"If `sintheta=(12)/(13)`, find the  value of `(sin^2theta-cos^2theta)/(2sinthetacostheta)xx1/(tan^
Channel: Doubtnut
Date: 2020-07-05

"If `sintheta=(12)/(13)`
, find the
  value of `(sin^2theta-cos^2theta)/(2sinthetacostheta)xx1/(tan^2theta)`"