Suppose f(x) is an odd function for which f(x + 2) = f(x) for all x, and
f(x) = x2 for x 2 (0, 1). Compute f(-3/2) + f(1).
Select: A) - 1 B) - 1 / 2 C) - 1 / 4 D) 1 / 4 E) 1 / 2

Rationale: because f is periodic , we know that f ( - 3 / 2 ) = f ( 1 / 2 ) = ( 1 / 2 ) 2 = 1 = 4 . because f is odd , we know that f ( 1 ) = - f ( / 1 ) , but because f is periodic , f ( 1 ) = f ( - 1 ) . therefore , f ( 1 ) = 0 and the answer is 1 = 4 . correct answer d
Answer: D