de Broglie wavelength `'lambda'` of an ideal gas molecule at any given temperature  is given as
Channel: Doubtnut
Date: 2020-04-19

de Broglie wavelength `'lambda'` of an ideal gas molecule at any given temperature  is given as `lambda prop m^(-x) xxT^(-y).`   Where `m=` mass of one gas molecule, `T=` temperature (K).   `"Given" x + y=?`