Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 540 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)	Answers:
A) 8 / 3  B) 3 / 8  C) 8 / 5  D) 12 / 5  E) 5 / 3

Rationale: "distance traveled by eddy = 540 km time taken by eddy = 3 hours average speed of eddy = 540 / 3 = 180 km / hour distance traveled by freddy = 300 km time taken by freddy = 4 hours average speed of freddy = 300 / 4 = 75 km / hour ratio of average speed of eddy to freddy = 180 / 75 = 12 / 5 answer d"
Answer: D