A 5 m long aluminium wire `(Y=7xx10^10(N)/(m^2)`) of diameter 3 mm supprts a 40 kg mass. In order
Channel: Doubtnut
Date: 2020-01-19

A 5 m long aluminium wire `(Y=7xx10^10(N)/(m^2)`) of diameter 3 mm supprts a 40 kg mass. In order to have the same elongation in a copper wire `(Y=12xx10^10(N)/(m^2)`) of the same length under the same weight, the diameter should now, in mm