A runs 1 2⁄3 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
Options:	A) 200 m	B) 250 m	C) 450 m	D) 350 m	E) 270 m

Rationale: speed of a : speed of b = 5 ⁄ 3 : 1 = 5 : 3 i . e . , in a race of 5 m , a runs 5 m and b runs 3 m i . e . , a gains 2 m over b in a race of 5 m = > a gains 80 m over b in a race of 52 × 80 = 200 m hence , winning point should be 200 m away from the starting point . answer : a
Answer: A