# Challenger de Saint-Brieuc 2017 (dobles masculino)

Open Harmonie mutuelle :
| Campeones: | Andre Begemann Frederik Nielsen | Andre Begemann Frederik Nielsen | Andre Begemann Frederik Nielsen | Andre Begemann Frederik Nielsen | Andre Begemann Frederik Nielsen | Andre Begemann Frederik Nielsen | Andre Begemann Frederik Nielsen | Andre Begemann Frederik Nielsen | Andre Begemann Frederik Nielsen |
| Subcampeones: | David O'Hare Joe Salisbury | David O'Hare Joe Salisbury | David O'Hare Joe Salisbury | David O'Hare Joe Salisbury | David O'Hare Joe Salisbury | David O'Hare Joe Salisbury | David O'Hare Joe Salisbury | David O'Hare Joe Salisbury | David O'Hare Joe Salisbury |
| Resultado: | 6–3, 6–4 | 6–3, 6–4 | 6–3, 6–4 | 6–3, 6–4 | 6–3, 6–4 | 6–3, 6–4 | 6–3, 6–4 | 6–3, 6–4 | 6–3, 6–4 |
| Modalidades |||||||||||
| Individual | Masculino | | | |
| Dobles | Masculino | |
| 2016 « Challenger de Saint-Brieuc » 2018 |||||||||||

## Presentación previa

Rameez Junaid y Andreas Siljeström eran ellos defensores del título, Andreas Siljeström decidió no participar este año.
Andre Begemann y Frederik Nielsen ganaron el título tras derrotar en la final David O'Hare y Joe Salisbury.

## Cabeza de serie

| Antonio Šančić / Andrei Vasilevski (Semifinales) Ken Skupski / Neal Skupski (Cuartos de final) | Roman Jebavý / Igor Zelenay (Primera ronda) Andre Begemann / Frederik Nielsen (Campeones) |

## Cuadro

| Q = Clasificado/a (Qualifier) WC = Invitación (Wild Card) LL = Perdedor/a afortunado/a (Lucky Loser) Alt = Suplente (Alternate) | SE = Exención especial (Special Exempt) PR = Ranking protegido (Protected Ranking) s = Partido suspendido (Suspended) | r = Retirado/a (Retired) w/o = No presentación (Walkover) d = Descalificado/a (Defaulted) |
| Primera ronda | Primera ronda | Primera ronda | Primera ronda | Primera ronda | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Semifinales | Semifinales | Semifinales | Semifinales | Final | Final | Final | Final |
| 1 | Antonio Šančić Andrei Vasilevski | 6 | 6 | |
| WC | Maxime Authom Gleb Sakharov | 3 | 3 | |
| WC | Maxime Authom Gleb Sakharov | 3 | 3 | | 1 | A Šančić A Vasilevski | 7$^7$ | 2 | [10] |
| | | | | | | D Pel J Vliegen | 6$^5$ | 6 | [5] |
| | David Pel Joran Vliegen | 6$^4$ | 6 | [10] | | D Pel J Vliegen | 6$^5$ | 6 | [5] |
| Alt | Petr Michnev Rubén Ramírez Hidalgo | 7$^7$ | 4 | [8] | | | | | |
| Alt | Petr Michnev Rubén Ramírez Hidalgo | 7$^7$ | 4 | [8] | | | | | | 1 | A Šančić A Vasilevski | 4 | 3 |
| | | | | | | | | | | 4 | A Begemann F Nielsen | 6 | 6 |
| 4 | Andre Begemann Frederik Nielsen | 4 | 6 | [10] | | | | | | 4 | A Begemann F Nielsen | 6 | 6 |
| | Grégoire Jacq Hugo Nys | 6 | 3 | [6] | | | | | | | | | |
| | Grégoire Jacq Hugo Nys | 6 | 3 | [6] | 4 | A Begemann F Nielsen | w/o | | | | | | |
| | | | | | WC | E Couacaud Q Halys | | | | | | | |
| | Alexander Kudryavtsev Aldin Šetkić | 2 | 1 | | WC | E Couacaud Q Halys | | | | | | | |
| WC | Enzo Couacaud Quentin Halys | 6 | 6 | | | | | | | | | | |
| WC | Enzo Couacaud Quentin Halys | 6 | 6 | | | | | | | | | | | 4 | A Begemann F Nielsen | 6 | 6 |
| | | | | | | | | | | | | | | | D O'Hare J Salisbury | 3 | 4 |
| | Marin Draganja Tomislav Draganja | 7$^9$ | 4 | [6] | | | | | | | | | | | D O'Hare J Salisbury | 3 | 4 |
| | Oscar Otte Franko Škugor | 6$^7$ | 6 | [10] | | | | | | | | | |
| | Oscar Otte Franko Škugor | 6$^7$ | 6 | [10] | | O Otte F Škugor | 7$^7$ | 6 | | | | | |
| | | | | | | L Lacko S Stakhovsky | 6$^5$ | 1 | | | | | |
| | Lukáš Lacko Sergiy Stakhovsky | 6 | 4 | [10] | | L Lacko S Stakhovsky | 6$^5$ | 1 | | | | | |
| 3 | Roman Jebavý Igor Zelenay | 4 | 6 | [5] | | | | | | | | | |
| 3 | Roman Jebavý Igor Zelenay | 4 | 6 | [5] | | | | | | | O Otte F Škugor | 2 | 3 |
| | | | | | | | | | | | D O'Hare J Salisbury | 6 | 6 |
| WC | Rémi Boutillier Evan Furness | 4 | 5 | | | | | | | | D O'Hare J Salisbury | 6 | 6 |
| | David O'Hare Joe Salisbury | 6 | 7 | | | | | | |
| | David O'Hare Joe Salisbury | 6 | 7 | | | D O'Hare J Salisbury | 6 | 6 | |
| | | | | | 2 | K Skupski N Skupski | 3 | 3 | |
| | Marco Chiudinelli Julian Knowle | 6 | 4 | [4] | 2 | K Skupski N Skupski | 3 | 3 | |
| 2 | Ken Skupski Neal Skupski | 3 | 6 | [10] |