RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Two trains run in opposite directions on a circular track. Train Q travels at a rate of 4π miles per hour and Train B runs at a rate of 6π miles per hour. If the track has a radius of 6 miles and the trains both start from Point S at the same time, how long, in hours, after the trains depart will they again meet at Point S?
A.3
B.6
C.9
D.18
Answer: B.6
Explanation: I don't agree with your solutions, first. And second the answer choices don't seem to contain the right answer.
My solution is as follows, and I ask anyone to correct me if I am wrong.
Solution 1
Let the distance covered by train Q be X, thus that covered by the train B will be 12*3.14-X
dQ = X dB = 12*3.14 - X
Times taken by A and B are
tQ= X/4*3.14 , tB = (12*3.14 - X)/6*3.14 (ii)
Since they have been traveling for the same period of time, then
X/4*3.14 = (12*3.14 - X)/6*3.14
X/2 =(12*3.14 -X)/3
3X = 2(12*3.14 -X)
5X = 24*3.14
X = 24*3.14/5
Plugging that in either equation of (ii) yields t = 6/5
Solution 2
We add the speed of Q and B: totalSpeed = 4*3.14 + 6*3.14 = 10*3.14
Total distance covered = 12*3.14
t ime = distance / speed = 12*3.14/10*3.14 = 6/5.
tQ =( X/4*3.14) =(24*3.14/5)/4*3.14 = 6/5.
Question: Complete the numerical series by replacing the question mark with the correct numbers.
5+3+2 = 151022
9+2+4 = 183652
8+6+3 = 482466
5+4+5 = 202541
9+5+5 = ??????
A.454584
B.454585
C.454586
D.454587
Answer: B.454585
Explanation: Solution:
454585
Explanation:
Number is formed as (numA*numB)(numB*numC)(numC*numA)
Following the formular, 1st row will be like
5+3+2 => 5*3 3*2 2*5 => 151022
Simillarly
(9*5)(9*5)(9*5+9*5-5) => 454585
Answer B
Question: Three 6 faced dice are thrown together. The probability that no two dice show the same number on them is
A.5/1
B.5/9
C.5/8
D.5/6
Answer: B.5/9
Explanation: No two dice show same number would mean all the three faces should show different numbers. The first can fall in any one of the six ways. The second die can show a different number in five ways. The third should show a number that is different from the first and second. This can happen in four ways.
Thus 6 * 5 * 4 = 120 favourable cases.
The total cases are 6 * 6 * 6 = 216.
The probability = 120/216 =5/9.
Answer:B
Question: If 12 machine can finish a job in 40 days, then how many more machines would be needed to finish the job in one -fourth less time?
A.a. 4
B.b. 8
C.c. 10
D.d. 12
Answer: A.a. 4
Explanation: You might think of this in a management context - we can use the principle of 'person-hours' to solve any problem where we have identical workers. So, using simpler numbers, suppose you know that 6 identical employees, working simultaneously, would finish a job in 5 hours. Then that job requires 6*5 = 30 total hours of person-work. If instead you wanted the job done in 3 hours, you'd assign 30/3 = 10 employees to do the job, because you want to get a total of 30 hours of work from the employees.
We can solve this problem identically. If 12 machines (identical ones, I assume) work simultaneously for 40 days, they will do a total of 12*40 machine-days of work. So the job requires 12*40 days of machine work in total. We instead want the job done in 1/4 less time, so in 30 days. So we'll need 12*40/30 = 16 machines, or 4 additional machines.
A
Question: In 1985 a company sold a brand of shoes to retailers for a fixed price per pair. In 1986 the number of pairs of the shoes that the company sold to retailers decreased by 20 percent, while the price per pair increased by 20 percent. If the company’s revenue from the sale of the shoes in 1986 was $3.0 million, what was the approximate revenue from the sale of the shoes in 1985 ?
A.$2.4 million
B.$2.9 million
C.$3.0 million
D.$3.1 million
Answer: D.$3.1 million
Explanation: Let the number of pairs of shoes sold in 1985 = N
let price per pair of shoe sold in 1985 = P
In 1986,number of pairs of shoes sold decreased by 20 % = .8N
Price per pair increased by 20% = 1.2P
Company's revenue from sale of shoes in 1986 = 3 million$
=> .8N * 1.2 P = 3
=>.96 NP = 3
=> NP = 3/.96 = 3.125 million $
Answer D
Question: If E is an integer greater than 6, which of the following must be divisible by 3?
A.E(E+1)(E-4)
B.N(N+2)(N-1)
C.N(N+3)(N-5)
D.N(N+4)(N-2)
Answer: A.E(E+1)(E-4)
Explanation: Now take E = 3k , E = 3k+1 E = 3k+2..put in all the choices. If by putting all the values of E we get it is divisible by 3, then it is correct answer choice.
A is correct. It will hardy take 10 sec per choice as we have to consider only 3k+1 and 3k+2.
Question: The length of the bridge, which a train 140 metres long and travelling at 45 km/hr can cross in 30 seconds, is?
A.76 m
B.178 m
C.235 m
D.187 m
Answer: C.235 m
Explanation: Speed = [45 X 5/18] m/sec
= [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (140 + x)/30 = 25/2
=> 2(140 + x)= 750 => x = 235 m.
Answer: C
Question: For how many unique pairs of nonnegative integers {a, b} is the equation a^2 - b^2 = 45 true?
A.1
B.3
C.5
D.7
Answer: B.3
Explanation: Answer B
(a+b)(a-b)=45
3cases For (a+b), (a-b)
45, 1
15, 3
9, 5
Answer B
Question: The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit?
A.3000
B.1230
C.2000
D.5600
Answer: C.2000
Explanation: C
C.P. be Rs. x.
Then, (1920 - x)/x * 100 = (x - 1280)/x * 100
1920 - x = x - 1280
2x = 3200 => x = 1600
Required S.P. = 125 % of Rs. 1600 = 125/100 * 1600 = Rs. 2000.
Question: A bag contains 6 red, 5 blue and 2 green balls. If 2 ballsare picked at random, what is the probability that both are red?
A.1/25
B.2/21
C.5/26
D.3/41
Answer: C.5/26
Explanation: P(Both are red),
=6C213C2=6C213C2
=5/26
C
Question: A and B’s salaries together amount to Rs. 2,000. A spends 95% of his salary and B spends 85% of his. If now their savings are the same, what is B’s salary?
A.777
B.500
C.789
D.776
Answer: B.500
Explanation: (5/100) A = (15/100) B
A = 3B
A + B = 2000
4B = 2000 => B = 500
Answer B
Question: Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 450 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)
A.8/3
B.2
C.8/5
D.5/8
Answer: B.2
Explanation: Distance traveled by Eddy = 450 km
Time taken by Eddy = 3 hours
Average speed of Eddy = 450/3 = 150 km/hour
Distance traveled by Freddy = 300 km
Time taken by Freddy = 4 hours
Average speed of Freddy = 300/4 = 75 km/hour
Ratio of average speed of Eddy to Freddy = 150/75 = 2
Answer B
Question: What is x if x + 2y = 10 and y = 3?
A.10
B.8
C.6
D.4
Answer: D.4
Explanation: Substitute y by 3 in x + 2y = 10
x + 2(3) = 10
x + 6 = 10
If we substitute x by 4 in x + 6 = 10, we have 4 + 6 = 10.
x = 4
correct answer is D) 4
Question: A factory has a fixed cost of $35,000 a month, and a cost of $2.5 for every item produced. If the selling price of a single item is $5, what is the number of items must be sold monthly for the factory to cover its cost exactly?
A.9,000
B.14,000
C.18,000
D.22,500
Answer: B.14,000
Explanation: selling price - Cost price = 2.5 so per unit profit =2.5
cost to recover =35000
no of items required = 35000/2.5 = 14000
Ans B
Question: A deer is standing 60 meters in from the west end of a tunnel. The deer sees a train approaching from the west at a constant speed ten times the speed the deer can run. The deer reacts by running toward the train and clears the exit when the train is 15 meters from the tunnel. If the deer ran in the opposite direction it would barely escape out the eastern entrance just as the train came out of the eastern entrance. How long is the tunnel in meters?
A.125
B.135
C.145
D.155
Answer: B.135
Explanation: Let x be the length of the tunnel.
When the deer runs 60 meters west, the train goes 600 meters to a point 15 meters from the west entrance of the tunnel.
When the deer runs east, the deer runs x-60 meters while the train goes x + 600 + 15 meters.
x + 600 + 15 = 10(x-60)
9x = 1215
x = 135 meters
The answer is B.
Question: The triplicate ratio of 1:4 is?
A.1:64
B.1:62
C.1:34
D.3:64
Answer: A.1:64
Explanation: 1^3: 4^3 = 1:64
ANSWER:A
Question: Two pipes A and B can separately fill a cistern in 60 min and 75 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 min. In how much time, the third pipe alone can empty the cistern?
A.188
B.100
C.177
D.268
Answer: B.100
Explanation: Work done by the third pipe in 1 min = 1/50 - (1/60 + 1/75) = - 1/100.
[-ve sign means emptying]
The third pipe alone can empty the cistern in 100 min.
AnswerB
Question: There are 3 questions in a question paper. If the questions have 4,3 and 2 solutions respectively, find the total number of solutions
A.24
B.25
C.30
D.40
Answer: A.24
Explanation: Here question 1 has 4 solutions, question 2 has 3 solutions and question 3 has 2 solutions.
=> By the multiplication (counting) rule,
Total number of solutions=4Ã—3Ã—2==4Ã—3Ã—2= 24
ANSWER A
Question: ram draws a card randomly among card 1-23 and keep it back.then sam draws a card among those.what is the prob than sam has drawn a card greatr than ram?
A.11/23
B.12/23
C.13/23
D.14/23
Answer: A.11/23
Explanation: Sum of probability of drowing a card greater than drawn by ram is (22/23)+(21/23)+.....(1/23)=253/23
but probability for choosing 1 card out of 23 is 1/23
therefore total probability is (253/23)*(1/23)=(11/23)
ANSWER:A
Question: Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together ?
A.100/11 min past 8
B.100/11 min past 9
C.100/11 min past 2
D.100/11 min past 1
Answer: A.100/11 min past 8
Explanation: Explanation:
In this type of problems the formulae is
x is replaced by the first interval of given time Here i.e 8
= min
Therefore the hands will be in the same straight line but not
together at min.past 8.
Answer: A) 100/11 min past 8
Question: By selling an article at Rs.600, a profit of 25% is made. Find its cost price?
A.Rs.287
B.Rs.429
C.Rs.480
D.Rs.412
Answer: C.Rs.480
Explanation: SP = 600
CP = (SP)*[100/(100+P)]
= 600 * [100/(100+25)]
= 600 * [100/125] = Rs.480
Answer:C
Question: How many three letter words are formed using the letters of the word TIME?
A.12
B.14
C.18
D.24
Answer: D.24
Explanation: The number of letters in the given word is four.
The number of three letter words that can be formed using these four letters is ⁴P₃
= 4 * 3 * 2 = 24.
Answer:D
Question: If chemistry book page and math book page ratio is 6:5.A child tore 25 page from chemistry book and 15 page from Math book.Now,ratio becomes 1:1.so,tell the initial no. of pages of chemistry.
A.50
B.60
C.70
D.80
Answer: B.60
Explanation: Chemistry pages=6x,Math pages=5x
6x-25/5x-15=1/1
6x-25=5x-15,6x-5x=10,x=10
chemistry pages=6x=60pages
answer B
Question: The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is:
A.12
B.16
C.24
D.48
Answer: D.48
Explanation: Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.
answer :D
Question: By selling 20 pencils for a rupee a man loses 30%. How many for a rupee should he sell in order to gain 30%?
A.8.56
B.10.75
C.14.5
D.16.5
Answer: B.10.75
Explanation: 70% --- 20
130% --- ?
70/130 * 20 = 10.75
Answer: B
Question: On a windy day, out of every 3 sand dunes formed, only 1 remains. Out of 5 blown-out
sand-dunes, 1 has treasure and only 2 out of 5 sand dunes formed have lucky coupons. Find
the probability that the blown-out sand dune will contain both the things.
A.2/25
B.4/75
C.7/75
D.3/5
Answer: B.4/75
Explanation: Probabilty of sand dune blown out = 2/3
Probabilty that it has treasure = 1/5
Probability that it has lucky coupon = 2/5
total probability = 2/3 * 1/5 * 2/5 = 4/75
ANSWER:B
Question: A car manufacturer sold 500 mini vans at $10000 each, 200 hatchbacks at $8000 each, and 220 sports utility vehicles at $18000 each. what percentage of the company's revenue is from the sale of sports utility vehicles?
A.27.5%
B.50.4%
C.37.5%
D.29.7%
Answer: C.37.5%
Explanation: Correct Answer: C
The company's total revenue from mini vans=500* $10000=$5 000 000
The company's total revenue from hatchbacks=200*$8000=$1 600 000
The company's total revenue from sports utility vehicles=220*$18000=$3 960 000
The combined total of all sales=$10560000
Therefore % of sports utility vehicles sales=3 960 000/10560000*100= 37.5%
Question: A number x is 6 times another number y. The percentage that y is less than x is
A.12.5%
B.83.3%
C.80.5%
D.81%
Answer: B.83.3%
Explanation: Say y=1 and x=6.
Then y=1 is less than x=6 by (6-1)/6*100=5/6*100=83.3%.
Answer: B.
Question: Rahul and Sham together can complete a task in 35 days, but Rahul alone can complete same work in 60 days. Calculate in how many days Sham can complete this work ?
A.84 days
B.82 days
C.76 days
D.68 days
Answer: A.84 days
Explanation: Explanation:
As Rahul and Sham together can finish work in 35 days.
1 days work of Rahul and Sham is 1/35
Rahul can alone complete this work in 60 days,
So, Rahul one day work is 1/60
Clearly, Sham one day work will be = (Rahul and Sham one day work) - (Rahul one day work)
=1/35-1/60
=1/84
Hence Sham will complete the given work in 84 days.
ANSWER IS A
Question: 7 teams compete in a track competition. If there are 12 events in the competition, no event ends in a tie, and no team wins more than 3 events, what is the minimum possible number of teams that won at least one event?
A.3
B.4
C.5
D.6
Answer: B.4
Explanation: 3(max wins) x 4 = 12 (4 teams win three events)
The answer is B.
Question: A and B can do a piece of work in 7 days. With the help of C they finish the work in 5 days. C alone can do that piece of work in?
A.40 days
B.20 days
C.30 days
D.60 days
Answer: C.30 days
Explanation: C
30 days
C = 1/5 – 1/6 = 1/30 => 30 days
Question: In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when a boy gets any no. of prizes?
A.54
B.90
C.64
D.92
Answer: C.64
Explanation: Ans.(C)
Sol. In this case, repetitions are allowed, so all the three prizes can be given in 4 ways, i.e. (4 x 4 x 4) ways = 43 ways = 64 ways Or nr ways = 43 ways = 64 ways
Question: A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 16 sec. What is the length of the platform?
A.287 m
B.431.25 m
C.267 m
D.287.25 m
Answer: B.431.25 m
Explanation: Speed = 300/16 = 75/4 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 75/4
=> x = 731.25 m
Answer:B (431.25)
Question: A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man's rate is?
A.1
B.2
C.3
D.4
Answer: A.1
Explanation: DS = 6
US = 4
S = ?
S = (6 - 4)/2 = 1 kmph
Answer: A
Question: Ritesh and Co. generated revenue of Rs. 1,250 in 2006. This was 12.5% of its gross revenue. In 2007, the gross revenue grew by Rs. 2,500. What is the percentage increase in the revenue in 2007?
A.12.5%
B.20%
C.25%
D.50%
Answer: C.25%
Explanation: Explanation :
Given, Ritesh and Co. generated revenue of Rs. 1,250 in 2006 and that this was 12.5% of the gross revenue.
Hence, if 1250 is 12.5% of the revenue, then 100% (gross revenue) is:
=>(100/12.5)×1250.
=>10,000.
Hence, the total revenue by end of 2007 is Rs. 10,000. In 2006, revenue grew by Rs. 2500. This is a growth of:
=>(2500/10000)×100.
=>25%.
Answer : C
Question: The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 51 kmph, find the speed of the stream?
A.15
B.17
C.14
D.18
Answer: B.17
Explanation: The ratio of the times taken is 2:1.
The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1) = 3/1 = 3:1
Speed of the stream = 51/3 = 17 kmph.
Answer:B
Question: If a, b, and c are integer and ab + c is odd, which of the must be true?
I. a + c is odd
II. b + c is odd
III. abc is even
A.I only
B.II only
C.III only
D.I and III only
Answer: C.III only
Explanation: Personally I'd approach this question in another way.
ab+c=odd, means:
1. ab=even (which means that at least one of them is even) and c=odd
OR:
2. ab=odd (which means that both are odd) and c=even
We can see that in both cases at least one is even thus option III (abc=even) is always true.
Now, for I: if c=odd(case 1) and a=odd(so b=even) then a+c=even≠odd, so this option is not always true.
Exactly the same for option II: if c=odd (case 1) and b=odd (so a=even) then b+c=even≠odd, so this option is not always true.
Answer: C (III only).
Question: A number is missing from the number series below.
Can you find it ?
84, 155, 258, 399 ,?, 819.
A.275
B.350
C.399
D.584
Answer: D.584
Explanation: D
The missing number is 584.
84 = 4^3 + 3^2 + 4
155 = 5^3 + 5^2 + 5
258 = 6^3 + 6^2 + 6
399 = 7^3 + 7^2 + 7
819 = 9^3 + 9^2 + 9
Thus,
584 = 8^3 + 8^2 + 8
Question: The sum of two numbers is 24 and their product is 148. Find the sum of the squares of that numbers.
A.250
B.280
C.230
D.290
Answer: B.280
Explanation: Let a and b be the two numbers(a+b)^2=a^2+2ab+b^2Given (a+b)=24ab=148 So, 24^2=a^2+b^2+2*148576=a^2+b^2+296a^2+b^2=280Ans B
Question: If 36 men can do a piece of work in 5 hours, in how many hours will15 men do it?
A.12
B.38
C.60
D.88
Answer: A.12
Explanation: Explanation:
Let the required no of hours be x. Then
Less men , More hours (Indirect Proportion)
\inline \fn_jvn \therefore 15:36 ::5:x \inline \fn_jvn \Leftrightarrow (15 x X)=(36 x 5) \inline \fn_jvn \Leftrightarrow \inline \fn_jvn x=\frac{36\times 5}{15}=12
Hence, 15 men can do it in 12 hours.
Answer: A) 12
Question: In the formula X = 1/(2y+1)^2, if y is halved, then X is multiplied by
A.25/9
B.25
C.1/9
D.1/25
Answer: A.25/9
Explanation: Say y=2 => X1 = 1/25
when y=1; X2 = 1/9
X2 = 25/9*X1.
Answer : A
Question: A man can row a boat at 20 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 78 km downstream?
A.3 hours
B.33/13 hours
C.31/13 hours
D.30/13 hours
Answer: A.3 hours
Explanation: Speed downstream = 20 + 6 = 26 kmph.
Time required to cover 78 km downstream = d/s = 78/26
= 3 hours.
Answer:A
Question: A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6 p.a for 2 years. Find his gain in the transaction per year.
A.100 rs
B.150 rs
C.160 rs
D.180 rs
Answer: A.100 rs
Explanation: Gain in 2 years =
[(5000*6*2)/100]-[(5000*4*2)/100]
600-400=200
Gain in 1 year =(200/2)=100 rs
ANSWER:A
Question: Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of the tickets sold, 35% were sold at half price and the remaining tickets were sold at the full price of $2. What was the total revenue from ticket sales?
A.$15,840
B.$17,820
C.$16,335
D.$19,800
Answer: C.$16,335
Explanation: 10000 seats --> Full Price : Half Price = 6500 : 3500
Price when all seats are filled = 13000 + 3500 = 16500
100 seats are unsold --> Loss due to unfilled seats = 35 + 2*65 = 165
Revenue = 16500 - 165 = 16335
Answer: C
Question: If -1 < a < 0, which of the following must be true? I. a^9 < a^4 II. a^3 < 1 – a III. a^6 < a^3
A.I only
B.III only
C.I,II,III only
D.II only
Answer: C.I,II,III only
Explanation: Answer : C
Question: A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?
A.65 km/hr
B.17 km/hr
C.76 km/hr
D.50 km/hr
Answer: D.50 km/hr
Explanation: Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 => x = 50 km/hr.
Answer: D
Question: In a class of 50 students, 20 play Baseball, 15 play Cricket and 11 play Football. 7 play both Baseball and Cricket, 4 play Cricket and Football and 5 play Baseball and football. If 18 students do not play any of these given sports, how many students play exactly two of these sports?
A.10
B.46
C.67
D.68
Answer: A.10
Explanation: Notice that7 play both Baseball and Cricket does not mean that out of those 7, some does not play Football too. The same for Cricket/Football and Baseball/Football.
[color=#ffff00]{Total}={Baseball}+{Cricket}+{Football}-{HC+CH+HF}+{All three}+{Neither}For more checkADVANCED OVERLAPPING SETS PROBLEMS
[/color]
50=20+15+11-(7+4+5)+{All three}+18 --> {All three}=2;
Those who play ONLY Baseball and Cricket are 7-2=5;
Those who play ONLY Cricket and Football are 4-2=2;
Those who play ONLY Baseball and Football are 5-2=3;
Hence, 5+2+3=10 students play exactly two of these sports.
Answer: A.
Question: A cricketer whose bowling average is 12.4 runs per wicket takes 5 wickets for 26 runs and there by decreases his average by 0.4. The number age of the family now is:
A.18
B.17
C.76
D.85
Answer: D.85
Explanation: Let the number of wickets taken till the last match be x. Then,
(12.4x + 26)/(x + 5) = 12
= 12.4x + 26 = 12x + 60
= 0.4x = 34
= x = 340/4 = 85.
Answer: D
Question: The salary of a person was reduced by 10%. By what percent should his
reduced salary be raised so as to bring it at par with his original salary?
A.100/9
B.100
C.110
D.98
Answer: A.100/9
Explanation: Let the original salary be $100. New salary = $90.
Increase on 90=10 , Increase on 100=((10/90)*100)%
= (100/9)%
Answer A)100/9
Question: the hiker walking at a constant rate of 5 miles per hour is passed by a cyclist traveling in the same direction along the same path at 20 miles per hour. the cyclist stops to wait for the hiker 5 minutes after passing her, while the hiker continues to walk at her constant rate, how many minutes must the cyclist wait until the hiker catches up?
A.15
B.10
C.20
D.30
Answer: A.15
Explanation: After passing the hiker the cyclist travels for 5 minutes at a rate of 20 miles/hour.
In those 5 mins the cyclist travels a distance of 5/3 miles.
In those 5 mins the hiker travels a distance of 5/12 miles.
So the hiker still has to cover 15/12 miles to meet the waiting cyclist.
The hiker will need 1/4 hours or 15 mins to cover the remaining 15/12 miles.
So the answer is A.
Question: An insect leaps 60 centimeters in 1.5 seconds. What is its speed?
A.9 centimeters per second
B.0.9 meters per second
C.4 meters per second
D.0.4 meters per second
Answer: D.0.4 meters per second
Explanation: 60 / 1.5 = 40 cm/s = 0.4 m/s
The answer is D.
Question: (1^2+2^2+3^2+.....+10^2)=?
A.330
B.345
C.365
D.385
Answer: D.385
Explanation: formula is (1^2+2^2+3^2+....+n^2=1/6 n(n+1)(2n+1)
n=10
=(1/6x10x11x21)
=385
Answer is D.
Question: Jill works as a waitress at the local diner where she earns an hourly wage of $5.00 per hour and a standard tip rate of 25% of the cost of the orders she serves. If she worked four 9-hour shifts this week and averaged $40 in orders per hour, how much did Jill earn this week?
A.280
B.300
C.540
D.350
Answer: C.540
Explanation: Jill earns 5 dollars/hour and the hourly tip is (1/4)*40.
Jill thus earns 5*9+9*10 per day(or 5(9)+10(9)=15(9)=135).
Jill has worked for 4 days -> 135*4=540.
This matches answer choice C.
Question: The result when a number subtracted from 100 is the same as the number added to 40. what is the number?
A.70
B.65
C.80
D.140
Answer: A.70
Explanation: Answer
Let the number be x.
Then, x - 40= 100- x
â‡’ 2x = 100+ 40= 140
â‡’ 2x = 140
âˆ´ x = 70
Correct Option: A
Question: In how many different number of ways 4 boys and 2 girls can sit on a bench such that girls always sit together.
A.A)720
B.B)240
C.C)740
D.D)780
Answer: B.B)240
Explanation: 240
Option 'B'
Question: What is the units' digit of the following expression (10)^5*(12)^5*(18)^5?
A.0
B.1
C.3
D.5
Answer: A.0
Explanation: We do not have to do any calculations or find units digit of remaining numbers...
all three terms - 10,12,18 - are EVEN and since the PRODUCT contains 0, the units digit of the product will remain 0
A