A number is selected at random from the first 30 natural numbers. What is the probability that the number is a multiple of either 2 or 19?
Select the correct option
A) 17 / 30	B) 2 / 5	C) 7 / 15	D) 8 / 15	E) 11 / 30

Rationale: "number of multiples of 2 from 1 through 30 = 30 / 2 = 15 number of multiples of 19 from 1 through 30 = 30 / 19 = 1 number of multiples of 2 and 19 both from 1 through 30 = number of multiples of 19 * 2 ( = 38 ) = 0 total favourable cases = 15 + 1 - 0 = 16 probability = 16 / 30 = 8 / 15 answer : option d"
Answer: D