If p^2 – 13p + 40 = h, and p is a positive integer between 1 and 10, inclusive, what is the probability that h < 0?  Choose the correct choice from the following choices
A) 1 / 10 B) 1 / 5 C) 2 / 5 D) 3 / 5 E) 3 / 10

Rationale: p 2 – 13 p + 40 = h so ( p – 8 ) ( p – 5 ) = h for q to be negative , the expressions ( p – 8 ) and ( p – 5 ) must have opposite signs . which integers on the number line will yield opposite signs for the expressions ( p – 8 ) and ( p – 5 ) ? those integers in the range 5 < p < 8 ( notice 5 and 8 are not included because they would both yield a value of zero and zero is a nonnegative integer ) . that means that there are only two integer values for p , 6 and 7 , that would yield a negative q . with a total of 10 possible p values , only 2 yield a negative q , so the probability is 2 / 10 or 1 / 5 . the correct answer is b .
Answer: B