Equation of the hyperbola with eccentricity 3/2 and foci at `(+-2, 0)\" is \"5x^(2)-4y^(2)=k^(
Channel: Doubtnut
Date: 2020-01-28

Equation of the hyperbola with eccentricity 3/2 and foci at `(+-2, 0)\" is \"5x^(2)-4y^(2)=k^(2)`. What is the value of k ?