Integer d is the product of the integers a,b, and c and 1<a<b<c. If the remainder when 233 is divided by d is 79, what is the value of a+c?  Choose one
A) 7
B) 9
C) 13
D) 14
E) 18

Rationale: 79 is the remainder , therefore the number ( a * b * c ) or multiple of the number we need is 79 less than 233 hence 233 - 79 = 154 therefore , 154 is either a number we want or it is a multiple of the number we want but the largest factor of 154 is 77 because 77 * 2 = 154 but 77 is less than 79 hence it can not be a number thus 154 is the number we want a * b * c = 154 now factorize 154 = 1 * 2 * 7 * 11 all are prime also we know 1 < a < b < c thus a = 2 and c = 11 therefore a + c = 2 + 11 = 13 answer : c
Answer: C