If 183 is divisible by 11, find the value of the smallest natural no. N? Options:
A) 5
B) 7
C) 9
D) 10
E) 12

Rationale: in aptitude tests , we get questions on divisibility by 11 . a number is divisible by 11 , when the difference between the sum of digits at even places and at odd places is 0 or multiple of 11 the given number is n 183 . ( sum of digits at even places ) – ( sum of digits at odd places ) = 0 ( 8 + n ) - ( 3 + 1 ) = 0 ( 8 + n ) - 4 = 0 here the value of n must be 7 b
Answer: B