RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A team won 40 percent of its first 30 games in a particular season, and 80 percent of its remaining games. If the team won a total of 70 percent of its games that season, what was the total number of games that the team played?
A.60
B.90
C.120
D.150
Answer: C.120
Explanation: 70% is 30%-points above 40% and 10%-points below 80%.
Thus the ratio of "the first 30 games" to "remaining games" is 1:3.
So the team played a total of 30+90 = 120 games.
The answer is C.
Question: A specialized type of sand consists of 40% mineral X by volume and 60% mineral Y by volume. If mineral X weighs 2.5 grams per cubic centimeter and mineral Y weighs 4 grams per cubic centimeter, how many grams does a cubic meter of specialized sand combination weigh? (1 meter = 100 centimeters)
A.3,400,000
B.2,800,000
C.55,000
D.28,000
Answer: A.3,400,000
Explanation: Let the volume be 1 m^3 = 1m * 1m * 1m = 100cm * 100cm * 100cm = 1,000,000 cm^3
By volume
40% is X = 400,000 cm^3
60% is Y = 600,000 cm^3
By weight,
In 1 cm^3, X is 2.5 gms
In 400,000 cm^3 , X = 2.5 * 400,000 = 1,000,000 grams
In 1 cm^3, Y is 4 gms
In 600,000 cm^3, Y = 4 * 600,000 = 2,400,000 gms
Total gms in 1 m^3 = 1,000,000 + 2,400,000 = 3,400,000
ANSWER:A
Question: A man purchased 3 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
A.450
B.992
C.276
D.187
Answer: A.450
Explanation: 10 * 150 = 1500
3 * 100 + 5 * 150 = 1050
1500 – 1050 = 450
Answer: A
Question: If x is Negative integer ,y is positive integer, and 7x+3y=14 , which of the following could be the value of x ?
A.-1
B.-5
C.-2
D.-3
Answer: A.-1
Explanation: Use answer options to solve this problem -
x is negative integer (-1,-2,-3......)
put x=-1
7x+3y=14
7(-1)+3y=14
-7+3y=14
3y=14+7
3y=21
y=7
Answer will be (A)
Question: The length of a rectangular plot is 10 meters more than its width. If the cost of fencing the plot at $15.50 per meter is $930, what is the length of the plot in meters?
A.23
B.20
C.28
D.11
Answer: B.20
Explanation: perimeter = 2L + 2W = 2L + 2(L-10) = 4L - 20
cost of fencing = (4L - 20) * 15.50 = 62L - 310 = 930
62L = 1240
L = 20 meters
The answer is B.
Question: If the area of a circle is 25pi square feet, find its circumference.
A.10 pi feet
B.28 pi feet
C.38 pi feet
D.48 pi feet
Answer: A.10 pi feet
Explanation: The area is given by pi *r* r. Hence
pi * r *r = 25 pi
r * r = 25 ; hence r = 25 feet
The circumference is given by
2 * pi * r = 2 * pi * 5 = 10 pi feet
correct answer A
Question: What is the dividend. divisor 17, the quotient is 8 and the remainder is 5
A.A)145
B.B)141
C.C)150
D.D)153
Answer: B.B)141
Explanation: D = d * Q + R
D = 17 * 8 + 5
D = 136 + 5
D = 141
Answer : B
Question: How many two-digit integers exist such that all their digits are odd?
A.80
B.25
C.120
D.125
Answer: B.25
Explanation: so last digit can be filled in 5 ways- 1,3,5,7,9
there are 5 possibilities. The answer is 5∗5=25
The correct answer is B
Question: The true discount on Rs.1600 due to after a certain of 5% per annum is Rs.160. The time after which it is due is
A.27months
B.23months
C.20months
D.12months
Answer: A.27months
Explanation: Explanation:
P.W. = Rs. (1600 - 160) = Rs. 1440
∴ S.I. on Rs.1440 at 5% is Rs. 160.
∴ Time = [100 × 160/1440 × 5] = 20/9 years = [20/9 × 12] months = 27 months.
Answer: A
Question: A shopkeeper sold sarees at Rs. 266 each after giving 5% discout on labelled price. Had he not given the discount, he would have earned a profit of 12% on the cost price. What was the cost price of each saree?
A.240
B.250
C.260
D.270
Answer: B.250
Explanation: Sol.
S.P. of 1 saree = Rs.266. Let the labelled price of each saree be Rs. x.
Then, 95/100x = 266 ⇒ x = Rs. [266*100]/95 = Rs. 280.
New, S.P. = Rs. 280, Profit = 12%.
∴ C.P. of 1 saree = Rs. [100/112 * 280] = Rs. 250.
Answer B
Question: Pipes A and B can fill a tank in 6 and 3 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
A.2 2/5 hours.
B.3 2/5 hours.
C.1 1/5 hours.
D.4 2/5 hours.
Answer: A.2 2/5 hours.
Explanation: Explanation:
Pipes A and B can fill the tank in 5 and 6 hours respectively. Therefore,
part filled by pipe A in 1 hour =1/6
part filled by pipe B in 1 hour = 1/3
Pipe C can empty the tank in 11 hours. Therefore,
part emptied by pipe C in 1 hour =1/12
Net part filled by Pipes A,B,C together in 1 hour
=1/6+1/3-1/12=5/12
i.e., the tank can be filled in 12//5=2 2/5 hours.
Answer: Option A
Question: Of the 13 employees in a certain department, 1 has an annual salary of 38,000, 2 have an annual salary of 45,900 each, 2 have an annual salary of 42,500 each, 3 have an annual salary of 40,000 each and 5 have an annual salary of 48,500 each. What is the median annual salary for the 13 employees?
A.38,000
B.40,000
C.42,500
D.45,900
Answer: D.45,900
Explanation: Median is just the value in the middle when you arrange all values in the ascending order
In this question, the 7th value would be the median (Since there are 13 employees)
38, 40, 40, 40, 42.5, 42.5,45.9
So, answer is D.
Question: Observe the dots on a dice (one to six dots) in the following figures. How many dots are contained on the face opposite to that containing four dots?
A.2
B.6
C.7
D.8
Answer: A.2
Explanation: Explanation:
We shall assume the dice in fig. (ii) to be rotated so that the 5 dots appear at the same position as in fig. (i) i.e. on RHS face (i.e. on face II as per activity 1) and 1 dot appears at the same position as in fig; (i) i.e. on Front face (i.e. on face I). Then, from the, two figures, 2 dots appear on the top face (i.e. on face V) and 4 dots appear on the Bottom face (i.e. on face VI).
Since, these two faces are opposite to each other, therefore, two dots are contained on the face opposite to that containing four dots.
Answer: A) 2
Question: When the integer n is divided by 17, the quotient is x and the remainder is 5. When n is divided by 23, the quotient is y and the remainder is 16. Which of the following is true?
A. 23x + 17y =19
B. 17x –23y = 11
C. 17x +23y =19
D. 14x + 5y = 6
Answer: B. 17x –23y = 11
Explanation: From the problem it follows:
n=17x+5
n=23y+16
So, 17x+5=23y+16
17x-23y=11
The answer is B
Question: 1, 8, 27, 64, 125, ?
A.216
B.205
C.200
D.250
Answer: A.216
Explanation: The sequence is a series of cubes, 1, 8, 27, 64, 125, 216....
Answer : A.
Question: The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is:
A.152600m2
B.153500m2
C.153600m2
D.153800m2
Answer: C.153600m2
Explanation: Explanation:
Question seems to be typical, but trust me it is too easy to solve, before solving this, lets analyse how we can solve this.
We are having speed and time so we can calculate the distance or perimeter in this question.
Then by applying the formula of perimeter of rectangle we can get value of length and breadth, So finally can get the area. Lets solve it:
Perimeter = Distance travelled in 8 minutes,
=> Perimeter = 12000/60 * 8 = 1600 meter. [because Distance = Speed * Time]
As per question length is 3x and width is 2x
We know perimeter of rectangle is 2(L+B)
So, 2(3x+2x) = 1600
=> x = 160
So Length = 160*3 = 480 meter
and Width = 160*2 = 320 meter
Finally, Area = length * breadth
= 480 * 320 = 153600
Answer: Option C
Question: A forest consists of 4 elms, 6 red woods, and 5 birches In how many ways can 2 elms, 2 red woods and 2 birches be selected from the given group?
A.987 ways
B.346 ways
C.5400 ways
D.157 ways
Answer: C.5400 ways
Explanation: The number of ways of selecting two elms, two red woods and two birches is:
= ⁴C₂ * ⁶C₂ * ⁵C₂
= (4 * 3 * 2)/(2 * 1) * (6 * 5)/(2 * 1) * (5 * 4 * 3)/(2 * 1)
= 12 * 15 * 30
= 5400 ways.
Answer: C
Question: A committee of 6 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed?
A.635
B.700
C.1404
D.2620
Answer: B.700
Explanation: The only cases possible are :
1. 2 men and 4 women : 8C2 * 5C4 = 140
2. 3 men and 3 women: 8C3*5C3 = 560
Rest of the cases will either have 1 or 0 men (not allowed) or will have 1 or 2 or 0 women (not allowed)
Total possible combinations = 140+560 = 700. Thus B is the correct answer.
Question: A box contains 100 balls, numbered from 1 to 100. If 3 balls are selected at random and with replacement from the box. If the 3 numbers on the balls selected contain two odd and one even. What is the probability J that the first ball picked up is odd numbered?
A.	0
B.	1/3
C.	1/2
D.	2/3
Answer: D.	2/3
Explanation: Answer-D
Selecting the balls either Even or Odd is having probability 50/100=1/2
We have already selected 3 balls with 2 odd numbers and 1 even number.
So we have 3 combinations OOE, OEO, EOO. We have 3 outcomes and 2 are favourable as in 2 cases 1st number is odd. So probability J is 2/3.D
Question: A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:
A.100
B.378
C.777
D.299
Answer: A.100
Explanation: Explanation:
When B runs 25 m, A runs \inline \fn_jvn {\color{Black} \frac{45}{2}} m
When B runs 1000 m, A runs \inline \fn_jvn {\color{Black} \left ( \frac{45}{2}\times \frac{1}{25}\times 1000 \right )}m = 900 m.
\inline \fn_jvn {\color{Black} \therefore }B beats A by 100 m.
Answer: A) 100 m
Question: The age of a father is 5/2 of his daughter. 5 years ago it was 3 times that of his daughter.what is daughter's present age?
A.20 YRS
B.25 YRS
C.15 YRS
D.10 YRS
Answer: A.20 YRS
Explanation: daughter's present age is x
father's present age is (5/2)*x
5 years ago father's age is (5x/2)-5=3(x-5)
Therefore,x=20 years
ANSWER:A
Question: In day before Yesterday it was Monday, What day will fall on day after tomorrow ?
A.Sunday
B.Tuesday
C.Saturday
D.Friday
Answer: D.Friday
Explanation: if day before yesterday was Monday then today is Wednesday
if today is wednesday then day after tommorrow will be Friday
ANSWER:D
Question: At 9 am a car (A) began a journey from a point, traveling at 40 mph. At 10 am another car (B) started traveling from the same point at 60 mph in the same direction as car (A). At what time will car B pass car A?
A.12p.m.
B.1p.m.
C.2p.m.
D.3p.m.
Answer: A.12p.m.
Explanation: If x hours have elapsed since 9AM:
A has traveled 40x
B has traveled 60(x - 1)
60(x - 1) = 40x
60x - 60 = 40x
60x - 40x = 60
20x = 60
x = 60/20
x = 3
ans: 9+3= 12p.m.
ANSWER:A
Question: If two dice are thrown simultaneously, then find the probability that the sum of numbers appeared on the dice is 2?
A.5/6
B.7/36
C.5/36
D.1/36
Answer: D.1/36
Explanation: The sum of numbers appeared is 2.
Therefore, the required probability = n(E)/n(S) = 1/36.
ANSWER:D
Question: On Monday, a certain animal shelter housed 72 cats and dogs. By Friday, 1/6 of the cats and 1/5 of the dogs had been adopted; no new cats or dogs were brought to the shelter during this period. What is the greatest possible number of pets that could have been adopted from the animal shelter between Monday and Friday?
A.11
B.12
C.13
D.14
Answer: D.14
Explanation: To maximize the number of pets adopted, we should maximize the number of dogs adopted since 1/5 > 1/6.
The greatest multiple of 5 less than 72 is 60 (such that the remaining number is divisible by 6), so let's assume there were 60 dogs and 12 cats.
Then the maximum number of adopted pets is 1/5*(60) + 1/6*(12) = 12 + 2 = 14.
The answer is D.
Question: When a merchant imported a certain item, she paid a 7 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that the merchant paid was $110.60, what was the total value of the item?
A.$2160
B.$2370
C.$2580
D.$2790
Answer: C.$2580
Explanation: Let x be the value of the item.
0.07*(x-1000) = 110.60
x = 2580
The answer is C.
Question: The roots of the equation ax2 + bx + c = 0 will be reciprocal if:
A.a = b,
B.a = bc,
C.c = a,
D.c = b
Answer: C.c = a,
Explanation: Solution:
Let k be one of the root of the given equation.
According to the problem,
1/k will be the other root of the given equation.
We know that, product of the roots of the equation = c/a.
Therefore, k × 1/k = c/a.
or, 1 = c/a.
or, a = c [multiplying a on both sides].
The roots of the equation ax2 + bx + c = 0 will be reciprocal if a = c.
Therefore, a = c or c = a.
Answer: C
Question: When positive integer t is divided by 13, the remainder is 2. When n is divided by 8, the remainder is 5. How many such values are less than 180?
A. 0
B. 1
C. 2
D. 3
Answer: B. 1
Explanation: the equation that can be formed t is 13x+2=8y+5..
13x-3=8y...
as we can see x can take only odd values as the RHS will always be even..
Also x can take values till 13 as 13*14>180..
now we have to substitue x as 1,3,5,7,9,11,13...
once we find 7 fitting in , any other value need not be checked as every 4th value will give us answer so next value will be 15..
ans 1.. B
Question: Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 8, while all other numbers remain the same, what is the new average of Set S?
A.6.6
B.6.7
C.6.8
D.7.0
Answer: D.7.0
Explanation: Old set S - Total is avg * no of elements = 6.2*10 = 62
If one number is increased by 8 then total increased to 62+8=70
New avg - 70/10 = 7.0.
Hence answer is D.
Question: 0---:-|---:--|-:--:-|--:---|-:----1
On the number line above, the segment from 0 to 1 has been divided into fifths, as indicated by the large tick marks, and also into sevenths, as indicated by the small tick marks. What is the LEAST possible distance Q between any two of the tick marks?
A.1/70
B.1/35
C.2/35
D.1/12
Answer: B.1/35
Explanation: divisions are 0 1/7 2/7 3/7 4/7 5/7 6/7 1
1/5 2/5 3/5 4/5 5/5
expressing the same in terms of the lcm of 5,7 ,i.e 35
0 7/35 14/35 21/35 28/35 35/35
5/35 10/35 15/35 20/35 25/35 30/35
by comparing the divisions with each other we can see 1/35 is the shortest possible distance between any two selected divisions.
Q=1/35
Answer is B.
Question: AZ + CD = AAA, where AZ and CD are two-digit numbers and AAA is a three digit number; A, Z, C, and D are distinct positive integers. In the addition problem above, what is the value of C?
A. 1
B. 3
C. 7
D. 9
Answer: D. 9
Explanation: Since AZ and CD are two-digit integers, their sum can give us only one three digit integer of a kind of AAA: 111.
So, A=1 and we have 1Z+CD=111
Now, C can not be less than 9, because no two-digit integer with first digit 1 (1Z<20) can be added to two-digit integer less than 90, so that to have the sum 111 (if CD<90, so if C<9, CD+1Z<111).
Hence C=9.
Answer: D.
Question: The weights of three boys are in the ratio 4 : 5 : 6. If the sum of the weights of the heaviest and the lightest boy is 48 kg more than the weight of the third boy, what is the weight of the lightest boy?
A.87 kg
B.38.4 kg
C.98.4kg
D.65.4 kg
Answer: B.38.4 kg
Explanation: Let the weights of the three boys be 4k, 5k and 6k respectively.
4k + 6k = 5k + 48
=> 5k = 48 => k = 9.6
Therefore the weight of the lightest boy
= 4k = 4(9.6) = 38.4 kg.
Answer:B
Question: A container holding 9 ounces of a solution that is 1 part alcohol to 2 parts water is added to a container holding 8 ounces of a solution that is 1 part alcohol to 3 parts water. What is the ratio of alcohol to water in the resulting solution?
A.2:5
B.3:7
C.3: 5
D.5:12
Answer: D.5:12
Explanation: Container 1 has 9 ounces in the ratio 1:2
or,
x+2x=9 gives x(alcohol)=3 and remaining water =6
container 2 has 8 ounces in the ratio 1:3
or,
x+3x=8 gives x(alcohol)=2 and remaining water =6
mixing both we have alcohol=3+2 and water =6+6
ratio thus alcohol/water =5/12
Answer D
Question: A fruit seller sells mangoes at the rate of Rs.12 per kg and thereby loses 15%. At what price per kg, he should have sold them to make a profit of 5%
A.Rs 8.82
B.Rs 9.82
C.Rs 10.82
D.Rs 14.82
Answer: D.Rs 14.82
Explanation: Explanation:
85 : 12 = 105 : x
x= (12×105/85)
= Rs 14.82
Option D
Question: Difference between the length &breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is?? We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103?
A.2500 m^2
B.25
C.2520 metre sq
D.2540 m^2
Answer: C.2520 metre sq
Explanation: Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) m2 = 2520 m ^2
C
Question: How many numbers from 15 to 65 are exactly divisible by 5?
A.5
B.7
C.9
D.10
Answer: D.10
Explanation: Option 'D'
15/5 = 3 and 65/5 = 13 ==> 13-3 = 10 Numbers
Question: Find Unit digit of(7^71*6^59*3^65)
A.18
B.55
C.66
D.4
Answer: D.4
Explanation: Explanation:
Unit digit of 7^71 is 3
Unit digit of 6^59 is 6
Unit digit of 3^65 is 3
Unit digit of(7^71*6^59*3^65)=(3*6*3)=4.
D
Question: 3 buffaloes eat as much as 4 cows or 2 oxen. At a farm there are 15 buffaloes, 8 oxen and 24 cows. The fodder for these cattle is available for 24days. If 8 more cows & 9 more buffaloes are brought in, how long will the fodder last?
A.8
B.10
C.12
D.18
Answer: D.18
Explanation: Sol. 2 oxen = 3 buffaloes = 4 cows 8 oxen = 16 cows and 15 buffaloes = 20 cows 16 cows + 20 cows + 24 cows = 60 cows Since fodder is available for 60 cows for 24 days
So fodder will be available for (60 + 8 + 12) = 80 cows c 24x60 .0 .
for-^—=18 days.
D
Question: A train 500m long takes 10 sec to cross a man walking at 6 kmph in a direction opposite to that of the train. Find the speed of the train?
A.A)175kmph
B.B)150kmph
C.C)162kmph
D.D)176kmph
Answer: D.D)176kmph
Explanation: Let the speed of the train be x kmph
Speed of the train relative to man = x+6 = (x+6)*5/18 m/sec
500/[(x+6)*5/18] = 10
10(x+6) = 1800
x = 176kmph
Answer is D
Question: For a light that has an intensity of 60 candles at its source, the intensity in candles, S, of the light at a point d d feet from the source is given by the formula S=60k/d^2 60, where k is a constant. If the intensity of the light is 40 candles at a distance of 3 feet from the source, what is the intensity of the light at a distance of 20 feet from the source?
A.3/10 candles
B.9/10 candles
C.1 1/3 candles
D.2 candles
Answer: B.9/10 candles
Explanation: S= 60k/d^2
At 3 feet
40 = 60k/9 so k = 6
At 20 feet
S = 60 *6/20^2 = 9/10
B
Question: A boat goes 100 km downstream in 4 hours, and 75 Km upstream in 15 hours. The speed of the stream is?
A.10
B.20
C.25
D.35
Answer: A.10
Explanation: 100 --- 10 DS = 25
? ---- 1
75 ---- 15 US = 5
? ----- 1 S = (25 - 5)/2
= 10 kmph.
Answer:A
Question: P and Q started a business investing Rs. 85,000 and Rs. 35,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively?
A.17:6
B.17:0
C.17:7
D.17:2
Answer: C.17:7
Explanation: P:Q = 85000 : 35000
= 17:7.
Answer: C
Question: A dice has one of the first 6 prime number on each its six sides ,with no two sides having the same number .the dice is rolled 10 times and the results added.the addition is most likely to be closet to
A.41
B.48
C.60
D.68
Answer: D.68
Explanation: if die is rolled then avg score = (2+3+5+7+11+13 )/6 = 41/6
so, most likely sum for 10 times = 41/6 * 10 = 68
ANSWER:D
Question: How much time will it take for an amount of 1800 to yield 81 as interest at 4.5% per annum of simple interest?
A.3 years
B.4 years
C.2 years
D.1 years
Answer: D.1 years
Explanation: Time = (100 x 81)/(1800 x 4.5) years = 1 years.
answer D
Question: In how many ways can the letters of the word 'LEADER' be arranged?
A.360
B.450
C.455
D.375
Answer: A.360
Explanation: The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.
Req = 6!/1!2!1!1!1! = 360
ANSWER A
Question: A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 350. Find the total worth of the stock?
A.20029
B.20000
C.20289
D.17500
Answer: D.17500
Explanation: Let the total worth of the stock be Rs. x.
The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50
The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50
Total SP = 11x/50 + 38x/50 = 49x/50
Overall loss = x - 49x/50 = x/50
x/50 = 350 => x = 17500
Answer: D
Question: If n = 2×3×5×7×11×13×19, then which of the following statements must be true?
I. n^2 is divisible by 600
II. n + 19 is divisible by 19
III. (n + 4)/2 is even
A.I only
B.II only
C.III only
D.I and III
Answer: B.II only
Explanation: Statement I: 600 = (2^3)*(3)*(5^2) this is NOT true.
Statement 2 Since n is divisible by 19 so n+19 is also divisible by 19. So this is true.
Statement 3: (n+4)/2 = n/2 + 2
So, ODD + 2 cannot be even.
So this is NOT true.
Hence option (B).
Question: From the set of numbers {p, t, u, v, w, x, y, z}, how many different combinations can we have without the t, the x, or the u in them? Ex:. (x,y), (x), (w,z,y,x), etc... and note that (x,y)=(y,x)
A.8
B.15
C.16
D.31
Answer: D.31
Explanation: Any letter (p, v, w, y, z) can be included or not.
Thus there are 2^5 combinations - 1 empty combination = 31 combinations
The answer is D.
Question: An air-conditioning unit costs $470. On December there was a discount for Christmas of 16%. Six months later, the holiday season was over so the company raised the price of the air-conditioning by 10%. How much will an air-conditioning unit cost in November?
A.$434
B.$470
C.$472
D.$484
Answer: A.$434
Explanation: if its previous November(before discount) then price is $470.
but if its November of next year then
16% discount on $470=470(1-16/100)=$394.8
again a corrected raised price of 10% over $394.8=394.8(1+10/100)=434.28~$434
Ans A
Question: A basket contains Rs 216 in the form of one rupee, 50 paise and 25 paise coins in the ratio of 3 : 4 : 4. The number of 50 paise coins is ?
A.96
B.128
C.144
D.100
Answer: C.144
Explanation: Let number of one rupee coins = 3K
Number of 50 paise coins = 4K
Number of 25 paise coins = 4K
Therefore 3K + 0.50 x 4K + 0.25 × 4K = 216
=> 3K + 2K + 1K = 216
=> K = 36
Therefore number of 50 paise coins = 4K = 144
ANSWER:C
Question: Jerry’s average (arithmetic mean) score on the first 3 of 4 tests is 90. If Jerry wants to raise his average by 2 points, what score must he earn on the fourth test?
A.87
B.89
C.90
D.98
Answer: D.98
Explanation: Total score on 3 tests = 90*3 = 270
Jerry wants the average to be = 92
Hence total score on 4 tests should be = 92*4 = 368
Score required on the fourth test = 368 - 270 = 98
Option D
Question: The greatest number that divides 60 and 190 leaving remainder 6 and 10 respectively is:
A.15
B.18
C.19
D.22
Answer: B.18
Explanation: explanation:
60-6= 54 ,190-10= 180
Highest number that divides 54 and 180 is HCF of numbers
HCF of 54 nad 180= 18
Answer:B
Question: 3 buffaloes eat as much as 4 cows or 2 oxen. At a farm, there are 15 buffaloes, 8 oxen, and 24 cows. The fodder for these cattle is available for 48 days. If 60 more cows and 30 more buffaloes are brought in, how many days will the fodder last?
A.15 days
B.18 days
C.21 days
D.24 days
Answer: B.18 days
Explanation: 2 oxen = 3 buffaloes = 4 cows
Also: 15 buffaloes + 8 oxen + 24 cows
= 10 oxen + 8 oxen + 12 oxen = 30 oxen
There is enough fodder for 1 oxen for 30*48 days.
60 cows + 30 buffaloes = 30 oxen + 20 oxen = 50 oxen
The new total is equal to 80 oxen instead of 30 oxen.
30*48 / 80 oxen = 18 days
The answer is B.
Question: The unit digit in the product (722 * 774 * 889 * 223) is:
A.2
B.7
C.6
D.8
Answer: C.6
Explanation: Explanation:
Unit digit in the given product = Unit Digit in (2*4*9*3) = 6
ANSWER: C
Question: After playing 40 games, the Lesley basketball team had won 50% of the games. The additional games played gave the team a 20% total winning average. How many additional games must the team have won to obtain this average?
A.2
B.15
C.7
D.10
Answer: B.15
Explanation: Explanation: Identify the parts, set up equation, and solve.
Number of games initially won by the team:
50% * 40 = 20
Additional games won by the team leaving a 20% average. (Let x represent the unknown number of additional games won.) Therefore, the total number of games played is 40+x, and the total number of games won is 20+x. This gives the equation as:
20%*(40+x)=20+x
Solve: Let's get rid of the percent sign
20/100*(40+x)=20+x
1/5 *(40+x)=20+x
Get rid of the fraction:
5[1/5 * (40+x)]=5(20+x)
1 * (40+x) =100+5x
40+x =100+5x
(40-100)+x = (100-100)+5x
-60+x= 5x
-60+(x-x)+5x-x
-60=4x
15 = x
Answer: B