A line has a slope of 3/4 and intersects the point T (-12, -39). At which point does this line intersect the x-axis? Pick
A) ( 40,0 )	B) ( 30,0 )	C) ( 0,40 )	D) ( 40,30 )	E) ( 0,30 )

Rationale: "assume that the equation of the line is y = mx + c , where m and c are the slope and y - intercept . you are also given that the line crosses the point ( - 12 , - 39 ) , this means that this point will also lie on the line above . thus you get - 39 = m * ( - 12 ) + c , with m = 3 / 4 as the slope is given to be 3 / 4 . after substituting the above values , you get c = - 30 . thus the equation of the line is y = 0.75 * x - 30 and the point where it will intersect the x - axis will be with y coordinate = 0 . put y = 0 in the above equation of the line and you will get , x = 40 . thus , the point t of intersection is ( 40,0 ) . a is the correct answer ."
Answer: A