Total number of divisors of `N=2^(5)*3^(4)*5^(10)*7^(6)` that are of the form `4n+2,n ge 1`,
Channel: Doubtnut
Date: 24/05/2020

Total number of divisors of `N=2^(5)*3^(4)*5^(10)*7^(6)` that are of the form `4n+2,n ge 1`, is equal to