# 2018 Bangkok Challenger – Singles

Janko Tipsarević was the defending champion but chose not to defend his title.
Marcel Granollers won the title after defeating Mats Moraing 4–6, 6–3, 7–5 in the final.

## Seeds

* Yannick Maden (second round, withdrew)
* Go Soeda (first round)
* Tatsuma Ito (first round)
* Nikola Milojević (first round, retired)
* Jürgen Zopp (first round)
* Marcel Granollers (champion)
* Zhang Ze (quarterfinals, withdrew)
* Gonçalo Oliveira (second round)

## Draw
### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Finals

| Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final | Final |
| 6 | Marcel Granollers | 6 | 6 | | | | | |
| | Blaž Rola | 2 | 3 | | | | | |
| | Blaž Rola | 2 | 3 | 6 | Marcel Granollers | 4 | 6 | 7 |
| | | | | Q | Mats Moraing | 6 | 3 | 5 |
| | Aleksandr Nedovyesov | 6$^4$ | 3 | Q | Mats Moraing | 6 | 3 | 5 |
| Q | Mats Moraing | 7$^7$ | 6 | | | | | |

### Top half

| First round | First round | First round | First round | First round | Second round | Second round | Second round | Second round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals |
| 1 | Y Maden | 6 | 6 | | | | | | | | | | | | | |
| | D Popko | 4 | 4 | | 1 | Y Maden | | | | | | | | | | |
| | D-h Lee | 7 | 6 | | | D-h Lee | w/o | | | | | | | | | |
| | T-h Yang | 5 | 4 | | | | | | | D-h Lee | 2 | 4 | | | | |
| Q | F Cipolla | 3 | 6 | 6 | | | | | 6 | M Granollers | 6 | 6 | | | | |
| | D Petrović | 6 | 3 | 3 | Q | F Cipolla | 3 | 0 | | | | | | | | |
| WC | Vorachon Rakpuangchon | 2 | 1 | | 6 | M Granollers | 6 | 6 | | | | | | | | |
| 6 | M Granollers | 6 | 6 | | | | | | | | | | 6 | M Granollers | 6 | 6 |
| 3 | T Ito | 6$^2$ | 6$^1$ | | | | | | | | | | | B Rola | 2 | 3 |
| | B Rola | 7$^7$ | 7$^7$ | | | B Rola | 6 | 6 | | | | | | | | |
| | M Trungelliti | 6$^4$ | 4 | | | A Arnaboldi | 4 | 3 | | | | | | | | |
| | A Arnaboldi | 7$^7$ | 6 | | | | | | | B Rola | 7$^{12}$ | 6 | | | | |
| Q | E Karlovskiy | 6 | 6 | | | | | | Q | E Karlovskiy | 6$^{10}$ | 4 | | | | |
| WC | Patcharapol Kawin | 1 | 1 | | Q | E Karlovskiy | 6 | 6 | | | | | | | | |
| | J Jung | 6 | 6 | | | J Jung | 4 | 4 | | | | | | | | |
| 5 | J Zopp | 1 | 2 | | | | | | | | | | | | | |

### Bottom half

| First round | First round | First round | First round | First round | Second round | Second round | Second round | Second round | Second round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals |
| 8 | G Oliveira | 4 | 6 | 6 | | | | | | | | | | | | | | |
| | L Vanni | 6 | 2 | 1 | 8 | G Oliveira | 4 | 3 | | | | | | | | | | |
| | Y Takahashi | 4 | 4 | | | A Nedovyesov | 6 | 6 | | | | | | | | | | |
| | A Nedovyesov | 6 | 6 | | | | | | | | A Nedovyesov | 7 | 3 | 7$^7$ | | | | |
| WC | P Isaro | 1 | 6 | 1 | | | | | | | Z Kolář | 5 | 6 | 6$^2$ | | | | |
| | Z Kolář | 6 | 2 | 6 | | Z Kolář | 1 | 6 | 6 | | | | | | | | | |
| | M Kecmanović | 6 | 0 | | | M Kecmanović | 6 | 4 | 1 | | | | | | | | | |
| 4 | N Milojević | 3 | 0$^r$ | | | | | | | | | | | | | A Nedovyesov | 6$^4$ | 3 |
| 7 | Ze Zhang | 6 | 6 | | | | | | | | | | | | Q | M Moraing | 7$^7$ | 6 |
| WC | W Trongcharoenchaikul | 3 | 4 | | 7 | Ze Zhang | 6 | 6 | | | | | | | | | | |
| Q | D Köpfer | 5 | 6 | 6$^5$ | | M Safwat | 0 | 1 | | | | | | | | | | |
| | M Safwat | 7 | 0 | 7$^7$ | | | | | | 7 | Ze Zhang | | | | | | | |
| | Z Li | 3 | 2 | | | | | | | Q | M Moraing | w/o | | | | | | |
| | D Wu | 6 | 6 | | | D Wu | 2 | 2 | | | | | | | | | | |
| Q | M Moraing | 6 | 6 | | Q | M Moraing | 6 | 6 | | | | | | | | | | |
| 2 | G Soeda | 1 | 1 | | | | | | | | | | | | | | | |