In any `DeltaABC` (i)`tan((B-C)/2)=((b-c)/(b+c))cot(A/2)` (ii) `tan((A-B)/2)=((a-b)/(a+b))cot(C/2)`
Channel: Doubtnut
Date: 2020-01-19

In any `DeltaABC` (i)`tan((B-C)/2)=((b-c)/(b+c))cot(A/2)` (ii) `tan((A-B)/2)=((a-b)/(a+b))cot(C/2)` (iii)`tan((C-A)/2)=((c-a)/(c+a))cot(B/2)`