When a metalic surface is illuminated with light of wavelength `lambda,`  the stopping potential is
Channel: Doubtnut
Date: 2021-11-02

When a metalic surface is illuminated with light of wavelength `lambda,`  the stopping potential is V. the same surface is illuminated by light of wavelength `2lambda` the stopping potential is `(V)/(3)` The thershold waelength for the surface is