RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Aravamudhan, Balakrishnan and Chinnan work in a developing software company in starting level positions. However their salaries are different. Aravamudhan's salary to Balakrishnan's salary and Balakrishnan's salary to Chinnan's salary are in the ratio 4:3. If the total salary of all the three employees is Rs.29230, what is the salary of Chinnan?
A.Rs.12640
B.Rs.9480
C.Rs.7110
D.Rs.8660
Answer: C.Rs.7110
Explanation: making them in equal proportion of Aravind:Bala:Cinnana=16:12:9
and given total salary 37*x=29230
x=790
Chinnana salary is 9*790=7110
ANSWER:C
Question: There are two positive integers a and b.What is the probability that a+b is odd/
A.3/2
B.6/7
C.1/2
D.7/2
Answer: C.1/2
Explanation: s=adding two numbers is (even+even),(even+odd),(odd+odd),(odd+even)
n(s)=4
e=(even+odd),(odd+even) are the points in the event.
n(e)=2
p(e)=n(e)/n(s)
=2/4
=1/2
Answer is option C
Question: A coin is tossed live times. What is the probability that there is at the least one tail?
A.31/32
B.31/36
C.31/27
D.31/28
Answer: A.31/32
Explanation: Let P(T) be the probability of getting least one tail when the coin is tossed five times.
= There is not even a single tail.
i.e. all the outcomes are heads.
= 1/32 ; P(T)
= 1 - 1/32
= 31/32
Answer: A
Question: If 70 percent of a class answered the first question on a certain test correctly, 55 percent answered the second question on the test correctly, and 20 percent answered neither of the questions correctly, what percent answered both correctly?
A.45%
B.40%
C.35%
D.30%
Answer: A.45%
Explanation: 70% answered the first question correctly and 20% answered neither correctly.
Then 10% missed the first question but answered the second question correctly.
Then the percent who answered both correctly is 55% - 10% = 45%.
The answer is A.
Question: 3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 4 men and 5 women will do that task.
A.13/14
B.13/10
C.13/18
D.13/16
Answer: A.13/14
Explanation: 3 m + 8 w = 6 m + 2 w
3 m = 6 w
1 m = 2 w
Therefore 3 m + 8 w = 14 w
4 m + 5 w =13 w
Answer is 13/14
Answer: A
Question: Find the surface area of a 12 cm x 4 cm x 3 cm brick.
A.84 cu cm.
B.124 cu cm.
C.164 cu cm.
D.192 cu cm.
Answer: D.192 cu cm.
Explanation: Sol.
Surface area = [2(12 x 4 + 4 x 3 + 12 x 3)]
= (2 x 96)
= 192 cu cm.
Answer D
Question: 1397 x 1397=?
A.1951609
B.1981709
C.18362619
D.2031719
Answer: A.1951609
Explanation: =(1397)^2
=(1400 - 3)^2
=(1400)^2+3^2-2 x 1400 x 3
=1960000+9-8400
=1960009-8400
=1951609
Answer is A
Question: A merchant marks his goods up by 40% and then offers a discount of 10% on the marked price. What % profit does the merchant make after the discount?
A.21%
B.26%
C.69%
D.31%
Answer: B.26%
Explanation: Let the price be 100.
The price becomes 140 after a 40% markup.
Now a discount of 10% on 140.
Profit=126-100
26%
answer B
Question: Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
A.33
B.289
C.48
D.77
Answer: C.48
Explanation: Relative speed = 45 + 30 = 75 km/hr.
75 * 5/18 = 125/6 m/sec.
Distance covered = 500 + 500 = 1000 m.
Required time = 1000 * 6/125 = 48 sec.
Answer: C
Question: A man's speed with the current is 12 km / hr and the speed of the current is 2 km / hr. The man's speed against the current i
A.8 km / hr
B.9 km / hr
C.10 km / hr
D.12.5 km / hr
Answer: A.8 km / hr
Explanation: Sol.
Man's rate in still in water = (12- 2) km / hr = 10km / hr.
Man's rate against the current = (10 - 2) km / hr = 8 km / hr.
Answer A
Question: A man is 24 years older than his son. In two years, his age will be twice the age of his son. The
present age of his son is
A.20 years
B.21 years
C.22 years
D.24 years
Answer: C.22 years
Explanation: Explanation:
Let the son's present age be x years. Then, man's present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22
Answer: Option C
Question: If f(x)=4x−1 and g(x)=2x+1 for all integers, which of the following is a possible value of g(f(x))?
A.-23
B.-17
C.0
D.8
Answer: B.-17
Explanation: g(f(x)) = 2*f(x)+1 = 2*(4x-1)+1 = 8x-1
Of these five options, only -17 has the form 8x-1.
The answer is B.
Question: In a tree, 1/5 of the birds are robins while the rest are bluejays. If 1/2 of the robins are female and 2/5 of the bluejays are female, what fraction of the birds in the tree are male?
A.9/25
B.12/25
C.17/25
D.29/50
Answer: D.29/50
Explanation: The fraction of birds that are male robins is (1/2)(1/5)=1/10.
The fraction of birds that are male bluejays is (3/5)(4/5)=12/25.
The total fraction of male birds is 1/10 + 12/25 = 29/50.
The answer is D.
Question: The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet?
A.12 a.m
B.13 a.m
C.14 a.m
D.11 a.m
Answer: D.11 a.m
Explanation: D
11 a.m
Suppose they meet x hrs after 8 a.m. Then,
(Distance moved by first in x hrs) + [Distance moved by second in (x - 1) hrs] = 330
60x + 75(x - 1) = 330 => x = 3
So, they meet at (8 + 3) i.e., 11 a.m.
Question: A man can row his boat with the stream at 36 km/h and against the stream in 8 km/h. The man's rate is?
A.1 kmph
B.6 kmph
C.7 kmph
D.14 kmph
Answer: D.14 kmph
Explanation: Explanation:
DS = 36
US = 8
S = ?
S = (36 - 8)/2 =14 kmph
Answer: D
Question: The avg weight of A,B & C is 50 kg. If D joins the group, the avg weight of the group becomes 53 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 51 kg. What is the weight of A?
A.56
B.65
C.73
D.89
Answer: C.73
Explanation: A + B + C = 3 *50 = 150
A + B + C + D = 4 * 53 = 212 ---- (i)
So, D = 62& E = 62 + 3 = 65
B + C + D +E = 51 * 4 = 204 --- (ii)
From Eq. (i) & (ii)
A-E = 212 – 204 = 8
A = E +8 = 65 + 8 = 73
Answer : C
Question: Ifaequals the sum of the even integers from 2 to 120, inclusive, andbequals the sum of the odd integers from 1 to 119, inclusive, what is the value of a - b ?
A.60
B.10
C.19
D.20
Answer: A.60
Explanation: This is a solution from Beatthegmat:
even numbers:
(120-2)/2 + 1 = 60 even integers.
(120+2)/2 = 61 is the average of the even set.
sum = avg*(#of elements) = 61*60 =3660 = a
odd numbers:
(119-1)/2 + 1 = 60 odd integers.
(119+1)/2 = 60 is the average of the odd set.
sum = avg*(#of elements) = 60*60 = 3600 = b
a-b = 3660 - 3600 = 60. Answer : A
Question: A, B and C are entered into a partnership. A invested Rs.6500 for 6 months, B invested Rs.8400 for 5 months and C invested for Rs.10000 for 3 months. A is a working partner and gets 5% of the total profit for the same. Find the share of C in a total profit of Rs.7400.
A.288
B.1900
C.1287
D.1271
Answer: B.1900
Explanation: 65 * 6 : 84 * 5 : 100 * 3
26:28:20
C share = 74000 * 95/100 = 7030 * 20/74 => 1900
Answer: B
Question: The average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?
A.Rs.19
B.Rs.29
C.Rs.15
D.Rs.10
Answer: C.Rs.15
Explanation: Total members in the group = 7
Average amount = Rs. 20
Total amount with them = 7 * 20
= Rs. 140
One number has Rs. 50. So, the amount with remaining 6 people
= 140 - 50 = Rs. 90
The average amount with them = 90/6
= Rs.15.
Answer:C
Question: Solve the given two equations and find the inequality of X and Y. (a) x^2-1=0 and (b) y^2+4y+3=0
A.If x>y
B.If x>=y
C.If x<y
D.If x<=y
Answer: B.If x>=y
Explanation: Solution:-
X=+1,-1 and Y= -1,-3
Comparing we get X>=Y
B
Question: A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
A.7 sec
B.6 sec
C.4 sec
D.5 sec
Answer: B.6 sec
Explanation: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [110 * 3/55] sec = 6 sec
Answer:B
Question: AB + CD = RRR, where AB and CD are two-digit numbers and RRR is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?
A. 1
B. 3
C. 7
D. 9
Answer: D. 9
Explanation: AB and CD are two digit integers, their sum can give us only one three digit integer of a kind of RRR it's 111.
So, A=1. 1B+CD=111
Now, C can not be less than 9, because no to digit integer with first digit 1 (mean that it's<20) can be added to two digit integer less than 90 to have the sum 111 (if CD<90 meaning C<9 CD+1B<111) --> C=9
Answer: D.
Question: Working together, printer A and printer B would finish the task in 40 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 4 pages a minute more than printer A ?
A.250
B.375
C.450
D.480
Answer: D.480
Explanation: 40*A + 40*B = x pages
in 40 mins printer A will print = 40/60 * x pages = 2/3*x pages
thus in 40 mins printer printer B will print x - 2/3*x = 1/3*x pages
Also it is given that printer B prints 4 more pages per min that printer A. In 40 mins printer B will print 160 more pages than printer A
thus 2/3*x - 1/3*x = 160 => x = 480 pages
Answer: D
Question: A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:
A.65
B.24
C.52
D.77
Answer: B.24
Explanation: Explanation:
Let the ten's and unit's digit be x and 8/x respectively.
Then,
(10x + 8/x) + 18 = 10 * 8/x + x
9x2 + 18x - 72 = 0
x2 + 2x - 8 = 0
(x + 4)(x - 2) = 0
x = 2
So, ten's digit = 2 and unit's digit = 4.
Hence, required number = 24.
Answer: B
Question: A train passes a man standing on the platform. If the train is 170 meters long and its speed is 72 kmph, how much time it took in doing so?
A.6 ½ sec
B.6 ½ sec
C.9 ½ sec
D.8 ½ sec
Answer: D.8 ½ sec
Explanation: D
8 ½ sec
D = 170
S = 72 * 5/18 = 20 mps
T = 170/20 = 8 ½ sec
Question: Walking at 8KMPH From Point W to Point railway station, mike will miss the train by 5 minutes. If he walks at 10KMPH he will reach the station by 5 minutes early.What is the distance between Point W to Railway station?
A.A)9KM
B.B)6.66KM
C.C)7.25KM
D.D)12.40KM
Answer: B.B)6.66KM
Explanation: Since time differences given are in minutes so let's convert speed in Km per minute
8 kmph = 8/60 km per minute = (2/15) km per minute
10 kmph = 10/60 km per minute = (1/6) km per minute
Let, Time of train to depart from station = t minutes
Distance between Point W and Railway Station = Speed*Time = (2/15)*(t+5)
Distance between Point W and Railway Station = Speed*Time = (1/6)*(t-5)
i.e. (2/15)*(t+5) = (1/6)*(t-5)
i.e. 12t+60 = 15t - 75
i.e. 3t = 135
i.e. t = 45 minutes
i.e. Distance = (1/6)*(t-5) = (1/6)*(45-5) = 40/6 = 20/3 Km = 6.66 Km
Answer: Option B
Question: The first year, two cows produced 8100 litres of milk. The second year their production increased by 15% and 10% respectively, and the total amount of milk increased to 9100 litres a year. How many litres were milked the second cow in the second year?
A.4730 lt
B.4356 lt
C.7665 lt
D.2314 lt
Answer: A.4730 lt
Explanation: Let x be the amount of milk the first cow produced during the first year. Then the second cow produced (8100−x) litres of milk that year. The second year, each cow produced the same amount of milk as they did the first year plus the increase of 15% or 10%
So 8100+15/100⋅x+10/100⋅(8100−x)=9100
Therefore 8100+320x+110(8100−x)=9100
120x=190
x=3800
Therefore, the cows produced 3800 and 4300 litres of milk the first year, and 4370 and 4730 litres of milk the second year, respectively.
correct answer A
Question: It takes 3 workers a total of 12 hours to build a giant machine with each worker working at the same rate. If 4 workers start to build the machine at 11:00 AM, and one extra worker per hour is added beginning at 3:00 PM, at what time will the machine be complete?
A.5:30
B.5:45
C.6:00
D.6:15
Answer: D.6:15
Explanation: 3 workers build 1/12 of a machine in one hour.
1 worker builds 1/36 of a machine in one hour.
In the first 4 hours, 4 workers build 4*(1/36)*4=16/36 of a machine
From 3:00 to 4:00, 5 workers build another 5/36. The total is 21/36.
From 4:00 to 5:00, 6 workers build another 6/36. The total is 27/36.
From 5:00 to 6:00, 7 workers build another 7/36. The total is 34/36.
To build another 2/36, 8 workers need (2/8)*60 minutes which is 15 minutes.
The machine is complete at 6:15.
The answer is D.
Question: A meal cost $ 35.50 and there was no tax. If the tip was more than 10 pc but less than 15pc of the price, then the total amount paid should be:
A.40-42
B.39-41
C.38-40
D.37-39
Answer: B.39-41
Explanation: 10%(35.5) = 3.55
15%(35.5) = 5.325
total amount could have been 35.5+3.55 and 35.5+5.325
=> could have been between 39.05 and 40.625
=> approximately between 39 and 41
Answer is B.
Question: Which one of the following is the common factor of (47^43 + 43^43) and (47^47 + 43^47) ?
A.(2+56)
B.(47+43)
C.(3+7)
D.(4+9)
Answer: B.(47+43)
Explanation: Explanation:
When n is odd, (x^ + a^n) is always divisible by (x + a).
Each one of (47^43 + 43^43) and (47^47 + 43^47) is divisible by (47 + 43).
B
Question: What is the sum of the prime factors of 3 and the prime factors of 1656?
A.35
B.45
C.55
D.25
Answer: A.35
Explanation: The prime factors of 3 are 3*1
The prime factors of 1656 are 2x2x2x3x3x23
2+2+2+3+3+23 = 35. A is the correct answer
Question: If 105 divides into n with no remainder, which of the following must be a factor of n?
A.2
B.4
C.6
D.7
Answer: D.7
Explanation: 105 / n = k (with k an integer)
(7)(5)(3) / n = k
n must have a 7 in his prime factorization to divide 105 without remainder.
answer D
Question: Two numbers are in the ratio of 5:9. If 25 be subtracted from each, they are in the ratio of 35:59. Find the numbers?
A.150,170
B.150,270
C.50,270
D.180,270
Answer: B.150,270
Explanation: (5x-25):(9x-25) = 35:59
x = 30 => 150,270
ANSWER:B
Question: On Monday morning, Chris receives tickets to a baseball game that will be played at 7pm on the next evening that it does not rain. However, Chris is only in town until Wednesday morning, at which point he must fly to another city. If there is a 70% chance of rain each of the next two evenings, what is the probability that Chris will be able to attend the game?
A. 36%
B. 51%
C. 66%
D. 80%
Answer: B. 51%
Explanation: Chris won't be able to attend the game if it be raining on Monday eveningandTuesday evening. The probability of that is 0.7*0.7 = 0.49. So, the probability that he will be able to attend is 1 - 0.49 = 0.51.
Answer: B.
Question: How many 2 3/4 foot pieces of cable can be cut out of a piece that is 30 feet long?
A.a.10
B.b.16
C.c.17
D.d.18
Answer: A.a.10
Explanation: Pretty Simple..the answer is choice (A) 10.
All that one has to do is :
1: Convert 2 3/4 into an improper fraction (11/4) or a decimal (2.75)
2: Divide 30 by 11/4 (or 2.75)
Answer =10 (A)
Question: The perimeter of one square is 44 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?
A.13√4
B.12.1√2
C.23√2
D.12√4
Answer: B.12.1√2
Explanation: 4a = 44 4a = 20
a = 11 a = 5
a2 = 121 a2 = 25
Combined area = a2 = 146 => a = 12.1
d = 12.1√2
Answer: B
Question: Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 9 hours. How many hours will take C alone to fill the tank?
A.23/2
B.41/3
C.49/4
D.54/5
Answer: D.54/5
Explanation: The rate of A+B+C is 1/6 of the tank per hour.
After 2 hours, the tank is 1/3 full.
The rate of A+B is 2/3 * 1/9 = 2/27 of a tank per hour.
The rate of C is 1/6 - 2/27 = 5/54
C can fill the tank in 54/5 hours.
The answer is D.
Question: The difference between a number and its three-fifths is 50.What is the number?
A.75
B.100
C.125
D.Cannot be determined
Answer: C.125
Explanation: Suppose the number is N.
Then N - 3⁄5N = 50
⇒ 2N⁄5 = 50
∴ N=50×52=125
Answer.C
Question: Number N is randomly selected from a set of all primes between 10 and 40, inclusive. Number Z is selected from a set of all multiples of 5 between 10 and 40 inclusive. What is the probability that N+Z is odd?
A. 1/2
B. 2/3
C. 3/4
D. 4/7
Answer: D. 4/7
Explanation: All primes except 2 are odd, thus N must be odd. For N + Z = odd + Z to be odd, Z must be even.
There are 7 multiples of 5 between 10 and 40, inclusive: 10, 15, 20, 25, 30, 35, and 40. Out of them 3 (15, 25, and 35) are odd.
Therefore the probability that N + Z is odd is 4/7.
Answer: D.
Question: A person starting with Rs.64 & making 6 bets, wins three times and loses 3times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If eachwager is for half the money remaining at thetime of the bet, then the final result is?
A.Rs.37
B.Rs.57
C.Rs.60
D.Rs.64
Answer: A.Rs.37
Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply initial amount by 1.5 thrice and by 0.5 thrice (in any order).
The overall resultant will remain same.
So final amount with the person will be (in all cases):
=64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)==64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs 2727
Hence the final result is:
64−27=3764−27=37:
A loss of Rs.37
A
Question: When 100 is divided by positive integer x, the remainder is 4. What is the remainder when 196 is divided by x?
A.2
B.3
C.4
D.6
Answer: C.4
Explanation: f100/x leaves a reminder 4 then (100-4) i.e. 96 is divisible by x
So (100+96)/x leaves a reminder rem(100/x)+rem(96/x)=> 4+0=4
Answer :C
Question: An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq. m ?
A.Rs. 4082.40
B.Rs. 1024.21
C.Rs. 2810.6
D.Rs. 3214
Answer: A.Rs. 4082.40
Explanation: Explanation:
Length of the first carpet = (1.44)(6) = 8.64 cm
Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m = (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 x 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40
ANSWER IS A
Question: If 3 persons can do 3 times of a particular work in 3 days, then, 7 persons can do 7 times of that work in?
A.2 days
B.3 days
C.5 days
D.7 days
Answer: B.3 days
Explanation: That is, 1 person can do one time of the work in 3 days.
Therefore, 7 persons can do 7 times work in the same 3 days itself.
B)
Question: Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 48 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
A. 15 seconds
B. 18 seconds
C. 24 seconds
D. 30 seconds
Answer: C. 24 seconds
Explanation: used pluging in method
say t is the time for cristina to catch up with Nicky, the equation will be as under:
for Nicky=N=3*t+48
for Cristina=C=5*t
@t=24, N=120 C=120 right answer
ans:C
Question: Number of divisors of 22050 except 1 and itself is.
A.22
B.52
C.87
D.26
Answer: B.52
Explanation: Explanation: 2 22050 3 11025 3 3675 5 1225 5 245 7 49 7 ⇒ 22050 = 21 × 32 × 52 × 72 Using the formula discussed earlier, ∴ Number of divisors = (1+1) (2+1) (2+1) (2+1) = 54 ∴ Number of divisors except 1 and itself = 54 –2 = 52
Answer:B
Question: Paul completes a piece of work in 80 days, Rose completes the same work in 120 days. If both of them work together, then the number of days required to complete the work is?
A.42
B.44
C.46
D.48
Answer: D.48
Explanation: If A can complete a work in x days and B can complete the same work in y days, then, both
of them together can complete the work in x y/ x+ y days.
That is, the required No. of days = 80 × 120/200 = 48 days
Answer is D
Question: If log303 = a, log305 = b, then log308 =?
A.3(1 - a - b)
B.(a - b + 1)
C.(1 - a - b)
D.(a - b + 1)
Answer: A.3(1 - a - b)
Explanation: a + b = log3015 = log30(30/2) = 1- log302
=> log302 = (1 - a - b)
Therefore, log308 = 3(1 - a - b).
ANSWER:A
Question: If the height of an equilateral triangle QBC is equal in length to the hypotenuse of an isosceles right triangle DEF, a side of ΔQBC is how many times as long as a leg of the right triangle DEF?
A.(√2)/(√3)
B.(√3)/(√2)
C.√2
D.(2√2)/(√3)
Answer: D.(2√2)/(√3)
Explanation: Side of the equilateral triangle QBC = 2m ----> height = m * sqtr(2)
Hipotenuse of the right triangle QBC = m * sqrt(3) ----> side = m * sqtr(3) / sqtr(2)
Question is 2m/m * sqtr(3) / sqtr(2) = 2*sqrt(2)/sqrt(3)=D
Question: If a-b= 6 and a^2+b^2=100, find the value of ab
A.10
B.32
C.15
D.18
Answer: B.32
Explanation: 2ab = (a^2 + b^2) - (a - b)^2
= 100 - 36 = 64
=> ab = 32
ANSWER:B
Question: Find the area of a parallelogram with base 24 cm and height 16 cm.
A.384 cm^2
B.200 cm^2
C.250 cm^2
D.350 cm^2
Answer: A.384 cm^2
Explanation: Area of a parallelogram = base * height = 24 * 16 = 384 cm2
ANSWER A
Question: If Q is an odd number and the median of Q consecutive integers is 110, what is the largest of these integers?
A.(Q - 1)/2 + 110
B.Q/2 + 109
C.Q/2 + 110
D.(Q + 109)/2
Answer: A.(Q - 1)/2 + 110
Explanation: Consider the easiest case, say Q=3, then;
Set = {109, 110, 111};
The largest integer = 111.
Now, plug Q=3 into the answers to see which yields 111.
Answer: A.
Question: The area of one square is x^2 + 10x + 25 and the area of another square is x^2 − 6x + 9. If the sum of the perimeters of both squares is 32, what is the value of x?
A.3
B.2
C.2.5
D.4.67
Answer: A.3
Explanation: spotting the pattern of equations both are in form of (X+C)^2 so
A1= (x+5)^2A2= (x-3)^2
L1= x+5L2= -3
P1 = 4( x+5)P2=4(x-3)
P1+P2=32
4( x+5) +4(x-3)=32.....3
Ans :A
Question: What is the value of 3x^2 − 2x + 0.3 for x = 0.5?
A.−0.3
B.0
C.0.05
D.1.08
Answer: C.0.05
Explanation: 3x^2-2x+0.3 for x=0.6
=3(0.5*0.5)-4*0.5*(0.5)+0.3
=-0.5*0.5+0.3
=-0.25+0.3
=0.05
Correct Option : C
Question: A certain manufacturer of cake, muffin, and bread mixes has 90 buyers, of whom 50 purchases cake mix, 40 purchase muffin mix, and 20 purchase both cake mix and muffin mix. If a buyer is to be selected at random from the 100 buyers, what is the probability that the buyer selected will be one who purchases neither cake mix nor muffin mix?
A.a. 1/10
B.b. 3/10
C.c. 1/3
D.d. 7/10
Answer: C.c. 1/3
Explanation: C+M+B-CM-MB-CB-2CMB = 90
C - cake buyers, M - muffin and B - Bread buyers. CM,MB,CB and CMB are intersecting regions.
the question asks for people who have bought only bread mixes = B-CB-MB-2CMB has to be found out.
50 + 40 + B-CB-MB-20-2CMB = 90
B-CB-MB-2CMB = 30
hence the probability = 30/90 = 30/90=1/3.
C
Question: Find the C.I. on Rs. 15,625 for 9 months at 16% per annum compounded quarterly?
A.2776
B.2777
C.1951
D.2966
Answer: C.1951
Explanation: Explanation:
P = Rs. 15625, n = 9 months = 3 quarters, R = 16% p.a. per quarter.
Amount = [15625 * (1 + 4/100)3]
= (15625 * 26/25 * 26/25 * 26/25) = Rs. 17576 C.I. = 17576 - 15625 = Rs. 1951.
Answer: C
Question: In my core I have 5 But 500 stand in the beginning and the end of mine. I also include the first letter and the first number to make me complete. I am the name of a King.
Who am I?
A.Johny
B.Jacky
C.Ricky
D.David
Answer: D.David
Explanation: D
I am DAVID.
At the core I have 5
If we talk in roman numeric system, 5 = V
Similarly, 500 stands in the beginning and end
500 = D
I also include the first letter i.e. A and the first number i.e. I (in roman numeric system)
All of them combine to form DAVID.
Question: A train 120 m long passed a pole in 20 sec. How long will it take to pass a platform 780 m long?
A.150
B.170
C.160
D.100
Answer: A.150
Explanation: Speed = 120/20 = 6 m/sec.
Required time = (120 + 780)/6 = 150 sec.
Answer: Option A
Question: Raju age after 9 years will be 5 times his age 3 years back, What is the present age of Raju
A.8 years
B.7 years
C.6 years
D.5 years
Answer: C.6 years
Explanation: Explanation:
Clearly,
x+9 = 5(x-3)
<=> 4x = 24 => x = 6
Option C