The vertices of a `DeltaABC` are `A(3, 0), B (0, 6) and C (6, 9)`. A straight line DE divides
Channel: Doubtnut
Date: 2020-04-05

The vertices of a `DeltaABC` are `A(3, 0), B (0, 6) and C (6, 9)`. A straight line DE divides AB and AC in the ration 1:2 at D and E respectively, prove that `(DeltaABC)/(DeltaADE) = 9`