PrincetonPLI/LongProc huggingface dataset:
[TASK]:
You will be given lines of pseudocode, your task is to write the corresponding C++ code. The pseudocode will provide detailed description of the c++ code line by line. The pseudocode is garanteed to be correct and complete.

[INSTRUCTION]:
The following libraries are already included in the code.
```cpp
#include <cstdio>
#include <iostream>
#include <vector>
#include <algorithm>
#include <numeric>
#include <cmath>
#include <cstring>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <list>
#include <fstream>
#include <climits>
#include <cassert>
#include <iomanip>
#include <sstream>
#include <bitset>
using namespace std;
```
Do not include them in your code again. Please surround your code with ```cpp and ``` markers. Note that the code should correspond to the pseudocode line by line.

[PSEUDOCODE]:
define the main function
    create string s
    read s
    create set<string> ss
    sort s
    do
        create string m = s
        create vector<string> v
        for i = 0 to 3 exclusive do push s.substr(2 * i, 2) onto v
        for i = 0 to 4 exclusive
            for i = 0 to 4 exclusive
                for i = 0 to 4 exclusive
                    create string str = v[0] + v[1] + v[2]
                    set m to min of m and str
                    swap v[1] and v[2]
                    swap v[2][0] and v[2][1]
                end of the block
                swap v[0] and v[1]
                swap v[0][0] and v[0][1]
            end of the block
            swap v[0] and v[2]
            swap v[2][0] and v[2][1]
        end of the block
        insert m into ss
    while next_permutation(s.begin(), s.end())
    print ss size
end of the block

[CODE]:

int main() {
    string s;
    cin >> s;
    set<string> ss;
    sort(s.begin(), s.end());
    do {
        string m = s;
        vector<string> v;
        for (int i = 0; i < 3; i++) { v.push_back(s.substr(2 * i, 2)); }
        for (int i = 0; i < 4; i++) {
            for (int i = 0; i < 4; i++) {
                for (int i = 0; i < 4; i++) {
                    string str = v[0] + v[1] + v[2];
                    m = min(m, str);
                    swap(v[1], v[2]);
                    swap(v[2][0], v[2][1]);
                }
                swap(v[0], v[1]);
                swap(v[0][0], v[0][1]);
            }
            swap(v[0], v[2]);
            swap(v[2][0], v[2][1]);
        }
        ss.insert(m);
    } while (next_permutation(s.begin(), s.end()));
    cout << ss.size() << "\n";
}
[TASK]:
You will be given lines of pseudocode, your task is to write the corresponding C++ code. The pseudocode will provide detailed description of the c++ code line by line. The pseudocode is garanteed to be correct and complete.

[INSTRUCTION]:
The following libraries are already included in the code.
```cpp
#include <cstdio>
#include <iostream>
#include <vector>
#include <algorithm>
#include <numeric>
#include <cmath>
#include <cstring>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <list>
#include <fstream>
#include <climits>
#include <cassert>
#include <iomanip>
#include <sstream>
#include <bitset>
using namespace std;
```
Do not include them in your code again. Please surround your code with ```cpp and ``` markers. Note that the code should correspond to the pseudocode line by line.

[PSEUDOCODE]:
create constant int N = 2e5 + 5
create string s
create queue<string> q
create map mp of string to int
in function bfs taking string s
    mp[s] = true
    push s onto q
    while q is not empty
        create string u = front of q, v1, v2, v3
        pop q
        v1 = v2 = v3 = u
        v1[0] = u[3], v1[1] = u[0], v1[2] = u[1], v1[3] = u[2]
        v2[0] = u[4], v2[5] = u[0], v2[2] = u[5], v2[4] = u[2]
        v3[5] = u[1], v3[3] = u[5], v3[4] = u[3], v3[1] = u[4]
        if not mp[v1] then mp[v1] = true, push v1 onto q
        if not mp[v2] then mp[v2] = true, push v2 onto q
        if not mp[v3] then mp[v3] = true, push v3 onto q
    end of the block
end of the block
define the main function
    read s
    create int res = 0
    sort s
    do
        if mp[s] then continue
        add 1 to res
        call bfs on s
    while next_permutation(s.begin(), s.end())
    print res
    return to indicate successful execution
end of the block

[CODE]:

const int N = 2e5 + 5;
string s;
queue<string> q;
map<string, int> mp;
void bfs(string s) {
    mp[s] = true;
    q.push(s);
    while (!q.empty()) {
        string u = q.front(), v1, v2, v3;
        q.pop();
        v1 = v2 = v3 = u;
        v1[0] = u[3], v1[1] = u[0], v1[2] = u[1], v1[3] = u[2];
        v2[0] = u[4], v2[5] = u[0], v2[2] = u[5], v2[4] = u[2];
        v3[5] = u[1], v3[3] = u[5], v3[4] = u[3], v3[1] = u[4];
        if (!mp[v1]) mp[v1] = true, q.push(v1);
        if (!mp[v2]) mp[v2] = true, q.push(v2);
        if (!mp[v3]) mp[v3] = true, q.push(v3);
    }
}
int main() {
    cin >> s;
    int res = 0;
    sort(s.begin(), s.end());
    do {
        if (mp[s]) continue;
        res++;
        bfs(s);
    } while (next_permutation(s.begin(), s.end()));
    cout << res << '\n';
    return 0;
}
[TASK]:
You will be given lines of pseudocode, your task is to write the corresponding C++ code. The pseudocode will provide detailed description of the c++ code line by line. The pseudocode is garanteed to be correct and complete.

[INSTRUCTION]:
The following libraries are already included in the code.
```cpp
#include <cstdio>
#include <iostream>
#include <vector>
#include <algorithm>
#include <numeric>
#include <cmath>
#include <cstring>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <list>
#include <fstream>
#include <climits>
#include <cassert>
#include <iomanip>
#include <sstream>
#include <bitset>
using namespace std;
```
Do not include them in your code again. Please surround your code with ```cpp and ``` markers. Note that the code should correspond to the pseudocode line by line.

[PSEUDOCODE]:
new char array called colors filled with 'R', 'O', 'Y', 'G', 'B', 'V'
declare vector of integers called v
declare new array of integers tedad with size 300
define the main function
    declare string variable with name s
    read s from the user input
    for integer i = 0 to length of s exclusive, increment tedad[s[i]]
    create new vector of integers v
    for i from 0 to 6 exclusive
        if tedad[color[i]] != 0, add tedad[color[i]] after the last element of v
    sort v
    if length of v = 1
        print 1
    else if length of v = 2
        if v[0] is equal to 1
            print 1
        else
            print 2 to the standard output
    else if length of v is equal to 3
        if v[0] = 1
            if v[1] is equal to 1
                print 2
            else
                print 3
        else
            print 6 to the stdout
    else if length of v is equal to 4
        if v[3] = 3
            print 5 to the standard output
        else if v[3] = 2
            print 8 to the output
    else if length of v = 5
        print 15
    else if length of v is equal to 6
        print 30
    return to indicate successful execution
end of the block

[CODE]:

char color[6] = {'R', 'O', 'Y', 'G', 'B', 'V'};
vector<int> v;
int tedad[300];
int main() {
    string s;
    cin >> s;
    for (int i = 0; i < s.length(); i++) tedad[s[i]]++;
    vector<int> v;
    for (int i = 0; i < 6; i++)
        if (tedad[color[i]]) v.push_back(tedad[color[i]]);
    sort(v.begin(), v.end());
    if (v.size() == 1)
        cout << 1 << endl;
    else if (v.size() == 2) {
        if (v[0] == 1)
            cout << 1 << endl;
        else
            cout << 2 << endl;
    } else if (v.size() == 3) {
        if (v[0] == 1) {
            if (v[1] == 1)
                cout << 2 << endl;
            else
                cout << 3 << endl;
        } else
            cout << 6 << endl;
    } else if (v.size() == 4) {
        if (v[3] == 3)
            cout << 5 << endl;
        else if (v[3] == 2)
            cout << 8 << endl;
    } else if (v.size() == 5)
        cout << 15 << endl;
    else if (v.size() == 6)
        cout << 30 << endl;
    return 0;
}