For the reaction `C_(2)H_(6)(g)hArrC_(2)H_(4)(g)+H_(2)(g)`   `K_(p)` is `5xx10^(-2)`
Channel: Doubtnut
Date: 19/04/2020

For the reaction `C_(2)H_(6)(g)hArrC_(2)H_(4)(g)+H_(2)(g)`   `K_(p)` is `5xx10^(-2)` atm. Calculate the mole per cent of `C_(2)H_(6)(g)` at equilibruium if pure `C_(2)H_(6)` at `1` atm is passed over a suitable catalyt at `900 K` :