The rate of decomposition of acetaldehyde into methane and CO in the presence
Channel: Doubtnut
Date: 2020-03-29

The rate of decomposition of acetaldehyde into methane and CO in the presence of `I_(2)` at 800 K follows the rate law: Rate `=k[CH_(3)CHO][I_(2)]` The decomposition is believed to go by a two step mechanism: `CH_(3)CHO + I_(2) to CH_(3)I + HI + CO` `CH_(3)I + HI to CH_(4) + I_(2)` What is the catalyst for the reaction ? Which of the two steps is a slower one ?