Xbox Controller for PC: Use with PC games & tv. Tips for gamers and gamers newbie

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Downloading files with JSZip is nice, but sometimes you need to extract a file and have a folder with the name you select. you can achieve this using thezip.dirname(this.archive, this.folder) method. The archive parameter contains the path to the archive you want to extract, and the folder parameter receives thepath to the directory where the file will be extracted. If no folder is specified, the current working directory is used. Call this method with a folder name as thesecond parameter. In the following example, you can see how to extract a file from a.zip archive into a folder with a default name. .zipArchive.file(pathToFile,this.zip.dirname('/Home/User/Desktop')); This is the.zip archive with sample files and folders. When you run this method, the folder created will be/Home/User/Desktop. You can also supply an array of folders to the folder method. This is the following example. .zipArchive.file(pathToFile,['/Home/User/Desktop', '/Home/User/Documents']); The folder name is the same as the array key. The folders within the array will be converted to the archive as
new folders. Back to the.zip example. The below example shows how to extract a file from an archive with a custom folder. .zipArchive.file(pathToFile,'dirname.zip', this.zip.dirname('dirname.zip')); This is the.zip archive with sample files and folders. When you run this method, the folder created will bedirname.zip. If no folders are added in the array, all files in the archive will be extracted to the current working directory. Back to the.zip example. This is the.zip
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