`int_0^2 x^3[1+cos((pix)/2)]dx`, where `[x]` denotes the integral part of `x`, is equal to (A) `1/2`
Channel: Doubtnut
Date: 2020-04-12

`int_0^2 x^3[1+cos((pix)/2)]dx`, where `[x]` denotes the integral part of `x`, is equal to (A) `1/2` (B) `1/4` (C) `0` (D) none of these