# Joint Entrance Examination/AIEEE 2009/Q070 VERNIER CALLIPER

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| Original Question by 164.100.170.4 Here's the question... q70. In an experiment the angles are required to be measured using an instrument. 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the smallest division of the main scale is half-a-degree (= 0.5°), then the least count of the instrument is (1) Half minute (2) One degree (3) Half degree (4) One minute Posted by 164.100.170.4 04:58, 24 September 2009 (UTC) Post a reply! | What's Up? Latest discussions on the forum Introductory-Physics-Help Joint Entrance Examination/2000 Screening/Q013 Dimensional analysis User:Thewinster/HHF/Introductory-Physics-Preload Joint Entrance Examination/AIEEE 2009/Q070 VERNIER CALLIPER Joint Entrance Examination/AIEEE 2009/Q077 KINEMATICS Physics-Help User:Thewinster/Sandbox/Forum-Watch User:Thewinster/Sandbox Joint Entrance Examination/2000 Screening/Q017 Electrostats - energy of a configuration Joint Entrance Examination/2000 Screening/Q028 Ball dropped from a height, graphs Joint Entrance Examination/2000 Screening/Q014 Intermediate image in a compound microscope |
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Reply to the thread, posted by 164.100.170.4
Thread post
Additional notes
29 Div of M.S = 30 Div of V.S
1 Div of V.S =
29/
30 Div of M.S
Least count = 1 Div of M.S – 1 Div V.S
1/
30 Div. of M.S
1/30 *1/2=1/60°=1minute
These comments, along with the notes on the left, were contributed by 164.100.170.4 05:02, 24 September 2009 (UTC) :