A sample of calcuium carbonate `(CaCO_(3))` has the following percentage composition: `Ca=40%,
Channel: Doubtnut
Date: 2020-01-19

A sample of calcuium carbonate `(CaCO_(3))` has the following percentage composition: `Ca=40%, C=12%, O=48%` If the law of constant proportions is true. Then the weight of calcium in `4 g` of a sample of calcium carbonate obtained from another source will be