RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Difference between the compound interest and the simple interest accrued on an amount of Rs. 18000 in two year is Rs. 405. What was the rate of interest?
A.14%
B.16%
C.12.5%
D.15%
Answer: D.15%
Explanation: C.I -S.I =P(R/100)^2
405=18000(R^2/10000)
(405*10000)/18000=R^2
R^2=225
Ans R=15%
ANSWER:D
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?
A.5.78
B.5.86
C.5.76
D.8.76
Answer: C.5.76
Explanation: M = 6
S = 1.2
DS = 7.2
US = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
D = 2.88 * 2 = 5.76
Answer:C
Question: In baseball, the batting average is defined as the ratio of a player’s hits to at bats. If a player had anywhere from 4 to 6 at bats in a recent game and had anywhere from 1 to 2 hits in the same game, the player’s actual batting average for that game could fall anywhere between
A.0.25 and 0.80
B.0.25 and 0.75
C.0.10 and 0.75
D.0.30 and 0.75
Answer: C.0.10 and 0.75
Explanation: Average Range = Hits to Bats i.e 1/6 to 2/4 = 0.16 to 0.50
Answer: C
Question: 6 litres of water are poured into an aquarium of dimensions 50cm length, 30cm breadth, and 40cm height. How high (in cm) will the water rise?
(1 litre = 1000cm³)
A.4
B.8
C.10
D.20
Answer: A.4
Explanation: lXbXh= 12000
h= 6000/50*30= 4 cm
'A' is the answer.
Question: The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?
A.120
B.180
C.270
D.260
Answer: C.270
Explanation: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 15
5x = 1350
x = 270
Smaller number = 270.
ANSWER: C
Question: Two taps can separately fill a cistern 7 minutes and 14 minutes respectively and when the waste pipe is open, they can together fill it in 8 minutes. The waste pipe can empty the full cistern in?
A.6.2
B.8.2
C.11.2
D.9.2
Answer: C.11.2
Explanation: 1/7 + 1/14 - 1/x = 1/8
x = 11.2
Answer:C
Question: In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 170 m. Then, A wins by:
A.60 m
B.20m
C.43m
D.20m
Answer: A.60 m
Explanation: To reach the winning post A will have to cover a distance of (500 - 170)m, i.e., 330 m.
While A covers 3 m, B covers 4 m.
While A covers 330 m, B covers 4 x 330/3	m	= 440 m.
Thus, when A reaches the winning post, B covers 440 m and therefore remains 60 m behind.
A wins by 60 m.
Answer:	A
Question: Remainder of 2^47/47 ?
A.2
B.3
C.4
D.5
Answer: A.2
Explanation: (2^(47/46))/47 = 2^1/47 = 2
ANSWER:A
Question: Among 100 people, 50% like strawberry jam, 40% like apple jam, and 30% like raspberry jam. If 30% of the people like both strawberry and apple jam, what is the largest possible number of people who like raspberry jam but do not like either strawberry or apple jam?
A.40%
B.30%
C.25%
D.50%
Answer: A.40%
Explanation: 50%+40%-30%=60% who like either Strawberry, Apple, or both.
That means 100%-60% = 40% do not like either Apple of Strawberry jam.
40% is the most possible that like raspberry jam but do not like either strawberry or apple (assuming nobody in the group does not like any)
Answer is A
Question: Bruno and Sacha are running in the same direction around a stadium. Sacha runs at a constant speed of 6 meters per second, and Bruno runs at a constant speed of 5 meters per second. At a certain point Sacha overtakes Bruno. If five minute afterward, Sacha stops and waits for Bruno to reach him, then how many seconds does he have to wait?
A.12
B.24
C.36
D.60
Answer: D.60
Explanation: the difference of the speed is 1m per second so in five minute Sacha will be 300 m ahead of Bruno..
Bruno will cover this in 300/5=60 secs..
D
Question: The unit’s digit in the product (3127)^173 is:
A.1
B.3
C.7
D.9
Answer: C.7
Explanation: Unit digit in (3127)^173 = Unit digit in 7^173.
Now, 7^4 gives unit digit 1.
Therefore, 7^173= (74)^43 * 7^1. Thus, 7^173 gives unit digit 7.
ANSWER:C
Question: The average weight of 8 people increases by 2.5 kg when a new person comes in place of one of them weighing 45 kg. What is the weight of the new person?
A.75 kg
B.85 kg
C.95 kg
D.65 kg
Answer: D.65 kg
Explanation: The total weight increase = (8 x 2.5) kg = 20 kg
weight of new person = (45 + 20) kg = 65 kg
The answer is D.
Question: As part of a game, five people each must secretly choose an integer between 1 and 5, inclusive. What is the approximate likelihood that all five people will choose different numbers?
A.4%
B.12%
C.16%
D.20%
Answer: A.4%
Explanation: Ans:a)
1st person has option no's- (1,2,3,4,5) - there fore probability of getting a no = 5c1/5c1 = 1
2nd person has option no's any four ,
he has to choose a no from four no's - there fore probability of getting a no = 4c1/5c1 = 4/5
3rd person has option no's any three ,
he has to choose a no from three no's -there fore probability of getting a no = 3c1/5c1 = 3/5
4th person has option no's any two - there fore probability of getting a no = 2c1/5c1 = 2/5
4th person has option no's only one - there fore probability of getting a no = 1c1/5c1 = 1/5
=1*4/5*3/5*2/5*1/5 = 4%
Question: The market price of an article was 40% more than its cost price. I was going to sell it at market price to a customer, but he showed me some defects in the article, due to which I gave him a discount of 28.57%. Next day he came again and showed me some more defects, hence I gave him another discount that was equal to 12.5% of the cost price. What was the approximate loss to me?
A.Loss of 10%
B.Loss of 12.5%
C.Loss of 15%
D.Loss of 25%
Answer: B.Loss of 12.5%
Explanation: Let the cost price be Rs 100
Then, market price is Rs 140
Now, the first discount is of 28.57% (approx.) = 2/7 th of market price.
Hence, its selling price = 140 x 5/7 = Rs 100
Now since you are selling at cost price, any further discount will be equal to loss percentage.
ANSWER:B
Question: Which of the following is equal to 1(1/2)%?
A.0.012/100
B.0.12/100
C.1.5/100
D.12/100
Answer: C.1.5/100
Explanation: This notation may be confusing for some, since it looks like we're multiplying 1 and 1/2
How about adding a space:Which of the following is equal to (1 1/2)%
(1 1/2)% = 1.5% = 1.5/100
Answer:
C
Question: A trader has 400 kg of rice, a part of which he sells at 36% profit and the rest at 24% loss. On the whole he losses 12%. What is the quantity sold at 24% loss?
A.80kg
B.100kg
C.175kg
D.320 kg
Answer: C.175kg
Explanation: Out of 400, some quantity gave 36% profit & remaining gave 24% loss
Now, 24% loss means -24% profit
From here, we got the 1st row of numbers i.e 36 & -24
The Resultant is again a loss of 12% , so profit of -12%; this will come up in the 2nd row
Using rules of alligation; -12 > -24; so subtracting:
- 12 - (-24) = -12 + 24 = 12
36 > -12; again subtracting:
36 - (-12) = 48
This gives the 3rd row i.e 12 & 48
So, the total (12 + 48) = 60, 48 have given a loss of 24%
So, calculation will be
48/(12+48)∗400=320 Answer = C
Question: Two cards are drawn at random from a pack of 52 cards.what is the probability that either both are black or both are queen
A.44/221
B.55/221
C.76/221
D.45/221
Answer: B.55/221
Explanation: WE HAVE N(S)=52C2=(52*51)/(2*1)=1326.
LET A=EVENT OF GETTING BOTH BLACK CARDS
B=EVENT OF GETTING BOTH QUEENS
AB=EVENT OF GETTING QUEEN OF BLACK CARDS
N(A)=26C2=(26*25)/(2*1)=325,
N(B)=4C2=(4*3)/(2*1)=6 AND
N(AB)=2C2=1
P(A)=N(A)/N(S)=325/1326;
P(B)=N(B)/N(S)=6/1326 AND
P(AB)=N(AB)/N(S)=1/1326
P(AB)=P(A)+P(B)-P(AB)=(325+6-1/1326)=330/1326=55/221
Option: B
Question: Nitin borrowed some money at the rate of 6% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years. If the total interest paid by him at the end of eleven years is Rs. 12240, how much money did he borrow?
A.12000
B.80288
C.2668
D.2600
Answer: A.12000
Explanation: Let the sum be Rs. x. Then,
[(x * 6 * 3)/100] + [(x * 9 * 5)/100] + [(x * 13 * 3)/100] = 12240
18x + 45x + 39x = (12240 * 100)
102x = 1224000 => x = 12000.
Answer:A
Question: A basket contains 5 apples, of which 1 is spoiled and the rest are good. If Henry is to select 2 apples from the basket simultaneously and at random, what is the probability W that the 2 apples selected will include the spoiled one?
A.a. 1/5
B.b. 3/10
C.c. 2/5
D.d. 1/2
Answer: C.c. 2/5
Explanation: there can be two ways in which one can select a spoiled apple and a good apple.
1. you pick the spoiled one first and the good one later..
Prob of picking bad one = 1/5 (one bad apple)
Prob of picking a good one from the remaining 4 good apples (4/4 =1)
therefore the total prob for case 1 = i/5 * 1 = 1/5
Total prob W= porb1 + prob2 = 1/5+1/5 = 2/5.C
Question: The average of a set of five distinct integers is 370. If each number is less than 2,000, and the median of the set is the greatest possible value, what is the sum of the two smallest numbers?
A.-4,494
B.-3,997
C.-3,494
D.-4,144
Answer: D.-4,144
Explanation: Sum of the set = 370*5=1850 Each number is less than 2000 and median of the set is the greatest possible value.
Therefore last 3 numbers can be 1999,1998 and 1997. Their sum=5994.
Therefore sum of two smallest numbers= 1850-5994= -4144
Answer=D
Question: A crate measures 7 feet by 8 feet by 12 feet on the inside. A stone pillar in the shape of a right circular cylinder must fit into the crate for shipping so that it rests upright when the crate sits on at least one of its six sides. What is the radius, in feet, of the pillar with the largest volume that could still fit in the crate?
A.2
B.4
C.6
D.7
Answer: D.7
Explanation: We can find the radius of all the three cases of cylinders.
The only crux to find the answer faster is that:
Voulme is pi*r^2*h. The volume is a function of r^2. so r has to be the highest to find the largest volume.
So r=7 for the surface 8*12 face.
Volume = 343pi
Answer D
Question: A car dealer has only red and yellow cars in his show room. He currently has 20% more yellow cars then red. IF he has 20 red cars, how many yellow cars does he have?
A.25
B.30
C.35
D.40
Answer: B.30
Explanation: Since we know the dealer only has yellow and red cars in their showroom we can conclude that red and yellow cars make up 100% of the cars. Since we know the difference between the amount of cars is 20% we can assume that the red cars make up 40% of the cars.
20/x=40/100 using cross multiplication we can find that 100x20=2000 and 2000/40=50
So now we know that there are 50 cars total. We can subtract the number of red cars from the total to find the number of yellow cars. 50-20=30
there are a total of 30 yellow cars. The answer is B
Question: If 4 men working 10 hours a day earn Rs. 1000 per week, then 9 men working 6 hours a day will earn how much per week?
A.Rs 840
B.Rs 1350
C.Rs 1620
D.Rs 1680
Answer: B.Rs 1350
Explanation: Explanation :
(Men 4:9) : (Hrs/Day 10:6) :: 1000 : x
hence 4 * 10 *x = 9 * 6 * 1000
or x = 9*6*1000/ 4*10 = 1350
Answer : B
Question: Mr. Ram is on tour and he has Rs 360 for his expenses. If he exceeds his tour by 4 days he must cut down daily expenses by Rs 3. The number of days of Mr. Ram's tour programme is
A.28 Days
B.24 Days
C.22 Days
D.20 Days
Answer: D.20 Days
Explanation: Solution:
Let Ram under takes a tour of x days.
Then, expenses for each day = 360/x
360/x+4=360/x−3
x=20x=20 and −24−24
Hence, x= 20 days.
Option(D)
Question: If x is an even integer, which of the following is an even integer?
A.3x-3
B.x+x^2
C.5x-3
D.2x+1
Answer: B.x+x^2
Explanation: Plug in an even integer; in this case 2
(3*2)-3 = 6-3 = 3 Odd
2+2^2 = 6 Even
(5*2)-3 = 10 - 3 = 7 Odd
(2*2)+1 = 4 + 1 = 5 Odd
(9*2)-5 = 18 - 5 = 13 Odd
Answer: B
Question: Two pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?
A.4 hrs
B.5 hrs
C.7 hrs
D.9 hrs
Answer: B.5 hrs
Explanation: Solution
A's work in 1 hour	= 1/6.
B's work in 1 hour	= 1/4.
(A+B)'s 2 hour's work when opened alternately	= (1/6 + 1/4)
= 5/12.
(A+B)'s 4 hour's work when opened alternately	= 10/12
= 5/6.
Remaining part	= (1 - 5/6)
= 1/6.
Therefore, total tank to fill the tank	(4+1)hrs = 5 hrs.
Answer B
Question: A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
A.Rs. 35
B.Rs. 245
C.Rs. 350
D.Cannot be determined
Answer: D.Cannot be determined
Explanation: EXPLANATION
We need to know the S.I., principal and time to find the rate.
Since the principal is not given, so data is inadequate.
Answer D
Question: Carl bought 16 gumballs, Lewis bought 12 gumballs, and Carey bought X gumballs. The average (arithmetic mean) number of gumballs the three bought is between 19 and 25, inclusive. What is the difference between the greatest number and the smallest number of gumballs Carey could have bought?
A.20
B.16
C.22
D.18
Answer: D.18
Explanation: Smallest gumballs = (19-16) + (19-12) +19= 29
Largest gumballs = (25-16) + (25-12) +25= 47
Difference = 47 - 29 = 18
D
Question: The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
A.10
B.50
C.20
D.30
Answer: D.30
Explanation: Let the three parts be A, B, C. Then,
A : B = 2 : 3 and B : C = 5 : 8
= (5 x (3/5)):(8 x (3/5))
= 3 : 24/5
A : B : C = 2 : 3 : 24/5
= 10 : 15 : 24
B = (98 x 15/49)= 30.
Answer is D.
Question: Maximum no of unsuccessful attempts, a thief can do in order to break a number locking system of 4 digits.
A.9988
B.9999
C.9799
D.9685
Answer: B.9999
Explanation: From 0 to 9999 there are 10000 four digit numbers
So maximum number of unsuccessful attempts = 10000 - 1 = 9999
ANSWER:B
Question: If a coin has an equal probability of landing heads up or tails up each time it is flipped , what is the probability that the coin will land Tails up exactly twice in 2 consecutive flips ?
A.0.125
B.0.25
C.0.375
D.0.5
Answer: B.0.25
Explanation: Total number of ways in which H or T can appear in 3 tosses of coin is
= 2 * 2 = 4 ways
For 2 H
TT,
Thus probability is
= P(TT)
= 1/4
= .25
Answer : B
Question: A woman took some money for borrowed, for 3 years the total will be Rs.4000 and 5 years it will be Rs.5000/-. Then how much amount she borrowed?
A.Rs.2500/-
B.Rs.2550/-
C.Rs.2590/-
D.Rs.2600/-
Answer: A.Rs.2500/-
Explanation: 3 years --------> Rs.4000/-
5 years --------> Rs.5000/-
~ ~
------------------------------
2 years ---------> Rs.1000/-
1 year ----------> Rs.500/-
3years * Rs.500/- = Rs.1500/-
P = Rs.4000/- - Rs.1500/- = Rs.2500/-
P = Rs.2500/-
A
Question: How many seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.878 meters
B.154 meters
C.500 meters
D.184 meters
Answer: C.500 meters
Explanation: Let length of tunnel is x meter
Distance = 800+x meter
Time = 1 minute = 60 seconds
Speed = 78 km/hr = 78*5/18 m/s = 65/3 m/s
Distance = Speed*Time
800+x = (65/3) * 60
800+x = 20 * 65 = 1300
x = 1300 - 800
=500 meters
Answer:C
Question: Approximately how many revolutions will be made by a car tire with a 12-inch diameter if the car travels 1 mile?
A.1,205
B.1,800
C.1,356
D.1,672
Answer: D.1,672
Explanation: Diameter of car tire = 12 inches
Radius of car tire = 6 inches = 6*2.54 cm = 15.24 cm
Circumference of the car tire = 2*pi * 15.24 = 2 *3.14 *15.24= 95.71 cm
Distance traveled by car =1 mile = 1 *1.6 km = 1.6 km = 1600 m = 1.6 * 10^5 cm
Number of revolutions =Distance traveled / Circumference of tire = 1.6 * 10^5 / 95.71 = 1671.72
Since the answer choices are far apart we should use estimation in this question .
Ideally ,in the GMAT the conversion between units would be provided .
Answer D
Question: A crew can row a certain course up the stream in 84 minutes; they can row the same course down stream in 6 minutes less than they can row it in still water. How long would they take to row down with the stream
A.45 or 23 minutes
B.63 or 12 minutes
C.78 minutes
D.19 minutes
Answer: C.78 minutes
Explanation: A method has been discussed here to nullify the calculations though.
All I can input here is,
speed of a crew in still water = 1/2 ( speed upstream + speed downstream)
approximating this for time,
t = 1/2(84+ (t-6))
giving t = 78
C.
Question: If k and y are integers, and 10k + y is odd, which of the following must be true?
A.k is odd
B.k is even
C.y is odd integer
D.y is even
Answer: C.y is odd integer
Explanation: 10k will be always even as 10 has 2 as one of its factors
if 10k+y is odd, then the only possible explanation is that y is odd
correct answer C
Question: what is the minimum possible range in scores of the three test-takers?Three people each took 5 tests. If the ranges of their scores in the 5 practice tests were 17, 25 and 36.
A.36
B.17
C.25
D.40
Answer: D.40
Explanation: I simply looked at the 3 different possible scores for each individual test: 17,36,25
We have to find the minimum range:
36-17=9
36-25=11
25-17=8
The find the minimum range, you have to make the set of the 5 scores as small as possible.
Which means that 4 of the 5 scores of each individual person is zero.
8*5 = 40
Answer:D
Question: What is the probability that a two digit number selected at random will be a multiple of '3' and not a multiple of '5'?
A.2/15
B.4/15
C.1/15
D.4/90
Answer: B.4/15
Explanation: Solution:
There are a total of 90 two digit numbers. Every third number will be divisible by '3'. Therefore, there are 30 of those numbers that are divisible by '3'.
Of these 30 numbers, the numbers that are divisible by '5' are those that are multiples of '15'. i.e. numbers that are divisible by both '3' and '5'.
There are 6 such numbers -- 15,30,45,60,75 and 90.
We need to find out numbers that are divisible by '3' and not by '5', which will be:
30âˆ’6=24
24 out of the 90 numbers are divisible by '3' and not by '5'.
The required probability is therefore,
=24/90
=4/15
ANSWER IS B
Question: In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 50 more than the correct answer. Find the number.
A.96
B.280
C.384
D.400
Answer: A.96
Explanation: Explanation:
Let the number be x.
5*x/6 = 5*x/16 +50
25*x/48 = 50
x = 96
ANSWER A
Question: man is 20 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
A.14years
B.26 years
C.17 years
D.18 years
Answer: D.18 years
Explanation: Let the son's present age be x years. Then, man's present age = (x + 20) years.
(x + 20) + 2 = 2(x + 2)
x + 22 = 2x + 4
x = 18.
answer :D
Question: From the word 'LAPAROSCOPY' how many independent meaningful words can be made without changing the order of the letters and using each letter only once ?
A.8
B.7
C.6
D.2
Answer: D.2
Explanation: Explanation:
The words are LAP and COPY.
Answer: D) 2
Question: Find (7x + 5y ) / (x-2y) if x/2y = 3/2 ?
A.24
B.25
C.26
D.27
Answer: C.26
Explanation: x/2y=3/2
=>x=6y/2=3y
=>(7x+5y)/(x-2y)=((7*(3y))+5y)/(3y-2y)
=>26y/y=26
ANSWER:C
Question: When positive integer n is divided by 4, the remainder is 2. When n is divided by 7, the remainder is 5. How many values less than 100 can n take?
A. 0
B. 2
C. 3
D. 4
Answer: C. 3
Explanation: a quick approac to this Q is..
the equation we can form is.. 3x+2=7y+5..
3x-3=7y... 3(x-1)=7y...
so (x-1) has to be a multiple of 7 as y then will take values of multiple of 3..
here we can see x can be 1,8,15,22,29 so 5 values till 100 is reached
as (29-1)*3=84 and next multiple of 7 will be 84+21>100..
ans 3.. C
Question: The number of cars present at a particular time was measured at 3,999 different locations on Tuesday and on Wednesday. The number of locations that had more cars on Wednesday was 10% higher than the number of locations that had more cars on Tuesday. How many of the locations had more cars on Tuesday?
A.1,159
B.1,333
C.1,860
D.1,904
Answer: D.1,904
Explanation: The question states that all these 3,999 locations were measured twice, once on each day.
It also breaks the 3,999 into two groups, the higher-on-Tuesday locations and the higher-on-Wednesday locations, which we can call T and W.
Therefore, we can write two equations:
For each of the first and second day count of locations, T + W = 3999
But, for the second day count, W = 1.10 T
i.e. for Second day count, T + 1.10T = 3999
i.e. 2.10 T = 3999
i.e. T = 1904
D
Question: Mixture of milk & water has been kept in two separate bowl. Ratio of milk to water in one of the bowls is 5 : 1 and that in the other bowl 7 : 2. In what ratio the mixtures of these 2 bowl should be added together so that the quantity of milk in the new mixture may become 80%?
A.2:3
B.1:3
C.2:5
D.2:7
Answer: A.2:3
Explanation: Lett. mixtures of the two containers be added together in the ratio of x
= = [ixoox l00%
Since the percentage quantity ofmilk in the new mixture is SO% — so% (45x + 42y) x 5 4 x 54(x y) 225x 210y 216.3E+216y
9x=6y
x:y=2:3
A
Question: Numbers from 1 to 10^2012 are given, there are 'm' no of 1's and 'n' no of 2's.
Then what is (m-n).
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: let us consider 1-100 here no of 1's m =21 and no.of 2's n = 20 there by m-n=1 similary from 1 to (10^2012-1) no.of 1's=no.of 2's but in last term 10^2012 a one is added there by the ans is 1.
ANSWER:B
Question: If z2 + 4y2 = 4zy, then z : y is :
A.2 : 1
B.1 : 2
C.1 : 1
D.1 : 4
Answer: D.1 : 4
Explanation: as the coefficient of z is 1 and coefficient of y is 4
ANSWER:D
Question: The sum of three consecutive even numbers is 42. Find the middle number of the three?
A.14
B.86
C.16
D.28
Answer: A.14
Explanation: Three consecutive even numbers (2P - 2), 2P, (2P + 2).
(2P - 2) + 2P + (2P + 2) = 42
6P = 42 => P = 7.
The middle number is: 2P
= 14.
Answer:A
Question: Arabica coffee costs $0.5 per ounce while Robusta coffee costs $0.3 per ounce. If the blend of Arabica and Robusta costs $0.33 per ounce, what is the share of Arabica in this blend?
A.15%
B.24%
C.30%
D.33%
Answer: A.15%
Explanation: a= amount of arabica coffee
1-a = amount of robusta coffee. because if you subtract a from the 1 ounce, the remaining amount is robusta
therefore:
.5a + .3(1-a) = .33
.5a + .3 - .3a = .33
a= .3/2
therefore: .3/2/1 ounce = 15%. Therefore, the answer should be A
Question: What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad
A.814
B.256
C.3258
D.896
Answer: A.814
Explanation: Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm^2.
Required number of tiles =(1517 x 902/41*41)= 814.
Answer : A
Question: Jerry’s average (arithmetic mean) score on the first 3 of 4 tests is 81. If Jerry wants to raise his average by 2 points, what score must he earn on the fourth test?
A.87
B.89
C.90
D.93
Answer: B.89
Explanation: Total score on 3 tests = 81*3 = 243
Jerry wants the average to be = 83
Hence total score on 4 tests should be = 83*4 = 332
Score required on the fourth test = 332 - 243 = 89
Option B
Question: What is remainder of the division (1625*1627*1629)/12?
A.3
B.2
C.1
D.0
Answer: A.3
Explanation: remainder will be number/ 100 here as the divisor is two digit number = 12.
hence checking for the last two digits = 5*7*9 = 15
Thus remainder = 3.
Answer : A
Question: There are 12 balls in a bag; 8 are blue balls and the other 4 are yellow balls. If 3 balls are to be selected at random from the 12 balls, what is the probability that at least one of the yellow ball will be selected?
A.57/55
B.56/55
C.54/55
D.53/55
Answer: C.54/55
Explanation: Total probability=12C3=220
8C3 +8C2*4C1+8C1*4C2=56+112+48=216
therefore the probability that at least one of the yellow ball will be selected= 216/220=54/55
answer is C