RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Four different objects 1,2,3,4 are distributed at random in four places marked 1,2,3,4. What is probability that none of the objects occupy the place corresponding to it's number?
A.17/24
B.3/8
C.1/2
D.5/8
Answer: B.3/8
Explanation: Since, we know there are only 24 possible outcomes in TOTAL, it might not be a big deal just LIST the outcomes where no object is in right place.
We'll list the objects (1, 2, 3, and 4) in an order so that no number is in the correct place.
To begin, we'll place a 2 in the first position to get the following:
2134
2341
2413
There are 3 possible outcomes.
IF we place a 3 in the first position, we should also get 3 possible outcomes.
To confirm:
3142
3412
3421
Yep, 3 possible outcomes
IF we place a 4 in the first position, we should also get 4 possible outcomes.
To confirm:
4123
4312
4321
Yep, 3 possible outcomes
# of outcomes where no object is in right place = 3 + 3 + 3 = 9
---------------------------
So, P(no object is in the right place) = 9/24 = 3/8 = B
Question: A train 110 m long is running with a speed of 90 km/h. In how many seconds will the train pass a man who is running at 9 km/h in the direction opposite to that in which the train is going?
A.3
B.4
C.5
D.6
Answer: B.4
Explanation: The speed of the train relative to the man = 90 + 9 = 99 km/h.
99000 m/h * 1h/3600 s = (990/36) m/s
(110 m) / (990/36 m/s) = (110 * 36) / 990 = 36/9 = 4 seconds
The answer is B.
Question: The letters C,K,L and U are rearranged to form the word 'Luck'. Find its probability.
A.1/120
B.1/235
C.1/24
D.1/76
Answer: C.1/24
Explanation: Explanation :
There are total 4 letters. The probability that C gets the first position is 1/4.
The probability that K is in the second position is 1/3.
Likewise, probability for L and U are 1/2 and 1/1.
Hence, the required probability is:-
=> (1/4) x (1/3) x (1/2) x 1.
=> 1/24.
Answer : C
Question: Car A leaves the airport at 8:00 am and travels at a constant rate of 40 km per hour. Car B leaves the airport at 8:15 am and travels in the same direction along the same highway at a constant rate of 46 km per hour. At what time will Car B be 11 km ahead of Car A?
A.10:45 am
B.11:00 am
C.11:15 am
D.11:45 am
Answer: D.11:45 am
Explanation: At 8:15 am, Car A will be 10 km ahead of Car B.
Car B travels at a rate 6 km per hour faster than Car A.
Car B needs to travel 21 km more than Car A in order to be 11 km ahead.
This will take 21 km/6 km per hour=3.5 hours.
Car B will be 11 km ahead at 11:45 am.
The answer is D.
Question: One skirt requires 3.75 yards of cloth. How many skirts you can make from 45 yards
A.9 skirts
B.10 skirts
C.11 skirts
D.12 skirts
Answer: D.12 skirts
Explanation: for 1 shirt --> 3.75 yards reqd
for x skirts --> 45 yards
x=45/3.75 => 45*100/375 = 12
We can make 12 skirts from 45 yards
Ans : 12 skirts
ANSWER:D
Question: Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?
A.2 : 3 : 4
B.6 : 7 : 8
C.6 : 8 : 9
D.7 : 8 : 9
Answer: A.2 : 3 : 4
Explanation: Explanation:
Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).
=>(140/100 X 5X), (150/100 X 7X) and (175/100 X 8X)
The required ratio = 7x :	21x/2 : 14X
=>14x : 21x : 28x
=>2 : 3 : 4
ANSWER IS A
Question: The average ages of three persons is 27 years. Their ages are in the proportion of 1:3:5. What is the age in years of the youngest one among them ?
A.33
B.77
C.55
D.09
Answer: D.09
Explanation: Let the age of three persons be x, 3x and 5x => 9x/3 = 27 = > x = 9
Answer:D
Question: The average of five numbers is 100. If one number is excluded, the average becomes 110. The excluded number is?
A.8
B.6
C.58
D.60
Answer: D.60
Explanation: Excluded number
= (100 * 5) - (110 * 4)
= 500 - 440 = 60
Answer:D
Question: If the average (arithmetic mean) of 5b,6b+4,7b,8b-4 and 2b is 140, what is the value of b?
A.20
B.22
C.25
D.30
Answer: C.25
Explanation: AM of 5b,6b+4,7b,8b-4 and 2b=5b+6b+4+7b+8b-4+2b= 28b/5
Given that 28b /5 = 140
b= 25
Answer is C
Question: A, B and C are partners in a business. Their capitals are respectively, Rs.5000, Rs.6000 and Rs.4000. A gets 30% of the total profit for managing the business. The remaining profit is divided among three in the ratio of their capitals. In the end of the year, the profit of A is Rs.200 more than the sum of the profits of B and C. Find the total profit?
A.3888
B.277
C.29889
D.3000
Answer: D.3000
Explanation: A:B:C = 5:6:4
Let the total profit = 100 - 30 = 70
5/15 * 70 = 70/3
A share = 70/3 + 30 = 160/3
B + C share = 100 - 160/3 = 140/3
A-(B+C) = 160/3 - 140/3 = 20/3
20/3 ---- 200
100 ---- ? => 3000
Answer: D
Question: A perfect square is defined as the square of an integer and a perfect cube is defined as the cube of an integer. How many positive integers n are there such that n is less than 5,000 and at the same time n is a perfect square and a perfect cube?
A.2
B.3
C.4
D.5
Answer: C.4
Explanation: If n is a perfect square and a perfect cube, then n = a^6 for some integer a.
The numbers are 1^6=1, 2^6=64, 3^6= 729, 4^6=4096.
The answer is C.
Question: If n is an integer and 101n^2 is less than or equal to 12100, what is the greatest possible value of n?
A.7
B.8
C.9
D.10
Answer: D.10
Explanation: 101 * n^2 <=12100
n^2 <=12100/101 which will be less than 121 since 12100/100 = 121 which is the square of 9
Next closest value of n where n^2<=121 is 10
Ans D
Question: The perimeter of a rectangular yard is completely surrounded by a fence that measures 14 meters. What is the length of the yard if the area of the yard is 6 meters squared?
A.8
B.6
C.2
D.4
Answer: B.6
Explanation: Perimeter of rectangular yard = 2(l + b) = 14 --> l + b = 7
Area = l * b = 6
b = 7 - l
l(7 - l) = 6
7l - l^2 = 6
l^2 - 7l + 6 = 0
Upon simplifying we get l = 1 or 6. Only 6 is there in the answer choice.
Answer: B
Question: Set X consists of all two-digit primes and set Y consists of all positive odd multiples of 7 less than 100. If the two sets are combined into one, what will be the range of the new set?
A. 84
B. 89
C. 90
D. 92
Answer: C. 90
Explanation: Set X = {11, 13, 17,............., 83, 89, 97}
Set Y = {7, 21, 35,..............., 77, 91,}
Combining two sets, say Set Z
Set Z = {7, 11, 13, 17,21,..................., 77, 83, 89, 91, 97}
Range = Max Value - Min Value
Range (Z) = 97 - 7 = 90
OA C is the answer.
Question: 75 apples on a scale weigh 18.035 kg. When 5 apples are removed from the scale, the average weight of the 70 apples is 240 grams. What is the average weight (in grams) of the 5 apples which were removed?
A.241
B.243
C.245
D.247
Answer: D.247
Explanation: 70*240=16800.
The other 5 apples weigh a total of 1235 grams.
The average weight is 1235/5 = 247 grams.
The answer is D.
Question: The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero ?
A.0
B.1
C.-1
D.-2
Answer: A.0
Explanation: Average of 20 numbers = 0.Sum of 20 numbers = (0 * 20) = 0.It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (- a). Answer : A
Question: The speed of a boat in upstream is 40 kmph and the speed of the boat downstream is 100 kmph. Find the speed of the boat in still water and the speed of the stream?
A.10 kmph
B.17 kmph
C.30 kmph
D.17 kmph
Answer: C.30 kmph
Explanation: Speed of the boat in still water
= (40+100)/2
= 70 kmph. Speed of the stream
= (100-40)/2
=30 kmph.
Answer: C
Question: The denominator of a fraction is 3 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction?
A.A)2/3
B.B)13/19
C.C)4/7
D.D)11/19
Answer: D.D)11/19
Explanation: Let the numerator and denominator of the fraction be 'n' and 'd' respectively.
d = 2n - 3
(n + 1)/(d + 1) = 3/5
5n + 5 = 3d + 3
5n + 5 = 3(2n - 3) + 3 => n = 11
d = 2n - 3 => d = 19
Hence the fraction is : 11/19
ANSWER:D
Question: A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
A.647
B.698
C.654
D.847
Answer: C.654
Explanation: S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Answer:C
Question: The average of first 13 natural numbers is?
A.5.2
B.5.5
C.7
D.9
Answer: C.7
Explanation: Sum of 13 natural no. = 182/2 = 91
Average = 91/13 = 7
Answer:C
Question: Four of the five parts numbered (a), (b), (c), (d) and (e) are exactly equal. Which of the parts is not equal to the other four? The number of that part is the answer.
A.40% of 160 + 1⁄3 of 240
B.120% of 1200
C.38 × 12 – 39 × 8
D.1648 – 938 – 566
Answer: B.120% of 1200
Explanation: Others are equal to 144 whereas (b) equals 1440.
Answer B
Question: In what ratio should a variety of Rice costing Rs. 7 per kg be mixed with another variety of Rice costing Rs. 14.50 per kg to obtain a mixture costing Rs. 9.75 per kg?
A.19:10
B.19 :11
C.11 :19
D.12 :18
Answer: B.19 :11
Explanation: Let us say the ratio of the quantities of cheaper and dearer varieties = x : y
By the rule of allegation, x/y = (14.50 - 9.75) / (9.75 - 7) = 31/15
ANSWER:B
Question: The sum of two numbers is 84, and one of them is 12 more than the other. What are the two numbers?
A.36-48
B.50-34
C.60-24
D.42-42
Answer: A.36-48
Explanation: In this problem, we are asked to find two numbers. Therefore, we must let x be one of them. Let x, then, be the first number.
We are told that the other number is 12 more, x + 12.
The problem states that their sum is 84:
word problem = 84
The line over x + 12 is a grouping symbol called a vinculum. It saves us writing parentheses.
We have:
2x = 84 − 12
= 72.
x = 72/2
= 36.
This is the first number. Therefore the other number is
x + 12 = 36 + 12 = 48.
The sum of 36 + 48 is 84.
Question: In a group of buffaloes and ducks, the number of legs are 24 more than twice the number of heads. What is the number of buffaloes in the group?
A.12
B.14
C.18
D.10
Answer: A.12
Explanation: Let the number of buffaloes be x and the number of ducks be y.
Then 4x+2y=2(x+y)+24
=>x=12
ANSWER A 12
Question: AB + CD = WWW, where AB and CD are two-digit numbers and WWW is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?
A. 1
B. 3
C. 7
D. 9
Answer: D. 9
Explanation: AB and CD are two digit integers, their sum can give us only one three digit integer of a kind of WWW it's 111.
So, A=1. 1B+CD=111
Now, C can not be less than 9, because no to digit integer with first digit 1 (mean that it's<20) can be added to two digit integer less than 90 to have the sum 111 (if CD<90 meaning C<9 CD+1B<111) --> C=9
Answer: D.
Question: A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 4. Find his average after 17th inning.
A.36
B.39
C.23
D.45
Answer: C.23
Explanation: Let the average after 17th inning = x.
Then, average after 16th inning = (x – 4).
∴ 16(x – 4) + 87 = 17x or x = (87 – 64) = 23.
Answer C
Question: Sujit incurred a loss of 45% on selling an article for Rs.3520/-. What was the cost price of the article?
A.Rs.5725/-
B.Rs.5080/-
C.Rs.6400/-
D.Rs.6750/-
Answer: C.Rs.6400/-
Explanation: Explanation:
45% loss means SP of Rs.3520/- is 55% of CP
:. CP = 3520x100/55 = Rs.6400/-
Answer: Option C
Question: What is the prime factors’ number of 12?
A.2
B.3
C.4
D.5
Answer: B.3
Explanation: prime factors’ number, as I assume, for a number X=a^n*b^m*c^o*d^p... is = n+m+o+p...
So, 24 = 2^2*3^1
prime factors’ number will be 2+1 = 3.
Hence, answer is B.
Question: A sum of Rs.4300 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
A.Rs.2520
B.Rs.3120
C.Rs.3320
D.Rs.2795
Answer: D.Rs.2795
Explanation: Let A be the amount received at the end of the three years.
A = 4300[1 + 10/100][1 + 20/100][1 + 25/100]
A = (4300 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.7095
So the interest = 7095 - 4300 = Rs.2795
ANSWER:D
Question: In a camp, there is a meal for 110 men or 200 children. If 140 children have taken the meal, how many men will be catered to with remaining meal?
A.41
B.30
C.35
D.33
Answer: D.33
Explanation: D
33
There is a meal for 200 children.
140 children have taken the meal.
Remaining meal is to be catered to 60 children.
Now, 200 children 110 men.
60 children = (110/200)x 60= 33 men.
Question: The average weight of 45 students in a class is 52 kg. 5 of them whose average weight is 48 kg leave the class and other 5 students whose average weight is 54 kg join the class. What is the new average weight (in kg) of the class ?
A.51 1⁄3
B.52 2⁄3
C.52 1⁄3
D.43.42
Answer: B.52 2⁄3
Explanation: Total weight of 45 students
= 45 × 52 = 2340 kg
Total weight of 5 students who leave
= 5 × 48 = 240 kg
Total weight of 5 students who join
= 5 × 54 = 270 kg
Therefore, new total weight of 45 students
= 2340 – 240 + 270 = 2370
⇒ New average weight = 2370⁄45 = 522⁄3 kg
Answer B
Question: Martha has 5 dogs and 4 cats. She takes each animal separately for a daily walk. She can take the animals for a walk to the park or to the barber shop. How many different options for a walk with a single animal does Martha have?
A.8
B.9
C.10
D.18
Answer: D.18
Explanation: 5 dogs, 4 cats; park/barber shop
1 dog - 2 options - either park or barber shop, so, 5 dogs - 10 options and 4 dogs - 8 options.
Total = 18 options.
ANS:D
Question: A retailer sold an appliance for $70. If the retailer's gross profit on the appliance was 25 percent of the retailer's cost for the appliance, how many dollars was the retailer's gross profit?
A.$14
B.$16
C.$20
D.$24
Answer: A.$14
Explanation: Gross Profit = Selling price - Cost = 70-x
70-x = 1/4x
x = 56
GP = 70-56 = 14
Question: What is the smallest integer a > 0 such that the inequality
1/n + 1
+
1/n + 2
+...+
1/2n + 1
< a - 2010-
1/3
is satisfied for all positive integers n?
A.2011
B.2012
C.2013
D.2014
Answer: B.2012
Explanation: Plugging in n = 1, we see that a > 2011. On the other hand, since there are n + 1
terms, and all of them are at most 1=(n + 1), the expression is at most 1, which means that
a = 2012 works.
correct answer B
Question: What is the rate percent when the simple interest on Rs.1200 amount to Rs.160 in 4 Years?
A.3.3%
B.7%
C.9%
D.2%
Answer: A.3.3%
Explanation: 160 = (1200*4*R)/100
R = 3.3%
Answer: A
Question: Convert the following unit:
2.1 hectares in ares
A.200 ares.
B.210 ares.
C.220 ares.
D.230 ares.
Answer: B.210 ares.
Explanation: 2.1 hectares in ares
1 hectare = 100 ares
Therefore, 2.1 hectares = 2.1 × 100 ares
= 210 ares.
ANSWER : OPTION B
Question: In a graduating class of 232 students, 144 took geometry and 119 took biology. What is the difference between the greatest possible number W and the smallest possible number of students that could have taken both geometry and biology?
A.144
B.119
C.113
D.88
Answer: D.88
Explanation: OFFICIAL SOLUTION:
First of all, notice that since 144 took geometry and 119 took biology, then the number of students who took both geometry and biology cannot be greater than 119.
{Total} = {geometry} + {biology} - {both} + {neither};
232 = 144 + 119 - {both} + {neither};
{both} = 31 + {neither}.
{both} is minimized when {neither} is 0. In this case {both} = 31.
The greatest possible number W of students that could have taken both geometry and biology, is 119.
Thus, the answer is 119 - 31 = 88.
Answer: D.
Question: In a bag there are a certain number of black balls and white balls. The probability of picking up exactly 1 white ball when 2 balls are randomly drawn, is 1/2. Which of the following is the ratio of the number of black balls to white balls in the bag
A.1:2
B.2:1
C.1:1
D.4:1
Answer: C.1:1
Explanation: since the probability of drawing a white ball out of two picks is 1/2.
the ratio of the white ball to black balls should be 1:1
C
Question: A person crosses a 600m long street in 5minnutes. What is his speed in km per hour?
A.5.8km/hr
B.7.2km/hr
C.9km/hr
D.2.5km/hr
Answer: B.7.2km/hr
Explanation: Speed = 600/5*60 = 2m/sec
=2*18/5
=7.2km/hr
Answer is B
Question: A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 440. What is the sum of the last 8 of the even integers?
A.568
B.584
C.596
D.604
Answer: A.568
Explanation: The sum of the first 8 numbers is: x + (x+2) +...+ (x+14) = 440
The sum of the next 8 numbers is: (x+16) + (x+2+16) +...+ (x+14+16) =
440 + 8(16) = 440 + 128 = 568
The answer is A.
Question: A train running at the speed of 60 km/hr crosses a pole in 6 seconds. What is the length of the train?
A.120 metres
B.180 metres
C.324 metres
D.100 metres
Answer: D.100 metres
Explanation: Speed=(60 x 5/18)/m/sec	=	50/3	m/sec.
Length of the train = (Speed x Time).
Length of the train =	50 x 6/3 m = 100 m.
ANSWER : OPTION D
Question: What is the solution of the equations x - y = 0.5 and 1(x + y)-1 = 2 ?
A.x = 0.5, y = 0
B.x = 1, y = 0.1
C.x = 2, y = 1.1
D.x = 1.2, y = 0.3
Answer: A.x = 0.5, y = 0
Explanation: Answer
x - y = 0.5 ...(i)
and 1(x + y)-1=2
⇒ 1/ (x + y) = 2
⇒ 2(x + y) =1
⇒ x + y = 1/2 ...(ii)
On solving Eqs.(i) and (ii),we get
x = 0.5
and y = 0
Correct Option: A
Question: In the graduating class of a certain college, 48 percent of the students are male and 52 percent are female. In this class 60 percent of the male and 20 percent of the female students are 25 years old or older. If one student in the class is randomly selected, approximately what is the probability that he or she will be less than 25 years old?
A.A)0.9
B.B)0.6
C.C)0.45
D.D)0.3
Answer: B.B)0.6
Explanation: Percent of students who are 25 years old or older is 0.6*48+0.2*52=~39, so percent of people who are less than 25 years old is 100-39=61.
Answer: B.
Question: The length of a rectangular floor is more than its breadth by 200%. If Rs. 324 is required to paint the floor at the rate of Rs. 3 per sq m, then what would be the length of the floor?
A.12
B.16
C.18
D.19
Answer: C.18
Explanation: Let the length and the breadth of the floor be l m and b m respectively.
l = b + 200% of b = l + 2b = 3b
Area of the floor = 324/3 = 108 sq m
l b = 108 i.e., l * l/3 = 108
l2 = 324 => l = 18.
Answer: C
Question: Find the cost of fencing around a circular field of diameter 42 m at the rate of Rs.5 a meter?
A.655.9
B.659.75
C.650.57
D.655.9
Answer: B.659.75
Explanation: 2 * 22/7 * 14 = 131.95
131.95 * 5 = Rs.659.75
Answer: B
Question: An man deposited $10000 in his bank account with a compound interest rate of 20%. How many years it will take to get the amount increased by 50%?
A.1
B.2
C.3
D.4
Answer: B.2
Explanation: 1 year: 100/4= $25: Total: 125
2nd year: 125/4 = $31: Total: 125+31= 156 >150
ANSWER:B - 2 years
Question: Susan weighs 15 pounds more than Anna does, and together they weigh a total of 145 pounds. Which of the following represents Anna’s weight in pounds?
A.60
B.65
C.63
D.64
Answer: B.65
Explanation: Total weight = 145
Anna's weight = 145-15 /2 = 65
Answer : B
Question: In expressing a length 81.479 km as nearly as possible with three significant digits, find the percentage error?
A.0.075%
B.0.156%
C.0.026%
D.0.048%
Answer: C.0.026%
Explanation: Error = 81.5-81.479 = 0.021
Required percentage = (0.021/81.479)*100 = 0.026%
Answer is C
Question: What is the Mode of the following data set S- {1,2,6,9,6,6,10}
A.9
B.6
C.10
D.1
Answer: B.6
Explanation: Mode of a set is the data point that is repeated the most number of times. In the set given, 6 is repeated.
Answer: B
Question: A rectangular photograph is surrounded by a border that is 1 inch wide on each side. The total area of the photograph and the border is M square inches. If the border had been 5 inches wide on each side, the total area would have been (M + 144) square inches. What is the perimeter of the photograph, in inches?
A.10
B.12
C.14
D.16
Answer: B.12
Explanation: Let x and y be the width and length of the photograph.
(x+2)(y+2)=M and so (1) xy + 2x + 2y + 4 = M
(x+10)(y+10)=M and so (2) xy + 10x + 10y + 100 = M+144
Let's subtract equation (1) from equation (2).
8x + 8y + 96 = 144
2x + 2y = 12, which is the perimeter of the photograph.
The answer is B.
Question: A family pays $800 per year for an insurance plan that pays 70 percent of the first $1,000 in expenses and 100 percent of all medical expenses thereafter. In any given year, the total amount paid by the family will equal the amount paid by the plan when the family's medical expenses total.
A.$1,000
B.$1,200
C.$1,400
D.$1,800
Answer: C.$1,400
Explanation: Upfront payment for insurance plan = 800$
Family needs to pay 30 % of first 1000 $ in expense = 300$
Total amount paid by family when medical expenses are equal to or greater than 1000 $ = 800 + 300 = 1100 $
Total amount paid by insurance plan for first 1000 $ = 800 $
Total amount paid by family will equal amount paid by plan when medical expense = 1400 $
(Since insurance plan will pay 100% of amount that exceeds 1100$ )
Answer C
Question: A man invested Rs. 1552 in a stock at 97 to obtain an income of Rs. 180. The dividend from the stock is :
A.7.5 %
B.8 %
C.11.25 %
D.None of these
Answer: C.11.25 %
Explanation: Solution
By investing Rs. 1552,income = Rs. 180.
By investing Rs. 97, income = Rs. (180/1552x97)= Rs.11.25
âˆ´ Dividend = 11.25%.
Answer C
Question: A box contains 12 mangoes out of which 4 are spoilt. If four mangoes are chosen at random, find the probability that A number is selected at random from first thirty natural numbers. What is the chance that it is a multiple of either 3 or 13?
A.17/30
B.2/5
C.11/30
D.4/15
Answer: B.2/5
Explanation: The probability that the number is a multiple of 3 is 10/30. (Since 3*10 = 30).
Similarly the probability that the number is a multiple of 13 is 2/30. {Since 13*2 =
26).
Neither 3 nor 13 has common multiple from 1 to 30. Hence these events are mutually exclusive events. Therefore chance that the selected number is a multiple of 3 or 13 is (10+2)/30 = 2/5.
ANSWER:B
Question: What is the sum of the different positive prime factors of 600?
A.5
B.7
C.10
D.17
Answer: C.10
Explanation: The prime factorization of 600
= 60 * 10
= 2^2*15 * 2*5
= 2^2*3*5 * 2*5
The sum of the different positive prime factors = 2+3+5 = 10
The answer is C.
Question: It is the New Year and Mandy has made a resolution to lose weight this year. She plans to exercise and do yoga. For exercise she plans to workout at the gym and ride her bicycle in the ratio of 2:3 everyday. She will also do yoga in the ratio, yoga:exercise = 2:3. If she rides her bike for 18 minutes, how much time will she spend doing yoga? (rounded to minutes)
A.30 min.
B.41 min.
C.17 min.
D.23 min.
Answer: A.30 min.
Explanation: The ratio is 2:3 = gym:ride, so (18)(3/2) = 27 minutes at the gym, and 27 + 18 = 45 minutes exercise, so (2/3)(45) = 30 minutes yoga.
Answer: A
Question: One boy forgot the last digit of a 7 digit telephone no. If he randomly dialthe final 3 digits after correctly dialing the 1st four, then what is the chance of dialing the correct no.?
A.1/500
B.2/455
C.1/1000
D.3/1000
Answer: C.1/1000
Explanation: it is given that last 3 digits are randomly dialed
Then, each of the digit can be selected out of 10 digits in 10 ways. Hence, required probability
= 1/(10)3 = 1/1000
C
Question: A rectangular window is twice as long as it is wide. If its perimeter is 14 feet, then what are its dimensions in feet?
A.3/2 by 7/2
B.7/3 by 14/3
C.2 by 4
D.3 by 6
Answer: B.7/3 by 14/3
Explanation: Let x be the width of the window. Then the length is 2x.
x+2x+x+2x = 14
6x = 14
x = 14/6 = 7/3
The width is 7/3 and the length is 14/3.
The answer is B.
Question: A certain sum amounts to Rs.1525 in 3 years and Rs.1875 in 5 years. Find the rate % per annum?
A.6.76%
B.3.76%
C.5.26%
D.5.76%
Answer: D.5.76%
Explanation: 3 --- 1525
5 --- 1875
--------------
2 --- 350
N = 1 I = 75 R = ?
P = 1525 - 225 = 1300
75 = (1300*1*R)/100
R = 5.76%
ANSWER:D