RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: A salesman sold twice as much pears in the afternoon than in the morning. If he sold $390 kilograms of pears that day, how many kilograms did he sell in the afternoon?
A.120
B.180
C.260
D.280
Answer: C.260
Explanation: 3x=390
x=130
Therefore, the salesman sold 130kg in the morning and 2⋅130=260 kg in the afternoon. So answer is C.
Question: 1600 men have provisions for 28 days in the temple. If after 4 days, 400 men leave the temple, how long will the food last now?
A.22
B.77
C.32
D.27
Answer: C.32
Explanation: 1600 ---- 28 days
1600 ---- 24
1200 ---- ?
1600*24 = 1200*x
x = 32 days
Answer: C
Question: The average of 9 observations was 9, that of the 1st of 5 being 10 and that of the last 5 being 8. What was the 5th observation?
A.9
B.8
C.7
D.6
Answer: A.9
Explanation: 1 to 9 = 9 * 9 = 81
1 to 5 = 5 * 10 = 50
5 to 9 = 5 * 8 = 40
5th = 50 + 40 = 90 – 81 = 9
Answer: A
Question: When positive integer x is divided by 9, the quotient is y and the remainder is 4. When 2x is divided by 7, the quotient is 2y and the remainder is 1. What is the value of 5y – x?
A.-3
B.3
C.-4
D.4
Answer: B.3
Explanation: (1) x = 9y+4
(2) 2x = 14y+1
(2)-(1): x=5y-3
5y-x=3
The answer is B.
Question: In what time will a train 140 m long cross an electric pole, it its speed be 144 km/hr?
A.2.5
B.3.5
C.4
D.5
Answer: B.3.5
Explanation: Speed = 144 * 5/18 = 40 m/sec
Time taken = 140/40 = 3.5 sec.
Answer: Option B
Question: Set X consists of prime numbers {3, 11, 7, K, 17, 19}. If integer Y represents the product of all elements in set X and if 11Y is an even number, what is the range of set X?
A.14
B.16
C.17
D.20
Answer: C.17
Explanation: y = product of all elements in set X. now, y will be even if 2 is part of this set (k=2), else y will be odd.
since we have, 11y as an even integer. therefore y must be even. (because 11 is odd, therefore the only way in which 11y can be even is when y is even.)
thus elements in the set X are {2,3,11,7,17,19} and thus its range is 19-2=17;
ANSWER:C
Question: Calculate the circumference of a circular field whose radius is 12 centimeters.
A.2
B.4
C.26
D.24
Answer: D.24
Explanation: Circumference C is given by
C = 2Ï€r = 2Ï€*12 = 24 Ï€ cm
correct answer D
Question: The sum of two consecutive numbers is 452. The greatest among these three number is:
A.226
B.228
C.229
D.230
Answer: A.226
Explanation: Let the numbers be x, x + 1
Then,
x + (x + 1) = 452
2x = 450
x = 225
Greatest number, (x + 1) = 226
ANSWER:A
Question: A certain number when divided by 45 leaves a remainder 31, what is the remainder if the same number be divided by 15?
A.13
B.11
C.9
D.1
Answer: D.1
Explanation: 45 + 31 = 76/15 = 1 (Remainder)
ANSWER:D
Question: A sum of Rs.4800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
A.282
B.3120
C.8383
D.8383
Answer: B.3120
Explanation: Let A be the amount received at the end of the three years.
A = 4800[1 + 10/100][1 + 20/100][1 + 25/100]
A = (4800 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.7920
So the interest = 7920 - 4800 = Rs.3120
Answer: B
Question: A cyclist bikes x distance at 20 miles per hour and returns over the same path at 16 miles per hour. What is the cyclist's average rate for the round trip in miles per hour?
A.17.6
B.17.3
C.8.6
D.17.2
Answer: A.17.6
Explanation: Distance = d1 = x miles
Speed = s1 = 20 miles per hour
Time = t1 = Distance/ Speed = x/20
2. Going from B to A
Distance = d2 = x miles
Speed = s2 = 16 miles per hour
Time = t2 = Distance/ Speed = x/16
3. Average Speed = Total Distance/Total Time
Total Distance = x + x = 2x
Total Time = x/20 + x/16 = 9x/80
Speed = 2x/(9x/80) = 160/9
= 17.6
Answer : A
Question: A river boat leaves Silver Town and travels upstream to Gold Town at an average speed of 4 kilometers per hour. It returns by the same route at an average speed of 7 kilometers per hour. What is the average speed for the round-trip in kilometers per hour?
A.5.1
B.7.1
C.7.2
D.7.5
Answer: A.5.1
Explanation: Pick a number which is LCM of 7 and 4 = 18.
Upstream time = 28/4 = 7 hrs
Downstream time = 28/7 = 4 hrs
Total time = 11hrs
Total distance = 56
Average Speed = 56/11 = 5.1 km/hr
Question: A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
A.230
B.9927
C.267
D.1268
Answer: A.230
Explanation: Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x = 230.
Answer: A
Question: If the productivity of a brigade grows by 20% when the number of the workers in the brigade is increased by one, then which of the following is closest to the ratio of the productivity of a 12-person brigade to that of a 10-person brigade?
A.0.21
B.0.82
C.1.31
D.1.21
Answer: C.1.31
Explanation: B = 10-men brigade
p = increase in the productivity = 20%
Solution: B x p = B x 1.2 = 1.2B -------> the productivity of 11 men brigade
1.2B x p = 1.2B x 1.1 = 1.31B -----> the productivity of 12 men brigade
The ratio of the productivity of a 12-men brigade to that of a 10-men brigade = 1.31B/B = 1.31
C
Question: There are 8 digit mobile no's. From that how many 8 digit mobile no.'s can be formed if any digit can be repeated and 0 can also start the mobile number?
A.9^8
B.8^2
C.10^8
D.9^3
Answer: C.10^8
Explanation: Here the digits(0,1,2,3,4,5,6,7,8,9) can be repeated and 0 can also be used to start the mobile number. Hence, any of the 10 digits can be placed at each place of the 8 digit number.
10 10 10 10 10 10 10 10
Hence, required number of 8 digit mobile numbers
=10^8
C
Question: A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 20 metres apart, how many poles will be needed ?
A.55
B.56
C.14
D.58
Answer: C.14
Explanation: Solution
Perimeter of the plot = 2(90 + 50) = 280 m.
∴ Number of poles = [280/20] =14m Answer C
Question: If logx(3) = 1/4, then x = ?
A.61
B.71
C.81
D.91
Answer: C.81
Explanation: Rewrite the given equation in exponential form
logx(3) = 1/4 if and only if x(1/4) = 3
We now solve, for x, the exponential equation obtained above by raising both sides to the power 4.
(x(1/4)) 4 = 3 4
x = 3 4 = 81
correct answer C
Question: Find the greatest number that will divide 150, 230 and 175 leaving 50, 5 and 25 as remainders respectively
A.19
B.17
C.32
D.9
Answer: C.32
Explanation: Explanation:
Answer will be HCF of (150-50, 230-5, 175-25)
HCF of (100, 225, 150) = 32
Option C
Question: In a certain neighborhood , 60 percent of the student are going to school (A) , and the rest are going to school (B) . A new school (C) is opened , If 30 percent of student of school (A) and 40 percent of student of school (B) are expected to go to the new school (C) , what percent of student are expected to go to the new school (C) ?
A. 30%
B. 34%
C. 38%
D. 42%
Answer: B. 34%
Explanation: Say there are total of 100 students in the neighborhood , 60 students are going to school (A) and 40 student are going to school (B)
60*0.3=18 student of school (A) are expected to go to the new school (C)
40*0.4=16 student of school (B) are expected to go to the new school (C)
Thus total of 18+16=34 student are expected to go to the new school (C) , which is 34% of students .
Answer: B.
Question: When 1/20% of 8,000 is subtracted from 1/10 of 8,000, the difference is
A.50
B.200
C.380
D.798
Answer: D.798
Explanation: 1/20 % of 8000 = 4
1/10 of 8000 = 800
800-2 = 798
Ans:D
Question: A train covers a distance of 12 km in 10 min. If it takes 8 sec to pass a telegraph post, then the length of the train is?
A.177 m
B.189 m
C.160 m
D.178 m
Answer: C.160 m
Explanation: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec
= 20 m/sec.
Length of the train = 20 * 8
= 160 m.
Answer: C
Question: What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 4 Years?
A.5%
B.6%
C.4 1/2%
D.3 1/2 %
Answer: A.5%
Explanation: Explanation:
160 = (180*4*R)/100
R = 5%
ANSWER IS A
Question: What is the greatest of 3 consecutive integers whose sum is 18 ?
A.6
B.7
C.8
D.9
Answer: B.7
Explanation: The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3
If the sum is 24, we need to solve the equation 3n + 3 = 18;
=> 3n = 15;
=> n = 5
The greatest of the three numbers is therefore 5 + 2 = 7 Answer: B
Question: The speed of a car is 90 km in the first hour and 60 km in the second hour. What is the average speed of the car?
A.15 kmph
B.18 kmph
C.19 kmph
D.12 kmph
Answer: B.18 kmph
Explanation: S = (90 + 60)/2
= 75 kmph
Answer:B
Question: What would be the minimum number of pumps required to fill a tank of 1000 m3 to 85% in one hour? The capacity of the pump is 150 m3/hour and operates at an efficiency of 75%.
A.6
B.8
C.10
D.11
Answer: B.8
Explanation: Volume handled by pump in one hour=150x.75=112.5
Volume of the tank that needs to be filled=1000x.85=850
Number of pumps needed=850/112.5=7.55â‰ˆ8
Answer:B
Question: If the wheel is 12 cm then the number of revolutions to cover a distance of 1056 cm is?
A.18
B.27
C.26
D.14
Answer: D.14
Explanation: 2 * 22/7 * 12 * x = 1056
=> x = 14
Answer: D
Question: 39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?
A.10
B.13
C.14
D.15
Answer: B.13
Explanation: According to the chain rule,
M1 x T1 = M2 x T2
Therefore, 36 x 12 x 5 = 30 x 6 x X
X = 13
Hence, the number of days = 13.
ANSWER:B
Question: Number of the students in a school 5000. It decreases annually at the rate of 10% p.a. What will be its number of the students after 3 years?
A.3635
B.3500
C.4000
D.4500
Answer: A.3635
Explanation: Formula :
( After =100 denominator
Ago = 100 numerator)
8000 Ã— 90/100 Ã— 90/100 x 90/100 = 3635
A
Question: A type E machine can complete a job in 5 hours and a type B machine can complete the job in 7 hours. How many hours will it take 2 type E machines and 3 type B machines working together and independently to complete the job?
A.1/5
B.29/35
C.5/6
D.35/29
Answer: D.35/29
Explanation: now D should be the answer.
E need 5 hours to complete
and B needs 7 hours to compete
so 2E + 3B will complete 2/5 + 3/7 or 29/35 portion of the job in 1 hour
so the whole job will take 35/29 hours....=D
Question: In a group of 80 children and 10 youngsters, each child got sweets that are 15% of the total number of children and each youngster got sweets that are 25% of the total number of children. How many sweets were there?
A.1160
B.2881
C.2678
D.2321
Answer: A.1160
Explanation: Number of sweets each child got = 15% of 80 = 15/100 * 80 = 12.
Number of sweets 80 children got = 80 * 12 = 960.
Number of sweets each youngster got = 25% of 80 = 25/100 * 80 = 20.
Number of sweets 10 youngsters got = 10 * 20 = 200.
Total number of sweets = 960 + 200 = 1160.
Answer:A
Question: 8 is 2% of a, and 2 is 8% of b. c equals b/a. What is the value of c?
A.1/16
B.1/4
C.1
D.4
Answer: A.1/16
Explanation: 2a/100 = 8
a = 400
8b/100 = 2
b = 25
c = b/a = 25/400 = 1/16
The answer is A.
Question: In a games hour 4 different types of players came to the ground? cricket 11, hockey 15, football 21, softball 15. In these 4 people play both cricket and hockey, 3people play both softball and football. 2 people play both cricket and football. How many people play only cricket?
A.11
B.5
C.8
D.3
Answer: B.5
Explanation: people play only cricket = total players in cricket- both cricket and football- both cricket and hockey.
people play only cricket = 11-4-2 = 5
Answer is B
Question: 38 69 22 73 31 47 13 82 66 97 41 79
Which of the following numbers is greater than three fourths of the numbers but less than one fourth of the numbers in the list above?
A.71
B.76
C.81
D.92
Answer: B.76
Explanation: Arrange the numbers in ascending order:
13, 22, 31, 38, 41, 47, 66, 69, 73, 79, 82, 97 (Just cross check the count to ensure that you didn't miss anything)
How many numbers do we see?
12, alright.
What's (1/4)12?
3.
What's (3/4)12?
9.
We're asked to find a number that are greater than 6 numbers in the list AND smaller than the remaining two.
13, 22, 31, 38, 41, 47, 66, 69, 73, 79, 82, 97
13, 22, 31, 38, 41, 47, 66, 69, 73: Find a number greater than any of these numbers.
79, 82, 97: Find a number smaller than any of these numbers.
Only 76 fits the description.
Ans:B
Question: The price of lunch for 20 people was $300 including a 20% gratuity for service. What was the average price per person, EXCLUDING the gratuity?
A.11.73
B.12.5
C.13.8
D.14
Answer: B.12.5
Explanation: Clearly B is the answer
I used POE here
Lets consider option (B)
20*12.5= 250 now 250(120/100)=300
=> possible ANSWER IMO B
Question: In a particular game, there can be eight players at one time on the pitch and they last for seventy minutes. In the total duration, six players substitute with each player. All the players are then for the same time on the pitch including the substitutes.
Can you calculate the time each player was on the pitch?
A.40 Min
B.37 Min
C.42 Min
D.45 Min
Answer: A.40 Min
Explanation: A
40 minutes
The total number of players = 8 + 6 = 14
According to the question, only eight players can be present on the field. Thus calculating the total time:
70 * 8 = 560
We know that there are 14 players in total so dividing the total time by 14 will give us the time spent by each player.
560/14 = 40 minutes
Question: Suresh started a business, investing Rs.18000. After 3 months and 4 months respectively, Rohan and Sudhir joined him with capitals of 12000 and 9000. At the end of the year the total profit was Rs.3872. What is the difference between Rohan’s and Sudhir’s share in the profit?
A.s.345
B.s.350
C.s.352
D.s.362
Answer: C.s.352
Explanation: Suresh : Rohan : Sudhir
Ratio of their investments = 18000 × 12 : 12000 × 9 : 9000 × 8
= 6 : 3: 2
The difference between Rohan’s and Sudhir’s share = 1 share
:.i.e. = Rs. 3872 × 1/11 = Rs.352.
C
Question: A person purchases tomatoes from each of the 4 places at the rate of 1 kg, 2 kg, 3 kg, 4 kg per rupee respectively. On an average he has purchased x kg of tomatoes per rupee. Then the value of x is
A.2
B.2.5
C.1.92
D.None of these
Answer: B.2.5
Explanation: x = 10/4 = 2.5
Answer: B.
Question: a car cover a distance of 715 km. with some speed.if speed of car is 10km/hour more,then it take 2 hour less to cover that distance.then initially what was the speed of the car?
A.45km/h
B.50km/h
C.55km/h
D.65km/h
Answer: C.55km/h
Explanation: let speed=x km./hour.then,
715/x-715/(x+10)=2,1/x-1/(x+10)=2/715;(x+10)-x/x(x+10)=2/715
2x(x+10)=7150;2x^2+20x-7150=0
x^2+10x-3575=0;x^2+65x-55x-3575=0
x(x+65)-55(x+65)=0;(x+65)(x-55)=0
x=55,because x can't be -65
answer C
Question: A pump can fill a tank with water in 2 hours. Because of a leak, it took 4 hours to fill the tank. The leak can drain all the water in ?
A.2hr
B.1hr
C.3hr
D.4hr
Answer: D.4hr
Explanation: Work done by the leak in 1 hour = 1/2 - 1/4 = 1/4
Leak will empty the tank in 4 hours
Answer is D
Question: What is 15% of 2/3 of 0.8?
A.0.08
B.0.8
C.9
D.90
Answer: A.0.08
Explanation: The best way to solve these questions is to convert every term into fraction
(15/100)*(2/3)*(8/10) = 240/3000 = 0.08
Option A
Question: 128 students represent x percent of the boys at a school. If the boys at the school make up 50% of the total school population of x students, what is x?
A.160
B.190
C.225
D.250
Answer: A.160
Explanation: Let B be the number of boys in the school.
128 = xB/100
B = 0.5x
12800=0.5x^2
x^2 = 25600
x = 160
The answer is A.
Question: If to a certain number, 720 be added, and the sum be divided by 125 ; the quotient will be equal to 7392 divided by 462. What is that number?
A.1280
B.1270
C.1260
D.1250
Answer: A.1280
Explanation: Solution
Let x = the number required.
a = 720 d = 7392
b = 125 h = 462
Then by the conditions of the problem (x + a)/b = d/h
Therefore x = (bd - ah)/h
Restoring the numbers,x = [(125.7392) - (720.462)]/462 = 1280.
Answer A
Question: In a class, the average age of 35 boys is 10 years and the average of 25 girls is 15 years. what is the average age of the whole class?
A.11 Years
B.12.1 Years
C.13 Years
D.13.5 Years
Answer: B.12.1 Years
Explanation: Total age of 60 students
(35X 10+25 X 15) = 725
Average = 725/60 = 12.1 Years
B)
Question: Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is?
A.17/25
B.17/24
C.17/29
D.17/20
Answer: D.17/20
Explanation: n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(EᴜP) = 10/20 + 8/20 - 1/20 = 17/20
Answer: D
Question: From the below series find the remainder from below? 1201 × 1203 ×1205 × 1207 is divided by 6
A.3
B.5
C.6
D.7
Answer: A.3
Explanation: If you don't know the above rule, this problem is really calculation intensive.
But by applying the above rule, when 1201, 1201, 1203, 1204 divided by 6, leaves remainders 1, 3, 5, 1. The product of these remainders = 15.
When 15 is divided by 6, Remainder is 3
A
Question: a is x % of b, b is x% more than a. Find x.
A.50%
B.62%
C.75%
D.37%
Answer: B.62%
Explanation: DETAILED SOLUTION
a = bx
b = a (1 + x), substituting this in the previous equation, we get
x (x + 1) = 1
x2 + x - 1 = 0
or x is approximately 0.62 or 62%.
Correct Answer: (B).
Question: A train 110 m long travels at 60 kmph. How long does it take to pass a telegraph post by the side of the track ?
A.3.4
B.2.4
C.6.6
D.2.8
Answer: C.6.6
Explanation: Speed of train = 60 ×5/18 m/s = 50/3 m/s ∴ Time taken to cross the telegraph post = 110/(50/3)
= 6.6 seconds
Answer: C
Question: The distance between two cities A and B is 465 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
A.09
B.07
C.12
D.05
Answer: C.12
Explanation: Explanation:
Suppose they meet x hrs after 8 a.m
then,
[Distance moved by first in x hrs] + [Distance moved by second in (x-1) hrs] = 465
Therefore, 60x + 75(x-1) = 465
=> x=3.
So,they meet at (8+4) i.e, 12 noon
Answer: C)
Question: Can you solve the alphametic?
ENLIST + SILENT + LISTEN = ANAGRAM
A.1816412
B.1416312
C.1516312
D.1216312
Answer: B.1416312
Explanation: Correct Answer : B
assume numeric values for alphabetics. like a=0, b=1, c=2, c=3, d=4, e=5,...
solution
547809+087549+780954 = 1416312
Question: If (x + 2)(x - a) = px2x2 + qx + 8, what are the values of the constants a, p and q?
A.299
B.278
C.-4,1,6
D.2378
Answer: C.-4,1,6
Explanation: (x + 2)(x - a) = px2px2 + qx + 8
⇒x2⇒x2 + 2x - ax - 2a = px2px2 + qx + 8
⇒x2⇒x2 + (2 - a) x - 2a = px2px2 + qx + 8
Equating the coefficients of x2x2 , x and constant terms on both sides.
p = 1; q = 2 - a
-2a = 8
Solving, we get a = -4, p = 1, q = 6
Answer:C
Question: A grocer has a sale of Rs 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6500 ?
A.4991
B.3435
C.2365
D.2443
Answer: A.4991
Explanation: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs.[(6500 x 6) - 34009]
= Rs. (39000 - 34009)
= Rs. 4991.
Answer: A
Question: A certain number when divided by 80 leaves a remainder 25, what is the remainder if the same no.be divided by 15?
A.4
B.5
C.6
D.7
Answer: D.7
Explanation: Explanation:
80 + 25 = 105/15 = 7 (Remainder)
D
Question: Write 870,000,000,000 in scientific notation.
A.8.7 * 10^11
B.800.900 * 10^11
C.8.900 * 10^11
D.80.9000* 10^11
Answer: A.8.7 * 10^11
Explanation: a * 10 n , where a is a real number such that 1 * |a| < 10 and n is an integer.
870,000,000,000 = 8.7* 100,000,000,000 = 8.7 * 10 11**
correct answer A
Question: Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 13 cm.
A.335 cm2
B.885 cm2
C.285 cm2
D.247 cm2
Answer: D.247 cm2
Explanation: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)
= 1/2 (20 + 18) * (13)
= 247 cm2
Answer: D
Question: A sum of Rs.4800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.
A.8120
B.3120
C.8776
D.2879
Answer: B.3120
Explanation: Let A be the amount received at the end of the three years.
A = 4800[1 + 10/100][1 + 20/100][1 + 25/100]
A = (4800 * 11 * 6 * 5)/(10 * 5 * 4)
A = Rs.7920
So the interest = 7920 - 4800 = Rs.3120
Answer: B
Question: A tank is filled to one quarter of its capacity with a mixture consisting of water and sodium chloride. The proportion of sodium chloride in the tank is 50% by volume and the capacity of the tank is 24 gallons. If the water evaporates from the tank at the rate of 0.5 gallons per hour, and the amount of sodium chloride stays the same, what will be the concentration of water in the mixture in 2 hours?
A.32%
B.36%
C.40%
D.44%
Answer: C.40%
Explanation: The number of gallons in the tank is (1/4)24 = 6 gallons
The amount of sodium chloride is 0.5(6) = 3 gallons
At the start, the amount of water is 0.5(6) = 3 gallons
After 2 hours, the amount of water is 3 - 0.5(2) = 2 gallons
The concentration of water is 2 / (3+2) = 2/5 = 40%
The answer is C.
Question: David is 18 years older than his daughter Rosy. In 6 years David will be twice as old as Rosy. What is Rosy current age.
A.12
B.14
C.18
D.24
Answer: A.12
Explanation: Now: Rosy = x, David =x+18
In 6 years Rosy = x+6, David = x+18+6 or 2(x+6)
x+24= 2x+12
x= 12
Rosy is 12 years old
Answer : A
Question: The area of the cardboard(in cm2) needed to make a box of size 25 cm * 15 cm * 8 cm will be?
A.1390 cm2
B.695 cm2
C.1280 cm2
D.1220 cm2
Answer: A.1390 cm2
Explanation: 2(25 * 15 + 15 * 8 + 25 * 8)
2(375 + 120 + 200) => 1390
ANSWER:A
Question: What annual installment will discharge a debt of Rs. 4600 due in 4 years at 10% simple interest?
A.1000
B.1030
C.1100
D.None of these
Answer: A.1000
Explanation: Let the 1st installment = 100/-
It is 3yrs before due
IInd is 2yr before due
III3rd is 1yr before due
IVth is 0 yrs before due
On 1st installment interest will be paid for 3yrs
2nd installment interest will be paid for 2yrs
3rd installment interest will be paid for 1yr
4th installment interest will be paid for 0yr
Interest = P[(100(3+2+1+0)x10)/100] = 60/-
Total loan discharged = 4*100+60/- = 460/-
Now installment of 100/- loan discharged = 460/-
Loan discharged 4600/- ? Installment = 1000/-
Answer: A.
Question: What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder?
A.1108
B.1683
C.2000
D.3300
Answer: B.1683
Explanation: LCM of 5,6,7 and 8 = 840
hence => (840*1)+3 = 843 which is not divisible by 9
if k = 2, no = (840*2)+3=1683 is divisble by 9
ANSWER B
Question: What approximate value should come in place of question mark (?) in the following equation
287.532 + 1894.029 – 657.48 = 643.095 + ?
A.870
B.790
C.880
D.770
Answer: C.880
Explanation: ? = 285 + 1895 – 655 – 645 or, ? = 880
Answer C
Question: A sum of money becomes triple itself in 5 years at simple interest. How many years will it become five times at the same rate?
A.12 Â½ years
B.62 Â½ years
C.18 Â½ years
D.10 Â½ years
Answer: D.10 Â½ years
Explanation: 100 ---- 200 ---- 5
200 ---- 5
100 ---- 2 1/2
------------------
500 ---- 10 Â½ years
Answer:D
Question: Which of the following is satisfied with |x-4|+|x-3|<4?
A.1<x<5
B.2<x<5
C.1.5<x<5.5
D.2.5<x<4
Answer: C.1.5<x<5.5
Explanation: --> If there is addition when there are 2 absolute values, you can just ignore the middle. That is, |x-4|+|x-3|<4 -> |x-4+x-3|<4 -> |2x-7|<4, -4<2x-7<4, 3<2x<11, 3/2<x<11/2 -> 1.5<x<5.5
Therefore, the answer is C.