The enthalpy of combustion of mol. Wt. 180 glucose is -2808 KJ `"mol"^(
Channel: Doubtnut
Date: 2020-04-19

The enthalpy of combustion of mol. Wt. 180 glucose is -2808 KJ `"mol"^(-1)` at `25^(@)`C . X and Y grams of glucose do you need to consume respectively cases [Assume wt=62.5 Kg].   (a) to climb a flight of stairs rising through 3M.   to climb a mountain of altitude 3000 M?   Assume that 25% of enthalpy can be converted to useful work.   X and Y are related as X=mY, then find m.