A Condition for Checking Subgroups
Channel: Andrew Misseldine
Date: 2020-09-25

In this video, we present and prove conditions for a subset being a subgroup. Essentially, the subset is a subgroup if it is closed under multiplication, it contains the identity, and it contains inverses. 

This is lecture 10 (part 3/5) of the lecture series offered by Dr. Andrew Misseldine for the course Math 4220 - Abstract Algebra I at Southern Utah University. A transcript of this lecture can be found at Dr. Misseldine's website or through his Google Drive at: https://drive.google.com/file/d/1esmgsyKVR-sRPPF0t09aWXT1Yc8OatA9/view

This lecture is based upon Sections 3.3 of Abstract Algebra: Theory and Applications (http://abstract.ups.edu/) by Tom Judson. Please post any questions you might have below in the comment field and Dr. Misseldine (or other commenters) can answer them for you. Please also subscribe for further updates.