A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 6% of bananas were rotten. Find the percentage of fruits in good condition?
Answers: A) 92.5 % B) 88.6 % C) 85.2 % D) 96.8 % E) 78.9 %

Rationale: "total number of fruits shopkeeper bought = 600 + 400 = 1000 number of rotten oranges = 15 % of 600 = 15 / 100 × 600 = 9000 / 100 = 90 number of rotten bananas = 6 % of 400 = 24 therefore , total number of rotten fruits = 90 + 24 = 114 therefore number of fruits in good condition = 1000 - 114 = 886 therefore percentage of fruits in good condition = ( 886 / 1000 × 100 ) % = ( 88600 / 1000 ) % = 88.6 % answer : b"
Answer: B