RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).
A.178.89 cm
B.178.29 cm
C.178.79 cm
D.177.89 cm
Answer: B.178.29 cm
Explanation: Calculated average height of 35 boys = 180 cm.
Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 166 cm. Correct total height of 35 boys = 180 * 35 cm - 166 cm + 106 cm
= 180 * 35 cm - 166 cm + 106 cm/35 = 180 cm - 60 /35 cm
= 180 cm - 1.71 cm = 178.29 cm.
Answer: B
Question: In how many ways can 10 engineers and 4 doctors be seated at a round table if all the 4 doctors do not sit together?
A.13! - (10! × 4!)
B.13! × 4!
C.14!
D.10! × 4!
Answer: A.13! - (10! × 4!)
Explanation: Explanation :
Initially let's find out the total number of ways in which 10 engineers and 4 doctors
can be seated at a round table
In this case, n = total number of persons = 10 + 4 = 14
Hence the total number of ways in which 10 engineers and 4 doctors can be seated at a round table
= (14-1)! = 13! ---(A)
Now let's find out the total number of ways in which 10 engineers and 4 doctors
can be seated at a round table where all the 4 doctors sit together.
Since all the 4 doctors sit together, group them together and consider as a single doctor.
Hence, n = total number of persons = 10 + 1 = 11
These 11 persons can be seated at a round table in (11-1)! = 10! ways ---(B)
However these 4 doctors can be arranged among themselves in 4! Ways ---(C)
From (B) and (C), the total number of ways in which 10 engineers and 4 doctors
can be seated at a round table where all the 4 doctors sit together
= 10! 4! ---(D)
From (A) and (D),
The total number of ways in which 10 engineers and 4 doctors can be seated at a round table
if all the 4 doctors do not sit together = 13! - (10! 4!)
Answer : A
Question: A pipe can fill a tank in 16 hours. Due to a leak in the bottom,it is filled in 24 hours. If the tank is full, how much time will the leak take to empty it ?
A.12 hrs
B.24 hrs
C.36 hrs
D.48 hrs
Answer: D.48 hrs
Explanation: Time taken by leak to empty tank = 1/(1/16-1/24) = 48 hrs
ANSWER:D
Question: In how many different ways can 3 physics, 2 math, and 3 chemistry books be arranged in a row so that all books of the same subject are together?
A.432
B.456
C.512
D.556
Answer: A.432
Explanation: Let's think of each subject as a group so there are 3 groups.
The number of ways to arrange these 3 groups is 3!
Within each subject the books can be re-arranged.
So we need to multiply 3! by 3!*2!*3! which is 3!*3!*2!*3! = 432
The answer is A.
Question: (11^2+12^2+13^2+......+20^2)=?
A.385
B.2485
C.2870
D.3255
Answer: B.2485
Explanation: =(1^2+2^2+3^2+......+30^2)-(1^2+2^2+3^2+......+10^2)
=(20x21x41/6 - 10x11x21/6)
Therefore, (1^2+2^2+....+n^2)=1/6n(n+1)(2n+1)
=(2870-385) = 2485.
Answer is B
Question: If 36 men can do a piece of work in 25 hours, in how many hours will 14 men
do it ?
A.65 hours
B.64 hours
C.30 hours
D.62 hours
Answer: B.64 hours
Explanation: Let the required number of hours be x. Then,
Less men, More hours	(Indirect Proportion)
14 : 36 : : 25 : x	(14 x x) = (36 x 25)	(36 x 25)/14 ~ 64
Answer is B.
Question: If $ 5,000 is invested in an account that earns 16% interest compounded semi-annually, then the interest earned after one year would be how much greater than if the $ 5,000 had been invested at 8% simple yearly interest?
A.$ 4
B.$ 8
C.$ 12
D.$ 16
Answer: D.$ 16
Explanation: Solution
Amount (CI) = P+(1+r/n)^nt = 5000+(1+0.16/2)^2= 5416
Amount (SI) = P+PTR/100 = 5000+(5000*1*16/100)=5400
Difference = 5416-5400=16 $
D
Question: Consider below info to be a table:
AMOUNT OF BACTERIA
TIME - AMOUNT
1PM - 10gms
4PM - x gms
7PM - 16.9 gms
Data for a certain biology experiment are given in the table above. If the amount of bacteria present increased by the same factor during each of the two 3-hour periods shown, how many grams of bacteria were present at 4PM ?
A.12.0
B.12.1
C.12.2
D.13.0
Answer: D.13.0
Explanation: let say the factor is x, the at 7PM quantity = 10 (i.e. quantity @1PM)* x^2 =16.9 => x^2 =1.69 or x = 1.3 => @4PM quantity = 10x =10*1.3 =13.
Answer D
Question: If a discount of 16% is given on the marked price of a book, the publisher gains 20%. If the discount is increased to 20% the gain percent is
A.14 2/7%
B.14 1/7%
C.14 3/7%
D.14 4/7%
Answer: A.14 2/7%
Explanation: Let MP = 100, then SP = 100 - 16 = 84.
CP = SP*100/(100 + Gain%) = 8400/120 = 70.
When discount = 20, SP = 80.
Thus gain % = (80 - 70)/70 * 100 = 14 2/7 %.
ANSWER:A
Question: In a match in team X, 3% candidates got selected from the total appeared candidates. team X had an equal number of candidates appeared and 12% candidates got selected with 27 more candidates got selected than ream x. what was the number of candidates appeared from each team?
A.300
B.200
C.258
D.456
Answer: A.300
Explanation: Explanation :
Solution: Let the number of candidates appeared from each team be x.
then, 12% of x - 3% of x =26.
=>9% of x =27
=>9x/100 =27 => x =27*100/9 = 300
Answer : A
Question: In a college the ratio of the numbers of boys to the girls is 8:5. If there are 175 girls, the total number of students in the college is?
A.562
B.356
C.455
D.416
Answer: C.455
Explanation: Let the number of boys and girls be 8x and 5x
Then , 5x = 175
x= 35
Total number of students = 13x = 13*35 = 455
Answer is C
Question: 16.02 Ã— 0.1 = ?
A.0.1602
B.0.001602
C.1.6021
D.0.01602
Answer: C.1.6021
Explanation: 16.02 Ã— 0.1 = 1.602
The answer is C.
Question: The maximum numbers of students among them 781 pens and 710 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is
A.71
B.910
C.1001
D.1911
Answer: A.71
Explanation: olution
Required number of students.
= H.C.F of 781 and 710.
â€¹=â€º 71.
Answer A
Question: R is the set of positive even integers less than 51, and S is the set of the squares of the integers in R. How many elements does the intersection of R and S contain ?
A. None
B. Three
C. Four
D. Five
Answer: B. Three
Explanation: R is the set of positive even integers less than 51, and S is the set of the squares of the integers in R.
How many elements does the intersection of R and S contain?
R=2,4,6,8,10,12...
S=4,16,36,64...
Numbers: 4, 16, and 36 are even integers (less than 51) that are in both sets.
Solution: Three
Answer: B
Question: If 6x = 10y = 14z, then what is a possible sum of positive integers x, y, and z?
A.213
B.58
C.84
D.122
Answer: A.213
Explanation: Answer = D = 122
6x = 10y = 14z
3x = 5y = 7z
3(5*7) = 5(3*7) = 7(3*5)
Addition = 35+21+15 = 71
Answer would be multiple of 71 which is 213
Answer : A
Question: In an examination 30% failed in Math and 70% failed in French. If 20% failed in both. What % of students passed in both.
A.25%
B.15%
C.20%
D.30%
Answer: C.20%
Explanation: Passed in Math = 100 - 30 = 70%
Passed in French = 100 - 70 = 30%
Students who passed Math or French = 100 -20 = 80%
Students passed in Math and French = (Passed in Math) + (Passed in French) - (Students who passed Math or French) = 70+30-80 =20%
ANSWER:C
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
A.87
B.44
C.88
D.76
Answer: B.44
Explanation: Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352
=> T = 44.
Answer:B
Question: Should a total ban be put on traping wild animals?
Arguments:
1. Yes. Trappers are making a lot of money
2. No. Bans on hunting and trapping are not effective
A.Only 1 is true
B.Only 2 is true
C.Either 1 or 2 is true
D.Neither 1 or 2 is true
Answer: D.Neither 1 or 2 is true
Explanation: Explanation:
Ban is necessary to protect our natural envoirnment .So none of the argument is strong enough
Answer: D) Neither 1 or 2 is true
Question: In one hour, a boat goes 11 km along the stream and 5 km against the stream. the sped of the boat in still water (in km/hr) is :
A.3
B.5
C.8
D.9
Answer: C.8
Explanation: Solution
Speed in still water= 1/2(11+5) km/hr= 8kmph. Answer C
Question: Find the odd man out. 13, 16, 12, 24, 12, 34, 46
A.16
B.46
C.24
D.13
Answer: D.13
Explanation: Explanation :
13 is the only odd number in the given series
Answer : Option D
Question: the two sides of a triangle are 32 and 68. the area is 960 sq.cm. find the third side of triangle?
A.45
B.50
C.60
D.70
Answer: C.60
Explanation: we see 68^2-32^2=(68+32)*(68-32)=100*36=60^2
now (1/2)*60*32=960(match with given options)
(i.e area of a right angled triangle whose sides are 32,60,68)
third side=60
ANSWER:C
Question: The ratio between the perimeter and the width of a rectangle is 5:1. If the area of the rectangle is 54 square centimeters, what is the length of the rectangle in centimeters?
A.6
B.7
C.8
D.9
Answer: D.9
Explanation: Perimeter = 2(W+L) = 5W
3W = 2L
W = 2L/3
WL = 54
2L^2/3 = 54
L^2 = 81
L = 9 cm
The answer is D.
Question: Two pipes A and B can separately fill a cistern in 60 min and 75 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 min. In how much time, the third pipe alone can empty the cistern?
A.761 min
B.100 min
C.167 min
D.367 min
Answer: B.100 min
Explanation: Work done by the third pipe in 1 min
= 1/50 - (1/60 + 1/75)
= - 1/100.
[-ve sign means emptying]
The third pipe alone can empty the cistern in 100 min.
Answer: B
Question: The grade point average of the entire class is 85. If the average of one third of the class is 97, what is the average of the rest of the class?
A.76
B.77
C.78
D.79
Answer: D.79
Explanation: Let x be the number of students in the class.
Let P be the average of the rest of the class.
85x = (1/3)97x + (2/3)(P)x
255 = 97 + 2P
2P = 158
P = 79.
The answer is D.
Question: The radius of a cylindrical vessel is 7cm and height is 3cm. Find the whole surface of the cylinder?
A.872
B.876
C.440
D.157
Answer: C.440
Explanation: r = 7 h = 3
2πr(h + r) = 2 * 22/7 * 7(10)
= 440
Answer: C
Question: A and B starts a business with Rs.8000 each, and after 8 months, B withdraws half of his capital . How should they share the profits at the end of the 10 months?
A.18:13
B.18:16
C.18:10
D.18:14
Answer: A.18:13
Explanation: A invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 8 months and then withdraws Rs.4000. So, the investment of B for remaining 10 months is Rs.4000 only.
A : B
8000*18 : (8000*8) + (4000*10)
14400 : 104000
A:B = 18:13
Answer: A
Question: A spirit and water solution is sold in a market. The cost per liter of the solution is directly proportional to the part (fraction) of spirit (by volume) the solution has. A solution of 1 liter of spirit and 1 liter of water costs 40 cents. How many cents does a solution of 1 liter of spirit and 2 liters of water cost?
A.40
B.33
C.50
D.51
Answer: A.40
Explanation: Yes, ensure that you understand the relation thoroughly!
Cost per liter = K * Fraction of Spirit
40 cents is the cost of 2 liters of solution (1 part water, 1 part spirit). So cost per liter is 20 cents. Fraction of spirit is 1/2.
20 = K * (1/2)
K = 40
Cost per liter = 40 * (1/3) (1 part spirit, 2 parts water)
Cost for 3 liters = 40 * (1/3) * 3 = 40 cents
A. 40 cents
Question: A real number x satisfying 1- (1/n) ≤ 3 + (1/n), for every positive integer n, is best described by ≤
A.1 < x < 4
B.1 < x ≤ 3
C.0 < x ≤4
D.1 ≤ x ≤ 3
Answer: C.0 < x ≤4
Explanation: Explanation :
1- (1/n) ≤ 3 + (1/n)
Put n =1 , we get 0 < x ≤4.
Answer : C
Question: In a six-sided polygon CQRSTV ∠C measures 48° less than the average (arithmetic mean) of the remaining five angles. What does ∠C equal to, in degrees?
A. 72
B. 80
C. 88
D. 96
Answer: B. 80
Explanation: The sum of interior angle in a polygon is (n-2)*180
so for a six sided figure, (6-2)*180 = 720
let the A.M of the other 5 angles be 'm'
--> m*5 + ∠C = 720, we know ∠C=m-48
--> m*5 + m - 48 = 720, solving we get m=128
hence ∠C= 128-48 = 80
Ans B.
Question: There are 3 sections with 5 questions each. If three questions are selected from each section, the chance of getting different questions is________
A.10
B.100
C.1000
D.10000
Answer: C.1000
Explanation: we have to select three questions from each section so the chances are 5C3.5C3.5C3=1000
ANSWER:C
Question: An investor can sell her MicroTron stock for 36$ per share and her Dynaco stock for 48$ per share, If she sells 300 shares altogether, some of each stock, at an average price per share of 40$, how many shares of Dynaco stock has she sold?
A.52
B.75
C.92
D.100
Answer: D.100
Explanation: w1/w2 = (A2 - Aavg)/(Aavg - A1) = (48 - 40)/(40 - 36) = 8/4 = 2/1 = Number of MicroTron stocks/Number of Dynaco stocks
So for every 2 MicroTron stock, she sold 1 Dynaco stock.
So out of 300 total stocks, (1/3)th i.e. 300/3 = 100 must be Dynaco stock.
Answer (D)
Question: Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
A.13 min
B.7 min
C.9 min
D.12 min
Answer: C.9 min
Explanation: 1/10 + 1/15 - 1/x = 1/18
x = 9
ANSWER C
Question: The triplicate ratio of 1:2 is?
A.1:5
B.1:8
C.1:3
D.1:4
Answer: B.1:8
Explanation: 13: 23 = 1:8
Answer: B
Question: The number of sequences in which 5 players can throw a ball, so that the youngest player may not be the last is ?
A.100
B.96
C.8
D.62
Answer: B.96
Explanation: x Not younger
The last ball can be thrown by any of the remaining 5 players. The first 4 players can throw the ball in 4P4 ways.
The required number of ways = 4(4!)
= 96
Answer:B
Question: If x is an integer, which of the following must also be an integer?
I. xy
II. y/x
III. y
A.I alone
B.II alone
C.III alone
D.I and III
Answer: D.I and III
Explanation: Lets take X = 11 and Y = 2
Then XY = 22 which is an integer.
But X/Y = 11/2 --> Not an integer.
Y/X = 2/11 --> Not an integer.
y alone is 2. which is an integer.
Hence D.
Question: If x^2 – 2y^2 = 2xy, then (x - y)^2 =
A.x^2
B.3x^2
C.4xy
D.3y^2
Answer: D.3y^2
Explanation: (x-y)^2 = x^2 + y^2 - 2xy = x^2 + y^2- x^2+2y^2 = 3y^2
Correct option : D
Question: If I walk at 3 kmph, I miss the train by 2 min, if however, I walk at 4 kmph. I reach the station 2 min before the arrival of the train. How far do I walk to reach the station?
A.4/5
B.4/9
C.4/8
D.4/1
Answer: A.4/5
Explanation: x/3 – x/4 = 4/60
x = 4/5 km
Answer: A
Question: if
21=3
32=7
82=22
92=25
than
72=?
A.17
B.19
C.21
D.23
Answer: B.19
Explanation: (2*1)+(2-1)=3
(3*2)+(3-2)=7
(8*2)+(8-2)=22
(9*2)+(9-2)=25
(7*2)+(7-2)=19
ANSWER:B
Question: Three independent strategies A, B and C have been initiated for cost cutting in a company producing respectively 20%, 40% and 10% savings. Assuming that they operate independently, what is the net saving achieved?
A.56.8%
B.64%
C.62.2%
D.68%
Answer: A.56.8%
Explanation: If initial cost is Rs 100, then
Final cost will be 100*0.8*0.6*0.9 = Rs. 43.2
savings = 100-43.2=56.8
so 56.8%
ANSWER:A
Question: You collect baseball cards. Suppose you start out with 16. Since you're nice, you give John 5 baseball cards. How many baseball cards do you have at the end?
A.11
B.12
C.13
D.14
Answer: A.11
Explanation: Solution
Start with 16 baseball cards.
John takes 5 baseball cards from you: 16 - 5 = 11 baseball cards.
So you have 11 at the end.
Correct answer : A
Question: A train passes a station platform in 36 seconds and a man standing on the platform in 10 seconds. If the speed of the train is 36 km/hr, what is the length of the platform?
A.338
B.60
C.287
D.267
Answer: B.60
Explanation: Speed = (36* 5/18) m/sec = 10 m/sec. Length of the train = (10 x 10)m = 100 m. Let the length of the platform be x meters. Then, (x + 100)/36 = 10==> x + 300 = 360 ==> x = 60 m.
Answer: B
Question: In how many ways can the letters of the word INTELLIGENCE be arranged?
A.2580
B.2500
C.200067
D.9979200
Answer: D.9979200
Explanation: INTELLIGENCE has 12 words, but I, N and L are repeated two times and E is repeated three times. Thus ways = 12! / 2!*2!*2!*3! = 9979200ways
D
Question: A certain list of 300 test scores has an arithmetic mean of 70 and a standard deviation of d, where d is positive. Which of the following two test scores, when added to the list, must result in a list of 302 test scores with a standard deviation less than d?
A. 70 and 70
B. 80 and 85
C. 70 and 75
D. 75 and 75
Answer: A. 70 and 70
Explanation: Deviation means spreading of the numbers from one median point value..
as the set is already established and we need to add only two numbers, this means we can only add numbers which are closer to the median to reduce the deviation.
so 70 and 70 are the most close numbers and they will increase the number of elements in the set without changing the median value.
A
Question: A windmill is taking advantage of strong air currents in order to produce electrical energy. On a typical day the wind speed is around 20 mph and in that speed the windmill produces 400 kw/h (kilowatts per hour). On a stormy day a windmill produces 20% more energy. How much kw/h can three windmills produce in two hours on a stormy day?
A.2880.
B.4860.
C.5780
D.5760
Answer: A.2880.
Explanation: Normal Day = 400 kw/h
Stormy Day = 400*1.2=480 kw/h
3 windmills for 2 hours on stormy day
480*3*2=2880
Answer: A
Question: A and B start a business with Rs.6000 and Rs.8000 respectively. Hoe should they share their profits at the end of one year?
A.3:9
B.3:4
C.3:2
D.3:1
Answer: B.3:4
Explanation: Explanation:
They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
6000 : 8000 => 3:4
Answer: B
Question: A technician makes a round-trip to and from a certain service center by the same route. If the technician completes the drive to the center and then completes 30 percent of the drive from the center, what percent of the round-trip has the technician completed?
A.60
B.65
C.55
D.50
Answer: B.65
Explanation: round trip means 2 trips i.e.to and fro. He has completed one i.e 50% completed. then he traveled another 30% of 50% i.e 15%. so he completed 50 +15 =65 % of total trip.
B
Question: A shopkeeper sold 15 articles at the cost price of 20 articles. Then find the profit% or lost%
A.30%
B.31%
C.20%
D.33.33%
Answer: D.33.33%
Explanation: here 15 articles selling price = 20 articles cost price
so the difference = 20-15 = 5
% of profit = 5*100/15 = 33.33%
correct option is D
Question: The number of permutations of the letters of the word 'MESMERISE' is?
A.9!/(2!)2 3!
B.9!/(2!)7 3!
C.9!/(2!)9 3!
D.9!/(2!)2 8!
Answer: A.9!/(2!)2 3!
Explanation: n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.
The letter pattern 'MESMERISE' consists of 10 letters of which there are 2M's, 3E's, 2S's and 1I and 1R.
Number of arrangements = 9!/(2!)2 3!
Answer:A
Question: The mean age of john,william,sam and katy is 25.the age of jhon is 22,age of sam is 30 and age of katy is 24.then tell me the age of william.
A.23
B.24
C.25
D.26
Answer: B.24
Explanation: solution
let age of william be x.
now, the mean of four age=(22+x+30+24)/4=25
76+x=100
so x=24.
answer B
Question: Q-1) Of the 64 parents who attended a meeting at a
school, 35 volunteered to supervise children during
the school picnic and 11 volunteered both to supervise
children during the picnic and to bring refreshments to
the picnic. If the number of parents who volunteered
to bring refreshments was 1.5 times the number of
parents who neither volunteered to supervise children
during the picnic nor volunteered to bring
refreshments, how many of the parents volunteered to
bring refreshments?
A.24
B.36
C.38
D.42
Answer: A.24
Explanation: i used the following formula: total = group1 + group2 + neither - both
using the information from the question stem, we have:
64 total people
35 who supervise (group1)
x who neither supervise nor bring refreshments
1.5x people who bring refreshments (group2)
11 who supervise AND bring refreshments (both)
therefore...
64 = 35 + 1.5x + x - 11
solving, we get x = 16
since we want the value of those who bring refreshments AND supervise:
1.5(16) = 24
answer is A
Question: A customer pays 70 dollars for a coffee maker after a discount of 20 dollars
What is the original price of the coffe maker?
A.50
B.40
C.90
D.60
Answer: C.90
Explanation: Let x be the original price.
x - 20 = 70
x - 20 + 20 = 70 + 20
x + 0 = 90
x = 90
Answer is C
Question: Fresh grapes contain 70% by weight while dried grapes contain 10% water by weight. What is the weight of dry grapes available from 100 kg of fresh grapes?
A.18.33 kg
B.21.50 kg
C.25.00 kg
D.33.33 kg
Answer: D.33.33 kg
Explanation: From the question we know: 100kg * 70% = 70kg of water in the fresh grapes
100kg - 70kg of water = 30kg of non-water mass
We are looking for the weight of the dry grapes (X).
Since the question tells us that 10% of the weight of the dry graps is water and we know that 30kg is non-water mass we can set up the following equation:
X = 1/10(X) + 30kg
9/10(X) = 30kg
X = 33.33 kg
Answer- D
Question: The area of a triangle is with base 2m and height3m?
A.11
B.10
C.787
D.3
Answer: D.3
Explanation: 1/2 * 2 * 3 = 3 m2
Answer: D
Question: A merchant purchased a jacket for $56 and then determined a selling price that equalled the purchase price of the jacket plus a markup that was 30 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant’s gross profit on this sale?
A. $0
B. $8
C. $4
D. $12
Answer: B. $8
Explanation: Actual Cost = $56
SP = Actual Cost + Mark up
= Actual Cost + 30% SP
= 56*100/70
on sale SP = 80/100(56*100/70) = 64
Gross profit = $8
Answer is B
Question: A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
A.2477
B.387
C.698
D.377
Answer: C.698
Explanation: Explanation:
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698
Answer: C) 698
Question: Sum of the squares of 3 no. is 149 and the sum of their products taken two at a time is 70. Find the sum?
A.17
B.19
C.21
D.13
Answer: A.17
Explanation: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 149 + 2* 70
a + b + c = âˆš289 = 17
Answer A
Question: If AB=3, BC=6, CD=7 and DE=9, what are the coordinates of point E in the figure above?
A.
B.
C.
D.
E.
A.(−8,8)
B.(4,−4)
C.(5,−5)
D.(2,−2)
Answer: C.(5,−5)
Explanation: Co-ordinates of Point B = (2, 2) (Same x co-ordinate as that of A and Y co ordinate 3 units up than y co ordinate of A)
Co-ordinates of Point C = (-4, 2) (Same Y co-ordinate as that of B and X co-ordinate 6 units Left than X co-ordinate of B)
Co-ordinates of Point D = (-4, -5) (Same x co-ordinate as that of C and Y co-ordinate 7 units Down than Y co-ordinate of C)
Co-ordinates of Point E = (5, -5) (Same Y co-ordinate as that of D and X co-ordinate 9 units Right than X co-ordinate of D)
Answer: Option C
Question: Find the area of the quadrilateral of one of its diagonals is 20 cm and its off sets 9 cm and 6 cm?
A.189 cm2
B.150 cm2
C.127 cm2
D.177 cm2
Answer: B.150 cm2
Explanation: 1/2 * 20(9 + 6)
= 150 cm2
Answer: B
Question: What is the greatest prime factor of 1+2+3+。。。+70?
A.71
B.69
C.31
D.59
Answer: A.71
Explanation: find the sum from direct formula = n(n+1)/2 = 70(70+1)/2 = 35*71...
71 is a PRIME number, so ans is 71..
A is the answer
Question: How many three digit numbers can be formed using the digits {1, 3, 4, 5, 7,8, 9}(repetition of digits is not allowed)?
A.360
B.210
C.278
D.279
Answer: B.210
Explanation: The given digits are six.
The number of four digit numbers that can be formed using six digits is
7P3 = 7* 6 * 5 = 210
Answer: B