`10 L` of hard water required `0.56 g` of lime `(CaO)` for removing hardness. Hence, temporary
Channel: Doubtnut
Date: 12/07/2020

`10 L` of hard water required `0.56 g` of lime `(CaO)` for removing hardness. Hence, temporary hardness in ppm (part per million `10^(6)`) of `CaCO_(3)` is: