Question: What percentage of households are in "Coroyell" out of its state?
SQL: SELECT CAST(SUM(CASE WHEN T1.county = 'CORYELL' THEN T2.households ELSE 0 END) AS REAL) * 100 / SUM(T2.households) FROM country AS T1 INNER JOIN zip_data AS T2 ON T1.zip_code = T2.zip_code