# Challenger de Scheveningen 2015 (dobles masculino)

Sport 1 Open :
| Campeones: | Ariel Behar Eduardo Dischinger | Ariel Behar Eduardo Dischinger | Ariel Behar Eduardo Dischinger | Ariel Behar Eduardo Dischinger | Ariel Behar Eduardo Dischinger | Ariel Behar Eduardo Dischinger | Ariel Behar Eduardo Dischinger | Ariel Behar Eduardo Dischinger | Ariel Behar Eduardo Dischinger |
| Subcampeones: | Aslan Karatsev Andrey Kuznetsov | Aslan Karatsev Andrey Kuznetsov | Aslan Karatsev Andrey Kuznetsov | Aslan Karatsev Andrey Kuznetsov | Aslan Karatsev Andrey Kuznetsov | Aslan Karatsev Andrey Kuznetsov | Aslan Karatsev Andrey Kuznetsov | Aslan Karatsev Andrey Kuznetsov | Aslan Karatsev Andrey Kuznetsov |
| Resultado: | 0–0 retiro. | 0–0 retiro. | 0–0 retiro. | 0–0 retiro. | 0–0 retiro. | 0–0 retiro. | 0–0 retiro. | 0–0 retiro. | 0–0 retiro. |
| Modalidades |||||||||||
| Individuales | Masculino | | | |
| Dobles | Masculino | |

## Presentación previa

Matwé Middelkoop y Boy Westerhof eran ellos defensores del título, decidieron no participar este año.
Ariel Behar y Eduardo Dischinger ganaron el título tras derrotar en la final Aslan Karatsev y Andrey Kuznetsov.

## Cabeza de serie

| Sergio Galdós / Fabricio Neis (Cuartos de final) Adam Hubble / Alexandre Sidorenko (Semifinales) | Aslan Karatsev / Andrey Kuznetsov (Finalistas) Sander Arends / Niels Lootsma (Semifinales) |

## Cuadro

| Primera ronda | Primera ronda | Primera ronda | Primera ronda | Primera ronda | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Semifinales | Semifinales | Semifinales | Semifinales | | Final | Final | Final |
| | | | | | 1 | S Galdós Fabricio Neis | 6 | 3 | [9] | | | | |
| | | | | | | A Behar E Dischinger | 4 | 6 | [11] | | | | |
| | Stephan Fransen Peter Torebko | | | | | A Behar E Dischinger | 4 | 6 | [11] | | | | |
| | Ariel Behar Eduardo Dischinger | w/o | | | | | | | | | | | |
| | Ariel Behar Eduardo Dischinger | w/o | | | | | | | | | A Behar E Dischinger | 6 | 7 |
| | | | | | | | | | | 4 | S Arends N Lootsma | 3 | 5 |
| 4 | Sander Arends Niels Lootsma | 7$^7$ | 6 | | | | | | | | | | | 4 | S Arends N Lootsma | 3 | 5 |
| WC | Roy de Valk Scott Griekspoor | 6$^5$ | 4 | | | | | | | | | | |
| WC | Roy de Valk Scott Griekspoor | 6$^5$ | 4 | | 4 | S Arends N Lootsma | 6$^2$ | 6 | [13] | | | | |
| | | | | | | J Kovalík J Mertl | 7$^7$ | 4 | [11] | | | | |
| WC | Jesse Timmermans Tim van Terheijden | 3 | 2 | | | J Kovalík J Mertl | 7$^7$ | 4 | [11] | | | | |
| | Jozef Kovalík Jan Mertl | 6 | 6 | | | | | | | | | | |
| | Jozef Kovalík Jan Mertl | 6 | 6 | | | | | | | | | | | | | A Behar E Dischinger | 0 |
| | | | | | | | | | | | | | | | 3 | A Karatsev A Kuznetsov | 0$^r$ |
| | Sander Groen Greg Ouelette | 3 | 6 | [7] | | | | | | | | | | | | | | 3 | A Karatsev A Kuznetsov | 0$^r$ |
| | Nikoloz Basilashvili Romano Frantzen | 6 | 3 | [10] | | | | | | | | | |
| | Nikoloz Basilashvili Romano Frantzen | 6 | 3 | [10] | | N Basilashvili R Frantzen | 3 | 6 | [7] | | | | |
| | | | | | 3 | A Karatsev A Kuznetsov | 6 | 3 | [10] | | | | |
| | | | | | | | | | | 3 | A Karatsev A Kuznetsov | 6 | 6 |
| | | | | | | | | | | 2 | A Hubble A Sidorenko | 4 | 3 |
| | Sergiy Sergiienko Artem Smirnov | 5 | 3 | | | | | | | | | | | 2 | A Hubble A Sidorenko | 4 | 3 |
| WC | Jesse Huta Galung Robert Willekes MacDonald | 7 | 6 | | | | | | | | | | |
| WC | Jesse Huta Galung Robert Willekes MacDonald | 7 | 6 | | WC | J Huta Galung RW MacDonald | 3 | 4 | | | | | |
| | | | | | 2 | A Hubble A Sidorenko | 6 | 6 | | | | | |