A light source of wavelength `lambda` illuminates a metal and ejects photoelectron with `(KE)^(max)
Channel: Doubtnut
Date: 19/04/2020

A light source of wavelength `lambda` illuminates a metal and ejects photoelectron with `(KE)^(max) = 1 eV.`   Another light source of wave length `(lambda)/(3),` ejects   photoelectrons from same metal with `(KE)^(max)=5 eV.`   Find the value of work function (eV) of metal.