RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The sum of the two numbers is 11 and their product is 24. What is the sum of the reciprocals of these numbers ?
A.11/24
B.11/25
C.13
D.13/15
Answer: A.11/24
Explanation: Let the numbers be
x
x and
y
y Then
x
+
y
=
11
x
y
=
24
x+y=11xy=24
Hence,
x
+
y
x
y
=
11
24
x+yxy=1124
⇒
1
y
+
1
x
=
11
24
Answer is A
Question: A car covers a distance of 1932 km in 7 hours. Find its speed?
A.104
B.288
C.271
D.276
Answer: D.276
Explanation: 1932/7 = 276 kmph
Answer: D
Question: If point A coordinates are (-4, -3) point B coordinates are (8 ,4 ) if C is along the line A-B so that AC = 1/2 CB. What are the coordinates of point C.
A.(-2, - 2/3)
B.(2, -2/3)
C.(2/3, -2)
D.(0, 2)
Answer: A.(-2, - 2/3)
Explanation: Look at the diagram below:
Line segment.pngSince, AC= 1/2 CB, then AC = 1/3 AB. This implies that point C is closer to A than to B, which on the other hand implies that the x-coordinate of C must be less than (-4+8)/2=0.5. Only D and A fits, but as (0 , 2) is clearly not on line segment AB, then the answer must be A.
Answer: A.
Question: Kim purchased n items from a catalog for $8 each. Postage and handling charges consisted of $4 for the first item and $1 for each additional item. Which of the following gives the total dollar amount for Kim’s purchase, including postage and handling, in terms of n ?
A.8n + 2
B.8n + 4
C.9n + 2
D.9n + 3
Answer: D.9n + 3
Explanation: its C
n items for $8 each
total price $8n
postage and handling of $3 for 1st item and $1 for the rest
total postage and handling = $ [4+ (n-1)]
= $ n+3
total cost
8n+n+3 = 9n+3
D
Question: Mr. Hanson has a pool of money from which to give out Christmas bonuses to his 5 employees. He wants all his employees to have identical bonuses, but when he divides them out, he finds he has 2 dollars left over, as the payroll system will only accept whole dollar amounts. The next Christmas, Mr. Hanson discovers the pool for the bonuses is 3 times the size. This time, how much money will be left over?
A.0
B.1
C.2
D.3
Answer: B.1
Explanation: Set x = to amount of money for bonuses, and y to be the amount of each individual bonus.
x = 5*y +2.
3x = 15*y+6
3x = 3*5*y + 6
3x = 5(3(y+1))+1
Remainder is then 1, so option B.
Question: Katie has 9 employees that she must assign to 3 different projects. If 3 employees are assigned to each project and no one is assigned to multiple projects, how many different combinations L of project assignments are possible?
A.252
B.1,680
C.2,340
D.362,880
Answer: B.1,680
Explanation: The ways to select three employees out of 9 for first project = 9C3
The ways to select three employees out of Remaining 6 for Second project = 6C3
Third Project already has the group of three to be assigned to it so need to select that
So total ways to assign 3 employees to each of 3 projects L= 9C3 * 6C3 * 1 = 1,680
Answer: Option B
Question: A lady grows cabbage in her garden that is in the shape of a square. Each cabbage takes 1 square foot of area in her garden. This year, she has increased her output by 127 cabbages when compared to last year. The shape of the area used for growing the cabbage has remained a square in both these years. How many cabbages did she produce this year?
A.4096
B.4098
C.5000
D.5096
Answer: A.4096
Explanation: Explanatory Answer
The shape of the area used for growing Cabbage has remained a square in both the years.
Let the side of the square area used for growing Cabbage this year be X ft.
Therefore, the area of the ground used for cultivation this year = X2 sq.ft.
Let the side of the square area used for growing Cabbage last year be Y ft.
Therefore, the area of the ground used for cultivation last year = Y2 sq.ft.
As the number of cabbage grown has increased by 127, the area would have increased by 127 sq ft because each cabbage takes 1 sq ft space.
Hence, X2 - Y2 = 127
(X + Y)(X - Y) = 127.
127 is a prime number and hence it will have only two factors. i.e., 127 and 1.
Therefore, 127 can be expressed as product of 2 numbers in only way = 127 * 1
i.e., (X + Y)(X - Y) = 127* 1
So, (X + Y) should be 127 and (X - Y) should be 1.
Solving the two equations we get X = 64 and Y = 63.
Therefore, number of cabbage produced this year = X2 = 642 = 4096.
Alternative Approach : Use answer choices
The area in both the years are squares of two numbers.
That rules out choice B,C and D. as 4098,5000 and 5096 are not the square of any number.
Check Choice A: If this year's produce is 4096, last year's produce would have been 4096 - 127 = 3969
3969 is the square of 63.
So, 4096 is the answer.
Choice A
Question: Out of 15 consecutive numbers, 2 are chosen at random. The probability that they are both odds or both primes is?
A.1/2
B.1/7
C.1/8
D.1/1
Answer: B.1/7
Explanation: A leap year has 52 weeks and two days
Total number of cases = 7
Number of favourable cases = 1
i.e., {Saturday, Sunday}
Required Probability = 1/7
Answer:B
Question: What is the probability that when a hand of 5 cards is drawn from a well shuffled deck of 52 cards,
it contains all Queens?
A.192/379017
B.192/379015
C.379015/192
D.1/379015
Answer: B.192/379015
Explanation: nCr = n!/(n-r)!r!
Total number of possible hands = 52C5
52C5 = 2274090
Number of hands with 4 Queens = 4C4 × 48C1
4C4 = 24
48C1 = 48
(other 1 card must be chosen from the rest 48 cards)
Hence P (a hand will have 4 Queens) = (4C4 × 48C1)/52C5 = 192/379015.
B
Question: Kiran travels from A to B by car and returns from B to A by cycle in 7 hours. If he travels both ways by car he saves 3 hours. What is the time taken to cover both ways by cycle?
A.10
B.16
C.15
D.15
Answer: A.10
Explanation: Let the time taken to cover from A to B in car and cycle be x hours and y hours respectively.
x + y = 7 --- (1) ; 2x = 4 --- (2)
solving both the equations, we get y = 5
So, time taken to cover both ways by cycle = 2y hours = 10 hours.
Answer: A
Question: Two trains are traveling on parallel tracks in the same direction. The faster train travels at 130 miles per hour, while the slower train travels at 100 miles per hour. At 2 o’clock the faster train is 15 miles behind the slower one. How far apart are the two trains at 5 o'clock?
A.60 miles
B.80 miles
C.75 miles
D.120 miles
Answer: C.75 miles
Explanation: Answer = C. 75 miles
Relational speed = 130 - 100 = 30 miles per hour
In 3 hours, difference = 30 * 3 = 90 miles
Fast train trailing 15 miles, so effective difference = 90 - 15 = 75 miles
Question: Two cars cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower car takes 1 hour more than the faster car.
A.873
B.838
C.960
D.838
Answer: C.960
Explanation: Explanation:
60(x + 1) = 64x
X = 15
60 * 16 = 960 km
Answer: Option C
Question: The average earning of amechanic for the first 4days of a week is Rs.18 and for the last four days is Rs.22. If heearns Rs.20 on the fourth day, his average earning forthe whole week is?
A.Rs. 10
B.Rs. 20
C.Rs. 30
D.Rs. 40
Answer: B.Rs. 20
Explanation: Total earning for the week = Sum of earning of first four days + Sum of earning of last four days - Earning of 4th day
= 4 x18 + 4 x 22 -20
= Rs. 140
∴ Average earning = 140 / 7
= Rs. 20
B
Question: A Sum of Rs.2600, is lent out in 2 parts SI at 10% for 5yrs is equal to SI on 2nd part at 9% rate for 6 yrs. find the ratio of parts.
A.23:21
B.27:25
C.25:27
D.23:29
Answer: B.27:25
Explanation: Solution :
Given SI1 = SI 2
P1 : P2 = 1/R1T1 : 1/R2T2
= 1/(10*5) : 1/(9:6)
27:25
B
Question: In a kilometer race, A beats B by 50 meters or 10 seconds. What time does A take to complete the race?
A.347
B.190
C.388
D.277
Answer: B.190
Explanation: Time taken by B run 1000 meters = (1000 * 10)/50 = 200 sec.
Time taken by A = 200 - 10 = 190 sec.
Answer: B
Question: In a park there are two ponds with both brown ducks and green ducks. In the smaller pond there are 20 ducks and in the larger pond there are 80 ducks. If 20% of the ducks in the smaller pond are green and 15% of the ducks in the larger pond are green, then what percentage of ducks are green?
A.13%
B.14%
C.15%
D.16%
Answer: D.16%
Explanation: Number of ducks in small pond = 20
green ducks in small pond = 20 % of 20 = 4 ducks
Number of ducks in large pond = 80
green ducks in large pond = 15 % of 80 = 12 ducks
Total number of ducks = 20 + 80 = 100
total number of green ducks = 4 + 12 = 16 ducks
percentage of green ducks = 16/100 * 100 = 16%
Answer: D
Question: At a party, everyone shook hands with everybody else. There were 66 handshakes.
How many people were at the party?
A.15
B.18
C.11
D.12
Answer: D.12
Explanation: D
12
If there are n people,
the first person will shake hand with n-1 persons,
the second with n-2,
the third with n-3,
and
the (n-1)th person with n-(n-1)=1 person means the last person.
Hence, total handshakes are (n-1)+(n-2)+(n-3)+….+3+2+1
Which can be equated using n(n-1)/2=66
Hence, n=12
Question: Find the area of the square, one of whose diagonals is 5.9 m long ?
A.37.14m^2
B.17.4m^2
C.8.96m^2
D.7.8m^2
Answer: B.17.4m^2
Explanation: Area of the square= 1/2(diagonal)^2
=(1/2*5.9*5.9)m^2
= 17.4 m^2
Answer (B)
Question: During a trip on an expressway, Don drove a total of x miles. His average speed on a certain 5-mile section of the expressway was 30 miles per hour, and his average speed for the remainder of the trip was 60 miles per hour. His travel time for the x-mile trip was what percent greater than it would have been if he had traveled at a constant rate of 40 miles per hour for the entire trip?
A.8.5%
B.50%
C.200/x%
D.60/x%
Answer: C.200/x%
Explanation: Say x = 5 miles (so no remainder of the trip).
Time to cover x = 5 miles at 30 miles per hour = (time) = (distance)/(rate) = 5/30 = 1/6 hours = 10 minutes.
Time to cover x = 5 miles at 60 miles per hour = (time) = (distance)/(rate) = 5/60 = 1/12 hours = 5 minutes.
(Or simply, half rate will result in doubling the time.)
So, we can see that the time to cover x = 5 miles at 30 miles per hour (10 minutes) is 100% greater than the time to cover x = 2 miles at 40 miles per hour (5 minutes).
Now, plug x = 2 miles into the answer choices to see which one yields 100%. Only answer E works.
Answer: C.
Question: The inverse ratio of 9: 2: 1 is?
A.1:9:18
B.2:9:18
C.2:7:18
D.2:13:18
Answer: B.2:9:18
Explanation: 1/9: 1/2: 1/1 = 2:9:18
ANSWER:B
Question: The price of a commodity was raised by 25%. So what is % amount of commodity would be reduced by family so that the amount spent on the commodity remains same
A.10%
B.20%
C.30%
D.40%
Answer: B.20%
Explanation: say price of commodity is 100
after raising price by 25% new price=125
to make it 100 again,
25=125*x/100, x% has to be reduced ie:20%
ANSWER:B
Question: An investor bought 200 shares of stock in ABCD company in 1990. By 1992, the investment was worth only 2/3 of its original value. By 1995, the 200 shares were worth only 1/4 of their value in 1990. By what percent did the value of the investment drop from 1992 to 1995?
A.62.5%
B.25%
C.33 1/3%
D.50%
Answer: A.62.5%
Explanation: Let price of each share in 1990 = X.
Total cost in 1990 = 200X
Now Price in 1992 = 2/3 * 200X = 400/3 * X
Now price in 1995 = 1/4 *200X= 50X
%Change in 1995 from 1992 = [(400/3* X -50X) / (400/3 *X) ] *100 = 62.5%
Answer A
Question: A train 300 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?
A.5 sec
B.9 sec
C.12 sec
D.18 sec
Answer: D.18 sec
Explanation: Speed of the train relative to man = (68 - 8) kmph
= (60* 5/18) m/sec = (50/3)m/sec
Time taken by the train to cross the man
= Time taken by It to cover 300 m at 50/3 m / sec = 300 *3/ 50 sec = 18 sec
Answer : D.
Question: A trader has 1600 kg of sugar. He sells a part at 8% profit and the rest at 12% profit. If he gains 11% on the whole , find the quantity sold at 12%?
A.1000
B.1200
C.1400
D.1450
Answer: B.1200
Explanation: By rule of alligation,
% Profit by selling part1	% Profit by selling part2
8	12
Net % Profit
11
12 - 11 = 1	11 - 8 = 3
=> Quantity of part1 : Quantity of part2 = 1 : 3
Given that total quantity = 1600 kg
Hence, quantity of part2 (quantity sold at 12% profit)
=
1600
×
3
4
=1200
B)
Question: The price of the jewel, passing through three hands, rises on the whole by 65%. If the first and the second sellers 20% and 25% profit respectively find the percentage profit earned by the third seller.
A.20
B.10
C.15
D.25
Answer: B.10
Explanation: Let the original price of the jewel be $ p and let the profit earned by the third seller be x% Then, (100+x)% of 125% of 120% of P =165% Of P ((100+X)/100*125/100*120/100*P)=(165/100*P)
==> (100+X)=(165*100*100)/(125*120)=110=>X=10%
Answer B) 10
Question: Juan is a gold medalist in athletics. In the month of May, if Juan takes 12 seconds to run y yards, how many seconds will it take him to run x yards at the same rate?
A.10x/y
B.11x/y
C.9x/y
D.12x/y
Answer: D.12x/y
Explanation: velocity=distance/time;
since he ran at same rate both d tyms,
y/12=x/t
so t=12x/y
ANSWER:D
Question: x^2 + dx + 72 = 0 has two distinct integer roots; how many values are possible for d?
A.3
B.6
C.8
D.12
Answer: D.12
Explanation: For a quadratic equation ax^2+dx+c=0, we know that -d/a is sum of roots and c/a is product of roots.
The quadratic equation here is x^2 + dx + 72 = 0, where product of roots is 72.
If we find all the factors of 72, we have the answer.
By prime factorization, we get 72= 2^3*3^2.
We know that total factors are (3+1)*(2+1) = 12 (Reason: with 2^n, we have n+1 possibilities. n^0 to n^n. so n+1)=D
Question: 495 x 495 = ?
A.250000
B.250025
C.5000
D.245025
Answer: D.245025
Explanation: 495 x 495 = (495 )2
= (500 - 5)2
= (500)2 + (5)2 - (2 x 500 x 5)
= 250000+ 25 - 5000
= 250025 - 5000
=245025.
D)
Question: An gun can take a maximum of four shotsat an enemyplane moving away from it. The probability of hitting the plane at the 1st, 2nd, third and 4th shots are 1.4, 1.3, 1.2 & 1.1 respectively. What is the probability that the plane is hit when all the four shots are fired?
A.0.6976
B.0.7893
C.0.8212
D.0.7541
Answer: A.0.6976
Explanation: Required probability:
=(0.4×0.7×0.8×0.9)+(0.6×0.3×0.8×0.9)+(0.6×0.7×0.2×0.9)+(0.6×0.7×0.8×0.1)+(0.4×0.3×0.8×0.9)+(0.4×0.7×0.2×0.9)+(0.4×0.7×0.8×0.1)+(0.6×0.3×0.2×0.9)+(0.6×0.3×0.8×0.1)+(0.6×0.7×0.2×0.1)+(0.4×0.3×0.2×0.9)+(0.6×0.3×0.2×0.1)+(0.4×0.3×0.8×0.1)+(0.4×0.7×0.2×0.1)+(0.4×0.3×0.2×0.1)=(0.4×0.7×0.8×0.9)+(0.6×0.3×0.8×0.9)+(0.6×0.7×0.2×0.9)+(0.6×0.7×0.8×0.1)+(0.4×0.3×0.8×0.9)+(0.4×0.7×0.2×0.9)+(0.4×0.7×0.8×0.1)+(0.6×0.3×0.2×0.9)+(0.6×0.3×0.8×0.1)+(0.6×0.7×0.2×0.1)+(0.4×0.3×0.2×0.9)+(0.6×0.3×0.2×0.1)+(0.4×0.3×0.8×0.1)+(0.4×0.7×0.2×0.1)+(0.4×0.3×0.2×0.1)
=0.2016+0.1296+0.756+0.336+0.864+0.504+0.224+0.324+0.144+0.0084+0.0216+0.0036+0.0096+0.0056+0.002=0.2016+0.1296+0.756+0.336+0.864+0.504+0.224+0.324+0.144+0.0084+0.0216+0.0036+0.0096+0.0056+0.002
=0.6976=0.6976
Edit: Thank you Vaibhav for providing an alternative method.
Alternate Method:
probability that the plane is hit when all the four shots are fired,
P=1−probability of not hitting the targetP=1−probability of not hitting the target
=1−(0.6×0.7×0.8×0.9)=1−(0.6×0.7×0.8×0.9)
=1−0.3024=1−0.3024
=0.6976
A
Question: If j and k are two positive integers and j/k = 1.05, then j can equal which one of the following?
A. 15
B. 21
C. 20
D. 22
Answer: B. 21
Explanation: j/k = 1.05 = 105/100 = 21/20
So, j COULD equal 21
Answer: B
Question: It rained as much as on Wednesday as on all the other days of the week combined. If the average rainfall for the whole week was 2 cms, How much did it rain on Wednesday?
A.10.9
B.7
C.10.2
D.10.1
Answer: B.7
Explanation: Explanation:
Let the rainfall on wednesday = 6x.
âˆ´ Rainfall on the remaining days = 6x
Given,
(6x + 6x )/7 = 2
â‡’12x = 14
â‡’6x = 7
Answer: B
Question: A rectangular grass field is 95 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m?
A.1350
B.1550
C.9676
D.1679
Answer: B.1550
Explanation: Area = (l + b +2d) 2d
= (95 + 55 +2.5 * 2) 2*2.5 => 775
775 * 2 = Rs.1550
Answer:B
Question: Anmol can eat 27 pastries in a hour.
Aakriti can eat 2 pastries in 10 minutes.
Divya can eat 7 pastries in 20 minutes.
How long will it take them to eat a 360 pastries ?
A.6 hours.
B.1 hours.
C.5 hours.
D.4 hours.
Answer: A.6 hours.
Explanation: In one hour, Anmol eats 27 pastries, Aakriti eats 12, and Divya eats 21. A total of 60 pastries. Therefore 360 pastries would take 360 ÷ 60 = 6 hours.
ANSWER A
Question: In a simultaneous throw of pair of dice .find the probability of getting the total more than 7
A.3/7
B.12/5
C.5/12
D.5/7
Answer: C.5/12
Explanation: Here n(S)=(6*6)=36
let E=event of getting a total more than 7
={(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)}
P(E)=n(E)/n(S)=15/36=5/12.
Ans: C
Question: ACME’s manufacturing costs for sets of horseshoes include a $11,450 initial outlay, and $19.75 per set. They can sell the sets $52.00. If profit is revenue from sales minus manufacturing costs, and the company producessells 987 sets of horseshoes, what was their profit?
A.$20,380.75
B.$30,943.25
C.$41,308.50
D.$51,817.50
Answer: A.$20,380.75
Explanation: its A
since options are not so close we can solve this by uniting calculation and guessing
total sales will be bit lower than 52000
from that initial outlay will get deducted 11500 so we left with 31500
variable cost say 20 X 1000 = 20000 will be deducted so finally we left with 20500
since we have considered the price greater than it actually is, the correct answer will certainly not cross the threshold of 20500.
Question: Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man?
A.22
B.35
C.56
D.70
Answer: D.70
Explanation: Possible groups = Possible groups of 3 women * possible groups of 1 men
Since order does not matter, its a combination problem.
=[5!/(3!2!)} * [7!/(6!1!)]
=70
ANSWER:D
Question: In a throw of dice what is the probability of getting number greater than 5
A.1/2
B.1/3
C.1/5
D.1/6
Answer: D.1/6
Explanation: Explanation:
Number greater than 5 is 6, so only 1 number
Total cases of dice = [1,2,3,4,5,6]
So probability = 1/6
Option D
Question: Points A and B are both in the line segment PQ and on the same side of its midpoint. A divides PQ in the ratio 2:3, and B divides PQ in the ratio 3:4. If AB=2, then the length of PQ is:
A.70
B.75
C.80
D.85
Answer: A.70
Explanation: Explanation :
Let, PA=2x and AB=3x and PB=3y and BQ=4y
PB:BQ=3:4
PA:QA=2:3
PQ=5x=7y
x=7/5 -------------------(i)
From equation (i) and (ii), we have
=>AB=PQ−PA−BQ.
=>7y−4y−2x,
=>3y−2x=2. (AB = 2 ) --------------------(ii)
=>y=10 and Hence, PQ = 70.
Answer : A
Question: In a six-sided polygon EQRSTV ∠E measures 48° less than the average (arithmetic mean) of the remaining five angles. What does ∠E equal to, in degrees?
A. 72
B. 80
C. 88
D. 96
Answer: B. 80
Explanation: The sum of interior angle in a polygon is (n-2)*180
so for a six sided figure, (6-2)*180 = 720
let the A.M of the other 5 angles be 'm'
--> m*5 + ∠E = 720, we know ∠E=m-48
--> m*5 + m - 48 = 720, solving we get m=128
hence ∠E= 128-48 = 80
Ans B.
Question: The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.
A.48.0
B.48.55
C.49.05
D.49.0
Answer: B.48.55
Explanation: Average weight of 16 boys = 50.25
Total weight of 16 boys = 50.25 × 16
Average weight of remaining 8 boys = 45.15
Total weight of remaining 8 boys = 45.15 × 8
Total weight of all boys in the class = (50.25 × 16)+ (45.15 × 8)
Total boys = 16 + 8 = 24
Average weight of all the boys = ((50.25×16)+(45.15×8))/24
=(50.25×2)+(45.15×1)/3
=(16.75×2)+15.05
=33.5+15.05=48.55
Answer is B.
Question: When a number is divided by 6 &then multiply by 12 the answer is 9 what is the no.?
A.4.5
B.5
C.5.5
D.5.8
Answer: A.4.5
Explanation: if $x$ is the number, x/6 * 12 = 9
=> 2x = 9
=> x = 4.5
A
Question: At a certain organisation, the number of male members went up by 12% in the year 2001 from year 2000, and the number of females members went down by 4% in the same time period. If the total membership at the organisation went up by 1.2% from the year 2000 to 2001, what was the ratio of male members to female members in the year 2000?
A.1:2
B.1:3
C.2:3
D.3:2
Answer: A.1:2
Explanation: men increase by 12% ==> 1.12M = males in 2001
women decrease by 4% ==> 0.96F = women in 2001
total employees increase by 1.2% ==> 1.012*(M + F) = total number of employees in 2001
Obviously
(males in 2001) + (females in 2001) = total number of employees in 2001
1.12M + 0.96F = 1.012*(M + F)
1.12M + 0.96F = 1.012M + 1.012F
1.12M - 1.012M = 1.012F - 0.96F
0.108M = 0.052F
M/F = (0.052)/(0.108) = 52/108 = 1/2
Answer =(A)
Question: A garden center sells a certain grass seed in 5-pound bags at $13.85 per bag, 10-pound bags at $20.43 per bag, and 25-pound bags $32.20 per bag. If a customer is to buy at least	65 pounds of the grass seed,	but no more than 80 pounds,	what is the least possible cost of the grass seed that the customer will buy?
A.$94.03
B.$96.75
C.$98.68
D.$102.07
Answer: C.$98.68
Explanation: there can be 2 cases
1)25+25+10+5=$98.68 or
2)25+25+25=$96.60
C
Question: The length of a rectangle is reduced by 22%. By what % would the width have to be increased to maintain the original area?
A.14%
B.15%
C.28%
D.30%
Answer: C.28%
Explanation: Sol. Required change = (22*100)/(100-22)=28.2%
C
Question: A flagpole 18 meters high casts a shadow of length 45 meters. If a building under similar conditions casts a shadow of length 70 meters, what is the height of the building (in meters)?
A.20
B.24
C.28
D.32
Answer: C.28
Explanation: The height:length ratio will be equal in both cases.
18 / 45 = x / 70
x = 28
The answer is C.
Question: A 160 meter long train crosses a man standing on the platform in 4 sec. What is the speed of the train?
A.176 kmph
B.144 kmph
C.176 kmph
D.134 kmph
Answer: B.144 kmph
Explanation: S = 160/4 * 18/5
= 144 kmph
Answer: B
Question: The price of the jewel, passing through three hands, rises on the whole by 68%. If the first and the second sellers 20% and 25% profit respectively find the percentage profit earned by the third seller.
A.20
B.12
C.15
D.25
Answer: B.12
Explanation: Let the original price of the jewel be $ p and let the profit earned by the third seller be x% Then, (100+x)% of 125% of 120% of P =168% Of P ((100+X)/100*125/100*120/100*P)=(168/100*P)
==> (100+X)=(168*100*100)/(125*120)=112=>X=12%
Answer B)
Question: Kamal bought a house, whose sale price was Rs. 8 lakh. He availed 20% discount as an early bird offer and then 10% discount due to cash payment. After that he spent 10% of the cost price in interior decoration and lawn of the house. At what price should he sell the house to earn a profit of 25%?
A.Rs. 9 lakh
B.Rs. 7.99 lakh
C.Rs. 7.92 lakh
D.Rs. 7 lakh
Answer: C.Rs. 7.92 lakh
Explanation: Solution: Let the marked price be 100.
100 == 20% ↓(discount)==> 80 == 10% ↓(discount)==> 72(CP) == 10% ↑(interior)==> 79.2(Total CP)
Now, selling price would be 25% above the Total cost price.
SP = 79.2 + 25% of 79.2
SP = 99
Now, On comparing,
100 ==> 800000
99 ==> (800000/100) *99 ==> 7, 92,000
So,
SP = Rs. 7, 92, 000.
Answer: Option C
Question: In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
A.2/3
B.3/4
C.7/19
D.8/21
Answer: D.8/21
Explanation: Solution
Total number of balls	= (8 + 7 + 6)
= 21.
Let E = event that the ball drawn is neither red nor green
=event that the ball drawn is red.
Therefore, n(E) = 8.
P(E) = 8/21.
Answer D
Question: A tank contains 10,000 gallons of a solution that is 5 percent sodium chloride by volume. If 3,500 gallons of water evaporate from the tank, the remaining solution will be approximately what percent sodium chloride?
A.6.43%
B.6.89%
C.7.69%
D.8.21%
Answer: C.7.69%
Explanation: The amount of sodium chloride is 0.05*10,000 = 500 gallons
500/6500 = 1/13 which is about 7.69%
The answer is C.