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Comments from an EVDL member
I'm forwarding these comments from an EVDL member:
 In the http://en.wikipedia.org/wiki/Image:WPEVStartRun.png image, the relay is called Ry RL, but down in the text it's referred to as Ry RS.

 Just a question:  in the first part of the article, it talks about how the car should operate like an ICE vehicle, requiring the key to be turned to the Start position.  But then later in the article, it talks about breaking people of the habit of the pressing the accelerator pedal.  Maybe I'm one of those operators of older vehicles talked about, but I still press the accelerator when I start my car, whether it's fuel-injected or not.  So it seems like in the same description, it's trying to make the car start like an ICE vehicle, and yet not make it start like an ICE vehicle.

 The rectangular area called In Cab confused me.  At first, I thought it was some special kind of component.  Then I came to think that, no, it's not a component at all; it just represents ""somewhere inside the cab.""  I think this latter view is the correct one, but I'd like text and/or picture to make it clearer.  I'm also not sure what the short blue wire between ""Run Buss"" and ""Run:"" is for.  My guess is that it's for other systems that are activated only when the ignition state has been latched, but the text doesn't make that clearand this also added to my confusion about the In Cab being a component.

 I don't know what this means:  ""The run buss is grounded when not in the run state, allowing additional interlocks to be included in order to ensure proper shutdown.""   Where would these additional interlock be placed?  How would they ensure proper shutdown? 

 Finally, I had to think about diode D1.  When the key switch is in the Start position and both relays are enabled, there will be 12V on each side of the diode.  Therefore the diode won't conduct, since one side isn't lower in voltage than the other.  When the key switch is then returned to the On position, the Alarm-Start Relay will open, removing the +12V on the negative side of the diode, so the diode will start conducting, thus keeping the Latch Relay energized.  Is that correct?  If so, maybe an explanation could be added to that effect for dummies like me.  If not, then perhaps add a description of the way it really works.

Thanks for your good work here (That's for YOU, not me).  Hope this helps. - Bill Dennis  "