Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability E that Jane will be on the same committee as Albert?  Choose the correct choice from the following answers
A) 12 %
B) 20 %
C) 33 %
D) 40 %
E) 50 %

Rationale: "total number of ways to choose 3 member committee - 6 c 3 = ( 6 ! / 3 ! 3 ! ) = 20 no . of ways albert n jane are in same committee : - ( 4 c 1 * 2 ) = 8 probability e = ( 8 / 20 ) * 100 = 40 % . + 1 for me . . : d"
Answer: D