RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A set of numbers contains 7 integers and has an average (arithmetic mean) value as well as a median value of 23. If the largest value is equal to 15 more than 4 times the smallest number, what is the largest possible range for the numbers in the set?
A.33
B.35
C.38
D.48
Answer: D.48
Explanation: The average of 7 numbers is 23 --> the sum of these numbers is 7*23=161;
The median of 7 numbers is 23 --> 23 is the middle term: {*, *, *, 23, *, *, *};
The largest value is equal to 15 more than 4 times the smallest number --> say the smallest number is x then the largest number would be 4x+15, so our set is {x, *, *, 23, *, *, 4x+15};
Now, in order to maximize the range we need to make the second and the third numbers equal to x and the fifth and sixth numbers equal to 23, so the set should be {x, x, x, 23, 23, 23, 4x+15}.
Since the sum is 161 then x+x+x+23+23+23+4x+15=161 --> x=11.
The range is (4x+15)-x=3x+15=48.
Answer: D.
Question: A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. If the smaller wheel has made 21 revolutions, what will be the number of revolutions made by the larger wheel?
A.15
B.12
C.21
D.9
Answer: D.9
Explanation: Explanation:
Let the number of revolutions made by the larger wheel be x
More cogs, less revolutions (Indirect proportion)
Hence we can write as
(cogs) 6 : 14 :: x : 21
⇒6×21=14 × x
⇒6×3=2 × x
⇒3×3 = x
⇒x = 9
Answer: Option D
Question: If the average (arithmetic mean) of a and b is 100, and the average of b and c is 160, what is the value of a − c?
A.−120
B.−100
C.100
D.135
Answer: A.−120
Explanation: Question: a - c = ?
(a + b)/ 2 =100 ===> a + b = 200
(b + c)/2 = 160 ===> b + c = 320
(a + b) - (b + c) = 200 - 320 ===> a + b - b - c = - 120 ===> a - c = - 120
Answer: A
Question: A and B can do a work in 12 days, B and C in 30 days and C and A in 36 days. In how many days will the work be completed, if all three of them work together?
A.180/15
B.180/10
C.180/13
D.180/15
Answer: C.180/13
Explanation: One day work of A and B = 1/12
One day work of B and C = 1/30
One day work of C and A = 1/36
2(A + B + C) = 1/12 + 1/30 + 1/36
2(A + B + C) = 13/90
(A + B + C) = 13/180
Number of days required = 180/13 days.
Answer: C
Question: A, B and C started a business with a total investment of Rs. 72000. A invests Rs. 6000 more than B and B invests Rs. 3000 less than C. If the total profit at the end of a year is Rs. 8640, Find C's share.
A.Rs. 3240
B.Rs. 2520
C.Rs. 2880
D.Rs. 3360
Answer: C.Rs. 2880
Explanation: Explanation:
Let C's investment = Rs. x
B's investment = Rs. (x - 3000)
A's investment = Rs. (x - 3000 + 6000) = Rs. (x + 3000)
Now, (A + B + C)'s investment = Rs. 72000
=> x + (x - 3000) + (x + 3000) = 72000
=> 3x = 72000
=> x = 24000
Hence, A's investment = Rs. 27000
B's investment = Rs. 21000
C's investment = Rs. 24000
Ratio of the capitals of A, B and C
= 27000 : 21000 : 24000
= 9 : 7 : 8
A's share = Rs. [(8/24) Ã— 8640] = Rs. 2880
Answer: Option C
Question: A work crew of 4 Men takes 5 days to complete one-half of a job. If 11 men are then added to the crew and the men continue to work at the same rate, how many days will it take the enlarged crew to do the rest of the job?
A.2
B.3
C.1 1/3
D.4
Answer: C.1 1/3
Explanation: Suppose 1 man can do work in X days..
so 4 men will do in ..
4/X=1/5*1/2 as half job is done
X=40
now 11 more are added then
15/40=1/2*1/d for remaining half job
d=1 1/3 Number of days
C
Question: The remainder when 1!+2!+3!...+50! divided by 6! will be
A.21
B.153
C.77
D.927
Answer: B.153
Explanation: The remainder when the terms greater than 6! are divided by 6! becomes 0 so we need to consider the terms upto 5!.
So remainder will be whatever is obtained by dividing 1!+2!+3!+4!+5! with 6!.
So remainder is obtained by dividing (1+2+6+24+120)= 153 with 6! ( 720)
So remainder is 153.
Answer:B
Question: The population of locusts in a certain swarm doubles every two hours. If 4 hours ago there were 1,000 locusts in the swarm, in approximately how many hours will the swarm population exceed 128,000 locusts?
A.12
B.8
C.4
D.10
Answer: D.10
Explanation: - 4 hours: 1,000
-2 hours: 2,000
Now: 4,000
+ 2 hours: 8,000
+ 4 hours: 16,000
+ 6 hours: 32,000
+ 8 hours: 64,000
+ 10 hours: 128,000
Answer : D
Question: Find the face value of 5 in 358946
A.50
B.5
C.500
D.5000
Answer: B.5
Explanation: Face value is the value of digit itself
face value of 5 = 5
Answer : B
Question: Rich has 3 green, 2 red and 3 blue balls in a bag. He randomly picks 5 from the bag without replacement. What is the probability E that of the 5 drawn balls, Rich has picked 1 red, 2 green, and 2 blue balls?
A.8/28
B.E=9/28
C.10/28
D.10/18
Answer: B.E=9/28
Explanation: (3c2*2c1 *3c2)/8c5
=(3*2*3)/(8*7*6/3*2)
=18/56
=9/28
B
Question: Find the value of (200+ 200/90) × 90
A.18500
B.18200
C.17500
D.16500
Answer: B.18200
Explanation: (18000 + 200)/90 * 90 = 18200
Answer : B
Question: Three years ago the average age of a family of six members was 19 years. A boy have been born, the average age of the family is the same today. What is the age of the boy?
A.1
B.2
C.7
D.3
Answer: A.1
Explanation: 6 * 22 = 132
7 * 19 = 133
--------------
1
Answer: A
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively . If they cross each other in 26 seconds, what is the ratio of their speeds?
A.1:3
B.9:1
C.2:3
D.3:2
Answer: B.9:1
Explanation: Let the speed of the trains be x and y respectively
length of train1 = 27x
length of train2 = 17y
Relative speed= x+ y
Time taken to cross each other = 26 s
= (27x + 17 y)/(x+y) = 26
= (27x + 17 y)/ = 26(x+y)
= x = 9y
=x/y = 9/1
Answer :B
Question: Three years ago the average age of a family of nine members was 23 years. A boy have been born, the average age of the family is the same today. What is the age of the boy?
A.A)4
B.B)5
C.C)6
D.D)7
Answer: A.A)4
Explanation: 9 * 26 = 234
10 * 23 = 230
--------------
4
Answer: A
Question: The average weight of 20 persons sitting in a boat had some value. A new person added to them whose weight was 49 kg only. Due to his arrival, the average weight of all the persons decreased by 5 kg. Find the average weight of first 20 persons?
A.55
B.56
C.57
D.58
Answer: B.56
Explanation: 20x + 49 = 21(x – 5)
X=56
ANSWER:B
Question: The surface of a cube is 24sq cm. Find its volume?
A.8
B.6
C.4
D.3
Answer: A.8
Explanation: 6a2 = 24
a = 2 => a3 = 8cc
Answer: A
Question: A sum of Rs.13000 is divided into three parts such that the simple interests accrued on them for two, three and four years respectively may be equal. Find the amount deposited for 4 years.
A.5000
B.6000
C.4000
D.3000
Answer: D.3000
Explanation: Let the amounts be x, y, z in ascending order of value. As the interest rate and interest accrued are
same for 4 years 3 years and 2 years i.e. 4x = 3y = 2z = k.
L.C.M. of 4,3,2 = 12 So x:y:z: = 3000 : 4000 :6000
The amount deposited for 4 years = 3000
ANSWER:D
Question: The sum of the present ages of A, B, C is 57 years. Three years ago their ages were in the ratio 1:2:3. What is the present age of A?
A.8
B.9
C.10
D.11
Answer: D.11
Explanation: Three years ago:
a:b:c = 1:2:3
Let a = 1x, b = 2x, and c = 3x.
Today:
(x+3) + (2x+3) + (3x+3) = 57
x = 8
So the present age of A is x+3 = 11
The answer is D.
Question: Find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 754.
A.122 , 124 ,126, 128
B.120 ,122 , 124 ,128
C.120 ,121 , 122 ,123
D.123 ,125 , 127 ,129
Answer: A.122 , 124 ,126, 128
Explanation: Let x, x + 2, x + 4 and x + 6 be the four integers. The sum of the first two
x + (x + 2)
twice the sum of the last two is written as
2 ((x + 4) + (x + 6)) = 4 x + 20
sum of the first two added to twice the sum of the last two is equal to 754 is written as
x + (x + 2) + 4 x + 20 = 754
Solve for x and find all four numbers
x = 122 , x + 2 = 124 , x + 4 = 126 , x + 6 = 128
Answer A
Question: Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?
A.11/P + 6
B.11/P + 9
C.11/P + 5
D.11/P + 3
Answer: A.11/P + 6
Explanation: Explanation:
Let Ben’s age now be B
Anita’s age now is A.
(A - 6) = P(B - 6)
But A is 17 and therefore 11 = P(B - 6)
11/P = B-6
(11/P) + 6 = B
Answer: A) 11/P + 6
Question: A camera lens filter kit containing 5 filters sells for $75.50. If the filters are purchased individually, 3 of them are priced at $7.35 each, 3 at $12.05 each, 1 at $12.50. The amount saved by purchasing the kit is what percent of the total price of the 5 filters purchased individually?
A.5.35%
B.6.35%
C.7.35%
D.8.35%
Answer: B.6.35%
Explanation: Cost of kit = $75.50
If filters are purchased individually - $7.35*3 + $12.05*3 + $12.50 = $70.70
Amount saved = $75.50 - $70.70 = $4.80
Required %age = ($4.80/$75.50)*100 = 6.35%
So, the correct answer is B.
Question: If the perimeter of a rhombus is 52 cm and one of its
diagonals is 24 cm, then the area of the rhombus is
A.100 sq.cm
B.110 sq.cm
C.120 sq.cm
D.130 sq.cm
Answer: C.120 sq.cm
Explanation: perimeter of rhombus = 4a (with side a)
4a=52 then a=13,
lets length of one diagonal p=24cm,
lenght of other diagonal is q;
area of rhombus = pq/2
using pythogorus theorem a^2= (p/2)^2 + (q/2)^2
we will get q=10.
then area=10*24/2=120 sq.cm
ANSWER:C
Question: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most
A.238
B.377
C.215
D.287
Answer: C.215
Explanation: Explanation:
Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 * 6 * 6 = 216. Of these attempts, one of them is a successful attempt.
Maximum number of unsuccessful attempts = 216 - 1 = 215.
Answer: C
Question: An accurate clock shows 8 o'clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 o'clock in the afternoon?
A.180
B.345
C.234
D.488
Answer: A.180
Explanation: Angle traced by the hour hand in 6 hours = (360)/12x 6º	= 180º.
Answer:A
Question: 3/4 of 1/2 of 2/5 of 5100 = ?
A.392
B.229
C.765
D.493
Answer: C.765
Explanation: C
765
? = 5100 * (2/5) * (1/2) * (3/4) = 765
Question: The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age was five times the age of the son. After 6 years, son's age will be:
A.5:2
B.7:3
C.9:2
D.13:4
Answer: B.7:3
Explanation: Let the age of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40 => x = 20.
Required ratio = (3x + 10):(x + 10) = 70:30 = 7:3
ANSWER:B
Question: There are three different pipes used to fill a pool: pipe x, pipe y, and pipe z. Pipe x can fill the pool in a days, pipe y in b days, and pipe z in c days, where a > b > c. When all three pipes are used together to fill a pool, it takes d days to fill the pool. Which of the following must be true?
I. d<c
II. d>b
III. c/3<d<a/3
A.II
B.I
C.III
D.I&II
Answer: A.II
Explanation: Name T = full pool
X fills a pool in a days ==> 1 day X fills: T/a
Y fills a pool in b days ==> 1 day Y fills: T/b
Z fills a pool in c days ==> 1 day Z fills: T/c
1 day (X+Y+Z) together fill: T(1/a + 1/b + 1/c)
d days (X+Y+Z) together fill: T
==> d = Tx1 / T(1/a+1/b+1/c) = abc/(ab+bc+ca)
A
==>d = abc/(ab+bc+ca)
d cannot be greater than c ; d is greater than b ; d is greater than c/3 but not less than a/3
Question: The number of bacteria in a petri dish increased by 50 percent every 2 hours. If there were 108 million bacteria in the dish at 5: 00 p.m., at what time were there 32 million bacteria in the dish?
A.11: 00 a.m.
B.8: 00 p.m.
C.6: 00 a.m.
D.8: 00 a.m.
Answer: A.11: 00 a.m.
Explanation: Given:
The number of bacteria in a petri dish increased by 50 percent every 2 hours
There were 108 million bacteria in the dish at 2: 00 p.m
Since the bacteria is increasing by 50% every 2 hours, this means that the number is multiplied by 1.5 every 2 hours.
Required: At what time were there 32 million bacteria in the dish?
Assume that there were n intervals of 2 hours between 32 million and 108 million.
32 * (1.5)^n = 108
(3/2)^n = 108/32 = 27/8 = (3/2)^3
Hence n = 3 intervals.
Each interval was of 2 hours. Therefore, the number of hours = 6
Subtracting 6 hours from 5 PM, we get 11 AM as the answer.
Option A
Question: If 2 cards are selected at random from the deck of 52 cards then What is the probability of selected cards will be Queen?
A deck of cards has a total of 52 cards, consisting of 4 suits; (spades(Black), hearts(Red), diamond(Red)s, and clubs(Black)); and 13 cards including 1 king, 1 queen and 1 jack in each suit
A.12/2652
B.14/2652
C.2/2652
D.4/2652
Answer: A.12/2652
Explanation: the total probability = (4/52 * 3/51) = 12/2652. A is the correct answer.
Question: A money lender lent a total of $1500 to two of his customers. He charged at the rate of 5%p.a. to one of them and 6% p.a. to the other. If he earned an average of 5.67% on $1500, how much did he lend to each of the two customers?
A.700; 1100
B.1005; 495
C.1000; 800
D.1200; 800
Answer: B.1005; 495
Explanation: The method given above is the one given in the book.
However the method I used was
(1*x*5)/100 + (1500-x)*6/100 = 1500*5.67/100
Simplifying we get x=495
B
Question: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
A.175
B.275
C.375
D.475
Answer: A.175
Explanation: Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x x 3.20 = 432
3.20x = 432 - 384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175.
Answer is A.
Question: In a competitive examination in state Madhya Pradesh, 4% candidates got selected from the total appeared candidates. State Uttar Pradesh had an equal number of candidates appeared and 9% candidates got selected with 72 more candidates got selected than Madhya Pradesh. what was the number of candidates appeared from each state?
A.1440
B.1400
C.1600
D.720
Answer: A.1440
Explanation: Explanation :
Solution: Let the number of candidates appeared from each state be x.
then, 9% of x - 4% of x =72.
=>5% of x =72
=>5x/100 =72 => x =72*100/5 = 1440
Answer : A
Question: The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
A.4 years
B.8 years
C.10 years
D.None of these
Answer: A.4 years
Explanation: EXPLANATION
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.
Age of the youngest child = x = 4 years.
Answer A
Question: The Sum of first N consecutive odd integers is N^2. What is the sum of all odd integers between 13 and 35 inclusive.
A.288
B.364
C.410
D.424
Answer: A.288
Explanation: We're dealing with a sequence of CONSECUTIVE ODD INTEGERS: 13 to 35, inclusive. We're asked for the SUM of this group.
1) Start with the sum of the smallest and the biggest: 13 + 35 = 48
2) Now look at the 'next smallest' and the 'next biggest': 15 + 33 = 48
Now we have proof that there is no middle term. We have 6 bunches of 48.
6(48) = 288
A
Question: One ball will drop from a certain height. The height it will reach after rebounding from the floor is 50 percent of the previous height. The total travel is 200cm when it touches the floor on third time. What is the value of the original height?
A.80cm
B.90cm
C.100cm
D.120cm
Answer: A.80cm
Explanation: when Ball comes down, Then i have indicated the distance covered in green
when Ball goes up, Then i have indicated the distance covered in red
Distance travelled uptil the ball touches the floor 3rd time:h+0.5h+0.5 h+0.5*0.5 h+0.5*0.5 h
h + 2 * 0.5 * h + 2 * 0.25 * h = h (1+2*0.5+2* 0.25) = h (1+1+0.5) = 80
2.5 h = 80
h = 80.
A is the answer.
Question: Three numbers are in the ratio of 2 : 3 : 4 and their L.C.M. is 264. What is their H.C.F.?
A.18
B.22
C.24
D.28
Answer: B.22
Explanation: Let the numbers be 2x, 3x, and 4x.
LCM of 2x, 3x and 4x is 12x.
12x = 264
x = 22
HCF of 2x, 3x and 4x = x = 22
The answer is B.
Question: In a two-digit number, if it is known that its unit's digit exceeds its ten's digit by 4 and that the product of the given number and the sum of its digits is equal to 90, then the number is:
A.15
B.27
C.38
D.46
Answer: A.15
Explanation: Let the ten's digit be x. Then, unit's digit = x + 4. Number = 10x + (x + 4) = 11x + 4
Sum of digits = x + (x + 4) = 2x + 4
(11x + 4)(2x + 4) = 90
22(x)(x) +52x - 74 = 0
(x - 1)(22x + 74) = 0
x = 1
Hence, required number = 11x + 4 = 15.
ANSWER:A
Question: Andrew has a certain number of coins in his pocket. He has four times as many dimes as quarters and six times as many nickels as dimes. A nickel is worth $0.05, a dime is worth $0.10 and a quarter is worth $0.25. If he has a total of $10.15, then which of the following represents the number of dimes in Andrew’s pocket?
A.9
B.10
C.18
D.20
Answer: C.18
Explanation: E.
Let number of quarters be q. Therefore , dimes are 3q and nickels are 18q.
Total value = 18q(.05) + 4q(0.1) + .25q =1.55q
Given total value = 10.15
therefore, 1.55q=10.15 or q=6
Number of dimes = 3q or 18
Answer : C
Question: If n is the product of the integers from 1 to 12, inclusive, how many different prime factors greater than 1 does n have?
A.Four
B.Five
C.Six
D.Seven
Answer: B.Five
Explanation: n = 1*2*3*4*5*6*7*8*9*10*11*12
The prime factors of n are 2, 3, 5, 7, and 11.
There are 5 prime factors.
The answer is B.
Question: A marketing survey of Anytown found that the ratio of trucks to sedans to motorcycles was 3:7:2, respectively. Given that there are 11,900 sedans in Anytown, how many motorcycles are there?
A.1260
B.2100
C.3400
D.4200
Answer: C.3400
Explanation: Let the total number of trucks = 3x
total number of sedans = 7x
total number of motorcycles = 2x
total number of sedans = 11900
=> 7x = 11900
=> x = 1700
total number of motorcycles =2x = 2*1700
=3400
Answer C
Question: A thief is spotted by a policeman from a distance of 100metres. When the policeman starts the chase, the thief also starts running. If the speed of the thief be 8km/hr and that of the policeman 10km/hr, how far the thief will have run before he is overtaken ?
A.400m
B.1km
C.500m
D.450m
Answer: A.400m
Explanation: Relative speed of the policeman = 10-8 = 2 km/hr
time taken by policeman to cover 100m = (100/1000)*(1/2) = 1/20 hr
In 1/20 hr the thief covers a distance of 8/20 km = 2/5 km = 400m
Answer is A
Question: A student scores 55% marks in 8 papers of 100 marks each. He scores 15% of his total marks in English. How much does he score in English?
A.55
B.66
C.77
D.44
Answer: B.66
Explanation: Given student scores 55% marks in english in 8 papers of 100 marks each.
so,his total marks are (55*800)/100 =>440
15% of his 440 marks is 440*(15/100)=>66
so,he scored 66 marks in english.
ANSWER:B
Question: Joe is now 26 years older than Ella. If in 12 years Joe will be three times as old as Ella, how old will Joe be in 6 years?
A.31
B.33
C.35
D.37
Answer: B.33
Explanation: J=E+26 so E=J-26.
J+12=3(E+12).
J+12=3(J-26+12).
J+12=3J-42.
2J=54.
J=27.
In 6 years, Joe will be 33 years old.
The answer is B.
Question: How many words, with or without meaning, can be formed using all letters of the word ORANGE using each letter exactly once?
A.700
B.720
C.740
D.760
Answer: B.720
Explanation: The Word ORANGE has exactly 6 letters which are all different.
Therefore the number of words that can be formed = Number of permutations of 6 letters taken all at a time.
= P (6, 6) = 6!
= 6 × 5 x 4 x 3 x 2 × 1
= 720
ANSWER:B
Question: A, B and C invest in a partnership in the ratio: 7/2,4/3,6/5. After 4 months, A increases his share 50%. If the total profit at the end of one year is Rs.21,600, then what is B's share in the profit?
A.2000
B.3000
C.5000
D.4000
Answer: D.4000
Explanation: Ratio of the initial investment
=7/2:4/3:6/5=105:40:36
Therefore, let the initial investments of A, B and C be 105x,40x and 36x respectively
A increases his share 50% after 4 months. Hence the ratio of their investments
=((105x)×4)+((105x)×150/100×8) :(40x)×12:(36x)×12
=105+(105×32×2) :40×3:36×3
=105×4:40×3:36×3
=35×4:40:36
=35:10:9
B's share = total profit × 10/54
=21600×10/54=4000
Answer is D.
Question: The total age of A and B is 18 years more than the total age of B and C. C is how many years younger than A.?
A.16
B.12
C.15
D.18
Answer: D.18
Explanation: (A+B)-(B-C)=18
A-C=18
Answer is D
Question: what is the 10 th term in 1,3,9,15,25,35,-----?
A.66
B.77
C.88
D.99
Answer: D.99
Explanation: 1^2 =1
2^2 -1 =3
3^2 =9
4^2 -1 =15
5^2 =25
6^2 -1 =35
7^2 =49
8^2 -1 =63
9^2 =81
10^2 -1=99
ANSWER:D
Question: A fair coin is tossed repeatedly. If heads appears on first 3 tosses what is the probability that tail appears on the next two tosses?
A.1/6
B.1/5
C.1/3
D.1/4
Answer: D.1/4
Explanation: Explanation :
Like mentioned in the question, the coin is fair. So chance of appearing of head and tail on each toss is same and each toss is independent from the previous one. So the chance of appearing tail on the next two tosses is still 1/2 each.
1/2 * 1/2 = 1/4
Answer : D
Question: A train 150 m long is running with a speed of 68 kmph. In what time will it pass a man who is running at 8 kmph in the same direction in which the train is going ?
A.5 seconds
B.6 seconds
C.9 seconds
D.8 seconds
Answer: C.9 seconds
Explanation: Relative speed of train and man=60kmph or 300/18m/s
Time taken by the train to pass the man:
Length of the train/relative speed
150/300/18=9 seconds.
ANSWER:C
Question: Evaluate 35% of 450 + 45% of 350
A.232
B.242
C.315
D.262
Answer: C.315
Explanation: Explanation:
= (35/100) * 450 + (45/100) * 350
= 315
Option C
Question: In how many ways letters of the word RESPECT be arranged?
A.2310
B.2536
C.3260
D.2520
Answer: D.2520
Explanation: RESPECT has 7 letters, out of which E repeated 2 times. Hence total ways = 7! / 2! = 2520 ways
D
Question: 15 litres of water are poured into an aquarium of dimensions 50cm length, 30cm breadth, and 40cm height. How high (in cm) will the water rise?
(1 litre = 1000cm³)
A.6
B.8
C.10
D.20
Answer: C.10
Explanation: lXbXh= 15000
h= 15000/50*30= 8 cm
'C' is the answer.
Question: For her customer feedback score, Jess wants to average at or above an 8.0 rating. For the month of June, she received the following scores: 9, 8, 8, 7, 9, 10, 6, 6, 8 and 7. By what percent did she fall short of her goal?
A. 2.5%
B. 5%
C. 8%
D. 10%
Answer: A. 2.5%
Explanation: Expected minimum rating = 8
Deviation from the expected minimum rating = (1 + 0 + 0 - 1 + 1 + 2 - 2 - 2 + 0 - 1)/10 = -2/10 = -0.2
Current rating is 0.2 less than 8.
Percentage = (0.2/8)*100 = 2.5%
Answer: A
Question: Ben is driving on the highway at x miles per hour. (One mile equals 5,280 feet.) Ben's tires have a circumference of z feet. Which of the following expressions gives the number of revolutions each wheel turns in one hour?
A.5,280(x/z)
B.5,280(y/x)
C.5,280(xy)
D.5,280/(xy)
Answer: A.5,280(x/z)
Explanation: In one hour, at the rate of x miles per hour, Ben covers x miles, so 5,280x feet.
The number of revolutions = distance/circumference = 5,280x/z.
Answer: A.
Question: A man buys an article for 10% less than its value and sells it for 10% more than its value. His gain or loss percent is:
A.no profit, no loss
B.20% profit
C.less than 20% profit
D.more than 20% profit
Answer: D.more than 20% profit
Explanation: Let the article be worth Rs. x.
C.P. 90% of Rs. x = Rs. 9x/10
S.P. = 110% of Rs. x = Rs. 11x/10
Gain = (11x/10 - 9x/10) = Rs. x/5
Gain % = x/5 * 10/9x * 100 = 22 2/9 % > 20%
ANSWER:D
Question: A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was
A.11 years
B.12 years
C.14 years
D.15 years
Answer: C.14 years
Explanation: Let the son's present age be x years. Then, (38 - x) = x
2x = 38.
x = 19.
Son's age 5 years back (19 - 5) = 14 years.
C)
Question: By selling 10 pens for a rupee a woman loses 18%. How many for a rupee should he sell in order to gain 30%?
A.12
B.14
C.45
D.6
Answer: D.6
Explanation: D
82% --- 10
130% --- ?
82/130 * 10 = 6