RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: ¹⁵/₇₁, ⁴¹/₇₁, ⁶²/₇₁ etc. are like/unlike fractions
A.unlike fraction
B.like fraction
C.both
D.none
Answer: B.like fraction
Explanation: Fractions having the same denominators are called like fractions.
denominators of all fractions are 71 so like fraction
ANSWER :B
Question: The Pinedale bus line travels at an average speed of 60 km/h, and has stops every 5 minutes along its route. Yahya wants to go from his house to the Pinedale Mall, which is 7 stops away. How far away, in kilometers, is Pinedale Mall away from Yahya's house?
A.20 km
B.35 km
C.40 km
D.50 km
Answer: B.35 km
Explanation: Number of stops in an hour: 60/5 = 12
Distance between stops: 60/12 = 5 km
Distance between Yahya's house and Pinedale Mall: 5 x 7 = 35 km
IMO, correct answer is "B."
Question: If the average (arithmetic mean) of five consecutive negative integers is 2k – 1, what is the difference Q between the greatest and least of the five integers?
A.4K
B.4k^2 -4k
C.4-4k
D.4
Answer: D.4
Explanation: (n-2 + n - 1 + n + n + 1 + n + 2)/5 = 2k - 1
=> n = 10k - 5
Greatest = n + 2 = 10k - 5 + 2 = 10k - 3
Least = n - 2 = 10k - 5 - 2
=> Difference Q= 10k - 3 - (10k - 7)
= 4
Answer - D
Question: There are 5 boys and 3 girls. In how many ways can they be seated in a row so that all the three girls do not sit together?
A.24000
B.36000
C.54200
D.32560
Answer: B.36000
Explanation: Total number of persons = 5+3 = 8
they can be seated in a row in 8! ways
Treat 3 girls as 1 so we have 6 people can be arranged in 6! ways
Three girls can be arranged among themselves in 3! ways
Required number of ways = 8!-6!*3! = 36000
Answer is B
Question: Adams's internet provider offers unlimited traffic which costs $0.5 per day charged off at 12 a.m. The service is discontinued when client's debt exceeds $5. If today in the morning Adams makes a payment of $7, for how many days, including today, will she be connected to the internet without any additional payments, given her initial balance was $0?
A. 15
B. 24
C. 25
D. 26
Answer: C. 25
Explanation: day 0- payment of $7 is made in the morning (after 12 am midnight)
day 1 onwards(after 12 am midnight) internet service will begin and will run for 7*2=14 days i.e. at the end of day 15 balance will be zero.
now Adams can still use the internet till her debt reaches $5 which means total of 5*2=10 days.
now the question states for how many days, including today, will she be connected to the internet without any additional paymentsi.e. we will have to include day0 also in our final answer. therefore total no. of days =1+14+10=25=C
Question: subash can copy 50 pages in 10 hrs.subash and prakash together can copy 300 pages in 40 hours.in how much time prakash can copy 18 pages.
A.8
B.10
C.2
D.14
Answer: C.2
Explanation: subhas 's 1 hr copy page=50/10=5 page
(subhas+prakash)'s 1 hr copy page=300/40=7.5 page
from above prakash's 1 hr copy page= 2.5 page
so time taken in 30 page's copy =(5/2.5)=2 hrs
ANSWER:C
Question: If cost of sugar increases by 10%. How much percent consumption of sugar should be decreased in order to keep expenditure fixed?
A.22%
B.50%
C.20%
D.9.1%
Answer: D.9.1%
Explanation: 100
110
-----
110 ----- 10
100 ------ ? => 9.1%
Answer: D
Question: The volumes of two cones are in the ratio 1 : 10 and the radii of the cones are in the ratio of 1 : 2. What is the length of the wire?
A.2:5
B.2:7
C.2:2
D.2:1
Answer: A.2:5
Explanation: The volume of the cone = (1/3)πr2h
Only radius (r) and height (h) are varying.
Hence, (1/3)π may be ignored.
V1/V2 = r12h1/r22h2 => 1/10 = (1)2h1/(2)2h2
=> h1/h2 = 2/5
i.e. h1 : h2 = 2 : 5
Answer: A
Question: What annual installment will discharge a debt of Rs. 1260 due in 3 years at 12% simple interest?
A.315
B.345
C.325
D.375
Answer: D.375
Explanation: Let each Installment be Rs. x
Then, ( x+ ((x*12*1)/100)) + (x+ ((x*12*2)/100) ) + x = 1260
=((28x/25) + (31x/25) + x) = 1260 ïƒ› (28x+31x+25x)=(1260*25)
x= (1260*25)/84 = Rs.375.
Therefore,	Each installment = Rs. 375.
Answer is D.
Question: (7.5 × 7.5 + 37.5 + 2.5 × 2.5) is equal to :
A.30
B.60
C.80
D.100
Answer: D.100
Explanation: Solution
Given expression = (7.5 × 7.5 + 2 × 7.5 × 2.5 + 2.5 × 2.5)
=(a 2 + 2ab + b 2) = (a + b)2 = (7.5 + 2.5)2 = 102 = 100 . Answer D
Question: x = y - (20/y), where x and y are both > 0. If the value of y is doubled in the equation above, the value of x will
A.decrease
B.stay the same
C.increase four fold
D.double
Answer: D.double
Explanation: Alternate approach
Plug in some values of y > 0
Let y = 10
So, x = y - (20/y)
Or, x = 10 - (20/10) =8
Let y = 20
So, x = y - (20/y)
Or, x = 20 - (20/20) =19
So, x increases from 8 to 19
Hence the number increases 2.2 times, thus the correct answer will be (D)
Question: The area of a square is equal to five times the area of a rectangle of dimensions 25 cm * 5 cm. What is the perimeter of the square?
A.100
B.800
C.500
D.600
Answer: A.100
Explanation: Area of the square = s * s = 5(25 * 5)
=> s = 25 cm
Perimeter of the square = 4 * 25 = 100 cm.
Answer: Option A
Question: If 75 percent of a class answered the first question on a certain test correctly, 45 percent answered the second question on the test correctly, and 20 percent answered neither of the questions correctly, what percent answered both correctly?
A.10%
B.(8) 40%
C.30%
D.50%
Answer: B.(8) 40%
Explanation: I didn't understand how to connect 20 percent with the whole equation.
Why 20 is out of the percentile diagram (circles) but inside of 100?
20% appeared in the exam; however did not answer Question AQuestion B correctly
So they are out of the two circles, however as they have appeared in the exam, they have to be taken into consideration for calculation purpose
I am doing it this way:
Suppose the total class size is 100, then 20 percent of the class answered incorrectly and rest 80 percent answered correctly in question 1 or 2 or both.
Now,
100 - [(75 - x) + x + (45 - x)] = 20 .......... values are in percent
x = 20 - 100 + 120
x = 40
Ans: B
Question: A sum of money deposited at C.I. amounts to Rs.9000 in 10 years and to Rs.9990 in 11 years. Find the rate percent?
A.9%
B.10%
C.11%
D.12%
Answer: C.11%
Explanation: 9000 --- 990
100 --- ? => 11%
Answer: C
Question: What is the most powerful tool used by the Reserve Bank of India to control inflation?
A.FDS
B.Reduce interest rates
C.Raise interest rates
D.Raise current supply
Answer: C.Raise interest rates
Explanation: Explanation:
No explanation is available for this question!
ANSWER:C
Question: A diet contains 400 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 49 grams of protein daily, how many grams of food X are in the mixture?
A.160
B.180
C.200
D.220
Answer: D.220
Explanation: Let x be the number of grams of food X in the mixture.
0.1x + 0.15(400-x) = 49
0.05x = 11
x = 220
The answer is D.
Question: A man decides to buy a nice horse. He pays $60 for it, and he is very content with the strong animal. After a year, the value of the horse has increased to $70 and he decides to sell the horse. However, already a few days later he regrets his decision to sell the beautiful horse, and he buys it again. Unfortunately, he has to pay $80 to get it back, so he loses $10. After another year of owning the horse, he finally decides to sell the horse for $90.
What is the overall profit the man makes?
A.$10
B.$60
C.$20
D.$50
Answer: C.$20
Explanation: C
$20
In the first trade, the man buys something for $60 and sells it again for $70, so he makes a profit of $10.
In the second trade, the man buys something for $80 and sells it again for $90, so he makes again a profit of $10.
Conclusion: The man makes an overall profit of $10 + $10 = $20.
You can also look at the problem as follows: the total expenses are $60 + $80 = $140 and the total earnings are $70 + $90 = $160. The overall profit is therefore $160 - $140 = $20.
Question: A given positive integer is divided by 9 with a remainder of 5. The same integer when divided by 12 has a remainder of 3. What is the remainder if the it integer is divided by 35.
A.Between 1 and 4, inclusive
B.Between 5 and 7, inclusive
C.Between 8 and 10, inclusive
D.5
Answer: B.Between 5 and 7, inclusive
Explanation: Put in real numbers.
Let the integer be x
9x+5= 12x+3
Start 9x+5 -->14, 23, 32,....41...
Of these only 41 fit the description 12x+3. The remainder when divided by 35 is 6. So answer is B).
Answer = B)
Question: In the table above, what is the least number of table entries that are needed to show the mileage between each city and each of the other five cities?
A.15
B.21
C.25
D.30
Answer: B.21
Explanation: Total number of entries 6*6(6rows*6columns) =36
Now 6 entries are representing mileage with the city itself so subtract that => 36-6
Minimum entries required = half the Total = 30/2 = 15
ANSWER:B
Question: Which is not a leap year?
A.2004
B.2012
C.1700
D.1704
Answer: C.1700
Explanation: the answer is 1700,
becz if the year is centurial ,that should be divisible by 400 for leap year
ex:400,800,1200
ANSWER:C
Question: Of the 800 employees of Company X, 80 percent have been with the company for at least ten years. If y of theselong-termmembers were to retire and no other employee changes were to occur, what value of y would reduce the percent oflong-termemployees in the company to 70 percent ?
A.200
B.266.67
C.112
D.80
Answer: B.266.67
Explanation: The # oflong-termemployees is 80%*800=640.
After y of them retire new # oflong-termemployees would become 640-y.
Total # of employees would become 800-y.
We want 640-y to be 70% of 800-y --> 640-y=(800 -y)*70% --> y = 266.67.
Answer: B.
Question: What is the average of 1/2, 4/5 and 7/10?
A.1/5
B.3/10
C.2/3
D.1/2
Answer: C.2/3
Explanation: Sum of 1/2,4/5,7/10 =20/10
Average = 20/10*1/3 =2/3
Answer C 2/3
Question: add 10% of 30 and 15% of 50.
A.9.5
B.10.5
C.11.5
D.12
Answer: B.10.5
Explanation: 10% of 30 + 15% of 50
30*10/100+50*15/100
3+7.5=10.5
answer B
Question: What annual payment will discharge a debt of Rs. 6450 due in 4 years at 5% per annum?
A.1500
B.1400
C.1700
D.1800
Answer: A.1500
Explanation: Explanation :
he amount needs to be repaid in 4 years = Rs.6450
Suppose Rs.x is paid annually to repay this debt
Then, amount paid after 1st year = Rs.x
Interest for this Rs.x for the remaining 3 years = x × 5×3/100=15x/100
Then, amount paid after 2nd year = Rs.x
Interest for this Rs.x for the remaining 2 years = x × 5 × 2 /100=10x/100
Amount paid after 3rd year = Rs.x
Interest for this Rs.x for the remaining 1 year = x × 5 ×1/100=5x/100
Amount paid after 4th year = Rs.x and this closes the entire debt
=>x+15x/100+x+10x/100+x+5x/100+x=6450
=>4x+30x/100=6450
=>4x+3x/10=6450
=>40x+3x=64500
=>43x=64500
=>x=1500
Answer : Option A
Question: What is the greatest of 3 consecutive integers whose sum is 33 ?
A.12
B.7
C.8
D.9
Answer: A.12
Explanation: The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3
If the sum is 24, we need to solve the equation 3n + 3 = 33;
=> 3n = 30;
=> n = 10
The greatest of the three numbers is therefore 10+ 2 = 12 Answer: A
Question: It was calculated that 75 men could complete a piece of work in 25 days. When work was scheduled to commence, it was found necessary to send 25 men to another project. How much longer will it take to complete the work?
A.28 days.
B.30 days.
C.37.5 days.
D.40 days.
Answer: C.37.5 days.
Explanation: One day work = 1 / 25
One man’s one day work = 1 / ( 25 * 75)
Now:
No. Of workers = 50
One day work = 50 * 1 / ( 25 * 75)
The total no. of days required to complete the work = (75 * 25) / 50 = 37.5
Answer:C
Question: In a 100 m race,A covers the distance in 30 seconds and B in 45 second.In this race A beats B by :
A.33.33 m
B.25 m
C.45 m
D.30 m
Answer: A.33.33 m
Explanation: Solution
Distance covered by B in 15 sec. = (100/45x15)m =33.33m.
∴ A beats B by33.33 metres.
Answer A
Question: A bowl contains many kinds of fruit. In the bowl there are twice as many apples then there are bananas, and three times as many oranges as bananas. If the total number of pieces of fruit is X, then how many apples are in the bowl as a fraction of X
A.X/2
B.X/3
C.2*X
D.X/6
Answer: A.X/2
Explanation: Since X is the total number of fruit: X = apples + bananas + oranges.
Since there are three times as many oranges as bananas then 1*orange = 3*bananas
Thus X = apples + bananas + (3*bananas); which simplifies to X = apples + 4*bananas
Since there are twice as many apples as bananas then 1*apple = 2*bananas; which converts to bananas=apple/2
Thus X = apples + 4*(apples/2); which simplifies to X = 2*apples.
Thus apples = X/2
Answer: A
Question: If x : 0.25 : : 3 : 5, then x is equal to :
A.0.25
B.0.15
C.0.2
D.0.3
Answer: B.0.15
Explanation: Explanation :
Solution: x : 0.25 : : 3 : 5
=> x*5 = 3*0.25 => x = 0.75/5 = 0.15
Answer : B
Question: Two trains of equal lengths take 10 sec and 15 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
A.16 sec
B.12 sec
C.41 sec
D.09 sec
Answer: B.12 sec
Explanation: Speed of the first train = 120/10 = 12 m/sec.
Speed of the second train = 120/5 = 8 m/sec.
Relative speed = 12 + 8 = 20 m/sec.
Required time = (120 + 120)/20
=12 sec.
Answer: B
Question: A man invested Rs. 14,400 in Rs. 100 shares of a company at 20% premium.If the company declares 5% dividend at the end of the year,then how much does he get ?
A.Rs. 500
B.Rs. 600
C.Rs. 650
D.Rs. 720
Answer: B.Rs. 600
Explanation: Solution
Number of shares = (14400/120) = 120.
Face value = Rs. (100x120 ) = Rs. 12000.
Annual income = Rs.(5/100x12000) = Rs. 600.
Answer B
Question: In a school with 5 classes, each class has 2 students less than the previous class. How many students are there in the largest class if the total number of students at school is 105?
A.24
B.25
C.26
D.27
Answer: B.25
Explanation: Let x be the number of students in the largest class.
Then x + (x-2) + (x-4) + (x-6) + (x-8) = 105
5x -20 = 105
5x = 125
x = 25
The answer is B.
Question: if radius of a circle is reduced by 10%,then how much % of its area will be reduced?
A.10%
B.19%
C.20%
D.36%
Answer: B.19%
Explanation: let initial radius=a then,area=πa^2.
new radius=90% of a=9a/10.new area=π*81a^2/100=81/100πa^2
reduce in area=[πa^2-81/100πa^2]=19/100πa^2
% reduce=[(19*πa^2/100)*(1*100/πa^2)]%=19%
answer B
Question: A box contains 100 balls, numbered from 1 to 100. If 3 balls are selected at random and with replacement from the box. If the 3 numbers on the balls selected contain two odd and one even. What is the probability G that the first ball picked up is odd numbered?
A.	0
B.	1/3
C.	1/2
D.	2/3
Answer: D.	2/3
Explanation: Answer-D
Selecting the balls either Even or Odd is having probability 50/100=1/2
We have already selected 3 balls with 2 odd numbers and 1 even number.
So we have 3 combinations OOE, OEO, EOO. We have 3 outcomes and 2 are favourable as in 2 cases 1st number is odd. So probability G is 2/3.D
Question: In a certain game, you perform three tasks. You flip a quarter, and success would be heads. You roll a single die, and success would be a six. You pick a card from a full playing-card deck, and success would be picking a spades card. If any of these task are successful, then you win the game. What is the probability of winning?
A.1/48
B.5/16
C.11/12
D.11/16
Answer: D.11/16
Explanation: Probability of event not happening is equal to (1 - Probability of event happening)
So, Probability NO heads=1/2
Probability NO number 6 =5/6
Probability NO picking a spades card =3/4
so, Probability NO winning = 1/2*5/6*3/4 = 15/48=5/16
Probability NO winning = 1 - 5/16 = 11/16 .
answer is D
Question: In a library, there are certain number of books on a shelf, ranging between 75 and 100. 1/6th of them are fiction and 12.5% of them are non-fiction. Find the number of books.
A.376
B.96
C.26
D.198
Answer: B.96
Explanation: Explanation:
12.5% can be written as 1/8th
Since 1/6th of the books are fiction and 1/8th are non-fiction, the total number of books must be exactly divisible by 6 and 8 and should be between 75 and 100.
Therefore, 96 is the only number, which fulfills the above criteria.
Note that the question doesn't imply that there are ONLY two varieties of books.
ANSWER: B
Question: A, B and C rents a pasture for Rs.841. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should C pay?
A.270
B.289
C.267
D.261
Answer: D.261
Explanation: 12*8 :16*9 = 18*6
8: 12: 9
9/29 * 841 = 261
Answer: D
Question: The grade point average of the entire class is 88. If the average of one third of the class is 94, what is the average of the rest of the class?
A.82
B.83
C.84
D.85
Answer: D.85
Explanation: Let x be the number of students in the class.
Let P be the average of the rest of the class.
88x = (1/3)94x + (2/3)(P)x
264 = 94 + 2P
2P = 170
P = 85.
The answer is D.
Question: If the cost of 15 kgs of rice is Rs.780/-, what is the cost of 112 kgs of rice?
A.Rs.5824/-
B.Rs.5720/-
C.Rs.5616/-
D.Rs.5512/-
Answer: A.Rs.5824/-
Explanation: Explanation:
Cost of 1 kg of rice = Rs.780/15 = Rs.52.
Therefore, cost of 112 kgs. = Rs.52x112 = Rs.5824/-
Answer: Option A
Question: The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?
A.18%
B.17%
C.78%
D.13%
Answer: A.18%
Explanation: 1500 ---- 270
100 ---- ? => 18%
Answer: A
Question: A child received a gift of six different soccer team flags, including Liverpool and Arsenal. If he only has space in his bedroom to display four flags in a row, how many arrangements are possible if he cannot display the Liverpool and Arsenal flags at the same time?
A.162
B.216
C.272
D.360
Answer: B.216
Explanation: The total number of ways to choose and arrange 4 flags out of 6 is C^46∗4!=360(or directly P^46).
We cannot have Liverpool and Arsenal flags at the same time. The number of ways to have and arrange Liverpool and Arsenal flags at the same time is C24∗4!=144 (choosing 2 flags out of 4 remaining, without Liverpool and Arsenal, and then arranging 4 flags with 4!);
Total - Restriction = 360 - 144 = 216.
Answer: B.
Question: In a panel of 10 light bulbs, the odds of any light bulb to burn out are 0.02 at any given 10 minutes. Should a light bulb burn out, the whole panel would instantly turn off. What are the odds that the panel would be turned off within the first 10 minutes after it was switched on?
A.1-0.02^10
B.1-0.98^10
C.(1-0.98)^10
D.0.06
Answer: B.1-0.98^10
Explanation: ans B.
Prob that light will not turned off = 0.98^10. Hence prob (turn off) = 1 - prob (not turn off).
Question: 15 years hence, Karthik will be just Quadrice as old as he was 15 years ago, How old is Karthik at now? [ Quadrice = 4 Times ]
A.25
B.26
C.22
D.29
Answer: A.25
Explanation: A
25
Let the current age of Karthikh = A years
Then, A+15 = 4(A – 15)
Therefore A = 25
Question: If the 11th day of a month is three days earlier than Friday, What day will it be on the 20th day of the month?
A.Thursday
B.Monday
C.Sunday
D.Wednesday
Answer: A.Thursday
Explanation: Explanation:
Given that 11th day of a month is three days earlier than Friday
=> 11th day is Tuesday
=> 18th is Tuesday
=> 20th is Thursday
Answer: Option A
Question: Twenty times a positive Integer is less than its square by 96. What is the integer?
A.4
B.25
C.24
D.16
Answer: C.24
Explanation: Let the Integer be x.
Then X2 - 20X = 96
X2 - 20X - 96 = 0
X2 + 4X - 24X - 96 = 0 ===> X(X + 4) -24(X + 4)
===> (X + 4)(X-24)
X = -4 or 24. as the Integer is positive the correct answer is
option C)24
Question: A train running at the speed of 60 km/hr crosses a pole in 12 seconds. What is the length of the train?
A.200 metres
B.180 metres
C.324 metres
D.150 metres
Answer: A.200 metres
Explanation: Speed=60 x5/18m/sec=50/3	m/sec.
Length of the train = (Speed x Time).
Length of the train =	50/3	x 12m = 200 m.
ANSWER:A
Question: In Badminton game, one player throws two fair, six-sided die at the same time. If the player receives at least a five or a one on either die, that player wins. What is the probability that a player wins after playing the game once?
A.1/3
B.4/9
C.5/9
D.2/3
Answer: C.5/9
Explanation: In Badminton game, Probably the easiest approach would be to find the probability of the opposite event and subtract it from 1:
P(win) = 1- P(not win) = 1 - 4/6*4/6 = 5/9.
Answer: C.
Question: The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 70% profit?
A.277
B.1088
C.277
D.266
Answer: B.1088
Explanation: Let C.P. = Rs. x.
Then, 832 - x = x - 448
2x = 1280 => x = 640
Required S.P. = 170% of Rs. 640 = 170/100 * 640 = Rs. 1088.
Answer: B
Question: 1100 male students and 700 female students are examined in a monthly test; 42% of the male students and 30% of the female students only pass in the examination. Find the percentage of the total failed?
A.62*2/3
B.40*2/3
C.55*2/3
D.50*2/3
Answer: A.62*2/3
Explanation: Total number = 1100 + 700 = 1800.
tot students passed = (42% of 1100 + 30% of 700) - (462 + 210) = 672.
Number of failures = 1800-672 = 1128.
Percentage of failure = (1128/1800 * 100 )% = 62 * 2/3 %.
ANSWER A
Question: The decimal 0.1 is how many times greater than the decimal (0.0001)^3?
A.10^9
B.10^10
C.10^11
D.10^12
Answer: C.10^11
Explanation: 0.1 = 10^-1
(0.0001)^3 = (10^-4)^3 = 10^-12
10^11 * 10^-12 = 10^-1
The answer is C.
Question: John throws a coin until a series of five consecutive heads or three consecutive tails appears. What is the probability that the game will end after the sixth throw?
A.1/32
B.2/16
C.3/16
D.7/16
Answer: A.1/32
Explanation: Let's consider the routes that would lead to ending the game on the fourth toss. In order to be a win at that point, tosses #2#3#4 would all have to be the same, either H or T, and in order for the game NOT to end on the third toss, the first toss would have to be different from the other four. Thus, the only two possible sequences are
H-T-T-T-T-T ----> P = (1/2)^6 = 1/64
T-H-H-H-H-H ----> P = (1/2)^6 = 1/64
Either one of these would satisfy the condition, so we could have one or the other. OR means add in probability.
1/64 + 1/64= 2/64 = 1/32
Answer(A).
Question: A can do a work in 8 days. B can do the same work in 4 days. Both A&B together will finish the work and they got $1000 from that work. Find their shares?
A.600,400
B.500,500
C.400,200
D.800,200
Answer: C.400,200
Explanation: Ratio of their works A:B = 8:4
Ratio of their wages A:B = 2:1
A's share = (2/5)1000 = 400
B's share = (1/5)1000 = 200
correct option is C
Question: 4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days?
A.16
B.77
C.88
D.26
Answer: A.16
Explanation: Explanation:
Let the required number of bottles be x.
More weavers, More mats (Direct Proportion)
More days, More mats (Direct Proportion)
{\color{Blue} \left.\begin{matrix} weavers &4:8 \\ days& 4:8 \end{matrix}\right\}::4:x}
{\color{Blue}\therefore }4 x 4 x x = 8 x 8 x 4
{\color{Blue}\Rightarrow x=\frac{8\times 8\times 4}{4\times 4} }
{\color{Blue} \Rightarrow }x = 16.
Answer: A) 16
Question: In the formula V = 1/(4r)^2, if r is halved, then V is multiplied by
A.64
B.8
C.4
D.64
Answer: C.4
Explanation: Say r=2 => V1 = 1/64
when r=1; V2 = 1/16
V2 = 4*V1.
Answer=C=4
Question: The ratio of the cost price and the selling price is 4:5. The profit percent is?
A.75%.
B.27%.
C.25%.
D.45%.
Answer: C.25%.
Explanation: Let C.P. = Rs. 4x. Then, S.P. = Rs. 5x
Gain = (5x - 4x) = Rs. x
Gain % = (x * 100)/ 4x = 25%.
Answer:C
Question: The number of ways in which six boys and six girls can be seated in a row for a photograph so that no two girls sit together is?
A.8! * ⁷P₆
B.6! * ⁷P₆
C.9! * ⁷P₆
D.5! * ⁷P₆
Answer: B.6! * ⁷P₆
Explanation: We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.
Hence required number of ways
= 6! * ⁷P₆
Answer: B