OpenLLM-France/wikimedia huggingface dataset:
# PowerShell

Part of the Information Technology School
PowerShell (including Windows PowerShell and PowerShell Core) is a task automation and configuration management framework from Microsoft available since 2006, consisting of a command-line shell and associated scripting language built on the .NET Framework. Initially a Windows component only, PowerShell was made open-source and cross-platform on 18 August 2016.
This entire Wikiversity course can be downloaded in book form by selecting Download Learning Guide in the sidebar.

## Approach

Many PowerShell tutorials approach PowerShell from a command-line scripting and automation perspective, assuming that you already know programming. This course takes a more traditional academic introduction to programming approach, with the assumption that once you understand programming using the PowerShell language, you will be able to use other resources to develop the scripts you need.

## Preparation

This is a third-semester, college-level course. Learners should already be familiar with introductory computer concepts and computer support concepts.

## Resources

The lessons in this course use a variety of information resources. All are free, but some require registration in order to access them. On Wikiversity, every effort is made to avoid this type of resource unless the quality of the resource clearly outweighs the nuisance factor. The online book Master-PowerShell | With Dr. Tobias Weltner at PowerShell.com is a high quality resource, and provides the option of opting out of any contact.

## Lessons

* Introduction
* Console
* ISE
* Variables
* Expressions
* Conditions
* Loops
* Arrays and Hash Tables
* Functions
* Errors
* File System
* Registry
* Systems Management
* Event Logs
* Additional Topics

## Examples

* Create-ShutdownTask
* Disable-InternetExplorerESC
* Install-Flowgorithm
* Install-GoogleChrome
* Install-SQLServerExpress2019
* Install-SQLServerManagementStudio184
* Install-VisualStudioCode

## See Also

* Microsoft Virtual Academy: Getting Started with PowerShell 3.0
* Microsoft Virtual Academy: Advanced Tools & Scripting with PowerShell 3.0
* TechNet: The Best Ways to Learn PowerShell
# Novial/Li Verdi Kordie

Back to the Novial front page
| Esperanto | Novial | Novial |
| La Verda Koro de Julio BAGHY Enhavo Leciono 1 Leciono 2 Leciono 3 Leciono 4 Leciono 5 Leciono 6 Leciono 7 Leciono 8 Leciono 9 Leciono 10 Leciono 11 | Li Verdi Kordie de Julio BAGHY Kontenaje Lektione 1 Lektione 2 Lektione 3 Lektione 4 Lektione 5 Lektione 6 Lektione 7 Lektione 8 Lektione 9 Lektione 10 Lektione 11 | Li Verdi Kordie de Julio BAGHY Kontenaje Lektione 1 Lektione 2 Lektione 3 Lektione 4 Lektione 5 Lektione 6 Lektione 7 Lektione 8 Lektione 9 Lektione 10 Lektione 11 |
The original Esperanto course is found here:
# Novel economic mechanisms

This project is intended to explore and possibly implement novel economic mechanisms that are potentially beneficial to all members of society.

## Discussion questions

* How might microinvestments be approached in order to allow large sums of capital to be accumulated and then have collaboratively decided business decisions be executed?
# Novial

Novial [nov- ("new") + IAL, International Auxiliary Language] is a constructed international auxiliary language (IAL) for universal communication between speakers of different native languages. It was devised by Otto Jespersen, a Danish linguist who was previously involved in the Ido movement, and subsequently in the development of Interlingua.

## Subpages

Special:Prefixindex/Novial/

## See Also

* Portal:Novial
* Wikipedia: Novial
# Novial/La Chanson de Roland

Back to the Novial front page
The Old French text is found here:
| Old French | Novial | Novial |
| I Carles li reis, nostre emper[er]e magnes Set anz tuz pleins ad estet en Espaigne: Tresqu'en la mer cunquist la tere altaigne. N'i ad castel ki devant lui remaigne; Mur ne citet n'i est remes a fraindre, Fors Sarraguce, ki est en une muntaigne. Li reis Marsilie la tient, ki Deu nen aimet; Mahumet sert e Apollin recleimet: Nes poet guarder que mals ne l'i ateignet. AOI. | I Carles li rego, nusen grand emperere Set yares tot plen ha es in Spania: Til li mare lo konquestad li alti tere. Non es kastele kel, devan lo, resista; Nuli mur ni urbe resta a bli venka, Exept Saragosa, kel es sur un monte. Li rego Marsilie tena lu, kelo Dee non ama; serva Mahomet e invoka Apollo: e non pove prevente ke malu atene lo. AOI. | I Carles li rego, nusen grand emperere Set yares tot plen ha es in Spania: Til li mare lo konquestad li alti tere. Non es kastele kel, devan lo, resista; Nuli mur ni urbe resta a bli venka, Exept Saragosa, kel es sur un monte. Li rego Marsilie tena lu, kelo Dee non ama; serva Mahomet e invoka Apollo: e non pove prevente ke malu atene lo. AOI. |
# Novial/Li Verdi Kordie/Lektione 11

Back to the Novial front page
Back to Li Verdi Kordie Contents

## TEXT 1

| Esperanto | Novial | Novial |
| 'Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |

## VOCABULARY

Back to the Novial front page
Back to Li Verdi Kordie Contents
# Novial/Li Verdi Kordie/Lektione 10

Back to the Novial front page
Back to Li Verdi Kordie Contents

## TEXT 1

| Esperanto | Novial | Novial |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |
| Esp | Nov | Nov |

## VOCABULARY

Back to the Novial front page
Back to Li Verdi Kordie Contents
# Plant identification/Senecio vulgaris

Add this to a quiz page by copying and pasting
             {{:Plant identification/Senecio vulgaris}}
What plant is this? :
* Scientific Name
* Senecio vulgaris
* Common (English) Name
* Common groundsel
* Links
* Wikipedia article
* Wikibooks chapter
* More images on Commons
# Plant identification/Stellaria media

Add this to a quiz page by copying and pasting
             {{:Plant identification/Stellaria media}}
What plant is this? :
* Scientific Name
* Stellaria media
* Common (English) Name
* Common chickweed
* Links
* Wikipedia article
* Wikibooks chapter
* More images on Commons
# Plant identification/Symplocarpus foetidus

Add this to a quiz page by copying and pasting
             {{:Plant identification/Symplocarpus foetidus}}
What plant is this? :
* Scientific Name
* Symplocarpus foetidus
* Common (English) Name
* Eastern Skunk Cabbage
* Links
* Wikipedia article
* More images on Commons
# Plant identification/Plant list
### A

* Acer griseum
* Acer saccharum
* Achillea millefolium
* Actaea spicata
* Aponogeton distachyos
* Atropa belladonna

### B

* Butomus umbellatus

### C

* Cardamine hirsuta
* Citrus sinensis

### E

* Eschscholzia californica
* Euphorbia pulcherrima

### G

* Gratiola officinalis

### H

* Hamamelis x intermedia
* Heliotropium indicum

### I

* Iris sibirica

### M

* Melia azedarach

### O

* Origanum majorana

### S

* Senecio vulgaris
* Stellaria media
* Symplocarpus foetidus

### T

* Taraxacum officinalis
* Trifolium repens
* Tussilago farfara
# Plant identification/Quiz 1

These plants were found blooming on a Pennsylvania farm on Dec 21, 2006.
What plant is this? :
* Scientific Name
* Symplocarpus foetidus
* Common (English) Name
* Eastern Skunk Cabbage
* Links
* Wikipedia article
* More images on Commons
What plant is this? :
* Scientific Name
* Cardamine hirsuta
* Common (English) Name
* Hairy bittercress
* Links
* Wikipedia article
* Wikibooks chapter
* More images on Commons
What plant is this? :
* Scientific Name
* Taraxacum officinalis
* Common (English) Name
* Common dandelion
* Links
* Wikipedia article
* Wikibooks chapter
* More images on Commons
# Plant identification/Tussilago farfara

Add this to a quiz page by copying and pasting
             {{:Plant identification/Tussilago farfara}}
What plant is this? :
* Scientific Name
* Tussilago farfara
* Common (English) Name
* Coltsfoot
* Links
* Wikipedia article
* More images on Commons
# Plant identification/Trifolium repens

Add this to a quiz page by copying and pasting
             {{:Plant identification/Trifolium repens}}
What plant is this? :
* Scientific Name
* Trifolium repens
* Common (English) Name
* White clover
* Links
* Wikipedia article
* Wikibooks chapter
* More images on Commons
# Plant identification/Taraxacum officinalis

Add this to a quiz page by copying and pasting
             {{:Plant identification/Taraxacum officinalis}}
What plant is this? :
* Scientific Name
* Taraxacum officinalis
* Common (English) Name
* Common dandelion
* Links
* Wikipedia article
* Wikibooks chapter
* More images on Commons
# Linear mapping/Kernel/2 3 0 -1/4 2 2 5/Exercise

Determine the kernel of the linear map
    $\varphi \colon \mathbb {R} ^{4}\longrightarrow \mathbb {R} ^{2},$
given by the matrix
    $M={\begin{pmatrix}2&3&0&-1\\4&2&2&5\end{pmatrix}}\,.$
# Linear mapping/Kernel/Injectivity/Fact

Let $K$ denote a field, let $V$ and $W$ denote $K$-vector spaces, and let
    $\varphi \colon V\longrightarrow W$
denote a $K$-linear mapping.
$\varphi$
injective if and only if $\operatorname {kern} \varphi =0$
# Linear mapping/Kernel/2 3 0 -1/4 2 2 5/Exercise/Solution

We determine the solution space of the system of linear equations
    $I\,\,\,\,\,\,\,\,\,2x+3y\,\,\,\,\,\,\,\,\,\,\,\,\,-w=0$
    $II\,\,\,\,\,\,4x+2y+2z+5w=0.$
We get
    $III=II-2\cdot I\,\,\,\,\,\,-4y+2z+7w=0.$
Thus we have an equivalent system in row echelon form.
We choose first $w=0$ and $z=2$. Then $y=1$ according to III and according to I we get $x=-{\frac {3}{2}}$. Hence
    ${\begin{pmatrix}-{\frac {3}{2}}\\1\\2\\0\end{pmatrix}}$
is a solution.
We choose now $w=1$ and $z=0$. Then $y={\frac {7}{4}}$ according to III and according to I we get
    $x=-{\frac {17}{8}}\,.$
Therefore
    ${\begin{pmatrix}-{\frac {17}{8}}\\{\frac {7}{4}}\\0\\1\end{pmatrix}}$
is another solution, which is linearly independent of the first solution. Since the rank of the matrix is $2$, the kernel is two-dimensional, hence the kernel equals
    ${\left\{a{\begin{pmatrix}-{\frac {3}{2}}\\1\\2\\0\end{pmatrix}}+b{\begin{pmatrix}-{\frac {17}{8}}\\{\frac {7}{4}}\\0\\1\end{pmatrix}}\mid a,b\in \mathbb {R} \right\}}.$
# Linear mapping/Linear form/Definition

Let $K$ be a field and let $V$ be a $K$-vector space. A linear mapping
    $V\longrightarrow K$
is called a Linear form on $V$.
# Linear mapping/Kernel/Definition

Let $K$ denote a field, let $V$ and $W$ denote $K$-vector spaces, and let
    $\varphi \colon V\longrightarrow W$
denote a $K$-linear mapping. Then
    $\operatorname {kern} \varphi :=\varphi ^{-1}(0)={\left\{v\in V\mid \varphi (v)=0\right\}}\,$
is called the kernel of $\varphi$.
# Linear mapping/Kernel/Injectivity criterion/Section
## Definition

Let $K$ denote a field, let $V$ and $W$ denote $K$-vector spaces, and let
    $\varphi \colon V\longrightarrow W$
denote a $K$-linear mapping. Then
    $\operatorname {kern} \varphi :=\varphi ^{-1}(0)={\left\{v\in V\mid \varphi (v)=0\right\}}\,$
$\varphi$
The kernel is a linear subspace of $V$.
The following criterion for injectivity is important.

## Lemma

Let $K$ denote a field, let $V$ and $W$ denote $K$-vector spaces, and let
    $\varphi \colon V\longrightarrow W$
denote a $K$-linear mapping. Then $\varphi$ is injective if and only if $\operatorname {kern} \varphi =0$

### Proof

If the mapping is injective, then there can exist, apart from $0\in V$, no other vector $v\in V$ with $\varphi (v)=0$. Hence, $\varphi ^{-1}(0)=\{0\}$. So suppose that $\operatorname {kern} \varphi =0$, and let $v_{1},v_{2}\in V$ be given with $\varphi (v_{1})=\varphi (v_{2})$. Then, due to linearity,
    $\varphi (v_{1}-v_{2})=\varphi (v_{1})-\varphi (v_{2})=0\,.$
Therefore, $v_{1}-v_{2}\in \operatorname {kern} \varphi$, and so $v_{1}=v_{2}$.
$\Box$
# Linear mapping/Linear combinations/Exercise

Let $K$ be a field, and let $V$ and $W$ be $K$-vector spaces. Let
    $\varphi \colon V\longrightarrow W$
be a linear map. Prove that for all vectors $v_{1},\ldots ,v_{n}\in V$ and coefficients $s_{1},\ldots ,s_{n}\in K$, the relationship
    $\varphi {\left(\sum _{i=1}^{n}s_{i}v_{i}\right)}=\sum _{i=1}^{n}\lambda _{i}\varphi (v_{i})\,$
holds.
# Linear mapping/Kernel/2152 3-27-1 2-1-43/Exercise/Solution

We have to solve the system of linear equations
    ${\begin{matrix}2x&+y&+5z&+2w&=&0\\3x&-2y&+7z&\,\,\,\,-w&=&0\\2x&\,\,\,\,-y&-4z&+3w&=&0\,\end{matrix}}.$
We eliminate with the help of the first equation the variable $y$. The resulting system is ($II'=II+2I$, $III'=III+I$)
    ${\begin{matrix}2x&+y&+5z&+2w&=&0\\7x&\,\,\,\,\,\,\,\,&+17z&+3w&=&0\\4x&\,\,\,\,\,\,\,\,&+z&+5w&=&0\,\end{matrix}}.$
We eliminate from $II'$ with $III'$ the variable $z$, this yields ($II'-17III'$)
    ${\begin{matrix}2x&+y&+5z&+2w&=&0\\4x&\,\,\,\,\,\,\,\,&+z&+5w&=&0\\-61x&\,\,\,\,\,\,\,\,&\,\,\,\,\,\,\,\,&-82w&=&0\,\end{matrix}}.$
We can now solve the system, because $x\neq 0$ determines the other variables. Set $x=82$. Then $w=-61$. Then
    $z=-4x-5w=-4\cdot 82-5(-61)=-328+305=-23\,.$
Finally we get
    $y=-2x-5z-2w=-2(82)-5(-23)-2(-61)=-164+115+122=73\,.$
The solution set, which is the kernel, is therefore
    ${\left\{s{\begin{pmatrix}82\\73\\-23\\-61\end{pmatrix}}\mid s\in \mathbb {R} \right\}}.$
# Linear mapping/Kernel/Injectivity/Fact/Proof

If the mapping is injective, then there can exist, apart from $0\in V$, no other vector $v\in V$ with $\varphi (v)=0$. Hence, $\varphi ^{-1}(0)=\{0\}$. So suppose that $\operatorname {kern} \varphi =0$, and let $v_{1},v_{2}\in V$ be given with $\varphi (v_{1})=\varphi (v_{2})$. Then, due to linearity,
    $\varphi (v_{1}-v_{2})=\varphi (v_{1})-\varphi (v_{2})=0\,.$
Therefore, $v_{1}-v_{2}\in \operatorname {kern} \varphi$, and so $v_{1}=v_{2}$.
# Polynomial ring/Field/One variable/Definition

The polynomial ring over a field $K$ consists of all polynomials
    $P=a_{0}+a_{1}X+a_{2}X^{2}+\cdots +a_{n}X^{n}\,,$
where $a_{i}\in K$, $n\in \mathbb {N}$. It is endowed with componentwise addition and a multiplication, which arises by distributive continuation of the rule
    $X^{n}\cdot X^{m}:=X^{n+m}\,.$
# Polynomial ring/Field/Polynomial function/Introduction/Section
## Definition

The polynomial ring over a field $K$ consists of all polynomials
    $P=a_{0}+a_{1}X+a_{2}X^{2}+\cdots +a_{n}X^{n}\,,$
where $a_{i}\in K$, $n\in \mathbb {N}$. It is endowed with componentwise addition and a multiplication, which arises by distributive continuation of the rule
    $X^{n}\cdot X^{m}:=X^{n+m}\,.$
A polynomial
    $P=\sum _{i=0}^{n}a_{i}X^{i}=a_{0}+a_{1}X+a_{2}X^{2}+\cdots +a_{n}X^{n}\,$
is, formally seen, nothing but the tuple $(a_{0},a_{1},\ldots ,a_{n})$, these numbers are called the coefficient of the polynomial. The polynomials are equal if and only if all their coefficients coincide. The letter $X$ is called the variable of the polynomial ring. In this context, the field $K$ is called the base field of the polynomial ring. Due to the componentwise definition of the addition, we have immediately a commutative group, with the zero polynomial (where all coefficients are $0$) as neutral element. The polynomials with $a_{i}=0$ for all $i\geq 1$ are called constant polynomials, they are simply written as $a_{0}$.
The way a polynomial is written suggests how the multiplication shall work, the product $X^{n}\cdot X^{m}$ is given by the addition of the exponents, thus $X^{n}\cdot X^{m}:=X^{n+m}$. For arbitrary polynomials, the multiplication arises from this simple multiplication rule by distributive continuation according to the law to multiply "everything with everything“. Explicitly, the multiplication is given by the following rule gegeben:
    ${\left(\sum _{i=0}^{n}a_{i}X^{i}\right)}\cdot {\left(\sum _{j=0}^{m}a_{j}X^{j}\right)}=\sum _{k=0}^{n+m}c_{k}X^{k}{\text{ where }}c_{k}=\sum _{r=0}^{k}a_{r}b_{k-r}.$
The multiplication is associative, commutative, distributive, and the constant polynomial $1$ is its neutral element, see exercise. Altogether, we have a commutative ring.

## Definition

The degree of a nonzero polynomial
    $P=a_{0}+a_{1}X+a_{2}X^{2}+\cdots +a_{n}X^{n}\,$
with $a_{n}\neq 0$
$n$
We do not define a degree for the zero polynomial. The coefficient $a_{n}$, where $n$ is the degree of the polynomial, is called the leading coefficient of the polynomial. The term $a_{n}X^{n}$ is called leading term. A polynomial with leading coefficient $1$ is called normed.
We can plug in (or insert or evaluate at) an element $a\in K$, into a polynomial $P\in K[X]$, by replacing the variable $X$ everywhere by $a$. This gives a mapping
    $K\longrightarrow K,a\longmapsto P(a),$
which we call the polynomial function defined by the polynomial. In general, this mapping is not linear, only the polynomials of the form $P=a_{1}X$ are linear.
* ↑ Here, like for the addition of polynomials of different degrees, the coefficients for $r>n$ or $k-r>m$ are $0$.
# Polynomial ring/Field/Domain/Exercise

Show that in a polynomial ring over a field $K$, the following statement holds: if $P,Q\in K[X]$ are not zero, then also $PQ\neq 0$.
# Polynomial ring/Field/One variable/Euclidean division/Fact

Let $K$ be a field and let $K[X]$ be the polynomial ring over $K$. Let $P,T\in K[X]$ be polynomials with $T\neq 0$.
$Q,R\in K[X]$ such that
    $P=TQ+R{\text{ and with }}\operatorname {deg} \,(R)<\operatorname {deg} \,(T){\text{ or }}R=0.$
# Polynomial ring/Field/One variable/Euclidean division/Fact/Proof

We prove the statement about the existence by induction over the degree of $P$. If the degree of $T$ is larger than the degree of $P$, then $Q=0$ and $R=P$ is a solution.
Suppose that $\operatorname {deg} \,(P)=0$. By the remark just made also $\operatorname {deg} \,(T)=0$ holds, so $T$ is a constant polynomial, and therefore (since $T\neq 0$ and $K$ is a field) $Q=P/T$ and $R=0$ is a solution.
So suppose now that $\operatorname {deg} \,(P)=n$ and that the statement for smaller degrees is already proven. We write $P=a_{n}X^{n}+\cdots +a_{1}X+a_{0}$ and $T=b_{k}X^{k}+\cdots +b_{1}X+b_{0}$ with $a_{n},b_{k}\neq 0,\,k\leq n$. Then setting $H={\frac {a_{n}}{b_{k}}}X^{n-k}$ we have the relation
    ${\begin{aligned}P'&:=P-TH\\&=0X^{n}+{\left(a_{n-1}-{\frac {a_{n}}{b_{k}}}b_{k-1}\right)}X^{n-1}+\cdots +{\left(a_{n-k}-{\frac {a_{n}}{b_{k}}}b_{0}\right)}X^{n-k}+a_{n-k-1}X^{n-k-1}+\cdots +a_{0}.\end{aligned}}$
The degree of this polynomial $P'$ is smaller than $n$ and we can apply the induction hypothesis to it. That means there exist $Q'$ and $R'$ such that
    $P'=TQ'+R'{\text{ and with }}\operatorname {deg} \,(R')<\operatorname {deg} \,(T){\text{ or }}R'=0.$
From this we get altogether
    $P=P'+TH=TQ'+TH+R'=T(Q'+H)+R'\,,$
so that $Q=Q'+H$ and $R=R'$ is a solution.
To prove uniqueness, let $P=TQ+R=TQ'+R'$, both fulfilling the stated conditions. Then $T(Q-Q')=R'-R$. Since the degree of the difference $R'-R$ is smaller than $\operatorname {deg} \,(T)$, this implies $R=R'$ and so $Q=Q'$.
# Polynomial ring/Evaluation/Remark

Let $K$ be a field, let $K[X]$ be the polynomial ring over $K$ and $a\in K$. Then the evaluation mapping
    $K[X]\longrightarrow K,P\longmapsto P(a),$
is $K$-linear. Moreover, we have
    $(PQ)(a)=P(a)Q(a)\,,$
see exercise.
# Polynomial ring/Field/Replacement/Structure/Exercise

Let $K$ be a field and let $K[X]$ be the polynomial ring over $K$. Let $a\in K$. Prove that the evaluating function
    $\psi \colon K[X]\longrightarrow K,P\longmapsto P(a),$
satisfies the following properties (here let $P,Q\in K[X]$).
    $(P+Q)(a)=P(a)+Q(a)\,.$
    $(P\cdot Q)(a)=P(a)\cdot Q(a)\,.$
    $1(a)=1\,.$
# Literature/1938/Chase

Authors :
* A B C D E F G H I J K L M N O P Q R S T U V W X Y Z &

## Wikimedia
### w: Stuart Chase

| w: General semantics | w: Alfred Korzybski w: S. I. Hayakawa |

## Chronology

* Austin, J. L. (1955). How to Do Things with Words. The William James Lectures delivered at Harvard University in 1955, ed. by J. O. Urmson. Oxford: Clarendon, 1962. $^{[^]}$
* Wittgenstein, Ludwig (1953). Philosophical Investigations. Blackwell Publishing. $^{[^]}$
* Hayakawa, S. I. (1949). Language in Thought and Action. Harcourt, Brace & Company, 1949. $^{[^]}$
* Orwell, George (1949). Nineteen Eighty-Four. London: Secker and Warburg, 1949. $^{[^]}$
* Ryle, Gilbert (1949). The Concept of Mind. University Of Chicago Press. $^{[^]}$
* Orwell, George (1946). "Politics and the English Language." Horizon, vol. 13, no. 76 (April), 252-265. $^{[^]}$
* Huxley, Aldous (1940). Words and Their Meanings. The Ward Ritchie Press, 1940. $^{[^]}$
* Chase, Stuart (1938). The Tyranny of Words. Harcourt, Brace & Co., 1938. $^{[^]}$
* Wells, H. G. (1938). World Brain. Garden City, NY: Doubleday, Doran & Co. $^{[^]}$
* Korzybski, Alfred (1933). Science and Sanity: An Introduction to Non-Aristotelian Systems and General Semantics. 5th ed., Institute of General Semantics, 1994. $^{[^]}$
* Magritte, René (1933). The Human Condition (La condition humaine). National Gallery of Art, Washington DC. $^{[^]}$
* Wells, H. G. (1933). The Shape of Things to Come. Hutchinson. $^{[^]}$
* Huxley, Aldous (1932). Brave New World. Harper Perennial, 1932. $^{[^]}$
* Wells, H. G. (1932). "Wanted: Professors of Foresight!" Reprinted in Futures Research Quarterly. Vol. 3 No. 1 (Spring 1987): 89-91. $^{[^]}$
* Frank, Jerome (1930). Law and the Modern Mind. Peter Smith, 1930. $^{[^]}$
* Ogden, C. K. (1930). Basic English: A General Introduction with Rules and Grammar. London: Paul Treber. $^{[^]}$
* Magritte, René (1929). The Treachery of Images (La trahison des images). Los Angeles County Museum of Art, Los Angeles, California. $^{[^]}$
* Russell, Bertrand (1926). "The Meaning of Meaning." Dial, vol.81 (August 1926) pp. 114-121. $^{[^]}$
* Ogden, C. K. & I. A. Richards (1923). The Meaning of Meaning: A Study of the Influence of Language upon Thought and of the Science of Symbolism. London: Routledge & Kegan Paul Ltd. $^{[^]}$
* Literature/1923/Sapir $^{[^]}$
* Wells, H. G. (1923). Men Like Gods. Cassell and Co., Ltd. $^{[^]}$
* Russell, Bertrand (1921). The Analysis of Mind. London: George Allen & Unwin. $^{[^]}$
* Watson, John B. (1913). "Psychology as the behaviorist views it," Psychological Review, 20, pp. 158-177. $^{[^]}$
* Wells, H. G. (1905). A Modern Utopia. New York, NY: Penguin Group, 2005. $^{[^]}$
# Literature/1938

Authors :
* A B C D E F G H I J K L M N O P Q R S T U V W X Y Z &

## Subpages

* Literature/1938/Bachelard $^{[^]}$
* Chase, Stuart (1938). The Tyranny of Words. Harcourt, Brace & Co., 1938. $^{[^]}$
* Literature/1938/Dewey $^{[^]}$
* Literature/1938/Pollard $^{[^]}$
* Literature/1938/Rand $^{[^]}$
* Wells, H. G. (1938). World Brain. Garden City, NY: Doubleday, Doran & Co. $^{[^]}$
# Literature/1939

Authors :
* A B C D E F G H I J K L M N O P Q R S T U V W X Y Z &

## Subpages

* Bernal, J. D. (1939). The Social Function of Science. London: Routledge & Kegan Paul Ltd. $^{[^]}$
* Literature/1939/Borges $^{[^]}$
* Literature/1939/Bush $^{[^]}$
* Literature/1939/Huxley $^{[^]}$
* Literature/1939/Joyce $^{[^]}$
* Literature/1939/Koestler $^{[^]}$
* Literature/1939/Orwell $^{[^]}$
* Literature/1939/Steinbeck $^{[^]}$