RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The difference of the squares of two consecutive even integers is divisible by which of the following integers ?
A.2
B.3
C.4
D.8
Answer: C.4
Explanation: Let the two consecutive even integers be 2n and (2n + 2). Then,
(2n + 2)2 = (2n + 2 + 2n)(2n + 2 - 2n)
= 2(4n + 2)
= 4(2n + 1), which is divisible by 4.
Option C
Question: The cost of registration at a professional association meeting was $50 per person; a lunch for registrants only was available for an additional $22 per person. If the number of registrants who paid for lunch was 40 more than the number who did not, and if receipts for registration and lunch totaled $39,480, how many people paid just for registration at the meeting?
A.700
B.800
C.300
D.1,500
Answer: C.300
Explanation: Hope this might be useful to you.
Let the number of people who have opted only to register = x
Now since the registration cost is 50$ per person, the total amount sums to = 50x $
As per the information given in the question, the number of registrants who paid for lunch was 40 more than the number who did not. That means, total number of people who registered and paid for lunch = 40 + x.
For the people who registered for lunch the cost is 50 $ (for the event registration) + 22 $ (for lunch) = 72 $.
Total amount in this case sums to = 72(40 + x) = 2880 + 72x
Now, total amount received was 39480
Thus, from the above data,
50x + 2880 + 72x = 39480
122x = 39480 - 2880
122x = 36600
x = 300.
Hence the correct Ans is C
Question: A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
A.240 m
B.200 m
C.500 m
D.360 m
Answer: A.240 m
Explanation: Explanation:
Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x = 240 m.
Answer:A
Question: If the area of a circle is 64pi square feet, find its circumference.
A.16 pi feet
B.28 pi feet
C.38 pi feet
D.48 pi feet
Answer: A.16 pi feet
Explanation: The area is given by pi *r* r. Hence
pi * r *r = 64 pi
r * r = 64; hence r = 64 feet
The circumference is given by
2 * pi * r = 2 * pi * 8 = 16 pi feet
correct answer A
Question: George baked a total of 75 pizzas for 7 straight days, beginning on Saturday. He baked 3/5 of the pizzas the first day, and 3/5 of the remaining pizzas the second day. If each successive day he baked fewer pizzas than the previous day, what is the maximum number of pizzas he could have baked on Wednesday?
A.5
B.4
C.2
D.6
Answer: C.2
Explanation: 3/5 of the 75 pizzas cooked on Saturday = 45 pizzas
3/5 of the remaining pizzas on Sunday = 18 pizzas
We're left with (75-45-18) =12 pizzas for the remaining 5 days. The prompt tells us that each day has FEWER pizzas than the day before it, so we can't have duplicate numbers.
M T W TH F
5 4 2 1 0 =12
W=2
C
Question: One half of the people at the game wore the team colors. Two thirds of those people wore team
hats as well. One fourth of those with team colors and team hats had banners to wave.
Twenty five people had team colors and banners, but no hats. One hundred people had only
banners. If there were 1824 people at the game, how many had banners?
A.177
B.277
C.377
D.477
Answer: B.277
Explanation: 1/2 x 1824 = 912 with team colors
2/3 x 912 = 608 with hats and colors
1/4 x 608 = 152 with hats, colors, and banners
152 + 100 + 25 = 277 with banners
correct answer B
Question: Dany bought a total of 20 game cards some of which cost $0.25 each and some of which cost $0.15 each. If Dany spent $4.2 to buy these cards, how many cards of each type did he buy?
A.4
B.10
C.7
D.8
Answer: D.8
Explanation: Let X be the number of cards that cost $0.25 each and Y the number of cards that cost $0.15 each. The total number of cards is 20. Hence
X + Y = 20
If X is the number of cards at $0.25, then the X cards cost
0.25 X
If Y is the number of cards at $0.15, then the Y cards cost
0.15 Y
The total cost of the X cards and the the Y cards is known to be $4.2 and also given by
0.25 X + 0.15 Y = 4.2
We now need to solve the system of equations
X + Y = 20
0.25 X + 0.15 Y = 4.2
The first equation gives Y = 20 - X. Substitute y by 20 - x in the second equation and solve
0.25 X + 0.15 (20 - X) = 4.2
X(0.25 - 0.15) + 3 = 4.2
0.1 X = 1.2
X = 12 and Y = 20 - 12 = 8
correct answer D
Question: 36 men can complete a piece of work in 18 days.In how days will 27 men can complete the work?
A.18
B.20
C.17
D.24
Answer: D.24
Explanation: Let the required number of days be x
Less men,more days(indirect proportion)
27:36::18:x
27x=36*18
x=(36*18)/27
x=24 days
option is D
Question: Kunal electronic services assemble computers. Over a period of time the engineers made the following observation regarding the two vital components - the USB port and CD drive. The probability that USB port is defective is 0.1, that both the USB port and CD drive are defective is 0.02, while the probability that only the CD drive is defective is 0.03 . The probability that the USB port is defective when the CD drive has been found to be defective is?
A.0.2
B.0.3
C.0.25
D.0.4
Answer: D.0.4
Explanation: Explanation :
USB Defective	USB OK	Total
CD Defective	0.02	0.03	(0.05)
CD OK	(0.08)	(0.87)
(0.95)
Total	0.1	(0.9)
The figures enclosed in brackets follow as conclusions. The probability that USB part is defective, when the CD drive is found to be defective is 0.02/0.02+0.03 = 2/5 = 0.40
Answer : D
Question: At an elementary school, 70% of the faculty members are women and 60% of the faculty members are married. If 2⁄3 of the men are single, what fraction of the men are married?
A.5⁄7
B.7⁄10
C.1⁄3
D.7⁄30
Answer: C.1⁄3
Explanation: --------------------M------W--------Total
Marrried----------10-----50---------60
Not married-----20-----20---------40
Total-------------30-----70--------100
need married man/total man, so 10/30=1/3
C
Question: Find out the wrong number in the series.
6, 12, 48, 94, 384, 768, 3072
A.768
B.384
C.94
D.488
Answer: C.94
Explanation: Each even term of the series is obtained by multiplying the previous term by 2.
2nd term = (1st term) x 2 = 6 x 2 = 12
4th term = (3rd term) x 2 = 48 x 2 = 96.
6th term = (5th term) x 2 = 384 x 2 =768.
4th term should be 96 instead of 94.
ANSWER:C
Question: A team bought a total of 472 balls. If each player on the team bought at least 19 balls, then what is the greatest possible number of players on the team?
A.21
B.22
C.23
D.24
Answer: D.24
Explanation: 472/19=24 plus remainder.
The answer is D.
Question: What percent of 12.4 kg is 20 gms ?
A.25
B.16
C.18
D.19
Answer: B.16
Explanation: Explanation:
Required percentage = (20/12400 * 100)% = 4/25% = 0.16%
Answer: B) .16%
Question: A cube of side one meter length is cut into small cubes of side 10 cm each. How many such small cubes can be obtained?
A.10
B.100
C.1000
D.10000
Answer: C.1000
Explanation: Along one edge, the number of small cubes that can be cut
= 100/10 = 10
Along each edge 10 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut = 10 * 10 * 10 = 1000
ANSWER:C
Question: Of the following, which is greater than Â½ ?
Indicate ALL such fractions.
A.4/0
B.4/7
C.4/2
D.4/1
Answer: B.4/7
Explanation: Explanation:
One way to deal with fractions is to convert them all to decimals.
In this case all you would need to do is to see which is greater than 0.5.
Otherwise to see which is greater than Â½, double the numerator and see if the result is greater than the denominator. In B doubling the numerator gives us 8, which is bigger than 7.
Answer: B
Question: Find the simple interest on Rs.350 for 10 months at 5 paisa per month?
A.277
B.175
C.288
D.266
Answer: B.175
Explanation: I = (350*10*5)/100 = 175
Answer: B
Question: The average of four positive integers is 69. The highest integer is 93 and the least integer is 39. The difference between the remaining two integers is 28. Which of the following integers is the higher of the remaining two integers?
A.76
B.86
C.56
D.45
Answer: B.86
Explanation: Let the four integers be A, B, C and D where A > B > C > D.
(A + B + C + D)/4 = 69 => A + B + C + D = 276 ---> (1)
A = 93, D = 39 and B - C = 28
(1) => B + C = 276 - (A + D) = 276 - 132 = 144.
B + B -28 = 144
B = (144 + 28)/2 = 86
Answer: B
Question: A train having a length of 240 m passes a post in 24 seconds. How long will it take to pass a platform having a length of 620 m?
A.120 sec
B.99 sec
C.89 sec
D.86 sec
Answer: D.86 sec
Explanation: Explanation:
v = 240/24 (where v is the speed of the train) = 10 m/s
t = (240+620)/10 = 86 seconds
Answer: Option D
Question: A cistern 8 meters long and 4 meters wide contains water up to a depth of 1 meter 25 cm. What is the total area of the wet surface?
A.40
B.48
C.54
D.62
Answer: D.62
Explanation: Area of the wet surface = [2(lb + bh + lh) - lb]
= 2(bh + lh) + lb
= [2 (4 x 1.25 + 8 x 1.25) + 8 x 4]
= 62
The answer is D.
Question: Anand and Deepak started a business investing Rs. 21,000 and Rs. 35,000 respectively. Out of a total profit of Rs. 13,800, Deepak's share is?
A.2777
B.2888
C.8625
D.2885
Answer: C.8625
Explanation: Ratio of their shares = 21000 : 35000 = 3:5
Deepak's share = 13800 * 5/8 = Rs. 8625.
Answer: C
Question: A coin is tossed six times. What is the probability that there is at the least one tail?
A.63/64
B.31/64
C.31/67
D.31/64
Answer: A.63/64
Explanation: Let P(T) be the probability of getting least one tail when the coin is tossed six times.
= There is not even a single tail.
i.e. all the outcomes are heads.
= 1/64 ; P(T) = 1 - 1/64
= 63/64
Answer: A
Question: Camel and carriage for Rs. 5000. He SP the camel at a gain of 20% and the carriage at a loss of 10%. If he gains 3% on the whole, then find the CP of the camel?
A.Rs.2166.67
B.Rs.2187.67
C.Rs.2188
D.Rs.2200
Answer: A.Rs.2166.67
Explanation: Now, in this numerical, there is no common loss and gain %.
Hence, solve it making equations.
Let cost price of camel be x.
As cost of camel and carriage = Rs 5000
Cost of carriage = Rs. (5000 – x)
After selling camel he gains 20% and on carriage a loss of 10%. But on the whole he gains 3%.
Therefore,
20% of x – 10 % of (5000 – x) = 3 % of 5000
20 × x – 10 × (5000 – x) = 3 × 5000
100 100 100
x – (5000 – x) = 150
5 10
10x – (5000 – x) × 10 = 150 × 10
5 10
2x-5000+x=1500
3x=1500+5000
x=2166.67
The cost of camel = Rs.2166.67
Option (A) is the correct answer
Question: A contractor undertakes to built a walls in 50 days. He employs 50 peoples for the same. However after 25 days he finds that only 40% of the work is complete. How many more man need to be employed to complete the work in time?
A.25
B.30
C.35
D.20
Answer: A.25
Explanation: 50 men complete 0.4 work in 25 days.
Applying the work rule, m1 × d1 × w2 = m2 × d2 × w1
we have,
50 × 25 × 0.6 = m2 × 25 × 0.4
or m2 = 50×25×0.6/25×0.4 = 75 men
AnswerA
Question: In how many ways can a committee of 4 people comprising at least 3 boys be formed using a group of 5 boys and 6 girls?
A.67
B.64
C.65
D.66
Answer: C.65
Explanation: There are 2 options: the selected groups have no girls or one girls.
-First case: 1 girl + 3 boys: 6C1 * 5C3 = 6*10 = 60
-Second case: 4 boys: 5C4 = 5
So there are 60 + 5 = 65
ANS:C
Question: Avinash is twice as fast as Bharat, and Bharat is one-third as fast as Chandra. If together they can complete a piece of work in 30 days, in how many days can Avinash, Bharat and Chandra do the work respectively?
A.90,180,60
B.90,180,68
C.90,180,62
D.90,180,69
Answer: A.90,180,60
Explanation: Let Chandra do the work in 2x days.
Bharat can do it in 6x days and Avinash can do it in 3x days.
1/(2x) + 1/(6x) + 1/(3x) = 1/30 => (3 + 1 +2)/6x = 1/30 => x = 30
So, the time taken to complete the work by Avinash, Bharat, Chandra is 90, 180, 60 days respectively.
Answer:a
Question: A man can row with a speed of 15 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is?
A.87
B.56
C.20
D.67
Answer: C.20
Explanation: M = 15
S = 5
DS = 15 + 5 = 20
Answer: C
Question: Find the average of first 35 natural numbers?
A.21
B.22
C.23
D.18
Answer: D.18
Explanation: Sum of first 100 natural numbers = 35*36/2 = 630Required average = 630/35 = 18Answer is D
Question: The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:
A.17 kg
B.20 kg
C.26 kg
D.31 kg
Answer: D.31 kg
Explanation: EXPLANATION
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 …. (i)
A + B = (40 x 2) = 80 …. (ii)
B + C = (43 x 2) = 86 ….(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 …. (iv)
Subtracting (i) from (iv), we get : B = 31.
B’s weight = 31 kg.
Answer D
Question: a student got 70% in one subject,80% in other.to get overall 75% how much he should get in third subject.
A.65%
B.75%
C.85%
D.95%
Answer: B.75%
Explanation: Already average of two subjects is (70+80)/2 = 75%
To maintain the percentage at 75%, he shouls get 75% marks in third subject
ANSWER:B
Question: A list of measurements in increasing order is 4, 5, 6, 8, 15 and x. If the median of these measurements is 2/3 times their arithmetic mean, what is the value of x?
A.20
B.22
C.25
D.28
Answer: C.25
Explanation: The median is (6+8)/2 = 7
The mean is (4+5+6+8+15+x)/6 = (38+x)/6
(38+x) /6 * 2/3 = 7
x = 63-38 = 25
The answer is C.
Question: How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.25
B.30
C.40
D.45
Answer: B.30
Explanation: Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec.
ANSWER:B
Question: The probability of two events A and B are0.25 and 0.40 respectively. The probability that both A and B occur is 0.15. The probability that neither A nor B occur is _________
A.0.45
B.0.4
C.0.5
D.0.05
Answer: C.0.5
Explanation: we are apply that formula..............
P(AorB)=P(A)+P(B)-P(A AND B)
=.25+.40-.15
=.50
but the probability of neither A nor B=1-.50
=0.50
ANSWER:C
Question: For any integer n greater than 1, #n denotes the product of all the integers from 1 to n, inclusive. How many prime numbers Q are there between #6 +2 and #6 +6 , inclusive?
A.None
B.One
C.Two
D.Three
Answer: A.None
Explanation: None is the answer. A.
Because for every k 6! + k :: k, because 6! :: k, since k is between 2 and 6.A
Question: A bucket full of nuts was discovered by the crow living in the basement. The crow eats a fifth of the total number of nuts in 6 hours. How many hours in total will it take the crow to finish a quarter of the nuts?
A.6.5
B.7.0
C.7.5
D.8.0
Answer: C.7.5
Explanation: In one hour, the crow eats 1/30 of the nuts.
(1/4) / (1/30) = 7.5 hours
The answer is C.
Question: What is the probability T of randomly selecting an arrangement of the letters of the wordMEDITERRANEANin which the first letter is E and the last letter is R?
A.1/13
B.1/20
C.1/26
D.1/50
Answer: C.1/26
Explanation: Why do you calculate the total combinations and everything, it is much easier to calculate as follows:
3/13 * 1 * 1 * 1 * 1 ..... * 2/12 = 6/156 = 1/26
This is because 3/13 = Probability that first letter will be E and 2/12 = probability that thefirstletter will be R. Between everything else cuts down to 1*1*1... e.g. probability T of the second letter is 11/11 = 1, > we do not care what's in between.C
Question: Two brothers took the GMAT exam, the higher score is X and the lower one is Y. If the difference between the two scores is 1/3, what is the value of X/Y ?
A.3.
B.2.
C.1/2.
D.4
Answer: D.4
Explanation: Answer is D : 4
X - Y = (X + Y)/2
Solving for X/Y = 4
Question: There are two circles of different radii. The are of a square is 784 sq cm and its side is twice the radius of the larger circle. The radius of the larger circle is seven - third that of the smaller circle. Find the circumference of the smaller circle.
A.87∏ cm
B.56∏ cm
C.12∏ cm
D.16∏ cm
Answer: C.12∏ cm
Explanation: Let the radii of the larger and the smaller circles be l cm and s cm respectively. Let the side of the square be a cm.
a2 = 784 = (4)(196) = (22).(142)
a = (2)(14) = 28
a = 2l, l = a/2 = 14
l = (7/3)s
Therefore s = (3/7)(l) = 6 Circumference of the smaller circle = 2∏s = 12∏ cm.
Answer:C
Question: There are 600 boys in a hostel. Each plays either hockey or football or both. If 75% play hockey and 60% play football, how many play both?
A.210
B.150
C.200
D.180
Answer: A.210
Explanation: n(A) = 75*600/100 = 450
n(B) = 60*600/100 = 360
n(AUB) = 600
n(AnB) = 450+360-600 = 210
Answer is A
Question: How many odd integers from 1 to 50 (both inclusive) have odd number of factors?
A.13
B.4
C.5
D.6
Answer: B.4
Explanation: Integers having odd number of factors will be perfect squares. Odd numbers will have odd perfect squares. Thus, the possible values for the perfect squares are :
1,9,25,49 and the corresponding integers are 1,3,5,7 (more than 3). Thus B is the correct answer .
Question: Which of the Conclusion is true fof the below statement
Statement : D @ M, M $ B, B ☆ R, R % T
Conclusion:
I. B ☆ D
II. B @ D
III. T ☆ M
A.Only I is true
B.Only II is true
C.Only III is true
D.Only either I or II is true
Answer: D.Only either I or II is true
Explanation: D=M, M>B, B<R, R>T D=M>=B<R>T
B @ D True
T ☆ M True
Option D
Question: Anu can do a work in 6 days and Binu alone in 9 days. Anu and Binu undertook to do it for Rs.4200. With help of Minu, they completed the work in 3 days. How much is to be paid to Minu and Anu?
A.s.700, Rs.2100
B.s.2000, Rs.750
C.s.750, Rs.2000
D.s.800, Rs.1250
Answer: A.s.700, Rs.2100
Explanation: Minuâ€™s one dayâ€™s work = 1/3 - 1/6 + 1/9= 1/3 - 5/18 = 1/18
Anuâ€™s wages: Binuâ€™s wages: Minuâ€™s wages = 1/6 : 1/9 : 1/18 = 6: 4: 2
Minuâ€™s share = Rs.4200* 2/12 = Rs.700
Anuâ€™s share = Rs.4200* 6 /12 = Rs.2100
ANSWER:A
Question: A Prototype fuel-efficient car (P-Car) is estimated to get 85% more miles per gallon of gasoline
than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type
of gasoline that costs 20% more per gallon than does the gasoline used by a T-Car. If the two
cars are driven the same distance, what percent less than the money spent on gasoline for the
T-Car is the money spent on gasoline for the P-Car?
A.16 2/3%
B.35.13 %
C.50%
D.60%
Answer: B.35.13 %
Explanation: Assumption
Miles/Gallon
T = 100
P = 185 ( 85% more)
$/gallon
T = 100
P = 120 (20% more)
Miles
100 for both
Cost = (Miles X $/ Gallon)/ M/gallon
T = 100
P = 64.86
Hence 100 - 64.86 =35.13%
Ans B
Question: A and B start walking towards each other at 1pm at speed of 5kmph and 7kmph. They were initially 24km apart. At what time do they meet?
A.4pm
B.6pm
C.3pm
D.10pm
Answer: C.3pm
Explanation: Time of meeting = distance / relative speed = 24/7+5 = 24/12 = 2 hrs after 1pm = 3pm
Answer is C
Question: P and Q started a business investing Rs.85,000 and Rs.15,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively?
A.3 : 4
B.3 : 5
C.15 : 23
D.17 : 3
Answer: D.17 : 3
Explanation: Solution
P : Q	= 85000 : 15000
=85 : 15
=17 : 3
Answer D
Question: If a = 105 and a^3 = 21 × 25 × 45 × w, what is the value of w?
A.35
B.42
C.45
D.49
Answer: D.49
Explanation: a=105 = 3* 5 *7
a^3 = 21 × 25 × 45 × w
=> a^3 = (7*3) x (5*5) x ( 3^2 * 5) x w
=> a^3 = 3^3 * 5^3 * 7 x w
=>( 3* 5 *7) ^3 = 3^3 * 5^3 * 7 x w
w = 7^2 = 49
Answer D
Question: 6 25 64 81 32 ?
Find The Last Number In the Series ?
A.5
B.4
C.1
D.2
Answer: C.1
Explanation: C
The answer is 1
6 {6^1}
25 {5^2}
64 {4^3}
81 {3^4}
32 {2^5}
1 {1^6}
Question: 2 dice are tossed. What is the probability that the total score is a prime no. is?
A.3/14
B.5/12
C.5/13
D.7/11
Answer: B.5/12
Explanation: 5/12
B
Question: The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product?
A.12%
B.12.5%
C.12.9%
D.12.11%
Answer: B.12.5%
Explanation: X Rate = Price
1 x 1 = 1
0.7 x 1.25 = 0.875
Decrease in price = (0.125/1) × 100 = 12.5%
B)
Question: A circular rim 14 inches in diameter rotates the same number of inches per second as a circular rim 21 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?
A.48pi/x
B.40x
C.48x
D.24x
Answer: B.40x
Explanation: Let's try the explanation. We have two wheels. One with 14pi and the other one with 21pi. They have the same speed. In the smaller wheel it's 14pi*x, which must be equal to the speed of the bigger one (21pi*a number of revolutions).They are asking that number of revolutions (but in minutes, which makes the question even harder).
Anyway, we have 14pi*x=21pi*a.
(14pi*x)/(21pi). As I said, that's in seconds. So, to convert it to minutes we multiply by 60 and we get the result, 40x.
Ans : B
Question: The ratio between the perimeter and the width of a rectangle is 5 : 1. If the area of the rectangle is 150 sq. cm, what is the width of the rectangle?
A.10 cm
B.12 cm
C.14 cm
D.16 cm
Answer: A.10 cm
Explanation: 2L+2W = 5W
L = 3W/2
W*L = 150
3W^2/2 = 150
W^2 = 100
W = 10
The answer is A.
Question: 'a' and 'b' are positive integers such that their LCM is 20 and their HCF is 1. What is the difference between the maximum and minimum possible values of 'a + b'?
A.0
B.12
C.13
D.9
Answer: A.0
Explanation: a = 4, b = 5 as they have to co-primes (HCF being 1 and LCM = 20)
So A+B = 9 is their max and min value
hence Difference = 0
Answer - A
Question: If the average (arithmetic mean) of (2a+16) and (3a-8) is 74, what is the value of a?
A.25
B.30
C.28
D.36
Answer: C.28
Explanation: ((2a+16) + (3a-8)) / 2 = (5a+8)/2 = 74
a= 28
The answer is C.
Question: A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?
A.187 ways
B.176 ways
C.166 ways
D.108 ways
Answer: D.108 ways
Explanation: The boy can select one trouser in nine ways.
The boy can select one shirt in 12 ways.
The number of ways in which he can select one trouser and one shirt is 9 * 12
= 108 ways.
Answer: D
Question: How many prime numbers are between 29/3 and 87/6?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: 29/3= 58/6 = 10-
87/6= 15-
Prime numbers between 10 and 15 are 11 and 13
- sign signifies that the number is marginally less .
Answer B
Question: A certain car uses 12 gallons of gasoline in traveling 180 miles. In order for the car to travel the same distance using 10 gallons of gasoline, by how many miles per gallon must the car’s gas mileage be increased?
A.2
B.3
C.6
D.8
Answer: B.3
Explanation: 180/10 = 18. The difference is 18 - 15 = 3.
Answer B
Question: The total of the ages of Jayant, Prem and Saransh is 93 years. Ten years ago, the ratio of their ages was
2 : 3 : 4. What is the present age of Saransh?
A.24 years
B.32 years
C.34 years
D.38 years
Answer: D.38 years
Explanation: Solution
Let the ages of Jayant, Prem and Saransh 10 years ago be 2x, 3x and 4x years respectively. Then,
(2x + 10)+(3x + 10)+(4x + 10)	= 93.
‹=›9x = 63
x = 7.
∴ Saransh's present age = 4x + 10 = 38 years.
Answer D
Question: If A,B,C are three integers and AB+C is even ; which of the following must be true? A)C is even B)B is Odd C)AB is Odd
A.I only
B.II only
C.None of the above
D.II,III only
Answer: C.None of the above
Explanation: If AB is Odd then C will not even. O+E = O
If AB is even then C will not be odd.
If B is even AB is even always. But If C is Odd E+O = O
If B is Odd AB is even or odd depends on A
None of the above are true.
Answer : C
Question: The ratio of boys to girl in a school is 5:4. If there are 1500 boys in the school, how many girls are there?
A.300
B.1200
C.1500
D.1800
Answer: B.1200
Explanation: Think of the ratio as 5 parts: 4 parts.
Divide 1500 by 5 to find 1 "part" of the ratio.
1500/5 = 300
Multiply this by 4 to get 4 "parts" of the ratio.
300*4 = 1200
There are 1200 girls in the school.
The answer is B
Question: A and B together can do a work in 3 days. If A alone can do it in 12 days. In how many days can B alone do it?
A.4
B.6
C.8
D.10
Answer: A.4
Explanation: A
4
1/3 â€“ 1/12 = 1/4 => 4
Question: What is 25 % of 4/12 of 520?
A.49
B.56
C.60
D.43
Answer: D.43
Explanation: 25 % = 25 / 100 = 1/4 of 4/12 = 1/4 * 4/12 = 1 / 12 of 520 = 1/12 * 520 = 43.33 ==43 Ans - D