QIAN-ME/bird_schema_data huggingface dataset:
You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 student_loan
【Schema】
# Table: unemployed
[
(name:TEXT, Primary Key, Examples: [student1000, student102, student106])
]
# Table: longest_absense_from_school
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(month:INTEGER, Examples: [0, 1, 2])
]
# Table: disabled
[
(name:TEXT, Primary Key, Examples: [student114, student125, student142])
]
# Table: person
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100])
]
# Table: male
[
(name:TEXT, Primary Key, Examples: [student1, student101, student102])
]
# Table: no_payment_due
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(bool:TEXT, Examples: [neg, pos])
]
# Table: enrolled
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(school:TEXT, Primary Key, Examples: [occ, smc, ucb]),
(month:INTEGER, Examples: [1, 2, 3])
]
# Table: enlist
[
(name:TEXT, Examples: [student40, student51, student109]),
(organ:TEXT, Examples: [fire_department, air_force, navy])
]
# Table: bool
[
(name:TEXT, Primary Key, Examples: [neg, pos])
]
# Table: filed_for_bankrupcy
[
(name:TEXT, Primary Key, Examples: [student122, student126, student136])
]
【Foreign keys】
unemployed.name=person.name
longest_absense_from_school.name=person.name
disabled.name=person.name
male.name=person.name
no_payment_due.name=person.name
no_payment_due.bool=bool.name
enrolled.name=person.name
enlist.name=person.name
filed_for_bankrupcy.name=person.name

    【Question】
    List at least 5 students who have payment due and are enlisted in Peace Corps organization? have payment due refers to bool = 'pos'; organization refers to organ; organ = 'Peace Corps';

    【Evidence】
    have payment due refers to bool = 'pos'; organization refers to organ; organ = 'Peace Corps';

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT T1.name FROM no_payment_due AS T1 INNER JOIN enlist AS T2 ON T2.name = T1.name WHERE T2.organ = 'peace_corps' AND T1.bool = 'pos' LIMIT 5
You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 student_loan
【Schema】
# Table: unemployed
[
(name:TEXT, Primary Key, Examples: [student1000, student102, student106])
]
# Table: longest_absense_from_school
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(month:INTEGER, Examples: [0, 1, 2])
]
# Table: disabled
[
(name:TEXT, Primary Key, Examples: [student114, student125, student142])
]
# Table: person
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100])
]
# Table: male
[
(name:TEXT, Primary Key, Examples: [student1, student101, student102])
]
# Table: no_payment_due
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(bool:TEXT, Examples: [neg, pos])
]
# Table: enrolled
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(school:TEXT, Primary Key, Examples: [occ, smc, ucb]),
(month:INTEGER, Examples: [1, 2, 3])
]
# Table: enlist
[
(name:TEXT, Examples: [student40, student51, student109]),
(organ:TEXT, Examples: [fire_department, air_force, navy])
]
# Table: bool
[
(name:TEXT, Primary Key, Examples: [neg, pos])
]
# Table: filed_for_bankrupcy
[
(name:TEXT, Primary Key, Examples: [student122, student126, student136])
]
【Foreign keys】
unemployed.name=person.name
longest_absense_from_school.name=person.name
disabled.name=person.name
male.name=person.name
no_payment_due.name=person.name
no_payment_due.bool=bool.name
enrolled.name=person.name
enlist.name=person.name
filed_for_bankrupcy.name=person.name

    【Question】
    How many disabled students are female? female refers to disabled.name who are NOT in male.name;

    【Evidence】
    female refers to disabled.name who are NOT in male.name;

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT COUNT(name) FROM disabled WHERE name NOT IN ( SELECT name FROM male )
You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 student_loan
【Schema】
# Table: unemployed
[
(name:TEXT, Primary Key, Examples: [student1000, student102, student106])
]
# Table: longest_absense_from_school
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(month:INTEGER, Examples: [0, 1, 2])
]
# Table: disabled
[
(name:TEXT, Primary Key, Examples: [student114, student125, student142])
]
# Table: person
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100])
]
# Table: male
[
(name:TEXT, Primary Key, Examples: [student1, student101, student102])
]
# Table: no_payment_due
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(bool:TEXT, Examples: [neg, pos])
]
# Table: enrolled
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(school:TEXT, Primary Key, Examples: [occ, smc, ucb]),
(month:INTEGER, Examples: [1, 2, 3])
]
# Table: enlist
[
(name:TEXT, Examples: [student40, student51, student109]),
(organ:TEXT, Examples: [fire_department, air_force, navy])
]
# Table: bool
[
(name:TEXT, Primary Key, Examples: [neg, pos])
]
# Table: filed_for_bankrupcy
[
(name:TEXT, Primary Key, Examples: [student122, student126, student136])
]
【Foreign keys】
unemployed.name=person.name
longest_absense_from_school.name=person.name
disabled.name=person.name
male.name=person.name
no_payment_due.name=person.name
no_payment_due.bool=bool.name
enrolled.name=person.name
enlist.name=person.name
filed_for_bankrupcy.name=person.name

    【Question】
    How many disabled students have payment due? have payment due refers to bool = 'pos';

    【Evidence】
    have payment due refers to bool = 'pos';

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT COUNT(T1.name) FROM disabled AS T1 INNER JOIN no_payment_due AS T2 ON T2.name = T1.name WHERE T2.bool = 'pos'
You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 student_loan
【Schema】
# Table: unemployed
[
(name:TEXT, Primary Key, Examples: [student1000, student102, student106])
]
# Table: longest_absense_from_school
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(month:INTEGER, Examples: [0, 1, 2])
]
# Table: disabled
[
(name:TEXT, Primary Key, Examples: [student114, student125, student142])
]
# Table: person
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100])
]
# Table: male
[
(name:TEXT, Primary Key, Examples: [student1, student101, student102])
]
# Table: no_payment_due
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(bool:TEXT, Examples: [neg, pos])
]
# Table: enrolled
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(school:TEXT, Primary Key, Examples: [occ, smc, ucb]),
(month:INTEGER, Examples: [1, 2, 3])
]
# Table: enlist
[
(name:TEXT, Examples: [student40, student51, student109]),
(organ:TEXT, Examples: [fire_department, air_force, navy])
]
# Table: bool
[
(name:TEXT, Primary Key, Examples: [neg, pos])
]
# Table: filed_for_bankrupcy
[
(name:TEXT, Primary Key, Examples: [student122, student126, student136])
]
【Foreign keys】
unemployed.name=person.name
longest_absense_from_school.name=person.name
disabled.name=person.name
male.name=person.name
no_payment_due.name=person.name
no_payment_due.bool=bool.name
enrolled.name=person.name
enlist.name=person.name
filed_for_bankrupcy.name=person.name

    【Question】
    Calculate the average number of female students who are disabled and who joined Foreign Legion organization. average = DIVIDE(COUNT(disabled.name who are not in male.name WHERE organ = 'foreign_legion'), COUNT(disabled.name)); female students who are disabled refers to disabled.name who are NOT in male.name; organization refers to organ; organ = 'Foreign Legion';

    【Evidence】
    average = DIVIDE(COUNT(disabled.name who are not in male.name WHERE organ = 'foreign_legion'), COUNT(disabled.name)); female students who are disabled refers to disabled.name who are NOT in male.name; organization refers to organ; organ = 'Foreign Legion';

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT CAST(SUM(IIF(T3.name IS NULL, 1, 0)) AS REAL) / COUNT(T1.name) FROM disabled AS T1 INNER JOIN enlist AS T2 ON T1.name = T2.name LEFT JOIN male AS T3 ON T2.name = T3.name WHERE T2.organ = 'foreign_legion'
You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 student_loan
【Schema】
# Table: unemployed
[
(name:TEXT, Primary Key, Examples: [student1000, student102, student106])
]
# Table: longest_absense_from_school
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(month:INTEGER, Examples: [0, 1, 2])
]
# Table: disabled
[
(name:TEXT, Primary Key, Examples: [student114, student125, student142])
]
# Table: person
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100])
]
# Table: male
[
(name:TEXT, Primary Key, Examples: [student1, student101, student102])
]
# Table: no_payment_due
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(bool:TEXT, Examples: [neg, pos])
]
# Table: enrolled
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(school:TEXT, Primary Key, Examples: [occ, smc, ucb]),
(month:INTEGER, Examples: [1, 2, 3])
]
# Table: enlist
[
(name:TEXT, Examples: [student40, student51, student109]),
(organ:TEXT, Examples: [fire_department, air_force, navy])
]
# Table: bool
[
(name:TEXT, Primary Key, Examples: [neg, pos])
]
# Table: filed_for_bankrupcy
[
(name:TEXT, Primary Key, Examples: [student122, student126, student136])
]
【Foreign keys】
unemployed.name=person.name
longest_absense_from_school.name=person.name
disabled.name=person.name
male.name=person.name
no_payment_due.name=person.name
no_payment_due.bool=bool.name
enrolled.name=person.name
enlist.name=person.name
filed_for_bankrupcy.name=person.name

    【Question】
    Calculate the ratio in percentage between the average number of female and male students who joined Fire Department organization. ratio = CONCAT(MULTIPLY(DIVIDE(COUNT(enlist.name WHERE organ = 'fire_department' which is NOT in male.name), COUNT(enlist.name WHERE organ = 'fire_department),'%'))) AS FEMALE; ratio = CONCAT(MULTIPLY(DIVIDE(COUNT(enlist.name WHERE organ = 'fire_department' which is IN male.name), COUNT(enlist.name WHERE organ = 'fire_department), 100))) AS MALE; female students refers to enlist.name who are NOT in male.name; male students refers to enlist.name who are IN male.name; organization refers to organ; organ = 'fire_department';

    【Evidence】
    ratio = CONCAT(MULTIPLY(DIVIDE(COUNT(enlist.name WHERE organ = 'fire_department' which is NOT in male.name), COUNT(enlist.name WHERE organ = 'fire_department),'%'))) AS FEMALE; ratio = CONCAT(MULTIPLY(DIVIDE(COUNT(enlist.name WHERE organ = 'fire_department' which is IN male.name), COUNT(enlist.name WHERE organ = 'fire_department), 100))) AS MALE; female students refers to enlist.name who are NOT in male.name; male students refers to enlist.name who are IN male.name; organization refers to organ; organ = 'fire_department';

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT CAST(SUM(IIF(T2.name IS NULL, 1, 0)) AS REAL) * 100 / COUNT(T1.name), CAST(SUM(IIF(T2.name IS NOT NULL, 1, 0)) AS REAL) * 100 / COUNT(T1.name) FROM enlist AS T1 LEFT JOIN male AS T2 ON T2.name = T1.name WHERE T1.organ = 'fire_department'
You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 student_loan
【Schema】
# Table: unemployed
[
(name:TEXT, Primary Key, Examples: [student1000, student102, student106])
]
# Table: longest_absense_from_school
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(month:INTEGER, Examples: [0, 1, 2])
]
# Table: disabled
[
(name:TEXT, Primary Key, Examples: [student114, student125, student142])
]
# Table: person
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100])
]
# Table: male
[
(name:TEXT, Primary Key, Examples: [student1, student101, student102])
]
# Table: no_payment_due
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(bool:TEXT, Examples: [neg, pos])
]
# Table: enrolled
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(school:TEXT, Primary Key, Examples: [occ, smc, ucb]),
(month:INTEGER, Examples: [1, 2, 3])
]
# Table: enlist
[
(name:TEXT, Examples: [student40, student51, student109]),
(organ:TEXT, Examples: [fire_department, air_force, navy])
]
# Table: bool
[
(name:TEXT, Primary Key, Examples: [neg, pos])
]
# Table: filed_for_bankrupcy
[
(name:TEXT, Primary Key, Examples: [student122, student126, student136])
]
【Foreign keys】
unemployed.name=person.name
longest_absense_from_school.name=person.name
disabled.name=person.name
male.name=person.name
no_payment_due.name=person.name
no_payment_due.bool=bool.name
enrolled.name=person.name
enlist.name=person.name
filed_for_bankrupcy.name=person.name

    【Question】
    How many students enlisted in the navy? navy refers to organ = 'navy';

    【Evidence】
    navy refers to organ = 'navy';

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT COUNT(name) FROM enlist WHERE organ = 'navy'
You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 student_loan
【Schema】
# Table: unemployed
[
(name:TEXT, Primary Key, Examples: [student1000, student102, student106])
]
# Table: longest_absense_from_school
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(month:INTEGER, Examples: [0, 1, 2])
]
# Table: disabled
[
(name:TEXT, Primary Key, Examples: [student114, student125, student142])
]
# Table: person
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100])
]
# Table: male
[
(name:TEXT, Primary Key, Examples: [student1, student101, student102])
]
# Table: no_payment_due
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(bool:TEXT, Examples: [neg, pos])
]
# Table: enrolled
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(school:TEXT, Primary Key, Examples: [occ, smc, ucb]),
(month:INTEGER, Examples: [1, 2, 3])
]
# Table: enlist
[
(name:TEXT, Examples: [student40, student51, student109]),
(organ:TEXT, Examples: [fire_department, air_force, navy])
]
# Table: bool
[
(name:TEXT, Primary Key, Examples: [neg, pos])
]
# Table: filed_for_bankrupcy
[
(name:TEXT, Primary Key, Examples: [student122, student126, student136])
]
【Foreign keys】
unemployed.name=person.name
longest_absense_from_school.name=person.name
disabled.name=person.name
male.name=person.name
no_payment_due.name=person.name
no_payment_due.bool=bool.name
enrolled.name=person.name
enlist.name=person.name
filed_for_bankrupcy.name=person.name

    【Question】
    Calculate the percentage of students who have never been absent. percentage = CONCAT(DIVIDE(MULTIPLY(COUNT(name WHERE month = 0), 100), COUNT(name)),'%'); never been absent refers to month = 0;

    【Evidence】
    percentage = CONCAT(DIVIDE(MULTIPLY(COUNT(name WHERE month = 0), 100), COUNT(name)),'%'); never been absent refers to month = 0;

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT CAST(SUM(IIF(month = 0, 1, 0)) AS REAL) * 100 / COUNT(name) FROM longest_absense_from_school
You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 student_loan
【Schema】
# Table: unemployed
[
(name:TEXT, Primary Key, Examples: [student1000, student102, student106])
]
# Table: longest_absense_from_school
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(month:INTEGER, Examples: [0, 1, 2])
]
# Table: disabled
[
(name:TEXT, Primary Key, Examples: [student114, student125, student142])
]
# Table: person
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100])
]
# Table: male
[
(name:TEXT, Primary Key, Examples: [student1, student101, student102])
]
# Table: no_payment_due
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(bool:TEXT, Examples: [neg, pos])
]
# Table: enrolled
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(school:TEXT, Primary Key, Examples: [occ, smc, ucb]),
(month:INTEGER, Examples: [1, 2, 3])
]
# Table: enlist
[
(name:TEXT, Examples: [student40, student51, student109]),
(organ:TEXT, Examples: [fire_department, air_force, navy])
]
# Table: bool
[
(name:TEXT, Primary Key, Examples: [neg, pos])
]
# Table: filed_for_bankrupcy
[
(name:TEXT, Primary Key, Examples: [student122, student126, student136])
]
【Foreign keys】
unemployed.name=person.name
longest_absense_from_school.name=person.name
disabled.name=person.name
male.name=person.name
no_payment_due.name=person.name
no_payment_due.bool=bool.name
enrolled.name=person.name
enlist.name=person.name
filed_for_bankrupcy.name=person.name

    【Question】
    What is the ratio of students who have payment due and those who do not have payment due? ratio =  DIVIDE(COUNT(name WHERE `bool` = 'pos'), COUNT(name WHERE `bool` = 'neg')); have payment due refers to `bool` = 'pos'; no payment due refers to `bool` = 'neg';

    【Evidence】
    ratio =  DIVIDE(COUNT(name WHERE `bool` = 'pos'), COUNT(name WHERE `bool` = 'neg')); have payment due refers to `bool` = 'pos'; no payment due refers to `bool` = 'neg';

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT CAST(SUM(IIF(`bool` = 'pos', 1, 0)) AS REAL) / SUM(IIF(`bool` = 'neg', 1, 0)) FROM no_payment_due
You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 student_loan
【Schema】
# Table: unemployed
[
(name:TEXT, Primary Key, Examples: [student1000, student102, student106])
]
# Table: longest_absense_from_school
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(month:INTEGER, Examples: [0, 1, 2])
]
# Table: disabled
[
(name:TEXT, Primary Key, Examples: [student114, student125, student142])
]
# Table: person
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100])
]
# Table: male
[
(name:TEXT, Primary Key, Examples: [student1, student101, student102])
]
# Table: no_payment_due
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(bool:TEXT, Examples: [neg, pos])
]
# Table: enrolled
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(school:TEXT, Primary Key, Examples: [occ, smc, ucb]),
(month:INTEGER, Examples: [1, 2, 3])
]
# Table: enlist
[
(name:TEXT, Examples: [student40, student51, student109]),
(organ:TEXT, Examples: [fire_department, air_force, navy])
]
# Table: bool
[
(name:TEXT, Primary Key, Examples: [neg, pos])
]
# Table: filed_for_bankrupcy
[
(name:TEXT, Primary Key, Examples: [student122, student126, student136])
]
【Foreign keys】
unemployed.name=person.name
longest_absense_from_school.name=person.name
disabled.name=person.name
male.name=person.name
no_payment_due.name=person.name
no_payment_due.bool=bool.name
enrolled.name=person.name
enlist.name=person.name
filed_for_bankrupcy.name=person.name

    【Question】
    Provide the students' names and schools who enrolled for 15 months. enrolled for 15 months refers to month = 15;

    【Evidence】
    enrolled for 15 months refers to month = 15;

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT name, school FROM enrolled WHERE month = 15
You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 student_loan
【Schema】
# Table: unemployed
[
(name:TEXT, Primary Key, Examples: [student1000, student102, student106])
]
# Table: longest_absense_from_school
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(month:INTEGER, Examples: [0, 1, 2])
]
# Table: disabled
[
(name:TEXT, Primary Key, Examples: [student114, student125, student142])
]
# Table: person
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100])
]
# Table: male
[
(name:TEXT, Primary Key, Examples: [student1, student101, student102])
]
# Table: no_payment_due
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(bool:TEXT, Examples: [neg, pos])
]
# Table: enrolled
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(school:TEXT, Primary Key, Examples: [occ, smc, ucb]),
(month:INTEGER, Examples: [1, 2, 3])
]
# Table: enlist
[
(name:TEXT, Examples: [student40, student51, student109]),
(organ:TEXT, Examples: [fire_department, air_force, navy])
]
# Table: bool
[
(name:TEXT, Primary Key, Examples: [neg, pos])
]
# Table: filed_for_bankrupcy
[
(name:TEXT, Primary Key, Examples: [student122, student126, student136])
]
【Foreign keys】
unemployed.name=person.name
longest_absense_from_school.name=person.name
disabled.name=person.name
male.name=person.name
no_payment_due.name=person.name
no_payment_due.bool=bool.name
enrolled.name=person.name
enlist.name=person.name
filed_for_bankrupcy.name=person.name

    【Question】
    Calculate the average enlisted students per organization. average = DIVIDE(FLOOR(COUNT(NAME), COUNT(DISTINCT organ)));

    【Evidence】
    average = DIVIDE(FLOOR(COUNT(NAME), COUNT(DISTINCT organ)));

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT CAST(COUNT(NAME) AS REAL) * 100 / COUNT(DISTINCT organ) FROM enlist
You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 student_loan
【Schema】
# Table: unemployed
[
(name:TEXT, Primary Key, Examples: [student1000, student102, student106])
]
# Table: longest_absense_from_school
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(month:INTEGER, Examples: [0, 1, 2])
]
# Table: disabled
[
(name:TEXT, Primary Key, Examples: [student114, student125, student142])
]
# Table: person
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100])
]
# Table: male
[
(name:TEXT, Primary Key, Examples: [student1, student101, student102])
]
# Table: no_payment_due
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(bool:TEXT, Examples: [neg, pos])
]
# Table: enrolled
[
(name:TEXT, Primary Key, Examples: [student1, student10, student100]),
(school:TEXT, Primary Key, Examples: [occ, smc, ucb]),
(month:INTEGER, Examples: [1, 2, 3])
]
# Table: enlist
[
(name:TEXT, Examples: [student40, student51, student109]),
(organ:TEXT, Examples: [fire_department, air_force, navy])
]
# Table: bool
[
(name:TEXT, Primary Key, Examples: [neg, pos])
]
# Table: filed_for_bankrupcy
[
(name:TEXT, Primary Key, Examples: [student122, student126, student136])
]
【Foreign keys】
unemployed.name=person.name
longest_absense_from_school.name=person.name
disabled.name=person.name
male.name=person.name
no_payment_due.name=person.name
no_payment_due.bool=bool.name
enrolled.name=person.name
enlist.name=person.name
filed_for_bankrupcy.name=person.name

    【Question】
    List down the enrolled schools and duration of student214. enrolled schools refers to school; duration refers to month; student214 is a name of student;

    【Evidence】
    enrolled schools refers to school; duration refers to month; student214 is a name of student;

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT school, month FROM enrolled WHERE name = 'student214'