Trajectory of a particle in a projectile motion is given as `y=x-(x^(2))/80`. Here `x` and `y`
Channel: Doubtnut
Date: 2021-11-02

Trajectory of a particle in a projectile motion is given as `y=x-(x^(2))/80`. Here `x` and `y` are in metre. For this projectile motion the following with `g=10m//s^(2)`. img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MPP_PHY_C03_S01_079_Q01.png" width="80%"img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MPP_PHY_C03_S01_079_Q01.png" width="80%"