Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the game remainder in each case. Then sum of the digits in N is : Choose the most appropriate option.
A) 4 B) 5 C) 6 D) 8 E) 9

Rationale: solution n = h . c . f . of ( 4665 - 1305 ) , ( 6905 - 4665 ) and ( 6905 - 1305 ) = h . c . f . of 3360 , 2240 and 5600 = 1120 . sum of digits in n = ( 1 + 1 + 2 + 0 ) = 4 . answer a
Answer: A