Let `vecAB = 3 hati + hatj - hatk and vecAC = hati -hatj + 3hatk` and a point P on the
Channel: Doubtnut
Date: 2020-05-24

Let `vecAB = 3 hati + hatj - hatk and vecAC = hati -hatj + 3hatk` and a point P on the line segment BC is  equidistant  from AB and AC, then `vec (AP)` is