࠙໬Ꮫ㸦ゎ⟅㸧ࠚ1ࢡ࣒ࣟ㓟 H2 CrO4 ࡢ 1 ẁ㝵┠ࡣ᏶඲࡟㟁㞳ࡋ㸪2 ẁ㝵┠ࡢ㟁㞳ᐃᩘࡀ Ka ࡞ࡢ࡛㸪◲㓟 H2 SO4 ࡜ྠᵝࡢィ⟬ࢆ⾜࠼ࡤࡼ࠸ࠋ
[H+ ][CrO4 2 ]= 106.5 mol/L
Ka =(1)[HCrO4  ]
㸦⟅㸧 1

3

[HCrO4  ][H+ ]=࡛࠶ࡿ࠿ࡽ㸪(2) ᘧࢆኚᙧࡋ࡚࠸ࡁ௦ධࡍࡿࠋ2
Ka[CrO4 ]
[CrO4 2 ]=2[CrO4 ] + [HCrO4  ]
11
Ka
=
=
=
[H+ ]
Ka + [H+ ][HCrO4  ]1+1+Ka[CrO4 2 ](1) ᘧࡼࡾ㸦⟅㸧 2(2)(3)

5୚࠼ࡽࢀࡓ⁐ゎᗘ✚ࡢ್ࡣ㸪ᑠࡉ࠸᪉࠿ࡽ BaCrO4 㸪SrCrO4 㸪CaCrO4 ࡢ㡰࡜࡞ࡗ࡚࠸ࡿࠋࡼࡗ࡚㸪[CrO4 2 ] ࡢ್
ࢆ 0 ࠿ࡽ኱ࡁࡃࡋ࡚࠸ࡃ࡜㸪ࡲࡎ BaCrO4 ࡀỿẊࡋ㸪ḟ࠸࡛ SrCrO4 ࡀỿẊࡍࡿࡇ࡜ࡀศ࠿ࡿࠋࡺ࠼࡟㸪Ba2+ ࡢࡳࢆ 99.9 % ௨ୖỿẊࡉࡏࡿ࡟ࡣ㸪Ba2+ ࡀỿẊࡋ㸪Sr2+ ࡀỿẊࡋ࡞࠸᮲௳ࢆ᥈ࡏࡤࡼ࠸ࠋ
㸦⟅㸧 3 2BaCrO4 ࡢỿẊࡀ⏕ᡂࡍࡿ࡜ࡁ [Ba2+ ] 5 2.0 × 105 mol/L ࡛࠶ࡿ࠿ࡽ㸪⁐ゎᗘ✚ࡢᐃ⩏ࡼࡾ
109.9 mol2 /L2109.9 mol2 /L2[CrO4 2 ] === 5.0 × 105.9 mol/L2+[Ba ]2.0 × 105 mol/Lࡀᚓࡽࢀࡿࠋ୍᪉㸪[CrO4 2 ] ࢆ኱ࡁࡃࡋ࡚ SrCrO4 ࡀỿẊࡋጞࡵࡿ▐㛫ࡢ [CrO4 2 ] ࡣ㸪⁐ゎᗘ✚ࡢᐃ⩏ࡼࡾ

[CrO4 2 ] =104.7 mol2 /L2104.7 mol2 /L2=
= 5.0 × 103.7 mol/L2+[Sr ]2.0 × 102 mol/L࡜࡞ࡿࠋ௨ୖࡼࡾ㸪㢟ពࢆ‶ࡓࡍ [CrO4 2 ] ࡢ⃰ᗘ⠊ᅖࡣ

5.0 × 105.9 mol/L 5 [CrO4 2 ] < 5.0 × 103.7 mol/L࡜Ỵࡲࡿࠋࡇࡇ࡛㸪H2 CrO4 ࡢึ⃰ᗘ࡜ (3) ᘧ࠿ࡽ
5.0 × 101 Ka mol/L[CrO4 2 ] = × 5.0 × 101 mol/L =Ka + [H+ ]࡜⾲ࡏࡿࠋ(4) ᘧࡢ㏫ᩘࢆྲྀࡗ࡚ (6) ᘧࢆ௦ධࡍࡿࠋ
1
Ka + [H+ ]1<55.0 × 103.7 mol/L
5.0 × 101 Ka mol/L
5.0 × 105.9 mol/L
Ka × 102.7 < Ka + [H+ ] 5 Ka × 104.9
¡ 2.7
¡¢
¢
! Ka 10  1 < [H+ ] 5 Ka 104.9  1㸦⟅㸧 4 25 76 47 9(5) ᘧ࡛ 1 ࡢ㒊ศࢆ↓どࡋ㸪(1) ᘧࡢ್ࢆ௦ධࡍࡿ࡜㸪ồࡵࡿ pH ࡢ⠊ᅖࡀᚓࡽࢀࡿࠋ

106.5 mol/L × 102.7 < [H+ ] 5 106.5 mol/L × 104.9
103.8 mol/L < [H+ ] 5 101.6 mol/L! 1.6 5 pH < 3.8

㸦⟅㸧 8

19610

3

118(4)

(6)

(5)

2
ศᏊᘧࡀ C5 H12 O ࡢ࢔ࣝࢥ࣮ࣝ࡟ࡣ㸪ḟࡢ (1) 㹼 (8) ࡢ 8 ✀㢮ࡢᵓ㐀␗ᛶయࡀᏑᅾࡍࡿࠋ

A ࡜ B ࡣ࡜ࡶ࡟┤㙐≧ࡢ 2 ⣭࢔ࣝࢥ࣮࡛ࣝ࠶ࡿࡀ㸪B ࡣ୙ᩧⅣ⣲ཎᏊࢆᣢࡘࡢ࡛ (2) ࡛࠶ࡾ㸪A ࡣ (3) ࡜ศ࠿ࡿࠋCࡣศᯞ≧ࡢ୙ᩧⅣ⣲ཎᏊࢆᣢࡘ 2 ⣭࢔ࣝࢥ࣮࡛ࣝ (5)㸪D ࡣศᯞ≧ࡢ୙ᩧⅣ⣲ཎᏊࢆᣢࡘ 1 ⣭࢔ࣝࢥ࣮ࣝ࡞ࡢ࡛ (7)࡛࠶ࡿࠋE ࡣศᏊෆ⬺Ỉ࡛ࡁ࡞࠸ࡢ࡛ (8) ࡜ỴࡲࡿࠋF ࡣ 3 ⣭࢔ࣝࢥ࣮ࣝࡢ (6) ࡜࡞ࡿࠋࡼࡗ࡚㸪⬺Ỉ཯ᛂࡢ⏕ᡂ≀࡛࠶ࡿ࢔ࣝࢣࣥࡀḟࡢࡼ࠺࡟Ỵᐃࡍࡿࠋၥ 1 ࣮ࣚࢻ࣒࣍ࣝ཯ᛂࡀ㝧ᛶ࡞ࡢࡣ (2) B ࡜ (5) C ࡛࠶ࡿࠋ㸦⟅㸧 12 ࣭ 13 2 ࣭ 3 㸦㡰୙ྠ㸧
ၥ 2 Ⅳ⣲ཎᏊࡀᖖ࡟ྠ୍ᖹ㠃ୖ࡟࠶ࡿࡢࡣ J ࡢࡳ࡛࠶ࡿࠋ
㸦⟅㸧 14 4ၥ 3 ࢜ࢰࣥศゎ࡛ CH3 CHO ࡀ⏕ᡂࡍࡿࡢࡣ Gc 㸪Gt 㸪J ࡛࠶ࡿࠋHCHO ࡀ⏕ᡂࡍࡿࡢࡣ H㸪I㸪K ࡛࠶ࡿࠋCH3 COCH3ࡀ⏕ᡂࡍࡿࡢࡣ J ࡛࠶ࡿࠋ㸦⟅㸧 15 ࣭ 16 ࣭ 17 1 ࣭ 2 ࣭ 518 ࣭ 19 ࣭ 20 3 ࣭ 4 ࣭ 621 5
ၥ 4 H ࡜ J ࡟ Br2 ࢆ௜ຍࡍࡿ࡜㸪ࡑࢀࡒࢀ CH3 CH2 CH2 C HBrCH2 Br ࡜ (CH3 )2 CBrC HBrCH3 ࢆ⏕ࡌࡿࡢ࡛㸪ᵓ㐀␗ᛶయࡣ 2 ಶ㸪୙ᩧⅣ⣲ཎᏊࢆᣢࡘᵓ㐀␗ᛶయࡶ 2 ಶ࡛࠶ࡿࠋḟ࡟㸪H ࡜ J ࡟ HBr ࢆ௜ຍࡍࡿ࡜㸪H ࠿ࡽࡣ
CH3 CH2 CH2 C HBrCH3 ࡜ CH3 CH2 CH2 CH2 CH2 Br㸪J ࠿ࡽࡣ (CH3 )2 CBrCH2 CH3 ࡜ (CH3 )2 CHC HBrCH3 ࢆ⏕ࡌࡿࡢ࡛㸪ᵓ㐀␗ᛶయࡣ 4 ಶ㸪୙ᩧⅣ⣲ཎᏊࢆᣢࡘᵓ㐀␗ᛶయࡣ 2 ಶ࡛࠶ࡿࠋ
㸦⟅㸧 22 223 224 2
ၥ 5 (8) E ࡣศᏊෆ⬺Ỉ࡛ࡁ࡞࠸ࡀ㸪2 ศᏊ㛫࡛⬺Ỉࡋ࡚࢚࣮ࢸࣝࡣ⏕ᡂ࡛ࡁࡿࠋ

2 C5 H12 O 㸦⟅㸧 255

C10 H22 O + H2 O

3
ၥ 1 ࣟ࢖ࢥࢺ࢚ࣜࣥ A4 ࡟ࡣ࢔࣑ࢻ⤖ྜࡀ࡞࠸ࡢ࡛㓝⣲ E1 ࡜ E2 ࡣస⏝ࡋ࡞࠸ࠋࣟ࢖ࢥࢺ࢚ࣜࣥ E4 ࡟ CS ⤖ྜࡀ࠶ࡿࡢ࡛㸪ࣟ࢖ࢥࢺ࢚ࣜࣥ B4 ࡟స⏝ࡍࡿ㓝⣲ࡣ E3 ࡛࠶ࡿࠋࡼࡗ࡚㸪ࣟ࢖ࢥࢺ࢚ࣜࣥ B4 ࡣ (a) 㹼 (c) ࡢ࠸ࡎࢀ࠿࡛࠶ࡿࡀ㸪5 ఩ࡢⅣ⣲࡟⤖ྜࡋ࡚࠸ࡿ OH ࡣ࢚࣮ࢸࣝ⤖ྜ࡟⏤᮶ࡋ㸪㓝⣲ E3 ࡣࠕ஧㔜⤖ྜࡋࡓⅣ⣲ཎᏊࡢࡦ࡜ࡘ࡟ࣄࢻࣟ࢟ࢩᇶࢆ௜ຍࡍࡿࠖ࡜࠶ࡿࡢ࡛㸪12 ఩ࡢⅣ⣲࡟ OH ࡀ⤖ྜࡋ࡚࠸ࡿ (c) ࡀヱᙜࡍࡿ㸦13 ఩
ࡸ 3 ఩ࡣࣟ࢖ࢥࢺ࢚ࣜࣥ A4 ࡟࠾࠸࡚஧㔜⤖ྜࡋࡓⅣ⣲ཎᏊ࡛ࡣ࡞࠸㸧ࠋ୍᪉㸪ࣟ࢖ࢥࢺ࢚ࣜࣥ C4 ࡢ⏕ᡂ࡟㛵୚ࡍࡿ㓝⣲ࡣ E4 ࡛࠶ࡾ㸪ࡑࡢᚋ࡛㓝⣲ E1 ࡜ E2 ࡟ࡼࡾ࢔࣑ࢻ⤖ྜࡀຍỈศゎࡉࢀࡿࡇ࡜ࢆ⪃៖ࡍࡿ࡜㸪࢔࣑ࢻ⤖ྜࢆ 2 ಶᣢࡘ (d) ࡀࣟ࢖ࢥࢺ࢚ࣜࣥ C4 ࡜Ỵᐃࡍࡿࠋࣟ࢖ࢥࢺ࢚ࣜࣥ C4 ࡢᚋࡣ㸪㡰ḟ࢔࣑ࢻ⤖ྜࡀຍỈศゎࡉࢀ࡚ࣟ࢖ࢥࢺ࢚ࣜࣥ D4 㸪ḟ࠸࡛ࣟ࢖ࢥࢺ࢚ࣜࣥ E4 ࡀ⏕ᡂࡍࡿࠋ㸦⟅㸧 26 7ၥ 2 ᐇ㦂 2 ࡼࡾ㸪㜼ᐖ๣ X ࡣࣟ࢖ࢥࢺ࢚ࣜࣥ D4 Ѝ ࣟ࢖ࢥࢺ࢚ࣜࣥ E4 ࡢኚ᥮ࢆ㜼ᐖࡋ࡚࠸ࡿࡇ࡜ࡀศ࠿ࡿࠋࡇࡢ
㐣⛬࡛ࡣ࢔࣑ࢻ⤖ྜࡀຍỈศゎࡉࢀࡿࡢ࡛㸪㓝⣲ E1 ࡲࡓࡣ E2 ࢆ㜼ᐖࡋ࡚࠸ࡿࠋ
㸦⟅㸧 27 5ၥ 3 ᐇ㦂 3 ࡼࡾ㸪㜼ᐖ๣ Y ࡣࣟ࢖ࢥࢺ࢚ࣜࣥ A4 Ѝ ࣟ࢖ࢥࢺ࢚ࣜࣥ C4 ࡢኚ᥮ࢆ㜼ᐖࡋ࡚࠸ࡿࡇ࡜ࡀศ࠿ࡿࠋࡇࡢ
㐣⛬࡛ࡣ CS ⤖ྜࡀ⏕ᡂࡍࡿࡢ࡛㸪㓝⣲ E4 ࢆ㜼ᐖࡋ࡚࠸ࡿࠋ
㸦⟅㸧 28 4ၥ 4 ᐇ㦂 4 ࡼࡾ㸪㜼ᐖ๣ Z ࡣࣟ࢖ࢥࢺ࢚ࣜࣥ C4 Ѝ ࣟ࢖ࢥࢺ࢚ࣜࣥ D4 ࡢኚ᥮ࢆ㜼ᐖࡋ࡚࠸ࡿࡇ࡜ࡀศ࠿ࡿࠋࡇࡢ
㐣⛬࡛ࡣ࢔࣑ࢻ⤖ྜࡀຍỈศゎࡉࢀࡿࡢ࡛㸪㓝⣲ E1 ࡲࡓࡣ E2 ࢆ㜼ᐖࡋ࡚࠸ࡿࠋ
㸦⟅㸧 29 5ၥ 5 ◲㯤ཎᏊࢆྵࡴࣟ࢖ࢥࢺ࢚ࣜࣥ㢮࡟ࡐࢇᜥ⑕≧ࢆᘬࡁ㉳ࡇࡍຠᯝࡀ࠶ࡿ࡜ࡋ࡚࠸ࡿࡢ࡛㸪ࣟ࢖ࢥࢺ࢚ࣜࣥ A4 Ѝࣟ࢖ࢥࢺ࢚ࣜࣥ C4 ࡢኚ᥮ࢆ㜼ᐖࡍࡿ Y ࡟ࡐࢇᜥ⑕≧ࡢ⦆࿴ຠᯝࡀ࠶ࡿ࡜⪃࠼ࡽࢀࡿࠋ㜼ᐖ๣ X ࠾ࡼࡧ Z ࡛ࡣ㸪◲㯤ཎᏊࢆྵࡴࣟ࢖ࢥࢺ࢚ࣜࣥ㢮ࡀ⏕ᡂࡍࡿࡢ࡛⦆࿴ຠᯝࡣ࡞࠸࡜⪃࠼ࡽࢀࡿࠋ
㸦⟅㸧 30 34ၥ 1㸦⟅㸧 312

ၥ 2 ᅗ 4-3 ࡢ࢔ࣛࢽࣥࡣ L య࡜࿧ࡤࢀࡿࠋCOOH ࢆᡭ๓࡟ࡍࡿ࡜㸪CH3 㸪NH2 㸪H ࡣ཯᫬ィᅇࡾ࡟㓄⨨ࡋ࡚࠸ࡿࠋゎ⟅⩌ࡢ࢔ࣛࢽࣥ 1 㹼 5 ࡟ࡘ࠸࡚ぢࡿ࡜㸪 5 ࡢࡳ L య࡜ศ࠿ࡿࠋ௚ࡢ 4 ࡘࡣ D య࡜࠸࠺ࠋ㸦⟅㸧 3255
ၥ 1 ୰࿴Ⅼࡣ⁲ᐃ᭤⥺ࡢഴࡁࡀ᭱ࡶ኱ࡁ࠸ V = 23.02 mL ࡛࠶ࡿࠋồࡵࡿ HB ࡢࣔࣝ⃰ᗘࢆ x mmol/L ࡜ࡍࡿ࡜㸪ḟࡢ㛵ಀࡀᡂࡾ❧ࡘࠋ

x mmol/L × 20.00 mL × 1 ౯ = 1.564 mmol/L × 23.02 mL × 1 ౯! x mmol/L = 1.800 mmol/L = 0.001800 mol/L㸦⟅㸧 338

ၥ 2 V = 20.00 mL ࡢ࡜ࡁ㸪Ỉ⁐ᾮࡢయ✚ࡀ (20.00 + 20.00) mL = 40.00 mL ࡟࡞ࡗ࡚࠸ࡿࡇ࡜࡟ὀពࡍࡿࠋ20.00 mL[Na+ ] = 1.564 mmol/L ×= 0.7820 mmol/L
40.00 mL
[H+ ] = 104.000 mol/L = 0.1000 mmol/L
20.00 mL
[HB] + [B ] = 1.800 mmol/L ×= 0.9000 mmol/L
40.00 mL
pH = 4.000 ࡛ࡣ H2 O ࡢ㟁㞳࡟ࡼࡿ [OH ] ࡣ↓ど࡛ࡁࡿࡢ࡛㸪㟁Ẽⓗ୰ᛶ᮲௳ࡼࡾ

[B ] = [Na+ ] + [H+ ]  [OH ] ; [Na+ ] + [H+ ] = (0.7820 + 0.1000) mmol/L = 0.8820 mmol/L[HB] = (0.9000  0.8820) mmol/L = 0.0180 mmol/L࡜ồࡵࡽࢀࡿࠋ
[H+ ][B ]0.1000 mmol/L × 0.8820 mmol/L
Ka === 4.9 mmol/L = 4.9 × 103 mol/L[HB]
0.0180 mmol/L㸦⟅㸧 344359363

=

[B ]
0.8820 mmol/L== 0.98[HB] + [B ]0.9000 mmol/L㸦⟅㸧 37 038 9⁲ᐃ㛤ጞ๓࡟ࡘ࠸࡚ࡣ㸪

39

8[Na+ ] = 0 mmol/L[H+ ] = 102.854 mol/L = 100.146 mmol/L = 1.400 mmol/L[HB] + [B ] = 1.800 mmol/L[B ] ; [Na+ ] + [H+ ] = (0 + 1.400) mmol/L = 1.400 mmol/L[HB] = (1.8000  1.4000) mmol/L = 0.4000 mmol/L࡜࡞ࡗ࡚࠸ࡿࠋࡼࡗ࡚㸪 0 ࡣḟࡢࡼ࠺࡟࡞ࡿࠋ
0 =

[B ]
1.4000 mmol/L== 0.78[HB] + [B ]1.8000 mmol/L㸦⟅㸧 40 6
࠙ὀࠚ100.146 ࡢ್ࢆィ⟬ࡍࡿࡇ࡜ࡀ࡛ࡁ࡞࠸ࠋၥ 3 ࡢࢢࣛࣇࢆཧ⪃࡟ࡍࡿࡋ࠿࡞࠸ࡔࢁ࠺ࠋ
ၥ 3 ⁲ୗ㔞ࡀ V = 0 mL ࡢ࡜ࡁࡢ್࡜ V = 20.00 mL ࡢ್ࢆཧ⪃࡟ࡋ࡚ࢢࣛࣇࢆ㑅ᢥࡍࡿࠋ࡞࠾㸪[OH ] ࡣ୰࿴Ⅼࡲ࡛ࡣ࡯ࡰ 0 ࡛࠶ࡾ㸪ࡑࡢᚋቑຍࡋ࡚࠸ࡃࠋ
㸦⟅㸧 41 642 543 844 9࠙໬Ꮫ㸦ㅮホ㸧ࠚ᫖ᖺᗘ࡜ྠࡌࡃ኱ၥࡣ 5 㢟࡛࠶ࡗࡓࠋࡲࡓ㸪࣐࣮ࢡᩘࡣ 2017 ᖺᗘࡀ 59㸪2018 ᖺᗘࡀ 38 ࡜࠿࡞ࡾῶᑡࡋࡓࡀ㸪௒
ᅇࡣ 44 ࡟࡞ࡾⱝᖸᡠࡋࡓࠋタၥᩘࡣ 2018 ᖺᗘ࡜ྠ⛬ᗘ࡛࠶ࡿࠋ☜ᐇ࡞ィ⟬ຊࢆᚲせ࡜ࡍࡿၥ㢟ࡀྵࡲࢀ㸪Ꮫ⩦ෆᐜ࡟⩦⇍ࡋ࡚࠸࡞࠸࡜㧗ᚓⅬࡣᮃࡵ࡞࠸ࠋ

1 2 ౯ࡢ㓟ࡢ㟁㞳ᖹ⾮㸪࠾ࡼࡧ⁐ゎᗘ✚ࡀ㛵ࢃࡿၥ㢟࡛࠶ࡾ㸪㢮㢟ࢆࡼࡃ₇⩦ࡋ࡚࠾࠸ࡓ࠿࡝࠺࠿࡛ᕪࡀ௜ࡃၥ㢟࡛࠶ࡿࠋᣦᩘࢆྵࡴィ⟬ࡢฎ⌮ࡀ☜ᐇ࡟࡛ࡁࡓࡔࢁ࠺࠿ࠋ
2 C5 H12 O ࡢศᏊᘧ࡛⾲ࡉࢀࡿ࢔ࣝࢥ࣮ࣝ࡟㛵ࡍࡿ඾ᆺၥ㢟࡛࠶ࡾ㸪᏶⟅ࡣᚲ㡲࡛࠶ࡿࠋ
3 ࣟ࢖ࢥࢺ࢚ࣜࣥ㢮ࡢ⏕ྜᡂ࡟㛵ࡍࡿၥ㢟࡛࠶ࡿࡀ㸪ணഛ▱㆑ࡣ≉࡟ᚲせ࡞ࡃ㸪㓝⣲ࡢᇶ㉁≉␗ᛶࢆ⌮ゎࡋ࡚࠸ࢀࡤពእ࡜㞴ࡋࡃࡣ࡞࠸ࡇ࡜ࡀศ࠿ࡿࠋYMS ࡢ 12 ᭶ᶍヨ࡛ࡣ㸪ࣟ࢖ࢥࢺ࢚ࣜࣥࡢ㏆⦕≀㉁࡛࠶ࡿࣉࣟࢫࢱࢢࣛ
ࣥࢪࣥࡢ⏕ྜᡂ㐣⛬ࢆ⪃ᐹࡍࡿၥ㢟ࢆฟ㢟ࡋࡓ㸟ࡋࡗ࠿ࡾ᚟⩦ࡋࡓேࡣ㸪ࡇࡢࡼ࠺࡞⏕ྜᡂ࡟㛵ࡍࡿၥ㢟ࡀฟ࡚ࡶៃ࡚࡞࠿ࡗࡓࡣࡎ࡛࠶ࡿࠋ
4 ࢔ࣛࢽࣥࡢ❧య㓄⨨࡟㛵ࡍࡿၥ㢟࡛ 2 ၥࡋ࠿࡞࠸ࡀ㸪❧య㓄⨨ࢆㄞࡴ⦎⩦ࢆࡸࡗࡓே࡟ࡣᐜ᫆࡞ၥ㢟࡛࠶ࡿࠋ
5 ᙅ㓟ࡢᙉሷᇶ࡟ࡼࡿ୰࿴⁲ᐃࢆᢅࡗ࡚࠸ࡿࡀ㸪⁲ᐃ᭤⥺࡛࡞ࡃ㸪⁲ᐃ್ࡢᩘ⾲ࢆ୚࠼࡚࠸ࡿࡇ࡜ࡀ┠᪂ࡋ࠸ࠋၥ 2ࡣ㉁㔞స⏝ࡢἲ๎㸪㟁Ẽⓗ୰ᛶ᮲௳㸪≀㉁཰ᨭ᮲௳ࢆ㐃❧ࡍࡿၥ㢟ࡢ⦎⩦㔞࡛ᕪࡀ௜ࡃࠋ࡞࠾㸪ᑐᩘ್ࡀ୚࠼ࡽࢀ࡚࠸࡞࠸ࡓࡵゎ⟅ࡀᅔ㞴࡞タၥࡀᏑᅾࡍࡿࠋ
᭱ప࡛ࡶၥ㢟 1 ࡢ 3 ࡲ࡛㸪ၥ㢟 2 ࡜ 4 ࡢ඲㒊㸪5 ࡢ 39 ࡲ࡛ࡣṇゎࡍࡿᚲせࡀ࠶ࡿࠋࡑࢀ࡟ຍ࠼࡚㸪3 ࡢ㢟ពࡀㄞࡳྲྀࢀࡉ࠼ࡍࢀࡤ᏶⟅ࡶྍ⬟࡛࠶ࡿࠋࡋ࠿ࡋ㸪᫬㛫ࡀࢱ࢖ࢺ࡞ࡢ࡛ᡭ㝿ࡼࡃฎ⌮ࡋ࡞࠸࡜࠸ࡅ࡞࠸ࠋ௨ୖࢆ຺
᱌ࡍࡿ࡜㸪70 % ࡢᚓⅬ⋡ࢆ┠ᶆ࡟ࡋࡓ࠸ࠋ