`0.85%` aqueous solution of `NaNO_(3)` is apparently `90%` dissociated at `27^(@)C`. Calculate its
Channel: Doubtnut
Date: 2020-08-02

`0.85%` aqueous solution of `NaNO_(3)` is apparently `90%` dissociated at `27^(@)C`. Calculate its osmotic pressure. `(R = 0.0821 atm K^(-1) mol^(-1)`)