If `[x]` denotes the integral part of `[x]`, show that: `int_0^((2n-1)pi) [sinx]dx=(1-n)pi,n in N`
Channel: Doubtnut
Date: 2020-04-12

If `[x]` denotes the integral part of `[x]`, show that: `int_0^((2n-1)pi) [sinx]dx=(1-n)pi,n in N`