user-0 提问: 求嵌入式平台下的加密解密算法

回复:
user: user-1
content: MD5只是摘要算法，不是加密算法，你可以用DES，3DES，速度非常快，适合嵌入式设备，还有AES

user: user-0
content: 要求最好没有什么依赖库，C语音平台...

user: user-2
content: 引用 6 楼 chenandczh 的回复:[quote=引用 3 楼 jwj070524 的回复:] 我以前看飞鸽传书的代码时，传文件用blowfish加密的。 这个讲解一下～ [/quote] 网上有源码的啊，Google一下，blowfish source code就出来了

user: user-0
content: 引用 9 楼 zhao4zhong1 的回复:  老赵，又来刷分了？

user: user-3
content: #include <stdio.h> #include <math.h> #include <string.h> #include <memory.h> const unsigned int s[4][4]={{7,12,17,22},{5,9,14,20},{4,11,16,23},{6,10,15,21}}; const unsigned long t[64]={//t[i]=4294967296*fabs(sin(i+1));  0xd76aa478,0xe8c7b756,0x242070db,0xc1bdceee,0xf57c0faf,0x4787c62a,0xa8304613,0xfd469501,  0x698098d8,0x8b44f7af,0xffff5bb1,0x895cd7be,0x6b901122,0xfd987193,0xa679438e,0x49b40821,  0xf61e2562,0xc040b340,0x265e5a51,0xe9b6c7aa,0xd62f105d,0x02441453,0xd8a1e681,0xe7d3fbc8,  0x21e1cde6,0xc33707d6,0xf4d50d87,0x455a14ed,0xa9e3e905,0xfcefa3f8,0x676f02d9,0x8d2a4c8a,  0xfffa3942,0x8771f681,0x6d9d6122,0xfde5380c,0xa4beea44,0x4bdecfa9,0xf6bb4b60,0xbebfbc70,  0x289b7ec6,0xeaa127fa,0xd4ef3085,0x04881d05,0xd9d4d039,0xe6db99e5,0x1fa27cf8,0xc4ac5665,  0xf4292244,0x432aff97,0xab9423a7,0xfc93a039,0x655b59c3,0x8f0ccc92,0xffeff47d,0x85845dd1,  0x6fa87e4f,0xfe2ce6e0,0xa3014314,0x4e0811a1,0xf7537e82,0xbd3af235,0x2ad7d2bb,0xeb86d391 }; const int serial[64]={  0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,  1,6,11,0,5,10,15,4,9,14,3,8,13,2,7,12,  5,8,11,14,1,4,7,10,13,0,3,6,9,12,15,2,  0,7,14,5,12,3,10,1,8,15,6,13,4,11,2,9 }; void func(unsigned long& a,           unsigned long b,           unsigned long c,           unsigned long d,           unsigned long M,           unsigned long t,           int s,           int turn) {     unsigned long temp;     switch(turn) {     case 0:         temp=(b&c)|((~b)&d);         break;     case 1:         temp=(d&b)|((~d)&c);         break;     case 2:         temp=b^c^d;         break;     case 3:         temp=c^(b|(~d));         break;     }     temp+=M+t+a;     _asm {         mov ecx,s         rol temp,cl     }     a=b+temp; } void MD512(const unsigned long M[16],unsigned long hash[4]) {     int i,j,index=0;     for (i=0;i<4;i++)         for (j=0;j<4;j++) {             func(hash[0],hash[1],hash[2],hash[3],M[serial[index]],t[index],s[i][0],i);             index++;             func(hash[3],hash[0],hash[1],hash[2],M[serial[index]],t[index],s[i][1],i);             index++;             func(hash[2],hash[3],hash[0],hash[1],M[serial[index]],t[index],s[i][2],i);             index++;             func(hash[1],hash[2],hash[3],hash[0],M[serial[index]],t[index],s[i][3],i);             index++;         } }  void MD5(char* M,int nLen,unsigned long output[4]) {     int i,j;     unsigned long Hash[4]={0x67452301,0xefcdab89,0x98badcfe,0x10325476};     unsigned long hash[4];      //填充     __int64 BitsLen=nLen*8;     int oldlen=nLen;     while(nLen%64!=56) {         M[nLen++]=0;     }     M[oldlen]=0x80u;     *(__int64*)(M+nLen)=BitsLen;     nLen+=8;      //开始处理分组     for (i=0;i<nLen;i+=64) {         memcpy(hash,Hash,sizeof(long)*4);         MD512((const unsigned long*)&M[i],hash);//处理512bits分组         for (j=0;j<4;j++)             Hash[j]+=hash[j];     }      //处理输出。     for (i=0;i<4;i++)         for (j=3;j>=0;j--) {             *((char*)(output+i)+j)=*((char*)(Hash+i)+3-j);         } } int main() {     int i;     char szMessage[1000]={0};     printf("input a string:\n>>>");     scanf("%s",szMessage);     unsigned long output[4];     MD5(szMessage,strlen(szMessage),output);     for (i=0;i<4;i++)         printf("%08lx",output[i]);     printf("\n");     return 0; }

user: user-4
content: 引用 7 楼 chenandczh 的回复:引用 4 楼 u012846431 的回复:md5怎么样md5方便移植吗？ 有源码，试过了可用

user: user-0
content: 引用 4 楼 u012846431 的回复:md5怎么样md5方便移植吗？

user: user-0
content: 引用 3 楼 jwj070524 的回复:我以前看飞鸽传书的代码时，传文件用blowfish加密的。 这个讲解一下～

user: user-0
content: 引用 2 楼 zxhuser-5 的回复:hash加密 应该可行～

user: user-4
content: md5怎么样

user: user-2
content: 我以前看飞鸽传书的代码时，传文件用blowfish加密的。

user: user-5
content: hash加密