A bar magnet with poles ` 25 cm` apart and of strength `14.4 amp - m` rests with centre
Channel: Doubtnut
Date: 05/07/2020

A bar magnet with poles ` 25 cm` apart and of strength `14.4 amp - m` rests with centre on a frictionless pivot. It  is held in equilibrium aat an angle of ` 60@` with respect to a uniform magnetic field of induction `0.25 Wb//m^(2) , by applying a force `F` at right angles to its axis at a point `12 cm` from pivot. Calculate `F`. What will happen if the force `F` is removed?