`18g` of glucose (molar mass `180g "mol"^(-1)`) is present in `500CM^(3)` of its aqueous
Channel: Doubtnut
Date: 2020-04-05

`18g` of glucose (molar mass `180g "mol"^(-1)`) is present in `500CM^(3)` of its aqueous solution. What is the molarity of the solution? What additional data is required if the molality of the solution is also required to be calculated?