In Young's double-slit experiment `lambda = 500 nm, d = 1 mm`, and `D = 4 m`. The minimum
Channel: Doubtnut
Date: 02/08/2020

In Young's double-slit experiment `lambda = 500 nm, d = 1 mm`, and `D = 4 m`. The minimum distance from the central maximum for which the intensity is half of the maximum intensity is `'**' xx 10^(-4) m`. What is the value of `'**'`?