# Sphericity

Sphericity is a measure of how closely the shape of an object resembles that of a perfect sphere. For example, the sphericity of the balls inside a ball bearing determines the quality of the bearing, such as the load it can bear or the speed at which it can turn without failing. Sphericity is a specific example of a compactness measure of a shape.
Sphericity applies in three dimensions; its analogue in two dimensions, such as the cross sectional circles along a cylindrical object such as a shaft, is called roundness.

## Definition

Defined by Wadell in 1935, the sphericity, $\Psi$, of an object is the ratio of the surface area of a sphere with the same volume to the object's surface area:
    $\Psi ={\frac {\pi ^{\frac {1}{3}}(6V_{p})^{\frac {2}{3}}}{A_{p}}}$
where $V_{p}$ is volume of the object and $A_{p}$ is the surface area. The sphericity of a sphere is unity by definition and, by the isoperimetric inequality, any shape which is not a sphere will have sphericity less than 1.

## Ellipsoidal objects

The sphericity, $\Psi$, of an oblate spheroid (similar to the shape of the planet Earth) is:
    $\Psi ={\frac {\pi ^{\frac {1}{3}}(6V_{p})^{\frac {2}{3}}}{A_{p}}}={\frac {2{\sqrt[{3}]{ab^{2}}}}{a+{\frac {b^{2}}{\sqrt {a^{2}-b^{2}}}}\ln {\left({\frac {a+{\sqrt {a^{2}-b^{2}}}}{b}}\right)}}},$
where a and b are the semi-major and semi-minor axes respectively.

## Derivation

Hakon Wadell defined sphericity as the surface area of a sphere of the same volume as the particle divided by the actual surface area of the particle.
First we need to write surface area of the sphere, $A_{s}$ in terms of the volume of the object being measured, $V_{p}$
    $A_{s}^{3}=\left(4\pi r^{2}\right)^{3}=4^{3}\pi ^{3}r^{6}=4\pi \left(4^{2}\pi ^{2}r^{6}\right)=4\pi \cdot 3^{2}\left({\frac {4^{2}\pi ^{2}}{3^{2}}}r^{6}\right)=36\pi \left({\frac {4\pi }{3}}r^{3}\right)^{2}=36\,\pi V_{p}^{2}$
therefore
    $A_{s}=\left(36\,\pi V_{p}^{2}\right)^{\frac {1}{3}}=36^{\frac {1}{3}}\pi ^{\frac {1}{3}}V_{p}^{\frac {2}{3}}=6^{\frac {2}{3}}\pi ^{\frac {1}{3}}V_{p}^{\frac {2}{3}}=\pi ^{\frac {1}{3}}\left(6V_{p}\right)^{\frac {2}{3}}$
hence we define $\Psi$ as:
    $\Psi ={\frac {A_{s}}{A_{p}}}={\frac {\pi ^{\frac {1}{3}}\left(6V_{p}\right)^{\frac {2}{3}}}{A_{p}}}$

## Sphericity of common objects

| Name | Volume | Surface area | Sphericity |
| Sphere | ${\frac {4}{3}}\pi r^{3}$ | $4\pi \,r^{2}$ | 1 |
| Disdyakis triacontahedron | ${\frac {180}{11}}\left(5+4{\sqrt {5}}\right)\,s^{3}$ | ${\frac {180}{11}}{\sqrt {179-24{\sqrt {5}}}}\,s^{2}$ | ${\frac {\left(\left(5+4{\sqrt {5}}\right)^{2}{\frac {11\pi }{5}}\right)^{\frac {1}{3}}}{\sqrt {179-24{\sqrt {5}}}}}\approx 0.9857$ |
| Rhombic triacontahedron | $4{\sqrt {5+2{\sqrt {5}}}}\,s^{3}$ | $12{\sqrt {5}}\,s^{2}$ | ${\frac {\pi ^{\frac {1}{3}}\left(24{\sqrt {5+2{\sqrt {5}}}}\right)^{\frac {2}{3}}}{12{\sqrt {5}}}}\approx 0.9609$ |
| Icosahedron | ${\frac {5}{12}}\left(3+{\sqrt {5}}\right)\,s^{3}$ | $5{\sqrt {3}}\,s^{2}$ | $\left({\frac {\left(3+{\sqrt {5}}\right)^{2}\pi }{60{\sqrt {3}}}}\right)^{\frac {1}{3}}\approx 0.939$ |
| Dodecahedron | ${\frac {1}{4}}\left(15+7{\sqrt {5}}\right)\,s^{3}$ | $3{\sqrt {25+10{\sqrt {5}}}}\,s^{2}$ | $\left({\frac {\left(15+7{\sqrt {5}}\right)^{2}\pi }{12\left(25+10{\sqrt {5}}\right)^{\frac {3}{2}}}}\right)^{\frac {1}{3}}\approx 0.910$ |
| Ideal torus $(R=r)$ | $2\pi ^{2}Rr^{2}=2\pi ^{2}\,r^{3}$ | $4\pi ^{2}Rr=4\pi ^{2}\,r^{2}$ | $\left({\frac {9}{4\pi }}\right)^{\frac {1}{3}}\approx 0.894$ |
| Ideal cylinder $(h=2\,r)$ | $\pi \,r^{2}h=2\pi \,r^{3}$ | $2\pi \,r(r+h)=6\pi \,r^{2}$ | $\left({\frac {2}{3}}\right)^{\frac {1}{3}}\approx 0.874$ |
| Octahedron | ${\frac {1}{3}}{\sqrt {2}}\,s^{3}$ | $2{\sqrt {3}}\,s^{2}$ | $\left({\frac {\pi }{3{\sqrt {3}}}}\right)^{\frac {1}{3}}\approx 0.846$ |
| Hemisphere (half sphere) | ${\frac {2}{3}}\pi \,r^{3}$ | $3\pi \,r^{2}$ | $\left({\frac {16}{27}}\right)^{\frac {1}{3}}\approx 0.840$ |
| Cube (hexahedron) | $\,s^{3}$ | $6\,s^{2}$ | $\left({\frac {\pi }{6}}\right)^{\frac {1}{3}}\approx 0.806$ |
| Ideal cone $(h=2{\sqrt {2}}r)$ | ${\frac {1}{3}}\pi \,r^{2}h={\frac {2{\sqrt {2}}}{3}}\pi \,r^{3}$ | $\pi \,r(r+{\sqrt {r^{2}+h^{2}}})=4\pi \,r^{2}$ | $\left({\frac {1}{2}}\right)^{\frac {1}{3}}\approx 0.794$ |
| Tetrahedron | ${\frac {\sqrt {2}}{12}}\,s^{3}$ | ${\sqrt {3}}\,s^{2}$ | $\left({\frac {\pi }{6{\sqrt {3}}}}\right)^{\frac {1}{3}}\approx 0.671$ |