The sum of the first 50 positive even integers is 2550. What is the sum E of even integers from 102 to 200 inclusive?	Answers:	A) 5100	B) 7550	C) 10100	D) 15500	E) 20100

Rationale: "my solution is : first 50 even integers : 2 4 6 8 < . . . > integers from 102 to 200 102 104 106 108 < . . . > we notice that each integer from the second set is 100 more than the respective integer in the first set . since we have 50 even integers from 102 to 200 , then : e = 2550 + ( 100 * 50 ) = 7550 . b"
Answer: B