If `e_1 and e_2` be the eccentricities of hyperbola and its conjugate, then `1/e^2_1 + 1/e^2_2 =` `
Channel: Doubtnut
Date: 2020-04-12

If `e_1 and e_2` be the eccentricities of hyperbola and its conjugate, then `1/e^2_1 + 1/e^2_2 =` (A) `sqrt(2)/8` (B) `1/4` (C) `1` (D) `4`