If an integer n is to be selected at random from 1 to 100, inclusive, what is probability n(n+1) will be divisible by 16? Pick.
A) 1 / 4	B) 1 / 8	C) 1 / 2	D) 2 / 3	E) 3 / 4

Rationale: "because n ( n + 1 ) is always an even product of even * odd or odd * even factors , there is a probability of 1 that that it will be divisible by 2 , and , thus , a probability of 1 / 2 that it will be divisible by 4 and , thus , a probability of 1 / 4 that it will be divisible by 8 and , thus , a probability of 1 / 8 that it will be divisible by 16 1 * 1 / 8 = 1 / 8 answer : b"
Answer: B