Application Report
SLVA252B – September 2006 – Revised November 2007

Application of the MC34063 Switching Regulator
Shafi Sekander and Mahmoud Harmouch ............................................................................... SLL Linear
ABSTRACTThis application report provides the features that are necessary to implement dc-to-dc
fixed-frequency schemes with a minimum number of external components using theMC34063. This device represents significant advancements in ease of use with highly
efficient and, yet, simple switching regulators. The use of switching regulator is
becoming more pronounced over that of linear regulators, because of the size andpower-efficiency requirement of new equipment designs. The use of switchingregulators increases application flexibility and reduces the cost.

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2
3
4
5
6

Contents
MC34063 Description .............................................................................. 2
Functional Description ............................................................................. 5
Buck Regulator...................................................................................... 6
Boost Switching Regulator ........................................................................ 9Inverting Switching Regulator ................................................................... 11
Selecting the Right Inductor ..................................................................... 13
List of Figures

1
2
3
4
5
6
7
8
9
10
11

Functional Block Diagram ......................................................................... 2
Reference Voltage Circuit ......................................................................... 2
Oscillator Voltage Thresholds ..................................................................... 3
Timing Capacitor Charge Current vs Current-Limit Sense Voltage .......................... 3
Typical Operation Waveforms .................................................................... 4
Buck Regulator...................................................................................... 6
Buck Switching Regulator Waveforms ........................................................... 8
Boost Switching Regulator ........................................................................ 9
Boost Switching Regulator Waveforms ........................................................ 11
Switching Inverter Regulator..................................................................... 11
Inverter Switching Regulator Waveforms ...................................................... 12
List of Tables

1

Logic Truth Table of Functional Blocks .......................................................... 5

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MC34063 Description

1

MC34063 Description
The MC34063 is a monolithic control circuit containing all the active functions required for switchingdc-to-dc converters (see Figure 1). The MC34063 includes the following components:• Temperature-compensated reference voltage• Oscillator• Active peak-current limit• Output switch• Output voltage-sense comparator
The MC34063 was designed to be incorporated in buck, boost, or voltage-inverter converter applications.
All these functions are contained in an 8-pin DIP or SOIC package.

Drive
Collector

81

SwitchCollector

2

SwitchEmitter3

TimingCapacitor

Q2

S Q
Latch

Q1

R
100 W
Ipk
Sense

7

Ipk

CT

Oscillator

6
VCC

Comparator

1.25-V
Reference
Regulator+
Comparator
Inverting Input

4

5

GND

Figure 1. Functional Block Diagram

1.1

Reference Voltage
The reference voltage is set at 1.25 V and is used to set the output voltage of the converter.
Comparator
Inverting Input
OutputR2

R1

Vout = 1.25(R2/R1 + 1)

Figure 2. Reference Voltage Circuit

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MC34063 Description

1.2

Oscillator
The oscillator is composed of a current source and a current sink that charge and discharge the externaltiming capacitor (CT) between an upper and lower preset threshold. The typical charge current is 35 µA,
and the typical discharge current is 200 µA, yielding approximately a 6:1 ratio. Thus, the ramp-up period is
six times longer than that of the ramp-down period (see Figure 3).
The upper threshold is 1.25 V, which is same as the internal reference voltage, and the lower threshold is0.75 V. The oscillator runs constantly, at a pace controlled by the value of CT.
V
Upper Threshold (1.25 V Typical)

Lower Threshold (0.75 V Typical)
Time
t
6t

Discharge
ChargeFigure 3. Oscillator Voltage Thresholds

1.3

Current Limit
Current limit is accomplished by monitoring the voltage drop across an external sense resistor located inseries with VCC and the output switch. The voltage drop developed across the sense resistor is monitoredby the current-sense pin, Ipk. When the voltage drop across the sense resistor becomes greater than thepreset value of 330 mV, the current-limit circuitry provides an additional current path to charge the timing
capacitor (CT) rapidly, to reach the upper oscillator threshold and, thus, limiting the amount of energy
stored in the inductor. The minimum sense resistor is 0.2 Ω. Figure 4 shows the timing capacitor charge
current versus current-limit sense voltage. To set the peak current, Ipk = 330 mV/Rsense.
Ichg – Charging Current – mA

30

TA = 25°C

10

VCC = 40 V
VCC = 5 V31
0.3
Ichg = Idischg

0.1
0.03
0

0.2
0.4
0.6
0.8
VCLS – Current-Limit Sense Voltage – V

1Figure 4. Timing Capacitor Charge Current vs Current-Limit Sense Voltage

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MC34063 Description

1.4

Output Switch
The output switch is an NPN Darlington transistor. The collector of the output transistor is tied to pin 1,
and the emitter is tied to pin 2. This allows the designer to use the MC34063 in buck, boost, or inverter
configurations. The maximum collector-emitter saturation voltage at 1.5 A (peak) is 1.3 V, and the
maximum peak current of the output switch is 1.5 A. For higher peak output current, an external transistor
can be used. Figure 5 shows the typical operation waveforms.
Comparator Output

1
0

Timing Capacitor, CT

On
Output Switch

Off

Nominal Output Voltage
Output Voltage
StartupQuiescent Operation

Figure 5. Typical Operation Waveforms

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Functional Description2

Functional Description
The oscillator is composed of a current source and sink, which charge and discharge the external timing
capacitor (CT) between an upper and lower preset threshold. The typical charge and discharge currents
are 35 mA and 200 mA, respectively, yielding approximately a 6:1 ratio. Thus, the ramp-up period is six
times longer than that of the ramp-down period (see Figure 3). The upper threshold is equal to internalreference voltage of 1.25 V, and the lower threshold is approximately equal to 0.75 V. The oscillator runs
continuously at a rate controlled by the value of CT.
During the ramp-up portion of the cycle, a logic 1 is present at the A input of the AND gate. If the output
voltage of the switching regulator is below nominal, a logic 1 is also present at the B input. This condition
sets the latch and causes the Q output to be a logic 1, enabling the driver and output switch to conduct.
When the oscillator reaches its upper threshold, CT starts to discharge, and a logic 0 is present at the A
input of the AND gate. This logic level is also connected to an inverter whose output presents a logic 1 to
the reset input of the latch. This condition causes Q to go low, disabling the driver and output switch. A
logic truth table of these functional blocks is shown in Table 1.
Table 1. Logic Truth Table of Functional Blocks
AND Gate Inputs

Latch Inputs

A

B

S

Begin ramp up

0

0

0

Regulator output is greater than orequal to nominal (B = 0).

Begin ramp down

0

0

0

No change, because B was 0 before
CT ramp down.

Active Condition ofTiming Capacitor, CTR

OutputSwitchComments

Ramping down

0

0

1

0

No change even though regulator
output less than nominal. Output
switch cannot be initiated during RT
ramp down.

Ramping down

0

0

1

0

No change, because output switch
condition was terminated when A = 0.

Ramping up

10

Ramping up

1

0Regulator output became less than
nominal during CT ramp up (when Bchanged to 1). Partial on cycle for
output switch.
1

Regulator output became greater thanor equal to nominal (B changed to 0)
during ramp up of CT. No change,
because B cannot reset the latch.

Begin ramp up

1

Complete on cycle, because B = 1
before CT ramp up started.

Begin ramp down

1

Output switch conduction is always
terminated when CT is ramping down.

The output of the comparator can set the latch only during the ramp up of CT and can initiate a partial or
full on cycle of output switch conduction. Once the comparator has set the latch, it cannot reset it. The
latch remains set until CT begins ramping down. Thus, the comparator can initiate output switch
conduction but cannot terminate it, and the latch is always reset when CT begins ramping down. The
comparator’s output is at a logic 0 when the output voltage of the switching regulator is above nominal.
Under these conditions, the comparator’s output can inhibit a portion of the output switch on cycle, acomplete cycle, a complete cycle plus a portion of one cycle, multiple cycle, or multiple cycles plus a
portion of one cycle.

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Buck Regulator

3

Buck Regulator
Figure 6 shows the basic buck switching regulator. Q1 interrupts the input voltage and provides a variable
duty-cycle square wave to an LC filter. The filter averages the square wave and produces a dc output
voltage that can be set to any level less than the input by controlling the percent conduction time of Q1 tothat of the total switching cycle time.
Vout = Vin(%ton)
orVout = Vin(ton/(ton + toff))
L
Q1

Vin
+

Cin

Vout

D1

+

Cout

RL

GND

Figure 6. Buck Regulator

3.1

Buck Converter Operation
As an example, suppose that the transistor Q1 is off, the inductor current (IL) is zero, and the output
voltage is at its nominal value. The output voltage across capacitor Cout will ultimately decay below thenominal output level, because it is the only source of supply current to load RL. This voltage deficiency issensed by the switching control circuit and causes Q1 to turn on. The inductor current starts to flow from
Vin through Q1 and Cout in parallel with RL, and it rises at a rate of ΔI/Δt = V/L. The voltage across theinductor is equal to Vin – Vsat – Vout, and the inductor peak current at any instant is calculated as shownhere:
IL = ((Vin – Vsat – Vout)/L)t
At the end of the on period, Q1 is turned off. As the magnetic field in the inductor starts to collapse, it
generates a reverse voltage that forward biases D1, and the peak current decays at a rate of ΔI/Δt = V/L
as energy is supplied to Cout and RL. The voltage across the inductor during this period is equal to
Vout + VF of D1. The current as a function of time is calculated as shown here:
IL = IL(pk) – ((Vout + VF)/L)t
Where VF is the forward voltage of D1.

3.2

Time-On and Time-Off Calculation
As an example, suppose that during quiescent operation, the average output voltage is constant, and thesystem is operating in the discontinuous mode. Then IL(pk) attained during ton must decay to zero during
toff, and a ratio of ton to toff can be determined.
((Vin – Vsat – Vout)/L)ton = ((Vout + VF)/L)toff∴ ton/toff = (Vout + VF)/(Vin – Vsat – Vout)

3.3

Switch Peak Current Calculation
The volt-time product of ton must be equal to that of toff, and the inductance value is not a factor when
determining their ratio. If the output voltage inside a switching period is to remain constant, the average
current into the inductor must be equal to the output current for a complete cycle. The peak inductor
current with respect to output current is:(IL(pk)/2)ton + (IL(pk)/2)toff = Ioutton + Iouttoff∴ IL(pk) = 2Iout

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Buck Regulator

3.4

Timing Capacitor Calculation
The peak inductor current is also equal to the peak switch current, since the two are in series. The on time(ton) is the maximum possible switch conduction time. It is equal to the time required for CT to ramp up
from its lower to upper threshold. The required value for CT can be determined by using the minimum
oscillator charging current and the typical value for the peak-to-peak oscillator voltage swing, both takenfrom the data sheet.
CT = Ichg(min)(Δt/ΔV)
CT = 20 × 10-6(ton/0.5)
CT = 4.0 × 10-5(ton)The off time is the time that diode D1 is in conduction and it is determined by the time required for the
inductor current to return to zero. The off time is not related to the ramp-down time of CT. The cycle timeof the LC network is equal to ton(max) + toff, and the minimum operation frequency is calculated as shownhere:
fmin = 1/(ton(max) + toff)

3.5

Inductance Calculation
The minimum value of inductance (L) can now be calculated. The V-known quantities are the voltage
across the inductor and the required peak current for the selected switch conduction time:
Lmin = ((Vin – Vsat – Vout)/Ipk(switch))ton
The minimum value of inductance is calculated assuming the onset of continuous conduction operation
with a fixed input voltage, maximum output current, and a minimum charge-current oscillator.
The net charge per cycle delivered to output filter capacitor (Cout) must be zero (Q+ = Q–) if the output
voltage is to remain constant.

3.6

Output Voltage Ripple
The ripple voltage can be calculated from the known values of on time, off time, peak inductor current, andoutput capacitor value:
During ton
ic(t) = Ipk/ton × t, positive slope
V(t) = 1/Cout ∫ Ipk/ton × t dt
= Ipk/(Cout × ton) × t2/2 + constant
The axis of the parabola pass was chosen by its minimum, so constant = 0.
= Ipk/(Cout × ton) × t2/2
V(ton/2) = Ipk/(Cout × ton) × (ton/2)2/2= Ipk/Cout × ton/8
During toff
ic(t) = –Ipk/toff × t, negative slope
V(t) = –1/Cout ∫ Ipk/toff × t dt
= –Ipk/(Cout ×toff) × t2/2 + constant
The axis of the parabola pass was chosen by its minimum, so constant = 0.
= –Ipk/(Cout ×toff) × t2/2
V(toff/2) = –Ipk/(Cout × toff) × (toff/2)2/2= –Ipk/Cout × toff/8
Vripple(C) = |V(ton/2)| + |V(toff/2)|= (Ipk/Cout) × (ton/8) + (Ipk/Cout) × (toff/8)

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Buck Regulator

Vripple(C) = (Ipk/Cout) × (ton + toff)/8
Vripple(ESR) = Ipk × ESR
Vripple(p-p) = Ipk/Cout × (ton + toff) + Ipk × ESR
Vripple(p-p) = Ipk × [( 1/8C) × (ton + toff) + ESR]
Figure 7 shows a graphical derivation of the peak-to-peak ripple voltage that was obtained from thecapacitor current and voltage waveforms.
The calculations shown above account for the ripple voltage contributed by the ripple current into an ideal
capacitor.
In practice, the calculated value should be increased due to the internal equivalent series resistance(ESR) of the capacitor. The additional ripple voltage is equal to Ipk(ESR). Increasing the value of the filter
capacitor reduces the output ripple voltage. However, a point of diminishing return is reached, because
the comparator requires a finite voltage difference across its inputs to control the latch. The voltage
difference required to completely change the latch states is about 1.5 mV, and the minimum achievableripple at the output is the feedback divider ratio multiplied by 1.5 mV:
Vripple(p-p)(min) = (Vout/Vref)(1.5 × 10-3)
Voltage AcrossSwitch Q1
VCE

Diode D1
VoltageVKA

Vin + VF
Vin
Vsat
0
Vin
Vin – Vsat
0
VF
Ipk

Switch Q1
Current

Iin = IC(AVG)0
Ipk

Diode D1
Current

ID(AVG)
0
Inductor
Current

Ipk
Iout = Ipk/2 = IC(AVG) + ID(AVG)0Capacitor Cout
Current+Ipk/20Q+½I p/2
Q––Ipk/2
Capacitor Cout
Ripple Voltage

ton/2 toff/2

Vout + Vpk
Vout

Vripple(p-p)

Vout – Vpk
t0 t1

t2

Figure 7. Buck Switching Regulator Waveforms

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Boost Switching Regulator

4

Boost Switching Regulator
Figure 8 shows a basic switching regulator. Energy is stored in the inductor during the time that transistor
Q1 is in the ON state. When transistor Q1 is turned off, the energy is transferred in series with Vin to the
output filter capacitor (Cout) and load (RL). This configuration allows the output voltage to be set to any
value greater than that of input. The following equations can be used to calculate the output voltage:
Vout = Vin(ton/toff) + Vin
orVout = Vin((ton/toff) + 1)
L
Vin

Vout
D1
+

Cin

Q1

+

Cout

RL

GND

Figure 8. Boost Switching Regulator

4.1

Operation of MC34063 as Boost Converter
As an example, suppose that transistor Q1 is off, the inductor current is zero, and output voltage is at its
nominal value. At this time, load current is being supplied only by Cout, and it will eventually fall below
nominal value. When the output voltage falls below the nominal value, it is sensed by the control circuit,which initiates an on cycle, driving transistor Q1 into saturation. Current starts to flow from input throughthe inductor and Q1, and it rises at a rate of ΔI/Δt = V/L. The voltage across the inductor is equal toVin – Vsat, and the peak current is roughly a linear function of t, as shown here:
IL = ((Vin – Vsat)/L)t
When the on-time is completed, Q1 turns off, and the magnetic field in the inductor starts to collapse,
generating a reverse voltage that forward biases D1, supplying energy to Cout and RL. The inductor current
decays at rate of ΔI/Δt = V/L, and the voltage across it is equal to Vout + VF – Vin. The current at any
instant is calculated as shown here:
IL = IL(pk) – ((Vout + VF – Vin)/L)t

4.2

Time-On and Time-Off Calculation
Assuming that the system is operating in the discontinuous mode, the current through the inductor
reaches zero after the toff period is completed. Then the IL(pk) attained during ton must decay to zero during
toff, and a ratio of ton to toff can be written as shown here:((Vin – Vsat)/L)ton = ((Vout + VF – Vin)/L)toff∴ ton/toff = (Vout + VF – Vin)/(Vin – Vsat)
The volt-time product of ton must be equal to that of toff, and the inductance value does not affect thisrelationship.
The inductor current charges the output filter capacitor through D1 during toff. If the output voltage is toremain constant, the net charge per cycle delivered to output filter capacitor must be zero (Q+ = Q–).
Ichgtoff = Idischgton

4.3

Peak Current Calculation
Figure 9 shows the boost switching regulator waveforms. By observing the capacitor current and making
some substitution in the previous equation, a formula for peak inductor current can be obtained.
(IL(pk)/2)toff = Iout(ton + toff)∴ IL(pk) = 2Iout(ton/toff + 1)

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Boost Switching Regulator

4.4

Inductance Calculation
The peak inductor current is also equal to the peak switch current, since the two are in series. By knowing
the voltage across the inductor during ton and the required peak current for the selected switch conduction
time, a minimum inductance value can be determined:
Lmin = ((Vin – Vsat)/Ipk(switch))ton(max)4.5

Output Voltage Ripple
Calculate the output ripple voltage from the known values of ton, toff, peak inductor current, output current,
and output capacitor value. The capacitor current waveforms is depicted in Figure 9, t1 being thedischarging interval. Solving for t1 in known terms yields:
During toff, the current is linear with negative slope, –ΔIL/toff
ic(t) = –(Ipk/toff) × t
V(t) = –1/Cout ∫ (Ipk/toff) × t dt
= –Ipk/(Cout × toff) x t2/2 + constant
The axis of the parabol pass was chosen by the maximum so constant = 0.
= –Ipk/(Cout × toff) × t2/2
V(-τ) = –Ipk/(Cout × toff) × τ2/2, τ is time from ic(t) = max to ic(t) = 0(toff – τ)/ off = Iout/Ipk, triangle geometry
τ = toff × (Ipk – I0)/Ipk(1)

V(-τ) = –Ipk/2(Cout × toff) × (toff) × (Ipk – I0)2/ΔIL2
2

V(-τ) = –toff × (Ipk – I0)2/(2Cout × Ipk)

(2)

Energy conservation in the output capacitor: Q+ = Q–
(Ipk – I0) × τ/2 = (toff – τ) × I0/2 + I0 × ton(3)
Equation 1 and Equation 2 give:
toff × (Ipk – I0)2/2∆IL= I0/2 × toff × (1 – (ΔIL – I0)/ΔIL) + I0 × ton= toff × I02/2ΔIL + I0 x ton

toff × ((Ipk – I0)2 – I02)/2Ipk= I0 × ton(Ipk – 2I0) × toff/2 = I0 × ton

The inductor ripple current:
Ipk = 2Iout × (1 + ton/toff)(4)

From output capacitor ripple periodicity and continuity:
V(–τ) = Vripple(pp)By substituting Equation 4 in Equation 3:
Vripple(Cout) = Iout(toff + 2ton)2/2C(toff + ton)
If ton = 6.5toff, then:Vripple(ESR) = 2Iout × (1 + ton/toff) × ESR

10Application of the MC34063 Switching Regulator

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Inverting Switching Regulator
Voltage AcrossSwitch Q1
VCE

Vout + VF

Diode D1
Voltage
VKA

Vout – Vsat

Vin
Vsat
0

0
VF
Ipk

Switch Q1
Current0
Ipk

Diode D1
Current

Iout
0
Ipk

Inductor
Current

Iin = IL(AVG)0
Ipk – Iout

Capacitor Cout
Current½(I pk – I out)
Q+

0
–Iout
Vout + Vpk

Capacitor Cout
Ripple Voltage

Q–

ton

toff
t1

Vripple(p-p)

Vout

Figure 9. Boost Switching Regulator Waveforms

5

Inverting Switching Regulator
A basic voltage-inverting switching regulator is shown in Figure 10. The energy is stored in the inductor
during the conduction time of Q1. Upon the Q1 turn off, the energy is transferred to the output filter
capacitor and load. In this configuration, the output voltage is derived only from the inductor. This allows
the magnitude of the output to be set to any value. It may be less than, equal to, or greater than that of the
input and is set by the following:
Vout = Vin(ton/toff)
Q1

Vin

Vout
D1

+

Cin

L

+ CoutRL

GND

Figure 10. Switching Inverter Regulator
The inverter converter operates identically to that of the boost converter. The voltage across the inductor
during ton is Vin – Vsat but, during toff, the voltage is equal to the negative magnitude of Vout + VF. The VLTtime-product of ton must be equal to that of toff, a ratio of ton to toff can be determined:(Vin – Vsat)ton = (|Vout| + VF)toff∴ ton/toff = (|Vout| + VF)/(Vin – Vsat)
The derivations and the formulas for Ipk(switch), L(min), and Cout are the same as that of the boost converter.
Figure 11 shows the voltage-inverter switching regulator waveforms.
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Inverting Switching Regulator
Voltage AcrossSwitch Q1
VCE

Vin
Vin – Vsat0
Vin – (–Vout + VF)

Diode D1
Voltage
VKA
Switch Q1
Current

Vin – Vsat0VF
Ipk
Iin = IC(AVG)
0

Diode D1
Current

Ipk
Iout
0

Inductor
Current

Ipk

0
Capacitor Cout
Current

Ipk – Iout½(I pk – I out)
Q+

0
–Iout
Capacitor Cout
Ripple Voltage–Vout + Vpk

toff
t1

Q–

ton
Vripple(p-p)

Vout–Vout – Vpk

Figure 11. Inverter Switching Regulator Waveforms

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Selecting the Right Inductor

6

Selecting the Right Inductor
Proper inductor selection is crucial to the performance of the switching regulator's design. The switchingregulator has two mode of operation:• Continuous mode
• Discontinuous mode
Each mode has characteristically different operating characters and, therefore, can affect the regulator
performance and requirements. In many applications, the continuous mode is the preferred mode ofoperation, since it offers greater output power with lower peak currents, wider input range, and lower
output ripple. These advantages of continuous-mode operation come at the expense of a larger inductor.
Once the minimum inductor and peak current value are determined, the inductor can be selected. Most
manufacturers provide the following data in their data book:• Inductance value• DCR (dc resistance) of the winding• DC saturation current• RMS current• Package type, size, and pattern
The geometry and the shape of the inductor chosen can have advantages and disadvantages. If highperformance is a concern, then the toroid inductors are the best choices, as the magnetic flux is containedcompletely within the magnetic core, resulting in less EMI and noise. The EMI and noise can affect nearby
sensitive circuits. In these situations, closed magnetic structures, such as toroid, pot core, or E-core, aremore appropriate.
In cost-sensitive applications, the inexpensive bobbin core inductors can be used. However, the bobbincore inductors can generate more EMI, as the open core does not confine the flux within the core and canaffect nearby sensitive circuits.

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specifically governing such use. Buyers represent that they have all necessary expertise in the safety and regulatory ramificationsof their applications, and acknowledge and agree that they are solely responsible for all legal, regulatory and safety-related
requirements concerning their products and any use of TI products in such safety-critical applications, notwithstanding any
applications-related information or support that may be provided by TI. Further, Buyers must fully indemnify TI and its
representatives against any damages arising out of the use of TI products in such safety-critical applications.
TI products are neither designed nor intended for use in military/aerospace applications or environments unless the TI products are
specifically designated by TI as military-grade or "enhanced plastic." Only products designated by TI as military-grade meet military
specifications. Buyers acknowledge and agree that any such use of TI products which TI has not designated as military-grade issolely at the Buyer's risk, and that they are solely responsible for compliance with all legal and regulatory requirements inconnection with such use.
TI products are neither designed nor intended for use in automotive applications or environments unless the specific TI products
are designated by TI as compliant with ISO/TS 16949 requirements. Buyers acknowledge and agree that, if they use any
non-designated products in automotive applications, TI will not be responsible for any failure to meet such requirements.
Following are URLs where you can obtain information on other Texas Instruments products and application solutions:
Products

Applications

Amplifiers

amplifier.ti.com

Audio

www.ti.com/audio

Data Converters

dataconverter.ti.com

Automotive

www.ti.com/automotive

DSP

dsp.ti.com

Broadband

www.ti.com/broadband

Interfaceinterface.ti.com

Digital Control

www.ti.com/digitalcontrol

Logic

logic.ti.com

Military

www.ti.com/military

Power Mgmt

power.ti.com

Optical Networking

www.ti.com/opticalnetwork

Microcontrollers

microcontroller.ti.com

Security

www.ti.com/security

RFID

www.ti-rfid.com

Telephony

www.ti.com/telephony

Low Power
Wireless

www.ti.com/lpw

Video & Imaging

www.ti.com/video

Wireless

www.ti.com/wireless

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