RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Find the greatest number that will divide 256, 193 and 210 leaving 6, 18 and 100 as remainders respectively
A.19
B.25
C.23
D.20
Answer: B.25
Explanation: Explanation:
Answer will be HCF of (256-6, 193-18, 210-10)
HCF of (250, 175, 200) = 25
Option B
Question: A bag contains 12 white and 18 black balls. 2balls are drawn in succession. What is the probability that first is white and second is black?
A.31/145
B.36/145
C.21/141
D.23/121
Answer: B.36/145
Explanation: The probability that first ball is white:
=12C130C1=12C130C1
=1230=1230
=25=25
Since, the ball is not replaced; hence the number of balls left in bag is 29.
Hence, the probability the second ball is black:
=18C129C1=18C129C1
=1829=1829
Required probability,
=(25)×(1829)=(25)×(1829)
=36/145
B
Question: Two pipes P and Q can fill a cistern in 12 and 15 minutes respectively. Both are opened together, but at the end of 3 minutes the first is turned off. How much longer will the cistern take to fill?
A.11 1/0
B.11 1/4
C.11 1/2
D.11 1/1
Answer: B.11 1/4
Explanation: 3/12 + x/15 = 1
x= 11 1/4
Answer:B
Question: A train speeds past a pole in 10 seconds and a platform 150 m long in 25 seconds. Its length is:
A.300 m.
B.250 m.
C.100 m.
D.200 m.
Answer: C.100 m.
Explanation: Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 10=> y = x/10
x + 150 / 25 = x / 10
x = 100 m.
Answer: Option C
Question: In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 58 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake?
A.57
B.2^4*3
C.24
D.38
Answer: A.57
Explanation: So 57 days
Answer A=57
Question: Cindy paddles her kayak upstream at a kilometers per hour, and then returns downstream the same distance at n kilometers per hour. How many kilometers upstream did she travel if she spent a total of p hours for the round trip?
A.mnp
B.an/p
C.(a + n)/p
D.anp/(a + n)
Answer: D.anp/(a + n)
Explanation: let t1 and t2 be the time taken to row upstream and downstream respectively
now,
t1=distance/speed=d/a
similarly,
t2=d/n (as same distance has to be rowed)
also,
t1+t2=p
therefore,
p=(d/a)+(d/n)
=d(a+n)/an
d=pan/(a+n)=D
Question: What number comes next in the following series? 4, 13, 40, 121, 364, x
A.1093
B.1100
C.1301
D.1400
Answer: A.1093
Explanation: 44 × 3 + 1 = 1313 × 3 + 1 = 4040 × 3 + 1 = 121121 × 3 + 1 = 364364 × 3 + 1 = 1093 A
Question: A train travels from station A to station B. If it travels at a speed of 100 miles per hour, it ends up reaching the station 30 minutes late. If it travels at 150 miles per hour, it reaches the station 15 minutes early. What is the amount of time that the train is scheduled to take for the journey and what is the distance between the stations?
A.	1.75 hours, 225 miles
B.	3 hours, 350 miles
C.	4 hours, 450 miles
D.	5 hours, 550 miles
Answer: A.	1.75 hours, 225 miles
Explanation: Let t be the usual time and x be the distance between AB. So we need to find t and Distance x. The question gives us 2 combinations of speedtime, but the distance remains the same for both condition.
Equation 1 - x= 100 (t+.5) (converted 30 mins into hr) added .5 hrs because it is late or took more time than usual.
Equation 2 - x= 150 (t-.25) subtracted .25 hrs because it is early or took less time than usual.
Now equating 12 we get 100(t+.5)=150(t-.25)
=> 10t +5 = 15t - 3.75
=> 5t=8.75 => t= 1.75 hrs.
Hence x= 100(1.75+.5) =>100 X 2.25 => 225 miles.
Hence correct answer A
Question: What is his percentage profit made by Elvis if he purchased 25 dozen belts at Rs. 35 per dozen. He sold 10 dozens at 15% profit and the remaining 15 dozens with 16% profit?
A.18%
B.12%
C.16%
D.15%
Answer: A.18%
Explanation: Explanation :
C.P of 25 dozen = Rs.(35 x 25) = Rs.875
C.P of 10 dozen = Rs. (35 x10) = Rs. 350.
C.P of 15 dozen =Rs. (35 x15) = Rs. 525
profit on 10 dozen at 15% = 15/100*350 = 52.5
profit on 15 remaining dozen at 20% = 20/100*525 = 105
total profit = 52.5 + 105 = 157.5
% profit = ?/100*875 = 157.5
= 18%
Answer : A
Question: A 250 meter long train crosses a platform in 40 seconds while it crosses a signal pole in 20 seconds. What is the length of the platform?
A.500
B.1000
C.350
D.250
Answer: D.250
Explanation: Speed = [250 / 20] m/sec =25/2 m/sec.
Let the length of the platform be x meters.
Then, x + 250 /40 = 25/2
2(x + 250) = 1000 è x = 250m. Answer: D
Question: If the price of petrol increases by 40, by how much must a user cut down his consumption so that his expenditure on petrol remains constant?
A.25%
B.20%
C.16.67%
D.28.6%
Answer: D.28.6%
Explanation: Explanation :
let us assume before increase the petrol will be Rs. 100.
After increase it will be Rs (100+40) i.e 140.
Now, his consumption should be reduced to :-
=(140−100)/140 ∗ 100.
Hence, the consumption should be reduced to 28.6%.
Answer : D
Question: Current age of Bruce and Tomy r in the ratio of 5:4 respectively. 3 years hence, the ratio of their ages will become 11:9 respectively. What is Tomy 's present age in years?
A.20 years
B.21 years
C.24 years
D.27 years
Answer: C.24 years
Explanation: Let the present ages of Bruce and Tomy be 5x years and 4x years respectively.
Then,	5x + 3	=	11
4x + 3	9
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x - 44x = 33 - 27
x = 6.
Anand's present age = 4x = 24 years.
C
Question: On increasing the price of T.V. sets by 70%, their sale decreases by 20%. What is the effect on the revenue receipts of the shop ?
A.4
B.5
C.36
D.2
Answer: C.36
Explanation: Explanation:
Let the price be = Rs.100, and number of units sold = 100
Then, sale value = Rs.(100 × 100) = Rs.10000
New sale value = Rs.(170 × 80) = Rs.13600
Increase% = 3600/10000 × 100 = 36%
Answer: C
Question: How many times digit 7 is used while writing numbers from 1 to 300?
A.28
B.42
C.41
D.35
Answer: B.42
Explanation: in 1 to 100 their are 14 seven's
in 100 to 200 their are 14 seven's
in 200 to 300 their are 14 seven's
so total answer is 42 seven's
CORRECT OPTION :B
Question: Paul has to secure 50% marks to clear his exam of class 7th.
He got 50 marks and failed by 10 marks.
What is the maximum marks ?
A.100
B.110
C.120
D.210
Answer: C.120
Explanation: C
120
To pass the exam ravish needs 50 + 10 = 60 marks.
=> (60/50) *100 = 120
Question: A furniture dealer purchased a desk for $240 and then set the selling price equal to the purchase price plus a markup that was 40% of the selling price. If the dealer sold the desk at the selling price, what was the amount of the dealer's gross profit from the purchase and the sale of the desk?
A.$40
B.$60
C.$160
D.$90
Answer: C.$160
Explanation: Purchase price = 240
Selling price = x
240 + 0.4*x = x
0.6*x = 240
x = 400
Profit = 400 - 240 = 160
ANSWER:C
Question: A man is 30 years older than his son. In three years, his age will be twice the age of his son. The present age of his son is:
A.20
B.21
C.27
D.23
Answer: C.27
Explanation: Let the son's present age be x years. Then, man's present age = (x + 30) years.
(x + 30) + 3 = 2(x + 3)
x + 33 = 2x + 6
x = 27.
Answer:C
Question: If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is?
A.1878
B.2890
C.2789
D.8112
Answer: D.8112
Explanation: A = 7500(26/25)2
= 8112
Answer:D
Question: A train 200m long passes a standing man in 12 seconds. What is the speed of the train?
A.30km/hr
B.36km/hr
C.42km/hr
D.60km/hr
Answer: D.60km/hr
Explanation: Speed of the train = 200/12* 18/5 = 60km/hr
Answer is D
Question: How many two-digit whole numbers yield a remainder of 1 when divided by 10 and also yield a remainder of 1 when divided by 6?
A.None
B.One
C.Two
D.Three
Answer: D.Three
Explanation: The possible number N can be written as follow:
N = Multiple of LCM(6,10) + 1st such number
N = 30x + 1
Possible values = 1, 31, 61, 91
Answer : 3 such 2 digit number.
ANSWER:D
Question: If six persons sit in a row, then the probability that three particular persons are always together is ?
A.1/5
B.2/8
C.1/6
D.1/7
Answer: C.1/6
Explanation: Six persons can be arranged in a row in 6! ways. Treat the three persons to sit together as one unit then there four persons and they can be arranged in 4! ways. Again three persons can be arranged among them selves in 3! ways. Favourable outcomes = 3!4! Required probability
= 3!4!/6!
= 1/5
Answer: C
Question: A can do a piece of work in 14 days which B alone can do in 21 days. They begin together but 3 days before the completion of the work, A leaves off. The total number of days for the work to be completed is
A.6 3/5 days
B.8 ½ days
C.10 1/5 days
D.13 ½ days
Answer: C.10 1/5 days
Explanation: Explanation:
B’s 1 day’s work = 1/21
B’s 3 day’s work = 1/21 ×3 = 1/7
The remaining work finished by both of them = 1 – 1/7 = 6/7
Both together can finish it in 14 × 21/35 days = 42/5 days
Their, 1 day’s work = 5/42
Therefore, the No. of days taken by them together to finish 6/7 work
= 6/7/5/42 = 6/7 × 42/5 = 36/5 = 7 1/5 days
Therefore, the total No. of days for the work to be completed = 3 + 7 1/5 = 10 1/5 days.
Answer: Option C
Question: The ratio of two quantities is 5 to 6. If each of the quantities are doubled, what is the ratio of these 2 new quantities?
A.5:6
B.10:12
C.20:24
D.5:12
Answer: A.5:6
Explanation: If both sides of a ratio are multiplied by the same number there is no change in the ratio.
5:6 means 5x:6x...
So when you double, 5(1): 6(1) becomes 5(2): 6(2)..
So if the Xs are equal the ratio does not change..
ANSWER:A
Question: What should be the least number to be added to the 11002 number to make it divisible by 11?
A.12
B.9
C.18
D.77
Answer: B.9
Explanation: Answer : 9
Option : B
Question: The average weight of 24 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.
A.48.975
B.42.255
C.50
D.51.255
Answer: A.48.975
Explanation: Explanation:
Average weight of 24 boys = 50.25
Total weight of 24 boys = 50.25 × 24
Average weight of remaining 8 boys = 45.15
Total weight of remaining 8 boys = 45.15 × 8
Total weight of all boys in the class = (50.25 × 24)+ (45.15 × 8)
Total boys = 24 + 8 = 32
Average weight of all the boys = (50.25×24)+(45.15×8)/32
=48.975
Answer: Option A
Question: x, a, z, and b are single digit positive integers. x = a/3. z = b/3. (10a + b) – (10x + z) could NOT equal
A.33
B.22
C.54
D.78
Answer: A.33
Explanation: 1) firstly we are not given that all are different integers..
2) since each is a positive single digit integer and x=a/3... Z=b/3
so in (10a + b) – (10x + z) ..
10a+b can be
33,66,99,132..
10x+z can be
11,12,21,22..
ans A
Question: The ages of 2 boys differ by 16 yrs. 6 yrs ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder boy?
A.10
B.20
C.30
D.40
Answer: C.30
Explanation: Let present age of the elder person =x and
present age of the younger person =x−16
(x−6)=3(x−16−6)⇒x−6=3x−66⇒2x=60⇒x=602=30
C
Question: A train traveling at 100 kmph overtakes a motorbike traveling at 64 kmph in 20 seconds. What is the length of the train in meters?
A.400 meters
B.1111 meters
C.1777 meters
D.200 meters
Answer: D.200 meters
Explanation: Train overtakes a bike means that we are talking about total length of the train. (train's head is close to bike when it started and its tail crosses the bike when it overtakes the bike)
Relative speed= 100-64= 36Km/h = 36000 m/h
time= 20 seconds
Distance= speed*time
36000* 20/3600= 200 meters.
D is the answer.
Question: By selling 90 pens, a trader gains the cost of 15 pens. Find his gain percentage?
A.16.66%
B.17.66%
C.18.66%
D.19.66%
Answer: A.16.66%
Explanation: Let the CP of each pen be Rs. 1.
CP of 90 pens = Rs. 90
Profit = Cost of 15 pens = Rs. 15
Profit% = 15/90 * 100 = 16.66%
Answer:A
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 7 kmph, what is the time taken to row a distance of 60 km downstream?
A.30/18 hours
B.37/13 hours
C.80/13 hours
D.20/9 hours
Answer: D.20/9 hours
Explanation: Speed downstream = 20 + 7 = 27 kmph.
Time required to cover 60 km downstream
= d/s = 60/27
= 20/9 hours.
Answer: D
Question: In a can, there is a mixture of milk and water in the ratio 4:3. If the can is filled with an additional 10 liters of milk, the can would be full and the ratio of milk and water would become 5:2. Find the capacity of the can?
A.24
B.26
C.28
D.30
Answer: D.30
Explanation: Let C be the capacity of the can.
(4/7)*(C-10)+10=(5/7)*C
4C-40+70=5C
C=30
The answer is D.
Question: The effective annual rate of interest corresponding to a nominal rate of 10% per annum payable half-yearly is?
A.10.06%
B.10.25%
C.10.35%
D.16.09%
Answer: B.10.25%
Explanation: Amount of Rs. 100 for 1 year when compounded half-yearly = [100 * (1 + 5/100)2] = Rs. 110.25 Effective rate = (110.25 - 100) = 10.25%
ANSWER:B
Question: A does half as much work as B in three-fourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it
A.40days
B.35days
C.30days
D.25days
Answer: C.30days
Explanation: Explanation:
Suppose B takes x dáys to do the work.
As per question A will take
2∗3 /4∗x=3x /2days
(A+B)s 1 days work= 1/18
1/x + 2/3x = 1/18 or x = 30 days
Option C
Question: If a quarter kg of potato costs 60 paise, how many paise will 200gm cost ?
A.45 paise
B.46 paise
C.47 paise
D.48 paise
Answer: D.48 paise
Explanation: Explanation:
Quarter of Kg means 250 gm
Less weight, less price (Direct Proportion)
So,
250:200::60:x=>x=200∗60/ 250=>x=48
So 200 gm will cost 48 paise.
Option D
Question: Find the odd man out. 15, 25, 30, 51, 85, 90, 115
A.15
B.25
C.51
D.90
Answer: C.51
Explanation: Explanation :
All except 51 are multiples of 5. Answer : Option C
Question: Find the area of a parallelogram with base 12 cm and height 48 cm?
A.122 cm2
B.576 cm2
C.246 cm2
D.42 cm2
Answer: B.576 cm2
Explanation: Area of a parallelogram
= base * height
= 12 * 48
= 576 cm2
Answer: B
Question: lexus car agency has 216 cars.he sold some cars at 9% profit and rest at 36% profit thus he gains 17% on the sale of all his cars.the no. of cars sold at 36% profit is?
A.36
B.64
C.38
D.39
Answer: B.64
Explanation: ratio of 36% profit cars to 9% profit cars = 8:19
so no. of cars sold at 36% profit = 216*8/27= 64 cars
ANSWER:B
Question: Bill made a profit of 10% by selling a product. If he had purchased that product for 10% less and sold it at a profit of 30%, he would have received $ 63 more. What was his original selling price?
A. $770
B. $660
C. $700
D. $990
Answer: D. $990
Explanation: Let the original purchase price be X
So original selling price at 10% profit = 1.1X
If product is purchased at 10% less of original = 0.9X
Profit of 30% on this price = 1.3(0.9X)
He would have received $63 more in second scenario => 1.3(0.9X) - 1.1X = 63
=> 0.07X = 63
=> X = $900
Original purchase price = $900
Hence, original selling price (at 10% of profit) = 1.1(900) = $990
Option D
Question: Joe needs to paint all the airplane hangars at the airport, so he buys 360 gallons of paint to do the job. During the first week, he uses 1/2 of all the paint. During the second week, he uses 1/5 of the remaining paint. How many gallons of paint has Joe used?
A.18
B.144
C.175
D.216
Answer: D.216
Explanation: Total paint initially = 360 gallons
Paint used in the first week = (1/2)*360 = 180 gallons.
Remaning paint = 180 gallons
Paint used in the second week = (1/5)*180 = 36 gallons
Total paint used = 216 gallons.
Option D
Question: For dinner, Sue ate 360 grams of fruit which was five times as much fruit as she ate for lunch, and three times as much fruit as she ate for breakfast. How much fruit did Sue eat in total?
A.552
B.560
C.568
D.576
Answer: A.552
Explanation: For breakfast, Sue ate 360 / 3 = 120 grams.
For lunch, Sue ate 360 / 5 = 72 grams.
For dinner, Sue ate 360 grams.
The total is 120 + 72 + 360 = 552 grams.
The answer is A.
Question: 60 percent of Andrea's living room floor is covered by a carpet that is 4 feet by 9 feet. What is the area of her living room floor?
A.14.4
B.180/7
C.50.4
D.60
Answer: D.60
Explanation: 60% of Area of the floor = 4*9 square feet = 36 square feet
i.e. 100% Area of Floor = (36/60)*100 = 60 square feet
Answer: Option D
Question: If a wagon wheel had 10 more spokes, the angle between them would decrease by 6 degrees. Can you identify the number of spokes in the wheel?
A.20 spokes
B.10 spokes
C.30 spokes
D.15 spokes
Answer: A.20 spokes
Explanation: A
20 spokes
360/S = A
360/(S +10) = A – 6
Thus there are 20 spokes in the wheel.
Question: (5!+6!+4!)/4!*0!*5*6=?
A.4/5
B.6/5
C.5/6
D.4/3
Answer: B.6/5
Explanation: 4!(5+30+1)/4!*1*5*6
36/30=6/5
answer B
Question: If (1 – 1.5)N = 1, then N =
A. −400
B. −140
C. −2
D. 4
Answer: C. −2
Explanation: (1 – 1.5)N = 1
Simplify to get: -0.5N = 1
Rewrite as (-1/2)N = 1
Multiply both sides by -2 to get: N = -2
Answer: C
Question: Aman started a business investing Rs. 70,000. Rakhi joined him after six months with an amount of Rs.. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business?
A.7 : 6 : 10
B.12 : 15 : 16
C.42 : 45 : 56
D.12 : 18 : 26
Answer: B.12 : 15 : 16
Explanation: Aman : Rakhi : Sagar =(70,000 x 36):(1,05,000 x 30):(1,40,000 x 24) = 12 : 15 : 16.
Answer: Option B
Question: A can do a piece of work in 80 days. He works at it for 10 days & then B alone finishes the remaining work in 42 days. In how much time will A and B, working together, finish the work?
A.23 days
B.25 days
C.30 days
D.33 days
Answer: C.30 days
Explanation: Work done by A in 10 days=10/80=1/8
Remaining work=(1-(1/8))=7/8
Now, work will be done by B in 42 days.
Whole work will be done by B in (42*8/7)=48 days
Therefore, A's one day's work=1/80
B’s one day's work=1/48
(A+B)'s one day's work=1/80+1/48=8/240=1/30
Hence, both will finish the work in 30 days.
Answer : C.
Question: A thief steals at a car at 2.30 p.m. and drives it at 60 km/hr. The theft is discovered at 3 p.m. and the owner sets off in another car at 75 km/hr. When will he overtake the thief?
A.2 p.m
B.6 p.m
C.5 p.m
D.7 p.m
Answer: C.5 p.m
Explanation: Suppose the thief is overtaken x hrs after 2.30 p.m.
Then, distance covered by the owner in (x - 1/2) hrs.
60x = 75(x - 1/2) => x = 5/2 hrs.
So, the thief is overtaken at 5 p.m.
Answer:C
Question: X and Y run a 200 m race,where X beats Y by 20 m. To do a favor to Y, X starts 20 m behind the starting line in a second 200 m race. Both run at the same previous speed. Which of the following is true?
A.X Beats Y by 2m
B.Y Beats X by 10m
C.Y Beats X by 11m
D.Y Beats X by 1m
Answer: A.X Beats Y by 2m
Explanation: Let's suppose that the speed of X is 20m/s and that the speed of Y is 18m/s.
So, in the first race, the results are the following:
X crosses the finish line in 10s. In other words, X has run 200m in 10 s.
In 10s, Y has run 180 meters.
Therefore, there is the difference of 20 meters mentioned in the question.
Now, let's review the second race.
In 11 seconds, X can complete the 200 meters race. We have to remember that X is 20 meters behind the starting line.
But in 11 seconds, Y has covered (180+18) =198 meters. Also, it is important to notice that in 11 seconds Y cannot arrive to the finish line.
So, 200 - 198 = 2 meter
Answer: A
Question: Tough and Tricky questions: Combinations.
The product of the digits of the four-digit number h is 48. No two digits of h are identical. How many different numbers are possible values of h?
A.6
B.12
C.24
D.36
Answer: C.24
Explanation: Answer = C = 24
Let number =abcd
Given that a*b*c*d = 48
a,b,c,d can be 1,2,3,8
Number of ways = 4*3*2 = 24
Question: The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?
A.18%
B.19%
C.78%
D.48%
Answer: A.18%
Explanation: 1500 ---- 270
100 ---- ? => 18%
Answer: A
Question: What is (19^7+19) / 19?
A.45225766
B.46855821
C.47045882
D.48925947
Answer: C.47045882
Explanation: (19^7+19) / 19 =
19*(19^6+1) / 19 =
19^6 + 1
Clearly this is a number which ends with a 2 in the units place.
The answer is C.
Question: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.87. How much was lent at 5%?
A.388
B.2998
C.277
D.300
Answer: D.300
Explanation: (x*5*1)/100 + [(1500 - x)*6*1]/100 = 87
5x/100 + 90 – 6x/100 = 87
x/100 = 3
=> x = 300.Answer: D
Question: What is the % profit or loss, if the cost price of 4 mangoes is equal to the selling price of 9 mangoes?
A.75.6%
B.13.6%
C.54.6%
D.55.6%
Answer: D.55.6%
Explanation: Let the cost price of 1 mangoes be Rs 1
Cost of 9 mangoes = Rs 9
Selling price of 9 mangoes = 4
Gain/loss = 9 - 4 = 5
%=5/9âˆ—100= 55.6
Answer: D
Question: The sum of two numbers is 30 and their difference is 10. Find their product.
A.104
B.114
C.315
D.200
Answer: D.200
Explanation: Let the numbers be x and y.
Then x + y = 30 and x - y = 10
x = 20; y = 10
xy = 20 * 10 = 200
ANSWER:D
Question: If (x + yi) / i = ( 7 + 9i ) , where x and y are real, what is the value of (x + yi)(x - yi)?
A.110
B.120
C.130
D.140
Answer: C.130
Explanation: (x + yi) / i = ( 7 + 9i )
(x + yi) = i(7 + 9i) = -9 + 7i
(x + yi)(x - yi) = (-9 + 7i)(-9 - 7i) = 81 + 49 = 130
CORRECT ANSWER IS C0130
Question: How many of the following numbers are divisible by 132?
264, 396, 462, 792, 968, 2178, 5544, 6336
A.4
B.5
C.6
D.7
Answer: B.5
Explanation: A number is divisible by 132, if it is divisible by each one of 11, 3 and 4.
Clearly, 968 is not divisible by 3. None of 462 and 2178 is divisible by 4.
Each one of remaining 5 is divisible by each one of 11, 3 and 4 and therefore, by 132.
ANSWER:B
Question: What decimal fraction is 20 ml of a litre ?
A..2
B.0.002
C..05
D..02
Answer: D..02
Explanation: Answer
Required fraction = 20/1000
= 2/100
= .02
Correct Option: D
Question: A crate of mangoes contains one bruised mango for every thirty mango in the crate. If three out of every four bruised mango are considerably unsaleble and there are 10 unsaleable mangoes in the crate then how msny mango are there in the crate?
A.100 mangoes
B.110 mangoes
C.120 mangoes
D.130 mangoes
Answer: A.100 mangoes
Explanation: 100 mangoes
ANSWER:A
Question: A can finish a work in 18 days and B can do same work in half the time taken by A. then working together, what part of same work they can finish in a day
A.1\5
B.1\6
C.1\7
D.1\8
Answer: B.1\6
Explanation: Explanation:
Please note in this question, we need to answer part of work for a day rather than complete work. It was worth mentioning here because many do mistake at this point in hurry to solve the question
So lets solve now,
A's 1 day work = 1/18
B's 1 day work = 1/9 [because B take half time than A]
(A+B)'s one day work =
(1/18+1/9)
=(1+2 /18)=1/6
So in one day 1/6 work will be done.
Option B
Question: A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 20 sec respectively. What is the speed of the train?
A.22.3 km/hr
B.22.9 km/hr
C.29.2 km/hr
D.79.2 km/hr
Answer: D.79.2 km/hr
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/20 = y
y = 22
Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.
Answer:D
Question: If Q is a positive integer, and Q/15 = 8.2, what is the remainder when Q is divided by 15?
A.A.1
B.B.2
C.C.3
D.D.4
Answer: C.C.3
Explanation: If Q were a multiple of 15, the quotient Q/15 would be an integer. The fact that it's a decimal tells us that 15 goes into Q eight whole times and some decimal part of a time. This decimal part, 0.2 is the remainder divided by the divisor. Let R be the remainder.
R/15 = 0.2 = 1/5
R = (15)*(1/5) = 3
Answer =(C)
Question: If 35 percent of 400 is 20 percent of x, then x =
A.200
B.350
C.700
D.900
Answer: C.700
Explanation: 5/100(400) = 2/10(x)
X = 700..
ANSWER:C