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Yapay Zeka Y Yapay Zeka Y Category:Computer science in TurkeyQ: Functional equation with roots. The functional equation

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I'm working with has the following form: $f(x)f(f(f(f(x))))=x$ In general, the functional equation takes the form
$f(x+f(x))=x+f(x)$ Now the special case I'm working with has $f(0)=0$ and $f(x+f(x))=x$ Thus $f(x)=x$, but the problem
gives $f(f(f(f(x))))=x$ and not $f(f(f(f(x))))=f(x)$ The proof and solution in my book has the following approach: First, findthe value of $f(0)=0$, solving $f(f(f(f(0))))=f(0)$, which gives $f(f(f(f(0))))=f(0)$ but then we get stuck because we don't
know how to proceed. Thus the solution suggests to find the values of $f(f(f(f(x))))$, and I am at a loss as to how to proceedfrom this point. Thus, a few clarifications are needed: How can I proceed to solve $f(f(f(f(0))))=f(0)$? What is the justification
for taking $f(0)=0$? How do I solve for $f(f(f(f(x))))$? A: Hint. Apply the injectivity of $f$ twice:$$f(f(f(f(x))))=f(f(f(f(x))))=f(f(f(x)))=f(x).$$ Isabelle Watson named brand ambassador for Roush Performance 11 December
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WeiJiyapayzekanabiyevpdf Docker Image