If `(log x)/(y-z)=(logy)/(z-x) =(logz)/(x-y)`, then prove that: `x^x y^y z^z=1`
Channel: Doubtnut
Date: 2020-04-05

If `(log x)/(y-z)=(logy)/(z-x) =(logz)/(x-y)`, then prove that: `x^x y^y z^z=1`