Get the light velocity, the Planck's constant,
Electron and the gravitational constant by thecomputation.
Shogo Niimi
89 Nishigo Kashima Gamagori Aichi, 4430037, JPN.

The famous scientists make as confuse as many unification of the space and the material a goal.

I think that this confusion happens by

do not have the standard that evaluates them.

I get the Light velocity and the Planck's constant in the identical condition on the theory.

Moreover, I could get Electron based on it.

Also, it links the gravitational constant.

I expect that find the grand unified theory inaddition to the standard by this theory if can raise this.
You will recognize that our space was[Fig.1]born with the Big Bang.

three-dimensional

However,no one knows the necessary condition,

I place vector P in thespace.

The

between this P and each dimension rj(jstatus and so on. I do not think that

=1,2,3) has ωjτ.

the Superstring theory1) and latest

P is composed by Pjsinω j τ and Pjcosω j τ.

M-theory2) which includes it are

Pj is the absolutevalue of P. By the way, I can replace Rω

expressing the truth of the Big Bang.

exp(±σjτ) of expression(3) to Pj. This isj

All theory handles light velocity cthe same as the cosine of P.

and Planck’s constant  as axiom

understand thatand cannot find them on their theory.

/////P = ( Pjcosωjτ, Pjsinωjτ)

Therefore, I need c and  that findthem on pure theory.

I want to find

angle

I can

is
/////P = ( Pjcosωjτ, Pjcosωkτ, Pjcosωlτ)

them out for the great development ofEach j, k and l has numbers 1, 2 and 3, however they cannot express the samethe science.

number at the same time. Therefore, I get relation

I develop original

theory for the goal.

Therefore, write

down the procedure below.

/////Psinωjτ = ( Pcosωkτ, Pcosωlτ)by the orthogonal relation of each ingredient.

First, I recognize the existencewhole-space H that does not have adimension.

This H is incomplete

stable and always likes a change.
After a lot of labile change, H became
H9 that has 9 dimensions by thephase transition. It is composed byreal-space R , complex-space G and3

3

imaginary-space I3 that have three
dimensions respectively.

I searched

for the solution that this H9 has.
Then, I got the elementary function.
2

f(θj) =

R ωj exp(±σjτ)cosωjτ22(σj +ωj )(1)

R is a merely symbol that does nothave a meaning as the value. Thisfunction has two kinds of expression.

You pay attention to the symbol thatis in the exponential function.

Icalculate them that give both an
identical condition to [+] and [-] inthe numerical.

I got a wonderfulsolution in case of [ωjτ=/wjτsinθj, wj
τ=/48.87668] on there.
expression

The side of
has

[+]

value

299792458[m1s-1] that is the same as c,
and

[-]

has

value

1.05457 ×

10 [V A s ] that is the same as .
-34

1

1 2

Then, I give the side of [+] vj and givethe side of [-] the symbol of  j inexpression (1). I discovered that w isthecurvature.

The

If you can believe that τ hasτ.

Planck time, then the value of radius
w in H9 has 9.06992×10+44[rad1s-1].
In the above, I have convincedthat the electromagnetic field exists
there.

Here, try to the creation ofelectron.

Therefore, I must put theelementary function into G3. Now, I
can find electric charge qj by these
expressions.

This value of qj has

width from 1.60167×10-19 to 1.60249×
10-19.

This width is equivalent tothe curvature radius then canvassed

micro movement angle

the elementary function.

ωjτ.

Therefore,

get a result that whole-space H9 has-１-

curvatureradius is determined by the value of⊿ωτ ofThis ⊿ωτ that electron has

the motion of precession angle.

Atlast, we discuss that need this ⊿ωτ[Fig.2]where find electronic mass mq, in thiscomplex space G3 that is enclosed by real

paper.

space R3 and imaginary space I3. The angle

I need this ⊿ωτ for getelectronic mass mq.

Finally, we will

I place complex vector C inthat between this C and dimensional axis rj

get gravitational constant GN after(j=1,2,3) has ω j τ.

grow this theory up.

replace Q ω j cos ω j τ /( ω j2+ σ j2) of

By the way, I can2

expression (8) to Dj. I know that [exp(-iσj
The elementary functionτ)] is [cosσjτ-isinσjτ].

I referred to the oscillation circuit3) ofgetting on ij.

the electronics to get the elementaryfunction.

I have an idea that theoscillation condition is the phasetransition,comparetoregularisinσjτ is

In this case, Dj has both ofthe cosine ingredient and the sine ingredient.
Therefore, I can set Dj in C, as follows.
//////C = ( Dj cosσjτ, - i Dj sinσjτ)
I can accept the orthogonal relation even if cosσjτ to isinσjτ is a difference ofvibration of the electromagnetic wave.

the real ingredient to the imaginary ingredient. Also, I make Cj that is absolute value

The amplification circuit and the|C|. In the above, I get

feedback

circuitcomposetheoscillation

circuit.

At

I

first,

replaced those circuits with R3 and I3.

//////Cj = ( |Dj 2cos2ωjτ|+|Dj 2sin2ωjτ| )1/2
In addition to it,//////C = ( Dj cosωjτ, Dj cosωkτ, Dj cosωlτ)This solution oscillates in surely.

You must be careful in that (iDj sinωjτ, iDj sinωkτ, iDj sinωlτ) is the double of C

However, I understand that spaceand has reverse direction.

itself is disappeared immediately//////-2C = ( iDj sinωjτ, iDj sinωkτ, iDj sinωlτ)after the phase transition in case of

As the result, I agree that it is possible to express by three dimension elements even

the whole space has H =/[ R |I ].

if C has six dimension elements.

6/

3

3

Therefore, must add another circuitG

3

for space not to disappear.

Ishould say it the resonance circuit.
Here,

write

transition

in

down

the

phase

whole-spaceH

asfollows.

Write down k( θ j) that is one ofingredient of it below.
//k(θj) = Rωj exp(±σjτ) cosωjτ/(3)This k(θj) is a solution that exists
only in R3.

phase tr//H →using the Laplace transform ([Fig.1]).

the numbers in j that has 1, 2, 3.

H9 = [ R3｜G3｜I3 ]//////////// (2)The relation between σ and ω isThis G3 is the complex space that iscomposedbyreal-space

imaginary-space I .
3

and

R3

I can choose any one of

I call it the gap

wj=/( σ j, ω j ) by the Bromwich=
Wagner theorem5).

Therefore,

they have σj/= wjcosθj, ωj/= wjsinθj.

space because G3 exists at the crack

Variables σj,of R3 and I3.

subordination each other.

They are in the

ωj, wj, θj are in theincomplete disintegration condition

elementarythat the information can be each

integration of k( θ j).

other exchanged.

function

Gap space G3 thathas some information and three
dimensions is like a membrane thatis the thin screen which partitions R

3and I3. We can imagine the beautiful
film of the soap bubble.

I am

possible to call G3 the holographic
membrane4) by applying it to the
M-theory.
I got solution k that has three
dimensions from expression (2) infunctiontoI getf( θ j)by

I make theeasy-to-understandexpressions.
[c]ωj exp(+σjτ)cosωjτ(σj2+ωj2)
1 -1/////////////////////[m s ] /// (4)2j =[]ωj exp(-σjτ)cosωjτ(σj2+ωj2)////////////////////[V1A1s2]/// /(5) is the symbol that has divided
Planck's constant h by 2π.

-２-

I use [c] and [  ] as the merely
symbol which does not have value.
The light velocity with the Planck's
constant
I must observe variables attentively
before calculation.

Specifically, can

not give isolated τ value.

The τ

has a high degree of freedom and I do
not have the logical limitation that
determines the value.

Therefore, I

always give sets [ωjτ], [σjτ], [wjτ]
value.

Properly, can give θj value.

However, must remember that thesevariables are in the subordinationeach other.

In above reason, I can

not calculate expression (3) except

2

vj =

Incidentally, on all paper6) of mine,

what ignores ω j.

However, cancalculate

is

the

most

important elementary function.

The

expressions (4), (5) are same.

The

(1)

that

work that I need now is to rewrite
expressions using θ j.

Will beenough, rewrite only (1).

Here, I

write down a solution of it.

f (θj)=R sin2θj exp(±wjτcosθj )[Fig.3]///////////////////////////////×cos(wjτsinθj )four axes ω j τ, wj τ, qj, θ j to the figure.

Each ⊿ w τ= 0.025235,⊿θ=////////////////////////////////////////////////////////(6)0.032126893 is the movement angle of wjτ,θj.

Also, ⊿q = 8.2×10-23 is width ofJust, I can calculate in having thisexpression.

Properly, I cannot missrelation ωjτ= wjτsinθj. For now, I
do not know a range with the value
that

is

given

to

all

variables.

Therefore, I who have no handhold

I examine what relations that I got value in this paper use a figure.

electric charge qj.

I giveThis ⊿wτ・⊿θ is the base that is the existence area of the

Product ⊿wτ・⊿θ is ⊿ωτ= 8.1058268×10-4 approximately.

electric charge.

Therefore, the electric charge exists in the area of ⊿wτ・⊿θ・qj. The straightlines that are bold in the figure are the size of the electric charges to correspond
number j. All electric charges on straight line  j/vj. Actually, ⊿ωτ=⊿wτ・
sin⊿θ.

and no special reason give ω j τ
inclination

axis(=/0.955316618).

ofelectron7)Θ

I can give wj τ allvalue which excludes zero.

Thevalue of θj has been determined by
I cannot give you

both of ωjτ, wjτ.

all my worksheets in here but givethe part of the interesting result[Sheet1].
ΘThe θj in case of ωjτ=/

and

has

wj τ =/48.886015

0.01954295990542.

In this condition,

vj=/3.71738×10+17 and  j/=/1.30765×
10-25.

Surely, you will give looks

like this frivolous solution of me highevaluation by compute ratio  j/vj.
This ratio has 3.51767×10-43 that is
the same as value /c.

I have thenext work on this positive result.

I

discovered that expression (4) and (5)has c and  in the following
condition

after

a

lot

of

value

calculation.
Case (1)
Condition (1)//////wjτ=/48.87668//////////ωjτ=/0.00001312066853π/2//////////θj/=/4.21671396911943×10-7
Result (1)are the following two expressions.

/////////// j/=/1.05457×10-34
The results have a small error by thelimit of my computer.

If I haveopportunity, want to give you all
worksheets.

I

hope

you

////// j/=/1.05457×10-34
I have case (2) that is a result ofwriting by the word and write down
another case (3) below.
Case (3)
Condition (3)//////wjτ=48.901915//////////ωjτ=0.999999999890292π/2//////////θj/=/0.0321268926188024
Result (3)///////////vj = 299791839.4

may

re-examine by your supercomputer.

[Q]ωj exp(+iσjτ)cosωjτ(σj2+ωj2)

(7)

2

Q-j =

[Q]ωj exp(-iσjτ)cosωjτ(σj2+ωj2)(8)

First, you must determine the value

Expression (7) has a singular point onof wjτ re-examine from case (1) toθj/=π/4. It has a special meaning(3).

Next, You should find ω j τ .

The

θ j

is

determined

in

the

relational expression of the variables.

but I consider only expression (8).

operation (refer to [Sheet2]).

I

give this expression (8) symbol Qj thatis vibrating.

You can get vj and  j after thisI must give this Qj the unit
dimension. Therefore, pay attention
to the relation in electric field

The creation of electron

E[V1m-1] and magnetic field B[A1m-1]

I use [VAMS] unit system

8)//////vj = 299792458

2

Q+j =

paper.

in this

Isao Imai - The University ofTokyo - is proposing this.

He takesby Maxwell9).

We get 1/(ε 0 μ 0)1/2

from ratio E/B.

As you know this is

the light velocity.

Incidentally, ε 0

it for the defect that mass Kg is a

is the dielectric constant in thefundamental unit in [MKSA] unit

vacuum and μ 0 is the magnetic

system and the other unsatisfactory

permeability.

cancellation.

understand[V1A1m-2s3].

Therefore,[Kg1] ≡

Seems complicated but

actually, it is simple.

For example,

Now,
that

unit

I

must

dimension[m1s-1] with velocity vj and unit
dimension [V1A-1] with ratio E/B are

Joule J [Kg m s ] in [MKSA] unit

the

same.

In

this

result,system has [V1A1s1] here.

understand

that

unit

dimension

1

2 -2

We need elementary function Qj
that exists in gap space G . They
3

-３-

I

[V1A1m-1s3] with ratio  /c is thesame as [A2s2].

Also, [A2s2] is the[Fig.4]same as the square of electric chargee [A1s1].

Moreover, I understandthat

product

a

by

c



First, I make the three-dimensional

space that has the curvature.

Next, I placeelectron e that is gotten by the experiment on

has

there.

ωjτ includes Θ.

The inclination angle[V1A1m1s1]=[V2s2] is the same as theof electron has Θ = 0.955316618.

square of magnetic flux Φ[V1s1].

minimal movement angle φ of Θ.

ｃ =/3.16153 × 10-26 and (c  ) 1/2 =q iselectron on the theory which was gotten in thisreconsider

Qj.

Give

the

conditions of case (1) and case (3) toQj.

Also, φis the motion of precession angle of e.

1.77807×10-13.
I⊿ ω τ isI get the following result.

We should accept the motion of precession of e that makes q. I am convinced thatthe electronic mass is born by electron has the motion of precession by the space has
the curvature.

Case (1)and Mj.

Result (1)※paper is not nonsense.

Now, I make tj/=τsinθj.

//////QR/=/3.21814×10

Then, ωj in Mj is ωjτsinθj becomes

We know what ratio /c has unit///////////QI/=/1.7487×10-13

not independent.

In addition, I

dimension [A2s2] that the square ofknow that Qj has the imaginary part.

the electric charge. In addition, weThis imaginary part does not appear

know that electric charge e has//////QR/=/3.21814×10

in R .

1.60217×10-19 [A1s1] in the experiment.

///////////QI/=/1.7487×10

Finally,

QR has the real part and QI has theexpression of the electric charge byhasimaginary part of Qj.

I know thatabove operation.

dimensionless.

absolute value |Qj| has 1.77807×10-13///qj = Mjτsinθj/Qj-14

Case (3)Result (3)※
-14

-13

on [Fig.2]. This value is the same as(c )1/2. Now, I understand that Qj
has unit dimension [V1s1] is the sameas magnetic flux Φ.
The elementary function (3) has
two

expressions.

Clearly,I

understand that the side of [+] has
acceleration aj[m1s-2] and the side of[-] has moment of force Mj[A2m1] byexpressions (4) and (5).

The absolutevalue of Mj has energy Ej[V1A1s1].
Intheabove,In this reason, I ignore it.

3I

collected

necessary materials for grasping the

=

I

get

the

particular

By the way, the ratio of /c and e2
β =/1.37036 × 10-5offind fine structure constant 1/ α[e]wjτexp(-wjτcosθj )(9)cos(wjτcosθj )[e] is a merely symbol of the electriccharge.

You refer to worksheet[Sheet2].

You can see that theelectric charge has the width of
1.60167 × 10-19 ≦ qj ≦ 1.60249 × 10-19.
This is a very important result.
Incidentally, the expression of theelectric charge is generalized asfollows.
///qj = [e]wjτ j/Qj/////////[A1s1]///// (10)=/137.036 if accept 4 πε 0c2/=/1×107.
However, 1/ α

is not a logicalsolution here now.
The result as the pre-section, thewidth of electric charge⊿q has 8.2×
10-23.

Let’s see cases (1), (3).

movement angle ⊿ w τ =/0.025235 ofwj τ .

Also, it exists in movementangle⊿ θ =/0.032126893

ofWe will combine ⊿q, β, ⊿wτ
and ⊿ θ .

I will give thiscombination the symbol of mq*.

of the electric charge in this paper infound electron by only got the electricqj.

charge.

Actually, need electronic////mq* =⊿q・β・⊿wτ・⊿θ

electric charge, adopt qj/=/Ajtj. Aj has

mass.

However,the electric current and tj has time.

electronic mass from existing theory.

Electric current Aj is expressed in

For example, electronic mass me

Mj/Qj.

I give that do not have theexists in the classic radius of electron

logical limitation tj value. Actually,

re/=/e2/me and the magnetic moment

the reason is tj and ωj cannot exist

as you say Bohr magneton

independently.

I

e/2me. They are not the expressions

understand that Aj, aj, Mj and Ej do

to get electronic mass originally.

not exist in the independence.

Therefore, I want to discuss how do

In

this

idea,

I

cannot

10)

find

μb/=

similarphysicalwe get electronic mass?

quantity but do not write.

By thepresupposition, we must convince

have

a

lot

of

way, how about the combination tj

As thethat the value that appeared in this

-４-

θ j

([Fig.3]).

I show the symbol

In many expressions of theWe

can understand that ⊿ q exists in

By the way, I cannot affirm thatelectric charge.

theTherefore, we can///////////=9.1100458×10-31////////////// (11)This solution is the same as the value
with electronic mass me/=/9.1093897×
10-31[V1A1m-2s3]

approximately

accidentally. We notices ⊿ωτ=⊿w
τ ・ sin ⊿ θwith the previous

considering.

In addition it, we

notice that value with ⊿ωτ is thesame as ⊿wτ・⊿θ approximately.
We need the agreement thatelectronic mass is invented by whole
space H9 has the curvature.

Then,should replace ⊿ωτ with sin⊿ωτ

1. In addition to it, we know qsinωx

Street> on the hydrodynamics as youtoτ =/(qcos ω y τ , qcos ω z τ ).

know11).

express

electronic

mass

mq

I willWhy <Kármán whirlpool>?

logically.

give it symbol q x. Then, (q + qy +Because, I think that situation of////mq =⊿q・β・sin⊿ωτqz2)1/2 becomes ( qx2 + q*x2 )1/2.

electron is born in the gap space////////=9.1084777×10 //////////////// (12)course, q*x2 has 2/3 electric charge.

resembles

We can distribute 1/3 electric charge

whirlpool is born.

and 2/3 each two quarks in theelectron can be supposed to Kármán

meson.

Also, we cannot doubt quark

whirlpool itself. I3 shows imaginary

confinement on the character of

space, G3 shows gap space and R3

expression |q|. Incidentally, will beshows real space in [Fig.5].

q is

careful of that this theory is different

Kármánandfrom QCD.

resistance object G is equivalent to*-31

I think that the cause of the small
error of mq and me is that electronic
unity e has the curvature.
Here now, let’s discuss aboutthat I suppose the electron spin has
the substance.

We know that allphysical quantities are composed on
the three dimensions. On this fact,
we rewrite expression (10) to q/=/[e]wτ/Q.

Also, can rewrite /Q to(×Q)/Qj2.

 has unit dimension[V1A1s2] of the angular momentum.
×Q expresses spin.

Qj2 is Q・Q.

The solution of Q ・ Q includes
quantum number 2.

As the result,

we understand that spin quantum
number s/=/1/2 appears in the electriccharge function6).

Therefore, willconvince that ⊿ωτ is the minimal
movement angle φ of inclination
axis of electron ω j τ = Θ .

By thisconviction, authorize that φ is the
motion of precession angle of electron([Fig.4]).

In case of this discussion,

we must understand that electronmass is produced by the motion ofprecession with electron.

To getabove result, we must believe thatspin and the motion of precession are
invented by whole space H9 has thecurvature.
We can discuss the fractional
electric charge of the quark. We canwrite q that is composed by the three
dimensions

asq/=/(qx,

qy,

qz).

Suppose that |q| is qj, this is (qx2+qy2+ qz2)1/2 ([Fig.1]). We know that the
inclination axis of electron is ωkτ=/Θ.

k has x, y and z.

Then, weget the solution that qk2/=/q2cos2ωkτ
is 1/3. In this way, the baryon has
the electric charge that is distributed
1/3 each three quarks.

However,the substance of the electric charge is

2
x

2

Of

In addition to the above, we canunderstand

that

the

anomalous

situation

of

KármánIn this way,

whirlpoolelectronthe isolate isle in the natural world.
The vertical line in G3 expresses themagnetic moment is born by thetransverse wave.

space has the curvature.

expresses the diffracted wave, I can

We get

The arc in R3, I3

experiment value μe of the magnetic

supposemoment by product g’ by Bohr

electromagnetic wave. [Fig.6] is the

b.

has

figure that adapted the value that

1.00115965226 that divided a g-factor

was gotten from the gap space theoryby 2.

to Kármán whirlpool.

magnetonμg’Electronic unity e has angle

that

they

are

the

Here, I giveΘ + φ in opened space H also has

the direction of x ωτ and give theangle Θ-φ in closed space H9 under

direction of y θ. Make width to thewe consider the motion of precession

Kármán whirlpool direction of x ⊿ωangle. We examine the cosine ratio

τ and make width to the direction of

9of them and Θ.

The value withy ⊿θ. Give isolate isle G width ⊿ratio g’a/=/cos Θ /cos( Θ + φ ) in thewτ. The way of giving these values

opened space has 1.001148.

The

value with ratio g’b/=/cos(Θ-φ)/cosΘ

does not have logical limitation, only
convenience as visual thinking.

in the closed space has 1.001146. By

The issue is that do I replace

the way, they do not agree with g’.

resistance object G to something of

We will describe the remainder ofthe gap space theory.

them by suppose the electronic unity

about this.

has the curvature same as electronicthat the mass does not born inmass mq.

resistance-less.

I consider

Generally, seem to be
Thestandard

We can anticipation that electronic

theory (the G-W-S theory) authorizes

unity e has the curvature by thethat the mass exists there by theeffect that H9 has the curvature.

Higgs mechanism12).

However, do not get the value ofway, some mechanism will exist here.

curvature with e because do not findFor example, it is following one.

the logical limitation. Nevertheless,

The Light velocity was decision by

all physical quantities have thethat the vacuum has the dielectric

possibility to be limited by curvature

constant and magnetic permeability.

in the space.

Therefore, seem to be that theIn the same

vacuum has viscosity.

I think that

The gravitational constantthis viscosity becomes resistance andWe cannot find the gravitational

generates mass.

constant by the concept, function that

acceptisgenerated by whole space H9 has the

known

same

as

the

mass.

Therefore, I take <Kármán Vortex

-５-

that

this

Therefore, I
resistancewas[Fig.5]////Whole space H9 is composed by real space R3, gap space G3 and imaginary

10-11 and G n = 6.8211×10-11. By the

space I3. For example, I suppose that there is a small hole on the boundary of G3 andway, they have Aʼ that is theR , also set resistance G. The vertical line in G is the vibration of magnetic flux Q.

difference about 2% between G N and

Real part Qr of Q leaks out R3 as I explained in [Fig.4].

G j. Then, I use the general theory of

33Then, Qr collides with G and

has an impact by the angular momentum that exists in R . In this result, electron q

relativity

byAlbertsame as Kármán whirlpool appears in their. This electron q takes the base as the(1879-1955)

for

this

minimum value of Planckʼs constant .

3Einsteindifference.

By the way, the unit of resistance G

Potential ψ in the field of a particle[V1A-1] agrees with the unit of speed [m1s-1]. G, i.e. v is the base of the gravitation,is gotten by the equation of the

supposing that the gravitation is a kind of resistance.

gravitational

Certainly, gravitational

constant GN is gotten by the combination of v, 1/w that is the curvature of the spaceand ο (omicron) that is the self-correction by the gravitation field. ο is gotten by

field

on

the

un-relativity, in the above relativity13).
Actually, ψ has unit [m1s-1]2 that is

the infinite product of the curvature of the space, but replace it to an approximate

square of the speed.

expression ‒sinwτ. Incidentally, I took an isolate isle as resistance G figuratively,

rewrite Gj in (14) use ψ, the result is

not a reality.

Correctly, the space has resistance.

It is clear by the relation
3

between the velocity and the resistance. Incidentally, the relation between G and I

3

Gj = vj /wj τ ψ .

Therefore, I

This expression

shows us that Gj need correction foradjust to the actual space because itis same as the above.

is the gravitational constant on theun-relativity.

So, is the gap space

theoryone

theapproximate

to

get

merelysolution?

The

conclusion is rashness.

I shouldconsiderwhytheequationofgravitational field on the relativity isa nonlinear. In other words, the gap
space theory shows an ideal conditionin the moment that whole space H9was born; on the other hand, thetheory of relativity and the quantum
theory express the condition that the
influence[Fig.6]ofconsidered.

the

self

must

be

Consequently, I should

accept that the theory of relativity,
the quantum theory and the gap
space

theory

also

the

value

of

experiment are correct.
Forward to GUT
curvature.

Resistance object G has

this meaning in [Fig.5], [Fig.6].

productoftoThree generations of the elementary

The relation ofparticle and the quark confinementtimeτ sin θ jAlso,

acceleration a j”.

I can explain that G relates to theboth is as follows.

are solved by elementary function fgravitational constant by accept that//w jτv j =a jτsinθj/////////// (13)(θj) that is a vector on 3-D space.

the curvature generates gravitation.

In

By the way, G is expressed thereverse of resistance Ω[V1A-1] on theelectromagnetism.

As described on

the <The creation of the electron>, theunit of the resistance is equal to unit
[m s ] with velocity. Therefore, the1 -1

key point is “ velocity v j” and “thethisresult,therelational

expressions of resistance object G are//Gj =1/wjτvj/////=1/ajτsinθj///////////// (14)I

getgravitational

approximatelybyconstantGNnumerical

calculation of (14) at two points of “j =1” and “j = n” [Sheet.3]. G 1 = 6.8246×-６-

For example, it is expressed as
F=/[f (θ1), f (θ2), f (θ3)]. As a result,
I got the light velocity and Planck’s
constantbycalculates

for

each

ingredient. The mass of elementary
particle is calculated in the same way.
It is the generation that threesolutions are gotten. In conclusion,aparticleof

eachgeneration

expresses each three form of some

The cause of the quark confinement

τ. In this result, |F| has minimum

elementary particle.

is existence in here.

value.

Also, I express

These

subjects

Certainly,

it

is

the

expressthegravitation. Unfortunately, I cannot

Properly, F has elevation Θ for eachinteraction in the same way.

For

realizeaxis, it is certification of a invariable

example,arebecause must take separated w andthe electron spin deal with vector F.

allinteractions

the interaction

on value

inclination angle that isexpressed by f (θj).

Θ=0.955316618 (cosΘ=(1/3)1/2)

unification of all interactions. If thelimitation of w and τ, get the newfor electron.

space were born in naught, |F| mustway.

In addition to it, I

Also, F is thecannot decompose absolute F.

be zero.

|F| =[ f (θ1)2+ f (θ2)2+ f (θ3)2]1/2///(15)curvature that has a limitation by w

1)

If

I

discoverthelogicalHowever, the space has

M. J. Duff/The Theory Formerly Known as Strings/Feb. 1998/Scientific American7)///////Leonard Susskind/Superstrings/Physics World, Vol.16, No.11, (2004)2)

τ .

Katuya Yamada/The Mechanism of the Photon with the Electron/Blue Backs, Kodansha, JPN.
(1999)G Veneziano/The Myth of the Beginning of Time/May 2004/Scientific American8)

Isao Imai/The Electromagnetic Unit Dimension System/Vol.72, No.1, KAGAKU, JPN. (2002)///////R. Bousso, J. Polchinski/The String Theory Landscape/Sep. 2004/Scientific American

9)

James C. Maxwell, Edinburgh U. K///////Yosihisa Kitazawa/Quantum-Gravity/Parity, Vol.19, No.10, JPN. (2004)

10)

Niels H. D. Bohr, Copenhagen Denmark///////Carlo Rovelli/Loop Quantum Gravity/Physics World, Vol.16, No.11, (2004)11)

Photo collection [Flow]/The Mechanics Society of Japan/Maruzen Co. Ltd./JPN.

////// Giovanni Amelino-Camelia/Quantum-Gravity Phenomenology/Physics World, Vol.16, No.11, (2004)///////Genki Yagawa/Study of the Flow science by PC/ BLUE BACKS/B-1337/Kodansha/JPN///////Special Issue/Brane World/Suuri Kagaku/Saiensu Co. No.487, January 2004, JPN

12)

3)

K. Simoda, K. Sakurai/The Base of Electronics/Syokabo Tokyo, JPN. (1986)///////Totsuka Yoji/Physics of the elementary particles/Modern Sciences/Iwanami Shoten

4)

J. D. Bekenstein/Information in the Holographic Universe/Aug. 2003/Scientific American

13)

M. J. G. Veltman/The Higgs Boson/Scientific American

L. D. Landau, E. M. Lifusit/Classical field theory/Curriculum of Theoretical Physics/Л. Д. Лан///////Thomas Banks/The Cosmological Constant Problem/Physics Today, Vol.57, No.3, (2004)дау и Е. М. Лифшиц/ТЕОРИЯ ПОЛЯ/Издание шестое, и

5)

N. Yamada, T. Kunieda/Laplace Transformation and Operational Calculus/CORONA, Pub. JPN.

справленное и дополненное, Издательство <Нау(1976)

ка>, Москва, 1973

6)

Shogo Niimi, http://www.fit-hp.com/-７-