The parallel infinitely large planar currents separated by a distance of $d$ are located at $z = -d / 2$ and $z = d / 2$, parallel to the $xy$ plane. The surface current densities are $K e_{s}$ and $K e_{y}$, respectively. What is the magnetic induction in the three spatial regions divided by the two infinitely large planes?

Options:
A. When $z <-\frac{d} {2} \,, \, \, \, \, B=-\frac{\mu_{0} K} {2} \, e_{x}-\frac{\mu_{0} K} {2} \, e_{z}$
When $- \frac{d} {2} < z < \frac{d} {2} \,, \; \; B=-\frac{\mu_{0} K} {2} \, e_{x}+\frac{\mu_{0} K} {2} \, e_{y}$
When $z > \frac{d} {2} \,, \; \; B=\frac{\mu_{0} K} {2} \, e_{x}-\frac{\mu_{0} K} {2} \, e_{y}$
B. When $z <-\frac{d} {2} \,, \, \, \, \, B=\frac{\mu_{0} K} {2} \, e_{x}-\frac{\mu_{0} K} {2} \, e_{y}$
When $- \frac{d} {2} < z < \frac{d} {2} \,, \; \; B=\frac{\mu_{0} K} {2} \, e_{x}+\frac{\mu_{0} K} {2} \, e_{y}$
When $z > \frac{d} {2} \,, \; \; B=-\frac{\mu_{0} K} {2} \, e_{x}-\frac{\mu_{0} K} {2} \, e_{y}$
C. When $z <-\frac{d} {2} \,, \, \, \, \, B=-\frac{\mu_{0} K} {2} \, e_{x}+\frac{\mu_{0} K} {2} \, e_{z}$
When $- \frac{d} {2} < z < \frac{d} {2} \,, \; \; B=-\frac{\mu_{0} K} {2} \, e_{y}+\frac{\mu_{0} K} {2} \, e_{x}$
When $z > \frac{d} {2} \,, \; \; B=-\frac{\mu_{0} K} {2} \, e_{z}+\frac{\mu_{0} K} {2} \, e_{y}$
D. When $z <-\frac{d} {2} \,, \, \, \, \, B=-\frac{\mu_{0} K} {2} \, e_{y}+\frac{\mu_{0} K} {2} \, e_{z}$
When $- \frac{d} {2} < z < \frac{d} {2} \,, \; \; B=-\frac{\mu_{0} K} {2} \, e_{z}-\frac{\mu_{0} K} {2} \, e_{x}$
When $z > \frac{d} {2} \,, \; \; B=\frac{\mu_{0} K} {2} \, e_{y}-\frac{\mu_{0} K} {2} \, e_{x}$
E. When $z <-\frac{d} {2} \,, \, \, \, \, B=-\frac{\mu_{0} K} {2} \, e_{x}+\frac{\mu_{0} K} {2} \, e_{y}$
When $- \frac{d} {2} < z < \frac{d} {2} \,, \; \; B=-\frac{\mu_{0} K} {2} \, e_{x}-\frac{\mu_{0} K} {2} \, e_{y}$
When $z > \frac{d} {2} \,, \; \; B=\frac{\mu_{0} K} {2} \, e_{x}+\frac{\mu_{0} K} {2} \, e_{y}$
F. When $z <-\frac{d} {2} \,, \, \, \, \, B=\frac{\mu_{0} K} {2} \, e_{y}+\frac{\mu_{0} K} {2} \, e_{z}$
When $- \frac{d} {2} < z < \frac{d} {2} \,, \; \; B=\frac{\mu_{0} K} {2} \, e_{x}+\frac{\mu_{0} K} {2} \, e_{y}$
When $z > \frac{d} {2} \,, \; \; B=-\frac{\mu_{0} K} {2} \, e_{y}-\frac{\mu_{0} K} {2} \, e_{x}$
G. When $z <-\frac{d} {2} \,, \, \, \, \, B=-\frac{\mu_{0} K} {2} \, e_{z}-\frac{\mu_{0} K} {2} \, e_{x}$
When $- \frac{d} {2} < z < \frac{d} {2} \,, \; \; B=\frac{\mu_{0} K} {2} \, e_{x}-\frac{\mu_{0} K} {2} \, e_{z}$
When $z > \frac{d} {2} \,, \; \; B=-\frac{\mu_{0} K} {2} \, e_{y}+\frac{\mu_{0} K} {2} \, e_{z}$
H. When $z <-\frac{d} {2} \,, \, \, \, \, B=\frac{\mu_{0} K} {2} \, e_{x}-\frac{\mu_{0} K} {2} \, e_{z}$
When $- \frac{d} {2} < z < \frac{d} {2} \,, \; \; B=\frac{\mu_{0} K} {2} \, e_{y}+\frac{\mu_{0} K} {2} \, e_{x}$
When $z > \frac{d} {2} \,, \; \; B=-\frac{\mu_{0} K} {2} \, e_{z}+\frac{\mu_{0} K} {2} \, e_{y}$
I. When $z <-\frac{d} {2} \,, \, \, \, \, B=\frac{\mu_{0} K} {2} \, e_{z}-\frac{\mu_{0} K} {2} \, e_{y}$
When $- \frac{d} {2} < z < \frac{d} {2} \,, \; \; B=-\frac{\mu_{0} K} {2} \, e_{y}-\frac{\mu_{0} K} {2} \, e_{z}$
When $z > \frac{d} {2} \,, \; \; B=\frac{\mu_{0} K} {2} \, e_{x}-\frac{\mu_{0} K} {2} \, e_{y}$
J. When $z <-\frac{d} {2} \,, \, \, \, \, B=-\frac{\mu_{0} K} {2} \, e_{y}+\frac{\mu_{0} K} {2} \, e_{x}$
When $- \frac{d} {2} < z < \frac{d} {2} \,, \; \; B=\frac{\mu_{0} K} {2} \, e_{x}-\frac{\mu_{0} K} {2} \, e_{y}$
When $z > \frac{d} {2} \,, \; \; B=-\frac{\mu_{0} K} {2} \, e_{x}+\frac{\mu_{0} K} {2} \, e_{y}$
Answer: E