A hare and a tortoise have a race along a circle of 100 yards diameter. The tortoise goes in one direction and the hare in the other. The hare starts after the tortoise has covered 1/5 of its distance and that too leisurely. The hare and tortoise meet when the hare has covered only 1/8 of the distance. By what factor should the hare increase its speed so as to tie the race?	Choose one.
A) 37.9
B) 37.2
C) 37.1
D) 37.82
E) 37.8

Rationale: assume the circumference of the circle is 200 meters . hare and tortoise started at the same point but moves in the opposite direction . it is given that by that time tortoise covered 40 m ( 1 / 5 th of the distance ) , hare started and both met after hare has covered 25 . this implies , in the time hare has covered 25 m , hare has covered 200 - 40 - 25 = 135 meters . so hare : tortoise speeds = 25 : 135 = 5 : 27 now hare and tortoise has to reach the starting point means , hare has to cover 175 meters and tortoise has to cover only 25 meters in the same time . as time = distancespeed = 2527 = 1755 × kdistancespeed = 2527 = 1755 × k ie . , hare has to increase its speed by a factor k . solving we get k = 37.8 answer : e
Answer: E