# 2017 ATP Finals – Doubles

Defending champions Henri Kontinen and John Peers successfully defended their title, defeating Łukasz Kubot and Marcelo Melo in the final, 6–4, 6–2 to win the doubles tennis title at the 2017 ATP Finals.
Melo secured the year-end world No. 1 doubles ranking for the second time when he and Kubot won their first round-robin match.

## Seeds

* Łukasz Kubot / Marcelo Melo (final)
* Henri Kontinen / John Peers (champions)
* Jean-Julien Rojer / Horia Tecău (round robin)
* Jamie Murray / Bruno Soares (semifinals)
* Bob Bryan / Mike Bryan (round robin)
* Pierre-Hugues Herbert / Nicolas Mahut (round robin, withdrew)
* Ivan Dodig / Marcel Granollers (round robin, withdrew)
* Ryan Harrison / Michael Venus (semifinals)

## Alternates

* Oliver Marach / Mate Pavić (replaced Dodig/Granollers, round robin)
* Raven Klaasen / Rajeev Ram (replaced Herbert/Mahut, round robin)

## Draw
### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Finals

| Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| 4 | Jamie Murray Bruno Soares | 6$^2$ | 2 | | | | |
| 2 | Henri Kontinen John Peers | 7$^7$ | 6 | | | | |
| 2 | Henri Kontinen John Peers | 7$^7$ | 6 | 2 | Henri Kontinen John Peers | 6 | 6 |
| | | | | 1 | Łukasz Kubot Marcelo Melo | 4 | 2 |
| 8 | Ryan Harrison Michael Venus | 1 | 4 | 1 | Łukasz Kubot Marcelo Melo | 4 | 2 |
| 1 | Łukasz Kubot Marcelo Melo | 6 | 6 | | | | |

### Woodbridge/Woodforde group

| | | Kubot Melo | Murray Soares | Bryan Bryan | Dodig Granollers Marach Pavić | RR W–L | Set W–L | Game W–L | Standings |
| 1 | Łukasz Kubot Marcelo Melo | | 2–6, 4–6 | 6–4, 6–3 | 7–6$^{(7–2)}$, 6–4 (w/ Dodig/Granollers) | 2–1 | 4–2 (66.7%) | 31–29 (51.7%) | 2 |
| 4 | Jamie Murray Bruno Soares | 6–2, 6–4 | | 5–7, 7–6$^{(7–3)}$, [8–10] | 6–1, 6–1 (w/ Dodig/Granollers) | 2–1 | 5–2 (71.4%) | 36–22 (62.1%) | 1 |
| 5 | Bob Bryan Mike Bryan | 4–6, 3–6 | 7–5, 6–7$^{(3–7)}$, [10–8] | | 4–6, 4–6 (w/ Marach/Pavić) | 1–2 | 2–5 (28.6%) | 29–36 (44.6%) | 3 |
| 7 9 | Ivan Dodig Marcel Granollers Oliver Marach Mate Pavić | 6–7$^{(2–7)}$, 4–6 (w/ Dodig/Granollers) | 1–6, 1–6 (w/ Dodig/Granollers) | 6–4, 6–4 (w/ Marach/Pavić) | | 0–2 1–0 | 0–4 (0%) 2–0 (100%) | 12–25 (32.4%) 12–8 (60%) | X 4 |
Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, then percentage of games won, then head-to-head records; 5. ATP rankings.

### Eltingh/Haarhuis group

| | | Kontinen Peers | Rojer Tecău | Herbert Mahut Klaasen Ram | Harrison Venus | RR W–L | Set W–L | Game W–L | Standings |
| 2 | Henri Kontinen John Peers | | 7–6$^{(7–3)}$, 7–6$^{(8–6)}$ | 2–6, 6–1, [10–8] (w/ Klaasen/Ram) | 4–6, 6–7$^{(8–10)}$ | 2–1 | 4–3 (57.1%) | 33–32 (50.8%) | 2 |
| 3 | Jean-Julien Rojer Horia Tecău | 6–7$^{(3–7)}$, 6–7$^{(6–8)}$ | | 6–1, 6–7$^{(7–9)}$, [8–10] (w/ Herbert/Mahut) | 3–6, 6–7$^{(5–7)}$ | 0–3 | 1–6 (14.3%) | 33–36 (47.8%) | 3 |
| 6 10 | Pierre-Hugues Herbert Nicolas Mahut Raven Klaasen Rajeev Ram | 6–2, 1–6, [8–10] (w/ Klaasen/Ram) | 1–6, 7–6$^{(9–7)}$, [10–8] (w/ Herbert/Mahut) | | 7–6$^{(7–4)}$, 4–6, [5–10] (w/ Herbert/Mahut) | 1–1 0–1 | 3–3 (50%) 1–2 (33.3%) | 20–25 (44.4%) 7–9 (43.8%) | X 4 |
| 8 | Ryan Harrison Michael Venus | 6–4, 7–6$^{(10–8)}$ | 6–3, 7–6$^{(7–5)}$ | 6–7$^{(4–7)}$, 6–4, [10–5] (w/ Herbert/Mahut) | | 3–0 | 6–1 (85.7%) | 39–30 (56.5%) | 1 |
Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, then percentage of games won, then head-to-head records; 5. ATP rankings.