"If the eccentricity of the hyperbola `x^2-y^2sec^2alpha=5\ i s\ sqrt(3)` times the eccentricity
Channel: Doubtnut
Date: 2020-07-05

"If the eccentricity of the hyperbola `x^2-y^2sec^2alpha=5\ i s\ sqrt(3)`
 times the eccentricity the ellipse `x^2sec^2alpha+y^2=25\ t h e n\ alpha=`
 
 a.`pi/6`
 b. `pi/4`
 c. `pi/3`
 d. `pi/2`"