In a bag, there are 5 green, 6 black and 7 red pens. One pen is picked up randomly. What is the probability that it is neither red nor green?	Pick
A) 5 / 18
B) 7 / 18
C) 1 / 3
D) 1 / 2
E) 1 / 5

Rationale: explanation : neither red nor green means the pen drawn is black . total number of outcomes = ( 5 + 6 + 7 ) = 18 . number of favourable outcomes = 6 = number of black pens . hence , probability of the event = 6 / 18 = 1 / 3 . answer : c
Answer: C