RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Jane spent $42 for shoes. This was $14 less than twice what she spent for a blouse. How much was the blouse?
A.32
B.28
C.17
D.45
Answer: B.28
Explanation: Let x, then, be how much she spent for the blouse. The problem states that "This" -- that is, $42 -- was $14 less than two times x.
Here is the equation:
2x − 14 = 42.
2x = 42 + 14
= 56.
x = 56
/2
= 28.
The blouse cost $28.
Question: Sri travels the first 6 hours of his journey at 40 mph speed and the remaining 3 hours at 20mph speed. What is the average speed of Sri's travel in mph?
A.33.3mph
B.33.8mph
C.32.3mph
D.34.3mph
Answer: A.33.3mph
Explanation: Explanation :
Average speed=Total Distance/Time.
Total distance travelled by sri = Distance covered in the first 6 hours + Distance covered in the next 3 hours.
Distance covered in the first 6 hours = 6Ã—40=240 miles
Distance covered in the next 3 hours= 3Ã—20=60 miles
Therefore, total distance travelled = 240+60=300 miles.
The total time taken = 6+3=9hours.
Hence, the average speed =300/9= 33.3mph.
Answer : A
Question: How much time will take for an amount of Rs. 300 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
A.7
B.4
C.6
D.3
Answer: C.6
Explanation: Time = (100 * 81) / (300 * 4.5) = 6 years'
Answer:C
Question: A rope of which a calf is tied is increased from 15 m to 18m, how much additional grassy ground shall it graze?
A.1218
B.1212
C.1210
D.3.11.14
Answer: D.3.11.14
Explanation: π (182 – 152) = 311.14
Answer: D
Question: A dealer purchased an article at 3/4 of its list price and sold 50% more than the list price. Find his gain percent?
A.75%
B.50%
C.100%
D.80%
Answer: C.100%
Explanation: MP = 100
CP = 75
SP = 150
------
75 ---- 75
100 ---- ? => 100%
ANSWER:C
Question: Two employees A and B are paid a total of Rs. 580 per week by their employer. If A is paid 150 percent of the sum paid to B, how much is B paid per week?
A.s.130
B.s.140
C.s.150
D.s.232
Answer: D.s.232
Explanation: Let the amount paid to A per week = x
and the amount paid to B per week = y
Then x + y = 580
But x = 150% of y = 150y/100 = 15y/10
∴15y/10 + y = 580
⇒ y[15/10 + 1] = 580
⇒ 25y/10 = 580
⇒ 25y = 5800
⇒ y = 5800/25 = Rs.232
D)
Question: The train travels at an average speed of 25km/h, to the top of the hill where the midpoint of the trip is. Going down hill, train travels at an average speed of 5km/h. Which of the following is the closest approximation of train's average speed, in kilometers per hour, for the round trip?
A.8.5
B.8.3
C.2.6
D.4.2
Answer: B.8.3
Explanation: Since we're not given a distance to work with, we can TEST any distance that we like. Here, since the speeds are 25 km/hour and 5 km/hour, using a multiple of both 25 and 5 would make the math easiest.
Let's set the Distance up the hill at 50 km.
So, going uphill, we have....
D = (R)(T)
50 = (25)(T)
50/25 = 2 = T
2 hours to go uphill
Going downhill, we have....
D = (R)(T)
50 = (5)(T)
50/5 = 10 = T
10 hours to go downhill
Total Distance = 100 km
Total Time = 10+2 = 12 hours
Average Speed = 100/12 = 8.3 km/hour
B
Question: A shopkeeper sold an article offering a discount of 5% and earned a profit of 27.3%. What would have been the percentage of profit earned if no discount had been offered?
A.28.5
B.27.675
C.30
D.34%
Answer: D.34%
Explanation: Giving no discount to customer implies selling the product on printed price. Suppose the cost price of the article is 100.
Then printed price = 100Ã—(100+27.3)/(100âˆ’5)
= 100Ã—127.3/95=134
Hence, required % Profit = 134 â€“ 100 = 34%
Answer D
Question: X and Y walk around a circular track. They start at 10 a.m from the same point in the opposite directions. X and Y walk at a speed of 6 rounds per hour and 7 rounds per hour respectively. How many times shall they cross each other before 3 p.m
A.64
B.65
C.66
D.67
Answer: B.65
Explanation: Explanation:
Relative speed = (6+7) =13 rounds per hour
So, they cross each other 13 times in an hour hence, they cross 65 times before 3 p.m
Answer: Option B
Question: Sahil purchased a machine at Rs 14000, then got it repaired at Rs 5000, then gave its transportation charges Rs 1000. Then he sold it with 50% of profit. At what price he actually sold it.
A.Rs. 22000
B.Rs. 24000
C.Rs. 26000
D.Rs. 30000
Answer: D.Rs. 30000
Explanation: Explanation:
Question seems a bit tricky, but it is very simple.
Just calculate all Cost price, then get 150% of CP.
C.P. = 14000 + 5000 + 1000 = 20000
150% of 20000 = 150/100 * 20000 = 30000
Option D
Question: John's marks wrongly entered as 82 instead of 62. Due to that the average marks for the class got increased by half (1/2). The number of John in the class is?
A.70
B.78
C.80
D.84
Answer: C.80
Explanation: otal increase in marks = x x	1 =	x
2	2
x/2	= (82 - 62) x/2	= 40 x= 80.
C
Question: Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:
A.14
B.12
C.15
D.16
Answer: A.14
Explanation: Filled in 2 hrs = 2/6 = 1/3
remain = (1-1/3)=2/3
(A+B)'S 7 HRS WORK = 2/3
(A+B)'S 1 hr work = 2/21
C'S 1 hr work = (A+B+C)'S 1 hr work - (A+B)'S 1 hr work
=(1/6-2/21)=1/14
=>c alone fill tank in 14 hrs
ANSWER A
Question: The present worth of Rs.169 due in 2 years at 4% per annum compound interest is
A.Rs.150.50
B.Rs.154.75
C.Rs.156.25
D.Rs.158
Answer: C.Rs.156.25
Explanation: Solution
Present Worth	= Rs.[169/(1+4/100)²]
= Rs.(169x25/26x25/26)
= Rs.156.25
Answer C
Question: A tailor trims 6 feet from opposite edges of a square piece of cloth, and 5 feet from the other two edges. If 120 square feet of cloth remain, what was the length of a side of the original piece of cloth?
A.20
B.22
C.24
D.26
Answer: B.22
Explanation: Let the original side of the square be x.
(x-12)*(x-10) = 120 = 10*12
x = 22
The answer is B.
Question: If a*b=2a-3b+ab,then3*5+5*3 is equal to
A.22
B.32
C.25
D.28
Answer: A.22
Explanation: 3*5+5*3= (2x3-3x5+3x5)+(2x5-3x3+5x3)
=22
ANSWER A 22
Question: A, B and C can do a piece of work in 5 days, 10 days and 15 days respectively. How long will they taken, if all the three work together?
A.2
B.4
C.2 8/11
D.67
Answer: C.2 8/11
Explanation: 1/5 + 1/10 + 1/15 = 11/30 => 30/11 => 2 8/11 days
Answer: C
Question: A chair is bought for Rs.900/- and sold at Rs.810/- find the loss percentage
A.10% Gain
B.10% Loss
C.20% Loss
D.25% Loss
Answer: B.10% Loss
Explanation: Formula = (Selling price ~ Cost price)/Cost price * 100
= (810 ~ 900)/900 = 10% Loss
B
Question: If 9!/3^x is an integer, what is the greatest possible value of x?
A.3
B.4
C.5
D.6
Answer: B.4
Explanation: 9 - 3*3
6 - 2*3
3 - 1*3
Hence max of 3^4 is allowed. IMO B.
Question: eight children, Arya, Betsy, Chen, Daniel, Emily, and Franco, are to be seated in a single row of six chairs. If Betsy cannot sit next to Emily, how many different arrangements of the six children are possible?
A.240
B.480
C.540
D.720
Answer: D.720
Explanation: Since it is more time consuming and error prone to find ways Betsy and E not sitting together, It is better we find ways in which they will be together and then subtract from total ways..
total ways = 6!..
ways B and E will be sitting together..
take both B and E as one, then these two together with other 4 can sit in 5! ways ...
Also B and E can sit within themselves in 2! ways..
so the answer required = 6!-2*5!=720..
ans D
Question: Mr. Evans will states that each of his children will receive an equal share of his estate and that his grandchildren will split a portion of the estate that is equal to the share received by each of his children. If Mr. Evans has 3 children and 6 grandchildren, then approximately what percentage of Mr. Evans estate will each grandchild receive?
A.16.25%
B.8.25%
C.4.25%
D.6.25%
Answer: D.6.25%
Explanation: 25/4 =6.25
Answer : D
Question: Egg Street begins at Toast Street and runs directly east for 6.6 kilometers until it ends when it meets Jam Street. Egg Street is intersected every 120 meters by a perpendicular street, and each of those streets other than Toast Street and Jam Street is given a number beginning at 1st Street (one block east of Toast Street) and continuing consecutively (2nd Street, 3rd Street, etc...) until the highest-numbered street one block west of Jam Street. What is the highest-numbered street that intersects Egg Street?
A.52nd
B.53rd
C.54th
D.56th
Answer: C.54th
Explanation: 6.6 km / 120 m = 55.
However, the street at the 6.6-km mark is not 55th Street; it is Jam Street.
Therefore, the highest numbered street is 54th Street.
The answer is C.
Question: If x and y are positive integers such that x < y and z=x/y, which of the following must be true?
I. z>(x − 1)/(y − 1)
II. z>(x − 1)/(y − 1)
III. z>(x + 1)/(y - 1)
A.II only
B.I and II
C.II and III
D.I only
Answer: B.I and II
Explanation: x < y --> Let x = 2 and y = 3 --> z = 2/3
I. z>(x − 1)/(y − 1) --> 2/3 > 1/2 --> True
II. z>(x − 1)/(y − 1) --> 2/3 > 1/2 --> True
III. z>(x + 1)/(y - 1) --> 2/3 > 3/2 --> False
Answer: B
Question: In a series of six consecutive even numbers, the sum of the fifth and sixth numbers is 42. What is the second number?
A.10
B.12
C.14
D.18
Answer: C.14
Explanation: Let the numbers be x, x + 2, x + 4, x + 6, x + 8 and x + 10.
Given (x + 8) + (x + 10) = 42
=> 2x + 18 = 24 => x = 12
The second number = x + 2 = 12 + 2 = 14.
Answer: C
Question: The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is:
A.20
B.30
C.40
D.None of these
Answer: A.20
Explanation: Let the numbers be a, b and c.
Then, a2 + b2 + c2 = 138 and (ab + bc + ca) = 131.
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) = 138 + 2 x 131 = 400.
(a + b + c) = 400 = 20.
ANSWER : A
Question: Which of the following is not an odd function?
A.f(x) = -x3
B.f(x) = x5
C.f(x) = x2 - x
D.f(x) = |x|3
Answer: D.f(x) = |x|3
Explanation: Solution:
An odd function is a function whose value reverses in sign for a reversal in sign of its argument. i.e. f(x) = -f(-x).
Except f(x) = |x|3 all other functions mentioned in the choices change values.
Answer D
Question: A, B and C invest in a partnership in the ratio: 7/2, 4/3, 6/5. After 4 months, A increases his share 50%. If the total profit at the end of one year be Rs. 22,680, then what is B's share in the profit?
A.Rs. 2000
B.Rs. 3000
C.Rs. 4200
D.Rs. 5200
Answer: C.Rs. 4200
Explanation: Explanation :
Ratio of the initial investment = 7/2 : 4/3 : 6/5
= 105 : 40 : 36
From this ratio, we can assume that actual initial investments of A, B and C
are 105x, 40x and 36x respectively
A increases his share 50% after 4 months. Hence the ratio of their investments =
(105x * 4) + (105x * 150/100 * 8) : 40x * 12 : 36x : 12
= 105 + (105 * 3/2 * 2) : 40*3 : 36 * 3
= 105 * 4 : 40 *3 : 36 * 3
= 35 * 4 : 40 : 36
= 35 : 10 : 9
B's share = total profit * (10/54) = 22,680 * 10/54 = 4200. Answer : Option C
Question: Anita, Indu and Geeta can do a piece of work in 18 days, 27 days and 36 days respectively. They start working together. After working for 4 days. Anita goes away and Indu leaves 7 days before the work is finished. Only Geeta remains at work from beginning to end. In how many days was the whole work done?
A.16
B.77
C.99
D.14
Answer: A.16
Explanation: 4/18 + (x -7)/27 + x/36 = 1
x = 16 days. Answer: A
Question: Country C imposes a two-tiered tax on imported cars: the first tier imposes a tax of 14% of the car's price up to a certain price level. If the car's price is higher than the first tier's level, the tax on the portion of the price that exceeds this value is 8%. If Ron imported a $14,000 imported car and ended up paying $1440 in taxes, what is the first tier's price level?
A.$1600
B.$5333
C.$6050
D.$7050
Answer: B.$5333
Explanation: Let T be the tier price, P be total price = 14000
Per the given conditions:
0.14T + 0.08(P-T) = 1440 ----> T=5333. B is the correct answer.
Question: A train 500 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
A.298 m
B.300 m
C.800 m
D.967 m
Answer: C.800 m
Explanation: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (500 + x)/60 = 65/3
x = 800 m.
Answer: C
Question: Dacid obtained 86, 89, 82, 87 and 81 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
A.79
B.99
C.88
D.85
Answer: D.85
Explanation: Average = (86+89+82+87+81)/5
= 425/5 = 85.
Answer:D
Question: In one hour, a boat goes 14 km/hr along the stream and 8 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
A.26
B.48
C.11
D.56
Answer: C.11
Explanation: Speed in still water = 1/2(a+b)km/hr
=1/2(14+8)km/hr=11 km/hr.
Answer:C
Question: What is the are of an equilateral triangle of side 12 cm?
A.36âˆš3 cm2
B.74âˆš3 cm2
C.64âˆš3 cm2
D.64âˆš5 cm2
Answer: A.36âˆš3 cm2
Explanation: Area of an equilateral triangle = âˆš3/4 S2
If S = 12, Area of triangle = âˆš3/4 * 12 * 12 = 36âˆš3 cm2;
Answer:A
Question: If one-third of one-fourth of a number is 18, then three-tenth of that number is:
A. 35
A.23
B.87
C.26
D.64.8
Answer: D.64.8
Explanation: Explanation:
The number is 1/3 of 1/4 is =15 then 1/3 Ã— 1/4 = 18
Number is 216 then 216 Ã— 3/10 = 64.8
Answer: D
Question: The true discount on a bill of Rs.4320 is Rs.720.The banker's discount is
A.862
B.864
C.866
D.868
Answer: B.864
Explanation: Solution
P.W	= Rs.(4320 - 720)
= Rs. 3600
S.I on Rs. 4320	=Rs.(720/3600 x 4320)
= Rs. 864.
Answer B
Question: Pat, Kate, and Mark charged a total of 126 hours to a certain project. If Pat charged twice as much time to the project as Kate and 1/3 as much time as Mark, how many more hours did Mark charge to the project than Kate?
A.18
B.36
C.72
D.70
Answer: D.70
Explanation: 70
all u do is do
2:1:6=>2x+x+6x=126=>x= 14
28:14:84
84-14=70
Answer D
Question: Find the area of a cuboid of length 12cm , breadth 6 cm . and height 10cm.
A.400 cm cube
B.410 cm cube
C.720 cm cube
D.730 cm cube
Answer: C.720 cm cube
Explanation: Area of a cuboid = lxbxh =12cm x 6cm x 10cm = 720 cm cube
answer :C
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20%?
A.20%
B.28%
C.22%
D.23%
Answer: A.20%
Explanation: SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Answer:A
Question: A man can row 30 km downstream and 20 km upstream in 4 hours. He can row 45 km downstream and 40 km upstream in 7 hours. Find the speed of man in still water?
A.15 kmph
B.10 kmph
C.12 kmph
D.12.5 kmph
Answer: D.12.5 kmph
Explanation: Let the speed of the man in still water be a kmph and let the speed of the stream be b kmph.
Now 30/(a + b) + 20/(a - b) = 4 and 45/(a + b) + 40/(a - b) = 7
Solving the equation, the speed of man in still water is 12.5 kmph.
ANSWER:D
Question: If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is?
A.50 km
B.58 km
C.60 km
D.70 km
Answer: A.50 km
Explanation: A
50 km
Let the actual distance traveled be x km. Then,
x/10 = (x + 20)/14
4x - 200 =>x = 50 km.
Question: What is the area of a square field whose diagonal of length 30 m?
A.287
B.269
C.450
D.200
Answer: C.450
Explanation: d2/2 = (30 * 30)/2
= 450
Answer:C
Question: Two trains start from A & B and travel towards each other at
speed of 70kmph and 80kmph resp. At the time of the meeting the
second train has traveled 200km more than the first.the distance
between them.
A.2500 km
B.3000 km
C.3500 km
D.4000 km
Answer: B.3000 km
Explanation: Let the distance traveled by the first train be x km
then distance covered by the second train is x + 200km
x/70 = x+200 / 80
x= 1400
so the distance between A & B is x + x + 200 = 3000 km
Answer is B.
Question: In a particular city there are 100 homes numbered from 1,2,3,..,100. The city was build by a builder from Chennai. There was 4 to 5 shops in the town which was build by a builder from Mumbai. The 2nd builder can build in 1½ times as compared to time by 1st builder. The 2nd builder builds in 15 days, then how many 2's are used by the builder from Chennai in
numbering the 100 homes?
A.17
B.18
C.19
D.20
Answer: D.20
Explanation: in the last line it should be given
the builder from Chennai in numbering the 100 homes?
then ans is 20
ANSWER:D
Question: A container has 40L milk. 4L milk is taken out and replaced with water, the process done three times. What is the amount of milk now left?
A.29.16L
B.29.19L
C.29.12L
D.29.11L
Answer: A.29.16L
Explanation: Explanation:
In regard to the problem let after n times liquid in the container is x and liquid removed is y
=>Liquid in container= x
=>Liquid removed= y
After one trial, quantity of pure liquid= x- (1-y/x)
After n trials quantity of pure liquid = x - (1 -y/x)n
Therefore, Putting the values ( x = 40L y = 4L N=3) and solving
=> 40- (1-4/40)3
= 29.16L
ANSWER:A
Question: An outlet pipe can empty 3/4 of a cistern in 12 minutes. In 4 minutes, what part of the cistern will be emptied?
A.1/2
B.1/3
C.1/4
D.1/5
Answer: C.1/4
Explanation: 4/12 * 3/4 = 1/4
The answer is C.
Question: A and B entered into a partnership investing Rs.25000 and Rs.30000 respectively. After 4 months C also joined the business with an investment of Rs.35000. What is the share of C in an annual profit of Rs.47000?
A.14020
B.11289
C.68928
D.14000
Answer: D.14000
Explanation: 25*12: 30*12: 35*8
15:18:14
14/47 * 47000
= 14000
Answer: D
Question: Which voltage source converts chemical energy to electrical energy?
A.23
B.39
C.27
D.98
Answer: B.39
Explanation: Answer: Option B
Question: A and B can do a work in 8days, B and C can do it in 12days; A,B and C together can finish it in 6days. A and C together will do it in?
A.8days
B.10days
C.12days
D.7days
Answer: A.8days
Explanation: A+B+C 1day work = 1/6
A+B 1day work = 1/8
B+C 1day work = 1/12
A+C 1day work = 2*1/6 - 1/8+1/12 = 1/3 - 5/24 = 3/24 = 1/8
A and C together will do the work in 8 days.
Answer is A
Question: What percent is 2 minutes 24 seconds of an hour?
A.6%
B.8%
C.4%
D.2%
Answer: C.4%
Explanation: 2mt 24s =144s
(144*100)/(60*60)=4%
ANSWER:C
Question: The total of the ages of Mahesh, Suresh, Ramesh is 93 years. Ten years ago, the ratio of their ages was 2:3:4. What is the present age of Mahesh?
A.32years
B.38years
C.42years
D.35years
Answer: B.38years
Explanation: Let ages of Mahesh, Suresh, Ramesh 10years ago be 2x,3x,4x
2x+10 + 3x+10 +4x+10 = 93
x = 7
Ramesh present age = 4*7+10 = 38 years
Answer is B
Question: The cost price of a radio is Rs.1390 and it was sold for Rs.890, find the loss %?
A.18%
B.12%
C.22%
D.35%
Answer: D.35%
Explanation: 1390 ---- 500
100 ---- ? => 35%
Answer:D
Question: Jack and Jill went up and down a hill. They started from the bottom and Jack
met jill again 20 miles from the top while returning. Jack completed the race
1 min a head of jill. if the hill is 440 mts high and their speed while down
journey is 1.5 times the up journey. how long it took for the Jack to
complete the race ?
A.10.6 min
B.11.6 min
C.12.6 min
D.13.6 min
Answer: C.12.6 min
Explanation: Let speed and time of Jack be s1 & t1 & Jill having s2 & t2.
Time taken for Jack to travel 440 miles up and 20 miles down
= Time taken for Jill to travel 440-20=420 miles up
440/s1 + 20/1.5s1 = 420/s2
68/1.5s1= 420/s2
68s2= 63s1
s2 = 63s1/68 ---(1)
Now from the second given condition- Jack reaches 1 min before Jill. So
t2-t1=1
880/s2 - 880/s1 = 1
1/s2 - 1/s2 = 1/880
from equation (1) put value of s2
Solving and putting value of s1 in t1=d/s1 (d=880)
t1 = 12.6 min
ANSWER:C
Question: The S.I. on a certain sum of money for 5 years at 6% per annum is half the C.I. on Rs. 3000 for 2 years at 15% per annum. The sum placed on S.I. is?
A.1525.2
B.1256.3
C.1612.5
D.1548.5
Answer: C.1612.5
Explanation: C.I. = [3000 * (1 + 15/100)2 - 3000]= (3000 * 23/20 * 23/20 - 3000) = Rs. 967.5.Sum = (483.75 * 100)/(5 * 6)= Rs.1612.5Answer:C
Question: If 18 is 15 percent of 20 percent of a certain number, what is the number?
A.9
B.36
C.40
D.600
Answer: D.600
Explanation: Let the certain number be x.
=> (15/100)*(20/100)*x = 18;
300x=18*10000;
3x = 1800;
x=1800/3
=> x=600;
Ans is (D).
Question: The two trains of lengths 400 m, 600 m respectively, running at same directions. The faster train can cross the slower train in 180 sec, the speed of the slower train is 48 km. then find the speed of the faster train?
A.67
B.68
C.26
D.11
Answer: B.68
Explanation: Length of the two trains = 600m + 400m
Speed of the first train = X
Speed of the second train= 48 Kmph
1000/X - 48 = 180
1000/x - 48 * 5/18 = 180
50 = 9X - 120
X = 68 Kmph
Answer:B
Question: Avg cost of 3 apples and 5 bananas isRs. 40.The avg cost of 5 apples and 8 bananas is Rs.65.Find the total cost of 15 apples and 15 bananas?
A.75
B.90
C.80
D.130
Answer: A.75
Explanation: Avg cost of 3 apples and 5 bananas is Rs. 40
(3 apple + 5 bananas) 8=40
therefore 1 apple cost is 40/8=5, so 3 apple cost is 3x5=15 and 5 bananas cost is 5x5=25
Again, avg cost of 5 apples and 8 bananas is Rs.65
(5 apple + 8 bananas) 13=65
therefore 1 apple cost is 65/13=5, so 5 apple cost is 5x5=25 and 8 bananas cost is 8x5=40
So 15 apple cost is (15/a)=75 and 15 bananas cost is (15x5)=75
ANSWER:A
Question: An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent?
A.3
B.4
C.5
D.6
Answer: A.3
Explanation: HCF of 4956, 3894 = 354
(4956 - 3894)/354 = 3
ANSWER:A
Question: A completes 80% of a work in 20 days. Then B also joins and A and B together finish the remaining work in 3 days. How long does it need for B if he alone completes the work?
A.37 ½ days
B.22 days
C.31 days
D.22 days
Answer: A.37 ½ days
Explanation: Explanation :
Work done by A in 20 days = 80/100 = 8/10 = 4/5
Work done by A in 1 day = (4/5) / 20 = 4/100 = 1/25 --- (1)
Work done by A and B in 3 days = 20/100 = 1/5 (Because remaining 20% is done in 3 days by A and B)
Work done by A and B in 1 day = 1/15 ---(2)
Work done by B in 1 day = 1/15 – 1/25 = 2/75
=> B can complete the work in 75/2 days = 37 ½ days
Answer : A
Question: John makes $60 a week from his job. He earns a raise andnow makes $70 a week. What is the % increase?
A.16%
B.16.66%
C.17.66%
D.17.98%
Answer: B.16.66%
Explanation: Increase = (10/60)*100 = (1/6)*100 = 16.66%.
B
Question: The population of a town is 10000. It increases annually at the rate of 20% p.a. What will be its population after 6 years?
A.14300
B.29859
C.14500
D.14600
Answer: B.29859
Explanation: Formula :
( After =100 denominator
Ago = 100 numerator)
10000 × 120/100^6 = 29859
B)
Question: A book is bought for Rs.675 and sold for Rs.900, find the profit percentage?
A.30 %
B.33%
C.33 1/3%
D.40%
Answer: C.33 1/3%
Explanation: 675--->225
100--> 33 1/3%
ANSWER C
Question: Sum of the squares of three numbers is 138 and the sum of their products taken two at a time is 131. Find the sum?
A.20
B.25
C.27
D.29
Answer: A.20
Explanation: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 138 + 2* 131
a + b + c = √400 = 20
A
Question: A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
A.80
B.90
C.95
D.98
Answer: B.90
Explanation: Let number of notes of each denomination be x.
Then x + 5x + 10x = 480
16x = 480
x = 30.
Hence, total number of notes = 3x = 90.
B
Question: (X+1 )is an even number and Y is a positive odd number. Which of the following expressions cannot be even?
A.(X+1)Y
B.Y
C.(X+1)^Y
D.(Y+1)^3
Answer: B.Y
Explanation: Y WILL BE ODD
B
Question: If x^2 + 1/x^2 = √12, what is the value of x^4 + 1/x^4 ?
A.10
B.12
C.14
D.16
Answer: A.10
Explanation: IMPORTANT: I notice that if we SQUARE x², we get x⁴, and if we SQUARE 1/x², we get 1/x⁴, so let's see what happens if we take the equation x² + 1/x² = √12 andSQUAREboth sides:
(x² + 1/x²)²= 12
So, (x² + 1/x²)(x² + 1/x²) = 12
Expand to get: x⁴ + 1 + 1 + 1/x⁴ = 12
Simplify: x⁴ + 1/x⁴ = 10
Answer: A
Question: Find the L.C.M of 16, 25, 24 and 10.
A.1000
B.1400
C.1320
D.1200
Answer: D.1200
Explanation: Explanation:
4 x 5 x 2 x 3 x 5 X 2= 1200
Answer: Option D
Question: If the number92737*2 is completely divisible by 8, then the smallest whole number in place of * will be?
A.2
B.1
C.3
D.4
Answer: B.1
Explanation: The number 7x2 must be divisible by 8.
x=1 as 712 is divisible by 8.
Correct Option : B