A tiger is 50 of its own leaps behind a deer. The tiger takes 5 leaps per minutes to deer’s 4. If the tiger and the deer cover 8 m and 5 m per leap respectively, what distance will the tiger have to run before it catches the deer ?
Options:
A) 600 m
B) 700 m
C) 800 m
D) 1000 m
E) 1200 m

Rationale: tiger takes 5 leaps / m and deer takes 4 leaps / m thus , tiger runs at the speed of 5 x 8 = 40 m / min and deer runs at the speed of 4 x 5 = 20 m / min tiger is 50 leaps behind , which is 50 x 8 = 400 m relative speed of tiger and deer is = 20 m / min thus , 400 / 20 = 20 m thus , the tiger will catch deer = 20 x 40 = 800 m answer : c
Answer: C