RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Two sacks together contained 40 kilograms of sugar. If after 1 kilogram of sugar was taken from the first sack and poured into the second the weight of the sugar in the first sack became 60% the weight of the sugar in the second, what was the original difference in the weights of the sacks?
A.4
B.6
C.8
D.10
Answer: C.8
Explanation: Say the weight of the second sack after change is x kilograms, then the weight of the first sack after change would be 0.6x. Since the total weight of sugar in both sacks remained the same then x+0.6x=40, which gives x=25.
Now, if the weight of the second sack after change is 25 kilograms then initially it was 25−1=24 kilograms and the initial weight of the first sack was 40−24=16 kilograms, so the difference was 24−16=8 kilograms.
Answer: C
Question: At a certain supplier, a machine of type A costs $20,000 and a machine of type B costs $60,000. Each machine can be purchased by making a 20 percent down payment and repaying the remainder of the cost and the finance charges over a period of time. If the finance charges are equal to 40 percent of the remainder of the cost, how much less would 2 machines of type A cost than 1 machine of type B under this arrangement?
A.$10,000
B.$26,400
C.$12,000
D.$12,800
Answer: B.$26,400
Explanation: 1 machine of type B will cost: 20% down payment of 60,000 = 12,000plusremaining sum (50,000-12,000=48,000) with 40% of finance charges 48,000*1.4=67,200 --> 12,000+67,200=79,200;
2 machine of type A will cost: 20% down payment of 2*20,000 = 8,000plusremaining sum (40,000-8,000=32,000) with 40% of finance charges 32,000*1.4=44,800 --> 8,000+44,800=52,800;
Difference = 79,200 - 52,800 = 26,400.
Answer: B.
Question: If |5x-30| = 100, then find the sum of the values of x?
A.1
B.-2
C.12
D.-3
Answer: C.12
Explanation: |5x-30| = 100
5x-30 = 100 or 5x-30 = -100
5x = 130 or 5x = -70
x = 26 or x = -14
sum = 26-14 = 12
Answer is C
Question: A and B start walking towards each other at 5am at speed of 4kmph and 8kmph. They were initially 36km apart. At what time do they meet?
A.8am
B.6am
C.7am
D.10am
Answer: A.8am
Explanation: Time of meeting = distance / relative speed = 36/8 + 4 = 36/12 = 3 hrs after 5am = 8am
Answer is A
Question: a number divided by 44 leaves remainder 17 what is the remainder when same number divided by 8
A.5
B.7
C.9
D.10
Answer: A.5
Explanation: add 44+17=61
now 61 divided by 8 so we get 5 as reaminder
ANSWER:A
Question: Health insurance Plan Q requires the insured to pay $1000 or 50% of total cost, whichever is lower. Plan B requires the insured to pay the initial $300, but then pays 80% of the cost over $300. Which of the following is a cost level for which both insurance plans pay out the same amount?
A.$600
B.$1000
C.$3800
D.$5300
Answer: B.$1000
Explanation: 0.5 * 600 = 300 where Q = B
Question: A 300 meter long train crosses a plaƞorm in 39 seconds while it crosses a signal pole in 18 seconds.
What is the length of the plaƞorm.
A.310 meter
B.335 meter
C.345 meter
D.350 meter
Answer: D.350 meter
Explanation: Explanation:
Speed = Distance/Ɵme = 300/18 = 50/3 m/sec
Let the length of the plaƞorm be x meters
then
Distance=Speed
∗
Timex+300=503
∗
39=>3(x+300)=1950=>x=350 meters
Answer: D
Question: It is being given that (2^32 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
A.16^2+1
B.12
C.(2^96+1)
D.24
Answer: C.(2^96+1)
Explanation: Explanation:
Let 2^32 = x. Then, (2^32 + 1) = (x + 1).
Let (x + 1) be completely divisible by the natural number N. Then,
(296 + 1) = [(2^32)3 + 1] = (x^3 + 1) = (x + 1)(x^2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
C
Question: Evaluate: 50 - 12÷4×2 =
A.44
B.54
C.16
D.27
Answer: A.44
Explanation: According to order of operations, 12÷4×2 (division and multiplication) is done first from left to right
12÷4×2 = 3 × 2 = 6
Hence
50 - 12÷4×2 = 50 - 6 = 44
correct answer A)44
Question: I sold a book at a profit of 10%. Had I sold it for $120 more, 15% would have been gained. Find the cost price?
A.$2000
B.$2500
C.$2400
D.$3120
Answer: C.$2400
Explanation: 115% of cost - 110% of cost = $120
5% of cost = $120
cost = 120*100/5 = $2400
Answer is C
Question: In how many ways can the letters of the word ABROAD be rearranged such that the vowels always appear together?
A.6!/2!
B.3!*3!
C.4!/2!
D.4! *(3!/2!)
Answer: D.4! *(3!/2!)
Explanation: In the word ABROAD , there are 3 vowels - 2 A's and O
Number of ways the letters of word ABACUS be rearranged such that the vowels always appear together
= (4! * 3! )/2!
We can consider the the 3 vowels as a single unit and there are 3 ways to arrange them . But since 2 elements of vowel group are identical we divide by 2! .
The entire vowel group is considered as a single group .
Answer D
Question: Mohit sold an article for Rs. 18000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article?
A.15000
B.15002
C.15029
D.15329
Answer: A.15000
Explanation: Let the CP be Rs. x.
Had he offered 10% discount, profit = 8%
Profit = 8/100 x and hence his SP = x + 8/100 x = Rs. 1.08x = 18000 - 10/100(18000) = 18000 - 1800 = Rs. 16200
=> 1.08x = 16200
=> x = 15000
Answer: A
Question: A cistern is filled by pipe A in 10 hours and the full cistern can be leaked out by an exhaust pipe B in 15 hours. If both the pipes are opened, in what time the cistern is full?
A.50hrs
B.30hrs
C.70hrs
D.80hrs
Answer: B.30hrs
Explanation: time taken to full the cistern=(1/10-1/15)hrs
=1/30
=30hrs
ANSWER:B
Question: A and B together can do a piece of work in 8 days. If A alone can do the same work in 12 days, then B alone can do the same work in?
A.25 days
B.24 days
C.22 days
D.27 days
Answer: B.24 days
Explanation: B
24 days
B = 1/8 – 1/2 = 1/24 => 24 days
Question: A man invests Rs. 8,000 at the rate of 5% per annum. How much more should he invest at the rate of 8%, so that he can earn a total of 6% per annum?
A.Rs. 1200
B.Rs. 1300
C.Rs. 1500
D.Rs. 4000
Answer: D.Rs. 4000
Explanation: Explanation :
Interest on Rs.8000 at 5% per annum = ( 8000 × 5 × 1) / 100 = Rs. 400
Let his additional investment at 8% = x
Interest on Rs.x at 8% per annum = ( x × 8 × 1 ) / 100 = 2x/25.
To earn 6% per annum for the total, interest = (8000 + x) × 6 × 1/100.
=> 400 + 2x/25 = (8000 + x) × 6 × 1/100.
=> 40000 + 8x = (8000 + x) × 6.
=> 40000 + 8x = 48000 + 6x.
=> 2x=8000.
=> x=4000.
Answer : D
Question: For a group of n people, k of whom are of the same sex, the (n-k)/n expression yields an index for a certain phenomenon in group dynamics for members of that sex. For a group that consists of 20 people, 8 of whom are females, by how much does the index for the females exceed the index for the males in the group?
A. 0.05
B. 0.0625
C. 0.2
D. 0.25
Answer: C. 0.2
Explanation: Index for females = (20-8)/20 = 3/5 = 0.6
Index for males = (20-12/20 = 2/5 = 0.4
Index for females exceeds males by 0.6 - 0.4 = 0.2
Answer: C
Question: There is a 30% increase in the price of an article in the first year, a 20% decrease in the second year and a 10% increase in the next year. If the final price of the article is Rs. 2288, then what was the price of the article initially?
A.Rs.2038
B.Rs.2073
C.Rs.2000
D.Rs.2027
Answer: C.Rs.2000
Explanation: Let the price of the article, four years age be Rs. 100 in the 1st year, price of the article = 100 + 30 = Rs. 130. In the 2nd year, price = 130 - 20% of 130 = 130 - 26 = Rs. 104.
In the 3rd year, price = 104 + 10% of 104 = 104 + 10.4 = Rs. 114.40.
But present price of the article is Rs. 2288
for 114.4 ---> 100 ; 2288 ---> ?
Required price = (2288 * 100)/114.4 = 20 * 100 = Rs.2000.
Answer:C
Question: There are three foam generators in the factory, each of the first two can generate 10 liters of foam in one hour and the third can generate 18 liters in an hour. The three generators start working together at the same time and after one hour and a half one of the first generators stops working and two hours after that the third generator stops working and only one generator is left. If 5 hours after they all started to work the last generator stops working, how many liters of foam were generated?
A.128
B.132.
C.146.
D.154.
Answer: A.128
Explanation: Let the foam generators capacity be -
A = 10 lit/hr
B = 10 lit/hr
C = 18 lit/hr
Total foam generation in 1 hour will be 38 lit ( 10 + 10 + 18 ) ; since in 1 and 1/2 hr they will generate 38 + 19 => 57 litres...
Now one of the first generators stops working ( Say A stops working ) , so we have -
B = 10 lit/hr
C = 18 lit/hr
Total foam generation in 2 hour will be 56 litres {2 (10+18)}
The third generator stops working and now only B works for the remaining time 1 and 1/2 ( 5 - 1 and 1/2 - 2 )...
Foam generated by B will be 3/2 * 10 => 15 litres
So, total foam generated will be 128 Litres ( 57 + 56 + 15 ) ; hence answer will be (A)
Question: In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 30 percent, but profits were 16 percent of revenues. The profits in 1999 were what percent of the profits in 1998?
A.80%
B.105%
C.120%
D.112%
Answer: D.112%
Explanation: 0,112R = x/100*0.1R
Answer D
Question: 30 percent of Andrea's living room floor is covered by a carpet that is 4 feet by 9 feet. What is the area of her living room floor?
A.14.4
B.120
C.50.4
D.60
Answer: B.120
Explanation: 30% of Area of the floor = 4*9 square feet = 36 square feet
i.e. 100% Area of Floor = (36/30)*100 = 120 square feet
Answer: Option B
Question: There are 5 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 4 other amateurs, what is the total number of chess games possible to be played in the tournament?
A.10
B.20
C.40
D.60
Answer: A.10
Explanation: Method 1:
Take the first amateur. He plays a game with each of the other four i.e. 4 games.
Now take the second one. He has already played a game with the first one. He plays 3 games with the rest of the 3 amateurs i.e. 3 more games are played.
Now take the third amateur. He has already played a game each with the first and the second amateur. Now he plays 2 games with the remaining 2 amateurs so 2 more games are played.
Now go on to the fourth amateur. He has already played 3 games with the first 3 amateurs. He just needs to play a game with the last one i.e. 1 more game is played.
The last amateur has already played 4 games.
Total no of games = 4+3+2+1 = 10
Method 2:
Each person is one participant of 4 games. So there are in all 4*5 = 20 instances of one participant games. But each game has 2 participants so total number of games = 20/2 = 10
Answer: A.
Question: If 28a+30b+31c=425.
then a+b+c=?.a,b,c are natural numbers
A.14
B.8
C.6
D.9
Answer: A.14
Explanation: have a look on your calender
since,we all knw a year consist of 365 days
february is d only month which has 28 days
4 months in a year has 30 days
and,rest 7 months has 31 days..
so,following d given eq. we can write 28*1 + 30*6 + 31*7..
hence values of a,b and c are 1, 6 and 7 respectively..
a+b+c=14
ANSWER:A
Question: A cistern is filled by a tap in 3 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how long will it take the leak to empty it?
A.88hours
B.38hours
C.78hours
D.28hours
Answer: D.28hours
Explanation: 2/7 - 1/x
= 1/4
x = 28
Answer:D
Question: What is the place value of 3 in the numeral 53468?
A.3000
B.30
C.3
D.330
Answer: A.3000
Explanation: place value of 3 = 3 * 1000 = 3000
Answer is A
Question: A child is playing with letter blocks (a playing cube in which an english letter is written). Before leaving the child to play on her own, her mon arranged 5 blocks into the word APPLE. How many different 6 letter words can the child make with these 5 blocks (Words need not have a meaning.She is just a child!) ?
A.2!
B.3!
C.4!
D.5!
Answer: C.4!
Explanation: There are 6 letter blocks to be arranged. Note that the letter P occurs twice. 2 'P' blocks can be arranged only in one way, since the two blocks are exactly the same(PP is same as PP). So we can consider PP as one letter and proceed to find the arrangement of 4 letters, A, PP, L, E. These four blocks can be arranged in 4! ways. So answer is C. 4!.
Question: A certain company charges $6 per package to ship packages weighing less than 2 pounds each. For a package weighing 2 pounds or more, the company charges an initial fee of $6 plus $2 per pound. If the company charged $30 to ship a certain package, which of the following was the weight of the package, in pounds?
A.6
B.8
C.10
D.12
Answer: D.12
Explanation: Let the weight of the package be X.
2X + 6= 30
X = 12
The answer is D.
Question: If four coins are tossed, the probability of getting two heads and two tails is
A.3/8
B.6/11
C.2/5
D.4/5
Answer: A.3/8
Explanation: Since four coins are tossed, sample space = 24
Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = 6/24 = 3/8
Answer : A
Question: If 0.75: x :: 5:9, then x is equal to:
A.1.12
B.1.16
C.1.2
D.1.35
Answer: D.1.35
Explanation: Explanation:
(x * 5) = (0.75 *9)
X=6.75/5 = 1.35
Answer: D
Question: By investing in 16 2/3% stock at 64, one earns Rs. 1500. The investment made is:
A.Rs. 5640
B.Rs. 5760
C.Rs. 7500
D.Rs. 8600
Answer: B.Rs. 5760
Explanation: To earn Rs.	50/3	, investment = Rs. 64.
To earn Rs. 1500, investment = Rs.64 x	3/50x 1500	= Rs. 5760.
ANSWER :B
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 720 grams per kg, what is his percent?
A.15%
B.25%
C.38.9%
D.45%
Answer: C.38.9%
Explanation: Explanation:
720 --- 280
100 --- ? => 38.9%
Answer: C
Question: A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?
A.240
B.288
C.665
D.199
Answer: A.240
Explanation: S = 600/40 = 15 mps
S = 3600/15 = 240 sec
= 4 min
Answer: A
Question: By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%?
A.123
B.480
C.266
D.1251
Answer: B.480
Explanation: SP = 800
Profit = 25%
CP = (SP)*[100/(100+P)]
= 800 * [100/125]
= 640
Loss = 25% = 25% of 640 = Rs.160
SP = CP - Loss = 640 - 160 = Rs.480Answer: B
Question: A bag contains 2 white balls, 3 black balls and 4 red balls. In how many ways can 3 balls be drawn from the bag, if at least one black ball is to be included in the draw
A.64
B.128
C.132
D.222
Answer: A.64
Explanation: Explanation:
From 2 white balls, 3 black balls and 4 red balls, 3 balls are to be selected such that
at least one black ball should be there.
Hence we have 3 choices
All three are black
Two are black and one is non black
One is black and two are non black
Total number of ways
= 3C3 + (3C2 x 6C1) + (3C1 x 6C2) [because 6 are non black]
=1+[3×6]+[3×(6×5/2×1)]=1+18+45=64
Option A
Question: A drought decreased the amount of water in city X’s reservoirs from 118 million gallons to 96 million gallons. If the reservoirs were at 79 percent of total capacity before the drought began, approximately how many million gallons were the reservoirs below total capacity after the drought?
A.67
B.58
C.54
D.46
Answer: C.54
Explanation: let T be the total capacity of the reservoir.
Now we can equate before cases i.e 79/100(T) = 118.
Lets take approximate values for easy calculation 80/100(T) = 120 => T = 150 MG.
We need to subtract total - after drought case = 150 - 96 = 54 MG..
Option C is correct answer...
Question: Evaluate : 986 x 237 + 986 x 863
A.986000
B.968000
C.978000
D.987000
Answer: A.986000
Explanation: 986 x 137 + 986 x 863 = 986 x (137 + 863) = 986 x 1000 = 986000.
Answer is A.
Question: The class mean score on a test was 50, and the standard deviation was 15. If Jack's score was within 2 standard deviations of the mean, what is the lowest score he could have received?
A.20
B.31
C.45
D.90
Answer: A.20
Explanation: 1SD from the mean ranges from 35 to 65, where 65 is within SD above the mean and 35 within 1SD below the mean
2SD=15 TWICE=30 from the the mean, which is 80 to 20, where 80 is within 2 SD above the mean AND 20 is within 2 SD below the mean.
Answer = A
Question: 256, 225, 196, 169, 144, ?
A.49
B.64
C.81
D.121
Answer: D.121
Explanation: Explanation :
The pattern is 16^2, 15^2, 14^2, 13^2, 12^2, ...
So next number is 11^2 = 121
Answer : Option D
Question: In a shop, 40% socks are white and rest are black. 60% socks are made of cotton and rest are made of wool. 25% white socks are made of cotton and 20 of the black socks are made of wool. How many black socks Z are made of cotton?
A.100
B.80
C.60
D.50
Answer: A.100
Explanation: I'll prefer to solve this with plug n play method.
As we know, White Cotton socks are only 25% and Total Cotton socks is 60% - Hence Black Cotton socks Z has to be [highlight]HIGH[/highlight]number. Thats why we've to pick high number... say 100 or 80.
100 fits perfectly after relevant calculations. Hence answer A.
Question: A certain junior class has 3000 students and a certain senior class has 800 students. Among these students, there are 60 siblings pairs each consisting of 1 junior and 1 senior. If 1 student is to be selected at random from each class, what is the probability that the 2 students selected will be a sibling pair?
A.1/40000
B.1/3600
C.9/2000
D.1/60
Answer: A.1/40000
Explanation: Let's see
Pick 60/3000 first
Then we can only pick 1 other pair from the 800
So total will be 60 / 800 *3000
Simplify and you get 1/40000
Answer is A
Question: A sum amounts to Rs.4410 in 2 years at the rate of 5% p.a. If interest was compounded yearly then what was the principal?
A.Rs.4000
B.Rs.5000
C.Rs.4500
D.Rs.4800
Answer: A.Rs.4000
Explanation: CI=4410,R=5,N=2
CI=P[1+R/100]^2
=P[1+5/100]^2
4410=P[21/20]^2
4410[20/21]^2
4000
ANSWER:A
Question: A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containg 19% alcohol and now the percentage of alcohol was found to be 26%. What quantity of whisky is replaced ?
A.1/3
B.2/3
C.2/5
D.3/5
Answer: B.2/3
Explanation: Let us assume the total original amount of whiskey = 10 ml ---> 4 ml alcohol and 6 ml non-alcohol.
Let x ml be the amount removed ---> total alcohol left = 4-0.4x
New quantity of whiskey added = x ml out of which 0.19 is the alcohol.
Thus, the final quantity of alcohol = 4-0.4x+0.19x ----> (4-0.21x)/ 10 = 0.26 ---> x = 20/3 ml.
Per the question, you need to find the x ml removed as a ratio of the initial volume ---> (20/3)/10 = 2/3.
Hence, B is the correct answer.
Question: In store A there are 50 pairs of pants for every 40 store B has. The price ratio between the pants in store B and the pants in store A is 3:4. If all the pants were sold in both places until the stock ran out, what is the ratio between the total amount stores A earned to the total amount store B earned?
A.3:16.
B.2:3.
C.5:3.
D.3:4.
Answer: C.5:3.
Explanation: 1st statement : ratio of pants
Store A : Store B
50x : 40x
5X:4X
Price :
4y:3y
Total revenue
20xy : 12xy
5:3
Answer is C
Question: The side of a cube is 15 m, find it's surface area?
A.1350
B.1750
C.1150
D.1450
Answer: A.1350
Explanation: Surface area = 6 a(power)2 sq. units
6 a(power)2 = 6 × 225 = 1350 m(power)2
Answer is A.
Question: A train 220 m long is running with a speed of 59 kmph.. In what will it pass a man who is running at 7 kmph in the direction opposite to that in which the train is going
A.8 sec
B.10 sec
C.12 sec
D.14 sec
Answer: C.12 sec
Explanation: Explanation:
Speed of the train relative to man = (59 + 7) kmph
= 66 ×5/18 m/sec = 55/3 m/sec.
Time taken by the train to cross the man = Time taken by it to cover 220 m
at (55/3) m / sec = (220 ×3/55) sec = 12 sec
Answer: Option C
Question: A train 500m long takes 10 sec to cross a man walking at 5kmph in a direction opposite to that of the train. Find the speed of the train?
A.175kmph
B.150kmph
C.162kmph
D.145kmph
Answer: A.175kmph
Explanation: Let the speed of the train be x kmph
Speed of the train relative to man = x+5 = (x+5)*5/18 m/sec
500/[(x+5)*5/18] = 10
10(x+5) = 1800
x = 175kmph
Answer is A
Question: The average age of applicants for a new job is 20, with a standard deviation of 8. The hiring manager is only willing to accept applicants whose age is within one standard deviation of the average age. Assuming that all applicants' ages are integers and that the endpoints of the range are included, what is the maximum number of different ages of the applicants?
A.8
B.16
C.17
D.18
Answer: C.17
Explanation: Minimum age = Average - 1 Standard deviation = 20 - 8 = 12
Maximum age = average + 1 Standard deviation = 20+ 8 = 28
Maximum number of different ages of the applicants = 28 - 12 + 1 = 17
Answer C
Question: A batsman makes a score of 87 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning?
A.39
B.35
C.42
D.40.5
Answer: A.39
Explanation: let the average after 16th inning =x
then total run after 16th inning=16x
then total run after 17th inning=16x+87
then average run after 17th inning=(16x+87)/17
(16x+87)/17=x+3;
x=36;
average after 17th inning =36+3=39
ANSWER:A
Question: Set S consists of integers {8, 11, 12, 14, 15}. If integer n is included in the set, the average (arithmetic mean) of set S will increase by 25%. What is the value of integer n?
A.28
B.32
C.36
D.40
Answer: D.40
Explanation: The average of the numbers in set S is 12.
If we increase the mean by 25%, the new mean is 15.
Thus, on average, 5 numbers increase by 5.
Therefore n = 15+25 = 40
The answer is D.
Question: There are 6 people and 6 chairs. In how many different ways people can occupy the chairs?
A.360
B.500
C.420
D.720
Answer: D.720
Explanation: number of ways =6! = 720
Answer is D
Question: The edges of cuboid are 4 cm; 5 cm and 6 cm. Find its surface area?
A.228
B.148
C.992
D.772
Answer: B.148
Explanation: 2(4*5 + 5*6 + 4*6) = 148
Answer: B
Question: The average score in an examination of 10 students of a class is 60. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark was 30 and the maximum mark was 100. It is also known that none of the students failed. If each of the top five scorers had distinct integral scores, the maximum possible score of the topper is
A.89
B.90
C.92
D.99
Answer: D.99
Explanation: The average score in an examination of 10 students of a class is 60 --> the total score = 10*60 = 600;
The 5 smallest scores have an average of 55 --> the total score of the 5 smallest scores = 275.
From above, the total score of the 5 largest scores = 600 - 275 = 325.
Say the 5 largest scores are a, b, c, d, and e (where a<b<c<d<e, since each of the top five scorers had distinct scores). We want to maximize e. To maximize e, we need to minimize a, b, c, and d. The least value of a, is 55 (The least score of the top 5 , a, should be equal to the highest of the bottom 5 and to minimize the highest of the bottom 5, all scores from the bottom 5 should be equal). In this case the least values of b, c, and d are 56, 57, and 58 respectively:
a + b + c + d + e = 55 + 56 +57 + 58 + e = 325;
e = 99.
Answer: D.
Question: Let us say that a table tennis tournament was going on with knock out terms which means the one who loses the match is out of the tournament. 86 players took part in that tournament. How many matches were played?
A.90 matches
B.95 matches
C.99 matches
D.85 matches
Answer: D.85 matches
Explanation: D 85 matches. The number of matches will always sum up to one less than the number of players in a knock out tournament. You may calculate it in any manner. Thus 85 matches were played.
Question: The speed at which a man can row a boat in still water is 15 km/hr. If he rows downstream, where the speed of current is 3 km/hr, how many seconds will he take to cover 100 meters?
A.14
B.16
C.18
D.20
Answer: D.20
Explanation: The speed of the boat downstream = 15 + 3 = 18 km/hr
18 km/hr * 5/18 = 5 m/s
The time taken to cover 100 meters = 100/5 = 20 seconds.
The answer is D.