In Fig. 6.38, the sides AB and AC of ABC are produced to points E and D respectively. If bisectors
Channel: Doubtnut
Date: 2020-07-12

In Fig. 6.38, the sides AB and AC of ABC are produced to points E and D respectively. If bisectors BO and CO of CBE and BCD respectively meet at point O, then prove that `/_B O C=90o-1/2/_B A C`.