RikoteMaster/aqua-rat-mcqa huggingface dataset:
Question: Suresh started a business with Rs.20,000. Kiran joined him after 4 months with Rs.30,000. After 2 more months, Suresh withdrew Rs.5,000 of his capital and 2 more months later, Kiran brought in Rs.20,000 more. What should be the ratio in which they should share their profits at the end of the year?
A.21:32
B.32:21
C.12:17
D.17:12
Answer: A.21:32
Explanation: Explanation:
Here capital is not the same.
Suresh invested 20000 for initial 6 months and 15000 for the next 6 months. Hence his term of ratio
=(20000×6+15000×6):(30000×4+50000×4)
=(20×6+15×6):(30×4+50×4)
=(20×3+15×3):(30×2:50×2)
=105:160
=21:32
Answer: Option A
Question: If a - b = 3 and a(power 2) + b(power 2) = 39, find the value of ab.
A.15
B.8
C.4
D.10
Answer: A.15
Explanation: 2ab = (a(power 2) + b(power 2) - (a - b)(power 2)
= 39 - 9 = 30
ab = 15.
Answer is A.
Question: What will come in place of the x in the following Number series? 5,28,57,88,125
A.124
B.154
C.166
D.178
Answer: C.166
Explanation: 28=23+5
57=29+28
88=31+57
125=37+88
166=41+125
=166
C
Question: If the sum of 8 consecutive integers is x, which of the must be true?
I. x is even
II. x is odd
III. x is a multiple of 8
A.I only
B.II only
C.III only
D.I and III
Answer: D.I and III
Explanation: sum of 6 consecutive integers
= (n) + (n+1) + (n+2) + (n+3) + (n+4) + (n+5)+(n+6)+(n+7)
= 8n + 28
= even + even = even
= 4(2n+7) = divisible by 4
Hence, x is even and divisible by 4.
Answer: D
Question: In a 100m, A beats B by 15m and B beats C by 10m. If A beats C by 5 sec then the speed of C.
A.5m/sec
B.Speed of C can not be found with given data.
C.4.7m/sec
D.4m/sec
Answer: C.4.7m/sec
Explanation: When A finishes the race , B is at 85m....
and when B travels 100m, C is at 100-10 = 90m.....
so C loses 10m on B's 100m................
or C will lose 1 m for every 10m of B.....
so C will lose 8.5 m when B travels 85m.....
From above we get correlation of all three..
A is at 100, B is at 85 and C is at 85-8.5 = 76.5
So C is 100-76.5 = 23.5 m behind A...
and C also loses by 5 secs, this means C covers this 23.5m in 5 secs..
speed of C =23.5/5=4.723.55=4.7 mps
ANSWER:C
Question: To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present?
A.63
B.64.5
C.62.5
D.60.5
Answer: C.62.5
Explanation: Let required number of buckets =x
If capacity of buckets are reduced, more number of buckets are required (indirect proportion). Therefore,
25:x=(2/5):1
⇒25=2x/5
⇒x=62.5
Answer: C
Question: In 10 years,A will be 5 times as old as B was 10 years ago.If A is now 9 years older than B,the present age of B is :
A.17.25 Years
B.29 Years
C.39 Years
D.49 Years
Answer: A.17.25 Years
Explanation: Solution
Let B's present age = x years.Then,A's present age =(x +9) years.
âˆ´ (x + 9)+ 10 = 5 (x - 10) â‡” x + 19 = 5x- 50 â‡” 4x = 69.
x = 17.25
Answer A
Question: A single discount equivalent to the discount series of 20%, 10% and 5% is?
A.31.6
B.31.0
C.31.6
D.31.1
Answer: C.31.6
Explanation: 100*(80/100)*(90/100)*(95/100)
= 68.4
100 - 68.4 = 31.6
Answer: C
Question: 25 % of 1250
A.330
B.315
C.312.5
D.370
Answer: C.312.5
Explanation: 1 % of 1250 is = 12.5025% of 1250 is = 12.50 * 25 = 312.5Answer : C
Question: What is the next number of the following sequence
8,0.5,16,4,15,0.3,50,4.5,6,.2,30,?
A.0.6
B.0.8
C.1.2
D.1.6
Answer: C.1.2
Explanation: 8,0.5,16,4,15,0.3,50,4.5,6,.2,30,X
(8,0.5,16,4),(15,0.3,50,4.5),(6,.2,30,X)
in each group, 1st/2nd=3rd & 1st*2nd=4th
8/0.5=16, 8*0.5=4
15/0.3=50, 15*0.3=4.5
6/.2 = 30, 6*.2=X => X=1.2
ANSWER:C
Question: A chair is bought for Rs.1000/- and sold at a loss of 20% find its selling price
A.Rs.800/-
B.Rs.510/-
C.Rs.515/-
D.Rs.530/-
Answer: A.Rs.800/-
Explanation: Loss = 1000*20/100 = 200
S.P = C.P - Loss
= 1000- 200
=Rs.800/-
Answer :A
Question: The speed of a boat in still water in 42 km/hr and the rate of current is 5 km/hr. The distance travelled downstream in 44 minutes is:
A.86.6 km
B.46.6 km
C.34.5 km
D.35.6 km
Answer: C.34.5 km
Explanation: Speed downstream = (42 + 5) = 47 kmph
Time = 44 minutes =44/60 hour = 11/15 hour
Distance travelled = Time × speed =11/15×47 = 34.5 km
ANSWER:C
Question: Series B(n) is such that i*B(i) = j*B(j) for any pair of positive integers (i, j). If B(1) is a positive integer, which of the following is possible?
I. 2*B(100) = B(99) + B(98)
II. B(1) is the only integer in the series
III. The series does not contain negative numbers
A.I only
B.II only
C.IIII only
D.IIIII only
Answer: D.IIIII only
Explanation: First thing I want to understand is this relation: i*B(i) = j*B(j) for any pair of positive integers. I will take examples to understand it.
When i = 1 and j = 2, B(1) = 2*B(2)
So B(2) = B(1)/2
When i = 1 and j = 3, B(1) = 3*B(3)
So B(3) = B(1)/3
I see it now. The series is: B(1), B(1)/2, B(1)/3, B(1)/4 and so on...
II and III are easily possible. We can see that without any calculations.
II. B(1) is the only integer in the series
If B(1) = 1, then series becomes 1, 1/2, 1/3, 1/4 ... all fractions except B(1)
III. The series does not contain negative numbers
Again, same series as above applies. In fact, since B(1) is a positive integer, this must be true.
I. 2*B(100) = B(99) + B(98)
2*B(1)/100 = B(1)/99 + B(1)/98 (cancel B(1) from both sides)
2/100 = 1/99 + 1/98
Not true hence this is not possible
Answer (D)
Question: In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 2009 were what percent of the profits in 2008?
A.80%
B.105%
C.120%
D.124.2%
Answer: C.120%
Explanation: x = profits
r= revenue
x/r = 0,1
x= 10
r=100
2009:
r=80
x/80 = 0,15 = 15/100
x= 80*15/100
x= 12
12/10 = 1,2 = 120%, Answer C
Question: Find the number that fits somewhere into the middle of the series. Some of the items involve both numbers and letters
Look at this series: E10, H13, __, N19, Q22, ... What number should fill the blank?
A.H13
B.I14
C.J15
D.K16
Answer: D.K16
Explanation: D
K16
In this series, the letters progress by 3, and the numbers increase by 3.
Question: Kramer can pack X boxes of cigarettes per minute. If there are Y boxes of cigarettes in one case, how many cases can Kramer pack in 1 hours?
A.60X/Y.
B.120X/Y.
C.60Y/X.
D.120Y/X.
Answer: A.60X/Y.
Explanation: Kramer can pack X boxes per min.
Therefore in 1 hrs(60mins)he can pack 60X boxes.
If there are Y boxes in one case then then the total number of cases packed by Kramer = 60X/Y
(ANSWER A)
Question: The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
A.4 years
B.8 years
C.6 years
D.2 years
Answer: A.4 years
Explanation: Let the ages of children be X, (X + 3), (X + 6), (X + 9) and (X + 12) years.
Then, X + (X + 3) + (X + 6) + (X + 9) + (X + 12) = 50
5X = 20
X = 4.
Age of the youngest child = X = 4 years.
ANSWER:A
Question: Score Interval Number of Scores
50-59 2
60-69 10
70-79 16
80-89 25
90-99 18
The table shows a distribution of test scores. Which score interval contains the median of the 71 scores?
A.a) 60-69
B.b) 70-79
C.c) 80-89
D.d) 90-99
Answer: C.c) 80-89
Explanation: 36th person
80-89 C
Question: Kala and Sudha stated a business with an investment of Rs.18000 and Rs.24000 respectively. After 3 months Gita joined in the business with an investment of Rs.20000, find share of Gita, if the difference between the profits received by Kala and Sudha is Rs.840 ?
A.2150
B.2200
C.2100
D.2250
Answer: C.2100
Explanation: Ratio of investments Kala : Sudha : Githa => 18000 : 24000 : 20000 => 9 : 12 : 10.
Investment x time.
Kala = 9 x 12 = 108.
Sudha = 12 x 12 = 144.
Githa = 10 x 9 = 180.
Or Kala : Sudha : Githa => 6 : 8 : 5.
Let shares of Kala, Sudha and Githa be = 6a : 8a : 5a.
Difference between the profits received by Kala and Sudha
6a – 8a = 2a = 840 or a = 420.
Githa = 5a = 5 x 420 = Rs.2100.
Option C
Question: A bowl contains equal numbers of red, orange, green, blue, and yellow candies. Kaz eats all of the green candies and half of the orange ones. Next, he eats half of the remaining pieces of each color. Finally, he eats red and yellow candies in equal proportions until the total number of remaining candies of all colors equals 32% of the original number. What percent of the red candies remain?
A.27.5%
B.33.3%
C.35.5%
D.42.5%
Answer: D.42.5%
Explanation: Let x be the original number of each color so there are a total of 5x candies.
Kaz eats all of the green candies and half of the orange ones.
There are 0 green candies and 0.5x orange candies remaining.
He eats half of the remaining pieces of each color.
There are 0.25x orange candies, and 0.5x each of red, yellow, and blue candies.
He eats red and yellow candies in equal proportions.
orange+blue+red+yellow = 0.75x + red + yellow = 1.6x
red + yellow = 0.85x
red = 0.425x, since red = yellow.
The answer is D.
Question: (935421 x 625) = ?
A.584638125
B.584638130
C.584638135
D.584638140
Answer: A.584638125
Explanation: 935421 x 625 = 935421 x 54 = 935421 x 10 4
2
=	935421 x 104	=	9354210000
24	16
= 584638125
A)
Question: The number of digits of the smallest number, which when multiplied by 7 gives the result consisting entirely of nines is
A.3
B.5
C.6
D.8
Answer: C.6
Explanation: Sol.
By hit and trial, we find that a number exactly divisible by 7 and consisting entirely of nines is 999999. Number of digits in it = 6.
Answer C
Question: Find the remainder when 2^31 is divided by 5.
A.9
B.7
C.1
D.3
Answer: D.3
Explanation: 2^31=(2^10*2^10*2^10)*2=(2^10)^3 *2=(1024)^3 *2
unit digit in 2^31=unit digit in {(1024)^3*2}=(4*2)=8.
Now, 8 when divided by 5 gives 3 as remainder
2^31 when divided by 5 gives remainder =3.
Answer is D
Question: The average weight of a group of boys is 30 kg. After a boy of weight 35 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
A.4
B.8
C.6
D.2
Answer: A.4
Explanation: Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 35 kg joins the group, total weight of boys = 30x + 35
So 30x + 35 + 31(x + 1) = > x = 4.
Answer:A
Question: In each series, look for the degree and direction of change between the numbers. In other words, do the numbers increase or decrease, and by how much
Look at this series: 3.5, 6.5, 9.5, 12.5, ... What number should come next?
A.4.7
B.3.6
C.4.9
D.15.5
Answer: D.15.5
Explanation: 15.5
In this simple addition series, each number increases by 3.0
Answer : D
Question: If sequence T is defined for all positive integers n such that t(n +1) = t(n) + n, and t 3 = 14, what is t 21?
A.101
B.187
C.191
D.221
Answer: D.221
Explanation: ok, not sure if this is the best explanation, but here is my way of solving this :
tn +1 = tn + n,
t 3 = 14
so:
t 4 = t 3 + 3
t 5 = t 4 + 4, so we replace t 4 with the previous result : t 5 = (t 3 + 3 ) + 4
....
so we get
t 21 = t 3 + 3 + 4 + 5 + 6....+ 19+20
the 3 + 4 + 5 + ... + 19 +20 sequence is equal the sequence 1 + 2 + ... + 19,+20 minus 1 + 2 at the beginning (so, minus 3)
and the 1 + 2 ... + 19 +20 sequence is equal to n*(n+1)/2 with n being 20, so equal to 20 * 21 / 2 = 210
so :
t 21 = t 3 + 210 - 3
t 21 = 14 + 210 - 3 = 210 + 11 = 221, hence answer D
Question: On a baseball team, 4 players including Alice want to play 1st base, 2nd base, or 3rd base. Before every game, the coach chooses a name randomly from a bag and this person plays 1st base. Then the coach chooses the next name randomly and this person plays 2nd base. The coach then chooses a third name randomly and this person plays 3rd base. What is the probability that Alice plays 1st, 2nd, or 3rd base?
A.3/4
B.5/6
C.7/8
D.9/16
Answer: A.3/4
Explanation: The total number of ways to choose three players is 4C3=4.
Excluding Alice, the number of ways to choose three players is 3C3=1.
P(Alice is not chosen)=1/4.
P(Alice is chosen)=1 - 1/4 = 3/4.
The answer is A.
Question: Out of a list of mailing addresses, company A has x addresses, company B has y addresses, and companies A and B combined have a total number of addresses equal to 3 times as many as company A has. How many mailing addresses belong to both companies?
A.x
B.y
C.x + y
D.y - 2x
Answer: D.y - 2x
Explanation: Let s denote the shared addresses between A and B.So A will have distinct x - s addresses and B will have y - s addresses
.
Given "A and B combined have a total number of addresses equal to 3 times as many as company A has"
i.e, x + y - s = 3 x (s is subtracted because it's captured twice)
solve for s and it gives, y - 2x.
Answer is D
Question: Find the no.of ways of arranging the boy and 8 guests at a circular table so that the boy always sits in a particular seat?
A.3! ways
B.8! ways
C.7! ways
D.10! ways
Answer: B.8! ways
Explanation: Ans.(B)
Sol. Total number of persons = 9 Host can sit in a particular seat in one way. Now, remaining positions are defined relative to the host. Hence, the remaining can sit in 8 places in 8P8 = 8! Ways ... The number of required arrangements = 8! x 1= 8! = 8! ways
Question: In a rectangular coordinate system, what is the square root of the area of a trapezoid whose vertices have the coordinates (2, -2), (2, 3), (20, 2), (20, -2)?
A.7.5
B.9
C.10.22
D.12.25
Answer: B.9
Explanation: we can form rectangle and then minus the area of triangle
18*5 -9 =81 sq rt of which is 9
ANSWER:B
Question: What number should replace the question mark? 5, 24, 11, 20, 17, 16, ---?
A.20
B.23
C.22
D.21
Answer: B.23
Explanation: Answer: B
5, 24, 11, 20, 17, 16, 23?
There are two alternate sequences: +6 and -4.
Question: Elena purchased Brand X pens for $4.00 apiece and brand Y for $2.80 apiece. If Elena purchased a total of 10 of these pens for $42.00, how many brand X pens did she purchase?
A.4
B.5
C.6
D.7
Answer: B.5
Explanation: 4x+2.8y=42 --> multiply by 2.5 (to get the integers) --> 10x+7y=105 --> only one positive integers solutions x=5 and y=5 (how to solve: 7y must have the last digit of 5 in order the last digit of the sum to be 5).
Answer: B.
Question: A certain freshman class has 600 students and a certain sophomore class has 900 students. Among these students, there are 75 two-person sets of lab partners, each consisting of 1 freshman and 1 sophomore. If 1 student is to be selected at random from each class, what is the probability that the 2 students selected will be a set of lab partners?
A.1/75
B.1/96
C.1/5400
D.1/7200
Answer: D.1/7200
Explanation: there are 600*900 two people sets. (total outcomes)
75 sets are 2 people sets and lab partners ( favorable outcomes)
so the probability that the 2
students selected will be a set of lab partners = 75/(600∗900)75/(600∗900)
= 1/7200
Answer: D
Question: There are 10 points in a plane out of which 4 are collinear. Find the number of triangles formed by the points as vertices.
A.120
B.116
C.140
D.20
Answer: B.116
Explanation: The number of triangle can be formed by 10 points = 10C3.
Similarly, the number of triangle can be formed by 4 points when no one is collinear=4C3.
In the question, given 4 points are collinear, Thus, required number of triangle can be formed,
= 10C3-4C3 = 120-4 = 116.
Option B
Question: Which of the following represents the profit from the investment of x dollars at n percent compound annual interest for 2 years?
A.5x (1+n/100)^2 - x
B.2x (1+n/100)^4 - x
C.3x (1+n/100)^3 - x
D.x (1+n/100)^2 - x
Answer: D.x (1+n/100)^2 - x
Explanation: Amount after 2 years compounded yearly = x (1+n/100)^2
Thus profit = Final amount - original principle = x (1+n/100)^2 - x . Answer : D
Question: The positive difference of the fourth powers of two consecutive positive integers must be divisible by
A.one less than twice the larger integer
B.one more than twice the larger integer
C.one less than four times the larger integer
D.one more than four times the larger integer
Answer: A.one less than twice the larger integer
Explanation: Using Picking Numbers for this, Let the two positive integers be 2, 3
3^4−2^4=81−16=65
(A) one less than twice the larger integer = 2(3) - 1 = 5 --> 65 is divisible by 5
(B) one more than twice the larger integer = 2(3) + 1 = 7 --> ruled out
(C) one less than four times the larger integer = 4(3) - 1 = 11 --> ruled out
(D) one more than four times the larger integer = 4(3) + 1 = 13 --> 65 is divisible by 13
(E) one more than eight times the larger integer = 8(3) + 1 = 25 --> ruled out
Another set of numbers, 3,4
4^4−3^4=256−81=175
(A) one less than twice the larger integer = 2(4) - 1 = 7 --> 175 is divisible by 7
(D) one more than four times the larger integer = 4(4) + 1 = 17 --> ruled out
Answer : A
Question: A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg?
A.Rs.41
B.Rs.48
C.Rs.40
D.Rs.42
Answer: C.Rs.40
Explanation: Explanation:
800*(25/100) = 200 ---- 5
? ---- 1 => Rs.40
Answer: C
Question: Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is?
A.277
B.299
C.125
D.99
Answer: C.125
Explanation: 3x * 2x = 3750 => x = 25
2(75 + 50) = 250 m
250 * 1/2 = Rs.125
Answer:C
Question: Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
A.17 a.m
B.10 a.m
C.70 a.m
D.16 a.m
Answer: B.10 a.m
Explanation: Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
Therefore 20x + 25(x - 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.
Answer:B
Question: How long will a boy take to run round a square field of side 50 meters, if he runs at the rate of 12km/hr?
A.52sec
B.45sec
C.60sec
D.25sec
Answer: C.60sec
Explanation: Speed = 12 km/hr = 12*5/18 = 10/3 m/sec
Distance = 50*4 = 200m
Time taken = 200*3/10 = 60sec
Answer is C
Question: At what rate percent on simple interest will Rs.750 amount to Rs.900 in 5 years?
A.5%
B.3 1/2%
C.4%
D.5 1/2 %
Answer: C.4%
Explanation: 150 = (750*5*R)/100
R = 4%
Answer :C
Question: Twenty years ago,a father was three times as old as his son.Now the father is only twice as old as his son. Then the sum of the present ages of the son and the father is :
A.120
B.76
C.108
D.105
Answer: A.120
Explanation: Let the present ages of the father and son be 2x and x years respectively.
then,(2x-20)=3 (x-20)
x=40.
Required sum =(2x+x)=3x=120 years.
Answer is A
Question: The total of company C's assets in 1994 was 300% greater than the total in 1993, which in turn was 200% greater than the total in 1992. If the total of company C's assets in in 1992 was N dollars, which one of the following represents company C's assets in 1994:
A.7N
B.8N
C.9N
D.12
Answer: D.12
Explanation: Let's use actual numbers. Starting in 1992, let's say company C had $100 in assets.
In 1993, the total assets were 200% GREATER, which means 1992 PLUS 200% of 1992:
$100 + 2x$100 = $100 + $200 =$300
In 1994, the total assets were 300% GREATER than they were in 1993, which means 1993 PLUS 300% of 1993:
$300 + 3x$300 = $300 + $900 =$1200
This is 12 times the 1992 number, so the correct answer is 12N.
D
Question: Zada has to distribute 15 choclates among 5 of her children Sana,ada,jaya,amir and farhan. She has to make sure that sana gets at least 3 and ada at most 6 choclates. In how many ways can this be done?
A.495
B.77
C.417
D.435
Answer: A.495
Explanation: (3,1,11)=165
(4,1,10)=120
(5,1,9)=84
(6,1,8)=56
ANSWER:A
Question: A number when divided by 219 gives a remainder 32, what remainder will be obtained by dividing the same number 12?
A.7
B.11
C.9
D.2
Answer: B.11
Explanation: Explanation:
219 + 32 = 251/12 = 9 (Remainder)
Answer: B
Question: To celebrate a colleague's retirement, the T coworkers in an office agreed to share equally the cost of a catered lunch. If the lunch costs a total of P dollars and S of the coworkers fail to pay their share, which of the following represents the additional amount, in dollars, that each of the remaining coworkers would have to contribute so that the cost of the lunch is completely paid?
A.P/T
B.P/(T-S)
C.SP/(T-S)
D.SP/T(T-S)
Answer: D.SP/T(T-S)
Explanation: Since no absolute values are given in the question we can replace the given parameters with assumed numbers,
Let Total colleagues be 100 (T)
Let total contribution be 700 (P) (point to note is that its total cost not per person)
Those who dont pay are S (30)
Per person cost = P/T = 700/100 = 7
So cost for those who failed to pay = (P/T) * S = SP/T = 30*7=210
The equation for people who would bear the total cost after S people fail = (T-S)=70
There fore the solution is (SP/T)/ (T-S) = SP/T(T-S) = 210/70
Answer D
Hope this helps !!!
Question: A and B complete a work in 6 days. A alone can do it in 10 days. If both together can do the work in how many days?
A.3.75 days
B.3.78 days
C.3.65 days
D.3.77 days
Answer: A.3.75 days
Explanation: 1/6 + 1/10 = 8/30 = 4/15
15/4 = 3.75 days
Answer:A
Question: A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
A.2997
B.2776
C.2988
D.1640
Answer: D.1640
Explanation: (x*8*3)/100 = ((2665 - x)*3*5)/100
24x/100 = 39975/100 - 15x/100
39x = 39975 => x = 1025
Second sum = 2665 – 1025 = 1640
Answer: D
Question: If a car went the first third of the distance at 10 kmh, the second third at 24 kmh, and the last third at 48 kmh, what was the average speed of the car for the entire trip?
A.36 kmh
B.19 kmh
C.42 kmh
D.44 kmh
Answer: B.19 kmh
Explanation: Assume D/3 = 240 (this number is convenient because it is divisible by 10, 24 and 48)
So:
240 = 10*T1 = 24 hrs
240 = 24*T2 = 10 hrs
240 = 48*T3 = 5 hrs
T = T1 + T2 + T3 = 39 hrs
D = RT
(240*3) = R*39
R = 19
ANSWER: B
Question: The difference between compound interest and simple interest on an amount of $15,000 for 2 years is $96. What is the rate of interest per annum?
A.6%
B.7%
C.9%
D.8%
Answer: D.8%
Explanation: [15000 x (1 + R/100)^2 - 15000] - [(15000 x R x 2)/100] = 96
==> 15000[(1 + R/100)^2 - 1 - 2R/100] = 96
==> 15000[((100 + R)^2 - 10000 - (200 x R))/10000] = 96
==> R^2 = (96 x 2)/3 = 64
==> R = 8. Rate = 8%
Answer D)8%
Question: The perimeter of a semi circle is 126 cm then the radius is?
A.22
B.28
C.98
D.24.5
Answer: D.24.5
Explanation: 36/7 r = 126
=> r
= 24.5
Answer: D
Question: During a trip, Francine traveled x percent of the total distance at an average speed of 60 miles per hour and the rest of the distance at an average speed of 40 miles per hour. In terms of x, what was Francineâ€™s average speed for the entire trip?
A.(180-x)/2
B.(x+60)/4
C.(300-x)/5
D.12,000/(300-x)
Answer: D.12,000/(300-x)
Explanation: D....
X% traveeled at 60 mph
100-X% traveeled at 40 mph
total timt taken = x/60 +(100-x)/40 = (300-x)/120
Total distance = x+(100-x) = 100
Av speed = Tot Dis/Time Taken which is D
Question: Martha has 5 dogs and 6 cats. She takes each animal separately for a daily walk. She can take the animals for a walk to the park or to the barber shop. How many different options for a walk with a single animal does Martha have?
A.22
B.9
C.10
D.18
Answer: A.22
Explanation: 5 dogs, 4 cats; park/barber shop
1 dog - 2 options - either park or barber shop, so, 5 dogs - 10 options and 6 dogs - 12 options.
Total = 22 options.
A
Question: A boy runs 200 metres in 48 seconds. What is his speed ?
A.10 km/hr
B.15 km/hr
C.11 km/hr
D.12 km/hr
Answer: B.15 km/hr
Explanation: 200/48 * 18/5 = 15 km/hr
ANSWER:B
Question: Last year the range of the annual salaries of the 100 employees at Company X was $30,000. If the annual salary of each of the 100 employees this year is 10 percent greater than it was last year, what is the range of the annual salaries of the 100 employees this year?
A.$27,000
B.$30,000
C.$33,000
D.$36,000
Answer: C.$33,000
Explanation: Plug in numbers...
Say on the lowest side we have $10,000 & the highest, $40,000
$10,000 x .10 = $1,000 --> New low side = $11,000
$40,000 x .10 = $4,000 --> New high side = $44,000
New range --> $44,000-$11,000 = $33,000
Correct answer is C