The volume of the sphere Q is (37/64)% less than the volume of sphere P and the volume of sphere R is (19/27)% less than that of sphere Q. By what is the surface area of sphere R less than the surface area of sphere P?	Pick one:
A) 77.77 %  B) 75 %  C) 67.5 %  D) 87.5 %  E) none of these

Rationale: explanation : let the volume of sphere p be 64 parts . therefore volume of sphere q = > 64 − ( 37 / 64 ) % of 64 . = > 64 − 37 = 27 parts . the volume of r is : - = > 27 − ( 19 / 27 ) × 27 . = > 27 − 19 = 8 parts . volume ratio : = > p : q : r = 64 : 27 : 8 . radius ratio : = > p : q : r = 4 : 3 : 2 . the surface area will be 16 : 9 : 5 . surface area of r is less than the surface area of sphere p . = > 16 k − 4 k = 12 k . now , = > ( 12 k / 16 k ) × 100 . = > 75 % . hence , the surface area of sphere r is less than the surface area of sphere p by 75 % . answer : b
Answer: B