Question: Among the males, list the region name of people with height greater than 87% of the average height of all people listed.
SQL: SELECT DISTINCT T1.region_name FROM noc_region AS T1 INNER JOIN person_region AS T2 ON T1.id = T2.region_id INNER JOIN person AS T3 ON T2.person_id = T3.id WHERE T3.gender = 'M' AND T3.height * 100 > ( SELECT AVG(height) FROM person WHERE gender = 'M' ) * 87