The neutron flux density distribution and geometric curvature within a finite-height semicylindrical reactor are ________, where $x_{1}=3.89$ is the first zero of $\operatorname{J}_{1}(x)$, i.e., $\mathrm{J}_{1}\left(x_{1}\right)=0$.

Options:
A. $$
\begin{aligned} {{\phi( r, z, \mu)}} & {{} {{} {}=A \mathrm{J}_{0} \left( \frac{x_{1} r} {R} \right) \mathrm{s i n} \theta\mathrm{c o s} \left( \frac{\pi z} {2H} \right)}} \\ {{B_{g}^{2}}} & {{} {{} {}=\left( \frac{x_{1}} {R} \right)^{2}+\left( \frac{\pi} {2H} \right)^{2}}} \\ \end{aligned}
$$
B. $$
\begin{aligned} {{\phi( r, z, \mu)}} & {{} {{} {}=A \mathrm{J}_{1} \left( \frac{x_{1} r} {R} \right) \mathrm{s i n} \theta\mathrm{s i n} \left( \frac{2\pi z} {H} \right)}} \\ {{B_{g}^{2}}} & {{} {{} {}=\left( \frac{x_{1}} {R} \right)^{2}+\left( \frac{\pi} {H} \right)^{2}}} \\ \end{aligned}
$$
C. $$
\begin{aligned} {{\phi( r, z, \mu)}} & {{} {{} {}=A \mathrm{J}_{2} \left( \frac{x_{1} r} {R} \right) \mathrm{s i n} \theta\mathrm{c o s} \left( \frac{\pi z} {H} \right)}} \\ {{B_{g}^{2}}} & {{} {{} {}=\left( \frac{x_{1}} {R} \right)^{2}+\left( \frac{\pi} {H} \right)^{2}}} \\ \end{aligned}
$$
D. $$
\begin{aligned} {{\phi( r, z, \mu)}} & {{} {{} {}=A \mathrm{J}_{0} \left( \frac{x_{1} r} {R} \right) \mathrm{s i n} \theta \mathrm{s i n} \left( \frac{\pi z} {H} \right)}} \\ {{B_{g}^{2}}} & {{} {{} {}=\left( \frac{x_{1}} {R} \right)^{2}+\left( \frac{\pi} {H} \right)^{2}}} \\ \end{aligned}
$$
E. $$
\begin{aligned} {{\phi( r, z, \mu)}} & {{} {{} {}=A \mathrm{J}_{1} \left( \frac{x_{1} r} {R} \right) \mathrm{s i n} \theta\mathrm{c o s} \left( \frac{\pi z} {H} \right)}} \\ {{B_{g}^{2}}} & {{} {{} {}=\left( \frac{x_{1}} {R} \right)^{2}+\left( \frac{\pi} {H} \right)^{2}}} \\ \end{aligned}
$$
F. $$
\begin{aligned} {{\phi( r, z, \mu)}} & {{} {{} {}=A \mathrm{J}_{0} \left( \frac{x_{1} r} {R} \right) \mathrm{c o s} \theta\mathrm{c o s} \left( \frac{\pi z} {H} \right)}} \\ {{B_{g}^{2}}} & {{} {{} {}=\left( \frac{x_{1}} {R} \right)^{2}+\left( \frac{\pi} {H} \right)^{2}}} \\ \end{aligned}
$$
G. $$
\begin{aligned} {{\phi( r, z, \mu)}} & {{} {{} {}=A \mathrm{J}_{1} \left( \frac{x_{3} r} {R} \right) \mathrm{s i n} \theta\mathrm{c o s} \left( \frac{\pi z} {H} \right)}} \\ {{B_{g}^{2}}} & {{} {{} {}=\left( \frac{x_{3}} {R} \right)^{2}+\left( \frac{\pi} {H} \right)^{2}}} \\ \end{aligned}
$$
H. $$
\begin{aligned} {{\phi( r, z, \mu)}} & {{} {{} {}=A \mathrm{J}_{1} \left( \frac{x_{2} r} {R} \right) \mathrm{c o s} \theta \mathrm{c o s} \left( \frac{\pi z} {H} \right)}} \\ {{B_{g}^{2}}} & {{} {{} {}=\left( \frac{x_{2}} {R} \right)^{2}+\left( \frac{\pi} {H} \right)^{2}}} \\ \end{aligned}
$$
I. $$
\begin{aligned} {{\phi( r, z, \mu)}} & {{} {{} {}=A \mathrm{J}_{1} \left( \frac{x_{1} r} {R} \right) \mathrm{c o s} \theta\mathrm{c o s} \left( \frac{\pi z} {2H} \right)}} \\ {{B_{g}^{2}}} & {{} {{} {}=\left( \frac{x_{1}} {R} \right)^{2}+\left( \frac{\pi} {2H} \right)^{2}}} \\ \end{aligned}
$$
J. $$
\begin{aligned} {{\phi( r, z, \mu)}} & {{} {{} {}=A \mathrm{J}_{1} \left( \frac{x_{1} r} {R} \right) \mathrm{c o s} \theta \mathrm{s i n} \left( \frac{\pi z} {H} \right)}} \\ {{B_{g}^{2}}} & {{} {{} {}=\left( \frac{x_{1}} {R} \right)^{2}+\left( \frac{2 \pi} {H} \right)^{2}}} \\ \end{aligned}
$$
Answer: E