Suppose there are 8 companies, denoted as $U = \{u_1, u_2, \ldots, u_8\}$. For each company, the level of technological intensity is characterized by the following three indicators: labor productivity of production workers, the number of employees per million yuan of fixed assets, and the proportion of technical management personnel among the employees. Let $u_i = (x_{i1}, x_{i2}, x_{i3})$, where $x_{i1}$, $x_{i2}$, and $x_{i3}$ represent the aforementioned three indicators, respectively.
$$
\begin{align*}
u_1 &= (1.8, 95, 0.15) \\
u_2 &= (2.1, 99, 0.21) \\
u_3 &= (3.2, 101, 0.18) \\
u_4 &= (2.2, 103, 0.17) \\
u_5 &= (2.5, 98, 0.16) \\
u_6 &= (2.8, 102, 0.20) \\
u_7 &= (1.9, 120, 0.09) \\
u_8 &= (2.0, 130, 0.11)
\end{align*}
$$
The unit of the first indicator is ten thousand yuan/(year·person). Try using the absolute value index method for cluster analysis; what is the value of $t(R)$?

Options:
A. $$
t(R)=
\begin{pmatrix}
1 & 0.67 & 0.65 & 0.67 & 0.67 & 0.67 & 0.66 &0.66\\
0.67 & 1 & 0.65 & 0.84 & 0.70 & 0.68 & 0.66 &0.66\\
0.65 & 0.65 & 1 & 0.65 & 0.65 & 0.65 & 0.65 &0.65\\
0.67 & 0.84 & 0.65 & 1 & 0.70 & 0.68 & 0.66 &0.66\\
0.67 & 0.70 & 0.65 & 0.70 & 1 & 0.68 & 0.66 &0.66\\
0.67 & 0.68 & 0.65 & 0.68 & 0.68 & 1 & 0.66 &0.66\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 1 &0.68\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 0.80&1
\end{pmatrix}
$$
B. $$
t(R)=
\begin{pmatrix}
1 & 0.67 & 0.65 & 0.67 & 0.67 & 0.67 & 0.66 &0.66\\
0.67 & 1 & 0.65 & 0.84 & 0.70 & 0.68 & 0.66 &0.66\\
0.65 & 0.65 & 1 & 0.66 & 0.65 & 0.65 & 0.65 &0.65\\
0.67 & 0.84 & 0.66 & 1 & 0.70 & 0.68 & 0.66 &0.66\\
0.67 & 0.70 & 0.65 & 0.70 & 1 & 0.68 & 0.67 &0.66\\
0.67 & 0.68 & 0.65 & 0.68 & 0.68 & 1 & 0.66 &0.66\\
0.66 & 0.66 & 0.65 & 0.66 & 0.67 & 0.66 & 1 &0.68\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 0.80&1
\end{pmatrix}
$$
C. $$
t(R)=
\begin{pmatrix}
1 & 0.67 & 0.65 & 0.67 & 0.67 & 0.67 & 0.66 &0.66\\
0.67 & 1 & 0.65 & 0.84 & 0.70 & 0.68 & 0.66 &0.66\\
0.65 & 0.66 & 1 & 0.65 & 0.65 & 0.65 & 0.65 &0.65\\
0.67 & 0.84 & 0.65 & 1 & 0.70 & 0.68 & 0.66 &0.66\\
0.67 & 0.70 & 0.65 & 0.70 & 1 & 0.68 & 0.66 &0.67\\
0.67 & 0.68 & 0.65 & 0.68 & 0.68 & 1 & 0.66 &0.66\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 1 &0.68\\
0.66 & 0.66 & 0.65 & 0.66 & 0.67 & 0.66 & 0.80&1
\end{pmatrix}
$$
D. $$
t(R)=
\begin{pmatrix}
1 & 0.67 & 0.65 & 0.67 & 0.67 & 0.66 & 0.66 &0.66\\
0.67 & 1 & 0.65 & 0.84 & 0.70 & 0.67 & 0.66 &0.66\\
0.65 & 0.65 & 1 & 0.65 & 0.65 & 0.65 & 0.65 &0.65\\
0.67 & 0.84 & 0.65 & 1 & 0.71 & 0.68 & 0.66 &0.66\\
0.67 & 0.70 & 0.65 & 0.71 & 1 & 0.68 & 0.66 &0.66\\
0.66 & 0.67 & 0.65 & 0.68 & 0.68 & 1 & 0.66 &0.66\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 1 &0.68\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 0.80&1
\end{pmatrix}
$$
E. $$
t(R)=
\begin{pmatrix}
1 & 0.67 & 0.65 & 0.67 & 0.67 & 0.67 & 0.66 &0.66\\
0.67 & 1 & 0.65 & 0.84 & 0.70 & 0.68 & 0.66 &0.66\\
0.65 & 0.65 & 1 & 0.65 & 0.65 & 0.65 & 0.65 &0.65\\
0.67 & 0.84 & 0.65 & 1 & 0.71 & 0.68 & 0.66 &0.66\\
0.67 & 0.70 & 0.65 & 0.71 & 1 & 0.68 & 0.66 &0.66\\
0.67 & 0.68 & 0.65 & 0.68 & 0.68 & 1 & 0.67 &0.66\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.67 & 1 &0.68\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 0.80&1
\end{pmatrix}
$$
F. $$
t(R)=
\begin{pmatrix}
1 & 0.67 & 0.65 & 0.67 & 0.67 & 0.67 & 0.66 &0.66\\
0.67 & 1 & 0.66 & 0.84 & 0.70 & 0.68 & 0.67 &0.66\\
0.65 & 0.66 & 1 & 0.65 & 0.65 & 0.65 & 0.65 &0.65\\
0.67 & 0.84 & 0.65 & 1 & 0.70 & 0.68 & 0.66 &0.66\\
0.67 & 0.70 & 0.65 & 0.70 & 1 & 0.68 & 0.66 &0.66\\
0.67 & 0.68 & 0.65 & 0.68 & 0.68 & 1 & 0.66 &0.66\\
0.66 & 0.67 & 0.65 & 0.66 & 0.66 & 0.66 & 1 &0.68\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 0.80&1
\end{pmatrix}
$$
G. $$
t(R)=
\begin{pmatrix}
1 & 0.67 & 0.65 & 0.66 & 0.67 & 0.68 & 0.66 &0.66\\
0.66 & 1 & 0.65 & 0.84 & 0.71 & 0.68 & 0.66 &0.66\\
0.65 & 0.65 & 1 & 0.65 & 0.65 & 0.65 & 0.65 &0.65\\
0.66 & 0.84 & 0.65 & 1 & 0.70 & 0.68 & 0.66 &0.66\\
0.67 & 0.71 & 0.65 & 0.70 & 1 & 0.68 & 0.66 &0.66\\
0.68 & 0.68 & 0.65 & 0.68 & 0.68 & 1 & 0.66 &0.66\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 1 &0.68\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 0.80&1
\end{pmatrix}
$$
H. $$
t(R)=
\begin{pmatrix}
1 & 0.68 & 0.65 & 0.67 & 0.67 & 0.67 & 0.66 &0.66\\
0.68 & 1 & 0.65 & 0.84 & 0.70 & 0.68 & 0.66 &0.67\\
0.65 & 0.65 & 1 & 0.65 & 0.65 & 0.65 & 0.65 &0.65\\
0.67 & 0.84 & 0.65 & 1 & 0.70 & 0.69 & 0.66 &0.66\\
0.67 & 0.70 & 0.65 & 0.70 & 1 & 0.68 & 0.66 &0.66\\
0.67 & 0.68 & 0.65 & 0.69 & 0.68 & 1 & 0.66 &0.66\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 1 &0.68\\
0.66 & 0.67 & 0.65 & 0.66 & 0.66 & 0.66 & 0.80&1
\end{pmatrix}
$$
I. $$
t(R)=
\begin{pmatrix}
1 & 0.67 & 0.66 & 0.67 & 0.67 & 0.65 & 0.66 &0.66\\
0.67 & 1 & 0.66 & 0.84 & 0.70 & 0.68 & 0.66 &0.66\\
0.66 & 0.66 & 1 & 0.65 & 0.65 & 0.65 & 0.65 &0.65\\
0.67 & 0.84 & 0.65 & 1 & 0.70 & 0.68 & 0.66 &0.66\\
0.67 & 0.70 & 0.65 & 0.70 & 1 & 0.65 & 0.66 &0.66\\
0.67 & 0.68 & 0.65 & 0.68 & 0.65 & 1 & 0.66 &0.66\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 1 &0.69\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 0.80&1
\end{pmatrix}
$$
J. $$
t(R)=
\begin{pmatrix}
1 & 0.66 & 0.65 & 0.67 & 0.67 & 0.67 & 0.66 &0.66\\
0.66 & 1 & 0.65 & 0.84 & 0.70 & 0.68 & 0.66 &0.66\\
0.65 & 0.65 & 1 & 0.65 & 0.65 & 0.66 & 0.65 &0.65\\
0.67 & 0.84 & 0.65 & 1 & 0.70 & 0.68 & 0.66 &0.66\\
0.67 & 0.70 & 0.66 & 0.70 & 1 & 0.68 & 0.66 &0.66\\
0.67 & 0.68 & 0.66 & 0.68 & 0.68 & 1 & 0.66 &0.66\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 1 &0.68\\
0.66 & 0.66 & 0.65 & 0.66 & 0.66 & 0.66 & 0.80&1
\end{pmatrix}
$$
Answer: A