RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: There are two numbers. If 50% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?
A.A)3/7
B.B)5/8
C.C)6
D.D)1/2
Answer: D.D)1/2
Explanation: Let the two numbers be x and y.
50/100 * x + y = 5/4y
=> 1/2 x = 1/4 y => x/y = 1/2
D)
Question: A boat ma goes 2km against the current of the stream in 1 hr and goes 1 km along the current in 10 min. how long will it take to go 12 km in stationary water
A.40 min
B.3hr
C.1hr 15 min
D.1hr 30 min
Answer: B.3hr
Explanation: rate down stream=(1/10*60)km/hr=6km/hr
rate up stream=2km/hr
speed still water =1/2(6+2)=4km/hr
required time =(12/4)=3 Hr
Answer(B)
Question: A certain fraction is equivalent to 2/5. If the numerator of the fraction is increased by 4 and the denominator is doubled, the new fraction is equivalent to 1/4. What is the sum of the numerator and denominator of the original fraction?
A. 49
B. 35
C. 56
D. 26
Answer: C. 56
Explanation: x/y = 2/5 -> 1
(x+4)/2y = 1/4 -> 2
Divide 1 by 2 :
=> 2x/(x+4) = 8/5
=> 5x = 4x + 16
=> x = 16
=> y = 5/2 *16 = 40
so x + y = 56
The answer is C
Question: A certain number when divided by 95 leaves a remainder 25, what is the remainder if the same no.be divided by 15?
A.4
B.5
C.6
D.8
Answer: D.8
Explanation: Explanation:
95 + 25 = 120/15 = 8 (Remainder)
D
Question: There are 200 questions on a 3 hrexamination.Among these questions are 50 mathematics problems.It is suggestedthat twice as much time be spent on each maths problem as for each otherquestion.How many minutes should be spent on mathematics problems
A.71min
B.72min
C.73min
D.74min
Answer: B.72min
Explanation: taking the time in min so convert time into min=60*3=180
x= time spent on maths question
2x=time spent on maths question
x(200-50)+2x(50)=180
150x+100x=180
250x=180
x=0.72
now time spent on maths questions=2*0.72*50=72min
ANSWER:B
Question: The workforce of Company X is 50% female. The company hired 20 additional male workers, and as a result, the percent of female workers dropped to 50%.How many employees did the company have after hiring the additional male workers?
A.225
B.220
C.230
D.235
Answer: B.220
Explanation: let x be the total worker then 0.5x =female worker and 0.5x is male worker then 20 male worker added
05x/(0.5x +20) = 50/100 or 50x = 50*( 0.5x+100) = 25x+ 5000 or 25x = 5000 , x = 5000/25=200
total worker = 200 +20= 220
B
Question: If $20,000 interest is invested in x percent simple annual interest for n years, which of the following represents the total amount of interest, in dollars, that will be earned by this investment in the n years?
A.10,000(x^n)
B.20,000n(x/100)
C.20,000(x/100)^n
D.10,000(1 + x/100)^n
Answer: B.20,000n(x/100)
Explanation: Principal * no.of years * percentage of interest
Answer : B
Question: The first three terms of a proportion are 3, 9 and 12. The fourth term is?
A.22
B.98
C.99
D.36
Answer: D.36
Explanation: (9*12)/3 = 36
Answer: D
Question: Average of 6 numbers is zero. At most how many numbers may be greater than zero
A.0
B.1
C.5
D.9
Answer: C.5
Explanation: Answer: Option C
Question: 20-3*4^2+53 = ?
A.25
B.-13
C.-73
D.13
Answer: A.25
Explanation: 20-3*4^2+53= 20-3*16+53=20-48+53=25..
A
Question: In 10 years,A will be six times as old as B was 10 years ago.If A is now 9 years older than B,the present age of B is :
A.15.8 Years
B.29 Years
C.39 Years
D.49 Years
Answer: A.15.8 Years
Explanation: Solution
Let B's present age = x years.Then,A's present age =(x +9) years.
âˆ´ (x + 9)+ 10 = 6 (x - 10) â‡” x + 19 = 6x- 60 â‡”5 x = 79
x=15.8 .Answer A
Question: The number of sequences in which 7 players can throw a ball, so that the youngest player may not be the last is?
A.4729
B.4329
C.4320
D.4372
Answer: C.4320
Explanation: x Not younger
The last ball can be thrown by any of the remaining 6 players. The first 6 players can throw the ball in ⁶P₆ ways.
The required number of ways = 6(6!) = 4320
Answer:C
Question: Two numbers N and 16 have LCM = 48 and GCF = 18. Find N.
A.24
B.34
C.44
D.54
Answer: D.54
Explanation: The product of two integers is equal to the product of their LCM and GCF. Hence.
16 × N = 48 × 18
N = 48 × 18 / 16 = 54
correct answer D
Question: Solve the following quadratic equation by factoring.
x^2+15x=-50
A.(5,10)
B.(2,4)
C.(-5,-10)
D.(9,0)
Answer: C.(-5,-10)
Explanation: Now all we need to do is use the zero factor property to get,
x+5=0
x=-5
x+10=0
x=-10
(-5,-10)
Ans: C
Question: A car was driving at 72 Km/h for 20 minutes, and then at 81 Km/h for another 40 minutes. What was its average speed?
A.76.
B.77.
C.78.
D.79.
Answer: A.76.
Explanation: driving at 72 Km/h for 20 minutes ,distance covered = 72*1/3=24 km
driving at 90 km/h for 40 minutes ,distance covered = 81*2/3=54 km
average speed = total distance/total time = 78/1 = 78 km/h
Answer: A
Question: I am three times as old as my son. Five year later, I shall be two and half times as old as my son. How old am I and how old is my son ?
A.45 year and 15 year
B.40 year and 10 year
C.42 year and 12 year
D.41 year and 11 year
Answer: A.45 year and 15 year
Explanation: Let my age is x years and my son’s age is y years, Then,
x = 3y
Five years later, my age will be (x + 5) years and my son’s age will be
(y + 5) years
Thus, (x + 5) = 5/2 (y + 5)
=> 2x - 5 y - 15 =0
putting x = 3y, we get
6y - 5y - 15 = 0
=> y = 15
Thus, x = 45
Hence, my present age is 45 years and my son’s present age is 15 years.
ANSWER:A
Question: Marie has 248 $ in her account of the bank. She has to buy presents for her 7 children and wants to distribute the money fairly. How much he will once have the money shared fairly?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: (248$ / 7children) = 35.42
Took the lowest number = 35 * 7 children = $245
$248 - $245 = staying $3
Correct option: C) 3$
Question: The winning relay team in a high school sports competition clocked 48 minutes for a distance of 13.2 km. Its runners A, B, C and D maintained speeds of 15 kmph, 16 kmph, 17 kmph, and 18 kmph respectively. What is the ratio of the time taken by B to than taken by D?
A.5:16
B.5:17
C.9:8
D.8:9
Answer: C.9:8
Explanation: Explanation :
Since it is a relay race, all the runners ran the same distance.
Hence for a same distance, (ratio of times) = 1/(ratio of speeds).
Hence ratio of times taken by B t& D = 18 : 16 = 9 : 8.
Answer : C
Question: Three cubes of metal whose edges are 9, 12 and 15 cm respectively, are melted and one new cube is made. Find the edge of the new cube?
A.88
B.77
C.88
D.18
Answer: D.18
Explanation: Explanation:
93 + 123 + 153 = a3 => a = 18
Answer: Option D
Question: 25% students of a class failed in Chemistry and 40% failed in Physics where 10% did not pass in any of the two subjects. If 30 students passed in only Physics, how many of them passed in both the subjects.
A.60
B.70
C.80
D.90
Answer: D.90
Explanation: n(C)=75% , n(P)=60% , n(PUC)= 90% => n(PnC)= 75% + 60% - 90% = 45%. given n(P) - n(PnC)= 30 , 60% - 45% = 30 => 15% = 30 => 1% = 2 . n(PnC) = 45% = 90
ANSWER:D
Question: Goldenrod and No Hope are in a horse race with 4 contestants. How many different arrangements of finishes are there if No Hope always finishes before Goldenrod and if all of the horses finish the race?
A.720
B.360
C.12
D.24
Answer: C.12
Explanation: All 4 horses can finish the race in 4! way (assuming no tie).
If no tie is possible between No Hope and Goldenrod, then in half of these cases No Hope will be before Goldenrod and in half of these cases after (not necessarily right before or right after). How else? So, there are 4!/2=12 different arrangements of finishes where No Hope always finishes before Goldenrod.
Answer: C.
Question: A class of 10 students is having an average age of 15, another group of 4 students whose average age is 12 has been added to them. What is the average of the new group formed?
A.12
B.13.4
C.14.14
D.15
Answer: C.14.14
Explanation: sum of ages of the new group formed= (15x10) + (4x12) = 198
Total number of people in the new group= 10+4= 14
Average of the new group=198/14 = 14.14
Answer: C
Question: There are 2 sections A and B in a class, consisting of 40 and 20 students respectively. If the average weight of section A is 50kg and that of section B is 40kg, Find the average of the whole class?
A.50.78kg
B.49.32kg
C.46.66kg
D.69.15kg
Answer: C.46.66kg
Explanation: Total weight of 40+20 students = 40*50 + 20*40 = 2000+800
Average weight of the class is = 2800/60 = 46.66 kg
Answer is C
Question: A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water ?
A.40 minutes
B.1 hour
C.1 hr 15 min
D.1 hr 30 min
Answer: C.1 hr 15 min
Explanation: Solution
Rate downstream =(1/60x60) km/hr = 6 km/hr, Rate upstream = 2 km/hr.
Speed in still water =1/2(6+2) km/hr = 4 km/hr.
∴ Required time = (5/4)hrs = 1 1/4hrs = 1 hr 15 min. Answer C
Question: In a game of 100 points there are three participants A, B, and C. A gives to B 10 points and to C 19 points, then how many points can B give to C
A.9 points
B.10 points
C.11 points
D.12 points
Answer: B.10 points
Explanation: A:B=100:90 (A can give 10 points to B means A is 10 points leads to B and from the problem A=100)
A:C=100:81
for B:C
B:C = (A:C)*(B:A)
= (100/81)*(90/100)
=10/9
= 10:9
multiply and devide by 100
B:C = 100:90
B can give 10 points to C
ANSWER:B
Question: How many seconds will a 400 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
A.24
B.30
C.40
D.45
Answer: A.24
Explanation: Relative speed of the train=63-3=60kmph=60*5/18=50/3 m/sec
t=400*3/50=24sec
ANSWER:A
Question: Of three numbers, the third is twice the second and the second is 4 times the first. If their average is 78, the greatest of the three numbers is:
A.180
B.144
C.200
D.212
Answer: B.144
Explanation: Explanation:
Let first number be x.
So,2nd no. = 4x & 3rd no.=8x.
So,x+4x+8x=78 × 3 = 234.
13x = 234
x = 234/13
Hence,smallest Number x=18.
The greatest of three number is 8 x 18=144
Answer:B
Question: Three numbers are in the ratio 1:3:5 and their H.C.F is 5. The numbers are?
A.5, 15, 35
B.5, 15, 30
C.5, 15, 25
D.5, 15, 40
Answer: C.5, 15, 25
Explanation: Let the required numbers be x, 3x and 5x. Then, their H.C.F = x. So, x = 5.
The numbers are 5, 15, 25.
Answer: C
Question: In a 300 m race A beats B by 22.5 m or 6 seconds. B's time over the course is:
A.86 sec
B.80 sec
C.76 sec
D.96 sec
Answer: B.80 sec
Explanation: runs 45/2m in 6 sec.
B covers 300 m in 6 x	2/45 x 300sec	= 80 sec.
ANSWER:B
Question: When two dice are rolled, what is the probability that the sum of the two numbers is 6?
A. 1/9
B. 5/36
C. 1/3
D. 2/36
Answer: B. 5/36
Explanation: We have 5 outcomes that satisfy the question:
1-5
2-4
3-3
4-2
5-1
the probability is (1/6*1/6)*5= 5/36.
I think the answer is B
Question: Convert the 15/36 m/s into kilometers per hour?
A.1.7
B.1.5
C.1.3
D.1.1
Answer: B.1.5
Explanation: 15/36 m/s = 15/36 * 18/5 = 3/2
= 1.5 kmph.
Answer: B
Question: When a number is divided by 6 &then multiply by 12 the answer is 11 what is the no.?
A.4.5
B.5
C.5.5
D.5.8
Answer: C.5.5
Explanation: if $x$ is the number, x/6 * 12 = 11
=> 2x = 11
=> x = 5.5
C
Question: A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long?
A. 65
A.28 sec
B.89 sec
C.85 sec
D.16 sec
Answer: B.89 sec
Explanation: Speed = 240/24 = 10 m/sec.
Required time = (240 + 650)/10
= 89 sec.
Answer:B
Question: Susan, John, Tim,and Kim need to be seated in 4 identical chairs in straight line so that Susan is seated always left to Tim. How many such arrangements are possible ?
A.A)12
B.B)120
C.C)80
D.D)240
Answer: A.A)12
Explanation: Total number of arrangements = 4! = 24
In exactly half, Susan will be to the left of Tim, which gives us 12 arrangements
Option (A)
Question: Find the least number must be added to 228712 so that remaining no.is divisible by 9?
A.5
B.3
C.1
D.6
Answer: A.5
Explanation: On dividing 228712 by 9 we get the remainder 4, so 5 should be subtracted
A
Question: If n = 2.0563 and n* is the decimal obtained by rounding n to the nearest hundredth, what is the value of n* – n?
A. -0.0053
B. -0.0003
C. 0.0007
D. 0.0037
Answer: D. 0.0037
Explanation: n*=2.06
n*-n=2.06-2.0563
0.0037
Answer: D
Question: A certain music store stocks 800 cellos and 600 violas. Of these instruments, there are 80 cello-viola pairs, such that a cello and a viola were both made with wood from the same tree (each tree can make at most one viola and one cello, so there are no pairs other than these 90). If one viola and one cello are chosen at random, what is the probability that the two instruments are made with wood from the same tree?
A.3/16,000
B.1/8,100
C.1/600
D.1/90
Answer: C.1/600
Explanation: Solution provided by stanford2012 is correct: 80/800 choosing one of the cellos which has a pair viola, 1/600 choosing the viola which is the pair of chosen cello --> P=80/800*1/600=1/6,000.
Answer: C.
Question: Caitlin bought three puppies for Rs. 200, Rs. 350 and Rs.450 and she sold that to George for Rs. 250, Rs. 300 and Rs.600.
What is the percentage of profit Caitlin got?
A.10
B.12
C.18
D.15
Answer: D.15
Explanation: Cost of buying=200+350+450=Rs.1000
Cost of selling=250+300+600=Rs. 1150
profit=1150-1000=Rs.150
profit%= (150/1000)x100=15%
Answer:D
Question: Ritesh and Co. generated revenue of Rs. 1,800 in 2006. This was 12.5% of its gross revenue. In 2007, the gross revenue grew by Rs. 2,500. What is the percentage increase in the revenue in 2007?
A.17.36%
B.20%
C.25%
D.50%
Answer: A.17.36%
Explanation: Explanation :
Given, Ritesh and Co. generated revenue of Rs. 1,800 in 2006 and that this was 12.5% of the gross revenue.
Hence, if 1800 is 12.5% of the revenue, then 100% (gross revenue) is:
=>(100/12.5)×1800.
=>14,400.
Hence, the total revenue by end of 2007 is Rs. 14,400. In 2006, revenue grew by Rs. 2500. This is a growth of:
=>(2500/14400)×100.
=>17.36%.
Answer : A
Question: If 5a + 7b = g, where a and b are positive integers, what is the largest possible value of g for which exactly one pair of integers (a, b) makes the equation true?
A.35
B.48
C.69
D.70
Answer: D.70
Explanation: 5*a1 + 7*b1 = g
5*a2 + 7*b2 = g
5*(a1 - a2) = 7*(b2 - b1)
since we are dealing with integers we can assume that a1 - a2 = 7*q and b2 - b1 = 5*q where q is integer, so whenever we get a pair for (a;b) we can find another one by simply adding 7 to a and subtracting 5 from b or vice versa, subtracting 7 from a and adding 5 to b.
Lets check how it works for our numbers, starting from the largest:
E)74 = 5*12 + 7*2 (a1 = 12, b1 = 2), subtract 7 from a and add 5 to b respectively, so a2 = 5 and b2 = 7, second pair - bad
D)70 = 5*7 + 7*5 (a1 = 7, b1 = 5), if we add 7 to a we will have to subtract 5 from b but b can't be 0, so - no pair, if we subtract 7 from a, we'll get a = 0 which also isn't allowed - no pair, thus this is the only pair for (a;b) that works,good!, thus
D is the answer
Question: Ram professes to sell his goods at the cost price but he made use of 900 grms instead of a kg, what is the gain percent?
A.11 1/8%
B.11 1/3%
C.11 1/9%
D.11 1/6%
Answer: C.11 1/9%
Explanation: 900 --- 100
100 --- ? => 11 1/9%
Answer: C
Question: There is a school were 60% are girls and 35% of the girls are poor. Students are selected at random, what is the probability of selecting a poor girl out of total strength?
A.21/100
B.22/100
C.23/100
D.24/100
Answer: A.21/100
Explanation: Let take 100 students
outoff 100 60 are girls
among girls poor girls are =35% 0f 60=21
pbt of selecting poor girl in total strength=21/100
ANSWER:A
Question: A boy has six trousers and 8 shirts. In how many different ways can he select a trouser and a shirt?
A.99
B.38
C.28
D.48
Answer: D.48
Explanation: The boy can select one trouser in six ways.
The boy can select one shirt in 8 ways.
The number of ways in which he can select one trouser and one shirt is 6 * 8
= 48 ways.
Answer: D
Question: We bought a total of 90 books at the store. Math books cost $4 and history books cost $5. The total price was $397. How many math books did we buy?
A.47
B.53
C.56
D.61
Answer: B.53
Explanation: Let M be the number of math books and let H be the number of history books.
M+H=90.
H=90-M.
4M+5H=397.
4M+5(90-M)=397.
-M+450=397.
M=450-397=53.
The answer is B.
Question: How many 5 digit even numbers with distinct digits can be formed using the digits 1, 2, 5, 5, 4 ?
A.16
B.36
C.24
D.48
Answer: C.24
Explanation: The 5 digit even numbers can be formed out of 1, 2, 5, 5, 4 by using either 2 or 4 in the unit’s place. This can be done in 2 ways.
Corresponding to each such arrangement, the remaining 4 places can be filled up by any of the remaining four digits in 4! / 2! = 12 ways. Hence, the total number of words = 2 x 12 = 24.
ANSWER:C
Question: Two pens and three pencils cost Rs 86. four Pens and a pencil cost Rs. 112. find the cost of a pen.
A.23
B.34
C.25
D.26
Answer: C.25
Explanation: 1 pen cost x,let 1 pencil cost y
2x+3y=86, ...y=(86-2x)/3
again,
4x+y=112
4x+(86-2x)/3=112
12x+86-2x=336
10x=250
x=25
ANSWER:C
Question: If in a box of dimensions 6 m * 5 m * 4 m smaller boxes of dimensions 60 cm * 50 cm * 40 cm are kept in it, then what will be the maximum number of the small boxes that can be kept in it?
A.1098
B.1000
C.1628
D.1098
Answer: B.1000
Explanation: 6 * 5 * 4 = 60/100 * 50/100 * 40/100 * x
1 = 1/10 * 1/10 * 1/10 * x
=> x = 1000
Answer: B
Question: At a local beach, the ratio of little dogs to average dogs to enormous dogs is 2:4:8. Late in the afternoon, the ratio of little dogs to average dogs doubles and the ratio of little dogs to enormous dogs increases. If the new percentage of little dogs and the new percentage of average dogs are both integers and there are fewer than 30 total dogs at the beach, which of the following represents a possible new percentage of enormous dogs?
A.25%
B.10% or 60%
C.50%
D.55%
Answer: B.10% or 60%
Explanation: Little Dogs(L), Average Dogs(A) and Enormous Dogs (E)
The initial ratio for L:A:E :: 2:4:8
Initial Total dogs = 14X ( x assumed; 2+4+8= 14), Since the total dogs are less than 30 therefore initial total value has to be 14
L = 2, A = 4 E = 8
L:A= 2:5
This ratio doubles
Hence New Dog count is
L= 4 , A = 4 E= X: Also 4+4+x<30
We need to Find X*100/(4+4+X)
Now it says that new percentage of little dogs and Average dogs is an integer
%L = 4*100/(8+x) %A = 4*100/(8+x); Only Value for X is 2 or 12 ; 9+x<30 and % integer
Therefore, Enormus Dogs % is = 12*100/(20) or 2*100/20 = 60% or 10%
B
Question: A can finish a work in 18 days and B can do the same work in half the time taken by A. Then, working together, what part of the same work they can finish in a day?
A.1/9
B.1/6
C.1/2
D.1/1
Answer: B.1/6
Explanation: Given that B alone can complete the same work in days = half the time taken by A
= 9days
A’s one day work = 1/18
B’s one day work = 1/9
(A+B)’s one day work = 1/18+1/9 = 1/6
Answer : B.
Question: What is the number of integers from 1 to 1000 (inclusive) that are divisible by neither 20 nor by 35?
A.567
B.850
C.560
D.923
Answer: D.923
Explanation: In 1000 consecutive numbers, number of multiples of 20 = 1000/20 = 50 (Ignore decimals)
In 1000 consecutive numbers, number of multiples of 35 = 1000/35 = 28
Number of multiples of 20*35 i.e. 700 = 1000/700 = 1
Number of integers from 1 to 1000 that are divisible by neither 20 nor by 35 = 1000 - (50 + 28 - 1) {Using the concept of sets here) = 923
Answer is D
Question: 5 kg of adulterated rice has 2% stones in it and the rest is rice. Half of the stone
content was removed. Now the percentage of stone content in it is
A.0.99%
B.1%
C.1.1%
D.1.01%
Answer: D.1.01%
Explanation: 2% of 5=0.1
Half of the stone has been remove so stone becomes 0.1/2=0.05
Total wt. becomes 5-0.05=4.95
% of stone=0.05*100/4.95=1.01%
ANSWER:D
Question: In 2008, a certain factory produced 10% more widgets than it did in 2007, and its production in 2009 was 110% of its production in 2008. By approximately what percent would its production need to decrease the following year for the factory to produce the same number of widgets it did in 2007?
A.12%
B.17%
C.20%
D.24%
Answer: B.17%
Explanation: Let P be the original level of production in 2007.
Let x be the rate of production in 2010 compared to 2009.
x*1.1*1.1*P = P
x = 1/1.21 = 0.826 which is a decrease of about 17%.
The answer is B.
Question: In how many different ways can 3 girls and 3 boys form a circle such that the boys and the girls alternate?
A.15
B.12
C.17
D.20
Answer: B.12
Explanation: Explanation :
In a circle, 3 boys can be arranged in 2! ways
Given that the boys and the girls alternate.
Hence there are 3 places for girls which can be arranged in 3! ways
Total number of ways = 2! x 3! = 2 x 6= 12. Answer : Option B
Question: What is the median from the below series 90, 92, 94, 88, 95, 88, 97, 87, and 98
A.80
B.85
C.93
D.97
Answer: C.93
Explanation: Ordering the data from least to greatest, we get:
87, 88, 88, 90, 93, 94, 95, 96, 98
The median quiz score was 93. (Four quiz scores were higher than 93 and four were lower.)
C
Question: In what ratio must be a grocer mix two varities of tea worth Rs.60 a kg and Rs.65 a Kg so that by selling the mixture at Rs.68.20 a Kg he may gain 10%?
A.3 : 4
B.3 : 2
C.3 : 5
D.4 : 5
Answer: B.3 : 2
Explanation: Solution
S.P. of 1 kg of the mixture = Rs. 68.20, Gain = 10 %
C.P. of 1 kg of the mixture = Rs. (100 / 110 x 68.20) = Rs. 62.
Required ratio = 3 : 2.
Answer B
Question: What is the value of 5x^2 − 1.9x − 3.7 for x = − 0.3?
A.−4.72
B.−3.82
C.−3.58
D.−2.68
Answer: D.−2.68
Explanation: 5x^2 - 1.9x - 3.7, x =-0.3
Firstly, 5x^2 can be written as 5 * x * x - substituting one of the x with -0.3
We have -1.5x - 1.9x -3.7 ---> -3.4x-3.7 ---> -3.4 (-0.3) -3.7 ---> 1.02 - 3.7 = -2.68
ANSWER:D
Question: A man gains 20% by selling an arƟcle for a certain price. If he sells it at double the price, the
percentage of profit will be
A.130%
B.140%
C.150%
D.160%
Answer: B.140%
Explanation: Explanation:
Let the C.P. = x,
Then S.P. = (120/100)x = 6x/5
New S.P. = 2(6x/5) = 12x/5
Profit = 12x/5 - x = 7x/5
Profit% = (Profit/C.P.) * 100
=> (7x/5) * (1/x) * 100 = 140 %
Answer: B
Question: the length of the bridge is 200m,which a 100 m long train cross in 60sec. then what is the speed of train?
A.6
B.5
C.4
D.10
Answer: B.5
Explanation: speed = length/time
length=(200+100)=300m
time=60 sec
speed = 300/60=5m/sec
answer B
Question: 826924 × 9999 = ?
A.8248402936
B.8268413076
C.8268413071
D.8064329671
Answer: B.8268413076
Explanation: B
8268413076
826924 × 9999 = 826924 × (10000 - 1)
= 826924 × 10000 - 826924 × 1
= 8269240000 - 826924
= 8268413076
Question: In N is a positive integer less than 200, and 24N/60 is an integer, then N has how many different positive prime factors?
A.1
B.3
C.5
D.6
Answer: A.1
Explanation: (A).
24n/60 must be an integer. => 2n/5 must be an integer. Hence n must be a multiple of 5.
=> n has 1 different prime integers.
Question: Express a speed of 36 kmph in meters per second?
A.10 mps
B.18 mps
C.19 mps
D.17 mps
Answer: A.10 mps
Explanation: 36 * 5/18
= 10 mps
Answer:A
Question: If I walk at 3 km/h, I miss the bus by 12 minutes. If I walk at 6 km/h, I reach 10 minutes before the arrival of the bus. How far I walk to reach the bus stand ?
A.2.19 km
B.2.22 km
C.2.00 km
D.1.19 km
Answer: A.2.19 km
Explanation: d = product of speed difference of time /difference of speed
d = 3x6/60[12âˆ’(âˆ’10)/6-3]
[Here, â€“ve sign indicates before the schedule time]
â‡’ d = 2.19 km
Answer A
Question: A is a working partner and B is a sleeping partner in the business. A puts in Rs.5000 and B Rs.1000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?
A.1978
B.2707
C.7728
D.8160
Answer: D.8160
Explanation: 5000:1000 => 5:1
9600*10/100 = 960
9600 - 960 = 8640
8640*5/6 = 7200 + 960
= 8160
Answer: D
Question: A car moves at the speed of 80 km/hr. what is the speed of the car in metres per second?
A.2/8
B.2/9
C.2/6
D.2/4
Answer: B.2/9
Explanation: Answer: D
Explanation:Formula
For convert km/hr into m/sec multiply the speed with 5/18
For convert m/sec into km/hr multiply the speed with 18/5
80 × 5/18 ⇒ 2/2 × 2/9 m.sec.
Answer:B