In a box, there are 8 orange, 7 black and 6 white balls. If one ball is picked up randomly. What is the probability that it is neither orange nor white?  Pick.
A) 2 / 3	B) 3 / 4	C) 7 / 19	D) 8 / 21	E) 10 / 21

Rationale: total balls are 21 and neither black nor white . so favor case will be only 8 c 1 and total case 21 c 1 probability will be 8 c 1 / 21 c 1 = 8 / 21 answer : d
Answer: D