Force between two identical charges placed at a distance  of `r` in vacume is `F`. Now a slab  of
Channel: Doubtnut
Date: 2020-08-16

Force between two identical charges placed at a distance  of `r` in vacume is `F`. Now a slab  of dielectric constant 4 is inserted between these two charges . If the thickness of the slab is `r//2`, then the force between the charges will becomes