# Joint Entrance Examination/AIEEE 2009/Q064 POTENTIAL

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| Original Question by 164.100.170.4 Here's the question... Q 64.Two point P and Q are maintained at the potentials of 10 V and –4 V respectively. The work done in moving 100 electrons from P to Q is (1) 9.60 × 10$^{–17}$ J (2) –2.24 × 10$^{–16}$ J (3) 2.24 × 10$^{–16}$ J (4) – 9.60 × 10$^{-17}$ J Posted by 164.100.170.4 04:52, 24 September 2009 (UTC) Post a reply! | What's Up? Latest discussions on the forum Electricity-And-Magnetism-Help Joint Entrance Examination/AIEEE 2009/Q072 RESISTANCE VS TEMPERATURE Joint Entrance Examination/2000 Screening/Q002 Uniform time varying magnetic field and induced electric field Joint Entrance Examination/AIEEE 2009/Q084 ELECTROSTAT Joint Entrance Examination/2000 Screening/Q012 Rotating particle with charge q mass m Joint Entrance Examination/2000 Screening/Q029 Coil of wire with conducting ring at centre and variable current Physics-Help User:Thewinster/Sandbox User:Thewinster/Sandbox/Forum-Watch Joint Entrance Examination/2000 Screening/Q006 Bohr model of an atom applied to an atom with some hypothetical particle Joint Entrance Examination/2000 Screening/Q025 Various energies of an electron in bohr model Joint Entrance Examination/2000 Screening/Q023 capcitors and dielectric, equivalent capcitance |
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Reply to the thread, posted by 164.100.170.4
Thread post
Additional notes
Solution :
Q = 100e = –100 × 1.6 × 10$^{–19}$ = –1.6 × 10$^{–17}$C
ΔV = –14 V
∴ W = QΔ V = 14 × 1.6 × 10$^{–17}$ = 2.24 × 10$^{–16}$ J
These comments, along with the notes on the left, were contributed by 164.100.170.4 04:53, 24 September 2009 (UTC) :
Reply to the thread, posted by 164.100.170.4
Thread post
Additional notes
Solution :
Q = 100e = –100 × 1.6 × 10$^{–19}$ = –1.6 × 10$^{–17}$C
ΔV = –14 V
∴ W = QΔ V = 14 × 1.6 × 10$^{–17}$ = 2.24 × 10$^{–16}$ J
These comments, along with the notes on the left, were contributed by 164.100.170.4 04:55, 24 September 2009 (UTC) :
[[Category:AIEEE 2009]
Reply to the thread, posted by 117.199.161.166
Thread post
the potential differenc between the two points is 14V . work done is q*V.Q=-100*1.6*10$^{-19}$.W=-100*1.6*10$^{-19}$*14 =-2.24 * 10$^{-16}$
Additional notes
These comments, along with the notes on the left, were contributed by 117.199.161.166 19:58, 16 December 2009 (UTC) :