Jean drew a gumball at random from a jar of pink and blue gumballs. Since the gumball she selected was blue and she wanted a pink one, she replaced it and drew another. The second gumball also happened to be blue and she replaced it as well. If the probability of her drawing the two blue gumballs was 16/36, what is the probability that the next one she draws will be pink? Options:	A) 1 / 49	B) 4 / 7	C) 3 / 7	D) 1 / 3	E) 40 / 49

Rationale: "the probability of drawing a pink gumball both times is the same . the probability that she drew two blue gumballs = 16 / 36 = ( 2 / 3 ) * ( 2 / 3 ) therefore probability that the next one she draws is pink = 1 / 3 option ( d )"
Answer: D