If `sinx+cosy=1` and `cos2x-cos2y=1` then the values of `x` and `y` are (A) `x=npi+(-1)^n pi/3, n
Channel: Doubtnut
Date: 12/04/2020

If `sinx+cosy=1` and `cos2x-cos2y=1` then the values of `x` and `y` are (A) `x=npi+(-1)^n pi/3, n in I, y=mpi+-pi/6, m in I` (B) `x=npi+(-1)^n pi/6, n in I, y=mpi+-pi/3, m in I` (C) `x=npi+(-1)^n pi/4, n in I, y=mpi+-pi/4, m in I` (D) none of these