A line has a slope of 3/4 and intersects the point (-12, -39). At which point E does this line intersect the x-axis?  Pick one
A) ( 400 ) B) ( 300 ) C) ( 040 ) D) ( 4030 ) E) ( 030 )

Rationale: assume that the equation of the line is y = mx + c , where m and c are the slope and y - intercept . you are also given that the line crosses the point ( - 12 , - 39 ) , this means that this point will also lie on the line above . thus you get - 39 = m * ( - 12 ) + c , with m = 3 / 4 as the slope is given to be 3 / 4 . after substituting the above values , you get c = - 30 . thus the equation of the line is y = 0.75 * x - 30 and the point where it will intersect the x - axis will be with y coordinate = 0 . put y = 0 in the above equation of the line and you will get , x = 40 . thus , the point e of intersection is ( 400 ) . a is the correct answer .
Answer: A