The shortest distance between the parabola `y^2 = 4x` and the circle `x^2 + y^2 + 6x - 12y + 20 = 0`
Channel: Doubtnut
Date: 12/04/2020

The shortest distance between the parabola `y^2 = 4x` and the circle `x^2 + y^2 + 6x - 12y + 20 = 0` is : (A) 0 (B) 1 (C) `4sqrt(2) -5` (D) `4sqrt(2) + 5`