LCR Circuit Experiment - (101% Overunity)
Channel: debunkified
Date: 2018-04-09

A simple LCR circuit experiment that is exhibiting an overunity measurement. Most if not all measures have been taken to get the most accurate meter readings. The meters are accurately portraying the input and output power in the form of watts. The measurements are completely consistent with Ohm's law and what it calculates. Although not entirely necessary, the capacitor is included just to make sure that the voltage is really there across the "load", which is a resistor, or a load resistor. The capacitor is a snubbing type bandwidth filter which acts to smooth out the voltage to it's real value, which the meter can measure with the most precision. Now with an accurate voltage we can divide that into the resistance of the load resistor and obtain an amperage (current) measurement which then of course can be multiplied with the voltage to find an accurate wattage. Although not an extremely huge amount of wattage is involved here, it is still an impressive result nevertheless. 

With the present 555 timer circuit if a higher value timing capacitor is used in order to lower the frequency then the effect goes away and a normal efficiency occurs where the load is receiving just 100% or slightly below, similar to what a pure direct current would normally do. The fact that 50% of the energy is lost in charging the capacitor is taken into account as well. However the 50% loss of energy no longer applies when the load resistor is connected in parallel to the capacitor. Once the resistor is added then the capacitor simply becomes the voltage source that the load resistor then draws current from, which of course slightly drops the voltage across the capacitor. Of course if the capacitor is completely discharged (near empty) and then pulse charged before the load resistor begins drawing current from it, then there is a 50% loss of energy from the power source into the capacitor. After the capacitor is fully charged then the circuit is in a solid steady state and the 101% efficiency stays continuously. Perhaps this is the reason and explanation of Nikola Tesla's "Method of Conversion" which doesn't make sense otherwise. Why pulse dc from a spark gap and into load of lamps when you could do directly from the DC power supply right? There is a reason and I believe this shows that reason.

Two different approaches are used in order to measure the input and output wattage. The first way has the meter measuring "all" current going into the circuit directly from the negative side of the the power supply and so everything is included in the input current. Here is the schematic for that approach. :

https://drive.google.com/open?id=1VSv9W5uHXX5jryCb9G6_rOOCdMlOyMJO

The second way is when another meter is placed in between the capacitor and the resistor to measure the current flowing into the load resistor "only". In this way we can see what the wattage of the output load actually is when compared with the input wattage. Keep in mind that there is a tiny little microamp constantly flowing through the capacitor at all times because there is current constantly leaking out of the capacitor. For all intents and purposes the capacitor is basically blocking most all of the current from the power source. It can be seen that the input and output current are essentially identical with each other, minus the tiny loss of the capacitor due to current leakage found in most capacitors. And so this is the reason for placing the meter in between the capacitor and resistor so that this current leakage is not included in the load resistor measurement. The input meter just after the power source's negative is also measuring the small 1.5µA as well and should be ignored if it's ignored on the output as well. In general all current going in is basically the same as all current going out and into the load resistor. Here's the schematic for this approach. :

https://drive.google.com/open?id=1tm-NJI9k2VkZ2UT0UtJou-znhEyrHNYk

The coil isn't absolutely necessary as well and the voltage across the load remains higher than the input voltage, but it does help boost the voltage up just a little higher. If the extra voltage isn't coming from the coil nor the capacitor, then where is it coming from? I postulate that it resides within the high frequency pulses from the power supply. The frequency of the 555 timer circuit is 145.758 KHz which is very good for a 555 timer which also happens to be a megahertz 555 chip. Only the power pulsing it's way through the mosfet switch and LCR circuit is being examined here and not the power driving the 555 timer switching, as that is meaningless when we are only concerned with the power supply pulsing the LCR and then comparing that to what it's output power is. If you have any questions I will try to answer them best that I can.