Under the action of a force, a `2 kg` body moves such that its position x as a function
Channel: Doubtnut
Date: 2020-07-12

Under the action of a force, a `2 kg` body moves such that its position x as a function of time is given by `x =(t^(3))/(3)` where x is in metre and t in second. The work done by the force in the first two seconds is .