RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A man's speed with the current is 20 kmph and speed of the current is 6 kmph. The Man's speed
against the current will be
A.11 kmph
B.12 kmph
C.14 kmph
D.8 kmph
Answer: D.8 kmph
Explanation: Explanation:
Speed with current is 20,
speed of the man + It is speed of the current
Speed in sƟll water = 20 - 6 = 14
Now speed against the current will be
speed of the man - speed of the current
= 14 - 6 = 8 kmph
Answer: D
Question: In a group of ducks and cows, the total number of legs are 24 more than twice the number of heads. Find the total number of cows.
A.12
B.14
C.16
D.18
Answer: A.12
Explanation: Let the number of ducks be d
and number of cows be c
Then, total number of legs = 2d + 4c = 2(d + 2c)
total number of heads = c + d
Given that total number of legs are 24 more than twice the number of heads
=> 2(d + 2c) = 24+ 2(c + d)
=> d + 2c = 12 + c + d
=> 2c = 12 + c
=> c = 12
i.e., total number of cows = 12
Answer is A.
Question: I bought three toys for my triplet boys (one for each). I placed the toys in the dark store. One by one each boy went to the store and pick the toy. What is the probability that no boy will choose his own toy?
A.1/4
B.1/3
C.1/6
D.2/3
Answer: B.1/3
Explanation: B
1/3
Assuming T1 is the Toy for brother1, T2 is the toy for brother2 and T3 is the toy for brother3.
Following are the possible cases for toys distribution:
Boy1 Boy2 Boy3
T1 T2 T3
T1 T3 T2
T2 T1 T3
T2 T3 T1 .... (A)
T3 T1 T2 .... (B)
T3 T2 T1
In both steps (A) & (B), no one gets the correct toy.
Therefore probability that none brother can get the own toy is 2/6 = 1/3
Question: Present ages of X and Y are in the ratio 5:6 respectively. Seven years hence this ratio will become 6:7 respectively. What is X's present age in years?
A.40
B.35
C.28
D.49
Answer: B.35
Explanation: Let the present ages of X and Y be 5x and 6x years respectively.
Then, (5x + 7)/(6x + 7) = 6/7
7(5x + 7) = 6(6x + 7) => x = 7
X's present age = 5x = 35 years.
ANSWER B
Question: n a 1000m race, if A gives B a start of 40m, A wing by 19sec. But if A gives B start of 30sec, B wins by 40m.
Find the time taken by B to run 4000m race?
A.500
B.700
C.400
D.600
Answer: D.600
Explanation: then 960/B -1000/A = 19 => 24/B - 25/A = 19/40
and 1000/B - 960/A = 30 => 25/B - 24/A = 30/40
solving equation A speed =8 and B=20/3
for 1000m b will take 4000/20/3= 600 sec
D
Question: Out of 10 persons working on a project, 4 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?
A.5/5
B.5/8
C.5/1
D.5/6
Answer: D.5/6
Explanation: P(at least one graduate) = 1 - P(no graduates)
= 1 - 6C3/10C3
= 1 - (6 * 5 * 4)/(10 * 9 * 8)
= 5/6
Answer:D
Question: K and L start the business, with L investing the total capital of Rs. 40,000 on the condition that K pays L interest @ 8% per annum on his half of the capital. L is a working partner and receives Rs.1200 per month from the total profit and any profit reamaining is equally shared by both of them. At the end of the year, it was found that the income of L is twice that of K. Find the total profit for the year ?
A.46409
B.46400
C.46129
D.46411
Answer: B.46400
Explanation: Interest received by L from K = 8% of half of Rs.40,000
= Rs.1600
Amount received by L per annum for being a working partner = 1200\small \times12 = Rs.14,400
Let 'A' be the part of remaing profit that 'L' receives as his share.
Total income of 'K' = only his share from the reamaing profit
= 'A', as both share equally.
Given income of L = Twice the income of K
Rightarrow (1600 + 14400 + A ) = 2A
Rightarrow A= Rs.16000
Thus total profit = 2A + Rs.14,400= 2(16000) + 14400
= 32000 +14400 = Rs.46,400.
Answer: B
Question: What is the median from the below series
90, 92, 93, 88, 95, 88, 97, 87, and 98
A.85
B.89
C.92
D.98
Answer: C.92
Explanation: Ordering the data from least to greatest, we get:
87, 88, 88, 90, 92, 93, 95, 96, 98
The median score is 92.
C
Question: A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered.If the area of the field is 600 sq.ft, how many feet of fencing will be required ?
A.80feet
B.70feet
C.60feet
D.50feet
Answer: A.80feet
Explanation: Explanation:
We are given with length and area, so we can find the breadth.
as Length * Breadth = Area
=> 20 * Breadth = 600
=> Breadth = 30 feet
Area to be fenced = 2B + L = 2*30 + 20
= 80feet
Answer: Option A
Question: The population of a town is 7600. It decreases annually at the rate of 10% p.a. What was its population 2 years ago?
A.9400
B.8000
C.8500
D.9500
Answer: A.9400
Explanation: Formula :
( After =100 denominator
Ago = 100 numerator)
7600 Ã— 100/90 Ã— 100/90 = 9382
A)
Question: A boat can move upstream at 33 kmph and downstream at 35 kmph, then the speed of the current is?
A.1
B.2
C.7
D.8
Answer: A.1
Explanation: US = 33
DS = 35
M = (35 - 33)/2 = 1
Answer: A
Question: If a certain number is divided by 3, the quotient, dividend, and divisor, added together, will amount to 63. What is the number?
A.18
B.28
C.45
D.38
Answer: C.45
Explanation: Let x = the number sought.
Then x/3 + x + 3 = 63.
And x = 45.
C
Question: nd the area of trapezium whose parallel sides are 20 cm and 15 cm long, and the distance between them is 14 cm?
A.230cm2
B.245cm2
C.255cm2
D.260cm2
Answer: B.245cm2
Explanation: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (20 + 15) * (14)
= 245 cm2
Answer:B
Question: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money M did Bob receive?
A.20
B.22
C.24
D.26
Answer: B.22
Explanation: Notice that we need not consider Ann's portion in the solution. We can just let K = the money REMAINING after Ann has received her portion and go from there.
Our equation will use the fact that, once we remove Bob's portion, we have $32 for Chloe.
So, we getK - Bob's $ = 32
Bob received 4 dollars plus one-third of what remained
Once Bob receives $4, the amount remaining is K-4 dollars. So, Bob gets a 1/3 of that as well.
1/3 of K-4 is (K-4)/3
So ALTOGETHER, Bob receives4 + (K-4)/3
So, our equation becomes:K -[4 + (K-4)/3 ]= 32
Simplify to get: K - 4 - (K-4)/3 = 32
Multiply both sides by 3 to get: 3K - 12 - K + 4 = 96
Simplify: 2K - 8 = 96
Solve: K = 52
Plug this K-value intoK - Bob's $ = 32to get: 52 - Bob's $ = 32
So, Bob's $ M= 20
Answer:
B
Question: A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is :
A.Rs. 700
B.Rs. 690
C.Rs. 650
D.Rs. 698
Answer: D.Rs. 698
Explanation: Explanation:
Simple Interest (SI) for 1 year = 854-815 = 39
Simple Interest (SI) for 3 years = 39 × 3 = 117
Principal = 815 - 117 = Rs.698
Answer: Option D
Question: A train ,140 meters long travels at a speed of 45 km/hr crosses a bridge in 30 seconds. The length of the bridge is
A.270 m
B.245 m
C.235 m
D.220 m
Answer: C.235 m
Explanation: Explanation:
Assume the length of the bridge = x meter
Total distance covered = 140+x meter
total time taken = 30s
speed = Total distance covered /total time taken = (140+x)/30 m/s
=> 45 Ã— (10/36) = (140+x)/30
=> 45 Ã— 10 Ã— 30 /36 = 140+x
=> 45 Ã— 10 Ã— 10 / 12 = 140+x
=> 15 Ã— 10 Ã— 10 / 4 = 140+x
=> 15 Ã— 25 = 140+x = 375
=> x = 375-140 =235
Answer: Option C
Question: Points A, B, and, C have xy-coordinates (2,0), (8,12), and (14,0), respectively. Points X, Y, and Z have xy-coordinates (6,0), (8,4), and (10,0), respectively. What fraction C of the area of triangle ABC is the area of triangle XYZ?
A. 1/9
B. 1/8
C. 1/6
D. 1/5
Answer: A. 1/9
Explanation: If you notice, both triangles ABC and XYZ have a side on X axis. we can take these sides as bases for each triangle, therefore
Area of ABC is 1/2*12*12 (Height of ABC is the y coordinate of the third point (8,12))
similarly Area of XYZ is 1/2*4*4
dividing area of XYZ with that of ABC gives C= 1/9.A
Question: In how many different number of ways 6 men and 2 women can sit on a shopa which can accommodate persons?
A.1250
B.1640
C.1240
D.1680
Answer: D.1680
Explanation: 8p4 = 8 x 7 x 6 × 5 = 1680
D)
Question: The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
A.228
B.267
C.200
D.750
Answer: D.750
Explanation: Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 25 è x = 25 * 60 / 2 = 750 .Answer: D
Question: If L = 775 × 778 × 781, what is the remainder when L is divided by 14?
A.6
B.7
C.8
D.9
Answer: A.6
Explanation: L 775/14 leaves a remainder 5
778/14 leaves a remainder 8
781/14 leaves a remainder 11
5*8*11 =440
So the remainder will be the remainder of 440/14 which is 6
Ans A
Question: Two persons A and B can complete a piece of work in 20 days and 40 days respectively. If they work together, what part of the work will be completed in 5 days?
A.1/8
B.1/3
C.3/6
D.3/8
Answer: D.3/8
Explanation: A's one day's work = 1/20
B's one day's work = 1/40
(A + B)'s one day's work = 1/20 + 1/40 = 3/40
The part of the work completed in 5 days = 5 (3/40) = 3/8.
Answer:D
Question: The division of a whole number N by 14 gives a quotient of 18 and a remainder of 2. Find N.
A.797
B.254
C.597
D.997
Answer: B.254
Explanation: According to the division process of whole numbers, N can be written, using multiplication, as follows
N = quotient *divisor + remainder = 18* 14 + 2 = 254 correc answer B
Question: If 2/3 of the air in a tank is removed with each stroke of a vacuum pump, how many strokes does it take before less than 1% of the original amount of air in the tank remains?
A. 2
B. 3
C. 4
D. 5
Answer: D. 5
Explanation: My approach is to find more or less good number and plug in. Lets take 90 as the total volume of an air, and the question asks after how many stokes there will be less than 0,9 air in a tank, if each stroke takes 2/3 of an air.
So after he1 strokethe volume will be 30 (90-60=30), and so on
2 stroke- 30-20=10
3 stroke- 10-6,7=3,3
4 stroke- 3,3-2,2=1,1
5 stroke- 1,1 - minus something that gets us less than 0,9 for sure. so the answer is: after 5 strokes there will be less than 1% of air left in a tank. OptionD.
Question: A man jumps into a river from a overbridge ,at the same time a hat drops in the river which flows with the stream of the water. That man travels 10 minute upstream and returns back where he was asked to catch the hat. He catches hat at a distance of 1000 yard down at a second bridge . Find the speed of the river.
A.50 yards per minute
B.40 yards per minute
C.60 yards per minute
D.55 yards per minute
Answer: A.50 yards per minute
Explanation: Suppose x is the distance travelled by the man in 10 min upstream.
Then
x/(v-u) = 10 where v is man's speed and u is river speed)
total time taken to swim by the man upstream and down stream is equal to the time taken by the hat to travel 1000 yards with the speed of river
1000/u = 10 + (x+1000)/(u+v)
now substitute x = 10(v-u) and simplify
we will get
100v = 2uv
means
2u = 100 and u = 50 yards per minute
ANSWER:A
Question: Two cars cover the same distance at the speed of 48 and 64 kmps respectively. Find the distance traveled by them if the slower car takes 1 hour more than the faster car.
A.87
B.138
C.192
D.83
Answer: C.192
Explanation: Explanation:
48(x + 1) = 64x
X = 3
48 * 4 = 192 km
Answer: Option C
Question: total dinning bill of 5 people was $139.00 and 10% tip divided the bill evenly ?what is the bill amount each person shared .
A.32.84
B.22.84
C.30.58
D.24.84
Answer: C.30.58
Explanation: dinner bill of 5 person = 139 + 10% tip
so,
10% of 139 = (139*10)/100 = 13.9
So, the actual total amount = 139+13.9 = $ 152.9
so per head bill = 152.9/5 = $ 30.58
ANSWER:C
Question: The distance between Delhi and Mathura is 170 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet?
A.10.50 a.m.
B.11.20 a.m.
C.10.30 a.m.
D.11.40 a.m.
Answer: B.11.20 a.m.
Explanation: D = 170 â€“ 20 = 150
RS = 20 + 25 = 45
T = 150/45 = 3 1/3 hours
8 a.m. + 3 hrs 20 min = 11.20 a.m.
ANSWER:B
Question: If f(x)= 5x^3- 2x+8 and g(y)= 6y+4, then g(f(x)) =
A.30x^3-12x+52
B.11x^2-12x+44
C.8x^3-8x+32
D.30x^3+4x+4
Answer: A.30x^3-12x+52
Explanation: g(f(x)) = 6(f(x)) +4 = 6(5x^3- 2x+8) + 4 = 30x^3-12x+52 =>A
Question: A walks around a circular field at the rate of one round per hour while B runs around it at the rate of six rounds per hour. They start in the same direction from the same point at 7.30 a.m. They shall first cross each other at:
A.5.30 a.m
B.6.42 a.m
C.7.55 a.m
D.7.42 a.m
Answer: D.7.42 a.m
Explanation: Sol.
Since A and B move in the same direction along the circle, so they will first meet each other when there is a difference of one round between the two
Relative speed of A and B = (6-1) = 5 rounds per hour.
Time taken to complete one round at this speed = 1/5 hr = 12 min.
Answer D
Question: If 5a + 7b = t, where a and b are positive integers, what is the largest possible value of t for which exactly one pair of integers (a, b) makes the equation true?
A.35
B.48
C.69
D.70
Answer: D.70
Explanation: 5*a1 + 7*b1 = t
5*a2 + 7*b2 = t
5*(a1 - a2) = 7*(b2 - b1)
since we are dealing with integers we can assume that a1 - a2 = 7*q and b2 - b1 = 5*q where q is integer, so whenever we get a pair for (a;b) we can find another one by simply adding 7 to a and subtracting 5 from b or vice versa, subtracting 7 from a and adding 5 to b.
Lets check how it works for our numbers, starting from the largest:
E)74 = 5*12 + 7*2 (a1 = 12, b1 = 2), subtract 7 fromaand add 5 tobrespectively, so a2 = 5 and b2 = 7, second pair - bad
D)70 = 5*7 + 7*5 (a1 = 7, b1 = 5), if we add 7 toawe will have to subtract 5 from b but b can't be 0, so - no pair, if we subtract 7 froma, we'll get a = 0 which also isn't allowed - no pair, thus this is the only pair for (a;b) that works,good!, thus
D is the answer
Question: A software programmer does 20% of the work in 80% of the time, and 80% of the work in the remaining 20% of the time. If the code he writes is X lines long and he was given one month (30 days) to accomplish the task, then, assuming that the programmer works at a constant rate in each of the two stages, How many lines of code were written in the last two weeks, in terms of X?
A.13x /15
B.15x/15
C.7x/15
D.2x/30
Answer: A.13x /15
Explanation: 30 days- X lines
80% of 30
24 days; 0.2X lines
Remaining 6 days:
0.8X lines
Need to find out for last 14 days;
We know the number of lines for last 6 days: 0.8X
How about 8 days before that;
24 days- 0.2X
1 day - 0.2X/24 lines
8 days - (0.2X/24)*8 lines = (1/15)X lines
Total number of lines in last 14 days
(1/15)x + 0.8X = (1/15)x + (8/10)X = (52/60)X = (13/15)X lines of codes
ANSWER:A
Question: In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 12 to the thrice of the remainder. The dividend is
A.74
B.78
C.86
D.126
Answer: D.126
Explanation: Divisor = (6 * 3) + 12 = 30
5 * Quotient = 30
Quotient = 6.
Dividend = (Divisor * Quotient) + Remainder
Dividend = (20 * 6) + 6 = 126.
D)
Question: The length of a room is 5.5 m and width is 3.75 m. Find the cost of paving the floor by slabs at the rate of Rs. 1000 per sq. metre.
A.Rs. 15000
B.Rs. 15550
C.Rs. 15600
D.Rs. 20625
Answer: D.Rs. 20625
Explanation: Solution
Area of the floor = (5.5 × 3.75) m2 = 20.625 m2
∴ Cost of paving = Rs. (1000 × 20.625) = 20625. Answer D
Question: What must be added to each term of the ratio 7:11, So as to make it equal to 3:4?
A.8
B.7.5
C.6.5
D.5
Answer: D.5
Explanation: Solution: Let x be added to each term.
According to question,
(7+x)/(11+x) = 3/4;
Or, 33+3x = 28+4x;
Or, x = 5.
Answer: Option D
Question: The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?
A.270
B.250
C.245
D.320
Answer: A.270
Explanation: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Smaller number = 270.
ANSWER A
Question: A ladder 14 feet long is leaning against a wall that is perpendicular to level ground. The bottom of the ladder is 9 feet from the base of the wall. If the top of the ladder slips down 1 feet, how many feet will the bottom of the ladder slip?
A.4
B.10
C.18
D.19
Answer: B.10
Explanation: 14^2-9^2=115
it means that the height is equal to 10.72.
since the top of the ladder slips down 1 feet, then the height of the wall =10.72-1=9.72
the bottom =sqrt(14^2-9.72^2)=sqrt(196-94.47)=10.07~=10
ans is B
Question: What day of the week was 1 January 1901
A.Monday
B.Tuesday
C.Saturday
D.Friday
Answer: B.Tuesday
Explanation: Explanation:
1 Jan 1901 = (1900 years + 1st Jan 1901)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfect multiple of 400)
Number of odd days in the period 1601-1900
= Number of odd days in 300 years
= 5 x 3 = 15 = 1
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
1st Jan 1901 = 1 odd day
Total number of odd days = (0 + 1 + 1) = 2
2 odd days = Tuesday
Hence 1 January 1901 is Tuesday.
Answer: Option B
Question: ((-1.9)(0.6) – (2.6)(1.2))/2.0 = ?
A.-0.71
B.-2.13
C.1.07
D.1.71
Answer: B.-2.13
Explanation: Dove straight into calculation
((-1.9)(0.6) – (2.6)(1.2))/2.0 = -2.13
Answer B
Question: Jayant opened a shop investing Rs. 30,000. Madhu joined him 2 months later, investing Rs. 45,000. They earned a profit of Rs. 52,000 after completion of one year. What will be Madhu's share of profit?
A.Rs. 27,000
B.Rs. 26,000
C.Rs. 30,000
D.Rs. 36,000
Answer: B.Rs. 26,000
Explanation: 30,000 *12=45,000*8
1:1
Madhu's share=1/2*52,000
i.e. Rs. 26,000
ANSWER:B
Question: lexus car agency has 189 cars.he sold some cars at 9% profit and rest at 36% profit thus he gains 17% on the sale of all his cars.the no. of cars sold at 36% profit is?
A.56
B.37
C.38
D.39
Answer: A.56
Explanation: ratio of 36% profit cars to 9% profit cars = 8:19
so no. of cars sold at 36% profit = 189*8/27= 56 cars
ANSWER:A
Question: Tom, working alone, can paint a room in 10 hours. Peter and John, working independently, can paint the same room in 5 hours and 2 hours, respectively. Tom starts painting the room and works on his own for two hour. He is then joined by Peter and they work together for two hour. Finally, John joins them and the three of them work together to finish the room, each one working at his respective rate. What fraction of the whole job was done by Peter?
A.1/3
B.1/2
C.1/4
D.1/5
Answer: B.1/2
Explanation: Let the time when all three were working together be t hours. Then:
Tom worked for t+4 hour and has done 1/10*(t+4) part of the job;
Peter worked for t+2 hour and has done 1/5*(t+2) part of the job;
John worked for t hours and has done 1/2*t part of the job:
1/10*(t+4)+1/5*(t+2)+1/2*t=1 --> multiply by 10 --> (t+4)+(2t+2)+5t=10 --> t=1/2;
Hence Peter has done 1/5*(1/2+2)=1/5 *5/2=1/2
Answer: B
Question: A group consists of 5 men, 5 women and 3 children. In how many ways can 2 men , 2 women and 1 child selected from the given group?
A.300 ways
B.400 ways
C.500 ways
D.360 ways
Answer: A.300 ways
Explanation: Two men, two women and one child can be selected in 5C₂ * 5C2 * 3C₁ ways
5*4/2*1*5*4/2*1*3
= 300 ways
Answer : A
Question: A butler is promised Rs. 100 and a cloak as his wages for a year. After 7 months he leaves this service, and receives the cloak and Rs.20 as his due. How much is the cloak worth?
A.22
B.98
C.92
D.72
Answer: C.92
Explanation: Explanation:
Let be the price of cloak is = x
According to the Question he should get 7/12th of 100 and 7/12th of cloak.
712(100)+712(x)=20+x712(100)+712(x)=20+x
⇒ x = 92.
Answer: C
Question: A barrel holds 4 litres of paint and 4 litres of turpentine. How many quarts of turpentinemust be added to the container to create a mixture that is 3 parts petrol to 5 parts turpentine by volume?
A.4/3
B.5/3
C.7/3
D.8/3
Answer: D.8/3
Explanation: An alternate to the alligation method is the more direct/algebraic method:
Let x be the amount of turpentine to be added.
New total amount of turpentine = 4+x
Total amount of paint = 4
New total = 4+4+x=8+x
Final ratio required (for turpentine) = 5/(5+3)=5/8
Thus, (4+x)/(8+x) = 5/8 --> solving for x you get x = 8/3.
D is thus the correct answer.
Question: A car covers a certain distance at aspeed of 50 kmph in 5 hours. To cover the same distance in 2 hrs, it must travel at a speed of?
A.125 km/hr
B.678 km/hr
C.782 km/hr
D.789 km/hr
Answer: A.125 km/hr
Explanation: Distance = (50 x 5) =250 km.
Speed = Distance/Time
Speed = 250/2 = 125 kmph
Answer : A
Question: Jim’s Taxi Service charges an initial fee of $2.25 at the beginning of a trip and an additional charge of $0.25 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles?
A.$3.15
B.$4.5
C.$4.80
D.$5.05
Answer: B.$4.5
Explanation: Let the fixed charge of Jim’s Taxi Service = 2.25 $
and charge per 2/5 mile(.4 mile) = .25$
Total charge for a trip of 3.6 miles = 2.25 + (3.6/.4) * .25
= 2.25 + 9*.25
= 4.5 $
Answer B
Question: If it is 7:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location.)
A.7:22
B.7:24
C.7:27
D.7:30
Answer: D.7:30
Explanation: 7:27minus 2,880,717in any way must end with 0, the only answer choice which ends with 0 is D.
Answer: D.
Question: In covering a distance of 90 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:
A.5 km/h
B.8 km/h
C.10 km/h
D.15 km/h
Answer: D.15 km/h
Explanation: Let A's speed be X km/hr.
Then, 90/x - 90/2x = 3
6x = 90
x = 15 km/hr.
Answer : D.
Question: What will come in place of the x in the following number series? 1, 4, 10, 22, 46, x
A.84
B.92
C.94
D.98
Answer: C.94
Explanation: 11 × 2 + 2 = 44 × 2 + 2 = 1010 × 2 + 2 = 2222 × 2 + 2 = 4646 × 2 + 2 = 94 C
Question: In a certificate by mistake a candidate gave his height as 20% more than actual height. In the interview panel, he clarified that his height was 5 feet 5 nches. Find the % correction made by the candidate from his stated height to his actual height?
A.13
B.20
C.30
D.43
Answer: A.13
Explanation: His height was = 5 feet 5 inch = 5 + 60 = 65 inch. Required % correction =65*(1.20-1) = 13
A
Question: A person crosses a 600 metre long street in 5 minutes. What is his speed in km per hour?
A.8.2
B.4.2
C.6.1
D.7.2
Answer: D.7.2
Explanation: Distance =600 metre =0.6 km
Time = 5 min = 1/12 hr
speed = dist/time = 0.6/(1/2) = 7.2 km/hr
ANSWER D
Question: The volume of the sphere QQ is (dfrac{37}{64}%)less than the volume of sphere PP and the volume of sphere RR is (dfrac{19}{27}%) less than that of sphere QQ. By what is the surface areaof sphere RR less than the surfacearea of sphere PP?
A.50%
B.60%
C.75%
D.80%
Answer: C.75%
Explanation: Let the volume of sphere PP be 64 parts.
Therefore volume of sphere QQ
=64−3764%=64−3764% of 6464
=64−37=27=64−37=27 parts.
The volume of RR
=27−1927×27=27−1927×27
=27−19=8=27−19=8 parts.
Volume ratio:
=P:Q:R=64:27:8=P:Q:R=64:27:8
Radius ratio:
=P:Q:R=4:3:2=P:Q:R=4:3:2
The surface area will be 16:9:516:9:5
Surface area of RR is less than the surface area of sphere PP
16k−4k=12k16k−4k=12k
Now,
=12k16k×100=12k16k×100
=75%=75%
Thus surface area of sphere RR is less than the surface area of sphere P by 75%
C
Question: An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:
A.4.04%
B.4.14%
C.4.16%
D.4.20%
Answer: A.4.04%
Explanation: 100 cm is read as 102 cm.
A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.
(A2 - A1) = [(102)2 - (100)2]
= (102 + 100) x (102 - 100)
= 404 cm2.
Percentage error = 404 x 100 % = 4.04%
100 x 100
A)