An object thrown directly upward is at a height of h feet after t seconds, where h = -15 (t-2)^2 + 150. At what height, in feet, is the object 2 seconds after it reaches its maximum height?  Answers.
A) 72  B) 90  C) 124  D) 132  E) 140

Rationale: "we see that h will be a maximum h = 150 when t - 2 = 0 , that is when t = 2 . at t = 4 , h = - 15 ( 4 - 2 ) ^ 2 + 150 = - 15 ( 4 ) + 150 = 90 the answer is b ."
Answer: B