RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Five friends go to a city where they can stay in 10 different hotels. In how many ways can they stay in these hotels if at least two of them stay together?
A.5^10−10C5∗5!
B.5^10−10C5
C.5^10−5!
D.10^5−10C5∗5!
Answer: D.10^5−10C5∗5!
Explanation: There are 10 hotels and each person can stay in 10 hotels
Total = 10 * 10 * 10 * 10 * 10 --> 10^5 --> Notice that there is no restriction to avoid a hotel.
Number of ways so that no person stays together with another friend = 10 * 9 * 8 * 7 * 6 = 10P5 = 10C5 * 5!
Number of ways can 5 friends stay in these hotels if at least two of them stay together = 10^5 - (10C5 * 5!)
Answer: D
Question: If nn is a positive integer and (n+1)(n+3)(n+1)(n+3) is odd, then (n+2)(n+4)(n+2)(n+4) must be a multiple of which one of the following?
A.5
B.7
C.6
D.8
Answer: D.8
Explanation: (n+1)(n+3)(n+1)(n+3) is odd only when both (n+1)(n+1) and (n+3)(n+3) are odd. This is possible only when nn is even.
Hence, n=2mn=2m, where mm is a positive integer. Then,
(n+2)(n+4)=(2m+2)(2m+4)=2(m+1)2(m+2)=4(m+1)(m+2)(n+2)(n+4)=(2m+2)(2m+4)=2(m+1)2(m+2)=4(m+1)(m+2)
=4 * (product of two consecutive positive integers, one which must be even)=4 * (product of two consecutive positive integers, one which must be even) =4 * (an even number), and this equals a number that is at least a multiple of 8=4 * (an even number), and this equals a number that is at least a multiple of 8
Hence, the answer is (D).
Question: Simple interest on a certain sum is 16 over 25 of the sum. Find the rate per cent and time, if both are equal.
A.8% and 8 years
B.6% and 6 years
C.10% and 10 years
D.12 % and 12 years
Answer: A.8% and 8 years
Explanation: 16⁄25P = P×R×R/100
⇒ R2 = 1600⁄25 ⇒ R = 40⁄5 = 8%
Also, time = 8 years
Answer A
Question: Ajay marked the price of his goods 30% more than his C.P. He then sells 1/4th of his stock at a discount of 15%, and half of the stock at the marked price, and the rest at a discount of 30%. Find his gain percentage.
A.16.5%
B.15.375%
C.14.20%
D.13.37%
Answer: B.15.375%
Explanation: If C.P = 100, M.P = 130
S.P = (1/4) x 110.5 + (1/2) x 130 + (1/4) x 91
S.P = 27.625 + 65 + 22.75 = 115.375
Hence , Profit = 15.375%
ANSWER:B
Question: At a certain school, the ratio of the number of English majors to the number of Sociology majors is 5 to 2, and the ratio of the number of Psychology majors to the number of Sociology majors is 3 to 4. If the ratio of the number of History majors to the number of English majors is 5 to 3, what is the ratio of the number of Psychology majors to the number of History majors
A.25 to 3
B.20 to 9
C.9 to 50
D.6 to 25
Answer: B.20 to 9
Explanation: Correct B
Question: John can do a piece of work in 30 days while michael can do it in 40 days. In how many days will they finish it together?
A.17 1/7 days
B.27 1/7 days
C.23 2/7 days
D.16 4/11 days
Answer: A.17 1/7 days
Explanation: Explanation:
1/30 + 1/40 = 7/120
120/7 = 17 1/7 days
Answer: A
Question: A and B can finish a piece of work in 30 days. They worked at it for 20 days and then B left. The remaining work was done by A alone in 20 more days. A alone can finish the work in
A.48 days
B.50 days
C.54 days
D.60 days
Answer: D.60 days
Explanation: Explanation:
(A + B)’s 1 day’s work = 1/30
Their 20day’s work = 1/30 × 20 = 2/3
Remaining 1/3 work is done by A in 20 days
Therefore, A alone can finish the work in 3 × 20 = 60 days.
Answer: Option D
Question: A and B can finish a work in 10 days while A alone can do the same work in 20 days. In how many days B alone will complete the work?
A.20 days
B.48 days
C.98 days
D.31 days
Answer: A.20 days
Explanation: B = 1/10 – 1/20 = 1/20 => 20 days
Answer: A
Question: It takes ten minutes to fry a steak (five minutes for each side). You are frying the steaks in a pan that can accommodate only two steaks at one time. What is the least amount of time by which you can fry all the three steaks you have?
A.14 Minutes
B.15 Minutes
C.16 Minutes
D.17 Minutes
Answer: B.15 Minutes
Explanation: Solution:
Fifteen Minutes.
After frying for five minutes, you can take out one steak and put the third one inside while turning the other one inside. After five more minutes, one steak is fried from both sides and you can take it out. Now put in the steak that we removed and turn the other one inside. After five more minutes, they both will also be fried from both sides.
Answer B
Question: A rectangular plot measuring 40 meters by 50 meters is to be enclosed by wire fencing. If the poles of the fence are kept 5 meters apart. How many poles will be needed?
A.46m
B.36m
C.26m
D.56m
Answer: B.36m
Explanation: Perimeter of the plot = 2(40+50) = 180m
no of poles =180/5 =36m
Answer: B
Question: There are two circles of different radii. The are of a square is 784 sq cm and its side is twice the radius of the larger circle. The radius of the larger circle is seven - third that of the smaller circle. Find the circumference of the smaller circle.
A.19∏ cm
B.10∏ cm
C.12∏ cm
D.11∏ cm
Answer: C.12∏ cm
Explanation: Explanation:
Let the radii of the larger and the smaller circles be l cm and s cm respectively. Let the side of the square be a cm.
a2 = 784 = (4)(196) = (22).(142)
a = (2)(14) = 28
a = 2l, l = a/2 = 14
l = (7/3)s
Therefore s = (3/7)(l) = 6 Circumference of the smaller circle = 2∏s = 12∏ cm.
Answer: Option C
Question: In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?
A.50
B.30
C.40
D.10
Answer: B.30
Explanation: Explanation :
Meal for 200 children = Meal for 120 men
Meal for 1 child = Meal for 120/200 men
Meal for 150 children = Meal for (120×150)/200 men=Meal for 90 men
Total mean available = Meal for 120 men
Renaming meal = Meal for 120 men - Meal for 90 men = Meal for 30 men . Answer : Option B
Question: Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 7. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?
A.(6m-21)/[m(m-7)]
B.(4m-21)/[m(m-7)]
C.(8m-21)/[m(m-5)]
D.(10m-21)/[m(m-5)]
Answer: B.(4m-21)/[m(m-7)]
Explanation: Three of the sandwiches were evenly divided among the students
i.e. Amount of Sandwiches with each students = 3/m
Amount of 4th Sandwich with remaining (m-7) students = 1/(m-7)
The amount of Sandwich that carol ate = 3/m + 1/(m-7) = (3m-21+m)/[m(m-7)] = (4m-21)/[m(m-7)]
Answer: B
Question: If 2|2 –f| = 5, what is the sum of all the possible values for f ?
A.1/2
B.2
C.5/2
D.4
Answer: D.4
Explanation: if f<2, then 2-f=5/2; f=-1/2
if f>2 , then f-2=5/2; f=9/2
9/2-1/2=8/2=4=D
Question: Enrollment in City College in 1980 was 42 percent of enrollment in 1990. What was the percent increase in the college’s enrollment from 1980 to 1990?
A.10%
B.138.09 %
C.20%
D.25%
Answer: B.138.09 %
Explanation: Assume 100 enrollments present in 1990
42 % of 1990 = enrollments on 1980
enrollments on 1980 = 42
% change = (enrollment in 1990 - enrollment in 1980)*100/(enrollment in 1980)
=(100 - 42) *100 / 42
= 5800 / 42
= 138.09 %
Ans - B
Question: Company S produces two kinds of stereos: basic and deluxe. Of the stereos produced by Company S last month, 2/3 were basic and the rest were deluxe. If it takes 1.1 as many hours to produce a deluxe stereo as it does to produce a basic stereo, then the number of hours it took to produce the deluxe stereos last month was what fraction of the total number of hours it took to produce all the stereos?
A.7/17
B.14/31
C.7/15
D.11/31
Answer: D.11/31
Explanation: The easiest way for me is to plug in numbers.
Let the number of basic stereos produced be 40, and number of delux stereos produced be 20. Total of 60 stereos.
If it takes an hour to produce a basic stereo then it will take 1.4 hours to produce a deluxe stereo.
40 basic stereos = 40 hours.
20 delux stereos = 22 hours.
Total hours = 62.
Then the fraction would be 22/62 = 11/31. Therefore answer
D.
Question: A garrison of 400 men had a provision for 31 days. After 28 days 280 persons re-enforcement leave the garrison. Find the number of days for which the remaining ration will be sufficient?
A.22
B.28
C.10
D.66
Answer: C.10
Explanation: 400 --- 31
400 --- 3
120 --- ?
400*3 = 120*x => x =10 days
Answer: C
Question: Of 32 applicants for a job, 14 had at least 4 years' experience, 18 had degrees, and 7 had less than 4 years' experience and did not have a degree. How many of the applicants had at least 4 years' experience and a degree?
A. 14
B. 13
C. 9
D. 7
Answer: D. 7
Explanation: set A : people with more than 4 years exp
set B : people with degree
AUB = total - (less than 4 exp and no degree)
AUB = 32-7=25
AUB = A + B - AiB
AiB = 18+14-25
=7
Answer D
Question: A car covers a certain distance at aspeed of 60 kmph in 5 hours. To cover the same distance in 4 hrs, it must travel at a speed of?
A.567 km/hr
B.75 km/hr
C.782 km/hr
D.789 km/hr
Answer: B.75 km/hr
Explanation: Distance = (60 x 5) = 300 km.
Speed = Distance/Time
Speed = 300/4 = 75 kmph
Answer : B
Question: A sports equipment store sold ping pong rackets for a total of $490. If the average (arithmetic mean) price of a pair of rackets is $9.8, how many pairs were sold?
A.50
B.100
C.490
D.500
Answer: A.50
Explanation: Average price for a pair of rackets = $9.8
Total cost = $9.8*x = $490
x = 50 pairs were sold.
ANSWER:A
Question: By walking at 4/5 of his usual speed, Mohan is 6 minute late to his office. find his usual time to cover the distance.
A.25 minutes
B.23 minutes
C.24 minute
D.26 minute
Answer: C.24 minute
Explanation: Here, Change in time = 6 and a/b = 4/5
We have, change in time = (b/a - 1) x original time
=> Original time = Change in time/(b/a - 1)
=>6(5/4 - 1) = 24 minute.
ANSWER:C
Question: A farm has only chickens and pigs. When the manager of the farm counted the heads of the animals on the farm, the number totaled up to 50. When the number of legs was counted, the number totaled up to 120. How many more chickens than pigs are there on the farm? Note: Each pig has 4 legs and each chicken had 2 legs.
A.30
B.32
C.34
D.36
Answer: A.30
Explanation: Let x be the number of chickens.
Then 50-x is the number of pigs.
2x+4(50-x)=120
2x=80
x=40 (chickens)
50-x=10 (pigs)
There are 40-10=30 more chickens on the farm.
The answer is A.
Question: If the operation ∆ is defined by a ∆ b = (b - a)^2/a^2 for all numbers a and b, and a ≠ 0, then what is the result when we evaluate this expression: (-5) ∆ (5 ∆ −5) ?
A.49/9
B.49/16
C.81/16
D.81/25
Answer: D.81/25
Explanation: (-5) ∆ (5 ∆ −5) =
(-5) ∆ (10^2/5^2) =
(-5) ∆ (4) =
(-9^2) / (-5)^2 = 81/25
The answer is D.
Question: A bag marked at $150 is sold for $120. The rate of discount is?
A.10%
B.25%
C.20%
D.50%
Answer: C.20%
Explanation: Rate of discount = 30/150 * 100 = 20%
Answer is C
Question: A family consists of grandparents, parents and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of the family ?
A.31( 5/7)
B.31( 5/9)
C.31( 5/2)
D.31( 4/7)
Answer: A.31( 5/7)
Explanation: Required average = (67 * 2 + 35 * 2 + 6 * 3) / (2 + 2 + 3)
= (134 + 70 + 18) / 7 = 222 / 7
= 31(5/7) years.
Answer: A
Question: Simplify:12345679 x 72
A.888888888
B.888888881
C.888888887
D.888888886
Answer: A.888888888
Explanation: 12345679 x 72	= 12345679 x (70 +2)
= 12345679 x 70 + 12345679 x 2
= 864197530 + 24691358
= 888888888
Answer is A
Question: A man is walking at a speed of 10 km per hour. After every kilometre, he takes rest for 7 minutes. How much time will be take to cover a distance of 7 kilometres?
A.80 min.
B.70 min.
C.84 min.
D.55 min.
Answer: C.84 min.
Explanation: Rest time = Number of rest Ã— Time for each rest
= 6 Ã— 7 = 42 minutes
Total time to cover 7 km
= (7â„10 Ã— 60)minutes + 42 minutes = 84 minutes
Answer C
Question: The first year, two cows produced 8100 litres of milk. The second year their production increased by 15% and 10% respectively, and the total amount of milk increased to 9100 litres a year. How many litres were milked from one cow?
A.2178 lt
B.3697 lt
C.6583 lt
D.4370 lt
Answer: D.4370 lt
Explanation: Let x be the amount of milk the first cow produced during the first year. Then the second cow produced (8100−x) litres of milk that year. The second year, each cow produced the same amount of milk as they did the first year plus the increase of 15%15% or 10%
So 8100+15100⋅x+10100⋅(8100−x)=9100
Therefore 8100+320x+110(8100−x)=9100
120x=190
x=3800
Therefore, the cows produced 3800 and 4300 litres of milk the first year, and 4370 and 4730 litres of milk the second year, => one cow produced 4370 litres
correct answer is D)4370 lt
Question: Three consecutive odd integers are in increasing order such that the sum of the last two integers is 13 more than the first integer. Find the three integers?
A.9, 11, 13
B.11, 13, 15
C.13, 15, 17
D.7, 9, 11
Answer: D.7, 9, 11
Explanation: Let the three consecutive odd integers be x, x + 2 and x + 4 respectively.
x + 4 + x + 2 = x + 13 => x = 7
Hence three consecutive odd integers are 7, 9 and 11.
ANSWER:D
Question: If A speaks the truth 80% of the times, B speaks the truth 60% of the times. What is the probability that at least one will tell the truth
A.0.8
B.0.92
C.1.02
D.1.2
Answer: B.0.92
Explanation: probability of A speaks truth p(A)=8/10;false=2/10
probability of B speaks truth p(B)=6/10;false=4/10.For given qtn
Ans=1-(neither of them tell truth).Because A & B are independent events
=1-[(2/10)*(4/10)]=1-8/10=1-0.08=0.92
ANSWER:B
Question: A certain sum of money doubles itself in 10 years in how much many years will it trible itself at the same rate?
A.20 years
B.76 years
C.88 years
D.44 years
Answer: A.20 years
Explanation: 100 ---- 100 --- 10
100 --- 10
--------------------
300 ---- 20 years
Answer: A
Question: if deepak has 5 pants and 3 shirts how many combinations can deepak make?
A.10
B.9
C.15
D.20
Answer: C.15
Explanation: If deepak can only choose one of each, there are 5*3 = 15 possible combinations.
Answer:C
Question: How many possible ways can 1 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?
A. 3
B. 4
C. 5
D. 6
Answer: A. 3
Explanation: Any one girl can go with 3 boys.
3 (A) is the answer
Question: A painter intends to mixed two jars of paint to create a new color. He chooses one paint jar randomly from a display containing 3 red and 2 blue samples, and a second jar is chosen at random from a different display containing 3 red and 2 blue samples. If he plans on mixing the two chosen jars together, what is the probability that when mixed together, the result will be purple paint? (The color purple is created with 1 part red and 1 part blue.)
A.1/5
B.1/2
C.2/3
D.4/5
Answer: C.2/3
Explanation: Painter has two buckets he has to randomly pick from 2 different lists ... Let these Lists be A and B ... He has to choose the first bucket from List A , and the second bucket from List B
FOR THE FIRST BUCKET ...
Red color - 2
Blue color - 2
FOR THE SECOND BUCKET
Red color - 3
Blue color -2
In order to get Purple he has to mix red with blue .. Both the LISTS contain either blue or red , therefore we have two scenarios :
Scenario I - He picks Red color from List A and Blue color from List B
Scenario II - He picks Blue color from List A and Red color from List B
Scenario I - Odds for red color from List A are 1/2 .. and for Blue color from List B are 2 /5 .. Multiplying them (because we have to find the odds that both colors are selected from their respective lists together (this is a AND not an OR problem) we get 1/5
Scenario II - Odds for blue color from List A are 1/2 , and for Red color from List B are 3/5 ... Multiplying them we get 3/10 ...
Both the scenarios are equally possible therefore we must ADD the two (not multiply ) because both of them do not have to hold true together (have to independently) for our desired result to be achieved ...
We get 1/5 + 3/10 = 2/3 (C)
Question: The average weight of a class of 20 boys was calculated to be 58.4 kgs and it was later found that one weight was misread as 56 kg instead of 66 kg. What is the correct weight?
A.58kgs
B.58.85kgs
C.58.9kgs
D.59kgs
Answer: C.58.9kgs
Explanation: Actual total weight is (20X 58.4 - 56 + 66) = 1178 Kgs
Actual average weight is 1178/20 = 58.9kgs
C
Question: What is the value of 3x^2 − 1.8x + 0.7 for x = 0.6?
A.−0.3
B.0
C.0.3
D.0.7
Answer: D.0.7
Explanation: 3x^2-1.8x+0.7 for x=0.6
=3(0.6*0.6)-3*0.6*(0.6)+0.7
=0+0.7
=0.7
ANSWER:D
Question: The number of timeshare condos available at Sunset Beach is 3/5 the number of timeshare condos available at Playa del Mar. If the total number of timeshare condos available at the two beaches combined is 400, what is the difference between the number of condos available at Sunset Beach and the number of condos available at Playa del Mar?
A.60
B.90
C.120
D.100
Answer: D.100
Explanation: Let x be the number of timeshare condos available at Playa del Mar.
Then number of timeshare condos available at Sunset Beach = 3/5x
We know, x + 3/5 x = 400
Hence, x = 250. So, number of timeshare condos available at Playa del Mar = 250
the difference between the number of condos available at Sunset Beach and the number of condos available at Playa del Mar = x - 3/5x = 2/5x = 2/5(250) = 100
The correct answer is D
Question: A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.600, what is the reduced price for kg?
A.30
B.60
C.70
D.80
Answer: A.30
Explanation: A
600*(25/100) = 150 ---- 5
? ---- 1 => Rs.30
Question: A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?
A.9, 46
B.9, 50
C.10, 46
D.10, 50
Answer: B.9, 50
Explanation: B = x
A = 3x-4
c = 6x-4
so. given A=3x-4 = 31
after 4 year A=3x = 31 -4 =27
B= x = 9
c = 6*9 -4 = 50
ANSWER:B
Question: A fifth of Arunâ€™s marks in mathematics exceed a third of his marks in English by 20.If he got 260 marks in two subjects together how many marks did he got in English?
A.120,80
B.180,60
C.200,60
D.200,40
Answer: C.200,60
Explanation: Let Arunâ€™s marks in mathematics and english be x and y
Then (1/5)x-(1/3)y=20
3x-5y=300â€¦â€¦>(1)
x+y=260â€¦â€¦.>(2)
solving (1) and (2)
x=200
and y=60
Answer is C.
Question: Which of the following is closest in value to (9^10)-(9^2)?
A.9^10
B.9^8
C.9^7
D.9^6
Answer: A.9^10
Explanation: 9^10 is much larger number than 9^2 and as we need approximate value then it's pretty much negligible in this case, so: (9^10)-(9^2) = ~9^10.
Answer: A.
Similar questions to practice:
Hope it helps.
Question: The arithmetic mean and standard deviation of a certain normal distribution are 15 and 1.5, respectively. What value is exactly 2 standard deviations less than the mean?
A.10.5
B.11
C.11.5
D.12
Answer: D.12
Explanation: The value which isexactlytwo SD less than the mean is:mean-2*SD=15-2*1.5=12.
Answer: D.
Question: Set A contains all the even numbers between 10 and 50 inclusive. Set B contains all the even numbers between 110 and 150 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A?
A.2100
B.2550
C.5050
D.6275
Answer: A.2100
Explanation: Set A contains 10, 12,14 , 16 ... 50
Set B contains 110 , 112 , 114 ... 150
Number of terms in each set = 21
Difference between corresponding terms in set A and B = 100
Difference between Sum of set B and set A = 100*21 = 2100
Answer A
Question: A bag contains 6 green balls and 8 white balls. If two balls are drawn simultaneously, what is the probability that both balls are the same colour?
A.5/14
B.8/21
C.12/21
D.43/91
Answer: D.43/91
Explanation: The total number of ways to draw two balls is 14C2 = 91
The number of ways to draw two green balls is 6C2 = 15
The number of ways to draw two white balls is 8C2 = 28
P(two balls of the same colour) = 43/91
The answer is D.
Question: A’s speed is 20/16 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat?
A.1/17
B.3/17
C.1/10
D.4/20
Answer: D.4/20
Explanation: We have the ratio of A’s speed and B’s speed. This means, we know how much distance A covers compared with B in the same time.
This is what the beginning of the race will look like:
(Start) A_________B______________________________
If A covers 20 meters, B covers 16 meters in that time. So if the race is 20 meters long, when A reaches the finish line, B would be 4 meters behind him. If we want the race to end in a dead heat, we want B to be at the finish line too at the same time. This means B should get a head start of 4 meters so that he doesn’t need to cover that. In that case, the time required by A (to cover 20 meters) would be the same as the time required by B (to cover 16 meters) to reach the finish line.
So B should get a head start of 4/20th of the race.
Answer (D)
Question: What is the probability of randomly selecting one of the shortest diagonals from all the diagonals of a regular octagon?
A.1/4
B.1/3
C.1/2
D.2/5
Answer: D.2/5
Explanation: From any vertex, there are two vertices on sides, which do not make a diagonal but a side.
So the remaining n-3 vertices make diagonals.
There are 2 of these diagonals which are the shortest.
The probability of choosing one of the shortest diagonals is 2/5.
The answer is D.
Question: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
A.223
B.175
C.297
D.267
Answer: B.175
Explanation: Explanation:
Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
{\color{Blue} \therefore } 160 x 2.40 + x x 3.20 = 432
=> 3.20x = 432 - 384 = 48
=> x = 15.
Hence, total hours of work = (160 + 15) = 175.
Answer: B) 175
Question: A boy has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
A.90
B.110
C.140
D.130
Answer: A.90
Explanation: Let number of notes of each denomination be x.
Then x + 5x + 10x = 480
16x = 480
x = 30.
Hence, total number of notes = 3x = 90.
A
Question: A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 20%?
A.3
B.4
C.5
D.6
Answer: C.5
Explanation: C.P. of 6 toffees = Rs. 1
S.P. of 6 toffees = 120% of Rs. 1 = Rs 6/5
For Rs. 6/5 Toffees Sold 6
For Rs. 1, toffees sold = 6x (5/6)= 5
answer :C
Question: Find the area of the quadrilateral of one of its diagonals is 22 cm and its off sets 9 cm and 6 cm?
A.188 cm2
B.165 cm2
C.168 cm2
D.198 cm2
Answer: B.165 cm2
Explanation: 1/2 * 22(9 + 6)
= 165 cm2
Answer: B
Question: The cross-section of a tunnel is a trapezium in shape. If the tunnel is 15 m wide at the top and 5 m wide at the bottom and the area of cross-section is 400 sq m, the depth of tunnel is?
A.200 m
B.600 m
C.400 m
D.800 m
Answer: C.400 m
Explanation: 1/2 * d (15 + 5) = 400
d = 400
ANSWER:C
Question: The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum.
A.17008
B.17000
C.170028
D.171776
Answer: B.17000
Explanation: The simple interest for the first year is 10200/2 is Rs.5100 and compound interest for first year also is Rs.5100. The compound interest for second year on Rs.5100 for one year
So rate of the interest = (100 * 1530)/ (5100 * 1) = 30% p.a.
So P = (100 * 10200)/ (30 * 2) = Rs.17000
Answer: B