The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 80 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B? Answers.
A) 75 %	B) 80 %	C) 100 %	D) 150 %	E) 159.2 %

Rationale: "let length of each side of square a be 10 area of a = 10 ^ 2 = 100 since , length of each side of square a is increased by 100 percent to make square b length of each side of square b = 2 * 10 = 20 area of b = 20 ^ 2 = 400 since , length of the side of square b is increased by 80 percent to make square c length of each side of square c = 1.8 * 20 = 36 area of c = 36 ^ 2 = 1296 difference in areas of c and cummulative areas of a and b = 1296 - ( 400 + 100 ) = 796 percent is the area of square c greater than the sum of the areas of squares a and b = ( 796 / 500 ) * 100 % = 159.2 % answer e"
Answer: E