RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
A.210
B.1050
C.25200
D.21400
Answer: C.25200
Explanation: Solution
Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)
7C3x 4C2 = ( 7x 6x5/3x2x1x 4x 3/2x1 ) = 210
Number of group,each having 3 consonants and 2 vowels = 201 .
Each group contains 5 letter.
Number of ways of arranging 5 letters among themselves
= 5 ! = (5 × 4 × 3 × 2 × 1) = 120 .
So, Required number of words = (210 × 120) = 25200 .
Answer C
Question: In how many ways can a cricket eleven be chosen out of a batch of 15 players.
A.1523
B.1365
C.1234
D.4512
Answer: B.1365
Explanation: Required number of ways
= 15C 11 = 15C (15-11)
= 15 C 4
15C4 = 15 * 14 * 13 * 12 / 4 * 3 * 2 *1
= 1365
Ans: B
Question: At what price must an article costing Rs.47.50 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price?
A.62.5
B.62.9
C.62.6
D.62.1
Answer: A.62.5
Explanation: CP = 47.50
SP = 47.50*(125/100) = 59.375
MP*(95/100) = 59.375
MP = 62.5
Answer: A
Question: Jill is dividing her six-person class into two teams of equal size for a basketball game. If no one will sit out, how many different match-ups between the two teams are possible?
A.10
B.25
C.126
D.252
Answer: A.10
Explanation: With 6 players, the process of figuring out how many groups of 3 can be formed is pretty straight-forward....
6C3 = 6!/(3!3!) = 20 possible groups of 3
Once forming that first group of 3, the remaining 3 players would all be placed on the second team by default.
The 'twist' is that the two teams of 3 canshow upin either order:
A
Question: The compound interest on a sum of money for 2 years is rs.832 and the simple interest on the same sum for the same period is rs.800 .the difference between the compound interest and simple interest for 3 years
A.98.5
B.08.56
C.98.56
D.98.86
Answer: C.98.56
Explanation: Explanation:
difference in C.I and S.I in 2years =Rs.32
S.I for 1year =Rs.400
S.I for Rs.400 for one year =Rs.32
rate=[100*32)/(400*1)%=8%
difference between in C.I and S.I for 3rd year
=S.I on Rs.832= Rs.(832*8*1)/100=Rs.66.56
Answer: C) Rs.98.56
Question: If 5% more is gained by selling an article for Rs. 220 than by selling it for Rs. 160, the cost of the article is?
A.127
B.1200
C.1600
D.1400
Answer: B.1200
Explanation: Let C.P. be Rs. x.
Then, 5% of x = 220 - 160= 60
x/20 = 60 => x = 1200
Answer: B
Question: Ram paid a sum of money for purchasing 25 pens, which he recovered in full when he sold 10 of them. What was his percentage of profit or loss per pen?
A.80%
B.125%
C.100%
D.70%
Answer: B.125%
Explanation: B
125%
If the sum he paid whilst purchasing 25 pens = A,
Then the Cost Price of each pen = A/25.
Since the amount he got whilst selling 10 pens is also = A
Then the Selling Price of each pen = A/10.
Since Selling Price > Cost Price, he made a profit.
Profit per pen = Selling Price - Cost Price = A/10 - A/25 = 3A/50.
Profit percentage per pen = Profit per pen / Cost per pen x 100 = (3A/60) / (A/25) x 100 = 125%. Answer :B
Question: In a group of hats consisting of only blue hats, green hats, and purple hats, the ratio of blue hats to green hats to purple hats is 7:4:12. If there are a total of 46 hats in this group, how many of these hats are not blue?
A.28
B.42
C.48
D.32
Answer: D.32
Explanation: Since the hats Blue, Green and Purple are in ratio of 7:4:12...The total no. of balls will be
7x+4x+12x=46 or 23x=46...here 7x,4x and 12x represent hats of each type
23x=46 so x=2...Blue hats =7*2=14...Not blue will be 46-14=32.
Ans D
Question: The 8 spokes of a custom circular bicycle wheel radiate from the central axle of the wheel and are arranged such that the sectors formed by adjacent spokes all have different central angles, which constitute an arithmetic series of numbers (that is, the difference between any angle and the next largest angle is constant). If the largest sector so formed has a central angle of 80°, what fraction of the wheel’s area is represented by the second smallest sector?
A.1/72
B.1/36
C.1/18
D.1/12
Answer: C.1/18
Explanation: Its an AP question .... it is given clearly in the question .
Let the smallest angle be a
and the circle has 8 sectors and hence 8 angle with a common difference d
hence all the angles can be written in AP form with Cd as d ,
a, a+d, a+2d, a+3d ,a+4d, a+5d, a+6d ,a+7d,
given that a+7d = 80 --------1
also
a + a+d + a+2d + a+3d +
a+4d + a+5d + a+6d + a+7d = 360 ( as sum of all the angle is 360)
which is 8a + 28d = 360 --------2
solving 1 and 2
we get a=10
We are almost done ,
now the question ask what fraction of the wheel’s area is represented by the smallest sector ?
(20/360)( pie r*r)/ (pie r*r) = 20/360= 1/18
C ans ....
Question: A student worked for 20 days. For each of the amounts shown in the first row of the table, the second row gives the number of days that the student earned that amount. What is the total amount of money that the students earned for the 16 days?
Amounts earned per day : $96 $84 $80 $70 $48
Number of days : 4 7 4 3 2
A.(1) $320
B.(2) $210
C.(3) $284
D.(4) $282
Answer: D.(4) $282
Explanation: 4+7+4+3+2 = 20
The series is as follows. Arrange the terms in increasing order of amounts earned and cumulatively add up the number of days of each amount.
1st to 2nd term = 48 (2 days)
3rd to 5th term = 70 (3 days)
6th to 9th term = 80 (4 days)
10th to 16th term = 84 (7 days)
total amount earned = 48+70+80+84
= 282
Pick D
Question: Of the female students at Barkely University, 5/6 are on the honor roll. Of the male students, 2/3 are on the honor roll. If 2/5 of the students are female, what fraction of all the students are on the honor roll?
A.5/9
B.3/15
C.23/30
D.22/30
Answer: D.22/30
Explanation: let the total students be 30
given 2/5 of the students are females = 12
then males = 3/5 = 18
5/6 of the females are on honor roll = 10
males on the honor roll = 2/3= 12
total students on honor roll = 12+10 =22
fraction = 22/30
D
Question: A man in a train notices that he can count 51 telephone posts in one minute. If they are known to be 100 metres apart, then at what speed is the train travelling?
A.250km/hr
B.150km/hr
C.225km/hr
D.300km/hr
Answer: D.300km/hr
Explanation: Number of gaps between 51 telephone posts = 50
distance travelled in 1 minute = 100*50 = 5000m = 5km
speed = 300km/hr
Answer is D
Question: The average of 13 numbers is 60. Average of the first 7 of them is 57 and that of the last 7 is 61. Find the 8th number?
A.46
B.77
C.88
D.544
Answer: A.46
Explanation: Sum of all the 13 numbers = 13 * 60 = 780
Sum of the first 7 of them = 7 * 57 = 399
Sum of the last 7 of them = 7 * 61 = 427
So, the 8th number = 427 + 399 - 780 = 46.
Answer: A
Question: Linda and Angela contract to paint a neighbor's house. Even though Linda
spends 25% more time painting the house than Angela, each receives a payment
of m dollars when the work is completed. If Angela decides to pay Linda n
dollars so that they would have received the same compensation per hour
worked, what is n in terms of m?
A.A)(1/2)m
B.B)(1/9)m
C.C)(1/4)m
D.D)(1/5)m
Answer: B.B)(1/9)m
Explanation: let angela work for 8hrs and get 900 rs. (m =900)
According to question, linda works 25% more time and gets the same amount. so let linda work 10 hrs and get 900 rs.
so they do a total of 10 +8 =18 hrs of work and get 1800 rs together . The question basically asks to equalise their payment. so a total of 1800 rs is received by them and they do 18 hrs work together. average rate will be 1800/18 = 100 rs per hr. so linda should get 10*100 =1000 rs. But she got only 900. so angela should give 100 rs to linda. answer = 100/900 =1/9
answer B
Question: A certain company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio W of revenue from car sales in 1996 to revenue from truck sales in 1996?
A. 1:2
B. 4:5
C. 1:1
D. 3:2
Answer: A. 1:2
Explanation: A.. I have probably solved this question 3-4 times by now.. Remember the answer.. 1:2
Question: On Thursday Mabel handled 90 transactions. Anthony handled 10% more transactions than Mabel, Cal handled 2/3rds of the transactions that Anthony handled, and Jade handled 16 more transactions than Cal. How much transactions did Jade handled?
A.56
B.35
C.82
D.89
Answer: C.82
Explanation: C
82
Mabel handled 90 transactions
Anthony handled 10% more transactions than Mabel
Anthony = 90 + 90 × 10%
= 90 + 90 × 0.10
= 90 + 9
= 99
Cal handled 2/3rds of the transactions than Anthony handled
Cal = 2/3 × 99
= 66
Jade handled 16 more transactions than Cal.
Jade = 66 + 16
= 82
Jade handled = 82 transactions.
Question: Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 1500. What is their H.C.F.?
A.5
B.15
C.25
D.35
Answer: C.25
Explanation: Let the numbers be 3x, 4x and 5x.
Then, their L.C.M. = 60x
60x = 1500
x = 25
The numbers are (3 x 25), (4 x 25) and (5 x 25).
The H.C.F. is 25.
The answer is C.
Question: (1000)7÷(10)15=?
A.10
B.100
C.1000000
D.10000
Answer: C.1000000
Explanation: Explanation:
=(103)7/(10)15
=(10)21/(10)15=10(6)=1000000
Option C
Question: If e > a and L < a, which of the following cannot be true?
A. d + L = 14
B. d - L = 7
C. d - L = 1
D. a - e = 9
Answer: D. a - e = 9
Explanation: Is the answer D?
If e>a, then e-a>0 (always positive). The converse would be a-e<0 (always negative). Option D states that a-e=9, which can never be true.
Question: A bag contains a certain number of 50 paise coins, 20 paise coins and 10 paise coins inthe ratio 2:3:4. If the total value of all the coins in the bag is Rs.400, find the number of coins of each kind?
A.50p coins = 400 20p coins = 600 10p coins = 800
B.50p coins = 300 20p coins = 700 10p coins = 200
C.50p coins = 800 20p coins = 400 10p coins = 200
D.50p coins = 400 20p coins = 500 10p coins = 300
Answer: A.50p coins = 400 20p coins = 600 10p coins = 800
Explanation: 50*2k + 20*3k + 10*4k = 40000
200k = 40000 => k = 200
50p coins = 2k = 2*200 = 400
20p coins = 3k = 3*200 = 600
10p coins = 4k = 4*200 = 800
Answer:A
Question: The difference between a number and its two-fifth is 510. What is 10% of that number?
A.12.75
B.85
C.204
D.250
Answer: B.85
Explanation: Explanation:
Let the number be x. Then,
x - 2/5 x = 510
x = (510 * 5)/3 = 850
10% of 850 = 85.
Answer IS B
Question: Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 8 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B?
A.64%
B.80%
C.100%
D.120%
Answer: A.64%
Explanation: For A, r=8/2pi. Its capacity = (4pi)^2 * 8= 128pi
For B, r=10/pi. Its capacity = (5pi)^2 *8 = 200pi
A/B = 128pi/200pi = 0.64
A
Question: In a recent election, James received 0.5 percent of the 2,000 votes cast. To win the election, a candidate needed to receive more than 45 percent of the vote. How many additional votes would James have needed to win the election?
A.901
B.989
C.990
D.891
Answer: D.891
Explanation: James = (0.5/100)*2000 = 10
Votes to win = (45/100)*Total Votes +1 = (45/100)*2000 +1 = 901
Remaining Voted needed to win election = 901 - 10 = 891
Answer: option D
Question: A freight elevator can carry a maximum load of 1300 pounds. Sean, who weighs 200 pounds, is in the elevator with two packages weighing 150 pounds and 280 pounds. If he needs to fit three more packages in the elevator that weigh as much as possible without exceeding the elevator limit, what is the difference between their average and the average of the two packages already in the elevator?
A.8
B.85
C.190
D.215
Answer: A.8
Explanation: The average of existing 2 package is150 + 280/2 = 430/2 = 215
Remaining allowed weight = 1300 - 200 - 430 = 670.
allowed per package = 670 / 3 =223
So difference in average of existing and allowable = 223-215 = 8
Hence A
Question: Two teams are distributing information booklets. Team A distributes 60% more boxes of booklets than Team W, but each box of Team A’s has 60% fewer booklets than each box of Team W’s. Which of the following could be the total number of booklets distributed by the two groups?
A.2,000
B.3,200
C.4,100
D.4,800
Answer: C.4,100
Explanation: Let x be the no of booklets in each box that team W distributes. So, Team A has 60% fewer - 0.4x.
Let y be the no. of boxes distributed by team W. So, Team A distributes 60% more - 1.6y
Total booklets distributed by team A = xy
Total booklets distributed by teamW=0.64xy
Total booklets distributed = xy+0.64xy=1.64xy
As no. of booklets can only be integer, plugging the answer choice equal to 1.64xy should give an integer.
Choice A - 1.64xy=2000; xy=2000/1.64 = doesn't provide an integer value.
Similarly all answer choices, except choice C, fail to provide an integer value.
Choice C = 4100/1.64= 2500 and is the correct answer.
Question: Wn = 2Wn-1 + 4 and Qn = 4Qn-1 + 8 for all n > 1. If W5 = Q4 and W7 = 316, what is the first value of n for which Qn is an integer?
A. 1
B. 2
C. 3
D. 4
Answer: C. 3
Explanation: Assuming I have understood the symbols used correctly answer is C- 3
W7 = 2S6 +4 = 316
W6 = 312/2 = 156 = 2W5 + 4
W5 = 152/2 = 76 = Q4
Q4 = 4Q3 + 8 = 76
Q3 = 68/4 = 17
Q3 = 4Q2 + 8 = 17
Q2 = 9/4 = 2.25
Q2 = 4Q1 + 8
Q1 will not be integer
Question: Harold works at a resort from the beginning of March to the end of September. During the month of August this past year, he made 4 times the average (arithmetic mean) of his monthly totals in tips for the other months. His total tips for August were what fraction of his total tips for all of the months he worked?
A.1/3
B.2/5
C.3/7
D.1/2
Answer: B.2/5
Explanation: The time from beginning of March to the end of September is 7 months.
If x is the average monthly tip for all months other than August then his August month tip will be 4*x
His total tip for the 7 months = 6*(average tip for the months other than August) + 4x
=10x
August tips as a fraction of total tips = 4x/10x =2/5. So B
Question: Angela has 11 pairs of matched socks. If she loses 7 individual socks, which of the following is NOT a possible number of matched pairs she has left?
A.8
B.9
C.10
D.11
Answer: A.8
Explanation: I think if Angela loses 7 individual socks,then she is bound to have lost minimum of 3 pairs and 1 individual sock,in this way she is left with only 7 pairs of socks (11-(3+1)).
Hence,8 cannot be the answer as maximum is 7.
Hence, option (A)
Question: Akash will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him or her. How many such arrangements of the 6 people are possible?
A.5
B.6
C.9
D.24
Answer: A.5
Explanation: Akash will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing is standing in front of someone in the second row. person with max height is in the second row, person with min height is in the first row. We need to select 1 person in the middle of each row... In the middle of the first row we can put only 2, 3 or 4. In the middle of the second row we can put only 3, 4, 5. If we select {3 in the sec. row, 2 in the first}, {4,2}, {5,2}, {4,3}, {5,3}, {5,4}. So, there are 0*1 + 1*1 + 2*1 + 1*1 + 1*1 + 0*1 = 5 cases...A
Question: In covering a distance of 60 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:
A.5 km/h
B.8 km/h
C.10 km/h
D.15 km/h
Answer: C.10 km/h
Explanation: Let A's speed be X km/hr.
Then, 60/x - 60/2x = 3
30/x = 3
x = 10 km/hr.
Answer : C
Question: What percent is 2 minutes 24 seconds of an hour?
A.6%
B.2%
C.4%
D.8%
Answer: C.4%
Explanation: 2mt 24s =144s
144*100/60*60=4%
ANSWER:C
Question: In how many different ways can the letters A, A, B, B, B, C, D, E be arranged if the letter C must be to the right of the letter D?
A.1680
B.2160
C.2520
D.3240
Answer: A.1680
Explanation: We have 8 letters out of which A appears twice and B appears three time. Total number of permutation of these letters (without restriction) would be: 8!/2!3!=3360
Now, in half of these cases D will be to the right of C and in half of these cases to the left, hence the final answer would be 3360/2=1680
Answer: A.
Question: Smitty Farm picks 9866 cherries a day. If Smitty distributes their apples evenly across 9 different retail shops, how many cherries would remain with him.
A.1 cherry
B.7 cherry
C.2 cherry
D.4 cherry
Answer: B.7 cherry
Explanation: This is equivalent to finding the first number that is divisible by 9 that occurs before 9,866.
In order to divide the sum in 9 parts, the amount must be divisible by 9
Divisibility rule of 9: The sum of the digits must be divisible by 9
Sum of digits of 9+8+6+6 = 29. If we add 7, then it is divisible by 9.
Hence, we need to add 7 to this number for it to be divisible by 9
Correct Option : B
Question: It rained as much as on Wednesday as on all the other days of the week combined. If the average rainfall for the whole week was 4 cms, How much did it rain on Wednesday?
A.14
B.10.5
C.10.2
D.10.1
Answer: A.14
Explanation: Explanation:
Let the rainfall on wednesday = 6x.
âˆ´ Rainfall on the remaining days = 6x
Given,
(6x + 6x )/7 = 4
â‡’12x = 28
â‡’6x = 14
Answer: A
Question: Find the next number in the Sequence
2, 9, 30, 65,?
A.114
B.165
C.167
D.122
Answer: A.114
Explanation: +7 =>9
+21 =>30
+35 =>65
+49 =>114
Answer is A
Question: Of the 3,600 employees of Company X, 1/4 are clerical. If the clerical staff were to be reduced by 1/4, what percent of the total number of the remaining employees would then be clerical?
A.25%
B.22.2%
C.20%
D.12.5%
Answer: C.20%
Explanation: Let's see, the way I did it was
1/4 are clerical out of 3600 so 900 are clerical
900 reduced by 1/4 is 900*1/4
so it reduced 225 people , so there is 675 clerical people left
but since 225 people left, it also reduced from the total of 3600 so there are 3375 people total
since 675 clerical left / 3375 people total
you get (C) 20%
Question: Prathik purchased 40 shirts for rs 3000.he spends 10% for transportation. What should be the selling price per shirt to earn profit of 20% ?
A.96 rs
B.97 rs
C.98 rs
D.99 rs
Answer: D.99 rs
Explanation: total CP = 3000 + 3000*10/100 = 3300
to gain 20% profit, SP = (100+20)*3300/100 = 3960
selling price per shirt = 3960/40 = 99 rs/shirt
ANSWER:D
Question: How many five-digit numbers that do not contain the digits 4 or 7 are there?
A.44648
B.27844
C.28642
D.16864
Answer: C.28642
Explanation: We can have 7 digits ( 1,2,3,5,6,8,9) for the first place ( ten thousand's place).
and similarly 8 digits for thousand's, hundred's, tenth's and unit digit. ( 0,1,2,3,5,6,8,9)
So in total 7*8*8*8*8= 28672
Hence C
Question: The slant height of a cone is 15 cm and radius of the base is 3cm, find the curved surface of the cone?
A.26
B.134
C.141
D.190
Answer: C.141
Explanation: π * 15 * 3
= 141
Answer:C
Question: If 3 boys can do 3 times of a particular work in 3 days, then, 7 boys can do 7 times of that work in?
A.days
B.days
C.days
D.days
Answer: B.days
Explanation: That is, 1 boys can do one time of the work in 3 days.
Therefore, 7 boys can do 7 times work in the same 3 days itself.
B)
Question: In an election contested by two parties, Party B secured 20% of the total votes more than Party C. If party C got 144,000 votes, by how many votes did it lose the election?
A.14,000
B.72,000
C.78,000
D.24,000
Answer: B.72,000
Explanation: B + C = 100 ---- (1)
B - C = 20 ---- (2)
Solving (1) and (2) B = 60% and R = 40%
40% of Total = 144000
Total = 360000
B = 216000
Difference = 216000 - 144000 = 72000
Answer: B
Question: A cistern has a leak which would empty the cistern in 20 minutes. A tap is turned on which admits 4 liters a minute into the cistern, and it is emptied in 24 minutes. How many liters does the cistern hold?
A. 480 liters
A.480
B.489
C.486
D.482
Answer: A.480
Explanation: 1/x - 1/20 = -1/24
x = 120
120 * 4 = 480
Answer: A
Question: Tough and Tricky questions: Coordinate Geometry.
Line L contains the points (2,3) and (p,a). If a = 2, which of the following could be the equation of line m, which is perpendicular to line L?
A. 2x + y = px + 7
B. 2x + y = –px
C. x + 2y = px + 7
D. y – 7 = x ÷ (p – 2)
Answer: A. 2x + y = px + 7
Explanation: we need m=p-2, so we should gety=mx+bform in answer choices
(A) 2x+y=px+7 => y=px-2x+7 => y=x(p-2)+7. It is what we need
(B) 2x + y = –px => y=-px-2x => y=x(-p-2). Wrong
(C) x + 2y = px + 7 => y=x(p-1/2)+7/2. Wrong
(D) y – 7 = x ÷ (p – 2) => y=(1/p-2)x+7. Wrong
(E) 2x + y = 7 – px => y=-px-2x+7 => y=x(-p-2)+7. Wrong
A=Answer
Question: Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in scheme B?
A.6400
B.2878
C.2899
D.2660
Answer: A.6400
Explanation: Let the sum invested in scheme A be Rs. x and that in scheme B be Rs. (13900 - x). Then,
(x * 14 * 2)/100 + [(13900 - x) * 11 * 2]/100 = 3508
28x - 22x = 350800 - (13900 * 22)
6x = 45000 => x = 7500
So, sum invested in scheme B = (13900 - 7500) = Rs. 6400.Answer:A
Question: A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?
A.111.12 m
B.111.13 m
C.117.12 m
D.111.92 m
Answer: A.111.12 m
Explanation: A runs 1000 m while B runs 900 m and C runs 800 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 800)/900 = 8000/9 = 888.88 m.
B can give C = 1000 -888.88 =111.12 m.
Answer:A
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
A.65 km/hr
B.50 km/hr
C.76 km/hr
D.56 km/hr
Answer: B.50 km/hr
Explanation: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 => x = 50 km/hr.
Answer:B
Question: 1,2,4,7,_,16
A.11
B.9
C.10
D.12
Answer: A.11
Explanation: Each new number is the same as the last number with the adder growing by 1. This would yield 11.
Question: Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 3 hours to complete the journey. If the distance between City A and City B is 600 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)
A.2/1
B.3/8
C.8/5
D.5/8
Answer: A.2/1
Explanation: Distance traveled by Eddy = 600 km
Time taken by Eddy = 3 hours
Average speed of Eddy = 600/3 = 200 km/hour
Distance traveled by Freddy = 300 km
Time taken by Freddy = 3 hours
Average speed of Freddy = 300/3 = 100 km/hour
Ratio of average speed of Eddy to Freddy = 200/100 = 2/1
Answer A
Question: In a rectangular coordinate system, what is the area of a rhombus whose vertices have the coordinates (0, 3.5), (9, 0), (0, -3.5), (-9, 0)?
A.63
B.88
C.112
D.116
Answer: A.63
Explanation: Ares of rhombus= 1/2* D1 *D2
Length of 1st diagonal = 9+9= 18
Length of 2nd diagonal= 3.5+3.5= 7
Area= 1/2*18*7= 63
A is the answer
Question: A woodworker normally makes a certain number of parts in 24 days. But he was able to increase his productivity by 5 parts per day, and so he not only finished the job in only 22 days but also he made 80 extra parts. How many parts does the woodworker normally makes per day and how many pieces does he make in 24 days?
A.360
B.350
C.340
D.370
Answer: A.360
Explanation: Let x be the number of parts the woodworker normally makes daily. In 24 days he makes 24⋅x pieces. His new daily production rate is x+5 pieces and in 22 days he made 22⋅(x+5) parts. This is 80 more than 24⋅x. Therefore the equation is:
24⋅x+80=22(x+5)
30=2x
x=15
Normally he makes 15 parts a day and in 24 days he makes 15⋅24=360 parts.
So answer is A.