A bag contains 7 red, 9 blue and 5 green balls. If 3 balls are picked at random, what is the probability that both are red?  Choices
A) 2 / 21
B) 3 / 41
C) 5 / 26
D) 1 / 38
E) 5 / 32

Rationale: "p ( both are red ) , = 7 c 3 / 21 c 3 = ( 7 * 6 * 5 ) / 21 * 20 * 19 = 1 / 38 d"
Answer: D