A body cools from `50^(@)C` to `49.9^(@)C` in `5` sec. it cools from `40^(@)C` to `39.9^(@)C`
Channel: Doubtnut
Date: 2020-01-28

A body cools from `50^(@)C` to `49.9^(@)C` in `5` sec. it cools from `40^(@)C` to `39.9^(@)C` in t sec. Assuming Newtons law of cooling to be valid and temperature of surrounds at `30^(@)C`, value of t//5 will be?