RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: What is the perimeter of a square with area 25p^2/16 ?
A.3p/4
B.3p^2/4
C.5p
D.3p^2
Answer: C.5p
Explanation: Area of square, (side)^2 = (5p/4)^2
Therefore side of the square = 5p/4
Perimeter of square = 4*side = 4* (5p/4) = 5p
Answer is C.
Question: A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is:
A.14 years
B.18 years
C.20 years
D.22 years
Answer: D.22 years
Explanation: Let the son's present age be x years.
Then, man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2) x + 26 = 2x + 4 => x = 22.
ANSWER:D
Question: In one hour, a boat goes 14 km/hr along the stream and 8 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
A.12 km/hr
B.11 km/hr
C.18 km/hr
D.10 km/hr
Answer: B.11 km/hr
Explanation: Speed in still water =1/2(14+8) kmph = 11 kmph.
Answer : Option B
Question: 12 men complete a work in 9 days. After they have worked for 6 days, 6 more
men joined them. How many days will they take to complete the remaining work?
A.3days
B.4days
C.2days
D.8days
Answer: C.2days
Explanation: 1 man's 1 day work = 1/108
12 men's 6 days work = 6/9 = 2/3
remaining work = 1 – 2/3 = 1/3
18 men's 1 days work = 18/108 = 1/6
1/6 work is done by them in 1 day
therefore, 1/3 work is done by them in 6/3 = 2 days.
ANSWER C 2days
Question: Annie and Sam set out together on bicycles traveling at 15 and 12 km per hour respectively. After 40 minutes, Annie stops to fix a flat tire. If it takes Annie 20 minutes to fix the flat tire and Sam continues to ride during this time, how many minutes will it take Annie to catch up with Sam assuming that Annie resumes riding at 15 km per hour?
A.20
B.40
C.60
D.80
Answer: B.40
Explanation: Annie gains 3 km per hour (or 1 km every 20 minutes) on Sam.
After 40 minutes Annie is 2 km ahead.
Sam rides 1 km every 5 minutes.
In the next 20 minutes, Sam rides 4 km so Sam will be 2 km ahead.
It will take Annie 40 minutes to catch Sam.
The answer is B.
Question: Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm.
A.235 cm2
B.265 cm2
C.285 cm2
D.295 cm2
Answer: C.285 cm2
Explanation: Explanation:
Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (20 + 18) * (15) = 285 cm2
Answer: Option C
Question: Myra drove at an average speed of 30 miles per hour for the first 30 miles of a trip & then at an average speed of 60 miles/hr for the remaining 30 miles of the trip. If she made no stops during the trip what was her average speed in miles/hr for the entire trip?
A.The average speed is 35 miles per hour.
B.The average speed is 40 miles per hour.
C.The average speed is 55 miles per hour.
D.The average speed is 66 miles per hour.
Answer: B.The average speed is 40 miles per hour.
Explanation: Here, distance for which Myra traveled at the two speeds is same.
Average Speed = 2ab/(a+b) = 2*30*60/(30 + 60) = 40 mph
Answer (B)
Question: In a particular 100 meter race, 5 athletes are participating that are numbered 1-5. In how many ways can athlete #5 finish ahead of #2 provided there's no tie among the athletes?
A.60
B.100
C.120
D.180
Answer: A.60
Explanation: The total number of ways for the athletes to finish is 5! = 120.
#5 will be ahead of #2 in exactly half of these possibilities.
120/2 = 60
The answer is A.
Question: A and B started a business in partnership investing Rs.20,000 and Rs.15,000 respectively. After 6months, C joined them with Rs.20,000. Whatwill be B's share in total profit of Rs.22,000 earned at the end of 2years from the startingof the business?
A.s. 5,000
B.s. 5,500
C.s. 5,700
D.s. 6,600
Answer: D.s. 6,600
Explanation: A : B : C = (20,000 x 24) : (15,000 x 24) : (20,000 x 18) = 4 : 3 : 3.
B's share = Rs. 22000 x	3/10	= Rs. 6,600.
D
Question: Walking 9/8 of his usual rate, a boy reaches his school 4 min early. Find his usual time to reach the school?
A.22
B.99
C.27
D.36
Answer: D.36
Explanation: Speed Ratio = 1:9/8 = 8:9
Time Ratio = 9:8
1 -------- 9
4 --------- ? 36 m.Answer:D
Question: In a group of 80 people, 45 have visited Iceland and 33 have visited Norway. If 41 people have visited both Iceland and Norway, how many people have visited neither country?
A.30
B.31
C.32
D.33
Answer: D.33
Explanation: This is an example of a standard Overlapping Sets question. It has no 'twists' to it, so you'll likely find using the Overlapping Sets Formula to be a fairly easy approach. If you're not familiar with it, then here is the Formula:
80= 45 + 33 - 41 + (# in Neither Group)
=33
The prompt gives you all of the numbers you need to get to the correct answer. Just plug in and solve.
D
Question: A boy wanted to calculate his speed on his bike. His starting point was 350 meters from the turning point. He made the round trip 5 times in 30 minutes. What was the boy's speed in kilometers per hour?
A.1.75
B.1
C.2.25
D.2.4
Answer: A.1.75
Explanation: The distance between the the starting point and the turning point was 350 meters.
The boy made the round trip 5 times so that was 10 times he traveled 350 meters.
10 * 350 = 3500 meters or 3.5 km.
30 minutes is half of an hour.
Divide the 3500 meters in half to put in the right time interval
3500/2 = 1750 meters or 1.75 km
Correct answer is A
Question: A palindrome is a number that reads the same front-to-back as it does back-to-front (e.g. 202, 575, 1991, etc.) p is the smallest integer greater than 300 that is both a prime and a palindrome. What is the sum of the digits of p?
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: Given that p is smallest integer greater than 300 - assume there is a 3-digit that satisfies the above conditions. Let the number be xyx ; question asks us the values of 2x+y
We can straight away cross out options A) and D) - sum of digits 3 or 6 implies it is divisible by 3 ---> we know that p is a prime number
Coming to option B) 2x + y = 4 --> only x = 2 and y = 0 satisfy this equation ( x> 2 will never give sum of digits = 4) ; but 202 is divisible by 2 ; we know that p is a prime number
Similarly option C) 2x+y = 5 --> only x = 2 and y = 1 satisfy this equation ( x> 2 will never give sum of digits = 5) ; but 212 is divisible by 2 ; we know that p is a prime number
Therefore answer option should be E ---> can be verified by taking 2x+y = 7 ---> x = 3 and y = 1 ; gives 313
D
Question: If six persons sit in a row, then the probability that three particular persons are always together is ?
A.1/9
B.1/4
C.1/5
D.1/3
Answer: C.1/5
Explanation: Six persons can be arranged in a row in 6! ways. Treat the three persons to sit together as one unit then there four persons and they can be arranged in 4! ways. Again three persons can be arranged among them selves in 3! ways. Favourable outcomes = 3!4! Required probability
= 3!4!/6! = 1/5
Answer:C
Question: A clock shows the time as 3:30 P.m. If the minute hand gains 2 minutes every hour, how many minutes will the clock gain by 2 a.m.?
A.23 Minutes
B.21 Minutes
C.25 Minutes
D.26 Minutes
Answer: B.21 Minutes
Explanation: if the minute hand gains 2 minutes in 1 hour the from 3:30 p.m-4:00 p.m it gains 1 min
then from 4:00p.m-2:00 a.m =10*2=20 total=21
ANSWER:B
Question: A six digit number which is consisting of only one digitseither 1, 2, 3, 4, 5, 6, 7, 8 or 9, e.g., 111111, 222222... etc.This number is always divisible by :
A.7
B.11
C.13
D.All of these
Answer: D.All of these
Explanation: Solution
Since the 7, 11 and 13 all are the factors of such a number.
Answer D
Question: $8,000 is deposited in a savings account that pays 12% annual interest compounded semiannually. To the nearest dollar, how much is in the account at the end of the year?
A.$8288.55
B.$8985.10
C.$8988.80
D.$8977.14
Answer: C.$8988.80
Explanation: this is the case of semi-annual compoundingso, multiply time period by 2 and divide rate by 2
So,
new time=2periods and new rate=12/2=6%
Now,
CA=8000(1+6/100)^2=$8988.80
Hence answer is C
Question: In a bag, there are seven 6-sided dice (numbered 1 to 6), three 12-sided dice (numbered 1 to 12), and two 20-sided dice (numbered 1 to 20). If four of these dice are selected at random from the bag, and then the four are rolled and we find the sum of numbers showing on the four dice, how many different possible totals are there for this sum?
A.46
B.60
C.42
D.61
Answer: D.61
Explanation: As 'complex-looking' as this question might appear, it's actually rather simple. Pay careful attention to what the specific questions asks for - the number of DIFFERENT possible SUMS from 4 dice. Since we're dealing with some 'special' dice (some 12-sided and 20-sided dice), we have to adjust out math accordingly, but the possibilities are rather limited:
1) The minimum number on any given die is 1
2) The maximum possible sum would only occur if we took the 4 biggest possible dice and rolled the highest possible number on each.
With 4 dice, we could end up with any SUM between:
4 (if we rolled 1s on all 4 dice)
to
64 (if we rolled two 20s on the 20-sided dice and two 12s on the 12-sided dice).
Thus, there are only 61 possible sums.
D
Question: An article is bought for Rs.600 and sold for Rs.500, find the loss percent?
A.16 2/5%
B.16 8/3%
C.16 2/7%
D.16 2/3%
Answer: D.16 2/3%
Explanation: 600 ---- 100
100 ---- ? => 16 2/3%
Answer: D
Question: The Salary of a Labourer increase consistently by 40% per year. If his present salary is Rs. 3000 then what will his salary be after 3 years ?
A.8232
B.3282
C.4282
D.8242
Answer: A.8232
Explanation: Explanation :
Salary = 3000 x 1.4 x 1.4 x 1.4 = 8232
Answer : Option A
Question: The speeds of three asteroids were compared. Asteroids X-13 and Y-14 were observed for identical durations, while asteroid Z-15 was observed for 2 seconds longer. During its period of observation, asteroid Y-14 traveled three times the distance X-13 traveled, and therefore Y-14 was found to be faster than X-13 by 2500 kilometers per second. Asteroid Z-15 had an identical speed as that of X-13, but because Z-15 was observed for a longer period, it traveled five times the distance X-13 traveled during X-13's inspection. Asteroid X-13 traveled how many kilometers during its observation?
A.500
B.625
C.1,000
D.1,500
Answer: B.625
Explanation: X13: (t, d, s)
Y14: (t, 3d, s+2500mi/hour)
Z15: (t+2 seconds, s, 5d)
d=?
Distance = Speed*Time
x13: d = s*t
x14: 3d = (s+2500)*t ===> 3d = ts+2500t
z15: 5d = s*(t+2t) ===> 5d = st+2st ===> 5d - 2st = st
3d = 5d - 2st + 2500t
-2d = -2st + 2500t
2d = 2st - 2500t
d = st - 1250t
x13: d = s*t
st - 1250t = s*t
s - 1250 = s
-625 = s
I got to this point and couldn't go any further. This seems like a problem where I can set up individual d=r*t formulas and solve but it appears that's not the case. For future reference how would I know not to waste my time setting up this problem in the aforementioned way? Thanks!!!
The distance of Z15 is equal to five times the distance of X13 (we established that x13 is the baseline and thus, it's measurements are d, s, t)
S(T+2) = 5(S*T)What clues would I have to know to set up the equation in this fashion? Is it because I am better off setting two identical distances together?
ST+2S = 5ST
T+2 = 5T
2=4T
t= 1/2
We are looking for distance (d=s*t) so we need to solve for speed now that we have time.
Speed y14 - speed x13
Speed = d/t
3d/t - d/t = 2500 (remember, t is the same because both asteroids were observed for the same amount of time)
2d = 2500
2 = 1250
d=s*t
d=1250*(1/2)
d=625
ANSWER: B
Question: How many ways are there to select a subcommittee of 7 members from among a committee of 17?
A.22888
B.19448
C.28791
D.27711
Answer: B.19448
Explanation: Explanation:
Since it does not matter what order the committee members are chosen in, the combination formula is used.
Committees are always a combination unless the problem states that someone like a president has higher hierarchy over another person. If the committee is ordered, then it is a permutation.
C(17,7)= 19,448
Answer: B) 19448
Question: A man is walking at a speed of 10 km per hour. After every kilometre, he takes rest for 5 minutes. How much time will be take to cover a distance of 5 kilometres?
A.48 min.
B.50 min.
C.45 min.
D.55 min.
Answer: B.50 min.
Explanation: Rest time = Number of rest × Time for each rest
= 4 × 5 = 20 minutes
Total time to cover 5km
= (5⁄10 × 60)minutes + 20 minutes = 50 minutes
Answer B
Question: In what ratio should a variety of wheat costing Rs. 3 per kg be mixed with another variety of wheat costing Rs. 6.25 per kg to obtain a mixture costing Rs. 4.50 per kg?
A.8 : 6
B.7 : 6
C.5 : 6
D.7 : 5
Answer: B.7 : 6
Explanation: Let us say the ratio of the quantities of cheaper and dearer varieties = x : y
By the rule of allegation, x/y = (6.25 - 4.50) / (4.50 - 3) = 7/6
ANSWER:B
Question: Two circular signs are to be painted. If the radius of the larger sign is five times that of the smaller sign, how many times more paint is needed to paint the larger sign? (We can assume that a given amount of paint covers the same area on both signs.)
A.5
B.15
C.25
D.35
Answer: C.25
Explanation: Let R be the radius of the smaller sign.
The area A of the smaller sign is A = piR^2.
The area of the larger sign is pi(5R)^2=25piR^2=25A.
Since the area is 25 times larger, we need 25 times more paint for the larger sign.
The answer is C.
Question: What is the last digit of 13^35?
A.5
B.7
C.6
D.8
Answer: B.7
Explanation: explanation:
Let’s begin by looking for a pattern as we increase the exponent.
13^1 = 13 (units digit is 3)
13^2 = 169 (units digit is 9)
13^3 = 2197 (units digit is 7)
Notice that a nice pattern emerges. We get: 3-9-7-1-3-9-7-1-3-9-7-1-…
Whenever n is a multiple of 4, the units digit of 13^n is 1
The units digit of 13^35 is 7
Answer is B
Question: Philip is going with 6 friends on a trip to London for spring break. Airfare and hotel costs a total of $2800.00 for the group of 7 friends. How much does each person have to pay for their hotel and airfare?
A.$100
B.$200
C.$300
D.$400
Answer: D.$400
Explanation: Answer= D
The total cost of the trip ($2800.00) divided by 7 equals $400.00.
Question: John started driving on a highway at a constant speed of R miles per hour at 13:00. Then, 2 hours later, Tom started driving on the same highway at a constant speed of 5R/4 miles per hour at 15:00. If both drivers maintained their speed, how many miles had John driven on the highway when Tom caught up with John?
A.6R
B.8R
C.10R
D.12R
Answer: C.10R
Explanation: In 2 hours, John drove 2R miles.
Tom can catch John at a rate of 5R/4 - R = R/4 miles per hour.
The time it takes Tom to catch John is 2R / (R/4) = 8 hours.
In 8 hours, John can drive another 8R miles for a total of 10R miles.
The answer is C.
Question: How many three letter words are formed using the letters of the word TWITCH?
A.65
B.60
C.55
D.50
Answer: B.60
Explanation: The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is 5P3
= 5 * 4 * 3 = 60.
Answer: B
Question: What is the least number to be subtracted from 11, 15, 21 and 30 each so that resultant numbers become proportional?
A.1
B.5
C.3
D.6
Answer: C.3
Explanation: Let the least number to be subtracted be x, then 11 - x, 15 - x, 21 - x and 30 - x are in proportion.
<=> (11 - x) : (15 - x) = (21 - x) : (30 - x)
=> (11 - x)(30 - x) = (15 - x)(21 - x)
From the options, when x = 3
=> 8 * 27 = 12 * 18
Answer:C
Question: 1/3 of certain journey is covered at the rate of 25kmph,one-fourth at the rate of 30kmph and the rest at 50 kmph.Find the avg speed for the whole journey.
A.28.5 kmph
B.31 kmph
C.33.333 kmph
D.45.98 kmph
Answer: C.33.333 kmph
Explanation: Average speed = total distance / total time
LCM = 3, 4 = 12
Average speed = 12 / (1/3*12*1/25 + ¼ * 12*1/30 +5/50)
= 12/ (4/25 + 3/30+ 5/30
= 150*12/54 = 33.333 kmph
C
Question: Out of 7 constants and 4 vowels how many words of 3 consonants and 2 vowels can be formed?
A.200
B.20000
C.25200
D.2500
Answer: C.25200
Explanation: Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)
= 7C3 * 4C2
= 210
Number of groups each having 3 consonants and 2 vowels = 210
Each group contains 5 letters
Number of ways of arranging 5 letters among themselves
= 5! = (5 * 4 * 3 * 2 * 1)
= 210
Required number of words = (210 * 210)
= 25200
ANSWER C
Question: Matt is touring a nation in which coins are issued in two amounts, 2¢ and 5¢, which are made of iron and copper, respectively. If Matt has five iron coins and ten copper coins, how many different sums from 1¢ to 60¢ can he make with a combination of his coins?
A.30
B.22
C.56
D.44
Answer: C.56
Explanation: The total sum is 5*2 + 10*5 = 60¢. If you can make each sum from 1 to 70 (1¢, 2¢, 3¢, ..., 60¢), then the answer would be 60 (maximum possible).
Now, with 2¢ and 5¢ we cannot make 1¢ and 3¢. We also cannot make 59¢ and 57¢ (since total sum is 60¢ we cannot remove 1¢ or 3¢ to get 59¢ or 57¢).
So, out of 60 sums 4 are for sure not possible, so the answer must be 60 - 4 = 56 sums or less. Only A fits.
Answer: C.
Question: Three numbers are in the ratio 1:3:6 and their H.C.F is 4. The numbers are?
A.4, 12, 24
B.4, 12, 20
C.4, 12, 22
D.4, 12, 28
Answer: A.4, 12, 24
Explanation: Let the required numbers be x, 3x and 6x. Then, their H.C.F = x. So, x = 4.
The numbers are 4, 12, 24.
Answer: A
Question: If 1/2 of the air in a tank is removed with each stroke of a vacuum pump, what fraction of the original amount of air has been removed after 6 strokes ?
A.63/64
B.7/8
C.1/4
D.1/8
Answer: A.63/64
Explanation: Left After 1st stroke = 1/2
Left After 2nd stroke = 1/2 * 1/2 = 1/4
Left After 3rd stroke = 1/2 * 1/4 = 1/8
Left After 4th stroke = 1/2 * 1/8 = 1/16
Left After 5th stroke = 1/2 * 1/16 = 1/32
Left After 6th stroke = 1/2 * 1/32 = 1/64
So removed = 1- 1/64 = 63/64
Question: A sum of money deposited at C.I. amounts to Rs.500 in 3 years and to Rs.650 in 4 years. Find the rate percent?
A.25%
B.30%
C.35%
D.40%
Answer: B.30%
Explanation: 500 --- 150
100 --- ? => 30%
Answer: B
Question: If a number is 40% more than the another, how much % is the smaller number less than the first ?
A.12(1/3)%
B.16(2/3)%
C.28(4/7)%
D.16(4/3)%
Answer: C.28(4/7)%
Explanation: Take a number 100,
Then the other number is 140
% the smaller number is less than the first = [(40/(140)) x 100]% = 28(4/7)%.
ANSWER:C
Question: Adam borrowed some money at the rate of 6% p.a. for the first two years, at the rate of 9% p.a. for the next three years, and at the rate of 14% p.a. for the period beyond four years. If he pays a total interest of 11,800 at the end of nine years, how much money did he borrow?
A.10,421
B.12,421
C.14,000
D.16,000
Answer: B.12,421
Explanation: Let the sum borrowed be x. Then,
(x×6×21/00)+(x×9×3/100)+(x×14×4/100)= 11800
⇒ (3⁄25x + 27⁄100x + 14⁄25x) = 11400 ⇒ 95⁄100x = 11800
⇒ x = (11800×100/95)= 12421
Hence, sum borrowed = 12,421
Answer B
Question: A bag contains 10 black and 20 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
A.1/2
B.3/4
C.2/3
D.1/5
Answer: C.2/3
Explanation: Total number of balls = 10+20 = 30
Number of white balls = 20
probability of drawing a white ball = 20/30 = 2/3
Answer is C
Question: The sum of two numbers is 22. Five times one number is equal to 6 times the other. The bigger of the two numbers is
A.10
B.12
C.16
D.22
Answer: B.12
Explanation: Sol.
Let the numbers be x and (22 - x).
Then, 5x = 6(22 - x)
⇔ 11x = 132⇔ x = 12.
So, the numbers are 12 and 10.
Answer B
Question: The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
A.377
B.268
C.245
D.665
Answer: C.245
Explanation: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.
Answer: C
Question: How much does a watch lose per day, if its hands coincide every 64 minutes?
A.32 8/11min
B.32 8/01min
C.32 8/31min
D.32 6/11min
Answer: A.32 8/11min
Explanation: 55 min. spaces are covered in 60 min.
60 min spaces are covered in (60/55 * 60)min = 65 5/11 min
Loss in 64 min = ( 65 5/11- 64 ) = 16/11 min
Loss in 24 hrs = ( 16/11 * 1/64 * 24 * 60 ) min
= 32 8/11 min
Answer: Option 'A'
Question: If each day a tree loses half its remaining leaves, what fraction of its leaves will it have lost after 6 days ?
A.X-1/8
B.X-1/16
C.X-1/64
D.X/32
Answer: C.X-1/64
Explanation: LET NO OF LEAVES IX X ..IST DAY X/2 ..2ND DAY X/4 ..3RD DAY X/8 , FOURTH DAY X/16 , 5TH DAY X/32 , 6TH DAY X/64 SO ON SO FOURTH.
FINALLY ON LEAVE WILL BE LEFT ..SO ON 3RD DAY LEAVE LOST IS X-1/64 ANSWER C
Question: 1,23,45,67 find ot next term
A.61
B.71
C.75
D.89
Answer: D.89
Explanation: 1+22=23
23+22=45
45+22=67
67+22=89
ANSWER:D
Question: Lary and Terry enter into a partnership by investing $700 and $300 respectively. At the end of one year, they divided their profits such that a third of the profit is divided equally for the efforts they have put into the business and the remaining amount of profit is divided in the ratio of the investments they made in the business. If Lary received $800 more than Terry did, what was the profit made by their business in that year?
A.3000
B.3546
C.35346
D.3521
Answer: A.3000
Explanation: Say the profit was $x.
Lary share = x/6 (half of the third) + (x-x/3)*0.7
Terry share = x/6 (half of the third) + (x-x/3)*0.3
Thus (x-x/3)*0.7-(x-x/3)*0.3=800 --> x=3000.
answer is A
Question: If you are given $3, and the amount doubles every day, how much money will you have after 9 days?
A.$19683
B.$19898
C.$10242
D.$20481
Answer: A.$19683
Explanation: 3^9=19683
The answer is A
Question: Of the 50 researchers in a workgroup, 30 percent will be assigned to Team A and the remaining 80 percent to Team B. However, 70 percent of the researchers prefer Team A and 30 percent prefer Team B. What is the lowest possible number of researchers who will NOT be assigned to the team they prefer?
A. 15
B. 17
C. 20
D. 25
Answer: C. 20
Explanation: I solved it by assuming 100 people and then dividing my answer in two to save time on calculations. (percentage equals number of people) In that case
30 will be in team A
70 will be in team B
The larger diff is
70 want team A so diff is 70-30=40. At least 40 people will NOT get their wish, so for 50 researchers the same number is 20.
Answer choice C
Question: An auction house charges a commission of 20% on the first $50,000 of the sale price of an item, plus 10% on the amount of of the sale price in excess of $50,000. What was the price of a painting for which the house charged a total commission of $24,000?
A.$115,000
B.$190,000
C.$215,000
D.$240,000
Answer: B.$190,000
Explanation: Say the price of the house was $x, then 0.2*50,000+0.1*(x-50,000)=24,000 --> x=$190,000 (20% of $50,000 plus 10% of the amount in excess of $50,000, which is x-50,000, should equal to total commission of $24,000).
Answer: B.
Question: What is the Mode of the following data set T- {1,2,9,1,6,9,9,10}
A.9
B.10
C.2
D.1
Answer: A.9
Explanation: Mode of a set is the data point that is repeated the most number of times. In the set given, 9 is the mode
Answer : A
Question: A IS TWICE AS GOOD A WORKMAN AS B AND TOGETHER THEY FINISH A PIECE OF WORK IN 14 DAYS. THE NUMBER OF DAYS TAKEN BY A ALONE TO FINISH THE WORK IS:
A.11
B.21
C.28
D.42
Answer: B.21
Explanation: (A'S 1 DAY'S WORK): (B'S 1 DAY'S WORK)=2:1
(A+B)'S 1 DAY'S WORK = 1/14
DIVIDE 1/14 IN THE RATIO 2:1
A'S 1 DAY'S WORK = (1/14x2/3)=1/21
HENCE, A ALONE CAN FINISH THE WORK IN 21 DAYS.
CORRECT OPTION : B
Question: If you multiply all the numbers on your mobile phone , what is the answer?
A.2
B.6
C.1
D.0
Answer: D.0
Explanation: D
0
Their is a zero in your phone.
Question: There are two divisions A and B of a class, consisting of 36 and 44 students respectively. If the average weight of divisions A is 40 kg and that of division b is 35 kg. What is the average weight of the whole class?
A.38.25
B.37.25
C.38.5
D.37
Answer: B.37.25
Explanation: Explanation:
Total weight of students in division A = 36 × 40
Total weight of students in division B = 44 × 35
Total students = 36 + 44 = 80
Average weight of the whole class
=(36×40)+(44×35)/80
=(9×40)+(11×35)/20
=(9×8)+(11×7)/4
=72+77/4
=149/4
=37.25
Answer: Option B