Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 27 percent ryegrass, what percent of the weight of this mixture is X ?
Options:	A) 10 %	B) 13.33 %	C) 40 %	D) 50 %	E) 66.66 %

Rationale: "- - - - - - - - - - - - - - - - > ryegrass x - - - - - - - - - - - - - - > 40 % y - - - - - - - - - - - - - - > 25 % m ( mixture ) - - - - > 27 % 0.4 x + ( m - x ) 0.25 = 0.27 m 0.15 x = 0.02 m x = 0.1333 m x = 13.33 % of m b"
Answer: B