x is a positive integer less than 400. When x is divided by 7, the remainder is 1; when x is divided by 3, the remainder is 2. How many x are there? Pick one
A) 21	B) 22	C) 23	D) 24	E) 25

Rationale: the nubmer which when divided by 7 leaves remainder 1 should be of the form 7 k + 1 this number when divided by 3 leaves remainder 2 . so , ( 7 k + 1 ) - 2 should be divisible by 3 or 7 k - 1 should be divisible by 3 . we now put the values of k starting from 0 to find first number divisible by 3 we find 1 st number at k = 1 thus smallest number will be 7 ( 1 ) + 1 = 8 now , next number will be = 8 + lcm of 37 i . e 29 now we will find number of all such values less than 500 by using the formula for last term of an a . p 8 + ( n - 1 ) 21 = 400 n = 23.42 or n = 23 answer : - c
Answer: C