# 1869 Iowa gubernatorial election

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The 1869 Iowa gubernatorial election was held on October 12, 1869. Incumbent Republican Samuel Merrill defeated Democratic nominee George Gillespie with 62.93% of the vote.

## General election
### Candidates

* Samuel Merrill, Republican
* George Gillespie, Democratic

### Results

1869 Iowa gubernatorial election :
| Party | Party | Candidate | Votes | % |
| | Republican | Samuel Merrill (incumbent) | 97,243 | 62.93% |
| | Democratic | George Gillespie | 57,287 | 37.07% |
| Majority | Majority | Majority | 39,956 | |
| Turnout | Turnout | Turnout | | |
| | Republican hold | Republican hold | Swing | |