RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What is the value of x^2yz − xyz^2, if x = − 2, y = 1, and z = 1?
A. 6
B. 24
C. 30
D. 32
Answer: A. 6
Explanation: 4*1*1 -(- 2*1*1)
=4+2 = 6
Ans: A
Question: What is the smallest positive integer which when increased by 1 is divisible by 22, 36, 26 and 21?
A. 7271
B. 36035
C. 122149
D. 22362621
Answer: B. 36035
Explanation: 22 = 2*11
36 = 2 * 2 * 3 * 3
26 = 2 * 13
21 = 3 * 7
So the answer is (2 * 2 * 3 * 3 * 7 * 11 * 13) - 1 = 36035, which is option B.
Question: A wall photo 2 inches wide is placed around a rectangular paper with dimensions 8 inches by 12 inches. What is the area of the wall photo, in square inches?
A.96
B.86
C.108
D.144
Answer: A.96
Explanation: This question is an example of a 'punch out' question - we have to find the area of EVERYTHING, then 'punch out' the part that we don't want.
We're told that a wall photo 2 inches wide is placed around a rectangular paper with dimensions 8 inches by 12 inches. We're asked for the area of the wall photo, in square inches.
Area of a rectangle = (length)(width)
So the area of the wall photo is... (8)(12) = 96
The wall photo 'adds' 2 inches to the top, bottom, left and right 'sides' of the picture, so the area of EVERYTHING is...
(8+2+2)(12+2+2) = (12)(16) = 196
When we 'punch out' the area of the paper, we'll be left with the area of the wall photo:
192 - 96 = 96
Final Answer:
A
Question: What was the day of the week on 17th June, 1998?
A.Sunday
B.Tuesday
C.Friday
D.Wednesday
Answer: D.Wednesday
Explanation: Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday
Answer: D) Wednesday
Question: In a class of 25 students, 3 students did not borrow any books from the library, 11 students each borrowed 1 book, 6 students each borrowed 2 books, and the rest borrowed at least 3 books. If the average number of books per student was 2, what is the maximum number of books any single student could have borrowed?
A.12
B.13
C.14
D.15
Answer: D.15
Explanation: The total number of books the students borrowed is 25*2=50.
The students who borrowed zero, one, or two books borrowed 11*1+6*2=23 books.
The 5 students who borrowed at least three books borrowed 50-23=27 books.
If 4 of these students borrowed exactly 3 books, then the maximum that one student could have borrowed is 27-12= 15 books.
The answer is D.
Question: Two trains 180m and 360m long run at the speed of 60kmph and 30kmph in opposite directions in parallel tracks. The time which they take to cross each other is?
A.21.6sec
B.8.9sec
C.10.8sec
D.12.6sec
Answer: A.21.6sec
Explanation: Relative speed = 60+30 = 90kmph * 5/18 = 25 m/s
Distance covered in crossing each other = 180+360 = 540m
Required time = 540*1/25 = 21.6 sec
Answer is A
Question: The difference between the compound interest compounded annually and simple interest for 2 years at 20% per annum is Rs.144. Find the principal?
A.2888
B.2669
C.3600
D.1279
Answer: C.3600
Explanation: P = 144(100/5)2 => P = 3600.Answer:C
Question: When positive integer g is divided by 6, the remainder is 1. Which of the following must be true?
I. g is a prime number
II. g is odd
III. g is divisible by 7
A.I only
B.II only
C.III only
D.I and II only
Answer: B.II only
Explanation: g=6q+1
Examine II) put q=0,1,2,3....... we have g=1,7,13,...25 so g must be odd
Examine III) 14/6 has reminder 249/7 has reminder 1 so not always true
Examine I) g= 7 true but while 2 is prime, it does not give reminder 1
Answer: B
Question: How many pieces of 75 cm can be cut from a rope 57 meters long?
A.30
B.40
C.76
D.None
Answer: C.76
Explanation: Explanation :
Total pieces of 75 cm that can be cut from a rope of 57 meters long is
= (57 meters)/(75 cm)
= (57 meters)/(0.75 meters)
= 76
Answer : C
Question: Each of the products produced yesterday was checked by worker x or worker y. 0.5% of the products checked by worker x are defective and 0.8% of the products checked by worker y are defective. If the total defective rate of all the products checked by worker x and worker y is 0.7%, what fraction of the products was checked by worker y?
A.2/3
B.5/6
C.7/8
D.4/5
Answer: A.2/3
Explanation: x: 0.5% is 0.2%-points from 0.7%.
y: 0.8% is 0.1%-points from 0.7%.
Therefore the ratio of products checked by y:x is 2:1.
Thus, worker y checked 2/3 of the products.
The answer is A.
Question: The salary of Charan was reduced by 10%. By what percent should his reduced salary be raised so as to bring it at par with his original salary?
A.12%
B.11.11%
C.11.5%
D.13%
Answer: B.11.11%
Explanation: Explanation :
Solution: Let the original salary be Rs. 100. new salary = Rs. 90.
Increase on 90 = 10
Increase on 100 = ?
= 10*100/90 = 11 1/9%.
Answer : B
Question: A certain college party is attended by both male and female students. The ratio of male to female students is 4 to 5. If 15 of the male students were to leave the party, the ratio would change to 1 to 2. How many total students are at the party?
A.60
B.70
C.80
D.90
Answer: D.90
Explanation: The ratio is 4:5 = 8:10, so there are 8k males and 10k females.
If 15 males left, the ratio would be 1:2 = 5:10, so there would be 5k males and 10k females.
8k-5k = 15
k = 5
8k + 10k = 40 + 50 = 90
The answer is D.
Question: The length of a cold storage is double its breadth. Its height is 3 metres. The area of its four walls(including doors) is 108 m2. Find its volume.
A.206
B.216
C.226
D.246
Answer: B.216
Explanation: let xbe breadth ,then 2x is the length
then 2x*3*2+x*3*2=108
12x+6x=108
x=108/18=6
length 12,breadth 6 ,height 3
volume=12*6*3=216m^3
ANSWER:B
Question: A can contain a mixture of two liquids A and B in the ratio 7:5 when 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many litres of liquid A was contained by the can initially?
A.28 litres
B.21 litres
C.45 litres
D.36 litres
Answer: B.21 litres
Explanation: Explanation :
Let, the can initially contains 7x and 5x litres of mixtures A and B respectively.
When 9 litres of mixture are drawn off, quantity of A in mixture left :-
=>7x−(7/12)×9=7x−(21/4) litres.
Similarly, quantity of B in mixture left:
=>5x−(5/12)×9=5x−(15/4) litres.
The ratio becomes :
=>(7x−21)/(5x−(15/4)+9)=7/9.
=>(28x−21)/(20x+21)=7/9.
=>252x−189=140x+147.
=>112x=336.
=>x=3.
Hence, the required initial amount of A is :
=>7×x=7×3=21 litres.
Answer : B
Question: A number when divided by a divisor leaves a remainder of 24. When twice the original number is divided by the same divisor, the remainder is 11. What is the value of the divisor?
A.37
B.30
C.25
D.28
Answer: A.37
Explanation: Original no be a
let divisor be d & let the quotient of the division of a by d be x
=> a/d = x and the remainder is 24
a = dx+24
when twice the original no is divided by d, 2a is divided by d
=>the problem state that (2dx + 48) / d leaves a remainder of 11
2dx is perfectly divisible by d and will not leave remainder
the remainder of 11 was obtained by dividing 48 by d
when 48 is divided by 37 the remainder that one will obtain is 11
the divisor is 37
ANSWER A
Question: Two persons , Ram & Lakshman , who are at a distance of 100 km from each other, move towards each other from two places P and Q at speeds of 20 kmph and 25 kmph respectively. Lakshman reaches P, returns immediately and meets Ram at R, who started on the return journey to P immediately after reaching Q. What is the distance between Q and R?
A.33 1/3 km
B.25 km
C.30km
D.27 1/3 km
Answer: A.33 1/3 km
Explanation: Ram takes 100/20 = 5 hours to cover the distance from P to Q. By that time Lakshman covers
covers 5 *25 = 125 km
Lakshman covers 25 km more than the distance PQ . Now the distance between them = 75 km
Time taken by them to meet = Distance/ Relative speed = 75/(20+25) = 75/45 = 5/3 hrs.
Distance between Q and R is nothing but the distance covered by Ram in 5/3 hours = 20 *5/3 = 100/3 km or 33 1/3 km
ANSWER:A
Question: If f(x) = (x^2 - 1)/(x), what is f(1/x) in terms of f(x)?
A.-1*f(x)
B.f(x)
C.1/f(x)
D.-1/f(x)
Answer: A.-1*f(x)
Explanation: f(1/x) = ((1/x)2 - 1) / ((1/x))
= ((1/x^2) - 1) / (1/x)
= ((1-x^2)/(x^2)) / (1/x
= (1-x^2)/(x^2)
= - ( (x^4) -1) / (x)
= -1* f(x)
Answer is A.
Question: Two watches are set for an alarm at 10 0'clock in the night. One watch gains 2 minutes per hour. When the faster watch shows 4:12 in the morning when the alarm rings what does the correct watch show?
A.5:00
B.4:00
C.4:10
D.5:20
Answer: B.4:00
Explanation: The faster watch gains 2 minutes per hour
The two watches show 10:00 at 10 0'clock
At 11 0'clock -
The correct watch is at 11:00
The faster watch is at 11:02 (1 hour + gains 2 minutes per hour)
At 12 midnight -
The correct watch is at 12:00
The faster watch is at 12:04 ( 2 hours + gains 4 minutes per 2 hours)
In 6 hours the faster watch gains 6*2 = 12 minutes and is at 4:12 and the correct watch is at 4:00
Answer is B
Question: The average weight of a class of 24 students is 35 kg. If the weight of the teacher be included, the average rises by 400 g. The weight of the teacher is :
A.45 kg
B.46 kg
C.47 kg
D.48 kg
Answer: A.45 kg
Explanation: Explanation:
Weight of the teacher = (35.4 x 25 - 35 x 24) kg = 45 kg. Answer: A
Question: A train 125 m long passes a man, running at 9 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
A.35 km/hr
B.50 km/hr
C.54 km/hr
D.65 km/hr
Answer: C.54 km/hr
Explanation: Speed of the train relative to man
= (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr
= 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed
= (x - 9) km/hr. x - 9 = 45 ==> x = 54 km/hr.
Answer: C
Question: Simple interest on a certain sum is 16/25 of the sum. Find the rate percent and time, If both are numerically equal.
A.1
B.8
C.5
D.4
Answer: B.8
Explanation: Explanation:
Let sum = X. Then S.I = 16x/25
Let rate = R% and Time = R years.
Therefore, (x * R * R)/100 = 16x/25 or R^2 = 1600/25, R = 40/5 = 8
Therefore, Rate = 8% and Time = 8 years.Answer:
B) Rate = 8% and Time = 8 years.
Question: if a die has 1 6 and 3 4 and 2 5 opposite each other how many such dies can be made
A.10
B.11
C.12
D.13
Answer: C.12
Explanation: if one face have 1,3,2, then the corossponding face will be occupied by respective pair i.e (6,4,5).
so there r 3 place and we have 3 place soit can be arranged in 3! way i.e 6 way and every pair will be suffled in 2 way so ans will be6*2=12.
ANSWER:C
Question: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train ?
A.27 7/9
B.28 7/9
C.29 7/9
D.30 7/9
Answer: A.27 7/9
Explanation: Explanation:
As Trains are moving in same direction,
So, Relative Speed = 40-20 = 20 kmph
= 20*(5/18) = 50/9 m/sec
Length of Train= Speed * Time
Length=50/9∗5
=250/9
=27 7/9
Option A
Question: If log1087.5 = 6.9421, then the number of digits in (875)10 is?
A.30
B.28
C.80
D.26
Answer: C.80
Explanation: X = (875)10 = (87.5 x 10)10
Therefore, log10X = 10(log1087.5 + 1)
= 10(6.9421 + 1)
= 10(7.9421) = 79.421
X = antilog(79.421)
Therefore, number of digits in X = 80.
ANSWER:C
Question: Ashok and Pyarelal invested money together in a business and share a capital of Ashok is 1/9 of that of Pyarelal.if the incur a loss of Rs 670 then loss of Pyarelal?
A.603
B.703
C.800
D.903
Answer: A.603
Explanation: Let the capital of Pyarelal be x, then capital of Ashok=x/9
So ratio of investment of Pyarelal and Ashok = x : x/9 =9x : x
Hence out of the total loss of 670, loss of Pyarelal= 670*9x/10x=603
ANSWER:A
Question: What is the sum of all remainders obtained when the first 120 natural numbers are divided by 9?
A.397
B.401
C.403
D.405
Answer: D.405
Explanation: A positive integer can give only the following 9 remainders when divided by 9: 1, 2, 3, 4, 5, 6, 7, 8, and 0.
1 divided by 9 gives the remainder of 1;
2 divided by 9 gives the remainder of 2;
...
8 divided by 9 gives the remainder of 8;
9 divided by 9 gives the remainder of 0.
We'll have 11 such blocks, since 99/9=11. The last will be:
91 divided by 9 gives the remainder of 1;
92 divided by 9 gives the remainder of 2;
...
98 divided by 9 gives the remainder of 8;
99 divided by 9 gives the remainder of 0.
The last number, 100, gives the remainder of 1 when divided by 9, thus the sum of all remainders will be:
11(1+2+3+4+5+6+7+8+0)+1=405.
Answer: D.
Question: The average weight of a group of boys is 20 kg. After a boy of weight 33 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
A.12
B.14
C.18
D.24
Answer: A.12
Explanation: Let the number off boys in the group originally be x.
Total weight of the boys = 20x
After the boy weighing 33 kg joins the group, total weight of boys = 20x + 33
So 20x + 33 = 21(x + 1) = > x = 12.
ANSWER:A
Question: The sides of a rectangular field are in the ratio 3 : 4. If the area of the field is 9408 sq. m, the cost of fencing the field @ 25 paise per metre is
A.Rs. 55.50
B.Rs. 67.50
C.Rs. 86.50
D.Rs. 98.00
Answer: D.Rs. 98.00
Explanation: Solution
Let length = (3x) metres and breadth = (4x) metres.
Then, 3x × 4x = 9408 ⇔ 12x2 = 9408 ⇔ x2 = 784 ⇔ x = 28.
So, length = 84 m and breadth = 112 m.
Perimeter = [2(84 + 112)] m = 392 m.
∴ Cost of fencing = Rs. (0.25 × 392) = Rs. 98.00. Answer D
Question: A 600 meter long train crosses a signal post in 20 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?
A.4 min
B.2 min
C.8 min
D.9 min
Answer: B.2 min
Explanation: S = 600/20 = 1530 mps
S = 3600/30 = 120 sec = 2 min
Answer: B
Question: If the speed of a man is 66 km per hour, then what is the distance traveled by him in 30 seconds ?
A.550m
B.500m
C.375 m
D.420 m
Answer: A.550m
Explanation: The distance traveled in 30 sec = 66*(5/18) *30 =550m
ANSWER:A
Question: In a family gathering, there is a basket in which there are oranges, bananas and apples. Half of the people in the family eat oranges, half of the other half eat bananas and the rest eat apples. If the number of people who eat oranges are 10 less than the total number of people, find the number of people in the gathering.
A.5
B.10
C.15
D.20
Answer: D.20
Explanation: Let the number of people who eat oranges be X. Then,
total number of people= X + (X/2) + (X/2)= 2X
=> 2X-10=X
=>X=10
=> Total number of people were 2X=20
Option D
Question: A cistern is filled by a tap in 6 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how many hours will it take the leak to empty it?
A.81
B.85
C.88
D.91
Answer: D.91
Explanation: filling rate - leak rate = net rate
1/6.5 - leak rate = 1/7
leak rate = 2/13 - 1/7 = 1/91
The answer is D.
Question: A telephone number contains 10 digit, including a 3-digit area code. Bob remembers the area code and the next 5 digits of the number. He also remembers that the remaining digits are not 0, 1, 2, 4, or 7. If Bob tries to find the number by guessing the remaining digits at random, the probability that he will be able to find the correct number in at most 2 attempts is closest to which of the following ?
A.1/625
B.2/625
C.4/625
D.50/625
Answer: D.50/625
Explanation: I think most of the answers are missing a point. Let me try to put it across:
Total number of possible numbers are : 5x5 = 25
Correct number =1
Case 1: When he gets it right in first attempt: P(E1) = 1/25
Case 2: He gets 1st attempt wrong and second right:
When he gets it wrong then the probability of getting wrong is 24/25.
Now there are 24 cases with him and he chooses the right one this time.
Probability of right case is 1/24
Thus, P(E2) = 24/25 x 1/24
=1/25
Probability of getting it right in at most two cases = P(E1) + P(E2)
= 1/25 + 1/25
= 2/25
= 50/625
Option (D) is therefore right as most of you mentioned but the method employed was wrong.
Question: A, B and C rent a pasture. A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing. If the rent of the pasture is Rs. 210, how much must C pay as his share of rent?
A.45
B.50
C.54
D.65
Answer: C.54
Explanation: Sol.
A : B : C = 10 * 7 : 12 * 5 : 15 * 3 = 70 : 60 : 45 = 14 : 12 : 9.
âˆ´ Câ€™s rent = Rs. [210* 9/35] = Rs. 54.
Answer C
Question: If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 3410 , R will receive
A.660
B.700
C.800
D.900
Answer: A.660
Explanation: Explanation :
Let P's capital = p, Q's capital = q and R's capital = r
Then
4p = 6q = 10r
=> 2p = 3q = 5r
=>q = 2p/3
r = 2p/5
P : Q : R = p : 2p/3 : 2p/5
= 15 : 10 : 6
R's share = 3410 * (6/31) = 110*6 = 660. Answer : Option A
Question: Three pieces of timber 42 m, 49 m and 63 m long have to be divided into planks of the same length, What is the greatest possible length of each plank ?
A.7 m
B.14 m
C.42 m
D.63 m
Answer: A.7 m
Explanation: Answer
Greatest possible length of each plank = H.C.F of 42, 49, 63 = 7 m
Correct Option: A
Question: Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5/6 hour before the second horse reaches A. If the distance between A and B is 50 km. what is the speed of the slower horse?
A.70 km/h
B.60 km/h
C.40 km/h
D.20 km/h
Answer: D.20 km/h
Explanation: Explanation:
If the speed of the faster horse be \inline f_{s} and that of slower horse be \inline s_{s} then
\inline f_{s}+s_{s}=\frac{50}{1}=50
and \inline \frac{50}{s_{s}}-\frac{50}{f_{s}}=\frac{5}{6}
Now, you can go through options.
The speed of slower horse is 20km/h
Since, 20+30=50
and \inline \frac{50}{20}-\frac{50}{30}=\frac{5}{6}
Answer: D
Question: A gets 3 times as much money as B gets, B gets only Rs.25 more then what C gets. The three gets Rs.625 in all. Find the share of B?
A.130
B.120
C.218
D.140
Answer: A.130
Explanation: A+B+C = 625
A = 3B
3B+B+B-25 = 625
5B = 650
B = 130
Answer: A
Question: In a certain pet shop, the ratio of dogs to cats to bunnies in stock is 3 : 7 : 12. If the shop carries 375 dogs and bunnies total in stock, how many dogs are there?
A.42
B.66
C.75
D.112
Answer: C.75
Explanation: Let us assume the number of dogs, cats and bunnies to be 3x, 7x and 12x
Total dogs and bunnies = 15x.
And we are given that 15x = 375.
Hence x = 25.
Dogs = 3x = 3*25 = 75 (Option C)
Question: If f(a)=5b, what is the value of (f(a)-f(6b)) ?
A.32b
B.25b
C.6a-6b
D.3a+2b
Answer: B.25b
Explanation: f(a)=5b
f(6b) = 30b
(f(6b)-f(a)) = 30b-5b = 25b
Answer is B
Question: The sum of two numbers is 16. The difference is 2. What are the two numbers?
A.10-6
B.8-8
C.9-7
D.11-5
Answer: C.9-7
Explanation: 9+7 = 16
9 - 7 = 2
The Answer is C
Question: Insert the missing number
4, -12, 36, -108, 324, (....)
A.-972
B.-972
C.452
D.-452
Answer: A.-972
Explanation: 4*-3=-12
-12*-3=36
36*-3=-108
-108*-3=324
324*-3=-972
ANSWER:A
Question: A certain amount earns simple interest of 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
A.35
B.245
C.350
D.Cannot be determined
Answer: D.Cannot be determined
Explanation: Explanation: We need to know the S.I., principal and time to find the rate.
Since the principal is not given, so data is inadequate.
Answer: Option D
Question: A is twice as good a workman as B and they took 7 days together to do the work B alone can do it in?
A.25 days
B.88 days
C.21 days
D.11 days
Answer: C.21 days
Explanation: WC = 2:1
2x + x = 1/7
x = 1/21 => 21 days
Answer: C
Question: The distance between Delhi and Mathura is 110 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet?
A.11 a.m
B.10 a.m
C.77 a.m
D.55 a.m
Answer: B.10 a.m
Explanation: D = 110 – 20 = 90
RS = 20 + 25 = 45
T = 90/45 = 2 hours
8 a.m. + 2 = 10 a.m.
Answer: B
Question: In an examination 65% failed in Math and 35% failed in French. If 22% failed in both. What % of students passed in both.
A.22%
B.15%
C.20%
D.30%
Answer: A.22%
Explanation: Passed in Math = 100 - 65 = 35%
Passed in French = 100 - 35 = 65%
Students who passed Math or French = 100 -22 = 78%
Students passed in Math and French = (Passed in Math) + (Passed in French) - (Students who passed Math or French) = 35+65-78 =22%
ANSWER:A
Question: The probability that a man will be alive for 10more yrs is 1/4 & the probability that his wife will alive for 10 more yrs is 1/3. The probability that none of them will be alive for 10 more yrs, is
A.1/2
B.1
C.2/3
D.3/4
Answer: A.1/2
Explanation: Sol. Required probability = Pg.) x P(B) = (1— D x(1 —I) =: x 1=1/2
Ans.(A)
Question: The speed of a car is 100 km in the first hour and 60 km in the second hour. What is the average speed of the car?
A.50 kmph
B.65 kmph
C.75 kmph
D.80 kmph
Answer: D.80 kmph
Explanation: Explanation:
S = (100 + 60)/2 = 80 kmph
D)
Question: When the no.7y86038 is exactly divisible by 11, then the smallest whole no.in place of y?
A.2
B.3
C.5
D.7
Answer: B.3
Explanation: The given number =7y86038
Sum of the odd places =8+0+8+7=23
Sum of the even places = 3+6+y
(Sum of the odd places)- (Sum of even places) = Number (exactly divisible by 11)
23-(9+y) = divisible by 11
14 � y = divisible by 11.
Y must be 3, to make given number divisible by 11.
B
Question: A seller purchased some mangoes for Rs 800 and some apples for Rs. 900. He sold the mangoes at a loss of 4 percent and apples at a profit of 10 percent. Overall he make a.?
A.55
B.58
C.56
D.60
Answer: B.58
Explanation: Let the SP of the mangoes and apples be Rs. m and Rs. a respectively.
m = 800(1 - 4/100) = 800 - 32
a = 900(1 + 5/100) = 900 + 90
Total SP - Total CP = m + a - (800 + 900) = - 32 + 90 = Rs. 58
As this is positive, an overall profit of Rs. 500 was made.
Answer: B
Question: Boy sells a book for Rs. 450 he gets a loss of 10 %, To gain 10%, what should be the SP?
A.430
B.450
C.550
D.590
Answer: C.550
Explanation: Find Selling Price to gain 10 %.
Now, we are asked to find selling price to gain 10% profit.
Hint:
Selling Price = (100 + Gain%) × C.P.
100
Selling Price = (100 + 10) × 500
100
Selling Price = (110) × 500
100
Therefore, selling Price = Rs.550
C
Question: John left home and drove at the rate of 45 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 50 mph to reach his destination. How many miles did John drive?
A.235 miles.
B.245 miles.
C.240 miles.
D.265 miles.
Answer: C.240 miles.
Explanation: The total distance D traveled by John is given by
D = 45 * 2 + 3 * 50 = 240 miles.
Answer C
Question: Arun borrowed a certain sum from Manish at a certain rate of simple interest for 2 years. He lent this sum to Sunil at the same rate of interest compounded annually for the same period. At the end of two years, he received Rs. 2400 as compound interest but paid Rs. 2000 only as simple interest. Find the rate of interest.
A.40%
B.30%
C.20%
D.10%
Answer: A.40%
Explanation: Explanation:
Let the sum be x
Simple interest on x for 2 years = Rs.2000
Simple interest = PRT/100
2000 = x Ã— R Ã— 2100
â‡’ x R = 100000 --- (1)
Compound Interest on x for 2 years = 2400
P(1+R/100)T âˆ’ P = 2400
x (1+R/100)2 âˆ’ x = 2400
x (1 +2R/100+R210000)âˆ’x=2400x(2R100+R210000)=2400
2xR/100 + xR2/10000 = 2400--- (2)
Substituting the value of xR from (1) in (2) ,we get
(2Ã—100000)/100 + 100000 Ã— R10000 = 2400
2000+10R = 2400
10R=400
R=40%
Answer: Option A
Question: Solve x^2 – 7x = 0
A.(0,7)
B.(0,3)
C.(0,2)
D.(0,5)
Answer: A.(0,7)
Explanation: This quadratic factors easily: Copyright © Elizabeth Stapel 2002-2011 All Rights Reserved
x^2 – 7x = 0
x(x – 7) = 0
x = 0 or x – 7 = 0
x = 0 or x = 7
The solution is x = 0, 7
Ans: A