The equation of a transverse travelling on a rope is given by `y=10sinpi (0.01x-2.00t) where y and x
Channel: Doubtnut
Date: 2020-01-19

The equation of a transverse travelling on a rope is given by `y=10sinpi (0.01x-2.00t)` where y and x are in cm and t in seconds. The maximum transverse speed of a particle in the rope is about