RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 45 liters and they are all empty, how much money total will it cost to fuel all cars?
A.320$
B.372$
C.420$
D.450$
Answer: B.372$
Explanation: Total Cost = ( 1.75*12 ) + ( 0.65 * 12 * 45 ) = 21 + 351 => 372
Hence answer will be (B) 372
Question: The point A and point B is 30 miles apart, the point B and point C is 25 miles apart. A car travels from point A to point B in 30 min and point B to point C in 40 min. What is the average speed of the car?
A.34.15
B.40.35
C.47.14
D.50.12
Answer: C.47.14
Explanation: Average speed=Total distance covered/Total time taken
=55miles/70min
=0.79miles/min
=47.14 miles/hour
Answer: C
Question: The L.C.M of two numbers is 2310 and their H.C.F is 30. If one number is 385 the Other is
A.180
B.300
C.270
D.250
Answer: A.180
Explanation: The other number
= L.C.M * H.C.F/given number
= 2310*30/385 = 180
Answer is A.
Question: If n is a positive integer, which of the following is a possible value of |46 - 5n| ?
A.7
B.2
C.11
D.15
Answer: C.11
Explanation: When 46>5n, then |46- 5n| = 46- 5n = (45-5n) + 1 = {multiple of 5} + 1
When 46<=5n, then |46- 5n| = -(46- 5n) = (5n-45) - 1 = {multiple of 5} - 1
So, the correct answer must be 1 greater or 1 less than a multiple of 5. Only C fits.
Answer: C
Question: The length of a train and that of a platform are equal. If with a speed of 54 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?
A.227
B.299
C.450
D.750
Answer: C.450
Explanation: Speed = [54 * 5/18] m/sec = 15 m/sec; Time = 1 min. = 60 sec.
Let the length of the train and that of the platform be x meters.
Then, 2x/60 = 15 è x = 15 * 60 / 2 = 450
Answer: C
Question: Sum of three numbers 286, If the first number be twice then second and third number be one third of the first, then the second number is
A.A)70
B.B)71
C.C)78
D.D)73
Answer: C.C)78
Explanation: Explanation:
Let the second number is x, then first is 2x, and third is 1/3(2x)
=>2x+x+2x/3=286
<=>11x/3=286
=>x=78
Answer: Option C
Question: Rony walks along Sunrise Boulevard daily. He starts walking at 07:00 from block 10 and walks to block 90 where he turns around and walks back to block 70, where he stops at 07:20. The blocks along the boulevard are numbered sequentially (1,2,3), and each block measures 35 meters. What is Rony's speed in meters per minute?
A.108
B.175
C.198
D.216
Answer: B.175
Explanation: Total distance from 10 to 90 =80 + from 90 to 70 =20
So the dist is 100×35(per block dist)
Speed = 3500mts/20min =175m/min
B is the answer
Question: Rs.1200 is divided so that 5 times the first share, 10 times the 2nd share and fifteen times third share amount to the same. What is the value of the second share?
A.s525
B.s527
C.s598
D.s400
Answer: D.s400
Explanation: A+B+C = 1200
5A = 10B = 15C = x
A:B:C = 1/5:1/10:1/15 =3:2:1
2/6 * 1200 =Rs 400
Answer:D
Question: Mohit sold an article for $12000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
A.16000
B.25000
C.10000
D.18000
Answer: C.10000
Explanation: Let the CP be $x.
Had he offered 10% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x = $1.08x = 12000 - 10/100(12000) = 12000 - 1200 = $10800
=> 1.08x = 10800
=> x = 10000
C
Question: A cab driver 5 days income was $250, $400, $750, $400 , $500. Then his average income is?
A.$440
B.$450
C.$460
D.$470
Answer: C.$460
Explanation: avg = sum of observations/number of observations
avg income=(250+400+750+400+500)/5 = 460
Answer is C
Question: The average weight of 25 persons sitting in a boat had some value. A new person added to them whose weight was 46 kg only. Due to his arrival, the average weight of all the persons decreased by 5 kg. Find the average weight of first 25 persons?
A.175
B.116
C.197
D.176
Answer: D.176
Explanation: 25x + 46
= 26(x – 5)
x = 176
Answer:D
Question: What is the next number of the following sequence.
3, 10, 13, 20, 23, 30,
A.28
B.29
C.30
D.33
Answer: D.33
Explanation: 3
3+7=10
10+3=13
13+7=20
20+3=23
23+7=30
30+3=33
ANSWER:D
Question: A regular square is inscribed in a circle. If A and B are adjacent vertices of the pentagon and O is the center of the circle, what is the value of ∠OAB ?
A.45 degrees
B.54 degrees
C.72 degrees
D.84 degrees
Answer: A.45 degrees
Explanation: its a regular square so divide the globe by 4.
= 360/4
= 90
90 would be the angle at O.
Angles at A and B are equivalent, so
90 + 2x = 180
2x = 90
x =45
Angles OAB and OBA will be 45 degrees each.
A
Question: 5 noun, 4 verbs and 3 adjectives are written on blackboard.we can form sentence by choosing 1 from each available set without caring it makes sense or not.what is the number of ways of doing this??
A.360
B.430
C.510
D.540
Answer: A.360
Explanation: we have to choose one from each set. 1 from 5 nouns and 1 from 4 verbs and 1 from 3 adjectives.
then we have to arrange 3 different sets in 3! ways.
so,
5c1*4c1*3c1*3!=360
ANSWER:A
Question: The Coen family consists of a father, a mother, two children and a dog. A photographer is about to take the family's picture. How many different arrangements (of standing in a row) does the photographer have, if it is known that the father insists of standing by his first child?
A.12
B.24
C.30
D.48
Answer: D.48
Explanation: We need to find the number of arrangements of Father, Mother, Child-1, Child-2, and a Dog, so that F and C1 are always together.
Consider F and C1 to be one unit, then we would have total of four units: {FC1}, {M}, {C2}, {D}. The number of arrangements of these four units is 4!, but F and C1 within their unit can be arranged in 2 ways: {FC1} or {C1F}, so total number of arrangements is 4!*2=48.
Answer: D.
Question: If x < y < z and y-x > 1, where x is an even integer and y and z are odd integers, what is the least possible value of z - x?
A.6
B.3
C.8
D.9
Answer: B.3
Explanation: We have:
1) x<y<z
2) y-x>1
3) x=2k (x is an even number)
4) y=2n+1 (y is an odd number)
5) z=2p+1 (z is an odd number)
6) z-x=? least value
z-x=2p+1-2k=2p-2k+1=2(p-k)+1 - that means that z-x must be an ODD number.
we are asked to find the least value, so we have to pick the least numbers
since y is odd and x is even, y-x must be odd. since y-x>1, the least value for y-x must be 3, the least value for x must be 2, and, thus, the least possible value for y must be 3 (y-2=1, y=3)
2<3<z, since z is odd, the least possible value for z is 5
z-x=5-2=3
Answer B
Question: A certain city with a population of 144,000 is to be divided into 11 voting districts , and no district is to have a population that is more than 10 percent greater than the population of any other district What is the minimum possible population that the least populated district could have ?
A.a) 10,700
B.b) 10,800
C.c) 10,900
D.d) 12,000
Answer: D.d) 12,000
Explanation: Let x = number of people in smallest district
x*1.1 = number of people in largest district
x will be minimised when the number of people in largest district is maximised
10*x*1.1 = 11x = total number of people in other districts
So we have 11x + x = 142k
x = 12,000
Answer : D
Question: 2, 6, 12, 20, 30, 42, 56, (...)
A.62
B.74
C.72
D.81
Answer: C.72
Explanation: The pattern is 1×2, 2×3, 3×4, 4×5, 5×6, 6×7, 7×8.
Hence, next number is 8×9 = 72
Answer is C
Question: In what ratio must water be mixed with milk to gain 1623% on selling the mixture at cost price?
A.6 : 1
B.1 : 6
C.1 : 4
D.4 : 1
Answer: B.1 : 6
Explanation: Explanation :
Let CP of 1 litre milk = Rs.1SP of 1 litre mixture = CP of 1 litre milk = Rs.1Gain=1623%=503%CP of 1 litre
mixture = 100(100+Gain%)×SP=100(100+503)×1=100(3503)=300350=67 By the rule of alligation, we
have
CP of 1 litre water CP of 1 litre milk
0 1
CP of 1 litre mixture
6/7
1 - 6/7 = 1/7 6/7 - 0 = 6/7
Quantity of water : Quantity of milk = 1/7 : 6/7 = 1 : 6
Answer : Option B
Question: Two mixers and one T.V. cost Rs. 7000, while two T.V.s and a mixer cost Rs, 9800. The value of one T.V. is:
A.Rs.4000
B.Rs.4500
C.Rs.4300
D.Rs.4200
Answer: D.Rs.4200
Explanation: Explanation :
Let C.P. of a mixer be Rs. x and that of a T.V. be Rs. y.
Then,
2x + y = 7000 and 2y + x = 9800.
Multiplying 2nd equatien by 2 and subtracting first from it, we get
3y = 19600 - 7000 = 12600
or
y = 4200 C.P. of a T.V. = Rs. 4200
Answer : D
Question: The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 40 percent of the pollutant?
A. $500,000
B. $100,000
C. $50,000
D. $10,000
Answer: A. $500,000
Explanation: To remove 90% of pollutant
C= 100,000(90)/(100-90) = 900,000
To remove 40% of pollutant
C' = 100,000(40)/(100-40) = 400,000
Difference = C - C' = 500,000
Answer - A
Question: The average age of a class of 12 students is 8 yrs. if the teacher's age is also included, the average increases by one year. Find the age of the teacher
A.30 Years
B.31 Years
C.21 Years
D.34 Years
Answer: C.21 Years
Explanation: Total age of students is 12X8 = 96 Years
Total age inclusive of teacher = 13X (8+1) = 117
So, Teacher's age is 117-96 = 21 Yrs
There is a shortcut for these type of problems
Teacher's age is 8+(13X1) = 21 Years
C
Question: A man counted his animals, 80 heads and 280 legs (ducks and goats). how many goats are there?
A.30
B.40
C.50
D.60
Answer: D.60
Explanation: let no of ducks=d and no of goat=g
d+g=80(heads)----------> eq 1
each duck has 2 legs and goat has 4 legs
2d+4g=240 and divide 2d+4g=240 by 2 we get d+2g=140 -----------> eq2
subtract eq1 from eq2
we get no of goats=60
ANSWER:D
Question: A fisherman sells 300 fish for Rs. 9000 at a profit of Rs. 6 per fish. Find his cost price for one metre of cloth?
A.24
B.36
C.30
D.18
Answer: A.24
Explanation: SP per fish = 9000/300 = Rs. 30 Profit per fish = Rs. 6 CP per metre = 30 - 6= Rs. 24Answer: A
Question: Pipe A can fill a tank in 6 hours, pipe B in 8 hours, and pipe C in 24 hours. If all the pipes are open, in how many hours will the tank be filled?
A.2.5
B.3
C.3.5
D.4
Answer: B.3
Explanation: The part filled by A + B + C in 1 hour
= 1/6 + 1/8 + 1/24
= 8/24 = 1/3
All the three pipes together will fill the tank in 3 hours.
The answer is B.
Question: If x is the reciprocal of a positive integer, then the maximum value of x^y, where y = –x^2, is achieved when x is the reciprocal of
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: Let's take answer C and try to substitute it in the task:
x=13
y=−(13)^2=−1/9
x^y=1/3−1/9
So x will be equal to ninth square root from 33.
And we can infer that maximum value will be when we take x=1 because then x^y will be equal to 1
Answer is A
Question: The area of an isosceles trapezoid with sides of length 5 and bases of length 9 and 15 is?
A.44
B.48
C.46
D.47
Answer: B.48
Explanation: Isosceles trapezoid indicates that if we draw perpendicular from two vertex of the smaller side, the longer side with side 15 will be divided into 3 parts= 9, 3 and 3 (Making one square and two right triangles)
For the right triangle, height will be= (5^2-3^2)^1/2= 4
And the area of trapezoid = 1/2 (B1+B2)H= 1/2*24*4= 48
B
Question: In what time will a train 200 m long cross an electric pole, it its speed be 144 km/hr?
A.5.0 sec
B.2.9 sec
C.1.3 sec
D.2.9 sec
Answer: A.5.0 sec
Explanation: Speed = 144 * 5/18
= 40 m/sec
Time taken = 200/40
= 5.0 sec.
Answer:A
Question: There are between 90 and 100 cards in a collection of cards. If they are counted out 3 at a time, there is 1 left over, but if they are counted out 4 at a time, there is 1 left over. How many cards are in the collection?
A.91
B.93
C.95
D.97
Answer: D.97
Explanation: The numbers with the form 4n+1 are 93 and 97.
Only 97 has the form 3k+1.
The answer is D.
Question: A man can row a boat at 25 kmph in still water. If the speed of the stream is 5 kmph, what is the time taken to row a distance of 50 km downstream?
A.1/2
B.4/3
C.2/3
D.5/3
Answer: D.5/3
Explanation: Speed downstream = 25 + 5 = 30 kmph.
Time required to cover 50 km downstream = d/s = 50/30
= 5/3 hours.
Answer: D
Question: The Salary of an employee increase consistently by 15% per year. If his present salary is Rs. 24000 then what will his salary be after 3 years ?
A.Rs. 32497
B.Rs. 34384
C.Rs. 35065
D.Rs. 36501
Answer: D.Rs. 36501
Explanation: Explanation :
Salary = 24000 x 1.15 x 1.15 x 1.15 = 36501
Answer : Option D
Question: From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first is a red card and the second is a king is
A.1/26
B.1/25
C.1/20
D.1/21
Answer: A.1/26
Explanation: Let E1 be the event of drawing a red card.
Let E2 be the event of drawing a king .
P(E1 ∩ E2) = P(E1) . P(E2)
(As E1 and E2 are independent)
= 1/2 * 1/13 = 1/26.
Answer: A
Question: In how many ways can two members be selected from a group of ten members?
A.10C2
B.10C8
C.10C4
D.10C3
Answer: A.10C2
Explanation: two members can be selected from ten members in
10C6
= 10C2 ways.
Answer: A
Question: In a survey conducted to find out the readership of three Newspapers A,B and C, it was found that the number of newspaper A is at least 20 and at most 40. The number of people who read newspaper B is at least 50 and at most 70. The number of people who read newspaper C is at least 70 and at most 83. It was also found that 7 people read all three newspapers. Find the minimum number of people who read both A and B but not C.
A.A)1
B.B)2
C.C)3
D.D)0
Answer: A.A)1
Explanation: I wish I could draw a diagram to show you but by giving you number A and B, it might help a little.
A and B and C is 7 - that means A and B is at least 7. This seems trivial given the value intervals of A and B but definitely helps to think through how to minimize A and B but not C
A and B but not C = |A|-|B| - 7
So i would pick A=35 and B =50 to minimize the value to a 1. (ANS A)
Question: A is 1.5 times as fast as B. A alone can do the work in 30 days. If A and B work on alternative days, beginning with A, in how many days will the work be completed?
A.23
B.22
C.21
D.36
Answer: D.36
Explanation: A can finish 1 work in 30 days
B can finish 1/1.5 work in 30 days - since A is 1.5 faster than B
This means
B can finish 1 work in 30*1.5 days = 45 days
Now using the awesome GMAT formula when two machines work together they can finish the job in = AB/ (A+B) = 45*30/(45+30) = 20*30/50 = 18 days
Since they alternate on days, it will take them double this time so total time = 18 * 2 = 36 days
So answer is D
Question: An apple orchard grows red and green apples. On the first day of harvest, 496 apples are collected. There are three times as many red apples as there are green apples. How many green apples were harvested?
A.99
B.112
C.118
D.124
Answer: D.124
Explanation: Let x be the number of green apples.
There were 496 total apples; there are three times as many red apples as green apples. Therefore,
x + 3x = 496
4x = 496
x = 124
Answer: D
Question: If A's height is 45% less than that of B, how much percent B's height is more than that of A?
A.66.66%
B.81.81%
C.66.766%
D.86.66%
Answer: B.81.81%
Explanation: Excess of B's height over A's = [(45/(100 - 45)] x 100%
= 81.81%
Answer: B)
Question: A and B’s salaries together amount to Rs. 2,000. A spends 95% of his salary and B spends 85% of his. If now their savings are the same, what is A’s salary?
A.Rs.500
B.Rs.750
C.Rs.1250
D.Rs.1500
Answer: D.Rs.1500
Explanation: (5/100) A = (15/100) B
A = 3B
A + B = 2000
4B = 2000 => B = 500
A = 1500
ANSWER:D
Question: If money is invested at r percent interest, compounded annually, the amount of the investment will double in approximately 50/r years. If Luke's parents invested $12,500 in a long term bond that pays 12 percent interest compounded annually, what will be the approximate total amount of the investment 12 years later, when Luke is ready for college?
A.62,000
B.85,500
C.95,500
D.100,500
Answer: A.62,000
Explanation: Since investment doubles in 70/r years then for r=8 it'll double in 70/8=~9 years (we are not asked about the exact amount so such an approximation will do). Thus in 18 years investment will double twice and become ($5,000*2)*2=$20,000 (after 9 years investment will become $5,000*2=$10,000 and in another 9 years it'll become $10,000*2=$20,000).
Answer: A.
Question: The value of ((x – y)³ + (y - z)³ + (z – x)³)/(18 (x – y) (y – z) (z – x))
is equal to :
A.0
B.1/6
C.1
D.1/4
Answer: B.1/6
Explanation: Since (x – y) + (y – z) + (z – x) = 0,
so (x – y)³ + (y – z)³ + (z – x)³= 3 (x – y) (y – z) (z – x).
(3 (x – y) (y – z) (z – x))/(18(x – y) (y – z) (z – x)) = 1/6.
ANSWER:B
Question: If mn > 0, which of the following must be negative?
A.2m+n
B.2m/n
C.m/n
D.-2mn
Answer: D.-2mn
Explanation: - * + = -
Answer : D
Question: There are 2 sections A and B in a class, consisting of 50 and 40 students respectively. If the average weight of section A is 50kg and that of section B is 70kg, Find the average of the whole class?
A.50.78kg
B.49.32kg
C.61.67kg
D.58.88kg
Answer: D.58.88kg
Explanation: Total weight of 50+40 students = 50*50 + 40*70 = 2500+2800
Average weight of the class is = 5300/90 = 58.88 kg
Answer is D
Question: A reading list for a certain course consists of 10 books, of which 4 are poems and the rest are novels. Each student is required to read a selection of 3 books from the list, including at most 2 novels. How many selections of 3 books satisfy the requirements?
A.40
B.115
C.130
D.144
Answer: A.40
Explanation: Ans: B
Solution: Selection requires at most 2 novels, means=
0N4P + 1N3P + 2N2P
6c0*4c3+ 6c1*4c2
= 4+ 36
= 40
Ans: A
Question: In a bowl, the number of marbles gets doubled after every minute. If the bowl gets filled after two hours of such process, how long do you think it will take for it to be half filled.
A.1 hour and 59 minutes
B.2 hour and 59 minutes
C.4 hour and 59 minutes
D.4 hour and 59 minutes
Answer: A.1 hour and 59 minutes
Explanation: Solution:
The correct way to solve this question is go backwards. If the number of marble gets doubled every minute and after two hours, it is filled completely, one minute ago it would be half.
So, it will take 1 hour and 59 minutes for it to be filled half.
Answer A
Question: R is an even integer greater than 300,000 and smaller than 1,000,000. How many numbers can R be?
A.300,000
B.349,999
C.350,000
D.399,999
Answer: B.349,999
Explanation: R 1,000,000-300,000=700,000 integers
700,000/2= 350,000 even integers.
350,000+1 inclusive. But since 1,000,000 and 300,000 are not included.
350,001-2=349,999
B
Question: Four different children have jelly beans: Aaron has 5, Bianca has 7, Callie has 8, and Dante has 13. How many jelly beans must Dante give to Aaron to ensure that no child has more than 1 fewer jelly beans than any other child?
A. 2
B. 3
C. 4
D. 5
Answer: D. 5
Explanation: Since Bianca and Callie are both within 1 jelly bean of each other and Aaron has 5, Dante must provide 3 of his 13 jelly beans so each child has no more than 1 fewer jelly bean than any other child.
Dante + Aaron = 13+5 =18/2 = 9
13-8 = 5 so Dante must provide 5 jelly beans to Aaron.
Answer (D)
Question: A car covers a distance of 540 km in10 hrs. What is its speed in mps.
A.40 m/s
B.25 m/s
C.20 m/s
D.15 m/s
Answer: D.15 m/s
Explanation: Explanation:
Distance = Speed x Time
Speed = (540/10) = 54 kmph
Spees in mps = 54 x 5/18 = 3 x 5 = 15 mps.
Answer: Option D
Question: How many such three letter passwords can exist?
A.216
B.26C6 *3
C.(26C6)^3
D.((26C6)^3) *63
Answer: D.((26C6)^3) *63
Explanation: 1st ring: 6 out of 26 alphabets can be selected in 26C6 ways.
And is for 2nd and 3rd ring.
Also, these 3 set of 6 letters can be arranged amongst themselves in 63 ways.
Hence, total number of 3 letter passwords = 26C6 * 26C6 *26C6 *63 ways.
ANSWER:D
Question: What amount does Kiran get if he invests Rs. 18000 at 12% p.a. simple interest for four years?
A.29893
B.26640
C.29989
D.28800
Answer: B.26640
Explanation: Simple interest = (18000 * 4 * 12)/100 = Rs. 8640
Amount = P + I = 18000 + 8640 = Rs. 26640
Answer: B
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 72 kmph. In how much time will the trains cross each other?
A.80/6 sec
B.80/7 sec
C.88/7 sec
D.80/9 sec
Answer: B.80/7 sec
Explanation: Relative speed = (54 + 72)* 5/18 = 7 * 5 = 35 mps.
The time required = d/s = (100 + 100 + 200)/35
= 400/35
=80/7 sec.
Answer:B
Question: A man spends Rs. 1600 per month on an average for the first three months, Rs 1550 for next four months and Rs. 1800 per month for the last five months and saves Rs . 4120 a year. What is his average monthly income?
A.2000
B.2010
C.2100
D.2200
Answer: B.2010
Explanation: Total expenditure for the first 3 months = 3 × 1600 = 4800
Total expenditure for 4 months = 4 × 1550 = 6200
Total expenditure for 5 months = 5 × 1800 = 9000
Total expenditure and saving (which is income for one year)
= 4800 + 6200 + 9000 + 4120 = Rs. 24120
So, Average monthly income = 24120/12 = Rs. 2010
B
Question: The Square of a Positive Number A is divided by 2 and then the Result is Multiplied by 4 if the result is equal to A * 8 then what is the value of A?
A.4
B.9
C.6
D.3
Answer: A.4
Explanation: (A*A)/2*4= 2(A*A)
2(A*A)=8A
2A=8
So the Correct Answer is 4
Question: If w,x,y,z are consecutive positive integers ; then which of the following is always odd?
[1] w*x+(y+2)^2*z
[2] w^x + z^y
[3] 2w^3
A.2
B.2
C.3
D.1 and 2
Answer: A.2
Explanation: Plug in some numbers
w = 1
x = 2
y = 3
z = 4
Check the options -
[1] w*x+(y+2)^2*z = 1*2 + (3+2)^2 * 4 => 2 + 25*4 = 102{ Not an odd Number }
[2] w^x + z^y = 1^2 + 4^3 => 1 + 64 = 65{ Odd number }
3 2w^3 = 2*1^3 = even
2
A
Question: What is the unit digit in {pow(2114,563) x pow(425,213) x pow(3371,67)}?
A.0
B.2
C.3
D.5
Answer: A.0
Explanation: Solution
Unit digit in pow((2114, 563)
= Unit digit in pow(4,563)
= Unit digit in [pow(pow(4,2),281) x 4]
= Unit digit in (6 x 4)
= 4 Unit digit in pow(425,213)
= Unit digit in pow(5,213)
= 5 Unit digit in pow(3371,67)
= Unit digit in pow(1,67) = 1
Required digit = Unit digit in (4 x 5 x 1) = 0.
Answer A
Question: A and B can do a piece of work in 3 days. With the help of C they finish the work in 2 days. C alone can do that piece of work in?
A.6 DAYS
B.5 DAYS
C.4 DAYS
D.3 DAYS
Answer: A.6 DAYS
Explanation: C = 1/2 – 1/3= 1/6 => 6 days
Answer:A
Question: Manoj borrowed Rs.3600 from Anwar at 6% p.a. simple interest for three years. He then added some more money to the borrowed sum and lent it to Ramu for the same time at 9% p.a. simple interest. If Manoj gains Rs.824.85 by way of interest on the borrowed sum as well as his own amount from the whole transaction, then what is the sum lent by him to Ramu?
A.22877
B.5455
C.2778
D.6787
Answer: B.5455
Explanation: Let the sum lent by Manoj to Ramu be Rs.P.
Amount gained by Manoj = P. 3.9 /100 = 3600.3.6/100 = Rs.824.85
27P = 64800 = 82485
P = (82485 + 64800)/27 = 3055 + 2400 = Rs.5455
Answer: B
Question: Four friends (A, B, C and D) started a business in partnership by investing capitals in the proportion 3 : 5 : 4 : 6. During the period of one-year, these capitals were utilized in the proportion of 6 : 4 : 5 : 3 respectively. If, at the end of the year, a profit of Rs. 15,550 was made, what will be the share of D?
A.3682.89
B.3682.87
C.3682.81
D.3682.82
Answer: A.3682.89
Explanation: Explanation:
A = (Investment * capital utilized) = (3 * 6) = 18
B = (5 * 4) = 20
C = (4 * 5) = 20
D = (6 * 3) = 18
Thus, out of Rs. 76 (18 +20 + 20 + 18), D's share is Rs. 18. Hence, out of Rs. 15,500 the share of D would be given as (18/76) * 15550 = Rs. 3682.89
ANSWER: A
Question: In each term of a sequence, 15 is added to get the next term. If the first term is 10, what is the eighty-first term?
A. 1630
B. 1210
C. 1110
D. 1720
Answer: B. 1210
Explanation: 1rst term + 80 terms = 10 + 15+15+15+15+15+15+15+...+15 (80 times)
10 + (15 x 80) = 10 + 1200 = 1210
Answer B