if(x-10)(y-5)(z-2)=1000 then what is the least value of x+y+z? if x,y,z are all integer no.  Pick one:	A) 7	B) 8	C) 9	D) 10	E) 11

Rationale: ( x - 10 ) ( y - 5 ) ( z - 2 ) = 1000 put x = 0 y = - 5 z = 12 then ( 0 - 10 ) ( - 5 - 5 ) ( 12 - 2 ) = 1000 ( - 10 ) ( - 10 ) ( 10 ) = 1000 1000 = 1000 answer : a
Answer: A