There is a current of 40 ampere in a wire of `10^(-6)m^(2)` are of cross-section
Channel: Doubtnut
Date: 2020-08-23

There is a current of 40 ampere in a wire of `10^(-6)m^(2)` are of cross-section. If the number of free electron per `m^(3)` is `10^(29)` then the drift velocity will be