RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What is the last digit in(7^95 - 3^58)?
A.5
B.6
C.4
D.9
Answer: C.4
Explanation: Explanation:
Unit digit in 795 = Unit digit in [(74)23 x 73]
= Unit digit in [(Unit digit in(2401))23 x (343)]
= Unit digit in (123 x 343)
= Unit digit in (343)
= 3
Unit digit in 358 = Unit digit in [(34)14 x 32]
= Unit digit in [Unit digit in (81)14 x 32]
= Unit digit in [(1)14 x 32]
= Unit digit in (1 x 9)
= Unit digit in (9)
= 9
Unit digit in (795 - 358) = Unit digit in (343 - 9) = Unit digit in (334) = 4.
So, Answer C
Question: The sector of a circle has radius of 21 cm and central angle 130o. Find its perimeter?
A.91.5 cm
B.89.6 cm
C.91.8 cm
D.92.5 cm
Answer: B.89.6 cm
Explanation: Perimeter of the sector = length of the arc + 2(radius)
= (130/360 * 2 * 22/7 * 21) + 2(21)
= 47.6 + 42
= 89.6 cm
Answer:B
Question: In a camp, there is a meal for 110 men or 180 children. If 145 children have taken the meal, how many men will be catered to with remaining meal?
A.20
B.30
C.50
D.21
Answer: D.21
Explanation: There is a meal for 180 children. 145 children have taken the meal.
Remaining meal is to be catered to 35 children.
Now, 180 children 110 men.
35 children (110/180)	* 35 = 21 men
Answer is D.
Question: Find the odd man out. 23, 27, 36, 52, 77, 111, 162
A.162
B.111
C.52
D.27
Answer: B.111
Explanation: Explanation :
23 + 22 = 27
27 + 32 = 36
36 + 42 = 52
52 + 52 = 77
77 + 62 = 113
113 + 72 = 162
Hence, 113 should have come in place of 111
Answer : Option B
Question: A watch was sold at a loss of 10%. If it was sold for Rs.225 more, there would have been a gain of 5%. What is the cost price?
A.1000
B.1500
C.2778
D.2788
Answer: B.1500
Explanation: 90%
105%
--------
15% ---- 225
100% ---- ? => Rs.1500
Answer:B
Question: A train 100 m long crosses a platform 125 m long in 2 sec; find the speed of the train?
A.36
B.405
C.200
D.302
Answer: B.405
Explanation: D = 100 + 125 = 225
T = 2
S = 225/2 * 18/5 = 405 kmph
Answer: B
Question: If x is an integer, then x(x - 1)(x - m) must be evenly divisible by three when m is any of the following values EXCEPT
A.-4
B.-2
C.-1
D.2
Answer: B.-2
Explanation: here's another approach
x(x - 1)(x - m)
all three are consecutive, so the product MUST be a multiple of 3
we don't know the value of k just yet ... so let's extend the series ... the extension itself reveals the answers
..(x-5)..(x-2)(x-1)x(x+1)..(x+4)..
we can see the possible values of m too from the series
m = 2 OR 2+3n [25]
m= -1 OR -1+3n [-1-4]
B i.e. -2 does not fit in any value of m
so B it is
Question: A train 400 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is?
A.298 m
B.500 m
C.900 m
D.967 m
Answer: C.900 m
Explanation: Speed = 78 * 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (400 + x)/60 = 65/3
x = 900 m.
Answer: C
Question: sale of Rs 6835, Rs. 9927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 7000 ?
A.4966
B.2477
C.2877
D.7991
Answer: D.7991
Explanation: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6500 x 6) - 34009]
= Rs. (42000 - 34009)
= Rs. 7991
Answer: D
Question: What is 990*990?
A. 974,169
B. 974,219
C. 974,549
D. 980,100
Answer: D. 980,100
Explanation: if you take a base of 1000 then 990 is 10 less than 1000
to get the product of 990 x 990 write like this
990- 10( as 10 less than base1000)
990- 10
now 10 x 10 = 100
and 990-10 = 980
so 990 x 990 = 980100 ... (bingo the answer is D . you can even have a shortcut ...... 10 x 10 = 100... only answer choice has last three digits as 100.. so no need to calculate 990-10 . after you get 10 x 10 you can straight way pick answer choice D.
Question: An ore contains 25% of an alloy that has 90% iron. Other than this, in the remaining 75% of the ore, there is no iron. How many kilograms of the ore are needed to obtain 60 kg of pure iron?
A.250 kg
B.275 kg
C.300 kg
D.266.66 kg
Answer: D.266.66 kg
Explanation: Solution: Let there is 100 kg of ore.
25% ore contains 90% off Iron that means 25 kg contains;
25*90/100 = 22.5 kg Iron.
22.5 kg Iron contains 100 kg of ore.
Then, 1 kg of iron contains = 25/100 kg ore;
Hence, 60 kg iron contains = 100*60/22.5 = 266.66 kg ore.
Answer: Option D
Question: A man purchased 3 blankets @ Rs.100 each, 6 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
A.A)300
B.B)350
C.C)450
D.D)470
Answer: A.A)300
Explanation: Explanation:
10 * 150 = 1500
3 * 100 + 6* 150 = 1200
1500 – 1200 =300
A
Question: In how many different number of ways 5 men and 2 women can sit on a shopa which can accommodate persons?
A.210
B.220
C.240
D.250
Answer: A.210
Explanation: 7p3 = 7 × 6 × 5 = 210
A)
Question: What is the compound interest paid on a sum of Rs.700 for the period of 2 years at 10% per annum.
A.130
B.620
C.147
D.120
Answer: C.147
Explanation: Solution= Interest % for 1st year= 10
Interest % for 2nd year= 10+ 10% of 10= 10+ 10 *10/100=11
Total % of interest= 10 + 11=21
Total interest = 21 % 700 = 700 * (21/100)= 147
Answer C
Question: Of the 80 electronics components that a factory must manufacture, 60 percent would be most e¢ ciently manufactured by Machine A and the remaining 40 percent would be most efficiently manufactured by Machine B, though either machine could manufacture any of the 80 components. If 60 percent of the components were manufactured by Machine A and the remainder were manufactured by Machine B, what is thehighest possible number of components that were manufactured by the machine that would manufacture them the most efficiently?
A.80
B. 32
C. 33
D. 35
Answer: A.80
Explanation: A can manufacture 60 % of 80 efficiently, which is 48.
B can manufacure 40 % of 80 efficiently, which is 32.
Now 60 % of 80 are produced by A. This means 48 parts. Since A can produce 48 efficiently, all 48 are produced efficiently. Rest (32) is produced by B, which can produce max. 32 parts efficiently.
Hence parts that were produced efficiently = 32+48 = 80. (A).
Question: Raja purchased a refrigerator for Rs. 12500 after getting a discount of 20% on the labelled price. He spent Rs. 125 on transport and Rs. 250 on installation. At what price should it be sold so that the profit earned would be 10% if no discount was offered?
A.68980
B.46898
C.56849
D.17600
Answer: D.17600
Explanation: D
Price at which the TV set is bought = Rs. 12,500
Discount offered = 20%
Marked Price = 12500 * 100/80 = Rs. 15625
The total amount spent on transport and installation = 125 + 250 = Rs. 375\Total price of TV set = 15625 + 375 = Rs. 16000
The price at which the TV should be sold to get a profit of 10% if no discount was offered = 16000 * 110/100 = Rs. 17600
Question: The edges of a cuboid are respectively 3cm, 4cm and 12 cm. Find the length of the diagonal of cuboid.
A.9: 8
B.9: 5
C.9: 1
D.9: 2
Answer: C.9: 1
Explanation: a1 : a2 = 3 : 1
6 a12 : 6 a22 = 9: 1
Answer:C
Question: When x is divided by y, the quotient is z with remainder r. Which of the following is equal to r?
A.yz – x
B.y/x−z
C.x – y – z
D.x – yz
Answer: D.x – yz
Explanation: (x/y)=z(+r)
(18/8)=2(+2)
x-yz
which is 18-(8*2)=2
Answer is D
Question: A miniature gumball machine contains 4 blue, 3 green, and 2 red gumballs, which are identical except for their colors. If the machine dispenses three gumballs at random, what is the probability that it dispenses one gumball of each color?
A.2/7
B.3/7
C.3/14
D.5/24
Answer: A.2/7
Explanation: The total number of ways to dispense 3 gumballs is 9C3=84.
The number of ways to choose one of each color is 4*3*2=24.
P(dispensing one of each color)=24/84=2/7.
The answer is A.
Question: In a History examination, the average for the entire class was 80 marks. If 10% of the students scored 35 marks and 20% scored 90 marks, what was the average marks of the remaining students of the class ?
A.22
B.27
C.75
D.29
Answer: C.75
Explanation: Explanation:
Let the number of students in the class be 100 and let this required average be x.
Then, (10 * 95) + (20 * 90) + (70 * x) = (100 * 80)
=> 70x = 8000 - (950 + 1800) = 5250
=> x = 75.
Answer: C) 75
Question: In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many
men will be catered to with the remaining meal ?
A.38 men
B.32 men
C.34 men
D.30 men
Answer: D.30 men
Explanation: Explanation:
There is meal for 200 children. 150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children = 120 men
So, 50 Children = 120/200 * 50 = 30 men
Answer: D
Question: The ratio between the presents of the A and B is 6:7. If B is 4 years older than A, what will be the ratio of the ages of A and B after 4 years?
A.1:2
B.9:11
C.7:8
D.6:7
Answer: C.7:8
Explanation: Let A and B ages will be 6x and 7x
7x - 6x = 4
x = 4
Required ratio = 6x+4 : 7x+4 = 28:32 = 7:8
Answer is C
Question: The salary of A, B, C, D, E is Rs. 10000, Rs. 5000, Rs. 11000, Rs. 7000, Rs. 9000 per month respectively, then the average salary of A, B, C, D, and E per month is
A.Rs. 7000
B.Rs. 8400
C.Rs. 8500
D.Rs. 9000
Answer: B.Rs. 8400
Explanation: Answer
Average salary
= 10000 + 5000 + 11000 + 7000 + 9000 / 5
= Rs. 8400
Correct Option: B
Question: The triplicate ratio of 1:8 is?
A.1:0
B.1:8
C.1:7
D.1:512
Answer: D.1:512
Explanation: 13: 83 = 1:512
Answer: D
Question: The length of the bridge, which a train 110 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
A.328
B.279
C.265
D.288
Answer: C.265
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (110 + X)/30 = 25/2 ==> 2(110 + X) = 750 ==> X = 265 m.Answer: C
Question: A man and a boy complete a work together in 24 days. If for the last 6 days man alone does the work then it is completed in 26 days. How long the boy will take to complete the work alone?
A.days
B.days
C.days
D.days
Answer: A.days
Explanation: Explanation:
(man + boy)’s 1 day’s work = 1/24
Their 20 day’s work = 1/24 × 20 = 5/6
The remaining 1/6 work is done by the man in 6days
Therefore, the man alone will finish the work in 6 × 6 days = 36 days
Man’s 1 day’s work = 1/36
Therefore, boy’s 1 day’s work = 1/24 – 1/36 = 3 – 2 /72 = 1/72
Therefore, the Boy alone will finish the work in 72 days.
Answer: Option A
Question: Pinky bought six Chocolate at an average price (arithmetic mean) of 5¢. If Pinky returned four chocolate to the retailer, and the average price of the remaining chocolate was 2¢, then what is the average price, in cents, of the four returned chocolates?
A.6.5
B.5.5
C.4.5
D.5
Answer: A.6.5
Explanation: Total price of 6 chocolates=6*5=30
Total price of 2 chocolates=2*2=4
Total price of 4 returned chocolates=30-4=26
Average price of 4 returned chocolate=26/4=6.5
Correct option Answer:A
Question: John makes $30 a week from his job. He earns a raise andnow makes $40 a week. What is the % increase?
A.16%
B.33.33%
C.33.69%
D.33.98%
Answer: B.33.33%
Explanation: Increase = (10/30)*100 = (1/3)*100 = 33.33%.
B
Question: The avearage age of boys in a class is 16 years and that of the girls is 15 years. The average age for the whole class is
A.15 years
B.15.5 years
C.16 years
D.Cannot be computed
Answer: D.Cannot be computed
Explanation: Solution
Clearly, to find the average,we ought to know the numbers of boys , girls or students in the class, neither of which has been given.
so the data provided is inadequate.
Answer D
Question: Shipment --- No. of Defective Chips/shipment --- Total Chips in shipment
S1 ---------------------- 5 ------------------------------------------ 5,000
S2 ---------------------- 5 ------------------- ---------------------- 12,000
S3 ---------------------- 8 ------------------------------------------ 17,000
S4 ---------------------- 7 ------------------------------------------ 16,000
A computer chip manufacturer expects the ratio of the number of defective chips to the total number of chips in all future shipments to equal the corresponding ratio for shipments S1, S2, S3, and S4 combined, as shown in the table above. What’s the expected number of defective chips in a shipment of 60,000 chips?
A.14
B.20
C.22
D.30
Answer: D.30
Explanation: for a total of 51000 chips (adding S1,S2,S3,S4) total number of defective chips is 17 ((adding defective chips of S1,S2,S3,S4) so ratio is 25/50000 or 1 every 2000 chips.
Keeping this ratio constant for 60000 chips number of defective chips will be (1/2000) * 60000 = 30
D
Question: A classroom has equal number of boys and girls. NINE girls left to play kho-kho, leaving twice as many boys as girls in the classroom. What was the total number of girls and boys present initially?
A.36
B.24
C.32
D.48
Answer: A.36
Explanation: after 9 girls left remaining 9 girls
now boys 18 are twice as many as remaining girls.
initially boys=18 and girls=18.
ANSWER:A
Question: A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
A.31.11 km/hr
B.35.55 km/hr
C.71.11 km/hr
D.36 km/hr
Answer: C.71.11 km/hr
Explanation: Total time taken = 160/64 + 160/80 = 9/2 hours
--> Average speed = 320 x 2/9 = 71.11 km/hr.
Answer : C.
Question: The average age of 35 students in a class is 16 years. The average age of 21 students is 14. What is the average age of remaining 95 students?
A.14 years
B.1.7 years
C.1.9 years
D.2.8 years
Answer: D.2.8 years
Explanation: Solution
Sum of the ages of 14 students	= (16 x 35) - (14 x 21)
= 560 - 294.
= 266.
∴ Required average	= 266 / 95
= 2.8years.
Answer D
Question: What decimal fraction is 40 ml of a litre ?
A..4
B..04
C..05
D.0.04
Answer: B..04
Explanation: Answer
Required fraction = 40/1000
= 4/100
= .04
Correct Option: B
Question: Rajani, Roja and Ramani share a sum of money in the ratio 7 : 8 : 16. If Ramani receives Rs. 27 more than Rajani, then the total money shared was:
A.Rs 33
B.Rs 49
C.Rs 93
D.Rs 69
Answer: C.Rs 93
Explanation: Explanation :
Let Rajani = 7x, Roja = 8x & Ramani = 16x. Then, total money = 31x.
Now, Ramani - Rajani = 27 so 16x7x = 27 that is why x = 3.
Total money 31*x = Rs.93.
Answer : C
Question: The positive numbers w, x, y, and z are such that x is 35 percent greater than y, y is 20 percent greater than z, and w is 20 percent less than x. What percent greater than z is w ?
A.15.2%
B.16.0%
C.20.0%
D.23.2%
Answer: C.20.0%
Explanation: My strategy is same as theDobermanbut instead take z=100, which makes life a bit easy. As:
z=100
y=120 (20% greater than z)
z=144(20% greater than y)
Now calculate w 20% less than z = 144*80/100= 115.2
Now by just looking, relation between w and z:
w-z/z*100 = 20 - Answer C
Question: A train covers a distance of 12 km in 10 min. If it takes 2 sec to pass a telegraph post, then the length of the train is?
A.40
B.80
C.120
D.60
Answer: A.40
Explanation: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec = 20 m/sec.
Length of the train = 20 * 2 = 40 m.
Answer: Option A
Question: In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
A.21/46
B.25/117
C.1/50
D.3/25
Answer: A.21/46
Explanation: Let S be the sample space and E be the event of selecting 1 girl and 2 boys.
Then, n(S)	= Number ways of selecting 3 students out of 25
= 25C3 `
=	(25 x 24 x 23)/(3 x 2 x 1)
= 2300.
n(E)	= (10C1 x 15C2)
=	[10 x	((15 x 14)/(2 x 1))]
= 1050.
P(E) =n(E)/n(S)=1050/2300=21/46	.
Answer :A
Question: A family has two children. find the probability that both the children are girls given that at least
one of them is a girl?
A.1/3
B.1/5
C.1/7
D.1/9
Answer: A.1/3
Explanation: Let b stand for boy and g for girl. The sample space of the experiment is
S = {(g, g), (g, b), (b, g), (b, b)}
Let E and F denote the following events :
E : ‘both the children are girls’
F : ‘at least one of the child is a girl’
Then E = {(g,g)} and F = {(g,g), (g,b), (b,g)}
Now E n F = {(g,g)}
Thus P(F) = 3/4
and P (E n F )= 1/4
Therefore P(E|F) = P(E ∩ F)/P(F) = (1/4)/(3/4) = 1/3
A
Question: Three friends (Sarah, Jane and Gina) are employees of a company. Their respective salaries are in the ratio of 1 : 3 : 7. Jane and Gina's salaries together is Rs. 7000. By what percent is Gina's salary than that of Sarah?
A.200%
B.600%
C.100%
D.300%
Answer: B.600%
Explanation: Explanation:
Let the salaries be x, 3x and 7x respectively.
Then,3x + 7x = 7000 => x = 700.
Sarah's salary = Rs. 700, Jane's salary = Rs. 2100, and Gina's salary Rs. 4900.
Excess of Gina's salary over Sarah's=[ (4200 /700) x 100] = 600%.
Answer: B
Question: A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
A.40 sec
B.42 sec
C.45 sec
D.48 sec
Answer: A.40 sec
Explanation: total length= 360+140=500
speed=45km/h=(45*5)/18= 25/2m/s
time=(500*2)/25=40 sec.
ANSWER:A
Question: A cyclist covers a distance of 750m in 2 min 30sec. What is the speed in km/hr of the cyclist?
A.18
B.15
C.9
D.5
Answer: A.18
Explanation: distance = 750 m
time = 2min 30 sec = 150 sec
speed = (750/150) m/s = 5m/s
speed in km/hr = 5*18/5 = 18 km/hr
correct option is A
Question: Naresh’s monthly income is 30% more than that of Raghu. Raghu’s monthly income is 20% less than that of Vishal. If the difference between the monthly incomes of Naresh and Vishal is 800, what is the monthly income of Raghu?
A.16,000
B.20,000
C.12,000
D.Data inadequate
Answer: A.16,000
Explanation: N = R + 30% of R = 1.3 RR
= V – 20% of V = 80% of V = 0.8 V
∴ N = 1.3 × 0.8V = 1.04 V
Now, N – V = 1.04 V – V = 0.04 V = 800(given)
∴ V = 20000
∴ R = 0.8 × 20000 = 16000
Answer A
Question: A car moves at 45 km/hr. What is the speed of the car in meters per second ?
A.12 1/2 m sec
B.12 2/9m sec
C.14 1/9m sec
D.16 1/2m sec
Answer: A.12 1/2 m sec
Explanation: Explanation:
Speed=(45∗5/18)m/sec
=25/2 m/sec
=12 1/2 msec
Option A
Question: 1, 9, 17, 33, 49, 73, ?
A.81
B.83
C.85
D.97
Answer: D.97
Explanation: The pattern is + 8, + 8, + 16, + 24,...
Answer : D.
Question: Robert ate 7 chocolates, Nickel ate 3 chocolates. How many more chocolates did Robert ate than nickel?
A.4
B.7
C.9
D.5
Answer: A.4
Explanation: 7-3=4. Answer is A
Question: The cost of 10 kg of mangos is equal to the cost of 24 kg of rice. The cost of 6 kg of flour equals the cost of 2 kg of rice. The cost of each kg of flour is $21. Find the total cost of 4 kg of mangos, 3 kg of rice and 5 kg of flour?
A.347.8
B.987.8
C.877.8
D.898.8
Answer: D.898.8
Explanation: Let the costs of each kg of mangos and each kg of rice be $a and $r respectively.
10a = 24r and 6 * 21 = 2r
a = 12/5 r and r = 63
a = 151.2
Required total cost = 4 * 151.2 + 3 * 63 + 5 * 21
= 604.8 + 189 + 105 = $898.80
D
Question: Which of the following must be true?
1) Every prime number greater than 5 can be written as either as 8n+1 or 8n-1
2) Every prime number greater than 5 can be written as 4n+1 or 4n-1
3) Every number greater than 5 of the form 8n+1 or 8n-1 is a prime number.
A.1,2,3
B.2,3
C.1,2
D.only 1
Answer: C.1,2
Explanation: Every prime number greater than 3 can be written in the form of 8n+1 or 8n-1 where n is an integer. So 1 can be possible.
3. This is not possible as 2 and 3 are being prime , we can't write then in the form of 8n+1 or 8n-1.
C
Question: The organizers of a week-long fair have hired exactly seven security guards to patrol the fairgrounds at night for the duration of the event. Exactly three guards are assigned to patrol the grounds every night, with no guard assigned consecutive nights. If the fair begins on a Monday, how many different groups of 3 guards will be available to patrol the fairgrounds on the following Saturday night?
A.3
B.4
C.5
D.6
Answer: B.4
Explanation: For any given day, only the guards patrolling on the previous day won't be available. So, 3 guards who patrolled on Friday won't be available. We are thus left with 4 guards.
To choose 3 out of 4, we will have 4C3 = 4 different groups.
The answer is B.
Question: If a certain sample of data has a mean of 23.0 and a standard deviation of 3.0, which of the following values is more than 2.5 standard deviations from the mean?
A.12.0
B.13.5
C.17.0
D.15.5
Answer: D.15.5
Explanation: The standard deviation is 3. 2.5 standard deviations, which is just 2.5 x 3.0 is 7.5. The only answer more than 7.5 away from the mean is D.
Question: 5+5 = 10
38+20 = 1858
5+3 = 28
9+1 = 810
8+6 = 214
5+4 = 19
7+3 = ?
A.400
B.410
C.420
D.430
Answer: B.410
Explanation: equence is like that first the sum of digits is written then subtraction of digits is written....ex 5+5=10 solution:5-5=0,5+5=10...same way 7+3=10and 7-3=4
so 7+3=410..
ANSWER:B
Question: city A to city B, Andrew drove for 1 hour at 50 mph and for 3 hours at 60 mph. What was the average speed for the whole trip?
A.57
B.57.5
C.56
D.59
Answer: B.57.5
Explanation: The total distance is 1×50+3×60=2301×50+3×60=230. And the total time is 4 hours. Hence,
Average Speed=(Total DistanceTotal Time)=2304=57.5
B
Question: add 15% of 25 and 12% of 45.
A.9.2
B.10.5
C.11.5
D.12.3
Answer: A.9.2
Explanation: 15% of 25 + 12% of 45
25*15/100+45*12/100
3.8+5.4=9.2
answer A
Question: A and B complete a work in 8 days. A alone can do it in 12 days. If both together can do the work in how many days?
A.3.75 days
B.3.99 days
C.2.99 days
D.4.8 days
Answer: D.4.8 days
Explanation: 1/8 + 1/12 = 5/24
24/5 = 4.8 days
Answer: D
Question: Three walls have wallpaper covering a combined area of 300 square meters. By overlapping the wallpaper to cover a wall with an area of 180 square meters, the area that is covered by exactly two layers of wallpaper is 30 square meters. What is the area that is covered with three layers of wallpaper?
A.5 Square Meters
B.36 Square Meters
C.42 Square Meters
D.45 Square Meters
Answer: D.45 Square Meters
Explanation: 300 - 180 = 120 sq m of the wallpaper overlaps (in either two layers or three layers)
If 36 sq m has two layers, 120 - 30= 90 sq m of the wallpaper overlaps in three layers. 90 sq m makes two extra layers hence the area over which it makes two extra layers is 45 sq m.
Answer (D).
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20%?
A.20
B.77
C.66
D.55
Answer: A.20
Explanation: SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Answer: A
Question: (X% of Y) +(Y% of X) is equal to:
A.X% of Y
B.20% of XY
C.2% of XY
D.2% of 100 XY
Answer: C.2% of XY
Explanation: Solution: According to question,
(XY /100) + (YX /100)
= 2XY /100
= 2% of XY.
Answer: Option C
Question: A shopkeeper purchased 70 kg of potatoes for Rs. 420 and sold the whole lot at the rate of Rs. 6.50 per kg. What will be his gain percent?
A.8 1/8 %
B.8 3/3 %
C.8 1/3 %
D.2 1/3 %
Answer: C.8 1/3 %
Explanation: Explanation:
C.P. of 1 kg = 420/7 = Rs. 6
S.P. of 1 kg = Rs. 6.50
Gain % = 0.50/6 * 100 = 25/3 = 8 1/3 %
Answer: C
Question: What no. should be subtracted from x^3+4x^2−7x+12x^3+4x^2−7x+12, if it is to be perfectly divisible by x+3x+3?
A.34
B.42
C.47
D.58
Answer: B.42
Explanation: According to remainder theorem when dfracf(x)x+adfracf(x)x+a, then the remainder is f(−a)f(−a).
In this case, as x+3x+3 divides x3+4x2−7x+12–kx3+4x2−7x+12–k perfectly (kk being the number to be subtracted), the remainder is 0 when the value of xx is substituted by -3.
i.e., (−3)3+4(−3)2−7(−3)+12−k=0(−3)3+4(−3)2−7(−3)+12−k=0
or −27+36+21+12=k−27+36+21+12=k
or k=k= 42
B
Question: If cost of 15 eggs be 70 rupees, then find out the cost of 5 dozen eggs.
A.276
B.400
C.500
D.600
Answer: A.276
Explanation: Cost of 15 eggs = 70 rupees
Cost of 1 egg = 70/15 = 4.6 rupees,
Cost of 5 dozens, i.e. 4.6 x 12 = 55.2 x 5 = 276
Answer : A
Question: If the area of circle is 616 sq cm then its circumference?
A.88
B.99
C.62
D.27
Answer: A.88
Explanation: 22/7 r2 = 616 => r = 14
2 * 22/7 * 14 = 88
Answer:A
Question: Jason flips a coin three times. What is the probability B that the coin will land on the same side in all three tosses?
A.1/16
B.1/8
C.1/4
D.1/3
Answer: C.1/4
Explanation: Total outcome is 2^3=8
Favorable cases HHH or TTT
Therefore, probability B is 2/8 or 1/4.C