RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A fruit vendor purchased 20 dozens of bananas at Rs. 15 per dozen. But one-fourth of the bananas were rotten and had to be thrown away. He sold two-third of the remaining bananas at Rs. 22.50 per dozen. At what price per dozen should he sell the remaining bananas to make neither a profit nor a loss?
A.Rs. 20
B.Rs. 15
C.Rs. 22.50
D.Rs. 7.50
Answer: B.Rs. 15
Explanation: CP of 20 dozen of bananas = 15 * 20 = Rs. 300
Number of bananas which are rotten = 1/4 * 20 = 5 dozen.
SP of two-third of remaining bananas = (2/3 * 15) * 22.5 = Rs. 225
SP of remaining 5 dozens of bananas to make no profit and no loss =(300 - 225) = Rs. 75.
SP of 1 dozen bananas = 75/5 = Rs. 15.
ANSWER:B
Question: A water tank, having the shape of a rectangular prism of base 100 square centimeters, is being filled at the rate of 1 liter per minute. Find the rate at which the height of the water in the water tank increases. Express your answer in centimeters per minute.
A.40 cm/m
B.15 cm/m
C.10 cm/m
D.35 cm/m
Answer: C.10 cm/m
Explanation: The volume of a rectangular prism is given by
area of base ? height
The rate at which the tank is being filled is 1 liter per minute which we need to convert
1 liter = 1 dm3
But 1 dm = 10 cm. Hence
1 liter = (10 cm)3 = 1000 cm3
The height h of the water is related to the volume by
volume = area of base ? h
In one minute the volume increases by 1 liter or 1000 cm3 and the height increases by
h = volume / area of base = 1000 cm3 / 100 cm2 = 10 cm
correct answer C
Question: An error 4% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is
A.8.04%
B.8.14%
C.8.23%
D.8.16%
Answer: D.8.16%
Explanation: 100 cm is read as 102 cm.
A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.
(A2 - A1) = [(104)2 - (100)2]
= (104 + 100) x (104 - 100)
= 816 cm2.
Percentage error = 8.16
D
Question: How much 60% of 50 is greater than 30% of 30?
A.21
B.91
C.11
D.17
Answer: A.21
Explanation: (60/100) * 50 – (30/100) * 30
30 - 9 = 21
Answer: A
Question: 2a
33
+ b9
____
99
If a and b represent positive single digits in the correctly worked computation above, what is the value of a + 3b ?
A.2
B.7
C.9
D.11
Answer: D.11
Explanation: Adding the digits in unit's place , a+ 3 + 9 = 19 (Since a and b are positive single digits )
=> a = 7
Now adding the digits in ten's place , 2+ 3 + b + 1= 9 (1 has been carried over from nit's place addition)
=> b= 3
a+3b = 2+2*3
=11
Answer D
Question: A goat is tied to one corner of a square plot of side 12m by a rope 7m long. Find the area it can graze?
A.32
B.36.5
C.38.5
D.39
Answer: C.38.5
Explanation: Area covered by goat = Pi*r^2/4 ( here we divide by 4 because rope is tied at the corner of the plot and only 1/4 part , the goat can graze)
where r= 7 m = length of rope
So area = (22/7)*7*7/4 = 38.5 sq m
answer :C
Question: Find the constant k so that : -x2 - (k + 8)x - 8 = -(x - 2)(x - 4)
A.11
B.12
C.14
D.19
Answer: C.14
Explanation: -x2 - (k + 8)x - 8 = -(x - 2)(x - 4) : given
-x2 - (k + 8)x - 8 = -x2 + 6x - 8
-(k + 8) = 6 : two polynomials are equal if their corresponding coefficients are equal.
k = -14 : solve the above for k
correct answer C
Question: Alfred buys an old scooter for Rs. 4700 and spends Rs. 800 on its repairs. If he sells the scooter for Rs. 5800, his gain percent is?
A.5 5/11%
B.6%
C.7%
D.8%
Answer: A.5 5/11%
Explanation: Cost Price (C.P.) = Rs. (4700 + 800) = Rs. 5500.
Selling Price (S.P.) = Rs. 5800.
Gain = (S.P.) - (C.P.) = Rs.(5800 - 5500) = Rs. 300.
Gain % = 300/5500 x 100	%	= 5	5/11	%
A)
Question: There are two concentric circles such that the area of the outer circle is four times the area of the inner circle. Let A, B and C be three distinct points on the perimeter of the outer circle such that AB and AC are tangents to the inner circle. If the area of the outer circle is 12 square centimetres then the area (in square centimetres) of the triangle ABC would be
A.π√​12
B.9/π
C.9√3/π
D.6√3/π
Answer: C.9√3/π
Explanation: Explanation :
Outer circle:
Since πR² = 12, R = √(12/π) = 2√(3/π).
Inner circle:
Since the area is 1/4 the area of the outer circle, πr² = 3 and r = √(3/π)
AO is the Radius of the outer circle and OD is the radius of the inner circle.
A line tangent to a circle and a radius drawn to the point of tangency form a right angle.
Thus, ∆AOD is a right triangle.
Hypotenuse AO is twice the length of leg OD.
A right triangle whose hypotenuse is twice the length of a leg is a 30-60-90 triangle.
Thus, ∆AOD is a 30-60-90 triangle.
In a 30-60-90 triangle, the sides are proportioned x : x√3 : 2x.
Thus, AD = √3 * √(3/π) * = 3/√π.
Using the same reasoning for ∆OCD, we can deduce that CD = 3/√π.
Thus, AC = 2 * 3/√π = 6/√π.
The formula for the area of an equilateral triangle = (s²√3)/4.
Since AC = 6/√π, the area of ∆ABC = (6/√π)² * √3/4 = 36/π * √3/4 = (9√3)/π.
Answer : C
Question: Capacity of a cylindrical vessel is 25,872 litres. If the height of the cylinder is 200% more than the radius of its base, what is the area of the base in square cms?
A.336
B.1232
C.616
D.926
Answer: C.616
Explanation: let r be the radius
so height,h=r+(200% of r)=r+2r=3r
volume of cylinder=pi*r^2*h
or pi*r^2*3r=25872
or 22/7 *r^3=8624
or r^3=392*7=8*7*7*7
0r r=14
so area of base=22/7 *14*14=616
ANSWER:C
Question: Visitors to show were charged Rs.15 each on the first day. Rs.7.50 on the second day, Rs.2.50 on the third day and total attendance on the three days were in ratio 2:5:13 respectively. The average charge per person for the whole show is?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: 2: 5: 13
2x 5x 13x
15 7.5 2.5
30x + 37.5x + 32.5x = 100x/20x
Average = 5
Answer: C
Question: A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
A.22 1/7
B.22 1/4
C.22 1/2
D.22 1/1
Answer: C.22 1/2
Explanation: 100 --- 10 DS = 10
? ---- 1
75 ---- 15 US = 5
? ----- 1 S = (10 - 5)/2
= 22 1/2 kmp Answer: C
Question: The price of a bushel of corn is currently $3.20, and the price of a peck of wheat is $9.80. The price of corn is increasing at a constant rate of 5x cents per day while the price of wheat is decreasing at a constant rate of x(2^1/2) - x cents per day. What is the approximate price when a bushel of corn costs the same amount as a peck of wheat?
A.$4.50
B.$5.10
C.$9.30
D.$5.50
Answer: C.$9.30
Explanation: I Tried using Time/Rate approach:-
Initial Price Difference = 9.80 - 3.20 = 6.60
Price of Corn increasing by 5x
Price of Wheat decreasing by x(1.4)-x = .4x
Since both the quantities are moving towards reducing the Price Gap hence:-
Relative Increase = 5x +.4x
Let T be the Time by which GAP is filled so,
6.6 = T(5.4x) -> T= (6.6)/5.4X
Final Price = 3.20 + 5X * T -> 3.20 + 5*6.6/5.4 = 9.3
Answer C.
Question: The marks obtained by Vijay and Amith are in the ratio 4:7 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of?
A.6:8
B.6:1
C.6:5
D.6:7
Answer: D.6:7
Explanation: 4:7
3:2
-------
12:21:14
12:14
6:7
Answer: D
Question: If each of 4 subsidiaries of Corporation R has been granted a line of credit of $791,000 and each of the other 3 subsidiaries of Corporation R has been granted a line of credit of $112,000, what is the average (arithmetic mean) line of credit granted to a subsidiary of Corporation R?
A. $500,000
B. $448,000
C. $406,000
D. $313,600
Answer: A. $500,000
Explanation: My take is A.
(791000*4 + 112000*3)/7 = 500000
Question: A sporting goods store sold 64 Frisbees in one week, some for $3 and the rest for $4 each. If receipts from Frisbee sales for the week totaled $200, what is the fewest number of $4 Frisbees that could have been sold?
A.24
B.8
C.12
D.4
Answer: B.8
Explanation: In this question however, because we are told that exactly 64 Frisbees have been sold and revenue was exactly $204, there is only one possible solution for the number of $3 and $4 Frisbees sold.
To solve, we have 2 equations and 2 unknowns
Let x = number of $3 Frisbees sold
Let y = number of $4 Frisbees sold
x + y = 64
3x + 4y = 200
x = 64 - y
3(64-y) + 4y = 200
192 - 3y + 4y = 200
y = 8
Answer: B
Question: If x is an integer and 2.13 × 10^x is less than 2100, what is the greatest possible value for x?
A.2
B.6
C.5
D.4
Answer: A.2
Explanation: If x=3
2.13 × 10^3 = 2130 > 2,100
So, x = 2
Answer : A
Question: k = 2^n + 8, where n is an integer greater than 1. If k is divisible by 9, which of the following MUST be divisible by 9?
A.2^n - 8
B.2^n - 2
C.2^n
D.2^n + 4
Answer: D.2^n + 4
Explanation: Given: k, M and N are integers
If k is a divisor of both N and M, then k is a divisor of N+M (and N–M and M–N)
We're told that 9 is a divisor of 2^n + 8
We also know that 9 is a divisor of9.
So, applying the above rule, 9 is a divisor of 2^n + 8 +9, and 9 is a divisor of 2^n + 8 -9=2^n -1
D
Question: How many positive integers less than 30 have no common prime factor with 30?
A.5
B.6
C.7
D.8
Answer: D.8
Explanation: 30=2*3*5. So, the number must be less than 30 and not have primes 2, 3, or 5.
This means that the number could be: 1, 7, 11, 13, 17, 19, 23, or 29. Total of 8 numbers.
Answer: D.
Question: Derek throws three dice in a special game. If he knows that he needs 15 or higher in this throw to win, then find the chance of his winning the game.
A.5/54
B.13/115
C.20/145
D.6/54
Answer: A.5/54
Explanation: Total cases = 6*6*6
= 216
n(X)/n(S)
=20/216 = > 5/54
ANSWER A
Question: A person travelled from his house to office at 30km/hr and office to house at 70km/hr. Then find the average speed?
A.30km/hr
B.40km/hr
C.42km/hr
D.50km/hr
Answer: C.42km/hr
Explanation: Average speed = (2*30*70)/(30+70)= 42km/hrAnswer is C
Question: What fraction is equivalent to 0.8% ?
A.1/125
B.1/129
C.1/121
D.1/122
Answer: A.1/125
Explanation: Explanation:
0.8% = 0.8/100 = 8/1000 = 4/500 = 2/250 = 1/125
ANSWER: A
Question: A basketball is dropped from a height of 30 feet. If it bounces back up to a height that is exactly half of its previous height, and it stops bouncing after hitting the ground for the fourth time, then how many total feet will the ball have traveled after 3 full bounces.
A.50
B.82.5
C.60
D.75
Answer: B.82.5
Explanation: Initial distance = 30 feet
first bounce = 15 feet up + 15 feet down = 30 feet
second bouche = 7.5 feet up + 7.5 feet down = 15 feet
third bounce = 375 feet up and 3.75 feet down= 7.5 feet
total distance covered = 30+30+15+7.5 = 82.5
ANSWER IS B
Question: The product of three consecutive numbers is 990. Then the sum of the smallest two numbers is ?
A.11
B.15
C.19
D.38
Answer: C.19
Explanation: Product of three numbers = 990
990 = 9*10*11.
So, the three numbers are 9, 10 and 11.
And Sum of smallest of these two = 9+10 = 19.
ANSWER : OPTION C
Question: Set Q consists of the following five numbers: Q = {5, 8, 13, 21, 34}. Which of the following sets has the same standard deviation as Set Q?
I. {35, 38, 43, 51, 64},
II. {10, 16, 26, 42, 68},
III. {46, 59, 67, 72, 75}
A.I only
B.I & II
C.I & III
D.II & III
Answer: C.I & III
Explanation: Original set: Q = {5, 8, 13, 21, 34}.
Notice that Set I is just every number in Q plus 30. When you add the same number to every number in a set, you simply shift it up without changing the spacing, so this doesn’t change the standard deviation at all. Set I has the same standard deviation as Q.
Notice that Set II is just every number in Q multiplied by 2. Multiplying by a number does change the spacing, so this does change the standard deviation. Set II does not have the same standard deviation as Q.
This one is very tricky, and probably is at the outer limit of what the GMAT could ever expect you to see. The spacing between the numbers in Set III, from right to left, is the same as the spacing between the numbers in Q from left to right. Another way to say that is: every number in Set III is a number in Q subtracted from 80. Again, would be very hard to “notice”, but once you see that, of course adding and subtraction the same number doesn’t change the standard deviation. Set III has the same standard deviation.
The correct combination is I and III, so the answer is C.
Question: A train speeds past a pole in 10 seconds and a platform 100 m long in 30 seconds. Its length is?
A.188 m
B.876 m
C.251 m
D.50 m
Answer: D.50 m
Explanation: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 10 => y = x/10
x + 100 / 30 = x / 10
x = 50 m.
Answer: D
Question: The least number of complete years in which a sum of money put out at 20% C.I. will be more than doubled is?
A.6
B.4
C.5
D.3
Answer: B.4
Explanation: P(1 + 20/100)n > 2P or (6/5)n > 2
Now, (6/5 * 6/5 * 6/5 * 6/5) > 2. So, n = 4 years.
Answer: B
Question: In how many ways a committee consisting of 4 men and 2 women can be formed from 7 men and 3 women?
A.A)105
B.B)15
C.C)20
D.D)18
Answer: A.A)105
Explanation: Required number of ways = 7C4*3C2 = 35*3 = 105
Answer is A
Question: There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
A.20
B.80
C.100
D.200
Answer: C.100
Explanation: Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Answer: Option C
Question: In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 500 newborn members of the population, approximately how many would be expected to survive the first 3 months of life?
A.340
B.346
C.352
D.365
Answer: D.365
Explanation: Number of newborns that can die in first month = 1/10 * 500 = 50
Survived = 450
Number of newborns that can die in second month = 1/10 * 450 = 45
Survived = 405
Number of newborns that can die in third month = 1/10 * 405 = 40
Survived = 365
Answer:D
Question: 90, 180, 12, 50, 100, 200, ?, 3, 50, 4, 25, 2, 6, 30, 3
A.100
B.150
C.180
D.200
Answer: B.150
Explanation: 30*3=90
6*30=180
6*2=12
25*2=50
4*25=100
50*4=200
3*50=150 ans is 150
ANSWER:B
Question: In the graduating class of a certain college, 48 percent of the students are male and 52 percent are female. In this class 40 percent of the male and 40 percent of the female students are 25 years old or older. If one student in the class is randomly selected, approximately what is the probability that he or she will be less than 25 years old?
A.A)0.9
B.B)0.6
C.C)0.45
D.D)0.3
Answer: B.B)0.6
Explanation: Percent of students who are 25 years old or older is 0.4*48+0.4*52=40, so percent of people who are less than 25 years old is 100-40=60.
Answer: B.
Question: If a number p is prime, and 2p+5= q, where q is also prime, then the decimal expansion of 1/q will produce a decimal with q-1 digits. If this method produces a decimal with 166 digits, what is the units digit of the product of p and q?
A.1
B.2
C.5
D.7
Answer: B.2
Explanation: 2/9 = 0.2222222222222.. (a repeating pattern one digit long)
B
Question: A worker can load one truck in 6 hours. A second worker can load the same truck in 5 hours. If both workers load one truck simultaneously while maintaining their constant rates, approximately how long, in hours, will it take them to fill one truck?
A.2.7
B.2.9
C.3.1
D.3.3
Answer: A.2.7
Explanation: The workers fill the truck at a rate of 1/6 + 1/5 = 11/30 of the truck per hour.
Then the time to fill one truck is 30/11 which is about 2.7 hours.
The answer is A.
Question: Which of the following equivalent to (1/27)^2?
A.(0.10)^3
B.(0.11)^3
C.(0.12)^3
D.(0.13)^3
Answer: B.(0.11)^3
Explanation: (1/27)^2 = (1/3^3)^2 = (1/3)^6 = (1/9)^3 = (0.11)^3
Answer: Option B
Question: In a LAB experiment, a 100 ml compound of element X and element Y needs to be increased to 210 ml by adding some quantity of element X, and some quantity of element Y. If the original compound contains 30% of element X, how much (in ml) of element Y must be added so that element X will be exactly one third of the resulting mixture ?
A.40 ml
B.70 ml
C.20 ml
D.20/3 ml
Answer: B.70 ml
Explanation: There are 0.3*100=30 ml of element X in the initial solution.
We need X to be 1/3rd of 210 ml in the resulting solution, so 70 ml. Thus out of 110 ml of solution added, 40 must be X (in order it to become 70 ml) ans the remaining 70 must be Y.
Answer: B
Question: An investment of $2000 was made in a certain account and earned interest that was compounded annually. The annual interest rate was fixed for the duration of the investment, and after 12 years the $1000 increased to $8000 by earning interest. In how many years after the initial investment was made the $1000 have increased to $16000 by earning interest at that rate?
A.18
B.12
C.20
D.24
Answer: A.18
Explanation: In 12 years the investment quadrupled (from $2,000 to $8,000).
Thus, at the same rate compounded annually, it would need additional 12/2=6 years to double (from $8,000 to $16,000).
Therefore, 12+6=18 years are needed $2,000 to increase to $16,000.
Answer: A.
Question: There are some pigeons and hares in a zoo. If heads are counted, there are 200. If legs are counted, there are 580. The number of hares in the zoo is?
A.100
B.120
C.90
D.95
Answer: C.90
Explanation: 200*2 = 400
580=>180
1----2
?----180 = 90
ANSWER C
Question: A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are drawn what is the probability that one is yellow and two are red?
A.12/429
B.12/429
C.12/455
D.12/927
Answer: C.12/455
Explanation: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
When three marbles are drawn, the probability that one is yellow and two are red
= (²C₁)(⁴C₂)/¹⁵C₃
= (2 * 4 * 3 * 3 * 2)/(1 * 2 * 15 * 14 * 13)
=12/455
Answer: C
Question: A, B and C enter into a partnership and their shares are in the ratio 1/2 : 1/3 : 1/4. After 2 months, A withdraws half of his capital and after 10 months, a profit of Rs. 378 is divided among them. What is B's share ?
A.130
B.145
C.140
D.144
Answer: D.144
Explanation: Explanation :
Ratio of initial investments = 1/2 : 1/3 : 1/4 = 6 : 4 : 3.
Let their initial investments be 6x, 2x and 3x respectively.
A : B : C = (6x * 2 + 3x * 10) : (4x * 12) : (3x * 12) = 42 : 48 : 36 = 7 : 8 : 6.
B's share = Rs. (378 * 8/21) = Rs. 144.
Answer : D
Question: What is the greatest prime factor of 10!9! + 9!8! ?
A.7
B.11
C.13
D.17
Answer: C.13
Explanation: 10!9! + 9!8! = 9!8!(10*9+1) = 9!*8!*91 = 9!*8!*7*13
The answer is C.
Question: A test has 150 questions. Each question has 5 options, but only 1 option is correct. If test-takers mark the correct option, they are awarded 1 point. However, if an answer is incorrectly marked, the test-taker loses 0.25 points. No points are awarded or deducted if a question is not attempted. A certain group of test-takers attempted different numbers of questions, but each test-taker still received the same net score of 40. What is the maximum possible number of such test-takers?
A.19
B.21
C.23
D.25
Answer: C.23
Explanation: A correct answers get you 1 point, an incorrect answer gets you MINUS 1/4 point and a skipped question gets you 0 points. Since there are 200 total questions, there are a variety of ways to get a total of 40 points.
Let C be the number of correct answers and let I be the number of incorrect answers.
To get 40 points, a test taker must have at least 40 correct answers. Then C=> 40.
For every correct question above 40, the test taker has 4 incorrect answers.
Then, the I = 4*(C - 40).
Also, I + C <= 150. Thus 5C <= 310 and so C <= 62.
Then 40 <= C <= 62 and C can have 23 possible values.
The answer is C.
Question: A man buys Rs. 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:
A.33
B.15
C.66
D.77
Answer: B.15
Explanation: Dividend on Rs. 20 = Rs. 9	x 20 = Rs.	9	.
100	5
Rs. 12 is an income on Rs. 100.
Rs.	9	is an income on Rs. 100	x	9 = Rs. 15.
Answer:B
Question: the present worth of a sum due sometimes hence is Rs. 5760 and the banker's gain is Rs.10 . what is the true discount?
A.480
B.420
C.240
D.120
Answer: C.240
Explanation: TD= square root of PW * BG = square root of 5760 * 10 = square root of 57600= Rs. 240
correct answer : (C)
Question: Calculate 1307 x 1307 =?
A.1601249
B.1607249
C.1701249
D.1708249
Answer: D.1708249
Explanation: Answer
1307 x 1307 = (1307)2
= (1300 + 7 )2
= (1300)2 + (7)2 + 2 x 1300 x 7
= 1690000 + 49 +18200
= 1708249
Option: D
Question: A train 960 m long passed a pole in 96 sec. How long will it take to pass a platform 2600 m long?
A.350
B.352
C.354
D.356
Answer: D.356
Explanation: Speed = 960/96 = 10 m/sec.
Required time = (960 + 2600)/10
= 356 sec.
Answer:D
Question: A trained covered x km at 40 kmph and another 4x km at 20 kmph. Find the average speed of the train in covering the entire 3x km.
A.11.33 kmph
B.12.33 kmph
C.13.33 kmph
D.14.33 kmph
Answer: C.13.33 kmph
Explanation: Total time taken = x/40 + 4x/20 hours
= 9x/40 hours
Average speed = 3x/(9x/40) = 13.33 kmph
ANSWER:C
Question: In how many ways the letters of the word REDUCTION be arranged?
A.344500
B.325479
C.226478
D.362880
Answer: D.362880
Explanation: Total ways of arranging the letters = 9! = 362880 ways.
D)
Question: An engineer undertakes a project to build a road 10 km long in 30 days and employs 30 men for the purpose. After 10 days, he finds only 2 km of the road has been completed. Find the (approximate) number of extra men he must employ to finish the work in time.
A.30
B.40
C.50
D.60
Answer: A.30
Explanation: 30 workers working already
Let x be the total men required to finish the task in next 20 days
2 km done hence remaining is 8 km
Also, work has to be completed in next 20 days (30 - 10 = 20)
We know that, proportion of men to distance is direct proportion
and, proportion of men to days is inverse proportion
Hence, X = (30 * 8 * 10) / (2 *20)
thus, X = 60
Thus, more men needed to finish the task = 60-30=30
Answer : A
Question: 7528:5306::4673:?
A.2351
B.2451
C.2551
D.2651
Answer: B.2451
Explanation: As there is a difference of 2222. 7528-2222 = 5306. so 4673-2222 = 2451
ANSWER:B
Question: There are two positive numbers in the ratio 5:8. If the larger number exceeds the smaller by 15, then find the smaller number?
A.25
B.81
C.86
D.16
Answer: A.25
Explanation: Let the two positive numbers be 5x and 8x respectively.
8x - 5x = 15
3x = 15 => x = 5
=> Smaller number = 5x = 25.
Answer: A
Question: A can do a piece of work in 4 days. B can do it in 6 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?
A.22 days
B.12 days
C.67 days
D.17 days
Answer: B.12 days
Explanation: C = 1/2 - 1/6 - 1/4 = 1/12
=> 12 days
Answer:B
Question: There are certain number of hats and gloves in a box.They are of 41 red,23 green,11 orange.Power gone but a woman can differentiate between hats and gloves.How many draws are required to obtain a pair of each color?
A.66
B.67
C.68
D.69
Answer: A.66
Explanation: the worst case senario will be
first take 40 red
then take 22 green
then take 1+1 red+green
then take 2 orange.
so total 40+22+2+2=66
ANSWER:A
Question: A car started running at a speed of 30 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey.
A.227
B.390
C.287
D.2771
Answer: B.390
Explanation: The total distance covered by the car in the first 10 hours = 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44 + 46 + 48 = sum of 10 terms in AP whose first term is 30 and last term is 48 = 10/2 [30 + 48] = 390 km.
Answer: B
Question: A bag contains a certain number of 50 paise coins, 20 paise coins and 10 paise coins inthe ratio 3:4:5. If the total value of all the coins in the bag is Rs.280, find the number of 50 paise coins ?
A.498
B.488
C.300
D.528
Answer: C.300
Explanation: 50*3k + 20*4k + 10*5k = 28000
280k = 28000 => k = 100
50p coins = 3k = 3*100 = 300
ANSWER:C