# 2014 ATP World Tour Finals – Doubles

Bob and Mike Bryan defeating Ivan Dodig and Marcelo Melo in the final, 6–7$^{(5–7)}$, 6–2, [10–7] to win the doubles tennis title at the 2014 ATP World Tour Finals. It was their fourth Tour Finals title.
David Marrero and Fernando Verdasco were the reigning champions, but did not qualify this year.

## Seeds

* Bob Bryan / Mike Bryan (champions)
* Daniel Nestor / Nenad Zimonjić (round robin)
* Alexander Peya / Bruno Soares (round robin)
* Julien Benneteau / Édouard Roger-Vasselin (semifinals)
* Jean-Julien Rojer / Horia Tecău (round robin)
* Marcel Granollers / Marc López (round robin)
* Ivan Dodig / Marcelo Melo (final)
* Łukasz Kubot / Robert Lindstedt (semifinals)

## Alternates

* Vasek Pospisil / Jack Sock (Did not play)
* Eric Butorac / Raven Klaasen (Did not play)

## Draw
### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Finals

| Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final | Final |
| 8 | Łukasz Kubot Robert Lindstedt | 6 | 4 | [6] | | | | | |
| 7 | Ivan Dodig Marcelo Melo | 4 | 6 | [10] | | | | | |
| 7 | Ivan Dodig Marcelo Melo | 4 | 6 | [10] | 7 | Ivan Dodig Marcelo Melo | 7$^7$ | 2 | [7] |
| | | | | | 1 | Bob Bryan Mike Bryan | 6$^5$ | 6 | [10] |
| 4 | Julien Benneteau Édouard Roger-Vasselin | 0 | 3 | | 1 | Bob Bryan Mike Bryan | 6$^5$ | 6 | [10] |
| 1 | Bob Bryan Mike Bryan | 6 | 6 | | | | | | |

### Group A

| | | Bryan Bryan | Peya Soares | Rojer Tecău | Kubot Lindstedt | RR W–L | Set W–L | Game W–L | Standings |
| 1 | Bob Bryan Mike Bryan | | 7–6$^{(7–3)}$, 7–6$^{(7–2)}$ | 6–7$^{(4–7)}$, 6–3, [10–6] | 6–7$^{(3–7)}$, 3–6 | 2–1 | 4–3 (57.1%) | 36–35 (50.7%) | 2 |
| 3 | Alexander Peya Bruno Soares | 6–7$^{(3–7)}$, 6–7$^{(2–7)}$ | | 6–3, 3–6, [12–10] | 4–6, 6–3, [6–10] | 1–2 | 3–5 (37.5%) | 32–33 (49.2%) | 3 |
| 5 | Jean-Julien Rojer Horia Tecău | 7–6$^{(7–4)}$, 3–6, [6–10] | 3–6, 6–3, [10–12] | | 4−6, 6−7$^{(4−7)}$ | 0–3 | 2–6 (25.0%) | 29–36 (44.6%) | 4 |
| 8 | Łukasz Kubot Robert Lindstedt | 7–6$^{(7–3)}$, 6–3 | 6–4, 3–6, [10–6] | 6−4, 7−6$^{(7−4)}$ | | 3–0 | 6–1 (85.7%) | 36–29 (55.4%) | 1 |

### Group B

| | | Nestor Zimonjić | Benneteau Roger-Vasselin | Granollers López | Dodig Melo | RR W–L | Set W–L | Game W–L | Standings |
| 2 | Daniel Nestor Nenad Zimonjić | | 4–6, 7–5, [4–10] | 6–7$^{(5–7)}$, 6–3, [11–9] | 3–6, 5–7 | 1–2 | 3–5 (37.5%) | 32–35 (47.8%) | 3 |
| 4 | Julien Benneteau Édouard Roger-Vasselin | 6–4, 5–7, [10–4] | | 4–6, 4–6 | 4–6, 6–2, [10–8] | 2–1 | 4–4 (50.0%) | 31–31 (50.0%) | 1 |
| 6 | Marcel Granollers Marc López | 7–6$^{(7–5)}$, 3–6, [9–11] | 6–4, 6–4 | | 6–7$^{(5–7)}$, 6–7$^{(12–14)}$ | 1–2 | 3–4 (42.9%) | 34–35 (49.3%) | 4 |
| 7 | Ivan Dodig Marcelo Melo | 6–3, 7–5 | 6–4, 2–6, [8–10] | 7–6$^{(7–5)}$, 7–6$^{(14–12)}$ | | 2–1 | 5–2 (71.4%) | 35–31 (53.0%) | 2 |
Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-player ties, head-to-head records; 4. in three-player ties, percentage of sets won, or of games won; 5. steering-committee decision.