RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: In measuring the sides of a rectangle, one side is taken 16% in excess and other 5% in deficit. Find the error percentage in the area calculated from these measurements.
A.3.5%
B.2.4%
C.10.2%
D.5%
Answer: C.10.2%
Explanation: Say both sides of the rectangle are equal to 100 (so consider that we have a square). In this case the area is 100*100=10,000.
Now, the area obtained with wrong measurements would be 116*95=11,020, which is 10.2% greater than the actual area.
Answer: C.
Question: The sale price shirts listed f or Rs.400 after successive discount is 10% and 5% is?
A.280
B.290
C.Rs.342
D.250
Answer: C.Rs.342
Explanation: 400*(90/100)*(95 / 100) = 342
C
Question: Find the fraction which has the same ratio to 2/13 that 5/34 has to 7/48.
A.240/1577
B.240/1527
C.240/1547
D.240/1518
Answer: C.240/1547
Explanation: P : 2/13 = 5/34 : 7/48
As the product of the means is equal to the product of the extremes.
P*7/48 = 2/13 * 5/34
P*7/48 = 10/442
P = 480/3094 => P = 240/1547
Answer:C
Question: In a certain parking lot, 10% of the cars are towed for parking illegally. However 80% of the cars which are parked illegally are not towed. What percentage of cars in the parking lot are parked illegally?
A.30%
B.40%
C.50%
D.60%
Answer: C.50%
Explanation: Let x be the number of cars and let y be the number of cars parked illegally.
10%*x = 20%*y
y/x = 1/2 = 50%
The answer is C.
Question: There are 12 red shoes, 7 green shoes. If one draw randomly a shoe what is the probability of getting a red shoe
A.11/19
B.12/19
C.15/19
D.14/19
Answer: B.12/19
Explanation: total 19 from take one.
19c1=19
red 12 from one
12c1=12
12/19
ANSWER:B
Question: If inflation increases at a rate of 8 p.c.p.a. what will a 20 article cost at the end of two years?
A.Between 20 and 21
B.Between 21 and 22
C.Between 22 and 23
D.Between 23 and 24
Answer: D.Between 23 and 24
Explanation: Required sum
= 20(1+8/100)2=20×27×27/25×25=23.3
Answer D
Question: If rupee one produces rupees nine over a period of 42 years, find the rate of simple interest?
A.22 1/7 %
B.22 3/2 %
C.21 3/7 %
D.22 1/2 %
Answer: C.21 3/7 %
Explanation: 9 = (1*42*R)/100
R = 21 3/7 %
Answer:C
Question: Two pens and three pencils cost Rs 86. four Pens and a pencil cost Rs. 112. find the cost of a pencil.
A.10
B.11
C.12
D.13
Answer: C.12
Explanation: 1 pen cost x,let 1 pencil cost y
2x+3y=86, ...y=(86-2x)/3
again,
4x+y=112
4x+(86-2x)/3=112
12x+86-2x=336
10x=250
x=25,
y=(86-50)/3=12
ANSWER:C
Question: The remainder obtained when a prime number greater than 4 is divided by 4 is
A.a) 1 or 3
B.b) 1 or 5
C.c) 3 or 5
D.d) 4 or 5
Answer: A.a) 1 or 3
Explanation: The easiest way to answer this question is probably to pick numbers. Use the next two prime numbers greater than 4, i.e. 7 and 5:
7/4 = 1 + remainder of 3
5 / 4 = 1 + remainder of 1
This is already sufficient to see that answer choice a) is correct.
A
Question: The batting average of a particular batsman is 60 runs in 46 innings. If the difference in his highest and lowest score is 160 runs and his average excluding these two innings is 58 runs, find his highest score.
A.184
B.367
C.269
D.177
Answer: A.184
Explanation: Explanation:
Total runs scored by the batsman = 60*46 = 2760 runs
Now excluding the two innings the runs scored = 58*44 = 2552 runs
Hence the runs scored in the two innings = 2760 â€“ 2552 = 208 runs.
Let the highest score be x, hence the lowest score = x â€“ 160
x + (x - 160) = 208
2x = 368
x = 184 runs
ANSWER: A
Question: If r and s are positive integers and r-s=6, which of the following has the greatest value J?
A.2r
B.2s
C.r +s
D.2r-s
Answer: A.2r
Explanation: You can answer this question by using Number Properties and logic or by TESTing VALUES.
We're told that R and S are POSITIVE INTEGERS and that R-S = 6. We're asked which of the 5 answers has the GREATEST value.
IF....
R = 8
S = 2
Answer A: 2R = 2(8) = 16
Answer B: 2S = 2(2) = 4
Answer C: R+S = 8+2 = 10
Answer D: 2R-S = 2(8) - 2 = 14
Answer E: 2S-R = 2(2) - 8 = -4
Final Answer:
A
Question: It takes 35 identical printing presses 12 hours to print 500,000 papers. How many hours would it take 30 of these printing presses to print 500,000 papers?
A.14
B.15
C.16
D.18
Answer: A.14
Explanation: 35 printing presses can do 1/12 of the job each hour.
30 printing presses can do 6/7*1/12 = 1/14 of the job each hour.
The answer is A.
Question: Salesperson A's compensation for any week is $300 plus 6 percent of the portion of A's total sales above $1,000 for that week. Salesperson B's compensation for any week is 8 percent of B's total sales for that week. For what amount of total weekly sales would both salepeople earn the same compensation?
A.$21,000
B.$12,000
C.$15,000
D.$ 4,500
Answer: B.$12,000
Explanation: sometime, setting up an equation is an easy way to go with:
300 + 0.06 (x - 1000) = 0.08 x
x = 12,000
Ans : B
Question: In a apartment, 30% of the people speak English, 20% speak Hindi and 10% speak both. If a people is selected at random, what is the probability that he has speak English or Hindi?
A.1/3
B.1/5
C.2/5
D.3/7
Answer: C.2/5
Explanation: P (E) = 30 / 100 = 3 / 10 , P (H) = 20 / 100 = 1 / 5 and P (E ∩ H) = 10 / 100 = 1 / 10
P (E or H) = P (E U H)
= P (E) + P (H) - P (E ∩ H)
= (3 / 10) + (1 / 5) - (1 / 10) = 4 / 10 = 2/5
C
Question: A train 600 m long can cross an electric pole in 20 sec and then find the speed of the train?
A.117 Kmph
B.178 Kmph
C.172 Kmph
D.108 Kmph
Answer: D.108 Kmph
Explanation: Length = Speed * time
Speed = L/T
S = 600/20
S = 30 M/Sec
Speed= 30*18/5 (To convert M/Sec in to Kmph multiply by 18/5)
Speed = 108 Kmph
Answer: D
Question: A rectangular tiled patio is composed of 30 square tiles. The rectangular patio will be rearranged so that there will be 2 fewer columns of tiles and 4 more rows of tiles. After the change in layout, the patio will still have 30 tiles, and it will still be rectangular. How many rows are in the tile patio before the change in layout?
A.5
B.6
C.10
D.13
Answer: A.5
Explanation: Suppose there are c columns and there are r rows
Original Situation
So, Number of tiles = c*r = 30
Also. Reach column has r tiles and each row has c tiles
New Situation
Number of tiles in each column is r-2 and number of tiles in each row is c+4
So, number of rows = r-2 and number of columns is c+4
So, Number of tiles = (r-2)*(c+4) = 30
Comparing both of them we get
c*r = (r-2)*(c+4)
=> 4r -2c = 8
c = 2r - 4
Putting it in c*r=30
(2r-4)*r = 30
2r^2 - 4r - 30=0
r cannot be negative so r =5
and c = 6
So, Answer will be A
Question: If 1+2+3+...+n=n (n+1), then
2 (1+3+5+....+89)=?
A.4100
B.4050
C.4250
D.4350
Answer: B.4050
Explanation: Explanation :
To solve this use the formula of AP,
Sn= (n/2)(a+l) ................(1)
To find n, use
=> Tn= a+(n-1)d
=> 89=1+(n-1)2
=> n=45
Use value of n in (1)
then,
Sn = (45/2)(1+89) = 2025
Ans:- 2(Sn) = 4050
Answer : B
Question: A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
A.186 m
B.176 m
C.872 m
D.150 m
Answer: D.150 m
Explanation: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train
= (Speed x Time) = (50/3 * 9) m
= 150 m.
Answer: D
Question: There are 9 days of school left. Cassie has $50. How much money does Cassie's mom need to give her in order for Cassie to spend $6 on lunch for each of the nine remaining school days?
A.$1
B.$2
C.$4
D.$6
Answer: C.$4
Explanation: For Cassie to spend $6 a day for nine days, she must multiply 9 days by $6 = $54. $54 minus $50 = $4. Hence the answer : C.
Question: John had a stock of 1200 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold?
A.50.4%
B.23.8%
C.66.5%
D.34.9%
Answer: C.66.5%
Explanation: Let N be the total number of books sold. Hence
N = 75 + 50 + 64 + 78 + 135 = 402
Let M be the books NOT sold
M = 1200 - N = 1200 - 402 = 798
Percentage
Books not sold / total number of books = 798/1200 = 0.665 = 66.5%
correct answer C
Question: The proportion of water to alcohol in Solution A is 2:1 and the proportion of water to alcohol in Solution B is 2:3. If an equal amount of each solution is mixed together, what is the concentration of alcohol in the new solution?
A.46.7%
B.47.3%
C.48.4%
D.50.6%
Answer: A.46.7%
Explanation: Let V be the total volume of the new solution.
Then a volume of V/2 was added from each solution A and B.
The amount of alcohol added to the new solution was:
(1/3)(V/2)+(3/5)(V/2)=V/6+3V/10=14V/30=7V/15.
The concentration of alcohol is 7/15=46.7%
The answer is A.
Question: Three numbers are in the ratio 3:5:7. The largest number value is 49. Find difference between Smallest & largest number is?
A.20
B.24
C.26
D.28
Answer: D.28
Explanation: == 3:5:7
Total parts = 15
= The largest number value is 49
= The largest number is = 7
= Then 7 parts -----> 49 ( 7 * 7 = 49 )
= smallest number = 3 & Largest number = 7
= Difference between smallest number & largest number is = 7 - 3 = 4
= Then 4 parts -----> 28 (4 * 7 = 28)
D
Question: A certain company has records stored with a record storage firm in 15-inch by 12-inch by 10-inch boxes. The boxes occupy 1.08 million cubic inches of space. If the company pays $0.8 per box per month for the record storage, what is the total amount that the company pays each month for record storage?
A.a. 480
B.b. 300
C.c. 600
D.d. 410
Answer: A.a. 480
Explanation: Volume Per Box: 15x12x10 = 1,800
Total Volume: 1,080,000
Number of Boxes: Total Volume / Volume Per Box = 1,080,000 / 1,800 = 600
Price Per Month: Number of Boxes * Price Per Box = 600 * 0.8 = 480
Answer: A
Question: Two numbers are respectively 20% and 25% more than a third number. The percentage that is first of the second is?
A.86%
B.56%
C.96%
D.98%
Answer: C.96%
Explanation: I II III
120 125 100
125----------120
100-----------? => 96%
Answer:C
Question: The number 0.127 is how much greater than 1/8 ?
A.1/100
B.1/1500
C.1/2
D.1/500
Answer: D.1/500
Explanation: Explanation:
0.127 expressed as a fraction = 127/1000
1/8 can also be expressed as (1 x 125) / (8 x 125) = 125/1000
The difference is 2/1000, which is 1/500
ANSWER IS D
Question: What quantity of water should be added to reduce 9 liters of 50% acidic liquid to 30% acidic liquid?
A.6liters
B.8liters
C.10liters
D.12liters
Answer: A.6liters
Explanation: Acid in 9 liters = 50% of 9 = 4.5 liters
Suppose x liters of water be added.
Then 4.5 liters of acid in 9+x liters of diluted solution
30% of 9+x = 4.5
27+3x = 45
x = 6liters
Answer is A
Question: The average salary of workers in an industry is Rs.300 the average salary of technicians being Rs.400 and that of non-technicians being Rs.125. What is the total number of workers?
A.230
B.234
C.250
D.547
Answer: B.234
Explanation: 400 125
\ /
300
/ \
175 100
7:4
7->150
11->?
=>234
ANSWER:B
Question: The edges of three metal cubes are 1 cm, 2 cm, and 4 cm respectively. A new cube is made by melting these three cubes together. What is the edge of the new cube (in centimeters)?
A.3.8
B.4.2
C.4.6
D.5.0
Answer: B.4.2
Explanation: The total volume is 1^3+2^3+4^3=73
The edge of the new cube is the cube root of 73 which is about 4.2 cm.
The answer is B.
Question: Albert buys 4 horses and 9 cows for Rs. 13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs. 1880. The cost of a horse is?
A.2888
B.2000
C.7768
D.1551
Answer: B.2000
Explanation: Let C.P. of each horse be Rs. x and C.P. of each cow be Rs. y.
Then, 4x + 9y = 13400 -- (i)
And, 10% of 4x + 20% of 9y = 1880
2/5 x + 9/5 y = 1880 => 2x + 9y = 9400 -- (ii)
Solving (i) and (ii), we get : x = 2000 and y = 600.
Cost price of each horse = Rs. 2000.
Answer:B
Question: A shopkeeper purchased 70 kg of potatoes for Rs. 420 and sold the whole lot at the rate of Rs. 6.30 per kg. What will be his gain percent?
A.8 1/7 %
B.2 1/3 %
C.5 %
D.8 1/8 %
Answer: C.5 %
Explanation: C.P. of 1 kg = 420/70 = Rs. 6
S.P. of 1 kg = Rs. 6.30
Gain % = 0.30/6 * 100 = 5
= 5 %
Answer:C
Question: A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.330. How much does C have?
A.50
B.78
C.30
D.29
Answer: C.30
Explanation: A+B+C = 500
A+C = 200
B+C = 330
--------------
A+B+2C = 530
A+B+C = 500
----------------
C = 30
Answer: C
Question: How many integers Z are prime numbers in the range 200 < Z < 220?
A. 1
B. 2
C. 3
D. 4
Answer: A. 1
Explanation: My friend, every single odd number greater than can be written either as 4Z+1 or as 4Z+3. If you divide any odd number by 4, you will get a remainder of either 1 or 3. That's not a rule unique to prime numbers at all.
The 6Z+1 or 6Z-1 rule is basically every odd number that is not divisible by three, so it narrows the search a little.
Here's how I thought about the problem. First, eliminate all the even numbers and the odd multiples of 5 in that range. That leaves us with:
{201, 203, 207, 209, 211, 213, 217, 219}
Eliminate the four multiples of 3. Notice that 21 is a multiple of 3, so 210 is also a multiple of 3. If we add or subtract 3 or 9, we get more multiples of three. When we eliminate those, we are left with.
{203, 209, 211, 217}
Now, notice that a cool thing about this range is that 210 is also a multiple 7 (again, because 21 is a multiple of 7). This means that
210 - 7 = 203
210 + 7 = 217
Those two numbers are also multiples of 7, so eliminate them from the list. Now, we are left with
{209, 211}.
We've already checked all the prime numbers less than 10, so we know that neither of these numbers is divisible by anything less than 10. We have to check 11 now. We know that 22 is a multiple of 11, so 220 is also a multiple of 11. This means that
220 - 11 = 209
is also a multiple of 11. We can eliminate this from the list also.
That leaves us with just 211. There's no zero option in the question, so this must be a prime number.
Answer = (A)
Question: The average of 6 observations is 12. A new seventh observation is included and the new average is decreased by 1. The seventh observation is :
A.1
B.3
C.5
D.6
Answer: C.5
Explanation: Explanation:
Seventh observation = (7××11-6××12)=5
Correct Option: C
Question: Two numbers N and 16 have LCM = 48 and GCF = 8. Find N.
A.11
B.32
C.24
D.48
Answer: C.24
Explanation: The product of two integers is equal to the product of their LCM and GCF. Hence.
16 * N = 48 * 8
N = 48 * 8 / 16 = 24
correct answer C
Question: A began a business with Rs. 85,000. He was joined afterwards by B with Ks. 42,500. For how much period does B join, if the profits at the end of the year are divided in the ratio of 6 : 1 ?
A.6 months
B.4 months
C.2 months
D.8 months
Answer: B.4 months
Explanation: Suppose B joined for x months . Then, ( 85000 * 12 )/(42500 * x) = 6. or x = (85000 * 12) / (42500 * 6) = 4.
So, B joined for 4 months.
Answer: B
Question: One man adds 3 liters of water to 12 liters of milk and another 4 liters of water to 10 liters of milk. What is the ratio of the strengths of milk in 2 mixtures?
A.11:21
B.15:33
C.28:25
D.3:2
Answer: C.28:25
Explanation: Strength of milk in the mixture = Quantity of milk/total quantity of mixture
strength of milk in the 1st mixture = 12/15
strength of the milk 2nd mixture = 10/14
The ratio of their strengths = 12/15 : 10/14 = 28:25
Answer is C
Question: What is the units digit of (498) (915) (381) (756) (29)
A.0
B.1
C.2
D.5
Answer: C.2
Explanation: Just multiply the digits in the units place for each term and you will get the answer. It should be 0. you got a 5 as a unit digit and an even number term. so the multiplication of this will definitely yield a 0. Answer has to be 0.
I also tried it using the calculator and the answer is 2.
IMO C.
Question: In how many ways the letters of the word ENGINEERING can be arranged?
A.200002
B.262011
C.277200
D.216181
Answer: C.277200
Explanation: Total number of ways=(11!)/(3!*3!*2!*2!*1!)
=(11*10*9*8*7*6*5*4*3!)/(3!*3*2*2*2)
=277200 ways
Option C
Question: Fence X is twice as long as fence Y, and fence Y is 1 feet shorter than fence Z. If 3 feet were added to each fence, which of the following must be true?
I) X is twice as long as Y.
II) Y is 1 feet shorter than Z.
III) X is longer than Z.
A.I only
B.II only
C.III only
D.II and III
Answer: D.II and III
Explanation: If X= 6
Y= 3
Z= 4
Then, after adding 3 feet to each:
X= 9
Y=6
Z=7
And the answer would be E, which is wrong.
D
Question: On dividing 109 by a number, the quotient is 9 and the remainder is 1. Find the divisor.
A.10
B.11
C.12
D.13
Answer: C.12
Explanation: d = (D-R)/Q
= (109 - 1)/9
= 108/9 = 12
C
Question: 120kg of an alloy A is mixed with 180 kg of alloy B. If alloy A has lead and tin in the ratio 2:3 and alloy B has tin and copper in the ratio 3:5, then the amount of tin in the new alloy is?
A.100.6kg
B.120.3kg
C.139.5kg
D.140.8kg
Answer: C.139.5kg
Explanation: Quantity of tin in 120kg of A = 120*3/5 = 72kg
Quantity of tin in 180kg of B = 180*3/8 = 67.5kg
Quantity of tin in the new alloy = 72+67.5 = 139.5kg
Answer is C
Question: 180,131,95,70,?
A.42
B.43
C.54
D.40
Answer: C.54
Explanation: 180 - 131 = 49 = 7^2
131 - 95 = 36 = 6^2
95 - 70 = 25 = 5^2
so we can write
70 - x = 16 = 4^2 , where x is the next number
x = 70 - 16 = 54
so the next number will be 54
ANSWER:C
Question: A plant manager must assign 6 new workers to one of five shifts. She needs a first, second, and third shift, and two alternate shifts. Each of the shifts will receive 2 new workers. How many different ways can she assign the new workers?
A.24
B.27
C.33
D.45
Answer: D.45
Explanation: whatever : my take selecting team of 2 out of 10 to assign to the shifts =6C2 = 15 ways.
now 2 out of 10 means total of 3 group possible.
so putting them in shifts = counting methode: first, second, third, alt , alt
= 3*2*1 = 6
here alt and alt are the same: so 6/2 = 3 ways.
total ways of selecting = (selecting 2 out of 6)*arranging those teams in shifts
= 15*3 = 45
Ans: D
Question: Albert invested an amount of Rs.8000 in a fixed deposit scheme for 2 years at compound interest rate 5 p.c.p.a. How much amount will Albert get on maturity of the fixed deposit ?
A.Rs.8600
B.Rs.8620
C.Rs.8840
D.Rs.8820
Answer: D.Rs.8820
Explanation: Solution
Amount	=Rs.[8000x(1+5/100)²]
= Rs.
[8000 x 21/20x21/20]
= Rs.8820.
Answer D
Question: If p+q=8z, then which of the following represents the average (arithmetic mean) of p, q, and z, in terms of z?
A. 2z+1
B. 3z
C. 5z
D. z/3
Answer: B. 3z
Explanation: Pick any number like P=12, Q=12 and Z= 3 so that P+Q=8Z, now then the arithmetic mean will be (12+12+3)/3=9. Now, just look at the answers and put the value of Z there.
(A) 2.3+1=7, no.
(B) 3.3=9, it can be the answer, lets check us the other options
(C) 5.3=15, no
(D) 3/3=1 no
(E) (3.3)/2=9/2, no
so the answer will be B..
Question: Due to 10% decrease in the price of sugar and John can buy 5kg more sugar in Rs100 , then find the CP of sugar?
A.Rs. 1(2/9)
B.Rs. 2(2/9)
C.Rs. 2(2/7)
D.Rs. 3(2/5)
Answer: B.Rs. 2(2/9)
Explanation: Here r = 10 % ,x = 100 and A = 5 kg
Actual price of sugar = 10*100/((100-10 )*5) = Rs. 2(2/9)
B
Question: A bag contain 4 red , 6 yellow, 5 green balls, 3 balls are drawn randomly . What is the probability that the balls drawn contain exactly two green balls ?
A.5/11
B.4/11
C.6/11
D.7/11
Answer: B.4/11
Explanation: 2 green balls can be selected from 5 green balls and the remaining one ball select from
(15-5) = 10 balls in 8C1 ways
n(E) 5C2 X 8C1
=10 X 8 =80
So, P(E) = 80/220 =4/11
Answer is B
Question: A team of 6 cooks is chosen from 6 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created?
A.140
B.320
C.275
D.700
Answer: C.275
Explanation: Only possible combinations are a team of 2M, 4 W or 3M,3W.
Possible ways to make a team of 2M,4W = 6C2 * 5C4 =15*5 =75
Possible ways to make a team of 3M,3W = 6C3* 5C3 = 20*10 = 200
Total possible ways = 75+200 = 275
Ans C it is.
Question: What percent of the different arrangements of the letters of the word ABACUS are those in which the vowels appear together?
A.10%
B.20%
C.40%
D.50%
Answer: B.20%
Explanation: The total number of different arrangements are 6!/2=360. We divide here by 2, since we have two same letters A.
Letters A, A, and U are vowels. Put them together and consider as one object. So, we have 4 different objects (AAU) B C S. The number of different arrangements of them are 4!=24. And we have 3 possibilities to arrange vowels: AAU, AUA, UAA. Therefore, we have 24*3=72 different arrangements.
Hence, 72/360*100%=20%.
The correct answer is B.
Question: The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years
A.A)3:4
B.B)3:5
C.of these
D.inadequate
Answer: C.of these
Explanation: Let P's age and Q's age be 6x and 7x years respectively.
Then, 7x - 6x = 4 => x = 4
Required ratio = (6x + 4) : (7x + 4)
28 : 32 = 7:8
ANSWER:C
Question: Three pounds of 05 grass seed contain 3 percent herbicide. A different type of grass seed, 20, which contains 20 percent herbicide, will be mixed with three pounds of 05 grass seed. How much grass seed of type 20 should be added to the three pounds of 05 grass seed so that the mixture contains 15 percent herbicide?
A.3
B.7.2
C.4.5
D.6
Answer: B.7.2
Explanation: 05 grass seed contains 5% herbicide and its amount is 3 pound
20 grass seed contains 20% herbicide and its amount is x
when these two types of grass seeds are mixed, their average becomes 15%
thus we have
3(3)+x(20)/(x+3) = 15
9+20x=15x +45
5x=36
or x=7.2
B
Question: What will be the reminder when (67^67+67) is divided by 68?
A.1
B.63
C.66
D.67
Answer: C.66
Explanation: (x^n+1) will be divisible by (x+1) only when n is odd;
(67^67+1) will be divisible by (67+1);
(67^67+1)+66 when divided by 68 will give 66 as remainder.
Correct Option : C
Question: There are 20 poles with a constant distance between each pole. A car takes 24 second to reach the 12th pole. How much will it take to reach the last pole.
A.41.4543
B.41.4545
C.41.45128
D.41.41288
Answer: B.41.4545
Explanation: Assuming the car starts at the first pole.
To reach the 12th pole, the car need to travel 11 poles (the first pole doesn't count, as the car is already there).
11 poles 24 seconds
1 pole (24/11) seconds
To reach the last (20th) pole, the car needs to travel 19 poles.
19 pole 19 x (24/11) seconds
= 41.4545 seconds
Answer:B
Question: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is?
A.3/8
B.3/2
C.3/5
D.3/9
Answer: B.3/2
Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y)
= 23 ==> 27 x + 17 y = 23 x + 23 y
==> 4 x = 6 y
==> x/y = 3/2.
Answer:B
Question: A person got Rs.60 more when he invested a certain sum at compound interest instead of simple interest for two years at 15% p.a. Find the sum?
A.7500
B.2666
C.2877
D.2667
Answer: B.2666
Explanation: P = (d * 1002) / R2
=> (60 * 100 * 100) / 15 * 15 = Rs.2666
Answer:B
Question: Q's mother is sister of P and daughter of M. S is daughter of P and sister of T.How is M related to T?
A.Grandfather
B.Grandmother
C.Father
D.Either Grandmother or Grandfather
Answer: D.Either Grandmother or Grandfather
Explanation: Explanation:
Q's mother is sister of P & daughter of M.[sex of P and M are not clear]
S is daughter of P and sister of T. [sex of P and T is not clear]
M's children : Q's mother and P
P's children :S[female] and T
\fn_cm \therefore M is either Grandmother or Grandfather of T
Answer: D
Question: Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
Year	Item of Expenditure
Salary	Fuel and Transport	Bonus	Interest on Loans	Taxes
1998	288	98	3.00	23.4	83
1999	342	112	2.52	32.5	108
2000	324	101	3.84	41.6	74
2001	336	133	3.68	36.4	88
2002	420	142	3.96	49.4	98
The total amount of Fuel paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?
A.A)0.5%
B.B)1%
C.C)1.25%
D.D)3%
Answer: B.B)1%
Explanation: Required percentage
=	(288 + 342 + 324 + 336 + 420)
=	[	17	x 100	]	%
1710
~= 1%.
Answer : B