user-0 提问: 字符型变量以整型格式存储，以字符格式输出的结果为什么不一样

回复:
user: user-1
content: 请判断scanf函数的返回值。  Format Specification Fields: scanf and wscanf Functions A format specification has the following form:  % [width] [{h | l | I64 | L}]type  The format argument specifies the interpretation of the input and can contain one or more of the following:   White-space characters: blank (' '); tab ('\t'); or newline ('\n'). A white-space character causes scanf to read, but not store, all consecutive white-space characters in the input up to the next non–white-space character. One white-space character in the format matches any number (including 0) and combination of white-space characters in the input.   Non–white-space characters, except for the percent sign (%). A non–white-space character causes scanf to read, but not store, a matching non–white-space character. If the next character in stdin does not match, scanf terminates.   Format specifications, introduced by the percent sign (%). A format specification causes scanf to read and convert characters in the input into values of a specified type. The value is assigned to an argument in the argument list.  The format is read from left to right. Characters outside format specifications are expected to match the sequence of characters in stdin; the matching characters in stdin are scanned but not stored. If a character in stdin conflicts with the format specification, scanf terminates, and the character is left in stdin as if it had not been read.  When the first format specification is encountered, the value of the first input field is converted according to this specification and stored in the location that is specified by the first argument. The second format specification causes the second input field to be converted and stored in the second argument, and so on through the end of the format string.  An input field is defined as all characters up to the first white-space character (space, tab, or newline), or up to the first character that cannot be converted according to the format specification, or until the field width (if specified) is reached. If there are too many arguments for the given specifications, the extra arguments are evaluated but ignored. The results are unpredictable if there are not enough arguments for the format specification.  Each field of the format specification is a single character or a number signifying a particular format option. The type character, which appears after the last optional format field, determines whether the input field is interpreted as a character, a string, or a number.   The simplest format specification contains only the percent sign and a type character (for example, %s). If a percent sign (%) is followed by a character that has no meaning as a format-control character, that character and the following characters (up to the next percent sign) are treated as an ordinary sequence of characters, that is, a sequence of characters that must match the input. For example, to specify that a percent-sign character is to be input, use %%.  An asterisk (*) following the percent sign suppresses assignment of the next input field, which is interpreted as a field of the specified type. The field is scanned but not stored.

user: user-2
content: 修改如下：  #include <stdio.h> int main() { 	int a, b, c, d; 	scanf("%d%d%d%d", &a, &b, &c, &d); 	printf("a=%d,b=%d,c=%d,d=%d\n", a, b, c, d); 	return 0; } //12 34 56 78 //a=12,b=34,c=56,d=78

user: user-3
content: 以%d格式向&c开始的内存中存储整数65，要占比char型更多的存储单元，于是将附近的一些数据给覆盖了。 这也是一种越界吧

user: user-0
content: 这个跟ASCII表有什么关系。能说清楚点么····

user: user-4
content: 去看ASCII码表

user: user-5
content: 引用 3 楼 wang0635 的回复:以%d格式向&c开始的内存中存储整数65，要占比char型更多的存储单元，于是将附近的一些数据给覆盖了。 这也是一种越界吧   这说的对，你定义c  d时是char，内存占1， 然后你存储时， 用%d，占4位，直接越界了。数据出错了。好多错误都是因为越界。