Steam at `100^(@)C` is passed into `20 g` of water at `10^(@)C` when water acquire a temperature of
Channel: Doubtnut
Date: 2020-01-19

Steam at `100^(@)C` is passed into `20 g` of water at `10^(@)C` when water acquire a temperature of `80^(@)C`, the mass of water present will be [Take specific heat of water `= 1 cal g^(-1).^(@) C^(-1)` and latent heat of steam ` = 540 cal g^(-1)`]