A metallic rod length `L` and the mass `M` is moving under the action of two unequal `F_(1)`
Channel: Doubtnut
Date: 30/08/2020

A metallic rod length `L` and the mass `M` is moving under the action of two unequal `F_(1)` and `F_(2)` (directed opposite to each other) acting at its ends along its length. Ignore gravity and any external magnetic field. If sepecific charge of electrons is `(e//m)`, then the potential difference between the ends of the rod is steady state must be