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Downloading files with JSZip is nice, but sometimes you need to
extract a file and have a folder with the name you select. you canachieve this using the zip.dirname(this.archive, this.folder)method. The archive parameter contains the path to the archive
you want to extract, and the folder parameter receives the path tothe directory where the file will be extracted. If no folder isspecified, the current working directory is used. Call this methodwith a folder name as the second parameter. In the following
example, you can see how to extract a file from a.zip archive intoa folder with a default name. .zipArchive.file(pathToFile,this.zip.dirname('/Home/User/Desktop')); This is the.zip archivewith sample files and folders. When you run this method, thefolder created will be /Home/User/Desktop. You can also supply
an array of folders to the folder method. This is the following
example. .zipArchive.file(pathToFile, ['/Home/User/Desktop','/Home/User/Documents']); The folder name is the same as thearray key. The folders within the array will be converted to the2/3archive as new folders. Back to the.zip example. The below
example shows how to extract a file from an archive with a custom
folder. .zipArchive.file(pathToFile, 'dirname.zip',this.zip.dirname('dirname.zip')); This is the.zip archive withsample files and folders. When you run this method, the folder
created will be dirname.zip. If no folders are added in the array, allfiles in the archive will be extracted to the current working
directory. Back to the.zip example. This is the.zip archive withsample files and folders, and two folders to extract in a specificlocation. When you run this method, the folder created will bedirname.zip, and the two folders inside will be/Users/User/Documents and /Users/User/Desktop. Mantenimiento
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Xbox Controller for PC: Use with PC games & tv. Tips for gamers and gamers newbie