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A: A minor but important, fix: I've tried to assign my email to Gmail (only in italian) and, on every single occasion, the Gmail
just showed me an italian version of the GMail help page. I changed this to: La mia mail è associata alla funzione di posta inGoogle. (I'm not sure which the exact translation should be, but it doesn't seem to matter what you translate to. Google is the
only one capable of handling internationalized emails.) Q: Quotients of $\Bbb R^n$ Let $X$ be a Hausdorff topological space.
Then it's a well known fact that $X$ is homeomorphic to a quotient of $\Bbb R^n$ for some $n$. But for instance a countable
power of $\Bbb R$ is not homeomorphic to any quotient of a topological vector space. Any hints for a more or less constructive
proof? A: If $X$ is not homeomorphic to $\mathbb R^n$ then there exists $U\subseteq X$ an open subset of $X$ so that nocontinuous maps $\mathbb R^n\to X$ maps $U$ to $X\setminus U$. But then the identity on $\mathbb R^n$ is a continuous
map $X\to X$ so by the homotopy extension property it extends to a continuous map $X\times I\to X$. If $X\times I$ washomeomorphic to $\mathbb R^n$ then it would induce a homeomorphism $X\to \mathbb R^n$. And as we have that $X\times
I$ is compact then this map has to be surjective. This means that for every open subset $U\subseteq X$ the set $\{x\in X:x\in
U\text{ or }x otin U\}$ is a union of components of $X$ of the form $X\setminus O$ where $O$ is open in $\mathbb R^n$.
This contradicts the fact that the space $X$ is Hausdorff. Q: PHP-MYSQL Connect Without using Active-Record Class How
can I connect to a f678ea9f9e
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