A vessel of 250 L was filled with 0.01 mole of `Sb_(2)S_(3)` and 0.01 mole of `H_(2)` to attain the
Channel: Doubtnut
Date: 26/01/2020

A vessel of 250 L was filled with 0.01 mole of `Sb_(2)S_(3)` and 0.01 mole of `H_(2)` to attain the equilibrium at `440^(@)C` as `Sb_(2)S_(3(s))+3H_(2(g))hArr2Sb_(s)+3H_(2)S_(g)` After equilibrium the `H_(2)S` formed was analysed by dissolving it in water and treating with excess of `Pb^(2+)` to give 1.19 g of PbS as precipitate. The value of `K_(C)` at `440^(@)C` is `(Pb=20S)`