`C_(6)H_(6) + Br_(2) rightarrow C_(6)H_(5)Br + HBr`   In an experiment, to prepare bromobenzene
Channel: Doubtnut
Date: 2020-04-26

`C_(6)H_(6) + Br_(2) rightarrow C_(6)H_(5)Br + HBr`   In an experiment, to prepare bromobenzene according to the equation, a student reacted 20.0g of `C_(6)H_(6)` with 0.310 mol of bromine. If 28.0 g of `C_(6)H_(5)Br` was obtained, what was the percentage yield?