Calculate the temperature at which the average K.E. of a molecule of a gas will be the
Channel: Doubtnut
Date: 2020-08-02

Calculate the temperature at which the average K.E. of a molecule of a gas will be the same as that of an electron accelerated through 1 volt. Boltzmann constant `= 1.4 xx 10^(-23) J "molecule"^(-1) K^(-1)`, charge of an electron `= 1.6 xx 10^(-19)C`.