user-0 提问: 菜鸟求助

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user: user-1
content: LZ 这样跟你讲：  为什么a=%d    意思是  你定义是 相当于定义了整形的 a  和  b    然后没有赋值 你那个scanf（）语句就相当于输出的整数然后给你定义的整形字母 赋值，  所以相当于你输入的十进制数等于 给整形赋值十进制，明白？？？？ 了解？？？LZ？？？

user: user-2
content: 空白字符会使scanf()函数在读操作中略去输入中的一个或多个空白字符，空白符可以是space,tab,newline等等，直到第一个非空白符出现为止。一个非空白字符会使scanf()函数在读入时剔除掉与这个非空白字符相同的字符。

user: user-2
content: 引用 3 楼 qq_34274794 的回复:[quote=引用 1 楼 qq423399099 的回复:] 空白字符会使scanf()函数在读操作中略去输入中的一个或多个空白字符，空白符可以是space,tab,newline等等，直到第一个非空白符出现为止。一个非空白字符会使scanf()函数在读入时剔除掉与这个非空白字符相同的字符。 如果我在中间加的是%*c，然后我输入两个逗号为什么会导致第二个数字读取的是1呢？[/quote] 楼主贴一下代码

user: user-0
content: 引用 3 楼 qq_34274794 的回复:[quote=引用 1 楼 qq423399099 的回复:] 空白字符会使scanf()函数在读操作中略去输入中的一个或多个空白字符，空白符可以是space,tab,newline等等，直到第一个非空白符出现为止。一个非空白字符会使scanf()函数在读入时剔除掉与这个非空白字符相同的字符。 如果我在中间加的是%*c，然后我输入两个逗号为什么会导致第二个数字读取的是1呢？[/quote] 我用的是DEVc++    好像所有没有读入的随机值都是1

user: user-3
content: Visual C++ 2010 Express简体中文版http://pan.baidu.com/s/1bnwRVLt  参考C:\Program Files\Microsoft Visual Studio 10.0\VC\crt\src\input.c的内容。

user: user-3
content: Format Specification Fields: scanf and wscanf Functions A format specification has the following form:  % [width] [{h | l | I64 | L}]type  The format argument specifies the interpretation of the input and can contain one or more of the following:   White-space characters: blank (' '); tab ('\t'); or newline ('\n'). A white-space character causes scanf to read, but not store, all consecutive white-space characters in the input up to the next non–white-space character. One white-space character in the format matches any number (including 0) and combination of white-space characters in the input.   Non–white-space characters, except for the percent sign (%). A non–white-space character causes scanf to read, but not store, a matching non–white-space character. If the next character in stdin does not match, scanf terminates.   Format specifications, introduced by the percent sign (%). A format specification causes scanf to read and convert characters in the input into values of a specified type. The value is assigned to an argument in the argument list.  The format is read from left to right. Characters outside format specifications are expected to match the sequence of characters in stdin; the matching characters in stdin are scanned but not stored. If a character in stdin conflicts with the format specification, scanf terminates, and the character is left in stdin as if it had not been read.  When the first format specification is encountered, the value of the first input field is converted according to this specification and stored in the location that is specified by the first argument. The second format specification causes the second input field to be converted and stored in the second argument, and so on through the end of the format string.  An input field is defined as all characters up to the first white-space character (space, tab, or newline), or up to the first character that cannot be converted according to the format specification, or until the field width (if specified) is reached. If there are too many arguments for the given specifications, the extra arguments are evaluated but ignored. The results are unpredictable if there are not enough arguments for the format specification.  Each field of the format specification is a single character or a number signifying a particular format option. The type character, which appears after the last optional format field, determines whether the input field is interpreted as a character, a string, or a number.   The simplest format specification contains only the percent sign and a type character (for example, %s). If a percent sign (%) is followed by a character that has no meaning as a format-control character, that character and the following characters (up to the next percent sign) are treated as an ordinary sequence of characters, that is, a sequence of characters that must match the input. For example, to specify that a percent-sign character is to be input, use %%.  An asterisk (*) following the percent sign suppresses assignment of the next input field, which is interpreted as a field of the specified type. The field is scanned but not stored.

user: user-0
content: 引用 1 楼 qq423399099 的回复:空白字符会使scanf()函数在读操作中略去输入中的一个或多个空白字符，空白符可以是space,tab,newline等等，直到第一个非空白符出现为止。一个非空白字符会使scanf()函数在读入时剔除掉与这个非空白字符相同的字符。 如果我在中间加的是%*c，然后我输入两个逗号为什么会导致第二个数字读取的是1呢？