RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Find the odd man out
2880, 480, 96, 24, 10, 4, 4
A.480
B.96
C.24
D.10
Answer: D.10
Explanation: from the right side
4*1=4,
4*2=8 but here given 10 so it's not.
8*3=24
24*4=96
96*5=480
480*6=2880
ANSWER:D
Question: 16 boys or 24 girls can construct the wall in 6 days. the number of days that 8 boys and 12 girls Will take to construct?
A.7 days
B.14 days
C.6 days
D.8 days
Answer: C.6 days
Explanation: Explanation:
16 boys =24 girls, 1 boy = 24/16 girls
1 boy = 6/4 girls
8 boys + 12 girls = 8 × 6/4 + 12 = 12 + 12 = 24 girls
6 days to complete the work
Answer: Option C
Question: 7 girls buy hand bag cost 70 dollars. On account of Christmas there is 20% discount. They Buy hand mirrors with their savings on bag. what is actual cost of each mirror.
A.15.5
B.14
C.17.5
D.15
Answer: C.17.5
Explanation: Solution: E.70*7 = 490 without off. 490 with 20% of is 392. and total 98 savings and 14 dollars each girl. mirror cost 14 but still Christmas discount applies. so actual cost of mirror is 17.5 dollars
Question: In how many ways can the letters of the word MOUSES be arranged?
A.390
B.360
C.320
D.330
Answer: B.360
Explanation: MOUSES has 6 words, but S is repeated two times. Thus ways = 6! / 2! = 360 ways
B
Question: A and B can do a job is 16 days and 12 days respectively. 4 days before finishing the job, A joins B. B has started the work alone. Find how many days B has worked alone?
A.6 days
B.4 days
C.5 days
D.7 days
Answer: C.5 days
Explanation: A’s one day’s work = 1⁄16 th work
B’s one day’s work 1⁄12 th work
Let B has worked alone = x days. Then,
A’s amount of work + B’s amount of work = 1
⇒ 4(1⁄16) + (x + 4)(1⁄12) = 1
⇒ 1/4+x+4/12 = 1 ⇒ x = 3⁄4 × 12 - 4
⇒ x = 5 days.
Answer C
Question: On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent Q of thatbeforeJuly 1 last year?
A.90%
B.99%
C.100%
D.101%
Answer: B.99%
Explanation: the total number of employees = n
the average salary = x
total salary to all emplyoees = xn
after
the total number of employees = n - 0.1n = 0.9n
the average salary = x + 10% of x = 1.1x
total salary to all emplyoees = 0.9n (1.1x)
total salary after as a % of total salary before Q= [0.9n (1.1x)]/xn= 0.99 or 99%=B
Question: What is the % change in the area of a rectangle when its length increases by 25% and its width decreases by 25%?
A.0%
B.20% increase
C.20% decrease
D.6% decrease
Answer: D.6% decrease
Explanation: (125/10)*(75/10) = 9375/100 ~94 of original area
0.94 is a 6% decrease from 100/100 ->D
Question: A certain car averages 20 miles per gallon of gasoline when driven in the city and 40 miles per gallon when driving on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?
A.28
B.30
C.34
D.36
Answer: C.34
Explanation: 10*1/20 gpm+50*1/40 gpm=1.75 total gallons
60 total miles/1.75 total gallons=34.3 average mpg
C. 34
Question: 3 candidates in an election and received 1136, 7636 and 11628 votes respectively. What % of the total votes did the winningcandidate got in that election?
A.45%
B.50%
C.57%
D.59%
Answer: C.57%
Explanation: Total number of votes polled = (1136 + 7636 + 11628) = 20400
So, Required percentage = 11628/20400 * 100 = 57%
C
Question: The total number of pupils in Class A is 40 out of which 18 are girls, In Class B there are 20 are boys out of total 35 and in Class C there are 16 girls out of total 32. What is the percent of total girls in all the classes.
A.33.9%
B.43.6%
C.32.7%
D.62.7%
Answer: C.32.7%
Explanation: Class A girls = 18
Class B girls = 35-20 = 15
Class C girls = 16
Total percentage = (18+15+16)/(40+35+32) = 35/107 = 0.327
C
Question: A number Y is chosen at random from the numbers 1, -3, -1, 0, 1, 2, 3. What is the probability that |X|<3?
A.1/5
B.2/7
C.2/9
D.3/7
Answer: D.3/7
Explanation: |X||X| can take 7 values.
To get |X|<2|X|<2 ( i.e., −2<x<+2−2<x
⇒ P(|X|<2)= Favourable CasesTotal CasesP(|X|<2)= Favourable CasesTotal Cases
= 3/7
D
Question: Consider below info to be a table:
AMOUNT OF BACTERIA
TIME - AMOUNT
1PM - 10gms
4PM - x gms
7PM - 22.5 gms
Data for a certain biology experiment are given in the table above. If the amount of bacteria present increased by the same factor during each of the two 3-hour periods shown, how many grams of bacteria were present at 4PM ?
A.15.0
B.12.1
C.12.2
D.12.3
Answer: A.15.0
Explanation: let say the factor is x, the at 7PM quantity = 10 (i.e. quantity @1PM)* x^2 =22.5 => x^2 =2.25 or x = 1.5 => @4PM quantity = 10x =10*1.5 =15.
Answer A
Question: A man spends 10% of his income in house rent, 20% of the rest on his children’s education, 25% of the rest miscellaneous causes. If he now posses Rs. 1944 then his income is?
A.3600
B.3607
C.3606
D.3655
Answer: A.3600
Explanation: X * (90/100) * (80/100) * (75/100) = 1944
X * 0.9 * 0.8 * 0.75
X = 1944/0.54
X = 3600
Answer: A
Question: Income and expenditure of a person are in the ratio 5 : 4. If the income of the person is Rs. 16000, then find his savings?
A.3600
B.3607
C.3200
D.3602
Answer: C.3200
Explanation: Let the income and the expenditure of the person be Rs. 5x and Rs. 4x respectively.
Income, 5x = 16000 => x = 3200
Savings = Income - expenditure = 5x - 4x = x
So, savings = Rs. 3200.
Answer:C
Question: If p is a natural number and p! ends with g trailing zeros, then the number of zeros that (5p)! ends with will be
A.a) (p+g) trailing zeros
B.b) (5p+y) trailing zeros
C.c) (5p+5y) trailing zeros
D.d) (p+5y) trailing zeros
Answer: A.a) (p+g) trailing zeros
Explanation: Let p = 1. p! = 1! = 1, which means g= 0
(5p)! = 5! = 120, trailing zeros = 1
1 = 1 + 0 = p + g
Answer (A).
Question: If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is:
A.Rs. 182
B.Rs. 190
C.Rs. 196
D.Rs. 204
Answer: D.Rs. 204
Explanation: Explanation:
Given ratio =1/2:2/3:3/4=6:8:9
1st part = Rs. 782*6/23=Rs. 204
Answer is D
Question: A and B together can do a piece of work in 8 days. If A alone can do the same work in 12 days, then B alone can do the same work in?
A.33
B.66
C.24
D.88
Answer: C.24
Explanation: B = 1/8 – 1/2 = 1/24 => 24 days
Answer:C
Question: M = {-6, -5, -4, -3, -2}
T = {-2, -1, 0, 1, 2, 3, 4}
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative?
A.0
B.11/35
C.4/7
D.1/2
Answer: C.4/7
Explanation: Answer C.
Total # of outcomes: 5*7= 35
# of outcomes where Product is -ve : (-6,1) ,(-6,2), (-6,3)... Hence, total: 20
Probability: 4/7
Question: Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively.
In 30 minutes, how many times do they toll together?
A.12
B.14
C.15
D.16
Answer: D.16
Explanation: Explanation :
Here's the simple solution :
Take lcm of 2,4,6,8,10,12 seconds
The outcome is 120seconds.
Convert it into minutes = 120 / 60
= 2 minutes
In 30mins it will rings 15times together
But ,In 0th second all bells rings together
Hence Total number of bell rings is = 15 + 1
= 16
Hence (D) is the correct answer.
Answer : D
Question: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
A.6
B.4
C.9
D.3
Answer: B.4
Explanation: M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9
= 4
Answer:B
Question: A random 10-letter code is to be formed using the letters A, B, C, D, E, F, G, H, I and I (only the “I” will be used twice). What is the probability that a code that has the two I’s adjacent to one another will be formed?
A.1/10
B.1/8
C.1/5
D.1/4
Answer: C.1/5
Explanation: Total number of combinations possible = 10!/2!10!/2!
Total favorable combinations = 9!9! - We have considered the two Is as one element. Since we have two Is, they can interchange their positions, without affecting the code.
Probability = 9!/(10!/2!)=9!∗2!/10!=1/59!/(10!/2!)=9!∗2!/10!=1/5
ANS:C
Question: Find the number of square tiles to cover the floor of a room measuring 6 m * 14 m leaving 0.50 m space around the room. A side of square tile is given to be 50 cms?
A.271
B.260
C.277
D.200
Answer: B.260
Explanation: 5 * 13 = 1/2 *1/2* x => x = 260
Answer: B
Question: The average age of P, Q, R, S five years ago was 45 years. By including T, the present average age of all the five is 49 years. The present age of T is?
A.64 years
B.48 years
C.45 years
D.40 years
Answer: C.45 years
Explanation: Present age of P, Q, R, S = 45 x 4 + 20 = 200
Present age of P, Q, R, S and T = 49 x 5 = 245
Hence, the age of T = 245 - 200 = 45 years.
ANSWER:C
Question: 8k8
+ k88
--------
1,6t6
If k and t represent non-zero digits within the integers above, what is t?
A.6
B.7
C.8
D.9
Answer: A.6
Explanation: 8k8
k88
--------
16t6
Trial and error or just plug-in method might be the shortest way to solve this problem. Though you can narrow down the possible values of k to just two: 7 and 8 --> 8**+7**=16** or 8**+8**=16** (k can not be less than 7 or 9, as the result won't be 16**). After that it's easy to get that k=7 and t=6.
Answer: A.
Question: Sam, Suresh and Sanket run a race of 1400 meters. Sam runs twice as fast as Suresh while Suresh runs thrice as fast as Sanket. If Sanket finishes the race by clocking 15 minutes, how far was Suresh from the finish line when Sam must have finished the race?
A.2887
B.278
C.987
D.700
Answer: D.700
Explanation: Explanation:
When Sanket finishes the race in 15 minutes, Suresh & Sam would finish the same race in 5 minutes and 2.5 minutes respectively. Thus, when Sam reaches the ”finish” mark, Suresh must be “half-way” through i.e. 700 meters behind the “finish” line when “Sam” must have finished the race.
ANSWER:D
Question: A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?
A.2 kmph
B.4 kmph
C.5 kmph
D.7 kmph
Answer: B.4 kmph
Explanation: M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9 = 4
Answer:B
Question: In what time a sum of money double itself at 3% per annum simple interest?
A.33 1/8%
B.33 1/3%
C.33 3/3%
D.33 1/7%
Answer: B.33 1/3%
Explanation: P = (P*3*R)/100
R = 33 1/3%
Answer: B
Question: The number of arrangements that can be made with the letters of the word MEADOWS so that the vowels occupy the even places?
A.788
B.144
C.298
D.177
Answer: B.144
Explanation: Explanation:
The word MEADOWS has 7 letters of which 3 are vowels.
-V-V-V-
As the vowels have to occupy even places, they can be arranged in the 3 even places in 3! i.e., 6 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways.
Hence the total ways are 24 * 6 = 144.
Answer: B
Question: A certain number of workers can do a work in 35 days. If there were 10 workers more it could be finished in 10 days less. How many workers are there?
A.25
B.30
C.28
D.24
Answer: A.25
Explanation: number of workers = 10* (35-10)/10 = 25
Answer is A
Question: Rahul went to a shop and bought things worth Rs. 50, out of which 80 Paise went on sales tax on taxable purchases. If the tax rate was 8%, then what was the cost of the tax free items?
A.21.4
B.12.4
C.41.2
D.39.2
Answer: D.39.2
Explanation: Total cost of the items he purchased = Rs.50
Given that out of this Rs.50, 80 Paise is given as tax
=> Total tax incurred = 80 Paise = Rs.80/100
Let the cost of the tax free items = x
Given that tax rate = 8%
∴ (50−80/100−x)8/100 = 80/100
⇒ 8(50 −0.8 −x) = 80
⇒ (50 − 0.8 − x) = 10
⇒ x = 50 − 0.8−10 = 39.2
D)
Question: In how many ways can 4 boys and 3 girls be seated on 8 chairs so that no two girls are together?
A.5760
B.14400
C.480
D.56
Answer: A.5760
Explanation: Let us take opposite of the constraint.
2 girls sitting together:	:
1 case is GGBGBBBB.
Total number of ways=3!*5!*5 with just shifting the rightmost girl.
Then the 2 leftmost girls can shift one position , and using the above reasoning, the total number of ways = 3!*5!*4 and so on till the rightmost girl has 1 position.
So total number of ways = 3!*5!(5+4+3+2+1)=120*90=10800
Similarly another case is:
GBGGBBBB.
Using the above reasoning, the total number of cases is: 3!*5!*(15) =10800
Let us take 3 girls sitting together
GGGBBBBB
There are 3! *5! Ways. The 3 leftmost girls can shift 6 positions. So there are a total of 3!*5!*6=4320 ways
So total is 2*10800 + 4320=25920
The total number of possibilities = 8! Ways =40,320
Answer is 40320-25920=5760
Hence A.
Question: Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can empty 5 gallons per minute. All the three pipes working together can fill the tank in 15 minutes. The capacity of the tank is?
A.60 gallons
B.200 gallons
C.120 gallons
D.180 gallons
Answer: B.200 gallons
Explanation: Work done by the waste pipe in 1 minute = 1/15 - (1/20 + 1/24) = - 1/40
Volume of 1/40 part = 5 gallons\
Volume of whole = 5 * 40 = 200 gallons.
ANSWER:B
Question: One fourth of one third of two fifth of a number is 15. What will be40% of that number
A.140
B.150
C.180
D.200
Answer: C.180
Explanation: Explanation:
(1/4) * (1/3) * (2/5) * x = 15
then x = 15 * 30 = 450
40% of 450 = 180
Answer: Option C
Question: There are three places P, Q and R such that 3 roads connects P and Q and 4 roads connects Q and R. In how many ways can one travel from P to R?
A.8
B.10
C.12
D.14
Answer: C.12
Explanation: Number of ways in which one can travel from P to R
=3×4=12
Answer: Option C
Question: 1000 men have provisions for 17 days. If 500 more men join them, for how many days will the provisions last now?
A.12.9
B.12.5
C.11.3
D.12.2
Answer: C.11.3
Explanation: 1000*17 = 1500*x
x = 11.3
Answer: C
Question: A train moves fast a telegraph post and a bridge 250 m long in 8 sec and 20 sec respectively. What is the speed of the train?
A.70
B.39
C.79
D.75
Answer: D.75
Explanation: Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 250)/20 = y
y = 20.83
Speed = 20.83 m/sec = 20.83 * 18/5 = 75 km/hr.
Answer:D
Question: A clock shows the time as 3:30 P.m. If the minute hand gains 2 minutes every hour, how many minutes will the clock gain by 6 a.m.?
A.23 Minutes
B.24 Minutes
C.29 Minutes
D.26 Minutes
Answer: C.29 Minutes
Explanation: if the minute hand gains 2 minutes in 1 hour the from 3:30 p.m-4:00 p.m it gains 1 min
then from 4:00p.m-6:00 a.m =14*2=28 total=29
ANSWER:C
Question: In a covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay double his speed, then he would take 1 hour less than Sammer. Abhay's speed is?
A.5 km/hr
B.1 km/hr
C.6 km/hr
D.3 km/hr
Answer: A.5 km/hr
Explanation: A
5 km/hr
Let Abhay's speed be x km//hr.
Then, 30/x - 30/2x = 3
x = 5 km/hr.
Question: If a, b, and c are consecutive odd positive integers and a < b < c, which of the following could be equal to c - b - a+4 ?
A.-2
B.5
C.-3
D.-4
Answer: B.5
Explanation: let we put values. a=1, b=3, c=5
5-3-1=1
1+4 =5
Answer :B
Question: A train 240 m long is running at a speed of 60 km/hr. In what time will it pass a bridge 240 m long?
A.28.8 sec
B.20.33 sec
C.60 sec
D.48 sec
Answer: A.28.8 sec
Explanation: total length= 240+240=480
speed=60 km/h=(60*5)/18= 50/3 m/s
time=(480*3)/50=28.8 sec.
ANSWER:A
Question: A sum amounts to Rs.4851 in 2 years at the rate of 5% p.a. If interest was compounded yearly then what was the principal?
A.s.4000
B.s.5000
C.s.4400
D.s.4800
Answer: C.s.4400
Explanation: CI=4851,R=5,N=2
CI=P[1+R/100]^2
=P[1+5/100]^2
4851=P[21/20]^2
4851[20/21]^2
4400
ANSWER:C
Question: The sub-duplicate ratio of 16:36 is
A.4:6
B.1:2
C.1:3
D.1:4
Answer: A.4:6
Explanation: root(16):root(36)=4:6
ANSWER:A
Question: Tina and Rebecca had the same number of candies. Tina gave Rebecca 20 candies so that now Rebecca has five times as many candies as Tina has. Rebecca has now how many candies?
A.50
B.48
C.54
D.55
Answer: A.50
Explanation: T = R
T - 20 ;R + 20
R + 20 = 5 ( T - 20 )
R + 20 =5T - 100
R - 5T = - 120
We knowR = T, so
R - 5T = - 120
Or, R - 5R = -120
Or, - 4R = - 120
Or, R = 30( This is the initital no of Candies Rebecca had)
Candles now she possesses is30+ 20 = 50
So , Rebecca now has 50 candies.
Answer will be (A) 50
Question: In what time will Rs. 1000 become Rs. 1331 at 10% per annum compounded annually?
A.3 years
B.2 years
C.4 years
D.1 year
Answer: A.3 years
Explanation: Principal = Rs. 1000; Amount = Rs. 1331; Rate = 10% p.a. Let the time be n years. Then,
[ 1000 (1+ (10/100))n ] = 1331 or (11/10)n = (1331/1000) = (11/10)3
n = 3 years.
ANSWER A 3 years
Question: A committee is reviewing a total of 40x black-and-white films and 4y color films for a festival. If the committee selects y/x% of the black-and-white films and all of the color films, what fraction of the selected films are in color?
A.20/11
B.16/11
C.17/11
D.10/11
Answer: D.10/11
Explanation: Say x=y=10. In this case we would have:
40x=200 black-and-white films;
4y=40 color films.
y/x%=10/10%=1% of the black-and-white films, so 4 black-and-white films and all 40 color films, thus total of 44 films were selected.
Color films thus compose 40/44=10/11 of the selected films.
Answer: D
Question: Car A is 16 miles behind car B, which is traveling in the same direction along the same route as Car A.Car A is traveling at a constant speed of 58 miles per hour and Car Bis traveling at a constant speed of 50miles per hour.How many hours will it take for Car A to overtake and drive 8 miles ahead of Car B?
A.1.5
B.2.0
C.2.5
D.3.0
Answer: D.3.0
Explanation: Relative speed of car A is 58-50=8 miles per hour, to catch up 16 miles and drive 8 miles ahead so to drive 24 miles it'll need 24/8=3 hours.
Answer: D
Question: A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 20%?
A.2
B.4
C.5
D.6
Answer: C.5
Explanation: C
C.P. of 6 toffees = Re. 1
S.P. of 6 toffees = 120% of Re. 1 = Rs. 6/5
For Rs. 6/5, toffees sold = 6. For re. 1.
Toffees sold = 6 * 5/6 = 5
Question: A certain list of 300 test scores has an average (arithmetic mean) of 85 and a standard deviation of d, where d is positive. Which of the following two test scores, when added to the list, must result in a list of 302 test scores with a standard deviation less than d ?
A. 80 and 80
B. 85 and 85
C. 80 and 90
D. 85 and 80
Answer: B. 85 and 85
Explanation: The standard deviation of a set shows how much variation there is from the mean, how widespread a given set is. So, a low standard deviation indicates that the data points tend to be very close to the mean, whereas high standard deviation indicates that the data are spread out over a large range of values.
So when we add numbers, which are far from the mean we are stretching the set making SD bigger and when we add numbers which are close to the mean we are shrinking the set making SD smaller.
According to the aboveadding two numbers which are closest to the mean will shrink the set most, thus decreasing SD by the greatest amount.
Closest to the mean are 85 and 85 (actually these numbers equal to the mean) thus adding them will definitely shrink the set, thus decreasing SD most.
Answer: B
Question: If the price of a computer were reduced by 13 percent, which of the following could not be the final price of the computer? (Assume initial price to be integer in cents)
A.$844.10
B.$891.10
C.$1,051.90
D.$1,132.30
Answer: A.$844.10
Explanation: Let X be the initial price of computer without discount
then price (final) after discount should be=X(1-16/100)------->X(67/77)=A(say)
means X=A*(77/67).....
so initial price to be integer(As per stem) final price must be multiple of 67
if we check options all were divisible by 67 except option (A)..which is Ans.
Ans A
Question: Boy sells a book for Rs. 450 he gets a loss of 10%, To gain 10%, at price he should sell?
A.Rs.400
B.Rs.450
C.Rs.550
D.Rs.600
Answer: C.Rs.550
Explanation: Find Selling Price to gain 10 %.
Now, we are asked to find selling price to gain 10% profit.
Hint:
Selling Price = (100 + Gain%) × C.P.
100
Selling Price = (100 + 10) × 500
100
Selling Price = (110) × 500
100
Therefore, selling Price = Rs.550
C
Question: A pool can be filled in 4 hours and drained in 5 hours. The valve that fills the pool was opened at 9:00 am and some time later the drain that empties the pool was also opened. If the pool was filled by 11:00 pm and not earlier, when was the drain opened?
A.at 10:30 am
B.at 11:30 am
C.at 12:30 pm
D.at 1:30 pm
Answer: A.at 10:30 am
Explanation: The filling rate is 1/4 and the draining rate is 1/5.
The combined rate of filling and draining is 1/4 - 1/5 = 1/20.
Let x be the number of hours before the drain was opened.
x/4 + (14-x)/20 = 1
5x + 14 - x = 20
4x = 6
x = 1.5
The answer is 10:30 am.
The answer is A.
Question: In a certain parking lot, 4% of the cars are towed for parking illegally. However 80% of the cars which are parked illegally are not towed. What percentage of cars in the parking lot are parked illegally?
A.20%
B.25%
C.30%
D.35%
Answer: A.20%
Explanation: Let x be the number of cars and let y be the number of cars parked illegally.
4%*x = 20%*y
y/x = 1/5 = 20%
The answer is A.
Question: A portion of the 85% solution of chemicals was replaced with an equal amount of 20% solution of chemicals. As a result, 40% solution of chemicals resulted. What part of the original solution was replaced?
A.5/13
B.6/13
C.9/13
D.13/9
Answer: C.9/13
Explanation: Let the original amount of 85 percent solution = x and amount replaced be y
0.85(x - y)+ 0.2y = 0.4 x
0.85x -0.85y+0.2y = 0.4x
0.45x = 0.65y
9x = 13y
y = 9x/13
So, amount replaced = 9/13 of original amount
ANSWER:C
Question: A can do a job in 18 days and B can do it in 24 days. A and B working together will finish twice the amount of work in days?
A.22 1/6
B.22 1/2
C.20 4/7
D.22 1/9
Answer: C.20 4/7
Explanation: 1/18 + 1/24 = 7/72
72/7 = 72/7 *2 = 20 4/7 days
Answer: C
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 15 seconds. The speed of the train is:
A.22
B.50
C.99
D.35
Answer: D.35
Explanation: Speed of the train relative to man = (125/15) m/sec = (25/3) m/sec. [(25/3) * (18/5)] km/hr = 30 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 30 ==> x = 35 km/hr.Answer: D
Question: 3/4th of a number exceeds its 2/3rd by 8. What is the number?
A.22
B.77
C.28
D.96
Answer: D.96
Explanation: Explanation:
Let the number be x.
3/4x = 2/3x + 8
Multiply by 12
9x = 8x + 96
x = 96
ANSWER:D
Question: A and B start a business jointly. A invests Rs 16000 for 8 month and B remains in the business for 4 months. Out of total profit, B claims 2/7 of the profit . How much money was contributed by B?
A.12800
B.13000
C.11500
D.12500
Answer: A.12800
Explanation: B claims 2/7 of the profit
A claims remaining 5/7 of the profit
=> A : B =5/7:2/7=5:2
Let the money contributed by B =b
Then A:B =16000×8:b×4
Therefore,
16000×8:b×4=5:2
16000×8×2=b×4×5
16000×2×2=b×5
3200×2×2=b
b=12800
Answer is A.
Question: The sum of the first 50 positive even integers is 2550. What is the sum of the even integers from 502 to 600 inclusive?
A.23,550
B.27,550
C.31,550
D.35,550
Answer: B.27,550
Explanation: 2 + 4 + 6 + 8 +...+ 100 = 2550
502 + 504 + ... + 600 = 50(500) + (2+4+...+100) = 25,000 + 2550 = 27,550
The answer is B.
Question: If a cyclist in motion increases his speed by 30 percent and then increases this speed by 10 percent, what percent of the original speed is the total increase in speed?
A.10%
B.40%
C.43%
D.64%
Answer: C.43%
Explanation: let the sped be 100
an increase of 30%
the speed now is 130
a further increase of 10% on 130 =13
total increase =43 on 100 =43% C