The proof of (e^x -1)/ x = 1 when x approaches 0 and d/dx(e^x) = e^x by first principle
Channel: mattam66
Date: 2013-01-24

In this video I have shown how the limit when x approaches 0 of the function (e^x-1)/x =1 and then used it to prove that d/dx(e^x) = e^x by first principle
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