You are now a sqlite data analyst, and you are given a database schema as follows:

    【Schema】
    【DB_ID】 financial
【Schema】
# Table: client
[
(client_id:INTEGER, Primary Key, Examples: [1, 2, 3]),
(gender:TEXT, Examples: [F, M]),
(birth_date:DATE, Examples: [1970-12-13]),
(district_id:INTEGER, Examples: [18, 1, 5])
]
# Table: card
[
(card_id:INTEGER, Primary Key, Examples: [1, 2, 3]),
(disp_id:INTEGER, Examples: [9, 19, 41]),
(type:TEXT, Examples: [gold, classic, junior]),
(issued:DATE, Examples: [1998-10-16])
]
# Table: disp
[
(disp_id:INTEGER, Primary Key, Examples: [1, 2, 3]),
(client_id:INTEGER, Examples: [1, 2, 3]),
(account_id:INTEGER, Examples: [1, 2, 3]),
(type:TEXT, Examples: [OWNER, DISPONENT])
]
# Table: account
[
(account_id:INTEGER, Primary Key, Examples: [1, 2, 3]),
(district_id:INTEGER, Examples: [18, 1, 5]),
(frequency:TEXT, Examples: [POPLATEK MESICNE, POPLATEK TYDNE, POPLATEK PO OBRATU]),
(date:DATE, Examples: [1995-03-24])
]
# Table: district
[
(district_id:INTEGER, Primary Key, Examples: [1, 2, 3]),
(A2:TEXT, Examples: [Hl.m. Praha, Benesov, Beroun]),
(A3:TEXT, Examples: [Prague, central Bohemia, south Bohemia]),
(A4:TEXT, Examples: [1204953, 88884, 75232]),
(A5:TEXT, Examples: [0, 80, 55]),
(A6:TEXT, Examples: [0, 26, 29]),
(A7:TEXT, Examples: [0, 6, 4]),
(A8:INTEGER, Examples: [1, 2, 3]),
(A9:INTEGER, Examples: [1, 5, 6]),
(A10:REAL, Examples: [100.0, 46.7, 41.7]),
(A11:INTEGER, Examples: [12541, 8507, 8980]),
(A12:REAL, Examples: [0.2, 1.6, 1.9]),
(A13:REAL, Examples: [0.43, 1.85, 2.21]),
(A14:INTEGER, Examples: [167, 132, 111]),
(A15:INTEGER, Examples: [85677, 2159, 2824]),
(A16:INTEGER, Examples: [99107, 2674, 2813])
]
# Table: order
[
(order_id:INTEGER, Primary Key, Examples: [29401, 29402, 29403]),
(account_id:INTEGER, Examples: [1, 2, 3]),
(bank_to:TEXT, Examples: [YZ, ST, QR]),
(account_to:INTEGER, Examples: [87144583, 89597016, 13943797]),
(amount:REAL, Examples: [2452.0, 3372.7, 7266.0]),
(k_symbol:TEXT, Examples: [SIPO, UVER, POJISTNE])
]
# Table: loan
[
(loan_id:INTEGER, Primary Key, Examples: [4959, 4961, 4962]),
(account_id:INTEGER, Examples: [2, 19, 25]),
(date:DATE, Examples: [1994-01-05]),
(amount:INTEGER, Examples: [80952, 30276, 318480]),
(duration:INTEGER, Examples: [24, 12, 60]),
(payments:REAL, Examples: [3373.0, 2523.0, 5308.0]),
(status:TEXT, Examples: [A, B, D])
]
# Table: trans
[
(trans_id:INTEGER, Primary Key, Examples: [1, 5, 6]),
(account_id:INTEGER, Examples: [1, 2, 3]),
(date:DATE, Examples: [1995-03-24]),
(type:TEXT, Examples: [PRIJEM, VYDAJ, VYBER]),
(operation:TEXT, Examples: [VKLAD, PREVOD Z UCTU, PREVOD NA UCET]),
(amount:INTEGER, Examples: [1000, 3679, 2452]),
(balance:INTEGER, Examples: [1000, 4679, 20977]),
(k_symbol:TEXT, Examples: [SIPO, SLUZBY, UVER]),
(bank:TEXT, Examples: [AB, YZ, ST]),
(account:INTEGER, Examples: [41403269, 87144583, 66487163])
]
【Foreign keys】
client.district_id=district.district_id
card.disp_id=disp.disp_id
disp.account_id=account.account_id
disp.client_id=client.client_id
account.district_id=district.district_id
order.account_id=account.account_id
loan.account_id=account.account_id
trans.account_id=account.account_id

    【Question】
    How many high-level credit cards have "OWNER" type of disposition? High-level credit cards refers to the cards with the gold type.

    【Evidence】
    High-level credit cards refers to the cards with the gold type.

    Please read and understand the database schema carefully, and generate an executable SQL based on the user's question and evidence. 

SQL: SELECT COUNT(T1.card_id) FROM card AS T1 INNER JOIN disp AS T2 ON T1.disp_id = T2.disp_id WHERE T1.type = 'gold' AND T2.type = 'OWNER'