On a certain transatlantic crossing, 15 percent of a ship's passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship's passengers held round-trip tickets?	Pick one:
A) 37.5 %
B) 40 %
C) 50 %
D) 60 %
E) 66.6 %

Rationale: 0.15 p = rt + c 0.6 ( rt ) = no c = > 0.40 ( rt ) had c 0.15 p = 0.40 ( rt ) rt / p = 37.5 % answer - a
Answer: A