To a `25 mL` of `H_(2)O_(2)` solution, excess of acidified solution of `KI` was added. The iodine
Channel: Doubtnut
Date: 02/11/2021

To a `25 mL` of `H_(2)O_(2)` solution, excess of acidified solution of `KI` was added. The iodine liberated required `20 mL` of 0.3 N `Na_(2)S_(2)O_(3)` solution. Calculate the volume strength of `H_(2)O_2` solution.  Strategy : Volume strength of `H_(2)O_(2)` solution is related to its normality by the following relation  Volume strength `(V)=5.6xx"Normality" (N)`  where, Normality`=((meq)H_(2)O_(2))/V_(mL)`  According to the law of equivalence  `(meq)_(Na_(2)S_(2)O_(3))=(meq)_(I_(2))=(meq)_(H_(2)O_(2))`