Question: What is the percentage of the most common conditions for patients age 60 and above?
SQL: SELECT CAST(SUM(CASE WHEN T5.DESCRIPTION = T3.DESCRIPTION THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T3.patient) FROM ( SELECT T2.DESCRIPTION, T1.patient FROM patients AS T1 INNER JOIN conditions AS T2 ON T1.patient = T2.PATIENT WHERE ROUND((strftime('%J', T2.START) - strftime('%J', T1.birthdate)) / 365) > 60 GROUP BY T2.DESCRIPTION ORDER BY COUNT(T2.DESCRIPTION) DESC LIMIT 1 ) AS T3 INNER JOIN patients AS T4 ON T3.patient = T4.patient INNER JOIN conditions AS T5 ON T4.patient = T5.PATIENT WHERE ROUND((strftime('%J', T5.START) - strftime('%J', T4.birthdate)) / 365) > 60