A point charge $Q$ is located within a right-angle space formed by two mutually perpendicular grounded conducting planes. Its distances to the two planes are $a$ and $b$. Find the potential in the space.

Options:
A. $$
\begin{aligned} {{}} & {{} {{\frac{Q} {4 \pi\varepsilon_{0}} \left[ \frac{+1} {\sqrt{( x+x_{0} )^{2}+( y-a )^{2}+( z-b )^{2}}}+\frac{+1} {\sqrt{( x+x_{0} )^{2}+( y+a )^{2}+( z-b )}} \right.}}} \\ {{}} & {{} {{} {\left.+\frac{+1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z-b )^{2}}}+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y-a )^{2}+( z+b )^{2}}} \right],}}} \\ \end{aligned}
$$
B. $$
\begin{aligned} {{}} & {{} {{\frac{Q} {4 \pi\varepsilon_{0}} \left[ \frac{+1} {\sqrt{( x-x_{0} )^{2}+( y-a )^{2}+( z-b )^{2}}}+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z-b )}} \right.}}} \\ {{}} & {{} {{} {\left.+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y-a )^{2}+( z+b )^{2}}}+\frac{+1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z+b )^{2}}} \right],}}} \\ \end{aligned}
$$
C. $$
\begin{aligned} {{}} & {{} {{\frac{Q} {4 \pi\varepsilon_{0}} \left[ \frac{-1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z-b )^{2}}}+\frac{+1} {\sqrt{( x-x_{0} )^{2}+( y-a )^{2}+( z+b )}} \right.}}} \\ {{}} & {{} {{} {\left.+\frac{+1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z+b )^{2}}}+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y-a )^{2}+( z-b )^{2}}} \right],}}} \\ \end{aligned}
$$
D. $$
\begin{aligned} {{}} & {{} {{\frac{Q} {4 \pi\varepsilon_{0}} \left[ \frac{-1} {\sqrt{( x+x_{0} )^{2}+( y-a )^{2}+( z-b )^{2}}}+\frac{-1} {\sqrt{( x+x_{0} )^{2}+( y+a )^{2}+( z+b )}} \right.}}} \\ {{}} & {{} {{} {\left.+\frac{+1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z+b )^{2}}}+\frac{-1} {\sqrt{( x+x_{0} )^{2}+( y-a )^{2}+( z+b )^{2}}} \right],}}} \\ \end{aligned}
$$
E. $$
\begin{aligned} {{}} & {{} {{\frac{Q} {4 \pi\varepsilon_{0}} \left[ \frac{-1} {\sqrt{( x-x_{0} )^{2}+( y-a )^{2}+( z+b )^{2}}}+\frac{+1} {\sqrt{( x+x_{0} )^{2}+( y+a )^{2}+( z-b )}} \right.}}} \\ {{}} & {{} {{} {\left.+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z-b )^{2}}}+\frac{+1} {\sqrt{( x+x_{0} )^{2}+( y-a )^{2}+( z+b )^{2}}} \right],}}} \\ \end{aligned}
$$
F. $$
\begin{aligned} {{}} & {{} {{\frac{Q} {4 \pi\varepsilon_{0}} \left[ \frac{+1} {\sqrt{( x-x_{0} )^{2}+( y-a )^{2}+( z-b )^{2}}}+\frac{+1} {\sqrt{( x+x_{0} )^{2}+( y+a )^{2}+( z-b )}} \right.}}} \\ {{}} & {{} {{} {\left.+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z+b )^{2}}}+\frac{-1} {\sqrt{( x+x_{0} )^{2}+( y-a )^{2}+( z+b )^{2}}} \right],}}} \\ \end{aligned}
$$
G. $$
\begin{aligned} {{}} & {{} {{\frac{Q} {4 \pi\varepsilon_{0}} \left[ \frac{+1} {\sqrt{( x+x_{0} )^{2}+( y+a )^{2}+( z-b )^{2}}}+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y-a )^{2}+( z+b )}} \right.}}} \\ {{}} & {{} {{} {\left.+\frac{+1} {\sqrt{( x+x_{0} )^{2}+( y-a )^{2}+( z+b )^{2}}}+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z+b )^{2}}} \right],}}} \\ \end{aligned}
$$
H. $$
\begin{aligned} {{}} & {{} {{\frac{Q} {4 \pi\varepsilon_{0}} \left[ \frac{-1} {\sqrt{( x+x_{0} )^{2}+( y+a )^{2}+( z-b )^{2}}}+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z-b )}} \right.}}} \\ {{}} & {{} {{} {\left.+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y-a )^{2}+( z+b )^{2}}}+\frac{+1} {\sqrt{( x+x_{0} )^{2}+( y-a )^{2}+( z+b )^{2}}} \right],}}} \\ \end{aligned}
$$
I. $$
\begin{aligned} {{}} & {{} {{\frac{Q} {4 \pi\varepsilon_{0}} \left[ \frac{-1} {\sqrt{( x+x_{0} )^{2}+( y-a )^{2}+( z-b )^{2}}}+\frac{+1} {\sqrt{( x+x_{0} )^{2}+( y+a )^{2}+( z+b )}} \right.}}} \\ {{}} & {{} {{} {\left.+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z+b )^{2}}}+\frac{+1} {\sqrt{( x-x_{0} )^{2}+( y-a )^{2}+( z-b )^{2}}} \right],}}} \\ \end{aligned}
$$
J. $$
\begin{aligned} {{}} & {{} {{\frac{Q} {4 \pi\varepsilon_{0}} \left[ \frac{+1} {\sqrt{( x+x_{0} )^{2}+( y-a )^{2}+( z+b )^{2}}}+\frac{-1} {\sqrt{( x-x_{0} )^{2}+( y+a )^{2}+( z-b )}} \right.}}} \\ {{}} & {{} {{} {\left.+\frac{+1} {\sqrt{( x+x_{0} )^{2}+( y+a )^{2}+( z+b )^{2}}}+\frac{-1} {\sqrt{( x+x_{0} )^{2}+( y-a )^{2}+( z+b )^{2}}} \right],}}} \\ \end{aligned}
$$
Answer: B