A box contains 22 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective is Choose the correct choice from the following options:
A) 4 / 19 B) 7 / 19 C) 12 / 19 D) 21 / 99 E) 26 / 77

Rationale: "solution p ( none is defective ) = 18 c 2 / 22 c 2 = 51 / 77 p ( at least one is defective ) = ( 1 - 51 / 77 ) = 26 / 77 . answer e"
Answer: E