Two reactions `R_(2) and R_(2)` have identical pre - exponential factors. Activations enery
Channel: Doubtnut
Date: 10/11/2021

Two reactions `R_(2) and R_(2)` have identical pre - exponential factors. Activations enery of `R_(1)` exceeds that of `R_(2)`  by 10 kJ `mol_(-1)` . If `k_(1) and k_(2)` are rate constants for rate constants  for reactions `R_(1) and R_(2)`   respectively at 300k , then In `(k_(2)/k_(1))`is equal to `(R=8.314 J mol^(-1)K^(-1))`