If the operation @ is defined for all a and b by the equation a@b =(a-b)/5,then (3@-2)@6=?
Answers:  A) 0  B) 1  C) 2  D) - 2  E) - 1

Rationale: work within the parenthesis first so solve ( 3 @ - 2 ) first ( 3 @ - 2 ) = ( 3 - ( - 2 ) ) / 5 = ( 3 + 2 ) / 5 = 1 now take 1 plug back into equation and solve the rest ( 1 @ 6 ) = ( 1 - 6 ) / 5 = - 5 / 5 = - 1 so - 1 is the answer . . . . this question is merely testing order of operations remember pemdas answer is option : e
Answer: E