RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: 9 friends are living in 9 different flats of an apartment. Each of them was allotted a parking spot to park their cars in the ground floor. But they used to park their cars randomly in any of the 9 parking spots. In how many ways can they park their cars so that exactly 7 people park their cars in the spots allotted to them?
A.24
B.36
C.48
D.60
Answer: B.36
Explanation: 9C7 = 36
The remaining 2 people in each case will be parked in each other's parking spots.
The answer is B.
Question: Machine A can print one lakh books in 8 hours. Machine B can do the same job in 10 hours. Machine C can do the same job in 12 hours. All the three machines start job at 9.00 am. A breaks down at 11.00 am and the other two machines finish the job. Approximately at what time will the job be finished?
A.12.00 noon
B.1.30 pm
C.1.00 pm
D.11.30 am
Answer: C.1.00 pm
Explanation: Part of print done by A, B and C in 2 hours = 2(1⁄8 + 1⁄10 + 1⁄12) = 37⁄60
Remaining = 1 - 37⁄60 = 23⁄60
If B and C print together, then they can print in 10×12/10+12
Therefore, remaining part can be printed by
B and C in 10×12/22×23/60 ≈ 2 hrs.
Hence, the job will be finished at
9 am + 2 + 2 = 1.00 p.m.
Answer C
Question: A coin is tossed 5 times, Probability of getting
head exactly 3 times is:
A.0.3125
B.0.4125
C.0.5125
D.0.6125
Answer: A.0.3125
Explanation: coin tossed 5 times so 2*2*2*2*2=32
getting heads only in 3 times=HHHHH,HHHHT,HHHTT,HHTTH,HTTHH,TTHHH,THHHT,THHTH,THTHH,HTHTH=10
PROBABILITY=10/32=0.3125.
ANSWER:A
Question: In a LAB experiment, a 100 ml compound of element X and element Y needs to be increased to 150 ml by adding some quantity of element X, and some quantity of element Y. If the original compound contains 30% of element X, how much (in ml) of element Y must be added so that element X will be exactly one third of the resulting mixture ?
A.40 ml
B.100/3 ml
C.30 ml
D.20/3 ml
Answer: C.30 ml
Explanation: There are 0.3*100=30 ml of element X in the initial solution.
We need X to be 1/3rd of 150 ml in the resulting solution, so 50 ml. Thus out of 50 ml of solution added, 20 must be X (in order it to become 50 ml) ans the remaining 30 must be Y.
Answer: C
Question: A milk man makes a profit of 20% on the sale of milk. If he were to add 10% water to the milk, by what % would his profit increase?
A.30
B.40⁄3
C.22
D.10
Answer: B.40⁄3
Explanation: Let profit per litre = 20
So, C.P. /litre = 100
S.P. / litre = 120
On adding 10% water to the milk
C.P. / 9⁄10 litre = 100
S.P. / 9⁄10 litre = 120
S.P / litre = 120×10/9=400/3
⇒ Profit / litre = 400⁄3 - 100 = 33.33
% by which profit increases = 33.33 – 20 = 13.3
Answer B
Question: What least number must be added to 696, so that the sum is completely divisible by 20 ?
A.2
B.4
C.3
D.5
Answer: B.4
Explanation: If we divide 696 by 20 remainder is 16
20 - 16 =4
Answer : B
Question: The average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?
A.Rs.17
B.Rs.12
C.Rs.15
D.Rs.29
Answer: C.Rs.15
Explanation: Total members in the group = 7
Average amount = Rs. 20
Total amount with them = 7 * 20 = Rs. 140
One number has Rs. 50. So, the amount with remaining 6 people = 140 - 50 = Rs. 90
The average amount with them = 90/6
= Rs.15.
Answer:C
Question: Two right circular cylinders of equal volumes have their heights in the ratio 1:2. Find the ratio of their radii.
A.√3:1
B.√7:1
C.√2:1
D.2:1
Answer: C.√2:1
Explanation: Explanation:
Let their heights be h and 2h and radii be r and R respectively then.
πr2h=πR2(2h)
=>r2/R2 = 2h/h
=2/1
=>r/R = √2/1
=>r:R = √2:1
ANSWER IS C
Question: How many positive integers less than 15 can be expressed as the sum of a positive multiple of 2 and a positive multiple of 3?
A.14
B.13
C.12
D.8
Answer: D.8
Explanation: The number = 2a + 3b < 20
When a = 1, b = 1, 2, 3, 4, 5 -> 2a = 2; 3b = 3, 6, 9-> the number = 5, 8, 11 --> 3 numbers
when a =2, b = 1,2,3-> ....--> 3 numbers
when a =3, b = 1,2,3,4 --> ....--> 2 numbers
Total number is already 8. Look at the answer there is no number greater than 8 --> we dont need to try any more
Answer must be D
Question: If [x] is the greatest integer less than or equal to x, what is the value of [-2.6]+[1.4]+[2.7]?
A. 0
B. 1
C. 2
D. 6
Answer: A. 0
Explanation: You are asked what the closest lesser integer value to [x] is.
[-2.6] = -3.0
[1.4] = 1.0
[2.7] = 2.0
Therefore , answer is: -3.0 + 1.0 + 2.0 = 0.0
Option A.
Question: A train 125 m long passes a man, running at 4 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
A.11
B.49
C.88
D.65
Answer: B.49
Explanation: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr
= 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 4) km/hr. x - 4 = 45 ==> x
= 49 km/hr.
Answer:B
Question: What is the remainder when 1201 × 1202 ×1203 × 1204 is divided by 6?
A.0
B.1
C.2
D.3
Answer: A.0
Explanation: The remainders when dividing each number by six are: 1, 2, 3, and 4.
The product is 1*2*3*4 = 24
The remainder when dividing 24 by 6 is 0.
The answer is A.
Question: What is the perimeter of a square field whose diagonal is 8√2?
A.82 m
B.32 m
C.27 m
D.26 m
Answer: B.32 m
Explanation: 4a = 32 m
Answer: B
Question: A person buys an article at $1200. At what price should he sell the article so as to make a profit of 40%?
A.1670
B.1600
C.1680
D.1900
Answer: C.1680
Explanation: C
1680
Cost price = $1200
profit = 40% of 1200 = $480
Selling price = Cost price + Profit
= 1200 + 480 = 1680
Question: There is a sufficient food for 200 men for 20 days after 15 days 100 men leave the place. For how many days will the rest of the food last for the rest of the men?
A.10 days
B.5 days
C.15 days
D.12 days
Answer: A.10 days
Explanation: Explanation:
After 13 days , 100 men left,
Therefore 5 days*200 men =x days*100men
X = 10 days
Answer: Option A
Question: If 2^(2w) = 8^(w−4), what is the value of w?
A.3
B.6
C.9
D.12
Answer: D.12
Explanation: 2^(2w) = 8^(w−4)
2^(2w) = 2^(3*(w−4))
2^(2w) = 2^(3w-12)
Let's equate the exponents as the bases are equal.
2w = 3w-12
w = 12
The answer is D.
Question: Salesperson A's compensation for any week is $260 plus 6 percent of the portion of A's total sales above $1,000 for that week. Salesperson B's compensation for any week is 8 percent of B's total sales for that week. For what amount of total weekly sales would both salespeople earn the same compensation?
A.$6000
B.$8000
C.$10,000
D.$12,000
Answer: C.$10,000
Explanation: 260+0.06(x-1000) = 0.08x
0.02x = 200
x = $10,000
The answer is C.
Question: A man travelled a distance of 80 km in 7 hours partly on foot at the rate of 8 km per hour and partly on bicycle at 16 km per hour. Find the distance travelled on foot.
A.26 km
B.32 km
C.30 km
D.28 km
Answer: B.32 km
Explanation: Total Time = 7hrs
Let the distance travelled by foot @ 8kmph be x kms
? distance travlled by bicycle @ 16kmph be (80-x)kms
ATQ. 7hr = x/8 + (80-x)/16
? 7 = (2x + 80 - x)/16
? x = 32kms
Answer: B.
Question: Express a speed of 30 kmph in meters per second?
A.10 mps
B.8 mps
C.9 mps
D.7 mps
Answer: B.8 mps
Explanation: 30 * 5/18
= 8 mps
Answer:B
Question: Anusha, Banu and Esha run a running race of 100 meters. Anusha is the fastest followed by Banu and then Esha. Anusha, Banu and Esha maintain constant speeds during the entire race. When Anusha reached the goal post, Banu was 10m behind. When Banu reached the goal post Esha was 10m behind. How far was behind Anusha when the latter reached the goal post.
A.22
B.88
C.81
D.66
Answer: C.81
Explanation: By that time Anusha covered 100m, Bhanu covered 90m. So ratio of their speeds = 10 : 9
By that time Bhanu reached 100m, Esha covered 90m. So ratio of their speeds = 10 : 9
Ratio of the speed of all the three = 100 : 90 : 81
By that time Anusha covered 100m, Esha Covers only 81.
Answer:C
Question: n^(n/2)=2 is true when n=2 in the same way what is the value of n if n^(n/2) =12?
A.12
B.6
C.14
D.16
Answer: A.12
Explanation: n^(n/2)=12Apply logN/2logn=log12nlogn=2log12=log12^2=log144Logn=log144Now apply antilogn= 144/nNow n=12ANSWER:A
Question: A, B, K start from the same place and travel in the same direction at speeds of 30km/hr, 40km/hr, 60km/hr respectively. B starts five hours after A. If B and K overtake A at the same instant, how many hours after A did K start?
A.3
B.4.5
C.4
D.d) 10
Answer: D.d) 10
Explanation: The table you made doesn't make sense to me. All three meet at the same point means the distance they cover is the same.
We know their rates are 30, 40 and 60.
Say the time taken by B is T hrs. Then A takes 5+T hrs. And we need to find the time taken by K.
Distance covered by A = Distance covered by B
30*(5+T) = 40*T
T = 15 hrs
Distance covered by B = Distance covered by K
40*T = 60*Time taken by K
Time taken by K = 40*15/60 = 10 hrs
Time taken by A = 5+T = 5+15 = 20 hrs
Time taken by K = 10 hrs
So K starts 20-10 = 10 hrs after A. (answer D)
Question: What is the product of the greatest 2 digit multiple of 5 and the greatest 2 digit prime number?
A.9,310
B.9,408
C.9,506
D.9,603
Answer: A.9,310
Explanation: the greatest 2 digit multiple of 5: 95
the greatest 2 digit prime numebr: 97
97*98.
A)9,310
Question: If the true discount on s sum due 2 years hence at 14% per annum be Rs. 168, the sum due is ?
A.948
B.876
C.768
D.658
Answer: C.768
Explanation: P.W. = (100*T.D)/(R*T) = (100*168)/(14*2) = 600 Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768. Answer : C
Question: If taxi fares were Rs 1.00 for the first 1/5 mile and Rs 0.20 for each 1/5 miles thereafter. The taxi fare for a 3-mile ride was
A.Rs 1.56
B.Rs 2.40
C.RS 3.00
D.Rs 3.80
Answer: D.Rs 3.80
Explanation: first 1/5 mile costs = 1.00
remaining miles to be covered = 3-1/5 =14/5, =1/5 +1/5+1/5+.... until 14,
hence 14*0.20=2.80
total fare = 2.80 + 1.00 =3.80
ANSWER:D
Question: Which of the following equations has a solution in common with x^2 + 14x + 33 = 0?
A.3x^2 - 5x - 2 = 0
B.-x^2 - 3x + 28 = 0
C.-x^2 - 2x + 99 = 0
D.3x^2 + 30x + 27 = 0
Answer: C.-x^2 - 2x + 99 = 0
Explanation: Given : x^2 + 14x + 33 = 0 => (x+3) (x+11) = 0 => -3 and -11 are the roots..
A. 3x^2 - 5x - 2 = 0 => (x-2) (3x+1)
B. -x^2 - 3x + 28 = 0 => (-x+7) (x+4)
C. -x^2 - 2x + 99 = 0 => (x+11) (-x+9)
D. 3x^2 + 30x + 27 = 0 => (x+9) (3x+3)
None of the answer equations have exactly both the same roots as the question equation, but at least one of them does share one of the two roots.
So IMO "C" is correct answer... because it shares the one root (part of the solution), (-11), from the (x+11) portion of its simplification.
Question: The Q train leaves station A moving at a constant speed, and passes by stations B and C, in this order. It takes the Q train 7 hours to reach station B, and 5 additional hours to reach station C. The distance between stations A and B is m kilometers longer than the distance between stations B and C. What is the distance between stations A and C in terms of m?
A.1.8m
B.6m
C.7m
D.9m
Answer: B.6m
Explanation: The reason it is failing for you is that you chose incorrect numbers. If the question says it Q took 7 hrs to reach from A to B and 5 hrs to reach from B to C at a constant speed. It shows that distance AB and BC should be in ratio of 7/5.
If you take such numbers you can solve problem.
AB = 7, BC=5
Therefore
AB-BC = 2
But from question, AB-BC =m
=> m=2
Now total distance = AB+BC= 12
Substitute 12 to get answer in terms of m
Total distance =12 =6m
Ans B
Question: There are 16 teams divided in 4 groups. Every team from each group will play with each other once. The top 2 teams will go to the next round and so on the top two teams will play the final match. Minimum how many matches will be played in that tournament?
A.43
B.44
C.45
D.46
Answer: A.43
Explanation: In each group, total matches played = 4C24C2 = 6.
So total matches played in the first round = 6 × 4 = 24
Now top two teams from each group progress to the next round. Now these 8 teams are pooled into 2 groups. Total matches played in the second round = 6 × 2 = 12
Now 4 teams progress to the next round. Total matches played in the third round = 6
From this round, 2 teams progress to the next round. And final will be played between them.
Total matches = 24 + 12 + 6 + 1 = 43
Answer:A
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when a boy gets any no. of prizes?
A.48
B.50
C.64
D.70
Answer: C.64
Explanation: Ans.(C)
Sol. In this case, repetitions are allowed, so all the three prizes can be given in 4 ways, i.e. (4 x 4 x 4) ways = 43 ways = 64 ways Or nr ways = 43 ways = 64 ways
Question: There are 16 bees in the hive , then 8 more fly. How many bees are there in all?
A.7
B.33
C.12
D.24
Answer: D.24
Explanation: 16+8=24 . Answer is D.
Question: Two boys starts from the same place walking at the rate of 4 kmph and 5.5 kmph respectively in the same direction. What time will they take to be 10.5 km apart?
A.8
B.5
C.7
D.9
Answer: C.7
Explanation: Explanation:
Relative speed = 5.5 - 4 = 1.5 kmph (because they walk in the same direction)
distance = 10.5 km
time = distance / speed=10.5/1.5=7 hr
Answer :C
Question: A cistern 5m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:
A.49 m2
B.42.5 m2
C.53.5 m2
D.55 m2
Answer: B.42.5 m2
Explanation: Area of the wet surface	= [2(lb + bh + lh) - lb]
= 2(bh + lh) + lb
= [2 (4 x 1.25 + 5 x 1.25) + 5 x 4] m2
= 42.5 m2.
Answer: Option B
Question: The average of 10 numbers is 23. If each number is increased by 4, what will the new average be?
A.22
B.27
C.88
D.76
Answer: B.27
Explanation: Sum of the 10 numbers = 230
If each number is increased by 4, the total increase =
4 * 10 = 40
The new sum = 230 + 40 = 270 The new average = 270/10 = 27.
Answer: B
Question: If n is an integer, then the least possible value of |48 - 7n| is?
A.1
B.0
C.5
D.4
Answer: A.1
Explanation: |48 - 7n| represents the distance between 48 and 7n on the number line. Now, the distance will be minimized when 7n, which is multiple of 7, is closest to 48. Multiple of 7 which is closest to 48 is 49 (for n = 7), so the least distance is 1: |48 - 49| = 1.
Answer: A.
Question: If 24 lines are drawn in a plane such that no two of them are parallel and no three are concurrent, then in how many points do they intersect?
A.276
B.350
C.425
D.512
Answer: A.276
Explanation: If two lines are not parallel, then they will intersect in exactly one point. Lines can be extended infinitely on both ends so somewhere they will intersect with each other if they are not parallel. We are also given that no three lines are concurrent. This means that no three lines intersect at the same point. So every pair of two lines we select will have a unique point of intersection which they will not share with any third line.
The number of ways to select 2 lines from 24 lines is 24C2 = 276
The answer is A.
Question: Evaluate 100 / .25
A.400
B.510
C.500
D.None of these
Answer: A.400
Explanation: Explanation:
100/.25 = 10000/25 = 400
Option A
Question: Lindsay can paint 1/x of a certain room in one hour. If Lindsay and Joseph, working together at their respective rates, can paint the room in five hours, what fraction of the room can Joseph paint in 20 minutes?
A.1/5x
B.x/(x-3)
C.(x-5)/15x
D.x/(x-5)
Answer: C.(x-5)/15x
Explanation: Let J be Joseph's rate per hour.
1/x + J = 1/5 of a room per hour
J = 1/5 - 1/x, of a room per hour
In 20 minutes, Joseph can paint 1/3*(1/5-1/x) = 1/15-1/3x = (x-5)/15x
The answer is C.
Question: A start walking from a place at a uniform speed of 7 kmph in a particular direction. After half an hour, B starts from the same place and walks in the same direction as A at a uniform speed and overtakes A after 1 hour 48 minutes. Find the speed of B.
A.4.7 kmph
B.7.6 kmph
C.4 kmph
D.7 kmph
Answer: B.7.6 kmph
Explanation: Distance covered by A in 30 min = 1 Km
B covers extra 1km in 1 hour 48 minutes (9/5 hr)
i.e. Relative speed of B over A = 1/(9/5) = 5/9
So the speed of B = Speed of A + 5/9
= 7 + 5/9
= 7.55
Answer B
Question: The distance between Delhi and Mathura is 110 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet?
A.19
B.10
C.14
D.17
Answer: B.10
Explanation: D = 110 – 20 = 90
RS = 20 + 25 = 45
T = 90/45 = 2 hours
8 a.m. + 2 = 10 a.m.
Answer: B
Question: Baseball's World Series matches 2 teams against each other in a best-of-seven series. The first team to win four games wins the series and no subsequent games are played. If you have no special information about either of the teams, what is the probability r that the World Series will consist of fewer than 7 games?
A. 12.5%
B. 25%
C. 31.25%
D. 68.75%
Answer: D. 68.75%
Explanation: In order to determine the probability r that the World Series will last less than 7 games, we can first determine the probability that the World Series WILL last exactly 7 games and then subtract this value from 1.
In order for the World Series to last exactly 7 games, the first 6 games of the series must results in 3 wins and 3 losses for each team.
Let's analyze one way this could happen for Team 1:
Game 1 Game 2 Game 3 Game 4 Game 5 Game 6
T1 Wins T1 Wins T1 Wins T1 Loses T1 Loses T1 Loses
There are many other ways this could happen for Team 1. Using the permutation formula, there are 6!/(3!)(3!) = 20 ways for Team 1 to win 3 games and lose 3 games in the first 6 games.
Logically, there are also 20 ways for Team 2 to win 3 games and lose 3 games in the first 6 games.
Thus, there are a total of 40 ways for the World Series to last the full 7 games.
The probability that any one of these 40 ways occurs can be calculated from the fact that the probability of a team winning a game equals the probability of a team losing a game = 1/2.
Given that 7 distinct events must happen in any 7 game series, and that each of these events has a probability of 1/2, the probability that any one particular 7 game series occurs is.
Since there are 40 possible different 7 game series, the probability that the World Series will last exactly 7 games is:
Thus the probability that the World Series will last less than 7 games is 100% - 31.25% = 68.75%.
The correct answer is D.
Question: If A : B=4 : 3 and B : C = 1 : 2, then A : B : C is:
A.2:5:9
B.4:6:3
C.7:5:3
D.4:3:6
Answer: D.4:3:6
Explanation: A:B=4:3, B:C=1:2, A:B:C=4Ã—1:1Ã—3:3Ã—2
â‡’ 4:3:6
Answer: D.
Question: If x and y are positive integers such that (3x + 7y) is a multiple of 11, then which of the followings are divisible by 11?
A.9x + 4y
B.x + y + 4
C.4x - 9y
D.4x + 6y
Answer: C.4x - 9y
Explanation: Explanation :
By hit and trial method, we get x=5 and y=1 such that 3x + 7y = 15 + 7 = 22 is a multiple of 11.
Then
(4x + 6y) = (4 × 5 + 6 × 1) = 26 which is not divisible by 11
(x + y + 4) = (5 + 1 + 4) = 10 which is not divisible by 11
(9x + 4y) = (9 × 5 + 4 × 1) = 49 which is not divisible by 11
(4x - 9y) = (4 × 5 - 9 × 1) = 20 - 9 = 11 which is divisible by 11. Answer : Option C
Question: Set X consists of all the prime numbers between 10 and 25. What is the range of set X?
A.12
B.13
C.16.6
D.17
Answer: A.12
Explanation: Answer of set X is 12=X
Question: A and B complete a work in 4 days. A alone can do it in 8 days. If both together can do the work in how many days?
A.3.75 days
B.3.99 days
C.2.67 days
D.2.98 days
Answer: C.2.67 days
Explanation: 1/4 + 1/8 = 3/8
8/3 = 2.67 days
Answer: C
Question: If four coins are tossed, the probability of getting two heads and two tails is -.
A.3/8
B.4/5
C.3/7
D.2/9
Answer: A.3/8
Explanation: n(E) = six ways
p(E) = 6/2^4 = 3/8
ANSWER A
Question: A jar has 500 marbles. 46% are dark colors, and the remainder light colors. Green, blue, and purple marbles are considered dark colors, and yellow, orange, and red are considered light colors. Green and blue make up 60% of the dark marbles, and there are half as many red marbles as there are purple marbles. What percent of the light marbles are not red?
A.54.5%
B.44.1%
C.44.8%
D.54.9%
Answer: C.44.8%
Explanation: 46% of 500 = 230 dark marbles
60% of 230 = 138 green and blue marbles
230-138 = 92 purple marbles
50% of 92 = 46 red marbles
500 total - 230 dark - 46 red = 224/500 = 44.8%
Answer is C
Question: A lemonade stand sold only small and large cups of lemonade on Tuesday. 3/5 of the cups sold were small and the rest were large. If the large cups were sold for 7/12 as much as the small cups, what fraction of Tuesday's total revenue was from the sale of large cups?
A.(a) 7/16
B.(b) 7/15
C.(c) 10/21
D.(d) 7/25
Answer: D.(d) 7/25
Explanation: This problem is very good example how easy and quick plug-in method might be.
Let the total # of cups be 10.
# of small cups sold 3/5*10=6;
# of large cups sold 10-6=4;
Let the price of small cup be $6, then the price of larges cup would be 7/12*6=$7/2;
Revenue from small cups: 6*$6=$36;
Revenue from large cups cups: 4*$7/2=$14;
Fraction of total revenue from large cups: 14/(36+14)=7/25.
Answer: D.
Question: A sequence of odd integers begins at 61 and ends at 119. What is the sum of all numbers in this sequence?
A.2610
B.2700
C.2790
D.5400
Answer: B.2700
Explanation: Last Term = First Term + Common difference * (n-1)
119=61+2∗(n−1)
119=61+2n−2
58=2n−2
60=2n
n=30
Multiply 30 with the average from (61+119)/2 = 90 => 90*30 = 2700
ANSWER:B
Question: The compound ratio of 1:3, 1:2 and 1:5?
A.1:30
B.1:5
C.1:7
D.1:1
Answer: A.1:30
Explanation: 1/3 * 1/2 * 1/5 = 1/301:30Answer: A
Question: Lilly has 10 fishes, rosy has 7 fishes. Totally how many fishes they have in all?
A.3
B.10
C.6
D.17
Answer: D.17
Explanation: 10+7=17. Answer is D.
Question: Three unbased coins are tossed. the probability of getting at most two head is ?
A.1/2
B.7/8
C.3/4
D.1/5
Answer: B.7/8
Explanation: S={TTT,TTH,THT,HTT,THH,HTH,HHT,HHH}
E be the event of getting at least two head is {THH,HTH,HHT,TTT,TTH,THT,HTT}
P(E)=n(E)/n(S)=7/8
Answer(B)
Question: Pipe A can fill a tank in 3 hours, pipe B in 4 hours, and pipe C in 6 hours. If all the pipes are open, in how many hours will the tank be filled?
A.1
B.1.3
C.1.6
D.1.9
Answer: B.1.3
Explanation: The part filled by A + B + C in 1 hour is 1/3 + 1/4 + 1/6 = 3/4
All the three pipes together will fill the tank in about 1.3 hours.
The answer is B.
Question: What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20%?
A.20%
B.80%
C.29%
D.90%
Answer: A.20%
Explanation: SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Answer: A
Question: The average score of a cricketer for ten matches is 38.9 runs. if the average for the first six matches is 42, then find the average for the last four matches.
A.33.5
B.33.5
C.34.25
D.35
Answer: C.34.25
Explanation: Solution
Required average =(38.9x10)-(42x6)/4 =137/4= 34.25 Answer C
Question: The greatest number that divides 2928 and 3240 leaving remainders 5 and 1 respectively is:
A.74
B.78
C.79
D.81
Answer: C.79
Explanation: explanation:
2928-5= 2923 ,3240-1= 3239
Highest number that can divide 2923 and 3239 is HCF of numbers.
HCF of 2923 and 3239 = 79
Answer:C
Question: What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent?
A.337
B.500
C.266
D.288
Answer: B.500
Explanation: 70 = (P*4*7/2)/100
P = 500
Answer: B