence as you go on, your terms keep becoming smaller and smaller. The first term is the greatest term.
An = 281 + (39- 1)*(-7)
An = 281 - 266 = 15
D
Question: Arun borrowed a certain sum from Manish at a certain rate of simple interest for 2 years. He lent this sum to Sunil at the same rate of interest compounded annually for the same period. At the end of two years, he received Rs. 2400 as compound interest but paid Rs. 2000 only as simple interest. Find the rate of interest.
A.20%
B.10%
C.40%
D.50%
Answer: C.40%
Explanation: Explanation:
Let the sum be x
Simple interest on x for 2 years = Rs.2000
Simple interest = PRT/100
2000 = x × R × 2100
⇒ xR = 100000 --- (1)
Compound Interest on x for 2 years = 2400
P(1+R/100)T−P=2400
x(1+R/100)2 − x = 2400
x(1+2R/100 + R2/10000) − x = 2400
x(2R/100 + R2/10000) = 2400
2xR/100 + xR2/10000 = 2400 --- (2)
Substituting the value of xR from (1) in (2) ,we get
(2 × 100000)/100 + (100000×R)/10000 = 2400
2000 + 10R = 2400
10R = 400R = 40%
Answer: Option C
Question: A man sells a horse for Rs.600 and loses something, if he had sold it for Rs.720 , his gain would have been double the former loss. Find the cost price of the horse?
A.27
B.98
C.27
D.40
Answer: D.40
Explanation: CP = SP + 1CP = SP - g
600 + x = 720 - 2x
3x = 120 => x = 40
Answer:D
Question: In what ratio must a grocer mix rice worth Rs.60 a kg and Rs.65 a kg.So that by selling the mixture at Rs. 68.20 a kg, He may gain 10%?
A.1:2
B.3:2
C.4:5
D.1:3
Answer: B.3:2
Explanation: S.P of 1kg mix = RS.68.20,
Gain = 10% C.P of 1kg mix =Rs.(100/110 x 68.20) =Rs.62 = 3 : 2
ANSWER B
Question: A and B enter into partnership with capitals in the ratio 3 : 4. At the end of 10 months A withdraws,and the profits now are divided in the ratio of 5 : 4. Find how long B remained in the business?
A.9 months
B.8 months
C.7 months
D.6 months
Answer: D.6 months
Explanation: Initially A’s investment = 3x and B’s investment = 4x
Let B remain in the business for ‘n’ months.
⇒ 3x × 10 : 4x × n = 5 : 4
∴ 3x × 10 × 4 = 4x × n × 5
⇒ n = 6
Answer D
Question: A group of hikers is planning a trip that will take them up a mountain using one route and back down using another route. They plan to travel down the mountain at a rate of one and a half times the rate they will use on the way up, but the time each route will take is the same. If they will go up the mountain at a rate of 6 miles per day and it will take them two days, how many miles long is the route down the mountain?
A.16
B.17
C.18
D.19
Answer: C.18
Explanation: On the way down, the rate is 1.5*6 = 9 miles per day.
The distance of the route down the mountain is 2*9 = 18 miles.
The answer is C.
Question: Peter is a trail runner who decides to take a day off work to run up and down a local mountain. He runs uphill at an average speed of 4 miles per hour and returns along the same route at an average speed of 6 miles per hour. Of the following, which is the closest to his average speed, in miles per hour, for the trip up and down the mountain?
A. 4.8
B. 5.8
C. 6.0
D. 6.3
Answer: A. 4.8
Explanation: to calculate average of 2 speeds a and b when distance is constant
Formula - 2ab/(a+b)
Here Peter's uphill speed = 4 mph
Peter's downhill speed = 6 mph
2*4*6/(4+6) = 48/10 = 4.8
Correct answer - A
Question: Calculate the different number of ways 7 boys and 2 girls can sit on a bench?
A.362881
B.362880
C.311880
D.362280
Answer: B.362880
Explanation: npn = n!
9p9 = 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 362880
B
Question: The population of a town increased from 1,75,000 to 2,10,000 in a decade. The average percent increase of population per year is
A.2%
B.5%
C.6%
D.8.75%
Answer: A.2%
Explanation: Solution
Increase in 10 years	= (210000 - 175000)
= 35000.
Increase%	= (35000/175000Ã—100)%
= 20%.
Required average	= (20/10)%
= 2%.
Answer A
Question: Mysoon collects glass ornaments. Ten more than 1/6 of the ornaments in her collection are handmade, and 1/2 of the handmade ornaments are antiques. If 1/6 of the ornaments in her collection are handmade antiques, how many ornaments are in her collection?
A.36
B.60
C.108
D.60
Answer: D.60
Explanation: The number of ornaments = a
Ten more than 1/6 of the ornaments in her collection are handmade => Handmade = 10+a/6
1/2 of the handmade ornaments are antiques => Handmade ornaments = 1/2*(10+a/6) = 5 + a/12
1/6 of the ornaments in her collection are handmade antiques => Handmade ornaments = a/6
=> 5 + a/12 = a/6 => a = 60
Ans: D
Question: The smallest 4 digit prime number is?
A.A)101
B.B)1003
C.C)109
D.D)113
Answer: B.B)1003
Explanation: The smallest 3-digit number is 1000, which is divisible by 2.
1000 is not a prime number.
1003< 11 and 101 is not divisible by any of the prime numbers 2, 3, 5, 7, 11.
1003 is a prime number.
Hence 1003 is the smallest 4-digit prime number.
B)
Question: The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is?
A.1994
B.1494
C.1349
D.1496
Answer: C.1349
Explanation: LCM = 1400
1400 - 6 = 1394
ANSWER:C
Question: a bank was to give a loan out to a newly married couple for 800,000 with no interest for 2 years and raise the price to 900,000 after 2 years. what is the interest rate?
A.17%
B.13%
C.12%
D.7%
Answer: D.7%
Explanation: for 0 years = (900,000- 800,000) = 100,000.
for 2 years = (100,000 x 2)/2= 100,000
Principal = (800,000 - 100,000) = 700,000.
Hence, rate = (100 x 100,000)/(700,000x2) = 7% ANSWER: D
Question: A horse chases a pony 8 hours after the pony runs. Horse takes 12 hours to reach the pony. If the average speed of the horse is 320 kmph, what s the average speed of the pony?
A.182kmph
B.192kmph
C.193kmph
D.196kmph
Answer: B.192kmph
Explanation: pony take 20 hours and horse take 12 hours...then Distance chased by them is 320*12.so speed of pony is (320*12)/20=192kmph.
ANSWER IS B
Question: How much time will take for an amount of Rs. 480 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
A.8 years
B.4 years
C.3 years 9 months
D.9 years
Answer: C.3 years 9 months
Explanation: Time = (100 * 81) / (480 * 4.5)
= 3 years 9 months
Answer: C
Question: A, B and C invests Rs.2000, Rs.3000 and Rs.4000 in a business. After one year A removed his money; B and C continued the business for one more year. If the net profit after 2 years be Rs.3200, then A's share in the profit is?
A.388
B.299
C.266
D.400
Answer: D.400
Explanation: 2*12 : 3*12 : 4*24
1: 3: 4
1/8 * 3200 = 400.Answer: D
Question: 195,383,575,763,955,___
A.1153
B.1143
C.1243
D.1343
Answer: B.1143
Explanation: 19*1 = 19 5
19*2 = 38 3
19*3 = 57 5
19*4 = 76 3
19*5 = 95 5
19*6 = 114 3
so ans=1143
ANSWER:B
Question: Find the number of ways of arranging the letters of the word "MATERIAL" such that all the vowels in the word are to come together?
A.1446
B.1440
C.1444
D.1441
Answer: B.1440
Explanation: In the word, "MATERIAL" there are three vowels A, I, E.
If all the vowels are together, the arrangement is MTRL'AAEI'.
Consider AAEI as one unit. The arrangement is as follows.
M T R L A A E I
The above 5 items can be arranged in 5! ways and AAEI can be arranged among themselves in 4!/2! ways.
Number of required ways of arranging the above letters = 5! * 4!/2!
= (120 * 24)/2 = 1440 ways.
Answer:B
Question: In a manufacturing plant, it takes 36 machines 8 hours of continuous work to fill 8 standard orders. At this rate, how many hours of continuous work by 72 machines are required to fill 12 standard orders?
A.3
B.6
C.8
D.9
Answer: B.6
Explanation: the choices give away the answer..
36 machines take 4 hours to fill 8 standard orders..
in next eq we aredoubling the machines from 36 to 72, but thework is not doubling(only 1 1/2 times), = 8*36/72*12/8 = 6
Ans B
Question: A sum of money deposited at C.I. amounts to Rs.6000 in 6 years and to Rs.7500 in 7 years. Find the rate percent?
A.25%
B.20%
C.15%
D.10%
Answer: A.25%
Explanation: 6000 --- 1500
100 --- ? => 25%
Answer: A
Question: In what time will a train 120 m long cross an electric pole, it its speed be 144 km/hr?
A.3 sec
B.2.9 sec
C.3.5 sec
D.7.5 sec
Answer: A.3 sec
Explanation: Speed = 144 * 5/18 = 40 m/sec
Time taken = 120/40
= 3 sec.
Answer: A
Question: The speeds of three motor bikes are in the ratio 6 : 5 : 4. The ratio between the time taken by them to
travel the same distance is :
A.10 : 12 : 15
B.12 : 10 : 8
C.15 : 12: 10
D.10 : 15 : 12
Answer: A.10 : 12 : 15
Explanation: Expl : Ratio of time taken : 1/6 :1/5 : 1/4 = 10 : 12 : 15
Answer: A
Question: A sum of money at simple interest amounts to $ 780 in 3 years and to $930 in 4 years. The sum is:
A.$153
B.$698
C.$330
D.$549
Answer: C.$330
Explanation: C
$330
S.I. for 1 year = $(930 - 780) = $150.
S.I. for 3 years = $(150 x 3) = $450.
Principal = $(780 - 450) = $330.
Question: A student chose a number, multiplied it by 2, then subtracted 138 from the result and got 102. What was the number he chose?
A.240
B.120
C.150
D.200
Answer: B.120
Explanation: Let x be the number he chose, then
2⋅x−138=102
2x=240
x=120
So answer is B
Question: In how many ways can the letters {U, R, R, R, R} be arranged?
A.5
B.20
C.120
D.720
Answer: A.5
Explanation: My answer : A
There is 5! ways to arrange those letters in total, however letter U repeats 1! times and letter R repeats 4! times
=> the way to arrange without repeating = 5!/ [1!x4!] = 5
Question: A local elementary school has 1049 students and nine teachers, How many students would have to be added to the school to make sure each teacher has the same amount of students in their classroom?
A.4
B.6
C.5
D.1
Answer: A.4
Explanation: Using the rule on the divisibility of nine, we add the digits of 1049 together to get 14. Since we are doing addition, the next number that is divisible by nine would be 18. Therefore, our answer 4(option A)
Question: A and B entered into a partnership investing Rs.25000 and Rs.30000 respectively. After 4 months C also joined the business with an investment of Rs.35000. What is the share of C in an annual profit of Rs.47000?
A.14028
B.14038
C.14079
D.14000
Answer: D.14000
Explanation: 25*12: 30*12: 35*8
15:18:14
14/47 * 47000 = 14000
Answer:D
Question: If the roots of a quadratic equation are 20 and -7, then find the equation?
A.x2 + 13x - 140 = 0
B.x2 - 13x + 140 = 0
C.x2 - 13x - 140 = 0
D.x2 + 13x + 140 = 0
Answer: C.x2 - 13x - 140 = 0
Explanation: Explanation:
Any quadratic equation is of the form
x2 - (sum of the roots)x + (product of the roots) = 0 ---- (1)
where x is a real variable. As sum of the roots is 13 and product of the roots is -140, the quadratic equation with roots as 20 and -7 is: x2 - 13x - 140 = 0.
ANSWER IS C
Question: 38, 87, 22,76, 31,47, 13, 82
Which of the following numbers is greater than three-fourth of the numbers but less than one-fourth of the numbers in the list above?
A.a- 55
B.b- 68
C.c- 79
D.d- 81
Answer: C.c- 79
Explanation: Important:- Arrange the numbers in ascending order first.
13, 22, 31, 38, 47, 76, 82, 87
3/4th of the number list represents- 76 (6th number)
remaining 1/4th list represents 82 (7 th number)
79 fits in between above 2
Answer:- C
Question: Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder .
A.1638
B.1863
C.1683
D.1836
Answer: C.1683
Explanation: L.C.M. of 5,6,7,8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 X 2 + 3)=1683
Answer is C.
Question: Tom and John traveled in the same direction along the equal route at their constant speed rates of 15 km per hour and 10 km per hour, respectively. After 15 minutes Tom passed John, Tom reaches a certain Gas station, how many T minutes it takes John to reach the station?
A.5 min
B.6 min
C.7 and 1/2 min
D.8 min
Answer: C.7 and 1/2 min
Explanation: Since the question states “after 15 minutes”, we can say Tom traveled 15/4km for 15 minutes as he can travel 15km per hour. Hence, using the same logic, we can say John traveled 10/4km as he travels 10km per hour. So, John has to travel (15/4)-(10/4)km=5/4km more. Since John’s speed is 10km/hour, which means 1km/6minutes. As he has to travel 5/4km more, it is going to take him 6(5/4) minutes. Hence, T=6(5/4)=15/2 minutes. The correct answer is C.
Question: How many 1/4s are there in 37 1/2?
A.150
B.450
C.500
D.650
Answer: A.150
Explanation: Required number = (75/2)/(1/4)
= (75/2 x 4/1)
= 150.
ANSWER:A
Question: When a certain number X is divided by 52, the remainder is 19. What is the remainder when X is divided by 7?
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: When a certain number X is divided by 52, the remainder is 19. What is the remainder when X is divided by 7?
Putting a value say x = 19 we get remainder as 19 when divided by 52.
When 19 divided by 7 we get 5 as remainder.
D is the answer.
Question: A cycle is bought for Rs.800 and sold for Rs.1080, find the gain percent?
A.22
B.20
C.35
D.88
Answer: C.35
Explanation: 800 ---- 180
100 ---- ? => 35%
Answer:C
Question: The cost of producing x tools by a company is given by
C(x) = 2500 x + 5500 (in $)
a) What is the cost of 100 tools?
A.222500 $
B.125800 $
C.225900 $
D.255500 $
Answer: D.255500 $
Explanation: Solution
C(100) = 2500*100 + 5500 = 255500 $
Answer D
Question: If n is an integer, then the least possible value of |31 - 4n| is?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: |31 - 4n| represents the distance between 31 and 4n on the number line. Now, the distance will be minimized when 4n, which is multiple of 4, is closest to 31. Multiple of 4 which is closest to 31 is 32 (for n = 8),
so the least distance is 1: |31 - 32| = 1.
Answer: B.
Question: A can do a job in 10days and B in 20days. If they work on it together for 4 days, then the fraction of the work that is left is?
A.2/5
B.8/15
C.3/11
D.1/12
Answer: A.2/5
Explanation: A's 1 day work = 1/10
B's 1day work = 1/20
A+B 1day work = 1/10 + 1/20 = 3/20
A+B 4days work = 3/20*4 = 3/5
Remaining work = 1 - 3/5 = 2/5
Answer is A
Question: Which of the following inequalities is equivalent to −4 < x < 8?
A.|x - 1| < 7
B.|x + 2| < 6
C.|x + 3| < 5
D.|x - 2| < 6
Answer: D.|x - 2| < 6
Explanation: We know that |x| < a means -a < x < a, where Sum of lower limit of x (i.e -a) and the upper limit of x (i.e a), is 0
Given is, -4 < x < 8, let's say by adding y to this inequality we will get into the above format
-4+y < x+y < 8+y
Now, to move this into the mod format, we need to have (-4+y) + (8+y) = 0 => y = -2
Thus, -6< x-2 < 6 => |x-2| < 6.
Hence, answer is D
Question: If (x - 1)^2 = 324, which of the following could be the value of x - 3?
A.17
B.15
C.13
D.-20
Answer: D.-20
Explanation: (x - 1)^2 = 324
(x - 1) = 18 or -18
x = 19 or -17
x - 3 = 16 or -20
The answer is D.
Question: The average of five numbers is 27. If one number is excluded, the average becomes 20. The excluded number is?
A.52
B.53
C.54
D.55
Answer: D.55
Explanation: Excluded number = (27 * 5) - (20 * 4)
= 135 - 80
= 55.
Answer: D
Question: If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 5 and 5K + 1 is 118, what is the value of K?
A. 11
B. 15 3/4
C. 22
D. 118
Answer: D. 118
Explanation: K + 2K +3 + 3K - 5 + 5K +1 = 11K -1
(11K -1)/4 = 118
11K = 118 * 4 +1 = 472 +1 = 473
K = 473 / 11 = 43.
Answer D.
Question: A boy was asked to multiply a number by 22. He instead multiplied the number by 44 and got the answer 308 more than the correct answer. What was the number to be multiplied?
A.10
B.12
C.08
D.14
Answer: D.14
Explanation: Let the number be x
22x + 308 = 44x
=> 44x - 22x = 308
=> 22x = 308
=> x = 308/22 = 154/11 = 14
Answer is D.
Question: The average weight of 2 person's increases by 4.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?
A.74 kg
B.76.5 kg
C.85 kg
D.78
Answer: A.74 kg
Explanation: Explanation:
Total weight increased = (2 x 4.5) kg = 9 kg.
Weight of new person = (65 + 9) kg = 74 kg.
Answer: A
Question: A pair of articles was bought for $720 at a discount of 10%. What must be the marked price of each of the article?
A.$300
B.$500
C.$350
D.$400
Answer: D.$400
Explanation: S.P. of each of the article = 720/2 = $360
Let M.P = $x
90% of x = 360
x = 360*100/90 =$400
Answer is D
Question: A pipe can filled a tank in 40 minutes and another pipe can empty it in 1hour. If the tank is already half full and both the taps are opened together, then the tank is filled in how many minutes?
A.25min
B.20min
C.15min
D.10min
Answer: A.25min
Explanation: T = 1/2 (25*50 / 50-25) = 25 minutes
Tank is filled in 25 minutes
Answer is A
Question: Two people P Q start a race in a circular track in opposite way different but constant speed. First they meet 900m cw from the starting pt. Then they meet 800m ccw from the starting pt. What's the circumference of the circle.
A.2600
B.2700
C.2800
D.2900
Answer: A.2600
Explanation: when they first met 900m cw from the starting pt.
second time, they will meet at 1800 m cw from starting point which is 800 m CCW from starting point.
so circumference of circle = 1800+800 = 2600 m
ANSWER:A
Question: In a triangle, the ratio of two angles is 7:2, and the third angle is the difference between the first two angles. What is the smallest angle, in degrees?
A.90/11
B.120/7
C.150/11
D.180/7
Answer: D.180/7
Explanation: the three angles are 7x, 2x, and (7x-2x)=5x for some value x (to create the ratio)
the three angles of a triangle add up to 180, so 7x+2x+5x = 180
14x = 180
x=180/14
x = 90/7
the smallest angle is 2x = 2*(90/7) = 180/7
D
Question: Ravi and sunil are partners in a business. Ravi invests Rs.12,000 for 4 months and Sunil invested Rs.10000 for 5 months then after one year ratio of their profits will be
A.1:3
B.2:3
C.24:25
D.20:22
Answer: C.24:25
Explanation: =(12000*4):(10000*5)
=48000:50000
=24:25
ANSWER:C
Question: A train covers a distance in 50 min, if it runs at a speed of 48kmph on an average. The speed at which the train must run to reduce the time of journey to 50min will be.
A.60 km/h
B.55 km/h
C.48 km/h
D.70 km/h
Answer: C.48 km/h
Explanation: Time=50/60 hr=5/6hr
Speed=48mph
distance=S*T=48*5/6=40km
time=50/60hr=5/6hr
New speed = 40* 6/5 kmph= 48kmph
Answer : C
Question: 135 kg of an alloy A is mixed with 145 kg of alloy B. If alloy A has lead and tin in the ratio 3:5 and alloy B has tin and copper in the ratio 2:3, then the amount of tin in the new alloy is?
A.100.6kg
B.142kg
C.135kg
D.110.8kg
Answer: B.142kg
Explanation: Quantity of tin in 135kg of A = 135*5/8 = 84kg
Quantity of tin in 145kg of B = 145*2/5 = 58kg
Quantity of tin in the new alloy = 84+58 = 142kg
Answer is B
Question: Carrie likes to buy t-shirts at the local clothing store. They cost $9.65 each. One day, she bought 12 t-shirts. How much money did she spend?
A.$115.8
B.$248.75
C.$200
D.$171.6
Answer: A.$115.8
Explanation: $9.65*12=$115.8. Answer is A.
Question: On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 14 more transactions than Cal. How much transactions did Jade handled?
A.80
B.81
C.82
D.83
Answer: A.80
Explanation: Solution:
Mabel handled 90 transactions
Anthony handled 10% more transactions than Mabel
Anthony = 90 + 90 × 10%
= 90 + 90 × 0.10
= 90 + 9
= 99
Cal handled 2/3rds of the transactions than Anthony handled
Cal = 2/3 × 99
= 66
Jade handled 14 more transactions than Cal.
Jade = 66 + 14
= 80
Jade handled = 80 transactions.
Answer: A
Question: The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 70 sq. cm. Find the length of the rectangle.
A.12cm
B.14cm
C.16cm
D.18cm
Answer: D.18cm
Explanation: Explanation:
Let breadth = x. Then, length = 2x. Then,
(2x - 5) (x + 5) - 2x * x = 70 => 5x - 25 = 70 => x = 18.
Length of the rectangle = 18 cm.
Answer: Option D