# C Programming/Arrays

* Objectives
* Learn about arrays and how to use them.
* Declaring arrays.
* Initializing arrays.
* Passing arrays to functions.
* Lesson
* Introduction
* An array, in it's simplest form, is a group of variables that ordered one after the other. One way to visualize this is to imagine a bookshelf, a bookshelf is of a certain size and can store only a certain number of books, but you can take any book out of a bookshelf without removing them all, unlike a stack. Arrays are typically used for the manipulation, storage and usage of large amounts of data.
* Arrays can be multi-dimensional, going back to the bookshelf analogy. A 2D multidimensional array would be a whole wall of bookshelves and a 3D multidimensional array would be multiple walls, similar to a room in a library.
* When they are defined, arrays must be given a type, For example, this means that an int array cannot be assigned float numbers without type conversion.
* The syntax for defining an array is:
* data_type array_name[size];
* For example:
* int x[5]; // defines an integer array called 'x', of size 5
* Would define this, an integer array of size 5:
* 1 dimensional integer array diagram
* Similarly, this:
* float y[6]; // defines a floating point array called 'y', of size 6
* Would define this, a float array of size 6:
* 1 dimensional float array diagram
* To access the elements of an array, you must use array notation. The first element of an array is at position 0, the second at position 1, etc. The last element of an array is at position size - 1. If it was not apparant from the above examples, array notation is not used when giving the size of an array during definition.
* x[0] = 10; // sets first element of the array 'x' to 10
* As you can see, once you have selected an element using array notation, you can manipulate that element as you would any variable. Here is a more complex example:
* int z[2];
* z[0] = 10;
* z[1] = 50;
* z[0] += z[1]; // z[0] now contains the integer 60
* Array Initialization
* When an array is declared, it is
* initially 'empty'; it does not contain any values. We can initialise an array as follows:
* int x[5] = {5, 7, 2, 3, 8};
* One dimensional array diagram
* {5, 7, 2, 3, 8} is called an array-initialization block. When we use an array initialization block, we do not need to specify the size of the array. The following is equivalent:
* int x = {5, 7, 2, 3, 8};
* This creates an array with 5 elements and assigns 5 to the first, 7 to the second and so on.
* Example code
* Let us look at a small code snippet that prints the number of days per month.
* #include <stdio.h>
* #define MONTHS 12
* int main(void)
* int days[MONTHS] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
* int i;
* for(i = 0; i < MONTHS; i++) {
* printf("Month %d has %d days.\n", i + 1, days[i]);
* return 0;
* Output
* Month 1 has 31 days.
* Month 2 has 28 days.
* Month 3 has 31 days.
* Month 4 has 30 days.
* Month 5 has 31 days.
* Month 6 has 30 days.
* Month 7 has 31 days.
* Month 8 has 31 days.
* Month 9 has 30 days.
* Month 10 has 31 days.
* Month 11 has 30 days.
* Month 12 has 31 days.
* (If you have not seen #define before. It is a preprocessor instruction that defines a constant called MONTHS and assigns it the value 12. A defined constant cannot be assigned to and changed, it can only be read.)
* Variable-length array
* A variable-length array, also called variable-sized or runtime-sized, is an array data structure whose length is determined at run-time (instead of at compile time).
* For example:
* void array(int n)
* int value[n];
* for (int i = 0; i < n; ++i) {
* value[i] = i;
* for (int i = 0; i < n; ++i) {
* printf("%d ", value[i]);
* printf("\n");
* int main(void)
* array(10);
* return 0;
* Multi-Dimensional Arrays
* Arrays can be multidimensional, a multidimensional array is exactly what it sounds like, an array that has been extended with increasing dimensions. For example, a 2D array will have 2 Dimensions worth of elements that could be filled with data, forming a data structure that looks like a rectangular grid. A 3D array will have 3 Dimensions of elements and form a data structure that looks like a rectangular prism.
* It should be noted that in C, multidimensional arrays are not a seperate, defined strcture . The compiler will generate code that acts as if the arrays inside it are multidimensional, but in reality. They are all just one dimensional arrays. This fact does not impact programs in most cases
* Multidimensional arrays have the same syntax as normal arrays, however, there are more array size declerators for the extra dimensions.
* data_type array_name[row_number][column_number][array_number]
* The array_number declerator is only present in the definition of 3D arrays.
* Some actual C code for a 2D array definition would be as follows:
* int a[5][6]; // two dimensional array of height 5 and length 6
* That code would generate this:
* Diagram of a 2D array
* A 3D array would be defined as follows:
* int b[5][6][3]; // three dimensional array of height 5, length 6 and width 3
* That array would look like this:
* Diagram of a 3D array
* They are assigned to and used in the same way normal arrays are. As follows:
* int a[5][6];
* int b[5][6][3];
* a[2][4] = 8;
* a[4][5] = 19;
* a[2][1] = 8 * 4;
* b[2][5][1] = 8;
* Passing Arrays to a Function
* Arrays cannot be passed to functions. If an array name is used as an argument in a function call, the address of the first element of the array is passed. The function can access the array through that address.
* Suppose we want to write a function that returns the sum of elements of the array.
* #include <stdio.h>
* int sum(int arr)
* int i, s = 0;
* for(i = 0; i < 5; i++)
* s = s + arr[i];
* return s;
* int main(void)
* int marbles = {5, 6, 2, 3, 7};
* int ans;
* ans = sum(marbles);
* printf("The total number of marbles: %d", ans);
* return 0;
* Note that the array name marbles is used as an argument to the function. The function is expecting an array because its parameter is defined as int arr. What is actually passed is the address of marbles[0]. The function then can access the array using array notation.
* How are arrays stored in memory?
* When we declare an array, space is reserved in the memory of the computer for the array. The elements of the array are stored in these memory locations. The important thing about arrays is that array elements are always stored in consecutive memory locations. We can verify this fact by printing the memory addresses of the elements. (Just like every person has a street address, every location in the memory has a memory address, usually a number, by which it can be uniquely identified.)
* #include<stdio.h>
* int main(void)
* int a = {1,2,3,4,5,6,7,8,9,10};
* int i;
* /* Print the Addresses */
* for (i = 0; i < 10; i++)
* printf("\nAddress of a[%d] : %p", i, (void *) &a[i]);
* return 0;
* OUTPUT
* Address of a[0] : ffe2
* Address of a[1] : ffe4
* Address of a[2] : ffe6
* Address of a[3] : ffe8
* Address of a[4] : ffea
* Address of a[5] : ffec
* Address of a[6] : ffee
* Address of a[7] : fff0
* Address of a[8] : fff2
* Address of a[9] : fff4
* As we can see from the output, the elements are stored at ffe2, ffe4, ffe6, etc. You might be wondering why the numbers are not consecutive. The reason is very simple. The size of the int data type in C is at least 2 bytes (depending on the implementation). In this example it is 2 bytes wide, so a[0] will be stored at ffe2, ffe3, a[1] will be stored at ffe4, ffe5, a[2] will be stored at ffe6, ffe7 and so on.
* If instead we declared an array of floats (which usually take around 4 bytes each), we will find a[0] will be stored at ffe2, ffe3, ffe4, ffe5, a[1] will be stored at ffe6, ffe7, ffe8, ffe9 and so on. Note that you may see entirely different numbers that represent the address locations.
* As you can see, the elements are consecutive. This concludes the lesson on arrays.
* The way arrays are placed in memory is so that the name of the array is actually the address of the lowest element in memory, so that higher elements are accessed by doing addition, as may be intuitive. However, a confusing part of this is that the stack grows downwards. What is meant by this is that the stack pointer (sp/esp/rsp - for accessing 16/32/64 its repectively) points to the top of the stack (often the top of the memory) allocated to the program, unless you use special settings (which you shouldn't), or you are on a special system. When you allocate to the stack, variables are allocated going downwards - so when you push (add) a value (or variable) onto the stack, sp/esp/rsp decreases to be pointing to available unused memory, and when you pop (remove) a value (or variable), esp increases to be pointing to the memory above the variable you popped. When you allocate an array, sp/esp/rsp is decreased by that array's size, and the name for the array is saved as it's offset from the frame of course. This means that, while allocated backwards, because it is allocated all at once, the array is accessed upwards. Note that the reason for the direction of stack growth is dynamic memory: dynamic memory, or heap memory, must grow upwards, as otherwise increases/decreases would have to apply to the start of the chunks of memory. Noting this, having both segments grow towards each other is the only safe way to properly allocate memory to actually maximise availability, otherwise there would be a split, making programs that utilise one more than the average suffer due to lack of available memory.
* Note: In terms of actual, physical addresses, things get more complicated due to paging, segments and something called a GDT. However, there are literally 2 things that require knowledge about these things: writing an OS and writing drivers, which is part of writing an OS.
* Assignments
Completion status: Almost complete, but you can help make it more thorough.
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