what is the smallest of 6 consecutive odd integers whose average ( arithmetic mean ) is b + 2 ?	Choose the correct choice:
A) b - 3
B) b - 6
C) b - 1
D) b
E) b + 1

Rationale: since the numbers are consecutive odd integers , mean = median = 3 rd integer + 4 th integer / 2 and 1 st integer = 3 rd integer - 4 let ' s say 3 rd integer = n and 4 th integer = n + 2 2 n + 2 / 2 = b + 2 n = b + 1 1 st integer = b + 1 - 4 = b - 3 a is the answer
Answer: A