A man loses 1/3rd of his money, then wins Rs. 10 loses 1/3rd of what he has and wins Rs. 20 and finds that he has exactly what be had at the beginning. What was the amount he originally bad ?
Select: A) 25 B) 36 C) 10 D) 48 E) 45

Rationale: let x be that amount so accordind to question , eqn will be like : ( ( ( x - x / 3 ) + 10 ) - ( ( ( x - x / 3 ) + 10 ) / 3 ) ) + 20 = x = > ( ( 2 x / 3 + 10 ) - ( ( 2 x / 3 + 10 ) / 3 ) ) + 20 = x = > 3 x - 4 x / 3 = 80 = > x = 48 answer : d
Answer: D