# Joint Entrance Examination/2000 Screening/Q017 Electrostats - energy of a configuration

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| Original Question by Dharav Here's the question... Three charges Q, +q and +q are placed at the vertices of a right angled isosceles triangle as shown. The net electrostatic energy of the configuration is zero if Q is equal to... ${\frac {-q}{1+{\sqrt {2}}}}$ ${\frac {-2q}{2+{\sqrt {2}}}}$ $-2q$ $+q$ Posted by Dharav 04:46, 18 August 2009 (UTC) | What's Up? Latest discussions on the forum Electricity-And-Magnetism-Help Joint Entrance Examination/2000 Screening/Q009 Magnetic field ratios in two different cases Joint Entrance Examination/2000 Screening/Q017 Electrostats - energy of a configuration Joint Entrance Examination/2000 Screening/Q023 capcitors and dielectric, equivalent capcitance Joint Entrance Examination/2000 Screening/Q031 Magnetic fields of parallel wires Joint Entrance Examination/AIEEE 2009/Q084 work done by electrostatic field Physics-Help User:Thewinster/Sandbox/Forum-Watch User:Thewinster/Sandbox Joint Entrance Examination/2000 Screening/Q009 Magnetic field ratios in two different cases Joint Entrance Examination/2000 Screening/Q032 Divergent beam passsing from a glass slab Joint Entrance Examination/2000 Screening/Q001 X Ray Tungsten filament and electrons |
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