An urn contains 5 red, 6 blue and 8 green balls. 4 balls are randomly selected from the urn, find the probability that the drawn ball are 1 blue and 3 red?	Select the correct option:
A) 1 / 969
B) 2 / 969
C) 4 / 969
D) 5 / 323
E) 21 / 789

Rationale: sample space = no . of ways 4 balls were drawn from urn = 19 c 4 = 3876 no . ways 1 blue balls and 3 red were drawn from bag = 6 c 1 * 5 c 3 = 60 probability = 60 / 3876 = 5 / 323 ans - d
Answer: D