# Joint Entrance Examination/2000 Screening/Q009 Magnetic field ratios in two different cases

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| Original Question by Dharav Here's the question... An infinitely long conductor PQR is bent to form a right angle as shown. A current I flows through PQR. The magnetic field due to this current at the point M is H1. Now, another infinitely long straight conductor QS is connected to Q so that the current is I/2 in QR as well as in QS, the current in PQ remaining unchanged. The magnetic field at M is now H2 . The ratio H1/H2 is given by... (A) 1/2 (B) 1 (C) 2/3 (D) 2 Posted by Dharav 04:23, 18 August 2009 (UTC) | What's Up? Latest discussions on the forum Electricity-And-Magnetism-Help Joint Entrance Examination/2000 Screening/Q009 Magnetic field ratios in two different cases Joint Entrance Examination/2000 Screening/Q017 Electrostats - energy of a configuration Joint Entrance Examination/2000 Screening/Q023 capcitors and dielectric, equivalent capcitance Joint Entrance Examination/2000 Screening/Q031 Magnetic fields of parallel wires Joint Entrance Examination/AIEEE 2009/Q084 work done by electrostatic field Physics-Help User:Thewinster/Sandbox/Forum-Watch User:Thewinster/Sandbox Joint Entrance Examination/2000 Screening/Q001 X Ray Tungsten filament and electrons Joint Entrance Examination/2000 Screening/Q010 Intensity versus wavelength graphs of blackbodies Joint Entrance Examination/2000 Screening/Q033 Glass slab in water and total internal reflection |
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