RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Peter invests a sum of money and gets back an amount of $ 830 in 3 years . David invests an equal amount of money and gets an amount of $854 in 4 years. If both amounts were invested at the same rate (simple interest ) What was the sum of money invested ?
A.670
B.664
C.698
D.758
Answer: D.758
Explanation: Since both Peter and David invested the same amount of money at the same rate, they would earn same interest per year.
David invested for one year more than Peter and hence he got interest amount for one more year.
Interest earned per year = Amount received by David - Amount received by Peter = 854 - 830 = 24
Interest earned for 3 years = 24*3 = 72
Amount invested = 830 - 72 = 758
Answer: D
Question: What is the probability of getting sum 10 with the help of three dice?
A.1/2
B.1/4
C.1/6
D.1/8
Answer: D.1/8
Explanation: the following has 6 permutations.
(1, 3, 6),(1, 4, 5),(2, 3, 5)
Each of the following has 3 permutations.
(2, 2, 6),(2, 4, 4),(3, 3, 4)
the total possibility = 6*3 + 3*3 = 27
total no. of outcomes = 6*6*6 = 216
probability = 27/216 = 1/8 = 0.125
ANSWER:D
Question: 70% of the employees in a multinational corporation have VCD players, 75 percent have microwave ovens, 90 percent have ACs and 85 percent have washing machines. At least what percentage of employees has all four gadgets?
A.(a) 15%
B.(b) 5%
C.(c) 10%
D.(d) 20%
Answer: D.(d) 20%
Explanation: so 30% employees don't have VCD devices.
25% employees don't have MO
10% employees don't have ACs
15% employees don't have WM
Summ of employees that don't have some device = 30%+25%+10%+15% = 80% < 100%
So definitely at least 20% employees have 4 devices.
ans: D
Question: I. 9a2 + 18a + 5 = 0,
II. 2b2 + 13b + 20 = 0 to solve both the equations to find the values of a and b?
A.If a > b
B.If a ≥ b
C.If a < b
D.If a ≤ b
Answer: A.If a > b
Explanation: I. 9a2 + 3a + 15a + 5 = 0
=>(3a + 5)(3a + 1) = 0 => a = -5/3, -1/3
II. 2b2 + 8b + 5b + 20 = 0
=>(2b + 5)(b + 4) = 0 => b = -5/2, -4
a is always more than b.
a > b.
ANSWER:A
Question: Griffin has a bag of marbles that contains 7 black marbles and 5 red marbles. If he removes 3 marbles at random without replacing any of the marbles, what is the probability that all 3 marbles selected will be red?
A.1/22
B.2/33
C.3/44
D.4/55
Answer: A.1/22
Explanation: P(3 red marbles) = 5/12*4/11*3/10 = 1/22
The answer is A.
Question: If $5,000 is invested in an account at a simple annual rate of r percent, the interest is $250. When $19,000 is invested at the same interest rate, what is the interest from the investment?
A.$700
B.$750
C.$800
D.$950
Answer: D.$950
Explanation: -> 250/5,000=5% and 19,000*5%=950.
Thus, D is the answer.
Question: A motor cyclist participant of a race says "We drove with the speed of 10 miles an hour one way, but while returning because of less traffic we drove on the same route with 20 miles per hour." What was their average speed in the whole journey?
A.13.3 miles/hour
B.12 miles/hour
C.11 miles/hour
D.13 miles/hour
Answer: A.13.3 miles/hour
Explanation: 2xy/x+y=13.3 miles/hour
ANSWER:A
Question: At a certain school 55% of the students join a band, 25% play a sport and 20% both join the band and play a sport. if a randomly selected student is a member of the band, what is the probablility that the student also plays a sport?
A.1) 3/4
B.2)4/5
C.3)2/5
D.4)1/2
Answer: B.2)4/5
Explanation: This is the way to approach the question:
25% of the students join a band => 25% of the students either only join a band or both join a band and play sports
25% of the students play sports => 25% of the students either only play sports or both play sports and join a band
If a randomly selected student is a member of the band, then probability that the student also plays a sport = percentage of cases in which the student can do both/percentage of cases in which the student can just play sports or do both
=20%/25% = 4/5
The answer is therefore (B)
Question: Find the value of y: y² + y − 2.
A.-1 and 2
B.-2 and -1
C.-2 and 1
D.1 and 2
Answer: C.-2 and 1
Explanation: That quadratic is factored as follows:y² + y − 2 = (y − 1)(y + 2).Now, it is easy to see that the first factor will be 0 when y = 1Now, it is easy to see that the second factor will be 0 when y = -2The solutions are:x	=	-2 and 1 C
Question: A train 100 m long crosses a platform 125 m long in 15 sec; find the speed of the train?
A.91.2 kmph
B.61.9 kmph
C.45.9 kmph
D.61.2 kmph
Answer: D.61.2 kmph
Explanation: D = 100 + 155 = 255
T = 15
S = 255/15 * 18/5 = 61.2 kmph
ANSWER:D
Question: 2^2*3^3*2^3*3^2*2^2 =
A.3^5*2^5
B.2^9*3^4
C.2^4*3^9
D.5^8
Answer: D.5^8
Explanation: 2^2*3^3*2^3*3^2*2^2 =
A) 3^5*2^5
B) 2^9*3^4
C) 2^4*3^9
D) 2^7*3^5
E) 6^10
If the base is same, powers are added so that follows D) 2^7*3^5.
Hence the answer is D
Question: A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are
A.600
B.500
C.400
D.300
Answer: B.500
Explanation: Explanation :
Given that the student got 125 marks and still he failed by 40 marks
=> The minimum pass mark = 125 + 40 = 165
Given that minimum pass mark = 33% of the total mark
=> Total Mark × (33/100) = 165
=> Total Mark = 16500/33 = 500
Answer : Option B
Question: If the mean of numbers 28, x, 42, 78, 82 and 104 is 62, then what is the mean of 128, 255, 511, 1023 and x?
A.395
B.275
C.391
D.415
Answer: C.391
Explanation: The mean of numbers 28, x, 42, 78 and 104 is 62: 28+x+42+78+82+104=62*6 --> x=38;
So, the mean of 128, 255, 511, 1023 and x is (128+255+511+1023+38)/5=391.
Answer: C.
Question: A rotameter is a device that measures flow of liquid and gases. When measuring liquid phase flows, 2.5 inches represent 60 liters per minute of liquid. With gas measurements the rotameter moves 50% of the movement he moves with the liquid phase. How many liters of gas passed through the rotameter if it measured 4 inches?
A.176
B.192
C.202
D.218
Answer: B.192
Explanation: In case of liquid- 2.5 inches represents 60 lit/min.
In case of gas- 50% of 2.5 inches represents 60 lit/min
1.25 inches represents 60 lit /min
4 inches will represent 60*4/1.25= 192
B is the answer
Question: Mr. X is rewriting legislation to unevenly split $6,000,000 in funds to towns in his district. There are 5 counties in his district. What is the least amount of money he could spend to equally distribute the funds per county?
A.$1,100,200
B.$1,250,000
C.$1,000,200
D.$1,200,000
Answer: D.$1,200,000
Explanation: This problem requires us to divide our main amount by 5.
Since the current amount is easily divisible by 5, as in anything that is either a multiple of 5 or 10 could be divided to an exact, whole number.
And by dividing our amount, we get the answer.
Correct option: D
Question: I flew my tiny seaplane to visit my mother. On the flight up, I flew at 110 mph. On the way home, I flew 90 mph. What was my average speed for the trip?
A.198 mph
B.110 mph
C.88 mph
D.100 mph
Answer: D.100 mph
Explanation: (110 mph +90 mph)/2= 100 mph
Correct answer is: D
Question: The average age of a group of persons going for picnic is 16 years. Twenty new persons with an average age of 15 years join the group on the spot due to which their average age becomes 15.5 years. The number of persons initially going for picnic i
A.66
B.20
C.12
D.21
Answer: B.20
Explanation: Explanation:
Let the initial number of persons be x. Then,
16x + 20 * 15 = 15.5 (x + 20) <=> 0.5x = 10 <=> x = 20.
Answer: B
Question: If 4/(a + 5) = 7/(a - 4), then a = ?
A.-15
B.-19
C.-17
D.-18
Answer: C.-17
Explanation: Multiply all terms of the given equation by (a + 5)(a - 4), simplify and solve
(a + 5)(a - 4)[ 4/(a + 5) ] = (a + 5)(a - 4) [ 7/(a - 4) ]
4 (a - 4) =7 (a + 5)
a = -17
correct answer C
Question: If the product of two numbers is 45276 and their H.C.F. is 22, find their L.C.M.
A.2574
B.2500
C.2100
D.2058
Answer: D.2058
Explanation: Explanation:
HCF * LCM = 45276, because we know
Product of two numbers = Product of HCF and LCM
LCM = 45276/22= 2058
Option D
Question: Amit started walking positioning his back towards the sun. After some time, he turned left, then turned right and towards the left again. In which direction is he going now?
A.North or South
B.East or West
C.North or West
D.South or West
Answer: A.North or South
Explanation: North or south
ANSWER:A
Question: If the number of different positive factors of (2^y)(3^3) is the same as the number of different factors of (2^51), what is the value of y?
A.11
B.12
C.13
D.48
Answer: B.12
Explanation: Number of factors of N=a^x∗b^y where 'a' and 'b' are prime factors of N is
(X+1) (y+1)
So 4 (y+1)=52
y=12
ANSWER:B
Question: A shopkeeper buys two articles for Rs.1000 each and then sells them, making 10% profit on the first article and 10% loss on second article. Find the net profit or loss percent?
A.200
B.278
C.100
D.202
Answer: C.100
Explanation: Profit on first article = 10% of 1000 = 100.
This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.
Answer: C
Question: The speed of three cars in the ratio 5 : 4 : 6. The ratio between the time taken by them to travel the same distance is
A.5 : 4 : 6
B.6 : 4 : 5
C.12 : 15 : 10
D.10 : 12 : 15
Answer: C.12 : 15 : 10
Explanation: Sol.
Ratio of time taken = 1 / 5 : 1/4 : 1/6 = 12 : 15 : 10.
Answer C
Question: A and B starts a business with Rs.8000 each, and after 9 months, B withdraws half of his capital . How should they share the profits at the end of the 18 months?
A.4:3
B.18:5
C.14:10
D.18:14
Answer: A.4:3
Explanation: A invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 9 months and then withdraws Rs.4000. So, the investment of B for remaining 9 months is Rs.4000 only.
A : B
8000*18 : (8000*9) + (4000*9)
14400 : 108000
A:B = 4:3
Answer: A
Question: The first ticket is purchased at $2,40 and then the following purchases of ten tickets costs $2,20/ticket. What is the total number of tickets purchased if $90,40 is paid?
A.38
B.39
C.40
D.41
Answer: D.41
Explanation: a is the number of ten packs of tickets.
90,40 = 2,40 + 10 * 2,20 *a
a = 4
The total number of tickets --> 4*10+1 = 41
Answer: D
Question: In a certain population, there are 2 times as many people aged twenty-one or under as there are people over twenty-one. The ratio of those twenty-one or under to the total population is
A. 1 to 2
B. 1 to 3
C. 1 to 4
D. 2 to 3
Answer: D. 2 to 3
Explanation: Consider the ratio of the under population of 21 to over the 21 as 2:1
therefore 2x:1X
Now the ratio of the under to the whole population becomes 2x/2x+1x
= 2/3
Answer is D
Question: Set A of 8 positive integers may have the same element and have 39. And set B of 8 positive integers must have different elements and have 39. When m and n are the greatest possible differences between 39 and other elements’ sums in set A and set B, respectively, m-n=?
A.20
B.23
C.21
D.25
Answer: C.21
Explanation: This is maximum-minimum. Hence, 39-(1+1+1+1+1+1+1)=32 and 39-(1+2+3+4+5+6+7)=11. So, 32-11=21. The correct answer is C.
Question: The line P represented by which of the following equation does not intersect with the line represented by y = 3x^2+5x+1
A.y = 2x^2+5x+1
B.y = x^2+5x+2
C.y = 3x^2+5x+2
D.y = 3x^2+7x+2
Answer: C.y = 3x^2+5x+2
Explanation: concept of slope for linesparabolas are different. Bunuel, please correct if I am wrong. Also please help to solve this problem if its a GMAT type question.
The general form of parabolic equ. is y^2= 4ax which implies the axis is x or x^2 = 4ay where axis is y.
We have a similar form as x^2 = 4ay.
here the vertex is origin.
So if we have same values of x and y but constant term changes then we will have parallel parabolas.
This is same as for straight line P which are parallel for different values of constant term c
ax + by +c1 = 0 and ax +by+ c2 =0
We have quadratic equations. These equations when drawn give parabolas, not lines. The question is: which of the following parabolas does not intersect with the parabola represented by y=3x^2+5x+1.C
Question: Find large no. from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 20 as remainder
A.1235
B.1456
C.1634
D.1678
Answer: C.1634
Explanation: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 20
5x = 1345
x = 269
Large number = 269+1365 = 1634
C
Question: What quantity of water should taken out to concentrate 21 liters of 40% acidic liquid to 60% acidic liquid?
A.5liters
B.10liters
C.7liters
D.8liters
Answer: C.7liters
Explanation: Required answer is = 21(60-40)/60 = 7 liters
Answer is C
Question: In a certain store, the profit is 320% of the cost. If the cost increases by 30% but the selling price
remains constant, approximately what percentage of the selling price is the profit
A.69%
B.89%
C.99%
D.100%
Answer: A.69%
Explanation: Explanation:
Let C.P.= Rs. 100.
Then, Profit = Rs. 320,
S.P. = Rs. 420.
New C.P. = 130% of Rs. 100 = Rs. 130
New S.P. = Rs. 420.
Profit = Rs. (420 - 130) = Rs. 290
Required percentage = (290/420) * 100
= 69%(approx)
Answer: A
Question: A wolf eats 6 Kg of meat in 2 days. A baby tiger eats 3 Kg of meat in 4 days. How much meat can the two combined eat in three days?
A.11.25
B.9.25
C.8.5
D.7.5
Answer: A.11.25
Explanation: 3/2*6+3/4*3=11.25kg
A
Question: A man goes into a barbershop and gets a $15 haircut. He pays the barber with a $20 bill, but the barber doesn't have change because it is an especially slow day. The barber goes to the flower shop next to his own and trades the $20 bill for a $10 dollar bill and two $5 bills. Then he gives the man his $5 in change.
Later the lady from the flower shop confronts the barber and tells him that the $20 bill he gave her was counterfeit. The barber agrees and he gives the lady a different $20 bill.
Later that day he tries to figure out how much money he lost. What did he lose?
A.$5
B.$10
C.$12
D.$15
Answer: A.$5
Explanation: He lost $5. The lady from the flower shop gave him $20 in change, but eventually got $20 back. She broke even. The man who got the haircut gave the barber nothing (except counterfeit money) but got $5 back from the barber. So the barber lost only $5, and gave a free haircut.
Question: Mr. loyd wants to fence his Square shaped land of 60Sqft each side.If a pole is laid every 12ft how many poles do he need?
A.20
B.30
C.40
D.50
Answer: A.20
Explanation: If each side is 120 feet..then total perimeter is 60*4=240
poles every 12 feet hence no of poles= 240/12=20
ANSWER:A
Question: A train crosses a platform 100 m long in 60 seconds at a speed of 45 kmph.The time taken by the train to cross an electric pole is
A.8 sec
B.52 sec
C.1 minute
D.2 minute
Answer: B.52 sec
Explanation: let the length of the train be x m.
and that of platform is 100m.
:., Total distance covered = (x+100)m
Speed of the train= 45 km/hr. = 45*5/18 m/s = 12.5 m/s
Since it crosses the platform in 60 sec.
So, (x+100)/12.5=60
or, x=60*12.5-100=650m
It will cross an electric pole in 650m/12.5m/s=52sec.
ANSWER:B
Question: It takes printer A 4 more minutes more than printer B to print 40 pages. Working together, the two printers can print 50 pages in 6 minutes. How long will it take Printer A to print 140 pages?
A.12
B.18
C.20
D.42
Answer: D.42
Explanation: If it takes 4 more minutes for A to print 40 pages than it takes B,
it takes 5 more minutes for A to print 50 pages than it takes B.
Thus if b is the number of minutes than B takes to print 50 pages,
we can write:
1/b+1/(b+5)=1/6 (since in 1 minute, they print 1/6th of the 50 page job)
6(2b+5)=b(b+5)
b^2-7b-30=0
(b-10)(b+3)=0
b=10
Thus it takes A 15 minutes to print 50 pages and 15*140/50=42 minutes to print 140 pages (ANSWER D)
Question: A cricketer scored 142 runs which included 12 boundaries and 2 sixes. What percent of his total score did he make by running between the wickets.
A.57.75%
B.54.54 %
C.63%
D.70%
Answer: A.57.75%
Explanation: Explanation :
Number of runs made by running = 142 - (12 x 4 + 2 x 6)
= 142 - (60)
= 82
Now, we need to calculate 82 is what percent of 142.
=> 82/142 * 100 = 57.75 %
Answer : A
Question: The average earning of amechanic for the first 4days of a week is Rs.25 and for the last four days is Rs.22. If heearns Rs.20 on the fourth day, his average earning forthe whole week is?
A.s. 10
B.s. 24
C.s. 30
D.s. 40
Answer: B.s. 24
Explanation: Total earning for the week = Sum of earning of first four days + Sum of earning of last four days - Earning of 4th day
= 4 x 25+ 4 x 22 -20
= Rs. 168
âˆ´ Average earning = 168/ 7
= Rs. 24
B
Question: A man performs 1/2 of the total journey by rail, 1/3 by bus and the remaining 2km on foot. His total journey is
A.16km
B.10km
C.12km
D.24km
Answer: C.12km
Explanation: Explanation:
Let the journey be x km
Then, 1x/2 + 1x/3 +2 =x
5x +12 =6x
X = 12km
Answer: Option C
Question: An electric wire runs for 1 km b/w some no: of poles. If one pole is removed the distance b/w each pole increases by 1 2/6 (mixed fraction). How many poles were there initially?
A.4
B.5
C.6
D.7
Answer: B.5
Explanation: let there be x no. of poles
distance b/w them= 1/(x-1)
now when one pole is removed
distance bw each pole=1/(x-2)
now according to the question
1/(x-2) =8/6 (1/x-1)
on solving you will get x=5
ANSWER:B
Question: For any integer n greater than 1, n* denotes the product of all the integers from 1 to n, inclusive. How many prime numbers are there between 6* + 2 and 6* + 6, inclusive?
A.None
B.One
C.Two
D.Three
Answer: A.None
Explanation: Given that n* denotes the product of all the integers from 1 to n, inclusive so, 6*+2=6!+2 and 6*+6=6!+6.
Now, notice that we can factor out 2 our of 6!+2 so it cannot be a prime number, we can factor out 3 our of 6!+3 so it cannot be a prime number, we can factor out 4 our of 6!+4 so it cannot be a prime number, ... The same way for all numbers between 6*+2=6!+2 and 6*+6=6!+6, inclusive. Which means that there are no primes in this range.
Answer: A.
Question: A man has Rs. 544 in the denominations of one-rupee notes, five-rupee notes and ten rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has?
A.102
B.60
C.75
D.90
Answer: A.102
Explanation: Let number of notes of each denomination be x.
Then x + 5x + 10x = 544
16x = 544
x = 34.
Hence, total number of notes = 3x = 102
Answer: Option A
Question: Two numbers have a H.C.F of 9 and a product of two numbers is 1800. Find the L.C.M of the two numbers?
A.200
B.150
C.160
D.170
Answer: A.200
Explanation: L.C.M of two numbers is given by
(Product of the two numbers) / (H.C.F of the two numbers) = 1800/9 = 200.
ANSWER:A
Question: eight books consisting of 5 financial management, 2 marketing management and Since the denominator will be 11! . And there is no way to divide 11 from numerator and denominator. Use a multiple of 11 in the denominator only answer 1 system management are placed on a shelf at random order. What is the probability that the books of each kind are all together.
A.1/1155
B.1/5040
C.1/256
D.1/2255
Answer: C.1/256
Explanation: Since the denominator will be 8! . And there is no way to divide8 from numerator and denominator. Use a multiple of 8in the denominator only answer
C
Question: The cost of 3 kg of sugar is $ 60. What will the cost of 8 kg of sugar be?
A.20
B.40
C.80
D.160
Answer: D.160
Explanation: This is a situation of direct variation, now we solve using unitary method.
Cost of 3 kg of sugar = $ 60
Cost of 1 kg of sugar = $ 60/3 = $ 20
Cost of 8 kg of sugar = $ 20 × 8
Therefore, cost of 8 kg of sugar = $ 160
ANSWER -D
Question: If the number 97215 * 6 is completely divisible by 11, then the smallest whole number in place of * will be:
A.2
B.4
C.6
D.3
Answer: D.3
Explanation: D
3
Given number = 97215x6
(6 + 5 + 2 + 9) - (x + 1 + 7) = (14 - x), which must be divisible by 11.
x = 3
Question: If y = ||x – 3| – 2|, for how many values of x is y = 5?
A.2
B.1
C.3
D.4
Answer: A.2
Explanation: y = ||x – 3| – 2| can be 4 only and only when X-3= +/-7. so there are 2 values of X
Answer : A
Question: Sid left a job paying $75,000 per year to accept a sales job paying $45,000 per year plus 15 percent commission. If each of his sales is for $750, what is the least number of sales he must make per year if he is not to lose money because of the change?
A.40
B.200
C.266
D.267
Answer: D.267
Explanation: In order not to lose money because of the change Sid's total commission must beat least$75,000-$45,000=$30,000, so total sales must beat least$30,000/0.15=$200,000. Which means that he must makeat least$200,000/750=800/3=266.6 sales, so 267 sales.
Answer: D.
Question: A group of men decided to do a work in 50days, but 10 of them became absent. If the rest of the group did the work in 60days, Find the original number of men?
A.60
B.50
C.40
D.100
Answer: A.60
Explanation: Original number of men = 10*60 / (60-50) = 60
Answer is A
Question: What is the total number of ways in which Dishu can distribute 9 distinct gifts among his 8 distinct girlfriends such that each of them gets at least one gift?
A.72 * 8!
B.144 * 8!
C.36 * 8!
D.9!
Answer: C.36 * 8!
Explanation: Solution:
As every girl friend should get one gift.
The number of ways 8 distinct gifts can be selected is: 9C8 = 9 ways.
The number of ways each GF gets one gift each out of these 8 selected gifts 8!
Total number of ways 8 gifts can be distributed is 9 *8!.
Now the last one gift can be given to any of the 8 GF hence, the total number of ways of distributing =(9 *8! *82)= 36 * 8! ways.
Answer: Option C
Question: The area of a rectangle is 63 sq m. The width is two meters shorter than the length. What is the width?
A.9
B.7
C.-9
D.11
Answer: B.7
Explanation: a = l x w
w = l - 2
l = w + 2
a = (w + 2 ) x w
a = w^2 + 2 x w
63 = w^2 + 2w
0 = w^2 + 2w - 63
0 = (w + 9)(w - 7)
w = -9 and w = 7, width cannot be negative so w = 7
Answer is B
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 30 ps per meter is?
A.s.122
B.s.105
C.s.125
D.s.120
Answer: B.s.105
Explanation: 3x * 2x = 3750 => x = 25
2(75 + 30) = 210 m
210 * 1/2 = Rs.105
Answer:B
Question: In what time will Rs.4000 lent at 3% per annum on simple interest earn as much interest as Rs.5000 will earn in 5 years at 4% per annum on simple interest?
A.8 1/3
B.8 1/9
C.8 1/6
D.8 1/2
Answer: A.8 1/3
Explanation: (4000*3*R)/100 = (5000*5*4)/100
R = 8 1/3
Answer: A
Question: In one hour a boat goes 11 km long the stream and 5 km against the stream.The speed of the boat in still water is?
A.7
B.8
C.6
D.5
Answer: A.7
Explanation: Speed in still water A = ½ ( 11+5) km/hr A= 8 kmph
Answer: A
Question: what is the value of y if the greatest common divisor of (y-4)!,(y+1)!, and (y+2)! is 720.
A.12
B.10
C.9
D.7
Answer: B.10
Explanation: GCD of (y-4)!,(y+1)!, and (y+2)! is 720. Find y.
Best way to find n is substitute each of the answer and find out the correct one.
Only option B gave the correct answer.
Option B: 10 and find GCD or 6!, 11! and 12!. 6! itself is 720 and 6! which is contained in the other two factorials. This satisfies the condition, hence answer is 10.
Answer is B.
Question: The monthly rent of a shop of dimension 18feet × 22feet is Rs.2244. What is the annual rent per square foot of the shop? (a) Rs. 5(2/3)
A.43
B.56
C.68
D.87
Answer: C.68
Explanation: Sol. Monthly rent per square feet = 2244/(18*22)
& Annual rent per square feet
=12*(2244/(18*22))=68
C
Question: A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
A.202
B.200
C.209
D.207
Answer: B.200
Explanation: The number of ways to select two men and three women = ⁵C₂ * ⁶C₃
= (5 *4 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)
= 200
Answer:B
Question: What will be the fraction of 50%
A.1/4
B.1/2
C.1/10
D.1/11
Answer: B.1/2
Explanation: Explanation:
It will 50*1/100 = 1/2
Option B