let `S_(n)` denote the sum of the cubes of the first n natural numbers and `s_(n)` denote the sum of
Channel: Doubtnut
Date: 2020-01-19

let `S_(n)` denote the sum of the cubes of the first n natural numbers and `s_(n)` denote the sum of the first n natural numbers , then `sum_(r=1)^(n)(S_(r))/(s_(r))` equals to