Two equal masses of `6.40 kg` are separted by a distance of `0.16 m`. A small body is released
Channel: Doubtnut
Date: 2020-08-02

Two equal masses of `6.40 kg` are separted by a distance of `0.16 m`. A small body is released from a point `P`, equidistant from the two masses and at a distance of `0.06 m` from the line joining them. Fig.   (a) Calculate the velocity of this body when it passes through `Q`.   (b) Calculate the acceleration of this body at `P` and `Q` if its mass is `0.1 kg`.   Use `G = 6.67 xx 10^(-11) N m^(2) kg^(-2)`