"In figure `A B=A C\ a n d\ C P||B A` and `A P` is the bisector of   exterior `/_C A D` of ` A B C`
Channel: Doubtnut
Date: 28/06/2020

"In figure `A B=A C\ a n d\ C P||B A`
 and `A P`
 is the bisector of
 
  exterior `/_C A D`
 of ` A B C`
 . Prove that
 `/_P A C=/_B C A`
  (ii) `A B C P`
 is a parallelogram"