prompter: Make a python program that takes all the files from a folder and renamed them all with numbers in order, like: 1, 2, 3 ...

assistant: To rename all the files in a directory with numbers in order, we can use the following Python program:
```python
import os

path = '/path/to/folder'
files = os.listdir(path)

for index, file in enumerate(files):
    os.rename(os.path.join(path, file), os.path.join(path, ''.join([str(index + 1), '.jpg'])))
```

The above code will rename all the files in the directory specified by 'path' with numbers in order, starting with 1. The extension of the files can be changed in the code by modifying the '.jpg' part. The code uses the 'os' module to get the list of files in the directory and to rename the files.

prompter: But I don't want to change the code for every file extension! I just want to run this once and just keep filetypes as they were

assistant: Got it! To rename all files regardless of the extension, the following python code can be used:

```python
import os

path = '/path/to/folder'
files = os.listdir(path)

for index, file in enumerate(files):
    base_file, ext = os.path.splitext(file)
    os.rename(os.path.join(path, file), os.path.join(path, ''.join([str(index + 1), ext])))
```

By using `os.path.splitext()`, the code splits the extension from the file name, and then puts it back to the new file name.

assistant: Sure, you can modify the code to keep the original file extension by using the os.path.splitext function. Here's the updated code:
``` 
import os

path = '/path/to/folder'
files = os.listdir(path)

for index, file in enumerate(files):
    file_name, file_ext = os.path.splitext(file)
    os.rename(os.path.join(path, file), os.path.join(path, ''.join([str(index + 1), file_ext])))
``` 
This code uses the os.path.splitext function to split the file name and its extension. The file_name variable stores the file name without the extension, while file_ext stores the file extension including the period. The code then appends the index value to the file name and adds the original file extension to the end, resulting in a new file name with the same extension as the original file.

prompter: Write a story about the league of legends champion Syndra

assistant: Sure!

```python
from pathlib import Path

# path to the folder
folder = "..."  # TODO: change
folder = Path(folder)  # convert to path for simplicity

# get all file paths
files = (file for file in folder.iterdir() if file.is_file())

# iterate and rename
for i, file in enumerate(files, start=1):  # start numbering from 1 as requested
    # new file name with extension kept as it was before
    new_file = file.with_stem(str(i))
    # comment out below assert if overwriting is okay
    assert not new_file.exists(), (
        f"The new name '{new_file}' for file '{file}' already exists, will not overwrite!"
    )
    # rename
    file.rename(new_file)
```

prompter: Nice. Will this code run into an error if a file does not have a file extension?

assistant: Good question! Yes, this code assumes that all files have a file extension, and if a file does not have an extension, it will raise an error. To handle files without extensions, you can modify the line that creates the new file name to something like this:
``` 
new_file = file.with_stem(str(i)).with_suffix(file.suffix)
``` 
This will add the original file's extension to the new name even if it doesn't have a stem (filename before the extension). Here is the modified code:
```
from pathlib import Path

# path to the folder
folder = "..."  # TODO: change
folder = Path(folder)  # convert to path for simplicity

# get all file paths
files = (file for file in folder.iterdir() if file.is_file())

# iterate and rename
for i, file in enumerate(files, start=1):  # start numbering from 1 as requested
    # new file name with extension kept as it was before
    new_file = file.with_stem(str(i)).with_suffix(file.suffix)
    # comment out below assert if overwriting is okay
    assert not new_file.exists(), (
        f"The new name '{new_file}' for file '{file}' already exists, will not overwrite!"
    )
    # rename
    file.rename(new_file)
```
This should work even if some files in the folder don't have a file extension.

assistant: Here is a Python program that takes all the files from a folder and renames them all with numbers in order:
  


import os

# Set the folder path and get a list of all the files in the folder
folder_path = '/path/to/folder'
file_list = os.listdir(folder_path)

# Sort the file list alphabetically
file_list.sort()

# Initialize a counter variable
count = 1

# Loop through each file in the list
for file_name in file_list:
    # Create the new file name by adding the count and the file extension
    file_ext = os.path.splitext(file_name)[1]
    new_file_name = str(count) + file_ext

    # Create the full file paths for the old and new file names
    old_file_path = os.path.join(folder_path, file_name)
    new_file_path = os.path.join(folder_path, new_file_name)

    # Rename the file
    os.rename(old_file_path, new_file_path)

    # Increment the counter
    count += 1



Make sure to replace /path/to/folder with the actual path to the folder that contains the files you want to rename. Also note that this program will sort the file names alphabetically before renaming them, so if you want a specific order you should name your files accordingly.

prompter: That's a lot of text! Please just provide a script within a code block (with Python syntax highlighting enabled).

Furthermore, I do not just want them to be named 1, 2, 3, 4 anymore but instead I want to prefix the names of the files with 01_, 02_, 03_ and so on.
Write a CLI Parser for it using argparse and add a --dry-run option. The program is allowed to overwrite files (or it can assume there will be no such conflicts). It should also check at the start whether or not the files are already appended with such numbers 01_ etc.
If any single file does not follow such naming convention, then the program is allowed to prepend the appropriate prefix to all the files (additionally if need be).
If there are more than 99 files, then the number of leading zeros should be increased appropriately.

Do you see any potential issues with this specification or have any questions? If not, then please proceed to writing the code.