RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The average marks in mathematics scored by the pupils of a school at the public examination were 39. If four of these pupils who actually scored 5, 12, 15 and 19 marks at the examination had not been sent up, the average marks for the school would have been 44. Find the number of pupils sent up for examination from the school?
A.12
B.25
C.28
D.245
Answer: B.25
Explanation: 39x = 5 + 12 + 15 + 19 + (x – 4)44
x = 25
Answer: B
Question: Six children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Children AB must sit next to each other, and child C must be somewhere to the right of AB. How many possible configurations are there for the children?
A.600
B.720
C.1440
D.4320
Answer: A.600
Explanation: A, B, C, D, E, F, G- seven children, of which AB must sit next to each other. Considering them as one X (A, B), we have X, C, D, E, F, G. These can be arranged in 6! ways. But A,B can arrange themselves in 2! ways. So a total of 6!*2! ways = 1440. Since in exactly half of them, C will be to the right of AB, and exactly half, C will be to the left of AB, therefore 1440/2 = 600.
A is the right answer.
Question: A, B, C, D and E are 5 consecutive points on a straight line. If BC = 3CD, DE = 7, AB = 5 and AC = 11, what is the length of AE?
A.18
B.19
C.20
D.21
Answer: C.20
Explanation: AC = 11 and AB = 5, so BC = 6.
BC = 3CD so CD = 2.
The length of AE is AB+BC+CD+DE = 5+6+2+7 = 20
The answer is C.
Question: You hold some gold in a vault as an investment. Over the past year the price of gold increases by 52%. In order to keep your gold in the vault, you must pay 6% of the total value of the gold per year. What percentage has the value of your holdings changed by over the past year.
A.42.88$
B.43%
C.45%
D.45.5%
Answer: A.42.88$
Explanation: (100%+52%)*(100%-6%) = 152*0.94 = 142.88% an increase of 42.88%
Your gold holdings have increased in value by 42.88%.
The Answer is A
Question: In how many ways can you seat 4 people on a bench if one of them, Rohit, does not want to sit on the middle seat or at either end?
A.720
B.1720
C.2880
D.6
Answer: D.6
Explanation: Since Rohit does not want to sit on the middle seat or at either end (3 chairs), then he can choose 1 chairs to sit. The remaining 3 people can sit in 3! ways. Thus the # of arrangements is 1*3! = 6.
Answer: D.
Question: A sum of Rs. 395 was divided among A, B, and C in such a way that B gets 25% more than A and 20% more than C. What is the share of A?
A.Rs.195
B.Rs.180
C.Rs. 98
D.Rs. 120
Answer: D.Rs. 120
Explanation: Let each one’s share is A,B and C respectively, then
B =125A/100 = 120C/100
A =100B/125 =4/5B, C = 100B/120 = 5/6B
4/5B +B +5/6B =395, 79B/30 =395, B =395*30/79 =150
A = 4*150/5 = 120
ANSWER:D
Question: Let us say that a table tennis tournament was going on with knock out terms which means the one who loses the match is out of the tournament. 50 players took part in that tournament.
How many matches were played?
A.99 matches.
B.88 matches.
C.49 matches.
D.66 matches.
Answer: C.49 matches.
Explanation: Solution:
49 matches.
The number of matches will always sum up to one less than the number of players in a knock out tournament. You may calculate it in any manner. Thus 49 matches were played.
Answer C
Question: Two cars start at the same time from A and B which are 120 km apart. If the two cars travel in opposite direction they meet after one hour and if they travel in same direction ( from A towards B) then A meets B after 6 hours. What is the speed of the car starting from A?
A.70 kmph
B.120 kmph
C.60 kmph
D.Data Inadequate
Answer: A.70 kmph
Explanation: Let, speed of car from A towards B = x km/hr
Let, speed of car from B towards A = y km/hr
Two cars start at same time which 120km apart = x + y = 120-----(i)
Travel in same direction, A meets B after 6hr = 6x-6y = 120-----(ii)
By Solving equation (i) and (ii), we get
12x = 840
x = 840/12
x = 70km/hr
Substituting x value in eqn (i) or (ii), we get
y = 50km/hr
So, speed of car starting from 70kmph.
ANSWER:A
Question: The profit obtained by selling an article for Rs. 57 is the same as the loss obtained by selling it for Rs. 43. What is the cost price of the article?
A.Rs. 40
B.Rs. 50
C.Rs. 49
D.Rs. 59
Answer: B.Rs. 50
Explanation: S.P 1- C.P = C.P – S.P 2
57 - C.P = C.P - 43
2 C.P = 57 + 43;
C.P = 100/2 = 50
ANSWER:B
Question: Ram professes to sell his goods at the cost price but he made use of 925 grms instead of a kg, what is the gain percent?
A.2 9/13%
B.7 9/13%
C.3 9/13%
D.4 9/13%
Answer: B.7 9/13%
Explanation: 925 --- 75
75 --- ? =>
=75/925 *100= 7 9/13%
Answer: B
Question: Two men Amar and Bhuvan have the ratio of their monthly incomes as 6 : 5. The ratio of their monthly expenditures is 3 : 2. If Bhuvan saves one-fourth of his income, find the ratio of their monthly savings?
A. 3 : 5
A.3:9
B.3:10
C.3:21
D.3:12
Answer: B.3:10
Explanation: Let the monthly incomes of Amar and Bhuvan be 6x and 5x respectively.
Let the monthly expenditure of Amar and Bhuvan be 3y and 2y respectively.
Savings of Bhuvan every month = 1/4(5x)
= (His income) - (His expenditure) = 5x - 2y.
=> 5x = 20x - 8y => y = 15x/8.
Ratio of savings of Amar and Bhuvan
= 6x - 3y : 1/4(5x) = 6x - 3(15x/8) : 5x/4 = 3x/8 : 5x/4
= 3 : 10.
Answer: Option B
Question: The total of a company's assets in 1994 was 200% greater than the total in 1993, which in turn was 400% greater than the total in 1992. If the total of the company's assets in 1992 was N dollars, what were the company's assets in 1994?
A.5N
B.7N
C.10N
D.15N
Answer: D.15N
Explanation: In 1992, the company's assets were N.
In 1993, the company's assets were N + 4N = 5N.
In 1994, the company's assets were 5N + 10N = 15N.
The answer is D.
Question: Three men rent a pasture for Rs. 660. The first used it for 50 sheep for 4 months, the 2nd for 40 sheep for 3 months and the 3rd for 46 sheep for 5 months. How much should the first pay ?
A.Rs. 220
B.Rs. 235
C.Rs. 240
D.Rs. 276
Answer: D.Rs. 276
Explanation: The payment should be in ratio of 200:120:230 or 20:12:23
First person should pay 20*660/55 = 240 Rs.
ANSWER:D
Question: In how many ways can 5 boys and 2 girls be seated on 8 chairs so that no two girls are together?
A.5760
B.14400
C.480
D.5670
Answer: D.5670
Explanation: Let us take opposite of the constraint.
2 girls sitting together:	:
1 case is GGBGBBBB.
Total number of ways=3!*5!*5 with just shifting the rightmost girl.
Then the 2 leftmost girls can shift one position , and using the above reasoning, the total number of ways = 3!*5!*4 and so on till the rightmost girl has 1 position.
So total number of ways = 3!*5!(5+4+3+2+1)=120*90=10800
Similarly another case is:
GBGGBBBB.
Using the above reasoning, the total number of cases is: 3!*5!*(15) =10800
Let us take 3 girls sitting together
GGGBBBBB
There are 3! *5! Ways. The 3 leftmost girls can shift 6 positions. So there are a total of 3!*5!*6=4320 ways
So total is 2*10800 + 4320=25920
The total number of possibilities = 8! Ways =40,320
Answer is 40320-25920=5670
Hence D.
Question: In how many ways can the letters of the word 'LEADER' be arranged?
A.739
B.73
C.360
D.840
Answer: C.360
Explanation: The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.
Required number of ways =6!/(1!)(2!)(1!)(1!)(1!)= 360.
Answer:C
Question: A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes?
A.100 m
B.150 m
C.190 m
D.200 m
Answer: A.100 m
Explanation: Explanation:
Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr
Distance covered in 6 minutes = (1/60 × 6) km = 1/10 km = 100 m
∴ Distance between the thief and policeman = (200 – 100) m = 100 m.
Answer: A
Question: If 21520 books need to be placed in boxes and each box can contain at most 9 books. How many books will be in the last unfilled box?
A.9 books
B.8 books
C.1 book
D.4 books
Answer: C.1 book
Explanation: The number of books that can be placed in boxes of 9 books is the first number that is divisible by 9 that occurs before 21520.
In order to divide the sum in 9 parts, the amount must be divisible by 9
Divisibility rule of 9: The sum of the digits must be divisible by 9
Sum of digits of 21520 = 10 and 9 is divisible by 9.
Hence, we need to remove 1 to this number for it to be divisible by 9
Correct Option: C
Question: How many seconds will a train 120 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?
A.27 sec
B.23 sec
C.24 sec
D.25 sec
Answer: A.27 sec
Explanation: D = 120 + 150 = 270
S = 36 * 5/18 = 10 mps
T = 270/10 = 27 sec
A
Question: A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
A.167
B.240
C.881
D.278
Answer: B.240
Explanation: Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x = 240 m.
Answer: B
Question: 287 x 287 + 269 x 269 - 2 x 287 x 269 = ?
A.466
B.646
C.666
D.324
Answer: D.324
Explanation: Given Exp.	= a2 + b2 - 2ab, where a = 287 and b = 269
= (a - b)2 = (287 - 269)2
= (182)
= 324
Correct Option is D
Question: If Re.100 amounts to Rs.300 over a period of 10 years. What is the rate of simple interest?
A.20%
B.30%
C.15%
D.10%
Answer: A.20%
Explanation: 200 = (100*10*R)/100
R = 20%
Answer:A
Question: When N is divided by 10 the remainder is 1 and when N is divided by 3 the remainder is 2. What is the remainder G when N is divided by 30?
A.(a) 4
B.(b) 7
C.(c) 11
D.(d) 13
Answer: C.(c) 11
Explanation: N ends in the digit 1 because when N is divided by 10, the remainder is 1. Since N ends in 1, the remainder G when N is divided by 30 also ends in a 1. 11 is the only choice which ends in a 1.C
Question: A recycling facility is staffed by 12 floor workers and one manager. All of the floor workers are paid equal wages, but the manager is paid n times as much as a floor worker. If the manager’s wages account for 1/11 of all wages paid at the facility, what is the value of n?
A.1.1
B.2.1
C.2.2
D.2.3
Answer: A.1.1
Explanation: Say each floor worker is paid $x, then the manager is paid $xn.
Total salary would be 12x+xn and we are told that it equals to 11xn:
11x+xn=11xn --> reduce by x: 11+n=11n -->10n=11
n = 11/10 = 1.1
Answer: A
Question: 8th Dec 2007 was Saturday, what day of the week was it on 8th Dec, 2006?
A.Sunday
B.Tuesday
C.Friday
D.Tuesday
Answer: C.Friday
Explanation: Given that 8th Dec 2007 was Saturday
Number of days from 8th Dec, 2006 to 7th Dec 2007 = 365 days
365 days = 1 odd day
Hence 8th Dec 2006 was = (Saturday - 1 odd day) = Friday
Correct answer is Friday
Question: In a school with 5 classes, each class has 2 students less than the previous class. How many students are there in the largest class if the total number of students at school is 115?
A.25
B.26
C.27
D.28
Answer: C.27
Explanation: Let x be the number of students in the largest class.
Then x + (x-2) + (x-4) + (x-6) + (x-8) = 115
5x - 20 = 115
5x = 135
x = 27
The answer is C.
Question: In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 8 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
A.44
B.58
C.74
D.12
Answer: A.44
Explanation: Explanation:
Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 8)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 8 = 4/9(T - 8)
10T = 792 - 352 => T = 44.
Answer:A
Question: Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 4 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is?
A.1:2
B.1:3
C.3:1
D.1:5
Answer: C.3:1
Explanation: Quantity of alcohol in vessel P = 62.5/100 * 4 = 5/2 litres
Quantity of alcohol in vessel Q = 87.5/100 * 4 = 7/2 litres
Quantity of alcohol in the mixture formed = 5/2 + 7/2 = 6 litres
As 8 litres of mixture is formed, ratio of alcohol and water in the mixture formed = 6 : 2 = 3:1.
Answer:C
Question: If the digits 35 in the decimal 0.00035 repeat indefinitely, what is the value of (10^5-10^3)(0.00035)?
A.37
B.41
C.3.5e-05
D.35
Answer: B.41
Explanation: 99*0.35=34.65 approx. 35
Answer : B
Question: Coins are to be put into 10 pockets so that each pocket contains at least one coin. At most 6 of the pockets are to contain the same number of coins, and no two of the remaining pockets are to contain an equal number of coins. What is the least possible number of coins needed for the pockets?
A.7
B.13
C.20
D.22
Answer: C.20
Explanation: Since at most 6 of the pockets are to contain the same number of coins then minimize # of coins in each, so let each contain just 1 coin;
Next, we are told that no two of the remaining 4 pockets should contain an equal number of coins, so they should contain 2, 3, 4, and 5 coins each (also minimum possible);
Total: 1+1+1+1+1+1+2+3+4+5=20
Answer: C.
Question: A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man's rate is?
A.1
B.2
C.3
D.7
Answer: A.1
Explanation: DS = 6
US = 4
S = ?
S = (6 - 4)/2 = 1 kmph Answer:A
Question: If a = 2, what is the value of –(a^2 + a^3 + a^4 + a^5)?
A.-14
B.-60
C.0
D.4
Answer: B.-60
Explanation: if a = -1, then putting values in equation
= -[ (2)^2 + (2)^3 + (2^4) + (2^5) ]
= -[ 4 + 8 + 16 + 32 ]
= -60
Answer = B = -60
Question: Two cards are drawn at random from a pack of 52 cards.what is the probability that either both are black or both are queen?
A.55/119
B.55/221
C.55/223
D.55/227
Answer: B.55/221
Explanation: We have n(s) = \inline {\color{Black}52C_{2}} = = 1326.
Let A = event of getting both black cards
B = event of getting both queens
A∩B = event of getting queen of black cards
n(A) = \inline {\color{Black}26C_{2}} = = 325, n(B)= \inline {\color{Black}4C_{2}} = = 6 and n(A∩B) = \inline {\color{Black}2C_{2}} = 1
P(A) = n(A)/n(S) = 325/1326;
P(B) = n(B)/n(S) = 6/1326 and
P(A∩B) = n(A∩B)/n(S) = 1/1326
P(A∪B) = P(A) + P(B) - P(A∩B) = (325+6-1) / 1326 = 330/1326 =
B
Question: When the price of an article was reduced by 15% its sale increased by 80%. What was the net effect on the sale?
A.44% increase
B.44% decrease
C.53% increase
D.66% increase
Answer: C.53% increase
Explanation: if n items are sold for $p each, revenue is $np. If we reduce the price by 15%, the new price is 0.85p. If we increase the number sold by 80%, the new number sold is 1.8n. So the new revenue is (0.85p)(1.8n) = 1.53np, which is 1.53 times the old revenue, so is 53% greater.
ANSWER:C
Question: Which number comes next in the series
5 12 24 36 ?
A.52
B.55
C.60
D.120
Answer: A.52
Explanation: A
52
sum of consecutive prime numbers
(2+3 , 5+7 , 11+13 , 17+19 , 23+29)
Question: How many ways are there to lay four balls, colored red, black, blue and green in a row?
A.11
B.33
C.44
D.23
Answer: B.33
Explanation: Answer:B
Question: Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
A.25200
B.210
C.120
D.1000
Answer: A.25200
Explanation: Required selection = select 3 consonants from 7 and 2 vowels frm 4
= 7C3 * 4C2
= 210
As we have to form 5 letter word the above combination of consonants and vowels can be done in 5! = 120 different ways
Required no. of ways = 210 * 120
= 25200
Ans - A
Question: X, Y, and Z are three different Prime numbers, the product XYZ is divisible by how many different positive numbers?
A.4
B.6
C.8
D.9
Answer: C.8
Explanation: PRIME # is the # that has only 2 factors: One is 1 and another is the # itself.
infer that
FOR any given # 1 and the # itself are the definite factors.
Knowing above concepts:
product of X,Y, and Z = XYZ
divisible by 1, xyz, x, y, z, xy,yz,xz ==> total 8
ANSWER "C"
Question: Jane and Ashley take 10 days and 40 days respectively to complete a project when they work on it alone. They thought if they worked on the project together, they would take fewer days to complete it. During the period that they were working together, Jane took an eight day leave from work. This led to Jane's working for four extra days on her own to complete the project. How long did it take to finish the project ?
A.10.2 Days
B.15.2 Days
C.16.2 Days
D.18 Days
Answer: B.15.2 Days
Explanation: Let us assume that the work is laying 40 bricks.
Jane = 4 bricks per day
Ashley = 1 brick per day
Together = 5 bricks per day
Let's say first 8 days Ashley works alone,
No of bricks = 8
Last 4 days Jane works alone,
No. of bricks = 16
Remaining bricks = 40 - 24= 16
So together, they would take 16/5 = 3.2
Total no. of days = 8 + 4 + 3.2 = 15.2
Answer is B
Question: Evaluate 35 / .07
A.400
B.500
C.505
D.None of these
Answer: B.500
Explanation: Explanation:
35/.07 = 3500/7 = 500
Option B
Question: The number N is 7,6H4, where H represents the ten's digit. If N is divisible by 9, what is the value of H?
A.1
B.3
C.5
D.7
Answer: A.1
Explanation: Integer is divisible by 9 - Sum of digits is divisible by 9
Answer: A
Question: Rs.585 is divided amongst A, B, C so that 4 times A's share, 6 times B's share and 3 times C's share are all equal. Find C's share?
A.260
B.150
C.817
D.716
Answer: A.260
Explanation: A+B+C = 5854A = 6B = 3C = xA:B:C = 1/4:1/6:1/3= 3:2:44/9 * 585= Rs.260Answer: A
Question: a = 2^15 - 625^3 and a/x is an integer, where x is a positive integer greater than 1, such that it does NOT have a factor p such that 1 < p < x, then how many different values for x are possible?
A.None
B.One
C.Two
D.Three
Answer: B.One
Explanation: This is a tricky worded question and I think the answer is should be D not C...
Here is my reason :
The stem says that x is a positive integer such that has no factor grater than 2 and less than x itself . The stem wants to say that X is a PRIME NUMBER . because any prime
Number has no factor grater than 1 and Itself .
On the other hand the stem says that X COULD get how many different number NOT MUST get different number ( this is very important issue )
AS our friends say, if we simplify Numerator more we can obtain : 5^12 ( 5^3-1) = 5^12 (124) = 5^12 (31*2*2) divided by x and we are told that this fraction is
An integer . so, X COULD Be ( not Must be) 5 , 31 ,or 2 !!! so , X could get 1 different values and answer is B....
Question: A train traveling at 72 kmph crosses a platform in 30 seconds and a man standing on the platform in 16 seconds. What is the length of the platform in meters?
A.240 meters
B.360 meters
C.280 meters
D.600 meters
Answer: C.280 meters
Explanation: Speed of the train in metres/sec = 72000/3600 = 20
Distance travelled by train to cross the platform = 30 * 20 = 600 = Length of train + Length of platform
Distance travelled by train to cross the man = 16 * 20 = 320 = Length of train
Length of platform = 600 - 320 = 280
Answer: C
Question: IN Common Wealth Games an athlete runs 400 meters in 24 seconds. Hisspeed is ?
A.25 km/hr
B.27 km/hr
C.60.60 km/hr
D.32 km/hr
Answer: C.60.60 km/hr
Explanation: Explanation :
(400/1000)/(24/3600)=60.60 km/hr
Answer : C
Question: If 2^2n + 2^2n + 2^2n + 2^2n = 4^28, then n =
A.3
B.6
C.12
D.27
Answer: D.27
Explanation: 2^2n + 2^2n + 2^2n + 2^2n = 4^28
=> 4 x 2^2n = 4^28 = 2^56
=> 2^2 x 2^2n = 2^56
=> 2^(2n+2) = 2^56
=> 2n+2 = 56=> n =27
So. Answer will be D.
Question: It takes Jim N minutes to prepare one omelet. It takes Cole N/2 minutes to prepare one omelet. It takes Mitch N/2 minutes to prepare 2 omelets. If Jim, Cole and Mitch together prepare a total of 30 omelets in 40 minutes, then how many minutes would it take Mitch alone to prepare 30 omelets?
A.70
B.120
C.140
D.160
Answer: A.70
Explanation: Cole is twice as fast as Jim and Mitch is 4 times as fast as Jim (it takes Mitch N/2 minutes to prepare 2 omelets, thus N/4 minutes to prepare one omelet).
Say the rate of Jim is x omelet/minute, the rate of Cole 2x omelet/minute, and the rate of Mitch 4x omelet/minute.
Then, from (time)(rate) = (job done):
(40 minutes)(x + 2x + 4x) = (30 omelets);
(40 minutes)(7x) = (30 omelets);
Since it takes 40 minutes to prepare 30 omelets at the rate of 7x omelet/minute, then it would take 40*7/4 = 70 minutes to prepare the same 30 omelets at the rate of 7x*4/7 = 4x omelet/minute (the rate of Mitch).
Or:
(40 minutes)(7x) = (30 omelets);
(40*7/4 minutes)(7x*4/7) = (30 omelets);
(70 minutes)(4x) = (30 omelets);
Answer: A.
Question: If a, b and c are even integers, which of the following could be the value of a^2 + b^2 + c^2?
A.a)82
B.b)84
C.c)85
D.d)87
Answer: B.b)84
Explanation: a, b and c are even integers which means that, supposing that x, y and z are integers, then a=2x, b=2y and c=2z
Therefore we have: a^2+b^2+c^2=2^2*x^2+2^2*y+2^2*z=4x^2+4y^2+4z^2=4(x^2+y^2+z^2).
Which means that the total a^2+b^2+c^2 must be divisible by 4.
The only choice which is divisible by 4 is: B)
84=8^2+4^2+2^2
Answer: B.
Question: A bag contains 8 red and 5 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
A.4/7
B.2/3
C.5/8
D.1/4
Answer: A.4/7
Explanation: Total number of balls = 8+6 = 14
number of white balls = 8
Probability = 8/14 = 4/7
Answer is A
Question: A farmer planned to plough a field by doing 120 hectares a day. After two days of work he increased his daily productivity by 25% and he finished the job two days ahead of schedule. What is the area of the field?
A.1420
B.1430
C.1450
D.1440
Answer: D.1440
Explanation: First of all we will find the new daily productivity of the farmer in hectares per day: 25% of 120 hectares is 25100⋅120=30 hectares, therefore 120+30=150 hectares is the new daily productivity. Lets x be the planned number of days allotted for the job. Then the farm is 120⋅x hectares. On the other hand, we get the same area if we add 120⋅2 hectares to 150(x−4) hectares. Then we get the equation
120x=120⋅2+150(x−4)
x=12
So, the job was initially supposed to take 12 days, but actually the field was ploughed in 12 - 2 =10 days. The field's area is 120⋅12=1440 hectares.
Answer is D.
Question: The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 42 degrees. Find the temperature on Friday?
A.28
B.27
C.22
D.34
Answer: D.34
Explanation: M + Tu + W + Th = 4 * 48 = 192
Tu + W + Th + F = 4 * 46 = 184
M = 42
Tu + W + Th = 192 -42 = 150
F = 184 – 150 = 34
Answer:D
Question: A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee can be assigned to an office. In how many ways can the company assign 7 employees to 2 different offices?
A.215
B.310
C.343
D.243
Answer: C.343
Explanation: Each of three employee can be assigned to either of offices, meaning that each has 2 choices --> 7*7*7=7^3=343.
Answer: C.
Question: 12 buckets of water fill a tank when the capacity of each tank is 13.5 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 9 litres?
A.8
B.15
C.16
D.18
Answer: D.18
Explanation: Capacity of the tank = (12 x 13.5) liters = 162 liters.
Capacity of each bucket = 9 liters.
Numbers of buckets needed = (162/9) = 18
ANSWER:D
Question: Which of the following number will completely divide (36^9)-1?
A.5
B.6
C.7
D.9
Answer: C.7
Explanation: x^n - 1 will be divisible by x+1 only when n is even.
36^9 - 1 = (6^2)^9 - 1 = 6^18 - 1 which is divisible by 6+1 i.e. 7
Answer is C
Question: If x is a positive number and 1/3 the square root of x is equal to 3x, then x =
A.1/3
B.1/9
C.1/81
D.1
Answer: C.1/81
Explanation: 1/3 of sqrt(x) = 3x, which means that sqrt(x) = 9x
or x = 81x^2 -> divide by x
1=81x
x=1/81
C.
Question: In a software company 4/10 of people know C++, 2/4 of them know java, 2/8 of them know neither,find the total possibility to know C++?
A.1/4
B.1/3
C.1/2
D.2/3
Answer: A.1/4
Explanation: Assume 100 persons in a company
person knows c++=4/10=100*4/100=20 persons
person knows java=2/4=100*2/4=50 persons
neither=2/8=100*2/8=25 persons
according to our assumption 100 person=20+50+25=95 person covered(5 remaining)
so,total possibility=20 person(c++)+5(remaining)=25 persons
which is 25/100=1/4
ANSWER:A