RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: 504 can be expressed as a product of primes as
.
A.2 × 2 × 3 × 3 × 7 × 7
B.2 × 3 × 3 × 3 × 7 × 7
C.2 × 3 × 3 × 3 × 3 × 7
D.2 × 2 × 2 × 3 × 3 × 7
Answer: D.2 × 2 × 2 × 3 × 3 × 7
Explanation: It is clear that 504 = 2 × 2 × 2 × 3 × 3 × 7
Answer: Option D
Question: Nancy works 3 days per week at a rate of x dollars per day. If Nancy works more than 3 days per week, any extra days are paid at double her normal rate. Nancy worked 4 weeks with no overtime, and then worked 2 more weeks, each with y days of overtime. Which of the following represents Nancy’s total earnings over this period?
A.a) 3y(7x+2xy)
B.b) 3x+12y
C.c) 2x(2y+9)
D.d) 3x(2y+7)
Answer: C.c) 2x(2y+9)
Explanation: Payment of a week for 3 days a week = $3x
Payment of 4 weeks for 3 days a week = $3x*4 = $12x
Payment of a week for y days overtime a week = $3x+$2xy
Payment of 2 weeks for y days overtime a week = ($3x+$2xy)*2
Total Earnings = $12x + ($3x+$2xy)*2 = 18x+4xy =2x(2y+9)
Answer: option C
Question: If f is a positive integer, and if the units' digit of f^2 is 4 and the units' digit of (f + 1)^2 is 1, what is the units' digit of (f + 2)^2 ?
A.	0
B.	2
C.	4
D.	6
Answer: A.	0
Explanation: A for me.
_1² = _1
_2² = _4
_3² = _9
_4² = _6
_5² = _5
_6² = _6
_7² = _9
_8² = _4
_9² = _1
_0² = _0
On the list, the only number that squared has the units digit = 4 preceding a number that squared has the units digit = 1 is the _8.
So, f = _8, that has square 4. The next square is 1 andnext nextsquare is 0.
Question: Which of the following is not a leap year?
A.700
B.800
C.1200
D.2000
Answer: A.700
Explanation: The century divisible by 400 is a leap year.
The year 700 is not a leap year.
Answer: Option A
Question: A can do a piece of work in 24 days. B in 15 days and C in 12 days. In how many days can A finish the work if he is assisted by B on one day and C on the next, alternately?
A.8 2/5days
B.10 2/5days
C.6 2/5days
D.18 2/5days
Answer: A.8 2/5days
Explanation: A + B = 1/24 + 1/15 = 13/120
A + C = 1/24 + 1/12 = 1/8
13/120 + 1/8 = 28/120
4 1/5 days * 2 = 8 2/5days
ANSWER:A
Question: In how many ways letters of the word OCCUPAY be arranged?
A.6178
B.9456
C.387
D.2520
Answer: D.2520
Explanation: OCCUPAY has 7 letters, out of which C repeated 2 times. Hence total ways = 7! / (2!) = 2520 ways
D
Question: A family has two children. find the probability that both the children are girls given that at least
one of them is a girl?
A.1/5
B.1/3
C.1/7
D.1/9
Answer: B.1/3
Explanation: Let b stand for boy and g for girl. The sample space of the experiment is
S = {(g, g), (g, b), (b, g), (b, b)}
Let E and F denote the following events :
E : ‘both the children are girls’
F : ‘at least one of the child is a girl’
Then E = {(g,g)} and F = {(g,g), (g,b), (b,g)}
Now E n F = {(g,g)}
Thus P(F) = 3/4
and P (E n F )= 1/4
Therefore P(E|F) = P(E ∩ F)/P(F) = (1/4)/(3/4) = 1/3
B)
Question: In a group of people, if 30 people were made to stand in each column, 16 columns could be formed. If 12 people were made to stand in a column, how many columns could be formed?
A.20
B.30
C.40
D.50
Answer: C.40
Explanation: 16*30 = 12*n
n = 40
The answer is C.
Question: The average age of all the student of a class is 18 years. The average age of boys of the class is 20 years and that of the girls is 15 years. If the number of girls in the class is 20, then find the number of boys in the class.
A.15
B.45
C.30
D.50
Answer: C.30
Explanation: Let Boys in class = B
Girls in class = 20
Now, (20B+15*20)/(B+20) = 18 => B = 30
Answer: C
Question: If a particular is never chosen, in how many ways can a cricketbe chosen out of 15 players?
A.245
B.256
C.364
D.370
Answer: C.364
Explanation: A particular players is never chosen, it means that 11 players are selected out of 14 players.
=> Required number of ways = 14C11
= 14!/11!x3! = 364
C
Question: A case of 12 rolls of paper towels sells for $9. The cost of one roll sold individually is $1.What is the percent Q of savings per roll for the 12-roll package over the cost of 12 rolls purchased individually?
A.9%
B.11%
C.15%
D.25%
Answer: D.25%
Explanation: Cost of 12 paper towels individually = 1*12=12
Cost of a set of 12 paper towels = 9
Cost of one roll = 9/12 = 3/4 = 0.75
Savings per roll = 1-.75 = 0.25
% of savings is Q= .25/ 1 *100 = 25% D is the answer.
Question: Visitors to show were charged Rs.15 each on the first day. Rs.7.50 on the second day, Rs.2.50 on the third day and total attendance on the three days were in ratio 2:5:13 respectively. The average charge per person for the whole show is?
A.1
B.4
C.5
D.6
Answer: C.5
Explanation: 2: 5: 13
2x 5x 13x
15 7.5 2.5
30x + 37.5x + 32.5x = 100x/20x
Average = 5
Answer: C
Question: A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
A.100 Kmph
B.110 Kmph
C.120 Kmph
D.130 Kmph
Answer: C.120 Kmph
Explanation: Let speed of the car be x kmph.
Then, speed of the train =150X/100 = 3X/2 Kmph.
75/X - 75/(3X/2) = 125/(10 *60)
75/X - 50/X = 5/24
X = 25 * 24/5 = 120 Kmph.
Answer C) 120 Kmph
Question: A man can swim in still water at 4.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
A.1.0
B.1.7
C.1.2
D.1.5
Answer: D.1.5
Explanation: M = 4.5
S = x
DS = 4.5 + x
US = 4.5 + x
4.5 + x = (4.5 - x)2
4.5 + x = 9 -2x
3x = 4.5
x = 1.5.Answer:D
Question: The sum of two numbers is 232 and their H.C.F is 29. How many pairs of such numbers are
A.1
B.2
C.0
D.3
Answer: B.2
Explanation: Explanation:
HCF of two numbers = 29
Let the numbers = 29x, 29y
x and y are prime to each other
According to the question,
29x + 29y = 232, 29(x+y) = 232, x + y = 8,
Possible pairs of x and y = (1,7) and (3,5)
numbers are = (29, 203) and (87,145)
Answer: Option B
Question: What will come in place of the x in the following Number series? 2, 3, 6, 6, 18, 12, 54, 24, x
A.162
B.96
C.78
D.144
Answer: A.162
Explanation: There are two series here
2, 6, 18, 54, ... (Multiply by 3)
3, 6, 12, 24 (Multiply by 2)
Hence, next term is 54 x 3 = 162
Correct Answer is A
Question: Ratio of ages of three persons is 4:7:9, Eight years ago, the sum of their ages was 56. Find their
present ages
A.16,35,36
B.12,28,36
C.16,28,27
D.16,28,36
Answer: D.16,28,36
Explanation: Explanation:
Let the present ages are 4x, 7x, 9x.
=> (4x-8) + (7x-8) + (9x-8) = 56
=> 20x = 80
=> x = 4
So their present ages are: 16,28,36
Answer: Option D
Question: An express traveled at an average speed of 150 km/hr, stopping for 3 min after every 80 kn. How long did it take to reach its destination 750 km from the starting point?
A.5 hrs 24 min
B.4 hrs 24 min
C.6 hrs 44 min
D.6 hrs 21 min
Answer: A.5 hrs 24 min
Explanation: A
5 hrs 24 min
Time taken to cover 750 km = 750/150 = 5 hrs.
Number of stoppages = 750/80 - 1 = 8
Total time of stoppages = 3 * 8 = 24 min
Hence, total time taken = 6 hrs 21 min.
Question: A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 1.8 kilometer long bridge, at the same speed?
A.4 min
B.2 min
C.8 min
D.9 min
Answer: B.2 min
Explanation: S = 600/40 = 15 mps
S = 1800/15 = 120 sec = 2 min.Answer: B
Question: Rooney, Hernandez, and Robin race each other in a 100 meters race. All of them run at a constant speed throughout the race.
Rooney beats Hernandez by 20 meters.
Hernandez beats Robin by 20 meters.
How many meters does Rooney beat Robin by ?
A.33 meters.
B.29 meters.
C.25 meters.
D.36 meters.
Answer: D.36 meters.
Explanation: D
36 meters.
100/v1 = 80/v2
100/v2 = 80/v3
20+(20/v2)*v3=20+16 = 36
Question: A man can row 7 Â½ kmph in still water.if in a river running at 1.5 km/hr an hour,it takes him 50 minutes to row to a place and back,how far off is the place?
A.4 km
B.2 km
C.5 km
D.3 km
Answer: D.3 km
Explanation: Speed downstream =(7.5+1.5)km/hr=9 km/hr;
Speed upstream=(7.5-1.5)kmph=6kmph.
Let the required distance be x km.then,
x/9+x/6=50/60.
2x+3x=(5/6*18)
5x=15
x=3.
Hence,the required distance is 3km.
ANSWER D
Question: How many times are the hands of a clock at right angle in a day?
A.22
B.44
C.41
D.21
Answer: B.44
Explanation: Correct Answer : B
In 12 hour hands of clock are at right angle 22 times
In 24 hour hands of clock are at right angle 44 times
Question: If a number is 60% more than the another, how much % is the smaller number less than the first ?
A.32(1/3)%
B.16(2/3)%
C.37(1/2)%
D.36(4/3)%
Answer: C.37(1/2)%
Explanation: Take a number 100,
Then the other number is 160
% the smaller number is less than the first = [(60/(160)) x 100]% = 37(1/2)%.
ANSWER:C
Question: S = { 8,4,7,3,2,9}
T = { 4,5,6,3,1,7}
what is the probability that x chosen from S and y chosen from T will result x*y = even
A.2/5
B.4/7
C.5/3
D.5/6
Answer: A.2/5
Explanation: p: the probability that x*y is even, then p=1-p(x*y is odd)
p(x*y odd)=p(x odd)*p(y odd)=3/6*4/5=1/3
And p=1-6/10=2/5
Option: A
Question: Working together, printer A and printer B would finish the task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 4 pages a minute more than printer A ?
A.600
B.480
C.1000
D.1200
Answer: B.480
Explanation: Answer: B.
Question: The average age of 15 men of a group is 15 years. Out of these, the average age of 5 men is 15 years and that of the other 9 men is 16 years. The age of the 15th man is?
A.11 years
B.17 years
C.6 years
D.14 years
Answer: C.6 years
Explanation: Age of the 15th student
=[15 * 15 - (15 * 5 + 16 * 9)]
= (225 - 219)
= 6 years.
Answer:C
Question: A rectangular field 30 m long and 20 m broad. How much deep it should be dug so that from the earth taken out, a platform can be formed which is 8 m long, 5.5 m broad and 1.5 m high where as the earth taken out is increase by 10/5?
A.77 cm
B.10 cm
C.88 cm
D.12 cm
Answer: B.10 cm
Explanation: 30 * 20 * x = (8 * 5.5 * 1.5)/2
Answer: B
Question: The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?
A.18%
B.19%
C.28%
D.38%
Answer: A.18%
Explanation: 1500 ---- 270
100 ---- ? => 18%
Answer:A
Question: At what price must an article costing Rs.47.50 be marked in order that after deducting 12% from the list price. It may be sold at a profit of 25% on the cost price?
A.62.5
B.67.5
C.62.7
D.62.2
Answer: B.67.5
Explanation: CP = 47.50
SP = 47.50*(125/100)
= 59.375
MP*(88/100)
= 59.375
MP = 67.5
Answer:B
Question: The perimeter of a triangle is 32 cm and the inradius of the triangle is 3.5 cm. What is the area of the triangle?
A.22
B.35
C.56
D.54
Answer: C.56
Explanation: Area of a triangle = r * s
Where r is the inradius and s is the semi perimeter of the triangle.
Area of triangle = 3.5 * 32/2
= 56 cm2
Answer:C
Question: The average of five numbers is 27. If one number is excluded, the average becomes 23. The excluded number is?
A.46
B.45
C.44
D.43
Answer: D.43
Explanation: Excluded number = (27 * 5) - (23 * 4)
= 135 - 92
= 43.
Answer: D
Question: 1/2, 1/4, 1/8 ....
In the sequence above each term after after the first one-half the previous term. If x is the tenth term of the sequence, then x satisfies which of the following inequalities?
A.0.1 < x < 1
B.0.01 < x < 0.1
C.0.001 < x < 0.01
D.0.0001 < x < 0.001
Answer: B.0.01 < x < 0.1
Explanation: In the Sequence notice that the sequence is just the 1/(2^n) ...
so for 1st term=1/2^1=1/2
2nd term=1/(2^2)1/4, 3rd term=1/(2^3)=1/8 and so on...
Thus the 10th term will be 1/(2^10)=1/1024
Roughly, 1/1024 can be 1/1000=0.001 but since denominator is a bit more than 1000 therefore the actual value will be a bit less than 0.001.
thus the ans will lie btw. 0.01 and 0.1.(B)
Question: A, B and C enter into a partnership and their shares are in the ratio 1/2 : 1/3 : 1/4. After 2 months, A withdraws half of his capital and after 10 months, a profit of Rs. 378 is divided among them. What is B's share ?
A.144
B.166
C.186
D.199
Answer: A.144
Explanation: Ratio of initial investments = 1/2 : 1/3 : 1/4 = 6 : 4 : 3.
Let their initial investments be 6x, 2x and 3x respectively.
A : B : C = (6x * 2 + 3x * 10) : (4x * 12) : (3x * 12) = 42 : 48 : 36 = 7 : 8 : 6.
B's share = = Rs. 144.
Answer: A
Question: A can do a work in 9 days and B can do the same work in 18 days. If they work together, in how many days will they complete the work?
A.4 days
B.6 days
C.8 days
D.2 days
Answer: B.6 days
Explanation: B
6 days
One day's work of A and B = 1/9 + 1/8 = (2+1)/18 = 1/6 So, the time taken to complete the work is 6 days.
Question: It takes John 25 minutes to walk to the car park and 45 to drive to work. At what time should he get out of the house in order to get to work at 9:00 a.m.?
A.8:50 a.m
B.5:50 a.m
C.7:50 a.m
D.6:50 a.m
Answer: C.7:50 a.m
Explanation: The time it takes John to get to work: time to walk to car park + time to drive
25 + 45 = 70 minutes = 1 hour and 10 minutes
John needs to get out of the house 1 hour and 10 minutes before 9:00 am at
9:00 - 1:10 = 7:50 a.m
correct answer C
Question: A train 140 m in length crosses a telegraph post in 16 seconds. The speed of the train is?
A.30.5 kmph
B.31.5 kmph
C.32.5 kmph
D.33.5 kmph
Answer: B.31.5 kmph
Explanation: S = 140/16 * 18/5 = 31.5 kmph
ANSWER:B
Question: How many integers between 100 and 1000 are there such that their unit digit is odd?
A.400
B.420
C.500
D.450
Answer: D.450
Explanation: 900 numbers between - 100 and 1000
Out of which half would be even, half odd.
Number of odd unit digit number = 450.
correct option is D
Question: A person works on a project and completes 5/8 of the job in 10 days. At this rate, how many more days will he it take to finish the job?
A.7
B.6
C.5
D.4
Answer: B.6
Explanation: Explanation:
Number of days he worked = 10
Work completed =5/8
Let the required number of days =x
Remaining Work to be completed =1−5/8=3/8
More work, more days(direct proportion)
Hence we can write as
(Work) 5/8 : 3/8:: 10 : x
⇒5/8×x=3/8×10
⇒5×x=3×10
⇒x=3×2=6
Answer: Option B
Question: What is the difference between the place value of 3 in the numeral 7339?
A.170
B.160
C.180
D.190
Answer: A.170
Explanation: 300 - 30 = 170
A
Question: If d=1/(2^3*5^10) is expressed as a terminating decimal, how many nonzero digits will d have?
A.One
B.Two
C.Three
D.Seven
Answer: C.Three
Explanation: Another way to do it is :
We know x^a*y^a=(X*Y)^a
given = 1/(2^3*5^10)
= Multiply and divide by 2^7
=2^7/(2^3*2^7*5^10)
=2^7/10^10
=> non zero digits are 128 => Ans C
Question: Let exp(m,n) = m to the power n. If exp(10, m) = n exp(2, 2) where to and n are integers then n =
A.27
B.272
C.98
D.25
Answer: D.25
Explanation: Given 10m=n.2210m=n.22
⇒⇒ 2m×5m=n.22⇒2m−2×5m=n2m×5m=n.22⇒2m−2×5m=n
For m = 2 we get least value of n = 25, and for m > 2 we get infinite values are possible for n.
Answer:D
Question: A, B and C started a shop by investing Rs. 10,000, Rs. 10,000 and Rs. 20,000 respectively. At the end of the year, the profits were distributed among them. If Câ€™s share of profit be Rs. 4,000, then the total profit was :
A.30,000
B.60,000
C.8,000
D.120,000
Answer: C.8,000
Explanation: Sol.
A : B : C = 10000 : 10000 : 20000 = 1: 1 : 2. so, Câ€™s share : Total Profit = 2 : 4
Let the total profit be Rs. x. Then, 2/4 = 36000/x or x
= 4000 * 4 / 2 = 8000.
Answer C
Question: In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:
A.20
B.99
C.88
D.27
Answer: A.20
Explanation: Distance covered by B in 9 sec. = \inline \fn_jvn {\color{Black} \left ( \frac{100}{45}\times 9 \right )m} = 20m
\fn_jvn {\color{Black} \therefore } A beats B by 20 metres.
Answer: A) 20m
Question: If a+b=−6, and a=10/b, what is the value of a^2+b^2?
A.22
B.24
C.16
D.18
Answer: C.16
Explanation: a^2 + b^2 should make you think of these formulas:
(a+b)(a+b) = a^2+b^2+2ab
We already know (a+b) = -6 and a*b = 10
(a+b)(a+b) = (-6)(-6) = a^2+b^2+2*(10)
a^2+b^2 = 36 - 20 = 16
Answer : C
Question: A boy standing idle sounds a whistle to his friend at a distance of 1200 m moving away from him in a speeding car at 108 kms /hr. Find the duration after which his friend is going to hear him. (Speed of sound = 330m/sec).
A.3.6 secs
B.4.00 secs
C.40 secs
D.45 secs
Answer: B.4.00 secs
Explanation: If friend hears sound after t secs, then
330*t = 1200 +(108*5/18)*t
300t =1200
t= 4 secs
ANSWER:B
Question: In a certain math department, students are required to enroll in either Calculus or Trigonometry, each of which is offered in beginner and advanced courses. The number of students enrolled in Trigonometry is 50% greater than the number of students enrolled in Calculus, and 80% of Calculus students are enrolled in the beginner course. If 4/5 of students are in the beginner courses, and one student is selected at random, what is the probability that a beginner Trigonometry student is selected?
A.40%
B.44%
C.48%
D.52%
Answer: C.48%
Explanation: Let x be the number of students in calculus.
Then the number of students in trigonometry is 1.5x
The number of students on beginner calculus is 0.8x
The number of students in beginner trigonometry is 4/5*(2.5x) - 0.8x = 1.2x
The percentage in beginner trigonometry is 1.2x / 2.5x = 48%
The answer is C.
Question: If each term in the sum E=a1+a2+a3+...+an either 2 or 22 and the sum equals 100, which of the following could be equal to n?
A.38
B.39
C.40
D.41
Answer: C.40
Explanation: Min value of 'n' can be 10 i.e 4*22+6*12=E => 22+22+22+22+2+2+2+2+2+2 = 100
Since we don't have 10 in the options proceed further, (10-1)+22/2 => 20 digits, which is again not in the options
(20-1) + 22/2 = 30 digits ( not in options)
(30-1) + 22/2 = 40 digits
Hence C.
Question: The probability of a lottery ticket being a prized ticket is 0.2. When 4 tickets are purchased, the probability of winning a prize on atleast one ticket is?
A.0.5907
B.0.5904
C.0.5902
D.0.5901
Answer: B.0.5904
Explanation: P(winning prize atleast on one ticket)
= 1 - P("Losing on all tickets")
= 1 - (0.8)4 = (1 + (0.8)2)(1 - (0.8)2)
= (1.64)(0.36) = 0.5904.Answer: B
Question: The average weight of a class of 20 boys was calculated to be 58.4 kgs and it was later found that one weight was misread as 56 kg instead of 62 kg. What is the correct weight?
A.58kgs
B.58.85kgs
C.58.7kgs
D.59kgs
Answer: C.58.7kgs
Explanation: Actual total weight is (20X 58.4 - 56 + 62) = 1174 Kgs
Actual average weight is 1174/20 = 58.7kgs
C
Question: A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 170, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?
A.30
B.33
C.55
D.77
Answer: A.30
Explanation: Let f = pure fuji , g = pure gala and c - cross pollinated.
c = 10% of x where x is total trees.
c = .1x
also 3x/4 = f and c+f = 170 => .1x + 3/4x = 170 => x = 200
200 - 170 = pure gala = 30.
Answer A
Question: If 5 less than x is 4 greater than y, then a number z that is 3 greater than x reduced by y is equal to
A.4
B.12
C.14
D.y + 9
Answer: B.12
Explanation: 12 it is....nice one....
B
Question: How much time will it take for an amount of Rs. 900 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
A.2 years
B.3 years
C.1 year
D.4 years
Answer: A.2 years
Explanation: Explanation:
P = Rs.900
SI = Rs.81
T = ?
R = 4.5%
T= (100×SI)/PR
= (100×81)/(900×4.5) = 2 years
Answer: Option A
Question: How many positive, 3-digit integers contain at least one 7?
A.171
B.200
C.243
D.252
Answer: C.243
Explanation: Contains only one 7:
7XX: 1*9*9 = 81
X7X: 8*1*9 = 72
XX7: 8*9*1 = 72
Contains two 7s:
77X: 1*1*9=9
X77: 8*1*1 = 8
Contains three 7s:
777: 1
Total 243
ANS:C
Question: Divide 71 into 2 parts such that 1 part exceeds the other by 8. What are the 2 no.'s in that part?
A.29
B.30
C.31
D.35
Answer: C.31
Explanation: Let $let n$ be the smaller and 71 - n be the larger number. Now, since the larger number exceeds the smaller number by 7, we can form the equation
larger number – smaller number = 7
which is equivalent to
Simplifying, we have 71 - 2n = 7. This gives us 2n = 78 which implies that the larger number is . The smaller is 71-39=31.
C
Question: what no should be subtracted from 92555 to make it a perfect square ?
A.128
B.158
C.178
D.139
Answer: D.139
Explanation: root 92555= 304.228
and
304^2=92416
92555-92416=139 should be subtracted from 92555 to make it a perfect square
ANSWER:D
Question: Mary, Peter, and Lucy were picking chestnuts. Mary picked twice as much chestnuts than Peter. Lucy picked 2 kg more than Peter. Together the three of them picked 26 kg of chestnuts. How many kilograms Lucy pick?
A.2 kilograms
B.4 kilograms
C.6 kilograms
D.8 kilograms
Answer: D.8 kilograms
Explanation: Let x be the amount Peter picked. Then Mary and Lucy picked 2x and x+2, respectively. So
x+2x+x+2=26
4x=24
x=6
Therefore, Peter, Mary, and Lucy picked 6, 12, and 8 kg, respectively.
correct answer D
Question: Which of the following is the Highest Common Factor of 27, 81 and 54?
A.8
B.9
C.6
D.14
Answer: B.9
Explanation: the Highest Common Factor is 9Ans is :B
Question: A man, a woman and a boy can complete a job in 3,4 and 12 days respectively.
How many boys must assist 1 man and 1 woman to complete the job in ¼ of a day?
A.1day
B.4days
C.19days
D.41days
Answer: D.41days
Explanation: (1 man + 1 woman)'s 1 days work = 1/3+1/4=7/12
Work done by 1 man and 1 women n 1/4 day=((7/12)*(1/4))=7/48
Remaining work= 1- 7/48= 41/48
Work done by 1 boy in ¼ day= ((1/12)*(1/4)) =1/48
Therefore, Number of boys required= ((41/48)*48)= 41 days
ANSWER D 41days
Question: A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. How far is the place?
A.2.86
B.2.88
C.2.80
D.2.87
Answer: B.2.88
Explanation: M = 6
S = 1.2
DS = 6 + 1.2 = 7.2
US = 6 - 1.2 = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
Answer: B
Question: A certain research group plans to create computer models of x% of a list of 10,000 bacterial species known to inhabit the human body. After a budget cut, the group finds it must reduce this selection by (x − 8)%. In terms of x, how many species of bacteria will the group be able to model?
A.x*x – 5x
B.(x)(105 – x)
C.(x)*(108 - x)
D.(100)(95 – x)
Answer: C.(x)*(108 - x)
Explanation: Initial: (x/100)*10000 = 100x (bacterial species)
After reduce BY (x - 8)%, the percentage of bacterial species = 1 - (x - 8)% = 1 - (x - 8)/100 = (108 - x)/100
Note: Difference betweenreduce to[means: the remain] andreduce by[means: the remain = 1 -reduce by]
So, the number of bacterial species after reducing: 100x*(108 - x)/100 = (x)*(108 - x)
Ans is C.
Question: A train is 250 meter long is running at a speed of 36 km/hour. In what time will it pass a station of 200 meter length?
A.28 seconds
B.27 seconds
C.45 seconds
D.26 seconds
Answer: C.45 seconds
Explanation: Speed = 36 Km/hr = 36*(5/18) m/sec = 10 m/sec
Total distance = 250+200 = 450 meter
Time = Distance/speed
= 450 * (10) = 45 seconds
Answer: C
Question: Simple interest on a sum at 4% per annum for 2 years is Rs.80. The C.I. on the same sum for the same period is?
A.81.6
B.81.5
C.81.1
D.81.9
Answer: A.81.6
Explanation: SI = 40 + 40
CI = 40 + 40 + 1.6
= 81.6
Answer: A
Question: Excluding stoppages, the speed of a train is 48 kmph and including stoppages it is 32 kmph. Of how many minutes does the train stop per hour?
A.A)40
B.B)30
C.C)20
D.D)10
Answer: C.C)20
Explanation: Explanation:
T = 16/48 * 60 = 20
Answer: Option C
Question: The edge of a cube is 4a cm. Find its surface?
A.104a2 cm2
B.64a2 cm2
C.96a2 cm2
D.84a2 cm2
Answer: C.96a2 cm2
Explanation: 6a2 = 6 * 4a * 4a = 96a2
Answer:C
Question: A and B are playing mathematical puzzles. A asks B "which whole numbers, greater than one, can divide all the nine three digit numbers 111,222,333,444,555,666, 777,888 and 999?"
B immediately gave the desired answer. It was :-
A.3, 37 and 119
B.3 AND 37 and 111
C.9, 37 and 111
D.3, 9 and 37
Answer: B.3 AND 37 and 111
Explanation: Explanation :
Each of the number can be written as a multiple of 111. And,
The factors of 111 are 3 and 37.
Thus, the desired answer is 3, 37 and 111.
Answer : B