Question: display the employee number, name( first name and last name ), and salary for all employees who earn more than the average salary and who work in a department with any employee with a 'J' in their first name.
SQL: SELECT employee_id ,  first_name ,  last_name ,  salary FROM employees WHERE salary  >  ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%J%')