A farmer planned to plough a field by doing 120 hectares a day. After two days of work he increased his daily productivity by 25% and he finished the job two days ahead of schedule.
a) What is the area of the field?
b) In how many days did the farmer get the job done?
c) In how many days did the farmer plan to get the job done?  Choose the correct choice from the following answers:	A) 2337	B) 2667	C) 1440	D) 2887	E) 2661

Rationale: first of all we will find the new daily productivity of the farmer in hectares per day : 25 % of 120 hectares is 25100 ⋅ 120 = 3025100 ⋅ 120 = 30 hectares , therefore 120 + 30 = 150120 + 30 = 150 hectares is the new daily productivity . lets x be the planned number of days allotted for the job . then the farm is 120 ⋅ x 120 ⋅ x hectares . on the other hand , we get the same area if we add 120 ⋅ 2120 ⋅ 2 hectares to 150 ( x − 4 ) 150 ( x − 4 ) hectares . then we get the equation 120 x = 120 ⋅ 2 + 150 ( x − 4 ) 120 x = 120 ⋅ 2 + 150 ( x − 4 ) x = 12 x = 12 so , the job was initially supposed to take 12 days , but actually the field was ploughed in 12 - 2 = 10 days . the field ' s area is 120 ⋅ 12 = 1440120 ⋅ 12 = 1440 hectares . answer : c
Answer: C