RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A certain auto manufacturer sold 5% fewer vehicles in 2007 than in 2006. If the manufacturer sold 2.1 million vehicles in 2006, how many vehicles, to the nearest 10,000, did the manufacturer sell in 2007?
A.63,000
B.2,000,000
C.2,030,000
D.2,040,000
Answer: B.2,000,000
Explanation: Let's assume in 2006 the manufacturer sold X.
In 2007 he sold X-5/100(X)
If sales in 2006,X= 2.1 million find X-5/100(X)
(2.1 x 10^6)-5/100(2.1 x 10^6)
2100000-105000=1,995,000-----> 2,000,000(approx)
ANSWER:B
Question: The ratio of the present ages of Giri and Hari is 5:8. 12 years hence, the ratio of their ages will be 11:14. Find the difference in their present ages?
A.7
B.6
C.9
D.2
Answer: B.6
Explanation: Let the present ages of Giri and Hari be 5x and 8x years respectively.
(5x + 12)/(8x + 12) = 11/14
70x + 168 = 88x + 132 => x = 2
Difference in their ages will be the same at all times.
This difference = Difference of their present ages
=> 8x - 5x = 3x => 6 years
Answer: B
Question: How many times are the hands of a clock at right angle in a day?
A.22
B.44
C.48
D.50
Answer: B.44
Explanation: IN 12 HR RIGHT ANGLES = 22
IN 24 HRS RIGHT ANGLES = 44 times
ANSWER B
Question: Gold is 10 times as heavy as water and copper is 6 times as heavy as water. In what ratio should these be mixed to get an alloy 8 times as heavy as water?
A.3:2
B.1:1
C.3:1
D.5:2
Answer: B.1:1
Explanation: G = 10W
C = 6W
Let 1gm of gold mixed with x gm of copper to get 1+x gm of the alloy
1gm gold + x gm copper = x+1 gm of alloy
10W+6Wx = x+1 * 8W
10+6x = 8(x+1)
x = 1/1
Ratio of gold with copper = 1:1 = 1:1
Answer is B
Question: Which of the following data sets has the smallest standard deviation?
A. {1, 2, 3, 4, 5}
B. {2, 3, 3, 3, 4}
C. {2, 2, 2, 4, 5}
D. {0, 2, 3, 4, 6}
Answer: B. {2, 3, 3, 3, 4}
Explanation: since we are asked to compare 'standard deviation', we should look out for similarity between all the sets..
The SIMILARITY is - the SUM of all sets is equal =15..
and hence average = 15/5 = 3...
Now we have 5 different sets which have AVG as 3, so we will look for the spread of the other elements of set around the AVERAGE..
clearly E has a range of 7-(-1) or 8, and has the highest standard deviation..
Next is D, which has a range of 6-0 or 6..
and {2, 3, 3, 3, 4} has smallest standard of deviation.
ans B
Question: A store owner estimates that the average price of type A products will increase by 20% next year and that the price of type B products will increase by 11% next year. This year, the total amount paid for type A products was $3500 and the total price paid for type B products was $8600. According to the store owner's estimate, and assuming the number of products purchased next year remains the same as that of this year, how much will be spent for both products next year?
A.$13,746
B.$15,325
C.$16,000
D.$16,225
Answer: A.$13,746
Explanation: cost of type A products next year = 1.20 * 3500 = 4200
cost of type B products next year = 1.11 * 8300 = 9546
total 4200 +9546 = 13746
ANSWER:A
Question: Two pipes A and B can separately fill a tank in 2 minutes and 15 minutes respectively. Both the pipes are opened together but 4 minutes after the start the pipe A is turned off. How much time will it take to fill the tank?
A.15
B.10
C.12
D.17
Answer: B.10
Explanation: 4/12 + x/15 = 1
x = 10
Answer:B
Question: How many of the following numbers are divisible by 132?
264, 396, 462, 792, 968, 2178, 5184, 6336,528,1320,660
A.4
B.5
C.6
D.7
Answer: D.7
Explanation: Explanation:
A number is divisible by 132, if it is divisible by each one of 11, 3 and 4.
Clearly, 968 is not divisible by 3. None of 462 and 2178 is divisible by 4.
Also, 5184 is not divisible by 11.
Each one of remaining 7 is divisible by each one of 11, 3 and 4 and therefore, by 132.
Answer: D
Question: Two trains of equal are running on parallel lines in the same direction at 44 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?
A.40
B.88
C.66
D.55
Answer: A.40
Explanation: Let the length of each train be x m.
Then, distance covered = 2x m.
Relative speed = 44 - 36 = 8 km/hr.
= 8 * 5/18 = 20/9 m/sec.
2x/36 = 20/9 => x = 40.
Answer:A
Question: What is the unit digit in (4137)754?
A.6
B.5
C.9
D.13
Answer: C.9
Explanation: Explanation:
Unit digit in (4137)754 = Unit digit in {[(4137)4]188 x (4137)2}
=Unit digit in { 292915317923361 x 17114769 }
= (1 x 9) = 9
C
Question: A husband wants to share of x% of his savings of total $10,0000 to his wife. After home expenses, the husband reduce this amount by (x − 9)%. In terms of x, how much $ amount will the wife get?
A.x*x – 9x
B.(x)(1009 – x)
C.(1000)(1009 – x)
D.(1000)(91– x)
Answer: B.(x)(1009 – x)
Explanation: Based on the answer choices and the question, this question begs the use of x=9 as a sample number.
Initial = 9%*100000 = 9000
Reduction = 9-9=0%, so no math required here to calculate the reduction; just make sure that you can calculate 9000 in your answer.
A. x*x – 9x = 0; No
B. (x)(1009 – x) = 9000; Winner!
C. (1000)(1009 – x) > 9000; No
D. (1000)(91 – x) > 9000; No
E. (x-9)/1000 = 0; No
B
Question: Find the missing figures :
?% of 70 = 2.125
A.3.04
B.6.05
C.8.7
D.7.7
Answer: A.3.04
Explanation: (i)	Let x% of 70= 2.125. Then , (x/100)*70 = 2.125
X = (2.125 * 100/70) = 3.04
Answer is A.
Question: What is the sum of natural numbers between 90 and 100
A.1045
B.4860
C.5000
D.5500
Answer: A.1045
Explanation: a = first number
l = last number
Sn = n/2[a + l]
between 90 and 100 numbers = 11 => 100 - 90 = 10 + 1 = 11
Sn = 11/2 Ã— 190 = 11 Ã— 95 = 1045
Answer : A
Question: The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum.
A.33498
B.17000
C.2665
D.28876
Answer: B.17000
Explanation: The simple interest for the first year is 10200/2 is Rs.5100 and compound interest for first year also is Rs.5100. The compound interest for second year on Rs.5100 for one year
So rate of the interest = (100 * 1530)/ (5100 * 1) = 30% p.a.
So P = (100 * 10200)/ (30 * 2) = Rs.17000
Answer:B
Question: Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.15 per cubic meter?
A.2998
B.2799
C.2890
D.1485
Answer: D.1485
Explanation: 22/7 * 14 * 3/2 * 3/2
= 99 m2
99 * 15
= 1485
Answer:D
Question: The banker's discount on Rs.1800 at 12% per annum is equal to the true discount on Rs.1872 for the same time at the same rate. Find the time?
A.3 months
B.4 months
C.5 months
D.6 months
Answer: B.4 months
Explanation: Solution
S.I on Rs.1800 = T.D on Rs.1872.
P.W on Rs.1872 is Rs.1800.
Rs.72 is S.I on Rs. 1800 at 12%.
Time	=(100x72 / 12x1800)
= 1/3 year
= 4 months.
Answer B
Question: Which of the following is a prime number?
A.2
B.4
C.25
D.9
Answer: A.2
Explanation: Clearly, 2 is a prime number. Ans : A
Question: How many multiples of 5 are there between 50 and 500 ?
A.128
B.91
C.89
D.61
Answer: C.89
Explanation: It should be mentioned whether 50 and 500 are inclusive.
If 50 and 500 are inclusive, then the answer is (500-50)/5+1=91.
If 50 and 500 are NOT inclusive, then the answer is (495-55)/5+1=89.
Since OA is C, then we have NOT inclusive case.
Question: What is the remainder when 14,451 × 15,651 × 16,788 is divided by 5?
A.1
B.2
C.4
D.3
Answer: D.3
Explanation: Only the unit's digit of the product will decide the remainder when divided by 5.
Hence, 1*1*8= will give units digit as 8
So, whatever be the number, if it ends in 8, the remainder after dividing with 5 will be 3.
OptionD
Question: Six persons standing in queue with different age group, after two years their average age will be 43 and seventh person joined with them. Hence the current average age has become 45. Find the age of the 7th person.
A.69
B.70
C.71
D.72
Answer: A.69
Explanation: Let ‘x’ be the average of 6 persons
Since there are 6 after 2 years the age will be increased by 2 for each. So 6*2=12
After two years age will be =x+12
Average age is 43
That is (x+12)/6=43
=>x=246
Let ‘y’ be the 7th person age
(x+y)/7 =45
(246+y)/7=45
y=(45*7)-246
y=69
Answer A
Question: 15 men and 12 boys finish a job in 11 days, 13 men and 13 boys finish it in 10 days. 10 men and 10 boys shall finish it in how many days?
A.18
B.17
C.12
D.11
Answer: D.11
Explanation: 13 M + 4 B ----- 11 days
9 M + 9 B ------- 10 days
12 M +12 B -------?
117 M + 36 B = 108 M +108 B
72 B =9 M => 1 M = 8 B
104 B + 4 B = 108 B ---- 11 days
96 B + 12 B = 108 B -----? => 11 days
Answer: D
Question: A grocer is storing soap boxes in cartons that measure 30 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 6 inches by 5 inches, then what is the maximum number of soap boxes that can be placed in each carton?
A.360
B.252
C.280
D.300
Answer: A.360
Explanation: however the process of dividing the volume of box by the volume of a soap seems flawed but it does work in this case due to the numbers
Dimensions of the box =30*42*60
Dimensions of the soap = 5*6*7
we get = 6x6x10 = 360
so the question is why this particular arrangement, in order to maximize number of soaps we need to minimize the space wasted and this is the only config where we dont waste any space so we can expect the maximum number
the answer is (A)
Question: A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 210, then how much amount should C pay as his share of rent?
A.54
B.45
C.25
D.15
Answer: A.54
Explanation: A : B : C
=10×7:12×5:15×3
=2×7:12×1:3×3
=14:12:9
Amount that C should pay
=210×9/35=6×9=54
Answer is A
Question: What should come in place of the question mark (?) in the following number series?
15 19 ? 27 31
A.21
B.23
C.20
D.25
Answer: B.23
Explanation: Explanation:
It increases by 4.
Answer:B
Question: In May, the groundskeeper at Spring Lake Golf Club built a circular green with an area of 65π square feet. In August, the groundskeeper doubled the distance from the center of the green to the edge of the green. What is the total area of the renovated green?
A.105π
B.130π
C.200π
D.260π
Answer: D.260π
Explanation: Area = πR^2, so doubling the radius results in an area that is 4 times the original area.
4(65π) = 260π
The answer is D.
Question: At a certain zoo, the ratio of sea horse to penguins is 5 to 11. If there are 85 more penguins than sea horses at the zoo, how many sea horses are there?
A.24
B.36
C.48
D.70
Answer: D.70
Explanation: 5/11 = x / x+85
5*85 = 6x
x=70
D. 70
Question: How many liters of water must be evaporated from 50 liters of a 3-percent sugar solution to get a 10-percent solution?
A.35
B.33 1/3
C.27
D.16 2/3
Answer: A.35
Explanation: 3% of a 50 liter solution is 1.5L. So you are trying to determine how many liters must a solution be for the 1.5L to represent 10% of the solution. Set up an inequality and solve for x:
1.5/x = 1/10
x = 15
Since you need a 15L solution, you must evaporate 35 of the original 50L solution to get a 10% solution.
Answer is A.
Question: A squirrel runs up a cylindrical post , in a perfect spiral path making one circuit for each rise of 3 feet . How many feet does the squirrel travels if the post is 27 feet tall and 3 feet in circumference?
A.10 feet
B.12 feet
C.27 feet
D.15 feet
Answer: C.27 feet
Explanation: total circuit=27/3=9
total feet squirrel travels=9*3=27 feet
ANSWER:C
Question: 7 people average age is 30. youngest person age is 8. find average of the people when youngest was born.
A.23
B.24
C.25
D.22
Answer: D.22
Explanation: average age of people =30
so have total age =210
before 7 years we have to deduct each person age by seven years 210-56=154
so average age would be 154/7=22
ANSWER:D
Question: The ratio of two numbers is 3:4 and their sum is 28. The greater of the two numbers is?
A.12
B.14
C.16
D.17
Answer: C.16
Explanation: 3:4
Total parts = 7
= 7 parts --> 28 (7 × 4 = 28)
= 1 part ---->4 (1 × 4 = 4)
= The greater of the two number is = 4
= 4 parts ----> 16 (4 × 4 = 16)
C)
Question: At the time of marriage, a man was 10 years elder to his wife. 16 years after their marriage, his age is 6/5 times the age of his wife. What was wife's age at the time of marriage ? Choose one answer.
A.36 years
B.16 years
C.14 years
D.24 years
Answer: C.14 years
Explanation: let wifes age= x
husband age = x+10
now after 16 years of mrg x+16 wifes age
x+10+12 husbands age
6/5(x+16)=x+10+12
after solving x=14
ANSWER:C
Question: A man is 22 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
A.14 years
B.18 years
C.20 years
D.22 years
Answer: C.20 years
Explanation: Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 22) + 2 = 2(x + 2)
x + 24 = 2x + 4
x = 20.
answer :C
Question: For a race a distance of 224 meters can be covered by P in 16 seconds and Q in 32 seconds. By what distance does P defeat Q eventually?
A.232m
B.238m
C.224m
D.331m
Answer: C.224m
Explanation: Explanation:
This is a simple speed time problem. Given conditions:
=>Speed of P= 224/16 = 14m/s
=>Speed of Q=224/32 = 7m/s
=>Difference in time taken = 16 seconds
Therefore, Distance covered by P in that time= 14m/s x 16 seconds = 224 metres
ANSWER: C
Question: If two dice are thrown simultaneously, then find the probability that the sum of numbers appeared on the dice is 12?
A.5/6
B.7/36
C.5/36
D.1/36
Answer: D.1/36
Explanation: The sum of numbers appeared is 12.
Therefore, the required probability = n(E)/n(S) = 1/36.
ANSWER:D
Question: If P(32, 6) = kC (32, 6), then what is the value of k?
A.6
B.32
C.120
D.720
Answer: D.720
Explanation: Solution
Since 32P6 = k32C6
⇒ 32!/ ( 32-6 )!= k 32!/ ( 32-6 )!
⇒k = 6! = 720. Answer D
Question: On a certain planet where people usually tend to live for more than a century, the ratio of present ages of father and son is 7:4. 10 years later, the ratio of their ages will be 5:3. What is the sum of their present ages?
A.220
B.200
C.140
D.80
Answer: A.220
Explanation: The ratio of present ages of father and son is 7:4, so suppose the present ages are 7x and 4x, respectively.
10 years later, the ages of father and son, respectively, shall be 7x + 10 and 4x + 10.
The ratio of ages 10 years later is given to be 5:3.
This means
(7x + 10)/(4x + 10) = 5/3
Solving we get x = 20.
So present age of father is 7x = 140 and present age of son is 4x = 80.
The sum of present ages is thus 220.
Ans A
Question: Venkat purchased twenty dozens of toys at the rate of 375 per dozen. He sold each one of them at the rate of 33. What was his percentage profit?
A.6.5
B.5.6
C.3.5
D.4.5
Answer: B.5.6
Explanation: Cost price of 20 dozen toys = 20 × 375 = 7,500
Selling price of 20 dozen toys = 20 × 33 × 12 = 7,920
Profit percentage = 7920−7500/7500×100=5.6%
Answer B
Question: 1/3 of certain journey is covered at the rate of 25kmph,one-fourth at the rate of 30kmph and the rest at 50 kmph.Find the avg speed for the whole journey.
A.25.56 kmph
B.28.675 kmph
C.33.333 kmph
D.40.134 kmph
Answer: C.33.333 kmph
Explanation: Average speed = total distance / total time
LCM = 3, 4 = 12
Average speed = 12 / (1/3*12*1/25 + ¼ * 12*1/30 +5/50)
= 12/ (4/25 + 3/30+ 5/30
= 150*12/54 = 33.333 kmph
C
Question: In a basketball game, Dhoni scored 10 points more than Dravid, but only half as many points as Shewag. If the three players scored a combined total of 130 points, how many points did Dhoni score?
A.45
B.55
C.35
D.65
Answer: C.35
Explanation: Let Dravid scored point = x
Then Dhoni Scored = x+10
Shewag Scored = 2*(x+10) = 2x+20
As given, x+x+10+2x+20 = 130 points
4x+30 = 130
x = 130-30/4 = 25
So Dhoni Scored = x +15 i.e) 25+10 = 35
Answer : C
Question: If P is a prime number greater than 10, what is the remainder when P^2 is divided by 2.
A.Cannot be determined
B.1
C.2
D.3
Answer: B.1
Explanation: take square of any prime number
remainder will be 1
Ans B
Question: In the coordinate plane, a circle centered on point (-3, -3) passes through point (1, 1). What is the area of the circle?
A.9π
B.32π
C.25π
D.37π
Answer: B.32π
Explanation: r^2=(-3-1)^2+(-3-1)^2=16+16=32
Area of circle=πr^2=32π
Answer : B
Question: Rahul can done a work in 5 days and meena can done a work in 10 days.In how many days that both are work together?
A.3/10
B.10/3
C.1/3
D.5
Answer: B.10/3
Explanation: A's one day work=1/5
B's one day work=1/10
A+B=1/5+1/10=10+5/50=10/3 days
Ans:option B
Question: P and Q started a business with respective investments of Rs. 4 lakhs and Rs. 10 lakhs. As P runs the business, his salary is Rs. 5000 per month. If they earned a profit of Rs. 2 lakhs at the end of the year, then find the ratio of their earnings?
A.1:5
B.1:3
C.1:1
D.1:2
Answer: D.1:2
Explanation: Ratio of investments of P and Q is 2 : 5
Total salary claimed by P = 12 * 5000 = Rs. 60000
Total profit = Rs. 2 lakhs.
Profit is to be shared = Rs. 140000
Share of P = (2/7) * 140000 = Rs. 400000
Share of Q = Rs. 100000
Total earnings of P = (60000 + 40000) = Rs. 100000
Ratio of their earnings = 1 : 1
Answer: D
Question: A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.18000. A's share is?
A.Rs.7500
B.Rs.7200
C.Rs.6000
D.Rs.5750
Answer: C.Rs.6000
Explanation: x* 12 : 2x* 6: 3x* 4
1:1:1
1/3 * 18000 = 6000
ANSWER:C
Question: In how much time will a train of length 140 m, moving at 36 kmph cross an electric pole?
A.sec
B.sec
C.sec
D.sec
Answer: D.sec
Explanation: Convert kmph to mps. 36 kmph = 36 * 5/18 = 10 mps.
The distance to be covered is equal to the length of the train.
Required time t = d/s = 140/10 = 14 sec.
Answer:D
Question: The ratio between the speeds of two persons is 7:8.If the second main runs 400 km in 4 hours,then find the speed of the another person?
A.91.6km/hr
B.87.5km/hr
C.80.5 km/hr
D.92 km/hr
Answer: B.87.5km/hr
Explanation: Let the speed of two persons be 7x and 8x km/hr
8x=400/4
x=100/8
x=12.5
Speed of first person=(7*12.5)km/hr
=87.5 km/hr
Answer is option B
Question: The distance between Delhi and Mathura is 110 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet?
A.08 a.m.
B.09 a.m.
C.12 a.m.
D.10 a.m.
Answer: D.10 a.m.
Explanation: D
10 a.m.
D = 110 – 20 = 90
RS = 20 + 25 = 45
T = 90/45 = 2 hours
8 a.m. + 2 = 10 a.m.
Question: In a certain group of 10 members, 4 members teach only French and the rest teach only Spanish or German. If the group is to choose 4-member committee, which must have at least 1 member who teaches French, how many different committee can be chosen ?
A.174
B.171
C.186
D.196
Answer: B.171
Explanation: Case 1
1french 3either German or Spanish: 4C1 * 6C3 = 80
Case 2
2french 2either German or Spanish: 4C2 * 6C2 = 90
Case 3
4french 4C4 = 1
Answer is B = 171
Question: Rectangular tile each of size 80cm by 40cm must be laid horizontally on a rectangular floor of size 130cm by 230cm,such that the tiles do not overlap and they are placed with edges jutting against each other on all edges. A tile can be placed in any orientation so long as its edges are parallel to the edges of floor. No tile should overshoot any edge of the floor. The maximum number of tiles that can be accommodated on the floor is:
A.6
B.2
C.8
D.9
Answer: D.9
Explanation: Area of tile = 80*40 = 3200
Area of floor = 130*230 = 29900
No of tiles = 29900/3200 = 9.34
So, the no of tile = 9
ANSWER:D
Question: There are two numbers. If 60% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?
A.5/12
B.5/7
C.5/3
D.5/8
Answer: A.5/12
Explanation: Let the two numbers be x and y.
60/100 * x + y = 5/4y
=> 3/5 x = 1/4 y => x/y
= 5/12
Answer: A
Question: At what rate percent per annum will a sum of money double in 9 years.
A.12.5%
B.13.5%
C.11.5%
D.11.1%
Answer: D.11.1%
Explanation: Let principal = P, Then, S.I.=P and Time=8 years
Rate = [(100 x P)/ (P x 9)]% = 11.1% per annum. Answer: D
Question: A dishonest dealer professes to sell goods at the cost price but uses a weight of 600 grams per kg, what is his percent?
A.11
B.25
C.66
D.88
Answer: C.66
Explanation: 600 --- 400
100 --- ? => 66%
Answer:C
Question: A certain car dealership offers its newest model in ten exterior and nine interior colors. If the ten interior colors are identical to the nine exterior colors, and the dealership sells every pair of colors except those that would result in a car with an identically colored interior and exterior, how many different color combinations are possible?
A.45
B.81
C.90
D.10!/2!
Answer: B.81
Explanation: I lined up the 10 different colours for Exterion and Interior like this:
E: A B C D E F G H I J
I: A B C D E F G H I J
I calculated the number of combinations: 10*10= 100 combinations.
But, from these 100 we need to delete sth: the same colours.
There are 10 possible pairs of coulours that will be the same. So, I deleted these 10 pairs from 100, resulting in 81.
Mind here, that the 10 do not result in 20 colours, because 1 pair is one unit that is not allowed. So, 10 units are not allowed (surprised that 80 wasn't among the answer options to confuse test takers...).
B
Question: Sum of the squares of three numbers is 363 and the sum of their products taken two at a time is 131. Find the sum?
A.20
B.22
C.25
D.27
Answer: C.25
Explanation: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 363 + 2* 131
a + b + c = √625 = 25
C
Question: If a is a positive number and 1/4 the square root of a is equal to 2a, then a =
A.1/64
B.1/16
C.1/2
D.4
Answer: A.1/64
Explanation: 1/4 of sqrt(a) = 2a, which means that sqrt(a) = 8a
or a = 64a^2 -> divide by a
1=64a
a=1/64
A.
Question: In March, Bill ran an average of 1 mile an hour. If by June he had increased his pace by 10 seconds per mile, then which of the following expresses the number of hours it would take Bill to complete one mile in June?
A.3590/60^2
B.2410/60^2
C.2390/60^2
D.3586/60
Answer: A.3590/60^2
Explanation: Bill ran at an average of 1 mile/hour in march. So to run 1 mile he would take 1 hour = (60 * 60) seconds = 3600 seconds.
If he increases his speed by 10 seconds, he will complete a mile in 3590 seconds. Converting in hours = 3590/(60 * 60) = 3590/(60^2)
ANSWER: A
Question: If positive integers x is even and y is odd, which of the following must be odd?
A.2xy
B.3x+y-1
C.x+y
D.x + y -1
Answer: C.x+y
Explanation: Let x = 2 and y = 1
2xy = 2*2*1 = 4
3x+y-1 = 3*2 + 1 -1 = 6
x+y = 2+1 = 3
x+y-1 = 2+1-1 = 2
3(x+y) - 3 = 6+3-3 = 6
Answer: C
Question: A car crosses a 600 m long bridge in 5 minutes. Whatis the speed of car in km per hour?
A.7 km/hr
B.7.2 km/hr
C.8 km/hr
D.8.2 km/hr
Answer: B.7.2 km/hr
Explanation: Speed = 600 m/sec.
5 x 60
= 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
= 2 x 18 km/hr
5
= 7.2 km/hr
B
Question: Last year the price range (per kg) for 100 varieties of apples in wholesale market was $1,00. If the prices of each of the 100 varieties increased by 10 percent this year over what it was last year, what is the range of the wholesale prices of the 1000 varieties of apples this year?
A. $ 50
B. $ 100
C. $ 110
D. $600
Answer: C. $ 110
Explanation: let the lowest price be x.
Therefore, highest price is x +100.
Now price of each variety is increased by 10%.
Therefore the price will remain arranged in the same order as before.
or Lowest price = 1.1x and Highest = 1.1 * (x+100)
or Range = highest - lowest = 1.1 * (x+100) - 1.1x
= 110, Hence, C
Question: A certain car's price decreased by 2.5% (from the original price) each year from 1996 to 2002, during that time the owner of the car invested in a new carburetor and a new audio system for the car, which increased car's price by $3,500. If the price of the car in 1996 was $22,000, what is the car's price in 2002?
A.$18,400
B.$19,500
C.$22,200
D.$20,400
Answer: C.$22,200
Explanation: Price in 96 = 22000
Price decrease each year = 2.5/100*22000 = 550
Price in 97 = 22000 - 550
Price in 98 = 22000 - 2*550
Price in 99 = 22000 - 3*550
Price in 00 = 22000 - 4*550
Price in 01 = 22000 - 5*550
Price in 02 = 22000 - 6*550 = 18700
Investment in the car = 3500
Net price of the car in 02 = 18700 + 3500 = $22200
Correct Option: C