RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
A.70,10 kmph
B.78,10 kmph
C.70,70 kmph
D.78,10 kmph
Answer: A.70,10 kmph
Explanation: Speed of the boat in still water
= (60+80)/2
= 70 kmph. Speed of the stream
= (80-60)/2
= 10 kmph.
Answer:A
Question: In filling a lot with sand, that is 40 m * 20 m * 2m the volumes of the sand filled will be?
A.1200 cu.m
B.2200 cu.m
C.4800 cu.m
D.1600 cu.m
Answer: D.1600 cu.m
Explanation: 40 * 20 * 2 = 1600
ANSWER:D
Question: One student's mark was wrongly entered as 73 instead of 63. Due to that the average marks for the class got increased by 1/3. What is the number of students in the class?
A.30
B.32
C.35
D.40
Answer: A.30
Explanation: Let the total number of students = a
The average marks increased by 1/3 due to an increase of 73 - 63 = 10 marks.
But total increase in the marks = 1/3 *x =x/3
Hence we can write as
=>x/3=10
=>x=30
ANSWER:A
Question: A person walks at a speed of 4 km/hr and runs at a speed of 8 km/hr. How many hours will the person require to cover a distance of 12 km, if the person completes half of the distance by walking and the other half by running?
A.1.25
B.1.75
C.2.25
D.2.75
Answer: C.2.25
Explanation: time = 6/4 + 6/8 = 18/8 = 2.25 hours
The answer is C.
Question: The average age of a class is 15.8 years. The average age of boys in the class is 16.4 years while that of girls is 15.4 years. What is the ratio of boys to girls in the class?
A.1:2
B.3:4
C.3:5
D.2:3
Answer: D.2:3
Explanation: let x = number of girls
y = number of boys
sum of girls ages / x = 15.4
sum of boys ages / y = 16.4
The sum of the girls' ages is 15.4x, and boys' sum is 16.4y
(sum of girls ages + sum of boys ages) / (x+y)= 15.8
(15.4x + 16.4y) / (x+y) = 15.8
15.4x + 16.4y = 15.8(x+y)
15.4x + 16.4y = 15.8x + 15.8y
0.6y = 0.4x
0.6y/x = 0.4
y/x = 0.4/0.6
y/x = 2/3 which is the ratio of boys to girls
ANSWER:D
Question: When positive integer n is divided by 3, the remainder is 1. When n is divided by 5, the remainder is 3. What is the smallest positive integer k such that k+n is a multiple of 15?
A.2
B.4
C.6
D.8
Answer: A.2
Explanation: n = 3p + 1 = 5q + 3
n+2 = 3p + 3 = 5q + 5
n+2 is a multiple of 3 and 5, so it is a multiple of 15.
The answer is A.
Question: How many three-digit integers exist such that all their digits are
odd?
A.80
B.100
C.120
D.125
Answer: D.125
Explanation: so last digit can be filled in 5 ways- 1,3,5,7,9
there are 5 possibilities. The answer is 5∗5∗5=125
The correct answer is D
Question: A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weights 8g/cm cube, then find the weight of the pipe.
A.3.696 kg
B.3.686 kg
C.2.696 kg
D.2.686 kg
Answer: A.3.696 kg
Explanation: Explanation:
In this type of question, we need to subtract external radius and internal radius to get the answer using the volume formula as the pipe is hollow. Oh! line become a bit complicated, sorry for that, lets solve it.
External radius = 4 cm
Internal radius = 3 cm [because thickness of pipe is 1 cm]
Volume of iron =πr2h=22/7∗[42−32]∗21cm3
=22/7∗1∗21cm3=462cm3
Weight of iron = 462*8 = 3696 gm
= 3.696 kg
Option A
Question: The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8339 for a computer table, then what was the cost price of the computer table?
A.Rs. 6825
B.Rs. 6721
C.Rs. 6725.
D.Rs. 4298
Answer: C.Rs. 6725.
Explanation: CP = SP * (100/(100 + profit%))
= 8339(100/124) = Rs. 6725.
Answer:C
Question: Two cards are selected at random from 10 cards numbered 1 to 10. Find the probability that the sum is odd if two cards are drawn together.
A.11
B.88
C.77
D.19
Answer: C.77
Explanation: Answer:C
Question: A man sitting in a train which is traveling at 50 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.?
A.50 kmph
B.58 kmph
C.62 kmph
D.65 kmph
Answer: C.62 kmph
Explanation: Relative speed = 280/9 m / sec = ((280/9)*(18/5)) kmph = 112 kmph.
Speed of goods train = (112 - 50) kmph = 62 kmph.
Answer : C.
Question: The ratio of males to females in a class is 2:3. The career preferences of the students in the class are represented in a circle graph. If the area of the graph allocated to each career preference is proportional to the number of students who have that career preference, how many degrees of the circle should be used to represent a career that is preferred by one-half of the males and one-fourth of the females in the class?
A.120
B.126
C.132
D.138
Answer: B.126
Explanation: 1/2*2/5 + 1/4*3/5 = 4/20 + 3/20 = 7/20
The number of degrees is 7/20 * 360 = 126 degrees
The answer is B.
Question: On a sum of money, the S.I. for 2 years is Rs. 660, while the C.I. is Rs. 696.30, the rate of interest being the same in both the cases. The rate of interest is?
A.10%
B.10.5%
C.12%
D.13%
Answer: D.13%
Explanation: Difference in C.I. and S.I for 2 years = (696.30 - 660) = Rs. 36.30.
S.I for one year = Rs. 330.
S.I. on Rs. 330 for 1 year = Rs. 36.30
Rate = (100 * 36.30)/(330 * 1) = 11%
ANSWER:D
Question: Jonathan can type a 50 page document in 40 minutes, Susan can type it in 30 minutes, and Jack can type it in 24 minutes. Working together, how much time will it take them to type the same document?
A.5 minutes
B.10 minutes
C.15 minutes
D.18 minutes
Answer: B.10 minutes
Explanation: You may set up common equation like this:
job/A+job/B+job/C=job/x
Memorize this universal formula, you will need it definitely for GMAT.
and find x from this equation
In this specific case, the equation will look like this:
50/40+50/30+50/24=50/x
If you solve this equation, you get the same answer B (10)
Question: A wheel that has 6 cogs is meshed with a larger wheel of 21 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions made by the larger wheel is:
A.9
B.10
C.6
D.8
Answer: C.6
Explanation: Explanation :
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
21:6::21:x => 21 * x = 21 * 6
=> x = (21 * 6)/21
=> x = 6
Answer : C
Question: What is the sum of all the multiples of 9 between 0 and 99?
A.500
B.594
C.450
D.340
Answer: B.594
Explanation: The multiples of 9 between 0 and 99 are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99. If these are all added together, the result is 594.
Final Answer:
B
Question: Compound interest earned on a sum for the second and the third years are Rs.1200 and Rs.1440 respectively. Find the rate of interest?
A.33
B.27
C.20
D.98
Answer: C.20
Explanation: Rs.1440 - 1200 = Rs.240 is the interest on Rs.1200 for one year.
Rate of interest = (100 * 240) / (100 * 1) = 20% p.a
Answer:C
Question: A can do a piece of work in 3 hours; B and C together can do it in 6 hours, while A and C together can do it in 9 hours. How long will B alone take to do it?
A.4 9/7 hours
B.3 5/7 hours
C.2 4/7 hours
D.3 8/7 hours
Answer: C.2 4/7 hours
Explanation: A's 1 hour's work = 1/3 ;
(B + C)'s 1 hour's work = 1/6 ;
(B + C)'s 1 hour's work = 1/9
(A + B + C)'s 1 hour's work = (1/3 + 1/6) = 1/2
B's 1 hour's work = (1/2 - 1/9) = 7/18
B alone will take 18/7 hours to do the work.
=2 4/7
Answer = C
Question: Calculate the value of 2.71 x 10^9 ?
A.2710000000
B.271000
C.2710000
D.27100000
Answer: A.2710000000
Explanation: 2.71 x 10^9 = 2.71 x 1000000000 = 2710000000.
Answer = A
Question: A is thrice good a workman as B and therefore is able to finish a job in 60 days less than B. Working together they can do it in?
A.20
B.22 ½
C.25
D.30
Answer: B.22 ½
Explanation: Explanation:
Ratio of times by A and B= 1:3
difference of time is 2 days B takes 3 days if diff of time is 60 days B takes 3/2 *60 =90 days
A’s 1day work is=1/30
B’s 1 day work =1/90
(A+B )’s one day work is=1/90 +1/30 =2/45
together can do work in 45/2 = 22 ½ days
Answer: Option B
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
A.23 m
B.23 (2/9)m
C.27 (7/9)m
D.29 m
Answer: C.27 (7/9)m
Explanation: Relative speed = (40 - 20) km/hr =	(20 x(5/18))m/sec =	(50/9)m/sec.
Therefore Length of faster train =	((50/9)	x 5) m =	(250/9)m = 27	(7/9)	m.
C
Question: If the product of all the factors of a positive integer, N, is 2 ^ 18 * 3 ^ 12, how many values can N take?
A.None
B.1
C.2
D.3
Answer: B.1
Explanation: Lets say
2^0 *3^0 * 2^0 * 3^1....2^0 * 3^n ...A0 >> 2^{0*(N+1)} * 3^{N(N+1)/2}
2^1 *3^0 * 2^1 * 3^1....2^1 * 3^n ...A2 >> 2^{1*(N+1)} * 3^{N(N+1)/2}
.
.
.
2^m *3^0 * 2^m * 3^1....2^m * 3^n ...AM >> 2^{M*(N+1)} * 3^[N(N+1)/2}
So product of all the factors are: A0 * A1 *...*AM = 2^{M(M+1)*(N+1)/2} * 3^{N(N+1)*(M+1)/2}
From the equation:
M(M+1)*(N+1)/2 = 18 --- X
N(N+1)*(M+1)/2 = 12 --- Y
dividing X, Y, we get M/N = 3/2
Lets say M = 3X, N = 2X
substituting the value in X OR Y we got X = 1 is the only integer satisfying
Hence the number is 2 ^ 3 * 3 ^ 2
Answer is B
Question: MAN1 is 30% more efficient than MAN2. How much time will they, working together, take to complete a job which MAN1 alone could have done in 23 days?
A.10 days
B.12 days
C.13 days
D.14 days
Answer: C.13 days
Explanation: Man1 and Man2 = 100:130 = 10:13
==> Man2 ==> x days
then 10:13:23 :x ==> x=(23*13/10)
x=299/10
Man 1 day work = 1/23
Man2 work = 10/299
(A+B) = 1/23+10/299 = 1/13
==>13 days
ANSWER C
Question: In a class there are 20 boys and 25 girls. In how many ways can a boy and a girl be selected?
A.400
B.500
C.600
D.530
Answer: B.500
Explanation: Explanation:
We can select one boy from 20 boys in 20 ways.
We select one girl from 25 girls in 25 ways
We select a boy and girl in 20 * 25 ways i.e., = 500 ways.
Answer: Option B
Question: Rs.8000 become Rs.9261 in a certain interval of time at the rate of 5% per annum of C.I. Find the time?
A.10years
B.12 years
C.5 years
D.3 years
Answer: D.3 years
Explanation: Explanation:
9261 = 8000(21/20)N
(21/20)3 = (21/20)N => N = 3 years
Answer:D
Question: There are 6 gentlemen and 3 ladies to dine at a round table. In how many ways can they seat themselves so that no two ladies are seated together.
A.8540
B.3640
C.2880
D.3880
Answer: C.2880
Explanation: First arrange the Gents. This is a circular arrangment. 6 Gents can be arranged in 5! ways.
Now there are 4 spaces (space in between two gents) and we have to seat 3 ladies there.
First select 3 places out of 4 available places. can be done in 4C3ways. Then arrange 3 ladies there in 3! ways.
Total: 5!*4C3*3! = 2880
C is the answer.
Question: A regular octagon is inscribed in a circle. If A and B are adjacent vertices of the pentagon and O is the center of the circle, what is the value of ∠OAB ?
A.48 degrees
B.54 degrees
C.67.5 degrees
D.84 degrees
Answer: C.67.5 degrees
Explanation: its a regular pentagon so divide the globe by 8.
= 360/8
= 45
45 would be the angle at O.
Angles at A and B are equivalent, so
45 + 2x = 180
2x = 135
x = 67.5
Angles OAB and OBA will be 67.5 degrees each.
C
Question: Given distinct positive integers 1, 10, 3, x, 2, and 9, which of the following could be the median?
A.3
B.4
C.7
D.8
Answer: B.4
Explanation: The median of a set with even number of terms is the average of two middle terms when arranged in ascending (or descending) order.
Arrange numbers in ascending order: 1, 2, 3, 9, 10, and x.
Now, x can not possibly be less than 3 as given that all integers are positive and distinct (and we already have 1, 2, and 3).
Next, if x is 3<x<9 then the median will be the average of 3 and x. As all answers for the median are integers, then try odd values for x:
If x=5, then median=(3+5)/2=4 --> OK;
Answer: B.
P.S. If x is more than 9 so 10 or more then the median will be the average of 3 and 9 so (3+9)/2=6 (the maximum median possible).
Question: Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 36 kmph. In how much time will the trains cross each other?
A.12 sec
B.13 sec
C.15 sec
D.16 sec
Answer: D.16 sec
Explanation: D
Relative speed = (54 + 36)* 5/18 = 5 * 5 = 25 mps.
The time required = d/s = (100 + 100 + 200)/25
= 400/25 = 16 sec.
Question: The sides BC, CA, AB of triangle ABC have 3, 4, 5 interior points respectively on them. How many triangles can be formed using these points as vertices.
A.200
B.205
C.400
D.410
Answer: B.205
Explanation: Total points: 3+4+5=12;
Any 3 points out of 12 but those which are collinear will form a triangle, so C312−(C33+C34+C35)=220−(1+4+10)=205C123−(C33+C43+C53)=220−(1+4+10)=205.
Answer: B.
Question: find two integers, neither of which ends in a zero, and whose product is exactly 1,000
A.64 and 15,625
B.60 and 15,625
C.8 and 125
D.64 and 15,635
Answer: C.8 and 125
Explanation: 1,000=10^3
=10x10x10
=(2x5)x(2x5)x(2x5)
=(2^3)x(5^3)
= 8x125
so the numbers are 8 and 125
ANSWER:C
Question: When x is multiplied by 3, the result is 16 more than the result of subtracting x from 36. What is the value of x?
A.-4
B.-2
C.11
D.13
Answer: D.13
Explanation: The equation that can be formed is:
3x-16=36-x
or, 4x=52
or, x=13.
Answer : D
Question: Three vehecle speed ratio 1:2:3 & time ratio 3:2:1...Distance ratio ??
A.3:4:2
B.3:4:3
C.3:4:6
D.3:4:9
Answer: B.3:4:3
Explanation: speed let ratio be x................x : 2x : 3x
time let ratio be y..................3y : 2y : y
since distance = speed * time ,,,,, 3xy : 4xy :3xy => 3:4:3
ANSWER:B
Question: After allowing a discount of 15% on the marked price, the selling price is Rs. 6800 for an article. If it was sold at marked price, there would have been a profit of 60%. The cost price of the article is?
A.Rs. 6400
B.Rs. 5600
C.Rs. 5000
D.Rs. 4800
Answer: C.Rs. 5000
Explanation: Given SP = Rs. 6800
Marked price = [SP(100)]/(100 - d%) = (6800 * 100)/(100 - 15) = Rs. 8000
If SP = Rs. 8000, profit = 60%
CP = [SP(100)]/(100 + 60) = (8000 * 100)/160 = Rs. 5000
ANSWER:C
Question: What will be the reminder when (19^19+19) is divided by 20?
A.18
B.40
C.21
D.43
Answer: A.18
Explanation: (x^n+1) will be divisible by (x+1) only when n is odd;
(19^19+1) will be divisible by (19+1);
(19^19+1)+18 when divided by 20 will give 18 as remainder.
Correct Option : A
Question: 8 liters of solution is removed from 20% milk solution and 8 liters of water is added to the solution. The resulting solution has 16% milk in it. What was the initial quantity of the 20% milk solution?
A.40
B.50
C.60
D.70
Answer: A.40
Explanation: Allegation method.
Concentration of Alcohol in original sol - 20%
Concentration of Alcohol in water -- 0%
Concentration of Alcohol in final sol -- 16%
After applying allegation as shown in figure they have to be mixed in 4:1 part
1 part is given as 8 ltr, so total initial volume is 5 part = 5*8 = 40 Ltrs
ANSWER:A
Question: The sides of a rectangular field are in the ratio 3 : 4. If the area of the field is 8748 sq. m, the cost of fencing the field @ 25 paise per metre is
A.Rs. 55.50
B.Rs. 67.50
C.Rs. 86.50
D.Rs. 94.50
Answer: D.Rs. 94.50
Explanation: Solution
Let length = (3x) metres and breadth = (4x) metres.
Then, 3x × 4x = 8748 ⇔ 12x2 = 8748 ⇔ x2 = 729 ⇔ x = 27.
So, length = 81 m and breadth = 108 m.
Perimeter = [2(81 + 108)] m = 378 m.
∴ Cost of fencing = Rs. (0.25 × 378) = Rs. 94.50. Answer D
Question: Water boils at 212°F or 100°C and melts at 32°F or 0°C . If the temparature of the particular day is 35°C , it is equal to :
A.85Â°F
B.95Â°F
C.96Â°F
D.97Â°F
Answer: B.95Â°F
Explanation: Explanation:
Let F and C denotes the temparature in Fahrenheit anid Celcsius respectively.
Then, (F - 32) /(212 - 32) = (C - 0)/(100 - 0), if c = 35, then F = 95.
Answer: B
Question: In a garden, trees are planted in rows. In each row there are as many trees as the number of rows in the garden. Each tree bears as many fruits as the number of trees in each row, and each fruit has as many seeds as the number of trees in each row. If the total number of seeds from the trees in that garden is n, then :
A.n is a perfect square
B.n is an odd number
C.n is an even number
D.n is a perfect cube.
Answer: A.n is a perfect square
Explanation: If there were 4 rows of trees, each row would have 4 trees, each tree would have 4 fruits, and each fruits would have 4 seeds. The total seeds are 4*4*4*4=256. 256 is a square of 16.
Answer: A
Question: A train 110 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
A.7 sec
B.6 sec
C.4 sec
D.2 sec
Answer: B.6 sec
Explanation: Speed of train relative to man = 60 + 6 = 66 km/hr.
= 66 * 5/18 = 55/3 m/sec.
Time taken to pass the men = 110 * 3/55 = 6 sec.
Answer: B
Question: A, B, C, D, E, F, G, and H are all integers, listed in order of increasing size. When these numbers are arranged on a number line, the distance between any two consecutive numbers is constant. If G and H are equal to 5^12 and 5^15, respectively, what is the value of A?
A.-24(5^12)
B.-25(5^12)
C.-24(5^6)
D.23(5^12)
Answer: B.-25(5^12)
Explanation: Ans : B
Assume that the numbers appear as shown below on the number line
A-----B-----C-----D-----E-----F-----G-----H
(5^12) (5^13)
As the values for G and H are given , we can calculate the difference between any two terms of the series .
Common Difference ,d = (5^13) - (5^12)
= (5^12) *[ 5-1 ]
= (5^12)*(4)
Also F + d = G as the terms are in equidistant and in increasing order.
So F + (5^12)*(4) = (5^12).
That is , F = (5^12) - (5^12)*(4)
= (5^12)[ 1-4]
= (5^12) (-3)
Similarly , E = F - d
= (5^12)[-3-4]
= (5^12)*(-7)
You can see a -4 getting added to the non-exponent part of the values . That is , according to the pattern , D SHOULD BE (5^12)*(-7-4)= (5^12)*(-11)
Following this pattern , A = (5^12)*(-25)
B
Question: How many positive factors do 160 and 96 have in common?
A.6
B.12
C.16
D.18
Answer: A.6
Explanation: The number of common factors will be same as number of factors of the Highest Common Factor(HCF)
HCF of 160 and 96 is 32
Number of factors of 32 = 6
Answer :A
Question: 13 ltr of water is added with 11 ltr of a solution containing 16%of alcohol in the water. The %of alcohol in the new mixture is?
A.7.33%
B.9%
C.9.67%
D.11%
Answer: A.7.33%
Explanation: We have an 11 litre solution containing 16% of alcohol in the water.
=> Quantity of alcohol in the solution
=11Ã—16/ 100
Now 13 litre of water is added to the solution.
=> Total quantity of the new solution = 11 + 13 = 24
Percentage of alcohol in the new solution
=11Ã—16/100
24
Ã—
100
=11Ã—1610024Ã—100
=11Ã—0.67/100
=7.33%
A
Question: In how many ways T can the crew of a ten oared boat be arranged ,when of the ten persons available, 2 of whom can row only on the bow side and 3 of whom can row only on the stroke side?
A.1. 10!/(2! * 3!)
B.2. 10!/(8! * 7!)
C.3. 5!/(3! * 2!)
D.4. (5!)^3/(3! * 2!)
Answer: D.4. (5!)^3/(3! * 2!)
Explanation: Ans is D.
Going by the assumtion that both the Bow side and Stroke side will have 5 person each.
Five(3+2) of them had allready been selected(according to their preference), so from the remaining 5 we have to select 2 for the stroke side or 3 for the bow side.
and the 5 crew of each side can be arranged in 5! ways.T
Hence answer is 5C3 * 5! * 5!= (5!)^3/ 3!2!.D
Question: The number of new words that can be formed by rearranging the letters of the word 'IS' is?
A.6
B.7
C.4
D.1
Answer: D.1
Explanation: Number of words which can be formed
= 2! - 1 = 2 - 1
= 1.
Answer:D
Question: The captain of a cricket team of 11 members is 25 years old and the wicket keeper is 5 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
A.20
B.21
C.23
D.25
Answer: C.23
Explanation: Let the average age of the whole team be x years.
11x - (25 + 30) = 9 (x - 1)
11x - 9x = 46
2x = 46
x = 23.
The average age of the team is 23 years.
The answer is C.
Question: When a producer allows 36% commission on retail price of his product, he earns a profit of 8.8%. what would be his profit % if the commision is reduced by 24%?
A.49.6%
B.49%
C.50%
D.48.6%
Answer: A.49.6%
Explanation: Let the retail price =Rs 100.then, commission=Rs 36
S.P=Rs(100-36)=Rs 64
But, profit=8.8%
C.P=Rs(100/108.8*64)=Rs 1000/17
New commission =Rs12. New S.P=Rs(100-12)Rs 88
Gain=Rs(88-1000/17)=Rs 496/17
Gain%=(496/17*17/1000*100)%=49.6%
Answer is A.
Question: A certain company charges $20 per package to ship packages weighing less than 5 pounds each. For a package weighing 5 pounds or more, the company charges an initial fee of $20 plus $5 per pound. If the company charged $65 to ship a certain package, which of the following was the weight of the package, in pounds?
A.13
B.15
C.17
D.19
Answer: A.13
Explanation: Let the weight of the package be X. Then the cost is 5*X + 20= 85 ---> 5X=65 ---> X=13
Answer : A
Question: If –6 and 3 are the solutions to the equation x^2 + bx + c = 0, where b and c are constants, what is the value of b + c?
A.–18
B.–15
C.–3
D.3
Answer: B.–15
Explanation: –6 and 3 are the solutions to the equation x^2 + bx + c = 0
= x^2 + bx + c = (x+6)(x-3) -> x^2+3x-18
we get b=3 and c=-18 ->b+c=3+(-18)=-15
ANSWER:B
Question: In an election contested by two parties, Party A secured 14% of the total votes more than Party B. If party B got 140,000 votes, by how many votes did it lose the election?
A.14,000
B.36,279
C.164,000
D.242,000
Answer: B.36,279
Explanation: A + B = 100 ---- (1)
A - B = 14 ---- (2)
Solving (1) and (2) A = 57% and B = 43%
43% of Total = 140000
Total = 316279
A = 176279
Difference = 176279 - 140000 = 36279
Answer: B
Question: In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 46, the dividend is:
A.5330
B.5336
C.5343
D.5345
Answer: B.5336
Explanation: Divisor = (5 * 46) = 230
= 10 * Quotient = Divisor
=> Quotient = 230/10 = 23
Dividend = (Divisor * Quotient) + Remainder
Dividend = (230 * 23) + 46 = 5336.
B
Question: A furniture dealer purchased a desk for $150 and then set the selling price equal to the purchase price plus a markup that was 50% of the selling price. If the dealer sold the desk at the selling price, what was the amount of the dealer's gross profit from the purchase and the sale of the desk?
A.60%
B.70%
C.100%
D.90%
Answer: C.100%
Explanation: Anyway, in this question, there is no discount but the mark up is given as 50% of the selling price. So it is not 50% of $150 but instead, 50% of Selling price which is obtained by adding mark up to $150.
So if selling price is S,
150 + 50% of S = S
S = 300
Profit = 150 which is calculated on cost price in % terms. So 150/150 * 100 = 100% is profit.
C
Question: Tommy's seafood restaurant gets a delivery of fresh seafood every day, 7 days per week, and her delivery company charges her dollars per delivery plus cents per item delivered. If lst week Sarah's seafood restaurant had an average of x items per day delivered, then which of the following is the total cost, in dollars, of last week's deliveries ?
A.7cdx/100
B.d + 7cx/100
C.7d + xc/100
D.7d + 7xc/100
Answer: D.7d + 7xc/100
Explanation: Answer is D. direct question.
Question: There is a 30% chance that Tigers will not win at all during the whole season. There is a 30% chance that Portugeese will not play at all in the whole season. What is the greatest possible probability that the Tigers will win and Portugeese will play during the season?
A. 55%
B. 60%
C. 70%
D. 72%
Answer: C. 70%
Explanation: There is a 30% chance that Tigers will not win at all during the whole season
We can infer that there is 70% chance Tigers will win .
Similarly There is a 30% chance that Portugeese will not play at all in the whole season
We can also infer that there is 70% chance that Portugeese will play.
Answer C
Question: Which of the following is closest to (3!-2!)/(3!+2!)?
A.0.01
B.0.1
C.0.2
D.0.5
Answer: D.0.5
Explanation: (3!-2!)/(3!+2!)
2! (3-1)/2! (3+1)
2/4 = 0.5
D is the answer