# 2015 ATP Challenger China International – Nanchang – Singles

Go Soeda was the defending champion.

## Seeds

* Lu Yen-hsun (withdrew, due to lower back injury)
* Go Soeda (first round)
* Luca Vanni (second round)
* Jürgen Zopp (quarterfinals)
* Peter Gojowczyk (champion)
* Yūichi Sugita (second round)
* Thomas Fabbiano (semifinals)
* Jordan Thompson (semifinals)

## Draw
### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Finals

| Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| 7 | Thomas Fabbiano | 6 | 6$^4$ | 6$^2$ | | | | |
| 5 | Peter Gojowczyk | 3 | 7$^7$ | 7$^7$ | | | | |
| 5 | Peter Gojowczyk | 3 | 7$^7$ | 7$^7$ | 5 | Peter Gojowczyk | 6 | 6 |
| | | | | | PR | Amir Weintraub | 2 | 1 |
| 8 | Jordan Thompson | 3 | 4 | | PR | Amir Weintraub | 2 | 1 |
| PR | Amir Weintraub | 6 | 6 | | | | | |

### Top half

| First round | First round | First round | First round | First round | Second round | Second round | Second round | Second round | Second round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals |
| | T Chen | 1 | 4 | | | | | | | | | | | | | | | |
| Q | F Tearney | 6 | 6 | | Q | F Tearney | 1 | 2 | | | | | | | | | | |
| | J Tatlot | 4 | 6$^5$ | | | A Sarkissian | 6 | 6 | | | | | | | | | | |
| | A Sarkissian | 6 | 7$^7$ | | | | | | | | A Sarkissian | 1 | 4 | | | | | |
| WC | Zhuoyang Qiu | 3 | 2 | | | | | | | 7 | T Fabbiano | 6 | 6 | | | | | |
| WC | Y He | 6 | 6 | | WC | Y He | 6 | 3 | 2 | | | | | | | | | |
| | H Moriya | 3 | 6 | 4 | 7 | T Fabbiano | 4 | 6 | 6 | | | | | | | | | |
| 7 | T Fabbiano | 6 | 0 | 6 | | | | | | | | | | 7 | T Fabbiano | 6 | 6$^4$ | 6$^2$ |
| 3 | L Vanni | 6 | 6 | | | | | | | | | | | 5 | P Gojowczyk | 3 | 7$^7$ | 7$^7$ |
| | L-c Huang | 4 | 3 | | 3 | L Vanni | 6 | 4 | 3 | | | | | | | | | |
| WC | Zhicheng Zhu | 1$^r$ | | | | N Meister | 4 | 6 | 6 | | | | | | | | | |
| | N Meister | 4 | | | | | | | | | N Meister | 2 | 2 | | | | | |
| Q | J Nedunchezhiyan | 6 | 4 | 6 | | | | | | 5 | P Gojowczyk | 6 | 6 | | | | | |
| | Gavin van Peperzeel | 1 | 6 | 3 | Q | J Nedunchezhiyan | 4 | 0 | | | | | | | | | | |
| LL | D Propoggia | 4 | 5 | | 5 | P Gojowczyk | 6 | 6 | | | | | | | | | | |
| 5 | P Gojowczyk | 6 | 7 | | | | | | | | | | | | | | | |

### Bottom half

| First round | First round | First round | First round | First round | Second round | Second round | Second round | Second round | Second round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals |
| 8 | J Thompson | 6 | 6 | | | | | | | | | | | | | | | |
| SE | D Medvedev | 1 | 4 | | 8 | J Thompson | 7$^7$ | 6 | | | | | | | | | | |
| | N Barrientos | 6 | 2 | 6 | | N Barrientos | 6$^5$ | 2 | | | | | | | | | | |
| Q | S Balaji | 3 | 6 | 1 | | | | | | 8 | J Thompson | 6 | 3 | 6 | | | | |
| | T-h Yang | 6 | 6 | | | | | | | 4 | J Zopp | 1 | 6 | 0 | | | | |
| | T Niki | 4 | 3 | | | T-h Yang | 7 | 4 | 2 | | | | | | | | | |
| | D-h Lee | 6$^2$ | 1 | | 4 | J Zopp | 5 | 6 | 6 | | | | | | | | | |
| 4 | J Zopp | 7$^7$ | 6 | | | | | | | | | | | | 8 | J Thompson | 3 | 4 |
| 6 | Y Sugita | 6 | 6 | | | | | | | | | | | | PR | A Weintraub | 6 | 6 |
| | J Eysseric | 3 | 3 | | 6 | Y Sugita | 4 | 3 | | | | | | | | | | |
| | Y Bai | 6 | 6 | | | Y Bai | 6 | 6 | | | | | | | | | | |
| WC | Yuqing Ning | 3 | 3 | | | | | | | | Y Bai | | | | | | | |
| | M Trungelliti | 1 | 6 | 1 | | | | | | PR | A Weintraub | w/o | | | | | | |
| Q | R Ghedin | 6 | 0 | 6 | Q | R Ghedin | 4 | 6$^3$ | | | | | | | | | | |
| PR | A Weintraub | 6 | 6 | | PR | A Weintraub | 6 | 7$^7$ | | | | | | | | | | |
| 2 | G Soeda | 2 | 1 | | | | | | | | | | | | | | | |