Patent ID: 7125831
Filing Date: 2006-10-24
Classification: C11D,D06L

Abstract:
1. A detergent composition for dry cleaning, which comprises a nonionic surfactant as component (a), a cyclic polysiloxane represented by the general formula (1) as component (b), a polyether modified silicone having a HLB value of at most 6 and represented by the general formula (2) as component (c), component (c) being different from the component (a), wherein the content of the component (a) is 5 to 70% by weight based on the total weight of the components (a), (b) and (c), the content of the total of the components (b) and (c) is 30 to 95% by weight based on the total weight of the components (a), (b) and (c), and the ratio by weight of the component (b) to the component (c) is 1/10 to 10/1, from 0.1 to 15% by weight of at least one species selected from the group consisting of an alkylimidazoline cationic surfactant or an alkyldimethylhydroxyethyl ammonium salt cationic surfactant as component (d), and a dry cleaning solvent selected from the group consisting of a halogen based solvent, a petroleum based solvent, or a silicone based solvent, said silicone based solvent being a different compound from said cyclic polysiloxane as component (e), wherein component (e) is present in an amount of 5 to 1000 times by volume, based on the total weight of components (a), (b), (c), and (d): wherein k is a number from 3 to 6, wherein R 1 is an alkyl group having 1 to 5 carbon atoms or a phenyl group; R 2 is —(CH 2 )p —O—(C 2 H 4 O)q (C 3 H 6 O)r —R 3 (R 3 is hydrogen atom or an alkyl group having 1 to 5 carbon atoms, p is a number from 1 to 5, q and r are each the average number of addition moles, q is a number from 0 to 50, r is a number from 0 to 30 with the proviso that 1≦q+r<60); m and n are each an average degree of polymerization, m is a number from 1 to 300, n is a number from 0 to 50; R 4 and R 5 are each an alkyl group having 1 to 5 carbon atoms or phenyl group or R 2 , and may be the same as or different from each other with the proviso that when n is equal to 0, at least one of R 4 and R 5 is R 2 .