Differential equation of all tangents to the parabola `y^2=4ax` is (A) `y=mx+a/m
Channel: Doubtnut
Date: 12/04/2020

Differential equation of all tangents to the parabola `y^2=4ax` is (A) `y=mx+a/m , m!=0` (B) `y_1(yy_1-x)=a` (C) `xy_1^2-yy_1+a=0` (D) none of these