The position vector of a particle R as function of time is given by R=4sin(2πt)i + 4cos(2πt)j where
Channel: Ritesh Dahiya (RD Sir) (KDC) Kota Doubt Counter
Date: 2020-09-04

The position vector of a particle R ⃗ as a function of time is given by R ⃗=4" " sin(2πt)i ̂+4cos(2πt)j ̂ where R is in metres, t is in seconds and i ̂  and j ̂ denote unit vectors along x-and y- directions, respectively. Which one of the following, statements are wrong for the motion of particle?   (NEET 2015)
Magnitude of the velocity of particle is 8π meter/ second. 
Path of the particle is a circle of radius 4 meter.
Acceleration vector is along -R ⃗.
Magnitude of acceleration vector is v^2/R, where v is the velocity of particle.


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