OpenLLM-France/wikimedia huggingface dataset:
# Snapshot journal/review policy
## Snapshot journal review policy

Contributions to Snapshot will be selected only from work submitted for assessment in a subject that has elected to incorporate the journal into its curriculum. Unsolicited submissions to Snapshot will only be accepted if they meet the criteria listed below and follow the unsolicited submission process. The explicit aim of the journal is to showcase work produced by La Trobe students during their studies.
All manuscripts submitted to Snapshot are vetted by the lecturer(s) who volunteer(s) as editor(s) for an issue of the journal. As editors, lecturers are expected to adhere to three key criteria in consultation with the journal editor:
* relevance to the theme of the journal issue;
* achievement of the assessment criteria - as outlined when the assessment task was set - to the standard of C grade or above;
* appropriateness of the work as an exemplar of the standard of undergraduate student work at La Trobe University, including mid-range as well as high-quality work;
* the original perspective that represents the diversity of student voices at La Trobe University.
The lecturer/editor will make recommendations to publish, rather than an anomymous reviewer. Submissions that meet these criteria but require additional work to improve the standard of writing will be referred to language consultants to ensure a minimum standard of content, structure and style.
Peer review within a subject's cohort will be undertaken at the discretion of the lecturer/section editor. This decision will be based on pedagogical appropriateness within the subject.

## Snapshot journal review guidelines

All contributions to Snapshot will be considered for publication by the section editor or the journal publisher in accordance with the review policy.
Lecturers shall nominate themselves and their subject for inclusion in the journal, and by doing so agree to the review policy outlined above. By agreeing to be involved in the journal, lecturers agree to take on the role of section editor with full responsibilites for curating the issue. Section editors must select a range of work from what has been presented for assessment by their students. The selection must contain C-graded work as well as B-graded and A-graded work. The selection process must adhere to the ethos of the journal in representing the voice of a diverse range of La Trobe University students, including students from regional campuses (where the subject is delivered into multuple campuses).
Section editors may request minor revisions to be made (by the student) to a student's work prior to publication. Subject editors may also refer students to Student Learning officers if assistance is required for development of a work prior to publication.
# Snapshot journal/cover art

Cover art for Snapshot journal
Cover photographs used on the first two editions of Snapshot were submitted by La Trobe University photojournalism students/graduates.

## Submitting cover artwork for consideration

La Trobe University students may submit artwork for consideration for use on covers of the journal.

### Requirements

Artwork must be submitted in JPG or GIF format, in medium-to-high resolution (minimum 400 x 600px). Contributors must agree to publish their work under a Creative Commons Attribution 4.0 licence or Creative Commons Attribution No-Derivatives 4.0 licence. Contributors will be asked to agree to these conditions during the submission process (see below). Read more about the Snapshot journal submission terms and conditions.
Artwork can be published in either landscape or portrait format.

### Submission process

Cover artwork contributors should follow submission procedures for authors.
* Register as an author
* Upload work (in JPG or GIF format), under Cover Art section
Once registered and logged in, read through the submission checklist and copyright notice thoroughly before agreeing to the terms and conditions.

### Selection policy

Cover art will be selected according to its relevance to the theme of any given edition of the journal. If selected for publication, student artists will be expected to apply the Snapshot cover template (Photoshop) to their work. Read more about Snapshot selection policies.
# Snapshot journal/participating subjects 2014
## Subjects participating in the Snapshot journal project in 2014

* SOC2UYC/SOC3UYC Understanding Youth (Bendigo); lecturer Paulina Billett
* ENG2ALT/ENG3ALT American Literature (multi-campus); lecturer Sofia Ahlberg
# Snapshot journal/copyediting instructions
## Copyediting instructions for Snapshot journal
### The purpose of copyediting

The copyediting stage is intended to improve the flow, clarity, grammar, wording, and formatting of the article. It represents the last chance for the author to make any substantial changes to the text, as the next stage is restricted to correcting typos and formatting. Copyediting for Snapshot journal should be non-interventionist: try as much as possible to preserve the author's voice. Changes should only be made where greater clarity is needed for the reader. Changes should not be made according to personal preference.

### How to go about copyediting

The file to be copyedited is in Word or .rtf format and therefore can be easily edited as a word processing document. Copyeditors should make all changes using Track Changes feature of Microsoft Word (see below). This ensures that all changes are highlighted and trace-able. Track Changes enables the copyeditor to make insertions (new text appears in colour) and deletions (text appears crossed out in colour or in the margins as deleted). The copyeditor can post queries to both the author (Author Queries) by inserting these queries in square brackets, or by using the Comments function.

#### How to use Track Changes

Microsoft Word's Track Changes is found under Tools in the menu bar. Once Track Changes is turned on, keep typing as per normal - you don't need to do anything else to highlight your changes. If you cannot see a trace of the changes you are making, ensure you select "view final showing changes" under preferences. To view the document with all the changes incorporated, select "show final".

### Once copyediting is finished

The copyedited version is uploaded to OJS and the editor is notified. The editor then reviews the text and notifies the author. The editor should leave those changes with which they are satisfied - do not 'accept' changes at this stage. Authors can "accept" the changes they are satisfied with. If further changes are necessary after copyediting, the editor and author can make changes to the initial insertions or deletions, as well as make new insertions or deletions elsewhere in the text.
Authors and editors should respond to each of the queries addressed to them, by adding responses to the same comment box. After the text has been reviewed by editor and author, the copyeditor will make a final pass over the text accepting the changes in preparation for the layout and galley stage.
# Snapshot journal/layout instructions

Snapshot journal layout instructions
Once the editing process is complete, the files must be prepared for publication. For Snapshot, the 'layout' stage involves formatting the file in the Snapshot template ready for publication.

## About the template

The template has been designed with set styles. All work published in Snapshot should be formatted following the instructions in the template file.

## Layout and preparation of final files

Once work is set in the Snapshot template, it should be proofread by the author and the editor, to check for typographical errors (typos) and other formatting errors.
Files should be saved in three formats for publication: Word doc (doc or docx file extension), HTML (Unicode UTF-8 encoding) and PDF. All these file formats can be produced using Microsoft Word 'Save As' function (Mac users must use the Print function to save as PDF).
More information on layout process to come.
# Stereoscopy/Create a WebApp
## Introduction

In this learning resource we will create a Stereoscopy AppLSAC that is able to create a stereoscopic image from two single images for left and right eye.

## Major Steps

* Load two images with FileReader into the browser and store the images into a canvas for the left and the right eye.
* allow image alignment via drag and drop on a canvas with a transparent view (overlay) for the left and right image.
* generate after alignment a stereoscopic image for the left and right eye.
* generate after alignment also a anaglyph 3D image for the left and right eye
* create a save button for anaglyph and stereoscopy image.
# Stereoscopy/Geometry

This learning resource addresses the application of stereoscopy in geometry lessons. The learning resource is based on the Open Community Approach.

## Learning Activities

* Install the Open Source software Geogebra and analyze the perspective drawings of projections on a mirror.
* Stereoscopy is based on the concept that the left and right eye perceive slightly different images of an object.
** These differences allow the brain to perceive the 3D space. Anaglyph images address that with a red and green filter for both eyes red colors are more or less hidden for the eye and the green filter hides green colors.
** green colors are visible with the red filter and vice versa red colors are visible the eye that is covered with green filter (remark the green filter could be replaced by cyan filter)
* (3D Cube Anaglyph - Red-Green Glasses - Animation) Analyze the anaglyph projections of cube in Geogebra. Wear the red-green glasses (or red-cyan glasses) to perceive the 3D projection of the cube. Look at the image and decide prior to wearing the red-green glasses if the red filter should be placed on the right eye or on the left eye. Look at object in different distances in front of you and close once the left eye and short time later only the right eye. Explain how objects move horizontally.
# Stereoscopy/Positioning of Images for Eyes
## Introduction

This page about Stereoscopy/Positioning of Images for Eyes can be displayed as Wiki2Reveal slides. Single sections are regarded as slides and modifications on the slides will immediately affect the content of the slides. The following aspects of Stereoscopy/Positioning of Images for Eyes are considered in detail:
* (1) Translation and Rotation of left/right eye image
* (2) mathematical background of transformations
* (3) application on examples of left and right images.

## Objective

This learning resource about Stereoscopy and the positioning of left and right eye images to eachother, in case of source images that are not created with two cameras mounted on a tripod with eye distance.

## Target Group

The target groups for Stereoscopy/Positioning of Images for Eyes of the learning resource are:
* Bachelor/Master students with the subject Mathematics
* Learners that want to create a stereoscopy image with a standard smartphone without any additional equiment.

### Left-Right Eye Image Alignment

The following image show the positioning of the right eye image with a transparent view over the left eye image.
What is the objective for the image alignment?

## Learning Tasks / Activities

Assume you take two images one after the other with one camera shifting the camera two right with eye distance while keeping the object of interest in the center of the camera.
* Explain, why a translation might be required for the second source image to have correct alignment between the images.
* Explain, why a rotation might be required for the second source image to have correct alignment between the images in the stereocopic view.
* How can a translation and rotation be represented and defined with a mathematical function?
# Step by step chopstick semi-automatic rubber band gun tutorial

step by step tutorial on how to make a chopstick rubber band gun:
Step by step process of making the chopstick rubber band gun:
(Please click on the pictures for a more detailed explanation as to creating and assembling the chopstick rubber band gun as well as high resolution pictures)
When done with the chopstick rubber band gun, in order to reload it you must pull a rubber band from the front muzzle of the gun back towards the trigger. While keeping the trigger pulled back at a 90 degree angle with the rest of the gun put the rubber band around the trigger, then proceed to wrap it under the left side of the unburst bar and then around the back handle of the rubber band gun and then finally hook the rubber band onto the trigger. Repeat this 3 more times alternating sides for wrapping underneath the unburst bar and then for the 5th rubber band just simply pull it back from the muzzle and then hook it on to the trigger simply. This mechanism will prevent all the rubber bands from firing at once and will also help to make the gun semi automatic. Have fun with it, try to hit your cat or sibling with it if you can (Don't aim for the face) :P
# Stereotype

This psychology resource is a "stub". Learn how you can help Wikiversity to develop it.
* Please help develop and classify this resource
* Learn how you can develop this resource to teach participants about Stereotype. Choose a subject, education level, and resource type to classify the resource by. You may learn more about the topic to help you develop and classify the resource from:
# UTPA STEM/CBI Courses Organized by STEM Category/Engineering and Computer Science/Civil Engineering

Courses
Design of Steel Structures
Dynamics
Engineering Materials
Graphics (Computer Aided Design)
Statics
Graphics
# UTPA STEM/CBI Courses Organized by STEM Category/Engineering and Computer Science/Civil Engineering/Soil Mechanics

Topics
(Reconstruction)
# UTPA STEM/CBI Courses Organized by STEM Category/Engineering and Computer Science

Fields
Courses
Fundamentals of Product Design
# UTPA STEM/CBI Courses Organized by STEM Category/Engineering and Computer Science/Biomedical Engineering

Topics
Emergency Response Robot
# UTPA STEM/CBI Courses Organized by STEM Category/Engineering and Computer Science/Computer Engineering

Courses
Computer Networks
Computer Science
Databases
Data Structures and Algorithms
Digital Systems
Introduction to VLSI
Microprocessor Systems
# University of Florida/Egm4313/s12.team11.perez.gp

Please visit User:Egm4313.s12.team11.perez.gp instead of this account.

## Team Homepage

Team 11

## Report 1 Problems

R1.4

## Report 2 Problems

R2.3

## Report 3 Problems

R3.2
R3.9

## Report 4 Problems

R4.1

## Report 5 Problems

Outdated R5.9
# University of Florida/Egm4313/s12.team11.imponenti/R2.9
## Report 2, Problem 9
### Problem Statement

Find and plot the solution for the L2-ODE-CC corresponding to
$\lambda ^{2}+4\lambda +13\!$
with $r(x)=0\!$
and initial conditions $y(0)=1\!$, $y'(0)=0\!$
In another figure, superimpose 3 figs.:(a)this fig. (b) the fig. in R2.6 p.5-6, and (c) the fig. in R2.1 p.3-7

### Quadratic Equation

$\lambda ={\frac {-b\pm {\sqrt {}b^{2}-4ac)}{2a}}\!$ with $a=1,b=4,c=13\!$
$\lambda ={\frac {-4\pm {\sqrt {}4^{2}-4*1*13)}{2*1}}=-2\pm 3i\!$
$\lambda =-2\pm 3i\!$

### Homogeneous Solution

The solution to a L2-ODE-CC with two complex roots is given by
$y(x)=e^{-{\frac {a}{2}}x}[Acos(\omega x)+Bsin(\omega x)]\!$
where $\lambda =-{\frac {a}{2}}\pm \omega i=-2\pm 3i\!$
$y(x)=e^{-2x}[Acos(3x)+Bsin(3x)]\!$

### Solving for A and B

first initial condition $y(0)=1\!$
$y(x)=e^{-2x}[Acos(3x)+Bsin(3x)]\!$
$y(0)=e^{-2*0}[Acos(3*0)+Bsin(3*0)]=1\!$
$A=1\!$
second initial condition $y'(0)=0\!$
$y'(x)={\frac {d}{dx}}y(x)={\frac {d}{dx}}e^{-2x}[cos(3x)+Bsin(3x)]\!$
$y'(x)=e^{-2x}[(-2B-3)sin(3x)+(3B-2)cos(3x)]\!$
$y'(0)=e^{-2*0}[(-2B-3)sin(3*0)+(3B-2)cos(3*0)]\!$
$0=3B-2\!$
$B={\frac {2}{3}}\!$
so the solution to our L2-ODE-CC is

### Solution to R2.6

After solving for the constants ${\frac {k}{c}}$ and ${\frac {k}{m}}$ we have the following homogeneous equation
$y''(x)+6y'(x)+9y=0\!$

#### Characteristic Equation and Roots

$\lambda ^{2}+6\lambda +9=0\!$
$(\lambda +3)(\lambda +3)=0\!$
We have a real double root $\lambda =-3\!$

#### Homogeneous Solution

We know the homogeneous solution to a L2-ODE-CC with a double real root to be
$y(x)=c_{1}e^{\lambda x}+c_{2}xe^{\lambda x}\!$
Assuming object starts from rest
$y(0)=1\!$, $y'(0)=0\!$
Plugging in $\lambda$ and applying our first initial condition
$y(0)=c_{1}e^{-3*0}+c_{2}*0*e^{-3*0}=1\!$
$c_{1}=1\!$
Taking the derivative and applying our second condition
$y'(x)={\frac {d}{dx}}y(x)={\frac {d}{dx}}e^{-3x}+c_{2}xe^{-3x}\!$
$y'(x)=-3e^{-3x}+c_{2}e^{-3x}-3c_{2}xe^{-3x}\!$
$y'(0)=-3e^{-3*0}+c_{2}e^{-3*0}-3c_{2}*0*e^{-3*0}=0\!$
$c_{2}=3\!$
Giving us the final solution

### Plots
#### Solution to this Equation

$y(x)=e^{-2x}[cos(3x)+{\frac {2}{3}}sin(3x)]\!$

#### Superimposed Graph

Our solution: $y(x)=e^{-2x}[cos(3x)+{\frac {2}{3}}sin(3x)]\!$ shown in blue
Equation for fig. in R2.1 p.3-7: $y(x)={\frac {5}{4}}e^{-2x}-{\frac {1}{4}}e^{5x}\!$ shown in red
Equation for fig. in R2.6 p.5-6:$y(x)=e^{-3x}+3xe^{-3x}\!$ shown in green
Egm4313.s12.team11.imponenti 03:38, 8 February 2012 (UTC)
# University of Florida/Egm4313/s12.team11.imponenti/R7.3
## R7.3
#### Problem Statement

Find (a) the scalar product, (b) the magnitude of $f\!$ and $g\!$ ,(c) the angle between $f\!$ and $g\!$ for:
1) $f(x)=cos(x),\ g(x)=x\ for-2\leq x\leq 10\!$
2) $f(x)={\frac {1}{2}}(3x^{2}-1),\ g(x)={\frac {1}{2}}(5x^{3}-3x)\ for-1\leq x\leq 1\!$

#### Part 2

solved by Luca Imponenti

##### Scalar Product

$<f,g>=\int _{a}^{b}f(x)g(x)\ dx\!$
$<f,g>=\int _{-1}^{1}[{\frac {1}{2}}(3x^{2}-1)][{\frac {1}{2}}(5x^{3}-3x)]\ dx\!$
          $=\int _{-1}^{1}{\frac {1}{4}}(15x^{5}-4x^{3}+3x)\ dx\!$
          $=\left.{\frac {1}{4}}({\frac {15}{6}}x^{6}-x^{4}+{\frac {3}{2}}x^{2})\right|_{-1}^{1}\!$
          $={\frac {1}{4}}[({\frac {15}{6}}1^{6}-1^{4}+{\frac {3}{2}}1^{2})-({\frac {15}{6}}(-1)^{6}-(-1)^{4}+{\frac {3}{2}}(-1)^{2})]\!$
Since all exponents are even, everything in brackets cancels out

##### Magnitude

$\|f\|=<f,f>^{1/2}=\int _{a}^{b}f^{2}(x)\ dx\!$
       $=\int _{-1}^{1}[{\frac {1}{2}}(3x^{2}-1)]^{2}\ dx\!$
       $=\int _{-1}^{1}{\frac {1}{4}}(9x^{4}-6x^{2}+1)\ dx\!$
       $=\left.{\frac {1}{4}}({\frac {9}{5}}x^{5}-2x^{3}+x)\right|_{-1}^{1}\!$
       $={\frac {1}{4}}[({\frac {9}{5}}1^{5}-2(1)^{3}+1)-({\frac {9}{5}}(-1)^{5}-2(-1)^{3}+(-1))]\!$
       $={\frac {1}{4}}[{\frac {4}{5}}-(-{\frac {4}{5}})]\!$
$\|g\|=\int _{a}^{b}g^{2}(x)\ dx\!$
       $=\int _{-1}^{1}[{\frac {1}{2}}(5x^{3}-3x)]^{2}\ dx\!$
       $=\int _{-1}^{1}{\frac {1}{4}}(25x^{6}-30x^{4}+9x^{2})\ dx\!$
       $=\left.{\frac {1}{4}}({\frac {25}{7}}x^{7}-6x^{5}+3x^{3})\right|_{-1}^{1}\!$
       $={\frac {1}{4}}[({\frac {25}{7}}1^{7}-6(1)^{5}+3(1)^{3})-({\frac {25}{7}}(-1)^{7}-6(-1)^{5}+3(-1)^{3})]\!$
       $={\frac {1}{4}}[{\frac {4}{7}}-(-{\frac {4}{7}})]\!$

##### Angle Between Functions

$cos(\theta )={\frac {<f,g>}{\|f\|\|g\|}}\!$
Since $<f,g>=0\!$ the two functions are orthogonal
# University of Florida/Egm4313/s12.team11.imponenti/R2.2
## Report 2, Problem 2
### Problem Statement

Find and plot the solution for the homogeneous L2-ODE-CC
    $y''(x)-10y'(x)+25y(x)=0\!$
with initial conditions $y(0)=1\!$ ,and $y'(0)=0\!$

### Characteristic Equation

$\lambda ^{2}-10\lambda +25=0\!$
$(\lambda -5)(\lambda -5)=0\!$
$\lambda =5\!$

### Homogeneous Solution

The solution to a L2-ODE-CC with real double root is given by
$y(x)=c_{1}e^{\lambda x}+c_{2}xe^{\lambda x}\!$
First initial condition
$y(0)=1\!$
$y(0)=c_{1}e^{5*0}+c_{2}*0*e^{5*0}=1\!$
$c_{1}=1\!$
Second initial condition
$y'(0)=0\!$
${\frac {d}{dx}}y(x)=y'(x)=5e^{5x}+c_{2}e^{5x}(5x+1)\!$
$y'(0)=5e^{5*0}+c_{2}e^{5*0}(5*0+1)=0\!$
$5+c_{2}=0\!$
$c_{2}=-5\!$
The solution to our L2-ODE-CC is

### Plot

$y(x)=e^{5x}(1-5x)\!$
Egm4313.s12.team11.imponenti 00:30, 8 February 2012 (UTC)
# University of Florida/Egm4313/s12.team11.imponenti/R5.5
## R5.6

solved by Luca Imponenti

#### Problem Statement

Complete the solution to the following problem
       $y''+4y'+13y=2e^{-2x}cos(3x)\!$
where
$y_{h}=e^{-2x}[Acos(3x)+Bsin(3x)]\!$
and
$y_{p}=xe^{-2x}[Mcos(3x)+Nsin(3x)]\!$
Find the overall solution $y(x)\!$ corresponds to the initial condition:
          $y(0)=1\ ,\ y'(0)=0\!$
       Plot the solution over 3 periods.
Taking the derivatives of the particular solution $y_{p}(x)\!$

#### Particular Solution

$y_{p}=xe^{-2x}[Mcos(3x)+Nsin(3x)]\!$
$y'_{p}=e^{-2x}[sin(3x)(N-2Nx-3Mx)+cos(3x)(3Nx+M-2Mx)]\!$
$y''_{p}=e^{-2x}[sin(3x)(12Mx-6M-5Nx-4N)+cos(3x)(6N-5Mx-4M-12Nx)]\!$
Plugging these into the ODE yields
$sin(3x)(6M-12Mx+5Nx+4N)+cos(3x)(5Mx+4M+12Nx-6N)+\!$ $4[sin(3x)(N-2Nx-3Mx)+cos(3x)(3Nx+M-2Mx)]+$ $13x[Mcos(3x)+Nsin(3x)]=2cos(3x)\!$
Equating like terms allows us to solve for M and N
$sin(3x)[(12Mx-6M-5Nx-4N)+4(N-2Nx-3Mx)+13Nx]=0\!$
$cos(3x)[(6N-5Mx-4M-12Nx)+4(3Nx+M-2Mx)+13Mx]=2cos(3x)\!$
$-6M=0\!$
$6N=2\!$
$M=0\ ,\ N={\frac {1}{3}}\!$
So the particular solution is
$y_{p}={\frac {1}{3}}xe^{-2x}sin(3x)\!$

#### Overall Solution

The overall solution in the sum of the homogeneous and particular solutions
$y(x)=y_{h}(x)+y_{p}(x)\!$
$y(x)=e^{-2x}[Acos(3x)+Bsin(3x)]+{\frac {1}{3}}xe^{-2x}sin(3x)\!$
To find A and B we apply the initial conditions
$y(0)=1\ ,\ y'(0)=0\!$
$y(0)=1=A\!$
Taking the derivative
$y'(x)={\frac {d}{dx}}[e^{-2x}[cos(3x)+Bsin(3x)]+{\frac {1}{3}}xe^{-2x}sin(3x)]\!$
$y'(x)=e^{-2x}[(3B+x-2)cos(3x)-(2B+{\frac {2}{3}}x+{\frac {8}{3}})sin(3x)]\!$
$y'(0)=0=3B-2\!$
$B={\frac {2}{3}}\!$
Giving us the overall solution

#### Plot

The period for $cos(3x)\ ,\ sin(3x)\!$ is ${\frac {2\pi }{3}}$
Plotting the solution $y(x)\!$ over 3 periods yields
Egm4313.s12.team11.imponenti (talk) 01:56, 30 March 2012 (UTC)
# University of Florida/Egm4313/s12.team11.imponenti/reports
#### Report 1

R1.3

#### Report 2

R2.2
R2.9

#### Report 3

R3.1
R3.8

#### Report 4

R4.4

#### Report 5

R5.5

#### Report 6

R6.4

#### Report 7

R7.3
# Volcanoes, list

List of volcanoes.

## Ring of fire

* Krakatau - Indonesia
* Papandayan - Indonesia
* MountTambora - Indonesia
* Nevado del Ruiz (La Mesa de Herveo) - Columbia
* Hibok-Hibok - Philippines
* Pinatubo - Philippines
* El Chichon - Mexico
* Mount Cotopaxi - Mexico
* Mount Unzen - Japan
* Asama - Japan
* Oshima - Japan
* Komagatake - Japan

## Atlantic

* Laki - Iceland
* Mount Pelee - Martineque

## Mediterranean

* Mount Vesuvius - Italy
# Volcanoes, list/Komagatake

Komagatake, Japan 1640