Given `P = (3,-6,10)and PQ = sqrt(17)` . If direction cosines of line PQ are ` (-2)/(sqrt(17)),3/
Channel: Doubtnut
Date: 24/05/2020

Given `P = (3,-6,10)and PQ = sqrt(17)` . If direction cosines of line PQ are ` (-2)/(sqrt(17)),3/(sqrt(17)),(-2)/(sqrt(17))` , then point Q can be