RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A car traveled the first quarter of a certain distance at one-seventh the speed it traveled the remaining distance. What proportion of the total time traveled, was the time taken to travel the first quarter of the distance?
A.1/22
B.1/25
C.1/26
D.1/27
Answer: A.1/22
Explanation: These problems can be solved through algebra or sly number picking. Being a big fan of solving problems with numbers, let's pick a total distance divisible by 4 (say 40) so we can break it up into quarters, and a speed that can easily be one-seventh, say 10. Each quarter is thus 10 kilometers (or miles or feet or angstroms for all it matters), and the runner's speed is 10 km/h for the first quarter and 1 3/7 km/h for the remaining quarters.
He'll take 1 hour to do the first quarter and then 7 hours for the second quarter, 7 hours for the third and 7 hours for the fourth. On total he will take 22 hours to complete this race, of which 1 hour was spent on the first quarter. So 1/22. Answer A.
Question: A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
A.150 m
B.200 m
C.350 m
D.400 m
Answer: C.350 m
Explanation: Sol.
Speed = [300 / 18] m/sec = 50/3 m/sec.
Let the length of the platform be x metres.
Then, x + 300 / 39 = 50/3 ⇔ 3(x + 300) = 1950 ⇔ x = 350m.
Answer C
Question: Present ages of Sameer and Anand are in the ratio of 5:4 respectively. Three years hence, the ratio of their ages will become 11:9 respectively. What is Anand's present age in years?
A.24 years
B.66 years
C.77 years
D.55 years
Answer: A.24 years
Explanation: Let the present ages of Sameer and Anand be 5x and 4x years respectively.
Then, (5x + 3)/(4x + 3) = 11/9
9(5x + 3) = 11(4x + 3) => x = 6
Anand's present age = 4x = 24 years.
Answer: A
Question: Paulson spends 75% of his income. His income is increased by 20% and he increased his expenditure by 10%. Find the percentage increase in his savings?
A.20%
B.25%
C.50%
D.75%
Answer: C.50%
Explanation: Let original income = $100
expenditure = $75
savings = $25
new income = $120
new expenditure = $110/100 * 75 = $165/2
New savings = 120 - 165/2 = $75/2
Increase in savings = 75/2 - 25 = $25/2
Increase % = 25/2 * 1/25 * 100 = 50%
Answer is C
Question: if p/q=3/4
then3p+4q=?
A.25/4
B.25/2
C.20/4
D.35/4
Answer: A.25/4
Explanation: 3p+4q=?
Divided by q,
3(p/q)+4=x
3*(3/4)+4=25/4
ANSWER:A
Question: If 0.6 : x :: 5 : 8, then x is equal to:
A.A)0.96
B.B)1.2
C.C)1.25
D.D)1.3
Answer: A.A)0.96
Explanation: (x * 5) = (0.6 * 8)
x = 4.8/5
x = 0.96
Answer = A
Question: What is the least number should be added to 929, so the sum of the number is completely divisible by 30?
A.1
B.2
C.5
D.6
Answer: A.1
Explanation: (929 / 30) gives remainder 29
29 + 1 = 30, So we need to add 1
Answer : A
Question: The positive number a is q percent greater than the positive number b, which is l percent less than a itself. If a is increased by l percent, and the result is then decreased by q percent to produce a positive number c, which of the following could be true?
I. c > a
II. c = a
III. c < a
A.I only
B.II only
C.III only
D.I and II only
Answer: C.III only
Explanation: Let q = 10% then l = 100/11 %
let b = 100 then a = 110
after increasing a by l and decreasing b yq we get c= 108
therefore c<a
C it is answer
Question: A, B, C subscribe Rs. 50,000 for a business. A subscribes Rs. 4000 more than B and B Rs. 5000 more than C. Out of a total profit of Rs. 30,000, A receives:
A.s. 12,000
B.s. 12,200
C.s. 12,400
D.s. 12,600
Answer: D.s. 12,600
Explanation: Let C = x.
Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.
So, x + x + 5000 + x + 9000 = 50000
3x = 36000
x = 12000
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
A's share = Rs. (30000 x 21/50) = Rs. 12,600.
D
Question: A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
A.7 sec
B.6 sec
C.8 sec
D.5 sec
Answer: B.6 sec
Explanation: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr
[66 * 5/18] m/sec = [55/3] m/sec.
Time taken to pass the man = [110 * 3/55] sec = 6 sec
Answer: B
Question: Find the principle on a certain sum of money at 8% per annum for 2 2/5 years if the amount being Rs.1120?
A.939.6
B.928.8
C.927.78
D.926.82
Answer: A.939.6
Explanation: 1120 = P [1 + (8*12/5)/100]
P=939.60
Answer: A
Question: The average of four positive integers is 69. The highest integer is 93 and the least integer is 39. The difference between the remaining two integers is 28. Which of the following integers is the higher of the remaining two integers?
A.65
B.48
C.37
D.23
Answer: B.48
Explanation: Let the four integers be A, B, C and D where A > B > C > D.
(A + B + C + D)/4 = 69 => A + B + C + D = 276 ---> (1)
A = 93, D = 39 and B - C = 28
(1) => B + C = 276 - (A + D) = 276 - 132 = 144.
B + B -28 = 144
B = (144 + 28)/2 = 86
Answer:B
Question: If the S.P of Rs. 12 results in a 40% discount on the list price, What S.P would result in a 10% discount on the list price?
A.s. 16
B.s. 17
C.s. 18
D.s. 19
Answer: C.s. 18
Explanation: Let the list price be Rs. X,
60/100*x = 12, x = 12*100/60 = 20
Required S.P = 90% of Rs. 20
= 90*20/100
=18
ANSWER:C
Question: Find the missing value : 8597 - ? = 7429 - 4358
A.5526
B.5426
C.5326
D.5226
Answer: A.5526
Explanation: Let 8597 - x = 7429 - 4358.
Then, x = (8597 + 4358) - 7429 = 12955 - 7429 = 5526.
Answer is A.
Question: What is the sum of all digits for the number 10^27 - 48?
A.212
B.222
C.232
D.242
Answer: C.232
Explanation: 10^27 is a 28-digit number: 1 followed by 27 zeros.
10^27 - 48 is a 27-digit number: 25 9's and 52 at the end.
The sum of the digits is 25*9+5+2=232.
The answer is C.
Question: A dealer purchased an article at 3/4 of its list price and sold 50% more than the list price. Find his gain percent?
A.180%
B.190%
C.100%
D.170%
Answer: C.100%
Explanation: MP = 100
CP = 75
SP = 150
------
75 ---- 75
100 ---- ? => 100%
Answer: C
Question: A group of 5 fishermen chartered a boat for a day to fish for flounder. The boat costs x dollars per day to rent. If the group can find 3 more fishermen on the docks who are willing to come aboard and share the rental costs, how much less will the rental cost be per person in terms of x?
A.x/70
B.x/35
C.3x/40
D.3x/10
Answer: C.3x/40
Explanation: cost of boat per day = x
cost per person =x/5
if three more persons afre there, cost =x/8
difference = x/5-x/8
=3x/40
Ans C
Question: One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 38 minutes, then the slower pipe alone will be able to fill the tank in
A.144 mins
B.140 mins
C.136 mins
D.152 minw
Answer: D.152 minw
Explanation: Explanation:
Let the slower pipe alone fill the tank in x minutes
then faster will fill in x/3 minutes.
Part filled by slower pipe in 1 minute = 1/x
Part filled by faster pipe in 1 minute = 3/x
Part filled by both in 1 minute =
1/x+3/x=1/38
=>4/x=1/38
x=38∗4=152mins
Option D
Question: A walks at 10 kmph and 3 hours after his start, B cycles after him at 20 kmph. How far from the start does B catch up with A?
A.100km
B.150km
C.60km
D.120km
Answer: C.60km
Explanation: Suppose after x km from the start B catches up with A. Then, the difference in the time taken by A to cover x km and that taken by B to cover x km is 3 hours.
x/10 - x/20 = 3
x = 60 km
Answer is C
Question: If x is an integer and (x)(x^4)(x^3) is positive, which of the following could be negative?
A.x^4
B.(x)(x^3)
C.(x)(x)
D.x + x^11
Answer: D.x + x^11
Explanation: A) X^4 - always positive (or 0).
B) X(X^3) = X^4 - Again always positive (or 0).
C) (x)(x) = X^2 - Again always positive (or 0).
D) x+x^11 - Could be -ve if x is -ve.
E) 3X^2 - again always positive (or 0)
Answer D.
Question: Renu can do a piece of work in 6 days, but with the help of her friend Suma , she can do it in 4 days. In what time Suma can do it alone?
A.10
B.12
C.14
D.15
Answer: B.12
Explanation: Renu’s one day’s work = 1/6
Suma’s one day’s work = 1/4 - 1/6 = 1/12
Suma can do it alone in 12 days.
ANSWER:B
Question: 2y - 3x = 2xy and x ≠ 0. If x and y are integers, which of the following could equal y?
A.2
B.1
C.0
D.-2
Answer: D.-2
Explanation: Plug in the answer choices in the equation from the question stem.
A) y = 2 >>> 4-3x = 4x >>> No value of x will satisfy this, not even 0. POE
B) y = 1 >>> 2 - 3x = 2x >>> Same, POE
C) y = 0 >>> -3x = 0 >>> x can not equal 0
D) y = -2 >>> -4 - 3x = -4x >>> Holds true for x = 4, no need to check E. This is the answer.
Answer D
Question: Five kilograms of oranges contained 95% of water. If the next day the concentration of water decreased by 5%, what was the new weight of the oranges, in kilograms?
A.30
B.25
C.15
D. 10
Answer: B.25
Explanation: Five kilograms of oranges contained 95% of water. If the next day the concentration of water decreased by 5%, what was the new weight of the oranges, in kilograms?
(A) 30
(B) 25
(C) 15
(D) 10
(E) 5
If B is the answer, then the question means that the concentration of water the newt day became 90%.
Out of 5 kilograms 95%, or 4.75 kilograms was water and 0.25 kilograms was non-water.
The next day, after some water evaporated, oranges became 90% water and 10% of non-water, so the next day 0.25 kilograms of non-water composed 10% of oranges, which means that the new weight of the oranges was x*0.10=0.25 --> x=25 kilograms.
Answer: B.
Question: The apartment on King-Williams street is an asset that its value is tramping about. From the year 1973 to 1983 it's value decreased by 16% and from 1983 to 1993 it's value increased by 16%. What is the value of the asset in 1993 if in 1973 it was worth $50,000?
A.$48,720
B.$40,000.
C.$38,976.
D.$39,679.
Answer: A.$48,720
Explanation: 50,000 *1.16*.84= Unit and tens digit of the expression is 6 and 7 respectively.
Only option A fulfills the condition and hence is the answer
Question: There are 5 marbles in a bag - 2 are orange and 3 are blue. If two marbles are pulled from the bag, what is the probability W that at least one will be orange?
A.W=7/10
B.W=3/5
C.W=2/5
D.W=3/10
Answer: A.W=7/10
Explanation: Method 1
Probability that at least one out of two marbles will be orange = 1 - Probability that both marbles are blue = 1- P(First marble is blue)*P(Second Marble is Blue) = 1- (3/5)(2/4) = 7/10
Method 2
Probability that at least one marble will be orange = P( First Marble is Orange)*P(Second Marble is Blue) + P (First Marble is Blue)*P(Second Marble is Orange) + P(First Marble is Orange) *P(Second Marble is Orange) = (2/5)*(3/4)*2 + (2/5)*(1/4) = 7/10
Method 3
Probabilty that at least one marble will be orange = 1 - Probability that both marbles are blue
= 1 - (Number of ways 2 blue marbles out of 3 can be pulled)/(Number of ways 2 marbles out of 5 can be pulled)
= 1 - 3C2/5C2
= 1-(3/10) = 7/10
Answer :A
Question: In a kickball competition of 8 teams, how many possible matches can each team play with each other?
A. 9
B. 16
C. 24
D. 28
Answer: D. 28
Explanation: 8C2 = 28
Option D
Question: If k is the sum of the digits of integer m, and m=11n, where n is an integer, which of the following must be true?
A.k is a multiple of 6
B.The sum of the digits of k is divisible by 3
C.m is a multiple of 10k
D.k is divisible by 2
Answer: D.k is divisible by 2
Explanation: m= 11n i.e n =1,2,3 ,4 etc or -1,-2.-3 ,-4 then m =11,22,33,44 or -11 ,-22 ,-33 ,-44 then k 2,4,6,8 or -(1+1) , -(2+2) , -(3+3) ,-(4+4) .
ans D
Question: Of the 5 numbers, whose average is 120, the first is one-fourth of the sum of the last 4. The first number is?
A.83
B.80
C.50
D.120
Answer: D.120
Explanation: Total of 5 numbers = 5 * 120 = 600
Let total of last 4 numbers = x
1st number = x/4
x+ x/4 = 600
5x = 2400 => x =480
1st number = 480/ 4 = 120
Answer :D
Question: Which one of the following is equal to 17?
A.3 - 4 * 5 + 6
B.3 *4 + 5 / 6
C.3 + 4 * 5 - 6
D.3/ 4 + 5 - 6
Answer: C.3 + 4 * 5 - 6
Explanation: In the table below, each of the five expressions is evaluated using the correct order of operations.
Expression Value
(A) 3 - 4 x 5 + 6= 3 - 20 + 6 = -17 + 6 = -11
(B) 3 x 4 + 5 + 6=12 + 5 / 6 = 12 + 5/6 = 12 5/6
(C) 3 + 4 x5- 6= 3 + 20 - 6 = 23- 6 = 17
(D) 3 / 4 + 5 * 6=3/4 + 5 - 6 = 5 3/4 - 6 = 23/4- 24/4 = -1/4
(E) 3x 4 /5 + 6 =12 5 + 6 = 12/5 + 6 = 2 2/5 + 6 = 8 2/5
The only expression that is equal to 17 is 3 + 4 * 5 - 6, or (C).
correct answer C
Question: A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
A.239
B.240
C.288
D.282
Answer: B.240
Explanation: Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x = 240 m.
Answer: B
Question: Vijay sells a cupboard at 12% below cost price. Had he got Rs.1650 more, he would have made a profit of 12%. What is the cost price of the cupboard?
A.7450
B.14900
C.7400
D.6875
Answer: D.6875
Explanation: Explanation:
Cost price = 1650/(0.12 + 0.12) = 2086/0.24
= Rs.6875
ANSWER D
Question: From a bunch of four keys, three particular keys have to be used to open a combination lock, such that the second key can be used only after the first key and the third key can be used only after the second key. What are the chances of opening the lock in a random selection of three keys?
A.1/24
B.1/36
C.1/60
D.1/80
Answer: A.1/24
Explanation: The probability is 1/4*1/3*1/2 = 1/24.
The answer is A.
Question: A contractor is engaged for 30days on the condition thathe receives Rs.25 for each day he works &is fined Rs.7.50 for each day is absent. He gets Rs.360 in all. For how many days was he absent?
A.8
B.12
C.15
D.17
Answer: B.12
Explanation: 30 * 25 = 750
360
-----------
380
25 + 7.50 = 32.5
390/32.5 = 12
B
Question: On a certain transatlantic crossing, 10 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?
A.33 1/3%
B.40%
C.50%
D.25%
Answer: D.25%
Explanation: On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?
Solution: Let total number of passengers be 100
According to Q stem 40% of passengers who had round-trip tics have taken cars - let number of passengers with round trip be X then
40% of X = 10 => X= 25.
Answer D
Question: If a number is subtracted from its square we get 272. Find the number?
A.22
B.29
C.17
D.29
Answer: C.17
Explanation: Explanation:
x2 â€“ x = 272 => x =17
Answer: C
Question: The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 245, what is the difference between the ages of Patrick and Monica?
A.27
B.48
C.80
D.72
Answer: C.80
Explanation: Ages of P and Mi=3x:5x
Ages of Mi and Mo=3x:5x
Rationalizing their ages. ratio of their ages will be 9x:15x:25x
Sum=49x=245
x=5
Difference if ages of Pa and Mo=25x-9x=16x=16*5=80
Answer C
Question: What is the next number of the following sequence
108,58,50,8,?
A.40
B.50
C.30
D.42
Answer: D.42
Explanation: 108-58=50
58-50=8
50-8=42
therefore next no. is 42
ANSWER:D
Question: In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B the present age of B is
A.37
B.38
C.39
D.40
Answer: C.39
Explanation: let present age of A be a and B be b
a+10 = 2*(b-10)
=> 2b-a = 30 ......(i)
a = b+9
=>2b-b-9 = 30
b=39
so the present age of b is 39 years
ANSWER:C
Question: A store sells two kinds of birdseed. If brand a is 40% millet and 60% sunflower and brand b is 65% millet and 35% sunflower . A customers purchases a mix of the two types that is 50% millet. What percent is brand A
A.30
B.40
C.50
D.60
Answer: D.60
Explanation: Let "a" and "b" be the amount of brand A and brand B respectively in the mixture.
Total amount of the mixture = a+b
Amount of millet in the mixture = 40% of a + 65 % b . This is also equal to 50% of the mixture as per the question i.e (a+b)/2
.4 a + .65 b = (a+b)/2 => .8a +1.3 b = a+b => .3b =.2 a => b =(2/3)a
We have to find the percent of brand A in the total mixture i.e (a/(a+b)) * 100 = (a/(a+(2/3)a))*100 = (3/5)*100 = 60%
ANSWER:D
Question: Stuart bought a sweater on sale for 30% off the original price and another 25% off the discounted price. If the original price of the sweater was $120, what was the final price of the sweater?
A.$25.75
B.$35.75
C.$63
D.$ 45.75
Answer: C.$63
Explanation: The price with 30% off
120 - 30% of 120 = 120 - (30 / 100) *120 = 84
The price with another 25% off
84 - 25% of 84 = 84 - (25/100)* 84 = $63
correct answer C
Question: There are 48 people in a certain community who belong to the local golf club, tennis club or both clubs. If twice as many people belong to the tennis club as belong to the golf club, what could be the number of people who belong to both clubs?
A.1) 4
B.2) 7
C.3) 17
D.4) 18
Answer: D.4) 18
Explanation: x -> Golf Club
2x -> Tennis Club
y -> both
x+2x-y = 48
3x - y =48
multiples of 3 greater than 48
51
54
57
60
63
66 - 18= 48
IMO (D)
Question: If the average (arithmetic mean) of five consecutive integers is k + 2, then the product of the greatest and least integer is
A.k^2 - 9
B.k^2 - 2k + 1
C.k^2 + 4k
D.k^2 + 6k + 9
Answer: C.k^2 + 4k
Explanation: n = smallest number
n+4 = largest number
(n + n + 4)/2 = k+2
=> (2n+4)/2 = k+ 2
=> n + 2 = k + 2
=> n = k
So Product of n and n+4 = (k)(k+4)
= k^2 + k
= k^2 + 4k
Answer - C
Question: If 313,252 football shoes need to be placed in boxes and each box can contain at most 11 pair of football shoes. How many pair of football shoes will be in the last unfilled box?
Options:
A.5 football shoes
B.3 football shoes
C.4 football shoes
D.7 football shoes
Answer: A.5 football shoes
Explanation: The number of football shoes that can be placed in boxes of 11 football shoes is the first number that is divisible by 11 that occurs before 313,252
In order to divide the sum in 11 parts, the amount must be divisible by 11
Divisibility rule of 11: Subtract the last digit from the remaining leading truncated number. If the result is divisible by 11, then so was the first number 313,252->31325-2=>3132-3=3129->312-9=303->30-3=27
Hence, we need to remove 5 to this number for it to be divisible by 11
Correct Option: A
Question: In the equation ax^2 + bx + c = 0 a, b, and c are constants, and abc # 0. If one root of the equation is -2, and b = 6a then which of the following is c equal to?
A.a/12
B.a/8
C.6a
D.8a
Answer: D.8a
Explanation: The sum of the roots is = -b/a = -6a/a = -6. Let the other root be x. Thus, x-2 = -6
x = -4. Again, the product of the roots is -2*-4 = 8. Thus, c/a = 8. c = 8a.
D.
Question: A car during its journey travels 30 minutes at a speed of 40 kmph, another 45 minutes at a speed of 80 kmph, and 2 hours at a speed of 50 kmph.The average speed of the car is
A.60.07 kmph
B.55.38 kmph
C.50.02 kmph
D.44.02 kmph
Answer: B.55.38 kmph
Explanation: First car travels 30 min at speed of 40 kmph
distance = 40 x 1/2 = 20 m
Then car travels 45 min at a speed of 80 kmph
distance = 45 min at speed of 80 kmph
distance = 80 x 3/4 = 60 m
at last it travels 2 hours at speed of 50 kmph
distance = 50 x 2 = 100 m
Total distance = 20 + 60 + 100 = 180
Total time= 1/2 + 3/4 + 2 = 3.25
Average speed of the car = 180/3.25 = 55.38
ANSWER:B
Question: A tourist purchased a total of $1,550 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
A.$1,430
B.$1,320
C.$1,290
D.$1,270
Answer: B.$1,320
Explanation: since total cashed checks = 7 ans $10 check cashed = one less or more than $50 checks
Therefore either $10 checks = 3 and $50 checks = 4 OR $10 checks = 4 and $50 checks = 3
using this information 1st option gives us the maximum cashed value therefore if we negate this value from total value we will get minimum value of which checks have lost
Therfore 1550 - 230 = 1320 hence answer is B
Question: Find the no.of ways of arranging the boy and 8 guests at a circular table so that the boy always sits in a particular seat?
A.5!
B.8!
C.9!
D.11!
Answer: B.8!
Explanation: Ans.(B)
Sol. Total number of persons = 9 Host can sit in a particular seat in one way. Now, remaining positions are defined relative to the host. Hence, the remaining can sit in 8 places in 8P8 = 8! Ways ... The number of required arrangements = 8! x 1= 8! = 8! ways
Question: A trader has 60 kg of rice, a part of which he sells at 14% profit and rest at 6% loss. On the whole his loss is 4% . What is the quantity sold at 14% profit and that at 6% loss?
A.6 and 54 kg
B.10 and 40 kg
C.15 and 35 kg
D.20 and 30 kg
Answer: A.6 and 54 kg
Explanation: Alligation Method
I PART II PART
14 (x1) -6 (x2)
\ /
x
/ \
(x2-x) (x-x1)
2 18
1 9
Ratio of quantities sold at 14% profit and 6% loss = 1: 9
Quantity sold at 14% profit = 60/1+9 *1 = 6 kg
Quantity sold at 6% loss = 60/1+9 *9 = 54kg
ANSWER:A
Question: Sum of products of three numbers taken two at a time is 131. Sum of squares of the three numbers is 138. What is the sum of the three numbers?
A.25
B.30
C.20
D.22
Answer: C.20
Explanation: Explanation:
All the data given in the question points to the equation mentioned below:
Considering the three numbers to be a,b and c:
(a+b+c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Accordingly, substitute for a, b and c and solve:
=> a2+b2+c2= 138, ab+bc+ac = 131. Thus, 2(ab+bc+ac)= 2*131= 262
(a+b+c)2= 138+262= 400.
Therefore, a+b+c= 20
ANSWER: C
Question: What annual payment will discharge a debt of Rs. 1025 due in 2 years at the rate of 5% compound interest?
A.Rs. 551.29
B.Rs. 551.25
C.Rs. 551.21
D.Rs. 551.22
Answer: B.Rs. 551.25
Explanation: Explanation:
Let each installment be Rs. x. Then,
x/(1 + 5/100) + x/(1 + 5/100)2 = 1025
820x + 1025 * 441
x = 551.25
So, value of each installment = Rs. 551.25
Answer:B
Question: P is a prime number. If 6p is between 15 and 95, which of the following Y can be a value of 7p + 2?
A.15
B.Y=79
C.121
D.65
Answer: B.Y=79
Explanation: [3,5,7,11,13] are prime numbers that fits this equation 15< 6X <95. Afterwards subtract 2 from all the answer n see if it's divisible by 7. Therefore A and E are out. Leaves out with B C D.
B =11
C =17
D = 9
Only 11 is the set of prime numbers that fit between 15 and 95. Therefore 79 is the answer.B
Question: If a trader sold two cars each at Rs. 325475 and gains 12% on the first and loses 12% on the second, then his profit or loss percent on the whole is?
A.1.44%
B.1.74%
C.1.84%
D.1.54%
Answer: A.1.44%
Explanation: SP of each car is Rs. 325475, he gains 12% on first car and losses 12% on second car.
In this case, there will be loss and percentage of loss is given by
= [(profit%)(loss%)]/100
= (12)(12)/100 % = 1.44%
Answer:A
Question: Peter rolls three dice at the same time. What is the probability that all the dices will show the same number?
A.a) 1/12
B.b) 1/36
C.c) 1/6
D.d) 1/36
Answer: D.d) 1/36
Explanation: We can have 6 different outcomes on a dice.
Total outcomes on two dices = 6*6*6 = 216
We need only the cases when Peter the same number with all the dices, that means only the outcomes in which the numbers on all three dices are same
They can be {1, 1, 1}, {2, 2, 2}, {3, 3, 3}, {4, 4, 4}, {5, 5, 5}, {6, 6, 6}.
A total of 6 outcomes
Probability = favorable outcomes/ total outcomes = 6/216 = 1/36.
Option D
Question: A man leaves a point P at 6 a.m. and reaches the point Q at 10 a.m. another man leaves the point give at 8 a.m. and reaches the point P at 12 noon. At what time do they meet?
A.7 a.m.
B.10 a.m.
C.9 a.m.
D.3 a.m.
Answer: C.9 a.m.
Explanation: Explanation:
9 a.m.
Answer: Option C