# 2018 ATP Challenger China International – Nanchang – Singles

Hiroki Moriya was the defending champion but chose not to defend his title.
Quentin Halys won the title after defeating Calvin Hemery 6–3, 6–2 in the final.

## Seeds

* Evgeny Donskoy (quarterfinals)
* Jordan Thompson (semifinals)
* Quentin Halys (champion)
* Ramkumar Ramanathan (quarterfinals)
* Calvin Hemery (final)
* Go Soeda (first round)
* Tatsuma Ito (first round)
* Alex Bolt (second round)

## Draw
### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Finals

| Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| 5 | Calvin Hemery | 6 | 6 | | | | |
| | Aleksandr Nedovyesov | 3 | 4 | | | | |
| | Aleksandr Nedovyesov | 3 | 4 | 5 | Calvin Hemery | 3 | 2 |
| | | | | 3 | Quentin Halys | 6 | 6 |
| 3 | Quentin Halys | 6 | 6 | 3 | Quentin Halys | 6 | 6 |
| 2 | Jordan Thompson | 1 | 3 | | | | |

### Top half

| First round | First round | First round | First round | First round | Second round | Second round | Second round | Second round | Second round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals |
| 1 | E Donskoy | 6 | 6 | | | | | | | | | | | | | | |
| WC | Y He | 2 | 2 | | 1 | E Donskoy | 6$^2$ | 6 | 7$^7$ | | | | | | | | |
| | T-h Yang | 0 | 7$^7$ | 6 | | T-h Yang | 7$^7$ | 3 | 6$^3$ | | | | | | | | |
| | L Grigelis | 6 | 6$^5$ | 3 | | | | | | 1 | E Donskoy | 3 | 3 | | | | |
| WC | Xia Zihao | 4 | 2 | | | | | | | 5 | C Hemery | 6 | 6 | | | | |
| Q | A Escoffier | 6 | 6 | | Q | A Escoffier | 4 | 1 | | | | | | | | | |
| | A Whittington | 5 | 3 | | 5 | C Hemery | 6 | 6 | | | | | | | | | |
| 5 | C Hemery | 7 | 6 | | | | | | | | | | | 5 | C Hemery | 6 | 6 |
| 4 | R Ramanathan | 4 | 6 | 6 | | | | | | | | | | | A Nedovyesov | 3 | 4 |
| WC | Y Wu | 6 | 2 | 3 | 4 | R Ramanathan | 7 | 6 | | | | | | | | | |
| | V Šafránek | 7$^8$ | 6 | | | V Šafránek | 5 | 1 | | | | | | | | | |
| | D Wu | 6$^6$ | 2 | | | | | | | 4 | R Ramanathan | 2 | 5 | | | | |
| | L Harris | 4 | 2 | | | | | | | | A Nedovyesov | 6 | 7 | | | | |
| | A Nedovyesov | 6 | 6 | | | A Nedovyesov | 6 | 6 | | | | | | | | | |
| Q | Y-s Chung | 6 | 7$^7$ | | Q | Y-s Chung | 4 | 2 | | | | | | | | | |
| 7 | T Ito | 4 | 6$^1$ | | | | | | | | | | | | | | |

### Bottom half

| First round | First round | First round | First round | Second round | Second round | Second round | Second round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals |
| 8 | A Bolt | 6 | 6 | | | | | | | | | | | | | |
| | S-w Kwon | 2 | 3 | 8 | A Bolt | 6$^5$ | 1 | | | | | | | | | |
| | C İlkel | 4 | 4 | | P Gunneswaran | 7$^7$ | 6 | | | | | | | | | |
| | P Gunneswaran | 6 | 6 | | | | | | P Gunneswaran | 4 | 3 | | | | | |
| WC | X Gao | 6 | 0 | | | | | 3 | Q Halys | 6 | 6 | | | | | |
| | Z Li | 3 | 0$^r$ | WC | X Gao | 2 | 1 | | | | | | | | | |
| | M Safwat | 6$^5$ | 4 | 3 | Q Halys | 6 | 6 | | | | | | | | | |
| 3 | Q Halys | 7$^7$ | 6 | | | | | | | | | | 3 | Q Halys | 6 | 6 |
| 6 | G Soeda | 4 | 6$^4$ | | | | | | | | | | 2 | J Thompson | 1 | 3 |
| | R Ortega Olmedo | 6 | 7$^7$ | | R Ortega Olmedo | 6 | 6 | | | | | | | | | |
| LL | S Mukund | 6 | 6 | LL | S Mukund | 4 | 2 | | | | | | | | | |
| | Ze Zhang | 4 | 4 | | | | | | R Ortega Olmedo | 6 | 2 | 2 | | | | |
| | K Majchrzak | 5 | 2 | | | | | 2 | J Thompson | 4 | 6 | 6 | | | | |
| Q | H Grenier | 7 | 6 | Q | H Grenier | 1 | 4 | | | | | | | | | |
| | D-h Lee | 2 | 1 | 2 | J Thompson | 6 | 6 | | | | | | | | | |
| 2 | J Thompson | 6 | 6 | | | | | | | | | | | | | |