"Let P be the   point on the parabola, `y^2=8x` which is at a minimum distance   from
Channel: Doubtnut
Date: 2020-07-05

"Let P be the   point on the parabola, `y^2=8x` which is at a minimum distance   from the centre C of the   circle,`x^2+(y+6)^2=1.` Then the equation of the circle, passing through C and having its centre at P is : (1) `x^2+y^2-4x+8y+12=0`  (2) `x^2+y^2-x+4y-12=0`  (3) `x^2+y^2-x/4+2y-24=0`  (4) `x^2+y^2-4x+9y+18=0`"