# 1900 United States presidential election in Rhode Island

"none" is preferred when the title is sufficiently descriptive; see [[WP:SDNONE]]
Elections in Rhode Island :
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1st sp
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Gubernatorial elections
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2022 :
Ballot measures
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Question 1 :
Providence
Mayoral elections
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2002
2006
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2022 :
vte :
The 1900 United States presidential election in Rhode Island took place on November 6, 1900, as part of the 1900 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
Rhode Island overwhelmingly voted for the Republican nominee, President William McKinley, over the Democratic nominee, former U.S. Representative and 1896 Democratic presidential nominee William Jennings Bryan. McKinley won Rhode Island by a margin of 24.7% in this rematch of the 1896 presidential election. The return of economic prosperity and recent victory in the Spanish–American War helped McKinley to score a decisive victory.
Bryan had previous lost Rhode Island to McKinley four years earlier and would later lose the state again in 1908 to William Howard Taft.

## Results

1900 United States presidential election in Rhode Island :
| Party | Party | Candidate | Running mate | Popular vote | Popular vote | Electoral vote | Electoral vote |
| Party | Party | Candidate | Running mate | Count | % | Count | % |
| | Republican | William McKinley of Ohio (incumbent) | Theodore Roosevelt of New York | 33,784 | 59.74% | 4 | 100.00% |
| | Democratic | William Jennings Bryan of Nebraska | Adlai Ewing Stevenson I of Illinois | 19,812 | 35.04% | 0 | 0.00% |
| | Prohibition | John Granville Woolley of Illinois | Henry Brewer Metcalf of Rhode Island | 1,529 | 2.70% | 0 | 0.00% |
| | Socialist Labor | Joseph F. Malloney of Massachusetts | Valentine Remmel of Pennsylvania | 1,423 | 2.52% | 0 | 0.00% |
| Total | Total | Total | Total | 56,198 | 100.00% | 4 | 100.00% |