What is the sum R of all 3 digit numbers that leave a remainder of '2' when divided by 3?
Choose the correct choice:
A) 897
B) 164850
C) 164749
D) 149700
E) 156720

Rationale: the series is = > 101 + . . . 998 number of terms = > 300 sum = > 300 / 2 * [ 101 + 998 ] hence sum r = > 164850 i . e . option b
Answer: B