Let S be the set of all positive integers that, when divided by 8, have a remainder of 5. What is the 79th number in this set?  Pick:  A) 605  B) 608  C) 613  D) 616  E) 629

Rationale: "the set s = { 5 , 13 , 21 , 29 , . . . . . . . . . . . . . . . . . . . . . } 1 st number = 8 * 0 + 5 = 5 2 nd number = 8 * 1 + 5 = 13 3 rd number = 8 * 2 + 5 = 21 79 th number = 8 * ( 79 - 1 ) + 5 = 629 answer = e"
Answer: E