Three coins are tossed. Find the probability of at least 2 tails ?	Options.
A) 1 / 2
B) 2 / 3
C) 1 / 4
D) 1 / 8
E) 3 / 8

Rationale: "n ( s ) = 2 ^ 3 = 8 let e is the event of getting at least 2 tails n ( e ) = ttt , tth , htt , tht = 4 p ( e ) = n ( e ) / n ( s ) = 4 / 8 = 1 / 2 ans - a"
Answer: A