Problem:
E:Subset Coloring
問題
$1$ から $N$ までの非負整数集合 $P = \{1, 2, \cdots ,N\}$ を考えます。
$P$ の全ての部分集合からなる集合族 $\mathcal{Q}$ に対し、 $\mathcal{Q}$ の各要素を以下の条件を満たすように色を塗ります。
$\mathcal{Q}$ から任意の $K$ 個の要素を選び、それらを $A_1, A_2, \cdots, A_K$ としたとき、 $A_1\cup A_2 \cup \cdots \cup A_K = P$ ならば $A_1, A_2, \cdots, A_K$ の色はすべて異なる
条件を満たすように色を塗るとき、最小で何色必要ですか? ただし答えは非常に大きくなる可能性があるので $998244353$ で割った余りを答えてください。
入力形式
入力は以下の形式で与えられる。
$N$ $K$
制約
$1 \leq N \leq 100{,}000$
$1 \leq K \leq min( 2^N,100{,}000)$
出力形式
条件を満たすように色を塗るときに必要な色の最小数を $998244353$ で割った余りを出力し、最後に改行してください。
入力例 1
2 2
出力例 1
3
$ϕ,\{1\}$ を赤、$\{2\}$ を青、$\{1,2\}$ を緑で塗ります。
入力例 2
31415 9265
出力例 2
407316974

Submitted solutions:

code_snippet: #include<bits/stdc++.h>
using namespace std;
#include <unordered_set>
#include <random>
//#define int long long
#define REP(i,m,n) for(int i=(m);i<(n);i++)
#define rep(i,n) REP(i,0,n)
#define pb push_back
#define all(a) a.begin(),a.end()
#define rall(c) (c).rbegin(),(c).rend()
#define mp make_pair
#define endl '\n'
//#define vec vector<ll>
//#define mat vector<vector<ll> >
#define fi first
#define se second
#define double long double
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll,ll> pll;
//typedef long double ld;
typedef complex<double> Complex;
const ll INF=1e9+7;
const ll MOD=998244353;
const ll inf=INF*INF;
const ll mod=MOD;
const ll MAX=100010;
const double PI=acos(-1.0);
typedef vector<vector<ll> > mat;
typedef vector<ll> vec;
double pi=M_PI;

//二分累乗

ll rui(ll a,ll b){
    ll res=1;
    ll x=a;
    while(b){
        if(b&1)res=res*x%mod;
        x=x*x%mod;
        b/=2;
    }
    return res;
}
long long extGCD(long long a,long long mod,long long &x,long long &y){
    if(mod==0){
        x=1;
        y=0;
        return a;
    }
    long long d=extGCD(mod,a%mod,y,x);
    y-=(a/mod)*x;
    return d;
}
long long invmod(long long a,long long mod){
    long long x,y;
    extGCD(a,mod,x,y);
    x%=mod;
    if(x<0)x+=mod;
    return x;
}
ll fac[MAX],finv[MAX],inv[MAX];
void combinit(){
    fac[0]=fac[1]=1;
    finv[0]=finv[1]=1;
    inv[1]=1;
    REP(i,2,MAX){
        fac[i]=fac[i-1]*i%mod;
        inv[i]=invmod(i,mod);
        finv[i]=finv[i-1]*inv[i]%mod;
    }
}
ll comb(ll n,ll k){
    if(n<k)return 0;
    if(n<0||k<0)return 0;
    return fac[n]*(finv[k]*finv[n-k]%mod)%mod;
}

void solve(){
    ll n,k;cin>>n>>k;
    combinit();
    if(k==1){
        cout<<1<<endl;
        return;
    }
    if(k>=3){
        cout<<rui(2,n)<<endl;
        return;
    }
    ll ans=n+1;
    cout<<ans<<endl;
}
signed main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    solve();
}
accuracy: 1
time_ms: 10
memory_kb: 5792
final_rank: 1

code_snippet: #include<bits/stdc++.h>
using namespace std;
#include <unordered_set>
#include <random>
//#define int long long
#define REP(i,m,n) for(int i=(m);i<(n);i++)
#define rep(i,n) REP(i,0,n)
#define pb push_back
#define all(a) a.begin(),a.end()
#define rall(c) (c).rbegin(),(c).rend()
#define mp make_pair
#define endl '\n'
//#define vec vector<ll>
//#define mat vector<vector<ll> >
#define fi first
#define se second
#define double long double
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll,ll> pll;
//typedef long double ld;
typedef complex<double> Complex;
const ll INF=1e9+7;
const ll MOD=998244353;
const ll inf=INF*INF;
const ll mod=MOD;
const ll MAX=100010;
const double PI=acos(-1.0);
typedef vector<vector<ll> > mat;
typedef vector<ll> vec;
double pi=M_PI;

//二分累乗

ll rui(ll a,ll b){
    ll res=1;
    ll x=a;
    while(b){
        if(b&1)res=res*x%mod;
        x=x*x%mod;
        b/=2;
    }
    return res;
}
long long extGCD(long long a,long long mod,long long &x,long long &y){
    if(mod==0){
        x=1;
        y=0;
        return a;
    }
    long long d=extGCD(mod,a%mod,y,x);
    y-=(a/mod)*x;
    return d;
}
long long invmod(long long a,long long mod){
    long long x,y;
    extGCD(a,mod,x,y);
    x%=mod;
    if(x<0)x+=mod;
    return x;
}
ll fac[MAX],finv[MAX],inv[MAX];
void combinit(){
    fac[0]=fac[1]=1;
    finv[0]=finv[1]=1;
    inv[1]=1;
    REP(i,2,MAX){
        fac[i]=fac[i-1]*i%mod;
        inv[i]=invmod(i,mod);
        finv[i]=finv[i-1]*inv[i]%mod;
    }
}
ll comb(ll n,ll k){
    if(n<k)return 0;
    if(n<0||k<0)return 0;
    return fac[n]*(finv[k]*finv[n-k]%mod)%mod;
}

void solve(){
    ll n,k;cin>>n>>k;
    combinit();
    if(k==1){
        cout<<1<<endl;
        return;
    }
    if(k>=3){
        cout<<rui(2,n)<<endl;
        return;
    }
    ll ans=n%2;
    for(int i=n;i>=(n+1)/2;i--){
        ans=(ans+comb(n,i))%mod;
    }
    if(ans<0)ans+=mod;
    cout<<ans<<endl;
}
signed main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    solve();
}
accuracy: 0.14583333333333334
time_ms: 10
memory_kb: 5788
final_rank: 5

code_snippet: #include<bits/stdc++.h>
using namespace std;
#include <unordered_set>
#include <random>
//#define int long long
#define REP(i,m,n) for(int i=(m);i<(n);i++)
#define rep(i,n) REP(i,0,n)
#define pb push_back
#define all(a) a.begin(),a.end()
#define rall(c) (c).rbegin(),(c).rend()
#define mp make_pair
#define endl '\n'
//#define vec vector<ll>
//#define mat vector<vector<ll> >
#define fi first
#define se second
#define double long double
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll,ll> pll;
//typedef long double ld;
typedef complex<double> Complex;
const ll INF=1e9+7;
const ll MOD=998244353;
const ll inf=INF*INF;
const ll mod=MOD;
const ll MAX=100010;
const double PI=acos(-1.0);
typedef vector<vector<ll> > mat;
typedef vector<ll> vec;
double pi=M_PI;

//二分累乗

ll rui(ll a,ll b){
    ll res=1;
    ll x=a;
    while(b){
        if(b&1)res=res*x%mod;
        x=x*x%mod;
        b/=2;
    }
    return res;
}
long long extGCD(long long a,long long mod,long long &x,long long &y){
    if(mod==0){
        x=1;
        y=0;
        return a;
    }
    long long d=extGCD(mod,a%mod,y,x);
    y-=(a/mod)*x;
    return d;
}
long long invmod(long long a,long long mod){
    long long x,y;
    extGCD(a,mod,x,y);
    x%=mod;
    if(x<0)x+=mod;
    return x;
}
ll fac[MAX],finv[MAX],inv[MAX];
void combinit(){
    fac[0]=fac[1]=1;
    finv[0]=finv[1]=1;
    inv[1]=1;
    REP(i,2,MAX){
        fac[i]=fac[i-1]*i%mod;
        inv[i]=invmod(i,mod);
        finv[i]=finv[i-1]*inv[i]%mod;
    }
}
ll comb(ll n,ll k){
    if(n<k)return 0;
    if(n<0||k<0)return 0;
    return fac[n]*(finv[k]*finv[n-k]%mod)%mod;
}

void solve(){
    ll n,k;cin>>n>>k;
    combinit();
    if(k==1){
        cout<<1<<endl;
        return;
    }
    if(k>=3){
        cout<<rui(2,n)<<endl;
        return;
    }
    ll ans=n%2;
    for(int i=n;i>=(n+1)/2;i--){
        ans=(ans+comb(n,i))%mod;
    }
    cout<<ans<<endl;
}
signed main(){
    cin.tie(0);
    ios::sync_with_stdio(false);
    solve();
}
accuracy: 0.14583333333333334
time_ms: 10
memory_kb: 5716
final_rank: 4

code_snippet: #pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<unordered_set>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
#include<array>
#include<chrono>
using namespace std;

//#define int long long
typedef long long ll;

typedef unsigned long long ul;
typedef unsigned int ui;
constexpr ll mod = 998244353;
//constexpr ll mod = 1000000007;
const ll INF = mod * mod;
typedef pair<int, int>P;

#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;

template<typename T>
void chmin(T& a, T b) {
	a = min(a, b);
}
template<typename T>
void chmax(T& a, T b) {
	a = max(a, b);
}
template<typename T>
void cinarray(vector<T>& v) {
	rep(i, v.size())cin >> v[i];
}
template<typename T>
void coutarray(vector<T>& v) {
	rep(i, v.size()) {
		if (i > 0)cout << " "; cout << v[i];
	}
	cout << "\n";
}
ll mod_pow(ll x, ll n, ll m = mod) {
	if (n < 0) {
		ll res = mod_pow(x, -n, m);
		return mod_pow(res, m - 2, m);
	}
	if (abs(x) >= m)x %= m;
	if (x < 0)x += m;
	//if (x == 0)return 0;
	ll res = 1;
	while (n) {
		if (n & 1)res = res * x % m;
		x = x * x % m; n >>= 1;
	}
	return res;
}
struct modint {
	int n;
	modint() :n(0) { ; }
	modint(ll m) {
		if (m < 0 || mod <= m) {
			m %= mod; if (m < 0)m += mod;
		}
		n = m;
	}
	operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
bool operator<(modint a, modint b) { return a.n < b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
	if (n == 0)return modint(1);
	modint res = (a * a) ^ (n / 2);
	if (n % 2)res = res * a;
	return res;
}

ll inv(ll a, ll p) {
	return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
modint operator/=(modint& a, modint b) { a = a / b; return a; }
const int max_n = 1 << 20;
modint fact[max_n], factinv[max_n];
void init_f() {
	fact[0] = modint(1);
	for (int i = 0; i < max_n - 1; i++) {
		fact[i + 1] = fact[i] * modint(i + 1);
	}
	factinv[max_n - 1] = modint(1) / fact[max_n - 1];
	for (int i = max_n - 2; i >= 0; i--) {
		factinv[i] = factinv[i + 1] * modint(i + 1);
	}
}
modint comb(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[b] * factinv[a - b];
}
modint combP(int a, int b) {
	if (a < 0 || b < 0 || a < b)return 0;
	return fact[a] * factinv[a - b];
}

ll gcd(ll a, ll b) {
	a = abs(a); b = abs(b);
	if (a < b)swap(a, b);
	while (b) {
		ll r = a % b; a = b; b = r;
	}
	return a;
}
typedef long double ld;
typedef pair<ld, ld> LDP;
const ld eps = 1e-8;
const ld pi = acosl(-1.0);
template<typename T>
void addv(vector<T>& v, int loc, T val) {
	if (loc >= v.size())v.resize(loc + 1, 0);
	v[loc] += val;
}
/*const int mn = 100005;
bool isp[mn];
vector<int> ps;
void init() {
	fill(isp + 2, isp + mn, true);
	for (int i = 2; i < mn; i++) {
		if (!isp[i])continue;
		ps.push_back(i);
		for (int j = 2 * i; j < mn; j += i) {
			isp[j] = false;
		}
	}
}*/

//[,val)
template<typename T>
auto prev_itr(set<T>& st, T val) {
	auto res = st.lower_bound(val);
	if (res == st.begin())return st.end();
	res--; return res;
}

//[val,)
template<typename T>
auto next_itr(set<T>& st, T val) {
	auto res = st.lower_bound(val);
	return res;
}
using mP = pair<modint, modint>;


int dx[4] = { 1,0,-1,0 };
int dy[4] = { 0,1,0,-1 };
//-----------------------------------------


void solve(){
	int n, k; cin >> n >> k;
	if (k >= 3) {
		modint ans = mod_pow(2, n);
		cout << ans << "\n";
		return;
	}
	if (k == 1) {
		cout << 1 << "\n"; return;
	}
	if (n == 1) {
		cout << 2 << "\n"; return;
	}
	cout << n+1 << "\n";
}

signed main() {
	ios::sync_with_stdio(false);
	cin.tie(0);
	//cout << fixed << setprecision(10);
	init_f();
	//init();
	//while(true)
	//expr();
	//int t; cin >> t; rep(i, t)
	solve();
	return 0;
}
accuracy: 1
time_ms: 10
memory_kb: 11640
final_rank: 2

code_snippet: #include<bits/stdc++.h>
using namespace std;
typedef unsigned long long int ull;
typedef long long int ll;
typedef pair<ll,ll> pll;
typedef long double D;
//typedef complex<D> P;
#define F first
#define S second
//const ll MOD=1000000007;
const ll MOD=998244353;

template<typename T,typename U>istream & operator >> (istream &i,pair<T,U> &A){i>>A.F>>A.S; return i;}
template<typename T>istream & operator >> (istream &i,vector<T> &A){for(auto &I:A){i>>I;} return i;}
template<typename T,typename U>ostream & operator << (ostream &o,const pair<T,U> &A){o<<A.F<<" "<<A.S; return o;}
template<typename T>ostream & operator << (ostream &o,const vector<T> &A){int i=A.size(); for(auto &I:A){o<<I<<(--i?" ":"");} return o;}
template<typename T,typename U>T & chmax(T &a,const U &b){if(a<b){a=b;} return a;}
template<typename T,typename U>T & chmin(T &a,const U &b){if(b<a){a=b;} return a;}




template<long long int mod=1000000007>
struct Mod_Int{
    typedef long long int ll;
    typedef pair<ll,ll> pll;
    typedef Mod_Int<mod> M;
    ll a;
    
    ll mod_pow(ll a,ll x){
        a%=mod;
        ll ans=1;
        for(int i=0;i<63;i++){
            if(x>>i&1){ans*=a; ans%=mod;}
            a*=a;
            a%=mod;
        }
        return ans;
    }
    
    pll Ex_gcd(ll a,ll b){
        if(b==0){return {1,0};}
        pll ret=Ex_gcd(b,a%b);
        ret.F-=a/b*ret.S;
        return {ret.S,ret.F};
    }
    
    ll prime_R(ll a){
        return mod_pow(a,mod-2);
    }
    
    ll R(ll a){
        ll ret=Ex_gcd(a,mod).F;
        ret%=mod;
        if(ret<0){ret+=mod;}
        return ret;
    }
    
    Mod_Int(ll A=1):a(A){
        a%=mod;
        if(a<0){a+=mod;}
    }
    
    Mod_Int(const M &b):a(b.a){}
    
    M & operator += (const M &b){
        a+=b.a;
        if(a>=mod){a-=mod;}
        return *this;
    }
    
    M operator + (const M &b) const {
        M c=*this;
        return c+=b;
    }
    
    M & operator -= (const M &b){
        a-=b.a;
        if(a<0){a+=mod;}
        return *this;
    }
    
    M operator - (const M &b) const {
        M c=*this;
        return c-=b;
    }
    
    M & operator *= (const M &b){
        (a*=b.a)%=mod;
        return *this;
    }
    
    M operator * (const M &b) const {
        M c=*this;
        return c*=b;
    }
    
    M & operator /= (const M &b){
        (a*=R(b.a))%=mod;
        return *this;
    }
    
    M operator / (const M &b) const {
        M c=*this;
        return c/=b;
    }
    
    M & mod_pow_equal(ll x){
        ll ans=1;
        while(x>0){
            if(x&1){ans*=a; ans%=mod;}
            a*=a;
            a%=mod;
            x>>=1;
        }
        a=ans;
        return *this;
    }
    
    M mod_pow(ll x){
        M c(a);
        return c.mod_pow_equal(x);
    }
    
    bool operator == (const M &b) const {return a==b.a;}
    
    bool operator != (const M &b) const {return a!=b.a;}
    
    bool operator <= (const M &b) const {return a<=b.a;}
    
    bool operator < (const M &b) const {return a<b.a;}
    
    bool operator > (const M &b) const {return a>b.a;}
    
    bool operator >= (const M &b) const {return a>=b.a;}
    
    M & operator = (const M &b){
        a=b.a;
        return *this;
    }
    
    M & operator = (const ll &b){
        (a=b)%=mod;
        if(a<0){a+=mod;}
        return *this;
    }
};

template<long long MOD>istream & operator >> (istream &i,Mod_Int<MOD> &A){ll a; cin>>a; A=Mod_Int<MOD>(a); return i;}
template<long long MOD>ostream & operator << (ostream &i,const Mod_Int<MOD> &A){i<<A.a; return i;}


class comb{
private:
    ll mod;
    ll mx;
    vector<ll> F;
    vector<ll> FR;
    
public:
    comb(ll mod=1000000007,ll mx=100000):mod(mod),mx(mx),F(mx+1,1),FR(mx+1,1){
        mk_F();
    }
    
    ll mod_pow(ll a,ll x){
        a%=mod;
        ll ans=1;
        while(x>0){
            if(x&1){ans*=a; ans%=mod;}
            a*=a;
            a%=mod;
            x>>=1;
        }
        return ans;
    }
    
    pll Ex_gcd(ll a,ll b){
        if(b==0){return {1,0};}
        pll ret=Ex_gcd(b,a%b);
        ret.F-=a/b*ret.S;
        return {ret.S,ret.F};
    }
    
    ll prime_R(ll a){
        return mod_pow(a,mod-2);
    }
    
    ll R(ll a){
        ll ret=Ex_gcd(a,mod).F;
        ret%=mod;
        if(ret<0){ret+=mod;}
        return ret;
    }
    
    void mk_F(){
        for(ll i=1;i<=mx;i++){F[i]=F[i-1]*i%mod; FR[i]=R(F[i]);}
    }
    
    ll c(ll n,ll k){
        if(n<k || k<0 || n<0){return 0;}
        if(n==k || k==0){return 1;}
        return F[n]*FR[n-k]%mod*FR[k]%mod;
    }
    
    //mod must be prime
    ll Lucas_C(ll n,ll m){
        ll ret=1;
        while(n>0 || m>0){
            ret*=c(n%mod,m%mod);
            ret%=mod;
            n/=mod; m/=mod;
        }
        return ret;
    }
    
    ll Stirling(ll n,ll k){
        ll ret=0;
        for(ll i=1;i<=k;i++){
            if((k-i)%2){ret-=c(k,i)*mod_pow(i,n)%mod;}
            else{ret+=c(k,i)*mod_pow(i,n)%mod;}
            ret%=mod;
        }
        ret*=R(F[k]);
        ret%=mod;
        if(ret<0){ret+=mod;}
        return ret;
    }
    
    ll Bell(ll n,ll k){
        ll ret=0;
        for(ll i=1;i<=k;i++){ret+=Stirling(n,i); ret%=mod;}
        return ret;
    }
};


using Int=Mod_Int<MOD>;

comb C(MOD,500000);


int main(){
  cin.tie(0);
  ios::sync_with_stdio(false);

  ll N,K;
  cin>>N>>K;
  if(K>=3){cout<<Int(2).mod_pow(N)<<endl;}
  else if(K==1){cout<<1<<endl;}
  else if(K==2){cout<<N+1<<endl;}

  return 0;
}
accuracy: 1
time_ms: 100
memory_kb: 10836
final_rank: 3