What is the positive difference between the sum of the squares of the first 6 positive integers and the sum of the prime numbers between the first square and fourth square?
Choose the correct choice from the following answers:	A) 11	B) 12	C) 13	D) 14	E) 50

Rationale: forget conventional ways of solving math questions . in ps , ivy approach is the easiest and quickest way to find the answer . the sum of the squares of the first 4 positive integers = 1 ^ 2 + 2 ^ 2 + 3 ^ 2 + 4 ^ 2 + 5 ^ 2 + 6 ^ 2 = 91 the sum of the prime numbers between the first square ( = 1 ) and fourth square ( = 16 ) = 2 + 3 + 5 + 7 + 11 + 13 = 41 . so the difference between 41 and 91 is 50 . so the answer is ( e ) .
Answer: E