Find the area of a triangle whose sides are 41 cm, 28 cm, 15 cm. Also, find the length of the altitude corresponding to the largest side of the triangle.
Select.
A) 4.1 cm  B) 5.1 cm  C) 6.1 cm  D) 7.1 cm  E) 8.1 cm

Rationale: semi - perimeter of the triangle = ( a + b + c ) / 2 = ( 41 + 28 + 15 ) / 2 = 84 / 2 = 42 cm therefore , area of the triangle = √ ( s ( s - a ) ( s - b ) ( s - c ) ) = √ ( 42 ( 42 - 41 ) ( 42 - 28 ) ( 42 - 15 ) ) cm ² = √ ( 42 × 1 × 27 × 14 ) cm ² = √ ( 3 × 3 × 3 × 3 × 2 × 2 × 7 × 7 ) cm ² = 3 × 3 × 2 × 7 cm ² = 126 cm ² now , area of triangle = 1 / 2 × b × h therefore , h = 2 a / b = ( 2 × 126 ) / 41 = 252 / 41 = 6.1 cm answer : option c
Answer: C