RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a class of 30 students in an examination in maths 3 students scored 95 marks each, 3 get zero each and the average of the rest was 45. What is the average of the whole class?
A.A)47
B.B)45.6
C.C)44
D.D)48.5
Answer: D.D)48.5
Explanation: Explanation:
Total marks obtained by a class of 25 students
= 3*95 + 3*0 + 26 * 45 =1455
Average marks of whole class = 1455/30 =48.5
Answer: Option D
Question: A certain auto manufacturer sold 4% fewer vehicles in 2007 than in 2006. If the manufacturer sold 2.1 million vehicles in 2006, how many vehicles, to the nearest 10,000, did the manufacturer sell in 2007?
A.63,000
B.2,000,000
C.2,020,000
D.2,040,000
Answer: C.2,020,000
Explanation: Let's assume in 2006 the manufacturer sold X.
In 2007 he sold X-4/100(X)
If sales in 2006,X= 2.1 million find X-4/100(X)
(2.1 x 10^6)-4/100(2.1 x 10^6)
2100000-84000=2,016,000-----> 2,020,000(approx)
ANSWER:C
Question: Suppose that f(x) is a function such that for every real number x,i)f(x)+f(1-x) = 11 and (ii) f(1+x) = 3+f(x). Then f(x)+f(-x)
must equal
A.8
B.9
C.10
D.11
Answer: A.8
Explanation: Since (ii) holds for every real number x, it will remain valid if we replace x with
-x. Therefore, f(1-x) = 3+f(-x). Now, from (i), 11 = f(x)+f(1-x) = f(x)+3+f(-x)
so that f(x) + f(-x) = 11-3 = 8. (Observe that f(x) = 3x + 4 satisfies the conditions
in the problem.)
correct answer A
Question: In the xy-plane, a triangle has vertices (0,0), (4,0) and (4,9). If a point (a,b) is selected at random from the triangular region, What is the probability that a-b>0?
A.1/5
B.1/3
C.1/2
D.2/9
Answer: D.2/9
Explanation: The area of the right triangle is (1/2)*4*9 = 18.
Only the points (a,b) below the line y=x satisfy a - b > 0.
The part of the triangle which is below the line y=x has an area of (1/2)(4)(4) = 8.
P(a - b > 0) = 8/18 = 2/9
The answer is D.
Question: The average of 10 numbers is calculated as 15. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is?
A.10
B.12
C.16
D.18
Answer: C.16
Explanation: Explanation:
10 * 15 + 36 – 26 = 160/10 = 16
C)
Question: In a group of 6 boys and 4 girls, four children are to be selected. In how many ways can they selected that at least one boy should be there?
A.159
B.194
C.205
D.209
Answer: D.209
Explanation: We may have( 1 black and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4boys)
=(6c1 x 4c3)+(6c2 x 4c2)+(6c3 x 4c1)+6c4
=24+90+80+15
=209
ANSWER D 209
Question: If 3 people can do 3 times of a particular work in 3 days, then how many days would it take 5 people to do 5 times of that particular work?
A.1
B.2
C.3
D.5
Answer: C.3
Explanation: 3 people can do the work one time in one day.
1 person can do 1/3 of the work in one day.
5 people can do 5/3 of the work in one day.
5 people can do 5 times the work in 3 days.
The answer is C.
Question: Length of a rectangular plot is 40 mtr more than its breadth. If the cost of fencin g the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
A.46 m
B.60 m
C.58 m
D.70 m
Answer: D.70 m
Explanation: Let breadth = x metres.
Then, length = (x + 40) metres.
Perimeter = 5300/26.5 m = 200 m.
2[(x + 40) + x] = 200
2x + 40 = 100
2x = 60
x = 30.
Hence, length = x + 40 = 70 m
D
Question: Darla decides to mix lemonade with limeade to make a new drink called citrusade. The lemonade is 50% water, 30% lemon juice, and 20% sugar. The limeade is 40% water, 28% lime juice, and 32% sugar. If the citrusade is more than 45% water and more than 24% sugar, which of the following could be the ratio of lemonade to limeade?
A.3 : 1
B.7 : 3
C.3 : 2
D.4 : 5
Answer: C.3 : 2
Explanation: The lemonade is 50% water and 20% sugar.
The limeade is 40% water and 32% sugar.
The crusade is more than 45% water and more than 24% sugar.
For the crusade to be 45% water, the ratio of lemonade to limeade must 1:1. Since the crusade is more than 45% water (the average of 50 and 40), then the ratio of lemonade to limeade must be more than 1:1. Eliminate D and E.
For the crusade to be 24% sugar, the ratio of lemonade to limeade must 2:1. Since the crusade is more than 24% water, then the ratio of lemonade to limeade must be less than 2:1. Eliminate A and B.
Answer: C.
Question: 9.99 x 9.9 x 9 ÷ 9.9 ÷ 0.3 = ?
A.276
B.299
C.310
D.3.33
Answer: D.3.33
Explanation: Explanation:
? = (9.99 x 9.9 x 9)/(9.9 x 0.9 x 0.3) = 3.33
Answer: Option D
Question: The sum of digits of a two digit number is 13,The difference between the digits is 5. Find the number
A.85
B.94
C.83
D.72
Answer: B.94
Explanation: Description :
=> x+y=13, x-y=5
Adding these 2x =18
=> x=9, y=4.
Thus the number is 94
Answer B
Question: Which number is the odd one out?
159
248
840
357
591
582
A.120
B.240
C.840
D.360
Answer: C.840
Explanation: C
840
In the rest there is the same difference between each digit, eg: 8 (Ã¢â‚¬â€œ4) 4 (Ã¢â‚¬â€œ4)0
Question: Find the number of square tiles to cover the floor of a room measuring 4 m * 9 m leaving 0.25 m space around the room. A side of square tile is given to be 25 cms?
A.187
B.476
C.268
D.208
Answer: B.476
Explanation: 3 1/2 * 8 1/2 = 1/4 * 1/4 * x => x
= 476
Answer: B
Question: Two trains started at the same time, one from A to B and the other from B to A . If they arrived at B and A respectively 4 hours and 9 hours after they passed each other the ratio of the speeds of the two trains was
A.2:1
B.3:2
C.4:3
D.5:4
Answer: B.3:2
Explanation: Explanation:
Note : If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then: (A's speed) : (B's speed) = (b : a)
Therefore, Ratio of the speeds of two trains = = 3 : 2. Answer: B
Question: At present, the ratio between the ages of Arun and Deepak is 4:8. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present?
A.17 years
B.15 years
C.18 years
D.40 years
Answer: D.40 years
Explanation: Let the present ages of Arun and Deepak be 4x and 8x years respectively.
Then, 4x + 6 = 26 => x
= 5
Deepak's age
= 8x
= 40 years.
Answer:D
Question: A new sales clerk in a department store has been assigned to mark sale items with red tags, and she has marked 30% of the store items for sale. However, 20% of the items that are supposed to be marked with their regular prices are now marked for sale, and 55% of the items that are supposed to be marked for sale are marked with regular prices. What percent of the items that are marked for sale are supposed to be marked with regular prices?
A.30%
B.35%
C.40%
D.45%
Answer: C.40%
Explanation: # of items 100 (assume);
# of items that should be marked for sale is x;
# of items that should be at the regular price is 100-x;
# of items that are actually marked for sale 0.3*100=30.
Let's see how many items are marked for sale:
20% of 100-x (20% of the items that are supposed to be marked with their regular prices (100-x) are now marked for sale);
100-55=45% of x (since 55% of the items that are supposed to be marked for sale (x) are marked with regular prices, then the remaining 45% of x are marked for sale);
So, 0.2(100-x)+0.45x=30 --> x=40 (# of items that should be marked for sale).
So, # of the items that are supposed to be marked with their regular prices is 0.2*(100-40)=12, which is 12/30*100=40% of # of items that are actually marked for sale.
Answer: C.
Question: A, B, C subscribe Rs. 50,000 for a business. If A subscribes Rs. 4000 more than B and B Rs. 5000 more than C, out of a total profit of Rs. 38,000, what will be the amount A receives?
A.14700
B.15960
C.14900
D.14300
Answer: B.15960
Explanation: Total amount invested = 50000
Assume that investment of C =x.
Then investment of B =5000+x,
Investment of A =4000+5000+x=9000+x
x+5000+x+9000+x=50000
⇒3x+14000=50000
⇒3x=50000–14000=36000
⇒x=36000/3=12000
Investment of C =x=12000
Investment of B =5000+x=17000
Investment of A =9000+x=21000
Ratio of the investment of A, B and C
=21000:17000:12000
=21:17:12
Share of A = Total profit ×21/50
=38000×21/50=15960
Answer is B
Question: Ms.James invested in Fund T and Fund B. The total amount she invested, in both funds combined, was $100,000. In one year, Fund T paid 23% and Fund B paid 17%. The interest earned in Fund B was exactly $200 greater than the interest earned in Fund T. How much did Ms. Morris invest in Fund T?
A. $32,000
B. $36,000
C. $40,000
D. $42,000
Answer: D. $42,000
Explanation: 0.17B-0.23T = 200 | * 100
17B-23T=20,000
T+B=100,000
B=100,000 - T
17(100,000 - T) - 23T = 20,000
1,700,000 - 17T - 23T = 20,000
1,680,000 = 40T
divide by 40
first two digits: 42...so answer is D.
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 16%?
A.20%
B.26%
C.13 1/30%
D.12%
Answer: B.26%
Explanation: SP2 = 2/3 SP1
CP = 100
SP2 = 84
2/3 SP1 = 84
SP1 = 126
100 --- 26 => 26%
ANSWER:B
Question: In a partnership between A, B and C. A's capital is Rs.5000. If his share of a profit of Rs.800 is Rs.200 and C's share is Rs.130, what is B's capital?
A.Rs.3250
B.Rs.6250
C.Rs.10250
D.Rs.11750
Answer: D.Rs.11750
Explanation: 200 + 130 = 330
800 - 330 = 470
200 ---- 5000
470 ---- ? => 11750
ANSWER:D
Question: The average age of husband, wife and their child 3 years ago was 33 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is
A.35 years
B.40 years
C.50 years
D.58 years
Answer: D.58 years
Explanation: Solution
Sum of the present ages of husband, wife and child	= (33x3+3x3) years
= 108 years.
Sum of the present ages of wife and child	= (20x2+5x2) years
= 50 years.
âˆ´ Husband's present age	= (108 - 50) years
= 58 years.
Answer D
Question: A sum of Rs. 2900 amounts to Rs. 3422 in 3 years. Had the rate of interest be 2% higher then what would the sum amount in the same time period?
A.Rs. 4465
B.Rs. 3683
C.Rs. 3596
D.Data inadequate
Answer: C.Rs. 3596
Explanation: 3422=2900+(2900*R*3/100)
R=6
If R is 2 more.
Then R=8
Sum=2900+(2900*8*3/100)
Sum=3596
ANSWER:C
Question: J is faster than P. J and P each walk 24 km. Sum of the speeds of J and P is 7 kmph. Sum of time taken by them is 14 hours. Then J speed is equal to
A.22
B.14
C.6
D.8
Answer: B.14
Explanation: Given J > P
J + P = 7, only options are (6, 1), (5, 2), (4, 3)
From the given options, If J = 4 the P = 3. Times taken by them = 244+243=14
Answer:B
Question: In a certain company, a third of the workers do not have a retirement plan. 20% of the workers who do not have a retirement plan are women, and 40% of the workers who do have a retirement plan are men. If 140 of the workers of that company are men, how many of the workers are women?
A.85
B.95
C.105
D.120
Answer: A.85
Explanation: 20% of the workerswithoutretirement plan are women, this means 80% of the workerswithoutretirement plan are men right? Makes 100% = no retirement plan.
Then 40% of those wo have a retirement plan are men, which means 60% of those who have a retirement plan are women. These percentages are always refering to the subgroupsRetirement plan = YesandNo Retirement Plan.
Make the total workers equal x and work from there and it should be fine > x/3 have no retirement plan at all. I struggled with the question a lot, it was hard for me although usually I have no problems with sets questions like this. I believe it must be a 700+ question.
Yes, you are right. I read the question incorrectly! I glazed overnotfor some reason.
If20% of the workers who do not have a retirement plan are women,80% who do not have retirement plan are men. Also 40% who do have retirement plan are men. Since 1/3 do not have retirement plan and 2/3 do have, it becomes a simple weighted average question.
Cavg = (80*1 + 40*2)/3 = 160/3% are men
Total = 120*300/160 = 225
No. of women = 225 - 140 = 85
A
Question: An aptitude test contains 4 questions from verbal reasoning, 5 questions from simple mathematics and 6 questions testing knowledge of English. Three questions are selected at random from the list of questions. The probability that all of them are from simple mathematics section, is:
A.2/91
B.1/22
C.3/22
D.2/77
Answer: A.2/91
Explanation: Explanation :
Let S be the sample space.
Then, n(S) = number of ways of selecting 3 questions out of 15= 15C3= (15 x 14 x 13)/(3 x 2 x 1)= 455
Let E = event of getting all the 3 questions from simple mathematics section.
n(E) = 5C3 = 5C2 = (5 x 4)/(2 x 1) = 10
P(E) = n(E)/n(S) = 10/455 = 2/91 .
Answer : A
Question: In a group of 100 cars, 49 cars do not have air conditioning. If at least 51 cars have racing stripes, what is the greatest number of cars that could have air conditioning but not racing stripes?
A.49
B.47
C.48
D.51
Answer: A.49
Explanation: Lets assume AC=51(includesonly AC carsandcars with AC and racing stripes)
lets assume RS(racing stripes)>=51(includescars with AC and racing stripesandonly racing stripes).
Now since we want to maximize(only AC) we have to see to it thatcars with AC and racing stripesis minimal(assume 0) But since RS>=51.. we have to assign atleast 2 tocars with AC and racing stripes.
Hence AC=51-2=49.
The answer is A
Question: A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train ?
A.69.5 km/hr
B.70 km/hr
C.79 km/hr
D.79.2 km/hr
Answer: D.79.2 km/hr
Explanation: Explanation:
Let the length of the train be x metres and its speed by y m/sec.
Then,
Now,
8y + 264 = 20y
y = 22.
Speed = 22 m/sec = km/hr = 79.2 km/hr.
ANSWER IS D
Question: 765 chairs are to be arranged in a column in such a way that the number of chairs in each column should be equal to the columns. How many chairs will be excluded to make this arrangement possible?
A.6
B.36
C.19
D.27
Answer: B.36
Explanation: 27(2) < 765 < 28(2)
∴ required no. of chairs to be excluded
= 765 – 729 = 36
Answer B
Question: A certain car traveled twice as many miles from Town A to Town B as it did from Town B to Town C. From Town A to Town B, the car averaged 20 miles per gallon, and from Town B to Town C, the car averaged 25 miles per gallon. What is the average miles per gallon that the car achieved on its trip from Town A through Town B to Town C?
A.20
B.18
C.21.4
D.16
Answer: C.21.4
Explanation: step 1) took LCM of 20 and 25.. came as 100.
step 2) 100 distance between B to C... do 100/25 hence 4 gallons used
step 3) twice distance.. hence 100*2= 200... do as above.. 200/20= 10 gallons used
step 4) total gallons.. 4+10= 14 gallons
step ) total miles= 100+200= 300 miles
hence.. average of whole journey = 300/14 which comes to 21.4
Answer : C
Question: In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?
A.5/21
B.5/81
C.5/29
D.9/21
Answer: A.5/21
Explanation: Explanation:
Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)
As remaining person can be any one among three couples left.
Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅
= (10 * 6)/252 = 5/21
Answer: Option A
Question: In what time will a train 100 meters long cross an electric pole, if its speed is 144 km/hr
A.5 seconds
B.4.5 seconds
C.3 seconds
D.2.5 seconds
Answer: D.2.5 seconds
Explanation: Explanation:
First convert speed into m/sec
Speed = 144*(5/18) = 40 m/sec
Time = Distance/speed
= 100/40 = 2.5 seconds
Answer: D
Question: Find the odd man out. 3576, 1784, 888, 440, 216, 105, 48
A.1784
B.888
C.216
D.105
Answer: D.105
Explanation: 3576
(3576-8)/2 = 1784
(1784-8)/2 = 888
(888-8)/2 = 440
(440-8)/2 = 216
(216-8)/2 = 104
(104-8)/2 = 48
Hence, 105 is wrong. 104 should have come in place of 105
Answer is D
Question: In how many different ways can 3 identical gold shirts and 3 identical sliver shirts be distributed among 6 children such that each child receives a shirt?
A.100
B.400
C.20
D.96416
Answer: C.20
Explanation: Approach 1:
1st Child: 6 has options
2nd Child: 5 has options…
Therefore, for all kids: 6 x 5 x 4 x 3 x 2 = 720 arrangements.
Since the golds are identical, we divide by 3!; Since the silvers are identical, we divide by another 3!
So: in all, 720/[ 3! X 3! ] = 20 ways.
(e.g. Answer: C)
Question: If 5^z is a factor of 160!, which of the following could be the value of z?
A.40
B.32
C.51
D.39
Answer: D.39
Explanation: 5^z is a factor of 160!, what values can z take.
Powers of 5 in 160! = [160/5] + [160/25] +[160/125] , where [x] is the integral part of x
Powers of 5 in 160! = 32 + 6 + 1 = 39
Hence the maximum value of 5^z in 160! = 5^39
Correct Option: D
Question: In the xy-plane, the line y = k is the perpendicular bisector of the line segment PQ and the line x = h is the perpendicular bisector of the line segment RQ. If the coordinates of the point R are (-h, -k), then what are the coordinates of the point P?
A.(-5h, -5k)
B.(-3h, -3k)
C.(2h, 2k)
D.(3h, 3k)
Answer: D.(3h, 3k)
Explanation: firstly the Question tells us that RQ and PQ are perpendicular at Q..
Now the coordinates of the point R are (-h, -k), so R is at a distance of 2h from line x and at dist of 2k from line Y..
as line X bisect RQ .... length of RQ =4h and coord (3h,-k)..
as line Y bisect PQ .... length of PQ =4k and coord (3h,3k).
ANSWER:D
Question: Two cars A and B start from Boston and New York respectively simultaneously and travel towards each other at constant speeds along the same route. After meeting at a point between Boston and New York the two cars A and B proceed to their respective destinations of New York and Boston. Car A reaches New York 20 minutes after the two cars have met and Car B reaches Boston 90 minutes after they have met. How long did Car A take to cover the distance between Boston and New York?
A.1 hour
B.1 hour 10 minutes
C.2 hours 30 minutes
D.1 hour 20 minutes
Answer: D.1 hour 20 minutes
Explanation: Both cars leave at the same time
Both cars travel at constant speed
Stealing a useful piece of information from Paragkan:
If two objects A and B start from opposite points and, after having met en route, reach their respective destinations in a and b mins (or any other measure of time) respectively, then the ratio of their speeds
ratio of speed: (a/b) = sq. rt(b/a)
sq. rt(b/a)
sq. rt(90/20)
sq. rt(3/2)
So, for every three units of distance A travels, B travels two. Because we know the ratio of speed and the time it took B to travel the distance A hasn't yet covered, we can find the time it took A to cover the distance B did in 90 minutes.
90*(2/3)where 2/3 represents the lesser amount of time it took A to travel the distance B did in 90 minutes.
= 60 minutes.
Therefore, A took 20 minutes to travel the first portion then 60 minutes to travel the distance B did in 90 minutes. A spent (20+60)=80 minutes on the road.
D. 1 hour 20 minutes
Question: A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
A.240
B.88
C.77
D.26
Answer: A.240
Explanation: Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x = 240 m.
Answer: A
Question: A owner of a mart earns an income of Re 1 on the first day of his business. On every subsequent day, he earns an income which is just double of that made on the previous day. On the 10th day of business, he earns an income of:
A.18
B.21
C.22
D.20
Answer: A.18
Explanation: 2nd day he earns = 2(2 – 1)
3rd day he earns = 2(3 – 1)
On 10th day he earns 2(10 -1) = 18 rupees
ANSWER:A
Question: What is the value of âˆš64% ?
A.80%
B.20%
C.40%
D.90%
Answer: A.80%
Explanation: Explanation: br>âˆš64%
=âˆš64/âˆš100
=8/10
=80/100=80%
correct answer is A)80%
Question: Three hundred multiples of seven are chosen at random, and 300 multiples of eight are chosen at random. Approximately what percentage of the 600 selected numbers are odd?
A.26.67%
B.36.67%
C.25%
D.46.67%
Answer: C.25%
Explanation: --> Multiples of 7 are 7, 14, 21, 28, 35, 42....
Out of first 4 multiples, 2 are odd; out of first 6 multiples, 3 are odd.
So approx. 50 % of the 300 multiples are odd i.e 150 multiples.
--> Similalrly, for 8 multiples are:8,16,24...
All are even so 0 % are odd.
Total odd= (150+0)/(300+300)= 150/600=(1/4) = 25%
Answer C
Question: What is the remainder when the number Y=14^2 * 15^8 is divided by 5?
A.0
B.1
C.2
D.4
Answer: A.0
Explanation: 14^2 has units digit 6
15^8 has units digit 5
Thus Y=14^2*15^8 has units digit 0 and will be divisible by 5. The remainder will be zero
Answer: (A)
Question: The number of six digit numbers that can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that digits do not repeat and the terminal digits are even is
A.144
B.72
C.288
D.720
Answer: D.720
Explanation: The first and the last (terminal) digits are even and there are three even digits. This arrangement can be done in 3P2 ways. For any one of these arrangements,two even digits are used; and the remaining digits are 5 (4 odd and 1 even) and the four digits in the six digits(leaving out the terminal digits) may be arranged using these 5 digits in 5P4 ways. The required number of numbers is 3P2 × 5P4 = 6 × 120 = 720.
Answer D
Question: If x is 20 percent greater than 40, then x =
A.48
B.70.4
C.86
D.105.6
Answer: A.48
Explanation: X is 20% greater than 40 means X is 1.2 times 40 (in other words 40 + 20/100 * 40 = 1.2 * 40)
Therefore, X = 1.2 * 40 = 48
ANSWER:A
Question: If the perimeter of a rectangular house is 1400 m, its length when its breadth is 300 m is?
A.300
B.400
C.500
D.600
Answer: B.400
Explanation: 2(l + 300) = 1400 => l = 400 m Answer: B
Question: There are 6 boxes numbered 1, 2,…,.6. Each box is to be filled up either with a red or a green ball in such a way that at least 1 box contains a green ball and the boxes containing green balls are consecutively numbered. The total number of ways in which this can be done is
A.22
B.21
C.45
D.27
Answer: B.21
Explanation: List down possibilities: From only 1 box all the way to all 6
If only one of the boxes has a green ball, it can be any of the 6 boxes. So, we have 6 possibilities.
If two of the boxes have green balls and then there are 5 consecutive sets of 2 boxes. 12, 23, 34, 45, 56.
If 3 of the boxes have green balls, there are 4 possibilities: 123, 234, 345, 456.
If 4 boxes have green balls, there are 3 possibilities: 1234, 2345, 3456.
If 5 boxes have green balls, there are 2 possibilities: 12345, 23456.
If all 6 boxes have green balls, there is just 1 possibility.
Total number of possibilities = 6 + 5 + 4 + 3 + 2 + 1 = 21.
Ans: B
Question: A circular logo is enlarged to fit the lid of a jar. The new diameter is 30 per cent larger than the original. By what percentage has the area of the logo increased?
A.50
B.80
C.69
D.125
Answer: C.69
Explanation: Let old diameter be 4 , so radius is 2
Old area = 4π
New diameter is 5.2 , so radius is 2.6
New area = 6.76π
Increase in area is 2.76π
% increase in area = 2.76/4*100
So, % increase is 69%
Answer will be (C)
Question: In Town X, 64 percent of the population are employed, and 35 percent of the population are employed males. What percent of the employed people in Town X are females?
A.16%
B.25%
C.32%
D.45%
Answer: D.45%
Explanation: We are asked to find the percentage of females in employed people.
Total employed people 64%, out of which 35 are employed males,hence 29% are employed females.
(employed females)/(total employed people)=29/64=45%
Answer:D.
Question: A train 60 m long is running with a speed of 54 km per hour. In what time will it pass a telegraph post?
A.11 s
B.10 s
C.7 s
D.4 s
Answer: D.4 s
Explanation: We know from the formula Time = Distance/ Speed
Thus, Time = 60/ 54 x 5/18
or, Time = 4 sec.
ANSWER:D