Calculate the enthalpy change for the following reaction:  `XeF_(4) rarr Xe^(o+) +F^(Theta)
Channel: Doubtnut
Date: 26/07/2020

Calculate the enthalpy change for the following reaction:  `XeF_(4) rarr Xe^(o+) +F^(Theta) +F_(2) +F`. The average `Xe-F` bond energy is `34 kcal mol^(-1)`, first `IE` of `Xe` is `279 kcal mol^(-1), EA` of `F` is `85 kcal mol^(-1)` and bond dissociation enegry of `F_(2)` is `38 kcal mol^(-1)`