What is the smallest number which when increased by 7 is divisible by 25, 49, 15, and 21? Choose the correct answer.
A) 3,551 B) 3,668 C) 3,733 D) 3,822 E) 3,957

Rationale: "first factor each of 25 , 49 , 15 , and 21 into primes : 25 = 5 * 5 ; 49 = 7 * 7 ; 15 = 3 * 5 ; 21 = 3 * 7 the smallest number divisible by each of the numbers is 3 * 5 * 5 * 7 * 7 = 3,675 3,675 - 7 = 3,668 thus 3,668 + 7 is the smallest number divisible by 25 , 49 , 15 , and 21 b"
Answer: B