RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A child must place 6 different toys in 4 different bins. If any of the toys can go in any of the bins, in how many ways can the child place the toys into the bins?
A.6^6
B.6^4
C.4^6
D.4^4
Answer: C.4^6
Explanation: there are 4 different bins and each of the toy can go to any of these bins..
so answer 4∗4∗4∗4∗4∗4=4^6
ANSWER:C
Question: If –1 < x <0 and x ≠ 0, which of the following inequalities must be true?
I. x^3 < x
II. x^2 < |x|
III. x^4 – x^5 > x^3 – x^2
A. I only
B. II only
C. III only
D. II and III only
Answer: B. II only
Explanation: Answer is D. Let's look at the statements one by one
Stmt I. x^3 < x
if 0<x<1 then x^3< x but if -1<x<0 then x^3>x
So this statement is not always true
Stmt II. x^2 < |x|
Because we know that x is a number less than one but not equal to zero then x^2 will always be less than |x|.
Why? think of positive fractions (and you can think in terms of positive fractions because the inequality is in regards to |x|). Lets set x = 1/2, then x^2 = 1/4 and 1/4<1/2
So Stmt II is always true
Stmt III. x^4 – x^5 > x^3 – x^2
This one may seem tricky but lets break it down. x^4 – x^5 > x^3 – x^2 = x^4(1-x)>x^2(x-1).
Because lets concentrate on (1-x) and (x-1). We are given that -1<x<1 which means that (1-x)>0 and (x-1)<0. x^4 will always be positive and x^2 will always be positive so without doing any math we are looking at positive > negative... which is always true.
So Stmt III is always true
B
Question: If the number 91876*2 is completely divisible by 8, then the smallest whole number in place of * will be?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: The number 6x2 must be divisible by 8.
x=3 as 632 is divisible by 8.
Correct Option : C
Question: A man walking at a rate of 15km/hr crosses a bridge in 10 minutes. The length of the bridge is?
A.500m
B.1110m
C.950m
D.1000m
Answer: A.500m
Explanation: Speed = 15*5/18 = 15/18 m/sec
Distance covered in 10 minutes = 15/18 *10 *60 = 500 m
Answer is A
Question: 10 books are placed at random in a shelf. The probability that a pair of books will always be together is
A.1/10
B.9/10
C.1/5
D.3/10
Answer: C.1/5
Explanation: 10 books can be rearranged in 10! ways consider the two books taken as a pair then number of favourable ways of getting these two books together is 9! 2!
Required probability = 1/5
ANSWER:C
Question: A company bought for its 6 offices 2 computers of brand N and 3 computers of brand M. In how many ways could computers be distributed among the offices if each office can have only 1 computer.
A.60
B.210
C.256
D.292
Answer: A.60
Explanation: This problem has to do withcombinations. Here's the general idea: if you have a set of n elements, and you are going to choose r of them (r < n), then the number of combinations of size r one could choose from this total set of n is:
# of combinations = nCr = (n!)/[(r!)((n-r)!)]
where n! is the factorial symbol, which means the product of every integer from n down to 1. BTW, nCr is readn choose r.
In this problem, let's consider first the three computers of brand M. How many ways can three computer be distributed to seven offices?
# of combinations = 6C3 = 20
There are 20 different ways to distribute three computers to 7 offices. (The massive amount of cancelling that occurred there is very much typical of what happens in the nCr formula.)
One we have distributed those three M computers, we have to distribute 2 N computers to the remaining four offices. How many ways can two computer be distributed to four offices?
# of combinations = 3C2 = 3
For each of the 20 configurations of distributing the M computers, we have 3 ways of distributing the N computers to the remaining offices. Thus, the total number of configurations is 20 * 3 = 60. Answer choice =A
Question: What is the next number of the following sequence
21,77,165,285,......
A.434
B.435
C.436
D.437
Answer: D.437
Explanation: 21=5^2-4
77=9^2-4
165=13^2-4
285=17^2-4
5,9,13,17,21(+4)
in the same way next no. will be
21^2-4=441-4=437
ANSWER:D
Question: A, B and C rents a pasture for Rs.870. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should A pay?
A.240
B.227
C.268
D.198
Answer: A.240
Explanation: 12*8 :16*9 = 18*6
8: 12: 9
8/29 * 870 = 240
Answer:A
Question: Two cubes have their volumes are in the ratio 1:27. Find the ratio of their surface area?
A.1:2
B.2:3
C.1:9
D.2:7
Answer: C.1:9
Explanation: Let their edges be a and b
Then, a^3 / b^3 = 1/27
(a/b)^3 = (1/3)^3
a/b = 1/3
Ratio of their surface areas = 6a^2 / 6b^2 = (a/b)^2 = 1/9 = 1:9
Answer is C
Question: If ty > 0 and yz < 0, which of the following must be negative:
A.tyz
B.ty(z^2)
C.t(y^2)z
D.t(y^2)(z^2)
Answer: C.t(y^2)z
Explanation: ty > 0 means that ty is positive.
yz < 0 means that yz is negative.
t(y^2)z = (ty)(yz) = positive*negative = negative. Thus option C is always negative.
Question: If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is?
A.1/4
B.1/2
C.1/8
D.1/0
Answer: B.1/2
Explanation: The number of exhaustive outcomes is 36.
Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2
P(E) = 1 - 1/2 = 1/2.
Answer: B
Question: The average of five numbers id 29. If one number is excluded, the average becomes 25. What is the excluded number?
A.30
B.40
C.32.5
D.45
Answer: D.45
Explanation: Explanation:
Sum of 5 numbers = 5 × 29
Sum of 4 numbers after excluding one number = 4 × 25
Excluded number
= 5 × 29 - 4 × 25
= 145 - 100 = 45
Answer: Option D
Question: John walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 9 minutes earlier. How far is the office from his house?
A.3 2/5 Km
B.3 1/5 Km
C.4 1/5 Km
D.5 1/5 Km
Answer: A.3 2/5 Km
Explanation: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 17/6
= 24/2 * 17/60
= 17/5 = 3 2/5 Km
A
Question: The average weight of 8 person's increases by 3 kg when a new person comes in place of one of them weighing 70 kg. What might be the weight of the new person?
A.94 kg
B.85 kg
C.90 kg
D.100 kg
Answer: A.94 kg
Explanation: Total weight increased = (8 x 3) kg = 24 kg.
Weight of new person = (70 + 24) kg = 94 kg.
Answer : A
Question: A soccer store typically sells replica jerseys at a discount of 30 percent to 50 percent off list price. During the annual summer sale, everything in the store is an additional 20 percent off the original list price. If a replica jersey's list price is $80, approximately what percent E of the list price is the lowest possible sale price?
A.20
B.25
C.30
D.40
Answer: D.40
Explanation: Let the list price be 2x
for min sale price, the first discount given should be 50%, 2x becomes x here
now, during summer sale additional 20% off is given ie sale price becomes 0.8x
it is given lise price is $80
=> 2x = 80
=> x = 40
and 0.8x = 32
so lowest sale price is 32, which E is 40% of 80
hence, D is the answer
Question: In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 4 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?
A. 200
B. 325
C. 565
D. 625
Answer: D. 625
Explanation: total fish = x
percentage of second catch = (4/50)*100 = 8%
so, x * 8% = 50
x = 625 ans D.
Question: in how many ways can a letters of word "BALLOON" is arranged so that two Ls do not come together
A.600
B.700
C.840
D.900
Answer: D.900
Explanation: Total # of arrangements: 7!/[2!*2*]
Total # of arrangements with the LL together:
Note: this means the LL is like one letter.
# = 6!/2!
Therefore, total number with the LL NOT together:
7!/(2!*2!) - 6!/2! = 1260 - 360 = 900
ANSWER:D
Question: If 625^(-x) + 25^(-2x) + 5^(-4x) = 14, what is the value of x?
A.-4
B.-1/4
C.0
D.1/4
Answer: D.1/4
Explanation: We're told that 625^(-X) + 25^(-2X) + 5^(-4X) = 15. We're asked for the value of X.
Since each of the calculated terms MUST be positive (regardless of what the exponent is), we can use thebasesto our advantage.....
With Answer A, we'd have 625^4, which is MUCH BIGGER than 15 (and we'd be adding to that big number). Eliminate A.
With Answer E, we'd have 625^(-4), which would create a TINY fraction (and we'd add some other fractions to it, so the total would be MUCH TOO SMALL). Eliminate E.
With Answer D, we'd have 625^(-1/4), which will also be a fraction (just not as tiny as the one in answer E), but the total would still be TOO SMALL. Eliminate D.
With Answer C, anything to the '0 power' is 1, so we'd have 1+1+1 = 3. This is not 15. Eliminate C.
D
Question: How many different ways can you select a pilot and a co pilot if you have 50 people to choose from?
A. 199
B. 200
C. 398
D. 2450
Answer: D. 2450
Explanation: You are not just choosing two from 50. Each of the two people chosen fills a particular slot. The first filling the pilot slot and the second filling the copilot slot is different from the first filling the copilot slot and the second filling the pilot slot.
So the answer is in a sense (50C2) x 2 = 2450=D
Question: If a, b, c, d, e and f are integers and (ab + cdef) < 0, then what is the maximum number W of integers that can be negative?
A.2
B.3
C.4
D.5
Answer: D.5
Explanation: Minimuum should be 1
Maximum should be 4:
1 out of a or b to make the multiplication negative
3 out of c, d, e or f to make the multiplication negative.
Negative+Negative<0
Answer:C
maximum will be 5..
you dont require both the multiplicatin to be negative for entire equation to be negative...
any one a or b can be negative to make ab negative and it can still be more(away from 0) than the multiplication of 4 other -ve numbers...
actually by writing minimum required as 1 out of 6,you are actually meaning 5 out of 6 also possible as you will see W=5 or 1 will give you same equation..
ans D
Question: 20 throws of a die produces following results
SCORE -- NUMBER OF OCCURRENCES
---1-------------------4
---2-------------------3
---3-------------------5
---4-------------------2
---5-------------------2
---6-------------------4
What is the probability that one more throw to this series will increase the mean score?
A.1/6
B.1/3
C.1/2
D.2/3
Answer: C.1/2
Explanation: The average score now is \frac{total \ score}{# \ of \ throws}=\frac{1*4+2*3+3*5+4*2+5*2+6*4}{20}=\frac{67}{20}=3.something.
Now, the average score will increase if we get more than the current average, so if we get 4, 5, or 6 on the next throw. The probability of that is 3/6=1/2.
Answer: C.
Hope it's clear.
Question: If there are three sum of money P, Q and R so that P is the simple interest on Q and Q is the simple interest of R, rate % and time are same in each case, then the relation of P, Q and R is given by
A.P2 = QR
B.Q2 = PR
C.R2 = PQ
D.PQR = 100
Answer: B.Q2 = PR
Explanation: P = Q×r×t/100 and Q = R×r×t/100
⇒ P/Q=Q/R=r×t/100
∴ Q2 = PR.
Answer B
Question: A certain lab experiments with white and brown mice only. In one experiment, 2/4 of the mice are white. If there are 16 brown mice in the experiment, how many mice in total are in the experiment?
A.32
B.36
C.34
D.39
Answer: A.32
Explanation: Let total number of mice = M
Number of white mice = 2/4 M
Number of brown mice = 2/4 M = 16
=> M = 32
Answer A
Question: A certain characteristic in a large population has a distribution that is symmetric about the mean a. If 68% of the distribution lies one standard deviation d of the mean, what percent of the distribution is less than a+d?
A. 16%
B. 32%
C. 48%
D. 84%
Answer: D. 84%
Explanation: 16%
________________________________________________ a+d
34%
________________________________________________ a
34%
________________________________________________ a-d
16%
since 68% lies one standard deviation from mean a, => 50% of 68% lies on either side as it is symmetric about a.
thus 16% lie below a-d and 16% lie above a+d
now below a+d = 16+34+34 = 84%
hence D
Question: For each positive integer,the quantitySn is defined such thatSn+2=(Sn)^4 -S(n+1).in addition ,S2=1.then which of the following must be true.
A.a)S4 +S3 +1=0
B.b)(S1)^2 +S4 +2=0
C.c) ifS1=-1thenS4 is also equal to-1.
D.d) ifS4 =-7thenS1=-2.
Answer: C.c) ifS1=-1thenS4 is also equal to-1.
Explanation: Since all the answers include S4, let's start from there.
S4=S2^2-S3
S3=S1^2-S2
Substituting S3 into the first equation we get:
S4=S2^2-(S1^2-S2)
Since S2=1
S4=1-(S1^2-1)
S4=2-S1^2
We need S1^2 in order to calculate S4.
E) provides S1 and from there we can calculate S4:
S4=2-(-3)^2
S4=-7
Correct.
As a side note, I would be very careful with answers in the formif S4=x then S1=y(such as option D ), as we are dealing with S1^2 (not S1), S1 can have two different values and it can not be determined for sure which root is the right answer.
For example:
If S4=-7 then S1=3 :
if we substitute S4 with - 7 we get:
-7=2-S1^2
S1^2=9
now S1 can be +/-3 !!
C
Question: How many such 4 consecutive numbers are there less than 1000 when added gives a sum which is divisible by 10? For example, 16 +17+18+19=70.
A.22
B.200
C.87
D.99
Answer: B.200
Explanation: Explanation:
Let the numbers be n, n+1, n+2, n+3.
Sum of these numbers = 4n + 6.
Let 4n + 6 = 10k
So n = 10k−6410k−64 = 2k−1+2k−242k−1+2k−24 = 2k−1+k−122k−1+k−12
So k takes only odd numbers.
For k = 1, n = 1
For k = 3, n = 6
For k = 5, n = 11
Final value of n = 996.
So total values = =l−ad+1=996−15+1=l−ad+1=996−15+1 = 200
Answer:B
Question: The radius of a circle is increased by 1%. Find how much % does its area increases?
A.2.07%
B.2.71%
C.2.41%
D.2.01%
Answer: D.2.01%
Explanation: Explanation:
r = 100 r = 101
r2 = 10000 r2 = 10201
10000 ---- 201
100 ---- ? => 2.01%
Answer: D
Question: The average of 10 numbers is calculated as 15. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is?
A.12
B.26
C.16
D.97
Answer: C.16
Explanation: 10 * 15 + 36 – 26
= 160/10
= 16
Answer: C
Question: David covered a distance of 50 miles on his first trip. On a later trip he traveled 450 miles while going three times as fast. His new time compared with the old time was:
A.twice as much
B.three times as much
C.the same
D.half as much
Answer: B.three times as much
Explanation: Let t be the time of the first trip.
On the later trip, David can travel 150 miles in time t.
The trip of 450 miles takes 3t.
The answer is B.
Question: An amount of Rs.1000 is divided between 5 persons. Each man gets Rs.250 while each woman gets Rs.125. Find the number of men and women.
A.2 men, 3 women
B.4 men, 1 woman
C.1 man, 4 women
D.3 men, 2 women
Answer: D.3 men, 2 women
Explanation: Let x be men, y be women
x+y=5.............eq(1)
250x+125y=1000..........eq(2)
solve eq 1 and 2
we get
x=3,y=2
ANSWER:D
Question: An art gallery owner is hanging paintings for a new show. Of the five paintings she has to choose from, she can only hang three on the main wall of the gallery. Assuming that she hangs as many as possible on that wall, in how many ways can she arrange the paintings?
A.18
B.30
C.60
D.120
Answer: C.60
Explanation: Arrangment means permutations questions..
5P3 = 5!/3! = 60.
IMO option C is correct answer..
Question: How many no.'s with 3 different digits, 2, 3, 5, 6, 7 and 9, which are divisible by 5?
A.10
B.20
C.30
D.40
Answer: B.20
Explanation: Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.
The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.
The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.
Required number of numbers = (1 x 5 x 4) = 20
B
Question: Company X provides bottled water to its employees in 5 liter bottles, $3 each. At least how many 5L bottles must Company X buy monthly, so that new contract with $50 fixed monthly rate and $1 for 20L bottle each paid off? (Assume that no other costs apply)
A. 15
B. 17
C. 19
D. 20
Answer: C. 19
Explanation: let the no. of 5 liter bottles be x, so the no. of 20l bottles will be x/4 (to equate the vol.) since the total cost will be equal , 3x= 50+x/4 so x= 18.18 or 19. Answer is (C).
Question: sunil start from home at 4 pm and reaches school everyday at 5pm to pick up his children.on saturday the school got over ai 4 pm and children started walking towards home.sunil met them on the way and returned home 15min early.if speed of sunil is 35km/hr then for how many min did children walk? what is speed of children???
A.4 km/hr.
B.5 km/hr.
C.6 km/hr.
D.7 km/hr.
Answer: B.5 km/hr.
Explanation: sunil reach 15 min early. it is time save at both for going to school and coming to home.
so, sunil meet children befor 15/2= 7.5 min.
speed of sunil is 35km/hr i.e. 583.33 m/min.
remaining distance to cover by sunil or else we can say total distance cover by children is 7.5*583.33=4375 m
Sunil meet children after 52.5 min i.e. (1hr-7.5min).
so 4375 is distance cover by children in 52.5min.
so, speed of children is 4375/52.5=83.33m/min=5 km/hr.
ANSWER:B
Question: A dishonest dealer professes to sell his goods at Cost Price but still gets 20% profit by using a false weight. What weight does he substitute for a kilogram?
A.833 1/7 grams
B.833 1/3 grams
C.833 8/3 grams
D.883 1/3 grams
Answer: B.833 1/3 grams
Explanation: If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.
If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.
How many grams he has to give instead of one kilogram(1000 gm).
120 gm ------ 100 gm
1000 gm ------ ?
(1000 * 100)/120 = 2500/3 = 833 1/3 grams.
Answer:B
Question: What number should replace the question mark in this series?
13 44 88 176 847 ?
A.1495
B.1595
C.1695
D.1458
Answer: B.1595
Explanation: First number is 13. Second number is 13+31 = 44. Third number is 44+44=88. Fourth number is 88+88 = 176. Fifth number is 176+671=847. So, next number is 847+748 = 1595
ANSWER:B
Question: Length of a rectangular plot is 20 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?
A.70 m
B.60 m
C.80 m
D.90 m
Answer: B.60 m
Explanation: Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m.
26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m
B
Question: The average age of a husband and a wife is 23 years when they were married five years ago but now the average age of the husband, wife and child is 21 years(the child was born during the interval). What is the present age of the child?
A.7 years
B.9 years
C.6 years
D.4 years
Answer: A.7 years
Explanation: 28 * 2 = 56
21 * 3 = 63
-----------
7 years
Answer: A
Question: If w,x,y,z are consecutive positive integers ; then which of the following is always odd?
[1] w*x+(y+2)^2*z
[2] w^x + z^y
[3] 6z^2
A.1
B.2
C.3
D.2
Answer: D.2
Explanation: Plug in some numbers
w = 1
x = 2
y = 3
z = 4
Check the options -
[1] w*x+(y+2)^2*z = 1*2 + (3+2)^2 * 4 => 2 + 25*4 = 102{ Not an odd Number }
[2] w^x + z^y = 1^2 + 4^3 => 1 + 64 = 65{ Odd number }
[3] 6z^2 = 6* 4^2 even
[2]
D
Question: 2.2 cubic dm of lead is to be drawn into a cylindrical wire 0.50 cm diameter. Find the length of the wire in meters.
A.110
B.111
C.113
D.112
Answer: D.112
Explanation: Let the length of the wire be h meters. Then,
∏ (0.50/(2 x 100))^2 x h = 2.2/1000
=h = ( (2.2/1000) x (100 x 100)/(0.25 x 0.25) x (7/22) ) = 112 m.
Answer is D.
Question: A and B start a business jointly. A invests Rs.18000 for 8 months and B remains in the business for 4 months. Out of the total profit B claims 2/7th share. How much money is contributed by B?
A.A)Rs.12829
B.B)Rs.14400
C.C)Rs.12293
D.D)Rs.12804
Answer: B.B)Rs.14400
Explanation: 18*8: x*4 = 5:2
x = 14.4 =>
Rs.14400
Answer: B
Question: Rajat, Vikas and Abhishek are submitting questions in the ratio 7:3:2. If total number of questions submitted by them is 24. Find the number of questions submitted by Vikas.
A.3
B.4
C.5
D.6
Answer: D.6
Explanation: Explanation :
Number of questions submitted by Vikas
= (24 * 3)/(7+3+2) = 6
Answer : D
Question: From an island, it is possible to reach the mainland by either Ferry P or Ferry Q. Ferry P travels for 3 hours at 6 kilometers per hour, while Ferry Q takes a route that is three times longer. If Ferry P is slower than Ferry Q by 3 kilometers per hour, how many hours longer is the journey of Ferry Q compared with the journey of Ferry P?
A.1
B.2
C.3
D.4
Answer: C.3
Explanation: The distance traveled by Ferry P is 18 km.
Then the distance traveled by Ferry Q is 54 km. Ferry Q travels at a speed of 9 kph. The time of the journey for Ferry Q is 54/9 = 6 hours, which is 3 hours more than Ferry P. The answer is C.
Question: In a class, candies were distributed among the children. Each child got candies equal to one-eighth of the total number of children in the class. If the number of children were half of the present number of children, then each child would have received 16 candies in total. Find the total number of candies distributed.
A.450
B.598
C.512
D.658
Answer: C.512
Explanation: Suppose the total number of children in the class be X. Then,
(X)*(1/8*X)=(X/2)*16
=> X=64
=>Total number of candies = (1/8)*X*X =(1/8)*64*64=512
Option C
Question: In what ratio must tea at Rs.62 per kg be mixed with tea at Rs. 72 per kg so that the mixture must be worth Rs. 64.50 per kg?
A.3:1
B.2:1
C.5:2
D.3:2
Answer: A.3:1
Explanation: Mean price = (72-64.5 = 7.5) (64.5-62=2.5)
req ratio = 7.5:2.5 = 3:1
ANSWER A
Question: What is the average (arithmetic mean) of all the multiples of ten from 10 to 180 inclusive?
A.90
B.95
C.100
D.105
Answer: A.90
Explanation: 10 and 190 inclusive would mean there are 19 terms.
No need to add up all the terms and further divide by 19 since the terms are evenly spaced in ascending order from 10, 20, 30........180
The middle term is the average which is the tenth term = 90
A is the answer.
Question: In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 300 newborn members of the population, approximately how many would be expected to survive the first 3 months of life?
A.219
B.246
C.252
D.262
Answer: A.219
Explanation: Number of newborns that can die in first month = 1/10 * 300 = 30
Survived = 270
Number of newborns that can die in second month = 1/10 * 270 = 27
Survived = 243
Number of newborns that can die in third month = 1/10 * 243 = 24
Survived = 219
Answer:A
Question: The average of 10 numbers was calculated as 16. It is discovered later on that while calculating the average, one number, namely 46, was incorrectly read as 26. What is the correct average?
A.18
B.19
C.20
D.21
Answer: A.18
Explanation: 10*16 - 26 + 46 = 180
180 / 10 = 18
The answer is A.
Question: A person walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 8 minutes earlier. How far is the office from his house?
A.3 1/5 Km
B.2 1/5 Km
C.4 Km
D.4 1/5 Km
Answer: A.3 1/5 Km
Explanation: Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 16/6
= 24/2 * 16/60
= 8 * 2/5
= 16/5 = 3 1/5 Km
A
Question: What amount does an investor receive if the investor invests $6000 at 10% p.a. compound interest for two years, compounding done annually?
A.$6980
B.$7070
C.$7120
D.$7260
Answer: D.$7260
Explanation: A = (1 + R/100)^n * P
(1.1)^2 * 6000 = 1.21 * 6000 = 7260
The answer is D.
Question: A mixture of 70 litres of milk and water contains 10% water. How many litres of water should be added to the mixture so that the mixture contains 12 1/2% water?
A.2
B.4
C.8
D.6
Answer: A.2
Explanation: Quantity of milk in the mixture = 90/100 (70) = 63 litres.
After adding water, milk would form 87 1/2% of the mixture.
Hence, if quantity of mixture after adding x liters of water, (87 1/2) / 100 x = 63 => x = 72
Hence 72 - 70 = 2 litres of water must be added.
ANSWER A
Question: The smallest number which when diminished by 9, is divisible 13, 26, 39, 52 and 65 is:
A.789
B.769
C.790
D.787
Answer: A.789
Explanation: Required number = (L.C.M. of 13, 26, 39, 52,65) + 9
= 780 + 7
= 789
Answer: Option A