RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Which of these following integers is the square of an integer?
A.49981101542
B.49206101137
C.49471101241
D.49859101723
Answer: C.49471101241
Explanation: The unit digit of any perfect square can not be 2, 3, 7, or 8.
The answer is C.
Question: A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in 36 hrs and a machine of type S does the same job in 18 hours. If the company used the same number of each type of machine to do the job in 3 hours, how many machines of type R were used?
A.3
B.4
C.6
D.9
Answer: B.4
Explanation: Rate of machine R = 1/36
Rate of machine S = 1/18
Rate of R+S = 1/12
To finish the work in 3 hrs, the combined rate needs to be 1/3.
x * 1/12 = 1/3
x = 4
The answer is B.
Question: One-seventh of the light switches produced by a certain factory are defective. Four-fifths of the defective switches are rejected and 1/15 of the non defective switches are rejected by mistake. If all the switches not rejected are sold, what percent of the switches sold by the factory are defective?
A.2.3%
B.3.4%
C.4.5%
D.5.6%
Answer: B.3.4%
Explanation: 1/7 of the switches are defective.
The defective switches that are not rejected are 1/5*1/7 = 1/35 = 3/105 of all switches.
The non defective switches that are sold are 6/7*14/15 = 84/105 of all switches.
The percent of switches sold that are defective is 3/87 which is about 3.4%.
The answer is B.
Question: Find large no. from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 30 as remainder
A.1235
B.1456
C.1567
D.1632
Answer: D.1632
Explanation: Let the smaller number be x. Then larger number = (x + 1365).
x + 1365 = 6x + 30
5x = 1335
x = 267
Large number = 267+1365 = 1632
D
Question: The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq. cm. Find the length of the rectangle.
A.10 cm
B.20 cm
C.30 cm
D.40 cm
Answer: B.20 cm
Explanation: Let breadth = x. Then, length = 2x. Then,
(2x - 5) (x + 5) - 2x * x = 75 <=> 5x - 25 = 75 <=> x = 20.
:. Length of the rectangle = 20 cm.
ANSWER B 20 cm
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 150 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
A.39
B.27
C.36
D.88
Answer: A.39
Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 150 = 390 m.
Time taken = 390/10 = 39 sec.
Answer: A
Question: Stacy and Heather are 20 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 2 mile per hour faster than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?
A.5miles
B.7 miles
C.9 miles
D.10 miles
Answer: B.7 miles
Explanation: Original distance between S and H = 20 miles.
Speed of S = 5+2 = 7 mph, Speed of H = 5 mph.
Time traveled by H = t hours ---> time traveled by S = t+24/60 = t+2/5 hours.
Now, the total distances traveled by S and H = 20 miles ---> 7*(t+2/5)+5*t=20 ---> t= 86/60 hours. Thus H has traveled for 86/60 hours giving you a total distance for H = 5*86/60 = 7 miles.
B is thus the correct answer.
P.S.: based on the wording of the question, you should calculatehow far from theoriginal destination has Heather walkedwhen the two meet. 'Original destination' for H does not make any sense. Original destination for H was situated at a distance of 20 miles.
Question: Two interconnected, circular gears travel at the same circumferential rate. If Gear A has a diameter of 80 centimeters and Gear B has a diameter of 50 centimeters, what is the ratio of the number of revolutions that Gear A makes per minute to the number of revolutions that Gear B makes per minute?
A.8:5
B.9:25
C.5:8
D.25:9
Answer: C.5:8
Explanation: Same circumferential rate means that a point on both the gears would take same time to come back to the same position again.
Hence in other words, time taken by the point to cover the circumference of gear A = time take by point to cover the circumference of gear B
Time A = 2*pi*25/Speed A
Time B = 2*pi*40/Speed B
Since the times are same,
50pi/Speed A = 80pi/Speed B
SpeedA/Speed B = 50pi/80pi = 5/8
Correct Option: C
Question: By using the numbers 1, 2, 3, 5 and 7 only once, how many five digit numbers can be made that are divisible by 20?
A.Not possible
B.9
C.4
D.6
Answer: A.Not possible
Explanation: A number to be divisible by 50 must end with 00 or 50.
So, not possible.
Answer: A.
Question: Kamal obtained 76, 60, 82, 67 and 85 marks(out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
A.65
B.69
C.74
D.75
Answer: C.74
Explanation: Sol.
Average
= 76 + 60 + 82 + 67 + 85 / 5)
= (375 / 5)
= 74.
Answer C
Question: If 15% of A is the same as 20% of B, then A : B is :
A.3 : 4
B.4 : 3
C.17 : 16
D.16 : 17
Answer: B.4 : 3
Explanation: Expl : 15% of A I= 20 % of B =15A/100 = 20B/100 = 4/3 = 4:3
Answer:B
Question: Tom wants to buy items costing $25.35, $50.69, and $95.96. He earns $6.50 an hour doing
odd jobs. If ten percent of his income is put aside for other purposes, how many hours must he
work to earn the money he needs for his purchases? Round your answer to the nearest whole
hour.
A.29 hours
B.48 hours
C.38 hours
D.18 hours
Answer: A.29 hours
Explanation: $6.50 x .10 = $.65 is 10% of his hourly income
$6.50 - .65 = $5.85 hourly amount available to spend
$25.35 + $50.69 + $95.96 = $172 total needed
$172 ÷ $5.85 = 29.4... rounds to 29 hours
correct answer A
Question: A sum of money is to be distributed among A, B, C, D in the proportion of 5:2:4:3. If C gets Rs. 500 more than D, what is B's share?
A.A)8239
B.B)2900
C.C)1000
D.D)2393
Answer: C.C)1000
Explanation: Let the shares of A, B, C and D be 5x, 2x, 4x and 3x Rs. respectively.
Then, 4x - 3x = 500 => x = 500.
B's share = Rs. 2x = 2 * 500 = Rs. 1000.
Answer: C
Question: If a square and a rhombus stand on the same base, then the ratio of the areas of the square and the rhombus is:
A.1:1
B.1:2
C.1:3
D.1:4
Answer: A.1:1
Explanation: A square and a rhombus on the same base are equal in area Answer: A
Question: 500 is increased by 30%. Find the final number.
A.550
B.500
C.650
D.600
Answer: C.650
Explanation: ExplanationFinal number = Initial number + 30%(original number) = 500 + 30%(500) = 500 + 150 = 650.Answer C
Question: Find the cost of fencing around a circular field of diameter 28 m at the rate of Rs.1.50 a meter?
A.288
B.132
C.772
D.592
Answer: B.132
Explanation: 2 * 22/7 * 14 = 88
88 * 1 1/2 = Rs.132
Answer: B
Question: If the President and Vice President must sit next to each other in a row with 4 other members of the Board, how many different seating arrangements are possible?
A.120
B.240
C.300
D.360
Answer: B.240
Explanation: We need to take President and VP as one unit. Therefore we have 5 people to arrange=5! ways
Also, we both President and VP can be arranged in 2 ! ways.
Reqd no of ways=5!*2!=240 ways
Answer B
Question: A store sells four different kinds of shirts. If we want to buy two different kinds of shirts, how many possible combinations of two shirts can we buy?
A.5
B.6
C.7
D.8
Answer: B.6
Explanation: 4C2=6.
The answer is B.
Question: A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
A.30
B.35
C.36
D.37
Answer: C.36
Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.
Answer: Option C
Question: A train covers a distance of 12 km in 5 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
A.120m
B.180m
C.240m
D.220m
Answer: C.240m
Explanation: Speed = (12/5 * 60) km/hr = (144 * 5/18) m/sec = 40 m/sec.
Length of the train = 40 * 6 = 240 m.
ANSWER:C
Question: The prime sum of an integer n greater than 1 is the sum of all the prime factors of n, including repetitions. For example , the prime sum of 12 is 7, since 12 = 2 x 2 x 3 and 2 +2 + 3 = 7. For which of the following integers is the prime sum greater than 36 ?
A.440
B.512
C.550
D.620
Answer: D.620
Explanation: Large numbers are made in two ways:
Either by taking small prime numbers and raising them to higher powers or taking large prime numbers in the first place.
31*2 = 62 (large prime number)
2^6 = 64 (many small prime numbers)
To get a sum as large as 36 or more, you would need some large prime numbers. So options such as 512, 700 and 750 which have small prime numbers as factors should be ignored first. 440 also splits into 11, 4( which is 2*2), 2, 5 - relatively small prime numbers.
You are left with 620 which is 31*2*2*5 (sum greater than 36)
Answer (D)
Question: Two years ago, Arthur gave each of his five children 20 percent of his fortune to invest in any way they saw Fit. In the first year, three of the children, Alice, Bob, and Carol, each earned a profit of 50 percent on their Investments, while two of the children, Dave and Errol, lost 40 percent on their investments. In the second Year, Alice and Bob each earned a 30 percent profit, Carol lost 60 percent, Dave earned 25 percent in profit, And Errol lost all the money he had remaining. What percentage of Arthur's fortune currently remains?
A.93%
B.97%
C.100%
D.105%
Answer: D.105%
Explanation: Say Arthur's fortune was $100. Then:
A = 20*1.5*1.3 = 39
B = 20*1.5*1.3 = 39
C = 20*1.5*0.4 = 12
D = 20*0.6*1.25 = 15
E = 0
Total 39 + 39 + 12 + 15 = 105.
Answer: D.
Question: How many words can be formed from the letters of the word ‘DIRECTOR’ So that the vowels are always together?
A.2160
B.2162
C.2161
D.2163
Answer: A.2160
Explanation: In the given word, we treat the vowels IEO as one letter.
Thus, we have DRCTR (IEO).
This group has 6 letters of which R occurs 2 times and others are different.
Number of ways of arranging these letters = 6!/2! = 360.
Now 3 vowels can be arranged among themselves in 3! = 6 ways.
Required number of ways = (360x6) = 2160.
Answer A.
Question: The instructions state that Deepthi needs 4/17 square yards of one type of material and 3/10 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 9/30 square yards left that she did not use. What is the total amount of square yards of material Deepthi used?
A.1/12
B.4/17
C.2/3
D.1 1/9
Answer: B.4/17
Explanation: Total bought = 4/17+3/10
left part 9/30--->3/10
so used part 4/17+3/10-3/10=4/17
ANSWER:B
Question: A dishonest dealer uses a scale of 85 cm instead of a metre scale and claims to sell at cost price. His profit is
A.17.65%
B.10%
C.12%
D.None of these
Answer: A.17.65%
Explanation: Solution
Gain%	= (15 / 85 x 100)%
= 17.65%
Answer A
Question: If 42.12 = k(14 + m/50), where k and m are positive integers and m < 50, then what is the value of k + m ?
A.5
B.7
C.8
D.9
Answer: A.5
Explanation: 42.12 = 14K + Km/50...we can rewrite the number as follows:
42+ 0.12= 14K + Km/50........Since K is integer, then 42=14K..........K=3
0.12=Km/50......12/100=3m/50......m=2
k+m=3+2=5
Answer: A
Question: (68-a)(68-b)(68-c)(68-d)(68-e)=725.wat is the value of a+b+c+d?
A.230
B.231
C.232
D.233
Answer: C.232
Explanation: factors of 725= 5,5 29
so (68-63)=5 ,(68-63)=5,(68-39)=29, (68-67)=1 ,(69-67)=1
so a+b+c+d= 232
ANSWER:C
Question: A placed three sheets with two carbons to get two extra copies of the original. Then he decided to get more carbon copies and folded the paper in such a way that the upper half of the sheets were on top of the lower half. Then he typed. How many carbon copies did he get?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: Explanation:
Since the number of carbons is 2, only two copies can be obtained.
Answer: B
Question: Two fair die with sides numbered 1 to 6 are tossed. What is the probability that the sum of the exposed faces on the die is a prime number?
A.5/11
B.5/12
C.5/21
D.2/9
Answer: A.5/11
Explanation: Two dices are thrown ! So we may get 1+1 or 1+2 ... or 1+6.. or 2+6 or 3+6 etc
Therefore the total different sum values we can get are :2,3,4,5,6,7,8,9,10,11,12[Sample space] ----------------(1)
Out of these values, 5 numbers are primes i.e.2,3,5,7,11[Favorable events] --------------------(2)
From (1)(2)
The answer is5/11!!
Option A
Question: 1,345
1,354
1,435
.....
....
+5,431
The addition problem above shows four of the 24 different integers that can be formed by using each of the digits 1,3,4,5 exactly once in each integer. What is the sum of these 24 integers?
A.78,690
B.82,240
C.86,658
D.90,240
Answer: C.86,658
Explanation: In each of the units, tens, hundreds, and thousands place, each digit will appear 6 times.
Then the sum equals 6(1111)+6(3333)+6(4444)+6(5555) = 86,658
The answer is C.
Question: A batsman makes a score of 65 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning.
A.17
B.39
C.42
D.45
Answer: A.17
Explanation: Let the average after 17th inning = x.
Then, average after 16th inning = (x – 3).
∴ 16(x – 3) + 65 = 17x or x = (65 – 48) = 17.
Answer A
Question: The actual price of an article was Rs. 6000/- the successive discount on 10% and 20% then Finds the selling price
A.Rs.3240/-
B.Rs. 4320/-
C.Rs.4230/-
D.Rs.4200/-
Answer: B.Rs. 4320/-
Explanation: Explanation:
Note: Selling price = MRP * (100 - d1)/100 * (100 - d2)/100 * -------------
MRP = 6000/- , d1 = 10, d2 = 20
Selling price = 6000 * (100 - 10)/100 * (100-20)/100 ==> 6000 * 90/100 * 80/100
=> 48 * 90 = Rs. 4320/-
Answer: Option B
Question: If a(a + 5) = 6 and b(b + 5) = 6, where a ≠ b, then a + b =
A. −5
B. −2
C. 2
D. 46
Answer: A. −5
Explanation: a(a + 5) = 6 and b(b + 5) = 6
=> a, b must be integers and if a is -6 or 1, b will be 1 and -6 respectively
=> a+b = -5
Ans: A
Question: John and Peter are among the eight players a volleyball coach can choose from to field a six-player team. If all six players are chosen at random, what is the probability of choosing a team that includes John and Peter?
A.7/15
B.11/20
C.14/25
D.15/28
Answer: D.15/28
Explanation: The total possible ways of selecting a 6-member team is 8C6 = 28
The possible ways which include John and Peter is 6C4 = 15
The probability of choosing both John and Peter is 15/28
The answer is D.
Question: If 15 Horses eat 15 bags of gram in 15 days, in how many days will one horse eat one bag of Grain?
A.15 days
B.1/15 days
C.1 day
D.30 days
Answer: A.15 days
Explanation: Horse*days=bags
15*15=15 and 1*days=1
(15*15)/(1*days)=15/1
Days=15
ANSWER:A
Question: An urn contains 10 balls, numbered from 1 to 10. If 2 balls are selected at random with replacement from the urn, what is the probability P that the sum of the 2 numbers on the balls will be even?
A.25%
B.37.5%
C.50%
D.62.5%
Answer: C.50%
Explanation: Correct Answer: C
Since there are 5 even numbered balls and 5 odd numbered balls, the probability of selecting either an even or an odd is 5/10= 1/2. In order for the sum of the numbers on the two balls to be even, either both numbers must be even or both numbers must be odd; one even and one odd number would add to an odd number. The probability of selecting two even numbers is:
1/2 * 1/2= 1/4
The probability of selecting two odd numbers is also:
1/2 * 1/2= 1/4
Adding both probabilities gives P=1/4+1/4= 1/2 , or 50%, as the probability that the sum of the numbers will be even. Thus, the correct answer is (C).
Question: The speed of a boat in still water is 60kmph and the speed of the current is 10kmph. Find the speed downstream and upstream?
A.87 kmph
B.40 kmph
C.50 kmph
D.15 kmph
Answer: C.50 kmph
Explanation: Speed downstream = 60 + 10
= 70 kmph
Speed upstream = 60 - 10
= 50 kmph
Answer:C
Question: A die is thrown three times. Events X and Y are defined as below:
X : 4 on the third throw
Y : 6 on the first and 5 on the second throw
What is the probability of X given that Y has already occurred.
A.1/6
B.1/7
C.1/11
D.1/13
Answer: A.1/6
Explanation: The sample space has 216 outcomes.
Now X =
(1,1,4) (1,2,4) ... (1,6,4) (2,1,4) (2,2,4) ... (2,6,4)
(3,1,4) (3,2,4) ... (3,6,4) (4,1,4) (4,2,4) ...(4,6,4)
(5,1,4) (5,2,4) ... (5,6,4) (6,1,4) (6,2,4) ...(6,5,4) (6,6,4)
Y = {(6,5,1), (6,5,2), (6,5,3), (6,5,4), (6,5,5), (6,5,6)}
and X n Y = {(6,5,4)}.
Now P(Y) = 6/216
and P (X n Y) = 1/216
Then P(X|Y) = (1/216)/(6/216) = 1/6
A)
Question: In a pet shop there are 120 eyes and 172 legs. How many birds and puppies are included in these?
A.Birds=34 , Puppies=26
B.Birds=36 , Puppies=26
C.Birds=34 , Puppies=20
D.Birds=32 , Puppies=24
Answer: A.Birds=34 , Puppies=26
Explanation: Let there are x birds and y puppies.
Each bird and puppy has 2 eyes. Each bird has 2 legs and each puppy has 4 legs.
Then
2x+2y = 120 => x+y = 60----------(1)
2x+4y = 172 => x+2y = 86-----------(2)
Solving (i) and (ii) we get
y = 26 & x = 34
So birds are 34 and puppies are 26. Answer : A
Question: Two boats are heading towards each other at constant speeds of 4 miles/hr and 20 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ?
A.1/12
B.6/15
C.1/6
D.1/3
Answer: B.6/15
Explanation: The question asks: how far apart will they be 1 minute=1/60 hours before they collide?
Since the combined rate of the boats is 4+20=25 mph then 1/60 hours before they collide they'll be rate*time=distance --> 24*1/60=6/15miles apart.
Answer: B.
Question: 0.009/x=0.03. find the value of X
A.0.0003
B.0.03
C.0.3
D.3
Answer: C.0.3
Explanation: x=0.009/0.03=0.3
ANSWER:C
Question: find the ratio of 8th and 4th term of sequence 3.1, 6.2, 12.4, .....?
A.16
B.12
C.4
D.8
Answer: A.16
Explanation: a= first term = 3.1
r = common ratio = 6.2/3.1 = 2 ====> 4th term = a * r^(4-1) = 3.1 * (2)^3 = 24.8 and 8th term = 3.1 * (2)^7 = 396.8
Ratio of a8/a4 = 396.8/24.8 = 16 ------Ans- A
Question: A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangule, whose length and breadth are in the ratio of 6 : 5. What is the area of the rectangle?
A.70 cm2
B.30 cm2
C.66 cm2
D.55 cm2
Answer: B.30 cm2
Explanation: The circumference of the circle is equal to the permeter of the rectangle.
Let l = 6x and b = 5x 2(6x + 5x) = 2 * 22/7 * 3.5
=> x = 1
Therefore l = 6 cm and b = 5 cm Area of the rectangle = 6 * 5 = 30 cm2
Answer: B
Question: Eight friends met for lunch at an expensive restaurant, and everyone decided to contribute equally to the total bill of $680. If one of the friends had a coupon for 12% off the total bill, and if each friend still contributed equally after the coupon was applied to the bill, how much did each friend pay?
A.$90
B.$74
C.$45
D.$37
Answer: B.$74
Explanation: 680 * 0,12 = 81
680 - 81 = 599
599 / 8 = 74
Answer B
Question: A train crosses a platform of 150 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
A.150
B.2787
C.277
D.279
Answer: A.150
Explanation: Length of the train be ‘X’
X + 150/15 = X + 250/20
4X + 600 = 3X + 750
X = 150m
Answer: A
Question: P and Q started a business with respective investments of Rs. 4 lakhs and Rs. 10 lakhs. As P runs the business, his salary is Rs. 5000 per month. If they earned a profit of Rs. 2 lakhs at the end of the year, then find the ratio of their earnings?
A.1:8
B.1:6
C.2:1
D.1:1
Answer: D.1:1
Explanation: Ratio of investments of P and Q is 2 : 5
Total salary claimed by P = 12 * 5000 = Rs. 60000
Total profit = Rs. 2 lakhs.
Profit is to be shared = Rs. 140000
Share of P = (2/7) * 140000 = Rs. 400000
Share of Q = Rs. 100000
Total earnings of P = (60000 + 40000) = Rs. 100000
Ratio of their earnings = 1:1
Answer:D
Question: If the area of circle is 520 sq cm then its circumference?
A.11
B.81
C.99
D.266
Answer: B.81
Explanation: 22/7 r2 = 520 => r = 12.9
2 * 22/7 * 12.9 = 81 Answer: B
Question: CP of two houses are Rs.1.995 lakhs each. On one gains 5% and on the other, loses 5%. What is the gain or loss percent in the whole transaction?
A..23%
B..25%
C..30%
D..50%
Answer: B..25%
Explanation: If a person sells two items at the same price; one at a gain of x % and another at a
loss of x %, then the seller always incurs a loss expressed as
Loss%=(Common Loss and Gain%10)2=(x10)2So in this case, he will have a loss. Loss%=(510)2=(12)2=(14)=.25%
B
Question: Rs.1070 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share?
A.Rs.190
B.Rs.260
C.Rs.493
D.Rs.393
Answer: C.Rs.493
Explanation: A+B+C = 1070
4A = 3B = 2C = x
A:B:C = 1/4:1/3:1/2 = 3:4:6
6/13 * 1070 = Rs.493
ANSWER:C
Question: If an object travels at six feet per second, how many feet does it travel in one hour?
A.30
B.21600
C.720
D.1800
Answer: B.21600
Explanation: Speed = 6 feet per second.
1 Hour= 60X60 Seconds = 3600 Seconds.
Total no of feet traveled in 1 hour = 3600X6 = 2160X10 =21600
Answer B
Question: Three friends Alice, Bond and Charlie divide $1260 amongs them in such a way that if $10, $20 and $30 are removed from the sums that Alice, Bond and Charlie received respectively, then the share of the sums that they got will be in the ratio of 10 : 20 : 30. How much did Charlie receive?
A.$490
B.$630
C.$500
D.$510
Answer: B.$630
Explanation: A+B+C = 1260
Given ratio 10:20:30
Let us say the shares of A,B,C deducting 10,20,30 be a,b,c
a+b+c = 1260-60= 1200 = 60K
c share = (1200X30)/60 = 600
C = charlie share = 600+30 = 630
Option B
Question: A walks at 4 kmph and 4 hours after his start, B cycles after him at 10 kmph. How far from the start does B catch up with A?
A.62.6 km
B.26.7 km
C.22.8 km
D.19.5 km
Answer: B.26.7 km
Explanation: Sol.
Suppose after x km from the start B catches up with A. Then, the difference in the time taken by A to cover x km and that taken by B to cover x km is 4 hours.
∴ x/4 - x/10 = 4 or x = 26.7 km.
Answer B
Question: What least value must be assigned to * so that th number 197*5462 is divisible by 9?
A.2
B.4
C.6
D.1
Answer: A.2
Explanation: Let the missing digit be x
Sum of digits = (1+9+7+x+5+4+6+2)=34+x
For 34+x to be divisible by 9 , x must be replaced by 2
The digit in place of x must be 2.
ANSWER A 2
Question: Find the value of x from this equation? 7(x - 1) = 21
A.2
B.3
C.4
D.6
Answer: C.4
Explanation: 1. Divide both sides by 7:
2. Simplify both sides:
x - 1 = 3
3. Add 1 to both sides:
x - 1 + 1 = 3 + 1
4. Simplify both sides:
x = 4
C
Question: What is his percentage profit made by Felix if he purchased 21 dozen t-shirts at Rs. 12 per dozen. He sold 7 dozens at 15% profit and the remaining 14 dozens with 18% profit?
A.18%
B.17%
C.15%
D.13%
Answer: B.17%
Explanation: Explanation :
C.P of 21 dozen = Rs.(12 x 21) = Rs.252
C.P of 7 dozen = Rs. (12 x7) = Rs. 84.
C.P of 14 dozen =Rs. (12 x14) = Rs. 168
profit on 7 dozen at 15% = 15/100*84 = 12.6
profit on 14 remaining dozen at 18% = 18/100*168 = 30.24
total profit = 12.6 + 30.24 = 42.84
% profit = ?/100*252 = 42.84
= 17%
Answer : B
Question: A certain manufacturer of cake, muffin, and bread mixes has 100 buyers, of whom 50 purchases cake mix, 40 purchase muffin mix, and 15 purchase both cake mix and muffin mix. If a buyer is to be selected at random from the 100 buyers, what is the probability that the buyer selected will be one who purchases neither cake mix nor muffin mix?
A.1/10
B.3/10
C.1/4
D.7/10
Answer: C.1/4
Explanation: C+M+B-CM-MB-CB-2CMB = 100
C - cake buyers, M - muffin and B - Bread buyers. CM,MB,CB and CMB are intersecting regions.
the question asks for people who have bought only bread mixes = B-CB-MB-2CMB has to be found out.
50 + 40 + B-CB-MB-15-2CMB = 100
B-CB-MB-2CMB = 25
hence the probability = 25/100 = 1/4.
C
Question: In an island, there are four men for every three women and five children for every three men. How many children are there in the island if it has 531 women ?
A.454
B.1180
C.1070
D.389
Answer: B.1180
Explanation: The ratio of Women : Men = 3 : 4
Men : Children = 3 : 5
The combined ratio,
Women : Men : Children = 9 : 12 : 20
In this ratio, 9 ==> 531 Women
Thus, 20 ==> 1180 Children
ANSWER:B