In a box of 12 pens, a total of 4 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?	Choose the correct option:
A) 1 / 6  B) 2 / 33  C) 14 / 33  D) 9 / 16  E) 3 / 44

Rationale: "method - 1 there are 9 fine pieces of pen and 4 defective in a lot of 12 pens i . e . probability of first pen not being defective = ( 8 / 12 ) i . e . probability of second pen not being defective = ( 7 / 11 ) [ 11 pen remaining with 8 defective remaining considering that first was defective ] probability of both pen being non - defective = ( 8 / 12 ) * ( 7 / 11 ) = 14 / 33 answer : option c"
Answer: C