RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a factory, there are 40% technicians and 60% non-technicians. If the 60% of the technicians and 40% of non-technicians are permanent employees, then the percentage of workers who are temporary is?
A.52
B.32
C.62
D.25
Answer: A.52
Explanation: Total = 100
T= 40 NT= 60
40*(60/100)=24 60*(40/100)=24
24 + 24 = 48 => 100 - 48 = 52%
ANSWER A
Question: Which of the following is a pair of Co - Primes ?
A.14,35
B.18,25
C.31,92
D.32,62
Answer: B.18,25
Explanation: Co Primes - two numbers are said to be co prime if their HCF is 1.
18 and 25 are co prime numbers. ANSWER : B
Question: Kim bought a total of $2.65 worth of postage stamps in four denominations. If she bought an equal number of 5-cent and 25-cent stamps and twice as many 10-cent stamps as 5-cent stamps, what is the least number of 3-cent stamps she could have bought ?
A. 5
B. 10
C. 15
D. 20
Answer: A. 5
Explanation: 2.65 = 0.05x + 0.25x + 2 * 0.10x + 0.03y
=> 2.65 = 0.30x + 0.20x + 0.03y
=> 265 = 50x + 3y
So Max value of 50x < 265 = 250
Hence y = 5
Answer - A
Question: A committee is reviewing a total of 40x black-and-white films and 10y color films for a festival. If the committee selects y/x% of the black-and-white films and all of the color films, what fraction of the selected films are in color?
A.50/52
B.55/52
C.60/52
D.40/52
Answer: A.50/52
Explanation: Say x=y=10. In this case we would have:
40x=400 black-and-white films;
10y=100 color films.
y/x%=10/10%=1% of the black-and-white films, so 4 black-and-white films and all 100 color films, thus total of 104 films were selected.
Color films thus compose 100/104=50/52 of the selected films.
Answer: A
Question: For every even positive integer m, f(m) represents the product of all even integers from 2 to m, inclusive. For example, f(12)=2x4x6x8x10x12. What is the greatest prime factor of f(28)?
A.2
B.7
C.11
D.13
Answer: D.13
Explanation: f(28) = 2*4*6*8*10*12*14*16*18*20*22*24*26*28
The greatest prime factor in this list is 13.
The answer is D.
Question: IF 2+3=13 ; 3+5=31 ; 5+7=59, Then 7+9=?
A.95
B.86
C.67
D.98
Answer: A.95
Explanation: 2 X 2 + 3^2 = 4 + 9 = 13
3 X 2 + 5^2= 6 + 25 = 31
5 X 2 + 7^2= 10 + 49 = 59
and
7 X 2 + 9^2= 14 + 81 = 95
ANSWER:A
Question: The average marks of a class of 30 students is 40 and that of another class of 50 students is 70. Find the average marks of all the students?
A.52.5
B.52.9
C.52.1
D.58.75
Answer: D.58.75
Explanation: Sum of the marks for the class of 30 students = 30 * 40 = 1200
Sum of the marks for the class of 50 students = 50 * 70 = 3500
Sum of the marks for the class of 80 students =
1200 + 3500 = 4700
Average marks of all the students = 4700/80
= 58.75
Answer:D
Question: In a stream running at 2 Kmph, a motor boat goes 10 Km upstream and back again to the starting point in 55 minutes. Find the speed of motor boat in still water?
A.11
B.15
C.22
D.18
Answer: C.22
Explanation: Let the speed of motor boat instill water be X kmph
Then, speed in downstream = (X + 2) km
and. speed in upstream = (X - 2) kmph
Time taken to row 10km & back = (10/X+2,10/X-2)
10/X+2 + 10/X-2 = 55/60
11X2 - 240X - 44 = 0
(X - 22)(11x + 2) = 0
X = 22 or X = -2/11
Then X = 22 kmph
Answer is C.
Question: A can give B 100 meters start and C 120 meters start in a kilometer race. How much start can B give C in a kilometer race?
A.10.22 meters
B.11.22 meters
C.22.22 meters
D.33.22 meters
Answer: C.22.22 meters
Explanation: Explanation:
A runs 1000 meters while B runs 900 meters and C runs 880 meters.
Therefore, B runs 900 meters while C runs 880 meters.
So, the number of meters that C runs when B runs 1000 meters = (1000 x 880)/900 = 977.778 meters
Thus, B can give C (1000 - 977.77) = 22.22 meters start
Answer: C
Question: In a certain game, a large bag is filled with blue, green, purple and red chips worth 1, 5, x and 11 points each, respectively. The purple chips are worth more than the green chips, but less than the red chips. A certain number of chips are then selected from the bag. If the product of the point values of the selected chips is 28160, how many purple chips were selected?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: 28160 = 1*5*8^3*11
The factors of 8 must come from the purple point value, so there are 3 purple chips.
The answer is C.
Question: A school currently maintains a fixed number of students per class. If the ratio of students per class were to be increased by 1, 10 fewer classes would be run for a total of 120 students. What is the current ratio T of students per class?
A.T=3
B.T=4
C.6
D.8
Answer: A.T=3
Explanation: Another way to look at the problem...
Since the total is 120, RATIO * CLASSES = R*C = 120.....(i)
we are looking where ratio increases by 1 and # of classes decreases by 10 = (R+1)(C-10) = RC+C-10R-10=120....(ii)
(ii)-(i)....
C=10R+10 = 10(R+1).......
so # of classes has to be multiple of 10
AS RC=120.... 10(R+1)*R = 120...................R(R+1) = 12..
so 12 is a multiple of consecutive numbers ONLY 3 *4 fits in..... and R=3
A
Question: In a certain lottery, the probability that a number between 14 and 20, inclusive, is drawn is 1/6 . If the probability that a number 14 or larger is drawn is 2/3 , what is the probability that a number less than or equal to 20 is drawn?
A. 1/18
B. 1/6
C. 1/2
D. 1/3
Answer: C. 1/2
Explanation: You can simply use sets concept in this question. The formula
Total = n(A) + n(B) - n(A and B) is applicable here too.
Set 1: Number 14 or larger
Set 2: Number 20 or smaller
1 = P(Set 1) + P(Set 2) - P(Set 1 and Set 2) (combined probability is 1 because every number will be either14 or moreOR20 or lessOR both)
2/3 + P(Set 2) - 1/6 = 1
P(Set 2) = 1/2
Answer (C)
Question: A question paper consists of five problems, each problem having three internal choices. In how many ways can a candidate attempt one or more problems?
A.1028
B.1024
C.1023
D.1025
Answer: C.1023
Explanation: Explanation:
Given that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.
Hence, the required number of ways = 45 - 1.
= 210 - 1 = 1024 - 1 = 1023
Answer:C
Question: A cube is divided into 729 identical cubelets. Each cut is made parallel to some surface of the cube . But before doing that the cube is coloured with green colour on one set of adjacent faces ,red on the other set of adjacent faces, blue on the third set. So, how many cubelets are there which are painted with exactly one colour?
A.293
B.294
C.295
D.296
Answer: B.294
Explanation: total cubes created are 729
so a plane of big cube has 9*9 cubes
out of that(n-2)*(n-2)=7*7=49 are painted only one side
and a cube has six sides=6*49=294
ANSWER:B
Question: What is the radius of a circle that has a circumference of 3.14 meters?
A.0.1
B.0.3
C.0.5
D.0.7
Answer: C.0.5
Explanation: Circumference of a circle = 2πr.
Given, circumference = 3.14 meters.
Therefore,
2πr = Circumference of a circle
or, 2πr = 3.14.
or, 2 * 3.14r = 3.14,[Putting the value of pi (π) = 3.14].
or, 6.28r = 3.14.
or, r = 3.14/6.28.
or, r = 0.5.
correct answer C
Question: Johnop went up a certain hill at the rate of one and a half kilometers per hour and came down at the rate of four and a half kilometers per hour, so that it took just four hours to make the double journey. How far was it to the top of the hill ?
A.3 km
B.6 km
C.4.5 km
D.km
Answer: C.4.5 km
Explanation: Assume the distance to the top of the hill (1 way) as: x
Now, speed=distance/time => time=distance/speed
So, for the first half of the journey, he traveled uphill at 1.5km/hr, so the time taken for the first leg of the journey is: x/1.5.
For the second half, he traveled downhill at 4.5km/hr, so the time taken for the second leg of the journey is: x/4.5
Now, the total time for the trip is given as 4 hrs.
Equating, (x/1.5)+(x/4.5)=4 => (3x+x)/4.5=4 => x=4.5 km
So, the distance one side is = 4.5 km.
The OA mentioned is 9km, which is exactly double of this distance, i.e., the total distance traveled during both legs of the journey, but the question only asked for the distance till the top of the hill, i.e., one way, so the answer should be 4.5km
Can someone assist me in understanding where am I wrong here?
Question: P and Q entered into a partnership investing Rs. 16,000 and Rs. 12,000 respectively. After 3 months, A withdrew Rs.5000 while B invested Rs. 5000 more. After 3 more months, C joins the business with a capital of Rs. 21,000. The share of B exceeds that of C, out of a total profit of Rs. 26,400 after one year by:
A.Rs.2400
B.Rs.3000
C.Rs.3600
D.Rs.4800
Answer: C.Rs.3600
Explanation: A : B : C = (16000 x 3 + 11000 * 9) : (12000 * 3 + 17000 * 9) : (21000 * 6)
= 147 : 189 : 126 = 7 : 9 : 6.
Therefore, Difference of B and C’s shares = Rs. 26400 x 9/22 – 26400 x 6/22
= Rs.3600
ANSWER:C
Question: Of the teams competing in the world archery championships, Fifty percent are from Europe. Half as many are from the United States and one twentieth are from Africa. What fraction of teams are from neither Europe, the US or Africa.
A.13/20
B.4/20
C.13/15
D.17/20
Answer: B.4/20
Explanation: Assume 100 total people.
50% of 100 = 50 --->Europeans
1/2 of 50 ---> 25 Americans
1/20 of 100 ---> 5 Africans
Now you would add them all up, and minus it by the total (100). 100 - 80= 20. So, 20 people out of 100 are not EU, US or Africans. 20/100 is also equal to 4/20.
So therefore, the answer is B.
Question: An empty fuel tank with a capacity of 212 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 30 gallons of ethanol, how many gallons of fuel A were added?
A.160
B.98
C.100
D.80
Answer: B.98
Explanation: Say there are A gallons of fuel A in the tank, then there would be 212-A gallons of fuel B.
The amount of ethanol in A gallons of fuel A is 0.12A;
The amount of ethanol in 212-A gallons of fuel B is 0.16(212-A);
Since the total amount of ethanol is 30 gallons then 0.12A+0.16(212-A)=30 --> A=98.
Answer: B.
Question: In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:
A.2700
B.2800
C.2000
D.2500
Answer: A.2700
Explanation: Number of valid votes = 80% of 7500 = 6000.
Valid votes polled by other candidate = 45% of 6000
=(45/100)x 6000= 2700.
ANSWER A
Question: If s > x > y > z on the number line, y is halfway between x and z, and x is halfway between w and z, then (y - x)/(y - s) =
A.1/4
B.1/3
C.1/2
D.3/4
Answer: B.1/3
Explanation: Let y-z=t ---> since y is halfway between x and z and x>y we have x-y=t. Moreover x-z=(x-y)+(y-z)=2t. Similarly since x is halfway between w and z, we have s-x=2t. So y-x=-t, y-s=-3t. ---> (y - x)/(y - s) = 1/3.
The answer is (B).
Question: In how many ways can the letters of wordTECHNOLOGYbe arranged such that all the Consonants always appear together?
A.9!
B.4!*7!
C.5!*5!
D.5!*4!*2!
Answer: B.4!*7!
Explanation: Let the arrangment be: _ _ _ _ _ _ _ _ _ _ (10 letters, 3 vowels E, O, O and 7 consonant T, C, H, N, L, G, Y)
For all consonants together, consider them as 1 group {T, C, H, N, L, G, Y} E O O --> this gives us 4! arrangements with {} group considered as 1 . Now {} group can in itself be arranged in 7! ways
Thus total arrangements with all consonants together = 4!*7! --> B is the correct answer.
Question: The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 60 metres?
A.11 seconds
B.88 seconds
C.99 seconds
D.12 seconds
Answer: D.12 seconds
Explanation: Speed of the boat downstream = 15 + 3 = 18 kmph
= 18 * 5/18 = 5 m/s
Hence time taken to cover 60 m = 60/5 = 12 seconds.Answer: D
Question: If p(x)=ax^4+bx^3+cx^2+dx+e has roots at x=1,2,3,4 and p(0)=48, what is p(5)
A.48
B.24
C.0
D.50
Answer: A.48
Explanation: p(x)=ax^4+bx^3+cx^2+dx+e
it can be written as
p(x)=a*(x-1)*(x-2)*(x-3)*(x-4) ----(1)
put x=0 in(1), we get
p(0)=a*(-1)(-2)(-3)(-4)
=> 48=a*24
=> a=2
so, p(x)=2*(x-1)*(x-2)*(x-3)*(x-4)
=> p(5)=2*(5-1)*(5-2)*(5-3)*(5-4)=2*4*3*2*1=48
p(5) = 48
ANSWER:A
Question: A person earns 15% on investment but loses 10% on another investment. If the ratio of the two investments be 3:5, what is the gain or loss on the two investments taken together?
A.0.63 %
B.0.64 %
C.0.65 %
D.0.66 %
Answer: A.0.63 %
Explanation: Sol.
Suppose he invested 300 & 500 respectively profit : 15% of 300 = 45 loss =
500 *10 = 50 net loss = - 5 5/800 *100 = 0.63 %
Answer A
Question: On a sum of money, the simple interest for 2 years is Rs. 320, while the compound interest is Rs. 340, the rate of interest being the same in both the cases. The rate of interest is
A.15%
B.14.25%
C.12.5%
D.10.5%
Answer: C.12.5%
Explanation: Explanation:
--------------------------------------------------------------------------------------
Solution 1
---------------------------------------------------------------------------------------
Simple interest for 2 years is Rs. 320
=> Simple interest for first year = 320/2 = 160
=> Similarly, simple interest for second year is also 160
Compound Interest for first year = 160
Compound Interest for second year = 340-160 = 180
we can see that compound Interest for second year is more than
simple interest for second year by 180-160 = 20
i.e., Rs.20 is the simple interest on Rs.160 for 1 year
R = 100 × SI/PT = (100 × 20)/(160 × 1) = 12.5%
--------------------------------------------------------------------------------------
Solution 2
---------------------------------------------------------------------------------------
The difference between compound interest and simple interest on Rs. P for 2 years at R% per annum
= (R × SI)/(2 × 100)
Difference between the compound interest and simple interest = 340 - 320 = 20
(R × SI)/(2 × 100) = 20
(R × 320)/(2 × 100) = 20
R = 20 × 100 × 2320 = 12.5%
Answer: Option C
Question: What will be the compound interest on a sum of Rs. 27,000 after 3 years at the rate of 12% p.a.?
A.s.10123.77
B.s.10123.21
C.s.10933.05
D.s.10123.28
Answer: C.s.10933.05
Explanation: Amount = [27000 * (1 + 12/100)3]
= 27000 * 28/25 * 28/25 * 28/25
= Rs. 37933.0
C.I. = (37933.056 - 27000)
= Rs. 10933.05
Answer:C
Question: In an encryption code 'PLAYS' is written as '{:SUD' when encoded and 'SLEEP' is written as 'D:RR{' when encoded. How is ''SLAPPY" written in that encryption code?
A.D:S{{U
B.SLAPPY
C.{RUDD:
D.{:SUU{
Answer: A.D:S{{U
Explanation: D = S
: = L
S = A
P = {
P = {
Y = U
Correct Answer: A
Question: The average of 10 consecutive integers is 25. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average?
A.19
B.19.5
C.20
D.20.5
Answer: D.20.5
Explanation: The total subtracted is (9+8+...+1) = (9*10) / 2 = 45
On average, each number will be reduced by 45/10 = 4.5
Therefore, the overall average will be reduced by 4.5
The answer is D.
Question: Amber works 8 days a month at d dollars per day for m months out of the year. Which of the following represents her monthly pay?
A.8d
B.20d
C.10md/6
D.20d/m
Answer: A.8d
Explanation: ANSWER: A The passage states that she works 8 days a month at d dollars per day, so 8 d is her monthly pay
Question: Jimâ€™s Taxi Service charges an initial fee of $2.25 at the beginning of a trip and an additional charge of $0.3 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles?
A.$3.15
B.$4.95
C.$4.80
D.$5.05
Answer: B.$4.95
Explanation: Let the fixed charge of Jimâ€™s Taxi Service = 2.25 $
and charge per 2/5 mile(.4 mile) = .3$
Total charge for a trip of 3.6 miles = 2.25 + (3.6/.4) * .3
= 2.25 + 9*.3
= 4.95 $
Answer B
Question: Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
A.50
B.88
C.77
D.66
Answer: A.50
Explanation: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 46 - 36 = 10 km/hr.
= 10 * 5/18 = 25/9 m/sec.
2x/36 = 25/9 => x = 50.
Answer: A
Question: The speed of the train, 150m long, is 50km/hr. How much time will it take to pass a platform 600m long?
A.74 secs.
B.64 secs.
C.54 secs.
D.44 secs.
Answer: C.54 secs.
Explanation: Distance covered = ( 150+600)= 750 m Speed =50km/hr=(50*5/18)=125/9m/s Time taken =750/125*9 =54 secs. Answer : C
Question: $392 is divided among A, B, and C so that A receives half as much as B, and B receives half as much as C. How much money is C's share?
A.$212
B.$216
C.$220
D.$224
Answer: D.$224
Explanation: Let the shares for A, B, and C be x, 2x, and 4x respectively.
7x = 392
x = 56
4x = 224
The answer is D.
Question: If it takes 6 identical printing presses exactly 4 hours T to print 5,000 newspapers, how long would it take 3 of these presses to print 3,000 newspapers?
A.3 hours, 20 minutes
B.4 hours, 20 minutes
C.4 hours, 48 minutes
D.5 hours, 48 minutes
Answer: C.4 hours, 48 minutes
Explanation: 6 presses - 5,000 newspapers - 4 hours ;
3 presses - 2,500 newspapers - 4 hours ;
3 presses - 3,000 newspapers - 4 hours + 1/5*4 hours = 4 hours, 48 minutes (since 2,500+1/5*2,500=3,000) = T.
Answer: C.
Question: A and B put in Rs.300 and Rs.400 respectively into a business. A reinvests into the business his share of the first year's profit of Rs.210 where as B does not. In what ratio should they divide the second year's profit?
A.39:40
B.40:39
C.3:4
D.4:3
Answer: A.39:40
Explanation: 3: 4
A = 3/7*210 = 90
390: 400
39:40
ANSWER:A
Question: How much water should be added to 11 liters of a 20%-solution of alcohol to reduce the concentration of alcohol in the solution by 75% ?
A.25 liters
B.29 liters
C.30 liters
D.32 liters
Answer: B.29 liters
Explanation: Let x ltr water to be added
2ltr alcohol to be represented as (20(1-3/4(new soln.=11+x)))
2=5%*(11+x)-------->x=29
Ans B
Question: A hat company ships its hats, individually wrapped, in 8-inch by 10-inch by 12-inch boxes. Each hat is valued at $7.50. If the company’s latest order required a truck with at least 240,000 cubic inches of storage space in which to ship the hats in their boxes, what was the minimum value of the order?
A.$960
B.$1,875
C.$1,725
D.$2,050
Answer: B.$1,875
Explanation: Number of boxes= Total volume/volume of one box= 240,000/ (8*10*12)= 250
One box costs 7.50, so 250 box will cost= 250*7.5= 1875
B is the answer
Question: The 80-milliliter solution of sugar and water is 25% sugar. How much water (in milliliters) must be added to make a solution that is 5% sugar?
A.300
B.320
C.340
D.360
Answer: B.320
Explanation: In the original solution the amount of sugar is 0.25*80=20 ml.
Let the volume of the new solution be V.
0.05V=20 ml.
V=400 ml.
The amount of water we need to add is 400 - 80 = 320 ml.
The answer is B.
Question: Consider a right triangle RBC with length of sides being x,y and z where y represents the hypotenuse , Which of these represent the radius of the circle which is inscribed in triangle RBC
A.[A] x+y+z/3
B.[B] x-y+z/3
C.[C] x-y+z/2
D.[D] (x^2 + y^2 + z^2)/3
Answer: C.[C] x-y+z/2
Explanation: Radius of a circle inscribed in the right triangle RBC r = (x + z - y)/2 where y is the hypotenuse and x and y are other two sides.
Answer: C
Question: How many words of 11letters could be Formed with all the vowels present only in the even places ,and the consonants only in the odd places,using letters of english alphabet each letter may appear only once.
A.21!
B.26!/5!
C.21! /(5! * 5! )
D.21!* 5!/15!
Answer: C.21! /(5! * 5! )
Explanation: (21*20*19*18*17*16)*5! = 21! * 5! / 15!
ANSWER:C
Question: If 9a - b = 10b + 60 = -12b - 2a, what is the value of 11a + 11b?
A.-8
B.-4
C.0
D.4
Answer: C.0
Explanation: (i) 9a - 11b = 60
(ii) 2a + 22b = -60
Adding (i) and (ii):
11a + 11b = 0
The answer is C.
Question: A survey was sent to 65 customers, 7 of whom responded. Then the survey was redesigned and sent to another 63 customers, 9 of whom responded. By approximately what percent did the response rate increase from the original survey to the redesigned survey?
A.2%
B.4%
C.14%
D.28%
Answer: B.4%
Explanation: case 1: (7/65)=x/100
x=10%
case 2: (9/63)=y/100
y=14%
So percent increase is =(y-x)=(14-10)%=4%
Answer is B
Question: What least value should be replaced by * in 842*124 so the number become divisible by 9
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: Explanation:
Trick: Number is divisible by 9, if sum of all digits is divisible by 9, so (8+4+2+*+1+2+4) = 21+* should be divisible by 9,
21+6 will be divisible by 9,
so that least number is 6.
Answer: Option D
Question: What is the CP of Rs 100 stock at 4 discount, with 1/5% brokerage?
A.99.6
B.96.2
C.97.5
D.98.25
Answer: B.96.2
Explanation: Explanation:
Use the formula,
CP= 100 – discount + brokerage%
CP= 100-4+1/5
96.2
Thus the CP is Rs 96.2.
ANSWER B
Question: P and Q are in a relay race. P runs the first leg of the course in 3 seconds. Q runs the second leg of the course in 57 seconds. What was the average time they took to run a leg of the course?
A.30
B.32
C.34
D.36
Answer: A.30
Explanation: (3 seconds +57 seconds)/2= 30 seconds
Correct option is: A
Question: Exactly 3/8 of the people in the room are under the age of 21, and exactly 5/12 of the people in the room are over the age of 65. If the total number of the people in the room is greater than 50 and less than 100, how many people in the room are under the age of 21?
A.21
B.36
C.39
D.60
Answer: B.36
Explanation: The total number of the people in the room must be a multiple of both 8 and 12 (in order 3/7 and 5/13 of the number to be an integer), thus the total number of the people must be a multiple of LCM of 8 and 12, which is 96.
Since, the total number of the people in the room is greater than 50 and less than 100, then there are 96 people in the room.
Therefore there are 3/8*96=36 people in the room under the age of 21.
Answer: B.
Question: What is the sum of the multiples of 4 between 38 and 127 inclusive?
A.1804
B.1816
C.1824
D.1828
Answer: A.1804
Explanation: the fastest way in an AP is to find the average and multiply with total integers..
between 38 and 127, the smallest multiple of 4 is 40 and largest =124..
average=(40+124)/2=164/2=82..
total numbers = (124-40)/4 + 1= =84/4+1=27+1=22..
sum=82*22=1804
ans A
Question: A fort had provision of food for 150 men for 45 days. After 10 days, 30 men left the fort. The number of days for which the remaining food will last, is:
A.29 1/5
B.37 1/4
C.43 3/4
D.54
Answer: C.43 3/4
Explanation: After 10 days : 150 men had food for 35 days.
Suppose 120 men had food for x days.
Now, Less men, More days (Indirect Proportion)
Therefore 120 : 150 :: 35 : x <=> 120 x x = 150 x 35
=> x =150 x 35/120
=> x = 43 3/4.
Correct answer is C
Question: A train of 25 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
A.2 mins 14 sec
B.2 mins 34 sec
C.180 sec
D.4 mins 54 sec
Answer: C.180 sec
Explanation: D = 25 * 60 + 1500 = 3000 m
T = 3000/60 * 18/5 = 180 sec
ANSWER:C
Question: If 4 men can paint 60 m long wall in 3 days, then 5 men can paint 50 m long wall in
A.3days
B.2days
C.5days
D.6days
Answer: B.2days
Explanation: The length of wall painted by one man in one day = 60 / 4 Ã— 3 = 5 m
No. of days required to paint 50 m wall by 5 men = 50/ 5 Ã— 5 = 2 day.
B
Question: if a tap could fill entire tank in 18 hrs due to leakage, then in how much time tank can be emptied by leakage if tap can fill entire tank in 12 hrs without leakage?
A.35 hrs
B.36 hrs
C.37 hrs
D.38 hrs
Answer: B.36 hrs
Explanation: if a tap could fill entire tank in 18 hrs due to leakage,
tap can fill entire tank in 12 hrs without leakage.
Tank emptied in 0ne hr by leakage = 1/12-1/18= (6-4)/72=2/72=1/36.
Full Tank can be emptied in 36 hrs.
ANSWER:B
Question: Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
A.10
B.12
C.15
D.18
Answer: B.12
Explanation: Speed of the first train =120/10m/sec = 12 m/sec.
Speed of the second train =120/15m/sec = 8 m/sec.
Relative speed = (12 + 8) = 20 m/sec.
Required time =(120 + 120)/20sec = 12 sec. ANSWER:B