Tickets numbered from 1 to 27 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3?	Pick one:	A) 1 / 3	B) 2 / 5	C) 3 / 10	D) 3 / 7	E) 1 / 7

Rationale: "here , s = [ 1 , 2 , 3 , 4 , … . , 19 , 20 , 21 , 22 , 23 , 24 , 25 , 26 , 27 ] let e = event of getting a multiple of 3 = [ 3 , 6 , 9 , 12 , 15 , 18 , 21 , 24 , 27 ] p ( e ) = n ( e ) / n ( s ) = 9 / 27 = 1 / 3 the answer is a ."
Answer: A