OpenLLM-France/wikimedia huggingface dataset:
# Wikiphilosophers/Meaning of life

The meaning of life pertains to the inherent significance or philosophical meaning of living (or existence in general). Does life have meaning? Or is life meaningless? Do we determine our own goals or are they determined for us?
Read users' philosophical views below.
* S. Perquin suggests that the purpose of life is created by universal consciousness, which deliberately attaches itself to the living body and influences its formation, indicating a purposeful existence orchestrated by this consciousness. Read more...
* Tropwine concludes that since life is simply a self-replicating series of chemical reactions, life's meaning lies in the nature of how these chemical reactions even occur or, in other words, how the universe itself is structured. Read more...
* User:Jaredscribe holds with Aristotle that "Nature does everything for a purpose / goal / end / w:Telos, and that an account of the final causes must be given, along with material, formal, and efficient causes, for an analysis of nature to be adequate. The purpose (not merely the function) of a leaf is to absorb sunlight and photosynthesize chemical energy. The purpose of an eye is to see, an ear to hear, a heart to pump blood, a stomach to absorb and digest food into chemical energy. These purposes are determined by our animal nature. Our unique brain's purpose is conceptual and moral reasoning, whereby we can cultivate intellectual and moral virtues, and exercise free will. Training humans to become free, is the purpose of the "liberal arts" education. I hold with w:Robert Solomon that those who claim "life is absurd" are blaming the universe for the absurdity of their own lives, and denying moral and intellectual responsibility for having chosen the wrong goals and having pursuing meaningless pleasures.
* Toby Lightheart posits that life creates all natural meaning and, therefore, has the ultimate significance in an otherwise meaningless universe. The purpose of life, individually and collectively, is to sustain and create more meaningful interactions, objects and life. This answer is a product of decomposing the question "what is the meaning of life?" and developing a new understanding of what "life" is. Read more...
# Group theory/Cyclic group/Definition

A group $G$ is called cyclic if it is generated by one element.
# Subgroups of Z/One generator/Fact

$\mathbb {Z}$
The subgroups of $\mathbb {Z}$ are precisely
    $\mathbb {Z} d={\left\{kd\mid k\in \mathbb {Z} \right\}}\,$
$d$
# Subgroups of Z/One generator/Fact/Proof

A subset of the form $\mathbb {Z} d$ is a subgroup due to the distributive law. Let now $H\subseteq \mathbb {Z}$ be a subgroup. In case $H=0$, we can take $d=0$. Hence, we may assume that $H$ contains beside $0$ another element $x$. If $x$ id negative, then subgroup $H$ must contain its negative $-x$, , which is positive. This means that $H$ contains also a positive number. Let $d$ denote the smallest positive number in $H$. We claim $H=\mathbb {Z} d$. Here, the inclusion $\mathbb {Z} d\subseteq H$ is clear, as all (positive and negative) multiples of $d$ must belong to the subgroup. To show the inverse inclusion, let $h\in H$ be arbitrary. Due to the division with remainder, we have
    $h=qd+r{\text{ with }}0\leq r<d.$
Because of $h\in H$ and $qd\in H$, also $r=h-qd\in H$ holds. Because of the choice of $d$ and $r<d$, we must have $r=0$. This means $h=qd$. Therefore $h\in \mathbb {Z} d$, thus $H\subseteq \mathbb {Z} d$.
# Z modulo n/Representatives/Associativity and group/Cyclic/Example

Let $n\in \mathbb {N} _{+}$, and consider on
    $\mathbb {Z} /(n)=\{0,1,\ldots ,n-1\}\,$
the binary operation
    $a+b:=(a+b)\mod n={\begin{cases}a+b,{\text{ if }}a+b<n\,,\\a+b-n,{\text{ if }}a+b\geq n\,.\end{cases}}\,$
With this operation, we have a group due to exercise. Because we can write every element as a certain sum of $1$ with itself, this is a cyclic group.
# Group homomorphism/R to C/e^it/Kernel and image/Example

We consider the analytic mapping
    $\mathbb {R} \longrightarrow \mathbb {C} ,t\longmapsto e^{{\mathrm {i} }t}=\cos t+{\mathrm {i} }\sin t.$
Due to the exponential law (or the addition theorems for the trigonometric functions), we have $e^{{\mathrm {i} }(t+s)}=e^{{\mathrm {i} }t}e^{{\mathrm {i} }s}$. Therefore, this is a group homomorphism from the additive group $(\mathbb {R} ,+,0)$ into the multiplicative group $([[:Template:Op:Unitgroup]],\cdot ,1)$. We determine the kernel and the image of this mapping. To determine the kernel, we must identify those real numbers $t$ fulfilling
    $\cos t=1\,\,{\text{ and }}\,\,\sin t=0.$
Because of the periodicity of the trigonometric functions, this is the case if and only if $t$ is an integer multiple of $2\pi$. Hence, the kernel is the subgroup $2\pi \mathbb {Z}$. For a point in the image, we have $\vert {e^{{\mathrm {i} }t}}\vert =\sin ^{2}t+\cos ^{2}t=1$; therefore, the image point belongs to the complex unit circle. The trigonometric functions run through the complete unit circle, so that the image group is the complex unit circle with its complex multiplication.
# Group homomorphism/Image/Subgroup/Fact

Let $G$ and $H$ denote groups, and let $\varphi \colon G\rightarrow H$ be a group homomorphism.
image of $\varphi$ is a subgroup
$H$
# Group homomorphism/Image/Subgroup/Fact/Proof

Let $B:=\operatorname {Im} \varphi$. We have $e_{H}=\varphi (e_{G})\in B$. Let $h_{1},h_{2}\in B$. Then there exist $g_{1},g_{2}\in G$ such that $\varphi (g_{1})=h_{1}$ and $\varphi (g_{2})=h_{2}$. Therefore, $h_{1}\cdot h_{2}=\varphi (g_{1})\cdot \varphi (g_{2})=\varphi (g_{1}\cdot g_{2})\in B$. Similarly, for $h\in B$ there exists a $g\in G$ fulfilling $\varphi (g)=h$. Hence, $h^{-1}=(\varphi (g))^{-1}=\varphi (g^{-1})\in B$.
# Group homomorphism/Introduction/Section
## Definition

Let $(G,\circ ,e_{G})$ and $(H,\circ ,e_{H})$ denote groups. A mapping
    $\psi \colon G\longrightarrow H$
is called group homomorphism, if the equality
    $\psi (g\circ g')=\psi (g)\circ \psi (g')\,$
holds for all
$g,g'\in G$
The set of all group homomorphisms from $G$ to $H$ is denoted by
    $\operatorname {Hom} _{\left(G,H\right)}.$
Linear mappings between vector spaces are in particular group homomorphisms. The following two lemmas follow directly from the definition.

## Lemma
### Proof

$\Box$

## Lemma
### Proof

$\Box$

## Lemma
### Proof

$\Box$
This lemma can be stated quickly by saying $G\cong \operatorname {Hom} _{\left(\mathbb {Z} ,G\right)}$. It is more difficult to characterize the group homomorphisms from a group $G$ to $\mathbb {Z}$. The group homomorphisms from $\mathbb {Z}$ to $\mathbb {Z}$ are just the multiplications with a fixed integer number $a$, that is,
    $\mathbb {Z} \longrightarrow \mathbb {Z} ,x\longmapsto ax.$
# Group isomorphisms/Automorphism/Introduction/Section
## Definition

Group isomorphism/Definition
Bijective linear mappings are in particular group isomorphisms.

## Definition

Groups/Isomorphic/Definition

## Lemma
### Proof

$\Box$

## Example

Isomorphic groups are equal with respect to their group-theoretic properties. An isomorphism of a group to itself is called automorphism. The set of all automorphisms on $G$ form, with the composition of mappings, a group, which is denoted by $[[:Template:Op:Aut]]$ and which is called the automorphism group of $G$. Important examples of automorphisms are the so-called inner automorphisms.

## Definition

Group theory/Inner automorphism/Definition
The mapping $\kappa _{g}$ is also called the conjugation with $g$. If $G$ is a commutative Gruppe, then, because of $gxg^{-1}=xgg^{-1}=x$, the identity is the only inner automorphism. Therefore, this concept is only interesting for non-commutative groups.

## Lemma
### Proof

$\Box$
# Group homomorphism/Kernel/Injectivity criterion/Introduction/Section
## Definition

Group homomorphism/Kernel/Definition

## Lemma
### Proof

$\Box$

## Lemma
### Proof

$\Box$
# Algebra II/Functions

    Intro to Functions: Speak Math Now!/Week 4: Functions
A vertical line test serves to check if a relation is a function or not. If more than two dots touch the "vertical line", it is not a function. Therefore, a function cannot be vertical (but, on the contrast, it can be horizontal).
Functions are graphical representation of algebra. Thus there will always be an algebraic equation to solve before representing it on the Cartesian plane.
A Cartesian plane is a cross that consist of two axis, the x and y axis. On this cross the horizontal line of it is the 'x axis' and the vertical line is the 'y axis'. The point of intersection of these two axis is called the origin. Numbers above the origin and on the y axis are positive and numbers below the origin are negative numbers of y axis. Numbers on the left side of x axis are negative and numbers on the right side are positive.Between these numbers is the point of intersection and the numerical value there is zero.
# Group homomorphism/Inverse to inverse/Fact

Let $G$ and $H$ denote groups, and let $\varphi \colon G\rightarrow H$ be a group homomorphism.
$\varphi (e_{G})=e_{H}$ and $(\varphi (g))^{-1}=\varphi {\left(g^{-1}\right)}$ for every
$g\in G$
# Group homomorphism/Inverse to inverse/Fact/Proof

To prove the first statement, consider
    $\varphi (e_{G})=\varphi (e_{G}e_{G})=\varphi (e_{G})\varphi (e_{G})\,.$
Multiplication with $\varphi (e_{G})^{-1}$ yields $e_{H}=\varphi (e_{G})$.
To prove the second claim, we use
    $\varphi {\left(g^{-1}\right)}\varphi (g)=\varphi {\left(g^{-1}g\right)}=\varphi (e_{G})=e_{H}\,.$
This means that $\varphi {\left(g^{-1}\right)}$ has the property that characterizes the inverse element of $\varphi (g)$. Since the inverse element in a group is, due to fact, uniquely determined, we must have $\varphi {\left(g^{-1}\right)}=(\varphi (g))^{-1}$.
# Group homomorphism/Categorial properties/Fact

Let $F,G,H$ denote groups. Then the following properties hold.
* The identity is a group homomorphism.
    $\operatorname {Id} \colon G\longrightarrow G$
* If $\varphi :F\rightarrow G$ and $\psi :G\rightarrow H$ are group homomorphisms, then the composition $\psi \circ \varphi \colon F\rightarrow H$ is a group homomorphism.
* For a subgroup $F\subseteq G$, the inclusion $F\hookrightarrow G$ is a group homomorphism.
* Let $\{e\}$ be the trivial group. Then the mapping $\{e\}\rightarrow G$ that sends $e$ to $e_{G}$ is a group homomorphism. Moreover, the (constant) mapping $G\rightarrow \{e\}$ is a group homomorphism.
# Group homomorphism/Z to Z/Example

Let $d\in \mathbb {N}$ be fixed. The mapping
    $\mathbb {Z} \longrightarrow \mathbb {Z} ,n\longmapsto dn,$
is a group homomorphism. This follows immediately from the distributive law. For $d\geq 1$, this mapping is injective, and the image is the subgroup $\mathbb {Z} d\subseteq \mathbb {Z}$. For $d=0$, we have the zero mapping. For $d=1$, the mapping is the identity. For $d\geq 2$, the mapping is not surjective.
# Group homomorphism/Z to Z mod d/Directly/Example

Let $d\in \mathbb {N} _{+}$. We consider the set
    $\mathbb {Z} /(d)=\{0,1,\ldots ,d-1\}\,,$
together with the addition described in exercise, which makes it a group. The mapping
    $\varphi \colon \mathbb {Z} \longrightarrow \mathbb {Z} /(d)$
that sends an integer number $n$ to its remainder after division by $d$ is a group homomorphism. For, if $m=ad+r$ and $n=bd+s$ are given with $0\leq r,s<d$, then
    $m+n=(a+b)d+r+s\,.$
Here, it may happen that $r+s\geq d$. In this case,
    $\varphi (m+n)=r+s-d\,,$
and this coincides with the addition of $r$ and $s$ in $\mathbb {Z} /(d)$. This mapping is surjective, but not injective.
# Group homomorphism/Determinant/Example

For a field $K$ and $n\in \mathbb {N} _{+}$, the determinant
    $\det \colon \operatorname {GL} _{n}\!{\left(K\right)}\longrightarrow K^{\times },M\longmapsto \det M,$
is a group homomorphism. This follows from the multiplication theorem for the determinant and fact.
# Group homomorphism/Sign/Example

The assignment
    $S_{n}\longrightarrow \{1,-1\},\pi \longmapsto \operatorname {sgn} (\pi ),$
where $S_{n}$ denotes the permutation group for $n$ elements, is a group homomorphism, due to fact.
# Group homomorphism/Z to group/Fact

Let $G$ denote a group.
$g\in G$ and group homomorphisms $\varphi$ from $\mathbb {Z}$ to $G$, given by
    $g\longmapsto (n\mapsto g^{n}){\text{ and }}\varphi \longmapsto \varphi (1).$
# Group homomorphism/Z to group/Fact/Proof

Let $g\in G$ be fixed. That the mapping
    $\varphi _{g}\colon \mathbb {Z} \longrightarrow G,n\longmapsto g^{n},$
is a
group homomorphism, is just a reformulation of the exponential laws. Because of $\varphi _{g}(1)=g^{1}=g$, we obtain from the power mapping $\varphi _{g}$ the group element back. Moreover, a group homomorphism $\varphi \colon \mathbb {Z} \rightarrow G$ is uniquely determined by $\varphi (1)$, as $\varphi (n)=(\varphi (1))^{n}$ for $n$ positive, and $\varphi (n)={\left((\varphi (1))^{-1}\right)}^{-n}$ for $n$ negative must hold.
# Linear algebra (Osnabrück 2024-2025)/Permutation/Sign/Group homomorphism/Fact/Factreferencenumber

Theorem 18.13
# Group homomorphism/Kernel/Definition

Group homomorphism/Situation Then the preimage of the neutral element is called the kernel of $\varphi$, denoted by
    $\operatorname {kern} \varphi =\varphi ^{-1}(e_{H})={\left\{g\in G\mid \varphi (g)=e_{H}\right\}}\,.$
# Group homomorphism/Kernel/Subgroup/Fact

Let $G$ and $H$ be groups, and let
    $\varphi \colon G\longrightarrow H$
be a group homomorphism.
kernel of $\varphi$ is a subgroup
$G$
# Group homomorphism/Kernel/Subgroup/Fact/Proof

Because of $\varphi (e_{G})=e_{H}$, we have $e_{G}\in \operatorname {kern} \varphi$. Let $g,g'\in \operatorname {kern} \varphi$. Then
    $\varphi (gg')=\varphi (g)\varphi (g')=e_{H}e_{H}=e_{H}\,;$
therefore, also $gg'\in \operatorname {kern} \varphi$. Hence, the kernel is a submonoid. Now, let $g\in \operatorname {kern} \varphi$, and consider the inverse element $g^{-1}$. Due to fact, we have
    $\varphi {\left(g^{-1}\right)}=(\varphi (g))^{-1}=e_{H}^{-1}=e_{H}\,;$
Hence, $g^{-1}\in \operatorname {kern} \varphi$.
# Group homomorphism/Injectivity and kernel/Fact

Let $G$ and $H$ be groups.
group homomorphism $\varphi \colon G\rightarrow H$ is injective if and only if the kernel
$\varphi$
# Group homomorphism/Injectivity and kernel/Fact/Proof

If $\varphi$ is injective, then every element $h\in H$ is hit by at most one element from $G$. As $e_{G}$ is sent to $e_{H}$, no further element can be sent to $e_{H}$. Therefore, $\operatorname {kern} \varphi =\{e_{G}\}$. Now assume that this holds. Let $g,{\tilde {g}}\in G$ be elements mapping to $h\in H$. Then
    $\varphi {\left(g{\tilde {g}}^{-1}\right)}=\varphi (g)\varphi ({\tilde {g}})^{-1}=hh^{-1}=e_{H}\,;$
hence, $g{\tilde {g}}^{-1}\in \operatorname {kern} \varphi$, and so $g{\tilde {g}}^{-1}=e_{G}$ by the condition. Therefore, $g={\tilde {g}}$.
# C Programming/Flow Control/Assignments
## Question 1

Assume that w=6, x=10, y=6 and z=3. What are the truth values of the following statements?
* w<9
* w!=y
* z>x
* z<=y
* x-6>y*2

## Question 2

With the same values of w,x,y and z, what are the values of the following combinations?
* w<9 && w!=y
* x+7>2 || x==6
* !(x-9>1)
* !((x>y) && (x<z))
* (x>7) && !(x>7)
* (x>7) || !(x>7)

## Question 3

Under what values of x, y, and z do the following numbered statements get executed? Give the answers in forms like x>y>z.

## Question 4

Under what values of x do the following numbered statements get executed?

## Draw a rectangle with dots

Draw a rectangle with dots with column = 3 and row = 4

## Draw a staircase

Draw a staircase of 6 steps

## Sum of all integer numbers from 1 to n

Use loop to calculate the sum of all integer numbers from 1 to n, where the value of n is passed from the command line while running the program.
# Group isomorphism/Definition

Let $G$ and $H$ be groups. A bijective group homomorphism
    $\varphi \colon G\longrightarrow H$
is called an isomorphism.
# Groups/Isomorphic/Definition

The groups $H$ and $G$ are called isomorphic, if there exists a group isomorphism $\varphi \colon G\rightarrow H$.
# Bijective group homomorphism/Inverse mapping/Homomorphism/Fact

Let $G$ and $H$ be groups, and let
    $\varphi \colon G\longrightarrow H$
be a group isomorphism.
inverse mapping
    $\varphi ^{-1}\colon H\longrightarrow G,h\longmapsto \varphi ^{-1}(h),$
# Bijective group homomorphism/Inverse mapping/Homomorphism/Fact/Proof

This follows from
    ${\begin{aligned}\varphi ^{-1}(h_{1}h_{2})&=\varphi ^{-1}{\left(\varphi (\varphi ^{-1}(h_{1}))\varphi (\varphi ^{-1}(h_{2}))\right)}\\&=\varphi ^{-1}{\left(\varphi {\left(\varphi ^{-1}(h_{1})\varphi ^{-1}(h_{2})\right)}\right)}\\&=\varphi ^{-1}(h_{1})\varphi ^{-1}(h_{2}).\end{aligned}}$
# Group isomorphism/Real exponential function/Example

We consider the additive group of the real numbers, that is $(\mathbb {R} ,0,+)$, and the multiplicative group of the positive real numbers, thus $(\mathbb {R} _{+},1,\cdot )$. Then the exponential function
    $\exp \colon \mathbb {R} \longrightarrow \mathbb {R} _{+},x\longmapsto \exp(x),$
is a group isomorphism. This rests on basic analytic properties of the exponential function. The homomorphism property is just a reformulation of the functional equation
    $\exp(x+y)=e^{x+y}=e^{x}e^{y}=\exp(x)\exp(y)\,.$
The injectivity of the mapping follows from the strict monotonicity, the surjectivity follows from the Intermediate value theorem. The inverse mapping is the natural logarithm, which is also a group isomorphism.
# Group theory/Inner automorphism/Definition

Let $G$ be a group, and $g\in G$ be fixed. The mapping defined by $g$,
    $\kappa _{g}\colon G\longrightarrow G,x\longmapsto gxg^{-1},$
is called an inner automorphism.
# Inner automorphism/Automorphism/Fact

An inner automorphism is indeed
The assignment
    $G\longrightarrow \operatorname {Aut} \,G,g\longmapsto \kappa _{g},$
is a group homomorphism.
# Inner automorphism/Automorphism/Fact/Proof

We have
    $\kappa _{g}(xy)=gxyg^{-1}=gxg^{-1}gyg^{-1}=\kappa _{g}(x)\kappa _{g}(y)\,,$
so that $\kappa _{g}$ this is a group homomorphism. We have
    $\kappa _{g}(\kappa _{h}(x))=\kappa _{g}(hxh^{-1})=ghxh^{-1}g^{-1}=ghx(gh)^{-1}=\kappa _{gh}\,.$
This implies, on one hand, that
    $\kappa _{g^{-1}}\circ \kappa _{g}=\kappa _{g^{-1}g}=\operatorname {Id} _{G}\,;$
therefore, $\kappa _{g}$ is bijective and an automorphism. On the other hand, this implies that the total mapping $\kappa$ is a group homomorphism.
# Matrices/Inner automorphisms/Base change/Example

For a fixed invertible matrix $B\in \operatorname {GL} _{n}\!{\left(K\right)}$, the conjugation
    $\kappa _{B}\colon \operatorname {GL} _{n}\!{\left(K\right)}\longrightarrow \operatorname {GL} _{n}\!{\left(K\right)},M\longmapsto BMB^{-1},$
is just the mapping that assigns, to a describing matrix $M$ of a linear mapping with respect to a basis, the describing matrix with respect to a new basis.
# Group theory/Left and right cosets/Examples/Introduction/Section
## Definition

Group theory/Subgroup/Equivalence relation/Definition
This is indeed an equivalence relation: From $x^{-1}x=e_{G}\in H$ we get that this relation is reflexive. From $x^{-1}y\in H$ we get immediately $y^{-1}x=(x^{-1}y)^{-1}\in H$, and from $x^{-1}y\in H$ and $y^{-1}z\in H$ we get $x^{-1}z\in H$.
Two group elements $x$ and $y$ are equivalent if and only if there exists an element $h\in H$ of the subgroup with $y=xh$. In accordance with example, we can interpret this situation in the sense that the subgroup $H$ provides a set of possible moves, and two elements are equivalent if and only if they can be moved to each other by a movement from $H$.

## Definition

Group theory/Left and right coset/Definition
The equivalence classes to the equivalence relation defined above are, because of
    ${\begin{aligned}{x}&={\left\{y\in G\mid x\sim y\right\}}\\&={\left\{y\in G\mid x^{-1}y\in H\right\}}\\&={\left\{y\in G\mid {\text{there exists }}h\in H{\text{ with }}x^{-1}y=h\right\}}\\&={\left\{y\in G\mid {\text{there exists }}h\in H{\text{ with }}y=xh\right\}}\\&=xH,\end{aligned}}$
the left cosets. The coset to the neutral element is the subgroup $H$ itself. Therefore, the left cosets form a disjoint decomposition (a partition) of $G$. This holds for the right cosets as well. In the commutative case, one does not have to distinguish between left cosets and right cosets.

## Lemma
### Proof

$\Box$
# Group theory/Lagrange's theorem/Section
## Theorem
### Proof

$\Box$

## Corollary
### Proof

$\Box$

## Definition

Group theory/Index/Definition
In the preceding definition, the number is in general to be understood as the cardinality of a set. However, the index is mainly used if it is finite, that is, if there are only finitely many cosets. This is, for finite $G$, always the case but can also hold for infinite $G$, as already the example $\mathbb {Z} n\subseteq \mathbb {Z}$, $n\geq 1$, shows. If $G$ is a finite group, and $H\subseteq G$ is a subgroup, then Lagrange's theorem yields the simple index formula
    ${\#\left(G\right)}={\#\left(H\right)}\cdot [[:Template:Op:Groupindex]]\,.$
# Normal subgroup/Residue class group/Introduction/Section
## Theorem
### Proof

$\Box$

## Definition

Residue class group/Representative/Definition
# The Varanasi Heritage Dossier/Sangameshvaran Temple

Detailed description of each heritage Site - Asi Ghat to Pancakota Ghat
Lakshminarayana Pancaratna and Asi Sangameshvara temples

### Location

25º 17.358’ North and 83º 00.356’ East (Lakshminarayana

##### Exact location on a map

At Asi Ghat, ascending about 20 steps to the right, is Lakshminarayana temple. By turning left in the lane, one meets the Asi Sangameshvara (Hariharbaba Ashram, No. B 1/ 75). 4.Area (in ha.) of proposed property: 0.01ha (Lakshminarayana temple); and 0.006ha (Asi Sangameshvara)

### Historical/cultural/natural significance

Asi Sangameshvara: This temple (of “the Lord of the confluence of Asi”) is marked with a marble plaque to commemorate the site's puranic heritage. In the 14th century text, the Kashi Khanda this temple is eulogised vividly, especially concerning various pilgrimages like Pancakroshi, Nagara Pradakshina, Kedarkhanda, etc.. Built in the 19th century on a small square, the temple consists of only the inner sanctum and lacks the surrounding veranda for circumambulation. Of course, four gates are facing to all the directions. In the inner sanctum, there is also the Baneshvara linga; in the niches, there are images of Ganesha, Vishnu, Surya, and Annapurna. This is an example of a simple Nagara style of architecture. In November of 1987, the family members of (late) Mahabir Prasad Jhunjhunwala repaired and renovated the temple.

### Present state of conservation

The temple trusts manages the temple. In 2012, there was no conservation plan or program.

### Specific measures being taken for conserving the specific property

No specific measures are taken to conserve and preserve the temple except to continue and maintain the daily religious activities of the Pujari family living therein, and sometimes, some devotees donate for the cleanness and repair.