The trajectory of a projectile in a vertical plane is `y = ax - bx^2`, where `a and b` are constant
Channel: Doubtnut
Date: 2020-07-26

The trajectory of a projectile in a vertical plane is `y = ax - bx^2`, where `a and b` are constant and `x and y` are, respectively, horizontal and vertical distances of the projectile from the point of projection. The maximum height attained by the particle and the angle of projectile from the horizontal are.