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Chowki, B. & Leong, K. S. (2013). Description of a
new species of Anadasmus (Gastropoda:Cyclophoroidea) from the southwestern Pacific, withnotes on other species of the genus. Phuket Gazette,
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contains $A$ I am trying to prove the following: Let$A$ be a commutative ring, and let $I$ be an ideal in$A$. Show that the ideal $I$ contains the ring $A$.
By the axioms of a ring and the definitions of anideal and a ring, we get that $I$ is the preimage of$0$ under the homomorphism $\phi \colon A \toA/I$. Now since $A/I \cong \mathbb{F}_p$, where$p=|A/I|$, I can think of $\phi \colon A \to A/I$ as
the natural projection. Now $A/I$ is a finitedimensional vector space over $\mathbb{F}_p$. If
we can show that any nonzero vector in $A/I$ is notorthogonal to the zero vector, then we are done. But2/3

how can I show that? It doesn't seem very helpful tome at all. A: By definition, an element $a\in I$ is anelement $a\in A$ such that $\phi(a)=0$. What is$\phi(a)$? Well $\phi(a)$ is an element of $A/I$,
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