The least number which when divided by 3, 4, 5 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is  Options:
A) 167  B) 243  C) 252  D) 336  E) none of these

Rationale: "explanation : l . c . m of 3 , 4 , 5 , 8 = 120 therefore required number is of the form 120 k + 3 . least value of k for which ( 120 k + 3 ) is divisible by 9 is k = 2 therefore required number = ( 120 x 2 + 3 ) = 243 answer : b"
Answer: B