Question: How many percent of universities got a score above 80 under International criteria in 2016? Among them, name the university which got the highest score.
SQL: SELECT CAST(SUM(CASE WHEN T2.score > 80 THEN 1 ELSE 0 END) AS REAL) / COUNT(*), ( SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'International' AND T2.year = 2016 AND T2.score > 80 ORDER BY T2.score DESC LIMIT 1 ) AS max FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'International' AND T2.year = 2016