RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Weights of two friends Ram and Shyam are in the ratio 3:5. If Ram's weight is increased by 10% and total weight of Ram and Shyam become 82.8 kg, with an increases of 15%. By what percent did the weight of Shyam has to be increased?
A.18%
B.10%
C.21%
D.16%
Answer: A.18%
Explanation: Solution:
given ratio of Ram and Shayam's weight = 3:5
Hence, (x-15)/(15-10) = 3/5
Or, x = 18%.
Answer: Option A
Question: The average age of 20 students in a class is 5years. If teacher's age is also included then average increases 1year then find the teacher's age?
A.28
B.24
C.20
D.22
Answer: C.20
Explanation: Total age of 50 students = 20*5 = 100
Total age of 51 persons = 20*6 = 120
Age of teacher = 120-100 = 20years
Answer is C
Question: A student chose a number, multiplied it by 2, then subtracted 138 from the result and got 108. What was the number he chose?
A.123
B.267
C.277
D.267
Answer: A.123
Explanation: Let xx be the number he chose, then
2â‹…xâˆ’138=108
x=123
Answer:A
Question: 140 college students were asked in a survey if they preferred Windows or Mac brand computers. 80 Students claimed that they preferred Mac to Windows brand computers. One third as many of the students who preferred Mac to Windows, equally preferred both brands. 50 of the students had no preference. How many of the students in the survey preferred Windows to Mac brand computers?
A.25
B.10
C.50
D.60
Answer: B.10
Explanation: 140 = 80(Mac) + x(Window) + 50(both) => x=10
ANSWER:B
Question: If n is a positive integer such that
n!/(n-2)! = 342, find n.
A.17
B.18
C.19
D.20
Answer: C.19
Explanation: We write n! = n*(n-1)(n-2!)
Therefore
n!/(n-2)! = n(n-1)*(n-2)!/(n-2)! = n(n-1).
--> n(n-1) = 342
--> n^2 -n - 342 = 0
--> n^2- 19n +18n -342 = 0
--> n(n-19) +18(n -19) = 0
--> (n-19)(n+18) = 0
Therefore n -19 = 0; n +18 = 0;
(i.e) n =19 ; n = -18
We want positive integer. So, n=19.
ANSWER:C
Question: A merchant marks his goods up by 40% and then offers a discount of 20% on the marked price. What % profit does the merchant make after the discount?
A.12%
B.10%
C.21%
D.15%
Answer: A.12%
Explanation: Let the price be 100.
The price becomes 140 after a 40% markup.
Now a discount of 20% on 140.
Profit=112-100
12%
answer A
Question: The radius of a cone is 49 m, slant height is 35 m. Find the curved surface area?
A.5160
B.5390
C.6430
D.6720
Answer: B.5390
Explanation: Cone curved surface area = Ï€rl
22/7 Ã— 49 Ã— 35 = 154 Ã— 35 = 5390 m(power2)
Answer is B.
Question: At a certain amateur bands rock show the ratio of freaks to nerds to geeks is 1:2:3. If these are the only types of people in the crowd, and each person in the crowd has the same chance of yelling "rock on!", what are the chances that the next person who yells "rock on!" will be a geek?
A.1/6
B.1/3
C.1/2
D.2/3
Answer: C.1/2
Explanation: the ratio of freaks to nerds to geeks is 1:2:3.
So, Assuming the number as x,2x and 3x for freaks , nerds and geeks respc.
Probability of next person being Geek = 3x/total
or 3x/6x= 1/2. Hence , C.
Question: The product of n^2 consecutive positive integers is always divisible by
A.n^2 -1
B.(n+1)!
C.2n +1
D.n^2 + 1
Answer: A.n^2 -1
Explanation: Plug in some vlues and check -
Product of first 2 number is 2*1
Product of first 3 number is 3*2*1
Product of first 4 number is 4*3*2*1
Product of first 5 number is 5*4*3*2*1
So, The product of first n natural numbers is always divisible by n! , answer will be (A)
Question: If a boat goes 5km upstream in 25 minutes and the speed of the stream is 7 kmph, then the speed of the boat in still water is ?
A.18
B.19
C.20
D.21
Answer: B.19
Explanation: Rate upsteram =(5/25*60)kmph=12kmph.
speed of the stream =7kmph let speed in still water be xkm/hr. then speed upstream=(x-7)km/hr. x-7=12==>x=19km/hr Answer(B)
Question: Write 450,000,000,000 in scientific notation.
A.400.50 * 10 11
B.400.5 * 10 11
C.40.5 * 10 11
D.4.5 * 10 11
Answer: D.4.5 * 10 11
Explanation: a * 10 n , where a is a real number such that 1 * |a| < 10 and n is an integer.
450,000,000,000 = 4.5 * 100,000,000,000 = 4.5 * 10 11**
correct answer D
Question: The Racing magic takes 60 seconds to circle the racing track once. The Charging bull makes 40 rounds of the track in an hour. If they left the starting point together, how many minutes will it take for them to meet at the starting point for the second time?
A.3
B.6
C.9
D.12
Answer: B.6
Explanation: Time taken by Racing magic to make one circle = 60 seconds
Time taken byCharging bullto make one circle = 60 mins / 40 = 1.5 mins = 90 seconds
LCM of 90 and 60 seconds = 180 seconds
Time taken for them to meet at the starting point for the second time = 180 *2 =360 seconds= 6 mins
Answer B
Question: Shekhar started a business investing Rs.25,000 in 1999.In 2000,he invested an additional amount of Rs.10,000 and Rajeev joined him with an amount of Rs.35,000.In 2001,Shekhar invested another additional amount of Rs.10,000 and Jatin joined them with an amount of Rs.35,000.What will be Rajeev’s share in the profit of Rs.2,10,000 earned at the end of 3 years from the start of the business in 1999 ?
A.Rs.45,000
B.Rs.50,000
C.Rs.70,000
D.Rs.75,000
Answer: C.Rs.70,000
Explanation: Solution
Shekhar : Rajeev : Jatin
= (25000x12+35000x12+45000x12) :(35000x24) : (35000x12)
= 1260000 : 840000 : 420000 = 3 : 2 : 1.
∴ Rajeev’s share = Rs.(21000x2/6) = Rs. 70,000. Answer C
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8339 for a computer table, then what was the cost price of the computer table?
A.Rs.6727
B.Rs.6735
C.Rs.6721
D.Rs.6725
Answer: D.Rs.6725
Explanation: CP = SP * (100/(100 + profit%))
= 8339(100/124)
= Rs.6725.
Answer: D
Question: The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 2500 resolutions?
A.1187 m
B.1704 m
C.2179 m
D.3520 m
Answer: D.3520 m
Explanation: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 2500 resolutions.
= 2500 * 2 * 22/7 * 22.4
= 352000 cm
= 3520 m
Answer:D
Question: The present population of a town is 500. Population increase rate is 10% p.a. Find the population of town before 2 years?
A.512
B.615
C.810
D.413
Answer: D.413
Explanation: P = 500
R = 10%
Required population of town = P/(1 + R/100)^T
= 500/(1 + 10/100)^2
= 500/(11/10)^2
= 413(approximately)
Answer is D
Question: 70, 75, 80, 85, 90, 105, 105, 130, 130, 130
The list shown consists of the times, in seconds, that it took each of 10 schoolchildren to run a distance of 400 on of meters. If the standard devastation of the 10 running times is 23.4 seconds, rounded to the nearest tenth of a second, how many of the 10 running times are more than 1 standard deviation below the mean of the 10 running times?
A.one
B.two
C.three
D.four
Answer: B.two
Explanation: The most time consuming part in this question is to define the mean. Under exam pressure and time pressure it is very easy to make mistake.
it is easier to group numbers: 130*3=390; 105*2=210; 75+85=160; 70+80=150; 90;
Next stage combine results, again using more convenient ways to calculate: 390+210=600; 160+150=310; 90. 600+310+90=1000. Since there are 10 numbers the mean is 100. Questions asks to find the quantity of numbers one SD BELOW the mean, which is 100-23,4=76,6. There are only two numbers below 76,6. The answer is B
Question: The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
A.12 years
B.14 years
C.18 years
D.20 years
Answer: D.20 years
Explanation: Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 6 = 5(x - 6)
54 - x = 5x - 30
6x = 84
x = 14.
Son's age after 6 years = (x+ 6) = 20 years.. Answer: Option D
Question: In the third grade of Windblown School there are 108 students, one third of them failed the math test and 1/6 failed that literature test. At least how many students failed both tests?
A.0.
B.6.
C.8.
D.10
Answer: A.0.
Explanation: One third of them failed the math test = 1/3 of 108 = 36. Passed in math test = 82.
And 1/6 failed that literature test = 18.
It is a possible scenario that these 18 (failed in literature) were the ones who passed the math test. So in this case, no one failed in both.
Hence A.
Question: One urn contains two pieces of candy{one green and one red. A second urn
contains four pieces of candy{one green and three red. For each urn, each piece of candy is
equally likely of being picked. You pick a piece of candy from each urn and eat the two chosen
candies.
If you eat exactly one piece of green candy, you draw a second piece of candy from the urn
still containing a green piece of candy. You now eat the candy you just chose. What is the
probability that you ate two pieces of green candy?
A.1/8
B.1/4
C.3/8
D.1/2
Answer: C.3/8
Explanation: There are four possibilities for the rst round:
You pick a green piece of candy from each urn. (Probability 1/2*1/4=1/8)
You pick the green piece of candy from the rst urn and the red piece of candy from the
second. (Probability 1/2 * 3/4 = 3/8 :) You have a 1/3 chance of eating the green piece of candy
on the second round (since three pieces of candy remain in the second urn, and one of
them is green.You pick the red piece of candy from the rst urn and the green piece of candy from the
second. (Probability 1/2 *1/4 = 1/8 :) There is only one more piece of candy in the rst urn,
so you eat it on the second round.
You pick a red piece of candy from each urn. (Probability 1/2 *3/4 = 3/8 .)
Your chance of eating two pieces of green candy is
1/8
+
3/8
1/3
+
1/8
=
3/8
correct answer C
Question: An athlete runs 200 meters in 24 seconds. His speed is ?
A.10 km/hr
B.17 k/hr
C.27 km/hr
D.30 km/hr
Answer: D.30 km/hr
Explanation: ExplanaƟon:
Speed=DistanceTime=20024m/sec=253m/sec253
∗
185km/hr=30km/hr
Answer: D
Question: In an election between the two candidates ,The candidates who gets 60% of votes polled is wined by 280 votes majority. What is the total number of votes polled?
A.1400
B.1500
C.1550
D.1600
Answer: A.1400
Explanation: Note : majority (20 %) = difference in votes polled to win (60 %) & defeated candidates (40 %)
20 % = 60 % - 40 %
20% -----> 280 (20×14 = 280 )
100% -----> 1400 (100×14 = 1400)
A
Question: Two numbers are in the ratio 3 : 4. If their L.C.M. is 48. what is sum of the numbers?
A.28
B.56
C.76
D.84
Answer: A.28
Explanation: Explanation:
Let the numbers be 3x and 4x
LCM of 3x and 4x = 12x (Since LCM of 3 and 4 is 12. Hence LCM of 3x and 4x is 12x)
Given that LCM of 3x and 4x is 48
=> 12x = 48
=> x = 48/12 = 4
Sum of the numbers
= 3x + 4x
= 7x
= 7 x 4 = 28
Answer: Option A
Question: How many options are there for a code consisting of 2 even digits followed by 2 odd digits?
A.4^5
B.5^4
C.5^5
D.4^4
Answer: B.5^4
Explanation: Even Numbers = 5 digits { 0 , 2 , 4 , 6 , 8 }
Odd Numbers = 5 digits { 1 , 3 , 5 , 7 , 9 }
EVEN EVEN ODD ODD
No of ways is 5*5*5*5 = 5^4
Hence, correct, answer must be (B) 5^4
Question: Evaluate the expression
[x : (y - 3)] ⋅ (-4) - [xy + (-3)] : -1 = ?
when x = -5 and y = -2
A.3
B.4
C.5
D.6
Answer: A.3
Explanation: Solution:
Evaluate the expression
[x : (y - 3)] ⋅ (-4) - [xy + (-3)] : -1 =
[(-5) : (-2 - 3)] ⋅ (-4) - [(-5) ⋅ (-2) + (-3)] : -1 =
[(-5) : (-5)] ⋅ (-4) - [10 + (-3)] : -1 =
(+1) ⋅ (-4) - (+7) : -1 = -4 - (-7) = -4 + 7 = 3
Answer A
Question: If the given two numbers are respectively 7% and 28% of a third number, then what percentage is the first of the second ?
A.20%
B.25%
C.18%
D.30%
Answer: B.25%
Explanation: Here, l = 7 and m = 28
Therefore, first number = l/m x 100% of second number = 7/28 x 100% of second number = 25% of second number
ANSWER:B
Question: Two trains each 250 m in length are running on the same parallel lines in opposite directions with the speed of 80 kmph and 70 kmph respectively. In what time will they cross each other completely?
A.11 sec
B.15 sec
C.19 sec
D.12 seconds
Answer: D.12 seconds
Explanation: D
D = 250 m + 250 m = 500 m
RS = 80 + 70 = 150 * 5/18 = 125/3
T = 500 * 3/125 = 12 sec
Question: If y = 35p, and p is prime, what is the greatest common factor of y and 14p, in terms of p?
A.p
B.2p
C.5p
D.7p
Answer: D.7p
Explanation: y = 35p = 5*7*p
14p = 2*7*p
The greatest common factor of 35p and 14p is the product of all the common prime factors, using the lower power of repeated factors. The greatest common factor is 7*p = 7p
The answer is D.
Question: A man can do a piece of work in 6days, but with the help of his son, he can finish it in 3days. In what time can the son do it alone?
A.5
B.5 1/2
C.7 1/2
D.6
Answer: D.6
Explanation: Son's 1day work = 1/3 - 1/6 = 1/6
Son alone can do the work in 6 days = 6 days
Answer is D
Question: A circular mat with diameter 20 inches is placed on a square tabletop, each of whose sides is 30 inches long. Which of the following is closest to the fraction of the tabletop covered by the mat?
A.5/12
B.0.3489
C.1/2
D.3/4
Answer: B.0.3489
Explanation: C.
It is a circle inscribed in a square.
Square side=30---> square(table) area=30^2
Circle diameter=20---> Circle area=PiR^2=100Pi (where Pi=~3.14)
covered fraction=100*3.14/30*30=~314/30*30=3.14/9=0.3489
B
Question: If apples are bought at the rate of 30 for Rs.100. How many apples must be sold for Rs.100 so as to gain 20%?
A.28
B.25
C.20
D.22
Answer: B.25
Explanation: SP for 30 apples to gain 20%= 100*120/100 =120
so 30 apples must be sold for rs 120
rs 120= 30 apples
rs 100= (30/120)*100 =25 apple
ANSWER:B
Question: How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
A.13.1 sec
B.12.1 sec
C.22.1 sec
D.32.1 sec
Answer: B.12.1 sec
Explanation: Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 110 + 132 = 242 m.
Required time = 242/20 = 12.1 sec.
Answer:B
Question: Nicky and Cristina are running a 300 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him?
A.40
B.50
C.30
D.60
Answer: C.30
Explanation: The distance traveled by both of them is the same at the time of overtaking.
3(t+12) = 5t
t=18.
Cristina will catch up Nicky in 18 seconds.
So in 18 seconds Cristina would cover = 18*5 = 90 meter.
Now Time taken my Nicky to cover 90 meter = 90/3 = 30 Seconds.
C
Question: Ifaequals the sum of the even integers from 2 to 20, inclusive, andbequals the sum of the odd integers from 1 to 19, inclusive, what is the value of (a - b)/2 ?
A.1
B.10
C.19
D.5
Answer: D.5
Explanation: Answer is 10
Yes! there is really a faster way to solve it.
Sum of consecutive odd or even integers = (no. of odd or even ints) * (first int + last int) / 2
Here A = sum of even ints from 2 to 20, inclusive
number of even ints = 10,
first int + last int = 2+20 = 22
A = 10*22 / 2 = 110
B = sum of odd ints from 1 to 19, inclusive
number of odd ints = 10,
first int + last int = 1+19 = 20
A = 10*20 / 2 = 100
(A-B)/2 = 110 - 100 = 10/2=5
Ans :D
Question: Replace X with the appropriate number in
4 , 5 , 14 , 15 , 24 , 25 , X
A.30
B.29
C.34
D.21
Answer: C.34
Explanation: C
list of consecutive numbers that has an 'f' in the spelling
Question: What should come in place of the question mark (?) in the following equation?
10000+ 566 = 45+ ?
A.73689
B.35876
C.45943
D.10521
Answer: D.10521
Explanation: 10000+ 566 = 45+ ?
10000+ 566 – 45= 10521
Answer D
Question: A sum at simple interests at 13 ½ % per annum amounts to Rs.2502.50 after 4 years find the sum.
A.1525
B.1625
C.1725
D.1825
Answer: B.1625
Explanation: let the sum be x=P
then sum(P)+(P*R*T)/100=2502.50
therefore
x+(x*4*13.5)/100=2502.50
x=1625
ANSWER:B
Question: Chang Li has pet cockroaches that multiply at the same rate every week.
The first week he had 5, the next week he had 10, the second week he had 20, and the fourth week he had 80. How many did he have on week 3?
A.30
B.25
C.40
D.60
Answer: C.40
Explanation: The answer is C) 40, because the cockroaches are doubling in size every week- half of 80 is 40, and 20 doubled is 40.
Question: If the positive integer x is a multiple of 5 and the positive integer y is a multiple of 6, then xy must be a multiple of which of the following?
I. 8
II. 12
III 18
A.II only
B.I and II only
C.I and III only
D.II and III only
Answer: C.I and III only
Explanation: Ans C.
From question x/4 is an integer.
x/4 = 2*2*q/4 ---> where q is the integer
Also y/6 = p => y/6 = 2*3*p/6
So, xy = 2*2*2*3 *pq
Thus 2*2*2 = 8 and 2*3*2 = 12 satisfy
C
Question: Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 km more than the second. The distance between P and Q is?
A.767 km
B.975 km
C.678 km
D.900 km
Answer: D.900 km
Explanation: At the time of meeting, let the distance traveled by the second train be x km. Then, distance covered by the first train is (x + 100) km.
x/40 = (x + 100)/50
50x = 40x + 4000 => x = 400
So, distance between P and Q = (x + x + 100)km =900 km.
Answer: D
Question: Danny bought 2Q steaks for W dollars. Jerome buys R steaks for a 50% discount, how much will the steaks cost him in cents?
A.50RW/Q.
B.50QR/W.
C.25RQ/W.
D.25RW/Q.
Answer: D.25RW/Q.
Explanation: Danny bought 2Q steaks for W dollars, so 1 steak = W/2Q
Jerome buys R steaks for a 50% discount: r* (W/4Q)
in cents the answer will be : r* (100 W/4Q)= 25 RW/Q
Question: The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is?
A.23
B.21
C.52
D.56
Answer: B.21
Explanation: Let the total number of workers be x. Then,
8000x
= (12000 * 7) + 6000(x - 7)
= 2000x = 42000
= x =21.
Answer:B
Question: When a certain perfect square is increased by 148, the result is another perfect square. What is the value of the original perfect square?
A.1296
B.1369
C.1681
D.1764
Answer: A.1296
Explanation: Let’s call the two perfect squares x^2 and y^2, respectively. Then the given information translates as x^2+148=y^2. Subtracting x^2 gives 148=y^2−x^2, a difference of squares. This, in turn, factors as (y+x)(y−x)=148.
The next step is tricky. It begins with factoring 148, which breaks down as 2∗2∗37. Since we’re dealing with perfect squares, x and y are positive integers, and (y+x) and (y−x) must be paired integer factors of 148. The options are 148∗1,74∗2, and 37∗4. But our number properties establish that (y+x) and (y−x) must be either both odd or both even, so only 74∗2 is an actual possibility. And because for any positive integers (y+x)>(y−x), we can conclude that y+x=74 and y–x=2. Solving by elimination, 2y=76, y=38, and x=36.
Finally, we just need to square 36 . But rather than multiplying it out, note that 36^2 ends in 6 – as does only one answer, choice A. This answer must be the one we want.
Question: If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?
A.120000
B.120029
C.187899
D.178968
Answer: A.120000
Explanation: X * (105/100) * (105/100) * (105/100) = 138915
X = 138915/1.157625
X = 120000
Answer:A
Question: If G = 775 × 778 × 781, what is the remainder when G is divided by 14?
A.6
B.7
C.8
D.9
Answer: A.6
Explanation: G 775/14 leaves a remainder 5
778/14 leaves a remainder 8
781/14 leaves a remainder 11
5*8*11 =440
So the remainder will be the remainder of 440/14 which is 6
Ans A
Question: ABCDEFGHI is a regular polygon with nine sides. What is the measure in degrees of angle ACB?
A.18
B.20
C.25
D.27
Answer: B.20
Explanation: the formula of sum of angles in a polygon of sides n=(n-2)*180
so sum of angles=7*180..
therefore each angle ,angle ABC=7*180/9=140..
when we join A and C to make a triangle ABC, it becomes an isosceles triangle with AB and BC equal..
so angle ACB=angleCAB=(180-140)/2=20..
ans B
Question: An uneducated retailer marks all his goods at 40% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the marked price. What is his actual profit on the sales?
A.12.50 %
B.13.50 %
C.5 %
D.14.50 %
Answer: C.5 %
Explanation: Sol.
Let C.P. = Rs. 100. Then, marked price = Rs. 140.
S.P. = 75% of Rs. 140 = Rs. 105.
∴ Gain% = 5%.
Answer C
Question: 21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement.
A.1/15
B.3/53
C.9/42
D.6/15
Answer: C.9/42
Explanation: The probability that first toy shows the even number,
=1021=1021
Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.
Hence, probability that second toy shows the even number,
=920=920
Required probability,
=(1021)×(920)=(1021)×(920)
=9/42
C
Question: The maximum numbers of students among them 451 pens and 410 toys can be distributed in such a way that each student gets the same number of pens and same number of toys is
A.41
B.910
C.1001
D.1911
Answer: A.41
Explanation: olution
Required number of students.
= H.C.F of 451 and 410.
â€¹=â€º41.
Answer A
Question: If you cut a 18ft piece of wood into two pieces making one piece 4ft longer than the other. What size is the smaller piece?
A.4ft
B.6ft
C.8ft
D.7ft
Answer: D.7ft
Explanation: Total length is 18ft, one piece is 4ft longer (x+4), leaving the other piece to figure out (x).
(x)+ (x+4)=18
x+x+4-4=18-4
2x=14
2x/2=14/2
x=7
The piece is D) 7ft.
Question: When is |x-14| = 14-x?
A.x=14
B.x=0
C.x>14
D.x<=14
Answer: D.x<=14
Explanation: When is |x-14| = 14-x?
Choice A: X=14, it is true but X cannot be always 14
Choice B: X=0, it is also true, but X cannot be always 0
Choice C: X>14, it is false, for e.g. X=6, then one side of equation is 2 and the other side is -2
Choice D: X<=14, this choice encapsulate Choice A, Choice B and for all other conditions and is true for above said equation. Hence the answer choice is D.
Question: The average age of a husband, wife and their child 5 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is?
A.10.1 years
B.54 years
C.11.4 years
D.12.6 years
Answer: C.11.4 years
Explanation: Sum of the present ages of husband, wife and child
= (23 * 2 + 5 * 2) = 57 years.
Required average
= 57/5
= 11.4 years.
Answer:C
Question: What least no. must be subtracted from 427398 so that remaining no.is divisible by 10?
A.8
B.9
C.7
D.6
Answer: A.8
Explanation: Explanation:
On dividing 427398 by 10 we get the remainder 8, so 8 should be subtracted
Option A
Question: If the selling price of 50 articles is equal to the cost price of 30 articles, then the loss or gain percent is:
A.40%
B.23%
C.20%
D.60%
Answer: A.40%
Explanation: C.P. of each article be Re. 1.
Then, C.P. of 50 articles = Rs. 50;
S.P. of 50 articles = Rs. 30.
Loss % = 20/50 * 100 = 40%
ANSWER A
Question: If 4 spiders make 3 webs in 9 days, then how many days are needed for 1 spider to make 1 web?
A.9
B.12
C.27
D.24
Answer: B.12
Explanation: Explanation:
Let, 1 spider make 1 web in x days.
More spiders, Less days (Indirect proportion)
More webs, more days (Direct proportion)
Hence we can write as
(spiders)4:1
(webs) 1:9}::x:3
â‡’4Ã—1Ã—9=1Ã—3 Ã— x
â‡’x=12
Answer: Option B
Question: Find out the C.I on Rs.9000 at 4% p.a. compound half-yearly for 1 1/2 years
A.550.87
B.506.07
C.506.04
D.506.03
Answer: A.550.87
Explanation: A = 9000(51/50)3
= 9550.87
9000
-----------
550.87
Answer:A
Question: A customer bought a product at the shop. However, the shopkeeper increased the price of the product by 10% so that the customer could not buy the required amount of the product. The customer managed to buy only 80% of the required amount. What is the difference in the amount of money that the customer paid for the second purchase compared to the first purchase?
A.10%
B.12%
C.14%
D.16%
Answer: B.12%
Explanation: Let x be the amount of money paid for the first purchase.
The second time, the customer paid 0.8(1.1x)=0.88x.
The difference is 12%.
The answer is B.
Question: The population of a town increased from 75,000 to 2,25,000 in a decade. The average percent increase of population per year is :
A.20%
B.5%
C.6%
D.8.75%
Answer: A.20%
Explanation: Solution
Increase in 10 year= (225000 - 75000) = 150000.
Increase% =( 150000/75000x 100 )% = 200%
âˆ´ Required average = ( 200/10 )% = 20%
Answer A